user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L213
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    0x70(%rsp),%r15
  lea    D20(%rip),%r12
L204:
  add    $0x1,%r13d
  mov    %r13d,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L158
  lea    (%r15,%r14,4),%rbp
  mov    $0x0,%ebx
L101:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L101
L158:
  mov    0xc(%rsp),%edx
  add    $0xa,%r14
  cmp    %edx,%r13d
  jl     L204
  test   %edx,%edx
  jle    L213
  lea    -0x1(%rdx),%edi
  mov    %edx,%ecx
  mov    $0x0,%eax
L182:
  movl   $0x0,0x10(%rsp,%rax,4)
  movl   $0x0,0x40(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L182
  lea    0x10(%rsp),%rsi
  lea    0x0(,%rdi,4),%rax
  add    %rax,%rdi
  lea    0x98(%rsp,%rdi,8),%rcx
  lea    0x14(%rsp,%rax,1),%r9
  mov    %edx,%edx
  imul   $0xffffffffffffffd8,%rdx,%rdi
L133:
  mov    %rsi,%r8
  mov    (%rsi),%edx
  lea    (%rdi,%rcx,1),%rax
L7:
  add    (%rax),%edx
  add    $0x28,%rax
  cmp    %rcx,%rax
  jne    L7
  mov    %edx,(%r8)
  add    $0x4,%rsi
  add    $0x4,%rcx
  cmp    %r9,%rsi
  jne    L133
L213:
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r13d
  lea    D16(%rip),%r14
  cmpl   $0x0,0xc(%rsp)
  jg     L113
L77:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L194:
  lea    0x1(%rbp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,0x40(%rsp,%rbp,4)
  jmp    L68
L117:
  add    $0x28,%rax
  cmp    %rdx,%rax
  je     L125
L9:
  cmpl   $0x1,(%rax)
  jne    L117
  subl   $0x1,(%rbx)
  jmp    L117
L125:
  add    $0x1,%rbp
  add    $0x4,%r12
  cmp    %ebp,%ecx
  jle    L190
L206:
  mov    %r12,%rbx
  cmpl   $0x0,(%r12)
  jne    L68
  cmpl   $0x0,0x40(%rsp,%rbp,4)
  je     L194
L68:
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L125
  lea    0x70(%rsp,%rbp,4),%rax
  lea    -0x1(%rcx),%edx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x0(%rbp,%rdx,2),%rdx
  lea    0x98(%rsp,%rdx,4),%rdx
  jmp    L9
L190:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jle    L77
L113:
  lea    0x10(%rsp),%r12
  mov    $0x0,%ebp
  cmpl   $0x0,0xc(%rsp)
  jg     L206
  jmp    L190
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D44
type_guessed: string
name: disassemble_data
arguments: data_tag: D20
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D40
type_guessed: string
name: disassemble_data
arguments: data_tag: D55
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D44: Enter the no of vertices:

tool: D20: %d

tool: D6: Enter the adjacency matrix:

tool: D40: Enter row %d


tool: D55: 
The topological order is:

tool: D16: %d 

assistant: ```c
int main() {
  int i, j, k, n, a[10][10], indeg[10], flag[10], count = 0;
  printf("Enter the no of vertices:\n");
  scanf("%d", &n);
  printf("Enter the adjacency matrix:\n");
  for (i = 0; i < n; i++) {
    printf("Enter row %d\n", i + 1);
    for (j = 0; j < n; j++)
      scanf("%d", &a[i][j]);
  }
  for (i = 0; i < n; i++) {
    indeg[i] = 0;
    flag[i] = 0;
  }
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      indeg[i] = indeg[i] + a[j][i];
  printf("\nThe topological order is:");
  while (count < n) {
    for (k = 0; k < n; k++) {
      if ((indeg[k] == 0) && (flag[k] == 0)) {
        printf("%d ", (k + 1));
        flag[k] = 1;
      }
      for (i = 0; i < n; i++) {
        if (a[i][k] == 1)
          indeg[k]--;
      }
    }
    count++;
  }
  return 0;
}
```