user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%rax
  lea    (%rsi,%rsi,8),%r8
  mov    %rsi,%rdi
  lea    (%rax,%r8,4),%r8
  test   %esi,%esi
  je     L252
  movslq %edx,%r9
  cmp    (%rax,%r9,4),%ecx
  je     L378
L252:
  test   %edx,%edx
  je     L116
  cmp    %ecx,(%r8)
  je     L378
L116:
  cmp    $0x1,%edi
  je     L68
  movslq %edx,%r9
  cmp    0x24(%rax,%r9,4),%ecx
  je     L378
L68:
  cmp    $0x1,%edx
  je     L379
  cmp    0x4(%r8),%ecx
  je     L378
L379:
  cmp    $0x2,%edi
  je     L6
  movslq %edx,%r9
  cmp    0x48(%rax,%r9,4),%ecx
  je     L378
L6:
  cmp    $0x2,%edx
  je     L192
  cmp    0x8(%r8),%ecx
  je     L378
L192:
  cmp    $0x3,%edi
  je     L307
  movslq %edx,%r9
  cmp    0x6c(%rax,%r9,4),%ecx
  je     L378
L307:
  cmp    $0x3,%edx
  je     L25
  cmp    0xc(%r8),%ecx
  je     L378
L25:
  cmp    $0x4,%edi
  je     L275
  movslq %edx,%r9
  cmp    0x90(%rax,%r9,4),%ecx
  je     L378
L275:
  cmp    $0x4,%edx
  je     L395
  cmp    0x10(%r8),%ecx
  je     L378
L395:
  cmp    $0x5,%edi
  je     L432
  movslq %edx,%r9
  cmp    0xb4(%rax,%r9,4),%ecx
  je     L378
L432:
  cmp    $0x5,%edx
  je     L402
  cmp    0x14(%r8),%ecx
  je     L378
L402:
  cmp    $0x6,%edi
  je     L128
  movslq %edx,%r9
  cmp    0xd8(%rax,%r9,4),%ecx
  je     L378
L128:
  cmp    $0x6,%edx
  je     L434
  cmp    0x18(%r8),%ecx
  je     L378
  cmp    $0x7,%edi
  je     L397
  movslq %edx,%r9
  cmp    0xfc(%rax,%r9,4),%ecx
  je     L378
L397:
  cmp    $0x7,%edx
  je     L443
L361:
  cmp    0x1c(%r8),%ecx
  je     L378
  cmp    $0x8,%edi
  je     L71
L154:
  movslq %edx,%r9
  cmp    %ecx,0x120(%rax,%r9,4)
  je     L378
L71:
  cmp    $0x8,%edx
  je     L211
L77:
  cmp    %ecx,0x20(%r8)
  je     L378
L211:
  imul   $0x55555556,%rsi,%rsi
  mov    %edi,%r8d
  push   %rbx
  sar    $0x1f,%r8d
  shr    $0x20,%rsi
  sub    %r8d,%esi
  mov    %edx,%r8d
  lea    (%rsi,%rsi,2),%r10d
  movslq %edx,%rsi
  sar    $0x1f,%r8d
  imul   $0x55555556,%rsi,%rsi
  lea    0x2(%r10),%ebx
  shr    $0x20,%rsi
  sub    %r8d,%esi
  movslq %r10d,%r8
  lea    (%rsi,%rsi,2),%r11d
  lea    (%r8,%r8,8),%r8
  lea    0x2(%r11),%esi
  lea    (%rax,%r8,4),%r8
  movslq %r11d,%r11
L454:
  cmp    %r10d,%edi
  mov    %r11,%rax
  sete   %r9b
L319:
  cmp    %eax,%edx
  jne    L374
  test   %r9b,%r9b
  jne    L326
L374:
  cmp    %ecx,(%r8,%rax,4)
  je     L111
L326:
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L319
  add    $0x1,%r10d
  add    $0x24,%r8
  cmp    %ebx,%r10d
  jle    L454
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L378:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L111:
  xor    %eax,%eax
  pop    %rbx
  ret
L443:
  cmp    $0x8,%edi
  jne    L154
  jmp    L77
L434:
  cmp    $0x7,%edi
  je     L361
  movslq %edx,%r9
  cmp    0xfc(%rax,%r9,4),%ecx
  jne    L397
  jmp    L378
```

assistant: ```c
int check(int (*a)[9], int x, int y, int b) {
  int i;
  int j;
  for (j = 0; j < 9; ++j) {
    if (j != x) {
      if (b == a[j][y])
        return 0;
    }
    if (j != y) {
      if (b == a[x][j])
        return 0;
    }
  }
  i = x - x % 3;
  j = y - y % 3;
  int loo1 = i;
  int loo2 = j;
  for (i = loo1; i < loo1 + 3; ++i)
    for (j = loo2; j < loo2 + 3; ++j) {
      if (i == x && j == y)
        continue;
      if (b == a[i][j])
        return 0;
    }
  return 1;
}
```