ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L47:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L46
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <token_char@plt>
  test   %rax,%rax
  jne    L47
L46:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L32
L7:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L32:
  leave
  ret
```

assistant: ```c
bool read_token(char const **const src, char **const dst) {
  char const *s = *src;
  char *d = *dst;
  while ('\0' != *s && token_char(*s))
    *d++ = *s++;
  if (d == *dst)
    return false;
  *src = s;
  *dst = d;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    (%rdi),%rbx
  mov    (%rsi),%rbp
  movzbl (%rbx),%edi
  mov    $0x0,%eax
  test   %dil,%dil
  je     L30
L14:
  movsbl %dil,%edi
  call   <token_char@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl -0x1(%rbx),%eax
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L14
L16:
  cmp    %rbp,(%r12)
  je     L15
  mov    %rbx,0x0(%r13)
  mov    %rbp,(%r12)
  mov    $0x1,%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%eax
  jmp    L30
```

assistant: ```c
bool read_token(char const **const src, char **const dst) {
  char const *s = *src;
  char *d = *dst;
  while ('\0' != *s && token_char(*s))
    *d++ = *s++;
  if (d == *dst)
    return false;
  *src = s;
  *dst = d;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_token>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    (%rsi),%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
  jmp    L32
  nopl   0x0(%rax)
L40:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rdi,%rbp
  movsbl (%rsi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  je     L25
L5:
  call   <token_char@plt>
  test   %rax,%rax
  jne    L40
L25:
  cmp    %rbp,(%r12)
  je     L32
  mov    %rbx,0x0(%r13)
  mov    $0x1,%eax
  mov    %rbp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool read_token(char const **const src, char **const dst) {
  char const *s = *src;
  char *d = *dst;
  while ('\0' != *s && token_char(*s))
    *d++ = *s++;
  if (d == *dst)
    return false;
  *src = s;
  *dst = d;
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_token>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    (%rsi),%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L6
  jmp    L22
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  movsb  %ds:(%rsi),%es:(%rdi)
  mov    %rdi,%rbp
  movsbl (%rsi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  je     L1
L6:
  call   <token_char@plt>
  test   %rax,%rax
  jne    L5
L1:
  cmp    %rbp,(%r12)
  je     L22
  mov    %rbx,0x0(%r13)
  mov    $0x1,%eax
  mov    %rbp,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool read_token(char const **const src, char **const dst) {
  char const *s = *src;
  char *d = *dst;
  while ('\0' != *s && token_char(*s))
    *d++ = *s++;
  if (d == *dst)
    return false;
  *src = s;
  *dst = d;
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ArrayContains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L23
  addl   $0x1,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ArrayContains(int x, int _array[], int length) {
  int i = 0, contains = 0;
  for (i = 0; i < length; i++) {
    if (_array[i] == x) {
      contains += 1;
    }
  }
  return contains;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ArrayContains>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%rsi
  mov    $0x0,%edx
L1:
  cmp    %edi,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L1
L23:
  mov    %edx,%eax
  ret
L14:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int ArrayContains(int x, int _array[], int length) {
  int i = 0, contains = 0;
  for (i = 0; i < length; i++) {
    if (_array[i] == x) {
      contains += 1;
    }
  }
  return contains;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ArrayContains>:
  endbr64
  test   %edx,%edx
  jle    L1
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %edx,%edx
  cmp    %edi,(%rsi)
  sete   %dl
  add    $0x4,%rsi
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ArrayContains(int x, int _array[], int length) {
  int i = 0, contains = 0;
  for (i = 0; i < length; i++) {
    if (_array[i] == x) {
      contains += 1;
    }
  }
  return contains;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ArrayContains>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L93
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L105
  mov    %rsi,%rax
  movd   %edi,%xmm3
  pxor   %xmm0,%xmm0
  mov    %edx,%esi
  shr    $0x2,%esi
  pshufd $0x0,%xmm3,%xmm2
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rcx,%rsi,1),%rsi
  nop
L23:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  pcmpeqd %xmm2,%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L23
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L8
L2:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r9
  cmp    %r8d,(%rcx,%rdi,4)
  je     L54
L41:
  lea    0x1(%rsi),%edi
  cmp    %edx,%edi
  jge    L3
  cmp    0x4(%rcx,%r9,1),%r8d
  je     L72
L83:
  add    $0x2,%esi
  cmp    %esi,%edx
  jle    L3
  cmp    0x8(%rcx,%r9,1),%r8d
  je     L51
L3:
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%eax
  jmp    L41
  nopl   (%rax)
L72:
  add    $0x1,%eax
  jmp    L83
  nopl   (%rax)
L8:
  ret
  nopl   0x0(%rax)
L51:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L93:
  xor    %eax,%eax
  ret
L105:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L2
```

assistant: ```c
int ArrayContains(int x, int _array[], int length) {
  int i = 0, contains = 0;
  for (i = 0; i < length; i++) {
    if (_array[i] == x) {
      contains += 1;
    }
  }
  return contains;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getbat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <readstring@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <readint@plt>
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <readint@plt>
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <readint@plt>
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L9
  mov    -0x1c(%rbp),%eax
  imul   $0x64,%eax,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x20(%rbp)
  jmp    L16
L9:
  mov    -0x1c(%rbp),%eax
  imul   $0x64,%eax,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x20(%rbp)
L16:
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <smprintf@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D3
datatype: string
name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D37
datatype: string

tool: D35: /sys/class/power_supply/BAT0/status

tool: D8: /sys/class/power_supply/BAT0/charge_now

tool: D3: /sys/class/power_supply/BAT0/charge_full

tool: D23: /sys/class/power_supply/BAT0/charge_full_design

tool: D37: bat: %s %d%%

assistant: ```c
char *getbat(void) {
  char *status = readstring("/sys/class/power_supply/BAT0"
                            "/status");
  char *result = NULL;
  int now_state = readint("/sys/class/power_supply/BAT0"
                          "/charge_now") /
                  10000;
  int now_full = readint("/sys/class/power_supply/BAT0"
                         "/charge_full") /
                 10000;
  int now_design = readint("/sys/class/power_supply/BAT0"
                           "/charge_full_design") /
                   10000;
  uint8_t bat_proc = 0;
  if (now_state > now_full)
    bat_proc = ((now_state * 100) / now_design);
  else
    bat_proc = ((now_state * 100) / now_full);
  result = smprintf("bat: %s %d%%", status, bat_proc);
  free(status);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getbat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rdi
  call   <readstring@plt>
  mov    %rax,%r12
  lea    D28(%rip),%rdi
  call   <readint@plt>
  mov    %eax,%edx
  movslq %eax,%rbx
  imul   $0x68db8bad,%rbx,%rbx
  sar    $0x2c,%rbx
  sar    $0x1f,%edx
  sub    %edx,%ebx
  lea    D39(%rip),%rdi
  call   <readint@plt>
  movslq %eax,%rbp
  imul   $0x68db8bad,%rbp,%rbp
  sar    $0x2c,%rbp
  sar    $0x1f,%eax
  sub    %eax,%ebp
  lea    D13(%rip),%rdi
  call   <readint@plt>
  cmp    %ebp,%ebx
  jle    L8
  mov    %eax,%edx
  imul   $0x64,%ebx,%eax
  movslq %edx,%rcx
  imul   $0x68db8bad,%rcx,%rcx
  sar    $0x2c,%rcx
  sar    $0x1f,%edx
  sub    %edx,%ecx
  cltd
  idiv   %ecx
L10:
  mov    %eax,%edx
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  call   <smprintf@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  imul   $0x64,%ebx,%eax
  cltd
  idiv   %ebp
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D39
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string

tool: D12: /sys/class/power_supply/BAT0/status

tool: D28: /sys/class/power_supply/BAT0/charge_now

tool: D39: /sys/class/power_supply/BAT0/charge_full

tool: D13: /sys/class/power_supply/BAT0/charge_full_design

tool: D8: bat: %s %d%%

assistant: ```c
char *getbat(void) {
  char *status = readstring("/sys/class/power_supply/BAT0"
                            "/status");
  char *result = NULL;
  int now_state = readint("/sys/class/power_supply/BAT0"
                          "/charge_now") /
                  10000;
  int now_full = readint("/sys/class/power_supply/BAT0"
                         "/charge_full") /
                 10000;
  int now_design = readint("/sys/class/power_supply/BAT0"
                           "/charge_full_design") /
                   10000;
  uint8_t bat_proc = 0;
  if (now_state > now_full)
    bat_proc = ((now_state * 100) / now_design);
  else
    bat_proc = ((now_state * 100) / now_full);
  result = smprintf("bat: %s %d%%", status, bat_proc);
  free(status);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getbat>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <readstring@plt>
  lea    D8(%rip),%rdi
  mov    %rax,%r12
  call   <readint@plt>
  lea    D0(%rip),%rdi
  movslq %eax,%rbx
  mov    %rbx,%rdx
  imul   $0x68db8bad,%rbx,%rbx
  sar    $0x1f,%edx
  sar    $0x2c,%rbx
  sub    %edx,%ebx
  call   <readint@plt>
  lea    D29(%rip),%rdi
  movslq %eax,%rbp
  sar    $0x1f,%eax
  imul   $0x68db8bad,%rbp,%rbp
  sar    $0x2c,%rbp
  sub    %eax,%ebp
  call   <readint@plt>
  cmp    %ebp,%ebx
  jle    L19
  mov    %eax,%edx
  imul   $0x64,%ebx,%eax
  movslq %edx,%rcx
  sar    $0x1f,%edx
  imul   $0x68db8bad,%rcx,%rcx
  sar    $0x2c,%rcx
  sub    %edx,%ecx
  cltd
  idiv   %ecx
L17:
  mov    %r12,%rsi
  mov    %eax,%edx
  lea    D34(%rip),%rdi
  call   <smprintf@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  imul   $0x64,%ebx,%eax
  cltd
  idiv   %ebp
  jmp    L17
```

tool_calls: name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D34
type: string

tool: D4: /sys/class/power_supply/BAT0/status

tool: D8: /sys/class/power_supply/BAT0/charge_now

tool: D0: /sys/class/power_supply/BAT0/charge_full

tool: D29: /sys/class/power_supply/BAT0/charge_full_design

tool: D34: bat: %s %d%%

assistant: ```c
char *getbat(void) {
  char *status = readstring("/sys/class/power_supply/BAT0"
                            "/status");
  char *result = NULL;
  int now_state = readint("/sys/class/power_supply/BAT0"
                          "/charge_now") /
                  10000;
  int now_full = readint("/sys/class/power_supply/BAT0"
                         "/charge_full") /
                 10000;
  int now_design = readint("/sys/class/power_supply/BAT0"
                           "/charge_full_design") /
                   10000;
  uint8_t bat_proc = 0;
  if (now_state > now_full)
    bat_proc = ((now_state * 100) / now_design);
  else
    bat_proc = ((now_state * 100) / now_full);
  result = smprintf("bat: %s %d%%", status, bat_proc);
  free(status);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getbat>:
  endbr64
  push   %r13
  lea    D39(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <readstring@plt>
  lea    D21(%rip),%rdi
  mov    %rax,%r12
  call   <readint@plt>
  lea    D44(%rip),%rdi
  movslq %eax,%rbx
  mov    %rbx,%rdx
  imul   $0x68db8bad,%rbx,%rbx
  sar    $0x1f,%edx
  sar    $0x2c,%rbx
  sub    %edx,%ebx
  call   <readint@plt>
  lea    D20(%rip),%rdi
  movslq %eax,%rbp
  sar    $0x1f,%eax
  imul   $0x68db8bad,%rbp,%rbp
  sar    $0x2c,%rbp
  sub    %eax,%ebp
  call   <readint@plt>
  cmp    %ebp,%ebx
  jle    L3
  mov    %eax,%edx
  imul   $0x64,%ebx,%eax
  movslq %edx,%rcx
  sar    $0x1f,%edx
  imul   $0x68db8bad,%rcx,%rcx
  sar    $0x2c,%rcx
  sub    %edx,%ecx
  cltd
  idiv   %ecx
L18:
  mov    %r12,%rsi
  mov    %eax,%edx
  lea    D45(%rip),%rdi
  call   <smprintf@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  imul   $0x64,%ebx,%eax
  cltd
  idiv   %ebp
  jmp    L18
```

tool_calls: name: unpack_data
arguments: tag: D39
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string
name: unpack_data
arguments: tag: D44
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D45
type_guessed: string

tool: D39: /sys/class/power_supply/BAT0/status

tool: D21: /sys/class/power_supply/BAT0/charge_now

tool: D44: /sys/class/power_supply/BAT0/charge_full

tool: D20: /sys/class/power_supply/BAT0/charge_full_design

tool: D45: bat: %s %d%%

assistant: ```c
char *getbat(void) {
  char *status = readstring("/sys/class/power_supply/BAT0"
                            "/status");
  char *result = NULL;
  int now_state = readint("/sys/class/power_supply/BAT0"
                          "/charge_now") /
                  10000;
  int now_full = readint("/sys/class/power_supply/BAT0"
                         "/charge_full") /
                 10000;
  int now_design = readint("/sys/class/power_supply/BAT0"
                           "/charge_full_design") /
                   10000;
  uint8_t bat_proc = 0;
  if (now_state > now_full)
    bat_proc = ((now_state * 100) / now_design);
  else
    bat_proc = ((now_state * 100) / now_full);
  result = smprintf("bat: %s %d%%", status, bat_proc);
  free(status);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printstr@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: Implement main(), foo!


assistant: ```c
int __attribute__((weak)) main(int argc, char **argv) {
  printstr("Implement main(), foo!\n");
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printstr@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: Implement main(), foo!


assistant: ```c
int __attribute__((weak)) main(int argc, char **argv) {
  printstr("Implement main(), foo!\n");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printstr@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: Implement main(), foo!


assistant: ```c
int __attribute__((weak)) main(int argc, char **argv) {
  printstr("Implement main(), foo!\n");
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printstr@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: Implement main(), foo!


assistant: ```c
int __attribute__((weak)) main(int argc, char **argv) {
  printstr("Implement main(), foo!\n");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x1a8(%rbp)
  jmp    L41
L10:
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L38
L9:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a4(%rbp)
L38:
  mov    -0x1ac(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L9
  mov    -0x1ac(%rbp),%edx
  lea    -0x1a0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <findMax@plt>
  mov    %eax,%edx
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1a8(%rbp)
L41:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D24
data_type: string

tool: D19: %d

tool: D24: Case %d: %d


assistant: ```c
int main() {
  int numTest, curCase, numStudent, speedArr[100], index;
  scanf("%d", &numTest);
  curCase = 1;
  while (curCase <= numTest) {
    scanf("%d", &numStudent);
    for (index = 0; index < numStudent; index++)
      scanf("%d", &speedArr[index]);
    printf("Case %d: %d\n", curCase, findMax(speedArr, numStudent));
    curCase++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L35
  mov    $0x1,%r13d
  lea    0xc(%rsp),%r15
  lea    D0(%rip),%r12
  lea    0x10(%rsp),%r14
L3:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L32
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L15
L32:
  mov    %r14,%rdi
  call   <findMax@plt>
  mov    %eax,%edx
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x8(%rsp)
  jge    L3
L35:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D0: %d

tool: D1: Case %d: %d


assistant: ```c
int main() {
  int numTest, curCase, numStudent, speedArr[100], index;
  scanf("%d", &numTest);
  curCase = 1;
  while (curCase <= numTest) {
    scanf("%d", &numStudent);
    for (index = 0; index < numStudent; index++)
      scanf("%d", &speedArr[index]);
    printf("Case %d: %d\n", curCase, findMax(speedArr, numStudent));
    curCase++;
  }
  return 0;
}
```