user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    D109(%rip),%r12
  mov    %rsp,%rbp
  lea    D93(%rip),%rbx
L63:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    $0x3e8,%eax
  jg     L63
  test   $0x1,%al
  je     L63
  lea    D76(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D93(%rip),%rbx
L6:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L6
  cmp    (%rsp),%eax
  jg     L6
  lea    D97(%rip),%r12
  lea    0x8(%rsp),%rbp
  lea    D93(%rip),%rbx
L20:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    0x4(%rsp),%eax
  jl     L20
  cmp    (%rsp),%eax
  jg     L20
  lea    D89(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D93(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L75
  lea    0x10(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D71(%rip),%r14
  lea    D93(%rip),%r13
L27:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0x8(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L27
  test   %eax,%eax
  jle    L75
  mov    $0x0,%ebp
  lea    D93(%rip),%r12
L91:
  mov    (%rbx),%esi
  imul   0xc(%rsp),%esi
  mov    %esi,(%rbx)
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,0x8(%rsp)
  jg     L91
L75:
  lea    D100(%rip),%rdi
  mov    $0x0,%eax
  call   <system@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0xfc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D109
data_type: string
name: disassemble_data
arguments: data_tag: D93
data_type: string
name: disassemble_data
arguments: data_tag: D76
data_type: string
name: disassemble_data
arguments: data_tag: D97
data_type: string
name: disassemble_data
arguments: data_tag: D89
data_type: string
name: disassemble_data
arguments: data_tag: D71
data_type: string
name: disassemble_data
arguments: data_tag: D100
data_type: string

tool: D109: Inserisci il valore di N2

tool: D93: %d

tool: D76: Inserisci il valore di N1

tool: D97: Inserisci il valore di K

tool: D89: Inserire lo scalare

tool: D71: Inserire il vettore 

tool: D100: PAUSE

assistant: ```c
main() {
  int N2;
  int N1;
  int K;
  int Num;
  int vett[999];
  int I;
  do {
    printf("Inserisci il valore di N2");
    scanf("%d", &N2);
  } while (N2 > 1000 || N2 % 2 == 0);
  do {
    printf("Inserisci il valore di N1");
    scanf("%d", &N1);
  } while (N1 < 0 || N1 > N2);
  do {
    printf("Inserisci il valore di K"), scanf("%d", &K);
  } while (K < N1 || K > N2);
  printf("Inserire lo scalare");
  scanf("%d", &Num);
  for (I = 0; I < K; I++) {
    printf("Inserire il vettore ");
    scanf("%d", &vett[I]);
  }
  for (I = 0; I < K; I++) {
    vett[I] = vett[I] * Num;
    printf("%d", vett[I]);
  }
  system("PAUSE");
}
```