ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<get_next_path_element>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract_colon_unit@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  jmp    L12
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <efree@plt>
  mov    $0x2,%edi
  call   <emalloc@plt>
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %rax,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: .

assistant: ```c
char *get_next_path_element(const char *path_list, int *path_index_pointer) {
  char *path;
  path = extract_colon_unit(path_list, path_index_pointer);
  if (!path)
    return (path);
  if (!*path) {
    efree(path);
    path = (char *)strcpy((char *)emalloc(1 + strlen(".")), ("."));
  }
  return (path);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_next_path_element>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_colon_unit@plt>
  test   %rax,%rax
  je     L16
  cmpb   $0x0,(%rax)
  je     L20
L16:
  add    $0x8,%rsp
  ret
L20:
  mov    %rax,%rdi
  call   <efree@plt>
  mov    $0x2,%edi
  call   <emalloc@plt>
  mov    %rax,%rdi
  lea    D0(%rip),%rsi
  call   <strcpy@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: .

assistant: ```c
char *get_next_path_element(const char *path_list, int *path_index_pointer) {
  char *path;
  path = extract_colon_unit(path_list, path_index_pointer);
  if (!path)
    return (path);
  if (!*path) {
    efree(path);
    path = (char *)strcpy((char *)emalloc(1 + strlen(".")), ("."));
  }
  return (path);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_next_path_element>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_colon_unit@plt>
  test   %rax,%rax
  je     L1
  cmpb   $0x0,(%rax)
  je     L5
L1:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  mov    %rax,%rdi
  call   <efree@plt>
  mov    $0x2,%edi
  call   <emalloc@plt>
  lea    D3(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <strcpy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: .

assistant: ```c
char *get_next_path_element(const char *path_list, int *path_index_pointer) {
  char *path;
  path = extract_colon_unit(path_list, path_index_pointer);
  if (!path)
    return (path);
  if (!*path) {
    efree(path);
    path = (char *)strcpy((char *)emalloc(1 + strlen(".")), ("."));
  }
  return (path);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_next_path_element>:
  endbr64
  sub    $0x8,%rsp
  call   <extract_colon_unit@plt>
  test   %rax,%rax
  je     L15
  cmpb   $0x0,(%rax)
  je     L2
L15:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L2:
  mov    %rax,%rdi
  call   <efree@plt>
  mov    $0x2,%edi
  call   <emalloc@plt>
  lea    D7(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <strcpy@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: .

assistant: ```c
char *get_next_path_element(const char *path_list, int *path_index_pointer) {
  char *path;
  path = extract_colon_unit(path_list, path_index_pointer);
  if (!path)
    return (path);
  if (!*path) {
    efree(path);
    path = (char *)strcpy((char *)emalloc(1 + strlen(".")), ("."));
  }
  return (path);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<VecCcwNormNormalReturnLength3fv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <VecSubtract3fv@plt>
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <VecSubtract3fv@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <VecCrossProd3fv@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <VecLength3fv@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x38(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <VecSelfScalarDiv3fv@plt>
  movss  -0x24(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
float VecCcwNormNormalReturnLength3fv(float n[3], const int a[3], const int b[3], const int c[3]) {
  float ab[3], ac[3];
  VecSubtract3fv(ab, b, a);
  VecSubtract3fv(ac, c, a);
  VecCrossProd3fv(n, ab, ac);
  float l = VecLength3fv(n);
  VecSelfScalarDiv3fv(n, l);
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VecCcwNormNormalReturnLength3fv>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %rbp,%rdx
  mov    %r13,%rdi
  call   <VecSubtract3fv@plt>
  lea    0x1c(%rsp),%r14
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <VecSubtract3fv@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <VecCrossProd3fv@plt>
  mov    %rbx,%rdi
  call   <VecLength3fv@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %rbx,%rdi
  call   <VecSelfScalarDiv3fv@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  movss  0xc(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float VecCcwNormNormalReturnLength3fv(float n[3], const int a[3], const int b[3], const int c[3]) {
  float ab[3], ac[3];
  VecSubtract3fv(ab, b, a);
  VecSubtract3fv(ac, c, a);
  VecCrossProd3fv(n, ab, ac);
  float l = VecLength3fv(n);
  VecSelfScalarDiv3fv(n, l);
  return l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<VecCcwNormNormalReturnLength3fv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %r12,%rdx
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x1c(%rsp),%r15
  mov    %r14,%rdi
  call   <VecSubtract3fv@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <VecSubtract3fv@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <VecCrossProd3fv@plt>
  mov    %rbp,%rdi
  call   <VecLength3fv@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <VecSelfScalarDiv3fv@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float VecCcwNormNormalReturnLength3fv(float n[3], const int a[3], const int b[3], const int c[3]) {
  float ab[3], ac[3];
  VecSubtract3fv(ab, b, a);
  VecSubtract3fv(ac, c, a);
  VecCrossProd3fv(n, ab, ac);
  float l = VecLength3fv(n);
  VecSelfScalarDiv3fv(n, l);
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VecCcwNormNormalReturnLength3fv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %r12,%rdx
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x1c(%rsp),%r15
  mov    %r14,%rdi
  call   <VecSubtract3fv@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <VecSubtract3fv@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <VecCrossProd3fv@plt>
  mov    %rbp,%rdi
  call   <VecLength3fv@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <VecSelfScalarDiv3fv@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float VecCcwNormNormalReturnLength3fv(float n[3], const int a[3], const int b[3], const int c[3]) {
  float ab[3], ac[3];
  VecSubtract3fv(ab, b, a);
  VecSubtract3fv(ac, c, a);
  VecCrossProd3fv(n, ab, ac);
  float l = VecLength3fv(n);
  VecSelfScalarDiv3fv(n, l);
  return l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  movss  D6(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D6
datatype: byte[4]
name: read_data
arguments: data_tag: D1
datatype: string

tool: D11: %f

tool: {"D6": [0x00,0x00,0xa0,0x40]}

tool: D1: %0.2f

assistant: ```c
main() {
  float num;
  scanf("%f", &num);
  printf("%0.2f", num / 5);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  divss  D13(%rip),%xmm0
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: byte[4]
name: read_data
arguments: data_label: D27
type_guessed: string

tool: D19: %f

tool: {"D13": [0x00,0x00,0xa0,0x40]}

tool: D27: %0.2f

assistant: ```c
main() {
  float num;
  scanf("%f", &num);
  printf("%0.2f", num / 5);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  movss  0x4(%rsp),%xmm0
  divss  D3(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: byte[4]

tool: D21: %f

tool: D9: %0.2f

tool: {"D3": [0x00,0x00,0xa0,0x40]}

assistant: ```c
main() {
  float num;
  scanf("%f", &num);
  printf("%0.2f", num / 5);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  movss  0x4(%rsp),%xmm0
  divss  D3(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
type: string
name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D3
type: byte[4]

tool: D21: %f

tool: D8: %0.2f

tool: {"D3": [0x00,0x00,0xa0,0x40]}

assistant: ```c
main() {
  float num;
  scanf("%f", &num);
  printf("%0.2f", num / 5);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<send_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  movzwl -0x28(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %ax,-0x28(%rbp)
  lea    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x34(%rbp),%eax
  lea    0x2(%rax),%ecx
  lea    -0x1c(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <cduck_encrypt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void send_packet(int socket, unsigned short msgid, const void *data, unsigned int dlen) {
  void *newblock2;
  unsigned int newblock2len;
  unsigned char *newblock = malloc(dlen + 2);
  memcpy(newblock + 2, data, dlen);
  msgid = htons(msgid);
  memcpy(newblock, &msgid, 2);
  newblock2 = cduck_encrypt(newblock, dlen + 2, &newblock2len);
  write(socket, newblock2, newblock2len);
  free(newblock2);
  free(newblock);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_packet>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %rdx,%r13
  mov    %ecx,%ebp
  mov    %si,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x2(%rcx),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x2(%rax),%rdi
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movzwl 0xc(%rsp),%edi
  call   <htons@plt>
  mov    %ax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x14(%rsp),%rdx
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <cduck_encrypt@plt>
  mov    %rax,%rbp
  mov    0x14(%rsp),%edx
  mov    %rax,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_packet(int socket, unsigned short msgid, const void *data, unsigned int dlen) {
  void *newblock2;
  unsigned int newblock2len;
  unsigned char *newblock = malloc(dlen + 2);
  memcpy(newblock + 2, data, dlen);
  msgid = htons(msgid);
  memcpy(newblock, &msgid, 2);
  newblock2 = cduck_encrypt(newblock, dlen + 2, &newblock2len);
  write(socket, newblock2, newblock2len);
  free(newblock2);
  free(newblock);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_packet>:
  endbr64
  push   %r15
  lea    0x2(%rcx),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %r15d,%edi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  sub    $0x20,%rsp
  mov    %si,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  lea    0x2(%rax),%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  movzwl 0xc(%rsp),%edi
  call   <htons@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    %ax,0xc(%rsp)
  call   <memcpy@plt>
  lea    0x14(%rsp),%rdx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <cduck_encrypt@plt>
  mov    0x14(%rsp),%edx
  mov    %r13d,%edi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <write@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_packet(int socket, unsigned short msgid, const void *data, unsigned int dlen) {
  void *newblock2;
  unsigned int newblock2len;
  unsigned char *newblock = malloc(dlen + 2);
  memcpy(newblock + 2, data, dlen);
  msgid = htons(msgid);
  memcpy(newblock, &msgid, 2);
  newblock2 = cduck_encrypt(newblock, dlen + 2, &newblock2len);
  write(socket, newblock2, newblock2len);
  free(newblock2);
  free(newblock);
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_packet>:
  endbr64
  push   %r15
  lea    0x2(%rcx),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %r15d,%edi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  sub    $0x20,%rsp
  mov    %si,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  lea    0x2(%rax),%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  movzwl 0xc(%rsp),%edi
  call   <htons@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    %ax,0xc(%rsp)
  call   <memcpy@plt>
  lea    0x14(%rsp),%rdx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <cduck_encrypt@plt>
  mov    0x14(%rsp),%edx
  mov    %r13d,%edi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <write@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_packet(int socket, unsigned short msgid, const void *data, unsigned int dlen) {
  void *newblock2;
  unsigned int newblock2len;
  unsigned char *newblock = malloc(dlen + 2);
  memcpy(newblock + 2, data, dlen);
  msgid = htons(msgid);
  memcpy(newblock, &msgid, 2);
  newblock2 = cduck_encrypt(newblock, dlen + 2, &newblock2len);
  write(socket, newblock2, newblock2len);
  free(newblock2);
  free(newblock);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ivec_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L8:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ivec_add(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] += v2[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ivec_add>:
  endbr64
  test   %rdx,%rdx
  jle    L16
  mov    $0x0,%eax
L15:
  mov    (%rsi,%rax,4),%ecx
  add    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L15
L16:
  ret
```

assistant: ```c
void ivec_add(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] += v2[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ivec_add>:
  endbr64
  test   %rdx,%rdx
  jle    L9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rsi,%rax,4),%ecx
  add    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L0
L9:
  ret
```

assistant: ```c
void ivec_add(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] += v2[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ivec_add>:
  endbr64
  mov    %rdi,%rcx
  test   %rdx,%rdx
  jle    L94
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L17
  cmp    $0x1,%rdx
  je     L17
  lea    -0x1(%rdx),%rax
  mov    %rdx,%r8
  cmp    $0x2,%rax
  jbe    L37
  mov    %rdx,%rdi
  xor    %eax,%eax
  shr    $0x2,%rdi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L3:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L3
  mov    %rdx,%rdi
  and    $0xfffffffffffffffc,%rdi
  mov    %rdi,%rax
  cmp    %rdi,%rdx
  je     L94
  sub    %rdi,%rdx
  mov    %rdx,%r8
  cmp    $0x1,%rdx
  je     L13
L8:
  lea    (%rcx,%rdi,4),%rdx
  movq   (%rsi,%rdi,4),%xmm0
  movq   (%rdx),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rdx)
  mov    %r8,%rdx
  and    $0xfffffffffffffffe,%rdx
  add    %rdx,%rax
  cmp    %rdx,%r8
  je     L94
L13:
  mov    (%rsi,%rax,4),%edx
  add    %edx,(%rcx,%rax,4)
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L78:
  mov    (%rsi,%rax,4),%edi
  add    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L78
L94:
  ret
L37:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
void ivec_add(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] += v2[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  jmp    L40
L39:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L52:
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L45
  mov    -0x20(%rbp),%eax
  shr    %eax
  xor    $0xedb88320,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L9
L45:
  shrl   -0x20(%rbp)
L9:
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x7,-0x4(%rbp)
  jle    L52
  subl   $0x1,-0x1c(%rbp)
L40:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L39
  mov    -0x20(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int crc32(char *addr, int num, unsigned int crc) {
  int i;
  for (; num > 0; num--) {
    crc = crc ^ *addr++;
    for (i = 0; i < 8; i++) {
      if (crc & 1)
        crc = (crc >> 1) ^ 0xEDB88320;
      else
        crc >>= 1;
    }
  }
  return (crc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crc32>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L28
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%r8
  jmp    L19
L31:
  cmp    %r8,%rdi
  je     L28
L19:
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L38:
  mov    %eax,%edx
  shr    %edx
  xor    $0xedb88320,%edx
  mov    %eax,%esi
  shr    %esi
  test   $0x1,%al
  mov    %edx,%eax
  cmove  %esi,%eax
  sub    $0x1,%ecx
  jne    L38
  jmp    L31
L28:
  ret
```

assistant: ```c
unsigned int crc32(char *addr, int num, unsigned int crc) {
  int i;
  for (; num > 0; num--) {
    crc = crc ^ *addr++;
    for (i = 0; i < 8; i++) {
      if (crc & 1)
        crc = (crc >> 1) ^ 0xEDB88320;
      else
        crc >>= 1;
    }
  }
  return (crc);
}
```