user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movq   $0xfffffffffffffff3,0x8(%rsp)
  lea    D40(%rip),%r14
L116:
  lea    0x10(%rsp),%rax
  lea    0x64(%rsp),%rdx
L97:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L97
  lea    0x4(%rsp),%rbx
L130:
  mov    $0x14,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x14,%eax
  jg     L130
  test   %eax,%eax
  js     L84
  mov    $0x2710,%ebx
  lea    0x8(%rsp),%rbp
  jmp    L96
L156:
  sub    $0x1,%ebx
  je     L104
L96:
  mov    %rbp,%rsi
  mov    0x4(%rsp),%edi
  call   <gamdev@plt>
  cmp    $0x14,%eax
  ja     L156
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  jmp    L156
L104:
  mov    $0x2710,%edx
  mov    0x4(%rsp),%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rcx
  lea    D23(%rip),%rdx
  lea    D7(%rip),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r13d
  lea    0x10(%rsp),%r15
  jmp    L109
L134:
  movsbl (%rbx,%r12,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L134
L139:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13
  cmp    $0x14,%r13
  je     L116
L109:
  mov    %r13d,%esi
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%r15,%r13,4),%xmm0
  divss  D83(%rip),%xmm0
  lea    0x71(%rsp),%rax
  lea    0xa3(%rsp),%rdx
L52:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L52
  movss  D76(%rip),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%eax
  mov    $0x32,%ebp
  cmp    %ebp,%eax
  cmovle %eax,%ebp
  test   %eax,%eax
  jle    L73
  mov    $0x1,%eax
L106:
  movb   $0x2a,0x70(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L106
  cvtss2sd %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    0x70(%rsp),%r12
  jmp    L134
L84:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L154
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L73:
  cvtss2sd %xmm0,%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L139
L154:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D40
type: string
name: disassemble_data
arguments: label: D24
type: string
name: disassemble_data
arguments: label: D45
type: string
name: disassemble_data
arguments: label: D39
type: string
name: disassemble_data
arguments: label: D31
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D83
type: byte[4]
name: disassemble_data
arguments: label: D76
type: byte[4]

tool: D40: %6d %8.4f  

tool: D24: Select order of Gamma distribution (n=1..%d), -1 to end


tool: D45: %d

tool: D39: 
gamma-distribution deviate, order %2d of %6d points


tool: D31: graph:

tool: D23: p(x)

tool: D7: x

tool: D10: %6s %7s %9s 


tool: {"D83": [0x00,0x40,0x1c,0x46]}

tool: {"D76": [0x00,0x00,0x48,0x43]}

assistant: ```c
int main(void) {
  char words[50 + 1];
  long idum = (-13);
  int i, ia, j, k, klim, dist[20 + 1];
  float dd;
  for (;;) {
    for (j = 0; j <= 20; j++)
      dist[j] = 0;
    do {
      printf("Select order of Gamma distribution (n=1..%d), -1 to end\n", 20);
      scanf("%d", &ia);
    } while (ia > 20);
    if (ia < 0)
      break;
    for (i = 1; i <= 10000; i++) {
      j = (int)gamdev(ia, &idum);
      if ((j >= 0) && (j <= 20))
        ++dist[j];
    }
    printf("\ngamma-distribution deviate, order %2d of %6d points\n", ia, 10000);
    printf("%6s %7s %9s \n", "x", "p(x)", "graph:");
    for (j = 0; j < 20; j++) {
      dd = (float)dist[j] / 10000;
      for (k = 1; k <= 50; k++)
        words[k] = ' ';
      klim = (int)(200 * dd);
      if (klim > 50)
        klim = 50;
      for (k = 1; k <= klim; k++)
        words[k] = '*';
      printf("%6d %8.4f  ", j, dd);
      for (k = 1; k <= klim; k++)
        printf("%c", words[k]);
      printf("\n");
    }
  }
  return 0;
}
```