ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<readnb>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L65
  mov    %edi,%ebx
  test   %edi,%edi
  je     L65
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  call   <rewind@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L1:
  jbe    L39
  add    %eax,%r12d
  sub    %eax,%ebx
L66:
  test   %eax,%eax
  je     L26
L55:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <read4k@plt>
  cmp    %eax,%ebx
  jne    L1
  add    %ebx,%r12d
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  xor    %r12d,%r12d
L26:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L39:
  jae    L66
  add    %ebx,%r12d
  jmp    L2
```

assistant: ```c
unsigned int readnb(unsigned int n, FILE *fp, char *copybuf) {
  unsigned int read = 0, read_bytes = 0;
  unsigned int remaining = n;
  if (!n)
    return 0;
  if (!fp)
    return 0;
  if (!copybuf)
    return 0;
  rewind(fp);
  do {
    read_bytes = read4k(fp, copybuf);
    if (read_bytes == remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = remaining - read_bytes;
    } else if (read_bytes < remaining) {
      ;
      ("%.*s", read_bytes, copybuf);
      read = read + read_bytes;
      remaining = remaining - read_bytes;
    } else if (read_bytes > remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = 0;
    }
  } while (remaining && read_bytes);
  return read;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<num2char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x2,-0x20(%rbp)
  je     L62
  cmpl   $0x2,-0x20(%rbp)
  jg     L169
  cmpl   $0x0,-0x20(%rbp)
  je     L60
  cmpl   $0x1,-0x20(%rbp)
  je     L2
  jmp    L169
L62:
  movb   $0x43,-0xf(%rbp)
  movb   $0x44,-0xe(%rbp)
  movb   $0x4d,-0xd(%rbp)
  jmp    L169
L2:
  movb   $0x58,-0xf(%rbp)
  movb   $0x4c,-0xe(%rbp)
  movb   $0x43,-0xd(%rbp)
  jmp    L169
L60:
  movb   $0x49,-0xf(%rbp)
  movb   $0x56,-0xe(%rbp)
  movb   $0x58,-0xd(%rbp)
  nop
L169:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L30
  cmpl   $0x9,-0x1c(%rbp)
  ja     L30
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x0,-0xc(%rbp)
  jmp    L66
L68:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L66:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L68
  jmp    L30
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L30
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L30
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
  movl   $0x5,-0xc(%rbp)
  jmp    L146
L25:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L146:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  jmp    L30
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  nop
L30:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void num2char(char **num, int bit, int n) {
  int i;
  char low, mid, high;
  char *p = *num;
  switch (n) {
  case 2:
    low = 'C';
    mid = 'D';
    high = 'M';
    break;
  case 1:
    low = 'X';
    mid = 'L';
    high = 'C';
    break;
  case 0:
    low = 'I';
    mid = 'V';
    high = 'X';
    break;
  }
  if (bit > 0) {
    switch (bit) {
    case 1:
    case 2:
    case 3:
      for (i = 0; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 4:
      *p++ = low;
      *p++ = mid;
      break;
    case 5:
      *p++ = mid;
      break;
    case 6:
    case 7:
    case 8:
      *p++ = mid;
      for (i = 5; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 9:
      *p++ = low;
      *p++ = high;
      break;
    }
  }
  *num = p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<num2char>:
  endbr64
  mov    %esi,%ecx
  mov    (%rdi),%rax
  cmp    $0x1,%edx
  je     L114
  cmp    $0x2,%edx
  je     L23
  test   %edx,%edx
  mov    $0x0,%r8d
  mov    $0x58,%esi
  cmove  %esi,%r8d
  mov    $0x0,%esi
  mov    $0x56,%r9d
  cmove  %r9d,%esi
  mov    $0x0,%edx
  mov    $0x49,%r9d
  cmove  %r9d,%edx
L98:
  test   %ecx,%ecx
  jle    L136
  cmp    $0x9,%ecx
  ja     L136
  mov    %ecx,%r9d
  lea    D9(%rip),%r10
  movslq (%r10,%r9,4),%r9
  add    %r10,%r9
  notrack jmp *%r9
L114:
  mov    $0x43,%r8d
  mov    $0x4c,%esi
  mov    $0x58,%edx
  jmp    L98
L23:
  mov    $0x4d,%r8d
  mov    $0x44,%esi
  mov    $0x43,%edx
  jmp    L98
  mov    %ecx,%ecx
  add    %rax,%rcx
L34:
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L34
  mov    %rcx,%rax
  jmp    L136
  mov    %dl,(%rax)
  mov    %sil,0x1(%rax)
  lea    0x2(%rax),%rax
L136:
  mov    %rax,(%rdi)
  ret
  mov    %sil,(%rax)
  lea    0x1(%rax),%rax
  jmp    L136
  lea    0x1(%rax),%r8
  mov    %sil,(%rax)
  cmp    $0x5,%ecx
  jle    L113
  lea    -0x6(%rcx),%esi
  lea    0x2(%rax,%rsi,1),%rcx
  mov    %r8,%rax
L93:
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L93
  lea    0x1(%r8,%rsi,1),%rax
  jmp    L136
  mov    %dl,(%rax)
  mov    %r8b,0x1(%rax)
  lea    0x2(%rax),%rax
  jmp    L136
L113:
  mov    %r8,%rax
  jmp    L136
```

assistant: ```c
void num2char(char **num, int bit, int n) {
  int i;
  char low, mid, high;
  char *p = *num;
  switch (n) {
  case 2:
    low = 'C';
    mid = 'D';
    high = 'M';
    break;
  case 1:
    low = 'X';
    mid = 'L';
    high = 'C';
    break;
  case 0:
    low = 'I';
    mid = 'V';
    high = 'X';
    break;
  }
  if (bit > 0) {
    switch (bit) {
    case 1:
    case 2:
    case 3:
      for (i = 0; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 4:
      *p++ = low;
      *p++ = mid;
      break;
    case 5:
      *p++ = mid;
      break;
    case 6:
    case 7:
    case 8:
      *p++ = mid;
      for (i = 5; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 9:
      *p++ = low;
      *p++ = high;
      break;
    }
  }
  *num = p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<num2char>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  mov    (%rdi),%rsi
  cmp    $0x2,%edx
  ja     L95
  mov    %edx,%edx
  lea    D6(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r8d
  lea    D7(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r9d
  lea    D22(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r10d
L95:
  test   %eax,%eax
  jle    L106
  cmp    $0x9,%eax
  ja     L106
  lea    D25(%rip),%rdi
  mov    %eax,%edx
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  mov    %r8b,(%rsi)
  add    $0x2,%rsi
  mov    %r9b,-0x1(%rsi)
L106:
  mov    %rsi,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
  mov    %r9b,(%rsi)
  cmp    $0x5,%eax
  lea    0x1(%rsi),%rdi
  lea    -0x5(%rax),%esi
  mov    $0x1,%eax
  movsbl %r8b,%r8d
  cmovle %rax,%rsi
  mov    %esi,%r9d
  test   %esi,%esi
  je     L12
  xor    %eax,%eax
L27:
  mov    %eax,%edx
  add    $0x1,%eax
  mov    %r8b,(%rdi,%rdx,1)
  cmp    %r9d,%eax
  jb     L27
L12:
  add    %rdi,%rsi
  jmp    L106
  cs nopw 0x0(%rax,%rax,1)
  movslq %eax,%r9
  movsbl %r8b,%r8d
  test   %eax,%eax
  je     L72
  xor    %edx,%edx
L18:
  mov    %edx,%edi
  add    $0x1,%edx
  mov    %r8b,(%rsi,%rdi,1)
  cmp    %eax,%edx
  jb     L18
L72:
  add    %r9,%rsi
  jmp    L106
  nop
  mov    %r8b,(%rsi)
  add    $0x2,%rsi
  mov    %r10b,-0x1(%rsi)
  jmp    L106
  nopl   (%rax)
  mov    %r9b,(%rsi)
  add    $0x1,%rsi
  jmp    L106
```

assistant: ```c
void num2char(char **num, int bit, int n) {
  int i;
  char low, mid, high;
  char *p = *num;
  switch (n) {
  case 2:
    low = 'C';
    mid = 'D';
    high = 'M';
    break;
  case 1:
    low = 'X';
    mid = 'L';
    high = 'C';
    break;
  case 0:
    low = 'I';
    mid = 'V';
    high = 'X';
    break;
  }
  if (bit > 0) {
    switch (bit) {
    case 1:
    case 2:
    case 3:
      for (i = 0; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 4:
      *p++ = low;
      *p++ = mid;
      break;
    case 5:
      *p++ = mid;
      break;
    case 6:
    case 7:
    case 8:
      *p++ = mid;
      for (i = 5; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 9:
      *p++ = low;
      *p++ = high;
      break;
    }
  }
  *num = p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<num2char>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  mov    (%rdi),%rsi
  cmp    $0x2,%edx
  ja     L27
  mov    %edx,%edx
  lea    D20(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r8d
  lea    D1(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r9d
  lea    D22(%rip),%rdi
  movzbl (%rdi,%rdx,1),%r10d
L27:
  test   %eax,%eax
  jle    L40
  cmp    $0x9,%eax
  ja     L40
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  mov    %r8b,(%rsi)
  add    $0x2,%rsi
  mov    %r9b,-0x1(%rsi)
L40:
  mov    %rsi,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
  mov    %r9b,(%rsi)
  cmp    $0x5,%eax
  lea    0x1(%rsi),%rdi
  lea    -0x5(%rax),%esi
  mov    $0x1,%eax
  movsbl %r8b,%r8d
  cmovle %rax,%rsi
  mov    %esi,%r9d
  test   %esi,%esi
  je     L102
  xor    %eax,%eax
L17:
  mov    %eax,%edx
  add    $0x1,%eax
  mov    %r8b,(%rdi,%rdx,1)
  cmp    %r9d,%eax
  jb     L17
L102:
  add    %rdi,%rsi
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
  movslq %eax,%r9
  movsbl %r8b,%r8d
  test   %eax,%eax
  je     L21
  xor    %edx,%edx
L39:
  mov    %edx,%edi
  add    $0x1,%edx
  mov    %r8b,(%rsi,%rdi,1)
  cmp    %eax,%edx
  jb     L39
L21:
  add    %r9,%rsi
  jmp    L40
  nop
  mov    %r8b,(%rsi)
  add    $0x2,%rsi
  mov    %r10b,-0x1(%rsi)
  jmp    L40
  nopl   (%rax)
  mov    %r9b,(%rsi)
  add    $0x1,%rsi
  jmp    L40
```

assistant: ```c
void num2char(char **num, int bit, int n) {
  int i;
  char low, mid, high;
  char *p = *num;
  switch (n) {
  case 2:
    low = 'C';
    mid = 'D';
    high = 'M';
    break;
  case 1:
    low = 'X';
    mid = 'L';
    high = 'C';
    break;
  case 0:
    low = 'I';
    mid = 'V';
    high = 'X';
    break;
  }
  if (bit > 0) {
    switch (bit) {
    case 1:
    case 2:
    case 3:
      for (i = 0; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 4:
      *p++ = low;
      *p++ = mid;
      break;
    case 5:
      *p++ = mid;
      break;
    case 6:
    case 7:
    case 8:
      *p++ = mid;
      for (i = 5; i < bit; i++) {
        *p++ = low;
      }
      break;
    case 9:
      *p++ = low;
      *p++ = high;
      break;
    }
  }
  *num = p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putmv1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x1c(%rbp)
  mov    %al,-0xc(%rbp)
  jmp    L56
L9:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L8
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  je     L8
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
L56:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L19
  cmpl   $0x7,-0x10(%rbp)
  jg     L19
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L19
  cmpl   $0x7,-0x14(%rbp)
  jle    L9
  jmp    L19
L8:
  nop
L19:
  pop    %rbp
  ret
```

assistant: ```c
void putmv1(char b[64], char p, int x, int y, int m, int n) {
  while ((x += m) >= 0 && x < 8 && (y += n) >= 0 && y < 8) {
    if (b[x * 8 + y] == '-' || b[x * 8 + y] == p)
      return;
    b[x * 8 + y] = p;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<putmv1>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%r11d
  lea    (%rdx,%r8,1),%r10d
  cmp    $0x7,%r10d
  ja     L59
  lea    (%rcx,%r9,1),%edx
  cmp    $0x7,%edx
  ja     L59
  lea    0x0(,%r8,8),%edi
  movslq %edi,%rdi
  movslq %r9d,%rcx
  add    %rcx,%rdi
  lea    0x0(,%r10,8),%ecx
  movslq %ecx,%rcx
  movslq %edx,%rsi
  add    %rsi,%rcx
  add    %rcx,%rax
L35:
  movzbl (%rax),%ecx
  cmp    %r11b,%cl
  je     L59
  cmp    $0x2d,%cl
  je     L59
  mov    %r11b,(%rax)
  add    %r8d,%r10d
  cmp    $0x7,%r10d
  ja     L59
  add    %r9d,%edx
  add    %rdi,%rax
  cmp    $0x7,%edx
  jbe    L35
L59:
  ret
```

assistant: ```c
void putmv1(char b[64], char p, int x, int y, int m, int n) {
  while ((x += m) >= 0 && x < 8 && (y += n) >= 0 && y < 8) {
    if (b[x * 8 + y] == '-' || b[x * 8 + y] == p)
      return;
    b[x * 8 + y] = p;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putmv1>:
  endbr64
  mov    %rdi,%rax
  lea    (%rdx,%r8,1),%edi
  mov    %esi,%r10d
  cmp    $0x7,%edi
  ja     L49
  lea    (%rcx,%r9,1),%edx
  cmp    $0x7,%edx
  ja     L49
  lea    0x0(,%r8,8),%esi
  movslq %r9d,%rcx
  movslq %edx,%r11
  movslq %esi,%rsi
  add    %rcx,%rsi
  lea    0x0(,%rdi,8),%ecx
  movslq %ecx,%rcx
  add    %r11,%rcx
  add    %rcx,%rax
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L48:
  add    %r9d,%edx
  add    %rsi,%rax
  cmp    $0x7,%edx
  ja     L49
L56:
  movzbl (%rax),%ecx
  cmp    %r10b,%cl
  je     L49
  cmp    $0x2d,%cl
  je     L49
  add    %r8d,%edi
  mov    %r10b,(%rax)
  cmp    $0x7,%edi
  jbe    L48
L49:
  ret
```

assistant: ```c
void putmv1(char b[64], char p, int x, int y, int m, int n) {
  while ((x += m) >= 0 && x < 8 && (y += n) >= 0 && y < 8) {
    if (b[x * 8 + y] == '-' || b[x * 8 + y] == p)
      return;
    b[x * 8 + y] = p;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<putmv1>:
  endbr64
  lea    (%rdx,%r8,1),%eax
  mov    %esi,%r10d
  cmp    $0x7,%eax
  ja     L359
  lea    (%rcx,%r9,1),%edx
  cmp    $0x7,%edx
  ja     L359
  cmp    $0x1,%r9d
  jne    L75
  lea    (%rdx,%rax,8),%r9d
  movslq %r9d,%r9
  add    %rdi,%r9
  movzbl (%r9),%r10d
  cmp    %sil,%r10b
  je     L359
  cmp    $0x2d,%r10b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%r9)
  cmp    $0x7,%eax
  ja     L359
  lea    0x2(%rcx),%r9d
  cmp    $0x6,%ecx
  je     L359
  lea    (%r9,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%rcx)
  cmp    $0x7,%eax
  ja     L359
  lea    0x2(%rdx),%ecx
  cmp    $0x6,%edx
  je     L359
  lea    (%rcx,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%rcx)
  cmp    $0x7,%eax
  ja     L359
  lea    0x3(%rdx),%ecx
  cmp    $0x5,%edx
  je     L359
  lea    (%rcx,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%rcx)
  cmp    $0x7,%eax
  ja     L359
  lea    0x4(%rdx),%ecx
  cmp    $0x4,%edx
  je     L359
  lea    (%rcx,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%rcx)
  cmp    $0x7,%eax
  ja     L359
  lea    0x5(%rdx),%ecx
  cmp    $0x3,%edx
  je     L359
  lea    (%rcx,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %r8d,%eax
  mov    %sil,(%rcx)
  cmp    $0x7,%eax
  ja     L359
  lea    0x6(%rdx),%ecx
  cmp    $0x2,%edx
  je     L359
  lea    (%rcx,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movzbl (%rcx),%r9d
  cmp    %sil,%r9b
  je     L359
  cmp    $0x2d,%r9b
  je     L359
  add    %eax,%r8d
  mov    %sil,(%rcx)
  cmp    $0x7,%r8d
  ja     L359
  test   %edx,%edx
  jne    L359
  lea    0x7(,%r8,8),%eax
  cltq
  add    %rax,%rdi
  movzbl (%rdi),%eax
  cmp    %sil,%al
  je     L359
  cmp    $0x2d,%al
  je     L359
  mov    %sil,(%rdi)
L359:
  ret
  nopl   (%rax)
L75:
  lea    0x0(,%r8,8),%r11d
  movslq %r9d,%rcx
  movslq %edx,%rsi
  movslq %r11d,%r11
  add    %rcx,%r11
  lea    0x0(,%rax,8),%ecx
  movslq %ecx,%rcx
  add    %rsi,%rcx
  add    %rdi,%rcx
  jmp    L122
  cs nopw 0x0(%rax,%rax,1)
L302:
  add    %r9d,%edx
  add    %r11,%rcx
  cmp    $0x7,%edx
  ja     L237
L122:
  movzbl (%rcx),%esi
  cmp    %r10b,%sil
  je     L359
  cmp    $0x2d,%sil
  je     L359
  add    %r8d,%eax
  mov    %r10b,(%rcx)
  cmp    $0x7,%eax
  jbe    L302
  ret
L237:
  ret
```

assistant: ```c
void putmv1(char b[64], char p, int x, int y, int m, int n) {
  while ((x += m) >= 0 && x < 8 && (y += n) >= 0 && y < 8) {
    if (b[x * 8 + y] == '-' || b[x * 8 + y] == p)
      return;
    b[x * 8 + y] = p;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<adjust_reading>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D12(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: f64
name: retrieve_data
arguments: data_tag: D12
type_infered: f64

tool: D3: 10500

tool: D12: 10000

assistant: ```c
double adjust_reading(double va) {
  double d;
  d = (va * 10500.0) / 10000.0;
  return (d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<adjust_reading>:
  endbr64
  mulsd  D19(%rip),%xmm0
  divsd  D2(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: f64
name: parse_data
arguments: data_tag: D2
type: f64

tool: D19: 10500

tool: D2: 10000

assistant: ```c
double adjust_reading(double va) {
  double d;
  d = (va * 10500.0) / 10000.0;
  return (d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adjust_reading>:
  endbr64
  mulsd  D10(%rip),%xmm0
  divsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: f64

tool: D10: 10500

tool: D13: 10000

assistant: ```c
double adjust_reading(double va) {
  double d;
  d = (va * 10500.0) / 10000.0;
  return (d);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<adjust_reading>:
  endbr64
  mulsd  D8(%rip),%xmm0
  divsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: f64
name: unpack_data
arguments: label: D4
data_type: f64

tool: D8: 10500

tool: D4: 10000

assistant: ```c
double adjust_reading(double va) {
  double d;
  d = (va * 10500.0) / 10000.0;
  return (d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<giantlizard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    D2(%rip),%rdx
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nicename@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L2:
  mov    $0xa,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %ebx,%eax
  lea    0x3(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D4
type: string

tool: D2: MM 326

tool: D28: giant lizard

tool: D4: %d: %d hp

assistant: ```c
void giantlizard(unsigned count) {
  int i;
  nicename(count, "giant lizard", "MM 326");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, d(10) + d(10) + d(10) + 3);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<giantlizard>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    D26(%rip),%rdx
  lea    D22(%rip),%rsi
  call   <nicename@plt>
  test   %r12d,%r12d
  je     L12
  mov    $0x0,%ebp
  lea    D9(%rip),%r13
L4:
  mov    $0xa,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    $0x1,%ebp
  lea    0x3(%rbx,%rax,1),%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%ebp
  jne    L4
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D9
datatype: string

tool: D26: MM 326

tool: D22: giant lizard

tool: D9: %d: %d hp

assistant: ```c
void giantlizard(unsigned count) {
  int i;
  nicename(count, "giant lizard", "MM 326");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, d(10) + d(10) + d(10) + 3);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<giantlizard>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdx
  lea    D16(%rip),%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <nicename@plt>
  test   %r12d,%r12d
  je     L14
  xor    %ebp,%ebp
  lea    D12(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <d@plt>
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    %r13,%rdi
  mov    %ebp,%esi
  lea    0x3(%rbx,%rax,1),%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%ebp
  jne    L16
L14:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D12
type: string

tool: D11: MM 326

tool: D16: giant lizard

tool: D12: %d: %d hp

assistant: ```c
void giantlizard(unsigned count) {
  int i;
  nicename(count, "giant lizard", "MM 326");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp", i + 1, d(10) + d(10) + d(10) + 3);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```