ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jbe    L22
  test   %edx,%edx
  jle    L1
  lea    -0x1(%rdx),%edi
  mov    $0x0,%edx
L56:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rcx
  jne    L56
  ret
L22:
  jae    L1
  sub    $0x1,%edx
  js     L1
  movslq %edx,%rdx
L26:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L26
L1:
  ret
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  int index;
  unsigned char *src_ptr;
  unsigned char *dst_ptr;
  index = 0;
  src_ptr = (unsigned char *)src;
  dst_ptr = (unsigned char *)dst;
  if (src > dst)
    while (index < (int)len) {
      dst_ptr[index] = src_ptr[index];
      index++;
    }
  else if (dst > src) {
    index = (int)len - 1;
    while (index > -1) {
      dst_ptr[index] = src_ptr[index];
      index--;
    }
  }
  return (dst);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jbe    L9
  test   %edx,%edx
  jle    L38
  lea    -0x1(%rdx),%edi
  xor    %edx,%edx
  nopl   (%rax)
L15:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L15
  ret
  nopl   0x0(%rax)
L9:
  jb     L56
L38:
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  sub    $0x1,%edx
  js     L38
  movslq %edx,%rdx
L36:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L36
  ret
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  int index;
  unsigned char *src_ptr;
  unsigned char *dst_ptr;
  index = 0;
  src_ptr = (unsigned char *)src;
  dst_ptr = (unsigned char *)dst;
  if (src > dst)
    while (index < (int)len) {
      dst_ptr[index] = src_ptr[index];
      index++;
    }
  else if (dst > src) {
    index = (int)len - 1;
    while (index > -1) {
      dst_ptr[index] = src_ptr[index];
      index--;
    }
  }
  return (dst);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rax
  cmp    %rdi,%rsi
  jbe    L31
  test   %edx,%edx
  jle    L142
  lea    0x1(%rsi),%r9
  mov    %r8,%rsi
  mov    %edx,%edi
  sub    %r9,%rsi
  lea    -0x1(%rdx),%edx
  cmp    $0xe,%rsi
  jbe    L120
  cmp    $0x6,%edx
  jbe    L120
  cmp    $0xe,%edx
  jbe    L24
  mov    %eax,%esi
  xor    %edx,%edx
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L15:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rsi,%rdx
  jne    L15
  mov    %eax,%esi
  and    $0xfffffff0,%esi
  mov    %esi,%edx
  cmp    %esi,%eax
  je     L142
  mov    %eax,%edi
  sub    %esi,%edi
  lea    -0x1(%rdi),%r9d
  cmp    $0x6,%r9d
  jbe    L22
L165:
  mov    (%rcx,%rsi,1),%r9
  mov    %r9,(%r8,%rsi,1)
  mov    %edi,%esi
  and    $0xfffffff8,%esi
  add    %esi,%edx
  cmp    %esi,%edi
  je     L142
L22:
  movslq %edx,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x1(%rdx),%esi
  cmp    %esi,%eax
  jle    L142
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x2(%rdx),%esi
  cmp    %esi,%eax
  jle    L142
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x3(%rdx),%esi
  cmp    %esi,%eax
  jle    L142
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x4(%rdx),%esi
  cmp    %esi,%eax
  jle    L142
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x5(%rdx),%esi
  cmp    %esi,%eax
  jle    L142
  movslq %esi,%rsi
  add    $0x6,%edx
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  cmp    %edx,%eax
  jle    L142
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,(%r8,%rdx,1)
L142:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  jae    L142
  sub    $0x1,%eax
  js     L142
  cltq
  nopl   0x0(%rax)
L177:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L177
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L120:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L26
  jmp    L142
L24:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L165
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  int index;
  unsigned char *src_ptr;
  unsigned char *dst_ptr;
  index = 0;
  src_ptr = (unsigned char *)src;
  dst_ptr = (unsigned char *)dst;
  if (src > dst)
    while (index < (int)len) {
      dst_ptr[index] = src_ptr[index];
      index++;
    }
  else if (dst > src) {
    index = (int)len - 1;
    while (index > -1) {
      dst_ptr[index] = src_ptr[index];
      index--;
    }
  }
  return (dst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L27
L0:
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L30:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L30
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L27:
  leave
  ret
```

assistant: ```c
char *str_dup(char *str) {
  char *dup_str = alloc(strlen(str) + 1);
  if (dup_str == NULL) {
    return NULL;
  }
  int index;
  for (index = 0; index < strlen(str); ++index) {
    dup_str[index] = str[index];
  }
  dup_str[index] = '\0';
  return dup_str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    $0x0,%ebx
  jmp    L22
L19:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L19
  movslq %ebx,%r13
  movb   $0x0,(%r12,%r13,1)
L24:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_dup(char *str) {
  char *dup_str = alloc(strlen(str) + 1);
  if (dup_str == NULL) {
    return NULL;
  }
  int index;
  for (index = 0; index < strlen(str); ++index) {
    dup_str[index] = str[index];
  }
  dup_str[index] = '\0';
  return dup_str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  xor    %ebx,%ebx
  jmp    L18
  nopl   0x0(%rax)
L19:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %ebx,%eax
  jg     L19
  movb   $0x0,(%rdx)
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_dup(char *str) {
  char *dup_str = alloc(strlen(str) + 1);
  if (dup_str == NULL) {
    return NULL;
  }
  int index;
  for (index = 0; index < strlen(str); ++index) {
    dup_str[index] = str[index];
  }
  dup_str[index] = '\0';
  return dup_str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  xor    %ebx,%ebx
  jmp    L11
  nopl   0x0(%rax)
L22:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdx
  cmp    %ebx,%eax
  jg     L22
  movb   $0x0,(%rdx)
L13:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_dup(char *str) {
  char *dup_str = alloc(strlen(str) + 1);
  if (dup_str == NULL) {
    return NULL;
  }
  int index;
  for (index = 0; index < strlen(str); ++index) {
    dup_str[index] = str[index];
  }
  dup_str[index] = '\0';
  return dup_str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_and_set_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x5,%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    -0x10(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_and_set_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile int *a = addr;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  retval = (mask & *a) != 0;
  *a |= mask;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_and_set_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,4),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    (%rdx),%esi
  mov    (%rdx),%ecx
  or     %eax,%ecx
  mov    %ecx,(%rdx)
  test   %eax,%esi
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_set_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile int *a = addr;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  retval = (mask & *a) != 0;
  *a |= mask;
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_and_set_bit>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,4),%rdx
  mov    $0x1,%eax
  mov    (%rdx),%esi
  shl    %cl,%eax
  mov    (%rdx),%ecx
  or     %eax,%ecx
  test   %eax,%esi
  setne  %al
  mov    %ecx,(%rdx)
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_set_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile int *a = addr;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  retval = (mask & *a) != 0;
  *a |= mask;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_and_set_bit>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,4),%rdx
  mov    $0x1,%eax
  mov    (%rdx),%esi
  shl    %cl,%eax
  mov    (%rdx),%ecx
  or     %eax,%ecx
  test   %eax,%esi
  setne  %al
  mov    %ecx,(%rdx)
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_set_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile int *a = addr;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  retval = (mask & *a) != 0;
  *a |= mask;
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L44
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L43
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L43:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L44:
  lea    -0xc(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0xe(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl -0xe(%rbp),%edx
  mov    %dx,(%rax)
L17:
  mov    -0xc(%rbp),%eax
  lea    -0x2922a849(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = state[0UL] - 690137161UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x3f60a4d(%rdx),%ecx
  mov    %ecx,%eax
  rol    $0x10,%eax
  test   $0x1,%dl
  jne    L1
  lea    (%rcx,%rcx,1),%eax
L1:
  sub    $0x2922a849,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = state[0UL] - 690137161UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x3f60a4d(%rdx),%ecx
  mov    %ecx,%eax
  rol    $0x10,%eax
  and    $0x1,%edx
  jne    L6
  lea    (%rcx,%rcx,1),%eax
L6:
  sub    $0x2922a849,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = state[0UL] - 690137161UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x3f60a4d(%rdx),%ecx
  mov    %ecx,%eax
  rol    $0x10,%eax
  and    $0x1,%edx
  jne    L9
  lea    (%rcx,%rcx,1),%eax
L9:
  sub    $0x2922a849,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      copy11 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy11;
    }
    output[0UL] = state[0UL] - 690137161UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BotMovementAutonomyForString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x2,%eax
  jmp    L23
L12:
  mov    -0x8(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L41
  mov    $0x1,%eax
  jmp    L23
L41:
  mov    -0x8(%rbp),%rax
  lea    D24(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Q_stricmp@plt>
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L23
L28:
  mov    $0xffffffff,%eax
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string

tool: D1: high

tool: D20: medium

tool: D24: low

assistant: ```c
int BotMovementAutonomyForString(char *string) {
  if (!Q_stricmp(string, "high")) {
    return 2;
  } else if (!Q_stricmp(string, "medium")) {
    return 1;
  } else if (!Q_stricmp(string, "low")) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BotMovementAutonomyForString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D14(%rip),%rsi
  call   <Q_stricmp@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L27
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <Q_stricmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L21
L27:
  pop    %rbx
  ret
L21:
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <Q_stricmp@plt>
  neg    %eax
  sbb    %eax,%eax
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string

tool: D14: high

tool: D17: medium

tool: D13: low

assistant: ```c
int BotMovementAutonomyForString(char *string) {
  if (!Q_stricmp(string, "high")) {
    return 2;
  } else if (!Q_stricmp(string, "medium")) {
    return 1;
  } else if (!Q_stricmp(string, "low")) {
    return 0;
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BotMovementAutonomyForString>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rsi
  mov    %rdi,%rbp
  call   <Q_stricmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L15
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <Q_stricmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L14
L15:
  pop    %rbp
  ret
  nop
L14:
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <Q_stricmp@plt>
  pop    %rbp
  neg    %eax
  sbb    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D12: high

tool: D16: medium

tool: D2: low

assistant: ```c
int BotMovementAutonomyForString(char *string) {
  if (!Q_stricmp(string, "high")) {
    return 2;
  } else if (!Q_stricmp(string, "medium")) {
    return 1;
  } else if (!Q_stricmp(string, "low")) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BotMovementAutonomyForString>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rsi
  mov    %rdi,%rbp
  call   <Q_stricmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L0
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <Q_stricmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L8
L0:
  pop    %rbp
  ret
  nop
L8:
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <Q_stricmp@plt>
  pop    %rbp
  neg    %eax
  sbb    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string

tool: D16: high

tool: D21: medium

tool: D11: low

assistant: ```c
int BotMovementAutonomyForString(char *string) {
  if (!Q_stricmp(string, "high")) {
    return 2;
  } else if (!Q_stricmp(string, "medium")) {
    return 1;
  } else if (!Q_stricmp(string, "low")) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sunDeclination>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x1,%edi
  call   <atan@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x1,%edi
  call   <atan@plt>
  shl    $0x3,%eax
  movslq %eax,%rdx
  imul   $0xffffffffb38cf9b1,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x8,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    $0xac,%eax
  sub    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edi
  call   <cos@plt>
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: byte[8]
name: unpack_data
arguments: data_label: D11
datatype: byte[8]

tool: {"D9": [0x33,0x33,0x33,0x33,0x33,0x73,0x57,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void sunDeclination(double *delta, int day) {
  *delta = ((23.45 * 4 * atan(1)) / 180) * cos(((2 * 4 * atan(1)) / 365) * (172 - day));
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sunDeclination>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    $0x1,%edi
  call   <atan@plt>
  mov    %eax,%ebp
  mov    $0x1,%edi
  call   <atan@plt>
  shl    $0x3,%eax
  movslq %eax,%rdi
  imul   $0xffffffffb38cf9b1,%rdi,%rdi
  shr    $0x20,%rdi
  add    %eax,%edi
  sar    $0x8,%edi
  sar    $0x1f,%eax
  sub    %eax,%edi
  mov    $0xac,%eax
  sub    %r12d,%eax
  imul   %eax,%edi
  call   <cos@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D4(%rip),%xmm0
  divsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D10
type_infered: byte[8]

tool: {"D4": [0x33,0x33,0x33,0x33,0x33,0x73,0x57,0x40]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void sunDeclination(double *delta, int day) {
  *delta = ((23.45 * 4 * atan(1)) / 180) * cos(((2 * 4 * atan(1)) / 365) * (172 - day));
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sunDeclination>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <atan@plt>
  mov    $0x1,%edi
  mov    %eax,%ebp
  call   <atan@plt>
  shl    $0x3,%eax
  movslq %eax,%rdi
  imul   $0xffffffffb38cf9b1,%rdi,%rdi
  shr    $0x20,%rdi
  add    %eax,%edi
  sar    $0x1f,%eax
  sar    $0x8,%edi
  sub    %eax,%edi
  mov    $0xac,%eax
  sub    %r12d,%eax
  imul   %eax,%edi
  call   <cos@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D7(%rip),%xmm0
  divsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: byte[8]
name: retrieve_data
arguments: tag: D12
type_infered: byte[8]

tool: {"D7": [0x33,0x33,0x33,0x33,0x33,0x73,0x57,0x40]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void sunDeclination(double *delta, int day) {
  *delta = ((23.45 * 4 * atan(1)) / 180) * cos(((2 * 4 * atan(1)) / 365) * (172 - day));
  return;
}
```