ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xd,-0x44(%rbp)
  movl   $0x13,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0xa,-0x38(%rbp)
  movl   $0xe,-0x34(%rbp)
  movl   $0x10,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0xb,-0x10(%rbp)
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <HeapSort@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: echo pause...

assistant: ```c
void main(int argc, char *argv[]) {
  const int heap_size = 13;
  int A[] = {19, 1, 10, 14, 16, 4, 7, 9, 3, 2, 8, 5, 11};
  HeapSort(A, heap_size);
  system("echo pause...");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x13,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0xa,0x8(%rsp)
  movl   $0xe,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x8,0x28(%rsp)
  movl   $0x5,0x2c(%rsp)
  movl   $0xb,0x30(%rsp)
  mov    %rsp,%rdi
  mov    $0xd,%esi
  call   <HeapSort@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x48,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: echo pause...

assistant: ```c
void main(int argc, char *argv[]) {
  const int heap_size = 13;
  int A[] = {19, 1, 10, 14, 16, 4, 7, 9, 3, 2, 8, 5, 11};
  HeapSort(A, heap_size);
  system("echo pause...");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0xd,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x100000013,%rax
  mov    %rsp,%rdi
  movl   $0xb,0x30(%rsp)
  mov    %rax,(%rsp)
  movabs $0xe0000000a,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000010,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x900000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000003,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x500000008,%rax
  mov    %rax,0x28(%rsp)
  call   <HeapSort@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D3: echo pause...

assistant: ```c
void main(int argc, char *argv[]) {
  const int heap_size = 13;
  int A[] = {19, 1, 10, 14, 16, 4, 7, 9, 3, 2, 8, 5, 11};
  HeapSort(A, heap_size);
  system("echo pause...");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movdqa D5(%rip),%xmm0
  mov    $0xd,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0xb,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D3(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D6(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <HeapSort@plt>
  lea    D28(%rip),%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: byte[16]
name: read_data
arguments: label: D3
data_type: byte[16]
name: read_data
arguments: label: D6
data_type: byte[16]
name: read_data
arguments: label: D28
data_type: string

tool: {"D5": [0x13,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

tool: {"D3": [0x10,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D6": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D28: echo pause...

assistant: ```c
void main(int argc, char *argv[]) {
  const int heap_size = 13;
  int A[] = {19, 1, 10, 14, 16, 4, 7, 9, 3, 2, 8, 5, 11};
  HeapSort(A, heap_size);
  system("echo pause...");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<altera_a10_cdr_lookup_clklow_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x61a80,-0x4(%rbp)
  jbe    L0
  mov    $0x1,%eax
  jmp    L17
L0:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int altera_a10_cdr_lookup_clklow_div(unsigned int fref) {
  if (fref > 400000)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<altera_a10_cdr_lookup_clklow_div>:
  endbr64
  cmp    $0x61a80,%edi
  seta   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned int altera_a10_cdr_lookup_clklow_div(unsigned int fref) {
  if (fref > 400000)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<altera_a10_cdr_lookup_clklow_div>:
  endbr64
  xor    %eax,%eax
  cmp    $0x61a80,%edi
  seta   %al
  ret
```

assistant: ```c
unsigned int altera_a10_cdr_lookup_clklow_div(unsigned int fref) {
  if (fref > 400000)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<altera_a10_cdr_lookup_clklow_div>:
  endbr64
  xor    %eax,%eax
  cmp    $0x61a80,%edi
  seta   %al
  ret
```

assistant: ```c
unsigned int altera_a10_cdr_lookup_clklow_div(unsigned int fref) {
  if (fref > 400000)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gdc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  jmp    L5
L1:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gdc>
L5:
  leave
  ret
```

assistant: ```c
int gdc(int x, int y) {
  if (y == 0)
    return (x);
  else
    return (gdc(y, x % y));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gdc>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  mov    %esi,%edi
  cltd
  idiv   %esi
  mov    %edx,%esi
  call   <gdc>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gdc(int x, int y) {
  if (y == 0)
    return (x);
  else
    return (gdc(y, x % y));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gdc>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L19
  jmp    L16
  nop
L28:
  mov    %edx,%r8d
L19:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L28
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gdc(int x, int y) {
  if (y == 0)
    return (x);
  else
    return (gdc(y, x % y));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gdc>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L26
  jmp    L10
  nop
L15:
  mov    %edx,%r8d
L26:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L15
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gdc(int x, int y) {
  if (y == 0)
    return (x);
  else
    return (gdc(y, x % y));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
L0:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: DO-WHILE


assistant: ```c
int main(void) {
  int i = 1;
  do {
    printf("DO-WHILE\n");
    i++;
  } while (i <= 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: DO-WHILE


assistant: ```c
int main(void) {
  int i = 1;
  do {
    printf("DO-WHILE\n");
    i++;
  } while (i <= 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: DO-WHILE


assistant: ```c
int main(void) {
  int i = 1;
  do {
    printf("DO-WHILE\n");
    i++;
  } while (i <= 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: DO-WHILE


assistant: ```c
int main(void) {
  int i = 1;
  do {
    printf("DO-WHILE\n");
    i++;
  } while (i <= 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <xputc@plt>
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void xputs(const char *str) {
  while (*str) {
    xputc(*str++);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L16
L10:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <xputc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L10
L16:
  pop    %rbx
  ret
```

assistant: ```c
void xputs(const char *str) {
  while (*str) {
    xputc(*str++);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L15:
  call   <xputc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L17:
  pop    %rbx
  ret
```

assistant: ```c
void xputs(const char *str) {
  while (*str) {
    xputc(*str++);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L3:
  call   <xputc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L18:
  pop    %rbx
  ret
```

assistant: ```c
void xputs(const char *str) {
  while (*str) {
    xputc(*str++);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L32
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L32:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xb9(%rbp)
  cmpl   $0x101,-0xcc(%rbp)
  jne    L22
  lea    D18(%rip),%rax
  mov    %al,-0xbb(%rbp)
  jmp    L19
L22:
  cmpl   $0x0,-0xcc(%rbp)
  jne    L19
  lea    D3(%rip),%rax
  mov    %al,-0xbb(%rbp)
L19:
  lea    -0xbb(%rbp),%rdx
  mov    -0xc8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D18: w

tool: D3: r

assistant: ```c
int open(const char *filename, int oflag, ...) {
  char mode[3];
  mode[2] = 0;
  if (oflag == (0x0001 | 0x0100))
    mode[0] = "w";
  else if (oflag == 0x0000)
    mode[0] = "r";
  return fopen(filename, mode);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<open>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  cmp    $0x101,%esi
  je     L35
  test   %esi,%esi
  jne    L4
  lea    D5(%rip),%rax
  mov    %al,0x5(%rsp)
  jmp    L4
L35:
  lea    D18(%rip),%rax
  mov    %al,0x5(%rsp)
L4:
  lea    0x5(%rsp),%rsi
  call   <fopen@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x18,%rsp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string

tool: D5: r

tool: D18: w

assistant: ```c
int open(const char *filename, int oflag, ...) {
  char mode[3];
  mode[2] = 0;
  if (oflag == (0x0001 | 0x0100))
    mode[0] = "w";
  else if (oflag == 0x0000)
    mode[0] = "r";
  return fopen(filename, mode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<open>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  cmp    $0x101,%esi
  je     L11
  test   %esi,%esi
  je     L49
L0:
  lea    0x5(%rsp),%rsi
  call   <fopen@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  lea    D8(%rip),%rax
  mov    %al,0x5(%rsp)
  jmp    L0
  nopl   (%rax)
L11:
  lea    D17(%rip),%rax
  mov    %al,0x5(%rsp)
  jmp    L0
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string
name: unpack_data
arguments: data_label: D17
data_type: string

tool: D8: r

tool: D17: w

assistant: ```c
int open(const char *filename, int oflag, ...) {
  char mode[3];
  mode[2] = 0;
  if (oflag == (0x0001 | 0x0100))
    mode[0] = "w";
  else if (oflag == 0x0000)
    mode[0] = "r";
  return fopen(filename, mode);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<open>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  cmp    $0x101,%esi
  je     L38
  test   %esi,%esi
  je     L44
L45:
  lea    0x5(%rsp),%rsi
  call   <fopen@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  lea    D16(%rip),%rax
  mov    %al,0x5(%rsp)
  jmp    L45
  nopl   (%rax)
L38:
  lea    D8(%rip),%rax
  mov    %al,0x5(%rsp)
  jmp    L45
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D16: r

tool: D8: w

assistant: ```c
int open(const char *filename, int oflag, ...) {
  char mode[3];
  mode[2] = 0;
  if (oflag == (0x0001 | 0x0100))
    mode[0] = "w";
  else if (oflag == 0x0000)
    mode[0] = "r";
  return fopen(filename, mode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L37:
  cmpl   $0x14,-0x8(%rbp)
  je     L48
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L38
  jmp    L37
L48:
  nop
  cmpl   $0x14,-0x4(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L22
L38:
  nop
  jmp    L21
L44:
  nop
L21:
  mov    $0xffffffff,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int a = 0;
  while (1) {
    if (i == 20) {
      goto LOOPEND;
    } else {
      i++;
      a++;
    }
    if (i != a) {
      goto ERROR;
    }
  }
LOOPEND:
  if (a != 20) {
    goto ERROR;
  }
  return (0);
ERROR:
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
L9:
  add    $0x1,%eax
  cmp    $0x14,%eax
  jne    L9
  setne  %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int a = 0;
  while (1) {
    if (i == 20) {
      goto LOOPEND;
    } else {
      i++;
      a++;
    }
    if (i != a) {
      goto ERROR;
    }
  }
LOOPEND:
  if (a != 20) {
    goto ERROR;
  }
  return (0);
ERROR:
  return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int a = 0;
  while (1) {
    if (i == 20) {
      goto LOOPEND;
    } else {
      i++;
      a++;
    }
    if (i != a) {
      goto ERROR;
    }
  }
LOOPEND:
  if (a != 20) {
    goto ERROR;
  }
  return (0);
ERROR:
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int a = 0;
  while (1) {
    if (i == 20) {
      goto LOOPEND;
    } else {
      i++;
      a++;
    }
    if (i != a) {
      goto ERROR;
    }
  }
LOOPEND:
  if (a != 20) {
    goto ERROR;
  }
  return (0);
ERROR:
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L42:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L31
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L0:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L37:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L42
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int binarySearch(int arr[], int top, int num) {
  int low = 0, high = top - 1, mid = (low + high) / 2;
  while (low <= high) {
    if (arr[mid] == num)
      return 1;
    else if (arr[mid] < num)
      low = mid + 1;
    else
      high = mid - 1;
    mid = (low + high) / 2;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binarySearch>:
  endbr64
  mov    %rdi,%r8
  sub    $0x1,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  test   %esi,%esi
  js     L17
  mov    $0x0,%edi
  jmp    L4
L35:
  lea    -0x1(%rax),%esi
L6:
  lea    (%rdi,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %esi,%edi
  jg     L49
L4:
  movslq %eax,%rcx
  mov    (%r8,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L11
  jge    L35
  lea    0x1(%rax),%edi
  jmp    L6
L49:
  mov    $0x0,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int binarySearch(int arr[], int top, int num) {
  int low = 0, high = top - 1, mid = (low + high) / 2;
  while (low <= high) {
    if (arr[mid] == num)
      return 1;
    else if (arr[mid] < num)
      low = mid + 1;
    else
      high = mid - 1;
    mid = (low + high) / 2;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binarySearch>:
  endbr64
  sub    $0x1,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  test   %esi,%esi
  js     L20
  xor    %r8d,%r8d
  jmp    L38
  nopl   0x0(%rax)
L15:
  lea    0x1(%rax),%r8d
L25:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %esi,%r8d
  jg     L20
L38:
  movslq %eax,%rcx
  cmp    %edx,(%rdi,%rcx,4)
  je     L53
  jl     L15
  lea    -0x1(%rax),%esi
  jmp    L25
  nopl   (%rax)
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int binarySearch(int arr[], int top, int num) {
  int low = 0, high = top - 1, mid = (low + high) / 2;
  while (low <= high) {
    if (arr[mid] == num)
      return 1;
    else if (arr[mid] < num)
      low = mid + 1;
    else
      high = mid - 1;
    mid = (low + high) / 2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binarySearch>:
  endbr64
  sub    $0x1,%esi
  mov    %rdi,%r8
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  test   %esi,%esi
  js     L59
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L53:
  movslq %eax,%rdi
  cmp    %edx,(%r8,%rdi,4)
  je     L17
L42:
  jge    L12
  lea    0x1(%rax),%ecx
  lea    (%rcx,%rsi,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  cmp    %esi,%ecx
  jle    L53
L59:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rax),%esi
  lea    (%rsi,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  cmp    %ecx,%esi
  jl     L59
  movslq %eax,%rdi
  cmp    %edx,(%r8,%rdi,4)
  jne    L42
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int binarySearch(int arr[], int top, int num) {
  int low = 0, high = top - 1, mid = (low + high) / 2;
  while (low <= high) {
    if (arr[mid] == num)
      return 1;
    else if (arr[mid] < num)
      low = mid + 1;
    else
      high = mid - 1;
    mid = (low + high) / 2;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mpui_string_strlen16bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,-0x8(%rbp)
  jmp    L19
L9:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t mpui_string_strlen16bit(const unsigned char *str) {
  const unsigned char *s;
  for (s = str++; *s++ || *s; s++)
    ;
  return (s - str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mpui_string_strlen16bit>:
  endbr64
  mov    %rdi,%rax
  jmp    L23
L11:
  add    $0x2,%rax
L23:
  cmpb   $0x0,(%rax)
  jne    L11
  cmpb   $0x0,0x1(%rax)
  jne    L11
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t mpui_string_strlen16bit(const unsigned char *str) {
  const unsigned char *s;
  for (s = str++; *s++ || *s; s++)
    ;
  return (s - str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mpui_string_strlen16bit>:
  endbr64
  mov    %rdi,%rax
  jmp    L12
  nopl   0x0(%rax)
L15:
  add    $0x2,%rax
L12:
  cmpb   $0x0,(%rax)
  jne    L15
  cmpb   $0x0,0x1(%rax)
  jne    L15
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t mpui_string_strlen16bit(const unsigned char *str) {
  const unsigned char *s;
  for (s = str++; *s++ || *s; s++)
    ;
  return (s - str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mpui_string_strlen16bit>:
  endbr64
  mov    %rdi,%rax
  jmp    L24
  nopl   0x0(%rax)
L6:
  add    $0x2,%rax
L24:
  cmpb   $0x0,(%rax)
  jne    L6
  cmpb   $0x0,0x1(%rax)
  jne    L6
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t mpui_string_strlen16bit(const unsigned char *str) {
  const unsigned char *s;
  for (s = str++; *s++ || *s; s++)
    ;
  return (s - str);
}
```