ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<refract>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  movq   %xmm2,%r14
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  movsd  %xmm1,(%rsp)
  mov    %rbx,%rdi
  call   <unrefract@plt>
  movsd  0x20(%rsp),%xmm7
  movq   %r14,%xmm4
  movsd  (%rsp),%xmm1
  movq   %r14,%xmm2
  subsd  %xmm7,%xmm4
  movsd  %xmm7,0x8(%rsp)
  mulsd  D15(%rip),%xmm4
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L27:
  movsd  0x8(%rsp),%xmm5
  xorpd  D20(%rip),%xmm0
  movsd  %xmm3,0x8(%rsp)
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm1
  subsd  %xmm3,%xmm5
  divsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm4
L18:
  addsd  %xmm4,%xmm2
  movq   %r15,%xmm0
  mov    %rbx,%rdi
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,(%rsp)
  call   <unrefract@plt>
  movsd  0x20(%rsp),%xmm3
  movq   %r14,%xmm0
  movsd  D9(%rip),%xmm6
  movsd  (%rsp),%xmm2
  subsd  %xmm3,%xmm0
  movapd %xmm0,%xmm5
  andpd  D38(%rip),%xmm5
  comisd %xmm5,%xmm6
  jb     L27
  movsd  %xmm2,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type: f64
name: parse_data
arguments: tag: D20
type: byte[16]
name: parse_data
arguments: tag: D9
type: byte[8]
name: parse_data
arguments: tag: D38
type: qword[2]

tool: D15: 0.8

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D9": [0x4b,0xd9,0x32,0x8f,0x84,0x44,0xa0,0x3e]}

tool: {"D38": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
void refract(double pr, double tr, double ta, double *aa) {
  double d, t, t0, a;
  unrefract(pr, tr, ta, &t);
  d = 0.8 * (ta - t);
  t0 = t;
  a = ta;
  while (1) {
    a += d;
    unrefract(pr, tr, a, &t);
    if (fabs(ta - t) <= ((0.1 / 3600.) * 3.141592653589793 / 180.))
      break;
    d *= -(ta - t) / (t0 - t);
    t0 = t;
  }
  *aa = a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<refract>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  movq   %xmm2,%r14
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  movsd  %xmm1,(%rsp)
  mov    %rbx,%rdi
  call   <unrefract@plt>
  movsd  0x20(%rsp),%xmm7
  movq   %r14,%xmm4
  movsd  (%rsp),%xmm1
  movq   %r14,%xmm2
  subsd  %xmm7,%xmm4
  movsd  %xmm7,0x8(%rsp)
  mulsd  D39(%rip),%xmm4
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L16:
  movsd  0x8(%rsp),%xmm5
  xorpd  D30(%rip),%xmm0
  movsd  %xmm3,0x8(%rsp)
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm1
  subsd  %xmm3,%xmm5
  divsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm4
L15:
  addsd  %xmm4,%xmm2
  movq   %r15,%xmm0
  mov    %rbx,%rdi
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,(%rsp)
  call   <unrefract@plt>
  movsd  0x20(%rsp),%xmm3
  movq   %r14,%xmm0
  movsd  D38(%rip),%xmm6
  movsd  (%rsp),%xmm2
  subsd  %xmm3,%xmm0
  movapd %xmm0,%xmm5
  andpd  D21(%rip),%xmm5
  comisd %xmm5,%xmm6
  jb     L16
  movsd  %xmm2,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_infered: f64
name: unpack_data
arguments: data_label: D30
type_infered: byte[16]
name: unpack_data
arguments: data_label: D38
type_infered: byte[8]
name: unpack_data
arguments: data_label: D21
type_infered: qword[2]

tool: D39: 0.8

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D38": [0x4b,0xd9,0x32,0x8f,0x84,0x44,0xa0,0x3e]}

tool: {"D21": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
void refract(double pr, double tr, double ta, double *aa) {
  double d, t, t0, a;
  unrefract(pr, tr, ta, &t);
  d = 0.8 * (ta - t);
  t0 = t;
  a = ta;
  while (1) {
    a += d;
    unrefract(pr, tr, a, &t);
    if (fabs(ta - t) <= ((0.1 / 3600.) * 3.141592653589793 / 180.))
      break;
    d *= -(ta - t) / (t0 - t);
    t0 = t;
  }
  *aa = a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  lea    -0x30(%rbp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L27:
  cmp    %rcx,%rsp
  je     L106
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L106:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L97
  orq    $0x0,-0x8(%rsp,%rax,1)
L97:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L8
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D38(%rip),%r14
L20:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    %ebx,-0x30(%rbp)
  jg     L20
L8:
  movl   $0x0,-0x2c(%rbp)
  lea    -0x2c(%rbp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%edi
  call   <sumc@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jle    L7
  mov    $0x1,%ebx
  lea    D38(%rip),%r14
L75:
  mov    -0x2c(%rbp),%edx
  lea    -0x1(%rbx),%eax
  cmp    %eax,%edx
  jle    L59
  lea    (%r12,%rbx,4),%rax
  sub    %ebx,%edx
  add    %rbx,%rdx
  lea    0x4(%r12,%rdx,4),%rdx
  mov    $0x0,%esi
L91:
  add    -0x4(%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L91
L32:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x2c(%rbp)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L75
L7:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L59:
  mov    $0x0,%esi
  jmp    L32
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string

tool: D16: %d 


tool: D38: %d

tool: D12: 
 %d

assistant: ```c
int main() {
  int N = 0;
  scanf("%d \n", &N);
  int a[N], i = 0;
  for (i = 0; i <= (N - 1); i++) {
    scanf("%d", &a[i]);
  }
  int k = 0;
  scanf("\n %d", &k);
  int x, y, c;
  c = sumc(k, N);
  for (y = 1; y <= c; y++) {
    int sum = 0;
    for (x = (y - 1); x <= (k - 1); x++) {
      sum = (sum + a[x]);
    }
    printf("%d", sum);
    printf("\n");
    sum = 0;
    k = k + 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L106
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L63
L106:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L9
L6:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L119
  mov    %r12,%r14
  xor    %r13d,%r13d
  lea    D2(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L101:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %r13d,-0x30(%rbp)
  jg     L101
L119:
  lea    -0x2c(%rbp),%rsi
  lea    D23(%rip),%rdi
  movl   $0x0,-0x2c(%rbp)
  call   <scanf@plt>
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%edi
  call   <sumc@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jle    L13
  mov    -0x2c(%rbp),%edx
  mov    $0x1,%r14d
  lea    D2(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L18:
  lea    -0x1(%r14),%eax
  cmp    %eax,%edx
  jle    L21
  sub    %r14d,%edx
  lea    (%r12,%r14,4),%rax
  xor    %esi,%esi
  add    %r14,%rdx
  lea    0x4(%r12,%rdx,4),%rdx
  nopl   0x0(%rax)
L8:
  add    -0x4(%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L8
L14:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  cmp    %r14d,%r13d
  jge    L18
L13:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %esi,%esi
  jmp    L14
L9:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D23
datatype: string

tool: D26: %d 


tool: D2: %d

tool: D23: 
 %d

assistant: ```c
int main() {
  int N = 0;
  scanf("%d \n", &N);
  int a[N], i = 0;
  for (i = 0; i <= (N - 1); i++) {
    scanf("%d", &a[i]);
  }
  int k = 0;
  scanf("\n %d", &k);
  int x, y, c;
  c = sumc(k, N);
  for (y = 1; y <= c; y++) {
    int sum = 0;
    for (x = (y - 1); x <= (k - 1); x++) {
      sum = (sum + a[x]);
    }
    printf("%d", sum);
    printf("\n");
    sum = 0;
    k = k + 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isValidMain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7b29285b7b29287b,%rax
  movabs $0x7d5d29285b7d5d7d,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d


assistant: ```c
void isValidMain(void) {
  char s[] = "{(){[(){}]}[()]}";
  printf("%d\n", isValid(s));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isValidMain>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x7b29285b7b29287b,%rax
  movabs $0x7d5d29285b7d5d7d,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
void isValidMain(void) {
  char s[] = "{(){[(){}]}[()]}";
  printf("%d\n", isValid(s));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isValidMain>:
  endbr64
  sub    $0x28,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <isValid@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type: byte[16]
name: retrieve_data
arguments: label: D2
type: string

tool: {"D10": [0x7b,0x28,0x29,0x7b,0x5b,0x28,0x29,0x7b,0x7d,0x5d,0x7d,0x5b,0x28,0x29,0x5d,0x7d]}

tool: D2: %d


assistant: ```c
void isValidMain(void) {
  char s[] = "{(){[(){}]}[()]}";
  printf("%d\n", isValid(s));
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValidMain>:
  endbr64
  sub    $0x28,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <isValid@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type: byte[16]
name: disassemble_data
arguments: tag: D11
type: string

tool: {"D10": [0x7b,0x28,0x29,0x7b,0x5b,0x28,0x29,0x7b,0x7d,0x5d,0x7d,0x5b,0x28,0x29,0x5d,0x7d]}

tool: D11: %d


assistant: ```c
void isValidMain(void) {
  char s[] = "{(){[(){}]}[()]}";
  printf("%d\n", isValid(s));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L17
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L23
L10:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D19: 
Queue is empty

tool: D4: %d   

assistant: ```c
void display(int *arr, int start, int end) {
  if (start == end)
    printf("\nQueue is empty");
  else
    while (start != end) {
      printf("%d   ", *(arr + start));
      start++;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<display>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %edx,%esi
  je     L14
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbx
  sub    $0x1,%edx
  sub    %esi,%edx
  add    %rax,%rdx
  lea    0x4(%rdi,%rdx,4),%r12
  lea    D5(%rip),%rbp
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D12
datatype: string

tool: D5: %d   

tool: D12: 
Queue is empty

assistant: ```c
void display(int *arr, int start, int end) {
  if (start == end)
    printf("\nQueue is empty");
  else
    while (start != end) {
      printf("%d   ", *(arr + start));
      start++;
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<display>:
  endbr64
  cmp    %edx,%esi
  je     L9
  sub    $0x1,%edx
  movslq %esi,%rax
  push   %r12
  sub    %esi,%edx
  push   %rbp
  lea    D17(%rip),%rbp
  add    %rax,%rdx
  push   %rbx
  lea    (%rdi,%rax,4),%rbx
  lea    0x4(%rdi,%rdx,4),%r12
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D17: %d   

tool: D19: 
Queue is empty

assistant: ```c
void display(int *arr, int start, int end) {
  if (start == end)
    printf("\nQueue is empty");
  else
    while (start != end) {
      printf("%d   ", *(arr + start));
      start++;
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<display>:
  endbr64
  cmp    %edx,%esi
  je     L13
  sub    $0x1,%edx
  movslq %esi,%rax
  push   %r12
  sub    %esi,%edx
  push   %rbp
  lea    D12(%rip),%rbp
  add    %rax,%rdx
  push   %rbx
  lea    (%rdi,%rax,4),%rbx
  lea    0x4(%rdi,%rdx,4),%r12
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D12: %d   

tool: D2: 
Queue is empty

assistant: ```c
void display(int *arr, int start, int end) {
  if (start == end)
    printf("\nQueue is empty");
  else
    while (start != end) {
      printf("%d   ", *(arr + start));
      start++;
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<q15_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7fff,%eax
  cmp    $0x4000,%eax
  jne    L11
  mov    $0x0,%edx
  jmp    L12
L11:
  mov    $0x4000,%edx
L12:
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sar    $0xf,%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t q15_mul(const int32_t j, const int32_t k) {
  const int32_t intermediate = j * k;
  return (intermediate + ((intermediate & 0x7FFF) == 0x4000 ? 0 : 0x4000)) >> 15;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<q15_mul>:
  endbr64
  imul   %esi,%edi
  mov    %edi,%eax
  and    $0x7fff,%eax
  cmp    $0x4000,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0xe,%eax
  add    %edi,%eax
  sar    $0xf,%eax
  ret
```

assistant: ```c
int32_t q15_mul(const int32_t j, const int32_t k) {
  const int32_t intermediate = j * k;
  return (intermediate + ((intermediate & 0x7FFF) == 0x4000 ? 0 : 0x4000)) >> 15;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<q15_mul>:
  endbr64
  imul   %esi,%edi
  mov    %edi,%eax
  and    $0x7fff,%eax
  cmp    $0x4000,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0xe,%eax
  add    %edi,%eax
  sar    $0xf,%eax
  ret
```

assistant: ```c
int32_t q15_mul(const int32_t j, const int32_t k) {
  const int32_t intermediate = j * k;
  return (intermediate + ((intermediate & 0x7FFF) == 0x4000 ? 0 : 0x4000)) >> 15;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<q15_mul>:
  endbr64
  imul   %esi,%edi
  mov    %edi,%eax
  and    $0x7fff,%eax
  cmp    $0x4000,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0xe,%eax
  add    %edi,%eax
  sar    $0xf,%eax
  ret
```

assistant: ```c
int32_t q15_mul(const int32_t j, const int32_t k) {
  const int32_t intermediate = j * k;
  return (intermediate + ((intermediate & 0x7FFF) == 0x4000 ? 0 : 0x4000)) >> 15;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MMtoDBFineMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  D10(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D7(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x8(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D8(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: f32
name: disassemble_data
arguments: data_label: D7
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D8
type_guessed: f64

tool: D10: 30

tool: {"D7": [0x00,0x00,0xb4,0xc2]}

tool: D8: 100

assistant: ```c
float MMtoDBFineMode(float mm) {
  float maxVal = 30;
  float minVal = -90;
  float db;
  db = minVal + (maxVal - minVal) * mm / 100.;
  return db;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MMtoDBFineMode>:
  endbr64
  mulss  D9(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D28(%rip),%xmm0
  subsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: byte[4]
name: read_data
arguments: data_label: D28
type_infered: f64
name: read_data
arguments: data_label: D12
type_infered: f64

tool: {"D9": [0x00,0x00,0xf0,0x42]}

tool: D28: 100

tool: D12: 90

assistant: ```c
float MMtoDBFineMode(float mm) {
  float maxVal = 30;
  float minVal = -90;
  float db;
  db = minVal + (maxVal - minVal) * mm / 100.;
  return db;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MMtoDBFineMode>:
  endbr64
  mulss  D12(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D20(%rip),%xmm0
  subsd  D5(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D12
type_guessed: byte[4]
name: parse_data
arguments: label: D20
type_guessed: f64
name: parse_data
arguments: label: D5
type_guessed: f64

tool: {"D12": [0x00,0x00,0xf0,0x42]}

tool: D20: 100

tool: D5: 90

assistant: ```c
float MMtoDBFineMode(float mm) {
  float maxVal = 30;
  float minVal = -90;
  float db;
  db = minVal + (maxVal - minVal) * mm / 100.;
  return db;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<MMtoDBFineMode>:
  endbr64
  mulss  D21(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D2(%rip),%xmm0
  subsd  D25(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_infered: byte[4]
name: retrieve_data
arguments: tag: D2
type_infered: f64
name: retrieve_data
arguments: tag: D25
type_infered: f64

tool: {"D21": [0x00,0x00,0xf0,0x42]}

tool: D2: 100

tool: D25: 90

assistant: ```c
float MMtoDBFineMode(float mm) {
  float maxVal = 30;
  float minVal = -90;
  float db;
  db = minVal + (maxVal - minVal) * mm / 100.;
  return db;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L28
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L24
L28:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L24
L4:
  movl   $0x0,-0x18(%rbp)
  jmp    L15
L54:
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jb     L54
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: No equals found. Input was %s


assistant: ```c
char *getKey(char *pair) {
  char *equalsAddress = strchr(pair, '=');
  if (equalsAddress == NULL) {
    printf("No equals found. Input was %s\n", pair);
    return NULL;
  }
  unsigned int numCharichters = (equalsAddress - pair) + 1;
  char *newString = (char *)malloc(numCharichters);
  if (newString == NULL)
    return NULL;
  for (unsigned int i = 0; i < numCharichters - 1; i++) {
    newString[i] = pair[i];
  }
  newString[numCharichters - 1] = '\0';
  return newString;
}
```