user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L147
L138:
  movl   $0x0,-0x2c(%rbp)
  jmp    L20
L21:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L21
  movl   $0x0,-0x28(%rbp)
  jmp    L28
L57:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L28:
  mov    -0x28(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L57
  movl   $0x0,-0x24(%rbp)
  jmp    L41
L73:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L41:
  mov    -0x24(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L73
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x3c(%rbp)
  subl   $0x1,-0x38(%rbp)
  addl   $0x2,-0x34(%rbp)
  addl   $0x1,-0x30(%rbp)
L147:
  mov    -0x30(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L138
  movl   $0x1,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  sub    $0x3,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L101
L0:
  movl   $0x0,-0x10(%rbp)
  jmp    L159
L141:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L159:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L141
  movl   $0x0,-0xc(%rbp)
  jmp    L89
L123:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L89:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L123
  movl   $0x0,-0x8(%rbp)
  jmp    L102
L93:
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L102:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L93
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x2,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L101:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D74
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D43
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string

tool: D74: -

tool: D43: *

tool: D37: 


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  n = atoi(argv[1]);
  int bir = n - 1;
  int iki = n - 1;
  int uc = 1;
  for (int k = 0; k < n; k++) {
    for (int i = 0; i < bir; i++) {
      printf("-");
    }
    for (int l = 0; l < uc; l++) {
      printf("*");
    }
    for (int j = 0; j < iki; j++) {
      printf("-");
    }
    printf("\n");
    bir -= 1;
    iki -= 1;
    uc += 2;
  }
  int birb = 1;
  int ikib = 1;
  int ucb = (n * 2) - 3;
  for (int m = 0; m < n; m++) {
    for (int i = 0; i < birb; i++) {
      printf("-");
    }
    for (int l = 0; l < ucb; l++) {
      printf("*");
    }
    for (int j = 0; j < ikib; j++) {
      printf("-");
    }
    printf("\n");
    birb += 1;
    ikib += 1;
    ucb -= 2;
  }
  return 0;
}
```