ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gpio_set_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x36,-0x14(%rbp)
  jle    L53
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L22
L53:
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  lea    0x200028(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <bcm2835_write@plt>
  jmp    L46
L12:
  cmpl   $0x1,-0x18(%rbp)
  jne    L58
  mov    -0x4(%rbp),%eax
  lea    0x20001c(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <bcm2835_write@plt>
  jmp    L46
L58:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
L46:
  mov    $0x0,%eax
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D2: GPIO%d too big


tool: D5: Invalid GPIO value %d


assistant: ```c
int gpio_set_value(int which_one, int value) {
  uint32_t address_offset, bit;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  if (value == 0) {
    bcm2835_write(((0 + 0x200000) + 0x28) + address_offset, bit);
  } else if (value == 1) {
    bcm2835_write(((0 + 0x200000) + 0x1c) + address_offset, bit);
  } else {
    printk("Invalid GPIO value %d\n", value);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gpio_set_value>:
  endbr64
  push   %rbx
  cmp    $0x36,%edi
  jg     L50
  mov    %esi,%ebx
  mov    $0x1,%esi
  mov    %edi,%ecx
  shl    %cl,%esi
  lea    0x1f(%rdi),%edx
  test   %edi,%edi
  cmovns %edi,%edx
  sar    $0x5,%edx
  shl    $0x2,%edx
  test   %ebx,%ebx
  je     L10
  cmp    $0x1,%ebx
  je     L46
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  call   <printk@plt>
  mov    $0x0,%eax
L37:
  pop    %rbx
  ret
L50:
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L37
L10:
  lea    0x200028(%rdx),%edi
  call   <bcm2835_write@plt>
  mov    %ebx,%eax
  jmp    L37
L46:
  lea    0x20001c(%rdx),%edi
  call   <bcm2835_write@plt>
  mov    $0x0,%eax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D0: Invalid GPIO value %d


tool: D7: GPIO%d too big


assistant: ```c
int gpio_set_value(int which_one, int value) {
  uint32_t address_offset, bit;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  if (value == 0) {
    bcm2835_write(((0 + 0x200000) + 0x28) + address_offset, bit);
  } else if (value == 1) {
    bcm2835_write(((0 + 0x200000) + 0x1c) + address_offset, bit);
  } else {
    printk("Invalid GPIO value %d\n", value);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gpio_set_value>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x36,%edi
  jg     L11
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  test   %edi,%edi
  mov    %eax,%r8d
  lea    0x1f(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x5,%eax
  shl    $0x2,%eax
  test   %esi,%esi
  je     L27
  cmp    $0x1,%esi
  je     L20
  lea    D13(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
L0:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  lea    0x20001c(%rax),%edi
  mov    %r8d,%esi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L27:
  lea    0x200028(%rax),%edi
  mov    %r8d,%esi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_infered: string
name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D13: Invalid GPIO value %d


tool: D2: GPIO%d too big


assistant: ```c
int gpio_set_value(int which_one, int value) {
  uint32_t address_offset, bit;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  if (value == 0) {
    bcm2835_write(((0 + 0x200000) + 0x28) + address_offset, bit);
  } else if (value == 1) {
    bcm2835_write(((0 + 0x200000) + 0x1c) + address_offset, bit);
  } else {
    printk("Invalid GPIO value %d\n", value);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gpio_set_value>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x36,%edi
  jg     L0
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  test   %edi,%edi
  mov    %eax,%r8d
  lea    0x1f(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x5,%eax
  shl    $0x2,%eax
  test   %esi,%esi
  je     L16
  cmp    $0x1,%esi
  je     L32
  lea    D0(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
L17:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  lea    0x20001c(%rax),%edi
  mov    %r8d,%esi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L16:
  lea    0x200028(%rax),%edi
  mov    %r8d,%esi
  call   <bcm2835_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printk@plt>
  mov    $0xffffffff,%eax
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D0: Invalid GPIO value %d


tool: D8: GPIO%d too big


assistant: ```c
int gpio_set_value(int which_one, int value) {
  uint32_t address_offset, bit;
  if (which_one > 54) {
    printk("GPIO%d too big\n", which_one);
    return -1;
  }
  bit = 1 << (which_one & 0x1f);
  address_offset = (which_one / 32) * 4;
  if (value == 0) {
    bcm2835_write(((0 + 0x200000) + 0x28) + address_offset, bit);
  } else if (value == 1) {
    bcm2835_write(((0 + 0x200000) + 0x1c) + address_offset, bit);
  } else {
    printk("Invalid GPIO value %d\n", value);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_dec_locator_events_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <show_dec_locator_events@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int test_dec_locator_events_p(const char *the_title) {
  show_dec_locator_events(the_title, 1, (1));
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_dec_locator_events_p>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <show_dec_locator_events@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_dec_locator_events_p(const char *the_title) {
  show_dec_locator_events(the_title, 1, (1));
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_dec_locator_events_p>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <show_dec_locator_events@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_dec_locator_events_p(const char *the_title) {
  show_dec_locator_events(the_title, 1, (1));
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_dec_locator_events_p>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <show_dec_locator_events@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_dec_locator_events_p(const char *the_title) {
  show_dec_locator_events(the_title, 1, (1));
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D3(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int func() {
  static int xfunc = 5;
  return xfunc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int func() {
  static int xfunc = 5;
  return xfunc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int func() {
  static int xfunc = 5;
  return xfunc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int func() {
  static int xfunc = 5;
  return xfunc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ntobr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3e72623c,0x12(%rsp)
  movw   $0xa,0x16(%rsp)
  movw   $0xa,0x10(%rsp)
  lea    0x12(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    (%rbx,%rbx,1),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,(%rsp)
  movb   $0x0,(%rax)
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r14,%rbp
  lea    0x10(%rsp),%r12
  jmp    L40
L18:
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    %rdx,%rbx
  movslq %r15d,%r13
  lea    (%rax,%r13,1),%rbp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  add    %r13,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L40:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L57
  cmp    %rax,%r14
  je     L18
  cmpb   $0x3e,-0x1(%rax)
  je     L18
  mov    %rax,%r13
  sub    %rbp,%r13
  add    %rbx,%r13
  movslq %r15d,%rbp
  add    %rax,%rbp
  lea    0x12(%rsp),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  movslq 0x8(%rsp),%rbx
  add    %r13,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L40
L57:
  mov    0xc(%rsp),%edx
  mov    (%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strscpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntobr(char textbuff[], int texbufftsize) {
  char replace[] = {"<br>\n"};
  char find[] = {"\n"};
  char *cptr;
  int rlen = strlen(replace);
  int flen = strlen(find);
  char *buff = malloc((texbufftsize * 2));
  char *bptr;
  char *cprtold = textbuff;
  buff[0] = '\0';
  cptr = textbuff;
  bptr = buff;
  strcpy(buff, textbuff);
  while ((cptr = (char *)strstr(cptr, find))) {
    if ((cptr == textbuff) || (cptr[-1] == '>')) {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, find);
      bptr = (bptr + flen);
      strcat(bptr, cptr);
    } else {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, replace);
      bptr = (bptr + rlen);
      strcat(bptr, cptr);
    }
    cprtold = cptr;
  }
  strscpy(textbuff, buff, texbufftsize);
  free(buff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ntobr>:
  endbr64
  push   %r15
  mov    $0xa,%edx
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%edi
  push   %rbx
  movslq %edi,%rdi
  mov    %rbp,%r15
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%eax
  mov    %dx,(%rsp)
  mov    %rsp,%r12
  movl   $0x3e72623c,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rbx
  nopl   (%rax)
L8:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L19
L9:
  mov    %rax,%rdx
  sub    %r15,%rdx
  lea    0x1(%rax),%r15
  add    %rbx,%rdx
  cmp    %rax,%rbp
  je     L3
  cmpb   $0x3e,-0x1(%rax)
  je     L3
  mov    0x2(%rsp),%eax
  lea    0x5(%rdx),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %eax,(%rdx)
  movzbl 0x6(%rsp),%eax
  mov    %al,0x4(%rdx)
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L9
L19:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strscpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L3:
  movzbl (%rsp),%eax
  lea    0x1(%rdx),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %al,(%rdx)
  call   <strcpy@plt>
  jmp    L8
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntobr(char textbuff[], int texbufftsize) {
  char replace[] = {"<br>\n"};
  char find[] = {"\n"};
  char *cptr;
  int rlen = strlen(replace);
  int flen = strlen(find);
  char *buff = malloc((texbufftsize * 2));
  char *bptr;
  char *cprtold = textbuff;
  buff[0] = '\0';
  cptr = textbuff;
  bptr = buff;
  strcpy(buff, textbuff);
  while ((cptr = (char *)strstr(cptr, find))) {
    if ((cptr == textbuff) || (cptr[-1] == '>')) {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, find);
      bptr = (bptr + flen);
      strcat(bptr, cptr);
    } else {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, replace);
      bptr = (bptr + rlen);
      strcat(bptr, cptr);
    }
    cprtold = cptr;
  }
  strscpy(textbuff, buff, texbufftsize);
  free(buff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ntobr>:
  endbr64
  push   %r15
  mov    $0xa,%edx
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%edi
  push   %rbx
  movslq %edi,%rdi
  mov    %rbp,%r15
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%eax
  mov    %dx,(%rsp)
  mov    %rsp,%r12
  movl   $0x3e72623c,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rbx
  nopl   (%rax)
L44:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L52
L56:
  mov    %rax,%rdx
  sub    %r15,%rdx
  lea    0x1(%rax),%r15
  add    %rbx,%rdx
  cmp    %rax,%rbp
  je     L28
  cmpb   $0x3e,-0x1(%rax)
  je     L28
  mov    0x2(%rsp),%eax
  lea    0x5(%rdx),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %eax,(%rdx)
  movzbl 0x6(%rsp),%eax
  mov    %al,0x4(%rdx)
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L56
L52:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strscpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L28:
  movzbl (%rsp),%eax
  lea    0x1(%rdx),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    %al,(%rdx)
  call   <strcpy@plt>
  jmp    L44
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntobr(char textbuff[], int texbufftsize) {
  char replace[] = {"<br>\n"};
  char find[] = {"\n"};
  char *cptr;
  int rlen = strlen(replace);
  int flen = strlen(find);
  char *buff = malloc((texbufftsize * 2));
  char *bptr;
  char *cprtold = textbuff;
  buff[0] = '\0';
  cptr = textbuff;
  bptr = buff;
  strcpy(buff, textbuff);
  while ((cptr = (char *)strstr(cptr, find))) {
    if ((cptr == textbuff) || (cptr[-1] == '>')) {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, find);
      bptr = (bptr + flen);
      strcat(bptr, cptr);
    } else {
      bptr = (bptr + (cptr - cprtold));
      cptr = (cptr + flen);
      strcpy(bptr, replace);
      bptr = (bptr + rlen);
      strcat(bptr, cptr);
    }
    cprtold = cptr;
  }
  strscpy(textbuff, buff, texbufftsize);
  free(buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<round_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L0
  movsd  -0x8(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L19
L0:
  movsd  -0x8(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
L19:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int round_score(double v) {
  if (v >= 0)
    return (int)(v + .5);
  else
    return (int)(v - .5);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<round_score>:
  endbr64
  comisd D17(%rip),%xmm0
  jb     L0
  addsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
L0:
  subsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
data_type: byte[16]
name: unpack_data
arguments: data_label: D26
data_type: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int round_score(double v) {
  if (v >= 0)
    return (int)(v + .5);
  else
    return (int)(v - .5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<round_score>:
  endbr64
  comisd D29(%rip),%xmm0
  jb     L5
  addsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  subsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: byte[8]

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int round_score(double v) {
  if (v >= 0)
    return (int)(v + .5);
  else
    return (int)(v - .5);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<round_score>:
  endbr64
  comisd D11(%rip),%xmm0
  jb     L4
  addsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  subsd  D15(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: byte[16]
name: disassemble_data
arguments: label: D15
datatype: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int round_score(double v) {
  if (v >= 0)
    return (int)(v + .5);
  else
    return (int)(v - .5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_basic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L46
L27:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L46:
  cmpl   $0x1fff,-0xc(%rbp)
  jle    L27
  cmpl   $0x2000,-0x8(%rbp)
  je     L44
  mov    $0x1,%eax
  jmp    L34
L44:
  cmpl   $0x2000,-0x4(%rbp)
  je     L6
  mov    $0x2,%eax
  jmp    L34
L6:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int test_basic() {
  int i;
  int sum_0 = 0;
  int sum_1 = 0;
#pragma acc parallel loop copy(sum_0, sum_1)
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sum_0++;
#pragma acc atomic update
    ++sum_1;
  }
  if (sum_0 != (8192)) {
    return 1;
  }
  if (sum_1 != (8192)) {
    return 2;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_basic>:
  endbr64
  mov    $0x2000,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test_basic() {
  int i;
  int sum_0 = 0;
  int sum_1 = 0;
#pragma acc parallel loop copy(sum_0, sum_1)
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sum_0++;
#pragma acc atomic update
    ++sum_1;
  }
  if (sum_0 != (8192)) {
    return 1;
  }
  if (sum_1 != (8192)) {
    return 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_basic>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_basic() {
  int i;
  int sum_0 = 0;
  int sum_1 = 0;
#pragma acc parallel loop copy(sum_0, sum_1)
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sum_0++;
#pragma acc atomic update
    ++sum_1;
  }
  if (sum_0 != (8192)) {
    return 1;
  }
  if (sum_1 != (8192)) {
    return 2;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_basic>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_basic() {
  int i;
  int sum_0 = 0;
  int sum_1 = 0;
#pragma acc parallel loop copy(sum_0, sum_1)
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sum_0++;
#pragma acc atomic update
    ++sum_1;
  }
  if (sum_0 != (8192)) {
    return 1;
  }
  if (sum_1 != (8192)) {
    return 2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smooth1d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x2,-0x2c(%rbp)
  jle    L17
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L25
L21:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x10(%rbp),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x18(%rbp)
L25:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jl     L21
  movsd  -0x10(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movsd  D18(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  jmp    L32
L17:
  nop
L32:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
data_type: f64
name: extract_symbolic_data
arguments: data_label: D18
data_type: f64

tool: D15: 0.25

tool: D18: 0.75

assistant: ```c
void smooth1d(double *data, int size) {
  long i;
  double oldy;
  double newy;
  if (size < 3) {
    return;
  }
  oldy = data[0];
  for (i = 0; i < (size - 1); i++) {
    newy = 0.25 * (oldy + 2 * data[i] + data[i + 1]);
    oldy = data[i];
    data[i] = newy;
  }
  data[size - 1] = 0.25 * oldy + 0.75 * data[size - 1];
  return;
}
```