ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <getenv@plt>
  mov    $0x1,%edx
  lea    D19(%rip),%rdi
  mov    %rax,%rsi
  call   <setenv@plt>
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D19
type_infered: string

tool: D5: PWD

tool: D19: OLDPWD

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  setenv("OLDPWD", getenv("PWD"), 1);
  setenv("PWD", argv[1], 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<numa_allocate_nodemask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <numa_max_possible_node_v2_int@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <numa_bitmask_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct bitmask *numa_allocate_nodemask(void) {
  struct bitmask *bmp;
  int nnodes = numa_max_possible_node_v2_int() + 1;
  bmp = numa_bitmask_alloc(nnodes);
  return bmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<numa_allocate_nodemask>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <numa_max_possible_node_v2_int@plt>
  lea    0x1(%rax),%edi
  call   <numa_bitmask_alloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct bitmask *numa_allocate_nodemask(void) {
  struct bitmask *bmp;
  int nnodes = numa_max_possible_node_v2_int() + 1;
  bmp = numa_bitmask_alloc(nnodes);
  return bmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numa_allocate_nodemask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <numa_max_possible_node_v2_int@plt>
  add    $0x8,%rsp
  lea    0x1(%rax),%edi
  jmp    1070 <numa_bitmask_alloc@plt>
```

assistant: ```c
struct bitmask *numa_allocate_nodemask(void) {
  struct bitmask *bmp;
  int nnodes = numa_max_possible_node_v2_int() + 1;
  bmp = numa_bitmask_alloc(nnodes);
  return bmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<numa_allocate_nodemask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <numa_max_possible_node_v2_int@plt>
  add    $0x8,%rsp
  lea    0x1(%rax),%edi
  jmp    1070 <numa_bitmask_alloc@plt>
```

assistant: ```c
struct bitmask *numa_allocate_nodemask(void) {
  struct bitmask *bmp;
  int nnodes = numa_max_possible_node_v2_int() + 1;
  bmp = numa_bitmask_alloc(nnodes);
  return bmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pl011_uart_getc_noblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  and    $0x10,%eax
  test   %eax,%eax
  je     L8
  mov    $0xffffffff,%eax
  jmp    L14
L8:
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int32_t pl011_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pl011_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L7
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L9:
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int32_t pl011_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pl011_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L8
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L19:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int32_t pl011_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pl011_uart_getc_noblock>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x201018,%edi
  call   <bcm2835_read@plt>
  test   $0x10,%al
  jne    L2
  mov    $0x201000,%edi
  call   <bcm2835_read@plt>
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int32_t pl011_uart_getc_noblock(void) {
  if (bcm2835_read((0 + 0x201000 + 0x18)) & (1 << 4)) {
    return -1;
  }
  return (bcm2835_read((0 + 0x201000 + 0x00))) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TestA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L7:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <disp_str@plt>
  mov    $0x12c,%edi
  call   <milli_delay@plt>
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: A.

assistant: ```c
void TestA() {
  int i = 0;
  while (1) {
    disp_str("A.");
    milli_delay(300);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<TestA>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
L4:
  mov    %rbx,%rdi
  call   <disp_str@plt>
  mov    $0x12c,%edi
  call   <milli_delay@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: A.

assistant: ```c
void TestA() {
  int i = 0;
  while (1) {
    disp_str("A.");
    milli_delay(300);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TestA>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rdi
  call   <disp_str@plt>
  mov    $0x12c,%edi
  call   <milli_delay@plt>
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: A.

assistant: ```c
void TestA() {
  int i = 0;
  while (1) {
    disp_str("A.");
    milli_delay(300);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TestA>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  call   <disp_str@plt>
  mov    $0x12c,%edi
  call   <milli_delay@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: A.

assistant: ```c
void TestA() {
  int i = 0;
  while (1) {
    disp_str("A.");
    milli_delay(300);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_get_termios>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct termios *ft_get_termios(void) {
  static struct termios term;
  return (&term);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_get_termios>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

assistant: ```c
struct termios *ft_get_termios(void) {
  static struct termios term;
  return (&term);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_get_termios>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

assistant: ```c
struct termios *ft_get_termios(void) {
  static struct termios term;
  return (&term);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_get_termios>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

assistant: ```c
struct termios *ft_get_termios(void) {
  static struct termios term;
  return (&term);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: hello  a world


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello  a world\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: hello  a world


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello  a world\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: hello  a world


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello  a world\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: hello  a world


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello  a world\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<turdro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x46,%esi
  mov    $0x0,%edi
  call   <motor@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <motor@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void turdro() {
  motor(0, 70);
  motor(1, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<turdro>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%esi
  mov    $0x0,%edi
  call   <motor@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <motor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void turdro() {
  motor(0, 70);
  motor(1, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<turdro>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%esi
  xor    %edi,%edi
  call   <motor@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <motor@plt>
```

assistant: ```c
void turdro() {
  motor(0, 70);
  motor(1, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<turdro>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%esi
  xor    %edi,%edi
  call   <motor@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <motor@plt>
```

assistant: ```c
void turdro() {
  motor(0, 70);
  motor(1, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vector>:
  endbr64
  mov    $0x0,%eax
L8:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L8
  ret
```

assistant: ```c
void __attribute__((no)) vector(int ary[(32 * 32 * 32 + 17)]) {
#pragma acc loop vector
  for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    if (__builtin_acc_on_device(5)) {
      int g = 0, w = 0, v = 0;
      __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
      __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
      __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
      ary[ix] = (g << 16) | (w << 8) | v;
    } else
      ary[ix] = ix;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<vector>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x8011,%rax
  jne    L7
  ret
```

assistant: ```c
void __attribute__((no)) vector(int ary[(32 * 32 * 32 + 17)]) {
#pragma acc loop vector
  for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    if (__builtin_acc_on_device(5)) {
      int g = 0, w = 0, v = 0;
      __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
      __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
      __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
      ary[ix] = (g << 16) | (w << 8) | v;
    } else
      ary[ix] = ix;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector>:
  endbr64
  movdqa D1(%rip),%xmm0
  movdqa D9(%rip),%xmm2
  mov    %rdi,%rax
  lea    0x20040(%rdi),%rdx
  xchg   %ax,%ax
L7:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L7
  movl   $0x8010,0x20040(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D9
type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void __attribute__((no)) vector(int ary[(32 * 32 * 32 + 17)]) {
#pragma acc loop vector
  for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    if (__builtin_acc_on_device(5)) {
      int g = 0, w = 0, v = 0;
      __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
      __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
      __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
      ary[ix] = (g << 16) | (w << 8) | v;
    } else
      ary[ix] = ix;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<camsys_gpio_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int camsys_gpio_get(unsigned char *io_name) {
  unsigned int gpio;
  unsigned int group;
  unsigned int group_pin;
  return gpio;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<camsys_gpio_get>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int camsys_gpio_get(unsigned char *io_name) {
  unsigned int gpio;
  unsigned int group;
  unsigned int group_pin;
  return gpio;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<camsys_gpio_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int camsys_gpio_get(unsigned char *io_name) {
  unsigned int gpio;
  unsigned int group;
  unsigned int group_pin;
  return gpio;
}
```
user: Translate the below assembly code into C programming language:

```asm
<camsys_gpio_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int camsys_gpio_get(unsigned char *io_name) {
  unsigned int gpio;
  unsigned int group;
  unsigned int group_pin;
  return gpio;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x73,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x73,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x73,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiError(char *buf) {
  buf[0] = 's';
  buf[2] = 's';
  buf[1] = 's';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiError>:
  endbr64
  movb   $0x73,(%rdi)
  movb   $0x73,0x2(%rdi)
  movb   $0x73,0x1(%rdi)
  ret
```

assistant: ```c
void multiError(char *buf) {
  buf[0] = 's';
  buf[2] = 's';
  buf[1] = 's';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiError>:
  endbr64
  mov    $0x7373,%eax
  movb   $0x73,0x2(%rdi)
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void multiError(char *buf) {
  buf[0] = 's';
  buf[2] = 's';
  buf[1] = 's';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiError>:
  endbr64
  mov    $0x7373,%eax
  movb   $0x73,0x2(%rdi)
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void multiError(char *buf) {
  buf[0] = 's';
  buf[2] = 's';
  buf[1] = 's';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testParse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sys_defs_init@plt>
  mov    $0x0,%eax
  call   <testParseIf@plt>
  mov    $0x0,%eax
  call   <testParseCstring@plt>
  mov    $0x0,%eax
  call   <sys_defs_free@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testParse() {
  sys_defs_init();
  testParseIf();
  testParseCstring();
  sys_defs_free();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testParse>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sys_defs_init@plt>
  mov    $0x0,%eax
  call   <testParseIf@plt>
  mov    $0x0,%eax
  call   <testParseCstring@plt>
  mov    $0x0,%eax
  call   <sys_defs_free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testParse() {
  sys_defs_init();
  testParseIf();
  testParseCstring();
  sys_defs_free();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testParse>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sys_defs_init@plt>
  xor    %eax,%eax
  call   <testParseIf@plt>
  xor    %eax,%eax
  call   <testParseCstring@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <sys_defs_free@plt>
```

assistant: ```c
void testParse() {
  sys_defs_init();
  testParseIf();
  testParseCstring();
  sys_defs_free();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testParse>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sys_defs_init@plt>
  xor    %eax,%eax
  call   <testParseIf@plt>
  xor    %eax,%eax
  call   <testParseCstring@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <sys_defs_free@plt>
```

assistant: ```c
void testParse() {
  sys_defs_init();
  testParseIf();
  testParseCstring();
  sys_defs_free();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_dot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L17
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L17
  cmpl   $0x0,-0x28(%rbp)
  js     L17
  mov    -0x28(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L17
  mov    -0x28(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L17
  movl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_dot(char Dots[], int Hgt, int Wid, int x, int y) {
  int retval = 0;
  if ((x >= 0) && (x < Wid) && (y >= 0) && (y < Hgt)) {
    if (Dots[(y * Wid) + x] == '1') {
      retval = 1;
    }
  }
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_dot>:
  endbr64
  mov    %ecx,%eax
  or     %r8d,%eax
  js     L9
  cmp    %edx,%ecx
  jge    L9
  mov    $0x0,%eax
  cmp    %esi,%r8d
  jge    L18
  imul   %r8d,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  cmpb   $0x31,(%rdi,%rdx,1)
  sete   %al
  movzbl %al,%eax
  ret
L9:
  mov    $0x0,%eax
L18:
  ret
```

assistant: ```c
int get_dot(char Dots[], int Hgt, int Wid, int x, int y) {
  int retval = 0;
  if ((x >= 0) && (x < Wid) && (y >= 0) && (y < Hgt)) {
    if (Dots[(y * Wid) + x] == '1') {
      retval = 1;
    }
  }
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_dot>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  xor    %r9d,%r9d
  or     %r8d,%edi
  js     L2
  cmp    %edx,%ecx
  jge    L2
  cmp    %esi,%r8d
  jge    L2
  imul   %r8d,%edx
  xor    %r9d,%r9d
  add    %ecx,%edx
  movslq %edx,%rdx
  cmpb   $0x31,(%rax,%rdx,1)
  sete   %r9b
L2:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int get_dot(char Dots[], int Hgt, int Wid, int x, int y) {
  int retval = 0;
  if ((x >= 0) && (x < Wid) && (y >= 0) && (y < Hgt)) {
    if (Dots[(y * Wid) + x] == '1') {
      retval = 1;
    }
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_dot>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  xor    %r9d,%r9d
  or     %r8d,%edi
  js     L6
  cmp    %edx,%ecx
  jge    L6
  cmp    %esi,%r8d
  jge    L6
  imul   %r8d,%edx
  xor    %r9d,%r9d
  add    %ecx,%edx
  movslq %edx,%rdx
  cmpb   $0x31,(%rax,%rdx,1)
  sete   %r9b
L6:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int get_dot(char Dots[], int Hgt, int Wid, int x, int y) {
  int retval = 0;
  if ((x >= 0) && (x < Wid) && (y >= 0) && (y < Hgt)) {
    if (Dots[(y * Wid) + x] == '1') {
      retval = 1;
    }
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <init_rts@plt>
  mov    $0x0,%eax
  call   <ROOTINIT@plt>
  mov    $0x0,%eax
  call   <pruneStaticHeap@plt>
  mov    $0x0,%eax
  call   <ROOT@plt>
  mov    $0x0,%eax
  call   <sleep_rts@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_rts(argc, argv);
  ROOTINIT();
  pruneStaticHeap();
  ROOT();
  sleep_rts();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init_rts@plt>
  mov    $0x0,%eax
  call   <ROOTINIT@plt>
  mov    $0x0,%eax
  call   <pruneStaticHeap@plt>
  mov    $0x0,%eax
  call   <ROOT@plt>
  mov    $0x0,%eax
  call   <sleep_rts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_rts(argc, argv);
  ROOTINIT();
  pruneStaticHeap();
  ROOT();
  sleep_rts();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init_rts@plt>
  xor    %eax,%eax
  call   <ROOTINIT@plt>
  xor    %eax,%eax
  call   <pruneStaticHeap@plt>
  xor    %eax,%eax
  call   <ROOT@plt>
  xor    %eax,%eax
  call   <sleep_rts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_rts(argc, argv);
  ROOTINIT();
  pruneStaticHeap();
  ROOT();
  sleep_rts();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <init_rts@plt>
  xor    %eax,%eax
  call   <ROOTINIT@plt>
  xor    %eax,%eax
  call   <pruneStaticHeap@plt>
  xor    %eax,%eax
  call   <ROOT@plt>
  xor    %eax,%eax
  call   <sleep_rts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  init_rts(argc, argv);
  ROOTINIT();
  pruneStaticHeap();
  ROOT();
  sleep_rts();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_baseline_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L5
L13:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x50(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L13
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t test_baseline_l(uint32_t *query_list, size_t num_queries, char **strings, char *output, uint8_t *lens) {
  size_t length = 0;
  for (size_t i = 0; i < num_queries; i++) {
    size_t query = query_list[i];
    uint8_t l = lens[query];
    char *string = strings[query];
    memcpy(output + length, string, l + 1);
    length += l + 1;
  }
  return length;
}
```