ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1b000(%rsp),%r11
L172:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L172
  sub    $0x788,%rsp
  mov    $0x1b76c,%edx
  xor    %esi,%esi
  mov    $0xc,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b778(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <memset@plt>
L177:
  mov    %ebp,%edi
  call   <sum_of_proper_divisors@plt>
  cmp    %ebp,%eax
  jle    L101
  cmp    $0x6ddb,%eax
  jg     L101
  movl   $0x1,(%rbx,%rbp,4)
L101:
  add    $0x1,%rbp
  cmp    $0x6ddc,%rbp
  jne    L177
  mov    $0x6dda,%eax
  jmp    L58
L21:
  sub    $0x1,%rax
  jb     L149
L58:
  cmpl   $0x1,(%rbx,%rax,4)
  mov    %eax,%r10d
  jne    L21
L45:
  mov    $0x1,%esi
  lea    0x4(%rsp),%r8
  mov    $0x1,%edi
  xor    %r9d,%r9d
  sub    %r10d,%esi
  nopl   (%rax)
L76:
  mov    %rbx,%rdx
  mov    %edi,%eax
  mov    %r8,%rcx
  test   %r10d,%r10d
  jne    L127
  jmp    L152
  nopw   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%eax
  add    $0x4,%rdx
  sub    $0x4,%rcx
  cmp    %esi,%eax
  je     L152
L127:
  cmpl   $0x1,(%rdx)
  jne    L4
  test   %eax,%eax
  je     L152
  js     L4
  cmpl   $0x1,(%rcx)
  jne    L4
  nop
L106:
  add    $0x1,%edi
  add    $0x1,%esi
  add    $0x4,%r8
  cmp    $0x6ddb,%edi
  jne    L76
  mov    %r9d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x1b778(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x1b788,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L152:
  add    %edi,%r9d
  jmp    L106
L149:
  mov    $0x6ddb,%r10d
  jmp    L45
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9: %i

assistant: ```c
int main(int argc, char *argv[]) {
  int abundants[28123];
  memset(abundants, 0, sizeof(int) * 28123);
  for (int i = 12; i <= 28123; i++) {
    int sum = sum_of_proper_divisors(i);
    if (i < sum && sum <= 28123) {
      abundants[i] = 1;
    }
  }
  int last_abundant = 28123;
  for (int i = 28123 - 1; i >= 0; i--) {
    if (abundants[i] == 1) {
      last_abundant = i;
      break;
    }
  }
  int sum = 0;
  for (int i = 1; i < 28123; i++) {
    for (int e = 0; e < last_abundant; e++) {
      if (abundants[e] == 1) {
        int compliment = i - e;
        if (compliment == 0)
          goto found;
        if (compliment < 0)
          continue;
        if (abundants[compliment] == 1) {
          goto not_found;
        }
      }
    }
  found:
    sum += i;
  not_found:;
  }
  printf("%i", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1e8000(%rsp),%r11
L39:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L39
  sub    $0x4b0,%rsp
  mov    %edi,-0x1e84a4(%rbp)
  mov    %rsi,-0x1e84b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1e849c(%rbp)
  movl   $0x0,-0x1e8498(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1e84a0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x1e8494(%rbp)
  jmp    L35
L15:
  lea    -0x1e8490(%rbp),%rdx
  mov    -0x1e8494(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1e8494(%rbp)
L35:
  mov    -0x1e84a0(%rbp),%eax
  cmp    %eax,-0x1e8494(%rbp)
  jl     L15
  mov    -0x1e84a0(%rbp),%eax
  lea    -0x1(%rax),%esi
  lea    -0x1e8498(%rbp),%rcx
  lea    -0x1e849c(%rbp),%rdx
  lea    -0x1e8490(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fnRecMaxMin@plt>
  mov    -0x1e8498(%rbp),%edx
  mov    -0x1e849c(%rbp),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D39
data_type: string
name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D44
data_type: string

tool: D39: 
Enter the size of the array

tool: D4: %d

tool: D19: 
Enter the elements of the array:

tool: D44: 
Max Element = %d
Min Element = %d


assistant: ```c
int main(int argc, char **argv) {
  int iaArr[500000], iNum, i;
  int iMax = 0, iMin = 0;
  printf("\nEnter the size of the array\n");
  scanf("%d", &iNum);
  printf("\nEnter the elements of the array:\n");
  for (i = 0; i < iNum; i++)
    scanf("%d", &iaArr[i]);
  fnRecMaxMin(iaArr, 0, iNum - 1, &iMax, &iMin);
  printf("\nMax Element = %d\nMin Element = %d\n", iMax, iMin);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0x4a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8498(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L22
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D29(%rip),%r12
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L23
L22:
  lea    0x8(%rsp),%rcx
  sub    $0x1,%edx
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%r8
  mov    $0x0,%esi
  call   <fnRecMaxMin@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x1e8498(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x1e84a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D7
type: string

tool: D28: 
Enter the size of the array

tool: D29: %d

tool: D14: 
Enter the elements of the array:

tool: D7: 
Max Element = %d
Min Element = %d


assistant: ```c
int main(int argc, char **argv) {
  int iaArr[500000], iNum, i;
  int iMax = 0, iMin = 0;
  printf("\nEnter the size of the array\n");
  scanf("%d", &iNum);
  printf("\nEnter the elements of the array:\n");
  for (i = 0; i < iNum; i++)
    scanf("%d", &iaArr[i]);
  fnRecMaxMin(iaArr, 0, iNum - 1, &iMax, &iMin);
  printf("\nMax Element = %d\nMin Element = %d\n", iMax, iMin);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0x4a8,%rsp
  lea    D33(%rip),%rdi
  lea    D12(%rip),%r12
  xor    %ebx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8498(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rbp
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L12
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L8
L12:
  sub    $0x1,%edx
  xor    %esi,%esi
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdi
  lea    0xc(%rsp),%r8
  call   <fnRecMaxMin@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x1e8498(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x1e84a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D33
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D33: 
Enter the size of the array

tool: D12: %d

tool: D20: 
Enter the elements of the array:

tool: D6: 
Max Element = %d
Min Element = %d


assistant: ```c
int main(int argc, char **argv) {
  int iaArr[500000], iNum, i;
  int iMax = 0, iMin = 0;
  printf("\nEnter the size of the array\n");
  scanf("%d", &iNum);
  printf("\nEnter the elements of the array:\n");
  for (i = 0; i < iNum; i++)
    scanf("%d", &iaArr[i]);
  fnRecMaxMin(iaArr, 0, iNum - 1, &iMax, &iMin);
  printf("\nMax Element = %d\nMin Element = %d\n", iMax, iMin);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x4a8,%rsp
  lea    D1(%rip),%rdi
  lea    D9(%rip),%r12
  xor    %ebx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8498(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rbp
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L16
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L34
L16:
  sub    $0x1,%edx
  xor    %esi,%esi
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdi
  lea    0xc(%rsp),%r8
  call   <fnRecMaxMin@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x1e8498(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x1e84a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D21
datatype: string

tool: D1: 
Enter the size of the array

tool: D9: %d

tool: D10: 
Enter the elements of the array:

tool: D21: 
Max Element = %d
Min Element = %d


assistant: ```c
int main(int argc, char **argv) {
  int iaArr[500000], iNum, i;
  int iMax = 0, iMin = 0;
  printf("\nEnter the size of the array\n");
  scanf("%d", &iNum);
  printf("\nEnter the elements of the array:\n");
  for (i = 0; i < iNum; i++)
    scanf("%d", &iaArr[i]);
  fnRecMaxMin(iaArr, 0, iNum - 1, &iMax, &iMin);
  printf("\nMax Element = %d\nMin Element = %d\n", iMax, iMin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,-0x68(%rbp)
  movl   $0x0,-0x60(%rbp)
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x1,-0x54(%rbp)
  movl   $0x2,-0x50(%rbp)
  movl   $0x3,-0x4c(%rbp)
  movl   $0x4,-0x48(%rbp)
  movl   $0x5,-0x44(%rbp)
  movl   $0x6,-0x40(%rbp)
  movl   $0x7,-0x3c(%rbp)
  movl   $0x8,-0x38(%rbp)
  movl   $0x9,-0x34(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0xd,-0x24(%rbp)
  movl   $0xe,-0x20(%rbp)
  movl   $0xf,-0x1c(%rbp)
  movl   $0xf,-0x18(%rbp)
  movl   $0xf,-0x14(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <check_inpos@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string

tool: D9: user@example.com

tool: D16: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str1 = "user@example.com";
  const int expected_inpos[] = {0, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 15, 15};
  return check_inpos("compress.cti,en-us-g2.ctb", str1, expected_inpos);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x4,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  movl   $0x8,0x28(%rsp)
  movl   $0x9,0x2c(%rsp)
  movl   $0xa,0x30(%rsp)
  movl   $0xb,0x34(%rsp)
  movl   $0xc,0x38(%rsp)
  movl   $0xd,0x3c(%rsp)
  movl   $0xe,0x40(%rsp)
  movl   $0xf,0x44(%rsp)
  movl   $0xf,0x48(%rsp)
  movl   $0xf,0x4c(%rsp)
  mov    %rsp,%rdx
  lea    D19(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <check_inpos@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x68,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D19: user@example.com

tool: D1: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str1 = "user@example.com";
  const int expected_inpos[] = {0, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 15, 15};
  return check_inpos("compress.cti,en-us-g2.ctb", str1, expected_inpos);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  lea    D16(%rip),%rsi
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  movq   $0x0,(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xb0000000a,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xd0000000c,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xf0000000e,%rax
  mov    %rax,0x40(%rsp)
  add    $0x1,%rax
  mov    %rax,0x48(%rsp)
  call   <check_inpos@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x68,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string

tool: D16: user@example.com

tool: D14: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str1 = "user@example.com";
  const int expected_inpos[] = {0, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 15, 15};
  return check_inpos("compress.cti,en-us-g2.ctb", str1, expected_inpos);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  movdqa D60(%rip),%xmm0
  lea    D5(%rip),%rsi
  lea    D64(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D68(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D17(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <check_inpos@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x68,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D60
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D64
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D68
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D7
type_infered: byte[16]

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D5: user@example.com

tool: D64: compress.cti,en-us-g2.ctb

tool: {"D23": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D68": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D17": [0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D7": [0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  const char *str1 = "user@example.com";
  const int expected_inpos[] = {0, 0, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 15, 15};
  return check_inpos("compress.cti,en-us-g2.ctb", str1, expected_inpos);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scrnextup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <nextwind@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <backpage@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <prevwind@plt>
  nop
  leave
  ret
```

assistant: ```c
scrnextup(f, n) int f, n;
{
  nextwind(0, 1);
  backpage(f, n);
  prevwind(0, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scrnextup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <nextwind@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <backpage@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <prevwind@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
scrnextup(f, n) int f, n;
{
  nextwind(0, 1);
  backpage(f, n);
  prevwind(0, 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scrnextup>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  mov    $0x1,%esi
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <nextwind@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <backpage@plt>
  add    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1070 <prevwind@plt>
```

assistant: ```c
scrnextup(f, n) int f, n;
{
  nextwind(0, 1);
  backpage(f, n);
  prevwind(0, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<scrnextup>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  mov    $0x1,%esi
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <nextwind@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <backpage@plt>
  add    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1070 <prevwind@plt>
```

assistant: ```c
scrnextup(f, n) int f, n;
{
  nextwind(0, 1);
  backpage(f, n);
  prevwind(0, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fun_coverage_if_neq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  je     L18
  mov    $0x8,%eax
  jmp    L5
L18:
  mov    $0x12,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int fun_coverage_if_neq(int x) {
  if (x != 5) {
    return 8;
  } else {
    return 18;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fun_coverage_if_neq>:
  endbr64
  cmp    $0x5,%edi
  mov    $0x8,%eax
  mov    $0x12,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int fun_coverage_if_neq(int x) {
  if (x != 5) {
    return 8;
  } else {
    return 18;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fun_coverage_if_neq>:
  endbr64
  cmp    $0x5,%edi
  mov    $0x12,%edx
  mov    $0x8,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int fun_coverage_if_neq(int x) {
  if (x != 5) {
    return 8;
  } else {
    return 18;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fun_coverage_if_neq>:
  endbr64
  cmp    $0x5,%edi
  mov    $0x12,%edx
  mov    $0x8,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int fun_coverage_if_neq(int x) {
  if (x != 5) {
    return 8;
  } else {
    return 18;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SetWatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D44(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x1,%eax
  jmp    L10
L28:
  mov    -0x8(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x2,%eax
  jmp    L10
L32:
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L109
  mov    $0x2,%eax
  jmp    L10
L109:
  mov    -0x8(%rbp),%rax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L73
  mov    $0x1,%eax
  jmp    L10
L73:
  mov    -0x8(%rbp),%rax
  lea    D43(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
  mov    $0x2,%eax
  jmp    L10
L48:
  mov    -0x8(%rbp),%rax
  lea    D45(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  mov    $0x2,%eax
  jmp    L10
L39:
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D44
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D55
type_guessed: string
name: retrieve_data
arguments: tag: D43
type_guessed: string
name: retrieve_data
arguments: tag: D45
type_guessed: string

tool: D44: printf

tool: D13: fprintf

tool: D6: sprintf

tool: D55: vprintf

tool: D43: vfprintf

tool: D45: vsprintf

assistant: ```c
int SetWatch(char *sym) {
  if (strcmp(sym, "printf") == 0)
    return 1;
  if (strcmp(sym, "fprintf") == 0)
    return 2;
  if (strcmp(sym, "sprintf") == 0)
    return 2;
  if (strcmp(sym, "vprintf") == 0)
    return 1;
  if (strcmp(sym, "vfprintf") == 0)
    return 2;
  if (strcmp(sym, "vsprintf") == 0)
    return 2;
  return 0;
}
```