ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_usbdm_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffff80,%edi
  cmp    $0x1,%edi
  ja     L33
  mov    %rsi,%rbx
  mov    %edx,%r12d
  test   %edx,%edx
  jle    L23
  mov    %edx,%ebp
  add    %rsi,%rbp
  jmp    L30
L26:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <console_txChar@plt>
  cmp    %rbp,%rbx
  je     L23
L30:
  cmpb   $0xa,(%rbx)
  jne    L26
  mov    $0xd,%edi
  call   <console_txChar@plt>
  jmp    L26
L33:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%r12d
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _usbdm_write(int file, char *ptr, int len) {
  int n;
  switch (file) {
  case STDOUT_FILENO:
  case STDERR_FILENO:
    for (n = 0; n < len; n++) {
      if (*ptr == '\n') {
        console_txChar('\r');
      }
      console_txChar(*ptr++);
    }
    break;
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_usbdm_write>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x1,%edi
  ja     L58
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  add    %rsi,%rbp
  mov    %rsi,%rbx
  test   %edx,%edx
  jg     L47
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
  call   <console_txChar@plt>
  cmp    %rbp,%rbx
  je     L39
L47:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  jne    L19
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <console_txChar@plt>
  movsbl -0x1(%rbx),%edi
  call   <console_txChar@plt>
  cmp    %rbp,%rbx
  jne    L47
L39:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _usbdm_write(int file, char *ptr, int len) {
  int n;
  switch (file) {
  case STDOUT_FILENO:
  case STDERR_FILENO:
    for (n = 0; n < len; n++) {
      if (*ptr == '\n') {
        console_txChar('\r');
      }
      console_txChar(*ptr++);
    }
    break;
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<_usbdm_write>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x1,%edi
  ja     L15
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  add    %rsi,%rbp
  mov    %rsi,%rbx
  test   %edx,%edx
  jle    L43
L46:
  movsbl (%rbx),%edi
  cmp    $0xa,%dil
  je     L1
  add    $0x1,%rbx
  call   <console_txChar@plt>
  cmp    %rbp,%rbx
  jne    L46
L43:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L1:
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <console_txChar@plt>
  movsbl -0x1(%rbx),%edi
  call   <console_txChar@plt>
  cmp    %rbx,%rbp
  jne    L46
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _usbdm_write(int file, char *ptr, int len) {
  int n;
  switch (file) {
  case STDOUT_FILENO:
  case STDERR_FILENO:
    for (n = 0; n < len; n++) {
      if (*ptr == '\n') {
        console_txChar('\r');
      }
      console_txChar(*ptr++);
    }
    break;
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  mov    $0x2d,%edi
  call   <putchar@plt>
  negl   -0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L5
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <printd>
L5:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10) {
    printd(n / 10);
  }
  putchar(n % 10 + '0');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printd>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L0
L22:
  lea    0x9(%rbx),%eax
  cmp    $0x12,%eax
  ja     L17
L29:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <putchar@plt>
  pop    %rbx
  ret
L0:
  mov    $0x2d,%edi
  call   <putchar@plt>
  neg    %ebx
  jmp    L22
L17:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <printd>
  jmp    L29
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10) {
    printd(n / 10);
  }
  putchar(n % 10 + '0');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L54
L18:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L67
L76:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L67:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L12
L16:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  jmp    L76
  nopl   0x0(%rax)
L54:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putchar@plt>
  jmp    L18
  nopl   0x0(%rax)
L12:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L8
L31:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putchar@plt>
  jmp    L16
  nop
L8:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <printd>
  jmp    L31
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10) {
    printd(n / 10);
  }
  putchar(n % 10 + '0');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L74
L36:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L32
L0:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L32:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L20
L10:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  jmp    L0
  nopl   0x0(%rax)
L74:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putchar@plt>
  jmp    L36
  nopl   0x0(%rax)
L20:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L43
L63:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putchar@plt>
  jmp    L10
  nop
L43:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <printd>
  jmp    L63
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10) {
    printd(n / 10);
  }
  putchar(n % 10 + '0');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<draw_holder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%edi
  call   <glCallList@plt>
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  mov    $0x0,%eax
  call   <draw_base@plt>
  movsd  D6(%rip),%xmm0
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  movsd  D29(%rip),%xmm0
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  movsd  D29(%rip),%xmm0
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: f64
name: extract_symbolic_data
arguments: tag: D19
type_infered: f64
name: extract_symbolic_data
arguments: tag: D29
type_infered: f64

tool: D6: 20

tool: D19: 0

tool: D29: 5

assistant: ```c
void draw_holder(void) {
  glCallList(8);
  glPushMatrix();
  draw_base();
  glTranslatef(0.0, 0.0, 20.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glPopMatrix();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw_holder>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <glCallList@plt>
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  mov    $0x0,%eax
  call   <draw_base@plt>
  movsd  D23(%rip),%xmm2
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  mov    D16(%rip),%rax
  movq   %rax,%xmm2
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  mov    D16(%rip),%rax
  movq   %rax,%xmm2
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  call   <glTranslatef@plt>
  mov    $0x0,%eax
  call   <draw_torus@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type: f64
name: disassemble_data
arguments: data_tag: D16
type: f64

tool: D23: 20

tool: D16: 5

assistant: ```c
void draw_holder(void) {
  glCallList(8);
  glPushMatrix();
  draw_base();
  glTranslatef(0.0, 0.0, 20.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glPopMatrix();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<draw_holder>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <glCallList@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  xor    %eax,%eax
  call   <draw_base@plt>
  pxor   %xmm1,%xmm1
  movsd  D5(%rip),%xmm2
  movapd %xmm1,%xmm0
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  pxor   %xmm0,%xmm0
  movsd  D14(%rip),%xmm2
  movapd %xmm0,%xmm1
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  mov    D14(%rip),%rax
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm2
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: f64

tool: D5: 20

tool: D14: 5

assistant: ```c
void draw_holder(void) {
  glCallList(8);
  glPushMatrix();
  draw_base();
  glTranslatef(0.0, 0.0, 20.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glPopMatrix();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<draw_holder>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <glCallList@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  xor    %eax,%eax
  call   <draw_base@plt>
  pxor   %xmm1,%xmm1
  movsd  D3(%rip),%xmm2
  movapd %xmm1,%xmm0
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  pxor   %xmm0,%xmm0
  movsd  D13(%rip),%xmm2
  movapd %xmm0,%xmm1
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  mov    D13(%rip),%rax
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm2
  call   <glTranslatef@plt>
  xor    %eax,%eax
  call   <draw_torus@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: f64
name: disassemble_data
arguments: data_tag: D13
data_type: f64

tool: D3: 20

tool: D13: 5

assistant: ```c
void draw_holder(void) {
  glCallList(8);
  glPushMatrix();
  draw_base();
  glTranslatef(0.0, 0.0, 20.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glTranslatef(0.0, 0.0, 5.000000);
  draw_torus();
  glPopMatrix();
}
```
user: Translate the below assembly code into C programming language:

```asm
<__gstrpart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L18:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L18
L10:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L10
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L21
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gstrswp@plt>
  jmp    L18
L21:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __gstrpart(char **array, int first, int last) {
  char *medium = array[first];
  int i = first - 1;
  int j = last + 1;
  while (1) {
    do {
      j--;
    } while (strcmp(array[j], medium) > 0);
    do {
      i++;
    } while (strcmp(array[i], medium) < 0);
    if (i < j)
      gstrswp(&array[i], &array[j]);
    else
      return j;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__gstrpart>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  movslq %esi,%rax
  mov    (%rdi,%rax,8),%r13
  lea    -0x1(%rsi),%ebp
  movslq %edx,%r12
  jmp    L24
L38:
  sub    $0x1,%r12
L24:
  mov    %r12d,0xc(%rsp)
  lea    (%r14,%r12,8),%r15
  mov    (%r14,%r12,8),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L38
  movslq %ebp,%rax
  lea    0x8(%r14,%rax,8),%rbx
L18:
  add    $0x1,%ebp
  mov    %rbx,(%rsp)
  mov    %r13,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  add    $0x8,%rbx
  test   %rax,%rax
  js     L18
  cmp    %r12d,%ebp
  jge    L5
  mov    %r15,%rsi
  mov    (%rsp),%rdi
  call   <gstrswp@plt>
  jmp    L38
L5:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __gstrpart(char **array, int first, int last) {
  char *medium = array[first];
  int i = first - 1;
  int j = last + 1;
  while (1) {
    do {
      j--;
    } while (strcmp(array[j], medium) > 0);
    do {
      i++;
    } while (strcmp(array[i], medium) < 0);
    if (i < j)
      gstrswp(&array[i], &array[j]);
    else
      return j;
  };
}
```
user: What is the c source code of the assembly code below?

```asm
<__gstrpart>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x18,%rsp
  mov    (%rdi,%rax,8),%r12
  jmp    L39
  nopl   0x0(%rax)
L3:
  sub    $0x1,%rbp
L39:
  mov    (%r14,%rbp,8),%rdi
  lea    (%r14,%rbp,8),%rax
  mov    %r12,%rsi
  mov    %ebp,0xc(%rsp)
  mov    %rax,(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L3
  movslq %ebx,%rax
  lea    0x8(%r14,%rax,8),%r15
  nopl   0x0(%rax)
L15:
  mov    (%r15),%rdi
  mov    %r12,%rsi
  mov    %r15,%r13
  add    $0x1,%ebx
  add    $0x8,%r15
  call   <strcmp@plt>
  test   %rax,%rax
  js     L15
  cmp    %ebp,%ebx
  jge    L13
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <gstrswp@plt>
  jmp    L3
  nopl   0x0(%rax)
L13:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __gstrpart(char **array, int first, int last) {
  char *medium = array[first];
  int i = first - 1;
  int j = last + 1;
  while (1) {
    do {
      j--;
    } while (strcmp(array[j], medium) > 0);
    do {
      i++;
    } while (strcmp(array[i], medium) < 0);
    if (i < j)
      gstrswp(&array[i], &array[j]);
    else
      return j;
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<__gstrpart>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x18,%rsp
  mov    (%rdi,%rax,8),%r12
  jmp    L19
  nopl   0x0(%rax)
L38:
  sub    $0x1,%rbp
L19:
  mov    (%r14,%rbp,8),%rdi
  lea    (%r14,%rbp,8),%rax
  mov    %r12,%rsi
  mov    %ebp,0xc(%rsp)
  mov    %rax,(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  jg     L38
  movslq %ebx,%rax
  lea    0x8(%r14,%rax,8),%r15
  nopl   0x0(%rax)
L21:
  mov    (%r15),%rdi
  mov    %r12,%rsi
  mov    %r15,%r13
  add    $0x1,%ebx
  add    $0x8,%r15
  call   <strcmp@plt>
  test   %rax,%rax
  js     L21
  cmp    %ebp,%ebx
  jge    L30
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <gstrswp@plt>
  jmp    L38
  nopl   0x0(%rax)
L30:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __gstrpart(char **array, int first, int last) {
  char *medium = array[first];
  int i = first - 1;
  int j = last + 1;
  while (1) {
    do {
      j--;
    } while (strcmp(array[j], medium) > 0);
    do {
      i++;
    } while (strcmp(array[i], medium) < 0);
    if (i < j)
      gstrswp(&array[i], &array[j]);
    else
      return j;
  };
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fat32_wr_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L19:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  shrl   $0x8,-0x1c(%rbp)
L0:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fat32_wr_n(void *p, unsigned v, unsigned n) {
  uint8_t *b = p;
  while (n-- > 0) {
    *b++ = v;
    v >>= 8;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fat32_wr_n>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L18
  mov    %eax,%eax
  lea    0x4(%rdi,%rax,4),%rax
L16:
  add    $0x4,%rdi
  mov    %esi,-0x4(%rdi)
  shr    $0x8,%esi
  cmp    %rax,%rdi
  jne    L16
L18:
  ret
```

assistant: ```c
void fat32_wr_n(void *p, unsigned v, unsigned n) {
  uint8_t *b = p;
  while (n-- > 0) {
    *b++ = v;
    v >>= 8;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fat32_wr_n>:
  endbr64
  test   %edx,%edx
  je     L13
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rax
  xchg   %ax,%ax
L17:
  add    $0x4,%rdi
  mov    %esi,-0x4(%rdi)
  shr    $0x8,%esi
  cmp    %rax,%rdi
  jne    L17
L13:
  ret
```

assistant: ```c
void fat32_wr_n(void *p, unsigned v, unsigned n) {
  uint8_t *b = p;
  while (n-- > 0) {
    *b++ = v;
    v >>= 8;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fat32_wr_n>:
  endbr64
  test   %edx,%edx
  je     L13
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rax
  xchg   %ax,%ax
L6:
  add    $0x4,%rdi
  mov    %esi,-0x4(%rdi)
  shr    $0x8,%esi
  cmp    %rax,%rdi
  jne    L6
L13:
  ret
```

assistant: ```c
void fat32_wr_n(void *p, unsigned v, unsigned n) {
  uint8_t *b = p;
  while (n-- > 0) {
    *b++ = v;
    v >>= 8;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L20:
  mov    $0x0,%eax
  call   <print_cpu_time@plt>
  movl   $0x1000000,-0x4(%rbp)
  jmp    L23
L16:
  subl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x0,-0x4(%rbp)
  jg     L16
  jmp    L20
```

assistant: ```c
int main() {
  while (1) {
    print_cpu_time();
    for (int i = 0x1000000; i > 0; i--)
      ;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L2:
  mov    $0x0,%eax
  call   <print_cpu_time@plt>
  mov    $0x1000000,%eax
L17:
  sub    $0x1,%eax
  jne    L17
  jmp    L2
```

assistant: ```c
int main() {
  while (1) {
    print_cpu_time();
    for (int i = 0x1000000; i > 0; i--)
      ;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <print_cpu_time@plt>
  mov    $0x1000000,%eax
  nopl   0x0(%rax)
L12:
  sub    $0x1,%eax
  jne    L12
  jmp    L9
```

assistant: ```c
int main() {
  while (1) {
    print_cpu_time();
    for (int i = 0x1000000; i > 0; i--)
      ;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <print_cpu_time@plt>
  mov    $0x1000000,%eax
  nopl   0x0(%rax)
L16:
  sub    $0x1,%eax
  jne    L16
  jmp    L10
```

assistant: ```c
int main() {
  while (1) {
    print_cpu_time();
    for (int i = 0x1000000; i > 0; i--)
      ;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GenReadLocal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0xd,-0x4(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L11
  movl   $0x9,-0x4(%rbp)
  jmp    L58
L11:
  cmpl   $0x1,-0x18(%rbp)
  jne    L16
  movl   $0xa,-0x4(%rbp)
  jmp    L58
L16:
  cmpl   $0xfffffffe,-0x18(%rbp)
  jne    L14
  movl   $0xb,-0x4(%rbp)
  jmp    L58
L14:
  cmpl   $0x2,-0x18(%rbp)
  jne    L58
  movl   $0xc,-0x4(%rbp)
L58:
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%r9d
  mov    $0x3e,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <GenPrintInstr2Operands@plt>
  nop
  leave
  ret
```

assistant: ```c
void GenReadLocal(int regDst, int opSz, int ofs) {
  int instr = 0x0D;
  if (opSz == -1) {
    instr = 0x09;
  } else if (opSz == 1) {
    instr = 0x0A;
  } else if (opSz == -2) {
    instr = 0x0B;
  } else if (opSz == 2) {
    instr = 0x0C;
  }
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x3E, ofs);
}
```