ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x9,0x4(%rsp)
  je     L155
L193:
  cmpl   $0x8,0x4(%rsp)
  je     L67
L165:
  cmpl   $0x7,0x4(%rsp)
  je     L72
L81:
  cmpl   $0x6,0x4(%rsp)
  je     L195
L74:
  cmpl   $0x5,0x4(%rsp)
  je     L149
L119:
  cmpl   $0x4,0x4(%rsp)
  je     L29
L42:
  cmpl   $0x3,0x4(%rsp)
  je     L41
L130:
  cmpl   $0x2,0x4(%rsp)
  je     L105
L163:
  cmpl   $0x1,0x4(%rsp)
  je     L13
L197:
  cmpl   $0x0,0x4(%rsp)
  je     L143
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L191
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L155:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L193
L67:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L165
L72:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L81
L195:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L74
L149:
  lea    D83(%rip),%rdi
  call   <printf@plt>
  jmp    L119
L29:
  lea    D93(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L41:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L130
L105:
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L163
L13:
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L197
L143:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L191:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D64
datatype: string
name: unpack_data
arguments: label: D46
datatype: string
name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D62
datatype: string
name: unpack_data
arguments: label: D83
datatype: string
name: unpack_data
arguments: label: D93
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D57
datatype: string
name: unpack_data
arguments: label: D63
datatype: string
name: unpack_data
arguments: label: D28
datatype: string

tool: D0: %d

tool: D64: 
 nine

tool: D46: 
 eight

tool: D19: 
 seven

tool: D62: 
 six

tool: D83: 
 five

tool: D93: 
 four

tool: D4: 
 three

tool: D57: 
 two

tool: D63: 
 one

tool: D28: 
 zero

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 9)
    printf("\n nine");
  if (n == 8)
    printf("\n eight");
  if (n == 7)
    printf("\n seven");
  if (n == 6)
    printf("\n six");
  if (n == 5)
    printf("\n five");
  if (n == 4)
    printf("\n four");
  if (n == 3)
    printf("\n three");
  if (n == 2)
    printf("\n two");
  if (n == 1)
    printf("\n one");
  if (n == 0)
    printf("\n zero");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D46(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  je     L173
L11:
  cmp    $0x8,%eax
  je     L0
L204:
  cmp    $0x7,%eax
  je     L118
L95:
  cmp    $0x6,%eax
  je     L164
L129:
  cmp    $0x5,%eax
  je     L59
L159:
  cmp    $0x4,%eax
  je     L64
L200:
  cmp    $0x3,%eax
  je     L58
L32:
  cmp    $0x2,%eax
  je     L132
L199:
  cmp    $0x1,%eax
  je     L202
L126:
  test   %eax,%eax
  je     L26
L121:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L121
L202:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L126
L132:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L199
L58:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L32
L64:
  lea    D68(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L200
L59:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L159
L164:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L129
L118:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L95
L0:
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L204
L173:
  lea    D91(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L11
L131:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D46
type_guessed: string
name: disassemble_data
arguments: data_tag: D84
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D64
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: string
name: disassemble_data
arguments: data_tag: D68
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D31
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string
name: disassemble_data
arguments: data_tag: D66
type_guessed: string
name: disassemble_data
arguments: data_tag: D91
type_guessed: string

tool: D46: %d

tool: D84: 
 zero

tool: D5: 
 one

tool: D64: 
 two

tool: D24: 
 three

tool: D68: 
 four

tool: D7: 
 five

tool: D31: 
 six

tool: D38: 
 seven

tool: D66: 
 eight

tool: D91: 
 nine

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 9)
    printf("\n nine");
  if (n == 8)
    printf("\n eight");
  if (n == 7)
    printf("\n seven");
  if (n == 6)
    printf("\n six");
  if (n == 5)
    printf("\n five");
  if (n == 4)
    printf("\n four");
  if (n == 3)
    printf("\n three");
  if (n == 2)
    printf("\n two");
  if (n == 1)
    printf("\n one");
  if (n == 0)
    printf("\n zero");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D103(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  je     L57
L166:
  cmp    $0x8,%eax
  je     L125
L62:
  cmp    $0x7,%eax
  je     L102
L44:
  cmp    $0x6,%eax
  je     L91
L187:
  cmp    $0x5,%eax
  je     L1
L70:
  cmp    $0x4,%eax
  je     L164
L11:
  cmp    $0x3,%eax
  je     L89
L197:
  cmp    $0x2,%eax
  je     L207
L151:
  cmp    $0x1,%eax
  je     L77
L86:
  test   %eax,%eax
  je     L47
L108:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L208
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L47:
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L108
L77:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L86
L207:
  lea    D100(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L151
L89:
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L197
L164:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L11
L1:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L70
L91:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L187
L102:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L44
L125:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L62
L57:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L166
L208:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D103
datatype: string
name: parse_data
arguments: tag: D58
datatype: string
name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D100
datatype: string
name: parse_data
arguments: tag: D56
datatype: string
name: parse_data
arguments: tag: D44
datatype: string
name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D49
datatype: string
name: parse_data
arguments: tag: D50
datatype: string
name: parse_data
arguments: tag: D48
datatype: string
name: parse_data
arguments: tag: D30
datatype: string

tool: D103: %d

tool: D58: 
 zero

tool: D34: 
 one

tool: D100: 
 two

tool: D56: 
 three

tool: D44: 
 four

tool: D12: 
 five

tool: D49: 
 six

tool: D50: 
 seven

tool: D48: 
 eight

tool: D30: 
 nine

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n == 9)
    printf("\n nine");
  if (n == 8)
    printf("\n eight");
  if (n == 7)
    printf("\n seven");
  if (n == 6)
    printf("\n six");
  if (n == 5)
    printf("\n five");
  if (n == 4)
    printf("\n four");
  if (n == 3)
    printf("\n three");
  if (n == 2)
    printf("\n two");
  if (n == 1)
    printf("\n one");
  if (n == 0)
    printf("\n zero");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  shrq   $0x18,-0x8(%rbp)
  shrq   -0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  unsigned ma, mb;
  unsigned long long accu;
  int ea, eb;
  accu >>= 24;
  accu >>= 1;
  assert(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned ma, mb;
  unsigned long long accu;
  int ea, eb;
  accu >>= 24;
  accu >>= 1;
  assert(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned ma, mb;
  unsigned long long accu;
  int ea, eb;
  accu >>= 24;
  accu >>= 1;
  assert(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unsigned ma, mb;
  unsigned long long accu;
  int ea, eb;
  accu >>= 24;
  accu >>= 1;
  assert(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D59
type: string
name: retrieve_data
arguments: tag: D50
type: string
name: retrieve_data
arguments: tag: D45
type: string
name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D1
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D69
type: string

tool: D59: Enter deposit value:

tool: D50: %f

tool: D45: Enter interest:

tool: D9: After 1 Year:%f


tool: D1: After 2 Year:%f


tool: D20: After 3 Year:%f


tool: D69: pause

assistant: ```c
int main() {
  float deposit, interest;
  printf("Enter deposit value:");
  scanf("%f", &deposit);
  printf("Enter interest:");
  scanf("%f", &interest);
  deposit = deposit + (deposit * interest);
  printf("After 1 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 2 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 3 Year:%f\n", deposit);
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm1
  movaps %xmm1,%xmm0
  mulss  0x4(%rsp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movaps %xmm1,%xmm0
  mulss  0x4(%rsp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D29(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movaps %xmm1,%xmm0
  mulss  0x4(%rsp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D34(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D64
data_type: string
name: read_data
arguments: label: D58
data_type: string
name: read_data
arguments: label: D29
data_type: string
name: read_data
arguments: label: D34
data_type: string
name: read_data
arguments: label: D7
data_type: string

tool: D28: Enter deposit value:

tool: D10: %f

tool: D64: Enter interest:

tool: D58: After 1 Year:%f


tool: D29: After 2 Year:%f


tool: D34: After 3 Year:%f


tool: D7: pause

assistant: ```c
int main() {
  float deposit, interest;
  printf("Enter deposit value:");
  scanf("%f", &deposit);
  printf("Enter interest:");
  scanf("%f", &interest);
  deposit = deposit + (deposit * interest);
  printf("After 1 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 2 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 3 Year:%f\n", deposit);
  system("pause");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D3(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D37(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D40(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D59
data_type: string
name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D54
data_type: string
name: read_data
arguments: label: D37
data_type: string
name: read_data
arguments: label: D40
data_type: string
name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D36
data_type: string

tool: D59: Enter deposit value:

tool: D3: %f

tool: D54: Enter interest:

tool: D37: After 1 Year:%f


tool: D40: After 2 Year:%f


tool: D28: After 3 Year:%f


tool: D36: pause

assistant: ```c
int main() {
  float deposit, interest;
  printf("Enter deposit value:");
  scanf("%f", &deposit);
  printf("Enter interest:");
  scanf("%f", &interest);
  deposit = deposit + (deposit * interest);
  printf("After 1 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 2 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 3 Year:%f\n", deposit);
  system("pause");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D47(%rip),%rdi
  lea    D24(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D29(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D47
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D54
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D20
type_guessed: string
name: read_data
arguments: label: D40
type_guessed: string

tool: D47: Enter deposit value:

tool: D24: %f

tool: D54: Enter interest:

tool: D29: After 1 Year:%f


tool: D5: After 2 Year:%f


tool: D20: After 3 Year:%f


tool: D40: pause

assistant: ```c
int main() {
  float deposit, interest;
  printf("Enter deposit value:");
  scanf("%f", &deposit);
  printf("Enter interest:");
  scanf("%f", &interest);
  deposit = deposit + (deposit * interest);
  printf("After 1 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 2 Year:%f\n", deposit);
  deposit = deposit + (deposit * interest);
  printf("After 3 Year:%f\n", deposit);
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L67:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0xc,%eax
  and    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x5,%eax
  and    $0x4,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x3,%eax
  and    $0x2,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  or     %edx,%eax
  add    $0x1,%eax
  mov    %al,-0xe(%rbp)
  movb   $0x1,-0xf(%rbp)
  jmp    L50
L37:
  mov    -0x8(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x2,%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x9,%eax
  xor    %edx,%eax
  and    $0x1,%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  movzbl -0xd(%rbp),%eax
  shl    $0xf,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L56
  mov    -0x8(%rbp),%eax
  and    $0x2000,%eax
  test   %eax,%eax
  je     L56
  mov    -0x4(%rbp),%eax
  and    $0xfffffffe,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L7
L56:
  mov    -0x4(%rbp),%eax
  or     $0x1,%eax
  mov    %eax,-0x8(%rbp)
L7:
  movzbl -0xf(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xf(%rbp)
L50:
  movzbl -0xf(%rbp),%eax
  cmp    -0xe(%rbp),%al
  jbe    L37
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0xfffe,-0xc(%rbp)
  jbe    L67
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D3: %#06x 

tool: D8: %#06x


assistant: ```c
int main() {
  unsigned int input = 0x0000;
  while (input < 0xFFFF) {
    unsigned int seed = input;
    unsigned int seed_tmp = 0;
    unsigned char count = 0;
    unsigned char idx;
    unsigned char fib_tap = 0;
    count = ((seed >> 0xC & 0x8) | (seed >> 0x5 & 0x4) | (seed >> 0x3 & 0x2) | (seed & 0x1)) + 1;
    for (idx = 1; idx <= count; idx++) {
      fib_tap = ((seed >> 1) ^ (seed >> 2) ^ (seed >> 8) ^ (seed >> 9)) & 1;
      seed_tmp = ((seed >> 1) | (fib_tap << 0xF));
      if ((seed >> 0x3 & 1) && (seed >> 0xD & 1)) {
        seed = seed_tmp & ~1;
      } else {
        seed = seed_tmp | 1;
      }
    }
    printf("%#06x ", input);
    printf("%#06x\n", seed);
    input++;
  }
}
```