ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtolh>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%edx
  test   %dl,%dl
  je     L19
  sub    $0x4b,%edx
  cmp    $0x22,%dl
  ja     L19
  lea    D1(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  shl    $0x14,%rax
  nopl   0x0(%rax)
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x18,%rsp
  ret
  nopl   (%rax)
  imul   $0xf4240,%rax,%rax
  jmp    L19
  nopl   0x0(%rax)
  imul   $0x3e8,%rax,%rax
  jmp    L19
  nopl   0x0(%rax)
  imul   $0x3b9aca00,%rax,%rax
  jmp    L19
  nopl   0x0(%rax)
  shl    $0xa,%rax
  jmp    L19
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long strtolh(const char *nptr, int base) {
  char *end;
  long result = strtol(nptr, &end, base);
  if (*end) {
    if (*end == 'k')
      result *= 1000;
    else if (*end == 'm')
      result *= 1000000;
    else if (*end == 'g')
      result *= 1000000000;
    else if (*end == 'K')
      result *= 0x400;
    else if (*end == 'M')
      result *= 0x100000;
    else if (*end == 'g')
      result *= 0x40000000;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<one_beat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rax,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <pselect@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void one_beat() {
  struct timespec ts = {.tv_sec = 0, .tv_nsec = 100};
  pselect(0, NULL, NULL, NULL, &ts, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<one_beat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x64,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    $0x0,%r9d
  mov    %rsp,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <pselect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void one_beat() {
  struct timespec ts = {.tv_sec = 0, .tv_nsec = 100};
  pselect(0, NULL, NULL, NULL, &ts, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<one_beat>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %rsp,%r8
  movq   $0x64,(%rsp)
  call   <pselect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void one_beat() {
  struct timespec ts = {.tv_sec = 0, .tv_nsec = 100};
  pselect(0, NULL, NULL, NULL, &ts, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<one_beat>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %rsp,%r8
  mov    %rax,(%rsp)
  call   <pselect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: byte[8]

tool: {"D4": [0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void one_beat() {
  struct timespec ts = {.tv_sec = 0, .tv_nsec = 100};
  pselect(0, NULL, NULL, NULL, &ts, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
L23:
  addq   $0x1,-0x10(%rbp)
L54:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L23
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L23
  jmp    L24
L93:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L24:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L93
  nop
L77:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  cmp    %rax,-0x18(%rbp)
  je     L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L77
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L77
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L77
L21:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *trim_blanks(char *s) {
  char *t = s, *u = s;
  while ((*t) && ((*t == ' ') || (*t == '\t')))
    t++;
  while (*t)
    *(u++) = *(t++);
  while ((u-- != s) && ((*u == ' ') || (*u == '\t') || (*u == '\n')))
    ;
  *(++u) = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim_blanks>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  test   %dl,%dl
  jne    L8
L28:
  lea    -0x1(%rax),%r8
  jmp    L19
L98:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L28
L8:
  cmp    $0x20,%dl
  je     L98
  cmp    $0x9,%dl
  je     L98
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L28
  mov    %rax,%rsi
L45:
  add    $0x1,%rcx
  mov    %rsi,%rdx
  add    $0x1,%rsi
  mov    %r8b,-0x1(%rsi)
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  jne    L45
  lea    -0x1(%rax),%r9
L47:
  mov    %rdx,%r8
  cmp    %r9,%rdx
  je     L19
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L47
  cmp    $0x20,%cl
  je     L47
L19:
  movb   $0x0,0x1(%r8)
  ret
```

assistant: ```c
char *trim_blanks(char *s) {
  char *t = s, *u = s;
  while ((*t) && ((*t == ' ') || (*t == '\t')))
    t++;
  while (*t)
    *(u++) = *(t++);
  while ((u-- != s) && ((*u == ' ') || (*u == '\t') || (*u == '\n')))
    ;
  *(++u) = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_blanks>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %dl,%dl
  jne    L63
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L46
L63:
  cmp    $0x20,%dl
  je     L2
  cmp    $0x9,%dl
  je     L2
  movzbl (%rcx),%esi
  test   %sil,%sil
  je     L46
  mov    %rax,%rdx
  nopl   0x0(%rax)
L82:
  add    $0x1,%rcx
  mov    %sil,(%rdx)
  add    $0x1,%rdx
  movzbl (%rcx),%esi
  test   %sil,%sil
  jne    L82
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %rdx,%rdi
  cmp    %rdx,%rax
  je     L12
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L84
  cmp    $0x20,%cl
  je     L84
L12:
  movb   $0x0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %rax,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
char *trim_blanks(char *s) {
  char *t = s, *u = s;
  while ((*t) && ((*t == ' ') || (*t == '\t')))
    t++;
  while (*t)
    *(u++) = *(t++);
  while ((u-- != s) && ((*u == ' ') || (*u == '\t') || (*u == '\n')))
    ;
  *(++u) = '\0';
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim_blanks>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  mov    %rdi,%rsi
  test   %cl,%cl
  jne    L70
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl 0x1(%rsi),%ecx
  add    $0x1,%rsi
  test   %cl,%cl
  je     L27
L70:
  cmp    $0x20,%cl
  je     L37
  cmp    $0x9,%cl
  je     L37
  mov    %rax,%rdx
  nopl   0x0(%rax)
L25:
  add    $0x1,%rsi
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L25
  nopl   0x0(%rax)
L36:
  mov    %rdx,%rdi
  cmp    %rdx,%rax
  je     L65
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L36
  cmp    $0x20,%cl
  je     L36
  movb   $0x0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rax,%rdi
L65:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
char *trim_blanks(char *s) {
  char *t = s, *u = s;
  while ((*t) && ((*t == ' ') || (*t == '\t')))
    t++;
  while (*t)
    *(u++) = *(t++);
  while ((u-- != s) && ((*u == ' ') || (*u == '\t') || (*u == '\n')))
    ;
  *(++u) = '\0';
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigterm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <ti@plt>
  mov    %rax,%rdi
  call   <putp@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: cnorm

assistant: ```c
void sigterm(int s) {
  putp((char *)ti("cnorm"));
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sigterm>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <ti@plt>
  mov    %rax,%rdi
  call   <putp@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: cnorm

assistant: ```c
void sigterm(int s) {
  putp((char *)ti("cnorm"));
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sigterm>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <ti@plt>
  mov    %rax,%rdi
  call   <putp@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: cnorm

assistant: ```c
void sigterm(int s) {
  putp((char *)ti("cnorm"));
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<sigterm>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <ti@plt>
  mov    %rax,%rdi
  call   <putp@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: cnorm

assistant: ```c
void sigterm(int s) {
  putp((char *)ti("cnorm"));
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<crearmsgq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getkey@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  or     $0x1b0,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <msgget@plt>
  leave
  ret
```

assistant: ```c
int crearmsgq(int id) {
  key_t clave;
  clave = getkey(id);
  return (msgget(clave, IPC_CREAT | IPC_EXCL | 0660));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crearmsgq>:
  endbr64
  sub    $0x8,%rsp
  call   <getkey@plt>
  mov    %eax,%edi
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    D13(%rip),%rax
  or     (%rax),%esi
  or     $0x1b0,%esi
  call   <msgget@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int crearmsgq(int id) {
  key_t clave;
  clave = getkey(id);
  return (msgget(clave, IPC_CREAT | IPC_EXCL | 0660));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crearmsgq>:
  endbr64
  sub    $0x8,%rsp
  call   <getkey@plt>
  mov    %eax,%edi
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  or     (%rax),%esi
  add    $0x8,%rsp
  or     $0x1b0,%esi
  jmp    1060 <msgget@plt>
```

assistant: ```c
int crearmsgq(int id) {
  key_t clave;
  clave = getkey(id);
  return (msgget(clave, IPC_CREAT | IPC_EXCL | 0660));
}
```
user: Translate the below assembly code into C programming language:

```asm
<crearmsgq>:
  endbr64
  sub    $0x8,%rsp
  call   <getkey@plt>
  mov    %eax,%edi
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  or     (%rax),%esi
  add    $0x8,%rsp
  or     $0x1b0,%esi
  jmp    1060 <msgget@plt>
```

assistant: ```c
int crearmsgq(int id) {
  key_t clave;
  clave = getkey(id);
  return (msgget(clave, IPC_CREAT | IPC_EXCL | 0660));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ismimespecial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x28,-0x4(%rbp)
  je     L3
  cmpb   $0x29,-0x4(%rbp)
  je     L3
  cmpb   $0x3c,-0x4(%rbp)
  je     L3
  cmpb   $0x3e,-0x4(%rbp)
  je     L3
  cmpb   $0x40,-0x4(%rbp)
  je     L3
  cmpb   $0x2c,-0x4(%rbp)
  je     L3
  cmpb   $0x3b,-0x4(%rbp)
  je     L3
  cmpb   $0x3a,-0x4(%rbp)
  je     L3
  cmpb   $0x5c,-0x4(%rbp)
  je     L3
  cmpb   $0x22,-0x4(%rbp)
  je     L3
  cmpb   $0x5b,-0x4(%rbp)
  je     L3
  cmpb   $0x5d,-0x4(%rbp)
  je     L3
  cmpb   $0x3f,-0x4(%rbp)
  je     L3
  cmpb   $0x3d,-0x4(%rbp)
  jne    L53
L3:
  mov    $0x1,%eax
  jmp    L103
L53:
  mov    $0x0,%eax
L103:
  pop    %rbp
  ret
```

assistant: ```c
int ismimespecial(char c) {
  if (c == '(' || c == ')' || c == '<' || c == '>' || c == '@' || c == ',' || c == ';' || c == ':' || c == '\\' || c == '"' || c == '[' || c == ']' || c == '?' || c == '=')
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ismimespecial>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3b,%cl
  ja     L7
  movabs $0xe0000007f0004c1,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ismimespecial(char c) {
  if (c == '(' || c == ')' || c == '<' || c == '>' || c == '@' || c == ',' || c == ';' || c == ':' || c == '\\' || c == '"' || c == '[' || c == ']' || c == '?' || c == '=')
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ismimespecial>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3b,%cl
  ja     L1
  movabs $0xe0000007f0004c1,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ismimespecial(char c) {
  if (c == '(' || c == ')' || c == '<' || c == '>' || c == '@' || c == ',' || c == ';' || c == ':' || c == '\\' || c == '"' || c == '[' || c == ']' || c == '?' || c == '=')
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ismimespecial>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3b,%cl
  ja     L5
  movabs $0xe0000007f0004c1,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ismimespecial(char c) {
  if (c == '(' || c == ')' || c == '<' || c == '>' || c == '@' || c == ',' || c == ';' || c == ':' || c == '\\' || c == '"' || c == '[' || c == ']' || c == '?' || c == '=')
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<SL11Write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  mov    $0xffffffffb00c0000,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0xffffffffb00c0008,%rdx
  movzbl -0x8(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SL11Write(unsigned char address, unsigned char data) {
  if (address > 0xff) {
    xprintf("Invalid register access, register %x\n");
  }
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000))) = (address);
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000 + 8))) = (data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SL11Write>:
  endbr64
  mov    %dil,0xffffffffb00c0000
  mov    %sil,0xffffffffb00c0008
  ret
```

assistant: ```c
void SL11Write(unsigned char address, unsigned char data) {
  if (address > 0xff) {
    xprintf("Invalid register access, register %x\n");
  }
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000))) = (address);
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000 + 8))) = (data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SL11Write>:
  endbr64
  mov    %dil,0xffffffffb00c0000
  mov    %sil,0xffffffffb00c0008
  ret
```

assistant: ```c
void SL11Write(unsigned char address, unsigned char data) {
  if (address > 0xff) {
    xprintf("Invalid register access, register %x\n");
  }
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000))) = (address);
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000 + 8))) = (data);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SL11Write>:
  endbr64
  mov    %dil,0xffffffffb00c0000
  mov    %sil,0xffffffffb00c0008
  ret
```

assistant: ```c
void SL11Write(unsigned char address, unsigned char data) {
  if (address > 0xff) {
    xprintf("Invalid register access, register %x\n");
  }
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000))) = (address);
  *((volatile unsigned char *)(((long unsigned int)(int)0xa0000000) | (0x100C0000 + 8))) = (data);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D83(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%r8
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L48
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L28
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L49
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jb     L70
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L48:
  lea    D70(%rip),%rdi
  call   <printf@plt>
L71:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L28:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L49:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L70:
  lea    D89(%rip),%rdi
  call   <printf@plt>
  jmp    L71
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D83
data_type: string
name: parse_data
arguments: tag: D37
data_type: string
name: parse_data
arguments: tag: D57
data_type: string
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D84
data_type: string
name: parse_data
arguments: tag: D70
data_type: string
name: parse_data
arguments: tag: D42
data_type: string
name: parse_data
arguments: tag: D39
data_type: string
name: parse_data
arguments: tag: D89
data_type: string

tool: D83: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D37: %f%f%f%f

tool: D57: Thank you. Now enter student score (percent) >

tool: D26: %lf

tool: D84: Student has a D grade


tool: D70: Student has a A grade


tool: D42: Student has a B grade


tool: D39: Student has a C grade


tool: D89: Student has failed the course


assistant: ```c
int main(void) {
  float a, b, c, d;
  double score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &score);
  if (score >= a)
    printf("Student has a A grade\n");
  else if (score >= b)
    printf("Student has a B grade\n");
  else if (score >= c)
    printf("Student has a C grade\n");
  else if (score >= d)
    printf("Student has a D grade\n");
  else
    printf("Student has failed the course\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    0xc(%rsp),%r8
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L61
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L56
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jae    L86
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  comisd %xmm1,%xmm0
  jb     L77
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L56:
  lea    D86(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L61:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L77:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L86:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D42
datatype: string
name: unpack_data
arguments: tag: D87
datatype: string
name: unpack_data
arguments: tag: D46
datatype: string
name: unpack_data
arguments: tag: D69
datatype: string
name: unpack_data
arguments: tag: D86
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D11: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D42: %f%f%f%f

tool: D87: Thank you. Now enter student score (percent) >

tool: D46: %lf

tool: D69: Student has a D grade


tool: D86: Student has a B grade


tool: D7: Student has a A grade


tool: D33: Student has failed the course


tool: D12: Student has a C grade


assistant: ```c
int main(void) {
  float a, b, c, d;
  double score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &score);
  if (score >= a)
    printf("Student has a A grade\n");
  else if (score >= b)
    printf("Student has a B grade\n");
  else if (score >= c)
    printf("Student has a C grade\n");
  else if (score >= d)
    printf("Student has a D grade\n");
  else
    printf("Student has failed the course\n");
  return (0);
}
```