ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L28
L48:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L35
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L35:
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  cmpl   $0x0,-0x4(%rbp)
  js     L32
  mov    -0x4(%rbp),%eax
  jmp    L19
L32:
  mov    -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int strindex(char s[], char t) {
  int i, k;
  for (i = 0, k = -1; s[i] != '\0'; i++)
    if (s[i] == t)
      k = i;
  if (k >= 0)
    return k;
  return k;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  mov    $0x0,%eax
  mov    $0xffffffff,%ecx
L3:
  cmp    %dl,%sil
  cmove  %eax,%ecx
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L3
L2:
  mov    %ecx,%eax
  ret
L7:
  mov    $0xffffffff,%ecx
  jmp    L2
```

assistant: ```c
int strindex(char s[], char t) {
  int i, k;
  for (i = 0, k = -1; s[i] != '\0'; i++)
    if (s[i] == t)
      k = i;
  if (k >= 0)
    return k;
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strindex>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  xor    %eax,%eax
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    %dl,%sil
  cmove  %eax,%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L18
  mov    %r8d,%eax
  ret
  nop
L7:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strindex(char s[], char t) {
  int i, k;
  for (i = 0, k = -1; s[i] != '\0'; i++)
    if (s[i] == t)
      k = i;
  if (k >= 0)
    return k;
  return k;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strindex>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L13
  xor    %eax,%eax
  mov    $0xffffffff,%r8d
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    %sil,%dl
  cmove  %eax,%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L11
  mov    %r8d,%eax
  ret
  nop
L13:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strindex(char s[], char t) {
  int i, k;
  for (i = 0, k = -1; s[i] != '\0'; i++)
    if (s[i] == t)
      k = i;
  if (k >= 0)
    return k;
  return k;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PutInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PutInt32(int val, char *ptr) {
  ptr[0] = (val >> 0) & 0xff;
  ptr[1] = (val >> 8) & 0xff;
  ptr[2] = (val >> 16) & 0xff;
  ptr[3] = (val >> 24) & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PutInt32>:
  endbr64
  mov    %edi,%eax
  mov    %dil,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rsi)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rsi)
  shr    $0x18,%eax
  mov    %al,0x3(%rsi)
  ret
```

assistant: ```c
void PutInt32(int val, char *ptr) {
  ptr[0] = (val >> 0) & 0xff;
  ptr[1] = (val >> 8) & 0xff;
  ptr[2] = (val >> 16) & 0xff;
  ptr[3] = (val >> 24) & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PutInt32>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void PutInt32(int val, char *ptr) {
  ptr[0] = (val >> 0) & 0xff;
  ptr[1] = (val >> 8) & 0xff;
  ptr[2] = (val >> 16) & 0xff;
  ptr[3] = (val >> 24) & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PutInt32>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void PutInt32(int val, char *ptr) {
  ptr[0] = (val >> 0) & 0xff;
  ptr[1] = (val >> 8) & 0xff;
  ptr[2] = (val >> 16) & 0xff;
  ptr[3] = (val >> 24) & 0xff;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <objc_getClass@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <objc_getClass@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: D16: NSObject

tool: D14: NSApplication

assistant: ```c
int main() {
  assert(objc_getClass("NSObject") > 0);
  assert(objc_getClass("NSApplication") > 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <objc_getClass@plt>
  test   %rax,%rax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D7(%rip),%rdi
  call   <objc_getClass@plt>
  test   %rax,%rax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: D10: NSObject

tool: D7: NSApplication

assistant: ```c
int main() {
  assert(objc_getClass("NSObject") > 0);
  assert(objc_getClass("NSApplication") > 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <objc_getClass@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  call   <assert@plt>
  lea    D16(%rip),%rdi
  call   <objc_getClass@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D0: NSObject

tool: D16: NSApplication

assistant: ```c
int main() {
  assert(objc_getClass("NSObject") > 0);
  assert(objc_getClass("NSApplication") > 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <objc_getClass@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  call   <assert@plt>
  lea    D11(%rip),%rdi
  call   <objc_getClass@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string

tool: D10: NSObject

tool: D11: NSApplication

assistant: ```c
int main() {
  assert(objc_getClass("NSObject") > 0);
  assert(objc_getClass("NSApplication") > 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x5,%esi
  mov    $0x2c,%edi
  call   <setup_aeskey@plt>
  mov    $0x2c,%edi
  call   <use_aeskey@plt>
  mov    -0x20(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x10000000,%ecx
  mov    %rax,%rdi
  call   <aes_decrypt@plt>
  nop
  leave
  ret
```

assistant: ```c
void decrypt(void *key, void *inbuf, void *outbuf, size_t size) {
  setup_aeskey(0x2C, 1 | 4, key);
  use_aeskey(0x2C);
  aes_decrypt(inbuf, outbuf, size / 0x10, 0x10000000);
}
```
user: What is the c source code of the assembly code below?

```asm
<decrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %rdi,%rdx
  mov    $0x5,%esi
  mov    $0x2c,%edi
  call   <setup_aeskey@plt>
  mov    $0x2c,%edi
  call   <use_aeskey@plt>
  shr    $0x4,%rbx
  mov    %rbx,%rdx
  mov    $0x10000000,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aes_decrypt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decrypt(void *key, void *inbuf, void *outbuf, size_t size) {
  setup_aeskey(0x2C, 1 | 4, key);
  use_aeskey(0x2C);
  aes_decrypt(inbuf, outbuf, size / 0x10, 0x10000000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decrypt>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  mov    %rdi,%rdx
  mov    $0x2c,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x5,%esi
  push   %rbx
  mov    %rcx,%rbx
  shr    $0x4,%rbx
  call   <setup_aeskey@plt>
  mov    $0x2c,%edi
  call   <use_aeskey@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x10000000,%ecx
  pop    %rbp
  pop    %r12
  jmp    1070 <aes_decrypt@plt>
```

assistant: ```c
void decrypt(void *key, void *inbuf, void *outbuf, size_t size) {
  setup_aeskey(0x2C, 1 | 4, key);
  use_aeskey(0x2C);
  aes_decrypt(inbuf, outbuf, size / 0x10, 0x10000000);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<decrypt>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  mov    %rdi,%rdx
  mov    $0x2c,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x5,%esi
  push   %rbx
  mov    %rcx,%rbx
  shr    $0x4,%rbx
  call   <setup_aeskey@plt>
  mov    $0x2c,%edi
  call   <use_aeskey@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x10000000,%ecx
  pop    %rbp
  pop    %r12
  jmp    1070 <aes_decrypt@plt>
```

assistant: ```c
void decrypt(void *key, void *inbuf, void *outbuf, size_t size) {
  setup_aeskey(0x2C, 1 | 4, key);
  use_aeskey(0x2C);
  aes_decrypt(inbuf, outbuf, size / 0x10, 0x10000000);
}
```
user: What is the c source code of the assembly code below?

```asm
<prints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0x20,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void prints(char *s) {
  int i = 0;
  for (i = 0; s[i] != '\0'; i++)
    putchar(s[i]);
  putchar(' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prints>:
  endbr64
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  lea    0x1(%rdi),%rbx
L7:
  movsbl %al,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L7
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void prints(char *s) {
  int i = 0;
  for (i = 0; s[i] != '\0'; i++)
    putchar(s[i]);
  putchar(' ');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<prints>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L14
  push   %rbx
  lea    0x1(%rdi),%rbx
L1:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L1
  mov    $0x20,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nop
L14:
  mov    $0x20,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void prints(char *s) {
  int i = 0;
  for (i = 0; s[i] != '\0'; i++)
    putchar(s[i]);
  putchar(' ');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<prints>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  push   %rbx
  lea    0x1(%rdi),%rbx
L1:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L1
  mov    $0x20,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nop
L9:
  mov    $0x20,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void prints(char *s) {
  int i = 0;
  for (i = 0; s[i] != '\0'; i++)
    putchar(s[i]);
  putchar(' ');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test();
  test(1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  test(1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  test(1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test();
  test(1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ftp_lite_login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0xa,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L18
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <do_getline@plt>
  test   %rax,%rax
  je     L20
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <do_getline@plt>
  test   %rax,%rax
  je     L20
  mov    $0x1,%eax
  jmp    L13
L20:
  mov    $0x0,%eax
L13:
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D9: %s login: 

tool: D7: password: 

assistant: ```c
int ftp_lite_login(const char *service, char *name, int namelen, char *pass, int passlen) {
  char *prompt;
  prompt = malloc(strlen(service) + 10);
  if (!prompt)
    return 0;
  sprintf(prompt, "%s login: ", service);
  int result = do_getline(prompt, name, namelen, 1) && do_getline("password: ", pass, passlen, 0);
  free(prompt);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ftp_lite_login>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%r14
  mov    %r8d,%r15d
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x1,%ecx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <do_getline@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  jne    L9
L33:
  mov    %rbx,%rdi
  call   <free@plt>
L3:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    $0x0,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  lea    D7(%rip),%rdi
  call   <do_getline@plt>
  test   %rax,%rax
  setne  %bpl
  movzbl %bpl,%ebp
  jmp    L33
L7:
  mov    $0x0,%ebp
  jmp    L3
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D7
datatype: string

tool: D14: %s login: 

tool: D7: password: 

assistant: ```c
int ftp_lite_login(const char *service, char *name, int namelen, char *pass, int passlen) {
  char *prompt;
  prompt = malloc(strlen(service) + 10);
  if (!prompt)
    return 0;
  sprintf(prompt, "%s login: ", service);
  int result = do_getline(prompt, name, namelen, 1) && do_getline("password: ", pass, passlen, 0);
  free(prompt);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ftp_lite_login>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L38
  mov    %rax,%rbp
  mov    %rbx,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    $0x1,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  xor    %r12d,%r12d
  call   <do_getline@plt>
  test   %rax,%rax
  jne    L26
L8:
  mov    %rbp,%rdi
  call   <free@plt>
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L26:
  xor    %ecx,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  xor    %r12d,%r12d
  lea    D17(%rip),%rdi
  call   <do_getline@plt>
  test   %rax,%rax
  setne  %r12b
  jmp    L8
L38:
  xor    %r12d,%r12d
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string

tool: D7: %s login: 

tool: D17: password: 

assistant: ```c
int ftp_lite_login(const char *service, char *name, int namelen, char *pass, int passlen) {
  char *prompt;
  prompt = malloc(strlen(service) + 10);
  if (!prompt)
    return 0;
  sprintf(prompt, "%s login: ", service);
  int result = do_getline(prompt, name, namelen, 1) && do_getline("password: ", pass, passlen, 0);
  free(prompt);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ftp_lite_login>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0xa(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %rbx,%rdx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    $0x1,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rdi
  xor    %r12d,%r12d
  call   <do_getline@plt>
  test   %rax,%rax
  jne    L8
L14:
  mov    %rbp,%rdi
  call   <free@plt>
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L8:
  xor    %ecx,%ecx
  mov    %r15d,%edx
  mov    %r14,%rsi
  xor    %r12d,%r12d
  lea    D4(%rip),%rdi
  call   <do_getline@plt>
  test   %rax,%rax
  setne  %r12b
  jmp    L14
L1:
  xor    %r12d,%r12d
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string

tool: D3: %s login: 

tool: D4: password: 

assistant: ```c
int ftp_lite_login(const char *service, char *name, int namelen, char *pass, int passlen) {
  char *prompt;
  prompt = malloc(strlen(service) + 10);
  if (!prompt)
    return 0;
  sprintf(prompt, "%s login: ", service);
  int result = do_getline(prompt, name, namelen, 1) && do_getline("password: ", pass, passlen, 0);
  free(prompt);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<data_producer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x30,%rsp
  mov    %edi,-0x8024(%rbp)
  mov    %rsi,-0x8030(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x4,-0x8024(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8030(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8020(%rbp)
  movl   $0x0,-0x801c(%rbp)
  mov    $0x0,%edi
  call   <Close@plt>
  jmp    L3
L10:
  mov    -0x8020(%rbp),%eax
  mov    $0x8000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x8018(%rbp)
  mov    -0x8018(%rbp),%edx
  lea    -0x8010(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <Write@plt>
  mov    %eax,-0x8014(%rbp)
  cmpl   $0x0,-0x8014(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8014(%rbp),%eax
  sub    %eax,-0x8020(%rbp)
  addl   $0x1,-0x801c(%rbp)
L3:
  cmpl   $0x0,-0x8020(%rbp)
  jg     L10
  mov    $0x1,%edi
  call   <Close@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int data_producer(int argl, void *args) {
  assert(argl == sizeof(int));
  int nbytes = *(int *)args;
  int i = 0;
  Close(0);
  char buffer[32768];
  while (nbytes > 0) {
    unsigned int n = (nbytes < 32768) ? nbytes : 32768;
    int rc = Write(1, buffer, n);
    assert(rc > 0);
    nbytes -= rc;
    i++;
  }
  Close(1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<data_producer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%ebx
  mov    $0x0,%edi
  call   <Close@plt>
  test   %ebx,%ebx
  jle    L13
  mov    %rsp,%r12
L35:
  mov    $0x8000,%edx
  cmp    %edx,%ebx
  cmovle %ebx,%edx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <Write@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    %ebp,%ebx
  test   %ebx,%ebx
  jg     L35
L13:
  mov    $0x1,%edi
  call   <Close@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x8010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int data_producer(int argl, void *args) {
  assert(argl == sizeof(int));
  int nbytes = *(int *)args;
  int i = 0;
  Close(0);
  char buffer[32768];
  while (nbytes > 0) {
    unsigned int n = (nbytes < 32768) ? nbytes : 32768;
    int rc = Write(1, buffer, n);
    assert(rc > 0);
    nbytes -= rc;
    i++;
  }
  Close(1);
  return 0;
}
```