ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<l4_widened_overrun_Bad>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  jmp    L14
  nopl   0x0(%rax)
L1:
  add    $0x1,%ebx
L14:
  mov    $0xb,%esi
  mov    %ebx,%edi
  call   <less_than@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void l4_widened_overrun_Bad() {
  int a[10];
  for (int i = 0; less_than(i, 11); i++) {
    a[i] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<l4_widened_overrun_Bad>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  jmp    L0
  nopl   0x0(%rax)
L8:
  add    $0x1,%ebx
L0:
  mov    $0xb,%esi
  mov    %ebx,%edi
  call   <less_than@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void l4_widened_overrun_Bad() {
  int a[10];
  for (int i = 0; less_than(i, 11); i++) {
    a[i] = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<StrMaxCpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  lea    D6(%rip),%rax
  jmp    L36
L11:
  cmpq   $0x1,-0x18(%rbp)
  jne    L33
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L36
L33:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  ja     L46
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L46:
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: 

assistant: ```c
char *StrMaxCpy(char *dst, const char *src, size_t maxLen) {
  if (maxLen < 1) {
    return "";
  }
  if (maxLen == 1) {
    dst[0] = '\0';
    return dst;
  }
  strncpy(dst, src, maxLen - 1);
  if ((strlen(src) + 1) >= maxLen) {
    dst[maxLen - 1] = '\0';
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<StrMaxCpy>:
  endbr64
  lea    D6(%rip),%rax
  test   %rdx,%rdx
  je     L37
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  cmp    $0x1,%rdx
  je     L23
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  mov    %rbp,%rax
  cmp    %rbx,%rdx
  jb     L9
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L9
L23:
  movb   $0x0,(%rdi)
  mov    %rdi,%rax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: 

assistant: ```c
char *StrMaxCpy(char *dst, const char *src, size_t maxLen) {
  if (maxLen < 1) {
    return "";
  }
  if (maxLen == 1) {
    dst[0] = '\0';
    return dst;
  }
  strncpy(dst, src, maxLen - 1);
  if ((strlen(src) + 1) >= maxLen) {
    dst[maxLen - 1] = '\0';
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StrMaxCpy>:
  endbr64
  lea    D4(%rip),%rax
  test   %rdx,%rdx
  je     L5
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x1,%rdx
  je     L8
  mov    %rsi,%r12
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    %rbp,%rax
  movslq %edx,%rdx
  cmp    %rbx,%rdx
  jb     L10
  movb   $0x0,-0x1(%rbp,%rbx,1)
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  movb   $0x0,(%rdi)
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: 

assistant: ```c
char *StrMaxCpy(char *dst, const char *src, size_t maxLen) {
  if (maxLen < 1) {
    return "";
  }
  if (maxLen == 1) {
    dst[0] = '\0';
    return dst;
  }
  strncpy(dst, src, maxLen - 1);
  if ((strlen(src) + 1) >= maxLen) {
    dst[maxLen - 1] = '\0';
  }
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<StrMaxCpy>:
  endbr64
  lea    D1(%rip),%rax
  test   %rdx,%rdx
  je     L9
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x1,%rdx
  je     L6
  mov    %rsi,%r12
  lea    -0x1(%rdx),%rdx
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    %rbp,%rax
  movslq %edx,%rdx
  cmp    %rbx,%rdx
  jb     L5
  movb   $0x0,-0x1(%rbp,%rbx,1)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  movb   $0x0,(%rdi)
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: 

assistant: ```c
char *StrMaxCpy(char *dst, const char *src, size_t maxLen) {
  if (maxLen < 1) {
    return "";
  }
  if (maxLen == 1) {
    dst[0] = '\0';
    return dst;
  }
  strncpy(dst, src, maxLen - 1);
  if ((strlen(src) + 1) >= maxLen) {
    dst[maxLen - 1] = '\0';
  }
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<number2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L0:
  mov    $0x7,%eax
  sub    -0x24(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x3c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x24(%rbp)
L11:
  cmpl   $0x7,-0x24(%rbp)
  jle    L0
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
void number2hex(char *s, uint32_t id) {
  char hex[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  uint32_t i;
  for (i = 0; i < 8; i++) {
    s[i] = hex[(id >> (28 - 4 * i)) & 0xf];
  }
  s[8] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<number2hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rdi,%rdx
  mov    $0x1c,%ecx
L2:
  mov    %esi,%eax
  sar    %cl,%eax
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,(%rdx)
  sub    $0x4,%ecx
  add    $0x1,%rdx
  cmp    $0xfffffffc,%ecx
  jne    L2
  movb   $0x0,0x8(%rdi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void number2hex(char *s, uint32_t id) {
  char hex[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  uint32_t i;
  for (i = 0; i < 8; i++) {
    s[i] = hex[(id >> (28 - 4 * i)) & 0xf];
  }
  s[8] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<number2hex>:
  endbr64
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    %rdi,%rdx
  mov    $0x1c,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax)
L17:
  mov    %esi,%eax
  add    $0x1,%rdx
  sar    %cl,%eax
  sub    $0x4,%ecx
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    $0xfffffffc,%ecx
  jne    L17
  movb   $0x0,0x8(%rdi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: byte[16]

tool: {"D2": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void number2hex(char *s, uint32_t id) {
  char hex[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  uint32_t i;
  for (i = 0; i < 8; i++) {
    s[i] = hex[(id >> (28 - 4 * i)) & 0xf];
  }
  s[8] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<number2hex>:
  endbr64
  mov    %esi,%eax
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  mov    %rdi,%rdx
  mov    %eax,%r11d
  mov    %eax,%edi
  mov    %eax,%r8d
  mov    %eax,%r9d
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  mov    %eax,%r10d
  sar    $0x4,%r11d
  and    $0xf,%eax
  movaps %xmm0,(%rsp)
  and    $0xf,%r11d
  movzbl (%rsp,%rax,1),%eax
  sar    $0x8,%r10d
  movzbl (%rsp,%r11,1),%r11d
  and    $0xf,%r10d
  sar    $0xc,%r9d
  mov    %esi,%ecx
  shl    $0x8,%rax
  movzbl (%rsp,%r10,1),%r10d
  and    $0xf,%r9d
  sar    $0x14,%edi
  or     %r11,%rax
  movzbl (%rsp,%r9,1),%r9d
  sar    $0x10,%r8d
  and    $0xf,%edi
  shl    $0x8,%rax
  and    $0xf,%r8d
  movzbl (%rsp,%rdi,1),%edi
  sar    $0x18,%esi
  or     %r10,%rax
  movzbl (%rsp,%r8,1),%r8d
  and    $0xf,%esi
  shr    $0x1c,%ecx
  shl    $0x8,%rax
  movzbl (%rsp,%rsi,1),%esi
  movzbl (%rsp,%rcx,1),%ecx
  movb   $0x0,0x8(%rdx)
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rdi,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: byte[16]

tool: {"D7": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void number2hex(char *s, uint32_t id) {
  char hex[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  uint32_t i;
  for (i = 0; i < 8; i++) {
    s[i] = hex[(id >> (28 - 4 * i)) & 0xf];
  }
  s[8] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sendall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L53
L35:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L26
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L53:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L35
  jmp    L16
L26:
  nop
L16:
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L11
L0:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int sendall(int s, const char *buf, int *len) {
  int total = 0;
  int bytesleft = *len;
  int n;
  while (total < *len) {
    n = send(s, buf + total, bytesleft, 0);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *len = total;
  return n == -1 ? -1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendall>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    (%rdx),%ebp
  test   %ebp,%ebp
  jle    L5
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    $0x0,%ebx
L9:
  movslq %ebx,%rsi
  add    %r14,%rsi
  mov    $0x0,%ecx
  mov    %ebp,%edx
  mov    %r13d,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L32
  add    %eax,%ebx
  sub    %eax,%ebp
  cmp    %ebx,(%r12)
  jg     L9
L32:
  mov    %ebx,(%r12)
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    $0x0,%ebx
  jmp    L32
```

assistant: ```c
int sendall(int s, const char *buf, int *len) {
  int total = 0;
  int bytesleft = *len;
  int n;
  while (total < *len) {
    n = send(s, buf + total, bytesleft, 0);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *len = total;
  return n == -1 ? -1 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sendall>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rdx),%r14d
  test   %r14d,%r14d
  jle    L20
  mov    %edi,%r12d
  mov    %rsi,%r13
  xor    %ebx,%ebx
  jmp    L13
  nopl   0x0(%rax)
L9:
  add    %eax,%ebx
  sub    %eax,%r14d
  cmp    %ebx,0x0(%rbp)
  jle    L8
L13:
  movslq %ebx,%rsi
  xor    %ecx,%ecx
  mov    %r14d,%edx
  mov    %r12d,%edi
  add    %r13,%rsi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  xor    %ebx,%ebx
L8:
  mov    %ebx,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int sendall(int s, const char *buf, int *len) {
  int total = 0;
  int bytesleft = *len;
  int n;
  while (total < *len) {
    n = send(s, buf + total, bytesleft, 0);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *len = total;
  return n == -1 ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sendall>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rdx),%r14d
  test   %r14d,%r14d
  jle    L21
  mov    %edi,%r12d
  mov    %rsi,%r13
  xor    %ebx,%ebx
  jmp    L38
  nopl   0x0(%rax)
L20:
  add    %eax,%ebx
  sub    %eax,%r14d
  cmp    %ebx,0x0(%rbp)
  jle    L24
L38:
  movslq %ebx,%rsi
  xor    %ecx,%ecx
  mov    %r14d,%edx
  mov    %r12d,%edi
  add    %r13,%rsi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L20
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  xor    %ebx,%ebx
L24:
  mov    %ebx,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int sendall(int s, const char *buf, int *len) {
  int total = 0;
  int bytesleft = *len;
  int n;
  while (total < *len) {
    n = send(s, buf + total, bytesleft, 0);
    if (n == -1) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *len = total;
  return n == -1 ? -1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x3f0,%rsp
  mov    %edi,-0x3e4(%rbp)
  mov    %rsi,-0x3f0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D59(%rip),%xmm0
  movsd  %xmm0,-0x3d0(%rbp)
  movsd  D83(%rip),%xmm0
  movsd  %xmm0,-0x3c8(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x3c0(%rbp)
  movsd  D50(%rip),%xmm0
  movsd  %xmm0,-0x3b8(%rbp)
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,-0x3b0(%rbp)
  movsd  D31(%rip),%xmm0
  movsd  %xmm0,-0x3a8(%rbp)
  movsd  D45(%rip),%xmm0
  movsd  %xmm0,-0x3a0(%rbp)
  movsd  D72(%rip),%xmm0
  movsd  %xmm0,-0x398(%rbp)
  movsd  D85(%rip),%xmm0
  movsd  %xmm0,-0x390(%rbp)
  movl   $0x3,-0x3d8(%rbp)
  movl   $0x2,-0x3d4(%rbp)
  mov    -0x3d4(%rbp),%edx
  mov    -0x3d8(%rbp),%ecx
  lea    -0x3d0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <pm@plt>
  mov    -0x3d4(%rbp),%edi
  lea    -0x330(%rbp),%rcx
  mov    -0x3d8(%rbp),%edx
  lea    -0x3d0(%rbp),%rsi
  lea    -0x380(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <svdu1v@plt>
  lea    -0x380(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <pm@plt>
  mov    -0x3d4(%rbp),%edx
  mov    -0x3d4(%rbp),%ecx
  lea    -0x330(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <pm@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D59
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D83
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D10
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D50
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D3
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D31
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D45
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D72
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D85
type: byte[8]

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D83": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D72": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D85": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
int main(int argc, char **argv) {
  double ma[9] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  double ou[100];
  double d[9];
  double ov[100];
  int m, n;
  m = 3;
  n = 2;
  pm(ma, m, n);
  svdu1v(d, ma, m, ov, n);
  pm(d, 1, 5);
  pm(ov, n, n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3c8(%rsp)
  xor    %eax,%eax
  mov    D39(%rip),%rax
  mov    %rax,(%rsp)
  mov    D14(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D41(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D21(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D66(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D45(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D44(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D34(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D54(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    %rsp,%r12
  mov    $0x2,%edx
  mov    $0x3,%esi
  mov    %r12,%rdi
  call   <pm@plt>
  lea    0xa0(%rsp),%rbx
  lea    0x50(%rsp),%rbp
  mov    $0x2,%r8d
  mov    %rbx,%rcx
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <svdu1v@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <pm@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <pm@plt>
  mov    0x3c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x3d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D14
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D41
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D21
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D66
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D45
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D44
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D34
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D54
type_guessed: byte[8]

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D66": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D54": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
int main(int argc, char **argv) {
  double ma[9] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  double ou[100];
  double d[9];
  double ov[100];
  int m, n;
  m = 3;
  n = 2;
  pm(ma, m, n);
  svdu1v(d, ma, m, ov, n);
  pm(d, 1, 5);
  pm(ov, n, n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2,%edx
  mov    $0x3,%esi
  push   %r12
  push   %rbp
  sub    $0x3d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3c8(%rsp)
  xor    %eax,%eax
  mov    D34(%rip),%rax
  mov    %rsp,%r13
  lea    0xa0(%rsp),%rbp
  mov    %r13,%rdi
  lea    0x50(%rsp),%r12
  mov    %rax,(%rsp)
  mov    D61(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D89(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D55(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D85(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D35(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D42(%rip),%rax
  mov    %rax,0x40(%rsp)
  call   <pm@plt>
  mov    %rbp,%rcx
  mov    $0x3,%edx
  mov    %r13,%rsi
  mov    $0x2,%r8d
  mov    %r12,%rdi
  call   <svdu1v@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <pm@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <pm@plt>
  mov    0x3c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x3d0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D34
data_type: byte[8]
name: parse_data
arguments: tag: D61
data_type: byte[8]
name: parse_data
arguments: tag: D23
data_type: byte[8]
name: parse_data
arguments: tag: D89
data_type: byte[8]
name: parse_data
arguments: tag: D55
data_type: byte[8]
name: parse_data
arguments: tag: D25
data_type: byte[8]
name: parse_data
arguments: tag: D85
data_type: byte[8]
name: parse_data
arguments: tag: D35
data_type: byte[8]
name: parse_data
arguments: tag: D42
data_type: byte[8]

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D85": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
int main(int argc, char **argv) {
  double ma[9] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  double ou[100];
  double d[9];
  double ov[100];
  int m, n;
  m = 3;
  n = 2;
  pm(ma, m, n);
  svdu1v(d, ma, m, ov, n);
  pm(d, 1, 5);
  pm(ov, n, n);
  return 0;
}
```