ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<af_to_dB>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %rsi,%rsi
  je     L22
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L22
  test   %edi,%edi
  jle    L83
  mov    %rsi,%r12
  movslq %edi,%rbp
  pxor   %xmm1,%xmm1
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L75:
  movss  (%r12,%rbx,4),%xmm0
  ucomiss %xmm1,%xmm0
  jp     L13
  jne    L13
  movl   $0xc3480000,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L75
L83:
  mov    $0x1,%eax
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  call   <log10@plt>
  mulss  0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  movss  %xmm0,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L75
  jmp    L83
L22:
  mov    $0xfffffffe,%eax
  jmp    L7
```

assistant: ```c
int af_to_dB(int n, float *in, float *out, float k) {
  int i = 0;
  if (!in || !out)
    return -2;
  for (i = 0; i < n; i++) {
    if (in[i] == 0.0)
      out[i] = -200.0;
    else
      out[i] = k * log10(in[i]);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<symmetry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L179
  mov    $0x0,%eax
  jmp    L98
L179:
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  subq   $0x1,-0x18(%rbp)
  jmp    L198
L174:
  addl   $0x1,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%ebx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%r12d
  cmp    $0x41,%bl
  jne    L126
  cmp    $0x54,%r12b
  jne    L22
L126:
  cmp    $0x54,%bl
  jne    L28
  cmp    $0x41,%r12b
  jne    L22
L28:
  cmp    $0x41,%r12b
  jne    L120
  cmp    $0x54,%bl
  jne    L22
L120:
  cmp    $0x54,%r12b
  jne    L164
  cmp    $0x41,%bl
  je     L164
L22:
  mov    $0x0,%eax
  jmp    L98
L164:
  cmp    $0x43,%bl
  jne    L152
  cmp    $0x47,%r12b
  jne    L82
L152:
  cmp    $0x47,%bl
  jne    L210
  cmp    $0x43,%r12b
  jne    L82
L210:
  cmp    $0x43,%r12b
  jne    L34
  cmp    $0x47,%bl
  jne    L82
L34:
  cmp    $0x47,%r12b
  jne    L117
  cmp    $0x43,%bl
  je     L117
L82:
  mov    $0x0,%eax
  jmp    L98
L117:
  addq   $0x1,-0x38(%rbp)
  subq   $0x1,-0x18(%rbp)
L198:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L174
  mov    $0x1,%eax
L98:
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int symmetry(const char *seq) {
  register char s;
  register char e;
  const char *seq_end = seq;
  int i = 0;
  int seq_len = (int)strlen(seq);
  int mp = seq_len / 2;
  if ((seq_len % 2) == 1) {
    return 0;
  }
  seq_end += seq_len;
  seq_end--;
  while (i < mp) {
    i++;
    s = *seq;
    e = *seq_end;
    if ((s == 'A' && e != 'T') || (s == 'T' && e != 'A') || (e == 'A' && s != 'T') || (e == 'T' && s != 'A')) {
      return 0;
    }
    if ((s == 'C' && e != 'G') || (s == 'G' && e != 'C') || (e == 'C' && s != 'G') || (e == 'G' && s != 'C')) {
      return 0;
    }
    seq++;
    seq_end--;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<symmetry>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  mov    $0x0,%ecx
  cmp    $0x1,%edx
  je     L123
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rsi
  cmp    $0x1,%eax
  jle    L266
  mov    $0x0,%ecx
  jmp    L122
L196:
  sub    $0x1,%rsi
  add    $0x1,%rcx
  cmp    %ecx,%edi
  jle    L72
L122:
  movzbl (%rbx,%rcx,1),%eax
  movzbl (%rsi),%edx
  cmp    $0x41,%al
  jne    L8
  cmp    $0x54,%dl
  jne    L135
L8:
  cmp    $0x54,%al
  jne    L106
  cmp    $0x41,%dl
  jne    L268
L106:
  cmp    $0x41,%dl
  jne    L289
  cmp    $0x54,%al
  jne    L33
L289:
  cmp    $0x54,%dl
  jne    L127
  cmp    $0x41,%al
  jne    L126
L127:
  cmp    $0x43,%al
  jne    L5
  cmp    $0x47,%dl
  jne    L18
L5:
  cmp    $0x47,%al
  jne    L140
  cmp    $0x43,%dl
  jne    L50
L140:
  cmp    $0x43,%dl
  jne    L113
  cmp    $0x47,%al
  jne    L16
L113:
  cmp    $0x47,%dl
  jne    L196
  cmp    $0x43,%al
  je     L196
  mov    $0x0,%ecx
  jmp    L123
L72:
  mov    $0x1,%ecx
  jmp    L123
L266:
  mov    $0x1,%ecx
  jmp    L123
L135:
  mov    $0x0,%ecx
L123:
  mov    %ecx,%eax
  pop    %rbx
  ret
L268:
  mov    $0x0,%ecx
  jmp    L123
L33:
  mov    $0x0,%ecx
  jmp    L123
L126:
  mov    $0x0,%ecx
  jmp    L123
L18:
  mov    $0x0,%ecx
  jmp    L123
L50:
  mov    $0x0,%ecx
  jmp    L123
L16:
  mov    $0x0,%ecx
  jmp    L123
```

assistant: ```c
int symmetry(const char *seq) {
  register char s;
  register char e;
  const char *seq_end = seq;
  int i = 0;
  int seq_len = (int)strlen(seq);
  int mp = seq_len / 2;
  if ((seq_len % 2) == 1) {
    return 0;
  }
  seq_end += seq_len;
  seq_end--;
  while (i < mp) {
    i++;
    s = *seq;
    e = *seq_end;
    if ((s == 'A' && e != 'T') || (s == 'T' && e != 'A') || (e == 'A' && s != 'T') || (e == 'T' && s != 'A')) {
      return 0;
    }
    if ((s == 'C' && e != 'G') || (s == 'G' && e != 'C') || (e == 'C' && s != 'G') || (e == 'G' && s != 'C')) {
      return 0;
    }
    seq++;
    seq_end--;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<symmetry>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  mov    %eax,%ecx
  mov    %eax,%edi
  shr    $0x1f,%ecx
  shr    $0x1f,%edi
  lea    (%rcx,%rax,1),%edx
  add    %eax,%edi
  and    $0x1,%edx
  sar    %edi
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L138
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rsi
  cmp    $0x1,%eax
  jle    L50
  xor    %ecx,%ecx
  jmp    L210
  nopl   0x0(%rax)
L26:
  cmp    $0x41,%dl
  jne    L88
L154:
  cmp    $0x54,%al
  jne    L88
L174:
  cmp    $0x54,%dl
  jne    L163
  cmp    $0x41,%al
  jne    L88
L163:
  cmp    $0x43,%al
  jne    L117
  cmp    $0x47,%dl
  jne    L88
L117:
  cmp    $0x47,%al
  jne    L76
  cmp    $0x43,%dl
  jne    L88
L99:
  cmp    $0x47,%al
  jne    L88
L66:
  cmp    $0x47,%dl
  jne    L48
  cmp    $0x43,%al
  jne    L88
L48:
  add    $0x1,%rcx
  sub    $0x1,%rsi
  cmp    %ecx,%edi
  jle    L50
L210:
  movzbl (%rbx,%rcx,1),%eax
  movzbl (%rsi),%edx
  cmp    $0x41,%al
  jne    L62
  cmp    $0x54,%dl
  jne    L88
L62:
  cmp    $0x54,%al
  je     L26
  cmp    $0x41,%dl
  jne    L174
  jmp    L154
L76:
  cmp    $0x43,%dl
  jne    L66
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L88:
  xor    %r8d,%r8d
L138:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    $0x1,%r8d
  jmp    L138
```

assistant: ```c
int symmetry(const char *seq) {
  register char s;
  register char e;
  const char *seq_end = seq;
  int i = 0;
  int seq_len = (int)strlen(seq);
  int mp = seq_len / 2;
  if ((seq_len % 2) == 1) {
    return 0;
  }
  seq_end += seq_len;
  seq_end--;
  while (i < mp) {
    i++;
    s = *seq;
    e = *seq_end;
    if ((s == 'A' && e != 'T') || (s == 'T' && e != 'A') || (e == 'A' && s != 'T') || (e == 'T' && s != 'A')) {
      return 0;
    }
    if ((s == 'C' && e != 'G') || (s == 'G' && e != 'C') || (e == 'C' && s != 'G') || (e == 'G' && s != 'C')) {
      return 0;
    }
    seq++;
    seq_end--;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<symmetry>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  mov    %eax,%ecx
  mov    %eax,%edi
  shr    $0x1f,%ecx
  shr    $0x1f,%edi
  lea    (%rcx,%rax,1),%edx
  add    %eax,%edi
  and    $0x1,%edx
  sar    %edi
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L218
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rsi
  cmp    $0x1,%eax
  jle    L28
  xor    %ecx,%ecx
  jmp    L144
  nopl   0x0(%rax)
L105:
  cmp    $0x41,%dl
  jne    L82
L149:
  cmp    $0x54,%al
  jne    L82
L161:
  cmp    $0x54,%dl
  jne    L179
  cmp    $0x41,%al
  jne    L82
L179:
  cmp    $0x43,%al
  jne    L158
  cmp    $0x47,%dl
  jne    L82
L158:
  cmp    $0x47,%al
  jne    L99
  cmp    $0x43,%dl
  jne    L82
L68:
  cmp    $0x47,%al
  jne    L82
L181:
  cmp    $0x47,%dl
  jne    L97
  cmp    $0x43,%al
  jne    L82
L97:
  add    $0x1,%rcx
  sub    $0x1,%rsi
  cmp    %ecx,%edi
  jle    L28
L144:
  movzbl (%rbx,%rcx,1),%eax
  movzbl (%rsi),%edx
  cmp    $0x41,%al
  jne    L157
  cmp    $0x54,%dl
  jne    L82
L157:
  cmp    $0x54,%al
  je     L105
  cmp    $0x41,%dl
  jne    L161
  jmp    L149
L99:
  cmp    $0x43,%dl
  jne    L181
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L82:
  xor    %r8d,%r8d
L218:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%r8d
  jmp    L218
```

assistant: ```c
int symmetry(const char *seq) {
  register char s;
  register char e;
  const char *seq_end = seq;
  int i = 0;
  int seq_len = (int)strlen(seq);
  int mp = seq_len / 2;
  if ((seq_len % 2) == 1) {
    return 0;
  }
  seq_end += seq_len;
  seq_end--;
  while (i < mp) {
    i++;
    s = *seq;
    e = *seq_end;
    if ((s == 'A' && e != 'T') || (s == 'T' && e != 'A') || (e == 'A' && s != 'T') || (e == 'T' && s != 'A')) {
      return 0;
    }
    if ((s == 'C' && e != 'G') || (s == 'G' && e != 'C') || (e == 'C' && s != 'G') || (e == 'G' && s != 'C')) {
      return 0;
    }
    seq++;
    seq_end--;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strength_test7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L13
  addl   $0x1,-0x4(%rbp)
  jmp    L24
L13:
  addl   $0x2,-0x4(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strength_test7(int *data) {
  int i = 0;
  do {
    if (data[1])
      i = i + 1;
    else
      i = i + 2;
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strength_test7>:
  endbr64
  mov    $0x0,%eax
  jmp    L17
L16:
  add    $0x1,%eax
L19:
  movslq 0x8(%rdi),%rdx
  movl   $0x2,(%rdi,%rdx,4)
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,4),%edx
  cmp    0xc(%rdi),%edx
  jge    L31
L17:
  cmpl   $0x0,0x4(%rdi)
  jne    L16
  add    $0x2,%eax
  jmp    L19
L31:
  ret
```

assistant: ```c
void strength_test7(int *data) {
  int i = 0;
  do {
    if (data[1])
      i = i + 1;
    else
      i = i + 2;
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strength_test7>:
  endbr64
  xor    %eax,%eax
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1,%eax
L12:
  movslq 0x8(%rdi),%rdx
  movl   $0x2,(%rdi,%rdx,4)
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,4),%edx
  cmp    0xc(%rdi),%edx
  jge    L26
L36:
  mov    0x4(%rdi),%edx
  test   %edx,%edx
  jne    L37
  add    $0x2,%eax
  jmp    L12
  nopl   (%rax)
L26:
  ret
```

assistant: ```c
void strength_test7(int *data) {
  int i = 0;
  do {
    if (data[1])
      i = i + 1;
    else
      i = i + 2;
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strength_test7>:
  endbr64
  xor    %eax,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%eax
L34:
  movslq 0x8(%rdi),%rdx
  movl   $0x2,(%rdi,%rdx,4)
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,4),%edx
  cmp    0xc(%rdi),%edx
  jge    L28
L12:
  mov    0x4(%rdi),%edx
  test   %edx,%edx
  jne    L38
  add    $0x2,%eax
  jmp    L34
  nopl   (%rax)
L28:
  ret
```

assistant: ```c
void strength_test7(int *data) {
  int i = 0;
  do {
    if (data[1])
      i = i + 1;
    else
      i = i + 2;
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rdx
  jmp    L13
L7:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%ecx
  and    $0x7f,%ecx
  mov    %cl,(%rax)
L26:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L7
L13:
  mov    %rdx,%rax
  lea    0x8(%rax),%rdx
  mov    (%rax),%rbx
  test   %rbx,%rbx
  jne    L26
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
trim(t) register char **t;
{
  register char *p;
  while (p = *t++)
    while (*p)
      *p++ &= 0177;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim>:
  endbr64
  lea    0x8(%rdi),%rcx
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  jne    L13
  ret
L1:
  add    $0x1,%rdx
  and    $0x7f,%eax
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L1
L21:
  add    $0x8,%rcx
  mov    -0x8(%rcx),%rdx
  test   %rdx,%rdx
  je     L8
L13:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L1
  jmp    L21
L8:
  ret
```

assistant: ```c
trim(t) register char **t;
{
  register char *p;
  while (p = *t++)
    while (*p)
      *p++ &= 0177;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  mov    (%rdi),%rdx
  lea    0x8(%rdi),%rcx
  test   %rdx,%rdx
  jne    L32
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdx
  and    $0x7f,%eax
  mov    %al,-0x1(%rdx)
L32:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L9
  mov    (%rcx),%rdx
  add    $0x8,%rcx
  test   %rdx,%rdx
  jne    L32
  ret
L0:
  ret
```

assistant: ```c
trim(t) register char **t;
{
  register char *p;
  while (p = *t++)
    while (*p)
      *p++ &= 0177;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trim>:
  endbr64
  mov    (%rdi),%rdx
  lea    0x8(%rdi),%rcx
  test   %rdx,%rdx
  jne    L1
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rdx
  and    $0x7f,%eax
  mov    %al,-0x1(%rdx)
L1:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L22
  mov    (%rcx),%rdx
  add    $0x8,%rcx
  test   %rdx,%rdx
  jne    L1
  ret
L37:
  ret
```

assistant: ```c
trim(t) register char **t;
{
  register char *p;
  while (p = *t++)
    while (*p)
      *p++ &= 0177;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1220,%rax
  mov    0x1c(%rax),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x17,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  add    $0x460,%rax
  mov    0x34(%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x17,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  add    $0x460,%rax
  mov    0x34(%rax),%eax
  cmp    $0x17,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(int (*a)[40]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpl   $0x17,0x123c(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x17,0x494(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x17,0x494(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  ret
```

assistant: ```c
void foo(int (*a)[40]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  cmpl   $0x17,0x123c(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x494(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x494(%rbx)
  pop    %rbx
  sete   %dil
  jmp    1050 <assert@plt>
```

assistant: ```c
void foo(int (*a)[40]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  cmpl   $0x17,0x123c(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x494(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x494(%rbx)
  pop    %rbx
  sete   %dil
  jmp    1050 <assert@plt>
```

assistant: ```c
void foo(int (*a)[40]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pd9p_dec2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *pd9p_dec2(char *buf, uint16_t *val) {
  *val = buf[0];
  *val += buf[1] << 8;
  return buf + 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pd9p_dec2>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *pd9p_dec2(char *buf, uint16_t *val) {
  *val = buf[0];
  *val += buf[1] << 8;
  return buf + 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pd9p_dec2>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *pd9p_dec2(char *buf, uint16_t *val) {
  *val = buf[0];
  *val += buf[1] << 8;
  return buf + 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pd9p_dec2>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *pd9p_dec2(char *buf, uint16_t *val) {
  *val = buf[0];
  *val += buf[1] << 8;
  return buf + 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_b64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L60:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doc_next@plt>
  mov    %rax,-0x8(%rbp)
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L67
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_b64@plt>
  test   %eax,%eax
  je     L60
L67:
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L61
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  jmp    L44
L61:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <from_b64@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L48
L68:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doc_next@plt>
L48:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doc_following@plt>
  mov    %rax,-0x8(%rbp)
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L47
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_b64@plt>
  test   %eax,%eax
  je     L68
L47:
  mov    -0xc(%rbp),%eax
L44:
  leave
  ret
```

assistant: ```c
int get_b64(struct pane *p, struct mark *m) {
  wint_t c;
  int ret;
  do {
    c = doc_next(p, m);
  } while (c != WEOF && !is_b64(c));
  if (c == WEOF)
    return WEOF;
  ret = from_b64(c);
  while ((c = doc_following(p, m)) != WEOF && !is_b64(c))
    doc_next(p, m);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_b64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <doc_next@plt>
  mov    %rax,%rbx
  mov    D14(%rip),%rax
  cmp    %rbx,(%rax)
  je     L17
  mov    %rbx,%rdi
  call   <is_b64@plt>
  test   %eax,%eax
  je     L18
  mov    D14(%rip),%rax
  cmp    %rbx,(%rax)
  je     L17
  mov    %rbx,%rdi
  call   <from_b64@plt>
  mov    %eax,%ebx
  jmp    L2
L50:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <doc_next@plt>
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <doc_following@plt>
  mov    %rax,%rdi
  mov    D14(%rip),%rax
  cmp    %rdi,(%rax)
  je     L17
  call   <is_b64@plt>
  test   %eax,%eax
  je     L50
L17:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_b64(struct pane *p, struct mark *m) {
  wint_t c;
  int ret;
  do {
    c = doc_next(p, m);
  } while (c != WEOF && !is_b64(c));
  if (c == WEOF)
    return WEOF;
  ret = from_b64(c);
  while ((c = doc_following(p, m)) != WEOF && !is_b64(c))
    doc_next(p, m);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_b64>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%r14
  jmp    L63
  xchg   %ax,%ax
L60:
  mov    %rax,%rdi
  call   <is_b64@plt>
  test   %eax,%eax
  jne    L21
L63:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <doc_next@plt>
  mov    %rax,%r12
  cmp    %rax,(%r14)
  jne    L60
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L21:
  cmp    %r12,(%r14)
  je     L8
  mov    %r12,%rdi
  call   <from_b64@plt>
  mov    %eax,%r12d
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L38:
  call   <is_b64@plt>
  test   %eax,%eax
  jne    L8
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <doc_next@plt>
L51:
  mov    %rbx,%rdi
  mov    %r13,%rsi
  call   <doc_following@plt>
  mov    %rax,%rdi
  cmp    %rax,(%r14)
  jne    L38
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_b64(struct pane *p, struct mark *m) {
  wint_t c;
  int ret;
  do {
    c = doc_next(p, m);
  } while (c != WEOF && !is_b64(c));
  if (c == WEOF)
    return WEOF;
  ret = from_b64(c);
  while ((c = doc_following(p, m)) != WEOF && !is_b64(c))
    doc_next(p, m);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_b64>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%r14
  jmp    L33
  xchg   %ax,%ax
L24:
  mov    %rax,%rdi
  call   <is_b64@plt>
  test   %eax,%eax
  jne    L35
L33:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <doc_next@plt>
  mov    %rax,%r12
  cmp    %rax,(%r14)
  jne    L24
L41:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L35:
  cmp    %r12,(%r14)
  je     L41
  mov    %r12,%rdi
  call   <from_b64@plt>
  mov    %eax,%r12d
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L12:
  call   <is_b64@plt>
  test   %eax,%eax
  jne    L41
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <doc_next@plt>
L14:
  mov    %rbx,%rdi
  mov    %r13,%rsi
  call   <doc_following@plt>
  mov    %rax,%rdi
  cmp    %rax,(%r14)
  jne    L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_b64(struct pane *p, struct mark *m) {
  wint_t c;
  int ret;
  do {
    c = doc_next(p, m);
  } while (c != WEOF && !is_b64(c));
  if (c == WEOF)
    return WEOF;
  ret = from_b64(c);
  while ((c = doc_following(p, m)) != WEOF && !is_b64(c))
    doc_next(p, m);
  return ret;
}
```