ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__lltostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L14
  cmpl   $0x24,-0x20(%rbp)
  jle    L77
L14:
  movl   $0xa,-0x20(%rbp)
L77:
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L88
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  movl   $0x1,-0xc(%rbp)
  jmp    L88
L68:
  subq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L73
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  cmpb   $0x0,-0x2c(%rbp)
  je     L34
  mov    $0x7,%eax
  jmp    L12
L34:
  mov    $0x27,%eax
L12:
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L73:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x28(%rbp)
  addl   $0x1,-0xc(%rbp)
L88:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L87
  cmpq   $0x0,-0x28(%rbp)
  jne    L68
L87:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __lltostr(char *s, int size, unsigned long long i, int base, char UpCase) {
  char *tmp;
  unsigned int j = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += (UpCase ? 'A' : 'a') - '9' - 1;
    i = i / base;
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__lltostr>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%rdi
  lea    -0x1(%rsi),%r9d
  movslq %r9d,%r9
  add    %r10,%r9
  movb   $0x0,(%r9)
  test   %ecx,%ecx
  je     L32
  cmp    $0x24,%ecx
  jg     L32
L97:
  test   %rdi,%rdi
  jne    L38
  lea    -0x1(%r9),%rsi
  movb   $0x30,-0x1(%r9)
  mov    $0x1,%ebx
L75:
  lea    0x1(%rbx),%edx
  mov    %r10,%rdi
  call   <memmove@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L32:
  mov    $0xa,%ecx
  jmp    L97
L38:
  cmp    %r10,%r9
  jbe    L59
  cmp    $0x1,%r8b
  sbb    %r8d,%r8d
  and    $0x20,%r8d
  add    $0x7,%r8d
  mov    %r9,%rsi
  movslq %ecx,%rcx
  jmp    L31
L79:
  mov    %rax,%rdi
L31:
  sub    $0x1,%rsi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x30,%edx
  lea    (%rdx,%r8,1),%eax
  cmp    $0x3a,%dl
  cmovge %eax,%edx
  mov    %dl,(%rsi)
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %r9d,%ebx
  sub    %esi,%ebx
  cmp    %rsi,%r10
  jae    L75
  cmp    %rdi,%rcx
  jbe    L79
  jmp    L75
L59:
  mov    %r9,%rsi
  mov    $0x0,%ebx
  jmp    L75
```

assistant: ```c
int __lltostr(char *s, int size, unsigned long long i, int base, char UpCase) {
  char *tmp;
  unsigned int j = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += (UpCase ? 'A' : 'a') - '9' - 1;
    i = i / base;
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__lltostr>:
  endbr64
  lea    -0x1(%rsi),%r9d
  mov    %rdi,%r10
  push   %r12
  mov    %rdx,%rdi
  movslq %r9d,%r9
  add    %r10,%r9
  movb   $0x0,(%r9)
  test   %ecx,%ecx
  je     L3
  cmp    $0x24,%ecx
  jg     L3
  test   %rdi,%rdi
  je     L99
L7:
  cmp    %r10,%r9
  jbe    L55
  cmp    $0x1,%r8b
  movslq %ecx,%rcx
  mov    %r9,%rsi
  sbb    %r11d,%r11d
  and    $0x20,%r11d
  add    $0x7,%r11d
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rax,%rdi
L69:
  xor    %edx,%edx
  mov    %rdi,%rax
  sub    $0x1,%rsi
  div    %rcx
  add    $0x30,%edx
  cmp    $0x3a,%dl
  lea    (%rdx,%r11,1),%r8d
  cmovge %r8d,%edx
  mov    %dl,(%rsi)
  mov    %r9d,%edx
  sub    %esi,%edx
  cmp    %rsi,%r10
  jae    L57
  cmp    %rcx,%rdi
  jae    L26
L57:
  lea    0x1(%rdx),%r8d
  mov    %edx,%r12d
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0xa,%ecx
  test   %rdi,%rdi
  jne    L7
L99:
  movb   $0x30,-0x1(%r9)
  lea    -0x1(%r9),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%r8d
L6:
  mov    %r8d,%edx
  mov    %r10,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L55:
  mov    %r9,%rsi
  xor    %r12d,%r12d
  mov    $0x1,%r8d
  jmp    L6
```

assistant: ```c
int __lltostr(char *s, int size, unsigned long long i, int base, char UpCase) {
  char *tmp;
  unsigned int j = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += (UpCase ? 'A' : 'a') - '9' - 1;
    i = i / base;
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<__lltostr>:
  endbr64
  lea    -0x1(%rsi),%r10d
  mov    %rdi,%r9
  push   %r12
  mov    %rdx,%rdi
  movslq %r10d,%r10
  add    %r9,%r10
  movb   $0x0,(%r10)
  test   %ecx,%ecx
  je     L65
  cmp    $0x24,%ecx
  jg     L65
  test   %rdi,%rdi
  je     L52
L43:
  cmp    %r9,%r10
  jbe    L45
  cmp    $0x1,%r8b
  mov    %r10,%rsi
  movslq %ecx,%r8
  sbb    %r11d,%r11d
  and    $0x20,%r11d
  add    $0x7,%r11d
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rax,%rdi
L73:
  xor    %edx,%edx
  mov    %rdi,%rax
  sub    $0x1,%rsi
  div    %r8
  add    $0x30,%edx
  cmp    $0x39,%dl
  lea    (%r11,%rdx,1),%ecx
  cmovg  %ecx,%edx
  mov    %dl,(%rsi)
  mov    %r10d,%edx
  sub    %esi,%edx
  cmp    %rsi,%r9
  jae    L92
  cmp    %rdi,%r8
  jbe    L61
L92:
  lea    0x1(%rdx),%r8d
  mov    %edx,%r12d
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L65:
  mov    $0xa,%ecx
  test   %rdi,%rdi
  jne    L43
L52:
  movb   $0x30,-0x1(%r10)
  lea    -0x1(%r10),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%r8d
L19:
  mov    %r8d,%edx
  mov    %r9,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L45:
  mov    %r10,%rsi
  xor    %r12d,%r12d
  mov    $0x1,%r8d
  jmp    L19
```

assistant: ```c
int __lltostr(char *s, int size, unsigned long long i, int base, char UpCase) {
  char *tmp;
  unsigned int j = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += (UpCase ? 'A' : 'a') - '9' - 1;
    i = i / base;
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4f4e,-0x74(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L7
L33:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x48,%al
  je     L30
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x51,%al
  je     L30
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x39,%al
  jne    L10
L30:
  movb   $0x59,-0x74(%rbp)
  movb   $0x45,-0x73(%rbp)
  movb   $0x53,-0x72(%rbp)
L10:
  addl   $0x1,-0x78(%rbp)
L7:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x78(%rbp)
  jl     L33
  lea    -0x74(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: string

tool: D9: %s

tool: D16: %s


assistant: ```c
int main() {
  char s[101], ans[4] = "NO";
  scanf("%s", s);
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == 'H' || s[i] == 'Q' || s[i] == '9')
      ans[0] = 'Y', ans[1] = 'E', ans[2] = 'S';
  }
  printf("%s\n", ans);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x4f4e,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
  jmp    L29
L17:
  mov    $0x1008001,%edx
  bt     %rax,%rdx
  jae    L8
  movb   $0x59,0xc(%rsp)
  movb   $0x45,0xd(%rsp)
  movb   $0x53,0xe(%rsp)
L8:
  add    $0x1,%rbx
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L45
  movzbl (%rbx,%rbp,1),%eax
  sub    $0x39,%eax
  cmp    $0x18,%al
  ja     L8
  jmp    L17
L45:
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string

tool: D12: %s

tool: D5: %s


assistant: ```c
int main() {
  char s[101], ans[4] = "NO";
  scanf("%s", s);
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == 'H' || s[i] == 'Q' || s[i] == '9')
      ans[0] = 'Y', ans[1] = 'E', ans[2] = 'S';
  }
  printf("%s\n", ans);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  mov    $0xfffffffffeff7ffe,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movl   $0x4f4e,0xc(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x39,%eax
  cmp    $0x18,%al
  ja     L10
  bt     %rax,%r12
  jb     L10
  mov    $0x4559,%eax
  movb   $0x53,0xe(%rsp)
  mov    %ax,0xc(%rsp)
L10:
  add    $0x1,%rbx
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L6
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D0
data_type: string

tool: D14: %s

tool: D0: %s


assistant: ```c
int main() {
  char s[101], ans[4] = "NO";
  scanf("%s", s);
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == 'H' || s[i] == 'Q' || s[i] == '9')
      ans[0] = 'Y', ans[1] = 'E', ans[2] = 'S';
  }
  printf("%s\n", ans);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  mov    $0xfffffffffeff7ffe,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movl   $0x4f4e,0xc(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L0:
  movzbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x39,%eax
  cmp    $0x18,%al
  ja     L30
  bt     %rax,%r12
  jb     L30
  mov    $0x4559,%eax
  movb   $0x53,0xe(%rsp)
  mov    %ax,0xc(%rsp)
L30:
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D5
type: string

tool: D16: %s

tool: D5: %s


assistant: ```c
int main() {
  char s[101], ans[4] = "NO";
  scanf("%s", s);
  int i;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == 'H' || s[i] == 'Q' || s[i] == '9')
      ans[0] = 'Y', ans[1] = 'E', ans[2] = 'S';
  }
  printf("%s\n", ans);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L62
L73:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  je     L84
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L54
L84:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L56
L54:
  movl   $0x1,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L49
L65:
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L38
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  add    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L38:
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L65
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jne    L87
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L87:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L56:
  addl   $0x1,-0x14(%rbp)
L62:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L73
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D37
datatype: string

tool: D0: %d

tool: D7: 0

tool: D37: %d


assistant: ```c
int main() {
  int t, s, i, j, a, q;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a);
    if (a == 1 || a == 0) {
      printf("0\n");
      continue;
    }
    s = 1;
    q = sqrt(a);
    for (j = 2; j <= q; j++)
      if (a % j == 0)
        s = s + j + a / j;
    if (q * q == a)
      s = s - q;
    printf("%d\n", s);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L118
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
  lea    D16(%rip),%rbp
  lea    D24(%rip),%r13
  lea    D18(%rip),%r14
  jmp    L111
L16:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L56
L97:
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  je     L55
L67:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L97
  add    %ecx,%esi
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %eax,%esi
  jmp    L97
L12:
  mov    $0x1,%esi
L55:
  mov    %r9d,%eax
  imul   %r9d,%eax
  cmp    0x4(%rsp),%eax
  je     L57
L116:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L56:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L118
L111:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jbe    L16
  call   <sqrt@plt>
  mov    %eax,%r9d
  cmp    $0x1,%eax
  jle    L12
  mov    0x4(%rsp),%edi
  lea    0x1(%rax),%r8d
  mov    $0x2,%ecx
  mov    $0x1,%esi
  jmp    L67
L57:
  sub    %r9d,%esi
  jmp    L116
L118:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D24
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D16: %d

tool: D24: %d


tool: D18: 0

assistant: ```c
int main() {
  int t, s, i, j, a, q;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a);
    if (a == 1 || a == 0) {
      printf("0\n");
      continue;
    }
    s = 1;
    q = sqrt(a);
    for (j = 2; j <= q; j++)
      if (a % j == 0)
        s = s + j + a / j;
    if (q * q == a)
      s = s - q;
    printf("%d\n", s);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jg     L73
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    %ebx,(%rsp)
  jle    L55
L73:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jbe    L33
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%r9d
  cmp    $0x1,%eax
  jle    L56
  lea    0x1(%rax),%r8d
  mov    $0x2,%ecx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %edi,%eax
  lea    (%rsi,%rcx,1),%r10d
  cltd
  idiv   %ecx
  add    %r10d,%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L71
L58:
  mov    %r9d,%edx
  mov    %esi,%eax
  imul   %r9d,%edx
  sub    %r9d,%eax
  cmp    %edi,%edx
  mov    %r13,%rdi
  cmove  %eax,%esi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L73
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    $0x1,%esi
  jmp    L58
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string

tool: D22: 0

tool: D10: %d


tool: D13: %d

assistant: ```c
int main() {
  int t, s, i, j, a, q;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a);
    if (a == 1 || a == 0) {
      printf("0\n");
      continue;
    }
    s = 1;
    q = sqrt(a);
    for (j = 2; j <= q; j++)
      if (a % j == 0)
        s = s + j + a / j;
    if (q * q == a)
      s = s - q;
    printf("%d\n", s);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jg     L27
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    %ebx,(%rsp)
  jle    L8
L27:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jbe    L75
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%r9d
  cmp    $0x1,%eax
  jle    L62
  lea    0x1(%rax),%r8d
  mov    $0x2,%ecx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %edi,%eax
  lea    (%rsi,%rcx,1),%r10d
  cltd
  idiv   %ecx
  add    %r10d,%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L15
L68:
  mov    %r9d,%edx
  mov    %esi,%eax
  imul   %r9d,%edx
  sub    %r9d,%eax
  cmp    %edi,%edx
  mov    %r13,%rdi
  cmove  %eax,%esi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L27
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L62:
  mov    $0x1,%esi
  jmp    L68
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D23
data_type: string

tool: D19: 0

tool: D15: %d


tool: D23: %d

assistant: ```c
int main() {
  int t, s, i, j, a, q;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &a);
    if (a == 1 || a == 0) {
      printf("0\n");
      continue;
    }
    s = 1;
    q = sqrt(a);
    for (j = 2; j <= q; j++)
      if (a % j == 0)
        s = s + j + a / j;
    if (q * q == a)
      s = s - q;
    printf("%d\n", s);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mem_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mf__mem_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_alloc(size);
  ;
  return (r_ptr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mem_alloc>:
  endbr64
  sub    $0x8,%rsp
  call   <mf__mem_alloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_alloc(size);
  ;
  return (r_ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mem_alloc>:
  endbr64
  jmp    1050 <mf__mem_alloc@plt>
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_alloc(size);
  ;
  return (r_ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mem_alloc>:
  endbr64
  jmp    1050 <mf__mem_alloc@plt>
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_alloc(size);
  ;
  return (r_ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xdrmem_getlong_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L7
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L10
L7:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  add    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L10:
  leave
  ret
```

assistant: ```c
bool_t xdrmem_getlong_aligned(XDR *xdrs, long *lp) {
  if ((xdrs->x_handy -= sizeof(int32_t)) < 0)
    return (FALSE);
  *lp = ntohl(*(int32_t *)(xdrs->x_private));
  xdrs->x_private += sizeof(int32_t);
  return (TRUE);
}
```