ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<finn_mat4_ortho>:
  endbr64
  push   %rbx
  movaps %xmm0,%xmm7
  mov    $0x40,%edx
  xor    %esi,%esi
  subss  %xmm1,%xmm7
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movss  D28(%rip),%xmm6
  movss  %xmm0,0x2c(%rsp)
  movaps %xmm6,%xmm10
  movaps %xmm6,%xmm9
  movaps %xmm6,%xmm8
  movss  %xmm1,0x28(%rsp)
  divss  %xmm7,%xmm10
  movaps %xmm2,%xmm7
  movss  %xmm2,0x20(%rsp)
  subss  %xmm3,%xmm7
  movss  %xmm3,0x1c(%rsp)
  movss  %xmm4,0x14(%rsp)
  movss  %xmm5,0x10(%rsp)
  divss  %xmm7,%xmm9
  movaps %xmm4,%xmm7
  subss  %xmm5,%xmm7
  movss  %xmm10,0x24(%rsp)
  divss  %xmm7,%xmm8
  movss  %xmm9,0x18(%rsp)
  movss  %xmm8,0xc(%rsp)
  call   <memset@plt>
  movss  0x24(%rsp),%xmm10
  movss  D11(%rip),%xmm7
  movss  0x18(%rsp),%xmm9
  movss  0x28(%rsp),%xmm1
  movss  0x2c(%rsp),%xmm0
  movss  0x1c(%rsp),%xmm3
  movaps %xmm10,%xmm11
  movss  0x20(%rsp),%xmm2
  movss  0x10(%rsp),%xmm5
  mulss  %xmm7,%xmm11
  movss  0x14(%rsp),%xmm4
  mulss  %xmm9,%xmm7
  addss  %xmm1,%xmm0
  movss  0xc(%rsp),%xmm8
  addss  %xmm3,%xmm2
  movss  D28(%rip),%xmm6
  addss  %xmm5,%xmm4
  mulss  %xmm10,%xmm0
  movss  %xmm6,0x3c(%rbx)
  mulss  %xmm9,%xmm2
  movss  %xmm11,(%rbx)
  mulss  %xmm8,%xmm4
  movss  %xmm7,0x14(%rbx)
  movaps %xmm8,%xmm7
  addss  %xmm8,%xmm7
  movss  %xmm0,0x30(%rbx)
  movss  %xmm7,0x28(%rbx)
  movss  %xmm2,0x34(%rbx)
  movss  %xmm4,0x38(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D28
type_infered: f32
name: extract_symbolic_data
arguments: tag: D11
type_infered: byte[4]

tool: D28: 1

tool: {"D11": [0x00,0x00,0x00,0xc0]}

assistant: ```c
void finn_mat4_ortho(float *mat, float left, float right, float bottom, float top, float near, float far) {
  float lr = 1 / (left - right);
  float bt = 1 / (bottom - top);
  float nf = 1 / (near - far);
  memset(mat, 0, sizeof(float) * 16);
  mat[0] = -2.0f * lr;
  mat[5] = -2.0f * bt;
  mat[10] = 2.0f * nf;
  mat[12] = (left + right) * lr;
  mat[13] = (top + bottom) * bt;
  mat[14] = (far + near) * nf;
  mat[15] = 1.0f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<finn_mat4_ortho>:
  endbr64
  push   %rbx
  movaps %xmm0,%xmm7
  movaps %xmm2,%xmm9
  movaps %xmm4,%xmm10
  subss  %xmm1,%xmm7
  subss  %xmm3,%xmm9
  mov    $0x40,%edx
  xor    %esi,%esi
  subss  %xmm5,%xmm10
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movss  D9(%rip),%xmm6
  movss  %xmm0,0x2c(%rsp)
  movaps %xmm6,%xmm8
  movss  %xmm1,0x28(%rsp)
  divss  %xmm7,%xmm8
  movaps %xmm6,%xmm7
  movss  %xmm2,0x24(%rsp)
  movss  %xmm3,0x20(%rsp)
  movss  %xmm4,0xc(%rsp)
  movss  %xmm5,0x8(%rsp)
  divss  %xmm9,%xmm7
  movaps %xmm6,%xmm9
  movaps %xmm8,%xmm11
  movss  %xmm8,0x1c(%rsp)
  divss  %xmm10,%xmm9
  unpcklps %xmm7,%xmm11
  movss  %xmm7,0x18(%rsp)
  movlps %xmm11,0x10(%rsp)
  movss  %xmm9,0x4(%rsp)
  call   <memset@plt>
  movss  0x18(%rsp),%xmm7
  movss  D16(%rip),%xmm10
  movss  0x28(%rsp),%xmm1
  movss  0x2c(%rsp),%xmm0
  movss  0x20(%rsp),%xmm3
  movss  0x24(%rsp),%xmm2
  mulss  %xmm10,%xmm7
  movss  0x8(%rsp),%xmm5
  movss  0xc(%rsp),%xmm4
  addss  %xmm1,%xmm0
  addss  %xmm3,%xmm2
  movss  0x4(%rsp),%xmm9
  movss  0x1c(%rsp),%xmm8
  addss  %xmm5,%xmm4
  movq   0x10(%rsp),%xmm11
  movss  D9(%rip),%xmm6
  mulss  %xmm10,%xmm8
  unpcklps %xmm2,%xmm0
  movss  %xmm7,0x14(%rbx)
  movaps %xmm9,%xmm7
  mulps  %xmm11,%xmm0
  addss  %xmm9,%xmm7
  movss  %xmm6,0x3c(%rbx)
  mulss  %xmm9,%xmm4
  movss  %xmm8,(%rbx)
  movss  %xmm7,0x28(%rbx)
  movlps %xmm0,0x30(%rbx)
  movss  %xmm4,0x38(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: f32
name: read_data
arguments: data_label: D16
type_guessed: byte[4]

tool: D9: 1

tool: {"D16": [0x00,0x00,0x00,0xc0]}

assistant: ```c
void finn_mat4_ortho(float *mat, float left, float right, float bottom, float top, float near, float far) {
  float lr = 1 / (left - right);
  float bt = 1 / (bottom - top);
  float nf = 1 / (near - far);
  memset(mat, 0, sizeof(float) * 16);
  mat[0] = -2.0f * lr;
  mat[5] = -2.0f * bt;
  mat[10] = 2.0f * nf;
  mat[12] = (left + right) * lr;
  mat[13] = (top + bottom) * bt;
  mat[14] = (far + near) * nf;
  mat[15] = 1.0f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Increment(int *x, int max) {
  if ((*x) < max)
    (*x)++;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L4
  add    $0x1,%eax
  mov    %eax,(%rdi)
L4:
  ret
```

assistant: ```c
void Increment(int *x, int max) {
  if ((*x) < max)
    (*x)++;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L1
  add    $0x1,%eax
  mov    %eax,(%rdi)
L1:
  ret
```

assistant: ```c
void Increment(int *x, int max) {
  if ((*x) < max)
    (*x)++;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Increment>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L4
  add    $0x1,%eax
  mov    %eax,(%rdi)
L4:
  ret
```

assistant: ```c
void Increment(int *x, int max) {
  if ((*x) < max)
    (*x)++;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L0:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L0
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: %d: %s


assistant: ```c
void printArray(char **a, long left, long right) {
  long i;
  for (i = left; i <= right; i = i + 1) {
    printf("%d: %s\n", i, a[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printArray>:
  endbr64
  cmp    %rdx,%rsi
  jg     L12
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    D8(%rip),%r13
L11:
  mov    (%r12,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: %d: %s


assistant: ```c
void printArray(char **a, long left, long right) {
  long i;
  for (i = left; i <= right; i = i + 1) {
    printf("%d: %s\n", i, a[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printArray>:
  endbr64
  cmp    %rdx,%rsi
  jg     L19
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%r12,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jge    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d: %s


assistant: ```c
void printArray(char **a, long left, long right) {
  long i;
  for (i = left; i <= right; i = i + 1) {
    printf("%d: %s\n", i, a[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printArray>:
  endbr64
  cmp    %rdx,%rsi
  jg     L18
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%r12,%rbx,8),%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jge    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: %d: %s


assistant: ```c
void printArray(char **a, long left, long right) {
  long i;
  for (i = left; i <= right; i = i + 1) {
    printf("%d: %s\n", i, a[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Wstr2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L27
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x0,-0x4(%rbp)
  jg     L35
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L23
  movl   $0x1,-0x8(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L12
L28:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int Wstr2int(char *str, int *iptr) {
  int i, j;
  sscanf(str, "%d", iptr);
  for (i = 0, j = ((*iptr) < 0 ? (*iptr) * -1 : (*iptr)); j > 0; i++)
    j /= 10;
  if (*iptr == 0)
    i = 1;
  if (str[0] == '+' || str[0] == '-')
    i++;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Wstr2int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  mov    0x0(%rbp),%r8d
  mov    %r8d,%edx
  neg    %edx
  cmovs  %r8d,%edx
  test   %edx,%edx
  jle    L23
  mov    $0x0,%ecx
L4:
  mov    %edx,%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  add    $0x1,%ecx
  cmp    $0x9,%esi
  jg     L4
L6:
  test   %r8d,%r8d
  mov    $0x1,%eax
  cmove  %eax,%ecx
  movzbl (%rbx),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%ecx
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0x0,%ecx
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int Wstr2int(char *str, int *iptr) {
  int i, j;
  sscanf(str, "%d", iptr);
  for (i = 0, j = ((*iptr) < 0 ? (*iptr) * -1 : (*iptr)); j > 0; i++)
    j /= 10;
  if (*iptr == 0)
    i = 1;
  if (str[0] == '+' || str[0] == '-')
    i++;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Wstr2int>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rsi,%rbp
  lea    D4(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <sscanf@plt>
  mov    0x0(%rbp),%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  test   %edx,%edx
  je     L18
  xor    %r8d,%r8d
  mov    $0xcccccccd,%edx
  nopl   (%rax)
L12:
  mov    %eax,%eax
  add    $0x1,%r8d
  imul   %rdx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L12
L4:
  movzbl (%rbx),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%r8d
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int Wstr2int(char *str, int *iptr) {
  int i, j;
  sscanf(str, "%d", iptr);
  for (i = 0, j = ((*iptr) < 0 ? (*iptr) * -1 : (*iptr)); j > 0; i++)
    j /= 10;
  if (*iptr == 0)
    i = 1;
  if (str[0] == '+' || str[0] == '-')
    i++;
  return (i);
}
```
user: What is the c source code of the assembly code below:

```asm
<Wstr2int>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rsi,%rbp
  lea    D2(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <sscanf@plt>
  mov    0x0(%rbp),%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  test   %edx,%edx
  je     L5
  xor    %r8d,%r8d
  mov    $0xcccccccd,%edx
  nopl   (%rax)
L29:
  mov    %eax,%eax
  add    $0x1,%r8d
  imul   %rdx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L29
L0:
  movzbl (%rbx),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%r8d
  jmp    L0
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: %d

assistant: ```c
int Wstr2int(char *str, int *iptr) {
  int i, j;
  sscanf(str, "%d", iptr);
  for (i = 0, j = ((*iptr) < 0 ? (*iptr) * -1 : (*iptr)); j > 0; i++)
    j /= 10;
  if (*iptr == 0)
    i = 1;
  if (str[0] == '+' || str[0] == '-')
    i++;
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rdtsc_is_invariant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x80000007,%edi
  call   <cpuid_edx@plt>
  and    $0x100,%eax
  test   %eax,%eax
  je     L10
  mov    $0x1,%eax
  jmp    L0
L10:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int rdtsc_is_invariant(void) {
  if (cpuid_edx(0x80000007) & (1 << 8)) {
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdtsc_is_invariant>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000007,%edi
  call   <cpuid_edx@plt>
  shr    $0x8,%eax
  and    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int rdtsc_is_invariant(void) {
  if (cpuid_edx(0x80000007) & (1 << 8)) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rdtsc_is_invariant>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000007,%edi
  call   <cpuid_edx@plt>
  add    $0x8,%rsp
  shr    $0x8,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int rdtsc_is_invariant(void) {
  if (cpuid_edx(0x80000007) & (1 << 8)) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <func@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %f


assistant: ```c
int main() {
  int array[] = {1, 2, 3, 4, 5};
  printf("%f\n", func(array, 5));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <func@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: %f


assistant: ```c
int main() {
  int array[] = {1, 2, 3, 4, 5};
  printf("%f\n", func(array, 5));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  movl   $0x5,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  call   <func@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: %f


assistant: ```c
int main() {
  int array[] = {1, 2, 3, 4, 5};
  printf("%f\n", func(array, 5));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x5,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <func@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: byte[16]
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: {"D2": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D0: %f


assistant: ```c
int main() {
  int array[] = {1, 2, 3, 4, 5};
  printf("%f\n", func(array, 5));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<double_add_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D38
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D16
data_type: string

tool: D38: DOUBLE_ADD_SUB:

tool: D26:   Input R1 = %f.


tool: D37:   Input R2 = %f.


tool: D16:   Output R3 = %f.


assistant: ```c
void double_add_sub(double *r1, double *r2, double *r3) {
  printf("\n");
  printf("DOUBLE_ADD_SUB:\n");
  printf("  Input R1 = %f.\n", *r1);
  printf("  Input R2 = %f.\n", *r2);
  *r3 = *r1 + *r2;
  printf("  Output R3 = %f.\n", *r3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<double_add_sub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  movsd  0x0(%rbp),%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rbx),%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x0(%rbp),%xmm0
  addsd  (%rbx),%xmm0
  movsd  %xmm0,(%r12)
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D4: DOUBLE_ADD_SUB:

tool: D0:   Input R1 = %f.


tool: D24:   Input R2 = %f.


tool: D13:   Output R3 = %f.


assistant: ```c
void double_add_sub(double *r1, double *r2, double *r3) {
  printf("\n");
  printf("DOUBLE_ADD_SUB:\n");
  printf("  Input R1 = %f.\n", *r1);
  printf("  Input R2 = %f.\n", *r2);
  *r3 = *r1 + *r2;
  printf("  Output R3 = %f.\n", *r3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<double_add_sub>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <putchar@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  movsd  0x0(%rbp),%xmm0
  mov    $0x1,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movsd  (%rbx),%xmm0
  mov    $0x1,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  movsd  0x0(%rbp),%xmm0
  addsd  (%rbx),%xmm0
  lea    D8(%rip),%rdi
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  movsd  %xmm0,(%r12)
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D8
data_type: string

tool: D36: DOUBLE_ADD_SUB:

tool: D10:   Input R1 = %f.


tool: D17:   Input R2 = %f.


tool: D8:   Output R3 = %f.


assistant: ```c
void double_add_sub(double *r1, double *r2, double *r3) {
  printf("\n");
  printf("DOUBLE_ADD_SUB:\n");
  printf("  Input R1 = %f.\n", *r1);
  printf("  Input R2 = %f.\n", *r2);
  *r3 = *r1 + *r2;
  printf("  Output R3 = %f.\n", *r3);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<double_add_sub>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <putchar@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  movsd  0x0(%rbp),%xmm0
  mov    $0x1,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  movsd  (%rbx),%xmm0
  mov    $0x1,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movsd  0x0(%rbp),%xmm0
  addsd  (%rbx),%xmm0
  lea    D14(%rip),%rdi
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  movsd  %xmm0,(%r12)
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
datatype: string
name: extract_symbolic_data
arguments: data_tag: D3
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string

tool: D13: DOUBLE_ADD_SUB:

tool: D3:   Input R1 = %f.


tool: D7:   Input R2 = %f.


tool: D14:   Output R3 = %f.


assistant: ```c
void double_add_sub(double *r1, double *r2, double *r3) {
  printf("\n");
  printf("DOUBLE_ADD_SUB:\n");
  printf("  Input R1 = %f.\n", *r1);
  printf("  Input R2 = %f.\n", *r2);
  *r3 = *r1 + *r2;
  printf("  Output R3 = %f.\n", *r3);
}
```