ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bash_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,D9(%rip)
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L27
L5:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7b,%al
  jne    L36
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L36
  addq   $0x1,-0x10(%rbp)
  jmp    L23
L36:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L23:
  addq   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D9(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *bash_color(const char *txt) {
  const char *point;
  char *point2;
  static char buf[8192 * 4];
  buf[0] = '\0';
  point2 = buf;
  for (point = txt; *point; point++) {
    if (*point == '{' && *(point + 1) != '\0') {
      point++;
      continue;
    }
    *point2 = *point;
    *++point2 = '\0';
  }
  *point2 = '\0';
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bash_color>:
  endbr64
  movb   $0x0,D7(%rip)
  movzbl (%rdi),%eax
  lea    D7(%rip),%rdx
  test   %al,%al
  jne    L27
L42:
  movb   $0x0,(%rdx)
  lea    D7(%rip),%rax
  ret
L24:
  mov    %al,(%rdx)
  movb   $0x0,0x1(%rdx)
  lea    0x1(%rdx),%rdx
  mov    %rdi,%rax
L21:
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L42
L27:
  cmp    $0x7b,%al
  jne    L24
  cmpb   $0x0,0x1(%rdi)
  je     L24
  lea    0x1(%rdi),%rax
  jmp    L21
```

assistant: ```c
char *bash_color(const char *txt) {
  const char *point;
  char *point2;
  static char buf[8192 * 4];
  buf[0] = '\0';
  point2 = buf;
  for (point = txt; *point; point++) {
    if (*point == '{' && *(point + 1) != '\0') {
      point++;
      continue;
    }
    *point2 = *point;
    *++point2 = '\0';
  }
  *point2 = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bash_color>:
  endbr64
  movb   $0x0,D7(%rip)
  movzbl (%rdi),%eax
  lea    D7(%rip),%r8
  mov    %r8,%rdx
  test   %al,%al
  jne    L32
  jmp    L53
  xchg   %ax,%ax
L7:
  mov    %al,(%rdx)
  mov    %rdi,%rax
  add    $0x1,%rdx
  movb   $0x0,(%rdx)
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L53
L32:
  cmp    $0x7b,%al
  jne    L7
  cmpb   $0x0,0x1(%rdi)
  je     L7
  lea    0x1(%rdi),%rax
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L32
L53:
  movb   $0x0,(%rdx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *bash_color(const char *txt) {
  const char *point;
  char *point2;
  static char buf[8192 * 4];
  buf[0] = '\0';
  point2 = buf;
  for (point = txt; *point; point++) {
    if (*point == '{' && *(point + 1) != '\0') {
      point++;
      continue;
    }
    *point2 = *point;
    *++point2 = '\0';
  }
  *point2 = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bash_color>:
  endbr64
  movb   $0x0,D6(%rip)
  movzbl (%rdi),%eax
  lea    D6(%rip),%r8
  mov    %r8,%rdx
  test   %al,%al
  jne    L29
  jmp    L14
  xchg   %ax,%ax
L3:
  mov    %al,(%rdx)
  mov    %rdi,%rax
  add    $0x1,%rdx
  movb   $0x0,(%rdx)
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L14
L29:
  cmp    $0x7b,%al
  jne    L3
  cmpb   $0x0,0x1(%rdi)
  je     L3
  lea    0x1(%rdi),%rax
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L29
L14:
  movb   $0x0,(%rdx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *bash_color(const char *txt) {
  const char *point;
  char *point2;
  static char buf[8192 * 4];
  buf[0] = '\0';
  point2 = buf;
  for (point = txt; *point; point++) {
    if (*point == '{' && *(point + 1) != '\0') {
      point++;
      continue;
    }
    *point2 = *point;
    *++point2 = '\0';
  }
  *point2 = '\0';
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DIABLO_Mobility_DownloadByIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getpagesize@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x28(%rbp)
  lea    -0x18(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <acclExchange@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L65
  mov    -0x28(%rbp),%eax
  test   %eax,%eax
  je     L86
  mov    -0x28(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x24(%rbp)
  mov    %eax,%ecx
  mov    -0x28(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x24(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L42
  mov    $0x1,%eax
  jmp    L88
L42:
  mov    $0x0,%eax
L88:
  add    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%ecx
  lea    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L9
L0:
  lea    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  jmp    L9
L86:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L9
L65:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
void *DIABLO_Mobility_DownloadByIndex(unsigned int block_index, unsigned int *block_length) {
  ;
  unsigned int page_size, buffer_size, ret, full_pages;
  void *temp_buffer, *out_buffer;
  page_size = getpagesize();
  buffer_size = page_size * 2;
  ret = acclExchange(20, (int)sizeof(unsigned int), (char *)&block_index, &buffer_size, (char **)&temp_buffer);
  if (0 == ret) {
    ;
    if (buffer_size > 0) {
      full_pages = buffer_size / page_size + (buffer_size % page_size > 0 ? 1 : 0);
      ;
      if (0 != posix_memalign(&out_buffer, page_size, full_pages * page_size)) {
        free(temp_buffer);
        return 0;
      }
      memcpy(block_length, &buffer_size, sizeof(unsigned int));
      memcpy(out_buffer, temp_buffer, buffer_size);
      ;
    } else {
      free(temp_buffer);
      return 0;
    }
  } else {
    free(temp_buffer);
    return 0;
  }
  free(temp_buffer);
  return out_buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DIABLO_Mobility_DownloadByIndex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <getpagesize@plt>
  mov    %eax,%ebx
  lea    (%rax,%rax,1),%eax
  mov    %eax,0x14(%rsp)
  lea    0x14(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x18(%rsp),%r8
  mov    $0x4,%esi
  mov    $0x14,%edi
  call   <acclExchange@plt>
  test   %eax,%eax
  jne    L4
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L45
  mov    $0x0,%edx
  div    %ebx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %ebx,%eax
  mov    %eax,%edx
  lea    0x20(%rsp),%rdi
  mov    %ebx,%esi
  call   <posix_memalign@plt>
  test   %rax,%rax
  jne    L44
  lea    0x14(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x14(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    0x20(%rsp),%rax
L49:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L49
L45:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L49
L4:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L49
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *DIABLO_Mobility_DownloadByIndex(unsigned int block_index, unsigned int *block_length) {
  ;
  unsigned int page_size, buffer_size, ret, full_pages;
  void *temp_buffer, *out_buffer;
  page_size = getpagesize();
  buffer_size = page_size * 2;
  ret = acclExchange(20, (int)sizeof(unsigned int), (char *)&block_index, &buffer_size, (char **)&temp_buffer);
  if (0 == ret) {
    ;
    if (buffer_size > 0) {
      full_pages = buffer_size / page_size + (buffer_size % page_size > 0 ? 1 : 0);
      ;
      if (0 != posix_memalign(&out_buffer, page_size, full_pages * page_size)) {
        free(temp_buffer);
        return 0;
      }
      memcpy(block_length, &buffer_size, sizeof(unsigned int));
      memcpy(out_buffer, temp_buffer, buffer_size);
      ;
    } else {
      free(temp_buffer);
      return 0;
    }
  } else {
    free(temp_buffer);
    return 0;
  }
  free(temp_buffer);
  return out_buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DIABLO_Mobility_DownloadByIndex>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <getpagesize@plt>
  lea    0xc(%rsp),%rdx
  lea    0x18(%rsp),%r8
  mov    %r13,%rcx
  mov    %eax,%ebp
  mov    $0x4,%esi
  add    %eax,%eax
  mov    $0x14,%edi
  mov    %eax,0x14(%rsp)
  call   <acclExchange@plt>
  test   %eax,%eax
  jne    L31
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L31
  xor    %edx,%edx
  lea    0x20(%rsp),%rdi
  mov    %ebp,%esi
  div    %ebp
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  call   <posix_memalign@plt>
  test   %rax,%rax
  jne    L31
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    0x14(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    0x20(%rsp),%rax
L14:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L14
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *DIABLO_Mobility_DownloadByIndex(unsigned int block_index, unsigned int *block_length) {
  ;
  unsigned int page_size, buffer_size, ret, full_pages;
  void *temp_buffer, *out_buffer;
  page_size = getpagesize();
  buffer_size = page_size * 2;
  ret = acclExchange(20, (int)sizeof(unsigned int), (char *)&block_index, &buffer_size, (char **)&temp_buffer);
  if (0 == ret) {
    ;
    if (buffer_size > 0) {
      full_pages = buffer_size / page_size + (buffer_size % page_size > 0 ? 1 : 0);
      ;
      if (0 != posix_memalign(&out_buffer, page_size, full_pages * page_size)) {
        free(temp_buffer);
        return 0;
      }
      memcpy(block_length, &buffer_size, sizeof(unsigned int));
      memcpy(out_buffer, temp_buffer, buffer_size);
      ;
    } else {
      free(temp_buffer);
      return 0;
    }
  } else {
    free(temp_buffer);
    return 0;
  }
  free(temp_buffer);
  return out_buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DIABLO_Mobility_DownloadByIndex>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x14(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <getpagesize@plt>
  lea    0xc(%rsp),%rdx
  lea    0x18(%rsp),%r8
  mov    %r13,%rcx
  mov    %eax,%ebp
  mov    $0x4,%esi
  add    %eax,%eax
  mov    $0x14,%edi
  mov    %eax,0x14(%rsp)
  call   <acclExchange@plt>
  test   %eax,%eax
  jne    L0
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L0
  xor    %edx,%edx
  lea    0x20(%rsp),%rdi
  mov    %ebp,%esi
  div    %ebp
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  imul   %ebp,%eax
  mov    %eax,%edx
  call   <posix_memalign@plt>
  test   %rax,%rax
  jne    L0
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    0x14(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  mov    0x20(%rsp),%rax
L35:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L35
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *DIABLO_Mobility_DownloadByIndex(unsigned int block_index, unsigned int *block_length) {
  ;
  unsigned int page_size, buffer_size, ret, full_pages;
  void *temp_buffer, *out_buffer;
  page_size = getpagesize();
  buffer_size = page_size * 2;
  ret = acclExchange(20, (int)sizeof(unsigned int), (char *)&block_index, &buffer_size, (char **)&temp_buffer);
  if (0 == ret) {
    ;
    if (buffer_size > 0) {
      full_pages = buffer_size / page_size + (buffer_size % page_size > 0 ? 1 : 0);
      ;
      if (0 != posix_memalign(&out_buffer, page_size, full_pages * page_size)) {
        free(temp_buffer);
        return 0;
      }
      memcpy(block_length, &buffer_size, sizeof(unsigned int));
      memcpy(out_buffer, temp_buffer, buffer_size);
      ;
    } else {
      free(temp_buffer);
      return 0;
    }
  } else {
    free(temp_buffer);
    return 0;
  }
  free(temp_buffer);
  return out_buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matFitHelix>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int matFitHelix(double p1[3], double p2[3], double p3[3], double ret[3]) {
  double A, B, C, D;
  double P, Q;
  double U, V, W;
  A = 2.3 * cos(2.0 * M_PI / 3.6);
  B = 2.3 * sin(2.0 * M_PI / 3.6);
  C = 2.3 * cos(4.0 * M_PI / 3.6);
  D = 2.3 * sin(4.0 * M_PI / 3.6);
  P = 2.0 * A - 2.3 - C;
  Q = 2.0 * B - D;
  U = 2 * p2[0] - p1[0] - p3[0];
  V = 2 * p2[1] - p1[1] - p3[1];
  W = 2 * p2[2] - p1[2] - p3[2];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matFitHelix>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int matFitHelix(double p1[3], double p2[3], double p3[3], double ret[3]) {
  double A, B, C, D;
  double P, Q;
  double U, V, W;
  A = 2.3 * cos(2.0 * M_PI / 3.6);
  B = 2.3 * sin(2.0 * M_PI / 3.6);
  C = 2.3 * cos(4.0 * M_PI / 3.6);
  D = 2.3 * sin(4.0 * M_PI / 3.6);
  P = 2.0 * A - 2.3 - C;
  Q = 2.0 * B - D;
  U = 2 * p2[0] - p1[0] - p3[0];
  V = 2 * p2[1] - p1[1] - p3[1];
  W = 2 * p2[2] - p1[2] - p3[2];
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matFitHelix>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int matFitHelix(double p1[3], double p2[3], double p3[3], double ret[3]) {
  double A, B, C, D;
  double P, Q;
  double U, V, W;
  A = 2.3 * cos(2.0 * M_PI / 3.6);
  B = 2.3 * sin(2.0 * M_PI / 3.6);
  C = 2.3 * cos(4.0 * M_PI / 3.6);
  D = 2.3 * sin(4.0 * M_PI / 3.6);
  P = 2.0 * A - 2.3 - C;
  Q = 2.0 * B - D;
  U = 2 * p2[0] - p1[0] - p3[0];
  V = 2 * p2[1] - p1[1] - p3[1];
  W = 2 * p2[2] - p1[2] - p3[2];
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L25:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L11
  cmpl   $0xb503,-0x4(%rbp)
  jle    L25
L11:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  imul   %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L24
L4:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int ft_sqrt(int nb) {
  int i;
  i = 1;
  while (i * i <= nb && i < 46340)
    i++;
  if ((i - 1) * (i - 1) == nb)
    return (i - 1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_sqrt>:
  endbr64
  test   %edi,%edi
  jle    L15
  mov    $0x1,%edx
L13:
  add    $0x1,%edx
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %edi,%eax
  jg     L26
  cmp    $0xb503,%edx
  jle    L13
L26:
  lea    -0x1(%rdx),%eax
  imul   %eax,%eax
  sub    $0x1,%edx
  cmp    %edi,%eax
  mov    $0x0,%eax
  cmove  %edx,%eax
  ret
L15:
  mov    $0x1,%edx
  jmp    L26
```

assistant: ```c
int ft_sqrt(int nb) {
  int i;
  i = 1;
  while (i * i <= nb && i < 46340)
    i++;
  if ((i - 1) * (i - 1) == nb)
    return (i - 1);
  else
    return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_sqrt>:
  endbr64
  test   %edi,%edi
  jle    L22
  mov    $0x1,%eax
  jmp    L8
  nop
L37:
  cmp    $0xb504,%eax
  je     L26
L8:
  mov    %eax,%r8d
  lea    0x1(%rax),%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jle    L37
  mov    %r8d,%eax
  imul   %r8d,%eax
L11:
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L26:
  mov    $0x7ffd3e09,%eax
  mov    $0xb503,%r8d
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L22:
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
int ft_sqrt(int nb) {
  int i;
  i = 1;
  while (i * i <= nb && i < 46340)
    i++;
  if ((i - 1) * (i - 1) == nb)
    return (i - 1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_sqrt>:
  endbr64
  test   %edi,%edi
  jle    L26
  mov    $0x1,%eax
  jmp    L5
  nop
L29:
  cmp    $0xb504,%eax
  je     L6
L5:
  mov    %eax,%r8d
  lea    0x1(%rax),%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jle    L29
  mov    %r8d,%eax
  imul   %r8d,%eax
L0:
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L6:
  mov    $0x7ffd3e09,%eax
  mov    $0xb503,%r8d
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
L26:
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L0
```

assistant: ```c
int ft_sqrt(int nb) {
  int i;
  i = 1;
  while (i * i <= nb && i < 46340)
    i++;
  if ((i - 1) * (i - 1) == nb)
    return (i - 1);
  else
    return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L16
  mov    $0x0,%eax
  jmp    L6
L16:
  cmpl   $0x2,-0x14(%rbp)
  jne    L80
  mov    $0x1,%eax
  jmp    L6
L80:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L58
  mov    $0x0,%eax
  jmp    L6
L58:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L69
L86:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L59
  mov    $0x0,%eax
  jmp    L6
L59:
  addl   $0x1,-0x8(%rbp)
L69:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jae    L86
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n <= 1)
    return 0;
  else if (n == 2)
    return 1;
  else if (n % 2 == 0)
    return 0;
  float root = sqrt(n);
  int i;
  for (i = 3; i <= root; i += 1)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L57
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L35
  mov    $0x0,%eax
  test   $0x1,%dil
  jne    L14
L35:
  pop    %rbx
  ret
L14:
  call   <sqrt@plt>
  comiss D4(%rip),%xmm0
  jb     L62
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L35
  mov    $0x3,%ecx
L16:
  add    $0x1,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  comiss %xmm1,%xmm0
  jb     L73
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L16
  jmp    L35
L73:
  mov    $0x1,%eax
  jmp    L35
L62:
  mov    $0x1,%eax
  jmp    L35
L57:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: byte[4]

tool: {"D4": [0x00,0x00,0x40,0x40]}

assistant: ```c
int is_prime(int n) {
  if (n <= 1)
    return 0;
  else if (n == 2)
    return 1;
  else if (n % 2 == 0)
    return 0;
  float root = sqrt(n);
  int i;
  for (i = 3; i <= root; i += 1)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L1
  test   $0x1,%dil
  jne    L79
L76:
  xor    %eax,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L79:
  call   <sqrt@plt>
  comiss D7(%rip),%xmm0
  jb     L1
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L76
  mov    $0x3,%ecx
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L76
L35:
  add    $0x1,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  comiss %xmm1,%xmm0
  jae    L57
L1:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: byte[4]

tool: {"D7": [0x00,0x00,0x40,0x40]}

assistant: ```c
int is_prime(int n) {
  if (n <= 1)
    return 0;
  else if (n == 2)
    return 1;
  else if (n % 2 == 0)
    return 0;
  float root = sqrt(n);
  int i;
  for (i = 3; i <= root; i += 1)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L73
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L50
  test   $0x1,%dil
  jne    L2
L27:
  xor    %eax,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  call   <sqrt@plt>
  comiss D7(%rip),%xmm0
  jb     L50
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L27
  mov    $0x3,%ecx
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L27
L48:
  add    $0x1,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  comiss %xmm1,%xmm0
  jae    L62
L50:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: byte[4]

tool: {"D7": [0x00,0x00,0x40,0x40]}

assistant: ```c
int is_prime(int n) {
  if (n <= 1)
    return 0;
  else if (n == 2)
    return 1;
  else if (n % 2 == 0)
    return 0;
  float root = sqrt(n);
  int i;
  for (i = 3; i <= root; i += 1)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<restore_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x30,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int restore_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(48, a, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<restore_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x30,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int restore_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(48, a, b, c);
  return fail;
}
```