user: 这段汇编代码用C语言表示是什么样的:

```asm
<inverseStrToBCD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movw   $0x0,-0x2(%rbp)
  movzwl -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %ax,%ax
  je     L35
  mov    $0x1,%eax
  jmp    L129
L35:
  movw   $0x0,-0x2(%rbp)
  jmp    L171
L104:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jbe    L213
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  ja     L213
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L157
L213:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jbe    L173
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  ja     L173
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L157
L173:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jbe    L125
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  ja     L125
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x57,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L157
L125:
  mov    $0x0,%edx
L157:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jbe    L10
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  ja     L10
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  jmp    L25
L10:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jbe    L45
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  ja     L45
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x37,%eax
  jmp    L25
L45:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jbe    L155
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  ja     L155
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x57,%eax
  jmp    L25
L155:
  mov    $0x0,%eax
L25:
  mov    %edx,%ecx
  or     %eax,%ecx
  movzwl -0x2(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  addq   $0x2,-0x18(%rbp)
L171:
  movzwl -0x1c(%rbp),%eax
  shr    %ax
  cmp    %ax,-0x2(%rbp)
  jb     L104
  movzwl -0x2(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inverseArray@plt>
  mov    $0x0,%eax
L129:
  leave
  ret
```

assistant: ```c
unsigned char inverseStrToBCD(unsigned char *s, unsigned short sLen, unsigned char *t, unsigned short tLen) {
  unsigned short i = 0;
  if (sLen % 2)
    return 0x01;
  for (i = 0; i < sLen / 2; i++, s += 2) {
    t[i] = (((s[0] >= '0' && s[0] <= '9') ? (s[0] - '0') : ((s[0] >= 'A' && s[0] <= 'F') ? (s[0] - 'A' + 10) : ((s[0] >= 'a' && s[0] <= 'f') ? (s[0] - 'a' + 10) : 0))) << 4 | ((s[1] >= '0' && s[1] <= '9') ? (s[1] - '0') : ((s[1] >= 'A' && s[1] <= 'F') ? (s[1] - 'A' + 10) : ((s[1] >= 'a' && s[1] <= 'f') ? (s[1] - 'a' + 10) : 0))));
  }
  inverseArray(t, i);
  return 0x00;
}
```