ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<dirnl_emit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L9
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  lea    D12(%rip),%rdx
  mov    %eax,%esi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L3
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x10(%rbp),%edx
  mov    %edx,%ecx
  lea    D5(%rip),%rdx
  mov    %eax,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L2
L3:
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    %ecx,%r8d
  mov    %edx,%ecx
  lea    D18(%rip),%rdx
  mov    %eax,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string

tool: D12: ,

tool: D5: %d

tool: D18: %d-%d

assistant: ```c
int dirnl_emit(char *buf, int buflen, int rbot, int rtop, int len) {
  if (len > 0)
    len += snprintf(buf + len, buflen - len, ",");
  if (rbot == rtop)
    len += snprintf(buf + len, buflen - len, "%d", rbot);
  else
    len += snprintf(buf + len, buflen - len, "%d-%d", rbot, rtop);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dirnl_emit>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%ebx
  test   %r8d,%r8d
  jg     L8
L6:
  cmp    %r13d,%r12d
  je     L35
  mov    %ebp,%esi
  sub    %ebx,%esi
  movslq %ebx,%rax
  lea    (%r14,%rax,1),%rdi
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  lea    D18(%rip),%rdx
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    %ebx,%eax
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  sub    %r8d,%esi
  movslq %r8d,%rdi
  add    %r14,%rdi
  lea    D11(%rip),%rdx
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    %eax,%ebx
  jmp    L6
L35:
  mov    %ebp,%esi
  sub    %ebx,%esi
  movslq %ebx,%rdi
  add    %r14,%rdi
  mov    %r12d,%ecx
  lea    D19(%rip),%rdx
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    %ebx,%eax
  jmp    L31
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D18: %d-%d

tool: D11: ,

tool: D19: %d

assistant: ```c
int dirnl_emit(char *buf, int buflen, int rbot, int rtop, int len) {
  if (len > 0)
    len += snprintf(buf + len, buflen - len, ",");
  if (rbot == rtop)
    len += snprintf(buf + len, buflen - len, "%d", rbot);
  else
    len += snprintf(buf + len, buflen - len, "%d-%d", rbot, rtop);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dirnl_emit>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %r8d,%rbx
  mov    %ebx,%r13d
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L16
  movslq %ebx,%rdi
  sub    %ebx,%esi
  lea    D28(%rip),%rdx
  xor    %eax,%eax
  add    %rbp,%rdi
  call   <snprintf@plt>
  lea    (%rbx,%rax,1),%r13d
  movslq %r13d,%rbx
L16:
  mov    %r12d,%esi
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %ebx,%esi
  cmp    %r15d,%r14d
  je     L5
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  lea    D2(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14d,%ecx
  lea    D27(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D2
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string

tool: D28: ,

tool: D2: %d-%d

tool: D27: %d

assistant: ```c
int dirnl_emit(char *buf, int buflen, int rbot, int rtop, int len) {
  if (len > 0)
    len += snprintf(buf + len, buflen - len, ",");
  if (rbot == rtop)
    len += snprintf(buf + len, buflen - len, "%d", rbot);
  else
    len += snprintf(buf + len, buflen - len, "%d-%d", rbot, rtop);
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dirnl_emit>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %r8d,%rbx
  mov    %ebx,%r13d
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L7
  movslq %ebx,%rdi
  sub    %ebx,%esi
  lea    D26(%rip),%rdx
  xor    %eax,%eax
  add    %rbp,%rdi
  call   <snprintf@plt>
  lea    (%rbx,%rax,1),%r13d
  movslq %r13d,%rbx
L7:
  mov    %r12d,%esi
  lea    0x0(%rbp,%rbx,1),%rdi
  sub    %ebx,%esi
  cmp    %r15d,%r14d
  je     L18
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  lea    D9(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r14d,%ecx
  lea    D8(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
type: string
name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D26: ,

tool: D9: %d-%d

tool: D8: %d

assistant: ```c
int dirnl_emit(char *buf, int buflen, int rbot, int rtop, int len) {
  if (len > 0)
    len += snprintf(buf + len, buflen - len, ",");
  if (rbot == rtop)
    len += snprintf(buf + len, buflen - len, "%d", rbot);
  else
    len += snprintf(buf + len, buflen - len, "%d-%d", rbot, rtop);
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<rtl_getvar2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L22
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L22:
  lea    D4(%rip),%rax
  jmp    L46
L5:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  lea    D4(%rip),%rax
  jmp    L46
L29:
  mov    -0x8(%rbp),%rax
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: 

assistant: ```c
char *rtl_getvar2(void *user, char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtl_getvar2>:
  endbr64
  lea    D14(%rip),%rax
  test   %rsi,%rsi
  je     L7
  cmpb   $0x0,(%rsi)
  jne    L0
L7:
  ret
L0:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  lea    D14(%rip),%rdx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string

tool: 

assistant: ```c
char *rtl_getvar2(void *user, char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtl_getvar2>:
  endbr64
  test   %rsi,%rsi
  je     L10
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rdi
  jne    L22
L10:
  lea    D12(%rip),%rax
  ret
  nopl   0x0(%rax)
L22:
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L20
  lea    D12(%rip),%rax
L20:
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string

tool: 

assistant: ```c
char *rtl_getvar2(void *user, char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtl_getvar2>:
  endbr64
  test   %rsi,%rsi
  je     L29
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rdi
  jne    L24
L29:
  lea    D19(%rip),%rax
  ret
  nopl   0x0(%rax)
L24:
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L15
  lea    D19(%rip),%rax
L15:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: string

tool: 

assistant: ```c
char *rtl_getvar2(void *user, char *name) {
  char *val;
  if (!name || !*name)
    return "";
  val = (char *)getenv(name);
  if (!val)
    return "";
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<residuo>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf68,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x3e8,%esi
  call   <clean@plt>
  cmp    %r13d,%ebx
  jge    L148
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,8),%rax
  sub    $0x1,%r13d
  sub    %ebx,%r13d
  add    %r13,%rdx
  lea    0x8(%rbp,%rdx,8),%rdx
  pxor   %xmm1,%xmm1
L122:
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L122
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L105
L70:
  sqrtsd %xmm1,%xmm1
  movsd  %xmm1,0x8(%rsp)
L66:
  test   %ebx,%ebx
  jle    L100
  mov    %r12,%rsi
  lea    -0x1(%rbx),%r8d
  mov    %ebx,%edi
  mov    $0x0,%ecx
  jmp    L52
L148:
  pxor   %xmm1,%xmm1
  jmp    L70
L105:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L66
L0:
  movsd  0x10(%rsp,%rcx,8),%xmm1
  mov    %rsi,%rdx
  mov    %rcx,%rax
L41:
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  0x0(%rbp,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L41
  movsd  %xmm1,0x10(%rsp,%rcx,8)
L97:
  add    $0x1,%rcx
  add    $0x1f40,%rsi
  cmp    %rdi,%rcx
  je     L62
L52:
  cmp    %ecx,%ebx
  jg     L0
  jmp    L97
L62:
  lea    0x10(%rsp),%rax
  lea    0x18(%rsp,%r8,8),%rdx
  pxor   %xmm1,%xmm1
L121:
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L121
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L94
L58:
  sqrtsd %xmm1,%xmm1
L136:
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L147
  add    $0x1f68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L100:
  pxor   %xmm1,%xmm1
  jmp    L58
L94:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L136
L147:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Residuo: = %.5f 


assistant: ```c
void residuo(double A[1000][1000], double b[1000], int rank, int n, int m) {
  double res1, res2;
  double aux[1000];
  int i, j;
  clean(aux, 1000);
  res1 = res2 = 0;
  for (i = rank; i < n; i++)
    res1 += (b[i] * b[i]);
  res1 = sqrt(res1);
  for (i = 0; i < rank; i++)
    for (j = i; j < rank; j++)
      aux[i] += (A[i][j] * b[j]);
  for (i = 0; i < rank; i++)
    res2 += (aux[i] * aux[i]);
  res2 = sqrt(res2);
  printf("Residuo: = %.5f \n", res1 + res2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<residuo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  lea    0x10(%rsp),%r13
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  mov    %ecx,%r14d
  mov    $0x3e8,%esi
  mov    %r13,%rdi
  call   <clean@plt>
  cmp    %r14d,%ebp
  jge    L43
  sub    $0x1,%r14d
  movslq %ebp,%rdx
  pxor   %xmm4,%xmm4
  sub    %ebp,%r14d
  lea    (%r12,%rdx,8),%rax
  movapd %xmm4,%xmm3
  add    %r14,%rdx
  lea    0x8(%r12,%rdx,8),%rdx
  cs nopw 0x0(%rax,%rax,1)
L100:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm3
  cmp    %rdx,%rax
  jne    L100
  ucomisd %xmm3,%xmm4
  ja     L41
L15:
  sqrtsd %xmm3,%xmm3
L9:
  test   %ebp,%ebp
  jle    L126
  mov    %rbx,%rdx
  lea    -0x1(%rbp),%edi
  mov    %ebp,%esi
  xor    %ecx,%ecx
  nopl   (%rax)
L122:
  movsd  0x0(%r13,%rcx,8),%xmm2
  mov    %rcx,%rax
  nopw   0x0(%rax,%rax,1)
L17:
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  (%r12,%rax,8),%xmm1
  add    $0x1,%rax
  addsd  %xmm1,%xmm2
  cmp    %eax,%ebp
  jg     L17
  movsd  %xmm2,0x0(%r13,%rcx,8)
  add    $0x1,%rcx
  add    $0x1f40,%rdx
  cmp    %rcx,%rsi
  jne    L122
  mov    %r13,%rax
  lea    0x18(%rsp,%rdi,8),%rdx
  movapd %xmm4,%xmm0
  nopw   0x0(%rax,%rax,1)
L65:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L65
  ucomisd %xmm0,%xmm4
  ja     L82
L76:
  sqrtsd %xmm0,%xmm0
L61:
  addsd  %xmm3,%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x1f60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm3
  jmp    L15
L126:
  movapd %xmm4,%xmm0
  jmp    L76
L41:
  movapd %xmm3,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movapd %xmm0,%xmm3
  jmp    L9
L53:
  call   <__stack_chk_fail@plt>
L82:
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  jmp    L61
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: Residuo: = %.5f 


assistant: ```c
void residuo(double A[1000][1000], double b[1000], int rank, int n, int m) {
  double res1, res2;
  double aux[1000];
  int i, j;
  clean(aux, 1000);
  res1 = res2 = 0;
  for (i = rank; i < n; i++)
    res1 += (b[i] * b[i]);
  res1 = sqrt(res1);
  for (i = 0; i < rank; i++)
    for (j = i; j < rank; j++)
      aux[i] += (A[i][j] * b[j]);
  for (i = 0; i < rank; i++)
    res2 += (aux[i] * aux[i]);
  res2 = sqrt(res2);
  printf("Residuo: = %.5f \n", res1 + res2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ParseOneUri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jne    L93
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x69,%al
  jne    L93
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x6c,%al
  jne    L93
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x65,%al
  jne    L93
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L93
  addq   $0x5,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L105
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L105
  addq   $0x2,-0x18(%rbp)
  jmp    L33
L21:
  cmpb   $0x0,-0x1(%rbp)
  je     L23
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x2f,-0x1(%rbp)
  jne    L21
L105:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Sony_Insert1@plt>
  jmp    L93
L23:
  nop
L93:
  leave
  ret
```

assistant: ```c
void ParseOneUri(char *s) {
  if (('f' == s[0]) && ('i' == s[1]) && ('l' == s[2]) && ('e' == s[3]) && (':' == s[4])) {
    s += 5;
    if (('/' == s[0]) && ('/' == s[1])) {
      char c;
      s += 2;
      while ((c = *s) != '/') {
        if (0 == c) {
          return;
        }
        ++s;
      }
    }
    (void)Sony_Insert1(s, 0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ParseOneUri>:
  endbr64
  cmpb   $0x66,(%rdi)
  je     L57
L89:
  ret
L57:
  cmpb   $0x69,0x1(%rdi)
  jne    L89
  cmpb   $0x6c,0x2(%rdi)
  jne    L89
  cmpb   $0x65,0x3(%rdi)
  jne    L89
  cmpb   $0x3a,0x4(%rdi)
  jne    L89
  lea    0x5(%rdi),%rax
  cmpb   $0x2f,0x5(%rdi)
  jne    L71
  cmpb   $0x2f,0x6(%rdi)
  je     L2
L71:
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Sony_Insert1@plt>
  add    $0x8,%rsp
  ret
L2:
  lea    0x7(%rdi),%rax
  movzbl 0x7(%rdi),%edx
  cmp    $0x2f,%dl
  je     L71
L51:
  test   %dl,%dl
  je     L89
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L51
  jmp    L71
```

assistant: ```c
void ParseOneUri(char *s) {
  if (('f' == s[0]) && ('i' == s[1]) && ('l' == s[2]) && ('e' == s[3]) && (':' == s[4])) {
    s += 5;
    if (('/' == s[0]) && ('/' == s[1])) {
      char c;
      s += 2;
      while ((c = *s) != '/') {
        if (0 == c) {
          return;
        }
        ++s;
      }
    }
    (void)Sony_Insert1(s, 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ParseOneUri>:
  endbr64
  cmpb   $0x66,(%rdi)
  je     L63
L4:
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  cmpb   $0x69,0x1(%rdi)
  jne    L4
  cmpb   $0x6c,0x2(%rdi)
  jne    L4
  cmpb   $0x65,0x3(%rdi)
  jne    L4
  cmpb   $0x3a,0x4(%rdi)
  jne    L4
  cmpb   $0x2f,0x5(%rdi)
  lea    0x5(%rdi),%r8
  jne    L61
  cmpb   $0x2f,0x6(%rdi)
  je     L84
L61:
  xor    %esi,%esi
  mov    %r8,%rdi
  jmp    1050 <Sony_Insert1@plt>
L84:
  movzbl 0x7(%rdi),%eax
  lea    0x7(%rdi),%r8
  cmp    $0x2f,%al
  jne    L70
  jmp    L61
L100:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x2f,%al
  je     L61
L70:
  test   %al,%al
  jne    L100
  ret
```

assistant: ```c
void ParseOneUri(char *s) {
  if (('f' == s[0]) && ('i' == s[1]) && ('l' == s[2]) && ('e' == s[3]) && (':' == s[4])) {
    s += 5;
    if (('/' == s[0]) && ('/' == s[1])) {
      char c;
      s += 2;
      while ((c = *s) != '/') {
        if (0 == c) {
          return;
        }
        ++s;
      }
    }
    (void)Sony_Insert1(s, 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ParseOneUri>:
  endbr64
  cmpb   $0x66,(%rdi)
  je     L84
L59:
  ret
  nopw   0x0(%rax,%rax,1)
L84:
  cmpb   $0x69,0x1(%rdi)
  jne    L59
  cmpb   $0x6c,0x2(%rdi)
  jne    L59
  cmpb   $0x65,0x3(%rdi)
  jne    L59
  cmpb   $0x3a,0x4(%rdi)
  jne    L59
  cmpb   $0x2f,0x5(%rdi)
  lea    0x5(%rdi),%r8
  jne    L52
  cmpb   $0x2f,0x6(%rdi)
  je     L103
L52:
  xor    %esi,%esi
  mov    %r8,%rdi
  jmp    1050 <Sony_Insert1@plt>
L103:
  movzbl 0x7(%rdi),%eax
  lea    0x7(%rdi),%r8
  cmp    $0x2f,%al
  jne    L9
  jmp    L52
L11:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x2f,%al
  je     L52
L9:
  test   %al,%al
  jne    L11
  ret
```

assistant: ```c
void ParseOneUri(char *s) {
  if (('f' == s[0]) && ('i' == s[1]) && ('l' == s[2]) && ('e' == s[3]) && (':' == s[4])) {
    s += 5;
    if (('/' == s[0]) && ('/' == s[1])) {
      char c;
      s += 2;
      while ((c = *s) != '/') {
        if (0 == c) {
          return;
        }
        ++s;
      }
    }
    (void)Sony_Insert1(s, 0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x186a0,%eax
  jg     L28
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L28:
  mov    -0x10(%rbp),%eax
  cmp    $0x186a0,%eax
  jle    L15
  mov    -0x10(%rbp),%eax
  cmp    $0x249f0,%eax
  jg     L15
  mov    -0x10(%rbp),%eax
  sub    $0x186a0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L15:
  mov    -0x10(%rbp),%eax
  sub    $0x249f0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D51(%rip),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D56
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D38
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D51
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D59
data_type: string

tool: D2: Enter your salary: 

tool: D56: %d

tool: D7: 0.15

tool: D38: 0.25

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x4c,0xbd,0x40]}

tool: D59: 
The net salary is %d

assistant: ```c
int main(void) {
  int salary, tax;
  printf("Enter your salary: ");
  scanf("%d", &salary);
  if (salary <= 100000)
    tax = salary * 0;
  else if (salary > 100000 && salary <= 150000)
    tax = (salary - 100000) * 0.15 + 100000 * 0;
  else
    tax = (salary - 150000) * 0.25 + (150000 - 100000) * 0.15 + 100000 * 0;
  printf("\nThe net salary is %d", salary - tax);
  return 0;
}
```