ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x64ffffffbd,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    $0xfffffffe,%eax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xffffffbe00000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4400000002,%rax
  mov    %rax,0x20(%rsp)
  call   <smallest@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: %i


assistant: ```c
int main(void) {
  int ints[] = {-67, 100, -2, 0, 1, 2, 3, -66, 2, 68};
  printf("%i\n", smallest(ints, sizeof(ints) / sizeof(int)));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D9(%rip),%xmm0
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D32(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <smallest@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[16]
name: parse_data
arguments: tag: D32
type: byte[8]
name: parse_data
arguments: tag: D8
type: byte[16]
name: parse_data
arguments: tag: D2
type: string

tool: {"D9": [0xbd,0xff,0xff,0xff,0x64,0x00,0x00,0x00,0xfe,0xff,0xff,0xff,0x00,0x00,0x00,0x00]}

tool: {"D32": [0x02,0x00,0x00,0x00,0x44,0x00,0x00,0x00]}

tool: {"D8": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0xbe,0xff,0xff,0xff]}

tool: D2: %i


assistant: ```c
int main(void) {
  int ints[] = {-67, 100, -2, 0, 1, 2, 3, -66, 2, 68};
  printf("%i\n", smallest(ints, sizeof(ints) / sizeof(int)));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<register_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <hide@plt>
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <hide@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void register_state(void) {
  register int a = 0;
  hide(a);
  a++;
  hide(a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<register_state>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <hide@plt>
  mov    $0x1,%edi
  call   <hide@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void register_state(void) {
  register int a = 0;
  hide(a);
  a++;
  hide(a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<register_state>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <hide@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <hide@plt>
```

assistant: ```c
void register_state(void) {
  register int a = 0;
  hide(a);
  a++;
  hide(a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<register_state>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <hide@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <hide@plt>
```

assistant: ```c
void register_state(void) {
  register int a = 0;
  hide(a);
  a++;
  hide(a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L15:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: %d 

assistant: ```c
void print_array(int array[], size_t size) {
  for (size_t i = 0; i < size; i++) {
    printf("%d ", array[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L12:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L12
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: %d 

assistant: ```c
void print_array(int array[], size_t size) {
  for (size_t i = 0; i < size; i++) {
    printf("%d ", array[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L3
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %d 

assistant: ```c
void print_array(int array[], size_t size) {
  for (size_t i = 0; i < size; i++) {
    printf("%d ", array[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_array>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L13
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string

tool: D9: %d 

assistant: ```c
void print_array(int array[], size_t size) {
  for (size_t i = 0; i < size; i++) {
    printf("%d ", array[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L49:
  cmpl   $0x5c,-0x4(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
L4:
  cmpl   $0x3e,-0x8(%rbp)
  jg     L18
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L21
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <contains@plt>
  test   %eax,%eax
  je     L49
L21:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void read_label(char *str, const char *skip) {
  int n = 0;
  int c;
  while ((c = getchar()) != EOF && !contains(skip, c)) {
    if (c == '\\') {
      c = getchar();
    }
    if (n < 63) {
      str[n] = c;
      n++;
    }
  }
  ungetc(c, stdin);
  str[n] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_label>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    $0x0,%ebp
L47:
  mov    %ebp,%r13d
  jmp    L66
L43:
  cmp    $0x3e,%ebp
  jle    L26
L66:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D10(%rip),%rax
  cmp    %ebx,(%rax)
  je     L65
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L65
  cmp    $0x5c,%ebx
  jne    L43
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  jmp    L43
L26:
  mov    %bl,(%r14,%rbp,1)
  add    $0x1,%rbp
  jmp    L47
L65:
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ungetc@plt>
  movslq %r13d,%r13
  movb   $0x0,(%r14,%r13,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void read_label(char *str, const char *skip) {
  int n = 0;
  int c;
  while ((c = getchar()) != EOF && !contains(skip, c)) {
    if (c == '\\') {
      c = getchar();
    }
    if (n < 63) {
      str[n] = c;
      n++;
    }
  }
  ungetc(c, stdin);
  str[n] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_label>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D2(%rip),%r13
L65:
  movslq %ebx,%r14
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L5:
  cmp    $0x3f,%rbx
  jne    L64
L43:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  je     L25
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L25
  cmp    $0x5c,%ebp
  jne    L5
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0x3f,%rbx
  je     L43
L64:
  mov    %bpl,(%r15,%rbx,1)
  add    $0x1,%rbx
  jmp    L65
  nopl   0x0(%rax)
L25:
  mov    D10(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  movb   $0x0,(%r15,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void read_label(char *str, const char *skip) {
  int n = 0;
  int c;
  while ((c = getchar()) != EOF && !contains(skip, c)) {
    if (c == '\\') {
      c = getchar();
    }
    if (n < 63) {
      str[n] = c;
      n++;
    }
  }
  ungetc(c, stdin);
  str[n] = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_label>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%r12
L12:
  movslq %r15d,%r13
  cmp    $0x3f,%r15
  jne    L40
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    (%r12),%eax
  je     L76
L67:
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L76
  cmp    $0x5c,%ebp
  jne    L22
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    (%r12),%eax
  jne    L67
L76:
  mov    D4(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  movb   $0x0,(%r14,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r12)
  je     L76
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <contains@plt>
  test   %eax,%eax
  jne    L76
  cmp    $0x5c,%ebp
  je     L8
L65:
  mov    %bpl,(%r14,%r15,1)
  add    $0x1,%r15
  jmp    L12
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  jmp    L65
```

assistant: ```c
void read_label(char *str, const char *skip) {
  int n = 0;
  int c;
  while ((c = getchar()) != EOF && !contains(skip, c)) {
    if (c == '\\') {
      c = getchar();
    }
    if (n < 63) {
      str[n] = c;
      n++;
    }
  }
  ungetc(c, stdin);
  str[n] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uint64_comparator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jge    L4
  mov    $0xffffffff,%eax
  jmp    L29
L4:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L5
  mov    $0x0,%eax
  jmp    L29
L5:
  mov    $0x1,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int32_t uint64_comparator(const void *l, const void *r) {
  uint64_t lv = (uint64_t)(uint64_t)(l);
  uint64_t rv = (uint64_t)(uint64_t)(r);
  if (lv < rv)
    return -1;
  else if (lv == rv)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uint64_comparator>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    %rsi,%rdi
  jl     L1
  setne  %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
int32_t uint64_comparator(const void *l, const void *r) {
  uint64_t lv = (uint64_t)(uint64_t)(l);
  uint64_t rv = (uint64_t)(uint64_t)(r);
  if (lv < rv)
    return -1;
  else if (lv == rv)
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uint64_comparator>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  mov    $0xffffffff,%edx
  setne  %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int32_t uint64_comparator(const void *l, const void *r) {
  uint64_t lv = (uint64_t)(uint64_t)(l);
  uint64_t rv = (uint64_t)(uint64_t)(r);
  if (lv < rv)
    return -1;
  else if (lv == rv)
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<uint64_comparator>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  mov    $0xffffffff,%edx
  setne  %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int32_t uint64_comparator(const void *l, const void *r) {
  uint64_t lv = (uint64_t)(uint64_t)(l);
  uint64_t rv = (uint64_t)(uint64_t)(r);
  if (lv < rv)
    return -1;
  else if (lv == rv)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: hello


assistant: ```c
int foo(void) {
  printf("hello\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: hello


assistant: ```c
int foo(void) {
  printf("hello\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: hello


assistant: ```c
int foo(void) {
  printf("hello\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: hello


assistant: ```c
int foo(void) {
  printf("hello\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xc8,-0x4(%rbp)
  je     L36
  cmpl   $0x194,-0x4(%rbp)
  je     L6
  jmp    L31
L36:
  lea    D29(%rip),%rax
  jmp    L10
L6:
  lea    D27(%rip),%rax
  jmp    L10
L31:
  lea    D29(%rip),%rax
L10:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string

tool: D29: HTTP/1.1 200 OK

tool: D27: HTTP/1.1 404 Not Found

assistant: ```c
char *response(int code) {
  switch (code) {
  case 200:
    return "HTTP/1.1 200 OK";
    break;
  case 404:
    return "HTTP/1.1 404 Not Found";
    break;
  default:
    return "HTTP/1.1 200 OK";
    break;
  }
  return "HTTP/1.1 200 OK";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<response>:
  endbr64
  cmp    $0x194,%edi
  lea    D7(%rip),%rax
  lea    D15(%rip),%rdx
  cmove  %rdx,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D7: HTTP/1.1 200 OK

tool: D15: HTTP/1.1 404 Not Found

assistant: ```c
char *response(int code) {
  switch (code) {
  case 200:
    return "HTTP/1.1 200 OK";
    break;
  case 404:
    return "HTTP/1.1 404 Not Found";
    break;
  default:
    return "HTTP/1.1 200 OK";
    break;
  }
  return "HTTP/1.1 200 OK";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<response>:
  endbr64
  cmp    $0x194,%edi
  lea    D5(%rip),%rdx
  lea    D13(%rip),%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string

tool: D5: HTTP/1.1 404 Not Found

tool: D13: HTTP/1.1 200 OK

assistant: ```c
char *response(int code) {
  switch (code) {
  case 200:
    return "HTTP/1.1 200 OK";
    break;
  case 404:
    return "HTTP/1.1 404 Not Found";
    break;
  default:
    return "HTTP/1.1 200 OK";
    break;
  }
  return "HTTP/1.1 200 OK";
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<response>:
  endbr64
  cmp    $0x194,%edi
  lea    D0(%rip),%rdx
  lea    D6(%rip),%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D6
data_type: string

tool: D0: HTTP/1.1 404 Not Found

tool: D6: HTTP/1.1 200 OK

assistant: ```c
char *response(int code) {
  switch (code) {
  case 200:
    return "HTTP/1.1 200 OK";
    break;
  case 404:
    return "HTTP/1.1 404 Not Found";
    break;
  default:
    return "HTTP/1.1 200 OK";
    break;
  }
  return "HTTP/1.1 200 OK";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_ip_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  movq   $0x0,-0x20(%rbp)
  jmp    L2
L12:
  movl   $0x0,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
L2:
  leave
  ret
```

assistant: ```c
void get_ip_addr(char const *domain, char *ip_addr) {
  struct hostent *host = gethostbyname(domain);
  if (!host) {
    ip_addr = NULL;
    return;
  }
  for (int i = 0; host->h_addr_list[i]; i++) {
    strcpy(ip_addr, inet_ntoa(*(struct in_addr *)host->h_addr_list[i]));
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ip_addr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L14
  mov    (%rax),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L23
L14:
  pop    %rbx
  ret
L23:
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L14
```

assistant: ```c
void get_ip_addr(char const *domain, char *ip_addr) {
  struct hostent *host = gethostbyname(domain);
  if (!host) {
    ip_addr = NULL;
    return;
  }
  for (int i = 0; host->h_addr_list[i]; i++) {
    strcpy(ip_addr, inet_ntoa(*(struct in_addr *)host->h_addr_list[i]));
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_ip_addr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L14
  mov    (%rax),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
L14:
  pop    %rbp
  ret
  nop
L13:
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
void get_ip_addr(char const *domain, char *ip_addr) {
  struct hostent *host = gethostbyname(domain);
  if (!host) {
    ip_addr = NULL;
    return;
  }
  for (int i = 0; host->h_addr_list[i]; i++) {
    strcpy(ip_addr, inet_ntoa(*(struct in_addr *)host->h_addr_list[i]));
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_ip_addr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L16
  mov    (%rax),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
L16:
  pop    %rbp
  ret
  nop
L15:
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
void get_ip_addr(char const *domain, char *ip_addr) {
  struct hostent *host = gethostbyname(domain);
  if (!host) {
    ip_addr = NULL;
    return;
  }
  for (int i = 0; host->h_addr_list[i]; i++) {
    strcpy(ip_addr, inet_ntoa(*(struct in_addr *)host->h_addr_list[i]));
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<initramfs_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L3:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L3
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int initramfs_read(struct riku_devfs_node *self, const char *buf, uint32_t count) {
  for (uint32_t i = 0; i < count; i++)
    *(char *)(buf + i) = 0x0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initramfs_read>:
  endbr64
  test   %rdx,%rdx
  jle    L3
  mov    %rsi,%rax
  add    %rdx,%rsi
L7:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L7
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int initramfs_read(struct riku_devfs_node *self, const char *buf, uint32_t count) {
  for (uint32_t i = 0; i < count; i++)
    *(char *)(buf + i) = 0x0;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<initramfs_read>:
  endbr64
  test   %rdx,%rdx
  jle    L0
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int initramfs_read(struct riku_devfs_node *self, const char *buf, uint32_t count) {
  for (uint32_t i = 0; i < count; i++)
    *(char *)(buf + i) = 0x0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initramfs_read>:
  endbr64
  test   %rdx,%rdx
  jle    L6
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int initramfs_read(struct riku_devfs_node *self, const char *buf, uint32_t count) {
  for (uint32_t i = 0; i < count; i++)
    *(char *)(buf + i) = 0x0;
  return 0;
}
```