ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdi
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: %016lx %016lx %016lx %016lx: %s


assistant: ```c
void print_output(void *_output, const char *test) {
  long *output = _output;
  printf("%016lx %016lx %016lx %016lx: %s\n", output[0], output[1], output[2], output[3], test);
  memset(output, 0, 32);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_output>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r9
  mov    0x10(%rdi),%rcx
  mov    0x8(%rdi),%rdx
  mov    0x18(%rdi),%r8
  mov    (%rdi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: %016lx %016lx %016lx %016lx: %s


assistant: ```c
void print_output(void *_output, const char *test) {
  long *output = _output;
  printf("%016lx %016lx %016lx %016lx: %s\n", output[0], output[1], output[2], output[3], test);
  memset(output, 0, 32);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_output>:
  endbr64
  push   %rbp
  mov    %rsi,%r9
  mov    0x8(%rdi),%rdx
  mov    %rdi,%rbp
  mov    (%rdi),%rsi
  mov    0x10(%rdi),%rcx
  mov    0x18(%rdi),%r8
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x20,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %016lx %016lx %016lx %016lx: %s


assistant: ```c
void print_output(void *_output, const char *test) {
  long *output = _output;
  printf("%016lx %016lx %016lx %016lx: %s\n", output[0], output[1], output[2], output[3], test);
  memset(output, 0, 32);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_output>:
  endbr64
  push   %rbp
  mov    %rsi,%r9
  mov    0x8(%rdi),%rdx
  mov    %rdi,%rbp
  mov    (%rdi),%rsi
  mov    0x10(%rdi),%rcx
  mov    0x18(%rdi),%r8
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x20,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: %016lx %016lx %016lx %016lx: %s


assistant: ```c
void print_output(void *_output, const char *test) {
  long *output = _output;
  printf("%016lx %016lx %016lx %016lx: %s\n", output[0], output[1], output[2], output[3], test);
  memset(output, 0, 32);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <standard@plt>
  mov    $0x0,%eax
  call   <stack_align@plt>
  mov    $0x0,%eax
  call   <gdb1253@plt>
  mov    $0x0,%eax
  call   <gdb1718@plt>
  mov    $0x0,%eax
  call   <gdb1338@plt>
  mov    $0x0,%eax
  call   <jump_at_beginning@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  standard();
  stack_align();
  gdb1253();
  gdb1718();
  gdb1338();
  jump_at_beginning();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <standard@plt>
  mov    $0x0,%eax
  call   <stack_align@plt>
  mov    $0x0,%eax
  call   <gdb1253@plt>
  mov    $0x0,%eax
  call   <gdb1718@plt>
  mov    $0x0,%eax
  call   <gdb1338@plt>
  mov    $0x0,%eax
  call   <jump_at_beginning@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  standard();
  stack_align();
  gdb1253();
  gdb1718();
  gdb1338();
  jump_at_beginning();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <standard@plt>
  xor    %eax,%eax
  call   <stack_align@plt>
  xor    %eax,%eax
  call   <gdb1253@plt>
  xor    %eax,%eax
  call   <gdb1718@plt>
  xor    %eax,%eax
  call   <gdb1338@plt>
  xor    %eax,%eax
  call   <jump_at_beginning@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  standard();
  stack_align();
  gdb1253();
  gdb1718();
  gdb1338();
  jump_at_beginning();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <standard@plt>
  xor    %eax,%eax
  call   <stack_align@plt>
  xor    %eax,%eax
  call   <gdb1253@plt>
  xor    %eax,%eax
  call   <gdb1718@plt>
  xor    %eax,%eax
  call   <gdb1338@plt>
  xor    %eax,%eax
  call   <jump_at_beginning@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  standard();
  stack_align();
  gdb1253();
  gdb1718();
  gdb1338();
  jump_at_beginning();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_isvalid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  jmp    L39
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L26
L1:
  addq   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isvalid(char c, const char *to_avoid) {
  while (*to_avoid != '\0') {
    if (*to_avoid == c)
      return (0);
    ++to_avoid;
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_isvalid>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L26
L4:
  cmp    %al,%dil
  je     L9
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L4
  mov    $0x1,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_isvalid(char c, const char *to_avoid) {
  while (*to_avoid != '\0') {
    if (*to_avoid == c)
      return (0);
    ++to_avoid;
  }
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isvalid>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmp    %al,%dil
  je     L26
  add    $0x1,%rsi
L16:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L13
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isvalid(char c, const char *to_avoid) {
  while (*to_avoid != '\0') {
    if (*to_avoid == c)
      return (0);
    ++to_avoid;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_isvalid>:
  endbr64
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L10:
  cmp    %al,%dil
  je     L13
  add    $0x1,%rsi
L15:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L10
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isvalid(char c, const char *to_avoid) {
  while (*to_avoid != '\0') {
    if (*to_avoid == c)
      return (0);
    ++to_avoid;
  }
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L56
L114:
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L114
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L114
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L114
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  jmp    L1
L108:
  subl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L108
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L108
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L108
L11:
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L92
  cmpq   $0x0,-0x28(%rbp)
  jne    L69
L92:
  mov    $0x0,%eax
  jmp    L29
L71:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L71
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L29:
  leave
  ret
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int i;
  int count;
  int len;
  char *strim;
  i = 0;
  count = 0;
  len = ft_strlen(s);
  while ((s[i] == ' ') || (s[i] == '\n') || (s[i] == '\t'))
    i++;
  if (s[i])
    while (s[len - 1] == ' ' || s[len - 1] == '\n' || s[len - 1] == '\t')
      len--;
  strim = malloc(sizeof(char *) * (len - i) + 1);
  if (!strim || !s)
    return (NULL);
  while (count < (len - i)) {
    strim[count] = s[i + count];
    count++;
  }
  strim[count] = '\0';
  return (strim);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_strtrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  movzbl (%rbx),%ecx
  lea    -0x9(%rcx),%edx
  cmp    $0x1,%dl
  jbe    L65
  cmp    $0x20,%cl
  jne    L125
L65:
  mov    $0x1,%edx
L52:
  mov    %edx,%ebp
  movzbl (%rbx,%rdx,1),%ecx
  add    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L52
  cmp    $0x20,%cl
  je     L52
L12:
  test   %cl,%cl
  je     L17
  movslq %eax,%rdx
  movzbl -0x1(%rbx,%rdx,1),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L67
  cmp    $0x20,%dl
  jne    L17
L67:
  sub    $0x1,%eax
  movslq %eax,%rdx
L97:
  mov    %edx,%eax
  movzbl -0x1(%rbx,%rdx,1),%ecx
  sub    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L97
  cmp    $0x20,%cl
  je     L97
L17:
  sub    %ebp,%eax
  mov    %eax,%r12d
  lea    0x1(,%rax,8),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L34
  test   %r12d,%r12d
  jle    L108
  mov    %r12d,%esi
  mov    $0x0,%edx
  movslq %ebp,%rbp
  add    %rbp,%rbx
L119:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L119
L77:
  movslq %r12d,%r12
  movb   $0x0,(%rax,%r12,1)
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L125:
  mov    $0x0,%ebp
  jmp    L12
L108:
  mov    $0x0,%r12d
  jmp    L77
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int i;
  int count;
  int len;
  char *strim;
  i = 0;
  count = 0;
  len = ft_strlen(s);
  while ((s[i] == ' ') || (s[i] == '\n') || (s[i] == '\t'))
    i++;
  if (s[i])
    while (s[len - 1] == ' ' || s[len - 1] == '\n' || s[len - 1] == '\t')
      len--;
  strim = malloc(sizeof(char *) * (len - i) + 1);
  if (!strim || !s)
    return (NULL);
  while (count < (len - i)) {
    strim[count] = s[i + count];
    count++;
  }
  strim[count] = '\0';
  return (strim);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_strtrim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  movzbl (%rbx),%ecx
  lea    -0x9(%rcx),%edx
  cmp    $0x1,%dl
  jbe    L116
  cmp    $0x20,%cl
  jne    L17
L116:
  mov    $0x1,%edx
  nop
L118:
  movzbl (%rbx,%rdx,1),%ecx
  movslq %edx,%rbp
  add    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L118
  cmp    $0x20,%cl
  je     L118
L69:
  test   %cl,%cl
  je     L98
  movslq %eax,%rcx
  lea    -0x1(%rcx),%rdx
  movzbl -0x1(%rbx,%rcx,1),%ecx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  ja     L94
  nopw   0x0(%rax,%rax,1)
L55:
  movzbl -0x1(%rbx,%rdx,1),%ecx
  mov    %edx,%eax
  sub    $0x1,%rdx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L55
L94:
  cmp    $0x20,%cl
  je     L55
L98:
  sub    %ebp,%eax
  movslq %eax,%r13
  lea    0x1(,%r13,8),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L80
  test   %r13d,%r13d
  jle    L96
  xor    %edx,%edx
  add    %rbp,%rbx
  nopw   0x0(%rax,%rax,1)
L107:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%r13
  jne    L107
  add    %rax,%r13
L88:
  movb   $0x0,0x0(%r13)
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  xor    %ebp,%ebp
  jmp    L69
L96:
  mov    %rax,%r13
  jmp    L88
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int i;
  int count;
  int len;
  char *strim;
  i = 0;
  count = 0;
  len = ft_strlen(s);
  while ((s[i] == ' ') || (s[i] == '\n') || (s[i] == '\t'))
    i++;
  if (s[i])
    while (s[len - 1] == ' ' || s[len - 1] == '\n' || s[len - 1] == '\t')
      len--;
  strim = malloc(sizeof(char *) * (len - i) + 1);
  if (!strim || !s)
    return (NULL);
  while (count < (len - i)) {
    strim[count] = s[i + count];
    count++;
  }
  strim[count] = '\0';
  return (strim);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skipchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  jmp    L1
L13:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  je     L13
L4:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *skipchar(const char *string, char tok) {
  while (*string != 0 && *string == tok)
    string++;
  return string;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skipchar>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  movzbl (%rdi),%edx
  cmp    %sil,%dl
  jne    L30
  test   %dl,%dl
  je     L30
L7:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  jne    L30
  test   %dl,%dl
  jne    L7
L30:
  ret
```

assistant: ```c
const char *skipchar(const char *string, char tok) {
  while (*string != 0 && *string == tok)
    string++;
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skipchar>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    %sil,%dl
  je     L0
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L10
L0:
  test   %dl,%dl
  jne    L27
L10:
  ret
```

assistant: ```c
const char *skipchar(const char *string, char tok) {
  while (*string != 0 && *string == tok)
    string++;
  return string;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipchar>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    %sil,%dl
  je     L6
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L4
L6:
  test   %dl,%dl
  jne    L36
L4:
  ret
```

assistant: ```c
const char *skipchar(const char *string, char tok) {
  while (*string != 0 && *string == tok)
    string++;
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cheia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x31,-0x4(%rbp)
  jne    L6
  mov    $0x1,%eax
  jmp    L16
L6:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int cheia(int fimLista) {
  if (fimLista + 1 == 50) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cheia>:
  endbr64
  cmp    $0x31,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int cheia(int fimLista) {
  if (fimLista + 1 == 50) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cheia>:
  endbr64
  xor    %eax,%eax
  cmp    $0x31,%edi
  sete   %al
  ret
```

assistant: ```c
int cheia(int fimLista) {
  if (fimLista + 1 == 50) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quat_rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movss  %xmm1,-0x30(%rbp)
  movss  %xmm2,-0x34(%rbp)
  movss  %xmm3,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm2,%xmm2
  cvtss2sd -0x38(%rbp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x34(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x30(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x2c(%rbp),%xmm4
  movq   %xmm4,%rdx
  lea    -0x20(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <quat_from_axis@plt>
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <quat_mul@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void quat_rotate(const float q[4], float a, float x, float y, float z, float out[4]) {
  float other[4];
  quat_from_axis(other, a, x, y, z);
  quat_mul(q, other, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quat_rotate>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cvtss2sd %xmm0,%xmm0
  mov    %rsp,%r12
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  mov    %r12,%rdi
  mov    $0x4,%eax
  call   <quat_from_axis@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <quat_mul@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quat_rotate(const float q[4], float a, float x, float y, float z, float out[4]) {
  float other[4];
  quat_from_axis(other, a, x, y, z);
  quat_mul(q, other, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quat_rotate>:
  endbr64
  push   %r13
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm2
  push   %r12
  mov    %rsi,%r12
  cvtss2sd %xmm1,%xmm1
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0x4,%eax
  mov    %r13,%rdi
  call   <quat_from_axis@plt>
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <quat_mul@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quat_rotate(const float q[4], float a, float x, float y, float z, float out[4]) {
  float other[4];
  quat_from_axis(other, a, x, y, z);
  quat_mul(q, other, out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quat_rotate>:
  endbr64
  push   %r13
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm2
  push   %r12
  mov    %rsi,%r12
  cvtss2sd %xmm1,%xmm1
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0x4,%eax
  mov    %r13,%rdi
  call   <quat_from_axis@plt>
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <quat_mul@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void quat_rotate(const float q[4], float a, float x, float y, float z, float out[4]) {
  float other[4];
  quat_from_axis(other, a, x, y, z);
  quat_mul(q, other, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L25:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L25
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string

tool: D14: %d

tool: D34: %d


assistant: ```c
int main() {
  int monthly;
  scanf("%d", &monthly);
  int n;
  scanf("%d", &n);
  int total = 0, i;
  for (i = 0; i < n; i++) {
    int next;
    scanf("%d", &next);
    total += next;
  }
  printf("%d\n", (n + 1) * monthly - total);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L2
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D29(%rip),%r12
L0:
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x14(%rsp),%ebp
  add    $0x1,%ebx
  mov    0x10(%rsp),%eax
  cmp    %ebx,%eax
  jg     L0
L20:
  lea    0x1(%rax),%esi
  imul   0xc(%rsp),%esi
  sub    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0x0,%ebp
  jmp    L20
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type: string
name: unpack_data
arguments: data_tag: D9
type: string

tool: D29: %d

tool: D9: %d


assistant: ```c
int main() {
  int monthly;
  scanf("%d", &monthly);
  int n;
  scanf("%d", &n);
  int total = 0, i;
  for (i = 0; i < n; i++) {
    int next;
    scanf("%d", &next);
    total += next;
  }
  printf("%d\n", (n + 1) * monthly - total);
  return 0;
}
```