ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ffts1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpl   $0x3,-0x1c(%rbp)
  je     L21
  cmpl   $0x3,-0x1c(%rbp)
  jg     L91
  cmpl   $0x2,-0x1c(%rbp)
  je     L121
  cmpl   $0x2,-0x1c(%rbp)
  jg     L91
  cmpl   $0x0,-0x1c(%rbp)
  je     L17
  cmpl   $0x1,-0x1c(%rbp)
  jne    L91
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fft2pt@plt>
  jmp    L128
L121:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fft4pt@plt>
  jmp    L128
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fft8pt@plt>
  jmp    L128
L91:
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bitrevR2@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    0x0(,%rax,4),%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  jne    L0
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bfR2@plt>
  shll   -0x8(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    0x0(,%rax,4),%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  cmp    $0x2,%eax
  jne    L94
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bfR4@plt>
  shll   $0x2,-0x8(%rbp)
L94:
  cmpl   $0xb,-0x1c(%rbp)
  jg     L79
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <bfstages@plt>
  jmp    L128
L79:
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <fftrecurs@plt>
  jmp    L128
L17:
  nop
L128:
  nop
  leave
  ret
```

assistant: ```c
void ffts1(float *ioptr, int M, float *Utbl, int16_t *BRLow) {
  int StageCnt;
  int NDiffU;
  switch (M) {
  case 0:
    break;
  case 1:
    fft2pt(ioptr);
    break;
  case 2:
    fft4pt(ioptr);
    break;
  case 3:
    fft8pt(ioptr);
    break;
  default:
    bitrevR2(ioptr, M, BRLow);
    StageCnt = (M - 1) / 3;
    NDiffU = 2;
    if ((M - 1 - (StageCnt * 3)) == 1) {
      bfR2(ioptr, M, NDiffU);
      NDiffU *= 2;
    }
    if ((M - 1 - (StageCnt * 3)) == 2) {
      bfR4(ioptr, M, NDiffU);
      NDiffU *= 4;
    }
    if (M <= (int)(11 - (sizeof(float) / 8)))
      bfstages(ioptr, M, Utbl, 1, NDiffU, StageCnt);
    else
      fftrecurs(ioptr, M, Utbl, 1, NDiffU, StageCnt);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ffts1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmp    $0x2,%esi
  je     L122
  mov    %esi,%ebx
  mov    %rdx,%r13
  jg     L105
  test   %esi,%esi
  je     L31
  cmp    $0x1,%esi
  jne    L28
  call   <fft2pt@plt>
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L105:
  cmp    $0x3,%esi
  jne    L28
  call   <fft8pt@plt>
  jmp    L31
L122:
  call   <fft4pt@plt>
  jmp    L31
L28:
  mov    %rcx,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <bitrevR2@plt>
  lea    -0x1(%rbx),%edx
  movslq %edx,%r12
  imul   $0x55555556,%r12,%r12
  shr    $0x20,%r12
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  lea    0x0(,%r12,4),%ecx
  mov    %r12d,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  je     L111
  mov    $0x2,%r8d
  cmp    $0x2,%eax
  je     L38
L89:
  cmp    $0xb,%ebx
  jg     L96
  mov    %r12d,%r9d
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <bfstages@plt>
  jmp    L31
L111:
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <bfR2@plt>
  mov    $0x4,%r8d
  jmp    L89
L38:
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <bfR4@plt>
  mov    $0x8,%r8d
  jmp    L89
L96:
  mov    %r12d,%r9d
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <fftrecurs@plt>
  jmp    L31
```

assistant: ```c
void ffts1(float *ioptr, int M, float *Utbl, int16_t *BRLow) {
  int StageCnt;
  int NDiffU;
  switch (M) {
  case 0:
    break;
  case 1:
    fft2pt(ioptr);
    break;
  case 2:
    fft4pt(ioptr);
    break;
  case 3:
    fft8pt(ioptr);
    break;
  default:
    bitrevR2(ioptr, M, BRLow);
    StageCnt = (M - 1) / 3;
    NDiffU = 2;
    if ((M - 1 - (StageCnt * 3)) == 1) {
      bfR2(ioptr, M, NDiffU);
      NDiffU *= 2;
    }
    if ((M - 1 - (StageCnt * 3)) == 2) {
      bfR4(ioptr, M, NDiffU);
      NDiffU *= 4;
    }
    if (M <= (int)(11 - (sizeof(float) / 8)))
      bfstages(ioptr, M, Utbl, 1, NDiffU, StageCnt);
    else
      fftrecurs(ioptr, M, Utbl, 1, NDiffU, StageCnt);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ffts1>:
  endbr64
  push   %r13
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x2,%esi
  je     L99
  mov    %esi,%ebp
  mov    %rdx,%r13
  jg     L57
  test   %esi,%esi
  je     L45
  cmp    $0x1,%esi
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1100 <fft2pt@plt>
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    $0x3,%esi
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1130 <fft8pt@plt>
  nopw   0x0(%rax,%rax,1)
L99:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    10e0 <fft4pt@plt>
  nopl   (%rax)
L34:
  mov    %rcx,%rdx
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  call   <bitrevR2@plt>
  lea    -0x1(%rbp),%edx
  mov    0x8(%rsp),%rdi
  movslq %edx,%rbx
  mov    %edx,%eax
  imul   $0x55555556,%rbx,%rbx
  sar    $0x1f,%eax
  shr    $0x20,%rbx
  sub    %eax,%ebx
  lea    0x0(,%rbx,4),%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  je     L4
  mov    $0x2,%r8d
  cmp    $0x2,%eax
  je     L7
L67:
  mov    %ebx,%r9d
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  cmp    $0xb,%ebp
  jg     L70
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1120 <bfstages@plt>
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  ret
  nopl   0x0(%rax)
L70:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    10f0 <fftrecurs@plt>
  nopl   (%rax)
L4:
  mov    $0x2,%edx
  mov    %ebp,%esi
  call   <bfR2@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x4,%r8d
  jmp    L67
  nopl   0x0(%rax)
L7:
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  call   <bfR4@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x8,%r8d
  jmp    L67
```

assistant: ```c
void ffts1(float *ioptr, int M, float *Utbl, int16_t *BRLow) {
  int StageCnt;
  int NDiffU;
  switch (M) {
  case 0:
    break;
  case 1:
    fft2pt(ioptr);
    break;
  case 2:
    fft4pt(ioptr);
    break;
  case 3:
    fft8pt(ioptr);
    break;
  default:
    bitrevR2(ioptr, M, BRLow);
    StageCnt = (M - 1) / 3;
    NDiffU = 2;
    if ((M - 1 - (StageCnt * 3)) == 1) {
      bfR2(ioptr, M, NDiffU);
      NDiffU *= 2;
    }
    if ((M - 1 - (StageCnt * 3)) == 2) {
      bfR4(ioptr, M, NDiffU);
      NDiffU *= 4;
    }
    if (M <= (int)(11 - (sizeof(float) / 8)))
      bfstages(ioptr, M, Utbl, 1, NDiffU, StageCnt);
    else
      fftrecurs(ioptr, M, Utbl, 1, NDiffU, StageCnt);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ffts1>:
  endbr64
  push   %r13
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x2,%esi
  je     L10
  mov    %esi,%ebp
  mov    %rdx,%r13
  jg     L71
  test   %esi,%esi
  je     L23
  cmp    $0x1,%esi
  jne    L52
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1100 <fft2pt@plt>
  nopw   0x0(%rax,%rax,1)
L71:
  cmp    $0x3,%esi
  jne    L52
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1130 <fft8pt@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    10e0 <fft4pt@plt>
  nopl   (%rax)
L52:
  mov    %rcx,%rdx
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  call   <bitrevR2@plt>
  lea    -0x1(%rbp),%edx
  mov    0x8(%rsp),%rdi
  movslq %edx,%rbx
  mov    %edx,%eax
  imul   $0x55555556,%rbx,%rbx
  sar    $0x1f,%eax
  shr    $0x20,%rbx
  sub    %eax,%ebx
  lea    0x0(,%rbx,4),%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  je     L90
  mov    $0x2,%r8d
  cmp    $0x2,%eax
  je     L81
L87:
  mov    %ebx,%r9d
  mov    $0x1,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  cmp    $0xb,%ebp
  jg     L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    1120 <bfstages@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r13
  jmp    10f0 <fftrecurs@plt>
  nopl   (%rax)
L90:
  mov    $0x2,%edx
  mov    %ebp,%esi
  call   <bfR2@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x4,%r8d
  jmp    L87
  nopl   0x0(%rax)
L81:
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %rdi,0x8(%rsp)
  call   <bfR4@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x8,%r8d
  jmp    L87
```

assistant: ```c
void ffts1(float *ioptr, int M, float *Utbl, int16_t *BRLow) {
  int StageCnt;
  int NDiffU;
  switch (M) {
  case 0:
    break;
  case 1:
    fft2pt(ioptr);
    break;
  case 2:
    fft4pt(ioptr);
    break;
  case 3:
    fft8pt(ioptr);
    break;
  default:
    bitrevR2(ioptr, M, BRLow);
    StageCnt = (M - 1) / 3;
    NDiffU = 2;
    if ((M - 1 - (StageCnt * 3)) == 1) {
      bfR2(ioptr, M, NDiffU);
      NDiffU *= 2;
    }
    if ((M - 1 - (StageCnt * 3)) == 2) {
      bfR4(ioptr, M, NDiffU);
      NDiffU *= 4;
    }
    if (M <= (int)(11 - (sizeof(float) / 8)))
      bfstages(ioptr, M, Utbl, 1, NDiffU, StageCnt);
    else
      fftrecurs(ioptr, M, Utbl, 1, NDiffU, StageCnt);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x7ffffffc,%eax
  mov    %eax,-0x8(%rbp)
  andl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x7ffffffc,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  andl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo2(int x, int y) {
  unsigned int xa = (unsigned int)x - (0x7fffffff - 3);
  xa &= 3;
  x = 0x7fffffff - 3 + xa;
  unsigned int ya = y + 1U;
  ya &= 1;
  y = ya - 1;
  return x - y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo2>:
  endbr64
  and    $0x3,%edi
  lea    0x7ffffffc(%rdi),%eax
  shl    $0x1f,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo2(int x, int y) {
  unsigned int xa = (unsigned int)x - (0x7fffffff - 3);
  xa &= 3;
  x = 0x7fffffff - 3 + xa;
  unsigned int ya = y + 1U;
  ya &= 1;
  y = ya - 1;
  return x - y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo2>:
  endbr64
  and    $0x3,%edi
  shl    $0x1f,%esi
  lea    0x7ffffffc(%rdi),%eax
  sar    $0x1f,%esi
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo2(int x, int y) {
  unsigned int xa = (unsigned int)x - (0x7fffffff - 3);
  xa &= 3;
  x = 0x7fffffff - 3 + xa;
  unsigned int ya = y + 1U;
  ya &= 1;
  y = ya - 1;
  return x - y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo2>:
  endbr64
  and    $0x3,%edi
  shl    $0x1f,%esi
  lea    0x7ffffffc(%rdi),%eax
  sar    $0x1f,%esi
  sub    %esi,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int foo2(int x, int y) {
  unsigned int xa = (unsigned int)x - (0x7fffffff - 3);
  xa &= 3;
  x = 0x7fffffff - 3 + xa;
  unsigned int ya = y + 1U;
  ya &= 1;
  y = ya - 1;
  return x - y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  %xmm2,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x18(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L10:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x63,-0x4(%rbp)
  jle    L10
  movss  -0x8(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float foo(int a) {
  float b;
  int i;
  b = ((float)(rand() % 65536)) / ((float)(rand() % 65536));
  for (i = 0; i < 100; i++)
    b /= a;
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %ebp,%ecx
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    0x0(%rbp,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  mov    $0x64,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
L8:
  divss  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float foo(int a) {
  float b;
  int i;
  b = ((float)(rand() % 65536)) / ((float)(rand() % 65536));
  for (i = 0; i < 100; i++)
    b /= a;
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rbx,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm0
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm1
  mov    $0x64,%eax
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  nopl   0x0(%rax,%rax,1)
L8:
  divss  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float foo(int a) {
  float b;
  int i;
  b = ((float)(rand() % 65536)) / ((float)(rand() % 65536));
  for (i = 0; i < 100; i++)
    b /= a;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebx,%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  sar    $0x1f,%ecx
  shr    $0x10,%ecx
  lea    (%rbx,%rcx,1),%edx
  movzwl %dx,%edx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm0
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm1
  mov    $0x64,%eax
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  nopl   0x0(%rax,%rax,1)
L1:
  divss  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float foo(int a) {
  float b;
  int i;
  b = ((float)(rand() % 65536)) / ((float)(rand() % 65536));
  for (i = 0; i < 100; i++)
    b /= a;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<contrast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x18(%rbp),%xmm0
  jb     L0
  movss  -0x18(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  addss  %xmm1,%xmm0
  jmp    L3
L0:
  pxor   %xmm2,%xmm2
  cvtss2sd -0x18(%rbp),%xmm2
  movsd  D24(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D24(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
L3:
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  movsd  D31(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  pxor   %xmm1,%xmm1
  movd   %eax,%xmm0
  call   <max@plt>
  cvtss2sd %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D31(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: f32
name: unpack_data
arguments: data_label: D24
datatype: f32[2]
name: unpack_data
arguments: data_label: D31
datatype: f64

tool: D4: 1

tool: {"D24": [0.0,1.875]}

tool: D31: 0.5

assistant: ```c
float contrast(float v, float contrast_value) {
  float _c = (contrast_value <= 0.0) ? contrast_value + 1.0 : (1.0 / (1.0 - contrast_value));
  return (v - 0.5) * max(_c, 0.0f) + 0.5;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<contrast>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jae    L5
  cvtss2sd %xmm1,%xmm1
  movsd  D1(%rip),%xmm0
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
L13:
  pxor   %xmm1,%xmm1
  call   <max@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  movsd  D28(%rip),%xmm2
  subsd  %xmm2,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  add    $0x18,%rsp
  ret
L5:
  addss  D0(%rip),%xmm1
  movaps %xmm1,%xmm0
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: f64
name: unpack_data
arguments: data_tag: D28
data_type: f64
name: unpack_data
arguments: data_tag: D0
data_type: byte[4]

tool: D1: 1

tool: D28: 0.5

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float contrast(float v, float contrast_value) {
  float _c = (contrast_value <= 0.0) ? contrast_value + 1.0 : (1.0 / (1.0 - contrast_value));
  return (v - 0.5) * max(_c, 0.0f) + 0.5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<contrast>:
  endbr64
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  comiss %xmm1,%xmm0
  jae    L0
  movsd  D11(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  divsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
L3:
  pxor   %xmm1,%xmm1
  movss  %xmm2,0xc(%rsp)
  call   <max@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm1
  movsd  D12(%rip),%xmm2
  add    $0x18,%rsp
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  addss  D1(%rip),%xmm1
  movaps %xmm1,%xmm0
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D11
datatype: f64
name: disassemble_data
arguments: data_label: D12
datatype: f64
name: disassemble_data
arguments: data_label: D1
datatype: byte[4]

tool: D11: 1

tool: D12: 0.5

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float contrast(float v, float contrast_value) {
  float _c = (contrast_value <= 0.0) ? contrast_value + 1.0 : (1.0 / (1.0 - contrast_value));
  return (v - 0.5) * max(_c, 0.0f) + 0.5;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<contrast>:
  endbr64
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  comiss %xmm1,%xmm0
  jae    L1
  movsd  D5(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  divsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
L6:
  pxor   %xmm1,%xmm1
  movss  %xmm2,0xc(%rsp)
  call   <max@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm1
  movsd  D18(%rip),%xmm2
  add    $0x18,%rsp
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  addss  D0(%rip),%xmm1
  movaps %xmm1,%xmm0
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: f64
name: disassemble_data
arguments: data_tag: D18
type_guessed: f64
name: disassemble_data
arguments: data_tag: D0
type_guessed: byte[4]

tool: D5: 1

tool: D18: 0.5

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float contrast(float v, float contrast_value) {
  float _c = (contrast_value <= 0.0) ? contrast_value + 1.0 : (1.0 / (1.0 - contrast_value));
  return (v - 0.5) * max(_c, 0.0f) + 0.5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  void **p = (void **)ptr;
  if (*p) {
    free(*p);
    *p = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
  movq   $0x0,(%rbx)
L3:
  pop    %rbx
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  void **p = (void **)ptr;
  if (*p) {
    free(*p);
    *p = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<safe_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  call   <free@plt>
  movq   $0x0,(%rbx)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  void **p = (void **)ptr;
  if (*p) {
    free(*p);
    *p = 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<safe_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
  call   <free@plt>
  movq   $0x0,(%rbx)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  void **p = (void **)ptr;
  if (*p) {
    free(*p);
    *p = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RefreshView>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <ShowMap@plt>
  mov    $0x0,%eax
  call   <ShowUnits@plt>
  mov    $0x2,%edi
  call   <curs_set@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RefreshView() {
  curs_set(0);
  ShowMap();
  ShowUnits();
  curs_set(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RefreshView>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <ShowMap@plt>
  mov    $0x0,%eax
  call   <ShowUnits@plt>
  mov    $0x2,%edi
  call   <curs_set@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void RefreshView() {
  curs_set(0);
  ShowMap();
  ShowUnits();
  curs_set(2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RefreshView>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <ShowMap@plt>
  xor    %eax,%eax
  call   <ShowUnits@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1080 <curs_set@plt>
```

assistant: ```c
void RefreshView() {
  curs_set(0);
  ShowMap();
  ShowUnits();
  curs_set(2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RefreshView>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <curs_set@plt>
  xor    %eax,%eax
  call   <ShowMap@plt>
  xor    %eax,%eax
  call   <ShowUnits@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1080 <curs_set@plt>
```

assistant: ```c
void RefreshView() {
  curs_set(0);
  ShowMap();
  ShowUnits();
  curs_set(2);
}
```