ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<fgets_with_openclose>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D5(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L16
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fclose@plt>
  test   %r13,%r13
  je     L2
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  pop    %r13
  jmp    1090 <strlen@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
L5:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: r

assistant: ```c
int fgets_with_openclose(char *fname, char *buf, size_t maxlen) {
  FILE *fp;
  char *s;
  if ((fp = fopen(fname, "r")) != NULL) {
    s = fgets(buf, maxlen, fp);
    fclose(fp);
    return (s != NULL) ? strlen(buf) : 0;
  } else {
    return -1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<compal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x40,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x40,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x100,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <comprs@plt>
  nop
  leave
  ret
```

assistant: ```c
compal(mrmcml) int *mrmcml;
{
  char *gridk, *gridl, *igrid;
  char *malloc();
  gridk = malloc(4 * (*mrmcml) + 256);
  gridl = malloc(4 * (*mrmcml) + 256);
  igrid = malloc(*mrmcml + 256);
  comprs(gridk, gridl, igrid);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%eax
  lea    0x100(,%rax,4),%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rbx),%eax
  lea    0x100(,%rax,4),%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,%r12
  mov    (%rbx),%edi
  add    $0x100,%edi
  mov    $0x0,%eax
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <comprs@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
compal(mrmcml) int *mrmcml;
{
  char *gridk, *gridl, *igrid;
  char *malloc();
  gridk = malloc(4 * (*mrmcml) + 256);
  gridl = malloc(4 * (*mrmcml) + 256);
  igrid = malloc(*mrmcml + 256);
  comprs(gridk, gridl, igrid);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%rbx
  lea    0x100(,%rax,4),%edi
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rbx),%eax
  lea    0x100(,%rax,4),%edi
  xor    %eax,%eax
  call   <malloc@plt>
  mov    (%rbx),%edi
  mov    %rax,%r12
  xor    %eax,%eax
  add    $0x100,%edi
  call   <malloc@plt>
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <comprs@plt>
```

assistant: ```c
compal(mrmcml) int *mrmcml;
{
  char *gridk, *gridl, *igrid;
  char *malloc();
  gridk = malloc(4 * (*mrmcml) + 256);
  gridl = malloc(4 * (*mrmcml) + 256);
  igrid = malloc(*mrmcml + 256);
  comprs(gridk, gridl, igrid);
}
```
user: What is the c source code of the assembly code below:

```asm
<compal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%rbx
  lea    0x100(,%rax,4),%edi
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rbx),%eax
  lea    0x100(,%rax,4),%edi
  xor    %eax,%eax
  call   <malloc@plt>
  mov    (%rbx),%edi
  mov    %rax,%r12
  xor    %eax,%eax
  add    $0x100,%edi
  call   <malloc@plt>
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <comprs@plt>
```

assistant: ```c
compal(mrmcml) int *mrmcml;
{
  char *gridk, *gridl, *igrid;
  char *malloc();
  gridk = malloc(4 * (*mrmcml) + 256);
  gridl = malloc(4 * (*mrmcml) + 256);
  igrid = malloc(*mrmcml + 256);
  comprs(gridk, gridl, igrid);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <str2int@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string

tool: D0: 3423lfdslj

tool: D16: %d  %s 


assistant: ```c
int main() {
  const char *p = NULL;
  int n = str2int("3423lfdslj", &p);
  printf("%d  %s \n", n, p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <str2int@plt>
  mov    %eax,%esi
  mov    (%rsp),%rdx
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D16
type_infered: string

tool: D15: 3423lfdslj

tool: D16: %d  %s 


assistant: ```c
int main() {
  const char *p = NULL;
  int n = str2int("3423lfdslj", &p);
  printf("%d  %s \n", n, p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <str2int@plt>
  mov    (%rsp),%rdx
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D1: 3423lfdslj

tool: D13: %d  %s 


assistant: ```c
int main() {
  const char *p = NULL;
  int n = str2int("3423lfdslj", &p);
  printf("%d  %s \n", n, p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <str2int@plt>
  mov    (%rsp),%rdx
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D4: 3423lfdslj

tool: D15: %d  %s 


assistant: ```c
int main() {
  const char *p = NULL;
  int n = str2int("3423lfdslj", &p);
  printf("%d  %s \n", n, p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mainserv_towrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <tcptowrite@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jle    L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mainserv_bytesout@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int32_t mainserv_towrite(int sock, const uint8_t *ptr, uint32_t leng, uint32_t timeout) {
  int32_t r;
  r = tcptowrite(sock, ptr, leng, timeout);
  if (r > 0) {
    mainserv_bytesout(r);
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mainserv_towrite>:
  endbr64
  push   %rbx
  call   <tcptowrite@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jg     L0
L16:
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  mov    %rax,%rdi
  call   <mainserv_bytesout@plt>
  jmp    L16
```

assistant: ```c
int32_t mainserv_towrite(int sock, const uint8_t *ptr, uint32_t leng, uint32_t timeout) {
  int32_t r;
  r = tcptowrite(sock, ptr, leng, timeout);
  if (r > 0) {
    mainserv_bytesout(r);
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mainserv_towrite>:
  endbr64
  push   %r12
  call   <tcptowrite@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jle    L7
  mov    %rax,%rdi
  call   <mainserv_bytesout@plt>
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int32_t mainserv_towrite(int sock, const uint8_t *ptr, uint32_t leng, uint32_t timeout) {
  int32_t r;
  r = tcptowrite(sock, ptr, leng, timeout);
  if (r > 0) {
    mainserv_bytesout(r);
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mainserv_towrite>:
  endbr64
  push   %r12
  call   <tcptowrite@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jle    L4
  mov    %rax,%rdi
  call   <mainserv_bytesout@plt>
L4:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int32_t mainserv_towrite(int sock, const uint8_t *ptr, uint32_t leng, uint32_t timeout) {
  int32_t r;
  r = tcptowrite(sock, ptr, leng, timeout);
  if (r > 0) {
    mainserv_bytesout(r);
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L23
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0xc(%rbp),%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L4
L23:
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string

tool: D24: Digite um inteiro: 

tool: D11: %d

tool: D30: 
Raiz quadrada aproximada de %d: %.2f.


tool: D15: 
Quadrado de %d: %d.


assistant: ```c
void main() {
  int num;
  printf("Digite um inteiro: ");
  scanf("%d", &num);
  if (num % 2 == 0)
    printf("\nRaiz quadrada aproximada de %d: %.2f.\n", num, sqrt(num));
  else
    printf("\nQuadrado de %d: %d.\n", num, num * num);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L15
  mov    %esi,%edi
  call   <sqrt@plt>
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
L15:
  mov    %esi,%edx
  imul   %esi,%edx
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D34
type_guessed: string
name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D39
type_guessed: string

tool: D34: Digite um inteiro: 

tool: D33: %d

tool: D11: 
Raiz quadrada aproximada de %d: %.2f.


tool: D39: 
Quadrado de %d: %d.


assistant: ```c
void main() {
  int num;
  printf("Digite um inteiro: ");
  scanf("%d", &num);
  if (num % 2 == 0)
    printf("\nRaiz quadrada aproximada de %d: %.2f.\n", num, sqrt(num));
  else
    printf("\nQuadrado de %d: %d.\n", num, num * num);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L10
  mov    %esi,%edi
  call   <sqrt@plt>
  mov    0x4(%rsp),%esi
  mov    $0x1,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  ret
L10:
  mov    %esi,%edx
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  imul   %esi,%edx
  call   <printf@plt>
  jmp    L22
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D35
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D39
type: string

tool: D15: Digite um inteiro: 

tool: D35: %d

tool: D3: 
Raiz quadrada aproximada de %d: %.2f.


tool: D39: 
Quadrado de %d: %d.


assistant: ```c
void main() {
  int num;
  printf("Digite um inteiro: ");
  scanf("%d", &num);
  if (num % 2 == 0)
    printf("\nRaiz quadrada aproximada de %d: %.2f.\n", num, sqrt(num));
  else
    printf("\nQuadrado de %d: %d.\n", num, num * num);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L11
  mov    %esi,%edi
  call   <sqrt@plt>
  mov    0x4(%rsp),%esi
  mov    $0x1,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L11:
  mov    %esi,%edx
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  imul   %esi,%edx
  call   <printf@plt>
  jmp    L23
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D9
type: string

tool: D18: Digite um inteiro: 

tool: D36: %d

tool: D8: 
Raiz quadrada aproximada de %d: %.2f.


tool: D9: 
Quadrado de %d: %d.


assistant: ```c
void main() {
  int num;
  printf("Digite um inteiro: ");
  scanf("%d", &num);
  if (num % 2 == 0)
    printf("\nRaiz quadrada aproximada de %d: %.2f.\n", num, sqrt(num));
  else
    printf("\nQuadrado de %d: %d.\n", num, num * num);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x41,-0x15(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L8
L29:
  movb   $0x41,-0x15(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L21:
  movsbl -0x15(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  movzbl -0x15(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x15(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string

tool: D35: Enter height of the patten: 

tool: D32: %d

tool: D31: Pattern: 


tool: D27: %2c

assistant: ```c
int main() {
  int i, j, lengthDown;
  char ch = 'A';
  printf("Enter height of the patten: ");
  scanf("%d", &lengthDown);
  printf("Pattern: \n\n");
  for (i = 0; i < lengthDown; i++) {
    for (ch = 'A', j = 0; j <= i; j++, ch++)
      printf("%2c", ch);
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D1(%rip),%r12
  cmpl   $0x0,0x4(%rsp)
  jg     L2
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  lea    0x41(%rbx),%esi
  movsbl %sil,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L46
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L45
L2:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L46
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D31
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D26
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D31: Enter height of the patten: 

tool: D22: %d

tool: D26: Pattern: 


tool: D1: %2c

assistant: ```c
int main() {
  int i, j, lengthDown;
  char ch = 'A';
  printf("Enter height of the patten: ");
  scanf("%d", &lengthDown);
  printf("Pattern: \n\n");
  for (i = 0; i < lengthDown; i++) {
    for (ch = 'A', j = 0; j <= i; j++, ch++)
      printf("%2c", ch);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L31
  xor    %ebp,%ebp
  lea    D30(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L5:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  lea    0x41(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  movsbl %sil,%esi
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L1
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L5
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string

tool: D2: Enter height of the patten: 

tool: D25: %d

tool: D5: Pattern: 


tool: D30: %2c

assistant: ```c
int main() {
  int i, j, lengthDown;
  char ch = 'A';
  printf("Enter height of the patten: ");
  scanf("%d", &lengthDown);
  printf("Pattern: \n\n");
  for (i = 0; i < lengthDown; i++) {
    for (ch = 'A', j = 0; j <= i; j++, ch++)
      printf("%2c", ch);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  xor    %ebp,%ebp
  lea    D27(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L20:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L25:
  lea    0x41(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  movsbl %sil,%esi
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L25
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L20
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string

tool: D29: Enter height of the patten: 

tool: D24: %d

tool: D15: Pattern: 


tool: D27: %2c

assistant: ```c
int main() {
  int i, j, lengthDown;
  char ch = 'A';
  printf("Enter height of the patten: ");
  scanf("%d", &lengthDown);
  printf("Pattern: \n\n");
  for (i = 0; i < lengthDown; i++) {
    for (ch = 'A', j = 0; j <= i; j++, ch++)
      printf("%2c", ch);
    printf("\n");
  }
}
```