ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<TOSH_long_uwait>:
  endbr64
  cmp    $0x3,%edi
  jbe    L8
  push   %rbx
  lea    -0x4(%rdi),%ebx
  cmp    $0x4,%dil
  jne    L18
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %eax,%ebx
  test   %al,%al
  je     L51
  xchg   %ax,%ax
L10:
  mov    $0xff,%edi
  xor    %eax,%eax
  sub    $0x1,%ebx
  call   <TOSH_short_uwait@plt>
  nop
  nop
  nop
  nop
  test   %bl,%bl
  jne    L10
L51:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  ret
  nopl   0x0(%rax)
L18:
  movzbl %bl,%edi
  xor    %eax,%eax
  call   <TOSH_short_uwait@plt>
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %eax,%ebx
  test   %al,%al
  jne    L10
  jmp    L51
```

assistant: ```c
void TOSH_long_uwait(unsigned int u_sec) {
  if (u_sec >= 4) {
    u_sec -= 4;
    {
      unsigned char u = (u_sec & 255);
      if (u > 0)
        TOSH_short_uwait(u);
      u = u_sec >> 8;
      while (u > 0) {
        TOSH_short_uwait(255);
        u--;
        asm("nop");
        asm("nop");
        asm("nop");
        asm("nop");
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2c4645442c434241,%rax
  movabs $0x204c4b4a0a494847,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x525150204f4e4d,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
L38:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L20
  lea    -0x20(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L35
L20:
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28(%rbp)
L35:
  cmpq   $0x0,-0x28(%rbp)
  je     L48
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L48:
  addl   $0x1,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L38
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D16: ,
 

tool: D8: token = %s


assistant: ```c
int main(void) {
  char target[] = "ABC,DEF,GHI\nJKL MNO PQR";
  char *token = NULL;
  int i = 0;
  do {
    if (i == 0) {
      token = strtok(target, ",\n ");
    } else {
      token = strtok(NULL, ",\n ");
    }
    if (token != NULL) {
      printf("token = %s\n", token);
    }
    i++;
  } while (token != NULL);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x2c4645442c434241,%rax
  movabs $0x204c4b4a0a494847,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x525150204f4e4d,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
  mov    %rsp,%r13
  lea    D2(%rip),%r12
  jmp    L1
L41:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  jmp    L19
L9:
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
L1:
  test   %ebx,%ebx
  je     L41
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
L19:
  test   %rax,%rax
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D17: ,
 

tool: D2: token = %s


assistant: ```c
int main(void) {
  char target[] = "ABC,DEF,GHI\nJKL MNO PQR";
  char *token = NULL;
  int i = 0;
  do {
    if (i == 0) {
      token = strtok(target, ",\n ");
    } else {
      token = strtok(NULL, ",\n ");
    }
    if (token != NULL) {
      printf("token = %s\n", token);
    }
    i++;
  } while (token != NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x525150204f4e4d,%rax
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %ebx,%ebx
  je     L1
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rsi,%rsi
  je     L25
L13:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L16
L1:
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rsi,%rsi
  jne    L13
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D18
type: byte[16]

tool: D25: token = %s


tool: D19: ,
 

tool: {"D18": [0x41,0x42,0x43,0x2c,0x44,0x45,0x46,0x2c,0x47,0x48,0x49,0x0a,0x4a,0x4b,0x4c,0x20]}

assistant: ```c
int main(void) {
  char target[] = "ABC,DEF,GHI\nJKL MNO PQR";
  char *token = NULL;
  int i = 0;
  do {
    if (i == 0) {
      token = strtok(target, ",\n ");
    } else {
      token = strtok(NULL, ",\n ");
    }
    if (token != NULL) {
      printf("token = %s\n", token);
    }
    i++;
  } while (token != NULL);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x525150204f4e4d,%rax
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %ebx,%ebx
  je     L36
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L0
L49:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L23
L36:
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L49
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: byte[16]

tool: D13: token = %s


tool: D19: ,
 

tool: {"D12": [0x41,0x42,0x43,0x2c,0x44,0x45,0x46,0x2c,0x47,0x48,0x49,0x0a,0x4a,0x4b,0x4c,0x20]}

assistant: ```c
int main(void) {
  char target[] = "ABC,DEF,GHI\nJKL MNO PQR";
  char *token = NULL;
  int i = 0;
  do {
    if (i == 0) {
      token = strtok(target, ",\n ");
    } else {
      token = strtok(NULL, ",\n ");
    }
    if (token != NULL) {
      printf("token = %s\n", token);
    }
    i++;
  } while (token != NULL);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<has_x_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x30(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <compare@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int has_x_command(char buffer[], char command[], int size) {
  char x_command_loc[10];
  strncpy(x_command_loc, buffer, size);
  return (compare(x_command_loc, command));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<has_x_command>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <compare@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int has_x_command(char buffer[], char command[], int size) {
  char x_command_loc[10];
  strncpy(x_command_loc, buffer, size);
  return (compare(x_command_loc, command));
}
```
user: Translate the below assembly code into C programming language:

```asm
<has_x_command>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <compare@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int has_x_command(char buffer[], char command[], int size) {
  char x_command_loc[10];
  strncpy(x_command_loc, buffer, size);
  return (compare(x_command_loc, command));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<has_x_command>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <compare@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int has_x_command(char buffer[], char command[], int size) {
  char x_command_loc[10];
  strncpy(x_command_loc, buffer, size);
  return (compare(x_command_loc, command));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <get_pid_max@plt>
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  movl   $0xfffff,-0x14(%rbp)
  jmp    L79
L31:
  subl   $0x1,-0x14(%rbp)
L79:
  cmpl   $0x0,-0x14(%rbp)
  jg     L31
  mov    $0x0,%edi
  call   <exit@plt>
L0:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%edi
  call   <wait4@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  movl   $0xfffff,-0x10(%rbp)
  jmp    L8
L7:
  subl   $0x1,-0x10(%rbp)
L8:
  cmpl   $0x0,-0x10(%rbp)
  jg     L7
  mov    $0x0,%edi
  call   <exit@plt>
L4:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  movl   $0xfffff,-0xc(%rbp)
  jmp    L63
L49:
  subl   $0x1,-0xc(%rbp)
L63:
  cmpl   $0x0,-0xc(%rbp)
  jg     L49
  mov    $0x0,%edi
  call   <exit@plt>
L10:
  mov    -0x4(%rbp),%eax
  mov    $0xffffffffffffffff,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wait4@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  pid_t epid = get_pid_max() + 1;
  pid_t child;
  wait4(epid, NULL, 0, NULL);
  wait4(-1, NULL, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, (int *)-1, 0, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, -1, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, 0, (struct rusage *)-1);
  wait4(child, 0, 0, NULL);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <get_pid_max@plt>
  lea    0x1(%rax),%edi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <wait4@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L1
  mov    $0xfffff,%eax
L12:
  sub    $0x1,%eax
  jne    L12
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    %ebx,%edi
  call   <wait4@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L36
  mov    $0xfffff,%eax
L32:
  sub    $0x1,%eax
  jne    L32
  mov    $0x0,%edi
  call   <exit@plt>
L36:
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <wait4@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L54
  mov    $0xfffff,%eax
L19:
  sub    $0x1,%eax
  jne    L19
  mov    $0x0,%edi
  call   <exit@plt>
L54:
  mov    $0xffffffffffffffff,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <wait4@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <wait4@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  pid_t epid = get_pid_max() + 1;
  pid_t child;
  wait4(epid, NULL, 0, NULL);
  wait4(-1, NULL, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, (int *)-1, 0, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, -1, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, 0, (struct rusage *)-1);
  wait4(child, 0, 0, NULL);
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <get_pid_max@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <wait4@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L13
L27:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xffffffffffffffff,%rsi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L42
L6:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L41
L23:
  mov    %ebp,%edi
  mov    $0xffffffffffffffff,%rcx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L27
L41:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L23
L42:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L6
```

assistant: ```c
int main() {
  pid_t epid = get_pid_max() + 1;
  pid_t child;
  wait4(epid, NULL, 0, NULL);
  wait4(-1, NULL, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, (int *)-1, 0, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, -1, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, 0, (struct rusage *)-1);
  wait4(child, 0, 0, NULL);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <get_pid_max@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <wait4@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L2
L25:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0xffffffffffffffff,%rsi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L40
L32:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L15
L47:
  mov    %ebp,%edi
  mov    $0xffffffffffffffff,%rcx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <wait4@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L25
L15:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L47
L40:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L32
```

assistant: ```c
int main() {
  pid_t epid = get_pid_max() + 1;
  pid_t child;
  wait4(epid, NULL, 0, NULL);
  wait4(-1, NULL, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, (int *)-1, 0, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, -1, NULL);
  wait4(child, 0, 0, NULL);
  child = fork();
  if (!child) {
    int i = 0xfffff;
    while (i > 0)
      i--;
    exit(0);
  }
  wait4(child, NULL, 0, (struct rusage *)-1);
  wait4(child, 0, 0, NULL);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_dobldobl_target_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L33:
  cmp    %rdx,%rsp
  je     L19
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L19:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L49
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L49:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L15
L4:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L15:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L4
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x21d,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_dobldobl_target_system_from_file(int n, char *filename) {
  int b[n], i, fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc4c(541, &n, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_dobldobl_target_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L23:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L39:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L31
  orq    $0x0,-0x8(%rsp,%rax,1)
L31:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L32
  mov    %ecx,%ecx
  mov    $0x0,%eax
L35:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L35
L32:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x21d,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  leave
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_dobldobl_target_system_from_file(int n, char *filename) {
  int b[n], i, fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc4c(541, &n, b, c, 0);
  return fail;
}
```