ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffff9c,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0xffffff9c,-0x4(%rbp)
  jmp    L29
L20:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x3,-0xc(%rbp)
  addl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L29
  mov    $0x0,%eax
  call   <remove_me@plt>
L29:
  cmpl   $0x0,-0x10(%rbp)
  jne    L20
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int a = -100;
  int b = 2;
  int d = -1;
  int e = -100;
  while (a) {
    a = a + b;
    b = b + 3;
    d = d + 3;
    e = e + d;
    if (a != e)
      remove_me();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  mov    $0xffffff9e,%edx
  mov    $0xffffff9e,%eax
  jmp    L1
L19:
  mov    $0x0,%eax
  call   <remove_me@plt>
L24:
  add    $0x3,%ebx
  mov    %r12d,%edx
  mov    %ebp,%eax
L1:
  test   %eax,%eax
  je     L11
  lea    (%rax,%rbx,1),%ebp
  lea    (%rbx,%rdx,1),%r12d
  cmp    %edx,%eax
  jne    L19
  jmp    L24
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int a = -100;
  int b = 2;
  int d = -1;
  int e = -100;
  while (a) {
    a = a + b;
    b = b + 3;
    d = d + 3;
    e = e + d;
    if (a != e)
      remove_me();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff9e,%edx
  mov    $0xffffff9e,%eax
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  jmp    L4
  nopl   0x0(%rax)
L19:
  lea    (%rbx,%rax,1),%ebp
  lea    (%rdx,%rbx,1),%r12d
  cmp    %eax,%edx
  je     L28
  xor    %eax,%eax
  call   <remove_me@plt>
L28:
  add    $0x3,%ebx
  mov    %r12d,%edx
  mov    %ebp,%eax
L4:
  test   %eax,%eax
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int a = -100;
  int b = 2;
  int d = -1;
  int e = -100;
  while (a) {
    a = a + b;
    b = b + 3;
    d = d + 3;
    e = e + d;
    if (a != e)
      remove_me();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff9e,%edx
  mov    $0xffffff9e,%eax
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  jmp    L35
  nopl   0x0(%rax)
L27:
  xor    %eax,%eax
  add    $0x3,%ebx
  call   <remove_me@plt>
  test   %ebp,%ebp
  je     L11
L24:
  mov    %ebp,%edx
  mov    %r12d,%eax
L35:
  lea    (%rbx,%rdx,1),%ebp
  lea    (%rbx,%rax,1),%r12d
  cmp    %eax,%edx
  jne    L27
  add    $0x3,%ebx
  test   %ebp,%ebp
  jne    L24
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int a = -100;
  int b = 2;
  int d = -1;
  int e = -100;
  while (a) {
    a = a + b;
    b = b + 3;
    d = d + 3;
    e = e + d;
    if (a != e)
      remove_me();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L18
L16:
  movq   $0x0,-0x8(%rbp)
  movabs $0xf800000000000000,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  shlq   $0x5,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x3b,%rax
  xor    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t hash(char *key) {
  uint64_t h = 0;
  for (uint64_t i = 0; key[i] != '\0'; i++) {
    uint64_t hb = 0;
    hb = h & 0xf800000000000000;
    h = h << 5;
    h = h ^ (hb >> 59);
    h = h ^ key[i];
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  add    $0x1,%rdi
  mov    $0x0,%eax
L5:
  rol    $0x5,%rax
  movsbq %dl,%rdx
  xor    %rdx,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L5
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint64_t hash(char *key) {
  uint64_t h = 0;
  for (uint64_t i = 0; key[i] != '\0'; i++) {
    uint64_t hb = 0;
    hb = h & 0xf800000000000000;
    h = h << 5;
    h = h ^ (hb >> 59);
    h = h ^ key[i];
  }
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  test   %dl,%dl
  je     L8
  add    $0x1,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  rol    $0x5,%rax
  add    $0x1,%rdi
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L2
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t hash(char *key) {
  uint64_t h = 0;
  for (uint64_t i = 0; key[i] != '\0'; i++) {
    uint64_t hb = 0;
    hb = h & 0xf800000000000000;
    h = h << 5;
    h = h ^ (hb >> 59);
    h = h ^ key[i];
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbq (%rdi),%rdx
  test   %dl,%dl
  je     L2
  add    $0x1,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  rol    $0x5,%rax
  add    $0x1,%rdi
  xor    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  test   %dl,%dl
  jne    L12
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t hash(char *key) {
  uint64_t h = 0;
  for (uint64_t i = 0; key[i] != '\0'; i++) {
    uint64_t hb = 0;
    hb = h & 0xf800000000000000;
    h = h << 5;
    h = h ^ (hb >> 59);
    h = h ^ key[i];
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2CStartSend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  or     $0x1,%dh
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void I2CStartSend(unsigned long ulBase) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000100;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<I2CStartSend>:
  endbr64
  mov    (%rdi),%rax
  or     $0x1,%ah
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void I2CStartSend(unsigned long ulBase) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000100;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<I2CStartSend>:
  endbr64
  mov    (%rdi),%rax
  or     $0x1,%ah
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void I2CStartSend(unsigned long ulBase) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000100;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2CStartSend>:
  endbr64
  mov    (%rdi),%rax
  or     $0x1,%ah
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void I2CStartSend(unsigned long ulBase) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000000))) |= 0x00000100;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x7,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <insertsort@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <assertorder@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <printarr@plt>
  movl   $0x1,-0x2c(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insertsort@plt>
  lea    -0x2c(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <assertorder@plt>
  lea    -0x2c(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <printarr@plt>
  movl   $0x2,-0x28(%rbp)
  movl   $0xfffffff4,-0x24(%rbp)
  lea    -0x28(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <insertsort@plt>
  lea    -0x28(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <assertorder@plt>
  lea    -0x28(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <printarr@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[6] = {1, 10, 3, 6, 4, 7};
  insertsort(arr, 6);
  assertorder(arr, 6);
  printarr(arr, 6);
  int arr1[1] = {1};
  insertsort(arr1, 1);
  assertorder(arr1, 1);
  printarr(arr1, 1);
  int arr2[2] = {2, -12};
  insertsort(arr2, 2);
  assertorder(arr2, 2);
  printarr(arr2, 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  lea    0x10(%rsp),%rbx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <insertsort@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <assertorder@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <printarr@plt>
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insertsort@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <assertorder@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printarr@plt>
  movl   $0x2,0x8(%rsp)
  movl   $0xfffffff4,0xc(%rsp)
  lea    0x8(%rsp),%rbx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <insertsort@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <assertorder@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printarr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[6] = {1, 10, 3, 6, 4, 7};
  insertsort(arr, 6);
  assertorder(arr, 6);
  printarr(arr, 6);
  int arr1[1] = {1};
  insertsort(arr1, 1);
  assertorder(arr1, 1);
  printarr(arr1, 1);
  int arr2[2] = {2, -12};
  insertsort(arr2, 2);
  assertorder(arr2, 2);
  printarr(arr2, 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xa00000001,%rax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000004,%rax
  mov    %rax,0x20(%rsp)
  call   <insertsort@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <assertorder@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  lea    0x4(%rsp),%rbp
  call   <printarr@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  movl   $0x1,0x4(%rsp)
  call   <insertsort@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <assertorder@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  lea    0x8(%rsp),%rbp
  call   <printarr@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  movabs $0xfffffff400000002,%rax
  mov    %rax,0x8(%rsp)
  call   <insertsort@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <assertorder@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printarr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int arr[6] = {1, 10, 3, 6, 4, 7};
  insertsort(arr, 6);
  assertorder(arr, 6);
  printarr(arr, 6);
  int arr1[1] = {1};
  insertsort(arr1, 1);
  assertorder(arr1, 1);
  printarr(arr1, 1);
  int arr2[2] = {2, -12};
  insertsort(arr2, 2);
  assertorder(arr2, 2);
  printarr(arr2, 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6,%esi
  sub    $0x30,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    D13(%rip),%rax
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  call   <insertsort@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <assertorder@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  lea    0x4(%rsp),%rbp
  call   <printarr@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  movl   $0x1,0x4(%rsp)
  call   <insertsort@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <assertorder@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  lea    0x8(%rsp),%rbp
  call   <printarr@plt>
  mov    D22(%rip),%rax
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  call   <insertsort@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <assertorder@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printarr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: byte[16]
name: retrieve_data
arguments: label: D13
datatype: byte[8]
name: retrieve_data
arguments: label: D22
datatype: byte[8]

tool: {"D15": [0x01,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D13": [0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D22": [0x02,0x00,0x00,0x00,0xf4,0xff,0xff,0xff]}

assistant: ```c
int main() {
  int arr[6] = {1, 10, 3, 6, 4, 7};
  insertsort(arr, 6);
  assertorder(arr, 6);
  printarr(arr, 6);
  int arr1[1] = {1};
  insertsort(arr1, 1);
  assertorder(arr1, 1);
  printarr(arr1, 1);
  int arr2[2] = {2, -12};
  insertsort(arr2, 2);
  assertorder(arr2, 2);
  printarr(arr2, 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  D74(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D20(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D26
datatype: string
name: disassemble_data
arguments: tag: D46
datatype: string
name: disassemble_data
arguments: tag: D71
datatype: string
name: disassemble_data
arguments: tag: D76
datatype: string
name: disassemble_data
arguments: tag: D74
datatype: f64
name: disassemble_data
arguments: tag: D20
datatype: byte[8]
name: disassemble_data
arguments: tag: D81
datatype: string
name: disassemble_data
arguments: tag: D65
datatype: string

tool: D26: Interest calculation program.

tool: D46: Starting balance? 

tool: D71: %lf

tool: D76: Annual interest rate percentage? 

tool: D74: 0.01

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D81: Balance after one year: %g


tool: D65: Balance after two year: %g


assistant: ```c
int main(int argc, const char *argv[]) {
  double start, rate, yearRate, year1;
  printf("Interest calculation program.\n");
  printf("Starting balance? ");
  scanf("%lf", &start);
  printf("Annual interest rate percentage? ");
  scanf("%lf", &rate);
  yearRate = (1 + 0.01 * rate);
  printf("Balance after one year: %g\n", year1 = start * yearRate);
  printf("Balance after two year: %g\n", year1 * yearRate);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  D56(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  addsd  D59(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm0,%xmm2
  mulsd  0x18(%rsp),%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  movapd %xmm1,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D43
type_infered: string
name: retrieve_data
arguments: label: D56
type_infered: f64
name: retrieve_data
arguments: label: D59
type_infered: byte[8]
name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D19
type_infered: string

tool: D24: Interest calculation program.

tool: D12: Starting balance? 

tool: D18: %lf

tool: D43: Annual interest rate percentage? 

tool: D56: 0.01

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D10: Balance after one year: %g


tool: D19: Balance after two year: %g


assistant: ```c
int main(int argc, const char *argv[]) {
  double start, rate, yearRate, year1;
  printf("Interest calculation program.\n");
  printf("Starting balance? ");
  scanf("%lf", &start);
  printf("Annual interest rate percentage? ");
  scanf("%lf", &rate);
  yearRate = (1 + 0.01 * rate);
  printf("Balance after one year: %g\n", year1 = start * yearRate);
  printf("Balance after two year: %g\n", year1 * yearRate);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D63(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  D76(%rip),%xmm1
  mulsd  0x20(%rsp),%xmm1
  lea    D62(%rip),%rdi
  addsd  D6(%rip),%xmm1
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  0x18(%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
data_type: string
name: disassemble_data
arguments: label: D63
data_type: string
name: disassemble_data
arguments: label: D71
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D76
data_type: f64
name: disassemble_data
arguments: label: D62
data_type: string
name: disassemble_data
arguments: label: D6
data_type: byte[8]
name: disassemble_data
arguments: label: D26
data_type: string

tool: D28: Interest calculation program.

tool: D63: %lf

tool: D71: Starting balance? 

tool: D11: Annual interest rate percentage? 

tool: D76: 0.01

tool: D62: Balance after one year: %g


tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D26: Balance after two year: %g


assistant: ```c
int main(int argc, const char *argv[]) {
  double start, rate, yearRate, year1;
  printf("Interest calculation program.\n");
  printf("Starting balance? ");
  scanf("%lf", &start);
  printf("Annual interest rate percentage? ");
  scanf("%lf", &rate);
  yearRate = (1 + 0.01 * rate);
  printf("Balance after one year: %g\n", year1 = start * yearRate);
  printf("Balance after two year: %g\n", year1 * yearRate);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D78(%rip),%rdi
  lea    D8(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  D31(%rip),%xmm1
  mulsd  0x20(%rsp),%xmm1
  lea    D55(%rip),%rdi
  addsd  D49(%rip),%xmm1
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  0x18(%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D78
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D76
datatype: string
name: extract_symbolic_data
arguments: data_label: D47
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: f64
name: extract_symbolic_data
arguments: data_label: D55
datatype: string
name: extract_symbolic_data
arguments: data_label: D49
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D39
datatype: string

tool: D78: Interest calculation program.

tool: D8: %lf

tool: D76: Starting balance? 

tool: D47: Annual interest rate percentage? 

tool: D31: 0.01

tool: D55: Balance after one year: %g


tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D39: Balance after two year: %g


assistant: ```c
int main(int argc, const char *argv[]) {
  double start, rate, yearRate, year1;
  printf("Interest calculation program.\n");
  printf("Starting balance? ");
  scanf("%lf", &start);
  printf("Annual interest rate percentage? ");
  scanf("%lf", &rate);
  yearRate = (1 + 0.01 * rate);
  printf("Balance after one year: %g\n", year1 = start * yearRate);
  printf("Balance after two year: %g\n", year1 * yearRate);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getnc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L39:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L3:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  je     L32
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x20,-0x5(%rbp)
  je     L32
  cmpb   $0x9,-0x5(%rbp)
  je     L32
  cmpb   $0xa,-0x5(%rbp)
  jne    L39
L32:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getnc(char *array, int n) {
  int i = 0;
  char c;
  while ((n--) && (c = getchar()) != ' ' && (c != '\t') && (c != '\n'))
    array[i++] = c;
  return i;
}
```