ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc8>:
  endbr64
  xor    %edi,%esi
  lea    (%rsi,%rsi,1),%eax
  mov    %eax,%edx
  xor    $0x7,%edx
  and    $0x80,%esi
  cmovne %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x7,%ecx
  test   $0x80,%al
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x7,%ecx
  and    $0x80,%edx
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x7,%ecx
  test   $0x80,%al
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x7,%ecx
  and    $0x80,%edx
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x7,%ecx
  test   $0x80,%al
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x7,%ecx
  and    $0x80,%edx
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%r8d
  mov    %r8d,%edx
  xor    $0x7,%edx
  test   $0x80,%al
  cmovne %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint8_t crc8(uint8_t crc, uint8_t a) {
  uint8_t crc_u = a;
  crc_u ^= crc;
  for (int i = 0; i < 8; i++) {
    crc_u = (crc_u & 0x80) ? 0x7 ^ (crc_u << 1) : (crc_u << 1);
  }
  return crc_u;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<led_polarities>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  and    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  and    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x3,%eax
  and    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x4,%eax
  and    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x5,%eax
  and    $0x20,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cap1166_polarity@plt>
  nop
  leave
  ret
```

assistant: ```c
void led_polarities(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_polarity(l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<led_polarities>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x4,%r8d
  and    $0x10,%r8d
  shl    $0x5,%r9d
  and    $0x20,%r9d
  or     %r9d,%r8d
  shl    $0x3,%ecx
  and    $0x8,%ecx
  or     %ecx,%r8d
  shl    $0x2,%edx
  and    $0x4,%edx
  or     %edx,%r8d
  and    $0x1,%edi
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  call   <cap1166_polarity@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void led_polarities(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_polarity(l);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<led_polarities>:
  endbr64
  shl    $0x4,%r8d
  shl    $0x5,%r9d
  and    $0x1,%edi
  shl    $0x3,%ecx
  and    $0x10,%r8d
  and    $0x20,%r9d
  shl    $0x2,%edx
  or     %r9d,%r8d
  and    $0x8,%ecx
  and    $0x4,%edx
  or     %ecx,%r8d
  or     %edx,%r8d
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  jmp    1050 <cap1166_polarity@plt>
```

assistant: ```c
void led_polarities(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_polarity(l);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<led_polarities>:
  endbr64
  shl    $0x4,%r8d
  shl    $0x5,%r9d
  and    $0x1,%edi
  shl    $0x3,%ecx
  and    $0x10,%r8d
  and    $0x20,%r9d
  shl    $0x2,%edx
  or     %r9d,%r8d
  and    $0x8,%ecx
  and    $0x4,%edx
  or     %ecx,%r8d
  or     %edx,%r8d
  or     %edi,%r8d
  lea    (%rsi,%rsi,1),%edi
  and    $0x2,%edi
  or     %r8d,%edi
  jmp    1050 <cap1166_polarity@plt>
```

assistant: ```c
void led_polarities(int s0, int s1, int s2, int s3, int s4, int s5) {
  unsigned int l;
  l = s0 & 0x01;
  l |= (s1 & 0x01) << 1;
  l |= (s2 & 0x01) << 2;
  l |= (s3 & 0x01) << 3;
  l |= (s4 & 0x01) << 4;
  l |= (s5 & 0x01) << 5;
  cap1166_polarity(l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x7,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    $0x1a,%edx
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D13: Usage: 

tool: D16:  [write list of integers]


assistant: ```c
void ft_usage(char *name) {
  write(1, "Usage: ", 7);
  ft_putstr(name);
  write(1, " [write list of integers]\n", 26);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x7,%edx
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbx,%rdi
  call   <ft_putstr@plt>
  mov    $0x1a,%edx
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D4: Usage: 

tool: D2:  [write list of integers]


assistant: ```c
void ft_usage(char *name) {
  write(1, "Usage: ", 7);
  ft_putstr(name);
  write(1, " [write list of integers]\n", 26);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_usage>:
  endbr64
  push   %rbp
  mov    $0x7,%edx
  mov    %rdi,%rbp
  lea    D16(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbp,%rdi
  call   <ft_putstr@plt>
  mov    $0x1a,%edx
  mov    $0x1,%edi
  pop    %rbp
  lea    D14(%rip),%rsi
  jmp    1060 <write@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D16: Usage: 

tool: D14:  [write list of integers]


assistant: ```c
void ft_usage(char *name) {
  write(1, "Usage: ", 7);
  ft_putstr(name);
  write(1, " [write list of integers]\n", 26);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_usage>:
  endbr64
  push   %rbp
  mov    $0x7,%edx
  mov    %rdi,%rbp
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbp,%rdi
  call   <ft_putstr@plt>
  mov    $0x1a,%edx
  mov    $0x1,%edi
  pop    %rbp
  lea    D12(%rip),%rsi
  jmp    1060 <write@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string

tool: D1: Usage: 

tool: D12:  [write list of integers]


assistant: ```c
void ft_usage(char *name) {
  write(1, "Usage: ", 7);
  ft_putstr(name);
  write(1, " [write list of integers]\n", 26);
}
```
user: What is the c source code of the assembly code below?

```asm
<rtl_getvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L35
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L35:
  lea    D19(%rip),%rax
  jmp    L27
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  lea    D19(%rip),%rax
  jmp    L27
L9:
  mov    -0x8(%rbp),%rax
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
data_type: string

tool: 

assistant: ```c
char *rtl_getvar(char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rtl_getvar>:
  endbr64
  lea    D7(%rip),%rax
  test   %rdi,%rdi
  je     L5
  cmpb   $0x0,(%rdi)
  jne    L8
L5:
  ret
L8:
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  lea    D7(%rip),%rdx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: 

assistant: ```c
char *rtl_getvar(char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtl_getvar>:
  endbr64
  test   %rdi,%rdi
  je     L9
  cmpb   $0x0,(%rdi)
  jne    L1
L9:
  lea    D17(%rip),%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L29
  lea    D17(%rip),%rax
L29:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
type_infered: string

tool: 

assistant: ```c
char *rtl_getvar(char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rtl_getvar>:
  endbr64
  test   %rdi,%rdi
  je     L9
  cmpb   $0x0,(%rdi)
  jne    L12
L9:
  lea    D11(%rip),%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L8
  lea    D11(%rip),%rax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string

tool: 

assistant: ```c
char *rtl_getvar(char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  D57(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D57
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string

tool: D18: Kilogram? 

tool: D25: %lf

tool: D57: 2.2

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

tool: D37: %g lb


tool: D47: %g oz


assistant: ```c
int main(int argc, const char *argv[]) {
  double kg, lb, oz;
  printf("Kilogram? ");
  scanf("%lf", &kg);
  lb = 2.2 * kg;
  oz = 16 * lb;
  printf("%g lb\n", lb);
  printf("%g oz\n", oz);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  movsd  D58(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movq   %xmm0,%rbx
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  mulsd  D49(%rip),%xmm0
  lea    D9(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D55
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D58
data_type: f64
name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D49
data_type: byte[8]
name: read_data
arguments: data_tag: D9
data_type: string

tool: D55: Kilogram? 

tool: D30: %lf

tool: D58: 2.2

tool: D21: %g lb


tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

tool: D9: %g oz


assistant: ```c
int main(int argc, const char *argv[]) {
  double kg, lb, oz;
  printf("Kilogram? ");
  scanf("%lf", &kg);
  lb = 2.2 * kg;
  oz = 16 * lb;
  printf("%g lb\n", lb);
  printf("%g oz\n", oz);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  D6(%rip),%xmm0
  mulsd  0x10(%rsp),%xmm0
  lea    D51(%rip),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D8(%rip),%rdi
  mulsd  D12(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D51
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: byte[8]

tool: D5: Kilogram? 

tool: D0: %lf

tool: D6: 2.2

tool: D51: %g lb


tool: D8: %g oz


tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

assistant: ```c
int main(int argc, const char *argv[]) {
  double kg, lb, oz;
  printf("Kilogram? ");
  scanf("%lf", &kg);
  lb = 2.2 * kg;
  oz = 16 * lb;
  printf("%g lb\n", lb);
  printf("%g oz\n", oz);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  movsd  D45(%rip),%xmm0
  mulsd  0x10(%rsp),%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D40(%rip),%rdi
  mulsd  D8(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type: string
name: read_data
arguments: tag: D51
type: string
name: read_data
arguments: tag: D45
type: f64
name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D40
type: string
name: read_data
arguments: tag: D8
type: byte[8]

tool: D16: Kilogram? 

tool: D51: %lf

tool: D45: 2.2

tool: D3: %g lb


tool: D40: %g oz


tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x40]}

assistant: ```c
int main(int argc, const char *argv[]) {
  double kg, lb, oz;
  printf("Kilogram? ");
  scanf("%lf", &kg);
  lb = 2.2 * kg;
  oz = 16 * lb;
  printf("%g lb\n", lb);
  printf("%g oz\n", oz);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strclr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  jmp    L22
L9:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  jmp    L13
L16:
  nop
L13:
  pop    %rbp
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  while (*s) {
    *s = '\0';
    s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  je     L18
  cmpb   $0x0,(%rdi)
  je     L18
L25:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L25
L18:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  while (*s) {
    *s = '\0';
    s++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  jne    L18
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L10:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L18:
  cmpb   $0x0,(%rdi)
  jne    L10
L22:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  while (*s) {
    *s = '\0';
    s++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  jne    L12
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L25:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L12:
  cmpb   $0x0,(%rdi)
  jne    L25
L2:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  while (*s) {
    *s = '\0';
    s++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Quaternion_Sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Quaternion_Sub(float *r, float *a, float *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
  r[3] = a[3] - b[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<Quaternion_Sub>:
  endbr64
  movss  (%rsi),%xmm0
  subss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  subss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  subss  0xc(%rdx),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void Quaternion_Sub(float *r, float *a, float *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
  r[3] = a[3] - b[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Quaternion_Sub>:
  endbr64
  movss  (%rsi),%xmm0
  subss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  subss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  subss  0xc(%rdx),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void Quaternion_Sub(float *r, float *a, float *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
  r[3] = a[3] - b[3];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Quaternion_Sub>:
  endbr64
  movss  (%rsi),%xmm0
  subss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  subss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  subss  0xc(%rdx),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void Quaternion_Sub(float *r, float *a, float *b) {
  r[0] = a[0] - b[0];
  r[1] = a[1] - b[1];
  r[2] = a[2] - b[2];
  r[3] = a[3] - b[3];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L7:
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: I am PTHREAD_2 : hello gatieme!


assistant: ```c
void func2(void *args) {
  while (1) {
    sleep(2);
    printf("I am PTHREAD_2 : hello gatieme!\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func2>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
L0:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: I am PTHREAD_2 : hello gatieme!


assistant: ```c
void func2(void *args) {
  while (1) {
    sleep(2);
    printf("I am PTHREAD_2 : hello gatieme!\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  nopl   0x0(%rax)
L7:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: I am PTHREAD_2 : hello gatieme!


assistant: ```c
void func2(void *args) {
  while (1) {
    sleep(2);
    printf("I am PTHREAD_2 : hello gatieme!\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func2>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: I am PTHREAD_2 : hello gatieme!


assistant: ```c
void func2(void *args) {
  while (1) {
    sleep(2);
    printf("I am PTHREAD_2 : hello gatieme!\n");
  }
}
```