ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<distPtSeg>:
  endbr64
  subss  %xmm2,%xmm4
  subss  %xmm3,%xmm5
  movaps %xmm0,%xmm6
  movaps %xmm1,%xmm8
  subss  %xmm3,%xmm8
  movaps %xmm4,%xmm7
  movaps %xmm5,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm7
  mulss  %xmm5,%xmm8
  addss  %xmm0,%xmm7
  movaps %xmm6,%xmm0
  subss  %xmm2,%xmm0
  mulss  %xmm4,%xmm0
  addss  %xmm8,%xmm0
  pxor   %xmm8,%xmm8
  comiss %xmm8,%xmm7
  jbe    L44
  divss  %xmm7,%xmm0
L44:
  comiss %xmm0,%xmm8
  ja     L17
  comiss D2(%rip),%xmm0
  jbe    L42
L27:
  addss  %xmm4,%xmm2
  addss  %xmm5,%xmm3
  subss  %xmm6,%xmm2
  subss  %xmm1,%xmm3
  mulss  %xmm2,%xmm2
  mulss  %xmm3,%xmm3
  addss  %xmm3,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   (%rax)
L42:
  mulss  %xmm0,%xmm4
  mulss  %xmm0,%xmm5
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L17:
  mulss  %xmm8,%xmm4
  mulss  %xmm8,%xmm5
  jmp    L27
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float distPtSeg(float x, float y, float px, float py, float qx, float qy) {
  float pqx, pqy, dx, dy, d, t;
  pqx = qx - px;
  pqy = qy - py;
  dx = x - px;
  dy = y - py;
  d = pqx * pqx + pqy * pqy;
  t = pqx * dx + pqy * dy;
  if (d > 0)
    t /= d;
  if (t < 0)
    t = 0;
  else if (t > 1)
    t = 1;
  dx = px + t * pqx - x;
  dy = py + t * pqy - y;
  return dx * dx + dy * dy;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<distPtSeg>:
  endbr64
  subss  %xmm2,%xmm4
  subss  %xmm3,%xmm5
  movaps %xmm0,%xmm6
  movaps %xmm1,%xmm8
  subss  %xmm3,%xmm8
  movaps %xmm4,%xmm7
  movaps %xmm5,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm7
  mulss  %xmm5,%xmm8
  addss  %xmm0,%xmm7
  movaps %xmm6,%xmm0
  subss  %xmm2,%xmm0
  mulss  %xmm4,%xmm0
  addss  %xmm8,%xmm0
  pxor   %xmm8,%xmm8
  comiss %xmm8,%xmm7
  jbe    L29
  divss  %xmm7,%xmm0
L29:
  comiss %xmm0,%xmm8
  ja     L41
  comiss D7(%rip),%xmm0
  jbe    L35
L10:
  addss  %xmm4,%xmm2
  addss  %xmm5,%xmm3
  subss  %xmm6,%xmm2
  subss  %xmm1,%xmm3
  mulss  %xmm2,%xmm2
  mulss  %xmm3,%xmm3
  addss  %xmm3,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   (%rax)
L35:
  mulss  %xmm0,%xmm4
  mulss  %xmm0,%xmm5
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L41:
  mulss  %xmm8,%xmm4
  mulss  %xmm8,%xmm5
  jmp    L10
```

tool_calls: name: read_data
arguments: label: D7
type: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float distPtSeg(float x, float y, float px, float py, float qx, float qy) {
  float pqx, pqy, dx, dy, d, t;
  pqx = qx - px;
  pqy = qy - py;
  dx = x - px;
  dy = y - py;
  d = pqx * pqx + pqy * pqy;
  t = pqx * dx + pqy * dy;
  if (d > 0)
    t /= d;
  if (t < 0)
    t = 0;
  else if (t > 1)
    t = 1;
  dx = px + t * pqx - x;
  dy = py + t * pqy - y;
  return dx * dx + dy * dy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<colvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <make_dv@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *colvec(double **a, int col, int nrows) {
  double *temp;
  int i;
  temp = make_dv(nrows);
  for (i = 1; i <= nrows; i++)
    temp[i] = a[i][col];
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<colvec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %edx,%edi
  call   <make_dv@plt>
  test   %r12d,%r12d
  jle    L18
  movslq %ebx,%rsi
  shl    $0x3,%rsi
  lea    0x1(%r12),%edi
  mov    $0x1,%edx
L17:
  mov    0x0(%rbp,%rdx,8),%rcx
  movsd  (%rcx,%rsi,1),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L17
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *colvec(double **a, int col, int nrows) {
  double *temp;
  int i;
  temp = make_dv(nrows);
  for (i = 1; i <= nrows; i++)
    temp[i] = a[i][col];
  return temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<colvec>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <make_dv@plt>
  test   %r12d,%r12d
  jle    L8
  movslq %ebx,%rsi
  lea    0x1(%r12),%edi
  mov    $0x1,%edx
  shl    $0x3,%rsi
  nopl   (%rax)
L2:
  mov    0x0(%rbp,%rdx,8),%rcx
  movsd  (%rcx,%rsi,1),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L2
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *colvec(double **a, int col, int nrows) {
  double *temp;
  int i;
  temp = make_dv(nrows);
  for (i = 1; i <= nrows; i++)
    temp[i] = a[i][col];
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<colvec>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <make_dv@plt>
  test   %r12d,%r12d
  jle    L9
  movslq %ebx,%rsi
  lea    0x1(%r12),%edi
  mov    $0x1,%edx
  shl    $0x3,%rsi
  nopl   (%rax)
L1:
  mov    0x0(%rbp,%rdx,8),%rcx
  movsd  (%rcx,%rsi,1),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L1
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *colvec(double **a, int col, int nrows) {
  double *temp;
  int i;
  temp = make_dv(nrows);
  for (i = 1; i <= nrows; i++)
    temp[i] = a[i][col];
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <printargs@plt>
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <trackon@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <root@plt>
  movq   %xmm0,%rax
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  movq   %rax,%xmm0
  mov    %ecx,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <trackoff@plt>
  mov    $0x0,%eax
  call   <trackprint@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: %dth root of %d = %f


assistant: ```c
int main(int argc, char *argv[]) {
  printargs(argc, argv);
  int pwr = atoi(argv[1]);
  int num = atoi(argv[2]);
  trackon();
  printf("%dth root of %d = %f\n", pwr, num, root(pwr, num));
  trackoff();
  trackprint();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  call   <printargs@plt>
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <trackon@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <root@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <trackoff@plt>
  mov    $0x0,%eax
  call   <trackprint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %dth root of %d = %f


assistant: ```c
int main(int argc, char *argv[]) {
  printargs(argc, argv);
  int pwr = atoi(argv[1]);
  int num = atoi(argv[2]);
  trackon();
  printf("%dth root of %d = %f\n", pwr, num, root(pwr, num));
  trackoff();
  trackprint();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <printargs@plt>
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <trackon@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <root@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <trackoff@plt>
  xor    %eax,%eax
  call   <trackprint@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: %dth root of %d = %f


assistant: ```c
int main(int argc, char *argv[]) {
  printargs(argc, argv);
  int pwr = atoi(argv[1]);
  int num = atoi(argv[2]);
  trackon();
  printf("%dth root of %d = %f\n", pwr, num, root(pwr, num));
  trackoff();
  trackprint();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <printargs@plt>
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <trackon@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <root@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <trackoff@plt>
  xor    %eax,%eax
  call   <trackprint@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: %dth root of %d = %f


assistant: ```c
int main(int argc, char *argv[]) {
  printargs(argc, argv);
  int pwr = atoi(argv[1]);
  int num = atoi(argv[2]);
  trackon();
  printf("%dth root of %d = %f\n", pwr, num, root(pwr, num));
  trackoff();
  trackprint();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<clear_dobldobl_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xae,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int clear_dobldobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(174, a, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clear_dobldobl_homotopy>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xae,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clear_dobldobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(174, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clear_dobldobl_homotopy>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xae,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int clear_dobldobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(174, a, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clear_dobldobl_homotopy>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xae,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int clear_dobldobl_homotopy(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(174, a, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fixup_null_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L13:
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
  call   <xalloc_die@plt>
L16:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *fixup_null_alloc(size_t n) {
  void *p;
  p = 0;
  if (n == 0)
    p = malloc((size_t)1);
  if (p == NULL)
    xalloc_die();
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fixup_null_alloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L18
  mov    $0x1,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L19
L18:
  mov    $0x0,%eax
  call   <xalloc_die@plt>
  mov    $0x0,%eax
L19:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *fixup_null_alloc(size_t n) {
  void *p;
  p = 0;
  if (n == 0)
    p = malloc((size_t)1);
  if (p == NULL)
    xalloc_die();
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fixup_null_alloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L3
  mov    $0x1,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <xalloc_die@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *fixup_null_alloc(size_t n) {
  void *p;
  p = 0;
  if (n == 0)
    p = malloc((size_t)1);
  if (p == NULL)
    xalloc_die();
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fixup_null_alloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L8
  mov    $0x1,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <xalloc_die@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *fixup_null_alloc(size_t n) {
  void *p;
  p = 0;
  if (n == 0)
    p = malloc((size_t)1);
  if (p == NULL)
    xalloc_die();
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NumberIO_ReadHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    $0x4f,%esi
  mov    %rax,%rdi
  call   <StrIO_ReadString@plt>
  mov    -0x68(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    $0x4f,%esi
  mov    %rax,%rdi
  call   <NumberIO_StrToHex@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void NumberIO_ReadHex(unsigned int *x) {
  typedef struct _T3_a _T3;
  struct _T3_a {
    char array[79 + 1];
  };
  _T3 a;
  StrIO_ReadString((char *)&a.array[0], 79);
  NumberIO_StrToHex((char *)&a.array[0], 79, x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NumberIO_ReadHex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x4f,%esi
  mov    %rbp,%rdi
  call   <StrIO_ReadString@plt>
  mov    %rbx,%rdx
  mov    $0x4f,%esi
  mov    %rbp,%rdi
  call   <NumberIO_StrToHex@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_ReadHex(unsigned int *x) {
  typedef struct _T3_a _T3;
  struct _T3_a {
    char array[79 + 1];
  };
  _T3 a;
  StrIO_ReadString((char *)&a.array[0], 79);
  NumberIO_StrToHex((char *)&a.array[0], 79, x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<NumberIO_ReadHex>:
  endbr64
  push   %r12
  mov    $0x4f,%esi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <StrIO_ReadString@plt>
  mov    %r12,%rdx
  mov    $0x4f,%esi
  mov    %rbp,%rdi
  call   <NumberIO_StrToHex@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_ReadHex(unsigned int *x) {
  typedef struct _T3_a _T3;
  struct _T3_a {
    char array[79 + 1];
  };
  _T3 a;
  StrIO_ReadString((char *)&a.array[0], 79);
  NumberIO_StrToHex((char *)&a.array[0], 79, x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NumberIO_ReadHex>:
  endbr64
  push   %r12
  mov    $0x4f,%esi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <StrIO_ReadString@plt>
  mov    %r12,%rdx
  mov    $0x4f,%esi
  mov    %rbp,%rdi
  call   <NumberIO_StrToHex@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_ReadHex(unsigned int *x) {
  typedef struct _T3_a _T3;
  struct _T3_a {
    char array[79 + 1];
  };
  _T3 a;
  StrIO_ReadString((char *)&a.array[0], 79);
  NumberIO_StrToHex((char *)&a.array[0], 79, x);
}
```
user: What is the c source code of the assembly code below?

```asm
<_SHAMD5DataWriteMultiple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <SHAMD5DataWrite@plt>
  addq   $0x40,-0x20(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L57
  nop
L59:
  mov    -0x14(%rbp),%eax
  add    $0x118,%eax
  cltq
  mov    (%rax),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L59
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L54:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  lea    0x80(%rdx),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  cltq
  mov    %rax,(%rdx)
  addl   $0x4,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L54
L57:
  nop
  leave
  ret
```

assistant: ```c
void _SHAMD5DataWriteMultiple(uint32_t ui32Base, uint32_t *pui32DataSrc, uint32_t ui32DataLength) {
  uint32_t ui32Idx, ui32Count;
  ;
  ui32Count = ui32DataLength / 64;
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    SHAMD5DataWrite(ui32Base, pui32DataSrc);
    pui32DataSrc += 16;
  }
  ui32Count = ui32DataLength % 64;
  if (ui32Count) {
    while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
    }
    for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx += 4) {
      (*((volatile unsigned long *)(ui32Base + 0x00000080 + ui32Idx))) = *pui32DataSrc++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_SHAMD5DataWriteMultiple>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %edx,%r12d
  lea    0x3f(%rdx),%r15d
  test   %edx,%edx
  cmovns %edx,%r15d
  sar    $0x6,%r15d
  cmp    $0x3f,%edx
  jle    L9
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L58:
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <SHAMD5DataWrite@plt>
  add    $0x40,%rbp
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jg     L58
  lea    -0x1(%r15),%eax
  add    $0x1,%rax
  shl    $0x6,%rax
  cmp    $0x3f,%r12d
  mov    $0x40,%edx
  cmovle %rdx,%rax
  add    %rax,%r13
L9:
  test   $0x3f,%r12b
  je     L49
  lea    0x118(%r14),%edx
  movslq %edx,%rdx
L37:
  mov    (%rdx),%rax
  test   $0x2,%al
  je     L37
  mov    %r12d,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  add    %eax,%r12d
  and    $0x3f,%r12d
  sub    %eax,%r12d
  test   %r12d,%r12d
  jle    L49
  movslq %r14d,%r14
  lea    0x80(%r14),%rax
  sub    $0x1,%r12d
  shr    $0x2,%r12d
  mov    %r12d,%edx
  lea    0x84(%r14,%rdx,4),%rcx
  sub    %r14,%r13
L28:
  movslq -0x80(%r13,%rax,1),%rdx
  mov    %rdx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void _SHAMD5DataWriteMultiple(uint32_t ui32Base, uint32_t *pui32DataSrc, uint32_t ui32DataLength) {
  uint32_t ui32Idx, ui32Count;
  ;
  ui32Count = ui32DataLength / 64;
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    SHAMD5DataWrite(ui32Base, pui32DataSrc);
    pui32DataSrc += 16;
  }
  ui32Count = ui32DataLength % 64;
  if (ui32Count) {
    while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
    }
    for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx += 4) {
      (*((volatile unsigned long *)(ui32Base + 0x00000080 + ui32Idx))) = *pui32DataSrc++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_SHAMD5DataWriteMultiple>:
  endbr64
  push   %r15
  lea    0x3f(%rdx),%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  cmovns %edx,%r15d
  sar    $0x6,%r15d
  cmp    $0x3f,%edx
  jle    L29
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rsi
  mov    %r12d,%edi
  add    $0x1,%ebx
  add    $0x40,%rbp
  call   <SHAMD5DataWrite@plt>
  cmp    %ebx,%r15d
  jg     L34
  lea    -0x1(%r15),%eax
  mov    $0x40,%edx
  add    $0x1,%rax
  shl    $0x6,%rax
  cmp    $0x3f,%r14d
  cmovle %rdx,%rax
  add    %rax,%r13
L29:
  test   $0x3f,%r14b
  je     L15
  lea    0x118(%r12),%edx
  movslq %edx,%rdx
  nopl   0x0(%rax)
L20:
  mov    (%rdx),%rax
  test   $0x2,%al
  je     L20
  mov    %r14d,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  add    %eax,%r14d
  and    $0x3f,%r14d
  sub    %eax,%r14d
  test   %r14d,%r14d
  jle    L15
  sub    $0x1,%r14d
  lea    0x80(%r12),%eax
  sub    %r12,%r13
  shr    $0x2,%r14d
  cltq
  mov    %r14d,%edx
  lea    0x84(%r12,%rdx,4),%rcx
  nop
L30:
  movslq -0x80(%rax,%r13,1),%rdx
  add    $0x4,%rax
  mov    %rdx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L30
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void _SHAMD5DataWriteMultiple(uint32_t ui32Base, uint32_t *pui32DataSrc, uint32_t ui32DataLength) {
  uint32_t ui32Idx, ui32Count;
  ;
  ui32Count = ui32DataLength / 64;
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    SHAMD5DataWrite(ui32Base, pui32DataSrc);
    pui32DataSrc += 16;
  }
  ui32Count = ui32DataLength % 64;
  if (ui32Count) {
    while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
    }
    for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx += 4) {
      (*((volatile unsigned long *)(ui32Base + 0x00000080 + ui32Idx))) = *pui32DataSrc++;
    }
  }
}
```