ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D51(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L50
  lea    0x20(%rsp),%r13
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D15(%rip),%rbx
  lea    D8(%rip),%r15
  lea    D16(%rip),%r14
  jmp    L77
  nopl   0x0(%rax)
L29:
  ucomisd %xmm4,%xmm8
  setnp  %dl
  cmove  %edx,%eax
  test   %al,%al
  jne    L72
  ucomisd %xmm0,%xmm4
  ja     L17
  sqrtsd %xmm0,%xmm0
L36:
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L77:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  D69(%rip),%xmm5
  pxor   %xmm4,%xmm4
  movsd  0x18(%rsp),%xmm7
  movsd  D69(%rip),%xmm0
  divsd  %xmm6,%xmm5
  movsd  0x20(%rsp),%xmm8
  movsd  D69(%rip),%xmm2
  divsd  %xmm7,%xmm0
  movapd %xmm5,%xmm3
  divsd  %xmm8,%xmm2
  addsd  %xmm0,%xmm3
  movapd %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  subsd  %xmm2,%xmm3
  mulsd  %xmm3,%xmm1
  movapd %xmm5,%xmm3
  subsd  %xmm0,%xmm3
  subsd  %xmm5,%xmm0
  addsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D69(%rip),%xmm0
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm4
  ja     L72
  ucomisd %xmm4,%xmm7
  mov    $0x0,%ecx
  setnp  %al
  cmovne %ecx,%eax
  ucomisd %xmm4,%xmm6
  setnp  %dl
  cmovne %ecx,%edx
  or     %dl,%al
  je     L29
L72:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L77
L50:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <sqrt@plt>
  jmp    L36
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D51
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D16
type: string
name: unpack_data
arguments: data_label: D69
type: f64

tool: D51: %d

tool: D15: %lf %lf %lf

tool: D8: These are invalid inputs!

tool: D16: %.3lf


tool: D69: 1

assistant: ```c
int main() {
  int t;
  double ha, hb, hc, total, root;
  scanf("%d", &t);
  while (t--) {
    while (1) {
      scanf("%lf %lf %lf", &ha, &hb, &hc);
      total = 1 / ((1.0 / ha + 1.0 / hb + 1.0 / hc) * (1.0 / ha + 1.0 / hb - 1.0 / hc) * (1.0 / ha - 1.0 / hb + 1.0 / hc) * (-1.0 / ha + 1.0 / hb + 1.0 / hc));
      if (total < 0 || ha == 0 || hb == 0 || hc == 0) {
        printf("These are invalid inputs!\n");
        break;
      } else {
        root = sqrt(total);
        printf("%.3lf\n", root);
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D41(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L3
  lea    0x20(%rsp),%r13
  lea    0x18(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D33(%rip),%rbx
  lea    D75(%rip),%r15
  lea    D48(%rip),%r14
  jmp    L44
  nopl   0x0(%rax)
L48:
  ucomisd %xmm4,%xmm8
  setnp  %dl
  cmove  %edx,%eax
  test   %al,%al
  jne    L16
  ucomisd %xmm0,%xmm4
  ja     L42
  sqrtsd %xmm0,%xmm0
L73:
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L44:
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  D76(%rip),%xmm5
  pxor   %xmm4,%xmm4
  movsd  0x18(%rsp),%xmm7
  movsd  D76(%rip),%xmm0
  divsd  %xmm6,%xmm5
  movsd  0x20(%rsp),%xmm8
  movsd  D76(%rip),%xmm2
  divsd  %xmm7,%xmm0
  movapd %xmm5,%xmm3
  divsd  %xmm8,%xmm2
  addsd  %xmm0,%xmm3
  movapd %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  subsd  %xmm2,%xmm3
  mulsd  %xmm3,%xmm1
  movapd %xmm5,%xmm3
  subsd  %xmm0,%xmm3
  subsd  %xmm5,%xmm0
  addsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D76(%rip),%xmm0
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm4
  ja     L16
  ucomisd %xmm4,%xmm7
  mov    $0x0,%ecx
  setnp  %al
  cmovne %ecx,%eax
  ucomisd %xmm4,%xmm6
  setnp  %dl
  cmovne %ecx,%edx
  or     %dl,%al
  je     L48
L16:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L44
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <sqrt@plt>
  jmp    L73
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D41
type_infered: string
name: unpack_data
arguments: tag: D33
type_infered: string
name: unpack_data
arguments: tag: D75
type_infered: string
name: unpack_data
arguments: tag: D48
type_infered: string
name: unpack_data
arguments: tag: D76
type_infered: f64

tool: D41: %d

tool: D33: %lf %lf %lf

tool: D75: These are invalid inputs!

tool: D48: %.3lf


tool: D76: 1

assistant: ```c
int main() {
  int t;
  double ha, hb, hc, total, root;
  scanf("%d", &t);
  while (t--) {
    while (1) {
      scanf("%lf %lf %lf", &ha, &hb, &hc);
      total = 1 / ((1.0 / ha + 1.0 / hb + 1.0 / hc) * (1.0 / ha + 1.0 / hb - 1.0 / hc) * (1.0 / ha - 1.0 / hb + 1.0 / hc) * (-1.0 / ha + 1.0 / hb + 1.0 / hc));
      if (total < 0 || ha == 0 || hb == 0 || hc == 0) {
        printf("These are invalid inputs!\n");
        break;
      } else {
        root = sqrt(total);
        printf("%.3lf\n", root);
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vbuschannel_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  cmpl   $0x0,-0x50(%rbp)
  jne    L132
  cmpl   $0x0,-0x4c(%rbp)
  jg     L0
  mov    $0x0,%eax
  jmp    L126
L0:
  mov    -0x48(%rbp),%rax
  movb   $0x30,(%rax)
  mov    $0x1,%eax
  jmp    L126
L72:
  cmpl   $0x1f,-0x38(%rbp)
  jle    L92
  mov    $0x0,%eax
  jmp    L126
L92:
  mov    -0x50(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x50(%rbp)
L132:
  cmpl   $0x0,-0x50(%rbp)
  jg     L72
  mov    -0x4c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jge    L71
  movl   $0x0,-0x34(%rbp)
  jmp    L110
L95:
  mov    -0x48(%rbp),%rax
  movb   $0x3f,(%rax)
  addl   $0x1,-0x34(%rbp)
  addq   $0x1,-0x48(%rbp)
L110:
  mov    -0x34(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L95
  mov    -0x4c(%rbp),%eax
  jmp    L126
L71:
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L43
L45:
  subl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%edx
  mov    -0x48(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x48(%rbp)
L43:
  cmpl   $0x0,-0x34(%rbp)
  jg     L45
  mov    -0x38(%rbp),%eax
L126:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L129
  call   <__stack_chk_fail@plt>
L129:
  leave
  ret
```

assistant: ```c
int vbuschannel_itoa(char *p, int remain, int num) {
  int digits = 0;
  char s[32];
  int i;
  if (num == 0) {
    if (remain <= 0)
      return 0;
    *p = '0';
    return 1;
  }
  while (num > 0) {
    if (digits >= (int)sizeof(s))
      return 0;
    s[digits++] = (num % 10) + '0';
    num = num / 10;
  }
  if (remain < digits) {
    for (i = 0; i < remain; i++, p++)
      *p = '?';
    return remain;
  }
  i = digits;
  while (i > 0) {
    i--;
    *p = s[i];
    p++;
  }
  return digits;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vbuschannel_itoa>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdi,%r8
  mov    %esi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L34
  mov    $0x1,%ecx
  lea    -0x1(%rsp),%r11
  jle    L41
L92:
  mov    %ecx,%r9d
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %edx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%r11,%rcx,1)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  jle    L134
  add    $0x1,%rcx
  cmp    $0x21,%rcx
  jne    L92
  mov    $0x0,%r9d
  jmp    L61
L34:
  mov    %edx,%r9d
  test   %esi,%esi
  jle    L61
  movb   $0x30,(%rdi)
  mov    $0x1,%r9d
L61:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    %r9d,%eax
  add    $0x38,%rsp
  ret
L134:
  cmp    %ecx,%r10d
  jl     L29
  movslq %ecx,%rax
  lea    (%rsp,%rax,1),%rax
  mov    %ecx,%ecx
  add    %r8,%rcx
  test   %r9d,%r9d
  jle    L61
L14:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%r8)
  add    $0x1,%r8
  sub    $0x1,%rax
  cmp    %rcx,%r8
  jne    L14
  jmp    L61
L29:
  test   %r10d,%r10d
  jle    L122
  mov    %r10d,%eax
  add    %r8,%rax
L128:
  movb   $0x3f,(%r8)
  add    $0x1,%r8
  cmp    %rax,%r8
  jne    L128
  mov    %r10d,%r9d
  jmp    L61
L122:
  mov    %r10d,%r9d
  jmp    L61
L41:
  test   %esi,%esi
  js     L29
  mov    $0x0,%r9d
  jmp    L61
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vbuschannel_itoa(char *p, int remain, int num) {
  int digits = 0;
  char s[32];
  int i;
  if (num == 0) {
    if (remain <= 0)
      return 0;
    *p = '0';
    return 1;
  }
  while (num > 0) {
    if (digits >= (int)sizeof(s))
      return 0;
    s[digits++] = (num % 10) + '0';
    num = num / 10;
  }
  if (remain < digits) {
    for (i = 0; i < remain; i++, p++)
      *p = '?';
    return remain;
  }
  i = digits;
  while (i > 0) {
    i--;
    *p = s[i];
    p++;
  }
  return digits;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vbuschannel_itoa>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L102
  mov    %edx,%ecx
  lea    -0x1(%rsp),%r11
  mov    $0x1,%edx
  mov    $0xcccccccd,%r10d
  jg     L127
  test   %esi,%esi
  js     L57
  nopw   0x0(%rax,%rax,1)
L133:
  xor    %r9d,%r9d
  jmp    L118
  nopl   (%rax)
L40:
  add    $0x1,%rdx
  cmp    $0x21,%rdx
  je     L133
L127:
  mov    %ecx,%eax
  mov    %ecx,%esi
  mov    %edx,%r9d
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  mov    %ecx,%edi
  mov    %eax,%ecx
  add    $0x30,%esi
  mov    %sil,(%r11,%rdx,1)
  cmp    $0x9,%edi
  jg     L40
  cmp    %edx,%ebx
  jl     L25
  movslq %edx,%rax
  lea    -0x1(%rdx),%ecx
  add    %rsp,%rax
  mov    %rax,%rdx
  sub    %rcx,%rdx
  jmp    L124
  nopl   (%rax)
L93:
  movzbl -0x2(%rax),%esi
  sub    $0x1,%rax
L124:
  mov    %sil,(%r8)
  add    $0x1,%r8
  cmp    %rax,%rdx
  jne    L93
  jmp    L118
  xchg   %ax,%ax
L102:
  test   %esi,%esi
  jle    L133
  movb   $0x30,(%rdi)
  mov    $0x1,%r9d
L118:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  add    $0x30,%rsp
  mov    %r9d,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  test   %ebx,%ebx
  jle    L57
  movslq %ebx,%rdx
  mov    $0x3f,%esi
  mov    %r8,%rdi
  call   <memset@plt>
L57:
  mov    %ebx,%r9d
  jmp    L118
L110:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vbuschannel_itoa(char *p, int remain, int num) {
  int digits = 0;
  char s[32];
  int i;
  if (num == 0) {
    if (remain <= 0)
      return 0;
    *p = '0';
    return 1;
  }
  while (num > 0) {
    if (digits >= (int)sizeof(s))
      return 0;
    s[digits++] = (num % 10) + '0';
    num = num / 10;
  }
  if (remain < digits) {
    for (i = 0; i < remain; i++, p++)
      *p = '?';
    return remain;
  }
  i = digits;
  while (i > 0) {
    i--;
    *p = s[i];
    p++;
  }
  return digits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vbuschannel_itoa>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L110
  mov    %edx,%ecx
  lea    -0x1(%rsp),%r11
  mov    $0x1,%edx
  mov    $0xcccccccd,%r10d
  jg     L106
  test   %esi,%esi
  js     L4
  xchg   %ax,%ax
L94:
  xor    %r9d,%r9d
  jmp    L16
  nopl   (%rax)
L37:
  add    $0x1,%rdx
  cmp    $0x21,%rdx
  je     L94
L106:
  mov    %ecx,%eax
  mov    %ecx,%esi
  mov    %edx,%r9d
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%r11,%rdx,1)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x9,%esi
  jg     L37
  cmp    %edx,%ebx
  jl     L116
  movslq %edx,%rax
  add    %r8,%rdx
  add    %rsp,%rax
  nopl   (%rax)
L56:
  movzbl -0x1(%rax),%ecx
  add    $0x1,%r8
  sub    $0x1,%rax
  mov    %cl,-0x1(%r8)
  cmp    %r8,%rdx
  jne    L56
  jmp    L16
  nop
L110:
  test   %esi,%esi
  jle    L94
  movb   $0x30,(%rdi)
  mov    $0x1,%r9d
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  mov    %r9d,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L116:
  test   %ebx,%ebx
  jle    L4
  movslq %ebx,%rdx
  mov    $0x3f,%esi
  mov    %r8,%rdi
  call   <memset@plt>
L4:
  mov    %ebx,%r9d
  jmp    L16
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vbuschannel_itoa(char *p, int remain, int num) {
  int digits = 0;
  char s[32];
  int i;
  if (num == 0) {
    if (remain <= 0)
      return 0;
    *p = '0';
    return 1;
  }
  while (num > 0) {
    if (digits >= (int)sizeof(s))
      return 0;
    s[digits++] = (num % 10) + '0';
    num = num / 10;
  }
  if (remain < digits) {
    for (i = 0; i < remain; i++, p++)
      *p = '?';
    return remain;
  }
  i = digits;
  while (i > 0) {
    i--;
    *p = s[i];
    p++;
  }
  return digits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__libc_sa_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x9,%eax
  ja     L7
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
  mov    $0x4,%eax
  jmp    L39
L7:
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_APPLETALK:
    return sizeof(struct sockaddr_at);
  case AF_ASH:
    return sizeof(struct sockaddr_ash);
  case AF_AX25:
    return sizeof(struct sockaddr_ax25);
  case AF_ECONET:
    return sizeof(struct sockaddr_ec);
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_INET6:
    return sizeof(struct sockaddr_in6);
  case AF_IPX:
    return sizeof(struct sockaddr_ipx);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  case AF_PACKET:
    return sizeof(struct sockaddr_ll);
  case AF_ROSE:
    return sizeof(struct sockaddr_rose);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x9,%edi
  setbe  %al
  movzbl %al,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_APPLETALK:
    return sizeof(struct sockaddr_at);
  case AF_ASH:
    return sizeof(struct sockaddr_ash);
  case AF_AX25:
    return sizeof(struct sockaddr_ax25);
  case AF_ECONET:
    return sizeof(struct sockaddr_ec);
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_INET6:
    return sizeof(struct sockaddr_in6);
  case AF_IPX:
    return sizeof(struct sockaddr_ipx);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  case AF_PACKET:
    return sizeof(struct sockaddr_ll);
  case AF_ROSE:
    return sizeof(struct sockaddr_rose);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_APPLETALK:
    return sizeof(struct sockaddr_at);
  case AF_ASH:
    return sizeof(struct sockaddr_ash);
  case AF_AX25:
    return sizeof(struct sockaddr_ax25);
  case AF_ECONET:
    return sizeof(struct sockaddr_ec);
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_INET6:
    return sizeof(struct sockaddr_in6);
  case AF_IPX:
    return sizeof(struct sockaddr_ipx);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  case AF_PACKET:
    return sizeof(struct sockaddr_ll);
  case AF_ROSE:
    return sizeof(struct sockaddr_rose);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x9,%edi
  setbe  %al
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_APPLETALK:
    return sizeof(struct sockaddr_at);
  case AF_ASH:
    return sizeof(struct sockaddr_ash);
  case AF_AX25:
    return sizeof(struct sockaddr_ax25);
  case AF_ECONET:
    return sizeof(struct sockaddr_ec);
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_INET6:
    return sizeof(struct sockaddr_in6);
  case AF_IPX:
    return sizeof(struct sockaddr_ipx);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  case AF_PACKET:
    return sizeof(struct sockaddr_ll);
  case AF_ROSE:
    return sizeof(struct sockaddr_rose);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string

tool: D15: Please type a string


tool: D12: 
%50[^
]s

assistant: ```c
int printString() {
  char mystring[50];
  printf("Please type a string\n\n");
  scanf("\n%50[^\n]s", mystring);
  printf("%s\n", mystring);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printString>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D4
type: string

tool: D15: Please type a string


tool: D4: 
%50[^
]s

assistant: ```c
int printString() {
  char mystring[50];
  printf("Please type a string\n\n");
  scanf("\n%50[^\n]s", mystring);
  printf("%s\n", mystring);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printString>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  lea    D19(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D1: Please type a string


tool: D19: 
%50[^
]s

assistant: ```c
int printString() {
  char mystring[50];
  printf("Please type a string\n\n");
  scanf("\n%50[^\n]s", mystring);
  printf("%s\n", mystring);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printString>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  lea    D1(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D8: Please type a string


tool: D1: 
%50[^
]s

assistant: ```c
int printString() {
  char mystring[50];
  printf("Please type a string\n\n");
  scanf("\n%50[^\n]s", mystring);
  printf("%s\n", mystring);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse_in_place>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L13:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse_in_place(char *data, size_t size) {
  char *end = data + (size - 1);
  while (end > data) {
    char tmp = *data;
    *data++ = *end;
    *end-- = tmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse_in_place>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L15
L1:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdi)
  sub    $0x1,%rax
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L1
L15:
  ret
```

assistant: ```c
void reverse_in_place(char *data, size_t size) {
  char *end = data + (size - 1);
  while (end > data) {
    char tmp = *data;
    *data++ = *end;
    *end-- = tmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse_in_place>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L19
  xchg   %ax,%ax
L7:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L7
L19:
  ret
```

assistant: ```c
void reverse_in_place(char *data, size_t size) {
  char *end = data + (size - 1);
  while (end > data) {
    char tmp = *data;
    *data++ = *end;
    *end-- = tmp;
  }
}
```