ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mul_images>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,-0x1c(%rsp)
  test   %ecx,%ecx
  jle    L98
  mov    %edx,%r11d
  test   %edx,%edx
  jle    L98
  mov    %edx,%eax
  lea    -0x1(%rdx),%ebx
  movslq %edx,%r12
  mov    %edx,%ebp
  shr    $0x2,%eax
  and    $0x3,%edx
  mov    %ebx,-0x18(%rsp)
  mov    %rsi,%rcx
  lea    -0x1(%rax),%r9d
  mov    %ebx,%eax
  mov    %edx,-0x14(%rsp)
  and    $0xfffffffc,%ebp
  shl    $0x2,%rax
  add    $0x1,%r9
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  sub    %rsi,%rax
  lea    0x0(,%r12,4),%r13
  shl    $0x4,%r9
  xor    %ebx,%ebx
  add    $0x4,%rax
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax)
L136:
  lea    0x0(,%r10,4),%rax
  lea    0x4(%rcx),%r15
  lea    (%rdi,%rax,1),%rdx
  mov    %rdx,%r14
  sub    %r15,%r14
  cmp    $0x8,%r14
  jbe    L69
  cmp    $0x1,%r11d
  je     L69
  cmpl   $0x2,-0x18(%rsp)
  jbe    L8
  xor    %eax,%eax
  nop
L39:
  movups (%rdx,%rax,1),%xmm0
  movups (%rcx,%rax,1),%xmm2
  mulps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L39
  cmp    %r11d,%ebp
  je     L58
  mov    -0x14(%rsp),%eax
  mov    %eax,%r15d
  cmp    $0x1,%eax
  je     L41
  mov    %ebp,%edx
  mov    %ebp,%eax
L135:
  add    %r10,%rdx
  lea    (%rdi,%rdx,4),%r14
  movq   (%rsi,%rdx,4),%xmm0
  mov    %r15d,%edx
  movq   (%r14),%xmm1
  and    $0xfffffffe,%edx
  add    %edx,%eax
  mulps  %xmm1,%xmm0
  movlps %xmm0,(%r14)
  cmp    %edx,%r15d
  je     L58
L106:
  add    %r8d,%eax
  cltq
  lea    (%rdi,%rax,4),%rdx
  movss  (%rdx),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx)
L58:
  add    $0x1,%ebx
  add    %r13,%rcx
  add    %r11d,%r8d
  add    %r12,%r10
  cmp    %ebx,-0x1c(%rsp)
  jne    L136
L98:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L69:
  mov    -0x10(%rsp),%rdx
  add    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L118:
  movss  (%rdi,%rax,1),%xmm0
  mulss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L118
  jmp    L58
L8:
  mov    %r11d,%r15d
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L135
L41:
  mov    %ebp,%eax
  jmp    L106
```

assistant: ```c
void mul_images(image1, image2, nx, ny) float *image1, *image2;
int nx, ny;
{
  int index, i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      index = i * nx + j;
      image1[index] = image1[index] * image2[index];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpo_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L35
  addq   $0x1,-0x18(%rbp)
  jmp    L35
L44:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L59
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L44
L59:
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    -0x8(%rbp),%eax
  neg    %eax
  jmp    L45
L22:
  mov    -0x8(%rbp),%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int cpo_atoi(const char *s) {
  int n = 0;
  int neg = *s == '-';
  if (neg)
    s++;
  while (*s >= '0' && *s <= '9')
    n = 10 * n + (*s++ - '0');
  return neg ? -n : n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpo_atoi>:
  endbr64
  movzbl (%rdi),%esi
  cmp    $0x2d,%sil
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L4
  mov    $0x0,%edx
L7:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L7
L12:
  mov    %edx,%eax
  neg    %eax
  cmp    $0x2d,%sil
  cmove  %eax,%edx
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int cpo_atoi(const char *s) {
  int n = 0;
  int neg = *s == '-';
  if (neg)
    s++;
  while (*s >= '0' && *s <= '9')
    n = 10 * n + (*s++ - '0');
  return neg ? -n : n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpo_atoi>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x2d,%cl
  je     L66
  lea    -0x30(%rcx),%edx
  mov    %ecx,%eax
  cmp    $0x9,%dl
  ja     L35
L18:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L4
  cmp    $0x2d,%cl
  je     L58
L27:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rsi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L32
  mov    %rsi,%rdi
  jmp    L18
L32:
  xor    %r8d,%r8d
L58:
  neg    %r8d
  mov    %r8d,%eax
  ret
L35:
  xor    %r8d,%r8d
  jmp    L27
```

assistant: ```c
int cpo_atoi(const char *s) {
  int n = 0;
  int neg = *s == '-';
  if (neg)
    s++;
  while (*s >= '0' && *s <= '9')
    n = 10 * n + (*s++ - '0');
  return neg ? -n : n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cpo_atoi>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x2d,%cl
  je     L13
  lea    -0x30(%rcx),%edx
  mov    %ecx,%eax
  cmp    $0x9,%dl
  ja     L43
L15:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L37:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L37
  cmp    $0x2d,%cl
  je     L46
L3:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rsi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L69
  mov    %rsi,%rdi
  jmp    L15
L69:
  xor    %r8d,%r8d
L46:
  neg    %r8d
  mov    %r8d,%eax
  ret
L43:
  xor    %r8d,%r8d
  jmp    L3
```

assistant: ```c
int cpo_atoi(const char *s) {
  int n = 0;
  int neg = *s == '-';
  if (neg)
    s++;
  while (*s >= '0' && *s <= '9')
    n = 10 * n + (*s++ - '0');
  return neg ? -n : n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eb_calc_crc_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L20:
  movzbl -0x6(%rbp),%eax
  test   %al,%al
  jns    L41
  movb   $0x9b,-0x5(%rbp)
  jmp    L23
L41:
  movb   $0x0,-0x5(%rbp)
L23:
  shlb   -0x6(%rbp)
  movzbl -0x14(%rbp),%eax
  test   %al,%al
  jns    L9
  orb    $0x1,-0x6(%rbp)
L9:
  movzbl -0x5(%rbp),%eax
  xor    %al,-0x6(%rbp)
  shlb   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L43:
  cmpl   $0x7,-0x4(%rbp)
  jle    L20
  movzbl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char eb_calc_crc_byte(unsigned char byte, unsigned char init_crc) {
  unsigned char crc, polynom;
  int i;
  crc = init_crc;
  for (i = 0; i < 8; i++) {
    if (crc & 0x80)
      polynom = (unsigned char)0x9B;
    else
      polynom = (unsigned char)0;
    crc = (unsigned char)((crc & ~0x80) << 1);
    if (byte & 0x80)
      crc = (unsigned char)(crc | 1);
    crc = (unsigned char)(crc ^ polynom);
    byte = (unsigned char)(byte << 1);
  }
  return crc;
}
```
user: What is the c source code of the assembly code below?

```asm
<eb_calc_crc_byte>:
  endbr64
  mov    %esi,%eax
  mov    $0x8,%ecx
L5:
  mov    %eax,%edx
  sar    $0x7,%dl
  and    $0xffffff9b,%edx
  add    %eax,%eax
  mov    %eax,%esi
  or     $0x1,%esi
  test   %dil,%dil
  cmovs  %esi,%eax
  xor    %edx,%eax
  add    %edi,%edi
  sub    $0x1,%ecx
  jne    L5
  ret
```

assistant: ```c
unsigned char eb_calc_crc_byte(unsigned char byte, unsigned char init_crc) {
  unsigned char crc, polynom;
  int i;
  crc = init_crc;
  for (i = 0; i < 8; i++) {
    if (crc & 0x80)
      polynom = (unsigned char)0x9B;
    else
      polynom = (unsigned char)0;
    crc = (unsigned char)((crc & ~0x80) << 1);
    if (byte & 0x80)
      crc = (unsigned char)(crc | 1);
    crc = (unsigned char)(crc ^ polynom);
    byte = (unsigned char)(byte << 1);
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eb_calc_crc_byte>:
  endbr64
  mov    %esi,%eax
  mov    $0x8,%ecx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %eax,%edx
  add    %eax,%eax
  sar    $0x7,%dl
  mov    %eax,%esi
  and    $0xffffff9b,%edx
  or     $0x1,%esi
  test   %dil,%dil
  cmovs  %esi,%eax
  add    %edi,%edi
  xor    %edx,%eax
  sub    $0x1,%ecx
  jne    L8
  ret
```

assistant: ```c
unsigned char eb_calc_crc_byte(unsigned char byte, unsigned char init_crc) {
  unsigned char crc, polynom;
  int i;
  crc = init_crc;
  for (i = 0; i < 8; i++) {
    if (crc & 0x80)
      polynom = (unsigned char)0x9B;
    else
      polynom = (unsigned char)0;
    crc = (unsigned char)((crc & ~0x80) << 1);
    if (byte & 0x80)
      crc = (unsigned char)(crc | 1);
    crc = (unsigned char)(crc ^ polynom);
    byte = (unsigned char)(byte << 1);
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eb_calc_crc_byte>:
  endbr64
  mov    %esi,%edx
  lea    (%rsi,%rsi,1),%eax
  mov    %edi,%ecx
  sar    $0x7,%dl
  mov    %eax,%esi
  and    $0xffffff9b,%edx
  or     $0x1,%esi
  test   %dil,%dil
  cmovs  %esi,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  add    %eax,%eax
  sar    $0x7,%dl
  mov    %eax,%esi
  and    $0xffffff9b,%edx
  or     $0x1,%esi
  test   $0x40,%dil
  cmovne %esi,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  add    %eax,%eax
  sar    $0x7,%dl
  mov    %eax,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%edx
  test   $0x20,%dil
  cmovne %esi,%eax
  xor    %eax,%edx
  mov    %edx,%eax
  add    %edx,%edx
  sar    $0x7,%al
  mov    %edx,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%eax
  test   $0x10,%dil
  cmovne %esi,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  add    %eax,%eax
  sar    $0x7,%dl
  mov    %eax,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%edx
  test   $0x8,%dil
  cmovne %esi,%eax
  xor    %eax,%edx
  mov    %edx,%eax
  add    %edx,%edx
  sar    $0x7,%al
  mov    %edx,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%eax
  test   $0x4,%dil
  cmovne %esi,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  add    %eax,%eax
  sar    $0x7,%dl
  mov    %eax,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%edx
  test   $0x2,%dil
  cmovne %esi,%eax
  xor    %eax,%edx
  mov    %edx,%eax
  add    %edx,%edx
  sar    $0x7,%al
  mov    %edx,%esi
  or     $0x1,%esi
  and    $0xffffff9b,%eax
  and    $0x1,%ecx
  cmovne %esi,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned char eb_calc_crc_byte(unsigned char byte, unsigned char init_crc) {
  unsigned char crc, polynom;
  int i;
  crc = init_crc;
  for (i = 0; i < 8; i++) {
    if (crc & 0x80)
      polynom = (unsigned char)0x9B;
    else
      polynom = (unsigned char)0;
    crc = (unsigned char)((crc & ~0x80) << 1);
    if (byte & 0x80)
      crc = (unsigned char)(crc | 1);
    crc = (unsigned char)(crc ^ polynom);
    byte = (unsigned char)(byte << 1);
  }
  return crc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sat_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *sat_free(void *mem) {
  if (mem)
    free(mem);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<sat_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *sat_free(void *mem) {
  if (mem)
    free(mem);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sat_free>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *sat_free(void *mem) {
  if (mem)
    free(mem);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sat_free>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *sat_free(void *mem) {
  if (mem)
    free(mem);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solveKepler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x10(%rbp),%xmm2
  movsd  D16(%rip),%xmm1
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L3
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: f64
name: parse_data
arguments: label: D16
data_type: f64

tool: D7: 3.141592653589793

tool: D16: 1

assistant: ```c
double solveKepler(double M, double e) {
  double E, Eprime = 3.141592653589793;
  do {
    double cosE = cos(Eprime);
    E = Eprime;
    Eprime = (M - e * (E * cosE - sin(E))) / (1.0 - e * cosE);
  } while (fabs(E - Eprime) > 1e-7);
  return (Eprime);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<solveKepler>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%rbx
  movsd  %xmm1,0x8(%rsp)
  movsd  D7(%rip),%xmm6
  movsd  %xmm6,(%rsp)
L4:
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movsd  (%rsp),%xmm0
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  (%rsp),%xmm4
  movapd %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  0x18(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm5
  mulsd  %xmm5,%xmm0
  movq   %rbx,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  mulsd  %xmm5,%xmm1
  movsd  D11(%rip),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm3
  movsd  %xmm3,(%rsp)
  subsd  %xmm3,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L4
  movsd  (%rsp),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: f64
name: retrieve_data
arguments: tag: D11
type_guessed: f64

tool: D7: 3.141592653589793

tool: D11: 1

assistant: ```c
double solveKepler(double M, double e) {
  double E, Eprime = 3.141592653589793;
  do {
    double cosE = cos(Eprime);
    E = Eprime;
    Eprime = (M - e * (E * cosE - sin(E))) / (1.0 - e * cosE);
  } while (fabs(E - Eprime) > 1e-7);
  return (Eprime);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solveKepler>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  sub    $0x28,%rsp
  movsd  D33(%rip),%xmm3
  movsd  D35(%rip),%xmm2
  movsd  D36(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  lea    0x18(%rsp),%rbx
  jmp    L6
  nopl   (%rax)
L18:
  movapd %xmm1,%xmm0
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <sincos@plt>
  movsd  (%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm1,%xmm0
L6:
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm5
  movsd  D10(%rip),%xmm4
  mulsd  %xmm3,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm2,%xmm1
  movq   %r14,%xmm2
  subsd  %xmm3,%xmm4
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm2
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <fabs@plt>
  movsd  (%rsp),%xmm1
  test   %eax,%eax
  jg     L18
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D35
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D36
data_type: f64
name: extract_symbolic_data
arguments: tag: D10
data_type: f64

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D35": [0x07,0x5c,0x14,0x33,0x26,0xa6,0xa1,0x3c]}

tool: D36: 3.141592653589793

tool: D10: 1

assistant: ```c
double solveKepler(double M, double e) {
  double E, Eprime = 3.141592653589793;
  do {
    double cosE = cos(Eprime);
    E = Eprime;
    Eprime = (M - e * (E * cosE - sin(E))) / (1.0 - e * cosE);
  } while (fabs(E - Eprime) > 1e-7);
  return (Eprime);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solveKepler>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  sub    $0x28,%rsp
  movsd  D19(%rip),%xmm3
  movsd  D25(%rip),%xmm2
  movsd  D2(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  lea    0x18(%rsp),%rbx
  jmp    L13
  nopl   (%rax)
L8:
  movapd %xmm1,%xmm0
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <sincos@plt>
  movsd  (%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm1,%xmm0
L13:
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm5
  movsd  D14(%rip),%xmm4
  mulsd  %xmm3,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm2,%xmm1
  movq   %r14,%xmm2
  subsd  %xmm3,%xmm4
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm2
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <fabs@plt>
  movsd  (%rsp),%xmm1
  test   %eax,%eax
  jg     L8
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D25
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D2
type_guessed: f64
name: retrieve_data
arguments: data_tag: D14
type_guessed: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D25": [0x07,0x5c,0x14,0x33,0x26,0xa6,0xa1,0x3c]}

tool: D2: 3.141592653589793

tool: D14: 1

assistant: ```c
double solveKepler(double M, double e) {
  double E, Eprime = 3.141592653589793;
  do {
    double cosE = cos(Eprime);
    E = Eprime;
    Eprime = (M - e * (E * cosE - sin(E))) / (1.0 - e * cosE);
  } while (fabs(E - Eprime) > 1e-7);
  return (Eprime);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D1(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: byte[4]
name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: {"D1": [0xcd,0xcc,0xcc,0x3e]}

tool: D19: result_normal = %f


tool: D0: result_cast = %f


assistant: ```c
int main(void) {
  float result_normal;
  float result_cast;
  result_normal = 2 / 5;
  result_cast = (float)2 / (float)5;
  printf("result_normal = %f\n", result_normal);
  printf("result_cast = %f\n", result_cast);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  movss  D26(%rip),%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D26
type_guessed: byte[4]
name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D15: result_normal = %f


tool: {"D26": [0xcd,0xcc,0xcc,0x3e]}

tool: D21: result_cast = %f


assistant: ```c
int main(void) {
  float result_normal;
  float result_cast;
  result_normal = 2 / 5;
  result_cast = (float)2 / (float)5;
  printf("result_normal = %f\n", result_normal);
  printf("result_cast = %f\n", result_cast);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  call   <printf@plt>
  movss  D19(%rip),%xmm0
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: byte[4]
name: disassemble_data
arguments: tag: D20
datatype: string

tool: D12: result_normal = %f


tool: {"D19": [0xcd,0xcc,0xcc,0x3e]}

tool: D20: result_cast = %f


assistant: ```c
int main(void) {
  float result_normal;
  float result_cast;
  result_normal = 2 / 5;
  result_cast = (float)2 / (float)5;
  printf("result_normal = %f\n", result_normal);
  printf("result_cast = %f\n", result_cast);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  lea    D25(%rip),%rdi
  call   <printf@plt>
  movss  D26(%rip),%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D25
data_type: string
name: read_data
arguments: data_label: D26
data_type: byte[4]
name: read_data
arguments: data_label: D7
data_type: string

tool: D25: result_normal = %f


tool: {"D26": [0xcd,0xcc,0xcc,0x3e]}

tool: D7: result_cast = %f


assistant: ```c
int main(void) {
  float result_normal;
  float result_cast;
  result_normal = 2 / 5;
  result_cast = (float)2 / (float)5;
  printf("result_normal = %f\n", result_normal);
  printf("result_cast = %f\n", result_cast);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L18
L4:
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L28:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x2,-0x34(%rbp)
  jle    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x38(%rbp)
L18:
  cmpl   $0x2,-0x38(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: %i

assistant: ```c
int main() {
  int matrix[3][3] = {0};
  matrix[0][0] = 1;
  matrix[2][2] = 1;
  for (int row = 0; row < 3; row++) {
    for (int column = 0; column < 3; column++) {
      printf("%i", matrix[row][column]);
    }
    printf("\n");
  }
  return 0;
}
```