ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: cl_ext_intel.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_ext_intel.h standalone test PASSED.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: cl_ext_intel.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_ext_intel.h standalone test PASSED.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: cl_ext_intel.h standalone test PASSED.


assistant: ```c
int main(void) {
  printf("cl_ext_intel.h standalone test PASSED.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L31
  mov    $0x0,%eax
  jmp    L32
L31:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  mov    $0x0,%eax
  jmp    L32
L18:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    $0x0,%eax
L32:
  leave
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  if (x < 0)
    return 0;
  int y = __VERIFIER_nondet_int();
  if (y < 0)
    return 0;
  int z = __VERIFIER_nondet_int();
  fact(x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L15
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L15
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %ebx,%edi
  call   <fact@plt>
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  if (x < 0)
    return 0;
  int y = __VERIFIER_nondet_int();
  if (y < 0)
    return 0;
  int z = __VERIFIER_nondet_int();
  fact(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L10
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L10
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %ebp,%edi
  call   <fact@plt>
L10:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  if (x < 0)
    return 0;
  int y = __VERIFIER_nondet_int();
  if (y < 0)
    return 0;
  int z = __VERIFIER_nondet_int();
  fact(x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L2
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  js     L2
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %ebp,%edi
  call   <fact@plt>
L2:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  if (x < 0)
    return 0;
  int y = __VERIFIER_nondet_int();
  if (y < 0)
    return 0;
  int z = __VERIFIER_nondet_int();
  fact(x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim_whites>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  jmp    L67
L90:
  addq   $0x1,-0x28(%rbp)
L67:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L90
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L96
L78:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L88
  cmpl   $0x0,-0x14(%rbp)
  jne    L88
  movq   $0x0,-0x10(%rbp)
  jmp    L75
L88:
  cmpq   $0x0,-0x10(%rbp)
  jne    L75
  cmpl   $0x0,-0x14(%rbp)
  je     L75
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L75:
  addq   $0x1,-0x8(%rbp)
L96:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  cmpq   $0x0,-0x10(%rbp)
  je     L32
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L32:
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim_whites(char *s) {
  for (; isspace(*s); ++s)
    ;
  char *end = 0, *p;
  for (p = s; *p; ++p) {
    int space = isspace(*p);
    if (end && !space)
      end = 0;
    else if (!end && space)
      end = p;
  }
  if (end)
    *end = 0;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<trim_whites>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
L12:
  add    $0x1,%rbx
L1:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L12
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L76
  mov    %rbx,%rbp
  mov    $0x0,%r12d
  jmp    L48
L40:
  mov    $0x0,%r12d
L43:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L51
L48:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %r12,%r12
  je     L35
  test   %eax,%eax
  je     L40
L35:
  test   %r12,%r12
  jne    L43
  test   %eax,%eax
  cmovne %rbp,%r12
  jmp    L43
L51:
  test   %r12,%r12
  je     L76
  movb   $0x0,(%r12)
L76:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim_whites(char *s) {
  for (; isspace(*s); ++s)
    ;
  char *end = 0, *p;
  for (p = s; *p; ++p) {
    int space = isspace(*p);
    if (end && !space)
      end = 0;
    else if (!end && space)
      end = p;
  }
  if (end)
    *end = 0;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<trim_whites>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  jmp    L2
  nopl   (%rax)
L13:
  add    $0x1,%r12
L2:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L13
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L78
  mov    %r12,%rbx
  xor    %ebp,%ebp
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L45:
  xor    %ebp,%ebp
L20:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L69
L97:
  call   <isspace@plt>
  test   %rbp,%rbp
  je     L60
  test   %eax,%eax
  je     L45
  test   %rbp,%rbp
  jne    L20
L60:
  test   %eax,%eax
  cmovne %rbx,%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L97
L69:
  test   %rbp,%rbp
  je     L78
  movb   $0x0,0x0(%rbp)
L78:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim_whites(char *s) {
  for (; isspace(*s); ++s)
    ;
  char *end = 0, *p;
  for (p = s; *p; ++p) {
    int space = isspace(*p);
    if (end && !space)
      end = 0;
    else if (!end && space)
      end = p;
  }
  if (end)
    *end = 0;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_whites>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  jmp    L93
  nopl   (%rax)
L0:
  add    $0x1,%r12
L93:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L0
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L28
  mov    %r12,%rbx
  xor    %ebp,%ebp
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %ebp,%ebp
L49:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L2
L52:
  call   <isspace@plt>
  test   %rbp,%rbp
  je     L20
  test   %eax,%eax
  je     L38
  test   %rbp,%rbp
  jne    L49
L20:
  test   %eax,%eax
  cmovne %rbx,%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L52
L2:
  test   %rbp,%rbp
  je     L28
  movb   $0x0,0x0(%rbp)
L28:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim_whites(char *s) {
  for (; isspace(*s); ++s)
    ;
  char *end = 0, *p;
  for (p = s; *p; ++p) {
    int space = isspace(*p);
    if (end && !space)
      end = 0;
    else if (!end && space)
      end = p;
  }
  if (end)
    *end = 0;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getDoomsday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <getCenturyAnchorDay@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  leave
  ret
```

assistant: ```c
int getDoomsday(int year) {
  int digits = year % 100;
  int a = floor(digits / 12);
  int b = digits % 12;
  int c = floor(b / 4);
  int d = getCenturyAnchorDay(year);
  return (a + b + c + d) % 7;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getDoomsday>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  movslq %edi,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  imul   $0x64,%ebx,%eax
  mov    %edi,%ebx
  sub    %eax,%ebx
  movslq %ebx,%r12
  imul   $0x2aaaaaab,%r12,%r12
  sar    $0x21,%r12
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  mov    %r12d,%edi
  call   <floor@plt>
  mov    %eax,%ebp
  lea    (%r12,%r12,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  lea    0x3(%rbx),%edi
  cmovns %ebx,%edi
  sar    $0x2,%edi
  call   <floor@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <getCenturyAnchorDay@plt>
  lea    0x0(%rbp,%rbx,1),%edx
  add    %r12d,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getDoomsday(int year) {
  int digits = year % 100;
  int a = floor(digits / 12);
  int b = digits % 12;
  int c = floor(b / 4);
  int d = getCenturyAnchorDay(year);
  return (a + b + c + d) % 7;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getDoomsday>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  mov    %rbx,%r13
  imul   $0x51eb851f,%rbx,%rbx
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sub    $0x8,%rsp
  sar    $0x25,%rbx
  sub    %eax,%ebx
  imul   $0x64,%ebx,%eax
  mov    %r13d,%ebx
  sub    %eax,%ebx
  movslq %ebx,%r12
  mov    %ebx,%eax
  imul   $0x2aaaaaab,%r12,%r12
  sar    $0x1f,%eax
  sar    $0x21,%r12
  sub    %eax,%r12d
  mov    %r12d,%edi
  call   <floor@plt>
  mov    %eax,%ebp
  lea    (%r12,%r12,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  lea    0x3(%rbx),%edi
  cmovns %ebx,%edi
  sar    $0x2,%edi
  call   <floor@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <getCenturyAnchorDay@plt>
  lea    0x0(%rbp,%rbx,1),%edx
  add    $0x8,%rsp
  add    %r12d,%edx
  pop    %rbx
  pop    %rbp
  add    %eax,%edx
  pop    %r12
  pop    %r13
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int getDoomsday(int year) {
  int digits = year % 100;
  int a = floor(digits / 12);
  int b = digits % 12;
  int c = floor(b / 4);
  int d = getCenturyAnchorDay(year);
  return (a + b + c + d) % 7;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getDoomsday>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  mov    %rbx,%r13
  imul   $0x51eb851f,%rbx,%rbx
  mov    %r13d,%eax
  sar    $0x1f,%eax
  sub    $0x8,%rsp
  sar    $0x25,%rbx
  sub    %eax,%ebx
  imul   $0x64,%ebx,%eax
  mov    %r13d,%ebx
  sub    %eax,%ebx
  movslq %ebx,%r12
  mov    %ebx,%eax
  imul   $0x2aaaaaab,%r12,%r12
  sar    $0x1f,%eax
  sar    $0x21,%r12
  sub    %eax,%r12d
  mov    %r12d,%edi
  call   <floor@plt>
  mov    %eax,%ebp
  lea    (%r12,%r12,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  lea    0x3(%rbx),%edi
  cmovns %ebx,%edi
  sar    $0x2,%edi
  call   <floor@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <getCenturyAnchorDay@plt>
  lea    0x0(%rbp,%rbx,1),%edx
  add    $0x8,%rsp
  add    %r12d,%edx
  pop    %rbx
  pop    %rbp
  add    %eax,%edx
  pop    %r12
  pop    %r13
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int getDoomsday(int year) {
  int digits = year % 100;
  int a = floor(digits / 12);
  int b = digits % 12;
  int c = floor(b / 4);
  int d = getCenturyAnchorDay(year);
  return (a + b + c + d) % 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L40
L58:
  cmpl   $0x0,-0x14(%rbp)
  jns    L23
  movl   $0xffffffff,-0x4(%rbp)
  negl   -0x14(%rbp)
L23:
  cmpl   $0x0,-0x14(%rbp)
  jle    L6
  jmp    L35
L59:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L35:
  cmpl   $0x0,-0x14(%rbp)
  jg     L59
L6:
  cmpl   $0x0,-0x4(%rbp)
  jns    L34
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strrev@plt>
  mov    $0x0,%eax
L40:
  leave
  ret
```

assistant: ```c
int itoa(int num, char *buff) {
  int i = 0;
  int neg = 1;
  if (num == 0) {
    buff[i] = '0';
    i++;
    buff[i] = '\0';
    return 0;
  }
  if (num < 0) {
    neg = -1;
    num = -num;
  }
  if (num > 0) {
    while (num > 0) {
      buff[i] = num % 10 + '0';
      num = num / 10;
      i++;
    }
  }
  if (neg < 0) {
    buff[i] = '-';
    i++;
  }
  buff[i] = '\0';
  strrev(buff);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  mov    %rsi,%r9
  test   %edi,%edi
  je     L18
  mov    %edi,%edx
  mov    $0x1,%r10d
  js     L41
L30:
  sub    $0x8,%rsp
  mov    %r9,%r8
  mov    $0x0,%ecx
L15:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %edx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%r8)
  mov    %edx,%esi
  mov    %eax,%edx
  mov    %ecx,%eax
  add    $0x1,%ecx
  add    $0x1,%r8
  cmp    $0x9,%esi
  jg     L15
  test   %r10d,%r10d
  jns    L37
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%rax),%ecx
L37:
  movslq %ecx,%rcx
  movb   $0x0,(%r9,%rcx,1)
  mov    %r9,%rdi
  call   <strrev@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L18:
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
  mov    $0x0,%eax
  ret
L41:
  neg    %edx
  mov    $0xffffffff,%r10d
  jmp    L30
```

assistant: ```c
int itoa(int num, char *buff) {
  int i = 0;
  int neg = 1;
  if (num == 0) {
    buff[i] = '0';
    i++;
    buff[i] = '\0';
    return 0;
  }
  if (num < 0) {
    neg = -1;
    num = -num;
  }
  if (num > 0) {
    while (num > 0) {
      buff[i] = num % 10 + '0';
      num = num / 10;
      i++;
    }
  }
  if (neg < 0) {
    buff[i] = '-';
    i++;
  }
  buff[i] = '\0';
  strrev(buff);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  mov    %rsi,%r9
  test   %edi,%edi
  je     L22
  mov    $0x1,%r10d
  js     L23
L21:
  sub    $0x8,%rsp
  mov    %r9,%rsi
  xor    %ecx,%ecx
  mov    $0xcccccccd,%r8d
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %edi,%eax
  add    $0x1,%rsi
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rsi)
  mov    %eax,%edi
  mov    %ecx,%eax
  add    $0x1,%ecx
  test   %edi,%edi
  jne    L55
  cmp    $0xffffffff,%r10d
  je     L54
L57:
  movslq %ecx,%rcx
  mov    %r9,%rdi
  movb   $0x0,(%r9,%rcx,1)
  call   <strrev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L23:
  neg    %edi
  mov    $0xffffffff,%r10d
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L54:
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%rax),%ecx
  jmp    L57
  nopl   (%rax)
L22:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int itoa(int num, char *buff) {
  int i = 0;
  int neg = 1;
  if (num == 0) {
    buff[i] = '0';
    i++;
    buff[i] = '\0';
    return 0;
  }
  if (num < 0) {
    neg = -1;
    num = -num;
  }
  if (num > 0) {
    while (num > 0) {
      buff[i] = num % 10 + '0';
      num = num / 10;
      i++;
    }
  }
  if (neg < 0) {
    buff[i] = '-';
    i++;
  }
  buff[i] = '\0';
  strrev(buff);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  mov    %rsi,%r9
  test   %edi,%edi
  je     L56
  mov    $0x1,%r10d
  js     L23
L53:
  sub    $0x8,%rsp
  mov    %r9,%rsi
  xor    %ecx,%ecx
  mov    $0xcccccccd,%r8d
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %edi,%eax
  add    $0x1,%rsi
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rsi)
  mov    %eax,%edi
  mov    %ecx,%eax
  add    $0x1,%ecx
  test   %edi,%edi
  jne    L34
  cmp    $0xffffffff,%r10d
  je     L24
L8:
  movslq %ecx,%rcx
  mov    %r9,%rdi
  movb   $0x0,(%r9,%rcx,1)
  call   <strrev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L23:
  neg    %edi
  mov    $0xffffffff,%r10d
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L24:
  movslq %ecx,%rcx
  movb   $0x2d,(%r9,%rcx,1)
  lea    0x2(%rax),%ecx
  jmp    L8
  nopl   (%rax)
L56:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int itoa(int num, char *buff) {
  int i = 0;
  int neg = 1;
  if (num == 0) {
    buff[i] = '0';
    i++;
    buff[i] = '\0';
    return 0;
  }
  if (num < 0) {
    neg = -1;
    num = -num;
  }
  if (num > 0) {
    while (num > 0) {
      buff[i] = num % 10 + '0';
      num = num / 10;
      i++;
    }
  }
  if (neg < 0) {
    buff[i] = '-';
    i++;
  }
  buff[i] = '\0';
  strrev(buff);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_setbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  orl    $0x80000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int test_setbit(unsigned int val) {
  val |= (1u << 31);
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_setbit>:
  endbr64
  mov    %edi,%eax
  or     $0x80000000,%eax
  ret
```

assistant: ```c
unsigned int test_setbit(unsigned int val) {
  val |= (1u << 31);
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_setbit>:
  endbr64
  mov    %edi,%eax
  or     $0x80000000,%eax
  ret
```

assistant: ```c
unsigned int test_setbit(unsigned int val) {
  val |= (1u << 31);
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_setbit>:
  endbr64
  mov    %edi,%eax
  or     $0x80000000,%eax
  ret
```

assistant: ```c
unsigned int test_setbit(unsigned int val) {
  val |= (1u << 31);
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dpoly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm2
  movsd  D33(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
datatype: f64
name: extract_symbolic_data
arguments: tag: D1
datatype: f64
name: extract_symbolic_data
arguments: tag: D6
datatype: byte[8]

tool: D33: 3

tool: D1: 1

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

assistant: ```c
double dpoly(double x) {
  double a = 3.0, b = 1.0, c = -5.0;
  return c + x * (2 * b + x * 3 * a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dpoly>:
  endbr64
  movsd  D8(%rip),%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  subsd  D27(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: f64
name: read_data
arguments: data_label: D23
type_guessed: byte[8]
name: read_data
arguments: data_label: D27
type_guessed: f64

tool: D8: 3

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D27: 5

assistant: ```c
double dpoly(double x) {
  double a = 3.0, b = 1.0, c = -5.0;
  return c + x * (2 * b + x * 3 * a);
}
```