user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D138(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sub@plt>
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mul@plt>
  mov    %eax,%esi
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gt@plt>
  test   %rax,%rax
  je     L7
  lea    D133(%rip),%rax
  jmp    L22
L7:
  lea    D76(%rip),%rax
L22:
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <lt@plt>
  test   %rax,%rax
  je     L9
  lea    D133(%rip),%rax
  jmp    L12
L9:
  lea    D76(%rip),%rax
L12:
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getByte@plt>
  mov    %eax,%esi
  lea    D104(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D42
data_type: string
name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D138
data_type: string
name: parse_data
arguments: tag: D64
data_type: string
name: parse_data
arguments: tag: D81
data_type: string
name: parse_data
arguments: tag: D133
data_type: string
name: parse_data
arguments: tag: D76
data_type: string
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D104
data_type: string

tool: D11: Enter an integer 

tool: D42: %u

tool: D12: 
Enter another integer 

tool: D138: 
i + j = %u


tool: D64: 
i - j = %u


tool: D81: 
i * j = %u


tool: D133: TRUE

tool: D76: FALSE

tool: D26: i > j = %s


tool: D33: i < j = %s


tool: D104: jth byte of i = %ux


assistant: ```c
int main(int argc, char **argv) {
  unsigned int i, j;
  printf("Enter an integer ");
  scanf("%u", &i);
  printf("\nEnter another integer ");
  scanf("%u", &j);
  printf("\ni + j = %u\n", add(i, j));
  printf("\ni - j = %u\n", sub(i, j));
  printf("\ni * j = %u\n", mul(i, j));
  printf("i > j = %s\n", (gt(i, j) ? "TRUE" : "FALSE"));
  printf("i < j = %s\n", (lt(i, j) ? "TRUE" : "FALSE"));
  printf("jth byte of i = %ux\n", getByte(i, j));
  return 0;
}
```