ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L42
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  jmp    L64
L69:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L13
L64:
  movzbl (%rdx),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L69
  test   $0xdf,%al
  je     L69
  mov    $0x0,%eax
  jmp    L62
L13:
  mov    $0x1,%eax
L62:
  pop    %rbx
  ret
L42:
  mov    $0x1,%eax
  jmp    L62
```

assistant: ```c
int blankline(char *s) {
  int i, nchar, stat;
  nchar = strlen(s);
  stat = 1;
  for (i = 0; i < nchar; i++) {
    if (s[i] != ' ' && s[i] != '\t' && s[i] != '\n' && s[i] != '\0') {
      stat = 0;
      break;
    }
  }
  return (stat);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L6:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L14
  test   $0xdf,%al
  jne    L28
L14:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L6
L15:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L28:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blankline(char *s) {
  int i, nchar, stat;
  nchar = strlen(s);
  stat = 1;
  for (i = 0; i < nchar; i++) {
    if (s[i] != ' ' && s[i] != '\t' && s[i] != '\n' && s[i] != '\0') {
      stat = 0;
      break;
    }
  }
  return (stat);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<blankline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L37:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L16
  test   $0xdf,%al
  jne    L1
L16:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L37
L14:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nop
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int blankline(char *s) {
  int i, nchar, stat;
  nchar = strlen(s);
  stat = 1;
  for (i = 0; i < nchar; i++) {
    if (s[i] != ' ' && s[i] != '\t' && s[i] != '\n' && s[i] != '\0') {
      stat = 0;
      break;
    }
  }
  return (stat);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x31,-0x4(%rbp)
  jle    L0
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int destroy(char *matrix[]) {
  int i = 0;
  for (i = 0; i < 50; i++) {
    free(matrix[i]);
  }
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<destroy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x190(%rdi),%rbp
L0:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L0
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int destroy(char *matrix[]) {
  int i = 0;
  for (i = 0; i < 50; i++) {
    free(matrix[i]);
  }
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<destroy>:
  endbr64
  push   %rbp
  lea    0x190(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int destroy(char *matrix[]) {
  int i = 0;
  for (i = 0; i < 50; i++) {
    free(matrix[i]);
  }
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<destroy>:
  endbr64
  push   %rbp
  lea    0x190(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int destroy(char *matrix[]) {
  int i = 0;
  for (i = 0; i < 50; i++) {
    free(matrix[i]);
  }
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<thing_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,-0x28(%rbp)
  movabs $0x20676e6f6c206f53,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x21776f6e,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x15(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L9
L4:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edi
  call   <puts@plt>
L9:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: Greetings from your computer!

assistant: ```c
void thing_2(void) {
  const char *hello = "Greetings from your computer!";
  char bye_bye[] = "So long now!";
  char *b;
  b = bye_bye;
  while (*hello)
    puts(hello++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<thing_2>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rbx
L7:
  mov    %ebx,%edi
  call   <puts@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L7
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: Greetings from your computer!

assistant: ```c
void thing_2(void) {
  const char *hello = "Greetings from your computer!";
  char bye_bye[] = "So long now!";
  char *b;
  b = bye_bye;
  while (*hello)
    puts(hello++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thing_2>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L1:
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <puts@plt>
  cmpb   $0x0,(%rbx)
  jne    L1
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: Greetings from your computer!

assistant: ```c
void thing_2(void) {
  const char *hello = "Greetings from your computer!";
  char bye_bye[] = "So long now!";
  char *b;
  b = bye_bye;
  while (*hello)
    puts(hello++);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thing_2>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L1:
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <puts@plt>
  cmpb   $0x0,(%rbx)
  jne    L1
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: Greetings from your computer!

assistant: ```c
void thing_2(void) {
  const char *hello = "Greetings from your computer!";
  char bye_bye[] = "So long now!";
  char *b;
  b = bye_bye;
  while (*hello)
    puts(hello++);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_cvc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jle    L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L32
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L32
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L32
  mov    $0x1,%eax
  jmp    L14
L32:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int is_cvc(char *s) {
  if ((strlen(s) >= 3) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_cvc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x2,%edx
  jg     L37
L30:
  pop    %rbx
  ret
L37:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L30
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L30
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L30
```

assistant: ```c
int is_cvc(char *s) {
  if ((strlen(s) >= 3) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_cvc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x2,%eax
  jg     L28
L29:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L29
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L29
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_cvc(char *s) {
  if ((strlen(s) >= 3) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_cvc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x2,%eax
  jg     L17
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%edi
  call   <is_consonant@plt>
  test   %rax,%rax
  je     L8
  movsbl 0x1(%rbx),%edi
  call   <is_vowel@plt>
  test   %rax,%rax
  je     L8
  movsbl 0x2(%rbx),%edi
  call   <is_consonant@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_cvc(char *s) {
  if ((strlen(s) >= 3) && is_consonant(s[0]) && is_vowel(s[1]) && is_consonant(s[2])) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D26(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_ascii_pcs@plt>
  test   %rax,%rax
  je     L16
  lea    D11(%rip),%rax
  jmp    L9
L16:
  lea    D16(%rip),%rax
L9:
  mov    -0x8(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D11
data_type: string
name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D33
data_type: string

tool: D26: Hello World

tool: 

tool: D16: not 

tool: D33: {%s} is %san 'ASCII printable characters' string.

assistant: ```c
int main(void) {
  const char *str = "Hello\x20World";
  printf("{%s} is %san 'ASCII printable characters' string.", str, is_ascii_pcs(str) ? "" : "not ");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D40(%rip),%rdi
  call   <is_ascii_pcs@plt>
  test   %rax,%rax
  lea    D19(%rip),%rdx
  lea    D29(%rip),%rax
  cmove  %rax,%rdx
  lea    D40(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D40
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D29
datatype: string
name: unpack_data
arguments: data_tag: D13
datatype: string

tool: D40: Hello World

tool: 

tool: D29: not 

tool: D13: {%s} is %san 'ASCII printable characters' string.

assistant: ```c
int main(void) {
  const char *str = "Hello\x20World";
  printf("{%s} is %san 'ASCII printable characters' string.", str, is_ascii_pcs(str) ? "" : "not ");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rbp
  mov    %rbp,%rdi
  call   <is_ascii_pcs@plt>
  lea    D19(%rip),%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  test   %rax,%rax
  lea    D8(%rip),%rax
  cmove  %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D23: Hello World

tool: 

tool: D2: {%s} is %san 'ASCII printable characters' string.

tool: D8: not 

assistant: ```c
int main(void) {
  const char *str = "Hello\x20World";
  printf("{%s} is %san 'ASCII printable characters' string.", str, is_ascii_pcs(str) ? "" : "not ");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rbp
  mov    %rbp,%rdi
  call   <is_ascii_pcs@plt>
  lea    D11(%rip),%rdx
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  test   %rax,%rax
  lea    D17(%rip),%rax
  cmove  %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D35
type: string
name: retrieve_data
arguments: label: D17
type: string

tool: D28: Hello World

tool: 

tool: D35: {%s} is %san 'ASCII printable characters' string.

tool: D17: not 

assistant: ```c
int main(void) {
  const char *str = "Hello\x20World";
  printf("{%s} is %san 'ASCII printable characters' string.", str, is_ascii_pcs(str) ? "" : "not ");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x1d,-0x4(%rbp)
  jle    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8:  |%c| 

assistant: ```c
void print_cipher(char *cipher) {
  int i;
  for (i = 0; i < 30; i++)
    printf(" |%c| ", cipher[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_cipher>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1e(%rdi),%r12
  lea    D2(%rip),%rbp
L7:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2:  |%c| 

assistant: ```c
void print_cipher(char *cipher) {
  int i;
  for (i = 0; i < 30; i++)
    printf(" |%c| ", cipher[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_cipher>:
  endbr64
  push   %r12
  lea    0x1e(%rdi),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8:  |%c| 

assistant: ```c
void print_cipher(char *cipher) {
  int i;
  for (i = 0; i < 30; i++)
    printf(" |%c| ", cipher[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_cipher>:
  endbr64
  push   %r12
  lea    0x1e(%rdi),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0:  |%c| 

assistant: ```c
void print_cipher(char *cipher) {
  int i;
  for (i = 0; i < 30; i++)
    printf(" |%c| ", cipher[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testSwap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7b,-0x18(%rbp)
  movl   $0x141,-0x14(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x141,%eax
  jne    L53
  mov    -0x14(%rbp),%eax
  cmp    $0x7b,%eax
  jne    L53
  mov    $0x1,%eax
  jmp    L38
L53:
  mov    $0x0,%eax
L38:
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x21f,-0x10(%rbp)
  movl   $0x22b,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x22b,%eax
  jne    L25
  mov    -0xc(%rbp),%eax
  cmp    $0x21f,%eax
  jne    L25
  mov    $0x1,%eax
  jmp    L59
L25:
  mov    $0x0,%eax
L59:
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void testSwap(void) {
  int i1 = 123;
  int i2 = 321;
  swap(&i1, &i2);
  assert(i1 == 321 && i2 == 123);
  int i3 = 543;
  int i4 = 555;
  swap(&i3, &i4);
  assert(i3 == 555 && i4 == 543);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testSwap>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x7b,0x8(%rsp)
  movl   $0x141,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <swap@plt>
  mov    $0x0,%edi
  cmpl   $0x141,0x8(%rsp)
  je     L42
L16:
  call   <assert@plt>
  movl   $0x21f,0x10(%rsp)
  movl   $0x22b,0x14(%rsp)
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <swap@plt>
  mov    $0x0,%edi
  cmpl   $0x22b,0x10(%rsp)
  je     L38
L48:
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  ret
L42:
  cmpl   $0x7b,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  jmp    L16
L38:
  cmpl   $0x21f,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  jmp    L48
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testSwap(void) {
  int i1 = 123;
  int i2 = 321;
  swap(&i1, &i2);
  assert(i1 == 321 && i2 == 123);
  int i3 = 543;
  int i4 = 555;
  swap(&i3, &i4);
  assert(i3 == 555 && i4 == 543);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<testSwap>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0xc(%rsp),%rsi
  movl   $0x7b,0x8(%rsp)
  movl   $0x141,0xc(%rsp)
  call   <swap@plt>
  xor    %edi,%edi
  cmpl   $0x141,0x8(%rsp)
  jne    L26
  xor    %edi,%edi
  cmpl   $0x7b,0xc(%rsp)
  sete   %dil
L26:
  call   <assert@plt>
  lea    0x10(%rsp),%rdi
  lea    0x14(%rsp),%rsi
  movl   $0x21f,0x10(%rsp)
  movl   $0x22b,0x14(%rsp)
  call   <swap@plt>
  xor    %edi,%edi
  cmpl   $0x22b,0x10(%rsp)
  jne    L3
  xor    %edi,%edi
  cmpl   $0x21f,0x14(%rsp)
  sete   %dil
L3:
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testSwap(void) {
  int i1 = 123;
  int i2 = 321;
  swap(&i1, &i2);
  assert(i1 == 321 && i2 == 123);
  int i3 = 543;
  int i4 = 555;
  swap(&i3, &i4);
  assert(i3 == 555 && i4 == 543);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<testSwap>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0xc(%rsp),%rsi
  movl   $0x7b,0x8(%rsp)
  movl   $0x141,0xc(%rsp)
  call   <swap@plt>
  xor    %edi,%edi
  cmpl   $0x141,0x8(%rsp)
  jne    L23
  xor    %edi,%edi
  cmpl   $0x7b,0xc(%rsp)
  sete   %dil
L23:
  call   <assert@plt>
  lea    0x10(%rsp),%rdi
  lea    0x14(%rsp),%rsi
  movl   $0x21f,0x10(%rsp)
  movl   $0x22b,0x14(%rsp)
  call   <swap@plt>
  xor    %edi,%edi
  cmpl   $0x22b,0x10(%rsp)
  jne    L26
  xor    %edi,%edi
  cmpl   $0x21f,0x14(%rsp)
  sete   %dil
L26:
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void testSwap(void) {
  int i1 = 123;
  int i2 = 321;
  swap(&i1, &i2);
  assert(i1 == 321 && i2 == 123);
  int i3 = 543;
  int i4 = 555;
  swap(&i3, &i4);
  assert(i3 == 555 && i4 == 543);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcat_rarch__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L14
  movq   $0x0,-0x28(%rbp)
  jmp    L3
L14:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
L3:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy_rarch__@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t strlcat_rarch__(char *dest, const char *source, size_t size) {
  size_t len = strlen(dest);
  dest += len;
  if (len > size)
    size = 0;
  else
    size -= len;
  return len + strlcpy_rarch__(dest, source, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcat_rarch__>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %r12,%rdx
  sub    %rax,%rdx
  cmp    %r12,%rax
  mov    $0x0,%eax
  cmova  %rax,%rdx
  mov    %r13,%rsi
  call   <strlcpy_rarch__@plt>
  add    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcat_rarch__(char *dest, const char *source, size_t size) {
  size_t len = strlen(dest);
  dest += len;
  if (len > size)
    size = 0;
  else
    size -= len;
  return len + strlcpy_rarch__(dest, source, size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlcat_rarch__>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,%rbx
  lea    0x0(%rbp,%rax,1),%rdi
  sub    %rax,%rdx
  xor    %eax,%eax
  cmp    %r12,%rbx
  cmova  %rax,%rdx
  call   <strlcpy_rarch__@plt>
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t strlcat_rarch__(char *dest, const char *source, size_t size) {
  size_t len = strlen(dest);
  dest += len;
  if (len > size)
    size = 0;
  else
    size -= len;
  return len + strlcpy_rarch__(dest, source, size);
}
```