ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L39
  lea    0x1(%rdi),%esi
  mov    $0x0,%edx
  mov    $0x0,%eax
L12:
  mov    %eax,%ecx
  imul   %eax,%ecx
  add    %ecx,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L12
L34:
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L39:
  mov    $0x0,%edx
  jmp    L34
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D0
data_type: string

tool: D11: Enter the number upto which the sum is to be calculated: 

tool: D29: %d

tool: D0: The sum is square of %d natural number is %d

assistant: ```c
int main() {
  int i, n, sum = 0, sq;
  printf("Enter the number upto which the sum is to be calculated: ");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    sq = i * i;
    sum = sum + sq;
  }
  printf("The sum is square of %d natural number is %d", n, sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  test   %r8d,%r8d
  js     L8
  lea    0x1(%r8),%esi
  xor    %edx,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %eax,%ecx
  imul   %eax,%ecx
  add    $0x1,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jne    L13
L19:
  xor    %eax,%eax
  mov    %r8d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  xor    %edx,%edx
  jmp    L19
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D25: Enter the number upto which the sum is to be calculated: 

tool: D16: %d

tool: D9: The sum is square of %d natural number is %d

assistant: ```c
int main() {
  int i, n, sum = 0, sq;
  printf("Enter the number upto which the sum is to be calculated: ");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    sq = i * i;
    sum = sum + sq;
  }
  printf("The sum is square of %d natural number is %d", n, sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L17
  lea    0x1(%rsi),%ecx
  cmp    $0x11,%esi
  jle    L78
  mov    %ecx,%edx
  movdqa D37(%rip),%xmm3
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  movdqa D24(%rip),%xmm4
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L11:
  movdqa %xmm3,%xmm0
  add    $0x1,%eax
  paddd  %xmm4,%xmm3
  movdqa %xmm0,%xmm2
  pmuludq %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm2
  paddd  %xmm2,%xmm1
  cmp    %edx,%eax
  jne    L11
  movdqa %xmm1,%xmm0
  mov    %ecx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  and    $0x3,%ecx
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%edx
  je     L13
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %eax,%ecx
  imul   %eax,%ecx
  add    $0x1,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jge    L40
L13:
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L17:
  xor    %edx,%edx
  jmp    L13
L78:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L40
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D24
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D44
datatype: string

tool: D9: Enter the number upto which the sum is to be calculated: 

tool: D6: %d

tool: {"D37": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D24": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D44: The sum is square of %d natural number is %d

assistant: ```c
int main() {
  int i, n, sum = 0, sq;
  printf("Enter the number upto which the sum is to be calculated: ");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    sq = i * i;
    sum = sum + sq;
  }
  printf("The sum is square of %d natural number is %d", n, sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L8:
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L20
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L20:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L5
L25:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L25
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D1: allocation failure 1 in matrix()

tool: D14: allocation failure 2 in matrix()

assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 0) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 0;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 0) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 0;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%r12
  sub    %rdi,%r12
  add    $0x1,%r12
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x0(,%r12,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L7:
  lea    0x0(,%r13,8),%rax
  mov    %rbx,%r15
  sub    %rax,%r15
  imul   %rbp,%r12
  lea    0x0(,%r12,4),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L49
L10:
  mov    0x8(%rsp),%rax
  shl    $0x2,%rax
  sub    %rax,(%rbx)
  cmp    %r13,%r14
  jle    L52
  shl    $0x2,%rbp
  lea    (%r15,%r14,8),%rdx
L35:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L35
L52:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  jmp    L7
L49:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D0: allocation failure 1 in matrix()

tool: D2: allocation failure 2 in matrix()

assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 0) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 0;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 0) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 0;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix>:
  endbr64
  push   %r15
  sub    %rdx,%rcx
  mov    %rdi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    %rdi,%r12
  lea    0x1(%rcx),%rbp
  push   %rbx
  add    $0x1,%r12
  lea    0x0(,%r12,8),%rdi
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L46
L47:
  imul   %rbp,%r12
  lea    0x0(,%r15,8),%rax
  mov    %rbx,%r8
  sub    %rax,%r8
  mov    %r8,0x8(%rsp)
  lea    0x0(,%r12,4),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,(%rbx)
  je     L30
L53:
  shl    $0x2,%r14
  sub    %r14,%rax
  mov    %rax,(%rbx)
  cmp    %r15,%r13
  jle    L23
  lea    0x0(,%rbp,4),%rcx
  mov    %rbx,%rax
  lea    (%r8,%r13,8),%rsi
L43:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L43
L23:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L46:
  lea    D19(%rip),%rdi
  call   <nrerror@plt>
  jmp    L47
  nopl   0x0(%rax)
L30:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  mov    (%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L53
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D3
datatype: string

tool: D19: allocation failure 1 in matrix()

tool: D3: allocation failure 2 in matrix()

assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 0) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 0;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 0) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 0;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%r15
  mov    %rdx,%r14
  push   %r13
  add    $0x1,%r15
  mov    %rdi,%r13
  push   %r12
  lea    0x0(,%r15,8),%rdi
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
L8:
  imul   %rbp,%r15
  lea    0x0(,%r13,8),%rax
  mov    %rbx,%r8
  sub    %rax,%r8
  mov    %r8,0x8(%rsp)
  lea    0x0(,%r15,4),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,(%rbx)
  je     L33
L25:
  shl    $0x2,%r14
  sub    %r14,%rax
  mov    %rax,(%rbx)
  cmp    %r13,%r12
  jle    L47
  shl    $0x2,%rbp
  lea    0x8(%rbx),%rdx
  lea    0x8(%r8,%r12,8),%rcx
  xchg   %ax,%ax
L39:
  add    %rbp,%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rcx,%rdx
  jne    L39
L47:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  jmp    L8
  nopl   0x0(%rax)
L33:
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
  mov    (%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string

tool: D3: allocation failure 1 in matrix()

tool: D5: allocation failure 2 in matrix()

assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 0) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 0;
  m -= nrl;
  m[nrl] = (float *)malloc((size_t)((nrow * ncol + 0) * sizeof(float)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 0;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_as_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float int_as_float(int i) {
  union {
    int i;
    float f;
  } u;
  u.i = i;
  return u.f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_as_float>:
  endbr64
  movd   %edi,%xmm0
  ret
```

assistant: ```c
float int_as_float(int i) {
  union {
    int i;
    float f;
  } u;
  u.i = i;
  return u.f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<int_as_float>:
  endbr64
  movd   %edi,%xmm0
  ret
```

assistant: ```c
float int_as_float(int i) {
  union {
    int i;
    float f;
  } u;
  u.i = i;
  return u.f;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2a,-0x2c(%rbp)
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movabs $0x6f57206f6c6c6548,%rax
  mov    $0x21646c72,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L2
L29:
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L2:
  cmpl   $0x10,-0x24(%rbp)
  jle    L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string

tool: {"D14": [0xd8,0x0f,0x49,0x40]}

tool: D27: LOCAL VAR ADDRESSES:
a -> %p
b -> %p


tool: D12: Char %d: %p


assistant: ```c
int main(void) {
  int a = 42, i;
  float b = 3.141592f;
  char c[17] = "Hello World!";
  printf("LOCAL VAR ADDRESSES:\na -> %p\nb -> %p\n", &a, &b);
  for (i = 0; i < 17; i++)
    printf("Char %d: %p\n", i, &c[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2a,0x8(%rsp)
  movl   $0x40490fd8,0xc(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  mov    $0x21646c72,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D17(%rip),%r12
L15:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0x11,%ebx
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string

tool: D19: LOCAL VAR ADDRESSES:
a -> %p
b -> %p


tool: D17: Char %d: %p


assistant: ```c
int main(void) {
  int a = 42, i;
  float b = 3.141592f;
  char c[17] = "Hello World!";
  printf("LOCAL VAR ADDRESSES:\na -> %p\nb -> %p\n", &a, &b);
  for (i = 0; i < 17; i++)
    printf("Char %d: %p\n", i, &c[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movdqa D25(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movl   $0x2a,0x8(%rsp)
  movl   $0x40490fd8,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  movb   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0x11,%ebx
  jne    L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: byte[16]

tool: D1: LOCAL VAR ADDRESSES:
a -> %p
b -> %p


tool: D18: Char %d: %p


tool: {"D25": [0x48,0x65,0x6c,0x6c,0x6f,0x20,0x57,0x6f,0x72,0x6c,0x64,0x21,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a = 42, i;
  float b = 3.141592f;
  char c[17] = "Hello World!";
  printf("LOCAL VAR ADDRESSES:\na -> %p\nb -> %p\n", &a, &b);
  for (i = 0; i < 17; i++)
    printf("Char %d: %p\n", i, &c[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movl   $0x2a,0x8(%rsp)
  movl   $0x40490fd8,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  movb   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0x11,%ebx
  jne    L12
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: byte[16]

tool: D24: LOCAL VAR ADDRESSES:
a -> %p
b -> %p


tool: D25: Char %d: %p


tool: {"D6": [0x48,0x65,0x6c,0x6c,0x6f,0x20,0x57,0x6f,0x72,0x6c,0x64,0x21,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a = 42, i;
  float b = 3.141592f;
  char c[17] = "Hello World!";
  printf("LOCAL VAR ADDRESSES:\na -> %p\nb -> %p\n", &a, &b);
  for (i = 0; i < 17; i++)
    printf("Char %d: %p\n", i, &c[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L18:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int addReverse(unsigned int added) {
  unsigned int reverse = 0, temp = added;
  while (temp != 0) {
    reverse *= 10;
    reverse += temp % 10;
    temp /= 10;
  }
  return added + reverse;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addReverse>:
  endbr64
  test   %edi,%edi
  je     L2
  mov    %edi,%ecx
  mov    $0x0,%esi
  mov    $0xcccccccd,%r10d
L15:
  lea    (%rsi,%rsi,4),%r9d
  mov    %ecx,%edx
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  mov    %ecx,%r8d
  sub    %esi,%r8d
  lea    (%r8,%r9,2),%esi
  mov    %ecx,%r8d
  mov    %edx,%ecx
  cmp    $0x9,%r8d
  ja     L15
L4:
  lea    (%rdi,%rsi,1),%eax
  ret
L2:
  mov    %edi,%esi
  jmp    L4
```

assistant: ```c
unsigned int addReverse(unsigned int added) {
  unsigned int reverse = 0, temp = added;
  while (temp != 0) {
    reverse *= 10;
    reverse += temp % 10;
    temp /= 10;
  }
  return added + reverse;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<addReverse>:
  endbr64
  test   %edi,%edi
  je     L0
  mov    %edi,%ecx
  xor    %esi,%esi
  mov    $0xcccccccd,%r10d
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ecx,%edx
  lea    (%rsi,%rsi,4),%r9d
  mov    %ecx,%r8d
  imul   %r10,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%r8d
  lea    (%r8,%r9,2),%esi
  mov    %ecx,%r8d
  mov    %edx,%ecx
  cmp    $0x9,%r8d
  ja     L4
  lea    (%rdi,%rsi,1),%eax
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int addReverse(unsigned int added) {
  unsigned int reverse = 0, temp = added;
  while (temp != 0) {
    reverse *= 10;
    reverse += temp % 10;
    temp /= 10;
  }
  return added + reverse;
}
```