ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fputc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xd(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int fputc(int c, FILE *file) {
  int fd;
  char ch = (char)c;
  fd = fileno(file);
  write(fd, &ch, 1);
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %bl,0x7(%rsp)
  call   <fileno@plt>
  mov    %eax,%edi
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputc(int c, FILE *file) {
  int fd;
  char ch = (char)c;
  fd = fileno(file);
  write(fd, &ch, 1);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fputc>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r12b,0x7(%rsp)
  call   <fileno@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputc(int c, FILE *file) {
  int fd;
  char ch = (char)c;
  fd = fileno(file);
  write(fd, &ch, 1);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fputc>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r12b,0x7(%rsp)
  call   <fileno@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fputc(int c, FILE *file) {
  int fd;
  char ch = (char)c;
  fd = fileno(file);
  write(fd, &ch, 1);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<drop_n_dice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_die@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void drop_n_dice(int *dice, int count) {
  int i;
  for (i = 0; i < count; i++) {
    remove_die(dice, dice[0]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<drop_n_dice>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L18:
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  call   <remove_die@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

assistant: ```c
void drop_n_dice(int *dice, int count) {
  int i;
  for (i = 0; i < count; i++) {
    remove_die(dice, dice[0]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<drop_n_dice>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L0:
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <remove_die@plt>
  cmp    %ebx,%r12d
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void drop_n_dice(int *dice, int count) {
  int i;
  for (i = 0; i < count; i++) {
    remove_die(dice, dice[0]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<drop_n_dice>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L9:
  mov    0x0(%rbp),%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <remove_die@plt>
  cmp    %ebx,%r12d
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  ret
```

assistant: ```c
void drop_n_dice(int *dice, int count) {
  int i;
  for (i = 0; i < count; i++) {
    remove_die(dice, dice[0]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: Bonjour le monde


assistant: ```c
int main(int argc, char **argv) {
  puts("Bonjour le monde\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: Bonjour le monde


assistant: ```c
int main(int argc, char **argv) {
  puts("Bonjour le monde\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Bonjour le monde


assistant: ```c
int main(int argc, char **argv) {
  puts("Bonjour le monde\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: Bonjour le monde


assistant: ```c
int main(int argc, char **argv) {
  puts("Bonjour le monde\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BoolPackSolution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L106:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L106
  sub    $0xc80,%rsp
  mov    %rdi,-0x9c68(%rbp)
  mov    %rsi,-0x9c70(%rbp)
  mov    %rdx,-0x9c78(%rbp)
  mov    %ecx,-0x9c7c(%rbp)
  mov    %r8d,-0x9c80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x9c80(%rbp),%eax
  mov    %eax,-0x9c60(%rbp)
  movl   $0x0,-0x9c5c(%rbp)
  movl   $0x0,-0x9c58(%rbp)
  lea    -0x9c50(%rbp),%rax
  mov    $0x9c44,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0x9c54(%rbp)
  jmp    L82
L97:
  mov    -0x9c54(%rbp),%eax
  cltq
  imul   $0x9c44,%rax,%rdx
  mov    -0x9c68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0x9c54(%rbp),%eax
  cltq
  add    $0x1,%rax
  imul   $0x9c44,%rax,%rcx
  mov    -0x9c68(%rbp),%rax
  add    %rax,%rcx
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  cmp    %eax,%edx
  jne    L15
  mov    -0x9c54(%rbp),%eax
  cltq
  movl   $0x0,-0x9c50(%rbp,%rax,4)
  jmp    L77
L15:
  mov    -0x9c54(%rbp),%eax
  cltq
  movl   $0x1,-0x9c50(%rbp,%rax,4)
  mov    -0x9c54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x9c70(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    %eax,-0x9c60(%rbp)
L77:
  addl   $0x1,-0x9c54(%rbp)
L82:
  mov    -0x9c54(%rbp),%eax
  cmp    -0x9c7c(%rbp),%eax
  jl     L97
  mov    -0x9c7c(%rbp),%eax
  cltq
  imul   $0x9c44,%rax,%rdx
  mov    -0x9c68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x9c60(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L54
  mov    -0x9c7c(%rbp),%eax
  cltq
  movl   $0x0,-0x9c50(%rbp,%rax,4)
  jmp    L62
L54:
  mov    -0x9c7c(%rbp),%eax
  cltq
  movl   $0x1,-0x9c50(%rbp,%rax,4)
L62:
  movl   $0x1,-0x9c54(%rbp)
  jmp    L25
L20:
  mov    -0x9c54(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L70
  mov    -0x9c54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x9c70(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x9c5c(%rbp)
  mov    -0x9c54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x9c78(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x9c58(%rbp)
L70:
  addl   $0x1,-0x9c54(%rbp)
L25:
  mov    -0x9c54(%rbp),%eax
  cmp    -0x9c7c(%rbp),%eax
  jle    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void BoolPackSolution(int B[][10000 + 1], int Weight[], int Value[], int num, int C) {
  int j = C, totalWeight = 0, totalValue = 0;
  int i, X[10000 + 1] = {0};
  for (i = 1; i < num; i++) {
    if (B[i][j] == B[i + 1][j])
      X[i] = 0;
    else {
      X[i] = 1;
      j = j - Weight[i];
    }
  }
  if (B[num][j] == 0)
    X[num] = 0;
  else {
    X[num] = 1;
  }
  for (i = 1; i <= num; i++) {
    if (X[i]) {
      totalWeight += Weight[i];
      totalValue += Value[i];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BoolPackSolution>:
  endbr64
  cmp    $0x1,%ecx
  jle    L5
  add    $0x13888,%rdi
  lea    0x4(%rsi),%rax
  lea    -0x2(%rcx),%edx
  lea    0x8(%rsi,%rdx,4),%rsi
  jmp    L41
L31:
  add    $0x9c44,%rdi
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L19
L41:
  movslq %r8d,%rdx
  mov    (%rdi,%rdx,4),%r9d
  cmp    %r9d,-0x9c44(%rdi,%rdx,4)
  je     L31
  sub    (%rax),%r8d
  jmp    L31
L19:
  mov    $0x1,%eax
L20:
  add    $0x1,%eax
  cmp    %eax,%ecx
  jge    L20
L5:
  ret
```

assistant: ```c
void BoolPackSolution(int B[][10000 + 1], int Weight[], int Value[], int num, int C) {
  int j = C, totalWeight = 0, totalValue = 0;
  int i, X[10000 + 1] = {0};
  for (i = 1; i < num; i++) {
    if (B[i][j] == B[i + 1][j])
      X[i] = 0;
    else {
      X[i] = 1;
      j = j - Weight[i];
    }
  }
  if (B[num][j] == 0)
    X[num] = 0;
  else {
    X[num] = 1;
  }
  for (i = 1; i <= num; i++) {
    if (X[i]) {
      totalWeight += Weight[i];
      totalValue += Value[i];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BoolPackSolution>:
  endbr64
  ret
```

assistant: ```c
void BoolPackSolution(int B[][10000 + 1], int Weight[], int Value[], int num, int C) {
  int j = C, totalWeight = 0, totalValue = 0;
  int i, X[10000 + 1] = {0};
  for (i = 1; i < num; i++) {
    if (B[i][j] == B[i + 1][j])
      X[i] = 0;
    else {
      X[i] = 1;
      j = j - Weight[i];
    }
  }
  if (B[num][j] == 0)
    X[num] = 0;
  else {
    X[num] = 1;
  }
  for (i = 1; i <= num; i++) {
    if (X[i]) {
      totalWeight += Weight[i];
      totalValue += Value[i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__scan_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__scan_float_int@plt>
  fstpt  -0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x31(%rbp)
  cmpb   $0x2e,-0x31(%rbp)
  jne    L8
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__scan_float_uint@plt>
  fstpt  -0x30(%rbp)
  jmp    L29
L8:
  movsbl -0x31(%rbp),%eax
  mov    -0x48(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  fldz
  fstpt  -0x30(%rbp)
L29:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x31(%rbp)
  cmpb   $0x65,-0x31(%rbp)
  je     L42
  cmpb   $0x45,-0x31(%rbp)
  jne    L49
L42:
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__scan_float_int@plt>
  fstpt  -0x20(%rbp)
  jmp    L16
L49:
  movsbl -0x31(%rbp),%eax
  mov    -0x48(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  fldz
  fstpt  -0x20(%rbp)
L16:
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  call   <log10l@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  call   <ceill@plt>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    $0xa,%edi
  call   <powl@plt>
  add    $0x10,%rsp
  fldt   -0x30(%rbp)
  fdivp  %st,%st(1)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x60(%rbp)
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  mov    $0xa,%edi
  call   <powl@plt>
  add    $0x10,%rsp
  fldt   -0x60(%rbp)
  fmulp  %st,%st(1)
  leave
  ret
```

assistant: ```c
long double __scan_float(FILE *stream, int flags) {
  long double i_part;
  long double f_part;
  long double e_part;
  char c;
  i_part = __scan_float_int(stream, flags);
  c = getc(stream);
  if (c == '.') {
    f_part = __scan_float_uint(stream, flags);
  } else {
    ungetc(c, stream);
    f_part = 0.0;
  }
  c = getc(stream);
  if (c == 'e' || c == 'E') {
    e_part = __scan_float_int(stream, flags);
  } else {
    ungetc(c, stream);
    e_part = 0.0;
  }
  return (i_part + f_part / powl(10, ceill(log10l(f_part)))) * powl(10, e_part);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__scan_float>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <__scan_float_int@plt>
  fstpt  0x20(%rsp)
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    $0x2e,%al
  je     L14
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <ungetc@plt>
  fldz
  fstpt  (%rsp)
L18:
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x45,%dl
  jne    L6
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <__scan_float_int@plt>
  fstpt  0x10(%rsp)
L21:
  push   0x8(%rsp)
  push   0x8(%rsp)
  call   <log10l@plt>
  mov    %eax,%edi
  call   <ceill@plt>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    $0xa,%edi
  call   <powl@plt>
  fldt   0x20(%rsp)
  fdivp  %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  add    $0x20,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  mov    $0xa,%edi
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <__scan_float_uint@plt>
  fstpt  (%rsp)
  jmp    L18
L6:
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <ungetc@plt>
  fldz
  fstpt  0x10(%rsp)
  jmp    L21
```

assistant: ```c
long double __scan_float(FILE *stream, int flags) {
  long double i_part;
  long double f_part;
  long double e_part;
  char c;
  i_part = __scan_float_int(stream, flags);
  c = getc(stream);
  if (c == '.') {
    f_part = __scan_float_uint(stream, flags);
  } else {
    ungetc(c, stream);
    f_part = 0.0;
  }
  c = getc(stream);
  if (c == 'e' || c == 'E') {
    e_part = __scan_float_int(stream, flags);
  } else {
    ungetc(c, stream);
    e_part = 0.0;
  }
  return (i_part + f_part / powl(10, ceill(log10l(f_part)))) * powl(10, e_part);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__scan_float>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  call   <__scan_float_int@plt>
  mov    %rbp,%rdi
  fstpt  0x10(%rsp)
  call   <getc@plt>
  cmp    $0x2e,%al
  je     L23
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  fldz
  fstpt  (%rsp)
L22:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x45,%dl
  jne    L39
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__scan_float_int@plt>
L15:
  fstpt  0x20(%rsp)
  push   0x8(%rsp)
  push   0x8(%rsp)
  call   <log10l@plt>
  mov    %eax,%edi
  call   <ceill@plt>
  sub    $0x10,%rsp
  mov    $0xa,%edi
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   0x20(%rsp)
  mov    $0xa,%edi
  fdivp  %st,%st(1)
  fldt   0x30(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  pop    %rax
  pop    %rdx
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   0x10(%rsp)
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  fmulp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L39:
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  fldz
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__scan_float_uint@plt>
  fstpt  (%rsp)
  jmp    L22
```

assistant: ```c
long double __scan_float(FILE *stream, int flags) {
  long double i_part;
  long double f_part;
  long double e_part;
  char c;
  i_part = __scan_float_int(stream, flags);
  c = getc(stream);
  if (c == '.') {
    f_part = __scan_float_uint(stream, flags);
  } else {
    ungetc(c, stream);
    f_part = 0.0;
  }
  c = getc(stream);
  if (c == 'e' || c == 'E') {
    e_part = __scan_float_int(stream, flags);
  } else {
    ungetc(c, stream);
    e_part = 0.0;
  }
  return (i_part + f_part / powl(10, ceill(log10l(f_part)))) * powl(10, e_part);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__scan_float>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  call   <__scan_float_int@plt>
  mov    %rbp,%rdi
  fstpt  0x10(%rsp)
  call   <getc@plt>
  cmp    $0x2e,%al
  je     L35
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  fldz
  fstpt  (%rsp)
L21:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  cmp    $0x45,%dl
  jne    L13
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__scan_float_int@plt>
L14:
  fstpt  0x20(%rsp)
  push   0x8(%rsp)
  push   0x8(%rsp)
  call   <log10l@plt>
  mov    %eax,%edi
  call   <ceill@plt>
  sub    $0x10,%rsp
  mov    $0xa,%edi
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   0x20(%rsp)
  mov    $0xa,%edi
  fdivp  %st,%st(1)
  fldt   0x30(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  pop    %rax
  pop    %rdx
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  call   <powl@plt>
  fldt   0x10(%rsp)
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  fmulp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L13:
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  fldz
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <__scan_float_uint@plt>
  fstpt  (%rsp)
  jmp    L21
```

assistant: ```c
long double __scan_float(FILE *stream, int flags) {
  long double i_part;
  long double f_part;
  long double e_part;
  char c;
  i_part = __scan_float_int(stream, flags);
  c = getc(stream);
  if (c == '.') {
    f_part = __scan_float_uint(stream, flags);
  } else {
    ungetc(c, stream);
    f_part = 0.0;
  }
  c = getc(stream);
  if (c == 'e' || c == 'E') {
    e_part = __scan_float_int(stream, flags);
  } else {
    ungetc(c, stream);
    e_part = 0.0;
  }
  return (i_part + f_part / powl(10, ceill(log10l(f_part)))) * powl(10, e_part);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0x123456789abcdef,%rax
  push   %rax
  nop
  pop    %rbp
  ret
```

assistant: ```c
void push() {
  asm volatile("movq $0x0123456789abcdef, %%rax\n\t"
               "pushq %%rax\n\t" ::
                   :);
}
```
user: What is the c source code of the assembly code below:

```asm
<push>:
  endbr64
  movabs $0x123456789abcdef,%rax
  push   %rax
  ret
```

assistant: ```c
void push() {
  asm volatile("movq $0x0123456789abcdef, %%rax\n\t"
               "pushq %%rax\n\t" ::
                   :);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<push>:
  endbr64
  movabs $0x123456789abcdef,%rax
  push   %rax
  ret
```

assistant: ```c
void push() {
  asm volatile("movq $0x0123456789abcdef, %%rax\n\t"
               "pushq %%rax\n\t" ::
                   :);
}
```
user: Translate the below assembly code into C programming language:

```asm
<push>:
  endbr64
  movabs $0x123456789abcdef,%rax
  push   %rax
  ret
```

assistant: ```c
void push() {
  asm volatile("movq $0x0123456789abcdef, %%rax\n\t"
               "pushq %%rax\n\t" ::
                   :);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nand_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <nand_select@plt>
  jmp    L0
L40:
  mov    $0x0,%edi
  call   <nand_cmd@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <nand_send_addr@plt>
  mov    $0x30,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_ready@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L48
L36:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <nand_get_data@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x20(%rbp)
L48:
  cmpl   $0xfff,-0x20(%rbp)
  jg     L37
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  ja     L36
L37:
  addl   $0x1000,-0x24(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  ja     L40
  mov    $0x0,%eax
  call   <nand_deselect@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int nand_read(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned int addr = nand_start;
  int i, count = 0;
  unsigned char *dest = (unsigned char *)ddr_start;
  nand_select();
  while (count < len) {
    nand_cmd(0x00);
    nand_send_addr(addr);
    nand_cmd(0x30);
    wait_ready();
    for (i = 0; i < 4096 && count < len; i++) {
      dest[count++] = nand_get_data();
    }
    addr += 4096;
  }
  nand_deselect();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nand_read>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    $0x0,%eax
  call   <nand_select@plt>
  test   %r13d,%r13d
  je     L28
  mov    $0x0,%r12d
  mov    %r14d,%r14d
L1:
  mov    $0x0,%edi
  call   <nand_cmd@plt>
  mov    %r15d,%edi
  call   <nand_send_addr@plt>
  mov    $0x30,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_ready@plt>
  cmp    %r12d,%r13d
  jbe    L28
  add    $0x1,%r12d
  movslq %r12d,%rbx
  mov    $0x0,%ebp
L0:
  mov    %ebx,%r12d
  mov    $0x0,%eax
  call   <nand_get_data@plt>
  mov    %al,-0x1(%rbx,%r14,1)
  add    $0x1,%ebp
  cmp    $0xfff,%ebp
  setle  %dl
  cmp    %ebx,%r13d
  seta   %al
  add    $0x1,%rbx
  test   %al,%dl
  jne    L0
  add    $0x1000,%r15d
  cmp    %r12d,%r13d
  ja     L1
L28:
  mov    $0x0,%eax
  call   <nand_deselect@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nand_read(unsigned int nand_start, unsigned int ddr_start, unsigned int len) {
  unsigned int addr = nand_start;
  int i, count = 0;
  unsigned char *dest = (unsigned char *)ddr_start;
  nand_select();
  while (count < len) {
    nand_cmd(0x00);
    nand_send_addr(addr);
    nand_cmd(0x30);
    wait_ready();
    for (i = 0; i < 4096 && count < len; i++) {
      dest[count++] = nand_get_data();
    }
    addr += 4096;
  }
  nand_deselect();
  return 0;
}
```