ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L24
  lea    D20(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L24:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xb7db3449,%esi
  je     L1
L4:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L4
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string

tool: D20: Call this program with %i arguments


tool: D4: %u


tool: D23: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3084596297U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L33
  lea    D22(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L33:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xb7db3449,%esi
  je     L11
L26:
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L26
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D22: Call this program with %i arguments


tool: D25: %u


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3084596297U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_string_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <safe_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_string_copy(const char *original) {
  size_t size;
  char *copy;
  size = strlen(original) + 1;
  copy = safe_malloc(size);
  memcpy(copy, original, size);
  return (copy);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_string_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <safe_malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_string_copy(const char *original) {
  size_t size;
  char *copy;
  size = strlen(original) + 1;
  copy = safe_malloc(size);
  memcpy(copy, original, size);
  return (copy);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_string_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <safe_malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_string_copy(const char *original) {
  size_t size;
  char *copy;
  size = strlen(original) + 1;
  copy = safe_malloc(size);
  memcpy(copy, original, size);
  return (copy);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_string_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <safe_malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_string_copy(const char *original) {
  size_t size;
  char *copy;
  size = strlen(original) + 1;
  copy = safe_malloc(size);
  memcpy(copy, original, size);
  return (copy);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lrtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x28(%rbp),%rax
  jmp    L38
L33:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L79
L2:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L79:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L94
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jbe    L2
L94:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L29
L35:
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L76
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jbe    L35
L76:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L90
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L59
L51:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L59:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L90:
  mov    -0x28(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
char *lrtrim(char *buff) {
  char *c;
  if (buff[0] == '\0')
    return buff;
  c = buff + strlen(buff);
  while ((c >= buff) && ((unsigned char)*c <= ' '))
    *c-- = '\0';
  c = buff;
  while ((*c != '\0') && ((unsigned char)*c <= ' '))
    c++;
  if (c != buff) {
    char *src = c;
    char *dst = buff;
    while (*src)
      *dst++ = *src++;
    *dst = '\0';
  }
  return buff;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lrtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L32
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
L32:
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jb     L45
L55:
  cmpb   $0x20,(%rax)
  ja     L45
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%rbx
  jbe    L55
L45:
  movzbl (%rbx),%eax
  lea    -0x1(%rax),%edx
  mov    %rbx,%rax
  cmp    $0x1f,%dl
  ja     L3
L97:
  add    $0x1,%rax
  movzbl (%rax),%esi
  lea    -0x1(%rsi),%edx
  cmp    $0x1f,%dl
  jbe    L97
  cmp    %rax,%rbx
  je     L3
  mov    %esi,%ecx
  test   %sil,%sil
  je     L75
  mov    %rbx,%rdx
L105:
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L105
L93:
  movb   $0x0,(%rdx)
  jmp    L3
L75:
  mov    %rbx,%rdx
  jmp    L93
```

assistant: ```c
char *lrtrim(char *buff) {
  char *c;
  if (buff[0] == '\0')
    return buff;
  c = buff + strlen(buff);
  while ((c >= buff) && ((unsigned char)*c <= ' '))
    *c-- = '\0';
  c = buff;
  while ((*c != '\0') && ((unsigned char)*c <= ' '))
    c++;
  if (c != buff) {
    char *src = c;
    char *dst = buff;
    while (*src)
      *dst++ = *src++;
    *dst = '\0';
  }
  return buff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lrtrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  mov    %rdi,%r12
  jne    L21
L88:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jae    L57
  jmp    L75
  cs nopw 0x0(%rax,%rax,1)
L73:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%r12
  ja     L75
L57:
  cmpb   $0x20,(%rax)
  jbe    L73
L75:
  movzbl (%r12),%eax
  lea    -0x1(%rax),%edx
  mov    %r12,%rax
  cmp    $0x1f,%dl
  ja     L88
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x1(%rdx),%ecx
  cmp    $0x1f,%cl
  jbe    L6
  cmp    %rax,%r12
  je     L88
  mov    %r12,%rcx
  test   %dl,%dl
  je     L70
  nopl   0x0(%rax)
L59:
  add    $0x1,%rax
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L59
L70:
  mov    %r12,%rax
  movb   $0x0,(%rcx)
  pop    %r12
  ret
```

assistant: ```c
char *lrtrim(char *buff) {
  char *c;
  if (buff[0] == '\0')
    return buff;
  c = buff + strlen(buff);
  while ((c >= buff) && ((unsigned char)*c <= ' '))
    *c-- = '\0';
  c = buff;
  while ((*c != '\0') && ((unsigned char)*c <= ' '))
    c++;
  if (c != buff) {
    char *src = c;
    char *dst = buff;
    while (*src)
      *dst++ = *src++;
    *dst = '\0';
  }
  return buff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lrtrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  push   %r12
  mov    %rdi,%r12
  jne    L62
L14:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L62:
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jae    L57
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L92:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%r12
  ja     L52
L57:
  cmpb   $0x20,(%rax)
  jbe    L92
L52:
  movzbl (%r12),%eax
  lea    -0x1(%rax),%edx
  mov    %r12,%rax
  cmp    $0x1f,%dl
  ja     L14
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  lea    -0x1(%rdx),%ecx
  cmp    $0x1f,%cl
  jbe    L38
  cmp    %rax,%r12
  je     L14
  mov    %r12,%rcx
  test   %dl,%dl
  je     L68
  nopl   0x0(%rax)
L90:
  add    $0x1,%rax
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L90
L68:
  mov    %r12,%rax
  movb   $0x0,(%rcx)
  pop    %r12
  ret
```

assistant: ```c
char *lrtrim(char *buff) {
  char *c;
  if (buff[0] == '\0')
    return buff;
  c = buff + strlen(buff);
  while ((c >= buff) && ((unsigned char)*c <= ' '))
    *c-- = '\0';
  c = buff;
  while ((*c != '\0') && ((unsigned char)*c <= ' '))
    c++;
  if (c != buff) {
    char *src = c;
    char *dst = buff;
    while (*src)
      *dst++ = *src++;
    *dst = '\0';
  }
  return buff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_ResizeRequest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5:     width %d, height %d


assistant: ```c
void do_ResizeRequest(XEvent *eventp) {
  XResizeRequestEvent *e = (XResizeRequestEvent *)eventp;
  printf("    width %d, height %d\n", e->width, e->height);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_ResizeRequest>:
  endbr64
  sub    $0x8,%rsp
  mov    0x4(%rdi),%edx
  mov    (%rdi),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9:     width %d, height %d


assistant: ```c
void do_ResizeRequest(XEvent *eventp) {
  XResizeRequestEvent *e = (XResizeRequestEvent *)eventp;
  printf("    width %d, height %d\n", e->width, e->height);
}
```
user: What is the c source code of the assembly code below?

```asm
<do_ResizeRequest>:
  endbr64
  mov    0x4(%rdi),%edx
  mov    (%rdi),%esi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0:     width %d, height %d


assistant: ```c
void do_ResizeRequest(XEvent *eventp) {
  XResizeRequestEvent *e = (XResizeRequestEvent *)eventp;
  printf("    width %d, height %d\n", e->width, e->height);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_ResizeRequest>:
  endbr64
  mov    0x4(%rdi),%edx
  mov    (%rdi),%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2:     width %d, height %d


assistant: ```c
void do_ResizeRequest(XEvent *eventp) {
  XResizeRequestEvent *e = (XResizeRequestEvent *)eventp;
  printf("    width %d, height %d\n", e->width, e->height);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<testandset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    $0x1,%eax
  mov    -0x18(%rbp),%rdx
  xchg   %eax,(%rcx)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
extern int testandset(int *spinlock) {
  int ret;
  __asm__ __volatile__("xchgl %0, %1" : "=r"(ret), "=m"(*spinlock) : "0"(1), "m"(*spinlock) : "memory");
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testandset>:
  endbr64
  mov    $0x1,%eax
  xchg   %eax,(%rdi)
  ret
```

assistant: ```c
extern int testandset(int *spinlock) {
  int ret;
  __asm__ __volatile__("xchgl %0, %1" : "=r"(ret), "=m"(*spinlock) : "0"(1), "m"(*spinlock) : "memory");
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testandset>:
  endbr64
  mov    $0x1,%eax
  xchg   %eax,(%rdi)
  ret
```

assistant: ```c
extern int testandset(int *spinlock) {
  int ret;
  __asm__ __volatile__("xchgl %0, %1" : "=r"(ret), "=m"(*spinlock) : "0"(1), "m"(*spinlock) : "memory");
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generate_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *generate_array(int size, int max) {
  int *array;
  int i;
  srand(time(NULL));
  array = malloc(sizeof(int) * size);
  for (i = 0; i < size; i++)
    array[i] = rand() % max;
  return array;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<generate_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L11
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,4),%r12
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L9
L11:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *generate_array(int size, int max) {
  int *array;
  int i;
  srand(time(NULL));
  array = malloc(sizeof(int) * size);
  for (i = 0; i < size; i++)
    array[i] = rand() % max;
  return array;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L15
  mov    %rax,%rbx
  lea    (%rax,%r12,4),%r12
  nopl   (%rax)
L1:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L1
L15:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *generate_array(int size, int max) {
  int *array;
  int i;
  srand(time(NULL));
  array = malloc(sizeof(int) * size);
  for (i = 0; i < size; i++)
    array[i] = rand() % max;
  return array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<generate_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L6
  mov    %rax,%rbx
  lea    (%rax,%r12,4),%r12
  nopl   (%rax)
L15:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L15
L6:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *generate_array(int size, int max) {
  int *array;
  int i;
  srand(time(NULL));
  array = malloc(sizeof(int) * size);
  for (i = 0; i < size; i++)
    array[i] = rand() % max;
  return array;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timeval_percentage_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tv_to_usec@plt>
  imul   $0x2710,%eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <tv_to_usec@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L23
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L29
L23:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L29:
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0x34(%rbp),%eax
  test   %rax,%rax
  js     L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L16
L4:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L16:
  movsd  D8(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: f64

tool: D8: 100

assistant: ```c
float timeval_percentage_of(const struct timeval *value, const struct timeval *from, unsigned int divider) {
  unsigned long long v;
  float p;
  v = (100 * 100 * tv_to_usec(value)) / tv_to_usec(from);
  p = (float)v / (100.0 * divider);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timeval_percentage_of>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  call   <tv_to_usec@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <tv_to_usec@plt>
  mov    %eax,%ecx
  imul   $0x2710,%ebx,%eax
  cltd
  idiv   %ecx
  cltq
  test   %rax,%rax
  js     L14
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
L19:
  cvtss2sd %xmm0,%xmm0
  mov    %ebp,%ebp
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbp,%xmm1
  mulsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: f64

tool: D3: 100

assistant: ```c
float timeval_percentage_of(const struct timeval *value, const struct timeval *from, unsigned int divider) {
  unsigned long long v;
  float p;
  v = (100 * 100 * tv_to_usec(value)) / tv_to_usec(from);
  p = (float)v / (100.0 * divider);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timeval_percentage_of>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  call   <tv_to_usec@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <tv_to_usec@plt>
  mov    %eax,%r8d
  imul   $0x2710,%ebx,%eax
  cltd
  idiv   %r8d
  cltq
  test   %rax,%rax
  js     L15
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
L16:
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %rbp,%xmm1
  mulsd  D8(%rip),%xmm1
  pop    %rbp
  pop    %r12
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: f64

tool: D8: 100

assistant: ```c
float timeval_percentage_of(const struct timeval *value, const struct timeval *from, unsigned int divider) {
  unsigned long long v;
  float p;
  v = (100 * 100 * tv_to_usec(value)) / tv_to_usec(from);
  p = (float)v / (100.0 * divider);
  return p;
}
```