ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hangul_pair_compose>:
  endbr64
  lea    -0x1161(%rdx),%eax
  xor    %r8d,%r8d
  cmp    $0x61,%eax
  ja     L0
  lea    -0x1100(%rsi),%ecx
  cmp    $0x12,%ecx
  jbe    L8
  lea    -0xac00(%rsi),%r9d
  cmp    $0x2ba3,%r9d
  ja     L0
L8:
  cmp    $0xabff,%esi
  jle    L26
  lea    -0x11a7(%rsi,%rdx,1),%eax
  mov    $0x3,%r8d
  mov    %eax,(%rdi)
L0:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  imul   $0x24c,%ecx,%ecx
  mov    $0x2,%r8d
  imul   $0x1c,%eax,%eax
  lea    0xac00(%rcx,%rax,1),%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hangul_pair_compose(uint32_t *code, uint32_t a, uint32_t b) {
  if (b < 0x1161 || b >= (0x11A7 + 28))
    return 0;
  if ((a < 0x1100 || a >= (0x1100 + 19)) && (a < 0xAC00 || a >= (0xAC00 + 11172)))
    return 0;
  if (a >= 0xAC00) {
    *code = a + (b - 0x11A7);
    return 3;
  } else {
    int li = a - 0x1100;
    int vi = b - 0x1161;
    *code = 0xAC00 + li * (21 * 28) + vi * 28;
    return 2;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hangul_pair_compose>:
  endbr64
  lea    -0x1161(%rdx),%eax
  xor    %r8d,%r8d
  cmp    $0x61,%eax
  ja     L27
  lea    -0x1100(%rsi),%ecx
  cmp    $0x12,%ecx
  jbe    L1
  lea    -0xac00(%rsi),%r9d
  cmp    $0x2ba3,%r9d
  ja     L27
L1:
  cmp    $0xabff,%esi
  jle    L16
  lea    -0x11a7(%rsi,%rdx,1),%eax
  mov    $0x3,%r8d
  mov    %eax,(%rdi)
L27:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  imul   $0x24c,%ecx,%ecx
  mov    $0x2,%r8d
  imul   $0x1c,%eax,%eax
  lea    0xac00(%rcx,%rax,1),%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hangul_pair_compose(uint32_t *code, uint32_t a, uint32_t b) {
  if (b < 0x1161 || b >= (0x11A7 + 28))
    return 0;
  if ((a < 0x1100 || a >= (0x1100 + 19)) && (a < 0xAC00 || a >= (0xAC00 + 11172)))
    return 0;
  if (a >= 0xAC00) {
    *code = a + (b - 0x11A7);
    return 3;
  } else {
    int li = a - 0x1100;
    int vi = b - 0x1161;
    *code = 0xAC00 + li * (21 * 28) + vi * 28;
    return 2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<softboundmpx_rindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_rindex(char *s, int c) {
  char *ret_ptr = rindex(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softboundmpx_rindex>:
  endbr64
  push   %rbx
  call   <rindex@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_rindex(char *s, int c) {
  char *ret_ptr = rindex(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<softboundmpx_rindex>:
  endbr64
  push   %r12
  call   <rindex@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_rindex(char *s, int c) {
  char *ret_ptr = rindex(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softboundmpx_rindex>:
  endbr64
  push   %r12
  call   <rindex@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_rindex(char *s, int c) {
  char *ret_ptr = rindex(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<convert_answer_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strtolower@plt>
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x1,%eax
  jmp    L33
L4:
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x0,%eax
  jmp    L33
L19:
  mov    $0xffffffff,%eax
L33:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string

tool: D18: yes

tool: D19: no

assistant: ```c
int convert_answer_to_int(char *answer) {
  strtolower(answer);
  if (strcmp(answer, "yes") == 0) {
    return 1;
  } else if (strcmp(answer, "no") == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convert_answer_to_int>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strtolower@plt>
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L14
L8:
  pop    %rbx
  ret
L14:
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D16
datatype: string

tool: D5: yes

tool: D16: no

assistant: ```c
int convert_answer_to_int(char *answer) {
  strtolower(answer);
  if (strcmp(answer, "yes") == 0) {
    return 1;
  } else if (strcmp(answer, "no") == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_answer_to_int>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strtolower@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L0
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  lea    D18(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D9: yes

tool: D18: no

assistant: ```c
int convert_answer_to_int(char *answer) {
  strtolower(answer);
  if (strcmp(answer, "yes") == 0) {
    return 1;
  } else if (strcmp(answer, "no") == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_answer_to_int>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strtolower@plt>
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L0
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D14: yes

tool: D4: no

assistant: ```c
int convert_answer_to_int(char *answer) {
  strtolower(answer);
  if (strcmp(answer, "yes") == 0) {
    return 1;
  } else if (strcmp(answer, "no") == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<countOcurrences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L1
  addl   $0x1,-0x4(%rbp)
L1:
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int countOcurrences(char *characters, char character, int quantityN, int quantityM) {
  int i, total = 0;
  for (i = 0; i < quantityN * quantityM; i++) {
    if ((int)characters[i] == (int)character)
      total++;
  }
  return total;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<countOcurrences>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdi
  mov    $0x0,%edx
L18:
  cmp    %sil,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L24:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int countOcurrences(char *characters, char character, int quantityN, int quantityM) {
  int i, total = 0;
  for (i = 0; i < quantityN * quantityM; i++) {
    if ((int)characters[i] == (int)character)
      total++;
  }
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<countOcurrences>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L1:
  xor    %edx,%edx
  cmp    %sil,(%rdi)
  sete   %dl
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L1
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int countOcurrences(char *characters, char character, int quantityN, int quantityM) {
  int i, total = 0;
  for (i = 0; i < quantityN * quantityM; i++) {
    if ((int)characters[i] == (int)character)
      total++;
  }
  return total;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x64,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D2: %s

tool: D15: %X 

assistant: ```c
int main() {
  char *str;
  int i;
  size_t length = 100;
  str = (char *)malloc(length);
  scanf("%s", str);
  printf("%s\n", str);
  for (i = 0; i < strlen(str); i++) {
    printf("%X ", str[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D17(%rip),%r12
  jmp    L15
L3:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D17
type: string

tool: D4: %s

tool: D17: %X 

assistant: ```c
int main() {
  char *str;
  int i;
  size_t length = 100;
  str = (char *)malloc(length);
  scanf("%s", str);
  printf("%s\n", str);
  for (i = 0; i < strlen(str); i++) {
    printf("%X ", str[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L8:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D7: %X 

tool: D2: %s

assistant: ```c
int main() {
  char *str;
  int i;
  size_t length = 100;
  str = (char *)malloc(length);
  scanf("%s", str);
  printf("%s\n", str);
  for (i = 0; i < strlen(str); i++) {
    printf("%X ", str[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L15:
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D11: %X 

tool: D12: %s

assistant: ```c
int main() {
  char *str;
  int i;
  size_t length = 100;
  str = (char *)malloc(length);
  scanf("%s", str);
  printf("%s\n", str);
  for (i = 0; i < strlen(str); i++) {
    printf("%X ", str[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<jambu_aut_ad_partial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8d,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x54(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x54(%rbp),%eax
  movl   $0x80,-0x30(%rbp,%rax,4)
  mov    $0x7,%eax
  sub    -0x54(%rbp),%eax
  mov    %eax,%edx
  mov    -0x54(%rbp),%eax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  lea    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <AESEncrypt@plt>
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  xor    %edx,%eax
  xor    $0x1,%eax
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x50(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  lea    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%ecx
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  add    $0xc,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x48(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x50(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void jambu_aut_ad_partial(const unsigned int *rk, const uint8_t *adblock, unsigned int *stateS, unsigned int *stateR, unsigned int len) {
  uint8_t p[8];
  memcpy(p, adblock, len);
  p[len] = 0x80;
  memset(p + len + 1, 0, 7 - len);
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= ((unsigned int *)p)[0];
  stateS[3] ^= ((unsigned int *)p)[1];
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<jambu_aut_ad_partial>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r8d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r8d,%edx
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%eax
  movl   $0x80,(%rsp,%rax,4)
  mov    $0x7,%edx
  sub    %r12d,%edx
  lea    0x4(%r14,%rax,4),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    (%rsp),%eax
  mov    %eax,0x8(%rbx)
  mov    0x4(%rsp),%edx
  xor    %edx,0xc(%rbx)
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void jambu_aut_ad_partial(const unsigned int *rk, const uint8_t *adblock, unsigned int *stateS, unsigned int *stateR, unsigned int len) {
  uint8_t p[8];
  memcpy(p, adblock, len);
  p[len] = 0x80;
  memset(p + len + 1, 0, 7 - len);
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= ((unsigned int *)p)[0];
  stateS[3] ^= ((unsigned int *)p)[1];
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jambu_aut_ad_partial>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %r8d,%edx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%eax
  mov    $0x7,%edx
  xor    %esi,%esi
  sub    %r12d,%edx
  lea    0x4(%r14,%rax,4),%rdi
  movl   $0x80,(%rsp,%rax,4)
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    (%rsp),%rdx
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    %rdx,0x8(%rbx)
  xor    (%rsp),%eax
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void jambu_aut_ad_partial(const unsigned int *rk, const uint8_t *adblock, unsigned int *stateS, unsigned int *stateR, unsigned int len) {
  uint8_t p[8];
  memcpy(p, adblock, len);
  p[len] = 0x80;
  memset(p + len + 1, 0, 7 - len);
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= ((unsigned int *)p)[0];
  stateS[3] ^= ((unsigned int *)p)[1];
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jambu_aut_ad_partial>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %r8d,%edx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%eax
  mov    $0x7,%edx
  xor    %esi,%esi
  sub    %r12d,%edx
  lea    0x4(%r14,%rax,4),%rdi
  movl   $0x80,(%rsp,%rax,4)
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <AESEncrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  xor    $0x1,%eax
  mov    (%rsp),%rdx
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%eax
  xor    %eax,0x4(%rbx)
  mov    0x8(%rbx),%eax
  xor    %rdx,0x8(%rbx)
  xor    (%rsp),%eax
  xor    %eax,0x0(%rbp)
  mov    0xc(%rbx),%eax
  xor    %eax,0x4(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void jambu_aut_ad_partial(const unsigned int *rk, const uint8_t *adblock, unsigned int *stateS, unsigned int *stateR, unsigned int len) {
  uint8_t p[8];
  memcpy(p, adblock, len);
  p[len] = 0x80;
  memset(p + len + 1, 0, 7 - len);
  AESEncrypt(rk, stateS);
  stateS[0] ^= stateR[0] ^ 0x01;
  stateS[1] ^= stateR[1];
  stateS[2] ^= ((unsigned int *)p)[0];
  stateS[3] ^= ((unsigned int *)p)[1];
  stateR[0] ^= stateS[2];
  stateR[1] ^= stateS[3];
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IPCLiteMtoCFunctionCall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    $0x400fb710,%eax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  or     -0x30(%rbp),%rax
  and    %rdx,%rax
  test   %rax,%rax
  je     L2
  movw   $0x1,-0x2(%rbp)
  jmp    L8
L2:
  mov    $0x400fb730,%eax
  movq   $0x12,(%rax)
  mov    $0x400fb734,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400fb738,%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400fb708,%eax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  or     -0x30(%rbp),%rax
  mov    $0x400fb708,%edx
  or     %rcx,%rax
  mov    %rax,(%rdx)
  movw   $0x0,-0x2(%rbp)
L8:
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short IPCLiteMtoCFunctionCall(unsigned long ulFlag, unsigned long ulAddress, unsigned long ulParam, unsigned long ulStatusFlag) {
  unsigned short returnStatus;
  if ((*((volatile unsigned long *)(0x400FB700 + 0x000000010))) & (ulFlag | ulStatusFlag)) {
    returnStatus = 0x0001;
  } else {
    (*((volatile unsigned long *)(0x400FB700 + 0x000000030))) = 0x00000012;
    (*((volatile unsigned long *)(0x400FB700 + 0x000000034))) = ulAddress;
    (*((volatile unsigned long *)(0x400FB700 + 0x000000038))) = ulParam;
    (*((volatile unsigned long *)(0x400FB700 + 0x000000008))) |= (ulFlag | ulStatusFlag);
    returnStatus = 0x0000;
  }
  return returnStatus;
}
```