user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L26
  lea    0x14(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x1,%ebp
  lea    D35(%rip),%r13
L80:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0xc(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jge    L80
  mov    0x14(%rsp),%edx
  test   %eax,%eax
  jle    L36
  lea    -0x1(%rax),%ecx
  lea    0x18(%rsp,%rcx,4),%rsi
L179:
  mov    (%rbx),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rbx
  cmp    %rsi,%rbx
  jne    L179
  test   %edx,%edx
  js     L99
L69:
  mov    $0x0,%ecx
L110:
  movl   $0x0,0x330(%rsp,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jge    L110
  test   %eax,%eax
  jle    L176
L99:
  mov    $0x1,%ecx
L177:
  movslq 0x10(%rsp,%rcx,4),%rsi
  addl   $0x1,0x330(%rsp,%rsi,4)
  add    $0x1,%rcx
  cmp    %ecx,%eax
  jge    L177
  test   %edx,%edx
  jle    L23
L156:
  lea    0x334(%rsp),%rcx
  mov    $0x1,%esi
L64:
  mov    -0x4(%rcx),%edi
  add    %edi,(%rcx)
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %esi,%edx
  jge    L64
  test   %eax,%eax
  jle    L170
L23:
  cltq
L0:
  mov    0x10(%rsp,%rax,4),%esi
  movslq %esi,%rcx
  mov    0x330(%rsp,%rcx,4),%edx
  movslq %edx,%rdi
  mov    %esi,0x1a0(%rsp,%rdi,4)
  sub    $0x1,%edx
  mov    %edx,0x330(%rsp,%rcx,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L0
L170:
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L95
  mov    $0x1,%ebx
  lea    D38(%rip),%rbp
L113:
  mov    0x1a0(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L113
L95:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x4d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    0x14(%rsp),%edx
L36:
  test   %edx,%edx
  jns    L69
L176:
  test   %edx,%edx
  jg     L156
  jmp    L170
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D46
type_guessed: string
name: retrieve_data
arguments: label: D39
type_guessed: string
name: retrieve_data
arguments: label: D38
type_guessed: string

tool: D18: Enter the number of elements to be sorted: 

tool: D35: %d

tool: D46: Enter %d elements to be sorted: 

tool: D39: The sorted elements are: 

tool: D38: %d 

assistant: ```c
int main() {
  int A[100], B[100], C[100], i, n, k, j;
  printf("Enter the number of elements to be sorted: ");
  scanf("%d", &n);
  printf("Enter %d elements to be sorted: ", n);
  for (i = 1; i <= n; i++)
    scanf("%d", &A[i]);
  k = A[1];
  for (i = 1; i <= n; i++) {
    if (A[i] > k)
      k = A[i];
  }
  for (i = 0; i <= k; i++)
    C[i] = 0;
  for (j = 1; j <= n; j++)
    C[A[j]] = C[A[j]] + 1;
  for (i = 1; i <= k; i++)
    C[i] = C[i] + C[i - 1];
  for (j = n; j >= 1; j--) {
    B[C[A[j]]] = A[j];
    C[A[j]] = C[A[j]] - 1;
  }
  printf("The sorted elements are: ");
  for (i = 1; i <= n; i++)
    printf("%d ", B[i]);
  printf("\n");
  return 0;
}
```