ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_in_place>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L4
  xchg   %ax,%ax
L17:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L17
L4:
  ret
```

assistant: ```c
void reverse_in_place(char *data, size_t size) {
  char *end = data + (size - 1);
  while (end > data) {
    char tmp = *data;
    *data++ = *end;
    *end-- = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeToListFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x128(%rbp)
  je     L28
  cmpq   $0x0,-0x130(%rbp)
  jne    L21
L28:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L21:
  movb   $0x0,-0x110(%rbp)
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0xff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0x110(%rbp),%rax
  mov    $0x6,%edx
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0x110(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x130(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L13:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D5: ERROR: Could not read filesystem


tool: D17: .list

tool: D31: a

tool: D26: %s


assistant: ```c
void writeToListFile(const char *path, const char *filename) {
  if (path == NULL || filename == NULL) {
    printf("ERROR: Could not read filesystem\n");
    return;
  }
  char filePath[255];
  filePath[0] = 0;
  strncat(filePath, path, 255);
  strncat(filePath, ".list", 6);
  FILE *file = fopen(filePath, "a");
  fprintf(file, "%s\n", filename);
  fclose(file);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writeToListFile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L22
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L22
  movb   $0x0,(%rsp)
  mov    %rsp,%rbp
  mov    $0xff,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    $0x6,%edx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  lea    D22(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L20:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D21
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D29
datatype: string

tool: D3: .list

tool: D21: a

tool: D22: %s


tool: D29: ERROR: Could not read filesystem


assistant: ```c
void writeToListFile(const char *path, const char *filename) {
  if (path == NULL || filename == NULL) {
    printf("ERROR: Could not read filesystem\n");
    return;
  }
  char filePath[255];
  filePath[0] = 0;
  strncat(filePath, path, 255);
  strncat(filePath, ".list", 6);
  FILE *file = fopen(filePath, "a");
  fprintf(file, "%s\n", filename);
  fclose(file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<writeToListFile>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L25
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L25
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    $0xff,%edx
  movb   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    $0x6,%edx
  mov    %rbp,%rdi
  lea    D32(%rip),%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  lea    D27(%rip),%rsi
  call   <fopen@plt>
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x118,%rsp
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <printf@plt>
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: D32: .list

tool: D27: a

tool: D0: %s


tool: D5: ERROR: Could not read filesystem


assistant: ```c
void writeToListFile(const char *path, const char *filename) {
  if (path == NULL || filename == NULL) {
    printf("ERROR: Could not read filesystem\n");
    return;
  }
  char filePath[255];
  filePath[0] = 0;
  strncat(filePath, path, 255);
  strncat(filePath, ".list", 6);
  FILE *file = fopen(filePath, "a");
  fprintf(file, "%s\n", filename);
  fclose(file);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeToListFile>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L10
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    $0xff,%edx
  movb   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    $0x6,%edx
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %r12,%rdx
  lea    D33(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x118,%rsp
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <printf@plt>
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
datatype: string
name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D19: .list

tool: D13: a

tool: D33: %s


tool: D14: ERROR: Could not read filesystem


assistant: ```c
void writeToListFile(const char *path, const char *filename) {
  if (path == NULL || filename == NULL) {
    printf("ERROR: Could not read filesystem\n");
    return;
  }
  char filePath[255];
  filePath[0] = 0;
  strncat(filePath, path, 255);
  strncat(filePath, ".list", 6);
  FILE *file = fopen(filePath, "a");
  fprintf(file, "%s\n", filename);
  fclose(file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage_and_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D32
datatype: string
name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D47
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string

tool: D27: Usage:


tool: D32:   Runs both passes: assembler <input file> <intermediate file> <output file>


tool: D15:   Run pass #1:      assembler -p1 <input file> <intermediate file>


tool: D47:   Run pass #2:      assembler -p2 <intermediate file> <output file>


tool: D16: Append -log <file name> after any option to save log files to a text file.


assistant: ```c
void print_usage_and_exit() {
  printf("Usage:\n");
  printf("  Runs both passes: assembler <input file> <intermediate file> <output file>\n");
  printf("  Run pass #1:      assembler -p1 <input file> <intermediate file>\n");
  printf("  Run pass #2:      assembler -p2 <intermediate file> <output file>\n");
  printf("Append -log <file name> after any option to save log files to a text file.\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string
name: disassemble_data
arguments: data_tag: D15
datatype: string

tool: D0: Usage:


tool: D16:   Runs both passes: assembler <input file> <intermediate file> <output file>


tool: D2:   Run pass #1:      assembler -p1 <input file> <intermediate file>


tool: D3:   Run pass #2:      assembler -p2 <intermediate file> <output file>


tool: D15: Append -log <file name> after any option to save log files to a text file.


assistant: ```c
void print_usage_and_exit() {
  printf("Usage:\n");
  printf("  Runs both passes: assembler <input file> <intermediate file> <output file>\n");
  printf("  Run pass #1:      assembler -p1 <input file> <intermediate file>\n");
  printf("  Run pass #2:      assembler -p2 <intermediate file> <output file>\n");
  printf("Append -log <file name> after any option to save log files to a text file.\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string

tool: D21: Usage:


tool: D1:   Runs both passes: assembler <input file> <intermediate file> <output file>


tool: D15:   Run pass #1:      assembler -p1 <input file> <intermediate file>


tool: D33:   Run pass #2:      assembler -p2 <intermediate file> <output file>


tool: D34: Append -log <file name> after any option to save log files to a text file.


assistant: ```c
void print_usage_and_exit() {
  printf("Usage:\n");
  printf("  Runs both passes: assembler <input file> <intermediate file> <output file>\n");
  printf("  Run pass #1:      assembler -p1 <input file> <intermediate file>\n");
  printf("  Run pass #2:      assembler -p2 <intermediate file> <output file>\n");
  printf("Append -log <file name> after any option to save log files to a text file.\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D38
type: string
name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D49
type: string
name: retrieve_data
arguments: label: D30
type: string

tool: D38: Usage:


tool: D1:   Runs both passes: assembler <input file> <intermediate file> <output file>


tool: D14:   Run pass #1:      assembler -p1 <input file> <intermediate file>


tool: D49:   Run pass #2:      assembler -p2 <intermediate file> <output file>


tool: D30: Append -log <file name> after any option to save log files to a text file.


assistant: ```c
void print_usage_and_exit() {
  printf("Usage:\n");
  printf("  Runs both passes: assembler <input file> <intermediate file> <output file>\n");
  printf("  Run pass #1:      assembler -p1 <input file> <intermediate file>\n");
  printf("  Run pass #2:      assembler -p2 <intermediate file> <output file>\n");
  printf("Append -log <file name> after any option to save log files to a text file.\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fps_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  add    %rax,-0x10(%rbp)
  jmp    L14
L3:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L14:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fps_reverse(unsigned char *q, unsigned char *p, unsigned long n) {
  p += n - 1;
  while (n-- != 0)
    *q++ = *p--;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fps_reverse>:
  endbr64
  lea    -0x1(%rdx,%rsi,1),%rax
  test   %rdx,%rdx
  je     L1
  add    %rdi,%rdx
L18:
  sub    $0x1,%rax
  add    $0x1,%rdi
  movzbl 0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L18
L1:
  ret
```

assistant: ```c
void fps_reverse(unsigned char *q, unsigned char *p, unsigned long n) {
  p += n - 1;
  while (n-- != 0)
    *q++ = *p--;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fps_reverse>:
  endbr64
  lea    -0x1(%rdx,%rsi,1),%rax
  test   %rdx,%rdx
  je     L12
  add    %rdi,%rdx
  nopl   0x0(%rax)
L15:
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L15
L12:
  ret
```

assistant: ```c
void fps_reverse(unsigned char *q, unsigned char *p, unsigned long n) {
  p += n - 1;
  while (n-- != 0)
    *q++ = *p--;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fps_reverse>:
  endbr64
  lea    -0x1(%rdx,%rsi,1),%rax
  test   %rdx,%rdx
  je     L17
  add    %rdi,%rdx
  nopl   0x0(%rax)
L10:
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L10
L17:
  ret
```

assistant: ```c
void fps_reverse(unsigned char *q, unsigned char *p, unsigned long n) {
  p += n - 1;
  while (n-- != 0)
    *q++ = *p--;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sig_usr1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D20: SIGUSR1%% 


tool: D7: Sleeping for 5 seconds 


tool: D4: Out of SIGUSR1%% 


assistant: ```c
void sig_usr1(int signo) {
  printf("SIGUSR1%% \n");
  printf("Sleeping for 5 seconds \n");
  sleep(5);
  printf("Out of SIGUSR1%% \n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sig_usr1>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string

tool: D14: SIGUSR1%% 


tool: D3: Sleeping for 5 seconds 


tool: D15: Out of SIGUSR1%% 


assistant: ```c
void sig_usr1(int signo) {
  printf("SIGUSR1%% \n");
  printf("Sleeping for 5 seconds \n");
  sleep(5);
  printf("Out of SIGUSR1%% \n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_usr1>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string

tool: D4: SIGUSR1%% 


tool: D22: Sleeping for 5 seconds 


tool: D18: Out of SIGUSR1%% 


assistant: ```c
void sig_usr1(int signo) {
  printf("SIGUSR1%% \n");
  printf("Sleeping for 5 seconds \n");
  sleep(5);
  printf("Out of SIGUSR1%% \n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_usr1>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string

tool: D10: SIGUSR1%% 


tool: D0: Sleeping for 5 seconds 


tool: D19: Out of SIGUSR1%% 


assistant: ```c
void sig_usr1(int signo) {
  printf("SIGUSR1%% \n");
  printf("Sleeping for 5 seconds \n");
  sleep(5);
  printf("Out of SIGUSR1%% \n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cache_line_aligned_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  add    $0x3f,%rax
  and    $0xffffffffffffffc0,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <check_assert@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: rc == 0

assistant: ```c
void *cache_line_aligned_calloc(const size_t alloc_size) {
  const size_t aligned_size = ((alloc_size + 64 - 1) / 64) * 64;
  void *buffer = NULL;
  int rc;
  rc = posix_memalign(&buffer, 64, aligned_size);
  check_assert(rc == 0, "rc == 0");
  memset(buffer, 0, aligned_size);
  return buffer;
}
```
user: What is the c source code of the assembly code below?

```asm
<cache_line_aligned_calloc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3f(%rdi),%rbx
  and    $0xffffffffffffffc0,%rbx
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    $0x40,%esi
  call   <posix_memalign@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D6(%rip),%rsi
  call   <check_assert@plt>
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    (%rsp),%rdi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: rc == 0

assistant: ```c
void *cache_line_aligned_calloc(const size_t alloc_size) {
  const size_t aligned_size = ((alloc_size + 64 - 1) / 64) * 64;
  void *buffer = NULL;
  int rc;
  rc = posix_memalign(&buffer, 64, aligned_size);
  check_assert(rc == 0, "rc == 0");
  memset(buffer, 0, aligned_size);
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cache_line_aligned_calloc>:
  endbr64
  push   %r12
  lea    0x3f(%rdi),%r12
  mov    $0x40,%esi
  and    $0xffffffffffffffc0,%r12
  mov    %r12,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <posix_memalign@plt>
  xor    %edi,%edi
  lea    D0(%rip),%rsi
  test   %eax,%eax
  sete   %dil
  call   <check_assert@plt>
  mov    (%rsp),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: rc == 0

assistant: ```c
void *cache_line_aligned_calloc(const size_t alloc_size) {
  const size_t aligned_size = ((alloc_size + 64 - 1) / 64) * 64;
  void *buffer = NULL;
  int rc;
  rc = posix_memalign(&buffer, 64, aligned_size);
  check_assert(rc == 0, "rc == 0");
  memset(buffer, 0, aligned_size);
  return buffer;
}
```
user: What is the c source code of the assembly code below?

```asm
<cache_line_aligned_calloc>:
  endbr64
  push   %r12
  lea    0x3f(%rdi),%r12
  mov    $0x40,%esi
  and    $0xffffffffffffffc0,%r12
  mov    %r12,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <posix_memalign@plt>
  xor    %edi,%edi
  lea    D2(%rip),%rsi
  test   %eax,%eax
  sete   %dil
  call   <check_assert@plt>
  mov    (%rsp),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: rc == 0

assistant: ```c
void *cache_line_aligned_calloc(const size_t alloc_size) {
  const size_t aligned_size = ((alloc_size + 64 - 1) / 64) * 64;
  void *buffer = NULL;
  int rc;
  rc = posix_memalign(&buffer, 64, aligned_size);
  check_assert(rc == 0, "rc == 0");
  memset(buffer, 0, aligned_size);
  return buffer;
}
```