ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x64(%rbp),%eax
  cmp    $0xf,%eax
  jg     L48
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L48:
  mov    -0x64(%rbp),%eax
  cmp    $0x11,%eax
  jg     L9
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    -0x64(%rbp),%eax
  cmp    $0x18,%eax
  jg     L43
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L43:
  mov    -0x64(%rbp),%eax
  cmp    $0x19,%eax
  jle    L47
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D37
datatype: string
name: read_data
arguments: label: D75
datatype: string
name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D73
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D89
datatype: string

tool: D23: Hey, what's your name?

tool: D37: %s

tool: D75: 
Ok, %s

tool: D36: , how old are you?

tool: D73: %d

tool: D24: You can't drive.

tool: D27: You can't vote

tool: D32: You can't rent a car.

tool: D89: You can do anything that's legal!

assistant: ```c
int main(int argc, char *argv[]) {
  char name[80];
  int age;
  printf("Hey, what's your name?");
  scanf("%s", &name);
  printf("\nOk, %s", name);
  printf(", how old are you?");
  scanf("%d", &age);
  if (age < 16) {
    printf("You can't drive.");
  }
  if (age < 18) {
    printf("You can't vote");
  }
  if (age < 25) {
    printf("You can't rent a car.");
  }
  if (age > 25) {
    printf("You can do anything that's legal!");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D73(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0xf,0xc(%rsp)
  jle    L65
L59:
  cmpl   $0x11,0xc(%rsp)
  jle    L88
L31:
  cmpl   $0x18,0xc(%rsp)
  jle    L83
L85:
  cmpl   $0x19,0xc(%rsp)
  jg     L9
L34:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L65:
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L88:
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L83:
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L9:
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D73
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D38
datatype: string
name: parse_data
arguments: data_label: D59
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string

tool: D5: Hey, what's your name?

tool: D73: %s

tool: D3: 
Ok, %s

tool: D35: , how old are you?

tool: D4: %d

tool: D38: You can't drive.

tool: D59: You can't vote

tool: D30: You can't rent a car.

tool: D33: You can do anything that's legal!

assistant: ```c
int main(int argc, char *argv[]) {
  char name[80];
  int age;
  printf("Hey, what's your name?");
  scanf("%s", &name);
  printf("\nOk, %s", name);
  printf(", how old are you?");
  scanf("%d", &age);
  if (age < 16) {
    printf("You can't drive.");
  }
  if (age < 18) {
    printf("You can't vote");
  }
  if (age < 25) {
    printf("You can't rent a car.");
  }
  if (age > 25) {
    printf("You can do anything that's legal!");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D57(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0xf,%eax
  jle    L38
L9:
  cmp    $0x11,%eax
  jle    L57
L82:
  cmp    $0x18,%eax
  jle    L37
L87:
  cmp    $0x19,%eax
  jg     L5
L66:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L38:
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L9
L5:
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L37:
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L87
L57:
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L82
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D57
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D60
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D30
datatype: string
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D49
datatype: string

tool: D57: Hey, what's your name?

tool: D6: %s

tool: D15: 
Ok, %s

tool: D60: , how old are you?

tool: D29: %d

tool: D32: You can't drive.

tool: D30: You can do anything that's legal!

tool: D36: You can't rent a car.

tool: D49: You can't vote

assistant: ```c
int main(int argc, char *argv[]) {
  char name[80];
  int age;
  printf("Hey, what's your name?");
  scanf("%s", &name);
  printf("\nOk, %s", name);
  printf(", how old are you?");
  scanf("%d", &age);
  if (age < 16) {
    printf("You can't drive.");
  }
  if (age < 18) {
    printf("You can't vote");
  }
  if (age < 25) {
    printf("You can't rent a car.");
  }
  if (age > 25) {
    printf("You can do anything that's legal!");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0xf,%eax
  jle    L21
L45:
  cmp    $0x11,%eax
  jle    L79
L85:
  cmp    $0x18,%eax
  jle    L23
L32:
  cmp    $0x19,%eax
  jg     L18
L64:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L21:
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L45
L18:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L64
L23:
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L32
L79:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L85
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D32
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string
name: retrieve_data
arguments: label: D63
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D46
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string

tool: D17: Hey, what's your name?

tool: D10: %s

tool: D32: 
Ok, %s

tool: D13: , how old are you?

tool: D27: %d

tool: D63: You can't drive.

tool: D1: You can do anything that's legal!

tool: D46: You can't rent a car.

tool: D38: You can't vote

assistant: ```c
int main(int argc, char *argv[]) {
  char name[80];
  int age;
  printf("Hey, what's your name?");
  scanf("%s", &name);
  printf("\nOk, %s", name);
  printf(", how old are you?");
  scanf("%d", &age);
  if (age < 16) {
    printf("You can't drive.");
  }
  if (age < 18) {
    printf("You can't vote");
  }
  if (age < 25) {
    printf("You can't rent a car.");
  }
  if (age > 25) {
    printf("You can do anything that's legal!");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_min_multi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L37:
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L10:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L4
  movsd  -0x8(%rbp),%xmm0
  jmp    L45
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
L45:
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L10
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L37
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double find_min_multi(double **array, int *n, int m) {
  int i;
  int j;
  double min = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      min = (array[i][j] > min) ? min : array[i][j];
    }
  }
  return min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_min_multi>:
  endbr64
  mov    (%rdi),%rax
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L37
  mov    %edx,%r8d
  mov    $0x0,%ecx
  jmp    L39
L28:
  mov    (%rdi,%rcx,8),%rax
  lea    -0x1(%rdx),%edx
  lea    0x8(%rax,%rdx,8),%rdx
L18:
  minsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L18
L30:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L37
L39:
  mov    (%rsi,%rcx,4),%edx
  test   %edx,%edx
  jg     L28
  jmp    L30
L37:
  ret
```

assistant: ```c
double find_min_multi(double **array, int *n, int m) {
  int i;
  int j;
  double min = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      min = (array[i][j] > min) ? min : array[i][j];
    }
  }
  return min;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_min_multi>:
  endbr64
  mov    (%rdi),%rax
  mov    %rdi,%r9
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L29
  movslq %edx,%r8
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rsi,%rdi,4),%eax
  test   %eax,%eax
  jle    L1
  mov    (%r9,%rdi,8),%rdx
  lea    -0x1(%rax),%ecx
  lea    0x8(%rdx),%rax
  lea    (%rax,%rcx,8),%rcx
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x8,%rax
L27:
  minsd  (%rdx),%xmm0
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L48
L1:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L8
L29:
  ret
```

assistant: ```c
double find_min_multi(double **array, int *n, int m) {
  int i;
  int j;
  double min = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      min = (array[i][j] > min) ? min : array[i][j];
    }
  }
  return min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_min_multi>:
  endbr64
  mov    (%rdi),%rax
  mov    %rdi,%r9
  movsd  (%rax),%xmm0
  test   %edx,%edx
  jle    L35
  movslq %edx,%r8
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%rsi,%rdi,4),%eax
  test   %eax,%eax
  jle    L41
  mov    (%r9,%rdi,8),%rdx
  lea    -0x1(%rax),%ecx
  lea    0x8(%rdx),%rax
  lea    (%rax,%rcx,8),%rcx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x8,%rax
L39:
  minsd  (%rdx),%xmm0
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L43
L41:
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L28
L35:
  ret
```

assistant: ```c
double find_min_multi(double **array, int *n, int m) {
  int i;
  int j;
  double min = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      min = (array[i][j] > min) ? min : array[i][j];
    }
  }
  return min;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_spack2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <util_saturate_n_no_state@plt>
  mov    %ax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <util_saturate_n_no_state@plt>
  mov    %ax,-0x2(%rbp)
  movswl -0x4(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  movswl -0x2(%rbp),%eax
  movzwl %ax,%eax
  or     %edx,%eax
  leave
  ret
```

assistant: ```c
int _spack2(int src1, int src2) {
  short s1 = (short)util_saturate_n_no_state(src1, 16);
  short s2 = (short)util_saturate_n_no_state(src2, 16);
  return ((unsigned int)s1 << 16) | (((int)s2) & 0xFFFF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_spack2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    $0x10,%esi
  call   <util_saturate_n_no_state@plt>
  mov    %rax,%rbx
  mov    $0x10,%esi
  mov    %ebp,%edi
  call   <util_saturate_n_no_state@plt>
  shl    $0x10,%ebx
  movzwl %ax,%eax
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _spack2(int src1, int src2) {
  short s1 = (short)util_saturate_n_no_state(src1, 16);
  short s2 = (short)util_saturate_n_no_state(src2, 16);
  return ((unsigned int)s1 << 16) | (((int)s2) & 0xFFFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_spack2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x10,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <util_saturate_n_no_state@plt>
  mov    %ebp,%edi
  mov    $0x10,%esi
  mov    %rax,%rbx
  call   <util_saturate_n_no_state@plt>
  shl    $0x10,%ebx
  add    $0x8,%rsp
  movzwl %ax,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _spack2(int src1, int src2) {
  short s1 = (short)util_saturate_n_no_state(src1, 16);
  short s2 = (short)util_saturate_n_no_state(src2, 16);
  return ((unsigned int)s1 << 16) | (((int)s2) & 0xFFFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_spack2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x10,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <util_saturate_n_no_state@plt>
  mov    %ebp,%edi
  mov    $0x10,%esi
  mov    %rax,%rbx
  call   <util_saturate_n_no_state@plt>
  shl    $0x10,%ebx
  add    $0x8,%rsp
  movzwl %ax,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _spack2(int src1, int src2) {
  short s1 = (short)util_saturate_n_no_state(src1, 16);
  short s2 = (short)util_saturate_n_no_state(src2, 16);
  return ((unsigned int)s1 << 16) | (((int)s2) & 0xFFFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jerasure_generate_schedule_cache>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %edx,0x8(%rsp)
  mov    %rcx,(%rsp)
  mov    %r8d,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x48(%rsp)
  cmp    $0x2,%esi
  jne    L35
  mov    %edi,%r13d
  lea    0x2(%rdi),%ebx
  mov    %ebx,0x2c(%rsp)
  lea    0x3(%rdi),%edi
  imul   %ebx,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,0x30(%rsp)
  mov    %rax,0x48(%rsp)
  test   %rax,%rax
  je     L13
  test   %ebx,%ebx
  jle    L35
  movl   $0x0,0x5c(%rsp)
  mov    0x2c(%rsp),%esi
  movslq %esi,%rax
  lea    0x8(,%rax,8),%rdx
  mov    %rdx,0x40(%rsp)
  lea    0x1(%r13),%edx
  add    $0x1,%rdx
  mov    %rdx,0x38(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x10(%rsp)
  mov    %esi,0x28(%rsp)
  mov    0x30(%rsp),%rax
  mov    %rax,0x20(%rsp)
  movq   $0x1,0x18(%rsp)
  lea    0x5c(%rsp),%r14
  jmp    L84
L2:
  mov    0x18(%rsp),%rcx
  mov    %ecx,0x5c(%rsp)
  mov    %ecx,%r15d
  test   %ecx,%ecx
  jle    L7
  movslq 0x28(%rsp),%rax
  mov    0x30(%rsp),%rsi
  lea    (%rsi,%rax,8),%r12
  lea    (%rsi,%rcx,8),%rbp
  mov    $0x0,%ebx
L70:
  mov    %ebx,0x60(%rsp)
  movl   $0xffffffff,0x64(%rsp)
  mov    0xc(%rsp),%r9d
  mov    %r14,%r8
  mov    (%rsp),%rcx
  mov    0x8(%rsp),%edx
  mov    $0x2,%esi
  mov    %r13d,%edi
  call   <jerasure_generate_decoding_schedule@plt>
  mov    %rax,(%r12)
  mov    %rax,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x8,%r12
  add    0x10(%rsp),%rbp
  cmp    %r15d,%ebx
  jne    L70
L7:
  addq   $0x1,0x18(%rsp)
  mov    0x40(%rsp),%rdx
  add    %rdx,0x20(%rsp)
  mov    0x2c(%rsp),%edi
  add    %edi,0x28(%rsp)
L84:
  movl   $0xffffffff,0x60(%rsp)
  mov    0xc(%rsp),%r9d
  mov    %r14,%r8
  mov    (%rsp),%rcx
  mov    0x8(%rsp),%edx
  mov    $0x2,%esi
  mov    %r13d,%edi
  call   <jerasure_generate_decoding_schedule@plt>
  mov    0x20(%rsp),%rdx
  mov    %rax,(%rdx)
  mov    0x38(%rsp),%rdi
  cmp    %rdi,0x18(%rsp)
  jne    L2
L35:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    0x48(%rsp),%rax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  movq   $0x0,0x48(%rsp)
  jmp    L35
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ***jerasure_generate_schedule_cache(int k, int m, int w, int *bitmatrix, int smart) {
  int i, tdone;
  char **ptrs;
  int **schedule;
  int ***scache;
  int erasures[3];
  int e1, e2;
  if (m != 2)
    return NULL;
  scache = (int ***)malloc(sizeof(int **) * ((k + m) * (k + m + 1)));
  if (scache == NULL)
    return NULL;
  for (e1 = 0; e1 < k + m; e1++) {
    erasures[0] = e1;
    for (e2 = 0; e2 < e1; e2++) {
      erasures[1] = e2;
      erasures[2] = -1;
      scache[e1 * (k + m) + e2] = jerasure_generate_decoding_schedule(k, m, w, bitmatrix, erasures, smart);
      scache[e2 * (k + m) + e1] = scache[e1 * (k + m) + e2];
    }
    erasures[1] = -1;
    scache[e1 * (k + m) + e1] = jerasure_generate_decoding_schedule(k, m, w, bitmatrix, erasures, smart);
  }
  return scache;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_quote>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rsi,%rdx
  lea    D24(%rip),%rsi
  lea    D54(%rip),%rdi
  call   <check_capacity@plt>
  test   %rbx,%rbx
  je     L73
  movq   $0x0,(%rbx)
L73:
  mov    D54(%rip),%rax
  test   %rax,%rax
  je     L81
  mov    %rax,0x10(%rsp)
  movb   $0x22,(%rax)
  test   %r12,%r12
  je     L20
  add    %rbp,%r12
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r15
  lea    D24(%rip),%r14
  lea    D54(%rip),%r13
  jmp    L71
L21:
  lea    0x1(%rbx),%rax
  mov    0x10(%rsp),%rdx
  movb   $0x5c,(%rdx,%rbx,1)
  add    $0x2,%rbx
  mov    0x10(%rsp),%rdx
  movb   $0x22,(%rdx,%rax,1)
L100:
  add    $0x1,%rbp
  cmp    %rbp,%r12
  je     L70
L71:
  lea    0x8(%rbx),%rdx
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <check_capacity@plt>
  mov    D54(%rip),%rax
  test   %rax,%rax
  je     L6
  movzbl 0x0(%rbp),%eax
  cmp    $0x22,%al
  je     L21
  cmp    $0x5c,%al
  je     L36
  mov    0x10(%rsp),%rdx
  mov    %al,(%rdx,%rbx,1)
  lea    0x1(%rbx),%rbx
  jmp    L100
L36:
  lea    0x1(%rbx),%rax
  mov    0x10(%rsp),%rdx
  movb   $0x5c,(%rdx,%rbx,1)
  add    $0x2,%rbx
  mov    0x10(%rsp),%rdx
  movb   $0x5c,(%rdx,%rax,1)
  jmp    L100
L20:
  mov    $0x1,%ebx
L70:
  lea    0x1(%rbx),%rdx
  mov    0x10(%rsp),%rax
  movb   $0x22,(%rax,%rbx,1)
  mov    0x10(%rsp),%rax
  movb   $0x0,0x1(%rax,%rbx,1)
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L81
  mov    %rdx,(%rax)
L81:
  mov    D54(%rip),%rax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *c_quote(char *str, size_t ilen, size_t *len) {
  static char *buf = NULL;
  static size_t buf_cap = 0;
  const char DQ = '"';
  const char E = '\\';
  check_capacity(&buf, &buf_cap, ilen, 0, 0);
  if (len)
    *len = 0;
  if (buf) {
    size_t i = 0;
    char *p = buf;
    p[i++] = DQ;
    while (ilen > 0) {
      check_capacity(&buf, &buf_cap, i + 8, &p, i);
      if (!buf)
        return buf;
      if (*str == DQ) {
        p[i++] = E;
        p[i++] = DQ;
      } else if (*str == E) {
        p[i++] = E;
        p[i++] = E;
      } else {
        p[i++] = *str;
      }
      str++;
      ilen--;
    }
    p[i++] = DQ;
    p[i] = 0;
    if (len)
      *len = i;
  }
  return buf;
}
```