ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ConsoleInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0xe002c000,%eax
  mov    (%rax),%eax
  and    $0xfffffff0,%eax
  mov    %eax,%edx
  mov    $0xe002c000,%eax
  or     $0x5,%edx
  mov    %edx,(%rax)
  mov    $0xe000c00c,%eax
  movl   $0x83,(%rax)
  mov    -0x4(%rbp),%eax
  mov    $0xe000c000,%edx
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    $0xe000c004,%eax
  mov    %edx,(%rax)
  mov    $0xe000c00c,%eax
  movl   $0x3,(%rax)
  mov    $0xe000c008,%eax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ConsoleInit(int iDivider) {
  *(volatile unsigned int *)0xE002C000 = (*(volatile unsigned int *)0xE002C000 & ~0x0000000F) | 0x00000005;
  *(volatile unsigned int *)0xE000C00C = 0x83;
  *(volatile unsigned int *)0xE000C000 = iDivider & 0xFF;
  *(volatile unsigned int *)0xE000C004 = iDivider >> 8;
  *(volatile unsigned int *)0xE000C00C = 0x03;
  *(volatile unsigned int *)0xE000C008 = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ConsoleInit>:
  endbr64
  mov    $0xe002c000,%edx
  mov    (%rdx),%eax
  and    $0xfffffff0,%eax
  or     $0x5,%eax
  mov    %eax,(%rdx)
  lea    -0x1fff4(%rdx),%rdx
  movl   $0x83,(%rdx)
  movzbl %dil,%eax
  movabs %eax,0xe000c000
  sar    $0x8,%edi
  mov    %edi,%eax
  movabs %eax,0xe000c004
  movl   $0x3,(%rdx)
  mov    $0xe000c008,%eax
  movl   $0x1,(%rax)
  ret
```

assistant: ```c
void ConsoleInit(int iDivider) {
  *(volatile unsigned int *)0xE002C000 = (*(volatile unsigned int *)0xE002C000 & ~0x0000000F) | 0x00000005;
  *(volatile unsigned int *)0xE000C00C = 0x83;
  *(volatile unsigned int *)0xE000C000 = iDivider & 0xFF;
  *(volatile unsigned int *)0xE000C004 = iDivider >> 8;
  *(volatile unsigned int *)0xE000C00C = 0x03;
  *(volatile unsigned int *)0xE000C008 = 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ConsoleInit>:
  endbr64
  mov    $0xe002c000,%edx
  mov    (%rdx),%eax
  and    $0xfffffff0,%eax
  or     $0x5,%eax
  mov    %eax,(%rdx)
  movzbl %dil,%eax
  sar    $0x8,%edi
  movl   $0x83,-0x1fff4(%rdx)
  movabs %eax,0xe000c000
  mov    %edi,%eax
  movabs %eax,0xe000c004
  mov    $0xe000c008,%eax
  movl   $0x3,-0x1fff4(%rdx)
  movl   $0x1,(%rax)
  ret
```

assistant: ```c
void ConsoleInit(int iDivider) {
  *(volatile unsigned int *)0xE002C000 = (*(volatile unsigned int *)0xE002C000 & ~0x0000000F) | 0x00000005;
  *(volatile unsigned int *)0xE000C00C = 0x83;
  *(volatile unsigned int *)0xE000C000 = iDivider & 0xFF;
  *(volatile unsigned int *)0xE000C004 = iDivider >> 8;
  *(volatile unsigned int *)0xE000C00C = 0x03;
  *(volatile unsigned int *)0xE000C008 = 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ConsoleInit>:
  endbr64
  mov    $0xe002c000,%edx
  mov    (%rdx),%eax
  and    $0xfffffff0,%eax
  or     $0x5,%eax
  mov    %eax,(%rdx)
  movzbl %dil,%eax
  sar    $0x8,%edi
  movl   $0x83,-0x1fff4(%rdx)
  movabs %eax,0xe000c000
  mov    %edi,%eax
  movabs %eax,0xe000c004
  mov    $0xe000c008,%eax
  movl   $0x3,-0x1fff4(%rdx)
  movl   $0x1,(%rax)
  ret
```

assistant: ```c
void ConsoleInit(int iDivider) {
  *(volatile unsigned int *)0xE002C000 = (*(volatile unsigned int *)0xE002C000 & ~0x0000000F) | 0x00000005;
  *(volatile unsigned int *)0xE000C00C = 0x83;
  *(volatile unsigned int *)0xE000C000 = iDivider & 0xFF;
  *(volatile unsigned int *)0xE000C004 = iDivider >> 8;
  *(volatile unsigned int *)0xE000C00C = 0x03;
  *(volatile unsigned int *)0xE000C008 = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L72
L36:
  movl   $0x0,-0x8(%rbp)
  jmp    L67
L74:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L77
  addl   $0x1,-0x8(%rbp)
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L74
  jmp    L2
L77:
  nop
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L78
L12:
  addl   $0x1,-0xc(%rbp)
L72:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L36
  mov    $0x0,%eax
L78:
  leave
  ret
```

assistant: ```c
char *memstr(const char *haystack, const char *needle, int heystacklen) {
  int i, j, needlelen = strlen(needle);
  for (i = 0; i <= heystacklen - needlelen; i++) {
    for (j = 0; j < needlelen; j++)
      if (haystack[i + j] != needle[j])
        break;
    if (j >= needlelen)
      return (char *)haystack + i;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %r12d,%edx
  sub    %eax,%edx
  js     L10
  mov    %rbp,%rsi
  mov    $0x0,%r9d
  mov    %eax,%r8d
  jmp    L49
L69:
  cmp    %ecx,%eax
  jle    L35
  add    $0x1,%r9d
  add    $0x1,%rsi
  cmp    %edx,%r9d
  jg     L73
L49:
  test   %eax,%eax
  jle    L35
  mov    $0x0,%ecx
L12:
  movzbl (%rbx,%rcx,1),%r10d
  cmp    %r10b,(%rsi,%rcx,1)
  jne    L69
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L12
L35:
  movslq %r9d,%r9
  lea    0x0(%rbp,%r9,1),%rax
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0x0,%eax
  jmp    L55
L73:
  mov    $0x0,%eax
  jmp    L55
```

assistant: ```c
char *memstr(const char *haystack, const char *needle, int heystacklen) {
  int i, j, needlelen = strlen(needle);
  for (i = 0; i <= heystacklen - needlelen; i++) {
    for (j = 0; j < needlelen; j++)
      if (haystack[i + j] != needle[j])
        break;
    if (j >= needlelen)
      return (char *)haystack + i;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  sub    %eax,%ebp
  js     L13
  mov    %r12,%rcx
  xor    %edi,%edi
  movslq %eax,%rsi
  nopl   0x0(%rax)
L30:
  test   %eax,%eax
  jle    L14
  xor    %edx,%edx
  jmp    L19
L1:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L14
L19:
  movzbl (%rbx,%rdx,1),%r8d
  cmp    %r8b,(%rcx,%rdx,1)
  je     L1
  add    $0x1,%edi
  add    $0x1,%rcx
  cmp    %ebp,%edi
  jle    L30
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  movslq %edi,%rdi
  pop    %rbx
  pop    %rbp
  lea    (%r12,%rdi,1),%rax
  pop    %r12
  ret
```

assistant: ```c
char *memstr(const char *haystack, const char *needle, int heystacklen) {
  int i, j, needlelen = strlen(needle);
  for (i = 0; i <= heystacklen - needlelen; i++) {
    for (j = 0; j < needlelen; j++)
      if (haystack[i + j] != needle[j])
        break;
    if (j >= needlelen)
      return (char *)haystack + i;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<memstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  sub    %eax,%ebp
  js     L22
  mov    %r12,%rcx
  xor    %edi,%edi
  movslq %eax,%rsi
  nopl   0x0(%rax)
L57:
  test   %eax,%eax
  jle    L56
  xor    %edx,%edx
  jmp    L14
L20:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L56
L14:
  movzbl (%rbx,%rdx,1),%r8d
  cmp    %r8b,(%rcx,%rdx,1)
  je     L20
  add    $0x1,%edi
  add    $0x1,%rcx
  cmp    %ebp,%edi
  jle    L57
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  movslq %edi,%rdi
  pop    %rbx
  pop    %rbp
  lea    (%r12,%rdi,1),%rax
  pop    %r12
  ret
```

assistant: ```c
char *memstr(const char *haystack, const char *needle, int heystacklen) {
  int i, j, needlelen = strlen(needle);
  for (i = 0; i <= heystacklen - needlelen; i++) {
    for (j = 0; j < needlelen; j++)
      if (haystack[i + j] != needle[j])
        break;
    if (j >= needlelen)
      return (char *)haystack + i;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTSmartCardDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x30,%edx
  movslq %edx,%rdx
  and    $0xfffffff7,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTSmartCardDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~0x00000008;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTSmartCardDisable>:
  endbr64
  add    $0x30,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffff7,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTSmartCardDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~0x00000008;
}
```
user: What is the c source code of the assembly code below?

```asm
<UARTSmartCardDisable>:
  endbr64
  add    $0x30,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffff7,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTSmartCardDisable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~0x00000008;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L2
L39:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L11
  mov    %r12d,%eax
  jmp    L35
L11:
  add    $0x1,%r12d
  add    $0x1,%ebx
L2:
  cmp    -0x24(%rbp),%ebx
  ja     L27
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
L27:
  mov    $0xffffffff,%eax
L35:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int strnpos(char *s, char *ch, unsigned int count) {
  register unsigned int pos = 0, i;
  for (i = 0; i <= count && *s; i++) {
    if (*s++ == *ch)
      return pos;
    pos++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strnpos>:
  endbr64
  mov    $0x0,%eax
L7:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L22
  cmp    %cl,(%rsi)
  je     L24
  add    $0x1,%rax
  cmp    %eax,%edx
  jae    L7
  mov    $0xffffffff,%eax
L24:
  ret
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strnpos(char *s, char *ch, unsigned int count) {
  register unsigned int pos = 0, i;
  for (i = 0; i <= count && *s; i++) {
    if (*s++ == *ch)
      return pos;
    pos++;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strnpos>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L28
  cmp    %cl,(%rsi)
  je     L7
  add    $0x1,%rax
  cmp    %eax,%edx
  jae    L1
L28:
  mov    $0xffffffff,%eax
L7:
  ret
```

assistant: ```c
int strnpos(char *s, char *ch, unsigned int count) {
  register unsigned int pos = 0, i;
  for (i = 0; i <= count && *s; i++) {
    if (*s++ == *ch)
      return pos;
    pos++;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strnpos>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L27
  cmp    %cl,(%rsi)
  je     L1
  add    $0x1,%rax
  cmp    %eax,%edx
  jae    L19
L27:
  mov    $0xffffffff,%eax
L1:
  ret
```

assistant: ```c
int strnpos(char *s, char *ch, unsigned int count) {
  register unsigned int pos = 0, i;
  for (i = 0; i <= count && *s; i++) {
    if (*s++ == *ch)
      return pos;
    pos++;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L0
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L23:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L23
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L0:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mstrncpy(const char *src, size_t len) {
  const char *s = src;
  char *b = NULL, *d;
  size_t i;
  if (s != NULL && len >= 0) {
    if ((b = (char *)malloc(len + 1))) {
      d = b;
      for (i = 0; i < len; i++)
        *d++ = *s++;
      *d = '\0';
    }
  }
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mstrncpy>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L32
  test   %rbp,%rbp
  je     L16
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
L6:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  movzbl -0x1(%rdx,%rbx,1),%esi
  mov    %sil,(%rcx)
  cmp    %rdi,%rdx
  jne    L6
  add    %rbp,%rax
L16:
  movb   $0x0,(%rax)
L32:
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *mstrncpy(const char *src, size_t len) {
  const char *s = src;
  char *b = NULL, *d;
  size_t i;
  if (s != NULL && len >= 0) {
    if ((b = (char *)malloc(len + 1))) {
      d = b;
      for (i = 0; i < len; i++)
        *d++ = *s++;
      *d = '\0';
    }
  }
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mstrncpy>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L19
  test   %rbx,%rbx
  je     L9
  mov    %rbp,%rdi
  lea    (%rax,%rbx,1),%rsi
  mov    %rax,%rdx
  sub    %rax,%rdi
  nopl   (%rax)
L47:
  mov    %rdx,%rcx
  movzbl (%rdx,%rdi,1),%r8d
  add    $0x1,%rdx
  mov    %r8b,(%rcx)
  cmp    %rsi,%rdx
  jne    L47
L25:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rax,%rdx
  jmp    L25
```

assistant: ```c
char *mstrncpy(const char *src, size_t len) {
  const char *s = src;
  char *b = NULL, *d;
  size_t i;
  if (s != NULL && len >= 0) {
    if ((b = (char *)malloc(len + 1))) {
      d = b;
      for (i = 0; i < len; i++)
        *d++ = *s++;
      *d = '\0';
    }
  }
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mstrncpy>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L151
  mov    %rax,%r8
  test   %rbx,%rbx
  je     L162
  lea    0x1(%rbp),%rsi
  mov    %rax,%rcx
  lea    -0x1(%rbx),%rdx
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L139
  cmp    $0x6,%rdx
  jbe    L139
  cmp    $0xe,%rdx
  jbe    L67
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rcx
  sub    %rax,%rsi
  add    %rax,%rcx
  nopl   0x0(%rax)
L49:
  movdqu (%rdx,%rsi,1),%xmm0
  add    $0x10,%rdx
  movups %xmm0,-0x10(%rdx)
  cmp    %rcx,%rdx
  jne    L49
  mov    %rbx,%rcx
  and    $0xfffffffffffffff0,%rcx
  lea    0x0(%rbp,%rcx,1),%rsi
  lea    (%rax,%rcx,1),%rdx
  cmp    %rcx,%rbx
  je     L111
  mov    %rbx,%r9
  sub    %rcx,%r9
  lea    -0x1(%r9),%rdi
  cmp    $0x6,%rdi
  jbe    L22
L166:
  mov    0x0(%rbp,%rcx,1),%rdi
  mov    %rdi,(%rax,%rcx,1)
  mov    %r9,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rsi
  add    %rdi,%rdx
  add    %rdi,%rcx
  cmp    %r9,%rdi
  je     L57
L22:
  movzbl (%rsi),%edi
  mov    %dil,(%rdx)
  lea    0x1(%rcx),%rdi
  cmp    %rdi,%rbx
  jbe    L57
  movzbl 0x1(%rsi),%edi
  mov    %dil,0x1(%rdx)
  lea    0x2(%rcx),%rdi
  cmp    %rdi,%rbx
  jbe    L57
  movzbl 0x2(%rsi),%edi
  mov    %dil,0x2(%rdx)
  lea    0x3(%rcx),%rdi
  cmp    %rdi,%rbx
  jbe    L57
  movzbl 0x3(%rsi),%edi
  mov    %dil,0x3(%rdx)
  lea    0x4(%rcx),%rdi
  cmp    %rdi,%rbx
  jbe    L57
  movzbl 0x4(%rsi),%edi
  mov    %dil,0x4(%rdx)
  lea    0x5(%rcx),%rdi
  cmp    %rdi,%rbx
  jbe    L57
  movzbl 0x5(%rsi),%edi
  add    $0x6,%rcx
  mov    %dil,0x5(%rdx)
  cmp    %rcx,%rbx
  jbe    L57
  movzbl 0x6(%rsi),%ecx
  mov    %cl,0x6(%rdx)
L57:
  lea    (%rax,%rbx,1),%rdx
L111:
  movb   $0x0,(%rdx)
L151:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L21:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L139:
  lea    (%rbx,%rax,1),%rdx
  sub    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L189:
  mov    %rax,%rcx
  movzbl (%rax,%rbp,1),%esi
  add    $0x1,%rax
  mov    %sil,(%rcx)
  cmp    %rdx,%rax
  jne    L189
  jmp    L111
  nopl   (%rax)
L162:
  mov    %rax,%rdx
  jmp    L111
L67:
  mov    %rbx,%r9
  mov    %rax,%rdx
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  jmp    L166
```

assistant: ```c
char *mstrncpy(const char *src, size_t len) {
  const char *s = src;
  char *b = NULL, *d;
  size_t i;
  if (s != NULL && len >= 0) {
    if ((b = (char *)malloc(len + 1))) {
      d = b;
      for (i = 0; i < len; i++)
        *d++ = *s++;
      *d = '\0';
    }
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L96
L77:
  lea    D47(%rip),%rbp
  jmp    L19
L96:
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jne    L77
L31:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L64:
  mov    %r13d,0x4(%rsp)
  test   %r13d,%r13d
  je     L31
L40:
  movslq %ebx,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,%r13d
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  mov    %ebx,%esi
  sub    %eax,%esi
  mov    %ebx,%eax
  mov    %r13d,%ebx
  cmp    $0x9,%eax
  jg     L36
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L64
L78:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L31
L19:
  test   %ebx,%ebx
  jns    L78
  neg    %ebx
  mov    %ebx,0x4(%rsp)
  lea    D47(%rip),%r12
  lea    D18(%rip),%rbp
  jmp    L40
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D47
datatype: string
name: disassemble_data
arguments: label: D67
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string

tool: D25: 
Enter an integer > 

tool: D32: %d

tool: D47: 
%d

tool: D67: 
0

tool: D4: 
That's all, have a nice day!

tool: D18: 
-%d

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  if (n == 0)
    printf("\n0");
  while (n) {
    if (n < 0) {
      n = -n;
      while (n) {
        r = n % 10;
        nn = n / 10;
        if (n < 10) {
          printf("\n-%d", r);
        } else if (n >= 10) {
          printf("\n%d", r);
        }
        n = nn;
      }
    } else {
      r = n % 10;
      nn = n / 10;
      n = nn;
      printf("\n%d", r);
    }
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r14d
  test   %r14d,%r14d
  je     L102
L29:
  lea    D12(%rip),%rbx
  jmp    L6
  nopl   0x0(%rax)
L48:
  movslq %r14d,%rax
  mov    %r14d,%edx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  test   %r14d,%r14d
  je     L45
L6:
  test   %r14d,%r14d
  jns    L48
  neg    %r14d
  mov    $0xcccccccd,%ebp
  lea    D12(%rip),%r13
  mov    %r14d,0x4(%rsp)
  lea    D64(%rip),%r12
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  je     L45
L23:
  mov    %r14d,%ebx
  mov    %r14d,%esi
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %r14d,%eax
  mov    %ebx,%r14d
  cmp    $0x9,%eax
  jle    L53
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  jne    L23
L45:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L102:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  test   %r14d,%r14d
  jne    L29
  jmp    L45
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D49
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D64
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string

tool: D28: 
Enter an integer > 

tool: D49: %d

tool: D12: 
%d

tool: D64: 
-%d

tool: D43: 
That's all, have a nice day!

tool: D26: 
0

assistant: ```c
int main() {
  int n, r, nn;
  printf("\nEnter an integer > ");
  scanf("%d", &n);
  if (n == 0)
    printf("\n0");
  while (n) {
    if (n < 0) {
      n = -n;
      while (n) {
        r = n % 10;
        nn = n / 10;
        if (n < 10) {
          printf("\n-%d", r);
        } else if (n >= 10) {
          printf("\n%d", r);
        }
        n = nn;
      }
    } else {
      r = n % 10;
      nn = n / 10;
      n = nn;
      printf("\n%d", r);
    }
  }
  printf("\nThat's all, have a nice day!\n");
  return 0;
}
```