ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<da>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%edi
  call   <set_pzs@plt>
  mov    $0x0,%esi
  mov    $0x2,%edi
  call   <wait@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void da(void) {
  set_pzs(8);
  wait(2, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<da>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <set_pzs@plt>
  mov    $0x0,%esi
  mov    $0x2,%edi
  call   <wait@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void da(void) {
  set_pzs(8);
  wait(2, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<da>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <set_pzs@plt>
  xor    %esi,%esi
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <wait@plt>
```

assistant: ```c
void da(void) {
  set_pzs(8);
  wait(2, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<da>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <set_pzs@plt>
  xor    %esi,%esi
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <wait@plt>
```

assistant: ```c
void da(void) {
  set_pzs(8);
  wait(2, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<setup_aeskey>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  movq   $0x19009060,(%rsp)
  movq   $0x10009090,0x8(%rsp)
  movq   $0x100090c0,0x10(%rsp)
  movq   $0x100090f0,0x18(%rsp)
  mov    0x10009000,%edx
  and    $0xfd7fffff,%edx
  mov    %esi,%ecx
  shl    $0x17,%ecx
  or     %ecx,%edx
  mov    %edx,0x10009000
  cmp    $0x3,%edi
  jle    L51
  cmp    $0x3f,%edi
  jg     L2
  mov    0x10009011,%edx
  and    $0xffffffc0,%edx
  or     %edi,%edx
  or     $0x80,%dl
  mov    %edx,0x10009011
  mov    (%rax),%edx
  mov    %edx,0x10009108
  mov    0x4(%rax),%edx
  mov    %edx,0x10009108
  mov    0x8(%rax),%edx
  mov    %edx,0x10009108
  mov    0xc(%rax),%eax
  mov    %eax,0x10009108
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  ret
L51:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rdx
  test   $0x4,%sil
  je     L56
  mov    0xc(%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    (%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L2
L56:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    0xc(%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L2
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setup_aeskey(uint32_t keyno, int value, void *key) {
  volatile uint32_t *aes_regs[] = {(volatile uint32_t *)0x19009060, (volatile uint32_t *)0x10009090, (volatile uint32_t *)0x100090C0, (volatile uint32_t *)0x100090F0};
  uint32_t *_key = (uint32_t *)key;
  *((volatile uint32_t *)0x10009000) = (*((volatile uint32_t *)0x10009000) & ~(0x00800000 | 0x02000000)) | (value << 23);
  if (keyno > 3) {
    if (keyno > 0x3F)
      return;
    *((volatile uint8_t *)0x10009011) = (*((volatile uint8_t *)0x10009011) >> 6 << 6) | (uint8_t)keyno | 0x80;
    *((volatile uint32_t *)0x10009108) = _key[0];
    *((volatile uint32_t *)0x10009108) = _key[1];
    *((volatile uint32_t *)0x10009108) = _key[2];
    *((volatile uint32_t *)0x10009108) = _key[3];
  } else {
    volatile uint32_t *aes_reg = aes_regs[keyno];
    if (value & 0x4) {
      aes_reg[0] = _key[3];
      aes_reg[1] = _key[2];
      aes_reg[2] = _key[1];
      aes_reg[3] = _key[0];
    } else {
      aes_reg[0] = _key[0];
      aes_reg[1] = _key[1];
      aes_reg[2] = _key[2];
      aes_reg[3] = _key[3];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup_aeskey>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  mov    %esi,%ecx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  shl    $0x17,%ecx
  movq   $0x19009060,(%rsp)
  movq   $0x10009090,0x8(%rsp)
  movq   $0x100090c0,0x10(%rsp)
  mov    0x10009000,%edx
  movq   $0x100090f0,0x18(%rsp)
  and    $0xfd7fffff,%edx
  or     %ecx,%edx
  mov    %edx,0x10009000
  cmp    $0x3,%edi
  jle    L4
  cmp    $0x3f,%edi
  jg     L47
  mov    0x10009011,%edx
  and    $0xffffffc0,%edx
  or     %edi,%edx
  or     $0x80,%dl
  mov    %edx,0x10009011
  mov    (%rax),%edx
  mov    %edx,0x10009108
  mov    0x4(%rax),%edx
  mov    %edx,0x10009108
  mov    0x8(%rax),%edx
  mov    %edx,0x10009108
  mov    0xc(%rax),%eax
  mov    %eax,0x10009108
L47:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L4:
  movslq %edi,%rdi
  and    $0x4,%esi
  mov    (%rsp,%rdi,8),%rdx
  je     L38
  mov    0xc(%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    (%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L47
  nopl   0x0(%rax)
L38:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    0xc(%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L47
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setup_aeskey(uint32_t keyno, int value, void *key) {
  volatile uint32_t *aes_regs[] = {(volatile uint32_t *)0x19009060, (volatile uint32_t *)0x10009090, (volatile uint32_t *)0x100090C0, (volatile uint32_t *)0x100090F0};
  uint32_t *_key = (uint32_t *)key;
  *((volatile uint32_t *)0x10009000) = (*((volatile uint32_t *)0x10009000) & ~(0x00800000 | 0x02000000)) | (value << 23);
  if (keyno > 3) {
    if (keyno > 0x3F)
      return;
    *((volatile uint8_t *)0x10009011) = (*((volatile uint8_t *)0x10009011) >> 6 << 6) | (uint8_t)keyno | 0x80;
    *((volatile uint32_t *)0x10009108) = _key[0];
    *((volatile uint32_t *)0x10009108) = _key[1];
    *((volatile uint32_t *)0x10009108) = _key[2];
    *((volatile uint32_t *)0x10009108) = _key[3];
  } else {
    volatile uint32_t *aes_reg = aes_regs[keyno];
    if (value & 0x4) {
      aes_reg[0] = _key[3];
      aes_reg[1] = _key[2];
      aes_reg[2] = _key[1];
      aes_reg[3] = _key[0];
    } else {
      aes_reg[0] = _key[0];
      aes_reg[1] = _key[1];
      aes_reg[2] = _key[2];
      aes_reg[3] = _key[3];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<setup_aeskey>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  movdqa D19(%rip),%xmm0
  mov    %esi,%ecx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  shl    $0x17,%ecx
  movaps %xmm0,(%rsp)
  movdqa D0(%rip),%xmm0
  mov    0x10009000,%edx
  movaps %xmm0,0x10(%rsp)
  and    $0xfd7fffff,%edx
  or     %ecx,%edx
  mov    %edx,0x10009000
  cmp    $0x3,%edi
  jle    L51
  cmp    $0x3f,%edi
  jg     L59
  mov    0x10009011,%edx
  and    $0xffffffc0,%edx
  or     %edi,%edx
  or     $0x80,%dl
  mov    %edx,0x10009011
  mov    (%rax),%edx
  mov    %edx,0x10009108
  mov    0x4(%rax),%edx
  mov    %edx,0x10009108
  mov    0x8(%rax),%edx
  mov    %edx,0x10009108
  mov    0xc(%rax),%eax
  mov    %eax,0x10009108
L59:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  movslq %edi,%rdi
  and    $0x4,%esi
  mov    (%rsp,%rdi,8),%rdx
  je     L35
  mov    0xc(%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    (%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L59
  nopl   0x0(%rax)
L35:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  mov    0x4(%rax),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0x8(%rax),%ecx
  mov    %ecx,0x8(%rdx)
  mov    0xc(%rax),%eax
  mov    %eax,0xc(%rdx)
  jmp    L59
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: byte[16]
name: unpack_data
arguments: tag: D0
data_type: byte[16]

tool: {"D19": [0x60,0x90,0x00,0x19,0x00,0x00,0x00,0x00,0x90,0x90,0x00,0x10,0x00,0x00,0x00,0x00]}

tool: {"D0": [0xc0,0x90,0x00,0x10,0x00,0x00,0x00,0x00,0xf0,0x90,0x00,0x10,0x00,0x00,0x00,0x00]}

assistant: ```c
void setup_aeskey(uint32_t keyno, int value, void *key) {
  volatile uint32_t *aes_regs[] = {(volatile uint32_t *)0x19009060, (volatile uint32_t *)0x10009090, (volatile uint32_t *)0x100090C0, (volatile uint32_t *)0x100090F0};
  uint32_t *_key = (uint32_t *)key;
  *((volatile uint32_t *)0x10009000) = (*((volatile uint32_t *)0x10009000) & ~(0x00800000 | 0x02000000)) | (value << 23);
  if (keyno > 3) {
    if (keyno > 0x3F)
      return;
    *((volatile uint8_t *)0x10009011) = (*((volatile uint8_t *)0x10009011) >> 6 << 6) | (uint8_t)keyno | 0x80;
    *((volatile uint32_t *)0x10009108) = _key[0];
    *((volatile uint32_t *)0x10009108) = _key[1];
    *((volatile uint32_t *)0x10009108) = _key[2];
    *((volatile uint32_t *)0x10009108) = _key[3];
  } else {
    volatile uint32_t *aes_reg = aes_regs[keyno];
    if (value & 0x4) {
      aes_reg[0] = _key[3];
      aes_reg[1] = _key[2];
      aes_reg[2] = _key[1];
      aes_reg[3] = _key[0];
    } else {
      aes_reg[0] = _key[0];
      aes_reg[1] = _key[1];
      aes_reg[2] = _key[2];
      aes_reg[3] = _key[3];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i2c_OLED_send_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L9
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <i2c_OLED_send_char@plt>
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void i2c_OLED_send_string(const char *string) {
  while (*string) {
    i2c_OLED_send_char(*string);
    string++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i2c_OLED_send_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L18:
  movsbl %dil,%edi
  call   <i2c_OLED_send_char@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L1:
  pop    %rbx
  ret
```

assistant: ```c
void i2c_OLED_send_string(const char *string) {
  while (*string) {
    i2c_OLED_send_char(*string);
    string++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<i2c_OLED_send_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L6:
  call   <i2c_OLED_send_char@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L6
L4:
  pop    %rbx
  ret
```

assistant: ```c
void i2c_OLED_send_string(const char *string) {
  while (*string) {
    i2c_OLED_send_char(*string);
    string++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<i2c_OLED_send_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L16:
  call   <i2c_OLED_send_char@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L16
L9:
  pop    %rbx
  ret
```

assistant: ```c
void i2c_OLED_send_string(const char *string) {
  while (*string) {
    i2c_OLED_send_char(*string);
    string++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stress_mount_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L17
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L19
L17:
  nop
  jmp    L19
L33:
  nop
L19:
  leave
  ret
```

assistant: ```c
void stress_mount_add(char *mnts[], const int max, int *n, const char *name) {
  char *mnt;
  if (*n >= max)
    return;
  mnt = strdup(name);
  if (!mnt)
    return;
  mnts[*n] = mnt;
  (*n)++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stress_mount_add>:
  endbr64
  cmp    %esi,(%rdx)
  jl     L12
  ret
L12:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%rdi
  call   <strdup@plt>
  test   %rax,%rax
  je     L7
  movslq (%rbx),%rdx
  mov    %rax,0x0(%rbp,%rdx,8)
  addl   $0x1,(%rbx)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stress_mount_add(char *mnts[], const int max, int *n, const char *name) {
  char *mnt;
  if (*n >= max)
    return;
  mnt = strdup(name);
  if (!mnt)
    return;
  mnts[*n] = mnt;
  (*n)++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stress_mount_add>:
  endbr64
  cmp    %esi,(%rdx)
  jl     L16
  ret
  nopl   0x0(%rax)
L16:
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  test   %rax,%rax
  je     L7
  movslq (%rbx),%rcx
  mov    %rcx,%rdx
  mov    %rax,0x0(%rbp,%rcx,8)
  add    $0x1,%edx
  mov    %edx,(%rbx)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stress_mount_add(char *mnts[], const int max, int *n, const char *name) {
  char *mnt;
  if (*n >= max)
    return;
  mnt = strdup(name);
  if (!mnt)
    return;
  mnts[*n] = mnt;
  (*n)++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stress_mount_add>:
  endbr64
  cmp    %esi,(%rdx)
  jl     L10
  ret
  nopl   0x0(%rax)
L10:
  push   %rbp
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  test   %rax,%rax
  je     L19
  movslq (%rbx),%rcx
  mov    %rcx,%rdx
  mov    %rax,0x0(%rbp,%rcx,8)
  add    $0x1,%edx
  mov    %edx,(%rbx)
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void stress_mount_add(char *mnts[], const int max, int *n, const char *name) {
  char *mnt;
  if (*n >= max)
    return;
  mnt = strdup(name);
  if (!mnt)
    return;
  mnts[*n] = mnt;
  (*n)++;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L18
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L22
L18:
  movl   $0x0,-0x14(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <sem_open@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <sem_open@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L37
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_wait@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_post@plt>
  addl   $0x1,-0x18(%rbp)
L37:
  cmpl   $0x5f5e0ff,-0x18(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D22
type: string

tool: D5: Customer starting (%d)


tool: D3: /my_semaphor_2_name_simple_seq

tool: D1: /my_semaphor_1_name_simple_seq

tool: D22: 			customer: put coin(%d)@%d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, myID;
  sem_t *coin, *lock;
  if (argc > 1)
    myID = atoi(argv[1]);
  else
    myID = 0;
  printf("Customer starting (%d)\n", myID);
  lock = sem_open("/my_semaphor_2_name_simple_seq", 0);
  coin = sem_open("/my_semaphor_1_name_simple_seq", 0);
  for (i = 0; i < 100 * 1000 * 1000; i++) {
    sem_wait(coin);
    printf("\t\t\tcustomer: put coin(%d)@%d\n", myID, i);
    sem_post(lock);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  cmp    $0x1,%edi
  jg     L12
L4:
  mov    %ebp,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D12(%rip),%rdi
  call   <sem_open@plt>
  mov    %rax,%r13
  mov    $0x0,%esi
  lea    D21(%rip),%rdi
  call   <sem_open@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  lea    D1(%rip),%r14
L5:
  mov    %r12,%rdi
  call   <sem_wait@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <sem_post@plt>
  add    $0x1,%ebx
  cmp    $0x5f5e100,%ebx
  jne    L5
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D39: Customer starting (%d)


tool: D12: /my_semaphor_2_name_simple_seq

tool: D21: /my_semaphor_1_name_simple_seq

tool: D1: 			customer: put coin(%d)@%d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, myID;
  sem_t *coin, *lock;
  if (argc > 1)
    myID = atoi(argv[1]);
  else
    myID = 0;
  printf("Customer starting (%d)\n", myID);
  lock = sem_open("/my_semaphor_2_name_simple_seq", 0);
  coin = sem_open("/my_semaphor_1_name_simple_seq", 0);
  for (i = 0; i < 100 * 1000 * 1000; i++) {
    sem_wait(coin);
    printf("\t\t\tcustomer: put coin(%d)@%d\n", myID, i);
    sem_post(lock);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  cmp    $0x1,%edi
  jle    L18
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L18:
  mov    %ebp,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  xor    %esi,%esi
  lea    D30(%rip),%rdi
  lea    D8(%rip),%r14
  call   <sem_open@plt>
  xor    %esi,%esi
  lea    D27(%rip),%rdi
  mov    %rax,%r13
  call   <sem_open@plt>
  mov    %rax,%r12
  nopl   0x0(%rax)
L19:
  mov    %r12,%rdi
  call   <sem_wait@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rdi
  call   <sem_post@plt>
  cmp    $0x5f5e100,%ebx
  jne    L19
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
type_infered: string
name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: string

tool: D33: Customer starting (%d)


tool: D30: /my_semaphor_2_name_simple_seq

tool: D8: 			customer: put coin(%d)@%d


tool: D27: /my_semaphor_1_name_simple_seq

assistant: ```c
int main(int argc, char *argv[]) {
  int i, myID;
  sem_t *coin, *lock;
  if (argc > 1)
    myID = atoi(argv[1]);
  else
    myID = 0;
  printf("Customer starting (%d)\n", myID);
  lock = sem_open("/my_semaphor_2_name_simple_seq", 0);
  coin = sem_open("/my_semaphor_1_name_simple_seq", 0);
  for (i = 0; i < 100 * 1000 * 1000; i++) {
    sem_wait(coin);
    printf("\t\t\tcustomer: put coin(%d)@%d\n", myID, i);
    sem_post(lock);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  cmp    $0x1,%edi
  jle    L11
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L11:
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  lea    D1(%rip),%r14
  call   <sem_open@plt>
  xor    %esi,%esi
  lea    D39(%rip),%rdi
  mov    %rax,%r13
  call   <sem_open@plt>
  mov    %rax,%r12
  nopl   0x0(%rax)
L17:
  mov    %r12,%rdi
  call   <sem_wait@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rdi
  call   <sem_post@plt>
  cmp    $0x5f5e100,%ebx
  jne    L17
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D39
type_guessed: string

tool: D6: Customer starting (%d)


tool: D21: /my_semaphor_2_name_simple_seq

tool: D1: 			customer: put coin(%d)@%d


tool: D39: /my_semaphor_1_name_simple_seq

assistant: ```c
int main(int argc, char *argv[]) {
  int i, myID;
  sem_t *coin, *lock;
  if (argc > 1)
    myID = atoi(argv[1]);
  else
    myID = 0;
  printf("Customer starting (%d)\n", myID);
  lock = sem_open("/my_semaphor_2_name_simple_seq", 0);
  coin = sem_open("/my_semaphor_1_name_simple_seq", 0);
  for (i = 0; i < 100 * 1000 * 1000; i++) {
    sem_wait(coin);
    printf("\t\t\tcustomer: put coin(%d)@%d\n", myID, i);
    sem_post(lock);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mumps_get_save_prefix_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x20(%rbp)
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D5: MUMPS_SAVE_PREFIX

tool: D2: NAME_NOT_INITIALIZED

assistant: ```c
void mumps_get_save_prefix_c(int *len_save_prefix, char *save_prefix, int l1) {
  char *tmp_save_prefix;
  tmp_save_prefix = getenv("MUMPS_SAVE_PREFIX");
  if (tmp_save_prefix == NULL) {
    tmp_save_prefix = "NAME_NOT_INITIALIZED";
  }
  *len_save_prefix = strlen(tmp_save_prefix);
  save_prefix = strncpy(save_prefix, tmp_save_prefix, l1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mumps_get_save_prefix_c>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    D11(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  lea    D4(%rip),%rax
  cmove  %rax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0x0(%r13)
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D11: MUMPS_SAVE_PREFIX

tool: D4: NAME_NOT_INITIALIZED

assistant: ```c
void mumps_get_save_prefix_c(int *len_save_prefix, char *save_prefix, int l1) {
  char *tmp_save_prefix;
  tmp_save_prefix = getenv("MUMPS_SAVE_PREFIX");
  if (tmp_save_prefix == NULL) {
    tmp_save_prefix = "NAME_NOT_INITIALIZED";
  }
  *len_save_prefix = strlen(tmp_save_prefix);
  save_prefix = strncpy(save_prefix, tmp_save_prefix, l1);
}
```