ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <getint@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%rax
L20:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L20
  mov    %edx,0xc(%rsp)
  movslq %edx,%rax
  movl   $0x3,(%rsp,%rax,4)
  mov    %edx,%ecx
  add    0xc(%rsp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  lea    (%rax,%rax,2),%esi
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  movslq %esi,%rsi
  lea    (%rdx,%rdx,1),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  add    $0x3,%eax
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  cltq
  add    (%rsp,%rax,4),%edx
  mov    %edx,(%rsp,%rsi,4)
L26:
  mov    (%rbx),%edi
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L26
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i;
  int s[10];
  int a;
  a = getint();
  a = a % 10;
  i = 0;
  while (i < 10) {
    s[i] = 1;
    i = i + 1;
  }
  s[3] = a;
  s[a] = 3;
  s[(s[(a + s[3]) % 10] * s[a]) % 10] = s[(s[a] + s[a * 2 % 10]) % 10] + a;
  i = 0;
  while (i < 10) {
    putint(s[i]);
    putchar(10);
    i = i + 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  call   <getint@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L21
  movslq %edx,%rax
  mov    %edx,0xc(%rsp)
  movl   $0x3,(%rsp,%rax,4)
  mov    0xc(%rsp),%ecx
  add    %edx,%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  lea    (%rax,%rax,2),%esi
  movslq %esi,%rax
  mov    %esi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rdx,%rdx,1),%ecx
  lea    (%rax,%rax,4),%eax
  mov    %ecx,%edi
  add    %eax,%eax
  sar    $0x1f,%edi
  sub    %eax,%esi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  movslq %esi,%rsi
  sar    $0x22,%rax
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  add    $0x3,%eax
  movslq %eax,%rcx
  mov    %eax,%edi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%edi
  sar    $0x22,%rcx
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  cltq
  add    (%rsp,%rax,4),%edx
  mov    %edx,(%rsp,%rsi,4)
  nopl   0x0(%rax,%rax,1)
L24:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L24
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i;
  int s[10];
  int a;
  a = getint();
  a = a % 10;
  i = 0;
  while (i < 10) {
    s[i] = 1;
    i = i + 1;
  }
  s[3] = a;
  s[a] = 3;
  s[(s[(a + s[3]) % 10] * s[a]) % 10] = s[(s[a] + s[a * 2 % 10]) % 10] + a;
  i = 0;
  while (i < 10) {
    putint(s[i]);
    putchar(10);
    i = i + 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  call   <getint@plt>
  movdqa D12(%rip),%xmm0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    D12(%rip),%rax
  mov    %edx,0xc(%rsp)
  mov    %rax,0x20(%rsp)
  movslq %edx,%rax
  movl   $0x3,(%rsp,%rax,4)
  mov    0xc(%rsp),%ecx
  add    %edx,%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  lea    (%rax,%rax,2),%esi
  movslq %esi,%rax
  mov    %esi,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rdx,%rdx,1),%ecx
  lea    (%rax,%rax,4),%eax
  mov    %ecx,%edi
  add    %eax,%eax
  sar    $0x1f,%edi
  sub    %eax,%esi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  movslq %esi,%rsi
  sar    $0x22,%rax
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,4),%eax
  add    $0x3,%eax
  movslq %eax,%rcx
  mov    %eax,%edi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%edi
  sar    $0x22,%rcx
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  cltq
  add    (%rsp,%rax,4),%edx
  mov    %edx,(%rsp,%rsi,4)
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L3
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
datatype: byte[16]

tool: {"D12": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i;
  int s[10];
  int a;
  a = getint();
  a = a % 10;
  i = 0;
  while (i < 10) {
    s[i] = 1;
    i = i + 1;
  }
  s[3] = a;
  s[a] = 3;
  s[(s[(a + s[3]) % 10] * s[a]) % 10] = s[(s[a] + s[a * 2 % 10]) % 10] + a;
  i = 0;
  while (i < 10) {
    putint(s[i]);
    putchar(10);
    i = i + 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<halfLife>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <randomize@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L40:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L46:
  mov    D2(%rip),%rax
  movq   %rax,%xmm0
  call   <randomChance@plt>
  test   %rax,%rax
  je     L44
  subl   $0x1,-0x18(%rbp)
L44:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L46
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L40
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: f64

tool: D2: 0.5

assistant: ```c
int halfLife(int year, int atoms) {
  int remains = atoms;
  randomize();
  for (int j = 0; j < year + 1; j++) {
    remains = atoms;
    for (int i = 0; i < remains; i++) {
      if (randomChance(0.5))
        atoms--;
    }
  }
  return remains;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<halfLife>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <randomize@plt>
  mov    $0x0,%r14d
  test   %r13d,%r13d
  jns    L33
L39:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  movsd  D1(%rip),%xmm0
  call   <randomChance@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L28
L7:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jl     L39
  mov    %ebp,%r12d
L33:
  mov    %r12d,%ebp
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L28
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: f64

tool: D1: 0.5

assistant: ```c
int halfLife(int year, int atoms) {
  int remains = atoms;
  randomize();
  for (int j = 0; j < year + 1; j++) {
    remains = atoms;
    for (int i = 0; i < remains; i++) {
      if (randomChance(0.5))
        atoms--;
    }
  }
  return remains;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<halfLife>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  call   <randomize@plt>
  test   %r13d,%r13d
  js     L1
  nopl   0x0(%rax)
L10:
  mov    %r12d,%ebp
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L43
  nopw   0x0(%rax,%rax,1)
L32:
  movsd  D3(%rip),%xmm0
  call   <randomChance@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L32
L43:
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jl     L1
  mov    %ebp,%r12d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L1:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: f64

tool: D3: 0.5

assistant: ```c
int halfLife(int year, int atoms) {
  int remains = atoms;
  randomize();
  for (int j = 0; j < year + 1; j++) {
    remains = atoms;
    for (int i = 0; i < remains; i++) {
      if (randomChance(0.5))
        atoms--;
    }
  }
  return remains;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<halfLife>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  call   <randomize@plt>
  test   %r13d,%r13d
  js     L48
  test   %r12d,%r12d
  jle    L48
L38:
  mov    %r12d,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  D3(%rip),%xmm0
  call   <randomChance@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L1
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jl     L48
  mov    %ebp,%r12d
  test   %r12d,%r12d
  jg     L38
L48:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: f64

tool: D3: 0.5

assistant: ```c
int halfLife(int year, int atoms) {
  int remains = atoms;
  randomize();
  for (int j = 0; j < year + 1; j++) {
    remains = atoms;
    for (int i = 0; i < remains; i++) {
      if (randomChance(0.5))
        atoms--;
    }
  }
  return remains;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculateWages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L15:
  movl   $0xc8,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x24(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L15
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: f64

tool: D9: 0.09

assistant: ```c
void calculateWages(int sales[], int wages[], int employees) {
  int i, pay;
  for (i = 0; i <= employees - 1; i++) {
    pay = 200;
    pay += sales[i] * 0.09;
    wages[i] = pay;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calculateWages>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    %edx,%edx
  mov    $0x0,%eax
  movsd  D0(%rip),%xmm2
  movsd  D11(%rip),%xmm1
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: f64
name: retrieve_data
arguments: data_tag: D11
data_type: byte[8]

tool: D0: 0.09

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x69,0x40]}

assistant: ```c
void calculateWages(int sales[], int wages[], int employees) {
  int i, pay;
  for (i = 0; i <= employees - 1; i++) {
    pay = 200;
    pay += sales[i] * 0.09;
    wages[i] = pay;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calculateWages>:
  endbr64
  test   %edx,%edx
  jle    L7
  movsd  D18(%rip),%xmm2
  movsd  D8(%rip),%xmm1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L6
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: f64
name: retrieve_data
arguments: tag: D8
type: byte[8]

tool: D18: 0.09

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x69,0x40]}

assistant: ```c
void calculateWages(int sales[], int wages[], int employees) {
  int i, pay;
  for (i = 0; i <= employees - 1; i++) {
    pay = 200;
    pay += sales[i] * 0.09;
    wages[i] = pay;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculateWages>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L7
  lea    0x4(%rdi),%rdi
  mov    %rsi,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L16
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L16
  mov    %edx,%edi
  movapd D20(%rip),%xmm3
  movapd D30(%rip),%xmm2
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L53:
  movdqu (%rcx,%rax,1),%xmm4
  cvtdq2pd (%rcx,%rax,1),%xmm1
  mulpd  %xmm3,%xmm1
  pshufd $0xee,%xmm4,%xmm0
  cvtdq2pd %xmm0,%xmm0
  mulpd  %xmm3,%xmm0
  addpd  %xmm2,%xmm1
  addpd  %xmm2,%xmm0
  cvttpd2dq %xmm1,%xmm1
  cvttpd2dq %xmm0,%xmm0
  punpcklqdq %xmm0,%xmm1
  movups %xmm1,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L53
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L7
  mov    %eax,%r8d
  pxor   %xmm0,%xmm0
  movsd  D20(%rip),%xmm2
  movsd  D30(%rip),%xmm1
  cvtsi2sdl (%rcx,%r8,4),%xmm0
  lea    0x0(,%r8,4),%rdi
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r9d
  mov    %r9d,(%rsi,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edx
  jle    L7
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2sdl 0x4(%rcx,%rdi,1),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r8d
  mov    %r8d,0x4(%rsi,%rdi,1)
  cmp    %eax,%edx
  jle    L7
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rcx,%rdi,1),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,0x8(%rsi,%rdi,1)
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  D20(%rip),%xmm2
  movsd  D30(%rip),%xmm1
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L23:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rcx,%rax,4),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  mov    %edi,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L23
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
type: f64[2]
name: retrieve_data
arguments: tag: D30
type: byte[16]

tool: {"D20": [0.09,0.09]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x69,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x69,0x40]}

assistant: ```c
void calculateWages(int sales[], int wages[], int employees) {
  int i, pay;
  for (i = 0; i <= employees - 1; i++) {
    pay = 200;
    pay += sales[i] * 0.09;
    wages[i] = pay;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utopiantree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L23
L25:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L30
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L23
L30:
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x2,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  subl   $0x1,-0x10(%rbp)
  jmp    L33
L16:
  subl   $0x2,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string

tool: D5: %d

tool: D3: 1

tool: D29: %d


assistant: ```c
int utopiantree(void) {
  int numCases;
  scanf("%d", &numCases);
  while (numCases--) {
    int cycles;
    scanf("%d", &cycles);
    int isEven = (cycles % 2 == 0);
    if (cycles == 0) {
      printf("1\n");
      continue;
    }
    if (isEven) {
      cycles--;
    }
    int treeHeight = 1 << ((cycles / 2) + 2);
    if (isEven) {
      treeHeight -= 1;
    } else {
      treeHeight -= 2;
    }
    printf("%d\n", treeHeight);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utopiantree>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L69
  lea    0x4(%rsp),%rbp
  lea    D35(%rip),%rbx
  lea    D27(%rip),%r12
  lea    D39(%rip),%r13
  jmp    L13
L8:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L79
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  add    $0x2,%ecx
  mov    $0x1,%esi
  shl    %cl,%esi
  sub    $0x2,%esi
L47:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L79:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L69
L13:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  test   %eax,%eax
  je     L8
  test   %edx,%edx
  jne    L42
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  add    $0x2,%ecx
  mov    $0x1,%esi
  shl    %cl,%esi
  sub    $0x1,%esi
  jmp    L47
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D27
data_type: string
name: retrieve_data
arguments: data_tag: D39
data_type: string

tool: D35: %d

tool: D27: %d


tool: D39: 1

assistant: ```c
int utopiantree(void) {
  int numCases;
  scanf("%d", &numCases);
  while (numCases--) {
    int cycles;
    scanf("%d", &cycles);
    int isEven = (cycles % 2 == 0);
    if (cycles == 0) {
      printf("1\n");
      continue;
    }
    if (isEven) {
      cycles--;
    }
    int treeHeight = 1 << ((cycles / 2) + 2);
    if (isEven) {
      treeHeight -= 1;
    } else {
      treeHeight -= 2;
    }
    printf("%d\n", treeHeight);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utopiantree>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L77
  lea    0x4(%rsp),%rbp
  mov    $0x1,%r13d
  lea    D28(%rip),%r12
  lea    D3(%rip),%r14
  jmp    L22
  xchg   %ax,%ax
L74:
  sub    $0x1,%eax
  mov    %r13d,%esi
  mov    %eax,%ecx
  mov    %eax,0x4(%rsp)
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  add    $0x2,%ecx
  shl    %cl,%esi
  sub    $0x1,%esi
L63:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L77
L22:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  test   %eax,%eax
  je     L19
  test   %edx,%edx
  je     L74
  mov    %eax,%ecx
  mov    %r13d,%esi
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  add    $0x2,%ecx
  shl    %cl,%esi
  sub    $0x2,%esi
  jmp    L63
  nopl   0x0(%rax)
L19:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L22
  nopl   (%rax)
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D16: %d

tool: D28: %d


tool: D3: 1

assistant: ```c
int utopiantree(void) {
  int numCases;
  scanf("%d", &numCases);
  while (numCases--) {
    int cycles;
    scanf("%d", &cycles);
    int isEven = (cycles % 2 == 0);
    if (cycles == 0) {
      printf("1\n");
      continue;
    }
    if (isEven) {
      cycles--;
    }
    int treeHeight = 1 << ((cycles / 2) + 2);
    if (isEven) {
      treeHeight -= 1;
    } else {
      treeHeight -= 2;
    }
    printf("%d\n", treeHeight);
  }
  return 0;
}
```