ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<palm>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    $0x14,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    $0xc2,%edi
  sub    $0x860,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x858(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  lea    D30(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  sub    $0x8,%rsp
  mov    %rbp,%r9
  movaps %xmm0,0x28(%rsp)
  movaps %xmm0,0x38(%rsp)
  movaps %xmm0,0x48(%rsp)
  push   %rax
  call   <doctrl@plt>
  mov    %rbp,%rdi
  lea    D28(%rip),%rdx
  lea    0x60(%rsp),%rbp
  mov    %eax,%esi
  call   <hex@plt>
  mov    $0x800,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x6,%edx
  mov    %rbp,%rsi
  mov    $0x6,%edi
  call   <recv_bulk@plt>
  lea    D9(%rip),%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <hex@plt>
  mov    $0x800,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x16,%edx
  mov    %rbp,%rsi
  mov    $0x6,%edi
  call   <recv_bulk@plt>
  lea    D34(%rip),%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <hex@plt>
  pop    %rax
  pop    %rdx
  mov    0x858(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x860,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D30
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D34
type_infered: string

tool: D30: vendor req

tool: D28: palm vendor req

tool: D9: bulk 1

tool: D34: bulk 2

assistant: ```c
void palm(void) {
  uint8_t abVendor[0x14] = {0};
  int cb = doctrl(0x80 | (0x2 << (5)) | 0x2, 0x04, 0, 0, 0x14, abVendor, "vendor req");
  hex(abVendor, cb, "palm vendor req");
  uint8_t abBuf[512];
  memset(abBuf, 0, sizeof(abBuf));
  cb = recv_bulk(6, abBuf, 6);
  hex(abBuf, cb, "bulk 1");
  memset(abBuf, 0, sizeof(abBuf));
  cb = recv_bulk(6, abBuf, 22);
  hex(abBuf, cb, "bulk 2");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  ja     L3
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L6
L3:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <av_strlcpy@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
L6:
  leave
  ret
```

assistant: ```c
size_t c_strlcat(char *dst, const char *src, size_t size) {
  size_t len = strlen(dst);
  if (size <= len + 1) {
    return len + strlen(src);
  }
  return len + av_strlcpy(dst + len, src, size - len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<c_strlcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    %r12,%rax
  jb     L0
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r12,%rdx
  sub    %rbx,%rdx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <av_strlcpy@plt>
  add    %rbx,%rax
  jmp    L15
```

assistant: ```c
size_t c_strlcat(char *dst, const char *src, size_t size) {
  size_t len = strlen(dst);
  if (size <= len + 1) {
    return len + strlen(src);
  }
  return len + av_strlcpy(dst + len, src, size - len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<c_strlcat>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  add    $0x1,%rax
  cmp    %r12,%rax
  jb     L9
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L9:
  mov    %r12,%rdx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rsi
  sub    %rbx,%rdx
  call   <av_strlcpy@plt>
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t c_strlcat(char *dst, const char *src, size_t size) {
  size_t len = strlen(dst);
  if (size <= len + 1) {
    return len + strlen(src);
  }
  return len + av_strlcpy(dst + len, src, size - len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_strlcat>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  add    $0x1,%rax
  cmp    %r12,%rax
  jb     L8
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L8:
  mov    %r12,%rdx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rsi
  sub    %rbx,%rdx
  call   <av_strlcpy@plt>
  add    $0x8,%rsp
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t c_strlcat(char *dst, const char *src, size_t size) {
  size_t len = strlen(dst);
  if (size <= len + 1) {
    return len + strlen(src);
  }
  return len + av_strlcpy(dst + len, src, size - len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<which>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  je     L52
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L52
  lea    -0x2c(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L39
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rcx
  lea    D12(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    -0x38(%rbp),%rax
  jmp    L18
L39:
  mov    $0x0,%eax
  jmp    L18
L52:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x18(%rbp)
L89:
  lea    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L18
L19:
  mov    -0x48(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D22(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    -0x2c(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L99
  mov    -0x38(%rbp),%rax
  jmp    L18
L99:
  movq   $0x0,-0x18(%rbp)
  jmp    L89
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
type_guessed: string
name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string

tool: D12: %s

tool: D37: PATH

tool: D15: :

tool: D22: %s/%s

assistant: ```c
char *which(char *outbuf, size_t bufsize, const char *filename) {
  struct stat statbuf;
  char *paths, *saveptr = NULL;
  if (filename && '/' == *filename) {
    int err = stat(filename, &statbuf);
    if (!err) {
      snprintf(outbuf, bufsize, "%s", filename);
      return outbuf;
    }
    return NULL;
  }
  for (paths = getenv("PATH");; paths = NULL) {
    char *path = strtok_r(paths, ":", &saveptr);
    int err;
    if (path == NULL)
      return NULL;
    snprintf(outbuf, bufsize, "%s/%s", path, filename);
    err = stat(outbuf, &statbuf);
    if (!err)
      return outbuf;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<which>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  test   %rdx,%rdx
  je     L13
  cmpb   $0x2f,(%rdx)
  je     L17
L13:
  lea    D5(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  lea    0x10(%rsp),%r14
  lea    D7(%rip),%r13
  lea    0xc(%rsp),%r15
L15:
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L62
  mov    %rbp,%r8
  lea    D38(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  mov    $0x0,%edi
  test   %eax,%eax
  jne    L15
  mov    %rbx,%rcx
L62:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    %rcx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  lea    0xc(%rsp),%rsi
  mov    %rdx,%rdi
  call   <stat@plt>
  mov    $0x0,%ecx
  test   %eax,%eax
  jne    L62
  mov    %rbp,%rcx
  lea    D18(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rcx
  jmp    L62
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D38
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D5: PATH

tool: D7: :

tool: D38: %s/%s

tool: D18: %s

assistant: ```c
char *which(char *outbuf, size_t bufsize, const char *filename) {
  struct stat statbuf;
  char *paths, *saveptr = NULL;
  if (filename && '/' == *filename) {
    int err = stat(filename, &statbuf);
    if (!err) {
      snprintf(outbuf, bufsize, "%s", filename);
      return outbuf;
    }
    return NULL;
  }
  for (paths = getenv("PATH");; paths = NULL) {
    char *path = strtok_r(paths, ":", &saveptr);
    int err;
    if (path == NULL)
      return NULL;
    snprintf(outbuf, bufsize, "%s/%s", path, filename);
    err = stat(outbuf, &statbuf);
    if (!err)
      return outbuf;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<which>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  test   %rdx,%rdx
  je     L24
  cmpb   $0x2f,(%rdx)
  je     L46
L24:
  lea    D10(%rip),%rdi
  lea    0x10(%rsp),%r14
  call   <getenv@plt>
  lea    D22(%rip),%r13
  lea    D16(%rip),%r15
  mov    %rax,%rdi
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %r12,%r8
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %rbx,%rdi
  lea    0xc(%rsp),%rsi
  call   <stat@plt>
  xor    %edi,%edi
  test   %eax,%eax
  je     L88
L58:
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L27
L77:
  xor    %eax,%eax
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L88:
  mov    %rbx,%rax
  jmp    L21
  nopl   (%rax)
L46:
  lea    0xc(%rsp),%rsi
  mov    %rdx,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L77
  mov    %r12,%rcx
  lea    D17(%rip),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  jmp    L21
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: D10: PATH

tool: D22: :

tool: D16: %s/%s

tool: D17: %s

assistant: ```c
char *which(char *outbuf, size_t bufsize, const char *filename) {
  struct stat statbuf;
  char *paths, *saveptr = NULL;
  if (filename && '/' == *filename) {
    int err = stat(filename, &statbuf);
    if (!err) {
      snprintf(outbuf, bufsize, "%s", filename);
      return outbuf;
    }
    return NULL;
  }
  for (paths = getenv("PATH");; paths = NULL) {
    char *path = strtok_r(paths, ":", &saveptr);
    int err;
    if (path == NULL)
      return NULL;
    snprintf(outbuf, bufsize, "%s/%s", path, filename);
    err = stat(outbuf, &statbuf);
    if (!err)
      return outbuf;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<which>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  test   %rdx,%rdx
  je     L58
  cmpb   $0x2f,(%rdx)
  je     L83
L58:
  lea    D19(%rip),%rdi
  lea    0x10(%rsp),%r14
  call   <getenv@plt>
  lea    D37(%rip),%r13
  lea    D11(%rip),%r15
  mov    %rax,%rdi
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L82:
  mov    %r12,%r8
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %rbx,%rdi
  lea    0xc(%rsp),%rsi
  call   <stat@plt>
  xor    %edi,%edi
  test   %eax,%eax
  je     L34
L11:
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L82
L27:
  xor    %eax,%eax
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rbx,%rax
  jmp    L5
  nopl   (%rax)
L83:
  lea    0xc(%rsp),%rsi
  mov    %rdx,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L27
  mov    %r12,%rcx
  lea    D21(%rip),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  jmp    L5
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D37
type: string
name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D21
type: string

tool: D19: PATH

tool: D37: :

tool: D11: %s/%s

tool: D21: %s

assistant: ```c
char *which(char *outbuf, size_t bufsize, const char *filename) {
  struct stat statbuf;
  char *paths, *saveptr = NULL;
  if (filename && '/' == *filename) {
    int err = stat(filename, &statbuf);
    if (!err) {
      snprintf(outbuf, bufsize, "%s", filename);
      return outbuf;
    }
    return NULL;
  }
  for (paths = getenv("PATH");; paths = NULL) {
    char *path = strtok_r(paths, ":", &saveptr);
    int err;
    if (path == NULL)
      return NULL;
    snprintf(outbuf, bufsize, "%s/%s", path, filename);
    err = stat(outbuf, &statbuf);
    if (!err)
      return outbuf;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
L48:
  mov    $0x0,%eax
  call   <menu@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L32
  mov    $0x0,%eax
  call   <insert@plt>
  jmp    L19
L32:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L53
  mov    $0x0,%eax
  call   <dele@plt>
  jmp    L19
L53:
  movl   $0x0,-0xc(%rbp)
L19:
  cmpl   $0x0,-0xc(%rbp)
  jne    L48
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string

tool: D22: 
enter Your choice:

tool: D0: %d

tool: D24: 

Program Ends



assistant: ```c
int main() {
  int i = 1, choice;
  do {
    menu();
    printf("\nenter Your choice:");
    scanf("%d", &choice);
    if (choice == 1) {
      insert();
    } else if (choice == 2) {
      dele();
    } else
      i = 0;
  } while (i);
  printf("\n\nProgram Ends\n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D8(%rip),%rbx
  jmp    L39
L26:
  mov    $0x0,%eax
  call   <insert@plt>
L39:
  mov    $0x0,%eax
  call   <menu@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L26
  cmp    $0x2,%eax
  jne    L34
  mov    $0x0,%eax
  call   <dele@plt>
  jmp    L39
L34:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D9: 
enter Your choice:

tool: D8: %d

tool: D16: 

Program Ends



assistant: ```c
int main() {
  int i = 1, choice;
  do {
    menu();
    printf("\nenter Your choice:");
    scanf("%d", &choice);
    if (choice == 1) {
      insert();
    } else if (choice == 2) {
      dele();
    } else
      i = 0;
  } while (i);
  printf("\n\nProgram Ends\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L0:
  xor    %eax,%eax
  call   <menu@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L6
  cmp    $0x2,%eax
  jne    L45
  xor    %eax,%eax
  call   <dele@plt>
  jmp    L0
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <insert@plt>
  jmp    L0
  nopl   0x0(%rax)
L45:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string

tool: D11: 
enter Your choice:

tool: D28: %d

tool: D23: 

Program Ends



assistant: ```c
int main() {
  int i = 1, choice;
  do {
    menu();
    printf("\nenter Your choice:");
    scanf("%d", &choice);
    if (choice == 1) {
      insert();
    } else if (choice == 2) {
      dele();
    } else
      i = 0;
  } while (i);
  printf("\n\nProgram Ends\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L25:
  xor    %eax,%eax
  call   <menu@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L43
  cmp    $0x2,%eax
  jne    L31
  xor    %eax,%eax
  call   <dele@plt>
  jmp    L25
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  call   <insert@plt>
  jmp    L25
  nopl   0x0(%rax)
L31:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string

tool: D17: 
enter Your choice:

tool: D1: %d

tool: D10: 

Program Ends



assistant: ```c
int main() {
  int i = 1, choice;
  do {
    menu();
    printf("\nenter Your choice:");
    scanf("%d", &choice);
    if (choice == 1) {
      insert();
    } else if (choice == 2) {
      dele();
    } else
      i = 0;
  } while (i);
  printf("\n\nProgram Ends\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dotstrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L109
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L109
  addq   $0x1,-0x8(%rbp)
  jmp    L84
L109:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L108
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L108
  addq   $0x1,-0x18(%rbp)
  jmp    L84
L108:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L154
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L154
  mov    $0x0,%eax
  jmp    L77
L154:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L77
L28:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L104
  mov    $0x1,%eax
  jmp    L77
L104:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L56
  mov    $0x1,%eax
  jmp    L77
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L148
  mov    $0xffffffff,%eax
  jmp    L77
L148:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L84:
  jmp    L11
L77:
  pop    %rbp
  ret
```

assistant: ```c
int dotstrcmp(const char *a_s, const char *a_e, const char *b_s, const char *b_e) {
  do {
    if ((a_s != a_e) && (*a_s == '.')) {
      a_s++;
      continue;
    }
    if ((b_s != b_e) && (*b_s == '.')) {
      b_s++;
      continue;
    }
    if ((a_s == a_e) && (b_s == b_e))
      return 0;
    if (a_s == a_e)
      return -1;
    if (b_s == b_e)
      return 1;
    if (*a_s > *b_s)
      return 1;
    if (*b_s > *a_s)
      return -1;
    a_s++;
    b_s++;
  } while (true);
}
```