ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<test_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <mksym_u32@plt>
  xor    %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  call   <limit2_u32@plt>
  mov    0x4(%rsp),%edi
  call   <__sw_hweight32@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  call   <gen___sw_hweight32@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_1() {
  unsigned int w;
  unsigned int res;
  w = mksym_u32();
  limit2_u32(&w, 0, UINT_MAX);
  res = 0;
  res = __sw_hweight32(w);
  gen___sw_hweight32(w, res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <mksym_u32@plt>
  xor    %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  call   <limit2_u32@plt>
  mov    0x4(%rsp),%edi
  call   <__sw_hweight32@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  call   <gen___sw_hweight32@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_1() {
  unsigned int w;
  unsigned int res;
  w = mksym_u32();
  limit2_u32(&w, 0, UINT_MAX);
  res = 0;
  res = __sw_hweight32(w);
  gen___sw_hweight32(w, res);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_smm_mkpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,D32(%rip)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rdi
  call   <smm_mkpath@plt>
  test   %rax,%rax
  je     L3
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
  jmp    L37
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rdi
  call   <smm_fstat@plt>
  cmp    $0x1,%eax
  je     L37
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
L37:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D32(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  test   %rax,%rax
  jne    L28
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D70
type_infered: string
name: parse_data
arguments: label: D75
type_infered: string
name: parse_data
arguments: label: D36
type_infered: string

tool: D70: MKDIR: %s


tool: D75: Boo!


tool: D36: FAILED!


assistant: ```c
int do_smm_mkpath(char *path) {
  static char *plist[] = {NULL, "Press/any/key to/continue/./../1234", "/root/home/user/folder/file", "./user/folder/file", "", NULL};
  int i;
  plist[0] = path;
  for (i = 0; plist[i]; i++) {
    slog_csoup_puts(0, (8 | 0), slog_csoup_format("MKDIR: %s\n", plist[i]));
    if (smm_mkpath(plist[i]) != 0) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("Boo!\n"));
    } else if (smm_fstat(plist[i]) != 1) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("FAILED!\n"));
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_smm_mkpath>:
  endbr64
  mov    %rdi,D1(%rip)
  test   %rdi,%rdi
  je     L22
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rbx
  lea    D47(%rip),%rbp
  lea    D41(%rip),%r13
  lea    D37(%rip),%r12
  jmp    L54
L13:
  mov    (%rbx),%rdi
  call   <smm_fstat@plt>
  cmp    $0x1,%eax
  jne    L49
L21:
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L10
L54:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
  mov    (%rbx),%rdi
  call   <smm_mkpath@plt>
  test   %rax,%rax
  je     L13
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
  jmp    L21
L49:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <slog_csoup_format@plt>
  mov    %eax,%edx
  mov    $0x8,%esi
  mov    $0x0,%edi
  call   <slog_csoup_puts@plt>
  jmp    L21
L10:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D47
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string
name: parse_data
arguments: data_label: D37
data_type: string

tool: D47: MKDIR: %s


tool: D41: FAILED!


tool: D37: Boo!


assistant: ```c
int do_smm_mkpath(char *path) {
  static char *plist[] = {NULL, "Press/any/key to/continue/./../1234", "/root/home/user/folder/file", "./user/folder/file", "", NULL};
  int i;
  plist[0] = path;
  for (i = 0; plist[i]; i++) {
    slog_csoup_puts(0, (8 | 0), slog_csoup_format("MKDIR: %s\n", plist[i]));
    if (smm_mkpath(plist[i]) != 0) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("Boo!\n"));
    } else if (smm_fstat(plist[i]) != 1) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("FAILED!\n"));
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_smm_mkpath>:
  endbr64
  mov    %rdi,D33(%rip)
  test   %rdi,%rdi
  je     L13
  push   %r13
  mov    %rdi,%rsi
  lea    D30(%rip),%r13
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  lea    D34(%rip),%rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L38:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <slog_csoup_format@plt>
  mov    $0x8,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <slog_csoup_puts@plt>
  mov    (%rbx),%rdi
  call   <smm_mkpath@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L12
  mov    (%rbx),%rdi
  call   <smm_fstat@plt>
  cmp    $0x1,%eax
  je     L19
  mov    %r13,%rdi
L12:
  xor    %eax,%eax
  call   <slog_csoup_format@plt>
  mov    $0x8,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <slog_csoup_puts@plt>
L19:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  jne    L38
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D30
datatype: string
name: read_data
arguments: label: D44
datatype: string
name: read_data
arguments: label: D34
datatype: string

tool: D30: FAILED!


tool: D44: Boo!


tool: D34: MKDIR: %s


assistant: ```c
int do_smm_mkpath(char *path) {
  static char *plist[] = {NULL, "Press/any/key to/continue/./../1234", "/root/home/user/folder/file", "./user/folder/file", "", NULL};
  int i;
  plist[0] = path;
  for (i = 0; plist[i]; i++) {
    slog_csoup_puts(0, (8 | 0), slog_csoup_format("MKDIR: %s\n", plist[i]));
    if (smm_mkpath(plist[i]) != 0) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("Boo!\n"));
    } else if (smm_fstat(plist[i]) != 1) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("FAILED!\n"));
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_smm_mkpath>:
  endbr64
  mov    %rdi,D18(%rip)
  test   %rdi,%rdi
  je     L9
  push   %r13
  mov    %rdi,%rsi
  lea    D39(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  lea    D35(%rip),%rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L33:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <slog_csoup_format@plt>
  mov    $0x8,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <slog_csoup_puts@plt>
  mov    (%rbx),%rdi
  call   <smm_mkpath@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L26
  mov    (%rbx),%rdi
  call   <smm_fstat@plt>
  cmp    $0x1,%eax
  je     L15
  mov    %r13,%rdi
L26:
  xor    %eax,%eax
  call   <slog_csoup_format@plt>
  mov    $0x8,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <slog_csoup_puts@plt>
L15:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  jne    L33
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D39
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D35
data_type: string

tool: D39: FAILED!


tool: D19: Boo!


tool: D35: MKDIR: %s


assistant: ```c
int do_smm_mkpath(char *path) {
  static char *plist[] = {NULL, "Press/any/key to/continue/./../1234", "/root/home/user/folder/file", "./user/folder/file", "", NULL};
  int i;
  plist[0] = path;
  for (i = 0; plist[i]; i++) {
    slog_csoup_puts(0, (8 | 0), slog_csoup_format("MKDIR: %s\n", plist[i]));
    if (smm_mkpath(plist[i]) != 0) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("Boo!\n"));
    } else if (smm_fstat(plist[i]) != 1) {
      slog_csoup_puts(0, (8 | 0), slog_csoup_format("FAILED!\n"));
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpl_bytearray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L21
L22:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L31
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <escape_char@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x5(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,-0x18(%rbp)
  addq   $0x2,-0x10(%rbp)
  jmp    L21
L31:
  mov    -0x18(%rbp),%eax
  lea    0x5(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L22
  mov    -0x30(%rbp),%rax
  movb   $0x5,(%rax)
  movl   $0x4,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L24
L6:
  mov    -0x1c(%rbp),%eax
  movsbl %al,%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x1c(%rbp)
L24:
  cmpl   $0x0,-0x14(%rbp)
  jg     L6
  addq   $0x1,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%eax
  add    $0x5,%eax
  leave
  ret
```

assistant: ```c
unsigned int cpl_bytearray(char **expr, char *bin) {
  unsigned int w, length = 0;
  int i;
  char *c, *o;
  c = *expr;
  c++;
  while (*c != '"') {
    if (*c == '\\') {
      o = escape_char(*(c + 1));
      strcpy(bin + length + (8 * sizeof(unsigned int)) / 8 + 1, o);
      length += strlen(o);
      c += 2;
    } else {
      bin[length + (8 * sizeof(unsigned int)) / 8 + 1] = *c;
      length++;
      c++;
    }
  }
  bin[0] = 5;
  for (i = (8 * sizeof(unsigned int)) / 8, w = length; i > 0; i--, w /= 256)
    bin[i] = (char)w % 256;
  *expr = ++c;
  return (unsigned int)(8 * sizeof(unsigned int)) / 8 + 1 + length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cpl_bytearray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    (%rdi),%rax
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%eax
  cmp    $0x22,%al
  je     L9
  mov    $0x0,%ebp
  jmp    L13
L45:
  movsbl 0x1(%rbx),%edi
  call   <escape_char@plt>
  mov    %rax,%r14
  mov    %ebp,%eax
  lea    0x5(%r12,%rax,1),%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebp
  add    $0x2,%rbx
L6:
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L58
L13:
  cmp    $0x5c,%al
  je     L45
  mov    %ebp,%edx
  mov    %al,0x5(%r12,%rdx,1)
  add    $0x1,%ebp
  add    $0x1,%rbx
  jmp    L6
L9:
  mov    $0x0,%ebp
L58:
  movb   $0x5,(%r12)
  lea    0x4(%r12),%rcx
  mov    %ebp,%esi
L47:
  movsbl %sil,%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %al,(%rcx)
  shr    $0x8,%esi
  sub    $0x1,%rcx
  cmp    %r12,%rcx
  jne    L47
  add    $0x1,%rbx
  mov    %rbx,0x0(%r13)
  lea    0x5(%rbp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int cpl_bytearray(char **expr, char *bin) {
  unsigned int w, length = 0;
  int i;
  char *c, *o;
  c = *expr;
  c++;
  while (*c != '"') {
    if (*c == '\\') {
      o = escape_char(*(c + 1));
      strcpy(bin + length + (8 * sizeof(unsigned int)) / 8 + 1, o);
      length += strlen(o);
      c += 2;
    } else {
      bin[length + (8 * sizeof(unsigned int)) / 8 + 1] = *c;
      length++;
      c++;
    }
  }
  bin[0] = 5;
  for (i = (8 * sizeof(unsigned int)) / 8, w = length; i > 0; i--, w /= 256)
    bin[i] = (char)w % 256;
  *expr = ++c;
  return (unsigned int)(8 * sizeof(unsigned int)) / 8 + 1 + length;
}
```
user: What is the c source code of the assembly code below?

```asm
<cpl_bytearray>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    0x1(%rax),%rbp
  movzbl 0x1(%rax),%eax
  cmp    $0x22,%al
  je     L69
  xor    %ebx,%ebx
  jmp    L62
  nop
L46:
  add    $0x1,%rbp
  mov    %al,0x0(%r13)
  add    $0x1,%ebx
  movzbl 0x0(%rbp),%eax
  cmp    $0x22,%al
  je     L7
L62:
  mov    %ebx,%edx
  lea    0x5(%r12,%rdx,1),%r13
  cmp    $0x5c,%al
  jne    L46
  movsbl 0x1(%rbp),%edi
  add    $0x2,%rbp
  call   <escape_char@plt>
  mov    %r13,%rdi
  mov    %rax,%r14
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  movzbl 0x0(%rbp),%eax
  cmp    $0x22,%al
  jne    L62
L7:
  lea    0x5(%rbx),%r8d
L32:
  movb   $0x5,(%r12)
  lea    0x4(%r12),%rax
L6:
  mov    %bl,(%rax)
  sub    $0x1,%rax
  shr    $0x8,%ebx
  cmp    %rax,%r12
  jne    L6
  add    $0x1,%rbp
  mov    %r8d,%eax
  mov    %rbp,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  mov    $0x5,%r8d
  xor    %ebx,%ebx
  jmp    L32
```

assistant: ```c
unsigned int cpl_bytearray(char **expr, char *bin) {
  unsigned int w, length = 0;
  int i;
  char *c, *o;
  c = *expr;
  c++;
  while (*c != '"') {
    if (*c == '\\') {
      o = escape_char(*(c + 1));
      strcpy(bin + length + (8 * sizeof(unsigned int)) / 8 + 1, o);
      length += strlen(o);
      c += 2;
    } else {
      bin[length + (8 * sizeof(unsigned int)) / 8 + 1] = *c;
      length++;
      c++;
    }
  }
  bin[0] = 5;
  for (i = (8 * sizeof(unsigned int)) / 8, w = length; i > 0; i--, w /= 256)
    bin[i] = (char)w % 256;
  *expr = ++c;
  return (unsigned int)(8 * sizeof(unsigned int)) / 8 + 1 + length;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpl_bytearray>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  lea    0x1(%rax),%rbp
  movzbl 0x1(%rax),%eax
  cmp    $0x22,%al
  je     L9
  xor    %ebx,%ebx
  jmp    L44
  nop
L15:
  mov    %al,(%r12)
  movzbl 0x1(%rbp),%eax
  add    $0x1,%ebx
  lea    0x1(%rbp),%rdx
  cmp    $0x22,%al
  je     L24
L3:
  mov    %rdx,%rbp
L44:
  mov    %ebx,%edx
  lea    0x5(%r13,%rdx,1),%r12
  cmp    $0x5c,%al
  jne    L15
  movsbl 0x1(%rbp),%edi
  call   <escape_char@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x2(%rbp),%rdx
  add    %eax,%ebx
  movzbl 0x2(%rbp),%eax
  cmp    $0x22,%al
  jne    L3
L24:
  lea    0x5(%rbx),%eax
L52:
  add    $0x1,%rdx
  movb   $0x5,0x0(%r13)
  bswap  %ebx
  mov    %ebx,0x1(%r13)
  mov    %rdx,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdx
  mov    $0x5,%eax
  xor    %ebx,%ebx
  jmp    L52
```

assistant: ```c
unsigned int cpl_bytearray(char **expr, char *bin) {
  unsigned int w, length = 0;
  int i;
  char *c, *o;
  c = *expr;
  c++;
  while (*c != '"') {
    if (*c == '\\') {
      o = escape_char(*(c + 1));
      strcpy(bin + length + (8 * sizeof(unsigned int)) / 8 + 1, o);
      length += strlen(o);
      c += 2;
    } else {
      bin[length + (8 * sizeof(unsigned int)) / 8 + 1] = *c;
      length++;
      c++;
    }
  }
  bin[0] = 5;
  for (i = (8 * sizeof(unsigned int)) / 8, w = length; i > 0; i--, w /= 256)
    bin[i] = (char)w % 256;
  *expr = ++c;
  return (unsigned int)(8 * sizeof(unsigned int)) / 8 + 1 + length;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_integer_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setge  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <random_integer@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int random_integer_range(int n, int m) {
  assert(n >= 0);
  assert(m >= n);
  return n + random_integer(m - n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<random_integer_range>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    %ebp,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <random_integer@plt>
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int random_integer_range(int n, int m) {
  assert(n >= 0);
  assert(m >= n);
  return n + random_integer(m - n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_integer_range>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setle  %dil
  call   <assert@plt>
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <random_integer@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int random_integer_range(int n, int m) {
  assert(n >= 0);
  assert(m >= n);
  return n + random_integer(m - n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<random_integer_range>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  not    %edi
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setle  %dil
  call   <assert@plt>
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <random_integer@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int random_integer_range(int n, int m) {
  assert(n >= 0);
  assert(m >= n);
  return n + random_integer(m - n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rdx
  jmp    L20
L16:
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  movzbl (%rcx),%esi
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movzbl (%rcx),%ecx
  cmp    %cl,%sil
  je     L20
  mov    $0x0,%eax
  jmp    L10
L20:
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L16
  mov    $0x1,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int prefix(pfx, string)
register char const *pfx;
register char const *string;
{
  while (*pfx) {
    if (*pfx++ != *string++)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prefix>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L14
  add    $0x1,%rax
  cmp    %dl,-0x1(%rsi,%rax,1)
  je     L8
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int prefix(pfx, string)
register char const *pfx;
register char const *string;
{
  while (*pfx) {
    if (*pfx++ != *string++)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmp    %dl,-0x1(%rsi,%rax,1)
  jne    L11
L21:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L8
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int prefix(pfx, string)
register char const *pfx;
register char const *string;
{
  while (*pfx) {
    if (*pfx++ != *string++)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rax
  cmp    %dl,-0x1(%rsi,%rax,1)
  jne    L5
L23:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L17
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int prefix(pfx, string)
register char const *pfx;
register char const *string;
{
  while (*pfx) {
    if (*pfx++ != *string++)
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GetCompressed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string

tool: D7: gunzip -c %s

tool: D14: r

assistant: ```c
FILE *GetCompressed(char *name) {
  char cmd[256];
  sprintf(cmd, "gunzip -c %s", name);
  return (popen(cmd, "r"));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetCompressed>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D8: gunzip -c %s

tool: D15: r

assistant: ```c
FILE *GetCompressed(char *name) {
  char cmd[256];
  sprintf(cmd, "gunzip -c %s", name);
  return (popen(cmd, "r"));
}
```