ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0xffffffff,0xc(%rsp)
  call   <foo@plt>
  xor    %edi,%edi
  cmpl   $0x2,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long N = 2;
  int v[N][N];
  v[N - 1][N - 1] = -1;
  foo(N, v);
  assert(v[N - 1][N - 1] == 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_sclk_apll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe0100100,%eax
  mov    (%rax),%eax
  sar    $0x10,%eax
  and    $0x3ff,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0xe0100100,%eax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0x3f,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0xe0100100,%eax
  mov    (%rax),%eax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0xe0100200,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  mov    %edx,%esi
  shl    %cl,%esi
  mov    $0x16e3600,%eax
  cltd
  idiv   %esi
  imul   -0xc(%rbp),%eax
  jmp    L4
L8:
  mov    $0x16e3600,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t get_sclk_apll() {
  uint32_t mdiv, pdiv, sdiv;
  mdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3ff0000) >> 16;
  pdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3f00) >> 8;
  sdiv = (*((volatile uint32_t *)0xE0100100)) & 0x03;
  if ((*((volatile uint32_t *)0xE0100200)) & 0x01)
    return mdiv * ((24000000) / (pdiv << (sdiv - 1)));
  else
    return (24000000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_sclk_apll>:
  endbr64
  mov    $0xe0100100,%eax
  mov    (%rax),%esi
  mov    (%rax),%ecx
  mov    (%rax),%edi
  movabs 0xe0100200,%eax
  mov    $0x16e3600,%edx
  test   $0x1,%al
  je     L2
  sar    $0x8,%ecx
  mov    %ecx,%eax
  and    $0x3f,%eax
  and    $0x3,%edi
  lea    -0x1(%rdi),%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  mov    $0x16e3600,%eax
  cltd
  idiv   %ecx
  sar    $0x10,%esi
  and    $0x3ff,%esi
  imul   %esi,%eax
  mov    %eax,%edx
L2:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t get_sclk_apll() {
  uint32_t mdiv, pdiv, sdiv;
  mdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3ff0000) >> 16;
  pdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3f00) >> 8;
  sdiv = (*((volatile uint32_t *)0xE0100100)) & 0x03;
  if ((*((volatile uint32_t *)0xE0100200)) & 0x01)
    return mdiv * ((24000000) / (pdiv << (sdiv - 1)));
  else
    return (24000000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_sclk_apll>:
  endbr64
  mov    $0xe0100100,%eax
  mov    (%rax),%esi
  mov    (%rax),%ecx
  mov    (%rax),%edi
  mov    0x100(%rax),%edx
  mov    $0x16e3600,%eax
  and    $0x1,%edx
  je     L1
  sar    $0x8,%ecx
  and    $0x3,%edi
  sar    $0x10,%esi
  mov    %ecx,%edx
  lea    -0x1(%rdi),%ecx
  and    $0x3ff,%esi
  and    $0x3f,%edx
  shl    %cl,%edx
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  imul   %esi,%eax
L1:
  ret
```

assistant: ```c
uint32_t get_sclk_apll() {
  uint32_t mdiv, pdiv, sdiv;
  mdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3ff0000) >> 16;
  pdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3f00) >> 8;
  sdiv = (*((volatile uint32_t *)0xE0100100)) & 0x03;
  if ((*((volatile uint32_t *)0xE0100200)) & 0x01)
    return mdiv * ((24000000) / (pdiv << (sdiv - 1)));
  else
    return (24000000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_sclk_apll>:
  endbr64
  mov    $0xe0100100,%eax
  mov    (%rax),%esi
  mov    (%rax),%ecx
  mov    (%rax),%edi
  mov    0x100(%rax),%edx
  mov    $0x16e3600,%eax
  and    $0x1,%edx
  je     L5
  sar    $0x8,%ecx
  and    $0x3,%edi
  sar    $0x10,%esi
  mov    %ecx,%edx
  lea    -0x1(%rdi),%ecx
  and    $0x3ff,%esi
  and    $0x3f,%edx
  shl    %cl,%edx
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  imul   %esi,%eax
L5:
  ret
```

assistant: ```c
uint32_t get_sclk_apll() {
  uint32_t mdiv, pdiv, sdiv;
  mdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3ff0000) >> 16;
  pdiv = ((*((volatile uint32_t *)0xE0100100)) & 0x3f00) >> 8;
  sdiv = (*((volatile uint32_t *)0xE0100100)) & 0x03;
  if ((*((volatile uint32_t *)0xE0100200)) & 0x01)
    return mdiv * ((24000000) / (pdiv << (sdiv - 1)));
  else
    return (24000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hex_from_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jg     L26
  mov    $0xffffffff,%eax
  jmp    L29
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  subl   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x2,-0x10(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %02x

assistant: ```c
int hex_from_bin(int dst_bytes, char *dst, int src_bytes, unsigned char *src) {
  if (dst_bytes < src_bytes * 2 + 1)
    return -1;
  for (; src_bytes; --src_bytes, ++src, dst += 2)
    sprintf(dst, "%02x", (unsigned char)*src);
  *dst = 0;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_from_bin>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  cmp    %edi,%eax
  jge    L9
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  mov    %edx,%r15d
  mov    %rcx,%rbp
  test   %edx,%edx
  je     L12
  mov    %edx,%eax
  lea    (%rsi,%rax,2),%r13
  mov    %rsi,%rbx
  lea    D8(%rip),%r12
L21:
  movzbl 0x0(%rbp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x1,%rbp
  add    $0x2,%rbx
  cmp    %r13,%rbx
  jne    L21
  lea    -0x1(%r15),%eax
  lea    0x2(%r14,%rax,2),%r14
L12:
  movb   $0x0,(%r14)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: %02x

assistant: ```c
int hex_from_bin(int dst_bytes, char *dst, int src_bytes, unsigned char *src) {
  if (dst_bytes < src_bytes * 2 + 1)
    return -1;
  for (; src_bytes; --src_bytes, ++src, dst += 2)
    sprintf(dst, "%02x", (unsigned char)*src);
  *dst = 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex_from_bin>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  cmp    %edi,%eax
  jge    L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L33
  mov    %edx,%edx
  mov    %rcx,%rbp
  lea    D1(%rip),%r13
  lea    (%rsi,%rdx,2),%r12
  nopl   0x0(%rax)
L23:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r12,%rbx
  jne    L23
L32:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L33:
  mov    %rsi,%r12
  jmp    L32
L4:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: %02x

assistant: ```c
int hex_from_bin(int dst_bytes, char *dst, int src_bytes, unsigned char *src) {
  if (dst_bytes < src_bytes * 2 + 1)
    return -1;
  for (; src_bytes; --src_bytes, ++src, dst += 2)
    sprintf(dst, "%02x", (unsigned char)*src);
  *dst = 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex_from_bin>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  cmp    %edi,%eax
  jge    L37
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L29
  mov    %edx,%edx
  mov    %rcx,%rbp
  lea    D1(%rip),%r13
  lea    (%rsi,%rdx,2),%r12
  nopl   0x0(%rax)
L0:
  movzbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x2,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r12,%rbx
  jne    L0
L4:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L29:
  mov    %rsi,%r12
  jmp    L4
L37:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: %02x

assistant: ```c
int hex_from_bin(int dst_bytes, char *dst, int src_bytes, unsigned char *src) {
  if (dst_bytes < src_bytes * 2 + 1)
    return -1;
  for (; src_bytes; --src_bytes, ++src, dst += 2)
    sprintf(dst, "%02x", (unsigned char)*src);
  *dst = 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Cyc_Parse_join_assn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L30
  cmpq   $0x0,-0x30(%rbp)
  je     L52
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Cyc_Absyn_and_exp@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  jmp    L36
L30:
  nop
  jmp    L14
L52:
  nop
L14:
  cmpq   $0x0,-0x28(%rbp)
  je     L57
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  jmp    L36
L57:
  nop
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
struct Cyc_Absyn_Exp *Cyc_Parse_join_assn(struct Cyc_Absyn_Exp *e1, struct Cyc_Absyn_Exp *e2) {
  struct Cyc_Absyn_Exp *_T0;
  struct Cyc_Absyn_Exp *_T1;
  struct Cyc_Absyn_Exp *_T2;
  if (e1 == 0)
    goto _TL192;
  if (e2 == 0)
    goto _TL192;
  _T0 = Cyc_Absyn_and_exp(e1, e2, 0U);
  return _T0;
_TL192:
  if (e1 == 0)
    goto _TL194;
  _T1 = e1;
  return _T1;
_TL194:
  _T2 = e2;
  return _T2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_Parse_join_assn>:
  endbr64
  test   %rsi,%rsi
  je     L8
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  mov    $0x0,%edx
  call   <Cyc_Absyn_and_exp@plt>
  add    $0x8,%rsp
  ret
L8:
  test   %rdi,%rdi
  mov    %rsi,%rax
  cmovne %rdi,%rax
  ret
```

assistant: ```c
struct Cyc_Absyn_Exp *Cyc_Parse_join_assn(struct Cyc_Absyn_Exp *e1, struct Cyc_Absyn_Exp *e2) {
  struct Cyc_Absyn_Exp *_T0;
  struct Cyc_Absyn_Exp *_T1;
  struct Cyc_Absyn_Exp *_T2;
  if (e1 == 0)
    goto _TL192;
  if (e2 == 0)
    goto _TL192;
  _T0 = Cyc_Absyn_and_exp(e1, e2, 0U);
  return _T0;
_TL192:
  if (e1 == 0)
    goto _TL194;
  _T1 = e1;
  return _T1;
_TL194:
  _T2 = e2;
  return _T2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Cyc_Parse_join_assn>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L4
  xor    %edx,%edx
  jmp    1050 <Cyc_Absyn_and_exp@plt>
  nopl   (%rax)
L4:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L10:
  mov    %rsi,%rax
  ret
```

assistant: ```c
struct Cyc_Absyn_Exp *Cyc_Parse_join_assn(struct Cyc_Absyn_Exp *e1, struct Cyc_Absyn_Exp *e2) {
  struct Cyc_Absyn_Exp *_T0;
  struct Cyc_Absyn_Exp *_T1;
  struct Cyc_Absyn_Exp *_T2;
  if (e1 == 0)
    goto _TL192;
  if (e2 == 0)
    goto _TL192;
  _T0 = Cyc_Absyn_and_exp(e1, e2, 0U);
  return _T0;
_TL192:
  if (e1 == 0)
    goto _TL194;
  _T1 = e1;
  return _T1;
_TL194:
  _T2 = e2;
  return _T2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Cyc_Parse_join_assn>:
  endbr64
  test   %rdi,%rdi
  je     L15
  test   %rsi,%rsi
  je     L18
  xor    %edx,%edx
  jmp    1050 <Cyc_Absyn_and_exp@plt>
  nopl   (%rax)
L18:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L15:
  mov    %rsi,%rax
  ret
```

assistant: ```c
struct Cyc_Absyn_Exp *Cyc_Parse_join_assn(struct Cyc_Absyn_Exp *e1, struct Cyc_Absyn_Exp *e2) {
  struct Cyc_Absyn_Exp *_T0;
  struct Cyc_Absyn_Exp *_T1;
  struct Cyc_Absyn_Exp *_T2;
  if (e1 == 0)
    goto _TL192;
  if (e2 == 0)
    goto _TL192;
  _T0 = Cyc_Absyn_and_exp(e1, e2, 0U);
  return _T0;
_TL192:
  if (e1 == 0)
    goto _TL194;
  _T1 = e1;
  return _T1;
_TL194:
  _T2 = e2;
  return _T2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L34
L58:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L51
L56:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L56
L2:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    -0x1c(%rbp),%eax
  jmp    L41
L32:
  subl   $0x1,-0x1c(%rbp)
L34:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L58
  mov    $0xffffffff,%eax
L41:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  i = j = k = 0;
  for (i = strlen(s) - strlen(t); i >= 0; i--) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strindex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  js     L9
  movzbl 0x0(%rbp),%edi
  movslq %eax,%rdx
  mov    %rbp,%rsi
  sub    %rdx,%rsi
  jmp    L57
L47:
  test   %cl,%cl
  je     L11
  sub    $0x1,%eax
  add    $0x1,%rsi
  cmp    $0xffffffff,%eax
  je     L11
L57:
  test   %dil,%dil
  je     L11
  mov    %rbp,%rdx
  sub    %rsi,%rdx
  mov    %edi,%ecx
L49:
  cmp    %cl,(%rbx,%rdx,1)
  jne    L47
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L49
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  i = j = k = 0;
  for (i = strlen(s) - strlen(t); i >= 0; i--) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  js     L23
  movslq %eax,%rdx
  mov    %r12,%rdi
  movzbl (%r12),%r8d
  sub    %rdx,%rdi
  nopl   (%rax)
L40:
  test   %r8b,%r8b
  je     L62
  mov    %r12,%rdx
  mov    %r8d,%ecx
  sub    %rdi,%rdx
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  test   %cl,%cl
  je     L62
L64:
  cmp    %cl,(%rbx,%rdx,1)
  je     L17
  sub    $0x1,%eax
  add    $0x1,%rdi
  cmp    $0xffffffff,%eax
  jne    L40
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L62
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  i = j = k = 0;
  for (i = strlen(s) - strlen(t); i >= 0; i--) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strindex>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  js     L63
  movslq %eax,%rdx
  mov    %r12,%rdi
  movzbl (%r12),%r8d
  sub    %rdx,%rdi
  nopl   (%rax)
L33:
  test   %r8b,%r8b
  je     L21
  mov    %r12,%rdx
  mov    %r8d,%ecx
  sub    %rdi,%rdx
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  test   %cl,%cl
  je     L21
L67:
  cmp    %cl,(%rbx,%rdx,1)
  je     L43
  sub    $0x1,%eax
  add    $0x1,%rdi
  cmp    $0xffffffff,%eax
  jne    L33
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L63:
  mov    $0xffffffff,%eax
  jmp    L21
```

assistant: ```c
int strindex(char *s, char *t) {
  int i, j, k;
  i = j = k = 0;
  for (i = strlen(s) - strlen(t); i >= 0; i--) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (t[k] == '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MApi_MOD_PVDD_Power_Setting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <MHal_MOD_PVDD_Power_Setting@plt>
  nop
  leave
  ret
```

assistant: ```c
void MApi_MOD_PVDD_Power_Setting(unsigned char bIs2p5) {
  ;
  MHal_MOD_PVDD_Power_Setting(bIs2p5);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MApi_MOD_PVDD_Power_Setting>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  call   <MHal_MOD_PVDD_Power_Setting@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MApi_MOD_PVDD_Power_Setting(unsigned char bIs2p5) {
  ;
  MHal_MOD_PVDD_Power_Setting(bIs2p5);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MApi_MOD_PVDD_Power_Setting>:
  endbr64
  movzbl %dil,%edi
  jmp    1050 <MHal_MOD_PVDD_Power_Setting@plt>
```

assistant: ```c
void MApi_MOD_PVDD_Power_Setting(unsigned char bIs2p5) {
  ;
  MHal_MOD_PVDD_Power_Setting(bIs2p5);
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MApi_MOD_PVDD_Power_Setting>:
  endbr64
  movzbl %dil,%edi
  jmp    1050 <MHal_MOD_PVDD_Power_Setting@plt>
```

assistant: ```c
void MApi_MOD_PVDD_Power_Setting(unsigned char bIs2p5) {
  ;
  MHal_MOD_PVDD_Power_Setting(bIs2p5);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xfffffc01,-0x4(%rbp)
  jl     L24
  cmpl   $0x0,-0x4(%rbp)
  jns    L24
  cmpl   $0xfffffc01,-0x8(%rbp)
  jl     L24
  cmpl   $0x0,-0x8(%rbp)
  jns    L24
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L14
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L24
L14:
  mov    $0x4d2,%eax
  jmp    L11
L24:
  mov    -0x4(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int f(int x, int y) {
  if (x > -1024 && x < 0 && y > -1024 && y < 0) {
    x = x ^ y;
    if (x < 0 || x > 1023)
      return 1234;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  mov    %edi,%eax
  cmp    $0xfffffc01,%edi
  jb     L8
  mov    %edi,%edx
  xor    %esi,%edx
  cmp    $0xfffffc01,%esi
  cmovae %edx,%eax
L8:
  ret
```

assistant: ```c
int f(int x, int y) {
  if (x > -1024 && x < 0 && y > -1024 && y < 0) {
    x = x ^ y;
    if (x < 0 || x > 1023)
      return 1234;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  cmp    $0xfffffc01,%edi
  jb     L7
  mov    %edi,%edx
  xor    %esi,%edx
  cmp    $0xfffffc01,%esi
  cmovae %edx,%eax
L7:
  ret
```

assistant: ```c
int f(int x, int y) {
  if (x > -1024 && x < 0 && y > -1024 && y < 0) {
    x = x ^ y;
    if (x < 0 || x > 1023)
      return 1234;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  cmp    $0xfffffc01,%edi
  jb     L1
  mov    %edi,%edx
  xor    %esi,%edx
  cmp    $0xfffffc01,%esi
  cmovae %edx,%eax
L1:
  ret
```

assistant: ```c
int f(int x, int y) {
  if (x > -1024 && x < 0 && y > -1024 && y < 0) {
    x = x ^ y;
    if (x < 0 || x > 1023)
      return 1234;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeInvalidParentheses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L49
L19:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L76
  addl   $0x1,-0x2c(%rbp)
  jmp    L66
L76:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L66
  cmpl   $0x0,-0x2c(%rbp)
  je     L37
  subl   $0x1,-0x2c(%rbp)
  jmp    L66
L37:
  addl   $0x1,-0x28(%rbp)
L66:
  addl   $0x1,-0x24(%rbp)
L49:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  mov    -0x28(%rbp),%edi
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x38(%rbp),%rax
  push   -0x40(%rbp)
  lea    -0x18(%rbp),%rcx
  push   %rcx
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  push   -0x10(%rbp)
  mov    $0x0,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <traverse@plt>
  add    $0x20,%rsp
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

assistant: ```c
char **removeInvalidParentheses(char *s, int *returnSize) {
  char **arr = (char **)malloc(sizeof(char *));
  *returnSize = 0;
  int left = 0, right = 0;
  for (int i = 0; s[i]; i++) {
    if (s[i] == '(')
      left++;
    else if (s[i] == ')') {
      if (left)
        left--;
      else
        right++;
    }
  }
  int len = strlen(s);
  char *stack = (char *)malloc(sizeof(char) * len);
  int top = -1;
  traverse(s, len, 0, left, right, 0, stack, top, &arr, returnSize);
  return arr;
}
```