ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_memcmp>:
  endbr64
  push   %r12
  mov    $0xa09,%edx
  mov    $0xb09,%ecx
  lea    D1(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x807060504030201,%rax
  lea    0xe(%rsp),%r12
  lea    0x4(%rsp),%rbp
  mov    %dx,0xc(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0xe(%rsp)
  call   <printf@plt>
  mov    $0x9,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L26
L6:
  mov    $0x1,%eax
L12:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L6
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L12
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D1: 	memcmp

tool: D3: 	passed.


assistant: ```c
int test_memcmp(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 11};
  printf("\tmemcmp");
  if (memcmp(value0, value1, 9) != 0)
    return 1;
  if (memcmp(value0, value1, 10) == 0)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_memcmp>:
  endbr64
  push   %r12
  mov    $0xa09,%edx
  mov    $0xb09,%ecx
  lea    D4(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x807060504030201,%rax
  lea    0xe(%rsp),%r12
  lea    0x4(%rsp),%rbp
  mov    %dx,0xc(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0xe(%rsp)
  call   <printf@plt>
  mov    $0x9,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L4
L16:
  mov    $0x1,%eax
L33:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L16
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L33
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D4: 	memcmp

tool: D10: 	passed.


assistant: ```c
int test_memcmp(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 11};
  printf("\tmemcmp");
  if (memcmp(value0, value1, 9) != 0)
    return 1;
  if (memcmp(value0, value1, 10) == 0)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<formatHashValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <binaryLog2@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L37
L19:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x8(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L19
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void formatHashValue(int value, char formattedString[], int bitsPerPosition) {
  int length, i;
  length = binaryLog2(value);
  for (i = 0; i < bitsPerPosition - length; i++) {
    formattedString[i] = '0';
  }
  for (i = bitsPerPosition - 1; i > bitsPerPosition - length - 1; i--) {
    formattedString[i] = (value % 2) + '0';
    value = value / 10;
  }
  formattedString[bitsPerPosition] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<formatHashValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %edx,%ebp
  call   <binaryLog2@plt>
  mov    %ebp,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L34
  mov    %r12,%rax
  lea    -0x1(%rcx),%edx
  lea    0x1(%r12,%rdx,1),%rdx
L5:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L34:
  lea    -0x1(%rbp),%edx
  cmp    %ecx,%edx
  jl     L33
  movslq %edx,%rdx
  add    %r12,%rdx
  movslq %ebp,%rax
  lea    -0x2(%r12,%rax,1),%rdi
  lea    -0x1(%rbp),%eax
  sub    %ecx,%eax
  sub    %rax,%rdi
L25:
  mov    %ebx,%esi
  sar    $0x1f,%esi
  mov    %ebx,%ecx
  shr    $0x1f,%ecx
  lea    (%rbx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %al,(%rdx)
  movslq %ebx,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  sub    %esi,%ebx
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L25
L33:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void formatHashValue(int value, char formattedString[], int bitsPerPosition) {
  int length, i;
  length = binaryLog2(value);
  for (i = 0; i < bitsPerPosition - length; i++) {
    formattedString[i] = '0';
  }
  for (i = bitsPerPosition - 1; i > bitsPerPosition - length - 1; i--) {
    formattedString[i] = (value % 2) + '0';
    value = value / 10;
  }
  formattedString[bitsPerPosition] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<formatHashValue>:
  endbr64
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %r12d,%r13d
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <binaryLog2@plt>
  sub    %eax,%r13d
  test   %r13d,%r13d
  jle    L14
  movslq %r13d,%rdx
  mov    $0x30,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L14:
  lea    -0x1(%r12),%eax
  cmp    %r13d,%eax
  jl     L25
  movslq %eax,%rdx
  lea    -0x2(%rbp,%r12,1),%rdi
  sub    %r13d,%eax
  add    %rbp,%rdx
  sub    %rax,%rdi
  nopl   0x0(%rax)
L18:
  mov    %ebx,%ecx
  mov    %ebx,%esi
  sub    $0x1,%rdx
  shr    $0x1f,%ecx
  sar    $0x1f,%esi
  lea    (%rbx,%rcx,1),%eax
  movslq %ebx,%rbx
  imul   $0x66666667,%rbx,%rbx
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  sar    $0x22,%rbx
  mov    %al,0x1(%rdx)
  sub    %esi,%ebx
  cmp    %rdi,%rdx
  jne    L18
L25:
  movb   $0x0,0x0(%rbp,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void formatHashValue(int value, char formattedString[], int bitsPerPosition) {
  int length, i;
  length = binaryLog2(value);
  for (i = 0; i < bitsPerPosition - length; i++) {
    formattedString[i] = '0';
  }
  for (i = bitsPerPosition - 1; i > bitsPerPosition - length - 1; i--) {
    formattedString[i] = (value % 2) + '0';
    value = value / 10;
  }
  formattedString[bitsPerPosition] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<formatHashValue>:
  endbr64
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %r12d,%r13d
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <binaryLog2@plt>
  sub    %eax,%r13d
  test   %r13d,%r13d
  jle    L22
  movslq %r13d,%rdx
  mov    $0x30,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L22:
  lea    -0x1(%r12),%eax
  cmp    %r13d,%eax
  jl     L7
  movslq %eax,%rdx
  lea    -0x2(%rbp,%r12,1),%rdi
  sub    %r13d,%eax
  add    %rbp,%rdx
  sub    %rax,%rdi
  nopl   0x0(%rax)
L26:
  mov    %ebx,%ecx
  mov    %ebx,%esi
  sub    $0x1,%rdx
  shr    $0x1f,%ecx
  sar    $0x1f,%esi
  lea    (%rbx,%rcx,1),%eax
  movslq %ebx,%rbx
  imul   $0x66666667,%rbx,%rbx
  and    $0x1,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  sar    $0x22,%rbx
  mov    %al,0x1(%rdx)
  sub    %esi,%ebx
  cmp    %rdx,%rdi
  jne    L26
L7:
  movb   $0x0,0x0(%rbp,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void formatHashValue(int value, char formattedString[], int bitsPerPosition) {
  int length, i;
  length = binaryLog2(value);
  for (i = 0; i < bitsPerPosition - length; i++) {
    formattedString[i] = '0';
  }
  for (i = bitsPerPosition - 1; i > bitsPerPosition - length - 1; i--) {
    formattedString[i] = (value % 2) + '0';
    value = value / 10;
  }
  formattedString[bitsPerPosition] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_last_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L2
L14:
  cmpl   $0x1,-0x4(%rbp)
  jne    L24
  mov    $0x1,%eax
  jmp    L2
L24:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sum_last_bits>
  add    %eax,%eax
  add    $0x1,%eax
L2:
  leave
  ret
```

assistant: ```c
int sum_last_bits(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return 2 * (sum_last_bits(n - 1)) + 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_last_bits>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L15
  cmp    $0x1,%edi
  jne    L6
L15:
  ret
L6:
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%edi
  call   <sum_last_bits>
  lea    0x1(%rax,%rax,1),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sum_last_bits(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return 2 * (sum_last_bits(n - 1)) + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_last_bits>:
  endbr64
  test   %edi,%edi
  je     L29
  cmp    $0x1,%edi
  je     L5
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L27:
  cmp    $0x1,%edi
  je     L49
L19:
  mov    %eax,%edx
  add    %eax,%eax
  add    %edx,%r8d
  sub    $0x1,%edi
  jne    L27
L54:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L49:
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
L29:
  xor    %r8d,%r8d
  jmp    L54
L5:
  mov    $0x1,%r8d
  jmp    L54
```

assistant: ```c
int sum_last_bits(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return 2 * (sum_last_bits(n - 1)) + 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_last_bits>:
  endbr64
  test   %edi,%edi
  je     L50
  cmp    $0x1,%edi
  je     L32
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    $0x1,%edi
  je     L5
L56:
  mov    %eax,%edx
  add    %eax,%eax
  add    %edx,%r8d
  sub    $0x1,%edi
  jne    L1
L17:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L5:
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
L50:
  xor    %r8d,%r8d
  jmp    L17
L32:
  mov    $0x1,%r8d
  jmp    L17
```

assistant: ```c
int sum_last_bits(int n) {
  if (n == 0) {
    return 0;
  } else if (n == 1) {
    return 1;
  } else {
    return 2 * (sum_last_bits(n - 1)) + 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x8(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd D2(%rip),%xmm0
  jb     L1
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: f64

tool: D2: 0.5

assistant: ```c
long round(double value) {
  long intpart;
  intpart = (long)value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D0(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: f64

tool: D0: 0.5

assistant: ```c
long round(double value) {
  long intpart;
  intpart = (long)value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D1(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: f64

tool: D1: 0.5

assistant: ```c
long round(double value) {
  long intpart;
  intpart = (long)value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D4(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: f64

tool: D4: 0.5

assistant: ```c
long round(double value) {
  long intpart;
  intpart = (long)value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<runq_dispatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L37:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <run_one@plt>
  test   %rax,%rax
  jle    L20
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x0,-0x1c(%rbp)
  je     L37
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L37
  jmp    L17
L20:
  nop
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int runq_dispatch(struct runq *r, unsigned int limit) {
  int count = 0;
  while (!limit || (count < limit)) {
    if (run_one(r) <= 0)
      break;
    count++;
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<runq_dispatch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  lea    -0x1(%rsi),%r13d
  mov    $0x0,%ebx
L14:
  mov    %ebx,%ebp
  mov    %r12,%rdi
  call   <run_one@plt>
  test   %rax,%rax
  jle    L17
  add    $0x1,%ebx
  mov    %ebx,%ebp
  cmp    %r13d,%ebx
  jbe    L14
L17:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int runq_dispatch(struct runq *r, unsigned int limit) {
  int count = 0;
  while (!limit || (count < limit)) {
    if (run_one(r) <= 0)
      break;
    count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<runq_dispatch>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  ja     L23
L14:
  mov    %rbx,%rdi
  call   <run_one@plt>
  test   %rax,%rax
  jg     L7
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int runq_dispatch(struct runq *r, unsigned int limit) {
  int count = 0;
  while (!limit || (count < limit)) {
    if (run_one(r) <= 0)
      break;
    count++;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<runq_dispatch>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  ja     L25
L6:
  mov    %rbx,%rdi
  call   <run_one@plt>
  test   %rax,%rax
  jg     L10
L25:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int runq_dispatch(struct runq *r, unsigned int limit) {
  int count = 0;
  while (!limit || (count < limit)) {
    if (run_one(r) <= 0)
      break;
    count++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int p2(int *a, int *b) {
  int c;
  c = *a;
  *a = *b;
  *b = c + 1;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<p2>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  lea    0x1(%rax),%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int p2(int *a, int *b) {
  int c;
  c = *a;
  *a = *b;
  *b = c + 1;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<p2>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  lea    0x1(%rax),%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int p2(int *a, int *b) {
  int c;
  c = *a;
  *a = *b;
  *b = c + 1;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L35
L39:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L21
L8:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L8
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L35:
  cmpl   $0x5,-0xc(%rbp)
  jle    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string

tool: D22: Que numero triangular quieres: 

tool: D13: %i

tool: D15: Numero triangular %i es %i



assistant: ```c
int main(void) {
  int n, numero, numeroTriangular, contador;
  for (contador = 1; contador <= 5; contador++) {
    printf("Que numero triangular quieres: ");
    scanf("%i", &numero);
    numeroTriangular = 0;
    for (n = 1; n <= numero; n++) {
      numeroTriangular += n;
    }
    printf("Numero triangular %i es %i\n\n", numero, numeroTriangular);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x5,%ebx
  lea    D18(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D13(%rip),%r12
  lea    D11(%rip),%rbp
L24:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L17
  lea    0x1(%rsi),%ecx
  mov    $0x0,%edx
  mov    $0x1,%eax
L9:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L9
L15:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L24
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0x0,%edx
  jmp    L15
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D11
type: string

tool: D18: Que numero triangular quieres: 

tool: D13: %i

tool: D11: Numero triangular %i es %i



assistant: ```c
int main(void) {
  int n, numero, numeroTriangular, contador;
  for (contador = 1; contador <= 5; contador++) {
    printf("Que numero triangular quieres: ");
    scanf("%i", &numero);
    numeroTriangular = 0;
    for (n = 1; n <= numero; n++) {
      numeroTriangular += n;
    }
    printf("Numero triangular %i es %i\n\n", numero, numeroTriangular);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
L20:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L35
  lea    0x1(%rsi),%ecx
  xor    %edx,%edx
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L27:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L27
L19:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  xor    %edx,%edx
  jmp    L19
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string

tool: D7: Que numero triangular quieres: 

tool: D19: %i

tool: D5: Numero triangular %i es %i



assistant: ```c
int main(void) {
  int n, numero, numeroTriangular, contador;
  for (contador = 1; contador <= 5; contador++) {
    printf("Que numero triangular quieres: ");
    scanf("%i", &numero);
    numeroTriangular = 0;
    for (n = 1; n <= numero; n++) {
      numeroTriangular += n;
    }
    printf("Numero triangular %i es %i\n\n", numero, numeroTriangular);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cptp_check_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L3
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L9
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char cptp_check_sum(unsigned char *b, size_t s) {
  unsigned char sum = 0;
  while (s--) {
    sum = sum + (*b);
    b++;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cptp_check_sum>:
  endbr64
  test   %rsi,%rsi
  je     L2
  add    %rdi,%rsi
  mov    $0x0,%eax
L11:
  add    (%rdi),%al
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L11
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char cptp_check_sum(unsigned char *b, size_t s) {
  unsigned char sum = 0;
  while (s--) {
    sum = sum + (*b);
    b++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cptp_check_sum>:
  endbr64
  test   %rsi,%rsi
  je     L16
  add    %rdi,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L13:
  add    (%rdi),%al
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L13
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char cptp_check_sum(unsigned char *b, size_t s) {
  unsigned char sum = 0;
  while (s--) {
    sum = sum + (*b);
    b++;
  }
  return sum;
}
```