ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<readString>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  lea    0x4(%rsp),%rdx
  mov    $0x24,%esi
  call   <readLong@plt>
  test   %eax,%eax
  jne    L12
L47:
  xor    %eax,%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x4(%rsp),%eax
  lea    0x2(%rax),%edi
  mov    %edi,0x4(%rsp)
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  mov    %rax,%rsi
  call   <readBytes@plt>
  test   %eax,%eax
  je     L47
  movslq 0x4(%rsp),%rax
  mov    (%rbx),%rdx
  lea    -0x2(%rdx,%rax,1),%rdi
  call   <consumeNewline@plt>
  test   %eax,%eax
  je     L47
  movslq 0x4(%rsp),%rax
  mov    (%rbx),%rdx
  movb   $0x0,-0x2(%rdx,%rax,1)
  mov    $0x1,%eax
  jmp    L23
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readString(FILE *fp, char **target) {
  ssize_t len;
  *target = NULL;
  if (!readLong(fp, '$', &len)) {
    return 0;
  }
  len += 2;
  *target = (char *)malloc(len);
  if (!readBytes(fp, *target, len)) {
    return 0;
  }
  if (!consumeNewline(*target + len - 2)) {
    return 0;
  }
  (*target)[len - 2] = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readString>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsi)
  lea    0x4(%rsp),%rdx
  mov    $0x24,%esi
  call   <readLong@plt>
  test   %eax,%eax
  jne    L39
L16:
  xor    %eax,%eax
L49:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    0x4(%rsp),%eax
  lea    0x2(%rax),%edi
  mov    %edi,0x4(%rsp)
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  mov    %rax,%rsi
  call   <readBytes@plt>
  test   %eax,%eax
  je     L16
  movslq 0x4(%rsp),%rax
  mov    (%rbx),%rdx
  lea    -0x2(%rdx,%rax,1),%rdi
  call   <consumeNewline@plt>
  test   %eax,%eax
  je     L16
  movslq 0x4(%rsp),%rax
  mov    (%rbx),%rdx
  movb   $0x0,-0x2(%rdx,%rax,1)
  mov    $0x1,%eax
  jmp    L49
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readString(FILE *fp, char **target) {
  ssize_t len;
  *target = NULL;
  if (!readLong(fp, '$', &len)) {
    return 0;
  }
  len += 2;
  *target = (char *)malloc(len);
  if (!readBytes(fp, *target, len)) {
    return 0;
  }
  if (!consumeNewline(*target + len - 2)) {
    return 0;
  }
  (*target)[len - 2] = '\0';
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L12:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
L2:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcat(char *new, const char *orig) {
  while (*new != '\0')
    new ++;
  do {
    *new ++ = *orig++;
  } while (*orig != '\0');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
L26:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L26
L0:
  add    $0x1,%rsi
  add    $0x1,%rdi
  movzbl -0x1(%rsi),%eax
  mov    %al,-0x1(%rdi)
  cmpb   $0x0,(%rsi)
  jne    L0
  ret
```

assistant: ```c
void strcat(char *new, const char *orig) {
  while (*new != '\0')
    new ++;
  do {
    *new ++ = *orig++;
  } while (*orig != '\0');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x1,%rdi
L11:
  cmpb   $0x0,(%rdi)
  jne    L26
  movzbl (%rsi),%edx
  xor    %eax,%eax
  xchg   %ax,%ax
L4:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L4
  ret
```

assistant: ```c
void strcat(char *new, const char *orig) {
  while (*new != '\0')
    new ++;
  do {
    *new ++ = *orig++;
  } while (*orig != '\0');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcat>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%rdi
L17:
  cmpb   $0x0,(%rdi)
  jne    L22
  nopl   0x0(%rax)
L18:
  movsb  %ds:(%rsi),%es:(%rdi)
  cmpb   $0x0,(%rsi)
  jne    L18
  ret
```

assistant: ```c
void strcat(char *new, const char *orig) {
  while (*new != '\0')
    new ++;
  do {
    *new ++ = *orig++;
  } while (*orig != '\0');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L38
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L38:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L17
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L17:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  *max = arr[0];
  *min = arr[0];
  for (i = 0; i < size; i++) {
    if (arr[i] > *max) {
      *max = arr[i];
    }
    if (arr[i] < *min) {
      *min = arr[i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<minmax>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  test   %esi,%esi
  jle    L41
  mov    %rdi,%rax
  lea    -0x1(%rsi),%esi
  lea    (%rdi,%rsi,4),%r8
  jmp    L23
L51:
  lea    0x4(%rax),%rsi
  cmp    %r8,%rax
  je     L41
  mov    %rsi,%rax
L23:
  mov    %rax,%rdi
  mov    (%rax),%esi
  cmp    (%rcx),%esi
  jle    L58
  mov    %esi,(%rcx)
L58:
  mov    (%rdi),%esi
  cmp    (%rdx),%esi
  jge    L51
  mov    %esi,(%rdx)
  jmp    L51
L41:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  *max = arr[0];
  *min = arr[0];
  for (i = 0; i < size; i++) {
    if (arr[i] > *max) {
      *max = arr[i];
    }
    if (arr[i] < *min) {
      *min = arr[i];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minmax>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%rsi
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rax,%rdi
L0:
  mov    (%rdi),%eax
  cmp    (%rcx),%eax
  jle    L5
  mov    %eax,(%rcx)
L5:
  cmp    (%rdx),%eax
  jge    L43
  mov    %eax,(%rdx)
L43:
  lea    0x4(%rdi),%rax
  cmp    %rsi,%rdi
  jne    L24
L38:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  *max = arr[0];
  *min = arr[0];
  for (i = 0; i < size; i++) {
    if (arr[i] > *max) {
      *max = arr[i];
    }
    if (arr[i] < *min) {
      *min = arr[i];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minmax>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%rsi
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rax,%rdi
L20:
  mov    (%rdi),%eax
  cmp    (%rcx),%eax
  jle    L10
  mov    %eax,(%rcx)
L10:
  cmp    (%rdx),%eax
  jge    L48
  mov    %eax,(%rdx)
L48:
  lea    0x4(%rdi),%rax
  cmp    %rsi,%rdi
  jne    L11
L22:
  ret
```

assistant: ```c
void minmax(int *arr, int size, int *min, int *max) {
  int i;
  *max = arr[0];
  *min = arr[0];
  for (i = 0; i < size; i++) {
    if (arr[i] > *max) {
      *max = arr[i];
    }
    if (arr[i] < *min) {
      *min = arr[i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_word(int address, int word) {
  int *a = (int *)address;
  *a = word;
}
```
user: What is the c source code of the assembly code below:

```asm
<write_word>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_word(int address, int word) {
  int *a = (int *)address;
  *a = word;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_word>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_word(int address, int word) {
  int *a = (int *)address;
  *a = word;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_word>:
  endbr64
  movslq %edi,%rdi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_word(int address, int word) {
  int *a = (int *)address;
  *a = word;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rel_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  mov    -0x28(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L14:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
time_t rel_time(time_t *ptr) {
  struct timespec reltime;
  clock_gettime(CLOCK_MONOTONIC, &reltime);
  time_t _time = (reltime.tv_sec * 1000) + (reltime.tv_nsec / 1000000);
  if (ptr)
    *ptr = _time;
  return _time;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rel_time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  test   %rbx,%rbx
  je     L7
  mov    %eax,(%rbx)
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t rel_time(time_t *ptr) {
  struct timespec reltime;
  clock_gettime(CLOCK_MONOTONIC, &reltime);
  time_t _time = (reltime.tv_sec * 1000) + (reltime.tv_nsec / 1000000);
  if (ptr)
    *ptr = _time;
  return _time;
}
```
user: What is the c source code of the assembly code below:

```asm
<rel_time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  test   %rbx,%rbx
  je     L10
  mov    %eax,(%rbx)
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t rel_time(time_t *ptr) {
  struct timespec reltime;
  clock_gettime(CLOCK_MONOTONIC, &reltime);
  time_t _time = (reltime.tv_sec * 1000) + (reltime.tv_nsec / 1000000);
  if (ptr)
    *ptr = _time;
  return _time;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rel_time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  test   %rbx,%rbx
  je     L10
  mov    %eax,(%rbx)
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t rel_time(time_t *ptr) {
  struct timespec reltime;
  clock_gettime(CLOCK_MONOTONIC, &reltime);
  time_t _time = (reltime.tv_sec * 1000) + (reltime.tv_nsec / 1000000);
  if (ptr)
    *ptr = _time;
  return _time;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_aln_maf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L16
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
L16:
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L12:
  mov    -0x2c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_maf_alignment@plt>
  leave
  ret
```

assistant: ```c
int parse_aln_maf(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_maf_alignment(fp, names, aln, verbosity);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_aln_maf>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L16
  movq   $0x0,(%rax)
L16:
  test   %r8,%r8
  je     L8
  movq   $0x0,(%r8)
L8:
  call   <parse_maf_alignment@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int parse_aln_maf(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_maf_alignment(fp, names, aln, verbosity);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_aln_maf>:
  endbr64
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L9
  movq   $0x0,(%rax)
L9:
  test   %r8,%r8
  je     L13
  movq   $0x0,(%r8)
L13:
  jmp    1050 <parse_maf_alignment@plt>
```

assistant: ```c
int parse_aln_maf(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_maf_alignment(fp, names, aln, verbosity);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_aln_maf>:
  endbr64
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L2
  movq   $0x0,(%rax)
L2:
  test   %r8,%r8
  je     L4
  movq   $0x0,(%r8)
L4:
  jmp    1050 <parse_maf_alignment@plt>
```

assistant: ```c
int parse_aln_maf(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_maf_alignment(fp, names, aln, verbosity);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<c_timegm>:
  endbr64
  mov    %rdi,%rsi
  mov    0x4(%rdi),%r9d
  mov    (%rdi),%edx
  movslq %r9d,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  mov    %r9d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x76c(%rdx,%rax,1),%r10d
  movslq %r10d,%rdi
  lea    (%rax,%rax,2),%eax
  shl    $0x2,%eax
  sub    %eax,%r9d
  lea    -0x7b2(%rdi),%rax
  lea    (%rax,%rax,8),%rdx
  lea    (%rax,%rdx,8),%rax
  lea    (%rax,%rax,4),%rax
  movslq %r9d,%rcx
  lea    D8(%rip),%rdx
  movslq (%rdx,%rcx,4),%rdx
  add    %rdx,%rax
  lea    -0x7ad(%rdi),%r11
  mov    %rdi,%rdx
  sub    $0x7b0,%rdx
  cmovns %rdx,%r11
  sar    $0x2,%r11
  add    %rax,%r11
  lea    -0x76c(%rdi),%r8
  movabs $0xa3d70a3d70a3d70b,%rcx
  mov    %r8,%rax
  imul   %rcx
  add    %r8,%rdx
  sar    $0x6,%rdx
  sar    $0x3f,%r8
  sub    %rdx,%r8
  add    %r11,%r8
  lea    -0x640(%rdi),%r11
  mov    %r11,%rax
  imul   %rcx
  lea    (%rdx,%r11,1),%rcx
  sar    $0x8,%rcx
  sar    $0x3f,%r11
  sub    %r11,%rcx
  add    %r8,%rcx
  test   $0x3,%r10b
  jne    L10
  movabs $0xa3d70a3d70a3d70b,%rdx
  mov    %rdi,%rax
  imul   %rdx
  add    %rdi,%rdx
  sar    $0x6,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  cmp    %rax,%rdi
  jne    L7
  movabs $0xa3d70a3d70a3d70b,%rdx
  mov    %rdi,%rax
  imul   %rdx
  add    %rdi,%rdx
  sar    $0x8,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  cmp    %rax,%rdi
  jne    L10
L7:
  cmp    $0x2,%r9d
  setl   %al
  movzbl %al,%eax
  sub    %rax,%rcx
L10:
  mov    0x8(%rsi),%eax
  sub    $0x1,%eax
  cltq
  add    %rcx,%rax
  lea    (%rax,%rax,2),%rdx
  mov    0x20(%rsi),%rax
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x18(%rsi),%rdx
  lea    (%rdx,%rax,4),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x10(%rsi),%rdx
  lea    (%rdx,%rax,4),%rax
  cmpl   $0x1,0xc(%rsi)
  je     L5
L22:
  ret
L5:
  sub    $0xe10,%rax
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: 

assistant: ```c
time_t c_timegm(struct tm *t) {
  long year;
  time_t result;
  static const int cdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  year = 1900 + t->tm_year + t->tm_mon / 12;
  result = (year - 1970) * 365 + cdays[t->tm_mon % 12];
  result += (year - 1968) / 4;
  result -= (year - 1900) / 100;
  result += (year - 1600) / 400;
  if ((year % 4) == 0 && ((year % 100) != 0 || (year % 400) == 0) && (t->tm_mon % 12) < 2) {
    result--;
  }
  result += t->tm_mday - 1;
  result *= 24;
  result += t->tm_hour;
  result *= 60;
  result += t->tm_min;
  result *= 60;
  result += t->tm_sec;
  if (t->tm_isdst == 1)
    result -= 3600;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<c_timegm>:
  endbr64
  movslq 0x4(%rdi),%rax
  mov    (%rdi),%edx
  mov    %rdi,%rsi
  mov    %rax,%r9
  imul   $0x2aaaaaab,%rax,%rax
  mov    %r9d,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    0x76c(%rdx,%rax,1),%r10d
  lea    (%rax,%rax,2),%eax
  movslq %r10d,%r8
  shl    $0x2,%eax
  sub    %eax,%r9d
  lea    -0x7b2(%r8),%rax
  lea    -0x7ad(%r8),%r11
  lea    (%rax,%rax,8),%rdx
  movslq %r9d,%rcx
  lea    -0x76c(%r8),%rdi
  lea    (%rax,%rdx,8),%rax
  lea    D3(%rip),%rdx
  movslq (%rdx,%rcx,4),%rdx
  lea    (%rax,%rax,4),%rax
  movabs $0xa3d70a3d70a3d70b,%rcx
  add    %rdx,%rax
  mov    %r8,%rdx
  sub    $0x7b0,%rdx
  cmovns %rdx,%r11
  sar    $0x2,%r11
  add    %rax,%r11
  mov    %rdi,%rax
  imul   %rcx
  add    %rdi,%rdx
  sar    $0x3f,%rdi
  sar    $0x6,%rdx
  sub    %rdx,%rdi
  add    %r11,%rdi
  lea    -0x640(%r8),%r11
  mov    %r11,%rax
  imul   %rcx
  add    %r11,%rdx
  sar    $0x3f,%r11
  sar    $0x8,%rdx
  sub    %r11,%rdx
  and    $0x3,%r10d
  lea    (%rdx,%rdi,1),%rax
  jne    L32
  movabs $0x8f5c28f5c28f5c29,%rdx
  movabs $0x28f5c28f5c28f5c,%rcx
  imul   %rdx,%r8
  movabs $0x51eb851eb851eb8,%rdx
  add    %r8,%rdx
  ror    $0x2,%rdx
  cmp    %rcx,%rdx
  jbe    L25
  xor    %edx,%edx
  cmp    $0x2,%r9d
  setl   %dl
  sub    %rdx,%rax
L32:
  mov    0x8(%rsi),%ecx
  lea    -0x1(%rcx),%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  mov    0x20(%rsi),%rax
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x18(%rsi),%rdx
  lea    (%rdx,%rax,4),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x10(%rsi),%rdx
  cmpl   $0x1,0xc(%rsi)
  lea    (%rdx,%rax,4),%rax
  je     L28
  ret
  nopl   0x0(%rax)
L28:
  sub    $0xe10,%rax
  ret
  nop
L25:
  movabs $0x51eb851eb851eb0,%rdx
  add    %rdx,%r8
  movabs $0xa3d70a3d70a3d6,%rdx
  ror    $0x4,%r8
  cmp    %rdx,%r8
  ja     L32
  xor    %edx,%edx
  cmp    $0x2,%r9d
  setl   %dl
  sub    %rdx,%rax
  jmp    L32
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: 

assistant: ```c
time_t c_timegm(struct tm *t) {
  long year;
  time_t result;
  static const int cdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  year = 1900 + t->tm_year + t->tm_mon / 12;
  result = (year - 1970) * 365 + cdays[t->tm_mon % 12];
  result += (year - 1968) / 4;
  result -= (year - 1900) / 100;
  result += (year - 1600) / 400;
  if ((year % 4) == 0 && ((year % 100) != 0 || (year % 400) == 0) && (t->tm_mon % 12) < 2) {
    result--;
  }
  result += t->tm_mday - 1;
  result *= 24;
  result += t->tm_hour;
  result *= 60;
  result += t->tm_min;
  result *= 60;
  result += t->tm_sec;
  if (t->tm_isdst == 1)
    result -= 3600;
  return result;
}
```