ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int32_size>:
  endbr64
  test   %edi,%edi
  js     L7
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L1
  mov    $0x2,%eax
  cmp    $0x3fff,%edi
  jle    L1
  mov    $0x3,%eax
  cmp    $0x1fffff,%edi
  jle    L1
  xor    %eax,%eax
  cmp    $0xfffffff,%edi
  setg   %al
  add    $0x4,%rax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xa,%eax
L1:
  ret
```

assistant: ```c
size_t int32_size(int32_t v) {
  if (v < 0)
    return 10;
  else if (v < (1 << 7))
    return 1;
  else if (v < (1 << 14))
    return 2;
  else if (v < (1 << 21))
    return 3;
  else if (v < (1 << 28))
    return 4;
  else
    return 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int32_size>:
  endbr64
  test   %edi,%edi
  js     L37
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L31
  mov    $0x2,%eax
  cmp    $0x3fff,%edi
  jle    L31
  mov    $0x3,%eax
  cmp    $0x1fffff,%edi
  jle    L31
  xor    %eax,%eax
  cmp    $0xfffffff,%edi
  setg   %al
  add    $0x4,%rax
  ret
  nopl   0x0(%rax)
L37:
  mov    $0xa,%eax
L31:
  ret
```

assistant: ```c
size_t int32_size(int32_t v) {
  if (v < 0)
    return 10;
  else if (v < (1 << 7))
    return 1;
  else if (v < (1 << 14))
    return 2;
  else if (v < (1 << 21))
    return 3;
  else if (v < (1 << 28))
    return 4;
  else
    return 5;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ft_islower@plt>
  test   %rax,%rax
  je     L12
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L8
L12:
  mov    -0x4(%rbp),%eax
L8:
  leave
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (ft_islower(c))
    return (c - 32);
  return (c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_toupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <ft_islower@plt>
  mov    %rax,%rdx
  lea    -0x20(%rbx),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (ft_islower(c))
    return (c - 32);
  return (c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <ft_islower@plt>
  mov    %rax,%r8
  lea    -0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (ft_islower(c))
    return (c - 32);
  return (c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_toupper>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <ft_islower@plt>
  mov    %rax,%r8
  lea    -0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (ft_islower(c))
    return (c - 32);
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gf8mul_11000010>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm2
  pxor   %xmm7,%xmm6
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm1
  pxor   %xmm6,%xmm5
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm1
  pxor   %xmm1,%xmm0
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gf8mul_11000010(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gf8mul_11000010>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm2
  pxor   %xmm7,%xmm6
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm1
  pxor   %xmm6,%xmm5
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm1
  pxor   %xmm1,%xmm0
  ret
```

assistant: ```c
void gf8mul_11000010(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gf8mul_11000010>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm2
  pxor   %xmm7,%xmm6
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm1
  pxor   %xmm6,%xmm5
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm1
  pxor   %xmm1,%xmm0
  ret
```

assistant: ```c
void gf8mul_11000010(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gf8mul_11000010>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm2
  pxor   %xmm7,%xmm6
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm1
  pxor   %xmm6,%xmm5
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm0
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm1
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm6
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm1,%xmm0
  pxor   %xmm0,%xmm7
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm1
  pxor   %xmm1,%xmm0
  ret
```

assistant: ```c
void gf8mul_11000010(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm1\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm6\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm1, %xmm0\n"
                       "\tpxor    %xmm0, %xmm7\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm1\n"
                       "\tpxor    %xmm1, %xmm0\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_cstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <alloc_mem@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L11
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
char *copy_cstring(const char *str) {
  char *new_string;
  size_t length;
  length = strlen(str);
  new_string = alloc_mem(length + 1);
  if (!new_string) {
    return NULL;
  }
  memcpy(new_string, str, length);
  new_string[length] = '\0';
  return new_string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_cstring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <alloc_mem@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
L0:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_cstring(const char *str) {
  char *new_string;
  size_t length;
  length = strlen(str);
  new_string = alloc_mem(length + 1);
  if (!new_string) {
    return NULL;
  }
  memcpy(new_string, str, length);
  new_string[length] = '\0';
  return new_string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_cstring>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <alloc_mem@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_cstring(const char *str) {
  char *new_string;
  size_t length;
  length = strlen(str);
  new_string = alloc_mem(length + 1);
  if (!new_string) {
    return NULL;
  }
  memcpy(new_string, str, length);
  new_string[length] = '\0';
  return new_string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_cstring>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <alloc_mem@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_cstring(const char *str) {
  char *new_string;
  size_t length;
  length = strlen(str);
  new_string = alloc_mem(length + 1);
  if (!new_string) {
    return NULL;
  }
  memcpy(new_string, str, length);
  new_string[length] = '\0';
  return new_string;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<interchange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L10
L0:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L10:
  mov    -0x28(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void interchange(int init, int order_c, int term, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t, t1;
    t = matrix[i];
    t1 = matrix[j];
    matrix[i] = t;
    matrix[j] = t1;
    matrix[i] = t1;
    matrix[j] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<interchange>:
  endbr64
  sub    $0x1,%edi
  imul   %esi,%edi
  sub    $0x1,%edx
  imul   %esi,%edx
  add    %edx,%esi
  cmp    %esi,%edx
  jge    L14
  movslq %edi,%rdi
  lea    (%rcx,%rdi,8),%rax
  sub    $0x1,%esi
  sub    %edx,%esi
  add    %rdi,%rsi
  lea    0x8(%rcx,%rsi,8),%rcx
  movslq %edx,%rdx
  sub    %rdi,%rdx
L9:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rdx,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L9
L14:
  ret
```

assistant: ```c
void interchange(int init, int order_c, int term, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t, t1;
    t = matrix[i];
    t1 = matrix[j];
    matrix[i] = t;
    matrix[j] = t1;
    matrix[i] = t1;
    matrix[j] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<interchange>:
  endbr64
  sub    $0x1,%edx
  sub    $0x1,%edi
  imul   %esi,%edx
  imul   %esi,%edi
  add    %edx,%esi
  cmp    %esi,%edx
  jge    L4
  sub    $0x1,%esi
  movslq %edi,%rdi
  sub    %edx,%esi
  movslq %edx,%rdx
  lea    (%rcx,%rdi,8),%rax
  add    %rdi,%rsi
  sub    %rdi,%rdx
  lea    0x8(%rcx,%rsi,8),%rcx
L3:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rdx,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L3
L4:
  ret
```

assistant: ```c
void interchange(int init, int order_c, int term, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t, t1;
    t = matrix[i];
    t1 = matrix[j];
    matrix[i] = t;
    matrix[j] = t1;
    matrix[i] = t1;
    matrix[j] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interchange>:
  endbr64
  sub    $0x1,%edx
  lea    -0x1(%rdi),%eax
  imul   %esi,%edx
  imul   %esi,%eax
  lea    (%rsi,%rdx,1),%r11d
  cmp    %r11d,%edx
  jge    L0
  movslq %edx,%r9
  push   %rbp
  mov    %esi,%r8d
  mov    %eax,%r10d
  lea    0x0(,%r9,8),%rsi
  push   %rbx
  movslq %eax,%rbx
  lea    0x0(,%rbx,8),%rdi
  lea    0x10(%rsi),%rax
  lea    0x10(,%rbx,8),%rbp
  cmp    %rdi,%rax
  setle  %al
  cmp    %rbp,%rsi
  setge  %bpl
  or     %bpl,%al
  je     L23
  lea    -0x1(%r8),%eax
  cmp    $0x1,%eax
  jbe    L23
  mov    %r8d,%r9d
  add    %rcx,%rdi
  add    %rcx,%rsi
  xor    %eax,%eax
  shr    %r9d
  shl    $0x4,%r9
  nopl   0x0(%rax)
L20:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm2
  movups %xmm2,(%rdi,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L20
  mov    %r8d,%esi
  and    $0xfffffffe,%esi
  lea    (%r10,%rsi,1),%eax
  add    %esi,%edx
  cmp    %esi,%r8d
  je     L58
  cltq
  lea    (%rcx,%rax,8),%rsi
  movslq %edx,%rax
  lea    (%rcx,%rax,8),%rax
  movsd  (%rsi),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  %xmm0,(%rax)
L58:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  sub    $0x1,%r11d
  lea    (%rcx,%rbx,8),%rax
  sub    %edx,%r11d
  lea    (%r11,%rbx,1),%rdx
  lea    0x8(%rcx,%rdx,8),%rcx
  mov    %r9,%rdx
  sub    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L50:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rdx,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L50
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void interchange(int init, int order_c, int term, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t, t1;
    t = matrix[i];
    t1 = matrix[j];
    matrix[i] = t;
    matrix[j] = t1;
    matrix[i] = t1;
    matrix[j] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nextlongrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl %ax,%eax
  imul   $0x41a7,%rax,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  imul   $0x41a7,%rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  and    $0x7fff0000,%eax
  add    %rax,-0x10(%rbp)
  mov    $0x80000000,%eax
  cmp    %rax,-0x10(%rbp)
  jb     L18
  andq   $0x7fffffff,-0x10(%rbp)
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  shr    $0xf,%rax
  add    %rax,-0x10(%rbp)
  mov    $0x80000000,%eax
  cmp    %rax,-0x10(%rbp)
  jb     L16
  andq   $0x7fffffff,-0x10(%rbp)
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long nextlongrand(long seed) {
  unsigned long lo, hi;
  lo = 16807 * (long)(seed & 0xFFFF);
  hi = 16807 * (long)((unsigned long)seed >> 16);
  lo += (hi & 0x7FFF) << 16;
  if (lo > 2147483647L) {
    lo &= 2147483647L;
    ++lo;
  }
  lo += hi >> 15;
  if (lo > 2147483647L) {
    lo &= 2147483647L;
    ++lo;
  }
  return (long)lo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextlongrand>:
  endbr64
  mov    %rdi,%rax
  movzwl %di,%ecx
  imul   $0x41a7,%rcx,%rcx
  shr    $0x10,%rax
  imul   $0x41a7,%rax,%rax
  mov    %rax,%rdx
  shl    $0x10,%rdx
  and    $0x7fff0000,%edx
  add    %rcx,%rdx
  mov    %rdx,%rcx
  and    $0x7fffffff,%ecx
  add    $0x1,%rcx
  cmp    $0x7fffffff,%rdx
  cmova  %rcx,%rdx
  shr    $0xf,%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0x7fffffff,%edx
  add    $0x1,%rdx
  cmp    $0x7fffffff,%rax
  cmova  %rdx,%rax
  ret
```

assistant: ```c
long nextlongrand(long seed) {
  unsigned long lo, hi;
  lo = 16807 * (long)(seed & 0xFFFF);
  hi = 16807 * (long)((unsigned long)seed >> 16);
  lo += (hi & 0x7FFF) << 16;
  if (lo > 2147483647L) {
    lo &= 2147483647L;
    ++lo;
  }
  lo += hi >> 15;
  if (lo > 2147483647L) {
    lo &= 2147483647L;
    ++lo;
  }
  return (long)lo;
}
```