ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L47
  mov    $0x1,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L47:
  movl   $0x0,-0x28(%rbp)
  jmp    L20
L11:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L20:
  cmpl   $0x0,-0x28(%rbp)
  jle    L11
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  cmp    $0x110,%rax
  jne    L40
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L40:
  movl   $0x0,-0x24(%rbp)
  jmp    L12
L44:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L12:
  cmpl   $0x0,-0x24(%rbp)
  jle    L44
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D21: Call this program with %i arguments


tool: D26: You win!

tool: D9: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 272UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L11
L17:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpq   $0x110,0x10(%rsp)
  je     L26
L30:
  mov    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L17
L26:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L30
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D22
type: string

tool: D0: %lu


tool: D11: Call this program with %i arguments


tool: D22: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 272UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L20
  lea    D18(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L20:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x110,%rsi
  je     L23
L5:
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L5
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D28
type_guessed: string

tool: D18: Call this program with %i arguments


tool: D29: %lu


tool: D28: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 272UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L30
  lea    D6(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L30:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x110,%rsi
  je     L22
L12:
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L12
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D6: Call this program with %i arguments


tool: D8: %lu


tool: D12: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 272UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<errorLogger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L24
L8:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L1
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%esi
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L1:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: %d and %d, @ %d and %d


assistant: ```c
int errorLogger(int arr[], int size) {
  int errors = 0;
  for (int i = 1; i < size; i++) {
    if (arr[i - 1] > arr[i]) {
      printf("%d and %d, @ %d and %d\n", arr[i - 1], arr[i], i - 1, i);
      errors++;
    }
  }
  return errors;
}
```
user: Translate the below assembly code into C programming language:

```asm
<errorLogger>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L34
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  lea    D4(%rip),%r14
  jmp    L3
L41:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L15
L3:
  lea    0x1(%rbx),%r8d
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x4(%rbp,%rbx,4),%edx
  cmp    %edx,%esi
  jle    L41
  mov    %ebx,%ecx
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  jmp    L41
L34:
  mov    $0x0,%r13d
L15:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: %d and %d, @ %d and %d


assistant: ```c
int errorLogger(int arr[], int size) {
  int errors = 0;
  for (int i = 1; i < size; i++) {
    if (arr[i - 1] > arr[i]) {
      printf("%d and %d, @ %d and %d\n", arr[i - 1], arr[i], i - 1, i);
      errors++;
    }
  }
  return errors;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<errorLogger>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L4
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r13d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  lea    D1(%rip),%r12
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L21
L24:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x4(%rbp,%rbx,4),%edx
  lea    0x1(%rbx),%r8d
  cmp    %edx,%esi
  jle    L18
  mov    %ebx,%ecx
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L24
L21:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %d and %d, @ %d and %d


assistant: ```c
int errorLogger(int arr[], int size) {
  int errors = 0;
  for (int i = 1; i < size; i++) {
    if (arr[i - 1] > arr[i]) {
      printf("%d and %d, @ %d and %d\n", arr[i - 1], arr[i], i - 1, i);
      errors++;
    }
  }
  return errors;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<errorLogger>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L11
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r13d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  lea    D9(%rip),%r12
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L3
L25:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x4(%rbp,%rbx,4),%edx
  lea    0x1(%rbx),%r8d
  cmp    %edx,%esi
  jle    L19
  mov    %ebx,%ecx
  mov    %r12,%rdi
  add    $0x1,%rbx
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L25
L3:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: %d and %d, @ %d and %d


assistant: ```c
int errorLogger(int arr[], int size) {
  int errors = 0;
  for (int i = 1; i < size; i++) {
    if (arr[i - 1] > arr[i]) {
      printf("%d and %d, @ %d and %d\n", arr[i - 1], arr[i], i - 1, i);
      errors++;
    }
  }
  return errors;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <func@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D7: Hello from prog1.c


assistant: ```c
int main(void) {
  printf("Hello from prog1.c\n");
  func();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <func@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: Hello from prog1.c


assistant: ```c
int main(void) {
  printf("Hello from prog1.c\n");
  func();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: Hello from prog1.c


assistant: ```c
int main(void) {
  printf("Hello from prog1.c\n");
  func();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <func@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: Hello from prog1.c


assistant: ```c
int main(void) {
  printf("Hello from prog1.c\n");
  func();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unican_interrupt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <can_get_irqsrc@plt>
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <can_isr@plt>
  nop
  leave
  ret
```

assistant: ```c
void unican_interrupt(int irq, void *dev_id, struct pt_regs *regs) {
  unsigned short int irqn;
  struct can_dev *chip = (struct can_dev *)dev_id;
  irqn = can_get_irqsrc(chip);
  can_isr(chip, irqn);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unican_interrupt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <can_get_irqsrc@plt>
  movzwl %ax,%esi
  mov    %rbx,%rdi
  call   <can_isr@plt>
  pop    %rbx
  ret
```

assistant: ```c
void unican_interrupt(int irq, void *dev_id, struct pt_regs *regs) {
  unsigned short int irqn;
  struct can_dev *chip = (struct can_dev *)dev_id;
  irqn = can_get_irqsrc(chip);
  can_isr(chip, irqn);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unican_interrupt>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <can_get_irqsrc@plt>
  mov    %rbp,%rdi
  pop    %rbp
  movzwl %ax,%esi
  jmp    1070 <can_isr@plt>
```

assistant: ```c
void unican_interrupt(int irq, void *dev_id, struct pt_regs *regs) {
  unsigned short int irqn;
  struct can_dev *chip = (struct can_dev *)dev_id;
  irqn = can_get_irqsrc(chip);
  can_isr(chip, irqn);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unican_interrupt>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <can_get_irqsrc@plt>
  mov    %rbp,%rdi
  pop    %rbp
  movzwl %ax,%esi
  jmp    1070 <can_isr@plt>
```

assistant: ```c
void unican_interrupt(int irq, void *dev_id, struct pt_regs *regs) {
  unsigned short int irqn;
  struct can_dev *chip = (struct can_dev *)dev_id;
  irqn = can_get_irqsrc(chip);
  can_isr(chip, irqn);
}
```
user: What is the c source code of the assembly code below:

```asm
<Hibbard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L10:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L10
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Hibbard(int n) {
  int i = 0;
  while ((2 << i) < n)
    i++;
  return (2 << i - 1) - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Hibbard>:
  endbr64
  cmp    $0x2,%edi
  jle    L25
  mov    $0x0,%ecx
  mov    $0x2,%edx
L29:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L29
L7:
  sub    $0x1,%ecx
  mov    $0x2,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  ret
L25:
  mov    $0x0,%ecx
  jmp    L7
```

assistant: ```c
int Hibbard(int n) {
  int i = 0;
  while ((2 << i) < n)
    i++;
  return (2 << i - 1) - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Hibbard>:
  endbr64
  cmp    $0x2,%edi
  jle    L15
  xor    %ecx,%ecx
  mov    $0x2,%esi
L11:
  mov    %ecx,%edx
  mov    %esi,%eax
  add    $0x1,%ecx
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L11
  mov    %edx,%ecx
  mov    $0x2,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0xffffffff,%edx
  mov    $0x2,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int Hibbard(int n) {
  int i = 0;
  while ((2 << i) < n)
    i++;
  return (2 << i - 1) - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Hibbard>:
  endbr64
  cmp    $0x2,%edi
  jle    L6
  xor    %ecx,%ecx
  mov    $0x2,%esi
L7:
  mov    %ecx,%edx
  mov    %esi,%eax
  add    $0x1,%ecx
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L7
  mov    %edx,%ecx
  mov    $0x2,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%edx
  mov    $0x2,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int Hibbard(int n) {
  int i = 0;
  while ((2 << i) < n)
    i++;
  return (2 << i - 1) - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LongLeftShift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %rdi,-0x7f8(%rbp)
  mov    %esi,-0x7fc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0xf,-0x7fc(%rbp)
  jg     L20
  mov    -0x7fc(%rbp),%edx
  mov    -0x7f8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <LeftShift@plt>
  jmp    L49
L20:
  mov    -0x7fc(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x7e4(%rbp)
  mov    -0x7e4(%rbp),%eax
  shl    $0x4,%eax
  sub    %eax,-0x7fc(%rbp)
  mov    -0x7f8(%rbp),%rax
  mov    %rax,%rdi
  call   <Degree@plt>
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <Initialize@plt>
  jmp    L11
L33:
  mov    -0x7e8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x7f8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x7e8(%rbp),%ecx
  mov    -0x7e4(%rbp),%edx
  add    %edx,%ecx
  mov    (%rax),%edx
  movslq %ecx,%rax
  mov    %edx,-0x7e0(%rbp,%rax,4)
  subl   $0x1,-0x7e8(%rbp)
L11:
  cmpl   $0x0,-0x7e8(%rbp)
  jns    L33
  mov    -0x7f8(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Copy@plt>
  mov    -0x7fc(%rbp),%edx
  mov    -0x7f8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <LeftShift@plt>
L49:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void LongLeftShift(unsigned a[], int sh) {
  int i, u;
  unsigned temp[500];
  if (sh < 16) {
    LeftShift(a, sh);
  } else {
    u = sh / 16;
    sh = sh - u * 16;
    i = Degree(a);
    Initialize(temp);
    while (i >= 0) {
      temp[i + u] = a[i];
      i--;
    }
    Copy(temp, a);
    LeftShift(a, sh);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<LongLeftShift>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  cmp    $0xf,%esi
  jg     L13
  call   <LeftShift@plt>
L30:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    0xf(%rsi),%r12d
  test   %esi,%esi
  cmovns %esi,%r12d
  sar    $0x4,%r12d
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rsi,%rax,1),%ebx
  and    $0xf,%ebx
  sub    %eax,%ebx
  call   <Degree@plt>
  mov    %eax,%r13d
  mov    %rsp,%rdi
  call   <Initialize@plt>
  test   %r13d,%r13d
  js     L49
  movslq %r13d,%rax
  add    %r13d,%r12d
  movslq %r12d,%r12
  sub    %rax,%r12
  lea    (%rsp,%r12,4),%rcx
L14:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L14
L49:
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <Copy@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <LeftShift@plt>
  jmp    L30
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LongLeftShift(unsigned a[], int sh) {
  int i, u;
  unsigned temp[500];
  if (sh < 16) {
    LeftShift(a, sh);
  } else {
    u = sh / 16;
    sh = sh - u * 16;
    i = Degree(a);
    Initialize(temp);
    while (i >= 0) {
      temp[i + u] = a[i];
      i--;
    }
    Copy(temp, a);
    LeftShift(a, sh);
  }
}
```