ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<unescape>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L68
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D3(%rip),%r10
  jmp    L15
  movslq %edx,%rax
  movb   $0x7,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0x8,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0xc,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0xa,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0xd,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0x9,(%r8,%rax,1)
  jmp    L22
  movslq %edx,%rax
  movb   $0xb,(%r8,%rax,1)
  jmp    L22
L70:
  lea    0x1(%rdx),%eax
  movslq %edx,%rdx
  movb   $0x5c,(%r8,%rdx,1)
  movzbl (%r9),%esi
  movslq %eax,%rdx
  mov    %sil,(%r8,%rdx,1)
  mov    %eax,%edx
  jmp    L22
L25:
  movslq %edx,%rsi
  mov    %al,(%r8,%rsi,1)
L22:
  add    $0x1,%edx
  add    $0x1,%ecx
  movslq %ecx,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  je     L114
L15:
  cmp    $0x5c,%al
  jne    L25
  lea    0x1(%rdi,%rsi,1),%r9
  movzbl (%r9),%esi
  test   %sil,%sil
  je     L25
  add    $0x1,%ecx
  sub    $0x61,%esi
  cmp    $0x15,%sil
  ja     L70
  movzbl %sil,%esi
  movslq (%r10,%rsi,4),%rax
  add    %r10,%rax
  notrack jmp *%rax
L68:
  mov    $0x0,%edx
L114:
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  ret
```

assistant: ```c
void unescape(char s[], char t[]) {
  int i, j, n;
  for (i = 0, j = 0; t[j] != '\0'; i++, j++) {
    if (t[j] == '\\' && t[j + 1] != '\0') {
      j++;
      switch (t[j]) {
      case 'a':
        s[i] = '\a';
        break;
      case 'b':
        s[i] = '\b';
        break;
      case 'f':
        s[i] = '\f';
        break;
      case 'n':
        s[i] = '\n';
        break;
      case 'r':
        s[i] = '\r';
        break;
      case 't':
        s[i] = '\t';
        break;
      case 'v':
        s[i] = '\v';
        break;
      default:
        s[i++] = '\\';
        s[i] = t[j];
        break;
      }
    } else {
      s[i] = t[j];
    }
  }
  s[i] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<unescape>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%r9
  mov    %rsi,%r8
  test   %dl,%dl
  je     L107
  xor    %eax,%eax
  xor    %esi,%esi
  lea    D0(%rip),%r11
  xor    %edi,%edi
  xchg   %ax,%ax
L116:
  movslq %esi,%rcx
  add    $0x1,%eax
  add    %r9,%rcx
  cmp    $0x5c,%dl
  je     L128
L19:
  mov    %dl,(%rcx)
L15:
  movslq %eax,%rdi
  add    $0x1,%esi
  movzbl (%r8,%rdi,1),%edx
  test   %dl,%dl
  jne    L116
  movslq %esi,%rsi
  add    %rsi,%r9
L107:
  movb   $0x0,(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L128:
  lea    0x1(%r8,%rdi,1),%r10
  movzbl (%r10),%edi
  test   %dil,%dil
  je     L19
  sub    $0x61,%edi
  cmp    $0x15,%dil
  ja     L38
  movzbl %dil,%edi
  movslq (%r11,%rdi,4),%rdx
  add    %r11,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
L38:
  movb   $0x5c,(%rcx)
  add    $0x1,%esi
  movzbl (%r10),%ecx
  add    $0x1,%eax
  movslq %esi,%rdx
  mov    %cl,(%r9,%rdx,1)
  jmp    L15
  movb   $0x7,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0x8,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0xc,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0xa,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0xd,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0x9,(%rcx)
  add    $0x1,%eax
  jmp    L15
  movb   $0xb,(%rcx)
  add    $0x1,%eax
  jmp    L15
```

assistant: ```c
void unescape(char s[], char t[]) {
  int i, j, n;
  for (i = 0, j = 0; t[j] != '\0'; i++, j++) {
    if (t[j] == '\\' && t[j + 1] != '\0') {
      j++;
      switch (t[j]) {
      case 'a':
        s[i] = '\a';
        break;
      case 'b':
        s[i] = '\b';
        break;
      case 'f':
        s[i] = '\f';
        break;
      case 'n':
        s[i] = '\n';
        break;
      case 'r':
        s[i] = '\r';
        break;
      case 't':
        s[i] = '\t';
        break;
      case 'v':
        s[i] = '\v';
        break;
      default:
        s[i++] = '\\';
        s[i] = t[j];
        break;
      }
    } else {
      s[i] = t[j];
    }
  }
  s[i] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unescape>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%r9
  mov    %rsi,%r8
  test   %dl,%dl
  je     L90
  xor    %eax,%eax
  xor    %esi,%esi
  lea    D6(%rip),%r11
  xor    %edi,%edi
  xchg   %ax,%ax
L15:
  movslq %esi,%rcx
  add    $0x1,%eax
  add    %r9,%rcx
  cmp    $0x5c,%dl
  je     L25
L17:
  mov    %dl,(%rcx)
L113:
  movslq %eax,%rdi
  add    $0x1,%esi
  movzbl (%r8,%rdi,1),%edx
  test   %dl,%dl
  jne    L15
  movslq %esi,%rsi
  add    %rsi,%r9
L90:
  movb   $0x0,(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    0x1(%r8,%rdi,1),%r10
  movzbl (%r10),%edi
  test   %dil,%dil
  je     L17
  sub    $0x61,%edi
  cmp    $0x15,%dil
  ja     L68
  movzbl %dil,%edi
  movslq (%r11,%rdi,4),%rdx
  add    %r11,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
L68:
  movb   $0x5c,(%rcx)
  add    $0x1,%esi
  movzbl (%r10),%ecx
  add    $0x1,%eax
  movslq %esi,%rdx
  mov    %cl,(%r9,%rdx,1)
  jmp    L113
  movb   $0x7,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0x8,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0xc,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0xa,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0xd,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0x9,(%rcx)
  add    $0x1,%eax
  jmp    L113
  movb   $0xb,(%rcx)
  add    $0x1,%eax
  jmp    L113
```

assistant: ```c
void unescape(char s[], char t[]) {
  int i, j, n;
  for (i = 0, j = 0; t[j] != '\0'; i++, j++) {
    if (t[j] == '\\' && t[j + 1] != '\0') {
      j++;
      switch (t[j]) {
      case 'a':
        s[i] = '\a';
        break;
      case 'b':
        s[i] = '\b';
        break;
      case 'f':
        s[i] = '\f';
        break;
      case 'n':
        s[i] = '\n';
        break;
      case 'r':
        s[i] = '\r';
        break;
      case 't':
        s[i] = '\t';
        break;
      case 'v':
        s[i] = '\v';
        break;
      default:
        s[i++] = '\\';
        s[i] = t[j];
        break;
      }
    } else {
      s[i] = t[j];
    }
  }
  s[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bwstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L15
L11:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bwstrdup_n@plt>
L15:
  leave
  ret
```

assistant: ```c
wchar_t *bwstrdup(const wchar_t *str) {
  if (!str)
    return NULL;
  return bwstrdup_n(str, wcslen(str));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bwstrdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L16
  call   <wcslen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <bwstrdup_n@plt>
L14:
  pop    %rbx
  ret
L16:
  mov    %rdi,%rax
  jmp    L14
```

assistant: ```c
wchar_t *bwstrdup(const wchar_t *str) {
  if (!str)
    return NULL;
  return bwstrdup_n(str, wcslen(str));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bwstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <wcslen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <bwstrdup_n@plt>
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *bwstrdup(const wchar_t *str) {
  if (!str)
    return NULL;
  return bwstrdup_n(str, wcslen(str));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bwstrdup>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbp
  mov    %rdi,%rbp
  call   <wcslen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <bwstrdup_n@plt>
  nopl   (%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
wchar_t *bwstrdup(const wchar_t *str) {
  if (!str)
    return NULL;
  return bwstrdup_n(str, wcslen(str));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RemoveLineEndings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x18(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L2:
  nop
  leave
  ret
```

assistant: ```c
void RemoveLineEndings(char *Buffer) {
  char *Text;
  Text = strrchr(Buffer, '\n');
  if (Text)
    *Text = 0;
  Text = strrchr(Buffer, '\r');
  if (Text)
    *Text = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RemoveLineEndings>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L14
  movb   $0x0,(%rax)
L14:
  pop    %rbx
  ret
```

assistant: ```c
void RemoveLineEndings(char *Buffer) {
  char *Text;
  Text = strrchr(Buffer, '\n');
  if (Text)
    *Text = 0;
  Text = strrchr(Buffer, '\r');
  if (Text)
    *Text = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RemoveLineEndings>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L16
  movb   $0x0,(%rax)
L16:
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  pop    %rbp
  ret
```

assistant: ```c
void RemoveLineEndings(char *Buffer) {
  char *Text;
  Text = strrchr(Buffer, '\n');
  if (Text)
    *Text = 0;
  Text = strrchr(Buffer, '\r');
  if (Text)
    *Text = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RemoveLineEndings>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L15
  movb   $0x0,(%rax)
L15:
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rax)
L17:
  pop    %rbp
  ret
```

assistant: ```c
void RemoveLineEndings(char *Buffer) {
  char *Text;
  Text = strrchr(Buffer, '\n');
  if (Text)
    *Text = 0;
  Text = strrchr(Buffer, '\r');
  if (Text)
    *Text = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <f@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%edi
  call   <f@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
main() {
  int x = f(1);
  int y = f(0);
  return x + y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <f@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <f@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int x = f(1);
  int y = f(0);
  return x + y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <f@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int x = f(1);
  int y = f(0);
  return x + y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <f@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <f@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int x = f(1);
  int y = f(0);
  return x + y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fileExist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L14
  mov    -0x10(%rbp),%eax
  jmp    L5
L14:
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int fileExist(char *filename) {
  struct stat st;
  stat(filename, &st);
  if (S_ISREG(st.st_mode))
    return st.st_size;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fileExist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExist(char *filename) {
  struct stat st;
  stat(filename, &st);
  if (S_ISREG(st.st_mode))
    return st.st_size;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fileExist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExist(char *filename) {
  struct stat st;
  stat(filename, &st);
  if (S_ISREG(st.st_mode))
    return st.st_size;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fileExist>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileExist(char *filename) {
  struct stat st;
  stat(filename, &st);
  if (S_ISREG(st.st_mode))
    return st.st_size;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_set_then_clear>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <cba_alloc@plt>
  mov    %rax,%rbp
  jmp    L108
  nopl   0x0(%rax)
L92:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_get@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  jne    L43
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_clear@plt>
  test   %rax,%rax
  js     L35
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_get@plt>
  test   %eax,%eax
  jne    L117
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L55
L108:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_set@plt>
  test   %rax,%rax
  jns    L92
  lea    D23(%rip),%rsi
L75:
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L129
L15:
  mov    %rbp,%rdi
  call   <cba_free@plt>
L129:
  xor    %r12d,%r12d
L64:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  lea    D39(%rip),%rsi
L41:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  jne    L15
  jmp    L129
  nopl   0x0(%rax)
L35:
  lea    D9(%rip),%rsi
  jmp    L75
  nopl   0x0(%rax)
L117:
  lea    D11(%rip),%rsi
  jmp    L41
L55:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  je     L64
  mov    %rbp,%rdi
  call   <cba_free@plt>
  jmp    L64
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D12
type_guessed: string

tool: D23: cba_set(ba, i) < 0

tool: D14: FAILED: %s


tool: D39: cba_get(ba, i) == 1

tool: D4: FAILED: !(%s)


tool: D9: cba_clear(ba, i) < 0

tool: D11: cba_get(ba, i) == 0

tool: D12: PASSED

assistant: ```c
int test_set_then_clear(void) {
  struct bitarray *ba = NULL;
  {
    int i;
    ba = cba_alloc(100);
    for (i = 0; i < 100; i++) {
      do {
        if (cba_set(ba, i) < 0) {
          printf("FAILED: %s\n", "cba_set(ba, i) < 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (!(cba_get(ba, i) == 1)) {
          printf("FAILED: !(%s)\n", "cba_get(ba, i) == 1");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (cba_clear(ba, i) < 0) {
          printf("FAILED: %s\n", "cba_clear(ba, i) < 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (!(cba_get(ba, i) == 0)) {
          printf("FAILED: !(%s)\n", "cba_get(ba, i) == 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
    }
  }
  printf("PASSED\n");
  if (ba)
    cba_free(ba);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_set_then_clear>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <cba_alloc@plt>
  mov    %rax,%rbp
  jmp    L42
  nopl   0x0(%rax)
L52:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_get@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  jne    L29
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_clear@plt>
  test   %rax,%rax
  js     L116
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_get@plt>
  test   %eax,%eax
  jne    L62
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L58
L42:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cba_set@plt>
  test   %rax,%rax
  jns    L52
  lea    D33(%rip),%rsi
L63:
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L118
L64:
  mov    %rbp,%rdi
  call   <cba_free@plt>
L118:
  xor    %r12d,%r12d
L127:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  lea    D66(%rip),%rsi
L13:
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  jne    L64
  jmp    L118
  nopl   0x0(%rax)
L116:
  lea    D25(%rip),%rsi
  jmp    L63
  nopl   0x0(%rax)
L62:
  lea    D54(%rip),%rsi
  jmp    L13
L58:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  test   %rbp,%rbp
  je     L127
  mov    %rbp,%rdi
  call   <cba_free@plt>
  jmp    L127
```

tool_calls: name: unpack_data
arguments: data_tag: D33
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D66
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D54
type_guessed: string
name: unpack_data
arguments: data_tag: D41
type_guessed: string

tool: D33: cba_set(ba, i) < 0

tool: D2: FAILED: %s


tool: D66: cba_get(ba, i) == 1

tool: D13: FAILED: !(%s)


tool: D25: cba_clear(ba, i) < 0

tool: D54: cba_get(ba, i) == 0

tool: D41: PASSED

assistant: ```c
int test_set_then_clear(void) {
  struct bitarray *ba = NULL;
  {
    int i;
    ba = cba_alloc(100);
    for (i = 0; i < 100; i++) {
      do {
        if (cba_set(ba, i) < 0) {
          printf("FAILED: %s\n", "cba_set(ba, i) < 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (!(cba_get(ba, i) == 1)) {
          printf("FAILED: !(%s)\n", "cba_get(ba, i) == 1");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (cba_clear(ba, i) < 0) {
          printf("FAILED: %s\n", "cba_clear(ba, i) < 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
      do {
        if (!(cba_get(ba, i) == 0)) {
          printf("FAILED: !(%s)\n", "cba_get(ba, i) == 0");
          if (ba)
            cba_free(ba);
          return 0;
        }
      } while (0);
    }
  }
  printf("PASSED\n");
  if (ba)
    cba_free(ba);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edx
  mov    $0xd,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  mov    %eax,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    $0x172,%esi
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x7bd,%edi
  call   <day_of_year@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1f,%edx
  mov    $0xc,%esi
  mov    $0x7df,%edi
  call   <day_of_year@plt>
  mov    %eax,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    $0x5a,%esi
  mov    $0x7df,%edi
  call   <month_day@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D43
type_infered: string
name: extract_symbolic_data
arguments: tag: D50
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D35
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D22: 13th month exists? %d


tool: D43: 32nd day exists? %d


tool: D50: 370th yearday exists? day = %d, month = %d


tool: D31: 1st day of 1st month exists? %d


tool: D35: 31st of 12th month exists? %d


tool: D1: 90th day of year exists? day = %d, month = %d


assistant: ```c
int main() {
  int month, day, yearday, ret;
  ret = day_of_year(2015, 13, 1);
  printf("13th month exists? %d\n", ret);
  ret = day_of_year(2015, 1, 32);
  printf("32nd day exists? %d\n", ret);
  month_day(2015, 370, &month, &day);
  printf("370th yearday exists? day = %d, month = %d\n", day, month);
  ret = day_of_year(1981, 1, 1);
  printf("1st day of 1st month exists? %d\n", ret);
  ret = day_of_year(2015, 12, 31);
  printf("31st of 12th month exists? %d\n", ret);
  month_day(2015, 90, &month, &day);
  printf("90th day of year exists? day = %d, month = %d\n", day, month);
  return 0;
}
```