ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getReservedAddr>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  lea    D42(%rip),%rdi
  push   %r13
  mov    %rsi,%r13
  lea    D18(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L3
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    %rax,%r12
  mov    $0x800,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L39
L40:
  xor    %eax,%eax
L43:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r13,%rdx
  lea    D39(%rip),%r13
  mov    $0x40,%ecx
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <getTokens@plt>
  xor    %esi,%esi
  mov    $0x800,%edx
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <memset@plt>
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L40
  mov    $0x40,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <getTokens@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  jmp    L43
  nopl   (%rax)
L3:
  lea    D54(%rip),%rsi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  jmp    L43
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D42
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D39
data_type: string
name: unpack_data
arguments: data_label: D54
data_type: string
name: unpack_data
arguments: data_label: D55
data_type: string
name: unpack_data
arguments: data_label: D37
data_type: string

tool: D42: /tmp/udhcpd_resrv.conf

tool: D18: r

tool: D39:  

tool: D54: error

tool: D55: %s, 

tool: D37: unable to open config file: /tmp/udhcpd_resrv.conf

assistant: ```c
int getReservedAddr(char reservedMacAddr[][100], char reservedIpAddr[][100]) {
  int numReservedMac = 0, numReservedIp = 0;
  char buffer[2 * 1024];
  FILE *in;
  if (!(in = fopen("/tmp/udhcpd_resrv.conf", "r"))) {
    do {
      printf("%s, ", "error");
      printf("unable to open config file: /tmp/udhcpd_resrv.conf");
      printf("\n");
    } while (0);
    return 0;
  }
  memset(buffer, 0, 2 * 1024);
  if (fgets(buffer, 2 * 1024, in)) {
    numReservedIp = getTokens(buffer, " ", reservedIpAddr, 64);
  } else {
    return 0;
  }
  memset(buffer, 0, 2 * 1024);
  if (fgets(buffer, 2 * 1024, in)) {
    numReservedMac = getTokens(buffer, " ", reservedMacAddr, 64);
  } else {
    return 0;
  }
  if (numReservedMac != numReservedIp) {
  }
  return (numReservedMac < numReservedIp ? numReservedMac : numReservedIp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getReservedAddr>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  lea    D14(%rip),%rdi
  push   %r13
  mov    %rsi,%r13
  lea    D9(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L56
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    %rax,%r12
  mov    $0x800,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L24
L16:
  xor    %eax,%eax
L37:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r13,%rdx
  lea    D59(%rip),%r13
  mov    $0x40,%ecx
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <getTokens@plt>
  xor    %esi,%esi
  mov    $0x800,%edx
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <memset@plt>
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L16
  mov    $0x40,%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <getTokens@plt>
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  jmp    L37
  nopl   (%rax)
L56:
  lea    D55(%rip),%rsi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  jmp    L37
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D59
type_guessed: string
name: parse_data
arguments: label: D55
type_guessed: string
name: parse_data
arguments: label: D58
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D14: /tmp/udhcpd_resrv.conf

tool: D9: r

tool: D59:  

tool: D55: error

tool: D58: %s, 

tool: D0: unable to open config file: /tmp/udhcpd_resrv.conf

assistant: ```c
int getReservedAddr(char reservedMacAddr[][100], char reservedIpAddr[][100]) {
  int numReservedMac = 0, numReservedIp = 0;
  char buffer[2 * 1024];
  FILE *in;
  if (!(in = fopen("/tmp/udhcpd_resrv.conf", "r"))) {
    do {
      printf("%s, ", "error");
      printf("unable to open config file: /tmp/udhcpd_resrv.conf");
      printf("\n");
    } while (0);
    return 0;
  }
  memset(buffer, 0, 2 * 1024);
  if (fgets(buffer, 2 * 1024, in)) {
    numReservedIp = getTokens(buffer, " ", reservedIpAddr, 64);
  } else {
    return 0;
  }
  memset(buffer, 0, 2 * 1024);
  if (fgets(buffer, 2 * 1024, in)) {
    numReservedMac = getTokens(buffer, " ", reservedMacAddr, 64);
  } else {
    return 0;
  }
  if (numReservedMac != numReservedIp) {
  }
  return (numReservedMac < numReservedIp ? numReservedMac : numReservedIp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<board_fix_long_desc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void board_fix_long_desc(int num, char *headers[30]) {
  struct obj_data *ob;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<board_fix_long_desc>:
  endbr64
  ret
```

assistant: ```c
void board_fix_long_desc(int num, char *headers[30]) {
  struct obj_data *ob;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<board_fix_long_desc>:
  endbr64
  ret
```

assistant: ```c
void board_fix_long_desc(int num, char *headers[30]) {
  struct obj_data *ob;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
void *sbrk(intptr_t increment) {
  errno = ENOSYS;
  return (void *)-1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sbrk>:
  endbr64
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
void *sbrk(intptr_t increment) {
  errno = ENOSYS;
  return (void *)-1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sbrk>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
void *sbrk(intptr_t increment) {
  errno = ENOSYS;
  return (void *)-1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sbrk>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
void *sbrk(intptr_t increment) {
  errno = ENOSYS;
  return (void *)-1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TK_SplitLine>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L70
  lea    D20(%rip),%r11
  lea    D37(%rip),%r9
  mov    %r11,%r8
  lea    D22(%rip),%r10
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    $0x20,%dl
  jle    L13
  cmp    $0x22,%dl
  je     L215
  movzbl (%rdi),%edx
  mov    %r9,%rax
  cmp    $0x20,%dl
  jle    L186
  nopl   0x0(%rax)
L105:
  add    $0x1,%rdi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jg     L105
L186:
  mov    %r9,(%r8)
  lea    0x1(%rax),%r9
  add    $0x8,%r8
  movb   $0x0,(%rax)
  movzbl (%rdi),%edx
L64:
  test   %dl,%dl
  jne    L27
L174:
  movq   $0x0,(%r8)
  mov    %r11,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L215:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  mov    %r9,%rsi
  test   %al,%al
  jne    L205
  jmp    L47
  nopl   0x0(%rax)
L50:
  add    $0x1,%rcx
L204:
  mov    %al,-0x1(%rsi)
  movzbl (%rcx),%eax
  test   %al,%al
  je     L47
L205:
  cmp    $0x22,%al
  je     L47
  add    $0x1,%rsi
  cmp    $0x5c,%al
  jne    L50
  movzbl 0x1(%rcx),%eax
  add    $0x2,%rcx
  lea    -0x5c(%rax),%edx
  cmp    $0x18,%dl
  ja     L204
  movzbl %dl,%edx
  movslq (%r10,%rdx,4),%rdx
  add    %r10,%rdx
  notrack jmp *%rdx
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r9,(%r8)
  mov    %rcx,%rdi
  lea    0x1(%rsi),%r9
  add    $0x8,%r8
  movb   $0x0,(%rsi)
  movzbl (%rcx),%edx
  jmp    L64
  nopl   0x0(%rax)
L13:
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jg     L64
  test   %dl,%dl
  jne    L195
  jmp    L174
  nopl   (%rax)
L139:
  cmp    $0x20,%dl
  jg     L64
L195:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L139
  movq   $0x0,(%r8)
  mov    %r11,%rax
  ret
  mov    $0xd,%eax
  jmp    L204
  mov    $0x9,%eax
  jmp    L204
  mov    $0x8,%eax
  jmp    L204
  mov    $0xa,%eax
  jmp    L204
L70:
  lea    D20(%rip),%r11
  mov    %r11,%r8
  mov    %r11,%rax
  movq   $0x0,(%r8)
  ret
```

assistant: ```c
char **TK_SplitLine(char *buf) {
  static char *ta[64];
  static char tb[512];
  char **a;
  char *s, *t, *t0;
  a = ta;
  s = buf;
  t = tb;
  while (*s) {
    if (*s <= ' ') {
      while (*s && *s <= ' ')
        s++;
      continue;
    }
    if (*s == '\"') {
      s++;
      t0 = t;
      while (*s && (*s != '\"')) {
        if (*s == '\\') {
          s++;
          switch (*s) {
          case 'b':
            s++;
            *t++ = '\b';
            break;
          case 'n':
            s++;
            *t++ = '\n';
            break;
          case 'r':
            s++;
            *t++ = '\r';
            break;
          case 't':
            s++;
            *t++ = '\t';
            break;
          case '\\':
            s++;
            *t++ = '\\';
            break;
          default:
            *t++ = *s++;
            break;
          }
          continue;
        }
        *t++ = *s++;
      }
      *t++ = 0;
      *a++ = t0;
      continue;
    }
    t0 = t;
    while (*s && (*s > ' ')) {
      *t++ = *s++;
    }
    *t++ = 0;
    *a++ = t0;
  }
  *a++ = ((void *)0);
  return (ta);
}
```
user: Translate the below assembly code into C programming language:

```asm
<TK_SplitLine>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L139
  lea    D26(%rip),%r10
  lea    D38(%rip),%rsi
  mov    %r10,%r8
  lea    D10(%rip),%r9
  nopw   0x0(%rax,%rax,1)
L158:
  cmp    $0x20,%al
  jle    L130
  mov    %rsi,%rdx
  cmp    $0x22,%al
  je     L187
  nopl   0x0(%rax,%rax,1)
L94:
  mov    %rdx,%rcx
  add    $0x1,%rdi
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jg     L94
  mov    %rsi,(%r8)
  lea    0x2(%rcx),%rsi
  add    $0x8,%r8
  movb   $0x0,(%rdx)
  movzbl (%rdi),%eax
L58:
  test   %al,%al
  jne    L158
L70:
  movq   $0x0,(%r8)
  mov    %r10,%rax
  ret
  nopl   (%rax)
L130:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L70
  cmp    $0x20,%al
  jle    L130
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L187:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rcx
  test   %al,%al
  jne    L107
  jmp    L113
  nopl   0x0(%rax)
L144:
  add    $0x1,%rdx
L90:
  mov    %al,-0x1(%rcx)
  movzbl (%rdx),%eax
  test   %al,%al
  je     L113
L107:
  cmp    $0x22,%al
  je     L113
  add    $0x1,%rcx
  cmp    $0x5c,%al
  jne    L144
  movzbl 0x1(%rdx),%eax
  add    $0x2,%rdx
  lea    -0x5c(%rax),%edi
  cmp    $0x18,%dil
  ja     L90
  movzbl %dil,%edi
  movslq (%r9,%rdi,4),%rdi
  add    %r9,%rdi
  notrack jmp *%rdi
  nopl   0x0(%rax)
L113:
  mov    %rsi,(%r8)
  mov    %rdx,%rdi
  lea    0x1(%rcx),%rsi
  add    $0x8,%r8
  movb   $0x0,(%rcx)
  movzbl (%rdx),%eax
  jmp    L58
  mov    $0xd,%eax
  jmp    L90
  mov    $0x9,%eax
  jmp    L90
  mov    $0x8,%eax
  jmp    L90
  mov    $0xa,%eax
  jmp    L90
L139:
  lea    D26(%rip),%r10
  mov    %r10,%r8
  mov    %r10,%rax
  movq   $0x0,(%r8)
  ret
```

assistant: ```c
char **TK_SplitLine(char *buf) {
  static char *ta[64];
  static char tb[512];
  char **a;
  char *s, *t, *t0;
  a = ta;
  s = buf;
  t = tb;
  while (*s) {
    if (*s <= ' ') {
      while (*s && *s <= ' ')
        s++;
      continue;
    }
    if (*s == '\"') {
      s++;
      t0 = t;
      while (*s && (*s != '\"')) {
        if (*s == '\\') {
          s++;
          switch (*s) {
          case 'b':
            s++;
            *t++ = '\b';
            break;
          case 'n':
            s++;
            *t++ = '\n';
            break;
          case 'r':
            s++;
            *t++ = '\r';
            break;
          case 't':
            s++;
            *t++ = '\t';
            break;
          case '\\':
            s++;
            *t++ = '\\';
            break;
          default:
            *t++ = *s++;
            break;
          }
          continue;
        }
        *t++ = *s++;
      }
      *t++ = 0;
      *a++ = t0;
      continue;
    }
    t0 = t;
    while (*s && (*s > ' ')) {
      *t++ = *s++;
    }
    *t++ = 0;
    *a++ = t0;
  }
  *a++ = ((void *)0);
  return (ta);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<factorial_ln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <error_and_exit@plt>
  movd   %xmm0,%eax
  jmp    L66
L5:
  cmpl   $0x1,-0x4(%rbp)
  jg     L54
  mov    D48(%rip),%eax
  jmp    L66
L54:
  cmpl   $0x64,-0x4(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D25(%rip),%rax
  movss  (%rdx,%rax,1),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L36
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L19
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D25(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  jmp    L66
L19:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D33(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <gammaln@plt>
  movd   %xmm0,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    D25(%rip),%rdx
  mov    %eax,(%rcx,%rdx,1)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D25(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  jmp    L66
L4:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D33(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <gammaln@plt>
  movd   %xmm0,%eax
L66:
  movd   %eax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D50
type: string
name: extract_symbolic_data
arguments: label: D48
type: f64
name: extract_symbolic_data
arguments: label: D33
type: f64

tool: D50: Negative factorial in routine factorial_ln

tool: D48: 0

tool: D33: 1

assistant: ```c
float factorial_ln(int n) {
  static float a[101];
  if (n < 0)
    return error_and_exit("Negative factorial in routine factorial_ln");
  if (n <= 1)
    return 0.0;
  if (n <= 100)
    return a[n] ? a[n] : (a[n] = gammaln(n + 1.0));
  else
    return gammaln(n + 1.0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factorial_ln>:
  endbr64
  push   %rbx
  test   %edi,%edi
  js     L57
  mov    %edi,%ebx
  pxor   %xmm0,%xmm0
  cmp    $0x1,%edi
  jle    L7
  cmp    $0x64,%edi
  jg     L5
  movslq %edi,%rax
  lea    D15(%rip),%rdx
  movss  (%rdx,%rax,4),%xmm0
  ucomiss D36(%rip),%xmm0
  jp     L7
  je     L28
L7:
  pop    %rbx
  ret
L57:
  lea    D44(%rip),%rdi
  call   <error_and_exit@plt>
  jmp    L7
L28:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D36(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <gammaln@plt>
  movslq %ebx,%rbx
  lea    D15(%rip),%rax
  movss  %xmm0,(%rax,%rbx,4)
  jmp    L7
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D36(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <gammaln@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
data_type: f64
name: extract_symbolic_data
arguments: data_label: D44
data_type: string

tool: D36: 1

tool: D44: Negative factorial in routine factorial_ln

assistant: ```c
float factorial_ln(int n) {
  static float a[101];
  if (n < 0)
    return error_and_exit("Negative factorial in routine factorial_ln");
  if (n <= 1)
    return 0.0;
  if (n <= 100)
    return a[n] ? a[n] : (a[n] = gammaln(n + 1.0));
  else
    return gammaln(n + 1.0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<factorial_ln>:
  endbr64
  test   %edi,%edi
  js     L26
  cmp    $0x1,%edi
  jle    L38
  cmp    $0x64,%edi
  jg     L33
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x8,%rsp
  movss  (%rbx,%rbp,4),%xmm0
  ucomiss D18(%rip),%xmm0
  jp     L27
  je     L10
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L33:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1060 <gammaln@plt>
  nopl   0x0(%rax)
L38:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L26:
  lea    D37(%rip),%rdi
  jmp    1070 <error_and_exit@plt>
  nopl   0x0(%rax)
L10:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D18(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <gammaln@plt>
  movss  %xmm0,(%rbx,%rbp,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: f64
name: read_data
arguments: tag: D37
type: string

tool: D18: 1

tool: D37: Negative factorial in routine factorial_ln

assistant: ```c
float factorial_ln(int n) {
  static float a[101];
  if (n < 0)
    return error_and_exit("Negative factorial in routine factorial_ln");
  if (n <= 1)
    return 0.0;
  if (n <= 100)
    return a[n] ? a[n] : (a[n] = gammaln(n + 1.0));
  else
    return gammaln(n + 1.0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factorial_ln>:
  endbr64
  test   %edi,%edi
  js     L17
  cmp    $0x1,%edi
  jle    L21
  cmp    $0x64,%edi
  jg     L34
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  movss  (%rbx,%rbp,4),%xmm0
  ucomiss D21(%rip),%xmm0
  jp     L13
  je     L45
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L34:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D21(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1060 <gammaln@plt>
  nopl   0x0(%rax)
L21:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L17:
  lea    D49(%rip),%rdi
  jmp    1070 <error_and_exit@plt>
  nopl   0x0(%rax)
L45:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  D21(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <gammaln@plt>
  movss  %xmm0,(%rbx,%rbp,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D21
data_type: f64
name: read_data
arguments: tag: D49
data_type: string

tool: D21: 1

tool: D49: Negative factorial in routine factorial_ln

assistant: ```c
float factorial_ln(int n) {
  static float a[101];
  if (n < 0)
    return error_and_exit("Negative factorial in routine factorial_ln");
  if (n <= 1)
    return 0.0;
  if (n <= 100)
    return a[n] ? a[n] : (a[n] = gammaln(n + 1.0));
  else
    return gammaln(n + 1.0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<thrd_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  test   %rax,%rax
  jns    L7
  mov    D16(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L39
L29:
  mov    $0xfffffffe,%eax
  jmp    L39
L7:
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int thrd_sleep(const struct timespec *duration, struct timespec *remaining) {
  if (nanosleep(duration, remaining) < 0)
    return errno == EINTR ? -1 : -2;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thrd_sleep>:
  endbr64
  sub    $0x8,%rsp
  call   <nanosleep@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L12
L4:
  add    $0x8,%rsp
  ret
L12:
  mov    D4(%rip),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  movzbl %al,%eax
  sub    $0x2,%eax
  jmp    L4
```

assistant: ```c
int thrd_sleep(const struct timespec *duration, struct timespec *remaining) {
  if (nanosleep(duration, remaining) < 0)
    return errno == EINTR ? -1 : -2;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<thrd_sleep>:
  endbr64
  sub    $0x8,%rsp
  call   <nanosleep@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L2
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L2:
  mov    D17(%rip),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  sub    $0x2,%eax
  ret
```

assistant: ```c
int thrd_sleep(const struct timespec *duration, struct timespec *remaining) {
  if (nanosleep(duration, remaining) < 0)
    return errno == EINTR ? -1 : -2;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thrd_sleep>:
  endbr64
  sub    $0x8,%rsp
  call   <nanosleep@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L6
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L6:
  mov    D5(%rip),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  sub    $0x2,%eax
  ret
```

assistant: ```c
int thrd_sleep(const struct timespec *duration, struct timespec *remaining) {
  if (nanosleep(duration, remaining) < 0)
    return errno == EINTR ? -1 : -2;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<showarray_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string

tool: D18: The first 7 prime numbers are : 

tool: D4:  %d,

assistant: ```c
void showarray_3(int *array, int size) {
  int x;
  printf("The first 7 prime numbers are : ");
  for (x = 0; x < size; x++)
    printf(" %d,", *(array + x));
}
```