ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<escape>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L46
  lea    D0(%rip),%rcx
  jmp    L89
  movb   $0x5c,(%rsi)
  movb   $0x61,0x1(%rsi)
  lea    0x2(%rsi),%rsi
L24:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L46
L89:
  lea    -0x7(%rdx),%eax
  cmp    $0x55,%al
  ja     L141
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  movb   $0x5c,(%rsi)
  movb   $0x62,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x66,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x6e,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x72,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x74,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x76,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x5c,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x27,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x22,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
  movb   $0x5c,(%rsi)
  movb   $0x3f,0x1(%rsi)
  lea    0x2(%rsi),%rsi
  jmp    L24
L141:
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L24
L46:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void escape(char *source, char *target) {
  while (*source != '\0') {
    switch (*source) {
    case '\a':
      *target++ = '\\';
      *target++ = 'a';
      break;
    case '\b':
      *target++ = '\\';
      *target++ = 'b';
      break;
    case '\f':
      *target++ = '\\';
      *target++ = 'f';
      break;
    case '\n':
      *target++ = '\\';
      *target++ = 'n';
      break;
    case '\r':
      *target++ = '\\';
      *target++ = 'r';
      break;
    case '\t':
      *target++ = '\\';
      *target++ = 't';
      break;
    case '\v':
      *target++ = '\\';
      *target++ = 'v';
      break;
    case '\\':
      *target++ = '\\';
      *target++ = '\\';
      break;
    case '\'':
      *target++ = '\\';
      *target++ = '\'';
      break;
    case '\"':
      *target++ = '\\';
      *target++ = '\"';
      break;
    case '\?':
      *target++ = '\\';
      *target++ = '?';
      break;
    default:
      *target++ = *source;
    }
    source++;
  }
  *target = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<escape>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L39
  lea    D9(%rip),%rcx
  nopw   0x0(%rax,%rax,1)
L1:
  lea    -0x7(%rdx),%eax
  cmp    $0x55,%al
  ja     L115
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L115:
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  cs nopw 0x0(%rax,%rax,1)
L22:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L1
L39:
  movb   $0x0,(%rsi)
  ret
  mov    $0x5c5c,%r9d
  add    $0x2,%rsi
  mov    %r9w,-0x2(%rsi)
  jmp    L22
  nopl   0x0(%rax)
  mov    $0x3f5c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x275c,%r8d
  add    $0x2,%rsi
  mov    %r8w,-0x2(%rsi)
  jmp    L22
  nopl   0x0(%rax)
  mov    $0x225c,%edx
  add    $0x2,%rsi
  mov    %dx,-0x2(%rsi)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x725c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
  nop
  mov    $0x665c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x765c,%r10d
  add    $0x2,%rsi
  mov    %r10w,-0x2(%rsi)
  jmp    L22
  nopl   0x0(%rax)
  mov    $0x6e5c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x745c,%r11d
  add    $0x2,%rsi
  mov    %r11w,-0x2(%rsi)
  jmp    L22
  nopl   0x0(%rax)
  mov    $0x625c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x615c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L22
```

assistant: ```c
void escape(char *source, char *target) {
  while (*source != '\0') {
    switch (*source) {
    case '\a':
      *target++ = '\\';
      *target++ = 'a';
      break;
    case '\b':
      *target++ = '\\';
      *target++ = 'b';
      break;
    case '\f':
      *target++ = '\\';
      *target++ = 'f';
      break;
    case '\n':
      *target++ = '\\';
      *target++ = 'n';
      break;
    case '\r':
      *target++ = '\\';
      *target++ = 'r';
      break;
    case '\t':
      *target++ = '\\';
      *target++ = 't';
      break;
    case '\v':
      *target++ = '\\';
      *target++ = 'v';
      break;
    case '\\':
      *target++ = '\\';
      *target++ = '\\';
      break;
    case '\'':
      *target++ = '\\';
      *target++ = '\'';
      break;
    case '\"':
      *target++ = '\\';
      *target++ = '\"';
      break;
    case '\?':
      *target++ = '\\';
      *target++ = '?';
      break;
    default:
      *target++ = *source;
    }
    source++;
  }
  *target = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<escape>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  lea    D2(%rip),%rcx
  nopw   0x0(%rax,%rax,1)
L7:
  lea    -0x7(%rdx),%eax
  cmp    $0x55,%al
  ja     L36
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L36:
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  cs nopw 0x0(%rax,%rax,1)
L29:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L7
L5:
  movb   $0x0,(%rsi)
  ret
  mov    $0x5c5c,%r9d
  add    $0x2,%rsi
  mov    %r9w,-0x2(%rsi)
  jmp    L29
  nopl   0x0(%rax)
  mov    $0x3f5c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
  mov    $0x275c,%r8d
  add    $0x2,%rsi
  mov    %r8w,-0x2(%rsi)
  jmp    L29
  nopl   0x0(%rax)
  mov    $0x225c,%edx
  add    $0x2,%rsi
  mov    %dx,-0x2(%rsi)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
  mov    $0x725c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
  nop
  mov    $0x665c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
  mov    $0x765c,%r10d
  add    $0x2,%rsi
  mov    %r10w,-0x2(%rsi)
  jmp    L29
  nopl   0x0(%rax)
  mov    $0x6e5c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
  mov    $0x745c,%r11d
  add    $0x2,%rsi
  mov    %r11w,-0x2(%rsi)
  jmp    L29
  nopl   0x0(%rax)
  mov    $0x625c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
  nopw   0x0(%rax,%rax,1)
  mov    $0x615c,%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  jmp    L29
```

assistant: ```c
void escape(char *source, char *target) {
  while (*source != '\0') {
    switch (*source) {
    case '\a':
      *target++ = '\\';
      *target++ = 'a';
      break;
    case '\b':
      *target++ = '\\';
      *target++ = 'b';
      break;
    case '\f':
      *target++ = '\\';
      *target++ = 'f';
      break;
    case '\n':
      *target++ = '\\';
      *target++ = 'n';
      break;
    case '\r':
      *target++ = '\\';
      *target++ = 'r';
      break;
    case '\t':
      *target++ = '\\';
      *target++ = 't';
      break;
    case '\v':
      *target++ = '\\';
      *target++ = 'v';
      break;
    case '\\':
      *target++ = '\\';
      *target++ = '\\';
      break;
    case '\'':
      *target++ = '\\';
      *target++ = '\'';
      break;
    case '\"':
      *target++ = '\\';
      *target++ = '\"';
      break;
    case '\?':
      *target++ = '\\';
      *target++ = '?';
      break;
    default:
      *target++ = *source;
    }
    source++;
  }
  *target = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L19
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D15: %d

tool: D3: %d


assistant: ```c
int main() {
  int a = 1, X;
  scanf("%d", &X);
  while (a <= X) {
    printf("%d\n", a);
    a = a + 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L11
  mov    $0x1,%ebx
  lea    D8(%rip),%rbp
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L5
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D19: %d

tool: D8: %d


assistant: ```c
int main() {
  int a = 1, X;
  scanf("%d", &X);
  while (a <= X) {
    printf("%d\n", a);
    a = a + 2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
  nop
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L0
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D3
datatype: string

tool: D1: %d

tool: D3: %d


assistant: ```c
int main() {
  int a = 1, X;
  scanf("%d", &X);
  while (a <= X) {
    printf("%d\n", a);
    a = a + 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L27
  mov    $0x1,%ebx
  lea    D4(%rip),%rbp
  nop
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L13
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D4
data_type: string

tool: D10: %d

tool: D4: %d


assistant: ```c
int main() {
  int a = 1, X;
  scanf("%d", &X);
  while (a <= X) {
    printf("%d\n", a);
    a = a + 2;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t1_init_ctxno_zc>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  shr    $0x7,%ecx
  and    $0x1,%ecx
  mov    %edi,%eax
  shr    $0x5,%eax
  and    $0x1,%eax
  add    %eax,%ecx
  shr    $0x4,%edi
  and    $0x1,%edi
  mov    %edx,%eax
  shr    $0x6,%eax
  and    $0x1,%eax
  add    %eax,%edi
  mov    %edx,%eax
  shr    $0x3,%eax
  and    $0x1,%eax
  mov    %edx,%r8d
  and    $0x1,%r8d
  add    %r8d,%eax
  mov    %edx,%r8d
  shr    %r8d
  and    $0x1,%r8d
  add    %r8d,%eax
  shr    $0x2,%edx
  and    $0x1,%edx
  add    %edx,%eax
  cmp    $0x2,%esi
  je     L128
  jg     L26
  cmp    $0x1,%esi
  ja     L58
L25:
  test   %ecx,%ecx
  jne    L102
  test   %edi,%edi
  jne    L131
  test   %eax,%eax
  je     L153
  cmp    $0x1,%eax
  mov    $0x2,%edx
  cmovne %edx,%eax
  jmp    L153
L26:
  cmp    $0x3,%esi
  jne    L144
  add    %edi,%ecx
  test   %eax,%eax
  jne    L90
  mov    %ecx,%eax
  test   %ecx,%ecx
  je     L153
  cmp    $0x1,%ecx
  mov    $0x2,%eax
  cmove  %ecx,%eax
  jmp    L153
L144:
  mov    $0x0,%eax
L153:
  add    $0x1,%eax
  ret
L128:
  mov    %ecx,%edx
  mov    %edi,%ecx
  mov    %edx,%edi
  jmp    L25
L131:
  cmp    $0x1,%edi
  setne  %al
  movzbl %al,%eax
  add    $0x3,%eax
  jmp    L153
L102:
  cmp    $0x1,%ecx
  je     L179
  mov    $0x8,%eax
  jmp    L153
L179:
  cmp    $0x1,%eax
  mov    $0x5,%eax
  sbb    $0xffffffff,%eax
  test   %edi,%edi
  mov    $0x7,%edx
  cmovne %edx,%eax
  jmp    L153
L90:
  cmp    $0x1,%eax
  je     L178
  cmp    $0x1,%ecx
  mov    $0x6,%edx
  sbb    $0xffffffff,%edx
  cmp    $0x2,%eax
  mov    $0x8,%eax
  cmove  %edx,%eax
  jmp    L153
L178:
  mov    %esi,%eax
  test   %ecx,%ecx
  je     L153
  cmp    $0x1,%ecx
  setne  %al
  movzbl %al,%eax
  add    $0x4,%eax
  jmp    L153
L58:
  mov    $0x0,%eax
  jmp    L153
```

assistant: ```c
int t1_init_ctxno_zc(int f, int orient) {
  int h, v, d, n, t, hv;
  n = 0;
  h = ((f & 0x0080) != 0) + ((f & 0x0020) != 0);
  v = ((f & 0x0010) != 0) + ((f & 0x0040) != 0);
  d = ((f & 0x0008) != 0) + ((f & 0x0001) != 0) + ((f & 0x0002) != 0) + ((f & 0x0004) != 0);
  switch (orient) {
  case 2:
    t = h;
    h = v;
    v = t;
  case 0:
  case 1:
    if (!h) {
      if (!v) {
        if (!d)
          n = 0;
        else if (d == 1)
          n = 1;
        else
          n = 2;
      } else if (v == 1) {
        n = 3;
      } else {
        n = 4;
      }
    } else if (h == 1) {
      if (!v) {
        if (!d)
          n = 5;
        else
          n = 6;
      } else {
        n = 7;
      }
    } else
      n = 8;
    break;
  case 3:
    hv = h + v;
    if (!d) {
      if (!hv) {
        n = 0;
      } else if (hv == 1) {
        n = 1;
      } else {
        n = 2;
      }
    } else if (d == 1) {
      if (!hv) {
        n = 3;
      } else if (hv == 1) {
        n = 4;
      } else {
        n = 5;
      }
    } else if (d == 2) {
      if (!hv) {
        n = 6;
      } else {
        n = 7;
      }
    } else {
      n = 8;
    }
    break;
  }
  return ((0 + 1) + n);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<msleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L15
L19:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L15:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void msleep(int ms) {
  while (ms--) {
    usleep(1000);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msleep>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  je     L16
L8:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  jne    L8
L16:
  pop    %rbx
  ret
```

assistant: ```c
void msleep(int ms) {
  while (ms--) {
    usleep(1000);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<msleep>:
  endbr64
  test   %edi,%edi
  je     L3
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void msleep(int ms) {
  while (ms--) {
    usleep(1000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msleep>:
  endbr64
  test   %edi,%edi
  je     L16
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  sub    $0x1,%ebx
  jne    L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
void msleep(int ms) {
  while (ms--) {
    usleep(1000);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<authString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  je     L7
  cmpq   $0x0,-0x48(%rbp)
  jne    L8
L7:
  mov    $0x0,%eax
  jmp    L22
L8:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <base64Dup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
L22:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string

tool: D19: :

tool: D18: 


assistant: ```c
char *authString(char *header, char *user, char *password) {
  char *ret = NULL;
  int templen;
  char *temp;
  char *temp64;
  if (!user || !password)
    return NULL;
  templen = strlen(user) + strlen(password) + 2;
  temp = malloc(templen);
  strcpy(temp, user);
  strcat(temp, ":");
  strcat(temp, password);
  temp64 = base64Dup(temp);
  free(temp);
  ret = malloc(strlen(temp64) + strlen(header) + 3);
  strcpy(ret, header);
  strcat(ret, temp64);
  strcat(ret, "\r\n");
  free(temp64);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<authString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L8
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L8
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <base64Dup@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x3(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L25:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    $0x0,%ebx
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D12: :

tool: D13: 


assistant: ```c
char *authString(char *header, char *user, char *password) {
  char *ret = NULL;
  int templen;
  char *temp;
  char *temp64;
  if (!user || !password)
    return NULL;
  templen = strlen(user) + strlen(password) + 2;
  temp = malloc(templen);
  strcpy(temp, user);
  strcat(temp, ":");
  strcat(temp, password);
  temp64 = base64Dup(temp);
  free(temp);
  ret = malloc(strlen(temp64) + strlen(header) + 3);
  strcpy(ret, header);
  strcat(ret, temp64);
  strcat(ret, "\r\n");
  free(temp64);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<authString>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L15
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L15
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D13(%rip),%rsi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <base64Dup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <free@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x3(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D13: :

tool: D14: 


assistant: ```c
char *authString(char *header, char *user, char *password) {
  char *ret = NULL;
  int templen;
  char *temp;
  char *temp64;
  if (!user || !password)
    return NULL;
  templen = strlen(user) + strlen(password) + 2;
  temp = malloc(templen);
  strcpy(temp, user);
  strcat(temp, ":");
  strcat(temp, password);
  temp64 = base64Dup(temp);
  free(temp);
  ret = malloc(strlen(temp64) + strlen(header) + 3);
  strcpy(ret, header);
  strcat(ret, temp64);
  strcat(ret, "\r\n");
  free(temp64);
  return ret;
}
```