ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bch>:
  endbr64
  mov    %edi,%r10d
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%eax
  sub    %esi,%r10d
  mov    $0x1,%esi
  lea    -0x1(%rdi),%ecx
  mov    %r8d,%edx
  mov    %esi,%edi
  shl    %cl,%edi
  mov    %r10d,%ecx
  shl    %cl,%eax
  lea    -0x1(%r9),%ecx
  shl    %cl,%edx
  lea    -0x1(%r10),%ecx
  shl    %cl,%esi
  cmp    %esi,%edi
  jle    L11
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %eax,%ecx
  xor    %edx,%ecx
  test   %eax,%edi
  cmovne %ecx,%eax
  sar    %edi
  sar    %edx
  cmp    %edi,%esi
  jl     L3
L11:
  ret
```

assistant: ```c
int bch(int totalBits, int dataBits, int data, int gpb) {
  int ecBits = totalBits - dataBits;
  int top = 1 << (totalBits - 1);
  data <<= ecBits;
  gpb <<= (dataBits - 1);
  while (top > 1 << (ecBits - 1)) {
    if ((top & data)) {
      data ^= gpb;
    }
    top >>= 1;
    gpb >>= 1;
  }
  return data;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L41
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <char_pointer_array_swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L44
L22:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L14
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <char_pointer_array_swap@plt>
L14:
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L22
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <char_pointer_array_swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <string_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <string_sort>
  jmp    L49
L41:
  nop
L49:
  leave
  ret
```

assistant: ```c
void string_sort(char *string_pointer_array[], int left, int right) {
  int element, last;
  if (left >= right)
    return;
  char_pointer_array_swap(string_pointer_array, left, (left + right) / 2);
  last = left;
  for (element = left + 1; element <= right; element++)
    if (strcmp(string_pointer_array[element], string_pointer_array[left]) < 0)
      char_pointer_array_swap(string_pointer_array, ++last, element);
  char_pointer_array_swap(string_pointer_array, left, last);
  string_sort(string_pointer_array, left, last - 1);
  string_sort(string_pointer_array, last + 1, right);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L31
  ret
L31:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <char_pointer_array_swap@plt>
  lea    0x1(%r13),%ebx
  cmp    %ebx,%r12d
  jl     L20
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,8),%r15
  movslq %ebx,%rbx
  mov    %r13d,%r14d
  jmp    L47
L53:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L9
L47:
  mov    %ebx,0xc(%rsp)
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    (%r15),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L53
  add    $0x1,%r14d
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <char_pointer_array_swap@plt>
  jmp    L53
L20:
  mov    %r13d,%r14d
L9:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <char_pointer_array_swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <string_sort>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <string_sort>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void string_sort(char *string_pointer_array[], int left, int right) {
  int element, last;
  if (left >= right)
    return;
  char_pointer_array_swap(string_pointer_array, left, (left + right) / 2);
  last = left;
  for (element = left + 1; element <= right; element++)
    if (strcmp(string_pointer_array[element], string_pointer_array[left]) < 0)
      char_pointer_array_swap(string_pointer_array, ++last, element);
  char_pointer_array_swap(string_pointer_array, left, last);
  string_sort(string_pointer_array, left, last - 1);
  string_sort(string_pointer_array, last + 1, right);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L30:
  cmp    %r14d,%ebp
  jle    L71
L18:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <char_pointer_array_swap@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L42
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L1
  nopl   0x0(%rax)
L16:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L51
L1:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L16
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <char_pointer_array_swap@plt>
  cmp    %r15d,%ebp
  jge    L1
L51:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <char_pointer_array_swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <string_sort>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jl     L18
L71:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <char_pointer_array_swap@plt>
  jmp    L30
```

assistant: ```c
void string_sort(char *string_pointer_array[], int left, int right) {
  int element, last;
  if (left >= right)
    return;
  char_pointer_array_swap(string_pointer_array, left, (left + right) / 2);
  last = left;
  for (element = left + 1; element <= right; element++)
    if (strcmp(string_pointer_array[element], string_pointer_array[left]) < 0)
      char_pointer_array_swap(string_pointer_array, ++last, element);
  char_pointer_array_swap(string_pointer_array, left, last);
  string_sort(string_pointer_array, left, last - 1);
  string_sort(string_pointer_array, last + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<string_sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L67:
  cmp    %r14d,%ebp
  jle    L19
L16:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <char_pointer_array_swap@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L4
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L1
  nopl   0x0(%rax)
L14:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L54
L1:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L14
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <char_pointer_array_swap@plt>
  cmp    %r15d,%ebp
  jge    L1
L54:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <char_pointer_array_swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <string_sort>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jl     L16
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <char_pointer_array_swap@plt>
  jmp    L67
```

assistant: ```c
void string_sort(char *string_pointer_array[], int left, int right) {
  int element, last;
  if (left >= right)
    return;
  char_pointer_array_swap(string_pointer_array, left, (left + right) / 2);
  last = left;
  for (element = left + 1; element <= right; element++)
    if (strcmp(string_pointer_array[element], string_pointer_array[left]) < 0)
      char_pointer_array_swap(string_pointer_array, ++last, element);
  char_pointer_array_swap(string_pointer_array, left, last);
  string_sort(string_pointer_array, left, last - 1);
  string_sort(string_pointer_array, last + 1, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_tmp_log_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x0,%eax
  call   <get_asf_tmp_dir@plt>
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x14,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <MALLOC@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r9d
  mov    %rsi,%r8
  mov    $0x2f,%ecx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: %s%c%s%i.log

assistant: ```c
const char *get_tmp_log_file(char *tool) {
  char *tmpDir = get_asf_tmp_dir();
  char *tmpLog = (char *)MALLOC(sizeof(char) * (strlen(tmpDir) + strlen(tool) + 20));
  sprintf(tmpLog, "%s%c%s%i.log", tmpDir, '/', tool, (int)getpid());
  return tmpLog;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_tmp_log_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%eax
  call   <get_asf_tmp_dir@plt>
  movslq %eax,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x14(%rbx,%rax,1),%rdi
  mov    $0x0,%eax
  call   <MALLOC@plt>
  movslq %eax,%rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%r9d
  mov    %r12,%r8
  mov    $0x2f,%ecx
  mov    %rbp,%rdx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s%c%s%i.log

assistant: ```c
const char *get_tmp_log_file(char *tool) {
  char *tmpDir = get_asf_tmp_dir();
  char *tmpLog = (char *)MALLOC(sizeof(char) * (strlen(tmpDir) + strlen(tool) + 20));
  sprintf(tmpLog, "%s%c%s%i.log", tmpDir, '/', tool, (int)getpid());
  return tmpLog;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_tmp_log_file>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  call   <get_asf_tmp_dir@plt>
  movslq %eax,%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x14(%r12,%rax,1),%rdi
  xor    %eax,%eax
  call   <MALLOC@plt>
  movslq %eax,%r12
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    %eax,%r9d
  mov    $0x2f,%ecx
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: %s%c%s%i.log

assistant: ```c
const char *get_tmp_log_file(char *tool) {
  char *tmpDir = get_asf_tmp_dir();
  char *tmpLog = (char *)MALLOC(sizeof(char) * (strlen(tmpDir) + strlen(tool) + 20));
  sprintf(tmpLog, "%s%c%s%i.log", tmpDir, '/', tool, (int)getpid());
  return tmpLog;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_tmp_log_file>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  call   <get_asf_tmp_dir@plt>
  movslq %eax,%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x14(%r12,%rax,1),%rdi
  xor    %eax,%eax
  call   <MALLOC@plt>
  movslq %eax,%r12
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    %eax,%r9d
  mov    $0x2f,%ecx
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: %s%c%s%i.log

assistant: ```c
const char *get_tmp_log_file(char *tool) {
  char *tmpDir = get_asf_tmp_dir();
  char *tmpLog = (char *)MALLOC(sizeof(char) * (strlen(tmpDir) + strlen(tool) + 20));
  sprintf(tmpLog, "%s%c%s%i.log", tmpDir, '/', tool, (int)getpid());
  return tmpLog;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipaddr_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <deduplicate_strings@plt>
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x2c,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <join_strings@plt>
  leave
  ret
```

assistant: ```c
char *ipaddr_string(const char **addrs, size_t addrs_len) {
  deduplicate_strings(addrs, addrs_len);
  return join_strings(addrs, addrs_len, ',');
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipaddr_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <deduplicate_strings@plt>
  mov    $0x2c,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <join_strings@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *ipaddr_string(const char **addrs, size_t addrs_len) {
  deduplicate_strings(addrs, addrs_len);
  return join_strings(addrs, addrs_len, ',');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipaddr_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <deduplicate_strings@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x2c,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <join_strings@plt>
```

assistant: ```c
char *ipaddr_string(const char **addrs, size_t addrs_len) {
  deduplicate_strings(addrs, addrs_len);
  return join_strings(addrs, addrs_len, ',');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ipaddr_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <deduplicate_strings@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x2c,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <join_strings@plt>
```

assistant: ```c
char *ipaddr_string(const char **addrs, size_t addrs_len) {
  deduplicate_strings(addrs, addrs_len);
  return join_strings(addrs, addrs_len, ',');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hc05_enter_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7f008164,%eax
  mov    (%rax),%eax
  mov    $0x7f008164,%edx
  or     $0x1,%ah
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hc05_enter_at(void) {
  (*(volatile unsigned int *)(0x7F008164)) |= 0x100;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hc05_enter_at>:
  endbr64
  mov    0x7f008164,%eax
  or     $0x1,%ah
  mov    %eax,0x7f008164
  ret
```

assistant: ```c
void hc05_enter_at(void) {
  (*(volatile unsigned int *)(0x7F008164)) |= 0x100;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<hc05_enter_at>:
  endbr64
  mov    0x7f008164,%eax
  or     $0x1,%ah
  mov    %eax,0x7f008164
  ret
```

assistant: ```c
void hc05_enter_at(void) {
  (*(volatile unsigned int *)(0x7F008164)) |= 0x100;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hc05_enter_at>:
  endbr64
  mov    0x7f008164,%eax
  or     $0x1,%ah
  mov    %eax,0x7f008164
  ret
```

assistant: ```c
void hc05_enter_at(void) {
  (*(volatile unsigned int *)(0x7F008164)) |= 0x100;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <test@plt>
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0xa,%edi
  call   <test@plt>
  mov    $0x19,%edi
  call   <test@plt>
  mov    $0x6bcc41e9,%edi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test(0);
  test(5);
  test(10);
  test(25);
  test(1808548329);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <test@plt>
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0xa,%edi
  call   <test@plt>
  mov    $0x19,%edi
  call   <test@plt>
  mov    $0x6bcc41e9,%edi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(0);
  test(5);
  test(10);
  test(25);
  test(1808548329);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <test@plt>
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0xa,%edi
  call   <test@plt>
  mov    $0x19,%edi
  call   <test@plt>
  mov    $0x6bcc41e9,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(0);
  test(5);
  test(10);
  test(25);
  test(1808548329);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <test@plt>
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0xa,%edi
  call   <test@plt>
  mov    $0x19,%edi
  call   <test@plt>
  mov    $0x6bcc41e9,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(0);
  test(5);
  test(10);
  test(25);
  test(1808548329);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D0: %d

tool: D9: Hello World %d 


assistant: ```c
int main() {
  int i;
  scanf("%d", &i);
  printf("Hello World %d \n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D15
type_infered: string

tool: D18: %d

tool: D15: Hello World %d 


assistant: ```c
int main() {
  int i;
  scanf("%d", &i);
  printf("Hello World %d \n", i);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D8: %d

tool: D3: Hello World %d 


assistant: ```c
int main() {
  int i;
  scanf("%d", &i);
  printf("Hello World %d \n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string

tool: D12: %d

tool: D17: Hello World %d 


assistant: ```c
int main() {
  int i;
  scanf("%d", &i);
  printf("Hello World %d \n", i);
  return 0;
}
```