ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  jmp    L26
L35:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L70
L34:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L83:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3e8,%eax
  jne    L20
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,%edx
  jne    L20
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L48
L20:
  addl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x1f3,-0x4(%rbp)
  jle    L83
  addl   $0x1,-0x8(%rbp)
L70:
  cmpl   $0x1f3,-0x8(%rbp)
  jle    L34
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x1f3,-0xc(%rbp)
  jle    L35
  mov    $0x0,%eax
L48:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D15
type_infered: string

tool: D14: A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:


tool: D15: %d


assistant: ```c
int main() {
  for (int a = 1; a < 500; a++) {
    for (int b = a + 1; b < 500; b++) {
      for (int c = b + 1; c < 500; c++) {
        if (a + b + c == 1000 && (a * a + b * b == c * c)) {
          printf("A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:\n", a, b, c);
          printf("%d\n", a * b * c);
          return 0;
        }
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r12d
  mov    $0x2,%edi
  mov    $0x2,%ebp
  jmp    L0
L33:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L51
L9:
  lea    (%rdx,%rbx,1),%eax
  cmp    $0x3e8,%eax
  jne    L33
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ecx
  jne    L33
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  imul   %r12d,%esi
  imul   %ebx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L67:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  lea    0x1(%rdi),%esi
  cmp    $0x1f3,%esi
  jg     L67
  mov    %edi,%r12d
  mov    %esi,%edi
L51:
  mov    %esi,%ebp
L0:
  lea    0x1(%rbp),%esi
  cmp    $0x1f3,%esi
  jg     L59
  mov    %ebp,%ecx
  imul   %ebp,%ecx
  mov    %r12d,%eax
  imul   %r12d,%eax
  add    %eax,%ecx
  mov    %esi,%ebx
  lea    (%r12,%rbp,1),%edx
  jmp    L9
```

tool_calls: name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D10
type: string

tool: D13: A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:


tool: D10: %d


assistant: ```c
int main() {
  for (int a = 1; a < 500; a++) {
    for (int b = a + 1; b < 500; b++) {
      for (int c = b + 1; c < 500; c++) {
        if (a + b + c == 1000 && (a * a + b * b == c * c)) {
          printf("A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:\n", a, b, c);
          printf("%d\n", a * b * c);
          return 0;
        }
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  mov    $0x1,%r12d
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L38:
  lea    0x1(%rbp),%esi
  cmp    $0x1f3,%ebp
  je     L54
  mov    %r12d,%ecx
  mov    %ebp,%eax
  lea    0x0(%rbp,%r12,1),%edx
  mov    %esi,%ebx
  imul   %r12d,%ecx
  imul   %ebp,%eax
  add    %eax,%ecx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L36
L5:
  lea    (%rdx,%rbx,1),%eax
  cmp    $0x3e8,%eax
  jne    L32
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ecx
  jne    L32
  mov    %r12d,%esi
  lea    D3(%rip),%rdi
  mov    %ebx,%ecx
  mov    %ebp,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  imul   %r12d,%esi
  imul   %ebx,%esi
  call   <printf@plt>
L58:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L54:
  lea    0x1(%rdi),%esi
  cmp    $0x1f3,%edi
  je     L58
  mov    %edi,%r12d
  mov    %esi,%edi
  nopl   0x0(%rax)
L36:
  mov    %esi,%ebp
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D3: A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:


tool: D2: %d


assistant: ```c
int main() {
  for (int a = 1; a < 500; a++) {
    for (int b = a + 1; b < 500; b++) {
      for (int c = b + 1; c < 500; c++) {
        if (a + b + c == 1000 && (a * a + b * b == c * c)) {
          printf("A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:\n", a, b, c);
          printf("%d\n", a * b * c);
          return 0;
        }
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edi
  mov    $0x1,%r12d
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L55:
  lea    0x1(%rbp),%esi
  cmp    $0x1f3,%ebp
  je     L36
  mov    %r12d,%ecx
  mov    %ebp,%eax
  lea    0x0(%rbp,%r12,1),%edx
  mov    %esi,%ebx
  imul   %r12d,%ecx
  imul   %ebp,%eax
  add    %eax,%ecx
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L62
L56:
  lea    (%rdx,%rbx,1),%eax
  cmp    $0x3e8,%eax
  jne    L43
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %eax,%ecx
  jne    L43
  mov    %r12d,%esi
  lea    D10(%rip),%rdi
  mov    %ebx,%ecx
  mov    %ebp,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  imul   %r12d,%esi
  imul   %ebx,%esi
  call   <printf@plt>
L23:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L36:
  lea    0x1(%rdi),%esi
  cmp    $0x1f3,%edi
  je     L23
  mov    %edi,%r12d
  mov    %esi,%edi
  nopl   0x0(%rax)
L62:
  mov    %esi,%ebp
  jmp    L55
```

tool_calls: name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string

tool: D10: A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:


tool: D19: %d


assistant: ```c
int main() {
  for (int a = 1; a < 500; a++) {
    for (int b = a + 1; b < 500; b++) {
      for (int c = b + 1; c < 500; c++) {
        if (a + b + c == 1000 && (a * a + b * b == c * c)) {
          printf("A Pythagorean triplet for which a+b+c = 1000 is: %d  %d  %d, where its product is:\n", a, b, c);
          printf("%d\n", a * b * c);
          return 0;
        }
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zeroFillSquareMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L37:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L37
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zeroFillSquareMatrix(double **sqMatrix, int dim) {
  int i, j;
  for (i = 0; i < dim; i++) {
    for (j = 0; j < dim; j++) {
      sqMatrix[i][j] = 0.0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zeroFillSquareMatrix>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  mov    %esi,%esi
  shl    $0x3,%rsi
L9:
  mov    $0x0,%eax
L3:
  mov    (%rcx),%rdx
  movq   $0x0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L3
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  jne    L9
L8:
  ret
```

assistant: ```c
void zeroFillSquareMatrix(double **sqMatrix, int dim) {
  int i, j;
  for (i = 0; i < dim; i++) {
    for (j = 0; j < dim; j++) {
      sqMatrix[i][j] = 0.0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<zeroFillSquareMatrix>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    0x0(,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

assistant: ```c
void zeroFillSquareMatrix(double **sqMatrix, int dim) {
  int i, j;
  for (i = 0; i < dim; i++) {
    for (j = 0; j < dim; j++) {
      sqMatrix[i][j] = 0.0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zeroFillSquareMatrix>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    0x0(,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  ret
```

assistant: ```c
void zeroFillSquareMatrix(double **sqMatrix, int dim) {
  int i, j;
  for (i = 0; i < dim; i++) {
    for (j = 0; j < dim; j++) {
      sqMatrix[i][j] = 0.0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<randstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x4,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x3,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x14(%rcx),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L19:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  lea    0x61(%rax),%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *randstr() {
  int len = 20 + rand() % 40;
  char *str = calloc(1, len + 1);
  str[len] = '\0';
  for (int i = 0; i < len; i++) {
    str[i] = 'a' + (rand() % 26);
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<randstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x24,%rbp
  cltd
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,4),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  lea    0x14(%rax),%ebx
  lea    0x15(%rax),%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %ebx,%ebx
  jle    L15
  mov    %r12,%rbx
  lea    0x13(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L0
L15:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *randstr() {
  int len = 20 + rand() % 40;
  char *str = calloc(1, len + 1);
  str[len] = '\0';
  for (int i = 0; i < len; i++) {
    str[i] = 'a' + (rand() % 26);
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<randstr>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <rand@plt>
  mov    $0x1,%edi
  movslq %eax,%rbx
  cltd
  imul   $0x66666667,%rbx,%rbx
  sar    $0x24,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,4),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  lea    0x15(%rax),%esi
  lea    0x14(%rax),%ebp
  mov    %eax,%ebx
  call   <calloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %ebp,%ebp
  jle    L8
  lea    0x13(%rbx),%eax
  mov    %r12,%rbp
  lea    0x1(%r12,%rax,1),%rbx
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,-0x1(%rbp)
  cmp    %rbx,%rbp
  jne    L17
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *randstr() {
  int len = 20 + rand() % 40;
  char *str = calloc(1, len + 1);
  str[len] = '\0';
  for (int i = 0; i < len; i++) {
    str[i] = 'a' + (rand() % 26);
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<randstr>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <rand@plt>
  mov    $0x1,%edi
  movslq %eax,%rbx
  cltd
  imul   $0x66666667,%rbx,%rbx
  sar    $0x24,%rbx
  sub    %edx,%ebx
  lea    (%rbx,%rbx,4),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  lea    0x15(%rax),%esi
  lea    0x14(%rax),%ebp
  mov    %eax,%ebx
  call   <calloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  test   %ebp,%ebp
  jle    L4
  lea    0x13(%rbx),%eax
  mov    %r12,%rbp
  lea    0x1(%r12,%rax,1),%rbx
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,-0x1(%rbp)
  cmp    %rbx,%rbp
  jne    L14
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *randstr() {
  int len = 20 + rand() % 40;
  char *str = calloc(1, len + 1);
  str[len] = '\0';
  for (int i = 0; i < len; i++) {
    str[i] = 'a' + (rand() % 26);
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set_udex_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: f64

tool: D9: 1

assistant: ```c
void set_udex_param(double *a0, double *a1, double *a2, double *a3) {
  *a0 = 1.0;
  *a1 = 1.0;
  *a2 = 1.0;
  *a3 = 1.0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_udex_param>:
  endbr64
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  %xmm0,(%rsi)
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: f64

tool: D5: 1

assistant: ```c
void set_udex_param(double *a0, double *a1, double *a2, double *a3) {
  *a0 = 1.0;
  *a1 = 1.0;
  *a2 = 1.0;
  *a3 = 1.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_udex_param>:
  endbr64
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  %xmm0,(%rsi)
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: f64

tool: D0: 1

assistant: ```c
void set_udex_param(double *a0, double *a1, double *a2, double *a3) {
  *a0 = 1.0;
  *a1 = 1.0;
  *a2 = 1.0;
  *a3 = 1.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_udex_param>:
  endbr64
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  %xmm0,(%rsi)
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
void set_udex_param(double *a0, double *a1, double *a2, double *a3) {
  *a0 = 1.0;
  *a1 = 1.0;
  *a2 = 1.0;
  *a3 = 1.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shuffleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <randomize@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L5:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <randomInteger@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swapIntegerElements@plt>
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int shuffleSort(int *array, int n) {
  int lh, rh;
  randomize();
  for (lh = 0; lh < n; lh++) {
    rh = randomInteger(0, n - 1);
    swapIntegerElements(array, lh, rh);
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shuffleSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <randomize@plt>
  test   %ebp,%ebp
  jle    L6
  mov    $0x0,%ebx
  lea    -0x1(%rbp),%r13d
L14:
  mov    %r13d,%esi
  mov    $0x0,%edi
  call   <randomInteger@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <swapIntegerElements@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L14
L6:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int shuffleSort(int *array, int n) {
  int lh, rh;
  randomize();
  for (lh = 0; lh < n; lh++) {
    rh = randomInteger(0, n - 1);
    swapIntegerElements(array, lh, rh);
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shuffleSort>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <randomize@plt>
  test   %r12d,%r12d
  jle    L12
  lea    -0x1(%r12),%r13d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r13d,%esi
  xor    %edi,%edi
  call   <randomInteger@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <swapIntegerElements@plt>
  cmp    %ebx,%r12d
  jne    L10
L12:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int shuffleSort(int *array, int n) {
  int lh, rh;
  randomize();
  for (lh = 0; lh < n; lh++) {
    rh = randomInteger(0, n - 1);
    swapIntegerElements(array, lh, rh);
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shuffleSort>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <randomize@plt>
  test   %r12d,%r12d
  jle    L8
  lea    -0x1(%r12),%r13d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r13d,%esi
  xor    %edi,%edi
  call   <randomInteger@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <swapIntegerElements@plt>
  cmp    %ebx,%r12d
  jne    L4
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int shuffleSort(int *array, int n) {
  int lh, rh;
  randomize();
  for (lh = 0; lh < n; lh++) {
    rh = randomInteger(0, n - 1);
    swapIntegerElements(array, lh, rh);
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: Foo for the win!


assistant: ```c
int foo(void) {
  printf("Foo for the win!\n");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: Foo for the win!


assistant: ```c
int foo(void) {
  printf("Foo for the win!\n");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: Foo for the win!


assistant: ```c
int foo(void) {
  printf("Foo for the win!\n");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: Foo for the win!


assistant: ```c
int foo(void) {
  printf("Foo for the win!\n");
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_getpwent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <setpwent@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L8:
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdi
  mov    -0x8(%rbp),%rax
  mov    0xc(%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  call   <getpwent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  call   <endpwent@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D9: %s: Testing getpwent()


tool: D4: %s: %s (%u:%u) %s


assistant: ```c
int _getpwent(char const *progname) {
  struct passwd *pw;
  setpwent();
  printf("%s: Testing getpwent()\n", progname);
  while ((pw = getpwent()) != NULL)
    printf("%s: %s (%u:%u) %s\n", progname, pw->pw_name, pw->pw_uid, pw->pw_gid, pw->pw_shell);
  endpwent();
  return 0;
}
```