ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<isMP3Header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L11
  mov    $0x0,%eax
  jmp    L96
L11:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    $0x3,%rax
  jg     L93
  mov    $0x0,%eax
  jmp    L96
L93:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xff,%al
  jne    L15
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    %eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L36
  mov    $0x0,%eax
  jmp    L96
L36:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  cmp    $0xf,%al
  jne    L3
  mov    $0x0,%eax
  jmp    L96
L3:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L94
  mov    $0x0,%eax
  jmp    L96
L94:
  mov    $0x1,%eax
  jmp    L96
L15:
  mov    $0x0,%eax
L96:
  pop    %rbp
  ret
```

assistant: ```c
int isMP3Header(const unsigned char *p, const unsigned char *e) {
  if (p > e)
    return 0;
  if (e - p < 4)
    return 0;
  if (p[0] == 0xff && (p[1] & 0xe0) == 0xe0) {
    if (((p[1] & 0x06) >> 1) == 0)
      return 0;
    if (((p[2] & 0xf0) >> 4) == 15)
      return 0;
    if (((p[2] & 0x0c) >> 2) == 3)
      return 0;
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isMP3Header>:
  endbr64
  mov    $0x0,%eax
  cmp    %rsi,%rdi
  ja     L38
  sub    %rdi,%rsi
  cmp    $0x3,%rsi
  jle    L38
  cmpb   $0xff,(%rdi)
  je     L6
L38:
  ret
L6:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%ecx
  and    $0xffffffe0,%ecx
  cmp    $0xe0,%cl
  jne    L38
  shr    %edx
  mov    %edx,%eax
  and    $0x3,%eax
  je     L38
  movzbl 0x2(%rdi),%edx
  mov    %edx,%ecx
  shr    $0x4,%cl
  mov    $0x0,%eax
  cmp    $0xf,%cl
  je     L38
  xor    $0xc,%edx
  test   $0xc,%dl
  setne  %al
  movzbl %al,%eax
  jmp    L38
```

assistant: ```c
int isMP3Header(const unsigned char *p, const unsigned char *e) {
  if (p > e)
    return 0;
  if (e - p < 4)
    return 0;
  if (p[0] == 0xff && (p[1] & 0xe0) == 0xe0) {
    if (((p[1] & 0x06) >> 1) == 0)
      return 0;
    if (((p[2] & 0xf0) >> 4) == 15)
      return 0;
    if (((p[2] & 0x0c) >> 2) == 3)
      return 0;
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<isMP3Header>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  ja     L44
  sub    %rdi,%rsi
  cmp    $0x3,%rsi
  jle    L44
  cmpb   $0xff,(%rdi)
  je     L9
L44:
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%ecx
  and    $0xffffffe0,%ecx
  cmp    $0xe0,%cl
  jne    L44
  shr    %edx
  mov    %edx,%eax
  and    $0x3,%eax
  je     L44
  movzbl 0x2(%rdi),%edx
  xor    %eax,%eax
  mov    %edx,%ecx
  shr    $0x4,%cl
  cmp    $0xf,%cl
  je     L44
  xor    $0xc,%edx
  xor    %eax,%eax
  and    $0xc,%edx
  setne  %al
  ret
```

assistant: ```c
int isMP3Header(const unsigned char *p, const unsigned char *e) {
  if (p > e)
    return 0;
  if (e - p < 4)
    return 0;
  if (p[0] == 0xff && (p[1] & 0xe0) == 0xe0) {
    if (((p[1] & 0x06) >> 1) == 0)
      return 0;
    if (((p[2] & 0xf0) >> 4) == 15)
      return 0;
    if (((p[2] & 0x0c) >> 2) == 3)
      return 0;
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isMP3Header>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  ja     L8
  sub    %rdi,%rsi
  cmp    $0x3,%rsi
  jle    L8
  cmpb   $0xff,(%rdi)
  je     L30
L8:
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%ecx
  and    $0xffffffe0,%ecx
  cmp    $0xe0,%cl
  jne    L8
  shr    %edx
  mov    %edx,%eax
  and    $0x3,%eax
  je     L8
  movzbl 0x2(%rdi),%edx
  xor    %eax,%eax
  mov    %edx,%ecx
  shr    $0x4,%cl
  cmp    $0xf,%cl
  je     L8
  xor    $0xc,%edx
  xor    %eax,%eax
  and    $0xc,%edx
  setne  %al
  ret
```

assistant: ```c
int isMP3Header(const unsigned char *p, const unsigned char *e) {
  if (p > e)
    return 0;
  if (e - p < 4)
    return 0;
  if (p[0] == 0xff && (p[1] & 0xe0) == 0xe0) {
    if (((p[1] & 0x06) >> 1) == 0)
      return 0;
    if (((p[2] & 0xf0) >> 4) == 15)
      return 0;
    if (((p[2] & 0x0c) >> 2) == 3)
      return 0;
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L23
  cmpl   $0x0,-0x10(%rbp)
  je     L7
  lea    D26(%rip),%rax
  jmp    L9
L7:
  lea    D7(%rip),%rax
L9:
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L23:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string

tool: D26: search

tool: D7: deletion

tool: D8: Incorrect %s index for %d: %d (actual) vs. %d (expected)


tool: D16: 
fail whale :(

assistant: ```c
void index_check(int key, int actual_index, int expected_index, int op) {
  if (actual_index != expected_index) {
    printf("Incorrect %s index for %d: %d (actual) vs. %d (expected)\n", (op ? "search" : "deletion"), key, actual_index, expected_index);
    printf("\nfail whale :(\n");
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<index_check>:
  endbr64
  cmp    %edx,%esi
  je     L4
  sub    $0x8,%rsp
  mov    %edx,%r8d
  test   %ecx,%ecx
  lea    D37(%rip),%rax
  lea    D2(%rip),%rdx
  cmove  %rdx,%rax
  mov    %esi,%ecx
  mov    %edi,%edx
  mov    %rax,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string

tool: D37: search

tool: D2: deletion

tool: D29: Incorrect %s index for %d: %d (actual) vs. %d (expected)


tool: D31: 
fail whale :(

assistant: ```c
void index_check(int key, int actual_index, int expected_index, int op) {
  if (actual_index != expected_index) {
    printf("Incorrect %s index for %d: %d (actual) vs. %d (expected)\n", (op ? "search" : "deletion"), key, actual_index, expected_index);
    printf("\nfail whale :(\n");
    exit(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<index_check>:
  endbr64
  cmp    %edx,%esi
  je     L6
  sub    $0x8,%rsp
  mov    %esi,%r9d
  test   %ecx,%ecx
  mov    %edx,%r8d
  lea    D34(%rip),%rax
  lea    D17(%rip),%rsi
  mov    %edi,%edx
  mov    %r9d,%ecx
  cmove  %rax,%rsi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D34
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D33
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D34: deletion

tool: D17: search

tool: D33: Incorrect %s index for %d: %d (actual) vs. %d (expected)


tool: D3: 
fail whale :(

assistant: ```c
void index_check(int key, int actual_index, int expected_index, int op) {
  if (actual_index != expected_index) {
    printf("Incorrect %s index for %d: %d (actual) vs. %d (expected)\n", (op ? "search" : "deletion"), key, actual_index, expected_index);
    printf("\nfail whale :(\n");
    exit(1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<index_check>:
  endbr64
  cmp    %edx,%esi
  je     L6
  sub    $0x8,%rsp
  mov    %esi,%r9d
  test   %ecx,%ecx
  mov    %edx,%r8d
  lea    D27(%rip),%rax
  lea    D3(%rip),%rsi
  mov    %edi,%edx
  mov    %r9d,%ecx
  cmove  %rax,%rsi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D33
type: string
name: unpack_data
arguments: data_label: D32
type: string

tool: D27: deletion

tool: D3: search

tool: D33: Incorrect %s index for %d: %d (actual) vs. %d (expected)


tool: D32: 
fail whale :(

assistant: ```c
void index_check(int key, int actual_index, int expected_index, int op) {
  if (actual_index != expected_index) {
    printf("Incorrect %s index for %d: %d (actual) vs. %d (expected)\n", (op ? "search" : "deletion"), key, actual_index, expected_index);
    printf("\nfail whale :(\n");
    exit(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L0:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *rc = s1;
  while ((*(s1++) = *(s2++)))
    ;
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L1:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L1
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *rc = s1;
  while ((*(s1++) = *(s2++)))
    ;
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L4:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L4
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *rc = s1;
  while ((*(s1++) = *(s2++)))
    ;
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *rc = s1;
  while ((*(s1++) = *(s2++)))
    ;
  return rc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  xor    %eax,-0x20(%rbp)
  movl   $0x8,-0x4(%rbp)
  jmp    L51
L14:
  mov    -0x20(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L52
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  xor    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L39
L52:
  shll   -0x20(%rbp)
L39:
  subl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x0,-0x4(%rbp)
  jg     L14
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    -0x20(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t crc16(uint8_t *message, int nBytes, uint16_t remainder, uint16_t polynomial) {
  int byte;
  uint8_t bit;
  for (byte = 0; byte < nBytes; ++byte) {
    remainder ^= (message[byte] << 8);
    for (bit = 8; bit > 0; --bit) {
      if (remainder & 0x8000) {
        remainder = (remainder << 1) ^ polynomial;
      } else {
        remainder = (remainder << 1);
      }
    }
  }
  return remainder;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc16>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L10
  mov    %rdi,%r8
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r9
  jmp    L46
L30:
  add    $0x4,%r8
  cmp    %r9,%r8
  je     L10
L46:
  mov    (%r8),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%esi
L44:
  lea    (%rax,%rax,1),%edx
  xor    %ecx,%edx
  lea    (%rax,%rax,1),%edi
  test   $0x80,%ah
  mov    %edx,%eax
  cmove  %edi,%eax
  sub    $0x1,%esi
  jne    L44
  jmp    L30
L10:
  ret
```

assistant: ```c
uint16_t crc16(uint8_t *message, int nBytes, uint16_t remainder, uint16_t polynomial) {
  int byte;
  uint8_t bit;
  for (byte = 0; byte < nBytes; ++byte) {
    remainder ^= (message[byte] << 8);
    for (bit = 8; bit > 0; --bit) {
      if (remainder & 0x8000) {
        remainder = (remainder << 1) ^ polynomial;
      } else {
        remainder = (remainder << 1);
      }
    }
  }
  return remainder;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crc16>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r9
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%edx
  nopl   0x0(%rax)
L5:
  mov    %eax,%r8d
  add    %eax,%eax
  mov    %eax,%esi
  and    $0x8000,%r8d
  xor    %ecx,%esi
  test   %r8d,%r8d
  cmovne %esi,%eax
  sub    $0x1,%edx
  jne    L5
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L7
L17:
  ret
```

assistant: ```c
uint16_t crc16(uint8_t *message, int nBytes, uint16_t remainder, uint16_t polynomial) {
  int byte;
  uint8_t bit;
  for (byte = 0; byte < nBytes; ++byte) {
    remainder ^= (message[byte] << 8);
    for (bit = 8; bit > 0; --bit) {
      if (remainder & 0x8000) {
        remainder = (remainder << 1) ^ polynomial;
      } else {
        remainder = (remainder << 1);
      }
    }
  }
  return remainder;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crc16>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r9
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rdi),%eax
  shl    $0x8,%eax
  xor    %r8d,%eax
  lea    (%rax,%rax,1),%esi
  mov    %esi,%edx
  xor    %ecx,%edx
  test   $0x80,%ah
  cmovne %edx,%esi
  lea    (%rsi,%rsi,1),%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  and    $0x8000,%esi
  cmovne %eax,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%esi
  xor    %ecx,%esi
  and    $0x80,%dh
  cmovne %esi,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%esi
  xor    %ecx,%esi
  test   $0x80,%ah
  cmovne %esi,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%esi
  xor    %ecx,%esi
  and    $0x80,%dh
  cmovne %esi,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%esi
  xor    %ecx,%esi
  test   $0x80,%ah
  cmovne %esi,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%esi
  xor    %ecx,%esi
  and    $0x80,%dh
  cmovne %esi,%eax
  lea    (%rax,%rax,1),%r8d
  mov    %r8d,%edx
  xor    %ecx,%edx
  test   $0x80,%ah
  cmovne %edx,%r8d
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L2
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint16_t crc16(uint8_t *message, int nBytes, uint16_t remainder, uint16_t polynomial) {
  int byte;
  uint8_t bit;
  for (byte = 0; byte < nBytes; ++byte) {
    remainder ^= (message[byte] << 8);
    for (bit = 8; bit > 0; --bit) {
      if (remainder & 0x8000) {
        remainder = (remainder << 1) ^ polynomial;
      } else {
        remainder = (remainder << 1);
      }
    }
  }
  return remainder;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x19(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L19:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L78:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L31
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L31
  movzbl -0x19(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L67
L31:
  mov    $0x20,%edi
  call   <putchar@plt>
L67:
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L78
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L33:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D9
type: string

tool: D13: Vuvedi vid simvol

tool: D15: %c

tool: D25: Vuvedi broi redove

tool: D9: %d

assistant: ```c
int main() {
  int n, i, h, z;
  char simvol;
  printf("Vuvedi vid simvol\n");
  scanf("%c", &simvol);
  printf("Vuvedi broi redove\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    h = n - i;
    for (z = 0; z < n * 2; z++) {
      if (z >= h && n * 2 - 1 - z > h) {
        printf("%c", simvol);
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    0x3(%rsp),%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  js     L88
  mov    $0x0,%r12d
  jmp    L12
L52:
  mov    $0x20,%edi
  call   <putchar@plt>
L95:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jle    L67
L69:
  cmp    %ebx,%ebp
  jg     L52
  sub    $0x1,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jle    L52
  movsbl 0x3(%rsp),%edi
  call   <putchar@plt>
  jmp    L95
L67:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  mov    0x4(%rsp),%ebp
  cmp    %r12d,%ebp
  jl     L88
L12:
  sub    %r12d,%ebp
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  test   %eax,%eax
  jle    L67
  mov    $0x0,%ebx
  jmp    L69
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D35
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D21: Vuvedi vid simvol

tool: D26: %c

tool: D35: Vuvedi broi redove

tool: D0: %d

assistant: ```c
int main() {
  int n, i, h, z;
  char simvol;
  printf("Vuvedi vid simvol\n");
  scanf("%c", &simvol);
  printf("Vuvedi broi redove\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    h = n - i;
    for (z = 0; z < n * 2; z++) {
      if (z >= h && n * 2 - 1 - z > h) {
        printf("%c", simvol);
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x3(%rsp),%rsi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L8
  nopl   (%rax)
L42:
  mov    %edx,%ebp
  lea    (%rdx,%rdx,1),%eax
  xor    %ebx,%ebx
  sub    %r12d,%ebp
  test   %edx,%edx
  jne    L67
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jle    L55
L67:
  cmp    %ebx,%ebp
  jg     L37
  sub    $0x1,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jle    L37
  movsbl 0x3(%rsp),%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jg     L67
  nopl   0x0(%rax,%rax,1)
L55:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  mov    0x4(%rsp),%edx
  cmp    %r12d,%edx
  jge    L42
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D38
datatype: string
name: parse_data
arguments: tag: D7
datatype: string

tool: D28: Vuvedi vid simvol

tool: D34: %c

tool: D38: Vuvedi broi redove

tool: D7: %d

assistant: ```c
int main() {
  int n, i, h, z;
  char simvol;
  printf("Vuvedi vid simvol\n");
  scanf("%c", &simvol);
  printf("Vuvedi broi redove\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    h = n - i;
    for (z = 0; z < n * 2; z++) {
      if (z >= h && n * 2 - 1 - z > h) {
        printf("%c", simvol);
      } else
        printf(" ");
    }
    printf("\n");
  }
}
```