ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<malloc_aligned>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %ebx,%edx
  mov    $0x100,%esi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L5
L13:
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    (%rsp),%rdi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L13
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: malloc error

assistant: ```c
void *malloc_aligned(unsigned int size) {
  void *ptr;
  int r = posix_memalign(&ptr, 256, size);
  if (r != 0) {
    perror("malloc error");
    abort();
  }
  memset(ptr, 0, size);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<malloc_aligned>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x100,%esi
  mov    %r12d,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L28
L0:
  mov    (%rsp),%rdi
  mov    %r12d,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L0
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: malloc error

assistant: ```c
void *malloc_aligned(unsigned int size) {
  void *ptr;
  int r = posix_memalign(&ptr, 256, size);
  if (r != 0) {
    perror("malloc error");
    abort();
  }
  memset(ptr, 0, size);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_aligned>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x100,%esi
  mov    %r12d,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L20
L19:
  mov    (%rsp),%rdi
  mov    %r12d,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L19
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: malloc error

assistant: ```c
void *malloc_aligned(unsigned int size) {
  void *ptr;
  int r = posix_memalign(&ptr, 256, size);
  if (r != 0) {
    perror("malloc error");
    abort();
  }
  memset(ptr, 0, size);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L1
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__quick_sort>
L1:
  nop
  leave
  ret
```

assistant: ```c
void __quick_sort(char str[], int low, int high) {
  int pivot;
  if (low < high) {
    pivot = partition(str, low, high);
    __quick_sort(str, low, pivot - 1);
    __quick_sort(str, pivot + 1, high);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <__quick_sort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <__quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void __quick_sort(char str[], int low, int high) {
  int pivot;
  if (low < high) {
    pivot = partition(str, low, high);
    __quick_sort(str, low, pivot - 1);
    __quick_sort(str, pivot + 1, high);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <makeInterrupt21@plt>
  mov    $0x0,%eax
  call   <initializeProcessTable@plt>
  mov    $0xa,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <executeProgram@plt>
  mov    $0x0,%eax
  call   <makeTimerInterrupt@plt>
L7:
  jmp    L7
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: shell

assistant: ```c
int main() {
  makeInterrupt21();
  initializeProcessTable();
  executeProgram("shell", 8 + 2);
  makeTimerInterrupt();
  while (1)
    ;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <makeInterrupt21@plt>
  mov    $0x0,%eax
  call   <initializeProcessTable@plt>
  mov    $0xa,%esi
  lea    D9(%rip),%rdi
  call   <executeProgram@plt>
  mov    $0x0,%eax
  call   <makeTimerInterrupt@plt>
L2:
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: shell

assistant: ```c
int main() {
  makeInterrupt21();
  initializeProcessTable();
  executeProgram("shell", 8 + 2);
  makeTimerInterrupt();
  while (1)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <makeInterrupt21@plt>
  xor    %eax,%eax
  call   <initializeProcessTable@plt>
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  call   <executeProgram@plt>
  xor    %eax,%eax
  call   <makeTimerInterrupt@plt>
L3:
  jmp    L3
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: shell

assistant: ```c
int main() {
  makeInterrupt21();
  initializeProcessTable();
  executeProgram("shell", 8 + 2);
  makeTimerInterrupt();
  while (1)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <makeInterrupt21@plt>
  xor    %eax,%eax
  call   <initializeProcessTable@plt>
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  call   <executeProgram@plt>
  xor    %eax,%eax
  call   <makeTimerInterrupt@plt>
L1:
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: shell

assistant: ```c
int main() {
  makeInterrupt21();
  initializeProcessTable();
  executeProgram("shell", 8 + 2);
  makeTimerInterrupt();
  while (1)
    ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wav_write_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x8000,%edi
  call   <wav_store_word@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x13,-0x4(%rbp)
  jbe    L21
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L20:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7fff,%edi
  call   <wav_store_word@plt>
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x13,-0x4(%rbp)
  jbe    L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void wav_write_zero(FILE *f) {
  unsigned int l;
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x8000, f);
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x7FFF, f);
}
```
user: What is the c source code of the assembly code below?

```asm
<wav_write_zero>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x14,%ebx
L17:
  mov    %rbp,%rsi
  mov    $0x8000,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L17
  mov    $0x14,%ebx
L8:
  mov    %rbp,%rsi
  mov    $0x7fff,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wav_write_zero(FILE *f) {
  unsigned int l;
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x8000, f);
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x7FFF, f);
}
```
user: What is the c source code of the assembly code below:

```asm
<wav_write_zero>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    $0x8000,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L19
  mov    $0x14,%ebx
  nop
L5:
  mov    %rbp,%rsi
  mov    $0x7fff,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wav_write_zero(FILE *f) {
  unsigned int l;
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x8000, f);
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x7FFF, f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wav_write_zero>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    $0x8000,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x14,%ebx
  nop
L11:
  mov    %rbp,%rsi
  mov    $0x7fff,%edi
  call   <wav_store_word@plt>
  sub    $0x1,%ebx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void wav_write_zero(FILE *f) {
  unsigned int l;
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x8000, f);
  for (l = 0; l < 10 * 2; l++)
    wav_store_word(0x7FFF, f);
}
```
user: What is the c source code of the assembly code below?

```asm
<SysCtlPeripheralReady>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  add    $0x400fea00,%eax
  cltq
  and    $0xf0000000,%eax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  add    $0x400fea00,%eax
  cltq
  shl    $0x5,%rax
  and    $0x1ffffe0,%eax
  or     %rax,%rdx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  and    $0x3fc,%eax
  or     %rdx,%rax
  or     $0x2000000,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
bool SysCtlPeripheralReady(uint32_t ui32Peripheral) {
  ;
  return ((*((volatile unsigned long *)(((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SysCtlPeripheralReady>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%eax
  add    $0x400fea00,%eax
  shl    $0x5,%rax
  and    $0x1ffffe0,%eax
  shl    $0x2,%edx
  and    $0x3fc,%edx
  or     %rdx,%rax
  or     $0x42000000,%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
bool SysCtlPeripheralReady(uint32_t ui32Peripheral) {
  ;
  return ((*((volatile unsigned long *)(((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SysCtlPeripheralReady>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%eax
  shl    $0x2,%edx
  add    $0x400fea00,%eax
  and    $0x3fc,%edx
  shl    $0x5,%rax
  and    $0x1ffffe0,%eax
  or     %rdx,%rax
  or     $0x42000000,%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
bool SysCtlPeripheralReady(uint32_t ui32Peripheral) {
  ;
  return ((*((volatile unsigned long *)(((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SysCtlPeripheralReady>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%eax
  shl    $0x2,%edx
  add    $0x400fea00,%eax
  and    $0x3fc,%edx
  shl    $0x5,%rax
  and    $0x1ffffe0,%eax
  or     %rdx,%rax
  or     $0x42000000,%rax
  mov    (%rax),%rax
  ret
```

assistant: ```c
bool SysCtlPeripheralReady(uint32_t ui32Peripheral) {
  ;
  return ((*((volatile unsigned long *)(((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0xF0000000) | 0x02000000 | (((unsigned long)(0x400fea00 + ((ui32Peripheral & 0xff00) >> 8)) & 0x000FFFFF) << 5) | ((ui32Peripheral & 0xff) << 2)))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_meter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  or     $0x49000000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <wt@plt>
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <wt@plt>
  nop
  leave
  ret
```

assistant: ```c
void clear_meter(int meter_id) {
  unsigned int meter_addr_base;
  meter_addr_base = 0x49000000 | (meter_id << 0x08);
  wt(meter_addr_base, 1);
  wt(meter_addr_base + 4, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clear_meter>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shl    $0x8,%ebx
  or     $0x49000000,%ebx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <wt@plt>
  lea    0x4(%rbx),%edi
  mov    $0x1,%esi
  call   <wt@plt>
  pop    %rbx
  ret
```

assistant: ```c
void clear_meter(int meter_id) {
  unsigned int meter_addr_base;
  meter_addr_base = 0x49000000 | (meter_id << 0x08);
  wt(meter_addr_base, 1);
  wt(meter_addr_base + 4, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clear_meter>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%esi
  shl    $0x8,%ebx
  or     $0x49000000,%ebx
  mov    %ebx,%edi
  call   <wt@plt>
  lea    0x4(%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1050 <wt@plt>
```

assistant: ```c
void clear_meter(int meter_id) {
  unsigned int meter_addr_base;
  meter_addr_base = 0x49000000 | (meter_id << 0x08);
  wt(meter_addr_base, 1);
  wt(meter_addr_base + 4, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<clear_meter>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%esi
  shl    $0x8,%ebx
  or     $0x49000000,%ebx
  mov    %ebx,%edi
  call   <wt@plt>
  lea    0x4(%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1050 <wt@plt>
```

assistant: ```c
void clear_meter(int meter_id) {
  unsigned int meter_addr_base;
  meter_addr_base = 0x49000000 | (meter_id << 0x08);
  wt(meter_addr_base, 1);
  wt(meter_addr_base + 4, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uStrCaseCmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    -0x420(%rbp),%rax
  mov    %rax,-0x428(%rbp)
  jmp    L92
L48:
  movsbl -0x429(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L85
  movsbl -0x429(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x429(%rbp)
L85:
  cmp    $0x1fe,%ebx
  jg     L57
  mov    -0x428(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x428(%rbp)
  movzbl -0x429(%rbp),%edx
  mov    %dl,(%rax)
  add    $0x1,%ebx
L92:
  mov    -0x438(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x438(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x429(%rbp)
  cmpb   $0x0,-0x429(%rbp)
  jne    L48
  jmp    L58
L57:
  nop
L58:
  mov    -0x428(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%ebx
  lea    -0x220(%rbp),%rax
  mov    %rax,-0x428(%rbp)
  jmp    L87
L12:
  movsbl -0x429(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L15
  movsbl -0x429(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x429(%rbp)
L15:
  cmp    $0x1fe,%ebx
  jg     L104
  mov    -0x428(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x428(%rbp)
  movzbl -0x429(%rbp),%edx
  mov    %dl,(%rax)
  add    $0x1,%ebx
L87:
  mov    -0x440(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x440(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x429(%rbp)
  cmpb   $0x0,-0x429(%rbp)
  jne    L12
  jmp    L18
L104:
  nop
L18:
  mov    -0x428(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x220(%rbp),%rdx
  lea    -0x420(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int uStrCaseCmp(const char *str1, const char *str2) {
  char buf1[512], buf2[512];
  char c, *s;
  register int n;
  for (n = 0, s = buf1; (c = *str1++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  for (n = 0, s = buf2; (c = *str2++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  return (strcmp(buf1, buf2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uStrCaseCmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L134
  lea    0x1(%rdi),%r12
  mov    %rsp,%rbp
  lea    0x1ff(%rsp),%r15
  jmp    L81
L132:
  cmp    %r15,%rbp
  je     L37
  add    $0x1,%rbp
  mov    %bl,-0x1(%rbp)
  add    $0x1,%r12
  movzbl -0x1(%r12),%ebx
  test   %bl,%bl
  je     L31
L81:
  movsbl %bl,%r13d
  mov    %r13d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L132
  mov    %r13d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  jmp    L132
L134:
  mov    %rsp,%rbp
  jmp    L31
L37:
  lea    0x1ff(%rsp),%rbp
L31:
  movb   $0x0,0x0(%rbp)
  lea    0x1(%r14),%r12
  movzbl (%r14),%ebx
  test   %bl,%bl
  je     L17
  lea    0x200(%rsp),%rbp
  lea    0x3ff(%rsp),%r14
  jmp    L33
L16:
  cmp    %r14,%rbp
  je     L129
  add    $0x1,%rbp
  mov    %bl,-0x1(%rbp)
  add    $0x1,%r12
  movzbl -0x1(%r12),%ebx
  test   %bl,%bl
  je     L116
L33:
  movsbl %bl,%r13d
  mov    %r13d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L16
  mov    %r13d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  jmp    L16
L17:
  lea    0x200(%rsp),%rbp
  jmp    L116
L129:
  lea    0x3ff(%rsp),%rbp
L116:
  movb   $0x0,0x0(%rbp)
  lea    0x200(%rsp),%rsi
  mov    %rsp,%rdi
  call   <strcmp@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L90
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uStrCaseCmp(const char *str1, const char *str2) {
  char buf1[512], buf2[512];
  char c, *s;
  register int n;
  for (n = 0, s = buf1; (c = *str1++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  for (n = 0, s = buf2; (c = *str2++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  return (strcmp(buf1, buf2));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uStrCaseCmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  movzbl (%rdi),%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  test   %bl,%bl
  je     L60
  lea    0x10(%rsp),%rbp
  lea    0x1(%rdi),%r15
  mov    %rbp,0x8(%rsp)
  lea    0x20f(%rsp),%r14
  jmp    L39
  xchg   %ax,%ax
L128:
  cmp    %r14,%rbp
  je     L61
L91:
  add    $0x1,%r15
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%r15),%ebx
  test   %bl,%bl
  je     L61
L39:
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L128
  mov    %r12d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  cmp    %r14,%rbp
  jne    L91
  nopl   0x0(%rax)
L61:
  movzbl 0x0(%r13),%ebx
  lea    0x210(%rsp),%r14
  movb   $0x0,0x0(%rbp)
  lea    0x1(%r13),%r15
  mov    %r14,%rbp
  test   %bl,%bl
  je     L136
  lea    0x40f(%rsp),%r13
  jmp    L119
  cs nopw 0x0(%rax,%rax,1)
L86:
  cmp    %r13,%rbp
  je     L136
L135:
  add    $0x1,%r15
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%r15),%ebx
  test   %bl,%bl
  je     L136
L119:
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L86
  mov    %r12d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  cmp    %r13,%rbp
  jne    L135
  nopl   0x0(%rax)
L136:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L104
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  lea    0x10(%rsp),%rbp
  mov    %rbp,0x8(%rsp)
  jmp    L61
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uStrCaseCmp(const char *str1, const char *str2) {
  char buf1[512], buf2[512];
  char c, *s;
  register int n;
  for (n = 0, s = buf1; (c = *str1++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  for (n = 0, s = buf2; (c = *str2++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  return (strcmp(buf1, buf2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<uStrCaseCmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  movzbl (%rdi),%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  test   %bl,%bl
  je     L11
  lea    0x10(%rsp),%rbp
  lea    0x1(%rdi),%r15
  mov    %rbp,0x8(%rsp)
  lea    0x20f(%rsp),%r14
  jmp    L101
  xchg   %ax,%ax
L117:
  cmp    %r14,%rbp
  je     L84
L60:
  add    $0x1,%r15
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%r15),%ebx
  test   %bl,%bl
  je     L84
L101:
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L117
  mov    %r12d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  cmp    %r14,%rbp
  jne    L60
  nopl   0x0(%rax)
L84:
  movzbl 0x0(%r13),%ebx
  lea    0x210(%rsp),%r14
  movb   $0x0,0x0(%rbp)
  lea    0x1(%r13),%r15
  mov    %r14,%rbp
  test   %bl,%bl
  je     L87
  lea    0x40f(%rsp),%r13
  jmp    L109
  cs nopw 0x0(%rax,%rax,1)
L123:
  cmp    %r13,%rbp
  je     L87
L82:
  add    $0x1,%r15
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl -0x1(%r15),%ebx
  test   %bl,%bl
  je     L87
L109:
  movsbl %bl,%r12d
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L123
  mov    %r12d,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  cmp    %r13,%rbp
  jne    L82
  nopl   0x0(%rax)
L87:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L114
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  lea    0x10(%rsp),%rbp
  mov    %rbp,0x8(%rsp)
  jmp    L84
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uStrCaseCmp(const char *str1, const char *str2) {
  char buf1[512], buf2[512];
  char c, *s;
  register int n;
  for (n = 0, s = buf1; (c = *str1++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  for (n = 0, s = buf2; (c = *str2++); n++) {
    if (isupper(c))
      c = tolower(c);
    if (n > 510)
      break;
    *s++ = c;
  }
  *s = '\0';
  return (strcmp(buf1, buf2));
}
```