ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <DefaultScreen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <RootWindow@plt>
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   $0x0
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    %eax,%esi
  push   $0x0
  mov    %rbp,%rdi
  push   $0x1
  call   <XCreateSimpleWindow@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <XMapWindow@plt>
  mov    %rbp,%rdi
  call   <XFlush@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <XCloseDisplay@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  Display *display;
  Window window, rootwindow;
  int screen;
  display = XOpenDisplay(NULL);
  screen = DefaultScreen(display);
  rootwindow = RootWindow(display, screen);
  window = XCreateSimpleWindow(display, rootwindow, 0, 0, 100, 100, 1, 0, 0);
  XMapWindow(display, window);
  XFlush(display);
  sleep(10);
  XCloseDisplay(display);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <XOpenDisplay@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <DefaultScreen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <RootWindow@plt>
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   $0x0
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    %eax,%esi
  push   $0x0
  mov    %rbp,%rdi
  push   $0x1
  call   <XCreateSimpleWindow@plt>
  add    $0x20,%rsp
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <XMapWindow@plt>
  mov    %rbp,%rdi
  call   <XFlush@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <XCloseDisplay@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  Display *display;
  Window window, rootwindow;
  int screen;
  display = XOpenDisplay(NULL);
  screen = DefaultScreen(display);
  rootwindow = RootWindow(display, screen);
  window = XCreateSimpleWindow(display, rootwindow, 0, 0, 100, 100, 1, 0, 0);
  XMapWindow(display, window);
  XFlush(display);
  sleep(10);
  XCloseDisplay(display);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *p;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int *p;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int *p;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int *p;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mc_dir_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L148
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L148:
  mov    -0x18(%rbp),%rax
  movb   $0x2e,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L54
L1:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L144
L57:
  subq   $0x1,-0x8(%rbp)
L144:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L36
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L57
  jmp    L36
L48:
  subq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L94
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L48
L94:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L33
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L20
  movzbl -0x24(%rbp),%eax
  jmp    L132
L20:
  mov    $0x2e,%eax
L132:
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L54
L33:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L78
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L33
L78:
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L54:
  leave
  ret
```

assistant: ```c
char *mc_dir_name(char *outbuf, const char *path, char pathsep) {
  const char *endp;
  int len;
  if (path == NULL || *path == '\0') {
    outbuf[0] = '.';
    outbuf[1] = '\0';
    return outbuf;
  }
  endp = path + strlen(path) - 1;
  while (endp > path && *endp == pathsep) {
    endp--;
  }
  while (endp > path && *endp != pathsep) {
    endp--;
  }
  if (endp == path) {
    outbuf[0] = (*endp == pathsep) ? pathsep : '.';
    outbuf[1] = '\0';
    return outbuf;
  } else {
    do {
      endp--;
    } while (endp > path && *endp == pathsep);
  }
  len = (int)(endp - path + 1);
  strncpy(outbuf, path, len);
  outbuf[len] = '\0';
  return outbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mc_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  test   %rsi,%rsi
  je     L154
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %edx,%ebx
  cmpb   $0x0,(%rsi)
  jne    L77
L154:
  movb   $0x2e,(%r12)
  movb   $0x0,0x1(%r12)
L82:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L77:
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jae    L27
L49:
  cmp    %bl,(%rax)
  jne    L70
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L49
  jmp    L122
L70:
  cmp    %rax,%rbp
  jae    L27
L64:
  cmp    %bl,(%rax)
  je     L32
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L64
L122:
  cmp    %r13b,0x0(%rbp)
  mov    $0x2e,%eax
  cmovne %eax,%ebx
L139:
  mov    %bl,(%r12)
  movb   $0x0,0x1(%r12)
  jmp    L82
L27:
  cmp    %rax,%rbp
  jne    L35
  mov    %rax,%rbp
  jmp    L122
L32:
  cmp    %rax,%rbp
  je     L139
L35:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jae    L73
  cmp    %bl,(%rax)
  je     L35
L73:
  sub    %rbp,%rax
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  jmp    L82
```

assistant: ```c
char *mc_dir_name(char *outbuf, const char *path, char pathsep) {
  const char *endp;
  int len;
  if (path == NULL || *path == '\0') {
    outbuf[0] = '.';
    outbuf[1] = '\0';
    return outbuf;
  }
  endp = path + strlen(path) - 1;
  while (endp > path && *endp == pathsep) {
    endp--;
  }
  while (endp > path && *endp != pathsep) {
    endp--;
  }
  if (endp == path) {
    outbuf[0] = (*endp == pathsep) ? pathsep : '.';
    outbuf[1] = '\0';
    return outbuf;
  } else {
    do {
      endp--;
    } while (endp > path && *endp == pathsep);
  }
  len = (int)(endp - path + 1);
  strncpy(outbuf, path, len);
  outbuf[len] = '\0';
  return outbuf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mc_dir_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L107
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbp
  jne    L59
L107:
  mov    $0x2e,%eax
  mov    %ax,(%r12)
L86:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %rsi,%rdi
  mov    %edx,%r13d
  mov    %edx,%ebx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jb     L106
  jmp    L143
  xchg   %ax,%ax
L76:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L131
L106:
  cmp    %bl,(%rax)
  je     L76
  cmp    %rax,%rbp
  jae    L143
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L131
  nopl   0x0(%rax,%rax,1)
L103:
  cmp    (%rax),%bl
  je     L130
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L103
L131:
  cmp    %r13b,0x0(%rbp)
  mov    $0x2e,%eax
  movb   $0x0,0x1(%r12)
  cmovne %eax,%ebx
  mov    %bl,(%r12)
  jmp    L86
  nopl   (%rax)
L2:
  cmp    %bl,(%rax)
  jne    L35
L130:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jb     L2
L35:
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L143:
  cmp    %rax,%rbp
  jne    L130
  jmp    L131
```

assistant: ```c
char *mc_dir_name(char *outbuf, const char *path, char pathsep) {
  const char *endp;
  int len;
  if (path == NULL || *path == '\0') {
    outbuf[0] = '.';
    outbuf[1] = '\0';
    return outbuf;
  }
  endp = path + strlen(path) - 1;
  while (endp > path && *endp == pathsep) {
    endp--;
  }
  while (endp > path && *endp != pathsep) {
    endp--;
  }
  if (endp == path) {
    outbuf[0] = (*endp == pathsep) ? pathsep : '.';
    outbuf[1] = '\0';
    return outbuf;
  } else {
    do {
      endp--;
    } while (endp > path && *endp == pathsep);
  }
  len = (int)(endp - path + 1);
  strncpy(outbuf, path, len);
  outbuf[len] = '\0';
  return outbuf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mc_dir_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L37
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbp
  jne    L13
L37:
  mov    $0x2e,%eax
  mov    %ax,(%r12)
L52:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %rsi,%rdi
  mov    %edx,%r13d
  mov    %edx,%ebx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jb     L57
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L149:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L26
L57:
  cmp    %bl,(%rax)
  je     L149
  cmp    %rax,%rbp
  jb     L86
  jmp    L109
  nopl   0x0(%rax)
L58:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L26
L86:
  cmp    %bl,(%rax)
  jne    L58
  cmp    %rax,%rbp
  jne    L91
  jmp    L20
  nopl   0x0(%rax)
L83:
  cmp    %bl,(%rax)
  jne    L53
L91:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jb     L83
L53:
  sub    %rbp,%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L109:
  cmp    %rax,%rbp
  jne    L91
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    %r13b,0x0(%rbp)
  mov    $0x2e,%eax
  cmovne %eax,%ebx
L20:
  mov    %bl,(%r12)
  movb   $0x0,0x1(%r12)
  jmp    L52
```

assistant: ```c
char *mc_dir_name(char *outbuf, const char *path, char pathsep) {
  const char *endp;
  int len;
  if (path == NULL || *path == '\0') {
    outbuf[0] = '.';
    outbuf[1] = '\0';
    return outbuf;
  }
  endp = path + strlen(path) - 1;
  while (endp > path && *endp == pathsep) {
    endp--;
  }
  while (endp > path && *endp != pathsep) {
    endp--;
  }
  if (endp == path) {
    outbuf[0] = (*endp == pathsep) ? pathsep : '.';
    outbuf[1] = '\0';
    return outbuf;
  } else {
    do {
      endp--;
    } while (endp > path && *endp == pathsep);
  }
  len = (int)(endp - path + 1);
  strncpy(outbuf, path, len);
  outbuf[len] = '\0';
  return outbuf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L92
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L92:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x1,(%rax)
  movq   $0x3,-0x20(%rbp)
  jmp    L94
L111:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L109
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
L109:
  addq   $0x1,-0x20(%rbp)
L94:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L111
  movq   $0x3,-0x20(%rbp)
  jmp    L31
L118:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x20(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L53
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  add    %rax,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L2
  jmp    L98
L23:
  nop
L98:
  addq   $0x2,-0x20(%rbp)
L31:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L118
  movq   $0x0,-0x20(%rbp)
  jmp    L126
L76:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L108
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L108:
  addq   $0x1,-0x20(%rbp)
L126:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L76
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D0: Could not allocate memory. Aborting.

tool: D15: %lld


assistant: ```c
void print_primes(long long n) {
  long long i, j;
  char *primes;
  long long rt = sqrt(n);
  primes = calloc(sizeof(char) * (n + 1), sizeof(char));
  if (!primes) {
    printf("Could not allocate memory. Aborting.\n");
    exit(1);
  }
  primes[0] = 0;
  primes[1] = 0;
  primes[2] = 1;
  for (i = 3; i <= n; i++) {
    if (i & 1)
      primes[i] = 1;
  }
  for (i = 3; i <= rt; i += 2) {
    if (!primes[i])
      continue;
    for (j = i * i; j <= n; j += 2 * i)
      primes[j] = 0;
  }
  for (i = 0; i <= n; i++)
    if (primes[i])
      printf("%lld\n", i);
  free(primes);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <sqrt@plt>
  mov    %rax,%r12
  lea    0x1(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L25
L120:
  movb   $0x0,(%rbx)
  movb   $0x0,0x1(%rbx)
  movb   $0x1,0x2(%rbx)
  cmp    $0x2,%rbp
  jle    L184
  lea    0x1(%rbp),%rdx
  mov    $0x3,%eax
  jmp    L142
L25:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L120
L156:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L111
L142:
  test   $0x1,%al
  je     L156
  movb   $0x1,(%rbx,%rax,1)
  jmp    L156
L184:
  cmp    $0x2,%r12
  jg     L129
L168:
  test   %rbp,%rbp
  js     L121
L108:
  mov    $0x0,%r12d
  lea    D9(%rip),%r13
  jmp    L141
L133:
  add    $0x2,%rdx
  cmp    %rdx,%r12
  jl     L168
L182:
  mov    %rdx,%rcx
  cmpb   $0x0,(%rbx,%rdx,1)
  je     L133
  mov    %rdx,%rax
  imul   %rdx,%rax
  cmp    %rax,%rbp
  jl     L133
  add    %rcx,%rcx
L98:
  movb   $0x0,(%rbx,%rax,1)
  add    %rcx,%rax
  cmp    %rax,%rbp
  jge    L98
  jmp    L133
L71:
  add    $0x1,%r12
  cmp    %r12,%rbp
  jl     L121
L141:
  cmpb   $0x0,(%rbx,%r12,1)
  je     L71
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L71
L121:
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L111:
  cmp    $0x2,%r12
  jle    L108
L129:
  mov    $0x3,%edx
  jmp    L182
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D3: Could not allocate memory. Aborting.

tool: D9: %lld


assistant: ```c
void print_primes(long long n) {
  long long i, j;
  char *primes;
  long long rt = sqrt(n);
  primes = calloc(sizeof(char) * (n + 1), sizeof(char));
  if (!primes) {
    printf("Could not allocate memory. Aborting.\n");
    exit(1);
  }
  primes[0] = 0;
  primes[1] = 0;
  primes[2] = 1;
  for (i = 3; i <= n; i++) {
    if (i & 1)
      primes[i] = 1;
  }
  for (i = 3; i <= rt; i += 2) {
    if (!primes[i])
      continue;
    for (j = i * i; j <= n; j += 2 * i)
      primes[j] = 0;
  }
  for (i = 0; i <= n; i++)
    if (primes[i])
      printf("%lld\n", i);
  free(primes);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  lea    0x1(%rbx),%edi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L50
  xor    %eax,%eax
  movb   $0x1,0x2(%rbp)
  mov    %ax,0x0(%rbp)
  cmp    $0x2,%rbx
  jle    L182
L147:
  lea    0x1(%rbx),%rdx
  mov    $0x3,%eax
  nop
L137:
  test   $0x1,%al
  je     L36
  movb   $0x1,0x0(%rbp,%rax,1)
L36:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L137
  cmp    $0x2,%r12
  jle    L144
L184:
  mov    $0x3,%edx
  jmp    L91
  nop
L82:
  add    $0x2,%rdx
  cmp    %rdx,%r12
  jl     L104
L91:
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  je     L82
  mov    %rdx,%rax
  imul   %rdx,%rax
  cmp    %rax,%rbx
  jl     L82
  lea    (%rdx,%rdx,1),%rcx
L153:
  movb   $0x0,0x0(%rbp,%rax,1)
  add    %rcx,%rax
  cmp    %rax,%rbx
  jge    L153
  add    $0x2,%rdx
  cmp    %rdx,%r12
  jge    L91
L104:
  test   %rbx,%rbx
  js     L123
L144:
  xor    %r12d,%r12d
  lea    D12(%rip),%r13
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L131:
  add    $0x1,%r12
  cmp    %r12,%rbx
  jl     L123
L60:
  cmpb   $0x0,0x0(%rbp,%r12,1)
  je     L131
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12,%rbx
  jge    L60
L123:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
L50:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  movb   $0x1,0x2(%rbp)
  mov    %ax,0x0(%rbp)
  cmp    $0x2,%rbx
  jg     L147
L182:
  cmp    $0x2,%r12
  jg     L184
  jmp    L104
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string

tool: D12: %lld


tool: D10: Could not allocate memory. Aborting.

assistant: ```c
void print_primes(long long n) {
  long long i, j;
  char *primes;
  long long rt = sqrt(n);
  primes = calloc(sizeof(char) * (n + 1), sizeof(char));
  if (!primes) {
    printf("Could not allocate memory. Aborting.\n");
    exit(1);
  }
  primes[0] = 0;
  primes[1] = 0;
  primes[2] = 1;
  for (i = 3; i <= n; i++) {
    if (i & 1)
      primes[i] = 1;
  }
  for (i = 3; i <= rt; i += 2) {
    if (!primes[i])
      continue;
    for (j = i * i; j <= n; j += 2 * i)
      primes[j] = 0;
  }
  for (i = 0; i <= n; i++)
    if (primes[i])
      printf("%lld\n", i);
  free(primes);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  lea    0x1(%rbx),%edi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L141
  xor    %eax,%eax
  movb   $0x1,0x2(%rbp)
  mov    %ax,0x0(%rbp)
  cmp    $0x2,%rbx
  jle    L22
L133:
  lea    0x1(%rbx),%rdx
  mov    $0x3,%eax
  nop
L19:
  test   $0x1,%al
  je     L173
  movb   $0x1,0x0(%rbp,%rax,1)
L173:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
  cmp    $0x2,%r12
  jle    L6
L53:
  mov    $0x3,%edx
  jmp    L165
  nop
L47:
  add    $0x2,%rdx
  cmp    %rdx,%r12
  jl     L119
L165:
  cmpb   $0x0,0x0(%rbp,%rdx,1)
  je     L47
  mov    %rdx,%rax
  imul   %rdx,%rax
  cmp    %rax,%rbx
  jl     L47
  lea    (%rdx,%rdx,1),%rcx
L125:
  movb   $0x0,0x0(%rbp,%rax,1)
  add    %rcx,%rax
  cmp    %rax,%rbx
  jge    L125
  add    $0x2,%rdx
  cmp    %rdx,%r12
  jge    L165
L119:
  test   %rbx,%rbx
  js     L89
L6:
  xor    %r12d,%r12d
  lea    D2(%rip),%r13
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x1,%r12
  cmp    %r12,%rbx
  jl     L89
L88:
  cmpb   $0x0,0x0(%rbp,%r12,1)
  je     L28
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12,%rbx
  jge    L88
L89:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
L141:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  movb   $0x1,0x2(%rbp)
  mov    %ax,0x0(%rbp)
  cmp    $0x2,%rbx
  jg     L133
L22:
  cmp    $0x2,%r12
  jg     L53
  jmp    L119
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D2: %lld


tool: D10: Could not allocate memory. Aborting.

assistant: ```c
void print_primes(long long n) {
  long long i, j;
  char *primes;
  long long rt = sqrt(n);
  primes = calloc(sizeof(char) * (n + 1), sizeof(char));
  if (!primes) {
    printf("Could not allocate memory. Aborting.\n");
    exit(1);
  }
  primes[0] = 0;
  primes[1] = 0;
  primes[2] = 1;
  for (i = 3; i <= n; i++) {
    if (i & 1)
      primes[i] = 1;
  }
  for (i = 3; i <= rt; i += 2) {
    if (!primes[i])
      continue;
    for (j = i * i; j <= n; j += 2 * i)
      primes[j] = 0;
  }
  for (i = 0; i <= n; i++)
    if (primes[i])
      printf("%lld\n", i);
  free(primes);
}
```