ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<getEnumWhoriz>:
  endbr64
  push   %r15
  mov    %edi,%edx
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %r14,%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L28
  mov    $0x1,%ebx
  mov    $0x3,%r15d
  xchg   %ax,%ax
L19:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r15d,%eax
  sub    %r8d,%eax
  mov    %eax,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L19
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int *getEnumWhoriz(int max) {
  int i;
  char buf[15];
  sprintf(buf, "%d", max);
  int *horizontalSpacingWidth = malloc(sizeof(int) * max);
  int tmp_width;
  const int sep = 3;
  for (i = 1; i <= max; i++) {
    sprintf(buf, "%d", i);
    tmp_width = strlen(buf);
    horizontalSpacingWidth[i] = sep - tmp_width;
  }
  return horizontalSpacingWidth;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getEnumWhoriz>:
  endbr64
  push   %r15
  mov    %edi,%edx
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  mov    %r14,%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L9
  mov    $0x1,%ebx
  mov    $0x3,%r15d
  xchg   %ax,%ax
L8:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r15d,%eax
  sub    %r8d,%eax
  mov    %eax,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L8
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %d

assistant: ```c
int *getEnumWhoriz(int max) {
  int i;
  char buf[15];
  sprintf(buf, "%d", max);
  int *horizontalSpacingWidth = malloc(sizeof(int) * max);
  int tmp_width;
  const int sep = 3;
  for (i = 1; i <= max; i++) {
    sprintf(buf, "%d", i);
    tmp_width = strlen(buf);
    horizontalSpacingWidth[i] = sep - tmp_width;
  }
  return horizontalSpacingWidth;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tmpfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  errno = ENOSYS;
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tmpfile>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  errno = ENOSYS;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tmpfile>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  errno = ENOSYS;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tmpfile>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  errno = ENOSYS;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x28(%rbp),%r8
  lea    -0x20(%rbp),%rdi
  lea    -0x2c(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x1c(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  add    $0x10,%rsp
  mov    -0x20(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <slope@plt>
  mov    %rax,%rbx
  mov    -0x1c(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <slope@plt>
  cmp    %rax,%rbx
  jne    L25
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L26
L25:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L26:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D36
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string

tool: D4: Enter three point as x and y one after the other

tool: D33: %d %d %d %d %d %d

tool: D36: The points lie on the same line.

tool: D35: The points dont lie on same line.

assistant: ```c
int main() {
  int x1, x2, x3, y1, y2, y3;
  puts("Enter three point as x and y one after the other");
  scanf("%d %d %d %d %d %d", &x1, &y1, &x2, &y2, &x3, &y3);
  if (slope(x1, y1, x2, y2) == slope(x1, y1, x3, y3))
    puts("The points lie on the same line.");
  else
    puts("The points dont lie on same line.");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x20(%rsp),%r8
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <slope@plt>
  mov    %rax,%rbx
  mov    0x24(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <slope@plt>
  add    $0x10,%rsp
  cmp    %rax,%rbx
  je     L18
  lea    D24(%rip),%rdi
  call   <puts@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L18:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string
name: retrieve_data
arguments: data_tag: D24
data_type: string
name: retrieve_data
arguments: data_tag: D32
data_type: string

tool: D35: Enter three point as x and y one after the other

tool: D12: %d %d %d %d %d %d

tool: D24: The points dont lie on same line.

tool: D32: The points lie on the same line.

assistant: ```c
int main() {
  int x1, x2, x3, y1, y2, y3;
  puts("Enter three point as x and y one after the other");
  scanf("%d %d %d %d %d %d", &x1, &y1, &x2, &y2, &x3, &y3);
  if (slope(x1, y1, x2, y2) == slope(x1, y1, x3, y3))
    puts("The points lie on the same line.");
  else
    puts("The points dont lie on same line.");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdx
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  mov    0x20(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <slope@plt>
  mov    0x24(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  mov    %rax,%rbx
  call   <slope@plt>
  pop    %rdx
  pop    %rcx
  cmp    %rax,%rbx
  je     L26
  lea    D0(%rip),%rdi
  call   <puts@plt>
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L26:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D4: Enter three point as x and y one after the other

tool: D19: %d %d %d %d %d %d

tool: D0: The points dont lie on same line.

tool: D12: The points lie on the same line.

assistant: ```c
int main() {
  int x1, x2, x3, y1, y2, y3;
  puts("Enter three point as x and y one after the other");
  scanf("%d %d %d %d %d %d", &x1, &y1, &x2, &y2, &x3, &y3);
  if (slope(x1, y1, x2, y2) == slope(x1, y1, x3, y3))
    puts("The points lie on the same line.");
  else
    puts("The points dont lie on same line.");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdx
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  mov    0x20(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <slope@plt>
  mov    0x24(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    0x10(%rsp),%edi
  mov    %rax,%rbx
  call   <slope@plt>
  pop    %rdx
  pop    %rcx
  cmp    %rax,%rbx
  je     L3
  lea    D31(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
data_type: string
name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D31
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D12: Enter three point as x and y one after the other

tool: D28: %d %d %d %d %d %d

tool: D31: The points dont lie on same line.

tool: D3: The points lie on the same line.

assistant: ```c
int main() {
  int x1, x2, x3, y1, y2, y3;
  puts("Enter three point as x and y one after the other");
  scanf("%d %d %d %d %d %d", &x1, &y1, &x2, &y2, &x3, &y3);
  if (slope(x1, y1, x2, y2) == slope(x1, y1, x3, y3))
    puts("The points lie on the same line.");
  else
    puts("The points dont lie on same line.");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L82:
  mov    -0x74(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <rspeak@plt>
L107:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gets@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <trim@plt>
  movzbl -0x60(%rbp),%eax
  test   %al,%al
  je     L60
  movzbl -0x60(%rbp),%eax
  mov    %al,-0x61(%rbp)
  cmpb   $0x79,-0x61(%rbp)
  je     L45
  cmpb   $0x59,-0x61(%rbp)
  jne    L76
L45:
  movl   $0x1,-0x74(%rbp)
  jmp    L41
L76:
  cmpb   $0x6e,-0x61(%rbp)
  je     L93
  cmpb   $0x4e,-0x61(%rbp)
  jne    L92
L93:
  movl   $0x0,-0x74(%rbp)
  jmp    L41
L92:
  mov    $0x28,%edi
  mov    $0x0,%eax
  call   <rspeak@plt>
  jmp    L107
L41:
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  jmp    L13
L60:
  nop
  cmpl   $0x16,-0x74(%rbp)
  je     L82
  mov    $0x16,%edi
  mov    $0x0,%eax
  call   <yes>
  test   %eax,%eax
  je     L82
  mov    $0x0,%edi
  call   <exit@plt>
L13:
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
yes(x) int x;
{
  char c, c1;
  char s[80];
beg:
  rspeak(x);
  for (;;) {
    gets(s);
    trim(s);
    if (s[0] == 0)
      goto quit;
    c = s[0];
    if (c == 'y' || c == 'Y' || c == 'д' || c == 'Д') {
      x = 1;
      break;
    } else if (c == 'n' || c == 'N' || c == 'н' || c == 'Н') {
      x = 0;
      break;
    } else {
      rspeak(40);
    }
  }
  return (x);
quit:
  if (x != 22 && yes(22))
    exit(0);
  goto beg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L11:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <rspeak@plt>
L1:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <gets@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <trim@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L116
  cmp    $0x6e,%al
  je     L33
  cmp    $0x6e,%al
  jg     L117
  cmp    $0x4e,%al
  je     L6
  cmp    $0x59,%al
  jne    L31
  mov    $0x1,%eax
L8:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L104
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L116:
  cmp    $0x16,%ebx
  je     L11
  mov    $0x16,%edi
  mov    $0x0,%eax
  call   <yes>
  test   %eax,%eax
  je     L11
  mov    $0x0,%edi
  call   <exit@plt>
L117:
  cmp    $0x79,%al
  je     L3
L31:
  mov    $0x28,%edi
  mov    $0x0,%eax
  call   <rspeak@plt>
  jmp    L1
L33:
  mov    $0x0,%eax
  jmp    L8
L6:
  mov    $0x0,%eax
  jmp    L8
L3:
  mov    $0x1,%eax
  jmp    L8
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
yes(x) int x;
{
  char c, c1;
  char s[80];
beg:
  rspeak(x);
  for (;;) {
    gets(s);
    trim(s);
    if (s[0] == 0)
      goto quit;
    c = s[0];
    if (c == 'y' || c == 'Y' || c == 'д' || c == 'Д') {
      x = 1;
      break;
    } else if (c == 'n' || c == 'N' || c == 'н' || c == 'Н') {
      x = 0;
      break;
    } else {
      rspeak(40);
    }
  }
  return (x);
quit:
  if (x != 22 && yes(22))
    exit(0);
  goto beg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<yes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L57:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <rspeak@plt>
L36:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <gets@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trim@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L18
  cmp    $0x6e,%al
  je     L60
  jg     L51
  cmp    $0x4e,%al
  je     L60
  cmp    $0x59,%al
  jne    L64
L35:
  mov    $0x1,%eax
L56:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L51:
  cmp    $0x79,%al
  je     L35
L64:
  mov    $0x28,%edi
  xor    %eax,%eax
  call   <rspeak@plt>
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L60:
  xor    %eax,%eax
  jmp    L56
  nopl   0x0(%rax)
L18:
  cmp    $0x16,%ebx
  je     L57
  xor    %eax,%eax
  mov    $0x16,%edi
  call   <yes>
  test   %eax,%eax
  je     L57
  xor    %edi,%edi
  call   <exit@plt>
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
yes(x) int x;
{
  char c, c1;
  char s[80];
beg:
  rspeak(x);
  for (;;) {
    gets(s);
    trim(s);
    if (s[0] == 0)
      goto quit;
    c = s[0];
    if (c == 'y' || c == 'Y' || c == 'д' || c == 'Д') {
      x = 1;
      break;
    } else if (c == 'n' || c == 'N' || c == 'н' || c == 'Н') {
      x = 0;
      break;
    } else {
      rspeak(40);
    }
  }
  return (x);
quit:
  if (x != 22 && yes(22))
    exit(0);
  goto beg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L78:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <rspeak@plt>
L17:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <gets@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <trim@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L39
  cmp    $0x6e,%al
  je     L60
  jg     L102
  cmp    $0x4e,%al
  je     L60
  cmp    $0x59,%al
  jne    L41
L44:
  mov    $0x1,%eax
L70:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L102:
  cmp    $0x79,%al
  je     L44
L41:
  mov    $0x28,%edi
  xor    %eax,%eax
  call   <rspeak@plt>
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L60:
  xor    %eax,%eax
  jmp    L70
  nopl   0x0(%rax)
L39:
  cmp    $0x16,%ebx
  je     L78
  xor    %eax,%eax
  mov    $0x16,%edi
  call   <yes>
  test   %eax,%eax
  je     L78
  xor    %edi,%edi
  call   <exit@plt>
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
yes(x) int x;
{
  char c, c1;
  char s[80];
beg:
  rspeak(x);
  for (;;) {
    gets(s);
    trim(s);
    if (s[0] == 0)
      goto quit;
    c = s[0];
    if (c == 'y' || c == 'Y' || c == 'д' || c == 'Д') {
      x = 1;
      break;
    } else if (c == 'n' || c == 'N' || c == 'н' || c == 'Н') {
      x = 0;
      break;
    } else {
      rspeak(40);
    }
  }
  return (x);
quit:
  if (x != 22 && yes(22))
    exit(0);
  goto beg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clk_enable_before>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D11: clk_enable_before

tool: D3: %s] :%s


assistant: ```c
int clk_enable_before(void *privdata) {
  printk("%s] :%s\n", __func__, privdata);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clk_enable_before>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D16(%rip),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D16: clk_enable_before

tool: D6: %s] :%s


assistant: ```c
int clk_enable_before(void *privdata) {
  printk("%s] :%s\n", __func__, privdata);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<clk_enable_before>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D13
datatype: string

tool: D9: clk_enable_before

tool: D13: %s] :%s


assistant: ```c
int clk_enable_before(void *privdata) {
  printk("%s] :%s\n", __func__, privdata);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clk_enable_before>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string

tool: D2: clk_enable_before

tool: D16: %s] :%s


assistant: ```c
int clk_enable_before(void *privdata) {
  printk("%s] :%s\n", __func__, privdata);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x120(%rbp)
  cmpq   $0x0,-0x120(%rbp)
  jne    L0
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L32
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L32
L31:
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
L32:
  mov    -0x120(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L31
  mov    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
data_type: string
name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D12
data_type: string

tool: D31: r

tool: D26: infile.txt

tool: D30: w

tool: D12: outfile.txt

assistant: ```c
int main(void) {
  FILE *src, *dst;
  char buf[256];
  if ((src = fopen("infile.txt", "r")) == NULL) {
    exit(1);
  }
  if ((dst = fopen("outfile.txt", "w")) == NULL) {
    exit(2);
  }
  while ((fgets(buf, 256, src)) != NULL) {
    fputs(buf, dst);
  }
  fclose(src);
  fclose(dst);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
L34:
  lea    D24(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L55:
  mov    %rsp,%rbx
  jmp    L14
L26:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
L13:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L55
L37:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
L14:
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L37
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string

tool: D8: r

tool: D19: infile.txt

tool: D24: w

tool: D27: outfile.txt

assistant: ```c
int main(void) {
  FILE *src, *dst;
  char buf[256];
  if ((src = fopen("infile.txt", "r")) == NULL) {
    exit(1);
  }
  if ((dst = fopen("outfile.txt", "w")) == NULL) {
    exit(2);
  }
  while ((fgets(buf, 256, src)) != NULL) {
    fputs(buf, dst);
  }
  fclose(src);
  fclose(dst);
  exit(0);
}
```