ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<noncoplanar_calibration_with_full_optimization>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ncc_three_parm_optimization@plt>
  test   %eax,%eax
  jne    L2
L13:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <ncc_nic_optimization@plt>
  test   %eax,%eax
  je     L13
  xor    %eax,%eax
  call   <ncc_full_optimization@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int noncoplanar_calibration_with_full_optimization() {
  if (!ncc_three_parm_optimization())
    return 0;
  if (!ncc_nic_optimization())
    return 0;
  if (!ncc_full_optimization())
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utils_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *utils_strcat(char *_str1, char *_str2) {
  char *str3 = (char *)calloc((strlen(_str1) + strlen(_str2)), sizeof(char));
  str3 = strcat(str3, _str1);
  str3 = strcat(str3, _str2);
  return str3;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utils_strcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <strcat@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *utils_strcat(char *_str1, char *_str2) {
  char *str3 = (char *)calloc((strlen(_str1) + strlen(_str2)), sizeof(char));
  str3 = strcat(str3, _str1);
  str3 = strcat(str3, _str2);
  return str3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utils_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    (%rbx,%rax,1),%rdi
  call   <calloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1090 <strcat@plt>
```

assistant: ```c
char *utils_strcat(char *_str1, char *_str2) {
  char *str3 = (char *)calloc((strlen(_str1) + strlen(_str2)), sizeof(char));
  str3 = strcat(str3, _str1);
  str3 = strcat(str3, _str2);
  return str3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utils_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    (%rbx,%rax,1),%rdi
  call   <calloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1090 <strcat@plt>
```

assistant: ```c
char *utils_strcat(char *_str1, char *_str2) {
  char *str3 = (char *)calloc((strlen(_str1) + strlen(_str2)), sizeof(char));
  str3 = strcat(str3, _str1);
  str3 = strcat(str3, _str2);
  return str3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L40:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L10
  addl   $0x1,-0x4(%rbp)
L10:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L40
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count(int **arr, int x, int y) {
  int i = 0, j = 0, count = 0;
  for (i = 0; i < x; i++) {
    for (j = 0; j < y; j++) {
      if (arr[i][j] != 0) {
        ++count;
      }
    }
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<count>:
  endbr64
  test   %esi,%esi
  jle    L49
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  lea    -0x1(%rdx),%eax
  mov    $0x0,%ecx
  lea    0x4(,%rax,4),%r9
  jmp    L4
L50:
  mov    (%r8),%rax
  lea    (%r9,%rax,1),%rsi
L18:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffff,%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L18
L56:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L34
L4:
  test   %edx,%edx
  jg     L50
  jmp    L56
L49:
  mov    $0x0,%ecx
L34:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int count(int **arr, int x, int y) {
  int i = 0, j = 0, count = 0;
  for (i = 0; i < x; i++) {
    for (j = 0; j < y; j++) {
      if (arr[i][j] != 0) {
        ++count;
      }
    }
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<count>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,8),%rsi
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%r9
  xchg   %ax,%ax
L15:
  test   %edx,%edx
  jle    L12
  mov    (%rdi),%rax
  lea    (%r9,%rax,1),%rcx
  nopl   0x0(%rax,%rax,1)
L32:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffff,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L32
L12:
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L15
  mov    %r8d,%eax
  ret
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count(int **arr, int x, int y) {
  int i = 0, j = 0, count = 0;
  for (i = 0; i < x; i++) {
    for (j = 0; j < y; j++) {
      if (arr[i][j] != 0) {
        ++count;
      }
    }
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  test   %esi,%esi
  jle    L33
  lea    -0x1(%rsi),%eax
  push   %rbp
  mov    %edx,%r10d
  mov    %edx,%r9d
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbx
  mov    %edx,%eax
  mov    %rdi,%rcx
  shr    $0x2,%eax
  lea    -0x1(%rdx),%ebp
  and    $0xfffffffc,%r10d
  xor    %r8d,%r8d
  lea    -0x1(%rax),%r11d
  pxor   %xmm2,%xmm2
  add    $0x1,%r11
  shl    $0x4,%r11
  xchg   %ax,%ax
L69:
  test   %r9d,%r9d
  jle    L58
  mov    (%rcx),%rsi
  cmp    $0x2,%ebp
  jbe    L76
  mov    %rsi,%rax
  lea    (%r11,%rsi,1),%rdx
  pxor   %xmm1,%xmm1
L79:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pcmpeqd %xmm2,%xmm0
  pcmpeqd %xmm2,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L79
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  add    %eax,%r8d
  mov    %r10d,%eax
  cmp    %r10d,%r9d
  je     L58
L17:
  movslq %eax,%rdx
  cmpl   $0x1,(%rsi,%rdx,4)
  lea    0x0(,%rdx,4),%rdi
  lea    0x1(%rax),%edx
  sbb    $0xffffffff,%r8d
  cmp    %r9d,%edx
  jge    L58
  cmpl   $0x1,0x4(%rsi,%rdi,1)
  sbb    $0xffffffff,%r8d
  add    $0x2,%eax
  cmp    %r9d,%eax
  jge    L58
  cmpl   $0x1,0x8(%rsi,%rdi,1)
  sbb    $0xffffffff,%r8d
L58:
  add    $0x8,%rcx
  cmp    %rbx,%rcx
  jne    L69
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L76:
  xor    %eax,%eax
  jmp    L17
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count(int **arr, int x, int y) {
  int i = 0, j = 0, count = 0;
  for (i = 0; i < x; i++) {
    for (j = 0; j < y; j++) {
      if (arr[i][j] != 0) {
        ++count;
      }
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_usage_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_usage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _usage_error() {
  _usage(stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <_usage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _usage_error() {
  _usage(stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <_usage@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void _usage_error() {
  _usage(stderr);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <_usage@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void _usage_error() {
  _usage(stderr);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L54
  jmp    L39
L4:
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L39:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L4
  jmp    L7
L54:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L7
  jmp    L42
L1:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L42:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L1
L7:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  void *const save = dst;
  if (dst > src)
    while (len-- > 0)
      *((unsigned char *)(dst + len)) = *((unsigned char *)(src + len));
  else if (dst < src)
    while (len-- > 0)
      *((unsigned char *)dst++) = *((unsigned char *)src++);
  return (save);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L46
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L0
L21:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L21
  ret
L46:
  jae    L0
  test   %rdx,%rdx
  je     L0
  mov    $0x0,%ecx
L39:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L39
L0:
  ret
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  void *const save = dst;
  if (dst > src)
    while (len-- > 0)
      *((unsigned char *)(dst + len)) = *((unsigned char *)(src + len));
  else if (dst < src)
    while (len-- > 0)
      *((unsigned char *)dst++) = *((unsigned char *)src++);
  return (save);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L2
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L1
  nopl   (%rax)
L32:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L32
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  jb     L55
L1:
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  test   %rdx,%rdx
  je     L1
  xor    %ecx,%ecx
  nop
L54:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L54
  ret
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  void *const save = dst;
  if (dst > src)
    while (len-- > 0)
      *((unsigned char *)(dst + len)) = *((unsigned char *)(src + len));
  else if (dst < src)
    while (len-- > 0)
      *((unsigned char *)dst++) = *((unsigned char *)src++);
  return (save);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  cmp    %rsi,%rdi
  jbe    L218
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L142
  nopl   0x0(%rax,%rax,1)
L178:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  jae    L178
L142:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L218:
  jae    L142
  lea    -0x1(%rdx),%rsi
  test   %rdx,%rdx
  je     L142
  lea    0x1(%rcx),%rdi
  mov    %r8,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L105
  cmp    $0x6,%rsi
  jbe    L105
  cmp    $0xe,%rsi
  jbe    L138
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  nopl   0x0(%rax)
L86:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L86
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  lea    (%r8,%rax,1),%rdi
  lea    (%rcx,%rax,1),%r9
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L142
  sub    %rax,%rdx
  lea    -0x1(%rdx),%r10
  cmp    $0x6,%r10
  jbe    L16
L95:
  mov    (%rcx,%rax,1),%rcx
  mov    %rcx,(%r8,%rax,1)
  mov    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  add    %rax,%rdi
  add    %rax,%r9
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L142
L16:
  movzbl (%r9),%eax
  mov    %al,(%rdi)
  test   %rsi,%rsi
  je     L142
  movzbl 0x1(%r9),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x1,%rsi
  je     L142
  movzbl 0x2(%r9),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x2,%rsi
  je     L142
  movzbl 0x3(%r9),%eax
  mov    %al,0x3(%rdi)
  cmp    $0x3,%rsi
  je     L142
  movzbl 0x4(%r9),%eax
  mov    %al,0x4(%rdi)
  cmp    $0x4,%rsi
  je     L142
  movzbl 0x5(%r9),%eax
  mov    %al,0x5(%rdi)
  cmp    $0x5,%rsi
  je     L142
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
  jmp    L142
L105:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L164:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L164
  jmp    L142
L138:
  mov    %rcx,%r9
  mov    %r8,%rdi
  xor    %eax,%eax
  jmp    L95
```

assistant: ```c
void *ft_memmove(void *dst, const void *src, size_t len) {
  void *const save = dst;
  if (dst > src)
    while (len-- > 0)
      *((unsigned char *)(dst + len)) = *((unsigned char *)(src + len));
  else if (dst < src)
    while (len-- > 0)
      *((unsigned char *)dst++) = *((unsigned char *)src++);
  return (save);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5c,%eax
  jne    L57
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x22,%eax
  cmp    $0x54,%eax
  ja     L117
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%rax
  movb   $0x7,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x8,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0xc,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0xa,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0xd,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x9,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0xb,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x27,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x22,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x5c,(%rax)
  mov    $0x2,%eax
  jmp    L79
  mov    -0x10(%rbp),%rax
  movb   $0x3f,(%rax)
  mov    $0x2,%eax
  jmp    L79
L117:
  nop
  nop
  jmp    L79
L57:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
char read_char(char *c, char *to) {
  switch (c[0]) {
  case '\\':
    switch (c[1]) {
    case 'a':
      *to = '\a';
      return 2;
      break;
    case 'b':
      *to = '\b';
      return 2;
      break;
    case 'f':
      *to = '\f';
      return 2;
      break;
    case 'n':
      *to = '\n';
      return 2;
      break;
    case 'r':
      *to = '\r';
      return 2;
      break;
    case 't':
      *to = '\t';
      return 2;
      break;
    case 'v':
      *to = '\v';
      return 2;
      break;
    case '\'':
      *to = '\'';
      return 2;
      break;
    case '\"':
      *to = '\"';
      return 2;
      break;
    case '\\':
      *to = '\\';
      return 2;
      break;
    case '?':
      *to = '\?';
      return 2;
      break;
    default:
      break;
    }
    break;
  default:
    *to = c[0];
    return 1;
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_char>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%edx
  cmp    $0x5c,%al
  je     L36
L56:
  mov    %al,(%rsi)
L62:
  mov    %edx,%eax
  ret
L36:
  movzbl 0x1(%rdi),%eax
  lea    -0x22(%rax),%edx
  cmp    $0x54,%dl
  ja     L62
  movzbl %dl,%edx
  lea    D9(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x7,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0xc,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0xa,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0xd,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0x9,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0xb,%eax
  mov    $0x2,%edx
  jmp    L56
  mov    $0x2,%edx
  jmp    L56
  mov    $0x2,%edx
  jmp    L56
  mov    $0x2,%edx
  jmp    L56
  mov    $0x2,%edx
  jmp    L56
  mov    $0x8,%eax
  mov    $0x2,%edx
  jmp    L56
```

assistant: ```c
char read_char(char *c, char *to) {
  switch (c[0]) {
  case '\\':
    switch (c[1]) {
    case 'a':
      *to = '\a';
      return 2;
      break;
    case 'b':
      *to = '\b';
      return 2;
      break;
    case 'f':
      *to = '\f';
      return 2;
      break;
    case 'n':
      *to = '\n';
      return 2;
      break;
    case 'r':
      *to = '\r';
      return 2;
      break;
    case 't':
      *to = '\t';
      return 2;
      break;
    case 'v':
      *to = '\v';
      return 2;
      break;
    case '\'':
      *to = '\'';
      return 2;
      break;
    case '\"':
      *to = '\"';
      return 2;
      break;
    case '\\':
      *to = '\\';
      return 2;
      break;
    case '?':
      *to = '\?';
      return 2;
      break;
    default:
      break;
    }
    break;
  default:
    *to = c[0];
    return 1;
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_char>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%r8d
  cmp    $0x5c,%al
  je     L87
L37:
  mov    %al,(%rsi)
L31:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  movzbl 0x1(%rdi),%eax
  lea    -0x22(%rax),%edx
  cmp    $0x54,%dl
  ja     L31
  lea    D6(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x8,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0xa,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0xc,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0xd,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0x9,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0xb,%eax
  mov    $0x2,%r8d
  jmp    L37
  mov    $0x7,%eax
  mov    $0x2,%r8d
  jmp    L37
```

assistant: ```c
char read_char(char *c, char *to) {
  switch (c[0]) {
  case '\\':
    switch (c[1]) {
    case 'a':
      *to = '\a';
      return 2;
      break;
    case 'b':
      *to = '\b';
      return 2;
      break;
    case 'f':
      *to = '\f';
      return 2;
      break;
    case 'n':
      *to = '\n';
      return 2;
      break;
    case 'r':
      *to = '\r';
      return 2;
      break;
    case 't':
      *to = '\t';
      return 2;
      break;
    case 'v':
      *to = '\v';
      return 2;
      break;
    case '\'':
      *to = '\'';
      return 2;
      break;
    case '\"':
      *to = '\"';
      return 2;
      break;
    case '\\':
      *to = '\\';
      return 2;
      break;
    case '?':
      *to = '\?';
      return 2;
      break;
    default:
      break;
    }
    break;
  default:
    *to = c[0];
    return 1;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_char>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x1,%r8d
  cmp    $0x5c,%al
  je     L42
L82:
  mov    %al,(%rsi)
L46:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  movzbl 0x1(%rdi),%eax
  lea    -0x22(%rax),%edx
  cmp    $0x54,%dl
  ja     L46
  lea    D8(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x8,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0xa,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0xc,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0xd,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0x9,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0xb,%eax
  mov    $0x2,%r8d
  jmp    L82
  mov    $0x7,%eax
  mov    $0x2,%r8d
  jmp    L82
```

assistant: ```c
char read_char(char *c, char *to) {
  switch (c[0]) {
  case '\\':
    switch (c[1]) {
    case 'a':
      *to = '\a';
      return 2;
      break;
    case 'b':
      *to = '\b';
      return 2;
      break;
    case 'f':
      *to = '\f';
      return 2;
      break;
    case 'n':
      *to = '\n';
      return 2;
      break;
    case 'r':
      *to = '\r';
      return 2;
      break;
    case 't':
      *to = '\t';
      return 2;
      break;
    case 'v':
      *to = '\v';
      return 2;
      break;
    case '\'':
      *to = '\'';
      return 2;
      break;
    case '\"':
      *to = '\"';
      return 2;
      break;
    case '\\':
      *to = '\\';
      return 2;
      break;
    case '?':
      *to = '\?';
      return 2;
      break;
    default:
      break;
    }
    break;
  default:
    *to = c[0];
    return 1;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_float_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movss  %xmm0,-0x30(%rbp)
  movss  %xmm1,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  movss  -0x34(%rbp),%xmm0
  mov    -0x30(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <random_float@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  ja     L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void random_float_array(float array[], const unsigned int length, const float min, const float max) {
  for (int i = 0; i < length; ++i)
    array[i] = random_float(min, max);
}
```