ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ckfread>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x1,%edx
  call   <fread@plt>
  test   %eax,%eax
  jle    L8
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L8:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: fread non riuscita

assistant: ```c
void ckfread(void *ptr, size_t size, FILE *stream) {
  if (fread(ptr, size, 1, stream) < 1) {
    perror("fread non riuscita");
    exit(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ckfread>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x1,%edx
  call   <fread@plt>
  test   %eax,%eax
  jle    L5
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L5:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: fread non riuscita

assistant: ```c
void ckfread(void *ptr, size_t size, FILE *stream) {
  if (fread(ptr, size, 1, stream) < 1) {
    perror("fread non riuscita");
    exit(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L50
  mov    D27(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L24
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L28
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L8
L28:
  mov    $0x3,%eax
  jmp    L8
L24:
  mov    $0x2,%eax
  jmp    L8
L50:
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (stdin != NULL)
    if (stderr != NULL)
      if (stdout != NULL)
        return EXIT_SUCCESS;
      else
        return 3;
    else
      return 2;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    D38(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L5
  mov    D19(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L18
  mov    D1(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L14
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  ret
L5:
  mov    $0x1,%eax
  ret
L18:
  mov    $0x2,%eax
  ret
L14:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  if (stdin != NULL)
    if (stderr != NULL)
      if (stdout != NULL)
        return EXIT_SUCCESS;
      else
        return 3;
    else
      return 2;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    D8(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L0
  mov    D23(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L4
  mov    D21(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L13
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L13:
  mov    $0x3,%eax
  ret
L4:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  if (stdin != NULL)
    if (stderr != NULL)
      if (stdout != NULL)
        return EXIT_SUCCESS;
      else
        return 3;
    else
      return 2;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    D1(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L17
  mov    D10(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L29
  mov    D37(%rip),%rax
  cmpq   $0x0,(%rax)
  je     L9
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  ret
L17:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x3,%eax
  ret
L29:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  if (stdin != NULL)
    if (stderr != NULL)
      if (stdout != NULL)
        return EXIT_SUCCESS;
      else
        return 3;
    else
      return 2;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<first_instance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  movl   $0x0,-0x4(%rbp)
L46:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%eax
  jmp    L27
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  jmp    L46
L12:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    $0xffffffff,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int first_instance(char *A, char *B) {
  int pos = 0, off;
  do {
    if (*(A + pos) == *(B)) {
      off = 0;
      do {
        off++;
        if (*(B + off) == '\0')
          return pos;
        if (*(A + pos + off) != *(B + off) || *(A + pos + off) == '\0')
          break;
      } while (1);
    }
    pos++;
  } while (*(A + pos) != '\0');
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<first_instance>:
  endbr64
  movzbl (%rsi),%r11d
  mov    $0x0,%edx
  jmp    L51
L15:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L3
L51:
  mov    %edx,%r10d
  cmp    %r11b,(%rdi,%rdx,1)
  jne    L15
  mov    $0x1,%eax
  lea    (%rdi,%rdx,1),%r9
L5:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L19
  movzbl (%r9,%rax,1),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  je     L15
  cmp    %r8b,%cl
  je     L5
  jmp    L15
L3:
  mov    $0xffffffff,%r10d
L19:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int first_instance(char *A, char *B) {
  int pos = 0, off;
  do {
    if (*(A + pos) == *(B)) {
      off = 0;
      do {
        off++;
        if (*(B + off) == '\0')
          return pos;
        if (*(A + pos + off) != *(B + off) || *(A + pos + off) == '\0')
          break;
      } while (1);
    }
    pos++;
  } while (*(A + pos) != '\0');
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<first_instance>:
  endbr64
  movzbl (%rsi),%r10d
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  jmp    L42
  nop
L50:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L27
L42:
  mov    %ecx,%r9d
  cmp    %al,%r10b
  jne    L50
  mov    $0x1,%eax
  lea    (%rdi,%rcx,1),%r8
  jmp    L56
  nop
L44:
  add    $0x1,%rax
  cmp    -0x1(%r8,%rax,1),%dl
  jne    L50
L56:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L44
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int first_instance(char *A, char *B) {
  int pos = 0, off;
  do {
    if (*(A + pos) == *(B)) {
      off = 0;
      do {
        off++;
        if (*(B + off) == '\0')
          return pos;
        if (*(A + pos + off) != *(B + off) || *(A + pos + off) == '\0')
          break;
      } while (1);
    }
    pos++;
  } while (*(A + pos) != '\0');
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<first_instance>:
  endbr64
  movzbl (%rsi),%r10d
  xor    %edx,%edx
  jmp    L31
  nopl   0x0(%rax)
L51:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L36
L31:
  mov    %edx,%r9d
  cmp    %r10b,(%rdi,%rdx,1)
  jne    L51
  mov    $0x1,%eax
  lea    (%rdi,%rdx,1),%r8
  jmp    L54
  xchg   %ax,%ax
L28:
  add    $0x1,%rax
  cmp    -0x1(%r8,%rax,1),%cl
  jne    L51
L54:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L28
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0xffffffff,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int first_instance(char *A, char *B) {
  int pos = 0, off;
  do {
    if (*(A + pos) == *(B)) {
      off = 0;
      do {
        off++;
        if (*(B + off) == '\0')
          return pos;
        if (*(A + pos + off) != *(B + off) || *(A + pos + off) == '\0')
          break;
      } while (1);
    }
    pos++;
  } while (*(A + pos) != '\0');
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_append_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x15a,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int solcon_append_dobldobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc4c(346, a, b, sol, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<solcon_append_dobldobl_solution>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdx
  mov    $0x0,%r8d
  mov    $0x0,%esi
  mov    $0x15a,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_dobldobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc4c(346, a, b, sol, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_append_dobldobl_solution>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %edi,(%rsp)
  mov    $0x15a,%edi
  mov    %esi,0x4(%rsp)
  xor    %esi,%esi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_dobldobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc4c(346, a, b, sol, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_append_dobldobl_solution>:
  endbr64
  sub    $0x18,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  mov    %rdx,%rcx
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rdx
  xor    %r8d,%r8d
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x15a,%edi
  movq   %xmm0,(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_dobldobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc4c(346, a, b, sol, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x60(%rbp),%eax
  cmp    $0xe,%eax
  jg     L37
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L28
L40:
  lea    -0x50(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x54(%rbp)
L28:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jle    L40
  jmp    L3
L37:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x58(%rbp),%rdx
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x58(%rbp),%xmm0
  mov    -0x5c(%rbp),%ecx
  mov    -0x60(%rbp),%eax
  lea    -0x50(%rbp),%rdx
  movaps %xmm0,%xmm1
  movd   %ecx,%xmm0
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <calculatePolynomRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D33
datatype: string
name: read_data
arguments: data_tag: D39
datatype: string
name: read_data
arguments: data_tag: D49
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D70
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string

tool: D38: Grau do polinomio: 

tool: D33: %d

tool: D39: Coeficientes do polinomio: 

tool: D49: %f

tool: D21: Grau do polinomio muito elevado!

tool: D70: 
Intervalo Desejado: 

tool: D31: %f %f

tool: D10: 
A raiz no intervalo e: %f

assistant: ```c
int main(void) {
  int level, currentCoefficient;
  float polynomialEquation[15], intervalBeginning, intervalEnding;
  printf("Grau do polinomio: ");
  scanf("%d", &level);
  if (level < 15) {
    printf("Coeficientes do polinomio: ");
    for (currentCoefficient = 0; currentCoefficient <= level; currentCoefficient++)
      scanf("%f", &polynomialEquation[currentCoefficient]);
  } else
    printf("Grau do polinomio muito elevado!");
  printf("\nIntervalo Desejado: ");
  scanf("%f %f", &intervalBeginning, &intervalEnding);
  printf("\nA raiz no intervalo e: %f", calculatePolynomRoot(level, polynomialEquation, intervalBeginning, intervalEnding));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0xe,0x4(%rsp)
  jg     L30
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  js     L3
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L49:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jge    L49
  jmp    L3
L30:
  lea    D73(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  mov    0x4(%rsp),%edi
  call   <calculatePolynomRoot@plt>
  lea    D33(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D34
type: string
name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D43
type: string
name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D73
type: string
name: parse_data
arguments: label: D56
type: string
name: parse_data
arguments: label: D20
type: string
name: parse_data
arguments: label: D33
type: string

tool: D34: Grau do polinomio: 

tool: D14: %d

tool: D43: Coeficientes do polinomio: 

tool: D2: %f

tool: D73: Grau do polinomio muito elevado!

tool: D56: 
Intervalo Desejado: 

tool: D20: %f %f

tool: D33: 
A raiz no intervalo e: %f

assistant: ```c
int main(void) {
  int level, currentCoefficient;
  float polynomialEquation[15], intervalBeginning, intervalEnding;
  printf("Grau do polinomio: ");
  scanf("%d", &level);
  if (level < 15) {
    printf("Coeficientes do polinomio: ");
    for (currentCoefficient = 0; currentCoefficient <= level; currentCoefficient++)
      scanf("%f", &polynomialEquation[currentCoefficient]);
  } else
    printf("Grau do polinomio muito elevado!");
  printf("\nIntervalo Desejado: ");
  scanf("%f %f", &intervalBeginning, &intervalEnding);
  printf("\nA raiz no intervalo e: %f", calculatePolynomRoot(level, polynomialEquation, intervalBeginning, intervalEnding));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0xe,0x4(%rsp)
  jg     L13
  xor    %eax,%eax
  lea    D75(%rip),%rdi
  lea    0x10(%rsp),%r13
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  js     L28
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D20(%rip),%r12
  xchg   %ax,%ax
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jge    L4
L28:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D70(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  movss  0xc(%rsp),%xmm1
  mov    %r13,%rsi
  movss  0x8(%rsp),%xmm0
  call   <calculatePolynomRoot@plt>
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <printf@plt>
  jmp    L28
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D53
type: string
name: parse_data
arguments: data_label: D75
type: string
name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D27
type: string
name: parse_data
arguments: data_label: D70
type: string
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D32
type: string

tool: D10: Grau do polinomio: 

tool: D53: %d

tool: D75: Coeficientes do polinomio: 

tool: D20: %f

tool: D27: 
Intervalo Desejado: 

tool: D70: %f %f

tool: D22: 
A raiz no intervalo e: %f

tool: D32: Grau do polinomio muito elevado!

assistant: ```c
int main(void) {
  int level, currentCoefficient;
  float polynomialEquation[15], intervalBeginning, intervalEnding;
  printf("Grau do polinomio: ");
  scanf("%d", &level);
  if (level < 15) {
    printf("Coeficientes do polinomio: ");
    for (currentCoefficient = 0; currentCoefficient <= level; currentCoefficient++)
      scanf("%f", &polynomialEquation[currentCoefficient]);
  } else
    printf("Grau do polinomio muito elevado!");
  printf("\nIntervalo Desejado: ");
  scanf("%f %f", &intervalBeginning, &intervalEnding);
  printf("\nA raiz no intervalo e: %f", calculatePolynomRoot(level, polynomialEquation, intervalBeginning, intervalEnding));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D73(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0xe,0x4(%rsp)
  jg     L32
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  lea    0x10(%rsp),%r13
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  js     L19
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D52(%rip),%r12
  xchg   %ax,%ax
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jge    L14
L19:
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D78(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  movss  0xc(%rsp),%xmm1
  mov    %r13,%rsi
  movss  0x8(%rsp),%xmm0
  call   <calculatePolynomRoot@plt>
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <printf@plt>
  jmp    L19
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D73
datatype: string
name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D52
datatype: string
name: disassemble_data
arguments: data_label: D42
datatype: string
name: disassemble_data
arguments: data_label: D78
datatype: string
name: disassemble_data
arguments: data_label: D43
datatype: string
name: disassemble_data
arguments: data_label: D51
datatype: string

tool: D73: Grau do polinomio: 

tool: D24: %d

tool: D5: Coeficientes do polinomio: 

tool: D52: %f

tool: D42: 
Intervalo Desejado: 

tool: D78: %f %f

tool: D43: 
A raiz no intervalo e: %f

tool: D51: Grau do polinomio muito elevado!

assistant: ```c
int main(void) {
  int level, currentCoefficient;
  float polynomialEquation[15], intervalBeginning, intervalEnding;
  printf("Grau do polinomio: ");
  scanf("%d", &level);
  if (level < 15) {
    printf("Coeficientes do polinomio: ");
    for (currentCoefficient = 0; currentCoefficient <= level; currentCoefficient++)
      scanf("%f", &polynomialEquation[currentCoefficient]);
  } else
    printf("Grau do polinomio muito elevado!");
  printf("\nIntervalo Desejado: ");
  scanf("%f %f", &intervalBeginning, &intervalEnding);
  printf("\nA raiz no intervalo e: %f", calculatePolynomRoot(level, polynomialEquation, intervalBeginning, intervalEnding));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  cmp    $0x3,%eax
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  cmp    $0x3,%eax
  jne    L8
  nop
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f3(int a) {
  switch (!!a) {
  case 3:
    break;
  }
  switch (!a) {
  case 3:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(int a) {
  switch (!!a) {
  case 3:
    break;
  }
  switch (!a) {
  case 3:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(int a) {
  switch (!!a) {
  case 3:
    break;
  }
  switch (!a) {
  case 3:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f3>:
  endbr64
  ret
```

assistant: ```c
void f3(int a) {
  switch (!!a) {
  case 3:
    break;
  }
  switch (!a) {
  case 3:
    break;
  }
}
```