ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strip_www>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  js     L20
  cltq
  xor    %ecx,%ecx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L32:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L20
L18:
  cmpb   $0x2e,(%r12,%rax,1)
  mov    %eax,%edx
  jne    L32
  cmp    $0x1,%ecx
  je     L13
  sub    $0x1,%rax
  mov    $0x1,%ecx
  test   %eax,%eax
  jns    L18
L20:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  add    $0x1,%edx
  movslq %edx,%rdx
  add    %rdx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strip_www(char *domain) {
  static char newdomain[256];
  int x, c = 0;
  for (x = strlen(domain); x >= 0; x--) {
    if (domain[x] == '.')
      c++;
    if (c == 2) {
      x++;
      return &(domain[x]);
    }
  }
  return domain;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strip_www>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  js     L50
  cltq
  xor    %ecx,%ecx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L50
L9:
  cmpb   $0x2e,(%r12,%rax,1)
  mov    %eax,%edx
  jne    L0
  cmp    $0x1,%ecx
  je     L23
  sub    $0x1,%rax
  mov    $0x1,%ecx
  test   %eax,%eax
  jns    L9
L50:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  add    $0x1,%edx
  movslq %edx,%rdx
  add    %rdx,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strip_www(char *domain) {
  static char newdomain[256];
  int x, c = 0;
  for (x = strlen(domain); x >= 0; x--) {
    if (domain[x] == '.')
      c++;
    if (c == 2) {
      x++;
      return &(domain[x]);
    }
  }
  return domain;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  imul   $0xfffffffffffe0ce3,%rax,%rax
  add    %rdx,%rax
  imul   $0x41a7,%rax,%rdx
  mov    -0x8(%rbp),%rax
  imul   $0xfffffffffffff4ec,%rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x7fffffff(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
long int random_number(long *idum) {
  long k;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  return *idum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_number>:
  endbr64
  mov    (%rdi),%rsi
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0xf,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xfffffffffffe0ce3,%rdx,%rax
  add    %rsi,%rax
  imul   $0x41a7,%rax,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  cmovs  %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
long int random_number(long *idum) {
  long k;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  return *idum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<random_number>:
  endbr64
  movabs $0x41a705af1fe3fb79,%rdx
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0xfffffffffffe0ce3,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rcx,%rax
  imul   $0x41a7,%rax,%rax
  add    %rdx,%rax
  jns    L1
  add    $0x7fffffff,%rax
L1:
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
long int random_number(long *idum) {
  long k;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  return *idum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<random_number>:
  endbr64
  movabs $0x41a705af1fe3fb79,%rdx
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0xf,%rdx
  sub    %rax,%rdx
  imul   $0xfffffffffffe0ce3,%rdx,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rcx,%rax
  imul   $0x41a7,%rax,%rax
  add    %rdx,%rax
  jns    L4
  add    $0x7fffffff,%rax
L4:
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
long int random_number(long *idum) {
  long k;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  return *idum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SumProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L12:
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x28(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double SumProduct(int n, const double *x, int dx, const double *y, int dy) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i) {
    Sum += (*x) * (*y);
    x += dx;
    y += dy;
  }
  return Sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SumProduct>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rax
  test   %edi,%edi
  jle    L3
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rdi
  movslq %r8d,%r8
  lea    0x0(,%r8,8),%rsi
  mov    $0x0,%edx
  pxor   %xmm1,%xmm1
L27:
  movsd  (%rax),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  %xmm0,%xmm1
  add    %rdi,%rax
  add    %rsi,%rcx
  add    $0x1,%edx
  cmp    %edx,%r9d
  jne    L27
L25:
  movapd %xmm1,%xmm0
  ret
L3:
  pxor   %xmm1,%xmm1
  jmp    L25
```

assistant: ```c
double SumProduct(int n, const double *x, int dx, const double *y, int dy) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i) {
    Sum += (*x) * (*y);
    x += dx;
    y += dy;
  }
  return Sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SumProduct>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rax
  test   %edi,%edi
  jle    L0
  movslq %edx,%rdx
  movslq %r8d,%r8
  pxor   %xmm1,%xmm1
  lea    0x0(,%rdx,8),%rdi
  lea    0x0(,%r8,8),%rsi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rax),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x1,%edx
  add    %rdi,%rax
  add    %rsi,%rcx
  addsd  %xmm0,%xmm1
  cmp    %edx,%r9d
  jne    L9
  movapd %xmm1,%xmm0
  ret
  nop
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double SumProduct(int n, const double *x, int dx, const double *y, int dy) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i) {
    Sum += (*x) * (*y);
    x += dx;
    y += dy;
  }
  return Sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<SumProduct>:
  endbr64
  mov    %rsi,%rax
  test   %edi,%edi
  jle    L37
  movslq %edx,%r9
  movslq %r8d,%r10
  shl    $0x3,%r9
  shl    $0x3,%r10
  cmp    $0x1,%r8d
  jne    L35
  xor    %esi,%esi
  pxor   %xmm1,%xmm1
  cmp    $0x1,%edx
  jne    L35
  nopw   0x0(%rax,%rax,1)
L31:
  movsd  (%rcx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x1,%esi
  add    %r9,%rax
  add    %r10,%rcx
  addsd  %xmm0,%xmm1
  cmp    %esi,%edi
  jne    L31
  movapd %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L35:
  xor    %edx,%edx
  pxor   %xmm1,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L19:
  movsd  (%rax),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x1,%edx
  add    %r9,%rax
  add    %r10,%rcx
  addsd  %xmm0,%xmm1
  cmp    %edx,%edi
  jne    L19
  movapd %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L37:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double SumProduct(int n, const double *x, int dx, const double *y, int dy) {
  double Sum = 0.0;
  for (int i = 0; i < n; ++i) {
    Sum += (*x) * (*y);
    x += dx;
    y += dy;
  }
  return Sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L32:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jle    L11
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jle    L13
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string

tool: D25: nc = %ld

tool: D7: Exceeded input limit!!!!

tool: D10: %ld


assistant: ```c
main() {
  long nc;
  int max;
  int tmpc;
  nc = 0;
  max = 10;
  tmpc = 0;
  while (nc <= max) {
    tmpc = getchar();
    nc++;
    printf("nc = %ld", nc);
  }
  if (nc > max)
    printf("Exceeded input limit!!!!");
  else
    printf("%ld\n", nc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L1:
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x1,%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L1
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D7: nc = %ld

tool: D19: Exceeded input limit!!!!

assistant: ```c
main() {
  long nc;
  int max;
  int tmpc;
  nc = 0;
  max = 10;
  tmpc = 0;
  while (nc <= max) {
    tmpc = getchar();
    nc++;
    printf("nc = %ld", nc);
  }
  if (nc > max)
    printf("Exceeded input limit!!!!");
  else
    printf("%ld\n", nc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getchar@plt>
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L3
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D2: nc = %ld

tool: D5: Exceeded input limit!!!!

assistant: ```c
main() {
  long nc;
  int max;
  int tmpc;
  nc = 0;
  max = 10;
  tmpc = 0;
  while (nc <= max) {
    tmpc = getchar();
    nc++;
    printf("nc = %ld", nc);
  }
  if (nc > max)
    printf("Exceeded input limit!!!!");
  else
    printf("%ld\n", nc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getchar@plt>
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L5
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D4: nc = %ld

tool: D1: Exceeded input limit!!!!

assistant: ```c
main() {
  long nc;
  int max;
  int tmpc;
  nc = 0;
  max = 10;
  tmpc = 0;
  while (nc <= max) {
    tmpc = getchar();
    nc++;
    printf("nc = %ld", nc);
  }
  if (nc > max)
    printf("Exceeded input limit!!!!");
  else
    printf("%ld\n", nc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvtnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L37
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L37
  mov    $0xffffffffffffffff,%rax
  jmp    L4
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x10(%rbp),%rax
  jmp    L4
L56:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L146
  mov    $0xffffffffffffffff,%rax
  jmp    L4
L146:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x65,%eax
  cmp    $0xf,%eax
  ja     L132
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D13(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%rax
  shl    $0xa,%rax
  jmp    L4
  mov    -0x10(%rbp),%rax
  shl    $0x14,%rax
  jmp    L4
  mov    -0x10(%rbp),%rax
  shl    $0x1e,%rax
  jmp    L4
  mov    -0x10(%rbp),%rax
  shl    $0x28,%rax
  jmp    L4
  mov    -0x10(%rbp),%rax
  shl    $0x32,%rax
  jmp    L4
  mov    -0x10(%rbp),%rax
  shl    $0x3c,%rax
  jmp    L4
L132:
  mov    $0xffffffffffffffff,%rax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
long long cvtnum(char *s) {
  long long i;
  char *sp;
  int c;
  i = strtoll(s, &sp, 0);
  if (i == 0 && sp == s)
    return -1LL;
  if (*sp == '\0')
    return i;
  if (sp[1] != '\0')
    return -1LL;
  c = tolower(*sp);
  switch (c) {
  case 'k':
    return ((long long)(i) << 10);
  case 'm':
    return ((long long)(i) << 20);
  case 'g':
    return ((long long)(i) << 30);
  case 't':
    return ((long long)(i) << 40);
  case 'p':
    return ((long long)(i) << 50);
  case 'e':
    return ((long long)(i) << 60);
  }
  return -1LL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cvtnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <strtoll@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L61
  cmp    %rbp,(%rsp)
  je     L33
L61:
  mov    (%rsp),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L2
  cmpb   $0x0,0x1(%rax)
  jne    L48
  movsbl %dil,%edi
  call   <tolower@plt>
  sub    $0x65,%eax
  cmp    $0xf,%eax
  ja     L87
  mov    %eax,%eax
  lea    D3(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  shl    $0xa,%rbx
  jmp    L2
  shl    $0x14,%rbx
  jmp    L2
  shl    $0x1e,%rbx
  jmp    L2
  shl    $0x28,%rbx
  jmp    L2
  shl    $0x32,%rbx
  jmp    L2
  shl    $0x3c,%rbx
  jmp    L2
L33:
  mov    $0xffffffffffffffff,%rbx
  jmp    L2
L48:
  mov    $0xffffffffffffffff,%rbx
  jmp    L2
L87:
  mov    $0xffffffffffffffff,%rbx
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long cvtnum(char *s) {
  long long i;
  char *sp;
  int c;
  i = strtoll(s, &sp, 0);
  if (i == 0 && sp == s)
    return -1LL;
  if (*sp == '\0')
    return i;
  if (sp[1] != '\0')
    return -1LL;
  c = tolower(*sp);
  switch (c) {
  case 'k':
    return ((long long)(i) << 10);
  case 'm':
    return ((long long)(i) << 20);
  case 'g':
    return ((long long)(i) << 30);
  case 't':
    return ((long long)(i) << 40);
  case 'p':
    return ((long long)(i) << 50);
  case 'e':
    return ((long long)(i) << 60);
  }
  return -1LL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L19
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L19:
  movl   $0x0,-0x28(%rbp)
  jmp    L61
L41:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L61:
  cmpl   $0x0,-0x28(%rbp)
  jle    L41
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  cmp    $0x5ffe5f36,%rax
  jne    L54
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L54:
  movl   $0x0,-0x24(%rbp)
  jmp    L39
L59:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L39:
  cmpl   $0x0,-0x24(%rbp)
  jle    L59
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string
name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D21
data_type: string

tool: D3: Call this program with %i arguments


tool: D17: You win!

tool: D21: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1610506038UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L40
L44:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpq   $0x5ffe5f36,0x10(%rsp)
  je     L19
L23:
  mov    0x10(%rsp),%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L44
L19:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type: string
name: parse_data
arguments: tag: D20
type: string
name: parse_data
arguments: tag: D12
type: string

tool: D14: %lu


tool: D20: Call this program with %i arguments


tool: D12: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1610506038UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L30
  lea    D4(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L30:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x5ffe5f36,%rsi
  je     L22
L5:
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L5
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string

tool: D4: Call this program with %i arguments


tool: D6: %lu


tool: D8: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1610506038UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```