ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int result;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int result;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string

tool: D17: Set: 

tool: D13: %i 

assistant: ```c
void printSet(int *set) {
  int i = 0;
  printf("Set: ");
  while (set[i] != -1) {
    printf("%i ", set[i]);
    i++;
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printSet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  cmp    $0xffffffff,%esi
  je     L11
  add    $0x4,%rbx
  lea    D6(%rip),%rbp
L14:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  cmp    $0xffffffff,%esi
  jne    L14
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D6
type: string

tool: D9: Set: 

tool: D6: %i 

assistant: ```c
void printSet(int *set) {
  int i = 0;
  printf("Set: ");
  while (set[i] != -1) {
    printf("%i ", set[i]);
    i++;
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printSet>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%esi
  cmp    $0xffffffff,%esi
  je     L11
  add    $0x4,%rbx
  lea    D8(%rip),%rbp
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffffff,%esi
  jne    L4
L11:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D1: Set: 

tool: D8: %i 

assistant: ```c
void printSet(int *set) {
  int i = 0;
  printf("Set: ");
  while (set[i] != -1) {
    printf("%i ", set[i]);
    i++;
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printSet>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%esi
  cmp    $0xffffffff,%esi
  je     L7
  add    $0x4,%rbx
  lea    D18(%rip),%rbp
  nopl   (%rax)
L17:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    $0xffffffff,%esi
  jne    L17
L7:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string

tool: D5: Set: 

tool: D18: %i 

assistant: ```c
void printSet(int *set) {
  int i = 0;
  printf("Set: ");
  while (set[i] != -1) {
    printf("%i ", set[i]);
    i++;
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rechac>:
  endbr64
  mov    %rsi,%rax
  mov    %ecx,%r8d
  test   %ecx,%ecx
  jle    L15
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    $0x0,%ecx
L12:
  mov    0x4(%rdi),%r10d
  mov    %r10d,%edx
  add    (%rdi),%edx
  add    $0x1,%edx
  sar    %edx
  add    (%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rax)
  mov    0x8(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x4(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x4(%rax)
  mov    0xc(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x8(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x8(%rax)
  mov    0x10(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0xc(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0xc(%rax)
  mov    0x14(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x10(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x10(%rax)
  mov    0x18(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x14(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x14(%rax)
  mov    0x1c(%rdi),%edx
  lea    0x1(%r9,%rdx,1),%r9d
  sar    %r9d
  add    0x18(%rax),%r9d
  add    $0x1,%r9d
  sar    %r9d
  mov    %r9d,0x18(%rax)
  add    0x20(%rdi),%edx
  add    $0x1,%edx
  sar    %edx
  add    0x1c(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rax)
  add    %rsi,%rdi
  add    %rsi,%rax
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L12
L15:
  ret
```

assistant: ```c
void rechac(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (dp[0] + ((uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1) + 1) >> 1;
    dp[1] = (dp[1] + ((uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1) + 1) >> 1;
    dp[2] = (dp[2] + ((uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1) + 1) >> 1;
    dp[3] = (dp[3] + ((uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1) + 1) >> 1;
    dp[4] = (dp[4] + ((uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1) + 1) >> 1;
    dp[5] = (dp[5] + ((uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1) + 1) >> 1;
    dp[6] = (dp[6] + ((uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1) + 1) >> 1;
    dp[7] = (dp[7] + ((uint32_t)(s2 + sp[8] + 1) >> 1) + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rechac>:
  endbr64
  mov    %rsi,%rax
  mov    %ecx,%r8d
  test   %ecx,%ecx
  jle    L13
  movslq %edx,%rdx
  xor    %ecx,%ecx
  lea    0x0(,%rdx,4),%rsi
  nop
L3:
  mov    0x4(%rdi),%r10d
  mov    (%rdi),%edx
  add    %r10d,%edx
  add    $0x1,%edx
  sar    %edx
  add    (%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rax)
  mov    0x8(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x4(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x4(%rax)
  mov    0xc(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x8(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x8(%rax)
  mov    0x10(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0xc(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0xc(%rax)
  mov    0x14(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x10(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x10(%rax)
  mov    0x18(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x14(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x14(%rax)
  mov    0x1c(%rdi),%edx
  lea    0x1(%r9,%rdx,1),%r9d
  sar    %r9d
  add    0x18(%rax),%r9d
  add    $0x1,%r9d
  sar    %r9d
  mov    %r9d,0x18(%rax)
  add    0x20(%rdi),%edx
  add    $0x1,%edx
  sar    %edx
  add    0x1c(%rax),%edx
  add    $0x1,%ecx
  add    %rsi,%rdi
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rax)
  add    %rsi,%rax
  cmp    %ecx,%r8d
  jne    L3
L13:
  ret
```

assistant: ```c
void rechac(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (dp[0] + ((uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1) + 1) >> 1;
    dp[1] = (dp[1] + ((uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1) + 1) >> 1;
    dp[2] = (dp[2] + ((uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1) + 1) >> 1;
    dp[3] = (dp[3] + ((uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1) + 1) >> 1;
    dp[4] = (dp[4] + ((uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1) + 1) >> 1;
    dp[5] = (dp[5] + ((uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1) + 1) >> 1;
    dp[6] = (dp[6] + ((uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1) + 1) >> 1;
    dp[7] = (dp[7] + ((uint32_t)(s2 + sp[8] + 1) >> 1) + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rechac>:
  endbr64
  mov    %rsi,%rax
  mov    %ecx,%r8d
  test   %ecx,%ecx
  jle    L5
  movslq %edx,%rdx
  xor    %ecx,%ecx
  lea    0x0(,%rdx,4),%rsi
  nop
L8:
  mov    0x4(%rdi),%r10d
  mov    (%rdi),%edx
  add    %r10d,%edx
  add    $0x1,%edx
  sar    %edx
  add    (%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rax)
  mov    0x8(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x4(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x4(%rax)
  mov    0xc(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x8(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x8(%rax)
  mov    0x10(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0xc(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0xc(%rax)
  mov    0x14(%rdi),%r10d
  lea    0x1(%r9,%r10,1),%edx
  sar    %edx
  add    0x10(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x10(%rax)
  mov    0x18(%rdi),%r9d
  lea    0x1(%r10,%r9,1),%edx
  sar    %edx
  add    0x14(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x14(%rax)
  mov    0x1c(%rdi),%edx
  lea    0x1(%r9,%rdx,1),%r9d
  sar    %r9d
  add    0x18(%rax),%r9d
  add    $0x1,%r9d
  sar    %r9d
  mov    %r9d,0x18(%rax)
  add    0x20(%rdi),%edx
  add    $0x1,%edx
  sar    %edx
  add    0x1c(%rax),%edx
  add    $0x1,%ecx
  add    %rsi,%rdi
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rax)
  add    %rsi,%rax
  cmp    %ecx,%r8d
  jne    L8
L5:
  ret
```

assistant: ```c
void rechac(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (dp[0] + ((uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1) + 1) >> 1;
    dp[1] = (dp[1] + ((uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1) + 1) >> 1;
    dp[2] = (dp[2] + ((uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1) + 1) >> 1;
    dp[3] = (dp[3] + ((uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1) + 1) >> 1;
    dp[4] = (dp[4] + ((uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1) + 1) >> 1;
    dp[5] = (dp[5] + ((uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1) + 1) >> 1;
    dp[6] = (dp[6] + ((uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1) + 1) >> 1;
    dp[7] = (dp[7] + ((uint32_t)(s2 + sp[8] + 1) >> 1) + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<snapUpSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  jg     L3
  movl   $0x8,-0x14(%rbp)
  jmp    L2
L3:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int snapUpSize(int i) {
  if (i < 8) {
    i = 8;
  } else {
    unsigned int j;
    j = i;
    j |= (j >> 1);
    j |= (j >> 2);
    j |= (j >> 4);
    j |= (j >> 8);
    j |= (j >> 16);
    i = j + 1;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<snapUpSize>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x7,%edi
  jle    L0
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
L0:
  ret
```

assistant: ```c
int snapUpSize(int i) {
  if (i < 8) {
    i = 8;
  } else {
    unsigned int j;
    j = i;
    j |= (j >> 1);
    j |= (j >> 2);
    j |= (j >> 4);
    j |= (j >> 8);
    j |= (j >> 16);
    i = j + 1;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snapUpSize>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x7,%edi
  jle    L7
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
L7:
  ret
```

assistant: ```c
int snapUpSize(int i) {
  if (i < 8) {
    i = 8;
  } else {
    unsigned int j;
    j = i;
    j |= (j >> 1);
    j |= (j >> 2);
    j |= (j >> 4);
    j |= (j >> 8);
    j |= (j >> 16);
    i = j + 1;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<snapUpSize>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x7,%edi
  jle    L7
  mov    %edi,%eax
  shr    %eax
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  or     %edx,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
L7:
  ret
```

assistant: ```c
int snapUpSize(int i) {
  if (i < 8) {
    i = 8;
  } else {
    unsigned int j;
    j = i;
    j |= (j >> 1);
    j |= (j >> 2);
    j |= (j >> 4);
    j |= (j >> 8);
    j |= (j >> 16);
    i = j + 1;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L8:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(c)
char *c;
{
  int len = 0;
  while (*(c++) != '\0')
    len++;
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L21:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L21
L10:
  mov    %ecx,%eax
  ret
L14:
  mov    $0x0,%ecx
  jmp    L10
```

assistant: ```c
int strlen(c)
char *c;
{
  int len = 0;
  while (*(c++) != '\0')
    len++;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L5
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L6:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(c)
char *c;
{
  int len = 0;
  while (*(c++) != '\0')
    len++;
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L3
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L7:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L7
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(c)
char *c;
{
  int len = 0;
  while (*(c++) != '\0')
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isoneofN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L27:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L2
L13:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L27
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int isoneofN(char ch, const char *what, int size) {
  const char *end = what + size;
  while (what < end) {
    if (ch == *what++)
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isoneofN>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
L0:
  cmp    %rdx,%rsi
  jae    L6
  add    $0x1,%rsi
  cmp    %dil,-0x1(%rsi)
  jne    L0
  mov    $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isoneofN(char ch, const char *what, int size) {
  const char *end = what + size;
  while (what < end) {
    if (ch == *what++)
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isoneofN>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
  jmp    L2
  nopl   0x0(%rax)
L15:
  add    $0x1,%rsi
  cmp    %dil,-0x1(%rsi)
  je     L16
L2:
  cmp    %rdx,%rsi
  jb     L15
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isoneofN(char ch, const char *what, int size) {
  const char *end = what + size;
  while (what < end) {
    if (ch == *what++)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isoneofN>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
  jmp    L9
  nopl   0x0(%rax)
L4:
  add    $0x1,%rsi
  cmp    %dil,-0x1(%rsi)
  je     L26
L9:
  cmp    %rdx,%rsi
  jb     L4
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isoneofN(char ch, const char *what, int size) {
  const char *end = what + size;
  while (what < end) {
    if (ch == *what++)
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<revControlAll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movzbl -0x1c(%rbp),%eax
  mov    $0xffffff89,%edx
  mul    %dl
  shr    $0x8,%ax
  shr    $0x3,%al
  movzbl %al,%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <useRevOption@plt>
  nop
  leave
  ret
```

assistant: ```c
void revControlAll(void *d, unsigned char u) {
  struct b_whirl *w = (struct b_whirl *)d;
  useRevOption(w, (int)(u / 15), 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<revControlAll>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff89,%edx
  mov    %esi,%eax
  mul    %dl
  shr    $0xb,%ax
  movzbl %al,%esi
  mov    $0x2,%edx
  call   <useRevOption@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void revControlAll(void *d, unsigned char u) {
  struct b_whirl *w = (struct b_whirl *)d;
  useRevOption(w, (int)(u / 15), 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<revControlAll>:
  endbr64
  mov    $0xffffff89,%edx
  mov    %esi,%eax
  mul    %dl
  mov    $0x2,%edx
  shr    $0xb,%ax
  movzbl %al,%esi
  jmp    1050 <useRevOption@plt>
```

assistant: ```c
void revControlAll(void *d, unsigned char u) {
  struct b_whirl *w = (struct b_whirl *)d;
  useRevOption(w, (int)(u / 15), 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<revControlAll>:
  endbr64
  mov    $0xffffff89,%edx
  mov    %esi,%eax
  mul    %dl
  mov    $0x2,%edx
  shr    $0xb,%ax
  movzbl %al,%esi
  jmp    1050 <useRevOption@plt>
```

assistant: ```c
void revControlAll(void *d, unsigned char u) {
  struct b_whirl *w = (struct b_whirl *)d;
  useRevOption(w, (int)(u / 15), 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tvsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L0
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0xf4240(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tvsub(struct timeval *out, struct timeval *in) {
  if ((out->tv_usec -= in->tv_usec) < 0) {
    --out->tv_sec;
    out->tv_usec += 1000000;
  }
  out->tv_sec -= in->tv_sec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tvsub>:
  endbr64
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  mov    %rax,(%rdi)
  js     L19
L11:
  mov    0x8(%rsi),%rax
  sub    %rax,0x8(%rdi)
  ret
L19:
  subq   $0x1,0x8(%rdi)
  add    $0xf4240,%rax
  mov    %rax,(%rdi)
  jmp    L11
```

assistant: ```c
void tvsub(struct timeval *out, struct timeval *in) {
  if ((out->tv_usec -= in->tv_usec) < 0) {
    --out->tv_sec;
    out->tv_usec += 1000000;
  }
  out->tv_sec -= in->tv_sec;
}
```
user: What is the c source code of the assembly code below?

```asm
<tvsub>:
  endbr64
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  mov    %rax,(%rdi)
  mov    0x8(%rdi),%rdx
  jns    L1
  sub    $0x1,%rdx
  add    $0xf4240,%rax
  mov    %rdx,0x8(%rdi)
  mov    %rax,(%rdi)
L1:
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  ret
```

assistant: ```c
void tvsub(struct timeval *out, struct timeval *in) {
  if ((out->tv_usec -= in->tv_usec) < 0) {
    --out->tv_sec;
    out->tv_usec += 1000000;
  }
  out->tv_sec -= in->tv_sec;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tvsub>:
  endbr64
  mov    (%rdi),%rax
  sub    (%rsi),%rax
  mov    %rax,(%rdi)
  mov    0x8(%rdi),%rdx
  jns    L6
  sub    $0x1,%rdx
  add    $0xf4240,%rax
  mov    %rdx,0x8(%rdi)
  mov    %rax,(%rdi)
L6:
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%rdi)
  ret
```

assistant: ```c
void tvsub(struct timeval *out, struct timeval *in) {
  if ((out->tv_usec -= in->tv_usec) < 0) {
    --out->tv_sec;
    out->tv_usec += 1000000;
  }
  out->tv_sec -= in->tv_sec;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<WriteEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L10:
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x4,-0x4(%rbp)
  jle    L10
  mov    $0x3b9aca00,%esi
  mov    $0x0,%edi
  call   <WriteTone@plt>
  nop
  leave
  ret
```

assistant: ```c
void WriteEnd() {
  for (int i = 0; i < 5; i++)
    WriteFSK(1);
  WriteTone(0, 1e9);
}
```
user: What is the c source code of the assembly code below?

```asm
<WriteEnd>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x3b9aca00,%esi
  mov    $0x0,%edi
  call   <WriteTone@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void WriteEnd() {
  for (int i = 0; i < 5; i++)
    WriteFSK(1);
  WriteTone(0, 1e9);
}
```
user: What is the c source code of the assembly code below?

```asm
<WriteEnd>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x1,%edi
  call   <WriteFSK@plt>
  mov    $0x3b9aca00,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <WriteTone@plt>
```

assistant: ```c
void WriteEnd() {
  for (int i = 0; i < 5; i++)
    WriteFSK(1);
  WriteTone(0, 1e9);
}
```