ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<xmalloc_aligned>:
  endbr64
  push   %r13
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
L8:
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  call   <posix_memalign@plt>
  test   %eax,%eax
  je     L44
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <panic@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbp
  pop    %r13
  ret
L44:
  mov    0x10(%rsp),%r13
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D19(%rip),%rdi
  mov    %rsi,0x8(%rsp)
  call   <panic@plt>
  mov    0x8(%rsp),%rsi
  jmp    L8
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D10: xmalloc_aligned: out of memory (allocating %zu bytes)


tool: D19: xmalloc_aligned: zero size


assistant: ```c
__attribute__((visibility("hidden"))) void *xmalloc_aligned(size_t size, size_t alignment) {
  int ret;
  void *ptr;
  if (size == 0)
    panic("xmalloc_aligned: zero size\n");
  ret = posix_memalign(&ptr, alignment, size);
  if (ret != 0)
    panic("xmalloc_aligned: out of memory (allocating %zu bytes)\n", size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L10:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L10
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float mac(const float *a, const float *b, unsigned int size) {
  float sum = 0;
  unsigned int i;
  for (i = 0; i < size; i++)
    sum += (*a++) * (*b++);
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mac>:
  endbr64
  test   %edx,%edx
  je     L5
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L26:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
L28:
  movaps %xmm1,%xmm0
  ret
L5:
  pxor   %xmm1,%xmm1
  jmp    L28
```

assistant: ```c
float mac(const float *a, const float *b, unsigned int size) {
  float sum = 0;
  unsigned int i;
  for (i = 0; i < size; i++)
    sum += (*a++) * (*b++);
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mac>:
  endbr64
  test   %edx,%edx
  je     L4
  mov    %edx,%edx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L15:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L15
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float mac(const float *a, const float *b, unsigned int size) {
  float sum = 0;
  unsigned int i;
  for (i = 0; i < size; i++)
    sum += (*a++) * (*b++);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mac>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  je     L68
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L38
  mov    %edx,%edi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L59:
  movups (%rcx,%rax,1),%xmm1
  movups (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulps  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L59
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edi
  shl    $0x2,%rdi
  add    %rdi,%rcx
  add    %rdi,%rsi
  cmp    %eax,%edx
  je     L20
L29:
  movss  (%rcx),%xmm1
  mulss  (%rsi),%xmm1
  lea    0x1(%rax),%edi
  addss  %xmm1,%xmm0
  cmp    %edi,%edx
  jbe    L1
  movss  0x4(%rcx),%xmm1
  mulss  0x4(%rsi),%xmm1
  add    $0x2,%eax
  addss  %xmm1,%xmm0
  cmp    %eax,%edx
  jbe    L1
  movss  0x8(%rsi),%xmm1
  mulss  0x8(%rcx),%xmm1
  addss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L68:
  pxor   %xmm0,%xmm0
L1:
  ret
  nopl   (%rax)
L20:
  ret
L38:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L29
```

assistant: ```c
float mac(const float *a, const float *b, unsigned int size) {
  float sum = 0;
  unsigned int i;
  for (i = 0; i < size; i++)
    sum += (*a++) * (*b++);
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x5c(%rbp)
  jmp    L52
L50:
  lea    -0x50(%rbp),%rdx
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x5c(%rbp)
  jne    L14
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  jmp    L17
L14:
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  cmp    %eax,-0x58(%rbp)
  jge    L45
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,-0x58(%rbp)
L45:
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  cmp    %eax,-0x54(%rbp)
  jle    L17
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,-0x54(%rbp)
L17:
  addl   $0x1,-0x5c(%rbp)
L52:
  cmpl   $0xe,-0x5c(%rbp)
  jle    L50
  mov    -0x58(%rbp),%edx
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string

tool: D19: %d

tool: D24: %d %d

tool: D22: pause

assistant: ```c
main() {
  int v[16], i, maior, menor, x;
  for (i = 0; i < 15; ++i) {
    scanf("%d", &v[i]);
    if (i == 0) {
      maior = v[0];
      menor = v[0];
    } else {
      if (v[i] > maior) {
        maior = v[i];
      }
      if (v[i] < menor) {
        menor = v[i];
      }
    }
  }
  printf("%d %d", menor, maior);
  system("pause");
  getch();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x1,%ebx
  lea    D26(%rip),%r14
  jmp    L0
L13:
  mov    (%rsp),%r12d
  mov    %r12d,%r13d
L31:
  add    $0x4,%rbp
  add    $0x1,%ebx
L0:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmp    $0x1,%ebx
  je     L13
  mov    0x0(%rbp),%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  cmp    $0xe,%ebx
  jle    L31
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string

tool: D26: %d

tool: D24: %d %d

tool: D21: pause

assistant: ```c
main() {
  int v[16], i, maior, menor, x;
  for (i = 0; i < 15; ++i) {
    scanf("%d", &v[i]);
    if (i == 0) {
      maior = v[0];
      menor = v[0];
    } else {
      if (v[i] > maior) {
        maior = v[i];
      }
      if (v[i] < menor) {
        menor = v[i];
      }
    }
  }
  printf("%d %d", menor, maior);
  system("pause");
  getch();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L49
  xchg   %ax,%ax
L35:
  mov    0x0(%rbp),%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  cmp    $0xf,%ebx
  je     L37
L21:
  add    $0x4,%rbp
L49:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    $0x1,%ebx
  jne    L35
  mov    (%rsp),%r12d
  mov    %r12d,%r13d
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D25
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D28: %d

tool: D25: %d %d

tool: D4: pause

assistant: ```c
main() {
  int v[16], i, maior, menor, x;
  for (i = 0; i < 15; ++i) {
    scanf("%d", &v[i]);
    if (i == 0) {
      maior = v[0];
      menor = v[0];
    } else {
      if (v[i] > maior) {
        maior = v[i];
      }
      if (v[i] < menor) {
        menor = v[i];
      }
    }
  }
  printf("%d %d", menor, maior);
  system("pause");
  getch();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L7
  xchg   %ax,%ax
L32:
  mov    0x0(%rbp),%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  cmp    $0xf,%ebx
  je     L16
L2:
  add    $0x4,%rbp
L7:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    $0x1,%ebx
  jne    L32
  mov    (%rsp),%r12d
  mov    %r12d,%r13d
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %r12d,%edx
  mov    %r13d,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D8: %d

tool: D22: %d %d

tool: D0: pause

assistant: ```c
main() {
  int v[16], i, maior, menor, x;
  for (i = 0; i < 15; ++i) {
    scanf("%d", &v[i]);
    if (i == 0) {
      maior = v[0];
      menor = v[0];
    } else {
      if (v[i] > maior) {
        maior = v[i];
      }
      if (v[i] < menor) {
        menor = v[i];
      }
    }
  }
  printf("%d %d", menor, maior);
  system("pause");
  getch();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x10,-0x24(%rbp)
  movl   $0x10,-0x20(%rbp)
  movl   $0x10,-0x1c(%rbp)
  movl   $0x3,-0x40(%rbp)
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L36:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L38:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L40
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L40:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L2
L17:
  mov    -0x30(%rbp),%rax
  mov    -0x44(%rbp),%edx
  movslq %edx,%rdx
  movl   $0x0,(%rax,%rdx,4)
  addl   $0x1,-0x44(%rbp)
L2:
  mov    -0x44(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L17
  mov    -0x40(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  lea    -0x24(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <get_ops@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: ops required %d

assistant: ```c
void main() {
  int a[] = {16, 16, 16};
  int len = sizeof(a) / sizeof(a[0]);
  int start[len];
  for (int i = 0; i < len; i++) {
    start[i] = 0;
  }
  int res = get_ops(a, start, len, 0, 0);
  printf("ops required %d", res);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x10,(%rsp)
  movl   $0x10,0x4(%rsp)
  movl   $0x10,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x3,%edx
  call   <get_ops@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: ops required %d

assistant: ```c
void main() {
  int a[] = {16, 16, 16};
  int len = sizeof(a) / sizeof(a[0]);
  int start[len];
  for (int i = 0; i < len; i++) {
    start[i] = 0;
  }
  int res = get_ops(a, start, len, 0, 0);
  printf("ops required %d", res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1000000010,%rax
  lea    0xc(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x10,0x8(%rsp)
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    %rax,(%rsp)
  call   <get_ops@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: ops required %d

assistant: ```c
void main() {
  int a[] = {16, 16, 16};
  int len = sizeof(a) / sizeof(a[0]);
  int start[len];
  for (int i = 0; i < len; i++) {
    start[i] = 0;
  }
  int res = get_ops(a, start, len, 0, 0);
  printf("ops required %d", res);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  lea    0x18(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movl   $0x10,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x20(%rsp)
  call   <get_ops@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
datatype: byte[8]
name: read_data
arguments: data_label: D17
datatype: string

tool: {"D11": [0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: D17: ops required %d

assistant: ```c
void main() {
  int a[] = {16, 16, 16};
  int len = sizeof(a) / sizeof(a[0]);
  int start[len];
  for (int i = 0; i < len; i++) {
    start[i] = 0;
  }
  int res = get_ops(a, start, len, 0, 0);
  printf("ops required %d", res);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strreplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  cmpq   $0x0,-0x20(%rbp)
  je     L4
  cmpq   $0x0,-0x28(%rbp)
  je     L4
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpos@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L13
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <strdel@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strinsert@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpos@plt>
  mov    %eax,-0x8(%rbp)
L13:
  cmpl   $0x0,-0x8(%rbp)
  jns    L10
L4:
  nop
  leave
  ret
```

assistant: ```c
void strreplace(char cadena1[], const char cadena2[], const char cadena3[]) {
  if (cadena1 != NULL && cadena2 != NULL && cadena3 != NULL) {
    unsigned int tamCad2 = strlen(cadena2);
    int pos = strpos(cadena1, cadena2);
    while (pos >= 0) {
      strdel(cadena1, pos, tamCad2);
      strinsert(cadena3, cadena1, pos);
      pos = strpos(cadena1, cadena2);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strreplace>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rsi,%rsi
  setne  %dl
  test   %r13,%r13
  setne  %al
  test   %al,%dl
  je     L24
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rdi,%rdi
  jne    L49
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strpos@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L24
L26:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <strdel@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strinsert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strpos@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L26
  jmp    L24
```

assistant: ```c
void strreplace(char cadena1[], const char cadena2[], const char cadena3[]) {
  if (cadena1 != NULL && cadena2 != NULL && cadena3 != NULL) {
    unsigned int tamCad2 = strlen(cadena2);
    int pos = strpos(cadena1, cadena2);
    while (pos >= 0) {
      strdel(cadena1, pos, tamCad2);
      strinsert(cadena3, cadena1, pos);
      pos = strpos(cadena1, cadena2);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strreplace>:
  endbr64
  push   %r14
  test   %rsi,%rsi
  push   %r13
  mov    %rdx,%r13
  setne  %dl
  test   %r13,%r13
  push   %r12
  setne  %al
  push   %rbp
  push   %rbx
  test   %al,%dl
  je     L23
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L10
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r14d
  jmp    L22
L35:
  mov    %r14d,%edx
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <strdel@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strinsert@plt>
L22:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strpos@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L35
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strreplace(char cadena1[], const char cadena2[], const char cadena3[]) {
  if (cadena1 != NULL && cadena2 != NULL && cadena3 != NULL) {
    unsigned int tamCad2 = strlen(cadena2);
    int pos = strpos(cadena1, cadena2);
    while (pos >= 0) {
      strdel(cadena1, pos, tamCad2);
      strinsert(cadena3, cadena1, pos);
      pos = strpos(cadena1, cadena2);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strreplace>:
  endbr64
  push   %r14
  test   %rsi,%rsi
  push   %r13
  mov    %rdx,%r13
  setne  %dl
  test   %r13,%r13
  push   %r12
  setne  %al
  push   %rbp
  push   %rbx
  test   %al,%dl
  je     L10
  mov    %rdi,%rbx
  test   %rdi,%rdi
  jne    L17
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r14d
  jmp    L23
L38:
  mov    %r14d,%edx
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <strdel@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strinsert@plt>
L23:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strpos@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L38
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strreplace(char cadena1[], const char cadena2[], const char cadena3[]) {
  if (cadena1 != NULL && cadena2 != NULL && cadena3 != NULL) {
    unsigned int tamCad2 = strlen(cadena2);
    int pos = strpos(cadena1, cadena2);
    while (pos >= 0) {
      strdel(cadena1, pos, tamCad2);
      strinsert(cadena3, cadena1, pos);
      pos = strpos(cadena1, cadena2);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<addN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double addN(double *numbers, int size) {
  double sum = 0.0;
  for (int index = 0; index < size; index++) {
    sum += *(numbers + index);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addN>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L14:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
  ret
L13:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double addN(double *numbers, int size) {
  double sum = 0.0;
  for (int index = 0; index < size; index++) {
    sum += *(numbers + index);
  }
  return sum;
}
```