ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f3(int y, int x) {
  int a = x | y;
  return x & a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f3>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f3(int y, int x) {
  int a = x | y;
  return x & a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f3>:
  endbr64
  mov    %esi,%eax
  ret
```

assistant: ```c
int f3(int y, int x) {
  int a = x | y;
  return x & a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L23:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L37
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L2:
  cmpl   $0x13,-0x8(%rbp)
  jle    L23
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D3: %s:


tool: D4: %d: 

tool: D12: %g 

assistant: ```c
void print_matrix(char *label, double m[256 + 1][20], int len) {
  int b, j;
  printf("%s:\n", label);
  for (b = 0; b < 20; b++) {
    printf("%d: ", b);
    for (j = 0; j < len; j++)
      printf("%g ", m[j][b]);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %edx,%r14d
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%r14),%eax
  lea    (%rax,%rax,4),%rdx
  shl    $0x5,%rdx
  lea    0xa0(%rbx,%rdx,1),%rbp
  mov    $0x0,%r13d
  lea    D17(%rip),%r15
  add    $0x1,%rax
  imul   $0xffffffffffffff60,%rax,%rax
  mov    %rax,0x8(%rsp)
  lea    D13(%rip),%r12
  jmp    L28
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    $0x8,%rbp
  cmp    $0x14,%r13d
  je     L7
L28:
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L9
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbp,1),%rbx
L11:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0xa0,%rbx
  cmp    %rbp,%rbx
  jne    L11
  jmp    L9
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D1: %s:


tool: D17: %d: 

tool: D13: %g 

assistant: ```c
void print_matrix(char *label, double m[256 + 1][20], int len) {
  int b, j;
  printf("%s:\n", label);
  for (b = 0; b < 20; b++) {
    printf("%d: ", b);
    for (j = 0; j < len; j++)
      printf("%g ", m[j][b]);
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_matrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    $0xffffffffffffff60,%r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D25(%rip),%rdi
  sub    $0x18,%rsp
  call   <printf@plt>
  lea    -0x1(%r13),%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  sub    %rax,%r15
  lea    0xa0(%rbx,%rax,1),%rbx
  mov    %r15,0x8(%rsp)
  nopl   (%rax)
L15:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L11
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbx,1),%r15
  nopl   0x0(%rax,%rax,1)
L0:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0xa0,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L0
L11:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    $0x14,%r12d
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string

tool: D4: %d: 

tool: D14: %g 

tool: D25: %s:


assistant: ```c
void print_matrix(char *label, double m[256 + 1][20], int len) {
  int b, j;
  printf("%s:\n", label);
  for (b = 0; b < 20; b++) {
    printf("%d: ", b);
    for (j = 0; j < len; j++)
      printf("%g ", m[j][b]);
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_matrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    $0xffffffffffffff60,%r15
  push   %r14
  lea    D26(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D20(%rip),%rdi
  sub    $0x18,%rsp
  call   <printf@plt>
  lea    -0x1(%r13),%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x5,%rax
  sub    %rax,%r15
  lea    0xa0(%rbx,%rax,1),%rbx
  mov    %r15,0x8(%rsp)
  nopl   (%rax)
L14:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L19
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbx,1),%r15
  nopl   0x0(%rax,%rax,1)
L4:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0xa0,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L4
L19:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    $0x14,%r12d
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string

tool: D26: %d: 

tool: D2: %g 

tool: D20: %s:


assistant: ```c
void print_matrix(char *label, double m[256 + 1][20], int len) {
  int b, j;
  printf("%s:\n", label);
  for (b = 0; b < 20; b++) {
    printf("%d: ", b);
    for (j = 0; j < len; j++)
      printf("%g ", m[j][b]);
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<outdec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L0
  negq   -0x8(%rbp)
  mov    $0x2d,%edi
  call   <outbyte@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <outd2@plt>
  nop
  leave
  ret
```

assistant: ```c
void outdec(long number) {
  if (number < 0) {
    number = -number;
    outbyte('-');
  }
  outd2(number);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<outdec>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  js     L1
L7:
  mov    %rbx,%rdi
  call   <outd2@plt>
  pop    %rbx
  ret
L1:
  neg    %rbx
  mov    $0x2d,%edi
  call   <outbyte@plt>
  jmp    L7
```

assistant: ```c
void outdec(long number) {
  if (number < 0) {
    number = -number;
    outbyte('-');
  }
  outd2(number);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<outdec>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  js     L2
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <outd2@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  neg    %rbp
  mov    $0x2d,%edi
  call   <outbyte@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <outd2@plt>
```

assistant: ```c
void outdec(long number) {
  if (number < 0) {
    number = -number;
    outbyte('-');
  }
  outd2(number);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outdec>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  js     L2
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <outd2@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  neg    %rbp
  mov    $0x2d,%edi
  call   <outbyte@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <outd2@plt>
```

assistant: ```c
void outdec(long number) {
  if (number < 0) {
    number = -number;
    outbyte('-');
  }
  outd2(number);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<confd_ipc_access_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %edi,-0x444(%rbp)
  mov    %rsi,-0x450(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x430(%rbp),%rcx
  mov    -0x444(%rbp),%eax
  mov    $0x11,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_fill@plt>
  mov    %eax,-0x434(%rbp)
  cmpl   $0x11,-0x434(%rbp)
  je     L3
  mov    -0x434(%rbp),%eax
  jmp    L100
L3:
  movzbl -0x430(%rbp),%eax
  cmp    $0xb,%al
  je     L53
  mov    $0x0,%eax
  jmp    L100
L53:
  mov    -0x450(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    $0x3f0,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x434(%rbp)
  lea    -0x410(%rbp),%rdx
  mov    -0x434(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    -0x430(%rbp),%rdx
  lea    0x1(%rdx),%rcx
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x434(%rbp),%eax
  lea    0x10(%rax),%ecx
  lea    -0x430(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x410(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <md5@plt>
  movb   $0xc,-0x430(%rbp)
  lea    -0x430(%rbp),%rcx
  mov    -0x444(%rbp),%eax
  mov    $0x11,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write_fill@plt>
  mov    %eax,-0x434(%rbp)
  cmpl   $0x11,-0x434(%rbp)
  je     L42
  mov    -0x434(%rbp),%eax
  jmp    L100
L42:
  lea    -0x430(%rbp),%rcx
  mov    -0x444(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_fill@plt>
  mov    %eax,-0x434(%rbp)
  cmpl   $0x1,-0x434(%rbp)
  je     L12
  mov    -0x434(%rbp),%eax
  jmp    L100
L12:
  movzbl -0x430(%rbp),%eax
  test   %al,%al
  je     L102
  mov    $0x0,%eax
  jmp    L100
L102:
  mov    $0x1,%eax
L100:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: %s

assistant: ```c
int confd_ipc_access_check(int sock, const unsigned char *secret) {
  unsigned char chall[1 + 16];
  unsigned char buf[1024];
  int n;
  if ((n = read_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if (chall[0] != 11) {
    return 0;
  }
  snprintf((char *)buf, sizeof(buf) - 16, "%s", secret);
  n = strlen((char *)buf);
  memcpy(&buf[n], &chall[1], 16);
  md5(buf, n + 16, &chall[1]);
  chall[0] = 12;
  if ((n = write_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if ((n = read_fill(sock, chall, 1)) != 1) {
    return n;
  }
  if (chall[0] != 0) {
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<confd_ipc_access_check>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x430,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x11,%edx
  call   <read_fill@plt>
  cmp    $0x11,%eax
  jne    L1
  mov    $0x0,%eax
  cmpb   $0xb,(%rsp)
  je     L31
L1:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x430,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  lea    0x20(%rsp),%r12
  mov    %rbp,%rcx
  lea    D0(%rip),%rdx
  mov    $0x3f0,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rsp,%r14
  lea    0x1(%rsp),%r13
  movslq %eax,%rdi
  add    %r12,%rdi
  mov    $0x10,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  lea    0x10(%rbp),%esi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <md5@plt>
  movb   $0xc,(%rsp)
  mov    $0x11,%edx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <write_fill@plt>
  cmp    $0x11,%eax
  jne    L1
  mov    %rsp,%rsi
  mov    $0x1,%edx
  mov    %ebx,%edi
  call   <read_fill@plt>
  cmp    $0x1,%eax
  jne    L1
  cmpb   $0x0,(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L1
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s

assistant: ```c
int confd_ipc_access_check(int sock, const unsigned char *secret) {
  unsigned char chall[1 + 16];
  unsigned char buf[1024];
  int n;
  if ((n = read_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if (chall[0] != 11) {
    return 0;
  }
  snprintf((char *)buf, sizeof(buf) - 16, "%s", secret);
  n = strlen((char *)buf);
  memcpy(&buf[n], &chall[1], 16);
  md5(buf, n + 16, &chall[1]);
  chall[0] = 12;
  if ((n = write_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if ((n = read_fill(sock, chall, 1)) != 1) {
    return n;
  }
  if (chall[0] != 0) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<confd_ipc_access_check>:
  endbr64
  push   %r15
  mov    $0x11,%edx
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <read_fill@plt>
  cmp    $0x11,%eax
  jne    L31
  xor    %eax,%eax
  cmpb   $0xb,(%rsp)
  je     L28
L31:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x430,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L28:
  lea    0x20(%rsp),%r14
  mov    %r13,%rcx
  mov    $0x3f0,%esi
  lea    D5(%rip),%rdx
  mov    %r14,%rdi
  lea    0x1(%rsp),%r15
  call   <snprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    $0x10,%edx
  mov    %r15,%rsi
  movslq %eax,%rdi
  mov    %rdi,%r13
  add    %r14,%rdi
  call   <memcpy@plt>
  lea    0x10(%r13),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  call   <md5@plt>
  mov    $0x11,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0xc,(%rsp)
  call   <write_fill@plt>
  cmp    $0x11,%eax
  jne    L31
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read_fill@plt>
  cmp    $0x1,%eax
  jne    L31
  xor    %eax,%eax
  cmpb   $0x0,(%rsp)
  sete   %al
  jmp    L31
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %s

assistant: ```c
int confd_ipc_access_check(int sock, const unsigned char *secret) {
  unsigned char chall[1 + 16];
  unsigned char buf[1024];
  int n;
  if ((n = read_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if (chall[0] != 11) {
    return 0;
  }
  snprintf((char *)buf, sizeof(buf) - 16, "%s", secret);
  n = strlen((char *)buf);
  memcpy(&buf[n], &chall[1], 16);
  md5(buf, n + 16, &chall[1]);
  chall[0] = 12;
  if ((n = write_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if ((n = read_fill(sock, chall, 1)) != 1) {
    return n;
  }
  if (chall[0] != 0) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<confd_ipc_access_check>:
  endbr64
  push   %r15
  mov    $0x11,%edx
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <read_fill@plt>
  cmp    $0x11,%eax
  jne    L1
  xor    %eax,%eax
  cmpb   $0xb,(%rsp)
  je     L48
L1:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x430,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L48:
  lea    0x20(%rsp),%r14
  mov    %r13,%rcx
  mov    $0x3f0,%esi
  lea    D1(%rip),%rdx
  mov    %r14,%rdi
  lea    0x1(%rsp),%r15
  call   <snprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    $0x10,%edx
  mov    %r15,%rsi
  movslq %eax,%rdi
  mov    %rdi,%r13
  add    %r14,%rdi
  call   <memcpy@plt>
  lea    0x10(%r13),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  call   <md5@plt>
  mov    $0x11,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0xc,(%rsp)
  call   <write_fill@plt>
  cmp    $0x11,%eax
  jne    L1
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read_fill@plt>
  cmp    $0x1,%eax
  jne    L1
  xor    %eax,%eax
  cmpb   $0x0,(%rsp)
  sete   %al
  jmp    L1
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: %s

assistant: ```c
int confd_ipc_access_check(int sock, const unsigned char *secret) {
  unsigned char chall[1 + 16];
  unsigned char buf[1024];
  int n;
  if ((n = read_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if (chall[0] != 11) {
    return 0;
  }
  snprintf((char *)buf, sizeof(buf) - 16, "%s", secret);
  n = strlen((char *)buf);
  memcpy(&buf[n], &chall[1], 16);
  md5(buf, n + 16, &chall[1]);
  chall[0] = 12;
  if ((n = write_fill(sock, chall, sizeof(chall))) != sizeof(chall)) {
    return n;
  }
  if ((n = read_fill(sock, chall, 1)) != 1) {
    return n;
  }
  if (chall[0] != 0) {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x30(%rsp),%rdi
  mov    $0x15,%ecx
  rep stos %rax,%es:(%rdi)
  call   <welcome@plt>
  lea    D4(%rip),%rbx
L62:
  mov    $0x0,%eax
  call   <menu@plt>
  cmp    $0x6,%eax
  ja     L62
  mov    %eax,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  lea    0x30(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <read_in@plt>
  jmp    L62
  cmpl   $0x1,0xc(%rsp)
  je     L0
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L62
L0:
  lea    0x10(%rsp),%rdi
  call   <display@plt>
  jmp    L62
  cmpl   $0x1,0xc(%rsp)
  je     L94
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L62
L94:
  lea    0x10(%rsp),%rdi
  call   <selection@plt>
  jmp    L62
  cmpl   $0x1,0xc(%rsp)
  je     L83
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L62
L83:
  lea    0x10(%rsp),%rdi
  call   <winner_check@plt>
  jmp    L62
  cmpl   $0x1,0xc(%rsp)
  je     L102
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L62
L102:
  lea    0x30(%rsp),%rdi
  call   <frequency@plt>
  jmp    L62
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type_infered: string

tool: D19: 
Thank you for using Paul Brittain's Lotto Checker


assistant: ```c
main() {
  int input_numbers[6], loop = 0, menu_num, input_confirmation = 0, cpy = 0;
  int count[42] = {0};
  int *counter = &count[0];
  int *inputs = &input_numbers[0];
  int *confirm = &input_confirmation;
  int *copy = &cpy;
  welcome();
  while (loop != 1) {
    menu_num = menu();
    switch (menu_num) {
    case 1: {
      read_in(inputs, confirm, counter);
      break;
    }
    case 2: {
      if (input_confirmation == 1) {
        display(inputs);
      } else {
        error();
      }
      break;
    }
    case 3: {
      if (input_confirmation == 1) {
        selection(inputs);
      } else {
        error();
      }
      break;
    }
    case 4: {
      if (input_confirmation == 1) {
        winner_check(inputs);
      } else {
        error();
      }
      break;
    }
    case 5: {
      if (input_confirmation == 1) {
        frequency(counter);
      } else {
        error();
      }
      break;
    }
    case 6: {
      printf("\nThank you for using Paul Brittain's Lotto Checker\n");
      loop = 1;
      break;
    }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x15,%ecx
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbp
  lea    0x10(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  call   <welcome@plt>
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <menu@plt>
  cmp    $0x6,%eax
  ja     L22
  mov    %eax,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  cmpl   $0x1,0xc(%rsp)
  je     L68
L4:
  xor    %eax,%eax
  call   <error@plt>
  jmp    L22
  nopl   0x0(%rax,%rax,1)
  cmpl   $0x1,0xc(%rsp)
  jne    L4
  mov    %r12,%rdi
  call   <winner_check@plt>
  jmp    L22
  nopl   0x0(%rax)
  cmpl   $0x1,0xc(%rsp)
  jne    L4
  mov    %r12,%rdi
  call   <selection@plt>
  jmp    L22
  nopl   0x0(%rax)
  cmpl   $0x1,0xc(%rsp)
  jne    L4
  mov    %r12,%rdi
  call   <display@plt>
  jmp    L22
  nopl   0x0(%rax)
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  call   <read_in@plt>
  jmp    L22
L68:
  mov    %rbp,%rdi
  call   <frequency@plt>
  jmp    L22
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: 
Thank you for using Paul Brittain's Lotto Checker


assistant: ```c
main() {
  int input_numbers[6], loop = 0, menu_num, input_confirmation = 0, cpy = 0;
  int count[42] = {0};
  int *counter = &count[0];
  int *inputs = &input_numbers[0];
  int *confirm = &input_confirmation;
  int *copy = &cpy;
  welcome();
  while (loop != 1) {
    menu_num = menu();
    switch (menu_num) {
    case 1: {
      read_in(inputs, confirm, counter);
      break;
    }
    case 2: {
      if (input_confirmation == 1) {
        display(inputs);
      } else {
        error();
      }
      break;
    }
    case 3: {
      if (input_confirmation == 1) {
        selection(inputs);
      } else {
        error();
      }
      break;
    }
    case 4: {
      if (input_confirmation == 1) {
        winner_check(inputs);
      } else {
        error();
      }
      break;
    }
    case 5: {
      if (input_confirmation == 1) {
        frequency(counter);
      } else {
        error();
      }
      break;
    }
    case 6: {
      printf("\nThank you for using Paul Brittain's Lotto Checker\n");
      loop = 1;
      break;
    }
    }
  }
}
```