ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<ilogbk>:
  endbr64
  sub    $0x8,%rsp
  movsd  D12(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L7
  mulsd  D14(%rip),%xmm0
  call   <doubleToRawLongBits@plt>
  mov    $0x34,%ecx
  add    $0x8,%rsp
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x52b,%eax
  ret
  nopl   0x0(%rax)
L7:
  call   <doubleToRawLongBits@plt>
  mov    $0x34,%ecx
  add    $0x8,%rsp
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type: byte[8]
name: read_data
arguments: data_tag: D14
type: f64

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x2d]}

tool: D14: 2.037035976334486e+90

assistant: ```c
__attribute__((always_)) const int ilogbk(double d) {
  int m = d < 4.9090934652977266E-91;
  d = m ? 2.037035976334486E90 * d : d;
  int q = (doubleToRawLongBits(d) >> 52) & 0x7ff;
  q = m ? q - (300 + 0x03ff) : q - 0x03ff;
  return q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ilogbk>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L8
  mulsd  D4(%rip),%xmm0
  call   <doubleToRawLongBits@plt>
  mov    $0x34,%ecx
  add    $0x8,%rsp
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x52b,%eax
  ret
  nopl   0x0(%rax)
L8:
  call   <doubleToRawLongBits@plt>
  mov    $0x34,%ecx
  add    $0x8,%rsp
  sar    %cl,%eax
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: byte[8]
name: retrieve_data
arguments: data_label: D4
data_type: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x2d]}

tool: D4: 2.037035976334486e+90

assistant: ```c
__attribute__((always_)) const int ilogbk(double d) {
  int m = d < 4.9090934652977266E-91;
  d = m ? 2.037035976334486E90 * d : d;
  int q = (doubleToRawLongBits(d) >> 52) & 0x7ff;
  q = m ? q - (300 + 0x03ff) : q - 0x03ff;
  return q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dbg_tmr_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x48040000,%edi
  call   <DMTimerDisable@plt>
  mov    $0x0,%esi
  mov    $0x48040000,%edi
  call   <DMTimerCounterSet@plt>
  mov    $0x0,%esi
  mov    $0x48040000,%edi
  call   <DMTimerReloadSet@plt>
  mov    $0x2,%esi
  mov    $0x48040000,%edi
  call   <DMTimerModeConfigure@plt>
  mov    $0x28,%esi
  mov    $0x48040000,%edi
  call   <DMTimerPreScalerClkEnable@plt>
  mov    $0x48040000,%edi
  call   <DMTimerEnable@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dbg_tmr_reset(void) {
  DMTimerDisable((0x48040000));
  DMTimerCounterSet((0x48040000), 0x0);
  DMTimerReloadSet((0x48040000), 0x0);
  DMTimerModeConfigure((0x48040000), ((0x00000002u)));
  DMTimerPreScalerClkEnable((0x48040000), ((2 << (0x00000002u)) | (0x00000020u)));
  DMTimerEnable((0x48040000));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dbg_tmr_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x48040000,%edi
  call   <DMTimerDisable@plt>
  mov    $0x0,%esi
  mov    $0x48040000,%edi
  call   <DMTimerCounterSet@plt>
  mov    $0x0,%esi
  mov    $0x48040000,%edi
  call   <DMTimerReloadSet@plt>
  mov    $0x2,%esi
  mov    $0x48040000,%edi
  call   <DMTimerModeConfigure@plt>
  mov    $0x28,%esi
  mov    $0x48040000,%edi
  call   <DMTimerPreScalerClkEnable@plt>
  mov    $0x48040000,%edi
  call   <DMTimerEnable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dbg_tmr_reset(void) {
  DMTimerDisable((0x48040000));
  DMTimerCounterSet((0x48040000), 0x0);
  DMTimerReloadSet((0x48040000), 0x0);
  DMTimerModeConfigure((0x48040000), ((0x00000002u)));
  DMTimerPreScalerClkEnable((0x48040000), ((2 << (0x00000002u)) | (0x00000020u)));
  DMTimerEnable((0x48040000));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dbg_tmr_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x48040000,%edi
  call   <DMTimerDisable@plt>
  xor    %esi,%esi
  mov    $0x48040000,%edi
  call   <DMTimerCounterSet@plt>
  xor    %esi,%esi
  mov    $0x48040000,%edi
  call   <DMTimerReloadSet@plt>
  mov    $0x2,%esi
  mov    $0x48040000,%edi
  call   <DMTimerModeConfigure@plt>
  mov    $0x48040000,%edi
  mov    $0x28,%esi
  call   <DMTimerPreScalerClkEnable@plt>
  mov    $0x48040000,%edi
  add    $0x8,%rsp
  jmp    10f0 <DMTimerEnable@plt>
```

assistant: ```c
void dbg_tmr_reset(void) {
  DMTimerDisable((0x48040000));
  DMTimerCounterSet((0x48040000), 0x0);
  DMTimerReloadSet((0x48040000), 0x0);
  DMTimerModeConfigure((0x48040000), ((0x00000002u)));
  DMTimerPreScalerClkEnable((0x48040000), ((2 << (0x00000002u)) | (0x00000020u)));
  DMTimerEnable((0x48040000));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dbg_tmr_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x48040000,%edi
  call   <DMTimerDisable@plt>
  xor    %esi,%esi
  mov    $0x48040000,%edi
  call   <DMTimerCounterSet@plt>
  xor    %esi,%esi
  mov    $0x48040000,%edi
  call   <DMTimerReloadSet@plt>
  mov    $0x2,%esi
  mov    $0x48040000,%edi
  call   <DMTimerModeConfigure@plt>
  mov    $0x48040000,%edi
  mov    $0x28,%esi
  call   <DMTimerPreScalerClkEnable@plt>
  mov    $0x48040000,%edi
  add    $0x8,%rsp
  jmp    10f0 <DMTimerEnable@plt>
```

assistant: ```c
void dbg_tmr_reset(void) {
  DMTimerDisable((0x48040000));
  DMTimerCounterSet((0x48040000), 0x0);
  DMTimerReloadSet((0x48040000), 0x0);
  DMTimerModeConfigure((0x48040000), ((0x00000002u)));
  DMTimerPreScalerClkEnable((0x48040000), ((2 << (0x00000002u)) | (0x00000020u)));
  DMTimerEnable((0x48040000));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<realloc_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  mov    $0x0,%ecx
  mov    -0x10(%rbp),%rax
  mulq   -0x18(%rbp)
  jno    L24
  mov    $0x1,%ecx
L24:
  mov    %rcx,%rax
  test   %rax,%rax
  je     L23
  mov    $0x1,%eax
  jmp    L45
L23:
  mov    $0x0,%eax
L45:
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L28
  mov    $0x0,%eax
  jmp    L47
L28:
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L47:
  leave
  ret
```

assistant: ```c
__attribute__((alloc_size(2, 3))) void *realloc_multiply(void *p, size_t a, size_t b) {
  if ((__builtin_expect(!!(b != 0 && a > ((size_t)-1) / b), 0)))
    return NULL;
  return realloc(p, a * b);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<realloc_multiply>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%edi
  test   %rdx,%rdx
  je     L4
  mov    %rsi,%rax
  mul    %rbx
  seto   %dil
  movzbl %dil,%edi
L4:
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L17
  imul   %rbp,%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((alloc_size(2, 3))) void *realloc_multiply(void *p, size_t a, size_t b) {
  if ((__builtin_expect(!!(b != 0 && a > ((size_t)-1) / b), 0)))
    return NULL;
  return realloc(p, a * b);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<realloc_multiply>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L17
  mov    %rsi,%rax
  mul    %rbx
  seto   %dil
  movzbl %dil,%edi
L17:
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  imul   %rbp,%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <realloc@plt>
  nopl   (%rax)
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((alloc_size(2, 3))) void *realloc_multiply(void *p, size_t a, size_t b) {
  if ((__builtin_expect(!!(b != 0 && a > ((size_t)-1) / b), 0)))
    return NULL;
  return realloc(p, a * b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<realloc_multiply>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L8
  mov    %rsi,%rax
  mul    %rbx
  seto   %dil
  movzbl %dil,%edi
L8:
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L6
  imul   %rbp,%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <realloc@plt>
  nopl   (%rax)
L6:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((alloc_size(2, 3))) void *realloc_multiply(void *p, size_t a, size_t b) {
  if ((__builtin_expect(!!(b != 0 && a > ((size_t)-1) / b), 0)))
    return NULL;
  return realloc(p, a * b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <bar@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = bar(1, 2, 3, 4);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <bar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = bar(1, 2, 3, 4);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = bar(1, 2, 3, 4);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int ret;
  ret = bar(1, 2, 3, 4);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<charToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L51
L37:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <checkDigit@plt>
  test   %eax,%eax
  jne    L39
  mov    $0x0,%eax
  jmp    L27
L39:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L31
  mov    $0x0,%eax
  jmp    L27
L31:
  addl   $0x1,-0xc(%rbp)
L51:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    -0x8(%rbp),%rax
L27:
  leave
  ret
```

assistant: ```c
unsigned int charToInt(char *charNumber) {
  unsigned long long int number = 0;
  for (unsigned int i = 0; charNumber[i] != '\0'; i++) {
    if (!checkDigit(charNumber[i]))
      return 0;
    number = number * 10 + charNumber[i] - '0';
    if (number > INT_MAX)
      return 0;
  }
  return (unsigned int)number;
}
```
user: What is the c source code of the assembly code below?

```asm
<charToInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %r13,%rbx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L6:
  movsbl %dil,%edi
  call   <checkDigit@plt>
  test   %eax,%eax
  je     L8
  lea    0x0(%rbp,%rbp,4),%rdx
  movsbq (%rbx),%rax
  lea    -0x30(%rax,%rdx,2),%rbp
  mov    D7(%rip),%rax
  cmp    %rbp,(%rax)
  jb     L13
  add    $0x1,%r12d
  mov    %r12d,%ebx
  add    %r13,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L6
L44:
  mov    %ebp,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x0,%ebp
  jmp    L44
L8:
  mov    $0x0,%eax
  jmp    L34
L13:
  mov    $0x0,%eax
  jmp    L34
```

assistant: ```c
unsigned int charToInt(char *charNumber) {
  unsigned long long int number = 0;
  for (unsigned int i = 0; charNumber[i] != '\0'; i++) {
    if (!checkDigit(charNumber[i]))
      return 0;
    number = number * 10 + charNumber[i] - '0';
    if (number > INT_MAX)
      return 0;
  }
  return (unsigned int)number;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<charToInt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L49
  mov    %r12,%rbx
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L35:
  movsbq (%rbx),%rax
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    -0x30(%rax,%rdx,2),%rbp
  mov    D8(%rip),%rax
  cmp    %rbp,(%rax)
  jb     L49
  lea    0x1(%r13),%ebx
  mov    %rbx,%r13
  add    %r12,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L9
L46:
  call   <checkDigit@plt>
  test   %eax,%eax
  jne    L35
L49:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int charToInt(char *charNumber) {
  unsigned long long int number = 0;
  for (unsigned int i = 0; charNumber[i] != '\0'; i++) {
    if (!checkDigit(charNumber[i]))
      return 0;
    number = number * 10 + charNumber[i] - '0';
    if (number > INT_MAX)
      return 0;
  }
  return (unsigned int)number;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<charToInt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  mov    %r12,%rbx
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L30:
  movsbq (%rbx),%rax
  lea    0x0(%rbp,%rbp,4),%rdx
  lea    -0x30(%rax,%rdx,2),%rbp
  mov    D2(%rip),%rax
  cmp    %rbp,(%rax)
  jb     L10
  lea    0x1(%r13),%ebx
  mov    %rbx,%r13
  add    %r12,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L39
L20:
  call   <checkDigit@plt>
  test   %eax,%eax
  jne    L30
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int charToInt(char *charNumber) {
  unsigned long long int number = 0;
  for (unsigned int i = 0; charNumber[i] != '\0'; i++) {
    if (!checkDigit(charNumber[i]))
      return 0;
    number = number * 10 + charNumber[i] - '0';
    if (number > INT_MAX)
      return 0;
  }
  return (unsigned int)number;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buidMaxHeap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxHeapify@plt>
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x1,-0x4(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(int A[], int n) {
  buidMaxHeap(A, n);
  int i;
  for (i = n; i >= 2; i--) {
    swap(&A[1], &A[i]);
    n--;
    maxHeapify(A, n, 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heapSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  call   <buidMaxHeap@plt>
  cmp    $0x1,%ebx
  jle    L17
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rbp
  lea    0x4(%r12),%r13
L1:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  sub    $0x1,%ebx
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <maxHeapify@plt>
  sub    $0x4,%rbp
  cmp    $0x1,%ebx
  jne    L1
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapSort(int A[], int n) {
  buidMaxHeap(A, n);
  int i;
  for (i = n; i >= 2; i--) {
    swap(&A[1], &A[i]);
    n--;
    maxHeapify(A, n, 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heapSort>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <buidMaxHeap@plt>
  cmp    $0x1,%ebx
  jle    L6
  movslq %ebx,%rax
  lea    0x4(%r12),%r13
  lea    (%r12,%rax,4),%rbp
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    $0x1,%ebx
  sub    $0x4,%rbp
  call   <swap@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <maxHeapify@plt>
  cmp    $0x1,%ebx
  jne    L5
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapSort(int A[], int n) {
  buidMaxHeap(A, n);
  int i;
  for (i = n; i >= 2; i--) {
    swap(&A[1], &A[i]);
    n--;
    maxHeapify(A, n, 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heapSort>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <buidMaxHeap@plt>
  cmp    $0x1,%ebx
  jle    L12
  movslq %ebx,%rax
  lea    0x4(%r12),%r13
  lea    (%r12,%rax,4),%rbp
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    $0x1,%ebx
  sub    $0x4,%rbp
  call   <swap@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <maxHeapify@plt>
  cmp    $0x1,%ebx
  jne    L2
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapSort(int A[], int n) {
  buidMaxHeap(A, n);
  int i;
  for (i = n; i >= 2; i--) {
    swap(&A[1], &A[i]);
    n--;
    maxHeapify(A, n, 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vfoo32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  bswap  %eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x7f,-0x4(%rbp)
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vfoo32(unsigned int *a) {
  int i = 0;
  for (i = 0; i < 128; ++i)
    a[i] = __builtin_bswap32(a[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vfoo32>:
  endbr64
  lea    0x200(%rdi),%rdx
L9:
  mov    (%rdi),%eax
  bswap  %eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L9
  ret
```

assistant: ```c
void vfoo32(unsigned int *a) {
  int i = 0;
  for (i = 0; i < 128; ++i)
    a[i] = __builtin_bswap32(a[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vfoo32>:
  endbr64
  lea    0x200(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  bswap  %eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jne    L4
  ret
```

assistant: ```c
void vfoo32(unsigned int *a) {
  int i = 0;
  for (i = 0; i < 128; ++i)
    a[i] = __builtin_bswap32(a[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vfoo32>:
  endbr64
  lea    0x200(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  bswap  %eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jne    L9
  ret
```

assistant: ```c
void vfoo32(unsigned int *a) {
  int i = 0;
  for (i = 0; i < 128; ++i)
    a[i] = __builtin_bswap32(a[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wBasQuickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <wNotYet@plt>
  mov    $0x0,%edi
  call   <wPushNumber@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: QuickSort

assistant: ```c
void wBasQuickSort() {
  wNotYet("QuickSort");
  wPushNumber(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wBasQuickSort>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <wNotYet@plt>
  mov    $0x0,%edi
  call   <wPushNumber@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: QuickSort

assistant: ```c
void wBasQuickSort() {
  wNotYet("QuickSort");
  wPushNumber(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wBasQuickSort>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <wNotYet@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <wPushNumber@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: QuickSort

assistant: ```c
void wBasQuickSort() {
  wNotYet("QuickSort");
  wPushNumber(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<wBasQuickSort>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <wNotYet@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <wPushNumber@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: QuickSort

assistant: ```c
void wBasQuickSort() {
  wNotYet("QuickSort");
  wPushNumber(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Substitute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  lea    D4(%rip),%rbx
  jmp    L24
L30:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L34
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  jmp    L16
L34:
  movzbl -0x18(%rbp),%eax
L16:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  movb   $0x0,(%rbx)
  lea    D4(%rip),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *Substitute(char *string, char old, char n) {
  register char *ptr;
  static char area[1024];
  ptr = area;
  while (*string) {
    *(ptr++) = (*string == old ? n : *string);
    string++;
  }
  *ptr = '\0';
  return (area);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Substitute>:
  endbr64
  movzbl (%rdi),%eax
  lea    D8(%rip),%rcx
  test   %al,%al
  je     L15
L7:
  cmp    %al,%sil
  cmove  %edx,%eax
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L15:
  movb   $0x0,(%rcx)
  lea    D8(%rip),%rax
  ret
```

assistant: ```c
char *Substitute(char *string, char old, char n) {
  register char *ptr;
  static char area[1024];
  ptr = area;
  while (*string) {
    *(ptr++) = (*string == old ? n : *string);
    string++;
  }
  *ptr = '\0';
  return (area);
}
```