ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_IEG2CRI_64C64_ONCRI>:
  endbr64
  cmpl   $0x0,(%rdx)
  jle    L13
  mov    $0x0,%eax
L8:
  movq   $0x0,(%rsi)
  movq   $0x0,0x8(%rsi)
  add    $0x1,%rax
  movslq (%rcx),%rdi
  lea    (%rsi,%rdi,8),%rsi
  movslq (%rdx),%rdi
  cmp    %rax,%rdi
  jg     L8
L13:
  ret
```

assistant: ```c
void _IEG2CRI_64C64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[2 * i];
    if ((iptr[2 * i] & (((1 << 11) - 1) << 52)) == 0)
      *optr = iptr[2 * i] & (1 << (52 + 11));
    *(optr + 1) = iptr[2 * i + 1];
    if ((iptr[2 * i + 1] & (((1 << 11) - 1) << 52)) == 0)
      *(optr + 1) = iptr[2 * i + 1] & (1 << (52 + 11));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_IEG2CRI_64C64_ONCRI>:
  endbr64
  movslq (%rdx),%rdi
  test   %rdi,%rdi
  jle    L16
  movslq (%rcx),%rdx
  xor    %eax,%eax
  shl    $0x3,%rdx
  nopl   (%rax)
L9:
  add    $0x1,%rax
  movq   $0x0,(%rsi)
  movq   $0x0,0x8(%rsi)
  add    %rdx,%rsi
  cmp    %rdi,%rax
  jne    L9
L16:
  ret
```

assistant: ```c
void _IEG2CRI_64C64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[2 * i];
    if ((iptr[2 * i] & (((1 << 11) - 1) << 52)) == 0)
      *optr = iptr[2 * i] & (1 << (52 + 11));
    *(optr + 1) = iptr[2 * i + 1];
    if ((iptr[2 * i + 1] & (((1 << 11) - 1) << 52)) == 0)
      *(optr + 1) = iptr[2 * i + 1] & (1 << (52 + 11));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_IEG2CRI_64C64_ONCRI>:
  endbr64
  mov    (%rdx),%edi
  test   %edi,%edi
  jle    L17
  movslq (%rcx),%rdx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shl    $0x3,%rdx
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%eax
  movups %xmm0,(%rsi)
  add    %rdx,%rsi
  cmp    %eax,%edi
  jne    L0
L17:
  ret
```

assistant: ```c
void _IEG2CRI_64C64_ONCRI(unsigned long *iptr, unsigned long *optr, int *numadd, int *strideadd) {
  long i;
  for (i = 0; i < *numadd; i++, optr += *strideadd) {
    *optr = iptr[2 * i];
    if ((iptr[2 * i] & (((1 << 11) - 1) << 52)) == 0)
      *optr = iptr[2 * i] & (1 << (52 + 11));
    *(optr + 1) = iptr[2 * i + 1];
    if ((iptr[2 * i + 1] & (((1 << 11) - 1) << 52)) == 0)
      *(optr + 1) = iptr[2 * i + 1] & (1 << (52 + 11));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_move_to_back>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sys_list_del_node@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_push_back@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_move_to_back(struct list_head *node, struct list_head *head) {
  sys_list_del_node(node);
  list_push_back(node, head);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_move_to_back>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <sys_list_del_node@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <list_push_back@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void list_move_to_back(struct list_head *node, struct list_head *head) {
  sys_list_del_node(node);
  list_push_back(node, head);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<list_move_to_back>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <sys_list_del_node@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <list_push_back@plt>
```

assistant: ```c
void list_move_to_back(struct list_head *node, struct list_head *head) {
  sys_list_del_node(node);
  list_push_back(node, head);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_move_to_back>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <sys_list_del_node@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <list_push_back@plt>
```

assistant: ```c
void list_move_to_back(struct list_head *node, struct list_head *head) {
  sys_list_del_node(node);
  list_push_back(node, head);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<QtoPi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %edx,-0xd4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xb8(%rbp)
  jmp    L78
L74:
  mov    -0xb8(%rbp),%eax
  cltq
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0xb8(%rbp)
L78:
  mov    -0xd4(%rbp),%eax
  cmp    -0xb8(%rbp),%eax
  jge    L74
  movl   $0x1,-0xb8(%rbp)
  jmp    L6
L83:
  movl   $0x0,-0xb4(%rbp)
  jmp    L72
L31:
  mov    -0xb4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xb8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0xd4(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,%ecx
  imul   -0xb8(%rbp),%ecx
  mov    -0xb4(%rbp),%edx
  add    %ecx,%edx
  movsd  (%rax),%xmm0
  movslq %edx,%rax
  movsd  %xmm0,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0xb4(%rbp)
L72:
  mov    -0xb4(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L31
  mov    -0xd4(%rbp),%eax
  add    $0x1,%eax
  imul   -0xb8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  add    %edx,%eax
  cltq
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0xb8(%rbp)
L6:
  mov    -0xb8(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L83
  mov    -0xd4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0xd0(%rbp),%rdx
  mov    -0xd4(%rbp),%esi
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <matinv@plt>
  movl   $0x0,-0xb8(%rbp)
  jmp    L40
L67:
  mov    -0xd4(%rbp),%eax
  add    $0x1,%eax
  imul   -0xb8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xd4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0xb8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xd0(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movsd  -0xb0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0xb8(%rbp)
L40:
  mov    -0xb8(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L67
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: f32[2]

tool: {"D8": [0.0,1.875]}

assistant: ```c
int QtoPi(double **Q, double *pi, int n) {
  int i, j;
  double T[20];
  for (i = 0; i < n + 1; i++)
    T[i] = 1;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n; j++) {
      T[i * (n + 1) + j] = Q[j][i];
    }
    T[i * (n + 1) + n] = 0.;
  }
  matinv(T, n, n + 1, pi);
  for (i = 0; i < n; i++) {
    pi[i] = T[i * (n + 1) + n];
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<QtoPi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  js     L35
  mov    %rsp,%rax
  mov    %edx,%edx
  lea    0x8(%rsp,%rdx,8),%rdx
  movsd  D6(%rip),%xmm0
L65:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L65
L35:
  cmp    $0x1,%ebx
  jle    L32
  lea    0x1(%rbx),%ebp
  movslq %ebx,%rax
  lea    0x8(,%rax,8),%r11
  lea    (%rsp,%r11,1),%rsi
  mov    %ebx,%r10d
  shl    $0x3,%r10
  mov    $0x8,%ecx
  mov    %ebx,%r8d
  movslq %ebp,%r13
L67:
  mov    $0x0,%eax
  mov    %rsi,%r9
L75:
  mov    (%rdi,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L75
  movq   $0x0,-0x8(%r9,%r13,8)
  add    $0x8,%rcx
  add    %r11,%rsi
  cmp    %r10,%rcx
  jne    L67
  mov    %rsp,%rdi
  mov    %r12,%rcx
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <matinv@plt>
L23:
  movslq %ebp,%rcx
  shl    $0x3,%rcx
  movslq %ebx,%rax
  lea    (%rsp,%rax,8),%rdx
  mov    $0x0,%eax
L10:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  add    %rcx,%rdx
  cmp    %eax,%ebx
  jg     L10
L87:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    0x1(%rbx),%ebp
  mov    %rsp,%rdi
  mov    %r12,%rcx
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <matinv@plt>
  cmp    $0x1,%ebx
  jne    L87
  jmp    L23
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: f32[2]

tool: {"D6": [0.0,1.875]}

assistant: ```c
int QtoPi(double **Q, double *pi, int n) {
  int i, j;
  double T[20];
  for (i = 0; i < n + 1; i++)
    T[i] = 1;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n; j++) {
      T[i * (n + 1) + j] = Q[j][i];
    }
    T[i * (n + 1) + n] = 0.;
  }
  matinv(T, n, n + 1, pi);
  for (i = 0; i < n; i++) {
    pi[i] = T[i * (n + 1) + n];
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<QtoPi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  js     L17
  mov    %rsp,%r12
  movslq %edx,%r8
  movsd  D8(%rip),%xmm0
  mov    %r12,%rax
  lea    0x8(%rsp,%r8,8),%rdx
  nopl   0x0(%rax)
L15:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L15
  lea    0x1(%rbx),%r14d
  cmp    $0x1,%ebx
  jle    L65
  movslq %r14d,%r13
  lea    0x0(,%r8,8),%r10
  mov    $0x8,%ecx
  lea    0x0(,%r13,8),%r9
  lea    (%r12,%r9,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rdi,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L3
  add    $0x8,%rcx
  movq   $0x0,(%rsi,%rax,8)
  add    %r9,%rsi
  cmp    %r10,%rcx
  jne    L68
  mov    %rbp,%rcx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <matinv@plt>
L76:
  lea    0x0(,%r13,8),%rcx
  xor    %eax,%eax
  lea    -0x8(%r12,%rcx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L27:
  movsd  (%rdx),%xmm0
  add    %rcx,%rdx
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L27
L10:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  lea    0x1(%rdx),%r14d
  mov    %rsp,%r12
L65:
  mov    %rbp,%rcx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <matinv@plt>
  cmp    $0x1,%ebx
  jne    L10
  movslq %r14d,%r13
  jmp    L76
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type: f32[2]

tool: {"D8": [0.0,1.875]}

assistant: ```c
int QtoPi(double **Q, double *pi, int n) {
  int i, j;
  double T[20];
  for (i = 0; i < n + 1; i++)
    T[i] = 1;
  for (i = 1; i < n; i++) {
    for (j = 0; j < n; j++) {
      T[i * (n + 1) + j] = Q[j][i];
    }
    T[i * (n + 1) + n] = 0.;
  }
  matinv(T, n, n + 1, pi);
  for (i = 0; i < n; i++) {
    pi[i] = T[i * (n + 1) + n];
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<testTortureExecute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffffff,%edi
  call   <f@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  f(-1);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <f@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testTortureExecute(void) {
  f(-1);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<testTortureExecute>:
  endbr64
  mov    $0xffffffff,%edi
  jmp    1050 <f@plt>
```

assistant: ```c
void testTortureExecute(void) {
  f(-1);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testTortureExecute>:
  endbr64
  mov    $0xffffffff,%edi
  jmp    1050 <f@plt>
```

assistant: ```c
void testTortureExecute(void) {
  f(-1);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_erros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L24
  cmpl   $0x2,-0x4(%rbp)
  je     L2
  jmp    L32
L24:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L32
L2:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L32:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D1: Erro ao abrir arquivo %s


tool: D3: Erro ao escrever no arquivo %s


assistant: ```c
void print_erros(int cod, char erro[]) {
  switch (cod) {
  case 1: {
    printf("Erro ao abrir arquivo %s\n", erro);
    break;
  }
  case 2: {
    printf("Erro ao escrever no arquivo %s\n", erro);
    break;
  }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_erros>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L0
  cmp    $0x2,%edi
  je     L23
L30:
  add    $0x8,%rsp
  ret
L0:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L23:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D3: Erro ao abrir arquivo %s


tool: D2: Erro ao escrever no arquivo %s


assistant: ```c
void print_erros(int cod, char erro[]) {
  switch (cod) {
  case 1: {
    printf("Erro ao abrir arquivo %s\n", erro);
    break;
  }
  case 2: {
    printf("Erro ao escrever no arquivo %s\n", erro);
    break;
  }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_erros>:
  endbr64
  cmp    $0x1,%edi
  je     L1
  cmp    $0x2,%edi
  jne    L0
  lea    D16(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
  nopl   0x0(%rax)
L1:
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string

tool: D16: Erro ao escrever no arquivo %s


tool: D1: Erro ao abrir arquivo %s


assistant: ```c
void print_erros(int cod, char erro[]) {
  switch (cod) {
  case 1: {
    printf("Erro ao abrir arquivo %s\n", erro);
    break;
  }
  case 2: {
    printf("Erro ao escrever no arquivo %s\n", erro);
    break;
  }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_erros>:
  endbr64
  cmp    $0x1,%edi
  je     L10
  cmp    $0x2,%edi
  jne    L17
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  ret
  nopl   0x0(%rax)
L10:
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D13
data_type: string

tool: D8: Erro ao escrever no arquivo %s


tool: D13: Erro ao abrir arquivo %s


assistant: ```c
void print_erros(int cod, char erro[]) {
  switch (cod) {
  case 1: {
    printf("Erro ao abrir arquivo %s\n", erro);
    break;
  }
  case 2: {
    printf("Erro ao escrever no arquivo %s\n", erro);
    break;
  }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L42:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L42
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
L12:
  mov    %eax,0x10(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x8000,%rax
  jne    L12
  lea    0x10(%rsp),%r11
  mov    %r11,%rbx
  mov    $0x0,%r10d
L5:
  lea    0x80(%rbx),%rcx
  mov    %rbx,%r8
  mov    $0x0,%r9d
  mov    $0x0,%edi
L53:
  mov    %r10d,%esi
  xor    %edi,%esi
  mov    %r8,%rax
  mov    $0x0,%edx
L91:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L91
  mov    %r10d,%esi
  or     %r9d,%esi
  mov    %r8,%rax
  mov    $0x0,%edx
L51:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L51
  add    $0x3,%edi
  sub    $0xffffffffffffff80,%r8
  sub    $0xffffffffffffff80,%rcx
  add    $0x5,%r9d
  cmp    $0x60,%edi
  jne    L53
  add    $0x1,%r10d
  add    $0x1000,%rbx
  cmp    $0x20,%r10d
  jne    L5
  lea    0x80(%r11),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
L55:
  mov    0x4(%rsp),%r15d
  shl    $0xa,%r15d
  mov    0x8(%rsp),%r12
  mov    $0x0,%r14d
L99:
  lea    -0x80(%r12),%rbx
  lea    (%r14,%r14,2),%edx
  mov    0x4(%rsp),%ecx
  xor    %ecx,%edx
  lea    (%r14,%r14,4),%eax
  or     %ecx,%eax
  lea    0x1(%rdx,%rax,1),%r13d
  mov    %r15d,%ebp
L32:
  cmp    %ebp,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  add    %r13d,%ebp
  cmp    %r12,%rbx
  jne    L32
  add    $0x1,%r14d
  add    $0x20,%r15d
  sub    $0xffffffffffffff80,%r12
  cmp    $0x20,%r14d
  jne    L99
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  addq   $0x1000,0x8(%rsp)
  cmp    $0x20,%eax
  jne    L55
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x20028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, arr[32 * 32 * 32];
  int pt[2];
  for (i = 0; i < 32 * 32 * 32; i++)
    arr[i] = i;
#pragma acc kernels copy(arr)
  {
    int j;
#pragma acc loop gang(num : 32)
    for (i = 0; i < 32; i++) {
#pragma acc loop worker(num : 32) private(pt)
      for (j = 0; j < 32; j++) {
        int k;
        pt[0] = i ^ j * 3;
#pragma acc loop vector(length : 32)
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[0] * k;
        pt[1] = i | j * 5;
#pragma acc loop vector(length : 32)
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[1] * k;
      }
    }
  }
  for (i = 0; i < 32; i++)
    for (int j = 0; j < 32; j++)
      for (int k = 0; k < 32; k++) {
        int idx = i * 1024 + j * 32 + k;
        assert(arr[idx] == idx + (i ^ j * 3) * k + (i | j * 5) * k);
      }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L91:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L91
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
L21:
  mov    %eax,(%r15,%rax,4)
  add    $0x1,%rax
  cmp    $0x8000,%rax
  jne    L21
  mov    %r15,%r11
  xor    %r10d,%r10d
L37:
  lea    0x80(%r11),%rcx
  mov    %r11,%r8
  xor    %r9d,%r9d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r10d,%esi
  mov    %r8,%rax
  xor    %edx,%edx
  xor    %edi,%esi
  nopw   0x0(%rax,%rax,1)
L43:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L43
  mov    %r10d,%esi
  mov    %r8,%rax
  xor    %edx,%edx
  or     %r9d,%esi
  nopl   0x0(%rax,%rax,1)
L76:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L76
  add    $0x3,%edi
  sub    $0xffffffffffffff80,%r8
  lea    0x80(%rax),%rcx
  add    $0x5,%r9d
  cmp    $0x60,%edi
  jne    L5
  add    $0x1,%r10d
  add    $0x1000,%r11
  cmp    $0x20,%r10d
  jne    L37
  lea    0x80(%r15),%rax
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
L34:
  mov    0x4(%rsp),%r13d
  mov    0x8(%rsp),%rbx
  xor    %r12d,%r12d
  shl    $0xa,%r13d
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%esi
  lea    (%r12,%r12,2),%ecx
  lea    (%r12,%r12,4),%eax
  mov    %r13d,%r15d
  lea    -0x80(%rbx),%r14
  xor    %esi,%ecx
  or     %esi,%eax
  lea    0x1(%rcx,%rax,1),%ebp
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %edi,%edi
  cmp    %r15d,(%r14)
  sete   %dil
  add    $0x4,%r14
  add    %ebp,%r15d
  call   <assert@plt>
  cmp    %r14,%rbx
  jne    L24
  add    $0x1,%r12d
  add    $0x20,%r13d
  sub    $0xffffffffffffff80,%rbx
  cmp    $0x20,%r12d
  jne    L18
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  addq   $0x1000,0x8(%rsp)
  cmp    $0x20,%eax
  jne    L34
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x20028,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i, arr[32 * 32 * 32];
  int pt[2];
  for (i = 0; i < 32 * 32 * 32; i++)
    arr[i] = i;
#pragma acc kernels copy(arr)
  {
    int j;
#pragma acc loop gang(num : 32)
    for (i = 0; i < 32; i++) {
#pragma acc loop worker(num : 32) private(pt)
      for (j = 0; j < 32; j++) {
        int k;
        pt[0] = i ^ j * 3;
#pragma acc loop vector(length : 32)
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[0] * k;
        pt[1] = i | j * 5;
#pragma acc loop vector(length : 32)
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[1] * k;
      }
    }
  }
  for (i = 0; i < 32; i++)
    for (int j = 0; j < 32; j++)
      for (int k = 0; k < 32; k++) {
        int idx = i * 1024 + j * 32 + k;
        assert(arr[idx] == idx + (i ^ j * 3) * k + (i | j * 5) * k);
      }
  return 0;
}
```