ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L41
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <randint@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L12
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jae    L5
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L5:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L0
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L7
L41:
  nop
L7:
  leave
  ret
```

assistant: ```c
void quicksort(unsigned int *hashedWords, int l, int u) {
  int i, m;
  if (l >= u)
    return;
  swap(hashedWords, l, randint(l, u));
  m = l;
  for (i = l + 1; i <= u; i++)
    if (hashedWords[i] < hashedWords[l])
      swap(hashedWords, ++m, i);
  swap(hashedWords, l, m);
  quicksort(hashedWords, l, m - 1);
  quicksort(hashedWords, m + 1, u);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L56
  ret
L56:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    %r13d,%edi
  call   <randint@plt>
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    0x1(%r13),%ebx
  cmp    %ebx,%r12d
  jl     L27
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%r15
  movslq %ebx,%rbx
  mov    %r13d,%r14d
  jmp    L42
L30:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L8
L42:
  mov    %ebx,%edx
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jae    L30
  add    $0x1,%r14d
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L30
L27:
  mov    %r13d,%r14d
L8:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(unsigned int *hashedWords, int l, int u) {
  int i, m;
  if (l >= u)
    return;
  swap(hashedWords, l, randint(l, u));
  m = l;
  for (i = l + 1; i <= u; i++)
    if (hashedWords[i] < hashedWords[l])
      swap(hashedWords, ++m, i);
  swap(hashedWords, l, m);
  quicksort(hashedWords, l, m - 1);
  quicksort(hashedWords, m + 1, u);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L30:
  cmp    %r14d,%r12d
  jle    L0
L15:
  mov    %r12d,%esi
  mov    %r14d,%edi
  lea    0x1(%r14),%ebx
  call   <randint@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jl     L74
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rax,4),%r15
  jmp    L23
  nopl   (%rax)
L33:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L17
L23:
  mov    (%r15),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jae    L33
  add    $0x1,%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jge    L23
L17:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r13),%r14d
  cmp    %r12d,%r14d
  jl     L15
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L74:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r12d
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L30
```

assistant: ```c
void quicksort(unsigned int *hashedWords, int l, int u) {
  int i, m;
  if (l >= u)
    return;
  swap(hashedWords, l, randint(l, u));
  m = l;
  for (i = l + 1; i <= u; i++)
    if (hashedWords[i] < hashedWords[l])
      swap(hashedWords, ++m, i);
  swap(hashedWords, l, m);
  quicksort(hashedWords, l, m - 1);
  quicksort(hashedWords, m + 1, u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L67:
  cmp    %r14d,%r12d
  jle    L71
L76:
  mov    %r12d,%esi
  mov    %r14d,%edi
  lea    0x1(%r14),%ebx
  call   <randint@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <swap@plt>
  cmp    %ebx,%r12d
  jl     L31
  movslq %r14d,%rax
  movslq %ebx,%rbx
  mov    %r14d,%r13d
  lea    0x0(%rbp,%rax,4),%r15
  jmp    L63
  nopl   (%rax)
L10:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L44
L63:
  mov    (%r15),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jae    L10
  add    $0x1,%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jge    L63
L44:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r13),%r14d
  cmp    %r12d,%r14d
  jl     L76
L71:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L31:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%r12d
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L67
```

assistant: ```c
void quicksort(unsigned int *hashedWords, int l, int u) {
  int i, m;
  if (l >= u)
    return;
  swap(hashedWords, l, randint(l, u));
  m = l;
  for (i = l + 1; i <= u; i++)
    if (hashedWords[i] < hashedWords[l])
      swap(hashedWords, ++m, i);
  swap(hashedWords, l, m);
  quicksort(hashedWords, l, m - 1);
  quicksort(hashedWords, m + 1, u);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bn_sqr_normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x44(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  subl   $0x1,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L27
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_mul_words@plt>
  mov    %rax,(%rbx)
  addq   $0x10,-0x18(%rbp)
L27:
  mov    -0x44(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L13
L17:
  subl   $0x1,-0x28(%rbp)
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_mul_add_words@plt>
  mov    %rax,(%rbx)
  addq   $0x10,-0x18(%rbp)
  subl   $0x1,-0x2c(%rbp)
L13:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L17
  mov    -0x24(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_add_words@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bn_sqr_words@plt>
  mov    -0x24(%rbp),%ecx
  mov    -0x50(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_add_words@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void bn_sqr_normal(unsigned long long *r, unsigned long long *a, int n, unsigned long long *tmp) {
  int i, j, max;
  unsigned long long *ap, *rp;
  max = n * 2;
  ap = a;
  rp = r;
  rp[0] = rp[max - 1] = 0;
  rp++;
  j = n;
  if (--j > 0) {
    ap++;
    rp[j] = bn_mul_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  for (i = n - 2; i > 0; i--) {
    j--;
    ap++;
    rp[j] = bn_mul_add_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  bn_add_words(r, r, r, max);
  bn_sqr_words(tmp, a, n);
  bn_add_words(r, r, tmp, max);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bn_sqr_normal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,0x10(%rsp)
  mov    %edx,%r15d
  mov    %rcx,0x18(%rsp)
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,0xc(%rsp)
  cltq
  movq   $0x0,-0x8(%rdi,%rax,8)
  movq   $0x0,(%rdi)
  lea    0x8(%rdi),%r12
  lea    -0x1(%rdx),%r13d
  mov    %rsi,%rbp
  test   %r13d,%r13d
  jg     L25
L10:
  lea    -0x2(%r15),%ebx
  test   %ebx,%ebx
  jle    L35
  movslq %r13d,%r13
  lea    -0x8(%r12,%r13,8),%r13
L26:
  add    $0x8,%rbp
  mov    -0x8(%rbp),%rcx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <bn_mul_add_words@plt>
  mov    %rax,0x0(%r13)
  add    $0x10,%r12
  add    $0x8,%r13
  sub    $0x1,%ebx
  jne    L26
L35:
  mov    0xc(%rsp),%ebp
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %r14,%rsi
  mov    %r14,%rdi
  call   <bn_add_words@plt>
  mov    %r15d,%edx
  mov    0x10(%rsp),%rsi
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rdi
  call   <bn_sqr_words@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r14,%rdi
  call   <bn_add_words@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  lea    0x8(%rsi),%rbp
  movslq %r13d,%rax
  lea    (%r12,%rax,8),%rbx
  mov    (%rsi),%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <bn_mul_words@plt>
  mov    %rax,(%rbx)
  lea    0x18(%r14),%r12
  jmp    L10
```

assistant: ```c
void bn_sqr_normal(unsigned long long *r, unsigned long long *a, int n, unsigned long long *tmp) {
  int i, j, max;
  unsigned long long *ap, *rp;
  max = n * 2;
  ap = a;
  rp = r;
  rp[0] = rp[max - 1] = 0;
  rp++;
  j = n;
  if (--j > 0) {
    ap++;
    rp[j] = bn_mul_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  for (i = n - 2; i > 0; i--) {
    j--;
    ap++;
    rp[j] = bn_mul_add_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  bn_add_words(r, r, r, max);
  bn_sqr_words(tmp, a, n);
  bn_add_words(r, r, tmp, max);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bn_sqr_normal>:
  endbr64
  push   %r15
  lea    (%rdx,%rdx,1),%eax
  mov    %rsi,%r15
  push   %r14
  lea    0x8(%rdi),%r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %eax,0xc(%rsp)
  cltq
  movq   $0x0,-0x8(%rdi,%rax,8)
  mov    %rsi,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  movq   $0x0,(%rdi)
  test   %r13d,%r13d
  jle    L1
  mov    (%rsi),%rcx
  lea    0x8(%rsi),%r15
  movslq %r13d,%rax
  mov    %r14,%rdi
  mov    %r13d,%edx
  mov    %r15,%rsi
  lea    (%r14,%rax,8),%rbx
  call   <bn_mul_words@plt>
  lea    0x18(%rbp),%r14
  mov    %rax,(%rbx)
L1:
  lea    -0x2(%r12),%ebx
  test   %ebx,%ebx
  jle    L12
  movslq %r13d,%rdx
  lea    -0x8(%r14,%rdx,8),%r13
  nop
L14:
  add    $0x8,%r15
  mov    -0x8(%r15),%rcx
  mov    %r14,%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  add    $0x10,%r14
  add    $0x8,%r13
  call   <bn_mul_add_words@plt>
  mov    %rax,-0x8(%r13)
  sub    $0x1,%ebx
  jne    L14
L12:
  mov    0xc(%rsp),%r14d
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %r14d,%ecx
  call   <bn_add_words@plt>
  mov    0x18(%rsp),%rbx
  mov    0x10(%rsp),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <bn_sqr_words@plt>
  add    $0x28,%rsp
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <bn_add_words@plt>
```

assistant: ```c
void bn_sqr_normal(unsigned long long *r, unsigned long long *a, int n, unsigned long long *tmp) {
  int i, j, max;
  unsigned long long *ap, *rp;
  max = n * 2;
  ap = a;
  rp = r;
  rp[0] = rp[max - 1] = 0;
  rp++;
  j = n;
  if (--j > 0) {
    ap++;
    rp[j] = bn_mul_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  for (i = n - 2; i > 0; i--) {
    j--;
    ap++;
    rp[j] = bn_mul_add_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  bn_add_words(r, r, r, max);
  bn_sqr_words(tmp, a, n);
  bn_add_words(r, r, tmp, max);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bn_sqr_normal>:
  endbr64
  push   %r15
  lea    (%rdx,%rdx,1),%eax
  mov    %rsi,%r15
  push   %r14
  lea    0x8(%rdi),%r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %eax,0xc(%rsp)
  cltq
  movq   $0x0,-0x8(%rdi,%rax,8)
  mov    %rsi,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  movq   $0x0,(%rdi)
  test   %r13d,%r13d
  jle    L23
  mov    (%rsi),%rcx
  lea    0x8(%rsi),%r15
  movslq %r13d,%rax
  mov    %r14,%rdi
  mov    %r13d,%edx
  mov    %r15,%rsi
  lea    (%r14,%rax,8),%rbx
  call   <bn_mul_words@plt>
  lea    0x18(%rbp),%r14
  mov    %rax,(%rbx)
L23:
  lea    -0x2(%r12),%ebx
  test   %ebx,%ebx
  jle    L12
  movslq %r13d,%rdx
  lea    -0x8(%r14,%rdx,8),%r13
  nop
L13:
  add    $0x8,%r15
  mov    -0x8(%r15),%rcx
  mov    %r14,%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  add    $0x10,%r14
  add    $0x8,%r13
  call   <bn_mul_add_words@plt>
  mov    %rax,-0x8(%r13)
  sub    $0x1,%ebx
  jne    L13
L12:
  mov    0xc(%rsp),%r14d
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %r14d,%ecx
  call   <bn_add_words@plt>
  mov    0x18(%rsp),%rbx
  mov    0x10(%rsp),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <bn_sqr_words@plt>
  add    $0x28,%rsp
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <bn_add_words@plt>
```

assistant: ```c
void bn_sqr_normal(unsigned long long *r, unsigned long long *a, int n, unsigned long long *tmp) {
  int i, j, max;
  unsigned long long *ap, *rp;
  max = n * 2;
  ap = a;
  rp = r;
  rp[0] = rp[max - 1] = 0;
  rp++;
  j = n;
  if (--j > 0) {
    ap++;
    rp[j] = bn_mul_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  for (i = n - 2; i > 0; i--) {
    j--;
    ap++;
    rp[j] = bn_mul_add_words(rp, ap, j, ap[-1]);
    rp += 2;
  }
  bn_add_words(r, r, r, max);
  bn_sqr_words(tmp, a, n);
  bn_add_words(r, r, tmp, max);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L32:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <tmpl@plt>
  addl   $0x1,-0x10(%rbp)
  addl   $0x2,-0xc(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L32
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L8:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <tmpl@plt>
  cmpl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: (le(i,j,k,n),le(i,j,k,n))

assistant: ```c
void main() {
  int n;
  int i = 0;
  int k = 0;
  while (i < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    i++;
    k = k + 2;
  }
  int j = 0;
  while (j < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    if (k <= 0)
    ERROR:;
      j++;
    k--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int n;
  int i = 0;
  int k = 0;
  while (i < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    i++;
    k = k + 2;
  }
  int j = 0;
  while (j < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    if (k <= 0)
    ERROR:;
      j++;
    k--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int n;
  int i = 0;
  int k = 0;
  while (i < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    i++;
    k = k + 2;
  }
  int j = 0;
  while (j < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    if (k <= 0)
    ERROR:;
      j++;
    k--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int n;
  int i = 0;
  int k = 0;
  while (i < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    i++;
    k = k + 2;
  }
  int j = 0;
  while (j < n) {
    tmpl("(le(i,j,k,n),le(i,j,k,n))");
    if (k <= 0)
    ERROR:;
      j++;
    k--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sumOfNaturalNumbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sumOfNaturalNumbers>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  jmp    L12
L15:
  mov    -0x4(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int sumOfNaturalNumbers(int number) {
  if (number != 0) {
    return number + sumOfNaturalNumbers(number - 1);
  } else {
    return number;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sumOfNaturalNumbers>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L4
L17:
  mov    %ebx,%eax
  pop    %rbx
  ret
L4:
  lea    -0x1(%rdi),%edi
  call   <sumOfNaturalNumbers>
  add    %eax,%ebx
  jmp    L17
```

assistant: ```c
int sumOfNaturalNumbers(int number) {
  if (number != 0) {
    return number + sumOfNaturalNumbers(number - 1);
  } else {
    return number;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sumOfNaturalNumbers>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L0
  nopw   0x0(%rax,%rax,1)
L16:
  add    %edi,%eax
  sub    $0x1,%edi
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
int sumOfNaturalNumbers(int number) {
  if (number != 0) {
    return number + sumOfNaturalNumbers(number - 1);
  } else {
    return number;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sumOfNaturalNumbers>:
  endbr64
  test   %edi,%edi
  je     L56
  lea    -0x1(%rdi),%edx
  mov    %edi,%ecx
  cmp    $0x9,%edx
  jbe    L74
  movd   %edi,%xmm4
  mov    %edi,%edx
  movdqa D10(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  paddd  D3(%rip),%xmm1
  shr    $0x2,%edx
  pxor   %xmm0,%xmm0
  xchg   %ax,%ax
L68:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L68
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%edi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%ecx
  je     L44
  lea    -0x1(%rdi),%edx
L38:
  add    %edi,%eax
  test   %edx,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x2,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x3,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x4,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x5,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x6,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x7,%edx
  je     L44
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x8,%edx
  je     L44
  add    %eax,%edx
  lea    -0x9(%rdi,%rdx,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
L44:
  ret
L74:
  xor    %eax,%eax
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D3
data_type: byte[16]

tool: {"D10": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D3": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

assistant: ```c
int sumOfNaturalNumbers(int number) {
  if (number != 0) {
    return number + sumOfNaturalNumbers(number - 1);
  } else {
    return number;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<comp_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x8000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L115
  negl   -0x14(%rbp)
L115:
  cmpl   $0x1fde,-0x14(%rbp)
  jle    L146
  movl   $0x1fde,-0x14(%rbp)
L146:
  addl   $0x21,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1000,%eax
  test   %eax,%eax
  je     L112
  movl   $0x7,-0x8(%rbp)
  jmp    L12
L112:
  mov    -0x14(%rbp),%eax
  and    $0x800,%eax
  test   %eax,%eax
  je     L134
  movl   $0x6,-0x8(%rbp)
  jmp    L12
L134:
  mov    -0x14(%rbp),%eax
  and    $0x400,%eax
  test   %eax,%eax
  je     L92
  movl   $0x5,-0x8(%rbp)
  jmp    L12
L92:
  mov    -0x14(%rbp),%eax
  and    $0x200,%eax
  test   %eax,%eax
  je     L75
  movl   $0x4,-0x8(%rbp)
  jmp    L12
L75:
  mov    -0x14(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L117
  movl   $0x3,-0x8(%rbp)
  jmp    L12
L117:
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L9
  movl   $0x2,-0x8(%rbp)
  jmp    L12
L9:
  mov    -0x14(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L33
  movl   $0x1,-0x8(%rbp)
  jmp    L12
L33:
  movl   $0x0,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  or     %edx,%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t comp_encode(int16_t sample) {
  int exp;
  int sign = sample & 0x8000;
  if (sign)
    sample = -sample;
  if (sample > 8158)
    sample = 8158;
  sample += 33;
  if (sample & (1 << 12))
    exp = 7;
  else if (sample & (1 << 11))
    exp = 6;
  else if (sample & (1 << 10))
    exp = 5;
  else if (sample & (1 << 9))
    exp = 4;
  else if (sample & (1 << 8))
    exp = 3;
  else if (sample & (1 << 7))
    exp = 2;
  else if (sample & (1 << 6))
    exp = 1;
  else
    exp = 0;
  return ~(((sample >> (exp + 1)) & 0xF) | (exp << 4) | (sign >> 8));
}
```