ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int FORWARD = 1;
  char *a = "baba";
  char *(*f)(const char *s, int c) = strchr;
  if (FORWARD) {
    f = strrchr;
  }
  char *x = f(a, 'b');
  test_assert(x == a + 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int FORWARD = 1;
  char *a = "baba";
  char *(*f)(const char *s, int c) = strchr;
  if (FORWARD) {
    f = strrchr;
  }
  char *x = f(a, 'b');
  test_assert(x == a + 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int FORWARD = 1;
  char *a = "baba";
  char *(*f)(const char *s, int c) = strchr;
  if (FORWARD) {
    f = strrchr;
  }
  char *x = f(a, 'b');
  test_assert(x == a + 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int max_sum(int num[], int i) {
  int p = max(num[0], num[1]);
  for (int j = 2; j < i; j++) {
    p = max(p, num[j]);
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_sum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    0x4(%rdi),%esi
  mov    (%rdi),%edi
  call   <max@plt>
  mov    %eax,%edi
  cmp    $0x2,%r12d
  jle    L1
  lea    0x8(%rbp),%rbx
  lea    -0x3(%r12),%eax
  lea    0xc(%rbp,%rax,4),%rbp
L7:
  mov    (%rbx),%esi
  call   <max@plt>
  mov    %eax,%edi
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L7
L1:
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int max_sum(int num[], int i) {
  int p = max(num[0], num[1]);
  for (int j = 2; j < i; j++) {
    p = max(p, num[j]);
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<max_sum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    0x4(%rdi),%esi
  mov    (%rdi),%edi
  call   <max@plt>
  mov    %eax,%edi
  cmp    $0x2,%r12d
  jle    L10
  lea    -0x3(%r12),%eax
  lea    0x8(%rbp),%rbx
  lea    0xc(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L0:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  call   <max@plt>
  mov    %eax,%edi
  cmp    %rbp,%rbx
  jne    L0
L10:
  pop    %rbx
  mov    %edi,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int max_sum(int num[], int i) {
  int p = max(num[0], num[1]);
  for (int j = 2; j < i; j++) {
    p = max(p, num[j]);
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max_sum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    0x4(%rdi),%esi
  mov    (%rdi),%edi
  call   <max@plt>
  mov    %eax,%edi
  cmp    $0x2,%r12d
  jle    L4
  lea    -0x3(%r12),%eax
  lea    0x8(%rbp),%rbx
  lea    0xc(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  call   <max@plt>
  mov    %eax,%edi
  cmp    %rbp,%rbx
  jne    L15
L4:
  pop    %rbx
  mov    %edi,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int max_sum(int num[], int i) {
  int p = max(num[0], num[1]);
  for (int j = 2; j < i; j++) {
    p = max(p, num[j]);
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_get_snes_rom_speed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  lea    D12(%rip),%rax
  jmp    L8
L15:
  lea    D7(%rip),%rax
L8:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string

tool: D12: "200ns"

tool: D7: "120ns"

assistant: ```c
char *_get_snes_rom_speed(int speed) {
  if (speed == 0)
    return "\"200ns\"";
  else
    return "\"120ns\"";
}
```
user: What is the c source code of the assembly code below:

```asm
<_get_snes_rom_speed>:
  endbr64
  test   %edi,%edi
  lea    D8(%rip),%rax
  lea    D9(%rip),%rdx
  cmovne %rdx,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D8: "200ns"

tool: D9: "120ns"

assistant: ```c
char *_get_snes_rom_speed(int speed) {
  if (speed == 0)
    return "\"200ns\"";
  else
    return "\"120ns\"";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_get_snes_rom_speed>:
  endbr64
  test   %edi,%edi
  lea    D7(%rip),%rdx
  lea    D4(%rip),%rax
  cmovne %rdx,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D7: "120ns"

tool: D4: "200ns"

assistant: ```c
char *_get_snes_rom_speed(int speed) {
  if (speed == 0)
    return "\"200ns\"";
  else
    return "\"120ns\"";
}
```
user: What is the c source code of the assembly code below:

```asm
<_get_snes_rom_speed>:
  endbr64
  test   %edi,%edi
  lea    D2(%rip),%rdx
  lea    D1(%rip),%rax
  cmovne %rdx,%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D2: "120ns"

tool: D1: "200ns"

assistant: ```c
char *_get_snes_rom_speed(int speed) {
  if (speed == 0)
    return "\"200ns\"";
  else
    return "\"120ns\"";
}
```
user: Translate the below assembly code into C programming language:

```asm
<dstrb_beta_mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x10(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dstrb_beta_mean(const double a, const double b) {
  assert(a > 0.);
  assert(b > 0.);
  return a / (a + b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dstrb_beta_mean>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  movq   %xmm1,%rbx
  pxor   %xmm3,%xmm3
  comisd %xmm3,%xmm0
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movq   %rbx,%xmm4
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm4
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movq   %rbx,%xmm1
  movsd  0x8(%rsp),%xmm2
  addsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double dstrb_beta_mean(const double a, const double b) {
  assert(a > 0.);
  assert(b > 0.);
  return a / (a + b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dstrb_beta_mean>:
  endbr64
  pxor   %xmm2,%xmm2
  sub    $0x18,%rsp
  comisd %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  (%rsp),%xmm1
  pxor   %xmm3,%xmm3
  xor    %edi,%edi
  comisd %xmm3,%xmm1
  seta   %dil
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  add    $0x18,%rsp
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dstrb_beta_mean(const double a, const double b) {
  assert(a > 0.);
  assert(b > 0.);
  return a / (a + b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dstrb_beta_mean>:
  endbr64
  pxor   %xmm2,%xmm2
  sub    $0x18,%rsp
  comisd %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movsd  (%rsp),%xmm1
  pxor   %xmm3,%xmm3
  xor    %edi,%edi
  comisd %xmm3,%xmm1
  seta   %dil
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  add    $0x18,%rsp
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double dstrb_beta_mean(const double a, const double b) {
  assert(a > 0.);
  assert(b > 0.);
  return a / (a + b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x18,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x10(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x8(%rdx)
  mov    $0x1388,%edi
  call   <htonl@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void fill_values(struct sockaddr_in *addr) {
  bzero(addr, sizeof(*addr));
  addr->sin_family = AF_INET;
  addr->sin_addr.s_addr = htonl(INADDR_ANY);
  addr->sin_port = htonl(5000);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fill_values>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x18,%esi
  call   <bzero@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rbx)
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %rax,0x8(%rbx)
  mov    $0x1388,%edi
  call   <htonl@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fill_values(struct sockaddr_in *addr) {
  bzero(addr, sizeof(*addr));
  addr->sin_family = AF_INET;
  addr->sin_addr.s_addr = htonl(INADDR_ANY);
  addr->sin_port = htonl(5000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_values>:
  endbr64
  push   %rbx
  mov    $0x18,%esi
  mov    %rdi,%rbx
  call   <bzero@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rbx)
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x1388,%edi
  mov    %rax,0x8(%rbx)
  call   <htonl@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fill_values(struct sockaddr_in *addr) {
  bzero(addr, sizeof(*addr));
  addr->sin_family = AF_INET;
  addr->sin_addr.s_addr = htonl(INADDR_ANY);
  addr->sin_port = htonl(5000);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fill_values>:
  endbr64
  push   %rbx
  mov    $0x18,%esi
  mov    %rdi,%rbx
  call   <bzero@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rbx)
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x1388,%edi
  mov    %rax,0x8(%rbx)
  call   <htonl@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fill_values(struct sockaddr_in *addr) {
  bzero(addr, sizeof(*addr));
  addr->sin_family = AF_INET;
  addr->sin_addr.s_addr = htonl(INADDR_ANY);
  addr->sin_port = htonl(5000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getFormattedTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  lea    D17(%rip),%rax
  mov    %rax,%rdx
  mov    $0x14,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    D26(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: string

tool: D17: %Y-%m-%d %H:%M:%S

assistant: ```c
char *getFormattedTime(void) {
  time_t rawtime;
  struct tm *timeinfo;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  static char _retval[20];
  strftime(_retval, sizeof(_retval), "%Y-%m-%d %H:%M:%S", timeinfo);
  return _retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getFormattedTime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    D15(%rip),%rdx
  mov    $0x14,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string

tool: D15: %Y-%m-%d %H:%M:%S

assistant: ```c
char *getFormattedTime(void) {
  time_t rawtime;
  struct tm *timeinfo;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  static char _retval[20];
  strftime(_retval, sizeof(_retval), "%Y-%m-%d %H:%M:%S", timeinfo);
  return _retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getFormattedTime>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D11(%rip),%rdx
  mov    $0x14,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
type: string

tool: D11: %Y-%m-%d %H:%M:%S

assistant: ```c
char *getFormattedTime(void) {
  time_t rawtime;
  struct tm *timeinfo;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  static char _retval[20];
  strftime(_retval, sizeof(_retval), "%Y-%m-%d %H:%M:%S", timeinfo);
  return _retval;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getFormattedTime>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D18(%rip),%rdx
  mov    $0x14,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string

tool: D18: %Y-%m-%d %H:%M:%S

assistant: ```c
char *getFormattedTime(void) {
  time_t rawtime;
  struct tm *timeinfo;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  static char _retval[20];
  strftime(_retval, sizeof(_retval), "%Y-%m-%d %H:%M:%S", timeinfo);
  return _retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x4,%eax
  je     L96
  cmp    $0x4,%eax
  jg     L93
  cmp    $0x3,%eax
  je     L90
  cmp    $0x3,%eax
  jg     L93
  cmp    $0x1,%eax
  je     L33
  cmp    $0x2,%eax
  je     L44
  jmp    L93
L33:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <add@plt>
  jmp    L79
L44:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply@plt>
  jmp    L79
L90:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <divide@plt>
  jmp    L79
L96:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <subtract@plt>
  jmp    L79
L93:
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L79:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L114
  call   <__stack_chk_fail@plt>
L114:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D82
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string
name: parse_data
arguments: tag: D62
type_guessed: string
name: parse_data
arguments: tag: D47
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D54
type_guessed: string

tool: D82: enter two numbers 


tool: D7: %d

tool: D18: Select your option 


tool: D62: 1. add the numbers 


tool: D47: 2. multiply the numbers 


tool: D8: 3. divide the numbers 


tool: D17: 4. subtract the numbers 


tool: D54: invalid

assistant: ```c
void main() {
  int a, b, option;
  printf("enter two numbers \n");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("Select your option \n");
  printf("1. add the numbers \n");
  printf("2. multiply the numbers \n");
  printf("3. divide the numbers \n");
  printf("4. subtract the numbers \n");
  scanf("%d", &option);
  switch (option) {
  case 1:
    add(a, b);
    break;
  case 2:
    multiply(a, b);
    break;
  case 3:
    divide(a, b);
    break;
  case 4:
    subtract(a, b);
    break;
  default:
    printf("invalid");
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L89
  jg     L31
  cmp    $0x1,%eax
  je     L19
  cmp    $0x2,%eax
  jne    L4
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <multiply@plt>
  jmp    L33
L31:
  cmp    $0x4,%eax
  jne    L4
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <subtract@plt>
  jmp    L33
L19:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <add@plt>
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x20,%rsp
  pop    %rbx
  ret
L89:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <divide@plt>
  jmp    L33
L4:
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D46
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D45
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D67
type_infered: string
name: disassemble_data
arguments: data_tag: D62
type_infered: string
name: disassemble_data
arguments: data_tag: D73
type_infered: string
name: disassemble_data
arguments: data_tag: D57
type_infered: string

tool: D46: enter two numbers 


tool: D9: %d

tool: D45: Select your option 


tool: D20: 1. add the numbers 


tool: D67: 2. multiply the numbers 


tool: D62: 3. divide the numbers 


tool: D73: 4. subtract the numbers 


tool: D57: invalid

assistant: ```c
void main() {
  int a, b, option;
  printf("enter two numbers \n");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("Select your option \n");
  printf("1. add the numbers \n");
  printf("2. multiply the numbers \n");
  printf("3. divide the numbers \n");
  printf("4. subtract the numbers \n");
  scanf("%d", &option);
  switch (option) {
  case 1:
    add(a, b);
    break;
  case 2:
    multiply(a, b);
    break;
  case 3:
    divide(a, b);
    break;
  case 4:
    subtract(a, b);
    break;
  default:
    printf("invalid");
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D56(%rip),%rdi
  lea    D18(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L57
  jg     L87
  cmp    $0x1,%eax
  je     L80
  cmp    $0x2,%eax
  jne    L20
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <multiply@plt>
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  cmp    $0x4,%eax
  jne    L20
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <subtract@plt>
  jmp    L44
L57:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <divide@plt>
  jmp    L44
L20:
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L80:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <add@plt>
  jmp    L44
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D56
data_type: string
name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D42
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D60
data_type: string

tool: D56: enter two numbers 


tool: D18: %d

tool: D28: Select your option 


tool: D9: 1. add the numbers 


tool: D19: 2. multiply the numbers 


tool: D42: 3. divide the numbers 


tool: D11: 4. subtract the numbers 


tool: D60: invalid

assistant: ```c
void main() {
  int a, b, option;
  printf("enter two numbers \n");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("Select your option \n");
  printf("1. add the numbers \n");
  printf("2. multiply the numbers \n");
  printf("3. divide the numbers \n");
  printf("4. subtract the numbers \n");
  scanf("%d", &option);
  switch (option) {
  case 1:
    add(a, b);
    break;
  case 2:
    multiply(a, b);
    break;
  case 3:
    divide(a, b);
    break;
  case 4:
    subtract(a, b);
    break;
  default:
    printf("invalid");
    break;
  }
}
```