ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<yudpsocket_sentto>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  mov    $0xc,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    %r15d,%edi
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %r14,%rdi
  mov    %eax,0x10(%rsp)
  call   <inet_addr@plt>
  xor    %ecx,%ecx
  mov    %r13d,%edx
  mov    $0xc,%r9d
  mov    %rbx,%r8
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,0xc(%rsp)
  call   <sendto@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yudpsocket_sentto(int socket_fd, char *msg, int len, char *toaddr, int topotr) {
  struct sockaddr_in address;
  socklen_t addrlen = sizeof(address);
  memset(&address, 0x0, sizeof(struct sockaddr_in));
  address.sin_family = AF_INET;
  address.sin_port = htons(topotr);
  address.sin_addr.s_addr = inet_addr(toaddr);
  int sendlen = (int)sendto(socket_fd, msg, len, 0, (struct sockaddr *)&address, addrlen);
  return sendlen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yudpsocket_sentto>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  mov    $0xc,%edx
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    %r15d,%edi
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %r14,%rdi
  mov    %eax,0x10(%rsp)
  call   <inet_addr@plt>
  xor    %ecx,%ecx
  mov    %r13d,%edx
  mov    $0xc,%r9d
  mov    %rbx,%r8
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,0xc(%rsp)
  call   <sendto@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yudpsocket_sentto(int socket_fd, char *msg, int len, char *toaddr, int topotr) {
  struct sockaddr_in address;
  socklen_t addrlen = sizeof(address);
  memset(&address, 0x0, sizeof(struct sockaddr_in));
  address.sin_family = AF_INET;
  address.sin_port = htons(topotr);
  address.sin_addr.s_addr = inet_addr(toaddr);
  int sendlen = (int)sendto(socket_fd, msg, len, 0, (struct sockaddr *)&address, addrlen);
  return sendlen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L12
L19:
  movl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L35
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x28(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D97(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L35:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L5
  mov    -0x2c(%rbp),%edx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L12:
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  jg     L19
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D88
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: f32[2]
name: extract_symbolic_data
arguments: data_tag: D48
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D97
datatype: f32[2]
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D88: How much is the limit? (<=0 to quit) :

tool: D12: %d

tool: {"D24": [0.0,-1.875]}

tool: D48: 1

tool: {"D97": [0.0,-0.0]}

tool: D21: Pos = %f and Neg = %f after %d times!


tool: D10: Thank you!

assistant: ```c
int main(void) {
  double pos, neg, minus;
  int i, j, limit;
  printf("How much is the limit? (<=0 to quit) :\n");
  scanf("%d", &limit);
  while (limit > 0) {
    for (i = 1, j = 1, pos = 0.0, neg = 0.0, minus = -1.0; i <= limit; i++, j++) {
      pos += 1.0 / i;
      minus *= -1.0;
      neg += 1.0 / (minus * j);
    }
    printf("Pos = %f and Neg = %f after %d times!\n", pos, neg, limit);
    printf("How much is the limit? (<=0 to quit) :\n");
    scanf("%d", &limit);
  }
  printf("Thank you!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L6
  mov    D47(%rip),%rbp
  lea    D36(%rip),%rbx
  jmp    L62
L63:
  lea    0x1(%rsi),%edx
  mov    $0x1,%eax
  movq   %rbp,%xmm4
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm3
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D66(%rip),%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm3
  xorpd  D90(%rip),%xmm4
  mulsd  %xmm4,%xmm0
  movsd  D66(%rip),%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L11
L30:
  movapd %xmm3,%xmm0
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L6
L62:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm3
  test   %esi,%esi
  jg     L63
  jmp    L30
L6:
  lea    D72(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D47
type: f32[2]
name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D66
type: f64
name: retrieve_data
arguments: tag: D90
type: f32[4]
name: retrieve_data
arguments: tag: D72
type: string

tool: D38: How much is the limit? (<=0 to quit) :

tool: D33: %d

tool: {"D47": [0.0,-1.875]}

tool: D36: Pos = %f and Neg = %f after %d times!


tool: D66: 1

tool: {"D90": [0.0,-0.0,0.0,0.0]}

tool: D72: Thank you!

assistant: ```c
int main(void) {
  double pos, neg, minus;
  int i, j, limit;
  printf("How much is the limit? (<=0 to quit) :\n");
  scanf("%d", &limit);
  while (limit > 0) {
    for (i = 1, j = 1, pos = 0.0, neg = 0.0, minus = -1.0; i <= limit; i++, j++) {
      pos += 1.0 / i;
      minus *= -1.0;
      neg += 1.0 / (minus * j);
    }
    printf("Pos = %f and Neg = %f after %d times!\n", pos, neg, limit);
    printf("How much is the limit? (<=0 to quit) :\n");
    scanf("%d", &limit);
  }
  printf("Thank you!");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D31(%rip),%rbp
  push   %rbx
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L39
  movsd  D42(%rip),%xmm4
  movq   D52(%rip),%xmm6
  lea    D58(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L15:
  mov    D86(%rip),%rdx
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movapd %xmm1,%xmm3
  movq   %rdx,%xmm2
  nopl   0x0(%rax)
L13:
  pxor   %xmm0,%xmm0
  movapd %xmm4,%xmm5
  xorpd  %xmm6,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  divsd  %xmm0,%xmm5
  mulsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm3
  movapd %xmm4,%xmm5
  divsd  %xmm0,%xmm5
  addsd  %xmm5,%xmm1
  cmp    %esi,%eax
  jle    L13
  movapd %xmm3,%xmm0
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    D42(%rip),%rax
  movq   D52(%rip),%xmm6
  test   %esi,%esi
  movq   %rax,%xmm4
  jg     L15
L39:
  xor    %eax,%eax
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D31
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D42
type_guessed: f64
name: disassemble_data
arguments: label: D52
type_guessed: f32[2]
name: disassemble_data
arguments: label: D58
type_guessed: string
name: disassemble_data
arguments: label: D86
type_guessed: f32[2]
name: disassemble_data
arguments: label: D61
type_guessed: string

tool: D31: %d

tool: D24: How much is the limit? (<=0 to quit) :

tool: D42: 1

tool: {"D52": [0.0,-0.0]}

tool: D58: Pos = %f and Neg = %f after %d times!


tool: {"D86": [0.0,-1.875]}

tool: D61: Thank you!

assistant: ```c
int main(void) {
  double pos, neg, minus;
  int i, j, limit;
  printf("How much is the limit? (<=0 to quit) :\n");
  scanf("%d", &limit);
  while (limit > 0) {
    for (i = 1, j = 1, pos = 0.0, neg = 0.0, minus = -1.0; i <= limit; i++, j++) {
      pos += 1.0 / i;
      minus *= -1.0;
      neg += 1.0 / (minus * j);
    }
    printf("Pos = %f and Neg = %f after %d times!\n", pos, neg, limit);
    printf("How much is the limit? (<=0 to quit) :\n");
    scanf("%d", &limit);
  }
  printf("Thank you!");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D85(%rip),%rbp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L37
  movsd  D84(%rip),%xmm4
  movq   D38(%rip),%xmm6
  lea    D12(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L12:
  mov    D28(%rip),%rdx
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movapd %xmm1,%xmm3
  movq   %rdx,%xmm2
  nopl   0x0(%rax)
L28:
  pxor   %xmm0,%xmm0
  movapd %xmm4,%xmm5
  xorpd  %xmm6,%xmm2
  cvtsi2sd %eax,%xmm0
  add    $0x1,%eax
  divsd  %xmm0,%xmm5
  mulsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm3
  movapd %xmm4,%xmm5
  divsd  %xmm0,%xmm5
  addsd  %xmm5,%xmm1
  cmp    %esi,%eax
  jle    L28
  movapd %xmm3,%xmm0
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    D84(%rip),%rax
  movq   D38(%rip),%xmm6
  test   %esi,%esi
  movq   %rax,%xmm4
  jg     L12
L37:
  xor    %eax,%eax
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D85
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D84
datatype: f64
name: unpack_data
arguments: tag: D38
datatype: f32[2]
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D28
datatype: f32[2]
name: unpack_data
arguments: tag: D66
datatype: string

tool: D85: %d

tool: D1: How much is the limit? (<=0 to quit) :

tool: D84: 1

tool: {"D38": [0.0,-0.0]}

tool: D12: Pos = %f and Neg = %f after %d times!


tool: {"D28": [0.0,-1.875]}

tool: D66: Thank you!

assistant: ```c
int main(void) {
  double pos, neg, minus;
  int i, j, limit;
  printf("How much is the limit? (<=0 to quit) :\n");
  scanf("%d", &limit);
  while (limit > 0) {
    for (i = 1, j = 1, pos = 0.0, neg = 0.0, minus = -1.0; i <= limit; i++, j++) {
      pos += 1.0 / i;
      minus *= -1.0;
      neg += 1.0 / (minus * j);
    }
    printf("Pos = %f and Neg = %f after %d times!\n", pos, neg, limit);
    printf("How much is the limit? (<=0 to quit) :\n");
    scanf("%d", &limit);
  }
  printf("Thank you!");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<serverThreadJob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L0:
  mov    $0x0,%eax
  call   <workQueuePop@plt>
  mov    %eax,%edi
  call   <handleClientRequest@plt>
  jmp    L0
```

assistant: ```c
void *serverThreadJob(void *unused) {
  (void)(unused);
  while (true)
    handleClientRequest(workQueuePop());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serverThreadJob>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <workQueuePop@plt>
  mov    %eax,%edi
  call   <handleClientRequest@plt>
  jmp    L0
```

assistant: ```c
void *serverThreadJob(void *unused) {
  (void)(unused);
  while (true)
    handleClientRequest(workQueuePop());
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<serverThreadJob>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <workQueuePop@plt>
  mov    %eax,%edi
  call   <handleClientRequest@plt>
  jmp    L3
```

assistant: ```c
void *serverThreadJob(void *unused) {
  (void)(unused);
  while (true)
    handleClientRequest(workQueuePop());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serverThreadJob>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <workQueuePop@plt>
  mov    %eax,%edi
  call   <handleClientRequest@plt>
  jmp    L3
```

assistant: ```c
void *serverThreadJob(void *unused) {
  (void)(unused);
  while (true)
    handleClientRequest(workQueuePop());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dnrm2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jle    L87
  cmpq   $0x0,-0x18(%rbp)
  jle    L87
  cmpq   $0x1,-0x20(%rbp)
  jne    L43
  mov    -0x50(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D12(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  jmp    L29
L43:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x40(%rbp)
  jmp    L32
L12:
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L22
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  je     L6
L22:
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D12(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L54
  movsd  -0x30(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  jmp    L6
L54:
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x40(%rbp)
L32:
  cmpq   $0x0,-0x40(%rbp)
  jns    L12
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x30(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  jmp    L29
L87:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
L29:
  movsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type: qword
name: parse_data
arguments: tag: D1
type: f64

tool: D12: 9223372036854775807

tool: D1: 1

assistant: ```c
double dnrm2_(int *n, double *x, int *incx) {
  long int ix, nn, iincx;
  double norm, scale, absxi, ssq, temp;
  nn = *n;
  iincx = *incx;
  if (nn > 0 && iincx > 0) {
    if (nn == 1) {
      norm = fabs(x[0]);
    } else {
      scale = 0.0;
      ssq = 1.0;
      for (ix = (nn - 1) * iincx; ix >= 0; ix -= iincx) {
        if (x[ix] != 0.0) {
          absxi = fabs(x[ix]);
          if (scale < absxi) {
            temp = scale / absxi;
            ssq = ssq * (temp * temp) + 1.0;
            scale = absxi;
          } else {
            temp = absxi / scale;
            ssq += temp * temp;
          }
        }
      }
      norm = scale * sqrt(ssq);
    }
  } else
    norm = 0.0;
  return norm;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dnrm2_>:
  endbr64
  movslq (%rdi),%rax
  mov    (%rdx),%edi
  test   %rax,%rax
  jle    L70
  movslq %edi,%rcx
  test   %rcx,%rcx
  jle    L70
  cmp    $0x1,%rax
  je     L74
  sub    $0x18,%rsp
  sub    $0x1,%rax
  imul   %rcx,%rax
  movslq %edi,%rdi
  neg    %rdi
  shl    $0x3,%rdi
  lea    (%rsi,%rax,8),%rdx
  movsd  D27(%rip),%xmm0
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movapd %xmm7,%xmm4
  movq   D13(%rip),%xmm6
  movapd %xmm0,%xmm7
  movapd %xmm4,%xmm5
  jmp    L66
L74:
  movsd  (%rsi),%xmm0
  andpd  D13(%rip),%xmm0
  ret
L86:
  divsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L104:
  add    %rdi,%rdx
  sub    %rcx,%rax
  js     L75
L66:
  movsd  (%rdx),%xmm1
  ucomisd %xmm4,%xmm1
  jp     L26
  ucomisd %xmm5,%xmm1
  je     L104
L26:
  movapd %xmm1,%xmm2
  andpd  %xmm6,%xmm2
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm2
  jbe    L86
  divsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm3
  mulsd  %xmm3,%xmm0
  addsd  %xmm7,%xmm0
  movsd  %xmm2,0x8(%rsp)
  jmp    L104
L75:
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L31:
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L10:
  call   <sqrt@plt>
  jmp    L31
L70:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D27
data_type: f64
name: retrieve_data
arguments: tag: D13
data_type: qword[2]

tool: D27: 1

tool: {"D13": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double dnrm2_(int *n, double *x, int *incx) {
  long int ix, nn, iincx;
  double norm, scale, absxi, ssq, temp;
  nn = *n;
  iincx = *incx;
  if (nn > 0 && iincx > 0) {
    if (nn == 1) {
      norm = fabs(x[0]);
    } else {
      scale = 0.0;
      ssq = 1.0;
      for (ix = (nn - 1) * iincx; ix >= 0; ix -= iincx) {
        if (x[ix] != 0.0) {
          absxi = fabs(x[ix]);
          if (scale < absxi) {
            temp = scale / absxi;
            ssq = ssq * (temp * temp) + 1.0;
            scale = absxi;
          } else {
            temp = absxi / scale;
            ssq += temp * temp;
          }
        }
      }
      norm = scale * sqrt(ssq);
    }
  } else
    norm = 0.0;
  return norm;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dnrm2_>:
  endbr64
  movslq (%rdi),%rax
  movslq (%rdx),%rcx
  test   %rax,%rax
  jle    L12
  test   %rcx,%rcx
  jle    L12
  cmp    $0x1,%rax
  je     L37
  sub    $0x1,%rax
  movsd  D4(%rip),%xmm6
  mov    %rcx,%rdi
  pxor   %xmm3,%xmm3
  imul   %rcx,%rax
  neg    %rdi
  movq   D1(%rip),%xmm5
  movapd %xmm3,%xmm2
  shl    $0x3,%rdi
  movapd %xmm6,%xmm0
  lea    (%rsi,%rax,8),%rdx
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L18:
  divsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm2
  mulsd  %xmm2,%xmm0
  movapd %xmm4,%xmm2
  addsd  %xmm6,%xmm0
L87:
  add    %rdi,%rdx
  sub    %rcx,%rax
  js     L7
L45:
  movsd  (%rdx),%xmm1
  ucomisd %xmm3,%xmm1
  jp     L51
  je     L87
L51:
  movapd %xmm1,%xmm4
  andpd  %xmm5,%xmm4
  comisd %xmm2,%xmm4
  ja     L18
  divsd  %xmm2,%xmm1
  add    %rdi,%rdx
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  sub    %rcx,%rax
  jns    L45
L7:
  ucomisd %xmm0,%xmm3
  ja     L15
  sqrtsd %xmm0,%xmm0
  mulsd  %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L12:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L37:
  movsd  (%rsi),%xmm0
  andpd  D1(%rip),%xmm0
  ret
L15:
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  mulsd  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: f64
name: read_data
arguments: data_tag: D1
datatype: qword[2]

tool: D4: 1

tool: {"D1": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double dnrm2_(int *n, double *x, int *incx) {
  long int ix, nn, iincx;
  double norm, scale, absxi, ssq, temp;
  nn = *n;
  iincx = *incx;
  if (nn > 0 && iincx > 0) {
    if (nn == 1) {
      norm = fabs(x[0]);
    } else {
      scale = 0.0;
      ssq = 1.0;
      for (ix = (nn - 1) * iincx; ix >= 0; ix -= iincx) {
        if (x[ix] != 0.0) {
          absxi = fabs(x[ix]);
          if (scale < absxi) {
            temp = scale / absxi;
            ssq = ssq * (temp * temp) + 1.0;
            scale = absxi;
          } else {
            temp = absxi / scale;
            ssq += temp * temp;
          }
        }
      }
      norm = scale * sqrt(ssq);
    }
  } else
    norm = 0.0;
  return norm;
}
```