ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  sub    $0x5,%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  sub    $0x5,%edi
  call   <triangle@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f(int x, int y) {
  return triangle(x % 10 - 5, y % 10 - 5);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %edi,%edx
  lea    (%rax,%rax,4),%eax
  sar    $0x1f,%edx
  add    %eax,%eax
  sub    %eax,%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sub    $0x5,%esi
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  sub    $0x5,%edi
  jmp    1050 <triangle@plt>
```

assistant: ```c
int f(int x, int y) {
  return triangle(x % 10 - 5, y % 10 - 5);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %edi,%edx
  lea    (%rax,%rax,4),%eax
  sar    $0x1f,%edx
  add    %eax,%eax
  sub    %eax,%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sub    $0x5,%esi
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  sub    $0x5,%edi
  jmp    1050 <triangle@plt>
```

assistant: ```c
int f(int x, int y) {
  return triangle(x % 10 - 5, y % 10 - 5);
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L12:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: 


assistant: ```c
int Space(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Space>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L2:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5: 


assistant: ```c
int Space(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Space>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L19
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: 


assistant: ```c
int Space(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Space>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L18
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: 


assistant: ```c
int Space(int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L12
L0:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strlwr(char *s) {
  int len, i;
  len = strlen(s);
  for (i = 0; i < len; i++)
    s[i] = tolower(s[i]);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlwr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%rbp
L5:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *s) {
  int len, i;
  len = strlen(s);
  for (i = 0; i < len; i++)
    s[i] = tolower(s[i]);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L19
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *s) {
  int len, i;
  len = strlen(s);
  for (i = 0; i < len; i++)
    s[i] = tolower(s[i]);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L5
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L12:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L12
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *s) {
  int len, i;
  len = strlen(s);
  for (i = 0; i < len; i++)
    s[i] = tolower(s[i]);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<L>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <eat@plt>
  mov    $0x0,%eax
  call   <I@plt>
  mov    $0x0,%eax
  call   <LP@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: L -> idIL'


assistant: ```c
void L() {
  printf("L -> idIL'\n");
  eat(6);
  I();
  LP();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<L>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <eat@plt>
  mov    $0x0,%eax
  call   <I@plt>
  mov    $0x0,%eax
  call   <LP@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: L -> idIL'


assistant: ```c
void L() {
  printf("L -> idIL'\n");
  eat(6);
  I();
  LP();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<L>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <I@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <LP@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: L -> idIL'


assistant: ```c
void L() {
  printf("L -> idIL'\n");
  eat(6);
  I();
  LP();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<L>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <I@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <LP@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: L -> idIL'


assistant: ```c
void L() {
  printf("L -> idIL'\n");
  eat(6);
  I();
  LP();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ut_write_to_stderr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ut_write_to_stderr(const char *const fmt, va_list args) {
  int nbytes = vfprintf(stderr, fmt, args);
  (void)fputc('\n', stderr);
  return nbytes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ut_write_to_stderr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    D5(%rip),%rbp
  mov    %rdi,%rsi
  mov    0x0(%rbp),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ut_write_to_stderr(const char *const fmt, va_list args) {
  int nbytes = vfprintf(stderr, fmt, args);
  (void)fputc('\n', stderr);
  return nbytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ut_write_to_stderr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %rdi,%rsi
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rbx
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  mov    %eax,%r12d
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int ut_write_to_stderr(const char *const fmt, va_list args) {
  int nbytes = vfprintf(stderr, fmt, args);
  (void)fputc('\n', stderr);
  return nbytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ut_write_to_stderr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %rdi,%rsi
  push   %rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rbx
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  mov    %eax,%r12d
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int ut_write_to_stderr(const char *const fmt, va_list args) {
  int nbytes = vfprintf(stderr, fmt, args);
  (void)fputc('\n', stderr);
  return nbytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <inverse@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D2
data_type: string

tool: D14: input string:

tool: D0: %s

tool: D2: inverse string:%s


assistant: ```c
int main() {
  void inverse(char str[]);
  char str[100];
  printf("input string:");
  scanf("%s", str);
  inverse(str);
  printf("inverse string:%s\n", str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <inverse@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D28
data_type: string
name: read_data
arguments: data_label: D11
data_type: string

tool: D0: input string:

tool: D28: %s

tool: D11: inverse string:%s


assistant: ```c
int main() {
  void inverse(char str[]);
  char str[100];
  printf("input string:");
  scanf("%s", str);
  inverse(str);
  printf("inverse string:%s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <inverse@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type: string
name: read_data
arguments: data_label: D26
type: string
name: read_data
arguments: data_label: D4
type: string

tool: D14: input string:

tool: D26: %s

tool: D4: inverse string:%s


assistant: ```c
int main() {
  void inverse(char str[]);
  char str[100];
  printf("input string:");
  scanf("%s", str);
  inverse(str);
  printf("inverse string:%s\n", str);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <inverse@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D2: input string:

tool: D21: %s

tool: D9: inverse string:%s


assistant: ```c
int main() {
  void inverse(char str[]);
  char str[100];
  printf("input string:");
  scanf("%s", str);
  inverse(str);
  printf("inverse string:%s\n", str);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strEquals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L8
  mov    $0x0,%eax
  jmp    L50
L8:
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L11:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L32
  mov    $0x0,%eax
  jmp    L50
L32:
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L11
  mov    $0x1,%eax
L50:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strEquals(char *a, char *b) {
  if (strlen(a) != strlen(b))
    return 0;
  int i;
  for (i = 0; i < strlen(a); i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strEquals>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%ebx
  jne    L38
  mov    $0x0,%ebx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L36
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    -0x1(%r12,%rbx,1),%al
  je     L7
  mov    $0x0,%eax
  jmp    L38
L36:
  mov    $0x1,%eax
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strEquals(char *a, char *b) {
  if (strlen(a) != strlen(b))
    return 0;
  int i;
  for (i = 0; i < strlen(a); i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strEquals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L1
  xor    %ebx,%ebx
  jmp    L7
  nopl   (%rax)
L26:
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    -0x1(%r12,%rbx,1),%al
  jne    L1
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L26
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strEquals(char *a, char *b) {
  if (strlen(a) != strlen(b))
    return 0;
  int i;
  for (i = 0; i < strlen(a); i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strEquals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L20
  xor    %ebx,%ebx
  jmp    L32
  nopl   (%rax)
L5:
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    -0x1(%r12,%rbx,1),%al
  jne    L20
L32:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L20:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strEquals(char *a, char *b) {
  if (strlen(a) != strlen(b))
    return 0;
  int i;
  for (i = 0; i < strlen(a); i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fix_any_quotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x1028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  mov    %rax,-0x1020(%rbp)
  mov    -0x1028(%rbp),%rax
  mov    %rax,-0x1018(%rbp)
  mov    -0x1028(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L23
L11:
  mov    -0x1020(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L52
  mov    -0x1020(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L52
  mov    -0x1028(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x1028(%rbp)
  movb   $0x27,(%rax)
  mov    -0x1020(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x1020(%rbp)
  mov    -0x1028(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x1028(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L23
L52:
  mov    -0x1020(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x1020(%rbp)
  mov    -0x1028(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x1028(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L23:
  mov    -0x1020(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x1028(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x1018(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *fix_any_quotes(char *d) {
  char tmp[4096 + 1];
  char *tmp_ptr = tmp;
  char *anchor = d;
  strcpy(tmp, d);
  while (*tmp_ptr) {
    if (*tmp_ptr == '\'' && *(tmp_ptr + 1) != '\'') {
      *d++ = '\'';
      *d++ = *tmp_ptr++;
    } else {
      *d++ = *tmp_ptr++;
    }
  }
  *d = '\0';
  return anchor;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fix_any_quotes>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L47
  lea    0x1(%rsp),%rdx
  mov    %rbx,%rcx
  jmp    L24
L30:
  mov    %rdx,%rsi
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rcx
L44:
  movzbl (%rsi),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L63
L24:
  cmp    $0x27,%al
  jne    L30
  mov    %rdx,%rsi
  cmpb   $0x27,(%rdx)
  je     L30
  movb   $0x27,(%rcx)
  movb   $0x27,0x1(%rcx)
  lea    0x2(%rcx),%rcx
  jmp    L44
L47:
  mov    %rbx,%rcx
L63:
  movb   $0x0,(%rcx)
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %rbx,%rax
  add    $0x1010,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *fix_any_quotes(char *d) {
  char tmp[4096 + 1];
  char *tmp_ptr = tmp;
  char *anchor = d;
  strcpy(tmp, d);
  while (*tmp_ptr) {
    if (*tmp_ptr == '\'' && *(tmp_ptr + 1) != '\'') {
      *d++ = '\'';
      *d++ = *tmp_ptr++;
    } else {
      *d++ = *tmp_ptr++;
    }
  }
  *d = '\0';
  return anchor;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fix_any_quotes>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%r12
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  movzbl (%rsp),%eax
  mov    %r12,%rcx
  test   %al,%al
  je     L33
  mov    %rbx,%rdx
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %al,(%rcx)
  movzbl (%rdx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L33
L54:
  add    $0x1,%rdx
  cmp    $0x27,%al
  jne    L0
  cmpb   $0x27,(%rdx)
  je     L0
  mov    $0x2727,%eax
  add    $0x2,%rcx
  mov    %ax,-0x2(%rcx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L54
  xchg   %ax,%ax
L33:
  movb   $0x0,(%rcx)
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x1018,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *fix_any_quotes(char *d) {
  char tmp[4096 + 1];
  char *tmp_ptr = tmp;
  char *anchor = d;
  strcpy(tmp, d);
  while (*tmp_ptr) {
    if (*tmp_ptr == '\'' && *(tmp_ptr + 1) != '\'') {
      *d++ = '\'';
      *d++ = *tmp_ptr++;
    } else {
      *d++ = *tmp_ptr++;
    }
  }
  *d = '\0';
  return anchor;
}
```