ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<zzz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L52
  mov    %rdi,%r8
  lea    -0x1(%rdx),%r9d
L19:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%r8,%rax,1)
  mov    %rax,%rdi
  add    $0x1,%rax
  cmp    %r9,%rdi
  jne    L19
L52:
  add    $0x6,%edx
  mov    %edx,(%rcx)
  mov    %rsp,%rbx
  mov    %rsp,%rax
L17:
  cmp    %rax,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L17
L48:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %al,0x4(%rsp)
  mov    %rsp,%rax
L34:
  cmp    %rax,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L34
L33:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %al,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%eax
  call   <foo@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    -0x8(%rbp),%rbx
  leave
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zzz(char *s1, char *s2, int len, int *q) {
  int z = 5;
  unsigned int i, b;
  struct {
    char a[z];
  } x;
  for (i = 0; i < len; i++)
    s1[i] = s2[i];
  b = z & 0x3;
  len += (b == 0 ? 0 : 1) + z;
  *q = len;
  foo(x, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zzz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L40
  mov    %edx,%r9d
  nopl   0x0(%rax,%rax,1)
L64:
  movzbl (%rsi,%rax,1),%r8d
  mov    %r8b,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L64
L40:
  add    $0x6,%edx
  mov    %rsp,%rbx
  mov    %edx,(%rcx)
  cmp    %rbx,%rsp
  je     L57
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rbx,%rsp
  jne    L10
L57:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %rsp,%rdi
  mov    %al,0x4(%rsp)
  cmp    %rdi,%rsp
  je     L65
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L42
L65:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %rsp,%rsi
  mov    %al,0x4(%rsp)
  xor    %eax,%eax
  call   <foo@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    -0x8(%rbp),%rbx
  leave
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zzz(char *s1, char *s2, int len, int *q) {
  int z = 5;
  unsigned int i, b;
  struct {
    char a[z];
  } x;
  for (i = 0; i < len; i++)
    s1[i] = s2[i];
  b = z & 0x3;
  len += (b == 0 ? 0 : 1) + z;
  *q = len;
  foo(x, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<zzz>:
  endbr64
  push   %rbp
  mov    %rcx,%r8
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L183
  lea    0x1(%rsi),%r9
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%eax
  sub    %r9,%rcx
  cmp    $0xe,%rcx
  jbe    L36
  cmp    $0x6,%eax
  jbe    L36
  mov    %edx,%ecx
  cmp    $0xe,%eax
  jbe    L191
  shr    $0x4,%ecx
  xor    %eax,%eax
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L50:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L50
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  test   $0xf,%dl
  je     L183
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    -0x1(%rcx),%r9d
  cmp    $0x6,%r9d
  jbe    L81
L110:
  mov    %eax,%r9d
  mov    (%rsi,%r9,1),%r10
  mov    %r10,(%rdi,%r9,1)
  mov    %ecx,%r9d
  and    $0xfffffff8,%r9d
  add    %r9d,%eax
  cmp    %r9d,%ecx
  je     L183
L81:
  mov    %eax,%ecx
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L183
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L183
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L183
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L183
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rdi,%rcx,1)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jbe    L183
  movzbl (%rsi,%rcx,1),%r9d
  add    $0x6,%eax
  mov    %r9b,(%rdi,%rcx,1)
  cmp    %eax,%edx
  jbe    L183
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
L183:
  add    $0x6,%edx
  mov    %rsp,%rbx
  mov    %edx,(%r8)
  cmp    %rbx,%rsp
  je     L43
L84:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rbx,%rsp
  jne    L84
L43:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %rsp,%rdi
  mov    %al,0x4(%rsp)
  cmp    %rdi,%rsp
  je     L217
L53:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L53
L217:
  sub    $0x10,%rsp
  orq    $0x0,0x8(%rsp)
  mov    -0x1d(%rbp),%eax
  mov    %eax,(%rsp)
  movzbl -0x19(%rbp),%eax
  mov    %rsp,%rsi
  mov    %al,0x4(%rsp)
  xor    %eax,%eax
  call   <foo@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %edx,%r9d
  xor    %eax,%eax
  nopl   (%rax)
L143:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L143
  jmp    L183
L191:
  xor    %eax,%eax
  jmp    L110
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zzz(char *s1, char *s2, int len, int *q) {
  int z = 5;
  unsigned int i, b;
  struct {
    char a[z];
  } x;
  for (i = 0; i < len; i++)
    s1[i] = s2[i];
  b = z & 0x3;
  len += (b == 0 ? 0 : 1) + z;
  *q = len;
  foo(x, x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x7b,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L50
L39:
  cmpl   $0x5,-0x8(%rbp)
  jne    L25
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L0
L25:
  cmpl   $0x6,-0x8(%rbp)
  jne    L18
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%eax
  jmp    L0
L18:
  addl   $0x1,-0x8(%rbp)
L50:
  cmpl   $0x63,-0x8(%rbp)
  jle    L39
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D6: 1


tool: D13: 2


tool: D17: 3


assistant: ```c
int main() {
  int i = 123, j = 5;
  while (i < 100) {
    if (i == 5) {
      printf("1\n");
      return 1;
    }
    if (i == 6) {
      printf("2\n");
      return 2;
    }
    i++;
  }
  printf("3\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: 3


assistant: ```c
int main() {
  int i = 123, j = 5;
  while (i < 100) {
    if (i == 5) {
      printf("1\n");
      return 1;
    }
    if (i == 6) {
      printf("2\n");
      return 2;
    }
    i++;
  }
  printf("3\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: 3


assistant: ```c
int main() {
  int i = 123, j = 5;
  while (i < 100) {
    if (i == 5) {
      printf("1\n");
      return 1;
    }
    if (i == 6) {
      printf("2\n");
      return 2;
    }
    i++;
  }
  printf("3\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: 3


assistant: ```c
int main() {
  int i = 123, j = 5;
  while (i < 100) {
    if (i == 5) {
      printf("1\n");
      return 1;
    }
    if (i == 6) {
      printf("2\n");
      return 2;
    }
    i++;
  }
  printf("3\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bitprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L48
L29:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  jne    L24
  mov    $0x30,%eax
  jmp    L19
L24:
  mov    $0x31,%eax
L19:
  mov    %eax,%edi
  call   <putchar@plt>
  shll   -0x14(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L32
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L32
  mov    $0x20,%edi
  call   <putchar@plt>
L32:
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void bitprint(int a) {
  int n = sizeof(int) * CHAR_BIT;
  int mask = 1 << (n - 1);
  int i;
  for (i = 1; i <= n; ++i) {
    putchar((!(a & mask)) ? '0' : '1');
    a <<= 1;
    if (!(i % CHAR_BIT) && i < n) {
      putchar(' ');
    }
  }
  putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitprint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    D6(%rip),%rax
  mov    (%rax),%r13d
  shl    $0x2,%r13d
  lea    -0x1(%r13),%ecx
  mov    $0x1,%r12d
  shl    %cl,%r12d
  test   %r13d,%r13d
  jle    L24
  mov    %edi,%ebp
  lea    0x1(%r13),%r14d
  mov    $0x1,%ebx
  jmp    L15
L36:
  mov    $0x20,%edi
  call   <putchar@plt>
L37:
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  je     L24
L15:
  mov    %r12d,%edi
  and    %ebp,%edi
  cmp    $0x1,%edi
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  call   <putchar@plt>
  add    %ebp,%ebp
  mov    D6(%rip),%rsi
  mov    %ebx,%eax
  cltd
  idivl  (%rsi)
  test   %edx,%edx
  jne    L37
  cmp    %ebx,%r13d
  jle    L37
  jmp    L36
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bitprint(int a) {
  int n = sizeof(int) * CHAR_BIT;
  int mask = 1 << (n - 1);
  int i;
  for (i = 1; i <= n; ++i) {
    putchar((!(a & mask)) ? '0' : '1');
    a <<= 1;
    if (!(i % CHAR_BIT) && i < n) {
      putchar(' ');
    }
  }
  putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rbx
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%r12d
  lea    -0x1(%r12),%ecx
  shl    %cl,%ebp
  test   %r12d,%r12d
  jle    L13
  mov    %edi,%r15d
  lea    0x1(%r12),%r13d
  mov    $0x1,%r14d
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %ebp,%edi
  and    %r15d,%edi
  cmp    $0x1,%edi
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  add    %r15d,%r15d
  call   <putchar@plt>
  mov    %r14d,%eax
  cltd
  idivl  (%rbx)
  test   %edx,%edx
  jne    L6
  cmp    %r14d,%r12d
  jle    L6
  mov    $0x20,%edi
  call   <putchar@plt>
L6:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jne    L33
L13:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
```

assistant: ```c
void bitprint(int a) {
  int n = sizeof(int) * CHAR_BIT;
  int mask = 1 << (n - 1);
  int i;
  for (i = 1; i <= n; ++i) {
    putchar((!(a & mask)) ? '0' : '1');
    a <<= 1;
    if (!(i % CHAR_BIT) && i < n) {
      putchar(' ');
    }
  }
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbx
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%r12d
  lea    -0x1(%r12),%ecx
  shl    %cl,%ebp
  test   %r12d,%r12d
  jle    L7
  mov    %edi,%r15d
  lea    0x1(%r12),%r13d
  mov    $0x1,%r14d
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebp,%edi
  and    %r15d,%edi
  cmp    $0x1,%edi
  mov    $0x30,%edi
  sbb    $0xffffffff,%edi
  add    %r15d,%r15d
  call   <putchar@plt>
  mov    %r14d,%eax
  cltd
  idivl  (%rbx)
  test   %edx,%edx
  jne    L36
  cmp    %r14d,%r12d
  jle    L36
  mov    $0x20,%edi
  call   <putchar@plt>
L36:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jne    L2
L7:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
```

assistant: ```c
void bitprint(int a) {
  int n = sizeof(int) * CHAR_BIT;
  int mask = 1 << (n - 1);
  int i;
  for (i = 1; i <= n; ++i) {
    putchar((!(a & mask)) ? '0' : '1');
    a <<= 1;
    if (!(i % CHAR_BIT) && i < n) {
      putchar(' ');
    }
  }
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int64_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L56
L57:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x4(,%r14,4),%rdi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L25
L4:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x2,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L54
  shl    $0x2,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L31:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L31
L54:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  lea    D5(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L57
L25:
  lea    D18(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D18
datatype: string

tool: D5: Allocation error 1 in imatrix()

tool: D18: Allocation error 2 in int64_matrix()

assistant: ```c
int64_t **int64_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int64_t **m;
  m = (int64_t **)malloc((size_t)((nrow + 1) * sizeof(int64_t *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in imatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (int64_t *)malloc((size_t)((nrow * ncol + 1) * sizeof(int64_t)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in int64_matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int64_matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L43
L36:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L52
L38:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L15
  lea    0x0(,%rbp,4),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L35
L15:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L43:
  lea    D10(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L36
  nopl   0x0(%rax)
L52:
  lea    D17(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string

tool: D10: Allocation error 1 in imatrix()

tool: D17: Allocation error 2 in int64_matrix()

assistant: ```c
int64_t **int64_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int64_t **m;
  m = (int64_t **)malloc((size_t)((nrow + 1) * sizeof(int64_t *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in imatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (int64_t *)malloc((size_t)((nrow * ncol + 1) * sizeof(int64_t)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in int64_matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int64_matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%rdi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L47
L31:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L16
L43:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L55
  lea    0x0(,%rbx,4),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
L21:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L21
L55:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  lea    D10(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  jmp    L31
  nopl   0x0(%rax)
L16:
  lea    D1(%rip),%rdi
  call   <zig_legacy_alloc_error@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L43
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D10: Allocation error 1 in imatrix()

tool: D1: Allocation error 2 in int64_matrix()

assistant: ```c
int64_t **int64_matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  int64_t **m;
  m = (int64_t **)malloc((size_t)((nrow + 1) * sizeof(int64_t *)));
  if (!m)
    zig_legacy_alloc_error("Allocation error 1 in imatrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (int64_t *)malloc((size_t)((nrow * ncol + 1) * sizeof(int64_t)));
  if (!m[nrl])
    zig_legacy_alloc_error("Allocation error 2 in int64_matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isComand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L77
  mov    $0x0,%eax
  jmp    L0
L77:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L53:
  cmpl   $0x0,-0x10(%rbp)
  jns    L54
  mov    $0x0,%eax
  jmp    L0
L54:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L56
  mov    $0x0,%eax
  jmp    L0
L56:
  subl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L17
  cmpl   $0x0,-0xc(%rbp)
  jns    L53
L17:
  mov    $0x1,%eax
L0:
  leave
  ret
```

assistant: ```c
int isComand(const char *argumento, const char *comando) {
  int i, j;
  int tamArgumento = strlen(argumento);
  int tamComando = strlen(comando);
  if (tamArgumento < tamComando)
    return 0;
  for (i = tamComando - 1, j = tamArgumento - 1; argumento[j] != '/' && j >= 0; i--, j--) {
    if (i < 0)
      return 0;
    if (comando[i] != argumento[j])
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isComand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%r12d
  jl     L37
  lea    -0x1(%r12),%edx
  movslq %edx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%ecx
  test   %edx,%edx
  js     L47
  cmp    $0x2f,%cl
  je     L47
  test   %eax,%eax
  jle    L93
  lea    -0x2(%r12),%edx
  movslq %edx,%rdx
  movslq %r12d,%r12
  lea    -0x3(%r12),%rsi
  lea    -0x1(%rax),%edi
  sub    %rdi,%rsi
  cltq
  sub    %r12,%rax
  add    %rbx,%rax
L85:
  cmp    %cl,0x1(%rax,%rdx,1)
  jne    L111
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %edx,%edx
  js     L80
  cmp    $0x2f,%cl
  je     L80
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L85
  mov    $0x0,%edx
  jmp    L37
L80:
  mov    $0x1,%edx
L37:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    $0x1,%edx
  jmp    L37
L93:
  mov    $0x0,%edx
  jmp    L37
L111:
  mov    $0x0,%edx
  jmp    L37
```

assistant: ```c
int isComand(const char *argumento, const char *comando) {
  int i, j;
  int tamArgumento = strlen(argumento);
  int tamComando = strlen(comando);
  if (tamArgumento < tamComando)
    return 0;
  for (i = tamComando - 1, j = tamArgumento - 1; argumento[j] != '/' && j >= 0; i--, j--) {
    if (i < 0)
      return 0;
    if (comando[i] != argumento[j])
      return 0;
  }
  return 1;
}
```