ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<isamax>:
  endbr64
  test   %edi,%edi
  jle    L51
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L40
  movsd  (%rsi),%xmm0
  movq   D6(%rip),%xmm2
  andpd  %xmm2,%xmm0
  cmp    $0x1,%edx
  je     L39
  movslq %edx,%rdx
  mov    $0x1,%eax
  shl    $0x3,%rdx
  add    %rdx,%rsi
  nopl   0x0(%rax,%rax,1)
L29:
  movsd  (%rsi),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%eax
  movapd %xmm1,%xmm0
  add    %rdx,%rsi
  cmp    %edi,%eax
  jl     L29
L40:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  nopl   (%rax)
L57:
  movsd  (%rsi,%rax,8),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %eax,%edi
  jg     L57
  mov    %r8d,%eax
  ret
L51:
  mov    $0xffffffff,%r8d
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: qword

tool: D6: 9223372036854775807

assistant: ```c
int isamax(int n, double *sx, int incx) {
  int i, ix, imax;
  double smax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 0;
    imax = 0;
    smax = fabs(sx[0]);
    ix += incx;
    for (i = 1; i < n; i++, ix += incx) {
      if (fabs(sx[ix]) > smax) {
        imax = i;
        smax = fabs(sx[ix]);
      }
    }
    return (imax);
  }
  imax = 0;
  smax = fabs(sx[0]);
  for (i = 1; i < n; i++) {
    if (fabs(sx[i]) > smax) {
      imax = i;
      smax = fabs(sx[i]);
    }
  }
  return (imax);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BASM_Parse_OpChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x40,-0x14(%rbp)
  jg     L109
  cmpl   $0x21,-0x14(%rbp)
  jge    L33
  jmp    L66
L88:
  mov    -0x14(%rbp),%eax
  sub    $0x5c,%eax
  movabs $0x500000005,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L65
  jmp    L66
L33:
  mov    -0x14(%rbp),%eax
  sub    $0x21,%eax
  mov    $0xfa00563d,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L65
  jmp    L66
L109:
  cmpl   $0x7e,-0x14(%rbp)
  jg     L66
  cmpl   $0x5c,-0x14(%rbp)
  jge    L88
  jmp    L66
L65:
  movl   $0x1,-0x4(%rbp)
  jmp    L53
L66:
  movl   $0x0,-0x4(%rbp)
  nop
L53:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int BASM_Parse_OpChar(int c) {
  int i;
  switch (c) {
  case '~':
  case '!':
  case '@':
  case '#':
  case '$':
  case '%':
  case '^':
  case '&':
  case '*':
  case '-':
  case '=':
  case '+':
  case '\\':
  case '|':
  case ':':
  case '<':
  case '>':
  case '?':
  case '/':
    i = 1;
    break;
  default:
    i = 0;
    break;
  }
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BASM_Parse_OpChar>:
  endbr64
  cmp    $0x40,%edi
  jg     L9
  cmp    $0x20,%edi
  jg     L11
  mov    $0x0,%eax
  ret
L11:
  lea    -0x21(%rdi),%ecx
  mov    $0xfa00563d,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L9:
  lea    -0x5c(%rdi),%ecx
  movabs $0x500000005,%rdx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  cmp    $0x23,%ecx
  mov    $0x0,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int BASM_Parse_OpChar(int c) {
  int i;
  switch (c) {
  case '~':
  case '!':
  case '@':
  case '#':
  case '$':
  case '%':
  case '^':
  case '&':
  case '*':
  case '-':
  case '=':
  case '+':
  case '\\':
  case '|':
  case ':':
  case '<':
  case '>':
  case '?':
  case '/':
    i = 1;
    break;
  default:
    i = 0;
    break;
  }
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BASM_Parse_OpChar>:
  endbr64
  cmp    $0x40,%edi
  jg     L0
  cmp    $0x20,%edi
  jg     L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L0:
  movabs $0x500000005,%rdx
  lea    -0x5c(%rdi),%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x23,%ecx
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  lea    -0x21(%rdi),%ecx
  mov    $0xfa00563d,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int BASM_Parse_OpChar(int c) {
  int i;
  switch (c) {
  case '~':
  case '!':
  case '@':
  case '#':
  case '$':
  case '%':
  case '^':
  case '&':
  case '*':
  case '-':
  case '=':
  case '+':
  case '\\':
  case '|':
  case ':':
  case '<':
  case '>':
  case '?':
  case '/':
    i = 1;
    break;
  default:
    i = 0;
    break;
  }
  return (i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BASM_Parse_OpChar>:
  endbr64
  cmp    $0x40,%edi
  jg     L4
  cmp    $0x20,%edi
  jg     L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  movabs $0x500000005,%rdx
  lea    -0x5c(%rdi),%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x23,%ecx
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    -0x21(%rdi),%ecx
  mov    $0xfa00563d,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int BASM_Parse_OpChar(int c) {
  int i;
  switch (c) {
  case '~':
  case '!':
  case '@':
  case '#':
  case '$':
  case '%':
  case '^':
  case '&':
  case '*':
  case '-':
  case '=':
  case '+':
  case '\\':
  case '|':
  case ':':
  case '<':
  case '>':
  case '?':
  case '/':
    i = 1;
    break;
  default:
    i = 0;
    break;
  }
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x68,-0x4(%rbp)
  je     L48
  cmpb   $0x6c,-0x4(%rbp)
  je     L48
  cmpb   $0x6a,-0x4(%rbp)
  je     L48
  cmpb   $0x7a,-0x4(%rbp)
  je     L48
  cmpb   $0x4c,-0x4(%rbp)
  jne    L32
L48:
  mov    $0x1,%eax
  jmp    L55
L32:
  mov    $0x0,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int is_mod(char c) {
  if (c == 'h' || c == 'l' || c == 'j' || c == 'z' || c == 'L')
    return (1);
  else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_mod>:
  endbr64
  lea    -0x4c(%rdi),%ecx
  cmp    $0x2e,%cl
  ja     L9
  movabs $0x400150000001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_mod(char c) {
  if (c == 'h' || c == 'l' || c == 'j' || c == 'z' || c == 'L')
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_mod>:
  endbr64
  lea    -0x4c(%rdi),%ecx
  cmp    $0x2e,%cl
  ja     L3
  movabs $0x400150000001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_mod(char c) {
  if (c == 'h' || c == 'l' || c == 'j' || c == 'z' || c == 'L')
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_mod>:
  endbr64
  lea    -0x4c(%rdi),%ecx
  cmp    $0x2e,%cl
  ja     L5
  movabs $0x400150000001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_mod(char c) {
  if (c == 'h' || c == 'l' || c == 'j' || c == 'z' || c == 'L')
    return (1);
  else
    return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: I am test exe2.


assistant: ```c
int main(int argc, char **argv) {
  printf("I am test exe2.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: I am test exe2.


assistant: ```c
int main(int argc, char **argv) {
  printf("I am test exe2.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D1: I am test exe2.


assistant: ```c
int main(int argc, char **argv) {
  printf("I am test exe2.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: I am test exe2.


assistant: ```c
int main(int argc, char **argv) {
  printf("I am test exe2.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_command_line_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L100
L59:
  addl   $0x1,-0x1c(%rbp)
L100:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L101
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x38(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L59
L101:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L70
  mov    $0x1,%eax
  jmp    L82
L70:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L38
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L61
L38:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L10
  mov    $0x1,%eax
  jmp    L82
L10:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isnum_float@plt>
  test   %rax,%rax
  je     L61
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L61:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isnum_float@plt>
  test   %rax,%rax
  je     L50
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    -0x40(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  jmp    L82
L50:
  mov    $0x2,%eax
L82:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int get_command_line_float(int argc, char *argv[], char *match, float *val, int *found_list) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return 1;
  found_list[i] = 1;
  if (strlen(argv[i]) > strlen(match))
    value_start = argv[i] + strlen(match);
  else {
    if (i == argc)
      return 1;
    value_start = argv[i + 1];
    if (isnum_float(value_start[0]))
      found_list[i + 1] = 1;
  }
  if (isnum_float(value_start[0])) {
    *val = atof(value_start);
  } else {
    return 2;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_command_line_float>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rcx,0x8(%rsp)
  mov    %r8,(%rsp)
  test   %edi,%edi
  jle    L12
  lea    0x8(%rsi),%r14
  mov    $0x1,%ebx
L71:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    (%r14),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L29
  add    $0x1,%ebx
  add    $0x8,%r14
  cmp    %ebx,%r12d
  jge    L71
L29:
  lea    0x1(%r12),%edx
  mov    $0x1,%eax
  cmp    %ebx,%edx
  je     L3
  movslq %ebx,%r14
  lea    0x0(,%r14,4),%rax
  mov    %rax,0x18(%rsp)
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%r14,4)
  shl    $0x3,%r14
  lea    0x0(%r13,%r14,1),%r15
  mov    (%r15),%rdi
  call   <strlen@plt>
  mov    %eax,0x14(%rsp)
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,0x14(%rsp)
  jg     L5
  mov    $0x1,%eax
  cmp    %ebx,%r12d
  je     L3
  mov    0x8(%r13,%r14,1),%rbx
  movsbl (%rbx),%edi
  call   <isnum_float@plt>
  test   %rax,%rax
  je     L73
  mov    (%rsp),%rax
  mov    0x18(%rsp),%rcx
  movl   $0x1,0x4(%rax,%rcx,1)
  jmp    L73
L12:
  mov    $0x1,%ebx
  jmp    L29
L5:
  mov    (%r15),%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
L73:
  movsbl (%rbx),%edi
  call   <isnum_float@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L3
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    0x8(%rsp),%rax
  movss  %xmm0,(%rax)
  mov    $0x0,%eax
L3:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int get_command_line_float(int argc, char *argv[], char *match, float *val, int *found_list) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return 1;
  found_list[i] = 1;
  if (strlen(argv[i]) > strlen(match))
    value_start = argv[i] + strlen(match);
  else {
    if (i == argc)
      return 1;
    value_start = argv[i + 1];
    if (isnum_float(value_start[0]))
      found_list[i + 1] = 1;
  }
  if (isnum_float(value_start[0])) {
    *val = atof(value_start);
  } else {
    return 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_command_line_float>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    %rcx,(%rsp)
  test   %edi,%edi
  jle    L52
  lea    0x8(%rsi),%r15
  mov    $0x1,%r14d
  jmp    L13
  nopl   (%rax)
L40:
  add    $0x1,%r14d
  add    $0x8,%r15
  cmp    %r14d,%ebx
  jl     L60
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%r15),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L40
L60:
  lea    0x1(%rbx),%eax
  cmp    %r14d,%eax
  je     L103
  movslq %r14d,%rax
  lea    0x0(,%rax,8),%r15
  lea    0x0(,%rax,4),%rcx
  movl   $0x1,0x0(%r13,%rax,4)
  lea    (%r12,%r15,1),%rsi
  mov    %rcx,0x18(%rsp)
  mov    (%rsi),%rdi
  mov    %rsi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  cmp    %eax,0xc(%rsp)
  mov    0x10(%rsp),%rsi
  jg     L78
  cmp    %r14d,%ebx
  je     L103
  mov    0x8(%r12,%r15,1),%rbp
  movsbl 0x0(%rbp),%edi
  call   <isnum_float@plt>
  test   %rax,%rax
  je     L101
  mov    0x18(%rsp),%rax
  movl   $0x1,0x4(%r13,%rax,1)
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L103:
  mov    $0x1,%eax
L75:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L78:
  mov    %rbp,%rdi
  mov    (%rsi),%rbx
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rbp
L101:
  movsbl 0x0(%rbp),%edi
  call   <isnum_float@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L75
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    (%rsp),%rax
  movss  %xmm0,(%rax)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  mov    $0x1,%r14d
  jmp    L60
```

assistant: ```c
int get_command_line_float(int argc, char *argv[], char *match, float *val, int *found_list) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return 1;
  found_list[i] = 1;
  if (strlen(argv[i]) > strlen(match))
    value_start = argv[i] + strlen(match);
  else {
    if (i == argc)
      return 1;
    value_start = argv[i + 1];
    if (isnum_float(value_start[0]))
      found_list[i + 1] = 1;
  }
  if (isnum_float(value_start[0])) {
    *val = atof(value_start);
  } else {
    return 2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_command_line_float>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x28,%rsp
  mov    %rcx,(%rsp)
  test   %edi,%edi
  jle    L4
  lea    0x8(%rsi),%r15
  mov    $0x1,%r14d
  jmp    L58
  nopl   (%rax)
L79:
  add    $0x1,%r14d
  add    $0x8,%r15
  cmp    %r14d,%ebx
  jl     L50
L58:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%r15),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L79
L50:
  lea    0x1(%rbx),%eax
  cmp    %r14d,%eax
  je     L21
  movslq %r14d,%rax
  lea    0x0(,%rax,8),%r15
  lea    0x0(,%rax,4),%rcx
  movl   $0x1,0x0(%r13,%rax,4)
  lea    (%r12,%r15,1),%rsi
  mov    %rcx,0x18(%rsp)
  mov    (%rsi),%rdi
  mov    %rsi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  cmp    %eax,0xc(%rsp)
  mov    0x10(%rsp),%rsi
  jg     L83
  cmp    %r14d,%ebx
  je     L21
  mov    0x8(%r12,%r15,1),%rbp
  movsbl 0x0(%rbp),%edi
  call   <isnum_float@plt>
  test   %rax,%rax
  je     L85
  mov    0x18(%rsp),%rax
  movl   $0x1,0x4(%r13,%rax,1)
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%eax
L34:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L83:
  mov    %rbp,%rdi
  mov    (%rsi),%rbx
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rbp
L85:
  movsbl 0x0(%rbp),%edi
  call   <isnum_float@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L34
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    (%rsp),%rax
  movss  %xmm0,(%rax)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0x1,%r14d
  jmp    L50
```

assistant: ```c
int get_command_line_float(int argc, char *argv[], char *match, float *val, int *found_list) {
  int i;
  char *value_start;
  i = 1;
  while ((i <= argc) && (strncmp(argv[i], match, strlen(match)) != 0))
    i++;
  if (i == argc + 1)
    return 1;
  found_list[i] = 1;
  if (strlen(argv[i]) > strlen(match))
    value_start = argv[i] + strlen(match);
  else {
    if (i == argc)
      return 1;
    value_start = argv[i + 1];
    if (isnum_float(value_start[0]))
      found_list[i + 1] = 1;
  }
  if (isnum_float(value_start[0])) {
    *val = atof(value_start);
  } else {
    return 2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BSP_GetPageAttribute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x18,%rax
  add    $0x612000,%rax
  shl    $0x2,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long BSP_GetPageAttribute(unsigned long addr) {
  return ({
    unsigned long __v = (*(volatile unsigned long *)((0x01848000 + 4 * (addr / 16777216))));
    __v;
  });
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BSP_GetPageAttribute>:
  endbr64
  shr    $0x18,%rdi
  add    $0x612000,%rdi
  mov    0x0(,%rdi,4),%rax
  ret
```

assistant: ```c
unsigned long BSP_GetPageAttribute(unsigned long addr) {
  return ({
    unsigned long __v = (*(volatile unsigned long *)((0x01848000 + 4 * (addr / 16777216))));
    __v;
  });
}
```
user: Translate the below assembly code into C programming language:

```asm
<BSP_GetPageAttribute>:
  endbr64
  shr    $0x18,%rdi
  add    $0x612000,%rdi
  mov    0x0(,%rdi,4),%rax
  ret
```

assistant: ```c
unsigned long BSP_GetPageAttribute(unsigned long addr) {
  return ({
    unsigned long __v = (*(volatile unsigned long *)((0x01848000 + 4 * (addr / 16777216))));
    __v;
  });
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filter1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L13
L2:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L2
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double filter1(double *x, double *a, size_t n) {
  double v;
  size_t i;
  v = 0.0;
  for (i = 0; i < n; i++)
    v += a[i] * x[i];
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filter1>:
  endbr64
  test   %rdx,%rdx
  je     L27
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L9:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L9
L12:
  movapd %xmm1,%xmm0
  ret
L27:
  pxor   %xmm1,%xmm1
  jmp    L12
```

assistant: ```c
double filter1(double *x, double *a, size_t n) {
  double v;
  size_t i;
  v = 0.0;
  for (i = 0; i < n; i++)
    v += a[i] * x[i];
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filter1>:
  endbr64
  test   %rdx,%rdx
  je     L16
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nop
L15:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L15
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L16:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double filter1(double *x, double *a, size_t n) {
  double v;
  size_t i;
  v = 0.0;
  for (i = 0; i < n; i++)
    v += a[i] * x[i];
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<filter1>:
  endbr64
  test   %rdx,%rdx
  je     L3
  cmp    $0x1,%rdx
  je     L12
  mov    %rdx,%rcx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %rcx
  shl    $0x4,%rcx
  nop
L15:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rdi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L15
  mov    %rdx,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%edx
  je     L37
L14:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L37:
  ret
  nopl   0x0(%rax)
L3:
  pxor   %xmm0,%xmm0
  ret
L12:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L14
```

assistant: ```c
double filter1(double *x, double *a, size_t n) {
  double v;
  size_t i;
  v = 0.0;
  for (i = 0; i < n; i++)
    v += a[i] * x[i];
  return v;
}
```