ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<get_next_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    $0x1f5,%edi
  call   <xmalloc@plt>
  mov    %rax,%r14
  mov    D93(%rip),%eax
  cmpl   $0x0,D85(%rip)
  je     L68
L37:
  mov    %eax,D66(%rip)
  mov    D85(%rip),%ecx
  cmp    %ecx,%eax
  jl     L77
  mov    %r14,%rbp
  mov    $0x0,%ebx
  lea    D66(%rip),%r12
  jmp    L82
L68:
  mov    $0x1f4,%edx
  lea    D66(%rip),%rsi
  mov    %r13d,%edi
  call   <xread@plt>
  jmp    L37
L39:
  add    $0x1,%ecx
  mov    %ecx,D40(%rip)
  movslq %ebx,%rbx
  movb   $0x0,(%r14,%rbx,1)
  jmp    L118
L38:
  mov    %eax,D40(%rip)
  mov    D40(%rip),%edx
  cmp    %eax,%edx
  mov    $0x0,%ecx
  cmovge %ecx,%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,D40(%rip)
  add    $0x1,%ebx
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%edx
  mov    %dl,0x0(%rbp)
  cmp    $0x1f4,%ebx
  jg     L97
  cmp    %eax,%ecx
  jg     L97
  add    $0x1,%rbp
  cmp    $0x1f4,%ebx
  je     L118
L82:
  movslq %ecx,%rdx
  cmpb   $0xa,(%r12,%rdx,1)
  je     L39
  cmp    %eax,%ecx
  jl     L38
  mov    $0x1f4,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <xread@plt>
  jmp    L38
L97:
  mov    $0x0,%r14d
L118:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  mov    $0x0,%r14d
  jmp    L118
```

assistant: ```c
char *get_next_line(const int fd) {
  static char buffer_read[500];
  static int i;
  static int cursor;
  int j;
  char *buffer_return;
  j = 0;
  buffer_return = xmalloc(sizeof(*buffer_return) * (500 + 1));
  cursor = (i == 0 ? xread(fd, buffer_read, 500) : cursor);
  while (i <= cursor && j <= 500) {
    if (j == 500)
      return (buffer_return);
    if (buffer_read[i] == '\n') {
      i++;
      buffer_return[j] = '\0';
      return (buffer_return);
    }
    cursor = (i >= cursor ? xread(fd, buffer_read, 500) : cursor);
    i = (i >= cursor ? 0 : i);
    buffer_return[j++] = buffer_read[i++];
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_next_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1f5,%edi
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    D57(%rip),%ecx
  mov    %rax,%r13
  mov    D14(%rip),%eax
  test   %ecx,%ecx
  je     L7
L68:
  mov    %eax,D29(%rip)
  xor    %ebp,%ebp
  lea    D29(%rip),%r12
  cmp    %eax,%ecx
  jle    L22
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L64:
  movslq D57(%rip),%rdx
  mov    %eax,D35(%rip)
  lea    0x1(%rdx),%ecx
  cmp    %eax,%edx
  jl     L16
  mov    $0x1,%ecx
  xor    %edx,%edx
L16:
  movzbl (%r12,%rdx,1),%edx
  mov    %ecx,D35(%rip)
  mov    %dl,0x0(%r13,%rbp,1)
  cmp    %eax,%ecx
  jg     L88
  add    $0x1,%rbp
  cmp    $0x1f4,%rbp
  je     L13
L22:
  movslq %ecx,%rdx
  movslq %ebp,%rsi
  cmpb   $0xa,(%r12,%rdx,1)
  je     L8
  cmp    %eax,%ecx
  jl     L64
  mov    $0x1f4,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <xread@plt>
  jmp    L64
  xchg   %ax,%ax
L88:
  xor    %r13d,%r13d
L13:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  add    $0x1,%ecx
  movb   $0x0,0x0(%r13,%rsi,1)
  mov    %r13,%rax
  mov    %ecx,D35(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  lea    D29(%rip),%r12
  mov    $0x1f4,%edx
  mov    %ebx,%edi
  mov    %r12,%rsi
  call   <xread@plt>
  mov    D35(%rip),%ecx
  jmp    L68
```

assistant: ```c
char *get_next_line(const int fd) {
  static char buffer_read[500];
  static int i;
  static int cursor;
  int j;
  char *buffer_return;
  j = 0;
  buffer_return = xmalloc(sizeof(*buffer_return) * (500 + 1));
  cursor = (i == 0 ? xread(fd, buffer_read, 500) : cursor);
  while (i <= cursor && j <= 500) {
    if (j == 500)
      return (buffer_return);
    if (buffer_read[i] == '\n') {
      i++;
      buffer_return[j] = '\0';
      return (buffer_return);
    }
    cursor = (i >= cursor ? xread(fd, buffer_read, 500) : cursor);
    i = (i >= cursor ? 0 : i);
    buffer_return[j++] = buffer_read[i++];
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_next_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1f5,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    D64(%rip),%edx
  mov    %rax,%r13
  mov    D55(%rip),%eax
  test   %edx,%edx
  je     L88
L3:
  mov    %eax,D26(%rip)
  xor    %ebx,%ebx
  lea    D26(%rip),%r12
  cmp    %eax,%edx
  jle    L7
  jmp    L85
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    %eax,D95(%rip)
L41:
  movslq %edx,%rcx
  add    $0x1,%edx
L14:
  movzbl (%r12,%rcx,1),%ecx
  mov    %edx,D95(%rip)
  mov    %cl,0x0(%r13,%rbx,1)
  cmp    %edx,%eax
  jl     L85
  add    $0x1,%rbx
  cmp    $0x1f4,%rbx
  je     L32
L7:
  movslq %edx,%rcx
  movslq %ebx,%rsi
  cmpb   $0xa,(%r12,%rcx,1)
  je     L21
  cmp    %eax,%edx
  jl     L94
  mov    $0x1f4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <xread@plt>
  mov    D95(%rip),%edx
  mov    %eax,D95(%rip)
  cmp    %eax,%edx
  jl     L41
  mov    $0x1,%edx
  xor    %ecx,%ecx
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L85:
  xor    %r13d,%r13d
L32:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  add    $0x1,%edx
  movb   $0x0,0x0(%r13,%rsi,1)
  mov    %r13,%rax
  mov    %edx,D95(%rip)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L88:
  lea    D26(%rip),%r12
  mov    $0x1f4,%edx
  mov    %ebp,%edi
  mov    %r12,%rsi
  call   <xread@plt>
  mov    D95(%rip),%edx
  jmp    L3
```

assistant: ```c
char *get_next_line(const int fd) {
  static char buffer_read[500];
  static int i;
  static int cursor;
  int j;
  char *buffer_return;
  j = 0;
  buffer_return = xmalloc(sizeof(*buffer_return) * (500 + 1));
  cursor = (i == 0 ? xread(fd, buffer_read, 500) : cursor);
  while (i <= cursor && j <= 500) {
    if (j == 500)
      return (buffer_return);
    if (buffer_read[i] == '\n') {
      i++;
      buffer_return[j] = '\0';
      return (buffer_return);
    }
    cursor = (i >= cursor ? xread(fd, buffer_read, 500) : cursor);
    i = (i >= cursor ? 0 : i);
    buffer_return[j++] = buffer_read[i++];
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x21656d2079706f43,%rax
  mov    %rax,-0x20(%rbp)
  movb   $0x0,-0x18(%rbp)
  movabs $0x2e2e2e2e2e2e2e2e,%rax
  mov    %rax,-0x17(%rbp)
  movl   $0x2e2e2e2e,-0xf(%rbp)
  movw   $0x2e2e,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x20(%rbp),%rcx
  lea    -0x17(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x17(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: Final string: '%s'


assistant: ```c
int main() {
  char src[] = "Copy me!";
  char dst[] = "..............";
  strncpy(dst, src, 4);
  printf("Final string: '%s'\n", dst);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x21656d2079706f43,%rax
  mov    %rax,(%rsp)
  movb   $0x0,0x8(%rsp)
  movabs $0x2e2e2e2e2e2e2e2e,%rax
  mov    %rax,0x9(%rsp)
  movl   $0x2e2e2e2e,0x11(%rsp)
  movw   $0x2e2e,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rsp,%rsi
  lea    0x9(%rsp),%rbx
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Final string: '%s'


assistant: ```c
int main() {
  char src[] = "Copy me!";
  char dst[] = "..............";
  strncpy(dst, src, 4);
  printf("Final string: '%s'\n", dst);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x21656d2079706f43,%rax
  lea    0x9(%rsp),%rbp
  mov    %rsp,%rsi
  movb   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  movl   $0x2e2e2e2e,0x11(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,(%rsp)
  movabs $0x2e2e2e2e2e2e2e2e,%rax
  mov    %rax,0x9(%rsp)
  mov    $0x2e2e,%eax
  mov    %ax,0x15(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Final string: '%s'


assistant: ```c
int main() {
  char src[] = "Copy me!";
  char dst[] = "..............";
  strncpy(dst, src, 4);
  printf("Final string: '%s'\n", dst);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x21656d2079706f43,%rax
  lea    0x9(%rsp),%rbp
  mov    %rsp,%rsi
  movb   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  movl   $0x2e2e2e2e,0x11(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,(%rsp)
  movabs $0x2e2e2e2e2e2e2e2e,%rax
  mov    %rax,0x9(%rsp)
  mov    $0x2e2e,%eax
  mov    %ax,0x15(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: Final string: '%s'


assistant: ```c
int main() {
  char src[] = "Copy me!";
  char dst[] = "..............";
  strncpy(dst, src, 4);
  printf("Final string: '%s'\n", dst);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_func_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cx,-0x18(%rbp)
  mov    %dl,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movzbl -0x14(%rbp),%edx
  movzwl -0x18(%rbp),%eax
  add    %eax,%edx
  movzbl -0x1c(%rbp),%eax
  add    %eax,%edx
  movzwl -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%edi
  movzwl -0x20(%rbp),%esi
  movzbl -0x1c(%rbp),%ecx
  movzwl -0x18(%rbp),%edx
  movzbl -0x14(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzwl -0x2(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string

tool: D0: %d %d %d %d: %d


assistant: ```c
unsigned short test_func_fn(unsigned char a1, unsigned short a2, unsigned char a3, unsigned short a4) {
  unsigned short result;
  result = a1 + a2 + a3 + a4;
  printf("%d %d %d %d: %d\n", a1, a2, a3, a4, result);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_func_fn>:
  endbr64
  push   %rbx
  mov    %ecx,%r8d
  movzbl %dl,%ebx
  add    %esi,%ebx
  add    %ecx,%ebx
  movzbl %dil,%ecx
  add    %ecx,%ebx
  movzbl %dl,%ecx
  movzwl %si,%edx
  movzbl %dil,%esi
  movzwl %bx,%r9d
  movzwl %r8w,%r8d
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: %d %d %d %d: %d


assistant: ```c
unsigned short test_func_fn(unsigned char a1, unsigned short a2, unsigned char a3, unsigned short a4) {
  unsigned short result;
  result = a1 + a2 + a3 + a4;
  printf("%d %d %d %d: %d\n", a1, a2, a3, a4, result);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_func_fn>:
  endbr64
  push   %r12
  movzbl %dl,%r12d
  mov    %ecx,%r8d
  add    %esi,%r12d
  movzwl %r8w,%r8d
  add    %ecx,%r12d
  movzbl %dil,%ecx
  add    %ecx,%r12d
  movzbl %dl,%ecx
  movzwl %si,%edx
  movzbl %dil,%esi
  movzwl %r12w,%r9d
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: %d %d %d %d: %d


assistant: ```c
unsigned short test_func_fn(unsigned char a1, unsigned short a2, unsigned char a3, unsigned short a4) {
  unsigned short result;
  result = a1 + a2 + a3 + a4;
  printf("%d %d %d %d: %d\n", a1, a2, a3, a4, result);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_func_fn>:
  endbr64
  push   %r12
  movzbl %dl,%r12d
  mov    %ecx,%r8d
  add    %esi,%r12d
  movzwl %r8w,%r8d
  add    %ecx,%r12d
  movzbl %dil,%ecx
  add    %ecx,%r12d
  movzbl %dl,%ecx
  movzwl %si,%edx
  movzbl %dil,%esi
  movzwl %r12w,%r9d
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d %d %d %d: %d


assistant: ```c
unsigned short test_func_fn(unsigned char a1, unsigned short a2, unsigned char a3, unsigned short a4) {
  unsigned short result;
  result = a1 + a2 + a3 + a4;
  printf("%d %d %d %d: %d\n", a1, a2, a3, a4, result);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CL_Quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <CL_Disconnect@plt>
  mov    $0x0,%eax
  call   <Com_Quit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CL_Quit(void) {
  CL_Disconnect(((void *)0));
  Com_Quit();
}
```
user: Translate the below assembly code into C programming language:

```asm
<CL_Quit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <CL_Disconnect@plt>
  mov    $0x0,%eax
  call   <Com_Quit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void CL_Quit(void) {
  CL_Disconnect(((void *)0));
  Com_Quit();
}
```
user: What is the c source code of the assembly code below?

```asm
<CL_Quit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <CL_Disconnect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <Com_Quit@plt>
```

assistant: ```c
void CL_Quit(void) {
  CL_Disconnect(((void *)0));
  Com_Quit();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CL_Quit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <CL_Disconnect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <Com_Quit@plt>
```

assistant: ```c
void CL_Quit(void) {
  CL_Disconnect(((void *)0));
  Com_Quit();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  lea    D57(%rip),%r14
  lea    D36(%rip),%r13
L46:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L46
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%r12
  lea    D50(%rip),%r13
L1:
  mov    (%r12),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L1
  mov    $0x9,%edi
  lea    0x24(%rbx),%rsi
  jmp    L27
L18:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L66
L79:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L18
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L18
L66:
  sub    $0x1,%edi
  je     L6
L27:
  mov    %rbx,%rax
  jmp    L79
L6:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    D50(%rip),%r12
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D57
type_infered: string
name: retrieve_data
arguments: data_tag: D36
type_infered: string
name: retrieve_data
arguments: data_tag: D42
type_infered: string
name: retrieve_data
arguments: data_tag: D50
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string

tool: D57: Enter a number --> 

tool: D36: %d

tool: D42: Numbers unsorted :

tool: D50: %6d

tool: D30: Numbers sorted :

assistant: ```c
int main() {
  int nums[10], i, j, temp;
  for (i = 0; i < 10; i++) {
    printf("Enter a number --> \n");
    scanf("%d", &nums[i]);
  }
  printf("Numbers unsorted :\n");
  for (i = 0; i < 10; i++) {
    printf("%6d", nums[i]);
    printf("\n");
  }
  for (j = 0; j < 10 - 1; j++)
    for (i = 0; i < 10 - 1; i++) {
      if (nums[i] > nums[i + 1]) {
        temp = nums[i];
        nums[i] = nums[i + 1];
        nums[i + 1] = temp;
      }
    }
  printf("Numbers sorted :\n");
  for (i = 0; i < 10; i++) {
    printf("%6d", nums[i]);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  nopl   0x0(%rax)
L53:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L53
  lea    D28(%rip),%rdi
  mov    %rbx,%r13
  lea    D45(%rip),%r12
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L55
  mov    $0x9,%edi
  lea    0x24(%rbx),%rsi
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L41
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L41:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L19
  sub    $0x1,%edi
  jne    L6
  lea    D15(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L26
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D45
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D7: Enter a number --> 

tool: D30: %d

tool: D28: Numbers unsorted :

tool: D45: %6d

tool: D15: Numbers sorted :

assistant: ```c
int main() {
  int nums[10], i, j, temp;
  for (i = 0; i < 10; i++) {
    printf("Enter a number --> \n");
    scanf("%d", &nums[i]);
  }
  printf("Numbers unsorted :\n");
  for (i = 0; i < 10; i++) {
    printf("%6d", nums[i]);
    printf("\n");
  }
  for (j = 0; j < 10 - 1; j++)
    for (i = 0; i < 10 - 1; i++) {
      if (nums[i] > nums[i + 1]) {
        temp = nums[i];
        nums[i] = nums[i + 1];
        nums[i + 1] = temp;
      }
    }
  printf("Numbers sorted :\n");
  for (i = 0; i < 10; i++) {
    printf("%6d", nums[i]);
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_sgid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rdx,%rcx
  lea    D18(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0xa0(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0xa8(%rbp)
  cmpq   $0x0,-0xa8(%rbp)
  jne    L33
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L29
L33:
  mov    -0xa8(%rbp),%rdx
  lea    -0xa0(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L64
  movl   $0x0,-0xbc(%rbp)
  movl   $0xc,-0xb8(%rbp)
  jmp    L31
L61:
  mov    -0xb8(%rbp),%eax
  add    $0x2,%eax
  cltq
  movb   $0x0,-0xa0(%rbp,%rax,1)
  mov    -0xb8(%rbp),%eax
  cltq
  lea    -0xa0(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xbc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0xb0(%rbp),%rax
  mov    $0x10,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtol@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0xbc(%rbp)
  addl   $0x3,-0xb8(%rbp)
L31:
  cmpl   $0xf,-0xbc(%rbp)
  jle    L61
  movl   $0x0,-0xb4(%rbp)
  jmp    L59
L64:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xffffffff,-0xb4(%rbp)
L59:
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xb4(%rbp),%eax
L29:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D30
type: string
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D11
type: string

tool: D18: //sys//class//net//%s//address

tool: D30: r

tool: D27: failed to open %s


tool: D11: failed to read sgid

assistant: ```c
int get_sgid(struct ifreq *ifr, union ibv_gid *sgid) {
  char buf[128], *end;
  FILE *f;
  int i, p, ret;
  snprintf(buf, sizeof buf, "//sys//class//net//%s//address", ifr->ifr_name);
  f = fopen(buf, "r");
  if (!f) {
    printf("failed to open %s\n", buf);
    return -1;
  }
  if (fgets(buf, sizeof buf, f)) {
    for (i = 0, p = 12; i < 16; i++, p += 3) {
      buf[p + 2] = '\0';
      sgid->raw[i] = (uint8_t)strtol(buf + p, &end, 16);
    }
    ret = 0;
  } else {
    printf("failed to read sgid\n");
    ret = -1;
  }
  fclose(f);
  return ret;
}
```