ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_diag_elems>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %r8d,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %ecx,%esi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <matmul@plt>
  mov    %rbp,%rdi
  call   <transpose@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r13,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <matmul@plt>
  mov    %rbp,%rdi
  call   <transpose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_diag_elems(long A[3][3], long P[3][3], long Q[3][3], const int i, const int j) {
  long L[3][3];
  swap_rows(L, i, j);
  matmul(A, L, A);
  matmul(P, L, P);
  transpose(A);
  swap_rows(L, i, j);
  matmul(A, L, A);
  matmul(Q, L, Q);
  transpose(A);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap_diag_elems>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %r8d,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %ecx,%esi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <matmul@plt>
  mov    %rbp,%rdi
  call   <transpose@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <swap_rows@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matmul@plt>
  mov    %r13,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <matmul@plt>
  mov    %rbp,%rdi
  call   <transpose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_diag_elems(long A[3][3], long P[3][3], long Q[3][3], const int i, const int j) {
  long L[3][3];
  swap_rows(L, i, j);
  matmul(A, L, A);
  matmul(P, L, P);
  transpose(A);
  swap_rows(L, i, j);
  matmul(A, L, A);
  matmul(Q, L, Q);
  transpose(A);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FileUtil_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    -0x10(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D19: stdout

tool: D6: stderr

assistant: ```c
void FileUtil_close(FILE *fp, char *fname) {
  if (strcmp(fname, "stdout") && strcmp(fname, "stderr")) {
    fclose(fp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FileUtil_close>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L19
  mov    %rbp,%rdi
  call   <fclose@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string
name: read_data
arguments: data_label: D4
data_type: string

tool: D7: stdout

tool: D4: stderr

assistant: ```c
void FileUtil_close(FILE *fp, char *fname) {
  if (strcmp(fname, "stdout") && strcmp(fname, "stderr")) {
    fclose(fp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FileUtil_close>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D18
type: string

tool: D5: stdout

tool: D18: stderr

assistant: ```c
void FileUtil_close(FILE *fp, char *fname) {
  if (strcmp(fname, "stdout") && strcmp(fname, "stderr")) {
    fclose(fp);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FileUtil_close>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
L13:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <fclose@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D11: stdout

tool: D18: stderr

assistant: ```c
void FileUtil_close(FILE *fp, char *fname) {
  if (strcmp(fname, "stdout") && strcmp(fname, "stderr")) {
    fclose(fp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0xe50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x4e48(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x4e48(%rbp),%eax
  mov    %eax,-0x4e44(%rbp)
  jmp    L39
L35:
  mov    -0x4e48(%rbp),%edx
  mov    -0x4e44(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x4e40(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2720(%rbp),%rdx
  lea    -0x4e40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <long_com_pat@plt>
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    -0x4e48(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4e48(%rbp)
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D66
type_infered: string
name: parse_data
arguments: data_label: D69
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D58
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D77
type_infered: string
name: parse_data
arguments: data_label: D34
type_infered: string

tool: D22: How many test cases? - 

tool: D66: %d

tool: D69: Test case %d


tool: D17: String A:

tool: D58: %s

tool: D29: String 2: 

tool: D77: Total match :

tool: D34: %d


assistant: ```c
int main() {
  int t;
  char a[10002], b[10002];
  printf("How many test cases? - ");
  scanf("%d", &t);
  int m = t;
  while (t--) {
    printf("Test case %d\n", m - t);
    printf("String A:\n");
    scanf("%s", a);
    printf("String 2: \n");
    scanf("%s", b);
    printf("Total match :");
    printf("%d\n", long_com_pat(a, b));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0xe58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e48(%rsp)
  xor    %eax,%eax
  lea    D75(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r13d
  lea    -0x1(%r13),%eax
  mov    %eax,0xc(%rsp)
  test   %r13d,%r13d
  je     L7
  lea    D69(%rip),%r15
  lea    D53(%rip),%r14
  lea    D33(%rip),%r12
L10:
  mov    %r13d,%esi
  sub    %eax,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    0x2730(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D74(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <long_com_pat@plt>
  mov    %eax,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  test   %edx,%edx
  jne    L10
L7:
  mov    0x4e48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x4e58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D75
data_type: string
name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D69
data_type: string
name: parse_data
arguments: data_label: D53
data_type: string
name: parse_data
arguments: data_label: D33
data_type: string
name: parse_data
arguments: data_label: D45
data_type: string
name: parse_data
arguments: data_label: D74
data_type: string
name: parse_data
arguments: data_label: D43
data_type: string

tool: D75: How many test cases? - 

tool: D2: %d

tool: D69: Test case %d


tool: D53: String A:

tool: D33: %s

tool: D45: String 2: 

tool: D74: Total match :

tool: D43: %d


assistant: ```c
int main() {
  int t;
  char a[10002], b[10002];
  printf("How many test cases? - ");
  scanf("%d", &t);
  int m = t;
  while (t--) {
    printf("Test case %d\n", m - t);
    printf("String A:\n");
    scanf("%s", a);
    printf("String 2: \n");
    scanf("%s", b);
    printf("Total match :");
    printf("%d\n", long_com_pat(a, b));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L20:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L20
  sub    $0xe68,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4e58(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  lea    -0x1(%rcx),%eax
  mov    %ecx,0xc(%rsp)
  mov    %eax,0x1c(%rsp)
  test   %ecx,%ecx
  je     L28
  lea    D3(%rip),%r15
  lea    D40(%rip),%r14
  lea    0x20(%rsp),%r12
  lea    D7(%rip),%rbp
  lea    D78(%rip),%r13
  lea    0x2740(%rsp),%rbx
L1:
  mov    0xc(%rsp),%esi
  mov    %r15,%rdi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <long_com_pat@plt>
  lea    D53(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,0x1c(%rsp)
  test   %edx,%edx
  jne    L1
L28:
  mov    0x4e58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x4e68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type: string
name: retrieve_data
arguments: data_label: D36
type: string
name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D40
type: string
name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D78
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D53
type: string

tool: D20: How many test cases? - 

tool: D36: %d

tool: D3: Test case %d


tool: D40: String A:

tool: D7: %s

tool: D78: String 2: 

tool: D15: Total match :

tool: D53: %d


assistant: ```c
int main() {
  int t;
  char a[10002], b[10002];
  printf("How many test cases? - ");
  scanf("%d", &t);
  int m = t;
  while (t--) {
    printf("Test case %d\n", m - t);
    printf("String A:\n");
    scanf("%s", a);
    printf("String 2: \n");
    scanf("%s", b);
    printf("Total match :");
    printf("%d\n", long_com_pat(a, b));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0xe68,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4e58(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%ecx
  lea    -0x1(%rcx),%eax
  mov    %ecx,0xc(%rsp)
  mov    %eax,0x1c(%rsp)
  test   %ecx,%ecx
  je     L24
  lea    D50(%rip),%r15
  lea    D71(%rip),%r14
  lea    0x20(%rsp),%r12
  lea    D15(%rip),%rbp
  lea    D37(%rip),%r13
  lea    0x2740(%rsp),%rbx
L20:
  mov    0xc(%rsp),%esi
  mov    %r15,%rdi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <long_com_pat@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,0x1c(%rsp)
  test   %edx,%edx
  jne    L20
L24:
  mov    0x4e58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x4e68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D78
type_infered: string
name: extract_symbolic_data
arguments: tag: D50
type_infered: string
name: extract_symbolic_data
arguments: tag: D71
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D37
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D6: How many test cases? - 

tool: D78: %d

tool: D50: Test case %d


tool: D71: String A:

tool: D15: %s

tool: D37: String 2: 

tool: D18: Total match :

tool: D13: %d


assistant: ```c
int main() {
  int t;
  char a[10002], b[10002];
  printf("How many test cases? - ");
  scanf("%d", &t);
  int m = t;
  while (t--) {
    printf("Test case %d\n", m - t);
    printf("String A:\n");
    scanf("%s", a);
    printf("String 2: \n");
    scanf("%s", b);
    printf("Total match :");
    printf("%d\n", long_com_pat(a, b));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<generate_macro_mul_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D17(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D17: void* mul_matrix(char const* param_type, int** mat_1, int**  mat_2, int mat_1_rows, int mat_1_cols, int mat_2_rows, int mat_2_cols) { 	int i, j, k;	if(strcmp("int", param_type) == 0) {		int** mat;		int sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(int));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];				}				mat[i][j] = sum;			}		}				return mat;	}	else {		double** mat;		double sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(double));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];					}				mat[i][j] = sum;			}		}				return mat;	}}


tool: D4: %s


assistant: ```c
void generate_macro_mul_matrix() {
  char *s = "void* mul_matrix(char const* param_type, int** mat_1, int**  mat_2, int mat_1_rows, int mat_1_cols, int mat_2_rows, int mat_2_cols) { 	int i, j, k;	if(strcmp(\"int\", param_type) == 0) {		int** mat;		int sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(int));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];				}				mat[i][j] = sum;			}		}				return mat;	}	else {		double** mat;		double sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di "
            "somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(double));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];					}				mat[i][j] = sum;			}		}				return mat;	}}\n";
  printf("%s\n", s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate_macro_mul_matrix>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D19: void* mul_matrix(char const* param_type, int** mat_1, int**  mat_2, int mat_1_rows, int mat_1_cols, int mat_2_rows, int mat_2_cols) { 	int i, j, k;	if(strcmp("int", param_type) == 0) {		int** mat;		int sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(int));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];				}				mat[i][j] = sum;			}		}				return mat;	}	else {		double** mat;		double sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(double));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];					}				mat[i][j] = sum;			}		}				return mat;	}}


tool: D0: %s


assistant: ```c
void generate_macro_mul_matrix() {
  char *s = "void* mul_matrix(char const* param_type, int** mat_1, int**  mat_2, int mat_1_rows, int mat_1_cols, int mat_2_rows, int mat_2_cols) { 	int i, j, k;	if(strcmp(\"int\", param_type) == 0) {		int** mat;		int sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(int));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];				}				mat[i][j] = sum;			}		}				return mat;	}	else {		double** mat;		double sum;		//alloco lo spazio per la matrice da ritornare		//ed effettuo nel contempo l'operazione di "
            "somma		mat = calloc(mat_1_rows, sizeof(void*));		for(i=0; i<mat_1_rows; i++) {			mat[i] = calloc(mat_2_cols, sizeof(double));			for(j=0; j<mat_2_cols; j++ ) {				//imposto la somma parziale a 0				sum = 0;				for(k = 0; k < mat_1_cols; k++) {					sum += mat_1[i][k] * mat_2[k][j];					}				mat[i][j] = sum;			}		}				return mat;	}}\n";
  printf("%s\n", s);
}
```