ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D90(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D51
data_type: string
name: disassemble_data
arguments: data_tag: D41
data_type: string
name: disassemble_data
arguments: data_tag: D84
data_type: string
name: disassemble_data
arguments: data_tag: D56
data_type: string
name: disassemble_data
arguments: data_tag: D42
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D67
data_type: string
name: disassemble_data
arguments: data_tag: D90
data_type: string

tool: D51: Usage: kwakd [OPTIONS]



tool: D41:   Serve a blank html page for any request



tool: D84:   -b, --background     background mode (disables console output, and allows


tool: D56:                        multiple requests to be served simultaneously)


tool: D42:   -p, --port           port to listen for requests on (and optionally address),


tool: D17:                        defaults to port 8000 (on all interfaces)


tool: D0:   -v, --verbose        verbose output


tool: D39:   -q, --quiet          suppress any output


tool: D67:   -V, --version        print version and exit


tool: D90:   -h, --help           display this message and exit


assistant: ```c
void help(void) {
  printf("Usage: kwakd [OPTIONS]\n\n");
  printf("  Serve a blank html page for any request\n\n");
  printf("  -b, --background     background mode (disables console output, and allows\n");
  printf("                       multiple requests to be served simultaneously)\n");
  printf("  -p, --port           port to listen for requests on (and optionally address),\n");
  printf("                       defaults to port 8000 (on all interfaces)\n");
  printf("  -v, --verbose        verbose output\n");
  printf("  -q, --quiet          suppress any output\n");
  printf("  -V, --version        print version and exit\n");
  printf("  -h, --help           display this message and exit\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D80(%rip),%rdi
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D64
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D43
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D68
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D46
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D80
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D85
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D74
type_guessed: string

tool: D64: Usage: kwakd [OPTIONS]



tool: D43:   Serve a blank html page for any request



tool: D68:   -b, --background     background mode (disables console output, and allows


tool: D46:                        multiple requests to be served simultaneously)


tool: D49:   -p, --port           port to listen for requests on (and optionally address),


tool: D59:                        defaults to port 8000 (on all interfaces)


tool: D18:   -v, --verbose        verbose output


tool: D80:   -q, --quiet          suppress any output


tool: D85:   -V, --version        print version and exit


tool: D74:   -h, --help           display this message and exit


assistant: ```c
void help(void) {
  printf("Usage: kwakd [OPTIONS]\n\n");
  printf("  Serve a blank html page for any request\n\n");
  printf("  -b, --background     background mode (disables console output, and allows\n");
  printf("                       multiple requests to be served simultaneously)\n");
  printf("  -p, --port           port to listen for requests on (and optionally address),\n");
  printf("                       defaults to port 8000 (on all interfaces)\n");
  printf("  -v, --verbose        verbose output\n");
  printf("  -q, --quiet          suppress any output\n");
  printf("  -V, --version        print version and exit\n");
  printf("  -h, --help           display this message and exit\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<diff_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <abs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += abs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diff_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edi,%edi
  jle    L24
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %edi,%ebp
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
L26:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  call   <abs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L26
L18:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L18
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += abs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<diff_buffer>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L13:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <abs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L13
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += abs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<diff_buffer>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L13:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <abs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L13
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double diff_buffer(int size, double *buf1, double *buf2) {
  int i;
  double diff = 0.0;
  for (i = 0; i < size; i++) {
    diff += abs(buf1[i] - buf2[i]);
  }
  return diff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L18
L15:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <vrniStevilo@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L15
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D51
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D41
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D46
type_infered: string

tool: D51: Please insert lower and upper bound(min 1 / max 1000):

tool: D28: Lower bound:

tool: D41: %d

tool: D7: Upper bound:

tool: D46: Number of letters used to write all the numbers between %d and %d in words: %d


assistant: ```c
int main() {
  int vsota = 0;
  int i, steviloCrk;
  int spodnjaMeja, zgornjaMeja;
  printf("Please insert lower and upper bound(min 1 / max 1000):\n");
  printf("Lower bound:\n");
  scanf("%d", &spodnjaMeja);
  printf("Upper bound:\n");
  scanf("%d", &zgornjaMeja);
  for (i = spodnjaMeja; i <= zgornjaMeja; i++) {
    steviloCrk = vrniStevilo(i);
    vsota += steviloCrk;
  }
  printf("Number of letters used to write all the numbers between %d and %d in words: %d\n", spodnjaMeja, zgornjaMeja, vsota);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%edx
  cmp    %edx,%ebx
  jg     L27
  mov    $0x0,%ebp
L20:
  mov    %ebx,%edi
  call   <vrniStevilo@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jge    L20
L35:
  mov    %ebp,%ecx
  mov    (%rsp),%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    $0x0,%ebp
  jmp    L35
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D24
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D44
data_type: string

tool: D12: Please insert lower and upper bound(min 1 / max 1000):

tool: D13: Lower bound:

tool: D24: %d

tool: D10: Upper bound:

tool: D44: Number of letters used to write all the numbers between %d and %d in words: %d


assistant: ```c
int main() {
  int vsota = 0;
  int i, steviloCrk;
  int spodnjaMeja, zgornjaMeja;
  printf("Please insert lower and upper bound(min 1 / max 1000):\n");
  printf("Lower bound:\n");
  scanf("%d", &spodnjaMeja);
  printf("Upper bound:\n");
  scanf("%d", &zgornjaMeja);
  for (i = spodnjaMeja; i <= zgornjaMeja; i++) {
    steviloCrk = vrniStevilo(i);
    vsota += steviloCrk;
  }
  printf("Number of letters used to write all the numbers between %d and %d in words: %d\n", spodnjaMeja, zgornjaMeja, vsota);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  lea    D34(%rip),%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%edx
  cmp    %edx,%ebx
  jg     L17
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L14:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <vrniStevilo@plt>
  mov    0x4(%rsp),%edx
  add    %eax,%r12d
  cmp    %ebx,%edx
  jge    L14
  mov    (%rsp),%esi
L35:
  xor    %eax,%eax
  mov    %r12d,%ecx
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L17:
  mov    %ebx,%esi
  xor    %r12d,%r12d
  jmp    L35
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D34
datatype: string
name: read_data
arguments: data_tag: D23
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D28
datatype: string

tool: D6: Please insert lower and upper bound(min 1 / max 1000):

tool: D34: %d

tool: D23: Lower bound:

tool: D13: Upper bound:

tool: D28: Number of letters used to write all the numbers between %d and %d in words: %d


assistant: ```c
int main() {
  int vsota = 0;
  int i, steviloCrk;
  int spodnjaMeja, zgornjaMeja;
  printf("Please insert lower and upper bound(min 1 / max 1000):\n");
  printf("Lower bound:\n");
  scanf("%d", &spodnjaMeja);
  printf("Upper bound:\n");
  scanf("%d", &zgornjaMeja);
  for (i = spodnjaMeja; i <= zgornjaMeja; i++) {
    steviloCrk = vrniStevilo(i);
    vsota += steviloCrk;
  }
  printf("Number of letters used to write all the numbers between %d and %d in words: %d\n", spodnjaMeja, zgornjaMeja, vsota);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  lea    D45(%rip),%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%edx
  cmp    %edx,%ebx
  jg     L22
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L25:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <vrniStevilo@plt>
  mov    0x4(%rsp),%edx
  add    %eax,%r12d
  cmp    %ebx,%edx
  jge    L25
  mov    (%rsp),%esi
L14:
  xor    %eax,%eax
  mov    %r12d,%ecx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L22:
  mov    %ebx,%esi
  xor    %r12d,%r12d
  jmp    L14
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
datatype: string
name: retrieve_data
arguments: data_label: D45
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string

tool: D25: Please insert lower and upper bound(min 1 / max 1000):

tool: D45: %d

tool: D8: Lower bound:

tool: D4: Upper bound:

tool: D10: Number of letters used to write all the numbers between %d and %d in words: %d


assistant: ```c
int main() {
  int vsota = 0;
  int i, steviloCrk;
  int spodnjaMeja, zgornjaMeja;
  printf("Please insert lower and upper bound(min 1 / max 1000):\n");
  printf("Lower bound:\n");
  scanf("%d", &spodnjaMeja);
  printf("Upper bound:\n");
  scanf("%d", &zgornjaMeja);
  for (i = spodnjaMeja; i <= zgornjaMeja; i++) {
    steviloCrk = vrniStevilo(i);
    vsota += steviloCrk;
  }
  printf("Number of letters used to write all the numbers between %d and %d in words: %d\n", spodnjaMeja, zgornjaMeja, vsota);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<frequence_of_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  jmp    L173
L31:
  mov    -0x28(%rbp),%eax
  cltq
  movl   $0x0,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x28(%rbp)
L173:
  cmpl   $0x5,-0x28(%rbp)
  jle    L31
  jmp    L124
L25:
  cmpl   $0xa,-0x24(%rbp)
  jne    L146
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L124
L146:
  cmpl   $0x20,-0x24(%rbp)
  jne    L116
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L124
L116:
  cmpl   $0x9,-0x24(%rbp)
  jne    L79
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L124
L79:
  cmpl   $0x2f,-0x24(%rbp)
  jle    L169
  cmpl   $0x39,-0x24(%rbp)
  jg     L169
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L124
L169:
  cmpl   $0x60,-0x24(%rbp)
  jle    L183
  cmpl   $0x7a,-0x24(%rbp)
  jle    L35
L183:
  cmpl   $0x40,-0x24(%rbp)
  jle    L24
  cmpl   $0x5a,-0x24(%rbp)
  jg     L24
L35:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L124
L24:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L124:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x24(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L25
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <n_height_column@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void frequence_of_chars(void) {
  int c, i;
  int get_frequence[6];
  for (i = 0; i < 6; i++)
    get_frequence[i] = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      ++get_frequence[0];
    else if (c == ' ')
      ++get_frequence[1];
    else if (c == '\t')
      ++get_frequence[2];
    else if (c >= '0' && c <= '9')
      ++get_frequence[3];
    else if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
      ++get_frequence[4];
    else
      ++get_frequence[5];
  }
  n_height_column(get_frequence);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<frequence_of_chars>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  jmp    L32
L34:
  addl   $0x1,(%rsp)
L32:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L17
  cmp    $0xa,%eax
  je     L34
  cmp    $0x20,%eax
  je     L61
  cmp    $0x9,%eax
  je     L8
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L121
  addl   $0x1,0xc(%rsp)
  jmp    L32
L61:
  addl   $0x1,0x4(%rsp)
  jmp    L32
L8:
  addl   $0x1,0x8(%rsp)
  jmp    L32
L121:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  ja     L104
  addl   $0x1,0x10(%rsp)
  jmp    L32
L104:
  addl   $0x1,0x14(%rsp)
  jmp    L32
L17:
  mov    %rsp,%rdi
  call   <n_height_column@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void frequence_of_chars(void) {
  int c, i;
  int get_frequence[6];
  for (i = 0; i < 6; i++)
    get_frequence[i] = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      ++get_frequence[0];
    else if (c == ' ')
      ++get_frequence[1];
    else if (c == '\t')
      ++get_frequence[2];
    else if (c >= '0' && c <= '9')
      ++get_frequence[3];
    else if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
      ++get_frequence[4];
    else
      ++get_frequence[5];
  }
  n_height_column(get_frequence);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frequence_of_chars>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    D0(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L125:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L47
L3:
  cmp    $0xa,%eax
  je     L48
  cmp    $0x20,%eax
  je     L71
  cmp    $0x9,%eax
  je     L87
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L127
  xor    %eax,%eax
  addl   $0x1,0xc(%rsp)
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L3
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %rsp,%rdi
  call   <n_height_column@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  addl   $0x1,(%rsp)
  jmp    L125
  cs nopw 0x0(%rax,%rax,1)
L71:
  addl   $0x1,0x4(%rsp)
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L87:
  addl   $0x1,0x8(%rsp)
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L127:
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  ja     L61
  addl   $0x1,0x10(%rsp)
  jmp    L125
  nopl   (%rax)
L61:
  addl   $0x1,0x14(%rsp)
  jmp    L125
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void frequence_of_chars(void) {
  int c, i;
  int get_frequence[6];
  for (i = 0; i < 6; i++)
    get_frequence[i] = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      ++get_frequence[0];
    else if (c == ' ')
      ++get_frequence[1];
    else if (c == '\t')
      ++get_frequence[2];
    else if (c >= '0' && c <= '9')
      ++get_frequence[3];
    else if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
      ++get_frequence[4];
    else
      ++get_frequence[5];
  }
  n_height_column(get_frequence);
}
```