user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  movl   $0x0,-0x6c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x68(%rbp)
L143:
  addl   $0x1,-0x70(%rbp)
  cmpl   $0x14,-0x70(%rbp)
  jg     L82
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L4
  subl   $0x1,-0x70(%rbp)
  movl   $0x1,-0x6c(%rbp)
  jmp    L4
L82:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  subl   $0x1,-0x70(%rbp)
  movl   $0x1,-0x6c(%rbp)
L4:
  cmpl   $0x0,-0x6c(%rbp)
  je     L143
  mov    -0x70(%rbp),%eax
  mov    %eax,-0x64(%rbp)
  jmp    L94
L29:
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x68(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x68(%rbp)
  subl   $0x1,-0x70(%rbp)
L94:
  cmpl   $0x0,-0x70(%rbp)
  jg     L29
  cmpl   $0x1,-0x64(%rbp)
  je     L136
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x64(%rbp),%xmm1
  movss  -0x68(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x68(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x68(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movl   $0x1,-0x70(%rbp)
  jmp    L113
L127:
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  ucomiss -0x68(%rbp),%xmm0
  jp     L32
  ucomiss -0x68(%rbp),%xmm0
  jne    L32
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L91
L32:
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  comiss -0x68(%rbp),%xmm0
  jbe    L91
  mov    -0x70(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L91:
  addl   $0x1,-0x70(%rbp)
L113:
  mov    -0x70(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L127
  jmp    L34
L136:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L34:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D69
type_infered: string
name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D48
type_infered: string
name: read_data
arguments: label: D22
type_infered: string

tool: D21: Digite um valor inteiro: 

tool: D12: %d

tool: D32: 
Limite maximo atingido!

tool: D69: 
Media e: %3.1f


tool: D8: 
%d e igual a media

tool: D48: 
%d e maior que a media

tool: D22: 
Por favor, digite mais de um valor.

assistant: ```c
main() {
  int numero[21], i = 0, fim = 0, total_valores;
  float media = 0;
  do {
    i++;
    if (i <= 20) {
      printf("Digite um valor inteiro: ");
      scanf("%d", &numero[i]);
      if (numero[i] == 0) {
        i--;
        fim = 1;
      }
    } else {
      printf("\nLimite maximo atingido!\n");
      i--;
      fim = 1;
    }
  } while (fim == 0);
  total_valores = i;
  while (i >= 1) {
    media = media + numero[i];
    i--;
  }
  if (total_valores != 1) {
    media = (float)media / total_valores;
    printf("\nMedia e: %3.1f\n", media);
    for (i = 1; i <= total_valores; i++) {
      if (numero[i] == media) {
        printf("\n%d e igual a media", numero[i]);
      } else if (numero[i] > media) {
        printf("\n%d e maior que a media", numero[i]);
      }
    }
  } else {
    printf("\nPor favor, digite mais de um valor.\n");
  }
}
```