ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Merge_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L2
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Merge_Sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Merge_Sort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Merge@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void Merge_Sort(char *str, int low, int high) {
  if (low < high) {
    int mid = (low + high) / 2;
    Merge_Sort(str, low, mid);
    Merge_Sort(str, mid + 1, high);
    Merge(str, low, mid, high);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Merge_Sort>:
  endbr64
  cmp    %edx,%esi
  jl     L3
  ret
L3:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <Merge_Sort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <Merge_Sort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <Merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Merge_Sort(char *str, int low, int high) {
  if (low < high) {
    int mid = (low + high) / 2;
    Merge_Sort(str, low, mid);
    Merge_Sort(str, mid + 1, high);
    Merge(str, low, mid, high);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0xf423f,-0x4(%rbp)
  jle    L5
  nop
  pop    %rbp
  ret
```

assistant: ```c
int t(int *a) {
  int i;
  for (i = 0; i < 1000000; i++)
    a[i]++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t>:
  endbr64
  lea    0x3d0900(%rdi),%rax
L9:
  addl   $0x1,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L9
  ret
```

assistant: ```c
int t(int *a) {
  int i;
  for (i = 0; i < 1000000; i++)
    a[i]++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t>:
  endbr64
  lea    0x3d0900(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L7:
  addl   $0x1,(%rdi)
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L7
  ret
```

assistant: ```c
int t(int *a) {
  int i;
  for (i = 0; i < 1000000; i++)
    a[i]++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t>:
  endbr64
  movdqa D0(%rip),%xmm1
  lea    0x3d0900(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L3:
  movdqu (%rdi),%xmm0
  add    $0x10,%rdi
  paddd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rdi)
  cmp    %rdi,%rax
  jne    L3
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: byte[16]

tool: {"D0": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int t(int *a) {
  int i;
  for (i = 0; i < 1000000; i++)
    a[i]++;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cache_dflush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x11,%edi
  call   <mfspr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  or     $0x40000,%rax
  mov    %rax,%rsi
  mov    $0x11,%edi
  call   <mtspr@plt>
  nop
  leave
  ret
```

assistant: ```c
void cache_dflush(void) {
  unsigned long sr = mfspr((17));
  mtspr((17), sr | (1 << 18));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cache_dflush>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <mfspr@plt>
  or     $0x40000,%rax
  mov    %rax,%rsi
  mov    $0x11,%edi
  call   <mtspr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cache_dflush(void) {
  unsigned long sr = mfspr((17));
  mtspr((17), sr | (1 << 18));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cache_dflush>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <mfspr@plt>
  mov    $0x11,%edi
  add    $0x8,%rsp
  or     $0x40000,%rax
  mov    %rax,%rsi
  jmp    1070 <mtspr@plt>
```

assistant: ```c
void cache_dflush(void) {
  unsigned long sr = mfspr((17));
  mtspr((17), sr | (1 << 18));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cache_dflush>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <mfspr@plt>
  mov    $0x11,%edi
  add    $0x8,%rsp
  or     $0x40000,%rax
  mov    %rax,%rsi
  jmp    1070 <mtspr@plt>
```

assistant: ```c
void cache_dflush(void) {
  unsigned long sr = mfspr((17));
  mtspr((17), sr | (1 << 18));
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_147_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_147_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_147_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_147_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_147_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_147_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_147_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_147_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & D;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ustrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L24
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L32
  mov    -0x18(%rbp),%rax
  jmp    L1
L32:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
char *ustrstr(const char *pcHaystack, const char *pcNeedle) {
  unsigned long ulLength;
  ulLength = strlen(pcNeedle);
  while (*pcHaystack) {
    if (strncmp(pcNeedle, pcHaystack, ulLength) == 0) {
      return ((char *)pcHaystack);
    }
    pcHaystack++;
  }
  return ((char *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ustrstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  cmpb   $0x0,(%rbx)
  je     L33
L35:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L35
  mov    $0x0,%eax
  jmp    L27
L33:
  mov    $0x0,%eax
  jmp    L27
L16:
  mov    %rbx,%rax
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ustrstr(const char *pcHaystack, const char *pcNeedle) {
  unsigned long ulLength;
  ulLength = strlen(pcNeedle);
  while (*pcHaystack) {
    if (strncmp(pcNeedle, pcHaystack, ulLength) == 0) {
      return ((char *)pcHaystack);
    }
    pcHaystack++;
  }
  return ((char *)0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ustrstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L39
  mov    %rax,%r12
  jmp    L19
L35:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L39
L19:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L35
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ustrstr(const char *pcHaystack, const char *pcNeedle) {
  unsigned long ulLength;
  ulLength = strlen(pcNeedle);
  while (*pcHaystack) {
    if (strncmp(pcNeedle, pcHaystack, ulLength) == 0) {
      return ((char *)pcHaystack);
    }
    pcHaystack++;
  }
  return ((char *)0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ustrstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L36
  mov    %rax,%r12
  jmp    L18
L2:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L36
L18:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L36:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ustrstr(const char *pcHaystack, const char *pcNeedle) {
  unsigned long ulLength;
  ulLength = strlen(pcNeedle);
  while (*pcHaystack) {
    if (strncmp(pcNeedle, pcHaystack, ulLength) == 0) {
      return ((char *)pcHaystack);
    }
    pcHaystack++;
  }
  return ((char *)0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1f,-0x40(%rbp)
  movl   $0x1c,-0x3c(%rbp)
  movl   $0x1f,-0x38(%rbp)
  movl   $0x1e,-0x34(%rbp)
  movl   $0x1f,-0x30(%rbp)
  movl   $0x1e,-0x2c(%rbp)
  movl   $0x1f,-0x28(%rbp)
  movl   $0x1f,-0x24(%rbp)
  movl   $0x1e,-0x20(%rbp)
  movl   $0x1f,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L27
L14:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    -0x44(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L27:
  mov    -0x44(%rbp),%eax
  cmp    $0xb,%eax
  jbe    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++)
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1f,(%rsp)
  movl   $0x1c,0x4(%rsp)
  movl   $0x1f,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  movl   $0x1f,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  movl   $0x1f,0x18(%rsp)
  movl   $0x1f,0x1c(%rsp)
  movl   $0x1e,0x20(%rsp)
  movl   $0x1f,0x24(%rsp)
  movl   $0x1e,0x28(%rsp)
  movl   $0x1f,0x2c(%rsp)
  mov    $0x1,%ebx
  lea    D9(%rip),%rbp
L19:
  mov    -0x4(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xd,%rbx
  jne    L19
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++)
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1f,%edx
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1c,0x4(%rsp)
  movabs $0x1e0000001f,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x1f0000001f,%rax
  mov    %rax,0x18(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    (%rsp,%rbx,4),%edx
  add    $0x1,%rbx
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0xc,%rbx
  jne    L3
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++)
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x40,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D13(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  nopl   0x0(%rax)
L16:
  mov    -0x4(%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xd,%rbx
  jne    L16
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: byte[16]
name: retrieve_data
arguments: data_label: D13
datatype: byte[16]
name: retrieve_data
arguments: data_label: D2
datatype: byte[16]

tool: D0: Month %2d has %d days.


tool: {"D6": [0x1f,0x00,0x00,0x00,0x1c,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D13": [0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

tool: {"D2": [0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++)
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mk_list@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {};
  mk_list(&head, a, 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x0,%edx
  call   <mk_list@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {};
  mk_list(&head, a, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <mk_list@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {};
  mk_list(&head, a, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <mk_list@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct ListNode *head = NULL;
  int a[] = {};
  mk_list(&head, a, 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csr1212_check_keyword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L51
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L83
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L63
L83:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L90
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L95
L90:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L68
  mov    $0xffffffff,%eax
  jmp    L85
L63:
  nop
  jmp    L65
L95:
  nop
  jmp    L65
L68:
  nop
L65:
  addq   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    $0x0,%eax
L85:
  pop    %rbp
  ret
```

assistant: ```c
int csr1212_check_keyword(const char *s) {
  for (; *s; s++) {
    if (('A' <= *s) && (*s <= 'Z'))
      continue;
    if (('0' <= *s) && (*s <= '9'))
      continue;
    if (*s == '-')
      continue;
    return -1;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csr1212_check_keyword>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
  movabs $0x3ffffff01ff9,%rdx
  jmp    L25
L9:
  bt     %rax,%rdx
  jae    L46
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L25:
  sub    $0x2d,%eax
  cmp    $0x2d,%al
  jbe    L9
  mov    $0xffffffff,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
L46:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int csr1212_check_keyword(const char *s) {
  for (; *s; s++) {
    if (('A' <= *s) && (*s <= 'Z'))
      continue;
    if (('0' <= *s) && (*s <= '9'))
      continue;
    if (*s == '-')
      continue;
    return -1;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<csr1212_check_keyword>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  movabs $0xffffc000000fe006,%rdx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L36:
  bt     %rax,%rdx
  jb     L17
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L20
L37:
  sub    $0x2d,%eax
  cmp    $0x2d,%al
  jbe    L36
L17:
  mov    $0xffffffff,%eax
  ret
  nop
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int csr1212_check_keyword(const char *s) {
  for (; *s; s++) {
    if (('A' <= *s) && (*s <= 'Z'))
      continue;
    if (('0' <= *s) && (*s <= '9'))
      continue;
    if (*s == '-')
      continue;
    return -1;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<csr1212_check_keyword>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  movabs $0xffffc000000fe006,%rdx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L41:
  bt     %rax,%rdx
  jb     L22
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L9
L42:
  sub    $0x2d,%eax
  cmp    $0x2d,%al
  jbe    L41
L22:
  mov    $0xffffffff,%eax
  ret
  nop
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int csr1212_check_keyword(const char *s) {
  for (; *s; s++) {
    if (('A' <= *s) && (*s <= 'Z'))
      continue;
    if (('0' <= *s) && (*s <= '9'))
      continue;
    if (*s == '-')
      continue;
    return -1;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <getpwuid@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  je     L19
  mov    (%rbx),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L5
L19:
  mov    $0x1,%eax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  register struct passwd *pw;
  register uid_t uid;
  uid = geteuid();
  pw = getpwuid(uid);
  if (pw) {
    printf("%s\n", pw->pw_name);
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    $0x1,%edx
  test   %rax,%rax
  jne    L8
L17:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    (%rax),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  register struct passwd *pw;
  register uid_t uid;
  uid = geteuid();
  pw = getpwuid(uid);
  if (pw) {
    printf("%s\n", pw->pw_name);
    return 0;
  }
  return 1;
}
```