ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiplicacion>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    0x1(%rsi),%ecx
  mov    $0x1,%edx
L7:
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L7
  mov    %esi,%eax
  imul   %edi,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int multiplicacion(int a, int b) {
  int resultado;
  int i;
  for (i = 1; i <= b; i = i + 1) {
    resultado = resultado + a;
  }
  return resultado;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<multiplicacion>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    %esi,%eax
  imul   %edi,%eax
  ret
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int multiplicacion(int a, int b) {
  int resultado;
  int i;
  for (i = 1; i <= b; i = i + 1) {
    resultado = resultado + a;
  }
  return resultado;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiplicacion>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %esi,%eax
  imul   %edi,%eax
  ret
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int multiplicacion(int a, int b) {
  int resultado;
  int i;
  for (i = 1; i <= b; i = i + 1) {
    resultado = resultado + a;
  }
  return resultado;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simp1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r9,(%rsp)
  mov    0x50(%rsp),%r12
  test   %ecx,%ecx
  jle    L65
  mov    %esi,%eax
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  mov    %r8d,%r15d
  mov    0x4(%rdx),%edx
  mov    (%rsp),%rsi
  mov    %edx,(%rsi)
  cltq
  lea    0x8(%rdi,%rax,8),%r14
  movslq %edx,%rdx
  mov    (%r14),%rax
  movss  0x4(%rax,%rdx,4),%xmm0
  movss  %xmm0,(%r12)
  cmp    $0x1,%ecx
  jle    L24
  mov    $0x2,%ebx
  jmp    L42
L65:
  movl   $0x0,(%r12)
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  movslq 0x0(%rbp,%rbx,4),%rdx
  mov    (%r14),%rax
  movss  0x4(%rax,%rdx,4),%xmm0
  call   <fabs@plt>
  movss  %xmm0,0xc(%rsp)
  movss  (%r12),%xmm0
  call   <fabs@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  subss  %xmm1,%xmm0
  jmp    L62
L9:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L24
L42:
  test   %r15d,%r15d
  jne    L16
  movslq 0x0(%rbp,%rbx,4),%rdx
  mov    (%r14),%rax
  movss  0x4(%rax,%rdx,4),%xmm0
  subss  (%r12),%xmm0
L62:
  pxor   %xmm2,%xmm2
  comiss %xmm2,%xmm0
  jbe    L9
  movslq 0x0(%rbp,%rbx,4),%rdx
  mov    (%r14),%rax
  movss  0x4(%rax,%rdx,4),%xmm0
  movss  %xmm0,(%r12)
  mov    0x0(%rbp,%rbx,4),%eax
  mov    (%rsp),%rcx
  mov    %eax,(%rcx)
  jmp    L9
```

assistant: ```c
void simp1(float **a, int mm, int ll[], int nll, int iabf, int *kp, float *bmax) {
  int k;
  float test;
  if (nll <= 0)
    *bmax = 0.0;
  else {
    *kp = ll[1];
    *bmax = a[mm + 1][*kp + 1];
    for (k = 2; k <= nll; k++) {
      if (iabf == 0)
        test = a[mm + 1][ll[k] + 1] - (*bmax);
      else
        test = fabs(a[mm + 1][ll[k] + 1]) - fabs(*bmax);
      if (test > 0.0) {
        *bmax = a[mm + 1][ll[k] + 1];
        *kp = ll[k];
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<simp1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r12
  test   %ecx,%ecx
  jle    L3
  movslq %esi,%rax
  mov    %rdx,%rbp
  movslq 0x4(%rdx),%rdx
  mov    %ecx,%r13d
  lea    0x8(%rdi,%rax,8),%r14
  mov    (%r14),%rax
  mov    %edx,(%r9)
  movss  0x4(%rax,%rdx,4),%xmm0
  movss  %xmm0,(%r12)
  cmp    $0x1,%ecx
  je     L58
  mov    %r8d,%r15d
  mov    $0x2,%ebx
  pxor   %xmm2,%xmm2
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L49:
  subss  (%r12),%xmm0
L29:
  comiss %xmm2,%xmm0
  jbe    L50
  movslq 0x0(%rbp,%rbx,4),%rcx
  mov    (%r14),%rdx
  movss  0x4(%rdx,%rcx,4),%xmm0
  movss  %xmm0,(%r12)
  mov    %ecx,(%r9)
L50:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L58
  mov    (%r14),%rax
L61:
  movslq 0x0(%rbp,%rbx,4),%rdx
  movss  0x4(%rax,%rdx,4),%xmm0
  test   %r15d,%r15d
  je     L49
  mov    %r9,0x8(%rsp)
  call   <fabs@plt>
  movss  %xmm0,0x4(%rsp)
  movss  (%r12),%xmm0
  call   <fabs@plt>
  movss  0x4(%rsp),%xmm1
  mov    0x8(%rsp),%r9
  pxor   %xmm2,%xmm2
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  jmp    L29
  nopl   0x0(%rax)
L3:
  movl   $0x0,(%r12)
L58:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void simp1(float **a, int mm, int ll[], int nll, int iabf, int *kp, float *bmax) {
  int k;
  float test;
  if (nll <= 0)
    *bmax = 0.0;
  else {
    *kp = ll[1];
    *bmax = a[mm + 1][*kp + 1];
    for (k = 2; k <= nll; k++) {
      if (iabf == 0)
        test = a[mm + 1][ll[k] + 1] - (*bmax);
      else
        test = fabs(a[mm + 1][ll[k] + 1]) - fabs(*bmax);
      if (test > 0.0) {
        *bmax = a[mm + 1][ll[k] + 1];
        *kp = ll[k];
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<simp1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%rbx
  test   %ecx,%ecx
  jle    L56
  movslq %esi,%rax
  mov    %rdx,%r12
  mov    %ecx,%r13d
  movslq 0x4(%rdx),%rdx
  lea    0x8(%rdi,%rax,8),%r15
  mov    %r9,%r14
  mov    (%r15),%rcx
  mov    %edx,(%r9)
  movss  0x4(%rcx,%rdx,4),%xmm0
  movss  %xmm0,(%rbx)
  cmp    $0x1,%r13d
  je     L70
  test   %r8d,%r8d
  jne    L39
  lea    -0x2(%r13),%edx
  lea    0x8(%r12),%rax
  pxor   %xmm2,%xmm2
  lea    0xc(%r12,%rdx,4),%rdi
  nopl   (%rax)
L21:
  movslq (%rax),%rsi
  movss  0x4(%rcx,%rsi,4),%xmm0
  movaps %xmm0,%xmm1
  subss  (%rbx),%xmm1
  comiss %xmm2,%xmm1
  jbe    L73
  movss  %xmm0,(%rbx)
  mov    %esi,(%r14)
L73:
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L21
L70:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L56:
  movl   $0x0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L39:
  mov    $0x2,%ebp
  pxor   %xmm2,%xmm2
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%r15),%rcx
L8:
  movslq (%r12,%rbp,4),%rax
  movss  %xmm2,0xc(%rsp)
  movss  0x4(%rcx,%rax,4),%xmm0
  call   <fabs@plt>
  movss  %xmm0,0x8(%rsp)
  movss  (%rbx),%xmm0
  call   <fabs@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  subss  %xmm0,%xmm1
  comiss %xmm2,%xmm1
  jbe    L59
  movslq (%r12,%rbp,4),%rcx
  mov    (%r15),%rdx
  movss  0x4(%rdx,%rcx,4),%xmm0
  movss  %xmm0,(%rbx)
  mov    %ecx,(%r14)
L59:
  add    $0x1,%rbp
  cmp    %ebp,%r13d
  jge    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void simp1(float **a, int mm, int ll[], int nll, int iabf, int *kp, float *bmax) {
  int k;
  float test;
  if (nll <= 0)
    *bmax = 0.0;
  else {
    *kp = ll[1];
    *bmax = a[mm + 1][*kp + 1];
    for (k = 2; k <= nll; k++) {
      if (iabf == 0)
        test = a[mm + 1][ll[k] + 1] - (*bmax);
      else
        test = fabs(a[mm + 1][ll[k] + 1]) - fabs(*bmax);
      if (test > 0.0) {
        *bmax = a[mm + 1][ll[k] + 1];
        *kp = ll[k];
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<device_reboot_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D40(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L18
  mov    D31(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D7(%rip)
  mov    D7(%rip),%eax
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L10
L18:
  movl   $0x0,D7(%rip)
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int device_reboot_now(volatile char *key_pressed, int key_code) {
  static int presses = 0;
  if (key_code == KEY_POWER) {
    ++presses;
    return presses == 5;
  } else {
    presses = 0;
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<device_reboot_now>:
  endbr64
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    D20(%rip),%rcx
  cmp    %esi,(%rcx)
  je     L16
L15:
  mov    %edx,D3(%rip)
  ret
L16:
  mov    D3(%rip),%eax
  lea    0x1(%rax),%edx
  cmp    $0x4,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L15
```

assistant: ```c
int device_reboot_now(volatile char *key_pressed, int key_code) {
  static int presses = 0;
  if (key_code == KEY_POWER) {
    ++presses;
    return presses == 5;
  } else {
    presses = 0;
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<device_reboot_now>:
  endbr64
  mov    D5(%rip),%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  cmp    %esi,(%rcx)
  jne    L0
  mov    D23(%rip),%eax
  cmp    $0x4,%eax
  lea    0x1(%rax),%edx
  sete   %al
  movzbl %al,%eax
L0:
  mov    %edx,D26(%rip)
  ret
```

assistant: ```c
int device_reboot_now(volatile char *key_pressed, int key_code) {
  static int presses = 0;
  if (key_code == KEY_POWER) {
    ++presses;
    return presses == 5;
  } else {
    presses = 0;
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<device_reboot_now>:
  endbr64
  mov    D7(%rip),%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  cmp    %esi,(%rcx)
  jne    L2
  mov    D14(%rip),%eax
  cmp    $0x4,%eax
  lea    0x1(%rax),%edx
  sete   %al
  movzbl %al,%eax
L2:
  mov    %edx,D6(%rip)
  ret
```

assistant: ```c
int device_reboot_now(volatile char *key_pressed, int key_code) {
  static int presses = 0;
  if (key_code == KEY_POWER) {
    ++presses;
    return presses == 5;
  } else {
    presses = 0;
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<spacedtext_get_next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L98
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L84
L98:
  mov    $0x0,%eax
  jmp    L39
L88:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L84:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L88
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L87:
  addq   $0x1,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L75
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L75
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L87
L75:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L82
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L78
L82:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L30
L78:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L30:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L39:
  pop    %rbp
  ret
```

assistant: ```c
char *spacedtext_get_next_token(char **text) {
  char *t, *ret;
  if (**text == '\0' || **text == '\n')
    return NULL;
  for (; **text == ' '; (*text)++) {
  }
  ret = *text;
  for (t = *text; *t != '\0' && *t != '\n' && *t != ' '; t++) {
  }
  if (*t == '\0' || *t == '\n')
    *text = t;
  else
    *text = t + 1;
  *t = '\0';
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spacedtext_get_next_token>:
  endbr64
  mov    (%rdi),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L91
  cmp    $0xa,%al
  je     L91
  cmp    $0x20,%al
  jne    L33
  lea    0x1(%rcx),%rax
L87:
  mov    %rax,%rcx
  mov    %rax,(%rdi)
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L87
  movzbl (%rcx),%eax
  test   $0xdf,%al
  je     L57
  cmp    $0xa,%al
  je     L57
L33:
  mov    %rcx,%rdx
L120:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   $0xdf,%al
  je     L29
  cmp    $0xa,%al
  jne    L120
L29:
  test   %al,%al
  je     L14
  cmp    $0xa,%al
  je     L14
  lea    0x1(%rdx),%rax
L103:
  mov    %rax,(%rdi)
  movb   $0x0,(%rdx)
L71:
  mov    %rcx,%rax
  ret
L57:
  mov    %rcx,%rdx
  jmp    L29
L14:
  mov    %rdx,%rax
  jmp    L103
L91:
  mov    $0x0,%ecx
  jmp    L71
```

assistant: ```c
char *spacedtext_get_next_token(char **text) {
  char *t, *ret;
  if (**text == '\0' || **text == '\n')
    return NULL;
  for (; **text == ' '; (*text)++) {
  }
  ret = *text;
  for (t = *text; *t != '\0' && *t != '\n' && *t != ' '; t++) {
  }
  if (*t == '\0' || *t == '\n')
    *text = t;
  else
    *text = t + 1;
  *t = '\0';
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<spacedtext_get_next_token>:
  endbr64
  mov    (%rdi),%r8
  movzbl (%r8),%eax
  test   %al,%al
  je     L33
  cmp    $0xa,%al
  je     L33
  cmp    $0x20,%al
  jne    L20
  lea    0x1(%r8),%rdx
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %rdx,(%rdi)
  mov    %rdx,%r8
  movzbl (%rdx),%eax
  lea    0x1(%rdx),%rdx
  cmp    $0x20,%al
  je     L62
  test   %al,%al
  je     L60
  cmp    $0xa,%al
  je     L60
L20:
  mov    %r8,%rdx
  jmp    L126
  xchg   %ax,%ax
L106:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L6
  cmp    $0xa,%al
  je     L113
L126:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    $0x20,%al
  jne    L106
L108:
  lea    0x1(%rcx),%rdx
L3:
  mov    %rdx,(%rdi)
  mov    %r8,%rax
  movb   $0x0,(%rcx)
  ret
L60:
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L113:
  test   %al,%al
  je     L6
  cmp    $0xa,%al
  jne    L92
L6:
  mov    %rdx,%rcx
  jmp    L3
  nopl   (%rax)
L33:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L92:
  mov    %rdx,%rcx
  jmp    L108
```

assistant: ```c
char *spacedtext_get_next_token(char **text) {
  char *t, *ret;
  if (**text == '\0' || **text == '\n')
    return NULL;
  for (; **text == ' '; (*text)++) {
  }
  ret = *text;
  for (t = *text; *t != '\0' && *t != '\n' && *t != ' '; t++) {
  }
  if (*t == '\0' || *t == '\n')
    *text = t;
  else
    *text = t + 1;
  *t = '\0';
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<spacedtext_get_next_token>:
  endbr64
  mov    (%rdi),%r8
  movzbl (%r8),%eax
  test   %al,%al
  je     L19
  cmp    $0xa,%al
  je     L19
  cmp    $0x20,%al
  jne    L41
  lea    0x1(%r8),%rdx
  nopl   0x0(%rax,%rax,1)
L86:
  mov    %rdx,(%rdi)
  mov    %rdx,%r8
  movzbl (%rdx),%eax
  lea    0x1(%rdx),%rdx
  cmp    $0x20,%al
  je     L86
  test   %al,%al
  je     L122
  cmp    $0xa,%al
  je     L122
L41:
  mov    %r8,%rdx
  jmp    L0
  xchg   %ax,%ax
L7:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L114
  cmp    $0xa,%al
  je     L85
L0:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    $0x20,%al
  jne    L7
L8:
  lea    0x1(%rcx),%rdx
L109:
  mov    %rdx,(%rdi)
  mov    %r8,%rax
  movb   $0x0,(%rcx)
  ret
L122:
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L85:
  test   %al,%al
  je     L114
  cmp    $0xa,%al
  jne    L138
L114:
  mov    %rdx,%rcx
  jmp    L109
  nopl   (%rax)
L19:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L138:
  mov    %rdx,%rcx
  jmp    L8
```

assistant: ```c
char *spacedtext_get_next_token(char **text) {
  char *t, *ret;
  if (**text == '\0' || **text == '\n')
    return NULL;
  for (; **text == ' '; (*text)++) {
  }
  ret = *text;
  for (t = *text; *t != '\0' && *t != '\n' && *t != ' '; t++) {
  }
  if (*t == '\0' || *t == '\n')
    *text = t;
  else
    *text = t + 1;
  *t = '\0';
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_div(int nb1, int nb2) {
  int result;
  result = nb1 / nb2;
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_div>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int my_div(int nb1, int nb2) {
  int result;
  result = nb1 / nb2;
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_div>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int my_div(int nb1, int nb2) {
  int result;
  result = nb1 / nb2;
  return (result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_div>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int my_div(int nb1, int nb2) {
  int result;
  result = nb1 / nb2;
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fn3>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn3>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn3>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b ^ a;
  return tem1 ^ tem2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L21
L13:
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <longitud_string@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D1: cadena: %s


tool: D11: longitud cadena: %d


tool: D19: %s

assistant: ```c
int main(void) {
  char string1[200];
  while (scanf("%s", string1) == 1) {
    printf("cadena: %s\n", string1);
    printf("longitud cadena: %d\n", longitud_string(string1));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D18(%rip),%rbp
  lea    D10(%rip),%r13
  lea    D22(%rip),%r12
  jmp    L29
L7:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <longitud_string@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L29:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L7
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D18: %s

tool: D10: cadena: %s


tool: D22: longitud cadena: %d


assistant: ```c
int main(void) {
  char string1[200];
  while (scanf("%s", string1) == 1) {
    printf("cadena: %s\n", string1);
    printf("longitud cadena: %d\n", longitud_string(string1));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L18
  xchg   %ax,%ax
L6:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <longitud_string@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L6
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D13: cadena: %s


tool: D8: longitud cadena: %d


tool: D5: %s

assistant: ```c
int main(void) {
  char string1[200];
  while (scanf("%s", string1) == 1) {
    printf("cadena: %s\n", string1);
    printf("longitud cadena: %d\n", longitud_string(string1));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L15
  xchg   %ax,%ax
L9:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <longitud_string@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L9
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string

tool: D18: cadena: %s


tool: D14: longitud cadena: %d


tool: D19: %s

assistant: ```c
int main(void) {
  char string1[200];
  while (scanf("%s", string1) == 1) {
    printf("cadena: %s\n", string1);
    printf("longitud cadena: %d\n", longitud_string(string1));
  }
  return 0;
}
```