ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D21
type: string

tool: D1: Enter a word to be reversed : 

tool: D0: %s

tool: D23: Entered Word :: %s 


tool: D21: Reversed  Word :: %s 


assistant: ```c
int main() {
  char str[200];
  printf("Enter a word to be reversed : ");
  scanf("%s", str);
  printf("Entered Word :: %s \n", str);
  reverse(str);
  printf("Reversed  Word :: %s \n", str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L24:
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  nop
L4:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *p = dst;
  while (*p)
    p++;
  while ((*p++ = *src++))
    ;
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L33
  mov    %rdi,%rcx
L18:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L18
L36:
  mov    $0x0,%edx
L20:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L20
  ret
L33:
  mov    %rdi,%rcx
  jmp    L36
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *p = dst;
  while (*p)
    p++;
  while ((*p++ = *src++))
    ;
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L6
  nop
L17:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L17
L6:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L10
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *p = dst;
  while (*p)
    p++;
  while ((*p++ = *src++))
    ;
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L5
  nop
L20:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L20
L5:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L24
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  char *p = dst;
  while (*p)
    p++;
  while ((*p++ = *src++))
    ;
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L5
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L38
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L0
L5:
  leave
  ret
```

assistant: ```c
int my_strrev(char *string) {
  if (string == NULL) {
    return 0;
  }
  int string_len = strlen(string);
  for (int left = 0, right = string_len - 1; left < right; left++, right--) {
    char temp_ch = string[left];
    string[left] = string[right];
    string[right] = temp_ch;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_strrev>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L14
  cltq
  mov    $0x0,%edx
L10:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L10
L14:
  pop    %rbx
  ret
L26:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int my_strrev(char *string) {
  if (string == NULL) {
    return 0;
  }
  int string_len = strlen(string);
  for (int left = 0, right = string_len - 1; left < right; left++, right--) {
    char temp_ch = string[left];
    string[left] = string[right];
    string[right] = temp_ch;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strrev>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L14
  cltq
  xor    %edx,%edx
  nopl   (%rax)
L3:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L3
L14:
  pop    %rbx
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_strrev(char *string) {
  if (string == NULL) {
    return 0;
  }
  int string_len = strlen(string);
  for (int left = 0, right = string_len - 1; left < right; left++, right--) {
    char temp_ch = string[left];
    string[left] = string[right];
    string[right] = temp_ch;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_strrev>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L22
  cltq
  xor    %edx,%edx
  nopl   (%rax)
L25:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L25
L22:
  pop    %rbx
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_strrev(char *string) {
  if (string == NULL) {
    return 0;
  }
  int string_len = strlen(string);
  for (int left = 0, right = string_len - 1; left < right; left++, right--) {
    char temp_ch = string[left];
    string[left] = string[right];
    string[right] = temp_ch;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<env_get_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <env_get_u32s@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned env_get_u32(char *name, unsigned value) {
  unsigned *values = env_get_u32s(name);
  if (values) {
    value = *values;
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<env_get_u32>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <env_get_u32s@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  test   %rdx,%rdx
  je     L3
  mov    (%rdx),%eax
L3:
  pop    %rbx
  ret
```

assistant: ```c
unsigned env_get_u32(char *name, unsigned value) {
  unsigned *values = env_get_u32s(name);
  if (values) {
    value = *values;
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<env_get_u32>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <env_get_u32s@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  test   %rdx,%rdx
  je     L0
  mov    (%rdx),%eax
L0:
  pop    %rbx
  ret
```

assistant: ```c
unsigned env_get_u32(char *name, unsigned value) {
  unsigned *values = env_get_u32s(name);
  if (values) {
    value = *values;
  }
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<env_get_u32>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <env_get_u32s@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  test   %rdx,%rdx
  je     L5
  mov    (%rdx),%eax
L5:
  pop    %rbx
  ret
```

assistant: ```c
unsigned env_get_u32(char *name, unsigned value) {
  unsigned *values = env_get_u32s(name);
  if (values) {
    value = *values;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uri_parse_query>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L10
  addq   $0x1,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L22
L41:
  addq   $0x1,-0x10(%rbp)
L22:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  je     L4
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
L4:
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L38
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int uri_parse_query(const char **queryb, size_t *queryl, const char **fragb) {
  size_t len;
  const char *queryb__;
  queryb__ = *queryb;
  if (queryb__[0] == '?') {
    queryb__++;
    len = 0;
    while (queryb__[len] != '#' && queryb__[len] != '\0') {
      len++;
    }
    *queryl = len;
    *fragb = queryb__ + len;
    *queryb = queryb__;
    return len;
  } else {
    *fragb = *queryb;
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uri_parse_query>:
  endbr64
  mov    (%rdi),%r9
  cmpb   $0x3f,(%r9)
  je     L50
  mov    %r9,(%rdx)
  mov    $0x0,%eax
  ret
L50:
  lea    0x1(%r9),%r11
  movzbl 0x1(%r9),%eax
  cmp    $0x23,%al
  je     L53
  test   %al,%al
  je     L53
  lea    0x2(%r9),%rcx
L54:
  mov    %rcx,%rax
  sub    %r9,%rax
  sub    $0x1,%rax
  mov    %rcx,%r10
  movzbl (%rcx),%r8d
  add    $0x1,%rcx
  cmp    $0x23,%r8b
  je     L1
  test   %r8b,%r8b
  jne    L54
L1:
  mov    %rax,(%rsi)
  mov    %r10,(%rdx)
  mov    %r11,(%rdi)
  ret
L53:
  mov    %r11,%r10
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
int uri_parse_query(const char **queryb, size_t *queryl, const char **fragb) {
  size_t len;
  const char *queryb__;
  queryb__ = *queryb;
  if (queryb__[0] == '?') {
    queryb__++;
    len = 0;
    while (queryb__[len] != '#' && queryb__[len] != '\0') {
      len++;
    }
    *queryl = len;
    *fragb = queryb__ + len;
    *queryb = queryb__;
    return len;
  } else {
    *fragb = *queryb;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uri_parse_query>:
  endbr64
  mov    (%rdi),%r8
  mov    %rdi,%r9
  cmpb   $0x3f,(%r8)
  je     L39
  mov    %r8,(%rdx)
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  movzbl 0x1(%r8),%eax
  lea    0x1(%r8),%r11
  test   %al,%al
  je     L58
  cmp    $0x23,%al
  je     L58
  lea    0x2(%r8),%rax
  nopl   (%rax)
L41:
  mov    %rax,%rcx
  movzbl (%rax),%edi
  mov    %rax,%r10
  add    $0x1,%rax
  sub    %r8,%rcx
  sub    $0x1,%rcx
  cmp    $0x23,%dil
  je     L10
  test   %dil,%dil
  jne    L41
L10:
  mov    %ecx,%eax
L22:
  mov    %rcx,(%rsi)
  mov    %r10,(%rdx)
  mov    %r11,(%r9)
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r11,%r10
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L22
```

assistant: ```c
int uri_parse_query(const char **queryb, size_t *queryl, const char **fragb) {
  size_t len;
  const char *queryb__;
  queryb__ = *queryb;
  if (queryb__[0] == '?') {
    queryb__++;
    len = 0;
    while (queryb__[len] != '#' && queryb__[len] != '\0') {
      len++;
    }
    *queryl = len;
    *fragb = queryb__ + len;
    *queryb = queryb__;
    return len;
  } else {
    *fragb = *queryb;
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uri_parse_query>:
  endbr64
  mov    (%rdi),%r8
  mov    %rdi,%r9
  cmpb   $0x3f,(%r8)
  je     L5
  mov    %r8,(%rdx)
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl 0x1(%r8),%eax
  lea    0x1(%r8),%r11
  test   %al,%al
  je     L42
  cmp    $0x23,%al
  je     L42
  lea    0x2(%r8),%rax
  nopl   (%rax)
L38:
  mov    %rax,%rcx
  movzbl (%rax),%edi
  mov    %rax,%r10
  add    $0x1,%rax
  sub    %r8,%rcx
  sub    $0x1,%rcx
  cmp    $0x23,%dil
  je     L50
  test   %dil,%dil
  jne    L38
L50:
  mov    %ecx,%eax
L34:
  mov    %rcx,(%rsi)
  mov    %r10,(%rdx)
  mov    %r11,(%r9)
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r11,%r10
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L34
```

assistant: ```c
int uri_parse_query(const char **queryb, size_t *queryl, const char **fragb) {
  size_t len;
  const char *queryb__;
  queryb__ = *queryb;
  if (queryb__[0] == '?') {
    queryb__++;
    len = 0;
    while (queryb__[len] != '#' && queryb__[len] != '\0') {
      len++;
    }
    *queryl = len;
    *fragb = queryb__ + len;
    *queryb = queryb__;
    return len;
  } else {
    *fragb = *queryb;
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x2a,-0x9(%rbp)
  mov    $0xb100d,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main() {
  char buf[40];
  buf[39] = 42;
  return 0xb100d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0xb100d,%eax
  ret
```

assistant: ```c
int main() {
  char buf[40];
  buf[39] = 42;
  return 0xb100d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0xb100d,%eax
  ret
```

assistant: ```c
int main() {
  char buf[40];
  buf[39] = 42;
  return 0xb100d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0xb100d,%eax
  ret
```

assistant: ```c
int main() {
  char buf[40];
  buf[39] = 42;
  return 0xb100d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L26
L31:
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  movq   $0x0,-0x10(%rbp)
  jmp    L29
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L14
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  mov    %rax,-0x8(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long atox(char *s) {
  unsigned long sum;
  while (isspace(*s))
    ++s;
  for (sum = 0L; isxdigit(*s); ++s) {
    unsigned long digit;
    if (isdigit(*s))
      digit = *s - '0';
    else
      digit = toupper(*s) - 'A' + 10;
    sum = sum * 16L + digit;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atox>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L3
L23:
  add    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L23
  mov    $0x0,%ebp
  jmp    L39
L12:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
L4:
  shl    $0x4,%rbp
  add    %rax,%rbp
  add    $0x1,%rbx
L39:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L18
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L4
L18:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long atox(char *s) {
  unsigned long sum;
  while (isspace(*s))
    ++s;
  for (sum = 0L; isxdigit(*s); ++s) {
    unsigned long digit;
    if (isdigit(*s))
      digit = *s - '0';
    else
      digit = toupper(*s) - 'A' + 10;
    sum = sum * 16L + digit;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atox>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L46
L58:
  add    $0x1,%rbx
L46:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
  xor    %r12d,%r12d
  jmp    L56
  cs nopw 0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
L0:
  shl    $0x4,%r12
  add    $0x1,%rbx
  add    %rax,%r12
L56:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L3
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L0
  nop
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned long atox(char *s) {
  unsigned long sum;
  while (isspace(*s))
    ++s;
  for (sum = 0L; isxdigit(*s); ++s) {
    unsigned long digit;
    if (isdigit(*s))
      digit = *s - '0';
    else
      digit = toupper(*s) - 'A' + 10;
    sum = sum * 16L + digit;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atox>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L42
L48:
  add    $0x1,%rbx
L42:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  xor    %r12d,%r12d
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L20:
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
L38:
  shl    $0x4,%r12
  add    $0x1,%rbx
  add    %rax,%r12
L45:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L0
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L20
  movsbl (%rbx),%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L38
  nop
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned long atox(char *s) {
  unsigned long sum;
  while (isspace(*s))
    ++s;
  for (sum = 0L; isxdigit(*s); ++s) {
    unsigned long digit;
    if (isdigit(*s))
      digit = *s - '0';
    else
      digit = toupper(*s) - 'A' + 10;
    sum = sum * 16L + digit;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D28(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D23
data_type: string
name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D28
data_type: f64
name: parse_data
arguments: tag: D35
data_type: string

tool: D23: Input your age:

tool: D2: %d

tool: D28: 31560000

tool: D35: You have past about %e seconds in your life!


assistant: ```c
int main(void) {
  int age;
  double seconds;
  printf("Input your age:");
  scanf("%d", &age);
  seconds = age * 3.156e7;
  printf("You have past about %e seconds in your life!\n", seconds);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x4(%rsp),%xmm0
  mulsd  D26(%rip),%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: f64
name: retrieve_data
arguments: label: D24
type_guessed: string

tool: D21: Input your age:

tool: D14: %d

tool: D26: 31560000

tool: D24: You have past about %e seconds in your life!


assistant: ```c
int main(void) {
  int age;
  double seconds;
  printf("Input your age:");
  scanf("%d", &age);
  seconds = age * 3.156e7;
  printf("You have past about %e seconds in your life!\n", seconds);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D25(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D21(%rip),%rdi
  cvtsi2sdl 0x4(%rsp),%xmm0
  mulsd  D10(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string
name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: f64

tool: D19: Input your age:

tool: D25: %d

tool: D21: You have past about %e seconds in your life!


tool: D10: 31560000

assistant: ```c
int main(void) {
  int age;
  double seconds;
  printf("Input your age:");
  scanf("%d", &age);
  seconds = age * 3.156e7;
  printf("You have past about %e seconds in your life!\n", seconds);
  return 0;
}
```