user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movl   $0x2,0x20(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movl   $0x0,0x70(%rsp)
  call   <scanf@plt>
  mov    (%r12),%r9d
  mov    %r9d,%esi
  test   %r9d,%r9d
  je     L8
  cmp    $0x1,%r9d
  je     L21
  mov    %r9d,%r8d
  mov    $0x2,%ecx
  xor    %r10d,%r10d
  jmp    L112
  nopl   0x0(%rax)
L20:
  movslq %r10d,%rax
  mov    %esi,%r8d
  mov    %edi,0x20(%rsp,%rax,4)
L220:
  mov    %edi,%edx
  imul   %edi,%edx
  cmp    %r8d,%edx
  cmovg  %r8d,%edi
  mov    %edi,0x20(%rsp,%rax,4)
  mov    %edi,%ecx
  cmp    $0x1,%r8d
  je     L89
  mov    (%r12),%esi
L112:
  mov    %r8d,%eax
  lea    0x1(%rcx),%edi
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L20
  mov    %esi,%r8d
  movslq %r10d,%rsi
  jmp    L200
  nopl   0x0(%rax,%rax,1)
L155:
  mov    %eax,(%r12)
  mov    %eax,%r8d
  mov    0x60(%rsp,%rsi,4),%eax
  add    $0x1,%eax
  mov    %eax,0x60(%rsp,%rsi,4)
  mov    %eax,0x40(%rsp,%rsi,4)
  cmp    $0x1,%r8d
  je     L123
L200:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L155
L123:
  add    $0x1,%r10d
  movslq %r10d,%rax
  mov    %edi,0x20(%rsp,%rax,4)
  jmp    L220
  nopl   0x0(%rax,%rax,1)
L89:
  lea    -0x1(%r10),%edi
  movl   $0x0,0x20(%rsp,%rax,4)
  test   %edi,%edi
  jne    L104
  mov    0x40(%rsp),%ecx
  mov    0x20(%rsp),%edx
  mov    %r9d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L81:
  add    $0x4,%r12
  jmp    L76
  nopl   0x0(%rax)
L104:
  jle    L171
  lea    -0x2(%r10),%eax
  lea    0x40(%rsp),%r11
  lea    0x44(%rsp,%rax,4),%r10
L56:
  mov    (%r11),%eax
  mov    0x4(%r11),%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L39
  jmp    L11
  nopl   0x0(%rax)
L40:
  mov    %esi,%ecx
L39:
  mov    %ecx,%eax
  mov    %edx,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L40
  mov    %ecx,(%r11)
  mov    %esi,0x4(%r11)
L11:
  add    $0x4,%r11
  cmp    %r11,%r10
  jne    L56
  movslq %edi,%rax
  xor    %esi,%esi
  lea    0x60(%rsp),%r11
  mov    0x40(%rsp,%rax,4),%r10d
  nopl   0x0(%rax)
L148:
  mov    (%r11,%rsi,4),%eax
  cltd
  idiv   %r10d
  test   %eax,%eax
  jle    L55
  mov    0x20(%rsp,%rsi,4),%ecx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L210:
  add    $0x1,%edx
  imul   %ecx,%r8d
  cmp    %eax,%edx
  jne    L210
L55:
  add    $0x1,%rsi
  cmp    %esi,%edi
  jge    L148
L13:
  mov    %r10d,%ecx
  mov    %r8d,%edx
  mov    %r9d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L81
L8:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L188
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L21:
  mov    0x3c(%rsp),%r10d
  mov    $0x1,%r8d
  jmp    L13
L188:
  call   <__stack_chk_fail@plt>
L171:
  mov    0x3c(%rsp),%r10d
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string

tool: D14: %d is %d to the power of %d.


tool: D15: %d

assistant: ```c
main() {
  int input, m[5], i, a[5], x, g[5], c, temp, output, d;
  for (i = 0; 1 == 1; i++) {
    a[0] = 2;
    int b[5] = {0, 0, 0, 0, 0};
    x = 0;
    c = 0;
    output = 1;
    scanf("%d", &m[i]);
    if (m[i] == 0)
      break;
    input = m[i];
    while (m[i] != 1) {
      if (m[i] % a[x] == 0) {
        while (m[i] % a[x] == 0) {
          m[i] = m[i] / a[x];
          b[x]++;
          g[x] = b[x];
          if (m[i] == 1)
            break;
        }
        x++;
        a[x] = a[x - 1] + 1;
      } else
        a[x]++;
      if ((a[x] * a[x]) > m[i]) {
        a[x] = m[i];
      }
    }
    a[x] = 0;
    x--;
    if (x == 0) {
      printf("%d is %d to the power of %d.\n", input, a[0], g[0]);
    } else {
      for (c = 0; c < x; c++) {
        while (g[c] % g[c + 1] != 0) {
          temp = g[c] % g[c + 1];
          g[c] = g[c + 1];
          g[c + 1] = temp;
        }
      }
      for (c = 0; c <= x; c++) {
        for (d = 0; d < (b[c] / g[x]); d++) {
          output = output * a[c];
        }
      }
      printf("%d is %d to the power of %d.\n", input, output, g[x]);
    }
  }
  return 0;
}
```