ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BesselI0>:
  endbr64
  mulsd  %xmm0,%xmm0
  movsd  D62(%rip),%xmm3
  movsd  D24(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D0(%rip),%xmm2
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm3
  movapd %xmm1,%xmm2
  divsd  D56(%rip),%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  movapd %xmm1,%xmm3
  divsd  D23(%rip),%xmm3
  addsd  %xmm2,%xmm3
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm2
  divsd  D50(%rip),%xmm2
  addsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm3
  divsd  D32(%rip),%xmm3
  addsd  %xmm2,%xmm3
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  movapd %xmm1,%xmm2
  divsd  D83(%rip),%xmm2
  addsd  %xmm3,%xmm2
  divsd  D84(%rip),%xmm0
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D62
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D24
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D0
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D56
datatype: f64
name: disassemble_data
arguments: data_tag: D23
datatype: f64
name: disassemble_data
arguments: data_tag: D50
datatype: f64
name: disassemble_data
arguments: data_tag: D32
datatype: f64
name: disassemble_data
arguments: data_tag: D83
datatype: f64
name: disassemble_data
arguments: data_tag: D84
datatype: f64

tool: {"D62": [0x00,0x00,0x00,0x00,0x00,0x00,0x90,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D56: 2304

tool: D23: 147456

tool: D50: 14745600

tool: D32: 2123366400

tool: D83: 416179814400

tool: D84: 106542032486400

assistant: ```c
double BesselI0(double x) {
  double sum, xx, x2;
  sum = 1;
  x2 = x * x;
  xx = x2;
  sum += xx / 4.0;
  xx *= x2;
  sum += xx / 64.0;
  xx *= x2;
  sum += xx / 2304.0;
  xx *= x2;
  sum += xx / 147456.0;
  xx *= x2;
  sum += xx / 14745600.0;
  xx *= x2;
  sum += xx / 2123366400.0;
  xx *= x2;
  sum += xx / 416179814400.0;
  xx *= x2;
  sum += xx / 106542032486400.0;
  return (sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vec4_transformQuat>:
  endbr64
  movss  (%rdi),%xmm2
  movss  0x4(%rdi),%xmm8
  movss  0x8(%rdi),%xmm6
  movss  (%rsi),%xmm11
  movss  0x4(%rsi),%xmm1
  movss  0x8(%rsi),%xmm7
  movss  0xc(%rsi),%xmm0
  movaps %xmm2,%xmm4
  mulss  %xmm0,%xmm4
  movaps %xmm6,%xmm3
  mulss  %xmm1,%xmm3
  addss  %xmm3,%xmm4
  movaps %xmm8,%xmm3
  mulss  %xmm7,%xmm3
  subss  %xmm3,%xmm4
  movaps %xmm8,%xmm3
  mulss  %xmm0,%xmm3
  movaps %xmm2,%xmm5
  mulss  %xmm7,%xmm5
  addss  %xmm5,%xmm3
  movaps %xmm6,%xmm5
  mulss  %xmm11,%xmm5
  subss  %xmm5,%xmm3
  movaps %xmm6,%xmm5
  mulss  %xmm0,%xmm5
  movaps %xmm8,%xmm9
  mulss  %xmm11,%xmm9
  addss  %xmm9,%xmm5
  movaps %xmm2,%xmm9
  mulss  %xmm1,%xmm9
  subss  %xmm9,%xmm5
  movss  D9(%rip),%xmm10
  movaps %xmm11,%xmm9
  xorps  %xmm10,%xmm9
  mulss  %xmm9,%xmm2
  mulss  %xmm1,%xmm8
  subss  %xmm8,%xmm2
  mulss  %xmm7,%xmm6
  subss  %xmm6,%xmm2
  movaps %xmm7,%xmm8
  xorps  %xmm10,%xmm8
  movaps %xmm0,%xmm6
  mulss  %xmm4,%xmm6
  movaps %xmm9,%xmm12
  mulss  %xmm2,%xmm12
  addss  %xmm12,%xmm6
  movaps %xmm8,%xmm12
  mulss  %xmm3,%xmm12
  addss  %xmm12,%xmm6
  movaps %xmm1,%xmm12
  mulss  %xmm5,%xmm12
  addss  %xmm12,%xmm6
  movss  %xmm6,(%rdi)
  xorps  %xmm10,%xmm1
  movaps %xmm0,%xmm6
  mulss  %xmm3,%xmm6
  movaps %xmm1,%xmm10
  mulss  %xmm2,%xmm10
  addss  %xmm10,%xmm6
  mulss  %xmm5,%xmm9
  addss  %xmm9,%xmm6
  mulss  %xmm4,%xmm7
  addss  %xmm7,%xmm6
  movss  %xmm6,0x4(%rdi)
  mulss  %xmm5,%xmm0
  mulss  %xmm2,%xmm8
  addss  %xmm8,%xmm0
  mulss  %xmm4,%xmm1
  addss  %xmm1,%xmm0
  mulss  %xmm3,%xmm11
  addss  %xmm11,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80]}

assistant: ```c
void vec4_transformQuat(float *dst, float *q) {
  float x = dst[0], y = dst[1], z = dst[2];
  float qx = q[0], qy = q[1], qz = q[2], qw = q[3];
  float ix = qw * x + qy * z - qz * y;
  float iy = qw * y + qz * x - qx * z;
  float iz = qw * z + qx * y - qy * x;
  float iw = -qx * x - qy * y - qz * z;
  dst[0] = ix * qw + iw * -qx + iy * -qz - iz * -qy;
  dst[1] = iy * qw + iw * -qy + iz * -qx - ix * -qz;
  dst[2] = iz * qw + iw * -qz + ix * -qy - iy * -qx;
  dst[3] = dst[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec4_transformQuat>:
  endbr64
  movss  (%rdi),%xmm2
  movss  0x8(%rdi),%xmm6
  movss  D7(%rip),%xmm11
  movss  0xc(%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  movaps %xmm2,%xmm4
  movaps %xmm6,%xmm3
  movss  0x4(%rdi),%xmm9
  movaps %xmm2,%xmm5
  mulss  %xmm1,%xmm3
  movss  0x8(%rsi),%xmm8
  movss  (%rsi),%xmm7
  mulss  %xmm0,%xmm4
  movaps %xmm9,%xmm10
  mulss  %xmm8,%xmm5
  mulss  %xmm7,%xmm10
  addss  %xmm3,%xmm4
  movaps %xmm9,%xmm3
  mulss  %xmm8,%xmm3
  subss  %xmm3,%xmm4
  movaps %xmm9,%xmm3
  mulss  %xmm0,%xmm3
  mulss  %xmm1,%xmm9
  addss  %xmm5,%xmm3
  movaps %xmm6,%xmm5
  mulss  %xmm7,%xmm5
  subss  %xmm5,%xmm3
  movaps %xmm6,%xmm5
  mulss  %xmm0,%xmm5
  mulss  %xmm8,%xmm6
  addss  %xmm10,%xmm5
  movaps %xmm2,%xmm10
  mulss  %xmm1,%xmm10
  subss  %xmm10,%xmm5
  movaps %xmm7,%xmm10
  mulss  %xmm3,%xmm7
  xorps  %xmm11,%xmm10
  mulss  %xmm10,%xmm2
  movaps %xmm10,%xmm12
  mulss  %xmm5,%xmm10
  subss  %xmm9,%xmm2
  movaps %xmm8,%xmm9
  mulss  %xmm4,%xmm8
  xorps  %xmm11,%xmm9
  subss  %xmm6,%xmm2
  movaps %xmm0,%xmm6
  mulss  %xmm4,%xmm6
  mulss  %xmm2,%xmm12
  addss  %xmm12,%xmm6
  movaps %xmm9,%xmm12
  mulss  %xmm3,%xmm12
  mulss  %xmm2,%xmm9
  addss  %xmm12,%xmm6
  movaps %xmm1,%xmm12
  xorps  %xmm11,%xmm1
  mulss  %xmm5,%xmm12
  movaps %xmm1,%xmm11
  mulss  %xmm2,%xmm11
  mulss  %xmm4,%xmm1
  addss  %xmm12,%xmm6
  movss  %xmm6,(%rdi)
  movaps %xmm0,%xmm6
  mulss  %xmm3,%xmm6
  mulss  %xmm5,%xmm0
  addss  %xmm11,%xmm6
  addss  %xmm9,%xmm0
  addss  %xmm10,%xmm6
  addss  %xmm1,%xmm0
  addss  %xmm8,%xmm6
  addss  %xmm7,%xmm0
  movss  %xmm6,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x80]}

assistant: ```c
void vec4_transformQuat(float *dst, float *q) {
  float x = dst[0], y = dst[1], z = dst[2];
  float qx = q[0], qy = q[1], qz = q[2], qw = q[3];
  float ix = qw * x + qy * z - qz * y;
  float iy = qw * y + qz * x - qx * z;
  float iz = qw * z + qx * y - qy * x;
  float iw = -qx * x - qy * y - qz * z;
  dst[0] = ix * qw + iw * -qx + iy * -qz - iz * -qy;
  dst[1] = iy * qw + iw * -qy + iz * -qx - ix * -qz;
  dst[2] = iz * qw + iw * -qz + ix * -qy - iy * -qx;
  dst[3] = dst[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec4_transformQuat>:
  endbr64
  movq   0x4(%rdi),%xmm10
  movss  (%rdi),%xmm1
  movq   (%rsi),%xmm11
  movq   (%rdi),%xmm8
  movaps %xmm10,%xmm5
  movss  0x8(%rsi),%xmm3
  movq   0x4(%rsi),%xmm9
  shufps $0xe5,%xmm5,%xmm5
  movaps %xmm5,%xmm0
  movaps %xmm8,%xmm2
  movaps %xmm11,%xmm13
  unpcklps %xmm1,%xmm0
  movq   0x8(%rsi),%xmm1
  unpcklps %xmm11,%xmm3
  movaps %xmm8,%xmm15
  mulps  %xmm3,%xmm2
  movaps %xmm0,%xmm14
  shufps $0xe5,%xmm15,%xmm15
  movq   D8(%rip),%xmm6
  mulps  %xmm9,%xmm14
  movaps %xmm1,%xmm4
  movaps %xmm5,%xmm12
  shufps $0xe5,%xmm1,%xmm1
  shufps $0xe5,%xmm4,%xmm4
  movaps %xmm4,%xmm7
  xorps  %xmm6,%xmm13
  xorps  %xmm3,%xmm6
  mulps  %xmm10,%xmm7
  mulps  %xmm10,%xmm3
  mulps  %xmm11,%xmm10
  addps  %xmm2,%xmm7
  movaps %xmm0,%xmm2
  mulps  %xmm11,%xmm2
  mulps  %xmm4,%xmm0
  subps  %xmm2,%xmm7
  movaps %xmm4,%xmm2
  mulps  %xmm8,%xmm2
  addps  %xmm10,%xmm0
  addps  %xmm14,%xmm2
  movaps %xmm15,%xmm14
  movaps %xmm9,%xmm15
  mulss  %xmm9,%xmm14
  shufps $0xe5,%xmm15,%xmm15
  mulss  %xmm15,%xmm12
  subps  %xmm3,%xmm2
  movss  (%rsi),%xmm3
  xorps  D13(%rip),%xmm3
  mulss  %xmm8,%xmm3
  mulps  %xmm9,%xmm8
  mulps  %xmm2,%xmm4
  subss  %xmm14,%xmm3
  subps  %xmm8,%xmm0
  subss  %xmm12,%xmm3
  mulps  %xmm9,%xmm0
  movaps %xmm3,%xmm8
  shufps $0xe0,%xmm8,%xmm8
  mulps  %xmm13,%xmm8
  shufps $0xe5,%xmm13,%xmm13
  addps  %xmm8,%xmm4
  movaps %xmm6,%xmm8
  mulps  %xmm7,%xmm8
  shufps $0xe5,%xmm7,%xmm7
  mulss  %xmm3,%xmm6
  mulss  %xmm7,%xmm1
  addps  %xmm8,%xmm4
  addss  %xmm6,%xmm1
  addps  %xmm4,%xmm0
  movlps %xmm0,(%rdi)
  movaps %xmm2,%xmm0
  shufps $0xe5,%xmm2,%xmm2
  mulss  %xmm13,%xmm0
  mulss  %xmm11,%xmm2
  addss  %xmm0,%xmm1
  addss  %xmm2,%xmm1
  movss  %xmm1,0x8(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: byte[8]
name: retrieve_data
arguments: data_tag: D13
type: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80]}

tool: {"D13": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void vec4_transformQuat(float *dst, float *q) {
  float x = dst[0], y = dst[1], z = dst[2];
  float qx = q[0], qy = q[1], qz = q[2], qw = q[3];
  float ix = qw * x + qy * z - qz * y;
  float iy = qw * y + qz * x - qx * z;
  float iz = qw * z + qx * y - qy * x;
  float iw = -qx * x - qy * y - qz * z;
  dst[0] = ix * qw + iw * -qx + iy * -qz - iz * -qy;
  dst[1] = iy * qw + iw * -qy + iz * -qx - ix * -qz;
  dst[2] = iz * qw + iw * -qz + ix * -qy - iy * -qx;
  dst[3] = dst[3];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x58(%rbp)
  movl   $0x3,-0x54(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x2,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0xffffffff,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0xfffffffe,-0x2c(%rbp)
  movl   $0xffffffff,-0x28(%rbp)
  movl   $0xfffffffe,-0x24(%rbp)
  movl   $0xfffffffe,-0x20(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0xfffffffe,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x64(%rbp),%eax
  mov    %eax,-0x5c(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L23
L9:
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x58(%rbp),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,8),%eax
  add    %edx,%eax
  mov    %eax,-0x58(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x4c(%rbp,%rax,8),%eax
  add    %edx,%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x58(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <eh_buraco@plt>
  test   %rax,%rax
  je     L32
  mov    -0x60(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x5c(%rbp)
  jmp    L15
L32:
  addl   $0x1,-0x60(%rbp)
L23:
  mov    -0x64(%rbp),%eax
  cmp    %eax,-0x60(%rbp)
  jl     L9
L15:
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string

tool: D19: %d

tool: D4: %d


assistant: ```c
int main(int argc, char *noargs[]) {
  int i, m, res, N, pos[2] = {4, 3};
  int moves[9][2] = {
      {0, 0}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}, {-2, 1}, {-1, 2},
  };
  scanf("%d", &N);
  res = N;
  for (i = 0; i < N; ++i) {
    scanf("%d", &m);
    pos[0] += moves[m][0];
    pos[1] += moves[m][1];
    if (eh_buraco(pos[0], pos[1])) {
      res = i + 1;
      break;
    }
  }
  printf("%d\n", res);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x2,0x28(%rsp)
  movl   $0xffffffff,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0xfffffffe,0x34(%rsp)
  movl   $0xffffffff,0x38(%rsp)
  movl   $0xfffffffe,0x3c(%rsp)
  movl   $0xfffffffe,0x40(%rsp)
  movl   $0xffffffff,0x44(%rsp)
  movl   $0xfffffffe,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  movl   $0xffffffff,0x50(%rsp)
  movl   $0x2,0x54(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r14d
  test   %r14d,%r14d
  jle    L28
  mov    $0x3,%r12d
  mov    $0x4,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L20:
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  mov    %ebp,%edi
  add    0x10(%rsp,%rax,8),%edi
  mov    %edi,%ebp
  mov    %r12d,%esi
  add    0x14(%rsp,%rax,8),%esi
  mov    %esi,%r12d
  call   <eh_buraco@plt>
  test   %rax,%rax
  jne    L32
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L20
  jmp    L28
L32:
  lea    0x1(%rbx),%r14d
L28:
  mov    %r14d,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D27
type_guessed: string

tool: D5: %d

tool: D27: %d


assistant: ```c
int main(int argc, char *noargs[]) {
  int i, m, res, N, pos[2] = {4, 3};
  int moves[9][2] = {
      {0, 0}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}, {-2, 1}, {-1, 2},
  };
  scanf("%d", &N);
  res = N;
  for (i = 0; i < N; ++i) {
    scanf("%d", &m);
    pos[0] += moves[m][0];
    pos[1] += moves[m][1];
    if (eh_buraco(pos[0], pos[1])) {
      res = i + 1;
      break;
    }
  }
  printf("%d\n", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movabs $0x200000001,%rax
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xffffffff00000002,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xfffffffe00000001,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xfffffffeffffffff,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1fffffffe,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x2ffffffff,%rax
  movq   $0xfffffffffffffffe,0x40(%rsp)
  mov    %rax,0x50(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%r15d
  test   %r15d,%r15d
  jle    L31
  mov    $0x3,%r12d
  mov    $0x4,%ebp
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r14
  jmp    L20
  nop
L36:
  cmp    %ebx,0xc(%rsp)
  jle    L31
L20:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  add    0x10(%rsp,%rax,8),%ebp
  add    0x14(%rsp,%rax,8),%r12d
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <eh_buraco@plt>
  test   %rax,%rax
  je     L36
  mov    %ebx,%r15d
L31:
  mov    %r15d,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D18: %d

tool: D13: %d


assistant: ```c
int main(int argc, char *noargs[]) {
  int i, m, res, N, pos[2] = {4, 3};
  int moves[9][2] = {
      {0, 0}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}, {-2, 1}, {-1, 2},
  };
  scanf("%d", &N);
  res = N;
  for (i = 0; i < N; ++i) {
    scanf("%d", &m);
    pos[0] += moves[m][0];
    pos[1] += moves[m][1];
    if (eh_buraco(pos[0], pos[1])) {
      res = i + 1;
      break;
    }
  }
  printf("%d\n", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D61(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  movdqa D41(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D54(%rip),%rax
  lea    0xc(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movdqa D39(%rip),%xmm0
  mov    %rax,0x50(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D37(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%r15d
  test   %r15d,%r15d
  jle    L14
  mov    $0x3,%r12d
  mov    $0x4,%ebp
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r14
  jmp    L9
  nopl   0x0(%rax)
L33:
  cmp    %ebx,0xc(%rsp)
  jle    L14
L9:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  add    0x10(%rsp,%rax,8),%ebp
  add    0x14(%rsp,%rax,8),%r12d
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <eh_buraco@plt>
  test   %rax,%rax
  je     L33
  mov    %ebx,%r15d
L14:
  mov    %r15d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D61
type: string
name: unpack_data
arguments: label: D41
type: byte[16]
name: unpack_data
arguments: label: D54
type: byte[8]
name: unpack_data
arguments: label: D39
type: byte[16]
name: unpack_data
arguments: label: D37
type: byte[16]
name: unpack_data
arguments: label: D10
type: byte[16]
name: unpack_data
arguments: label: D9
type: string

tool: D61: %d

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D54": [0xff,0xff,0xff,0xff,0x02,0x00,0x00,0x00]}

tool: {"D39": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0xff,0xff,0xff,0xff]}

tool: {"D37": [0x01,0x00,0x00,0x00,0xfe,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff]}

tool: {"D10": [0xfe,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0x01,0x00,0x00,0x00]}

tool: D9: %d


assistant: ```c
int main(int argc, char *noargs[]) {
  int i, m, res, N, pos[2] = {4, 3};
  int moves[9][2] = {
      {0, 0}, {1, 2}, {2, 1}, {2, -1}, {1, -2}, {-1, -2}, {-2, -1}, {-2, 1}, {-1, 2},
  };
  scanf("%d", &N);
  res = N;
  for (i = 0; i < N; ++i) {
    scanf("%d", &m);
    pos[0] += moves[m][0];
    pos[1] += moves[m][1];
    if (eh_buraco(pos[0], pos[1])) {
      res = i + 1;
      break;
    }
  }
  printf("%d\n", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L1
L30:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L30
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L11
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L6
L11:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L6:
  nop
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D28
type: string
name: parse_data
arguments: label: D47
type: string
name: parse_data
arguments: label: D0
type: string

tool: D15: enter the no:

tool: D8: %d

tool: D28: 
The reversed no is %d


tool: D47: its paindrome

tool: D0: its not paindrome

assistant: ```c
int main() {
  int a, b, rem, rev = 0;
  printf("enter the no:");
  scanf("%d", &a);
  b = a;
  while (a != 0) {
    rem = a % 10;
    rev = rev * 10 + rem;
    a /= 10;
  }
  printf("\nThe reversed no is %d\n", rev);
  if (b == rev)
    printf("its paindrome\n");
  else
    printf("its not paindrome\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L29
  mov    %ebx,%edx
  mov    $0x0,%ebp
L44:
  lea    0x0(%rbp,%rbp,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ebp
  mov    %eax,%edx
  test   %eax,%eax
  jne    L44
  movl   $0x0,0x4(%rsp)
  mov    %ebp,%esi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L47
  lea    D4(%rip),%rdi
  call   <puts@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x0,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L36
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D46
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D59
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D29
datatype: string

tool: D46: enter the no:

tool: D38: %d

tool: D59: 
The reversed no is %d


tool: D4: its not paindrome

tool: D29: its paindrome

assistant: ```c
int main() {
  int a, b, rem, rev = 0;
  printf("enter the no:");
  scanf("%d", &a);
  b = a;
  while (a != 0) {
    rem = a % 10;
    rev = rev * 10 + rem;
    a /= 10;
  }
  printf("\nThe reversed no is %d\n", rev);
  if (b == rev)
    printf("its paindrome\n");
  else
    printf("its not paindrome\n");
  return;
}
```