ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hpack_decode_int>:
  endbr64
  push   %r14
  lea    -0x1(%rdi),%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    $0x7,%eax
  push   %rbx
  mov    (%rdx),%rbx
  setbe  %dil
  mov    (%rsi),%r14
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %ebp,%ecx
  mov    $0x1,%edx
  mov    (%r14),%eax
  shl    %cl,%edx
  lea    0x4(%r14),%rdi
  lea    -0x2(%rbx),%rsi
  xor    %ecx,%ecx
  sub    $0x1,%edx
  and    %edx,%eax
  cmp    %eax,%edx
  je     L28
  lea    -0x1(%rbx),%rsi
L27:
  mov    %rdi,0x0(%r13)
  mov    %rsi,(%r12)
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L28:
  cmp    $0xffffffffffffffff,%rsi
  je     L51
L3:
  cmp    $0x1c,%ecx
  je     L46
  mov    (%rdi),%r8d
  add    $0x4,%rdi
  mov    %r8d,%edx
  and    $0x7f,%edx
  shl    %cl,%edx
  add    $0x7,%ecx
  add    %edx,%eax
  and    $0x80,%r8d
  lea    -0x1(%rsi),%rdx
  je     L27
  mov    %rdx,%rsi
  cmp    $0xffffffffffffffff,%rsi
  jne    L3
L51:
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L14
  xchg   %ax,%ax
L46:
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int_fast32_t hpack_decode_int(unsigned n, const uint8_t **restrict datap, size_t *restrict lengthp) {
  const uint8_t *p = *datap;
  size_t length = *lengthp;
  assert(n >= 1 && n <= 8);
  assert(length >= 1);
  unsigned mask = (1 << n) - 1;
  uint_fast32_t i = *(p++) & mask;
  length--;
  if (i == mask) {
    unsigned shift = 0;
    uint8_t b;
    do {
      if (length-- < 1) {
        errno = EINVAL;
        return -1;
      }
      if (shift >= 28) {
        errno = ERANGE;
        return -1;
      }
      b = *(p++);
      i += (b & 0x7F) << shift;
      shift += 7;
    } while (b & 0x80);
  }
  *datap = p;
  *lengthp = length;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hpack_decode_int>:
  endbr64
  push   %r14
  lea    -0x1(%rdi),%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    $0x7,%eax
  push   %rbx
  mov    (%rdx),%r14
  setbe  %dil
  mov    (%rsi),%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  mov    %ebp,%ecx
  mov    $0x1,%edx
  mov    (%rbx),%eax
  shl    %cl,%edx
  lea    0x4(%rbx),%rsi
  lea    -0x1(%r14),%rcx
  sub    $0x1,%edx
  and    %edx,%eax
  cmp    %eax,%edx
  je     L85
L23:
  mov    %rsi,0x0(%r13)
  mov    %rcx,(%r12)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L85:
  lea    -0x2(%r14),%rdi
  test   %rcx,%rcx
  je     L28
  mov    0x4(%rbx),%ecx
  lea    0x8(%rbx),%rsi
  mov    %ecx,%eax
  and    $0x7f,%eax
  add    %edx,%eax
  and    $0x80,%ecx
  je     L64
  lea    -0x3(%r14),%rcx
  test   %rdi,%rdi
  je     L28
  mov    0x8(%rbx),%edi
  lea    0xc(%rbx),%rsi
  mov    %edi,%edx
  shl    $0x7,%edx
  and    $0x3f80,%edx
  add    %edx,%eax
  and    $0x80,%edi
  je     L23
  lea    -0x4(%r14),%rdi
  test   %rcx,%rcx
  je     L28
  mov    0xc(%rbx),%ecx
  lea    0x10(%rbx),%rsi
  mov    %ecx,%edx
  shl    $0xe,%edx
  and    $0x1fc000,%edx
  add    %edx,%eax
  and    $0x80,%ecx
  je     L64
  lea    -0x5(%r14),%rcx
  test   %rdi,%rdi
  je     L28
  mov    0x10(%rbx),%edi
  lea    0x14(%rbx),%rsi
  mov    %edi,%edx
  shl    $0x15,%edx
  and    $0xfe00000,%edx
  add    %edx,%eax
  and    $0x80,%edi
  je     L23
  test   %rcx,%rcx
  je     L28
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L19
  nopl   0x0(%rax)
L64:
  mov    %rdi,%rcx
  jmp    L23
```

assistant: ```c
int_fast32_t hpack_decode_int(unsigned n, const uint8_t **restrict datap, size_t *restrict lengthp) {
  const uint8_t *p = *datap;
  size_t length = *lengthp;
  assert(n >= 1 && n <= 8);
  assert(length >= 1);
  unsigned mask = (1 << n) - 1;
  uint_fast32_t i = *(p++) & mask;
  length--;
  if (i == mask) {
    unsigned shift = 0;
    uint8_t b;
    do {
      if (length-- < 1) {
        errno = EINVAL;
        return -1;
      }
      if (shift >= 28) {
        errno = ERANGE;
        return -1;
      }
      b = *(p++);
      i += (b & 0x7F) << shift;
      shift += 7;
    } while (b & 0x80);
  }
  *datap = p;
  *lengthp = length;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L30:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x60,-0xd(%rbp)
  jle    L39
  cmpb   $0x7a,-0xd(%rbp)
  jle    L38
L39:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sub    $0x7a,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x60,%eax
  mov    %al,-0xd(%rbp)
L38:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L30
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: %c

assistant: ```c
void shift(char a[], int n, int count) {
  int i, l, p;
  char c;
  l = n % 26;
  for (i = 0; i < count; i++) {
    c = a[i] + l;
    if ((c < 'a') || (c > 'z')) {
      p = a[i] + l - 'z';
      c = 'a' + p - 1;
    }
    printf("%c", c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shift>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %esi,%rbx
  imul   $0x4ec4ec4f,%rbx,%rbx
  sar    $0x23,%rbx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  imul   $0x1a,%ebx,%eax
  mov    %esi,%ebx
  sub    %eax,%ebx
  test   %edx,%edx
  jle    L18
  mov    %rdi,%rbp
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%r13
  lea    D2(%rip),%r12
L17:
  movzbl 0x0(%rbp),%eax
  lea    (%rax,%rbx,1),%esi
  sub    $0x61,%esi
  lea    -0x1a(%rax,%rbx,1),%edx
  add    %ebx,%eax
  cmp    $0x1a,%sil
  cmovb  %eax,%edx
  movsbl %dl,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L17
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: %c

assistant: ```c
void shift(char a[], int n, int count) {
  int i, l, p;
  char c;
  l = n % 26;
  for (i = 0; i < count; i++) {
    c = a[i] + l;
    if ((c < 'a') || (c > 'z')) {
      p = a[i] + l - 'z';
      c = 'a' + p - 1;
    }
    printf("%c", c);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  push   %r14
  mov    %esi,%eax
  push   %r13
  sar    $0x1f,%eax
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  imul   $0x4ec4ec4f,%rbx,%rbx
  sar    $0x23,%rbx
  sub    %eax,%ebx
  imul   $0x1a,%ebx,%eax
  mov    %esi,%ebx
  sub    %eax,%ebx
  test   %edx,%edx
  jle    L0
  lea    -0x1(%rdx),%eax
  mov    %ebx,%r14d
  lea    D0(%rip),%rbp
  mov    %rdi,%r13
  lea    0x1(%rdi,%rax,1),%r12
  nopl   0x0(%rax)
L19:
  movzbl 0x0(%r13),%eax
  mov    %rbp,%rdi
  lea    (%rax,%r14,1),%esi
  lea    -0x1a(%rax,%rbx,1),%edx
  add    %r14d,%eax
  sub    $0x61,%esi
  cmp    $0x1a,%sil
  cmovb  %eax,%edx
  add    $0x1,%r13
  movsbl %dl,%esi
  call   <printf@plt>
  cmp    %r13,%r12
  jne    L19
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: %c

assistant: ```c
void shift(char a[], int n, int count) {
  int i, l, p;
  char c;
  l = n % 26;
  for (i = 0; i < count; i++) {
    c = a[i] + l;
    if ((c < 'a') || (c > 'z')) {
      p = a[i] + l - 'z';
      c = 'a' + p - 1;
    }
    printf("%c", c);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift>:
  endbr64
  push   %r14
  mov    %esi,%eax
  push   %r13
  sar    $0x1f,%eax
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  imul   $0x4ec4ec4f,%rbp,%rbp
  push   %rbx
  sar    $0x23,%rbp
  sub    %eax,%ebp
  imul   $0x1a,%ebp,%eax
  sub    %eax,%esi
  test   %edx,%edx
  jle    L2
  lea    -0x1(%rdx),%eax
  mov    %esi,%ebp
  mov    %esi,%r14d
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rax,1),%r13
  lea    D8(%rip),%r12
  nopl   0x0(%rax)
L11:
  movzbl (%rbx),%eax
  lea    (%rax,%r14,1),%esi
  lea    -0x61(%rsi),%edx
  cmp    $0x19,%dl
  jbe    L3
  lea    -0x1a(%rax,%rbp,1),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  movsbl %sil,%esi
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L11
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  movzbl %sil,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: %c

assistant: ```c
void shift(char a[], int n, int count) {
  int i, l, p;
  char c;
  l = n % 26;
  for (i = 0; i < count; i++) {
    c = a[i] + l;
    if ((c < 'a') || (c > 'z')) {
      p = a[i] + l - 'z';
      c = 'a' + p - 1;
    }
    printf("%c", c);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_random_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movq   $0x3fe,-0x28(%rbp)
  movl   $0x1,-0x34(%rbp)
L35:
  mov    $0x0,%eax
  call   <random@plt>
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <random@plt>
  or     %ebx,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L20
  subq   $0x1f,-0x28(%rbp)
  jmp    L35
L20:
  nop
  jmp    L29
L30:
  shll   -0x34(%rbp)
  subq   $0x1,-0x28(%rbp)
L29:
  mov    -0x34(%rbp),%eax
  cltq
  and    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L30
  mov    -0x20(%rbp),%rax
  sar    $0xb,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x34,%rax
  or     -0x18(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double my_random_double() {
  long x;
  long mant;
  long exp = 1022;
  int mask = 1;
  union {
    double d;
    long l;
  } b;
  while (1) {
    x = random() << 32 | random();
    if (x == 0) {
      exp -= 31;
    } else {
      break;
    }
  }
  while (x & mask) {
    mask <<= 1;
    exp--;
  }
  mant = x >> 11;
  b.l = (exp << 52) | mant;
  return b.d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_random_double>:
  endbr64
  push   %rbx
  mov    $0x3fe,%ebx
  jmp    L12
L23:
  sub    $0x1f,%rbx
L12:
  mov    $0x0,%eax
  call   <random@plt>
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rcx
  test   %rcx,%rcx
  je     L23
  mov    %eax,%edx
  and    $0x1,%edx
  je     L29
L22:
  add    %edx,%edx
  sub    $0x1,%rbx
  test   %edx,%eax
  jne    L22
L29:
  shl    $0x34,%rbx
  sar    $0xb,%rcx
  or     %rcx,%rbx
  movq   %rbx,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double my_random_double() {
  long x;
  long mant;
  long exp = 1022;
  int mask = 1;
  union {
    double d;
    long l;
  } b;
  while (1) {
    x = random() << 32 | random();
    if (x == 0) {
      exp -= 31;
    } else {
      break;
    }
  }
  while (x & mask) {
    mask <<= 1;
    exp--;
  }
  mant = x >> 11;
  b.l = (exp << 52) | mant;
  return b.d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_random_double>:
  endbr64
  push   %rbx
  mov    $0x3fe,%ebx
  jmp    L26
  nopl   0x0(%rax)
L8:
  sub    $0x1f,%rbx
L26:
  xor    %eax,%eax
  call   <random@plt>
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rcx
  test   %rcx,%rcx
  je     L8
  mov    %eax,%edx
  and    $0x1,%edx
  je     L5
  nopl   0x0(%rax)
L38:
  add    %edx,%edx
  sub    $0x1,%rbx
  test   %edx,%eax
  jne    L38
L5:
  shl    $0x34,%rbx
  sar    $0xb,%rcx
  or     %rcx,%rbx
  movq   %rbx,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double my_random_double() {
  long x;
  long mant;
  long exp = 1022;
  int mask = 1;
  union {
    double d;
    long l;
  } b;
  while (1) {
    x = random() << 32 | random();
    if (x == 0) {
      exp -= 31;
    } else {
      break;
    }
  }
  while (x & mask) {
    mask <<= 1;
    exp--;
  }
  mant = x >> 11;
  b.l = (exp << 52) | mant;
  return b.d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_random_double>:
  endbr64
  push   %rbx
  mov    $0x3fe,%ebx
  jmp    L14
  nopl   0x0(%rax)
L16:
  sub    $0x1f,%rbx
L14:
  xor    %eax,%eax
  call   <random@plt>
  xor    %eax,%eax
  call   <random@plt>
  movslq %eax,%rcx
  test   %rcx,%rcx
  je     L16
  mov    %eax,%edx
  and    $0x1,%edx
  je     L5
  nopl   0x0(%rax)
L22:
  add    %edx,%edx
  sub    $0x1,%rbx
  test   %edx,%eax
  jne    L22
L5:
  shl    $0x34,%rbx
  sar    $0xb,%rcx
  or     %rcx,%rbx
  movq   %rbx,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double my_random_double() {
  long x;
  long mant;
  long exp = 1022;
  int mask = 1;
  union {
    double d;
    long l;
  } b;
  while (1) {
    x = random() << 32 | random();
    if (x == 0) {
      exp -= 31;
    } else {
      break;
    }
  }
  while (x & mask) {
    mask <<= 1;
    exp--;
  }
  mant = x >> 11;
  b.l = (exp << 52) | mant;
  return b.d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%esi
  mov    %r9d,%ecx
  mov    0x10(%rbp),%edx
  mov    %al,-0x10(%rbp)
  mov    %esi,%eax
  mov    %al,-0x14(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x18(%rbp)
  mov    %edx,%eax
  mov    %al,-0x1c(%rbp)
  cmpb   $0x1,-0x1c(%rbp)
  jne    L21
  movzbl -0x10(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  jne    L21
  movzbl -0x14(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  jne    L21
  movzbl -0x18(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  je     L27
L21:
  call   <abort@plt>
L27:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int f(int a, int b, int c, _Bool d, _Bool e, _Bool f, char g) {
  if (g != 1 || d != 1 || e != 1 || f != 1)
    abort();
  return a + b + c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x1,0x10(%rsp)
  jne    L10
  mov    %edi,%eax
  cmp    $0x1,%cl
  jne    L10
  test   %r8b,%r8b
  je     L10
  test   %r9b,%r9b
  je     L10
  add    %esi,%eax
  add    %edx,%eax
  add    $0x8,%rsp
  ret
L10:
  call   <abort@plt>
```

assistant: ```c
int f(int a, int b, int c, _Bool d, _Bool e, _Bool f, char g) {
  if (g != 1 || d != 1 || e != 1 || f != 1)
    abort();
  return a + b + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x1,0x10(%rsp)
  jne    1060 <f.cold>
  cmp    $0x1,%cl
  jne    1060 <f.cold>
  test   %r8b,%r8b
  je     1060 <f.cold>
  test   %r9b,%r9b
  je     1060 <f.cold>
  mov    %edi,%eax
  add    $0x8,%rsp
  add    %esi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c, _Bool d, _Bool e, _Bool f, char g) {
  if (g != 1 || d != 1 || e != 1 || f != 1)
    abort();
  return a + b + c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x1,0x10(%rsp)
  jne    1060 <f.cold>
  cmp    $0x1,%cl
  jne    1060 <f.cold>
  test   %r8b,%r8b
  je     1060 <f.cold>
  test   %r9b,%r9b
  je     1060 <f.cold>
  mov    %edi,%eax
  add    $0x8,%rsp
  add    %esi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int f(int a, int b, int c, _Bool d, _Bool e, _Bool f, char g) {
  if (g != 1 || d != 1 || e != 1 || f != 1)
    abort();
  return a + b + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<satisfyCapacity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jg     L39
  mov    $0x1,%eax
  jmp    L3
L39:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int satisfyCapacity(int capacity[], int lenArr, int numPeople) {
  int index;
  for (index = 0; index < lenArr; index++)
    if (capacity[index] >= numPeople)
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<satisfyCapacity>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L23:
  cmp    %edx,(%rax)
  jge    L24
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
  mov    $0x0,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int satisfyCapacity(int capacity[], int lenArr, int numPeople) {
  int index;
  for (index = 0; index < lenArr; index++)
    if (capacity[index] >= numPeople)
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<satisfyCapacity>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L21
L17:
  cmp    %edx,(%rdi)
  jl     L26
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int satisfyCapacity(int capacity[], int lenArr, int numPeople) {
  int index;
  for (index = 0; index < lenArr; index++)
    if (capacity[index] >= numPeople)
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<satisfyCapacity>:
  endbr64
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L23
L14:
  cmp    %edx,(%rdi)
  jl     L37
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int satisfyCapacity(int capacity[], int lenArr, int numPeople) {
  int index;
  for (index = 0; index < lenArr; index++)
    if (capacity[index] >= numPeople)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pscore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L43
L9:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L25
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L6
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L6:
  addl   $0x1,-0x18(%rbp)
L43:
  cmpl   $0x9,-0x18(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L23
L55:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L23:
  cmpl   $0x9,-0x18(%rbp)
  jle    L55
  movss  -0x14(%rbp),%xmm0
  movss  D9(%rip),%xmm1
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: f32

tool: D9: 8

assistant: ```c
float pscore(int *p) {
  int *max, *min, i;
  float s = 0;
  max = min = p;
  for (i = 0; i < 10; i++) {
    if (*max < *(p + i))
      max = (p + i);
    if (*min > *(p + i))
      min = (p + i);
  }
  *min = 0;
  *max = 0;
  for (i = 0; i < 10; i++)
    s += *(p + i);
  return s / 8.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pscore>:
  endbr64
  mov    %rdi,%rdx
  lea    0x28(%rdi),%r8
  mov    %rdi,%rax
  mov    %rdi,%rcx
L2:
  mov    (%rax),%esi
  cmp    %esi,(%rdi)
  cmovl  %rax,%rdi
  cmp    (%rcx),%esi
  cmovl  %rax,%rcx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L2
  movl   $0x0,(%rcx)
  movl   $0x0,(%rdi)
  pxor   %xmm0,%xmm0
L13:
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rdx),%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L13
  mulss  D6(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3e]}

assistant: ```c
float pscore(int *p) {
  int *max, *min, i;
  float s = 0;
  max = min = p;
  for (i = 0; i < 10; i++) {
    if (*max < *(p + i))
      max = (p + i);
    if (*min > *(p + i))
      min = (p + i);
  }
  *min = 0;
  *max = 0;
  for (i = 0; i < 10; i++)
    s += *(p + i);
  return s / 8.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pscore>:
  endbr64
  mov    %rdi,%rdx
  lea    0x28(%rdi),%r8
  mov    %rdi,%rax
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L13:
  mov    (%rax),%esi
  cmp    %esi,(%rdi)
  cmovl  %rax,%rdi
  cmp    (%rcx),%esi
  cmovl  %rax,%rcx
  add    $0x4,%rax
  cmp    %rax,%r8
  jne    L13
  movl   $0x0,(%rcx)
  pxor   %xmm0,%xmm0
  movl   $0x0,(%rdi)
  nop
L2:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdx
  cvtsi2ssl -0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  cmp    %r8,%rdx
  jne    L2
  mulss  D6(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3e]}

assistant: ```c
float pscore(int *p) {
  int *max, *min, i;
  float s = 0;
  max = min = p;
  for (i = 0; i < 10; i++) {
    if (*max < *(p + i))
      max = (p + i);
    if (*min > *(p + i))
      min = (p + i);
  }
  *min = 0;
  *max = 0;
  for (i = 0; i < 10; i++)
    s += *(p + i);
  return s / 8.0;
}
```