ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<run>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L13
  lea    -0x2(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopl   0x0(%rax,%rax,1)
L12:
  movsbl 0x1(%rbx),%esi
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <shortest_route@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L12
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int run(char *str, int len) {
  len--;
  int counter = 0;
  for (int i = 0; i < len; i++)
    counter += shortest_route(str[i], str[i + 1]);
  return counter;
}
```
user: What is the c source code of the assembly code below?

```asm
<run>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopl   0x0(%rax,%rax,1)
L3:
  movsbl 0x1(%rbx),%esi
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <shortest_route@plt>
  add    %eax,%r12d
  cmp    %rbx,%rbp
  jne    L3
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int run(char *str, int len) {
  len--;
  int counter = 0;
  for (int i = 0; i < len; i++)
    counter += shortest_route(str[i], str[i + 1]);
  return counter;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strlow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L16
L14:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L16:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  nop
  leave
  ret
```

assistant: ```c
strlow(newbuf, buf) char *newbuf;
char *buf;
{
  while (*buf != '\0')
    *newbuf++ = tolower(*buf++);
  *newbuf = '\0';
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlow>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L13
L17:
  add    $0x1,%rbp
  movsbl %dil,%edi
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L17
L13:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
strlow(newbuf, buf) char *newbuf;
char *buf;
{
  while (*buf != '\0')
    *newbuf++ = tolower(*buf++);
  *newbuf = '\0';
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlow>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L18
  mov    %rsi,%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  call   <tolower@plt>
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L10
L18:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
strlow(newbuf, buf) char *newbuf;
char *buf;
{
  while (*buf != '\0')
    *newbuf++ = tolower(*buf++);
  *newbuf = '\0';
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlow>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L17
  mov    %rsi,%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  call   <tolower@plt>
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L15
L17:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
strlow(newbuf, buf) char *newbuf;
char *buf;
{
  while (*buf != '\0')
    *newbuf++ = tolower(*buf++);
  *newbuf = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: result is %d


assistant: ```c
int main() {
  int n = 4;
  printf("result is %d\n", fact(n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <fact@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: result is %d


assistant: ```c
int main() {
  int n = 4;
  printf("result is %d\n", fact(n));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <fact@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: result is %d


assistant: ```c
int main() {
  int n = 4;
  printf("result is %d\n", fact(n));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <fact@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: result is %d


assistant: ```c
int main() {
  int n = 4;
  printf("result is %d\n", fact(n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<geteuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
uid_t geteuid(void) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<geteuid>:
  endbr64
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uid_t geteuid(void) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<geteuid>:
  endbr64
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uid_t geteuid(void) {
  errno = ENOSYS;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<geteuid>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uid_t geteuid(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_f77_func_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *free_f77_func_data(void *p) {
  free(p);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_f77_func_data>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *free_f77_func_data(void *p) {
  free(p);
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<free_f77_func_data>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *free_f77_func_data(void *p) {
  free(p);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_f77_func_data>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *free_f77_func_data(void *p) {
  free(p);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<repeat_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L1:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void repeat_char(const char c, const int repeat) {
  for (int i = 0; i < repeat; i++)
    putchar(c);
}
```
user: What is the c source code of the assembly code below:

```asm
<repeat_char>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    $0x0,%ebx
  movsbl %dil,%ebp
L4:
  mov    %ebp,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  ret
```

assistant: ```c
void repeat_char(const char c, const int repeat) {
  for (int i = 0; i < repeat; i++)
    putchar(c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<repeat_char>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L0:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void repeat_char(const char c, const int repeat) {
  for (int i = 0; i < repeat; i++)
    putchar(c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<repeat_char>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L5:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void repeat_char(const char c, const int repeat) {
  for (int i = 0; i < repeat; i++)
    putchar(c);
}
```
user: What is the c source code of the assembly code below?

```asm
<relabsd_util_parse_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <strtol@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
L56:
  mov    $0xffffffff,%eax
  jmp    L48
L53:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jl     L16
  mov    -0x30(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jle    L40
L16:
  mov    $0xfffffffe,%eax
  jmp    L48
L40:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int relabsd_util_parse_int(const char string[const restrict 1], const int min, const int max, int output[const restrict 1]) {
  char *invalid_char;
  long int buffer;
  buffer = strtol(string, &invalid_char, 10);
  if ((invalid_char[0] != '\0') || (string[0] == '\0')) {
    return -1;
  }
  if ((buffer < ((long int)min)) || (buffer > ((long int)max))) {
    return -2;
  }
  *output = ((int)buffer);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<relabsd_util_parse_int>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L50
  cmpb   $0x0,(%rbx)
  je     L18
  cmp    %ebp,%eax
  jg     L32
  cmp    %r12d,%eax
  jl     L32
  mov    %eax,0x0(%r13)
  mov    $0x0,%eax
L54:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  mov    $0xffffffff,%eax
  jmp    L54
L18:
  mov    $0xffffffff,%eax
  jmp    L54
L32:
  mov    $0xfffffffe,%eax
  jmp    L54
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int relabsd_util_parse_int(const char string[const restrict 1], const int min, const int max, int output[const restrict 1]) {
  char *invalid_char;
  long int buffer;
  buffer = strtol(string, &invalid_char, 10);
  if ((invalid_char[0] != '\0') || (string[0] == '\0')) {
    return -1;
  }
  if ((buffer < ((long int)min)) || (buffer > ((long int)max))) {
    return -2;
  }
  *output = ((int)buffer);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<relabsd_util_parse_int>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  mov    $0xa,%edx
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L47
  cmpb   $0x0,(%rbx)
  je     L47
  cmp    %ebp,%eax
  jl     L5
  cmp    %r12d,%eax
  jg     L5
  mov    %eax,0x0(%r13)
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L47:
  mov    $0xffffffff,%eax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xfffffffe,%eax
  jmp    L12
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int relabsd_util_parse_int(const char string[const restrict 1], const int min, const int max, int output[const restrict 1]) {
  char *invalid_char;
  long int buffer;
  buffer = strtol(string, &invalid_char, 10);
  if ((invalid_char[0] != '\0') || (string[0] == '\0')) {
    return -1;
  }
  if ((buffer < ((long int)min)) || (buffer > ((long int)max))) {
    return -2;
  }
  *output = ((int)buffer);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<relabsd_util_parse_int>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  mov    $0xa,%edx
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L53
  cmpb   $0x0,(%rbx)
  je     L53
  cmp    %ebp,%eax
  jl     L25
  cmp    %r12d,%eax
  jg     L25
  mov    %eax,0x0(%r13)
  xor    %eax,%eax
L61:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L53:
  mov    $0xffffffff,%eax
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0xfffffffe,%eax
  jmp    L61
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int relabsd_util_parse_int(const char string[const restrict 1], const int min, const int max, int output[const restrict 1]) {
  char *invalid_char;
  long int buffer;
  buffer = strtol(string, &invalid_char, 10);
  if ((invalid_char[0] != '\0') || (string[0] == '\0')) {
    return -1;
  }
  if ((buffer < ((long int)min)) || (buffer > ((long int)max))) {
    return -2;
  }
  *output = ((int)buffer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flushToAfterTag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L1
  movl   $0x0,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  ja     L5
  jmp    L37
L43:
  nop
L37:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flushToAfterTag(uint8_t **buf, char *tag, uint8_t *endOfBuffer) {
  int pos;
  for (pos = 0; *buf < endOfBuffer; (*buf)++) {
    if (tag[pos] == 0)
      break;
    if (**buf != tag[pos++])
      pos = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flushToAfterTag>:
  endbr64
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jbe    L13
  mov    $0x0,%ecx
  mov    $0x0,%r9d
L8:
  movslq %ecx,%r8
  movzbl (%rsi,%r8,1),%r8d
  test   %r8b,%r8b
  je     L13
  add    $0x1,%ecx
  cmp    (%rax),%r8b
  cmovne %r9d,%ecx
  add    $0x1,%rax
  mov    %rax,(%rdi)
  cmp    %rdx,%rax
  jne    L8
L13:
  ret
```

assistant: ```c
void flushToAfterTag(uint8_t **buf, char *tag, uint8_t *endOfBuffer) {
  int pos;
  for (pos = 0; *buf < endOfBuffer; (*buf)++) {
    if (tag[pos] == 0)
      break;
    if (**buf != tag[pos++])
      pos = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flushToAfterTag>:
  endbr64
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jbe    L18
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%ecx
  cmp    (%rax),%r8b
  cmovne %r9d,%ecx
  add    $0x1,%rax
  mov    %rax,(%rdi)
  cmp    %rdx,%rax
  je     L18
L12:
  movslq %ecx,%r8
  movzbl (%rsi,%r8,1),%r8d
  test   %r8b,%r8b
  jne    L10
L18:
  ret
```

assistant: ```c
void flushToAfterTag(uint8_t **buf, char *tag, uint8_t *endOfBuffer) {
  int pos;
  for (pos = 0; *buf < endOfBuffer; (*buf)++) {
    if (tag[pos] == 0)
      break;
    if (**buf != tag[pos++])
      pos = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flushToAfterTag>:
  endbr64
  mov    (%rdi),%rax
  cmp    %rax,%rdx
  jbe    L19
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x1,%ecx
  cmp    (%rax),%r8b
  cmovne %r9d,%ecx
  add    $0x1,%rax
  mov    %rax,(%rdi)
  cmp    %rdx,%rax
  je     L19
L3:
  movslq %ecx,%r8
  movzbl (%rsi,%r8,1),%r8d
  test   %r8b,%r8b
  jne    L24
L19:
  ret
```

assistant: ```c
void flushToAfterTag(uint8_t **buf, char *tag, uint8_t *endOfBuffer) {
  int pos;
  for (pos = 0; *buf < endOfBuffer; (*buf)++) {
    if (tag[pos] == 0)
      break;
    if (**buf != tag[pos++])
      pos = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fpoly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  D2(%rip),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x2,-0x4(%rbp)
  jmp    L17
L5:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: f32

tool: D2: 1

assistant: ```c
void fpoly(float x, float p[], int np) {
  int j;
  p[1] = 1.0;
  for (j = 2; j <= np; j++)
    p[j] = p[j - 1] * x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fpoly>:
  endbr64
  movl   $0x3f800000,0x4(%rdi)
  cmp    $0x1,%esi
  jle    L1
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rdx
L17:
  movaps %xmm0,%xmm1
  mulss  (%rax),%xmm1
  movss  %xmm1,0x4(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L17
L1:
  ret
```

assistant: ```c
void fpoly(float x, float p[], int np) {
  int j;
  p[1] = 1.0;
  for (j = 2; j <= np; j++)
    p[j] = p[j - 1] * x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fpoly>:
  endbr64
  movl   $0x3f800000,0x4(%rdi)
  cmp    $0x1,%esi
  jle    L2
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rdx
  nopl   0x0(%rax)
L11:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rax)
  cmp    %rdx,%rax
  jne    L11
L2:
  ret
```

assistant: ```c
void fpoly(float x, float p[], int np) {
  int j;
  p[1] = 1.0;
  for (j = 2; j <= np; j++)
    p[j] = p[j - 1] * x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fpoly>:
  endbr64
  movss  D1(%rip),%xmm1
  movss  %xmm1,0x4(%rdi)
  cmp    $0x1,%esi
  jle    L8
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  lea    0xc(%rdi,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L12:
  mulss  %xmm0,%xmm1
  add    $0x4,%rax
  movss  %xmm1,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L12
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: f32

tool: D1: 1

assistant: ```c
void fpoly(float x, float p[], int np) {
  int j;
  p[1] = 1.0;
  for (j = 2; j <= np; j++)
    p[j] = p[j - 1] * x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D35
data_type: string
name: read_data
arguments: label: D29
data_type: string

tool: D10: true and false is %d


tool: D4: true or false is %d


tool: D35: true xor false is %d


tool: D29: not true is %d

assistant: ```c
int main() {
  printf("true and false is %d\n", 1 && 0);
  printf("true or false is %d\n", 1 || 0);
  printf("true xor false is %d\n", 1 ^ 0);
  printf("not true is %d", !1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string

tool: D23: true and false is %d


tool: D26: true or false is %d


tool: D22: true xor false is %d


tool: D14: not true is %d

assistant: ```c
int main() {
  printf("true and false is %d\n", 1 && 0);
  printf("true or false is %d\n", 1 || 0);
  printf("true xor false is %d\n", 1 ^ 0);
  printf("not true is %d", !1);
  return 0;
}
```