ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
L6:
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: 
 Inside func2 


assistant: ```c
void func2(void) {
  printf("\n Inside func2 \n");
  int i = 0;
  for (; i < 0xffffffaa; i++)
    ;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x80(%rbp)
  movl   $0x1,-0x7c(%rbp)
  movl   $0x9,-0x78(%rbp)
  movl   $0xa,-0x74(%rbp)
  movl   $0xb,-0x70(%rbp)
  movl   $0x63,-0x6c(%rbp)
  movl   $0x64,-0x68(%rbp)
  movl   $0x65,-0x64(%rbp)
  movl   $0x3e7,-0x60(%rbp)
  movl   $0x3e8,-0x5c(%rbp)
  movl   $0x3e9,-0x58(%rbp)
  movl   $0x270f,-0x54(%rbp)
  movl   $0x2710,-0x50(%rbp)
  movl   $0x2711,-0x4c(%rbp)
  movl   $0x1869f,-0x48(%rbp)
  movl   $0x186a0,-0x44(%rbp)
  movl   $0x186a1,-0x40(%rbp)
  movl   $0xf423f,-0x3c(%rbp)
  movl   $0xf4240,-0x38(%rbp)
  movl   $0xf4241,-0x34(%rbp)
  movl   $0x98967f,-0x30(%rbp)
  movl   $0x989680,-0x2c(%rbp)
  movl   $0x989681,-0x28(%rbp)
  movl   $0x5f5e0ff,-0x24(%rbp)
  movl   $0x5f5e100,-0x20(%rbp)
  movl   $0x5f5e101,-0x1c(%rbp)
  movl   $0x3b9ac9ff,-0x18(%rbp)
  movl   $0x3b9aca00,-0x14(%rbp)
  movl   $0x3b9aca01,-0x10(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x88(%rbp)
  jmp    L6
L22:
  addq   $0x1,-0x88(%rbp)
L6:
  cmpq   $0x1d,-0x88(%rbp)
  jbe    L22
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void test(void) {
  size_t i;
  const uint32_t arr[] = {0, 1, 9, 10, 11, 99, 100, 101, 999, 1000, 1001, 9999, 10000, 10001, 99999, 100000, 100001, 999999, 1000000, 1000001, 9999999, 10000000, 10000001, 99999999, 100000000, 100000001, 999999999, 1000000000, 1000000001, UINT_MAX};
  for (i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  mov    $0x1e,%eax
L8:
  sub    $0x1,%rax
  jne    L8
  ret
```

assistant: ```c
void test(void) {
  size_t i;
  const uint32_t arr[] = {0, 1, 9, 10, 11, 99, 100, 101, 999, 1000, 1001, 9999, 10000, 10001, 99999, 100000, 100001, 999999, 1000000, 1000001, 9999999, 10000000, 10000001, 99999999, 100000000, 100000001, 999999999, 1000000000, 1000000001, UINT_MAX};
  for (i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test(void) {
  size_t i;
  const uint32_t arr[] = {0, 1, 9, 10, 11, 99, 100, 101, 999, 1000, 1001, 9999, 10000, 10001, 99999, 100000, 100001, 999999, 1000000, 1000001, 9999999, 10000000, 10000001, 99999999, 100000000, 100000001, 999999999, 1000000000, 1000000001, UINT_MAX};
  for (i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test(void) {
  size_t i;
  const uint32_t arr[] = {0, 1, 9, 10, 11, 99, 100, 101, 999, 1000, 1001, 9999, 10000, 10001, 99999, 100000, 100001, 999999, 1000000, 1000001, 9999999, 10000000, 10000001, 99999999, 100000000, 100000001, 999999999, 1000000000, 1000000001, UINT_MAX};
  for (i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tt_saveCoordsToFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tt_chktop@plt>
  test   %rax,%rax
  je     L6
  mov    $0xfffffffb,%eax
  jmp    L8
L6:
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x24(%rbp),%r8d
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <l_saveCoordsToFile@plt>
  add    $0x10,%rsp
L8:
  leave
  ret
```

assistant: ```c
int tt_saveCoordsToFile(FILE *outfile, char *buf, int maxLen, int table, long top, int isOrig, char *sep) {
  if (tt_chktop(&table, &top))
    return -5;
  return l_saveCoordsToFile(outfile, buf, maxLen, table, top, isOrig, sep);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tt_saveCoordsToFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,0xc(%rsp)
  mov    %r8,(%rsp)
  mov    %r9d,%r13d
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <tt_chktop@plt>
  test   %rax,%rax
  jne    L8
  sub    $0x8,%rsp
  push   0x48(%rsp)
  mov    %r13d,%r9d
  mov    0x10(%rsp),%r8
  mov    0x1c(%rsp),%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <l_saveCoordsToFile@plt>
  add    $0x10,%rsp
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    $0xfffffffb,%eax
  jmp    L0
```

assistant: ```c
int tt_saveCoordsToFile(FILE *outfile, char *buf, int maxLen, int table, long top, int isOrig, char *sep) {
  if (tt_chktop(&table, &top))
    return -5;
  return l_saveCoordsToFile(outfile, buf, maxLen, table, top, isOrig, sep);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tt_saveCoordsToFile>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  mov    %ecx,0xc(%rsp)
  mov    %r8,(%rsp)
  call   <tt_chktop@plt>
  test   %rax,%rax
  jne    L8
  sub    $0x8,%rsp
  mov    %r13d,%edx
  mov    %ebx,%r9d
  mov    %r12,%rsi
  push   0x48(%rsp)
  mov    0x10(%rsp),%r8
  mov    %rbp,%rdi
  mov    0x1c(%rsp),%ecx
  call   <l_saveCoordsToFile@plt>
  pop    %rdx
  pop    %rcx
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xfffffffb,%eax
  jmp    L13
```

assistant: ```c
int tt_saveCoordsToFile(FILE *outfile, char *buf, int maxLen, int table, long top, int isOrig, char *sep) {
  if (tt_chktop(&table, &top))
    return -5;
  return l_saveCoordsToFile(outfile, buf, maxLen, table, top, isOrig, sep);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tt_saveCoordsToFile>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  mov    %ecx,0xc(%rsp)
  mov    %r8,(%rsp)
  call   <tt_chktop@plt>
  test   %rax,%rax
  jne    L7
  sub    $0x8,%rsp
  mov    %r13d,%edx
  mov    %ebx,%r9d
  mov    %r12,%rsi
  push   0x48(%rsp)
  mov    0x10(%rsp),%r8
  mov    %rbp,%rdi
  mov    0x1c(%rsp),%ecx
  call   <l_saveCoordsToFile@plt>
  pop    %rdx
  pop    %rcx
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xfffffffb,%eax
  jmp    L12
```

assistant: ```c
int tt_saveCoordsToFile(FILE *outfile, char *buf, int maxLen, int table, long top, int isOrig, char *sep) {
  if (tt_chktop(&table, &top))
    return -5;
  return l_saveCoordsToFile(outfile, buf, maxLen, table, top, isOrig, sep);
}
```
user: What is the c source code of the assembly code below:

```asm
<reboot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cli
  mov    $0xfe,%al
  out    %al,$0x64
```

assistant: ```c
void reboot() {
  asm volatile("cli");
  asm volatile("mov $0xFE, %al");
  asm volatile("out %al, $0x64");
  asm volatile("halt:jmp halt");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reboot>:
  endbr64
  cli
  mov    $0xfe,%al
  out    %al,$0x64
```

assistant: ```c
void reboot() {
  asm volatile("cli");
  asm volatile("mov $0xFE, %al");
  asm volatile("out %al, $0x64");
  asm volatile("halt:jmp halt");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reboot>:
  endbr64
  cli
  mov    $0xfe,%al
  out    %al,$0x64
```

assistant: ```c
void reboot() {
  asm volatile("cli");
  asm volatile("mov $0xFE, %al");
  asm volatile("out %al, $0x64");
  asm volatile("halt:jmp halt");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reboot>:
  endbr64
  cli
  mov    $0xfe,%al
  out    %al,$0x64
```

assistant: ```c
void reboot() {
  asm volatile("cli");
  asm volatile("mov $0xFE, %al");
  asm volatile("out %al, $0x64");
  asm volatile("halt:jmp halt");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initArrays@plt>
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  initArrays();
  print();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initArrays@plt>
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initArrays();
  print();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initArrays@plt>
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initArrays();
  print();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initArrays@plt>
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initArrays();
  print();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bcon_calc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x38,%rax
  movsd  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x3,-0x4(%rbp)
  jle    L3
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bcon_calc(double *pr, double *ucon, double *ucov, double *bcon) {
  int j;
  bcon[(0)] = pr[(5)] * ucov[1] + pr[(6)] * ucov[2] + pr[(7)] * ucov[3];
  for (j = 1; j < 4; j++)
    bcon[j] = (pr[(5) - 1 + j] + bcon[(0)] * ucon[j]) / ucon[(0)];
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bcon_calc>:
  endbr64
  movsd  0x28(%rdi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  0x10(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  mov    $0x8,%eax
L7:
  movsd  (%rcx),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  0x20(%rdi,%rax,1),%xmm0
  divsd  (%rsi),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L7
  ret
```

assistant: ```c
void bcon_calc(double *pr, double *ucon, double *ucov, double *bcon) {
  int j;
  bcon[(0)] = pr[(5)] * ucov[1] + pr[(6)] * ucov[2] + pr[(7)] * ucov[3];
  for (j = 1; j < 4; j++)
    bcon[j] = (pr[(5) - 1 + j] + bcon[(0)] * ucon[j]) / ucon[(0)];
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bcon_calc>:
  endbr64
  movsd  0x28(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm1
  mov    $0x8,%eax
  mulsd  0x10(%rdx),%xmm1
  mulsd  0x8(%rdx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
L3:
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  0x20(%rdi,%rax,1),%xmm0
  divsd  (%rsi),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  je     L7
  movsd  (%rcx),%xmm0
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void bcon_calc(double *pr, double *ucon, double *ucov, double *bcon) {
  int j;
  bcon[(0)] = pr[(5)] * ucov[1] + pr[(6)] * ucov[2] + pr[(7)] * ucov[3];
  for (j = 1; j < 4; j++)
    bcon[j] = (pr[(5) - 1 + j] + bcon[(0)] * ucon[j]) / ucon[(0)];
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bcon_calc>:
  endbr64
  movsd  0x28(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm1
  mov    %rsi,%rax
  mulsd  0x10(%rdx),%xmm1
  lea    0x20(%rax),%r8
  mulsd  0x8(%rdx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  0x18(%rdx),%xmm1
  lea    0x20(%rcx),%rdx
  cmp    %rdx,%rax
  setae  %dl
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  movsd  0x8(%rsi),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x28(%rdi),%xmm1
  divsd  (%rsi),%xmm1
  lea    0x10(%rcx),%rsi
  movsd  %xmm1,0x8(%rcx)
  cmp    %r8,%rsi
  setae  %r8b
  or     %r8b,%dl
  je     L5
  lea    0x38(%rdi),%rdx
  cmp    %rdx,%rsi
  je     L5
  movupd 0x10(%rax),%xmm2
  unpcklpd %xmm0,%xmm0
  movupd 0x30(%rdi),%xmm1
  mulpd  %xmm2,%xmm0
  addpd  %xmm1,%xmm0
  movsd  (%rax),%xmm1
  unpcklpd %xmm1,%xmm1
  divpd  %xmm1,%xmm0
  movups %xmm0,0x10(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movsd  0x10(%rax),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x30(%rdi),%xmm1
  divsd  (%rax),%xmm1
  movsd  %xmm1,0x10(%rcx)
  mulsd  0x18(%rax),%xmm0
  addsd  0x38(%rdi),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,0x18(%rcx)
  ret
```

assistant: ```c
void bcon_calc(double *pr, double *ucon, double *ucov, double *bcon) {
  int j;
  bcon[(0)] = pr[(5)] * ucov[1] + pr[(6)] * ucov[2] + pr[(7)] * ucov[3];
  for (j = 1; j < 4; j++)
    bcon[j] = (pr[(5) - 1 + j] + bcon[(0)] * ucon[j]) / ucon[(0)];
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xf0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0xf0(%rbp),%rax
  mov    %rax,-0xf8(%rbp)
  jmp    L4
L12:
  mov    -0xf8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xf8(%rbp),%rax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0xf8(%rbp)
L4:
  lea    -0x80(%rbp),%rdx
  mov    -0xf8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0xf8(%rbp)
  cmpq   $0x0,-0xf8(%rbp)
  jne    L12
  lea    -0xf0(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D12: enter s1

tool: D15: enter s2

tool: D2: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, ptr + strlen(s2), strlen(ptr) - 1);
    ptr += strlen(s2);
  }
  printf("%s\n", s1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  lea    0x70(%rsp),%rbp
  jmp    L26
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%r12),%edx
  movslq %eax,%rsi
  add    %rbx,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
L26:
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L7
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D28
type_infered: string

tool: D8: enter s1

tool: D18: enter s2

tool: D28: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, ptr + strlen(s2), strlen(ptr) - 1);
    ptr += strlen(s2);
  }
  printf("%s\n", s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  jmp    L13
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  movslq %eax,%rsi
  add    %rbx,%rsi
  call   <memmove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
L13:
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
  mov    %r12,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D23
type_guessed: string

tool: D2: enter s1

tool: D3: enter s2

tool: D23: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, ptr + strlen(s2), strlen(ptr) - 1);
    ptr += strlen(s2);
  }
  printf("%s\n", s1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x70(%rsp),%rbp
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  jmp    L7
  nopl   0x0(%rax)
L21:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  movslq %eax,%rsi
  add    %rbx,%rsi
  call   <memmove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
L7:
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L21
  mov    %r12,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string

tool: D21: enter s1

tool: D13: enter s2

tool: D22: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, ptr + strlen(s2), strlen(ptr) - 1);
    ptr += strlen(s2);
  }
  printf("%s\n", s1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skip_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L28
L0:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L0
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_blanks(char *str) {
  while (((*str == ' ') || (*str == '\t'))) {
    str++;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_blanks>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L4
  cmp    $0x9,%dl
  jne    L0
L4:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L4
  cmp    $0x9,%dl
  je     L4
L0:
  ret
```

assistant: ```c
char *skip_blanks(char *str) {
  while (((*str == ' ') || (*str == '\t'))) {
    str++;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_blanks>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L21
  nop
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L25
L21:
  cmp    $0x9,%dl
  je     L25
  ret
```

assistant: ```c
char *skip_blanks(char *str) {
  while (((*str == ' ') || (*str == '\t'))) {
    str++;
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skip_blanks>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L0
  nop
L20:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L20
L0:
  cmp    $0x9,%dl
  je     L20
  ret
```

assistant: ```c
char *skip_blanks(char *str) {
  while (((*str == ' ') || (*str == '\t'))) {
    str++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L22
  negl   -0x14(%rbp)
L22:
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L48:
  cmpl   $0x0,-0x14(%rbp)
  js     L7
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L7:
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bar@plt>
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L48
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(int e, int n) {
  int i, bb2, bb5;
  if (e > 0)
    e = -e;
  for (i = 0; i < n; i++) {
    if (e >= 0) {
      bb2 = 0;
      bb5 = 0;
    } else {
      bb5 = -e;
      bb2 = bb5;
    }
    bar(bb5, bb2);
  }
}
```