ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mpeg4_cpu>:
  endbr64
  push   %r13
  lea    0x400(%rdx),%r11
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
L14:
  mov    %r12,%r8
  mov    $0x10,%edi
L30:
  movss  (%r8),%xmm1
  lea    -0x10(%rdi),%r10d
  mov    %rbp,%r9
  mov    %rbx,%rsi
  nopl   0x0(%rax)
L31:
  mov    %r9,%rdx
  mov    %r10d,%eax
  xchg   %ax,%ax
L32:
  mov    %eax,%ecx
  add    $0x1,%eax
  add    $0x4,%rdx
  movss  (%rsi,%rcx,4),%xmm0
  mulss  -0x4(%rdx),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,(%r8)
  cmp    %eax,%edi
  jne    L32
  add    $0x40,%r9
  add    $0x4040,%rsi
  cmp    %r9,%r11
  jne    L31
  add    $0x1,%edi
  add    $0x4,%r8
  cmp    $0x1010,%edi
  jne    L30
  add    $0x1,%r13d
  add    $0x4040,%rbx
  add    $0x4000,%r12
  cmp    $0x1000,%r13d
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mpeg4_cpu(float result[4096][4096], float prev[4096 + 16][4096 + 16], float curr[16 * 16]) {
  unsigned int i;
  unsigned int j;
  unsigned int k;
  unsigned int l;
  for (i = 0; i < 4096; ++i)
    for (j = 0; j < 4096; ++j)
      for (k = 0; k < 16; ++k)
        for (l = 0; l < 16; ++l)
          result[i][j] += prev[i + k][j + l] * curr[k * 16 + l];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<terminate_string_at_first_slash_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L0:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *terminate_string_at_first_slash_n(char *str) {
  char *ptr;
  ptr = strchr(str, '\n');
  if (ptr != NULL) {
    *ptr = '\0';
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<terminate_string_at_first_slash_n>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *terminate_string_at_first_slash_n(char *str) {
  char *ptr;
  ptr = strchr(str, '\n');
  if (ptr != NULL) {
    *ptr = '\0';
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<terminate_string_at_first_slash_n>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *terminate_string_at_first_slash_n(char *str) {
  char *ptr;
  ptr = strchr(str, '\n');
  if (ptr != NULL) {
    *ptr = '\0';
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<terminate_string_at_first_slash_n>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
L3:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *terminate_string_at_first_slash_n(char *str) {
  char *ptr;
  ptr = strchr(str, '\n');
  if (ptr != NULL) {
    *ptr = '\0';
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strnew>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ft_memalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L19
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_memset@plt>
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *ft_strnew(size_t size) {
  void *str;
  str = ft_memalloc(size + 1);
  if (str == NULL)
    return (NULL);
  ft_memset(str, '\0', size + 1);
  return ((char *)str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strnew>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%rbp
  mov    %rbp,%rdi
  call   <ft_memalloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_memset@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strnew(size_t size) {
  void *str;
  str = ft_memalloc(size + 1);
  if (str == NULL)
    return (NULL);
  ft_memset(str, '\0', size + 1);
  return ((char *)str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strnew>:
  endbr64
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <ft_memalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <ft_memset@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strnew(size_t size) {
  void *str;
  str = ft_memalloc(size + 1);
  if (str == NULL)
    return (NULL);
  ft_memset(str, '\0', size + 1);
  return ((char *)str);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_strnew>:
  endbr64
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <ft_memalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <ft_memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strnew(size_t size) {
  void *str;
  str = ft_memalloc(size + 1);
  if (str == NULL)
    return (NULL);
  ft_memset(str, '\0', size + 1);
  return ((char *)str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<execvpe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int execvpe(const char *path, char *const argv[], char *const envp[]) {
  errno = EINVAL;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execvpe>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execvpe(const char *path, char *const argv[], char *const envp[]) {
  errno = EINVAL;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<execvpe>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execvpe(const char *path, char *const argv[], char *const envp[]) {
  errno = EINVAL;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execvpe>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execvpe(const char *path, char *const argv[], char *const envp[]) {
  errno = EINVAL;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<permuta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxIndex@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  je     L8
  mov    -0x30(%rbp),%edi
  mov    -0xc(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <switchCol@plt>
  jmp    L3
L8:
  nop
L3:
  leave
  ret
```

assistant: ```c
void permuta(double A[1000][1000], double sigma[1000], int ordem[1000], int index, int n, int m) {
  int i, j, k;
  double aux;
  double max = sigma[index];
  k = maxIndex(sigma, index, m);
  if (k == index)
    return;
  switchCol(A, ordem, index, k, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<permuta>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%r12
  mov    %ecx,%ebx
  mov    %r8d,%r13d
  mov    %r9d,%edx
  mov    %ecx,%esi
  call   <maxIndex@plt>
  cmp    %eax,%ebx
  je     L7
  mov    %r13d,%r8d
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <switchCol@plt>
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void permuta(double A[1000][1000], double sigma[1000], int ordem[1000], int index, int n, int m) {
  int i, j, k;
  double aux;
  double max = sigma[index];
  k = maxIndex(sigma, index, m);
  if (k == index)
    return;
  switchCol(A, ordem, index, k, n);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<permuta>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    %r9d,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %ecx,%esi
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <maxIndex@plt>
  cmp    %eax,%r12d
  je     L4
  add    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r12d,%edx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <switchCol@plt>
  nopl   0x0(%rax)
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void permuta(double A[1000][1000], double sigma[1000], int ordem[1000], int index, int n, int m) {
  int i, j, k;
  double aux;
  double max = sigma[index];
  k = maxIndex(sigma, index, m);
  if (k == index)
    return;
  switchCol(A, ordem, index, k, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<permuta>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    %r9d,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %ecx,%esi
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <maxIndex@plt>
  cmp    %eax,%r12d
  je     L1
  add    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r12d,%edx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <switchCol@plt>
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void permuta(double A[1000][1000], double sigma[1000], int ordem[1000], int index, int n, int m) {
  int i, j, k;
  double aux;
  double max = sigma[index];
  k = maxIndex(sigma, index, m);
  if (k == index)
    return;
  switchCol(A, ordem, index, k, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_gaussian_prior_integrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x78,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  %xmm5,-0x60(%rbp)
  movsd  %xmm6,-0x68(%rbp)
  movsd  %xmm7,-0x70(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  -0x68(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x70(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movq   D2(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x60(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x78(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x68(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x78(%rbp),%xmm0
  movsd  %xmm0,-0x78(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm3
  subsd  -0x50(%rbp),%xmm3
  movq   %xmm3,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %eax,%ebx
  mov    -0x58(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  lea    (%rax,%rax,1),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x78(%rbp),%xmm2
  subsd  %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double log_gaussian_prior_integrand(double u, double ak, double bk, double mulB, double siglB, double T, double B_best, double lB_best) {
  double B = exp(u) * B_best;
  double lB = u + lB_best;
  double ret = exp(-ak / (2 * T) * pow(B - B_best, 2) - pow(lB - mulB, 2) / (2 * pow(siglB, 2)));
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<log_gaussian_prior_integrand>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%r14
  movq   %xmm1,%r12
  movq   %xmm3,%rbx
  movq   %xmm4,%rbp
  movsd  %xmm5,0x8(%rsp)
  movsd  %xmm6,0x18(%rsp)
  movq   %xmm7,%r15
  call   <exp@plt>
  movq   %r14,%xmm2
  movq   %r15,%xmm7
  addsd  %xmm7,%xmm2
  movsd  %xmm2,0x10(%rsp)
  movq   %r12,%xmm4
  xorpd  D3(%rip),%xmm4
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  movapd %xmm4,%xmm5
  divsd  %xmm1,%xmm5
  movsd  %xmm5,0x8(%rsp)
  movsd  0x18(%rsp),%xmm6
  mulsd  %xmm6,%xmm0
  subsd  %xmm6,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm3
  mulsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movsd  0x10(%rsp),%xmm0
  movq   %rbx,%xmm2
  subsd  %xmm2,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  mov    $0x2,%edi
  movq   %rbp,%xmm0
  call   <pow@plt>
  lea    (%rax,%rax,1),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double log_gaussian_prior_integrand(double u, double ak, double bk, double mulB, double siglB, double T, double B_best, double lB_best) {
  double B = exp(u) * B_best;
  double lB = u + lB_best;
  double ret = exp(-ak / (2 * T) * pow(B - B_best, 2) - pow(lB - mulB, 2) / (2 * pow(siglB, 2)));
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_gaussian_prior_integrand>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm1,0x38(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm6,0x20(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <exp@plt>
  movsd  0x28(%rsp),%xmm5
  mov    $0x2,%edi
  movsd  0x38(%rsp),%xmm1
  xorpd  D5(%rip),%xmm1
  movsd  0x20(%rsp),%xmm6
  addsd  %xmm5,%xmm5
  movsd  0x18(%rsp),%xmm2
  addsd  0x8(%rsp),%xmm2
  mulsd  %xmm6,%xmm0
  divsd  %xmm5,%xmm1
  movsd  %xmm2,0x18(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  cvtsi2sd %eax,%xmm0
  subsd  0x10(%rsp),%xmm2
  mov    $0x2,%edi
  mulsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm4
  mov    $0x2,%edi
  mov    %eax,%ebx
  movapd %xmm4,%xmm0
  call   <pow@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  add    $0x40,%rsp
  lea    (%rax,%rax,1),%ecx
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %ecx
  cvtsi2sd %eax,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  jmp    1070 <exp@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double log_gaussian_prior_integrand(double u, double ak, double bk, double mulB, double siglB, double T, double B_best, double lB_best) {
  double B = exp(u) * B_best;
  double lB = u + lB_best;
  double ret = exp(-ak / (2 * T) * pow(B - B_best, 2) - pow(lB - mulB, 2) / (2 * pow(siglB, 2)));
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_gaussian_prior_integrand>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x30(%rsp)
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm1,0x38(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm6,0x20(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <exp@plt>
  movsd  0x28(%rsp),%xmm5
  mov    $0x2,%edi
  movsd  0x38(%rsp),%xmm1
  xorpd  D2(%rip),%xmm1
  movsd  0x20(%rsp),%xmm6
  addsd  %xmm5,%xmm5
  movsd  0x18(%rsp),%xmm2
  addsd  0x8(%rsp),%xmm2
  mulsd  %xmm6,%xmm0
  divsd  %xmm5,%xmm1
  movsd  %xmm2,0x18(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  cvtsi2sd %eax,%xmm0
  subsd  0x10(%rsp),%xmm2
  mov    $0x2,%edi
  mulsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm4
  mov    $0x2,%edi
  mov    %eax,%ebx
  movapd %xmm4,%xmm0
  call   <pow@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  add    $0x40,%rsp
  lea    (%rax,%rax,1),%ecx
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %ecx
  cvtsi2sd %eax,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  jmp    1070 <exp@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double log_gaussian_prior_integrand(double u, double ak, double bk, double mulB, double siglB, double T, double B_best, double lB_best) {
  double B = exp(u) * B_best;
  double lB = u + lB_best;
  double ret = exp(-ak / (2 * T) * pow(B - B_best, 2) - pow(lB - mulB, 2) / (2 * pow(siglB, 2)));
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x38(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D48(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D20(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D48
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D25
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D11
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D20
data_type: byte[8]

tool: {"D7": [0x23,0x0e,0x14,0x62,0xaa,0xff,0xef,0x3f]}

tool: {"D48": [0xe7,0x53,0x9d,0x89,0xe6,0x5d,0xec,0x3e]}

tool: {"D25": [0xcc,0xac,0xea,0xe4,0x86,0xf3,0xdf,0xbf]}

tool: {"D11": [0xdc,0x31,0xa8,0xfd,0xf7,0x7e,0x0c,0xbf]}

tool: {"D20": [0xee,0xec,0x64,0x01,0x12,0x44,0xa4,0x3f]}

assistant: ```c
double cos(double x) {
  const double a0 = 9.99959174689540053e-1;
  const double a1 = 1.35263438100583208e-5;
  const double a2 = -4.99238704253639242e-1;
  const double a3 = -5.43517523575486391e-5;
  const double a4 = 3.95818354322389060e-2;
  return a0 + x * (a1 + x * (a2 + x * (a3 + x * a4)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cos>:
  endbr64
  movapd %xmm0,%xmm1
  mulsd  D36(%rip),%xmm1
  subsd  D38(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D23(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D36
datatype: byte[8]
name: unpack_data
arguments: data_label: D38
datatype: byte[8]
name: unpack_data
arguments: data_label: D23
datatype: byte[8]
name: unpack_data
arguments: data_label: D9
datatype: byte[8]
name: unpack_data
arguments: data_label: D4
datatype: byte[8]

tool: {"D36": [0xee,0xec,0x64,0x01,0x12,0x44,0xa4,0x3f]}

tool: {"D38": [0xdc,0x31,0xa8,0xfd,0xf7,0x7e,0x0c,0x3f]}

tool: {"D23": [0xcc,0xac,0xea,0xe4,0x86,0xf3,0xdf,0x3f]}

tool: {"D9": [0xe7,0x53,0x9d,0x89,0xe6,0x5d,0xec,0x3e]}

tool: {"D4": [0x23,0x0e,0x14,0x62,0xaa,0xff,0xef,0x3f]}

assistant: ```c
double cos(double x) {
  const double a0 = 9.99959174689540053e-1;
  const double a1 = 1.35263438100583208e-5;
  const double a2 = -4.99238704253639242e-1;
  const double a3 = -5.43517523575486391e-5;
  const double a4 = 3.95818354322389060e-2;
  return a0 + x * (a1 + x * (a2 + x * (a3 + x * a4)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cos>:
  endbr64
  movsd  D37(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D35(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D41(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D26(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D45(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D37
type_guessed: byte[8]
name: retrieve_data
arguments: label: D35
type_guessed: byte[8]
name: retrieve_data
arguments: label: D41
type_guessed: byte[8]
name: retrieve_data
arguments: label: D26
type_guessed: byte[8]
name: retrieve_data
arguments: label: D45
type_guessed: byte[8]

tool: {"D37": [0xee,0xec,0x64,0x01,0x12,0x44,0xa4,0x3f]}

tool: {"D35": [0xdc,0x31,0xa8,0xfd,0xf7,0x7e,0x0c,0x3f]}

tool: {"D41": [0xcc,0xac,0xea,0xe4,0x86,0xf3,0xdf,0x3f]}

tool: {"D26": [0xe7,0x53,0x9d,0x89,0xe6,0x5d,0xec,0x3e]}

tool: {"D45": [0x23,0x0e,0x14,0x62,0xaa,0xff,0xef,0x3f]}

assistant: ```c
double cos(double x) {
  const double a0 = 9.99959174689540053e-1;
  const double a1 = 1.35263438100583208e-5;
  const double a2 = -4.99238704253639242e-1;
  const double a3 = -5.43517523575486391e-5;
  const double a4 = 3.95818354322389060e-2;
  return a0 + x * (a1 + x * (a2 + x * (a3 + x * a4)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cos>:
  endbr64
  movsd  D8(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D24(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D39(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D14(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D28(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D24
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D39
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D14
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D28
type_guessed: byte[8]

tool: {"D8": [0xee,0xec,0x64,0x01,0x12,0x44,0xa4,0x3f]}

tool: {"D24": [0xdc,0x31,0xa8,0xfd,0xf7,0x7e,0x0c,0x3f]}

tool: {"D39": [0xcc,0xac,0xea,0xe4,0x86,0xf3,0xdf,0x3f]}

tool: {"D14": [0xe7,0x53,0x9d,0x89,0xe6,0x5d,0xec,0x3e]}

tool: {"D28": [0x23,0x0e,0x14,0x62,0xaa,0xff,0xef,0x3f]}

assistant: ```c
double cos(double x) {
  const double a0 = 9.99959174689540053e-1;
  const double a1 = 1.35263438100583208e-5;
  const double a2 = -4.99238704253639242e-1;
  const double a3 = -5.43517523575486391e-5;
  const double a4 = 3.95818354322389060e-2;
  return a0 + x * (a1 + x * (a2 + x * (a3 + x * a4)));
}
```