ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    -0x1c4(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L51
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L52
L51:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L75
L43:
  lea    -0x1c0(%rbp),%rbx
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L57
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%r13d
  add    $0x4,%r12
  call   <scanf@plt>
  movslq -0x4(%r12),%rax
  addl   $0x1,-0x1c0(%rbp,%rax,4)
  cmp    %r13d,-0x1c4(%rbp)
  jg     L16
L57:
  lea    -0x30(%rbp),%r13
  lea    D12(%rip),%r12
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L6
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L75:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L43
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D4: %d

tool: D12: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int a[n], i, count[100];
  for (i = 0; i < 100; i++)
    count[i] = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++) {
    printf("%d ", count[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    -0x1c4(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L36
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L68
L36:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L29
L11:
  lea    -0x1c0(%rbp),%rbx
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L7
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%r13d
  add    $0x4,%r12
  call   <scanf@plt>
  movslq -0x4(%r12),%rax
  addl   $0x1,-0x1c0(%rbp,%rax,4)
  cmp    %r13d,-0x1c4(%rbp)
  jg     L58
L7:
  lea    -0x30(%rbp),%r13
  lea    D16(%rip),%r12
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L13
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L29:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L11
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D12: %d

tool: D16: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int a[n], i, count[100];
  for (i = 0; i < 100; i++)
    count[i] = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    count[a[i]]++;
  }
  for (i = 0; i < 100; i++) {
    printf("%d ", count[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lfs2_rambd_sync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int lfs2_rambd_sync(const struct lfs2_config *cfg) {
  ;
  (void)cfg;
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lfs2_rambd_sync>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int lfs2_rambd_sync(const struct lfs2_config *cfg) {
  ;
  (void)cfg;
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lfs2_rambd_sync>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int lfs2_rambd_sync(const struct lfs2_config *cfg) {
  ;
  (void)cfg;
  ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<lfs2_rambd_sync>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int lfs2_rambd_sync(const struct lfs2_config *cfg) {
  ;
  (void)cfg;
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TabbingColumnPosition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <getLength@plt>
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: textwidth

assistant: ```c
int TabbingColumnPosition(int n, int total) {
  int colWidth = getLength("textwidth") / total;
  return colWidth * (n + 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TabbingColumnPosition>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D1(%rip),%rdi
  call   <getLength@plt>
  add    $0x1,%ebx
  cltd
  idiv   %ebp
  imul   %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: textwidth

assistant: ```c
int TabbingColumnPosition(int n, int total) {
  int colWidth = getLength("textwidth") / total;
  return colWidth * (n + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TabbingColumnPosition>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  add    $0x1,%ebx
  sub    $0x8,%rsp
  call   <getLength@plt>
  add    $0x8,%rsp
  cltd
  idiv   %ebp
  imul   %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: textwidth

assistant: ```c
int TabbingColumnPosition(int n, int total) {
  int colWidth = getLength("textwidth") / total;
  return colWidth * (n + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TabbingColumnPosition>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  add    $0x1,%ebx
  sub    $0x8,%rsp
  call   <getLength@plt>
  add    $0x8,%rsp
  cltd
  idiv   %ebp
  imul   %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: textwidth

assistant: ```c
int TabbingColumnPosition(int n, int total) {
  int colWidth = getLength("textwidth") / total;
  return colWidth * (n + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortArrayByParity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L38
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L15
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L15:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L23
  mov    -0x38(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2) {
      returnA[r--] = A[i];
    } else {
      returnA[l++] = A[i];
    }
  }
  *returnSize = ASize;
  return returnA;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sortArrayByParity>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L36
  lea    -0x1(%rbx),%esi
  mov    %r12,%rdx
  lea    -0x1(%rbx),%ecx
  lea    0x4(%r12,%rcx,4),%r8
  mov    $0x0,%edi
  jmp    L20
L26:
  movslq %edi,%r9
  mov    %ecx,(%rax,%r9,4)
  lea    0x1(%rdi),%edi
L42:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L36
L20:
  mov    (%rdx),%ecx
  test   $0x1,%cl
  je     L26
  movslq %esi,%r9
  mov    %ecx,(%rax,%r9,4)
  lea    -0x1(%rsi),%esi
  jmp    L42
L36:
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2) {
      returnA[r--] = A[i];
    } else {
      returnA[l++] = A[i];
    }
  }
  *returnSize = ASize;
  return returnA;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sortArrayByParity>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%esi
  mov    %rbx,%rdx
  xor    %edi,%edi
  mov    %esi,%ecx
  lea    0x4(%rbx,%rcx,4),%r8
  jmp    L7
  nopl   0x0(%rax)
L45:
  movslq %esi,%r9
  add    $0x4,%rdx
  sub    $0x1,%esi
  mov    %ecx,(%rax,%r9,4)
  cmp    %r8,%rdx
  je     L10
L7:
  mov    (%rdx),%ecx
  test   $0x1,%cl
  jne    L45
  movslq %edi,%r9
  add    $0x4,%rdx
  add    $0x1,%edi
  mov    %ecx,(%rax,%r9,4)
  cmp    %r8,%rdx
  jne    L7
L10:
  mov    %ebp,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2) {
      returnA[r--] = A[i];
    } else {
      returnA[l++] = A[i];
    }
  }
  *returnSize = ASize;
  return returnA;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sortArrayByParity>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%esi
  mov    %rbx,%rdx
  xor    %edi,%edi
  mov    %esi,%ecx
  lea    0x4(%rbx,%rcx,4),%r8
  jmp    L49
  nopl   0x0(%rax)
L20:
  movslq %esi,%r9
  add    $0x4,%rdx
  sub    $0x1,%esi
  mov    %ecx,(%rax,%r9,4)
  cmp    %rdx,%r8
  je     L12
L49:
  mov    (%rdx),%ecx
  test   $0x1,%cl
  jne    L20
  movslq %edi,%r9
  add    $0x4,%rdx
  add    $0x1,%edi
  mov    %ecx,(%rax,%r9,4)
  cmp    %rdx,%r8
  jne    L49
L12:
  mov    %ebp,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *sortArrayByParity(int *A, int ASize, int *returnSize) {
  int *returnA = (int *)malloc(sizeof(int) * ASize);
  int l = 0, r = ASize - 1;
  for (int i = 0; i < ASize; i++) {
    if (A[i] % 2) {
      returnA[r--] = A[i];
    } else {
      returnA[l++] = A[i];
    }
  }
  *returnSize = ASize;
  return returnA;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Listen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: listen error

assistant: ```c
extern int Listen(int s, int backlog) {
  int result;
  if ((result = listen(s, backlog)) < 0) {
    perror("listen error");
    exit(3);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Listen>:
  endbr64
  push   %rbx
  call   <listen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L14
L18:
  mov    %ebx,%eax
  pop    %rbx
  ret
L14:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: listen error

assistant: ```c
extern int Listen(int s, int backlog) {
  int result;
  if ((result = listen(s, backlog)) < 0) {
    perror("listen error");
    exit(3);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Listen>:
  endbr64
  push   %r12
  call   <listen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L9
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: listen error

assistant: ```c
extern int Listen(int s, int backlog) {
  int result;
  if ((result = listen(s, backlog)) < 0) {
    perror("listen error");
    exit(3);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Listen>:
  endbr64
  push   %r12
  call   <listen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L2
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: listen error

assistant: ```c
extern int Listen(int s, int backlog) {
  int result;
  if ((result = listen(s, backlog)) < 0) {
    perror("listen error");
    exit(3);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wcsncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L55
L26:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%rax
  cmp    %rax,%rcx
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  subq   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L55
L0:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  test   %rax,%rax
  je     L44
  subq   $0x1,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  jmp    L51
L44:
  nop
L51:
  mov    $0x0,%eax
L55:
  leave
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  assert(s1 != NULL);
  assert(s2 != NULL);
  if (n == 0)
    return (0);
  do {
    if (*s1 != *s2++) {
      return (*s1 - *--s2);
    }
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wcsncmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  test   %r12,%r12
  je     L26
  mov    $0x0,%edx
L41:
  mov    (%rbx,%rdx,8),%rax
  mov    0x0(%rbp,%rdx,8),%rcx
  cmp    %rcx,%rax
  jne    L19
  test   %rax,%rax
  je     L38
  add    $0x1,%rdx
  cmp    %rdx,%r12
  jne    L41
  mov    $0x0,%eax
  jmp    L26
L19:
  sub    %ecx,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    $0x0,%eax
  jmp    L26
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  assert(s1 != NULL);
  assert(s2 != NULL);
  if (n == 0)
    return (0);
  do {
    if (*s1 != *s2++) {
      return (*s1 - *--s2);
    }
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wcsncmp>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  test   %r12,%r12
  je     L12
  xor    %ecx,%ecx
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L48:
  test   %rax,%rax
  je     L13
  add    $0x1,%rcx
  cmp    %rcx,%r12
  je     L13
L10:
  mov    (%rbx,%rcx,8),%rax
  mov    0x0(%rbp,%rcx,8),%rdi
  cmp    %rdi,%rax
  je     L48
  sub    %edi,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  assert(s1 != NULL);
  assert(s2 != NULL);
  if (n == 0)
    return (0);
  do {
    if (*s1 != *s2++) {
      return (*s1 - *--s2);
    }
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcsncmp>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  test   %r12,%r12
  je     L44
  xor    %ecx,%ecx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L42:
  test   %rax,%rax
  je     L12
  add    $0x1,%rcx
  cmp    %rcx,%r12
  je     L12
L35:
  mov    (%rbx,%rcx,8),%rax
  mov    0x0(%rbp,%rcx,8),%rdi
  cmp    %rdi,%rax
  je     L42
  sub    %edi,%eax
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *s1, const wchar_t *s2, size_t n) {
  assert(s1 != NULL);
  assert(s2 != NULL);
  if (n == 0)
    return (0);
  do {
    if (*s1 != *s2++) {
      return (*s1 - *--s2);
    }
    if (*s1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emb_hash_table_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1505,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L27
L20:
  mov    -0x8(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L20
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int emb_hash_table_hash(const char *key, unsigned int size) {
  unsigned int hash = 5381;
  int c;
  if (!key)
    return 0;
  while ((c = *key++))
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<emb_hash_table_hash>:
  endbr64
  test   %rdi,%rdi
  je     L10
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L44
  mov    $0x1505,%eax
L4:
  mov    %eax,%edi
  shl    $0x5,%edi
  add    %edi,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L4
L40:
  mov    $0x0,%edx
  div    %esi
L17:
  mov    %edx,%eax
  ret
L44:
  mov    $0x1505,%eax
  jmp    L40
L10:
  mov    $0x0,%edx
  jmp    L17
```

assistant: ```c
unsigned int emb_hash_table_hash(const char *key, unsigned int size) {
  unsigned int hash = 5381;
  int c;
  if (!key)
    return 0;
  while ((c = *key++))
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<emb_hash_table_hash>:
  endbr64
  test   %rdi,%rdi
  je     L1
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L19
  nopl   0x0(%rax)
L15:
  mov    %eax,%edi
  add    $0x1,%rcx
  shl    $0x5,%edi
  add    %edi,%eax
  add    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L15
L19:
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int emb_hash_table_hash(const char *key, unsigned int size) {
  unsigned int hash = 5381;
  int c;
  if (!key)
    return 0;
  while ((c = *key++))
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```
user: What is the c source code of the assembly code below:

```asm
<emb_hash_table_hash>:
  endbr64
  test   %rdi,%rdi
  je     L18
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L10
  nopl   0x0(%rax)
L13:
  mov    %eax,%edi
  add    $0x1,%rcx
  shl    $0x5,%edi
  add    %edi,%eax
  add    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L13
L10:
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int emb_hash_table_hash(const char *key, unsigned int size) {
  unsigned int hash = 5381;
  int c;
  if (!key)
    return 0;
  while ((c = *key++))
    hash = ((hash << 5) + hash) + c;
  return hash % size;
}
```