ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Ket_StateOverwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L19:
  mov    $0x1,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x20(%rbp),%edx
  cmp    %eax,%edx
  cmovbe %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edi
  mov    -0x8(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <KeccakF200_StateOverwriteBytesInLane@plt>
  mov    -0x4(%rbp),%eax
  add    %rax,-0x28(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
L12:
  cmpl   $0x0,-0x20(%rbp)
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void Ket_StateOverwrite(void *state, unsigned int offset, const unsigned char *data, unsigned int length) {
  unsigned int lanePosition;
  unsigned int laneOffset;
  unsigned int sizeInLane;
  lanePosition = offset / 1;
  laneOffset = offset % 1;
  while (length != 0) {
    sizeInLane = (((1 - laneOffset) < (length)) ? (1 - laneOffset) : (length));
    KeccakF200_StateOverwriteBytesInLane(state, lanePosition, data, laneOffset, sizeInLane);
    data += sizeInLane;
    length -= sizeInLane;
    ++lanePosition;
    laneOffset = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Ket_StateOverwrite>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%r12
  mov    %ecx,%ebp
  test   %ecx,%ecx
  je     L10
L6:
  cmp    $0x0,%ebp
  mov    $0x1,%ebx
  cmovbe %ebp,%ebx
  mov    %ebx,%r8d
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <KeccakF200_StateOverwriteBytesInLane@plt>
  mov    %ebx,%eax
  add    %rax,%r12
  add    $0x1,%r13d
  sub    %ebx,%ebp
  jne    L6
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Ket_StateOverwrite(void *state, unsigned int offset, const unsigned char *data, unsigned int length) {
  unsigned int lanePosition;
  unsigned int laneOffset;
  unsigned int sizeInLane;
  lanePosition = offset / 1;
  laneOffset = offset % 1;
  while (length != 0) {
    sizeInLane = (((1 - laneOffset) < (length)) ? (1 - laneOffset) : (length));
    KeccakF200_StateOverwriteBytesInLane(state, lanePosition, data, laneOffset, sizeInLane);
    data += sizeInLane;
    length -= sizeInLane;
    ++lanePosition;
    laneOffset = 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<Ket_StateOverwrite>:
  endbr64
  test   %ecx,%ecx
  je     L11
  push   %r13
  mov    %ecx,%ecx
  sub    %edx,%esi
  push   %r12
  mov    %esi,%r13d
  mov    %rdi,%r12
  push   %rbp
  lea    (%rdx,%rcx,1),%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  lea    0x0(%r13,%rbx,1),%esi
  mov    %rbx,%rdx
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <KeccakF200_StateOverwriteBytesInLane@plt>
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
void Ket_StateOverwrite(void *state, unsigned int offset, const unsigned char *data, unsigned int length) {
  unsigned int lanePosition;
  unsigned int laneOffset;
  unsigned int sizeInLane;
  lanePosition = offset / 1;
  laneOffset = offset % 1;
  while (length != 0) {
    sizeInLane = (((1 - laneOffset) < (length)) ? (1 - laneOffset) : (length));
    KeccakF200_StateOverwriteBytesInLane(state, lanePosition, data, laneOffset, sizeInLane);
    data += sizeInLane;
    length -= sizeInLane;
    ++lanePosition;
    laneOffset = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Ket_StateOverwrite>:
  endbr64
  test   %ecx,%ecx
  je     L12
  push   %r13
  mov    %ecx,%ecx
  sub    %edx,%esi
  push   %r12
  mov    %esi,%r13d
  mov    %rdi,%r12
  push   %rbp
  lea    (%rdx,%rcx,1),%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  lea    0x0(%r13,%rbx,1),%esi
  mov    %rbx,%rdx
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <KeccakF200_StateOverwriteBytesInLane@plt>
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  ret
```

assistant: ```c
void Ket_StateOverwrite(void *state, unsigned int offset, const unsigned char *data, unsigned int length) {
  unsigned int lanePosition;
  unsigned int laneOffset;
  unsigned int sizeInLane;
  lanePosition = offset / 1;
  laneOffset = offset % 1;
  while (length != 0) {
    sizeInLane = (((1 - laneOffset) < (length)) ? (1 - laneOffset) : (length));
    KeccakF200_StateOverwriteBytesInLane(state, lanePosition, data, laneOffset, sizeInLane);
    data += sizeInLane;
    length -= sizeInLane;
    ++lanePosition;
    laneOffset = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_intake_temp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x7,%edx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <obd_get_bytes@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L6
L2:
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  sub    $0x28,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: 010F 1

assistant: ```c
int get_intake_temp(int fd) {
  long int *data;
  int intake_temp = 0;
  write(fd, "010F 1\r", 7);
  data = obd_get_bytes(fd, 1);
  if (data == NULL) {
    intake_temp = -1;
  } else {
    intake_temp = (int)data[2] - 40;
    free(data);
  }
  return intake_temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_intake_temp>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x7,%edx
  lea    D2(%rip),%rsi
  call   <write@plt>
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <obd_get_bytes@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  mov    0x10(%rax),%eax
  lea    -0x28(%rax),%ebx
  call   <free@plt>
L13:
  mov    %ebx,%eax
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%ebx
  jmp    L13
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: 010F 1

assistant: ```c
int get_intake_temp(int fd) {
  long int *data;
  int intake_temp = 0;
  write(fd, "010F 1\r", 7);
  data = obd_get_bytes(fd, 1);
  if (data == NULL) {
    intake_temp = -1;
  } else {
    intake_temp = (int)data[2] - 40;
    free(data);
  }
  return intake_temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_intake_temp>:
  endbr64
  push   %r12
  lea    D5(%rip),%rsi
  mov    $0x7,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <write@plt>
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <obd_get_bytes@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  mov    0x10(%rax),%eax
  lea    -0x28(%rax),%r12d
  call   <free@plt>
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%r12d
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: 010F 1

assistant: ```c
int get_intake_temp(int fd) {
  long int *data;
  int intake_temp = 0;
  write(fd, "010F 1\r", 7);
  data = obd_get_bytes(fd, 1);
  if (data == NULL) {
    intake_temp = -1;
  } else {
    intake_temp = (int)data[2] - 40;
    free(data);
  }
  return intake_temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_intake_temp>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  mov    $0x7,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <write@plt>
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <obd_get_bytes@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rdi
  mov    0x10(%rax),%eax
  lea    -0x28(%rax),%r12d
  call   <free@plt>
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%r12d
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: 010F 1

assistant: ```c
int get_intake_temp(int fd) {
  long int *data;
  int intake_temp = 0;
  write(fd, "010F 1\r", 7);
  data = obd_get_bytes(fd, 1);
  if (data == NULL) {
    intake_temp = -1;
  } else {
    intake_temp = (int)data[2] - 40;
    free(data);
  }
  return intake_temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L13:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: %016llx

assistant: ```c
void print_array(const uint64_t *array, uint16_t size) {
  uint16_t i;
  for (i = size; i > 0;)
    printf("%016llx", array[--i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D8(%rip),%r12
L12:
  sub    $0x1,%rbx
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  jne    L12
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: %016llx

assistant: ```c
void print_array(const uint64_t *array, uint16_t size) {
  uint16_t i;
  for (i = size; i > 0;)
    printf("%016llx", array[--i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_array>:
  endbr64
  test   %rsi,%rsi
  je     L10
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  sub    $0x1,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    0x0(%rbp,%rbx,4),%esi
  call   <printf@plt>
  test   %rbx,%rbx
  jne    L14
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L10:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: %016llx

assistant: ```c
void print_array(const uint64_t *array, uint16_t size) {
  uint16_t i;
  for (i = size; i > 0;)
    printf("%016llx", array[--i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_array>:
  endbr64
  test   %rsi,%rsi
  je     L12
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    0x0(%rbp,%rbx,4),%esi
  call   <printf@plt>
  test   %rbx,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: %016llx

assistant: ```c
void print_array(const uint64_t *array, uint16_t size) {
  uint16_t i;
  for (i = size; i > 0;)
    printf("%016llx", array[--i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<input_double>:
  endbr64
  movabs 0x100000200,%rax
  xchg   %ax,%ax
L54:
  cmp    $0xffffffffffffffff,%rax
  je     L58
  cmp    $0x2d,%rax
  je     L59
  cmp    $0x39,%rax
  jg     L54
  cmp    $0x2f,%rax
  jle    L54
L46:
  jmp    L46
L59:
  jmp    L59
  nopl   0x0(%rax)
L58:
  movq   $0x0,(%rdi)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long input_double(double *result) {
  long c;
  long is_neg;
  long is_checking;
  long n;
  double d;
  double scale;
  long rt;
  long ret;
  long e;
  n = 0;
  d = 0.0;
  is_neg = 0;
  is_checking = 1;
  ret = -1;
  e = 0;
  do {
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c == (long)'-') {
      c = *(long *)0x100000200;
      if (c <= (long)'9') {
        if (c >= (long)'0') {
          is_neg = 1;
          is_checking = 0;
          ret = 0;
        }
      }
    } else if (c <= (long)'9') {
      if (c >= (long)'0') {
        is_checking = 0;
        ret = 0;
      }
    }
  } while (is_checking == 1);
  is_checking = 1;
  do {
    n = n * 10 + (long)c - (long)'0';
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c == (long)'.')
      goto input_double_after_dot;
    if (c > (long)'9') {
      is_checking = 0;
    }
    if (c < (long)'0') {
      is_checking = 0;
    }
  } while (is_checking == 1);
  goto input_double_exit;
input_double_after_dot:
  is_checking = 1;
  scale = 0.1;
  do {
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c <= (long)'9') {
      if (c >= (long)'0') {
        c = (long)c - (long)'0';
        d = d + scale * (double)c;
        scale = scale / 10.0;
      } else {
        is_checking = 0;
      }
    } else {
      is_checking = 0;
    }
  } while (is_checking == 1);
input_double_exit:
  d = d + (double)n;
  if (c == 'E') {
    rt = input_long(&e);
    if (rt != 0)
      e = 0;
  }
  if (c == 'e') {
    rt = input_long(&e);
    if (rt != 0)
      e = 0;
  }
  if (e > 0) {
    d = d * (double)(ipow(10, e));
  } else if (e < 0) {
    d = d / (double)(ipow(10, e));
  }
  if (is_neg == 1) {
    d = 0.0 - d;
  }
  *result = d;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_double>:
  endbr64
  movabs 0x100000200,%rax
  xchg   %ax,%ax
L59:
  cmp    $0xffffffffffffffff,%rax
  je     L15
  cmp    $0x2d,%rax
  je     L32
  cmp    $0x39,%rax
  jg     L59
  cmp    $0x2f,%rax
  jle    L59
L48:
  jmp    L48
L32:
  jmp    L32
  nopl   0x0(%rax)
L15:
  movq   $0x0,(%rdi)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long input_double(double *result) {
  long c;
  long is_neg;
  long is_checking;
  long n;
  double d;
  double scale;
  long rt;
  long ret;
  long e;
  n = 0;
  d = 0.0;
  is_neg = 0;
  is_checking = 1;
  ret = -1;
  e = 0;
  do {
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c == (long)'-') {
      c = *(long *)0x100000200;
      if (c <= (long)'9') {
        if (c >= (long)'0') {
          is_neg = 1;
          is_checking = 0;
          ret = 0;
        }
      }
    } else if (c <= (long)'9') {
      if (c >= (long)'0') {
        is_checking = 0;
        ret = 0;
      }
    }
  } while (is_checking == 1);
  is_checking = 1;
  do {
    n = n * 10 + (long)c - (long)'0';
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c == (long)'.')
      goto input_double_after_dot;
    if (c > (long)'9') {
      is_checking = 0;
    }
    if (c < (long)'0') {
      is_checking = 0;
    }
  } while (is_checking == 1);
  goto input_double_exit;
input_double_after_dot:
  is_checking = 1;
  scale = 0.1;
  do {
    c = *(long *)0x100000200;
    if (c == (-1))
      goto input_double_exit;
    if (c <= (long)'9') {
      if (c >= (long)'0') {
        c = (long)c - (long)'0';
        d = d + scale * (double)c;
        scale = scale / 10.0;
      } else {
        is_checking = 0;
      }
    } else {
      is_checking = 0;
    }
  } while (is_checking == 1);
input_double_exit:
  d = d + (double)n;
  if (c == 'E') {
    rt = input_long(&e);
    if (rt != 0)
      e = 0;
  }
  if (c == 'e') {
    rt = input_long(&e);
    if (rt != 0)
      e = 0;
  }
  if (e > 0) {
    d = d * (double)(ipow(10, e));
  } else if (e < 0) {
    d = d / (double)(ipow(10, e));
  }
  if (is_neg == 1) {
    d = 0.0 - d;
  }
  *result = d;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L12:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L12
  cmpl   $0x9,-0x4(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L93
  cmpl   $0x2e,-0x4(%rbp)
  je     L93
  mov    -0x4(%rbp),%eax
  jmp    L42
L93:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L108
  jmp    L111
L114:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L111:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L114
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L108:
  cmpl   $0x2e,-0x4(%rbp)
  jne    L105
  jmp    L41
L13:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L41:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L105:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L1:
  mov    $0x30,%eax
L42:
  leave
  ret
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L102:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L102
  cmp    $0x20,%al
  je     L102
  movb   $0x0,0x1(%rbp)
  mov    %eax,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%ebx
  je     L83
  test   %rax,%rax
  je     L84
L83:
  mov    %ebx,%edi
  call   <isdigit@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L25
  mov    $0x0,%r12d
  jmp    L54
L9:
  mov    %bl,0x0(%rbp,%r12,1)
L54:
  mov    %r12d,%r13d
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L9
  add    $0x1,%r13d
  movslq %r13d,%rax
  mov    %bl,0x0(%rbp,%rax,1)
L25:
  movslq %r13d,%r12
  cmp    $0x2e,%ebx
  je     L23
L1:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D1(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L99
  mov    $0x30,%ebx
L84:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L103:
  mov    %bl,0x0(%rbp,%r12,1)
L23:
  mov    %r12d,%r13d
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L103
  add    $0x1,%r13d
  movslq %r13d,%rax
  mov    %bl,0x0(%rbp,%rax,1)
  jmp    L1
L99:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L84
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L74:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L74
  cmp    $0x20,%al
  je     L74
  movb   $0x0,0x1(%rbx)
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L122
  cmp    $0x2e,%r12d
  je     L52
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L52:
  mov    $0x2e,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L95
L3:
  cltq
  lea    0x1(%rbx,%rax,1),%rbx
  jmp    L106
L29:
  mov    %r12b,(%rbx)
  add    $0x1,%rbx
L106:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L29
  mov    %r12b,(%rbx)
  movb   $0x0,(%rax)
  mov    D7(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L1
L102:
  add    $0x8,%rsp
  mov    $0x30,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L122:
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L75
L95:
  mov    %ebx,%r13d
  lea    0x1(%rbx),%rbp
  neg    %r13d
  jmp    L126
  xchg   %ax,%ax
L7:
  add    $0x1,%rbp
L126:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  mov    %r12b,0x0(%rbp)
  mov    %rax,%r8
  lea    0x0(%r13,%rbp,1),%eax
  test   %r8,%r8
  jne    L7
L75:
  cmp    $0x2e,%r12d
  je     L3
  cltq
  add    %rbx,%rax
  movb   $0x0,(%rax)
  mov    D7(%rip),%rax
  cmp    %r12d,(%rax)
  je     L102
L1:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.')
    return c;
  i = 0;
  if (isdigit(c)) {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  if (c == '.') {
    while (isdigit(c = getch())) {
      s[++i] = c;
    }
    s[++i] = c;
  }
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```