ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L0
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *x = realloc(ptr, size);
  if (__builtin_expect(!!(!x), 0))
    exit(errno);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L15
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
L15:
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L3
```

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *x = realloc(ptr, size);
  if (__builtin_expect(!!(!x), 0))
    exit(errno);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *x = realloc(ptr, size);
  if (__builtin_expect(!!(!x), 0))
    exit(errno);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L4
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *xrealloc(void *ptr, size_t size) {
  void *x = realloc(ptr, size);
  if (__builtin_expect(!!(!x), 0))
    exit(errno);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<grow_expansion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  movsd  %xmm0,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L8
L2:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  addl   $0x1,-0x3c(%rbp)
L8:
  mov    -0x3c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L2
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int grow_expansion(elen, e, b, h)
int elen;
double *e;
double b;
double *h;
{
  double Q;
  double Qnew;
  int eindex;
  double enow;
  double bvirt;
  double avirt, bround, around;
  Q = b;
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    h[eindex] = around + bround;
    Q = Qnew;
  }
  h[eindex] = Q;
  return eindex + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<grow_expansion>:
  endbr64
  test   %edi,%edi
  jle    L21
  mov    %edi,%eax
  mov    $0x0,%ecx
L1:
  movsd  (%rsi,%rcx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  movapd %xmm0,%xmm4
  subsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm1
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L1
L2:
  movslq %edi,%rax
  movsd  %xmm0,(%rdx,%rax,8)
  lea    0x1(%rdi),%eax
  ret
L21:
  mov    $0x0,%edi
  jmp    L2
```

assistant: ```c
int grow_expansion(elen, e, b, h)
int elen;
double *e;
double b;
double *h;
{
  double Q;
  double Qnew;
  int eindex;
  double enow;
  double bvirt;
  double avirt, bround, around;
  Q = b;
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    h[eindex] = around + bround;
    Q = Qnew;
  }
  h[eindex] = Q;
  return eindex + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<grow_expansion>:
  endbr64
  test   %edi,%edi
  jle    L8
  movslq %edi,%r8
  xor    %ecx,%ecx
  nopl   (%rax)
L12:
  movsd  (%rsi,%rcx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L12
  lea    (%rdx,%r8,8),%rdx
  lea    0x1(%rdi),%eax
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%eax
  movsd  %xmm0,(%rdx)
  ret
```

assistant: ```c
int grow_expansion(elen, e, b, h)
int elen;
double *e;
double b;
double *h;
{
  double Q;
  double Qnew;
  int eindex;
  double enow;
  double bvirt;
  double avirt, bround, around;
  Q = b;
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    h[eindex] = around + bround;
    Q = Qnew;
  }
  h[eindex] = Q;
  return eindex + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<grow_expansion>:
  endbr64
  test   %edi,%edi
  jle    L0
  movslq %edi,%r8
  xor    %ecx,%ecx
  nopl   (%rax)
L6:
  movsd  (%rsi,%rcx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  subsd  %xmm1,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L6
  lea    (%rdx,%r8,8),%rdx
  lea    0x1(%rdi),%eax
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  movsd  %xmm0,(%rdx)
  ret
```

assistant: ```c
int grow_expansion(elen, e, b, h)
int elen;
double *e;
double b;
double *h;
{
  double Q;
  double Qnew;
  int eindex;
  double enow;
  double bvirt;
  double avirt, bround, around;
  Q = b;
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    h[eindex] = around + bround;
    Q = Qnew;
  }
  h[eindex] = Q;
  return eindex + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x80000000,%eax
  mov    %rax,-0x20(%rbp)
  mov    $0x80000004,%eax
  mov    %rax,-0x18(%rbp)
  mov    $0x80000008,%eax
  mov    %rax,-0x10(%rbp)
  mov    $0x8000000c,%eax
  mov    %rax,-0x8(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  movl   $0xdeadbeef,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rax
  movl   $0xba5eba11,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  movl   $0xc001d00d,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  movl   $0x1badbabe,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D43
data_type: string
name: parse_data
arguments: tag: D66
data_type: string
name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D30
data_type: string

tool: D43: Writing to AR

tool: D66: Reading from AR: 0x%08x


tool: D7: Writing to CR

tool: D5: Reading from CR: 0x%08x


tool: D9: Writing to IESR

tool: D44: Reading from IESR: 0x%08x


tool: D30: Writing to CCR

assistant: ```c
int main() {
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  unsigned int *volatile cr = (unsigned int *)0x80000000U + 1;
  unsigned int *volatile iesr = (unsigned int *)0x80000000U + 2;
  unsigned int *volatile ccr = (unsigned int *)0x80000000U + 3;
  printf("Writing to AR\n");
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Writing to CR\n");
  *cr = 0xBA5EBA11;
  printf("Reading from CR: 0x%08x\n", *cr);
  printf("Writing to IESR\n");
  *iesr = 0xC001D00D;
  printf("Reading from IESR: 0x%08x\n", *iesr);
  printf("Writing to CCR\n");
  *ccr = 0x1BADBABE;
  printf("Reading from AR: 0x%08x\n", *ccr);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    $0x80000000,%eax
  mov    %rax,(%rsp)
  lea    0x4(%rax),%rax
  mov    %rax,0x8(%rsp)
  lea    0x4(%rax),%rax
  mov    %rax,0x10(%rsp)
  lea    0x4(%rax),%rax
  mov    %rax,0x18(%rsp)
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rax
  movl   $0xdeadbeef,(%rax)
  mov    (%rsp),%rax
  mov    (%rax),%esi
  lea    D64(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  movl   $0xba5eba11,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rax
  movl   $0xc001d00d,(%rax)
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  movl   $0x1badbabe,(%rax)
  mov    0x18(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D53
data_type: string
name: retrieve_data
arguments: tag: D64
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D40
data_type: string
name: retrieve_data
arguments: tag: D32
data_type: string
name: retrieve_data
arguments: tag: D2
data_type: string

tool: D53: Writing to AR

tool: D64: Reading from AR: 0x%08x


tool: D12: Writing to CR

tool: D31: Reading from CR: 0x%08x


tool: D40: Writing to IESR

tool: D32: Reading from IESR: 0x%08x


tool: D2: Writing to CCR

assistant: ```c
int main() {
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  unsigned int *volatile cr = (unsigned int *)0x80000000U + 1;
  unsigned int *volatile iesr = (unsigned int *)0x80000000U + 2;
  unsigned int *volatile ccr = (unsigned int *)0x80000000U + 3;
  printf("Writing to AR\n");
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Writing to CR\n");
  *cr = 0xBA5EBA11;
  printf("Reading from CR: 0x%08x\n", *cr);
  printf("Writing to IESR\n");
  *iesr = 0xC001D00D;
  printf("Reading from IESR: 0x%08x\n", *iesr);
  printf("Writing to CCR\n");
  *ccr = 0x1BADBABE;
  printf("Reading from AR: 0x%08x\n", *ccr);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80000000,%eax
  lea    D67(%rip),%rdi
  lea    D62(%rip),%rbp
  sub    $0x20,%rsp
  mov    %rax,(%rsp)
  add    $0x4,%rax
  mov    %rax,0x8(%rsp)
  add    $0x4,%rax
  mov    %rax,0x10(%rsp)
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  call   <puts@plt>
  mov    (%rsp),%rax
  mov    %rbp,%rdi
  movl   $0xdeadbeef,(%rax)
  mov    (%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  lea    D37(%rip),%rdi
  movl   $0xba5eba11,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rax
  lea    D1(%rip),%rdi
  movl   $0xc001d00d,(%rax)
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  mov    %rbp,%rdi
  movl   $0x1badbabe,(%rax)
  mov    0x18(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D67
type_infered: string
name: disassemble_data
arguments: tag: D62
type_infered: string
name: disassemble_data
arguments: tag: D41
type_infered: string
name: disassemble_data
arguments: tag: D37
type_infered: string
name: disassemble_data
arguments: tag: D54
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D66
type_infered: string

tool: D67: Writing to AR

tool: D62: Reading from AR: 0x%08x


tool: D41: Writing to CR

tool: D37: Reading from CR: 0x%08x


tool: D54: Writing to IESR

tool: D1: Reading from IESR: 0x%08x


tool: D66: Writing to CCR

assistant: ```c
int main() {
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  unsigned int *volatile cr = (unsigned int *)0x80000000U + 1;
  unsigned int *volatile iesr = (unsigned int *)0x80000000U + 2;
  unsigned int *volatile ccr = (unsigned int *)0x80000000U + 3;
  printf("Writing to AR\n");
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Writing to CR\n");
  *cr = 0xBA5EBA11;
  printf("Reading from CR: 0x%08x\n", *cr);
  printf("Writing to IESR\n");
  *iesr = 0xC001D00D;
  printf("Reading from IESR: 0x%08x\n", *iesr);
  printf("Writing to CCR\n");
  *ccr = 0x1BADBABE;
  printf("Reading from AR: 0x%08x\n", *ccr);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80000000,%eax
  lea    D54(%rip),%rdi
  lea    D53(%rip),%rbp
  sub    $0x20,%rsp
  mov    %rax,(%rsp)
  add    $0x4,%rax
  mov    %rax,0x8(%rsp)
  add    $0x4,%rax
  mov    %rax,0x10(%rsp)
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  call   <puts@plt>
  mov    (%rsp),%rax
  mov    %rbp,%rdi
  movl   $0xdeadbeef,(%rax)
  mov    (%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  lea    D17(%rip),%rdi
  movl   $0xba5eba11,(%rax)
  mov    0x8(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rax
  lea    D11(%rip),%rdi
  movl   $0xc001d00d,(%rax)
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  mov    %rbp,%rdi
  movl   $0x1badbabe,(%rax)
  mov    0x18(%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D54
type_guessed: string
name: unpack_data
arguments: data_label: D53
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D59
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string

tool: D54: Writing to AR

tool: D53: Reading from AR: 0x%08x


tool: D0: Writing to CR

tool: D17: Reading from CR: 0x%08x


tool: D59: Writing to IESR

tool: D11: Reading from IESR: 0x%08x


tool: D41: Writing to CCR

assistant: ```c
int main() {
  unsigned int *volatile ar = (unsigned int *)0x80000000U;
  unsigned int *volatile cr = (unsigned int *)0x80000000U + 1;
  unsigned int *volatile iesr = (unsigned int *)0x80000000U + 2;
  unsigned int *volatile ccr = (unsigned int *)0x80000000U + 3;
  printf("Writing to AR\n");
  *ar = 0xDEADBEEF;
  printf("Reading from AR: 0x%08x\n", *ar);
  printf("Writing to CR\n");
  *cr = 0xBA5EBA11;
  printf("Reading from CR: 0x%08x\n", *cr);
  printf("Writing to IESR\n");
  *iesr = 0xC001D00D;
  printf("Reading from IESR: 0x%08x\n", *iesr);
  printf("Writing to CCR\n");
  *ccr = 0x1BADBABE;
  printf("Reading from AR: 0x%08x\n", *ccr);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L27
L20:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L27:
  cmpl   $0x9,-0x38(%rbp)
  jle    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x3,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L26
L1:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L26:
  cmpl   $0x9,-0x34(%rbp)
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string

tool: D4: %d 

tool: D28: %d


assistant: ```c
int main() {
  int n[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  printf("%d\n", search(n, 10, 3));
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D19(%rip),%r13
L19:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x3,%edx
  mov    $0xa,%esi
  call   <search@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D21
type: string

tool: D19: %d 

tool: D21: %d


assistant: ```c
int main() {
  int n[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  printf("%d\n", search(n, 10, 3));
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%r14
  lea    0x4(%rsp),%rbp
  lea    0x28(%rsp),%r12
  mov    %r14,%rbx
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    0x0(%rbp),%esi
  add    $0x4,%rbp
L16:
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%esi
  mov    %r14,%rdi
  mov    $0x3,%edx
  call   <search@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D5
type: string

tool: D19: %d 

tool: D5: %d


assistant: ```c
int main() {
  int n[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  printf("%d\n", search(n, 10, 3));
  for (int j = 0; j < 10; j++)
    printf("%d ", n[j]);
  printf("\n");
  return 0;
}
```