ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<imprimirRegiao>:
  endbr64
  test   %edi,%edi
  je     L2
  test   %esi,%esi
  je     L2
  test   %edi,%edi
  jle    L18
  test   %esi,%esi
  jle    L16
  lea    D25(%rip),%rdi
  jmp    1050 <printf@plt>
L18:
  test   %esi,%esi
  jle    L43
  lea    D41(%rip),%rdi
  jmp    1050 <printf@plt>
L2:
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L43:
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L16:
  lea    D33(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D41
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string

tool: D25: NE


tool: D41: NO


tool: D1: divisa


tool: D0: SO


tool: D33: SE


assistant: ```c
void imprimirRegiao(int x, int y) {
  if (x == 0 || y == 0) {
    printf("divisa\n");
  } else {
    if (x > 0) {
      if (y > 0) {
        printf("NE\n");
      } else {
        printf("SE\n");
      }
    } else {
      if (y > 0) {
        printf("NO\n");
      } else {
        printf("SO\n");
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpl_dict>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x9,(%rax)
  addq   $0x1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L13
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cpl_expr@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cpl_expr@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_space@plt>
  mov    -0x4(%rbp),%eax
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x7d,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int cpl_dict(char **expr, char *bin) {
  unsigned int length, total = 2;
  bin[0] = 9;
  bin++;
  (*expr)++;
  while (**expr != '}') {
    length = cpl_expr(expr, bin);
    bin += length;
    total += length;
    (*expr)++;
    length = cpl_expr(expr, bin);
    skip_space(expr);
    bin += length;
    total += length;
  }
  (*expr)++;
  *bin = '\x00';
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpl_dict>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movb   $0x9,(%rsi)
  lea    0x1(%rsi),%rbx
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  cmpb   $0x7d,0x1(%rdx)
  je     L28
  mov    $0x2,%r13d
L22:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <cpl_expr@plt>
  mov    %eax,%ebp
  mov    %eax,%r14d
  add    %rbx,%r14
  addq   $0x1,(%r12)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <cpl_expr@plt>
  mov    %eax,%ebx
  add    %eax,%ebp
  mov    %r12,%rdi
  call   <skip_space@plt>
  mov    %ebx,%ebx
  add    %r14,%rbx
  add    %ebp,%r13d
  mov    (%r12),%rax
  cmpb   $0x7d,(%rax)
  jne    L22
L11:
  add    $0x1,%rax
  mov    %rax,(%r12)
  movb   $0x0,(%rbx)
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    $0x2,%r13d
  jmp    L11
```

assistant: ```c
unsigned int cpl_dict(char **expr, char *bin) {
  unsigned int length, total = 2;
  bin[0] = 9;
  bin++;
  (*expr)++;
  while (**expr != '}') {
    length = cpl_expr(expr, bin);
    bin += length;
    total += length;
    (*expr)++;
    length = cpl_expr(expr, bin);
    skip_space(expr);
    bin += length;
    total += length;
  }
  (*expr)++;
  *bin = '\x00';
  return total;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cpl_dict>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    0x1(%rsi),%r13
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  push   %rbx
  movb   $0x9,(%rsi)
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  cmpb   $0x7d,0x1(%rdx)
  je     L19
  nopl   0x0(%rax)
L8:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <cpl_expr@plt>
  addq   $0x1,(%r14)
  mov    %r14,%rdi
  mov    %eax,%ebx
  mov    %eax,%eax
  add    %rax,%r13
  mov    %r13,%rsi
  call   <cpl_expr@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <skip_space@plt>
  mov    (%r14),%rax
  add    %ebp,%ebx
  add    %rbp,%r13
  add    %ebx,%r12d
  cmpb   $0x7d,(%rax)
  jne    L8
L19:
  add    $0x1,%rax
  mov    %rax,(%r14)
  mov    %r12d,%eax
  movb   $0x0,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int cpl_dict(char **expr, char *bin) {
  unsigned int length, total = 2;
  bin[0] = 9;
  bin++;
  (*expr)++;
  while (**expr != '}') {
    length = cpl_expr(expr, bin);
    bin += length;
    total += length;
    (*expr)++;
    length = cpl_expr(expr, bin);
    skip_space(expr);
    bin += length;
    total += length;
  }
  (*expr)++;
  *bin = '\x00';
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpl_dict>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    0x1(%rsi),%r13
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  push   %rbx
  movb   $0x9,(%rsi)
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rdi)
  cmpb   $0x7d,0x1(%rdx)
  je     L18
  nopl   0x0(%rax)
L9:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <cpl_expr@plt>
  addq   $0x1,(%r14)
  mov    %r14,%rdi
  mov    %eax,%ebx
  mov    %eax,%eax
  add    %rax,%r13
  mov    %r13,%rsi
  call   <cpl_expr@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <skip_space@plt>
  mov    (%r14),%rax
  add    %ebp,%ebx
  add    %rbp,%r13
  add    %ebx,%r12d
  cmpb   $0x7d,(%rax)
  jne    L9
L18:
  add    $0x1,%rax
  mov    %rax,(%r14)
  mov    %r12d,%eax
  movb   $0x0,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int cpl_dict(char **expr, char *bin) {
  unsigned int length, total = 2;
  bin[0] = 9;
  bin++;
  (*expr)++;
  while (**expr != '}') {
    length = cpl_expr(expr, bin);
    bin += length;
    total += length;
    (*expr)++;
    length = cpl_expr(expr, bin);
    skip_space(expr);
    bin += length;
    total += length;
  }
  (*expr)++;
  *bin = '\x00';
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x12,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,-0x88(%rbp)
  movl   $0x1,-0xa4(%rbp)
  jmp    L32
L48:
  movl   $0x1,-0xa8(%rbp)
  jmp    L84
L3:
  mov    -0xa4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0xa0(%rbp,%rax,4),%ecx
  mov    -0xa8(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rsi
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  mov    -0xa0(%rbp,%rax,4),%eax
  add    %eax,%ecx
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  mov    %ecx,-0xa0(%rbp,%rax,4)
  addl   $0x1,-0xa8(%rbp)
L84:
  cmpl   $0x5,-0xa8(%rbp)
  jle    L3
  addl   $0x1,-0xa4(%rbp)
L32:
  cmpl   $0x5,-0xa4(%rbp)
  jle    L48
  movl   $0x1,-0xa4(%rbp)
  jmp    L73
L14:
  movl   $0x1,-0xa8(%rbp)
  jmp    L75
L66:
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0xa0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xa8(%rbp)
L75:
  cmpl   $0x5,-0xa8(%rbp)
  jle    L66
  addl   $0x1,-0xa4(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L73:
  cmpl   $0x5,-0xa4(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: %d 

assistant: ```c
int main() {
  int x, y, a[6][6] = {0, 0, 0, 0, 0, 0, 1};
  for (y = 1; y <= 5; y++)
    for (x = 1; x <= 5; x++)
      a[y][x] = a[y - 1][x] + a[y][x - 1];
  for (y = 1; y <= 5; y++, printf("\n"))
    for (x = 1; x <= 5; x++)
      printf("%d ", a[y][x]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x12,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x18(%rsp)
  mov    %rsp,%r13
  lea    0x2c(%rsp),%rcx
  lea    0xa4(%rsp),%rsi
L30:
  lea    -0x14(%rcx),%rax
L3:
  mov    (%rax),%edx
  add    -0x14(%rax),%edx
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L3
  add    $0x18,%rcx
  cmp    %rsi,%rcx
  jne    L30
  lea    0x18(%rsp),%rbp
  add    $0x90,%r13
  lea    D2(%rip),%r12
L31:
  mov    $0x1,%ebx
L20:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rbp
  cmp    %r13,%rbp
  jne    L31
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: %d 

assistant: ```c
int main() {
  int x, y, a[6][6] = {0, 0, 0, 0, 0, 0, 1};
  for (y = 1; y <= 5; y++)
    for (x = 1; x <= 5; x++)
      a[y][x] = a[y - 1][x] + a[y][x - 1];
  for (y = 1; y <= 5; y++, printf("\n"))
    for (x = 1; x <= 5; x++)
      printf("%d ", a[y][x]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x12,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%r13
  lea    0x2c(%rsp),%rsi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x18(%rsp)
  mov    $0xffffffffffffffe8,%rdi
L21:
  lea    -0x14(%rsi),%rax
  add    %ecx,%edx
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L40
L66:
  lea    (%rax,%rdi,1),%rdx
  add    $0x4,%rax
  mov    0x4(%rdx,%r8,1),%ecx
  mov    -0x4(%rax),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  cmp    %rsi,%rax
  jne    L66
L40:
  sub    $0x18,%rdi
  lea    0x18(%rax),%rsi
  add    $0x18,%r8
  cmp    $0xffffffffffffff70,%rdi
  je     L48
  mov    -0x28(%rsi),%ecx
  mov    -0x14(%rsi),%edx
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L48:
  lea    0x18(%rsp),%rbp
  add    $0x90,%r13
  lea    D5(%rip),%r12
L64:
  mov    $0x1,%ebx
L24:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L24
  mov    $0xa,%edi
  add    $0x18,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L64
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: %d 

assistant: ```c
int main() {
  int x, y, a[6][6] = {0, 0, 0, 0, 0, 0, 1};
  for (y = 1; y <= 5; y++)
    for (x = 1; x <= 5; x++)
      a[y][x] = a[y - 1][x] + a[y][x - 1];
  for (y = 1; y <= 5; y++, printf("\n"))
    for (x = 1; x <= 5; x++)
      printf("%d ", a[y][x]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xf,%ecx
  push   %r12
  lea    D54(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x18(%rsp),%rbp
  lea    0x90(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  movups %xmm0,0x1c(%rsp)
  movdqa D21(%rip),%xmm0
  movl   $0x1,0x2c(%rsp)
  movups %xmm0,0x34(%rsp)
  movdqa D50(%rip),%xmm0
  movl   $0x5,0x44(%rsp)
  movups %xmm0,0x4c(%rsp)
  movdqa D19(%rip),%xmm0
  movl   $0xf,0x5c(%rsp)
  movl   $0x0,(%rdi)
  movups %xmm0,0x64(%rsp)
  movdqa D25(%rip),%xmm0
  movl   $0x23,0x74(%rsp)
  movl   $0x46,0x8c(%rsp)
  movups %xmm0,0x7c(%rsp)
L12:
  mov    $0x1,%ebx
L7:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L7
  mov    $0xa,%edi
  add    $0x18,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L12
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D54
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D21
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D50
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D19
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D25
type_guessed: byte[16]

tool: D54: %d 

tool: {"D18": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D21": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D50": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D19": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: {"D25": [0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x23,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int x, y, a[6][6] = {0, 0, 0, 0, 0, 0, 1};
  for (y = 1; y <= 5; y++)
    for (x = 1; x <= 5; x++)
      a[y][x] = a[y - 1][x] + a[y][x - 1];
  for (y = 1; y <= 5; y++, printf("\n"))
    for (x = 1; x <= 5; x++)
      printf("%d ", a[y][x]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sock_bufferize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x10(%rbp)
  mov    %r9d,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L29
  cmpq   $0x0,0x10(%rbp)
  je     L19
  mov    0x18(%rbp),%eax
  lea    D6(%rip),%rdx
  mov    %eax,%esi
  mov    0x10(%rbp),%rdi
  call   <snprintf@plt>
  mov    0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L19:
  mov    $0xffffffff,%eax
  jmp    L17
L29:
  cmpl   $0x0,-0x24(%rbp)
  jne    L34
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L34:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: Not enough space in the temporary send buffer.

assistant: ```c
int sock_bufferize(const char *buffer, int size, char *tempbuf, int *offset, int totsize, int checkonly, char *errbuf, int errbuflen) {
  if ((*offset + size) > totsize) {
    if (errbuf) {
      snprintf(errbuf, errbuflen, "Not enough space in the temporary send buffer.");
      errbuf[errbuflen - 1] = 0;
    }
    return -1;
  };
  if (!checkonly)
    memcpy(tempbuf + (*offset), buffer, size);
  (*offset) += size;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sock_bufferize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rcx,%rbx
  mov    (%rcx),%ecx
  lea    (%rcx,%rsi,1),%esi
  cmp    %r8d,%esi
  jg     L17
  mov    %rdi,%rax
  test   %r9d,%r9d
  je     L24
L28:
  add    %ebp,(%rbx)
  mov    $0x0,%eax
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0xffffffff,%eax
  cmpq   $0x0,0x20(%rsp)
  je     L39
  lea    D1(%rip),%rdx
  mov    0x28(%rsp),%esi
  mov    0x20(%rsp),%rdi
  call   <snprintf@plt>
  movslq 0x28(%rsp),%rax
  mov    0x20(%rsp),%rbx
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    $0xffffffff,%eax
  jmp    L39
L24:
  movslq %ecx,%rcx
  lea    (%rdx,%rcx,1),%rdi
  mov    %ebp,%edx
  mov    %rax,%rsi
  call   <memcpy@plt>
  jmp    L28
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: Not enough space in the temporary send buffer.

assistant: ```c
int sock_bufferize(const char *buffer, int size, char *tempbuf, int *offset, int totsize, int checkonly, char *errbuf, int errbuflen) {
  if ((*offset + size) > totsize) {
    if (errbuf) {
      snprintf(errbuf, errbuflen, "Not enough space in the temporary send buffer.");
      errbuf[errbuflen - 1] = 0;
    }
    return -1;
  };
  if (!checkonly)
    memcpy(tempbuf + (*offset), buffer, size);
  (*offset) += size;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sock_bufferize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  movslq (%rcx),%rcx
  lea    (%rcx,%rsi,1),%eax
  cmp    %r8d,%eax
  jg     L45
  test   %r9d,%r9d
  je     L42
L15:
  mov    %eax,(%rbx)
  xor    %r12d,%r12d
L29:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %rdi,%r10
  mov    %esi,%ebp
  lea    (%rdx,%rcx,1),%rdi
  mov    %esi,%edx
  mov    %r10,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%eax
  add    %ebp,%eax
  jmp    L15
  nopl   0x0(%rax)
L45:
  cmpq   $0x0,0x20(%rsp)
  mov    $0xffffffff,%r12d
  je     L29
  mov    0x28(%rsp),%esi
  mov    0x20(%rsp),%rdi
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  movslq 0x28(%rsp),%rax
  mov    0x20(%rsp),%rbx
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L29
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: Not enough space in the temporary send buffer.

assistant: ```c
int sock_bufferize(const char *buffer, int size, char *tempbuf, int *offset, int totsize, int checkonly, char *errbuf, int errbuflen) {
  if ((*offset + size) > totsize) {
    if (errbuf) {
      snprintf(errbuf, errbuflen, "Not enough space in the temporary send buffer.");
      errbuf[errbuflen - 1] = 0;
    }
    return -1;
  };
  if (!checkonly)
    memcpy(tempbuf + (*offset), buffer, size);
  (*offset) += size;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sock_bufferize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  movslq (%rcx),%rcx
  lea    (%rcx,%rsi,1),%eax
  cmp    %r8d,%eax
  jg     L3
  test   %r9d,%r9d
  je     L37
L40:
  mov    %eax,(%rbx)
  xor    %r12d,%r12d
L19:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rdi,%r10
  mov    %esi,%ebp
  lea    (%rdx,%rcx,1),%rdi
  mov    %esi,%edx
  mov    %r10,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%eax
  add    %ebp,%eax
  jmp    L40
  nopl   0x0(%rax)
L3:
  cmpq   $0x0,0x20(%rsp)
  mov    $0xffffffff,%r12d
  je     L19
  mov    0x28(%rsp),%esi
  mov    0x20(%rsp),%rdi
  lea    D2(%rip),%rdx
  call   <snprintf@plt>
  movslq 0x28(%rsp),%rax
  mov    0x20(%rsp),%rbx
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L19
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: Not enough space in the temporary send buffer.

assistant: ```c
int sock_bufferize(const char *buffer, int size, char *tempbuf, int *offset, int totsize, int checkonly, char *errbuf, int errbuflen) {
  if ((*offset + size) > totsize) {
    if (errbuf) {
      snprintf(errbuf, errbuflen, "Not enough space in the temporary send buffer.");
      errbuf[errbuflen - 1] = 0;
    }
    return -1;
  };
  if (!checkonly)
    memcpy(tempbuf + (*offset), buffer, size);
  (*offset) += size;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L15
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L15:
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0xb4(%rbp)
  cmpl   $0x0,-0xb4(%rbp)
  jns    L17
L9:
  jmp    L9
L17:
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  int res;
  res = __infer_nondet_int();
  if (res < 0)
    while (1)
      ;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  js     L13
  add    $0x8,%rsp
  ret
L13:
  jmp    L13
```

assistant: ```c
int printf(const char *format, ...) {
  int res;
  res = __infer_nondet_int();
  if (res < 0)
    while (1)
      ;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  js     L18
  add    $0x8,%rsp
  ret
L18:
  jmp    L18
```

assistant: ```c
int printf(const char *format, ...) {
  int res;
  res = __infer_nondet_int();
  if (res < 0)
    while (1)
      ;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printf>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %eax,%eax
  js     L9
  add    $0x8,%rsp
  ret
L9:
  jmp    L9
```

assistant: ```c
int printf(const char *format, ...) {
  int res;
  res = __infer_nondet_int();
  if (res < 0)
    while (1)
      ;
  return res;
}
```