user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D78(%rip),%r13
  lea    D88(%rip),%r12
  lea    D60(%rip),%rbp
  jmp    L49
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <insertbeg@plt>
  mov    $0x0,%eax
  call   <display@plt>
L49:
  mov    %rsp,%rbx
L42:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    $0x8,%eax
  je     L115
  cmp    $0x7,%eax
  ja     L42
  mov    %eax,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <insertend@plt>
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L49
  lea    D66(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <deleteele@plt>
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L49
  mov    $0x0,%eax
  call   <count@plt>
  mov    %eax,%esi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L49
  lea    D74(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <search@plt>
  cmp    $0x1,%eax
  je     L113
  lea    D45(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L113:
  lea    D84(%rip),%rdi
  call   <puts@plt>
  jmp    L49
  mov    $0x0,%eax
  call   <reverse@plt>
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L49
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L49
L115:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D78
type: string
name: unpack_data
arguments: data_label: D88
type: string
name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D66
type: string
name: unpack_data
arguments: data_label: D80
type: string
name: unpack_data
arguments: data_label: D74
type: string
name: unpack_data
arguments: data_label: D45
type: string
name: unpack_data
arguments: data_label: D84
type: string

tool: D78: Enter choice: 1. Insertbeg 2. Insertend 3. Delete ele 4. Count 5. Search 6. Reverse 7. Display 8. Exit - 

tool: D88: %d

tool: D27: Enter element to be inserted

tool: D66: Enter element to be deleted

tool: D80: Count = %d

tool: D74: Enter element to be searched

tool: D45: Element not found

tool: D84: Element found

assistant: ```c
void main() {
  int ch, ele, z;
  while (1) {
    printf("Enter choice: 1. Insertbeg 2. Insertend 3. Delete ele 4. Count 5. Search 6. Reverse 7. Display 8. Exit - ");
    scanf("%d", &ch);
    if (ch == 8)
      break;
    switch (ch) {
    case 1:
      printf("Enter element to be inserted\n");
      scanf("%d", &ele);
      insertbeg(ele);
      display();
      break;
    case 2:
      printf("Enter element to be inserted\n");
      scanf("%d", &ele);
      insertend(ele);
      display();
      break;
    case 3:
      printf("Enter element to be deleted\n");
      scanf("%d", &ele);
      deleteele(ele);
      display();
      break;
    case 4:
      z = count();
      printf("Count = %d", z);
      break;
    case 5:
      printf("Enter element to be searched\n");
      scanf("%d", &ele);
      z = search(ele);
      if (z == 1)
        printf("Element found\n");
      else
        printf("Element not found\n");
      break;
    case 6:
      reverse();
      display();
      break;
    case 7:
      display();
      break;
    }
  }
}
```