ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  cmp    0x10(%rsp),%r8d
  jle    L26
  cmp    0x14(%rsp),%r8d
  jl     L65
L68:
  mov    0x10(%rsp),%esi
L46:
  cmp    0x14(%rsp),%esi
  jle    L59
  cmp    %r8d,%esi
  jl     L113
L74:
  mov    0x14(%rsp),%r8d
L149:
  cmp    0xc(%rsp),%r8d
  jle    L115
  cmp    %esi,%r8d
  jl     L30
L152:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L30:
  mov    %r8d,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r8d
L115:
  cmp    0x10(%rsp),%r8d
  jle    L152
  cmp    0xc(%rsp),%r8d
  jge    L152
  mov    %r8d,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L152
L113:
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
L59:
  mov    0x14(%rsp),%r8d
  cmp    0xc(%rsp),%esi
  jle    L149
  cmp    %r8d,%esi
  jge    L149
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  jmp    L74
L65:
  mov    %r8d,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
L26:
  mov    0x10(%rsp),%esi
  cmp    0x14(%rsp),%r8d
  jle    L46
  cmp    %esi,%r8d
  jge    L46
  mov    %r8d,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  jmp    L68
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D58
type: string
name: extract_symbolic_data
arguments: tag: D47
type: string

tool: D9: Pleaes enter 3 numbers separated by spaces > 

tool: D58: %d%d%d

tool: D47: %d is the median


assistant: ```c
int main(void) {
  int A, B, C;
  printf("Pleaes enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &A, &B, &C);
  if (A > B && A < C)
    printf("%d is the median\n", A);
  if (A > C && A < B)
    printf("%d is the median\n", A);
  if (B > C && B < A)
    printf("%d is the median\n", B);
  if (B > A && B < C)
    printf("%d is the median\n", B);
  if (C > A && C < B)
    printf("%d is the median\n", C);
  if (C > B && C < A)
    printf("%d is the median\n", C);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  cmp    0x10(%rsp),%r8d
  jle    L7
  cmp    0x14(%rsp),%r8d
  jl     L28
L116:
  mov    0x10(%rsp),%esi
L30:
  cmp    0x14(%rsp),%esi
  jle    L113
  cmp    %r8d,%esi
  jl     L1
L121:
  mov    0x14(%rsp),%r8d
L16:
  cmp    0xc(%rsp),%r8d
  jle    L158
  cmp    %esi,%r8d
  jl     L128
L152:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L128:
  mov    %r8d,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%r8d
L158:
  cmp    0x10(%rsp),%r8d
  jle    L152
  cmp    0xc(%rsp),%r8d
  jge    L152
  mov    %r8d,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L152
L1:
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
L113:
  mov    0x14(%rsp),%r8d
  cmp    0xc(%rsp),%esi
  jle    L16
  cmp    %r8d,%esi
  jge    L16
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  jmp    L121
L28:
  mov    %r8d,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
L7:
  mov    0x10(%rsp),%esi
  cmp    0x14(%rsp),%r8d
  jle    L30
  cmp    %esi,%r8d
  jge    L30
  mov    %r8d,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%r8d
  jmp    L116
L136:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D51
type_guessed: string

tool: D3: Pleaes enter 3 numbers separated by spaces > 

tool: D22: %d%d%d

tool: D51: %d is the median


assistant: ```c
int main(void) {
  int A, B, C;
  printf("Pleaes enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &A, &B, &C);
  if (A > B && A < C)
    printf("%d is the median\n", A);
  if (A > C && A < B)
    printf("%d is the median\n", A);
  if (B > C && B < A)
    printf("%d is the median\n", B);
  if (B > A && B < C)
    printf("%d is the median\n", B);
  if (C > A && C < B)
    printf("%d is the median\n", C);
  if (C > B && C < A)
    printf("%d is the median\n", C);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x12b,-0x4(%rbp)
  jle    L0
  movb   $0xff,-0x6(%rbp)
  movsbl -0x6(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D1
type: string

tool: D4: i = %i, c = %i


tool: D1: (char)0xFF = %i


assistant: ```c
int main(void) {
  unsigned char c;
  char d;
  int i;
  for (i = 0; i < 300; i++) {
    c = i * i;
    printf("i = %i, c = %i\n", i, c);
  }
  d = 0xFF;
  printf("(char)0xFF = %i\n", d);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L1:
  mov    %ebx,%eax
  imul   %ebx,%eax
  movzbl %al,%edx
  movsbl %bl,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x12c,%ebx
  jne    L1
  mov    $0xffffffff,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string

tool: D3: i = %i, c = %i


tool: D18: (char)0xFF = %i


assistant: ```c
int main(void) {
  unsigned char c;
  char d;
  int i;
  for (i = 0; i < 300; i++) {
    c = i * i;
    printf("i = %i, c = %i\n", i, c);
  }
  d = 0xFF;
  printf("(char)0xFF = %i\n", d);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%eax
  movsbl %bl,%esi
  mov    %rbp,%rdi
  imul   %ebx,%eax
  add    $0x1,%ebx
  movzbl %al,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x12c,%ebx
  jne    L3
  mov    $0xffffffff,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D9: i = %i, c = %i


tool: D10: (char)0xFF = %i


assistant: ```c
int main(void) {
  unsigned char c;
  char d;
  int i;
  for (i = 0; i < 300; i++) {
    c = i * i;
    printf("i = %i, c = %i\n", i, c);
  }
  d = 0xFF;
  printf("(char)0xFF = %i\n", d);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%eax
  movsbl %bl,%esi
  mov    %rbp,%rdi
  imul   %ebx,%eax
  add    $0x1,%ebx
  movzbl %al,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x12c,%ebx
  jne    L9
  mov    $0xffffffff,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D19: i = %i, c = %i


tool: D4: (char)0xFF = %i


assistant: ```c
int main(void) {
  unsigned char c;
  char d;
  int i;
  for (i = 0; i < 300; i++) {
    c = i * i;
    printf("i = %i, c = %i\n", i, c);
  }
  d = 0xFF;
  printf("(char)0xFF = %i\n", d);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<function1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L11:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x4e1f,-0x8(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void function1() {
  int i, j;
  for (i = 0; i < 20000; i++)
    j += i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<function1>:
  endbr64
  mov    $0x4e20,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  ret
```

assistant: ```c
void function1() {
  int i, j;
  for (i = 0; i < 20000; i++)
    j += i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<function1>:
  endbr64
  ret
```

assistant: ```c
void function1() {
  int i, j;
  for (i = 0; i < 20000; i++)
    j += i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<function1>:
  endbr64
  ret
```

assistant: ```c
void function1() {
  int i, j;
  for (i = 0; i < 20000; i++)
    j += i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcpy_literal_string_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: test

assistant: ```c
void strcpy_literal_string_Bad() {
  char dst[4];
  strcpy(dst, "test");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy_literal_string_Bad>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: test

assistant: ```c
void strcpy_literal_string_Bad() {
  char dst[4];
  strcpy(dst, "test");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy_literal_string_Bad>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: test

assistant: ```c
void strcpy_literal_string_Bad() {
  char dst[4];
  strcpy(dst, "test");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcpy_literal_string_Bad>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: test

assistant: ```c
void strcpy_literal_string_Bad() {
  char dst[4];
  strcpy(dst, "test");
}
```
user: What is the c source code of the assembly code below?

```asm
<equal_ignore_case>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L18
L43:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L24
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x41,%al
  jle    L78
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x59,%al
  jg     L78
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  cmp    %eax,%edx
  je     L24
  mov    $0x0,%eax
  jmp    L1
L78:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x61,%al
  jle    L57
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x79,%al
  jg     L57
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  cmp    %eax,%edx
  je     L24
  mov    $0x0,%eax
  jmp    L1
L57:
  mov    $0x0,%eax
  jmp    L1
L24:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
L44:
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int equal_ignore_case(const char *a, const char *b) {
  while (*a != 0 && *b != 0) {
    if (*a != *b) {
      if (*a > 'A' && *a < 'Z') {
        if (*b != *a + ('a' - 'A'))
          return 0;
      } else if (*a > 'a' && *a < 'z') {
        if (*a != *b + ('a' - 'A'))
          return 0;
      } else {
        return 0;
      }
    }
    a++;
    b++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<equal_ignore_case>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%ecx
  test   %al,%al
  jne    L8
  mov    $0x1,%eax
  ret
L9:
  lea    -0x62(%rax),%r8d
  cmp    $0x17,%r8b
  ja     L44
  movsbl %al,%eax
  movsbl %dl,%edx
  add    $0x20,%edx
  cmp    %edx,%eax
  jne    L23
L78:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L14
L8:
  movzbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  je     L4
  cmp    %al,%dl
  je     L78
  lea    -0x42(%rax),%r8d
  cmp    $0x17,%r8b
  ja     L9
  movsbl %dl,%edx
  movsbl %al,%eax
  add    $0x20,%eax
  cmp    %eax,%edx
  je     L78
  mov    $0x0,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
L44:
  mov    $0x0,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal_ignore_case(const char *a, const char *b) {
  while (*a != 0 && *b != 0) {
    if (*a != *b) {
      if (*a > 'A' && *a < 'Z') {
        if (*b != *a + ('a' - 'A'))
          return 0;
      } else if (*a > 'a' && *a < 'z') {
        if (*a != *b + ('a' - 'A'))
          return 0;
      } else {
        return 0;
      }
    }
    a++;
    b++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<equal_ignore_case>:
  endbr64
  movsbl (%rdi),%eax
  xor    %ecx,%ecx
  test   %al,%al
  jne    L2
  jmp    L32
  nop
L73:
  add    $0x20,%eax
  cmp    %al,%dl
  jne    L61
L38:
  add    $0x1,%rcx
  movsbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L32
L2:
  movsbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  je     L32
  cmp    %al,%dl
  je     L38
  lea    -0x42(%rax),%r8d
  cmp    $0x17,%r8b
  jbe    L73
  lea    -0x62(%rax),%r8d
  cmp    $0x17,%r8b
  ja     L61
  add    $0x20,%edx
  cmp    %edx,%eax
  je     L38
L61:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal_ignore_case(const char *a, const char *b) {
  while (*a != 0 && *b != 0) {
    if (*a != *b) {
      if (*a > 'A' && *a < 'Z') {
        if (*b != *a + ('a' - 'A'))
          return 0;
      } else if (*a > 'a' && *a < 'z') {
        if (*a != *b + ('a' - 'A'))
          return 0;
      } else {
        return 0;
      }
    }
    a++;
    b++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<equal_ignore_case>:
  endbr64
  movsbl (%rdi),%eax
  xor    %ecx,%ecx
  test   %al,%al
  jne    L47
  jmp    L73
  nop
L64:
  add    $0x20,%eax
  cmp    %al,%dl
  jne    L20
L36:
  add    $0x1,%rcx
  movsbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L73
L47:
  movsbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  je     L73
  cmp    %al,%dl
  je     L36
  lea    -0x42(%rax),%r8d
  cmp    $0x17,%r8b
  jbe    L64
  lea    -0x62(%rax),%r8d
  cmp    $0x17,%r8b
  ja     L20
  add    $0x20,%edx
  cmp    %edx,%eax
  je     L36
L20:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L73:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal_ignore_case(const char *a, const char *b) {
  while (*a != 0 && *b != 0) {
    if (*a != *b) {
      if (*a > 'A' && *a < 'Z') {
        if (*b != *a + ('a' - 'A'))
          return 0;
      } else if (*a > 'a' && *a < 'z') {
        if (*a != *b + ('a' - 'A'))
          return 0;
      } else {
        return 0;
      }
    }
    a++;
    b++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<half_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L8
  mov    -0x14(%rbp),%eax
  jmp    L11
L8:
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <half_add>
L11:
  leave
  ret
```

assistant: ```c
uint32_t half_add(uint32_t a, uint32_t b) {
  if (b == 0)
    return a;
  uint32_t sum = a ^ b;
  uint32_t carry = (a & b) << 1;
  return half_add(sum, carry);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<half_add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  mov    %esi,%edx
  and    %edi,%edx
  add    %edx,%edx
  mov    %esi,%edi
  xor    %eax,%edi
  mov    %edx,%esi
  call   <half_add>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t half_add(uint32_t a, uint32_t b) {
  if (b == 0)
    return a;
  uint32_t sum = a ^ b;
  uint32_t carry = (a & b) << 1;
  return half_add(sum, carry);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<half_add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L15
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %edx,%esi
  add    %esi,%esi
  jne    L11
L15:
  ret
```

assistant: ```c
uint32_t half_add(uint32_t a, uint32_t b) {
  if (b == 0)
    return a;
  uint32_t sum = a ^ b;
  uint32_t carry = (a & b) << 1;
  return half_add(sum, carry);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<half_add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L12
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %edx,%esi
  add    %esi,%esi
  jne    L6
L12:
  ret
```

assistant: ```c
uint32_t half_add(uint32_t a, uint32_t b) {
  if (b == 0)
    return a;
  uint32_t sum = a ^ b;
  uint32_t carry = (a & b) << 1;
  return half_add(sum, carry);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ftg_stristr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  jmp    L85
L90:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L54
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L87
L105:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L35
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L87:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L105
  jmp    L7
L35:
  nop
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L54
  mov    -0x28(%rbp),%rax
  jmp    L85
L54:
  addq   $0x1,-0x28(%rbp)
L4:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L90
  mov    $0x0,%eax
L85:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ftg_stristr(const char *haystack, const char *needle) {
  if (!*needle)
    return (char *)(haystack + strlen(haystack));
  for (; *haystack; ++haystack) {
    if (tolower(*haystack) == tolower(*needle)) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if (tolower(*h) != tolower(*n))
          break;
      }
      if (!*n)
        return (char *)haystack;
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ftg_stristr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  cmpb   $0x0,(%rsi)
  je     L89
  mov    %rsi,%r13
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L14
  mov    $0x0,%r12d
  jmp    L83
L89:
  call   <strlen@plt>
  cltq
  add    %rax,%r12
  jmp    L83
L15:
  cmpb   $0x0,(%rbx)
  je     L83
L85:
  add    $0x1,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L57
L14:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L85
  movzbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%rbp
  test   %dil,%dil
  je     L15
L101:
  cmpb   $0x0,(%rbx)
  je     L83
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%r14
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %rax,%r14
  jne    L15
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L101
  jmp    L15
L57:
  mov    $0x0,%r12d
L83:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ftg_stristr(const char *haystack, const char *needle) {
  if (!*needle)
    return (char *)(haystack + strlen(haystack));
  for (; *haystack; ++haystack) {
    if (tolower(*haystack) == tolower(*needle)) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if (tolower(*h) != tolower(*n))
          break;
      }
      if (!*n)
        return (char *)haystack;
    }
  }
  return NULL;
}
```