ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putnas>:
  endbr64
  movzbl (%rdi),%esi
  test   %esi,%esi
  je     L13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  lea    D2(%rip),%r12
  lea    D17(%rip),%rbp
L9:
  cmp    $0x7f,%esi
  mov    %rbp,%rdi
  cmovl  %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %esi,%esi
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string

tool: D2: %c

tool: D17: \%03o

assistant: ```c
void putnas(str) register char *str;
{
  register int c;
  while (c = 0xFF & (*str++))
    printf(c <= '~' ? "%c" : "\\%03o", c);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<putnas>:
  endbr64
  movzbl (%rdi),%esi
  test   %esi,%esi
  je     L18
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  nopl   0x0(%rax)
L16:
  cmp    $0x7f,%esi
  mov    %rbp,%rdi
  cmovl  %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%esi
  test   %esi,%esi
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D15
type: string

tool: D18: %c

tool: D15: \%03o

assistant: ```c
void putnas(str) register char *str;
{
  register int c;
  while (c = 0xFF & (*str++))
    printf(c <= '~' ? "%c" : "\\%03o", c);
}
```
user: What is the c source code of the assembly code below?

```asm
<putnas>:
  endbr64
  movzbl (%rdi),%esi
  test   %esi,%esi
  je     L22
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L39:
  cmp    $0x7e,%esi
  jle    L13
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%esi
  test   %esi,%esi
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %esi,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%esi
  test   %esi,%esi
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: \%03o

assistant: ```c
void putnas(str) register char *str;
{
  register int c;
  while (c = 0xFF & (*str++))
    printf(c <= '~' ? "%c" : "\\%03o", c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L15
L16:
  mov    -0xc(%rbp),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L40
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <addtab@plt>
  jmp    L15
L40:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <adddir@plt>
L15:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void add(char *name) {
  struct stat st;
  if (stat(name, &st) < 0) {
    perror(name);
    return;
  }
  if ((st.st_mode & S_IFMT) == S_IFREG)
    addtab(name, &st);
  else
    adddir((char *)0, name);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L17
  mov    D11(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  mov    D3(%rip),%rdx
  cmp    (%rdx),%eax
  je     L10
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <adddir@plt>
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  mov    %rbx,%rdi
  call   <perror@plt>
  jmp    L44
L10:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <addtab@plt>
  jmp    L44
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add(char *name) {
  struct stat st;
  if (stat(name, &st) < 0) {
    perror(name);
    return;
  }
  if ((st.st_mode & S_IFMT) == S_IFREG)
    addtab(name, &st);
  else
    adddir((char *)0, name);
}
```
user: What is the c source code of the assembly code below?

```asm
<add>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L5
  mov    D13(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  mov    D18(%rip),%rdx
  cmp    (%rdx),%eax
  je     L26
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <adddir@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <addtab@plt>
  jmp    L47
  nopl   (%rax)
L5:
  mov    %rbp,%rdi
  call   <perror@plt>
  jmp    L47
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add(char *name) {
  struct stat st;
  if (stat(name, &st) < 0) {
    perror(name);
    return;
  }
  if ((st.st_mode & S_IFMT) == S_IFREG)
    addtab(name, &st);
  else
    adddir((char *)0, name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L23
  mov    D14(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  mov    D16(%rip),%rdx
  cmp    (%rdx),%eax
  je     L43
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <adddir@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <addtab@plt>
  jmp    L1
  nopl   (%rax)
L23:
  mov    %rbp,%rdi
  call   <perror@plt>
  jmp    L1
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add(char *name) {
  struct stat st;
  if (stat(name, &st) < 0) {
    perror(name);
    return;
  }
  if ((st.st_mode & S_IFMT) == S_IFREG)
    addtab(name, &st);
  else
    adddir((char *)0, name);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L82
L76:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x4(%rbp)
  je     L48
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x38e38e39,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L48
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1a,-0x4(%rbp)
  je     L6
  cmpl   $0x35,-0x4(%rbp)
  jne    L12
L6:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L12
L48:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L27
  mov    $0x7c,%edi
  call   <putchar@plt>
  jmp    L27
L12:
  nop
L27:
  addl   $0x1,-0x4(%rbp)
L82:
  cmpl   $0x50,-0x4(%rbp)
  jle    L76
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D13: %d

tool: D2: ---|---|---

assistant: ```c
void print(int *grid) {
  int i;
  for (i = 0; i < 9 * 9; i++) {
    printf("%d", grid[i]);
    if (i != 0 && (i + 1) % 9 == 0) {
      printf("\n");
      if (i == (9 * 3 - 1) || i == (9 * 6 - 1))
        printf("---|---|---\n");
    } else if ((i + 1) % 3 == 0)
      printf("|");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
  lea    D12(%rip),%r14
  jmp    L89
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x1a,%ebx
  je     L53
  cmp    $0x35,%ebx
  je     L53
L2:
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  je     L67
L89:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L2
  lea    0x1(%rbx),%edx
  movslq %edx,%rax
  imul   $0x38e38e39,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%eax
  cmp    %eax,%edx
  je     L1
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  jne    L2
  mov    $0x7c,%edi
  call   <putchar@plt>
  jmp    L2
L53:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L2
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string

tool: D5: %d

tool: D12: ---|---|---

assistant: ```c
void print(int *grid) {
  int i;
  for (i = 0; i < 9 * 9; i++) {
    printf("%d", grid[i]);
    if (i != 0 && (i + 1) % 9 == 0) {
      printf("\n");
      if (i == (9 * 3 - 1) || i == (9 * 6 - 1))
        printf("---|---|---\n");
    } else if ((i + 1) % 3 == 0)
      printf("|");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print>:
  endbr64
  push   %r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L19
  nopl   0x0(%rax)
L73:
  imul   $0xaaaaaaab,%eax,%eax
  cmp    $0x55555555,%eax
  ja     L65
  mov    $0x7c,%edi
  call   <putchar@plt>
L65:
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  je     L48
L19:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  test   %rbx,%rbx
  je     L65
  imul   $0x38e38e39,%eax,%edx
  cmp    $0x1c71c71c,%edx
  ja     L73
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x1a,%ebx
  je     L32
  cmp    $0x35,%ebx
  jne    L65
L32:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    $0x51,%rbx
  jne    L19
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: string
name: extract_symbolic_data
arguments: label: D8
type: string

tool: D19: ---|---|---

tool: D8: %d

assistant: ```c
void print(int *grid) {
  int i;
  for (i = 0; i < 9 * 9; i++) {
    printf("%d", grid[i]);
    if (i != 0 && (i + 1) % 9 == 0) {
      printf("\n");
      if (i == (9 * 3 - 1) || i == (9 * 6 - 1))
        printf("---|---|---\n");
    } else if ((i + 1) % 3 == 0)
      printf("|");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print>:
  endbr64
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L0
  nopl   0x0(%rax)
L11:
  imul   $0xaaaaaaab,%eax,%eax
  cmp    $0x55555555,%eax
  ja     L69
  mov    $0x7c,%edi
  call   <putchar@plt>
L69:
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  je     L24
L0:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  test   %rbx,%rbx
  je     L69
  imul   $0x38e38e39,%eax,%edx
  cmp    $0x1c71c71c,%edx
  ja     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x1a,%ebx
  je     L4
  cmp    $0x35,%ebx
  jne    L69
L4:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    $0x51,%rbx
  jne    L0
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D18: ---|---|---

tool: D14: %d

assistant: ```c
void print(int *grid) {
  int i;
  for (i = 0; i < 9 * 9; i++) {
    printf("%d", grid[i]);
    if (i != 0 && (i + 1) % 9 == 0) {
      printf("\n");
      if (i == (9 * 3 - 1) || i == (9 * 6 - 1))
        printf("---|---|---\n");
    } else if ((i + 1) % 3 == 0)
      printf("|");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<confstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__confstr_alias@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long int confstr(signed int __name, char *__buf, unsigned long int __len) {
  unsigned long int return_value___confstr_chk$1;
  unsigned long int return_value___confstr_chk_warn$2;
  unsigned long int return_value___confstr_alias$3;
  return_value___confstr_alias$3 = __confstr_alias(__name, __buf, __len);
  return return_value___confstr_alias$3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<confstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__confstr_alias@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long int confstr(signed int __name, char *__buf, unsigned long int __len) {
  unsigned long int return_value___confstr_chk$1;
  unsigned long int return_value___confstr_chk_warn$2;
  unsigned long int return_value___confstr_alias$3;
  return_value___confstr_alias$3 = __confstr_alias(__name, __buf, __len);
  return return_value___confstr_alias$3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<confstr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__confstr_alias@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long int confstr(signed int __name, char *__buf, unsigned long int __len) {
  unsigned long int return_value___confstr_chk$1;
  unsigned long int return_value___confstr_chk_warn$2;
  unsigned long int return_value___confstr_alias$3;
  return_value___confstr_alias$3 = __confstr_alias(__name, __buf, __len);
  return return_value___confstr_alias$3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<confstr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__confstr_alias@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long int confstr(signed int __name, char *__buf, unsigned long int __len) {
  unsigned long int return_value___confstr_chk$1;
  unsigned long int return_value___confstr_chk_warn$2;
  unsigned long int return_value___confstr_alias$3;
  return_value___confstr_alias$3 = __confstr_alias(__name, __buf, __len);
  return return_value___confstr_alias$3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d_canberra>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movq   D19(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L25
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   D19(%rip),%xmm1
  andpd  %xmm1,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L25:
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L4
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
datatype: qword

tool: D19: 9223372036854775807

assistant: ```c
double d_canberra(double *f1, double *f2, int n) {
  int i;
  double dist = 0.0f, aux;
  for (i = 0; i < n; i++) {
    aux = fabs(f1[i] + f2[i]);
    if (aux > 0)
      dist += (fabs(f1[i] - f2[i]) / aux);
  }
  return (dist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d_canberra>:
  endbr64
  test   %edx,%edx
  jle    L28
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm3,%xmm3
  movq   D3(%rip),%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm5,%xmm6
  jmp    L47
L25:
  subsd  %xmm2,%xmm0
  andpd  %xmm6,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
L34:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L18
L47:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  andpd  %xmm5,%xmm1
  comisd %xmm4,%xmm1
  ja     L25
  jmp    L34
L28:
  pxor   %xmm3,%xmm3
L18:
  movapd %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: qword

tool: D3: 9223372036854775807

assistant: ```c
double d_canberra(double *f1, double *f2, int n) {
  int i;
  double dist = 0.0f, aux;
  for (i = 0; i < n; i++) {
    aux = fabs(f1[i] + f2[i]);
    if (aux > 0)
      dist += (fabs(f1[i] - f2[i]) / aux);
  }
  return (dist);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<d_canberra>:
  endbr64
  test   %edx,%edx
  jle    L5
  pxor   %xmm5,%xmm5
  movq   D1(%rip),%xmm3
  movslq %edx,%rdx
  xor    %eax,%eax
  movapd %xmm5,%xmm4
  nopl   (%rax)
L12:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  andpd  %xmm3,%xmm1
  comisd %xmm5,%xmm1
  jbe    L20
  subsd  %xmm2,%xmm0
  andpd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm4
L20:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  movapd %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: qword

tool: D1: 9223372036854775807

assistant: ```c
double d_canberra(double *f1, double *f2, int n) {
  int i;
  double dist = 0.0f, aux;
  for (i = 0; i < n; i++) {
    aux = fabs(f1[i] + f2[i]);
    if (aux > 0)
      dist += (fabs(f1[i] - f2[i]) / aux);
  }
  return (dist);
}
```
user: What is the c source code of the assembly code below?

```asm
<d_canberra>:
  endbr64
  test   %edx,%edx
  jle    L26
  pxor   %xmm5,%xmm5
  movq   D4(%rip),%xmm3
  movslq %edx,%rdx
  xor    %eax,%eax
  movapd %xmm5,%xmm4
  nopl   (%rax)
L23:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  andpd  %xmm3,%xmm1
  comisd %xmm5,%xmm1
  jbe    L20
  subsd  %xmm2,%xmm0
  andpd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm4
L20:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L23
  movapd %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: qword

tool: D4: 9223372036854775807

assistant: ```c
double d_canberra(double *f1, double *f2, int n) {
  int i;
  double dist = 0.0f, aux;
  for (i = 0; i < n; i++) {
    aux = fabs(f1[i] + f2[i]);
    if (aux > 0)
      dist += (fabs(f1[i] - f2[i]) / aux);
  }
  return (dist);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<makelit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rbx
  jmp    L7
L8:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L7
  sub    $0x1,%rbx
  mov    %rbx,%r12
  nop
L14:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  lea    0x1(%r12),%rax
  movb   $0x0,(%rax)
  jmp    L44
L49:
  lea    0x1(%r12),%rax
  movzbl (%r12),%edx
  mov    %dl,(%rax)
L44:
  mov    %r12,%rax
  lea    -0x1(%rax),%r12
  cmp    %rax,%rbx
  jb     L49
  add    $0x2,%rbx
L7:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L8
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
makelit(s) char *s;
{
  register char *sp;
  register char *ep;
  sp = s;
  while (*sp)
    if (*sp++ == '%') {
      ep = --sp;
      while (*ep++)
        ;
      *(ep + 1) = 0;
      while (ep-- > sp)
        *(ep + 1) = *ep;
      sp += 2;
    }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<makelit>:
  endbr64
L3:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  lea    0x1(%rdi),%rcx
  cmp    $0x25,%al
  je     L15
  mov    %rcx,%rdi
  jmp    L3
L15:
  mov    %rdi,%rdx
L38:
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L38
  movb   $0x0,0x1(%rdx)
  cmp    %rdx,%rdi
  jae    L55
  mov    %rdx,%rax
L56:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jb     L56
L55:
  lea    0x1(%rcx),%rdi
  jmp    L3
L7:
  ret
```

assistant: ```c
makelit(s) char *s;
{
  register char *sp;
  register char *ep;
  sp = s;
  while (*sp)
    if (*sp++ == '%') {
      ep = --sp;
      while (*ep++)
        ;
      *(ep + 1) = 0;
      while (ep-- > sp)
        *(ep + 1) = *ep;
      sp += 2;
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<makelit>:
  endbr64
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L60:
  lea    0x1(%rdi),%rcx
  cmp    $0x25,%al
  je     L72
  mov    %rcx,%rdi
L89:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L60
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %rdi,%rdx
  jmp    L77
  nopl   (%rax)
L22:
  movzbl (%rdx),%eax
L77:
  add    $0x1,%rdx
  test   %al,%al
  jne    L22
  movb   $0x0,0x1(%rdx)
  cmp    %rdx,%rdi
  jb     L88
  jmp    L81
  cs nopw 0x0(%rax,%rax,1)
L40:
  movzbl -0x1(%rdx),%eax
L88:
  mov    %al,(%rdx)
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  jb     L40
L81:
  lea    0x1(%rcx),%rdi
  jmp    L89
```

assistant: ```c
makelit(s) char *s;
{
  register char *sp;
  register char *ep;
  sp = s;
  while (*sp)
    if (*sp++ == '%') {
      ep = --sp;
      while (*ep++)
        ;
      *(ep + 1) = 0;
      while (ep-- > sp)
        *(ep + 1) = *ep;
      sp += 2;
    }
}
```