ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ex4>:
  endbr64
  push   %rbp
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <charIn@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rdi
  mov    $0x1,%esi
  call   <charIn@plt>
  movsbl 0x7(%rsp),%edx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <findElem@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D6
type: string

tool: D10: Digita uma frase: 

tool: D6: O que deseja procurar: 

assistant: ```c
void ex4() {
  int MAX_SIZE = 256;
  char *phrase = malloc(MAX_SIZE), alone;
  printf("Digita uma frase: ");
  charIn(phrase, MAX_SIZE);
  printf("O que deseja procurar: ");
  charIn(&alone, 1);
  findElem(phrase, MAX_SIZE, alone);
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search_iter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L40
L45:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L48
  mov    -0x4(%rbp),%eax
  jmp    L47
L48:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L40
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L45
  mov    $0xffffffff,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search_iter(int *arr, int n, int value) {
  int low = 0;
  int high = n;
  int mid;
  while (low != high) {
    mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      low = mid + 1;
    } else {
      high = mid;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binary_search_iter>:
  endbr64
  mov    $0x0,%r8d
L18:
  cmp    %esi,%r8d
  je     L16
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L19
  jl     L25
  mov    %eax,%esi
  jmp    L18
L25:
  lea    0x1(%rax),%r8d
  jmp    L18
L16:
  mov    $0xffffffff,%r9d
L19:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int binary_search_iter(int *arr, int n, int value) {
  int low = 0;
  int high = n;
  int mid;
  while (low != high) {
    mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      low = mid + 1;
    } else {
      high = mid;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary_search_iter>:
  endbr64
  xor    %r8d,%r8d
  jmp    L9
  nopl   0x0(%rax)
L3:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    %eax,%r9d
  cmp    %edx,(%rdi,%rcx,4)
  je     L25
  jl     L28
  mov    %eax,%esi
L9:
  cmp    %esi,%r8d
  jne    L3
  mov    $0xffffffff,%r9d
L25:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    0x1(%rax),%r8d
  jmp    L9
```

assistant: ```c
int binary_search_iter(int *arr, int n, int value) {
  int low = 0;
  int high = n;
  int mid;
  while (low != high) {
    mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      low = mid + 1;
    } else {
      high = mid;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_search_iter>:
  endbr64
  xor    %r8d,%r8d
  jmp    L48
  nopl   0x0(%rax)
L34:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    %eax,%r9d
  cmp    %edx,(%rdi,%rcx,4)
  je     L2
  jl     L18
  mov    %eax,%esi
L48:
  cmp    %esi,%r8d
  jne    L34
  mov    $0xffffffff,%r9d
L2:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  lea    0x1(%rax),%r8d
  jmp    L48
```

assistant: ```c
int binary_search_iter(int *arr, int n, int value) {
  int low = 0;
  int high = n;
  int mid;
  while (low != high) {
    mid = (low + high) / 2;
    if (value == arr[mid]) {
      return mid;
    } else if (arr[mid] < value) {
      low = mid + 1;
    } else {
      high = mid;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen_QUIT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_QUIT@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_QUIT() {
  handle_QUIT(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gen_QUIT>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_QUIT@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_QUIT() {
  handle_QUIT(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_QUIT>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_QUIT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_QUIT() {
  handle_QUIT(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gen_QUIT>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_QUIT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_QUIT() {
  handle_QUIT(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tds7_crypt_pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  or     %ecx,%eax
  xor    $0xffffffa5,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L17
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *tds7_crypt_pass(const unsigned char *clear_pass, size_t len, unsigned char *crypt_pass) {
  size_t i;
  for (i = 0; i < len; i++)
    crypt_pass[i] = ((clear_pass[i] << 4) | (clear_pass[i] >> 4)) ^ 0xA5;
  return crypt_pass;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tds7_crypt_pass>:
  endbr64
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L6
  mov    $0x0,%r8d
L18:
  movzbl (%rdi,%r8,1),%ecx
  rol    $0x4,%cl
  xor    $0xffffffa5,%ecx
  mov    %cl,(%rax,%r8,1)
  add    $0x1,%r8
  cmp    %r8,%rsi
  jne    L18
L6:
  ret
```

assistant: ```c
unsigned char *tds7_crypt_pass(const unsigned char *clear_pass, size_t len, unsigned char *crypt_pass) {
  size_t i;
  for (i = 0; i < len; i++)
    crypt_pass[i] = ((clear_pass[i] << 4) | (clear_pass[i] >> 4)) ^ 0xA5;
  return crypt_pass;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tds7_crypt_pass>:
  endbr64
  mov    %rdx,%rax
  test   %rsi,%rsi
  je     L13
  xor    %r8d,%r8d
  nop
L6:
  movzbl (%rdi,%r8,1),%ecx
  rol    $0x4,%cl
  xor    $0xffffffa5,%ecx
  mov    %cl,(%rax,%r8,1)
  add    $0x1,%r8
  cmp    %r8,%rsi
  jne    L6
L13:
  ret
```

assistant: ```c
unsigned char *tds7_crypt_pass(const unsigned char *clear_pass, size_t len, unsigned char *crypt_pass) {
  size_t i;
  for (i = 0; i < len; i++)
    crypt_pass[i] = ((clear_pass[i] << 4) | (clear_pass[i] >> 4)) ^ 0xA5;
  return crypt_pass;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mus_char_to_uninterpreted_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  mov    -0x10(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int mus_char_to_uninterpreted_int(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mus_char_to_uninterpreted_int>:
  endbr64
  mov    $0x0,%eax
  mov    (%rdi),%al
  movzbl 0x1(%rdi),%edx
  mov    %dl,%ah
  movzbl 0x2(%rdi),%ecx
  shl    $0x10,%ecx
  movzwl %ax,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int mus_char_to_uninterpreted_int(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mus_char_to_uninterpreted_int>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int mus_char_to_uninterpreted_int(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mus_char_to_uninterpreted_int>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int mus_char_to_uninterpreted_int(const unsigned char *inp) {
  int o;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  outp[0] = inp[0];
  outp[1] = inp[1];
  outp[2] = inp[2];
  outp[3] = inp[3];
  return (o);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L69
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L56:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L56
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L5
L69:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L63
L66:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <repeat@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <helper>
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  jmp    L19
L4:
  nop
L19:
  addl   $0x1,-0x8(%rbp)
L63:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L66
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: %d 

assistant: ```c
void helper(int nums[], const int size, const int start) {
  int i, j;
  if (start == size) {
    for (j = 0; j < size; ++j) {
      printf("%d ", nums[j]);
    }
    printf("\n");
    return;
  }
  for (i = start; i < size; ++i) {
    if (repeat(nums, start, i))
      continue;
    swap(&(nums[start]), &(nums[i]));
    helper(nums, size, start + 1);
    swap(&(nums[i]), &(nums[start]));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  cmp    %esi,%edx
  je     L61
  mov    %edx,%ebp
  jge    L77
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r15
  mov    %r15,%r13
  mov    %edx,%ebx
  lea    0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  jmp    L76
L61:
  test   %esi,%esi
  jle    L75
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D6(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
L75:
  mov    $0xa,%edi
  call   <putchar@plt>
L77:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    %ebx,%r12d
  je     L77
L76:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <repeat@plt>
  test   %rax,%rax
  jne    L55
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <helper>
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L55
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: %d 

assistant: ```c
void helper(int nums[], const int size, const int start) {
  int i, j;
  if (start == size) {
    for (j = 0; j < size; ++j) {
      printf("%d ", nums[j]);
    }
    printf("\n");
    return;
  }
  for (i = start; i < size; ++i) {
    if (repeat(nums, start, i))
      continue;
    swap(&(nums[start]), &(nums[i]));
    helper(nums, size, start + 1);
    swap(&(nums[i]), &(nums[start]));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<helper>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  cmp    %esi,%edx
  je     L45
  jge    L58
  movslq %edx,%rax
  mov    %esi,%r13d
  mov    %edx,%ebp
  lea    (%rdi,%rax,4),%r14
  lea    0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  mov    %r14,%r12
L29:
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <repeat@plt>
  test   %rax,%rax
  jne    L51
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <helper>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
L51:
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    %ebp,%r13d
  jne    L29
L58:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  test   %edx,%edx
  jle    L26
  lea    -0x1(%rdx),%eax
  lea    D6(%rip),%rbp
  lea    0x4(%rdi,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L39
L26:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6: %d 

assistant: ```c
void helper(int nums[], const int size, const int start) {
  int i, j;
  if (start == size) {
    for (j = 0; j < size; ++j) {
      printf("%d ", nums[j]);
    }
    printf("\n");
    return;
  }
  for (i = start; i < size; ++i) {
    if (repeat(nums, start, i))
      continue;
    swap(&(nums[start]), &(nums[i]));
    helper(nums, size, start + 1);
    swap(&(nums[i]), &(nums[start]));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<helper>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  cmp    %esi,%edx
  je     L26
  jge    L24
  movslq %edx,%rax
  mov    %esi,%r13d
  mov    %edx,%ebp
  lea    (%rdi,%rax,4),%r14
  lea    0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  mov    %r14,%r12
L41:
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <repeat@plt>
  test   %rax,%rax
  jne    L37
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <helper>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
L37:
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    %ebp,%r13d
  jne    L41
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  test   %edx,%edx
  jle    L2
  lea    -0x1(%rdx),%eax
  lea    D6(%rip),%rbp
  lea    0x4(%rdi,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L45:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L45
L2:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: %d 

assistant: ```c
void helper(int nums[], const int size, const int start) {
  int i, j;
  if (start == size) {
    for (j = 0; j < size; ++j) {
      printf("%d ", nums[j]);
    }
    printf("\n");
    return;
  }
  for (i = start; i < size; ++i) {
    if (repeat(nums, start, i))
      continue;
    swap(&(nums[start]), &(nums[i]));
    helper(nums, size, start + 1);
    swap(&(nums[i]), &(nums[start]));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toml_rtoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L151
  mov    %rsi,%rbx
  lea    0x4(%rsp),%rax
  test   %rsi,%rsi
  cmove  %rax,%rbx
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L158
  lea    0x10(%rsp),%rdx
  cmp    $0x2d,%al
  je     L25
L164:
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  je     L80
  lea    0x74(%rsp),%rsi
  test   %al,%al
  jne    L213
  jmp    L169
L158:
  add    $0x1,%rdi
  movb   $0x2b,0x10(%rsp)
  lea    0x11(%rsp),%rdx
  jmp    L164
L25:
  add    $0x1,%rdi
  movb   $0x2d,0x10(%rsp)
  lea    0x11(%rsp),%rdx
  jmp    L164
L80:
  cmpb   $0x0,0x1(%rdi)
  jne    L155
  movl   $0x0,(%rbx)
  mov    $0x0,%eax
  jmp    L11
L207:
  movzbl (%rdi),%eax
  test   %al,%al
  setne  %cl
  cmp    %rsi,%rdx
  jae    L193
  test   %cl,%cl
  je     L193
L213:
  add    $0x1,%rdi
  cmp    $0x5f,%al
  je     L207
  mov    %al,(%rdx)
  lea    0x1(%rdx),%rdx
  jmp    L207
L193:
  lea    0x74(%rsp),%rax
  cmp    %rax,%rdx
  je     L161
  test   %cl,%cl
  jne    L161
L169:
  movb   $0x0,(%rdx)
  mov    D0(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x0,%edx
  call   <strtoll@plt>
  mov    %eax,(%rbx)
  cmpq   $0x0,0x0(%rbp)
  jne    L40
  mov    0x8(%rsp),%rax
  movzbl (%rax),%eax
  neg    %al
  sbb    %eax,%eax
L11:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L116
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L151:
  mov    $0xffffffff,%eax
  jmp    L11
L155:
  mov    $0xffffffff,%eax
  jmp    L11
L161:
  mov    $0xffffffff,%eax
  jmp    L11
L40:
  mov    $0xffffffff,%eax
  jmp    L11
L116:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toml_rtoi(const char *src, int64_t *ret_) {
  if (!src)
    return -1;
  char buf[100];
  char *p = buf;
  char *q = p + sizeof(buf);
  const char *s = src;
  int64_t dummy;
  int64_t *ret = ret_ ? ret_ : &dummy;
  if (*s == '+')
    *p++ = *s++;
  else if (*s == '-')
    *p++ = *s++;
  if ('0' == s[0]) {
    if (s[1])
      return -1;
    return *ret = 0, 0;
  }
  while (*s && p < q) {
    int ch = *s++;
    if (ch == '_')
      ;
    else
      *p++ = ch;
  }
  if (*s || p == q)
    return -1;
  *p = 0;
  char *endp;
  errno = 0;
  *ret = strtoll(buf, &endp, 0);
  return (errno || *endp) ? -1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toml_rtoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L108
  lea    0x4(%rsp),%rax
  mov    %rsi,%rbx
  test   %rsi,%rsi
  cmove  %rax,%rbx
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L109
  lea    0x10(%rsp),%rdx
  cmp    $0x2d,%al
  je     L97
L0:
  cmp    $0x30,%al
  je     L166
L61:
  lea    0x74(%rsp),%rcx
  test   %al,%al
  jne    L20
  jmp    L130
L1:
  cmp    %rcx,%rdx
  jae    L108
L20:
  add    $0x1,%rdi
  cmp    $0x5f,%al
  je     L123
  mov    %al,(%rdx)
  add    $0x1,%rdx
L123:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
  cmp    %rcx,%rdx
  je     L108
L130:
  movb   $0x0,(%rdx)
  mov    D0(%rip),%rbp
  xor    %edx,%edx
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movq   $0x0,0x0(%rbp)
  call   <strtoll@plt>
  cmpq   $0x0,0x0(%rbp)
  mov    %eax,(%rbx)
  jne    L108
  mov    0x8(%rsp),%rax
  movzbl (%rax),%eax
  neg    %al
  sbb    %eax,%eax
L86:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L97:
  movzbl 0x1(%rdi),%eax
  movb   $0x2d,0x10(%rsp)
  add    $0x1,%rdi
  lea    0x11(%rsp),%rdx
  cmp    $0x30,%al
  jne    L61
L166:
  cmpb   $0x0,0x1(%rdi)
  jne    L108
  movl   $0x0,(%rbx)
  xor    %eax,%eax
  jmp    L86
  nopw   0x0(%rax,%rax,1)
L108:
  mov    $0xffffffff,%eax
  jmp    L86
  nopw   0x0(%rax,%rax,1)
L109:
  movzbl 0x1(%rdi),%eax
  movb   $0x2b,0x10(%rsp)
  add    $0x1,%rdi
  lea    0x11(%rsp),%rdx
  jmp    L0
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toml_rtoi(const char *src, int64_t *ret_) {
  if (!src)
    return -1;
  char buf[100];
  char *p = buf;
  char *q = p + sizeof(buf);
  const char *s = src;
  int64_t dummy;
  int64_t *ret = ret_ ? ret_ : &dummy;
  if (*s == '+')
    *p++ = *s++;
  else if (*s == '-')
    *p++ = *s++;
  if ('0' == s[0]) {
    if (s[1])
      return -1;
    return *ret = 0, 0;
  }
  while (*s && p < q) {
    int ch = *s++;
    if (ch == '_')
      ;
    else
      *p++ = ch;
  }
  if (*s || p == q)
    return -1;
  *p = 0;
  char *endp;
  errno = 0;
  *ret = strtoll(buf, &endp, 0);
  return (errno || *endp) ? -1 : 0;
}
```