ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<average_CPU_time>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  jle    L17
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %edx,%ebp
  xor    %r14d,%r14d
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L8:
  mov    $0x3e7,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%r14d
  call   <randomInitialize@plt>
  xor    %eax,%eax
  call   <clock@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   *%r13
  xor    %eax,%eax
  call   <clock@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  sub    %r15,%rax
  cvtsi2sd %rax,%xmm1
  mov    D9(%rip),%rax
  divsd  (%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %r14d,%r12d
  jne    L8
L19:
  pxor   %xmm1,%xmm1
  add    $0x18,%rsp
  cvtsi2sd %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L17:
  pxor   %xmm0,%xmm0
  jmp    L19
```

assistant: ```c
double average_CPU_time(void (*sortFuncPtr)(int[], int), int arr[], int size, int numRuns) {
  int i;
  double total = 0.0;
  clock_t start, end;
  for (i = 0; i < numRuns; ++i) {
    randomInitialize(arr, size, 1, 999);
    start = clock();
    (*sortFuncPtr)(arr, size);
    end = clock();
    total += ((double)(end - start)) / CLOCKS_PER_SEC;
  }
  return total / numRuns;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tsCreate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L17
L1:
  addq   $0x1,-0x18(%rbp)
  subq   $0x3b9aca00,-0x20(%rbp)
L17:
  cmpq   $0x3b9ac9ff,-0x20(%rbp)
  jg     L1
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
struct timespec tsCreate(long seconds, long nanoseconds) {
  struct timespec result;
  seconds = (seconds < 0) ? 0 : seconds;
  nanoseconds = (nanoseconds < 0) ? 0 : nanoseconds;
  while (nanoseconds >= 1000000000L) {
    seconds++;
    nanoseconds = nanoseconds - 1000000000L;
  }
  result.tv_sec = seconds;
  result.tv_nsec = nanoseconds;
  return (result);
}
```
user: What is the c source code of the assembly code below?

```asm
<tsCreate>:
  endbr64
  test   %rdi,%rdi
  mov    $0x0,%eax
  cmovns %rdi,%rax
  test   %rsi,%rsi
  mov    $0x0,%edx
  cmovns %rsi,%rdx
  cmp    $0x3b9ac9ff,%rsi
  jle    L1
L17:
  add    $0x1,%rax
  sub    $0x3b9aca00,%rdx
  cmp    $0x3b9ac9ff,%rdx
  jg     L17
L1:
  ret
```

assistant: ```c
struct timespec tsCreate(long seconds, long nanoseconds) {
  struct timespec result;
  seconds = (seconds < 0) ? 0 : seconds;
  nanoseconds = (nanoseconds < 0) ? 0 : nanoseconds;
  while (nanoseconds >= 1000000000L) {
    seconds++;
    nanoseconds = nanoseconds - 1000000000L;
  }
  result.tv_sec = seconds;
  result.tv_nsec = nanoseconds;
  return (result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tsCreate>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  cmovns %rdi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  cmovns %rsi,%rdx
  cmp    $0x3b9ac9ff,%rsi
  jle    L5
  nop
L3:
  sub    $0x3b9aca00,%rdx
  add    $0x1,%rax
  cmp    $0x3b9ac9ff,%rdx
  jg     L3
L5:
  ret
```

assistant: ```c
struct timespec tsCreate(long seconds, long nanoseconds) {
  struct timespec result;
  seconds = (seconds < 0) ? 0 : seconds;
  nanoseconds = (nanoseconds < 0) ? 0 : nanoseconds;
  while (nanoseconds >= 1000000000L) {
    seconds++;
    nanoseconds = nanoseconds - 1000000000L;
  }
  result.tv_sec = seconds;
  result.tv_nsec = nanoseconds;
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tsCreate>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  cmovns %rdi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  cmovns %rsi,%rdx
  cmp    $0x3b9ac9ff,%rsi
  jle    L17
  nop
L10:
  sub    $0x3b9aca00,%rdx
  add    $0x1,%rax
  cmp    $0x3b9ac9ff,%rdx
  jg     L10
L17:
  ret
```

assistant: ```c
struct timespec tsCreate(long seconds, long nanoseconds) {
  struct timespec result;
  seconds = (seconds < 0) ? 0 : seconds;
  nanoseconds = (nanoseconds < 0) ? 0 : nanoseconds;
  while (nanoseconds >= 1000000000L) {
    seconds++;
    nanoseconds = nanoseconds - 1000000000L;
  }
  result.tv_sec = seconds;
  result.tv_nsec = nanoseconds;
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDL_ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L14
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
  mov    -0x18(%rbp),%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <SDL_ultoa@plt>
  jmp    L8
L14:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SDL_ultoa@plt>
L8:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *SDL_ltoa(long value, char *string, int radix) {
  char *bufp = string;
  if (value < 0) {
    *bufp++ = '-';
    SDL_ultoa(-value, bufp, radix);
  } else {
    SDL_ultoa(value, bufp, radix);
  }
  return string;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SDL_ltoa>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  js     L12
  call   <SDL_ultoa@plt>
L11:
  mov    %rbx,%rax
  pop    %rbx
  ret
L12:
  movb   $0x2d,(%rsi)
  lea    0x1(%rsi),%rsi
  neg    %rdi
  call   <SDL_ultoa@plt>
  jmp    L11
```

assistant: ```c
char *SDL_ltoa(long value, char *string, int radix) {
  char *bufp = string;
  if (value < 0) {
    *bufp++ = '-';
    SDL_ultoa(-value, bufp, radix);
  } else {
    SDL_ultoa(value, bufp, radix);
  }
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SDL_ltoa>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  test   %rdi,%rdi
  js     L7
  call   <SDL_ultoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  movb   $0x2d,(%rsi)
  neg    %rdi
  lea    0x1(%rsi),%rsi
  call   <SDL_ultoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SDL_ltoa(long value, char *string, int radix) {
  char *bufp = string;
  if (value < 0) {
    *bufp++ = '-';
    SDL_ultoa(-value, bufp, radix);
  } else {
    SDL_ultoa(value, bufp, radix);
  }
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SDL_ltoa>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  test   %rdi,%rdi
  js     L9
  call   <SDL_ultoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  movb   $0x2d,(%rsi)
  neg    %rdi
  lea    0x1(%rsi),%rsi
  call   <SDL_ultoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SDL_ltoa(long value, char *string, int radix) {
  char *bufp = string;
  if (value < 0) {
    *bufp++ = '-';
    SDL_ultoa(-value, bufp, radix);
  } else {
    SDL_ultoa(value, bufp, radix);
  }
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L8:
  mov    $0xfffffff5,%edi
  call   <close@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x9,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; i++)
    close(-11);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
L7:
  mov    $0xfffffff5,%edi
  call   <close@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; i++)
    close(-11);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xfffffff5,%edi
  call   <close@plt>
  sub    $0x1,%ebx
  jne    L4
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; i++)
    close(-11);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xfffffff5,%edi
  call   <close@plt>
  sub    $0x1,%ebx
  jne    L1
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; i++)
    close(-11);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L4
L32:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L32
L9:
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: string

tool: D18: Copied %c


tool: D12: Skipping %c


assistant: ```c
void compress(char *str) {
  char *dest = str;
  int j = 0;
  while (*str) {
    printf("Copied %c\n", *str);
    dest[j++] = *str;
    while (*str && *str == *(str + 1)) {
      str++;
      printf("Skipping %c\n", *str);
    }
    str++;
  }
  dest[j++] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L26
  mov    %rdi,%rbx
  mov    $0x1,%r12d
  lea    D1(%rip),%r15
  lea    D16(%rip),%rbp
  jmp    L60
L2:
  mov    %rbx,%rax
  jmp    L28
L38:
  mov    %rbx,%rax
L28:
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L15
L60:
  movsbl %sil,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12d,%r14d
  movzbl (%rbx),%eax
  mov    %al,-0x1(%r13,%r12,1)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L2
L49:
  movzbl 0x1(%rbx),%esi
  cmp    %al,%sil
  jne    L38
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L49
  mov    %rbx,%rax
  jmp    L28
L26:
  mov    $0x0,%r14d
L15:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D16
data_type: string

tool: D1: Copied %c


tool: D16: Skipping %c


assistant: ```c
void compress(char *str) {
  char *dest = str;
  int j = 0;
  while (*str) {
    printf("Copied %c\n", *str);
    dest[j++] = *str;
    while (*str && *str == *(str + 1)) {
      str++;
      printf("Skipping %c\n", *str);
    }
    str++;
  }
  dest[j++] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L46
  mov    %rdi,%r15
  mov    $0x1,%ebp
  lea    D5(%rip),%r14
  lea    D19(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L73:
  movsbl %al,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  movsbl (%r15),%esi
  mov    %ebp,0xc(%rsp)
  mov    %sil,-0x1(%r12,%rbp,1)
  test   %sil,%sil
  jne    L31
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %rbx,%rdi
  call   <printf@plt>
  movsbl 0x1(%r13),%esi
  test   %sil,%sil
  je     L69
L31:
  movzbl 0x1(%r15),%eax
  mov    %r15,%r13
  lea    0x1(%r15),%r15
  cmp    %sil,%al
  je     L55
  lea    0x1(%r13),%r15
  add    $0x1,%rbp
  test   %al,%al
  jne    L73
L38:
  movslq 0xc(%rsp),%r13
  add    %r13,%r12
L46:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  movzbl 0x2(%r13),%eax
  mov    %r15,%r13
  add    $0x1,%rbp
  lea    0x1(%r13),%r15
  test   %al,%al
  jne    L73
  jmp    L38
L41:
  movzbl 0x1(%r15),%eax
  mov    %r15,%r13
  add    $0x1,%rbp
  lea    0x1(%r13),%r15
  test   %al,%al
  jne    L73
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D5: Copied %c


tool: D19: Skipping %c


assistant: ```c
void compress(char *str) {
  char *dest = str;
  int j = 0;
  while (*str) {
    printf("Copied %c\n", *str);
    dest[j++] = *str;
    while (*str && *str == *(str + 1)) {
      str++;
      printf("Skipping %c\n", *str);
    }
    str++;
  }
  dest[j++] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  mov    %rdi,%r15
  mov    $0x1,%ebp
  lea    D16(%rip),%r14
  lea    D13(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L74:
  movsbl %al,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  movsbl (%r15),%esi
  mov    %ebp,0xc(%rsp)
  mov    %sil,-0x1(%r12,%rbp,1)
  test   %sil,%sil
  jne    L19
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %rbx,%rdi
  call   <printf@plt>
  movsbl 0x1(%r13),%esi
  test   %sil,%sil
  je     L18
L19:
  movzbl 0x1(%r15),%eax
  mov    %r15,%r13
  lea    0x1(%r15),%r15
  cmp    %sil,%al
  je     L61
  lea    0x1(%r13),%r15
  add    $0x1,%rbp
  test   %al,%al
  jne    L74
L87:
  movslq 0xc(%rsp),%r13
  add    %r13,%r12
L31:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl 0x2(%r13),%eax
  mov    %r15,%r13
  add    $0x1,%rbp
  lea    0x1(%r13),%r15
  test   %al,%al
  jne    L74
  jmp    L87
L50:
  movzbl 0x1(%r15),%eax
  mov    %r15,%r13
  add    $0x1,%rbp
  lea    0x1(%r13),%r15
  test   %al,%al
  jne    L74
  jmp    L87
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D16: Copied %c


tool: D13: Skipping %c


assistant: ```c
void compress(char *str) {
  char *dest = str;
  int j = 0;
  while (*str) {
    printf("Copied %c\n", *str);
    dest[j++] = *str;
    while (*str && *str == *(str + 1)) {
      str++;
      printf("Skipping %c\n", *str);
    }
    str++;
  }
  dest[j++] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L29
L8:
  mov    -0x8(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
L27:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L8
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, c;
  while ((c = getchar()) != EOF) {
    if (i % 20 == 0) {
      putchar('\n');
    }
    putchar(c);
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L14
L27:
  mov    %ebx,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
L14:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D1(%rip),%rax
  cmp    %ebx,(%rax)
  je     L7
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  cmp    %eax,%ebp
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L27
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, c;
  while ((c = getchar()) != EOF) {
    if (i % 20 == 0) {
      putchar('\n');
    }
    putchar(c);
    ++i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    D4(%rip),%r12
  push   %rbp
  push   %rbx
  jmp    L26
  nopl   0x0(%rax)
L9:
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
L26:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r12)
  je     L8
  imul   $0xcccccccd,%ebx,%edx
  add    $0x19999998,%edx
  ror    $0x2,%edx
  cmp    $0xccccccc,%edx
  ja     L9
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L9
  nopl   0x0(%rax)
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int i, c;
  while ((c = getchar()) != EOF) {
    if (i % 20 == 0) {
      putchar('\n');
    }
    putchar(c);
    ++i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    D5(%rip),%r12
  push   %rbp
  push   %rbx
  jmp    L5
  nopl   0x0(%rax)
L2:
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
L5:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r12)
  je     L17
  imul   $0xcccccccd,%ebx,%edx
  add    $0x19999998,%edx
  ror    $0x2,%edx
  cmp    $0xccccccc,%edx
  ja     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L2
  nopl   0x0(%rax)
L17:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main() {
  int i, c;
  while ((c = getchar()) != EOF) {
    if (i % 20 == 0) {
      putchar('\n');
    }
    putchar(c);
    ++i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_rotate_x>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rbx),%xmm3
  movsd  0x40(%rbx),%xmm4
  movapd %xmm0,%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm5
  mulsd  %xmm4,%xmm5
  addsd  %xmm5,%xmm1
  movsd  %xmm1,0x20(%rbx)
  movapd %xmm2,%xmm1
  xorpd  D3(%rip),%xmm1
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x40(%rbx)
  movsd  0x28(%rbx),%xmm3
  movsd  0x48(%rbx),%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  movapd %xmm2,%xmm6
  mulsd  %xmm4,%xmm6
  addsd  %xmm6,%xmm5
  movsd  %xmm5,0x28(%rbx)
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x48(%rbx)
  movsd  0x30(%rbx),%xmm3
  movsd  0x50(%rbx),%xmm4
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  movapd %xmm2,%xmm6
  mulsd  %xmm4,%xmm6
  addsd  %xmm6,%xmm5
  movsd  %xmm5,0x30(%rbx)
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x50(%rbx)
  movsd  0x38(%rbx),%xmm5
  movsd  0x58(%rbx),%xmm4
  movapd %xmm0,%xmm3
  mulsd  %xmm5,%xmm3
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm3
  movsd  %xmm3,0x38(%rbx)
  mulsd  %xmm5,%xmm1
  mulsd  %xmm4,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x58(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix_rotate_x(double *a, double degree) {
  double temp;
  temp = a[4];
  a[4] = (cos(degree) * a[4]) + (sin(degree) * a[8]);
  a[8] = (-sin(degree) * temp) + (cos(degree) * a[8]);
  temp = a[5];
  a[5] = (cos(degree) * a[5]) + (sin(degree) * a[9]);
  a[9] = (-sin(degree) * temp) + (cos(degree) * a[9]);
  temp = a[6];
  a[6] = (cos(degree) * a[6]) + (sin(degree) * a[10]);
  a[10] = (-sin(degree) * temp) + (cos(degree) * a[10]);
  temp = a[7];
  a[7] = (cos(degree) * a[7]) + (sin(degree) * a[11]);
  a[11] = (-sin(degree) * temp) + (cos(degree) * a[11]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_rotate_x>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rbx),%xmm3
  movsd  0x40(%rbx),%xmm4
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm5
  movapd %xmm2,%xmm6
  mulsd  %xmm4,%xmm5
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm4
  addsd  %xmm5,%xmm1
  movapd %xmm0,%xmm5
  movsd  %xmm1,0x20(%rbx)
  movapd %xmm2,%xmm1
  xorpd  D1(%rip),%xmm1
  mulsd  %xmm1,%xmm3
  addsd  %xmm4,%xmm3
  movsd  0x48(%rbx),%xmm4
  mulsd  %xmm4,%xmm6
  movsd  %xmm3,0x40(%rbx)
  movsd  0x28(%rbx),%xmm3
  mulsd  %xmm0,%xmm4
  mulsd  %xmm3,%xmm5
  mulsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm5
  movapd %xmm2,%xmm6
  addsd  %xmm4,%xmm3
  movsd  0x50(%rbx),%xmm4
  movsd  %xmm5,0x28(%rbx)
  mulsd  %xmm4,%xmm6
  movapd %xmm0,%xmm5
  movsd  %xmm3,0x48(%rbx)
  movsd  0x30(%rbx),%xmm3
  mulsd  %xmm0,%xmm4
  mulsd  %xmm3,%xmm5
  mulsd  %xmm1,%xmm3
  addsd  %xmm6,%xmm5
  addsd  %xmm4,%xmm3
  movsd  0x58(%rbx),%xmm4
  movsd  %xmm5,0x30(%rbx)
  movsd  0x38(%rbx),%xmm5
  mulsd  %xmm4,%xmm2
  movsd  %xmm3,0x50(%rbx)
  movapd %xmm0,%xmm3
  mulsd  %xmm5,%xmm3
  mulsd  %xmm5,%xmm1
  mulsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm3
  addsd  %xmm0,%xmm1
  movsd  %xmm3,0x38(%rbx)
  movsd  %xmm1,0x58(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix_rotate_x(double *a, double degree) {
  double temp;
  temp = a[4];
  a[4] = (cos(degree) * a[4]) + (sin(degree) * a[8]);
  a[8] = (-sin(degree) * temp) + (cos(degree) * a[8]);
  temp = a[5];
  a[5] = (cos(degree) * a[5]) + (sin(degree) * a[9]);
  a[9] = (-sin(degree) * temp) + (cos(degree) * a[9]);
  temp = a[6];
  a[6] = (cos(degree) * a[6]) + (sin(degree) * a[10]);
  a[10] = (-sin(degree) * temp) + (cos(degree) * a[10]);
  temp = a[7];
  a[7] = (cos(degree) * a[7]) + (sin(degree) * a[11]);
  a[11] = (-sin(degree) * temp) + (cos(degree) * a[11]);
}
```