ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  mov    $0x37a,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D11
type: string

tool: D18: %d

tool: D11: %d


assistant: ```c
main() {
  int x;
  x = printf("%d\n", x = printf("%d", 890));
  printf("%d", x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L0
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x4(%rbp)
L0:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 10;
  int c = 0;
  if (a != 0)
    c = b / a;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 10;
  int c = 0;
  if (a != 0)
    c = b / a;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 10;
  int c = 0;
  if (a != 0)
    c = b / a;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  int b = 10;
  int c = 0;
  if (a != 0)
    c = b / a;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_swap(void **a, void **b) {
  void *s;
  s = *a;
  *a = *b;
  *b = s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_swap(void **a, void **b) {
  void *s;
  s = *a;
  *a = *b;
  *b = s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_swap(void **a, void **b) {
  void *s;
  s = *a;
  *a = *b;
  *b = s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void ft_swap(void **a, void **b) {
  void *s;
  s = *a;
  *a = *b;
  *b = s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  jmp    L9
L14:
  mov    $0xffffffff,%eax
L9:
  leave
  ret
```

assistant: ```c
int fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115>:
  endbr64
  sub    $0x8,%rsp
  call   <fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115>:
  endbr64
  jmp    1050 <fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115@plt>
```

assistant: ```c
int fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115>:
  endbr64
  jmp    1050 <fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115@plt>
```

assistant: ```c
int fn_al_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_105_ch_115_ch_106_ch_111_ch_105_ch_110_ch_116_ch_79_ch_98_ch_106_ch_101_ch_99_ch_116_ch_80_ch_114_ch_111_ch_112_ch_101_ch_114_ch_116_ch_105_ch_101_ch_115(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printDij>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: %d -> %d : %d


assistant: ```c
void printDij(int parent[], int key[], int graph[10][10], int V) {
  int i = 0;
  for (i = 1; i < V; i++) {
    printf("%d -> %d : %d\n", parent[i], i, graph[i][parent[i]]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printDij>:
  endbr64
  cmp    $0x1,%ecx
  jle    L18
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  lea    0x28(%rdx),%rbp
  mov    %ecx,%r12d
  mov    $0x1,%ebx
  lea    D0(%rip),%r14
L8:
  mov    0x0(%r13,%rbx,4),%esi
  movslq %esi,%rax
  mov    0x0(%rbp,%rax,4),%ecx
  mov    %ebx,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x28,%rbp
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string

tool: D0: %d -> %d : %d


assistant: ```c
void printDij(int parent[], int key[], int graph[10][10], int V) {
  int i = 0;
  for (i = 1; i < V; i++) {
    printf("%d -> %d : %d\n", parent[i], i, graph[i][parent[i]]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printDij>:
  endbr64
  cmp    $0x1,%ecx
  jle    L9
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  lea    0x28(%rdx),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  movslq (%r14,%rbx,4),%rax
  mov    %ebx,%edx
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    0x0(%rbp,%rax,4),%ecx
  mov    %rax,%rsi
  add    $0x28,%rbp
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d -> %d : %d


assistant: ```c
void printDij(int parent[], int key[], int graph[10][10], int V) {
  int i = 0;
  for (i = 1; i < V; i++) {
    printf("%d -> %d : %d\n", parent[i], i, graph[i][parent[i]]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printDij>:
  endbr64
  cmp    $0x1,%ecx
  jle    L15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  lea    0x28(%rdx),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  movslq (%r14,%rbx,4),%rax
  mov    %ebx,%edx
  mov    %r13,%rdi
  add    $0x1,%rbx
  mov    0x0(%rbp,%rax,4),%ecx
  mov    %rax,%rsi
  add    $0x28,%rbp
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string

tool: D6: %d -> %d : %d


assistant: ```c
void printDij(int parent[], int key[], int graph[10][10], int V) {
  int i = 0;
  for (i = 1; i < V; i++) {
    printf("%d -> %d : %d\n", parent[i], i, graph[i][parent[i]]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unpack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x214e554630315343,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <cgc_strlen@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L24
L6:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  cltq
  movzbl -0x11(%rbp,%rax,1),%eax
  xor    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L6
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void unpack(unsigned char *fn_bytes, size_t num_bytes) {
  char unpack_key[] = "CS10FUN!";
  int i = 0;
  int keylen = cgc_strlen(unpack_key);
  for (i = 0; i < num_bytes; i++)
    fn_bytes[i] ^= unpack_key[i % keylen];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unpack>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x214e554630315343,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xf(%rsp),%rdi
  call   <cgc_strlen@plt>
  test   %rbp,%rbp
  je     L23
  mov    %eax,%esi
  mov    $0x0,%ecx
L7:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  movzbl 0xf(%rsp,%rdx,1),%eax
  xor    %al,(%rbx,%rcx,1)
  add    $0x1,%rcx
  cmp    %rbp,%rcx
  jne    L7
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack(unsigned char *fn_bytes, size_t num_bytes) {
  char unpack_key[] = "CS10FUN!";
  int i = 0;
  int keylen = cgc_strlen(unpack_key);
  for (i = 0; i < num_bytes; i++)
    fn_bytes[i] ^= unpack_key[i % keylen];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unpack>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x214e554630315343,%rax
  lea    0xf(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <cgc_strlen@plt>
  test   %rbp,%rbp
  je     L6
  mov    %eax,%edi
  xor    %ecx,%ecx
  nopl   (%rax)
L25:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  movslq %edx,%rdx
  movzbl 0xf(%rsp,%rdx,1),%eax
  xor    %al,(%rbx,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L25
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack(unsigned char *fn_bytes, size_t num_bytes) {
  char unpack_key[] = "CS10FUN!";
  int i = 0;
  int keylen = cgc_strlen(unpack_key);
  for (i = 0; i < num_bytes; i++)
    fn_bytes[i] ^= unpack_key[i % keylen];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unpack>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x214e554630315343,%rax
  lea    0xf(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <cgc_strlen@plt>
  test   %rbp,%rbp
  je     L7
  mov    %eax,%edi
  xor    %ecx,%ecx
  nopl   (%rax)
L20:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  movslq %edx,%rdx
  movzbl 0xf(%rsp,%rdx,1),%eax
  xor    %al,(%rbx,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L20
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack(unsigned char *fn_bytes, size_t num_bytes) {
  char unpack_key[] = "CS10FUN!";
  int i = 0;
  int keylen = cgc_strlen(unpack_key);
  for (i = 0; i < num_bytes; i++)
    fn_bytes[i] ^= unpack_key[i % keylen];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<path_11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L89
L52:
  cmpl   $0x0,-0x14(%rbp)
  jne    L34
  subl   $0x1,-0x10(%rbp)
  jmp    L41
L34:
  cmpl   $0x0,-0x10(%rbp)
  jne    L55
  subl   $0x1,-0x14(%rbp)
  jmp    L41
L55:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <min3@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L8
  ucomisd -0x8(%rbp),%xmm0
  jne    L8
  subl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
  jmp    L41
L8:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L10
  ucomisd -0x8(%rbp),%xmm0
  jne    L10
  subl   $0x1,-0x10(%rbp)
  jmp    L41
L10:
  subl   $0x1,-0x14(%rbp)
L41:
  addl   $0x1,-0xc(%rbp)
L89:
  cmpl   $0x0,-0x14(%rbp)
  jg     L52
  cmpl   $0x0,-0x10(%rbp)
  jg     L52
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int path_11(double **cost, int n, int m) {
  int i, j, k, z1, z2;
  int *px;
  int *py;
  double min_cost;
  i = n - 1;
  j = m - 1;
  k = 1;
  while ((i > 0) || (j > 0)) {
    if (i == 0) {
      j--;
    } else if (j == 0) {
      i--;
    } else {
      min_cost = min3(cost[i - 1][j], cost[i - 1][j - 1], cost[i][j - 1]);
      if (cost[i - 1][j - 1] == min_cost) {
        i--;
        j--;
      } else if (cost[i][j - 1] == min_cost) {
        j--;
      } else {
        i--;
      }
    }
    k++;
  }
  return k;
}
```
user: What is the c source code of the assembly code below:

```asm
<path_11>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    -0x1(%rsi),%ebx
  lea    -0x1(%rdx),%ebp
  test   %ebx,%ebx
  jg     L70
  test   %ebp,%ebp
  jle    L49
L70:
  mov    $0x1,%r12d
L110:
  test   %ebx,%ebx
  jne    L94
  sub    $0x1,%ebp
L73:
  add    $0x1,%r12d
  test   %ebx,%ebx
  jg     L110
  test   %ebp,%ebp
  jg     L110
L30:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  test   %ebp,%ebp
  jne    L6
  sub    $0x1,%ebx
  jmp    L73
L6:
  movslq %ebx,%rax
  shl    $0x3,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,1),%r15
  movslq %ebp,%rdx
  lea    0x0(,%rdx,8),%r13
  lea    -0x8(%rcx,%rax,1),%r14
  mov    (%r14),%rax
  mov    (%r15),%rcx
  movsd  (%rax,%rdx,8),%xmm0
  movsd  -0x8(%rcx,%r13,1),%xmm2
  movsd  -0x8(%rax,%r13,1),%xmm1
  call   <min3@plt>
  mov    (%r14),%rax
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L145
  jne    L145
  sub    $0x1,%ebx
  sub    $0x1,%ebp
  jmp    L73
L145:
  mov    (%r15),%rax
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L139
  jne    L139
  sub    $0x1,%ebp
  jmp    L73
L139:
  sub    $0x1,%ebx
  jmp    L73
L49:
  mov    $0x1,%r12d
  jmp    L30
```

assistant: ```c
int path_11(double **cost, int n, int m) {
  int i, j, k, z1, z2;
  int *px;
  int *py;
  double min_cost;
  i = n - 1;
  j = m - 1;
  k = 1;
  while ((i > 0) || (j > 0)) {
    if (i == 0) {
      j--;
    } else if (j == 0) {
      i--;
    } else {
      min_cost = min3(cost[i - 1][j], cost[i - 1][j - 1], cost[i][j - 1]);
      if (cost[i - 1][j - 1] == min_cost) {
        i--;
        j--;
      } else if (cost[i][j - 1] == min_cost) {
        j--;
      } else {
        i--;
      }
    }
    k++;
  }
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<path_11>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  sub    $0x18,%rsp
  test   %ebx,%ebx
  jg     L81
  test   %ebp,%ebp
  jg     L81
L120:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  setg   %al
L45:
  add    $0x1,%r12d
  test   %al,%al
  je     L120
L81:
  test   %ebp,%ebp
  je     L75
  test   %ebx,%ebx
  jne    L27
  sub    $0x1,%ebp
  test   %ebp,%ebp
  setg   %al
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L27:
  movslq %ebp,%rax
  movslq %ebx,%rdx
  shl    $0x3,%rax
  lea    0x0(,%rdx,8),%r13
  lea    (%r14,%rax,1),%rcx
  lea    -0x8(%r14,%rax,1),%r15
  mov    (%r15),%rax
  mov    (%rcx),%rsi
  mov    %rcx,0x8(%rsp)
  movsd  (%rax,%rdx,8),%xmm0
  movsd  -0x8(%rax,%r13,1),%xmm1
  movsd  -0x8(%rsi,%r13,1),%xmm2
  call   <min3@plt>
  mov    (%r15),%rax
  mov    0x8(%rsp),%rcx
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L17
  jne    L17
  sub    $0x1,%ebp
  sub    $0x1,%ebx
L125:
  test   %ebp,%ebp
  setg   %al
  test   %ebx,%ebx
  setg   %dl
  or     %edx,%eax
  jmp    L45
L17:
  mov    (%rcx),%rax
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L59
  jne    L59
  sub    $0x1,%ebx
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L59:
  sub    $0x1,%ebp
  jmp    L125
```

assistant: ```c
int path_11(double **cost, int n, int m) {
  int i, j, k, z1, z2;
  int *px;
  int *py;
  double min_cost;
  i = n - 1;
  j = m - 1;
  k = 1;
  while ((i > 0) || (j > 0)) {
    if (i == 0) {
      j--;
    } else if (j == 0) {
      i--;
    } else {
      min_cost = min3(cost[i - 1][j], cost[i - 1][j - 1], cost[i][j - 1]);
      if (cost[i - 1][j - 1] == min_cost) {
        i--;
        j--;
      } else if (cost[i][j - 1] == min_cost) {
        j--;
      } else {
        i--;
      }
    }
    k++;
  }
  return k;
}
```
user: What is the c source code of the assembly code below?

```asm
<path_11>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  sub    $0x18,%rsp
  test   %ebx,%ebx
  jg     L81
  test   %ebp,%ebp
  jg     L81
L87:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L120:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  setg   %al
L99:
  add    $0x1,%r12d
  test   %al,%al
  je     L87
L81:
  test   %ebp,%ebp
  je     L120
  test   %ebx,%ebx
  jne    L52
  sub    $0x1,%ebp
  test   %ebp,%ebp
  setg   %al
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L52:
  movslq %ebp,%rax
  movslq %ebx,%rdx
  shl    $0x3,%rax
  lea    0x0(,%rdx,8),%r13
  lea    (%r14,%rax,1),%rcx
  lea    -0x8(%r14,%rax,1),%r15
  mov    (%r15),%rax
  mov    (%rcx),%rsi
  mov    %rcx,0x8(%rsp)
  movsd  (%rax,%rdx,8),%xmm0
  movsd  -0x8(%rax,%r13,1),%xmm1
  movsd  -0x8(%rsi,%r13,1),%xmm2
  call   <min3@plt>
  mov    (%r15),%rax
  mov    0x8(%rsp),%rcx
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L35
  jne    L35
  sub    $0x1,%ebp
  sub    $0x1,%ebx
L20:
  test   %ebp,%ebp
  setg   %al
  test   %ebx,%ebx
  setg   %dl
  or     %edx,%eax
  jmp    L99
L35:
  mov    (%rcx),%rax
  ucomisd -0x8(%rax,%r13,1),%xmm0
  jp     L118
  jne    L118
  sub    $0x1,%ebx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L118:
  sub    $0x1,%ebp
  jmp    L20
```

assistant: ```c
int path_11(double **cost, int n, int m) {
  int i, j, k, z1, z2;
  int *px;
  int *py;
  double min_cost;
  i = n - 1;
  j = m - 1;
  k = 1;
  while ((i > 0) || (j > 0)) {
    if (i == 0) {
      j--;
    } else if (j == 0) {
      i--;
    } else {
      min_cost = min3(cost[i - 1][j], cost[i - 1][j - 1], cost[i][j - 1]);
      if (cost[i - 1][j - 1] == min_cost) {
        i--;
        j--;
      } else if (cost[i][j - 1] == min_cost) {
        j--;
      } else {
        i--;
      }
    }
    k++;
  }
  return k;
}
```