ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashString>:
  endbr64
  mov    %rdi,%r10
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L28
  push   %r12
  xor    %esi,%esi
  mov    $0x32,%r8d
  xor    %r9d,%r9d
  movabs $0x2c3ce1ec00,%r12
  push   %rbp
  movabs $0x469ee58469ee5847,%r11
  movabs $0xd79435e50d79436,%rbp
  push   %rbx
  movabs $0x438558d400,%rbx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r9d,%ecx
  sub    $0x41,%edi
  imul   %r9d,%ecx
  mov    %edi,%eax
  movslq %edi,%rdi
  imul   %r9,%rdi
  add    $0x1,%r9
  shl    %cl,%eax
  movslq %eax,%rcx
  lea    (%r8,%r8,2),%rax
  shl    $0x3,%rax
  sub    %r8,%rax
  xor    %rax,%rcx
  add    %r12,%rcx
  mov    %rcx,%rax
  imul   %rbp
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rax
  sub    %rax,%rcx
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  mov    %rcx,%r8
  sub    %rsi,%rax
  add    %rbx,%rax
  add    %rax,%rdi
  mov    %rdi,%rax
  imul   %r11
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x3,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    0x0(,%rsi,8),%rax
  sub    %rsi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    %rdi,%rsi
  movsbl (%r10,%r9,1),%edi
  sub    %rax,%rsi
  test   %dil,%dil
  jne    L29
  lea    D9(%rip),%rax
  mov    (%rax,%rsi,8),%rcx
  movabs $0x2e90edd000,%rax
  cmp    %rsi,%rcx
  je     L13
  movabs $0x6666666666666667,%rdx
  add    %rax,%rcx
  pop    %rbx
  pop    %rbp
  mov    %rcx,%rax
  pop    %r12
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x3,%rdx
  sub    %rax,%rdx
  mov    %ecx,%eax
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  movabs $0xcccccccccccccccd,%rdx
  lea    (%r8,%rax,1),%rcx
  pop    %rbx
  pop    %rbp
  mov    %rcx,%rax
  pop    %r12
  mul    %rdx
  mov    %ecx,%eax
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xa,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: 

assistant: ```c
int hashString(char *str) {
  static const long long precalculated_table[31] = {0, 4, 2, 16, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 19, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30};
  long long i, ret = 50, sub = 0;
  for (i = 0; str[i] != 0; i++) {
    ret = (190000000000LL + ((ret * 23) ^ ((str[i] - 'A') << i * i))) % 19;
    sub = (290000000000LL + sub * 23 + (str[i] - 'A') * i) % 29;
  }
  return (int)((200000000000LL + (sub != precalculated_table[sub] ? precalculated_table[sub] : ret)) % 20LL);
}
```
user: What is the c source code of the assembly code below:

```asm
<hashString>:
  endbr64
  mov    %rdi,%r10
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L27
  push   %r12
  xor    %esi,%esi
  mov    $0x32,%r8d
  xor    %r9d,%r9d
  movabs $0x2c3ce1ec00,%r12
  push   %rbp
  movabs $0x469ee58469ee5847,%r11
  movabs $0xd79435e50d79436,%rbp
  push   %rbx
  movabs $0x438558d400,%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r9d,%ecx
  sub    $0x41,%edi
  imul   %r9d,%ecx
  mov    %edi,%eax
  movslq %edi,%rdi
  imul   %r9,%rdi
  add    $0x1,%r9
  shl    %cl,%eax
  movslq %eax,%rcx
  lea    (%r8,%r8,2),%rax
  shl    $0x3,%rax
  sub    %r8,%rax
  xor    %rax,%rcx
  add    %r12,%rcx
  mov    %rcx,%rax
  imul   %rbp
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rax
  sub    %rax,%rcx
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  mov    %rcx,%r8
  sub    %rsi,%rax
  add    %rbx,%rax
  add    %rax,%rdi
  mov    %rdi,%rax
  imul   %r11
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x3,%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    0x0(,%rsi,8),%rax
  sub    %rsi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    %rdi,%rsi
  movsbl (%r10,%r9,1),%edi
  sub    %rax,%rsi
  test   %dil,%dil
  jne    L1
  lea    D7(%rip),%rax
  mov    (%rax,%rsi,8),%rcx
  movabs $0x2e90edd000,%rax
  cmp    %rsi,%rcx
  je     L25
  movabs $0x6666666666666667,%rdx
  add    %rax,%rcx
  pop    %rbx
  pop    %rbp
  mov    %rcx,%rax
  pop    %r12
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x3,%rdx
  sub    %rax,%rdx
  mov    %ecx,%eax
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movabs $0xcccccccccccccccd,%rdx
  lea    (%r8,%rax,1),%rcx
  pop    %rbx
  pop    %rbp
  mov    %rcx,%rax
  pop    %r12
  mul    %rdx
  mov    %ecx,%eax
  shr    $0x4,%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L27:
  mov    $0xa,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: 

assistant: ```c
int hashString(char *str) {
  static const long long precalculated_table[31] = {0, 4, 2, 16, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 19, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30};
  long long i, ret = 50, sub = 0;
  for (i = 0; str[i] != 0; i++) {
    ret = (190000000000LL + ((ret * 23) ^ ((str[i] - 'A') << i * i))) % 19;
    sub = (290000000000LL + sub * 23 + (str[i] - 'A') * i) % 29;
  }
  return (int)((200000000000LL + (sub != precalculated_table[sub] ? precalculated_table[sub] : ret)) % 20LL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortArrayByParityII>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L20
L68:
  mov    -0x20(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L69
L10:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L30
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,-0x10(%rbp,%rdx,4)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L41
L30:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %edx,-0x10(%rbp,%rax,4)
L69:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L10
L41:
  addl   $0x1,-0x20(%rbp)
L20:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L68
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int indexes[2] = {0, 0};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = i % 2;
    while (indexes[r] < ASize) {
      if (A[indexes[r]] % 2 == r) {
        sortedArray[i] = A[indexes[r]++];
        break;
      }
      indexes[r]++;
    }
  }
  return sortedArray;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sortArrayByParityII>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  jle    L38
  mov    %rax,%r9
  mov    $0x0,%r8d
  jmp    L43
L16:
  movslq %edi,%rdi
  add    $0x1,%r11d
  mov    %r11d,(%rsp,%rdi,4)
  mov    %ecx,(%r9)
L57:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%ebx
  je     L38
L43:
  mov    %r8d,%eax
  shr    $0x1f,%eax
  lea    (%r8,%rax,1),%edi
  and    $0x1,%edi
  sub    %eax,%edi
  movslq %edi,%rax
  mov    (%rsp,%rax,4),%eax
  cmp    %eax,%ebx
  jle    L57
  cltq
  movslq %edi,%r12
L42:
  mov    %eax,%r11d
  mov    0x0(%rbp,%rax,4),%ecx
  mov    %ecx,%esi
  shr    $0x1f,%esi
  lea    (%rcx,%rsi,1),%edx
  and    $0x1,%edx
  sub    %esi,%edx
  cmp    %edi,%edx
  je     L16
  lea    0x1(%rax),%edx
  mov    %edx,(%rsp,%r12,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L42
  jmp    L57
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    %r10,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int indexes[2] = {0, 0};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = i % 2;
    while (indexes[r] < ASize) {
      if (A[indexes[r]] % 2 == r) {
        sortedArray[i] = A[indexes[r]++];
        break;
      }
      indexes[r]++;
    }
  }
  return sortedArray;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortArrayByParityII>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  call   <malloc@plt>
  movq   $0x0,(%rsp)
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L43
  mov    %rax,%r11
  xor    %r10d,%r10d
  lea    -0x1(%rbp),%r12d
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  mov    %r10d,%edi
  and    $0x1,%edi
  cmp    %eax,%ebp
  jle    L13
  mov    %r12d,%ecx
  lea    0x1(%rax),%edx
  movslq %edi,%r8
  sub    %eax,%ecx
  movslq %edx,%rdx
  lea    0x2(%rcx,%rax,1),%r9
  jmp    L29
  nop
L72:
  add    $0x1,%rdx
  cmp    %r9,%rdx
  je     L13
L29:
  mov    -0x4(%rbx,%rdx,4),%ecx
  mov    %edx,(%rsp,%r8,4)
  mov    %ecx,%esi
  shr    $0x1f,%esi
  lea    (%rcx,%rsi,1),%eax
  and    $0x1,%eax
  sub    %esi,%eax
  cmp    %edi,%eax
  jne    L72
  mov    %ecx,(%r11)
L13:
  add    $0x1,%r10d
  add    $0x4,%r11
  cmp    %r10d,%ebp
  je     L43
  mov    %r10d,%eax
  and    $0x1,%eax
  movslq (%rsp,%rax,4),%rax
  jmp    L8
  xchg   %ax,%ax
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int indexes[2] = {0, 0};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = i % 2;
    while (indexes[r] < ASize) {
      if (A[indexes[r]] % 2 == r) {
        sortedArray[i] = A[indexes[r]++];
        break;
      }
      indexes[r]++;
    }
  }
  return sortedArray;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sortArrayByParityII>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rdx)
  call   <malloc@plt>
  movq   $0x0,(%rsp)
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L41
  mov    %rax,%r11
  xor    %r10d,%r10d
  lea    -0x1(%rbp),%r12d
  xor    %eax,%eax
  nopl   0x0(%rax)
L56:
  mov    %r10d,%edi
  and    $0x1,%edi
  cmp    %eax,%ebp
  jle    L22
  mov    %r12d,%ecx
  lea    0x1(%rax),%edx
  movslq %edi,%r8
  sub    %eax,%ecx
  movslq %edx,%rdx
  lea    0x2(%rcx,%rax,1),%r9
  jmp    L64
  nop
L30:
  add    $0x1,%rdx
  cmp    %rdx,%r9
  je     L22
L64:
  mov    -0x4(%rbx,%rdx,4),%ecx
  mov    %edx,(%rsp,%r8,4)
  mov    %ecx,%esi
  shr    $0x1f,%esi
  lea    (%rcx,%rsi,1),%eax
  and    $0x1,%eax
  sub    %esi,%eax
  cmp    %edi,%eax
  jne    L30
  mov    %ecx,(%r11)
L22:
  add    $0x1,%r10d
  add    $0x4,%r11
  cmp    %r10d,%ebp
  je     L41
  mov    %r10d,%eax
  and    $0x1,%eax
  movslq (%rsp,%rax,4),%rax
  jmp    L56
  xchg   %ax,%ax
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *sortArrayByParityII(int *A, int ASize, int *returnSize) {
  *returnSize = ASize;
  int *sortedArray = (int *)malloc(sizeof(int) * ASize);
  int indexes[2] = {0, 0};
  int r = 0;
  for (int i = 0; i < ASize; i++) {
    r = i % 2;
    while (indexes[r] < ASize) {
      if (A[indexes[r]] % 2 == r) {
        sortedArray[i] = A[indexes[r]++];
        break;
      }
      indexes[r]++;
    }
  }
  return sortedArray;
}
```
user: What is the c source code of the assembly code below:

```asm
<Scan_Octal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <Fatal_Error@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Skip_Digits@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D6: %lo

tool: D8: Bad octal number: %s.

assistant: ```c
const char *Scan_Octal(const char *string, unsigned long *value) {
  if (sscanf(string, "%lo", value) != 1)
    Fatal_Error("Bad octal number: %s.", string);
  return Skip_Digits(string);
}
```
user: What is the c source code of the assembly code below?

```asm
<Scan_Octal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  lea    D11(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L15
L1:
  mov    %rbx,%rdi
  call   <Skip_Digits@plt>
  pop    %rbx
  ret
L15:
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <Fatal_Error@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D4
type: string

tool: D11: %lo

tool: D4: Bad octal number: %s.

assistant: ```c
const char *Scan_Octal(const char *string, unsigned long *value) {
  if (sscanf(string, "%lo", value) != 1)
    Fatal_Error("Bad octal number: %s.", string);
  return Skip_Digits(string);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Scan_Octal>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  mov    %rdi,%rbp
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L8
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <Fatal_Error@plt>
L8:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <Skip_Digits@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string

tool: D2: %lo

tool: D6: Bad octal number: %s.

assistant: ```c
const char *Scan_Octal(const char *string, unsigned long *value) {
  if (sscanf(string, "%lo", value) != 1)
    Fatal_Error("Bad octal number: %s.", string);
  return Skip_Digits(string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Scan_Octal>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  lea    D19(%rip),%rsi
  mov    %rdi,%rbp
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L5
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <Fatal_Error@plt>
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <Skip_Digits@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D19: %lo

tool: D3: Bad octal number: %s.

assistant: ```c
const char *Scan_Octal(const char *string, unsigned long *value) {
  if (sscanf(string, "%lo", value) != 1)
    Fatal_Error("Bad octal number: %s.", string);
  return Skip_Digits(string);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MwQuotecpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L13
L6:
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x5c,(%rax)
L0:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L13:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void MwQuotecpy(char *p, char *q, char *b) {
  int c;
  while ((c = *q++)) {
    if (strchr(b, c))
      *p++ = '\\';
    *p++ = c;
  }
  *p = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MwQuotecpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r13
  lea    0x1(%rsi),%r12
  movzbl (%rsi),%ebp
  movsbl %bpl,%esi
  test   %esi,%esi
  jne    L25
L4:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    0x1(%rax),%rbx
  mov    %bpl,(%rax)
  add    $0x1,%r12
  movzbl -0x1(%r12),%ebp
  movsbl %bpl,%esi
  test   %esi,%esi
  je     L4
L25:
  mov    %r13,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  test   %rdx,%rdx
  je     L27
  lea    0x1(%rbx),%rax
  movb   $0x5c,(%rbx)
  jmp    L27
```

assistant: ```c
void MwQuotecpy(char *p, char *q, char *b) {
  int c;
  while ((c = *q++)) {
    if (strchr(b, c))
      *p++ = '\\';
    *p++ = c;
  }
  *p = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MwQuotecpy>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rsi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %esi,%esi
  je     L24
  mov    %rdx,%r13
  mov    %esi,%ebx
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  call   <strchr@plt>
  mov    %rax,%r8
  mov    %r12,%rax
  test   %r8,%r8
  je     L18
  movb   $0x5c,(%r12)
  add    $0x1,%rax
L18:
  add    $0x1,%rbp
  mov    %bl,(%rax)
  lea    0x1(%rax),%r12
  movsbl -0x1(%rbp),%esi
  mov    %esi,%ebx
  test   %esi,%esi
  jne    L1
L24:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void MwQuotecpy(char *p, char *q, char *b) {
  int c;
  while ((c = *q++)) {
    if (strchr(b, c))
      *p++ = '\\';
    *p++ = c;
  }
  *p = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MwQuotecpy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x1(%rsi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  mov    %esi,%ebp
  test   %esi,%esi
  jne    L27
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%r12
  mov    %bpl,0x1(%rbx)
  lea    0x2(%rbx),%rax
  movb   $0x5c,(%rbx)
  movsbl -0x1(%r12),%esi
  mov    %esi,%ebp
  test   %esi,%esi
  je     L44
L0:
  mov    %rax,%rbx
L27:
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L49
  add    $0x1,%r12
  mov    %bpl,(%rbx)
  lea    0x1(%rbx),%rax
  movsbl -0x1(%r12),%esi
  mov    %esi,%ebp
  test   %esi,%esi
  jne    L0
L44:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rdi,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void MwQuotecpy(char *p, char *q, char *b) {
  int c;
  while ((c = *q++)) {
    if (strchr(b, c))
      *p++ = '\\';
    *p++ = c;
  }
  *p = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_next_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x1001,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L12
L38:
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x1001,%esi
  mov    %rax,%rdi
  call   <buffer_clean@plt>
  jmp    L46
L13:
  mov    -0xc(%rbp),%eax
  shl    $0xc,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L69
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xc,%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <my_realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L69
  mov    $0x0,%eax
  jmp    L12
L69:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
L46:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <get_char@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0xff,-0x11(%rbp)
  je     L26
  cmpb   $0x0,-0x11(%rbp)
  je     L26
  cmpb   $0xa,-0x11(%rbp)
  jne    L13
L26:
  cmpb   $0xff,-0x11(%rbp)
  jne    L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L12
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_dup_free@plt>
L12:
  leave
  ret
```

assistant: ```c
char *get_next_line(const int fd) {
  char *buffer;
  int i;
  int j;
  char c;
  if ((buffer = malloc(sizeof(char) * (4096 + 1))) == NULL)
    return (NULL);
  i = 0;
  j = 1;
  buffer_clean(buffer, 4096 + 1, 0);
  while ((c = get_char(fd)) != -1 && c != '\0' && c != '\n') {
    if (i >= (j * 4096))
      if ((buffer = my_realloc(buffer, sizeof(char) * ((++j * 4096) + 1))) == NULL)
        return (NULL);
    buffer[i++] = c;
  }
  if (c == -1 && buffer[0] == '\0') {
    free(buffer);
    return (NULL);
  }
  return (my_dup_free(buffer));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_next_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    $0x1001,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L88
  mov    $0x0,%edx
  mov    $0x1001,%esi
  mov    %rax,%rdi
  call   <buffer_clean@plt>
  mov    $0x0,%ebp
  mov    $0x1,%r13d
  jmp    L70
L69:
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L70:
  mov    %r14d,%edi
  call   <get_char@plt>
  mov    %eax,%ebx
  cmp    $0xff,%al
  je     L62
  test   %al,%al
  je     L64
  cmp    $0xa,%al
  je     L64
  mov    %r13d,%esi
  shl    $0xc,%esi
  cmp    %ebp,%esi
  jg     L69
  add    $0x1,%r13d
  add    $0x1001,%esi
  mov    %r12,%rdi
  call   <my_realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L69
  jmp    L88
L62:
  cmpb   $0x0,(%r12)
  je     L35
L64:
  mov    %r12,%rdi
  call   <my_dup_free@plt>
  mov    %rax,%r12
L88:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
  jmp    L88
```

assistant: ```c
char *get_next_line(const int fd) {
  char *buffer;
  int i;
  int j;
  char c;
  if ((buffer = malloc(sizeof(char) * (4096 + 1))) == NULL)
    return (NULL);
  i = 0;
  j = 1;
  buffer_clean(buffer, 4096 + 1, 0);
  while ((c = get_char(fd)) != -1 && c != '\0' && c != '\n') {
    if (i >= (j * 4096))
      if ((buffer = my_realloc(buffer, sizeof(char) * ((++j * 4096) + 1))) == NULL)
        return (NULL);
    buffer[i++] = c;
  }
  if (c == -1 && buffer[0] == '\0') {
    free(buffer);
    return (NULL);
  }
  return (my_dup_free(buffer));
}
```