user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L17
  mov    (%rsi),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L17:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jle    L93
L15:
  mov    0x8(%rbx),%rdi
  lea    D46(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D64(%rip),%rbx
  call   <atoi@plt>
  lea    D51(%rip),%rdi
  movl   $0xffffffff,0x4(%rsp)
  mov    %eax,%r13d
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  ja     L25
  mov    %r13d,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7fffffff,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L29
  cmp    $0x2,%eax
  jne    L82
  lea    0x7fffffff(%r13),%r14d
  mov    %r13d,%edx
  mov    $0x7fffffff,%esi
  xor    %eax,%eax
  mov    %r14d,%ecx
  lea    D59(%rip),%rdi
  call   <printf@plt>
L82:
  sub    $0x8,%rsp
  mov    %r13d,%ecx
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  push   %r14
  mov    $0x7fffffff,%edx
  mov    $0x7fffffff,%esi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    $0x7fffffff,%edi
  call   <checkForOverflow@plt>
  pop    %rdx
  pop    %rcx
  test   %rax,%rax
  je     L42
  lea    D23(%rip),%rdi
  call   <puts@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L29:
  imul   $0x7fffffff,%r13d,%r14d
  mov    %r13d,%edx
  mov    $0x7fffffff,%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  mov    %r14d,%ecx
  call   <printf@plt>
  jmp    L82
L93:
  mov    (%rbx),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L15
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D46
type_infered: string
name: read_data
arguments: data_tag: D64
type_infered: string
name: read_data
arguments: data_tag: D51
type_infered: string
name: read_data
arguments: data_tag: D47
type_infered: string
name: read_data
arguments: data_tag: D57
type_infered: string
name: read_data
arguments: data_tag: D59
type_infered: string
name: read_data
arguments: data_tag: D30
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string

tool: D17: usage: %s [POSITIVE NUMBER]


tool: D46: >> 

tool: D64: %d

tool: D51: 
Enter
1: Multiplication
2: Addition

tool: D47: You entered %d


tool: D57: The largest signed 32-bit integer is 0x7FFFFFFF = %d


tool: D59: %d + %d = %d


tool: D30: In hex:
%d = 0x%x
%d = 0x%x
%d = 0x%x


tool: D23: 
Overflow exists.

tool: D19: 
Overflow does not exist.

tool: D20: %d x %d = %d


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("usage: %s [POSITIVE NUMBER]\n", argv[0]);
    exit(0);
  }
  if (atoi(argv[1]) < 1) {
    printf("usage: %s [POSITIVE NUMBER]\n", argv[0]);
    exit(0);
  }
  int baseNum = 0x7FFFFFFF;
  int x = atoi(argv[1]);
  int ans;
  int temp = -1;
  printf("\nEnter\n1: Multiplication\n2: Addition\n");
  do {
    printf(">> ");
    scanf("%d", &temp);
  } while ((temp != 1) && (temp != 2));
  printf("You entered %d\n", x);
  printf("The largest signed 32-bit integer is 0x7FFFFFFF = %d\n", baseNum);
  switch (temp) {
  case 1:
    ans = x * baseNum;
    printf("%d x %d = %d\n", baseNum, x, ans);
    break;
  case 2:
    ans = x + baseNum;
    printf("%d + %d = %d\n", baseNum, x, ans);
  }
  printf("In hex:\n%d = 0x%x\n%d = 0x%x\n%d = 0x%x\n", baseNum, baseNum, x, x, ans, ans);
  if (checkForOverflow(baseNum, x, ans)) {
    printf("\nOverflow exists.\n");
  } else {
    printf("\nOverflow does not exist.\n");
  }
}
```