ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vec_abs_s64>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %esi,%esi
  mov    $0x0,%eax
L5:
  mov    (%rdx,%rax,8),%r8
  mov    %r8,%rcx
  neg    %rcx
  cmovs  %r8,%rcx
  mov    %rcx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L5
L14:
  ret
```

assistant: ```c
void vec_abs_s64(int64_t *pY, int len, const int64_t *pX) {
  int n;
  for (n = 0; n < len; n++) {
    pY[n] = (int64_t)labs(pX[n]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_abs_s64>:
  endbr64
  test   %esi,%esi
  jle    L10
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   (%rax)
L11:
  mov    (%rdx,%rax,8),%r8
  mov    %r8,%rcx
  neg    %rcx
  cmovs  %r8,%rcx
  mov    %rcx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L11
L10:
  ret
```

assistant: ```c
void vec_abs_s64(int64_t *pY, int len, const int64_t *pX) {
  int n;
  for (n = 0; n < len; n++) {
    pY[n] = (int64_t)labs(pX[n]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec_abs_s64>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  je     L28
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L28
  mov    %esi,%ecx
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  movdqu (%rdx,%rax,1),%xmm0
  movdqa %xmm3,%xmm1
  movdqa %xmm0,%xmm2
  psrlq  $0x3f,%xmm2
  psubq  %xmm2,%xmm1
  pxor   %xmm1,%xmm0
  psubq  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L9
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L18
  mov    (%rdx,%rax,8),%rcx
  mov    %rcx,%rdx
  neg    %rdx
  cmovs  %rcx,%rdx
  mov    %rdx,(%rdi,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L35:
  mov    (%rdx,%rax,8),%r8
  mov    %r8,%rcx
  neg    %rcx
  cmovs  %r8,%rcx
  mov    %rcx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L35
L18:
  ret
```

assistant: ```c
void vec_abs_s64(int64_t *pY, int len, const int64_t *pX) {
  int n;
  for (n = 0; n < len; n++) {
    pY[n] = (int64_t)labs(pX[n]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wanttoyell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x79,-0x4(%rbp)
  jne    L27
  lea    D95(%rip),%rax
  jmp    L7
L27:
  lea    D32(%rip),%rax
L7:
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <my_printf@plt>
  mov    $0x0,%esi
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <help@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <my_printf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <get_single_quiet@plt>
  cmp    $0x59,%eax
  je     L117
  cmp    $0x59,%eax
  jg     L66
  cmp    $0x34,%eax
  je     L121
  cmp    $0x34,%eax
  jg     L66
  cmp    $0x33,%eax
  je     L97
  cmp    $0x33,%eax
  jg     L66
  cmp    $0x31,%eax
  je     L68
  cmp    $0x32,%eax
  je     L12
  jmp    L66
L68:
  mov    $0x0,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <help@plt>
  jmp    L90
L12:
  mov    $0x0,%esi
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  call   <help@plt>
  jmp    L90
L97:
  mov    $0x0,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <help@plt>
  jmp    L90
L121:
  mov    $0x0,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <help@plt>
  jmp    L90
L117:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x1,%eax
  jmp    L146
L66:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  nop
L90:
  mov    $0x0,%eax
L146:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D95
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string
name: unpack_data
arguments: data_tag: D61
type_guessed: string
name: unpack_data
arguments: data_tag: D94
type_guessed: string
name: unpack_data
arguments: data_tag: D35
type_guessed: string
name: unpack_data
arguments: data_tag: D68
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D91
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D95: Yell to Sysop


tool: D32: Upload Yell to Sysop


tool: D61: %s

tool: D94: yell.list

tool: D35: Enter your choice -> 

tool: D68: 1234YN 


tool: D20: yell.voice.1

tool: D91: yell.voice.2

tool: D12: yell.voice.3

tool: D7: yell.voice.4

assistant: ```c
int wanttoyell(int cmd) {
  my_printf("%s", cmd == 'y' ? "Yell to Sysop\n" : "Upload Yell to Sysop\n");
  help("yell.list", 0);
  my_printf("Enter your choice -> ");
  switch (get_single_quiet("1234YN \n")) {
  case '1':
    help("yell.voice.1", 0);
    break;
  case '2':
    help("yell.voice.2", 0);
    break;
  case '3':
    help("yell.voice.3", 0);
    break;
  case '4':
    help("yell.voice.4", 0);
    break;
  case 'Y':
    my_putchar('\n');
    return (1);
  default:
    my_putchar('\n');
    break;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wanttoyell>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x79,%edi
  lea    D85(%rip),%rsi
  lea    D63(%rip),%rax
  cmovne %rax,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <my_printf@plt>
  mov    $0x0,%esi
  lea    D96(%rip),%rdi
  call   <help@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <my_printf@plt>
  lea    D34(%rip),%rdi
  call   <get_single_quiet@plt>
  cmp    $0x33,%eax
  je     L84
  jle    L48
  cmp    $0x34,%eax
  je     L106
  cmp    $0x59,%eax
  jne    L55
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x1,%eax
  jmp    L4
L48:
  cmp    $0x31,%eax
  je     L29
  cmp    $0x32,%eax
  jne    L55
  mov    $0x0,%esi
  lea    D28(%rip),%rdi
  call   <help@plt>
  mov    $0x0,%eax
  jmp    L4
L29:
  mov    $0x0,%esi
  lea    D22(%rip),%rdi
  call   <help@plt>
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  ret
L84:
  mov    $0x0,%esi
  lea    D61(%rip),%rdi
  call   <help@plt>
  mov    $0x0,%eax
  jmp    L4
L106:
  mov    $0x0,%esi
  lea    D74(%rip),%rdi
  call   <help@plt>
  mov    $0x0,%eax
  jmp    L4
L55:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x0,%eax
  jmp    L4
```

tool_calls: name: unpack_data
arguments: tag: D85
datatype: string
name: unpack_data
arguments: tag: D63
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D96
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D34
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D61
datatype: string
name: unpack_data
arguments: tag: D74
datatype: string

tool: D85: Yell to Sysop


tool: D63: Upload Yell to Sysop


tool: D19: %s

tool: D96: yell.list

tool: D7: Enter your choice -> 

tool: D34: 1234YN 


tool: D28: yell.voice.2

tool: D22: yell.voice.1

tool: D61: yell.voice.3

tool: D74: yell.voice.4

assistant: ```c
int wanttoyell(int cmd) {
  my_printf("%s", cmd == 'y' ? "Yell to Sysop\n" : "Upload Yell to Sysop\n");
  help("yell.list", 0);
  my_printf("Enter your choice -> ");
  switch (get_single_quiet("1234YN \n")) {
  case '1':
    help("yell.voice.1", 0);
    break;
  case '2':
    help("yell.voice.2", 0);
    break;
  case '3':
    help("yell.voice.3", 0);
    break;
  case '4':
    help("yell.voice.4", 0);
    break;
  case 'Y':
    my_putchar('\n');
    return (1);
  default:
    my_putchar('\n');
    break;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<wanttoyell>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rax
  cmp    $0x79,%edi
  lea    D84(%rip),%rsi
  lea    D34(%rip),%rdi
  cmovne %rax,%rsi
  xor    %eax,%eax
  call   <my_printf@plt>
  xor    %esi,%esi
  lea    D51(%rip),%rdi
  call   <help@plt>
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <my_printf@plt>
  lea    D7(%rip),%rdi
  call   <get_single_quiet@plt>
  cmp    $0x33,%eax
  je     L39
  jle    L41
  cmp    $0x34,%eax
  je     L23
  cmp    $0x59,%eax
  jne    L30
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    $0x31,%eax
  je     L59
  cmp    $0x32,%eax
  jne    L30
  xor    %esi,%esi
  lea    D46(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L39:
  xor    %esi,%esi
  lea    D38(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L23:
  xor    %esi,%esi
  lea    D26(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L30:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L59:
  xor    %esi,%esi
  lea    D40(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D84
type: string
name: unpack_data
arguments: tag: D34
type: string
name: unpack_data
arguments: tag: D51
type: string
name: unpack_data
arguments: tag: D45
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D46
type: string
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D26
type: string
name: unpack_data
arguments: tag: D40
type: string

tool: D1: Upload Yell to Sysop


tool: D84: Yell to Sysop


tool: D34: %s

tool: D51: yell.list

tool: D45: Enter your choice -> 

tool: D7: 1234YN 


tool: D46: yell.voice.2

tool: D38: yell.voice.3

tool: D26: yell.voice.4

tool: D40: yell.voice.1

assistant: ```c
int wanttoyell(int cmd) {
  my_printf("%s", cmd == 'y' ? "Yell to Sysop\n" : "Upload Yell to Sysop\n");
  help("yell.list", 0);
  my_printf("Enter your choice -> ");
  switch (get_single_quiet("1234YN \n")) {
  case '1':
    help("yell.voice.1", 0);
    break;
  case '2':
    help("yell.voice.2", 0);
    break;
  case '3':
    help("yell.voice.3", 0);
    break;
  case '4':
    help("yell.voice.4", 0);
    break;
  case 'Y':
    my_putchar('\n');
    return (1);
  default:
    my_putchar('\n');
    break;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wanttoyell>:
  endbr64
  sub    $0x8,%rsp
  lea    D48(%rip),%rax
  cmp    $0x79,%edi
  lea    D76(%rip),%rsi
  lea    D28(%rip),%rdi
  cmovne %rax,%rsi
  xor    %eax,%eax
  call   <my_printf@plt>
  xor    %esi,%esi
  lea    D63(%rip),%rdi
  call   <help@plt>
  lea    D97(%rip),%rdi
  xor    %eax,%eax
  call   <my_printf@plt>
  lea    D24(%rip),%rdi
  call   <get_single_quiet@plt>
  cmp    $0x33,%eax
  je     L57
  jle    L20
  cmp    $0x34,%eax
  je     L46
  cmp    $0x59,%eax
  jne    L40
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x31,%eax
  je     L59
  cmp    $0x32,%eax
  jne    L40
  xor    %esi,%esi
  lea    D49(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L57:
  xor    %esi,%esi
  lea    D22(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L46:
  xor    %esi,%esi
  lea    D26(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L40:
  mov    $0xa,%edi
  call   <my_putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L59:
  xor    %esi,%esi
  lea    D32(%rip),%rdi
  call   <help@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D48
type_guessed: string
name: extract_symbolic_data
arguments: label: D76
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D63
type_guessed: string
name: extract_symbolic_data
arguments: label: D97
type_guessed: string
name: extract_symbolic_data
arguments: label: D24
type_guessed: string
name: extract_symbolic_data
arguments: label: D49
type_guessed: string
name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string

tool: D48: Upload Yell to Sysop


tool: D76: Yell to Sysop


tool: D28: %s

tool: D63: yell.list

tool: D97: Enter your choice -> 

tool: D24: 1234YN 


tool: D49: yell.voice.2

tool: D22: yell.voice.3

tool: D26: yell.voice.4

tool: D32: yell.voice.1

assistant: ```c
int wanttoyell(int cmd) {
  my_printf("%s", cmd == 'y' ? "Yell to Sysop\n" : "Upload Yell to Sysop\n");
  help("yell.list", 0);
  my_printf("Enter your choice -> ");
  switch (get_single_quiet("1234YN \n")) {
  case '1':
    help("yell.voice.1", 0);
    break;
  case '2':
    help("yell.voice.2", 0);
    break;
  case '3':
    help("yell.voice.3", 0);
    break;
  case '4':
    help("yell.voice.4", 0);
    break;
  case 'Y':
    my_putchar('\n');
    return (1);
  default:
    my_putchar('\n');
    break;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ctz32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_ctz@plt>
  jmp    L2
L4:
  mov    $0x20,%eax
L2:
  leave
  ret
```

assistant: ```c
int ctz32(uint32_t val) {
  if (val)
    return __builtin_ctz(val);
  else
    return 32;
}
```
user: What is the c source code of the assembly code below?

```asm
<ctz32>:
  endbr64
  mov    $0x20,%eax
  test   %rdi,%rdi
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  call   <__builtin_ctz@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ctz32(uint32_t val) {
  if (val)
    return __builtin_ctz(val);
  else
    return 32;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctz32>:
  endbr64
  test   %rdi,%rdi
  jne    L2
  mov    $0x20,%eax
  ret
  nop
L2:
  jmp    1050 <__builtin_ctz@plt>
```

assistant: ```c
int ctz32(uint32_t val) {
  if (val)
    return __builtin_ctz(val);
  else
    return 32;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ctz32>:
  endbr64
  test   %rdi,%rdi
  jne    L9
  mov    $0x20,%eax
  ret
  nop
L9:
  jmp    1050 <__builtin_ctz@plt>
```

assistant: ```c
int ctz32(uint32_t val) {
  if (val)
    return __builtin_ctz(val);
  else
    return 32;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Problem4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfb4(%rbp)
  jmp    L30
L24:
  mov    -0xfb4(%rbp),%eax
  cltq
  movl   $0x0,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfb4(%rbp)
L30:
  cmpl   $0x3e7,-0xfb4(%rbp)
  jle    L24
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xfb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L5
L19:
  mov    -0xfb8(%rbp),%edx
  lea    -0xfb0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printSubset@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xfb8(%rbp),%edx
  lea    -0xfb0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <addOneBit@plt>
L5:
  mov    -0xfb8(%rbp),%edx
  lea    -0xfb0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <highestBin@plt>
  test   %rax,%rax
  je     L19
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string

tool: D18: Problem 4: Prints the powerset of the set containing integers 1 - n

tool: D14: 
 1 < n < 1000: 

tool: D37: %d

tool: D27: , 

assistant: ```c
void Problem4() {
  int binrep[1000];
  int ix;
  for (ix = 0; ix < 1000; ix++) {
    binrep[ix] = 0;
  }
  int input;
  printf("Problem 4: Prints the powerset of the set containing integers 1 - n");
  printf("\n 1 < n < 1000: ");
  scanf("%d", &input);
  while (highestBin(binrep, input) == 0) {
    printSubset(binrep, input);
    printf(", ");
    addOneBit(binrep, input);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Problem4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0xfb0(%rsp),%rdx
L11:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rbp
  jmp    L33
L20:
  lea    0x10(%rsp),%rbx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printSubset@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <addOneBit@plt>
L33:
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <highestBin@plt>
  test   %rax,%rax
  je     L20
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D35
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string

tool: D21: Problem 4: Prints the powerset of the set containing integers 1 - n

tool: D19: 
 1 < n < 1000: 

tool: D35: %d

tool: D20: , 

assistant: ```c
void Problem4() {
  int binrep[1000];
  int ix;
  for (ix = 0; ix < 1000; ix++) {
    binrep[ix] = 0;
  }
  int input;
  printf("Problem 4: Prints the powerset of the set containing integers 1 - n");
  printf("\n 1 < n < 1000: ");
  scanf("%d", &input);
  while (highestBin(binrep, input) == 0) {
    printSubset(binrep, input);
    printf(", ");
    addOneBit(binrep, input);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Problem4>:
  endbr64
  push   %rbp
  mov    $0x1f4,%ecx
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printSubset@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <addOneBit@plt>
L16:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <highestBin@plt>
  test   %rax,%rax
  je     L29
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string

tool: D12: , 

tool: D23: Problem 4: Prints the powerset of the set containing integers 1 - n

tool: D2: 
 1 < n < 1000: 

tool: D7: %d

assistant: ```c
void Problem4() {
  int binrep[1000];
  int ix;
  for (ix = 0; ix < 1000; ix++) {
    binrep[ix] = 0;
  }
  int input;
  printf("Problem 4: Prints the powerset of the set containing integers 1 - n");
  printf("\n 1 < n < 1000: ");
  scanf("%d", &input);
  while (highestBin(binrep, input) == 0) {
    printSubset(binrep, input);
    printf(", ");
    addOneBit(binrep, input);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Problem4>:
  endbr64
  push   %rbp
  mov    $0x1f4,%ecx
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L14:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <printSubset@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <addOneBit@plt>
L27:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <highestBin@plt>
  test   %rax,%rax
  je     L14
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D28: , 

tool: D16: Problem 4: Prints the powerset of the set containing integers 1 - n

tool: D27: 
 1 < n < 1000: 

tool: D5: %d

assistant: ```c
void Problem4() {
  int binrep[1000];
  int ix;
  for (ix = 0; ix < 1000; ix++) {
    binrep[ix] = 0;
  }
  int input;
  printf("Problem 4: Prints the powerset of the set containing integers 1 - n");
  printf("\n 1 < n < 1000: ");
  scanf("%d", &input);
  while (highestBin(binrep, input) == 0) {
    printSubset(binrep, input);
    printf(", ");
    addOneBit(binrep, input);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type: string
name: read_data
arguments: tag: D19
type: string

tool: D16: HOME

tool: D19: %s


assistant: ```c
int main() {
  char *val = getenv("HOME");
  printf("%s\n", val);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D3: HOME

tool: D9: %s


assistant: ```c
int main() {
  char *val = getenv("HOME");
  printf("%s\n", val);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <getenv@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D9: HOME

tool: D12: %s


assistant: ```c
int main() {
  char *val = getenv("HOME");
  printf("%s\n", val);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <getenv@plt>
  lea    D8(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D2: HOME

tool: D8: %s


assistant: ```c
int main() {
  char *val = getenv("HOME");
  printf("%s\n", val);
  return 0;
}
```