ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L3
  xor    %eax,%eax
  call   <abort@plt>
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1, 2, 3) != 3)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1, 2, 3) != 3)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fts_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L29
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L20
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
L20:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,0x8(%rax)
L29:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,0x20(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x20(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,0x18(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x28(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  nop
  leave
  ret
```

assistant: ```c
void fts_load(FTS *sp, FTSENT *p) {
  size_t len;
  char *cp;
  len = p->fts_pathlen = p->fts_namelen;
  memmove(sp->fts_path, p->fts_name, len + 1);
  if ((cp = strrchr(p->fts_name, '/')) && (cp != p->fts_name || cp[1])) {
    len = strlen(++cp);
    memmove(p->fts_name, cp, len + 1);
    p->fts_namelen = len;
  }
  p->fts_accpath = p->fts_path = sp->fts_path;
  sp->fts_dev = p->fts_dev;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fts_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdx
  mov    %rdx,(%rsi)
  add    $0x1,%rdx
  mov    0x10(%rsi),%rsi
  mov    (%rdi),%rdi
  call   <memmove@plt>
  mov    0x10(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L18
  mov    0x10(%rbx),%r14
  cmp    %rax,%r14
  je     L0
L37:
  lea    0x1(%rax),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memmove@plt>
  mov    %r13,0x8(%rbx)
L18:
  mov    (%r12),%rax
  mov    %rax,0x20(%rbx)
  mov    %rax,0x18(%rbx)
  mov    0x28(%rbx),%eax
  mov    %eax,0x8(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  cmpb   $0x0,0x1(%rax)
  je     L18
  jmp    L37
```

assistant: ```c
void fts_load(FTS *sp, FTSENT *p) {
  size_t len;
  char *cp;
  len = p->fts_pathlen = p->fts_namelen;
  memmove(sp->fts_path, p->fts_name, len + 1);
  if ((cp = strrchr(p->fts_name, '/')) && (cp != p->fts_name || cp[1])) {
    len = strlen(++cp);
    memmove(p->fts_name, cp, len + 1);
    p->fts_namelen = len;
  }
  p->fts_accpath = p->fts_path = sp->fts_path;
  sp->fts_dev = p->fts_dev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fts_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdx
  mov    %rsi,%rbx
  mov    (%rdi),%rdi
  mov    %rdx,(%rsi)
  mov    0x10(%rsi),%rsi
  add    $0x1,%rdx
  call   <memmove@plt>
  mov    0x10(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L31
  mov    0x10(%rbx),%r14
  cmp    %rax,%r14
  je     L1
L9:
  lea    0x1(%rax),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %rax,%r13
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %r13,0x8(%rbx)
L31:
  mov    (%r12),%rax
  mov    %rax,0x20(%rbx)
  mov    %rax,0x18(%rbx)
  mov    0x28(%rbx),%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,0x8(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  cmpb   $0x0,0x1(%r14)
  je     L31
  jmp    L9
```

assistant: ```c
void fts_load(FTS *sp, FTSENT *p) {
  size_t len;
  char *cp;
  len = p->fts_pathlen = p->fts_namelen;
  memmove(sp->fts_path, p->fts_name, len + 1);
  if ((cp = strrchr(p->fts_name, '/')) && (cp != p->fts_name || cp[1])) {
    len = strlen(++cp);
    memmove(p->fts_name, cp, len + 1);
    p->fts_namelen = len;
  }
  p->fts_accpath = p->fts_path = sp->fts_path;
  sp->fts_dev = p->fts_dev;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fts_load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdx
  mov    %rsi,%rbx
  mov    (%rdi),%rdi
  mov    %rdx,(%rsi)
  mov    0x10(%rsi),%rsi
  add    $0x1,%rdx
  call   <memmove@plt>
  mov    0x10(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L15
  mov    0x10(%rbx),%r14
  cmp    %rax,%r14
  je     L13
L11:
  lea    0x1(%rax),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %rax,%r13
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %r13,0x8(%rbx)
L15:
  movq   (%r12),%xmm0
  mov    0x28(%rbx),%eax
  punpcklqdq %xmm0,%xmm0
  movups %xmm0,0x18(%rbx)
  pop    %rbx
  pop    %rbp
  mov    %eax,0x8(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmpb   $0x0,0x1(%r14)
  je     L15
  jmp    L11
```

assistant: ```c
void fts_load(FTS *sp, FTSENT *p) {
  size_t len;
  char *cp;
  len = p->fts_pathlen = p->fts_namelen;
  memmove(sp->fts_path, p->fts_name, len + 1);
  if ((cp = strrchr(p->fts_name, '/')) && (cp != p->fts_name || cp[1])) {
    len = strlen(++cp);
    memmove(p->fts_name, cp, len + 1);
    p->fts_namelen = len;
  }
  p->fts_accpath = p->fts_path = sp->fts_path;
  sp->fts_dev = p->fts_dev;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pumas_electronic_dcs>:
  endbr64
  movapd %xmm2,%xmm6
  addsd  %xmm2,%xmm6
  addsd  %xmm3,%xmm6
  mulsd  %xmm3,%xmm6
  addsd  %xmm2,%xmm3
  movapd %xmm6,%xmm7
  mulsd  D54(%rip),%xmm7
  movapd %xmm3,%xmm5
  addsd  %xmm3,%xmm5
  movsd  D39(%rip),%xmm8
  addsd  %xmm8,%xmm5
  mulsd  %xmm8,%xmm5
  mulsd  %xmm2,%xmm2
  addsd  %xmm5,%xmm2
  divsd  %xmm2,%xmm7
  pxor   %xmm2,%xmm2
  comisd %xmm7,%xmm4
  ja     L0
  mulsd  D46(%rip),%xmm1
  pxor   %xmm2,%xmm2
  comisd %xmm4,%xmm1
  jae    L0
  mulsd  %xmm3,%xmm3
  divsd  %xmm3,%xmm6
  movsd  D53(%rip),%xmm1
  divsd  %xmm4,%xmm1
  movapd %xmm6,%xmm4
  divsd  %xmm7,%xmm4
  movapd %xmm1,%xmm2
  subsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  D55(%rip),%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  D52(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  divsd  %xmm6,%xmm2
L0:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D54
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D39
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D46
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D53
type_guessed: f64
name: disassemble_data
arguments: data_tag: D55
type_guessed: f64
name: disassemble_data
arguments: data_tag: D52
type_guessed: byte[8]

tool: {"D54": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x50,0x3f]}

tool: {"D39": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x40,0x3f]}

tool: {"D46": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xe6,0x3f]}

tool: D53: 1

tool: D55: 0.5

tool: {"D52": [0xce,0xef,0x1a,0x56,0x2a,0x8c,0x60,0x39]}

assistant: ```c
double pumas_electronic_dcs(double Z, double I, double m, double K, double q) {
  const double P2 = K * (K + 2. * m);
  const double E = K + m;
  const double Wmax = 2. * 0.510998910E-03 * P2 / (m * m + 0.510998910E-03 * (0.510998910E-03 + 2. * E));
  if (q > Wmax)
    return 0.;
  const double Wmin = (13.6 / 19.2) * I;
  if (q <= Wmin)
    return 0.;
  const double E2 = E * E;
  const double beta2 = P2 / E2;
  const double a0 = 0.5 / E2;
  const double a1 = beta2 / Wmax;
  const double cs = 2 * 3.14159265358979323846 * 0.510998910E-03 * 2.817940285E-15 * 2.817940285E-15 * Z * (a0 + 1. / q * (1 / q - a1)) / beta2;
  return cs;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pumas_electronic_dcs>:
  endbr64
  movapd %xmm2,%xmm6
  movsd  D14(%rip),%xmm7
  movsd  D43(%rip),%xmm8
  addsd  %xmm2,%xmm6
  addsd  %xmm3,%xmm6
  mulsd  %xmm3,%xmm6
  addsd  %xmm2,%xmm3
  mulsd  %xmm2,%xmm2
  movapd %xmm3,%xmm5
  addsd  %xmm3,%xmm5
  mulsd  %xmm6,%xmm7
  addsd  %xmm8,%xmm5
  mulsd  %xmm8,%xmm5
  addsd  %xmm5,%xmm2
  divsd  %xmm2,%xmm7
  pxor   %xmm2,%xmm2
  comisd %xmm7,%xmm4
  ja     L16
  mulsd  D25(%rip),%xmm1
  pxor   %xmm2,%xmm2
  comisd %xmm4,%xmm1
  jae    L16
  mulsd  %xmm3,%xmm3
  movsd  D8(%rip),%xmm1
  mulsd  D7(%rip),%xmm0
  divsd  %xmm4,%xmm1
  divsd  %xmm3,%xmm6
  movapd %xmm1,%xmm2
  movapd %xmm6,%xmm4
  divsd  %xmm7,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  D6(%rip),%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm6,%xmm2
L16:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D43
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: f64

tool: {"D14": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x50,0x3f]}

tool: {"D43": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x40,0x3f]}

tool: {"D25": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xe6,0x3f]}

tool: D8: 1

tool: {"D7": [0xce,0xef,0x1a,0x56,0x2a,0x8c,0x60,0x39]}

tool: D6: 0.5

assistant: ```c
double pumas_electronic_dcs(double Z, double I, double m, double K, double q) {
  const double P2 = K * (K + 2. * m);
  const double E = K + m;
  const double Wmax = 2. * 0.510998910E-03 * P2 / (m * m + 0.510998910E-03 * (0.510998910E-03 + 2. * E));
  if (q > Wmax)
    return 0.;
  const double Wmin = (13.6 / 19.2) * I;
  if (q <= Wmin)
    return 0.;
  const double E2 = E * E;
  const double beta2 = P2 / E2;
  const double a0 = 0.5 / E2;
  const double a1 = beta2 / Wmax;
  const double cs = 2 * 3.14159265358979323846 * 0.510998910E-03 * 2.817940285E-15 * 2.817940285E-15 * Z * (a0 + 1. / q * (1 / q - a1)) / beta2;
  return cs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pumas_electronic_dcs>:
  endbr64
  movapd %xmm2,%xmm6
  movsd  D39(%rip),%xmm7
  movsd  D24(%rip),%xmm8
  addsd  %xmm2,%xmm6
  addsd  %xmm3,%xmm6
  mulsd  %xmm3,%xmm6
  addsd  %xmm2,%xmm3
  mulsd  %xmm2,%xmm2
  movapd %xmm3,%xmm5
  addsd  %xmm3,%xmm5
  mulsd  %xmm6,%xmm7
  addsd  %xmm8,%xmm5
  mulsd  %xmm8,%xmm5
  addsd  %xmm5,%xmm2
  divsd  %xmm2,%xmm7
  pxor   %xmm2,%xmm2
  comisd %xmm7,%xmm4
  ja     L18
  mulsd  D38(%rip),%xmm1
  pxor   %xmm2,%xmm2
  comisd %xmm4,%xmm1
  jae    L18
  mulsd  %xmm3,%xmm3
  movsd  D52(%rip),%xmm1
  mulsd  D25(%rip),%xmm0
  divsd  %xmm4,%xmm1
  divsd  %xmm3,%xmm6
  movapd %xmm1,%xmm2
  movapd %xmm6,%xmm4
  divsd  %xmm7,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  D0(%rip),%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm6,%xmm2
L18:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D39
datatype: byte[8]
name: disassemble_data
arguments: label: D24
datatype: byte[8]
name: disassemble_data
arguments: label: D38
datatype: byte[8]
name: disassemble_data
arguments: label: D52
datatype: f64
name: disassemble_data
arguments: label: D25
datatype: byte[8]
name: disassemble_data
arguments: label: D0
datatype: f64

tool: {"D39": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x50,0x3f]}

tool: {"D24": [0xd6,0xb5,0xa9,0xcd,0x91,0xbe,0x40,0x3f]}

tool: {"D38": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xe6,0x3f]}

tool: D52: 1

tool: {"D25": [0xce,0xef,0x1a,0x56,0x2a,0x8c,0x60,0x39]}

tool: D0: 0.5

assistant: ```c
double pumas_electronic_dcs(double Z, double I, double m, double K, double q) {
  const double P2 = K * (K + 2. * m);
  const double E = K + m;
  const double Wmax = 2. * 0.510998910E-03 * P2 / (m * m + 0.510998910E-03 * (0.510998910E-03 + 2. * E));
  if (q > Wmax)
    return 0.;
  const double Wmin = (13.6 / 19.2) * I;
  if (q <= Wmin)
    return 0.;
  const double E2 = E * E;
  const double beta2 = P2 / E2;
  const double a0 = 0.5 / E2;
  const double a1 = beta2 / Wmax;
  const double cs = 2 * 3.14159265358979323846 * 0.510998910E-03 * 2.817940285E-15 * 2.817940285E-15 * Z * (a0 + 1. / q * (1 / q - a1)) / beta2;
  return cs;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_ACK>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clear_SDA@plt>
  mov    $0x0,%eax
  call   <set_SDA_output@plt>
  mov    $0x1,%edi
  call   <_delay_us@plt>
  mov    $0x0,%eax
  call   <send_SCL_pulse@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void send_ACK(void) {
  clear_SDA();
  set_SDA_output();
  _delay_us(1);
  send_SCL_pulse();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<send_ACK>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_SDA@plt>
  mov    $0x0,%eax
  call   <set_SDA_output@plt>
  mov    $0x1,%edi
  call   <_delay_us@plt>
  mov    $0x0,%eax
  call   <send_SCL_pulse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void send_ACK(void) {
  clear_SDA();
  set_SDA_output();
  _delay_us(1);
  send_SCL_pulse();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<send_ACK>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_SDA@plt>
  xor    %eax,%eax
  call   <set_SDA_output@plt>
  mov    $0x1,%edi
  call   <_delay_us@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <send_SCL_pulse@plt>
```

assistant: ```c
void send_ACK(void) {
  clear_SDA();
  set_SDA_output();
  _delay_us(1);
  send_SCL_pulse();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<send_ACK>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_SDA@plt>
  xor    %eax,%eax
  call   <set_SDA_output@plt>
  mov    $0x1,%edi
  call   <_delay_us@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <send_SCL_pulse@plt>
```

assistant: ```c
void send_ACK(void) {
  clear_SDA();
  set_SDA_output();
  _delay_us(1);
  send_SCL_pulse();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compose_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0xc000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <transpose_image@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L19:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x6,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <compose_row@plt>
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L19
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <transpose_image@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L11:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x6,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <compose_row@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void compose_image(float *image) {
  int row;
  float *transposed_image = (float *)malloc(sizeof(float) * 3 * 64 * 64);
  transpose_image(image, transposed_image);
  for (row = 0; row < 64; ++row)
    compose_row(transposed_image + 3 * 64 * row);
  transpose_image(transposed_image, image);
  for (row = 0; row < 64; ++row)
    compose_row(image + 3 * 64 * row);
  free(transposed_image);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compose_image>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0xc000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <transpose_image@plt>
  mov    %r13,%rbx
  lea    0xc000(%r13),%r12
L14:
  mov    %rbx,%rdi
  call   <compose_row@plt>
  add    $0x300,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <transpose_image@plt>
  mov    %rbp,%rbx
  add    $0xc000,%rbp
L15:
  mov    %rbx,%rdi
  call   <compose_row@plt>
  add    $0x300,%rbx
  cmp    %rbp,%rbx
  jne    L15
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void compose_image(float *image) {
  int row;
  float *transposed_image = (float *)malloc(sizeof(float) * 3 * 64 * 64);
  transpose_image(image, transposed_image);
  for (row = 0; row < 64; ++row)
    compose_row(transposed_image + 3 * 64 * row);
  transpose_image(transposed_image, image);
  for (row = 0; row < 64; ++row)
    compose_row(image + 3 * 64 * row);
  free(transposed_image);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compose_image>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  mov    %rax,%rsi
  call   <transpose_image@plt>
  mov    %r13,%rbp
  lea    0xc000(%r13),%r12
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  add    $0x300,%rbp
  call   <compose_row@plt>
  cmp    %r12,%rbp
  jne    L8
  mov    %rbx,%rsi
  mov    %r13,%rdi
  lea    0xc000(%rbx),%rbp
  call   <transpose_image@plt>
  xchg   %ax,%ax
L14:
  mov    %rbx,%rdi
  add    $0x300,%rbx
  call   <compose_row@plt>
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void compose_image(float *image) {
  int row;
  float *transposed_image = (float *)malloc(sizeof(float) * 3 * 64 * 64);
  transpose_image(image, transposed_image);
  for (row = 0; row < 64; ++row)
    compose_row(transposed_image + 3 * 64 * row);
  transpose_image(transposed_image, image);
  for (row = 0; row < 64; ++row)
    compose_row(image + 3 * 64 * row);
  free(transposed_image);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compose_image>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  mov    %rax,%rsi
  call   <transpose_image@plt>
  mov    %r13,%rbp
  lea    0xc000(%r13),%r12
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  add    $0x300,%rbp
  call   <compose_row@plt>
  cmp    %rbp,%r12
  jne    L17
  mov    %rbx,%rsi
  mov    %r13,%rdi
  lea    0xc000(%rbx),%rbp
  call   <transpose_image@plt>
  xchg   %ax,%ax
L1:
  mov    %rbx,%rdi
  add    $0x300,%rbx
  call   <compose_row@plt>
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void compose_image(float *image) {
  int row;
  float *transposed_image = (float *)malloc(sizeof(float) * 3 * 64 * 64);
  transpose_image(image, transposed_image);
  for (row = 0; row < 64; ++row)
    compose_row(transposed_image + 3 * 64 * row);
  transpose_image(transposed_image, image);
  for (row = 0; row < 64; ++row)
    compose_row(image + 3 * 64 * row);
  free(transposed_image);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_consonant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x494541756f696561,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x554f,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x18(%rbp)
  cmpb   $0x40,-0x24(%rbp)
  jle    L67
  cmpb   $0x7a,-0x24(%rbp)
  jle    L48
L67:
  mov    $0x0,%eax
  jmp    L50
L61:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  cmp    %al,-0x24(%rbp)
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L50
L40:
  addl   $0x1,-0x18(%rbp)
L48:
  cmpl   $0x9,-0x18(%rbp)
  jle    L61
  mov    $0x1,%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int is_consonant(char ch) {
  char vowels[11] = "aeiouAEIOU";
  int i = 0;
  if (ch < 'A' || ch > 'z') {
    return 0;
  }
  while (i < 10) {
    if (vowels[i] == ch) {
      return -1;
    }
    i++;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_consonant>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x494541756f696561,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x554f,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  sub    $0x41,%edi
  mov    $0x0,%eax
  cmp    $0x39,%dil
  ja     L11
  lea    0xd(%rsp),%rax
  lea    0x17(%rsp),%rcx
L33:
  cmp    %dl,(%rax)
  je     L21
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L33
  mov    $0x1,%eax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x28,%rsp
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L11
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_consonant(char ch) {
  char vowels[11] = "aeiouAEIOU";
  int i = 0;
  if (ch < 'A' || ch > 'z') {
    return 0;
  }
  while (i < 10) {
    if (vowels[i] == ch) {
      return -1;
    }
    i++;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_consonant>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%ecx
  sub    $0x41,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x494541756f696561,%rax
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xd(%rsp)
  mov    $0x554f,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  cmp    $0x39,%dil
  ja     L54
  lea    0xe(%rsp),%rax
  lea    0x17(%rsp),%rsi
  mov    $0x61,%edx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rax),%edx
  add    $0x1,%rax
L34:
  cmp    %cl,%dl
  je     L5
  cmp    %rsi,%rax
  jne    L7
  mov    $0x1,%eax
L54:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  jmp    L54
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_consonant(char ch) {
  char vowels[11] = "aeiouAEIOU";
  int i = 0;
  if (ch < 'A' || ch > 'z') {
    return 0;
  }
  while (i < 10) {
    if (vowels[i] == ch) {
      return -1;
    }
    i++;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_consonant>:
  endbr64
  lea    -0x41(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x39,%cl
  ja     L1
  mov    $0x1,%eax
  cmp    $0x34,%cl
  ja     L1
  movabs $0xffefbeeeffefbeee,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  or     $0x1,%eax
L1:
  ret
```

assistant: ```c
int is_consonant(char ch) {
  char vowels[11] = "aeiouAEIOU";
  int i = 0;
  if (ch < 'A' || ch > 'z') {
    return 0;
  }
  while (i < 10) {
    if (vowels[i] == ch) {
      return -1;
    }
    i++;
  }
  return 1;
}
```