ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <crmode@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  nop
  mov    $0x0,%esi
  mov    $0x20,%edi
  call   <start_scene@plt>
  nop
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  while (initscr(), crmode(), noecho(), 0) {
  }
  while (start_scene(' ', 0), 0) {
  }
  while (endwin(), 0) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <crmode@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%esi
  mov    $0x20,%edi
  call   <start_scene@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  while (initscr(), crmode(), noecho(), 0) {
  }
  while (start_scene(' ', 0), 0) {
  }
  while (endwin(), 0) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <crmode@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %esi,%esi
  mov    $0x20,%edi
  call   <start_scene@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  while (initscr(), crmode(), noecho(), 0) {
  }
  while (start_scene(' ', 0), 0) {
  }
  while (endwin(), 0) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <crmode@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %esi,%esi
  mov    $0x20,%edi
  call   <start_scene@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  while (initscr(), crmode(), noecho(), 0) {
  }
  while (start_scene(' ', 0), 0) {
  }
  while (endwin(), 0) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<driver>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x70(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <encodeNegativeBase@plt>
  lea    -0x50(%rbp),%rcx
  mov    -0x70(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decodeNegativeBase@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rcx
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string

tool: D19: %12d encoded in base %3d = %12s


tool: D9: %12s decoded in base %3d = %12d


assistant: ```c
void driver(long n, long b) {
  char buf[64];
  long value;
  encodeNegativeBase(n, b, buf);
  printf("%12d encoded in base %3d = %12s\n", n, b, buf);
  value = decodeNegativeBase(buf, b);
  printf("%12s decoded in base %3d = %12d\n", buf, b, value);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<driver>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <encodeNegativeBase@plt>
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <decodeNegativeBase@plt>
  mov    %rax,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string

tool: D2: %12d encoded in base %3d = %12s


tool: D18: %12s decoded in base %3d = %12d


assistant: ```c
void driver(long n, long b) {
  char buf[64];
  long value;
  encodeNegativeBase(n, b, buf);
  printf("%12d encoded in base %3d = %12s\n", n, b, buf);
  value = decodeNegativeBase(buf, b);
  printf("%12s decoded in base %3d = %12d\n", buf, b, value);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<driver>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <encodeNegativeBase@plt>
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <decodeNegativeBase@plt>
  lea    D6(%rip),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D10: %12d encoded in base %3d = %12s


tool: D6: %12s decoded in base %3d = %12d


assistant: ```c
void driver(long n, long b) {
  char buf[64];
  long value;
  encodeNegativeBase(n, b, buf);
  printf("%12d encoded in base %3d = %12s\n", n, b, buf);
  value = decodeNegativeBase(buf, b);
  printf("%12s decoded in base %3d = %12d\n", buf, b, value);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<driver>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <encodeNegativeBase@plt>
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <decodeNegativeBase@plt>
  lea    D18(%rip),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D19: %12d encoded in base %3d = %12s


tool: D18: %12s decoded in base %3d = %12d


assistant: ```c
void driver(long n, long b) {
  char buf[64];
  long value;
  encodeNegativeBase(n, b, buf);
  printf("%12d encoded in base %3d = %12s\n", n, b, buf);
  value = decodeNegativeBase(buf, b);
  printf("%12s decoded in base %3d = %12d\n", buf, b, value);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L29
  mov    $0x1,%eax
  jmp    L57
L29:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L91
  mov    $0x0,%eax
  jmp    L57
L91:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L98
  mov    $0x0,%eax
  jmp    L57
L98:
  movl   $0x0,-0xc(%rbp)
  jmp    L86
L73:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L53
  mov    $0x0,%eax
  jmp    L57
L53:
  addl   $0x1,-0xc(%rbp)
L86:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L73
  mov    $0x1,%eax
L57:
  leave
  ret
```

assistant: ```c
char endswith(char *str, char *var) {
  if (str == var) {
    return 1;
  }
  int varLen = strlen(var);
  if (varLen == 0) {
    return 0;
  }
  int strLen = strlen(str);
  if (strLen == 0) {
    return 0;
  }
  for (int i = 0; i < varLen; i++) {
    if (str[strLen - 1 - i] != var[varLen - 1 - i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<endswith>:
  endbr64
  mov    $0x1,%eax
  cmp    %rsi,%rdi
  je     L54
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  test   %r12d,%r12d
  jne    L82
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x0,%eax
  test   %esi,%esi
  je     L45
  test   %r12d,%r12d
  jle    L61
  lea    -0x1(%r12),%ecx
  not    %rcx
  mov    $0x0,%edx
  movslq %esi,%rsi
  add    %rsi,%rbp
  movslq %r12d,%r12
  add    %r12,%rbx
L27:
  movzbl -0x1(%rdx,%rbx,1),%eax
  cmp    %al,-0x1(%rbp,%rdx,1)
  jne    L28
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L27
  mov    $0x1,%eax
  jmp    L45
L61:
  mov    $0x1,%eax
  jmp    L45
L28:
  mov    $0x0,%eax
  jmp    L45
L54:
  ret
```

assistant: ```c
char endswith(char *str, char *var) {
  if (str == var) {
    return 1;
  }
  int varLen = strlen(var);
  if (varLen == 0) {
    return 0;
  }
  int strLen = strlen(str);
  if (strLen == 0) {
    return 0;
  }
  for (int i = 0; i < varLen; i++) {
    if (str[strLen - 1 - i] != var[varLen - 1 - i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<endswith>:
  endbr64
  cmp    %rsi,%rdi
  je     L28
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  test   %r12d,%r12d
  jne    L20
L58:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L58
  test   %r12d,%r12d
  jle    L37
  lea    -0x1(%r12),%ecx
  cltq
  xor    %edx,%edx
  add    %r12,%rbx
  not    %rcx
  add    %rax,%rbp
  jmp    L50
  nopl   (%rax)
L60:
  sub    $0x1,%rdx
  cmp    %rdx,%rcx
  je     L37
L50:
  movzbl -0x1(%rdx,%rbx,1),%eax
  cmp    %al,-0x1(%rdx,%rbp,1)
  je     L60
  jmp    L58
  xchg   %ax,%ax
L37:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char endswith(char *str, char *var) {
  if (str == var) {
    return 1;
  }
  int varLen = strlen(var);
  if (varLen == 0) {
    return 0;
  }
  int strLen = strlen(str);
  if (strLen == 0) {
    return 0;
  }
  for (int i = 0; i < varLen; i++) {
    if (str[strLen - 1 - i] != var[varLen - 1 - i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<endswith>:
  endbr64
  cmp    %rsi,%rdi
  je     L8
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  test   %r12d,%r12d
  jne    L42
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L37
  test   %r12d,%r12d
  jle    L17
  lea    -0x1(%r12),%ecx
  cltq
  xor    %edx,%edx
  add    %r12,%rbx
  not    %rcx
  add    %rax,%rbp
  jmp    L58
  nopl   (%rax)
L23:
  sub    $0x1,%rdx
  cmp    %rdx,%rcx
  je     L17
L58:
  movzbl -0x1(%rdx,%rbx,1),%eax
  cmp    %al,-0x1(%rdx,%rbp,1)
  je     L23
  jmp    L37
  xchg   %ax,%ax
L17:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char endswith(char *str, char *var) {
  if (str == var) {
    return 1;
  }
  int varLen = strlen(var);
  if (varLen == 0) {
    return 0;
  }
  int strLen = strlen(str);
  if (strLen == 0) {
    return 0;
  }
  for (int i = 0; i < varLen; i++) {
    if (str[strLen - 1 - i] != var[varLen - 1 - i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_rm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L4
L10:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jns    L0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L0:
  addq   $0x8,-0x10(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cmp    $0x1,%eax
  jg     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void do_rm(int argc, const char **argv) {
  while (argc-- > 1) {
    if (unlink(argv[1]) < 0)
      perror(argv[1]);
    argv++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_rm>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    (%rsi,%rax,8),%rbp
  jmp    L31
L19:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L44
L31:
  mov    0x8(%rbx),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jns    L19
  mov    0x8(%rbx),%rdi
  call   <perror@plt>
  jmp    L19
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

assistant: ```c
void do_rm(int argc, const char **argv) {
  while (argc-- > 1) {
    if (unlink(argv[1]) < 0)
      perror(argv[1]);
    argv++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<do_rm>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    (%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L48
L39:
  mov    0x8(%rbx),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jns    L3
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <perror@plt>
  cmp    %rbp,%rbx
  jne    L39
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
void do_rm(int argc, const char **argv) {
  while (argc-- > 1) {
    if (unlink(argv[1]) < 0)
      perror(argv[1]);
    argv++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_rm>:
  endbr64
  cmp    $0x1,%edi
  jle    L18
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    (%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L26
L37:
  mov    0x8(%rbx),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jns    L42
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <perror@plt>
  cmp    %rbp,%rbx
  jne    L37
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void do_rm(int argc, const char **argv) {
  while (argc-- > 1) {
    if (unlink(argv[1]) < 0)
      perror(argv[1]);
    argv++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x4,%eax
  ja     L18
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  jmp    L13
L18:
  lea    D1(%rip),%rax
L13:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: ?!?!?

assistant: ```c
const char *chname(int chno) {
  static const char *chnames[] = {"FROM_PEER", "TO_PEER", "CHILD_STDIN", "CHILD_STDOUT", "CHILD_STDERR"};
  if (chno < (sizeof(chnames) / sizeof(*(chnames))))
    return chnames[chno];
  return "?!?!?";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chname>:
  endbr64
  lea    D11(%rip),%rax
  cmp    $0x4,%edi
  jbe    L15
L19:
  ret
L15:
  movslq %edi,%rdi
  lea    D4(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  jmp    L19
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string

tool: D11: ?!?!?

assistant: ```c
const char *chname(int chno) {
  static const char *chnames[] = {"FROM_PEER", "TO_PEER", "CHILD_STDIN", "CHILD_STDOUT", "CHILD_STDERR"};
  if (chno < (sizeof(chnames) / sizeof(*(chnames))))
    return chnames[chno];
  return "?!?!?";
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<chname>:
  endbr64
  lea    D14(%rip),%rax
  cmp    $0x4,%edi
  jbe    L7
  ret
  nopl   0x0(%rax)
L7:
  movslq %edi,%rdi
  lea    D11(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string

tool: D14: ?!?!?

assistant: ```c
const char *chname(int chno) {
  static const char *chnames[] = {"FROM_PEER", "TO_PEER", "CHILD_STDIN", "CHILD_STDOUT", "CHILD_STDERR"};
  if (chno < (sizeof(chnames) / sizeof(*(chnames))))
    return chnames[chno];
  return "?!?!?";
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<chname>:
  endbr64
  lea    D2(%rip),%rax
  cmp    $0x4,%edi
  jbe    L5
  ret
  nopl   0x0(%rax)
L5:
  movslq %edi,%rdi
  lea    D11(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: ?!?!?

assistant: ```c
const char *chname(int chno) {
  static const char *chnames[] = {"FROM_PEER", "TO_PEER", "CHILD_STDIN", "CHILD_STDOUT", "CHILD_STDERR"};
  if (chno < (sizeof(chnames) / sizeof(*(chnames))))
    return chnames[chno];
  return "?!?!?";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<project_vn_vnvn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dot_vnvn@plt>
  movq   %xmm0,%rbx
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dot_vnvn@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mul_vnvn_fl@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void project_vn_vnvn(double v_out[], const double p[], const double v_proj[], const uint dims) {
  const double mul = dot_vnvn(p, v_proj, dims) / dot_vnvn(v_proj, v_proj, dims);
  mul_vnvn_fl(v_out, v_proj, mul, dims);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<project_vn_vnvn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    %ecx,%edx
  mov    %rbx,%rsi
  call   <dot_vnvn@plt>
  movq   %xmm0,%rbp
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <dot_vnvn@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  divsd  %xmm1,%xmm0
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <mul_vnvn_fl@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void project_vn_vnvn(double v_out[], const double p[], const double v_proj[], const uint dims) {
  const double mul = dot_vnvn(p, v_proj, dims) / dot_vnvn(v_proj, v_proj, dims);
  mul_vnvn_fl(v_out, v_proj, mul, dims);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<project_vn_vnvn>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  mov    %ecx,%edx
  mov    %rbp,%rsi
  sub    $0x10,%rsp
  call   <dot_vnvn@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <dot_vnvn@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  movsd  0x8(%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  divsd  %xmm0,%xmm1
  pop    %r13
  movapd %xmm1,%xmm0
  jmp    1060 <mul_vnvn_fl@plt>
```

assistant: ```c
void project_vn_vnvn(double v_out[], const double p[], const double v_proj[], const uint dims) {
  const double mul = dot_vnvn(p, v_proj, dims) / dot_vnvn(v_proj, v_proj, dims);
  mul_vnvn_fl(v_out, v_proj, mul, dims);
}
```
user: What is the c source code of the assembly code below:

```asm
<celcon_is_stable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x36f,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int celcon_is_stable(int *flag) {
  int fail;
  int *b;
  double *c;
  fail = _ada_use_c2phc4c(879, flag, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<celcon_is_stable>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x36f,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int celcon_is_stable(int *flag) {
  int fail;
  int *b;
  double *c;
  fail = _ada_use_c2phc4c(879, flag, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<celcon_is_stable>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x36f,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int celcon_is_stable(int *flag) {
  int fail;
  int *b;
  double *c;
  fail = _ada_use_c2phc4c(879, flag, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<celcon_is_stable>:
  endbr64
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x36f,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int celcon_is_stable(int *flag) {
  int fail;
  int *b;
  double *c;
  fail = _ada_use_c2phc4c(879, flag, b, c, 0);
  return fail;
}
```