user: 这段汇编代码用C语言表示是什么样的?

```asm
<getLines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L88
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L55
L80:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L84
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%esi
  mov    $0x1,%r15d
  jmp    L114
L88:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%r13
  jmp    L54
L55:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  movl   $0x0,(%rax)
  jmp    L80
L111:
  mov    %rax,%r13
  mov    0xc(%rsp),%r15d
L127:
  movslq %r12d,%rax
  mov    (%rsp),%rdi
  mov    %rdi,0x0(%r13,%rax,8)
  add    $0x1,%r12d
  mov    %ebx,%esi
L52:
  lea    0x1(%rbx),%rdx
  movzbl -0x1(%rbp,%rdx,1),%eax
  test   %al,%al
  je     L37
  mov    %rdx,%rbx
L114:
  lea    -0x1(%rbx),%edx
  cmp    $0xa,%al
  jne    L52
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %rax,(%rsp)
  cmp    %r12d,%r15d
  jne    L127
  lea    (%r15,%r15,1),%eax
  mov    %eax,0xc(%rsp)
  mov    %r15d,%edi
  shl    $0x4,%edi
  call   <malloc@plt>
  test   %r15d,%r15d
  jle    L111
  lea    -0x1(%r15),%edx
  lea    0x8(%rax,%rdx,8),%rsi
  mov    %rax,%rdx
  sub    %rax,%r13
L72:
  mov    0x0(%r13,%rdx,1),%rcx
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L72
  mov    %rax,%r13
  mov    0xc(%rsp),%r15d
  jmp    L127
L37:
  cmpb   $0xa,-0x1(%rbp,%rbx,1)
  je     L49
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %rax,%rbx
  cmp    %r12d,%r15d
  je     L179
L58:
  movslq %r12d,%rax
  mov    %rbx,0x0(%r13,%rax,8)
  add    $0x1,%r12d
L49:
  mov    %r12d,(%r14)
L54:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L179:
  mov    %r15d,%edi
  shl    $0x4,%edi
  call   <malloc@plt>
  test   %r15d,%r15d
  jle    L6
  lea    -0x1(%r15),%edx
  lea    0x8(%rax,%rdx,8),%rsi
  mov    %rax,%rdx
  sub    %rax,%r13
L40:
  mov    0x0(%r13,%rdx,1),%rcx
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L40
  mov    %rax,%r13
  jmp    L58
L6:
  mov    %rax,%r13
  jmp    L58
L84:
  mov    $0x0,%r12d
  cmpb   $0xa,-0x1(%rbp)
  je     L49
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <substring@plt>
  mov    %rax,%rbx
  mov    $0x0,%r12d
  jmp    L58
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D15
datatype: string

tool: D2: getLines() recieved a null message

tool: D15: Len is null

assistant: ```c
char **getLines(char *message, int *len) {
  if (message == NULL) {
    puts("getLines() recieved a null message");
    return NULL;
  }
  if (len == NULL) {
    puts("Len is null");
    len = (int *)malloc(sizeof(int));
    *len = 0;
  }
  int index = 0, size = 1, leftIndex = 0, arrIndex = 0;
  char **arr = (char **)malloc(sizeof(char *));
  while (message[index] != 0) {
    if (message[index] == '\n') {
      char *sub = substring(message, leftIndex, index);
      if (arrIndex == size) {
        char **tmpArr = (char **)malloc(sizeof(char *) * (size * 2));
        for (int i = 0; i < size; i++) {
          tmpArr[i] = arr[i];
        }
        size = size * 2;
        arr = tmpArr;
      }
      arr[arrIndex] = sub;
      arrIndex++;
      leftIndex = index + 1;
    }
    index++;
  }
  if (message[index - 1] != '\n') {
    char *sub = substring(message, leftIndex, index);
    if (arrIndex == size) {
      char **tmpArr = (char **)malloc(sizeof(char *) * (size * 2));
      for (int i = 0; i < size; i++) {
        tmpArr[i] = arr[i];
      }
      size = size * 2;
      arr = tmpArr;
    }
    arr[arrIndex] = sub;
    arrIndex++;
  }
  *len = arrIndex;
  return arr;
}
```