ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  push   %rbp
  sub    $0x428,%rsp
  mov    (%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  movq   $0x2f,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0xc(%rsp),%r12
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  lea    D19(%rip),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L62
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L62
L28:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L23
  mov    0xc(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L23
L21:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L21
  nopl   0x0(%rax)
L62:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L28
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D19: .

tool: D10: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strcat(path, argv[0]);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  push   %rbp
  sub    $0x428,%rsp
  mov    (%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  movq   $0x2f,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0xc(%rsp),%r12
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L26
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L26
L59:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L12
  mov    0xc(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L12
L4:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L4
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L59
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string

tool: D9: .

tool: D7: pass


assistant: ```c
int main(int argc, char *argv[]) {
  char path[1024] = "/";
  struct stat buf;
  strcat(path, argv[0]);
  if (lstat(".", &buf) != 0 || !S_ISDIR(buf.st_mode))
    abort();
  if (lstat(path, &buf) != 0 || !S_ISREG(buf.st_mode))
    abort();
  printf("pass\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L9
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L35
L9:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  jmp    L35
L1:
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  int sum = 0;
  sum = a + b + c;
  if (sum < a * b) {
    return a + b;
  }
  if (sum == a * b) {
    return b + c;
  }
  return a + c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  lea    (%rax,%rdx,1),%ecx
  mov    %edi,%r8d
  imul   %esi,%r8d
  cmp    %ecx,%r8d
  jg     L1
  add    %edx,%esi
  add    %edx,%edi
  cmp    %ecx,%r8d
  mov    %esi,%eax
  cmovne %edi,%eax
L1:
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  int sum = 0;
  sum = a + b + c;
  if (sum < a * b) {
    return a + b;
  }
  if (sum == a * b) {
    return b + c;
  }
  return a + c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  mov    %edi,%r8d
  lea    (%rdi,%rsi,1),%eax
  imul   %esi,%r8d
  lea    (%rax,%rdx,1),%ecx
  cmp    %ecx,%r8d
  jg     L1
  add    %edx,%esi
  add    %edx,%edi
  cmp    %ecx,%r8d
  mov    %esi,%eax
  cmovne %edi,%eax
L1:
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  int sum = 0;
  sum = a + b + c;
  if (sum < a * b) {
    return a + b;
  }
  if (sum == a * b) {
    return b + c;
  }
  return a + c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    %edi,%r8d
  lea    (%rdi,%rsi,1),%eax
  imul   %esi,%r8d
  lea    (%rax,%rdx,1),%ecx
  cmp    %ecx,%r8d
  jg     L5
  add    %edx,%esi
  add    %edx,%edi
  cmp    %ecx,%r8d
  mov    %esi,%eax
  cmovne %edi,%eax
L5:
  ret
```

assistant: ```c
int f(int a, int b, int c) {
  int sum = 0;
  sum = a + b + c;
  if (sum < a * b) {
    return a + b;
  }
  if (sum == a * b) {
    return b + c;
  }
  return a + c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<br_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L37
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L37
L43:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: 

assistant: ```c
char *br_strndup(const char *str, size_t size) {
  char *result = (char *)((void *)0);
  size_t len;
  if (str == (const char *)((void *)0))
    return (char *)((void *)0);
  len = strlen(str);
  if (len == 0)
    return strdup("");
  if (size > len)
    size = len;
  result = (char *)malloc(len + 1);
  memcpy(result, str, size);
  result[size] = '\0';
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<br_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L12
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  lea    D3(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L7
L18:
  mov    %rdi,%r12
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: 

assistant: ```c
char *br_strndup(const char *str, size_t size) {
  char *result = (char *)((void *)0);
  size_t len;
  if (str == (const char *)((void *)0))
    return (char *)((void *)0);
  len = strlen(str);
  if (len == 0)
    return strdup("");
  if (size > len)
    size = len;
  result = (char *)malloc(len + 1);
  memcpy(result, str, size);
  result[size] = '\0';
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<br_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L25
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L3
  cmp    %rbx,%rax
  lea    0x1(%rax),%rdi
  cmovbe %rax,%rbx
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L15:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
L25:
  xor    %r12d,%r12d
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: 

assistant: ```c
char *br_strndup(const char *str, size_t size) {
  char *result = (char *)((void *)0);
  size_t len;
  if (str == (const char *)((void *)0))
    return (char *)((void *)0);
  len = strlen(str);
  if (len == 0)
    return strdup("");
  if (size > len)
    size = len;
  result = (char *)malloc(len + 1);
  memcpy(result, str, size);
  result[size] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<br_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L22
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L27
  cmp    %rbx,%rax
  lea    0x1(%rax),%rdi
  cmovbe %rax,%rbx
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rbx,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
L22:
  xor    %r12d,%r12d
  jmp    L18
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: 

assistant: ```c
char *br_strndup(const char *str, size_t size) {
  char *result = (char *)((void *)0);
  size_t len;
  if (str == (const char *)((void *)0))
    return (char *)((void *)0);
  len = strlen(str);
  if (len == 0)
    return strdup("");
  if (size > len)
    size = len;
  result = (char *)malloc(len + 1);
  memcpy(result, str, size);
  result[size] = '\0';
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pop_safe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L69
  mov    $0xffffffff,%eax
  jmp    L33
L69:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  cmpq   $0x0,-0x10(%rbp)
  jne    L68
L18:
  mov    $0xffffffff,%eax
  jmp    L33
L68:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L33
L25:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jae    L74
  mov    $0xffffffff,%eax
  jmp    L33
L74:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L33:
  leave
  ret
```

assistant: ```c
int pop_safe(void *stack, size_t *count, size_t size, void *data, size_t max_count) {
  if (data == NULL)
    return -1;
  memset(data, 0, size);
  if (stack == NULL || count == NULL)
    return -1;
  if (*count == 0)
    return -1;
  if (*count > max_count)
    return -1;
  memcpy(data, stack + (*count - 1) * size, size);
  *count -= 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pop_safe>:
  endbr64
  test   %rcx,%rcx
  je     L44
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  test   %rbp,%rbp
  je     L48
  test   %rbx,%rbx
  je     L48
  mov    (%rbx),%rax
  cmp    %r14,%rax
  ja     L3
  test   %rax,%rax
  je     L3
  sub    $0x1,%rax
  imul   %r13,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <memcpy@plt>
  subq   $0x1,(%rbx)
  mov    $0x0,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  mov    $0xffffffff,%eax
  ret
L48:
  mov    $0xffffffff,%eax
  jmp    L20
L3:
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int pop_safe(void *stack, size_t *count, size_t size, void *data, size_t max_count) {
  if (data == NULL)
    return -1;
  memset(data, 0, size);
  if (stack == NULL || count == NULL)
    return -1;
  if (*count == 0)
    return -1;
  if (*count > max_count)
    return -1;
  memcpy(data, stack + (*count - 1) * size, size);
  *count -= 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pop_safe>:
  endbr64
  test   %rcx,%rcx
  je     L53
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <memset@plt>
  test   %rbp,%rbp
  je     L22
  test   %rbx,%rbx
  je     L22
  mov    (%rbx),%rax
  test   %rax,%rax
  je     L22
  cmp    %r14,%rax
  ja     L22
  sub    $0x1,%rax
  mov    %r13,%rdx
  mov    %r12,%rdi
  imul   %r13,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  call   <memcpy@plt>
  subq   $0x1,(%rbx)
  xor    %eax,%eax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0xffffffff,%eax
  jmp    L40
L53:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int pop_safe(void *stack, size_t *count, size_t size, void *data, size_t max_count) {
  if (data == NULL)
    return -1;
  memset(data, 0, size);
  if (stack == NULL || count == NULL)
    return -1;
  if (*count == 0)
    return -1;
  if (*count > max_count)
    return -1;
  memcpy(data, stack + (*count - 1) * size, size);
  *count -= 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pop_safe>:
  endbr64
  test   %rcx,%rcx
  je     L32
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  call   <memset@plt>
  test   %rbp,%rbp
  je     L8
  test   %rbx,%rbx
  je     L8
  mov    (%rbx),%rax
  test   %rax,%rax
  je     L8
  cmp    %r14,%rax
  ja     L8
  sub    $0x1,%rax
  mov    %r13,%rdx
  mov    %r12,%rdi
  imul   %r13,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  call   <memcpy@plt>
  subq   $0x1,(%rbx)
  xor    %eax,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  jmp    L49
L32:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int pop_safe(void *stack, size_t *count, size_t size, void *data, size_t max_count) {
  if (data == NULL)
    return -1;
  memset(data, 0, size);
  if (stack == NULL || count == NULL)
    return -1;
  if (*count == 0)
    return -1;
  if (*count > max_count)
    return -1;
  memcpy(data, stack + (*count - 1) * size, size);
  *count -= 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%r12
  mov    -0x20(%rbp),%rbx
  jmp    L8
L12:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%edx
  movzbl (%r12),%eax
  cmp    %al,%dl
  jne    L8
  add    $0x1,%r12
  mov    -0x20(%rbp),%rbx
L8:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L12
  mov    %r12,%rax
  sub    -0x18(%rbp),%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  register const char *s = s1;
  register const char *p = s2;
  while (*p) {
    if (*p++ == *s) {
      ++s;
      p = s2;
    }
  }
  return s - s1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strspn>:
  endbr64
  mov    %rdi,%rax
L3:
  mov    %rsi,%rdx
L29:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L6
  add    $0x1,%rdx
  cmp    %cl,(%rax)
  jne    L29
  add    $0x1,%rax
  jmp    L3
L6:
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  register const char *s = s1;
  register const char *p = s2;
  while (*p) {
    if (*p++ == *s) {
      ++s;
      p = s2;
    }
  }
  return s - s1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strspn>:
  endbr64
  mov    %rdi,%rax
L3:
  mov    %rsi,%rdx
  jmp    L16
  nopl   0x0(%rax)
L2:
  add    $0x1,%rdx
  cmp    %cl,(%rax)
  je     L20
L16:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L2
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  jmp    L3
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  register const char *s = s1;
  register const char *p = s2;
  while (*p) {
    if (*p++ == *s) {
      ++s;
      p = s2;
    }
  }
  return s - s1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strspn>:
  endbr64
  mov    %rdi,%rax
L11:
  mov    %rsi,%rdx
  jmp    L28
  nopl   0x0(%rax)
L32:
  add    $0x1,%rdx
  cmp    %cl,(%rax)
  je     L30
L28:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L32
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rax
  jmp    L11
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  register const char *s = s1;
  register const char *p = s2;
  while (*p) {
    if (*p++ == *s) {
      ++s;
      p = s2;
    }
  }
  return s - s1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L2:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: y


assistant: ```c
int main() {
  while (1) {
    printf("y\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
L6:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: y


assistant: ```c
int main() {
  while (1) {
    printf("y\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: y


assistant: ```c
int main() {
  while (1) {
    printf("y\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
  nopl   0x0(%rax)
L1:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: y


assistant: ```c
int main() {
  while (1) {
    printf("y\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Dico_String>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <Label_Printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D38
type_infered: string

tool: D26: .LC

tool: D16: %s%d:

tool: D21: %s

tool: D38: .string

assistant: ```c
void Dico_String(int str_no, char *asciiz) {
  Label_Printf("%s%d:", ".LC", str_no);
  Inst_Printf(".string", "%s", asciiz);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Dico_String>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    %rsi,%rbx
  lea    D29(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <Label_Printf@plt>
  mov    %rbx,%rdx
  lea    D23(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <Inst_Printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D23
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D29: .LC

tool: D2: %s%d:

tool: D23: %s

tool: D7: .string

assistant: ```c
void Dico_String(int str_no, char *asciiz) {
  Label_Printf("%s%d:", ".LC", str_no);
  Inst_Printf(".string", "%s", asciiz);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Dico_String>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %rsi,%r12
  lea    D35(%rip),%rdi
  lea    D0(%rip),%rsi
  call   <Label_Printf@plt>
  mov    %r12,%rdx
  pop    %r12
  lea    D38(%rip),%rsi
  lea    D33(%rip),%rdi
  jmp    1070 <Inst_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D35
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D38
data_type: string
name: retrieve_data
arguments: tag: D33
data_type: string

tool: D35: %s%d:

tool: D0: .LC

tool: D38: %s

tool: D33: .string

assistant: ```c
void Dico_String(int str_no, char *asciiz) {
  Label_Printf("%s%d:", ".LC", str_no);
  Inst_Printf(".string", "%s", asciiz);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Dico_String>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %rsi,%r12
  lea    D10(%rip),%rdi
  lea    D4(%rip),%rsi
  call   <Label_Printf@plt>
  mov    %r12,%rdx
  pop    %r12
  lea    D39(%rip),%rsi
  lea    D8(%rip),%rdi
  jmp    1070 <Inst_Printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D4
type: string
name: unpack_data
arguments: tag: D39
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D10: %s%d:

tool: D4: .LC

tool: D39: %s

tool: D8: .string

assistant: ```c
void Dico_String(int str_no, char *asciiz) {
  Label_Printf("%s%d:", ".LC", str_no);
  Inst_Printf(".string", "%s", asciiz);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <os_error@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: Memory allocation failed

assistant: ```c
void *get_mem(size_t n) {
  void *p;
  p = (void *)malloc(n);
  if (p == NULL)
    os_error("Memory allocation failed");
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_mem>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L19:
  mov    %rbx,%rax
  pop    %rbx
  ret
L12:
  lea    D9(%rip),%rdi
  call   <os_error@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: Memory allocation failed

assistant: ```c
void *get_mem(size_t n) {
  void *p;
  p = (void *)malloc(n);
  if (p == NULL)
    os_error("Memory allocation failed");
  return p;
}
```