ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_chunk>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r13
  imul   %esi,%edx
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    (%rsi,%rdx,1),%r13d
  mov    %edx,%ebx
  sub    $0x8,%rsp
L0:
  mov    %ebx,%esi
  mov    %r12,%rdi
  lea    (%rax,%rax,1),%ebp
  add    $0x1,%ebx
  call   <get_bit@plt>
  or     %ebp,%eax
  cmp    %r13d,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_chunk(const char *bytes, int k, int i) {
  int chunk = 0;
  for (int j = 0; j < k; j++) {
    chunk = (chunk << 1) | get_bit(bytes, (i * k) + j);
  }
  return chunk;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quantiUgualiConMergeLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L111
L98:
  movl   $0x0,-0xc(%rbp)
  cmpl   $0xa,-0x8(%rbp)
  jg     L99
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L83
L92:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jne    L10
  addl   $0x1,-0x14(%rbp)
L10:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L83:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L9
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L92
  jmp    L9
L99:
  mov    $0x14,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L22
L26:
  mov    -0x8(%rbp),%eax
  lea    -0xa(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    $0x9,%eax
  sub    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x8(%rbp),%eax
  lea    -0xa(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    $0x9,%eax
  sub    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jne    L13
  addl   $0x1,-0x14(%rbp)
L13:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L9
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L26
L9:
  addl   $0x1,-0x8(%rbp)
L111:
  cmpl   $0x13,-0x8(%rbp)
  jg     L126
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L98
L126:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop(int A[][10], int B[][10], int k) {
  int cont = 0, howMany = 0, i, numElem;
  int dn = 1;
  while (dn <= 2 * 10 - 1 && howMany < k) {
    i = 0;
    if (dn <= 10) {
      numElem = dn;
      while (i < numElem && howMany < k) {
        if (A[i][dn - 1 - i] == B[i][dn - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    } else {
      numElem = 10 - (dn - 10);
      while (i < numElem && howMany < k) {
        if (A[dn - 10 + i][10 - 1 - i] == B[dn - 10 + i][10 - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    }
    dn++;
  }
  return cont;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quantiUgualiConMergeLoop>:
  endbr64
  test   %edx,%edx
  jle    L71
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %edx,%edi
  mov    $0xfffffffffffffebc,%r12
  mov    $0x13,%ebx
  mov    $0x0,%ebp
  mov    $0x1,%r8d
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L88
L12:
  mov    %ebx,%r13d
  test   %ebx,%ebx
  jle    L101
  cmp    %eax,%edi
  jle    L101
  mov    %r12,%rdx
  mov    $0x0,%esi
L70:
  mov    (%r10,%rdx,1),%r11d
  cmp    %r11d,(%r9,%rdx,1)
  sete   %r11b
  movzbl %r11b,%r11d
  add    %r11d,%ecx
  add    $0x1,%eax
  add    $0x1,%esi
  add    $0x24,%rdx
  cmp    %r13d,%esi
  jge    L101
  cmp    %eax,%edi
  jg     L70
L101:
  add    $0x1,%r8d
  add    $0x1,%rbp
  sub    $0x1,%ebx
  add    $0x28,%r12
  cmp    $0x13,%r8d
  jg     L42
  cmp    %edi,%eax
  jge    L42
L88:
  cmp    $0xa,%r8d
  jg     L12
  test   %r8d,%r8d
  jle    L101
  cmp    %eax,%edi
  jle    L101
  lea    0x0(,%rbp,4),%rdx
  mov    $0x0,%esi
L52:
  mov    (%r10,%rdx,1),%r11d
  cmp    %r11d,(%r9,%rdx,1)
  sete   %r11b
  movzbl %r11b,%r11d
  add    %r11d,%ecx
  add    $0x1,%eax
  add    $0x1,%esi
  add    $0x24,%rdx
  cmp    %r8d,%esi
  jge    L101
  cmp    %eax,%edi
  jg     L52
  jmp    L101
L71:
  mov    $0x0,%ecx
  mov    %ecx,%eax
  ret
L42:
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop(int A[][10], int B[][10], int k) {
  int cont = 0, howMany = 0, i, numElem;
  int dn = 1;
  while (dn <= 2 * 10 - 1 && howMany < k) {
    i = 0;
    if (dn <= 10) {
      numElem = dn;
      while (i < numElem && howMany < k) {
        if (A[i][dn - 1 - i] == B[i][dn - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    } else {
      numElem = 10 - (dn - 10);
      while (i < numElem && howMany < k) {
        if (A[dn - 10 + i][10 - 1 - i] == B[dn - 10 + i][10 - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    }
    dn++;
  }
  return cont;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quantiUgualiConMergeLoop>:
  endbr64
  test   %edx,%edx
  jle    L86
  push   %r12
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %edx,%edi
  push   %rbp
  mov    $0xfffffffffffffebc,%r12
  xor    %ebp,%ebp
  mov    $0x1,%r11d
  push   %rbx
  xor    %eax,%eax
  mov    $0x13,%ebx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L11:
  cmp    $0xa,%r11d
  jg     L45
  cmp    %eax,%edi
  jle    L61
  lea    0x0(,%rbp,4),%rcx
  xor    %esi,%esi
  nopl   0x0(%rax)
L95:
  mov    (%r10,%rcx,1),%edx
  cmp    %edx,(%r9,%rcx,1)
  sete   %dl
  add    $0x1,%eax
  add    $0x1,%esi
  movzbl %dl,%edx
  add    %edx,%r8d
  cmp    %eax,%edi
  setg   %dl
  add    $0x24,%rcx
  cmp    %r11d,%esi
  jge    L20
  test   %dl,%dl
  jne    L95
L20:
  add    $0x1,%r11d
  add    $0x1,%rbp
  sub    $0x1,%ebx
  add    $0x28,%r12
  cmp    $0x13,%r11d
  jg     L61
  test   %dl,%dl
  jne    L11
L61:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    %eax,%edi
  jle    L61
  mov    %r12,%rcx
  xor    %esi,%esi
  nopl   0x0(%rax)
L24:
  mov    (%r10,%rcx,1),%edx
  cmp    %edx,(%r9,%rcx,1)
  sete   %dl
  add    $0x1,%eax
  add    $0x1,%esi
  movzbl %dl,%edx
  add    %edx,%r8d
  cmp    %eax,%edi
  setg   %dl
  add    $0x24,%rcx
  cmp    %esi,%ebx
  jle    L20
  test   %dl,%dl
  jne    L24
  jmp    L20
L86:
  xor    %eax,%eax
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop(int A[][10], int B[][10], int k) {
  int cont = 0, howMany = 0, i, numElem;
  int dn = 1;
  while (dn <= 2 * 10 - 1 && howMany < k) {
    i = 0;
    if (dn <= 10) {
      numElem = dn;
      while (i < numElem && howMany < k) {
        if (A[i][dn - 1 - i] == B[i][dn - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    } else {
      numElem = 10 - (dn - 10);
      while (i < numElem && howMany < k) {
        if (A[dn - 10 + i][10 - 1 - i] == B[dn - 10 + i][10 - 1 - i])
          cont++;
        howMany++;
        i++;
      }
    }
    dn++;
  }
  return cont;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_hint_int_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L18:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string

tool: D2: 	%s:	FINEST


tool: D14: 	%s:	%d


assistant: ```c
void print_hint_int_values(const char *name, const int val) {
  if (val == -1) {
    printf("\t%s:\tFINEST\n", name);
    return;
  }
  printf("\t%s:\t%d\n", name, val);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_hint_int_values>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L13
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  add    $0x8,%rsp
  ret
L13:
  mov    %rdi,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D15: 	%s:	%d


tool: D18: 	%s:	FINEST


assistant: ```c
void print_hint_int_values(const char *name, const int val) {
  if (val == -1) {
    printf("\t%s:\tFINEST\n", name);
    return;
  }
  printf("\t%s:\t%d\n", name, val);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_hint_int_values>:
  endbr64
  mov    %esi,%edx
  mov    %rdi,%rsi
  cmp    $0xffffffff,%edx
  je     L6
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L6:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D5: 	%s:	%d


tool: D17: 	%s:	FINEST


assistant: ```c
void print_hint_int_values(const char *name, const int val) {
  if (val == -1) {
    printf("\t%s:\tFINEST\n", name);
    return;
  }
  printf("\t%s:\t%d\n", name, val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_hint_int_values>:
  endbr64
  mov    %esi,%edx
  mov    %rdi,%rsi
  cmp    $0xffffffff,%edx
  je     L0
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L0:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D10
type_guessed: string

tool: D15: 	%s:	%d


tool: D10: 	%s:	FINEST


assistant: ```c
void print_hint_int_values(const char *name, const int val) {
  if (val == -1) {
    printf("\t%s:\tFINEST\n", name);
    return;
  }
  printf("\t%s:\t%d\n", name, val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stringCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movw   $0xffff,-0x2(%rbp)
L3:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short stringCopy(unsigned char *dest, unsigned char *source) {
  short length = -1;
  do {
    *dest++ = *source++;
    length++;
  } while (*(source - 1) != 0);
  return (unsigned short)length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringCopy>:
  endbr64
  mov    $0x0,%eax
L2:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned short stringCopy(unsigned char *dest, unsigned char *source) {
  short length = -1;
  do {
    *dest++ = *source++;
    length++;
  } while (*(source - 1) != 0);
  return (unsigned short)length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stringCopy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r8d
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short stringCopy(unsigned char *dest, unsigned char *source) {
  short length = -1;
  do {
    *dest++ = *source++;
    length++;
  } while (*(source - 1) != 0);
  return (unsigned short)length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stringCopy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r8d
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short stringCopy(unsigned char *dest, unsigned char *source) {
  short length = -1;
  do {
    *dest++ = *source++;
    length++;
  } while (*(source - 1) != 0);
  return (unsigned short)length;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p)
    die("strdup");
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
L1:
  mov    %rbx,%rax
  pop    %rbx
  ret
L12:
  lea    D1(%rip),%rdi
  call   <die@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p)
    die("strdup");
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L3:
  mov    %r12,%rax
  pop    %r12
  ret
L11:
  lea    D5(%rip),%rdi
  call   <die@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p)
    die("strdup");
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L15:
  mov    %r12,%rax
  pop    %r12
  ret
L11:
  lea    D6(%rip),%rdi
  call   <die@plt>
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p)
    die("strdup");
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long addbase(unsigned long base, int offset) {
  base += offset * 32;
  return base;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<addbase>:
  endbr64
  shl    $0x5,%esi
  movslq %esi,%rax
  add    %rdi,%rax
  ret
```

assistant: ```c
unsigned long addbase(unsigned long base, int offset) {
  base += offset * 32;
  return base;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<addbase>:
  endbr64
  shl    $0x5,%esi
  movslq %esi,%rax
  add    %rdi,%rax
  ret
```

assistant: ```c
unsigned long addbase(unsigned long base, int offset) {
  base += offset * 32;
  return base;
}
```
user: What is the c source code of the assembly code below:

```asm
<addbase>:
  endbr64
  shl    $0x5,%esi
  movslq %esi,%rax
  add    %rdi,%rax
  ret
```

assistant: ```c
unsigned long addbase(unsigned long base, int offset) {
  base += offset * 32;
  return base;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x64(%rbp)
  movq   $0x64,-0x60(%rbp)
  movq   $0xc8,-0x58(%rbp)
  movq   $0x52,-0x50(%rbp)
  movq   $0xa,-0x48(%rbp)
  movq   $0x9,-0x40(%rbp)
  movq   $0x48,-0x38(%rbp)
  movq   $0x31,-0x30(%rbp)
  movq   $0x11,-0x28(%rbp)
  movq   $0x18,-0x20(%rbp)
  movq   $0xc,-0x18(%rbp)
  movq   $0x22,-0x10(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <benchmark_heapsort@plt>
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int N = 10;
  long ary[] = {100, 200, 82, 10, 9, 72, 49, 17, 24, 12, 34};
  int i;
  benchmark_heapsort(N, ary);
  printf("%ld\n", ary[N]);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movq   $0x64,(%rsp)
  movq   $0xc8,0x8(%rsp)
  movq   $0x52,0x10(%rsp)
  movq   $0xa,0x18(%rsp)
  movq   $0x9,0x20(%rsp)
  movq   $0x48,0x28(%rsp)
  movq   $0x31,0x30(%rsp)
  movq   $0x11,0x38(%rsp)
  movq   $0x18,0x40(%rsp)
  movq   $0xc,0x48(%rsp)
  movq   $0x22,0x50(%rsp)
  mov    %rsp,%rsi
  mov    $0xa,%edi
  call   <benchmark_heapsort@plt>
  mov    0x50(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int N = 10;
  long ary[] = {100, 200, 82, 10, 9, 72, 49, 17, 24, 12, 34};
  int i;
  benchmark_heapsort(N, ary);
  printf("%ld\n", ary[N]);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0xa,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x64,(%rsp)
  movq   $0xc8,0x8(%rsp)
  movq   $0x52,0x10(%rsp)
  movq   $0xa,0x18(%rsp)
  movq   $0x9,0x20(%rsp)
  movq   $0x48,0x28(%rsp)
  movq   $0x31,0x30(%rsp)
  movq   $0x11,0x38(%rsp)
  movq   $0x18,0x40(%rsp)
  movq   $0xc,0x48(%rsp)
  movq   $0x22,0x50(%rsp)
  call   <benchmark_heapsort@plt>
  mov    0x50(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int N = 10;
  long ary[] = {100, 200, 82, 10, 9, 72, 49, 17, 24, 12, 34};
  int i;
  benchmark_heapsort(N, ary);
  printf("%ld\n", ary[N]);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  movdqa D56(%rip),%xmm0
  mov    $0xa,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x22,0x50(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D3(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D37(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D41(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D48(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <benchmark_heapsort@plt>
  mov    0x50(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D3
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D37
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D41
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D48
data_type: byte[16]
name: retrieve_data
arguments: data_tag: D33
data_type: string

tool: {"D56": [0x64,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc8,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D3": [0x52,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D37": [0x09,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D41": [0x31,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D48": [0x18,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D33: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int N = 10;
  long ary[] = {100, 200, 82, 10, 9, 72, 49, 17, 24, 12, 34};
  int i;
  benchmark_heapsort(N, ary);
  printf("%ld\n", ary[N]);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<forwardSubstitution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <allocateDoubleVector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L2
L32:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L37
L39:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L39
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *forwardSubstitution(int n, double **A, double *b) {
  int i, j;
  double *x, a;
  x = allocateDoubleVector(n);
  for (i = 0; i < n; i++) {
    a = b[i];
    for (j = 0; j <= i; j++)
      a = a - A[i][j] * x[j];
    x[i] = a / A[i][i];
  }
  return x;
}
```