ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strsplit3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0xc(%rbp)
  jmp    L4
L39:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L39
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
  jmp    L2
L22:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strsplit3(char *string, char sep, char *first, char *second) {
  while (*string != sep) {
    *first++ = *string++;
  }
  *first = '\0';
  string++;
  while (*string != '\0') {
    *second++ = *string++;
  }
  *second = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strsplit3>:
  endbr64
  mov    %esi,%r8d
  movzbl (%rdi),%eax
  cmp    %al,%sil
  je     L33
L38:
  add    $0x1,%rdi
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rdi),%eax
  cmp    %r8b,%al
  jne    L38
L33:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L0
L34:
  add    $0x1,%rdx
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L34
L0:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void strsplit3(char *string, char sep, char *first, char *second) {
  while (*string != sep) {
    *first++ = *string++;
  }
  *first = '\0';
  string++;
  while (*string != '\0') {
    *second++ = *string++;
  }
  *second = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strsplit3>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%r8d
  cmp    %al,%sil
  je     L36
  nop
L9:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rdi),%eax
  cmp    %r8b,%al
  jne    L9
L36:
  movb   $0x0,(%rdx)
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L4
  nopl   0x0(%rax)
L8:
  add    $0x1,%rdx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L8
L4:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void strsplit3(char *string, char sep, char *first, char *second) {
  while (*string != sep) {
    *first++ = *string++;
  }
  *first = '\0';
  string++;
  while (*string != '\0') {
    *second++ = *string++;
  }
  *second = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strsplit3>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%r8d
  cmp    %al,%sil
  je     L13
  nop
L4:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rdi),%eax
  cmp    %r8b,%al
  jne    L4
L13:
  movb   $0x0,(%rdx)
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L24
  nopl   0x0(%rax)
L26:
  add    $0x1,%rdx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L26
L24:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void strsplit3(char *string, char sep, char *first, char *second) {
  while (*string != sep) {
    *first++ = *string++;
  }
  *first = '\0';
  string++;
  while (*string != '\0') {
    *second++ = *string++;
  }
  *second = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clad_test_floateq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movss  %xmm1,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  movss  -0x20(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L5
  movss  -0x4(%rbp),%xmm0
  movss  D13(%rip),%xmm1
  xorps  %xmm1,%xmm0
  jmp    L6
L5:
  movss  -0x4(%rbp),%xmm0
L6:
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%esi
  mov    -0x28(%rbp),%rcx
  movss  -0x20(%rbp),%xmm0
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  lea    D7(%rip),%rdx
  mov    %rax,%rdi
  call   <clad_test_assert@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: byte[4]
name: retrieve_data
arguments: data_tag: D5
type: f64
name: retrieve_data
arguments: data_tag: D7
type: string

tool: {"D13": [0x00,0x00,0x00,0x80]}

tool: D5: 1e-07

tool: D7: Floats should be equal: %f %f; %s 

assistant: ```c
struct clad_test *clad_test_floateq(struct clad_test *test, float d1, float d2, const char *explain) {
  float delta = d2 - d1;
  delta = ((delta < 0) ? -delta : delta);
  return clad_test_assert(test, delta < 0.0000001, "Floats should be equal: %f %f; %s ", d1, d2, explain);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clad_test_floateq>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  pxor   %xmm3,%xmm3
  comiss %xmm2,%xmm3
  ja     L11
L19:
  cvtss2sd %xmm2,%xmm2
  movsd  D29(%rip),%xmm3
  comisd %xmm2,%xmm3
  seta   %sil
  movzbl %sil,%esi
  lea    D27(%rip),%rdx
  call   <clad_test_assert@plt>
  add    $0x8,%rsp
  ret
L11:
  xorps  D15(%rip),%xmm2
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: f64
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D15
type: byte[16]

tool: D29: 1e-07

tool: D27: Floats should be equal: %f %f; %s 

tool: {"D15": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
struct clad_test *clad_test_floateq(struct clad_test *test, float d1, float d2, const char *explain) {
  float delta = d2 - d1;
  delta = ((delta < 0) ? -delta : delta);
  return clad_test_assert(test, delta < 0.0000001, "Floats should be equal: %f %f; %s ", d1, d2, explain);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clad_test_floateq>:
  endbr64
  movaps %xmm1,%xmm2
  pxor   %xmm3,%xmm3
  mov    %rsi,%rcx
  subss  %xmm0,%xmm2
  comiss %xmm2,%xmm3
  jbe    L5
  xorps  D17(%rip),%xmm2
L5:
  movsd  D25(%rip),%xmm3
  xor    %esi,%esi
  cvtss2sd %xmm2,%xmm2
  lea    D3(%rip),%rdx
  comisd %xmm2,%xmm3
  seta   %sil
  jmp    1050 <clad_test_assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D25
data_type: f64
name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: {"D17": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D25: 1e-07

tool: D3: Floats should be equal: %f %f; %s 

assistant: ```c
struct clad_test *clad_test_floateq(struct clad_test *test, float d1, float d2, const char *explain) {
  float delta = d2 - d1;
  delta = ((delta < 0) ? -delta : delta);
  return clad_test_assert(test, delta < 0.0000001, "Floats should be equal: %f %f; %s ", d1, d2, explain);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clad_test_floateq>:
  endbr64
  movaps %xmm1,%xmm2
  pxor   %xmm3,%xmm3
  mov    %rsi,%rcx
  subss  %xmm0,%xmm2
  comiss %xmm2,%xmm3
  jbe    L6
  xorps  D14(%rip),%xmm2
L6:
  movsd  D3(%rip),%xmm3
  xor    %esi,%esi
  cvtss2sd %xmm2,%xmm2
  lea    D23(%rip),%rdx
  comisd %xmm2,%xmm3
  seta   %sil
  jmp    1050 <clad_test_assert@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: byte[16]
name: retrieve_data
arguments: label: D3
datatype: f64
name: retrieve_data
arguments: label: D23
datatype: string

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D3: 1e-07

tool: D23: Floats should be equal: %f %f; %s 

assistant: ```c
struct clad_test *clad_test_floateq(struct clad_test *test, float d1, float d2, const char *explain) {
  float delta = d2 - d1;
  delta = ((delta < 0) ? -delta : delta);
  return clad_test_assert(test, delta < 0.0000001, "Floats should be equal: %f %f; %s ", d1, d2, explain);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L67
L69:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L23
L31:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L66
  mov    $0xa,%edi
  call   <putchar@plt>
L66:
  addl   $0x1,-0x24(%rbp)
L23:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L31
  mov    -0x28(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L17
  mov    $0xa,%edi
  call   <putchar@plt>
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
L40:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L69
L67:
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  jg     L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D34
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string

tool: D34: %d

tool: D0: %s

tool: D1: %20s

assistant: ```c
int main() {
  int t, i, c;
  char s[21];
  while (scanf("%d", &t) > 0)
    while (t--) {
      scanf("%d", &c);
      for (i = 1; i <= c; i++) {
        scanf("%s", s);
        printf("%20s", s);
        if (i % 4 == 0)
          putchar('\n');
      }
      if (c % 4 != 0)
        putchar('\n');
      putchar('\n');
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%r14
  lea    D19(%rip),%r13
  lea    D24(%rip),%r12
L20:
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  jle    L81
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  lea    0xc(%rsp),%r15
  test   %eax,%eax
  jne    L75
  jmp    L20
L62:
  test   $0x3,%al
  jne    L61
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L20
L75:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L62
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    0x10(%rsp),%rbp
L80:
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jl     L62
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  test   $0x3,%bl
  jne    L80
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L80
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L40
L81:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D24
data_type: string

tool: D17: %d

tool: D19: %s

tool: D24: %20s

assistant: ```c
int main() {
  int t, i, c;
  char s[21];
  while (scanf("%d", &t) > 0)
    while (t--) {
      scanf("%d", &c);
      for (i = 1; i <= c; i++) {
        scanf("%s", s);
        printf("%20s", s);
        if (i % 4 == 0)
          putchar('\n');
      }
      if (c % 4 != 0)
        putchar('\n');
      putchar('\n');
    }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  lea    0x1c(%rsp),%r14
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L48
  mov    0x18(%rsp),%eax
  lea    0x20(%rsp),%rbx
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L80
  nopl   0x0(%rax)
L74:
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L33
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    $0x1,%r15d
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L58:
  mov    0x1c(%rsp),%eax
  add    $0x1,%r15d
  cmp    %r15d,%eax
  jl     L33
L99:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   $0x3,%r15b
  jne    L58
  mov    $0xa,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
  cmp    %r15d,%eax
  jge    L99
L33:
  test   $0x3,%al
  jne    L34
L75:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L74
  jmp    L80
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L75
L48:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D26
type: string

tool: D18: %d

tool: D11: %s

tool: D26: %20s

assistant: ```c
int main() {
  int t, i, c;
  char s[21];
  while (scanf("%d", &t) > 0)
    while (t--) {
      scanf("%d", &c);
      for (i = 1; i <= c; i++) {
        scanf("%s", s);
        printf("%20s", s);
        if (i % 4 == 0)
          putchar('\n');
      }
      if (c % 4 != 0)
        putchar('\n');
      putchar('\n');
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  lea    0x1c(%rsp),%r14
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L115
  mov    0x18(%rsp),%eax
  lea    0x20(%rsp),%rbx
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L39
  nopl   0x0(%rax)
L103:
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L83
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    $0x2,%r15d
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  cmp    $0x1,%eax
  jle    L83
  nopl   0x0(%rax)
L55:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   $0x3,%r15b
  je     L35
  mov    0x1c(%rsp),%eax
  add    $0x1,%r15d
  cmp    %r15d,%eax
  jge    L55
L83:
  test   $0x3,%al
  jne    L6
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L103
  jmp    L39
  nopl   0x0(%rax)
L35:
  mov    $0xa,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  mov    0x1c(%rsp),%eax
  cmp    %eax,%r15d
  jle    L55
  test   $0x3,%al
  je     L12
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L12
L115:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D9: %d

tool: D5: %s

tool: D19: %20s

assistant: ```c
int main() {
  int t, i, c;
  char s[21];
  while (scanf("%d", &t) > 0)
    while (t--) {
      scanf("%d", &c);
      for (i = 1; i <= c; i++) {
        scanf("%s", s);
        printf("%20s", s);
        if (i % 4 == 0)
          putchar('\n');
      }
      if (c % 4 != 0)
        putchar('\n');
      putchar('\n');
    }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vp8_dequant_idct_add_uv_block_neon>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,0x8(%rsp)
  mov    %r8d,%r12d
  mov    %r9,%rbx
  movzwl (%r9),%eax
  test   %ax,%ax
  je     L68
  test   $0xfefe,%eax
  je     L100
  mov    %r8d,%ecx
  call   <idct_dequant_full_2x_neon@plt>
L68:
  lea    0x0(,%r12,4),%r15d
  movslq %r15d,%r15
  movzwl 0x2(%rbx),%eax
  test   %ax,%ax
  je     L90
  lea    0x40(%rbp),%rdi
  lea    (%r14,%r15,1),%rdx
  test   $0xfefe,%eax
  je     L21
  mov    %r12d,%ecx
  mov    %r13,%rsi
  call   <idct_dequant_full_2x_neon@plt>
L90:
  movzwl 0x4(%rbx),%eax
  test   %ax,%ax
  je     L24
  lea    0x80(%rbp),%rdi
  test   $0xfefe,%eax
  je     L79
  mov    %r12d,%ecx
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  call   <idct_dequant_full_2x_neon@plt>
L24:
  movzwl 0x6(%rbx),%eax
  test   %ax,%ax
  je     L73
  lea    0xc0(%rbp),%rdi
  mov    0x8(%rsp),%rdx
  add    %r15,%rdx
  test   $0xfefe,%eax
  je     L81
  mov    %r12d,%ecx
  mov    %r13,%rsi
  call   <idct_dequant_full_2x_neon@plt>
L73:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L100:
  movswl (%rsi),%esi
  mov    %r8d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L68
L21:
  movswl 0x0(%r13),%esi
  mov    %r12d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L90
L79:
  movswl 0x0(%r13),%esi
  mov    %r12d,%ecx
  mov    0x8(%rsp),%rdx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L24
L81:
  movswl 0x0(%r13),%esi
  mov    %r12d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L73
```

assistant: ```c
void vp8_dequant_idct_add_uv_block_neon(short *q, short *dq, unsigned char *dstu, unsigned char *dstv, int stride, char *eobs) {
  if (((short *)(eobs))[0]) {
    if (((short *)eobs)[0] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstu, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstu, stride);
  }
  q += 32;
  dstu += 4 * stride;
  if (((short *)(eobs))[1]) {
    if (((short *)eobs)[1] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstu, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstu, stride);
  }
  q += 32;
  if (((short *)(eobs))[2]) {
    if (((short *)eobs)[2] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstv, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstv, stride);
  }
  q += 32;
  dstv += 4 * stride;
  if (((short *)(eobs))[3]) {
    if (((short *)eobs)[3] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstv, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstv, stride);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vp8_dequant_idct_add_uv_block_neon>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  movzwl (%r9),%eax
  mov    %rcx,0x8(%rsp)
  test   %ax,%ax
  je     L9
  test   $0xfefe,%eax
  je     L42
  mov    %r8d,%ecx
  call   <idct_dequant_full_2x_neon@plt>
L9:
  movzwl 0x2(%rbx),%eax
  lea    0x0(,%r12,4),%r15d
  movslq %r15d,%r15
  test   %ax,%ax
  je     L62
  lea    0x40(%rbp),%rdi
  lea    (%r14,%r15,1),%rdx
  test   $0xfefe,%eax
  je     L87
  mov    %r12d,%ecx
  mov    %r13,%rsi
  call   <idct_dequant_full_2x_neon@plt>
L62:
  movzwl 0x4(%rbx),%eax
  test   %ax,%ax
  je     L49
  lea    0x80(%rbp),%rdi
  test   $0xfefe,%eax
  je     L91
  mov    0x8(%rsp),%rdx
  mov    %r12d,%ecx
  mov    %r13,%rsi
  call   <idct_dequant_full_2x_neon@plt>
L49:
  movzwl 0x6(%rbx),%eax
  test   %ax,%ax
  je     L88
  mov    0x8(%rsp),%rdx
  lea    0xc0(%rbp),%rdi
  add    %r15,%rdx
  test   $0xfefe,%eax
  je     L46
  add    $0x18,%rsp
  mov    %r12d,%ecx
  mov    %r13,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <idct_dequant_full_2x_neon@plt>
  nopw   0x0(%rax,%rax,1)
L88:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L46:
  movswl 0x0(%r13),%esi
  add    $0x18,%rsp
  mov    %r12d,%ecx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <idct_dequant_0_2x_neon@plt>
  nopl   0x0(%rax,%rax,1)
L91:
  movswl 0x0(%r13),%esi
  mov    0x8(%rsp),%rdx
  mov    %r12d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L87:
  movswl 0x0(%r13),%esi
  mov    %r12d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L42:
  movswl (%rsi),%esi
  mov    %r8d,%ecx
  call   <idct_dequant_0_2x_neon@plt>
  jmp    L9
```

assistant: ```c
void vp8_dequant_idct_add_uv_block_neon(short *q, short *dq, unsigned char *dstu, unsigned char *dstv, int stride, char *eobs) {
  if (((short *)(eobs))[0]) {
    if (((short *)eobs)[0] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstu, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstu, stride);
  }
  q += 32;
  dstu += 4 * stride;
  if (((short *)(eobs))[1]) {
    if (((short *)eobs)[1] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstu, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstu, stride);
  }
  q += 32;
  if (((short *)(eobs))[2]) {
    if (((short *)eobs)[2] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstv, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstv, stride);
  }
  q += 32;
  dstv += 4 * stride;
  if (((short *)(eobs))[3]) {
    if (((short *)eobs)[3] & 0xfefe)
      idct_dequant_full_2x_neon(q, dq, dstv, stride);
    else
      idct_dequant_0_2x_neon(q, dq[0], dstv, stride);
  }
}
```