ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D30
type: string

tool: D14: sizeof (char) = %lu


tool: D18: sizeof (int) = %lu


tool: D22: sizeof (double) = %lu


tool: D30: sizeof (long) = %lu


assistant: ```c
int main(int argc, const char *argv[]) {
  char c;
  int i;
  double d;
  long l;
  printf("sizeof (char) = %lu\n", sizeof(c));
  printf("sizeof (int) = %lu\n", sizeof(i));
  printf("sizeof (double) = %lu\n", sizeof(d));
  printf("sizeof (long) = %lu\n", sizeof(l));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string

tool: D6: sizeof (char) = %lu


tool: D12: sizeof (int) = %lu


tool: D28: sizeof (double) = %lu


tool: D9: sizeof (long) = %lu


assistant: ```c
int main(int argc, const char *argv[]) {
  char c;
  int i;
  double d;
  long l;
  printf("sizeof (char) = %lu\n", sizeof(c));
  printf("sizeof (int) = %lu\n", sizeof(i));
  printf("sizeof (double) = %lu\n", sizeof(d));
  printf("sizeof (long) = %lu\n", sizeof(l));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D33
datatype: string
name: read_data
arguments: data_tag: D37
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string

tool: D33: sizeof (char) = %lu


tool: D37: sizeof (int) = %lu


tool: D4: sizeof (double) = %lu


tool: D15: sizeof (long) = %lu


assistant: ```c
int main(int argc, const char *argv[]) {
  char c;
  int i;
  double d;
  long l;
  printf("sizeof (char) = %lu\n", sizeof(c));
  printf("sizeof (int) = %lu\n", sizeof(i));
  printf("sizeof (double) = %lu\n", sizeof(d));
  printf("sizeof (long) = %lu\n", sizeof(l));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string

tool: D37: sizeof (char) = %lu


tool: D17: sizeof (int) = %lu


tool: D14: sizeof (double) = %lu


tool: D11: sizeof (long) = %lu


assistant: ```c
int main(int argc, const char *argv[]) {
  char c;
  int i;
  double d;
  long l;
  printf("sizeof (char) = %lu\n", sizeof(c));
  printf("sizeof (int) = %lu\n", sizeof(i));
  printf("sizeof (double) = %lu\n", sizeof(d));
  printf("sizeof (long) = %lu\n", sizeof(l));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<winfirst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clearscreen@plt>
  mov    $0x0,%eax
  call   <curinvis@plt>
  mov    $0x0,%eax
  call   <wingo@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
winfirst() {
  clearscreen();
  curinvis();
  wingo();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<winfirst>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clearscreen@plt>
  mov    $0x0,%eax
  call   <curinvis@plt>
  mov    $0x0,%eax
  call   <wingo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
winfirst() {
  clearscreen();
  curinvis();
  wingo();
}
```
user: Translate the below assembly code into C programming language:

```asm
<winfirst>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clearscreen@plt>
  xor    %eax,%eax
  call   <curinvis@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <wingo@plt>
```

assistant: ```c
winfirst() {
  clearscreen();
  curinvis();
  wingo();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<winfirst>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clearscreen@plt>
  xor    %eax,%eax
  call   <curinvis@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <wingo@plt>
```

assistant: ```c
winfirst() {
  clearscreen();
  curinvis();
  wingo();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_attributes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L0
L7:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x8,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D14
data_type: string

tool: D10: Selected attributes: 

tool: D14: 	%s


assistant: ```c
void print_attributes(const char **attributes) {
  printf("Selected attributes: \n");
  while (*attributes) {
    printf("\t%s\n", *attributes);
    ++attributes;
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_attributes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L19
  lea    D19(%rip),%rbp
L2:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L2
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string

tool: D3: Selected attributes: 

tool: D19: 	%s


assistant: ```c
void print_attributes(const char **attributes) {
  printf("Selected attributes: \n");
  while (*attributes) {
    printf("\t%s\n", *attributes);
    ++attributes;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_attributes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D11(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L14
  lea    D3(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L19
L14:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: string

tool: D11: Selected attributes: 

tool: D3: 	%s


assistant: ```c
void print_attributes(const char **attributes) {
  printf("Selected attributes: \n");
  while (*attributes) {
    printf("\t%s\n", *attributes);
    ++attributes;
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_attributes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D14(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L7
  lea    D1(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L16
L7:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string

tool: D14: Selected attributes: 

tool: D1: 	%s


assistant: ```c
void print_attributes(const char **attributes) {
  printf("Selected attributes: \n");
  while (*attributes) {
    printf("\t%s\n", *attributes);
    ++attributes;
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BX_ToDNF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_bx_to_nnf@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L39
L32:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_to_dnf@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BX_DecRef@plt>
  mov    $0x0,%eax
  jmp    L39
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BX_DecRef@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <_bx_mark_flags@plt>
  mov    -0x8(%rbp),%rax
L39:
  leave
  ret
```

assistant: ```c
struct BoolExpr *BX_ToDNF(struct BoolExpr *ex) {
  struct BoolExpr *nnf;
  struct BoolExpr *dnf;
  do {
    if ((nnf = _bx_to_nnf(ex)) == NULL)
      return NULL;
  } while (0);
  do {
    if ((dnf = _to_dnf(nnf)) == NULL) {
      BX_DecRef(nnf);
      return NULL;
    }
  } while (0);
  BX_DecRef(nnf);
  _bx_mark_flags(dnf, 0x02 | 0x01);
  return dnf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BX_ToDNF>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <_bx_to_nnf@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  mov    %rax,%rdi
  call   <_to_dnf@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  mov    %rbx,%rdi
  call   <BX_DecRef@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <_bx_mark_flags@plt>
L25:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rbx,%rdi
  call   <BX_DecRef@plt>
  jmp    L25
L27:
  mov    %rax,%rbp
  jmp    L25
```

assistant: ```c
struct BoolExpr *BX_ToDNF(struct BoolExpr *ex) {
  struct BoolExpr *nnf;
  struct BoolExpr *dnf;
  do {
    if ((nnf = _bx_to_nnf(ex)) == NULL)
      return NULL;
  } while (0);
  do {
    if ((dnf = _to_dnf(nnf)) == NULL) {
      BX_DecRef(nnf);
      return NULL;
    }
  } while (0);
  BX_DecRef(nnf);
  _bx_mark_flags(dnf, 0x02 | 0x01);
  return dnf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BX_ToDNF>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_bx_to_nnf@plt>
  test   %rax,%rax
  je     L26
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <_to_dnf@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  call   <BX_DecRef@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  call   <_bx_mark_flags@plt>
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  call   <BX_DecRef@plt>
  jmp    L11
```

assistant: ```c
struct BoolExpr *BX_ToDNF(struct BoolExpr *ex) {
  struct BoolExpr *nnf;
  struct BoolExpr *dnf;
  do {
    if ((nnf = _bx_to_nnf(ex)) == NULL)
      return NULL;
  } while (0);
  do {
    if ((dnf = _to_dnf(nnf)) == NULL) {
      BX_DecRef(nnf);
      return NULL;
    }
  } while (0);
  BX_DecRef(nnf);
  _bx_mark_flags(dnf, 0x02 | 0x01);
  return dnf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BX_ToDNF>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_bx_to_nnf@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <_to_dnf@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  call   <BX_DecRef@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  call   <_bx_mark_flags@plt>
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L11:
  call   <BX_DecRef@plt>
  jmp    L24
```

assistant: ```c
struct BoolExpr *BX_ToDNF(struct BoolExpr *ex) {
  struct BoolExpr *nnf;
  struct BoolExpr *dnf;
  do {
    if ((nnf = _bx_to_nnf(ex)) == NULL)
      return NULL;
  } while (0);
  do {
    if ((dnf = _to_dnf(nnf)) == NULL) {
      BX_DecRef(nnf);
      return NULL;
    }
  } while (0);
  BX_DecRef(nnf);
  _bx_mark_flags(dnf, 0x02 | 0x01);
  return dnf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getpixel_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L33
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L33
  cmpl   $0x0,-0x18(%rbp)
  js     L33
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L22
L33:
  mov    D0(%rip),%rax
  movss  (%rax),%xmm0
  jmp    L25
L22:
  mov    -0x18(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L25:
  pop    %rbp
  ret
```

assistant: ```c
float getpixel_nan(float *x, int w, int h, int i, int j) {
  if (i < 0 || i >= w || j < 0 || j >= h)
    return NAN;
  return x[i + j * w];
}
```
user: Translate the below assembly code into C programming language:

```asm
<getpixel_nan>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  or     %r8d,%edi
  js     L11
  cmp    %esi,%ecx
  jge    L11
  cmp    %edx,%r8d
  jge    L11
  imul   %r8d,%esi
  add    %ecx,%esi
  movslq %esi,%rsi
  movss  (%rax,%rsi,4),%xmm0
  ret
L11:
  mov    D4(%rip),%rax
  movss  (%rax),%xmm0
  ret
```

assistant: ```c
float getpixel_nan(float *x, int w, int h, int i, int j) {
  if (i < 0 || i >= w || j < 0 || j >= h)
    return NAN;
  return x[i + j * w];
}
```
user: What is the c source code of the assembly code below:

```asm
<getpixel_nan>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  or     %r8d,%edi
  js     L17
  cmp    %esi,%ecx
  jge    L17
  cmp    %edx,%r8d
  jge    L17
  imul   %r8d,%esi
  add    %ecx,%esi
  movslq %esi,%rsi
  movss  (%rax,%rsi,4),%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    D4(%rip),%rax
  movss  (%rax),%xmm0
  ret
```

assistant: ```c
float getpixel_nan(float *x, int w, int h, int i, int j) {
  if (i < 0 || i >= w || j < 0 || j >= h)
    return NAN;
  return x[i + j * w];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getpixel_nan>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  or     %r8d,%edi
  js     L13
  cmp    %esi,%ecx
  jge    L13
  cmp    %edx,%r8d
  jge    L13
  imul   %r8d,%esi
  add    %ecx,%esi
  movslq %esi,%rsi
  movss  (%rax,%rsi,4),%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    D5(%rip),%rax
  movss  (%rax),%xmm0
  ret
```

assistant: ```c
float getpixel_nan(float *x, int w, int h, int i, int j) {
  if (i < 0 || i >= w || j < 0 || j >= h)
    return NAN;
  return x[i + j * w];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L6:
  mov    $0x0,%eax
  call   <decompress_byte@plt>
  mov    %rax,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <write_char@plt>
  jmp    L6
L2:
  nop
  leave
  ret
```

assistant: ```c
void decompress(void) {
  uint16_t t;
  for (;;) {
    t = decompress_byte();
    if (t == (uint16_t)EOF)
      return;
    write_char(t);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<decompress>:
  endbr64
  sub    $0x8,%rsp
  jmp    L11
L19:
  call   <write_char@plt>
L11:
  mov    $0x0,%eax
  call   <decompress_byte@plt>
  mov    %rax,%rdi
  mov    D5(%rip),%rax
  cmp    %rdi,(%rax)
  jne    L19
  add    $0x8,%rsp
  ret
```

assistant: ```c
void decompress(void) {
  uint16_t t;
  for (;;) {
    t = decompress_byte();
    if (t == (uint16_t)EOF)
      return;
    write_char(t);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<decompress>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  jmp    L0
  xchg   %ax,%ax
L9:
  call   <write_char@plt>
L0:
  xor    %eax,%eax
  call   <decompress_byte@plt>
  mov    %rax,%rdi
  cmp    %rax,(%rbx)
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void decompress(void) {
  uint16_t t;
  for (;;) {
    t = decompress_byte();
    if (t == (uint16_t)EOF)
      return;
    write_char(t);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decompress>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  jmp    L2
  xchg   %ax,%ax
L1:
  call   <write_char@plt>
L2:
  xor    %eax,%eax
  call   <decompress_byte@plt>
  mov    %rax,%rdi
  cmp    %rax,(%rbx)
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void decompress(void) {
  uint16_t t;
  for (;;) {
    t = decompress_byte();
    if (t == (uint16_t)EOF)
      return;
    write_char(t);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_data_codewords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L1
  cmpl   $0x28,-0x14(%rbp)
  jg     L1
  cmpl   $0x0,-0x18(%rbp)
  js     L1
  cmpl   $0x3,-0x18(%rbp)
  jg     L1
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <get_total_codewords@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <get_ec_codewords@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  jmp    L8
L1:
  mov    $0xffffffff,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int get_data_codewords(int version, int ecLevel) {
  if (version > 0 && version < 41 && ecLevel >= 0 && ecLevel < 4) {
    return get_total_codewords(version) - get_ec_codewords(version, ecLevel);
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_data_codewords>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0x27,%eax
  ja     L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  cmp    $0x3,%esi
  ja     L7
  call   <get_total_codewords@plt>
  mov    %eax,%ebp
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <get_ec_codewords@plt>
  mov    %eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    $0xffffffff,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int get_data_codewords(int version, int ecLevel) {
  if (version > 0 && version < 41 && ecLevel >= 0 && ecLevel < 4) {
    return get_total_codewords(version) - get_ec_codewords(version, ecLevel);
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_data_codewords>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0x27,%eax
  ja     L17
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x3,%esi
  ja     L0
  mov    %edi,%ebp
  call   <get_total_codewords@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <get_ec_codewords@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  sub    %r8d,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_data_codewords(int version, int ecLevel) {
  if (version > 0 && version < 41 && ecLevel >= 0 && ecLevel < 4) {
    return get_total_codewords(version) - get_ec_codewords(version, ecLevel);
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_data_codewords>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0x27,%eax
  ja     L29
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x3,%esi
  ja     L1
  mov    %edi,%ebp
  call   <get_total_codewords@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <get_ec_codewords@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  sub    %r8d,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%eax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_data_codewords(int version, int ecLevel) {
  if (version > 0 && version < 41 && ecLevel >= 0 && ecLevel < 4) {
    return get_total_codewords(version) - get_ec_codewords(version, ecLevel);
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  cmpl   $0x4,-0x18(%rbp)
  je     L56
  cmpl   $0x4,-0x18(%rbp)
  jg     L65
  cmpl   $0x1,-0x18(%rbp)
  je     L74
  cmpl   $0x2,-0x18(%rbp)
  je     L27
  jmp    L65
L33:
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L74:
  cmpl   $0x0,-0x14(%rbp)
  jne    L33
  jmp    L65
L69:
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L27:
  cmpl   $0x0,-0x14(%rbp)
  jne    L69
  jmp    L65
L26:
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L56:
  cmpl   $0x0,-0x14(%rbp)
  jne    L26
  nop
L65:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_memory(unsigned long phys_addr, void *addr, int len, int iosize, unsigned long value) {
  switch (iosize) {
  case 1:
    while (len) {
      *(unsigned char *)addr = value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 2:
    while (len) {
      *(unsigned short *)addr = value;
      len -= iosize;
      addr += iosize;
    }
    break;
  case 4:
    while (len) {
      *(unsigned long *)addr = value;
      len -= iosize;
      addr += iosize;
    }
    break;
  }
}
```