user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movq   $0x0,-0x50(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  jmp    L29
L36:
  addq   $0x1,-0x50(%rbp)
  mov    -0x60(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x60(%rbp)
L29:
  mov    -0x60(%rbp),%rax
  test   %rax,%rax
  jne    L36
  mov    -0x50(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    %rax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    %rax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L107:
  cmp    %rdx,%rsp
  je     L26
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L107
L26:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L58
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L58:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x64(%rbp)
  jmp    L4
L59:
  mov    -0x58(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%ecx
  movslq %ecx,%rcx
  mov    %rdx,(%rax,%rcx,8)
  mov    -0x58(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x58(%rbp)
  subl   $0x1,-0x64(%rbp)
L4:
  cmpl   $0x0,-0x64(%rbp)
  jns    L59
  movl   $0x0,-0x64(%rbp)
  jmp    L53
L43:
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L1
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  lea    0x1(%rax),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    %rcx,(%rax,%rdx,8)
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L44
L1:
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    %rcx,(%rax,%rdx,8)
  mov    -0x40(%rbp),%rax
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  addl   $0x1,-0x64(%rbp)
L53:
  mov    -0x64(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  jg     L43
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L112
  call   <__stack_chk_fail@plt>
L112:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
datatype: string

tool: D28: %ld

assistant: ```c
int main() {
  long l, k, sirina = 0;
  scanf("%ld", &l);
  k = l;
  while (l) {
    sirina++;
    l /= 10;
  }
  long x[sirina];
  int i;
  for (i = sirina - 1; i >= 0; i--) {
    x[i] = k % 10;
    k /= 10;
  }
  for (i = 0; i < sirina; i++)
    if (x[i] % 2 == 0)
      printf("%ld", x[i] += 1);
    else
      printf("%ld", x[i] -= 1);
  printf("\n");
  return 0;
}
```