ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D26(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    $0x1,%eax
  jle    L11
  mov    $0x1,%r12d
  lea    D3(%rip),%rbp
  mov    $0xaaaaaaab,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  lea    -0x1(%r12),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  or     %esi,%edx
  and    %r12d,%esi
  add    $0x1,%r12d
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  imul   %rbx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edx
  mov    %esi,%eax
  imul   %rbx,%rax
  add    $0x1,%edx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x1,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    %r12d,%eax
  jg     L18
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D3
datatype: string

tool: D26: Enter the number of Disks

tool: D7: %d

tool: D3: 
Move from Peg %d to Peg %d

assistant: ```c
int main() {
  printf("Enter the number of Disks");
  int n;
  scanf("%d", &n);
  for (int i = 1; i < (1 << n); i++)
    printf("\nMove from Peg %d to Peg %d", (i & i - 1) % 3 + 1, ((i | i - 1) + 1) % 3 + 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    $0x1,%eax
  jle    L17
  mov    $0x1,%r12d
  lea    D2(%rip),%rbp
  mov    $0xaaaaaaab,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%r12),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  or     %esi,%edx
  and    %r12d,%esi
  add    $0x1,%r12d
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  imul   %rbx,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edx
  mov    %esi,%eax
  imul   %rbx,%rax
  add    $0x1,%edx
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x1,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    %r12d,%eax
  jg     L6
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D18: Enter the number of Disks

tool: D4: %d

tool: D2: 
Move from Peg %d to Peg %d

assistant: ```c
int main() {
  printf("Enter the number of Disks");
  int n;
  scanf("%d", &n);
  for (int i = 1; i < (1 << n); i++)
    printf("\nMove from Peg %d to Peg %d", (i & i - 1) % 3 + 1, ((i | i - 1) + 1) % 3 + 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tidFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: thread: thread
	pid: %u, tid: %u(%#0x)


assistant: ```c
void *tidFunc(void *args) {
  printf("thread: thread\n\tpid: %u, tid: %u(%#0x)\n", (unsigned int)getpid(), (unsigned int)pthread_self(), (unsigned int)pthread_self());
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tidFunc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: thread: thread
	pid: %u, tid: %u(%#0x)


assistant: ```c
void *tidFunc(void *args) {
  printf("thread: thread\n\tpid: %u, tid: %u(%#0x)\n", (unsigned int)getpid(), (unsigned int)pthread_self(), (unsigned int)pthread_self());
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tidFunc>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <pthread_self@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <pthread_self@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: thread: thread
	pid: %u, tid: %u(%#0x)


assistant: ```c
void *tidFunc(void *args) {
  printf("thread: thread\n\tpid: %u, tid: %u(%#0x)\n", (unsigned int)getpid(), (unsigned int)pthread_self(), (unsigned int)pthread_self());
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tidFunc>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <pthread_self@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <pthread_self@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: thread: thread
	pid: %u, tid: %u(%#0x)


assistant: ```c
void *tidFunc(void *args) {
  printf("thread: thread\n\tpid: %u, tid: %u(%#0x)\n", (unsigned int)getpid(), (unsigned int)pthread_self(), (unsigned int)pthread_self());
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L65
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  mov    $0x0,%eax
  jmp    L42
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L42
L19:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    $0x1,%eax
  jmp    L42
L53:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L0
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L95
  mov    $0xffffffff,%eax
  jmp    L42
L95:
  mov    $0x1,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1 == *s2; s1++, s2++) {
    if (*s1 == '\0' && *s2 == '\0')
      return 0;
    if (*s1 == '\0')
      return -1;
    if (*s2 == '\0')
      return 1;
  }
  if (*s1 == '\0')
    return -1;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  cmp    %dl,%al
  jne    L46
  mov    $0x1,%ecx
L11:
  mov    %eax,%r8d
  or     %dl,%r8b
  je     L18
  test   %al,%al
  je     L36
  test   %dl,%dl
  je     L41
  movzbl (%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  movzbl -0x1(%rsi,%rcx,1),%edx
  cmp    %dl,%al
  je     L11
L46:
  cmp    $0x1,%al
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
L36:
  mov    $0xffffffff,%eax
  ret
L41:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1 == *s2; s1++, s2++) {
    if (*s1 == '\0' && *s2 == '\0')
      return 0;
    if (*s1 == '\0')
      return -1;
    if (*s2 == '\0')
      return 1;
  }
  if (*s1 == '\0')
    return -1;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L31
  mov    $0x1,%eax
  jmp    L9
  nopl   (%rax)
L38:
  test   %cl,%cl
  je     L41
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L31
L9:
  test   %dl,%dl
  jne    L38
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L31:
  cmp    $0x1,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nopl   0x0(%rax)
L41:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1 == *s2; s1++, s2++) {
    if (*s1 == '\0' && *s2 == '\0')
      return 0;
    if (*s1 == '\0')
      return -1;
    if (*s2 == '\0')
      return 1;
  }
  if (*s1 == '\0')
    return -1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L40
  mov    $0x1,%eax
  jmp    L41
  nopl   (%rax)
L18:
  test   %cl,%cl
  je     L35
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L40
L41:
  test   %dl,%dl
  jne    L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L40:
  cmp    $0x1,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nopl   0x0(%rax)
L35:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  for (; *s1 == *s2; s1++, s2++) {
    if (*s1 == '\0' && *s2 == '\0')
      return 0;
    if (*s1 == '\0')
      return -1;
    if (*s2 == '\0')
      return 1;
  }
  if (*s1 == '\0')
    return -1;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<filter2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    0x14(%rdi),%r15
  mov    $0x0,%r13d
L12:
  mov    -0x44(%rbp),%esi
  mov    (%rbx),%edi
  call   *%r14
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r13d
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L12
  movslq %r13d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L95:
  cmp    %rdx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L95
L17:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L4
  orq    $0x0,-0x8(%rsp,%rax,1)
L4:
  mov    %rsp,-0x50(%rbp)
  mov    $0x0,%ebx
  jmp    L92
L52:
  add    $0x4,%r12
  cmp    %r15,%r12
  je     L102
L92:
  mov    -0x44(%rbp),%esi
  mov    (%r12),%edi
  call   *%r14
  test   %eax,%eax
  je     L52
  movslq %ebx,%rax
  mov    (%r12),%edx
  mov    -0x50(%rbp),%rcx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%ebx
  jmp    L52
L102:
  test   %r13d,%r13d
  jle    L19
  mov    -0x50(%rbp),%rax
  mov    %rax,%rbx
  mov    %r13d,%r13d
  lea    (%rax,%r13,4),%r13
  lea    D9(%rip),%r12
L2:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L2
L19:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %d 


assistant: ```c
void filter2(const int *myarray, int (*comp)(const int, const int), const int val) {
  int count = 0;
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      count += 1;
  }
  int retarray[count];
  int index = 0;
  for (int j = 0; j < 5; j++) {
    if (comp(myarray[j], val)) {
      retarray[index] = myarray[j];
      index += 1;
    }
  }
  for (int k = 0; k < count; k++)
    printf("%d \n", retarray[k]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<filter2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x14(%rdi),%rax
  mov    %rax,-0x48(%rbp)
L39:
  mov    (%r15),%edi
  mov    %r13d,%esi
  call   *%r12
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  add    $0x4,%r15
  cmp    -0x48(%rbp),%r15
  jne    L39
  movslq %ebx,%rax
  mov    %rsp,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L35
L55:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L55
L35:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L38
L4:
  mov    %rsp,-0x50(%rbp)
  xor    %r15d,%r15d
L22:
  mov    (%r14),%edi
  mov    %r13d,%esi
  call   *%r12
  test   %eax,%eax
  je     L71
  mov    (%r14),%ecx
  mov    -0x50(%rbp),%rdx
  movslq %r15d,%rax
  add    $0x1,%r15d
  mov    %ecx,(%rdx,%rax,4)
L71:
  add    $0x4,%r14
  cmp    -0x48(%rbp),%r14
  jne    L22
  test   %ebx,%ebx
  je     L90
  mov    -0x50(%rbp),%r12
  mov    %ebx,%ebx
  lea    (%r12,%rbx,4),%r13
  lea    D5(%rip),%rbx
  nopl   (%rax)
L88:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %r13,%r12
  jne    L88
L90:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L4
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: %d 


assistant: ```c
void filter2(const int *myarray, int (*comp)(const int, const int), const int val) {
  int count = 0;
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      count += 1;
  }
  int retarray[count];
  int index = 0;
  for (int j = 0; j < 5; j++) {
    if (comp(myarray[j], val)) {
      retarray[index] = myarray[j];
      index += 1;
    }
  }
  for (int k = 0; k < count; k++)
    printf("%d \n", retarray[k]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filter2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x14(%rdi),%rax
  mov    %rax,-0x48(%rbp)
L3:
  mov    (%r15),%edi
  mov    %r13d,%esi
  call   *%r12
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ebx
  add    $0x4,%r15
  cmp    -0x48(%rbp),%r15
  jne    L3
  movslq %ebx,%rax
  mov    %rsp,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L8
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L60
L8:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L38
L29:
  mov    %rsp,-0x50(%rbp)
  xor    %r15d,%r15d
L76:
  mov    (%r14),%edi
  mov    %r13d,%esi
  call   *%r12
  test   %eax,%eax
  je     L87
  mov    (%r14),%ecx
  mov    -0x50(%rbp),%rdx
  movslq %r15d,%rax
  add    $0x1,%r15d
  mov    %ecx,(%rdx,%rax,4)
L87:
  add    $0x4,%r14
  cmp    -0x48(%rbp),%r14
  jne    L76
  test   %ebx,%ebx
  je     L75
  mov    -0x50(%rbp),%r12
  mov    %ebx,%ebx
  lea    (%r12,%rbx,4),%r13
  lea    D9(%rip),%rbx
  nopl   (%rax)
L83:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %r13,%r12
  jne    L83
L75:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L29
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: %d 


assistant: ```c
void filter2(const int *myarray, int (*comp)(const int, const int), const int val) {
  int count = 0;
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      count += 1;
  }
  int retarray[count];
  int index = 0;
  for (int j = 0; j < 5; j++) {
    if (comp(myarray[j], val)) {
      retarray[index] = myarray[j];
      index += 1;
    }
  }
  for (int k = 0; k < count; k++)
    printf("%d \n", retarray[k]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mc_io_readable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x2c(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  lea    -0x28(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  cmpl   $0x0,-0x38(%rbp)
  je     L107
  mov    -0x38(%rbp),%eax
  test   %rax,%rax
  js     L39
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L79
L39:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L79:
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%eax
  mov    %rax,-0x18(%rbp)
L107:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L45
  mov    $0xffffffff,%eax
  jmp    L89
L45:
  cmpl   $0x0,-0x24(%rbp)
  jle    L80
  lea    -0x28(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L23
  mov    $0xffffffff,%eax
  jmp    L89
L23:
  lea    -0x2c(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L80
  mov    $0x1,%eax
  jmp    L89
L80:
  mov    $0x0,%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: f64

tool: D9: 0.001

assistant: ```c
int mc_io_readable(int fd, unsigned int timedout) {
  struct timeval tv = {0, 0};
  fd_set fds;
  fd_set fd_error;
  int retval;
  FD_ZERO(&fds);
  FD_ZERO(&fd_error);
  FD_SET(fd, &fds);
  FD_SET(fd, &fd_error);
  if (timedout > 0) {
    tv.tv_sec = (long)(timedout * 0.001);
    tv.tv_usec = (long)((timedout % 1000) * 1000);
  }
  retval = select((int)(fd + 1), &fds, NULL, &fd_error, &tv);
  if (retval < 0) {
    return (-1);
  }
  if (retval > 0) {
    if (FD_ISSET(fd, &fd_error)) {
      return (-1);
    }
    if (FD_ISSET(fd, &fds)) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mc_io_readable>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    0x8(%rsp),%r13
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  test   %ebx,%ebx
  je     L36
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,0x10(%rsp)
  mov    %ebx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,%eax
  mov    %rax,0x18(%rsp)
L36:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  lea    0x1(%rbp),%edi
  lea    0x10(%rsp),%r8
  mov    $0x0,%edx
  call   <select@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  js     L50
  mov    $0x0,%edx
  jg     L39
L50:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %edx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  lea    0xc(%rsp),%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  mov    $0xffffffff,%edx
  test   %rax,%rax
  jne    L50
  lea    0x8(%rsp),%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  setne  %dl
  movzbl %dl,%edx
  jmp    L50
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: f64

tool: D4: 0.001

assistant: ```c
int mc_io_readable(int fd, unsigned int timedout) {
  struct timeval tv = {0, 0};
  fd_set fds;
  fd_set fd_error;
  int retval;
  FD_ZERO(&fds);
  FD_ZERO(&fd_error);
  FD_SET(fd, &fds);
  FD_SET(fd, &fd_error);
  if (timedout > 0) {
    tv.tv_sec = (long)(timedout * 0.001);
    tv.tv_usec = (long)((timedout % 1000) * 1000);
  }
  retval = select((int)(fd + 1), &fds, NULL, &fd_error, &tv);
  if (retval < 0) {
    return (-1);
  }
  if (retval > 0) {
    if (FD_ISSET(fd, &fd_error)) {
      return (-1);
    }
    if (FD_ISSET(fd, &fds)) {
      return 1;
    }
  }
  return 0;
}
```