ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop_w_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
L29:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L29
  mov    %rsp,%rdi
  mov    $0x0,%esi
L5:
  mov    %rdi,%rdx
  mov    $0x0,%eax
L22:
  mov    %eax,%ecx
  xor    %esi,%ecx
  add    %ecx,(%rdx)
  add    $0x3,%eax
  add    $0x4,%rdx
  cmp    $0x60,%eax
  jne    L22
  add    $0x1,%esi
  sub    $0xffffffffffffff80,%rdi
  cmp    $0x20,%esi
  jne    L5
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L41:
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1b,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    0x1f(%rbx),%edx
  test   %ebx,%ebx
  cmovns %ebx,%edx
  sar    $0x5,%edx
  xor    %edx,%eax
  add    %ebx,%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  add    $0x1,%rbx
  cmp    $0x400,%rbx
  jne    L41
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_w_1() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (i = 0; i < 32; i++) {
#pragma acc loop worker private(x)
      for (j = 0; j < 32; j++) {
        x = i ^ j * 3;
        __asm__ __volatile__("");
        arr[i * 32 + j] += x;
      }
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + ((i / 32) ^ (i % 32) * 3));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<loop_w_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L22:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L22
  mov    %rbp,%rdi
  xor    %esi,%esi
  nopl   (%rax)
L29:
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L23:
  mov    %eax,%ecx
  add    $0x3,%eax
  xor    %esi,%ecx
  add    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    $0x60,%eax
  jne    L23
  add    $0x1,%esi
  sub    $0xffffffffffffff80,%rdi
  cmp    $0x20,%esi
  jne    L29
  xor    %ebx,%ebx
L36:
  mov    %ebx,%eax
  mov    %ebx,%edx
  xor    %edi,%edi
  and    $0x1f,%eax
  sar    $0x5,%edx
  lea    (%rax,%rax,2),%eax
  xor    %edx,%eax
  add    %ebx,%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0x400,%rbx
  jne    L36
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_w_1() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (i = 0; i < 32; i++) {
#pragma acc loop worker private(x)
      for (j = 0; j < 32; j++) {
        x = i ^ j * 3;
        __asm__ __volatile__("");
        arr[i * 32 + j] += x;
      }
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + ((i / 32) ^ (i % 32) * 3));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loop_w_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movdqa D5(%rip),%xmm0
  movdqa D4(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1000(%rsp),%rdx
  mov    %rbp,%rdi
  mov    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L23:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L23
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L14:
  mov    %eax,%ecx
  add    $0x3,%eax
  xor    %esi,%ecx
  add    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    $0x60,%eax
  jne    L14
  add    $0x1,%esi
  sub    $0xffffffffffffff80,%rdi
  cmp    $0x20,%esi
  jne    L18
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%eax
  mov    %ebx,%edx
  xor    %edi,%edi
  and    $0x1f,%eax
  sar    $0x5,%edx
  lea    (%rax,%rax,2),%eax
  xor    %edx,%eax
  add    %ebx,%eax
  cmp    0x0(%rbp,%rbx,4),%eax
  sete   %dil
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <assert@plt>
  cmp    $0x400,%rbx
  jne    L17
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: byte[16]
name: unpack_data
arguments: data_tag: D4
type: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void loop_w_1() {
  int x = 5, i, arr[32 * 32];
  for (i = 0; i < 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (i = 0; i < 32; i++) {
#pragma acc loop worker private(x)
      for (j = 0; j < 32; j++) {
        x = i ^ j * 3;
        __asm__ __volatile__("");
        arr[i * 32 + j] += x;
      }
    }
  }
  for (i = 0; i < 32 * 32; i++)
    assert(arr[i] == i + ((i / 32) ^ (i % 32) * 3));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <GET_CHR@plt>
  nop
  leave
  ret
```

assistant: ```c
GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <GET_CHR@plt>
  pop    %rbx
  ret
```

assistant: ```c
GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <GET_CHR@plt>
```

assistant: ```c
GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GET_PROMPT_CHR>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <GET_CHR@plt>
```

assistant: ```c
GET_PROMPT_CHR(c, s) int *c;
char *s;
{
  puts((char *)s);
  GET_CHR(c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L1:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int strlen_unsigned(const unsigned char *str) {
  unsigned const char *wrk = str;
  int retval;
  for (retval = 0; *wrk != '\0'; wrk++)
    retval++;
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen_unsigned>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L26
  mov    %rdi,%rax
  mov    $0x1,%edx
  sub    %edi,%edx
L19:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
L11:
  mov    %ecx,%eax
  ret
L26:
  mov    $0x0,%ecx
  jmp    L11
```

assistant: ```c
unsigned int strlen_unsigned(const unsigned char *str) {
  unsigned const char *wrk = str;
  int retval;
  for (retval = 0; *wrk != '\0'; wrk++)
    retval++;
  return retval;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen_unsigned>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    $0x1,%eax
  sub    %edi,%eax
L2:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int strlen_unsigned(const unsigned char *str) {
  unsigned const char *wrk = str;
  int retval;
  for (retval = 0; *wrk != '\0'; wrk++)
    retval++;
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen_unsigned>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x1,%eax
  sub    %edi,%eax
L15:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L15
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int strlen_unsigned(const unsigned char *str) {
  unsigned const char *wrk = str;
  int retval;
  for (retval = 0; *wrk != '\0'; wrk++)
    retval++;
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calculate_output>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    $0x0,%eax
L55:
  movq   $0x0,(%r11,%rax,1)
  movq   $0x0,(%r10,%rax,1)
  add    $0x8,%rax
  cmp    $0x1f40,%rax
  jne    L55
  mov    %r10,%rdx
  mov    %r11,%rcx
  lea    0x1f40(%r10),%r12
L4:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  mov    $0x0,%eax
L64:
  movsd  (%r8,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  movsd  (%r9,%rax,1),%xmm1
  mulsd  (%rsi,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%r9,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  movsd  (%r8,%rax,1),%xmm1
  mulsd  (%rsi,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  cmp    $0x1f40,%rax
  jne    L64
  add    $0x8,%rdx
  add    $0x1f40,%rbp
  add    $0x1f40,%rbx
  add    $0x8,%rcx
  cmp    %r12,%rdx
  jne    L4
  mov    D8(%rip),%rax
  movsd  (%rax),%xmm2
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L8
L39:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  je     L37
L8:
  movsd  (%r10,%rax,8),%xmm0
  movsd  (%r11,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jb     L39
  mov    %eax,%edx
  movapd %xmm0,%xmm2
  jmp    L39
L37:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int calculate_output(double aux_real[1000], double aux_img[1000], double matrice_real[1000][1000], double matrice_img[1000][1000], double snapshot_real[1000], double snapshot_img[1000]) {
  int i, j, t;
  double val, t_val;
  int t1, t2, t3;
  int lb, ub, lbp, ubp, lb2, ub2;
  register int lbv, ubv;
  lbp = 0;
  ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
  for (t2 = lbp; t2 <= ubp; t2++) {
    aux_img[t2] = 0;
    ;
    aux_real[t2] = 0;
    ;
  }
  if (1000 >= 1) {
    lbp = 0;
    ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
    for (t2 = lbp; t2 <= ubp; t2++) {
      for (t3 = 0; t3 <= 1000 - 1; t3++) {
        aux_real[t2] += snapshot_real[t3] * matrice_real[t2][t3] - snapshot_img[t3] * matrice_img[t2][t3];
        aux_img[t2] += snapshot_img[t3] * matrice_real[t2][t3] + snapshot_real[t3] * matrice_img[t2][t3];
        ;
      }
    }
  }
  t = 0;
  ;
  t_val = DBL_MIN;
  ;
  if (1000 >= 1) {
    for (t2 = 0; t2 <= 1000 - 1; t2++) {
      val = aux_real[t2] * aux_real[t2] + aux_img[t2] * aux_img[t2];
      t = (val >= t_val) ? (t_val = val, t2) : t;
      ;
    }
  }
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calculate_output>:
  endbr64
  lea    0x1f3f(%rdi),%rax
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%rbx
  sub    %rsi,%rax
  mov    %rcx,%r11
  cmp    $0x3e7e,%rax
  mov    $0x0,%eax
  jbe    L47
  lea    0x8(%rsi),%rdi
  mov    %rsi,%rcx
  movq   $0x0,(%rsi)
  movq   $0x0,0x1f38(%rsi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1f40,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  movq   $0x0,(%r10)
  movq   $0x0,0x1f38(%r10)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1f40,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
L12:
  mov    %rbx,%rdi
  mov    %r11,%rcx
  mov    %r10,%rdx
  mov    %rsi,%r11
  lea    0x1f40(%r10),%rbx
L54:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L58:
  movsd  (%r8,%rax,1),%xmm0
  movsd  (%r9,%rax,1),%xmm1
  mulsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%r9,%rax,1),%xmm0
  movsd  (%r8,%rax,1),%xmm1
  mulsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  addsd  (%r11),%xmm0
  movsd  %xmm0,(%r11)
  cmp    $0x1f40,%rax
  jne    L58
  add    $0x8,%rdx
  add    $0x1f40,%rdi
  add    $0x1f40,%rcx
  add    $0x8,%r11
  cmp    %rbx,%rdx
  jne    L54
  mov    D6(%rip),%rax
  xor    %r8d,%r8d
  movsd  (%rax),%xmm2
  xor    %eax,%eax
L17:
  movsd  (%r10,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jb     L19
  mov    %eax,%r8d
  movapd %xmm0,%xmm2
L19:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L17
  mov    %r8d,%eax
  pop    %rbx
  ret
L47:
  movq   $0x0,(%rsi,%rax,1)
  movq   $0x0,(%r10,%rax,1)
  add    $0x8,%rax
  cmp    $0x1f40,%rax
  jne    L47
  jmp    L12
```

assistant: ```c
int calculate_output(double aux_real[1000], double aux_img[1000], double matrice_real[1000][1000], double matrice_img[1000][1000], double snapshot_real[1000], double snapshot_img[1000]) {
  int i, j, t;
  double val, t_val;
  int t1, t2, t3;
  int lb, ub, lbp, ubp, lb2, ub2;
  register int lbv, ubv;
  lbp = 0;
  ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
  for (t2 = lbp; t2 <= ubp; t2++) {
    aux_img[t2] = 0;
    ;
    aux_real[t2] = 0;
    ;
  }
  if (1000 >= 1) {
    lbp = 0;
    ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
    for (t2 = lbp; t2 <= ubp; t2++) {
      for (t3 = 0; t3 <= 1000 - 1; t3++) {
        aux_real[t2] += snapshot_real[t3] * matrice_real[t2][t3] - snapshot_img[t3] * matrice_img[t2][t3];
        aux_img[t2] += snapshot_img[t3] * matrice_real[t2][t3] + snapshot_real[t3] * matrice_img[t2][t3];
        ;
      }
    }
  }
  t = 0;
  ;
  t_val = DBL_MIN;
  ;
  if (1000 >= 1) {
    for (t2 = 0; t2 <= 1000 - 1; t2++) {
      val = aux_real[t2] * aux_real[t2] + aux_img[t2] * aux_img[t2];
      t = (val >= t_val) ? (t_val = val, t2) : t;
      ;
    }
  }
  return t;
}
```
user: What is the c source code of the assembly code below:

```asm
<calculate_output>:
  endbr64
  lea    0x1f3f(%rdi),%rax
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%rbx
  sub    %rsi,%rax
  mov    %rcx,%r11
  cmp    $0x3e7e,%rax
  mov    $0x0,%eax
  jbe    L53
  lea    0x8(%rsi),%rdi
  mov    %rsi,%rcx
  movq   $0x0,(%rsi)
  movq   $0x0,0x1f38(%rsi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1f40,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  movq   $0x0,(%r10)
  movq   $0x0,0x1f38(%r10)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1f40,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
L66:
  mov    %rbx,%rdi
  mov    %r11,%rcx
  mov    %r10,%rdx
  mov    %rsi,%r11
  lea    0x1f40(%r10),%rbx
L40:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L38:
  movsd  (%r8,%rax,1),%xmm0
  movsd  (%r9,%rax,1),%xmm1
  mulsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%r9,%rax,1),%xmm0
  movsd  (%r8,%rax,1),%xmm1
  mulsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  addsd  (%r11),%xmm0
  movsd  %xmm0,(%r11)
  cmp    $0x1f40,%rax
  jne    L38
  add    $0x8,%rdx
  add    $0x1f40,%rdi
  add    $0x1f40,%rcx
  add    $0x8,%r11
  cmp    %rbx,%rdx
  jne    L40
  mov    D2(%rip),%rax
  xor    %r8d,%r8d
  movsd  (%rax),%xmm2
  xor    %eax,%eax
L19:
  movsd  (%r10,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jb     L52
  mov    %eax,%r8d
  movapd %xmm0,%xmm2
L52:
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L19
  mov    %r8d,%eax
  pop    %rbx
  ret
L53:
  movq   $0x0,(%rsi,%rax,1)
  movq   $0x0,(%r10,%rax,1)
  add    $0x8,%rax
  cmp    $0x1f40,%rax
  jne    L53
  jmp    L66
```

assistant: ```c
int calculate_output(double aux_real[1000], double aux_img[1000], double matrice_real[1000][1000], double matrice_img[1000][1000], double snapshot_real[1000], double snapshot_img[1000]) {
  int i, j, t;
  double val, t_val;
  int t1, t2, t3;
  int lb, ub, lbp, ubp, lb2, ub2;
  register int lbv, ubv;
  lbp = 0;
  ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
  for (t2 = lbp; t2 <= ubp; t2++) {
    aux_img[t2] = 0;
    ;
    aux_real[t2] = 0;
    ;
  }
  if (1000 >= 1) {
    lbp = 0;
    ubp = 1000 - 1;
#pragma omp parallel for private(lbv, ubv, t3)
    for (t2 = lbp; t2 <= ubp; t2++) {
      for (t3 = 0; t3 <= 1000 - 1; t3++) {
        aux_real[t2] += snapshot_real[t3] * matrice_real[t2][t3] - snapshot_img[t3] * matrice_img[t2][t3];
        aux_img[t2] += snapshot_img[t3] * matrice_real[t2][t3] + snapshot_real[t3] * matrice_img[t2][t3];
        ;
      }
    }
  }
  t = 0;
  ;
  t_val = DBL_MIN;
  ;
  if (1000 >= 1) {
    for (t2 = 0; t2 <= 1000 - 1; t2++) {
      val = aux_real[t2] * aux_real[t2] + aux_img[t2] * aux_img[t2];
      t = (val >= t_val) ? (t_val = val, t2) : t;
      ;
    }
  }
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CleanupPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L0
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L28
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L0
L28:
  subl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *CleanupPath(const char *Path) {
  unsigned Len;
  char *NewPath;
  Len = strlen(Path);
  if (Len > 0 && (Path[Len - 1] == '\\' || Path[Len - 1] == '/')) {
    --Len;
  }
  NewPath = (char *)xmalloc(Len + 1);
  memcpy(NewPath, Path, Len);
  NewPath[Len] = '\0';
  return NewPath;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CleanupPath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L13
  lea    -0x1(%rax),%edx
  mov    %edx,%eax
  movzbl (%r12,%rax,1),%eax
  cmp    $0x5c,%al
  je     L6
  cmp    $0x2f,%al
  jne    L13
L6:
  mov    %edx,%ebx
L13:
  lea    0x1(%rbx),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %ebx,%ebx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *CleanupPath(const char *Path) {
  unsigned Len;
  char *NewPath;
  Len = strlen(Path);
  if (Len > 0 && (Path[Len - 1] == '\\' || Path[Len - 1] == '/')) {
    --Len;
  }
  NewPath = (char *)xmalloc(Len + 1);
  memcpy(NewPath, Path, Len);
  NewPath[Len] = '\0';
  return NewPath;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CleanupPath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L30
  lea    -0x1(%rax),%ebx
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %rbx,%rdx
  cmp    $0x5c,%al
  je     L42
  cmp    $0x2f,%al
  je     L42
  lea    0x1(%r12),%edi
  mov    %r12d,%ebx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %ebx,%ebx
  mov    $0x1,%edi
L12:
  call   <xmalloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L42:
  mov    %r12d,%edi
  mov    %edx,%r12d
  jmp    L12
```

assistant: ```c
char *CleanupPath(const char *Path) {
  unsigned Len;
  char *NewPath;
  Len = strlen(Path);
  if (Len > 0 && (Path[Len - 1] == '\\' || Path[Len - 1] == '/')) {
    --Len;
  }
  NewPath = (char *)xmalloc(Len + 1);
  memcpy(NewPath, Path, Len);
  NewPath[Len] = '\0';
  return NewPath;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CleanupPath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L41
  lea    -0x1(%rax),%ebx
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %rbx,%rdx
  cmp    $0x5c,%al
  je     L30
  cmp    $0x2f,%al
  je     L30
  lea    0x1(%r12),%edi
  mov    %r12d,%ebx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L41:
  xor    %ebx,%ebx
  mov    $0x1,%edi
L0:
  call   <xmalloc@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  mov    %r12d,%edi
  mov    %edx,%r12d
  jmp    L0
```

assistant: ```c
char *CleanupPath(const char *Path) {
  unsigned Len;
  char *NewPath;
  Len = strlen(Path);
  if (Len > 0 && (Path[Len - 1] == '\\' || Path[Len - 1] == '/')) {
    --Len;
  }
  NewPath = (char *)xmalloc(Len + 1);
  memcpy(NewPath, Path, Len);
  NewPath[Len] = '\0';
  return NewPath;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L1
L20:
  movzbl -0x3f0(%rbp),%eax
  cmp    $0xa,%al
  je     L1
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getlineuser@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  while ((len = getlineuser(line, 1000)) > 0) {
    if (line[0] == '\n')
      ;
    else
      printf("%s", line);
  }
  return 0;
}
```