ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0x28(%rsp)
  cmp    $0x1,%esi
  jle    L11
  mov    %rdi,%r15
  mov    %esi,%ebx
  sar    %ebx
  mov    %ebx,0x14(%rsp)
  mov    %ebx,%ebx
  mov    %rbx,0x20(%rsp)
  mov    %esi,%ebx
  movslq %esi,%rax
  lea    -0x4(,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%r13d
  and    $0x1,%ebx
  mov    %ebx,0x2c(%rsp)
L0:
  lea    0x0(,%r13,4),%rax
  mov    %rax,0x8(%rsp)
  mov    0x28(%rsp),%eax
  sub    %r13d,%eax
  cltq
  lea    -0x8(%r15,%rax,8),%r14
  lea    -0x4(,%rax,4),%rax
  mov    %rax,(%rsp)
  mov    0x2c(%rsp),%r12d
  neg    %r12d
  mov    0x18(%rsp),%rbp
  mov    $0x0,%ebx
L12:
  mov    0x8(%rsp),%rcx
  add    (%r15,%rbp,2),%rcx
  mov    %rbp,%rdx
  add    (%r14),%rdx
  mov    (%rsp),%rsi
  add    (%r15,%rbx,2),%rsi
  mov    %rbx,%rdi
  add    (%r15,%r13,8),%rdi
  call   <rotate4@plt>
  sub    $0x4,%rbp
  add    $0x4,%rbx
  add    $0x1,%r12d
  cmp    %r12d,0x14(%rsp)
  jg     L12
  add    $0x1,%r13
  cmp    0x20(%rsp),%r13
  jne    L0
L11:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void rotate(int **matrix, int matrixRowSize, int matrixColSize) {
  if (matrixRowSize <= 1)
    return;
  int i, j;
  for (i = 0; i < (matrixRowSize >> 1); i++) {
    for (j = 0; j - (matrixRowSize & 1) < (matrixRowSize >> 1); j++) {
      rotate4(&matrix[i][j], &matrix[j][matrixRowSize - i - 1], &matrix[matrixRowSize - i - 1][matrixRowSize - j - 1], &matrix[matrixRowSize - j - 1][i]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotate>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  push   %r15
  mov    %esi,%eax
  xor    %r15d,%r15d
  push   %r14
  sar    %eax
  mov    %rdi,%r14
  push   %r13
  movslq %eax,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movslq %esi,%rsi
  and    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %eax,0x18(%rsp)
  lea    0x0(,%r13,4),%rax
  mov    %ebx,0x1c(%rsp)
  lea    -0x4(,%rsi,4),%rbx
  mov    %rbx,0x10(%rsp)
  mov    %rbx,%r13
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L8:
  mov    0x1c(%rsp),%r12d
  mov    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  neg    %r12d
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%r14,%rbp,2),%rcx
  mov    (%r14,%rbx,2),%rsi
  add    $0x1,%r12d
  mov    (%r14,%r13,2),%rdx
  mov    (%r14,%r15,2),%rdi
  add    %r15,%rcx
  add    %r13,%rsi
  add    %rbp,%rdx
  add    %rbx,%rdi
  sub    $0x4,%rbp
  add    $0x4,%rbx
  call   <rotate4@plt>
  cmp    %r12d,0x18(%rsp)
  jg     L0
  add    $0x4,%r15
  sub    $0x4,%r13
  cmp    %r15,0x8(%rsp)
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  ret
```

assistant: ```c
void rotate(int **matrix, int matrixRowSize, int matrixColSize) {
  if (matrixRowSize <= 1)
    return;
  int i, j;
  for (i = 0; i < (matrixRowSize >> 1); i++) {
    for (j = 0; j - (matrixRowSize & 1) < (matrixRowSize >> 1); j++) {
      rotate4(&matrix[i][j], &matrix[j][matrixRowSize - i - 1], &matrix[matrixRowSize - i - 1][matrixRowSize - j - 1], &matrix[matrixRowSize - j - 1][i]);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotate>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  push   %r15
  mov    %esi,%eax
  xor    %r15d,%r15d
  push   %r14
  sar    %eax
  mov    %rdi,%r14
  push   %r13
  movslq %eax,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movslq %esi,%rsi
  and    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %eax,0x18(%rsp)
  lea    0x0(,%r13,4),%rax
  mov    %ebx,0x1c(%rsp)
  lea    -0x4(,%rsi,4),%rbx
  mov    %rbx,0x10(%rsp)
  mov    %rbx,%r13
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L10:
  mov    0x1c(%rsp),%r12d
  mov    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  neg    %r12d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%r14,%rbp,2),%rcx
  mov    (%r14,%rbx,2),%rsi
  add    $0x1,%r12d
  mov    (%r14,%r13,2),%rdx
  mov    (%r14,%r15,2),%rdi
  add    %r15,%rcx
  add    %r13,%rsi
  add    %rbp,%rdx
  add    %rbx,%rdi
  sub    $0x4,%rbp
  add    $0x4,%rbx
  call   <rotate4@plt>
  cmp    %r12d,0x18(%rsp)
  jg     L19
  add    $0x4,%r15
  sub    $0x4,%r13
  cmp    %r15,0x8(%rsp)
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  ret
```

assistant: ```c
void rotate(int **matrix, int matrixRowSize, int matrixColSize) {
  if (matrixRowSize <= 1)
    return;
  int i, j;
  for (i = 0; i < (matrixRowSize >> 1); i++) {
    for (j = 0; j - (matrixRowSize & 1) < (matrixRowSize >> 1); j++) {
      rotate4(&matrix[i][j], &matrix[j][matrixRowSize - i - 1], &matrix[matrixRowSize - i - 1][matrixRowSize - j - 1], &matrix[matrixRowSize - j - 1][i]);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L16
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jg     L25
  mov    $0x0,%eax
  call   <abort@plt>
L25:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L16:
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_n(const unsigned char *buf, size_t count) {
  while (count) {
    ssize_t wrote = write(1, buf, count);
    if (wrote <= 0)
      abort();
    count -= wrote;
    buf += wrote;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_n>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rsi,%rsi
  jne    L23
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  add    %rbx,%r12
  sub    %rbx,%rbp
  je     L4
L23:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jg     L19
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L19
```

assistant: ```c
void write_n(const unsigned char *buf, size_t count) {
  while (count) {
    ssize_t wrote = write(1, buf, count);
    if (wrote <= 0)
      abort();
    count -= wrote;
    buf += wrote;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_n>:
  endbr64
  test   %rsi,%rsi
  je     L10
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L26
  nopl   (%rax)
L13:
  add    %rbx,%r12
  sub    %rbx,%rbp
  je     L14
L26:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jg     L13
  xor    %eax,%eax
  add    %rbx,%r12
  call   <abort@plt>
  sub    %rbx,%rbp
  jne    L26
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void write_n(const unsigned char *buf, size_t count) {
  while (count) {
    ssize_t wrote = write(1, buf, count);
    if (wrote <= 0)
      abort();
    count -= wrote;
    buf += wrote;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_n>:
  endbr64
  test   %rsi,%rsi
  je     L29
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L43
  nopl   (%rax)
L37:
  add    %rbx,%r12
  sub    %rbx,%rbp
  je     L36
L43:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jg     L37
  xor    %eax,%eax
  add    %rbx,%r12
  call   <abort@plt>
  sub    %rbx,%rbp
  jne    L43
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L29:
  ret
```

assistant: ```c
void write_n(const unsigned char *buf, size_t count) {
  while (count) {
    ssize_t wrote = write(1, buf, count);
    if (wrote <= 0)
      abort();
    count -= wrote;
    buf += wrote;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <run@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int c, char **v) {
  run();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <run@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int c, char **v) {
  run();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int c, char **v) {
  run();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int c, char **v) {
  run();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L29
L2:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L10:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x2,-0x14(%rbp)
  jle    L10
  addl   $0x1,-0x18(%rbp)
L29:
  cmpl   $0x6,-0x18(%rbp)
  jle    L2
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string

tool: D27: smax

tool: D3: # c::%s:len=%d


tool: D17: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smax", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D26(%rip),%r15
  jmp    L2
L38:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L17
L2:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L29:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L29
  jmp    L38
L17:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
datatype: string
name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D26: smax

tool: D24: # c::%s:len=%d


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smax", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D11(%rip),%r15
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L11:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L5:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L5
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L11
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D4
type: string

tool: D11: smax

tool: D9: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smax", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D28(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L19:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L0:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L0
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L19
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D28: smax

tool: D1: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smax", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_dwt_aonarrayupload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  call   <dwt_write8bitoffsetreg@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  call   <dwt_write8bitoffsetreg@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _dwt_aonarrayupload(void) {
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x00);
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x02);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_dwt_aonarrayupload>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  call   <dwt_write8bitoffsetreg@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  call   <dwt_write8bitoffsetreg@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _dwt_aonarrayupload(void) {
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x00);
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x02);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_dwt_aonarrayupload>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  call   <dwt_write8bitoffsetreg@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x2c,%edi
  add    $0x8,%rsp
  jmp    1050 <dwt_write8bitoffsetreg@plt>
```

assistant: ```c
void _dwt_aonarrayupload(void) {
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x00);
  dwt_write8bitoffsetreg(0x2C, 0x02, 0x02);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prntft>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    D20(%rip),%r9
  lea    D33(%rip),%r8
  lea    D69(%rip),%rcx
  lea    D60(%rip),%rdx
  lea    D87(%rip),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%r12),%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd 0x4(%r12),%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm0
  lea    D80(%rip),%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%r13
  cmp    $0x2,%r13
  jbe    L4
  lea    (%r12,%rbx,8),%rbp
  mov    $0x3,%ebx
  lea    D57(%rip),%r14
L10:
  pxor   %xmm0,%xmm0
  cvtss2sd (%r12,%rbx,4),%xmm0
  lea    -0x1(%rbx),%rsi
  shr    %rsi
  pxor   %xmm3,%xmm3
  cvtss2sd 0x0(%rbp),%xmm3
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%r12,%rbx,4),%xmm1
  mov    %r14,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  add    $0x2,%rbx
  sub    $0x8,%rbp
  cmp    %r13,%rbx
  jbe    L10
L4:
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D20
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D69
type_guessed: string
name: read_data
arguments: tag: D60
type_guessed: string
name: read_data
arguments: tag: D87
type_guessed: string
name: read_data
arguments: tag: D37
type_guessed: string
name: read_data
arguments: tag: D80
type_guessed: string
name: read_data
arguments: tag: D57
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string

tool: D20: imag.(N-n)

tool: D33: real(N-n)

tool: D69: imag.(n)

tool: D60: real(n)

tool: D87: n

tool: D37: %4s %13s %13s %12s %13s


tool: D80:    0 %14.6f %12.6f %12.6f %12.6f


tool: D57: %4lu %14.6f %12.6f %12.6f %12.6f


tool: D48:  press return to continue ...

assistant: ```c
void prntft(float data[], unsigned long nn) {
  unsigned long n;
  printf("%4s %13s %13s %12s %13s\n", "n", "real(n)", "imag.(n)", "real(N-n)", "imag.(N-n)");
  printf("   0 %14.6f %12.6f %12.6f %12.6f\n", data[1], data[2], data[1], data[2]);
  for (n = 3; n <= nn + 1; n += 2) {
    printf("%4lu %14.6f %12.6f %12.6f %12.6f\n", ((n - 1) / 2), data[n], data[n + 1], data[2 * nn + 2 - n], data[2 * nn + 3 - n]);
  }
  printf(" press return to continue ...\n");
  (void)getchar();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prntft>:
  endbr64
  push   %r14
  lea    D10(%rip),%r9
  xor    %eax,%eax
  lea    D36(%rip),%r8
  push   %r13
  lea    D22(%rip),%rcx
  lea    D87(%rip),%rdx
  push   %r12
  mov    %rdi,%r12
  lea    D60(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D23(%rip),%rsi
  lea    0x1(%rbx),%r13
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  lea    D6(%rip),%rdi
  cvtss2sd 0x8(%r12),%xmm1
  cvtss2sd 0x4(%r12),%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm2,%xmm0
  mov    $0x4,%eax
  call   <printf@plt>
  cmp    $0x2,%r13
  jbe    L17
  lea    (%r12,%rbx,8),%rbp
  lea    D37(%rip),%r14
  mov    $0x3,%ebx
  nopl   0x0(%rax)
L9:
  lea    -0x1(%rbx),%rsi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r14,%rdi
  shr    %rsi
  pxor   %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  mov    $0x4,%eax
  cvtss2sd (%r12,%rbx,4),%xmm0
  cvtss2sd 0x4(%r12,%rbx,4),%xmm1
  add    $0x2,%rbx
  cvtss2sd 0x0(%rbp),%xmm3
  cvtss2sd -0x4(%rbp),%xmm2
  call   <printf@plt>
  sub    $0x8,%rbp
  cmp    %r13,%rbx
  jbe    L9
L17:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <getchar@plt>
```

tool_calls: name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D36
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D87
datatype: string
name: read_data
arguments: tag: D60
datatype: string
name: read_data
arguments: tag: D23
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D37
datatype: string
name: read_data
arguments: tag: D1
datatype: string

tool: D10: imag.(N-n)

tool: D36: real(N-n)

tool: D22: imag.(n)

tool: D87: real(n)

tool: D60: %4s %13s %13s %12s %13s


tool: D23: n

tool: D6:    0 %14.6f %12.6f %12.6f %12.6f


tool: D37: %4lu %14.6f %12.6f %12.6f %12.6f


tool: D1:  press return to continue ...

assistant: ```c
void prntft(float data[], unsigned long nn) {
  unsigned long n;
  printf("%4s %13s %13s %12s %13s\n", "n", "real(n)", "imag.(n)", "real(N-n)", "imag.(N-n)");
  printf("   0 %14.6f %12.6f %12.6f %12.6f\n", data[1], data[2], data[1], data[2]);
  for (n = 3; n <= nn + 1; n += 2) {
    printf("%4lu %14.6f %12.6f %12.6f %12.6f\n", ((n - 1) / 2), data[n], data[n + 1], data[2 * nn + 2 - n], data[2 * nn + 3 - n]);
  }
  printf(" press return to continue ...\n");
  (void)getchar();
  return;
}
```