ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  movl   $0x6,-0x24(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <twoSum@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: index 1:%d index 2:%d


assistant: ```c
int main() {
  int array[] = {3, 2, 4};
  int target = 6;
  int *ptr = NULL;
  ptr = twoSum(array, sizeof(array) / sizeof(array[0]), target);
  printf("index 1:%d index 2:%d\n", ptr[0], ptr[1]);
  free(ptr);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x6,%edx
  mov    $0x3,%esi
  call   <twoSum@plt>
  mov    %rax,%rbx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: index 1:%d index 2:%d


assistant: ```c
int main() {
  int array[] = {3, 2, 4};
  int target = 6;
  int *ptr = NULL;
  ptr = twoSum(array, sizeof(array) / sizeof(array[0]), target);
  printf("index 1:%d index 2:%d\n", ptr[0], ptr[1]);
  free(ptr);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6,%edx
  mov    $0x3,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000003,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x4,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <twoSum@plt>
  lea    D3(%rip),%rdi
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: index 1:%d index 2:%d


assistant: ```c
int main() {
  int array[] = {3, 2, 4};
  int target = 6;
  int *ptr = NULL;
  ptr = twoSum(array, sizeof(array) / sizeof(array[0]), target);
  printf("index 1:%d index 2:%d\n", ptr[0], ptr[1]);
  free(ptr);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6,%edx
  mov    $0x3,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x4,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <twoSum@plt>
  lea    D13(%rip),%rdi
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: byte[8]
name: read_data
arguments: data_label: D13
data_type: string

tool: {"D6": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D13: index 1:%d index 2:%d


assistant: ```c
int main() {
  int array[] = {3, 2, 4};
  int target = 6;
  int *ptr = NULL;
  ptr = twoSum(array, sizeof(array) / sizeof(array[0]), target);
  printf("index 1:%d index 2:%d\n", ptr[0], ptr[1]);
  free(ptr);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wildcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L89
  mov    $0x0,%eax
  jmp    L52
L89:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L68
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L14
L68:
  mov    $0x0,%eax
  jmp    L52
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ebx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <text@plt>
  cmp    %al,%bl
  je     L0
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L52
L0:
  addl   $0x1,-0x14(%rbp)
  jmp    L37
L52:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int wildcmp(char *s, char *t) {
  int i;
  for (i = 0;; i++) {
    if (s[i] == 42)
      return (0);
    if ((s[i] == '\0') && ((t[i] == '\0') || (t[i] == '\n')))
      return (0);
    if (s[i] != text(t[i]))
      return (s[i] - t[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wildcmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  cmp    $0x2a,%bpl
  je     L99
  mov    %rdi,%r12
  mov    %rsi,%rbx
  jmp    L60
L31:
  movsbl (%rbx),%edi
  call   <text@plt>
  cmp    %bpl,%al
  jne    L41
  add    $0x1,%r12
  movzbl (%r12),%ebp
  add    $0x1,%rbx
  cmp    $0x2a,%bpl
  je     L72
L60:
  test   %bpl,%bpl
  jne    L31
  movzbl (%rbx),%eax
  test   %al,%al
  je     L40
  cmp    $0xa,%al
  jne    L31
L40:
  mov    $0x0,%eax
  jmp    L78
L41:
  movsbl (%r12),%eax
  movsbl (%rbx),%edx
  sub    %edx,%eax
L78:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  mov    $0x0,%eax
  jmp    L78
L99:
  mov    $0x0,%eax
  jmp    L78
```

assistant: ```c
int wildcmp(char *s, char *t) {
  int i;
  for (i = 0;; i++) {
    if (s[i] == 42)
      return (0);
    if ((s[i] == '\0') && ((t[i] == '\0') || (t[i] == '\n')))
      return (0);
    if (s[i] != text(t[i]))
      return (s[i] - t[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wildcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  cmp    $0x2a,%bl
  jne    L6
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  add    $0x1,%r12
  cmp    $0x2a,%bl
  je     L52
L6:
  movsbl (%r12),%edi
  test   %bl,%bl
  jne    L11
  test   %dil,%dil
  je     L52
  cmp    $0xa,%dil
  je     L52
L11:
  call   <text@plt>
  cmp    %bl,%al
  je     L1
  movsbl 0x0(%rbp),%eax
  movsbl (%r12),%edx
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L52:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wildcmp(char *s, char *t) {
  int i;
  for (i = 0;; i++) {
    if (s[i] == 42)
      return (0);
    if ((s[i] == '\0') && ((t[i] == '\0') || (t[i] == '\n')))
      return (0);
    if (s[i] != text(t[i]))
      return (s[i] - t[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wildcmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  cmp    $0x2a,%bl
  jne    L50
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L0:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  add    $0x1,%r12
  cmp    $0x2a,%bl
  je     L31
L50:
  movsbl (%r12),%edi
  test   %bl,%bl
  jne    L11
  test   %dil,%dil
  je     L31
  cmp    $0xa,%dil
  je     L31
L11:
  call   <text@plt>
  cmp    %bl,%al
  je     L0
  movsbl 0x0(%rbp),%eax
  movsbl (%r12),%edx
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L31:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wildcmp(char *s, char *t) {
  int i;
  for (i = 0;; i++) {
    if (s[i] == 42)
      return (0);
    if ((s[i] == '\0') && ((t[i] == '\0') || (t[i] == '\n')))
      return (0);
    if (s[i] != text(t[i]))
      return (s[i] - t[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<make_md5_salt_para>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x10,%eax
  jg     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  lea    D10(%rip),%rax
  mov    %rax,%rdx
  mov    $0x15,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D33(%rip),%rax
  jmp    L18
L1:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: string
name: unpack_data
arguments: data_tag: D16
type: string

tool: D10: $1$%s$

tool: D16: Invalid Salt, please use up to 16 random alphanumeric characters


assistant: ```c
char *make_md5_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_md5_salt_para>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L26
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L19
L26:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L6:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rcx
  lea    D22(%rip),%rdx
  mov    $0x15,%esi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D22
data_type: string

tool: D3: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D22: $1$%s$

assistant: ```c
char *make_md5_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_md5_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L6
L3:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rcx
  lea    D9(%rip),%r12
  lea    D7(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D7
data_type: string

tool: D15: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D7: $1$%s$

assistant: ```c
char *make_md5_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<make_md5_salt_para>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L17
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x10,%eax
  jle    L19
L17:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rcx
  lea    D6(%rip),%r12
  lea    D14(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string

tool: D9: Invalid Salt, please use up to 16 random alphanumeric characters


tool: D14: $1$%s$

assistant: ```c
char *make_md5_salt_para(const char *saltpara) {
  static char salt[21];
  if (saltpara && (strlen(saltpara) <= 16)) {
    snprintf(salt, sizeof(salt), "$1$%s$", saltpara);
    return salt;
  }
  printf("Invalid Salt, please use up to 16 random alphanumeric characters\n");
  exit(1);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__aeabi_unwind_cpp_pr1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L5:
  jmp    L5
```

assistant: ```c
void __aeabi_unwind_cpp_pr1(void) {
  for (;;)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__aeabi_unwind_cpp_pr1>:
  endbr64
L3:
  jmp    L3
```

assistant: ```c
void __aeabi_unwind_cpp_pr1(void) {
  for (;;)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__aeabi_unwind_cpp_pr1>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
void __aeabi_unwind_cpp_pr1(void) {
  for (;;)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__aeabi_unwind_cpp_pr1>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void __aeabi_unwind_cpp_pr1(void) {
  for (;;)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<truncate_trailing_non_slashes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L12
L33:
  subq   $0x1,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L23
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L33
  jmp    L28
L23:
  nop
L28:
  nop
  leave
  ret
```

assistant: ```c
void truncate_trailing_non_slashes(char *string) {
  size_t len = strlen(string);
  size_t pos = len;
  for (size_t i = 0; i <= len; i++) {
    pos--;
    if (string[pos] == '/') {
      break;
    } else {
      string[pos] = '\0';
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<truncate_trailing_non_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  lea    -0x2(%rbx),%rdi
L17:
  cmpb   $0x2f,(%rax)
  je     L13
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L17
L13:
  pop    %rbx
  ret
```

assistant: ```c
void truncate_trailing_non_slashes(char *string) {
  size_t len = strlen(string);
  size_t pos = len;
  for (size_t i = 0; i <= len; i++) {
    pos--;
    if (string[pos] == '/') {
      break;
    } else {
      string[pos] = '\0';
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<truncate_trailing_non_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x2(%rbx),%rdi
  lea    -0x1(%rbx,%rax,1),%rax
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmpb   $0x2f,(%rax)
  je     L5
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L17
L5:
  pop    %rbx
  ret
```

assistant: ```c
void truncate_trailing_non_slashes(char *string) {
  size_t len = strlen(string);
  size_t pos = len;
  for (size_t i = 0; i <= len; i++) {
    pos--;
    if (string[pos] == '/') {
      break;
    } else {
      string[pos] = '\0';
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<truncate_trailing_non_slashes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x2(%rbx),%rdi
  lea    -0x1(%rbx,%rax,1),%rax
  cs nopw 0x0(%rax,%rax,1)
L15:
  cmpb   $0x2f,(%rax)
  je     L16
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L15
L16:
  pop    %rbx
  ret
```

assistant: ```c
void truncate_trailing_non_slashes(char *string) {
  size_t len = strlen(string);
  size_t pos = len;
  for (size_t i = 0; i <= len; i++) {
    pos--;
    if (string[pos] == '/') {
      break;
    } else {
      string[pos] = '\0';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<recv_ni>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  jmp    L39
L31:
  mov    D14(%rip),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L39
  mov    -0x4(%rbp),%eax
  jmp    L6
L39:
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L31
  mov    -0x4(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
ssize_t recv_ni(int s, void *buf, size_t len, int flags) {
  int retval;
  while ((retval = recv(s, buf, len, flags)) < 0) {
    if (errno != EINTR)
      return retval;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<recv_ni>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%ebx
L7:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  test   %eax,%eax
  jns    L14
  mov    D9(%rip),%rcx
  mov    D7(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L7
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t recv_ni(int s, void *buf, size_t len, int flags) {
  int retval;
  while ((retval = recv(s, buf, len, flags)) < 0) {
    if (errno != EINTR)
      return retval;
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<recv_ni>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L4:
  mov    D14(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L11
L28:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  test   %eax,%eax
  js     L4
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t recv_ni(int s, void *buf, size_t len, int flags) {
  int retval;
  while ((retval = recv(s, buf, len, flags)) < 0) {
    if (errno != EINTR)
      return retval;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv_ni>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L23:
  mov    D17(%rip),%rdx
  mov    D7(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L4
L13:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  test   %eax,%eax
  js     L23
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t recv_ni(int s, void *buf, size_t len, int flags) {
  int retval;
  while ((retval = recv(s, buf, len, flags)) < 0) {
    if (errno != EINTR)
      return retval;
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x468,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x458(%rsp)
  xor    %eax,%eax
  call   <init@plt>
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <extract@plt>
  mov    %rax,%rbx
  lea    D44(%rip),%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  lea    0x70(%rsp),%r12
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  lea    D34(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rsp,%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <file@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <diff@plt>
L19:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x458(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x468,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <file@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D53
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D44
type_infered: string
name: read_data
arguments: data_tag: D34
type_infered: string
name: read_data
arguments: data_tag: D25
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string

tool: D53: Enter the location to perform Filing (Drive or any folder): 

tool: D24: %s

tool: D17: 
Now Scanning %s

tool: D44: r

tool: D34: .TMP

tool: D25: File was not previously catalogued.

tool: D23: File successfully catalogued.

assistant: ```c
void main(int argc, char *argv[]) {
  FILE *cr;
  char loc[100], *generated;
  init();
  printf("Enter the location to perform Filing (Drive or any folder): ");
  scanf("%s", loc);
  printf("\nNow Scanning %s", loc);
  generated = extract(loc);
  cr = fopen(generated, "r");
  if (!cr) {
    printf("File was not previously catalogued.\n");
    file(generated, loc);
    printf("File successfully catalogued.\n");
  } else {
    char tmpname[1000];
    strcpy(tmpname, generated);
    strcat(tmpname, ".TMP");
    file(tmpname, loc);
    diff(tmpname, generated, loc);
  }
  fclose(cr);
  free(generated);
  return;
}
```