ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf4240,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x124f80,%edi
  mov    %rax,%r12
  call   <polybench_alloc_data@plt>
  mov    %rsp,%rdx
  mov    %r12,%rcx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  mov    %rax,%r8
  mov    %rax,%rbp
  call   <init_array@plt>
  movsd  (%rsp),%xmm0
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  call   <kernel_trmm@plt>
  cmp    $0x2a,%ebx
  jle    L29
  mov    0x0(%r13),%rax
  cmpb   $0x0,(%rax)
  je     L38
L29:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %rbp,%rdx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  call   <print_array@plt>
  jmp    L29
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int m = 1000;
  int n = 1200;
  double alpha;
  double(*A)[1000 + 0][1000 + 0];
  A = (double(*)[1000 + 0][1000 + 0]) polybench_alloc_data((1000 + 0) * (1000 + 0), sizeof(double));
  ;
  double(*B)[1000 + 0][1200 + 0];
  B = (double(*)[1000 + 0][1200 + 0]) polybench_alloc_data((1000 + 0) * (1200 + 0), sizeof(double));
  ;
  init_array(m, n, &alpha, *A, *B);
  ;
  kernel_trmm(m, n, alpha, *A, *B);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *B);
  free((void *)A);
  ;
  free((void *)B);
  ;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf4240,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x124f80,%edi
  mov    %rax,%r12
  call   <polybench_alloc_data@plt>
  mov    %rsp,%rdx
  mov    %r12,%rcx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  mov    %rax,%r8
  mov    %rax,%rbp
  call   <init_array@plt>
  movsd  (%rsp),%xmm0
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  call   <kernel_trmm@plt>
  cmp    $0x2a,%ebx
  jle    L25
  mov    0x0(%r13),%rax
  cmpb   $0x0,(%rax)
  je     L32
L25:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %rbp,%rdx
  mov    $0x4b0,%esi
  mov    $0x3e8,%edi
  call   <print_array@plt>
  jmp    L25
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int m = 1000;
  int n = 1200;
  double alpha;
  double(*A)[1000 + 0][1000 + 0];
  A = (double(*)[1000 + 0][1000 + 0]) polybench_alloc_data((1000 + 0) * (1000 + 0), sizeof(double));
  ;
  double(*B)[1000 + 0][1200 + 0];
  B = (double(*)[1000 + 0][1200 + 0]) polybench_alloc_data((1000 + 0) * (1200 + 0), sizeof(double));
  ;
  init_array(m, n, &alpha, *A, *B);
  ;
  kernel_trmm(m, n, alpha, *A, *B);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *B);
  free((void *)A);
  ;
  free((void *)B);
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numprocessos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x238(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x3c,-0x228(%rbp)
  mov    -0x228(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,-0x220(%rbp)
  mov    -0x220(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,-0x218(%rbp)
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <sysinfo@plt>
  movb   $0x0,-0x200(%rbp)
  mov    -0x208(%rbp),%ecx
  mov    -0x210(%rbp),%rax
  cqto
  idivq  -0x228(%rbp)
  mov    %rdx,%rsi
  mov    -0x210(%rbp),%rax
  cqto
  idivq  -0x220(%rbp)
  mov    %rdx,%rax
  cqto
  idivq  -0x228(%rbp)
  mov    %rax,%r8
  mov    -0x210(%rbp),%rax
  cqto
  idivq  -0x218(%rbp)
  mov    %rdx,%rax
  cqto
  idivq  -0x220(%rbp)
  mov    %rax,%rdi
  mov    -0x210(%rbp),%rax
  cqto
  idivq  -0x218(%rbp)
  mov    %rax,%rdx
  lea    -0x200(%rbp),%rax
  push   %rcx
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    $0x1f4,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  add    $0x10,%rsp
  mov    -0x240(%rbp),%rdx
  lea    -0x200(%rbp),%rcx
  mov    -0x238(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: <b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes

assistant: ```c
int numprocessos(char *b, size_t s) {
  const long minuto = 60;
  const long hora = minuto * 60;
  const long dia = hora * 24;
  struct sysinfo si;
  sysinfo(&si);
  char buffer[500];
  buffer[0] = '\x0';
  snprintf(buffer, 500, "<b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes", si.uptime / dia, (si.uptime % dia) / hora, (si.uptime % hora) / minuto, si.uptime % minuto, si.procs);
  strncat(b, buffer, s);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numprocessos>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sysinfo@plt>
  movb   $0x0,0x10(%rsp)
  mov    (%rsp),%rsi
  movabs $0x48d159e26af37c05,%r8
  mov    %rsi,%rax
  imul   %r8
  sar    $0xa,%rdx
  mov    %rsi,%r13
  sar    $0x3f,%r13
  sub    %r13,%rdx
  imul   $0xe10,%rdx,%rdx
  mov    %rsi,%r10
  sub    %rdx,%r10
  movabs $0x8888888888888889,%rcx
  mov    %r10,%rax
  imul   %rcx
  lea    (%rdx,%r10,1),%r9
  sar    $0x5,%r9
  sar    $0x3f,%r10
  movabs $0x1845c8a0ce512957,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0xd,%rdx
  mov    %rdx,%rdi
  sub    %r13,%rdi
  imul   $0x15180,%rdi,%rax
  mov    %rsi,%r11
  sub    %rax,%r11
  mov    %r11,%rax
  imul   %r8
  mov    %rdx,%r8
  sar    $0xa,%r8
  sar    $0x3f,%r11
  lea    0x10(%rsp),%r12
  mov    0x8(%rsp),%eax
  push   %rax
  mov    %rsi,%rax
  imul   %rcx
  lea    (%rdx,%rsi,1),%rcx
  sar    $0x5,%rcx
  sub    %r13,%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  sub    %rcx,%rax
  shl    $0x2,%rax
  sub    %rax,%rsi
  push   %rsi
  sub    %r10,%r9
  sub    %r11,%r8
  mov    %rdi,%rcx
  lea    D2(%rip),%rdx
  mov    $0x1f4,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  add    $0x10,%rsp
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: <b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes

assistant: ```c
int numprocessos(char *b, size_t s) {
  const long minuto = 60;
  const long hora = minuto * 60;
  const long dia = hora * 24;
  struct sysinfo si;
  sysinfo(&si);
  char buffer[500];
  buffer[0] = '\x0';
  snprintf(buffer, 500, "<b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes", si.uptime / dia, (si.uptime % dia) / hora, (si.uptime % hora) / minuto, si.uptime % minuto, si.procs);
  strncat(b, buffer, s);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<numprocessos>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%r13
  call   <sysinfo@plt>
  mov    (%rsp),%rsi
  movb   $0x0,0x10(%rsp)
  movabs $0x48d159e26af37c05,%r8
  movabs $0x8888888888888889,%rcx
  mov    %rsi,%rax
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  mov    %rsi,%r11
  imul   %r8
  sar    $0x3f,%rbx
  sar    $0xa,%rdx
  sub    %rbx,%rdx
  imul   $0xe10,%rdx,%rdx
  sub    %rdx,%rdi
  mov    %rdi,%rax
  imul   %rcx
  mov    %rsi,%rax
  lea    (%rdx,%rdi,1),%r9
  sar    $0x3f,%rdi
  movabs $0x1845c8a0ce512957,%rdx
  imul   %rdx
  sar    $0x5,%r9
  sub    %rdi,%r9
  mov    %r13,%rdi
  sar    $0xd,%rdx
  sub    %rbx,%rdx
  imul   $0x15180,%rdx,%rax
  mov    %rdx,%r10
  sub    %rax,%r11
  mov    %r11,%rax
  sar    $0x3f,%r11
  imul   %r8
  mov    0x8(%rsp),%eax
  push   %rax
  mov    %rsi,%rax
  mov    %rdx,%r8
  imul   %rcx
  sar    $0xa,%r8
  sub    %r11,%r8
  lea    (%rdx,%rsi,1),%rcx
  lea    D8(%rip),%rdx
  sar    $0x5,%rcx
  sub    %rbx,%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  sub    %rcx,%rax
  mov    %r10,%rcx
  shl    $0x2,%rax
  sub    %rax,%rsi
  push   %rsi
  mov    $0x1f4,%esi
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  pop    %rax
  pop    %rdx
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x218,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: <b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes

assistant: ```c
int numprocessos(char *b, size_t s) {
  const long minuto = 60;
  const long hora = minuto * 60;
  const long dia = hora * 24;
  struct sysinfo si;
  sysinfo(&si);
  char buffer[500];
  buffer[0] = '\x0';
  snprintf(buffer, 500, "<b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes", si.uptime / dia, (si.uptime % dia) / hora, (si.uptime % hora) / minuto, si.uptime % minuto, si.procs);
  strncat(b, buffer, s);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<numprocessos>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%r13
  call   <sysinfo@plt>
  mov    (%rsp),%rsi
  movb   $0x0,0x10(%rsp)
  movabs $0x48d159e26af37c05,%r8
  movabs $0x8888888888888889,%rcx
  mov    %rsi,%rax
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  mov    %rsi,%r11
  imul   %r8
  sar    $0x3f,%rbx
  sar    $0xa,%rdx
  sub    %rbx,%rdx
  imul   $0xe10,%rdx,%rdx
  sub    %rdx,%rdi
  mov    %rdi,%rax
  imul   %rcx
  mov    %rsi,%rax
  lea    (%rdx,%rdi,1),%r9
  sar    $0x3f,%rdi
  movabs $0x1845c8a0ce512957,%rdx
  imul   %rdx
  sar    $0x5,%r9
  sub    %rdi,%r9
  mov    %r13,%rdi
  sar    $0xd,%rdx
  sub    %rbx,%rdx
  imul   $0x15180,%rdx,%rax
  mov    %rdx,%r10
  sub    %rax,%r11
  mov    %r11,%rax
  sar    $0x3f,%r11
  imul   %r8
  mov    0x8(%rsp),%eax
  push   %rax
  mov    %rsi,%rax
  mov    %rdx,%r8
  imul   %rcx
  sar    $0xa,%r8
  sub    %r11,%r8
  lea    (%rdx,%rsi,1),%rcx
  lea    D8(%rip),%rdx
  sar    $0x5,%rcx
  sub    %rbx,%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  sub    %rcx,%rax
  mov    %r10,%rcx
  shl    $0x2,%rax
  sub    %rax,%rsi
  push   %rsi
  mov    $0x1f4,%esi
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  pop    %rax
  pop    %rdx
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x218,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: <b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes

assistant: ```c
int numprocessos(char *b, size_t s) {
  const long minuto = 60;
  const long hora = minuto * 60;
  const long dia = hora * 24;
  struct sysinfo si;
  sysinfo(&si);
  char buffer[500];
  buffer[0] = '\x0';
  snprintf(buffer, 500, "<b>UpTime:</b> %ld days, %ld:%02ld:%02ld hours<br> <b>Number of Processes:</b> <br>%d Processes", si.uptime / dia, (si.uptime % dia) / hora, (si.uptime % hora) / minuto, si.uptime % minuto, si.procs);
  strncat(b, buffer, s);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isDir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int isDir(const char *path) {
  struct stat path_stat;
  stat(path, &path_stat);
  return S_ISDIR(path_stat.st_mode);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isDir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isDir(const char *path) {
  struct stat path_stat;
  stat(path, &path_stat);
  return S_ISDIR(path_stat.st_mode);
}
```
user: What is the c source code of the assembly code below?

```asm
<isDir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isDir(const char *path) {
  struct stat path_stat;
  stat(path, &path_stat);
  return S_ISDIR(path_stat.st_mode);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isDir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isDir(const char *path) {
  struct stat path_stat;
  stat(path, &path_stat);
  return S_ISDIR(path_stat.st_mode);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L16:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ptr = malloc(size);
  if (ptr == NULL)
    abort();
  else
    memset(ptr, 0, size);
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L5
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ptr = malloc(size);
  if (ptr == NULL)
    abort();
  else
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xmalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L15:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L10
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ptr = malloc(size);
  if (ptr == NULL)
    abort();
  else
    memset(ptr, 0, size);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L5:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ptr = malloc(size);
  if (ptr == NULL)
    abort();
  else
    memset(ptr, 0, size);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<sort_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfb4(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0xfb4(%rbp)
  jmp    L45
L14:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfb4(%rbp)
L45:
  cmpl   $0x3e7,-0xfb4(%rbp)
  jle    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0xfb0(%rbp),%rax
  mov    $0x3e7,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  movl   $0x0,-0xfb4(%rbp)
  jmp    L35
L39:
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfb4(%rbp)
L35:
  cmpl   $0x3e7,-0xfb4(%rbp)
  jle    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
data_type: string

tool: D16: %d 

assistant: ```c
void sort_test() {
  int i = 0;
  int data[1000];
  srand((unsigned)time(NULL));
  for (i = 0; i < 1000; i++) {
    data[i] = rand() % 1000;
    printf("%d ", data[i]);
  }
  printf("\n");
  printf("\n");
  printf("\n");
  printf("\n");
  quickSort(data, 0, 1000 - 1);
  for (i = 0; i < 1000; i++) {
    printf("%d ", data[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort_test>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  lea    0xfa0(%rsp),%r12
  mov    %rbx,%rbp
  lea    D6(%rip),%r13
L28:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rsi
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  cltd
  sub    %edx,%esi
  imul   $0x3e8,%esi,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %eax,0x0(%rbp)
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x3e7,%edx
  mov    $0x0,%esi
  call   <quickSort@plt>
  lea    D6(%rip),%rbp
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d 

assistant: ```c
void sort_test() {
  int i = 0;
  int data[1000];
  srand((unsigned)time(NULL));
  for (i = 0; i < 1000; i++) {
    data[i] = rand() % 1000;
    printf("%d ", data[i]);
  }
  printf("\n");
  printf("\n");
  printf("\n");
  printf("\n");
  quickSort(data, 0, 1000 - 1);
  for (i = 0; i < 1000; i++) {
    printf("%d ", data[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_test>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0xfa0(%rsp),%r12
  call   <time@plt>
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  mov    %r13,%rdi
  movslq %eax,%rsi
  cltd
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  sub    %edx,%esi
  imul   $0x3e8,%esi,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x3e7,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <quickSort@plt>
  nop
L3:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: %d 

assistant: ```c
void sort_test() {
  int i = 0;
  int data[1000];
  srand((unsigned)time(NULL));
  for (i = 0; i < 1000; i++) {
    data[i] = rand() % 1000;
    printf("%d ", data[i]);
  }
  printf("\n");
  printf("\n");
  printf("\n");
  printf("\n");
  quickSort(data, 0, 1000 - 1);
  for (i = 0; i < 1000; i++) {
    printf("%d ", data[i]);
  }
  printf("\n");
}
```