ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<postfix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x68,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movb   $0x24,0x30(%rsp)
  movq   $0x0,0x18(%rsp)
  jmp    L115
L127:
  mov    0x8(%rsp),%rcx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %r13b,(%rcx,%rax,1)
L84:
  addq   $0x1,0x18(%rsp)
L115:
  mov    0x20(%rsp),%rdi
  call   <strlen@plt>
  cmp    0x18(%rsp),%eax
  jle    L77
  mov    0x20(%rsp),%rax
  mov    0x18(%rsp),%rsi
  movsbl (%rax,%rsi,1),%r13d
  mov    %r13d,%edi
  mov    %r13b,0x2f(%rsp)
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L127
  movslq %ebx,%rdx
  cmpb   $0x29,0x2f(%rsp)
  movzbl 0x30(%rsp,%rdx,1),%ecx
  je     L30
  lea    0x30(%rsp),%rax
  movslq %ebp,%r14
  mov    %rdx,%r15
  mov    %rax,0x10(%rsp)
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L59:
  mov    0x8(%rsp),%rax
  mov    %r12b,(%rax,%r14,1)
  add    $0x1,%r14
L102:
  mov    0x10(%rsp),%rax
  mov    %r15d,0x28(%rsp)
  mov    %r14d,%ebp
  movsbl (%rax,%r15,1),%edi
  sub    $0x1,%r15
  mov    %edi,%r12d
  call   <ISP@plt>
  mov    %r13d,%edi
  mov    %rax,%rbx
  call   <ICP@plt>
  cmp    %rax,%rbx
  jge    L59
  mov    0x28(%rsp),%ebx
  movzbl 0x2f(%rsp),%edx
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %dl,0x30(%rsp,%rax,1)
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L30:
  cmp    $0x28,%cl
  je     L68
  lea    0x30(%rsp),%rsi
  lea    -0x1(%rbx),%edx
  mov    %rsi,0x10(%rsp)
  lea    0x1(%rbp),%eax
  movslq %edx,%rdx
  cltq
  nopw   0x0(%rax,%rax,1)
L62:
  mov    0x8(%rsp),%rsi
  mov    %edx,%ebx
  mov    %eax,%ebp
  mov    %cl,-0x1(%rsi,%rax,1)
  mov    0x10(%rsp),%rsi
  add    $0x1,%rax
  movzbl (%rsi,%rdx,1),%ecx
  sub    $0x1,%rdx
  cmp    $0x28,%cl
  jne    L62
L68:
  sub    $0x1,%ebx
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L77:
  test   %ebx,%ebx
  jle    L56
  mov    0x8(%rsp),%rsi
  movslq %ebx,%rax
  movslq %ebp,%rcx
  lea    0x30(%rsp,%rax,1),%rdx
  lea    (%rsi,%rcx,1),%rax
  lea    0x1(%rsi,%rcx,1),%rsi
  lea    -0x1(%rbx),%ecx
  mov    %rcx,%rbx
  add    %rcx,%rsi
  xchg   %ax,%ax
L67:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L67
  lea    0x1(%rbp,%rbx,1),%ebp
L56:
  mov    0x8(%rsp),%rax
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void postfix(char in[], char p[]) {
  int i, j = 0, top = 0;
  char x, S[40];
  S[0] = '$';
  for (i = 0; i < strlen(in); i++) {
    x = in[i];
    if (isalnum(x))
      p[j++] = x;
    else if (x == ')') {
      while (S[top] != '(')
        p[j++] = S[top--];
      top--;
    } else {
      while (ISP(S[top]) >= ICP(x))
        p[j++] = S[top--];
      S[++top] = x;
    }
  }
  while (top > 0)
    p[j++] = S[top--];
  p[j] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L5
L19:
  addl   $0x1,-0x34(%rbp)
  addl   $0x1,-0x38(%rbp)
L5:
  mov    -0x38(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L19
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: tamanho de (%s) = %d

assistant: ```c
int main() {
  char string[30];
  int i = 0, cont = 0;
  gets(string);
  while (string[i] != '\0') {
    cont++;
    i++;
  }
  printf("tamanho de (%s) = %d", string, cont);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L3
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
L6:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,(%rcx,%rax,1)
  jne    L6
L35:
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L3:
  mov    $0x0,%edx
  jmp    L35
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: tamanho de (%s) = %d

assistant: ```c
int main() {
  char string[30];
  int i = 0, cont = 0;
  gets(string);
  while (string[i] != '\0') {
    cont++;
    i++;
  }
  printf("tamanho de (%s) = %d", string, cont);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L15
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  nopl   0x0(%rax)
L21:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,(%rcx,%rax,1)
  jne    L21
L25:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  xor    %edx,%edx
  jmp    L25
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: tamanho de (%s) = %d

assistant: ```c
int main() {
  char string[30];
  int i = 0, cont = 0;
  gets(string);
  while (string[i] != '\0') {
    cont++;
    i++;
  }
  printf("tamanho de (%s) = %d", string, cont);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L21
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  nopl   0x0(%rax)
L32:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,(%rcx,%rax,1)
  jne    L32
L11:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L21:
  xor    %edx,%edx
  jmp    L11
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: tamanho de (%s) = %d

assistant: ```c
int main() {
  char string[30];
  int i = 0, cont = 0;
  gets(string);
  while (string[i] != '\0') {
    cont++;
    i++;
  }
  printf("tamanho de (%s) = %d", string, cont);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clear_bits_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t clear_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint64_t mask = ~(((uint64_t)1 << (bit1 + 1)) - 1);
  mask |= ((uint64_t)1 << bit0) - 1;
  return data & mask;
}
```
user: What is the c source code of the assembly code below:

```asm
<clear_bits_uint64>:
  endbr64
  mov    %edi,%r8d
  lea    0x1(%rdx),%ecx
  mov    $0x1,%edi
  mov    %edi,%edx
  shl    %cl,%edx
  neg    %edx
  mov    %esi,%ecx
  shl    %cl,%edi
  lea    -0x1(%rdi),%eax
  or     %edx,%eax
  and    %r8d,%eax
  ret
```

assistant: ```c
uint64_t clear_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint64_t mask = ~(((uint64_t)1 << (bit1 + 1)) - 1);
  mask |= ((uint64_t)1 << bit0) - 1;
  return data & mask;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear_bits_uint64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x1,%edi
  lea    0x1(%rdx),%ecx
  mov    %edi,%edx
  shl    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%edi
  neg    %edx
  lea    -0x1(%rdi),%eax
  or     %edx,%eax
  and    %r8d,%eax
  ret
```

assistant: ```c
uint64_t clear_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint64_t mask = ~(((uint64_t)1 << (bit1 + 1)) - 1);
  mask |= ((uint64_t)1 << bit0) - 1;
  return data & mask;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clear_bits_uint64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x1,%edi
  lea    0x1(%rdx),%ecx
  mov    %edi,%edx
  shl    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%edi
  neg    %edx
  lea    -0x1(%rdi),%eax
  or     %edx,%eax
  and    %r8d,%eax
  ret
```

assistant: ```c
uint64_t clear_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint64_t mask = ~(((uint64_t)1 << (bit1 + 1)) - 1);
  mask |= ((uint64_t)1 << bit0) - 1;
  return data & mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L18
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  jmp    L3
L11:
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  cmpl   $0x0,-0xc(%rbp)
  jne    L49
  mov    -0x8(%rbp),%rax
  jmp    L3
L49:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strchr(char const *s, int c) {
  while (*s) {
    if (*s == c)
      return ((char *)s);
    s++;
  }
  if (c == '\0')
    return ((char *)s);
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
L10:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L29
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
L0:
  test   %esi,%esi
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L29:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(char const *s, int c) {
  while (*s) {
    if (*s == c)
      return ((char *)s);
    s++;
  }
  if (c == '\0')
    return ((char *)s);
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strchr>:
  endbr64
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L16:
  cmp    %esi,%edx
  je     L17
  add    $0x1,%rdi
L4:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L16
  xor    %eax,%eax
  test   %esi,%esi
  cmove  %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(char const *s, int c) {
  while (*s) {
    if (*s == c)
      return ((char *)s);
    s++;
  }
  if (c == '\0')
    return ((char *)s);
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strchr>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L21:
  cmp    %esi,%edx
  je     L17
  add    $0x1,%rdi
L12:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L21
  xor    %eax,%eax
  test   %esi,%esi
  cmove  %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(char const *s, int c) {
  while (*s) {
    if (*s == c)
      return ((char *)s);
    s++;
  }
  if (c == '\0')
    return ((char *)s);
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_persistent_storage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <get_storage_path@plt>
  mov    -0x818(%rbp),%rcx
  lea    -0x810(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmp    $0x3ff,%eax
  jle    L1
  movb   $0x0,-0x11(%rbp)
L1:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: %s_%s

assistant: ```c
void remove_persistent_storage(const char *tag) {
  char buf[1024];
  char path[1024];
  get_storage_path(buf);
  if (snprintf(path, 1024, "%s_%s", buf, tag) >= 1024)
    path[1024 - 1] = '\0';
  unlink(path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_persistent_storage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <get_storage_path@plt>
  lea    0x400(%rsp),%rdi
  mov    %rbx,%r8
  mov    %rbp,%rcx
  lea    D6(%rip),%rdx
  mov    $0x400,%esi
  call   <snprintf@plt>
  cmp    $0x3ff,%eax
  jle    L17
  movb   $0x0,0x7ff(%rsp)
L17:
  lea    0x400(%rsp),%rdi
  call   <unlink@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: %s_%s

assistant: ```c
void remove_persistent_storage(const char *tag) {
  char buf[1024];
  char path[1024];
  get_storage_path(buf);
  if (snprintf(path, 1024, "%s_%s", buf, tag) >= 1024)
    path[1024 - 1] = '\0';
  unlink(path);
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_persistent_storage>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x400(%rsp),%rbp
  mov    %r12,%rdi
  call   <get_storage_path@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x400,%esi
  lea    D3(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    $0x3ff,%eax
  jle    L13
  movb   $0x0,0x7ff(%rsp)
L13:
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %s_%s

assistant: ```c
void remove_persistent_storage(const char *tag) {
  char buf[1024];
  char path[1024];
  get_storage_path(buf);
  if (snprintf(path, 1024, "%s_%s", buf, tag) >= 1024)
    path[1024 - 1] = '\0';
  unlink(path);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<remove_persistent_storage>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x400(%rsp),%rbp
  mov    %r12,%rdi
  call   <get_storage_path@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x400,%esi
  lea    D4(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    $0x3ff,%eax
  jle    L4
  movb   $0x0,0x7ff(%rsp)
L4:
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: %s_%s

assistant: ```c
void remove_persistent_storage(const char *tag) {
  char buf[1024];
  char path[1024];
  get_storage_path(buf);
  if (snprintf(path, 1024, "%s_%s", buf, tag) >= 1024)
    path[1024 - 1] = '\0';
  unlink(path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clock_getres_bogus_id_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <syscall_prepare@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <clock_getres_syscall_wrapper@plt>
  jmp    L2
L6:
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <clock_getres_vdso_wrapper@plt>
L2:
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <record_syscall_result@plt>
  nop
  leave
  ret
```

assistant: ```c
void clock_getres_bogus_id_null(void *arg, struct syscall_result *res) {
  int err;
  syscall_prepare();
  err = arg ? clock_getres_syscall_wrapper((clockid_t)-1, NULL) : clock_getres_vdso_wrapper((clockid_t)-1, NULL);
  record_syscall_result(res, err, errno);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clock_getres_bogus_id_null>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <syscall_prepare@plt>
  test   %rbp,%rbp
  je     L4
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <clock_getres_syscall_wrapper@plt>
  mov    %eax,%esi
L17:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    %rbx,%rdi
  call   <record_syscall_result@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <clock_getres_vdso_wrapper@plt>
  mov    %eax,%esi
  jmp    L17
```

assistant: ```c
void clock_getres_bogus_id_null(void *arg, struct syscall_result *res) {
  int err;
  syscall_prepare();
  err = arg ? clock_getres_syscall_wrapper((clockid_t)-1, NULL) : clock_getres_vdso_wrapper((clockid_t)-1, NULL);
  record_syscall_result(res, err, errno);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clock_getres_bogus_id_null>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <syscall_prepare@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  test   %rbx,%rbx
  je     L11
  call   <clock_getres_syscall_wrapper@plt>
  mov    %eax,%esi
L18:
  mov    D0(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%edx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <record_syscall_result@plt>
  nopl   0x0(%rax)
L11:
  call   <clock_getres_vdso_wrapper@plt>
  mov    %eax,%esi
  jmp    L18
```

assistant: ```c
void clock_getres_bogus_id_null(void *arg, struct syscall_result *res) {
  int err;
  syscall_prepare();
  err = arg ? clock_getres_syscall_wrapper((clockid_t)-1, NULL) : clock_getres_vdso_wrapper((clockid_t)-1, NULL);
  record_syscall_result(res, err, errno);
}
```
user: Translate the below assembly code into C programming language:

```asm
<clock_getres_bogus_id_null>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <syscall_prepare@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  test   %rbx,%rbx
  je     L4
  call   <clock_getres_syscall_wrapper@plt>
  mov    %eax,%esi
L8:
  mov    D5(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%edx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <record_syscall_result@plt>
  nopl   0x0(%rax)
L4:
  call   <clock_getres_vdso_wrapper@plt>
  mov    %eax,%esi
  jmp    L8
```

assistant: ```c
void clock_getres_bogus_id_null(void *arg, struct syscall_result *res) {
  int err;
  syscall_prepare();
  err = arg ? clock_getres_syscall_wrapper((clockid_t)-1, NULL) : clock_getres_vdso_wrapper((clockid_t)-1, NULL);
  record_syscall_result(res, err, errno);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L21
  mov    $0x0,%eax
  jmp    L8
L21:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L22
  mov    $0xffffffff,%eax
  jmp    L8
L22:
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int compare_int(int *x, int *y) {
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return -1;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compare_int>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x0,%eax
  cmp    %edx,%ecx
  je     L2
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L2:
  ret
```

assistant: ```c
int compare_int(int *x, int *y) {
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return -1;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_int>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L6
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L6:
  ret
```

assistant: ```c
int compare_int(int *x, int *y) {
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return -1;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare_int>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L1
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L1:
  ret
```

assistant: ```c
int compare_int(int *x, int *y) {
  if (*x == *y)
    return 0;
  else if (*x < *y)
    return -1;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_cc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    %eax
  and    $0x7,%eax
  cmp    $0x7,%eax
  ja     L14
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x18(%rbp),%eax
  and    $0x800,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x40,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x41,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x80,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
  mov    -0x18(%rbp),%eax
  and    $0x40,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  sete   %dl
  mov    -0x18(%rbp),%eax
  and    $0x800,%eax
  test   %eax,%eax
  sete   %al
  xor    %edx,%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  nop
L14:
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  xor    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_cc(unsigned int condition, unsigned int flags) {
  int rc = 0;
  switch ((condition & 15) >> 1) {
  case 0:
    rc |= (flags & (1 << 11));
    break;
  case 1:
    rc |= (flags & (1 << 0));
    break;
  case 2:
    rc |= (flags & (1 << 6));
    break;
  case 3:
    rc |= (flags & ((1 << 0) | (1 << 6)));
    break;
  case 4:
    rc |= (flags & (1 << 7));
    break;
  case 5:
    rc |= (flags & (1 << 2));
    break;
  case 7:
    rc |= (flags & (1 << 6));
  case 6:
    rc |= (!(flags & (1 << 7)) != !(flags & (1 << 11)));
    break;
  }
  return (!!rc ^ (condition & 1));
}
```