ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<divs100>:
  endbr64
  mov    %edi,%eax
  sar    $0x1f,%edi
  and    $0x63,%edi
  add    %eax,%edi
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x3,%edx
  sar    %eax
  add    %edx,%eax
  mov    %edi,%edx
  sar    $0x6,%edx
  add    %edx,%eax
  mov    %edi,%edx
  sar    $0xa,%edx
  sub    %edx,%eax
  mov    %edi,%edx
  sar    $0xc,%edx
  add    %edx,%eax
  mov    %edi,%edx
  sar    $0xd,%edx
  add    %edx,%eax
  mov    %edi,%edx
  sar    $0x10,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  sar    $0x14,%edx
  add    %eax,%edx
  sar    $0x6,%edx
  imul   $0xffffff9c,%edx,%eax
  lea    0x1c(%rdi,%rax,1),%eax
  sar    $0x7,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int divs100(int n) {
  int q, r;
  n = n + (n >> 31 & 99);
  q = (n >> 1) + (n >> 3) + (n >> 6) - (n >> 10) + (n >> 12) + (n >> 13) - (n >> 16);
  q = q + (q >> 20);
  q = q >> 6;
  r = n - q * 100;
  return q + ((r + 28) >> 7);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Clear_2_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%edi
  call   <LCDClear@plt>
  mov    $0x3,%edi
  call   <LCDClear@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Clear_2_3() {
  LCDClear(2);
  LCDClear(3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Clear_2_3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <LCDClear@plt>
  mov    $0x3,%edi
  call   <LCDClear@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Clear_2_3() {
  LCDClear(2);
  LCDClear(3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Clear_2_3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <LCDClear@plt>
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <LCDClear@plt>
```

assistant: ```c
void Clear_2_3() {
  LCDClear(2);
  LCDClear(3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Clear_2_3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <LCDClear@plt>
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <LCDClear@plt>
```

assistant: ```c
void Clear_2_3() {
  LCDClear(2);
  LCDClear(3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CG_VoiceTellAttacker_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <CG_LastAttacker@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0xffffffff,-0x114(%rbp)
  je     L2
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <trap_Args@plt>
  lea    -0x90(%rbp),%rcx
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D8(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <Com_sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <trap_SendClientCommand@plt>
  jmp    L15
L2:
  nop
L15:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: vtell %i %s

assistant: ```c
void CG_VoiceTellAttacker_f(void) {
  int clientNum;
  char command[128];
  char message[128];
  clientNum = CG_LastAttacker();
  if (clientNum == -1) {
    return;
  }
  trap_Args(message, 128);
  Com_sprintf(command, 128, "vtell %i %s", clientNum, message);
  trap_SendClientCommand(command);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CG_VoiceTellAttacker_f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <CG_LastAttacker@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    %eax,%ebx
  lea    0x80(%rsp),%r12
  mov    $0x80,%esi
  mov    %r12,%rdi
  call   <trap_Args@plt>
  mov    %rsp,%rbp
  mov    %r12,%r8
  mov    %ebx,%ecx
  lea    D7(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <Com_sprintf@plt>
  mov    %rbp,%rdi
  call   <trap_SendClientCommand@plt>
L5:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: vtell %i %s

assistant: ```c
void CG_VoiceTellAttacker_f(void) {
  int clientNum;
  char command[128];
  char message[128];
  clientNum = CG_LastAttacker();
  if (clientNum == -1) {
    return;
  }
  trap_Args(message, 128);
  Com_sprintf(command, 128, "vtell %i %s", clientNum, message);
  trap_SendClientCommand(command);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CG_VoiceTellAttacker_f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <CG_LastAttacker@plt>
  cmp    $0xffffffff,%eax
  je     L9
  lea    0x80(%rsp),%rbx
  mov    %eax,%r12d
  mov    $0x80,%esi
  mov    %rsp,%rbp
  mov    %rbx,%rdi
  call   <trap_Args@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    %r12d,%ecx
  lea    D7(%rip),%rdx
  mov    $0x80,%esi
  call   <Com_sprintf@plt>
  mov    %rbp,%rdi
  call   <trap_SendClientCommand@plt>
L9:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: vtell %i %s

assistant: ```c
void CG_VoiceTellAttacker_f(void) {
  int clientNum;
  char command[128];
  char message[128];
  clientNum = CG_LastAttacker();
  if (clientNum == -1) {
    return;
  }
  trap_Args(message, 128);
  Com_sprintf(command, 128, "vtell %i %s", clientNum, message);
  trap_SendClientCommand(command);
}
```
user: What is the c source code of the assembly code below:

```asm
<CG_VoiceTellAttacker_f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <CG_LastAttacker@plt>
  cmp    $0xffffffff,%eax
  je     L2
  lea    0x80(%rsp),%rbx
  mov    %eax,%r12d
  mov    $0x80,%esi
  mov    %rsp,%rbp
  mov    %rbx,%rdi
  call   <trap_Args@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    %r12d,%ecx
  lea    D4(%rip),%rdx
  mov    $0x80,%esi
  call   <Com_sprintf@plt>
  mov    %rbp,%rdi
  call   <trap_SendClientCommand@plt>
L2:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: vtell %i %s

assistant: ```c
void CG_VoiceTellAttacker_f(void) {
  int clientNum;
  char command[128];
  char message[128];
  clientNum = CG_LastAttacker();
  if (clientNum == -1) {
    return;
  }
  trap_Args(message, 128);
  Com_sprintf(command, 128, "vtell %i %s", clientNum, message);
  trap_SendClientCommand(command);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jumpOpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jg     L28
  mov    $0x0,%eax
  jmp    L7
L28:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L46
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L48
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L34
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L34:
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L2
  mov    -0xc(%rbp),%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int jumpOpt(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return 0;
  }
  int farthest = nums[0];
  int jump = 1;
  int farAt = nums[0];
  for (int i = 1; i < numsSize - 1; i++) {
    if (nums[i] + i > farthest) {
      farthest = nums[i] + i;
    }
    if (farAt == i) {
      jump++;
      farAt = farthest;
    }
  }
  return jump;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jumpOpt>:
  endbr64
  mov    $0x0,%r9d
  cmp    $0x1,%esi
  jle    L51
  mov    (%rdi),%edx
  cmp    $0x2,%esi
  jle    L39
  lea    -0x3(%rsi),%r8d
  add    $0x2,%r8
  mov    %edx,%esi
  mov    $0x1,%eax
  mov    $0x1,%r9d
  jmp    L38
L27:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L51
L38:
  mov    %eax,%ecx
  add    (%rdi,%rax,4),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  cmp    %eax,%esi
  jne    L27
  add    $0x1,%r9d
  mov    %edx,%esi
  jmp    L27
L39:
  mov    $0x1,%r9d
L51:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int jumpOpt(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return 0;
  }
  int farthest = nums[0];
  int jump = 1;
  int farAt = nums[0];
  for (int i = 1; i < numsSize - 1; i++) {
    if (nums[i] + i > farthest) {
      farthest = nums[i] + i;
    }
    if (farAt == i) {
      jump++;
      farAt = farthest;
    }
  }
  return jump;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<jumpOpt>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L18
  mov    (%rdi),%edx
  cmp    $0x2,%esi
  je     L11
  lea    -0x3(%rsi),%r8d
  mov    $0x1,%eax
  mov    %edx,%esi
  mov    $0x1,%r9d
  add    $0x2,%r8
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rdi,%rax,4),%ecx
  add    %eax,%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  cmp    %eax,%esi
  jne    L43
  add    $0x1,%r9d
  mov    %edx,%esi
L43:
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L34
L18:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%r9d
  jmp    L18
```

assistant: ```c
int jumpOpt(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return 0;
  }
  int farthest = nums[0];
  int jump = 1;
  int farAt = nums[0];
  for (int i = 1; i < numsSize - 1; i++) {
    if (nums[i] + i > farthest) {
      farthest = nums[i] + i;
    }
    if (farAt == i) {
      jump++;
      farAt = farthest;
    }
  }
  return jump;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jumpOpt>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L0
  mov    (%rdi),%edx
  cmp    $0x2,%esi
  je     L40
  lea    -0x3(%rsi),%r8d
  mov    $0x1,%eax
  mov    %edx,%esi
  mov    $0x1,%r9d
  add    $0x2,%r8
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rdi,%rax,4),%ecx
  add    %eax,%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  cmp    %eax,%esi
  jne    L2
  add    $0x1,%r9d
  mov    %edx,%esi
L2:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L29
L0:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L40:
  mov    $0x1,%r9d
  jmp    L0
```

assistant: ```c
int jumpOpt(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return 0;
  }
  int farthest = nums[0];
  int jump = 1;
  int farAt = nums[0];
  for (int i = 1; i < numsSize - 1; i++) {
    if (nums[i] + i > farthest) {
      farthest = nums[i] + i;
    }
    if (farAt == i) {
      jump++;
      farAt = farthest;
    }
  }
  return jump;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<update_rect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    $0x0,%eax
  call   <cli@plt>
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <update_rect0@plt>
  mov    $0x0,%eax
  call   <sti@plt>
  nop
  leave
  ret
```

assistant: ```c
void update_rect(int sid, int x, int y, int w, int h) {
  cli();
  update_rect0(sid, x, y, w, h, true);
  sti();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<update_rect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    $0x0,%eax
  call   <cli@plt>
  mov    $0x1,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <update_rect0@plt>
  mov    $0x0,%eax
  call   <sti@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void update_rect(int sid, int x, int y, int w, int h) {
  cli();
  update_rect0(sid, x, y, w, h, true);
  sti();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_rect>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  call   <cli@plt>
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x1,%r9d
  call   <update_rect0@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <sti@plt>
```

assistant: ```c
void update_rect(int sid, int x, int y, int w, int h) {
  cli();
  update_rect0(sid, x, y, w, h, true);
  sti();
}
```
user: Translate the below assembly code into C programming language:

```asm
<update_rect>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  call   <cli@plt>
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x1,%r9d
  call   <update_rect0@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <sti@plt>
```

assistant: ```c
void update_rect(int sid, int x, int y, int w, int h) {
  cli();
  update_rect0(sid, x, y, w, h, true);
  sti();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Swap(int *x, int *y) {
  int Tmp;
  Tmp = *x;
  *x = *y;
  *y = Tmp;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void Swap(int *x, int *y) {
  int Tmp;
  Tmp = *x;
  *x = *y;
  *y = Tmp;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void Swap(int *x, int *y) {
  int Tmp;
  Tmp = *x;
  *x = *y;
  *y = Tmp;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void Swap(int *x, int *y) {
  int Tmp;
  Tmp = *x;
  *x = *y;
  *y = Tmp;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_gids>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setresgid@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int set_gids(gid_t rgid, gid_t egid, gid_t sgid) {
  if ((setresgid(rgid, egid, sgid)) == -1)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_gids>:
  endbr64
  sub    $0x8,%rsp
  call   <setresgid@plt>
  cmp    $0xffffffff,%eax
  je     L8
L15:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L15
```

assistant: ```c
int set_gids(gid_t rgid, gid_t egid, gid_t sgid) {
  if ((setresgid(rgid, egid, sgid)) == -1)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_gids>:
  endbr64
  sub    $0x8,%rsp
  call   <setresgid@plt>
  cmp    $0xffffffff,%eax
  je     L4
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_gids(gid_t rgid, gid_t egid, gid_t sgid) {
  if ((setresgid(rgid, egid, sgid)) == -1)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_gids>:
  endbr64
  sub    $0x8,%rsp
  call   <setresgid@plt>
  cmp    $0xffffffff,%eax
  je     L9
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int set_gids(gid_t rgid, gid_t egid, gid_t sgid) {
  if ((setresgid(rgid, egid, sgid)) == -1)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L39
L59:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  jne    L8
  cmpl   $0x1,-0xc(%rbp)
  jne    L8
  movl   $0x1,-0x14(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L8:
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L59
L27:
  cmpl   $0x0,-0x14(%rbp)
  jne    L43
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L43:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D25: %d

tool: D0: Yes

tool: D19: No

assistant: ```c
int main() {
  int n, check1, check2, x = 2, y = 0;
  scanf("%d", &n);
  while (x <= n - 2) {
    check1 = check_prime(x);
    check2 = check_prime(n - x);
    if (check1 == 1 && check2 == 1) {
      y = 1;
      printf("Yes");
      break;
    }
    x = x + 1;
  }
  if (y == 0)
    printf("No");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L53
  mov    $0x2,%ebx
  jmp    L26
L57:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L53
L26:
  mov    %ebx,%edi
  call   <check_prime@plt>
  mov    %eax,%ebp
  mov    0x4(%rsp),%edi
  sub    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%ebp
  jne    L57
  cmp    $0x1,%eax
  jne    L57
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L53:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D7: %d

tool: D11: Yes

tool: D3: No

assistant: ```c
int main() {
  int n, check1, check2, x = 2, y = 0;
  scanf("%d", &n);
  while (x <= n - 2) {
    check1 = check_prime(x);
    check2 = check_prime(n - x);
    if (check1 == 1 && check2 == 1) {
      y = 1;
      printf("Yes");
      break;
    }
    x = x + 1;
  }
  if (y == 0)
    printf("No");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L55
  mov    $0x2,%ebx
  jmp    L16
  nopl   0x0(%rax)
L23:
  mov    0x4(%rsp),%eax
  add    $0x1,%ebx
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L55
L16:
  mov    %ebx,%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%ebp
  sub    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%ebp
  jne    L23
  cmp    $0x1,%eax
  jne    L23
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L55:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D19: %d

tool: D24: Yes

tool: D3: No

assistant: ```c
int main() {
  int n, check1, check2, x = 2, y = 0;
  scanf("%d", &n);
  while (x <= n - 2) {
    check1 = check_prime(x);
    check2 = check_prime(n - x);
    if (check1 == 1 && check2 == 1) {
      y = 1;
      printf("Yes");
      break;
    }
    x = x + 1;
  }
  if (y == 0)
    printf("No");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L48
  mov    $0x2,%ebx
  jmp    L67
  nopl   0x0(%rax)
L38:
  mov    0x4(%rsp),%eax
  add    $0x1,%ebx
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L48
L67:
  mov    %ebx,%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%ebp
  sub    %ebx,%edi
  call   <check_prime@plt>
  cmp    $0x1,%ebp
  jne    L38
  cmp    $0x1,%eax
  jne    L38
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L50
L48:
  lea    D18(%rip),%rdi
  call   <printf@plt>
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: string
name: unpack_data
arguments: data_tag: D26
type_infered: string
name: unpack_data
arguments: data_tag: D18
type_infered: string

tool: D17: %d

tool: D26: Yes

tool: D18: No

assistant: ```c
int main() {
  int n, check1, check2, x = 2, y = 0;
  scanf("%d", &n);
  while (x <= n - 2) {
    check1 = check_prime(x);
    check2 = check_prime(n - x);
    if (check1 == 1 && check2 == 1) {
      y = 1;
      printf("Yes");
      break;
    }
    x = x + 1;
  }
  if (y == 0)
    printf("No");
  return 0;
}
```