ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x186a0,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L0:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: gettimdofday = {%ld, %ld}


assistant: ```c
int main(int argc, char *argv[]) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  printf("gettimdofday = {%ld, %ld}\n", tv.tv_sec, tv.tv_usec);
  int i = 0;
  for (i = 0; i < 100000; i++)
    gettimeofday(&tv, NULL);
  printf("gettimdofday = {%ld, %ld}\n", tv.tv_sec, tv.tv_usec);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stepToNextBezierForwardat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L24:
  mov    -0x8(%rbp),%eax
  add    $0x8000,%eax
  sar    $0x10,%eax
  add    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x8000,%eax
  sar    $0x10,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x10,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x14,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L14
  cmpl   $0x0,-0x14(%rbp)
  jns    L24
L14:
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x4,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  add    $0xc,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stepToNextBezierForwardat(int updateData, int yValue) {
  int fwDy;
  int lastX;
  int minY;
  int lastY;
  int fwDx;
  lastX = (((int *)updateData))[0];
  lastY = (((int *)updateData))[1];
  fwDx = (((int *)updateData))[2];
  fwDy = (((int *)updateData))[3];
  minY = yValue * 256;
  while ((minY > lastY) && (fwDy >= 0)) {
    lastX += ((int)(fwDx + 32768) >> 16);
    lastY += ((int)(fwDy + 32768) >> 16);
    fwDx += (((int *)updateData))[4];
    fwDy += (((int *)updateData))[5];
  }
  (((int *)updateData))[0] = lastX;
  (((int *)updateData))[1] = lastY;
  (((int *)updateData))[2] = fwDx;
  (((int *)updateData))[3] = fwDy;
  return ((int)lastX >> 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stepToNextBezierForwardat>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  mov    0x8(%rdi),%r9d
  mov    0xc(%rdi),%edx
  shl    $0x8,%esi
  cmp    %esi,%r8d
  jge    L1
  test   %edx,%edx
  js     L1
  mov    0x10(%rdi),%r11d
  mov    0x14(%rdi),%r10d
L10:
  lea    0x8000(%r9),%ecx
  sar    $0x10,%ecx
  add    %ecx,%eax
  lea    0x8000(%rdx),%ecx
  sar    $0x10,%ecx
  add    %ecx,%r8d
  add    %r11d,%r9d
  add    %r10d,%edx
  cmp    %r8d,%esi
  jle    L1
  test   %edx,%edx
  jns    L10
L1:
  mov    %eax,(%rdi)
  mov    %r8d,0x4(%rdi)
  mov    %r9d,0x8(%rdi)
  mov    %edx,0xc(%rdi)
  sar    $0x8,%eax
  ret
```

assistant: ```c
int stepToNextBezierForwardat(int updateData, int yValue) {
  int fwDy;
  int lastX;
  int minY;
  int lastY;
  int fwDx;
  lastX = (((int *)updateData))[0];
  lastY = (((int *)updateData))[1];
  fwDx = (((int *)updateData))[2];
  fwDy = (((int *)updateData))[3];
  minY = yValue * 256;
  while ((minY > lastY) && (fwDy >= 0)) {
    lastX += ((int)(fwDx + 32768) >> 16);
    lastY += ((int)(fwDy + 32768) >> 16);
    fwDx += (((int *)updateData))[4];
    fwDy += (((int *)updateData))[5];
  }
  (((int *)updateData))[0] = lastX;
  (((int *)updateData))[1] = lastY;
  (((int *)updateData))[2] = fwDx;
  (((int *)updateData))[3] = fwDy;
  return ((int)lastX >> 8);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stepToNextBezierForwardat>:
  endbr64
  movslq %edi,%rdi
  shl    $0x8,%esi
  mov    0xc(%rdi),%edx
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  mov    0x8(%rdi),%r9d
  test   %edx,%edx
  js     L27
  cmp    %esi,%r8d
  jge    L27
  mov    0x10(%rdi),%r11d
  mov    0x14(%rdi),%r10d
  nopl   0x0(%rax,%rax,1)
L3:
  lea    0x8000(%r9),%ecx
  add    %r11d,%r9d
  sar    $0x10,%ecx
  add    %ecx,%eax
  lea    0x8000(%rdx),%ecx
  add    %r10d,%edx
  sar    $0x10,%ecx
  add    %ecx,%r8d
  cmp    %r8d,%esi
  jle    L27
  test   %edx,%edx
  jns    L3
L27:
  mov    %eax,(%rdi)
  sar    $0x8,%eax
  mov    %r8d,0x4(%rdi)
  mov    %r9d,0x8(%rdi)
  mov    %edx,0xc(%rdi)
  ret
```

assistant: ```c
int stepToNextBezierForwardat(int updateData, int yValue) {
  int fwDy;
  int lastX;
  int minY;
  int lastY;
  int fwDx;
  lastX = (((int *)updateData))[0];
  lastY = (((int *)updateData))[1];
  fwDx = (((int *)updateData))[2];
  fwDy = (((int *)updateData))[3];
  minY = yValue * 256;
  while ((minY > lastY) && (fwDy >= 0)) {
    lastX += ((int)(fwDx + 32768) >> 16);
    lastY += ((int)(fwDy + 32768) >> 16);
    fwDx += (((int *)updateData))[4];
    fwDy += (((int *)updateData))[5];
  }
  (((int *)updateData))[0] = lastX;
  (((int *)updateData))[1] = lastY;
  (((int *)updateData))[2] = fwDx;
  (((int *)updateData))[3] = fwDy;
  return ((int)lastX >> 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stepToNextBezierForwardat>:
  endbr64
  movslq %edi,%rdi
  shl    $0x8,%esi
  movdqu (%rdi),%xmm0
  mov    0xc(%rdi),%eax
  mov    0x8(%rdi),%ecx
  mov    0x4(%rdi),%r8d
  movd   %xmm0,%r9d
  test   %eax,%eax
  js     L29
  cmp    %r8d,%esi
  jle    L29
  mov    0x10(%rdi),%r11d
  mov    0x14(%rdi),%r10d
  xchg   %ax,%ax
L17:
  lea    0x8000(%rcx),%edx
  add    %r11d,%ecx
  sar    $0x10,%edx
  add    %edx,%r9d
  lea    0x8000(%rax),%edx
  add    %r10d,%eax
  sar    $0x10,%edx
  add    %edx,%r8d
  cmp    %r8d,%esi
  jle    L2
  test   %eax,%eax
  jns    L17
L2:
  movd   %ecx,%xmm1
  movd   %eax,%xmm2
  movd   %r9d,%xmm0
  movd   %r8d,%xmm3
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
L29:
  movd   %xmm0,%eax
  movups %xmm0,(%rdi)
  sar    $0x8,%eax
  ret
```

assistant: ```c
int stepToNextBezierForwardat(int updateData, int yValue) {
  int fwDy;
  int lastX;
  int minY;
  int lastY;
  int fwDx;
  lastX = (((int *)updateData))[0];
  lastY = (((int *)updateData))[1];
  fwDx = (((int *)updateData))[2];
  fwDy = (((int *)updateData))[3];
  minY = yValue * 256;
  while ((minY > lastY) && (fwDy >= 0)) {
    lastX += ((int)(fwDx + 32768) >> 16);
    lastY += ((int)(fwDy + 32768) >> 16);
    fwDx += (((int *)updateData))[4];
    fwDy += (((int *)updateData))[5];
  }
  (((int *)updateData))[0] = lastX;
  (((int *)updateData))[1] = lastY;
  (((int *)updateData))[2] = fwDx;
  (((int *)updateData))[3] = fwDy;
  return ((int)lastX >> 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<new_thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: Thread %zu created


assistant: ```c
void *new_thread(void *arg) {
  printf("Thread %zu created\n", (size_t)arg);
  return arg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<new_thread>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: Thread %zu created


assistant: ```c
void *new_thread(void *arg) {
  printf("Thread %zu created\n", (size_t)arg);
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<new_thread>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: Thread %zu created


assistant: ```c
void *new_thread(void *arg) {
  printf("Thread %zu created\n", (size_t)arg);
  return arg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<new_thread>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: Thread %zu created


assistant: ```c
void *new_thread(void *arg) {
  printf("Thread %zu created\n", (size_t)arg);
  return arg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L23
  cmpl   $0x5c,-0x4(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L2
L23:
  nop
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <getch@plt>
  leave
  ret
```

assistant: ```c
int skip_string(int quote) {
  int ch = quote;
  for (;;) {
    ch = getch(ch);
    if (ch == quote)
      break;
    if (ch == '\\')
      ch = getch(ch);
  }
  return getch(ch);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skip_string>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L0:
  call   <getch@plt>
  mov    %eax,%edi
  cmp    %eax,%ebx
  je     L14
  cmp    $0x5c,%eax
  jne    L0
  call   <getch@plt>
  mov    %eax,%edi
  jmp    L0
L14:
  call   <getch@plt>
  pop    %rbx
  ret
```

assistant: ```c
int skip_string(int quote) {
  int ch = quote;
  for (;;) {
    ch = getch(ch);
    if (ch == quote)
      break;
    if (ch == '\\')
      ch = getch(ch);
  }
  return getch(ch);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  jmp    L37
  nopl   0x0(%rax)
L2:
  cmp    $0x5c,%eax
  je     L29
L37:
  call   <getch@plt>
  mov    %eax,%edi
  cmp    %eax,%ebp
  jne    L2
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <getch@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  call   <getch@plt>
  mov    %eax,%edi
  jmp    L37
```

assistant: ```c
int skip_string(int quote) {
  int ch = quote;
  for (;;) {
    ch = getch(ch);
    if (ch == quote)
      break;
    if (ch == '\\')
      ch = getch(ch);
  }
  return getch(ch);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  jmp    L14
  nopl   0x0(%rax)
L24:
  cmp    $0x5c,%eax
  je     L11
L14:
  call   <getch@plt>
  mov    %eax,%edi
  cmp    %eax,%ebp
  jne    L24
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <getch@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  call   <getch@plt>
  mov    %eax,%edi
  jmp    L14
```

assistant: ```c
int skip_string(int quote) {
  int ch = quote;
  for (;;) {
    ch = getch(ch);
    if (ch == quote)
      break;
    if (ch == '\\')
      ch = getch(ch);
  }
  return getch(ch);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pidfile_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void pidfile_delete(char *pidfile) {
  if (pidfile)
    unlink(pidfile);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pidfile_delete>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <unlink@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void pidfile_delete(char *pidfile) {
  if (pidfile)
    unlink(pidfile);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pidfile_delete>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <unlink@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void pidfile_delete(char *pidfile) {
  if (pidfile)
    unlink(pidfile);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pidfile_delete>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <unlink@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void pidfile_delete(char *pidfile) {
  if (pidfile)
    unlink(pidfile);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calcpathv>:
  endbr64
  test   %rdx,%rdx
  je     L22
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %rsi,%rcx
  mov    %rdi,%r11
  mov    $0x0,%r9d
  jmp    L66
L68:
  mov    (%rcx),%rsi
  mov    (%rsi,%rdx,1),%rdi
  add    %rdi,(%rsi,%r8,1)
L4:
  add    $0x1,%rax
  add    $0x8,%rdx
  cmp    %rax,%rbx
  je     L106
L96:
  lea    0x0(,%rax,8),%r8
  mov    (%r11),%rsi
  mov    (%rsi,%rax,8),%rdi
  mov    (%rcx),%rsi
  mov    %rdi,(%rsi,%rax,8)
  mov    %r9,%rdi
  or     %rax,%rdi
  je     L4
  test   %r9,%r9
  je     L68
  test   %rax,%rax
  je     L64
  mov    (%rcx),%rsi
  mov    (%rsi,%rdx,1),%r12
  mov    -0x8(%rcx),%rdi
  mov    (%rdi,%r8,1),%rdi
  cmp    %rdi,%r12
  jbe    L103
  add    %r12,(%rsi,%r8,1)
  jmp    L4
L64:
  mov    (%rcx),%rsi
  mov    -0x8(%rcx),%rdi
  mov    (%rdi),%rdi
  add    %rdi,(%rsi)
  jmp    L4
L103:
  add    %rdi,(%rsi,%r8,1)
  jmp    L4
L106:
  add    $0x1,%r9
  add    $0x8,%rcx
  add    $0x8,%r11
  cmp    %r9,%rbp
  je     L98
L66:
  mov    $0xfffffffffffffff8,%rdx
  mov    $0x0,%eax
  test   %rbx,%rbx
  jne    L96
  jmp    L106
L98:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  ret
```

assistant: ```c
void calcpathv(int32_t **map, int32_t **path, int32_t n, int32_t m) {
  int32_t i, j;
  i = 0;
  while (i < n) {
    j = 0;
    while (j < m) {
      path[i][j] = map[i][j];
      if (i == 0 && j == 0)
        ;
      else if (i == 0)
        path[i][j] += path[i][j - 1];
      else if (j == 0)
        path[i][j] += path[i - 1][j];
      else if (path[i][j - 1] > path[i - 1][j]) {
        path[i][j] += path[i][j - 1];
      } else {
        path[i][j] += path[i - 1][j];
      }
      j++;
    }
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calcpathv>:
  endbr64
  test   %rdx,%rdx
  je     L51
  push   %r12
  mov    %rsi,%r11
  mov    %rdi,%r10
  mov    %rcx,%r8
  push   %rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  nop
L19:
  test   %r8,%r8
  je     L62
  mov    (%r10,%rsi,8),%r9
  mov    (%r11,%rsi,8),%rcx
  xor    %eax,%eax
  jmp    L94
  nopl   0x0(%rax)
L69:
  mov    -0x8(%r11,%rsi,8),%rbp
  test   %rax,%rax
  je     L48
  mov    0x0(%rbp,%rdi,1),%rdi
  mov    -0x8(%rcx),%r12
  lea    (%rdx,%rdi,1),%rbp
  add    %r12,%rdx
  cmp    %rdi,%r12
  cmovbe %rbp,%rdx
  mov    %rdx,(%rcx)
L28:
  add    $0x1,%rax
  add    $0x8,%rcx
  cmp    %rax,%r8
  je     L62
L94:
  mov    (%r9,%rax,8),%rdx
  mov    %rsi,%rbp
  lea    0x0(,%rax,8),%rdi
  or     %rax,%rbp
  mov    %rdx,(%rcx)
  je     L28
  test   %rsi,%rsi
  jne    L69
  add    -0x8(%rcx),%rdx
  add    $0x1,%rax
  add    $0x8,%rcx
  mov    %rdx,-0x8(%rcx)
  cmp    %rax,%r8
  jne    L94
  nopw   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rsi
  cmp    %rsi,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  add    0x0(%rbp),%rdx
  mov    %rdx,(%rcx)
  jmp    L28
L51:
  ret
```

assistant: ```c
void calcpathv(int32_t **map, int32_t **path, int32_t n, int32_t m) {
  int32_t i, j;
  i = 0;
  while (i < n) {
    j = 0;
    while (j < m) {
      path[i][j] = map[i][j];
      if (i == 0 && j == 0)
        ;
      else if (i == 0)
        path[i][j] += path[i][j - 1];
      else if (j == 0)
        path[i][j] += path[i - 1][j];
      else if (path[i][j - 1] > path[i - 1][j]) {
        path[i][j] += path[i][j - 1];
      } else {
        path[i][j] += path[i - 1][j];
      }
      j++;
    }
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcpathv>:
  endbr64
  test   %rdx,%rdx
  je     L85
  mov    %rsi,%r9
  mov    %rdi,%r8
  mov    %rdx,%r10
  mov    %rcx,%rsi
  xor    %r11d,%r11d
L12:
  test   %rsi,%rsi
  je     L156
  mov    (%r8,%r11,8),%rdi
  mov    (%r9,%r11,8),%rcx
  test   %r11,%r11
  je     L87
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
L48:
  mov    -0x8(%r9,%r11,8),%r12
  xor    %eax,%eax
  jmp    L119
  nopl   (%rax)
L116:
  mov    (%r12,%rax,8),%rbx
  mov    -0x8(%rcx,%rax,8),%rbp
  lea    0x0(%rbp,%rdx,1),%r13
  add    %rbx,%rdx
  cmp    %rbx,%rbp
  cmova  %r13,%rdx
  mov    %rdx,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L19
L119:
  mov    (%rdi,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
  test   %rax,%rax
  jne    L116
  add    (%r12),%rdx
  add    $0x1,%rax
  mov    %rdx,(%rcx)
  cmp    %rax,%rsi
  jne    L119
L19:
  add    $0x1,%r11
  cmp    %r11,%r10
  je     L122
L127:
  test   %rsi,%rsi
  je     L19
  mov    (%r8,%r11,8),%rdi
  mov    (%r9,%r11,8),%rcx
  test   %r11,%r11
  jne    L48
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rdi,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
  test   %rax,%rax
  je     L30
  add    -0x8(%rcx,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
L30:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L8
  add    $0x1,%r11
  cmp    %r11,%r10
  jne    L127
L122:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L87:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L54:
  mov    (%rdi,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
  test   %rax,%rax
  je     L109
  add    -0x8(%rcx,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
L109:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L54
L156:
  add    $0x1,%r11
  cmp    %r11,%r10
  jne    L12
  ret
L85:
  ret
```

assistant: ```c
void calcpathv(int32_t **map, int32_t **path, int32_t n, int32_t m) {
  int32_t i, j;
  i = 0;
  while (i < n) {
    j = 0;
    while (j < m) {
      path[i][j] = map[i][j];
      if (i == 0 && j == 0)
        ;
      else if (i == 0)
        path[i][j] += path[i][j - 1];
      else if (j == 0)
        path[i][j] += path[i - 1][j];
      else if (path[i][j - 1] > path[i - 1][j]) {
        path[i][j] += path[i][j - 1];
      } else {
        path[i][j] += path[i - 1][j];
      }
      j++;
    }
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <test_porcelain@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <test_algorithms@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D6: test/resources/almost_complete.puzzle

tool: D16: test/resources/only_zeroes.puzzle

assistant: ```c
int main() {
  char *puzzle_key = "test/resources/almost_complete.puzzle";
  char *zeroes = "test/resources/only_zeroes.puzzle";
  while (1) {
    test_porcelain(zeroes);
    test_algorithms(zeroes);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
L5:
  mov    %rbx,%rdi
  call   <test_porcelain@plt>
  mov    %rbx,%rdi
  call   <test_algorithms@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: test/resources/only_zeroes.puzzle

assistant: ```c
int main() {
  char *puzzle_key = "test/resources/almost_complete.puzzle";
  char *zeroes = "test/resources/only_zeroes.puzzle";
  while (1) {
    test_porcelain(zeroes);
    test_algorithms(zeroes);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdi
  call   <test_porcelain@plt>
  mov    %rbx,%rdi
  call   <test_algorithms@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: test/resources/only_zeroes.puzzle

assistant: ```c
int main() {
  char *puzzle_key = "test/resources/almost_complete.puzzle";
  char *zeroes = "test/resources/only_zeroes.puzzle";
  while (1) {
    test_porcelain(zeroes);
    test_algorithms(zeroes);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <test_porcelain@plt>
  mov    %rbx,%rdi
  call   <test_algorithms@plt>
  jmp    L4
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: test/resources/only_zeroes.puzzle

assistant: ```c
int main() {
  char *puzzle_key = "test/resources/almost_complete.puzzle";
  char *zeroes = "test/resources/only_zeroes.puzzle";
  while (1) {
    test_porcelain(zeroes);
    test_algorithms(zeroes);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lefttrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L4
  cmpl   $0x0,-0x14(%rbp)
  je     L3
L4:
  movl   $0x1,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L3:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *lefttrim(char *string, char junk) {
  char *original = string;
  char *p = original;
  int trimmed = 0;
  do {
    if (*original != junk || trimmed) {
      trimmed = 1;
      *p++ = *original;
    }
  } while (*original++ != '\0');
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lefttrim>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  mov    %rdi,%rdx
  mov    $0x0,%r8d
  mov    $0x1,%r10d
  mov    $0x0,%r11d
  jmp    L5
L2:
  mov    %r9b,(%rcx)
  lea    0x1(%rcx),%rcx
  mov    %r10d,%r8d
L6:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  je     L22
L5:
  movzbl (%rdx),%r9d
  test   %r8d,%r8d
  jne    L2
  mov    %r11d,%r8d
  cmp    %sil,%r9b
  jne    L2
  jmp    L6
L22:
  ret
```

assistant: ```c
char *lefttrim(char *string, char junk) {
  char *original = string;
  char *p = original;
  int trimmed = 0;
  do {
    if (*original != junk || trimmed) {
      trimmed = 1;
      *p++ = *original;
    }
  } while (*original++ != '\0');
  return string;
}
```