ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movzbl 0x40(%rsp),%edx
  test   %dl,%dl
  je     L6
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r8
  lea    0x3f(%rsp),%rsi
  nop
L23:
  mov    %dl,(%r8,%rax,1)
  mov    %eax,%edi
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L23
  movslq %edi,%rsi
  lea    (%rsp,%rsi,1),%rdx
  lea    0x0(%rbp,%rsi,1),%rax
  lea    0x41(%rsp,%rsi,1),%rsi
  add    %rcx,%rsi
  nopl   0x0(%rax)
L16:
  movzbl -0x1(%rdx),%ecx
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L16
  lea    0x1(%rdi,%rdi,1),%eax
L38:
  cltq
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  movb   $0x0,0x40(%rsp,%rax,1)
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  movzbl -0x1(%rsp),%eax
  mov    %al,0x40(%rsp)
  mov    $0x1,%eax
  jmp    L38
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string

tool: D8: %s

tool: D3: %s


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, i = 0;
  char temp[51], in[101];
  scanf("%s", in);
  while (in[i] != '\0') {
    temp[i] = in[i];
    i++;
  }
  n = i;
  while (i >= 0) {
    in[n] = temp[--i];
    n++;
  }
  in[n] = '\0';
  printf("%s\n", in);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f26>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xffffffcf,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x1b,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
signed int f26(signed int v_foo) {
  signed int v_and = v_foo & -49;
  signed int v_parta = v_and << 5;
  signed int v_partb = ((unsigned int)v_and) >> 27;
  signed int v_rotl = v_parta | v_partb;
  return v_rotl;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f26>:
  endbr64
  mov    %edi,%eax
  and    $0xffffffcf,%eax
  rol    $0x5,%eax
  ret
```

assistant: ```c
signed int f26(signed int v_foo) {
  signed int v_and = v_foo & -49;
  signed int v_parta = v_and << 5;
  signed int v_partb = ((unsigned int)v_and) >> 27;
  signed int v_rotl = v_parta | v_partb;
  return v_rotl;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f26>:
  endbr64
  mov    %edi,%eax
  and    $0xffffffcf,%eax
  rol    $0x5,%eax
  ret
```

assistant: ```c
signed int f26(signed int v_foo) {
  signed int v_and = v_foo & -49;
  signed int v_parta = v_and << 5;
  signed int v_partb = ((unsigned int)v_and) >> 27;
  signed int v_rotl = v_parta | v_partb;
  return v_rotl;
}
```
user: What is the c source code of the assembly code below?

```asm
<f26>:
  endbr64
  mov    %edi,%eax
  and    $0xffffffcf,%eax
  rol    $0x5,%eax
  ret
```

assistant: ```c
signed int f26(signed int v_foo) {
  signed int v_and = v_foo & -49;
  signed int v_parta = v_and << 5;
  signed int v_partb = ((unsigned int)v_and) >> 27;
  signed int v_rotl = v_parta | v_partb;
  return v_rotl;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Increment(int *i) {
  if (*i > 0) {
    (*i)++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  jle    L5
  add    $0x1,%eax
  mov    %eax,(%rdi)
L5:
  ret
```

assistant: ```c
void Increment(int *i) {
  if (*i > 0) {
    (*i)++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  jle    L4
  add    $0x1,%eax
  mov    %eax,(%rdi)
L4:
  ret
```

assistant: ```c
void Increment(int *i) {
  if (*i > 0) {
    (*i)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  jle    L4
  add    $0x1,%eax
  mov    %eax,(%rdi)
L4:
  ret
```

assistant: ```c
void Increment(int *i) {
  if (*i > 0) {
    (*i)++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<tun_to_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %edi,-0x7f4(%rbp)
  mov    %esi,-0x7f8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7e0(%rbp),%rcx
  mov    -0x7f4(%rbp),%eax
  mov    $0x7d0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0xffffffff,-0x7e4(%rbp)
  jne    L12
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L12:
  mov    -0x7e4(%rbp),%edx
  lea    -0x7e0(%rbp),%rcx
  mov    -0x7f8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write_to_serial@plt>
  mov    -0x7e4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: tun_to_serial: read

assistant: ```c
int tun_to_serial(int infd, int outfd) {
  struct {
    unsigned char inbuf[2000];
  } uip;
  int size = read(infd, uip.inbuf, 2000);
  if (size == -1) {
    err(1, "tun_to_serial: read");
  }
  write_to_serial(outfd, uip.inbuf, size);
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tun_to_serial>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x7d0,%edx
  call   <read@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L17
L24:
  mov    %rsp,%rsi
  mov    %ebx,%edx
  mov    %ebp,%edi
  call   <write_to_serial@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %ebx,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L24
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: tun_to_serial: read

assistant: ```c
int tun_to_serial(int infd, int outfd) {
  struct {
    unsigned char inbuf[2000];
  } uip;
  int size = read(infd, uip.inbuf, 2000);
  if (size == -1) {
    err(1, "tun_to_serial: read");
  }
  write_to_serial(outfd, uip.inbuf, size);
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tun_to_serial>:
  endbr64
  push   %r13
  mov    $0x7d0,%edx
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L18
L3:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write_to_serial@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x7e0,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L3
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: tun_to_serial: read

assistant: ```c
int tun_to_serial(int infd, int outfd) {
  struct {
    unsigned char inbuf[2000];
  } uip;
  int size = read(infd, uip.inbuf, 2000);
  if (size == -1) {
    err(1, "tun_to_serial: read");
  }
  write_to_serial(outfd, uip.inbuf, size);
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tun_to_serial>:
  endbr64
  push   %r13
  mov    $0x7d0,%edx
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L10
L18:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write_to_serial@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x7e0,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L10:
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: tun_to_serial: read

assistant: ```c
int tun_to_serial(int infd, int outfd) {
  struct {
    unsigned char inbuf[2000];
  } uip;
  int size = read(infd, uip.inbuf, 2000);
  if (size == -1) {
    err(1, "tun_to_serial: read");
  }
  write_to_serial(outfd, uip.inbuf, size);
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rewind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rewind(FILE *stream) {
  FILE tmp;
  tmp = *stream;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rewind>:
  endbr64
  ret
```

assistant: ```c
void rewind(FILE *stream) {
  FILE tmp;
  tmp = *stream;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rewind>:
  endbr64
  ret
```

assistant: ```c
void rewind(FILE *stream) {
  FILE tmp;
  tmp = *stream;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rewind>:
  endbr64
  ret
```

assistant: ```c
void rewind(FILE *stream) {
  FILE tmp;
  tmp = *stream;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L7:
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x59,-0x8(%rbp)
  jle    L7
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a, b;
  a = a * 8 + b;
  while (a < 90) {
    a = a + 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
L3:
  add    $0x1,%eax
  cmp    $0x5a,%eax
  jne    L3
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a, b;
  a = a * 8 + b;
  while (a < 90) {
    a = a + 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b;
  a = a * 8 + b;
  while (a < 90) {
    a = a + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b;
  a = a * 8 + b;
  while (a < 90) {
    a = a + 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bytes_needed_for_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L79
L45:
  cmpl   $0xff,-0x4(%rbp)
  jg     L23
  mov    $0x1,%eax
  jmp    L79
L23:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L38
  mov    $0x2,%eax
  jmp    L79
L38:
  cmpl   $0xffffff,-0x4(%rbp)
  jg     L48
  mov    $0x3,%eax
  jmp    L79
L48:
  mov    $0x4,%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int bytes_needed_for_size(uint32_t size) {
  if (size == 1)
    return 0;
  else if (size <= 0xFF)
    return 1;
  else if (size <= 0xFFFF)
    return 2;
  else if (size <= 0xFFFFFF)
    return 3;
  else
    return 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bytes_needed_for_size>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L20
  mov    $0x1,%eax
  cmp    $0xff,%edi
  jle    L20
  mov    $0x2,%eax
  cmp    $0xffff,%edi
  jle    L20
  cmp    $0xffffff,%edi
  setg   %al
  movzbl %al,%eax
  add    $0x3,%eax
L20:
  ret
```

assistant: ```c
unsigned int bytes_needed_for_size(uint32_t size) {
  if (size == 1)
    return 0;
  else if (size <= 0xFF)
    return 1;
  else if (size <= 0xFFFF)
    return 2;
  else if (size <= 0xFFFFFF)
    return 3;
  else
    return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bytes_needed_for_size>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L17
  mov    $0x1,%eax
  cmp    $0xff,%edi
  jle    L17
  mov    $0x2,%eax
  cmp    $0xffff,%edi
  jle    L17
  xor    %eax,%eax
  cmp    $0xffffff,%edi
  setg   %al
  add    $0x3,%eax
L17:
  ret
```

assistant: ```c
unsigned int bytes_needed_for_size(uint32_t size) {
  if (size == 1)
    return 0;
  else if (size <= 0xFF)
    return 1;
  else if (size <= 0xFFFF)
    return 2;
  else if (size <= 0xFFFFFF)
    return 3;
  else
    return 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<bytes_needed_for_size>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L9
  mov    $0x1,%eax
  cmp    $0xff,%edi
  jle    L9
  mov    $0x2,%eax
  cmp    $0xffff,%edi
  jle    L9
  xor    %eax,%eax
  cmp    $0xffffff,%edi
  setg   %al
  add    $0x3,%eax
L9:
  ret
```

assistant: ```c
unsigned int bytes_needed_for_size(uint32_t size) {
  if (size == 1)
    return 0;
  else if (size <= 0xFF)
    return 1;
  else if (size <= 0xFFFF)
    return 2;
  else if (size <= 0xFFFFFF)
    return 3;
  else
    return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  mov    -0x20(%rbp),%rax
  movb   $0xff,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] > local2 << (((local1 >> (unsigned char)1) & (unsigned char)7) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
          state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 834686897UL) | (unsigned char)255;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movb   $0xff,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] > local2 << (((local1 >> (unsigned char)1) & (unsigned char)7) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
          state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 834686897UL) | (unsigned char)255;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movb   $0xff,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] > local2 << (((local1 >> (unsigned char)1) & (unsigned char)7) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
          state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 834686897UL) | (unsigned char)255;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movb   $0xff,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        if (state[0UL] > local2 << (((local1 >> (unsigned char)1) & (unsigned char)7) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> (unsigned char)4) & (unsigned char)7) | 1UL);
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local2] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
          state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 834686897UL) | (unsigned char)255;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%edi
  call   <f@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x5,-0x10(%rbp)
  je     L20
  mov    $0x1,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L20:
  mov    $0x100,%edi
  call   <f@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L4
  mov    $0x2,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L4:
  mov    $0x10001,%edi
  call   <s@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  je     L9
  mov    $0x3,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
L9:
  mov    $0x1,%edi
  call   <d@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L36
  mov    $0x4,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <exit@plt>
L36:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D49
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D49: Error %d


tool: D2: Success

assistant: ```c
int main() {
  {
    int x1 = f(5);
    if (x1 != 5) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int x2 = f(256);
    if (x2 != 0) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    int x3 = s(65536 + 1);
    if (x3 != 1) {
      printf("Error %d\n", (int)3);
      exit(3);
    };
  }
  {
    int x4 = d(1);
    if (x4 != 1) {
      printf("Error %d\n", (int)4);
      exit(4);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <f@plt>
  cmp    $0x5,%eax
  jne    L30
L52:
  mov    $0x100,%edi
  call   <f@plt>
  test   %eax,%eax
  jne    L29
L22:
  mov    $0x10001,%edi
  call   <s@plt>
  cmp    $0x1,%eax
  jne    L43
L58:
  mov    $0x1,%edi
  call   <d@plt>
  cmp    $0x1,%eax
  jne    L72
L79:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L30:
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L52
L29:
  mov    $0x2,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L22
L43:
  mov    $0x3,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L58
L72:
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <exit@plt>
  jmp    L79
```

tool_calls: name: retrieve_data
arguments: data_label: D35
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D35: Success

tool: D5: Error %d


assistant: ```c
int main() {
  {
    int x1 = f(5);
    if (x1 != 5) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int x2 = f(256);
    if (x2 != 0) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    int x3 = s(65536 + 1);
    if (x3 != 1) {
      printf("Error %d\n", (int)3);
      exit(3);
    };
  }
  {
    int x4 = d(1);
    if (x4 != 1) {
      printf("Error %d\n", (int)4);
      exit(4);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <f@plt>
  cmp    $0x5,%eax
  je     L47
  lea    D5(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L47:
  mov    $0x100,%edi
  call   <f@plt>
  test   %eax,%eax
  jne    L49
L23:
  mov    $0x10001,%edi
  call   <s@plt>
  cmp    $0x1,%eax
  je     L45
  lea    D5(%rip),%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
L45:
  mov    $0x1,%edi
  call   <d@plt>
  cmp    $0x1,%eax
  je     L31
  lea    D5(%rip),%rdi
  mov    $0x4,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <exit@plt>
L31:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L49:
  mov    $0x2,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D34
datatype: string

tool: D5: Error %d


tool: D34: Success

assistant: ```c
int main() {
  {
    int x1 = f(5);
    if (x1 != 5) {
      printf("Error %d\n", (int)1);
      exit(1);
    };
  }
  {
    int x2 = f(256);
    if (x2 != 0) {
      printf("Error %d\n", (int)2);
      exit(2);
    };
  }
  {
    int x3 = s(65536 + 1);
    if (x3 != 1) {
      printf("Error %d\n", (int)3);
      exit(3);
    };
  }
  {
    int x4 = d(1);
    if (x4 != 1) {
      printf("Error %d\n", (int)4);
      exit(4);
    };
  }
  {
    printf("Success\n");
    exit(0);
  };
}
```