ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<term_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dump_summary_ebb_state@plt>
  xor    %eax,%eax
  call   <dump_ebb_hw_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <abort@plt>
```

assistant: ```c
void term_handler(int signal) {
  dump_summary_ebb_state();
  dump_ebb_hw_state();
  abort();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IndexOfAnd2_internal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    0x10(%rbp),%edx
  mov    0x18(%rbp),%eax
  mov    %dl,-0x44(%rbp)
  mov    %al,-0x48(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L1:
  movsbl -0x48(%rbp),%edx
  movsbl -0x44(%rbp),%esi
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%ecx
  mov    %eax,%edi
  call   <UpdateWithin@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L2
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L2
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L86
L4:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L14
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L70
L14:
  addl   $0x1,-0x4(%rbp)
L86:
  mov    -0x4(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L4
L70:
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L33
  addl   $0x1,-0x10(%rbp)
  cmpl   $0xffffffff,-0x40(%rbp)
  je     L17
  mov    -0x10(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  je     L17
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L33
L2:
  nop
L33:
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x38(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L1
L17:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int IndexOfAnd2_internal(char *input, char *target, const int start, const int length, const int lengthT, const int count, const char openSymbolWithin, const char closeSymbolWithin) {
  int output = -1;
  int count0 = 1;
  int within = 0;
  int i = 0;
  for (i = start + 1; i < length - lengthT + 1; i++) {
    within = UpdateWithin(input[i], openSymbolWithin, closeSymbolWithin, within);
    if (within == 1 || input[i] != target[0]) {
      continue;
    }
    output = i;
    int i2 = 0;
    for (i2 = 0; i2 < lengthT; i2++) {
      if (input[i + i2] != target[i2]) {
        output = -1;
        break;
      }
    }
    if (output != -1) {
      count0++;
      if (count == -1 || count0 == count) {
        break;
      } else
        output = -1;
    }
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<IndexOfAnd2_internal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0x8(%rsp)
  mov    %r9d,0xc(%rsp)
  movzbl 0x50(%rsp),%r15d
  movzbl 0x58(%rsp),%r14d
  lea    0x1(%rdx),%ebx
  sub    %r8d,%ecx
  cmp    %ecx,%ebx
  jg     L51
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %ecx,%r13d
  movslq %ebx,%rbx
  mov    $0x0,%ecx
  movl   $0x1,0x4(%rsp)
  movsbl %r14b,%r14d
  jmp    L55
L9:
  cmp    $0xffffffff,%ebx
  je     L120
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0xc(%rsp),%edi
  cmp    $0xffffffff,%edi
  je     L57
  cmp    %edi,%eax
  je     L57
L120:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L115
L55:
  mov    %ebx,(%rsp)
  movsbl %r15b,%esi
  movsbl (%r12,%rbx,1),%edi
  mov    %r14d,%edx
  call   <UpdateWithin@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  je     L120
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r12,%rbx,1)
  jne    L120
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L9
  mov    %eax,%esi
  mov    $0x1,%edx
  lea    (%r12,%rbx,1),%rdi
L63:
  cmp    %rsi,%rdx
  je     L9
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    -0x1(%rbp,%rdx,1),%al
  je     L63
  jmp    L120
L115:
  movl   $0xffffffff,(%rsp)
L57:
  mov    (%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  movl   $0xffffffff,(%rsp)
  jmp    L57
```

assistant: ```c
int IndexOfAnd2_internal(char *input, char *target, const int start, const int length, const int lengthT, const int count, const char openSymbolWithin, const char closeSymbolWithin) {
  int output = -1;
  int count0 = 1;
  int within = 0;
  int i = 0;
  for (i = start + 1; i < length - lengthT + 1; i++) {
    within = UpdateWithin(input[i], openSymbolWithin, closeSymbolWithin, within);
    if (within == 1 || input[i] != target[0]) {
      continue;
    }
    output = i;
    int i2 = 0;
    for (i2 = 0; i2 < lengthT; i2++) {
      if (input[i + i2] != target[i2]) {
        output = -1;
        break;
      }
    }
    if (output != -1) {
      count0++;
      if (count == -1 || count0 == count) {
        break;
      } else
        output = -1;
    }
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IndexOfAnd2_internal>:
  endbr64
  push   %r15
  mov    %r8d,%eax
  push   %r14
  sub    %eax,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r12d
  mov    0x68(%rsp),%r13d
  mov    %r8d,0x18(%rsp)
  lea    0x1(%rdx),%r8d
  mov    %r9d,0x1c(%rsp)
  mov    %ecx,0x10(%rsp)
  cmp    %ecx,%r8d
  jg     L94
  movl   $0x1,0x14(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%r14
  xor    %ecx,%ecx
  movslq 0x18(%rsp),%rbx
  movsbl %r13b,%r13d
  movsbl %r12b,%r12d
  movslq %r8d,%r15
  jmp    L21
  xchg   %ax,%ax
L16:
  add    $0x1,%r15
  cmp    %r15d,0x10(%rsp)
  jl     L94
L21:
  movsbl 0x0(%rbp,%r15,1),%edi
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r15d,0xc(%rsp)
  call   <UpdateWithin@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  je     L16
  movzbl (%r14),%eax
  cmp    %al,0x0(%rbp,%r15,1)
  jne    L16
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L125
  mov    $0x1,%edx
  lea    0x0(%rbp,%r15,1),%rsi
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L81:
  movzbl (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    -0x1(%r14,%rdx,1),%al
  jne    L16
L88:
  cmp    %rdx,%rbx
  jne    L81
L125:
  cmp    $0xffffffff,%r15d
  je     L16
  mov    0x1c(%rsp),%esi
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    $0xffffffff,%esi
  je     L57
  cmp    %esi,%eax
  jne    L16
L57:
  mov    0xc(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L57
```

assistant: ```c
int IndexOfAnd2_internal(char *input, char *target, const int start, const int length, const int lengthT, const int count, const char openSymbolWithin, const char closeSymbolWithin) {
  int output = -1;
  int count0 = 1;
  int within = 0;
  int i = 0;
  for (i = start + 1; i < length - lengthT + 1; i++) {
    within = UpdateWithin(input[i], openSymbolWithin, closeSymbolWithin, within);
    if (within == 1 || input[i] != target[0]) {
      continue;
    }
    output = i;
    int i2 = 0;
    for (i2 = 0; i2 < lengthT; i2++) {
      if (input[i + i2] != target[i2]) {
        output = -1;
        break;
      }
    }
    if (output != -1) {
      count0++;
      if (count == -1 || count0 == count) {
        break;
      } else
        output = -1;
    }
  }
  return output;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<IndexOfAnd2_internal>:
  endbr64
  push   %r15
  mov    %r8d,%eax
  push   %r14
  sub    %eax,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r12d
  mov    0x68(%rsp),%r13d
  mov    %r8d,0x18(%rsp)
  lea    0x1(%rdx),%r8d
  mov    %r9d,0x1c(%rsp)
  mov    %ecx,0x10(%rsp)
  cmp    %ecx,%r8d
  jg     L61
  movl   $0x1,0x14(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%r14
  xor    %ecx,%ecx
  movslq 0x18(%rsp),%rbx
  movsbl %r13b,%r13d
  movsbl %r12b,%r12d
  movslq %r8d,%r15
  jmp    L35
  xchg   %ax,%ax
L128:
  add    $0x1,%r15
  cmp    %r15d,0x10(%rsp)
  jl     L61
L35:
  movsbl 0x0(%rbp,%r15,1),%edi
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r15d,0xc(%rsp)
  call   <UpdateWithin@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  je     L128
  movzbl (%r14),%eax
  cmp    %al,0x0(%rbp,%r15,1)
  jne    L128
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L125
  mov    $0x1,%edx
  lea    0x0(%rbp,%r15,1),%rsi
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L112:
  movzbl (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    -0x1(%r14,%rdx,1),%al
  jne    L128
L113:
  cmp    %rdx,%rbx
  jne    L112
L125:
  cmp    $0xffffffff,%r15d
  je     L128
  mov    0x1c(%rsp),%esi
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    $0xffffffff,%esi
  je     L102
  cmp    %esi,%eax
  jne    L128
L102:
  mov    0xc(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L102
```

assistant: ```c
int IndexOfAnd2_internal(char *input, char *target, const int start, const int length, const int lengthT, const int count, const char openSymbolWithin, const char closeSymbolWithin) {
  int output = -1;
  int count0 = 1;
  int within = 0;
  int i = 0;
  for (i = start + 1; i < length - lengthT + 1; i++) {
    within = UpdateWithin(input[i], openSymbolWithin, closeSymbolWithin, within);
    if (within == 1 || input[i] != target[0]) {
      continue;
    }
    output = i;
    int i2 = 0;
    for (i2 = 0; i2 < lengthT; i2++) {
      if (input[i + i2] != target[i2]) {
        output = -1;
        break;
      }
    }
    if (output != -1) {
      count0++;
      if (count == -1 || count0 == count) {
        break;
      } else
        output = -1;
    }
  }
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<seval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %r9,-0x58(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L9
  movl   $0x0,-0x14(%rbp)
L9:
  cmpl   $0x0,-0x14(%rbp)
  jns    L26
  movl   $0x0,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x30(%rbp),%xmm0
  ja     L21
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L33
L21:
  movl   $0x0,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L35:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L59
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L59:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jb     L34
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jg     L35
L33:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm3
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  %xmm3,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double seval(int n, double u, double x[], double y[], double b[], double c[], double d[]) {
  int i, j, k;
  double w;
  if (i >= n - 1)
    i = 0;
  if (i < 0)
    i = 0;
  if ((x[i] > u) || (x[i + 1] < u)) {
    i = 0;
    j = n;
    do {
      k = (i + j) / 2;
      if (u < x[k])
        j = k;
      if (u >= x[k])
        i = k;
    } while (j > i + 1);
  }
  w = u - x[i];
  w = y[i] + w * (b[i] + w * (c[i] + w * d[i]));
  return (w);
}
```
user: Translate the below assembly code into C programming language:

```asm
<seval>:
  endbr64
  mov    %rdx,%r10
  mov    %rcx,%r11
  movsd  (%rsi),%xmm1
  comisd %xmm0,%xmm1
  ja     L34
  mov    $0x0,%edx
  comisd 0x8(%rsi),%xmm0
  ja     L12
  mov    $0x0,%edx
  jmp    L15
L34:
  mov    $0x0,%edx
L12:
  lea    (%rdx,%rdi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  movsd  (%rsi,%rcx,8),%xmm1
  ucomisd %xmm0,%xmm1
  cmova  %eax,%edi
  ucomisd %xmm1,%xmm0
  cmovae %eax,%edx
  lea    0x1(%rdx),%eax
  cmp    %edi,%eax
  jl     L12
L15:
  movslq %edx,%rdx
  subsd  (%rsi,%rdx,8),%xmm0
  movapd %xmm0,%xmm1
  mulsd  (%r9,%rdx,8),%xmm1
  addsd  (%r8,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r11,%rdx,8),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  (%r10,%rdx,8),%xmm0
  ret
```

assistant: ```c
double seval(int n, double u, double x[], double y[], double b[], double c[], double d[]) {
  int i, j, k;
  double w;
  if (i >= n - 1)
    i = 0;
  if (i < 0)
    i = 0;
  if ((x[i] > u) || (x[i + 1] < u)) {
    i = 0;
    j = n;
    do {
      k = (i + j) / 2;
      if (u < x[k])
        j = k;
      if (u >= x[k])
        i = k;
    } while (j > i + 1);
  }
  w = u - x[i];
  w = y[i] + w * (b[i] + w * (c[i] + w * d[i]));
  return (w);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<seval>:
  endbr64
  movsd  (%rsi),%xmm1
  mov    %rdx,%r10
  mov    %rcx,%r11
  comisd %xmm0,%xmm1
  ja     L8
  comisd 0x8(%rsi),%xmm0
  jbe    L17
L8:
  xor    %edx,%edx
  nopl   (%rax)
L9:
  lea    (%rdx,%rdi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  movsd  (%rsi,%rcx,8),%xmm1
  ucomisd %xmm0,%xmm1
  cmova  %eax,%edi
  ucomisd %xmm1,%xmm0
  cmovae %eax,%edx
  lea    0x1(%rdx),%eax
  cmp    %edi,%eax
  jl     L9
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rax
  movsd  (%rsi,%rdx,8),%xmm1
  add    %rax,%r10
  add    %rax,%r11
  add    %rax,%r8
  add    %rax,%r9
L17:
  subsd  %xmm1,%xmm0
  movsd  (%r9),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r11),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  (%r10),%xmm0
  ret
```

assistant: ```c
double seval(int n, double u, double x[], double y[], double b[], double c[], double d[]) {
  int i, j, k;
  double w;
  if (i >= n - 1)
    i = 0;
  if (i < 0)
    i = 0;
  if ((x[i] > u) || (x[i + 1] < u)) {
    i = 0;
    j = n;
    do {
      k = (i + j) / 2;
      if (u < x[k])
        j = k;
      if (u >= x[k])
        i = k;
    } while (j > i + 1);
  }
  w = u - x[i];
  w = y[i] + w * (b[i] + w * (c[i] + w * d[i]));
  return (w);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<seval>:
  endbr64
  push   %rbx
  movsd  (%rsi),%xmm1
  mov    %rsi,%r10
  mov    %rdx,%r11
  mov    %rcx,%rbx
  comisd %xmm0,%xmm1
  ja     L44
  comisd 0x8(%rsi),%xmm0
  jbe    L45
L44:
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L32:
  lea    (%rdi,%rcx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rsi
  movsd  (%r10,%rsi,8),%xmm1
  mov    %rsi,%rdx
  ucomisd %xmm0,%xmm1
  cmova  %esi,%edi
  comisd %xmm1,%xmm0
  jae    L50
  lea    0x1(%rcx),%eax
  cmp    %edi,%eax
  jl     L32
  movslq %ecx,%rdx
L46:
  lea    0x0(,%rdx,8),%rax
  movsd  (%r10,%rdx,8),%xmm1
  add    %rax,%r11
  add    %rax,%rbx
  add    %rax,%r8
  add    %rax,%r9
L45:
  subsd  %xmm1,%xmm0
  movsd  (%r9),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%r8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rbx),%xmm1
  pop    %rbx
  mulsd  %xmm1,%xmm0
  addsd  (%r11),%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  lea    0x1(%rax),%ecx
  cmp    %edi,%ecx
  jge    L46
  mov    %eax,%ecx
  jmp    L32
```

assistant: ```c
double seval(int n, double u, double x[], double y[], double b[], double c[], double d[]) {
  int i, j, k;
  double w;
  if (i >= n - 1)
    i = 0;
  if (i < 0)
    i = 0;
  if ((x[i] > u) || (x[i + 1] < u)) {
    i = 0;
    j = n;
    do {
      k = (i + j) / 2;
      if (u < x[k])
        j = k;
      if (u >= x[k])
        i = k;
    } while (j > i + 1);
  }
  w = u - x[i];
  w = y[i] + w * (b[i] + w * (c[i] + w * d[i]));
  return (w);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bit_sat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bit_sat(int nbit, int val) {
  int pad = (1 << nbit) - 1;
  return (val + pad) & (~pad);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bit_sat>:
  endbr64
  mov    $0x1,%edx
  mov    %edi,%ecx
  shl    %cl,%edx
  lea    -0x1(%rdx,%rsi,1),%eax
  neg    %edx
  and    %edx,%eax
  ret
```

assistant: ```c
int bit_sat(int nbit, int val) {
  int pad = (1 << nbit) - 1;
  return (val + pad) & (~pad);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bit_sat>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  lea    -0x1(%rdx,%rsi,1),%eax
  neg    %edx
  and    %edx,%eax
  ret
```

assistant: ```c
int bit_sat(int nbit, int val) {
  int pad = (1 << nbit) - 1;
  return (val + pad) & (~pad);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bit_sat>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  lea    -0x1(%rdx,%rsi,1),%eax
  neg    %edx
  and    %edx,%eax
  ret
```

assistant: ```c
int bit_sat(int nbit, int val) {
  int pad = (1 << nbit) - 1;
  return (val + pad) & (~pad);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_valid_varname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L29
  cmpb   $0x5f,-0x5(%rbp)
  je     L29
  mov    $0x0,%eax
  jmp    L48
L29:
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L60:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L74
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L74
  mov    $0x0,%eax
  jmp    L48
L74:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L60
  mov    $0x1,%eax
L48:
  leave
  ret
```

assistant: ```c
int is_valid_varname(const char *name, int length) {
  char c = name[0];
  if (!isalpha(c) && c != '_') {
    return 0;
  }
  int i;
  for (i = 1; i < length; i++) {
    if (!isalnum(name[i]) && name[i] != '_') {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_valid_varname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  movzbl (%rdi),%ebx
  movsbl %bl,%edi
  call   <isalpha@plt>
  cmp    $0x5f,%bl
  je     L46
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L8
L46:
  cmp    $0x1,%r12d
  jle    L67
  lea    0x1(%rbp),%rbx
  lea    -0x2(%r12),%eax
  lea    0x2(%rbp,%rax,1),%rbp
  jmp    L0
L15:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L50
L0:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L15
  cmpb   $0x5f,(%rbx)
  je     L15
  jmp    L8
L50:
  mov    $0x1,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  mov    $0x1,%eax
  jmp    L8
```

assistant: ```c
int is_valid_varname(const char *name, int length) {
  char c = name[0];
  if (!isalpha(c) && c != '_') {
    return 0;
  }
  int i;
  for (i = 1; i < length; i++) {
    if (!isalnum(name[i]) && name[i] != '_') {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_valid_varname>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %edi,%ebx
  call   <isalpha@plt>
  cmp    $0x5f,%bl
  je     L43
  test   %eax,%eax
  je     L3
L43:
  cmp    $0x1,%r12d
  jle    L2
  lea    -0x2(%r12),%eax
  lea    0x1(%rbp),%rbx
  lea    0x2(%rbp,%rax,1),%rbp
  nopl   (%rax)
L4:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L5
  cmpb   $0x5f,(%rbx)
  jne    L3
L5:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
L2:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int is_valid_varname(const char *name, int length) {
  char c = name[0];
  if (!isalpha(c) && c != '_') {
    return 0;
  }
  int i;
  for (i = 1; i < length; i++) {
    if (!isalnum(name[i]) && name[i] != '_') {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_valid_varname>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %edi,%ebx
  call   <isalpha@plt>
  cmp    $0x5f,%bl
  je     L14
  test   %eax,%eax
  je     L18
L14:
  cmp    $0x1,%r12d
  jle    L52
  lea    -0x2(%r12),%eax
  lea    0x1(%rbp),%rbx
  lea    0x2(%rbp,%rax,1),%rbp
  nopl   (%rax)
L9:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L23
  cmpb   $0x5f,(%rbx)
  jne    L18
L23:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L52:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int is_valid_varname(const char *name, int length) {
  char c = name[0];
  if (!isalpha(c) && c != '_') {
    return 0;
  }
  int i;
  for (i = 1; i < length; i++) {
    if (!isalnum(name[i]) && name[i] != '_') {
      return 0;
    }
  }
  return 1;
}
```