ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<perm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  cmp    $0x1,%esi
  jle    L52
  lea    -0x2(%rsi),%edi
  mov    $0x0,%eax
  mov    $0x0,%esi
  jmp    L6
L41:
  mov    %eax,%r12d
L33:
  lea    0x1(%rax),%rdx
  cmp    %rdi,%rax
  je     L57
  mov    %rdx,%rax
L6:
  mov    0x4(%rbx,%rax,4),%edx
  cmp    %edx,(%rbx,%rax,4)
  jl     L41
  add    $0x1,%esi
  jmp    L33
L52:
  mov    $0x0,%esi
L57:
  lea    -0x1(%rbp),%edx
  mov    $0x1,%eax
  cmp    %esi,%edx
  jle    L72
  lea    0x1(%r12),%eax
  cmp    %eax,%ebp
  jle    L38
  movslq %r12d,%rdx
  mov    (%rbx,%rdx,4),%edx
  cltq
L75:
  cmp    (%rbx,%rax,4),%edx
  cmovl  %eax,%ecx
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L75
L38:
  mov    %ecx,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printv@plt>
  mov    $0x0,%eax
L72:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int perm(int p[], int n) {
  int l, k, i, counter = 0, t = n - 2;
  for (i = 0; i <= t; i++) {
    if (p[i] < p[i + 1])
      k = i;
    else
      counter++;
  }
  if (counter > n - 2)
    return 1;
  t = n - 1;
  for (i = k + 1; i < n; i++) {
    if (p[k] < p[i])
      l = i;
  }
  swap(p, k, l);
  reverse(p, n, k);
  printv(p, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<perm>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  cmp    $0x1,%esi
  jle    L33
  lea    -0x2(%rsi),%esi
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L54
  nopl   0x0(%rax)
L85:
  add    $0x1,%ecx
  lea    0x1(%rax),%rdx
  cmp    %rsi,%rax
  je     L77
L45:
  mov    %rdx,%rax
L54:
  mov    0x4(%rbp,%rax,4),%edi
  cmp    %edi,0x0(%rbp,%rax,4)
  jge    L85
  mov    %eax,%r13d
  lea    0x1(%rax),%rdx
  cmp    %rsi,%rax
  jne    L45
L77:
  lea    -0x1(%r12),%edx
  mov    $0x1,%eax
  cmp    %ecx,%edx
  jle    L39
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  jle    L78
  movslq %r13d,%rdx
  cltq
  mov    0x0(%rbp,%rdx,4),%edx
  nopl   (%rax)
L26:
  cmp    0x0(%rbp,%rax,4),%edx
  cmovl  %eax,%r8d
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L26
L78:
  mov    %r8d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printv@plt>
  xor    %eax,%eax
L39:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  xor    %ecx,%ecx
  jmp    L77
```

assistant: ```c
int perm(int p[], int n) {
  int l, k, i, counter = 0, t = n - 2;
  for (i = 0; i <= t; i++) {
    if (p[i] < p[i + 1])
      k = i;
    else
      counter++;
  }
  if (counter > n - 2)
    return 1;
  t = n - 1;
  for (i = k + 1; i < n; i++) {
    if (p[k] < p[i])
      l = i;
  }
  swap(p, k, l);
  reverse(p, n, k);
  printv(p, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func1(void) {
  for (; 1;) {
    for (; 1;) {
      for (; 1;) {
        for (; 1;) {
          for (; 1;) {
            return (1);
          }
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func1>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int func1(void) {
  for (; 1;) {
    for (; 1;) {
      for (; 1;) {
        for (; 1;) {
          for (; 1;) {
            return (1);
          }
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func1>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int func1(void) {
  for (; 1;) {
    for (; 1;) {
      for (; 1;) {
        for (; 1;) {
          for (; 1;) {
            return (1);
          }
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_cdq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0xaabbccdd,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  cltd
  mov    %eax,-0x10(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  je     L11
  mov    $0x1,%eax
  (bad)
L11:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L36
  mov    $0xffffffff,%edx
  jmp    L45
L36:
  mov    $0x0,%edx
L45:
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  je     L28
  mov    $0x1,%eax
  (bad)
L28:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
void test_cdq(int x) {
  volatile int a, d, newa, newd;
  a = x;
  d = 0xaabbccdd;
  __asm__ __volatile__("mov %2, %%eax\n\t"
                       "mov %3, %%edx\n\t"
                       "cltd\n\t"
                       "mov %%eax, %0\n\t"
                       "mov %%edx, %1\n\t"
                       : "=m"(newa), "=m"(newd)
                       : "m"(a), "m"(d)
                       : "eax", "edx");
  do {
    if (!(newa == a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
  do {
    if (!(newd == (a < 0 ? -1 : 0)))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_cdq>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x8(%rsp)
  movl   $0xaabbccdd,0xc(%rsp)
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cltd
  mov    %eax,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    0x10(%rsp),%edx
  mov    0x8(%rsp),%eax
  cmp    %eax,%edx
  je     L7
  mov    $0x1,%eax
  (bad)
L7:
  mov    0x8(%rsp),%eax
  mov    0x14(%rsp),%edx
  sar    $0x1f,%eax
  cmp    %eax,%edx
  je     L0
  mov    $0x1,%eax
  (bad)
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cdq(int x) {
  volatile int a, d, newa, newd;
  a = x;
  d = 0xaabbccdd;
  __asm__ __volatile__("mov %2, %%eax\n\t"
                       "mov %3, %%edx\n\t"
                       "cltd\n\t"
                       "mov %%eax, %0\n\t"
                       "mov %%edx, %1\n\t"
                       : "=m"(newa), "=m"(newd)
                       : "m"(a), "m"(d)
                       : "eax", "edx");
  do {
    if (!(newa == a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
  do {
    if (!(newd == (a < 0 ? -1 : 0)))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_cdq>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x8(%rsp)
  movl   $0xaabbccdd,0xc(%rsp)
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cltd
  mov    %eax,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    0x10(%rsp),%edx
  mov    0x8(%rsp),%eax
  cmp    %eax,%edx
  je     L13
  mov    $0x1,%eax
  (bad)
L13:
  mov    0x8(%rsp),%eax
  mov    0x14(%rsp),%edx
  sar    $0x1f,%eax
  cmp    %eax,%edx
  je     L27
  mov    $0x1,%eax
  (bad)
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cdq(int x) {
  volatile int a, d, newa, newd;
  a = x;
  d = 0xaabbccdd;
  __asm__ __volatile__("mov %2, %%eax\n\t"
                       "mov %3, %%edx\n\t"
                       "cltd\n\t"
                       "mov %%eax, %0\n\t"
                       "mov %%edx, %1\n\t"
                       : "=m"(newa), "=m"(newd)
                       : "m"(a), "m"(d)
                       : "eax", "edx");
  do {
    if (!(newa == a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
  do {
    if (!(newd == (a < 0 ? -1 : 0)))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_cdq>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x8(%rsp)
  movl   $0xaabbccdd,0xc(%rsp)
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cltd
  mov    %eax,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  mov    0x10(%rsp),%edx
  mov    0x8(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  mov    $0x1,%eax
  (bad)
L0:
  mov    0x8(%rsp),%eax
  mov    0x14(%rsp),%edx
  sar    $0x1f,%eax
  cmp    %eax,%edx
  je     L18
  mov    $0x1,%eax
  (bad)
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_cdq(int x) {
  volatile int a, d, newa, newd;
  a = x;
  d = 0xaabbccdd;
  __asm__ __volatile__("mov %2, %%eax\n\t"
                       "mov %3, %%edx\n\t"
                       "cltd\n\t"
                       "mov %%eax, %0\n\t"
                       "mov %%edx, %1\n\t"
                       : "=m"(newa), "=m"(newd)
                       : "m"(a), "m"(d)
                       : "eax", "edx");
  do {
    if (!(newa == a))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
  do {
    if (!(newd == (a < 0 ? -1 : 0)))
      asm volatile(".byte 0xd6" : : "a"(1));
  } while (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<unparse_wolopts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x10,%edx
  mov    $0x0,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L41
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L75
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x70,(%rax)
L75:
  mov    -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L68
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x75,(%rax)
L68:
  mov    -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L16
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x6d,(%rax)
L16:
  mov    -0x14(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x62,(%rax)
L34:
  mov    -0x14(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L48
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x61,(%rax)
L48:
  mov    -0x14(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L58
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x67,(%rax)
L58:
  mov    -0x14(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L26
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x73,(%rax)
  jmp    L26
L41:
  mov    -0x8(%rbp),%rax
  movb   $0x64,(%rax)
L26:
  lea    D18(%rip),%rax
  leave
  ret
```

assistant: ```c
char *unparse_wolopts(int wolopts) {
  static char buf[16];
  char *p = buf;
  memset(buf, 0, sizeof(buf));
  if (wolopts) {
    if (wolopts & (1 << 0))
      *p++ = 'p';
    if (wolopts & (1 << 1))
      *p++ = 'u';
    if (wolopts & (1 << 2))
      *p++ = 'm';
    if (wolopts & (1 << 3))
      *p++ = 'b';
    if (wolopts & (1 << 4))
      *p++ = 'a';
    if (wolopts & (1 << 5))
      *p++ = 'g';
    if (wolopts & (1 << 6))
      *p++ = 's';
  } else {
    *p = 'd';
  }
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<unparse_wolopts>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edx
  mov    $0x0,%esi
  lea    D48(%rip),%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L60
  lea    D48(%rip),%rax
  test   $0x1,%bl
  je     L84
  movb   $0x70,D48(%rip)
  lea    0x1(%rax),%rax
L84:
  test   $0x2,%bl
  je     L83
  movb   $0x75,(%rax)
  lea    0x1(%rax),%rax
L83:
  test   $0x4,%bl
  je     L43
  movb   $0x6d,(%rax)
  lea    0x1(%rax),%rax
L43:
  test   $0x8,%bl
  je     L9
  movb   $0x62,(%rax)
  lea    0x1(%rax),%rax
L9:
  test   $0x10,%bl
  je     L49
  movb   $0x61,(%rax)
  lea    0x1(%rax),%rax
L49:
  test   $0x20,%bl
  je     L72
  movb   $0x67,(%rax)
  lea    0x1(%rax),%rax
L72:
  test   $0x40,%bl
  je     L61
  movb   $0x73,(%rax)
  jmp    L61
L60:
  movb   $0x64,D48(%rip)
L61:
  lea    D48(%rip),%rax
  pop    %rbx
  ret
```

assistant: ```c
char *unparse_wolopts(int wolopts) {
  static char buf[16];
  char *p = buf;
  memset(buf, 0, sizeof(buf));
  if (wolopts) {
    if (wolopts & (1 << 0))
      *p++ = 'p';
    if (wolopts & (1 << 1))
      *p++ = 'u';
    if (wolopts & (1 << 2))
      *p++ = 'm';
    if (wolopts & (1 << 3))
      *p++ = 'b';
    if (wolopts & (1 << 4))
      *p++ = 'a';
    if (wolopts & (1 << 5))
      *p++ = 'g';
    if (wolopts & (1 << 6))
      *p++ = 's';
  } else {
    *p = 'd';
  }
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unparse_wolopts>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  xor    %esi,%esi
  mov    $0x10,%edx
  push   %rbx
  mov    %edi,%ebx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  test   %ebx,%ebx
  je     L15
  mov    %r12,%rax
  test   $0x1,%bl
  je     L38
  movb   $0x70,D2(%rip)
  add    $0x1,%rax
L38:
  test   $0x2,%bl
  je     L69
  movb   $0x75,(%rax)
  add    $0x1,%rax
L69:
  test   $0x4,%bl
  je     L53
  movb   $0x6d,(%rax)
  add    $0x1,%rax
L53:
  test   $0x8,%bl
  je     L21
  movb   $0x62,(%rax)
  add    $0x1,%rax
L21:
  test   $0x10,%bl
  je     L79
  movb   $0x61,(%rax)
  add    $0x1,%rax
L79:
  test   $0x20,%bl
  je     L7
  movb   $0x67,(%rax)
  add    $0x1,%rax
L7:
  and    $0x40,%ebx
  je     L64
  movb   $0x73,(%rax)
L64:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  movb   $0x64,D2(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *unparse_wolopts(int wolopts) {
  static char buf[16];
  char *p = buf;
  memset(buf, 0, sizeof(buf));
  if (wolopts) {
    if (wolopts & (1 << 0))
      *p++ = 'p';
    if (wolopts & (1 << 1))
      *p++ = 'u';
    if (wolopts & (1 << 2))
      *p++ = 'm';
    if (wolopts & (1 << 3))
      *p++ = 'b';
    if (wolopts & (1 << 4))
      *p++ = 'a';
    if (wolopts & (1 << 5))
      *p++ = 'g';
    if (wolopts & (1 << 6))
      *p++ = 's';
  } else {
    *p = 'd';
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unparse_wolopts>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  xor    %esi,%esi
  mov    $0x10,%edx
  push   %rbx
  mov    %edi,%ebx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  test   %ebx,%ebx
  je     L65
  mov    %r12,%rax
  test   $0x1,%bl
  je     L48
  movb   $0x70,D17(%rip)
  add    $0x1,%rax
L48:
  test   $0x2,%bl
  je     L41
  movb   $0x75,(%rax)
  add    $0x1,%rax
L41:
  test   $0x4,%bl
  je     L52
  movb   $0x6d,(%rax)
  add    $0x1,%rax
L52:
  test   $0x8,%bl
  je     L20
  movb   $0x62,(%rax)
  add    $0x1,%rax
L20:
  test   $0x10,%bl
  je     L68
  movb   $0x61,(%rax)
  add    $0x1,%rax
L68:
  test   $0x20,%bl
  je     L66
  movb   $0x67,(%rax)
  add    $0x1,%rax
L66:
  and    $0x40,%ebx
  je     L15
  movb   $0x73,(%rax)
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L65:
  movb   $0x64,D17(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *unparse_wolopts(int wolopts) {
  static char buf[16];
  char *p = buf;
  memset(buf, 0, sizeof(buf));
  if (wolopts) {
    if (wolopts & (1 << 0))
      *p++ = 'p';
    if (wolopts & (1 << 1))
      *p++ = 'u';
    if (wolopts & (1 << 2))
      *p++ = 'm';
    if (wolopts & (1 << 3))
      *p++ = 'b';
    if (wolopts & (1 << 4))
      *p++ = 'a';
    if (wolopts & (1 << 5))
      *p++ = 'g';
    if (wolopts & (1 << 6))
      *p++ = 's';
  } else {
    *p = 'd';
  }
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  add    $0x1c,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L59
L42:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L3
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L8
L3:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
L8:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L26
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xa(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L0
L26:
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
L0:
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L59:
  cmpb   $0x0,-0xa(%rbp)
  je     L42
  movzbl -0x9(%rbp),%eax
  lea    0x5c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] = state[local1] - state[0UL];
      }
      if (state[0UL] > local1) {
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] *= state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 180391357UL) + (unsigned char)25;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movb   $0x5c,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] = state[local1] - state[0UL];
      }
      if (state[0UL] > local1) {
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] *= state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 180391357UL) + (unsigned char)25;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movb   $0x5c,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] = state[local1] - state[0UL];
      }
      if (state[0UL] > local1) {
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] *= state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 180391357UL) + (unsigned char)25;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movb   $0x5c,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
      } else {
        state[0UL] = state[local1] - state[0UL];
      }
      if (state[0UL] > local1) {
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] *= state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 180391357UL) + (unsigned char)25;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L30
L34:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <convert@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L26
  movzbl -0x50(%rbp),%eax
  cmp    $0x30,%al
  jne    L34
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D16
datatype: string

tool: D7: %d


tool: D16: %s

assistant: ```c
int main() {
  char str[64];
  int ans;
  while (scanf("%s", str) == 1 && str[0] != '0') {
    ans = convert(str, strlen(str));
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D18(%rip),%rbp
  lea    D16(%rip),%r12
  jmp    L37
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <convert@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L37:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L2
  cmpb   $0x30,(%rsp)
  jne    L17
L2:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string

tool: D18: %s

tool: D16: %d


assistant: ```c
int main() {
  char str[64];
  int ans;
  while (scanf("%s", str) == 1 && str[0] != '0') {
    ans = convert(str, strlen(str));
    printf("%d\n", ans);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L2
  nop
L4:
  cmpb   $0x30,(%rsp)
  je     L28
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <convert@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L4
L28:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D19
type: string

tool: D1: %d


tool: D19: %s

assistant: ```c
int main() {
  char str[64];
  int ans;
  while (scanf("%s", str) == 1 && str[0] != '0') {
    ans = convert(str, strlen(str));
    printf("%d\n", ans);
  }
  return 0;
}
```