ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tips>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D42
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D65
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D37
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D42: Notice that during encrypt the input file should be your plaintext, 

tool: D4: and the output file will be the correspondent ciphertext.


tool: D25: But, during decryption, the input file must be the ciphertext, 

tool: D65: and the output file will be the correspondent plaintext.


tool: D21: The program will also search for a file called 'keyfile' to use as key.

tool: D37: If the keyfile can't be found, the program will generate a key for you.

tool: D48: One must use the same keyfile to encrypt and decrypt to get the algorithm

tool: D5: to work properly.


assistant: ```c
void tips() {
  printf("Notice that during encrypt the input file should be your plaintext, ");
  printf("and the output file will be the correspondent ciphertext.\n");
  printf("But, during decryption, the input file must be the ciphertext, ");
  printf("and the output file will be the correspondent plaintext.\n");
  printf("The program will also search for a file called 'keyfile' to use as key.");
  printf("If the keyfile can't be found, the program will generate a key for you.");
  printf("One must use the same keyfile to encrypt and decrypt to get the algorithm");
  printf("to work properly.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tips>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D27
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string
name: retrieve_data
arguments: tag: D69
data_type: string
name: retrieve_data
arguments: tag: D64
data_type: string
name: retrieve_data
arguments: tag: D45
data_type: string
name: retrieve_data
arguments: tag: D10
data_type: string
name: retrieve_data
arguments: tag: D44
data_type: string

tool: D5: Notice that during encrypt the input file should be your plaintext, 

tool: D27: and the output file will be the correspondent ciphertext.


tool: D29: But, during decryption, the input file must be the ciphertext, 

tool: D69: and the output file will be the correspondent plaintext.


tool: D64: The program will also search for a file called 'keyfile' to use as key.

tool: D45: If the keyfile can't be found, the program will generate a key for you.

tool: D10: One must use the same keyfile to encrypt and decrypt to get the algorithm

tool: D44: to work properly.


assistant: ```c
void tips() {
  printf("Notice that during encrypt the input file should be your plaintext, ");
  printf("and the output file will be the correspondent ciphertext.\n");
  printf("But, during decryption, the input file must be the ciphertext, ");
  printf("and the output file will be the correspondent plaintext.\n");
  printf("The program will also search for a file called 'keyfile' to use as key.");
  printf("If the keyfile can't be found, the program will generate a key for you.");
  printf("One must use the same keyfile to encrypt and decrypt to get the algorithm");
  printf("to work properly.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Ket_StateExtractByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  lea    -0x9(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <KeccakP400_ExtractBytes@plt>
  movzbl -0x9(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
unsigned char Ket_StateExtractByte(void *state, unsigned int offset) {
  unsigned char data[1];
  KeccakP400_ExtractBytes(state, data, offset, 1);
  return data[0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Ket_StateExtractByte>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%ecx
  call   <KeccakP400_ExtractBytes@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char Ket_StateExtractByte(void *state, unsigned int offset) {
  unsigned char data[1];
  KeccakP400_ExtractBytes(state, data, offset, 1);
  return data[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Ket_StateExtractByte>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <KeccakP400_ExtractBytes@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char Ket_StateExtractByte(void *state, unsigned int offset) {
  unsigned char data[1];
  KeccakP400_ExtractBytes(state, data, offset, 1);
  return data[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<Ket_StateExtractByte>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <KeccakP400_ExtractBytes@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char Ket_StateExtractByte(void *state, unsigned int offset) {
  unsigned char data[1];
  KeccakP400_ExtractBytes(state, data, offset, 1);
  return data[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<debug_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edi
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%r9
  mov    %edi,%r8d
  mov    %esi,%ecx
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: %s:%d: calloc(%d, %d)=%p


assistant: ```c
void *debug_calloc(const size_t num, const size_t size, const char *file, const int line) {
  void *ptr = (calloc)(num, size);
  printf("%s:%d: calloc(%d, %d)=%p\n", file, line, (int)num, (int)size, ptr);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_calloc>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %rbx,%r9
  mov    %ebx,%r8d
  mov    %edi,%ecx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s:%d: calloc(%d, %d)=%p


assistant: ```c
void *debug_calloc(const size_t num, const size_t size, const char *file, const int line) {
  void *ptr = (calloc)(num, size);
  printf("%s:%d: calloc(%d, %d)=%p\n", file, line, (int)num, (int)size, ptr);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<debug_calloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %r12,%r9
  mov    %r12d,%r8d
  mov    %edi,%ecx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: %s:%d: calloc(%d, %d)=%p


assistant: ```c
void *debug_calloc(const size_t num, const size_t size, const char *file, const int line) {
  void *ptr = (calloc)(num, size);
  printf("%s:%d: calloc(%d, %d)=%p\n", file, line, (int)num, (int)size, ptr);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<debug_calloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %r12,%r9
  mov    %r12d,%r8d
  mov    %edi,%ecx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: %s:%d: calloc(%d, %d)=%p


assistant: ```c
void *debug_calloc(const size_t num, const size_t size, const char *file, const int line) {
  void *ptr = (calloc)(num, size);
  printf("%s:%d: calloc(%d, %d)=%p\n", file, line, (int)num, (int)size, ptr);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unitptn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x40000002,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unitptn(int *lab, int *ptn, int *numcells, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    lab[i] = i;
    ptn[i] = 0x40000002;
  }
  ptn[n - 1] = 0;
  *numcells = 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<unitptn>:
  endbr64
  test   %ecx,%ecx
  jle    L13
  mov    %ecx,%r8d
  mov    $0x0,%eax
L2:
  mov    %eax,(%rdi,%rax,4)
  movl   $0x40000002,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L2
L13:
  movslq %ecx,%rcx
  movl   $0x0,-0x4(%rsi,%rcx,4)
  movl   $0x1,(%rdx)
  ret
```

assistant: ```c
void unitptn(int *lab, int *ptn, int *numcells, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    lab[i] = i;
    ptn[i] = 0x40000002;
  }
  ptn[n - 1] = 0;
  *numcells = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<unitptn>:
  endbr64
  test   %ecx,%ecx
  movslq %ecx,%rcx
  jle    L2
  xor    %eax,%eax
  nopl   (%rax)
L6:
  mov    %eax,(%rdi,%rax,4)
  movl   $0x40000002,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L2:
  movl   $0x0,-0x4(%rsi,%rcx,4)
  movl   $0x1,(%rdx)
  ret
```

assistant: ```c
void unitptn(int *lab, int *ptn, int *numcells, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    lab[i] = i;
    ptn[i] = 0x40000002;
  }
  ptn[n - 1] = 0;
  *numcells = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unitptn>:
  endbr64
  mov    %rdx,%r8
  mov    %ecx,%edx
  test   %ecx,%ecx
  jle    L50
  lea    0x4(%rdi),%rcx
  mov    %rsi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L26
  lea    -0x1(%rdx),%eax
  cmp    $0x3,%eax
  jbe    L26
  mov    %edx,%ecx
  movdqa D21(%rip),%xmm0
  xor    %eax,%eax
  movdqa D11(%rip),%xmm3
  shr    $0x2,%ecx
  movdqa D12(%rip),%xmm2
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L43:
  movdqa %xmm0,%xmm1
  paddd  %xmm3,%xmm0
  movups %xmm1,(%rdi,%rax,1)
  movups %xmm2,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L43
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L50
  mov    %eax,%r9d
  mov    %eax,(%rdi,%r9,4)
  lea    0x0(,%r9,4),%rcx
  movl   $0x40000002,(%rsi,%r9,4)
  lea    0x1(%rax),%r9d
  cmp    %r9d,%edx
  jle    L50
  add    $0x2,%eax
  mov    %r9d,0x4(%rdi,%rcx,1)
  movl   $0x40000002,0x4(%rsi,%rcx,1)
  cmp    %eax,%edx
  jle    L50
  mov    %eax,0x8(%rdi,%rcx,1)
  movl   $0x40000002,0x8(%rsi,%rcx,1)
L50:
  movslq %edx,%rdx
  movl   $0x0,-0x4(%rsi,%rdx,4)
  movl   $0x1,(%r8)
  ret
  xchg   %ax,%ax
L26:
  mov    %edx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  mov    %eax,(%rdi,%rax,4)
  movl   $0x40000002,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L1
  jmp    L50
```

tool_calls: name: disassemble_data
arguments: label: D21
type_guessed: byte[16]
name: disassemble_data
arguments: label: D11
type_guessed: byte[16]
name: disassemble_data
arguments: label: D12
type_guessed: byte[16]

tool: {"D21": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D12": [0x02,0x00,0x00,0x40,0x02,0x00,0x00,0x40,0x02,0x00,0x00,0x40,0x02,0x00,0x00,0x40]}

assistant: ```c
void unitptn(int *lab, int *ptn, int *numcells, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    lab[i] = i;
    ptn[i] = 0x40000002;
  }
  ptn[n - 1] = 0;
  *numcells = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TimerControlWaitOnTrigger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_TimerBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0xff,-0x8(%rbp)
  je     L84
  cmpl   $0xff00,-0x8(%rbp)
  je     L84
  cmpl   $0xffff,-0x8(%rbp)
  jne    L99
L84:
  mov    $0x1,%eax
  jmp    L2
L99:
  mov    $0x0,%eax
L2:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L94
  cmpl   $0x0,-0xc(%rbp)
  je     L75
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x4,%edx
  movslq %edx,%rdx
  or     $0x40,%eax
  mov    %eax,(%rdx)
  jmp    L94
L75:
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x4,%edx
  movslq %edx,%rdx
  and    $0xffffffbf,%eax
  mov    %eax,(%rdx)
L94:
  mov    -0x8(%rbp),%eax
  and    $0xff00,%eax
  test   %eax,%eax
  je     L79
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x8,%edx
  movslq %edx,%rdx
  or     $0x40,%eax
  mov    %eax,(%rdx)
  jmp    L79
L18:
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x8,%edx
  movslq %edx,%rdx
  and    $0xffffffbf,%eax
  mov    %eax,(%rdx)
L79:
  nop
  leave
  ret
```

assistant: ```c
void TimerControlWaitOnTrigger(uint32_t ui32Base, uint32_t ui32Timer, bool bWait) {
  ASSERT(_TimerBaseValid(ui32Base));
  ASSERT((ui32Timer == 0x000000ff) || (ui32Timer == 0x0000ff00) || (ui32Timer == 0x0000ffff));
  if ((ui32Timer & 0x000000ff) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) &= ~(0x00000040);
    }
  }
  if ((ui32Timer & 0x0000ff00) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x00000040);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TimerControlWaitOnTrigger>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  call   <_TimerBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmp    $0xff,%ebx
  sete   %dil
  cmp    $0xff00,%ebx
  sete   %al
  or     %eax,%edi
  cmp    $0xffff,%ebx
  sete   %al
  or     %eax,%edi
  movzbl %dil,%edi
  call   <ASSERT@plt>
  test   %bl,%bl
  je     L13
  test   %r12d,%r12d
  je     L58
  lea    0x4(%rbp),%eax
  cltq
  mov    (%rax),%edx
  or     $0x40,%edx
  mov    %edx,(%rax)
  test   $0xff,%bh
  je     L18
L16:
  add    $0x8,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%eax
  or     $0x40,%eax
  mov    %eax,0x0(%rbp)
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  lea    0x4(%rbp),%eax
  cltq
  mov    (%rax),%edx
  and    $0xffffffbf,%edx
  mov    %edx,(%rax)
  test   $0xff,%bh
  je     L18
L65:
  add    $0x8,%ebp
  movslq %ebp,%rbp
  mov    0x0(%rbp),%eax
  and    $0xffffffbf,%eax
  mov    %eax,0x0(%rbp)
  jmp    L18
L13:
  test   $0xff,%bh
  je     L18
  test   %r12d,%r12d
  je     L65
  jmp    L16
```

assistant: ```c
void TimerControlWaitOnTrigger(uint32_t ui32Base, uint32_t ui32Timer, bool bWait) {
  ASSERT(_TimerBaseValid(ui32Base));
  ASSERT((ui32Timer == 0x000000ff) || (ui32Timer == 0x0000ff00) || (ui32Timer == 0x0000ffff));
  if ((ui32Timer & 0x000000ff) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) &= ~(0x00000040);
    }
  }
  if ((ui32Timer & 0x0000ff00) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x00000040);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<TimerControlWaitOnTrigger>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_TimerBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmp    $0xff,%ebx
  sete   %dil
  cmp    $0xff00,%ebx
  sete   %al
  or     %eax,%edi
  cmp    $0xffff,%ebx
  sete   %al
  or     %eax,%edi
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %ebx,%edx
  and    $0xff00,%edx
  test   %bl,%bl
  je     L60
  lea    0x4(%r12),%eax
  cltq
  mov    (%rax),%ecx
  test   %ebp,%ebp
  je     L36
  or     $0x40,%ecx
  mov    %ecx,(%rax)
  test   %edx,%edx
  je     L28
L1:
  add    $0x8,%r12d
  movslq %r12d,%r12
  mov    (%r12),%eax
  or     $0x40,%eax
  mov    %eax,(%r12)
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L60:
  test   %edx,%edx
  je     L28
  test   %ebp,%ebp
  jne    L1
L25:
  add    $0x8,%r12d
  movslq %r12d,%r12
  mov    (%r12),%eax
  and    $0xffffffbf,%eax
  mov    %eax,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L36:
  and    $0xffffffbf,%ecx
  mov    %ecx,(%rax)
  test   %edx,%edx
  jne    L25
  jmp    L28
```

assistant: ```c
void TimerControlWaitOnTrigger(uint32_t ui32Base, uint32_t ui32Timer, bool bWait) {
  ASSERT(_TimerBaseValid(ui32Base));
  ASSERT((ui32Timer == 0x000000ff) || (ui32Timer == 0x0000ff00) || (ui32Timer == 0x0000ffff));
  if ((ui32Timer & 0x000000ff) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) &= ~(0x00000040);
    }
  }
  if ((ui32Timer & 0x0000ff00) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x00000040);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TimerControlWaitOnTrigger>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_TimerBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmp    $0xff,%ebx
  sete   %dil
  cmp    $0xff00,%ebx
  sete   %al
  or     %eax,%edi
  cmp    $0xffff,%ebx
  sete   %al
  or     %eax,%edi
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %ebx,%edx
  and    $0xff00,%edx
  test   %bl,%bl
  je     L37
  lea    0x4(%r12),%eax
  cltq
  mov    (%rax),%ecx
  test   %ebp,%ebp
  je     L17
  or     $0x40,%ecx
  mov    %ecx,(%rax)
  test   %edx,%edx
  je     L41
L36:
  add    $0x8,%r12d
  movslq %r12d,%r12
  mov    (%r12),%eax
  or     $0x40,%eax
  mov    %eax,(%r12)
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L37:
  test   %edx,%edx
  je     L41
  test   %ebp,%ebp
  jne    L36
L69:
  add    $0x8,%r12d
  movslq %r12d,%r12
  mov    (%r12),%eax
  and    $0xffffffbf,%eax
  mov    %eax,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L17:
  and    $0xffffffbf,%ecx
  mov    %ecx,(%rax)
  test   %edx,%edx
  jne    L69
  jmp    L41
```

assistant: ```c
void TimerControlWaitOnTrigger(uint32_t ui32Base, uint32_t ui32Timer, bool bWait) {
  ASSERT(_TimerBaseValid(ui32Base));
  ASSERT((ui32Timer == 0x000000ff) || (ui32Timer == 0x0000ff00) || (ui32Timer == 0x0000ffff));
  if ((ui32Timer & 0x000000ff) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000004))) &= ~(0x00000040);
    }
  }
  if ((ui32Timer & 0x0000ff00) != 0) {
    if (bWait) {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000040;
    } else {
      (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x00000040);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<e_o2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  ucomisd D1(%rip),%xmm0
  jp     L8
  movsd  -0x18(%rbp),%xmm0
  ucomisd D1(%rip),%xmm0
  jne    L8
  movsd  D42(%rip),%xmm0
  jmp    L17
L8:
  movsd  -0x18(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D27(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  D22(%rip),%xmm1
  mulsd  %xmm1,%xmm0
L17:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: byte[8]
name: unpack_data
arguments: tag: D42
type_guessed: byte[8]
name: unpack_data
arguments: tag: D5
type_guessed: byte[8]
name: unpack_data
arguments: tag: D27
type_guessed: byte[8]
name: unpack_data
arguments: tag: D22
type_guessed: f64

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x80,0x61,0x40]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x80,0x47,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x80,0x5a,0x40]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x42,0xad,0xc0]}

tool: D22: 100.8

assistant: ```c
double e_o2(double o2) {
  if (o2 == 140)
    return 47;
  else {
    double a;
    a = pow(o2 + -106, 2);
    return 100.8 * exp(a / -3745);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<e_o2>:
  endbr64
  ucomisd D34(%rip),%xmm0
  jp     L5
  movsd  D7(%rip),%xmm1
  jne    L5
  movapd %xmm1,%xmm0
  ret
L5:
  sub    $0x8,%rsp
  subsd  D33(%rip),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  divsd  D49(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  mulsd  D27(%rip),%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D34
type: byte[8]
name: parse_data
arguments: tag: D7
type: byte[8]
name: parse_data
arguments: tag: D33
type: byte[8]
name: parse_data
arguments: tag: D49
type: byte[8]
name: parse_data
arguments: tag: D27
type: f64

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x80,0x61,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x80,0x47,0x40]}

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x80,0x5a,0x40]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x42,0xad,0xc0]}

tool: D27: 100.8

assistant: ```c
double e_o2(double o2) {
  if (o2 == 140)
    return 47;
  else {
    double a;
    a = pow(o2 + -106, 2);
    return 100.8 * exp(a / -3745);
  }
}
```