ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<millis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ftime@plt>
  mov    -0x20(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
long millis() {
  struct timeb tb;
  ftime(&tb);
  return (long)(tb.time * 1000 + tb.millitm);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ftime@plt>
  imul   $0x3e8,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis() {
  struct timeb tb;
  ftime(&tb);
  return (long)(tb.time * 1000 + tb.millitm);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ftime@plt>
  imul   $0x3e8,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis() {
  struct timeb tb;
  ftime(&tb);
  return (long)(tb.time * 1000 + tb.millitm);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<millis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <ftime@plt>
  imul   $0x3e8,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long millis() {
  struct timeb tb;
  ftime(&tb);
  return (long)(tb.time * 1000 + tb.millitm);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GenReadCRegIndirect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%r9d
  mov    $0x3,%r8d
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L33
  mov    $0x0,%r9d
  mov    $0x1b,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <GenPrintInstr2Operands@plt>
  jmp    L15
L33:
  cmpl   $0x1,-0x4(%rbp)
  jne    L17
  mov    $0x0,%r9d
  mov    $0x1b,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x2,%edi
  call   <GenPrintInstr2Operands@plt>
  jmp    L15
L17:
  mov    $0x0,%r9d
  mov    $0x1a,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
L15:
  nop
  leave
  ret
```

assistant: ```c
void GenReadCRegIndirect(int opSz) {
  GenPrintInstr2Operands(0x00, 0, 0x04, 0, 0x03, 0);
  if (opSz == -1)
    GenPrintInstr2Operands(0x01, 0, 0x05, 0, 0x1B, 0);
  else if (opSz == 1)
    GenPrintInstr2Operands(0x02, 0, 0x05, 0, 0x1B, 0);
  else
    GenPrintInstr2Operands(0x00, 0, 0x05, 0, 0x1A, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GenReadCRegIndirect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%r9d
  mov    $0x3,%r8d
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
  cmp    $0xffffffff,%ebx
  je     L28
  cmp    $0x1,%ebx
  je     L17
  mov    $0x0,%r9d
  mov    $0x1a,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
L4:
  pop    %rbx
  ret
L28:
  mov    $0x0,%r9d
  mov    $0x1b,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <GenPrintInstr2Operands@plt>
  jmp    L4
L17:
  mov    $0x0,%r9d
  mov    $0x1b,%r8d
  mov    $0x0,%ecx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    $0x2,%edi
  call   <GenPrintInstr2Operands@plt>
  jmp    L4
```

assistant: ```c
void GenReadCRegIndirect(int opSz) {
  GenPrintInstr2Operands(0x00, 0, 0x04, 0, 0x03, 0);
  if (opSz == -1)
    GenPrintInstr2Operands(0x01, 0, 0x05, 0, 0x1B, 0);
  else if (opSz == 1)
    GenPrintInstr2Operands(0x02, 0, 0x05, 0, 0x1B, 0);
  else
    GenPrintInstr2Operands(0x00, 0, 0x05, 0, 0x1A, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GenReadCRegIndirect>:
  endbr64
  push   %rbx
  xor    %r9d,%r9d
  mov    %edi,%ebx
  mov    $0x3,%r8d
  xor    %ecx,%ecx
  mov    $0x4,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <GenPrintInstr2Operands@plt>
  xor    %r9d,%r9d
  cmp    $0xffffffff,%ebx
  je     L0
  cmp    $0x1,%ebx
  je     L3
  mov    $0x1a,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
  nopl   0x0(%rax)
L3:
  mov    $0x1b,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    $0x2,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1b,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenReadCRegIndirect(int opSz) {
  GenPrintInstr2Operands(0x00, 0, 0x04, 0, 0x03, 0);
  if (opSz == -1)
    GenPrintInstr2Operands(0x01, 0, 0x05, 0, 0x1B, 0);
  else if (opSz == 1)
    GenPrintInstr2Operands(0x02, 0, 0x05, 0, 0x1B, 0);
  else
    GenPrintInstr2Operands(0x00, 0, 0x05, 0, 0x1A, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GenReadCRegIndirect>:
  endbr64
  push   %rbx
  xor    %r9d,%r9d
  mov    %edi,%ebx
  mov    $0x3,%r8d
  xor    %ecx,%ecx
  mov    $0x4,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <GenPrintInstr2Operands@plt>
  xor    %r9d,%r9d
  cmp    $0xffffffff,%ebx
  je     L3
  cmp    $0x1,%ebx
  je     L10
  mov    $0x1a,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
  nopl   0x0(%rax)
L10:
  mov    $0x1b,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    $0x2,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x1b,%r8d
  xor    %ecx,%ecx
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1050 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenReadCRegIndirect(int opSz) {
  GenPrintInstr2Operands(0x00, 0, 0x04, 0, 0x03, 0);
  if (opSz == -1)
    GenPrintInstr2Operands(0x01, 0, 0x05, 0, 0x1B, 0);
  else if (opSz == 1)
    GenPrintInstr2Operands(0x02, 0, 0x05, 0, 0x1B, 0);
  else
    GenPrintInstr2Operands(0x00, 0, 0x05, 0, 0x1A, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  leave
  ret
```

assistant: ```c
int write_long(FILE *fp, int l) {
  putc(l, fp);
  putc(l >> 8, fp);
  putc(l >> 16, fp);
  return (putc(l >> 24, fp));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_long>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdi,%rsi
  mov    %ebx,%edi
  call   <putc@plt>
  mov    %ebx,%edi
  sar    $0x8,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    %ebx,%edi
  sar    $0x10,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  sar    $0x18,%ebx
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int write_long(FILE *fp, int l) {
  putc(l, fp);
  putc(l >> 8, fp);
  putc(l >> 16, fp);
  return (putc(l >> 24, fp));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_long>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  sar    $0x8,%edi
  call   <putc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  sar    $0x18,%ebx
  sar    $0x10,%edi
  call   <putc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
int write_long(FILE *fp, int l) {
  putc(l, fp);
  putc(l >> 8, fp);
  putc(l >> 16, fp);
  return (putc(l >> 24, fp));
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_long>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  sar    $0x8,%edi
  call   <putc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  sar    $0x18,%ebx
  sar    $0x10,%edi
  call   <putc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
int write_long(FILE *fp, int l) {
  putc(l, fp);
  putc(l >> 8, fp);
  putc(l >> 16, fp);
  return (putc(l >> 24, fp));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<runpattern>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  shr    $0x3,%rsi
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    $0x0,%r13d
  lea    D4(%rip),%r14
  jmp    L79
L106:
  mov    %rbx,%rdi
  call   <rol@plt>
  mov    %rax,%rbx
  add    $0x1,%rbp
  add    $0x8,%r15
  cmp    %rbp,%r12
  jbe    L139
L78:
  mov    (%r15),%rcx
  cmp    %rbx,%rcx
  je     L106
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L106
L139:
  lea    0x1(%r13),%r15
  cmp    $0x1f,%r15
  ja     L2
  mov    0x8(%rsp),%rbx
  test   %r15,%r15
  je     L108
L100:
  mov    0x8(%rsp),%rbx
  mov    $0x0,%ebp
  mov    %rbx,%rdi
L134:
  call   <rol@plt>
  mov    %rax,%rdi
  add    $0x1,%rbp
  cmp    %r15,%rbp
  jne    L134
  mov    %rax,%rbx
L108:
  add    $0x1,%r13
L79:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x7,0x10(%rsp)
  jbe    L40
  mov    0x18(%rsp),%r15
  mov    $0x0,%ebp
  mov    %rbx,%rdi
L89:
  mov    %rdi,(%r15)
  call   <rol@plt>
  mov    %rax,%rdi
  add    $0x1,%rbp
  add    $0x8,%r15
  cmp    %rbp,%r12
  ja     L89
  mov    0x8(%rsp),%rbx
  test   %r13,%r13
  je     L92
L25:
  mov    0x8(%rsp),%rbx
  mov    $0x0,%ebp
  mov    %rbx,%rdi
L10:
  call   <rol@plt>
  mov    %rax,%rdi
  add    $0x1,%rbp
  cmp    %rbp,%r13
  jne    L10
  mov    %rax,%rbx
  cmpq   $0x7,0x10(%rsp)
  jbe    L139
L92:
  mov    0x18(%rsp),%r15
  mov    $0x0,%ebp
  jmp    L78
L40:
  mov    $0x1,%r15d
  test   %r13,%r13
  jne    L25
  jmp    L100
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D4: Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x


tool: D8: Pass %2d: 0x%08x


assistant: ```c
void runpattern(unsigned long base, unsigned long size, unsigned long pattern) {
  unsigned long pp;
  unsigned long ii;
  unsigned long pat;
  unsigned long *mbase = (unsigned long *)base;
  unsigned long bound = size / sizeof(mbase);
  for (pp = 0; pp < 32; ++pp) {
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    printf("Pass %2d: 0x%08x\n", pp, pat);
    for (ii = 0; ii < bound; ++ii) {
      mbase[ii] = pat;
      pat = rol(pat);
    }
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    for (ii = 0; ii < bound; ++ii) {
      if (mbase[ii] != pat) {
        printf("Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x\n", ii, pat, mbase[ii]);
      }
      pat = rol(pat);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<runpattern>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  and    $0xfffffffffffffff8,%rsi
  push   %r12
  add    %rdi,%rsi
  shr    $0x3,%r13
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rsi,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
  mov    %r15,%rdx
  lea    D18(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  test   %r13,%r13
  je     L77
  mov    0x10(%rsp),%rbx
  mov    0x18(%rsp),%r14
  mov    %r15,%rdi
  nopw   0x0(%rax,%rax,1)
L98:
  mov    %rdi,(%rbx)
  add    $0x8,%rbx
  call   <rol@plt>
  mov    %rax,%rdi
  cmp    %r14,%rbx
  jne    L98
  mov    0x8(%rsp),%r15
  add    $0x1,%rbp
  test   %r12,%r12
  je     L106
L44:
  mov    0x8(%rsp),%r15
  xor    %ebx,%ebx
  mov    %r15,%rdi
  nopl   0x0(%rax)
L119:
  call   <rol@plt>
  add    $0x1,%rbx
  mov    %rax,%rdi
  cmp    %rbx,%r12
  jne    L119
  mov    %rax,%r15
  test   %r13,%r13
  je     L0
L106:
  mov    0x10(%rsp),%rbx
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L28:
  mov    (%rbx),%rcx
  cmp    %r15,%rcx
  je     L72
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L72:
  mov    %r15,%rdi
  add    $0x1,%r14
  add    $0x8,%rbx
  call   <rol@plt>
  mov    %rax,%r15
  cmp    %r14,%r13
  ja     L28
L0:
  cmp    $0x20,%rbp
  je     L114
L10:
  mov    0x8(%rsp),%r15
  xor    %ebx,%ebx
  mov    %r15,%rdi
  nopl   0x0(%rax)
L49:
  call   <rol@plt>
  add    $0x1,%rbx
  mov    %rax,%rdi
  cmp    %rbp,%rbx
  jne    L49
  mov    %rax,%r15
  add    $0x1,%r12
  jmp    L75
  nopl   (%rax)
L77:
  add    $0x1,%rbp
  test   %r12,%r12
  jne    L44
  jmp    L10
L114:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D18: Pass %2d: 0x%08x


tool: D5: Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x


assistant: ```c
void runpattern(unsigned long base, unsigned long size, unsigned long pattern) {
  unsigned long pp;
  unsigned long ii;
  unsigned long pat;
  unsigned long *mbase = (unsigned long *)base;
  unsigned long bound = size / sizeof(mbase);
  for (pp = 0; pp < 32; ++pp) {
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    printf("Pass %2d: 0x%08x\n", pp, pat);
    for (ii = 0; ii < bound; ++ii) {
      mbase[ii] = pat;
      pat = rol(pat);
    }
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    for (ii = 0; ii < bound; ++ii) {
      if (mbase[ii] != pat) {
        printf("Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x\n", ii, pat, mbase[ii]);
      }
      pat = rol(pat);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<runpattern>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  and    $0xfffffffffffffff8,%rsi
  push   %rbp
  add    %rdi,%rsi
  shr    $0x3,%r12
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rsi,0x18(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  mov    %r15,%rdx
  lea    D11(%rip),%rdi
  mov    %rbx,%rsi
  call   <printf@plt>
  test   %r12,%r12
  je     L117
  mov    0x10(%rsp),%r13
  mov    0x18(%rsp),%r14
  mov    %r15,%rdi
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rdi,0x0(%r13)
  add    $0x8,%r13
  call   <rol@plt>
  mov    %rax,%rdi
  cmp    %r14,%r13
  jne    L11
  mov    0x8(%rsp),%r15
  add    $0x1,%rbx
  test   %rbp,%rbp
  je     L0
L108:
  mov    0x8(%rsp),%r15
  xor    %r13d,%r13d
  mov    %r15,%rdi
  xchg   %ax,%ax
L33:
  call   <rol@plt>
  add    $0x1,%r13
  mov    %rax,%rdi
  cmp    %r13,%rbp
  jne    L33
  mov    %rax,%r15
  test   %r12,%r12
  je     L18
L0:
  mov    0x10(%rsp),%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L26:
  mov    0x0(%r13),%rcx
  cmp    %r15,%rcx
  je     L81
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,%rdi
  add    $0x1,%r14
  add    $0x8,%r13
  call   <rol@plt>
  mov    %rax,%r15
  cmp    %r12,%r14
  jb     L26
L18:
  cmp    $0x20,%rbx
  je     L43
L137:
  mov    0x8(%rsp),%r15
  xor    %r14d,%r14d
  mov    %r15,%rdi
  xchg   %ax,%ax
L68:
  call   <rol@plt>
  add    $0x1,%r14
  mov    %rax,%rdi
  cmp    %rbx,%r14
  jne    L68
  mov    %rax,%r15
  add    $0x1,%rbp
  jmp    L12
  nopl   (%rax)
L81:
  mov    %r15,%rdi
  add    $0x1,%r14
  add    $0x8,%r13
  call   <rol@plt>
  mov    %rax,%r15
  cmp    %r14,%r12
  ja     L26
  cmp    $0x20,%rbx
  jne    L137
L43:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L117:
  add    $0x1,%rbx
  test   %rbp,%rbp
  jne    L108
  jmp    L137
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string

tool: D11: Pass %2d: 0x%08x


tool: D12: Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x


assistant: ```c
void runpattern(unsigned long base, unsigned long size, unsigned long pattern) {
  unsigned long pp;
  unsigned long ii;
  unsigned long pat;
  unsigned long *mbase = (unsigned long *)base;
  unsigned long bound = size / sizeof(mbase);
  for (pp = 0; pp < 32; ++pp) {
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    printf("Pass %2d: 0x%08x\n", pp, pat);
    for (ii = 0; ii < bound; ++ii) {
      mbase[ii] = pat;
      pat = rol(pat);
    }
    pat = pattern;
    for (ii = 0; ii < pp; ++ii) {
      pat = rol(pat);
    }
    for (ii = 0; ii < bound; ++ii) {
      if (mbase[ii] != pat) {
        printf("Pattern mismatch at 0x%08x, expect 0x%08x, got 0x%08x\n", ii, pat, mbase[ii]);
      }
      pat = rol(pat);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<JSToMotorIME>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <GetIntegratedMotorEncoder@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L46
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jge    L46
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getJSAnalog@plt>
  cmpl   $0x1,-0x20(%rbp)
  jne    L17
  mov    $0xffffffff,%edx
  jmp    L31
L17:
  mov    $0x1,%edx
L31:
  imul   %edx,%eax
  jmp    L44
L46:
  mov    $0x0,%eax
L44:
  mov    -0x1c(%rbp),%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <SetMotor@plt>
  nop
  leave
  ret
```

assistant: ```c
void JSToMotorIME(int joystick, int channel, int motor, int inverse, long min, long max) {
  long enc = GetIntegratedMotorEncoder(motor);
  SetMotor(motor, enc > min && enc < max ? (getJSAnalog(joystick, channel) * (inverse == 1 ? -1 : 1)) : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<JSToMotorIME>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %r8,%rbp
  mov    %r9,%r12
  mov    %edx,%edi
  call   <GetIntegratedMotorEncoder@plt>
  cmp    %rbp,%rax
  jle    L0
  cmp    %r12,%rax
  jl     L12
L0:
  mov    $0x0,%esi
L25:
  mov    %ebx,%edi
  call   <SetMotor@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <getJSAnalog@plt>
  cmp    $0x1,%r13d
  setne  %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx,%rdx,1),%edx
  imul   %edx,%eax
  mov    %eax,%esi
  jmp    L25
```

assistant: ```c
void JSToMotorIME(int joystick, int channel, int motor, int inverse, long min, long max) {
  long enc = GetIntegratedMotorEncoder(motor);
  SetMotor(motor, enc > min && enc < max ? (getJSAnalog(joystick, channel) * (inverse == 1 ? -1 : 1)) : 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<JSToMotorIME>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edi,%r14d
  mov    %edx,%edi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <GetIntegratedMotorEncoder@plt>
  cmp    %rbx,%rax
  jle    L7
  cmp    %r12,%rax
  jl     L18
L7:
  xor    %esi,%esi
L15:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <SetMotor@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <getJSAnalog@plt>
  mov    %eax,%esi
  neg    %eax
  cmp    $0x1,%r13d
  cmove  %eax,%esi
  jmp    L15
```

assistant: ```c
void JSToMotorIME(int joystick, int channel, int motor, int inverse, long min, long max) {
  long enc = GetIntegratedMotorEncoder(motor);
  SetMotor(motor, enc > min && enc < max ? (getJSAnalog(joystick, channel) * (inverse == 1 ? -1 : 1)) : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<JSToMotorIME>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edi,%r14d
  mov    %edx,%edi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <GetIntegratedMotorEncoder@plt>
  cmp    %rbx,%rax
  jle    L23
  cmp    %r12,%rax
  jl     L2
L23:
  xor    %esi,%esi
L16:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <SetMotor@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <getJSAnalog@plt>
  mov    %eax,%esi
  neg    %eax
  cmp    $0x1,%r13d
  cmove  %eax,%esi
  jmp    L16
```

assistant: ```c
void JSToMotorIME(int joystick, int channel, int motor, int inverse, long min, long max) {
  long enc = GetIntegratedMotorEncoder(motor);
  SetMotor(motor, enc > min && enc < max ? (getJSAnalog(joystick, channel) * (inverse == 1 ? -1 : 1)) : 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L0
L7:
  mov    -0x4(%rbp),%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int mod(int a, int b) {
  int x = (a % b);
  return x < 0 ? x + b : x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  test   %edx,%edx
  mov    %edx,%eax
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int a, int b) {
  int x = (a % b);
  return x < 0 ? x + b : x;
}
```
user: What is the c source code of the assembly code below?

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int a, int b) {
  int x = (a % b);
  return x < 0 ? x + b : x;
}
```