ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<distanceSquared>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm2
  subsd  (%rsi),%xmm0
  subsd  0x8(%rsi),%xmm2
  movsd  0x10(%rdi),%xmm1
  subsd  0x10(%rsi),%xmm1
  mulsd  %xmm2,%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double distanceSquared(double a[3], double b[3]) {
  double dis_components[3] = {0.0, 0.0, 0.0};
  dis_components[0] = (a[0] - b[0]);
  dis_components[1] = (a[1] - b[1]);
  dis_components[2] = (a[2] - b[2]);
  return ((dis_components[0]) * (dis_components[0]) + (dis_components[1]) * (dis_components[1]) + (dis_components[2]) * (dis_components[2]));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  mov    $0xce4,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe01fc084,%eax
  movl   $0x24,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  mov    $0xe01fc080,%eax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  nop
L3:
  mov    $0xe01fc088,%eax
  mov    (%rax),%eax
  and    $0x400,%eax
  test   %eax,%eax
  je     L3
  mov    $0xe01fc080,%eax
  movl   $0x3,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  mov    $0xe01fc004,%eax
  movl   $0x3,(%rax)
  mov    $0xe01fc000,%eax
  movl   $0x2,(%rax)
  mov    $0xe01fc100,%eax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Initialize(void) {
  *(volatile unsigned int *)0xE01FC084 = 0x24;
  feed();
  *(volatile unsigned int *)0xE01FC080 = 0x1;
  feed();
  while (!(*(volatile unsigned int *)0xE01FC088 & 0x400))
    ;
  *(volatile unsigned int *)0xE01FC080 = 0x3;
  feed();
  *(volatile unsigned int *)0xE01FC004 = 0x3;
  *(volatile unsigned int *)0xE01FC000 = 0x2;
  *(volatile unsigned int *)0xE01FC100 = 0x1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Initialize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe01fc084,%eax
  movl   $0x24,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  mov    $0xe01fc080,%eax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  mov    $0xe01fc088,%edx
L7:
  mov    (%rdx),%eax
  test   $0x4,%ah
  je     L7
  mov    $0xe01fc080,%eax
  movl   $0x3,(%rax)
  mov    $0x0,%eax
  call   <feed@plt>
  mov    $0xe01fc004,%eax
  movl   $0x3,(%rax)
  lea    -0x4(%rax),%rax
  movl   $0x2,(%rax)
  lea    0x100(%rax),%rax
  movl   $0x1,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Initialize(void) {
  *(volatile unsigned int *)0xE01FC084 = 0x24;
  feed();
  *(volatile unsigned int *)0xE01FC080 = 0x1;
  feed();
  while (!(*(volatile unsigned int *)0xE01FC088 & 0x400))
    ;
  *(volatile unsigned int *)0xE01FC080 = 0x3;
  feed();
  *(volatile unsigned int *)0xE01FC004 = 0x3;
  *(volatile unsigned int *)0xE01FC000 = 0x2;
  *(volatile unsigned int *)0xE01FC100 = 0x1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Initialize>:
  endbr64
  mov    $0xe01fc084,%eax
  sub    $0x8,%rsp
  movl   $0x24,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc080,%eax
  movl   $0x1,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc088,%edx
  nopl   0x0(%rax)
L4:
  mov    (%rdx),%eax
  test   $0x4,%ah
  je     L4
  mov    $0xe01fc080,%eax
  movl   $0x3,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc004,%eax
  movl   $0x3,(%rax)
  movl   $0x2,-0x4(%rax)
  movl   $0x1,0xfc(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Initialize(void) {
  *(volatile unsigned int *)0xE01FC084 = 0x24;
  feed();
  *(volatile unsigned int *)0xE01FC080 = 0x1;
  feed();
  while (!(*(volatile unsigned int *)0xE01FC088 & 0x400))
    ;
  *(volatile unsigned int *)0xE01FC080 = 0x3;
  feed();
  *(volatile unsigned int *)0xE01FC004 = 0x3;
  *(volatile unsigned int *)0xE01FC000 = 0x2;
  *(volatile unsigned int *)0xE01FC100 = 0x1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Initialize>:
  endbr64
  mov    $0xe01fc084,%eax
  sub    $0x8,%rsp
  movl   $0x24,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc080,%eax
  movl   $0x1,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc088,%edx
  nopl   0x0(%rax)
L5:
  mov    (%rdx),%eax
  test   $0x4,%ah
  je     L5
  mov    $0xe01fc080,%eax
  movl   $0x3,(%rax)
  xor    %eax,%eax
  call   <feed@plt>
  mov    $0xe01fc004,%eax
  movl   $0x3,(%rax)
  movl   $0x2,-0x4(%rax)
  movl   $0x1,0xfc(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Initialize(void) {
  *(volatile unsigned int *)0xE01FC084 = 0x24;
  feed();
  *(volatile unsigned int *)0xE01FC080 = 0x1;
  feed();
  while (!(*(volatile unsigned int *)0xE01FC088 & 0x400))
    ;
  *(volatile unsigned int *)0xE01FC080 = 0x3;
  feed();
  *(volatile unsigned int *)0xE01FC004 = 0x3;
  *(volatile unsigned int *)0xE01FC000 = 0x2;
  *(volatile unsigned int *)0xE01FC100 = 0x1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<delete_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
bool delete_map(volatile uint32_t *address) {
  munmap((void *)address, 4096);
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<delete_map>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%esi
  call   <munmap@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool delete_map(volatile uint32_t *address) {
  munmap((void *)address, 4096);
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<delete_map>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%esi
  call   <munmap@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool delete_map(volatile uint32_t *address) {
  munmap((void *)address, 4096);
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<delete_map>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000,%esi
  call   <munmap@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool delete_map(volatile uint32_t *address) {
  munmap((void *)address, 4096);
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%edi
  call   <f@plt>
  cmp    $0x4,%eax
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  if (f(2) != 4)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <f@plt>
  cmp    $0x4,%eax
  jne    L13
L12:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L13:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L12
```

assistant: ```c
main() {
  if (f(2) != 4)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <f@plt>
  cmp    $0x4,%eax
  je     L2
  xor    %eax,%eax
  call   <abort@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  if (f(2) != 4)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <f@plt>
  cmp    $0x4,%eax
  je     L5
  xor    %eax,%eax
  call   <abort@plt>
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  if (f(2) != 4)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  js     L7
  cmpb   $0x0,-0x1c(%rbp)
  js     L7
  movzbl -0x18(%rbp),%edx
  movzbl -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x1(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jge    L16
  movzbl -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x14(%rbp)
L16:
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x18(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
L7:
  movsbl -0x18(%rbp),%edx
  movsbl -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <makeShort@plt>
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: t %d


assistant: ```c
short sub(char a, char b, char c, char d) {
  char t;
  if (a >= 0 && c >= 0) {
    t = b + d;
    printf("t %d\n", t);
    if (t < b) {
      a = a + 1;
    }
    b = t;
    t = a + c;
    if (t < a && t < c) {
    }
  }
  return makeShort(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  or     %dil,%dl
  jns    L16
L24:
  movsbl %sil,%esi
  movsbl %r13b,%edi
  call   <makeShort@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %edi,%ebx
  mov    %esi,%r12d
  lea    (%rcx,%rsi,1),%ebp
  movsbl %bpl,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  cmp    %bpl,%r12b
  jle    L24
  lea    0x1(%rbx),%r13d
  jmp    L24
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: t %d


assistant: ```c
short sub(char a, char b, char c, char d) {
  char t;
  if (a >= 0 && c >= 0) {
    t = b + d;
    printf("t %d\n", t);
    if (t < b) {
      a = a + 1;
    }
    b = t;
    t = a + c;
    if (t < a && t < c) {
    }
  }
  return makeShort(a, b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sub>:
  endbr64
  or     %dil,%dl
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  jns    L0
L8:
  pop    %rbx
  movsbl %bpl,%edi
  mov    %r14d,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <makeShort@plt>
  xchg   %ax,%ax
L0:
  lea    (%rcx,%rsi,1),%r13d
  mov    %edi,%ebx
  lea    D8(%rip),%rdi
  movsbl %r13b,%r14d
  add    $0x1,%ebx
  mov    %r14d,%esi
  call   <printf@plt>
  cmp    %r12b,%r13b
  cmovl  %ebx,%ebp
  jmp    L8
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: t %d


assistant: ```c
short sub(char a, char b, char c, char d) {
  char t;
  if (a >= 0 && c >= 0) {
    t = b + d;
    printf("t %d\n", t);
    if (t < b) {
      a = a + 1;
    }
    b = t;
    t = a + c;
    if (t < a && t < c) {
    }
  }
  return makeShort(a, b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sub>:
  endbr64
  or     %dil,%dl
  push   %r14
  movsbl %sil,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  jns    L4
L16:
  pop    %rbx
  movsbl %bpl,%edi
  mov    %r14d,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <makeShort@plt>
  xchg   %ax,%ax
L4:
  lea    (%rcx,%rsi,1),%r13d
  mov    %edi,%ebx
  lea    D5(%rip),%rdi
  movsbl %r13b,%r14d
  add    $0x1,%ebx
  mov    %r14d,%esi
  call   <printf@plt>
  cmp    %r12b,%r13b
  cmovl  %ebx,%ebp
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: t %d


assistant: ```c
short sub(char a, char b, char c, char d) {
  char t;
  if (a >= 0 && c >= 0) {
    t = b + d;
    printf("t %d\n", t);
    if (t < b) {
      a = a + 1;
    }
    b = t;
    t = a + c;
    if (t < a && t < c) {
    }
  }
  return makeShort(a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortPointers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <do_qsort@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <insertion@plt>
  nop
  leave
  ret
```

assistant: ```c
void sortPointers(void **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  do_qsort(vals, cmp, 0, total_elems - 1);
  insertion(vals, cmp, 0, total_elems - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortPointers>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  lea    -0x1(%rsi),%r12d
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  call   <do_qsort@plt>
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <insertion@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sortPointers(void **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  do_qsort(vals, cmp, 0, total_elems - 1);
  insertion(vals, cmp, 0, total_elems - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortPointers>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %rdx,%r12
  mov    %r13d,%ecx
  xor    %edx,%edx
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  call   <do_qsort@plt>
  mov    %r13d,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <insertion@plt>
```

assistant: ```c
void sortPointers(void **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  do_qsort(vals, cmp, 0, total_elems - 1);
  insertion(vals, cmp, 0, total_elems - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sortPointers>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  mov    %rdx,%r12
  mov    %r13d,%ecx
  xor    %edx,%edx
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  call   <do_qsort@plt>
  mov    %r13d,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <insertion@plt>
```

assistant: ```c
void sortPointers(void **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  do_qsort(vals, cmp, 0, total_elems - 1);
  insertion(vals, cmp, 0, total_elems - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mixedSignedness18>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    -0x4(%rbp),%eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  cmpl   $0x80000000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  cmpl   $0xffffffff,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  jmp    L19
L2:
  nop
L19:
  leave
  ret
```

assistant: ```c
void mixedSignedness18(int a) {
  if (a >= 0)
    return;
  clang_analyzer_eval(a < 0);
  clang_analyzer_eval(a == (unsigned)(-((~0U) & ((~0U) >> 1)) - 1));
  clang_analyzer_eval(a == (~0U));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mixedSignedness18>:
  endbr64
  test   %edi,%edi
  js     L1
  ret
L1:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <clang_analyzer_eval@plt>
  cmp    $0x80000000,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  cmp    $0xffffffff,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  pop    %rbx
  ret
```

assistant: ```c
void mixedSignedness18(int a) {
  if (a >= 0)
    return;
  clang_analyzer_eval(a < 0);
  clang_analyzer_eval(a == (unsigned)(-((~0U) & ((~0U) >> 1)) - 1));
  clang_analyzer_eval(a == (~0U));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mixedSignedness18>:
  endbr64
  test   %edi,%edi
  js     L1
  ret
  nopl   0x0(%rax)
L1:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    $0x80000000,%ebx
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%ebx
  pop    %rbx
  sete   %dil
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void mixedSignedness18(int a) {
  if (a >= 0)
    return;
  clang_analyzer_eval(a < 0);
  clang_analyzer_eval(a == (unsigned)(-((~0U) & ((~0U) >> 1)) - 1));
  clang_analyzer_eval(a == (~0U));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mixedSignedness18>:
  endbr64
  test   %edi,%edi
  js     L1
  ret
  nopl   0x0(%rax)
L1:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    $0x80000000,%ebx
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%ebx
  pop    %rbx
  sete   %dil
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void mixedSignedness18(int a) {
  if (a >= 0)
    return;
  clang_analyzer_eval(a < 0);
  clang_analyzer_eval(a == (unsigned)(-((~0U) & ((~0U) >> 1)) - 1));
  clang_analyzer_eval(a == (~0U));
}
```
user: What is the c source code of the assembly code below?

```asm
<psmat4_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat4_negative@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_negative(struct mat4 *result, struct mat4 *m) {
  mat4_negative((float *)result, (float *)m);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psmat4_negative>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat4_negative@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_negative(struct mat4 *result, struct mat4 *m) {
  mat4_negative((float *)result, (float *)m);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psmat4_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_negative(struct mat4 *result, struct mat4 *m) {
  mat4_negative((float *)result, (float *)m);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %p


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%p\n", malloc(4));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: %p


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%p\n", malloc(4));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string

tool: D3: %p


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%p\n", malloc(4));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: %p


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%p\n", malloc(4));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BrzCaseFetch_requp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <TRACE_FOLLOW_THREAD@plt>
  mov    $0x1,%edi
  call   <SEND_REQUP@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzCaseFetch_requp(struct comp *comp, int port) {
  struct BrzCaseFetch_ *c = (struct BrzCaseFetch_ *)comp;
  TRACE_FOLLOW_THREAD(1, 0);
  SEND_REQUP(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BrzCaseFetch_requp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <TRACE_FOLLOW_THREAD@plt>
  mov    $0x1,%edi
  call   <SEND_REQUP@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzCaseFetch_requp(struct comp *comp, int port) {
  struct BrzCaseFetch_ *c = (struct BrzCaseFetch_ *)comp;
  TRACE_FOLLOW_THREAD(1, 0);
  SEND_REQUP(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BrzCaseFetch_requp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %esi,%esi
  call   <TRACE_FOLLOW_THREAD@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <SEND_REQUP@plt>
```

assistant: ```c
void BrzCaseFetch_requp(struct comp *comp, int port) {
  struct BrzCaseFetch_ *c = (struct BrzCaseFetch_ *)comp;
  TRACE_FOLLOW_THREAD(1, 0);
  SEND_REQUP(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BrzCaseFetch_requp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %esi,%esi
  call   <TRACE_FOLLOW_THREAD@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <SEND_REQUP@plt>
```

assistant: ```c
void BrzCaseFetch_requp(struct comp *comp, int port) {
  struct BrzCaseFetch_ *c = (struct BrzCaseFetch_ *)comp;
  TRACE_FOLLOW_THREAD(1, 0);
  SEND_REQUP(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<right_rotate_array_k_times_v4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L56
  cmpl   $0x0,-0xc(%rbp)
  jle    L56
  cmpl   $0x0,-0x10(%rbp)
  jle    L56
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L43
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse_array_section@plt>
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse_array_section@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse_array_section@plt>
  jmp    L20
L56:
  nop
  jmp    L20
L43:
  nop
L20:
  leave
  ret
```

assistant: ```c
void right_rotate_array_k_times_v4(int *array, int len, int k) {
  int index, index_k, j, prev, temp;
  int *copy;
  if (!array || (len <= 0) || (k <= 0)) {
    return;
  }
  k = k % len;
  if (!k) {
    return;
  }
  reverse_array_section(array, 0, len - 1);
  reverse_array_section(array, 0, k - 1);
  reverse_array_section(array, k, len - 1);
}
```