ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bs>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mov    %rdi,%rbx
  subsd  %xmm3,%xmm0
  sub    $0x20,%rsp
  comisd D37(%rip),%xmm0
  jbe    L13
  nopw   0x0(%rax,%rax,1)
L33:
  movapd %xmm3,%xmm2
  movsd  %xmm1,0x10(%rsp)
  addsd  %xmm1,%xmm2
  mulsd  D28(%rip),%xmm2
  movsd  %xmm3,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rbx
  pxor   %xmm4,%xmm4
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  comisd %xmm4,%xmm0
  jbe    L27
  movsd  0x18(%rsp),%xmm3
  movapd %xmm2,%xmm0
  subsd  %xmm3,%xmm0
  comisd D37(%rip),%xmm0
  jbe    L13
  movapd %xmm2,%xmm1
  jmp    L33
  nopl   0x0(%rax)
L27:
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm3
  subsd  %xmm2,%xmm0
  comisd D37(%rip),%xmm0
  ja     L33
L13:
  add    $0x20,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D37
datatype: byte[16]
name: parse_data
arguments: tag: D28
datatype: byte[8]

tool: {"D37": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double bs(double a, double b, double (*f)(double)) {
  while (b - a > 1e-6) {
    double m = (a + b) / 2;
    if (f(m) > 0)
      b = m;
    else
      a = m;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<popcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L1
L28:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L20
  addb   $0x1,-0x1(%rbp)
L20:
  shrl   -0x14(%rbp)
L1:
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char popcount(unsigned int bits) {
  unsigned char count = 0;
  while (bits) {
    if (bits & 0X1)
      count += 1;
    bits >>= 1;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<popcount>:
  endbr64
  test   %edi,%edi
  je     L2
  mov    $0x0,%eax
L1:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  shr    %edi
  jne    L1
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char popcount(unsigned int bits) {
  unsigned char count = 0;
  while (bits) {
    if (bits & 0X1)
      count += 1;
    bits >>= 1;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<popcount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L18
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  shr    %edi
  jne    L3
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
unsigned char popcount(unsigned int bits) {
  unsigned char count = 0;
  while (bits) {
    if (bits & 0X1)
      count += 1;
    bits >>= 1;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<popcount>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L19
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edi,%edx
  and    $0x1,%edx
  add    %edx,%eax
  shr    %edi
  jne    L15
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
unsigned char popcount(unsigned int bits) {
  unsigned char count = 0;
  while (bits) {
    if (bits & 0X1)
      count += 1;
    bits >>= 1;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strremovelower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movb   $0x61,-0x19(%rbp)
  jmp    L11
L24:
  movsbl -0x19(%rbp),%edx
  lea    -0xa(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0xa(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strreplace@plt>
  mov    %rax,-0x18(%rbp)
  movzbl -0x19(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x19(%rbp)
L11:
  cmpb   $0x7a,-0x19(%rbp)
  jle    L24
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string

tool: D7: %c

tool: 

assistant: ```c
const char *strremovelower(const char *orig) {
  char *str = (char *)orig;
  for (char c = 'a'; c <= 'z'; c++) {
    char buf[2];
    sprintf(buf, "%c", c);
    str = (char *)strreplace(str, buf, "");
  }
  return (const char *)str;
}
```
user: What is the c source code of the assembly code below:

```asm
<strremovelower>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x61,%ebp
  lea    0x6(%rsp),%r12
  lea    D11(%rip),%r14
  lea    D14(%rip),%r13
L10:
  mov    %ebp,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strreplace@plt>
  mov    %rax,%rbx
  add    $0x1,%ebp
  cmp    $0x7b,%ebp
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D11: %c

tool: 

assistant: ```c
const char *strremovelower(const char *orig) {
  char *str = (char *)orig;
  for (char c = 'a'; c <= 'z'; c++) {
    char buf[2];
    sprintf(buf, "%c", c);
    str = (char *)strreplace(str, buf, "");
  }
  return (const char *)str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strremovelower>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x61,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <strreplace@plt>
  mov    %rax,%rbp
  cmp    $0x7b,%ebx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D0: %c

tool: 

assistant: ```c
const char *strremovelower(const char *orig) {
  char *str = (char *)orig;
  for (char c = 'a'; c <= 'z'; c++) {
    char buf[2];
    sprintf(buf, "%c", c);
    str = (char *)strreplace(str, buf, "");
  }
  return (const char *)str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strremovelower>:
  endbr64
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x61,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <strreplace@plt>
  mov    %rax,%rbp
  cmp    $0x7b,%ebx
  jne    L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string

tool: D18: %c

tool: 

assistant: ```c
const char *strremovelower(const char *orig) {
  char *str = (char *)orig;
  for (char c = 'a'; c <= 'z'; c++) {
    char buf[2];
    sprintf(buf, "%c", c);
    str = (char *)strreplace(str, buf, "");
  }
  return (const char *)str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_drawCEmptyCircle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <_drawPixel@plt>
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <_drawPixel@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L11
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void _drawCEmptyCircle(int x, int y, int radius) {
  int deltax = radius;
  int deltay = 0;
  int err = 0;
  while (deltax >= deltay) {
    _drawPixel(x + deltax, y + deltay);
    _drawPixel(x + deltay, y + deltax);
    _drawPixel(x - deltay, y + deltax);
    _drawPixel(x - deltax, y + deltay);
    _drawPixel(x - deltax, y - deltay);
    _drawPixel(x - deltay, y - deltax);
    _drawPixel(x + deltay, y - deltax);
    _drawPixel(x + deltax, y - deltay);
    deltay += 1;
    err += 1 + 2 * deltay;
    if (2 * (err - deltax) + 1 > 0) {
      deltax -= 1;
      err += 1 - 2 * deltax;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_drawCEmptyCircle>:
  endbr64
  test   %edx,%edx
  js     L8
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  jmp    L24
L36:
  sub    $0x1,%ebx
  lea    (%rbx,%rbx,1),%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  add    %eax,%r14d
L46:
  cmp    %ebp,%ebx
  jl     L38
L24:
  lea    0x0(%r13,%rbp,1),%eax
  lea    (%r12,%rbx,1),%edx
  mov    %eax,0x4(%rsp)
  mov    %eax,%esi
  mov    %edx,(%rsp)
  mov    %edx,%edi
  call   <_drawPixel@plt>
  lea    0x0(%r13,%rbx,1),%r15d
  lea    0x0(%rbp,%r12,1),%ecx
  mov    %r15d,%esi
  mov    %ecx,0x8(%rsp)
  mov    %ecx,%edi
  call   <_drawPixel@plt>
  mov    %r12d,%eax
  sub    %ebp,%eax
  mov    %r15d,%esi
  mov    %eax,0xc(%rsp)
  mov    %eax,%edi
  call   <_drawPixel@plt>
  mov    %r12d,%r15d
  sub    %ebx,%r15d
  mov    0x4(%rsp),%esi
  mov    %r15d,%edi
  call   <_drawPixel@plt>
  mov    %r13d,%ecx
  sub    %ebp,%ecx
  mov    %ecx,0x4(%rsp)
  mov    %ecx,%esi
  mov    %r15d,%edi
  call   <_drawPixel@plt>
  mov    %r13d,%r15d
  sub    %ebx,%r15d
  mov    %r15d,%esi
  mov    0xc(%rsp),%edi
  call   <_drawPixel@plt>
  mov    %r15d,%esi
  mov    0x8(%rsp),%edi
  call   <_drawPixel@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <_drawPixel@plt>
  add    $0x1,%ebp
  lea    0x1(%r14,%rbp,2),%r14d
  cmp    %ebx,%r14d
  jge    L36
  jmp    L46
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  ret
```

assistant: ```c
void _drawCEmptyCircle(int x, int y, int radius) {
  int deltax = radius;
  int deltay = 0;
  int err = 0;
  while (deltax >= deltay) {
    _drawPixel(x + deltax, y + deltay);
    _drawPixel(x + deltay, y + deltax);
    _drawPixel(x - deltay, y + deltax);
    _drawPixel(x - deltax, y + deltay);
    _drawPixel(x - deltax, y - deltay);
    _drawPixel(x - deltay, y - deltax);
    _drawPixel(x + deltay, y - deltax);
    _drawPixel(x + deltax, y - deltay);
    deltay += 1;
    err += 1 + 2 * deltay;
    if (2 * (err - deltax) + 1 > 0) {
      deltax -= 1;
      err += 1 - 2 * deltax;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_drawCEmptyCircle>:
  endbr64
  test   %edx,%edx
  js     L10
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L4:
  lea    0x0(%rbp,%r13,1),%r9d
  lea    (%r12,%rbx,1),%r15d
  mov    %r9d,%esi
  mov    %r15d,%edi
  mov    %r9d,0x4(%rsp)
  call   <_drawPixel@plt>
  lea    (%r12,%rbp,1),%r10d
  lea    0x0(%r13,%rbx,1),%esi
  mov    %r10d,%edi
  mov    %r10d,0xc(%rsp)
  mov    %esi,(%rsp)
  call   <_drawPixel@plt>
  mov    %r12d,%r11d
  mov    (%rsp),%esi
  sub    %ebp,%r11d
  mov    %r11d,%edi
  mov    %r11d,0x8(%rsp)
  call   <_drawPixel@plt>
  mov    0x4(%rsp),%esi
  mov    %r12d,%edi
  sub    %ebx,%edi
  mov    %edi,(%rsp)
  call   <_drawPixel@plt>
  mov    %r13d,%r9d
  mov    (%rsp),%edi
  sub    %ebp,%r9d
  add    $0x1,%ebp
  mov    %r9d,%esi
  mov    %r9d,0x4(%rsp)
  lea    0x1(%r14,%rbp,2),%r14d
  call   <_drawPixel@plt>
  mov    0x8(%rsp),%edi
  mov    %r13d,%esi
  sub    %ebx,%esi
  mov    %esi,(%rsp)
  call   <_drawPixel@plt>
  mov    (%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <_drawPixel@plt>
  mov    0x4(%rsp),%esi
  mov    %r15d,%edi
  call   <_drawPixel@plt>
  cmp    %ebx,%r14d
  jl     L11
  sub    $0x1,%ebx
  mov    $0x1,%eax
  lea    (%rbx,%rbx,1),%edx
  sub    %edx,%eax
  add    %eax,%r14d
L11:
  cmp    %ebp,%ebx
  jge    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void _drawCEmptyCircle(int x, int y, int radius) {
  int deltax = radius;
  int deltay = 0;
  int err = 0;
  while (deltax >= deltay) {
    _drawPixel(x + deltax, y + deltay);
    _drawPixel(x + deltay, y + deltax);
    _drawPixel(x - deltay, y + deltax);
    _drawPixel(x - deltax, y + deltay);
    _drawPixel(x - deltax, y - deltay);
    _drawPixel(x - deltay, y - deltax);
    _drawPixel(x + deltay, y - deltax);
    _drawPixel(x + deltax, y - deltay);
    deltay += 1;
    err += 1 + 2 * deltay;
    if (2 * (err - deltax) + 1 > 0) {
      deltax -= 1;
      err += 1 - 2 * deltax;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_drawCEmptyCircle>:
  endbr64
  test   %edx,%edx
  js     L34
  push   %r15
  xor    %ecx,%ecx
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x1,%r15d
  mov    $0x1,%eax
  lea    (%r15,%r15,1),%esi
  sub    %esi,%eax
  add    %eax,%ecx
  cmp    %r15d,%ebx
  jg     L23
L31:
  lea    (%r12,%r15,1),%r14d
  lea    0x0(%rbp,%r15,1),%r13d
L21:
  lea    (%rbx,%rbp,1),%r8d
  mov    %r14d,%edi
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,%esi
  mov    %r8d,0xc(%rsp)
  call   <_drawPixel@plt>
  lea    (%r12,%rbx,1),%r9d
  mov    %r13d,%esi
  mov    %r9d,%edi
  mov    %r9d,0x18(%rsp)
  call   <_drawPixel@plt>
  mov    %r12d,%r10d
  mov    %r13d,%esi
  sub    %ebx,%r10d
  mov    %r10d,%edi
  mov    %r10d,0x14(%rsp)
  call   <_drawPixel@plt>
  mov    0xc(%rsp),%esi
  mov    %r12d,%edi
  sub    %r15d,%edi
  mov    %edi,0xc(%rsp)
  call   <_drawPixel@plt>
  mov    %ebp,%r8d
  mov    0xc(%rsp),%edi
  sub    %ebx,%r8d
  add    $0x1,%ebx
  mov    %r8d,%esi
  mov    %r8d,0x10(%rsp)
  call   <_drawPixel@plt>
  mov    0x14(%rsp),%edi
  mov    %ebp,%esi
  sub    %r15d,%esi
  mov    %esi,0xc(%rsp)
  call   <_drawPixel@plt>
  mov    0xc(%rsp),%esi
  mov    0x18(%rsp),%edi
  call   <_drawPixel@plt>
  mov    0x10(%rsp),%esi
  mov    %r14d,%edi
  call   <_drawPixel@plt>
  mov    0x1c(%rsp),%ecx
  lea    0x1(%rcx,%rbx,2),%ecx
  cmp    %r15d,%ecx
  jge    L17
  cmp    %r15d,%ebx
  jle    L21
L23:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  ret
```

assistant: ```c
void _drawCEmptyCircle(int x, int y, int radius) {
  int deltax = radius;
  int deltay = 0;
  int err = 0;
  while (deltax >= deltay) {
    _drawPixel(x + deltax, y + deltay);
    _drawPixel(x + deltay, y + deltax);
    _drawPixel(x - deltay, y + deltax);
    _drawPixel(x - deltax, y + deltay);
    _drawPixel(x - deltax, y - deltay);
    _drawPixel(x - deltay, y - deltax);
    _drawPixel(x + deltay, y - deltax);
    _drawPixel(x + deltax, y - deltay);
    deltay += 1;
    err += 1 + 2 * deltay;
    if (2 * (err - deltax) + 1 > 0) {
      deltax -= 1;
      err += 1 - 2 * deltax;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ckTerminalPrintString_unsafe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ckTerminalPutChar_unsafe@plt>
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void ckTerminalPrintString_unsafe(const char *str) {
  while (*str != '\0')
    ckTerminalPutChar_unsafe(*str++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ckTerminalPrintString_unsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L7:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <ckTerminalPutChar_unsafe@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L7
L8:
  pop    %rbx
  ret
```

assistant: ```c
void ckTerminalPrintString_unsafe(const char *str) {
  while (*str != '\0')
    ckTerminalPutChar_unsafe(*str++);
}
```
user: What is the c source code of the assembly code below:

```asm
<ckTerminalPrintString_unsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L4:
  call   <ckTerminalPutChar_unsafe@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L4
L2:
  pop    %rbx
  ret
```

assistant: ```c
void ckTerminalPrintString_unsafe(const char *str) {
  while (*str != '\0')
    ckTerminalPutChar_unsafe(*str++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ckTerminalPrintString_unsafe>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L15:
  call   <ckTerminalPutChar_unsafe@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L0:
  pop    %rbx
  ret
```

assistant: ```c
void ckTerminalPrintString_unsafe(const char *str) {
  while (*str != '\0')
    ckTerminalPutChar_unsafe(*str++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6e616d2066726144,%rax
  movabs $0x63696c6b72697720,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x656972206f732068,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x6e656863,-0x18(%rbp)
  movw   $0x3f,-0x14(%rbp)
  movb   $0x21,-0x3d(%rbp)
  movl   $0x0,-0x3c(%rbp)
  lea    -0x3d(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L29
L5:
  mov    -0x3c(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  mov    %al,-0x3d(%rbp)
  movzbl -0x3d(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x3c(%rbp)
L29:
  movzbl -0x3d(%rbp),%eax
  test   %al,%al
  jne    L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  char string[] = "Darf man wirklich so riechen?";
  char ch = '!';
  int x = 0;
  char *c = &ch;
  while (ch != '\0') {
    ch = string[x];
    putchar(ch);
    x++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6e616d2066726144,%rax
  movabs $0x63696c6b72697720,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x656972206f732068,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x6e656863,0x18(%rsp)
  movw   $0x3f,0x1c(%rsp)
  mov    %rsp,%rbx
L2:
  movzbl (%rbx),%ebp
  movsbl %bpl,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  test   %bpl,%bpl
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char string[] = "Darf man wirklich so riechen?";
  char ch = '!';
  int x = 0;
  char *c = &ch;
  while (ch != '\0') {
    ch = string[x];
    putchar(ch);
    x++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x44,%ebx
  sub    $0x38,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  movl   $0x6e656863,0x18(%rsp)
  movabs $0x656972206f732068,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x3f,%eax
  mov    %ax,0x1c(%rsp)
  movaps %xmm0,(%rsp)
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl 0x0(%rbp),%ebx
  add    $0x1,%rbp
L24:
  movsbl %bl,%edi
  call   <putchar@plt>
  test   %bl,%bl
  jne    L27
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: byte[16]

tool: {"D8": [0x44,0x61,0x72,0x66,0x20,0x6d,0x61,0x6e,0x20,0x77,0x69,0x72,0x6b,0x6c,0x69,0x63]}

assistant: ```c
int main(void) {
  char string[] = "Darf man wirklich so riechen?";
  char ch = '!';
  int x = 0;
  char *c = &ch;
  while (ch != '\0') {
    ch = string[x];
    putchar(ch);
    x++;
  }
  return 0;
}
```