ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L35
  jg     L32
  cmp    $0x2a,%al
  je     L25
  cmp    $0x2b,%al
  jne    L53
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <sum@plt>
L53:
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <euclides_mdc@plt>
  mov    %eax,%r9d
  mov    0x24(%rsp),%edi
  mov    0x20(%rsp),%esi
  mov    %edi,%eax
  cltd
  idiv   %r9d
  mov    %eax,%r8d
  mov    %esi,%eax
  cltd
  idiv   %r9d
  mov    %eax,%ecx
  mov    %edi,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  ret
L32:
  cmp    $0x2f,%al
  jne    L53
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <div@plt>
  jmp    L53
L35:
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <subtr@plt>
  jmp    L53
L25:
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <mult@plt>
  jmp    L53
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D2: %d / %d %c %d / %d

tool: D5: %d/%d = %d/%d


assistant: ```c
void calc() {
  int n1, d1, n2, d2, r1, r2;
  char operator;
  scanf("%d / %d %c %d / %d", &n1, &d1, &operator, & n2, &d2);
  switch (operator) {
  case '+':
    sum(n1, d1, n2, d2, &r1, &r2);
    break;
  case '-':
    subtr(n1, d1, n2, d2, &r1, &r2);
    break;
  case '*':
    mult(n1, d1, n2, d2, &r1, &r2);
    break;
  case '/':
    div(n1, d1, n2, d2, &r1, &r2);
    break;
  }
  int mdc = euclides_mdc(r1, r2);
  printf("%d/%d = %d/%d\n", r1, r2, r1 / mdc, r2 / mdc, mdc);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calc>:
  endbr64
  sub    $0x38,%rsp
  lea    D18(%rip),%rdi
  lea    0xf(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L27
  jg     L72
  cmp    $0x2a,%al
  je     L52
  cmp    $0x2b,%al
  jne    L43
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <sum@plt>
  nopl   0x0(%rax,%rax,1)
L43:
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <euclides_mdc@plt>
  mov    0x24(%rsp),%r10d
  mov    0x20(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    %eax,%r9d
  mov    %r10d,%eax
  cltd
  idiv   %r9d
  mov    %eax,%r8d
  mov    %esi,%eax
  cltd
  idiv   %r9d
  mov    %r10d,%edx
  mov    %eax,%ecx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x38,%rsp
  ret
  nop
L72:
  cmp    $0x2f,%al
  jne    L43
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <div@plt>
  jmp    L43
  nopl   (%rax)
L27:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <subtr@plt>
  jmp    L43
  nopl   0x0(%rax)
L52:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <mult@plt>
  jmp    L43
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D19
type: string

tool: D18: %d / %d %c %d / %d

tool: D19: %d/%d = %d/%d


assistant: ```c
void calc() {
  int n1, d1, n2, d2, r1, r2;
  char operator;
  scanf("%d / %d %c %d / %d", &n1, &d1, &operator, & n2, &d2);
  switch (operator) {
  case '+':
    sum(n1, d1, n2, d2, &r1, &r2);
    break;
  case '-':
    subtr(n1, d1, n2, d2, &r1, &r2);
    break;
  case '*':
    mult(n1, d1, n2, d2, &r1, &r2);
    break;
  case '/':
    div(n1, d1, n2, d2, &r1, &r2);
    break;
  }
  int mdc = euclides_mdc(r1, r2);
  printf("%d/%d = %d/%d\n", r1, r2, r1 / mdc, r2 / mdc, mdc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calc>:
  endbr64
  sub    $0x38,%rsp
  lea    D12(%rip),%rdi
  lea    0xf(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2d,%al
  je     L7
  jg     L18
  cmp    $0x2a,%al
  je     L35
  cmp    $0x2b,%al
  jne    L87
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <sum@plt>
  nopl   0x0(%rax,%rax,1)
L87:
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <euclides_mdc@plt>
  mov    0x24(%rsp),%r10d
  mov    0x20(%rsp),%esi
  lea    D15(%rip),%rdi
  mov    %eax,%r9d
  mov    %r10d,%eax
  cltd
  idiv   %r9d
  mov    %eax,%r8d
  mov    %esi,%eax
  cltd
  idiv   %r9d
  mov    %r10d,%edx
  mov    %eax,%ecx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x38,%rsp
  ret
  nop
L18:
  cmp    $0x2f,%al
  jne    L87
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <div@plt>
  jmp    L87
  nopl   (%rax)
L7:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <subtr@plt>
  jmp    L87
  nopl   0x0(%rax)
L35:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <mult@plt>
  jmp    L87
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D15
type: string

tool: D12: %d / %d %c %d / %d

tool: D15: %d/%d = %d/%d


assistant: ```c
void calc() {
  int n1, d1, n2, d2, r1, r2;
  char operator;
  scanf("%d / %d %c %d / %d", &n1, &d1, &operator, & n2, &d2);
  switch (operator) {
  case '+':
    sum(n1, d1, n2, d2, &r1, &r2);
    break;
  case '-':
    subtr(n1, d1, n2, d2, &r1, &r2);
    break;
  case '*':
    mult(n1, d1, n2, d2, &r1, &r2);
    break;
  case '/':
    div(n1, d1, n2, d2, &r1, &r2);
    break;
  }
  int mdc = euclides_mdc(r1, r2);
  printf("%d/%d = %d/%d\n", r1, r2, r1 / mdc, r2 / mdc, mdc);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L14:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L23:
  cmpl   $0x3ff,-0x10(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  int i;
  union {
    int i;
    char b[4];
  } b4;
  for (i = 0; i < 1024; i++) {
    b4.i = i;
    putchar(b4.b[0]);
    putchar(b4.b[1]);
    putchar(b4.b[2]);
    putchar(b4.b[3]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L0:
  movsbl %bl,%edi
  call   <putchar@plt>
  movsbl %bh,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x8,%edi
  sar    $0x18,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x18,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    $0x400,%ebx
  jne    L0
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  int i;
  union {
    int i;
    char b[4];
  } b4;
  for (i = 0; i < 1024; i++) {
    b4.i = i;
    putchar(b4.b[0]);
    putchar(b4.b[1]);
    putchar(b4.b[2]);
    putchar(b4.b[3]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  movsbl %bl,%edi
  call   <putchar@plt>
  movsbl %bh,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x8,%edi
  sar    $0x18,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  sar    $0x18,%edi
  call   <putchar@plt>
  cmp    $0x400,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  int i;
  union {
    int i;
    char b[4];
  } b4;
  for (i = 0; i < 1024; i++) {
    b4.i = i;
    putchar(b4.b[0]);
    putchar(b4.b[1]);
    putchar(b4.b[2]);
    putchar(b4.b[3]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl %bl,%edi
  call   <putchar@plt>
  movsbl %bh,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x8,%edi
  sar    $0x18,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  sar    $0x18,%edi
  call   <putchar@plt>
  cmp    $0x400,%ebx
  jne    L5
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  int i;
  union {
    int i;
    char b[4];
  } b4;
  for (i = 0; i < 1024; i++) {
    b4.i = i;
    putchar(b4.b[0]);
    putchar(b4.b[1]);
    putchar(b4.b[2]);
    putchar(b4.b[3]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<editdist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L37
  mov    -0x28(%rbp),%eax
  jmp    L18
L37:
  cmpl   $0x0,-0x28(%rbp)
  jne    L15
  mov    -0x24(%rbp),%eax
  jmp    L18
L15:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <editdist>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <editdist>
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <editdist>
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  setne  %al
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <minthree@plt>
L18:
  leave
  ret
```

assistant: ```c
int editdist(char str1[], char str2[], int m, int n) {
  if (m == 0) {
    return n;
  }
  if (n == 0) {
    return m;
  }
  int left = editdist(str1, str2, m - 1, n) + 1;
  int right = editdist(str1, str2, m, n - 1) + 1;
  int corner = editdist(str1, str2, m - 1, n - 1) + (str1[m] == str2[n] ? 0 : 1);
  return minthree(left, right, corner);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<editdist>:
  endbr64
  mov    %ecx,%eax
  test   %edx,%edx
  je     L24
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    %edx,%eax
  test   %ecx,%ecx
  jne    L18
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  lea    -0x1(%rdx),%r14d
  mov    %r14d,%edx
  call   <editdist>
  mov    %eax,0x8(%rsp)
  lea    -0x1(%rbx),%r15d
  mov    %r15d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <editdist>
  mov    %eax,0xc(%rsp)
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <editdist>
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  movzbl (%r12,%rbx,1),%ecx
  cmp    %cl,0x0(%r13,%rbp,1)
  setne  %dl
  movzbl %dl,%edx
  add    %eax,%edx
  mov    0xc(%rsp),%esi
  add    $0x1,%esi
  mov    0x8(%rsp),%edi
  add    $0x1,%edi
  call   <minthree@plt>
  jmp    L1
L24:
  ret
```

assistant: ```c
int editdist(char str1[], char str2[], int m, int n) {
  if (m == 0) {
    return n;
  }
  if (n == 0) {
    return m;
  }
  int left = editdist(str1, str2, m - 1, n) + 1;
  int right = editdist(str1, str2, m, n - 1) + 1;
  int corner = editdist(str1, str2, m - 1, n - 1) + (str1[m] == str2[n] ? 0 : 1);
  return minthree(left, right, corner);
}
```
user: What is the c source code of the assembly code below?

```asm
<editdist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x18,%rsp
  test   %ebx,%ebx
  je     L8
  mov    %ebx,%eax
  test   %ebp,%ebp
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L2:
  lea    -0x1(%rbx),%r13d
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %ebp,%ecx
  mov    %r13d,%edx
  call   <editdist>
  lea    -0x1(%rbp),%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %ecx,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  call   <editdist>
  mov    0xc(%rsp),%ecx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %eax,%r14d
  call   <editdist>
  movzbl (%r12,%rbp,1),%esi
  mov    0x8(%rsp),%edi
  xor    %edx,%edx
  cmp    %sil,(%r15,%rbx,1)
  lea    0x1(%r14),%esi
  setne  %dl
  add    $0x18,%rsp
  add    $0x1,%edi
  pop    %rbx
  add    %eax,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <minthree@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x18,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int editdist(char str1[], char str2[], int m, int n) {
  if (m == 0) {
    return n;
  }
  if (n == 0) {
    return m;
  }
  int left = editdist(str1, str2, m - 1, n) + 1;
  int right = editdist(str1, str2, m, n - 1) + 1;
  int corner = editdist(str1, str2, m - 1, n - 1) + (str1[m] == str2[n] ? 0 : 1);
  return minthree(left, right, corner);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<page48>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2d,%edi
  call   <new_clone@plt>
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D43
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string

tool: D13: The tubecar shoots forward as you enter, slamming you back into a pile of


tool: D43: garbage.  The front end rotates upward and you, the garbage and the garbage


tool: D10: disposal car shoot straight up out of Alpha Complex.  One of the last things


tool: D24: you see is a small blue sphere slowly dwindling behind you.  After you fail to


tool: D16: report in, you will be assumed dead.


assistant: ```c
page48() {
  printf("The tubecar shoots forward as you enter, slamming you back into a pile of\n");
  printf("garbage.  The front end rotates upward and you, the garbage and the garbage\n");
  printf("disposal car shoot straight up out of Alpha Complex.  One of the last things\n");
  printf("you see is a small blue sphere slowly dwindling behind you.  After you fail to\n");
  printf("report in, you will be assumed dead.\n");
  return new_clone(45);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<page48>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x2d,%edi
  call   <new_clone@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D37
type_guessed: string
name: parse_data
arguments: data_tag: D43
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string

tool: D21: The tubecar shoots forward as you enter, slamming you back into a pile of


tool: D49: garbage.  The front end rotates upward and you, the garbage and the garbage


tool: D37: disposal car shoot straight up out of Alpha Complex.  One of the last things


tool: D43: you see is a small blue sphere slowly dwindling behind you.  After you fail to


tool: D35: report in, you will be assumed dead.


assistant: ```c
page48() {
  printf("The tubecar shoots forward as you enter, slamming you back into a pile of\n");
  printf("garbage.  The front end rotates upward and you, the garbage and the garbage\n");
  printf("disposal car shoot straight up out of Alpha Complex.  One of the last things\n");
  printf("you see is a small blue sphere slowly dwindling behind you.  After you fail to\n");
  printf("report in, you will be assumed dead.\n");
  return new_clone(45);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<page48>:
  endbr64
  sub    $0x8,%rsp
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x2d,%edi
  add    $0x8,%rsp
  jmp    1070 <new_clone@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D38
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D48
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string

tool: D30: The tubecar shoots forward as you enter, slamming you back into a pile of


tool: D38: garbage.  The front end rotates upward and you, the garbage and the garbage


tool: D6: disposal car shoot straight up out of Alpha Complex.  One of the last things


tool: D48: you see is a small blue sphere slowly dwindling behind you.  After you fail to


tool: D24: report in, you will be assumed dead.


assistant: ```c
page48() {
  printf("The tubecar shoots forward as you enter, slamming you back into a pile of\n");
  printf("garbage.  The front end rotates upward and you, the garbage and the garbage\n");
  printf("disposal car shoot straight up out of Alpha Complex.  One of the last things\n");
  printf("you see is a small blue sphere slowly dwindling behind you.  After you fail to\n");
  printf("report in, you will be assumed dead.\n");
  return new_clone(45);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<page48>:
  endbr64
  sub    $0x8,%rsp
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x2d,%edi
  add    $0x8,%rsp
  jmp    1070 <new_clone@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D29: The tubecar shoots forward as you enter, slamming you back into a pile of


tool: D8: garbage.  The front end rotates upward and you, the garbage and the garbage


tool: D21: disposal car shoot straight up out of Alpha Complex.  One of the last things


tool: D0: you see is a small blue sphere slowly dwindling behind you.  After you fail to


tool: D4: report in, you will be assumed dead.


assistant: ```c
page48() {
  printf("The tubecar shoots forward as you enter, slamming you back into a pile of\n");
  printf("garbage.  The front end rotates upward and you, the garbage and the garbage\n");
  printf("disposal car shoot straight up out of Alpha Complex.  One of the last things\n");
  printf("you see is a small blue sphere slowly dwindling behind you.  After you fail to\n");
  printf("report in, you will be assumed dead.\n");
  return new_clone(45);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vfscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int vfscanf(FILE *file, const char *format, va_list parameters) {
  (void)(file);
  (void)(format);
  (void)(parameters);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vfscanf>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int vfscanf(FILE *file, const char *format, va_list parameters) {
  (void)(file);
  (void)(format);
  (void)(parameters);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vfscanf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int vfscanf(FILE *file, const char *format, va_list parameters) {
  (void)(file);
  (void)(format);
  (void)(parameters);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vfscanf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int vfscanf(FILE *file, const char *format, va_list parameters) {
  (void)(file);
  (void)(format);
  (void)(parameters);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_invalid_clause>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L19:
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0xf,-0x4(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp parallel
#pragma omp for foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp parallel
#pragma omp for foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp parallel
#pragma omp for foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp parallel
#pragma omp for foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```