user: What would the C source look like for the assembly code provided here?

```asm
<testLU>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  mov    -0x40(%rbp),%rax
  movsd  D108(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  D32(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  D42(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  movsd  D102(%rip),%xmm0
  movsd  %xmm0,(%rax)
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  mov    -0x38(%rbp),%rax
  movsd  D108(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  D32(%rip),%xmm0
  movsd  %xmm0,(%rax)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x40(%rbp),%rax
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <LUDecomposition@plt>
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  lea    -0x20(%rbp),%rdx
  mov    $0x1,%r8d
  mov    %rdx,%rcx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <BackSubstitution@plt>
  mov    -0x20(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <BackSubstitution@plt>
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <zeros@plt>
  mov    -0x18(%rbp),%rsi
  mov    -0x40(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rdx
  push   %rdx
  mov    $0x1,%r9d
  mov    $0x2,%r8d
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <mult@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D108
type: byte[8]
name: retrieve_data
arguments: label: D32
type: byte[8]
name: retrieve_data
arguments: label: D42
type: byte[8]
name: retrieve_data
arguments: label: D102
type: byte[8]
name: retrieve_data
arguments: label: D66
type: string
name: retrieve_data
arguments: label: D40
type: string
name: retrieve_data
arguments: label: D64
type: string
name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D73
type: string

tool: {"D108": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D102": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D66: A


tool: D40: B


tool: D64: L


tool: D21: U


tool: D73: x


assistant: ```c
void testLU() {
  double *mat;
  zeros(2, 2, &mat);
  mat[0] = 1;
  mat[1] = 2;
  mat[1 * 2] = 3;
  mat[1 * 2 + 1] = 4;
  double *b;
  zeros(2, 1, &b);
  b[0] = 1;
  b[1] = 2;
  double *L, *U, *z, *x;
  zeros(2, 2, &L);
  zeros(2, 2, &U);
  zeros(2, 1, &z);
  zeros(2, 1, &x);
  printf("A\n");
  print(mat, 2, 2);
  printf("B\n");
  print(b, 2, 1);
  LUDecomposition(mat, 2, &L, &U);
  printf("L\n");
  print(L, 2, 2);
  printf("U\n");
  print(U, 2, 2);
  BackSubstitution(L, b, 2, &z, 1);
  BackSubstitution(U, z, 2, &x, 0);
  printf("x\n");
  print(x, 2, 1);
  double *bstar;
  zeros(2, 1, &bstar);
  mult(mat, x, 2, 2, 2, 1, &bstar);
  print(bstar, 2, 1);
}
```