user: 请从给定的汇编指令推导出C源代码：

```asm
<printgraph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  sub    $0x40,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L182
L196:
  movl   $0x0,-0x8(%rbp)
  jmp    L86
L225:
  cmpl   $0x0,-0xc(%rbp)
  je     L186
  cmpl   $0x0,-0x8(%rbp)
  je     L186
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L67
L186:
  mov    $0x41,%edi
  call   <putchar@plt>
  jmp    L250
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L82
  mov    -0x8(%rbp),%eax
  add    $0x41,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L250
L82:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L111
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L111
  mov    -0xc(%rbp),%eax
  add    $0x41,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L250
L111:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    -0x8(%rbp),%edx
  sub    %edx,%eax
  add    $0x3f,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L250:
  addl   $0x1,-0x8(%rbp)
L86:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L225
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L182:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L196
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L113
L205:
  movl   $0x0,-0x8(%rbp)
  jmp    L76
L96:
  cmpl   $0x0,-0xc(%rbp)
  je     L10
  cmpl   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L9
L10:
  mov    $0x41,%edi
  call   <putchar@plt>
  jmp    L126
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L78
  mov    -0x8(%rbp),%eax
  add    $0x41,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L126
L78:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L219
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L219
  mov    -0xc(%rbp),%eax
  add    $0x41,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L126
L219:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    -0x8(%rbp),%edx
  sub    %edx,%eax
  add    $0x3f,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L126:
  addl   $0x1,-0x8(%rbp)
L76:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L96
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0xc(%rbp)
L113:
  cmpl   $0x0,-0xc(%rbp)
  jns    L205
  nop
  nop
  leave
  ret
```

assistant: ```c
void printgraph(char ch) {
  int i, j;
  int n = ch - 'A' + 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < 2 * n - 1; j++) {
      if (i == 0 || j == 0 || j == 2 * n - 2)
        putchar('A');
      else {
        if (j <= i)
          putchar('A' + j);
        else if (j > i && j < 2 * n - 2 - i)
          putchar('A' + i);
        else
          putchar('A' + 2 * n - 2 - j);
      }
    }
    putchar('\n');
  }
  for (i = n - 2; i >= 0; i--) {
    for (j = 0; j < 2 * n - 1; j++) {
      if (i == 0 || j == 0 || j == 2 * n - 2)
        putchar('A');
      else {
        if (j <= i)
          putchar('A' + j);
        else if (j > i && j < 2 * n - 2 - i)
          putchar('A' + i);
        else
          putchar('A' + 2 * n - 2 - j);
      }
    }
    putchar('\n');
  }
}
```