ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<XauFileName>:
  endbr64
  push   %r12
  lea    D70(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <getenv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  lea    D26(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    D1(%rip),%rdi
  lea    0x2(%rbp,%rax,1),%ebp
  cmp    %ebp,D53(%rip)
  jge    L7
  test   %rdi,%rdi
  je     L19
  call   <free@plt>
L19:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,D91(%rip)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L16
  mov    %ebp,D91(%rip)
L7:
  mov    %rbx,%rsi
  call   <strcpy@plt>
  cmpb   $0x1,0x1(%rbx)
  mov    D91(%rip),%rdi
  lea    D91(%rip),%rsi
  adc    $0x0,%rsi
  call   <strcat@plt>
  mov    D91(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D70
type_infered: string
name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D91
type_infered: string

tool: D70: XAUTHORITY

tool: D26: HOME

tool: D13: .Xauthority

tool: D91: /.Xauthority

assistant: ```c
char *XauFileName() {
  char *slashDotXauthority = "/.Xauthority";
  char *name;
  static char *buf;
  static int bsize;
  int size;
  if ((name = getenv("XAUTHORITY")))
    return name;
  name = getenv("HOME");
  if (!name) {
    return 0;
  }
  size = strlen(name) + strlen(&slashDotXauthority[1]) + 2;
  if (size > bsize) {
    if (buf)
      free(buf);
    buf = malloc((unsigned)size);
    if (!buf)
      return 0;
    bsize = size;
  }
  strcpy(buf, name);
  strcat(buf, slashDotXauthority + (name[1] == '\0' ? 1 : 0));
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<XauFileName>:
  endbr64
  push   %r12
  lea    D89(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <getenv@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  lea    D21(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    D41(%rip),%rdi
  lea    0x2(%rbp,%rax,1),%ebp
  cmp    %ebp,D90(%rip)
  jge    L11
  test   %rdi,%rdi
  je     L20
  call   <free@plt>
L20:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,D55(%rip)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L14
  mov    %ebp,D55(%rip)
L11:
  mov    %rbx,%rsi
  call   <strcpy@plt>
  cmpb   $0x1,0x1(%rbx)
  mov    D55(%rip),%rdi
  lea    D55(%rip),%rsi
  adc    $0x0,%rsi
  call   <strcat@plt>
  mov    D55(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D89
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D55
type_infered: string

tool: D89: XAUTHORITY

tool: D21: HOME

tool: D3: .Xauthority

tool: D55: /.Xauthority

assistant: ```c
char *XauFileName() {
  char *slashDotXauthority = "/.Xauthority";
  char *name;
  static char *buf;
  static int bsize;
  int size;
  if ((name = getenv("XAUTHORITY")))
    return name;
  name = getenv("HOME");
  if (!name) {
    return 0;
  }
  size = strlen(name) + strlen(&slashDotXauthority[1]) + 2;
  if (size > bsize) {
    if (buf)
      free(buf);
    buf = malloc((unsigned)size);
    if (!buf)
      return 0;
    bsize = size;
  }
  strcpy(buf, name);
  strcat(buf, slashDotXauthority + (name[1] == '\0' ? 1 : 0));
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<USBDevConnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40050000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x1,%edx
  movslq %edx,%rdx
  or     $0x40,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void USBDevConnect(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000040;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<USBDevConnect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x1,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x40,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBDevConnect(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000040;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBDevConnect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x1,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x40,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBDevConnect(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000040;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBDevConnect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0x1,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x40,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void USBDevConnect(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  (*((volatile uint8_t *)(ui32Base + 0x00000001))) |= 0x00000040;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__set_file_attribute@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
L4:
  jmp    L4
L0:
  mov    -0x8(%rbp),%rax
  jmp    L13
L39:
  mov    $0xffffffff,%eax
L13:
  leave
  ret
```

assistant: ```c
int socket(int namespace, int style, int protocol) {
  int *ret = malloc(sizeof(int));
  if (ret) {
    __set_file_attribute(ret);
    if (ret < (int *)1)
      while (1)
        ;
    return ret;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<socket>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__set_file_attribute@plt>
  mov    %ebx,%eax
L2:
  pop    %rbx
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int socket(int namespace, int style, int protocol) {
  int *ret = malloc(sizeof(int));
  if (ret) {
    __set_file_attribute(ret);
    if (ret < (int *)1)
      while (1)
        ;
    return ret;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<socket>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbx
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <__set_file_attribute@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L1:
  or     $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int socket(int namespace, int style, int protocol) {
  int *ret = malloc(sizeof(int));
  if (ret) {
    __set_file_attribute(ret);
    if (ret < (int *)1)
      while (1)
        ;
    return ret;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<socket>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <__set_file_attribute@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L7:
  or     $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int socket(int namespace, int style, int protocol) {
  int *ret = malloc(sizeof(int));
  if (ret) {
    __set_file_attribute(ret);
    if (ret < (int *)1)
      while (1)
        ;
    return ret;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <do_clear_work@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: Please wait for clear operations


assistant: ```c
void process_signal(int signo) {
  printf("Please wait for clear operations\n");
  do_clear_work();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<process_signal>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <do_clear_work@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: Please wait for clear operations


assistant: ```c
void process_signal(int signo) {
  printf("Please wait for clear operations\n");
  do_clear_work();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<process_signal>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_clear_work@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: Please wait for clear operations


assistant: ```c
void process_signal(int signo) {
  printf("Please wait for clear operations\n");
  do_clear_work();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<process_signal>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_clear_work@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: Please wait for clear operations


assistant: ```c
void process_signal(int signo) {
  printf("Please wait for clear operations\n");
  do_clear_work();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__builtin_ia32_stmxcsr@plt>
  mov    $0x0,%eax
  call   <f1@plt>
  pop    %rbp
  ret
```

assistant: ```c
int f2() {
  __builtin_ia32_stmxcsr();
  return f1();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__builtin_ia32_stmxcsr@plt>
  mov    $0x0,%eax
  call   <f1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f2() {
  __builtin_ia32_stmxcsr();
  return f1();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__builtin_ia32_stmxcsr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <f1@plt>
```

assistant: ```c
int f2() {
  __builtin_ia32_stmxcsr();
  return f1();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__builtin_ia32_stmxcsr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <f1@plt>
```

assistant: ```c
int f2() {
  __builtin_ia32_stmxcsr();
  return f1();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<derotate_180_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D18(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L11
  mov    -0x4(%rbp),%eax
  imul   $0xb4,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L19
L11:
  mov    -0x4(%rbp),%eax
  imul   $0xb4,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L19:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L15
  movsd  -0x18(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L15:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: qword
name: parse_data
arguments: data_tag: D0
data_type: f64

tool: D18: 9223372036854775807

tool: D0: 180

assistant: ```c
double derotate_180_double(double a) {
  int i;
  i = fabs(a) / 180.0;
  if (a > 0)
    a -= 180 * i;
  else
    a += 180 * i;
  if (a < 0)
    a += 180;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<derotate_180_double>:
  endbr64
  movapd %xmm0,%xmm1
  andpd  D10(%rip),%xmm1
  divsd  D30(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  comisd D3(%rip),%xmm0
  jbe    L9
  imul   $0xb4,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
L35:
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
L3:
  ret
L9:
  imul   $0xb4,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  jmp    L35
L6:
  addsd  D30(%rip),%xmm0
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: qword[2]
name: read_data
arguments: data_tag: D30
type_infered: f64
name: read_data
arguments: data_tag: D3
type_infered: byte[16]

tool: {"D10": [0x7fffffffffffffff,0x0000000000000000]}

tool: D30: 180

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
double derotate_180_double(double a) {
  int i;
  i = fabs(a) / 180.0;
  if (a > 0)
    a -= 180 * i;
  else
    a += 180 * i;
  if (a < 0)
    a += 180;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<derotate_180_double>:
  endbr64
  movsd  D6(%rip),%xmm2
  movapd %xmm0,%xmm1
  pxor   %xmm3,%xmm3
  andpd  D5(%rip),%xmm1
  divsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%eax
  pxor   %xmm1,%xmm1
  imul   $0xb4,%eax,%eax
  comisd %xmm1,%xmm0
  cvtsi2sd %eax,%xmm3
  jbe    L8
  subsd  %xmm3,%xmm0
L15:
  comisd %xmm0,%xmm1
  ja     L21
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  addsd  %xmm2,%xmm0
  ret
  nopl   (%rax)
L8:
  addsd  %xmm3,%xmm0
  jmp    L15
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: f64
name: parse_data
arguments: data_label: D5
data_type: qword[2]

tool: D6: 180

tool: {"D5": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double derotate_180_double(double a) {
  int i;
  i = fabs(a) / 180.0;
  if (a > 0)
    a -= 180 * i;
  else
    a += 180 * i;
  if (a < 0)
    a += 180;
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<derotate_180_double>:
  endbr64
  movsd  D18(%rip),%xmm2
  movapd %xmm0,%xmm1
  pxor   %xmm3,%xmm3
  andpd  D5(%rip),%xmm1
  divsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%eax
  pxor   %xmm1,%xmm1
  imul   $0xb4,%eax,%eax
  comisd %xmm1,%xmm0
  cvtsi2sd %eax,%xmm3
  jbe    L14
  subsd  %xmm3,%xmm0
L26:
  comisd %xmm0,%xmm1
  ja     L4
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  addsd  %xmm2,%xmm0
  ret
  nopl   (%rax)
L14:
  addsd  %xmm3,%xmm0
  jmp    L26
```

tool_calls: name: parse_data
arguments: data_label: D18
type_guessed: f64
name: parse_data
arguments: data_label: D5
type_guessed: qword[2]

tool: D18: 180

tool: {"D5": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double derotate_180_double(double a) {
  int i;
  i = fabs(a) / 180.0;
  if (a > 0)
    a -= 180 * i;
  else
    a += 180 * i;
  if (a < 0)
    a += 180;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x3,(%rax)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x9,(%rax)
  mov    -0x1c(%rbp),%eax
  cmp    $0x9,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a, b, c;
  int *p;
  a = 0;
  p = &b;
  *p = 1;
  p = &c;
  *p = 3;
  a = b + c;
  b = 3;
  c = 5;
  p = &a;
  *p = 9;
  test_assert(a == 9);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a, b, c;
  int *p;
  a = 0;
  p = &b;
  *p = 1;
  p = &c;
  *p = 3;
  a = b + c;
  b = 3;
  c = 5;
  p = &a;
  *p = 9;
  test_assert(a == 9);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a, b, c;
  int *p;
  a = 0;
  p = &b;
  *p = 1;
  p = &c;
  *p = 3;
  a = b + c;
  b = 3;
  c = 5;
  p = &a;
  *p = 9;
  test_assert(a == 9);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a, b, c;
  int *p;
  a = 0;
  p = &b;
  *p = 1;
  p = &c;
  *p = 3;
  a = b + c;
  b = 3;
  c = 5;
  p = &a;
  *p = 9;
  test_assert(a == 9);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mbrot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  mov    %esi,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L11
L12:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L21
L2:
  mov    -0x14(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %edx,%edi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <count@plt>
  mov    %eax,(%rbx)
  subl   $0x1,-0x18(%rbp)
L21:
  cmpl   $0x0,-0x18(%rbp)
  jns    L2
  subl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x0,-0x14(%rbp)
  jns    L12
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mbrot(int *matrix, double r, double i, double step, int n) {
  int x, y;
  for (y = n - 1; y >= 0; y--)
    for (x = n - 1; x >= 0; x--)
      matrix[y * n + x] = count(r, i, step, x, y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mbrot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  mov    %esi,%r15d
  sub    $0x1,%r15d
  js     L11
  movq   %xmm2,%r14
  mov    %esi,%eax
  neg    %eax
  cltq
  lea    0x0(,%rax,4),%r13
  imul   %r15d,%esi
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r12
  mov    %r15d,%ebp
L0:
  movslq %r15d,%rbx
L26:
  mov    %ebp,%esi
  mov    %ebx,%edi
  movq   %r14,%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   <count@plt>
  mov    %eax,(%r12,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L26
  sub    $0x1,%ebp
  add    %r13,%r12
  cmp    $0xffffffff,%ebp
  jne    L0
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mbrot(int *matrix, double r, double i, double step, int n) {
  int x, y;
  for (y = n - 1; y >= 0; y--)
    for (x = n - 1; x >= 0; x--)
      matrix[y * n + x] = count(r, i, step, x, y);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mbrot>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  sub    $0x1,%r14d
  js     L23
  mov    %esi,%r12d
  imul   %r14d,%esi
  movq   %xmm0,%r15
  movslq %r14d,%r13
  neg    %r12d
  movslq %r12d,%r12
  movslq %esi,%rax
  shl    $0x2,%r12
  lea    (%rdi,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %ebx,%edi
  mov    %r14d,%esi
  movq   %r15,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <count@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L24
  sub    $0x1,%r14d
  add    %r12,%rbp
  cmp    $0xffffffff,%r14d
  jne    L6
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mbrot(int *matrix, double r, double i, double step, int n) {
  int x, y;
  for (y = n - 1; y >= 0; y--)
    for (x = n - 1; x >= 0; x--)
      matrix[y * n + x] = count(r, i, step, x, y);
}
```
user: What is the c source code of the assembly code below?

```asm
<mbrot>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  sub    $0x1,%r14d
  js     L25
  mov    %esi,%r12d
  imul   %r14d,%esi
  movq   %xmm0,%r15
  movslq %r14d,%r13
  neg    %r12d
  movslq %r12d,%r12
  movslq %esi,%rax
  shl    $0x2,%r12
  lea    (%rdi,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%edi
  mov    %r14d,%esi
  movq   %r15,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <count@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L20
  sub    $0x1,%r14d
  add    %r12,%rbp
  cmp    $0xffffffff,%r14d
  jne    L19
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mbrot(int *matrix, double r, double i, double step, int n) {
  int x, y;
  for (y = n - 1; y >= 0; y--)
    for (x = n - 1; x >= 0; x--)
      matrix[y * n + x] = count(r, i, step, x, y);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: %d 

assistant: ```c
void show_array(const int ar[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d ", ar[i]);
  }
  putchar('\n');
}
```