ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<ltrim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  ja     L4
  movslq %edx,%rbp
  test   %rbp,%rbp
  jle    L4
  mov    %rsi,%r13
  lea    -0x1(%rdi),%r15
  mov    %rdi,%r14
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L33:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  cmovne %rbx,%r14
L96:
  sub    $0x1,%rbx
  cmp    %rbx,%r15
  je     L99
L70:
  mov    %r13,%rax
  sub    %rbx,%rax
  cmp    %rbp,%rax
  jg     L99
L89:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L96
  cmp    %rbx,%r12
  jne    L33
  sub    $0x1,%rbx
  mov    %r12,%r14
  cmp    %rbx,%r15
  jne    L70
  nopw   0x0(%rax,%rax,1)
L99:
  cmp    %r12,%r14
  jbe    L46
  movsbl -0x1(%r14),%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r14
L46:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12,%r14
  jmp    L46
```

assistant: ```c
char *ltrim(char *c, char *b, int d) {
  char *a, *x;
  a = c;
  for (x = b - 1; x >= c && b - x <= d; x--)
    if (!isspace(x[0]) && (x == c || isspace(x[-1])))
      a = x;
  if (a > c && !isspace(a[-1]))
    a--;
  return (a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bisearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L65
L90:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   *%rdx
  cmp    $0x1,%eax
  je     L83
  cmp    $0x1,%eax
  jg     L65
  cmp    $0xffffffff,%eax
  je     L32
  test   %eax,%eax
  je     L75
  jmp    L65
L32:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L65
L83:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L65
L75:
  mov    -0x4(%rbp),%eax
  jmp    L61
L65:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L90
  mov    $0xffffffff,%eax
L61:
  leave
  ret
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *, const void *)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  sub    $0x1,%edx
  js     L15
  mov    %rsi,%r13
  mov    %ecx,%r14d
  mov    %r8,%r15
  mov    %edx,%r12d
  mov    $0x0,%ebp
  jmp    L2
L67:
  add    $0x1,%ebx
  cmp    $0xffffffff,%eax
  cmove  %ebx,%ebp
L42:
  cmp    %r12d,%ebp
  jg     L69
L2:
  lea    0x0(%rbp,%r12,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%edi
  imul   %r14d,%edi
  movslq %edi,%rdi
  add    0x8(%rsp),%rdi
  mov    %r13,%rsi
  call   *%r15
  test   %eax,%eax
  je     L33
  cmp    $0x1,%eax
  jne    L67
  lea    -0x1(%rbx),%r12d
  jmp    L42
L69:
  movl   $0xffffffff,0x4(%rsp)
L33:
  mov    0x4(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  movl   $0xffffffff,0x4(%rsp)
  jmp    L33
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *, const void *)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  sub    $0x1,%edx
  js     L22
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %r8,%r14
  mov    %edx,%r13d
  xor    %r15d,%r15d
L28:
  mov    0xc(%rsp),%edi
  lea    (%r15,%r13,1),%r12d
  mov    %rbp,%rsi
  sar    %r12d
  imul   %r12d,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  je     L42
  cmp    $0x1,%eax
  je     L48
  add    $0x1,%r12d
  cmp    $0xffffffff,%eax
  cmove  %r12d,%r15d
L18:
  cmp    %r15d,%r13d
  jge    L28
L22:
  mov    $0xffffffff,%r12d
L42:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  lea    -0x1(%r12),%r13d
  jmp    L18
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *, const void *)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  sub    $0x1,%edx
  js     L7
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %r8,%r14
  mov    %edx,%r13d
  xor    %r15d,%r15d
L43:
  mov    0xc(%rsp),%edi
  lea    (%r15,%r13,1),%r12d
  mov    %rbp,%rsi
  sar    %r12d
  imul   %r12d,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  je     L39
  cmp    $0x1,%eax
  je     L45
  add    $0x1,%r12d
  cmp    $0xffffffff,%eax
  cmove  %r12d,%r15d
L12:
  cmp    %r15d,%r13d
  jge    L43
L7:
  mov    $0xffffffff,%r12d
L39:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  lea    -0x1(%r12),%r13d
  jmp    L12
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *, const void *)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L20
L7:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    $0x9,%eax
  jle    L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L0:
  mov    -0x14(%rbp),%eax
  cmp    $0xfffffff7,%eax
  jl     L48
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jg     L48
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L48:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L7
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D7
type: f64
name: extract_symbolic_data
arguments: data_tag: D49
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string

tool: D36: Enter an integer > 

tool: D4: %d

tool: D7: 10

tool: D49: %d


tool: D23: That's all, have a nice day!

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > ");
  scanf("%d", &Num);
  printf("\n");
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  printf("That's all, have a nice day!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  je     L69
  lea    D12(%rip),%r12
  jmp    L79
L24:
  mov    %ebx,%esi
  neg    %esi
  cmovs  %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L53:
  mov    %ebp,0x4(%rsp)
  test   %ebp,%ebp
  je     L69
L79:
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%ebx
  sub    %eax,%ebx
  mov    %ebp,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D0(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cmp    $0x9,%eax
  jg     L24
L31:
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L53
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L53
L69:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: f64
name: retrieve_data
arguments: data_label: D38
type_infered: string

tool: D39: Enter an integer > 

tool: D5: %d

tool: D12: %d


tool: D0: 10

tool: D38: That's all, have a nice day!

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > ");
  scanf("%d", &Num);
  printf("\n");
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  printf("That's all, have a nice day!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L25
  lea    D38(%rip),%r12
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L56
L30:
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  je     L25
L40:
  movslq %ebx,%rbp
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%edx
  imul   $0x66666667,%rbp,%rbp
  sar    $0x1f,%eax
  sar    $0x22,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,4),%eax
  mov    %ebx,%ebp
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  sub    %eax,%ebp
  mov    %edx,%eax
  divsd  D29(%rip),%xmm0
  neg    %eax
  cvttsd2si %xmm0,%ebx
  cmovs  %edx,%eax
  cmp    $0x9,%eax
  jle    L4
  mov    %ebp,%esi
  mov    %r12,%rdi
  neg    %esi
  cmovs  %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L30
L56:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,0x4(%rsp)
  test   %ebx,%ebx
  jne    L40
L25:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D40
type_guessed: string
name: read_data
arguments: data_label: D38
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: f64
name: read_data
arguments: data_label: D49
type_guessed: string

tool: D22: Enter an integer > 

tool: D40: %d

tool: D38: %d


tool: D29: 10

tool: D49: That's all, have a nice day!

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > ");
  scanf("%d", &Num);
  printf("\n");
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  printf("That's all, have a nice day!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L58
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L54
L5:
  mov    %r12d,0x4(%rsp)
  test   %r12d,%r12d
  je     L36
L48:
  mov    %r12d,%eax
L58:
  movslq %eax,%rbp
  cltd
  pxor   %xmm0,%xmm0
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  mov    %eax,%ebp
  add    %edx,%edx
  cvtsi2sd %edx,%xmm0
  sub    %edx,%ebp
  mov    %eax,%edx
  divsd  D23(%rip),%xmm0
  neg    %edx
  cvttsd2si %xmm0,%r12d
  cmovs  %eax,%edx
  cmp    $0x9,%edx
  jle    L9
  mov    %ebp,%esi
  mov    %rbx,%rdi
  neg    %esi
  cmovs  %ebp,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L5
L54:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,0x4(%rsp)
  test   %r12d,%r12d
  jne    L48
L36:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D33
type: string
name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D23
type: f64
name: read_data
arguments: data_label: D3
type: string

tool: D8: Enter an integer > 

tool: D33: %d


tool: D11: %d

tool: D23: 10

tool: D3: That's all, have a nice day!

assistant: ```c
int main() {
  int X, Num, NewNum;
  printf("Enter an integer > ");
  scanf("%d", &Num);
  printf("\n");
  while (Num) {
    X = Num % 10;
    NewNum = (Num - X) / 10.0;
    if (abs(Num) >= 10) {
      printf("%d\n", abs(X));
    }
    if (abs(Num) < 10) {
      printf("%d\n", X);
    }
    Num = NewNum;
  }
  printf("That's all, have a nice day!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun_stub_base_11_stub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: fun_stub_base_11_stub:a = %lld 


assistant: ```c
int fun_stub_base_11_stub(long long a) {
  printf("fun_stub_base_11_stub:a = %lld \n", a);
  return a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fun_stub_base_11_stub>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: fun_stub_base_11_stub:a = %lld 


assistant: ```c
int fun_stub_base_11_stub(long long a) {
  printf("fun_stub_base_11_stub:a = %lld \n", a);
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fun_stub_base_11_stub>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: fun_stub_base_11_stub:a = %lld 


assistant: ```c
int fun_stub_base_11_stub(long long a) {
  printf("fun_stub_base_11_stub:a = %lld \n", a);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fun_stub_base_11_stub>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: fun_stub_base_11_stub:a = %lld 


assistant: ```c
int fun_stub_base_11_stub(long long a) {
  printf("fun_stub_base_11_stub:a = %lld \n", a);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x9,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
void display(int a[]) {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d\n", a[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x28(%rdi),%r12
  lea    D3(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: %d


assistant: ```c
void display(int a[]) {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d\n", a[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<display>:
  endbr64
  push   %r12
  lea    0x28(%rdi),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %d


assistant: ```c
void display(int a[]) {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d\n", a[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<display>:
  endbr64
  push   %r12
  lea    0x28(%rdi),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: %d


assistant: ```c
void display(int a[]) {
  int i;
  for (i = 0; i < 10; i++)
    printf("%d\n", a[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CMS_compress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CMSerr@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
CMS_ContentInfo *CMS_compress(BIO *in, int comp_nid, unsigned int flags) {
  CMSerr(CMS_F_CMS_COMPRESS, CMS_R_UNSUPPORTED_COMPRESSION_ALGORITHM);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CMS_compress>:
  endbr64
  sub    $0x8,%rsp
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <CMSerr@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
CMS_ContentInfo *CMS_compress(BIO *in, int comp_nid, unsigned int flags) {
  CMSerr(CMS_F_CMS_COMPRESS, CMS_R_UNSUPPORTED_COMPRESSION_ALGORITHM);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CMS_compress>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <CMSerr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
CMS_ContentInfo *CMS_compress(BIO *in, int comp_nid, unsigned int flags) {
  CMSerr(CMS_F_CMS_COMPRESS, CMS_R_UNSUPPORTED_COMPRESSION_ALGORITHM);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CMS_compress>:
  endbr64
  sub    $0x8,%rsp
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <CMSerr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
CMS_ContentInfo *CMS_compress(BIO *in, int comp_nid, unsigned int flags) {
  CMSerr(CMS_F_CMS_COMPRESS, CMS_R_UNSUPPORTED_COMPRESSION_ALGORITHM);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<chiedi_secondo_fattore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D6: Inserisci il secondo fattore
> 

tool: D11: %d

assistant: ```c
int chiedi_secondo_fattore() {
  int y;
  printf("Inserisci il secondo fattore\n> ");
  scanf("%d", &y);
  return y;
}
```