ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<finn_mat4_perspective>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mulss  D6(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0x4(%rsp)
  call   <tan@plt>
  mov    %rbx,%rdi
  mov    $0x40,%edx
  xor    %esi,%esi
  movss  %xmm0,(%rsp)
  call   <memset@plt>
  movss  (%rsp),%xmm0
  movss  D13(%rip),%xmm4
  movl   $0xbf800000,0x2c(%rbx)
  movss  0xc(%rsp),%xmm1
  movss  0x4(%rsp),%xmm3
  movaps %xmm4,%xmm5
  movss  0x8(%rsp),%xmm2
  divss  %xmm0,%xmm4
  mulss  %xmm0,%xmm1
  movaps %xmm3,%xmm0
  addss  %xmm2,%xmm0
  divss  %xmm1,%xmm5
  movaps %xmm3,%xmm1
  addss  %xmm3,%xmm3
  subss  %xmm2,%xmm1
  mulss  %xmm2,%xmm3
  movss  %xmm4,0x14(%rbx)
  movss  D19(%rip),%xmm4
  xorps  %xmm4,%xmm0
  xorps  %xmm4,%xmm3
  divss  %xmm1,%xmm0
  movss  %xmm5,(%rbx)
  divss  %xmm1,%xmm3
  movss  %xmm0,0x28(%rbx)
  movss  %xmm3,0x38(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: byte[4]
name: parse_data
arguments: tag: D13
type_guessed: byte[4]
name: parse_data
arguments: tag: D19
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3f]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D19": [0x00,0x00,0x00,0x80]}

assistant: ```c
void finn_mat4_perspective(float *result, float fov, float aspect, float near, float far) {
  const float tanHalfFov = tan(fov / 2.0f);
  memset(result, 0, sizeof(float) * 16);
  result[0] = 1.0f / (aspect * tanHalfFov);
  result[5] = 1.0f / (tanHalfFov);
  result[10] = -(far + near) / (far - near);
  result[11] = -1.0f;
  result[14] = -(2.0f * far * near) / (far - near);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<finn_mat4_perspective>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mulss  D14(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0x4(%rsp)
  call   <tan@plt>
  mov    %rbx,%rdi
  mov    $0x40,%edx
  xor    %esi,%esi
  movss  %xmm0,(%rsp)
  call   <memset@plt>
  movss  (%rsp),%xmm0
  movss  D6(%rip),%xmm4
  movl   $0xbf800000,0x2c(%rbx)
  movss  0xc(%rsp),%xmm1
  movss  0x4(%rsp),%xmm3
  movaps %xmm4,%xmm5
  movss  0x8(%rsp),%xmm2
  divss  %xmm0,%xmm4
  mulss  %xmm0,%xmm1
  movaps %xmm3,%xmm0
  addss  %xmm2,%xmm0
  divss  %xmm1,%xmm5
  movaps %xmm3,%xmm1
  addss  %xmm3,%xmm3
  subss  %xmm2,%xmm1
  mulss  %xmm2,%xmm3
  movss  %xmm4,0x14(%rbx)
  movss  D10(%rip),%xmm4
  xorps  %xmm4,%xmm0
  xorps  %xmm4,%xmm3
  divss  %xmm1,%xmm0
  movss  %xmm5,(%rbx)
  divss  %xmm1,%xmm3
  movss  %xmm0,0x28(%rbx)
  movss  %xmm3,0x38(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: byte[4]
name: retrieve_data
arguments: data_label: D6
datatype: byte[4]
name: retrieve_data
arguments: data_label: D10
datatype: byte[4]

tool: {"D14": [0x00,0x00,0x00,0x3f]}

tool: {"D6": [0x00,0x00,0x80,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x80]}

assistant: ```c
void finn_mat4_perspective(float *result, float fov, float aspect, float near, float far) {
  const float tanHalfFov = tan(fov / 2.0f);
  memset(result, 0, sizeof(float) * 16);
  result[0] = 1.0f / (aspect * tanHalfFov);
  result[5] = 1.0f / (tanHalfFov);
  result[10] = -(far + near) / (far - near);
  result[11] = -1.0f;
  result[14] = -(2.0f * far * near) / (far - near);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dumb_hash_contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L24
L39:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10121457,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x7f7,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D24(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  test   %rax,%rax
  je     L27
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D24(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L33
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  lea    D24(%rip),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rcx,%rdx,1)
  mov    $0x0,%eax
L33:
  leave
  ret
```

assistant: ```c
int dumb_hash_contains(const char *filename) {
  static const char *hash_table[2039] = {
      0,
  };
  const signed char *p = filename;
  uint32_t h = *p;
  for (p += 1; *p != '\0'; p++)
    h = (h << 5) - h + *p;
  h %= 2039;
  if (hash_table[h])
    return !strcmp(hash_table[h], filename);
  hash_table[h] = filename;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dumb_hash_contains>:
  endbr64
  movsbl (%rdi),%ecx
  lea    0x1(%rdi),%rsi
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L16
L7:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L7
L16:
  movslq %ecx,%rax
  imul   $0x10121457,%rax,%rax
  sar    $0x27,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x7f7,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  movslq %eax,%rcx
  lea    D4(%rip),%rdx
  mov    (%rdx,%rcx,8),%rdx
  test   %rdx,%rdx
  je     L3
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L3:
  cltq
  lea    D4(%rip),%rdx
  mov    %rdi,(%rdx,%rax,8)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int dumb_hash_contains(const char *filename) {
  static const char *hash_table[2039] = {
      0,
  };
  const signed char *p = filename;
  uint32_t h = *p;
  for (p += 1; *p != '\0'; p++)
    h = (h << 5) - h + *p;
  h %= 2039;
  if (hash_table[h])
    return !strcmp(hash_table[h], filename);
  hash_table[h] = filename;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dumb_hash_contains>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl (%rdi),%ecx
  mov    %rdi,%r8
  test   %al,%al
  je     L12
  lea    0x1(%rdi),%rsi
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %ecx,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L14
L12:
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x10121457,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x7f7,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  lea    D8(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%rdi
  test   %rdi,%rdi
  je     L11
  sub    $0x8,%rsp
  mov    %r8,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L11:
  mov    %r8,(%rdx,%rax,8)
  xor    %eax,%eax
  ret
```

assistant: ```c
int dumb_hash_contains(const char *filename) {
  static const char *hash_table[2039] = {
      0,
  };
  const signed char *p = filename;
  uint32_t h = *p;
  for (p += 1; *p != '\0'; p++)
    h = (h << 5) - h + *p;
  h %= 2039;
  if (hash_table[h])
    return !strcmp(hash_table[h], filename);
  hash_table[h] = filename;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dumb_hash_contains>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl (%rdi),%ecx
  mov    %rdi,%r8
  test   %al,%al
  je     L6
  lea    0x1(%rdi),%rsi
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ecx,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L1
L6:
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x10121457,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x27,%rax
  sub    %edx,%eax
  imul   $0x7f7,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  lea    D2(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%rdi
  test   %rdi,%rdi
  je     L19
  sub    $0x8,%rsp
  mov    %r8,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L19:
  mov    %r8,(%rdx,%rax,8)
  xor    %eax,%eax
  ret
```

assistant: ```c
int dumb_hash_contains(const char *filename) {
  static const char *hash_table[2039] = {
      0,
  };
  const signed char *p = filename;
  uint32_t h = *p;
  for (p += 1; *p != '\0'; p++)
    h = (h << 5) - h + *p;
  h %= 2039;
  if (hash_table[h])
    return !strcmp(hash_table[h], filename);
  hash_table[h] = filename;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strchrsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %al,-0x2c(%rbp)
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x1,%eax
  jmp    L23
L2:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  mov    $0x1,%eax
  jmp    L23
L35:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
int strchrsplit(const char *str, const char sep, char **former_result, char **latter_result) {
  char *split;
  char *former, *latter;
  split = strchr(str, sep);
  if (!split) {
    return 1;
  }
  former = malloc(split - str + 1);
  if (!former) {
    return 1;
  }
  strncpy(former, str, split - str);
  former[split - str] = '\0';
  latter = strdup(split + 1);
  *former_result = former;
  *latter_result = latter;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strchrsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r14
  mov    %rcx,%r13
  movsbl %sil,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L13
  mov    %rbx,%r15
  sub    %rbp,%r15
  lea    0x1(%r15),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1,%eax
  test   %r12,%r12
  je     L13
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r15,1)
  lea    0x1(%rbx),%rdi
  call   <strdup@plt>
  mov    %r12,(%r14)
  mov    %rax,0x0(%r13)
  mov    $0x0,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strchrsplit(const char *str, const char sep, char **former_result, char **latter_result) {
  char *split;
  char *former, *latter;
  split = strchr(str, sep);
  if (!split) {
    return 1;
  }
  former = malloc(split - str + 1);
  if (!former) {
    return 1;
  }
  strncpy(former, str, split - str);
  former[split - str] = '\0';
  latter = strdup(split + 1);
  *former_result = former;
  *latter_result = latter;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strchrsplit>:
  endbr64
  push   %r15
  movsbl %sil,%esi
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%r15
  mov    %rax,%rbx
  sub    %rbp,%r15
  lea    0x1(%r15),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L1
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%r15,1)
  lea    0x1(%rbx),%rdi
  call   <strdup@plt>
  mov    %r14,0x0(%r13)
  mov    %rax,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strchrsplit(const char *str, const char sep, char **former_result, char **latter_result) {
  char *split;
  char *former, *latter;
  split = strchr(str, sep);
  if (!split) {
    return 1;
  }
  former = malloc(split - str + 1);
  if (!former) {
    return 1;
  }
  strncpy(former, str, split - str);
  former[split - str] = '\0';
  latter = strdup(split + 1);
  *former_result = former;
  *latter_result = latter;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchrsplit>:
  endbr64
  push   %r15
  movsbl %sil,%esi
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%r15
  mov    %rax,%rbx
  sub    %rbp,%r15
  lea    0x1(%r15),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L14
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%r15,1)
  lea    0x1(%rbx),%rdi
  call   <strdup@plt>
  mov    %r14,0x0(%r13)
  mov    %rax,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strchrsplit(const char *str, const char sep, char **former_result, char **latter_result) {
  char *split;
  char *former, *latter;
  split = strchr(str, sep);
  if (!split) {
    return 1;
  }
  former = malloc(split - str + 1);
  if (!former) {
    return 1;
  }
  strncpy(former, str, split - str);
  former[split - str] = '\0';
  latter = strdup(split + 1);
  *former_result = former;
  *latter_result = latter;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<entryAction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: Entering %s


assistant: ```c
void entryAction(void *stateData, struct event *event) {
  const char *stateName = (const char *)stateData;
  printf("Entering %s\n", stateName);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<entryAction>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: Entering %s


assistant: ```c
void entryAction(void *stateData, struct event *event) {
  const char *stateName = (const char *)stateData;
  printf("Entering %s\n", stateName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<entryAction>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: Entering %s


assistant: ```c
void entryAction(void *stateData, struct event *event) {
  const char *stateName = (const char *)stateData;
  printf("Entering %s\n", stateName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<entryAction>:
  endbr64
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Entering %s


assistant: ```c
void entryAction(void *stateData, struct event *event) {
  const char *stateName = (const char *)stateData;
  printf("Entering %s\n", stateName);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bbm_com_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movzwl -0x20(%rbp),%edx
  movzwl -0x1c(%rbp),%esi
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <bbm_data@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bbm_com_data(void *handle, unsigned short devid, unsigned short addr, unsigned char *data, unsigned int size) {
  int res;
  res = bbm_data(handle, devid, addr, data, size);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bbm_com_data>:
  endbr64
  sub    $0x8,%rsp
  movzwl %dx,%edx
  movzwl %si,%esi
  call   <bbm_data@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bbm_com_data(void *handle, unsigned short devid, unsigned short addr, unsigned char *data, unsigned int size) {
  int res;
  res = bbm_data(handle, devid, addr, data, size);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bbm_com_data>:
  endbr64
  movzwl %dx,%edx
  movzwl %si,%esi
  jmp    1050 <bbm_data@plt>
```

assistant: ```c
int bbm_com_data(void *handle, unsigned short devid, unsigned short addr, unsigned char *data, unsigned int size) {
  int res;
  res = bbm_data(handle, devid, addr, data, size);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bbm_com_data>:
  endbr64
  movzwl %dx,%edx
  movzwl %si,%esi
  jmp    1050 <bbm_data@plt>
```

assistant: ```c
int bbm_com_data(void *handle, unsigned short devid, unsigned short addr, unsigned char *data, unsigned int size) {
  int res;
  res = bbm_data(handle, devid, addr, data, size);
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffb38cf9b1,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x8,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffb38cf9b1,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x8,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x16d,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1e,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D42
type_infered: string

tool: D37: %d

tool: D46: %d ano(s)


tool: D11: %d mes(es)


tool: D7: %d dia(s)


tool: D42: pause

assistant: ```c
int main() {
  int X;
  scanf("%d", &X);
  printf("%d ano(s)\n", X / 365);
  X = X % 365;
  printf("%d mes(es)\n", X / 30);
  X = X % 30;
  printf("%d dia(s)\n", X);
  system("pause");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0xffffffffb38cf9b1,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x8,%esi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0xffffffffb38cf9b1,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x16d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,0x4(%rsp)
  movslq %eax,%rsi
  imul   $0xffffffff88888889,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x4,%esi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rsi
  imul   $0xffffffff88888889,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x4,%esi
  cltd
  sub    %edx,%esi
  imul   $0x1e,%esi,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %eax,0x4(%rsp)
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D39
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D15: %d

tool: D21: %d ano(s)


tool: D48: %d mes(es)


tool: D39: %d dia(s)


tool: D0: pause

assistant: ```c
int main() {
  int X;
  scanf("%d", &X);
  printf("%d ano(s)\n", X / 365);
  X = X % 365;
  printf("%d mes(es)\n", X / 30);
  X = X % 30;
  printf("%d dia(s)\n", X);
  system("pause");
  return 0;
}
```