ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<String2TermType>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L40
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8d,%r8d
  je     L40
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x3,%eax
  test   %r8d,%r8d
  je     L40
  lea    D51(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x4,%eax
  test   %r8d,%r8d
  je     L40
  lea    D62(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x5,%eax
  test   %r8d,%r8d
  je     L40
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x6,%eax
  test   %r8d,%r8d
  je     L40
  lea    D79(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x7,%eax
  test   %r8d,%r8d
  je     L40
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  shl    $0x3,%eax
L40:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D39
datatype: string
name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D51
datatype: string
name: disassemble_data
arguments: label: D62
datatype: string
name: disassemble_data
arguments: label: D21
datatype: string
name: disassemble_data
arguments: label: D79
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D7: VT52

tool: D39: VT100

tool: D33: ANSI

tool: D51: KAYPRO

tool: D62: ADM31

tool: D21: C128

tool: D79: MEMOTECH

tool: D9: CPC

assistant: ```c
int String2TermType(char *name) {
  if (!strcmp(name, "VT52"))
    return 1;
  else if (!strcmp(name, "VT100"))
    return 2;
  else if (!strcmp(name, "ANSI"))
    return 3;
  else if (!strcmp(name, "KAYPRO"))
    return 4;
  else if (!strcmp(name, "ADM31"))
    return 5;
  else if (!strcmp(name, "C128"))
    return 6;
  else if (!strcmp(name, "MEMOTECH"))
    return 7;
  else if (!strcmp(name, "CPC"))
    return 8;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<childExit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string

tool: D8: 
Numeric value of signal SIGCHLD is %d


tool: D16: Parent received the signal

assistant: ```c
void childExit(int sig) {
  printf("\nNumeric value of signal SIGCHLD is %d\n", sig);
  printf("Parent received the signal\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<childExit>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D19
type: string

tool: D17: 
Numeric value of signal SIGCHLD is %d


tool: D19: Parent received the signal

assistant: ```c
void childExit(int sig) {
  printf("\nNumeric value of signal SIGCHLD is %d\n", sig);
  printf("Parent received the signal\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<childExit>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D3: 
Numeric value of signal SIGCHLD is %d


tool: D10: Parent received the signal

assistant: ```c
void childExit(int sig) {
  printf("\nNumeric value of signal SIGCHLD is %d\n", sig);
  printf("Parent received the signal\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<childExit>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D1: 
Numeric value of signal SIGCHLD is %d


tool: D18: Parent received the signal

assistant: ```c
void childExit(int sig) {
  printf("\nNumeric value of signal SIGCHLD is %d\n", sig);
  printf("Parent received the signal\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<knots2mph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  mov    -0x4(%rbp),%eax
  jmp    L18
L1:
  mov    -0x4(%rbp),%eax
  imul   $0xe213,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <round@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: f64

tool: D3: 50292

assistant: ```c
int knots2mph(int knots) {
  if (knots < 0)
    return knots;
  return round(knots * 57875 / 50292.0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<knots2mph>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  js     L4
  sub    $0x8,%rsp
  imul   $0xe213,%edi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D9(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <round@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: f64

tool: D9: 50292

assistant: ```c
int knots2mph(int knots) {
  if (knots < 0)
    return knots;
  return round(knots * 57875 / 50292.0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<knots2mph>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  js     L2
  imul   $0xe213,%edi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1050 <round@plt>
  nopl   0x0(%rax)
L2:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: f64

tool: D4: 50292

assistant: ```c
int knots2mph(int knots) {
  if (knots < 0)
    return knots;
  return round(knots * 57875 / 50292.0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<knots2mph>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  js     L9
  imul   $0xe213,%edi,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1050 <round@plt>
  nopl   0x0(%rax)
L9:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: f64

tool: D3: 50292

assistant: ```c
int knots2mph(int knots) {
  if (knots < 0)
    return knots;
  return round(knots * 57875 / 50292.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divpwr2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int bias = ((1 << n) + (~0)) & (x >> 31);
  return (x + bias) >> n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int bias = ((1 << n) + (~0)) & (x >> 31);
  return (x + bias) >> n;
}
```
user: What is the c source code of the assembly code below:

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  mov    %edi,%edx
  shl    %cl,%eax
  sar    $0x1f,%edx
  sub    $0x1,%eax
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int bias = ((1 << n) + (~0)) & (x >> 31);
  return (x + bias) >> n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  mov    %edi,%edx
  shl    %cl,%eax
  sar    $0x1f,%edx
  sub    $0x1,%eax
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int bias = ((1 << n) + (~0)) & (x >> 31);
  return (x + bias) >> n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <numberOf1InBinary@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D17
type: string

tool: D1: Input a number:

tool: D7: %d

tool: D17: It's %d of 1


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("Input a number:");
  scanf("%d", &number);
  printf("It's %d of 1\n", numberOf1InBinary(number));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <numberOf1InBinary@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string

tool: D3: Input a number:

tool: D12: %d

tool: D23: It's %d of 1


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("Input a number:");
  scanf("%d", &number);
  printf("It's %d of 1\n", numberOf1InBinary(number));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <numberOf1InBinary@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D22
datatype: string
name: parse_data
arguments: data_tag: D29
datatype: string

tool: D17: Input a number:

tool: D22: %d

tool: D29: It's %d of 1


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("Input a number:");
  scanf("%d", &number);
  printf("It's %d of 1\n", numberOf1InBinary(number));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <numberOf1InBinary@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D13: Input a number:

tool: D17: %d

tool: D19: It's %d of 1


assistant: ```c
int main(int argc, const char *argv[]) {
  int number;
  printf("Input a number:");
  scanf("%d", &number);
  printf("It's %d of 1\n", numberOf1InBinary(number));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<yamlprintable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  je     L27
  cmpl   $0xa,-0x4(%rbp)
  je     L27
  cmpl   $0xd,-0x4(%rbp)
  je     L27
  cmpl   $0x1f,-0x4(%rbp)
  jle    L0
  cmpl   $0x7e,-0x4(%rbp)
  jle    L27
L0:
  cmpl   $0x85,-0x4(%rbp)
  je     L27
  cmpl   $0x9f,-0x4(%rbp)
  jle    L28
  cmpl   $0xd7ff,-0x4(%rbp)
  jle    L27
L28:
  cmpl   $0xe000,-0x4(%rbp)
  jg     L7
  cmpl   $0xfffc,-0x4(%rbp)
  jg     L27
L7:
  cmpl   $0xffff,-0x4(%rbp)
  jle    L64
  cmpl   $0x10ffff,-0x4(%rbp)
  jg     L64
L27:
  mov    $0x1,%eax
  jmp    L90
L64:
  mov    $0x0,%eax
L90:
  pop    %rbp
  ret
```

assistant: ```c
int yamlprintable(wint_t c) {
  if (c == 0x9 || c == 0xA || c == 0xD || (c >= 0x20 && c <= 0x7E) || c == 0x85 || (c >= 0xA0 && c <= 0xD7FF) || (c <= 0xE000 && c >= 0xFFFD) || (c >= 0x10000 && c <= 0x10FFFF)) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yamlprintable>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L38
  cmp    $0xd,%edi
  je     L38
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%eax
  jbe    L17
  cmp    $0x85,%edi
  je     L17
  lea    -0xa0(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0xd75f,%edx
  jbe    L37
  sub    $0x10000,%edi
  cmp    $0xfffff,%edi
  setbe  %al
  movzbl %al,%eax
  ret
L38:
  mov    $0x1,%eax
  ret
L17:
  mov    $0x1,%eax
L37:
  ret
```

assistant: ```c
int yamlprintable(wint_t c) {
  if (c == 0x9 || c == 0xA || c == 0xD || (c >= 0x20 && c <= 0x7E) || c == 0x85 || (c >= 0xA0 && c <= 0xD7FF) || (c <= 0xE000 && c >= 0xFFFD) || (c >= 0x10000 && c <= 0x10FFFF)) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yamlprintable>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L25
  cmp    $0xd,%edi
  je     L25
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%eax
  jbe    L25
  cmp    $0x85,%edi
  je     L25
  lea    -0xa0(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0xd75f,%edx
  jbe    L34
  sub    $0x10000,%edi
  xor    %eax,%eax
  cmp    $0xfffff,%edi
  setbe  %al
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
L34:
  ret
```

assistant: ```c
int yamlprintable(wint_t c) {
  if (c == 0x9 || c == 0xA || c == 0xD || (c >= 0x20 && c <= 0x7E) || c == 0x85 || (c >= 0xA0 && c <= 0xD7FF) || (c <= 0xE000 && c >= 0xFFFD) || (c >= 0x10000 && c <= 0x10FFFF)) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yamlprintable>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L0
  cmp    $0xd,%edi
  je     L0
  lea    -0x20(%rdi),%eax
  cmp    $0x5e,%eax
  jbe    L0
  cmp    $0x85,%edi
  je     L0
  lea    -0xa0(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0xd75f,%edx
  jbe    L17
  sub    $0x10000,%edi
  xor    %eax,%eax
  cmp    $0xfffff,%edi
  setbe  %al
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
L17:
  ret
```

assistant: ```c
int yamlprintable(wint_t c) {
  if (c == 0x9 || c == 0xA || c == 0xD || (c >= 0x20 && c <= 0x7E) || c == 0x85 || (c >= 0xA0 && c <= 0xD7FF) || (c <= 0xE000 && c >= 0xFFFD) || (c >= 0x10000 && c <= 0x10FFFF)) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sprintf_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %ecx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  jne    L69
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  movb   $0x30,-0x20(%rbp,%rax,1)
  jmp    L62
L69:
  cmpl   $0x0,-0x4c(%rbp)
  jns    L32
  movl   $0x1,-0x30(%rbp)
  negl   -0x4c(%rbp)
  jmp    L32
L11:
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4c(%rbp)
L32:
  cmpl   $0x0,-0x4c(%rbp)
  jg     L11
  jmp    L62
L43:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  movb   $0x30,-0x20(%rbp,%rax,1)
L62:
  mov    -0x54(%rbp),%eax
  sub    -0x34(%rbp),%eax
  test   %eax,%eax
  jg     L43
  cmpl   $0x1,-0x30(%rbp)
  jne    L72
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  movb   $0x2d,-0x20(%rbp,%rax,1)
  jmp    L72
L66:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  movzbl -0x20(%rbp,%rdx,1),%edx
  mov    %dl,(%rax)
L72:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  test   %eax,%eax
  jg     L66
  mov    -0x28(%rbp),%rax
  sub    -0x48(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int sprintf_dec(char *str, int num, int zero_padding, int width) {
  char *dst;
  int i = 0;
  char tmp_buf[16 + 1];
  int minus_sign = 0;
  int one_digit;
  dst = str;
  if (num == 0) {
    tmp_buf[i++] = '0';
  } else {
    if (num < 0) {
      minus_sign = 1;
      num = -1 * num;
    }
    while (num > 0) {
      one_digit = num % 10;
      tmp_buf[i++] = '0' + one_digit;
      num /= 10;
    }
  }
  while (width - i > 0) {
    tmp_buf[i++] = '0';
  }
  if (minus_sign == 1) {
    tmp_buf[i++] = '-';
  }
  while (i-- > 0) {
    *dst++ = tmp_buf[i];
  }
  return dst - str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sprintf_dec>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %ecx,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jne    L77
  movb   $0x30,(%rsp)
  mov    $0x1,%edx
  cmp    $0x1,%ecx
  jle    L96
L2:
  lea    0x1(%rdx),%eax
  cltq
  lea    -0x1(%rsp),%r8
  add    $0x1,%r11d
L128:
  mov    %eax,%edx
  movb   $0x30,(%r8,%rax,1)
  add    $0x1,%rax
  mov    %r11d,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jg     L128
L8:
  cmp    $0x1,%esi
  je     L65
L81:
  lea    -0x1(%rdx),%esi
  test   %edx,%edx
  jle    L38
L96:
  movslq %edx,%rax
  lea    (%rsp,%rax,1),%rcx
  mov    %edx,%edx
  add    %rdi,%rdx
  mov    %rdi,%rax
L83:
  add    $0x1,%rax
  movzbl -0x1(%rcx),%r8d
  mov    %r8b,-0x1(%rax)
  sub    $0x1,%rcx
  cmp    %rdx,%rax
  jne    L83
  lea    0x1(%rsi),%eax
  add    %rdi,%rax
L21:
  sub    %edi,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L77:
  js     L122
  mov    %esi,%ecx
  mov    $0x0,%esi
L36:
  mov    $0x1,%r8d
  lea    -0x1(%rsp),%rbx
L110:
  mov    %r8d,%edx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  lea    (%rax,%rax,4),%r10d
  add    %r10d,%r10d
  mov    %ecx,%r9d
  sub    %r10d,%r9d
  add    $0x30,%r9d
  mov    %r9b,(%rbx,%r8,1)
  mov    %ecx,%r9d
  mov    %eax,%ecx
  add    $0x1,%r8
  cmp    $0x9,%r9d
  jg     L110
  cmp    %edx,%r11d
  jg     L2
  jmp    L8
L122:
  neg    %esi
  mov    %esi,%ecx
  mov    $0x1,%esi
  jmp    L36
L65:
  movslq %edx,%rax
  movb   $0x2d,(%rsp,%rax,1)
  lea    0x1(%rdx),%edx
  jmp    L81
L38:
  mov    %rdi,%rax
  jmp    L21
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sprintf_dec(char *str, int num, int zero_padding, int width) {
  char *dst;
  int i = 0;
  char tmp_buf[16 + 1];
  int minus_sign = 0;
  int one_digit;
  dst = str;
  if (num == 0) {
    tmp_buf[i++] = '0';
  } else {
    if (num < 0) {
      minus_sign = 1;
      num = -1 * num;
    }
    while (num > 0) {
      one_digit = num % 10;
      tmp_buf[i++] = '0' + one_digit;
      num /= 10;
    }
  }
  while (width - i > 0) {
    tmp_buf[i++] = '0';
  }
  if (minus_sign == 1) {
    tmp_buf[i++] = '-';
  }
  while (i-- > 0) {
    *dst++ = tmp_buf[i];
  }
  return dst - str;
}
```