ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<errexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
int errexit(const char *format, ...) {
  va_list argsList;
  va_start(argsList, format);
  vfprintf(stderr, format, argsList);
  va_end(argsList);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<errexit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int errexit(const char *format, ...) {
  va_list argsList;
  va_start(argsList, format);
  vfprintf(stderr, format, argsList);
  va_end(argsList);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<errexit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int errexit(const char *format, ...) {
  va_list argsList;
  va_start(argsList, format);
  vfprintf(stderr, format, argsList);
  va_end(argsList);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<errexit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int errexit(const char *format, ...) {
  va_list argsList;
  va_start(argsList, format);
  vfprintf(stderr, format, argsList);
  va_end(argsList);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<br_enc32be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void br_enc32be(unsigned char *dst, uint32_t x) {
  dst[3] = (unsigned char)x;
  dst[2] = (unsigned char)(x >> 8);
  dst[1] = (unsigned char)(x >> 16);
  dst[0] = (unsigned char)(x >> 24);
}
```
user: Translate the below assembly code into C programming language:

```asm
<br_enc32be>:
  endbr64
  mov    %esi,%eax
  mov    %sil,0x3(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x1(%rdi)
  sar    $0x18,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void br_enc32be(unsigned char *dst, uint32_t x) {
  dst[3] = (unsigned char)x;
  dst[2] = (unsigned char)(x >> 8);
  dst[1] = (unsigned char)(x >> 16);
  dst[0] = (unsigned char)(x >> 24);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<br_enc32be>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void br_enc32be(unsigned char *dst, uint32_t x) {
  dst[3] = (unsigned char)x;
  dst[2] = (unsigned char)(x >> 8);
  dst[1] = (unsigned char)(x >> 16);
  dst[0] = (unsigned char)(x >> 24);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<br_enc32be>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void br_enc32be(unsigned char *dst, uint32_t x) {
  dst[3] = (unsigned char)x;
  dst[2] = (unsigned char)(x >> 8);
  dst[1] = (unsigned char)(x >> 16);
  dst[0] = (unsigned char)(x >> 24);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_logname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x28(%rbp)
  lea    -0x12(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string

tool: D5: %Y%W

tool: D10: %s

assistant: ```c
char *get_logname(void) {
  time_t clocker;
  struct tm *tm;
  char buf[10], bufs[10], *p;
  time(&clocker);
  tm = localtime(&clocker);
  strftime(buf, sizeof(buf), "%Y%W", tm);
  sprintf(bufs, "%s", buf);
  p = (char *)calloc(sizeof(char), 10);
  strcpy(p, bufs);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_logname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    0x4(%rsp),%rbx
  lea    D19(%rip),%rdx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  lea    0xe(%rsp),%rbp
  mov    %rbx,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D5
data_type: string

tool: D19: %Y%W

tool: D5: %s

assistant: ```c
char *get_logname(void) {
  time_t clocker;
  struct tm *tm;
  char buf[10], bufs[10], *p;
  time(&clocker);
  tm = localtime(&clocker);
  strftime(buf, sizeof(buf), "%Y%W", tm);
  sprintf(bufs, "%s", buf);
  p = (char *)calloc(sizeof(char), 10);
  strcpy(p, bufs);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_logname>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  lea    0xe(%rsp),%rbp
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    $0xa,%esi
  lea    D2(%rip),%rdx
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D2: %Y%W

tool: D5: %s

assistant: ```c
char *get_logname(void) {
  time_t clocker;
  struct tm *tm;
  char buf[10], bufs[10], *p;
  time(&clocker);
  tm = localtime(&clocker);
  strftime(buf, sizeof(buf), "%Y%W", tm);
  sprintf(bufs, "%s", buf);
  p = (char *)calloc(sizeof(char), 10);
  strcpy(p, bufs);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_logname>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  lea    0xe(%rsp),%rbp
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    $0xa,%esi
  lea    D0(%rip),%rdx
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string

tool: D0: %Y%W

tool: D6: %s

assistant: ```c
char *get_logname(void) {
  time_t clocker;
  struct tm *tm;
  char buf[10], bufs[10], *p;
  time(&clocker);
  tm = localtime(&clocker);
  strftime(buf, sizeof(buf), "%Y%W", tm);
  sprintf(bufs, "%s", buf);
  p = (char *)calloc(sizeof(char), 10);
  strcpy(p, bufs);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<testPrecedence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x2b,-0x2(%rbp)
  movb   $0x2a,-0x1(%rbp)
  movsbl -0x1(%rbp),%edx
  movsbl -0x2(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <precedence@plt>
  mov    %eax,%ecx
  movsbl -0x1(%rbp),%edx
  movsbl -0x2(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: precedence( %c, %c ) = %d 


assistant: ```c
void testPrecedence() {
  char op1 = '+', op2 = '*';
  printf("precedence( %c, %c ) = %d \n", op1, op2, precedence(op1, op2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testPrecedence>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  mov    $0x2b,%edi
  call   <precedence@plt>
  mov    %eax,%ecx
  mov    $0x2a,%edx
  mov    $0x2b,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: precedence( %c, %c ) = %d 


assistant: ```c
void testPrecedence() {
  char op1 = '+', op2 = '*';
  printf("precedence( %c, %c ) = %d \n", op1, op2, precedence(op1, op2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testPrecedence>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  mov    $0x2b,%edi
  call   <precedence@plt>
  mov    $0x2a,%edx
  mov    $0x2b,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%ecx
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: precedence( %c, %c ) = %d 


assistant: ```c
void testPrecedence() {
  char op1 = '+', op2 = '*';
  printf("precedence( %c, %c ) = %d \n", op1, op2, precedence(op1, op2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testPrecedence>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  mov    $0x2b,%edi
  call   <precedence@plt>
  mov    $0x2a,%edx
  mov    $0x2b,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%ecx
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: precedence( %c, %c ) = %d 


assistant: ```c
void testPrecedence() {
  char op1 = '+', op2 = '*';
  printf("precedence( %c, %c ) = %d \n", op1, op2, precedence(op1, op2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_striter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L48
  cmpq   $0x0,-0x10(%rbp)
  je     L48
  jmp    L3
L38:
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  jmp    L42
L48:
  nop
L42:
  leave
  ret
```

assistant: ```c
void ft_striter(char *str, void (*f)(char *)) {
  if (!str || !f)
    return;
  while (*str != '\0') {
    f(str);
    str++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L17
  cmpb   $0x0,(%rdi)
  je     L17
L10:
  mov    %rbx,%rdi
  call   *%rbp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L10
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  ret
```

assistant: ```c
void ft_striter(char *str, void (*f)(char *)) {
  if (!str || !f)
    return;
  while (*str != '\0') {
    f(str);
    str++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L33
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L33
  nop
L24:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L24
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L34:
  ret
```

assistant: ```c
void ft_striter(char *str, void (*f)(char *)) {
  if (!str || !f)
    return;
  while (*str != '\0') {
    f(str);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_striter>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L7
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L7
  nop
L23:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   *%rbp
  cmpb   $0x0,(%rbx)
  jne    L23
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L36:
  ret
```

assistant: ```c
void ft_striter(char *str, void (*f)(char *)) {
  if (!str || !f)
    return;
  while (*str != '\0') {
    f(str);
    str++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multipRec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L6
L19:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multipRec>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L6:
  leave
  ret
```

assistant: ```c
int multipRec(int n1, int n2) {
  if (n2 == 0)
    return 0;
  return n1 + multipRec(n1, n2 - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multipRec>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jne    L0
  ret
L0:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rsi),%esi
  call   <multipRec>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int multipRec(int n1, int n2) {
  if (n2 == 0)
    return 0;
  return n1 + multipRec(n1, n2 - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multipRec>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int multipRec(int n1, int n2) {
  if (n2 == 0)
    return 0;
  return n1 + multipRec(n1, n2 - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multipRec>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int multipRec(int n1, int n2) {
  if (n2 == 0)
    return 0;
  return n1 + multipRec(n1, n2 - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RSA_padding_add_none>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L30
  mov    D29(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L0
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L7
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L0
L7:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L0:
  leave
  ret
```

assistant: ```c
int RSA_padding_add_none(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  if (flen > tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  if (flen < tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_SMALL_FOR_KEY_SIZE);
    return (0);
  }
  memcpy(to, from, (unsigned int)flen);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RSA_padding_add_none>:
  endbr64
  sub    $0x8,%rsp
  cmp    %esi,%ecx
  jg     L10
  mov    %rdx,%rsi
  jl     L4
  mov    %ecx,%edx
  call   <memcpy@plt>
  mov    $0x1,%eax
L34:
  add    $0x8,%rsp
  ret
L10:
  mov    D29(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L34
L4:
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L34
```

assistant: ```c
int RSA_padding_add_none(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  if (flen > tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  if (flen < tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_SMALL_FOR_KEY_SIZE);
    return (0);
  }
  memcpy(to, from, (unsigned int)flen);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RSA_padding_add_none>:
  endbr64
  sub    $0x8,%rsp
  cmp    %esi,%ecx
  jg     L6
  jl     L18
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <memcpy@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    D10(%rip),%rax
L27:
  mov    (%rax),%esi
  mov    D26(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    D21(%rip),%rax
  jmp    L27
```

assistant: ```c
int RSA_padding_add_none(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  if (flen > tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  if (flen < tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_SMALL_FOR_KEY_SIZE);
    return (0);
  }
  memcpy(to, from, (unsigned int)flen);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RSA_padding_add_none>:
  endbr64
  sub    $0x8,%rsp
  cmp    %esi,%ecx
  jg     L13
  jl     L0
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <memcpy@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    D16(%rip),%rax
L25:
  mov    (%rax),%esi
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    D21(%rip),%rax
  jmp    L25
```

assistant: ```c
int RSA_padding_add_none(unsigned char *to, int tlen, const unsigned char *from, int flen) {
  if (flen > tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_LARGE_FOR_KEY_SIZE);
    return (0);
  }
  if (flen < tlen) {
    RSAerr(RSA_F_RSA_PADDING_ADD_NONE, RSA_R_DATA_TOO_SMALL_FOR_KEY_SIZE);
    return (0);
  }
  memcpy(to, from, (unsigned int)flen);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Sigma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L2
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L11
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double Sigma(const double *data, int num) {
  int i;
  double mean = 0.0, sum = 0.0, tmp;
  for (i = 0; i < num; i++)
    mean += data[i];
  mean /= (double)num;
  for (i = 0; i < num; i++) {
    tmp = data[i] - mean;
    sum += tmp * tmp;
  }
  return sqrt(sum / (double)num);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Sigma>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L0:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L0
  pxor   %xmm3,%xmm3
  cvtsi2sd %esi,%xmm3
  divsd  %xmm3,%xmm0
  pxor   %xmm2,%xmm2
L8:
  movsd  (%rax),%xmm1
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L8
L17:
  divsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm2,%xmm1
  ja     L20
  sqrtsd %xmm0,%xmm0
  ret
L20:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
L4:
  pxor   %xmm3,%xmm3
  cvtsi2sd %esi,%xmm3
  pxor   %xmm2,%xmm2
  jmp    L17
```

assistant: ```c
double Sigma(const double *data, int num) {
  int i;
  double mean = 0.0, sum = 0.0, tmp;
  for (i = 0; i < num; i++)
    mean += data[i];
  mean /= (double)num;
  for (i = 0; i < num; i++) {
    tmp = data[i] - mean;
    sum += tmp * tmp;
  }
  return sqrt(sum / (double)num);
}
```