ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6e,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_infered: string
name: extract_symbolic_data
arguments: label: D67
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D27
type_infered: string
name: extract_symbolic_data
arguments: label: D46
type_infered: string
name: extract_symbolic_data
arguments: label: D63
type_infered: string

tool: D23: Usage optionsn

tool: D67:   -h --help            Prints this messagen

tool: D31:   -d --debug           Prints debug informationn

tool: D6:   -c --columns         Sets the number of columns of the matrix (default value = %d)n

tool: D27:   -r --rows            Sets the number of rows of the matrix (default value = %d)n

tool: D46:   -bycolumn            Accesses the matrix by columnn

tool: D63:   -byrow               Accesses the matrix by row (default)n

assistant: ```c
void usage() {
  printf("Usage optionsn");
  printf("  -h --help            Prints this messagen");
  printf("  -d --debug           Prints debug informationn");
  printf("  -c --columns         Sets the number of columns of the matrix (default value = %d)n", 100);
  printf("  -r --rows            Sets the number of rows of the matrix (default value = %d)n", 100);
  printf("  -bycolumn            Accesses the matrix by columnn");
  printf("  -byrow               Accesses the matrix by row (default)n");
  printf("n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6e,%edi
  add    $0x8,%rsp
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D25
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D56
type: string
name: unpack_data
arguments: tag: D39
type: string
name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D55
type: string

tool: D0: Usage optionsn

tool: D25:   -h --help            Prints this messagen

tool: D12:   -d --debug           Prints debug informationn

tool: D56:   -c --columns         Sets the number of columns of the matrix (default value = %d)n

tool: D39:   -r --rows            Sets the number of rows of the matrix (default value = %d)n

tool: D1:   -bycolumn            Accesses the matrix by columnn

tool: D55:   -byrow               Accesses the matrix by row (default)n

assistant: ```c
void usage() {
  printf("Usage optionsn");
  printf("  -h --help            Prints this messagen");
  printf("  -d --debug           Prints debug informationn");
  printf("  -c --columns         Sets the number of columns of the matrix (default value = %d)n", 100);
  printf("  -r --rows            Sets the number of rows of the matrix (default value = %d)n", 100);
  printf("  -bycolumn            Accesses the matrix by columnn");
  printf("  -byrow               Accesses the matrix by row (default)n");
  printf("n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6e,%edi
  add    $0x8,%rsp
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D68
datatype: string
name: read_data
arguments: tag: D2
datatype: string
name: read_data
arguments: tag: D51
datatype: string
name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D36
datatype: string

tool: D68: Usage optionsn

tool: D2:   -h --help            Prints this messagen

tool: D51:   -d --debug           Prints debug informationn

tool: D11:   -c --columns         Sets the number of columns of the matrix (default value = %d)n

tool: D18:   -r --rows            Sets the number of rows of the matrix (default value = %d)n

tool: D24:   -bycolumn            Accesses the matrix by columnn

tool: D36:   -byrow               Accesses the matrix by row (default)n

assistant: ```c
void usage() {
  printf("Usage optionsn");
  printf("  -h --help            Prints this messagen");
  printf("  -d --debug           Prints debug informationn");
  printf("  -c --columns         Sets the number of columns of the matrix (default value = %d)n", 100);
  printf("  -r --rows            Sets the number of rows of the matrix (default value = %d)n", 100);
  printf("  -bycolumn            Accesses the matrix by columnn");
  printf("  -byrow               Accesses the matrix by row (default)n");
  printf("n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcd_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <lcd_wr_char@plt>
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void lcd_string(char *str) {
  while (*str != '\0') {
    lcd_wr_char(*str);
    str++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lcd_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L18:
  movsbl %dil,%edi
  call   <lcd_wr_char@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L4:
  pop    %rbx
  ret
```

assistant: ```c
void lcd_string(char *str) {
  while (*str != '\0') {
    lcd_wr_char(*str);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcd_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L13:
  call   <lcd_wr_char@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L19:
  pop    %rbx
  ret
```

assistant: ```c
void lcd_string(char *str) {
  while (*str != '\0') {
    lcd_wr_char(*str);
    str++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<lcd_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L7:
  call   <lcd_wr_char@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L14:
  pop    %rbx
  ret
```

assistant: ```c
void lcd_string(char *str) {
  while (*str != '\0') {
    lcd_wr_char(*str);
    str++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xilinxcorelib_a_4066303846_3212880686_p_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x1018,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x39(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x61b0,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl -0x39(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast@plt>
  mov    -0x48(%rbp),%rax
  add    $0x5fd0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void xilinxcorelib_a_4066303846_3212880686_p_6(char *t0) {
  char *t1;
  char *t2;
  unsigned char t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
  char *t8;
LAB0:
LAB3:
  t1 = (t0 + 4120U);
  t2 = *((char **)t1);
  t3 = *((unsigned char *)t2);
  t1 = (t0 + 25008);
  t4 = (t1 + 56U);
  t5 = *((char **)t4);
  t6 = (t5 + 56U);
  t7 = *((char **)t6);
  *((unsigned char *)t7) = t3;
  xsi_driver_first_trans_fast(t1);
LAB2:
  t8 = (t0 + 24528);
  *((int *)t8) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xilinxcorelib_a_4066303846_3212880686_p_6>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x1018(%rdi),%rax
  movzbl (%rax),%edx
  mov    0x61e8(%rdi),%rax
  mov    0x38(%rax),%rax
  mov    %dl,(%rax)
  lea    0x61b0(%rdi),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5fd0(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_4066303846_3212880686_p_6(char *t0) {
  char *t1;
  char *t2;
  unsigned char t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
  char *t8;
LAB0:
LAB3:
  t1 = (t0 + 4120U);
  t2 = *((char **)t1);
  t3 = *((unsigned char *)t2);
  t1 = (t0 + 25008);
  t4 = (t1 + 56U);
  t5 = *((char **)t4);
  t6 = (t5 + 56U);
  t7 = *((char **)t6);
  *((unsigned char *)t7) = t3;
  xsi_driver_first_trans_fast(t1);
LAB2:
  t8 = (t0 + 24528);
  *((int *)t8) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: What is the c source code of the assembly code below:

```asm
<xilinxcorelib_a_4066303846_3212880686_p_6>:
  endbr64
  push   %rbx
  mov    0x1018(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x61b0(%rdi),%rdi
  movzbl (%rax),%edx
  mov    0x38(%rdi),%rax
  mov    0x38(%rax),%rax
  mov    %dl,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5fd0(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_4066303846_3212880686_p_6(char *t0) {
  char *t1;
  char *t2;
  unsigned char t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
  char *t8;
LAB0:
LAB3:
  t1 = (t0 + 4120U);
  t2 = *((char **)t1);
  t3 = *((unsigned char *)t2);
  t1 = (t0 + 25008);
  t4 = (t1 + 56U);
  t5 = *((char **)t4);
  t6 = (t5 + 56U);
  t7 = *((char **)t6);
  *((unsigned char *)t7) = t3;
  xsi_driver_first_trans_fast(t1);
LAB2:
  t8 = (t0 + 24528);
  *((int *)t8) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xilinxcorelib_a_4066303846_3212880686_p_6>:
  endbr64
  push   %rbx
  mov    0x1018(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x61b0(%rdi),%rdi
  movzbl (%rax),%edx
  mov    0x38(%rdi),%rax
  mov    0x38(%rax),%rax
  mov    %dl,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5fd0(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_4066303846_3212880686_p_6(char *t0) {
  char *t1;
  char *t2;
  unsigned char t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
  char *t8;
LAB0:
LAB3:
  t1 = (t0 + 4120U);
  t2 = *((char **)t1);
  t3 = *((unsigned char *)t2);
  t1 = (t0 + 25008);
  t4 = (t1 + 56U);
  t5 = *((char **)t4);
  t6 = (t5 + 56U);
  t7 = *((char **)t6);
  *((unsigned char *)t7) = t3;
  xsi_driver_first_trans_fast(t1);
LAB2:
  t8 = (t0 + 24528);
  *((int *)t8) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<splitline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L145
  mov    D4(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <emalloc@plt>
  mov    %rax,%r14
  mov    0x0(%rbp),%eax
  mov    %eax,0xc(%rsp)
  cltq
  shr    $0x3,%rax
  mov    %eax,0x8(%rsp)
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  cmpb   $0x0,(%rbx)
  jne    L79
L154:
  movslq %r13d,%r13
  movq   $0x0,(%r14,%r13,8)
L84:
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L134:
  mov    D4(%rip),%rbx
  mov    0xc(%rsp),%r15d
  mov    %r15d,%esi
  add    (%rbx),%esi
  mov    %r14,%rdi
  call   <erealloc@plt>
  mov    %rax,%r14
  mov    (%rbx),%eax
  add    %eax,%r15d
  mov    %r15d,0xc(%rsp)
  cltq
  shr    $0x3,%rax
  add    %eax,0x8(%rsp)
  jmp    L71
L61:
  lea    (%r14,%rbp,8),%r15
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <newstr@plt>
  mov    %rax,(%r15)
  add    $0x1,%rbp
  cmpb   $0x0,(%rbx)
  je     L154
L79:
  mov    %ebp,%edx
  mov    %ebp,%r13d
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L117
  mov    %rbx,%r12
  cmp    $0x9,%al
  jne    L94
L117:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L117
  cmp    $0x9,%al
  je     L117
  mov    %rbx,%r12
L94:
  test   %al,%al
  je     L154
  lea    0x1(%rdx),%r13d
  cmp    0x8(%rsp),%r13d
  jge    L134
L71:
  lea    0x1(%r12),%rbx
  movzbl 0x1(%r12),%eax
  mov    $0x1,%esi
  test   %al,%al
  je     L61
L0:
  cmp    $0x20,%al
  je     L61
  cmp    $0x9,%al
  je     L61
  add    $0x1,%esi
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L0
  jmp    L61
L145:
  mov    %rdi,%r14
  jmp    L84
```

assistant: ```c
char **splitline(char *line) {
  char *newstr();
  char **args;
  int spots = 0;
  int bufspace = 0;
  int argnum = 0;
  char *cp = line;
  char *start;
  int len;
  if (line == NULL)
    return NULL;
  args = emalloc(BUFSIZ);
  bufspace = BUFSIZ;
  spots = BUFSIZ / sizeof(char *);
  while (*cp != '\0') {
    while (((*cp) == ' ' || (*cp) == '\t'))
      cp++;
    if (*cp == '\0')
      break;
    if (argnum + 1 >= spots) {
      args = erealloc(args, bufspace + BUFSIZ);
      bufspace += BUFSIZ;
      spots += BUFSIZ / sizeof(char *);
    }
    start = cp;
    len = 1;
    while (*++cp != '\0' && !((*cp) == ' ' || (*cp) == '\t'))
      len++;
    args[argnum++] = newstr(start, len);
  }
  args[argnum] = NULL;
  return args;
}
```
user: What is the c source code of the assembly code below?

```asm
<splitline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L16
  mov    D37(%rip),%rax
  mov    %rdi,%rbx
  xor    %r15d,%r15d
  mov    (%rax),%edi
  call   <emalloc@plt>
  mov    %rax,%r12
  mov    D37(%rip),%rax
  movslq (%rax),%rbp
  movzbl (%rbx),%eax
  mov    %ebp,0x4(%rsp)
  shr    $0x3,%rbp
  test   %al,%al
  je     L87
  nop
L55:
  mov    %r15d,%r14d
  movslq %r15d,%rdx
  cmp    $0x9,%al
  je     L28
  cmp    $0x20,%al
  jne    L152
  xchg   %ax,%ax
L28:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L28
  cmp    $0x9,%al
  je     L28
  test   %al,%al
  je     L117
L152:
  add    $0x1,%r14d
  mov    %rbx,%r8
  cmp    %ebp,%r14d
  jge    L159
L25:
  movzbl 0x1(%r8),%eax
  add    $0x1,%rbx
  mov    $0x1,%esi
  test   %al,%al
  je     L62
  cs nopw 0x0(%rax,%rax,1)
L26:
  cmp    $0x20,%al
  je     L62
  cmp    $0x9,%al
  je     L62
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%esi
  test   %al,%al
  jne    L26
L62:
  mov    %r8,%rdi
  xor    %eax,%eax
  lea    (%r12,%r15,8),%r13
  add    $0x1,%r15
  call   <newstr@plt>
  mov    %rax,0x0(%r13)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L55
  movslq %r14d,%r14
  lea    (%r12,%r14,8),%rax
L60:
  movq   $0x0,(%rax)
L38:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L159:
  mov    D37(%rip),%rax
  mov    0x4(%rsp),%r13d
  mov    %r12,%rdi
  mov    %rbx,0x8(%rsp)
  mov    (%rax),%esi
  add    %r13d,%esi
  call   <erealloc@plt>
  mov    0x8(%rsp),%r8
  mov    %rax,%r12
  mov    D37(%rip),%rax
  movslq (%rax),%rax
  add    %eax,%r13d
  shr    $0x3,%rax
  mov    %r13d,0x4(%rsp)
  add    %eax,%ebp
  jmp    L25
L117:
  lea    (%r12,%rdx,8),%rax
  jmp    L60
L16:
  xor    %r12d,%r12d
  jmp    L38
L87:
  mov    %r12,%rax
  jmp    L60
```

assistant: ```c
char **splitline(char *line) {
  char *newstr();
  char **args;
  int spots = 0;
  int bufspace = 0;
  int argnum = 0;
  char *cp = line;
  char *start;
  int len;
  if (line == NULL)
    return NULL;
  args = emalloc(BUFSIZ);
  bufspace = BUFSIZ;
  spots = BUFSIZ / sizeof(char *);
  while (*cp != '\0') {
    while (((*cp) == ' ' || (*cp) == '\t'))
      cp++;
    if (*cp == '\0')
      break;
    if (argnum + 1 >= spots) {
      args = erealloc(args, bufspace + BUFSIZ);
      bufspace += BUFSIZ;
      spots += BUFSIZ / sizeof(char *);
    }
    start = cp;
    len = 1;
    while (*++cp != '\0' && !((*cp) == ' ' || (*cp) == '\t'))
      len++;
    args[argnum++] = newstr(start, len);
  }
  args[argnum] = NULL;
  return args;
}
```
user: Translate the below assembly code into C programming language:

```asm
<splitline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L45
  mov    D35(%rip),%rax
  mov    %rdi,%rbx
  xor    %r15d,%r15d
  mov    (%rax),%edi
  call   <emalloc@plt>
  mov    %rax,%r12
  mov    D35(%rip),%rax
  movslq (%rax),%rbp
  movzbl (%rbx),%eax
  mov    %ebp,0x4(%rsp)
  shr    $0x3,%rbp
  test   %al,%al
  je     L68
  nop
L164:
  mov    %r15d,%r14d
  movslq %r15d,%rdx
  cmp    $0x9,%al
  je     L57
  cmp    $0x20,%al
  jne    L87
  xchg   %ax,%ax
L57:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L57
  cmp    $0x9,%al
  je     L57
  test   %al,%al
  je     L69
L87:
  add    $0x1,%r14d
  mov    %rbx,%r8
  cmp    %r14d,%ebp
  jle    L60
L12:
  movzbl 0x1(%r8),%eax
  add    $0x1,%rbx
  mov    $0x1,%esi
  test   %al,%al
  je     L108
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    $0x20,%al
  je     L108
  cmp    $0x9,%al
  je     L108
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%esi
  test   %al,%al
  jne    L19
L108:
  mov    %r8,%rdi
  xor    %eax,%eax
  lea    (%r12,%r15,8),%r13
  add    $0x1,%r15
  call   <newstr@plt>
  mov    %rax,0x0(%r13)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L164
  movslq %r14d,%r14
  lea    (%r12,%r14,8),%rax
L132:
  movq   $0x0,(%rax)
L93:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  mov    D35(%rip),%rax
  mov    0x4(%rsp),%r13d
  mov    %r12,%rdi
  mov    %rbx,0x8(%rsp)
  mov    (%rax),%esi
  add    %r13d,%esi
  call   <erealloc@plt>
  mov    0x8(%rsp),%r8
  mov    %rax,%r12
  mov    D35(%rip),%rax
  movslq (%rax),%rax
  add    %eax,%r13d
  shr    $0x3,%rax
  mov    %r13d,0x4(%rsp)
  add    %eax,%ebp
  jmp    L12
L69:
  lea    (%r12,%rdx,8),%rax
  jmp    L132
L45:
  xor    %r12d,%r12d
  jmp    L93
L68:
  mov    %r12,%rax
  jmp    L132
```

assistant: ```c
char **splitline(char *line) {
  char *newstr();
  char **args;
  int spots = 0;
  int bufspace = 0;
  int argnum = 0;
  char *cp = line;
  char *start;
  int len;
  if (line == NULL)
    return NULL;
  args = emalloc(BUFSIZ);
  bufspace = BUFSIZ;
  spots = BUFSIZ / sizeof(char *);
  while (*cp != '\0') {
    while (((*cp) == ' ' || (*cp) == '\t'))
      cp++;
    if (*cp == '\0')
      break;
    if (argnum + 1 >= spots) {
      args = erealloc(args, bufspace + BUFSIZ);
      bufspace += BUFSIZ;
      spots += BUFSIZ / sizeof(char *);
    }
    start = cp;
    len = 1;
    while (*++cp != '\0' && !((*cp) == ' ' || (*cp) == '\t'))
      len++;
    args[argnum++] = newstr(start, len);
  }
  args[argnum] = NULL;
  return args;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ip_or_domain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L57
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jg     L63
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L63
  mov    $0x1,%eax
  jmp    L57
L63:
  nop
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L1
  mov    $0x0,%eax
L57:
  leave
  ret
```

assistant: ```c
int ip_or_domain(const char *host) {
  if (!host) {
    return -1;
  }
  int i;
  for (i = 0; i < strlen(host); i++) {
    if ((host[i] <= '9' && host[i] >= '0') || '.' == host[i]) {
      continue;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ip_or_domain>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L26:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L16
  movzbl (%rbx,%rbp,1),%eax
  add    $0x1,%rbp
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L26
  cmp    $0x2e,%al
  je     L26
  mov    $0x1,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x0,%eax
  jmp    L9
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ip_or_domain(const char *host) {
  if (!host) {
    return -1;
  }
  int i;
  for (i = 0; i < strlen(host); i++) {
    if ((host[i] <= '9' && host[i] >= '0') || '.' == host[i]) {
      continue;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ip_or_domain>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L22:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L12
  movzbl (%rbx,%rbp,1),%eax
  add    $0x1,%rbp
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L22
  cmp    $0x2e,%al
  je     L22
  mov    $0x1,%eax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  jmp    L42
```

assistant: ```c
int ip_or_domain(const char *host) {
  if (!host) {
    return -1;
  }
  int i;
  for (i = 0; i < strlen(host); i++) {
    if ((host[i] <= '9' && host[i] >= '0') || '.' == host[i]) {
      continue;
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ip_or_domain>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L15
  movzbl (%rbx,%rbp,1),%eax
  add    $0x1,%rbp
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L5
  cmp    $0x2e,%al
  je     L5
  mov    $0x1,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  jmp    L19
```

assistant: ```c
int ip_or_domain(const char *host) {
  if (!host) {
    return -1;
  }
  int i;
  for (i = 0; i < strlen(host); i++) {
    if ((host[i] <= '9' && host[i] >= '0') || '.' == host[i]) {
      continue;
    } else {
      return 1;
    }
  }
  return 0;
}
```