ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<gpio_get_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x36,-0x14(%rbp)
  jle    L9
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L9:
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  shl    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x200034,%eax
  mov    %eax,%edi
  call   <bcm2835_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: GPIO%d too big


assistant: ```c
int gpio_get_value(int which_one) {
  uint32_t address_offset, bit;
  uint32_t result;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  result = bcm2835_read(((0 + 0x200000) + 0x34) + address_offset);
  result = !!(result & bit);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gpio_get_value>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x36,%edi
  jg     L17
  lea    0x1f(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x200034(,%rax,4),%edi
  call   <bcm2835_read@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  test   %edx,%eax
  setne  %al
  movzbl %al,%eax
L15:
  pop    %rbx
  ret
L17:
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: GPIO%d too big


assistant: ```c
int gpio_get_value(int which_one) {
  uint32_t address_offset, bit;
  uint32_t result;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  result = bcm2835_read(((0 + 0x200000) + 0x34) + address_offset);
  result = !!(result & bit);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpio_get_value>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x36,%edi
  jg     L8
  test   %edi,%edi
  lea    0x1f(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x200034(,%rax,4),%edi
  call   <bcm2835_read@plt>
  mov    %r12d,%ecx
  pop    %r12
  mov    %eax,%r8d
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %r8d,%eax
  setne  %al
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L8:
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: GPIO%d too big


assistant: ```c
int gpio_get_value(int which_one) {
  uint32_t address_offset, bit;
  uint32_t result;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  result = bcm2835_read(((0 + 0x200000) + 0x34) + address_offset);
  result = !!(result & bit);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gpio_get_value>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x36,%edi
  jg     L4
  test   %edi,%edi
  lea    0x1f(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x200034(,%rax,4),%edi
  call   <bcm2835_read@plt>
  mov    %r12d,%ecx
  pop    %r12
  mov    %eax,%r8d
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %r8d,%eax
  setne  %al
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L4:
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: GPIO%d too big


assistant: ```c
int gpio_get_value(int which_one) {
  uint32_t address_offset, bit;
  uint32_t result;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  result = bcm2835_read(((0 + 0x200000) + 0x34) + address_offset);
  result = !!(result & bit);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linfo_se>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L9:
  nop
  leave
  ret
```

assistant: ```c
void linfo_se(int len, int info, int *value1, int *dummy) {
  int n;
  n = (int)pow(2, (len / 2)) + info - 1;
  *value1 = (n + 1) / 2;
  if ((n & 0x01) == 0)
    *value1 = -*value1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<linfo_se>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %edi,%eax
  shr    $0x1f,%eax
  lea    (%rax,%rdi,1),%esi
  sar    %esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    0x0(%rbp,%rax,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  neg    %ecx
  test   $0x1,%dl
  cmovne %ecx,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void linfo_se(int len, int info, int *value1, int *dummy) {
  int n;
  n = (int)pow(2, (len / 2)) + info - 1;
  *value1 = (n + 1) / 2;
  if ((n & 0x01) == 0)
    *value1 = -*value1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<linfo_se>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %rdx,%rbp
  push   %rbx
  shr    $0x1f,%eax
  mov    %esi,%ebx
  lea    (%rax,%rdi,1),%esi
  mov    $0x2,%edi
  sar    %esi
  sub    $0x8,%rsp
  call   <pow@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  neg    %ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void linfo_se(int len, int info, int *value1, int *dummy) {
  int n;
  n = (int)pow(2, (len / 2)) + info - 1;
  *value1 = (n + 1) / 2;
  if ((n & 0x01) == 0)
    *value1 = -*value1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<linfo_se>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %rdx,%rbp
  push   %rbx
  shr    $0x1f,%eax
  mov    %esi,%ebx
  lea    (%rax,%rdi,1),%esi
  mov    $0x2,%edi
  sar    %esi
  sub    $0x8,%rsp
  call   <pow@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  neg    %ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void linfo_se(int len, int info, int *value1, int *dummy) {
  int n;
  n = (int)pow(2, (len / 2)) + info - 1;
  *value1 = (n + 1) / 2;
  if ((n & 0x01) == 0)
    *value1 = -*value1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strrm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L12
  addl   $0x1,-0x8(%rbp)
L12:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strrm(char *dest, const char *src, char ch) {
  int j = 0;
  for (int i = 0; src[i]; i++) {
    dest[j] = src[i];
    if (dest[j] != ch) {
      j++;
    }
  }
  dest[j] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strrm>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L2
  add    $0x1,%rsi
  mov    $0x0,%ecx
L5:
  movslq %ecx,%r8
  mov    %al,(%rdi,%r8,1)
  cmp    %al,%dl
  setne  %al
  movzbl %al,%eax
  add    %eax,%ecx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L5
L24:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  ret
L2:
  mov    $0x0,%ecx
  jmp    L24
```

assistant: ```c
void strrm(char *dest, const char *src, char ch) {
  int j = 0;
  for (int i = 0; src[i]; i++) {
    dest[j] = src[i];
    if (dest[j] != ch) {
      j++;
    }
  }
  dest[j] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrm>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L8
  add    $0x1,%rsi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   (%rax)
L24:
  lea    (%rdi,%r8,1),%rcx
  mov    %al,(%rcx)
  cmp    %al,%dl
  je     L13
  add    $0x1,%r9d
  movslq %r9d,%r8
  lea    (%rdi,%r8,1),%rcx
L13:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  jne    L24
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void strrm(char *dest, const char *src, char ch) {
  int j = 0;
  for (int i = 0; src[i]; i++) {
    dest[j] = src[i];
    if (dest[j] != ch) {
      j++;
    }
  }
  dest[j] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrm>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L8
  add    $0x1,%rsi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   (%rax)
L28:
  lea    (%rdi,%r8,1),%rcx
  mov    %al,(%rcx)
  cmp    %al,%dl
  je     L29
  add    $0x1,%r9d
  movslq %r9d,%r8
  lea    (%rdi,%r8,1),%rcx
L29:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  jne    L28
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void strrm(char *dest, const char *src, char ch) {
  int j = 0;
  for (int i = 0; src[i]; i++) {
    dest[j] = src[i];
    if (dest[j] != ch) {
      j++;
    }
  }
  dest[j] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blStrLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L19:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int blStrLen(const char *string) {
  int i = 0;
  for (; *string++; i++)
    ;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<blStrLen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L2:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L2
L10:
  mov    %ecx,%eax
  ret
L23:
  mov    $0x0,%ecx
  jmp    L10
```

assistant: ```c
int blStrLen(const char *string) {
  int i = 0;
  for (; *string++; i++)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<blStrLen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L13
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L16:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int blStrLen(const char *string) {
  int i = 0;
  for (; *string++; i++)
    ;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<blStrLen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L2
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L11:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int blStrLen(const char *string) {
  int i = 0;
  for (; *string++; i++)
    ;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<toBaseFib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    -0x48(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoull@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x5,%edi
  call   <sqrt@plt>
  imul   -0x30(%rbp),%rax
  test   %rax,%rax
  js     L1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L58
L1:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L58:
  movsd  D16(%rip),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%ebx
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getFibonacci@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L30
L6:
  mov    -0x34(%rbp),%eax
  sub    -0x38(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L20
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x31,(%rax)
  jmp    L12
L20:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L12:
  addl   $0x1,-0x38(%rbp)
L30:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L6
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type: f64
name: unpack_data
arguments: label: D12
type: f64

tool: D16: 0.5

tool: D12: 1.61803398875

assistant: ```c
void toBaseFib(char *value, char *result) {
  unsigned long long n = strtoull(value, NULL, 10);
  double temp = n * sqrt(5) + 0.5;
  int size = (int)(log(temp) / log(1.61803398875));
  unsigned long long *fibonacci = malloc(sizeof(unsigned long long) * size);
  getFibonacci(fibonacci, size);
  for (int i = 0; i < size; i++) {
    unsigned long long F = fibonacci[size - i - 1];
    if (n >= F) {
      n -= F;
      result[i] = '1';
    } else {
      result[i] = '0';
    }
  }
  result[size] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toBaseFib>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoull@plt>
  mov    %rax,%rbx
  mov    $0x5,%edi
  call   <sqrt@plt>
  imul   %rbx,%rax
  test   %rax,%rax
  js     L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L11:
  addsd  D16(%rip),%xmm0
  call   <log@plt>
  mov    %eax,%r13d
  movsd  D0(%rip),%xmm0
  call   <log@plt>
  mov    %eax,%ecx
  mov    %r13d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
  movslq %eax,%r12
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <getFibonacci@plt>
  test   %r13d,%r13d
  jle    L53
  lea    -0x8(%r14,%r12,8),%rcx
  mov    %rbp,%rdx
  lea    -0x1(%r13),%eax
  lea    0x1(%rbp,%rax,1),%rsi
  jmp    L27
L4:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L11
L39:
  movb   $0x30,(%rdx)
L14:
  sub    $0x8,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L53
L27:
  mov    (%rcx),%rax
  cmp    %rbx,%rax
  ja     L39
  sub    %rax,%rbx
  movb   $0x31,(%rdx)
  jmp    L14
L53:
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
type: f64
name: disassemble_data
arguments: label: D0
type: f64

tool: D16: 0.5

tool: D0: 1.61803398875

assistant: ```c
void toBaseFib(char *value, char *result) {
  unsigned long long n = strtoull(value, NULL, 10);
  double temp = n * sqrt(5) + 0.5;
  int size = (int)(log(temp) / log(1.61803398875));
  unsigned long long *fibonacci = malloc(sizeof(unsigned long long) * size);
  getFibonacci(fibonacci, size);
  for (int i = 0; i < size; i++) {
    unsigned long long F = fibonacci[size - i - 1];
    if (n >= F) {
      n -= F;
      result[i] = '1';
    } else {
      result[i] = '0';
    }
  }
  result[size] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<toBaseFib>:
  endbr64
  push   %r14
  mov    $0xa,%edx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  call   <strtoull@plt>
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  imul   %rbx,%rax
  test   %rax,%rax
  js     L15
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L16:
  addsd  D16(%rip),%xmm0
  call   <log@plt>
  movsd  D8(%rip),%xmm0
  mov    %eax,%r12d
  call   <log@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  movslq %eax,%r14
  lea    0x0(,%r14,8),%edi
  call   <malloc@plt>
  mov    %r14d,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <getFibonacci@plt>
  test   %r14d,%r14d
  jle    L20
  lea    -0x1(%r14),%eax
  lea    -0x8(%r13,%r14,8),%rcx
  mov    %rbp,%rdx
  lea    0x1(%rbp,%rax,1),%rdi
  nopl   0x0(%rax)
L44:
  mov    (%rcx),%rsi
  mov    $0x30,%eax
  cmp    %rbx,%rsi
  ja     L3
  sub    %rsi,%rbx
  mov    $0x31,%eax
L3:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  sub    $0x8,%rcx
  cmp    %rdi,%rdx
  jne    L44
L20:
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r14,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: f64
name: retrieve_data
arguments: data_label: D8
data_type: f64

tool: D16: 0.5

tool: D8: 1.61803398875

assistant: ```c
void toBaseFib(char *value, char *result) {
  unsigned long long n = strtoull(value, NULL, 10);
  double temp = n * sqrt(5) + 0.5;
  int size = (int)(log(temp) / log(1.61803398875));
  unsigned long long *fibonacci = malloc(sizeof(unsigned long long) * size);
  getFibonacci(fibonacci, size);
  for (int i = 0; i < size; i++) {
    unsigned long long F = fibonacci[size - i - 1];
    if (n >= F) {
      n -= F;
      result[i] = '1';
    } else {
      result[i] = '0';
    }
  }
  result[size] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toBaseFib>:
  endbr64
  push   %r14
  mov    $0xa,%edx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  call   <strtoull@plt>
  mov    $0x5,%edi
  mov    %rax,%rbx
  call   <sqrt@plt>
  imul   %rbx,%rax
  test   %rax,%rax
  js     L3
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L45:
  addsd  D4(%rip),%xmm0
  call   <log@plt>
  movsd  D18(%rip),%xmm0
  mov    %eax,%r12d
  call   <log@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  movslq %eax,%r14
  lea    0x0(,%r14,8),%edi
  call   <malloc@plt>
  mov    %r14d,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <getFibonacci@plt>
  test   %r14d,%r14d
  jle    L32
  lea    -0x1(%r14),%eax
  lea    -0x8(%r13,%r14,8),%rcx
  mov    %rbp,%rdx
  lea    0x1(%rbp,%rax,1),%rdi
  nopl   0x0(%rax)
L27:
  mov    (%rcx),%rsi
  mov    $0x30,%eax
  cmp    %rbx,%rsi
  ja     L47
  sub    %rsi,%rbx
  mov    $0x31,%eax
L47:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  sub    $0x8,%rcx
  cmp    %rdi,%rdx
  jne    L27
L32:
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r14,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L45
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: f64
name: retrieve_data
arguments: tag: D18
type_guessed: f64

tool: D4: 0.5

tool: D18: 1.61803398875

assistant: ```c
void toBaseFib(char *value, char *result) {
  unsigned long long n = strtoull(value, NULL, 10);
  double temp = n * sqrt(5) + 0.5;
  int size = (int)(log(temp) / log(1.61803398875));
  unsigned long long *fibonacci = malloc(sizeof(unsigned long long) * size);
  getFibonacci(fibonacci, size);
  for (int i = 0; i < size; i++) {
    unsigned long long F = fibonacci[size - i - 1];
    if (n >= F) {
      n -= F;
      result[i] = '1';
    } else {
      result[i] = '0';
    }
  }
  result[size] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <sleep@plt>
  movl   $0x2,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %lx %d


assistant: ```c
int main() {
  sleep(1);
  int a = 2;
  printf("%lx %d\n", &a, a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <sleep@plt>
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x2,%edx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string

tool: D2: %lx %d


assistant: ```c
int main() {
  sleep(1);
  int a = 2;
  printf("%lx %d\n", &a, a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sleep@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x2,%edx
  lea    D0(%rip),%rdi
  movl   $0x2,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: %lx %d


assistant: ```c
int main() {
  sleep(1);
  int a = 2;
  printf("%lx %d\n", &a, a);
}
```