ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sqlite3StrNDup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L0
  movslq %esi,%rbx
  mov    %rdi,%rbp
  mov    $0x1,%esi
  lea    0x1(%rbx),%edi
  call   <sqlite3MallocRaw@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *sqlite3StrNDup(const char *z, int n) {
  char *zNew;
  if (z == 0)
    return 0;
  zNew = sqlite3MallocRaw(n + 1, 1);
  if (zNew) {
    memcpy(zNew, z, n);
    zNew[n] = 0;
  }
  return zNew;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<microtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D6(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: f64

tool: D6: 1000000

assistant: ```c
double microtime() {
  struct timeval tm;
  gettimeofday(&tm, 0);
  return tm.tv_sec + tm.tv_usec / 1000000.0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<microtime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D7(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: f64

tool: D7: 1000000

assistant: ```c
double microtime() {
  struct timeval tm;
  gettimeofday(&tm, 0);
  return tm.tv_sec + tm.tv_usec / 1000000.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<microtime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D3(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: f64

tool: D3: 1000000

assistant: ```c
double microtime() {
  struct timeval tm;
  gettimeofday(&tm, 0);
  return tm.tv_sec + tm.tv_usec / 1000000.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<microtime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D4(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: f64

tool: D4: 1000000

assistant: ```c
double microtime() {
  struct timeval tm;
  gettimeofday(&tm, 0);
  return tm.tv_sec + tm.tv_usec / 1000000.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  char *aString = "Hello, World!";
  const char *aConstString = "Hello, World!";
  char aChar = 'a';
  const char aConstChar = 'b';
  signed char aSignedChar = 'c';
  const signed char aConstSignedChar = 'd';
  unsigned char aUnsignedChar = 'e';
  const unsigned char aConstUnsignedChar = 'f';
  short aShort = -32767;
  const short aConstShort = -32767;
  signed short aSignedShort = -32767;
  const signed short aConstSignedShort = -32767;
  signed short int aSignedShortInt = -32767;
  const signed short int aConstSignedShortInt = -32767;
  unsigned short aUnsignedShort = 32767;
  const unsigned short aConstUnsignedShort = 32767;
  unsigned short int aUnsignedShortInt = 32767;
  const unsigned short int aConstUnsignedShortInt = 32767;
  int aInt = -32767;
  const int aConstInt = -32767;
  signed int aSignedInt = -32767;
  const signed int aConstSignedInt = -32767;
  unsigned aUnsigned = -32767;
  const unsigned aConstUnsigned = -32767;
  unsigned int aUnsignedInt = -32767;
  const unsigned int aConstUnsignedInt = -32767;
  long aLong = -2147483647;
  const long aConstLong = -2147483647;
  long int aLongInt = -2147483647;
  const long int aConstLongInt = -2147483647;
  signed long aSignedLong = -2147483647;
  const signed long aConstSignedLong = -2147483647;
  signed long int aSignedLongInt = -2147483647;
  const signed long int aConstSignedLongInt = -2147483647;
  unsigned long aUnsignedLong = 2147483647;
  const unsigned long aConstUnsignedLong = 2147483647;
  unsigned long int aUnsignedLongInt = 2147483647;
  const unsigned long int aConstUnsignedLongInt = 2147483647;
  long long aLongLong = -9223372036854775807;
  const long long aConstLongLong = -9223372036854775807;
  long long int aLongLongInt = -9223372036854775807;
  const long long int aConstLongLongInt = -9223372036854775807;
  signed long long aSignedLongLong = -9223372036854775807;
  const signed long long aConstSignedLongLong = -9223372036854775807;
  signed long long int aSignedLongLongInt = -9223372036854775807;
  const signed long long int aConstSignedLongLongInt = -9223372036854775807;
  unsigned long long aUnsignedLongLong = 9223372036854775807;
  const unsigned long long aConstUnsignedLongLong = 9223372036854775807;
  unsigned long long int aUnsignedLongLongInt = 9223372036854775807;
  const unsigned long long int aConstUnsignedLongLongInt = 9223372036854775807;
  float aFloat = 3.14295;
  const float aConstFloat = 3.14295;
  double aDouble = 3.14295;
  const double aConstDouble = 3.14295;
  long double aLongDouble = 3.14295;
  const long double aConstLongDouble = 3.14295;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char *aString = "Hello, World!";
  const char *aConstString = "Hello, World!";
  char aChar = 'a';
  const char aConstChar = 'b';
  signed char aSignedChar = 'c';
  const signed char aConstSignedChar = 'd';
  unsigned char aUnsignedChar = 'e';
  const unsigned char aConstUnsignedChar = 'f';
  short aShort = -32767;
  const short aConstShort = -32767;
  signed short aSignedShort = -32767;
  const signed short aConstSignedShort = -32767;
  signed short int aSignedShortInt = -32767;
  const signed short int aConstSignedShortInt = -32767;
  unsigned short aUnsignedShort = 32767;
  const unsigned short aConstUnsignedShort = 32767;
  unsigned short int aUnsignedShortInt = 32767;
  const unsigned short int aConstUnsignedShortInt = 32767;
  int aInt = -32767;
  const int aConstInt = -32767;
  signed int aSignedInt = -32767;
  const signed int aConstSignedInt = -32767;
  unsigned aUnsigned = -32767;
  const unsigned aConstUnsigned = -32767;
  unsigned int aUnsignedInt = -32767;
  const unsigned int aConstUnsignedInt = -32767;
  long aLong = -2147483647;
  const long aConstLong = -2147483647;
  long int aLongInt = -2147483647;
  const long int aConstLongInt = -2147483647;
  signed long aSignedLong = -2147483647;
  const signed long aConstSignedLong = -2147483647;
  signed long int aSignedLongInt = -2147483647;
  const signed long int aConstSignedLongInt = -2147483647;
  unsigned long aUnsignedLong = 2147483647;
  const unsigned long aConstUnsignedLong = 2147483647;
  unsigned long int aUnsignedLongInt = 2147483647;
  const unsigned long int aConstUnsignedLongInt = 2147483647;
  long long aLongLong = -9223372036854775807;
  const long long aConstLongLong = -9223372036854775807;
  long long int aLongLongInt = -9223372036854775807;
  const long long int aConstLongLongInt = -9223372036854775807;
  signed long long aSignedLongLong = -9223372036854775807;
  const signed long long aConstSignedLongLong = -9223372036854775807;
  signed long long int aSignedLongLongInt = -9223372036854775807;
  const signed long long int aConstSignedLongLongInt = -9223372036854775807;
  unsigned long long aUnsignedLongLong = 9223372036854775807;
  const unsigned long long aConstUnsignedLongLong = 9223372036854775807;
  unsigned long long int aUnsignedLongLongInt = 9223372036854775807;
  const unsigned long long int aConstUnsignedLongLongInt = 9223372036854775807;
  float aFloat = 3.14295;
  const float aConstFloat = 3.14295;
  double aDouble = 3.14295;
  const double aConstDouble = 3.14295;
  long double aLongDouble = 3.14295;
  const long double aConstLongDouble = 3.14295;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char *aString = "Hello, World!";
  const char *aConstString = "Hello, World!";
  char aChar = 'a';
  const char aConstChar = 'b';
  signed char aSignedChar = 'c';
  const signed char aConstSignedChar = 'd';
  unsigned char aUnsignedChar = 'e';
  const unsigned char aConstUnsignedChar = 'f';
  short aShort = -32767;
  const short aConstShort = -32767;
  signed short aSignedShort = -32767;
  const signed short aConstSignedShort = -32767;
  signed short int aSignedShortInt = -32767;
  const signed short int aConstSignedShortInt = -32767;
  unsigned short aUnsignedShort = 32767;
  const unsigned short aConstUnsignedShort = 32767;
  unsigned short int aUnsignedShortInt = 32767;
  const unsigned short int aConstUnsignedShortInt = 32767;
  int aInt = -32767;
  const int aConstInt = -32767;
  signed int aSignedInt = -32767;
  const signed int aConstSignedInt = -32767;
  unsigned aUnsigned = -32767;
  const unsigned aConstUnsigned = -32767;
  unsigned int aUnsignedInt = -32767;
  const unsigned int aConstUnsignedInt = -32767;
  long aLong = -2147483647;
  const long aConstLong = -2147483647;
  long int aLongInt = -2147483647;
  const long int aConstLongInt = -2147483647;
  signed long aSignedLong = -2147483647;
  const signed long aConstSignedLong = -2147483647;
  signed long int aSignedLongInt = -2147483647;
  const signed long int aConstSignedLongInt = -2147483647;
  unsigned long aUnsignedLong = 2147483647;
  const unsigned long aConstUnsignedLong = 2147483647;
  unsigned long int aUnsignedLongInt = 2147483647;
  const unsigned long int aConstUnsignedLongInt = 2147483647;
  long long aLongLong = -9223372036854775807;
  const long long aConstLongLong = -9223372036854775807;
  long long int aLongLongInt = -9223372036854775807;
  const long long int aConstLongLongInt = -9223372036854775807;
  signed long long aSignedLongLong = -9223372036854775807;
  const signed long long aConstSignedLongLong = -9223372036854775807;
  signed long long int aSignedLongLongInt = -9223372036854775807;
  const signed long long int aConstSignedLongLongInt = -9223372036854775807;
  unsigned long long aUnsignedLongLong = 9223372036854775807;
  const unsigned long long aConstUnsignedLongLong = 9223372036854775807;
  unsigned long long int aUnsignedLongLongInt = 9223372036854775807;
  const unsigned long long int aConstUnsignedLongLongInt = 9223372036854775807;
  float aFloat = 3.14295;
  const float aConstFloat = 3.14295;
  double aDouble = 3.14295;
  const double aConstDouble = 3.14295;
  long double aLongDouble = 3.14295;
  const long double aConstLongDouble = 3.14295;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x50(%rbp)
  movl   $0x8,-0x4c(%rbp)
  movl   $0x2,-0x48(%rbp)
  movl   $0x5,-0x44(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x6,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x7,-0x34(%rbp)
  movl   $0x8,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x6,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x8,-0x60(%rbp)
  movl   $0x1,-0x5c(%rbp)
  mov    -0x5c(%rbp),%ecx
  mov    -0x60(%rbp),%edx
  lea    -0x50(%rbp),%rsi
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <createTree@plt>
  mov    %rax,-0x58(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <preorder@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <nonRecursivePreorder@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <inorder@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <nonRecursiveInorder@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <postorder@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <levelOrder@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D48
type: string
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D53
type: string
name: retrieve_data
arguments: label: D38
type: string

tool: D48: 
PREOREDER TRAVERSAL--------------





tool: D26: 
NON recursive preorder


tool: D23: 

INOREDER TRAVERSAL--------------





tool: D9: 
NON recursive inorder


tool: D53: 

POSTOREDER TRAVERSAL--------------





tool: D38: 
LEVEL ORDER TRAVERSAL--------------


assistant: ```c
int main() {
  int in[] = {4, 8, 2, 5, 1, 6, 3, 7};
  int post[] = {8, 4, 5, 2, 6, 7, 3, 1};
  int n = 8;
  int t = 1;
  struct node *root = createTree(post, in, n, t);
  printf("\nPREOREDER TRAVERSAL--------------\n\n\n\n");
  preorder(root);
  printf("\nNON recursive preorder\n");
  nonRecursivePreorder(root);
  printf("\n\nINOREDER TRAVERSAL--------------\n\n\n\n");
  inorder(root);
  printf("\nNON recursive inorder\n");
  nonRecursiveInorder(root);
  printf("\n\nPOSTOREDER TRAVERSAL--------------\n\n\n\n");
  postorder(root);
  printf("\nLEVEL ORDER TRAVERSAL--------------\n");
  levelOrder(root);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x4,0x24(%rsp)
  movl   $0x5,0x28(%rsp)
  movl   $0x2,0x2c(%rsp)
  movl   $0x6,0x30(%rsp)
  movl   $0x7,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x1,0x3c(%rsp)
  mov    %rsp,%rsi
  lea    0x20(%rsp),%rdi
  mov    $0x1,%ecx
  mov    $0x8,%edx
  call   <createTree@plt>
  mov    %rax,%rbx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <preorder@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <nonRecursivePreorder@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <inorder@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <nonRecursiveInorder@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <postorder@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <levelOrder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D31
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D26
data_type: string

tool: D29: 
PREOREDER TRAVERSAL--------------





tool: D12: 
NON recursive preorder


tool: D31: 

INOREDER TRAVERSAL--------------





tool: D10: 
NON recursive inorder


tool: D9: 

POSTOREDER TRAVERSAL--------------





tool: D26: 
LEVEL ORDER TRAVERSAL--------------


assistant: ```c
int main() {
  int in[] = {4, 8, 2, 5, 1, 6, 3, 7};
  int post[] = {8, 4, 5, 2, 6, 7, 3, 1};
  int n = 8;
  int t = 1;
  struct node *root = createTree(post, in, n, t);
  printf("\nPREOREDER TRAVERSAL--------------\n\n\n\n");
  preorder(root);
  printf("\nNON recursive preorder\n");
  nonRecursivePreorder(root);
  printf("\n\nINOREDER TRAVERSAL--------------\n\n\n\n");
  inorder(root);
  printf("\nNON recursive inorder\n");
  nonRecursiveInorder(root);
  printf("\n\nPOSTOREDER TRAVERSAL--------------\n\n\n\n");
  postorder(root);
  printf("\nLEVEL ORDER TRAVERSAL--------------\n");
  levelOrder(root);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x8,%edx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x800000004,%rax
  mov    %rsp,%rsi
  lea    0x20(%rsp),%rdi
  mov    %rax,(%rsp)
  movabs $0x500000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000008,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x200000005,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x100000003,%rax
  mov    %rax,0x38(%rsp)
  call   <createTree@plt>
  lea    D25(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <preorder@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <nonRecursivePreorder@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <inorder@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <nonRecursiveInorder@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <postorder@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <levelOrder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D47
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string

tool: D25: 
PREOREDER TRAVERSAL--------------





tool: D20: 
NON recursive preorder


tool: D47: 

INOREDER TRAVERSAL--------------





tool: D26: 
NON recursive inorder


tool: D11: 

POSTOREDER TRAVERSAL--------------





tool: D13: 
LEVEL ORDER TRAVERSAL--------------


assistant: ```c
int main() {
  int in[] = {4, 8, 2, 5, 1, 6, 3, 7};
  int post[] = {8, 4, 5, 2, 6, 7, 3, 1};
  int n = 8;
  int t = 1;
  struct node *root = createTree(post, in, n, t);
  printf("\nPREOREDER TRAVERSAL--------------\n\n\n\n");
  preorder(root);
  printf("\nNON recursive preorder\n");
  nonRecursivePreorder(root);
  printf("\n\nINOREDER TRAVERSAL--------------\n\n\n\n");
  inorder(root);
  printf("\nNON recursive inorder\n");
  nonRecursiveInorder(root);
  printf("\n\nPOSTOREDER TRAVERSAL--------------\n\n\n\n");
  postorder(root);
  printf("\nLEVEL ORDER TRAVERSAL--------------\n");
  levelOrder(root);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x8,%edx
  sub    $0x50,%rsp
  movdqa D86(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x20(%rsp),%rdi
  movaps %xmm0,(%rsp)
  movdqa D38(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D45(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D60(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <createTree@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <preorder@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <nonRecursivePreorder@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <inorder@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <nonRecursiveInorder@plt>
  lea    D90(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <postorder@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <levelOrder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D86
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D38
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D45
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D60
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string
name: unpack_data
arguments: data_tag: D59
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D90
type_guessed: string
name: unpack_data
arguments: data_tag: D28
type_guessed: string

tool: {"D86": [0x04,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D38": [0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D45": [0x08,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D60": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D10: 
PREOREDER TRAVERSAL--------------





tool: D32: 
NON recursive preorder


tool: D59: 

INOREDER TRAVERSAL--------------





tool: D12: 
NON recursive inorder


tool: D90: 

POSTOREDER TRAVERSAL--------------





tool: D28: 
LEVEL ORDER TRAVERSAL--------------


assistant: ```c
int main() {
  int in[] = {4, 8, 2, 5, 1, 6, 3, 7};
  int post[] = {8, 4, 5, 2, 6, 7, 3, 1};
  int n = 8;
  int t = 1;
  struct node *root = createTree(post, in, n, t);
  printf("\nPREOREDER TRAVERSAL--------------\n\n\n\n");
  preorder(root);
  printf("\nNON recursive preorder\n");
  nonRecursivePreorder(root);
  printf("\n\nINOREDER TRAVERSAL--------------\n\n\n\n");
  inorder(root);
  printf("\nNON recursive inorder\n");
  nonRecursiveInorder(root);
  printf("\n\nPOSTOREDER TRAVERSAL--------------\n\n\n\n");
  postorder(root);
  printf("\nLEVEL ORDER TRAVERSAL--------------\n");
  levelOrder(root);
}
```