ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mkargv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L137
  lea    D7(%rip),%r14
  mov    %rdi,%r13
  mov    $0x80,%edx
  mov    %rsi,%rbp
  mov    %r14,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x7f,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  mov    %r14,%rdi
  mov    %r14,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  movslq %eax,%rbx
  add    %r14,%rbx
  cmp    %rdi,%rbx
  jbe    L45
  test   %rdi,%rdi
  je     L45
  xor    %r14d,%r14d
  lea    D14(%rip),%r15
L27:
  cmpb   $0x22,(%rdi)
  lea    0x0(%rbp,%r14,8),%r13
  je     L30
  mov    %rsp,%rdi
  mov    %r15,%rsi
  call   <strsep@plt>
  test   %rax,%rax
  je     L81
  cmpb   $0x0,(%rax)
  mov    (%rsp),%rdi
  jne    L120
L136:
  test   %rdi,%rdi
  je     L124
  cmp    %rdi,%rbx
  ja     L27
L124:
  lea    0x0(%rbp,%r14,8),%r13
  nopw   0x0(%rax,%rax,1)
L81:
  movq   $0x0,0x0(%r13)
L137:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rdi
  mov    $0x22,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L81
  movb   $0x0,(%rax)
  mov    (%rsp),%rcx
  lea    0x1(%rcx),%rdx
  cmp    %rax,%rdx
  jae    L17
  mov    %rdx,0x0(%r13)
  add    $0x1,%r12d
  movslq %r12d,%r14
L17:
  lea    0x1(%rax),%rdi
  mov    %rdi,(%rsp)
  jmp    L136
L120:
  add    $0x1,%r12d
  mov    %rax,0x0(%r13)
  mov    (%rsp),%rdi
  movslq %r12d,%r14
  jmp    L136
  nopl   0x0(%rax)
L45:
  mov    %rbp,%r13
  xor    %r12d,%r12d
  jmp    L81
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: string

tool: D14: =/ 	

assistant: ```c
int mkargv(char *str, char **argv, int max) {
  int n = 0;
  char *p, *q, *es;
  char **args = argv;
  char *sep = "=/ \t";
  static char buf[(128)];
  if (str == NULL)
    return n;
  memset(buf, 0, sizeof(buf));
  strncpy(buf, str, sizeof(buf) - 1);
  p = buf;
  es = p + strlen(buf);
  while (p && p < es) {
    if (*p == '"') {
      q = strchr(p + 1, '"');
      if (!q)
        goto ret;
      *q = '\0';
      if (q > p + 1)
        args[n++] = p + 1;
      p = ++q;
      continue;
    }
    if ((q = strsep(&p, sep)) != NULL) {
      if (*q != '\0')
        args[n++] = q;
      continue;
    }
    break;
  }
ret:
  args[n] = NULL;
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mkargv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L103
  lea    D8(%rip),%r14
  mov    %rdi,%r13
  mov    $0x80,%edx
  mov    %rsi,%rbp
  mov    %r14,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x7f,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  mov    %r14,%rdi
  mov    %r14,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  movslq %eax,%rbx
  add    %r14,%rbx
  cmp    %rdi,%rbx
  jbe    L114
  test   %rdi,%rdi
  je     L114
  xor    %r14d,%r14d
  lea    D13(%rip),%r15
L138:
  cmpb   $0x22,(%rdi)
  lea    0x0(%rbp,%r14,8),%r13
  je     L57
  mov    %rsp,%rdi
  mov    %r15,%rsi
  call   <strsep@plt>
  test   %rax,%rax
  je     L69
  cmpb   $0x0,(%rax)
  mov    (%rsp),%rdi
  jne    L111
L67:
  test   %rdi,%rdi
  je     L113
  cmp    %rdi,%rbx
  ja     L138
L113:
  lea    0x0(%rbp,%r14,8),%r13
  nopw   0x0(%rax,%rax,1)
L69:
  movq   $0x0,0x0(%r13)
L103:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  add    $0x1,%rdi
  mov    $0x22,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L69
  movb   $0x0,(%rax)
  mov    (%rsp),%rcx
  lea    0x1(%rcx),%rdx
  cmp    %rax,%rdx
  jae    L10
  mov    %rdx,0x0(%r13)
  add    $0x1,%r12d
  movslq %r12d,%r14
L10:
  lea    0x1(%rax),%rdi
  mov    %rdi,(%rsp)
  jmp    L67
L111:
  add    $0x1,%r12d
  mov    %rax,0x0(%r13)
  mov    (%rsp),%rdi
  movslq %r12d,%r14
  jmp    L67
  nopl   0x0(%rax)
L114:
  mov    %rbp,%r13
  xor    %r12d,%r12d
  jmp    L69
L131:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D13: =/ 	

assistant: ```c
int mkargv(char *str, char **argv, int max) {
  int n = 0;
  char *p, *q, *es;
  char **args = argv;
  char *sep = "=/ \t";
  static char buf[(128)];
  if (str == NULL)
    return n;
  memset(buf, 0, sizeof(buf));
  strncpy(buf, str, sizeof(buf) - 1);
  p = buf;
  es = p + strlen(buf);
  while (p && p < es) {
    if (*p == '"') {
      q = strchr(p + 1, '"');
      if (!q)
        goto ret;
      *q = '\0';
      if (q > p + 1)
        args[n++] = p + 1;
      p = ++q;
      continue;
    }
    if ((q = strsep(&p, sep)) != NULL) {
      if (*q != '\0')
        args[n++] = q;
      continue;
    }
    break;
  }
ret:
  args[n] = NULL;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kcm_get_char_or_hex_token_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %rsi,-0x220(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rcx
  mov    -0x218(%rbp),%rax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <kcm_get_token@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x218(%rbp)
  je     L11
  mov    -0x220(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <kcm_get_char_or_hex_val@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  jmp    L39
L11:
  mov    -0x218(%rbp),%rax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
const char *kcm_get_char_or_hex_token_value(const char *line, unsigned short *val) {
  char token[512];
  line = kcm_get_token(line, token, 512);
  if (NULL != line) {
    if (kcm_get_char_or_hex_val(token, val)) {
      return NULL;
    }
  }
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kcm_get_char_or_hex_token_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x200,%edx
  call   <kcm_get_token@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <kcm_get_char_or_hex_val@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%rbx
L14:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %rbx,%rax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *kcm_get_char_or_hex_token_value(const char *line, unsigned short *val) {
  char token[512];
  line = kcm_get_token(line, token, 512);
  if (NULL != line) {
    if (kcm_get_char_or_hex_val(token, val)) {
      return NULL;
    }
  }
  return line;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kcm_get_char_or_hex_token_value>:
  endbr64
  push   %r13
  mov    $0x200,%edx
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <kcm_get_token@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <kcm_get_char_or_hex_val@plt>
  test   %rax,%rax
  jne    L7
L8:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x210,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  xor    %r12d,%r12d
  jmp    L8
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *kcm_get_char_or_hex_token_value(const char *line, unsigned short *val) {
  char token[512];
  line = kcm_get_token(line, token, 512);
  if (NULL != line) {
    if (kcm_get_char_or_hex_val(token, val)) {
      return NULL;
    }
  }
  return line;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kcm_get_char_or_hex_token_value>:
  endbr64
  push   %r13
  mov    $0x200,%edx
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <kcm_get_token@plt>
  test   %rax,%rax
  je     L11
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <kcm_get_char_or_hex_val@plt>
  test   %rax,%rax
  jne    L11
L15:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x210,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  xor    %r12d,%r12d
  jmp    L15
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *kcm_get_char_or_hex_token_value(const char *line, unsigned short *val) {
  char token[512];
  line = kcm_get_token(line, token, 512);
  if (NULL != line) {
    if (kcm_get_char_or_hex_val(token, val)) {
      return NULL;
    }
  }
  return line;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printspaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L10
L15:
  mov    $0x20,%edi
  call   <putchar@plt>
L10:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void printspaces(int spaces) {
  while (spaces--)
    putchar(' ');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printspaces>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  je     L13
L1:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L1
L13:
  pop    %rbx
  ret
```

assistant: ```c
void printspaces(int spaces) {
  while (spaces--)
    putchar(' ');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printspaces>:
  endbr64
  test   %edi,%edi
  je     L19
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L12
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void printspaces(int spaces) {
  while (spaces--)
    putchar(' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printspaces>:
  endbr64
  test   %edi,%edi
  je     L11
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L3
  pop    %rbx
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
void printspaces(int spaces) {
  while (spaces--)
    putchar(' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %d

assistant: ```c
void main() {
  char *pChar;
  printf("%d", add(2, 3));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: %d

assistant: ```c
void main() {
  char *pChar;
  printf("%d", add(2, 3));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <add@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
void main() {
  char *pChar;
  printf("%d", add(2, 3));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <add@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1070 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
void main() {
  char *pChar;
  printf("%d", add(2, 3));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L3:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: freeing null

assistant: ```c
void pfree(void *p) {
  if (p == NULL)
    error("freeing null");
  free(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<pfree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L16
L17:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L16:
  lea    D7(%rip),%rdi
  call   <error@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: freeing null

assistant: ```c
void pfree(void *p) {
  if (p == NULL)
    error("freeing null");
  free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D0(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: freeing null

assistant: ```c
void pfree(void *p) {
  if (p == NULL)
    error("freeing null");
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D6(%rip),%rdi
  call   <error@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: freeing null

assistant: ```c
void pfree(void *p) {
  if (p == NULL)
    error("freeing null");
  free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<UCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L37:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int UCase(char in[]) {
  int i;
  for (i = 0; in[i]; i++)
    if (in[i] >= 'a' && in[i] <= 'z')
      in[i] -= 32;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UCase>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L36
L21:
  mov    $0x1,%eax
  ret
L32:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
L36:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L32
  sub    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L32
```

assistant: ```c
int UCase(char in[]) {
  int i;
  for (i = 0; in[i]; i++)
    if (in[i] >= 'a' && in[i] <= 'z')
      in[i] -= 32;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UCase>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L16
  sub    $0x20,%eax
  mov    %al,(%rdi)
L16:
  add    $0x1,%rdi
L23:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L8
  mov    $0x1,%eax
  ret
```

assistant: ```c
int UCase(char in[]) {
  int i;
  for (i = 0; in[i]; i++)
    if (in[i] >= 'a' && in[i] <= 'z')
      in[i] -= 32;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UCase>:
  endbr64
  nopl   0x0(%rax)
L19:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
L12:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L13
  sub    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L33:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L13:
  add    $0x1,%rdi
  jmp    L19
```

assistant: ```c
int UCase(char in[]) {
  int i;
  for (i = 0; in[i]; i++)
    if (in[i] >= 'a' && in[i] <= 'z')
      in[i] -= 32;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vector_print_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L15:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L15
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D17
data_type: string

tool: D2: %s=[


tool: D19: %lf 

tool: D17: ]

assistant: ```c
void vector_print_double(const char *name, const double *a, const unsigned int dim) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dim; i++) {
    printf("%lf ", a[i]);
  }
  printf("]\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vector_print_double>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L7
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D5(%rip),%rbp
L13:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
L7:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D5
type: string
name: disassemble_data
arguments: label: D2
type: string

tool: D8: %s=[


tool: D5: %lf 

tool: D2: ]

assistant: ```c
void vector_print_double(const char *name, const double *a, const unsigned int dim) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dim; i++) {
    printf("%lf ", a[i]);
  }
  printf("]\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_print_double>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L17
  lea    -0x1(%rbp),%eax
  lea    D6(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax)
L18:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
L17:
  pop    %rbx
  lea    D12(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D25: %s=[


tool: D6: %lf 

tool: D12: ]

assistant: ```c
void vector_print_double(const char *name, const double *a, const unsigned int dim) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dim; i++) {
    printf("%lf ", a[i]);
  }
  printf("]\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_print_double>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L12
  lea    -0x1(%rbp),%eax
  lea    D18(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax)
L7:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
L12:
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string
name: retrieve_data
arguments: tag: D23
type_guessed: string

tool: D5: %s=[


tool: D18: %lf 

tool: D23: ]

assistant: ```c
void vector_print_double(const char *name, const double *a, const unsigned int dim) {
  printf("%s=[\n", name);
  for (unsigned int i = 0; i < dim; i++) {
    printf("%lf ", a[i]);
  }
  printf("]\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x5fcfbc1c(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 29120926UL) + 1578328702UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x5f35c761,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 29120926UL) + 1578328702UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x5f35c761,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 29120926UL) + 1578328702UL;
  }
}
```