ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<search_in_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x228(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x218(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L59
L19:
  mov    -0x230(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L50
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L59
L50:
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L59:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: r

assistant: ```c
int search_in_file(char *fname, char *str) {
  FILE *fp;
  char temp[512];
  if ((fp = fopen(fname, "r")) == NULL)
    return 0;
  while (fgets(temp, 512, fp) != NULL) {
    if ((strstr(temp, str)) != NULL) {
      fclose(fp);
      return 1;
    }
  }
  fclose(fp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<search_in_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L54
  mov    %rax,%rbp
  mov    %rsp,%rbx
L14:
  mov    %rbp,%rdx
  mov    $0x200,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L11
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L14
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L25
L11:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L25:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  mov    $0x0,%eax
  jmp    L25
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: r

assistant: ```c
int search_in_file(char *fname, char *str) {
  FILE *fp;
  char temp[512];
  if ((fp = fopen(fname, "r")) == NULL)
    return 0;
  while (fgets(temp, 512, fp) != NULL) {
    if ((strstr(temp, str)) != NULL) {
      fclose(fp);
      return 1;
    }
  }
  fclose(fp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<search_in_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L31
  mov    %rax,%rbp
  mov    %rsp,%rbx
  jmp    L60
  xchg   %ax,%ax
L51:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L65
L60:
  mov    %rbp,%rdx
  mov    $0x200,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L51
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L56:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L65:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L56
  nop
L31:
  xor    %eax,%eax
  jmp    L56
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: r

assistant: ```c
int search_in_file(char *fname, char *str) {
  FILE *fp;
  char temp[512];
  if ((fp = fopen(fname, "r")) == NULL)
    return 0;
  while (fgets(temp, 512, fp) != NULL) {
    if ((strstr(temp, str)) != NULL) {
      fclose(fp);
      return 1;
    }
  }
  fclose(fp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<search_in_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L41
  mov    %rax,%rbp
  mov    %rsp,%rbx
  jmp    L61
  xchg   %ax,%ax
L22:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L62
L61:
  mov    %rbp,%rdx
  mov    $0x200,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L22
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L60:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L62:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L60
  nop
L41:
  xor    %eax,%eax
  jmp    L60
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: r

assistant: ```c
int search_in_file(char *fname, char *str) {
  FILE *fp;
  char temp[512];
  if ((fp = fopen(fname, "r")) == NULL)
    return 0;
  while (fgets(temp, 512, fp) != NULL) {
    if ((strstr(temp, str)) != NULL) {
      fclose(fp);
      return 1;
    }
  }
  fclose(fp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L42
L33:
  mov    -0x18(%rbp),%eax
  sub    $0xf4240,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <stdlib_base_labs@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L10
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L32
L10:
  addl   $0x1,-0x18(%rbp)
L42:
  cmpl   $0xf423f,-0x18(%rbp)
  jle    L33
L32:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L9
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: should not return a negative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int x;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = i - 1000000;
    y = stdlib_base_labs(x);
    if (y < 0) {
      printf("should not return a negative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should not return a negative number\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xfff0bdc0,%ebx
L19:
  mov    %ebx,%edi
  call   <stdlib_base_labs@plt>
  test   %eax,%eax
  js     L18
  add    $0x1,%ebx
  jne    L19
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L12
L18:
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L12:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: should not return a negative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int x;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = i - 1000000;
    y = stdlib_base_labs(x);
    if (y < 0) {
      printf("should not return a negative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should not return a negative number\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xfff0bdc0,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L10
  xchg   %ax,%ax
L14:
  add    $0x1,%ebx
  je     L20
L10:
  mov    %ebx,%edi
  call   <stdlib_base_labs@plt>
  test   %eax,%eax
  jns    L14
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: should not return a negative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int x;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = i - 1000000;
    y = stdlib_base_labs(x);
    if (y < 0) {
      printf("should not return a negative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should not return a negative number\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xfff0bdc0,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L24
  xchg   %ax,%ax
L3:
  add    $0x1,%ebx
  je     L23
L24:
  mov    %ebx,%edi
  call   <stdlib_base_labs@plt>
  test   %eax,%eax
  jns    L3
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: should not return a negative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int x;
  int y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = i - 1000000;
    y = stdlib_base_labs(x);
    if (y < 0) {
      printf("should not return a negative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should not return a negative number\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<removeDuplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L78
L75:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L61
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L54
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L54
L61:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L54
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L54:
  addl   $0x1,-0x4(%rbp)
L78:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L75
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L15
  mov    -0x1c(%rbp),%eax
  jmp    L10
L15:
  mov    -0x8(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int storePos = -1, forwardPos = 1;
  for (; forwardPos < numsSize; forwardPos++) {
    if (nums[forwardPos] != nums[forwardPos - 1]) {
      if (storePos != -1) {
        nums[storePos++] = nums[forwardPos];
      }
    } else {
      if (storePos == -1) {
        storePos = forwardPos;
      }
    }
  }
  return storePos == -1 ? numsSize : storePos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<removeDuplicates>:
  endbr64
  cmp    $0x1,%esi
  jle    L35
  mov    %esi,%r9d
  mov    $0x1,%eax
  mov    $0xffffffff,%edx
  jmp    L52
L5:
  cmp    $0xffffffff,%edx
  cmove  %eax,%edx
L53:
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L41
L52:
  mov    (%rdi,%rax,4),%ecx
  cmp    -0x4(%rdi,%rax,4),%ecx
  je     L5
  cmp    $0xffffffff,%edx
  je     L53
  movslq %edx,%r8
  mov    %ecx,(%rdi,%r8,4)
  lea    0x1(%rdx),%edx
  jmp    L53
L41:
  cmp    $0xffffffff,%edx
  cmove  %esi,%edx
L24:
  mov    %edx,%eax
  ret
L35:
  mov    %esi,%edx
  jmp    L24
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int storePos = -1, forwardPos = 1;
  for (; forwardPos < numsSize; forwardPos++) {
    if (nums[forwardPos] != nums[forwardPos - 1]) {
      if (storePos != -1) {
        nums[storePos++] = nums[forwardPos];
      }
    } else {
      if (storePos == -1) {
        storePos = forwardPos;
      }
    }
  }
  return storePos == -1 ? numsSize : storePos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<removeDuplicates>:
  endbr64
  cmp    $0x1,%esi
  jle    L46
  movslq %esi,%rcx
  mov    $0x1,%eax
  mov    $0xffffffff,%r8d
  jmp    L13
  nopl   0x0(%rax)
L10:
  cmp    $0xffffffff,%r8d
  je     L47
  movslq %r8d,%r9
  add    $0x1,%r8d
  mov    %edx,(%rdi,%r9,4)
L47:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L2
L13:
  mov    (%rdi,%rax,4),%edx
  cmp    -0x4(%rdi,%rax,4),%edx
  jne    L10
  cmp    $0xffffffff,%r8d
  cmove  %eax,%r8d
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
L2:
  cmp    $0xffffffff,%r8d
  je     L46
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L46:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int storePos = -1, forwardPos = 1;
  for (; forwardPos < numsSize; forwardPos++) {
    if (nums[forwardPos] != nums[forwardPos - 1]) {
      if (storePos != -1) {
        nums[storePos++] = nums[forwardPos];
      }
    } else {
      if (storePos == -1) {
        storePos = forwardPos;
      }
    }
  }
  return storePos == -1 ? numsSize : storePos;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeDuplicates>:
  endbr64
  cmp    $0x1,%esi
  jle    L20
  movslq %esi,%rcx
  mov    $0x1,%eax
  mov    $0xffffffff,%r8d
  jmp    L32
  nopl   0x0(%rax)
L12:
  cmp    $0xffffffff,%r8d
  je     L34
  movslq %r8d,%r9
  add    $0x1,%r8d
  mov    %edx,(%rdi,%r9,4)
L34:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L9
L32:
  mov    (%rdi,%rax,4),%edx
  cmp    -0x4(%rdi,%rax,4),%edx
  jne    L12
  cmp    $0xffffffff,%r8d
  cmove  %eax,%r8d
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L32
L9:
  cmp    $0xffffffff,%r8d
  je     L20
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L20:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  int storePos = -1, forwardPos = 1;
  for (; forwardPos < numsSize; forwardPos++) {
    if (nums[forwardPos] != nums[forwardPos - 1]) {
      if (storePos != -1) {
        nums[storePos++] = nums[forwardPos];
      }
    } else {
      if (storePos == -1) {
        storePos = forwardPos;
      }
    }
  }
  return storePos == -1 ? numsSize : storePos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x6,%edi
  call   <legal_lookahead@plt>
  test   %eax,%eax
  je     L5
  mov    $0x0,%eax
  call   <factor@plt>
  jmp    L20
L34:
  mov    $0x0,%eax
  call   <advance@plt>
  mov    $0x0,%eax
  call   <factor@plt>
L20:
  mov    $0x3,%edi
  call   <match@plt>
  test   %rax,%rax
  jne    L34
  jmp    L22
L5:
  nop
L22:
  pop    %rbp
  ret
```

assistant: ```c
void term() {
  if (!legal_lookahead(6, 4, 0))
    return;
  factor();
  while (match(3)) {
    advance();
    factor();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<term>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x6,%edi
  call   <legal_lookahead@plt>
  test   %eax,%eax
  jne    L9
L24:
  add    $0x8,%rsp
  ret
L9:
  mov    $0x0,%eax
  call   <factor@plt>
  jmp    L23
L38:
  mov    $0x0,%eax
  call   <advance@plt>
  mov    $0x0,%eax
  call   <factor@plt>
L23:
  mov    $0x3,%edi
  call   <match@plt>
  test   %rax,%rax
  jne    L38
  jmp    L24
```

assistant: ```c
void term() {
  if (!legal_lookahead(6, 4, 0))
    return;
  factor();
  while (match(3)) {
    advance();
    factor();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<term>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    $0x6,%edi
  call   <legal_lookahead@plt>
  test   %eax,%eax
  jne    L13
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <advance@plt>
L13:
  xor    %eax,%eax
  call   <factor@plt>
  mov    $0x3,%edi
  call   <match@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  ret
```

assistant: ```c
void term() {
  if (!legal_lookahead(6, 4, 0))
    return;
  factor();
  while (match(3)) {
    advance();
    factor();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<term>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    $0x6,%edi
  call   <legal_lookahead@plt>
  test   %eax,%eax
  jne    L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <advance@plt>
L2:
  xor    %eax,%eax
  call   <factor@plt>
  mov    $0x3,%edi
  call   <match@plt>
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  ret
```

assistant: ```c
void term() {
  if (!legal_lookahead(6, 4, 0))
    return;
  factor();
  while (match(3)) {
    advance();
    factor();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_poly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L25:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L28:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L19
  cmpl   $0x3b,-0x4(%rbp)
  jne    L25
L19:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3b,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void read_poly(int *nc, char p[]) {
  int c, i = 0;
  while ((c = getchar()) != EOF && c != ';')
    p[i++] = c;
  p[i++] = ';';
  p[i++] = '\0';
  *nc = i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_poly>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebx
L19:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L21
  cmp    $0x3b,%eax
  je     L21
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  jmp    L19
L21:
  movslq %ebp,%rax
  movb   $0x3b,(%r12,%rax,1)
  lea    0x1(%rbp),%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
  add    $0x2,%ebp
  mov    %ebp,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void read_poly(int *nc, char p[]) {
  int c, i = 0;
  while ((c = getchar()) != EOF && c != ';')
    p[i++] = c;
  p[i++] = ';';
  p[i++] = '\0';
  *nc = i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_poly>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    D8(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L15
  nopl   0x0(%rax)
L12:
  cmp    $0x3b,%eax
  je     L1
  mov    %al,(%rbx)
  mov    %edx,%r14d
  add    $0x1,%rbx
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x1(%r14),%edx
  cmp    %eax,0x0(%rbp)
  jne    L12
L1:
  add    $0x2,%r14d
  movslq %edx,%rdx
  movb   $0x3b,(%rbx)
  pop    %rbx
  movb   $0x0,(%r12,%rdx,1)
  pop    %rbp
  mov    %r14d,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void read_poly(int *nc, char p[]) {
  int c, i = 0;
  while ((c = getchar()) != EOF && c != ';')
    p[i++] = c;
  p[i++] = ';';
  p[i++] = '\0';
  *nc = i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_poly>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    D0(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L3
  nopl   0x0(%rax)
L1:
  cmp    $0x3b,%eax
  je     L24
  mov    %al,(%rbx)
  mov    %edx,%r14d
  add    $0x1,%rbx
L3:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x1(%r14),%edx
  cmp    %eax,0x0(%rbp)
  jne    L1
L24:
  add    $0x2,%r14d
  movslq %edx,%rdx
  movb   $0x3b,(%rbx)
  pop    %rbx
  movb   $0x0,(%r12,%rdx,1)
  pop    %rbp
  mov    %r14d,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void read_poly(int *nc, char p[]) {
  int c, i = 0;
  while ((c = getchar()) != EOF && c != ';')
    p[i++] = c;
  p[i++] = ';';
  p[i++] = '\0';
  *nc = i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TimerPrescaleGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xff,-0x8(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  add    $0x38,%eax
  cltq
  mov    (%rax),%eax
  jmp    L8
L12:
  mov    -0x4(%rbp),%eax
  add    $0x3c,%eax
  cltq
  mov    (%rax),%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t TimerPrescaleGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  return ((ui32Timer == 0x000000ff) ? (*((volatile uint32_t *)(ui32Base + 0x00000038))) : (*((volatile uint32_t *)(ui32Base + 0x0000003C))));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TimerPrescaleGet>:
  endbr64
  cmp    $0xff,%esi
  je     L9
  add    $0x3c,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
L9:
  add    $0x38,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t TimerPrescaleGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  return ((ui32Timer == 0x000000ff) ? (*((volatile uint32_t *)(ui32Base + 0x00000038))) : (*((volatile uint32_t *)(ui32Base + 0x0000003C))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TimerPrescaleGet>:
  endbr64
  cmp    $0xff,%esi
  je     L6
  add    $0x3c,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
  nopl   (%rax)
L6:
  add    $0x38,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t TimerPrescaleGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  return ((ui32Timer == 0x000000ff) ? (*((volatile uint32_t *)(ui32Base + 0x00000038))) : (*((volatile uint32_t *)(ui32Base + 0x0000003C))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerPrescaleGet>:
  endbr64
  cmp    $0xff,%esi
  je     L4
  add    $0x3c,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
  nopl   (%rax)
L4:
  add    $0x38,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t TimerPrescaleGet(uint32_t ui32Base, uint32_t ui32Timer) {
  ;

  ;
  return ((ui32Timer == 0x000000ff) ? (*((volatile uint32_t *)(ui32Base + 0x00000038))) : (*((volatile uint32_t *)(ui32Base + 0x0000003C))));
}
```