ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x231d,-0x8(%rbp)
  movl   $0xbf89ba38,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
L2:
  movl   $0xb7000060,-0x4(%rbp)
  jmp    L27
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <browser@plt>
  addl   $0x1000,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    $0xb7fff060,%eax
  jbe    L4
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port = 8989, addr = 0xbf89ba38;
  if (argc > 1)
    port = atoi(argv[1]);
  for (addr = 0xb7000060; addr <= 0xb7fff060; addr = addr + 0x00001000)
    browser(port, addr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x231d,%ebp
  cmp    $0x1,%edi
  jg     L14
L20:
  mov    $0xb7000060,%ebx
L12:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <browser@plt>
  add    $0x1000,%ebx
  cmp    $0xb8000060,%ebx
  jne    L12
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L20
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port = 8989, addr = 0xbf89ba38;
  if (argc > 1)
    port = atoi(argv[1]);
  for (addr = 0xb7000060; addr <= 0xb7fff060; addr = addr + 0x00001000)
    browser(port, addr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x231d,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L19
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L19:
  mov    $0xb7000060,%ebx
  nopl   0x0(%rax)
L7:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1000,%ebx
  call   <browser@plt>
  cmp    $0xb8000060,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port = 8989, addr = 0xbf89ba38;
  if (argc > 1)
    port = atoi(argv[1]);
  for (addr = 0xb7000060; addr <= 0xb7fff060; addr = addr + 0x00001000)
    browser(port, addr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x231d,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L16
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L16:
  mov    $0xb7000060,%ebx
  nopl   0x0(%rax)
L5:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1000,%ebx
  call   <browser@plt>
  cmp    $0xb8000060,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port = 8989, addr = 0xbf89ba38;
  if (argc > 1)
    port = atoi(argv[1]);
  for (addr = 0xb7000060; addr <= 0xb7fff060; addr = addr + 0x00001000)
    browser(port, addr);
}
```
user: What is the c source code of the assembly code below:

```asm
<szl_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L23
L17:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  jne    L24
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L64
L24:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  je     L3
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L59
L18:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L59:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jae    L62
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  jne    L18
L62:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  jmp    L64
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L64:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <szl_ltrim@plt>
L23:
  leave
  ret
```

assistant: ```c
void szl_trim(char *s, char **start, char **end) {
  size_t len;
  if (!s[0]) {
    *start = *end = s;
    return;
  }
  len = 1 + strlen(s + 1);
  if (len == 1)
    *end = &s[1];
  else {
    *end = &s[len - 1];
    if (szl_isspace(**end)) {
      for (--*end; (*end > s) && szl_isspace(**end); --*end)
        ;
      ++*end;
      **end = '\0';
    } else
      *end = &s[len];
  }
  szl_ltrim(s, start);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<szl_trim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  cmpb   $0x0,(%rdi)
  jne    L44
  mov    %rdi,0x0(%rbp)
  mov    %rdi,(%r12)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  lea    0x1(%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  movslq %eax,%r14
  cmp    $0x1,%eax
  jne    L32
  mov    %r13,0x0(%rbp)
L27:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <szl_ltrim@plt>
  jmp    L5
L32:
  lea    -0x1(%rbx,%r14,1),%rax
  mov    %rax,0x0(%rbp)
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  je     L28
  mov    0x0(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,0x0(%rbp)
  cmp    %rbx,%rax
  jbe    L81
L52:
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  je     L81
  mov    0x0(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,0x0(%rbp)
  cmp    %rbx,%rax
  ja     L52
L81:
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  movb   $0x0,0x1(%rax)
  jmp    L27
L28:
  add    %rbx,%r14
  mov    %r14,0x0(%rbp)
  jmp    L27
```

assistant: ```c
void szl_trim(char *s, char **start, char **end) {
  size_t len;
  if (!s[0]) {
    *start = *end = s;
    return;
  }
  len = 1 + strlen(s + 1);
  if (len == 1)
    *end = &s[1];
  else {
    *end = &s[len - 1];
    if (szl_isspace(**end)) {
      for (--*end; (*end > s) && szl_isspace(**end); --*end)
        ;
      ++*end;
      **end = '\0';
    } else
      *end = &s[len];
  }
  szl_ltrim(s, start);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<szl_trim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  mov    %rdx,%rbx
  jne    L77
  mov    %rdi,(%rbx)
  pop    %rbx
  mov    %rdi,(%r12)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L77:
  lea    0x1(%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  movslq %eax,%r14
  cmp    $0x1,%eax
  jne    L76
  mov    %r13,(%rbx)
L75:
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <szl_ltrim@plt>
  nopl   (%rax)
L76:
  lea    -0x1(%rbp,%r14,1),%rax
  mov    %rax,(%rbx)
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  jne    L36
  add    %rbp,%r14
  mov    %r14,(%rbx)
  jmp    L75
  nopl   (%rax)
L17:
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  je     L56
L36:
  mov    (%rbx),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,(%rbx)
  cmp    %rbp,%rax
  ja     L17
L70:
  mov    %rdx,(%rbx)
  movb   $0x0,0x1(%rax)
  jmp    L75
  nopl   (%rax)
L56:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  jmp    L70
```

assistant: ```c
void szl_trim(char *s, char **start, char **end) {
  size_t len;
  if (!s[0]) {
    *start = *end = s;
    return;
  }
  len = 1 + strlen(s + 1);
  if (len == 1)
    *end = &s[1];
  else {
    *end = &s[len - 1];
    if (szl_isspace(**end)) {
      for (--*end; (*end > s) && szl_isspace(**end); --*end)
        ;
      ++*end;
      **end = '\0';
    } else
      *end = &s[len];
  }
  szl_ltrim(s, start);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<szl_trim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  mov    %rdx,%rbx
  jne    L71
  mov    %rdi,(%rbx)
  pop    %rbx
  mov    %rdi,(%r12)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  lea    0x1(%rdi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  movslq %eax,%r14
  cmp    $0x1,%eax
  jne    L30
  mov    %r13,(%rbx)
L53:
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <szl_ltrim@plt>
  nopl   (%rax)
L30:
  lea    -0x1(%rbp,%r14,1),%rax
  mov    %rax,(%rbx)
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  jne    L49
  add    %rbp,%r14
  mov    %r14,(%rbx)
  jmp    L53
  nopl   (%rax)
L59:
  movsbl (%rax),%edi
  call   <szl_isspace@plt>
  test   %rax,%rax
  je     L28
L49:
  mov    (%rbx),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,(%rbx)
  cmp    %rbp,%rax
  ja     L59
L22:
  mov    %rdx,(%rbx)
  movb   $0x0,0x1(%rax)
  jmp    L53
  nopl   (%rax)
L28:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  jmp    L22
```

assistant: ```c
void szl_trim(char *s, char **start, char **end) {
  size_t len;
  if (!s[0]) {
    *start = *end = s;
    return;
  }
  len = 1 + strlen(s + 1);
  if (len == 1)
    *end = &s[1];
  else {
    *end = &s[len - 1];
    if (szl_isspace(**end)) {
      for (--*end; (*end > s) && szl_isspace(**end); --*end)
        ;
      ++*end;
      **end = '\0';
    } else
      *end = &s[len];
  }
  szl_ltrim(s, start);
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L69
  jmp    L38
L24:
  nop
  addq   $0x1,-0x18(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L3
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L58
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L58
  movl   $0x1,-0xc(%rbp)
  jmp    L58
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L58
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L58
  movl   $0x1,-0xc(%rbp)
  jmp    L58
L69:
  movl   $0x1,-0xc(%rbp)
L58:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int check_name(const char *name, const char *filter, int exact) {
  int nlen, flen;
  int ret = 0;
  if (filter != NULL) {
    for (; isspace(*name); name++)
      continue;
    do {
    } while (0);
    nlen = strlen(name);
    flen = strlen(filter);
    if (exact) {
      if (nlen == flen && memcmp(name, filter, flen) == 0)
        ret = 1;
    } else {
      if (flen <= nlen && memcmp(name, filter, flen) == 0)
        ret = 1;
    }
  } else {
    ret = 1;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L35
L26:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L64
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  test   %ebx,%ebx
  je     L52
  mov    $0x0,%eax
  cmp    %edx,%r13d
  je     L14
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  add    $0x1,%rbp
  jmp    L26
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L35
L52:
  mov    %ebx,%eax
  cmp    %edx,%r13d
  jl     L35
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L35
```

assistant: ```c
int check_name(const char *name, const char *filter, int exact) {
  int nlen, flen;
  int ret = 0;
  if (filter != NULL) {
    for (; isspace(*name); name++)
      continue;
    do {
    } while (0);
    nlen = strlen(name);
    flen = strlen(filter);
    if (exact) {
      if (nlen == flen && memcmp(name, filter, flen) == 0)
        ret = 1;
    } else {
      if (flen <= nlen && memcmp(name, filter, flen) == 0)
        ret = 1;
    }
  } else {
    ret = 1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_name>:
  endbr64
  test   %rsi,%rsi
  je     L28
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
L11:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  jne    L5
  cmp    %edx,%r13d
  jge    L25
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    %edx,%r13d
  jne    L42
  mov    %r13d,%edx
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rbp
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_name(const char *name, const char *filter, int exact) {
  int nlen, flen;
  int ret = 0;
  if (filter != NULL) {
    for (; isspace(*name); name++)
      continue;
    do {
    } while (0);
    nlen = strlen(name);
    flen = strlen(filter);
    if (exact) {
      if (nlen == flen && memcmp(name, filter, flen) == 0)
        ret = 1;
    } else {
      if (flen <= nlen && memcmp(name, filter, flen) == 0)
        ret = 1;
    }
  } else {
    ret = 1;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_name>:
  endbr64
  test   %rsi,%rsi
  je     L14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
L10:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L39
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  jne    L57
  cmp    %edx,%r13d
  jge    L51
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  cmp    %edx,%r13d
  jne    L53
  mov    %r13d,%edx
L51:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rbp
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_name(const char *name, const char *filter, int exact) {
  int nlen, flen;
  int ret = 0;
  if (filter != NULL) {
    for (; isspace(*name); name++)
      continue;
    do {
    } while (0);
    nlen = strlen(name);
    flen = strlen(filter);
    if (exact) {
      if (nlen == flen && memcmp(name, filter, flen) == 0)
        ret = 1;
    } else {
      if (flen <= nlen && memcmp(name, filter, flen) == 0)
        ret = 1;
    }
  } else {
    ret = 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    0xf40537d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0xea65ec2,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0xea65ec2,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0xea65ec2,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (!(state[0UL] > local1)) {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L19:
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  jmp    L14
L13:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strcat(char *dst, char *src) {
  char *dest = dst;
  while (*dst)
    dst++;
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L24
  mov    %rdi,%rdx
L1:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L1
L32:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L49
L38:
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rsi
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L38
L49:
  movb   $0x0,(%rdx)
  ret
L24:
  mov    %rdi,%rdx
  jmp    L32
```

assistant: ```c
char *my_strcat(char *dst, char *src) {
  char *dest = dst;
  while (*dst)
    dst++;
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rdx
  je     L24
  nop
L18:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L18
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L16
L37:
  mov    %cl,(%rdx)
  add    $0x1,%rsi
  add    $0x1,%rdx
L24:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L37
L16:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *my_strcat(char *dst, char *src) {
  char *dest = dst;
  while (*dst)
    dst++;
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rdx
  je     L10
  nop
L12:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L12
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L25
L18:
  mov    %cl,(%rdx)
  add    $0x1,%rsi
  add    $0x1,%rdx
L10:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L18
L25:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *my_strcat(char *dst, char *src) {
  char *dest = dst;
  while (*dst)
    dst++;
  while (*src) {
    *dst = *src;
    dst++;
    src++;
  }
  *dst = '\0';
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L14
L16:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L14:
  cmpq   $0x0,-0x20(%rbp)
  jne    L16
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long gcd(unsigned long num1, unsigned long num2) {
  unsigned long tmp;
  while (num2) {
    tmp = num2;
    num2 = num1 % num2;
    num1 = tmp;
  }
  return num1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L19
L28:
  mov    %rsi,%rcx
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rsi
  mov    %rcx,%rax
  test   %rdx,%rdx
  jne    L28
L16:
  mov    %rcx,%rax
  ret
L19:
  mov    %rdi,%rcx
  jmp    L16
```

assistant: ```c
unsigned long gcd(unsigned long num1, unsigned long num2) {
  unsigned long tmp;
  while (num2) {
    tmp = num2;
    num2 = num1 % num2;
    num1 = tmp;
  }
  return num1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L10
  nop
L2:
  mov    %rdx,%r8
  xor    %edx,%edx
  div    %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L2
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L10:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long gcd(unsigned long num1, unsigned long num2) {
  unsigned long tmp;
  while (num2) {
    tmp = num2;
    num2 = num1 % num2;
    num1 = tmp;
  }
  return num1;
}
```