ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lReverse>:
  endbr64
  test   %edi,%edi
  je     L24
  mov    $0x0,%edx
  mov    $0x0,%eax
L37:
  add    %eax,%eax
  mov    %edi,%ecx
  and    $0x1,%ecx
  or     %ecx,%eax
  add    $0x1,%edx
  shr    %edi
  jne    L37
  cmp    $0x13,%edx
  jle    L28
L29:
  ret
L24:
  mov    $0x0,%edx
  mov    $0x0,%eax
L28:
  mov    $0x14,%ecx
  sub    %edx,%ecx
  shl    %cl,%eax
  jmp    L29
```

assistant: ```c
int lReverse(int fval) {
  unsigned int in = fval;
  int result = 0, cnt = 0;
  while (in) {
    result <<= 1;
    result |= in & 1;
    in >>= 1;
    cnt++;
  }
  if (cnt < 20)
    result <<= 20 - cnt;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<lReverse>:
  endbr64
  test   %edi,%edi
  je     L27
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  mov    %edi,%ecx
  add    %eax,%eax
  add    $0x1,%edx
  and    $0x1,%ecx
  or     %ecx,%eax
  shr    %edi
  jne    L16
  cmp    $0x13,%edx
  jle    L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x14,%ecx
  sub    %edx,%ecx
  shl    %cl,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int lReverse(int fval) {
  unsigned int in = fval;
  int result = 0, cnt = 0;
  while (in) {
    result <<= 1;
    result |= in & 1;
    in >>= 1;
    cnt++;
  }
  if (cnt < 20)
    result <<= 20 - cnt;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lReverse>:
  endbr64
  test   %edi,%edi
  je     L1
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  mov    %edi,%ecx
  add    %eax,%eax
  add    $0x1,%edx
  and    $0x1,%ecx
  or     %ecx,%eax
  shr    %edi
  jne    L3
  cmp    $0x13,%edx
  jle    L22
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    $0x14,%ecx
  sub    %edx,%ecx
  shl    %cl,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int lReverse(int fval) {
  unsigned int in = fval;
  int result = 0, cnt = 0;
  while (in) {
    result <<= 1;
    result |= in & 1;
    in >>= 1;
    cnt++;
  }
  if (cnt < 20)
    result <<= 20 - cnt;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rax
  lea    0x16(%rsp),%rsi
  mov    %rbx,%rdx
L115:
  movzbl (%rdx),%edi
  lea    -0x30(%rdi),%ecx
  cmp    $0x9,%cl
  ja     L67
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L115
  mov    $0x1,%esi
L113:
  movzbl 0xf(%rsp),%edx
  cmp    $0x35,%dl
  jg     L97
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x31,%cl
  je     L6
  cmp    $0x35,%dl
  jne    L1
L6:
  cmpb   $0x33,0x10(%rsp)
  mov    $0x0,%edx
  cmovge %edx,%esi
L1:
  movzbl 0x11(%rsp),%edx
  cmp    $0x2f,%dl
  jle    L78
  cmp    $0x33,%dl
  jne    L24
  cmpb   $0x32,0x12(%rsp)
  mov    $0x0,%edx
  cmovge %edx,%esi
  jmp    L24
L67:
  mov    $0x0,%esi
  jmp    L113
L97:
  mov    $0x0,%esi
  jmp    L1
L78:
  mov    $0x0,%esi
L24:
  lea    0xa(%rbx),%rdx
L59:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L59
  movsbl 0xe(%rsp),%edx
  movsbl 0xd(%rsp),%eax
  lea    (%rax,%rdx,2),%eax
  movsbl 0xf(%rsp),%edx
  lea    (%rax,%rdx,4),%edx
  movsbl 0x10(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rdx,2),%edx
  movsbl 0x11(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  movsbl 0x12(%rsp),%edx
  lea    (%rdx,%rdx,8),%edx
  add    %edx,%eax
  movsbl 0x13(%rsp),%edx
  lea    (%rax,%rdx,8),%eax
  sub    %edx,%eax
  movsbl 0x14(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%eax
  movsbl 0x15(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  movsbl 0x16(%rsp),%edx
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmovne %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D1
type: string

tool: D2: %s

tool: D1: %d

assistant: ```c
int main() {
  char s[11];
  int i, v, sum = 0;
  scanf("%s", s);
  v = 1;
  for (i = 0; i < 9; i++)
    if (s[i] < '0' || s[i] > '9') {
      v = 0;
      break;
    }
  if (s[2] > '5')
    v = 0;
  if (s[2] == '1' || s[2] == '3' || s[2] == '5')
    if (s[3] > '2')
      v = 0;
  if (s[4] < '0' && '3' > s[4])
    v = 0;
  if (s[4] == '3')
    if (s[5] > '1')
      v = 0;
  for (i = 0; i < 10; i++)
    s[i] = s[i] - 48;
  sum = s[0] * 2 + s[1] * 4 + s[2] * 8 + s[3] * 5 + s[4] * 10 + s[5] * 9 + s[6] * 7 + s[7] * 3 + s[8] * 6;
  sum = sum % 11;
  if (sum == 10)
    sum = 0;
  if (sum != s[9])
    v = 0;
  printf("%d", v);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rax
  lea    0x16(%rsp),%rsi
  mov    %rbx,%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rdx),%edi
  lea    -0x30(%rdi),%ecx
  cmp    $0x9,%cl
  ja     L16
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L7
  mov    $0x1,%esi
L103:
  movzbl 0xf(%rsp),%edx
  cmp    $0x35,%dl
  jg     L72
  mov    %edx,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x31,%cl
  jne    L85
L109:
  xor    %edx,%edx
  cmpb   $0x33,0x10(%rsp)
  cmovge %edx,%esi
L113:
  movzbl 0x11(%rsp),%edx
  cmp    $0x2f,%dl
  jle    L37
  cmp    $0x33,%dl
  jne    L28
  xor    %edx,%edx
  cmpb   $0x32,0x12(%rsp)
  cmovge %edx,%esi
L28:
  lea    0xa(%rbx),%rdx
  nopl   0x0(%rax)
L4:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
  movsbl 0xe(%rsp),%edx
  movsbl 0xd(%rsp),%eax
  lea    D9(%rip),%rdi
  lea    (%rax,%rdx,2),%eax
  movsbl 0xf(%rsp),%edx
  lea    (%rax,%rdx,4),%edx
  movsbl 0x10(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rdx,2),%edx
  movsbl 0x11(%rsp),%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  movsbl 0x12(%rsp),%edx
  lea    (%rdx,%rdx,8),%edx
  add    %edx,%eax
  movsbl 0x13(%rsp),%edx
  lea    (%rax,%rdx,8),%eax
  sub    %edx,%eax
  movsbl 0x14(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%eax
  movsbl 0x15(%rsp),%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rax,%rdx,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  movsbl 0x16(%rsp),%ecx
  cmp    $0xa,%eax
  cmove  %edx,%eax
  cmp    %eax,%ecx
  cmovne %edx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L37:
  xor    %esi,%esi
  jmp    L28
L72:
  xor    %esi,%esi
  jmp    L113
L16:
  xor    %esi,%esi
  jmp    L103
L85:
  cmp    $0x35,%dl
  je     L109
  jmp    L113
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D5: %s

tool: D9: %d

assistant: ```c
int main() {
  char s[11];
  int i, v, sum = 0;
  scanf("%s", s);
  v = 1;
  for (i = 0; i < 9; i++)
    if (s[i] < '0' || s[i] > '9') {
      v = 0;
      break;
    }
  if (s[2] > '5')
    v = 0;
  if (s[2] == '1' || s[2] == '3' || s[2] == '5')
    if (s[3] > '2')
      v = 0;
  if (s[4] < '0' && '3' > s[4])
    v = 0;
  if (s[4] == '3')
    if (s[5] > '1')
      v = 0;
  for (i = 0; i < 10; i++)
    s[i] = s[i] - 48;
  sum = s[0] * 2 + s[1] * 4 + s[2] * 8 + s[3] * 5 + s[4] * 10 + s[5] * 9 + s[6] * 7 + s[7] * 3 + s[8] * 6;
  sum = sum % 11;
  if (sum == 10)
    sum = 0;
  if (sum != s[9])
    v = 0;
  printf("%d", v);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SDL_imageFilterSub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  mov    $0x0,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  test   %rax,%rax
  je     L2
  cmpl   $0x7,-0x4c(%rbp)
  jle    L2
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <SDL_imageFilterSubMMX@plt>
  mov    -0x4c(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jle    L73
  mov    -0x4c(%rbp),%eax
  and    $0xfffffff8,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L73:
  mov    $0x0,%eax
  jmp    L77
L2:
  movl   $0x0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L34:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L43
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L19
  movl   $0x0,-0x1c(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x24(%rbp)
L43:
  mov    -0x4c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jb     L36
  mov    $0x0,%eax
L77:
  leave
  ret
```

assistant: ```c
int SDL_imageFilterSub(unsigned char *Src1, unsigned char *Src2, unsigned char *Dest, int length) {
  unsigned int i, istart;
  unsigned char *cursrc1, *cursrc2, *curdst;
  int result;
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterSubMMX(Src1, Src2, Dest, length);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      cursrc2 = &Src2[istart];
      curdst = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    cursrc2 = Src2;
    curdst = Dest;
  }
  for (i = istart; i < length; i++) {
    result = (int)*cursrc1 - (int)*cursrc2;
    if (result < 0)
      result = 0;
    *curdst = (unsigned char)result;
    cursrc1++;
    cursrc2++;
    curdst++;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDL_imageFilterSub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    $0x0,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  cmp    $0x7,%r13d
  jle    L56
  test   %rax,%rax
  jne    L35
L56:
  mov    $0x0,%eax
L51:
  cmp    %r13d,%eax
  jae    L25
  lea    -0x1(%r13),%esi
  sub    %eax,%esi
  mov    $0x0,%edx
L37:
  movzbl (%rbx,%rdx,1),%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  sub    %ecx,%eax
  mov    $0x0,%ecx
  cmovs  %ecx,%eax
  mov    %al,(%r12,%rdx,1)
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L37
L25:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <SDL_imageFilterSubMMX@plt>
  test   $0x7,%r13b
  je     L25
  mov    %r13d,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%edx
  add    %rdx,%rbx
  add    %rdx,%rbp
  add    %rdx,%r12
  jmp    L51
```

assistant: ```c
int SDL_imageFilterSub(unsigned char *Src1, unsigned char *Src2, unsigned char *Dest, int length) {
  unsigned int i, istart;
  unsigned char *cursrc1, *cursrc2, *curdst;
  int result;
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterSubMMX(Src1, Src2, Dest, length);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      cursrc2 = &Src2[istart];
      curdst = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    cursrc2 = Src2;
    curdst = Dest;
  }
  for (i = istart; i < length; i++) {
    result = (int)*cursrc1 - (int)*cursrc2;
    if (result < 0)
      result = 0;
    *curdst = (unsigned char)result;
    cursrc1++;
    cursrc2++;
    curdst++;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDL_imageFilterSub>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <SDL_imageFilterMMXdetect@plt>
  test   %rax,%rax
  je     L53
  cmp    $0x7,%ebx
  jg     L12
L53:
  xor    %eax,%eax
L29:
  cmp    %ebx,%eax
  jae    L4
  lea    -0x1(%rbx),%ecx
  xor    %edx,%edx
  sub    %eax,%ecx
  nopw   0x0(%rax,%rax,1)
L52:
  movzbl (%r12,%rdx,1),%esi
  movzbl 0x0(%rbp,%rdx,1),%eax
  sub    %esi,%eax
  mov    $0x0,%esi
  cmovs  %esi,%eax
  mov    %al,0x0(%r13,%rdx,1)
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L52
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SDL_imageFilterSubMMX@plt>
  test   $0x7,%bl
  je     L4
  mov    %ebx,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%edx
  add    %rdx,%rbp
  add    %rdx,%r12
  add    %rdx,%r13
  jmp    L29
```

assistant: ```c
int SDL_imageFilterSub(unsigned char *Src1, unsigned char *Src2, unsigned char *Dest, int length) {
  unsigned int i, istart;
  unsigned char *cursrc1, *cursrc2, *curdst;
  int result;
  if ((SDL_imageFilterMMXdetect()) && (length > 7)) {
    SDL_imageFilterSubMMX(Src1, Src2, Dest, length);
    if ((length & 7) > 0) {
      istart = length & 0xfffffff8;
      cursrc1 = &Src1[istart];
      cursrc2 = &Src2[istart];
      curdst = &Dest[istart];
    } else {
      return (0);
    }
  } else {
    istart = 0;
    cursrc1 = Src1;
    cursrc2 = Src2;
    curdst = Dest;
  }
  for (i = istart; i < length; i++) {
    result = (int)*cursrc1 - (int)*cursrc2;
    if (result < 0)
      result = 0;
    *curdst = (unsigned char)result;
    cursrc1++;
    cursrc2++;
    curdst++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<load1r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x320,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x324,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x328,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x32c,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int load1r(int *array) {
  int a = 0;
  a += array[200];
  a += array[201];
  a += array[202];
  a += array[203];
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<load1r>:
  endbr64
  mov    0x324(%rdi),%eax
  add    0x320(%rdi),%eax
  add    0x328(%rdi),%eax
  add    0x32c(%rdi),%eax
  ret
```

assistant: ```c
int load1r(int *array) {
  int a = 0;
  a += array[200];
  a += array[201];
  a += array[202];
  a += array[203];
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<load1r>:
  endbr64
  mov    0x324(%rdi),%eax
  add    0x320(%rdi),%eax
  add    0x328(%rdi),%eax
  add    0x32c(%rdi),%eax
  ret
```

assistant: ```c
int load1r(int *array) {
  int a = 0;
  a += array[200];
  a += array[201];
  a += array[202];
  a += array[203];
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<load1r>:
  endbr64
  mov    0x324(%rdi),%eax
  add    0x320(%rdi),%eax
  add    0x328(%rdi),%eax
  add    0x32c(%rdi),%eax
  ret
```

assistant: ```c
int load1r(int *array) {
  int a = 0;
  a += array[200];
  a += array[201];
  a += array[202];
  a += array[203];
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<make_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    -0x18(%rbp),%rax
  mov    $0x1c0,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L0:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int make_dir(char *dirname) {
  struct stat st = {0};
  if (-1 == stat(dirname, &st))
    mkdir(dirname, 0700);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<make_dir>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L26
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  mov    $0x1c0,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  jmp    L7
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_dir(char *dirname) {
  struct stat st = {0};
  if (-1 == stat(dirname, &st))
    mkdir(dirname, 0700);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<make_dir>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L11
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1c0,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L1
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_dir(char *dirname) {
  struct stat st = {0};
  if (-1 == stat(dirname, &st))
    mkdir(dirname, 0700);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_dir>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L28
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1c0,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L21
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_dir(char *dirname) {
  struct stat st = {0};
  if (-1 == stat(dirname, &st))
    mkdir(dirname, 0700);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SHAMD5HMACPPKeyGenerate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  nop
L48:
  mov    -0x14(%rbp),%eax
  add    $0x118,%eax
  cltq
  mov    (%rax),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L48
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  cltq
  mov    %rax,(%rdx)
  addl   $0x4,-0x4(%rbp)
L43:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L18
  mov    -0x14(%rbp),%eax
  add    $0x44,%eax
  cltq
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  add    $0x44,%edx
  movslq %edx,%rdx
  or     $0x20,%rax
  mov    %rax,(%rdx)
  mov    -0x14(%rbp),%eax
  add    $0x48,%eax
  cltq
  movq   $0x0,(%rax)
  nop
L49:
  mov    -0x14(%rbp),%eax
  add    $0x118,%eax
  cltq
  mov    (%rax),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L49
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L26:
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addl   $0x4,-0x4(%rbp)
L25:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5HMACPPKeyGenerate(uint32_t ui32Base, uint8_t *pui8Key, uint8_t *pui8PPKey) {
  uint32_t ui32Index;
  ;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000008) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index))) = *((uint32_t *)(pui8Key + ui32Index));
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000044))) |= 0x00000020;
  (*((volatile unsigned long *)(ui32Base + 0x00000048))) = 0;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000001) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    *((uint32_t *)(pui8PPKey + ui32Index)) = (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SHAMD5HMACPPKeyGenerate>:
  endbr64
  mov    %edi,%r10d
  mov    %rdx,%r9
  lea    0x118(%rdi),%edi
  movslq %edi,%rdi
L11:
  mov    (%rdi),%rax
  test   $0x8,%al
  je     L11
  movslq %r10d,%rax
  lea    0x40(%rax),%rcx
  mov    %rax,%r11
  neg    %r11
  shl    $0x2,%r11
  lea    (%rsi,%r11,1),%r8
  mov    %rax,%rdx
L18:
  movslq (%r8,%rdx,4),%rsi
  mov    %rsi,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L18
  lea    0x44(%r10),%edx
  movslq %edx,%rdx
  mov    (%rdx),%rsi
  or     $0x20,%rsi
  mov    %rsi,(%rdx)
  add    $0x48,%r10d
  movslq %r10d,%r10
  movq   $0x0,(%r10)
L35:
  mov    (%rdi),%rdx
  test   $0x1,%dl
  je     L35
  lea    (%r9,%r11,1),%rsi
L30:
  mov    (%rax),%rdx
  mov    %edx,(%rsi,%rax,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L30
  ret
```

assistant: ```c
void SHAMD5HMACPPKeyGenerate(uint32_t ui32Base, uint8_t *pui8Key, uint8_t *pui8PPKey) {
  uint32_t ui32Index;
  ;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000008) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index))) = *((uint32_t *)(pui8Key + ui32Index));
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000044))) |= 0x00000020;
  (*((volatile unsigned long *)(ui32Base + 0x00000048))) = 0;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000001) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    *((uint32_t *)(pui8PPKey + ui32Index)) = (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index)));
  }
}
```