ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   $0x64,%eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string

tool: D12: %d

tool: D15: %d


assistant: ```c
int main() {
  int x = 0;
  scanf("%d", &x);
  int a = x / 100;
  int b = x % 100 / 10;
  int c = x % 10;
  printf("%d\n", c * 100 + b * 10 + a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rdi
  sar    $0x25,%rdi
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edi
  imul   $0x64,%edi,%ecx
  mov    %edx,%esi
  sub    %ecx,%esi
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  sar    $0x1f,%esi
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  imul   $0x64,%edx,%edx
  lea    (%rdx,%rcx,2),%esi
  add    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D19: %d

tool: D12: %d


assistant: ```c
int main() {
  int x = 0;
  scanf("%d", &x);
  int a = x / 100;
  int b = x % 100 / 10;
  int c = x % 10;
  printf("%d\n", c * 100 + b * 10 + a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x51eb851f,%rax,%rdi
  mov    %eax,%r8d
  mov    %rax,%rdx
  mov    %eax,%esi
  sar    $0x1f,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x25,%rdi
  sub    %r8d,%edi
  sar    $0x22,%rax
  imul   $0x64,%edi,%ecx
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %ecx,%esi
  sub    %eax,%edx
  movslq %esi,%rcx
  imul   $0x64,%edx,%edx
  sar    $0x1f,%esi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rdx,%rcx,2),%esi
  add    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D4: %d

tool: D0: %d


assistant: ```c
int main() {
  int x = 0;
  scanf("%d", &x);
  int a = x / 100;
  int b = x % 100 / 10;
  int c = x % 10;
  printf("%d\n", c * 100 + b * 10 + a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x51eb851f,%rax,%rdi
  mov    %eax,%r8d
  mov    %rax,%rdx
  mov    %eax,%esi
  sar    $0x1f,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x25,%rdi
  sub    %r8d,%edi
  sar    $0x22,%rax
  imul   $0x64,%edi,%ecx
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %ecx,%esi
  sub    %eax,%edx
  movslq %esi,%rcx
  imul   $0x64,%edx,%edx
  sar    $0x1f,%esi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rdx,%rcx,2),%esi
  add    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D5: %d

tool: D3: %d


assistant: ```c
int main() {
  int x = 0;
  scanf("%d", &x);
  int a = x / 100;
  int b = x % 100 / 10;
  int c = x % 10;
  printf("%d\n", c * 100 + b * 10 + a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  je     L32
  cmp    $0xa,%eax
  jg     L34
  cmp    $0x8,%eax
  je     L67
  cmp    $0x9,%eax
  je     L55
  jmp    L34
L32:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L34
L55:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L67:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L34:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D33
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D17
type: string

tool: D19: %d

tool: D33: Number is 10


tool: D27: Number is 9


tool: D17: Number is 8


assistant: ```c
int main() {
  int number;
  scanf("%d", &number);
  switch (number) {
  case 10:
    printf("Number is 10\n");
    break;
  case 9:
    printf("Number is 9\n");
  case 8:
    printf("Number is 8\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  je     L41
  cmp    $0xa,%eax
  je     L7
  cmp    $0x8,%eax
  je     L26
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L41:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L26:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type: string
name: disassemble_data
arguments: data_label: D31
type: string
name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D20: %d

tool: D31: Number is 10


tool: D15: Number is 9


tool: D27: Number is 8


assistant: ```c
int main() {
  int number;
  scanf("%d", &number);
  switch (number) {
  case 10:
    printf("Number is 10\n");
    break;
  case 9:
    printf("Number is 9\n");
  case 8:
    printf("Number is 8\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  je     L8
  cmp    $0xa,%eax
  je     L14
  cmp    $0x8,%eax
  je     L59
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L59:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L14:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D23: %d

tool: D12: Number is 9


tool: D7: Number is 8


tool: D15: Number is 10


assistant: ```c
int main() {
  int number;
  scanf("%d", &number);
  switch (number) {
  case 10:
    printf("Number is 10\n");
    break;
  case 9:
    printf("Number is 9\n");
  case 8:
    printf("Number is 8\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  je     L59
  cmp    $0xa,%eax
  je     L56
  cmp    $0x8,%eax
  je     L19
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L59:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L19:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L56:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D31
datatype: string

tool: D27: %d

tool: D4: Number is 9


tool: D21: Number is 8


tool: D31: Number is 10


assistant: ```c
int main() {
  int number;
  scanf("%d", &number);
  switch (number) {
  case 10:
    printf("Number is 10\n");
    break;
  case 9:
    printf("Number is 9\n");
  case 8:
    printf("Number is 8\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <log_monitor_init@plt>
  mov    $0x0,%eax
  call   <log_player_init@plt>
  mov    $0x0,%eax
  call   <log_utils_init@plt>
  mov    $0x0,%eax
  call   <log_ui_init@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test();
  log_monitor_init();
  log_player_init();
  log_utils_init();
  log_ui_init();
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <log_monitor_init@plt>
  mov    $0x0,%eax
  call   <log_player_init@plt>
  mov    $0x0,%eax
  call   <log_utils_init@plt>
  mov    $0x0,%eax
  call   <log_ui_init@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  log_monitor_init();
  log_player_init();
  log_utils_init();
  log_ui_init();
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <log_monitor_init@plt>
  xor    %eax,%eax
  call   <log_player_init@plt>
  xor    %eax,%eax
  call   <log_utils_init@plt>
  xor    %eax,%eax
  call   <log_ui_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  log_monitor_init();
  log_player_init();
  log_utils_init();
  log_ui_init();
  ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <log_monitor_init@plt>
  xor    %eax,%eax
  call   <log_player_init@plt>
  xor    %eax,%eax
  call   <log_utils_init@plt>
  xor    %eax,%eax
  call   <log_ui_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  log_monitor_init();
  log_player_init();
  log_utils_init();
  log_ui_init();
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gfx_read_reg16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <READ_REG16@plt>
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned short gfx_read_reg16(unsigned long offset) {
  unsigned short value;
  value = READ_REG16(offset);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gfx_read_reg16>:
  endbr64
  sub    $0x8,%rsp
  call   <READ_REG16@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned short gfx_read_reg16(unsigned long offset) {
  unsigned short value;
  value = READ_REG16(offset);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gfx_read_reg16>:
  endbr64
  jmp    1050 <READ_REG16@plt>
```

assistant: ```c
unsigned short gfx_read_reg16(unsigned long offset) {
  unsigned short value;
  value = READ_REG16(offset);
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gfx_read_reg16>:
  endbr64
  jmp    1050 <READ_REG16@plt>
```

assistant: ```c
unsigned short gfx_read_reg16(unsigned long offset) {
  unsigned short value;
  value = READ_REG16(offset);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<data_print_padd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L2
L5:
  mov    $0x20,%edi
  call   <putchar@plt>
L2:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void data_print_padd(unsigned int i) {
  while (i-- > 0)
    putchar(' ');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<data_print_padd>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%ebx
  test   %edi,%edi
  je     L0
L6:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L6
L0:
  pop    %rbx
  ret
```

assistant: ```c
void data_print_padd(unsigned int i) {
  while (i-- > 0)
    putchar(' ');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<data_print_padd>:
  endbr64
  test   %edi,%edi
  je     L14
  push   %rbx
  lea    -0x1(%rdi),%ebx
  nopl   0x0(%rax)
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L3
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void data_print_padd(unsigned int i) {
  while (i-- > 0)
    putchar(' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<data_print_padd>:
  endbr64
  test   %edi,%edi
  je     L3
  push   %rbx
  lea    -0x1(%rdi),%ebx
  nopl   0x0(%rax)
L4:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L4
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void data_print_padd(unsigned int i) {
  while (i-- > 0)
    putchar(' ');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compte_jusque_lastcharacter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L6:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  ja     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compte_jusque_lastcharacter(char *character, char *lastcharacter) {
  int i = 0;
  int position_lastcharacter = 0;
  while (character + i < lastcharacter) {
    position_lastcharacter++;
    i++;
  }
  return position_lastcharacter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compte_jusque_lastcharacter>:
  endbr64
  cmp    %rsi,%rdi
  jae    L4
  mov    %esi,%ecx
  sub    %edi,%ecx
  mov    $0x0,%edx
L8:
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L8
  mov    %esi,%eax
  sub    %edi,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int compte_jusque_lastcharacter(char *character, char *lastcharacter) {
  int i = 0;
  int position_lastcharacter = 0;
  while (character + i < lastcharacter) {
    position_lastcharacter++;
    i++;
  }
  return position_lastcharacter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compte_jusque_lastcharacter>:
  endbr64
  mov    %esi,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  cmp    %rsi,%rdi
  cmovae %edx,%eax
  ret
```

assistant: ```c
int compte_jusque_lastcharacter(char *character, char *lastcharacter) {
  int i = 0;
  int position_lastcharacter = 0;
  while (character + i < lastcharacter) {
    position_lastcharacter++;
    i++;
  }
  return position_lastcharacter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compte_jusque_lastcharacter>:
  endbr64
  mov    %esi,%eax
  xor    %edx,%edx
  sub    %edi,%eax
  cmp    %rsi,%rdi
  cmovae %edx,%eax
  ret
```

assistant: ```c
int compte_jusque_lastcharacter(char *character, char *lastcharacter) {
  int i = 0;
  int position_lastcharacter = 0;
  while (character + i < lastcharacter) {
    position_lastcharacter++;
    i++;
  }
  return position_lastcharacter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  fldl   -0x8(%rbp)
  frndint
  fstpl  -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double t3(double x) {
  register long double result;
  __asm __volatile("frndint" : "=t"(result) : "0"(x));
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t3>:
  endbr64
  movsd  %xmm0,-0x10(%rsp)
  fldl   -0x10(%rsp)
  frndint
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
double t3(double x) {
  register long double result;
  __asm __volatile("frndint" : "=t"(result) : "0"(x));
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<t3>:
  endbr64
  movsd  %xmm0,-0x10(%rsp)
  fldl   -0x10(%rsp)
  frndint
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
double t3(double x) {
  register long double result;
  __asm __volatile("frndint" : "=t"(result) : "0"(x));
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hpsort_doubledouble>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%r8
  test   %rdi,%rdi
  je     L15
  mov    %rdi,%r9
  shr    %r9
  add    $0x1,%r9
  jmp    L59
L33:
  lea    -0x8(,%rcx,8),%rax
  lea    (%rsi,%rax,1),%rdx
  movsd  (%rdx),%xmm1
  add    %r8,%rax
  movsd  (%rax),%xmm2
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%r8),%xmm0
  movsd  %xmm0,(%rax)
  sub    $0x1,%rcx
  cmp    $0x1,%rcx
  jne    L2
  movsd  %xmm1,(%rsi)
  movsd  %xmm2,(%r8)
  ret
L14:
  lea    0x0(,%rax,8),%rdi
  movsd  -0x8(%rsi,%rdi,1),%xmm0
  comisd %xmm1,%xmm0
  jbe    L98
  shl    $0x3,%rdx
  movsd  %xmm0,-0x8(%rsi,%rdx,1)
  movsd  -0x8(%r8,%rdi,1),%xmm0
  movsd  %xmm0,-0x8(%r8,%rdx,1)
  mov    %rax,%rdx
  add    %rax,%rax
L75:
  cmp    %rcx,%rax
  ja     L88
L20:
  cmp    %rax,%rcx
  jbe    L14
  movsd  (%rsi,%rax,8),%xmm0
  comisd -0x8(%rsi,%rax,8),%xmm0
  jbe    L14
  add    $0x1,%rax
  jmp    L14
L98:
  lea    0x1(%rcx),%rax
  jmp    L75
L22:
  mov    %r9,%rdx
L88:
  shl    $0x3,%rdx
  movsd  %xmm1,-0x8(%rsi,%rdx,1)
  movsd  %xmm2,-0x8(%r8,%rdx,1)
L59:
  cmp    $0x1,%r9
  jbe    L33
  sub    $0x1,%r9
  lea    0x0(,%r9,8),%rax
  movsd  -0x8(%rsi,%rax,1),%xmm1
  movsd  -0x8(%r8,%rax,1),%xmm2
L2:
  lea    (%r9,%r9,1),%rax
  cmp    %rax,%rcx
  jb     L22
  mov    %r9,%rdx
  jmp    L20
L15:
  ret
```

assistant: ```c
void hpsort_doubledouble(unsigned long n, double ra[], double ra2[]) {
  unsigned long i, ir, j, l;
  double rra;
  double rra2;
  if (n < 1)
    return;
  l = (n >> 1) + 1;
  ir = n;
  for (;;) {
    if (l > 1) {
      rra = ra[--l - 1];
      rra2 = ra2[l - 1];
    } else {
      rra = ra[ir - 1];
      rra2 = ra2[ir - 1];
      ra[ir - 1] = ra[0];
      ra2[ir - 1] = ra2[0];
      if (--ir == 1) {
        ra[0] = rra;
        ra2[0] = rra2;
        break;
      }
    }
    i = l;
    j = l + l;
    while (j <= ir) {
      if (j < ir && ra[j - 1] < ra[j])
        j++;
      if (rra < ra[j - 1]) {
        ra[i - 1] = ra[j - 1];
        ra2[i - 1] = ra2[j - 1];
        i = j;
        j <<= 1;
      } else
        j = ir + 1;
    }
    ra[i - 1] = rra;
    ra2[i - 1] = rra2;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hpsort_doubledouble>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r8
  mov    %rdx,%r10
  shr    %rbx
  add    $0x1,%rbx
  cmp    $0x1,%rbx
  je     L26
  nopl   0x0(%rax,%rax,1)
L97:
  sub    $0x1,%rbx
  lea    -0x8(,%rbx,8),%rcx
  lea    (%rbx,%rbx,1),%rax
  lea    (%r8,%rcx,1),%rsi
  add    %r10,%rcx
  movsd  (%rsi),%xmm1
  movsd  (%rcx),%xmm3
L2:
  cmp    %rax,%rdi
  jb     L27
  mov    %rbx,%r11
  jmp    L110
  nopl   (%rax)
L43:
  add    %r10,%rcx
  movsd  %xmm0,(%r9)
  mov    %rax,%r11
  add    %rax,%rax
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rdi,%rax
  ja     L27
L110:
  lea    0x0(,%rax,8),%rdx
  lea    -0x8(%rdx),%rcx
  lea    (%r8,%rcx,1),%rsi
  movsd  (%rsi),%xmm0
  cmp    %rax,%rdi
  jbe    L31
  lea    (%r8,%rdx,1),%r9
  movsd  (%r9),%xmm2
  comisd %xmm0,%xmm2
  jbe    L31
  add    $0x1,%rax
  movapd %xmm2,%xmm0
  mov    %r9,%rsi
  mov    %rdx,%rcx
L31:
  lea    -0x8(,%r11,8),%rdx
  lea    (%r8,%rdx,1),%r9
  add    %r10,%rdx
  comisd %xmm1,%xmm0
  ja     L43
  lea    0x1(%rdi),%rax
  mov    %rdx,%rcx
  mov    %r9,%rsi
  cmp    %rdi,%rax
  jbe    L110
L27:
  movsd  %xmm1,(%rsi)
  movsd  %xmm3,(%rcx)
  cmp    $0x1,%rbx
  jne    L97
L26:
  movsd  (%r8),%xmm0
  lea    -0x8(,%rdi,8),%rax
  sub    $0x1,%rdi
  lea    (%r8,%rax,1),%rdx
  add    %r10,%rax
  movsd  (%rdx),%xmm1
  movsd  (%rax),%xmm3
  movsd  %xmm0,(%rdx)
  movsd  (%r10),%xmm0
  movsd  %xmm0,(%rax)
  cmp    $0x1,%rdi
  je     L89
  mov    %r10,%rcx
  mov    %r8,%rsi
  mov    $0x2,%eax
  jmp    L2
L89:
  movsd  %xmm1,(%r8)
  movsd  %xmm3,(%r10)
  pop    %rbx
  ret
L17:
  ret
```

assistant: ```c
void hpsort_doubledouble(unsigned long n, double ra[], double ra2[]) {
  unsigned long i, ir, j, l;
  double rra;
  double rra2;
  if (n < 1)
    return;
  l = (n >> 1) + 1;
  ir = n;
  for (;;) {
    if (l > 1) {
      rra = ra[--l - 1];
      rra2 = ra2[l - 1];
    } else {
      rra = ra[ir - 1];
      rra2 = ra2[ir - 1];
      ra[ir - 1] = ra[0];
      ra2[ir - 1] = ra2[0];
      if (--ir == 1) {
        ra[0] = rra;
        ra2[0] = rra2;
        break;
      }
    }
    i = l;
    j = l + l;
    while (j <= ir) {
      if (j < ir && ra[j - 1] < ra[j])
        j++;
      if (rra < ra[j - 1]) {
        ra[i - 1] = ra[j - 1];
        ra2[i - 1] = ra2[j - 1];
        i = j;
        j <<= 1;
      } else
        j = ir + 1;
    }
    ra[i - 1] = rra;
    ra2[i - 1] = rra2;
  }
}
```