ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<in_array>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L48
  mov    %rsi,%rbp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L40:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L48
L12:
  cmpb   $0x0,(%rdi)
  je     L40
  call   <strlen@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L40
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int in_array(char **array, char *str) {
  int i;
  for (i = 0; array[i]; i++) {
    if (array[i][0] && !strncmp(str, array[i], strlen(array[i])))
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<user_poly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rcx
  lea    -0x24(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getmousepos@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L19
L17:
  mov    -0x24(%rbp),%eax
  cmp    $0x1,%eax
  jne    L39
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <hidemouseptr@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <array_line_entry@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%eax
  mov    $0x1,%r8d
  mov    %eax,%edi
  call   <bresline@plt>
  mov    $0x0,%eax
  call   <showmouseptr@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    $0xc8,%edi
  call   <delay@plt>
L39:
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rcx
  lea    -0x24(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getmousepos@plt>
L19:
  mov    -0x24(%rbp),%eax
  cmp    $0x2,%eax
  jne    L17
  mov    $0x0,%eax
  call   <hidemouseptr@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <array_line_entry@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%eax
  mov    $0x1,%r8d
  mov    %eax,%edi
  call   <bresline@plt>
  mov    $0x0,%eax
  call   <showmouseptr@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void user_poly() {
  int inix, iniy, curx1, cury1, curx2, cury2;
  int mousex, mousey, button;
  getmousepos(&button, &mousex, &mousey);
  inix = mousex;
  iniy = mousey;
  curx1 = inix;
  cury1 = iniy;
  for (; button != 2; getmousepos(&button, &mousex, &mousey)) {
    if (button == 1) {
      curx2 = mousex;
      cury2 = mousey;
      hidemouseptr();
      array_line_entry(curx1, cury1, curx2, cury2);
      bresline(curx1, cury1, curx2, cury2, 1);
      showmouseptr();
      curx1 = curx2;
      cury1 = cury2;
      delay(200);
    }
  }
  hidemouseptr();
  array_line_entry(curx1, cury1, inix, iniy);
  bresline(curx1, cury1, inix, iniy, 1);
  showmouseptr();
}
```
user: Translate the below assembly code into C programming language:

```asm
<user_poly>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    0x24(%rsp),%rdi
  call   <getmousepos@plt>
  mov    0x1c(%rsp),%ebp
  mov    %ebp,0xc(%rsp)
  mov    0x20(%rsp),%r15d
  mov    0x24(%rsp),%eax
  cmp    $0x2,%eax
  je     L45
  mov    %r15d,%r12d
  lea    0x20(%rsp),%rbx
  jmp    L3
L58:
  lea    0x1c(%rsp),%rsi
  lea    0x24(%rsp),%rdi
  mov    %rbx,%rdx
  call   <getmousepos@plt>
  mov    0x24(%rsp),%eax
  cmp    $0x2,%eax
  je     L25
L3:
  cmp    $0x1,%eax
  jne    L58
  mov    0x1c(%rsp),%r13d
  mov    0x20(%rsp),%r14d
  mov    $0x0,%eax
  call   <hidemouseptr@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <array_line_entry@plt>
  mov    $0x1,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bresline@plt>
  mov    $0x0,%eax
  call   <showmouseptr@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    %r14d,%r12d
  mov    %r13d,%ebp
  jmp    L58
L45:
  mov    %r15d,%r12d
  mov    0xc(%rsp),%ebp
L25:
  mov    $0x0,%eax
  call   <hidemouseptr@plt>
  mov    %r15d,%ecx
  mov    0xc(%rsp),%ebx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <array_line_entry@plt>
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bresline@plt>
  mov    $0x0,%eax
  call   <showmouseptr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void user_poly() {
  int inix, iniy, curx1, cury1, curx2, cury2;
  int mousex, mousey, button;
  getmousepos(&button, &mousex, &mousey);
  inix = mousex;
  iniy = mousey;
  curx1 = inix;
  cury1 = iniy;
  for (; button != 2; getmousepos(&button, &mousex, &mousey)) {
    if (button == 1) {
      curx2 = mousex;
      cury2 = mousey;
      hidemouseptr();
      array_line_entry(curx1, cury1, curx2, cury2);
      bresline(curx1, cury1, curx2, cury2, 1);
      showmouseptr();
      curx1 = curx2;
      cury1 = cury2;
      delay(200);
    }
  }
  hidemouseptr();
  array_line_entry(curx1, cury1, inix, iniy);
  bresline(curx1, cury1, inix, iniy, 1);
  showmouseptr();
}
```
user: What is the c source code of the assembly code below?

```asm
<user_poly>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  lea    0x1c(%rsp),%rbx
  lea    0x24(%rsp),%r12
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <getmousepos@plt>
  mov    0x1c(%rsp),%r13d
  mov    0x20(%rsp),%r14d
  mov    0x24(%rsp),%eax
  mov    %r13d,0x8(%rsp)
  mov    %r14d,0xc(%rsp)
  cmp    $0x2,%eax
  jne    L33
  jmp    L22
  xchg   %ax,%ax
L26:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <getmousepos@plt>
  mov    0x24(%rsp),%eax
  cmp    $0x2,%eax
  je     L25
L33:
  cmp    $0x1,%eax
  jne    L26
  mov    0x1c(%rsp),%eax
  mov    0x20(%rsp),%r15d
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <hidemouseptr@plt>
  mov    0x4(%rsp),%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %r15d,%ecx
  call   <array_line_entry@plt>
  mov    0x4(%rsp),%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %r15d,%r14d
  call   <bresline@plt>
  xor    %eax,%eax
  call   <showmouseptr@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    0x4(%rsp),%r13d
  jmp    L26
  nopl   (%rax)
L22:
  mov    0xc(%rsp),%r14d
  mov    0x8(%rsp),%r13d
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  call   <hidemouseptr@plt>
  mov    0xc(%rsp),%r15d
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    0x8(%rsp),%ebx
  mov    %r15d,%ecx
  mov    %ebx,%edx
  call   <array_line_entry@plt>
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <bresline@plt>
  xor    %eax,%eax
  call   <showmouseptr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void user_poly() {
  int inix, iniy, curx1, cury1, curx2, cury2;
  int mousex, mousey, button;
  getmousepos(&button, &mousex, &mousey);
  inix = mousex;
  iniy = mousey;
  curx1 = inix;
  cury1 = iniy;
  for (; button != 2; getmousepos(&button, &mousex, &mousey)) {
    if (button == 1) {
      curx2 = mousex;
      cury2 = mousey;
      hidemouseptr();
      array_line_entry(curx1, cury1, curx2, cury2);
      bresline(curx1, cury1, curx2, cury2, 1);
      showmouseptr();
      curx1 = curx2;
      cury1 = cury2;
      delay(200);
    }
  }
  hidemouseptr();
  array_line_entry(curx1, cury1, inix, iniy);
  bresline(curx1, cury1, inix, iniy, 1);
  showmouseptr();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<user_poly>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  lea    0x1c(%rsp),%rbx
  lea    0x24(%rsp),%r12
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <getmousepos@plt>
  mov    0x20(%rsp),%eax
  mov    0x1c(%rsp),%r13d
  mov    %eax,0xc(%rsp)
  mov    %eax,%r14d
  mov    0x24(%rsp),%eax
  mov    %r13d,0x8(%rsp)
  cmp    $0x2,%eax
  je     L4
  nopl   (%rax)
L10:
  cmp    $0x1,%eax
  je     L8
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <getmousepos@plt>
  mov    0x24(%rsp),%eax
  cmp    $0x2,%eax
  jne    L10
L4:
  xor    %eax,%eax
  call   <hidemouseptr@plt>
  mov    0xc(%rsp),%r15d
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    0x8(%rsp),%ebx
  mov    %r15d,%ecx
  mov    %ebx,%edx
  call   <array_line_entry@plt>
  mov    $0x1,%r8d
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <bresline@plt>
  xor    %eax,%eax
  call   <showmouseptr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  mov    0x1c(%rsp),%eax
  mov    0x20(%rsp),%r15d
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <hidemouseptr@plt>
  mov    0x4(%rsp),%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %r15d,%ecx
  call   <array_line_entry@plt>
  mov    0x4(%rsp),%edx
  mov    %r14d,%esi
  mov    %r15d,%ecx
  mov    $0x1,%r8d
  mov    %r13d,%edi
  mov    %r15d,%r14d
  call   <bresline@plt>
  xor    %eax,%eax
  call   <showmouseptr@plt>
  mov    $0xc8,%edi
  call   <delay@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <getmousepos@plt>
  mov    0x24(%rsp),%eax
  mov    0x4(%rsp),%r13d
  cmp    $0x2,%eax
  jne    L10
  jmp    L4
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void user_poly() {
  int inix, iniy, curx1, cury1, curx2, cury2;
  int mousex, mousey, button;
  getmousepos(&button, &mousex, &mousey);
  inix = mousex;
  iniy = mousey;
  curx1 = inix;
  cury1 = iniy;
  for (; button != 2; getmousepos(&button, &mousex, &mousey)) {
    if (button == 1) {
      curx2 = mousex;
      cury2 = mousey;
      hidemouseptr();
      array_line_entry(curx1, cury1, curx2, cury2);
      bresline(curx1, cury1, curx2, cury2, 1);
      showmouseptr();
      curx1 = curx2;
      cury1 = cury2;
      delay(200);
    }
  }
  hidemouseptr();
  array_line_entry(curx1, cury1, inix, iniy);
  bresline(curx1, cury1, inix, iniy, 1);
  showmouseptr();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argparse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    -0x58(%rbp),%r15
  movl   $0x0,-0x48(%rbp)
  mov    -0x48(%rbp),%r12d
  mov    %r12d,-0x44(%rbp)
  jmp    L69
L67:
  addl   $0x1,-0x48(%rbp)
  cmp    $0x20,%r13d
  jne    L77
  cmpl   $0x20,-0x44(%rbp)
  je     L77
  add    $0x1,%r12d
L77:
  mov    %r13d,-0x44(%rbp)
L69:
  mov    %r15,%rax
  lea    0x1(%rax),%r15
  movzbl (%rax),%eax
  movsbl %al,%r13d
  test   %r13d,%r13d
  jne    L67
  add    $0x3,%r12d
  movslq %r12d,%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x48(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x58(%rbp),%r15
  mov    -0x38(%rbp),%rbx
  mov    -0x40(%rbp),%r14
  movl   $0x0,-0x44(%rbp)
  mov    %r14,%rax
  lea    0x8(%rax),%r14
  mov    %rbx,(%rax)
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  mov    $0x2,%r12d
  mov    %r14,%rax
  lea    0x8(%rax),%r14
  mov    %rbx,(%rax)
  jmp    L49
L64:
  cmp    $0x20,%r13d
  je     L46
  cmpl   $0x20,-0x44(%rbp)
  jne    L34
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  mov    %r14,%rax
  lea    0x8(%rax),%r14
  mov    %rbx,(%rax)
  add    $0x1,%r12d
L34:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  mov    %r13d,%edx
  mov    %dl,(%rax)
L46:
  mov    %r13d,-0x44(%rbp)
L49:
  mov    %r15,%rax
  lea    0x1(%rax),%r15
  movzbl (%rax),%eax
  movsbl %al,%r13d
  test   %r13d,%r13d
  jne    L64
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  mov    -0x60(%rbp),%rax
  mov    %r12d,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
char **argparse(char *line, int *cntp) {
  register char *from;
  register char *to;
  register int cnt;
  register int ch;
  int length;
  int lastch;
  register char **argv;
  char **argarray;
  char *args;
  from = line;
  lastch = cnt = length = 0;
  while ((ch = *from++) != '\0') {
    length++;
    if (ch == ' ' && lastch != ' ') {
      cnt++;
    }
    lastch = ch;
  }
  cnt += 3;
  argarray = (char **)malloc(cnt * sizeof(char *));
  args = (char *)malloc(length + 2);
  from = line;
  to = args;
  argv = argarray;
  lastch = '\0';
  *argv++ = to;
  *to++ = '\0';
  cnt = 2;
  *argv++ = to;
  while ((ch = *from++) != '\0') {
    if (ch != ' ') {
      if (lastch == ' ') {
        *to++ = '\0';
        *argv++ = to;
        cnt++;
      }
      *to++ = ch;
    }
    lastch = ch;
  }
  *to++ = '\0';
  *cntp = cnt;
  return (argarray);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<argparse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  lea    0x1(%rdi),%rbx
  movsbl (%rdi),%edx
  test   %edx,%edx
  je     L38
  mov    %rbx,%rax
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x1,%r8d
  sub    %ebx,%r8d
  jmp    L100
L104:
  add    $0x1,%rax
  movsbl -0x1(%rax),%ecx
  mov    %edx,%esi
  test   %ecx,%ecx
  je     L93
  mov    %ecx,%edx
L100:
  lea    (%r8,%rax,1),%ebp
  cmp    $0x20,%edx
  jne    L104
  cmp    $0x20,%esi
  setne  %cl
  cmp    $0x1,%cl
  sbb    $0xffffffff,%edi
  jmp    L104
L38:
  mov    %edx,%ebp
  mov    %edx,%edi
L93:
  lea    0x18(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  lea    0x2(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
  lea    0x10(%r14),%rdi
  mov    %rdx,0x8(%r14)
  movzbl 0x0(%r13),%ecx
  movsbl %cl,%eax
  test   %eax,%eax
  je     L46
  mov    $0x0,%esi
  mov    $0x2,%r8d
  jmp    L32
L3:
  mov    %cl,(%rdx)
  mov    %eax,%esi
  lea    0x1(%rdx),%rdx
L57:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ecx
  movsbl %cl,%eax
  test   %eax,%eax
  je     L99
L32:
  cmp    $0x20,%eax
  je     L40
  cmp    $0x20,%esi
  jne    L3
  lea    0x1(%rdx),%rsi
  movb   $0x0,(%rdx)
  mov    %rsi,(%rdi)
  add    $0x1,%r8d
  lea    0x8(%rdi),%rdi
  mov    %rsi,%rdx
  jmp    L3
L40:
  mov    %eax,%esi
  jmp    L57
L46:
  mov    $0x2,%r8d
L99:
  movb   $0x0,(%rdx)
  mov    %r8d,(%r12)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **argparse(char *line, int *cntp) {
  register char *from;
  register char *to;
  register int cnt;
  register int ch;
  int length;
  int lastch;
  register char **argv;
  char **argarray;
  char *args;
  from = line;
  lastch = cnt = length = 0;
  while ((ch = *from++) != '\0') {
    length++;
    if (ch == ' ' && lastch != ' ') {
      cnt++;
    }
    lastch = ch;
  }
  cnt += 3;
  argarray = (char **)malloc(cnt * sizeof(char *));
  args = (char *)malloc(length + 2);
  from = line;
  to = args;
  argv = argarray;
  lastch = '\0';
  *argv++ = to;
  *to++ = '\0';
  cnt = 2;
  *argv++ = to;
  while ((ch = *from++) != '\0') {
    if (ch != ' ') {
      if (lastch == ' ') {
        *to++ = '\0';
        *argv++ = to;
        cnt++;
      }
      *to++ = ch;
    }
    lastch = ch;
  }
  *to++ = '\0';
  *cntp = cnt;
  return (argarray);
}
```
user: Translate the below assembly code into C programming language:

```asm
<argparse>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rbx
  test   %edx,%edx
  je     L75
  mov    $0x1,%r9d
  mov    %rbx,%rax
  xor    %esi,%esi
  xor    %edi,%edi
  sub    %ebx,%r9d
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %ecx,%edx
L24:
  lea    (%r9,%rax,1),%r8d
  cmp    $0x20,%edx
  jne    L45
  cmp    $0x20,%esi
  setne  %cl
  cmp    $0x1,%cl
  sbb    $0xffffffff,%edi
L45:
  movsbl (%rax),%ecx
  add    $0x1,%rax
  mov    %edx,%esi
  test   %ecx,%ecx
  jne    L71
  lea    0x18(,%rdi,8),%edi
  lea    0x2(%r8),%r12d
L42:
  call   <malloc@plt>
  mov    %r12d,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  lea    0x10(%r14),%rdi
  lea    0x1(%rax),%rdx
  mov    %rax,(%r14)
  movb   $0x0,(%rax)
  mov    %rdx,0x8(%r14)
  movsbl 0x0(%r13),%eax
  mov    %eax,%ecx
  test   %eax,%eax
  je     L20
  xor    %esi,%esi
  mov    $0x2,%r8d
  jmp    L65
  xchg   %ax,%ax
L34:
  cmp    $0x20,%esi
  jne    L113
  lea    0x1(%rdx),%rsi
  movb   $0x0,(%rdx)
  add    $0x1,%r8d
  add    $0x8,%rdi
  mov    %rsi,-0x8(%rdi)
  mov    %rsi,%rdx
L113:
  add    $0x1,%rbx
  mov    %cl,(%rdx)
  mov    %eax,%esi
  add    $0x1,%rdx
  movsbl -0x1(%rbx),%eax
  mov    %eax,%ecx
  test   %eax,%eax
  je     L14
L65:
  cmp    $0x20,%eax
  jne    L34
  movsbl (%rbx),%eax
  add    $0x1,%rbx
  mov    $0x20,%esi
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L65
L14:
  movb   $0x0,(%rdx)
  mov    %r14,%rax
  pop    %rbx
  mov    %r8d,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  mov    $0x2,%r12d
  mov    $0x18,%edi
  jmp    L42
L20:
  mov    $0x2,%r8d
  jmp    L14
```

assistant: ```c
char **argparse(char *line, int *cntp) {
  register char *from;
  register char *to;
  register int cnt;
  register int ch;
  int length;
  int lastch;
  register char **argv;
  char **argarray;
  char *args;
  from = line;
  lastch = cnt = length = 0;
  while ((ch = *from++) != '\0') {
    length++;
    if (ch == ' ' && lastch != ' ') {
      cnt++;
    }
    lastch = ch;
  }
  cnt += 3;
  argarray = (char **)malloc(cnt * sizeof(char *));
  args = (char *)malloc(length + 2);
  from = line;
  to = args;
  argv = argarray;
  lastch = '\0';
  *argv++ = to;
  *to++ = '\0';
  cnt = 2;
  *argv++ = to;
  while ((ch = *from++) != '\0') {
    if (ch != ' ') {
      if (lastch == ' ') {
        *to++ = '\0';
        *argv++ = to;
        cnt++;
      }
      *to++ = ch;
    }
    lastch = ch;
  }
  *to++ = '\0';
  *cntp = cnt;
  return (argarray);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<argparse>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movsbl (%rdi),%ecx
  lea    0x1(%rdi),%rbx
  test   %ecx,%ecx
  je     L34
  mov    $0x1,%r9d
  mov    %rbx,%rax
  xor    %esi,%esi
  xor    %edi,%edi
  sub    %ebx,%r9d
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %edx,%ecx
L33:
  lea    (%r9,%rax,1),%r8d
  cmp    $0x20,%esi
  je     L57
  cmp    $0x20,%ecx
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%edi
L57:
  movsbl (%rax),%edx
  add    $0x1,%rax
  mov    %ecx,%esi
  test   %edx,%edx
  jne    L42
  lea    0x18(,%rdi,8),%edi
  lea    0x2(%r8),%r12d
L76:
  call   <malloc@plt>
  mov    %r12d,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  lea    0x10(%r14),%rdi
  lea    0x1(%rax),%rdx
  mov    %rax,(%r14)
  movb   $0x0,(%rax)
  mov    %rdx,0x8(%r14)
  movsbl 0x0(%r13),%eax
  mov    %eax,%ecx
  test   %eax,%eax
  je     L108
  xor    %esi,%esi
  mov    $0x2,%r8d
  jmp    L55
  xchg   %ax,%ax
L64:
  cmp    $0x20,%esi
  jne    L37
  lea    0x1(%rdx),%rsi
  movb   $0x0,(%rdx)
  add    $0x1,%r8d
  add    $0x8,%rdi
  mov    %rsi,-0x8(%rdi)
  mov    %rsi,%rdx
L37:
  add    $0x1,%rbx
  mov    %cl,(%rdx)
  mov    %eax,%esi
  add    $0x1,%rdx
  movsbl -0x1(%rbx),%eax
  mov    %eax,%ecx
  test   %eax,%eax
  je     L52
L55:
  cmp    $0x20,%eax
  jne    L64
  movsbl (%rbx),%eax
  add    $0x1,%rbx
  mov    $0x20,%esi
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L55
L52:
  movb   $0x0,(%rdx)
  mov    %r14,%rax
  pop    %rbx
  mov    %r8d,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x2,%r12d
  mov    $0x18,%edi
  jmp    L76
L108:
  mov    $0x2,%r8d
  jmp    L52
```

assistant: ```c
char **argparse(char *line, int *cntp) {
  register char *from;
  register char *to;
  register int cnt;
  register int ch;
  int length;
  int lastch;
  register char **argv;
  char **argarray;
  char *args;
  from = line;
  lastch = cnt = length = 0;
  while ((ch = *from++) != '\0') {
    length++;
    if (ch == ' ' && lastch != ' ') {
      cnt++;
    }
    lastch = ch;
  }
  cnt += 3;
  argarray = (char **)malloc(cnt * sizeof(char *));
  args = (char *)malloc(length + 2);
  from = line;
  to = args;
  argv = argarray;
  lastch = '\0';
  *argv++ = to;
  *to++ = '\0';
  cnt = 2;
  *argv++ = to;
  while ((ch = *from++) != '\0') {
    if (ch != ' ') {
      if (lastch == ' ') {
        *to++ = '\0';
        *argv++ = to;
        cnt++;
      }
      *to++ = ch;
    }
    lastch = ch;
  }
  *to++ = '\0';
  *cntp = cnt;
  return (argarray);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D7(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: f64

tool: D7: 1e-06

assistant: ```c
double get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (double)(tv.tv_sec) + 0.000001 * tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm0
  movsd  D6(%rip),%xmm1
  mulsd  (%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: f64

tool: D6: 1e-06

assistant: ```c
double get_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (double)(tv.tv_sec) + 0.000001 * tv.tv_usec;
}
```