ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_signalfd>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigfillset@plt>
  mov    D15(%rip),%rax
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  or     (%rax),%edx
  call   <signalfd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_signalfd() {
  sigset_t mask;
  sigfillset(&mask);
  return signalfd(-1, &mask, SFD_CLOEXEC | SFD_NONBLOCK);
}
```
user: What is the c source code of the assembly code below:

```asm
<create_signalfd>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigfillset@plt>
  mov    D16(%rip),%rax
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  or     (%rax),%edx
  call   <signalfd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_signalfd() {
  sigset_t mask;
  sigfillset(&mask);
  return signalfd(-1, &mask, SFD_CLOEXEC | SFD_NONBLOCK);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<long2net>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3,%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
  shrq   $0x8,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
  shrq   $0x8,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
  shrq   $0x8,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void long2net(unsigned long int l, unsigned char **bufp) {
  *(*bufp + 3) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 2) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 1) = (unsigned char)l;
  l >>= 8;
  **bufp = (unsigned char)l;
  *bufp += 4;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<long2net>:
  endbr64
  mov    %rdi,%rax
  mov    (%rsi),%rdx
  mov    %dil,0x3(%rdx)
  mov    (%rsi),%rdx
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdx)
  mov    (%rsi),%rdx
  mov    %rdi,%rcx
  shr    $0x10,%rcx
  mov    %cl,0x1(%rdx)
  mov    (%rsi),%rdx
  shr    $0x18,%rax
  mov    %al,(%rdx)
  addq   $0x4,(%rsi)
  ret
```

assistant: ```c
void long2net(unsigned long int l, unsigned char **bufp) {
  *(*bufp + 3) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 2) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 1) = (unsigned char)l;
  l >>= 8;
  **bufp = (unsigned char)l;
  *bufp += 4;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<long2net>:
  endbr64
  mov    (%rsi),%rdx
  mov    %rdi,%rax
  mov    %rdi,%rcx
  shr    $0x10,%rcx
  mov    %dil,0x3(%rdx)
  mov    (%rsi),%rdx
  mov    %ah,0x2(%rdx)
  mov    (%rsi),%rdx
  shr    $0x18,%rax
  mov    %cl,0x1(%rdx)
  mov    (%rsi),%rdx
  mov    %al,(%rdx)
  addq   $0x4,(%rsi)
  ret
```

assistant: ```c
void long2net(unsigned long int l, unsigned char **bufp) {
  *(*bufp + 3) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 2) = (unsigned char)l;
  l >>= 8;
  *(*bufp + 1) = (unsigned char)l;
  l >>= 8;
  **bufp = (unsigned char)l;
  *bufp += 4;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L42:
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  cmpl   $0x5,-0x4(%rbp)
  jne    L49
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L3:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L49:
  addl   $0x5,-0xc(%rbp)
L31:
  cmpl   $0x13,-0xc(%rbp)
  jle    L42
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D21
type_infered: string

tool: D6: 1


tool: D4: 2


tool: D21: 3


assistant: ```c
int main() {
  int i = 0, j = 0, k = 0;
  while (j < 20) {
    if (i == 0) {
      if (k == 5) {
        printf("1\n");
        goto label;
      }
    } else {
      printf("2\n");
    label:
      printf("3\n");
      j++;
    }
    j += 5;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i = 0, j = 0, k = 0;
  while (j < 20) {
    if (i == 0) {
      if (k == 5) {
        printf("1\n");
        goto label;
      }
    } else {
      printf("2\n");
    label:
      printf("3\n");
      j++;
    }
    j += 5;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 0, j = 0, k = 0;
  while (j < 20) {
    if (i == 0) {
      if (k == 5) {
        printf("1\n");
        goto label;
      }
    } else {
      printf("2\n");
    label:
      printf("3\n");
      j++;
    }
    j += 5;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 0, j = 0, k = 0;
  while (j < 20) {
    if (i == 0) {
      if (k == 5) {
        printf("1\n");
        goto label;
      }
    } else {
      printf("2\n");
    label:
      printf("3\n");
      j++;
    }
    j += 5;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_files>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    $0x1,%eax
  jmp    L54
L17:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  je     L14
  mov    $0x1,%eax
  jmp    L54
L14:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    $0x1,%eax
  jmp    L54
L27:
  mov    $0x0,%eax
L54:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D27: /tmp/new_login

tool: D21: /tmp/new_config

tool: D19: /tmp/new_network

assistant: ```c
int check_files() {
  if (check_file("/tmp/new_login") != -1)
    return 1;
  if (check_file("/tmp/new_config") != -1)
    return 1;
  if (check_file("/tmp/new_network") != -1)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_files>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <check_file@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0xffffffff,%edx
  je     L4
L17:
  add    $0x8,%rsp
  ret
L4:
  lea    D8(%rip),%rdi
  call   <check_file@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0xffffffff,%edx
  jne    L17
  lea    D9(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D19: /tmp/new_login

tool: D8: /tmp/new_config

tool: D9: /tmp/new_network

assistant: ```c
int check_files() {
  if (check_file("/tmp/new_login") != -1)
    return 1;
  if (check_file("/tmp/new_config") != -1)
    return 1;
  if (check_file("/tmp/new_network") != -1)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_files>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  je     L1
L9:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D21(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  lea    D23(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D23
type: string

tool: D7: /tmp/new_login

tool: D21: /tmp/new_config

tool: D23: /tmp/new_network

assistant: ```c
int check_files() {
  if (check_file("/tmp/new_login") != -1)
    return 1;
  if (check_file("/tmp/new_config") != -1)
    return 1;
  if (check_file("/tmp/new_network") != -1)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_files>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  je     L14
L6:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  lea    D15(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  lea    D5(%rip),%rdi
  call   <check_file@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D2: /tmp/new_login

tool: D15: /tmp/new_config

tool: D5: /tmp/new_network

assistant: ```c
int check_files() {
  if (check_file("/tmp/new_login") != -1)
    return 1;
  if (check_file("/tmp/new_config") != -1)
    return 1;
  if (check_file("/tmp/new_network") != -1)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L9
  mov    -0x8(%rbp),%rax
  movl   $0x2,(%rax)
L9:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(volatile int *a, int *b) {
  *a = 1;
  if (*b)
    *a = 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  movl   $0x1,(%rdi)
  cmpl   $0x0,(%rsi)
  je     L1
  movl   $0x2,(%rdi)
L1:
  ret
```

assistant: ```c
void foo(volatile int *a, int *b) {
  *a = 1;
  if (*b)
    *a = 2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  movl   $0x1,(%rdi)
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L3
  movl   $0x2,(%rdi)
L3:
  ret
```

assistant: ```c
void foo(volatile int *a, int *b) {
  *a = 1;
  if (*b)
    *a = 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  movl   $0x1,(%rdi)
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L1
  movl   $0x2,(%rdi)
L1:
  ret
```

assistant: ```c
void foo(volatile int *a, int *b) {
  *a = 1;
  if (*b)
    *a = 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<savePlotFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L17:
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0x1c(%rbp),%xmm0
  movd   %xmm0,%esi
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  movd   %esi,%xmm0
  lea    D26(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L25
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D28: w

tool: D6: Can't open output plot file: %s


tool: D26: %d %d %e


assistant: ```c
void savePlotFile(const char *plot_file_name, float d_sampled_p0, int *out_step, int *out_level, float *out_pressure, int wav_sample_count) {
  FILE *fw;
  fw = fopen(plot_file_name, "w");
  if (fw == NULL) {
    printf("Can't open output plot file: %s\n", plot_file_name);
    exit(-1);
  }
  for (int i = 0; i < wav_sample_count; i++) {
    fprintf(fw, "%d %d %e\n", out_step[i], out_level[i], out_pressure[i] - d_sampled_p0);
  }
  fclose(fw);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<savePlotFile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  movss  %xmm0,0xc(%rsp)
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %r8d,%ebp
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L37
L29:
  test   %ebp,%ebp
  jle    L35
  mov    %ebp,%ebp
  mov    $0x0,%ebx
L10:
  movss  (%r15,%rbx,4),%xmm0
  subss  0xc(%rsp),%xmm0
  mov    (%r14,%rbx,4),%ecx
  mov    0x0(%r13,%rbx,4),%edx
  lea    D1(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L35:
  mov    %r12,%rdi
  call   <fclose@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D28
datatype: string

tool: D3: w

tool: D1: %d %d %e


tool: D28: Can't open output plot file: %s


assistant: ```c
void savePlotFile(const char *plot_file_name, float d_sampled_p0, int *out_step, int *out_level, float *out_pressure, int wav_sample_count) {
  FILE *fw;
  fw = fopen(plot_file_name, "w");
  if (fw == NULL) {
    printf("Can't open output plot file: %s\n", plot_file_name);
    exit(-1);
  }
  for (int i = 0; i < wav_sample_count; i++) {
    fprintf(fw, "%d %d %e\n", out_step[i], out_level[i], out_pressure[i] - d_sampled_p0);
  }
  fclose(fw);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<savePlotFile>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D23(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  movss  %xmm0,0x4(%rsp)
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
L24:
  test   %ebx,%ebx
  jle    L3
  movslq %ebx,%rax
  lea    D13(%rip),%r15
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
L6:
  movss  (%r14,%rbx,4),%xmm0
  mov    (%r12,%rbx,4),%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  subss  0x4(%rsp),%xmm0
  mov    0x0(%r13,%rbx,4),%ecx
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,0x8(%rsp)
  jne    L6
L3:
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <fclose@plt>
  nopl   0x0(%rax)
L7:
  mov    %r15,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D23: w

tool: D13: %d %d %e


tool: D8: Can't open output plot file: %s


assistant: ```c
void savePlotFile(const char *plot_file_name, float d_sampled_p0, int *out_step, int *out_level, float *out_pressure, int wav_sample_count) {
  FILE *fw;
  fw = fopen(plot_file_name, "w");
  if (fw == NULL) {
    printf("Can't open output plot file: %s\n", plot_file_name);
    exit(-1);
  }
  for (int i = 0; i < wav_sample_count; i++) {
    fprintf(fw, "%d %d %e\n", out_step[i], out_level[i], out_pressure[i] - d_sampled_p0);
  }
  fclose(fw);
}
```
user: Translate the below assembly code into C programming language:

```asm
<savePlotFile>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D22(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  movss  %xmm0,0x4(%rsp)
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L32
L18:
  test   %ebx,%ebx
  jle    L22
  movslq %ebx,%rax
  lea    D14(%rip),%r15
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
L16:
  movss  (%r14,%rbx,4),%xmm0
  mov    (%r12,%rbx,4),%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  subss  0x4(%rsp),%xmm0
  mov    0x0(%r13,%rbx,4),%ecx
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,0x8(%rsp)
  jne    L16
L22:
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <fclose@plt>
  nopl   0x0(%rax)
L32:
  mov    %r15,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: label: D22
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D24
data_type: string

tool: D22: w

tool: D14: %d %d %e


tool: D24: Can't open output plot file: %s


assistant: ```c
void savePlotFile(const char *plot_file_name, float d_sampled_p0, int *out_step, int *out_level, float *out_pressure, int wav_sample_count) {
  FILE *fw;
  fw = fopen(plot_file_name, "w");
  if (fw == NULL) {
    printf("Can't open output plot file: %s\n", plot_file_name);
    exit(-1);
  }
  for (int i = 0; i < wav_sample_count; i++) {
    fprintf(fw, "%d %d %e\n", out_step[i], out_level[i], out_pressure[i] - d_sampled_p0);
  }
  fclose(fw);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  lea    D2(%rip),%rbx
  test   %eax,%eax
  jne    L8
  jmp    L67
L24:
  lea    D66(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L8
L67:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L51:
  call   <sqrt@plt>
L1:
  lea    D64(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L8:
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm5
  movsd  D7(%rip),%xmm4
  divsd  %xmm5,%xmm4
  movsd  0x18(%rsp),%xmm6
  movsd  D7(%rip),%xmm0
  divsd  %xmm6,%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm0,%xmm3
  movsd  0x20(%rsp),%xmm7
  movsd  D7(%rip),%xmm2
  divsd  %xmm7,%xmm2
  movapd %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  subsd  %xmm2,%xmm3
  mulsd  %xmm3,%xmm1
  movapd %xmm4,%xmm3
  subsd  %xmm0,%xmm3
  addsd  %xmm2,%xmm3
  mulsd  %xmm3,%xmm1
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D7(%rip),%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L24
  ucomisd %xmm4,%xmm6
  setnp  %al
  mov    $0x0,%ecx
  cmovne %ecx,%eax
  ucomisd %xmm4,%xmm5
  setnp  %dl
  cmovne %ecx,%edx
  or     %dl,%al
  jne    L24
  ucomisd %xmm4,%xmm7
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  jne    L24
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L51
  sqrtsd %xmm0,%xmm0
  jmp    L1
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D36
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D66
type: string
name: retrieve_data
arguments: data_label: D64
type: string
name: retrieve_data
arguments: data_label: D7
type: f64

tool: D36: %d

tool: D2: %lf %lf %lf

tool: D66: These are invalid inputs!

tool: D64: %.3lf


tool: D7: 1

assistant: ```c
int main() {
  int t;
  double ha, hb, hc, total, root;
  scanf("%d", &t);
  while (t--) {
    while (1) {
      scanf("%lf %lf %lf", &ha, &hb, &hc);
      total = 1 / ((1.0 / ha + 1.0 / hb + 1.0 / hc) * (1.0 / ha + 1.0 / hb - 1.0 / hc) * (1.0 / ha - 1.0 / hb + 1.0 / hc) * (-1.0 / ha + 1.0 / hb + 1.0 / hc));
      if (total < 0 || ha == 0 || hb == 0 || hc == 0) {
        printf("These are invalid inputs!\n");
        break;
      } else {
        root = sqrt(total);
        printf("%.3lf\n", root);
      }
    }
  }
  return 0;
}
```