ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_atatline>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L17
  mov    %rsi,%rbx
  mov    $0x2d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L67
  lea    0x1(%rax),%r15
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %r15,%rdi
  call   <strtoul@plt>
  cmp    %r15,(%rsp)
  je     L67
  mov    %rax,(%rbx)
L17:
  test   %r12,%r12
  je     L22
  mov    %rbp,%rdi
  call   <orig_num_lines@plt>
  mov    %rax,(%r12)
L22:
  test   %r13,%r13
  je     L96
  mov    $0x2b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L67
  lea    0x1(%rax),%rbx
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtoul@plt>
  cmp    %rbx,(%rsp)
  je     L67
  mov    %rax,0x0(%r13)
L96:
  xor    %r12d,%r12d
  test   %r14,%r14
  je     L39
  mov    %rbp,%rdi
  call   <new_num_lines@plt>
  mov    %rax,(%r14)
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L67:
  mov    $0x1,%r12d
  jmp    L39
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_atatline(const char *atatline, unsigned long *orig_offset, unsigned long *orig_count, unsigned long *new_offset, unsigned long *new_count) {
  char *endptr;
  unsigned long res;
  char *p;
  if (orig_offset) {
    p = strchr(atatline, '-');
    if (!p)
      return 1;
    p++;
    res = strtoul(p, &endptr, 10);
    if (p == endptr)
      return 1;
    *orig_offset = res;
  }
  if (orig_count)
    *orig_count = orig_num_lines(atatline);
  if (new_offset) {
    p = strchr(atatline, '+');
    if (!p)
      return 1;
    p++;
    res = strtoul(p, &endptr, 10);
    if (p == endptr)
      return 1;
    *new_offset = res;
  }
  if (new_count)
    *new_count = new_num_lines(atatline);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int *pa;
  int a;
  pa = &a;
  a = 5;
  int b = 3;
  a = *pa + b;
  return a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main() {
  int *pa;
  int a;
  pa = &a;
  a = 5;
  int b = 3;
  a = *pa + b;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main() {
  int *pa;
  int a;
  pa = &a;
  a = 5;
  int b = 3;
  a = *pa + b;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main() {
  int *pa;
  int a;
  pa = &a;
  a = 5;
  int b = 3;
  a = *pa + b;
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L52
  mov    -0x18(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  jne    L52
  mov    $0x1,%eax
  jmp    L34
L52:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  jne    L6
  mov    -0x18(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L6
  mov    $0x2,%eax
  jmp    L34
L6:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int check_bit(u_int old, u_int new, u_int bit) {
  int mask = 1 << bit;
  if ((old & mask) && !(new &mask))
    return (1);
  if (!(old & mask) && (new &mask))
    return (2);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<check_bit>:
  endbr64
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  test   %edi,%eax
  je     L8
  test   %esi,%eax
  sete   %al
  movzbl %al,%eax
  ret
L8:
  test   %esi,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int check_bit(u_int old, u_int new, u_int bit) {
  int mask = 1 << bit;
  if ((old & mask) && !(new &mask))
    return (1);
  if (!(old & mask) && (new &mask))
    return (2);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_bit>:
  endbr64
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  and    %eax,%esi
  test   %edi,%eax
  jne    L7
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  add    %eax,%eax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
  ret
```

assistant: ```c
int check_bit(u_int old, u_int new, u_int bit) {
  int mask = 1 << bit;
  if ((old & mask) && !(new &mask))
    return (1);
  if (!(old & mask) && (new &mask))
    return (2);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_bit>:
  endbr64
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  and    %eax,%esi
  test   %edi,%eax
  jne    L1
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  add    %eax,%eax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  test   %esi,%esi
  sete   %al
  ret
```

assistant: ```c
int check_bit(u_int old, u_int new, u_int bit) {
  int mask = 1 << bit;
  if ((old & mask) && !(new &mask))
    return (1);
  if (!(old & mask) && (new &mask))
    return (2);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countSegments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L54
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L1
  movl   $0x1,-0x10(%rbp)
  jmp    L61
L1:
  cmpl   $0x1,-0x10(%rbp)
  jne    L61
  movl   $0x0,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L61:
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  cmpl   $0x1,-0x10(%rbp)
  jne    L29
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int countSegments(char *s) {
  int size = strlen(s);
  int hasChar = 0;
  int cnt = 0;
  for (int i = 0; i < size; i++) {
    if (s[i] != ' ' && s[i] != '\n') {
      hasChar = 1;
    } else {
      if (hasChar == 1) {
        hasChar = 0;
        cnt++;
      }
    }
  }
  if (hasChar == 1)
    cnt++;
  return cnt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<countSegments>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L20
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  jmp    L46
L36:
  mov    %r8d,%ecx
L19:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L21
L46:
  movzbl (%rdx),%eax
  cmp    $0x20,%al
  je     L71
  cmp    $0xa,%al
  jne    L36
L71:
  cmp    $0x1,%ecx
  jne    L19
  add    $0x1,%edi
  mov    %r9d,%ecx
  jmp    L19
L21:
  add    %ecx,%edi
L68:
  mov    %edi,%eax
  pop    %rbx
  ret
L20:
  mov    $0x0,%edi
  jmp    L68
```

assistant: ```c
int countSegments(char *s) {
  int size = strlen(s);
  int hasChar = 0;
  int cnt = 0;
  for (int i = 0; i < size; i++) {
    if (s[i] != ' ' && s[i] != '\n') {
      hasChar = 1;
    } else {
      if (hasChar == 1) {
        hasChar = 0;
        cnt++;
      }
    }
  }
  if (hasChar == 1)
    cnt++;
  return cnt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<countSegments>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L63
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%rcx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%edx
L22:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  je     L44
L24:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L64
  cmp    $0xa,%al
  jne    L11
L64:
  cmp    $0x1,%edx
  jne    L22
  add    $0x1,%rdi
  add    $0x1,%r8d
  xor    %edx,%edx
  cmp    %rcx,%rdi
  jne    L24
L44:
  add    %edx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L63:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countSegments(char *s) {
  int size = strlen(s);
  int hasChar = 0;
  int cnt = 0;
  for (int i = 0; i < size; i++) {
    if (s[i] != ' ' && s[i] != '\n') {
      hasChar = 1;
    } else {
      if (hasChar == 1) {
        hasChar = 0;
        cnt++;
      }
    }
  }
  if (hasChar == 1)
    cnt++;
  return cnt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<countSegments>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L46
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%rcx
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L50:
  mov    $0x1,%edx
L68:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  je     L6
L62:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L27
  cmp    $0xa,%al
  jne    L50
L27:
  cmp    $0x1,%edx
  jne    L68
  add    $0x1,%rdi
  add    $0x1,%r8d
  xor    %edx,%edx
  cmp    %rdi,%rcx
  jne    L62
L6:
  add    %edx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L46:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countSegments(char *s) {
  int size = strlen(s);
  int hasChar = 0;
  int cnt = 0;
  for (int i = 0; i < size; i++) {
    if (s[i] != ' ' && s[i] != '\n') {
      hasChar = 1;
    } else {
      if (hasChar == 1) {
        hasChar = 0;
        cnt++;
      }
    }
  }
  if (hasChar == 1)
    cnt++;
  return cnt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<os_close_files>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L20
  cmpl   $0x0,-0x4(%rbp)
  jns    L31
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L35:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L35
  jmp    L6
L20:
  nop
L6:
  leave
  ret
```

assistant: ```c
void os_close_files(int fd_min, int fd_max) {
  if (fd_min > fd_max)
    return;
  else if (fd_min < 0)
    fd_min = 0;
  for (; fd_min <= fd_max; fd_min++)
    close(fd_min);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<os_close_files>:
  endbr64
  cmp    %esi,%edi
  jg     L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %edi,%edi
  mov    $0x0,%eax
  cmovns %edi,%eax
  mov    %eax,%ebx
  cmp    %eax,%esi
  jl     L25
L7:
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L7
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
void os_close_files(int fd_min, int fd_max) {
  if (fd_min > fd_max)
    return;
  else if (fd_min < 0)
    fd_min = 0;
  for (; fd_min <= fd_max; fd_min++)
    close(fd_min);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<os_close_files>:
  endbr64
  cmp    %esi,%edi
  jg     L9
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovns %edi,%eax
  mov    %eax,%ebx
  cmp    %eax,%esi
  jl     L3
  nopl   (%rax)
L1:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    %ebx,%ebp
  jge    L1
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L9:
  ret
```

assistant: ```c
void os_close_files(int fd_min, int fd_max) {
  if (fd_min > fd_max)
    return;
  else if (fd_min < 0)
    fd_min = 0;
  for (; fd_min <= fd_max; fd_min++)
    close(fd_min);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<os_close_files>:
  endbr64
  cmp    %esi,%edi
  jg     L12
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  cmovns %edi,%eax
  mov    %eax,%ebx
  cmp    %eax,%esi
  jl     L2
  nopl   (%rax)
L1:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    %ebx,%ebp
  jge    L1
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void os_close_files(int fd_min, int fd_max) {
  if (fd_min > fd_max)
    return;
  else if (fd_min < 0)
    fd_min = 0;
  for (; fd_min <= fd_max; fd_min++)
    close(fd_min);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scaleShorts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x20(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cvttss2si %xmm0,%edx
  mov    %dx,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scaleShorts(short *shorts, int numShorts, float scalar) {
  int i;
  for (i = 0; i < numShorts; i++) {
    shorts[i] *= scalar;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scaleShorts>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x2(%rdi,%rdx,2),%rcx
L18:
  movswl (%rax),%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%edx
  mov    %dx,(%rax)
  add    $0x2,%rax
  cmp    %rcx,%rax
  jne    L18
L10:
  ret
```

assistant: ```c
void scaleShorts(short *shorts, int numShorts, float scalar) {
  int i;
  for (i = 0; i < numShorts; i++) {
    shorts[i] *= scalar;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scaleShorts>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x2(%rdi,%rax,2),%rdx
L17:
  movswl (%rdi),%eax
  pxor   %xmm1,%xmm1
  add    $0x2,%rdi
  cvtsi2ss %eax,%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%eax
  mov    %ax,-0x2(%rdi)
  cmp    %rdx,%rdi
  jne    L17
L15:
  ret
```

assistant: ```c
void scaleShorts(short *shorts, int numShorts, float scalar) {
  int i;
  for (i = 0; i < numShorts; i++) {
    shorts[i] *= scalar;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scaleShorts>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  movaps %xmm0,%xmm4
  test   %esi,%esi
  jle    L70
  lea    -0x1(%rsi),%eax
  cmp    $0x6,%eax
  jbe    L83
  shr    $0x3,%esi
  movaps %xmm0,%xmm3
  pxor   %xmm5,%xmm5
  mov    %rdi,%rax
  sub    $0x1,%esi
  shufps $0x0,%xmm3,%xmm3
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   (%rax)
L68:
  movdqu (%rax),%xmm1
  movdqa %xmm5,%xmm2
  add    $0x10,%rax
  pcmpgtw %xmm1,%xmm2
  movdqa %xmm1,%xmm0
  punpcklwd %xmm2,%xmm0
  punpckhwd %xmm2,%xmm1
  cvtdq2ps %xmm0,%xmm0
  cvtdq2ps %xmm1,%xmm1
  mulps  %xmm3,%xmm0
  mulps  %xmm3,%xmm1
  cvttps2dq %xmm0,%xmm0
  movdqa %xmm0,%xmm2
  cvttps2dq %xmm1,%xmm1
  punpcklwd %xmm1,%xmm0
  punpckhwd %xmm1,%xmm2
  movdqa %xmm0,%xmm1
  punpcklwd %xmm2,%xmm0
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L68
  mov    %edx,%esi
  and    $0xfffffff8,%esi
  test   $0x7,%dl
  je     L74
L67:
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  add    %rax,%rax
  lea    (%rcx,%rax,1),%rdi
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  lea    0x1(%rsi),%edi
  cmp    %edi,%edx
  jle    L70
  lea    0x2(%rcx,%rax,1),%rdi
  pxor   %xmm0,%xmm0
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  lea    0x2(%rsi),%edi
  cmp    %edi,%edx
  jle    L70
  lea    0x4(%rcx,%rax,1),%rdi
  pxor   %xmm0,%xmm0
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  lea    0x3(%rsi),%edi
  cmp    %edi,%edx
  jle    L70
  lea    0x6(%rcx,%rax,1),%rdi
  pxor   %xmm0,%xmm0
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  lea    0x4(%rsi),%edi
  cmp    %edi,%edx
  jle    L70
  lea    0x8(%rcx,%rax,1),%rdi
  pxor   %xmm0,%xmm0
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  lea    0x5(%rsi),%edi
  cmp    %edi,%edx
  jle    L70
  lea    0xa(%rcx,%rax,1),%rdi
  pxor   %xmm0,%xmm0
  add    $0x6,%esi
  movswl (%rdi),%r8d
  cvtsi2ss %r8d,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%r8d
  mov    %r8w,(%rdi)
  cmp    %esi,%edx
  jle    L70
  lea    0xc(%rcx,%rax,1),%rax
  pxor   %xmm0,%xmm0
  movswl (%rax),%edx
  cvtsi2ss %edx,%xmm0
  mulss  %xmm4,%xmm0
  cvttss2si %xmm0,%edx
  mov    %dx,(%rax)
L70:
  ret
  nopl   0x0(%rax)
L74:
  ret
L83:
  xor    %esi,%esi
  jmp    L67
```

assistant: ```c
void scaleShorts(short *shorts, int numShorts, float scalar) {
  int i;
  for (i = 0; i < numShorts; i++) {
    shorts[i] *= scalar;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L26
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L26:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D22
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D21
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D22: Enter a number


tool: D19: %d

tool: D21: The entered number is prime


tool: D5: The entered number is not prime


assistant: ```c
int main() {
  printf("Enter a number\n");
  int n;
  scanf("%d", &n);
  if (isPrime(n))
    printf("The entered number is prime\n");
  else
    printf("The entered number is not prime\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L12
  lea    D29(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D35
data_type: string
name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D39
data_type: string

tool: D35: Enter a number


tool: D34: %d

tool: D29: The entered number is prime


tool: D39: The entered number is not prime


assistant: ```c
int main() {
  printf("Enter a number\n");
  int n;
  scanf("%d", &n);
  if (isPrime(n))
    printf("The entered number is prime\n");
  else
    printf("The entered number is not prime\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L17
  lea    D13(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L17:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D0: Enter a number


tool: D20: %d

tool: D13: The entered number is prime


tool: D18: The entered number is not prime


assistant: ```c
int main() {
  printf("Enter a number\n");
  int n;
  scanf("%d", &n);
  if (isPrime(n))
    printf("The entered number is prime\n");
  else
    printf("The entered number is not prime\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L2
  lea    D31(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string

tool: D33: Enter a number


tool: D9: %d

tool: D31: The entered number is prime


tool: D26: The entered number is not prime


assistant: ```c
int main() {
  printf("Enter a number\n");
  int n;
  scanf("%d", &n);
  if (isPrime(n))
    printf("The entered number is prime\n");
  else
    printf("The entered number is not prime\n");
  return 0;
}
```