ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SSIDMAEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x24(%rax),%rdx
  mov    (%rdx),%rcx
  add    $0x24,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SSIDMAEnable(uint32_t ui32Base, uint32_t ui32DMAFlags) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000024))) |= ui32DMAFlags;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SSIDMAEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x24(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x24(%rdx)
  ret
```

assistant: ```c
void SSIDMAEnable(uint32_t ui32Base, uint32_t ui32DMAFlags) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000024))) |= ui32DMAFlags;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SSIDMAEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x24(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x24(%rdx)
  ret
```

assistant: ```c
void SSIDMAEnable(uint32_t ui32Base, uint32_t ui32DMAFlags) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000024))) |= ui32DMAFlags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SSIDMAEnable>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    %rsi,-0x10(%rsp)
  mov    -0x10(%rsp),%rcx
  mov    -0x8(%rsp),%rdx
  mov    0x24(%rdx),%rax
  or     %rcx,%rax
  mov    %rax,0x24(%rdx)
  ret
```

assistant: ```c
void SSIDMAEnable(uint32_t ui32Base, uint32_t ui32DMAFlags) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000024))) |= ui32DMAFlags;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  jmp    L33
L16:
  mov    -0x18(%rbp),%eax
  sar    %eax
  cltq
  imul   -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L11
  mov    -0x8(%rbp),%rax
  jmp    L12
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  subl   $0x1,-0x18(%rbp)
  sarl   -0x18(%rbp)
L33:
  cmpl   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *pbase, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *base = (char *)pbase;
  int line;
  int test;
  for (line = nmemb; line != 0; line >>= 1) {
    void *ptr = base + (line >> 1) * size;
    if ((test = (*cmp)(key, ptr)) <= 0)
      return ptr;
    else {
      base = (char *)ptr + size;
      line--;
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bsearch>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rcx,%rbp
  mov    %r8,%r12
  mov    %edx,%ebx
  test   %edx,%edx
  je     L30
L8:
  mov    %ebx,%eax
  sar    %eax
  cltq
  imul   %rbp,%rax
  add    %rax,%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   *%r12
  test   %eax,%eax
  jle    L15
  add    %rbp,%r14
  sub    $0x1,%ebx
  sar    %ebx
  jne    L8
  mov    $0x0,%r14d
L15:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  mov    $0x0,%r14d
  jmp    L15
```

assistant: ```c
void *bsearch(const void *key, const void *pbase, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *base = (char *)pbase;
  int line;
  int test;
  for (line = nmemb; line != 0; line >>= 1) {
    void *ptr = base + (line >> 1) * size;
    if ((test = (*cmp)(key, ptr)) <= 0)
      return ptr;
    else {
      base = (char *)ptr + size;
      line--;
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bsearch>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  je     L12
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rcx,%rbx
  mov    %r8,%rbp
  mov    %edx,%r13d
  jmp    L2
  nopl   0x0(%rax)
L34:
  sub    $0x1,%r13d
  add    %rbx,%r14
  sar    %r13d
  je     L12
L2:
  mov    %r13d,%eax
  mov    %r12,%rdi
  sar    %eax
  cltq
  imul   %rbx,%rax
  add    %rax,%r14
  mov    %r14,%rsi
  call   *%rbp
  test   %eax,%eax
  jg     L34
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *pbase, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *base = (char *)pbase;
  int line;
  int test;
  for (line = nmemb; line != 0; line >>= 1) {
    void *ptr = base + (line >> 1) * size;
    if ((test = (*cmp)(key, ptr)) <= 0)
      return ptr;
    else {
      base = (char *)ptr + size;
      line--;
    }
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsearch>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  je     L0
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rcx,%rbx
  mov    %r8,%rbp
  mov    %edx,%r13d
  jmp    L22
  nopl   0x0(%rax)
L29:
  sub    $0x1,%r13d
  add    %rbx,%r14
  sar    %r13d
  je     L0
L22:
  mov    %r13d,%eax
  mov    %r12,%rdi
  sar    %eax
  cltq
  imul   %rbx,%rax
  add    %rax,%r14
  mov    %r14,%rsi
  call   *%rbp
  test   %eax,%eax
  jg     L29
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *pbase, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *base = (char *)pbase;
  int line;
  int test;
  for (line = nmemb; line != 0; line >>= 1) {
    void *ptr = base + (line >> 1) * size;
    if ((test = (*cmp)(key, ptr)) <= 0)
      return ptr;
    else {
      base = (char *)ptr + size;
      line--;
    }
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getAnswer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x418(%rbp)
  movl   $0x0,-0x414(%rbp)
L55:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x418(%rbp),%rcx
  mov    -0x430(%rbp),%rdx
  lea    -0x410(%rbp),%rsi
  mov    -0x424(%rbp),%eax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x400,%edx
  mov    %eax,%edi
  call   <recvfrom@plt>
  test   %rax,%rax
  jns    L52
  mov    -0x424(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <dieError@plt>
  jmp    L55
L52:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L55
  lea    -0x410(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x414(%rbp)
  movb   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  js     L55
  lea    -0x410(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x414(%rbp)
  je     L50
  jmp    L55
L50:
  nop
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D5
type: string

tool: D13: recvfrom() failed

tool: D5: %s

assistant: ```c
void getAnswer(int sock, struct sockaddr_in6 *client_addr) {
  socklen_t clilen = sizeof(*client_addr);
  char buffer[1024];
  int lenAns = 0;
  do {
    memset(buffer, 0, 1024);
    if (recvfrom(sock, buffer, 1024, 0, (struct sockaddr *)client_addr, &clilen) < 0) {
      dieError("recvfrom() failed", sock);
    } else if (strlen(buffer) > 0) {
      lenAns = (int)strtol(&buffer[0], NULL, 8);
      buffer[1024] = '\0';
      if (lenAns >= 0) {
        printf("%s", buffer + 1);
        if (lenAns == 0)
          break;
      }
    }
  } while (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getAnswer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movl   $0x4,0xc(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%r14
  lea    D16(%rip),%r15
  jmp    L35
L38:
  mov    %r12d,%esi
  lea    D15(%rip),%rdi
  call   <dieError@plt>
L35:
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r14,%r9
  mov    %r13,%r8
  mov    $0x0,%ecx
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recvfrom@plt>
  test   %rax,%rax
  js     L38
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L35
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %rax,%rbp
  movb   $0x0,0x410(%rsp)
  test   %eax,%eax
  js     L35
  lea    0x11(%rsp),%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jne    L35
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D16
type_infered: string
name: disassemble_data
arguments: label: D15
type_infered: string

tool: D16: %s

tool: D15: recvfrom() failed

assistant: ```c
void getAnswer(int sock, struct sockaddr_in6 *client_addr) {
  socklen_t clilen = sizeof(*client_addr);
  char buffer[1024];
  int lenAns = 0;
  do {
    memset(buffer, 0, 1024);
    if (recvfrom(sock, buffer, 1024, 0, (struct sockaddr *)client_addr, &clilen) < 0) {
      dieError("recvfrom() failed", sock);
    } else if (strlen(buffer) > 0) {
      lenAns = (int)strtol(&buffer[0], NULL, 8);
      buffer[1024] = '\0';
      if (lenAns >= 0) {
        printf("%s", buffer + 1);
        if (lenAns == 0)
          break;
      }
    }
  } while (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getAnswer>:
  endbr64
  push   %r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x21(%rsp),%rax
  movl   $0x4,0x1c(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r13
L46:
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  xor    %ecx,%ecx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recvfrom@plt>
  test   %rax,%rax
  js     L51
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L46
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  movb   $0x0,0x420(%rsp)
  mov    %rax,%r15
  test   %eax,%eax
  js     L46
  mov    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  test   %r15d,%r15d
  jne    L46
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L51:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <dieError@plt>
  jmp    L46
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D6
datatype: string

tool: D0: recvfrom() failed

tool: D6: %s

assistant: ```c
void getAnswer(int sock, struct sockaddr_in6 *client_addr) {
  socklen_t clilen = sizeof(*client_addr);
  char buffer[1024];
  int lenAns = 0;
  do {
    memset(buffer, 0, 1024);
    if (recvfrom(sock, buffer, 1024, 0, (struct sockaddr *)client_addr, &clilen) < 0) {
      dieError("recvfrom() failed", sock);
    } else if (strlen(buffer) > 0) {
      lenAns = (int)strtol(&buffer[0], NULL, 8);
      buffer[1024] = '\0';
      if (lenAns >= 0) {
        printf("%s", buffer + 1);
        if (lenAns == 0)
          break;
      }
    }
  } while (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getAnswer>:
  endbr64
  push   %r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x21(%rsp),%rax
  movl   $0x4,0x1c(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r13
L57:
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  xor    %ecx,%ecx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recvfrom@plt>
  test   %rax,%rax
  js     L37
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L57
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  movb   $0x0,0x420(%rsp)
  mov    %rax,%r15
  test   %eax,%eax
  js     L57
  mov    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  test   %r15d,%r15d
  jne    L57
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L37:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <dieError@plt>
  jmp    L57
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D13: recvfrom() failed

tool: D3: %s

assistant: ```c
void getAnswer(int sock, struct sockaddr_in6 *client_addr) {
  socklen_t clilen = sizeof(*client_addr);
  char buffer[1024];
  int lenAns = 0;
  do {
    memset(buffer, 0, 1024);
    if (recvfrom(sock, buffer, 1024, 0, (struct sockaddr *)client_addr, &clilen) < 0) {
      dieError("recvfrom() failed", sock);
    } else if (strlen(buffer) > 0) {
      lenAns = (int)strtol(&buffer[0], NULL, 8);
      buffer[1024] = '\0';
      if (lenAns >= 0) {
        printf("%s", buffer + 1);
        if (lenAns == 0)
          break;
      }
    }
  } while (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__cpuid@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  uint32_t eax, ebx, ecx, edx;
  __cpuid(0, eax, ebx, ecx, edx);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__cpuid@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  uint32_t eax, ebx, ecx, edx;
  __cpuid(0, eax, ebx, ecx, edx);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__cpuid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  uint32_t eax, ebx, ecx, edx;
  __cpuid(0, eax, ebx, ecx, edx);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__cpuid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  uint32_t eax, ebx, ecx, edx;
  __cpuid(0, eax, ebx, ecx, edx);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninitvar_strcpy_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <strcpy_s@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <strcpy_s@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strcpy_s@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strcpy_s@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string

tool: D16: a

assistant: ```c
void uninitvar_strcpy_s(char *strDest, ssize_t s, char *source) {
  char *strUninit1;
  char *strUninit2;
  ssize_t size;
  (void)strcpy_s(strUninit1, 1, "a");
  (void)strcpy_s(strDest, 1, strUninit2);
  (void)strcpy_s(strDest, size, "a");
  (void)strcpy_s(strDest, s, source);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uninitvar_strcpy_s>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  lea    D8(%rip),%r13
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <strcpy_s@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <strcpy_s@plt>
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strcpy_s@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <strcpy_s@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: a

assistant: ```c
void uninitvar_strcpy_s(char *strDest, ssize_t s, char *source) {
  char *strUninit1;
  char *strUninit2;
  ssize_t size;
  (void)strcpy_s(strUninit1, 1, "a");
  (void)strcpy_s(strDest, 1, strUninit2);
  (void)strcpy_s(strDest, size, "a");
  (void)strcpy_s(strDest, s, source);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_strcpy_s>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r14,%rdx
  push   %r12
  mov    %esi,%r12d
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <strcpy_s@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x1,%esi
  call   <strcpy_s@plt>
  mov    %r14,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <strcpy_s@plt>
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <strcpy_s@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: a

assistant: ```c
void uninitvar_strcpy_s(char *strDest, ssize_t s, char *source) {
  char *strUninit1;
  char *strUninit2;
  ssize_t size;
  (void)strcpy_s(strUninit1, 1, "a");
  (void)strcpy_s(strDest, 1, strUninit2);
  (void)strcpy_s(strDest, size, "a");
  (void)strcpy_s(strDest, s, source);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uninitvar_strcpy_s>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r14,%rdx
  push   %r12
  mov    %esi,%r12d
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <strcpy_s@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x1,%esi
  call   <strcpy_s@plt>
  mov    %r14,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <strcpy_s@plt>
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <strcpy_s@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: a

assistant: ```c
void uninitvar_strcpy_s(char *strDest, ssize_t s, char *source) {
  char *strUninit1;
  char *strUninit2;
  ssize_t size;
  (void)strcpy_s(strUninit1, 1, "a");
  (void)strcpy_s(strDest, 1, strUninit2);
  (void)strcpy_s(strDest, size, "a");
  (void)strcpy_s(strDest, s, source);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<d_l_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L8:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %edi,%r8d
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L8
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: %s %3d %3d % 12.7lf


assistant: ```c
void d_l_print(int Q, double *par, const char s[], int *Lq, int nL, FILE *f) {
  for (int L = 0; L <= Lq[Q]; L++) {
    fprintf(f, "%s %3d %3d % 12.7lf\n", s, Q, L, par[Q * nL + L]);
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d_l_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movslq %edi,%rdx
  lea    (%rcx,%rdx,4),%r13
  cmpl   $0x0,0x0(%r13)
  js     L18
  mov    %edi,%ebp
  mov    %r9,%r12
  imul   %edi,%r8d
  movslq %r8d,%r8
  lea    (%rsi,%r8,8),%r15
  mov    $0x0,%ebx
  lea    D8(%rip),%r14
L5:
  movsd  (%r15,%rbx,8),%xmm0
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    0x8(%rsp),%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%r13)
  jge    L5
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: %s %3d %3d % 12.7lf


assistant: ```c
void d_l_print(int Q, double *par, const char s[], int *Lq, int nL, FILE *f) {
  for (int L = 0; L <= Lq[Q]; L++) {
    fprintf(f, "%s %3d %3d % 12.7lf\n", s, Q, L, par[Q * nL + L]);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d_l_print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  movslq %edi,%rdx
  push   %rbp
  lea    (%rcx,%rdx,4),%rcx
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rcx),%eax
  mov    %rcx,0x8(%rsp)
  test   %eax,%eax
  js     L2
  imul   %edi,%r8d
  mov    %edi,%ebp
  mov    %r9,%r13
  xor    %ebx,%ebx
  lea    D6(%rip),%r15
  movslq %r8d,%r8
  lea    (%rsi,%r8,8),%r14
L9:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <fprintf@plt>
  mov    0x8(%rsp),%rax
  cmp    %ebx,(%rax)
  jge    L9
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: %s %3d %3d % 12.7lf


assistant: ```c
void d_l_print(int Q, double *par, const char s[], int *Lq, int nL, FILE *f) {
  for (int L = 0; L <= Lq[Q]; L++) {
    fprintf(f, "%s %3d %3d % 12.7lf\n", s, Q, L, par[Q * nL + L]);
  }
  return;
}
```