user: 请从给定的汇编指令推导出C源代码:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %edx,%r9d
  mov    %rsp,%rbp
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %r8d,%eax
  mov    %rsp,%rcx
  sub    %esi,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L83
L142:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L142
L83:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L96
L125:
  mov    %rsp,%r8
  mov    %r15d,%r12d
  cmp    %r9d,%r15d
  jg     L61
  cmp    %ebx,%r14d
  jl     L61
  mov    $0x1,%eax
  jmp    L42
L74:
  mov    %esi,%edx
  add    $0x1,%r12d
  mov    %edx,-0x4(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r9d,%r12d
  jg     L85
L105:
  cmp    %r14d,%ebx
  jg     L85
L42:
  movslq %r12d,%rdx
  mov    %eax,%ecx
  mov    0x0(%r13,%rdx,4),%esi
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %edx,%esi
  jl     L74
  mov    %edx,-0x4(%r8,%rax,4)
  add    $0x1,%ebx
  add    $0x1,%rax
  cmp    %r9d,%r12d
  jle    L105
L85:
  cmp    %r12d,%r9d
  jl     L65
  movslq %ecx,%rax
  mov    %ecx,-0x54(%rbp)
  lea    (%r8,%rax,4),%rdi
  mov    %r9d,%eax
  mov    %r8,-0x50(%rbp)
  sub    %r12d,%eax
  mov    %r9d,-0x48(%rbp)
  lea    0x4(,%rax,4),%rdx
  movslq %r12d,%rax
  lea    0x0(%r13,%rax,4),%rsi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r9d
  mov    -0x54(%rbp),%ecx
  mov    -0x50(%rbp),%r8
  lea    0x1(%rcx,%r9,1),%ecx
  sub    %r12d,%ecx
L65:
  cmp    %ebx,%r14d
  jl     L49
  mov    %r14d,%eax
  movslq %ecx,%rcx
  mov    %r8,-0x48(%rbp)
  sub    %ebx,%eax
  movslq %ebx,%rbx
  lea    (%r8,%rcx,4),%rdi
  lea    0x4(,%rax,4),%rdx
  lea    0x0(%r13,%rbx,4),%rsi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r8
L49:
  cmp    %r14d,%r15d
  jg     L141
  movslq %r15d,%rax
  sub    %r15d,%r14d
  mov    %r8,%rsi
  lea    0x0(%r13,%rax,4),%rdi
  lea    0x4(,%r14,4),%rdx
  call   <memcpy@plt>
L141:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L96:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L125
L61:
  xor    %ecx,%ecx
  jmp    L85
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int *a, int left1, int left2, int right1, int right2) {
  int low = left1;
  int high = right2;
  int leftpoint = left1;
  int rightpoint = right1;
  int i = 0;
  int temp[right2 - left1 + 1];
  while ((leftpoint <= left2) && (rightpoint <= right2)) {
    if (a[leftpoint] < a[rightpoint]) {
      temp[i] = a[leftpoint];
      leftpoint++;
      i++;
    } else {
      temp[i] = a[rightpoint];
      rightpoint++;
      i++;
    }
  }
  while ((leftpoint <= left2)) {
    temp[i] = a[leftpoint];
    leftpoint++;
    i++;
  }
  while ((rightpoint <= right2)) {
    temp[i] = a[rightpoint];
    rightpoint++;
    i++;
  }
  int d = 0;
  for (i = low; i <= high; i++)
    a[i] = temp[d++];
}
```