user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L91
  cmpq   $0x0,-0x30(%rbp)
  je     L91
  cmpq   $0x0,-0x38(%rbp)
  jne    L81
L91:
  mov    $0xffffffff,%eax
  jmp    L17
L81:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L53
L3:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L10
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L12
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L10:
  cmpl   $0x0,-0xc(%rbp)
  je     L77
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
L77:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L12:
  addl   $0x1,-0x10(%rbp)
L53:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
L17:
  leave
  ret
```

assistant: ```c
int split(char *source, char **destination, char *delimiter) {
  if (!(source && destination && delimiter))
    return -1;
  int substring_number = 0, source_index = 0, delimiter_index = 0, substring_index = 0;
  int delimiterLength;
  delimiterLength = strlen(delimiter);
  while (source[source_index] != 0) {
    if (source[source_index] == delimiter[delimiter_index]) {
      delimiter_index++;
      if (delimiter_index == delimiterLength) {
        delimiter_index = 0;
        destination[substring_number][substring_index] = 0;
        substring_number++;
        substring_index = 0;
      }
    } else {
      if (delimiter_index) {
        strncpy(destination[substring_number], delimiter, delimiter_index);
        substring_index = substring_index + delimiter_index;
        delimiter_index = 0;
      }
      destination[substring_number][substring_index] = source[source_index];
      substring_index++;
    }
    source_index++;
  }
  destination[substring_number][substring_index] = 0;
  substring_number++;
  return substring_number;
}
```