ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff9c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x2,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0xa,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x56aa1d2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x134c225,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x75bcd15,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x75bcd15,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x3ade68b1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x75bcd15,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x4c4ba4,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0xf4245,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x483f807c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  cmp    $0x423a612e,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(-1 == find_minimum_num_formed_from_digits_of_given_num(-100));
  assert(0 == find_minimum_num_formed_from_digits_of_given_num(0));
  assert(1 == find_minimum_num_formed_from_digits_of_given_num(1));
  assert(2 == find_minimum_num_formed_from_digits_of_given_num(2));
  assert(10 == find_minimum_num_formed_from_digits_of_given_num(10));
  assert(20234789 == find_minimum_num_formed_from_digits_of_given_num(90874322));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(123456789));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(987654321));
  assert(1000005 == find_minimum_num_formed_from_digits_of_given_num(5000100));
  assert(1111122222 == find_minimum_num_formed_from_digits_of_given_num(1212121212));
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff9c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x56aa1d2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x134c225,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x75bcd15,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x75bcd15,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3ade68b1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x75bcd15,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x4c4ba4,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xf4245,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x483f807c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x423a612e,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(-1 == find_minimum_num_formed_from_digits_of_given_num(-100));
  assert(0 == find_minimum_num_formed_from_digits_of_given_num(0));
  assert(1 == find_minimum_num_formed_from_digits_of_given_num(1));
  assert(2 == find_minimum_num_formed_from_digits_of_given_num(2));
  assert(10 == find_minimum_num_formed_from_digits_of_given_num(10));
  assert(20234789 == find_minimum_num_formed_from_digits_of_given_num(90874322));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(123456789));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(987654321));
  assert(1000005 == find_minimum_num_formed_from_digits_of_given_num(5000100));
  assert(1111122222 == find_minimum_num_formed_from_digits_of_given_num(1212121212));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff9c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x56aa1d2,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x134c225,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x75bcd15,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x75bcd15,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3ade68b1,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x75bcd15,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x4c4ba4,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0xf4245,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x483f807c,%edi
  call   <find_minimum_num_formed_from_digits_of_given_num@plt>
  xor    %edi,%edi
  cmp    $0x423a612e,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(-1 == find_minimum_num_formed_from_digits_of_given_num(-100));
  assert(0 == find_minimum_num_formed_from_digits_of_given_num(0));
  assert(1 == find_minimum_num_formed_from_digits_of_given_num(1));
  assert(2 == find_minimum_num_formed_from_digits_of_given_num(2));
  assert(10 == find_minimum_num_formed_from_digits_of_given_num(10));
  assert(20234789 == find_minimum_num_formed_from_digits_of_given_num(90874322));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(123456789));
  assert(123456789 == find_minimum_num_formed_from_digits_of_given_num(987654321));
  assert(1000005 == find_minimum_num_formed_from_digits_of_given_num(5000100));
  assert(1111122222 == find_minimum_num_formed_from_digits_of_given_num(1212121212));
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<schedule_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <assert_context_process@plt>
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_long@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long schedule_timeout(long timeout) {
  long tmp;
  {
    {
      assert_context_process();
      tmp = __VERIFIER_nondet_long();
    }
    return (tmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<schedule_timeout>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <assert_context_process@plt>
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_long@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long schedule_timeout(long timeout) {
  long tmp;
  {
    {
      assert_context_process();
      tmp = __VERIFIER_nondet_long();
    }
    return (tmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<schedule_timeout>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assert_context_process@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <__VERIFIER_nondet_long@plt>
```

assistant: ```c
long schedule_timeout(long timeout) {
  long tmp;
  {
    {
      assert_context_process();
      tmp = __VERIFIER_nondet_long();
    }
    return (tmp);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<schedule_timeout>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assert_context_process@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <__VERIFIER_nondet_long@plt>
```

assistant: ```c
long schedule_timeout(long timeout) {
  long tmp;
  {
    {
      assert_context_process();
      tmp = __VERIFIER_nondet_long();
    }
    return (tmp);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L42
  mov    D12(%rip),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L4
L42:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  movq   $0x0,D12(%rip)
  mov    $0x0,%eax
  jmp    L4
L31:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L38:
  mov    -0x10(%rbp),%rax
  mov    %rax,D10(%rip)
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
char *strtok(char *s, const char *ct) {
  const char *s1;
  char *s2;
  static char *savestring = NULL;
  if (s == NULL) {
    s = savestring;
    if (s == NULL) {
      return ((char *)NULL);
    }
  }
  s1 = s + strspn(s, ct);
  if (*s1 == '\0') {
    savestring = NULL;
    return ((char *)NULL);
  }
  s2 = strpbrk(s1, ct);
  if (s2) {
    *s2++ = '\0';
  }
  savestring = s2;
  return ((char *)s1);
}
```
user: What is the c source code of the assembly code below:

```asm
<strtok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L21
L56:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  je     L44
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L46
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
L46:
  mov    %rdx,D9(%rip)
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    D9(%rip),%rbx
  test   %rbx,%rbx
  jne    L56
  jmp    L15
L44:
  movq   $0x0,D9(%rip)
  mov    $0x0,%ebx
  jmp    L15
```

assistant: ```c
char *strtok(char *s, const char *ct) {
  const char *s1;
  char *s2;
  static char *savestring = NULL;
  if (s == NULL) {
    s = savestring;
    if (s == NULL) {
      return ((char *)NULL);
    }
  }
  s1 = s + strspn(s, ct);
  if (*s1 == '\0') {
    savestring = NULL;
    return ((char *)NULL);
  }
  s2 = strpbrk(s1, ct);
  if (s2) {
    *s2++ = '\0';
  }
  savestring = s2;
  return ((char *)s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strtok>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
L39:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L20
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L47
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L47:
  mov    %rdx,D25(%rip)
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    D25(%rip),%r12
  test   %r12,%r12
  jne    L39
  xor    %r12d,%r12d
  jmp    L18
  nopl   0x0(%rax)
L20:
  movq   $0x0,D25(%rip)
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *s, const char *ct) {
  const char *s1;
  char *s2;
  static char *savestring = NULL;
  if (s == NULL) {
    s = savestring;
    if (s == NULL) {
      return ((char *)NULL);
    }
  }
  s1 = s + strspn(s, ct);
  if (*s1 == '\0') {
    savestring = NULL;
    return ((char *)NULL);
  }
  s2 = strpbrk(s1, ct);
  if (s2) {
    *s2++ = '\0';
  }
  savestring = s2;
  return ((char *)s1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtok>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L11
L9:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L1
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L23
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L23:
  mov    %rdx,D2(%rip)
L38:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    D2(%rip),%r12
  test   %r12,%r12
  jne    L9
  xor    %r12d,%r12d
  jmp    L38
  nopl   0x0(%rax)
L1:
  movq   $0x0,D2(%rip)
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *s, const char *ct) {
  const char *s1;
  char *s2;
  static char *savestring = NULL;
  if (s == NULL) {
    s = savestring;
    if (s == NULL) {
      return ((char *)NULL);
    }
  }
  s1 = s + strspn(s, ct);
  if (*s1 == '\0') {
    savestring = NULL;
    return ((char *)NULL);
  }
  s2 = strpbrk(s1, ct);
  if (s2) {
    *s2++ = '\0';
  }
  savestring = s2;
  return ((char *)s1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raspberry_serial_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <dev_puts_func@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int raspberry_serial_printf(char *format, ...) {
  dev_puts_func(format);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<raspberry_serial_printf>:
  endbr64
  sub    $0x8,%rsp
  call   <dev_puts_func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int raspberry_serial_printf(char *format, ...) {
  dev_puts_func(format);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<raspberry_serial_printf>:
  endbr64
  sub    $0x8,%rsp
  call   <dev_puts_func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int raspberry_serial_printf(char *format, ...) {
  dev_puts_func(format);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<raspberry_serial_printf>:
  endbr64
  sub    $0x8,%rsp
  call   <dev_puts_func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int raspberry_serial_printf(char *format, ...) {
  dev_puts_func(format);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x11,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = 3, y = 2;
  int a = x + y;
  int b = x + y;
  a = 17;
  int c = x + y;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x = 3, y = 2;
  int a = x + y;
  int b = x + y;
  a = 17;
  int c = x + y;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 3, y = 2;
  int a = x + y;
  int b = x + y;
  a = 17;
  int c = x + y;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 3, y = 2;
  int a = x + y;
  int b = x + y;
  a = 17;
  int c = x + y;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mp_hal_stdin_rx_chr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xd(%rbp)
  lea    -0xd(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  movzbl -0xd(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int mp_hal_stdin_rx_chr(void) {
  unsigned char c = 0;
  int r = read(0, &c, 1);
  (void)r;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mp_hal_stdin_rx_chr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mp_hal_stdin_rx_chr(void) {
  unsigned char c = 0;
  int r = read(0, &c, 1);
  (void)r;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mp_hal_stdin_rx_chr>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mp_hal_stdin_rx_chr(void) {
  unsigned char c = 0;
  int r = read(0, &c, 1);
  (void)r;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mp_hal_stdin_rx_chr>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mp_hal_stdin_rx_chr(void) {
  unsigned char c = 0;
  int r = read(0, &c, 1);
  (void)r;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply335>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L12
L11:
  movl   $0x0,-0x3c(%rbp)
  jmp    L29
L18:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L29:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L18
  addl   $0x1,-0x40(%rbp)
L12:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L11
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply335(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply335>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L20:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L25:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L25
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  ret
```

assistant: ```c
void multiply335(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiply335>:
  endbr64
  test   %edi,%edi
  jle    L24
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L0
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L26
  pop    %rbx
  ret
L24:
  ret
```

assistant: ```c
void multiply335(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```