ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movb   $0xac,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        }
      } else {
        state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 1059477100UL) >> (unsigned char)7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movb   $0xac,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned char)7;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        } else {
          state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL);
        }
      } else {
        state[0UL] = state[local1] >> ((state[local1] & (unsigned char)7) | 1UL);
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 1059477100UL) >> (unsigned char)7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RS_mso>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x10,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L51
L31:
  shrl   -0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L28
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  jmp    L51
L28:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L51:
  cmpl   $0x1,-0x4(%rbp)
  ja     L31
  mov    -0x8(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L18
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  jmp    L25
L18:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int RS_mso(n)
unsigned int n;
{
  unsigned int p = sizeof(unsigned int) << 2;
  unsigned int w = p;
  while (w > 1) {
    w >>= 1;
    if (n & ((~(unsigned int)0x0) << p))
      p += w;
    else
      p -= w;
  }
  if (n & ((~(unsigned int)0x0) << p))
    return 0x1 << p;
  else
    return 0x1 << (p - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RS_mso>:
  endbr64
  mov    $0x4,%edx
  mov    $0x10,%eax
  mov    $0x10,%ecx
  mov    $0xffffffff,%r9d
L17:
  shr    %eax
  mov    %r9d,%r8d
  shl    %cl,%r8d
  lea    (%rcx,%rax,1),%esi
  sub    %eax,%ecx
  test   %edi,%r8d
  cmovne %esi,%ecx
  sub    $0x1,%edx
  jne    L17
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  test   %edi,%eax
  je     L5
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
L5:
  sub    $0x1,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned int RS_mso(n)
unsigned int n;
{
  unsigned int p = sizeof(unsigned int) << 2;
  unsigned int w = p;
  while (w > 1) {
    w >>= 1;
    if (n & ((~(unsigned int)0x0) << p))
      p += w;
    else
      p -= w;
  }
  if (n & ((~(unsigned int)0x0) << p))
    return 0x1 << p;
  else
    return 0x1 << (p - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RS_mso>:
  endbr64
  mov    $0x4,%edx
  mov    $0x10,%eax
  mov    $0x10,%ecx
  mov    $0xffffffff,%r9d
  nopl   0x0(%rax)
L17:
  mov    %r9d,%r8d
  shr    %eax
  shl    %cl,%r8d
  lea    (%rcx,%rax,1),%esi
  sub    %eax,%ecx
  test   %edi,%r8d
  cmovne %esi,%ecx
  sub    $0x1,%edx
  jne    L17
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  test   %edi,%eax
  jne    L5
  sub    $0x1,%ecx
L5:
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned int RS_mso(n)
unsigned int n;
{
  unsigned int p = sizeof(unsigned int) << 2;
  unsigned int w = p;
  while (w > 1) {
    w >>= 1;
    if (n & ((~(unsigned int)0x0) << p))
      p += w;
    else
      p -= w;
  }
  if (n & ((~(unsigned int)0x0) << p))
    return 0x1 << p;
  else
    return 0x1 << (p - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RS_mso>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  xor    %dx,%dx
  cmp    $0x1,%edx
  mov    $0xffffffff,%edx
  sbb    %ecx,%ecx
  mov    %edx,%edi
  and    $0xfffffff0,%ecx
  add    $0x18,%ecx
  shl    %cl,%edi
  lea    -0x4(%rcx),%esi
  add    $0x4,%ecx
  test   %eax,%edi
  mov    %edx,%edi
  cmove  %esi,%ecx
  shl    %cl,%edi
  lea    -0x2(%rcx),%esi
  add    $0x2,%ecx
  test   %eax,%edi
  mov    %edx,%edi
  cmove  %esi,%ecx
  shl    %cl,%edi
  lea    0x1(%rcx),%esi
  sub    $0x1,%ecx
  test   %eax,%edi
  cmovne %esi,%ecx
  shl    %cl,%edx
  test   %eax,%edx
  jne    L5
  sub    $0x1,%ecx
L5:
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned int RS_mso(n)
unsigned int n;
{
  unsigned int p = sizeof(unsigned int) << 2;
  unsigned int w = p;
  while (w > 1) {
    w >>= 1;
    if (n & ((~(unsigned int)0x0) << p))
      p += w;
    else
      p -= w;
  }
  if (n & ((~(unsigned int)0x0) << p))
    return 0x1 << p;
  else
    return 0x1 << (p - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file_cat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %rdi,-0x208(%rbp)
  mov    %rsi,-0x210(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L26
L27:
  mov    -0x208(%rbp),%rdx
  lea    -0x200(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
L26:
  mov    -0x210(%rbp),%rdx
  lea    -0x200(%rbp),%rax
  mov    $0x1f4,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L27
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
bool file_cat(FILE *dest, FILE *src) {
  char buf[500];
  while (fgets(buf, 500, src) != NULL) {
    fputs(buf, dest);
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<file_cat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L3
L11:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L3:
  mov    %rbp,%rdx
  mov    $0x1f4,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L11
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x1,%eax
  add    $0x200,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool file_cat(FILE *dest, FILE *src) {
  char buf[500];
  while (fgets(buf, 500, src) != NULL) {
    fputs(buf, dest);
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<file_cat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L17
  nopl   (%rax)
L16:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L17:
  mov    %rbp,%rdx
  mov    $0x1f4,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L16
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x200,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool file_cat(FILE *dest, FILE *src) {
  char buf[500];
  while (fgets(buf, 500, src) != NULL) {
    fputs(buf, dest);
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file_cat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L12
  nopl   (%rax)
L1:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L12:
  mov    %rbp,%rdx
  mov    $0x1f4,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L1
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x200,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool file_cat(FILE *dest, FILE *src) {
  char buf[500];
  while (fgets(buf, 500, src) != NULL) {
    fputs(buf, dest);
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <create_storage@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <set_number@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <set_number@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <lookup_number@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <lookup_number@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: Has ten? %d
Has thirty? %d


assistant: ```c
int main() {
  const int num_blocks = 10;
  char *bit_vector = create_storage(num_blocks);
  set_number(bit_vector, 10);
  set_number(bit_vector, 20);
  bool has_ten = lookup_number(bit_vector, 10);
  bool has_thirty = lookup_number(bit_vector, 30);
  printf("Has ten? %d\nHas thirty? %d\n", has_ten, has_thirty);
  free(bit_vector);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <create_storage@plt>
  mov    %rax,%rbx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <set_number@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <set_number@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <lookup_number@plt>
  mov    %eax,%ebp
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <lookup_number@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Has ten? %d
Has thirty? %d


assistant: ```c
int main() {
  const int num_blocks = 10;
  char *bit_vector = create_storage(num_blocks);
  set_number(bit_vector, 10);
  set_number(bit_vector, 20);
  bool has_ten = lookup_number(bit_vector, 10);
  bool has_thirty = lookup_number(bit_vector, 30);
  printf("Has ten? %d\nHas thirty? %d\n", has_ten, has_thirty);
  free(bit_vector);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <create_storage@plt>
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <set_number@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <set_number@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <lookup_number@plt>
  mov    %rbp,%rdi
  mov    $0x1e,%esi
  mov    %eax,%r12d
  call   <lookup_number@plt>
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: Has ten? %d
Has thirty? %d


assistant: ```c
int main() {
  const int num_blocks = 10;
  char *bit_vector = create_storage(num_blocks);
  set_number(bit_vector, 10);
  set_number(bit_vector, 20);
  bool has_ten = lookup_number(bit_vector, 10);
  bool has_thirty = lookup_number(bit_vector, 30);
  printf("Has ten? %d\nHas thirty? %d\n", has_ten, has_thirty);
  free(bit_vector);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <create_storage@plt>
  mov    $0xa,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <set_number@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <set_number@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <lookup_number@plt>
  mov    %rbp,%rdi
  mov    $0x1e,%esi
  mov    %eax,%r12d
  call   <lookup_number@plt>
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: Has ten? %d
Has thirty? %d


assistant: ```c
int main() {
  const int num_blocks = 10;
  char *bit_vector = create_storage(num_blocks);
  set_number(bit_vector, 10);
  set_number(bit_vector, 20);
  bool has_ten = lookup_number(bit_vector, 10);
  bool has_thirty = lookup_number(bit_vector, 30);
  printf("Has ten? %d\nHas thirty? %d\n", has_ten, has_thirty);
  free(bit_vector);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<rk_my_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L27
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
  jmp    L39
L28:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int rk_my_strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2) {
    if (!(*s1)) {
      return 0;
    }
    s1++;
    s2++;
  }
  return (*s1) - (*s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rk_my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L13
  mov    $0x1,%eax
L9:
  test   %dl,%dl
  je     L15
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L9
L13:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rk_my_strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2) {
    if (!(*s1)) {
      return 0;
    }
    s1++;
    s2++;
  }
  return (*s1) - (*s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rk_my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L17
  mov    $0x1,%eax
  jmp    L8
  nopl   (%rax)
L0:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L17
L8:
  test   %dl,%dl
  jne    L0
  xor    %eax,%eax
  ret
L17:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int rk_my_strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2) {
    if (!(*s1)) {
      return 0;
    }
    s1++;
    s2++;
  }
  return (*s1) - (*s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rk_my_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L20
  mov    $0x1,%eax
  jmp    L31
  nopl   (%rax)
L35:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L20
L31:
  test   %dl,%dl
  jne    L35
  xor    %eax,%eax
  ret
L20:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int rk_my_strcmp(const char *s1, const char *s2) {
  while (*s1 == *s2) {
    if (!(*s1)) {
      return 0;
    }
    s1++;
    s2++;
  }
  return (*s1) - (*s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L15
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L15:
  mov    $0x0,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  y = *r;
  assert(y >= 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  jmp    L2
L14:
  mov    (%rbx),%eax
  add    $0x1,%eax
L2:
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L14
  mov    (%rbx),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  y = *r;
  assert(y >= 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%eax
  add    $0x1,%eax
L6:
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L4
  mov    (%rbx),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  y = *r;
  assert(y >= 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%eax
  add    $0x1,%eax
L13:
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <nondet@plt>
  test   %rax,%rax
  jne    L11
  mov    (%rbx),%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *r;
  int y;
  r = (int *)malloc(4);
  *r = 0;
  while (nondet()) {
    *r = *r + 1;
  }
  y = *r;
  assert(y >= 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  abort();
  abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  abort();
  abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  abort();
  abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  abort();
  abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <insertNode@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <insertNode@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <insertNode@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <insertNode@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <insertNode@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printlist@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <recursivereverse@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printlist@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: 


assistant: ```c
int main() {
  struct node *head = NULL;
  insertNode(&head, 2);
  insertNode(&head, 4);
  insertNode(&head, 6);
  insertNode(&head, 8);
  insertNode(&head, 10);
  printlist(head);
  recursivereverse(&head);
  printf("\n");
  printlist(head);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <insertNode@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <insertNode@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <insertNode@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <insertNode@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <insertNode@plt>
  mov    (%rsp),%rdi
  call   <printlist@plt>
  mov    %rbx,%rdi
  call   <recursivereverse@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <printlist@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: 


assistant: ```c
int main() {
  struct node *head = NULL;
  insertNode(&head, 2);
  insertNode(&head, 4);
  insertNode(&head, 6);
  insertNode(&head, 8);
  insertNode(&head, 10);
  printlist(head);
  recursivereverse(&head);
  printf("\n");
  printlist(head);
  return 0;
}
```