ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<afficher_chaine_masquee>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  jmp    L48
  nopl   0x0(%rax)
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r12,%rbx
  je     L2
L48:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L14
  mov    $0x5f,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L48
L2:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

assistant: ```c
void afficher_chaine_masquee(const char *chaine, const char *trouves) {
  int taille = strlen(chaine), i;
  for (i = 0; i < taille; i++) {
    if (strchr(trouves, chaine[i]) == NULL) {
      printf("_");
    } else {
      printf("%c", chaine[i]);
    }
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L6:
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x20,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setchar@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x4f,-0x4(%rbp)
  jle    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void clear_line(int line) {
  for (int col = 0; col < 80; col++)
    setchar(line, col, ' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clear_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L2:
  mov    $0x20,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <setchar@plt>
  add    $0x1,%ebx
  cmp    $0x50,%ebx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void clear_line(int line) {
  for (int col = 0; col < 80; col++)
    setchar(line, col, ' ');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_line>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L3:
  mov    %ebx,%esi
  mov    $0x20,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <setchar@plt>
  cmp    $0x50,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void clear_line(int line) {
  for (int col = 0; col < 80; col++)
    setchar(line, col, ' ');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clear_line>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L9:
  mov    %ebx,%esi
  mov    $0x20,%edx
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <setchar@plt>
  cmp    $0x50,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void clear_line(int line) {
  for (int col = 0; col < 80; col++)
    setchar(line, col, ' ');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_ctr>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  mov    %rsp,%rcx
  lea    0x10(%rsp),%r9
  mov    %rcx,%rsi
L28:
  mov    (%rdi),%eax
  shl    $0x18,%eax
  mov    0x4(%rdi),%r8d
  shl    $0x10,%r8d
  or     %r8d,%eax
  or     0xc(%rdi),%eax
  mov    0x8(%rdi),%r8d
  shl    $0x8,%r8d
  or     %r8d,%eax
  mov    %eax,(%rsi)
  add    $0x10,%rdi
  add    $0x4,%rsi
  cmp    %r9,%rsi
  jne    L28
  lea    -0x10(%rcx),%r8
  mov    %rcx,%rax
L36:
  mov    0xc(%rax),%edi
  lea    (%rdi,%r10,1),%esi
  cmp    %esi,%edi
  setg   %r10b
  movzbl %r10b,%r10d
  mov    %esi,0xc(%rax)
  sub    $0x4,%rax
  cmp    %r8,%rax
  jne    L36
L2:
  mov    (%rcx),%eax
  mov    %eax,%esi
  sar    $0x18,%esi
  mov    %esi,(%rdx)
  mov    %eax,%esi
  sar    $0x10,%esi
  mov    %esi,0x4(%rdx)
  mov    %eax,%esi
  sar    $0x8,%esi
  mov    %esi,0x8(%rdx)
  mov    %eax,0xc(%rdx)
  add    $0x4,%rcx
  add    $0x10,%rdx
  cmp    %r9,%rcx
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_ctr(void *ctr, uint32_t carry) {
  uint32_t counter[4];
  uint8_t *outctr = (uint8_t *)ctr;
  uint32_t sum;
  int32_t i;
  for (i = 0; i < 4; i++) {
    counter[i] = (outctr[i * 4 + 0] << 24) | (outctr[i * 4 + 1] << 16) | (outctr[i * 4 + 2] << 8) | (outctr[i * 4 + 3] << 0);
  }
  for (i = 3; i >= 0; i--) {
    sum = counter[i] + carry;
    if (sum < counter[i]) {
      carry = 1;
    } else {
      carry = 0;
    }
    counter[i] = sum;
  }
  for (i = 0; i < 4; i++) {
    outctr[i * 4 + 0] = counter[i] >> 24;
    outctr[i * 4 + 1] = counter[i] >> 16;
    outctr[i * 4 + 2] = counter[i] >> 8;
    outctr[i * 4 + 3] = counter[i] >> 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_ctr>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %esi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x10(%rsp),%r9
  mov    %rdx,%rcx
  mov    %rsi,%rdi
L0:
  mov    (%rcx),%eax
  mov    0x4(%rcx),%r8d
  add    $0x4,%rdi
  add    $0x10,%rcx
  shl    $0x10,%r8d
  shl    $0x18,%eax
  or     %r8d,%eax
  mov    -0x8(%rcx),%r8d
  or     -0x4(%rcx),%eax
  shl    $0x8,%r8d
  or     %r8d,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%r9
  jne    L0
  lea    -0x10(%rsi),%r8
  mov    %rsi,%rax
L36:
  mov    0xc(%rax),%edi
  lea    (%rdi,%r10,1),%ecx
  xor    %r10d,%r10d
  cmp    %ecx,%edi
  mov    %ecx,0xc(%rax)
  setg   %r10b
  sub    $0x4,%rax
  cmp    %rax,%r8
  jne    L36
L23:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  add    $0x10,%rdx
  mov    %eax,%ecx
  mov    %eax,-0x4(%rdx)
  sar    $0x18,%ecx
  mov    %ecx,-0x10(%rdx)
  mov    %eax,%ecx
  sar    $0x10,%ecx
  mov    %ecx,-0xc(%rdx)
  mov    %eax,%ecx
  sar    $0x8,%ecx
  mov    %ecx,-0x8(%rdx)
  cmp    %rsi,%r9
  jne    L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_ctr(void *ctr, uint32_t carry) {
  uint32_t counter[4];
  uint8_t *outctr = (uint8_t *)ctr;
  uint32_t sum;
  int32_t i;
  for (i = 0; i < 4; i++) {
    counter[i] = (outctr[i * 4 + 0] << 24) | (outctr[i * 4 + 1] << 16) | (outctr[i * 4 + 2] << 8) | (outctr[i * 4 + 3] << 0);
  }
  for (i = 3; i >= 0; i--) {
    sum = counter[i] + carry;
    if (sum < counter[i]) {
      carry = 1;
    } else {
      carry = 0;
    }
    counter[i] = sum;
  }
  for (i = 0; i < 4; i++) {
    outctr[i * 4 + 0] = counter[i] >> 24;
    outctr[i * 4 + 1] = counter[i] >> 16;
    outctr[i * 4 + 2] = counter[i] >> 8;
    outctr[i * 4 + 3] = counter[i] >> 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add_ctr>:
  endbr64
  movdqu (%rdi),%xmm2
  movdqu 0x20(%rdi),%xmm3
  xor    %edx,%edx
  movdqu 0x10(%rdi),%xmm7
  movdqu 0x30(%rdi),%xmm6
  movdqa %xmm2,%xmm1
  movdqa %xmm3,%xmm5
  shufps $0x88,%xmm7,%xmm1
  shufps $0xdd,%xmm7,%xmm2
  movdqa %xmm1,%xmm4
  movdqa %xmm2,%xmm0
  shufps $0x88,%xmm6,%xmm5
  shufps $0xdd,%xmm6,%xmm3
  shufps $0x88,%xmm5,%xmm4
  shufps $0x88,%xmm3,%xmm0
  pslld  $0x18,%xmm4
  shufps $0xdd,%xmm5,%xmm1
  pslld  $0x10,%xmm0
  shufps $0xdd,%xmm3,%xmm2
  pslld  $0x8,%xmm1
  por    %xmm4,%xmm0
  por    %xmm2,%xmm1
  por    %xmm1,%xmm0
  pshufd $0xff,%xmm0,%xmm1
  movq   %xmm0,-0x18(%rsp)
  punpckhdq %xmm0,%xmm0
  movd   %xmm1,%eax
  add    %eax,%esi
  cmp    %eax,%esi
  movd   %xmm0,%eax
  movd   %esi,%xmm5
  setl   %dl
  add    %edx,%eax
  movd   %eax,%xmm6
  punpckldq %xmm5,%xmm6
  movq   %xmm6,-0x10(%rsp)
  movdqa -0x18(%rsp),%xmm0
  movdqa -0x18(%rsp),%xmm1
  movdqa -0x18(%rsp),%xmm3
  psrad  $0x18,%xmm0
  psrad  $0x10,%xmm1
  psrad  $0x8,%xmm3
  movdqa %xmm0,%xmm2
  punpckldq %xmm3,%xmm2
  punpckhdq %xmm3,%xmm0
  movdqa %xmm1,%xmm3
  punpckldq -0x18(%rsp),%xmm3
  punpckhdq -0x18(%rsp),%xmm1
  movdqa %xmm2,%xmm4
  punpckhdq %xmm3,%xmm2
  punpckldq %xmm3,%xmm4
  movups %xmm2,0x10(%rdi)
  movdqa %xmm0,%xmm2
  punpckhdq %xmm1,%xmm0
  punpckldq %xmm1,%xmm2
  movups %xmm4,(%rdi)
  movups %xmm2,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  ret
```

assistant: ```c
void add_ctr(void *ctr, uint32_t carry) {
  uint32_t counter[4];
  uint8_t *outctr = (uint8_t *)ctr;
  uint32_t sum;
  int32_t i;
  for (i = 0; i < 4; i++) {
    counter[i] = (outctr[i * 4 + 0] << 24) | (outctr[i * 4 + 1] << 16) | (outctr[i * 4 + 2] << 8) | (outctr[i * 4 + 3] << 0);
  }
  for (i = 3; i >= 0; i--) {
    sum = counter[i] + carry;
    if (sum < counter[i]) {
      carry = 1;
    } else {
      carry = 0;
    }
    counter[i] = sum;
  }
  for (i = 0; i < 4; i++) {
    outctr[i * 4 + 0] = counter[i] >> 24;
    outctr[i * 4 + 1] = counter[i] >> 16;
    outctr[i * 4 + 2] = counter[i] >> 8;
    outctr[i * 4 + 3] = counter[i] >> 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printIntArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L8:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: 	%d 

assistant: ```c
void printIntArray(int a[10], int n) {
  int i;
  for (i = 0; i < n;) {
    printf("\t%d ", a[++i]);
    if (i % 5 == 0)
      printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printIntArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L27
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    0x4(%rdi),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%r12d
  mov    $0x2,%ebx
  lea    D5(%rip),%r13
  jmp    L11
L19:
  add    $0x1,%rbx
L11:
  cmp    %rbx,%r12
  je     L27
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %ebx,%eax
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L19
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: 	%d 

assistant: ```c
void printIntArray(int a[10], int n) {
  int i;
  for (i = 0; i < n;) {
    printf("\t%d ", a[++i]);
    if (i % 5 == 0)
      printf("\n");
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printIntArray>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  lea    D5(%rip),%r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x1(%rbx),%r12d
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  mov    0x4(%rdi),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L27
  mov    $0xa,%edi
  call   <putchar@plt>
L27:
  add    $0x1,%rbx
L35:
  cmp    %rbx,%r12
  jne    L1
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: 	%d 

assistant: ```c
void printIntArray(int a[10], int n) {
  int i;
  for (i = 0; i < n;) {
    printf("\t%d ", a[++i]);
    if (i % 5 == 0)
      printf("\n");
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printIntArray>:
  endbr64
  test   %esi,%esi
  jle    L29
  push   %r14
  mov    %esi,%r14d
  xor    %eax,%eax
  push   %r13
  lea    0x1(%r14),%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    0x4(%rdi),%esi
  mov    %r12,%rdi
  mov    $0x2,%ebx
  call   <printf@plt>
  cmp    $0x1,%r14d
  je     L1
  nopl   0x0(%rax)
L12:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L37
  mov    $0xa,%edi
  call   <putchar@plt>
L37:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L12
L1:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
L29:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: 	%d 

assistant: ```c
void printIntArray(int a[10], int n) {
  int i;
  for (i = 0; i < n;) {
    printf("\t%d ", a[++i]);
    if (i % 5 == 0)
      printf("\n");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fi4c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <atomic_compare_exchange_strong@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
_Bool fi4c(atomic_int *i) {
  int cmp = 0;
  return atomic_compare_exchange_strong(i, &cmp, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fi4c>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <atomic_compare_exchange_strong@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_Bool fi4c(atomic_int *i) {
  int cmp = 0;
  return atomic_compare_exchange_strong(i, &cmp, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fi4c>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <atomic_compare_exchange_strong@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_Bool fi4c(atomic_int *i) {
  int cmp = 0;
  return atomic_compare_exchange_strong(i, &cmp, 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fi4c>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <atomic_compare_exchange_strong@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_Bool fi4c(atomic_int *i) {
  int cmp = 0;
  return atomic_compare_exchange_strong(i, &cmp, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hard_bsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  bsr    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hard_bsr(unsigned int n) {
  unsigned long r;
  __asm__ __volatile__("bsr %1,%0" : "=r"(r) : "rm"(n));
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_fixed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L20:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x9,-0xc(%rbp)
  jbe    L29
  mov    $0x0,%eax
  jmp    L31
L29:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L20
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char const *parse_fixed(char const *s, int digits, int *res) {
  int n = 0;
  char const *lim = s + digits;
  while (s < lim) {
    unsigned d = *s++ - '0';
    if (9 < d)
      return 0;
    n = 10 * n + d;
  }
  *res = n;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_fixed>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L3
  mov    $0x0,%ecx
L49:
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L23
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  cmp    %rdi,%rsi
  jne    L49
L16:
  mov    %ecx,(%rdx)
L9:
  mov    %rsi,%rax
  ret
L3:
  mov    %rdi,%rsi
  mov    $0x0,%ecx
  jmp    L16
L23:
  mov    $0x0,%esi
  jmp    L9
```

assistant: ```c
char const *parse_fixed(char const *s, int digits, int *res) {
  int n = 0;
  char const *lim = s + digits;
  while (s < lim) {
    unsigned d = *s++ - '0';
    if (9 < d)
      return 0;
    n = 10 * n + d;
  }
  *res = n;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_fixed>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%r8
  cmp    %r8,%rdi
  jae    L31
  xor    %ecx,%ecx
  jmp    L10
  nopl   0x0(%rax)
L1:
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  cmp    %rdi,%r8
  je     L33
L10:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L1
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L31:
  mov    %rdi,%r8
  xor    %ecx,%ecx
L33:
  mov    %ecx,(%rdx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *parse_fixed(char const *s, int digits, int *res) {
  int n = 0;
  char const *lim = s + digits;
  while (s < lim) {
    unsigned d = *s++ - '0';
    if (9 < d)
      return 0;
    n = 10 * n + d;
  }
  *res = n;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_fixed>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%r8
  cmp    %r8,%rdi
  jae    L20
  xor    %ecx,%ecx
  jmp    L35
  nopl   0x0(%rax)
L13:
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  cmp    %rdi,%r8
  je     L14
L35:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L13
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L20:
  mov    %rdi,%r8
  xor    %ecx,%ecx
L14:
  mov    %ecx,(%rdx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *parse_fixed(char const *s, int digits, int *res) {
  int n = 0;
  char const *lim = s + digits;
  while (s < lim) {
    unsigned d = *s++ - '0';
    if (9 < d)
      return 0;
    n = 10 * n + d;
  }
  *res = n;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jg     L13
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
L13:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <init@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <run@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: ./sphc <init file> <steps> <dt>


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 4) {
    printf("./sphc <init file> <steps> <dt>\n");
    return 1;
  }
  init(argv[1]);
  double steps = atoi(argv[2]);
  double dt = atof(argv[3]);
  run(steps, dt);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L4
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <init@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  movq   %xmm0,%rbp
  mov    0x18(%rbx),%rdi
  call   <atof@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  call   <run@plt>
  mov    $0x0,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: ./sphc <init file> <steps> <dt>


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 4) {
    printf("./sphc <init file> <steps> <dt>\n");
    return 1;
  }
  init(argv[1]);
  double steps = atoi(argv[2]);
  double dt = atof(argv[3]);
  run(steps, dt);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x3,%edi
  jle    L17
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <init@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <run@plt>
  xor    %eax,%eax
L4:
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: ./sphc <init file> <steps> <dt>


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 4) {
    printf("./sphc <init file> <steps> <dt>\n");
    return 1;
  }
  init(argv[1]);
  double steps = atoi(argv[2]);
  double dt = atof(argv[3]);
  run(steps, dt);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x3,%edi
  jle    L0
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <init@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <run@plt>
  xor    %eax,%eax
L14:
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: ./sphc <init file> <steps> <dt>


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 4) {
    printf("./sphc <init file> <steps> <dt>\n");
    return 1;
  }
  init(argv[1]);
  double steps = atoi(argv[2]);
  double dt = atof(argv[3]);
  run(steps, dt);
  return 0;
}
```