ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %edx,%r12d
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L45
L49:
  mov    $0x0,%ebx
  lea    D14(%rip),%r15
  jmp    L79
L45:
  mov    %r14,%rsi
  lea    D28(%rip),%rdi
  call   <die@plt>
  jmp    L49
L63:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <die@plt>
L79:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L0
  mov    %r12d,%edx
  sub    %ebx,%edx
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  add    %rax,%rbx
  mov    %rbp,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L63
  mov    %r12d,%eax
  cmp    %rbx,%rax
  jne    L79
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L79
  jmp    L63
L0:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string

tool: D4: r

tool: D14: Error reading %s

tool: D28: Couldn't open %s

assistant: ```c
size_t read_file(const char *file, void *buf, unsigned buflen) {
  FILE *fp = fopen(file, "r");
  size_t size = 0;
  if (fp == NULL)
    die("Couldn't open %s", file);
  while (!feof(fp)) {
    size += fread(buf + size, 1, buflen - size, fp);
    if (ferror(fp) || (size == buflen && !feof(fp)))
      die("Error reading %s", file);
  }
  fclose(fp);
  return size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_file>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D8(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L56
L8:
  xor    %r12d,%r12d
  lea    D9(%rip),%r15
  nopl   0x0(%rax)
L40:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L18
L43:
  mov    %ebx,%edx
  lea    0x0(%r13,%r12,1),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  sub    %r12d,%edx
  call   <fread@plt>
  mov    %rbp,%rdi
  add    %rax,%r12
  call   <ferror@plt>
  test   %rax,%rax
  jne    L53
  mov    %ebx,%eax
  cmp    %r12,%rax
  jne    L40
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L40
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %r15,%rdi
  mov    %r14,%rsi
  call   <die@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L43
L18:
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L56:
  mov    %r14,%rsi
  lea    D5(%rip),%rdi
  call   <die@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D8: r

tool: D9: Error reading %s

tool: D5: Couldn't open %s

assistant: ```c
size_t read_file(const char *file, void *buf, unsigned buflen) {
  FILE *fp = fopen(file, "r");
  size_t size = 0;
  if (fp == NULL)
    die("Couldn't open %s", file);
  while (!feof(fp)) {
    size += fread(buf + size, 1, buflen - size, fp);
    if (ferror(fp) || (size == buflen && !feof(fp)))
      die("Error reading %s", file);
  }
  fclose(fp);
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_file>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D24(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
L22:
  xor    %r12d,%r12d
  lea    D0(%rip),%r15
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L10
L62:
  mov    %ebx,%edx
  lea    0x0(%r13,%r12,1),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  sub    %r12d,%edx
  call   <fread@plt>
  mov    %rbp,%rdi
  add    %rax,%r12
  call   <ferror@plt>
  test   %rax,%rax
  jne    L23
  mov    %ebx,%eax
  cmp    %r12,%rax
  jne    L19
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L19
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %r15,%rdi
  mov    %r14,%rsi
  call   <die@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L62
L10:
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  mov    %r14,%rsi
  lea    D13(%rip),%rdi
  call   <die@plt>
  jmp    L22
```

tool_calls: name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D24: r

tool: D0: Error reading %s

tool: D13: Couldn't open %s

assistant: ```c
size_t read_file(const char *file, void *buf, unsigned buflen) {
  FILE *fp = fopen(file, "r");
  size_t size = 0;
  if (fp == NULL)
    die("Couldn't open %s", file);
  while (!feof(fp)) {
    size += fread(buf + size, 1, buflen - size, fp);
    if (ferror(fp) || (size == buflen && !feof(fp)))
      die("Error reading %s", file);
  }
  fclose(fp);
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strduplicate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L24:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  test   %rax,%rax
  je     L5
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L5:
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x64,-0xc(%rbp)
  jle    L24
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strduplicate(char *inp) {
  char *dup = NULL;
  int i;
  for (i = 0; i <= 100; ++i) {
    if ((inp + 1) != NULL)
      *(dup + i) = *(inp + i);
  }
  return dup;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strduplicate>:
  endbr64
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    $0x65,%rax
  jne    L5
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strduplicate(char *inp) {
  char *dup = NULL;
  int i;
  for (i = 0; i <= 100; ++i) {
    if ((inp + 1) != NULL)
      *(dup + i) = *(inp + i);
  }
  return dup;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strduplicate>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    $0x65,%rax
  jne    L8
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strduplicate(char *inp) {
  char *dup = NULL;
  int i;
  for (i = 0; i <= 100; ++i) {
    if ((inp + 1) != NULL)
      *(dup + i) = *(inp + i);
  }
  return dup;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strduplicate>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    $0x65,%rax
  jne    L1
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strduplicate(char *inp) {
  char *dup = NULL;
  int i;
  for (i = 0; i <= 100; ++i) {
    if ((inp + 1) != NULL)
      *(dup + i) = *(inp + i);
  }
  return dup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uStrCasePrefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L44
L39:
  movsbl -0x2(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L22
  movsbl -0x2(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x2(%rbp)
L22:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L0
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
L0:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L60
  mov    $0x0,%eax
  jmp    L76
L60:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  cmpb   $0x0,-0x2(%rbp)
  je     L71
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L39
L71:
  cmpb   $0x0,-0x2(%rbp)
  je     L51
  mov    $0x0,%eax
  jmp    L76
L51:
  mov    $0x1,%eax
L76:
  leave
  ret
```

assistant: ```c
int uStrCasePrefix(char *prefix, char *str) {
  char c1;
  char c2;
  while (((c1 = *prefix) != '\0') && ((c2 = *str) != '\0')) {
    if (isupper(c1))
      c1 = tolower(c1);
    if (isupper(c2))
      c2 = tolower(c2);
    if (c1 != c2)
      return 0;
    prefix++;
    str++;
  }
  if (c1 != '\0')
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uStrCasePrefix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  movzbl (%rdi),%ebx
  test   %bl,%bl
  jne    L62
L38:
  test   %bl,%bl
  sete   %al
  movzbl %al,%eax
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  jmp    L43
L81:
  cmp    %bpl,%bl
  jne    L26
  add    $0x1,%r12
  add    $0x1,%r13
  movzbl (%r12),%ebx
  test   %bl,%bl
  je     L38
L62:
  movzbl 0x0(%r13),%ebp
  test   %bpl,%bpl
  je     L38
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L56
L43:
  movsbl %bpl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L81
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  jmp    L81
L26:
  mov    $0x0,%eax
  jmp    L61
```

assistant: ```c
int uStrCasePrefix(char *prefix, char *str) {
  char c1;
  char c2;
  while (((c1 = *prefix) != '\0') && ((c2 = *str) != '\0')) {
    if (isupper(c1))
      c1 = tolower(c1);
    if (isupper(c2))
      c2 = tolower(c2);
    if (c1 != c2)
      return 0;
    prefix++;
    str++;
  }
  if (c1 != '\0')
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uStrCasePrefix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  jne    L58
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L16:
  movsbl %bpl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L70
  cmp    %bpl,%bl
  jne    L18
L38:
  movzbl 0x1(%r12),%ebx
  add    $0x1,%r12
  add    $0x1,%r13
  test   %bl,%bl
  je     L32
L58:
  movzbl 0x0(%r13),%ebp
  test   %bpl,%bpl
  je     L18
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L16
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  jmp    L16
  nop
L70:
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  cmp    %bpl,%bl
  je     L38
L18:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int uStrCasePrefix(char *prefix, char *str) {
  char c1;
  char c2;
  while (((c1 = *prefix) != '\0') && ((c2 = *str) != '\0')) {
    if (isupper(c1))
      c1 = tolower(c1);
    if (isupper(c2))
      c2 = tolower(c2);
    if (c1 != c2)
      return 0;
    prefix++;
    str++;
  }
  if (c1 != '\0')
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uStrCasePrefix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  jne    L49
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl %bpl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L28
  cmp    %bpl,%bl
  jne    L34
L57:
  movzbl 0x1(%r12),%ebx
  add    $0x1,%r12
  add    $0x1,%r13
  test   %bl,%bl
  je     L60
L49:
  movzbl 0x0(%r13),%ebp
  test   %bpl,%bpl
  je     L34
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L35
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  jmp    L35
  nop
L28:
  mov    %r14d,%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  cmp    %bpl,%bl
  je     L57
L34:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int uStrCasePrefix(char *prefix, char *str) {
  char c1;
  char c2;
  while (((c1 = *prefix) != '\0') && ((c2 = *str) != '\0')) {
    if (isupper(c1))
      c1 = tolower(c1);
    if (isupper(c2))
      c2 = tolower(c2);
    if (c1 != c2)
      return 0;
    prefix++;
    str++;
  }
  if (c1 != '\0')
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_wattroff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L4
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  lea    D37(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L61
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L14
L61:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x14(%rbp),%rdx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L46
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L14
L46:
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L14
L4:
  nop
L14:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D37: %p

tool: D20: BAD ARGUMENT

tool: D4: %d

assistant: ```c
void cmd_wattroff(int nargs, char **args) {
  WINDOW *win;
  int attr;
  if (check_arg_count(nargs, 2) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &attr) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(wattroff(win, attr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_wattroff>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x2,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L57
  lea    0x10(%rsp),%rdx
  lea    D28(%rip),%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L38
  lea    0xc(%rsp),%rdx
  mov    0x8(%rbx),%rdi
  lea    D27(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L6
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <wattroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L57:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x20,%rsp
  pop    %rbx
  ret
L38:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D21(%rip),%rdi
  call   <report_error@plt>
  jmp    L57
L6:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D21(%rip),%rdi
  call   <report_error@plt>
  jmp    L57
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: string

tool: D28: %p

tool: D27: %d

tool: D21: BAD ARGUMENT

assistant: ```c
void cmd_wattroff(int nargs, char **args) {
  WINDOW *win;
  int attr;
  if (check_arg_count(nargs, 2) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &attr) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(wattroff(win, attr));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_wattroff>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L30
  mov    (%rbx),%rdi
  lea    0x10(%rsp),%rdx
  lea    D21(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L28
  mov    0x8(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  lea    D19(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L28
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <wattroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  call   <report_error@plt>
  jmp    L30
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D21: %p

tool: D19: %d

tool: D9: BAD ARGUMENT

assistant: ```c
void cmd_wattroff(int nargs, char **args) {
  WINDOW *win;
  int attr;
  if (check_arg_count(nargs, 2) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &attr) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(wattroff(win, attr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_wattroff>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L37
  mov    (%rbx),%rdi
  lea    0x10(%rsp),%rdx
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L28
  mov    0x8(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  lea    D22(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L28
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <wattroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L37:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D24(%rip),%rdi
  call   <report_error@plt>
  jmp    L37
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D22
type: string
name: read_data
arguments: label: D24
type: string

tool: D7: %p

tool: D22: %d

tool: D24: BAD ARGUMENT

assistant: ```c
void cmd_wattroff(int nargs, char **args) {
  WINDOW *win;
  int attr;
  if (check_arg_count(nargs, 2) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &attr) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(wattroff(win, attr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ece_import_public_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <EC_KEY_new_by_curve_name@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L18
L33:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <EC_KEY_oct2key@plt>
  cmp    $0x1,%eax
  je     L14
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EC_KEY_free@plt>
  mov    $0x0,%eax
  jmp    L18
L14:
  mov    -0x8(%rbp),%rax
L18:
  leave
  ret
```

assistant: ```c
EC_KEY *ece_import_public_key(const uint8_t *rawKey, size_t rawKeyLen) {
  EC_KEY *key = EC_KEY_new_by_curve_name(NID_X9_62_prime256v1);
  if (!key) {
    return NULL;
  }
  if (EC_KEY_oct2key(key, rawKey, rawKeyLen, NULL) != 1) {
    EC_KEY_free(key);
    return NULL;
  }
  return key;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ece_import_public_key>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <EC_KEY_new_by_curve_name@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <EC_KEY_oct2key@plt>
  cmp    $0x1,%eax
  jne    L20
L14:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    %rbx,%rdi
  call   <EC_KEY_free@plt>
  mov    $0x0,%ebx
  jmp    L14
```

assistant: ```c
EC_KEY *ece_import_public_key(const uint8_t *rawKey, size_t rawKeyLen) {
  EC_KEY *key = EC_KEY_new_by_curve_name(NID_X9_62_prime256v1);
  if (!key) {
    return NULL;
  }
  if (EC_KEY_oct2key(key, rawKey, rawKeyLen, NULL) != 1) {
    EC_KEY_free(key);
    return NULL;
  }
  return key;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ece_import_public_key>:
  endbr64
  mov    D7(%rip),%rax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rax),%edi
  call   <EC_KEY_new_by_curve_name@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  xor    %ecx,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <EC_KEY_oct2key@plt>
  cmp    $0x1,%eax
  jne    L19
L16:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <EC_KEY_free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
EC_KEY *ece_import_public_key(const uint8_t *rawKey, size_t rawKeyLen) {
  EC_KEY *key = EC_KEY_new_by_curve_name(NID_X9_62_prime256v1);
  if (!key) {
    return NULL;
  }
  if (EC_KEY_oct2key(key, rawKey, rawKeyLen, NULL) != 1) {
    EC_KEY_free(key);
    return NULL;
  }
  return key;
}
```