ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minHeapSort>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L17
  mov    %rdi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    0x0(%rbp),%esi
  call   <swap@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <minHeapFixdown@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L13
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void minHeapSort(int a[], int n) {
  for (int i = n - 1; i >= 1; i--) {
    swap(a[i], a[0]);
    minHeapFixdown(a, 0, i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<minHeapSort>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L0
  mov    %rdi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    0x0(%rbp),%esi
  call   <swap@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <minHeapFixdown@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L10
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void minHeapSort(int a[], int n) {
  for (int i = n - 1; i >= 1; i--) {
    swap(a[i], a[0]);
    minHeapFixdown(a, 0, i);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<encrypt_sku>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rsi
  lea    D31(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L30
  lea    D32(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%r15
  test   %rax,%rax
  jne    L51
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L30:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L88:
  mov    0x8(%rsp),%rcx
  mov    $0x1,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <fwrite@plt>
L51:
  mov    (%rsp),%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %r15,%rdi
  call   <fread@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L6
  movsbl 0x10(%rsp),%edi
  mov    $0x8,%esi
  call   <reverse_bits@plt>
  mov    %al,0x10(%rsp)
  lea    -0x1(%r14),%r12d
  test   %r12d,%r12d
  jle    L88
  movslq %r14d,%rbp
  add    %r15,%rbp
L10:
  mov    %r12d,%edi
  sub    $0x1,%r12d
  movzbl -0x2(%rbp),%ebx
  movzbl -0x1(%rbp),%r13d
  call   <fib@plt>
  xor    %r13d,%ebx
  xor    %eax,%ebx
  mov    %bl,-0x1(%rbp)
  sub    $0x1,%rbp
  test   %r12d,%r12d
  jne    L10
  jmp    L88
L6:
  mov    (%rsp),%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <fclose@plt>
L72:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_guessed: string
name: disassemble_data
arguments: data_tag: D31
type_guessed: string
name: disassemble_data
arguments: data_tag: D32
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D50
type_guessed: string

tool: D28: r

tool: D31: sku.testout

tool: D32: w

tool: D16: sku.test17out

tool: D39: couldn't open output file sku.testout


tool: D50: couldn't open input file sku.17


assistant: ```c
void encrypt_sku(void) {
  FILE *sku17;
  FILE *skutestout;
  char sku_buffer[1024];
  int num_bytes_read;
  if ((sku17 = fopen("sku.testout", "r")) == NULL) {
    printf("couldn't open input file sku.17\n");
    return;
  }
  if ((skutestout = fopen("sku.test17out", "w")) == NULL) {
    printf("couldn't open output file sku.testout\n");
    return;
  }
  while (num_bytes_read = fread(sku_buffer, 1, 1024, sku17)) {
    int current_byte;
    sku_buffer[0] = reverse_bits(sku_buffer[0], 8);
    for (current_byte = num_bytes_read - 1; current_byte > 0; --current_byte) {
      sku_buffer[current_byte] = sku_buffer[current_byte - 1] ^ sku_buffer[current_byte] ^ (fib(current_byte) & 0xFF);
    }
    fwrite(sku_buffer, num_bytes_read, 1, skutestout);
  }
  fclose(sku17);
  fclose(skutestout);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ExpressionStackPushValueByType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <VariableAllocValueFromType@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ExpressionStackPushValueNode@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct Value *ExpressionStackPushValueByType(struct ParseState *Parser, struct ExpressionStack **StackTop, struct ValueType *PushType) {
  struct Value *ValueLoc = VariableAllocValueFromType(Parser, PushType, 0, 0, 0);
  ExpressionStackPushValueNode(Parser, StackTop, ValueLoc);
  return ValueLoc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ExpressionStackPushValueByType>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <VariableAllocValueFromType@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <ExpressionStackPushValueNode@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct Value *ExpressionStackPushValueByType(struct ParseState *Parser, struct ExpressionStack **StackTop, struct ValueType *PushType) {
  struct Value *ValueLoc = VariableAllocValueFromType(Parser, PushType, 0, 0, 0);
  ExpressionStackPushValueNode(Parser, StackTop, ValueLoc);
  return ValueLoc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ExpressionStackPushValueByType>:
  endbr64
  push   %r13
  xor    %r8d,%r8d
  mov    %rsi,%r13
  xor    %ecx,%ecx
  push   %r12
  mov    %rdx,%rsi
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  call   <VariableAllocValueFromType@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <ExpressionStackPushValueNode@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct Value *ExpressionStackPushValueByType(struct ParseState *Parser, struct ExpressionStack **StackTop, struct ValueType *PushType) {
  struct Value *ValueLoc = VariableAllocValueFromType(Parser, PushType, 0, 0, 0);
  ExpressionStackPushValueNode(Parser, StackTop, ValueLoc);
  return ValueLoc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ExpressionStackPushValueByType>:
  endbr64
  push   %r13
  xor    %r8d,%r8d
  mov    %rsi,%r13
  xor    %ecx,%ecx
  push   %r12
  mov    %rdx,%rsi
  xor    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  call   <VariableAllocValueFromType@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <ExpressionStackPushValueNode@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct Value *ExpressionStackPushValueByType(struct ParseState *Parser, struct ExpressionStack **StackTop, struct ValueType *PushType) {
  struct Value *ValueLoc = VariableAllocValueFromType(Parser, PushType, 0, 0, 0);
  ExpressionStackPushValueNode(Parser, StackTop, ValueLoc);
  return ValueLoc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f77096573656854,%rax
  movabs $0x965726109736472,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6574617261706573,%rax
  movabs $0x6261740979620964,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x2e73,-0x10(%rbp)
  movb   $0x0,-0xe(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <count_words@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D9: 
== test6 =====================================================

tool: D4: |%s|


tool: D1: Word count is %2i


assistant: ```c
void test6(void) {
  char string[] = "These\twords\tare\tseparated\tby\ttabs.";
  int count;
  printf("\n== test6 =====================================================\n");
  printf("|%s|\n", string);
  count = count_words(string);
  printf("Word count is %2i\n", count);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test6>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f77096573656854,%rax
  movabs $0x965726109736472,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x6574617261706573,%rax
  movabs $0x6261740979620964,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x2e73,0x20(%rsp)
  movb   $0x0,0x22(%rsp)
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <count_words@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type_infered: string
name: unpack_data
arguments: data_tag: D24
type_infered: string
name: unpack_data
arguments: data_tag: D11
type_infered: string

tool: D28: 
== test6 =====================================================

tool: D24: |%s|


tool: D11: Word count is %2i


assistant: ```c
void test6(void) {
  char string[] = "These\twords\tare\tseparated\tby\ttabs.";
  int count;
  printf("\n== test6 =====================================================\n");
  printf("|%s|\n", string);
  count = count_words(string);
  printf("Word count is %2i\n", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test6>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x2e73,%eax
  movb   $0x0,0x22(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D3(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <count_words@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D3
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D37
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D22: 
== test6 =====================================================

tool: {"D4": [0x54,0x68,0x65,0x73,0x65,0x09,0x77,0x6f,0x72,0x64,0x73,0x09,0x61,0x72,0x65,0x09]}

tool: {"D3": [0x73,0x65,0x70,0x61,0x72,0x61,0x74,0x65,0x64,0x09,0x62,0x79,0x09,0x74,0x61,0x62]}

tool: D37: |%s|


tool: D1: Word count is %2i


assistant: ```c
void test6(void) {
  char string[] = "These\twords\tare\tseparated\tby\ttabs.";
  int count;
  printf("\n== test6 =====================================================\n");
  printf("|%s|\n", string);
  count = count_words(string);
  printf("Word count is %2i\n", count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test6>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x2e73,%eax
  movb   $0x0,0x22(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D17(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <count_words@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D17
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D28: 
== test6 =====================================================

tool: {"D36": [0x54,0x68,0x65,0x73,0x65,0x09,0x77,0x6f,0x72,0x64,0x73,0x09,0x61,0x72,0x65,0x09]}

tool: {"D17": [0x73,0x65,0x70,0x61,0x72,0x61,0x74,0x65,0x64,0x09,0x62,0x79,0x09,0x74,0x61,0x62]}

tool: D14: |%s|


tool: D3: Word count is %2i


assistant: ```c
void test6(void) {
  char string[] = "These\twords\tare\tseparated\tby\ttabs.";
  int count;
  printf("\n== test6 =====================================================\n");
  printf("|%s|\n", string);
  count = count_words(string);
  printf("Word count is %2i\n", count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<self_adj_desired_freq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L12
L13:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   D2(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L13
  movl   $0x1,-0x1c(%rbp)
  jmp    L27
L35:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L27:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L35
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: f64
name: retrieve_data
arguments: data_label: D2
type_guessed: f32[2]

tool: D0: 1

tool: {"D2": [0.0,-0.0]}

assistant: ```c
void self_adj_desired_freq(double *freq_ref, int grid_size, double freq_zeta) {
  int i;
  double sumv;
  sumv = 0.0;
  for (i = 1; i <= grid_size + 1; i++) {
    freq_ref[i] = exp(-(i - 1.0) * freq_zeta);
    sumv += freq_ref[i];
  }
  for (i = 1; i <= grid_size + 1; i++)
    freq_ref[i] /= sumv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<self_adj_desired_freq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  js     L26
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x1,%r12d
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
L22:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  subsd  D2(%rip),%xmm0
  xorpd  D3(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  %xmm0,0x0(%rbp,%r12,8)
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%r12
  lea    -0x1(%r12),%eax
  cmp    %eax,%ebx
  jge    L22
  lea    0x8(%rbp),%rax
  mov    %ebx,%ebx
  lea    0x10(%rbp,%rbx,8),%rdx
L19:
  movsd  (%rax),%xmm0
  divsd  (%rsp),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L26:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: f64
name: retrieve_data
arguments: tag: D3
data_type: f32[4]

tool: D2: 1

tool: {"D3": [0.0,-0.0,0.0,0.0]}

assistant: ```c
void self_adj_desired_freq(double *freq_ref, int grid_size, double freq_zeta) {
  int i;
  double sumv;
  sumv = 0.0;
  for (i = 1; i <= grid_size + 1; i++) {
    freq_ref[i] = exp(-(i - 1.0) * freq_zeta);
    sumv += freq_ref[i];
  }
  for (i = 1; i <= grid_size + 1; i++)
    freq_ref[i] /= sumv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<self_adj_desired_freq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %ebx,%ebx
  js     L3
  mov    %rdi,%rbp
  mov    $0x1,%r12d
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L9:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,(%rsp)
  cvtsi2sd %r12d,%xmm0
  subsd  D6(%rip),%xmm0
  xorpd  D4(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x0(%rbp,%r12,8)
  add    $0x1,%r12
  lea    -0x1(%r12),%eax
  addsd  %xmm0,%xmm1
  cmp    %eax,%ebx
  jge    L9
  lea    0x8(%rbp),%rax
  lea    0x10(%rbp,%rbx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L29:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L29
L3:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: f64
name: retrieve_data
arguments: data_label: D4
datatype: f32[4]

tool: D6: 1

tool: {"D4": [0.0,-0.0,0.0,0.0]}

assistant: ```c
void self_adj_desired_freq(double *freq_ref, int grid_size, double freq_zeta) {
  int i;
  double sumv;
  sumv = 0.0;
  for (i = 1; i <= grid_size + 1; i++) {
    freq_ref[i] = exp(-(i - 1.0) * freq_zeta);
    sumv += freq_ref[i];
  }
  for (i = 1; i <= grid_size + 1; i++)
    freq_ref[i] /= sumv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<self_adj_desired_freq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  js     L49
  mov    %rdi,%r12
  mov    %esi,%ebp
  pxor   %xmm1,%xmm1
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,(%rsp)
  cvtsi2sd %ebx,%xmm0
  subsd  D1(%rip),%xmm0
  xorpd  D17(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  addsd  %xmm0,%xmm1
  cmp    %eax,%ebp
  jge    L6
  lea    0x1(%rbp),%ecx
  test   %ebp,%ebp
  je     L30
  mov    %ecx,%edx
  movapd %xmm1,%xmm2
  lea    0x8(%r12),%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%r12,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L39:
  movupd (%rax),%xmm0
  add    $0x10,%rax
  divpd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L39
  mov    %ecx,%eax
  or     $0x1,%eax
  and    $0x1,%ecx
  je     L49
L31:
  cltq
  lea    (%r12,%rax,8),%rax
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L49:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  mov    $0x1,%eax
  jmp    L31
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: f64
name: parse_data
arguments: data_tag: D17
data_type: f32[4]

tool: D1: 1

tool: {"D17": [0.0,-0.0,0.0,0.0]}

assistant: ```c
void self_adj_desired_freq(double *freq_ref, int grid_size, double freq_zeta) {
  int i;
  double sumv;
  sumv = 0.0;
  for (i = 1; i <= grid_size + 1; i++) {
    freq_ref[i] = exp(-(i - 1.0) * freq_zeta);
    sumv += freq_ref[i];
  }
  for (i = 1; i <= grid_size + 1; i++)
    freq_ref[i] /= sumv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exgcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L11
  mov    -0x28(%rbp),%rax
  movq   $0x1,(%rax)
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L18
L11:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <exgcd>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rcx
  imul   %rax,%rcx
  mov    -0x8(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
L18:
  leave
  ret
```

assistant: ```c
long exgcd(long a, long b, long *x, long *y) {
  if (b == 0) {
    *x = 1;
    *y = 0;
    return a;
  } else {
    long d = exgcd(b, a % b, x, y);
    long t = *x;
    *x = *y;
    *y = t - a / b * (*y);
    return d;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<exgcd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    $0x1,%edx
  test   %rsi,%rsi
  jne    L13
L11:
  mov    %rdx,(%r12)
  mov    %rdi,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  cqto
  idiv   %rsi
  mov    %rdx,%rsi
  mov    %rax,%rbx
  mov    %r12,%rdx
  call   <exgcd>
  mov    %rax,%rcx
  mov    0x0(%rbp),%rdx
  mov    %rbx,%rax
  imul   %rdx,%rax
  mov    (%r12),%rdi
  sub    %rax,%rdi
  mov    %rcx,%rax
  jmp    L11
```

assistant: ```c
long exgcd(long a, long b, long *x, long *y) {
  if (b == 0) {
    *x = 1;
    *y = 0;
    return a;
  } else {
    long d = exgcd(b, a % b, x, y);
    long t = *x;
    *x = *y;
    *y = t - a / b * (*y);
    return d;
  }
}
```