ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo_short>:
  endbr64
  sub    $0x18,%rsp
  mov    %di,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    %si,0x8(%rsp)
  movswl %di,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  movswl 0x8(%rsp),%esi
  lea    0x8(%rsp),%rdx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movzwl 0xc(%rsp),%eax
  imul   0x8(%rsp),%ax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D1: foo_short: i: %hd, address: %p


tool: D7: foo_short: j: %hd, address: %p


assistant: ```c
short foo_short(short i, short j) {
  printf("foo_short: i: %hd, address: %p\n", i, &i);
  printf("foo_short: j: %hd, address: %p\n", j, &j);
  return i * j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quick_sort_iterative_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L16
L32:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L4
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L4:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L16
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jns    L32
  nop
  nop
  leave
  ret
```

assistant: ```c
void quick_sort_iterative_index(double val[], int arr[], int n, int *stack) {
  int h, l;
  h = n - 1;
  l = 0;
  int top = -1;
  stack[++top] = l;
  stack[++top] = h;
  while (top >= 0) {
    h = stack[top--];
    l = stack[top--];
    int p = partition(val, arr, l, h);
    if (p - 1 > l) {
      stack[++top] = l;
      stack[++top] = p - 1;
    }
    if (p + 1 < h) {
      stack[++top] = p + 1;
      stack[++top] = h;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quick_sort_iterative_index>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rcx,%r15
  movl   $0x0,(%rcx)
  sub    $0x1,%edx
  mov    %edx,0x4(%rcx)
  mov    $0x1,%ebp
  jmp    L45
L47:
  mov    %ebx,(%r14)
  mov    %edx,0x0(%r13)
L5:
  add    $0x1,%eax
  cmp    %r12d,%eax
  jl     L6
L45:
  test   %ebp,%ebp
  js     L27
  movslq %ebp,%rax
  shl    $0x2,%rax
  lea    (%r15,%rax,1),%r13
  mov    0x0(%r13),%r12d
  lea    -0x4(%r15,%rax,1),%r14
  mov    (%r14),%ebx
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %ebx,%edx
  jg     L47
  sub    $0x2,%ebp
  jmp    L5
L6:
  lea    0x1(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,(%r15,%rdx,4)
  add    $0x2,%ebp
  mov    %r12d,0x4(%r15,%rdx,4)
  jmp    L45
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quick_sort_iterative_index(double val[], int arr[], int n, int *stack) {
  int h, l;
  h = n - 1;
  l = 0;
  int top = -1;
  stack[++top] = l;
  stack[++top] = h;
  while (top >= 0) {
    h = stack[top--];
    l = stack[top--];
    int p = partition(val, arr, l, h);
    if (p - 1 > l) {
      stack[++top] = l;
      stack[++top] = p - 1;
    }
    if (p + 1 < h) {
      stack[++top] = p + 1;
      stack[++top] = h;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quick_sort_iterative_index>:
  endbr64
  push   %r15
  sub    $0x1,%edx
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,(%rcx)
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rcx)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x1,%eax
  sub    $0x2,%r13d
  cmp    %r15d,%eax
  jl     L1
L33:
  test   %r13d,%r13d
  js     L57
L29:
  movslq %r13d,%rax
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rbx
  lea    -0x4(%r14,%rax,1),%rbp
  mov    (%rbx),%r15d
  mov    0x0(%rbp),%r12d
  mov    %r15d,%ecx
  mov    %r12d,%edx
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  jle    L58
  add    $0x1,%eax
  mov    %r12d,0x0(%rbp)
  mov    %edx,(%rbx)
  cmp    %r15d,%eax
  jge    L33
L1:
  lea    0x1(%r13),%edx
  add    $0x2,%r13d
  movslq %edx,%rdx
  mov    %eax,(%r14,%rdx,4)
  mov    %r15d,0x4(%r14,%rdx,4)
  test   %r13d,%r13d
  jns    L29
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quick_sort_iterative_index(double val[], int arr[], int n, int *stack) {
  int h, l;
  h = n - 1;
  l = 0;
  int top = -1;
  stack[++top] = l;
  stack[++top] = h;
  while (top >= 0) {
    h = stack[top--];
    l = stack[top--];
    int p = partition(val, arr, l, h);
    if (p - 1 > l) {
      stack[++top] = l;
      stack[++top] = p - 1;
    }
    if (p + 1 < h) {
      stack[++top] = p + 1;
      stack[++top] = h;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quick_sort_iterative_index>:
  endbr64
  push   %r15
  sub    $0x1,%edx
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,(%rcx)
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rcx)
  jmp    L0
  nopl   0x0(%rax)
L32:
  add    $0x1,%eax
  sub    $0x2,%r13d
  cmp    %r14d,%eax
  jl     L51
L0:
  test   %r13d,%r13d
  js     L18
L17:
  movslq %r13d,%rax
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  lea    -0x4(%r15,%rax,4),%rbx
  mov    (%r15,%rax,4),%r14d
  mov    (%rbx),%r12d
  mov    %r14d,%ecx
  mov    %r12d,%edx
  call   <partition@plt>
  movd   %r12d,%xmm0
  lea    -0x1(%rax),%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  cmp    %r12d,%edx
  jle    L32
  add    $0x1,%eax
  movq   %xmm0,(%rbx)
  cmp    %r14d,%eax
  jge    L0
L51:
  lea    0x1(%r13),%edx
  movd   %eax,%xmm0
  movd   %r14d,%xmm2
  add    $0x2,%r13d
  movslq %edx,%rdx
  punpckldq %xmm2,%xmm0
  movq   %xmm0,(%r15,%rdx,4)
  test   %r13d,%r13d
  jns    L17
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quick_sort_iterative_index(double val[], int arr[], int n, int *stack) {
  int h, l;
  h = n - 1;
  l = 0;
  int top = -1;
  stack[++top] = l;
  stack[++top] = h;
  while (top >= 0) {
    h = stack[top--];
    l = stack[top--];
    int p = partition(val, arr, l, h);
    if (p - 1 > l) {
      stack[++top] = l;
      stack[++top] = p - 1;
    }
    if (p + 1 < h) {
      stack[++top] = p + 1;
      stack[++top] = h;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<writetwodig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x63,-0xc(%rbp)
  jle    L4
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <writeint@plt>
  jmp    L12
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <writech@plt>
  mov    -0xc(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    $0x30,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <writech@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
void writetwodig(sp, i) struct slot *sp;
{
  if (i >= 100)
    writeint(sp, i);
  else {
    writech(sp, i / 10 + '0');
    writech(sp, i % 10 + '0');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writetwodig>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  cmp    $0x63,%esi
  jle    L6
  mov    $0x0,%eax
  call   <writeint@plt>
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  movslq %esi,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%esi
  mov    $0x0,%eax
  call   <writech@plt>
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <writech@plt>
  jmp    L9
```

assistant: ```c
void writetwodig(sp, i) struct slot *sp;
{
  if (i >= 100)
    writeint(sp, i);
  else {
    writech(sp, i / 10 + '0');
    writech(sp, i % 10 + '0');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writetwodig>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x63,%esi
  jle    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <writeint@plt>
  nopl   (%rax)
L1:
  movslq %esi,%rbx
  mov    %esi,%eax
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    0x30(%rbx),%esi
  call   <writech@plt>
  lea    (%rbx,%rbx,4),%eax
  mov    %r12,%rdi
  pop    %rbx
  add    %eax,%eax
  sub    %eax,%ebp
  xor    %eax,%eax
  lea    0x30(%rbp),%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <writech@plt>
```

assistant: ```c
void writetwodig(sp, i) struct slot *sp;
{
  if (i >= 100)
    writeint(sp, i);
  else {
    writech(sp, i / 10 + '0');
    writech(sp, i % 10 + '0');
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writetwodig>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    $0x63,%esi
  jle    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <writeint@plt>
  nopl   (%rax)
L9:
  movslq %esi,%rbx
  mov    %esi,%eax
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  xor    %eax,%eax
  lea    0x30(%rbx),%esi
  call   <writech@plt>
  lea    (%rbx,%rbx,4),%eax
  mov    %r12,%rdi
  pop    %rbx
  add    %eax,%eax
  sub    %eax,%ebp
  xor    %eax,%eax
  lea    0x30(%rbp),%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <writech@plt>
```

assistant: ```c
void writetwodig(sp, i) struct slot *sp;
{
  if (i >= 100)
    writeint(sp, i);
  else {
    writech(sp, i / 10 + '0');
    writech(sp, i % 10 + '0');
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<string_substitute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x38(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strcpyn@plt>
  mov    -0x50(%rbp),%rax
  jmp    L14
L89:
  mov    -0x8(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L59
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L52
L63:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L52:
  mov    -0x20(%rbp),%rax
  sub    -0x50(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x58(%rbp),%rax
  sub    $0x2,%eax
  cltq
  cmp    %rax,%rdx
  jge    L72
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
L72:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L31
L59:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L31:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x58(%rbp),%rax
  add    $0x2,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L89
L34:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x50(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *string_substitute(const char *str, const char *oldstr, const char *newstr, char *buf, size_t maxlen) {
  const char *ptr = str;
  char *ptr2 = buf;
  size_t len = strlen(oldstr);
  size_t clen = 0;
  if (len == 0) {
    strcpyn(buf, maxlen, str);
    return buf;
  }
  while (*ptr && clen < (maxlen + 2)) {
    if (!strncmp(ptr, oldstr, len)) {
      for (const char *ptr3 = newstr; ((ptr2 - buf) < (int)(maxlen - 2)) && *ptr3;)
        *(ptr2++) = *(ptr3++);
      ptr += len;
      clen += len;
    } else {
      *(ptr2++) = *(ptr++);
      clen++;
    }
  }
  *ptr2 = '\0';
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_substitute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %rcx,%r12
  mov    %r8,%r15
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L103
  movzbl 0x0(%rbp),%r14d
  test   %r14b,%r14b
  je     L74
  mov    %r12,%rbx
  mov    $0x0,%r13d
  mov    %r15,%rax
  lea    -0x2(%r15),%r15d
  movslq %r15d,%r15
  add    $0x2,%rax
  mov    %rax,0x10(%rsp)
  jne    L37
  jmp    L40
L103:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcpyn@plt>
  jmp    L45
L66:
  add    $0x1,%rbp
  mov    %r14b,(%rbx)
  add    $0x1,%r13
  lea    0x1(%rbx),%rbx
L23:
  movzbl 0x0(%rbp),%r14d
  test   %r14b,%r14b
  je     L40
  cmp    0x10(%rsp),%r13
  jae    L40
L37:
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L66
  mov    %rbx,%rdx
  sub    %r12,%rdx
  mov    0x18(%rsp),%rax
  cmp    %r15,%rdx
  jge    L12
L9:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L12
  add    $0x1,%rax
  add    $0x1,%rbx
  mov    %dl,-0x1(%rbx)
  mov    %rbx,%rdx
  sub    %r12,%rdx
  cmp    %r15,%rdx
  jl     L9
L12:
  mov    (%rsp),%rax
  add    %rax,%rbp
  add    %rax,%r13
  jmp    L23
L74:
  mov    %r12,%rbx
L40:
  movb   $0x0,(%rbx)
L45:
  mov    %r12,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *string_substitute(const char *str, const char *oldstr, const char *newstr, char *buf, size_t maxlen) {
  const char *ptr = str;
  char *ptr2 = buf;
  size_t len = strlen(oldstr);
  size_t clen = 0;
  if (len == 0) {
    strcpyn(buf, maxlen, str);
    return buf;
  }
  while (*ptr && clen < (maxlen + 2)) {
    if (!strncmp(ptr, oldstr, len)) {
      for (const char *ptr3 = newstr; ((ptr2 - buf) < (int)(maxlen - 2)) && *ptr3;)
        *(ptr2++) = *(ptr3++);
      ptr += len;
      clen += len;
    } else {
      *(ptr2++) = *(ptr++);
      clen++;
    }
  }
  *ptr2 = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_substitute>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %r8,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rsi
  test   %rax,%rax
  je     L119
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  je     L130
  lea    -0x2(%rsi),%r9d
  xor    %ebp,%ebp
  add    $0x2,%rsi
  mov    %rax,%r10
  mov    %rsi,0x10(%rsp)
  mov    %r15,%rbx
  movslq %r9d,%r13
  jne    L70
  jmp    L69
  nopl   (%rax)
L102:
  add    $0x1,%r14
  mov    %r11b,(%rbx)
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  je     L69
L133:
  cmp    0x10(%rsp),%rbp
  jae    L69
L70:
  mov    %r10,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r11b,0xf(%rsp)
  mov    %r10,(%rsp)
  call   <strncmp@plt>
  mov    (%rsp),%r10
  movzbl 0xf(%rsp),%r11d
  test   %eax,%eax
  jne    L102
  mov    %rbx,%rdx
  mov    0x18(%rsp),%rax
  sub    %r15,%rdx
  cmp    %r13,%rdx
  jl     L8
  jmp    L30
  xchg   %ax,%ax
L24:
  add    $0x1,%rbx
  mov    %dl,-0x1(%rbx)
  add    $0x1,%rax
  mov    %rbx,%rdx
  sub    %r15,%rdx
  cmp    %r13,%rdx
  jge    L30
L8:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L24
L30:
  add    %r10,%r14
  add    %r10,%rbp
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  jne    L133
  nopl   0x0(%rax)
L69:
  movb   $0x0,(%rbx)
L56:
  add    $0x28,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L119:
  mov    %r14,%rdx
  mov    %r15,%rdi
  call   <strcpyn@plt>
  jmp    L56
L130:
  mov    %r15,%rbx
  jmp    L69
```

assistant: ```c
char *string_substitute(const char *str, const char *oldstr, const char *newstr, char *buf, size_t maxlen) {
  const char *ptr = str;
  char *ptr2 = buf;
  size_t len = strlen(oldstr);
  size_t clen = 0;
  if (len == 0) {
    strcpyn(buf, maxlen, str);
    return buf;
  }
  while (*ptr && clen < (maxlen + 2)) {
    if (!strncmp(ptr, oldstr, len)) {
      for (const char *ptr3 = newstr; ((ptr2 - buf) < (int)(maxlen - 2)) && *ptr3;)
        *(ptr2++) = *(ptr3++);
      ptr += len;
      clen += len;
    } else {
      *(ptr2++) = *(ptr++);
      clen++;
    }
  }
  *ptr2 = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_substitute>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %r8,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rsi
  test   %rax,%rax
  je     L22
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  je     L133
  lea    -0x2(%rsi),%r9d
  xor    %ebp,%ebp
  add    $0x2,%rsi
  mov    %rax,%r10
  mov    %rsi,0x10(%rsp)
  mov    %r15,%rbx
  movslq %r9d,%r13
  jne    L113
  jmp    L14
  nopl   (%rax)
L37:
  add    $0x1,%r14
  mov    %r11b,(%rbx)
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  je     L14
L39:
  cmp    0x10(%rsp),%rbp
  jae    L14
L113:
  mov    %r10,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r11b,0xf(%rsp)
  mov    %r10,(%rsp)
  call   <strncmp@plt>
  mov    (%rsp),%r10
  movzbl 0xf(%rsp),%r11d
  test   %eax,%eax
  jne    L37
  mov    %rbx,%rdx
  mov    0x18(%rsp),%rax
  sub    %r15,%rdx
  cmp    %r13,%rdx
  jl     L13
  jmp    L77
  xchg   %ax,%ax
L35:
  add    $0x1,%rbx
  mov    %dl,-0x1(%rbx)
  add    $0x1,%rax
  mov    %rbx,%rdx
  sub    %r15,%rdx
  cmp    %r13,%rdx
  jge    L77
L13:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L35
L77:
  add    %r10,%r14
  add    %r10,%rbp
  movzbl (%r14),%r11d
  test   %r11b,%r11b
  jne    L39
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rbx)
L52:
  add    $0x28,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L22:
  mov    %r14,%rdx
  mov    %r15,%rdi
  call   <strcpyn@plt>
  jmp    L52
L133:
  mov    %r15,%rbx
  jmp    L14
```

assistant: ```c
char *string_substitute(const char *str, const char *oldstr, const char *newstr, char *buf, size_t maxlen) {
  const char *ptr = str;
  char *ptr2 = buf;
  size_t len = strlen(oldstr);
  size_t clen = 0;
  if (len == 0) {
    strcpyn(buf, maxlen, str);
    return buf;
  }
  while (*ptr && clen < (maxlen + 2)) {
    if (!strncmp(ptr, oldstr, len)) {
      for (const char *ptr3 = newstr; ((ptr2 - buf) < (int)(maxlen - 2)) && *ptr3;)
        *(ptr2++) = *(ptr3++);
      ptr += len;
      clen += len;
    } else {
      *(ptr2++) = *(ptr++);
      clen++;
    }
  }
  *ptr2 = '\0';
  return buf;
}
```