ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<SortSV>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %rbp
  push   %rbx
  mov    %edx,%r8d
  lea    -0x1(%rdx),%ebp
  mov    %ebp,%ebx
  mov    %edx,%edx
  mov    $0x0,%eax
L18:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
  mov    $0x0,%r9d
L34:
  mov    %r9d,%edx
  mov    (%rdi,%r9,4),%r10d
  movslq %r10d,%rax
  movsd  (%rsi,%rax,8),%xmm0
  cmp    %rbx,%r9
  je     L36
  lea    0x1(%r9),%r11
  mov    %r11,%rax
L1:
  movslq (%rdi,%rax,4),%rcx
  movsd  (%rsi,%rcx,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L1
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r9,4)
  mov    %r10d,(%rax)
  mov    %r11,%r9
  jmp    L34
L36:
  movslq %ebp,%rbp
  lea    (%rdi,%rbp,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%rbx,4)
  mov    %r10d,(%rax)
  pop    %rbx
  pop    %rbp
  ret
L16:
  ret
```

assistant: ```c
void SortSV(int *svPerm, double *w, const int n) {
  int i, j, iTmp;
  double tmp;
  for (i = 0; i < n; i++)
    svPerm[i] = i;
  for (i = 0; i < n; i++) {
    tmp = w[svPerm[i]];
    iTmp = i;
    for (j = i + 1; j < n; j++)
      if (w[svPerm[j]] > tmp) {
        tmp = w[svPerm[j]];
        iTmp = j;
      }
    j = svPerm[i];
    svPerm[i] = svPerm[iTmp];
    svPerm[iTmp] = j;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SortSV>:
  endbr64
  test   %edx,%edx
  jle    L19
  push   %rbx
  mov    %edx,%r8d
  lea    -0x1(%rdx),%ebx
  xor    %eax,%eax
  mov    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L22
  xor    %r9d,%r9d
  nop
L15:
  movslq (%rdi,%r9,4),%rax
  mov    %r9d,%edx
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%r10
  cmp    %r9,%rbx
  je     L20
  lea    0x1(%r9),%r11
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L10:
  movslq (%rdi,%rax,4),%rcx
  movsd  (%rsi,%rcx,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%edx
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %eax,%r8d
  jg     L10
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r9,4)
  mov    %r11,%r9
  mov    %r10d,(%rax)
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L20:
  pop    %rbx
  ret
L19:
  ret
```

assistant: ```c
void SortSV(int *svPerm, double *w, const int n) {
  int i, j, iTmp;
  double tmp;
  for (i = 0; i < n; i++)
    svPerm[i] = i;
  for (i = 0; i < n; i++) {
    tmp = w[svPerm[i]];
    iTmp = i;
    for (j = i + 1; j < n; j++)
      if (w[svPerm[j]] > tmp) {
        tmp = w[svPerm[j]];
        iTmp = j;
      }
    j = svPerm[i];
    svPerm[i] = svPerm[iTmp];
    svPerm[iTmp] = j;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SortSV>:
  endbr64
  mov    %edx,%r8d
  test   %edx,%edx
  jle    L14
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L81
  shr    $0x2,%edx
  movdqa D18(%rip),%xmm0
  movdqa D7(%rip),%xmm2
  mov    %rdi,%rax
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   (%rax)
L6:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L6
  mov    %r8d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r8b
  je     L29
L40:
  movslq %eax,%rdx
  mov    %eax,(%rdi,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r8d
  jle    L71
  add    $0x2,%eax
  mov    %edx,0x4(%rdi,%rcx,1)
  cmp    %eax,%r8d
  jle    L29
  mov    %eax,0x8(%rdi,%rcx,1)
L29:
  movslq (%rdi),%rax
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%r10
L82:
  lea    -0x2(%r8),%r11d
  mov    $0x1,%r9d
  add    $0x2,%r11
  nopl   0x0(%rax)
L62:
  lea    -0x1(%r9),%edx
  mov    %r9,%rax
  nop
L26:
  movslq (%rdi,%rax,4),%rcx
  movsd  (%rsi,%rcx,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%edx
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %eax,%r8d
  jg     L26
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%rdi,%r9,4)
  mov    %r10d,(%rax)
  movslq (%rdi,%r9,4),%rax
  add    $0x1,%r9
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%r10
  cmp    %r9,%r11
  jne    L62
  ret
L71:
  movslq (%rdi),%rax
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%r10
  cmp    $0x1,%r8d
  jne    L82
L14:
  ret
L81:
  xor    %eax,%eax
  jmp    L40
```

tool_calls: name: parse_data
arguments: tag: D18
type: byte[16]
name: parse_data
arguments: tag: D7
type: byte[16]

tool: {"D18": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void SortSV(int *svPerm, double *w, const int n) {
  int i, j, iTmp;
  double tmp;
  for (i = 0; i < n; i++)
    svPerm[i] = i;
  for (i = 0; i < n; i++) {
    tmp = w[svPerm[i]];
    iTmp = i;
    for (j = i + 1; j < n; j++)
      if (w[svPerm[j]] > tmp) {
        tmp = w[svPerm[j]];
        iTmp = j;
      }
    j = svPerm[i];
    svPerm[i] = svPerm[iTmp];
    svPerm[iTmp] = j;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<upper_power_of_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    %eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int upper_power_of_2(int n) {
  n--;
  n |= n >> 1;
  n |= n >> 2;
  n |= n >> 4;
  n |= n >> 8;
  n |= n >> 16;
  return ++n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<upper_power_of_2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int upper_power_of_2(int n) {
  n--;
  n |= n >> 1;
  n |= n >> 2;
  n |= n >> 4;
  n |= n >> 8;
  n |= n >> 16;
  return ++n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<upper_power_of_2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int upper_power_of_2(int n) {
  n--;
  n |= n >> 1;
  n |= n >> 2;
  n |= n >> 4;
  n |= n >> 8;
  n |= n >> 16;
  return ++n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<upper_power_of_2>:
  endbr64
  sub    $0x1,%edi
  mov    %edi,%eax
  sar    %eax
  or     %edi,%eax
  mov    %eax,%edi
  sar    $0x2,%edi
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x4,%eax
  or     %edi,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  or     %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int upper_power_of_2(int n) {
  n--;
  n |= n >> 1;
  n |= n >> 2;
  n |= n >> 4;
  n |= n >> 8;
  n |= n >> 16;
  return ++n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fnv_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L6:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   $0x1000193,%eax,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int fnv_hash(const void *key, int length, unsigned int seed) {
  const unsigned char *data = (const unsigned char *)key;
  int n;
  unsigned int xord;
  unsigned int hash = seed;
  for (n = 0; n < length; n++) {
    xord = hash ^ data[n];
    hash = (xord * 16777619) % 4294967296;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fnv_hash>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%ecx
  add    %rcx,%rdi
L10:
  movzbl (%rdx),%ecx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rcx
  jne    L10
L4:
  ret
```

assistant: ```c
unsigned int fnv_hash(const void *key, int length, unsigned int seed) {
  const unsigned char *data = (const unsigned char *)key;
  int n;
  unsigned int xord;
  unsigned int hash = seed;
  for (n = 0; n < length; n++) {
    xord = hash ^ data[n];
    hash = (xord * 16777619) % 4294967296;
  }
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fnv_hash>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%ecx
  add    %rdi,%rcx
L19:
  movzbl (%rdi),%edx
  xor    %edx,%eax
  mov    %rdi,%rdx
  add    $0x1,%rdi
  imul   $0x1000193,%eax,%eax
  cmp    %rcx,%rdx
  jne    L19
L10:
  ret
```

assistant: ```c
unsigned int fnv_hash(const void *key, int length, unsigned int seed) {
  const unsigned char *data = (const unsigned char *)key;
  int n;
  unsigned int xord;
  unsigned int hash = seed;
  for (n = 0; n < length; n++) {
    xord = hash ^ data[n];
    hash = (xord * 16777619) % 4294967296;
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fnv_hash>:
  endbr64
  mov    %edx,%eax
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%ecx
  add    %rdi,%rcx
L18:
  movzbl (%rdi),%edx
  xor    %edx,%eax
  mov    %rdi,%rdx
  add    $0x1,%rdi
  imul   $0x1000193,%eax,%eax
  cmp    %rdx,%rcx
  jne    L18
L5:
  ret
```

assistant: ```c
unsigned int fnv_hash(const void *key, int length, unsigned int seed) {
  const unsigned char *data = (const unsigned char *)key;
  int n;
  unsigned int xord;
  unsigned int hash = seed;
  for (n = 0; n < length; n++) {
    xord = hash ^ data[n];
    hash = (xord * 16777619) % 4294967296;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<MCD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L45:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L2
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L2
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L2
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L2:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L45
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int MCD(int n, int m) {
  int tmp = 1;
  for (int i = 1; i < max(n, m); i++) {
    if (n % i == 0 && m % i == 0 && i > tmp) {
      tmp = i;
    }
  }
  return tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<MCD>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x1,%ebx
  mov    $0x1,%r13d
  jmp    L3
L6:
  add    $0x1,%ebx
L3:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <max@plt>
  cmp    %ebx,%eax
  jle    L23
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L6
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  cmp    %ebx,%r13d
  mov    %ebx,%eax
  cmovge %r13d,%eax
  test   %edx,%edx
  cmove  %eax,%r13d
  jmp    L6
L23:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int MCD(int n, int m) {
  int tmp = 1;
  for (int i = 1; i < max(n, m); i++) {
    if (n % i == 0 && m % i == 0 && i > tmp) {
      tmp = i;
    }
  }
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MCD>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L0
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  cmp    %ebx,%r14d
  mov    %ebx,%eax
  cmovge %r14d,%eax
  test   %edx,%edx
  cmove  %eax,%r14d
L0:
  add    $0x1,%ebx
L19:
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <max@plt>
  cmp    %ebx,%eax
  jg     L25
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int MCD(int n, int m) {
  int tmp = 1;
  for (int i = 1; i < max(n, m); i++) {
    if (n % i == 0 && m % i == 0 && i > tmp) {
      tmp = i;
    }
  }
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MCD>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L16
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  cmp    %ebx,%r14d
  mov    %ebx,%eax
  cmovge %r14d,%eax
  test   %edx,%edx
  cmove  %eax,%r14d
L16:
  add    $0x1,%ebx
L7:
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <max@plt>
  cmp    %ebx,%eax
  jg     L22
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int MCD(int n, int m) {
  int tmp = 1;
  for (int i = 1; i < max(n, m); i++) {
    if (n % i == 0 && m % i == 0 && i > tmp) {
      tmp = i;
    }
  }
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ArgPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L48
L25:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L39
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L39:
  mov    -0x4(%rbp),%eax
  jmp    L38
L3:
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    $0xffffffff,%eax
L38:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: Argument missing for %s


assistant: ```c
int ArgPos(char *str, int argc, char **argv) {
  int a;
  for (a = 1; a < argc; a++) {
    if (!strcmp(str, argv[a])) {
      if (a == argc - 1) {
        printf("Argument missing for %s\n", str);
        exit(1);
      }
      return a;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ArgPos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L4
  mov    %rdi,%rbp
  mov    %esi,%r15d
  mov    %rdx,%r12
  mov    %esi,%r14d
  mov    $0x1,%ebx
L58:
  mov    %ebx,%r13d
  mov    (%r12,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L49
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L58
  mov    $0xffffffff,%r13d
L52:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  sub    $0x1,%r15d
  cmp    %ebx,%r15d
  jne    L52
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L52
L4:
  mov    $0xffffffff,%r13d
  jmp    L52
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: Argument missing for %s


assistant: ```c
int ArgPos(char *str, int argc, char **argv) {
  int a;
  for (a = 1; a < argc; a++) {
    if (!strcmp(str, argv[a])) {
      if (a == argc - 1) {
        printf("Argument missing for %s\n", str);
        exit(1);
      }
      return a;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ArgPos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L39
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%r15
  movslq %esi,%rbp
  mov    $0x1,%ebx
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L39
L54:
  mov    (%r15,%rbx,8),%rsi
  mov    %r14,%rdi
  mov    %ebx,%r12d
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L50
  sub    $0x1,%r13d
  cmp    %ebx,%r13d
  jne    L37
  mov    %r14,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L37
L39:
  mov    $0xffffffff,%r12d
L37:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: Argument missing for %s


assistant: ```c
int ArgPos(char *str, int argc, char **argv) {
  int a;
  for (a = 1; a < argc; a++) {
    if (!strcmp(str, argv[a])) {
      if (a == argc - 1) {
        printf("Argument missing for %s\n", str);
        exit(1);
      }
      return a;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ArgPos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L12
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%r15
  movslq %esi,%rbp
  mov    $0x1,%ebx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L12
L4:
  mov    (%r15,%rbx,8),%rsi
  mov    %r14,%rdi
  mov    %ebx,%r12d
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L46
  sub    $0x1,%r13d
  cmp    %ebx,%r13d
  jne    L48
  mov    %r14,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L48
L12:
  mov    $0xffffffff,%r12d
L48:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: Argument missing for %s


assistant: ```c
int ArgPos(char *str, int argc, char **argv) {
  int a;
  for (a = 1; a < argc; a++) {
    if (!strcmp(str, argv[a])) {
      if (a == argc - 1) {
        printf("Argument missing for %s\n", str);
        exit(1);
      }
      return a;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LAR_AppendFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <iself@plt>
  test   %rax,%rax
  je     L50
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <LAR_AppendSelf@plt>
  jmp    L7
L50:
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L69
  mov    $0xffffffff,%eax
  jmp    L7
L69:
  lea    -0x1c(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  je     L56
  mov    $0xffffffff,%eax
  jmp    L7
L56:
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%esi
  mov    $0x0,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,-0x10(%rbp)
  mov    D30(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L23
  mov    $0xffffffff,%eax
  jmp    L7
L23:
  mov    -0x1c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <LAR_AppendBuffer@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <munmap@plt>
  mov    -0x14(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

assistant: ```c
int LAR_AppendFile(struct LAR *lar, const char *filename, struct LARAttr *attr) {
  int fd;
  struct stat s;
  char *filep;
  int ret;
  if (iself((char *)filename))
    return LAR_AppendSelf(lar, filename, attr);
  fd = open(filename, O_RDONLY);
  if (fd == -1)
    return -1;
  if (fstat(fd, &s))
    return -1;
  filep = (char *)mmap(0, s.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (filep == MAP_FAILED)
    return -1;
  ret = LAR_AppendBuffer(lar, (unsigned char *)filep, s.st_size, attr);
  munmap(filep, s.st_size);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LAR_AppendFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <iself@plt>
  test   %rax,%rax
  jne    L46
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L40
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L23
  mov    $0x0,%r9d
  mov    %ebx,%r8d
  mov    D12(%rip),%rax
  mov    (%rax),%ecx
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    0x4(%rsp),%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,%r13
  mov    D37(%rip),%rax
  cmp    %r13,(%rax)
  je     L1
  mov    %r12,%rcx
  mov    0x4(%rsp),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <LAR_AppendBuffer@plt>
  mov    %eax,%ebx
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <munmap@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <LAR_AppendSelf@plt>
  mov    %eax,%ebx
  jmp    L40
L23:
  mov    $0xffffffff,%ebx
  jmp    L40
L1:
  mov    $0xffffffff,%ebx
  jmp    L40
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int LAR_AppendFile(struct LAR *lar, const char *filename, struct LARAttr *attr) {
  int fd;
  struct stat s;
  char *filep;
  int ret;
  if (iself((char *)filename))
    return LAR_AppendSelf(lar, filename, attr);
  fd = open(filename, O_RDONLY);
  if (fd == -1)
    return -1;
  if (fstat(fd, &s))
    return -1;
  filep = (char *)mmap(0, s.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (filep == MAP_FAILED)
    return -1;
  ret = LAR_AppendBuffer(lar, (unsigned char *)filep, s.st_size, attr);
  munmap(filep, s.st_size);
  return ret;
}
```