ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L18
  cmp    $0x10000000,%edi
  ja     L18
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0x180,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/parse_tab.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/parse_tab.c", 384));
  return word_ans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L7
  cmp    $0x10000000,%edi
  ja     L7
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0x180,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/parse_tab.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/pgerakios/Concurrent-Cyclone-with-inference/refs/heads/master/bin/genfiles/parse_tab.c", 384));
  return word_ans;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bla2le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L7
  mov    $0x0,%eax
  call   <this_comparison_is_not_decidable@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void bla2le(int var) {
  if (var + 10 <= INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bla2le>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  jge    L2
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <this_comparison_is_not_decidable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bla2le(int var) {
  if (var + 10 <= INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bla2le>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  jge    L8
  ret
L8:
  xor    %eax,%eax
  jmp    1050 <this_comparison_is_not_decidable@plt>
```

assistant: ```c
void bla2le(int var) {
  if (var + 10 <= INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bla2le>:
  endbr64
  mov    D3(%rip),%rax
  cmp    %edi,(%rax)
  jge    L5
  ret
L5:
  xor    %eax,%eax
  jmp    1050 <this_comparison_is_not_decidable@plt>
```

assistant: ```c
void bla2le(int var) {
  if (var + 10 <= INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<matrix_ij_H>:
  endbr64
  mov    %rsi,%rcx
  movapd %xmm0,%xmm6
  mulsd  %xmm0,%xmm6
  mulsd  %xmm3,%xmm6
  movapd %xmm0,%xmm5
  mulsd  %xmm1,%xmm5
  mulsd  %xmm3,%xmm5
  mulsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  mulsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm2
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  addsd  0x8(%rsi),%xmm3
  movsd  %xmm3,0x8(%rsi)
  movsd  D9(%rip),%xmm7
  movapd %xmm5,%xmm3
  mulsd  %xmm7,%xmm3
  movapd %xmm3,%xmm8
  addsd  0x10(%rsi),%xmm8
  movsd  %xmm8,0x10(%rsi)
  movslq %edi,%rdx
  shl    $0x3,%rdx
  lea    (%rsi,%rdx,1),%rax
  movsd  (%rax),%xmm8
  subsd  %xmm0,%xmm8
  movsd  %xmm8,(%rax)
  lea    0x8(%rsi,%rdx,1),%rsi
  movapd %xmm1,%xmm8
  addsd  (%rsi),%xmm8
  movsd  %xmm8,(%rsi)
  lea    0x10(%rcx,%rdx,1),%rsi
  movapd %xmm6,%xmm8
  subsd  %xmm4,%xmm8
  addsd  (%rsi),%xmm8
  movsd  %xmm8,(%rsi)
  lea    (%rdi,%rdi,1),%esi
  movslq %esi,%r8
  add    %rdx,%rax
  movapd %xmm5,%xmm8
  addsd  (%rax),%xmm8
  movsd  %xmm8,(%rax)
  lea    0x8(%rcx,%r8,8),%r9
  movapd %xmm2,%xmm8
  subsd  %xmm6,%xmm8
  addsd  (%r9),%xmm8
  movsd  %xmm8,(%r9)
  lea    0x10(%rcx,%r8,8),%r8
  movsd  (%r8),%xmm6
  subsd  %xmm1,%xmm6
  movsd  %xmm6,(%r8)
  add    %rdx,%rax
  subsd  %xmm2,%xmm4
  addsd  (%rax),%xmm4
  movsd  %xmm4,(%rax)
  add    %edi,%esi
  movslq %esi,%rsi
  lea    0x8(,%rsi,8),%rsi
  lea    (%rcx,%rsi,1),%r8
  movsd  (%r8),%xmm2
  subsd  %xmm5,%xmm2
  movsd  %xmm2,(%r8)
  lea    0x8(%rcx,%rsi,1),%rsi
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rsi)
  add    %rdx,%rax
  mulsd  %xmm7,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  lea    0x0(,%rdi,4),%eax
  cltq
  lea    0x10(%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%rax)
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
void matrix_ij_H(int n, double *mat, double ex, double ey, double ez, double yh) {
  double h1;
  double h1xx, h1xy, h1xz, h1yy, h1yz, h1zz;
  double exx, eyy, ezz, exy, eyz, exz;
  h1 = yh;
  exx = ex * ex;
  eyy = ey * ey;
  ezz = ez * ez;
  exy = ex * ey;
  eyz = ey * ez;
  exz = ez * ex;
  h1xx = h1 * exx;
  h1xy = h1 * exy;
  h1xz = h1 * exz;
  h1yy = h1 * eyy;
  h1yz = h1 * eyz;
  h1zz = h1 * ezz;
  mat[0 * n + 1] += +2.0 * h1xz;
  mat[0 * n + 2] += -2.0 * h1xy;
  mat[1 * n + 0] += -h1xz;
  mat[1 * n + 1] += +h1yz;
  mat[1 * n + 2] += +h1xx - h1yy;
  mat[2 * n + 0] += +h1xy;
  mat[2 * n + 1] += -h1xx + h1zz;
  mat[2 * n + 2] += -h1yz;
  mat[3 * n + 0] += +h1yy - h1zz;
  mat[3 * n + 1] += -h1xy;
  mat[3 * n + 2] += +h1xz;
  mat[4 * n + 0] += -2.0 * h1yz;
  mat[4 * n + 2] += +2.0 * h1xy;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_ij_H>:
  endbr64
  movapd %xmm0,%xmm6
  movapd %xmm0,%xmm5
  movapd %xmm1,%xmm4
  movslq %edi,%rdx
  mulsd  %xmm0,%xmm6
  shl    $0x3,%rdx
  mov    %rsi,%rcx
  movsd  D2(%rip),%xmm7
  mulsd  %xmm2,%xmm0
  movsd  0x10(%rsi),%xmm8
  lea    (%rsi,%rdx,1),%rax
  mulsd  %xmm1,%xmm5
  mulsd  %xmm1,%xmm4
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm5
  mulsd  %xmm3,%xmm6
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm4
  movapd %xmm0,%xmm3
  addsd  %xmm0,%xmm3
  addsd  0x8(%rsi),%xmm3
  movsd  %xmm3,0x8(%rsi)
  movapd %xmm5,%xmm3
  mulsd  %xmm7,%xmm3
  addsd  %xmm3,%xmm8
  movsd  %xmm8,0x10(%rsi)
  movsd  (%rax),%xmm8
  lea    0x8(%rsi,%rdx,1),%rsi
  subsd  %xmm0,%xmm8
  movsd  %xmm8,(%rax)
  movsd  (%rsi),%xmm8
  add    %rdx,%rax
  addsd  %xmm1,%xmm8
  movsd  %xmm8,(%rsi)
  lea    0x10(%rcx,%rdx,1),%rsi
  movapd %xmm6,%xmm8
  subsd  %xmm4,%xmm8
  addsd  (%rsi),%xmm8
  subsd  %xmm2,%xmm4
  movsd  %xmm8,(%rsi)
  movsd  (%rax),%xmm8
  lea    (%rdi,%rdi,1),%esi
  movslq %esi,%r8
  add    %edi,%esi
  addsd  %xmm5,%xmm8
  lea    0x8(%rcx,%r8,8),%r9
  movslq %esi,%rsi
  lea    0x10(%rcx,%r8,8),%r8
  lea    0x8(,%rsi,8),%rsi
  movsd  %xmm8,(%rax)
  movapd %xmm2,%xmm8
  add    %rdx,%rax
  subsd  %xmm6,%xmm8
  addsd  (%r9),%xmm8
  movsd  %xmm8,(%r9)
  movsd  (%r8),%xmm6
  subsd  %xmm1,%xmm6
  mulsd  %xmm7,%xmm1
  movsd  %xmm6,(%r8)
  addsd  (%rax),%xmm4
  lea    (%rcx,%rsi,1),%r8
  lea    0x8(%rcx,%rsi,1),%rsi
  movsd  %xmm4,(%rax)
  movsd  (%r8),%xmm2
  add    %rdx,%rax
  subsd  %xmm5,%xmm2
  movsd  %xmm2,(%r8)
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rsi)
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  lea    0x0(,%rdi,4),%eax
  cltq
  lea    0x10(%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%rax)
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
void matrix_ij_H(int n, double *mat, double ex, double ey, double ez, double yh) {
  double h1;
  double h1xx, h1xy, h1xz, h1yy, h1yz, h1zz;
  double exx, eyy, ezz, exy, eyz, exz;
  h1 = yh;
  exx = ex * ex;
  eyy = ey * ey;
  ezz = ez * ez;
  exy = ex * ey;
  eyz = ey * ez;
  exz = ez * ex;
  h1xx = h1 * exx;
  h1xy = h1 * exy;
  h1xz = h1 * exz;
  h1yy = h1 * eyy;
  h1yz = h1 * eyz;
  h1zz = h1 * ezz;
  mat[0 * n + 1] += +2.0 * h1xz;
  mat[0 * n + 2] += -2.0 * h1xy;
  mat[1 * n + 0] += -h1xz;
  mat[1 * n + 1] += +h1yz;
  mat[1 * n + 2] += +h1xx - h1yy;
  mat[2 * n + 0] += +h1xy;
  mat[2 * n + 1] += -h1xx + h1zz;
  mat[2 * n + 2] += -h1yz;
  mat[3 * n + 0] += +h1yy - h1zz;
  mat[3 * n + 1] += -h1xy;
  mat[3 * n + 2] += +h1xz;
  mat[4 * n + 0] += -2.0 * h1yz;
  mat[4 * n + 2] += +2.0 * h1xy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix_ij_H>:
  endbr64
  movapd %xmm0,%xmm4
  movapd %xmm2,%xmm5
  movapd D8(%rip),%xmm6
  mov    %rsi,%rcx
  mulsd  %xmm0,%xmm0
  unpcklpd %xmm1,%xmm5
  unpcklpd %xmm4,%xmm4
  mulpd  %xmm5,%xmm4
  movapd %xmm3,%xmm5
  unpcklpd %xmm5,%xmm5
  mulpd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm5
  mulpd  %xmm4,%xmm6
  movapd %xmm4,%xmm7
  mulsd  %xmm3,%xmm0
  unpckhpd %xmm7,%xmm7
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm2
  movupd 0x8(%rsi),%xmm3
  addpd  %xmm6,%xmm3
  unpckhpd %xmm6,%xmm6
  movups %xmm3,0x8(%rsi)
  movslq %edi,%rsi
  shl    $0x3,%rsi
  lea    (%rcx,%rsi,1),%rax
  lea    0x8(%rcx,%rsi,1),%rdx
  movsd  (%rax),%xmm3
  subsd  %xmm4,%xmm3
  movsd  %xmm3,(%rax)
  movsd  (%rdx),%xmm3
  add    %rsi,%rax
  addsd  %xmm1,%xmm3
  movsd  %xmm3,(%rdx)
  lea    0x10(%rcx,%rsi,1),%rdx
  movapd %xmm5,%xmm3
  subsd  %xmm0,%xmm3
  addsd  (%rdx),%xmm3
  subsd  %xmm2,%xmm0
  movsd  %xmm3,(%rdx)
  movsd  (%rax),%xmm3
  lea    (%rdi,%rdi,1),%edx
  movslq %edx,%r8
  add    %edi,%edx
  addsd  %xmm7,%xmm3
  lea    0x8(%rcx,%r8,8),%r9
  movslq %edx,%rdx
  lea    0x10(%rcx,%r8,8),%r8
  lea    0x8(,%rdx,8),%rdx
  movsd  %xmm3,(%rax)
  movapd %xmm2,%xmm3
  add    %rsi,%rax
  subsd  %xmm5,%xmm3
  addsd  (%r9),%xmm3
  movsd  %xmm3,(%r9)
  movsd  (%r8),%xmm3
  subsd  %xmm1,%xmm3
  mulsd  D13(%rip),%xmm1
  movsd  %xmm3,(%r8)
  addsd  (%rax),%xmm0
  lea    (%rcx,%rdx,1),%r8
  lea    0x8(%rcx,%rdx,1),%rdx
  movsd  %xmm0,(%rax)
  movsd  (%r8),%xmm0
  add    %rsi,%rax
  subsd  %xmm7,%xmm0
  movsd  %xmm0,(%r8)
  addsd  (%rdx),%xmm4
  movsd  %xmm4,(%rdx)
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  lea    0x0(,%rdi,4),%eax
  cltq
  lea    0x10(%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  subsd  %xmm6,%xmm0
  movsd  %xmm0,(%rax)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: f64[2]
name: parse_data
arguments: data_tag: D13
type_guessed: byte[8]

tool: {"D8": [2.0,-2.0]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
void matrix_ij_H(int n, double *mat, double ex, double ey, double ez, double yh) {
  double h1;
  double h1xx, h1xy, h1xz, h1yy, h1yz, h1zz;
  double exx, eyy, ezz, exy, eyz, exz;
  h1 = yh;
  exx = ex * ex;
  eyy = ey * ey;
  ezz = ez * ez;
  exy = ex * ey;
  eyz = ey * ez;
  exz = ez * ex;
  h1xx = h1 * exx;
  h1xy = h1 * exy;
  h1xz = h1 * exz;
  h1yy = h1 * eyy;
  h1yz = h1 * eyz;
  h1zz = h1 * ezz;
  mat[0 * n + 1] += +2.0 * h1xz;
  mat[0 * n + 2] += -2.0 * h1xy;
  mat[1 * n + 0] += -h1xz;
  mat[1 * n + 1] += +h1yz;
  mat[1 * n + 2] += +h1xx - h1yy;
  mat[2 * n + 0] += +h1xy;
  mat[2 * n + 1] += -h1xx + h1zz;
  mat[2 * n + 2] += -h1yz;
  mat[3 * n + 0] += +h1yy - h1zz;
  mat[3 * n + 1] += -h1xy;
  mat[3 * n + 2] += +h1xz;
  mat[4 * n + 0] += -2.0 * h1yz;
  mat[4 * n + 2] += +2.0 * h1xy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<buddy_list_replace_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <buddy_list_replace@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <buddy_list_init@plt>
  nop
  leave
  ret
```

assistant: ```c
void buddy_list_replace_init(struct buddy_list *old, struct buddy_list *new) {
  buddy_list_replace(old, new);
  buddy_list_init(old);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<buddy_list_replace_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <buddy_list_replace@plt>
  mov    %rbx,%rdi
  call   <buddy_list_init@plt>
  pop    %rbx
  ret
```

assistant: ```c
void buddy_list_replace_init(struct buddy_list *old, struct buddy_list *new) {
  buddy_list_replace(old, new);
  buddy_list_init(old);
}
```
user: Translate the below assembly code into C programming language:

```asm
<buddy_list_replace_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <buddy_list_replace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <buddy_list_init@plt>
```

assistant: ```c
void buddy_list_replace_init(struct buddy_list *old, struct buddy_list *new) {
  buddy_list_replace(old, new);
  buddy_list_init(old);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buddy_list_replace_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <buddy_list_replace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <buddy_list_init@plt>
```

assistant: ```c
void buddy_list_replace_init(struct buddy_list *old, struct buddy_list *new) {
  buddy_list_replace(old, new);
  buddy_list_init(old);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<long_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_printf@plt>
  test   %rax,%rax
  jg     L16
  mov    $0x0,%eax
  jmp    L2
L16:
  mov    $0x1,%eax
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: %ld


assistant: ```c
int long_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  if (BIO_printf(out, "%ld\n", *(long *)pval) <= 0)
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<long_print>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdx
  lea    D2(%rip),%rsi
  call   <BIO_printf@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: %ld


assistant: ```c
int long_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  if (BIO_printf(out, "%ld\n", *(long *)pval) <= 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<long_print>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdx
  lea    D7(%rip),%rsi
  call   <BIO_printf@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %ld


assistant: ```c
int long_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  if (BIO_printf(out, "%ld\n", *(long *)pval) <= 0)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<long_print>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdx
  lea    D1(%rip),%rsi
  call   <BIO_printf@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %ld


assistant: ```c
int long_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  if (BIO_printf(out, "%ld\n", *(long *)pval) <= 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mymalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L27
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L11:
  mov    -0x8(%rbp),%rax
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: 
memory allocation failure in file: %s at line number: %d


assistant: ```c
void *_mymalloc(size_t size, int line, char *message) {
  char *temp;
  if (size == 0)
    return NULL;
  temp = (char *)malloc(size);
  if (temp == NULL) {
    printf("\nmemory allocation failure in file: %s at line number: %d\n", message, line);
    exit(-1);
  }
  return (void *)temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_mymalloc>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %rdx,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L17
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  jmp    L24
L6:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: 
memory allocation failure in file: %s at line number: %d


assistant: ```c
void *_mymalloc(size_t size, int line, char *message) {
  char *temp;
  if (size == 0)
    return NULL;
  temp = (char *)malloc(size);
  if (temp == NULL) {
    printf("\nmemory allocation failure in file: %s at line number: %d\n", message, line);
    exit(-1);
  }
  return (void *)temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_mymalloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L18
  mov    %esi,%r12d
  mov    %rdx,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%r13
L18:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L8:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 
memory allocation failure in file: %s at line number: %d


assistant: ```c
void *_mymalloc(size_t size, int line, char *message) {
  char *temp;
  if (size == 0)
    return NULL;
  temp = (char *)malloc(size);
  if (temp == NULL) {
    printf("\nmemory allocation failure in file: %s at line number: %d\n", message, line);
    exit(-1);
  }
  return (void *)temp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_mymalloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L11
  mov    %esi,%r12d
  mov    %rdx,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%r13
L11:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: 
memory allocation failure in file: %s at line number: %d


assistant: ```c
void *_mymalloc(size_t size, int line, char *message) {
  char *temp;
  if (size == 0)
    return NULL;
  temp = (char *)malloc(size);
  if (temp == NULL) {
    printf("\nmemory allocation failure in file: %s at line number: %d\n", message, line);
    exit(-1);
  }
  return (void *)temp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bpnn_randomize_weights>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L9:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    $0x0,%eax
  call   <dpn1@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L16
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L9
  nop
  leave
  ret
```

assistant: ```c
bpnn_randomize_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = dpn1();
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bpnn_randomize_weights>:
  endbr64
  test   %esi,%esi
  js     L28
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r14d
  mov    %edx,%r12d
  mov    %rdi,%rbp
  mov    $0x0,%r13d
  jmp    L3
L12:
  mov    $0x0,%eax
  call   <dpn1@plt>
  mov    0x0(%rbp),%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rdx,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L12
L32:
  add    $0x1,%r13d
  add    $0x8,%rbp
  cmp    %r13d,%r14d
  jl     L20
L3:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jns    L12
  jmp    L32
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  ret
```

assistant: ```c
bpnn_randomize_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = dpn1();
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bpnn_randomize_weights>:
  endbr64
  test   %esi,%esi
  js     L11
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  js     L31
  cs nopw 0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  call   <dpn1@plt>
  pxor   %xmm0,%xmm0
  mov    (%r14),%rdx
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rdx,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L38
L31:
  add    $0x1,%r12d
  add    $0x8,%r14
  cmp    %r12d,%r13d
  jge    L35
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  ret
```

assistant: ```c
bpnn_randomize_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = dpn1();
    }
  }
}
```