user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  D48(%rip),%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L6:
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  D51(%rip),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D42(%rip),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D87
type: string
name: read_data
arguments: data_label: D66
type: string
name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D48
type: byte[4]
name: read_data
arguments: data_label: D51
type: f32
name: read_data
arguments: data_label: D42
type: byte[8]
name: read_data
arguments: data_label: D20
type: string

tool: D2: Enter amount of loan:

tool: D87: %f

tool: D66: Enter interest rate:

tool: D9: Enter payment times:

tool: D36: %d

tool: {"D48": [0x00,0x00,0xc8,0x42]}

tool: D51: 1

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D20: loan remain:%.2f


assistant: ```c
int main() {
  int i, times;
  float rate, loan, remainder;
  printf("Enter amount of loan:");
  scanf("%f", &loan);
  printf("Enter interest rate:");
  scanf("%f", &rate);
  printf("Enter payment times:");
  scanf("%d", &times);
  rate /= (float)times * 100;
  for (i = 0; i < times; i++) {
    remainder = (loan * (((float)times - i - 1) / (float)times)) * (1.0 + rate);
    printf("loan remain:%.2f\n", remainder);
  }
  return 0;
}
```