user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x50,-0x9c(%rbp)
  movl   $0x28,-0x98(%rbp)
  movl   $0x64,-0x94(%rbp)
  movl   $0x0,-0xa8(%rbp)
  jmp    L20
L68:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xa8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x98(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x80(%rbp)
  movl   $0x0,-0xa4(%rbp)
  jmp    L66
L56:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xa4(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x9c(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x90(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  movb   $0x23,-0xa9(%rbp)
  movl   $0x0,-0xa0(%rbp)
  jmp    L16
L15:
  movsd  -0x90(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x70(%rbp)
  movsd  -0x88(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  movsd  -0x70(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x68(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L53
  movsd  -0x90(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x88(%rbp),%xmm0
  movsd  -0x80(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  movsd  -0x70(%rbp),%xmm0
  subsd  -0x68(%rbp),%xmm0
  movsd  -0x78(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x90(%rbp)
  jmp    L39
L53:
  movb   $0x2e,-0xa9(%rbp)
  jmp    L23
L39:
  addl   $0x1,-0xa0(%rbp)
L16:
  mov    -0xa0(%rbp),%eax
  cmp    -0x94(%rbp),%eax
  jl     L15
L23:
  mov    -0xa4(%rbp),%eax
  cltq
  movzbl -0xa9(%rbp),%edx
  mov    %dl,-0x60(%rbp,%rax,1)
  addl   $0x1,-0xa4(%rbp)
L66:
  mov    -0xa4(%rbp),%eax
  cmp    -0x9c(%rbp),%eax
  jl     L56
  mov    -0xa4(%rbp),%eax
  cltq
  movb   $0x0,-0x60(%rbp,%rax,1)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xa8(%rbp)
L20:
  mov    -0xa8(%rbp),%eax
  cmp    -0x98(%rbp),%eax
  jl     L68
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: f64
name: disassemble_data
arguments: label: D9
datatype: f64
name: disassemble_data
arguments: label: D18
datatype: string

tool: D15: 4

tool: D9: 2

tool: D18: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int w = 80;
  int h = 40;
  int iter = 100;
  int i, j, k;
  double x0, y0, xx, yy, xx2, yy2;
  char row[80 + 1];
  char c;
  for (i = 0; i < h; i++) {
    y0 = (double)i / (double)h * 4.0 - 2.0;
    for (j = 0; j < w; j++) {
      x0 = (double)j / (double)w * 4.0 - 2.0;
      xx = 0.0;
      yy = 0.0;
      c = '#';
      for (k = 0; k < iter; k++) {
        xx2 = xx * xx;
        yy2 = yy * yy;
        if (xx2 + yy2 < 4.0) {
          yy = 2 * xx * yy + y0;
          xx = xx2 - yy2 + x0;
        } else {
          c = '.';
          break;
        }
      }
      row[j] = c;
    }
    row[j] = (char)0;
    printf("%s\n", row);
  }
  return 0;
}
```