ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<rand_array>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  lea    -0x1(%rbp),%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L35
  cmp    $0x2,%ebx
  jbe    L6
  mov    %ebp,%edx
  movdqa D4(%rip),%xmm0
  movdqa D19(%rip),%xmm2
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %rax,%rdx
  nopl   (%rax)
L73:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L73
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bpl
  je     L85
L13:
  movslq %eax,%rdx
  mov    %eax,(%r12,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L35
  add    $0x2,%eax
  mov    %edx,0x4(%r12,%rcx,1)
  cmp    %eax,%ebp
  jle    L85
  mov    %eax,0x8(%r12,%rcx,1)
L85:
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%r12,%rbx,4),%ecx
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%r12,%rbx,4)
  sub    $0x1,%rbx
  mov    %ecx,(%rax)
  test   %ebx,%ebx
  jg     L16
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L35:
  test   %ebx,%ebx
  jg     L85
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  xor    %eax,%eax
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D19
type_infered: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D19": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *rand_array(const int size) {
  int i;
  int *elements = malloc(sizeof(int) * size);
  for (i = 0; i < size; ++i)
    elements[i] = i;
  for (i = size - 1; i > 0; --i) {
    int w = rand() % i;
    int t = elements[i];
    elements[i] = elements[w];
    elements[w] = t;
  }
  return elements;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x74(%rbp)
  jmp    L13
L1:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x79(%rbp)
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x79(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x78(%rbp)
  subl   $0x1,-0x74(%rbp)
L13:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L1
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D5: 
Enter the string :

tool: D2: 
Reverse string is :%s

assistant: ```c
int main() {
  char str[100], temp;
  int i, j = 0;
  printf("\nEnter the string :");
  gets(str);
  i = 0;
  j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReverse string is :%s", str);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L20
  mov    %rsp,%rsi
  movslq %eax,%rdx
  add    %rbx,%rdx
L13:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rsi)
  mov    %dil,-0x1(%rdx)
  mov    %ecx,%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %r8d,%edi
  cmp    %edi,%ecx
  jg     L13
L20:
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D3: 
Enter the string :

tool: D9: 
Reverse string is :%s

assistant: ```c
int main() {
  char str[100], temp;
  int i, j = 0;
  printf("\nEnter the string :");
  gets(str);
  i = 0;
  j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReverse string is :%s", str);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L7
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L21
L7:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string

tool: D11: 
Enter the string :

tool: D16: 
Reverse string is :%s

assistant: ```c
int main() {
  char str[100], temp;
  int i, j = 0;
  printf("\nEnter the string :");
  gets(str);
  i = 0;
  j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReverse string is :%s", str);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L9
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L21
L9:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D9
type: string

tool: D15: 
Enter the string :

tool: D9: 
Reverse string is :%s

assistant: ```c
int main() {
  char str[100], temp;
  int i, j = 0;
  printf("\nEnter the string :");
  gets(str);
  i = 0;
  j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReverse string is :%s", str);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mag_pchecksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L3:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0xc(%rbp)
  subl   $0x1,-0x1c(%rbp)
L2:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L3
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int mag_pchecksum(const char *const buf, int len) {
  int csum = 0;
  const char *p = buf;
  for (; len; len--) {
    csum ^= *p++;
  }
  return csum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mag_pchecksum>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L13
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
L19:
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%edx
  xor    %edx,%eax
  cmp    %rcx,%rdi
  jne    L19
L13:
  ret
```

assistant: ```c
unsigned int mag_pchecksum(const char *const buf, int len) {
  int csum = 0;
  const char *p = buf;
  for (; len; len--) {
    csum ^= *p++;
  }
  return csum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mag_pchecksum>:
  endbr64
  test   %esi,%esi
  je     L1
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L8:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L8
  ret
  nop
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int mag_pchecksum(const char *const buf, int len) {
  int csum = 0;
  const char *p = buf;
  for (; len; len--) {
    csum ^= *p++;
  }
  return csum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mag_pchecksum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  je     L165
  lea    -0x1(%rsi),%ecx
  cmp    $0xe,%ecx
  jbe    L144
  mov    %esi,%ecx
  pxor   %xmm2,%xmm2
  pxor   %xmm6,%xmm6
  mov    %rdi,%rax
  shr    $0x4,%ecx
  pxor   %xmm4,%xmm4
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L51:
  movdqu (%rax),%xmm0
  movdqa %xmm6,%xmm3
  add    $0x10,%rax
  pcmpgtb %xmm0,%xmm3
  movdqa %xmm0,%xmm1
  punpcklbw %xmm3,%xmm1
  punpckhbw %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm0,%xmm3
  movdqa %xmm0,%xmm5
  punpcklwd %xmm3,%xmm5
  punpckhwd %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm1,%xmm3
  pxor   %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpcklwd %xmm3,%xmm5
  punpckhwd %xmm3,%xmm1
  pxor   %xmm5,%xmm1
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L51
  movdqa %xmm2,%xmm0
  mov    %edx,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffff0,%ecx
  pxor   %xmm0,%xmm2
  mov    %ecx,%r8d
  sub    %ecx,%edx
  movdqa %xmm2,%xmm0
  add    %r8,%rdi
  psrldq $0x4,%xmm0
  pxor   %xmm0,%xmm2
  movd   %xmm2,%eax
  cmp    %ecx,%esi
  je     L114
  lea    -0x1(%rdx),%ecx
L133:
  movsbl (%rdi),%esi
  xor    %esi,%eax
  test   %ecx,%ecx
  je     L114
  movsbl 0x1(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x2,%edx
  je     L114
  movsbl 0x2(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x3,%edx
  je     L114
  movsbl 0x3(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x4,%edx
  je     L114
  movsbl 0x4(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x5,%edx
  je     L114
  movsbl 0x5(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x6,%edx
  je     L114
  movsbl 0x6(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x7,%edx
  je     L114
  movsbl 0x7(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x8,%edx
  je     L114
  movsbl 0x8(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0x9,%edx
  je     L114
  movsbl 0x9(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0xa,%edx
  je     L114
  movsbl 0xa(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0xb,%edx
  je     L114
  movsbl 0xb(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0xc,%edx
  je     L114
  movsbl 0xc(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0xd,%edx
  je     L114
  movsbl 0xd(%rdi),%ecx
  xor    %ecx,%eax
  cmp    $0xe,%edx
  je     L114
  movsbl 0xe(%rdi),%edx
  xor    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L165:
  xor    %eax,%eax
L114:
  ret
L144:
  xor    %eax,%eax
  jmp    L133
```

assistant: ```c
unsigned int mag_pchecksum(const char *const buf, int len) {
  int csum = 0;
  const char *p = buf;
  for (; len; len--) {
    csum ^= *p++;
  }
  return csum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_pmac_test_vectors@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D1: Some PMAC test vectors



tool: D5: 



assistant: ```c
int main(void) {
  printf("Some PMAC test vectors\n\n");
  print_pmac_test_vectors();
  printf("\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_pmac_test_vectors@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string

tool: D10: Some PMAC test vectors



tool: D19: 



assistant: ```c
int main(void) {
  printf("Some PMAC test vectors\n\n");
  print_pmac_test_vectors();
  printf("\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_pmac_test_vectors@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D3: Some PMAC test vectors



tool: D4: 



assistant: ```c
int main(void) {
  printf("Some PMAC test vectors\n\n");
  print_pmac_test_vectors();
  printf("\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_pmac_test_vectors@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D17
type_infered: string

tool: D12: Some PMAC test vectors



tool: D17: 



assistant: ```c
int main(void) {
  printf("Some PMAC test vectors\n\n");
  print_pmac_test_vectors();
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<confidence2x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L35
L6:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <symrange@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x38(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L24
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L38
L24:
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L38:
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L35:
  cmpl   $0x1f,-0x24(%rbp)
  jle    L6
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D25
type_guessed: byte[8]
name: unpack_data
arguments: tag: D7
type_guessed: byte[8]
name: unpack_data
arguments: tag: D2
type_guessed: byte[8]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double confidence2x(double confidence) {
  double i, j, k, rj;
  int x;
  i = 0;
  j = 3;
  k = 6;
  for (x = 0; x < 32; x++) {
    rj = symrange(j);
    if (confidence > rj) {
      i = j;
    } else {
      k = j;
    }
    j = (i + k) / 2;
  }
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<confidence2x>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  mov    $0x20,%ebp
  movsd  D8(%rip),%xmm7
  movsd  %xmm7,0x10(%rsp)
  mov    D20(%rip),%rbx
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
L3:
  movq   %rbx,%xmm0
  call   <symrange@plt>
  movapd %xmm0,%xmm1
  movsd  0x18(%rsp),%xmm4
  cmpltsd %xmm4,%xmm1
  movsd  0x10(%rsp),%xmm2
  andpd  %xmm1,%xmm2
  movq   %rbx,%xmm5
  andnpd %xmm5,%xmm1
  movapd %xmm1,%xmm3
  orpd   %xmm2,%xmm3
  movsd  %xmm3,0x10(%rsp)
  cmpltsd %xmm4,%xmm0
  movq   %rbx,%xmm1
  andpd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm6
  andnpd %xmm6,%xmm0
  orpd   %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm3,%xmm0
  mulsd  D15(%rip),%xmm0
  movq   %xmm0,%rbx
  sub    $0x1,%ebp
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D20
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D15
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double confidence2x(double confidence) {
  double i, j, k, rj;
  int x;
  i = 0;
  j = 3;
  k = 6;
  for (x = 0; x < 32; x++) {
    rj = symrange(j);
    if (confidence > rj) {
      i = j;
    } else {
      k = j;
    }
    j = (i + k) / 2;
  }
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<confidence2x>:
  endbr64
  push   %rbx
  pxor   %xmm3,%xmm3
  mov    $0x20,%ebx
  sub    $0x20,%rsp
  movsd  D13(%rip),%xmm2
  movsd  D9(%rip),%xmm1
  movsd  %xmm0,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L2:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <symrange@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  cmpltsd 0x18(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm4
  andpd  %xmm0,%xmm2
  andnpd %xmm1,%xmm4
  andpd  %xmm0,%xmm1
  andnpd %xmm3,%xmm0
  movapd %xmm0,%xmm3
  orpd   %xmm4,%xmm2
  orpd   %xmm1,%xmm3
  movapd %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  D1(%rip),%xmm1
  sub    $0x1,%ebx
  jne    L2
  add    $0x20,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
data_type: byte[8]
name: disassemble_data
arguments: label: D9
data_type: byte[8]
name: disassemble_data
arguments: label: D1
data_type: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double confidence2x(double confidence) {
  double i, j, k, rj;
  int x;
  i = 0;
  j = 3;
  k = 6;
  for (x = 0; x < 32; x++) {
    rj = symrange(j);
    if (confidence > rj) {
      i = j;
    } else {
      k = j;
    }
    j = (i + k) / 2;
  }
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<confidence2x>:
  endbr64
  push   %r14
  pxor   %xmm4,%xmm4
  movq   %xmm0,%r14
  push   %rbx
  mov    $0x20,%ebx
  sub    $0x28,%rsp
  movsd  D30(%rip),%xmm3
  movsd  D20(%rip),%xmm1
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm3,0x18(%rsp)
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L27:
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  D22(%rip),%xmm0
  sub    $0x1,%ebx
  je     L29
  movsd  %xmm1,0x10(%rsp)
L25:
  movapd %xmm0,%xmm1
L49:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <symrange@plt>
  movq   %r14,%xmm2
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm2
  ja     L27
  movsd  0x10(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  D22(%rip),%xmm0
  sub    $0x1,%ebx
  je     L29
  movsd  %xmm1,0x18(%rsp)
  jmp    L25
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D30
datatype: byte[8]
name: unpack_data
arguments: data_tag: D20
datatype: byte[8]
name: unpack_data
arguments: data_tag: D22
datatype: byte[8]

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double confidence2x(double confidence) {
  double i, j, k, rj;
  int x;
  i = 0;
  j = 3;
  k = 6;
  for (x = 0; x < 32; x++) {
    rj = symrange(j);
    if (confidence > rj) {
      i = j;
    } else {
      k = j;
    }
    j = (i + k) / 2;
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcpy4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy3@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy4(char *dest, const char *src) {
  if ((*dest = *src) != 0)
    strcpy3(dest + 1, src + 1);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  jne    L9
L13:
  mov    %rbx,%rax
  pop    %rbx
  ret
L9:
  add    $0x1,%rsi
  lea    0x1(%rdi),%rdi
  call   <strcpy3@plt>
  jmp    L13
```

assistant: ```c
char *strcpy4(char *dest, const char *src) {
  if ((*dest = *src) != 0)
    strcpy3(dest + 1, src + 1);
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcpy4>:
  endbr64
  push   %r12
  movzbl (%rsi),%eax
  mov    %rdi,%r12
  mov    %al,(%rdi)
  test   %al,%al
  jne    L4
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rsi
  lea    0x1(%rdi),%rdi
  call   <strcpy3@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strcpy4(char *dest, const char *src) {
  if ((*dest = *src) != 0)
    strcpy3(dest + 1, src + 1);
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy4>:
  endbr64
  push   %r12
  movzbl (%rsi),%eax
  mov    %rdi,%r12
  mov    %al,(%rdi)
  test   %al,%al
  jne    L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rsi
  lea    0x1(%rdi),%rdi
  call   <strcpy3@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strcpy4(char *dest, const char *src) {
  if ((*dest = *src) != 0)
    strcpy3(dest + 1, src + 1);
  return dest;
}
```