ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  movb   $0x0,0x5(%rsp)
  call   <strlen@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: byte[16]
name: read_data
arguments: data_label: D9
type_infered: string

tool: {"D10": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x00,0x00,0x00,0x00,0x00]}

tool: D9: %d


assistant: ```c
main() {
  char s1[20] = "hello world";
  s1[5] = '\0';
  printf("%d\n", strlen(s1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_hash1_case_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    $0x0,%r12d
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L6
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  or     $0x20202020,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shr    $0x3,%eax
  xor    %ebx,%eax
  add    %eax,%r12d
  addq   $0x4,-0x18(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L36
  mov    $0x0,%ebx
  jmp    L20
L34:
  shl    $0x8,%ebx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  movsbl %al,%eax
  add    %eax,%ebx
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L34
  mov    %ebx,%eax
  shr    $0x3,%eax
  xor    %ebx,%eax
  add    %eax,%r12d
  mov    %r12d,%eax
  shr    $0xb,%eax
  lea    (%r12,%rax,1),%edx
  mov    %r12d,%ecx
  shr    $0xd,%ecx
  mov    %r12d,%eax
  shr    $0x17,%eax
  add    %ecx,%eax
  add    %edx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_hash1_case_raw(const char *s, int len) {
  const char *p;
  register unsigned v;
  register unsigned h;
  h = 0;
  do {
    for ((p) = (s); (p) <= ((s + len) - 4); (p) += 4) {
      (v) = ((*(p) << 24) + ((p)[1] << 16) + ((p)[2] << 8) + (p)[3]) | 0x20202020;
      (h) += (v) ^ ((v) >> 3);
    }
    (v) = 0;
    for (; (p) < (s + len); (p)++) {
      (v) <<= 8;
      (v) += *(p) | 0x20;
    }
    (h) += (v) ^ ((v) >> 3);
  } while (0);
  return (((h) + ((h) >> 11)) + (((h) >> 13) + ((h) >> 23)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_hash1_case_raw>:
  endbr64
  movslq %esi,%r9
  lea    -0x4(%r9),%r10
  mov    %rdi,%r8
  add    %r10,%r8
  jb     L56
  mov    %rdi,%rdx
  mov    $0x0,%esi
L55:
  movsbl (%rdx),%eax
  shl    $0x18,%eax
  movsbl 0x1(%rdx),%ecx
  shl    $0x10,%ecx
  add    %ecx,%eax
  movsbl 0x2(%rdx),%ecx
  shl    $0x8,%ecx
  add    %ecx,%eax
  movsbl 0x3(%rdx),%ecx
  add    %ecx,%eax
  or     $0x20202020,%eax
  mov    %eax,%ecx
  shr    $0x3,%ecx
  xor    %ecx,%eax
  add    %eax,%esi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jbe    L55
  shr    $0x2,%r10
  lea    0x4(%rdi,%r10,4),%rcx
L18:
  add    %r9,%rdi
  cmp    %rcx,%rdi
  jbe    L35
  mov    $0x0,%eax
L24:
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl (%rcx),%eax
  or     $0x20,%eax
  movsbl %al,%eax
  add    %edx,%eax
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L24
L27:
  mov    %eax,%edx
  shr    $0x3,%edx
  xor    %eax,%edx
  add    %esi,%edx
  mov    %edx,%eax
  shr    $0xb,%eax
  mov    %edx,%ecx
  shr    $0xd,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  shr    $0x17,%edx
  add    %edx,%eax
  ret
L56:
  mov    %rdi,%rcx
  mov    $0x0,%esi
  jmp    L18
L35:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
unsigned int get_hash1_case_raw(const char *s, int len) {
  const char *p;
  register unsigned v;
  register unsigned h;
  h = 0;
  do {
    for ((p) = (s); (p) <= ((s + len) - 4); (p) += 4) {
      (v) = ((*(p) << 24) + ((p)[1] << 16) + ((p)[2] << 8) + (p)[3]) | 0x20202020;
      (h) += (v) ^ ((v) >> 3);
    }
    (v) = 0;
    for (; (p) < (s + len); (p)++) {
      (v) <<= 8;
      (v) += *(p) | 0x20;
    }
    (h) += (v) ^ ((v) >> 3);
  } while (0);
  return (((h) + ((h) >> 11)) + (((h) >> 13) + ((h) >> 23)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_hash1_case_raw>:
  endbr64
  movslq %esi,%r9
  mov    %rdi,%r8
  lea    -0x4(%r9),%r10
  add    %r10,%r8
  jb     L2
  mov    %rdi,%rdx
  xor    %esi,%esi
  nopl   0x0(%rax)
L32:
  movsbl (%rdx),%eax
  movsbl 0x1(%rdx),%ecx
  add    $0x4,%rdx
  shl    $0x10,%ecx
  shl    $0x18,%eax
  add    %ecx,%eax
  movsbl -0x2(%rdx),%ecx
  shl    $0x8,%ecx
  add    %ecx,%eax
  movsbl -0x1(%rdx),%ecx
  add    %ecx,%eax
  or     $0x20202020,%eax
  mov    %eax,%ecx
  shr    $0x3,%ecx
  xor    %ecx,%eax
  add    %eax,%esi
  cmp    %r8,%rdx
  jbe    L32
  shr    $0x2,%r10
  lea    0x4(%rdi,%r10,4),%rcx
L27:
  add    %r9,%rdi
  cmp    %rcx,%rdi
  jbe    L1
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L14:
  shl    $0x8,%eax
  add    $0x1,%rcx
  mov    %eax,%edx
  movzbl -0x1(%rcx),%eax
  or     $0x20,%eax
  movsbl %al,%eax
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L14
  mov    %eax,%edx
  shr    $0x3,%edx
  xor    %edx,%eax
  add    %eax,%esi
L1:
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0xb,%eax
  shr    $0xd,%edx
  add    %edx,%eax
  add    %esi,%eax
  shr    $0x17,%esi
  add    %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rcx
  xor    %esi,%esi
  jmp    L27
```

assistant: ```c
unsigned int get_hash1_case_raw(const char *s, int len) {
  const char *p;
  register unsigned v;
  register unsigned h;
  h = 0;
  do {
    for ((p) = (s); (p) <= ((s + len) - 4); (p) += 4) {
      (v) = ((*(p) << 24) + ((p)[1] << 16) + ((p)[2] << 8) + (p)[3]) | 0x20202020;
      (h) += (v) ^ ((v) >> 3);
    }
    (v) = 0;
    for (; (p) < (s + len); (p)++) {
      (v) <<= 8;
      (v) += *(p) | 0x20;
    }
    (h) += (v) ^ ((v) >> 3);
  } while (0);
  return (((h) + ((h) >> 11)) + (((h) >> 13) + ((h) >> 23)));
}
```
user: What is the c source code of the assembly code below?

```asm
<m68k_op_pea_32_pcdi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <m68ki_get_ea_pcdi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <m68ki_push_32@plt>
  nop
  leave
  ret
```

assistant: ```c
void m68k_op_pea_32_pcdi(void) {
  unsigned int ea = m68ki_get_ea_pcdi();
  m68ki_push_32(ea);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m68k_op_pea_32_pcdi>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m68ki_get_ea_pcdi@plt>
  mov    %eax,%edi
  call   <m68ki_push_32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m68k_op_pea_32_pcdi(void) {
  unsigned int ea = m68ki_get_ea_pcdi();
  m68ki_push_32(ea);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<m68k_op_pea_32_pcdi>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m68ki_get_ea_pcdi@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <m68ki_push_32@plt>
```

assistant: ```c
void m68k_op_pea_32_pcdi(void) {
  unsigned int ea = m68ki_get_ea_pcdi();
  m68ki_push_32(ea);
}
```
user: What is the c source code of the assembly code below:

```asm
<m68k_op_pea_32_pcdi>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <m68ki_get_ea_pcdi@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <m68ki_push_32@plt>
```

assistant: ```c
void m68k_op_pea_32_pcdi(void) {
  unsigned int ea = m68ki_get_ea_pcdi();
  m68ki_push_32(ea);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jogar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  jmp    L4
L65:
  mov    $0x0,%eax
  call   <aleatorio@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L19
  mov    -0x20(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  jmp    L22
L19:
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  cmpl   $0x0,-0x14(%rbp)
  jle    L32
  cmpl   $0x0,-0x18(%rbp)
  jg     L65
L32:
  cmpl   $0x0,-0x14(%rbp)
  jg     L61
  movl   $0x2,-0x8(%rbp)
  jmp    L11
L61:
  movl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: Dado %d EV1 %d EV2 %d


assistant: ```c
int jogar(int ev1, int ev2, int at, int d) {
  int dado, ganhador;
  while (ev1 > 0 && ev2 > 0) {
    dado = aleatorio();
    if (dado <= at) {
      ev1 += d;
      ev2 -= d;
    } else {
      ev1 -= d;
      ev2 += d;
    }
    printf("Dado %d EV1 %d EV2 %d\n", dado, ev1, ev2);
  }
  if (ev1 <= 0) {
    ganhador = 2;
  } else {
    ganhador = 1;
  }
  return ganhador;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jogar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L35
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%r12d
  test   %esi,%esi
  jle    L35
  lea    D1(%rip),%r14
  jmp    L47
L29:
  sub    %r12d,%ebx
  add    %r12d,%ebp
L21:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r14,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L35
  test   %ebp,%ebp
  jle    L35
L47:
  mov    $0x0,%eax
  call   <aleatorio@plt>
  mov    %eax,%esi
  cmp    %r13d,%eax
  jg     L29
  add    %r12d,%ebx
  sub    %r12d,%ebp
  jmp    L21
L35:
  test   %ebx,%ebx
  setle  %al
  movzbl %al,%eax
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: Dado %d EV1 %d EV2 %d


assistant: ```c
int jogar(int ev1, int ev2, int at, int d) {
  int dado, ganhador;
  while (ev1 > 0 && ev2 > 0) {
    dado = aleatorio();
    if (dado <= at) {
      ev1 += d;
      ev2 -= d;
    } else {
      ev1 -= d;
      ev2 += d;
    }
    printf("Dado %d EV1 %d EV2 %d\n", dado, ev1, ev2);
  }
  if (ev1 <= 0) {
    ganhador = 2;
  } else {
    ganhador = 1;
  }
  return ganhador;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jogar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %esi,%esi
  jle    L37
  test   %edi,%edi
  jle    L37
  mov    %esi,%r14d
  mov    %edx,%r12d
  lea    D7(%rip),%r13
  mov    %ecx,%ebp
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L6:
  add    %ebp,%ebx
  sub    %ebp,%r14d
L42:
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L37
  test   %r14d,%r14d
  jle    L37
L51:
  xor    %eax,%eax
  call   <aleatorio@plt>
  mov    %eax,%esi
  cmp    %r12d,%eax
  jle    L6
  sub    %ebp,%ebx
  add    %ebp,%r14d
  jmp    L42
L37:
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  pop    %rbp
  setle  %al
  pop    %r12
  pop    %r13
  add    $0x1,%eax
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: Dado %d EV1 %d EV2 %d


assistant: ```c
int jogar(int ev1, int ev2, int at, int d) {
  int dado, ganhador;
  while (ev1 > 0 && ev2 > 0) {
    dado = aleatorio();
    if (dado <= at) {
      ev1 += d;
      ev2 -= d;
    } else {
      ev1 -= d;
      ev2 += d;
    }
    printf("Dado %d EV1 %d EV2 %d\n", dado, ev1, ev2);
  }
  if (ev1 <= 0) {
    ganhador = 2;
  } else {
    ganhador = 1;
  }
  return ganhador;
}
```
user: What is the c source code of the assembly code below?

```asm
<jogar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %esi,%esi
  jle    L62
  test   %edi,%edi
  jle    L62
  mov    %esi,%r14d
  mov    %edx,%r12d
  lea    D7(%rip),%r13
  mov    %ecx,%ebp
  nopl   (%rax)
L56:
  xor    %eax,%eax
  call   <aleatorio@plt>
  mov    %eax,%esi
  cmp    %r12d,%eax
  jg     L72
  add    %ebp,%ebx
  sub    %ebp,%r14d
  mov    %r13,%rdi
  mov    %r14d,%ecx
  mov    %ebx,%edx
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L62
  test   %ebx,%ebx
  jg     L56
L62:
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  pop    %rbp
  setle  %al
  pop    %r12
  pop    %r13
  add    $0x1,%eax
  pop    %r14
  ret
  nopl   0x0(%rax)
L72:
  sub    %ebp,%ebx
  add    %ebp,%r14d
  mov    %r13,%rdi
  mov    %r14d,%ecx
  mov    %ebx,%edx
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L62
  test   %r14d,%r14d
  jg     L56
  jmp    L62
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: Dado %d EV1 %d EV2 %d


assistant: ```c
int jogar(int ev1, int ev2, int at, int d) {
  int dado, ganhador;
  while (ev1 > 0 && ev2 > 0) {
    dado = aleatorio();
    if (dado <= at) {
      ev1 += d;
      ev2 -= d;
    } else {
      ev1 -= d;
      ev2 += d;
    }
    printf("Dado %d EV1 %d EV2 %d\n", dado, ev1, ev2);
  }
  if (ev1 <= 0) {
    ganhador = 2;
  } else {
    ganhador = 1;
  }
  return ganhador;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GreatestCommonDenominatorArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  jmp    L36
L9:
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L42
L23:
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    -0x28(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GreatestCommonDenominator@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x18(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x18(%rbp)
  jl     L23
  mov    -0x2c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
L36:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L9
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int GreatestCommonDenominatorArray(int iNumbers[], int iCount) {
  while (iCount != 1) {
    int iTmpCount = iCount - (iCount % 2);
    for (int i = 0; i < (iTmpCount / 2); ++i) {
      iNumbers[i] = GreatestCommonDenominator(iNumbers[i * 2], iNumbers[(i * 2) + 1]);
    }
    if (iCount % 2) {
      iNumbers[iTmpCount / 2] = iNumbers[iCount - 1];
    }
    iCount = (iTmpCount / 2) + (iCount % 2);
  }
  return iNumbers[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GreatestCommonDenominatorArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  cmp    $0x1,%esi
  jne    L30
L22:
  mov    0x0(%rbp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  lea    (%r14,%r12,1),%r13d
  cmp    $0x1,%r13d
  je     L22
L30:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  lea    0x0(%r13,%rax,1),%r14d
  and    $0x1,%r14d
  sub    %eax,%r14d
  mov    %r13d,%eax
  sub    %r14d,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L53
  mov    $0x0,%ebx
L19:
  mov    0x4(%rbp,%rbx,8),%esi
  mov    0x0(%rbp,%rbx,8),%edi
  call   <GreatestCommonDenominator@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L19
L53:
  test   $0x1,%r13b
  je     L14
  movslq %r13d,%r13
  mov    -0x4(%rbp,%r13,4),%edx
  movslq %r12d,%rax
  mov    %edx,0x0(%rbp,%rax,4)
  jmp    L14
```

assistant: ```c
int GreatestCommonDenominatorArray(int iNumbers[], int iCount) {
  while (iCount != 1) {
    int iTmpCount = iCount - (iCount % 2);
    for (int i = 0; i < (iTmpCount / 2); ++i) {
      iNumbers[i] = GreatestCommonDenominator(iNumbers[i * 2], iNumbers[(i * 2) + 1]);
    }
    if (iCount % 2) {
      iNumbers[iTmpCount / 2] = iNumbers[iCount - 1];
    }
    iCount = (iTmpCount / 2) + (iCount % 2);
  }
  return iNumbers[0];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GreatestCommonDenominatorArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x1,%esi
  je     L9
  mov    %esi,%r13d
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  lea    0x0(%r13,%rax,1),%r14d
  and    $0x1,%r14d
  sub    %eax,%r14d
  mov    %r13d,%eax
  sub    %r14d,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L38
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L22:
  mov    0x4(%rbp,%rbx,8),%esi
  mov    0x0(%rbp,%rbx,8),%edi
  call   <GreatestCommonDenominator@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L22
L38:
  test   $0x1,%r13b
  je     L24
  movslq %r13d,%r13
  movslq %r12d,%rax
  mov    -0x4(%rbp,%r13,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
L24:
  lea    (%r14,%r12,1),%r13d
  cmp    $0x1,%r13d
  jne    L5
L9:
  pop    %rbx
  mov    0x0(%rbp),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int GreatestCommonDenominatorArray(int iNumbers[], int iCount) {
  while (iCount != 1) {
    int iTmpCount = iCount - (iCount % 2);
    for (int i = 0; i < (iTmpCount / 2); ++i) {
      iNumbers[i] = GreatestCommonDenominator(iNumbers[i * 2], iNumbers[(i * 2) + 1]);
    }
    if (iCount % 2) {
      iNumbers[iTmpCount / 2] = iNumbers[iCount - 1];
    }
    iCount = (iTmpCount / 2) + (iCount % 2);
  }
  return iNumbers[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GreatestCommonDenominatorArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x1,%esi
  je     L48
  mov    %esi,%r13d
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  lea    0x0(%r13,%rax,1),%r14d
  and    $0x1,%r14d
  sub    %eax,%r14d
  mov    %r13d,%eax
  sub    %r14d,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  cmp    $0x1,%eax
  jle    L32
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L30:
  mov    0x4(%rbp,%rbx,8),%esi
  mov    0x0(%rbp,%rbx,8),%edi
  call   <GreatestCommonDenominator@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L30
L32:
  test   $0x1,%r13b
  je     L1
  movslq %r13d,%r13
  movslq %r12d,%rax
  mov    -0x4(%rbp,%r13,4),%edx
  mov    %edx,0x0(%rbp,%rax,4)
L1:
  lea    (%r14,%r12,1),%r13d
  cmp    $0x1,%r13d
  jne    L11
L48:
  pop    %rbx
  mov    0x0(%rbp),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int GreatestCommonDenominatorArray(int iNumbers[], int iCount) {
  while (iCount != 1) {
    int iTmpCount = iCount - (iCount % 2);
    for (int i = 0; i < (iTmpCount / 2); ++i) {
      iNumbers[i] = GreatestCommonDenominator(iNumbers[i * 2], iNumbers[(i * 2) + 1]);
    }
    if (iCount % 2) {
      iNumbers[iTmpCount / 2] = iNumbers[iCount - 1];
    }
    iCount = (iTmpCount / 2) + (iCount % 2);
  }
  return iNumbers[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generated_above>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L27:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L35
  mov    $0x1,%eax
  jmp    L12
L35:
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L27
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int generated_above(const int *celms, size_t level) {
  size_t i;
  for (i = 0; i < level; i++)
    if (celms[i] == celms[level])
      return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generated_above>:
  endbr64
  test   %rsi,%rsi
  je     L9
  mov    (%rdi,%rsi,4),%edx
  mov    $0x0,%eax
L25:
  cmp    %edx,(%rdi,%rax,4)
  je     L14
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L25
  mov    $0x0,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int generated_above(const int *celms, size_t level) {
  size_t i;
  for (i = 0; i < level; i++)
    if (celms[i] == celms[level])
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<generated_above>:
  endbr64
  test   %rsi,%rsi
  je     L10
  mov    (%rdi,%rsi,4),%edx
  xor    %eax,%eax
  jmp    L28
L36:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L10
L28:
  cmp    %edx,(%rdi,%rax,4)
  jne    L36
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int generated_above(const int *celms, size_t level) {
  size_t i;
  for (i = 0; i < level; i++)
    if (celms[i] == celms[level])
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generated_above>:
  endbr64
  test   %rsi,%rsi
  je     L21
  mov    (%rdi,%rsi,4),%edx
  xor    %eax,%eax
  jmp    L28
L29:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L21
L28:
  cmp    %edx,(%rdi,%rax,4)
  jne    L29
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int generated_above(const int *celms, size_t level) {
  size_t i;
  for (i = 0; i < level; i++)
    if (celms[i] == celms[level])
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_if_ping>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string

tool: D15:  

tool: D2: ping

assistant: ```c
int check_if_ping(char *cmd) {
  char *first = strtok(cmd, " ");
  return strcmp(first, "ping") == 0;
}
```