ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<duplicateArray>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  movl   $0x0,0x38(%rsp)
  lea    (%rdi,%rax,4),%r9
  movaps %xmm0,(%rsp)
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  cmp    %r9,%rdi
  jae    L44
  mov    (%rdi),%eax
  xor    %ecx,%ecx
  nop
L71:
  mov    %eax,%edx
  mov    0x4(%rdi),%eax
  cmp    %edx,%eax
  je     L64
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %edx,(%rsp,%r8,4)
L64:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jb     L71
L44:
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  mov    %rsp,%rbx
  lea    D3(%rip),%r12
  lea    0x4(%rsp,%rax,4),%rbp
  jmp    L54
  nopl   0x0(%rax)
L74:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L17
L54:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L74
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L54
L17:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: %d  

assistant: ```c
void duplicateArray(int *array, int count) {
  int resultArray[15] = {0};
  int index = 0;
  for (int *p = array; p < array + count; p++) {
    if (*(p) != *(p + 1)) {
      resultArray[index] = *p;
      index++;
    }
  }
  for (int i = 0; i < count; i++) {
    if (resultArray[i] != 0) {
      printf("%d  ", resultArray[i]);
    }
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<kernels_noreturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <abort@plt>
```

assistant: ```c
int kernels_noreturn(void) {
#pragma acc kernels
  __builtin_abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kernels_noreturn>:
  endbr64
  sub    $0x8,%rsp
  call   <abort@plt>
```

assistant: ```c
int kernels_noreturn(void) {
#pragma acc kernels
  __builtin_abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernels_noreturn>:
  endbr64
  push   %rax
  call   <abort@plt>
```

assistant: ```c
int kernels_noreturn(void) {
#pragma acc kernels
  __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kernels_noreturn>:
  endbr64
  push   %rax
  call   <abort@plt>
```

assistant: ```c
int kernels_noreturn(void) {
#pragma acc kernels
  __builtin_abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum_pairs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jl     L17
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sum_pairs(int *A, int N, int *B) {
  int i;
  for (i = 0; i < N / 2; i++)
    *(B + i) = *(A + 2 * i) + *(A + 2 * i + 1);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum_pairs>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L14
  mov    $0x0,%eax
L16:
  mov    0x4(%rdi,%rax,8),%ecx
  add    (%rdi,%rax,8),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L16
L14:
  ret
```

assistant: ```c
void sum_pairs(int *A, int N, int *B) {
  int i;
  for (i = 0; i < N / 2; i++)
    *(B + i) = *(A + 2 * i) + *(A + 2 * i + 1);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum_pairs>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L18
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x4(%rdi,%rax,8),%ecx
  add    (%rdi,%rax,8),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L12
L18:
  ret
```

assistant: ```c
void sum_pairs(int *A, int N, int *B) {
  int i;
  for (i = 0; i < N / 2; i++)
    *(B + i) = *(A + 2 * i) + *(A + 2 * i + 1);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum_pairs>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edi
  shr    $0x1f,%edi
  add    %esi,%edi
  sar    %edi
  cmp    $0x1,%esi
  jle    L37
  mov    %edi,%r8d
  lea    (%rdx,%r8,4),%rax
  lea    (%rcx,%r8,8),%r8
  cmp    %rax,%rcx
  setae  %al
  cmp    %r8,%rdx
  setae  %r8b
  or     %r8b,%al
  je     L31
  cmp    $0x7,%esi
  jle    L31
  mov    %edi,%esi
  xor    %eax,%eax
  shr    $0x2,%esi
  shl    $0x4,%rsi
  xchg   %ax,%ax
L55:
  movdqu (%rcx,%rax,2),%xmm0
  movdqu 0x10(%rcx,%rax,2),%xmm2
  movdqa %xmm0,%xmm1
  shufps $0xdd,%xmm2,%xmm0
  shufps $0x88,%xmm2,%xmm1
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L55
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L37
  lea    (%rax,%rax,1),%esi
  push   %rbx
  movslq %eax,%rbx
  movslq %esi,%r8
  lea    0x0(,%rbx,4),%r10
  mov    (%rcx,%r8,4),%r9d
  add    0x4(%rcx,%r8,4),%r9d
  lea    0x0(,%r8,4),%r11
  mov    %r9d,(%rdx,%rbx,4)
  lea    0x1(%rax),%r9d
  cmp    %r9d,%edi
  jle    L78
  add    $0x3,%esi
  mov    0x8(%rcx,%r11,1),%r9d
  add    $0x2,%eax
  movslq %esi,%rsi
  add    (%rcx,%rsi,4),%r9d
  mov    %r9d,0x4(%rdx,%r10,1)
  cmp    %eax,%edi
  jle    L78
  mov    0x10(%rcx,%r11,1),%eax
  add    0x14(%rcx,%r8,4),%eax
  mov    %eax,0x8(%rdx,%r10,1)
L78:
  pop    %rbx
  ret
  nop
L37:
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x4(%rcx,%rax,8),%esi
  add    (%rcx,%rax,8),%esi
  mov    %esi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L36
  ret
```

assistant: ```c
void sum_pairs(int *A, int N, int *B) {
  int i;
  for (i = 0; i < N / 2; i++)
    *(B + i) = *(A + 2 * i) + *(A + 2 * i + 1);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IcsExistFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L18
L5:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: rb

assistant: ```c
int IcsExistFile(char const *filename) {
  FILE *fp;
  if ((fp = fopen(filename, "rb")) != NULL) {
    fclose(fp);
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IcsExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L3
  call   <fclose@plt>
  mov    $0x1,%eax
L3:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: rb

assistant: ```c
int IcsExistFile(char const *filename) {
  FILE *fp;
  if ((fp = fopen(filename, "rb")) != NULL) {
    fclose(fp);
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<IcsExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  call   <fclose@plt>
  mov    $0x1,%eax
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: rb

assistant: ```c
int IcsExistFile(char const *filename) {
  FILE *fp;
  if ((fp = fopen(filename, "rb")) != NULL) {
    fclose(fp);
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IcsExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  call   <fclose@plt>
  mov    $0x1,%eax
L3:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: rb

assistant: ```c
int IcsExistFile(char const *filename) {
  FILE *fp;
  if ((fp = fopen(filename, "rb")) != NULL) {
    fclose(fp);
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply160>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L37
L19:
  movl   $0x0,-0x3c(%rbp)
  jmp    L31
L32:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L31:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L32
  addl   $0x1,-0x40(%rbp)
L37:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L19
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply160(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply160>:
  endbr64
  test   %edi,%edi
  jle    L26
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L24:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L29:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L29
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L24
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  ret
```

assistant: ```c
void multiply160(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply160>:
  endbr64
  test   %edi,%edi
  jle    L0
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L14
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L11
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void multiply160(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply160>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L18
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L87:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L17
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L17
  nopl   0x0(%rax)
L48:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L48
  cmp    -0x24(%rsp),%r11d
  je     L69
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L69
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L69
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L69:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L87
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L94:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L94
  mov    -0x18(%rsp),%r8
  jmp    L69
```

assistant: ```c
void multiply160(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L41
  mov    $0x0,%eax
  jmp    L11
L41:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x8,%edx
  jne    L29
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x8,%edx
  jne    L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <count8>
  add    $0x2,%eax
  jmp    L11
L29:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x8,%edx
  jne    L17
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <count8>
  add    $0x1,%eax
  jmp    L11
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <count8>
L11:
  leave
  ret
```

assistant: ```c
int count8(int n) {
  if (n == 0)
    return 0;
  if ((n / 10) % 10 == 8 && n % 10 == 8)
    return 2 + count8(n / 10);
  if (n % 10 == 8)
    return 1 + count8(n / 10);
  return count8(n / 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count8>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L22
  sub    $0x8,%rsp
  mov    %edi,%edx
  movslq %edi,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edi,%ecx
  sub    %eax,%ecx
  cmp    $0x8,%ecx
  je     L33
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  cmp    $0x8,%edx
  je     L56
L9:
  call   <count8>
L28:
  add    $0x8,%rsp
  ret
L33:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  cmp    $0x8,%edx
  jne    L9
  call   <count8>
  add    $0x2,%eax
  jmp    L28
L56:
  call   <count8>
  add    $0x1,%eax
  jmp    L28
L22:
  ret
```

assistant: ```c
int count8(int n) {
  if (n == 0)
    return 0;
  if ((n / 10) % 10 == 8 && n % 10 == 8)
    return 2 + count8(n / 10);
  if (n % 10 == 8)
    return 1 + count8(n / 10);
  return count8(n / 10);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<count8>:
  endbr64
  mov    %edi,%ecx
  xor    %r8d,%r8d
  test   %edi,%edi
  jne    L48
  jmp    L31
  nop
L35:
  xor    %edx,%edx
  cmp    $0x8,%esi
  sete   %dl
  add    %edx,%r8d
  test   %eax,%eax
  je     L31
L48:
  movslq %ecx,%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  movslq %eax,%rdx
  lea    (%rax,%rax,4),%edi
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  add    %edi,%edi
  sub    %edi,%esi
  mov    %eax,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  mov    %eax,%edi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  cmp    $0x8,%edi
  jne    L35
  lea    0x2(%r8),%edx
  cmp    $0x8,%esi
  cmove  %edx,%r8d
  test   %eax,%eax
  jne    L48
L31:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count8(int n) {
  if (n == 0)
    return 0;
  if ((n / 10) % 10 == 8 && n % 10 == 8)
    return 2 + count8(n / 10);
  if (n % 10 == 8)
    return 1 + count8(n / 10);
  return count8(n / 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count8>:
  endbr64
  mov    %edi,%ecx
  xor    %r8d,%r8d
  test   %edi,%edi
  jne    L22
  jmp    L17
  nop
L0:
  xor    %edx,%edx
  cmp    $0x8,%esi
  sete   %dl
  add    %edx,%r8d
  test   %eax,%eax
  je     L17
L22:
  movslq %ecx,%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  movslq %eax,%rdx
  lea    (%rax,%rax,4),%edi
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  add    %edi,%edi
  sub    %edi,%esi
  mov    %eax,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  mov    %eax,%edi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  cmp    $0x8,%edi
  jne    L0
  lea    0x2(%r8),%edx
  cmp    $0x8,%esi
  cmove  %edx,%r8d
  test   %eax,%eax
  jne    L22
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count8(int n) {
  if (n == 0)
    return 0;
  if ((n / 10) % 10 == 8 && n % 10 == 8)
    return 2 + count8(n / 10);
  if (n % 10 == 8)
    return 1 + count8(n / 10);
  return count8(n / 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<barRead32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  or     -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t barRead32(uint32_t bar, uint32_t offset) {
  volatile uint32_t *pReg = (volatile uint32_t *)(bar | (offset & 0xFF));
  return (*pReg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<barRead32>:
  endbr64
  movzbl %sil,%esi
  or     %edi,%esi
  movslq %esi,%rsi
  mov    (%rsi),%eax
  ret
```

assistant: ```c
uint32_t barRead32(uint32_t bar, uint32_t offset) {
  volatile uint32_t *pReg = (volatile uint32_t *)(bar | (offset & 0xFF));
  return (*pReg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<barRead32>:
  endbr64
  movzbl %sil,%esi
  or     %edi,%esi
  movslq %esi,%rsi
  mov    (%rsi),%eax
  ret
```

assistant: ```c
uint32_t barRead32(uint32_t bar, uint32_t offset) {
  volatile uint32_t *pReg = (volatile uint32_t *)(bar | (offset & 0xFF));
  return (*pReg);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<barRead32>:
  endbr64
  movzbl %sil,%esi
  or     %edi,%esi
  movslq %esi,%rsi
  mov    (%rsi),%eax
  ret
```

assistant: ```c
uint32_t barRead32(uint32_t bar, uint32_t offset) {
  volatile uint32_t *pReg = (volatile uint32_t *)(bar | (offset & 0xFF));
  return (*pReg);
}
```
user: What is the c source code of the assembly code below:

```asm
<internal_vw_scanw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vw_scanw@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int internal_vw_scanw(WINDOW *win, char *arg1, ...) {
  va_list va;
  int rv;
  va_start(va, arg1);
  rv = vw_scanw(win, arg1, va);
  va_end(va);
  return rv;
}
```