user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rsi
  lea    D61(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x20(%rsp),%r8
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  cmpq   $0x0,0x20(%rsp)
  je     L8
  lea    D34(%rip),%r12
L55:
  lea    0x18(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  mov    0x18(%rsp),%rax
  movb   $0x1,0x0(%rbp,%rax,1)
  mov    0x20(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,0x20(%rsp)
  jne    L55
L8:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x10(%rsp),%rdi
  add    0x8(%rsp),%rdi
  add    $0x1,%rdi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    0x10(%rsp),%rdx
  lea    (%rax,%rdx,8),%rbx
  movq   $0x1,(%rbx)
  movq   $0x0,0x18(%rsp)
  cmpq   $0x0,0x8(%rsp)
  jle    L66
  mov    $0x0,%esi
  movabs $0x89705f3112a28fe5,%r8
  jmp    L49
L58:
  mov    0x18(%rsp),%rax
  lea    0x1(%rax),%rsi
  mov    %rsi,0x18(%rsp)
  cmp    0x8(%rsp),%rsi
  jge    L66
L49:
  lea    0x0(,%rsi,8),%rdi
  mov    0x20(%rsp),%rcx
  add    (%rbx,%rsi,8),%rcx
  mov    %rsi,%rax
  sub    0x10(%rsp),%rax
  sub    (%rbx,%rax,8),%rcx
  add    $0x3b9aca07,%rcx
  mov    %rcx,%rax
  imul   %r8
  add    %rcx,%rdx
  sar    $0x1d,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,0x20(%rsp)
  cmpb   $0x0,0x1(%rbp,%rsi,1)
  jne    L58
  mov    %rcx,0x8(%rbx,%rdi,1)
  jmp    L58
L66:
  lea    D59(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    0x8(%rsp),%rax
  mov    (%rbx,%rax,8),%rdx
  lea    D60(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D61
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D59
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D60
type_guessed: string

tool: D12: r

tool: D61: quacau.inp

tool: D25: %ld %ld %Ld

tool: D34: %ld

tool: D59: w

tool: D10: quacau.out

tool: D60: %Ld


assistant: ```c
int main() {
  FILE *f = fopen("quacau.inp", "r");
  long n, m, i;
  long long k, *ways;
  char *broken;
  fscanf(f, "%ld %ld %Ld", &n, &m, &k);
  broken = calloc(n + 1, sizeof(char));
  for (; k; k--) {
    fscanf(f, "%ld", &i);
    broken[i] = 1;
  }
  fclose(f);
  ways = (long long *)calloc(n + m + 1, sizeof(long long)) + m;
  *ways = 1;
  for (i = 0; i < n; i++) {
    k = (ways[i] + k - ways[i - m] + 1000000007) % 1000000007;
    if (!broken[i + 1])
      ways[i + 1] = k;
  }
  f = fopen("quacau.out", "w");
  fprintf(f, "%Ld\n", ways[n]);
  fclose(f);
  return 0;
}
```