ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<vfprintf>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <flockfile@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vfprintf_unlocked@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <funlockfile@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int vfprintf(FILE *restrict file, const char *restrict format, va_list ap) {
  flockfile(file);
  int result = vfprintf_unlocked(file, format, ap);
  funlockfile(file);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_error>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %rdi,%r13
  mov    %rsi,%r12
  lea    0x960(%rcx),%r14
  mov    $0x12c,%r15d
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
L8:
  mov    0x8(%rsp),%rax
  lea    (%rax,%r15,8),%rbp
  mov    $0x1,%ebx
L0:
  movsd  -0x8(%r13,%rbx,8),%xmm1
  movsd  0x0(%r13,%rbx,8),%xmm4
  movsd  -0x8(%r12,%rbx,8),%xmm3
  movsd  0x948(%r12,%rbx,8),%xmm2
  movapd %xmm1,%xmm0
  mulsd  0x0(%rbp),%xmm0
  movapd %xmm4,%xmm5
  mulsd  0x10(%rbp),%xmm5
  addsd  %xmm5,%xmm0
  movapd %xmm3,%xmm5
  mulsd  -0x958(%rbp),%xmm5
  addsd  %xmm5,%xmm0
  movapd %xmm2,%xmm5
  mulsd  0x968(%rbp),%xmm5
  addsd  %xmm5,%xmm0
  addsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  0x8(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  subsd  (%r14,%rbx,8),%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%rbx
  add    $0x8,%rbp
  cmp    $0x12b,%rbx
  jne    L0
  add    $0x12c,%r15
  add    $0x958,%r13
  add    $0x950,%r12
  add    $0x960,%r14
  cmp    $0x15e64,%r15
  jne    L8
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double compute_error(double *a_x, double *a_y, double *P, double *fn) {
  double error = 0.0;
  long indx, indx_rght, indx_frnt, indx_lft, indx_bck, i, j, indx_ax, indx_ay;
  for (i = 1; i < 300 - 1; i++) {
    for (j = 1; j < 300 - 1; j++) {
      indx = i * 300 + j;
      indx_rght = indx + 1;
      indx_frnt = indx + 300;
      indx_lft = indx - 1;
      indx_bck = indx - 300;
      indx_ax = (i - 1) * (300 - 1) + j - 1;
      indx_ay = (i - 1) * (300 - 2) + j - 1;
      error += fabs(a_x[indx_ax] * P[indx_lft] + a_x[indx_ax + 1] * P[indx_rght] + a_y[indx_ay] * P[indx_bck] + a_y[indx_ay + (300 - 2)] * P[indx_frnt] - (a_x[indx_ax] + a_x[indx_ax + 1] + a_y[indx_ay] + a_y[indx_ay + (300 - 2)]) * P[indx] - 1.0 * 1.0 * fn[indx]);
    }
  }
  return (error);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compute_error>:
  endbr64
  push   %r15
  pxor   %xmm7,%xmm7
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x12c,%ebp
  push   %rbx
  lea    0x960(%rcx),%rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movsd  %xmm7,(%rsp)
L18:
  mov    0x8(%rsp),%rax
  mov    $0x1,%r13d
  lea    (%rax,%rbp,8),%r14
  nopl   0x0(%rax)
L15:
  movsd  -0x8(%r12,%r13,8),%xmm1
  movsd  (%r12,%r13,8),%xmm4
  add    $0x8,%r14
  movsd  -0x8(%r14),%xmm0
  movsd  0x8(%r14),%xmm5
  movsd  -0x8(%r15,%r13,8),%xmm3
  movsd  0x948(%r15,%r13,8),%xmm2
  mulsd  %xmm4,%xmm5
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm5,%xmm0
  movsd  -0x960(%r14),%xmm5
  addsd  %xmm2,%xmm1
  mulsd  (%r14),%xmm1
  mulsd  %xmm3,%xmm5
  addsd  %xmm5,%xmm0
  movsd  0x960(%r14),%xmm5
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm0
  subsd  %xmm1,%xmm0
  subsd  (%rbx,%r13,8),%xmm0
  add    $0x1,%r13
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x12b,%r13
  jne    L15
  add    $0x12c,%rbp
  add    $0x958,%r12
  add    $0x950,%r15
  add    $0x960,%rbx
  cmp    $0x15e64,%rbp
  jne    L18
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double compute_error(double *a_x, double *a_y, double *P, double *fn) {
  double error = 0.0;
  long indx, indx_rght, indx_frnt, indx_lft, indx_bck, i, j, indx_ax, indx_ay;
  for (i = 1; i < 300 - 1; i++) {
    for (j = 1; j < 300 - 1; j++) {
      indx = i * 300 + j;
      indx_rght = indx + 1;
      indx_frnt = indx + 300;
      indx_lft = indx - 1;
      indx_bck = indx - 300;
      indx_ax = (i - 1) * (300 - 1) + j - 1;
      indx_ay = (i - 1) * (300 - 2) + j - 1;
      error += fabs(a_x[indx_ax] * P[indx_lft] + a_x[indx_ax + 1] * P[indx_rght] + a_y[indx_ay] * P[indx_bck] + a_y[indx_ay + (300 - 2)] * P[indx_frnt] - (a_x[indx_ax] + a_x[indx_ax + 1] + a_y[indx_ay] + a_y[indx_ay + (300 - 2)]) * P[indx] - 1.0 * 1.0 * fn[indx]);
    }
  }
  return (error);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compute_error>:
  endbr64
  push   %r15
  pxor   %xmm7,%xmm7
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x12c,%ebp
  push   %rbx
  lea    0x960(%rcx),%rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movsd  %xmm7,(%rsp)
L19:
  mov    0x8(%rsp),%rax
  mov    $0x1,%r13d
  lea    (%rax,%rbp,8),%r14
  nopl   0x0(%rax)
L3:
  movsd  -0x8(%r12,%r13,8),%xmm1
  movsd  (%r12,%r13,8),%xmm4
  add    $0x8,%r14
  movsd  -0x8(%r14),%xmm0
  movsd  0x8(%r14),%xmm5
  movsd  -0x8(%r15,%r13,8),%xmm3
  movsd  0x948(%r15,%r13,8),%xmm2
  mulsd  %xmm4,%xmm5
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  addsd  %xmm5,%xmm0
  movsd  -0x960(%r14),%xmm5
  addsd  %xmm2,%xmm1
  mulsd  (%r14),%xmm1
  mulsd  %xmm3,%xmm5
  addsd  %xmm5,%xmm0
  movsd  0x960(%r14),%xmm5
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm0
  subsd  %xmm1,%xmm0
  subsd  (%rbx,%r13,8),%xmm0
  add    $0x1,%r13
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x12b,%r13
  jne    L3
  add    $0x12c,%rbp
  add    $0x958,%r12
  add    $0x950,%r15
  add    $0x960,%rbx
  cmp    $0x15e64,%rbp
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double compute_error(double *a_x, double *a_y, double *P, double *fn) {
  double error = 0.0;
  long indx, indx_rght, indx_frnt, indx_lft, indx_bck, i, j, indx_ax, indx_ay;
  for (i = 1; i < 300 - 1; i++) {
    for (j = 1; j < 300 - 1; j++) {
      indx = i * 300 + j;
      indx_rght = indx + 1;
      indx_frnt = indx + 300;
      indx_lft = indx - 1;
      indx_bck = indx - 300;
      indx_ax = (i - 1) * (300 - 1) + j - 1;
      indx_ay = (i - 1) * (300 - 2) + j - 1;
      error += fabs(a_x[indx_ax] * P[indx_lft] + a_x[indx_ax + 1] * P[indx_rght] + a_y[indx_ay] * P[indx_bck] + a_y[indx_ay + (300 - 2)] * P[indx_frnt] - (a_x[indx_ax] + a_x[indx_ax + 1] + a_y[indx_ay] + a_y[indx_ay + (300 - 2)]) * P[indx] - 1.0 * 1.0 * fn[indx]);
    }
  }
  return (error);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x12,%eax
  seta   %dl
  test   %dl,%dl
  jne    L5
  mov    $0x40144,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L5
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <parseStmt@plt>
  mov    %eax,-0x4(%rbp)
  nop
L5:
  nop
  leave
  ret
```

assistant: ```c
int parse(int state, int flags) {
  switch (state) {
  case 8:
  case 18:
  case 6:
  case 2:
    state = parseStmt(state, flags);
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse>:
  endbr64
  cmp    $0x12,%edi
  ja     L11
  mov    $0x40144,%eax
  bt     %rdi,%rax
  jb     L16
L11:
  ret
L16:
  sub    $0x8,%rsp
  call   <parseStmt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int parse(int state, int flags) {
  switch (state) {
  case 8:
  case 18:
  case 6:
  case 2:
    state = parseStmt(state, flags);
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<parse>:
  endbr64
  cmp    $0x12,%edi
  ja     L4
  mov    $0x40144,%eax
  bt     %rdi,%rax
  jb     L12
L4:
  ret
  nopl   (%rax)
L12:
  jmp    1050 <parseStmt@plt>
```

assistant: ```c
int parse(int state, int flags) {
  switch (state) {
  case 8:
  case 18:
  case 6:
  case 2:
    state = parseStmt(state, flags);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse>:
  endbr64
  cmp    $0x12,%edi
  ja     L10
  mov    $0x40144,%eax
  bt     %rdi,%rax
  jb     L6
L10:
  ret
  nopl   (%rax)
L6:
  jmp    1050 <parseStmt@plt>
```

assistant: ```c
int parse(int state, int flags) {
  switch (state) {
  case 8:
  case 18:
  case 6:
  case 2:
    state = parseStmt(state, flags);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xa000(%rsp),%r11
L35:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L35
  sub    $0x600,%rsp
  mov    %edi,-0xa5f4(%rbp)
  mov    %rsi,-0xa600(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa5ec(%rbp),%rdx
  lea    -0xa5e0(%rbp),%rcx
  lea    -0xa2a0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readArgs@plt>
  mov    %eax,-0xa5e4(%rbp)
  mov    -0xa5ec(%rbp),%edi
  lea    -0xa440(%rbp),%rcx
  lea    -0xa5e0(%rbp),%rdx
  lea    -0xa2a0(%rbp),%rsi
  mov    -0xa5e4(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <sumVeryLongIntegers@plt>
  mov    %eax,-0xa5e4(%rbp)
  mov    -0xa5e4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xa5e8(%rbp)
  jmp    L15
L2:
  mov    -0xa5e8(%rbp),%eax
  cltq
  mov    -0xa440(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0xa5e8(%rbp)
L15:
  cmpl   $0x0,-0xa5e8(%rbp)
  jns    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, maxLength, loop;
  int integersLengths[102];
  int veryLongIntegers[102][102];
  int result[102];
  n = readArgs(veryLongIntegers, integersLengths, &maxLength);
  n = sumVeryLongIntegers(n, veryLongIntegers, integersLengths, result, maxLength);
  for (loop = n - 1; loop >= 0; loop--)
    printf("%d", result[loop]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0x5f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa5e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rbp
  lea    0x350(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readArgs@plt>
  mov    %eax,%edi
  lea    0x1b0(%rsp),%rcx
  mov    0xc(%rsp),%r8d
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <sumVeryLongIntegers@plt>
  test   %eax,%eax
  jle    L6
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    0x1b0(%rsp,%rdx,1),%rbx
  lea    0x1ac(%rsp,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  shl    $0x2,%rax
  sub    %rax,%rbp
  lea    D5(%rip),%r12
L14:
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xa5e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0xa5f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, maxLength, loop;
  int integersLengths[102];
  int veryLongIntegers[102][102];
  int result[102];
  n = readArgs(veryLongIntegers, integersLengths, &maxLength);
  n = sumVeryLongIntegers(n, veryLongIntegers, integersLengths, result, maxLength);
  for (loop = n - 1; loop >= 0; loop--)
    printf("%d", result[loop]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L14:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L14
  sub    $0x5f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa5e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rdx
  lea    0x350(%rsp),%rbp
  mov    %r12,%rsi
  lea    0x1b0(%rsp),%rbx
  mov    %rbp,%rdi
  call   <readArgs@plt>
  mov    0xc(%rsp),%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <sumVeryLongIntegers@plt>
  test   %eax,%eax
  jle    L7
  movslq %eax,%rdx
  sub    $0x1,%eax
  lea    D4(%rip),%r12
  shl    $0x2,%rdx
  shl    $0x2,%rax
  lea    0x1ac(%rsp,%rdx,1),%rbp
  add    %rdx,%rbx
  sub    %rax,%rbp
  nopl   0x0(%rax)
L20:
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L20
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xa5e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xa5f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, maxLength, loop;
  int integersLengths[102];
  int veryLongIntegers[102][102];
  int result[102];
  n = readArgs(veryLongIntegers, integersLengths, &maxLength);
  n = sumVeryLongIntegers(n, veryLongIntegers, integersLengths, result, maxLength);
  for (loop = n - 1; loop >= 0; loop--)
    printf("%d", result[loop]);
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x5f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa5e8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rdx
  lea    0x350(%rsp),%rbp
  mov    %r12,%rsi
  lea    0x1b0(%rsp),%rbx
  mov    %rbp,%rdi
  call   <readArgs@plt>
  mov    0xc(%rsp),%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <sumVeryLongIntegers@plt>
  test   %eax,%eax
  jle    L3
  movslq %eax,%rdx
  sub    $0x1,%eax
  lea    D5(%rip),%r12
  shl    $0x2,%rdx
  shl    $0x2,%rax
  lea    0x1ac(%rsp,%rdx,1),%rbp
  add    %rdx,%rbx
  sub    %rax,%rbp
  nopl   0x0(%rax)
L33:
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L33
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xa5e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa5f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, maxLength, loop;
  int integersLengths[102];
  int veryLongIntegers[102][102];
  int result[102];
  n = readArgs(veryLongIntegers, integersLengths, &maxLength);
  n = sumVeryLongIntegers(n, veryLongIntegers, integersLengths, result, maxLength);
  for (loop = n - 1; loop >= 0; loop--)
    printf("%d", result[loop]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<showbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x7,-0xc(%rbp)
  jmp    L19
L20:
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movsbl -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L23
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L23:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  subl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x0,-0xc(%rbp)
  jns    L20
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string

tool: D20: 0

tool: D19: 1

tool: D16: 


assistant: ```c
void showbits(char n) {
  int i, k, andmask;
  for (i = 7; i >= 0; i--) {
    andmask = 1 << i;
    k = n & andmask;
    k == 0 ? printf("0") : printf("1");
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<showbits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x7,%ebx
  mov    $0x1,%r12d
  movsbl %dil,%ebp
  lea    D9(%rip),%r14
  lea    D13(%rip),%r13
  jmp    L24
L13:
  mov    %r14,%rdi
  call   <printf@plt>
L18:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L21
L24:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  test   %ebp,%eax
  jne    L13
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L18
L21:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D9: 1

tool: D13: 0

tool: D5: 


assistant: ```c
void showbits(char n) {
  int i, k, andmask;
  for (i = 7; i >= 0; i--) {
    andmask = 1 << i;
    k = n & andmask;
    k == 0 ? printf("0") : printf("1");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<showbits>:
  endbr64
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    $0x7,%ebx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jb     L38
L20:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  test   %ebp,%eax
  je     L28
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L20
L38:
  pop    %rbx
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string

tool: D18: 1

tool: D22: 0

tool: D17: 


assistant: ```c
void showbits(char n) {
  int i, k, andmask;
  for (i = 7; i >= 0; i--) {
    andmask = 1 << i;
    k = n & andmask;
    k == 0 ? printf("0") : printf("1");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<showbits>:
  endbr64
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    $0x7,%ebx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jb     L18
L3:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  test   %ebp,%eax
  je     L22
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L3
L18:
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D28: 1

tool: D22: 0

tool: D0: 


assistant: ```c
void showbits(char n) {
  int i, k, andmask;
  for (i = 7; i >= 0; i--) {
    andmask = 1 << i;
    k = n & andmask;
    k == 0 ? printf("0") : printf("1");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_SSIBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_SSIIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void SSIIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ASSERT(_SSIBaseValid(ui32Base));
  ui32Int = _SSIIntNumberGet(ui32Base);
  ASSERT(ui32Int != 0);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <_SSIBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    %rbx,%rdi
  call   <_SSIIntNumberGet@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <IntRegister@plt>
  mov    %rbx,%rdi
  call   <IntEnable@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SSIIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ASSERT(_SSIBaseValid(ui32Base));
  ui32Int = _SSIIntNumberGet(ui32Base);
  ASSERT(ui32Int != 0);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SSIIntRegister>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_SSIBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  call   <_SSIIntNumberGet@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <IntRegister@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ASSERT(_SSIBaseValid(ui32Base));
  ui32Int = _SSIIntNumberGet(ui32Base);
  ASSERT(ui32Int != 0);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SSIIntRegister>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_SSIBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  call   <_SSIIntNumberGet@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <ASSERT@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <IntRegister@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ASSERT(_SSIBaseValid(ui32Base));
  ui32Int = _SSIIntNumberGet(ui32Base);
  ASSERT(ui32Int != 0);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```