ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binsearch_refblock_ge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x200,-0x10(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  jmp    L34
L24:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jge    L70
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L34
L70:
  mov    -0x30(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L49
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L24
  jmp    L5
L49:
  nop
L5:
  mov    -0x30(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L65
  mov    $0xffffffffffffffff,%rax
  jmp    L44
L65:
  mov    -0x8(%rbp),%rax
L44:
  pop    %rbp
  ret
```

assistant: ```c
signed long long binsearch_refblock_ge(signed long long *refs, signed long long ref) {
  signed int low = 0;
  signed int high = (4096 / sizeof(signed long long));
  signed long long p_ref = -1;
  while (low < high) {
    signed int p = (high + low) / 2;
    p_ref = refs[p];
    if (ref < p_ref) {
      high = p;
    } else if (ref > p_ref) {
      p_ref = refs[p + 1];
      low = p + 1;
    } else {
      break;
    }
  }
  if (ref > p_ref) {
    return -1;
  }
  return p_ref;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<binsearch_refblock_ge>:
  endbr64
  mov    $0xffffffffffffffff,%rcx
  mov    $0x200,%edx
  mov    $0x0,%r8d
L62:
  cmp    %edx,%r8d
  jge    L15
  lea    (%r8,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  lea    0x0(,%rcx,8),%r9
  mov    (%rdi,%rcx,8),%rcx
  cmp    %rsi,%rcx
  jle    L14
  mov    %eax,%edx
  jmp    L62
L14:
  jge    L16
  mov    0x8(%rdi,%r9,1),%rcx
  lea    0x1(%rax),%r8d
  jmp    L62
L15:
  cmp    %rsi,%rcx
  jl     L64
L16:
  mov    %rcx,%rax
  ret
L64:
  mov    $0xffffffffffffffff,%rcx
  jmp    L16
```

assistant: ```c
signed long long binsearch_refblock_ge(signed long long *refs, signed long long ref) {
  signed int low = 0;
  signed int high = (4096 / sizeof(signed long long));
  signed long long p_ref = -1;
  while (low < high) {
    signed int p = (high + low) / 2;
    p_ref = refs[p];
    if (ref < p_ref) {
      high = p;
    } else if (ref > p_ref) {
      p_ref = refs[p + 1];
      low = p + 1;
    } else {
      break;
    }
  }
  if (ref > p_ref) {
    return -1;
  }
  return p_ref;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binsearch_refblock_ge>:
  endbr64
  mov    $0xffffffffffffffff,%r8
  mov    $0x200,%edx
  xor    %r9d,%r9d
  jmp    L63
  nopl   (%rax)
L55:
  lea    (%r9,%rdx,1),%eax
  sar    %eax
  movslq %eax,%rcx
  mov    (%rdi,%rcx,8),%r8
  lea    0x0(,%rcx,8),%r10
  cmp    %rsi,%r8
  jle    L27
  mov    %eax,%edx
L63:
  cmp    %edx,%r9d
  jl     L55
  cmp    %rsi,%r8
  jl     L62
L13:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  jge    L13
  mov    0x8(%rdi,%r10,1),%r8
  lea    0x1(%rax),%r9d
  jmp    L63
L62:
  mov    $0xffffffffffffffff,%r8
  jmp    L13
```

assistant: ```c
signed long long binsearch_refblock_ge(signed long long *refs, signed long long ref) {
  signed int low = 0;
  signed int high = (4096 / sizeof(signed long long));
  signed long long p_ref = -1;
  while (low < high) {
    signed int p = (high + low) / 2;
    p_ref = refs[p];
    if (ref < p_ref) {
      high = p;
    } else if (ref > p_ref) {
      p_ref = refs[p + 1];
      low = p + 1;
    } else {
      break;
    }
  }
  if (ref > p_ref) {
    return -1;
  }
  return p_ref;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<binsearch_refblock_ge>:
  endbr64
  mov    $0xffffffffffffffff,%r8
  mov    $0x200,%edx
  xor    %r9d,%r9d
  jmp    L45
  nopl   (%rax)
L16:
  lea    (%r9,%rdx,1),%eax
  sar    %eax
  movslq %eax,%rcx
  mov    (%rdi,%rcx,8),%r8
  lea    0x0(,%rcx,8),%r10
  cmp    %rsi,%r8
  jle    L36
  mov    %eax,%edx
L45:
  cmp    %edx,%r9d
  jl     L16
  cmp    %rsi,%r8
  jl     L8
L4:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  jge    L4
  mov    0x8(%rdi,%r10,1),%r8
  lea    0x1(%rax),%r9d
  jmp    L45
L8:
  mov    $0xffffffffffffffff,%r8
  jmp    L4
```

assistant: ```c
signed long long binsearch_refblock_ge(signed long long *refs, signed long long ref) {
  signed int low = 0;
  signed int high = (4096 / sizeof(signed long long));
  signed long long p_ref = -1;
  while (low < high) {
    signed int p = (high + low) / 2;
    p_ref = refs[p];
    if (ref < p_ref) {
      high = p;
    } else if (ref > p_ref) {
      p_ref = refs[p + 1];
      low = p + 1;
    } else {
      break;
    }
  }
  if (ref > p_ref) {
    return -1;
  }
  return p_ref;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_Lex_trie_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5e,-0x4(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  sub    $0x3b,%eax
  jmp    L38
L9:
  cmpl   $0x40,-0x4(%rbp)
  jle    L20
  mov    -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L38
L20:
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int Cyc_Lex_trie_char(int c) {
  if (c >= 95)
    return c - 59;
  else {
    if (c > 64)
      return c - 55;
  }
  return c - 48;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cyc_Lex_trie_char>:
  endbr64
  cmp    $0x5e,%edi
  jg     L7
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x41,%edi
  cmovge %edx,%eax
  ret
L7:
  lea    -0x3b(%rdi),%eax
  ret
```

assistant: ```c
int Cyc_Lex_trie_char(int c) {
  if (c >= 95)
    return c - 59;
  else {
    if (c > 64)
      return c - 55;
  }
  return c - 48;
}
```
user: What is the c source code of the assembly code below:

```asm
<Cyc_Lex_trie_char>:
  endbr64
  cmp    $0x5e,%edi
  jg     L6
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x41,%edi
  cmovge %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    -0x3b(%rdi),%eax
  ret
```

assistant: ```c
int Cyc_Lex_trie_char(int c) {
  if (c >= 95)
    return c - 59;
  else {
    if (c > 64)
      return c - 55;
  }
  return c - 48;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Cyc_Lex_trie_char>:
  endbr64
  cmp    $0x5e,%edi
  jg     L5
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x41,%edi
  cmovge %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    -0x3b(%rdi),%eax
  ret
```

assistant: ```c
int Cyc_Lex_trie_char(int c) {
  if (c >= 95)
    return c - 59;
  else {
    if (c > 64)
      return c - 55;
  }
  return c - 48;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spd_out_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0xc8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int spd_out_printf(char *buf, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vsprintf(buf + strlen(buf), format, ap);
  va_end(ap);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spd_out_printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int spd_out_printf(char *buf, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vsprintf(buf + strlen(buf), format, ap);
  va_end(ap);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<spd_out_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int spd_out_printf(char *buf, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  int result = vsprintf(buf + strlen(buf), format, ap);
  va_end(ap);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L29
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L23
L29:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D26
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D28: %d %d

tool: D26: 0

tool: D6: 1

assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  b = (b >> a);
  if (b % 2 == 0)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%eax
  sar    %cl,%eax
  mov    %eax,0x4(%rsp)
  test   $0x1,%al
  jne    L12
  lea    D28(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D2: %d %d

tool: D28: 0

tool: D17: 1

assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  b = (b >> a);
  if (b % 2 == 0)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%ecx
  sar    %cl,%eax
  mov    %eax,0x4(%rsp)
  test   $0x1,%al
  jne    L14
  lea    D24(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D24
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string

tool: D13: %d %d

tool: D24: 0

tool: D22: 1

assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  b = (b >> a);
  if (b % 2 == 0)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%ecx
  sar    %cl,%eax
  mov    %eax,0x4(%rsp)
  test   $0x1,%al
  jne    L1
  lea    D23(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D23
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D24: %d %d

tool: D23: 0

tool: D16: 1

assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  b = (b >> a);
  if (b % 2 == 0)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    D29(%rip),%eax
  test   %eax,%eax
  jns    L0
  mov    -0x20(%rbp),%eax
  mov    %eax,D7(%rip)
L0:
  mov    -0x20(%rbp),%eax
  mov    D7(%rip),%edx
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: byte[8]

tool: {"D7": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
void wtime(double *t) {
  static int sec = -1;
  struct timeval tv;
  gettimeofday(&tv, (struct timezone *)0);
  if (sec < 0)
    sec = tv.tv_sec;
  *t = (tv.tv_sec - sec) + 1.0e-6 * tv.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<manual_MK_engine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L34
L2:
  movl   $0x0,-0x74(%rbp)
  jmp    L21
L3:
  mov    -0x74(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x78(%rbp),%eax
  add    $0x1,%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1a,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rcx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x74(%rbp)
L21:
  mov    -0x74(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x78(%rbp)
L34:
  mov    -0x78(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L2
  mov    -0x84(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <PLAY_engine@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string

tool: D10: clear

tool: D16: Preencha o tabuleiro:



tool: D28: %c Digite o caractere da linha %d e da coluna %d: 

tool: D13:  %c

assistant: ```c
void manual_MK_engine(int padrao_tam) {
  int i, j;
  char final[10][10];
  system("clear");
  printf("Preencha o tabuleiro:\n\n\n");
  for (i = 0; i < padrao_tam; i++) {
    for (j = 0; j < padrao_tam; j++) {
      printf("%c Digite o caractere da linha %d e da coluna %d: ", 26, i + 1, j + 1);
      scanf(" %c", &final[i][j]);
    }
    printf("\n");
  }
  PLAY_engine(final, padrao_tam);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<manual_MK_engine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <system@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  test   %r13d,%r13d
  jle    L28
  movq   $0x0,(%rsp)
  mov    $0x1,%r12d
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D8(%rip),%r15
  lea    D32(%rip),%r14
L15:
  mov    0x8(%rsp),%rbp
  add    (%rsp),%rbp
  mov    $0x0,%ebx
L47:
  add    $0x1,%ebx
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    $0x1a,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%rbp
  cmp    %r13d,%ebx
  jne    L47
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%r12),%eax
  addq   $0xa,(%rsp)
  cmp    %r13d,%r12d
  je     L28
  mov    %eax,%r12d
  jmp    L15
L28:
  lea    0x10(%rsp),%rdi
  mov    %r13d,%esi
  call   <PLAY_engine@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D32
type_infered: string

tool: D17: clear

tool: D34: Preencha o tabuleiro:



tool: D8: %c Digite o caractere da linha %d e da coluna %d: 

tool: D32:  %c

assistant: ```c
void manual_MK_engine(int padrao_tam) {
  int i, j;
  char final[10][10];
  system("clear");
  printf("Preencha o tabuleiro:\n\n\n");
  for (i = 0; i < padrao_tam; i++) {
    for (j = 0; j < padrao_tam; j++) {
      printf("%c Digite o caractere da linha %d e da coluna %d: ", 26, i + 1, j + 1);
      scanf(" %c", &final[i][j]);
    }
    printf("\n");
  }
  PLAY_engine(final, padrao_tam);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<manual_MK_engine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  lea    D38(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L3
  lea    0x10(%rsp),%rax
  xor    %ebp,%ebp
  movq   $0x0,(%rsp)
  lea    D26(%rip),%r14
  mov    %rax,0x8(%rsp)
  lea    D7(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L42:
  mov    0x8(%rsp),%rbx
  add    $0x1,%ebp
  add    (%rsp),%rbx
  xor    %r15d,%r15d
  nop
L39:
  add    $0x1,%r15d
  mov    %ebp,%edx
  mov    $0x1a,%esi
  mov    %r14,%rdi
  mov    %r15d,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <scanf@plt>
  cmp    %r12d,%r15d
  jne    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0xa,(%rsp)
  cmp    %ebp,%r12d
  jne    L42
L31:
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  call   <PLAY_engine@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L31
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D38
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string

tool: D38: clear

tool: D5: Preencha o tabuleiro:



tool: D26: %c Digite o caractere da linha %d e da coluna %d: 

tool: D7:  %c

assistant: ```c
void manual_MK_engine(int padrao_tam) {
  int i, j;
  char final[10][10];
  system("clear");
  printf("Preencha o tabuleiro:\n\n\n");
  for (i = 0; i < padrao_tam; i++) {
    for (j = 0; j < padrao_tam; j++) {
      printf("%c Digite o caractere da linha %d e da coluna %d: ", 26, i + 1, j + 1);
      scanf(" %c", &final[i][j]);
    }
    printf("\n");
  }
  PLAY_engine(final, padrao_tam);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<manual_MK_engine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  lea    D27(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L16
  lea    0x10(%rsp),%rax
  xor    %ebp,%ebp
  movq   $0x0,(%rsp)
  lea    D20(%rip),%r14
  mov    %rax,0x8(%rsp)
  lea    D4(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L13:
  mov    0x8(%rsp),%rbx
  add    $0x1,%ebp
  add    (%rsp),%rbx
  xor    %r15d,%r15d
  nop
L18:
  add    $0x1,%r15d
  mov    %ebp,%edx
  mov    $0x1a,%esi
  mov    %r14,%rdi
  mov    %r15d,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <scanf@plt>
  cmp    %r12d,%r15d
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0xa,(%rsp)
  cmp    %ebp,%r12d
  jne    L13
L0:
  mov    0x8(%rsp),%rdi
  mov    %r12d,%esi
  call   <PLAY_engine@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L0
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D4
datatype: string

tool: D27: clear

tool: D17: Preencha o tabuleiro:



tool: D20: %c Digite o caractere da linha %d e da coluna %d: 

tool: D4:  %c

assistant: ```c
void manual_MK_engine(int padrao_tam) {
  int i, j;
  char final[10][10];
  system("clear");
  printf("Preencha o tabuleiro:\n\n\n");
  for (i = 0; i < padrao_tam; i++) {
    for (j = 0; j < padrao_tam; j++) {
      printf("%c Digite o caractere da linha %d e da coluna %d: ", 26, i + 1, j + 1);
      scanf(" %c", &final[i][j]);
    }
    printf("\n");
  }
  PLAY_engine(final, padrao_tam);
}
```