ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <bloco_b@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D5
type: string

tool: D15: Informe N:


tool: D5: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int quantidade;
  printf("Informe N:\n");
  scanf("%d", &quantidade);
  bloco_b(quantidade);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <bloco_b@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D18: Informe N:


tool: D8: %d

assistant: ```c
int main(int argc, const char *argv[]) {
  int quantidade;
  printf("Informe N:\n");
  scanf("%d", &quantidade);
  bloco_b(quantidade);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zero_neighbours_clustering>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    $0x0,%ebx
  jmp    L11
L3:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  add    $0x1,%ebx
L11:
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  cmp    %eax,%ebx
  jle    L3
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void zero_neighbours_clustering(int *arr, int lim) {
  register int i;
  for (i = 0; i < lim + 5; i++) {
    arr[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero_neighbours_clustering>:
  endbr64
  cmp    $0xfffffffc,%esi
  jl     L1
  mov    %rdi,%rax
  lea    0x4(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L10:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L10
L1:
  ret
```

assistant: ```c
void zero_neighbours_clustering(int *arr, int lim) {
  register int i;
  for (i = 0; i < lim + 5; i++) {
    arr[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero_neighbours_clustering>:
  endbr64
  cmp    $0xfffffffc,%esi
  jl     L6
  lea    0x4(%rsi),%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void zero_neighbours_clustering(int *arr, int lim) {
  register int i;
  for (i = 0; i < lim + 5; i++) {
    arr[i] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<zero_neighbours_clustering>:
  endbr64
  cmp    $0xfffffffc,%esi
  jl     L1
  lea    0x4(%rsi),%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void zero_neighbours_clustering(int *arr, int lim) {
  register int i;
  for (i = 0; i < lim + 5; i++) {
    arr[i] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  if (0666 == 666) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  if (0666 == 666) {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  if (0666 == 666) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  if (0666 == 666) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<malloc_or_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: malloc or die

assistant: ```c
void *malloc_or_die(size_t nbytes) {
  void *result;
  result = malloc(nbytes);
  if (result == NULL) {
    perror("malloc or die");
    abort();
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_or_die>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L1:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: malloc or die

assistant: ```c
void *malloc_or_die(size_t nbytes) {
  void *result;
  result = malloc(nbytes);
  if (result == NULL) {
    perror("malloc or die");
    abort();
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<malloc_or_die>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L15:
  mov    %r12,%rax
  pop    %r12
  ret
L18:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: malloc or die

assistant: ```c
void *malloc_or_die(size_t nbytes) {
  void *result;
  result = malloc(nbytes);
  if (result == NULL) {
    perror("malloc or die");
    abort();
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<malloc_or_die>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L13:
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: malloc or die

assistant: ```c
void *malloc_or_die(size_t nbytes) {
  void *result;
  result = malloc(nbytes);
  if (result == NULL) {
    perror("malloc or die");
    abort();
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  jmp    L58
L5:
  mov    -0x40(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  movl   $0x1,-0x3c(%rbp)
  jmp    L39
L37:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
L39:
  mov    -0x3c(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jle    L37
  addl   $0x1,-0x40(%rbp)
L58:
  cmpl   $0x9,-0x40(%rbp)
  jle    L5
  movl   $0x0,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  jmp    L50
L31:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <digit_fact_sum@plt>
  cmp    %eax,-0x34(%rbp)
  jne    L62
  mov    -0x34(%rbp),%eax
  add    %eax,-0x38(%rbp)
L62:
  addl   $0x1,-0x34(%rbp)
L50:
  cmpl   $0x1869f,-0x34(%rbp)
  jle    L31
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int digits[10];
  for (int i = 0; i < 10; ++i) {
    digits[i] = 1;
    for (int j = 1; j <= i; ++j) {
      digits[i] *= j;
    }
  }
  int sum = 0;
  for (int i = 3; i < 100000; ++i) {
    if (i == digit_fact_sum(i, digits)) {
      sum += i;
    }
  }
  printf("%d\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x2,%ecx
L2:
  mov    %rsi,%rdi
  movl   $0x1,(%rsi)
  lea    -0x1(%rcx),%eax
  test   %eax,%eax
  jle    L24
  mov    $0x1,%edx
  mov    $0x1,%eax
L25:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L25
  mov    %edx,(%rdi)
L24:
  add    $0x4,%rsi
  add    $0x1,%ecx
  cmp    $0xb,%ecx
  jne    L2
  mov    $0x3,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r12
L17:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <digit_fact_sum@plt>
  mov    %eax,%edx
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%edx
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x186a0,%ebx
  jne    L17
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int digits[10];
  for (int i = 0; i < 10; ++i) {
    digits[i] = 1;
    for (int j = 1; j <= i; ++j) {
      digits[i] *= j;
    }
  }
  int sum = 0;
  for (int i = 3; i < 100000; ++i) {
    if (i == digit_fact_sum(i, digits)) {
      sum += i;
    }
  }
  printf("%d\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%ecx
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  lea    0x4(%rsp),%rsi
  nopl   (%rax)
L15:
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L24
  mov    %edx,(%rsi)
  lea    0x1(%rax),%ecx
  add    $0x4,%rsi
  cmp    $0xa,%eax
  jne    L15
  mov    $0x3,%ebx
  xor    %ebp,%ebp
  mov    %rsp,%r12
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %ebx,%edi
  mov    %r12,%rsi
  call   <digit_fact_sum@plt>
  mov    %eax,%r8d
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%r8d
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x186a0,%ebx
  jne    L29
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char **argv) {
  int digits[10];
  for (int i = 0; i < 10; ++i) {
    digits[i] = 1;
    for (int j = 1; j <= i; ++j) {
      digits[i] *= j;
    }
  }
  int sum = 0;
  for (int i = 3; i < 100000; ++i) {
    if (i == digit_fact_sum(i, digits)) {
      sum += i;
    }
  }
  printf("%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x30,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D29(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  mov    %r12,%rsi
  call   <digit_fact_sum@plt>
  mov    %eax,%r8d
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%r8d
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x186a0,%ebx
  jne    L9
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type_infered: byte[16]
name: parse_data
arguments: label: D17
type_infered: byte[8]
name: parse_data
arguments: label: D29
type_infered: byte[16]
name: parse_data
arguments: label: D13
type_infered: string

tool: {"D19": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D17": [0x80,0x9d,0x00,0x00,0x80,0x89,0x05,0x00]}

tool: {"D29": [0x18,0x00,0x00,0x00,0x78,0x00,0x00,0x00,0xd0,0x02,0x00,0x00,0xb0,0x13,0x00,0x00]}

tool: D13: %d


assistant: ```c
int main(int argc, char **argv) {
  int digits[10];
  for (int i = 0; i < 10; ++i) {
    digits[i] = 1;
    for (int j = 1; j <= i; ++j) {
      digits[i] *= j;
    }
  }
  int sum = 0;
  for (int i = 3; i < 100000; ++i) {
    if (i == digit_fact_sum(i, digits)) {
      sum += i;
    }
  }
  printf("%d\n", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x7c(%rbp)
  movq   $0x11,-0x70(%rbp)
  movq   $0xf,-0x68(%rbp)
  movq   $0x0,-0x78(%rbp)
  jmp    L44
L20:
  mov    -0x68(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  mov    -0x7c(%rbp),%edx
  movslq %edx,%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    -0x78(%rbp),%rax
  mov    %eax,-0x60(%rbp,%rdx,4)
  addq   $0x1,-0x78(%rbp)
L44:
  mov    -0x78(%rbp),%rax
  cmp    -0x70(%rbp),%rax
  jb     L20
  mov    -0x70(%rbp),%rcx
  mov    -0x68(%rbp),%rdx
  mov    -0x7c(%rbp),%esi
  lea    -0x60(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <move_to_beginning@plt>
  movq   $0x0,-0x78(%rbp)
  jmp    L15
L17:
  mov    -0x78(%rbp),%rax
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x78(%rbp)
L15:
  mov    -0x78(%rbp),%rax
  cmp    -0x70(%rbp),%rax
  jb     L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
datatype: string

tool: D9: %d 

assistant: ```c
int main() {
  int N = 20;
  int A[20];
  size_t size = 17;
  size_t begin = 15;
  size_t i;
  for (i = 0; i < size; ++i) {
    A[(begin + i) % N] = i;
  }
  move_to_beginning(A, N, begin, size, 0);
  for (i = 0; i < size; ++i) {
    printf("%d ", A[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  movabs $0xcccccccccccccccd,%rdi
L23:
  lea    0xf(%rcx),%rsi
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rax
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %ecx,(%rsp,%rsi,4)
  add    $0x1,%rcx
  cmp    $0x11,%rcx
  jne    L23
  mov    %rsp,%rbx
  mov    $0x0,%r8d
  mov    $0xf,%edx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <move_to_beginning@plt>
  lea    0x44(%rsp),%r12
  lea    D8(%rip),%rbp
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: %d 

assistant: ```c
int main() {
  int N = 20;
  int A[20];
  size_t size = 17;
  size_t begin = 15;
  size_t i;
  for (i = 0; i < size; ++i) {
    A[(begin + i) % N] = i;
  }
  move_to_beginning(A, N, begin, size, 0);
  for (i = 0; i < size; ++i) {
    printf("%d ", A[i]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  movabs $0xcccccccccccccccd,%rdi
  push   %r12
  xor    %ecx,%ecx
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  lea    0xf(%rcx),%rsi
  mov    %rsi,%rax
  mul    %rdi
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rax
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %ecx,(%rsp,%rsi,4)
  add    $0x1,%rcx
  cmp    $0x11,%rcx
  jne    L3
  mov    %rsp,%rbx
  xor    %r8d,%r8d
  mov    $0xf,%edx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  lea    0x44(%rsp),%r12
  lea    D4(%rip),%rbp
  call   <move_to_beginning@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: %d 

assistant: ```c
int main() {
  int N = 20;
  int A[20];
  size_t size = 17;
  size_t begin = 15;
  size_t i;
  for (i = 0; i < size; ++i) {
    A[(begin + i) % N] = i;
  }
  move_to_beginning(A, N, begin, size, 0);
  for (i = 0; i < size; ++i) {
    printf("%d ", A[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  mov    $0x11,%ecx
  mov    $0xf,%edx
  push   %rbp
  mov    $0x14,%esi
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  movdqa D34(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x44(%rsp),%r12
  movl   $0x4,0x4c(%rsp)
  movups %xmm0,0x3c(%rsp)
  movdqa D18(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D30(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <move_to_beginning@plt>
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D18
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D23
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D30
type_guessed: byte[16]

tool: D5: %d 

tool: {"D34": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D23": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D30": [0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int N = 20;
  int A[20];
  size_t size = 17;
  size_t begin = 15;
  size_t i;
  for (i = 0; i < size; ++i) {
    A[(begin + i) % N] = i;
  }
  move_to_beginning(A, N, begin, size, 0);
  for (i = 0; i < size; ++i) {
    printf("%d ", A[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<put_char_cropped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,%eax
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    %al,-0x24(%rbp)
  mov    0x10(%rbp),%edi
  call   <select_font@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x7,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L97
L88:
  movl   $0x0,-0x14(%rbp)
  jmp    L85
L105:
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L4
  mov    -0x10(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L4
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cmp    $0x27f,%eax
  jg     L4
  mov    -0x10(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  cmp    $0x1df,%eax
  jg     L4
  movzbl -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  cltq
  shl    $0x4,%rax
  add    %rcx,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    $0x8,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L19
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L4
L19:
  cmpl   $0x0,-0x38(%rbp)
  je     L4
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x34(%rbp),%edx
  mov    %dl,(%rax)
L4:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L85:
  cmpl   $0x7,-0x14(%rbp)
  jle    L105
  addl   $0x278,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L97:
  cmpl   $0xf,-0x10(%rbp)
  jle    L88
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int put_char_cropped(unsigned char c, int x, int y, int fg_color, int bg_color, int overwrite, int which_font, unsigned char *buffer) {
  int xx, yy;
  int output_pointer;
  unsigned char(*font)[256][16];
  font = select_font(which_font);
  output_pointer = (y * 640) + x;
  for (yy = 0; yy < 16; yy++) {
    for (xx = 0; xx < 8; xx++) {
      if ((xx + x >= 0) && (yy + y >= 0) && (xx + x < 640) && (yy + y < 480)) {
        if ((*font)[c][yy] & (1 << (8 - xx))) {
          buffer[output_pointer] = fg_color;
        } else if (overwrite) {
          buffer[output_pointer] = bg_color;
        }
      }
      output_pointer++;
    }
    output_pointer += (640 - 8);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<put_char_cropped>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %r8d,%r15d
  mov    %r9d,%r12d
  mov    0x40(%rsp),%edi
  call   <select_font@plt>
  lea    0x0(%rbp,%rbp,4),%edx
  shl    $0x7,%edx
  add    %ebx,%edx
  movslq %edx,%rdx
  mov    %rdx,%rsi
  add    0x48(%rsp),%rsi
  movzbl %r14b,%r14d
  shl    $0x4,%r14
  lea    (%rax,%r14,1),%rdi
  mov    0x48(%rsp),%rax
  lea    0x2800(%rax,%rdx,1),%r8
  add    $0x8,%ebx
  jmp    L8
L34:
  test   %r12d,%r12d
  je     L54
  mov    %r15b,(%rdx)
L54:
  add    $0x1,%rdx
  sub    $0x1,%eax
  je     L84
L87:
  mov    %ebx,%ecx
  sub    %eax,%ecx
  cmp    $0x27f,%ecx
  ja     L54
  cmp    $0x1df,%ebp
  ja     L54
  movzbl (%rdi),%ecx
  bt     %eax,%ecx
  jae    L34
  mov    %r13b,(%rdx)
  jmp    L54
L84:
  add    $0x280,%rsi
  add    $0x1,%ebp
  add    $0x1,%rdi
  cmp    %r8,%rsi
  je     L0
L8:
  mov    %rsi,%rdx
  mov    $0x8,%eax
  jmp    L87
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int put_char_cropped(unsigned char c, int x, int y, int fg_color, int bg_color, int overwrite, int which_font, unsigned char *buffer) {
  int xx, yy;
  int output_pointer;
  unsigned char(*font)[256][16];
  font = select_font(which_font);
  output_pointer = (y * 640) + x;
  for (yy = 0; yy < 16; yy++) {
    for (xx = 0; xx < 8; xx++) {
      if ((xx + x >= 0) && (yy + y >= 0) && (xx + x < 640) && (yy + y < 480)) {
        if ((*font)[c][yy] & (1 << (8 - xx))) {
          buffer[output_pointer] = fg_color;
        } else if (overwrite) {
          buffer[output_pointer] = bg_color;
        }
      }
      output_pointer++;
    }
    output_pointer += (640 - 8);
  }
  return 0;
}
```