user: 这段汇编代码用C语言表示是什么样的：

```asm
<stage_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movw   $0x0,-0x16(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  and    $0xff,%ax
  mov    %ax,-0x18(%rbp)
  jmp    L61
L18:
  cmpw   $0x7f,-0x18(%rbp)
  jbe    L33
  movzwl -0x18(%rbp),%eax
  mov    %ax,-0x16(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  and    $0xff,%ax
  mov    %ax,-0x18(%rbp)
L33:
  movzwl -0x18(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x18(%rbp),%eax
  and    $0xf0,%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  and    $0xf,%eax
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %ax,-0x18(%rbp)
  movzwl -0x16(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %ax,-0x16(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  movzbl %al,%ebx
  movzwl -0x14(%rbp),%eax
  add    $0x1,%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cbtw
  imul   %ebx,%eax
  mov    %ax,-0x12(%rbp)
  cmpw   $0x1ff,-0x12(%rbp)
  jbe    L44
  mov    $0xffffffff,%eax
  jmp    L14
L44:
  movzwl -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cbtw
  mov    %ax,-0x14(%rbp)
  jmp    L28
L60:
  movzwl -0x12(%rbp),%eax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzwl -0x16(%rbp),%edx
  mov    %dl,(%rax)
  movzwl -0x16(%rbp),%eax
  and    $0xff00,%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  movzwl -0x12(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movzwl -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x14(%rbp)
  addw   $0x2,-0x12(%rbp)
L28:
  cmpw   $0x0,-0x14(%rbp)
  jne    L60
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  and    $0xff,%ax
  mov    %ax,-0x18(%rbp)
L61:
  cmpw   $0xff,-0x18(%rbp)
  jne    L18
  mov    $0x0,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stage_1(long *pointer, char *rompointer, char *bufferpointer) {
  unsigned short in_val;
  unsigned short out_val = 0;
  unsigned short num_times;
  unsigned short offset;
  for (in_val = (*((*pointer)++ + rompointer) & 0xFF); in_val != 0xFF; in_val = (*((*pointer)++ + rompointer) & 0xFF)) {
    if (in_val > 0x7F) {
      out_val = in_val;
      in_val = (*((*pointer)++ + rompointer) & 0xFF);
    }
    num_times = 0x08 - (in_val & 0x0F);
    in_val = ((in_val & 0xF0) / 0x10) + ((in_val & 0x0F) * 0x10);
    out_val = (out_val & 0x0F) + (in_val * 0x10);
    offset = (*((*pointer)++ + rompointer) & 0xFF) * pow(2, (num_times + 1));
    if (offset >= 0x200) {
      return -1;
    }
    num_times = pow(2, num_times);
    for (; num_times != 0; num_times--, offset += 2) {
      *(bufferpointer + offset + 1) = (out_val & 0x00FF);
      *(bufferpointer + offset) = ((out_val & 0xFF00) / 0x100);
    }
  }
  return 0;
}
```