ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<yy_1_PreParaWs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yy_1_PreParaWs(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yy_1_PreParaWs>:
  endbr64
  ret
```

assistant: ```c
void yy_1_PreParaWs(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yy_1_PreParaWs>:
  endbr64
  ret
```

assistant: ```c
void yy_1_PreParaWs(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yy_1_PreParaWs>:
  endbr64
  ret
```

assistant: ```c
void yy_1_PreParaWs(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <malloc4_lcs@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <lcs@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D4: ABCBDAB

tool: D13: BDCABC

tool: D16: '%s', %zd


assistant: ```c
int main(int argc, char const *argv[]) {
  char *x = "ABCBDAB";
  char *y = "BDCABC";
  char *z = malloc4_lcs(y, x);
  size_t len = lcs(z, y, x);
  printf("'%s', %zd\n", z, len);
  free(z);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%r12
  mov    %r12,%rsi
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  call   <malloc4_lcs@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <lcs@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D6
type: string

tool: D8: ABCBDAB

tool: D17: BDCABC

tool: D6: '%s', %zd


assistant: ```c
int main(int argc, char const *argv[]) {
  char *x = "ABCBDAB";
  char *y = "BDCABC";
  char *z = malloc4_lcs(y, x);
  size_t len = lcs(z, y, x);
  printf("'%s', %zd\n", z, len);
  free(z);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %r12,%rdi
  call   <malloc4_lcs@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <lcs@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string

tool: D4: ABCBDAB

tool: D24: BDCABC

tool: D18: '%s', %zd


assistant: ```c
int main(int argc, char const *argv[]) {
  char *x = "ABCBDAB";
  char *y = "BDCABC";
  char *z = malloc4_lcs(y, x);
  size_t len = lcs(z, y, x);
  printf("'%s', %zd\n", z, len);
  free(z);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %r12,%rdi
  call   <malloc4_lcs@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <lcs@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D27
type_guessed: string

tool: D18: ABCBDAB

tool: D24: BDCABC

tool: D27: '%s', %zd


assistant: ```c
int main(int argc, char const *argv[]) {
  char *x = "ABCBDAB";
  char *y = "BDCABC";
  char *z = malloc4_lcs(y, x);
  size_t len = lcs(z, y, x);
  printf("'%s', %zd\n", z, len);
  free(z);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SelectionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L49
L26:
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L17
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L47
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L47:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x1c(%rbp)
L49:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SelectionSort(float *array, int length) {
  int max, i;
  float temp;
  while (length > 0) {
    max = 0;
    for (i = 1; i < length; i++)
      if (array[i] > array[max])
        max = i;
    temp = array[length - 1];
    array[length - 1] = array[max];
    array[max] = temp;
    length--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<SelectionSort>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%r8d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%r9
  jmp    L13
L38:
  movss  -0x4(%r9),%xmm0
  movss  (%rcx),%xmm1
  movss  %xmm1,-0x4(%r9)
  movss  %xmm0,(%rcx)
  test   %r8d,%r8d
  jg     L11
L0:
  ret
L11:
  sub    $0x1,%r8d
  sub    $0x4,%r9
L13:
  lea    0x1(%r8),%eax
  cmp    $0x1,%eax
  jle    L38
  lea    -0x1(%r8),%edi
  add    $0x2,%rdi
  mov    $0x1,%eax
  mov    $0x0,%edx
L7:
  movslq %edx,%rsi
  movss  (%rcx,%rax,4),%xmm0
  ucomiss (%rcx,%rsi,4),%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L7
  movss  -0x4(%r9),%xmm0
  movslq %edx,%rdx
  lea    (%rcx,%rdx,4),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,-0x4(%r9)
  movss  %xmm0,(%rax)
  jmp    L11
```

assistant: ```c
void SelectionSort(float *array, int length) {
  int max, i;
  float temp;
  while (length > 0) {
    max = 0;
    for (i = 1; i < length; i++)
      if (array[i] > array[max])
        max = i;
    temp = array[length - 1];
    array[length - 1] = array[max];
    array[max] = temp;
    length--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SelectionSort>:
  endbr64
  test   %esi,%esi
  jle    L21
  movslq %esi,%r9
  nop
L46:
  movss  (%rdi),%xmm1
  movss  -0x4(%rdi,%r9,4),%xmm2
  mov    %r9d,%r8d
  xor    %esi,%esi
  lea    0x4(%rdi),%rax
  mov    $0x1,%edx
  cmp    $0x1,%r9d
  jg     L65
  jmp    L63
  nopl   0x0(%rax)
L41:
  movslq %esi,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rdi,%rcx,4),%rcx
  cmp    %r8d,%edx
  je     L35
L65:
  movss  (%rax),%xmm0
  mov    %rax,%rcx
  comiss %xmm1,%xmm0
  jbe    L41
  mov    %edx,%esi
  add    $0x1,%edx
  movaps %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %r8d,%edx
  jne    L65
L35:
  movss  %xmm1,-0x4(%rdi,%r9,4)
  movss  %xmm2,(%rcx)
L17:
  sub    $0x1,%r9
  jmp    L46
  nopl   0x0(%rax)
L63:
  lea    -0x1(%r9),%eax
  movss  %xmm1,-0x4(%rdi,%r9,4)
  movss  %xmm2,(%rdi)
  test   %eax,%eax
  jg     L17
L21:
  ret
```

assistant: ```c
void SelectionSort(float *array, int length) {
  int max, i;
  float temp;
  while (length > 0) {
    max = 0;
    for (i = 1; i < length; i++)
      if (array[i] > array[max])
        max = i;
    temp = array[length - 1];
    array[length - 1] = array[max];
    array[max] = temp;
    length--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SelectionSort>:
  endbr64
  test   %esi,%esi
  jle    L6
  movslq %esi,%r9
  nop
L4:
  movss  (%rdi),%xmm1
  movss  -0x4(%rdi,%r9,4),%xmm2
  mov    %r9d,%r8d
  xor    %esi,%esi
  lea    0x4(%rdi),%rax
  mov    $0x1,%edx
  cmp    $0x1,%r9d
  jg     L68
  jmp    L10
  nopl   0x0(%rax)
L2:
  movslq %esi,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rdi,%rcx,4),%rcx
  cmp    %edx,%r8d
  je     L25
L68:
  movss  (%rax),%xmm0
  mov    %rax,%rcx
  comiss %xmm1,%xmm0
  jbe    L2
  mov    %edx,%esi
  add    $0x1,%edx
  movaps %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %edx,%r8d
  jne    L68
L25:
  movss  %xmm1,-0x4(%rdi,%r9,4)
  movss  %xmm2,(%rcx)
L77:
  sub    $0x1,%r9
  jmp    L4
  nopl   0x0(%rax)
L10:
  lea    -0x1(%r9),%eax
  movss  %xmm1,-0x4(%rdi,%r9,4)
  movss  %xmm2,(%rdi)
  test   %eax,%eax
  jg     L77
L6:
  ret
```

assistant: ```c
void SelectionSort(float *array, int length) {
  int max, i;
  float temp;
  while (length > 0) {
    max = 0;
    for (i = 1; i < length; i++)
      if (array[i] > array[max])
        max = i;
    temp = array[length - 1];
    array[length - 1] = array[max];
    array[max] = temp;
    length--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapCharacters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapCharacters(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swapCharacters>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swapCharacters(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swapCharacters>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swapCharacters(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swapCharacters>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swapCharacters(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xMu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  add    %ecx,%eax
  and    $0xf,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x3,-0x4(%rbp)
  jle    L10
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int xMu(int idx, int x[4]) {
  int tI = idx;
  for (int i = 0; i < 4; i++) {
    x[i] = tI % 16;
    tI /= 16;
  };
  return tI;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xMu>:
  endbr64
  mov    %edi,%eax
  lea    0x10(%rsi),%rdi
L2:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  mov    %edx,(%rsi)
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  add    $0x4,%rsi
  cmp    %rdi,%rsi
  jne    L2
  ret
```

assistant: ```c
int xMu(int idx, int x[4]) {
  int tI = idx;
  for (int i = 0; i < 4; i++) {
    x[i] = tI % 16;
    tI /= 16;
  };
  return tI;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xMu>:
  endbr64
  mov    %edi,%eax
  lea    0x10(%rsi),%rdi
L2:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  test   %eax,%eax
  mov    %edx,(%rsi)
  lea    0xf(%rax),%edx
  cmovs  %edx,%eax
  add    $0x4,%rsi
  sar    $0x4,%eax
  cmp    %rdi,%rsi
  jne    L2
  ret
```

assistant: ```c
int xMu(int idx, int x[4]) {
  int tI = idx;
  for (int i = 0; i < 4; i++) {
    x[i] = tI % 16;
    tI /= 16;
  };
  return tI;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xMu>:
  endbr64
  lea    0xf(%rdi),%eax
  lea    0xfff(%rdi),%ecx
  movd   %edi,%xmm0
  test   %edi,%edi
  cmovns %edi,%eax
  movdqa D3(%rip),%xmm2
  sar    $0x4,%eax
  test   %edi,%edi
  mov    %eax,%edx
  lea    0xff(%rdi),%eax
  cmovns %edi,%eax
  movd   %edx,%xmm4
  punpckldq %xmm4,%xmm0
  sar    $0x8,%eax
  test   %edi,%edi
  cmovns %edi,%ecx
  movd   %eax,%xmm1
  lea    0xffff(%rdi),%eax
  sar    $0xc,%ecx
  test   %edi,%edi
  movd   %ecx,%xmm3
  cmovns %edi,%eax
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  sar    $0x10,%eax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm2,%xmm1
  paddd  %xmm1,%xmm0
  pand   %xmm2,%xmm0
  psubd  %xmm1,%xmm0
  movups %xmm0,(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: byte[16]

tool: {"D3": [0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

assistant: ```c
int xMu(int idx, int x[4]) {
  int tI = idx;
  for (int i = 0; i < 4; i++) {
    x[i] = tI % 16;
    tI /= 16;
  };
  return tI;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stats_report>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L11
  cmpl   $0x1,-0x30(%rbp)
  jne    L21
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_stats@plt>
L21:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: %s


assistant: ```c
int stats_report(int *recnums, char **ptr, char **formlist, int numrecs, int statsval) {
  int i;
  for (i = 0; i < numrecs; ++i)
    printf("%s\n", *(formlist + i));
  if (statsval == 1)
    print_stats(ptr, numrecs);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<stats_report>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r15
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  test   %ecx,%ecx
  jle    L28
  mov    %rdx,%rbx
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%r12
  lea    D1(%rip),%rbp
L27:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L27
L28:
  cmp    $0x1,%r14d
  je     L22
L36:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <print_stats@plt>
  jmp    L36
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: %s


assistant: ```c
int stats_report(int *recnums, char **ptr, char **formlist, int numrecs, int statsval) {
  int i;
  for (i = 0; i < numrecs; ++i)
    printf("%s\n", *(formlist + i));
  if (statsval == 1)
    print_stats(ptr, numrecs);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stats_report>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L4
  lea    -0x1(%rcx),%eax
  mov    %rdx,%rbx
  lea    D5(%rip),%rbp
  lea    0x8(%rdx,%rax,8),%r15
  nopl   0x0(%rax)
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L1
L4:
  cmp    $0x1,%r14d
  je     L22
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <print_stats@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: %s


assistant: ```c
int stats_report(int *recnums, char **ptr, char **formlist, int numrecs, int statsval) {
  int i;
  for (i = 0; i < numrecs; ++i)
    printf("%s\n", *(formlist + i));
  if (statsval == 1)
    print_stats(ptr, numrecs);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stats_report>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L28
  lea    -0x1(%rcx),%eax
  mov    %rdx,%rbx
  lea    D3(%rip),%rbp
  lea    0x8(%rdx,%rax,8),%r15
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L14
L28:
  cmp    $0x1,%r14d
  je     L4
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <print_stats@plt>
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: %s


assistant: ```c
int stats_report(int *recnums, char **ptr, char **formlist, int numrecs, int statsval) {
  int i;
  for (i = 0; i < numrecs; ++i)
    printf("%s\n", *(formlist + i));
  if (statsval == 1)
    print_stats(ptr, numrecs);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type_guessed: string
name: disassemble_data
arguments: data_label: D92
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D59
type_guessed: string
name: disassemble_data
arguments: data_label: D51
type_guessed: string
name: disassemble_data
arguments: data_label: D94
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D44
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D83
type_guessed: string
name: disassemble_data
arguments: data_label: D55
type_guessed: string

tool: D37: Pad a file to an even number of bytes.


tool: D92: Output by default written to stdout.


tool: D12: pad [options] file


tool: D59: -f             Force output (if no padding, normally writes nothing)


tool: D51: -n             Do not output anything, print what would happen


tool: D94: -o FILE        output to FILE


tool: D5: -p NUM         pad to 2 4 8 16 bytes. Default 4 bytes.


tool: D44: -u [BYTE]      pad using BYTE. If BYTE 0 or not given,


tool: D34:                then will repeat the last bytes of the  


tool: D83:                in file. Pads with zeros by default.  


tool: D55: -v             Print some debugging info (verbose)


assistant: ```c
void print_usage(void) {
  printf("Pad a file to an even number of bytes.\n");
  printf("Output by default written to stdout.\n");
  printf("pad [options] file\n");
  printf("-f             Force output (if no padding, normally writes nothing)\n");
  printf("-n             Do not output anything, print what would happen\n");
  printf("-o FILE        output to FILE\n");
  printf("-p NUM         pad to 2 4 8 16 bytes. Default 4 bytes.\n");
  printf("-u [BYTE]      pad using BYTE. If BYTE 0 or not given,\n");
  printf("               then will repeat the last bytes of the  \n");
  printf("               in file. Pads with zeros by default.  \n");
  printf("-v             Print some debugging info (verbose)\n");
}
```