user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffff9e,-0x50(%rbp)
  movl   $0xffffff8a,-0x4c(%rbp)
  movl   $0xffffffa5,-0x48(%rbp)
  movl   $0xc,-0x44(%rbp)
  movl   $0xffffffcf,-0x40(%rbp)
  movl   $0x23,-0x3c(%rbp)
  movl   $0x1c,-0x38(%rbp)
  movl   $0x5f,-0x34(%rbp)
  movl   $0xc,-0x30(%rbp)
  movl   $0xfffffff8,-0x2c(%rbp)
  movl   $0xfffffff8,-0x28(%rbp)
  movl   $0x1e,-0x24(%rbp)
  movl   $0xffffffca,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0xffffffad,-0x18(%rbp)
  movl   $0xffffffd8,-0x14(%rbp)
  movl   $0x0,-0x70(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L82
L102:
  movl   $0x0,-0x64(%rbp)
  jmp    L116
L32:
  movl   $0x0,-0x70(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L111
L29:
  mov    -0x68(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x68(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x70(%rbp)
  addl   $0x1,-0x68(%rbp)
L111:
  cmpl   $0x3,-0x68(%rbp)
  jle    L29
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x70(%rbp),%eax
  mov    %eax,-0x60(%rbp,%rdx,4)
  addl   $0x1,-0x64(%rbp)
L116:
  cmpl   $0x1,-0x64(%rbp)
  jle    L32
  addl   $0x1,-0x6c(%rbp)
L82:
  cmpl   $0x1,-0x6c(%rbp)
  jle    L102
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L18
L53:
  movl   $0x0,-0x64(%rbp)
  jmp    L42
L88:
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L42:
  cmpl   $0x3,-0x64(%rbp)
  jle    L88
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x6c(%rbp)
L18:
  cmpl   $0x1,-0x6c(%rbp)
  jle    L53
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L59
L181:
  movl   $0x0,-0x64(%rbp)
  jmp    L49
L138:
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L49:
  cmpl   $0x1,-0x64(%rbp)
  jle    L138
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x6c(%rbp)
L59:
  cmpl   $0x3,-0x6c(%rbp)
  jle    L181
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L157
L77:
  movl   $0x0,-0x64(%rbp)
  jmp    L7
L103:
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L7:
  cmpl   $0x1,-0x64(%rbp)
  jle    L103
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x6c(%rbp)
L157:
  cmpl   $0x1,-0x6c(%rbp)
  jle    L77
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D48
data_type: string
name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D48: Calculando Matriz C:

tool: D9: MatrizA:

tool: D13: %d	

tool: D38: MatrizB:

tool: D8: MatrizC:

assistant: ```c
int main() {
  int matrizA[2][4] = {-98, -118, -91, 12, -49, 35, 28, 95};
  int matrizB[4][2] = {12, -8, -8, 30, -54, 7, -83, -40};
  int matrizC[2][2];
  int soma = 0;
  int linA, linB;
  int colB;
  printf("Calculando Matriz C:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++) {
      soma = 0;
      for (linB = 0; linB < 4; linB++)
        soma += matrizA[linA][linB] * matrizB[linB][colB];
      matrizC[linA][colB] = soma;
    }
  }
  printf("MatrizA:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 4; colB++)
      printf("%d\t", matrizA[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizB:\n");
  for (linA = 0; linA < 4; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizB[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizC:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizC[linA][colB]);
    printf("\n");
  }
  return 0;
}
```