ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<CE_pHP_HCO3>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm6
  movq   %xmm1,%r15
  movq   %xmm2,%rbx
  movq   %xmm3,%rbp
  movq   %xmm4,%r12
  movq   %xmm5,%r14
  movsd  D4(%rip),%xmm0
  subsd  %xmm6,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D6(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm4
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm4
  movsd  %xmm4,(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %rbx,%xmm7
  divsd  %xmm0,%xmm7
  movq   %xmm7,%rbx
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm6
  divsd  %xmm0,%xmm6
  movsd  %xmm6,0x8(%rsp)
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbx,%xmm2
  xorpd  D1(%rip),%xmm2
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  movq   %r15,%xmm5
  mulsd  %xmm5,%xmm1
  movq   %r12,%xmm3
  divsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x8(%rsp),%xmm2
  addsd  %xmm4,%xmm2
  divsd  %xmm2,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: byte[8]
name: parse_data
arguments: tag: D6
type_infered: byte[8]
name: parse_data
arguments: tag: D1
type_infered: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_HCO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K1 * (P * H3O - Kw + H3O * H3O) / (-K1 * K2 + H3O * H3O);
  return t0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CE_pHP_HCO3>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D24(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm3,0x38(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D14(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm5,%xmm0
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm5,%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x20(%rsp)
  call   <pow@plt>
  movsd  0x38(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm2
  xorpd  D17(%rip),%xmm2
  divsd  %xmm0,%xmm4
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm6
  mulsd  0x10(%rsp),%xmm1
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x8(%rsp),%xmm2
  add    $0x48,%rsp
  addsd  %xmm6,%xmm2
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
type_guessed: byte[8]
name: parse_data
arguments: tag: D14
type_guessed: byte[8]
name: parse_data
arguments: tag: D17
type_guessed: byte[16]

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_HCO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K1 * (P * H3O - Kw + H3O * H3O) / (-K1 * K2 + H3O * H3O);
  return t0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CE_pHP_HCO3>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D2(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm3,0x38(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D24(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm5,%xmm0
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm5,%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x20(%rsp)
  call   <pow@plt>
  movsd  0x38(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm2
  xorpd  D22(%rip),%xmm2
  divsd  %xmm0,%xmm4
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm6
  mulsd  0x10(%rsp),%xmm1
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x8(%rsp),%xmm2
  add    $0x48,%rsp
  addsd  %xmm6,%xmm2
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: byte[8]
name: retrieve_data
arguments: label: D24
type: byte[8]
name: retrieve_data
arguments: label: D22
type: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_HCO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K1 * (P * H3O - Kw + H3O * H3O) / (-K1 * K2 + H3O * H3O);
  return t0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1020304,%ecx
  mov    $0x4030201,%edx
  mov    $0x1020304,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xadd,%ecx
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xadd,%ecx
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa0d,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xadd,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D35
type_infered: string
name: retrieve_data
arguments: label: D43
type_infered: string

tool: D27: s = %x, t = %x, u = %x 


tool: D8: nb = %u => %u => %u


tool: D39: nb = %x => %x => %x


tool: D35:  2573 = %x


tool: D43:  2781 = %x


assistant: ```c
int main(int argc, char **argv) {
  uint32_t s = 0x01020304;
  uint32_t t, u;
  t = (((s & 0xff) << 24) + (((s >> 8) & 0xff) << 16) + (((s >> 16) & 0xff) << 8) + ((s >> 24) & 0xff));
  u = (((t & 0xff) << 24) + (((t >> 8) & 0xff) << 16) + (((t >> 16) & 0xff) << 8) + ((t >> 24) & 0xff));
  printf("s = %x, t = %x, u = %x \n", s, t, u);
  uint32_t nb = 2781;
  uint32_t nb2 = (((nb & 0xff) << 24) + (((nb >> 8) & 0xff) << 16) + (((nb >> 16) & 0xff) << 8) + ((nb >> 24) & 0xff));
  uint32_t nb3 = (((nb2 & 0xff) << 24) + (((nb2 >> 8) & 0xff) << 16) + (((nb2 >> 16) & 0xff) << 8) + ((nb2 >> 24) & 0xff));
  printf("nb = %u => %u => %u\n", nb, nb2, nb3);
  printf("nb = %x => %x => %x\n", nb, nb2, nb3);
  uint32_t nbframes = 2573;
  uint32_t nbframes2 = 2781;
  printf(" 2573 = %x\n", nbframes);
  printf(" 2781 = %x\n", nbframes2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1020304,%ecx
  mov    $0x4030201,%edx
  xor    %eax,%eax
  mov    $0x1020304,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xadd,%ecx
  xor    %eax,%eax
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xadd,%ecx
  xor    %eax,%eax
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0xa0d,%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xadd,%esi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D44
type_guessed: string
name: retrieve_data
arguments: data_tag: D37
type_guessed: string
name: retrieve_data
arguments: data_tag: D48
type_guessed: string

tool: D0: s = %x, t = %x, u = %x 


tool: D9: nb = %u => %u => %u


tool: D44: nb = %x => %x => %x


tool: D37:  2573 = %x


tool: D48:  2781 = %x


assistant: ```c
int main(int argc, char **argv) {
  uint32_t s = 0x01020304;
  uint32_t t, u;
  t = (((s & 0xff) << 24) + (((s >> 8) & 0xff) << 16) + (((s >> 16) & 0xff) << 8) + ((s >> 24) & 0xff));
  u = (((t & 0xff) << 24) + (((t >> 8) & 0xff) << 16) + (((t >> 16) & 0xff) << 8) + ((t >> 24) & 0xff));
  printf("s = %x, t = %x, u = %x \n", s, t, u);
  uint32_t nb = 2781;
  uint32_t nb2 = (((nb & 0xff) << 24) + (((nb >> 8) & 0xff) << 16) + (((nb >> 16) & 0xff) << 8) + ((nb >> 24) & 0xff));
  uint32_t nb3 = (((nb2 & 0xff) << 24) + (((nb2 >> 8) & 0xff) << 16) + (((nb2 >> 16) & 0xff) << 8) + ((nb2 >> 24) & 0xff));
  printf("nb = %u => %u => %u\n", nb, nb2, nb3);
  printf("nb = %x => %x => %x\n", nb, nb2, nb3);
  uint32_t nbframes = 2573;
  uint32_t nbframes2 = 2781;
  printf(" 2573 = %x\n", nbframes);
  printf(" 2781 = %x\n", nbframes2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1020304,%ecx
  mov    $0x4030201,%edx
  xor    %eax,%eax
  mov    $0x1020304,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0xadd,%ecx
  xor    %eax,%eax
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0xadd,%ecx
  xor    %eax,%eax
  mov    $0xdd0a0000,%edx
  mov    $0xadd,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0xa0d,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xadd,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D25
datatype: string
name: unpack_data
arguments: data_label: D39
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string

tool: D20: s = %x, t = %x, u = %x 


tool: D11: nb = %u => %u => %u


tool: D25: nb = %x => %x => %x


tool: D39:  2573 = %x


tool: D21:  2781 = %x


assistant: ```c
int main(int argc, char **argv) {
  uint32_t s = 0x01020304;
  uint32_t t, u;
  t = (((s & 0xff) << 24) + (((s >> 8) & 0xff) << 16) + (((s >> 16) & 0xff) << 8) + ((s >> 24) & 0xff));
  u = (((t & 0xff) << 24) + (((t >> 8) & 0xff) << 16) + (((t >> 16) & 0xff) << 8) + ((t >> 24) & 0xff));
  printf("s = %x, t = %x, u = %x \n", s, t, u);
  uint32_t nb = 2781;
  uint32_t nb2 = (((nb & 0xff) << 24) + (((nb >> 8) & 0xff) << 16) + (((nb >> 16) & 0xff) << 8) + ((nb >> 24) & 0xff));
  uint32_t nb3 = (((nb2 & 0xff) << 24) + (((nb2 >> 8) & 0xff) << 16) + (((nb2 >> 16) & 0xff) << 8) + ((nb2 >> 24) & 0xff));
  printf("nb = %u => %u => %u\n", nb, nb2, nb3);
  printf("nb = %x => %x => %x\n", nb, nb2, nb3);
  uint32_t nbframes = 2573;
  uint32_t nbframes2 = 2781;
  printf(" 2573 = %x\n", nbframes);
  printf(" 2781 = %x\n", nbframes2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xf,%edi
  call   <newNode@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <newNode@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x9,%edi
  call   <newNode@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x9,%edi
  call   <newNode@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <pathSumWithRoot@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: %d


assistant: ```c
int main() {
  struct TreeNode *n15 = newNode(15, NULL, NULL);
  struct TreeNode *n7 = newNode(7, NULL, NULL);
  struct TreeNode *n20 = newNode(9, n15, n7);
  struct TreeNode *n9 = newNode(9, NULL, NULL);
  struct TreeNode *n3 = newNode(3, n9, n20);
  printf("%d\n", pathSumWithRoot(n3, 12));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xf,%edi
  call   <newNode@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <newNode@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    $0x9,%edi
  call   <newNode@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x9,%edi
  call   <newNode@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdx
  mov    $0x3,%edi
  call   <newNode@plt>
  mov    %rax,%rdi
  mov    $0xc,%esi
  call   <pathSumWithRoot@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %d


assistant: ```c
int main() {
  struct TreeNode *n15 = newNode(15, NULL, NULL);
  struct TreeNode *n7 = newNode(7, NULL, NULL);
  struct TreeNode *n20 = newNode(9, n15, n7);
  struct TreeNode *n9 = newNode(9, NULL, NULL);
  struct TreeNode *n3 = newNode(3, n9, n20);
  printf("%d\n", pathSumWithRoot(n3, 12));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <newNode@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x7,%edi
  mov    %rax,%r12
  call   <newNode@plt>
  mov    %r12,%rsi
  mov    $0x9,%edi
  mov    %rax,%rdx
  call   <newNode@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x9,%edi
  mov    %rax,%r12
  call   <newNode@plt>
  mov    %r12,%rdx
  mov    $0x3,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <pathSumWithRoot@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  struct TreeNode *n15 = newNode(15, NULL, NULL);
  struct TreeNode *n7 = newNode(7, NULL, NULL);
  struct TreeNode *n20 = newNode(9, n15, n7);
  struct TreeNode *n9 = newNode(9, NULL, NULL);
  struct TreeNode *n3 = newNode(3, n9, n20);
  printf("%d\n", pathSumWithRoot(n3, 12));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <newNode@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x7,%edi
  mov    %rax,%r12
  call   <newNode@plt>
  mov    %r12,%rsi
  mov    $0x9,%edi
  mov    %rax,%rdx
  call   <newNode@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x9,%edi
  mov    %rax,%r12
  call   <newNode@plt>
  mov    %r12,%rdx
  mov    $0x3,%edi
  mov    %rax,%rsi
  call   <newNode@plt>
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <pathSumWithRoot@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %d


assistant: ```c
int main() {
  struct TreeNode *n15 = newNode(15, NULL, NULL);
  struct TreeNode *n7 = newNode(7, NULL, NULL);
  struct TreeNode *n20 = newNode(9, n15, n7);
  struct TreeNode *n9 = newNode(9, NULL, NULL);
  struct TreeNode *n3 = newNode(3, n9, n20);
  printf("%d\n", pathSumWithRoot(n3, 12));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <init_outbuf@plt>
  mov    $0x0,%eax
  call   <init@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <flush_outbuf@plt>
  nop
  leave
  ret
```

assistant: ```c
void run(int phase) {
  init_outbuf();
  init();
  match(phase);
  flush_outbuf();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<run>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <init_outbuf@plt>
  mov    $0x0,%eax
  call   <init@plt>
  mov    %ebx,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <flush_outbuf@plt>
  pop    %rbx
  ret
```

assistant: ```c
void run(int phase) {
  init_outbuf();
  init();
  match(phase);
  flush_outbuf();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<run>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <init_outbuf@plt>
  xor    %eax,%eax
  call   <init@plt>
  mov    %ebp,%edi
  call   <match@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <flush_outbuf@plt>
```

assistant: ```c
void run(int phase) {
  init_outbuf();
  init();
  match(phase);
  flush_outbuf();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<run>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <init_outbuf@plt>
  xor    %eax,%eax
  call   <init@plt>
  mov    %ebp,%edi
  call   <match@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <flush_outbuf@plt>
```

assistant: ```c
void run(int phase) {
  init_outbuf();
  init();
  match(phase);
  flush_outbuf();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2d,%eax
  je     L64
  cmp    $0x2d,%eax
  jg     L11
  cmp    $0x2b,%eax
  je     L52
  cmp    $0x2b,%eax
  jg     L11
  cmp    $0x9,%eax
  je     L108
  cmp    $0x20,%eax
  jne    L11
  jmp    L108
L64:
  addl   $0x1,-0xc(%rbp)
L52:
  addq   $0x1,-0x18(%rbp)
  jmp    L11
L108:
  nop
  addq   $0x1,-0x18(%rbp)
  jmp    L49
L11:
  nop
  jmp    L3
L72:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L72
L28:
  cmpl   $0x0,-0xc(%rbp)
  je     L136
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L82
L136:
  mov    -0x8(%rbp),%rax
L82:
  pop    %rbp
  ret
```

assistant: ```c
long atol(char *p) {
  long n;
  int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9') {
    n = n * 10 + *p++ - '0';
  }
  return (f ? -n : n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atol>:
  endbr64
L11:
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L55
  jg     L33
  cmp    $0x9,%al
  je     L86
  cmp    $0x20,%al
  jne    L8
L86:
  add    $0x1,%rdi
  jmp    L11
L8:
  mov    $0x0,%esi
  jmp    L31
L33:
  mov    $0x1,%esi
  cmp    $0x2d,%al
  jne    L1
L78:
  add    $0x1,%rdi
L31:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  ja     L40
L104:
  add    $0x1,%rdi
  lea    (%rdx,%rdx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L104
L40:
  mov    %rdx,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%rdx
  mov    %rdx,%rax
  ret
L1:
  mov    $0x0,%esi
  jmp    L31
L55:
  mov    $0x0,%esi
  jmp    L78
```

assistant: ```c
long atol(char *p) {
  long n;
  int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9') {
    n = n * 10 + *p++ - '0';
  }
  return (f ? -n : n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x2b,%al
  je     L30
L80:
  jg     L53
  cmp    $0x9,%al
  je     L90
  cmp    $0x20,%al
  jne    L76
L90:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L80
L30:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
L24:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L76
L49:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L79:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rdx
  movsbq (%rdi),%rax
  lea    -0x30(%rdx),%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L79
  mov    $0x30,%eax
  sub    %rdx,%rax
  test   %esi,%esi
  cmovne %rax,%r8
L58:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L53:
  cmp    $0x2d,%al
  jne    L24
  movsbq 0x1(%rdi),%rax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L49
L76:
  xor    %r8d,%r8d
  jmp    L58
```

assistant: ```c
long atol(char *p) {
  long n;
  int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9') {
    n = n * 10 + *p++ - '0';
  }
  return (f ? -n : n);
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  movsbq (%rdi),%rax
  cmp    $0x2b,%al
  je     L7
L82:
  jg     L63
  cmp    $0x9,%al
  je     L24
  cmp    $0x20,%al
  jne    L94
L24:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  cmp    $0x2b,%al
  jne    L82
L7:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
L88:
  lea    -0x30(%rax),%edx
  xor    %esi,%esi
  cmp    $0x9,%dl
  ja     L94
L81:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L66:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rdx
  movsbq (%rdi),%rax
  lea    -0x30(%rdx),%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L66
  mov    $0x30,%eax
  sub    %rdx,%rax
  test   %esi,%esi
  cmovne %rax,%r8
L59:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L63:
  cmp    $0x2d,%al
  jne    L88
  movsbq 0x1(%rdi),%rax
  mov    $0x1,%esi
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L81
L94:
  xor    %r8d,%r8d
  jmp    L59
```

assistant: ```c
long atol(char *p) {
  long n;
  int f;
  n = 0;
  f = 0;
  for (;; p++) {
    switch (*p) {
    case ' ':
    case '\t':
      continue;
    case '-':
      f++;
    case '+':
      p++;
    }
    break;
  }
  while (*p >= '0' && *p <= '9') {
    n = n * 10 + *p++ - '0';
  }
  return (f ? -n : n);
}
```