ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<print_quotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <print_img_link@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L29
L65:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_quotes(char *str) {
  int i = 0;
  while (str[i]) {
    if (str[i] == '"') {
      print_img_link(&str[i + 1]);
      ++i;
      while (str[i] != '"' && str[i])
        ++i;
    }
    if (str[i])
      ++i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_quotes>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%edx
  jmp    L0
L28:
  lea    0x1(%rbp,%rdx,1),%rdi
  call   <print_img_link@plt>
  lea    0x1(%rbx),%edx
  movslq %edx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  cmp    $0x22,%al
  je     L69
  test   %al,%al
  je     L69
  lea    0x2(%rbx),%eax
  cltq
L13:
  mov    %eax,%ebx
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x22,%dl
  je     L3
  test   %dl,%dl
  jne    L13
  jmp    L3
L69:
  mov    %edx,%ebx
  jmp    L3
L8:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%eax
  test   %al,%al
  je     L25
L0:
  cmp    $0x22,%al
  je     L28
L3:
  movslq %ebx,%rax
  cmpb   $0x0,0x0(%rbp,%rax,1)
  jne    L8
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  ret
```

assistant: ```c
void print_quotes(char *str) {
  int i = 0;
  while (str[i]) {
    if (str[i] == '"') {
      print_img_link(&str[i + 1]);
      ++i;
      while (str[i] != '"' && str[i])
        ++i;
    }
    if (str[i])
      ++i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_quotes>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  cmp    $0x22,%al
  je     L92
L34:
  movslq %ebx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
L64:
  test   %al,%al
  jne    L36
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%eax
  test   %al,%al
  je     L68
  cmp    $0x22,%al
  jne    L34
L92:
  lea    0x1(%rbp,%rdx,1),%rdi
  call   <print_img_link@plt>
  lea    0x1(%rbx),%edx
  movslq %edx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  cmp    $0x22,%al
  je     L49
  test   %al,%al
  je     L49
  add    $0x2,%ebx
  movslq %ebx,%rdx
  xchg   %ax,%ax
L15:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    %edx,%ebx
  add    $0x1,%rdx
  cmp    $0x22,%al
  je     L64
  test   %al,%al
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  ret
L49:
  mov    %edx,%ebx
  jmp    L64
```

assistant: ```c
void print_quotes(char *str) {
  int i = 0;
  while (str[i]) {
    if (str[i] == '"') {
      print_img_link(&str[i + 1]);
      ++i;
      while (str[i] != '"' && str[i])
        ++i;
    }
    if (str[i])
      ++i;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_quotes>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L76
  xchg   %ax,%ax
L10:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%eax
  test   %al,%al
  je     L41
L76:
  cmp    $0x22,%al
  jne    L10
  lea    0x1(%rbp,%rdx,1),%rdi
  call   <print_img_link@plt>
  lea    0x1(%rbx),%edx
  movslq %edx,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  cmp    $0x22,%al
  je     L75
  test   %al,%al
  je     L41
  add    $0x2,%ebx
  movslq %ebx,%rbx
  cs nopw 0x0(%rax,%rax,1)
L90:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %ebx,%edx
  add    $0x1,%rbx
  cmp    $0x22,%al
  je     L75
  test   %al,%al
  jne    L90
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  test   %al,%al
  je     L41
  mov    %edx,%ebx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L32:
  ret
```

assistant: ```c
void print_quotes(char *str) {
  int i = 0;
  while (str[i]) {
    if (str[i] == '"') {
      print_img_link(&str[i + 1]);
      ++i;
      while (str[i] != '"' && str[i])
        ++i;
    }
    if (str[i])
      ++i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fulfil2DArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L4:
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L6
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fulfil2DArray(int **arr, int n, int m) {
  int i = 0, j = 0;
  int count = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      arr[i][j] = count;
      count++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fulfil2DArray>:
  endbr64
  test   %esi,%esi
  jle    L37
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r9
  mov    $0x1,%eax
  jmp    L26
L27:
  mov    (%r8),%rsi
  mov    %eax,(%rsi,%rcx,1)
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    %edi,%eax
  jne    L27
L1:
  add    $0x8,%r8
  cmp    %r9,%r8
  je     L37
L26:
  lea    (%rax,%rdx,1),%edi
  mov    $0x0,%ecx
  test   %edx,%edx
  jg     L27
  jmp    L1
L37:
  ret
```

assistant: ```c
void fulfil2DArray(int **arr, int n, int m) {
  int i = 0, j = 0;
  int count = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      arr[i][j] = count;
      count++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fulfil2DArray>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r8
  mov    $0x1,%eax
  nopl   (%rax)
L23:
  test   %edx,%edx
  jle    L16
  mov    (%rdi),%rcx
  lea    (%rdx,%rax,1),%esi
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %eax,(%rcx)
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    %esi,%eax
  jne    L20
L16:
  add    $0x8,%rdi
  cmp    %r8,%rdi
  jne    L23
L11:
  ret
```

assistant: ```c
void fulfil2DArray(int **arr, int n, int m) {
  int i = 0, j = 0;
  int count = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      arr[i][j] = count;
      count++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fulfil2DArray>:
  endbr64
  test   %esi,%esi
  jle    L67
  mov    %edx,%r8d
  test   %edx,%edx
  jle    L67
  lea    -0x1(%rsi),%eax
  push   %r13
  mov    %edx,%r9d
  movdqa D7(%rip),%xmm2
  push   %r12
  lea    -0x1(%rdx),%r11d
  and    $0xfffffffc,%r9d
  push   %rbp
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbx
  mov    %edx,%eax
  mov    $0x1,%edx
  shr    $0x2,%eax
  lea    -0x1(%rax),%r10d
  add    $0x1,%r10
  shl    $0x4,%r10
  xchg   %ax,%ax
L88:
  mov    (%rdi),%rsi
  cmp    $0x2,%r11d
  jbe    L68
  lea    0x2(%rdx),%ecx
  lea    0x1(%rdx),%eax
  movd   %edx,%xmm0
  movd   %ecx,%xmm1
  lea    0x3(%rdx),%ecx
  movd   %eax,%xmm4
  mov    %rsi,%rax
  movd   %ecx,%xmm3
  punpckldq %xmm4,%xmm0
  lea    (%r10,%rsi,1),%rcx
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  nopl   0x0(%rax)
L54:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rcx
  jne    L54
  lea    (%rdx,%r9,1),%eax
  mov    %r9d,%ecx
  cmp    %r9d,%r8d
  je     L85
L11:
  movslq %ecx,%rbp
  lea    0x1(%rax),%r13d
  mov    %eax,(%rsi,%rbp,4)
  lea    0x0(,%rbp,4),%r12
  lea    0x1(%rcx),%ebp
  cmp    %r8d,%ebp
  jge    L85
  add    $0x2,%ecx
  mov    %r13d,0x4(%rsi,%r12,1)
  add    $0x2,%eax
  cmp    %ecx,%r8d
  jle    L85
  mov    %eax,0x8(%rsi,%r12,1)
L85:
  add    $0x8,%rdi
  add    %r8d,%edx
  cmp    %rdi,%rbx
  jne    L88
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L68:
  mov    %edx,%eax
  xor    %ecx,%ecx
  jmp    L11
L67:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: byte[16]

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void fulfil2DArray(int **arr, int n, int m) {
  int i = 0, j = 0;
  int count = 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      arr[i][j] = count;
      count++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_for_learn_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %rdi,-0x2728(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2728(%rbp),%rdx
  lea    -0x2720(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <str_lower@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <trim_extra_spaces@plt>
  movzbl -0x2720(%rbp),%eax
  cmp    $0x7b,%al
  jne    L86
  movzbl -0x271f(%rbp),%eax
  cmp    $0x6c,%al
  jne    L86
  movzbl -0x271e(%rbp),%eax
  cmp    $0x65,%al
  jne    L86
  movzbl -0x271d(%rbp),%eax
  cmp    $0x61,%al
  jne    L86
  movzbl -0x271c(%rbp),%eax
  cmp    $0x72,%al
  jne    L86
  movzbl -0x271b(%rbp),%eax
  cmp    $0x6e,%al
  jne    L86
  movzbl -0x271a(%rbp),%eax
  cmp    $0x7d,%al
  jne    L86
  mov    $0x1,%eax
  jmp    L58
L86:
  mov    $0x0,%eax
L58:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

assistant: ```c
int check_for_learn_command(char *str) {
  char usrqry[10000];
  strcpy(usrqry, str);
  str_lower(usrqry);
  trim_extra_spaces(usrqry);
  if (usrqry[0] == '{' && usrqry[1] == 'l' && usrqry[2] == 'e' && usrqry[3] == 'a' && usrqry[4] == 'r' && usrqry[5] == 'n' && usrqry[6] == '}') {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_for_learn_command>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <str_lower@plt>
  mov    %rbx,%rdi
  call   <trim_extra_spaces@plt>
  mov    $0x0,%eax
  cmpb   $0x7b,(%rsp)
  je     L53
L3:
  mov    0x2718(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x2720,%rsp
  pop    %rbx
  ret
L53:
  cmpb   $0x6c,0x1(%rsp)
  jne    L3
  cmpb   $0x65,0x2(%rsp)
  jne    L3
  cmpb   $0x61,0x3(%rsp)
  jne    L3
  cmpb   $0x72,0x4(%rsp)
  jne    L3
  cmpb   $0x6e,0x5(%rsp)
  jne    L3
  cmpb   $0x7d,0x6(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L3
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_for_learn_command(char *str) {
  char usrqry[10000];
  strcpy(usrqry, str);
  str_lower(usrqry);
  trim_extra_spaces(usrqry);
  if (usrqry[0] == '{' && usrqry[1] == 'l' && usrqry[2] == 'e' && usrqry[3] == 'a' && usrqry[4] == 'r' && usrqry[5] == 'n' && usrqry[6] == '}') {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_for_learn_command>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <str_lower@plt>
  mov    %rbp,%rdi
  call   <trim_extra_spaces@plt>
  xor    %eax,%eax
  cmpb   $0x7b,(%rsp)
  je     L69
L14:
  mov    0x2718(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x2720,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L69:
  cmpb   $0x6c,0x1(%rsp)
  jne    L14
  cmpb   $0x65,0x2(%rsp)
  jne    L14
  cmpb   $0x61,0x3(%rsp)
  jne    L14
  cmpb   $0x72,0x4(%rsp)
  jne    L14
  cmpb   $0x6e,0x5(%rsp)
  jne    L14
  xor    %eax,%eax
  cmpb   $0x7d,0x6(%rsp)
  sete   %al
  jmp    L14
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_for_learn_command(char *str) {
  char usrqry[10000];
  strcpy(usrqry, str);
  str_lower(usrqry);
  trim_extra_spaces(usrqry);
  if (usrqry[0] == '{' && usrqry[1] == 'l' && usrqry[2] == 'e' && usrqry[3] == 'a' && usrqry[4] == 'r' && usrqry[5] == 'n' && usrqry[6] == '}') {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_for_learn_command>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <str_lower@plt>
  mov    %rbp,%rdi
  call   <trim_extra_spaces@plt>
  xor    %eax,%eax
  cmpb   $0x7b,(%rsp)
  je     L47
L62:
  mov    0x2718(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x2720,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L47:
  cmpb   $0x6c,0x1(%rsp)
  jne    L62
  cmpb   $0x65,0x2(%rsp)
  jne    L62
  cmpb   $0x61,0x3(%rsp)
  jne    L62
  cmpb   $0x72,0x4(%rsp)
  jne    L62
  cmpb   $0x6e,0x5(%rsp)
  jne    L62
  xor    %eax,%eax
  cmpb   $0x7d,0x6(%rsp)
  sete   %al
  jmp    L62
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_for_learn_command(char *str) {
  char usrqry[10000];
  strcpy(usrqry, str);
  str_lower(usrqry);
  trim_extra_spaces(usrqry);
  if (usrqry[0] == '{' && usrqry[1] == 'l' && usrqry[2] == 'e' && usrqry[3] == 'a' && usrqry[4] == 'r' && usrqry[5] == 'n' && usrqry[6] == '}') {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gamm_rndc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L10:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gengam@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void gamm_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = gengam(a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gamm_rndc>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  movq   %xmm1,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r13
L11:
  movq   %r12,%xmm1
  movq   %rbp,%xmm0
  call   <gengam@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

assistant: ```c
void gamm_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = gengam(a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gamm_rndc>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %r14
  lea    -0x1(%rdi),%eax
  movq   %xmm0,%r14
  push   %rbp
  lea    0x8(%rsi,%rax,8),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
L7:
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <gengam@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void gamm_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = gengam(a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gamm_rndc>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r14
  lea    -0x1(%rdi),%eax
  movq   %xmm0,%r14
  push   %rbp
  lea    0x8(%rsi,%rax,8),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
L14:
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <gengam@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  nopl   (%rax)
L5:
  ret
```

assistant: ```c
void gamm_rndc(int n, double a, double b, double *array) {
  int i;
  for (i = 0; i < n; i++)
    *(array + i) = gengam(a, b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AllocAndReadFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1000,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L5
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L19
L5:
  nop
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint8_t *AllocAndReadFile(FILE *fh, uint32_t *size) {
  const int blocksize = 4096;
  uint8_t *buf = malloc(blocksize);
  uint32_t total = 0;
  for (;;) {
    uint32_t actual = fread(buf + total, 1, blocksize, fh);
    total += actual;
    if (actual < blocksize)
      break;
    buf = realloc(buf, total + blocksize);
  }
  *size = total;
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AllocAndReadFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%ebp
  jmp    L4
L1:
  lea    0x1000(%rbp),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
L4:
  movslq %ebp,%rax
  lea    (%rbx,%rax,4),%rdi
  mov    %r12,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  add    %eax,%ebp
  cmp    $0xfff,%eax
  jg     L1
  mov    %ebp,0x0(%r13)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint8_t *AllocAndReadFile(FILE *fh, uint32_t *size) {
  const int blocksize = 4096;
  uint8_t *buf = malloc(blocksize);
  uint32_t total = 0;
  for (;;) {
    uint32_t actual = fread(buf + total, 1, blocksize, fh);
    total += actual;
    if (actual < blocksize)
      break;
    buf = realloc(buf, total + blocksize);
  }
  *size = total;
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<AllocAndReadFile>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdi
  lea    0x1000(%r13),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L7:
  movslq %r13d,%rax
  mov    %rbx,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  lea    0x0(%rbp,%rax,4),%rdi
  call   <fread@plt>
  add    %eax,%r13d
  cmp    $0xfff,%eax
  jg     L10
  mov    %r13d,(%r12)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint8_t *AllocAndReadFile(FILE *fh, uint32_t *size) {
  const int blocksize = 4096;
  uint8_t *buf = malloc(blocksize);
  uint32_t total = 0;
  for (;;) {
    uint32_t actual = fread(buf + total, 1, blocksize, fh);
    total += actual;
    if (actual < blocksize)
      break;
    buf = realloc(buf, total + blocksize);
  }
  *size = total;
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<AllocAndReadFile>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  lea    0x1000(%r13),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L11:
  movslq %r13d,%rax
  mov    %rbx,%rcx
  mov    $0x1000,%edx
  mov    $0x1,%esi
  lea    0x0(%rbp,%rax,4),%rdi
  call   <fread@plt>
  add    %eax,%r13d
  cmp    $0xfff,%eax
  jg     L7
  mov    %r13d,(%r12)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint8_t *AllocAndReadFile(FILE *fh, uint32_t *size) {
  const int blocksize = 4096;
  uint8_t *buf = malloc(blocksize);
  uint32_t total = 0;
  for (;;) {
    uint32_t actual = fread(buf + total, 1, blocksize, fh);
    total += actual;
    if (actual < blocksize)
      break;
    buf = realloc(buf, total + blocksize);
  }
  *size = total;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kore_buf_appendf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <kore_buf_appendv@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void kore_buf_appendf(struct kore_buf *buf, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_buf_appendv(buf, fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kore_buf_appendf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <kore_buf_appendv@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void kore_buf_appendf(struct kore_buf *buf, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_buf_appendv(buf, fmt, args);
  va_end(args);
}
```