ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<string_pipe_fetch>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L38:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L38
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L44
  lea    D5(%rip),%rsi
  movb   $0x0,(%rsp)
  mov    %rsp,%r12
  call   <popen@plt>
  mov    %r12,%rdi
  mov    $0x10000,%edx
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <string_input@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L0
  call   <pclose@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
L37:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x10018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  call   <pclose@plt>
  xor    %eax,%eax
  jmp    L37
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  jmp    L37
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: r

assistant: ```c
char *string_pipe_fetch(char *system_string) {
  char buffer[65536];
  FILE *p;
  int null_input = 0;
  if (!system_string)
    return (char *)0;
  *buffer = '\0';
  p = popen(system_string, "r");
  if (!string_input(buffer, p, 65536))
    null_input = 1;
  pclose(p);
  if (null_input)
    return (char *)0;
  else
    return strdup(buffer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_pipe_fetch>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x10000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L55
  lea    D6(%rip),%rsi
  movb   $0x0,(%rsp)
  mov    %rsp,%r12
  call   <popen@plt>
  mov    %r12,%rdi
  mov    $0x10000,%edx
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <string_input@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  je     L42
  call   <pclose@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
L52:
  mov    0x10008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10018,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L42:
  call   <pclose@plt>
  xor    %eax,%eax
  jmp    L52
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
  jmp    L52
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: r

assistant: ```c
char *string_pipe_fetch(char *system_string) {
  char buffer[65536];
  FILE *p;
  int null_input = 0;
  if (!system_string)
    return (char *)0;
  *buffer = '\0';
  p = popen(system_string, "r");
  if (!string_input(buffer, p, 65536))
    null_input = 1;
  pclose(p);
  if (null_input)
    return (char *)0;
  else
    return strdup(buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isort3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L26
L47:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L41
L24:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L41:
  cmpl   $0x0,-0x8(%rbp)
  jle    L33
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L24
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void isort3(int *A, int n) {
  int i, j;
  int t;
  for (i = 1; i < n; i++) {
    t = A[i];
    for (j = i; j > 0 && A[j - 1] > t; j--)
      A[j] = A[j - 1];
    A[j] = t;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isort3>:
  endbr64
  cmp    $0x1,%esi
  jle    L45
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  jmp    L27
L46:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%esi
  je     L45
L27:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9d,%edx
  test   %r9d,%r9d
  jle    L46
L20:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L46
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L20
  jmp    L46
L45:
  ret
```

assistant: ```c
void isort3(int *A, int n) {
  int i, j;
  int t;
  for (i = 1; i < n; i++) {
    t = A[i];
    for (j = i; j > 0 && A[j - 1] > t; j--)
      A[j] = A[j - 1];
    A[j] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isort3>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L0
  nopl   0x0(%rax,%rax,1)
L33:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L29:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L36
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rax,%rdi
  jne    L29
  mov    %rdi,%rcx
L36:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L33
L0:
  ret
```

assistant: ```c
void isort3(int *A, int n) {
  int i, j;
  int t;
  for (i = 1; i < n; i++) {
    t = A[i];
    for (j = i; j > 0 && A[j - 1] > t; j--)
      A[j] = A[j - 1];
    A[j] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isort3>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L6
  nopl   0x0(%rax,%rax,1)
L24:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L18:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L10
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L18
  mov    %rdi,%rcx
L10:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L24
L6:
  ret
```

assistant: ```c
void isort3(int *A, int n) {
  int i, j;
  int t;
  for (i = 1; i < n; i++) {
    t = A[i];
    for (j = i; j > 0 && A[j - 1] > t; j--)
      A[j] = A[j - 1];
    A[j] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    D0(%rip),%rdi
  lea    (%rax,%rax,2),%ebp
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  xor    %eax,%eax
  shl    $0x2,%ebp
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    0x10(%rsp),%esi
  mov    %ebp,%edx
  movsd  D58(%rip),%xmm1
  cvtss2sd 0x14(%rsp),%xmm0
  mov    $0x2,%eax
  lea    D61(%rip),%rdi
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  lea    D87(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  pxor   %xmm0,%xmm0
  lea    D98(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0x14(%rsp),%xmm0
  call   <printf@plt>
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebp,%esi
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D79
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D58
data_type: f64
name: extract_symbolic_data
arguments: tag: D61
data_type: string
name: extract_symbolic_data
arguments: tag: D87
data_type: string
name: extract_symbolic_data
arguments: tag: D98
data_type: string
name: extract_symbolic_data
arguments: tag: D53
data_type: string
name: extract_symbolic_data
arguments: tag: D36
data_type: string

tool: D14: Enter your age in years please :

tool: D79: %i

tool: D0: Enter your height in cm please :

tool: D13: %f

tool: D58: 0.3937

tool: D61: 

With the great power invested in me I can tell you
 (show it on the screen)
... that you are %i years (which would mean %i months)
                 and %.f cm in height (which would mean %.3f inches)!

tool: D87: 

Age	Height(cm)

tool: D98: 
%i	%.f

tool: D53: 
Months	Inches

tool: D36: 
%i	%.3f

assistant: ```c
int main() {
  char input[20];
  int age;
  float height;
  ;
  printf("Enter your age in years please :");
  scanf("%i", &age);
  int months = age * 12;
  printf("Enter your height in cm please :");
  scanf("%f", &height);
  float inches = height * 0.3937;
  printf("\n\nWith the great power invested in me I can tell you"
         "\n (show it on the screen)"
         "\n... that you are %i years (which would mean %i months)"
         "\n                 and %.f cm in height (which would mean %.3f inches)!",
         age, months, height, inches);
  printf("\n\nAge\tHeight(cm)");
  printf("\n%i\t%.f", age, height);
  printf("\nMonths\tInches");
  printf("\n%i\t%.3f", months, inches);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L36
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L22
  mov    -0x4(%rbp),%eax
  jmp    L4
L22:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
L36:
  mov    $0xffffffff,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int search(int a[], int size, int x) {
  if (a) {
    int i;
    for (i = 0; i < size; i++) {
      if (a[i] == x) {
        return i;
      }
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<search>:
  endbr64
  test   %rdi,%rdi
  je     L32
  test   %esi,%esi
  jle    L49
  mov    %esi,%esi
  mov    $0x0,%eax
L8:
  mov    %eax,%ecx
  cmp    %edx,(%rdi,%rax,4)
  je     L40
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L8
  mov    $0xffffffff,%ecx
L40:
  mov    %ecx,%eax
  ret
L32:
  mov    $0xffffffff,%ecx
  jmp    L40
L49:
  mov    $0xffffffff,%ecx
  jmp    L40
```

assistant: ```c
int search(int a[], int size, int x) {
  if (a) {
    int i;
    for (i = 0; i < size; i++) {
      if (a[i] == x) {
        return i;
      }
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<search>:
  endbr64
  test   %rdi,%rdi
  je     L48
  test   %esi,%esi
  jle    L48
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax)
L14:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L48
L10:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L14
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L48:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int search(int a[], int size, int x) {
  if (a) {
    int i;
    for (i = 0; i < size; i++) {
      if (a[i] == x) {
        return i;
      }
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<search>:
  endbr64
  test   %rdi,%rdi
  je     L37
  test   %esi,%esi
  jle    L37
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L23
  nopl   0x0(%rax)
L11:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L37
L23:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L37:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int search(int a[], int size, int x) {
  if (a) {
    int i;
    for (i = 0; i < size; i++) {
      if (a[i] == x) {
        return i;
      }
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transfer_YUV888_to_YUVA8888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl 0x1(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl 0x2(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0xff,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUV888_to_YUVA8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = (int)input[0];
  *(*output)++ = input[1];
  *(*output)++ = input[2];
  *(*output)++ = 0xff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transfer_YUV888_to_YUVA8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  ret
```

assistant: ```c
void transfer_YUV888_to_YUVA8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = (int)input[0];
  *(*output)++ = input[1];
  *(*output)++ = input[2];
  *(*output)++ = 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<transfer_YUV888_to_YUVA8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  ret
```

assistant: ```c
void transfer_YUV888_to_YUVA8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = (int)input[0];
  *(*output)++ = input[1];
  *(*output)++ = input[2];
  *(*output)++ = 0xff;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<transfer_YUV888_to_YUVA8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  ret
```

assistant: ```c
void transfer_YUV888_to_YUVA8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = (int)input[0];
  *(*output)++ = input[1];
  *(*output)++ = input[2];
  *(*output)++ = 0xff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  neg    %rax
  and    $0x7,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L10
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x38(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  or     %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,-0x14(%rbp)
  jmp    L22
L59:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x8(%rbp)
L22:
  cmpq   $0x0,-0x8(%rbp)
  jne    L59
  mov    -0x38(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L66:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L36:
  cmpq   $0x0,-0x8(%rbp)
  jne    L66
  andq   $0x7,-0x38(%rbp)
  jmp    L10
L31:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x38(%rbp)
L10:
  cmpq   $0x0,-0x38(%rbp)
  jne    L31
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t count) {
  char *xs = (char *)s;
  size_t len = (-(size_t)s) & (sizeof(size_t) - 1);
  int cc = c & 0xff;
  if (count > len) {
    count -= len;
    cc |= cc << 8;
    cc |= cc << 16;
    for (; len > 0; len--)
      *xs++ = c;
    for (len = count / sizeof(size_t); len > 0; len--) {
      *((size_t *)xs) = cc;
      xs += sizeof(size_t);
    }
    count &= sizeof(size_t) - 1;
  }
  for (; count > 0; count--)
    *xs++ = c;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset>:
  endbr64
  mov    %rdi,%rcx
  neg    %rcx
  and    $0x7,%ecx
  mov    %rdi,%rax
  cmp    %rdx,%rcx
  jae    L0
  movzbl %sil,%r8d
  sub    %rcx,%rdx
  mov    %r8d,%eax
  shl    $0x8,%eax
  or     %r8d,%eax
  mov    %eax,%r8d
  shl    $0x10,%r8d
  or     %eax,%r8d
  test   %rcx,%rcx
  je     L67
  lea    (%rdi,%rcx,1),%rax
  mov    %rdi,%rcx
L78:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rax
  jne    L78
L11:
  mov    %rdx,%r9
  shr    $0x3,%r9
  cmp    $0x7,%rdx
  jbe    L57
  mov    $0x0,%ecx
  movslq %r8d,%r8
L28:
  mov    %r8,(%rax,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L28
  mov    %rdx,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%rax
L57:
  and    $0x7,%edx
L0:
  test   %rdx,%rdx
  je     L44
  add    %rax,%rdx
L48:
  add    $0x1,%rax
  mov    %sil,-0x1(%rax)
  cmp    %rax,%rdx
  jne    L48
L44:
  mov    %rdi,%rax
  ret
L67:
  mov    %rdi,%rax
  jmp    L11
```

assistant: ```c
void *memset(void *s, int c, size_t count) {
  char *xs = (char *)s;
  size_t len = (-(size_t)s) & (sizeof(size_t) - 1);
  int cc = c & 0xff;
  if (count > len) {
    count -= len;
    cc |= cc << 8;
    cc |= cc << 16;
    for (; len > 0; len--)
      *xs++ = c;
    for (len = count / sizeof(size_t); len > 0; len--) {
      *((size_t *)xs) = cc;
      xs += sizeof(size_t);
    }
    count &= sizeof(size_t) - 1;
  }
  for (; count > 0; count--)
    *xs++ = c;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memset>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  mov    %r8,%rax
  mov    %r8,%rcx
  neg    %rax
  and    $0x7,%eax
  cmp    %rdx,%rax
  jae    L9
  movzbl %sil,%esi
  sub    %rax,%rdx
  mov    %esi,%ecx
  shl    $0x8,%ecx
  or     %esi,%ecx
  mov    %ecx,%esi
  shl    $0x10,%esi
  or     %ecx,%esi
  test   %rax,%rax
  je     L58
  movsbl %dil,%r10d
  mov    %eax,%r11d
  test   %eax,%eax
  je     L0
  xor    %ecx,%ecx
L42:
  mov    %ecx,%r9d
  add    $0x1,%ecx
  mov    %r10b,(%r8,%r9,1)
  cmp    %r11d,%ecx
  jb     L42
L0:
  add    %r8,%rax
L38:
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  je     L1
  movslq %esi,%rsi
  lea    (%rax,%rcx,8),%rcx
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L43
L61:
  and    $0x7,%edx
L9:
  test   %rdx,%rdx
  je     L80
  movsbl %dil,%esi
  mov    %edx,%edi
  test   %edx,%edx
  je     L80
  xor    %eax,%eax
L74:
  mov    %eax,%edx
  add    $0x1,%eax
  mov    %sil,(%rcx,%rdx,1)
  cmp    %edi,%eax
  jb     L74
L80:
  mov    %r8,%rax
  ret
L58:
  mov    %r8,%rax
  jmp    L38
L1:
  mov    %rax,%rcx
  jmp    L61
```

assistant: ```c
void *memset(void *s, int c, size_t count) {
  char *xs = (char *)s;
  size_t len = (-(size_t)s) & (sizeof(size_t) - 1);
  int cc = c & 0xff;
  if (count > len) {
    count -= len;
    cc |= cc << 8;
    cc |= cc << 16;
    for (; len > 0; len--)
      *xs++ = c;
    for (len = count / sizeof(size_t); len > 0; len--) {
      *((size_t *)xs) = cc;
      xs += sizeof(size_t);
    }
    count &= sizeof(size_t) - 1;
  }
  for (; count > 0; count--)
    *xs++ = c;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  mov    %rdi,%r8
  mov    %rdi,%rsi
  neg    %rax
  and    $0x7,%eax
  cmp    %rdx,%rax
  jae    L7
  movzbl %cl,%edi
  sub    %rax,%rdx
  mov    %edi,%r9d
  shl    $0x8,%r9d
  or     %edi,%r9d
  mov    %r9d,%edi
  shl    $0x10,%edi
  or     %r9d,%edi
  test   %rax,%rax
  je     L102
  movsbl %cl,%r10d
  mov    %eax,%r11d
  test   %eax,%eax
  je     L14
  xor    %esi,%esi
L112:
  mov    %esi,%r9d
  add    $0x1,%esi
  mov    %r10b,(%r8,%r9,1)
  cmp    %r11d,%esi
  jb     L112
L14:
  lea    (%r8,%rax,1),%rsi
L102:
  mov    %rdx,%r11
  shr    $0x3,%r11
  je     L31
  movslq %edi,%rdi
  cmp    $0x1,%r11
  je     L58
  mov    %rdx,%r10
  mov    %rdx,%r9
  movq   %rdi,%xmm0
  mov    %rsi,%rax
  and    $0xfffffffffffffff0,%r10
  shr    $0x4,%r9
  punpcklqdq %xmm0,%xmm0
  add    %rsi,%r10
  nopl   0x0(%rax,%rax,1)
L61:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%r10
  jne    L61
  lea    (%r9,%r9,1),%r10
  shl    $0x4,%r9
  lea    (%rsi,%r9,1),%rax
  cmp    %r11,%r10
  je     L52
L32:
  mov    %rdi,(%rax)
L52:
  lea    (%rsi,%r11,8),%rsi
L31:
  and    $0x7,%edx
L7:
  test   %rdx,%rdx
  je     L100
  movsbl %cl,%ecx
  mov    %edx,%edi
  test   %edx,%edx
  je     L100
  xor    %eax,%eax
L90:
  mov    %eax,%edx
  add    $0x1,%eax
  mov    %cl,(%rsi,%rdx,1)
  cmp    %edi,%eax
  jb     L90
L100:
  mov    %r8,%rax
  ret
L58:
  mov    %rsi,%rax
  jmp    L32
```

assistant: ```c
void *memset(void *s, int c, size_t count) {
  char *xs = (char *)s;
  size_t len = (-(size_t)s) & (sizeof(size_t) - 1);
  int cc = c & 0xff;
  if (count > len) {
    count -= len;
    cc |= cc << 8;
    cc |= cc << 16;
    for (; len > 0; len--)
      *xs++ = c;
    for (len = count / sizeof(size_t); len > 0; len--) {
      *((size_t *)xs) = cc;
      xs += sizeof(size_t);
    }
    count &= sizeof(size_t) - 1;
  }
  for (; count > 0; count--)
    *xs++ = c;
  return s;
}
```