user: 这段汇编代码用C语言表示是什么样的？

```asm
<eval_6hand_fast>:
  endbr64
  push   %r14
  mov    $0x270f,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xa0,%rsp
  movdqa D62(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    D48(%rip),%rax
  lea    0x20(%rsp),%rbx
  mov    %rsp,%r12
  movaps %xmm0,0x20(%rsp)
  movdqa D12(%rip),%xmm0
  lea    0x98(%rsp),%r13
  mov    %rax,0x90(%rsp)
  movaps %xmm0,0x30(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D45(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D14(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D79(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  movdqa D15(%rip),%xmm0
  movaps %xmm0,0x80(%rsp)
  nopl   0x0(%rax)
L3:
  movslq 0x4(%rbx),%rax
  movslq 0xc(%rbx),%rcx
  mov    %r12,%rdi
  movslq (%rbx),%rdx
  movslq 0x8(%rbx),%rsi
  mov    0x0(%rbp,%rax,4),%eax
  mov    0x0(%rbp,%rcx,4),%ecx
  movd   0x0(%rbp,%rdx,4),%xmm0
  movd   0x0(%rbp,%rsi,4),%xmm1
  movd   %eax,%xmm3
  movslq 0x10(%rbx),%rax
  movd   %ecx,%xmm2
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  mov    0x0(%rbp,%rax,4),%eax
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  mov    %eax,0x10(%rsp)
  call   <eval_5hand_fast@plt>
  movswl %r14w,%edx
  cmp    %eax,%edx
  cmovg  %eax,%r14d
  add    $0x14,%rbx
  cmp    %r13,%rbx
  jne    L3
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa0,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D62
type_infered: byte[16]
name: unpack_data
arguments: label: D48
type_infered: byte[8]
name: unpack_data
arguments: label: D12
type_infered: byte[16]
name: unpack_data
arguments: label: D9
type_infered: byte[16]
name: unpack_data
arguments: label: D45
type_infered: byte[16]
name: unpack_data
arguments: label: D14
type_infered: byte[16]
name: unpack_data
arguments: label: D79
type_infered: byte[16]
name: unpack_data
arguments: label: D15
type_infered: byte[16]

tool: {"D62": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D48": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D9": [0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D45": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D79": [0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D15": [0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
short eval_6hand_fast(int *hand) {
  int i;
  short best = 9999;
  int perm[][5] = {
      {0, 1, 2, 3, 4}, {0, 1, 2, 3, 5}, {0, 1, 2, 4, 5}, {0, 1, 3, 4, 5}, {0, 2, 3, 4, 5}, {1, 2, 3, 4, 5},
  };
  for (i = 0; i < 6; i++) {
    int subhand[5];
    int j;
    for (j = 0; j < 5; j++)
      subhand[j] = hand[perm[i][j]];
    int q = eval_5hand_fast(subhand);
    if (q < best)
      best = q;
  }
  return best;
}
```