ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L121
L58:
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <infoCard@plt>
  cltq
  mov    %rax,-0xa0(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <infoCard@plt>
  cltq
  mov    %rax,-0x98(%rbp)
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x6,%eax
  jne    L20
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L20:
  mov    -0x98(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x6,%eax
  jne    L15
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L15:
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x98(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L113
  mov    -0xa0(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x98(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L25
  lea    -0x90(%rbp),%rax
  jmp    L19
L25:
  lea    -0x50(%rbp),%rax
L19:
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L113:
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  jne    L80
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L80:
  mov    -0x98(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  jne    L34
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L34:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L64:
  mov    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L121:
  lea    -0x50(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  jne    L58
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D16: ERROR

tool: D5: %[^-]-%[^
]


assistant: ```c
int main(int argc, char const *argv[]) {
  char a[64], b[64];
  while (~scanf("%[^-]-%[^\n]\n", a, b)) {
    int *ai = infoCard(a), *bi = infoCard(b);
    if (ai[0] == 6)
      printf("%s\n", a);
    else if (bi[0] == 6)
      printf("%s\n", b);
    else if (ai[0] == bi[0])
      printf("%s\n", ai[1] > bi[1] ? a : b);
    else if (ai[0] == 4)
      printf("%s\n", a);
    else if (bi[0] == 4)
      printf("%s\n", b);
    else
      printf("ERROR\n");
    free(ai);
    free(bi);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%r13
  mov    %rsp,%r12
  lea    D4(%rip),%r14
  lea    D12(%rip),%r15
  jmp    L11
L77:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L83
L56:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L83
L73:
  mov    %r12,%rdi
  mov    0x4(%rbp),%eax
  cmp    %eax,0x4(%rbx)
  cmovle %r13,%rdi
  call   <puts@plt>
L83:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L11:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L105
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <infoCard@plt>
  movslq %eax,%rbx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <infoCard@plt>
  movslq %eax,%rbp
  mov    (%rbx),%eax
  cmp    $0x6,%eax
  je     L77
  mov    0x0(%rbp),%edx
  cmp    $0x6,%edx
  je     L56
  cmp    %edx,%eax
  je     L73
  cmp    $0x4,%eax
  je     L75
  cmp    $0x4,%edx
  je     L44
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L83
L75:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L83
L44:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L83
L105:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string

tool: D4: %[^-]-%[^
]


tool: D12: ERROR

assistant: ```c
int main(int argc, char const *argv[]) {
  char a[64], b[64];
  while (~scanf("%[^-]-%[^\n]\n", a, b)) {
    int *ai = infoCard(a), *bi = infoCard(b);
    if (ai[0] == 6)
      printf("%s\n", a);
    else if (bi[0] == 6)
      printf("%s\n", b);
    else if (ai[0] == bi[0])
      printf("%s\n", ai[1] > bi[1] ? a : b);
    else if (ai[0] == 4)
      printf("%s\n", a);
    else if (bi[0] == 4)
      printf("%s\n", b);
    else
      printf("ERROR\n");
    free(ai);
    free(bi);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D15(%rip),%r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%r13
  jmp    L76
L78:
  cmp    $0x4,%eax
  je     L81
  cmp    $0x4,%edx
  je     L39
  mov    %r15,%rdi
  call   <puts@plt>
L28:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
L76:
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L77
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <infoCard@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <infoCard@plt>
  movslq %eax,%r12
  mov    0x0(%rbp),%eax
  cmp    $0x6,%eax
  je     L81
  mov    (%r12),%edx
  cmp    $0x6,%edx
  je     L39
  cmp    %edx,%eax
  jne    L78
  mov    0x4(%r12),%eax
  mov    %r13,%rdi
  cmp    %eax,0x4(%rbp)
  cmovg  %rbx,%rdi
  call   <puts@plt>
  jmp    L28
L81:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L28
  nopl   (%rax)
L77:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D6
type: string

tool: D15: ERROR

tool: D6: %[^-]-%[^
]


assistant: ```c
int main(int argc, char const *argv[]) {
  char a[64], b[64];
  while (~scanf("%[^-]-%[^\n]\n", a, b)) {
    int *ai = infoCard(a), *bi = infoCard(b);
    if (ai[0] == 6)
      printf("%s\n", a);
    else if (bi[0] == 6)
      printf("%s\n", b);
    else if (ai[0] == bi[0])
      printf("%s\n", ai[1] > bi[1] ? a : b);
    else if (ai[0] == 4)
      printf("%s\n", a);
    else if (bi[0] == 4)
      printf("%s\n", b);
    else
      printf("ERROR\n");
    free(ai);
    free(bi);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%r15
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%r13
  jmp    L104
L32:
  cmp    $0x4,%eax
  je     L59
  cmp    $0x4,%edx
  je     L46
  mov    %r15,%rdi
  call   <puts@plt>
L15:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
L104:
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <infoCard@plt>
  mov    %r13,%rdi
  movslq %eax,%rbp
  xor    %eax,%eax
  call   <infoCard@plt>
  movslq %eax,%r12
  mov    0x0(%rbp),%eax
  cmp    $0x6,%eax
  je     L59
  mov    (%r12),%edx
  cmp    $0x6,%edx
  je     L46
  cmp    %edx,%eax
  jne    L32
  mov    0x4(%r12),%eax
  mov    %r13,%rdi
  cmp    %eax,0x4(%rbp)
  cmovg  %rbx,%rdi
  call   <puts@plt>
  jmp    L15
L59:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L15
  nopl   (%rax)
L27:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D14: ERROR

tool: D9: %[^-]-%[^
]


assistant: ```c
int main(int argc, char const *argv[]) {
  char a[64], b[64];
  while (~scanf("%[^-]-%[^\n]\n", a, b)) {
    int *ai = infoCard(a), *bi = infoCard(b);
    if (ai[0] == 6)
      printf("%s\n", a);
    else if (bi[0] == 6)
      printf("%s\n", b);
    else if (ai[0] == bi[0])
      printf("%s\n", ai[1] > bi[1] ? a : b);
    else if (ai[0] == 4)
      printf("%s\n", a);
    else if (bi[0] == 4)
      printf("%s\n", b);
    else
      printf("ERROR\n");
    free(ai);
    free(bi);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<token_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L5:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L5
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *token_data(char **tok_arr) {
  int i = 0;
  while (tok_arr[i])
    ++i;
  return tok_arr[i + 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<token_data>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L4
  mov    $0x1,%eax
L1:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L1
L12:
  mov    0x8(%rdi,%rdx,8),%rax
  ret
L4:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
char *token_data(char **tok_arr) {
  int i = 0;
  while (tok_arr[i])
    ++i;
  return tok_arr[i + 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<token_data>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L12
  mov    $0x1,%eax
  nop
L17:
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L17
  shl    $0x3,%rax
  mov    (%rdi,%rax,1),%rax
  ret
  nopl   (%rax)
L12:
  mov    $0x8,%eax
  mov    (%rdi,%rax,1),%rax
  ret
```

assistant: ```c
char *token_data(char **tok_arr) {
  int i = 0;
  while (tok_arr[i])
    ++i;
  return tok_arr[i + 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<token_data>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  nop
L10:
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L10
  shl    $0x3,%rax
  mov    (%rdi,%rax,1),%rax
  ret
  nopl   (%rax)
L1:
  mov    $0x8,%eax
  mov    (%rdi,%rax,1),%rax
  ret
```

assistant: ```c
char *token_data(char **tok_arr) {
  int i = 0;
  while (tok_arr[i])
    ++i;
  return tok_arr[i + 1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D1: Usage: 7zip input-file output-file kernel/loader big/little


tool: D7:            -k(K): self-decompress in kernel


tool: D6:            -l(L): decompress in loader


assistant: ```c
void print_usage(void) {
  printf("Usage: 7zip input-file output-file kernel/loader big/little\n");
  printf("           -k(K): self-decompress in kernel\n");
  printf("           -l(L): decompress in loader\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D27
type: string

tool: D0: Usage: 7zip input-file output-file kernel/loader big/little


tool: D29:            -k(K): self-decompress in kernel


tool: D27:            -l(L): decompress in loader


assistant: ```c
void print_usage(void) {
  printf("Usage: 7zip input-file output-file kernel/loader big/little\n");
  printf("           -k(K): self-decompress in kernel\n");
  printf("           -l(L): decompress in loader\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string

tool: D6: Usage: 7zip input-file output-file kernel/loader big/little


tool: D18:            -k(K): self-decompress in kernel


tool: D12:            -l(L): decompress in loader


assistant: ```c
void print_usage(void) {
  printf("Usage: 7zip input-file output-file kernel/loader big/little\n");
  printf("           -k(K): self-decompress in kernel\n");
  printf("           -l(L): decompress in loader\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D26
type: string

tool: D7: Usage: 7zip input-file output-file kernel/loader big/little


tool: D4:            -k(K): self-decompress in kernel


tool: D26:            -l(L): decompress in loader


assistant: ```c
void print_usage(void) {
  printf("Usage: 7zip input-file output-file kernel/loader big/little\n");
  printf("           -k(K): self-decompress in kernel\n");
  printf("           -l(L): decompress in loader\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x1,-0x14(%rbp)
  jg     L6
  mov    $0x1,%eax
  jmp    L0
L6:
  cmpb   $0x14,-0x14(%rbp)
  jle    L14
  mov    $0x0,%eax
  jmp    L0
L14:
  movsbq -0x14(%rbp),%rbx
  movzbl -0x14(%rbp),%eax
  sub    $0x2,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   %rbx,%rax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long factorial(char n) {
  if (n <= 1) {
    return 1;
  } else if (n > 20) {
    return 0;
  }
  return n * factorial(n - 2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%dil
  jle    L16
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  cmp    $0x14,%dil
  jle    L27
L10:
  pop    %rbx
  ret
L27:
  lea    -0x2(%rdi),%edi
  movsbl %dil,%edi
  call   <factorial>
  mov    %rax,%rdx
  movsbq %bl,%rax
  imul   %rdx,%rax
  jmp    L10
L16:
  ret
```

assistant: ```c
unsigned long factorial(char n) {
  if (n <= 1) {
    return 1;
  } else if (n > 20) {
    return 0;
  }
  return n * factorial(n - 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factorial>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%dil
  jle    L10
  xor    %r12d,%r12d
  cmp    $0x14,%dil
  jle    L31
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L31:
  lea    -0x2(%rdi),%eax
  movsbq %dil,%r12
  cmp    $0x1,%al
  jbe    L10
  lea    -0x4(%rdi),%ebp
  movzbl %al,%ebx
  cmp    $0x1,%bpl
  jbe    L39
  sub    $0x6,%edi
  movzbl %bpl,%ebp
  movzbl %dil,%edi
  call   <factorial>
  mov    %rax,%r8
  mov    %rbp,%rax
  imul   %rbx,%rax
  imul   %r8,%rax
  mov    %rax,%rbx
L39:
  imul   %rbx,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long factorial(char n) {
  if (n <= 1) {
    return 1;
  } else if (n > 20) {
    return 0;
  }
  return n * factorial(n - 2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factorial>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%dil
  jle    L35
  xor    %r12d,%r12d
  cmp    $0x14,%dil
  jle    L9
L35:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  lea    -0x2(%rdi),%eax
  movsbq %dil,%r12
  cmp    $0x1,%al
  jbe    L35
  lea    -0x4(%rdi),%ebp
  movzbl %al,%ebx
  cmp    $0x1,%bpl
  jbe    L29
  sub    $0x6,%edi
  movzbl %bpl,%ebp
  movzbl %dil,%edi
  call   <factorial>
  mov    %rax,%r8
  mov    %rbp,%rax
  imul   %rbx,%rax
  imul   %r8,%rax
  mov    %rax,%rbx
L29:
  imul   %rbx,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long factorial(char n) {
  if (n <= 1) {
    return 1;
  } else if (n > 20) {
    return 0;
  }
  return n * factorial(n - 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmdline_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0x4(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r15d
  mov    %ecx,%r14d
  cmp    $0xffffffff,%edx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r15d,%ebx
  je     L29
  mov    $0x0,%ebp
  jmp    L61
L25:
  cmp    $0x1,%r12d
  sbb    $0xffffffff,%ebp
  test   %ebx,%ebx
  je     L43
  lea    -0x1(%rbx),%edx
  cmpb   $0x27,(%rax,%rdx,1)
  je     L14
L43:
  add    $0x3,%ebp
  mov    $0x0,%r12d
  jmp    L99
L14:
  add    $0x1,%ebp
  mov    $0x0,%r12d
  jmp    L99
L20:
  add    $0x2,%ebp
  mov    $0x1,%r12d
L99:
  add    $0x1,%ebx
L85:
  mov    0x0(%r13),%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L81
  mov    0x0(%r13),%rax
  mov    %ebx,%edx
  cmpb   $0x27,(%rax,%rdx,1)
  je     L25
  test   %r12d,%r12d
  jne    L54
  test   %r14d,%r14d
  jne    L20
L54:
  add    $0x1,%ebp
  test   %r14d,%r14d
  mov    $0x1,%eax
  cmovne %eax,%r12d
  jmp    L99
L81:
  cmp    $0x1,%r12d
  sbb    $0xffffffff,%ebp
  mov    0x0(%r13),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    0x2(%rbp),%eax
  test   %edx,%edx
  cmove  %eax,%ebp
  add    $0x1,%ebp
  add    $0x1,%r15d
  cmp    0x4(%rsp),%r15d
  je     L109
L61:
  mov    %r15d,%eax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,8),%r13
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L85
L29:
  mov    $0x0,%ebp
L109:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cmdline_length(int argc, char **argv, int index, bool want_extra_quotes) {
  assert(index != -1);
  unsigned i, j;
  int len = 0;
  unsigned argcnt = argc - index;
  bool in_quotes = false;
  for (i = 0; i < argcnt; i++) {
    in_quotes = false;
    for (j = 0; j < strlen(argv[i + index]); j++) {
      if (argv[i + index][j] == '\'') {
        if (in_quotes)
          len++;
        if (j > 0 && argv[i + index][j - 1] == '\'')
          len++;
        else
          len += 3;
        in_quotes = false;
      } else {
        if (!in_quotes && want_extra_quotes)
          len++;
        len++;
        if (want_extra_quotes)
          in_quotes = true;
      }
    }
    if (in_quotes) {
      len++;
    }
    if (strlen(argv[i + index]) == 0) {
      len += 2;
    }
    len++;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmdline_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  xor    %edi,%edi
  cmp    $0xffffffff,%edx
  setne  %dil
  mov    %rsi,0x8(%rsp)
  xor    %r14d,%r14d
  call   <assert@plt>
  cmp    %r12d,%ebx
  je     L0
  nopl   0x0(%rax)
L21:
  mov    0x8(%rsp),%rdx
  mov    %r12d,%eax
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  lea    (%rdx,%rax,8),%rbx
  mov    (%rbx),%rdi
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L39:
  lea    0x1(%r14),%eax
  test   $0x1,%r13b
  jne    L2
  test   %ebp,%ebp
  je     L2
  add    $0x2,%r14d
  mov    $0x1,%r13d
L22:
  add    $0x1,%r15d
L54:
  call   <strlen@plt>
  cmp    %r15d,%eax
  jbe    L35
  mov    (%rbx),%rdi
  mov    %r15d,%eax
  cmpb   $0x27,(%rdi,%rax,1)
  jne    L39
  cmp    $0x1,%r13d
  sbb    $0xffffffff,%r14d
  test   %r15d,%r15d
  je     L36
  lea    -0x1(%r15),%eax
  cmpb   $0x27,(%rdi,%rax,1)
  je     L98
L36:
  add    $0x3,%r14d
  xor    %r13d,%r13d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %eax,%r14d
  test   %ebp,%ebp
  mov    $0x1,%eax
  cmovne %eax,%r13d
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L35:
  mov    (%rbx),%rdi
  cmp    $0x1,%r13d
  sbb    $0xffffffff,%r14d
  call   <strlen@plt>
  mov    %eax,%r9d
  lea    0x2(%r14),%eax
  test   %r9d,%r9d
  cmove  %eax,%r14d
  add    $0x1,%r12d
  add    $0x1,%r14d
  cmp    %r12d,0x4(%rsp)
  jne    L21
L0:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L98:
  add    $0x1,%r14d
  xor    %r13d,%r13d
  jmp    L22
```

assistant: ```c
int cmdline_length(int argc, char **argv, int index, bool want_extra_quotes) {
  assert(index != -1);
  unsigned i, j;
  int len = 0;
  unsigned argcnt = argc - index;
  bool in_quotes = false;
  for (i = 0; i < argcnt; i++) {
    in_quotes = false;
    for (j = 0; j < strlen(argv[i + index]); j++) {
      if (argv[i + index][j] == '\'') {
        if (in_quotes)
          len++;
        if (j > 0 && argv[i + index][j - 1] == '\'')
          len++;
        else
          len += 3;
        in_quotes = false;
      } else {
        if (!in_quotes && want_extra_quotes)
          len++;
        len++;
        if (want_extra_quotes)
          in_quotes = true;
      }
    }
    if (in_quotes) {
      len++;
    }
    if (strlen(argv[i + index]) == 0) {
      len += 2;
    }
    len++;
  }
  return len;
}
```