ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,(%rbx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,0x8(%rbx)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,0x10(%rbx)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rbx)
  movl   $0x2,0x0(%r13)
  movl   $0x3,(%r12)
  movl   $0x4,0x4(%r12)
  movl   $0x6,0x0(%rbp)
  movl   $0x5,0x4(%rbp)
  movl   $0x7,0x8(%rbp)
  movl   $0x4,(%rax)
  movl   $0x1,0x4(%rax)
  movl   $0x8,0x8(%rax)
  movl   $0x3,0xc(%rax)
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <minimumTotal@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  call   <free@plt>
  mov    0x10(%rbx),%rdi
  call   <free@plt>
  mov    0x18(%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main(void) {
  int **x = malloc(4 * sizeof(int *));
  x[0] = malloc(1 * sizeof(int));
  x[1] = malloc(2 * sizeof(int));
  x[2] = malloc(3 * sizeof(int));
  x[3] = malloc(4 * sizeof(int));
  x[0][0] = 2;
  x[1][0] = 3;
  x[1][1] = 4;
  x[2][0] = 6;
  x[2][1] = 5;
  x[2][2] = 7;
  x[3][0] = 4;
  x[3][1] = 1;
  x[3][2] = 8;
  x[3][3] = 3;
  printf("%d\n", minimumTotal(x, 4));
  free(x[0]);
  free(x[1]);
  free(x[2]);
  free(x[3]);
  free(x);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x20,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r13
  mov    %rax,0x0(%rbp)
  call   <malloc@plt>
  mov    $0xc,%edi
  mov    %rax,%r12
  mov    %rax,0x8(%rbp)
  call   <malloc@plt>
  mov    $0x10,%edi
  mov    %rax,%rbx
  mov    %rax,0x10(%rbp)
  call   <malloc@plt>
  mov    %rbp,%rdi
  movabs $0x400000003,%rdx
  movabs $0x500000006,%rcx
  mov    %rdx,(%r12)
  mov    $0x4,%esi
  movabs $0x100000004,%rdx
  mov    %rcx,(%rbx)
  movabs $0x300000008,%rcx
  mov    %rdx,(%rax)
  mov    %rcx,0x8(%rax)
  mov    %rax,0x18(%rbp)
  xor    %eax,%eax
  movl   $0x2,0x0(%r13)
  movl   $0x7,0x8(%rbx)
  call   <minimumTotal@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    0x8(%rbp),%rdi
  call   <free@plt>
  mov    0x10(%rbp),%rdi
  call   <free@plt>
  mov    0x18(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D2: %d


assistant: ```c
int main(void) {
  int **x = malloc(4 * sizeof(int *));
  x[0] = malloc(1 * sizeof(int));
  x[1] = malloc(2 * sizeof(int));
  x[2] = malloc(3 * sizeof(int));
  x[3] = malloc(4 * sizeof(int));
  x[0][0] = 2;
  x[1][0] = 3;
  x[1][1] = 4;
  x[2][0] = 6;
  x[2][1] = 5;
  x[2][2] = 7;
  x[3][0] = 4;
  x[3][1] = 1;
  x[3][2] = 8;
  x[3][3] = 3;
  printf("%d\n", minimumTotal(x, 4));
  free(x[0]);
  free(x[1]);
  free(x[2]);
  free(x[3]);
  free(x);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x20,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r13
  mov    %rax,0x0(%rbp)
  call   <malloc@plt>
  mov    $0xc,%edi
  mov    %rax,%r12
  mov    %rax,0x8(%rbp)
  call   <malloc@plt>
  mov    $0x10,%edi
  mov    %rax,%rbx
  mov    %rax,0x10(%rbp)
  call   <malloc@plt>
  mov    D18(%rip),%rdx
  mov    %rbp,%rdi
  movdqa D15(%rip),%xmm0
  mov    %rax,0x18(%rbp)
  mov    $0x4,%esi
  mov    %rdx,(%r12)
  mov    D25(%rip),%rdx
  movups %xmm0,(%rax)
  xor    %eax,%eax
  mov    %rdx,(%rbx)
  movl   $0x2,0x0(%r13)
  movl   $0x7,0x8(%rbx)
  call   <minimumTotal@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    0x8(%rbp),%rdi
  call   <free@plt>
  mov    0x10(%rbp),%rdi
  call   <free@plt>
  mov    0x18(%rbp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type_guessed: byte[8]
name: read_data
arguments: tag: D15
type_guessed: byte[16]
name: read_data
arguments: tag: D25
type_guessed: byte[8]
name: read_data
arguments: tag: D4
type_guessed: string

tool: {"D18": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D15": [0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D25": [0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D4: %d


assistant: ```c
int main(void) {
  int **x = malloc(4 * sizeof(int *));
  x[0] = malloc(1 * sizeof(int));
  x[1] = malloc(2 * sizeof(int));
  x[2] = malloc(3 * sizeof(int));
  x[3] = malloc(4 * sizeof(int));
  x[0][0] = 2;
  x[1][0] = 3;
  x[1][1] = 4;
  x[2][0] = 6;
  x[2][1] = 5;
  x[2][2] = 7;
  x[3][0] = 4;
  x[3][1] = 1;
  x[3][2] = 8;
  x[3][3] = 3;
  printf("%d\n", minimumTotal(x, 4));
  free(x[0]);
  free(x[1]);
  free(x[2]);
  free(x[3]);
  free(x);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<shift_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L53
L44:
  mov    -0x14(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rcx,%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L48
L16:
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x48(%rbp),%xmm1
  mov    -0x10(%rbp),%rax
  sub    $0x4,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x40(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  subq   $0x4,-0x8(%rbp)
  subq   $0x4,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L48:
  mov    -0x2c(%rbp),%eax
  sub    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L16
  mov    -0x10(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x48(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L1:
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L1
  addl   $0x1,-0x14(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L44
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shift_right(float *dat, int w, int h, int dn, double a, double b) {
  int x, y;
  float *sp, *dp;
  for (y = 0; y < h; y++) {
    dp = dat + y * w + w - 1;
    sp = dat + y * w - dn + w - 1;
    for (x = 0; x < w - dn - 1; x++) {
      *dp = *sp * b + *(sp - 1) * a;
      dp--;
      sp--;
    }
    *dp-- = *sp-- * b;
    for (x = 0; x < dn; x++)
      *dp-- = 0.0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shift_right>:
  endbr64
  test   %edx,%edx
  jle    L26
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %edx,%ebp
  mov    %ecx,%r11d
  movslq %esi,%rax
  lea    0x0(,%rax,4),%r13
  movslq %ecx,%rbx
  sub    %rbx,%rax
  lea    -0x4(%rdi,%rax,4),%rdi
  shl    $0x2,%rbx
  sub    %ecx,%r10d
  lea    -0x2(%r10),%r9d
  mov    %r9,%rsi
  not    %rsi
  shl    $0x2,%rsi
  neg    %r9
  shl    $0x2,%r9
  lea    -0x1(%rcx),%eax
  shl    $0x2,%rax
  mov    $0x0,%r8d
  lea    -0x4(%rbx,%r9,1),%r14
  sub    $0x4,%r9
  mov    $0xfffffffffffffff8,%r12
  sub    %rax,%r12
L43:
  lea    (%rdi,%rbx,1),%rdx
  mov    %rdi,%rcx
  cmp    $0x1,%r10d
  jle    L27
  mov    $0x0,%eax
L36:
  pxor   %xmm2,%xmm2
  cvtss2sd (%rcx,%rax,1),%xmm2
  mulsd  %xmm1,%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd -0x4(%rcx,%rax,1),%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,(%rdx,%rax,1)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L36
  lea    (%r14,%rdi,1),%rdx
  lea    (%r9,%rdi,1),%rcx
L27:
  lea    -0x4(%rdx),%rax
  pxor   %xmm2,%xmm2
  cvtss2sd (%rcx),%xmm2
  mulsd  %xmm1,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,(%rdx)
  test   %r11d,%r11d
  jle    L15
  add    %r12,%rdx
L29:
  movl   $0x0,(%rax)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L29
L15:
  add    $0x1,%r8d
  add    %r13,%rdi
  cmp    %r8d,%ebp
  jne    L43
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  ret
```

assistant: ```c
void shift_right(float *dat, int w, int h, int dn, double a, double b) {
  int x, y;
  float *sp, *dp;
  for (y = 0; y < h; y++) {
    dp = dat + y * w + w - 1;
    sp = dat + y * w - dn + w - 1;
    for (x = 0; x < w - dn - 1; x++) {
      *dp = *sp * b + *(sp - 1) * a;
      dp--;
      sp--;
    }
    *dp-- = *sp-- * b;
    for (x = 0; x < dn; x++)
      *dp-- = 0.0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shift_right>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x14(%rsp)
  mov    %ecx,0x18(%rsp)
  test   %edx,%edx
  jle    L34
  mov    %esi,%ebp
  movslq %ecx,%r10
  mov    %ecx,%esi
  mov    %rdi,%rbx
  movslq %ebp,%rax
  sub    %ecx,%ebp
  lea    0x0(,%r10,4),%r14
  lea    -0x2(%rbp),%ecx
  lea    0x0(,%rax,4),%r15
  sub    %r10,%rax
  mov    %ebp,0x1c(%rsp)
  not    %rcx
  lea    -0x4(,%rax,4),%rax
  xor    %ebp,%ebp
  lea    0x0(,%rcx,4),%r13
  add    %rax,%rbx
  lea    0x0(%r13,%rax,1),%r8
  lea    -0x1(%rsi),%eax
  add    $0x1,%rax
  lea    (%rdi,%r8,1),%r12
  lea    0x0(,%rax,4),%rsi
  neg    %rax
  mov    %rsi,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L28:
  cmpl   $0x1,0x1c(%rsp)
  lea    (%rbx,%r14,1),%rdx
  mov    %rbx,%rax
  jle    L1
  xor    %eax,%eax
L12:
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd (%rbx,%rax,1),%xmm2
  cvtss2sd -0x4(%rbx,%rax,1),%xmm3
  mulsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,(%rdx,%rax,1)
  sub    $0x4,%rax
  cmp    %rax,%r13
  jne    L12
  lea    (%r12,%r14,1),%rdx
  mov    %r12,%rax
L1:
  pxor   %xmm2,%xmm2
  cvtss2sd (%rax),%xmm2
  mulsd  %xmm1,%xmm2
  mov    0x18(%rsp),%eax
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,(%rdx)
  test   %eax,%eax
  jle    L8
  mov    0x28(%rsp),%rax
  xor    %esi,%esi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  lea    (%rdx,%rax,4),%rdi
  mov    0x20(%rsp),%rdx
  call   <memset@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
L8:
  add    $0x1,%ebp
  add    %r15,%r12
  add    %r15,%rbx
  cmp    %ebp,0x14(%rsp)
  jne    L28
L34:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shift_right(float *dat, int w, int h, int dn, double a, double b) {
  int x, y;
  float *sp, *dp;
  for (y = 0; y < h; y++) {
    dp = dat + y * w + w - 1;
    sp = dat + y * w - dn + w - 1;
    for (x = 0; x < w - dn - 1; x++) {
      *dp = *sp * b + *(sp - 1) * a;
      dp--;
      sp--;
    }
    *dp-- = *sp-- * b;
    for (x = 0; x < dn; x++)
      *dp-- = 0.0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gu_str_table_append_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  lea    -0x12(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <gu_str_append@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %zu

assistant: ```c
char *gu_str_table_append_size(char *str, size_t *off, size_t n) {
  char buf[10];
  size_t len = snprintf(buf, sizeof(buf), "%zu", n);
  return gu_str_append(str, off, buf, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gu_str_table_append_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    D4(%rip),%rdx
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <gu_str_append@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: %zu

assistant: ```c
char *gu_str_table_append_size(char *str, size_t *off, size_t n) {
  char buf[10];
  size_t len = snprintf(buf, sizeof(buf), "%zu", n);
  return gu_str_append(str, off, buf, len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gu_str_table_append_size>:
  endbr64
  push   %r13
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  push   %r12
  mov    %rsi,%r12
  mov    $0xa,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  call   <gu_str_append@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: %zu

assistant: ```c
char *gu_str_table_append_size(char *str, size_t *off, size_t n) {
  char buf[10];
  size_t len = snprintf(buf, sizeof(buf), "%zu", n);
  return gu_str_append(str, off, buf, len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gu_str_table_append_size>:
  endbr64
  push   %r13
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  push   %r12
  mov    %rsi,%r12
  mov    $0xa,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  call   <gu_str_append@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: %zu

assistant: ```c
char *gu_str_table_append_size(char *str, size_t *off, size_t n) {
  char buf[10];
  size_t len = snprintf(buf, sizeof(buf), "%zu", n);
  return gu_str_append(str, off, buf, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BoundDctMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L27:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jns    L12
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L15
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x1c(%rbp),%eax
  test   %eax,%eax
  jle    L15
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L15:
  addq   $0x4,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  add    $0x100,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BoundDctMatrix(matrix, Bound) int *matrix;
int Bound;
{
  static char RoutineName[] = "BoundDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    if (*mptr + Bound < 0)
      *mptr = -Bound;
    else if (*mptr - Bound > 0)
      *mptr = Bound;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BoundDctMatrix>:
  endbr64
  lea    0x100(%rdi),%rdx
  mov    %esi,%r8d
  neg    %r8d
  jmp    L47
L15:
  mov    %r8d,(%rdi)
L28:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L24
L47:
  mov    (%rdi),%eax
  mov    %eax,%ecx
  add    %esi,%ecx
  js     L15
  cmp    %esi,%eax
  jle    L28
  mov    %esi,(%rdi)
  jmp    L28
L24:
  ret
```

assistant: ```c
void BoundDctMatrix(matrix, Bound) int *matrix;
int Bound;
{
  static char RoutineName[] = "BoundDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    if (*mptr + Bound < 0)
      *mptr = -Bound;
    else if (*mptr - Bound > 0)
      *mptr = Bound;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BoundDctMatrix>:
  endbr64
  mov    %esi,%r8d
  lea    0x100(%rdi),%rdx
  neg    %r8d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L3:
  cmp    %esi,%eax
  jle    L13
  mov    %esi,(%rdi)
L13:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L8
L12:
  mov    (%rdi),%eax
  mov    %eax,%ecx
  add    %esi,%ecx
  jns    L3
  mov    %r8d,(%rdi)
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L12
L8:
  ret
```

assistant: ```c
void BoundDctMatrix(matrix, Bound) int *matrix;
int Bound;
{
  static char RoutineName[] = "BoundDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    if (*mptr + Bound < 0)
      *mptr = -Bound;
    else if (*mptr - Bound > 0)
      *mptr = Bound;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BoundDctMatrix>:
  endbr64
  mov    %esi,%r8d
  lea    0x100(%rdi),%rdx
  neg    %r8d
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %esi,%eax
  jle    L29
  mov    %esi,(%rdi)
L29:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L49
L27:
  mov    (%rdi),%eax
  mov    %eax,%ecx
  add    %esi,%ecx
  jns    L7
  mov    %r8d,(%rdi)
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L27
L49:
  ret
```

assistant: ```c
void BoundDctMatrix(matrix, Bound) int *matrix;
int Bound;
{
  static char RoutineName[] = "BoundDctMatrix";
  int *mptr;
  for (mptr = matrix; mptr < matrix + 64; mptr++) {
    if (*mptr + Bound < 0)
      *mptr = -Bound;
    else if (*mptr - Bound > 0)
      *mptr = Bound;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<k_quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L36
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L41:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <k_quicksort_cmp@plt>
  test   %rax,%rax
  jns    L37
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L37:
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <k_quicksort_swap@plt>
  mov    -0x1c(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <k_quicksort_t@plt>
  jmp    L9
L36:
  nop
L9:
  leave
  ret
```

assistant: ```c
void k_quicksort(int data[], int n) {
  int i = 0;
  int max = 0;
  if (2 > n) {
    return;
  }
  for (i = 1, max = 0; i < n; ++i) {
    if (0 > k_quicksort_cmp(data[max], data[i])) {
      max = i;
    }
  }
  k_quicksort_swap(&data[n - 1], &data[max]);
  k_quicksort_t(data, 0, n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<k_quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L3
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %esi,%r14d
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L2:
  mov    (%r12,%rbx,4),%esi
  movslq %ebp,%rax
  mov    (%r12,%rax,4),%edi
  call   <k_quicksort_cmp@plt>
  test   %rax,%rax
  cmovs  %ebx,%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L2
  movslq %ebp,%rbp
  lea    (%r12,%rbp,4),%rsi
  movslq %r13d,%rax
  lea    -0x4(%r12,%rax,4),%rdi
  call   <k_quicksort_swap@plt>
  lea    -0x2(%r13),%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <k_quicksort_t@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  ret
```

assistant: ```c
void k_quicksort(int data[], int n) {
  int i = 0;
  int max = 0;
  if (2 > n) {
    return;
  }
  for (i = 1, max = 0; i < n; ++i) {
    if (0 > k_quicksort_cmp(data[max], data[i])) {
      max = i;
    }
  }
  k_quicksort_swap(&data[n - 1], &data[max]);
  k_quicksort_t(data, 0, n - 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<k_quicksort>:
  endbr64
  push   %r15
  movslq %esi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%r15d
  jle    L22
  mov    %rdi,%r14
  lea    0x4(%rdi),%rbx
  xor    %r13d,%r13d
  mov    $0x1,%r12d
  jmp    L14
  nopl   (%rax)
L1:
  mov    %eax,%r12d
L14:
  movslq %r13d,%rax
  mov    (%rbx),%esi
  lea    (%r14,%rax,4),%rbp
  mov    0x0(%rbp),%edi
  call   <k_quicksort_cmp@plt>
  test   %rax,%rax
  lea    0x1(%r12),%eax
  cmovs  %rbx,%rbp
  cmovs  %r12d,%r13d
  add    $0x4,%rbx
  cmp    %eax,%r15d
  jne    L1
  lea    -0x4(%r14,%r15,4),%rdi
  mov    %rbp,%rsi
  call   <k_quicksort_swap@plt>
  add    $0x8,%rsp
  lea    -0x1(%r12),%edx
  xor    %esi,%esi
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <k_quicksort_t@plt>
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void k_quicksort(int data[], int n) {
  int i = 0;
  int max = 0;
  if (2 > n) {
    return;
  }
  for (i = 1, max = 0; i < n; ++i) {
    if (0 > k_quicksort_cmp(data[max], data[i])) {
      max = i;
    }
  }
  k_quicksort_swap(&data[n - 1], &data[max]);
  k_quicksort_t(data, 0, n - 2);
}
```