ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rdx
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rbx
  mov    (%rsp),%r12
  mov    %r13,%rdi
  lea    -0x1(%r12),%rbp
  lea    -0x1(%rbx),%rax
  mov    %rbp,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %rax,%rcx
  mov    %rbp,%rax
  cqto
  idiv   %rcx
  mov    %rbx,%rax
  mov    %rdx,%r8
  cqto
  idiv   %rcx
  mov    %rdx,%r9
  mov    %r8,%rdx
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    %rdx,%r9
  cmove  %rsi,%rdi
  cmpb   $0x42,0x10(%rsp,%rdx,1)
  jne    L12
  add    $0x1,%rsi
L12:
  lea    0x1(%rdx),%rax
  cqto
  idiv   %rcx
  cmp    %rdx,%r8
  jne    L16
  sub    %r12,%rbx
  lea    0x1(%rbx),%rax
  cqto
  idiv   %rcx
  imul   %rsi,%rax
  lea    (%rax,%rdi,1),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string

tool: D5: %s %lli %lli

tool: D2: %lli

assistant: ```c
int main(int argc, const char *argv[]) {
  long long i, n, l, r, ans = 0, ln, rn, j = 0;
  char a[105], started = 1;
  scanf("%s %lli %lli", a, &l, &r);
  --l, --r;
  n = strlen(a);
  ln = l % n;
  rn = (r + 1) % n;
  for (i = ln; started || i != ln; i = (i + 1) % n) {
    started = 0;
    if (i == rn)
      j = ans;
    if (a[i] == 'B')
      ++ans;
  }
  printf("%lli", (r - l + 1) / n * ans + j);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%rcx
  mov    %rsp,%rdx
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rbx
  mov    (%rsp),%r12
  mov    %r13,%rdi
  lea    -0x1(%r12),%rbp
  lea    -0x1(%rbx),%rax
  mov    %rbp,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %rax,%rcx
  mov    %rbp,%rax
  cqto
  idiv   %rcx
  mov    %rbx,%rax
  mov    %rdx,%r8
  cqto
  idiv   %rcx
  mov    %rdx,%r9
  mov    %r8,%rdx
  nopl   0x0(%rax,%rax,1)
L10:
  cmp    %r9,%rdx
  cmove  %rsi,%rdi
  cmpb   $0x42,0x10(%rsp,%rdx,1)
  jne    L24
  add    $0x1,%rsi
L24:
  lea    0x1(%rdx),%rax
  cqto
  idiv   %rcx
  cmp    %rdx,%r8
  jne    L10
  sub    %r12,%rbx
  lea    0x1(%rbx),%rax
  cqto
  idiv   %rcx
  imul   %rsi,%rax
  lea    (%rax,%rdi,1),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type: string
name: disassemble_data
arguments: tag: D1
type: string

tool: D11: %s %lli %lli

tool: D1: %lli

assistant: ```c
int main(int argc, const char *argv[]) {
  long long i, n, l, r, ans = 0, ln, rn, j = 0;
  char a[105], started = 1;
  scanf("%s %lli %lli", a, &l, &r);
  --l, --r;
  n = strlen(a);
  ln = l % n;
  rn = (r + 1) % n;
  for (i = ln; started || i != ln; i = (i + 1) % n) {
    started = 0;
    if (i == rn)
      j = ans;
    if (a[i] == 'B')
      ++ans;
  }
  printf("%lli", (r - l + 1) / n * ans + j);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bthGetConnectionParameters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  lea    D10(%rip),%rax
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <getDeviceParameters@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: string

tool: 

assistant: ```c
char **bthGetConnectionParameters(const char *identifier) {
  static const char *const names[] = {"address", "timeout", "channel", "discover", NULL};
  if (!identifier)
    identifier = "";
  return getDeviceParameters(names, identifier);
}
```
user: What is the c source code of the assembly code below:

```asm
<bthGetConnectionParameters>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  test   %rdi,%rdi
  lea    D9(%rip),%rax
  cmove  %rax,%rsi
  lea    D19(%rip),%rdi
  call   <getDeviceParameters@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: 

assistant: ```c
char **bthGetConnectionParameters(const char *identifier) {
  static const char *const names[] = {"address", "timeout", "channel", "discover", NULL};
  if (!identifier)
    identifier = "";
  return getDeviceParameters(names, identifier);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bthGetConnectionParameters>:
  endbr64
  mov    %rdi,%rsi
  test   %rdi,%rdi
  lea    D7(%rip),%rax
  cmove  %rax,%rsi
  lea    D19(%rip),%rdi
  jmp    1050 <getDeviceParameters@plt>
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: 

assistant: ```c
char **bthGetConnectionParameters(const char *identifier) {
  static const char *const names[] = {"address", "timeout", "channel", "discover", NULL};
  if (!identifier)
    identifier = "";
  return getDeviceParameters(names, identifier);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bthGetConnectionParameters>:
  endbr64
  mov    %rdi,%rsi
  test   %rdi,%rdi
  lea    D0(%rip),%rax
  cmove  %rax,%rsi
  lea    D16(%rip),%rdi
  jmp    1050 <getDeviceParameters@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: 

assistant: ```c
char **bthGetConnectionParameters(const char *identifier) {
  static const char *const names[] = {"address", "timeout", "channel", "discover", NULL};
  if (!identifier)
    identifier = "";
  return getDeviceParameters(names, identifier);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kernel_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <uart_init@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
L0:
  mov    $0x0,%eax
  call   <uart_getc@plt>
  mov    %eax,%edi
  call   <uart_putc@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: Userspace is overrated.


assistant: ```c
void kernel_main(uint32_t r0, uint32_t r1, uint32_t atags) {
  (void)r0;
  (void)r1;
  (void)atags;
  uart_init();
  uart_puts("Userspace is overrated.\r\n");
  while (true)
    uart_putc(uart_getc());
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kernel_main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <uart_init@plt>
  lea    D5(%rip),%rdi
  call   <uart_puts@plt>
L6:
  mov    $0x0,%eax
  call   <uart_getc@plt>
  mov    %eax,%edi
  call   <uart_putc@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: Userspace is overrated.


assistant: ```c
void kernel_main(uint32_t r0, uint32_t r1, uint32_t atags) {
  (void)r0;
  (void)r1;
  (void)atags;
  uart_init();
  uart_puts("Userspace is overrated.\r\n");
  while (true)
    uart_putc(uart_getc());
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kernel_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart_init@plt>
  lea    D7(%rip),%rdi
  call   <uart_puts@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <uart_getc@plt>
  mov    %eax,%edi
  call   <uart_putc@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: Userspace is overrated.


assistant: ```c
void kernel_main(uint32_t r0, uint32_t r1, uint32_t atags) {
  (void)r0;
  (void)r1;
  (void)atags;
  uart_init();
  uart_puts("Userspace is overrated.\r\n");
  while (true)
    uart_putc(uart_getc());
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart_init@plt>
  lea    D6(%rip),%rdi
  call   <uart_puts@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <uart_getc@plt>
  mov    %eax,%edi
  call   <uart_putc@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Userspace is overrated.


assistant: ```c
void kernel_main(uint32_t r0, uint32_t r1, uint32_t atags) {
  (void)r0;
  (void)r1;
  (void)atags;
  uart_init();
  uart_puts("Userspace is overrated.\r\n");
  while (true)
    uart_putc(uart_getc());
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decompose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L23
L59:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L43
L33:
  mov    -0x40(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  cmpq   $0x2,-0x20(%rbp)
  jne    L43
  cmpq   $0x1,-0x38(%rbp)
  je     L43
  movq   $0x2,-0x30(%rbp)
  jmp    L83
L70:
  mov    -0x38(%rbp),%rax
  sub    -0x30(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x50(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x30(%rbp)
L83:
  mov    -0x30(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jbe    L70
  mov    -0x50(%rbp),%rax
  add    $0x10,%rax
  movq   $0x2,(%rax)
L43:
  cmpq   $0x1,-0x40(%rbp)
  jne    L33
  jmp    L68
L15:
  nop
L68:
  addq   $0x1,-0x28(%rbp)
L23:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L59
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x50(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int32_t decompose(int32_t n, int32_t *ifac, const int32_t *ntryh) {
  int32_t nl = n, nf = 0, i, j = 0;
  for (j = 0; ntryh[j]; ++j) {
    int32_t ntry = ntryh[j];
    while (nl != 1) {
      int32_t nq = nl / ntry;
      int32_t nr = nl - ntry * nq;
      if (nr == 0) {
        ifac[2 + nf++] = ntry;
        nl = nq;
        if (ntry == 2 && nf != 1) {
          for (i = 2; i <= nf; ++i) {
            int32_t ib = nf - i + 2;
            ifac[ib + 1] = ifac[ib];
          }
          ifac[2] = 2;
        }
      } else
        break;
    }
  }
  ifac[0] = n;
  ifac[1] = nf;
  return nf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decompose>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r10
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  je     L12
  lea    0x8(%rdx),%r11
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  lea    0x8(%r10),%r9
  jmp    L73
L1:
  movq   $0x2,0x10(%r10)
L27:
  cmp    $0x1,%rsi
  je     L129
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x8,%rdi
  test   %rdx,%rdx
  jne    L129
  mov    %rax,%rsi
L96:
  add    $0x1,%r8
  mov    %rcx,0x8(%rdi)
  cmp    $0x2,%rcx
  jne    L27
  cmp    $0x1,%r8
  je     L27
  jbe    L1
  mov    %rdi,%rax
L67:
  mov    (%rax),%rdx
  mov    %rdx,0x8(%rax)
  sub    $0x8,%rax
  cmp    %rax,%r9
  jne    L67
  jmp    L1
L129:
  add    $0x8,%r11
  mov    -0x8(%r11),%rcx
  test   %rcx,%rcx
  je     L6
L73:
  cmp    $0x1,%rsi
  je     L129
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L129
  lea    0x8(%r10,%r8,8),%rdi
  mov    %rax,%rsi
  jmp    L96
L12:
  mov    %rcx,%r8
L6:
  mov    %rbx,(%r10)
  mov    %r8,0x8(%r10)
  mov    %r8,%rax
  pop    %rbx
  ret
```

assistant: ```c
int32_t decompose(int32_t n, int32_t *ifac, const int32_t *ntryh) {
  int32_t nl = n, nf = 0, i, j = 0;
  for (j = 0; ntryh[j]; ++j) {
    int32_t ntry = ntryh[j];
    while (nl != 1) {
      int32_t nq = nl / ntry;
      int32_t nr = nl - ntry * nq;
      if (nr == 0) {
        ifac[2 + nf++] = ntry;
        nl = nq;
        if (ntry == 2 && nf != 1) {
          for (i = 2; i <= nf; ++i) {
            int32_t ib = nf - i + 2;
            ifac[ib + 1] = ifac[ib];
          }
          ifac[2] = 2;
        }
      } else
        break;
    }
  }
  ifac[0] = n;
  ifac[1] = nf;
  return nf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decompose>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdx),%rbp
  mov    %rdi,0x8(%rsp)
  test   %rbp,%rbp
  je     L108
  lea    0x8(%rdx),%rax
  mov    %rdi,%rbx
  lea    0x10(%rsi),%r14
  xor    %r12d,%r12d
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L88:
  cmp    $0x1,%rbx
  je     L94
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L94
  cmp    $0x2,%rbp
  mov    %rax,%rbx
  sete   %r13b
  jmp    L112
L86:
  cmp    $0x1,%rbx
  je     L94
L93:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L94
  mov    %rax,%rbx
L112:
  add    $0x1,%r12
  mov    %rbp,0x8(%r15,%r12,8)
  cmp    $0x1,%r12
  je     L86
  test   %r13b,%r13b
  je     L86
  cmp    $0x1,%r12
  jbe    L23
  lea    -0x8(,%r12,8),%rdx
  lea    0x18(%r15),%rdi
  mov    %r14,%rsi
  call   <memmove@plt>
L23:
  movq   $0x2,0x10(%r15)
  cmp    $0x1,%rbx
  jne    L93
  nopw   0x0(%rax,%rax,1)
L94:
  addq   $0x8,(%rsp)
  mov    (%rsp),%rax
  mov    -0x8(%rax),%rbp
  test   %rbp,%rbp
  jne    L88
L68:
  mov    0x8(%rsp),%rax
  mov    %r12,0x8(%r15)
  mov    %rax,(%r15)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L108:
  xor    %r12d,%r12d
  jmp    L68
```

assistant: ```c
int32_t decompose(int32_t n, int32_t *ifac, const int32_t *ntryh) {
  int32_t nl = n, nf = 0, i, j = 0;
  for (j = 0; ntryh[j]; ++j) {
    int32_t ntry = ntryh[j];
    while (nl != 1) {
      int32_t nq = nl / ntry;
      int32_t nr = nl - ntry * nq;
      if (nr == 0) {
        ifac[2 + nf++] = ntry;
        nl = nq;
        if (ntry == 2 && nf != 1) {
          for (i = 2; i <= nf; ++i) {
            int32_t ib = nf - i + 2;
            ifac[ib + 1] = ifac[ib];
          }
          ifac[2] = 2;
        }
      } else
        break;
    }
  }
  ifac[0] = n;
  ifac[1] = nf;
  return nf;
}
```
user: What is the c source code of the assembly code below:

```asm
<decompose>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdx),%rbp
  mov    %rdi,0x8(%rsp)
  test   %rbp,%rbp
  je     L57
  lea    0x8(%rdx),%rax
  mov    %rdi,%rbx
  lea    0x10(%rsi),%r14
  xor    %r12d,%r12d
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    $0x1,%rbx
  je     L29
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L29
  cmp    $0x2,%rbp
  mov    %rax,%rbx
  sete   %r13b
  jmp    L118
L97:
  cmp    $0x1,%rbx
  je     L29
L81:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rbp
  test   %rdx,%rdx
  jne    L29
  mov    %rax,%rbx
L118:
  add    $0x1,%r12
  mov    %rbp,0x8(%r15,%r12,8)
  cmp    $0x1,%r12
  je     L97
  test   %r13b,%r13b
  je     L97
  cmp    $0x1,%r12
  jbe    L80
  lea    -0x8(,%r12,8),%rdx
  lea    0x18(%r15),%rdi
  mov    %r14,%rsi
  call   <memmove@plt>
L80:
  movq   $0x2,0x10(%r15)
  cmp    $0x1,%rbx
  jne    L81
  nopw   0x0(%rax,%rax,1)
L29:
  addq   $0x8,(%rsp)
  mov    (%rsp),%rax
  mov    -0x8(%rax),%rbp
  test   %rbp,%rbp
  jne    L33
L50:
  movq   0x8(%rsp),%xmm0
  movq   %r12,%xmm1
  mov    %r12,%rax
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%r15)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  xor    %r12d,%r12d
  jmp    L50
```

assistant: ```c
int32_t decompose(int32_t n, int32_t *ifac, const int32_t *ntryh) {
  int32_t nl = n, nf = 0, i, j = 0;
  for (j = 0; ntryh[j]; ++j) {
    int32_t ntry = ntryh[j];
    while (nl != 1) {
      int32_t nq = nl / ntry;
      int32_t nr = nl - ntry * nq;
      if (nr == 0) {
        ifac[2 + nf++] = ntry;
        nl = nq;
        if (ntry == 2 && nf != 1) {
          for (i = 2; i <= nf; ++i) {
            int32_t ib = nf - i + 2;
            ifac[ib + 1] = ifac[ib];
          }
          ifac[2] = 2;
        }
      } else
        break;
    }
  }
  ifac[0] = n;
  ifac[1] = nf;
  return nf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blendcolor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  movzbl -0xc(%rbp),%eax
  jmp    L14
L10:
  movzbl -0xc(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x10(%rbp),%eax
  or     %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char blendcolor(unsigned char *table, unsigned char color1, unsigned char color2) {
  if (!table)
    return color1;
  return table[color1 << 8 | color2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blendcolor>:
  endbr64
  test   %rdi,%rdi
  je     L3
  movzbl %sil,%esi
  shl    $0x8,%esi
  movzbl %dl,%edx
  or     %edx,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%eax
  ret
L3:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned char blendcolor(unsigned char *table, unsigned char color1, unsigned char color2) {
  if (!table)
    return color1;
  return table[color1 << 8 | color2];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blendcolor>:
  endbr64
  test   %rdi,%rdi
  je     L4
  movzbl %sil,%esi
  movzbl %dl,%edx
  shl    $0x8,%esi
  or     %edx,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%eax
  ret
  nopl   (%rax)
L4:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned char blendcolor(unsigned char *table, unsigned char color1, unsigned char color2) {
  if (!table)
    return color1;
  return table[color1 << 8 | color2];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<blendcolor>:
  endbr64
  test   %rdi,%rdi
  je     L7
  movzbl %sil,%esi
  movzbl %dl,%edx
  shl    $0x8,%esi
  or     %edx,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%eax
  ret
  nopl   (%rax)
L7:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned char blendcolor(unsigned char *table, unsigned char color1, unsigned char color2) {
  if (!table)
    return color1;
  return table[color1 << 8 | color2];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<glsadff1t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jg     L6
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L16:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double glsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  x -= d[0] * g;
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = d[i + 1];
  return (x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glsadff1t>:
  endbr64
  mov    %rdi,%rcx
  mulsd  (%rdx),%xmm1
  subsd  %xmm1,%xmm0
  movslq %esi,%rax
  movapd %xmm0,%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L26
  cltq
L36:
  movapd %xmm0,%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  addsd  (%rdx,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L36
L26:
  test   %esi,%esi
  jle    L0
  mov    %rdx,%rax
  lea    -0x1(%rsi),%ecx
  lea    (%rdx,%rcx,8),%rcx
L1:
  mov    %rax,%rdx
  movsd  0x8(%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rdx
  jne    L1
L0:
  ret
```

assistant: ```c
double glsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  x -= d[0] * g;
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = d[i + 1];
  return (x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<glsadff1t>:
  endbr64
  mulsd  (%rdx),%xmm1
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  mov    %rdx,%rdi
  movslq %esi,%rdx
  subsd  %xmm1,%xmm0
  movsd  (%rcx,%rdx,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rdx,8)
  test   %eax,%eax
  jle    L26
  cltq
  nopl   0x0(%rax)
L18:
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rdi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L18
L26:
  test   %esi,%esi
  jle    L20
  sub    $0x18,%rsp
  shl    $0x3,%rdx
  lea    0x8(%rdi),%rsi
  movsd  %xmm0,0x8(%rsp)
  call   <memmove@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L20:
  ret
```

assistant: ```c
double glsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  x -= d[0] * g;
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = d[i + 1];
  return (x);
}
```