ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  js     L5
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D12(%rip),%r14
  lea    D19(%rip),%r13
  jne    L55
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L15:
  cmp    $0x7,%rax
  je     L79
L59:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  je     L81
L55:
  movsbl (%r12,%rbx,1),%edi
  mov    $0x2,%esi
  call   <putxval@plt>
  mov    %rbx,%rax
  and    $0xf,%eax
  cmp    $0xf,%rax
  jne    L15
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  jne    L55
  nopl   0x0(%rax,%rax,1)
L81:
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %eax,%eax
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L59
L5:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L70
```

tool_calls: name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string

tool: D12: 


tool: D19:  

tool: D26: no data.


assistant: ```c
int dump(char *buf, long size) {
  long i;
  if (size < 0) {
    puts("no data.\n");
    return -1;
  }
  for (i = 0; i < size; i++) {
    putxval(buf[i], 2);
    if ((i & 0xf) == 15) {
      puts("\n");
    } else {
      if ((i & 0xf) == 7)
        puts(" ");
      puts(" ");
    }
  }
  puts("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  js     L61
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D20(%rip),%r14
  lea    D25(%rip),%r13
  jne    L85
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L6:
  cmp    $0x7,%rax
  je     L54
L63:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  je     L75
L85:
  movsbl (%r12,%rbx,1),%edi
  mov    $0x2,%esi
  call   <putxval@plt>
  mov    %rbx,%rax
  and    $0xf,%eax
  cmp    $0xf,%rax
  jne    L6
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  jne    L85
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %eax,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L63
L61:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L45
```

tool_calls: name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string
name: disassemble_data
arguments: label: D3
type_infered: string

tool: D20: 


tool: D25:  

tool: D3: no data.


assistant: ```c
int dump(char *buf, long size) {
  long i;
  if (size < 0) {
    puts("no data.\n");
    return -1;
  }
  for (i = 0; i < size; i++) {
    putxval(buf[i], 2);
    if ((i & 0xf) == 15) {
      puts("\n");
    } else {
      if ((i & 0xf) == 7)
        puts(" ");
      puts(" ");
    }
  }
  puts("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<testCommentLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isConfigLine@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L1
L8:
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: # this is a comment


assistant: ```c
bool testCommentLine(void) {
  char const *line = "# this is a comment\n";
  if (!isConfigLine(line)) {
    return true;
  } else {
    return false;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<testCommentLine>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <isConfigLine@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: # this is a comment


assistant: ```c
bool testCommentLine(void) {
  char const *line = "# this is a comment\n";
  if (!isConfigLine(line)) {
    return true;
  } else {
    return false;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testCommentLine>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <isConfigLine@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: # this is a comment


assistant: ```c
bool testCommentLine(void) {
  char const *line = "# this is a comment\n";
  if (!isConfigLine(line)) {
    return true;
  } else {
    return false;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testCommentLine>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <isConfigLine@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: # this is a comment


assistant: ```c
bool testCommentLine(void) {
  char const *line = "# this is a comment\n";
  if (!isConfigLine(line)) {
    return true;
  } else {
    return false;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rule_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x11,%eax
  cmp    $0x9,%eax
  ja     L12
  mov    $0x12c,%eax
  jmp    L16
L12:
  mov    -0x4(%rbp),%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int rule_match(int token) {
  switch (token) {
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
    return 300;
  }
  return token;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rule_match>:
  endbr64
  lea    -0x11(%rdi),%eax
  cmp    $0xa,%eax
  mov    $0x12c,%eax
  cmovae %edi,%eax
  ret
```

assistant: ```c
int rule_match(int token) {
  switch (token) {
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
    return 300;
  }
  return token;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rule_match>:
  endbr64
  lea    -0x11(%rdi),%eax
  cmp    $0xa,%eax
  mov    $0x12c,%eax
  cmovae %edi,%eax
  ret
```

assistant: ```c
int rule_match(int token) {
  switch (token) {
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
    return 300;
  }
  return token;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ar_member_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ar_name_equal@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L3
L6:
  mov    -0x18(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
long int ar_member_pos(desc, mem, hdrpos, datapos, size, date, uid, gid, mode, name)
int desc;
char *mem;
long int hdrpos, datapos, size, date;
int uid, gid, mode;
char *name;
{
  if (!ar_name_equal(name, mem))
    return 0;
  return hdrpos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ar_member_pos>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    0x28(%rsp),%rdi
  mov    $0x0,%eax
  call   <ar_name_equal@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %rax,%rbx
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long int ar_member_pos(desc, mem, hdrpos, datapos, size, date, uid, gid, mode, name)
int desc;
char *mem;
long int hdrpos, datapos, size, date;
int uid, gid, mode;
char *name;
{
  if (!ar_name_equal(name, mem))
    return 0;
  return hdrpos;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ar_member_pos>:
  endbr64
  push   %r12
  mov    0x28(%rsp),%rdi
  xor    %eax,%eax
  mov    %rdx,%r12
  call   <ar_name_equal@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long int ar_member_pos(desc, mem, hdrpos, datapos, size, date, uid, gid, mode, name)
int desc;
char *mem;
long int hdrpos, datapos, size, date;
int uid, gid, mode;
char *name;
{
  if (!ar_name_equal(name, mem))
    return 0;
  return hdrpos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ar_member_pos>:
  endbr64
  push   %r12
  mov    0x28(%rsp),%rdi
  xor    %eax,%eax
  mov    %rdx,%r12
  call   <ar_name_equal@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long int ar_member_pos(desc, mem, hdrpos, datapos, size, date, uid, gid, mode, name)
int desc;
char *mem;
long int hdrpos, datapos, size, date;
int uid, gid, mode;
char *name;
{
  if (!ar_name_equal(name, mem))
    return 0;
  return hdrpos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D14(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x4(%rbp)
L16:
  cmpl   $0x12c,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: {"D14": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D17: %3d %6.1f


assistant: ```c
int main(void) {
  int cur_fahr;
  for (cur_fahr = 0; cur_fahr <= 300; cur_fahr = cur_fahr + 20) {
    printf("%3d %6.1f\n", cur_fahr, (5.0 / 9.0) * (cur_fahr - 32));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D12(%rip),%rbp
L9:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D13(%rip),%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D13
type: byte[8]

tool: D12: %3d %6.1f


tool: {"D13": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
int main(void) {
  int cur_fahr;
  for (cur_fahr = 0; cur_fahr <= 300; cur_fahr = cur_fahr + 20) {
    printf("%3d %6.1f\n", cur_fahr, (5.0 / 9.0) * (cur_fahr - 32));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D14(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: byte[8]

tool: D18: %3d %6.1f


tool: {"D14": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
int main(void) {
  int cur_fahr;
  for (cur_fahr = 0; cur_fahr <= 300; cur_fahr = cur_fahr + 20) {
    printf("%3d %6.1f\n", cur_fahr, (5.0 / 9.0) * (cur_fahr - 32));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  lea    -0x20(%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D18(%rip),%xmm0
  add    $0x14,%ebx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D18
type: byte[8]

tool: D8: %3d %6.1f


tool: {"D18": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

assistant: ```c
int main(void) {
  int cur_fahr;
  for (cur_fahr = 0; cur_fahr <= 300; cur_fahr = cur_fahr + 20) {
    printf("%3d %6.1f\n", cur_fahr, (5.0 / 9.0) * (cur_fahr - 32));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memSetInvalid8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memSetInvalid8(uint16_t addr, uint8_t val) {
  (void)addr;
  (void)val;
}
```
user: What is the c source code of the assembly code below?

```asm
<memSetInvalid8>:
  endbr64
  ret
```

assistant: ```c
void memSetInvalid8(uint16_t addr, uint8_t val) {
  (void)addr;
  (void)val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memSetInvalid8>:
  endbr64
  ret
```

assistant: ```c
void memSetInvalid8(uint16_t addr, uint8_t val) {
  (void)addr;
  (void)val;
}
```
user: What is the c source code of the assembly code below:

```asm
<memSetInvalid8>:
  endbr64
  ret
```

assistant: ```c
void memSetInvalid8(uint16_t addr, uint8_t val) {
  (void)addr;
  (void)val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmdln_get_nsec_or_help>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x2,%esi
  je     L22
  jg     L148
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    0x8(%rdx),%r12
  mov    %rdi,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L47
  mov    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  xor    %edx,%edx
  nopl   0x0(%rax)
L113:
  movzbl (%rsi),%ecx
  cmp    $0x30,%cl
  je     L86
  cmp    $0x31,%cl
  je     L86
  cmp    $0x32,%cl
  jne    L125
  nopw   0x0(%rax,%rax,1)
L86:
  add    $0x1,%edx
L146:
  add    $0x1,%rsi
  cmp    %rsi,%rdi
  jne    L113
  movslq %edx,%rdx
  cmp    %rdx,%rax
  je     L47
  lea    D34(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L148
  lea    D38(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L148
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L157
L148:
  mov    (%rbx),%rsi
  lea    D43(%rip),%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10a0 <printf@plt>
L125:
  cmp    $0x33,%cl
  je     L86
  cmp    $0x34,%cl
  je     L86
  cmp    $0x35,%cl
  je     L86
  cmp    $0x36,%cl
  je     L86
  cmp    $0x37,%cl
  je     L86
  cmp    $0x38,%cl
  je     L86
  cmp    $0x39,%cl
  je     L86
  jmp    L146
  xchg   %ax,%ax
L47:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  jmp    L19
L157:
  lea    D49(%rip),%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D34
type_infered: string
name: unpack_data
arguments: data_tag: D38
type_infered: string
name: unpack_data
arguments: data_tag: D18
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D49
type_infered: string

tool: D34: help

tool: D38: -help

tool: D18: --help

tool: D43: Usage: %s [ string [-[-]]help | int seconds] 


tool: D49:  Did not understand argument " %s ".


assistant: ```c
void cmdln_get_nsec_or_help(int *nsec, int argc, char *argv[]) {
  int i, j;
  char digits[10] = {"0"
                     "1"
                     "2"
                     "3"
                     "4"
                     "5"
                     "6"
                     "7"
                     "8"
                     "9"};
  int knt = 0;
  if (argc == 2) {
    for (j = 0; j < strlen(argv[1]); j++)
      for (i = 0; i < 10; i++)
        if (argv[1][j] == digits[i]) {
          knt++;
        };
    if (knt == strlen(argv[1])) {
      *nsec = atoi(argv[1]);
    } else if (!strcmp(argv[1], "help") || !strcmp(argv[1], "-help") || !strcmp(argv[1], "--help"))
      printf("Usage: %s [ string [-[-]]help | int seconds] \n", argv[0]);
    else {
      printf(" Did not understand argument \" %s \".\n", argv[1]);
      exit(1);
    }
  }
  if (argc > 2)
    printf("Usage: %s [ string [-[-]]help | int seconds] \n", argv[0]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<norm2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double norm2(int n, double *x) {
  int i;
  double sum = 0;
  for (i = 0; i < n; i++) {
    sum += x[i] * x[i];
  }
  return sqrt(sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<norm2>:
  endbr64
  test   %edi,%edi
  jle    L27
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L14:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L2
L13:
  sqrtsd %xmm0,%xmm0
  ret
L27:
  pxor   %xmm0,%xmm0
  jmp    L13
L2:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double norm2(int n, double *x) {
  int i;
  double sum = 0;
  for (i = 0; i < n; i++) {
    sum += x[i] * x[i];
  }
  return sqrt(sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<norm2>:
  endbr64
  test   %edi,%edi
  jle    L13
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rsi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L0:
  movsd  (%rsi),%xmm1
  add    $0x8,%rsi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L0
  ucomisd %xmm0,%xmm2
  ja     L24
  sqrtsd %xmm0,%xmm0
  ret
L13:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L24:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm2(int n, double *x) {
  int i;
  double sum = 0;
  for (i = 0; i < n; i++) {
    sum += x[i] * x[i];
  }
  return sqrt(sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<norm2>:
  endbr64
  test   %edi,%edi
  jle    L26
  cmp    $0x1,%edi
  je     L24
  mov    %edi,%edx
  pxor   %xmm3,%xmm3
  mov    %rsi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L15:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L15
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L17
L1:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L17:
  ucomisd %xmm0,%xmm3
  ja     L27
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L26:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L24:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L1
L27:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm2(int n, double *x) {
  int i;
  double sum = 0;
  for (i = 0; i < n; i++) {
    sum += x[i] * x[i];
  }
  return sqrt(sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ieee_p_1242562249_sub_17249857350030274602_1035706684>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0xc(%rcx),%ebp
  test   %ebp,%ebp
  je     L12
  mov    %rsp,%rsi
  call   <ieee_p_1242562249_sub_18075413680674704129_1035706684@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%r13d
  mov    %r13d,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%r12
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%eax
  mov    %edx,%ebp
  sub    %ecx,%ebp
  imul   %eax,%ebp
  add    $0x1,%ebp
L25:
  mov    %ecx,(%rbx)
  mov    %edx,0x4(%rbx)
  mov    %eax,0x8(%rbx)
  mov    %ebp,0xc(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %r12,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    0x508(%rdi),%r13
  mov    $0x0,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%r12
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0xffffffff,%eax
  jmp    L25
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ieee_p_1242562249_sub_17249857350030274602_1035706684(char *t1, char *t2, char *t3, char *t4, int t5) {
  char t7[24];
  char t20[16];
  char *t0;
  char *t8;
  unsigned char t9;
  char *t10;
  char *t11;
  char *t12;
  unsigned int t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  int t18;
  unsigned int t19;
  int t21;
  char *t22;
  int t23;
  char *t24;
  char *t25;
  int t26;
LAB0:
  t8 = (t7 + 4U);
  t9 = (t3 != 0);
  if (t9 == 1)
    goto LAB3;
LAB2:
  t10 = (t7 + 12U);
  *((char **)t10) = t4;
  t11 = (t7 + 20U);
  *((int *)t11) = t5;
  t12 = (t4 + 12U);
  t13 = *((unsigned int *)t12);
  t14 = (t13 < 1);
  if (t14 != 0)
    goto LAB4;
LAB6:
LAB5:
  t12 = ieee_p_1242562249_sub_18075413680674704129_1035706684(t1, t20, t3, t4, t5);
  t15 = (t20 + 12U);
  t13 = *((unsigned int *)t15);
  t13 = (t13 * 1U);
  t0 = xsi_get_transient_memory(t13);
  memcpy(t0, t12, t13);
  t16 = (t20 + 0U);
  t18 = *((int *)t16);
  t17 = (t20 + 4U);
  t21 = *((int *)t17);
  t22 = (t20 + 8U);
  t23 = *((int *)t22);
  t24 = (t2 + 0U);
  t25 = (t24 + 0U);
  *((int *)t25) = t18;
  t25 = (t24 + 4U);
  *((int *)t25) = t21;
  t25 = (t24 + 8U);
  *((int *)t25) = t23;
  t26 = (t21 - t18);
  t19 = (t26 * t23);
  t19 = (t19 + 1);
  t25 = (t24 + 12U);
  *((unsigned int *)t25) = t19;
LAB1:
  return t0;
LAB3:
  *((char **)t8) = t3;
  goto LAB2;
LAB4:
  t15 = (t1 + 1288U);
  t16 = *((char **)t15);
  t0 = xsi_get_transient_memory(0U);
  memcpy(t0, t16, 0U);
  t15 = (t2 + 0U);
  t17 = (t15 + 0U);
  *((int *)t17) = 0;
  t17 = (t15 + 4U);
  *((int *)t17) = 1;
  t17 = (t15 + 8U);
  *((int *)t17) = -1;
  t18 = (1 - 0);
  t19 = (t18 * -1);
  t19 = (t19 + 1);
  t17 = (t15 + 12U);
  *((unsigned int *)t17) = t19;
  goto LAB1;
LAB7:
  goto LAB5;
LAB8:;
}
```