user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
L6:
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x58(%rbp),%eax
  test   %eax,%eax
  jle    L6
  mov    -0x58(%rbp),%eax
  cmp    $0x2710,%eax
  jg     L6
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L140:
  cmp    %rdx,%rsp
  je     L135
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L140
L135:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L87
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L87:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L12
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%ecx
  movslq %ecx,%rcx
  mov    %edx,(%rax,%rcx,4)
  addl   $0x1,-0x54(%rbp)
L12:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L22
  movl   $0x0,-0x54(%rbp)
  jmp    L148
L60:
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x50(%rbp)
  jmp    L19
L49:
  mov    -0x40(%rbp),%rax
  mov    -0x50(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  cmp    %eax,%ecx
  jge    L66
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x50(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  mov    -0x40(%rbp),%rax
  mov    -0x50(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x4c(%rbp),%ecx
  mov    %ecx,(%rax,%rdx,4)
L66:
  addl   $0x1,-0x50(%rbp)
L19:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L49
  addl   $0x1,-0x54(%rbp)
L148:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L60
  movl   $0x0,-0x54(%rbp)
  jmp    L65
L113:
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x54(%rbp)
L65:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L113
  mov    %rbx,%rsp
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D19
datatype: string

tool: D17: %d

tool: D19: %4d

assistant: ```c
main() {
  int i, nl, k, j;
  do {
    scanf("%d", &nl);
  } while ((nl <= 0) || (nl > 10000));
  int a[nl];
  for (i = 0; i < nl; i++) {
    a[i] = rand() % 101;
  }
  for (i = 0; i < nl; i++) {
    for (j = i + 1; j < nl; j++) {
      if (a[j] < a[i]) {
        k = a[i];
        a[i] = a[j];
        a[j] = k;
      }
    }
  }
  for (i = 0; i < nl; i++) {
    printf("%4d", a[i]);
  }
}
```