ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L14
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(const int vec[], int size) {
  int tmp = 0;
  for (int i = 0; i < size; i++)
    tmp += vec[i];
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L61
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L44:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L44
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L18
L25:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L64
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L64
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
L64:
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
L61:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L25
```

assistant: ```c
int sum(const int vec[], int size) {
  int tmp = 0;
  for (int i = 0; i < size; i++)
    tmp += vec[i];
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unbind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x8893,%edi
  call   <_ptrc_glBindBuffer@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool unbind() {
  _ptrc_glBindBuffer(0x8893, 0);
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unbind>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x8893,%edi
  call   <_ptrc_glBindBuffer@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool unbind() {
  _ptrc_glBindBuffer(0x8893, 0);
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<unbind>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x8893,%edi
  call   <_ptrc_glBindBuffer@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool unbind() {
  _ptrc_glBindBuffer(0x8893, 0);
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unbind>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x8893,%edi
  call   <_ptrc_glBindBuffer@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool unbind() {
  _ptrc_glBindBuffer(0x8893, 0);
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<process_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    $0xdd,%eax
  jne    L5
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <read_cycle_stat@plt>
  jmp    L9
L5:
  lea    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
L9:
  nop
  leave
  ret
```

assistant: ```c
void process_input(int fd, uint8_t val) {
  switch (val) {
  case 0xDD:
    read_cycle_stat(fd);
    break;
  default:
    write(1, &val, 1);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_input>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    $0xdd,%esi
  je     L11
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
L5:
  add    $0x18,%rsp
  ret
L11:
  call   <read_cycle_stat@plt>
  jmp    L5
```

assistant: ```c
void process_input(int fd, uint8_t val) {
  switch (val) {
  case 0xDD:
    read_cycle_stat(fd);
    break;
  default:
    write(1, &val, 1);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<process_input>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    $0xdd,%esi
  je     L8
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L8:
  call   <read_cycle_stat@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void process_input(int fd, uint8_t val) {
  switch (val) {
  case 0xDD:
    read_cycle_stat(fd);
    break;
  default:
    write(1, &val, 1);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<process_input>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    $0xdd,%esi
  je     L7
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L7:
  call   <read_cycle_stat@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void process_input(int fd, uint8_t val) {
  switch (val) {
  case 0xDD:
    read_cycle_stat(fd);
    break;
  default:
    write(1, &val, 1);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<retmaior>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L12
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int retmaior(int *a, int *b) {
  int *tmp;
  if (*a > *b)
    return *a;
  else {
    *tmp = *a;
    *a = *b;
    *b = *tmp;
    return *b;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<retmaior>:
  endbr64
  mov    (%rdi),%eax
  cmp    (%rsi),%eax
  jg     L8
  mov    $0x0,%edx
  mov    %eax,(%rdx)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rdx),%eax
  mov    %eax,(%rsi)
L8:
  ret
```

assistant: ```c
int retmaior(int *a, int *b) {
  int *tmp;
  if (*a > *b)
    return *a;
  else {
    *tmp = *a;
    *a = *b;
    *b = *tmp;
    return *b;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<retmaior>:
  endbr64
  mov    (%rdi),%eax
  cmp    (%rsi),%eax
  jg     L4
  xor    %edx,%edx
  mov    %eax,(%rdx)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rdx),%eax
  mov    %eax,(%rsi)
L4:
  ret
```

assistant: ```c
int retmaior(int *a, int *b) {
  int *tmp;
  if (*a > *b)
    return *a;
  else {
    *tmp = *a;
    *a = *b;
    *b = *tmp;
    return *b;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<retmaior>:
  endbr64
  mov    (%rdi),%eax
  cmp    (%rsi),%eax
  jg     L8
  xor    %edx,%edx
  mov    %eax,(%rdx)
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rdx),%eax
  mov    %eax,(%rsi)
L8:
  ret
```

assistant: ```c
int retmaior(int *a, int *b) {
  int *tmp;
  if (*a > *b)
    return *a;
  else {
    *tmp = *a;
    *a = *b;
    *b = *tmp;
    return *b;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scan_white>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L1
L29:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L29
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L29
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *scan_white(char *src) {
  while (*src == ' ' || *src == '\t')
    src++;
  return src;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<scan_white>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L8
  cmp    $0x9,%dl
  jne    L31
L8:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L8
  cmp    $0x9,%dl
  je     L8
L31:
  ret
```

assistant: ```c
char *scan_white(char *src) {
  while (*src == ' ' || *src == '\t')
    src++;
  return src;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scan_white>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L14
  nop
L3:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L3
L14:
  cmp    $0x9,%dl
  je     L3
  ret
```

assistant: ```c
char *scan_white(char *src) {
  while (*src == ' ' || *src == '\t')
    src++;
  return src;
}
```
user: What is the c source code of the assembly code below:

```asm
<scan_white>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L7
  nop
L22:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L22
L7:
  cmp    $0x9,%dl
  je     L22
  ret
```

assistant: ```c
char *scan_white(char *src) {
  while (*src == ' ' || *src == '\t')
    src++;
  return src;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  cmpb   $0x0,-0xa(%rbp)
  je     L8
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L49
L44:
  movzbl -0x9(%rbp),%eax
  cmp    -0xa(%rbp),%al
  jne    L4
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L4
  subq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
L49:
  leave
  ret
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  c = *find++;
  if (c != 0) {
    len = strlen(find);
    do {
      do {
        sc = *s++;
        if (sc == 0)
          return NULL;
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return (char *)s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  je     L65
  lea    0x1(%rsi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  lea    0x1(%rbp),%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%ebp
  jmp    L65
L55:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L62
L7:
  lea    -0x1(%rbx),%rbp
  cmp    %al,%r12b
  jne    L55
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L55
  jmp    L65
L62:
  mov    $0x0,%ebp
L65:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  c = *find++;
  if (c != 0) {
    len = strlen(find);
    do {
      do {
        sc = *s++;
        if (sc == 0)
          return NULL;
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return (char *)s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L21
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L48
  nopl   0x0(%rax)
L13:
  xor    %r12d,%r12d
L21:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L21
  nopl   0x0(%rax,%rax,1)
L47:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L13
L48:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L47
  jmp    L45
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  c = *find++;
  if (c != 0) {
    len = strlen(find);
    do {
      do {
        sc = *s++;
        if (sc == 0)
          return NULL;
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return (char *)s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L4
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L18
  nopl   0x0(%rax)
L58:
  xor    %r12d,%r12d
L4:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L4
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L58
L18:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L16
  jmp    L26
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  c = *find++;
  if (c != 0) {
    len = strlen(find);
    do {
      do {
        sc = *s++;
        if (sc == 0)
          return NULL;
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return (char *)s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x31(%rbp),%eax
  add    $0x61,%eax
  mov    %al,-0x30(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(void) {
  char s[27];
  char t;
  s[0] = 'a' + t;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[27];
  char t;
  s[0] = 'a' + t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[27];
  char t;
  s[0] = 'a' + t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[27];
  char t;
  s[0] = 'a' + t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<time_eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jne    L2
  mov    $0x1,%eax
  jmp    L11
L2:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int time_eq(struct timespec *a, struct timespec *b) {
  if ((a->tv_sec == b->tv_sec) && (a->tv_nsec == b->tv_nsec))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<time_eq>:
  endbr64
  mov    $0x0,%eax
  mov    (%rsi),%rdx
  cmp    %rdx,(%rdi)
  je     L0
L3:
  ret
L0:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

assistant: ```c
int time_eq(struct timespec *a, struct timespec *b) {
  if ((a->tv_sec == b->tv_sec) && (a->tv_nsec == b->tv_nsec))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<time_eq>:
  endbr64
  mov    (%rsi),%rdx
  xor    %eax,%eax
  cmp    %rdx,(%rdi)
  je     L0
  ret
  nop
L0:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int time_eq(struct timespec *a, struct timespec *b) {
  if ((a->tv_sec == b->tv_sec) && (a->tv_nsec == b->tv_nsec))
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<time_eq>:
  endbr64
  mov    (%rsi),%rdx
  xor    %eax,%eax
  cmp    %rdx,(%rdi)
  je     L5
  ret
  nop
L5:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int time_eq(struct timespec *a, struct timespec *b) {
  if ((a->tv_sec == b->tv_sec) && (a->tv_nsec == b->tv_nsec))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init_demo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%edi
  call   <LED_INIT@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_demo(void) {
  LED_INIT(2);
  {};
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_demo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <LED_INIT@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_demo(void) {
  LED_INIT(2);
  {};
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init_demo>:
  endbr64
  mov    $0x2,%edi
  jmp    1050 <LED_INIT@plt>
```

assistant: ```c
void init_demo(void) {
  LED_INIT(2);
  {};
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_demo>:
  endbr64
  mov    $0x2,%edi
  jmp    1050 <LED_INIT@plt>
```

assistant: ```c
void init_demo(void) {
  LED_INIT(2);
  {};
}
```
user: What is the c source code of the assembly code below:

```asm
<ho_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L23
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  jmp    L29
L26:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
char *ho_strchr(const char *s, int c) {
  for (; *s; ++s) {
    if (*s == c)
      return (char *)s;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ho_strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
L21:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L12
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L21
  mov    $0x0,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
L12:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ho_strchr(const char *s, int c) {
  for (; *s; ++s) {
    if (*s == c)
      return (char *)s;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ho_strchr>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    %esi,%edx
  je     L16
  add    $0x1,%rdi
L13:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ho_strchr(const char *s, int c) {
  for (; *s; ++s) {
    if (*s == c)
      return (char *)s;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ho_strchr>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    %esi,%edx
  je     L5
  add    $0x1,%rdi
L10:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ho_strchr(const char *s, int c) {
  for (; *s; ++s) {
    if (*s == c)
      return (char *)s;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_regular_polygon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  movss  %xmm0,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x30(%rbp),%xmm1
  movsd  D37(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x34(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  mov    0x18(%rbp),%rax
  mov    0x10(%rbp),%r8d
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x30(%rbp),%edx
  mov    0x18(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L1
L0:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mov    -0x2c(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mov    -0x2c(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    0x18(%rbp),%rax
  lea    D30(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  mov    0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D37
datatype: byte[8]
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D30
datatype: string

tool: {"D37": [0xea,0x2e,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D25: %d %d %d


tool: D21: %d


tool: D30: %d %d 

assistant: ```c
void write_regular_polygon(int x0, int y0, int radius, int numverts, float theta0, int r, int g, int b, FILE *f) {
  double dtheta = (2 * 3.14159265359) / numverts, theta = theta0;
  int x, y;
  fprintf(f, "%d %d %d\n", r, g, b);
  fprintf(f, "%d\n", numverts);
  for (int i = 0; i < numverts; i++) {
    x = (int)(radius * cos(theta));
    y = (int)(radius * sin(theta));
    fprintf(f, "%d %d ", x0 + x, y0 + y);
    theta += dtheta;
  }
  fprintf(f, "\n");
}
```