ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_csi>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  jmp    L69
  xchg   %ax,%ax
L16:
  cmp    $0x5b,%al
  jne    L46
  test   %ebx,%ebx
  jne    L9
L46:
  cmp    $0x1b,%al
  sete   %al
  xor    $0x1,%ebx
  and    %eax,%ebx
L69:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L16
L9:
  mov    $0x1,%ebx
  lea    -0x1(%rsp),%rbp
  jmp    L42
  nopl   0x0(%rax)
L83:
  add    $0x1,%rbx
  cmp    $0x20,%rbx
  je     L56
L42:
  xor    %eax,%eax
  call   <getchar@plt>
  movslq %ebx,%rdx
  mov    %al,0x0(%rbp,%rbx,1)
  sub    $0x40,%eax
  cmp    $0x3e,%al
  ja     L83
L49:
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <strdup@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  mov    $0x20,%edx
  jmp    L49
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_csi() {
  char c;
  bool in_esc = false;
  while ((c = getchar())) {
    if (c == 0x9b)
      break;
    if (in_esc && c == 0x5b)
      break;
    if (!in_esc && c == 0x1b)
      in_esc = true;
    else
      in_esc = false;
  }
  char csi[32];
  int i = 0;
  for (; i < sizeof(csi) - 1; i++) {
    c = csi[i] = getchar();
    if (c >= 0x40 && c <= 0x7e)
      break;
  }
  csi[++i] = 0;
  return strdup(csi);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_csi>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  jmp    L64
  xchg   %ax,%ax
L89:
  cmp    $0x5b,%al
  jne    L57
  test   %ebx,%ebx
  jne    L36
L57:
  cmp    $0x1b,%al
  sete   %al
  xor    $0x1,%ebx
  and    %eax,%ebx
L64:
  xor    %eax,%eax
  call   <getchar@plt>
  test   %al,%al
  jne    L89
L36:
  mov    $0x1,%ebx
  lea    -0x1(%rsp),%rbp
  jmp    L80
  nopl   0x0(%rax)
L63:
  add    $0x1,%rbx
  cmp    $0x20,%rbx
  je     L34
L80:
  xor    %eax,%eax
  call   <getchar@plt>
  movslq %ebx,%rdx
  mov    %al,0x0(%rbp,%rbx,1)
  sub    $0x40,%eax
  cmp    $0x3e,%al
  ja     L63
L58:
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <strdup@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0x20,%edx
  jmp    L58
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_csi() {
  char c;
  bool in_esc = false;
  while ((c = getchar())) {
    if (c == 0x9b)
      break;
    if (in_esc && c == 0x5b)
      break;
    if (!in_esc && c == 0x1b)
      in_esc = true;
    else
      in_esc = false;
  }
  char csi[32];
  int i = 0;
  for (; i < sizeof(csi) - 1; i++) {
    c = csi[i] = getchar();
    if (c >= 0x40 && c <= 0x7e)
      break;
  }
  csi[++i] = 0;
  return strdup(csi);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drwav__is_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int drwav__is_little_endian() {
  int n = 1;
  return (*(char *)&n) == 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drwav__is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int drwav__is_little_endian() {
  int n = 1;
  return (*(char *)&n) == 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drwav__is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int drwav__is_little_endian() {
  int n = 1;
  return (*(char *)&n) == 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<drwav__is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int drwav__is_little_endian() {
  int n = 1;
  return (*(char *)&n) == 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intervalCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L6
  mov    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  add    $0x8,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int intervalCount(int nsegs, int *intervals) {
  int retval;
  retval = intervals[1] - intervals[0];
  if (nsegs > 1) {
    retval += intervals[3] - intervals[2];
  }
  return (retval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<intervalCount>:
  endbr64
  mov    0x4(%rsi),%eax
  sub    (%rsi),%eax
  cmp    $0x1,%edi
  jle    L8
  add    0xc(%rsi),%eax
  sub    0x8(%rsi),%eax
L8:
  ret
```

assistant: ```c
int intervalCount(int nsegs, int *intervals) {
  int retval;
  retval = intervals[1] - intervals[0];
  if (nsegs > 1) {
    retval += intervals[3] - intervals[2];
  }
  return (retval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intervalCount>:
  endbr64
  mov    0x4(%rsi),%eax
  sub    (%rsi),%eax
  cmp    $0x1,%edi
  jle    L7
  add    0xc(%rsi),%eax
  sub    0x8(%rsi),%eax
L7:
  ret
```

assistant: ```c
int intervalCount(int nsegs, int *intervals) {
  int retval;
  retval = intervals[1] - intervals[0];
  if (nsegs > 1) {
    retval += intervals[3] - intervals[2];
  }
  return (retval);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<intervalCount>:
  endbr64
  mov    0x4(%rsi),%eax
  sub    (%rsi),%eax
  cmp    $0x1,%edi
  jle    L5
  add    0xc(%rsi),%eax
  sub    0x8(%rsi),%eax
L5:
  ret
```

assistant: ```c
int intervalCount(int nsegs, int *intervals) {
  int retval;
  retval = intervals[1] - intervals[0];
  if (nsegs > 1) {
    retval += intervals[3] - intervals[2];
  }
  return (retval);
}
```
user: What is the c source code of the assembly code below:

```asm
<chk_html_colorcode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  je     L28
  mov    $0xffffffff,%eax
  jmp    L42
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L42
L21:
  addl   $0x1,-0x4(%rbp)
L59:
  cmpl   $0x5,-0x4(%rbp)
  jle    L49
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
int chk_html_colorcode(const char *color) {
  int i;
  if (strlen(color) != 6)
    return -1;
  for (i = 0; i < 6; i++)
    if (isxdigit(color[i]) == 0)
      return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chk_html_colorcode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x6,%eax
  jne    L8
  mov    %rbp,%rbx
  add    $0x6,%rbp
L28:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L40
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L28
  mov    $0x0,%eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L38
L40:
  mov    $0xffffffff,%eax
  jmp    L38
```

assistant: ```c
int chk_html_colorcode(const char *color) {
  int i;
  if (strlen(color) != 6)
    return -1;
  for (i = 0; i < 6; i++)
    if (isxdigit(color[i]) == 0)
      return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chk_html_colorcode>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x6,%eax
  jne    L21
  lea    0x6(%rbx),%rbp
L29:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int chk_html_colorcode(const char *color) {
  int i;
  if (strlen(color) != 6)
    return -1;
  for (i = 0; i < 6; i++)
    if (isxdigit(color[i]) == 0)
      return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chk_html_colorcode>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x6,%eax
  jne    L20
  lea    0x6(%rbx),%rbp
L29:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L20
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int chk_html_colorcode(const char *color) {
  int i;
  if (strlen(color) != 6)
    return -1;
  for (i = 0; i < 6; i++)
    if (isxdigit(color[i]) == 0)
      return -1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x3e7,-0x28(%rbp)
  jmp    L50
L45:
  movl   $0x3e7,-0x24(%rbp)
  jmp    L69
L28:
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  lea    -0x16(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x16(%rbp),%rdx
  lea    -0xf(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0xf(%rbp),%rax
  mov    %rax,%rdi
  call   <strrev@plt>
  lea    -0xf(%rbp),%rdx
  lea    -0x16(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L64
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L64:
  subl   $0x1,-0x24(%rbp)
L69:
  cmpl   $0x63,-0x24(%rbp)
  jg     L28
  subl   $0x1,-0x28(%rbp)
L50:
  cmpl   $0x63,-0x28(%rbp)
  jg     L45
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D15: %d

tool: D7: Answer = %d


assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int max = 0;
  char a[7];
  char b[7];
  for (x = 999; x > 99; x--) {
    for (y = 999; y > 99; y--) {
      z = x * y;
      sprintf(a, "%d", z);
      strcpy(b, a);
      strrev(b);
      if (strcmp(a, b) == 0) {
        if (z > max) {
          max = z;
        }
      }
    }
  }
  printf("Answer = %d\n", max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffc19,0xc(%rsp)
  mov    $0x0,%ebp
  lea    D16(%rip),%r15
L16:
  imul   $0xfffffc19,0xc(%rsp),%ebx
  mov    $0x384,%r14d
L14:
  lea    0x1a(%rsp),%r12
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    0x21(%rsp),%r13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strrev@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  cmp    %ebx,%ebp
  mov    %ebx,%eax
  cmovge %ebp,%eax
  test   %rdx,%rdx
  cmove  %eax,%ebp
  add    0xc(%rsp),%ebx
  sub    $0x1,%r14d
  jne    L14
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0xffffff9d,%eax
  jne    L16
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string

tool: D16: %d

tool: D13: Answer = %d


assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int max = 0;
  char a[7];
  char b[7];
  for (x = 999; x > 99; x--) {
    for (y = 999; y > 99; y--) {
      z = x * y;
      sprintf(a, "%d", z);
      strcpy(b, a);
      strrev(b);
      if (strcmp(a, b) == 0) {
        if (z > max) {
          max = z;
        }
      }
    }
  }
  printf("Answer = %d\n", max);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffc19,0xc(%rsp)
  lea    0x1a(%rsp),%r13
  lea    0x21(%rsp),%r12
L17:
  imul   $0xfffffc19,0xc(%rsp),%ebx
  mov    $0x384,%ebp
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strrev@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  cmp    %ebx,%r14d
  mov    %rax,%r9
  mov    %ebx,%eax
  cmovge %r14d,%eax
  test   %r9,%r9
  cmove  %eax,%r14d
  add    0xc(%rsp),%ebx
  sub    $0x1,%ebp
  jne    L14
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0xffffff9d,%eax
  jne    L17
  mov    %r14d,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D9: %d

tool: D17: Answer = %d


assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int max = 0;
  char a[7];
  char b[7];
  for (x = 999; x > 99; x--) {
    for (y = 999; y > 99; y--) {
      z = x * y;
      sprintf(a, "%d", z);
      strcpy(b, a);
      strrev(b);
      if (strcmp(a, b) == 0) {
        if (z > max) {
          max = z;
        }
      }
    }
  }
  printf("Answer = %d\n", max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffc19,0xc(%rsp)
  lea    0x1a(%rsp),%r13
  lea    0x21(%rsp),%r12
L15:
  imul   $0xfffffc19,0xc(%rsp),%ebx
  mov    $0x384,%ebp
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strrev@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  cmp    %ebx,%r14d
  mov    %rax,%r9
  mov    %ebx,%eax
  cmovge %r14d,%eax
  test   %r9,%r9
  cmove  %eax,%r14d
  add    0xc(%rsp),%ebx
  sub    $0x1,%ebp
  jne    L20
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0xffffff9d,%eax
  jne    L15
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D18: %d

tool: D1: Answer = %d


assistant: ```c
int main(void) {
  int x;
  int y;
  int z;
  int max = 0;
  char a[7];
  char b[7];
  for (x = 999; x > 99; x--) {
    for (y = 999; y > 99; y--) {
      z = x * y;
      sprintf(a, "%d", z);
      strcpy(b, a);
      strrev(b);
      if (strcmp(a, b) == 0) {
        if (z > max) {
          max = z;
        }
      }
    }
  }
  printf("Answer = %d\n", max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortHand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L34
L36:
  movl   $0x0,-0x18(%rbp)
  jmp    L19
L3:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getCardFace@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getCardFace@plt>
  cmp    %rax,%rbx
  jle    L43
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
L43:
  addl   $0x1,-0x18(%rbp)
L19:
  cmpl   $0x3,-0x18(%rbp)
  jle    L3
  addl   $0x1,-0x1c(%rbp)
L34:
  cmpl   $0x4,-0x1c(%rbp)
  jle    L36
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void sortHand(const int wDeck[][13], int hand[]) {
  int pass, j, temp;
  for (pass = 0; pass < 5; pass++) {
    for (j = 0; j < 5 - 1; j++) {
      if (getCardFace(wDeck, hand[j]) > getCardFace(wDeck, hand[j + 1])) {
        temp = hand[j];
        hand[j] = hand[j + 1];
        hand[j + 1] = temp;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sortHand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    $0x5,%r14d
  lea    0x10(%rsi),%r13
  jmp    L30
L43:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L52
L6:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <getCardFace@plt>
  mov    %rax,%rbp
  mov    0x4(%rbx),%esi
  mov    %r12,%rdi
  call   <getCardFace@plt>
  cmp    %rax,%rbp
  jle    L43
  mov    (%rbx),%eax
  mov    0x4(%rbx),%edx
  mov    %edx,(%rbx)
  mov    %eax,0x4(%rbx)
  jmp    L43
L52:
  sub    $0x1,%r14d
  je     L24
L30:
  mov    %r15,%rbx
  jmp    L6
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortHand(const int wDeck[][13], int hand[]) {
  int pass, j, temp;
  for (pass = 0; pass < 5; pass++) {
    for (j = 0; j < 5 - 1; j++) {
      if (getCardFace(wDeck, hand[j]) > getCardFace(wDeck, hand[j + 1])) {
        temp = hand[j];
        hand[j] = hand[j + 1];
        hand[j + 1] = temp;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sortHand>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    $0x5,%r14d
  push   %r13
  lea    0x10(%rsi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L0:
  mov    %r15,%rbx
L17:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <getCardFace@plt>
  mov    0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <getCardFace@plt>
  cmp    %rax,%rbp
  jle    L19
  mov    (%rbx),%eax
  mov    0x4(%rbx),%edx
  mov    %eax,0x4(%rbx)
  mov    %edx,(%rbx)
L19:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L17
  sub    $0x1,%r14d
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortHand(const int wDeck[][13], int hand[]) {
  int pass, j, temp;
  for (pass = 0; pass < 5; pass++) {
    for (j = 0; j < 5 - 1; j++) {
      if (getCardFace(wDeck, hand[j]) > getCardFace(wDeck, hand[j + 1])) {
        temp = hand[j];
        hand[j] = hand[j + 1];
        hand[j + 1] = temp;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortHand>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    $0x5,%r14d
  push   %r13
  lea    0x10(%rsi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L3:
  mov    %r15,%rbx
L16:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <getCardFace@plt>
  mov    0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <getCardFace@plt>
  cmp    %rax,%rbp
  jle    L15
  rolq   $0x20,(%rbx)
L15:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L16
  sub    $0x1,%r14d
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortHand(const int wDeck[][13], int hand[]) {
  int pass, j, temp;
  for (pass = 0; pass < 5; pass++) {
    for (j = 0; j < 5 - 1; j++) {
      if (getCardFace(wDeck, hand[j]) > getCardFace(wDeck, hand[j + 1])) {
        temp = hand[j];
        hand[j] = hand[j + 1];
        hand[j + 1] = temp;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L30
L36:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %dl,-0x17(%rbp,%rax,1)
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  cmp    $0xe,%eax
  jbe    L36
  lea    -0x17(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L31
L3:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x17(%rbp,%rax,1),%eax
  test   %al,%al
  je     L13
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L13:
  addl   $0x1,-0x1c(%rbp)
L31:
  mov    -0x1c(%rbp),%eax
  cmp    $0xe,%eax
  jbe    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  char b[15];
  for (i = 0; i < sizeof(b); i++) {
    b[i] = i;
  }
  f(b);
  for (i = 0; i < sizeof(b); i++) {
    if (0 != b[i])
      __builtin_abort();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L30:
  mov    %al,0x9(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0xf,%rax
  jne    L30
  lea    0x9(%rsp),%rbx
  mov    %rbx,%rdi
  call   <f@plt>
  lea    0x18(%rsp),%rbp
  jmp    L51
L33:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L43
L51:
  cmpb   $0x0,(%rbx)
  je     L33
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L33
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  char b[15];
  for (i = 0; i < sizeof(b); i++) {
    b[i] = i;
  }
  f(b);
  for (i = 0; i < sizeof(b); i++) {
    if (0 != b[i])
      __builtin_abort();
  }
  return 0;
}
```