ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nc_getch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  mov    D14(%rip),%r12
  jmp    L43
L109:
  mov    D14(%rip),%rcx
  mov    D15(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L43
  test   %ebx,%ebx
  jne    L90
  test   %r13d,%r13d
  jne    L66
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  jmp    L43
L72:
  cmp    $0xd,%eax
  je     L61
  cmp    $0x16,%eax
  jne    L66
  mov    $0x1,%ebx
  test   %rbp,%rbp
  je     L43
  movl   $0x1,0x0(%rbp)
L43:
  movq   $0x0,(%r12)
  mov    $0x0,%eax
  call   <getch@plt>
  test   %eax,%eax
  js     L109
  test   %ebx,%ebx
  jne    L90
  cmp    $0x1a,%eax
  je     L70
  test   %r13d,%r13d
  jne    L72
  jmp    L90
L61:
  mov    $0xa,%eax
L66:
  test   %rbp,%rbp
  je     L90
  movl   $0x0,0x0(%rbp)
  jmp    L90
```

assistant: ```c
int nc_getch(bool mapraw, bool *wasraw) {
  bool ctrl_v = false;
  int ch;
restart:
  errno = 0;
  ch = getch();
  if (ch < 0 && errno == EINTR)
    goto restart;
  if (ctrl_v)
    return ch;
  if (ch == (('z') & 037)) {
    raise(SIGTSTP);
    goto restart;
  }
  if (mapraw) {
    if (ch == '\r') {
      ch = '\n';
    } else if (ch == (('v') & 037)) {
      if (wasraw)
        *wasraw = true;
      ctrl_v = true;
      goto restart;
    }
    if (wasraw)
      *wasraw = false;
  }
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nc_getch>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D21(%rip),%rbp
L9:
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  call   <getch@plt>
  test   %eax,%eax
  js     L14
  test   %r13d,%r13d
  jne    L34
L150:
  cmp    $0x1a,%eax
  je     L200
  test   %r12d,%r12d
  je     L34
  cmp    $0xd,%eax
  je     L148
  cmp    $0x16,%eax
  jne    L33
L127:
  test   %rbx,%rbx
  je     L11
  movl   $0x1,(%rbx)
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  call   <getch@plt>
  test   %eax,%eax
  js     L198
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  call   <getch@plt>
  test   %eax,%eax
  jns    L34
  mov    D51(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,0x0(%rbp)
  jne    L34
L42:
  mov    $0x1,%r13d
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L198:
  mov    D51(%rip),%rdx
  mov    0x0(%rbp),%rcx
  cmp    %rcx,(%rdx)
  je     L42
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L200:
  mov    D54(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  call   <getch@plt>
  test   %eax,%eax
  jns    L150
  mov    D51(%rip),%rdx
  mov    0x0(%rbp),%rcx
  cmp    %rcx,(%rdx)
  jne    L166
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D51(%rip),%rdx
  mov    (%rdx),%rdi
  cmp    %rdi,0x0(%rbp)
  je     L9
  test   %r13d,%r13d
  jne    L34
L166:
  test   %r12d,%r12d
  je     L34
  cmp    $0x16,%eax
  je     L127
  nop
L33:
  test   %rbx,%rbx
  je     L34
  movl   $0x0,(%rbx)
  jmp    L34
  nopl   0x0(%rax)
L148:
  mov    $0xa,%eax
  jmp    L33
```

assistant: ```c
int nc_getch(bool mapraw, bool *wasraw) {
  bool ctrl_v = false;
  int ch;
restart:
  errno = 0;
  ch = getch();
  if (ch < 0 && errno == EINTR)
    goto restart;
  if (ctrl_v)
    return ch;
  if (ch == (('z') & 037)) {
    raise(SIGTSTP);
    goto restart;
  }
  if (mapraw) {
    if (ch == '\r') {
      ch = '\n';
    } else if (ch == (('v') & 037)) {
      if (wasraw)
        *wasraw = true;
      ctrl_v = true;
      goto restart;
    }
    if (wasraw)
      *wasraw = false;
  }
  return ch;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L3:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L19:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x7,-0x4(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x7,-0x8(%rbp)
  jle    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero(unsigned m[8][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      m[i][j] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero>:
  endbr64
  lea    0x100(%rdi),%rax
L1:
  movl   $0x0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x10(%rdi)
  movl   $0x0,0x14(%rdi)
  movl   $0x0,0x18(%rdi)
  movl   $0x0,0x1c(%rdi)
  add    $0x20,%rdi
  cmp    %rdi,%rax
  jne    L1
  ret
```

assistant: ```c
void zero(unsigned m[8][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      m[i][j] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0xf0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x100(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void zero(unsigned m[8][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      m[i][j] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<zero>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm0,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  movups %xmm0,0x70(%rdi)
  movups %xmm0,0x80(%rdi)
  movups %xmm0,0x90(%rdi)
  movups %xmm0,0xa0(%rdi)
  movups %xmm0,0xb0(%rdi)
  movups %xmm0,0xc0(%rdi)
  movups %xmm0,0xd0(%rdi)
  movups %xmm0,0xe0(%rdi)
  movups %xmm0,0xf0(%rdi)
  ret
```

assistant: ```c
void zero(unsigned m[8][8]) {
  int i, j;
  for (i = 0; i < 8; i++)
    for (j = 0; j < 8; j++)
      m[i][j] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rand_double_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L2
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L2:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D0(%rip),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double rand_double_range(double min, double max) {
  if (min > max) {
    double tmp = min;
    min = max;
    max = tmp;
  }
  double r = (double)rand() / RAND_MAX;
  return min + r * (max - min);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rand_double_range>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%r14
  movq   %xmm1,%rbx
  comisd %xmm1,%xmm0
  jbe    L2
  movq   %xmm1,%r14
  movq   %xmm0,%rbx
L2:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D2(%rip),%rax
  divsd  (%rax),%xmm0
  movq   %rbx,%xmm1
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double rand_double_range(double min, double max) {
  if (min > max) {
    double tmp = min;
    min = max;
    max = tmp;
  }
  double r = (double)rand() / RAND_MAX;
  return min + r * (max - min);
}
```
user: What is the c source code of the assembly code below?

```asm
<rand_double_range>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  jbe    L5
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L5:
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <rand@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  mov    D3(%rip),%rax
  subsd  %xmm0,%xmm1
  divsd  (%rax),%xmm2
  add    $0x18,%rsp
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double rand_double_range(double min, double max) {
  if (min > max) {
    double tmp = min;
    min = max;
    max = tmp;
  }
  double r = (double)rand() / RAND_MAX;
  return min + r * (max - min);
}
```
user: What is the c source code of the assembly code below?

```asm
<rand_double_range>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  jbe    L3
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L3:
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <rand@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  mov    D5(%rip),%rax
  subsd  %xmm0,%xmm1
  divsd  (%rax),%xmm2
  add    $0x18,%rsp
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double rand_double_range(double min, double max) {
  if (min > max) {
    double tmp = min;
    min = max;
    max = tmp;
  }
  double r = (double)rand() / RAND_MAX;
  return min + r * (max - min);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sum@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  sum();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sum@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sum();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sum@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sum();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sum@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  sum();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D13: Hello, what is your name?

tool: D25: %s

tool: D14: Hello %s, how are you doing today?


assistant: ```c
int main() {
  printf("Hello, what is your name?");
  char name[50];
  scanf("%s", name);
  printf("Hello %s, how are you doing today?\n", name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D27
datatype: string
name: parse_data
arguments: tag: D24
datatype: string

tool: D15: Hello, what is your name?

tool: D27: %s

tool: D24: Hello %s, how are you doing today?


assistant: ```c
int main() {
  printf("Hello, what is your name?");
  char name[50];
  scanf("%s", name);
  printf("Hello %s, how are you doing today?\n", name);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string

tool: D22: Hello, what is your name?

tool: D14: %s

tool: D17: Hello %s, how are you doing today?


assistant: ```c
int main() {
  printf("Hello, what is your name?");
  char name[50];
  scanf("%s", name);
  printf("Hello %s, how are you doing today?\n", name);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D18
datatype: string

tool: D28: Hello, what is your name?

tool: D19: %s

tool: D18: Hello %s, how are you doing today?


assistant: ```c
int main() {
  printf("Hello, what is your name?");
  char name[50];
  scanf("%s", name);
  printf("Hello %s, how are you doing today?\n", name);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wrhit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <writel@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <wrint@plt>
  mov    $0x2e,%edi
  mov    $0x0,%eax
  call   <writec@plt>
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <writec@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: Blot hit on 

assistant: ```c
void wrhit(i) register int i;
{
  writel("Blot hit on ");
  wrint(i);
  writec('.');
  writec('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wrhit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <writel@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <wrint@plt>
  mov    $0x2e,%edi
  mov    $0x0,%eax
  call   <writec@plt>
  mov    $0xa,%edi
  mov    $0x0,%eax
  call   <writec@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: Blot hit on 

assistant: ```c
void wrhit(i) register int i;
{
  writel("Blot hit on ");
  wrint(i);
  writec('.');
  writec('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wrhit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  call   <writel@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <wrint@plt>
  mov    $0x2e,%edi
  xor    %eax,%eax
  call   <writec@plt>
  mov    $0xa,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <writec@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: Blot hit on 

assistant: ```c
void wrhit(i) register int i;
{
  writel("Blot hit on ");
  wrint(i);
  writec('.');
  writec('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wrhit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  call   <writel@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <wrint@plt>
  mov    $0x2e,%edi
  xor    %eax,%eax
  call   <writec@plt>
  mov    $0xa,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <writec@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: Blot hit on 

assistant: ```c
void wrhit(i) register int i;
{
  writel("Blot hit on ");
  wrint(i);
  writec('.');
  writec('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<q_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  or     -0x20(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  je     L14
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  xor    -0x1c(%rbp),%eax
  and    $0xfffffff8,%eax
  test   %eax,%eax
  je     L14
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
L14:
  cmpl   $0x8,-0x20(%rbp)
  jg     L1
  mov    -0x1c(%rbp),%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    -0x20(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    $0x1,%eax
  and    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L56
L1:
  mov    -0x1c(%rbp),%eax
  sar    $0x3,%eax
  cltq
  add    %rax,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L37
L43:
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rcx,%rax
  mov    %rax,-0x8(%rbp)
  subl   $0x8,-0x20(%rbp)
L37:
  cmpl   $0x0,-0x20(%rbp)
  jg     L43
L56:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string

tool: D12: get %d %d ...

tool: D6: unsupported alignment (get %d,%d)

tool: D2:   %ld

assistant: ```c
unsigned long q_get(unsigned char *table, int pos, int size) {
  unsigned long value;
  int end;
  q_report(3, "get %d %d ...", pos, size);
  end = pos + size;
  if (((pos | size) & 7) && ((pos ^ (end - 1)) & ~7))
    q_report(-1, "unsupported alignment (get %d,%d)", pos, size);
  if (size <= 8)
    value = (table[pos >> 3] >> (pos & 7)) & ((1 << size) - 1);
  else {
    table += pos >> 3;
    value = 0;
    while (size > 0) {
      value = (value << 8) | *table++;
      size -= 8;
    }
  }
  q_report(3, "  %ld", value);
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<q_get>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  movslq %esi,%r13
  mov    %edx,%ecx
  mov    %r13,%rdx
  lea    D6(%rip),%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
  mov    %r12d,%eax
  or     %ebp,%eax
  test   $0x7,%al
  je     L46
  lea    -0x1(%r12,%rbp,1),%eax
  xor    %r12d,%eax
  test   $0xfffffff8,%eax
  jne    L12
L46:
  cmp    $0x8,%ebp
  jg     L15
  mov    %r12d,%eax
  sar    $0x3,%eax
  cltq
  movzbl (%rbx,%rax,1),%ebx
  mov    %r12d,%ecx
  and    $0x7,%ecx
  sar    %cl,%ebx
  mov    $0x1,%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  and    %eax,%ebx
  movslq %ebx,%rbx
L44:
  mov    %rbx,%rdx
  lea    D20(%rip),%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %ebp,%ecx
  mov    %r13,%rdx
  lea    D17(%rip),%rsi
  mov    $0xffffffff,%edi
  mov    $0x0,%eax
  call   <q_report@plt>
  jmp    L46
L15:
  sar    $0x3,%r12d
  movslq %r12d,%r12
  lea    (%rbx,%r12,1),%rax
  lea    -0x1(%rbp),%edx
  shr    $0x3,%edx
  add    $0x1,%edx
  mov    %edx,%edx
  add    %rax,%rdx
  mov    $0x0,%ebx
L7:
  shl    $0x8,%rbx
  add    $0x1,%rax
  movzbl -0x1(%rax),%ecx
  or     %rcx,%rbx
  cmp    %rdx,%rax
  jne    L7
  jmp    L44
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D20
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string

tool: D6: get %d %d ...

tool: D20:   %ld

tool: D17: unsupported alignment (get %d,%d)

assistant: ```c
unsigned long q_get(unsigned char *table, int pos, int size) {
  unsigned long value;
  int end;
  q_report(3, "get %d %d ...", pos, size);
  end = pos + size;
  if (((pos | size) & 7) && ((pos ^ (end - 1)) & ~7))
    q_report(-1, "unsupported alignment (get %d,%d)", pos, size);
  if (size <= 8)
    value = (table[pos >> 3] >> (pos & 7)) & ((1 << size) - 1);
  else {
    table += pos >> 3;
    value = 0;
    while (size > 0) {
      value = (value << 8) | *table++;
      size -= 8;
    }
  }
  q_report(3, "  %ld", value);
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<q_get>:
  endbr64
  push   %r14
  movslq %esi,%r14
  mov    %edx,%ecx
  lea    D8(%rip),%rsi
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  mov    %r14,%rdx
  push   %r12
  mov    %rdi,%r12
  mov    $0x3,%edi
  push   %rbx
  mov    %r14,%rbx
  sub    $0x8,%rsp
  call   <q_report@plt>
  mov    %r14d,%eax
  or     %r13d,%eax
  test   $0x7,%al
  je     L3
  lea    -0x1(%r14,%r13,1),%eax
  xor    %r14d,%eax
  and    $0xfffffff8,%eax
  jne    L43
L3:
  mov    %ebx,%eax
  sar    $0x3,%eax
  cltq
  lea    (%r12,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0x8,%r13d
  jg     L55
  and    $0x7,%ebx
  mov    $0x1,%edx
  mov    %ebx,%ecx
  sar    %cl,%eax
  mov    %r13d,%ecx
  shl    %cl,%edx
  sub    $0x1,%edx
  and    %edx,%eax
  movslq %eax,%r12
L35:
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    $0x3,%edi
  xor    %eax,%eax
  call   <q_report@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L55:
  lea    -0x1(%r13),%eax
  xor    %r12d,%r12d
  shr    $0x3,%eax
  add    $0x1,%eax
  add    %rdx,%rax
L32:
  movzbl (%rdx),%ecx
  shl    $0x8,%r12
  add    $0x1,%rdx
  or     %rcx,%r12
  cmp    %rdx,%rax
  jne    L32
  jmp    L35
  nopl   (%rax)
L43:
  mov    %r13d,%ecx
  mov    %r14,%rdx
  lea    D25(%rip),%rsi
  xor    %eax,%eax
  mov    $0xffffffff,%edi
  call   <q_report@plt>
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string

tool: D8: get %d %d ...

tool: D6:   %ld

tool: D25: unsupported alignment (get %d,%d)

assistant: ```c
unsigned long q_get(unsigned char *table, int pos, int size) {
  unsigned long value;
  int end;
  q_report(3, "get %d %d ...", pos, size);
  end = pos + size;
  if (((pos | size) & 7) && ((pos ^ (end - 1)) & ~7))
    q_report(-1, "unsupported alignment (get %d,%d)", pos, size);
  if (size <= 8)
    value = (table[pos >> 3] >> (pos & 7)) & ((1 << size) - 1);
  else {
    table += pos >> 3;
    value = 0;
    while (size > 0) {
      value = (value << 8) | *table++;
      size -= 8;
    }
  }
  q_report(3, "  %ld", value);
  return value;
}
```