ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getAll>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %ebp,%ebp
  js     L33
  mov    %ebx,%eax
  je     L25
  movzbl 0x10(%rsp),%eax
  cmp    $0x1,%ebp
  je     L25
  lea    0x8(%rsp),%r13
  lea    D10(%rip),%r14
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L48
  cmp    $0x2,%ebp
  je     L74
L25:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L75
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L33:
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x6e,%eax
  jmp    L25
  nop
L74:
  mov    %r13,%rdx
  mov    %r14,%rsi
  xor    %edi,%edi
  call   <strtok_r@plt>
  movzbl (%rax),%eax
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x6e,%eax
  jmp    L25
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string

tool: D10: ,

tool: D20: 
ERROR: getAll: negative position detected: %d


tool: D15: 
ERROR: getAll: impossible to take the %dth allele from alt: %s, only one present.


assistant: ```c
char getAll(char ref, char *alt, int x) {
  char alt1[20];
  char *s, *sps;
  unsigned int i;
  strcpy(alt1, alt);
  if (x < 0) {
    printf("\nERROR: getAll: negative position detected: %d\n", x);
    return 'n';
  } else {
    if (x == 0) {
      return ref;
    } else {
      if (x == 1) {
        return alt1[0];
      } else {
        s = strtok_r(alt1, ",", &sps);
        if (s == NULL) {
          printf("\nERROR: getAll: impossible to take the %dth allele from alt: %s, only one present.\n", x, alt1);
          return 'n';
        }
        i = 2;
        while (i == x) {
          s = strtok_r(NULL, ",", &sps);
          if ((s == NULL) && (i < x)) {
            printf("\nERROR: getAll: impossible to take the %dth allele from alt: %s, position out of bounds.\n", x, alt1);
            return 'n';
          }
          if (i == x) {
            return s[0];
          }
          i++;
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_reclen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void write_reclen(FILE *f, int n) {
  fputc(n & 0377, f);
  fputc((n >> 8) & 0377, f);
  fputc((n >> 16) & 0377, f);
  fputc((n >> 24) & 0377, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_reclen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movzbl %sil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  sar    $0x10,%edi
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  shr    $0x18,%ebx
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_reclen(FILE *f, int n) {
  fputc(n & 0377, f);
  fputc((n >> 8) & 0377, f);
  fputc((n >> 16) & 0377, f);
  fputc((n >> 24) & 0377, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_reclen>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  shr    $0x18,%ebx
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void write_reclen(FILE *f, int n) {
  fputc(n & 0377, f);
  fputc((n >> 8) & 0377, f);
  fputc((n >> 16) & 0377, f);
  fputc((n >> 24) & 0377, f);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_reclen>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  shr    $0x18,%ebx
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void write_reclen(FILE *f, int n) {
  fputc(n & 0377, f);
  fputc((n >> 8) & 0377, f);
  fputc((n >> 16) & 0377, f);
  fputc((n >> 24) & 0377, f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<accept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int accept(int __fd, __SOCKADDR_ARG __addr, socklen_t *__restrict __addr_len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<accept>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int accept(int __fd, __SOCKADDR_ARG __addr, socklen_t *__restrict __addr_len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<accept>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int accept(int __fd, __SOCKADDR_ARG __addr, socklen_t *__restrict __addr_len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<accept>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int accept(int __fd, __SOCKADDR_ARG __addr, socklen_t *__restrict __addr_len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <list@plt>
  mov    $0x0,%eax
  call   <tail@plt>
  mov    $0x0,%eax
  call   <circular@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  list();
  tail();
  circular();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <list@plt>
  mov    $0x0,%eax
  call   <tail@plt>
  mov    $0x0,%eax
  call   <circular@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  list();
  tail();
  circular();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <list@plt>
  xor    %eax,%eax
  call   <tail@plt>
  xor    %eax,%eax
  call   <circular@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  list();
  tail();
  circular();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <list@plt>
  xor    %eax,%eax
  call   <tail@plt>
  xor    %eax,%eax
  call   <circular@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  list();
  tail();
  circular();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6568,-0x16(%rbp)
  movw   $0x6f,-0x12(%rbp)
  movabs $0x657962646f6f67,%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  char s[] = "hello";
  char ss[] = "goodbye";
  if (s == "hello") {
    printf("[%s] == 'hello'\n", s);
  }
  if (ss == "hello") {
    printf("[%s] == 'hello'\n", ss);
  }
  if (s == "goodbye") {
    printf("[%s] == 'goodbye'\n", s);
  }
  if (ss == "goodbye") {
    printf("[%s] == 'goodbye'\n", ss);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[] = "hello";
  char ss[] = "goodbye";
  if (s == "hello") {
    printf("[%s] == 'hello'\n", s);
  }
  if (ss == "hello") {
    printf("[%s] == 'hello'\n", ss);
  }
  if (s == "goodbye") {
    printf("[%s] == 'goodbye'\n", s);
  }
  if (ss == "goodbye") {
    printf("[%s] == 'goodbye'\n", ss);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[] = "hello";
  char ss[] = "goodbye";
  if (s == "hello") {
    printf("[%s] == 'hello'\n", s);
  }
  if (ss == "hello") {
    printf("[%s] == 'hello'\n", ss);
  }
  if (s == "goodbye") {
    printf("[%s] == 'goodbye'\n", s);
  }
  if (ss == "goodbye") {
    printf("[%s] == 'goodbye'\n", ss);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char s[] = "hello";
  char ss[] = "goodbye";
  if (s == "hello") {
    printf("[%s] == 'hello'\n", s);
  }
  if (ss == "hello") {
    printf("[%s] == 'hello'\n", ss);
  }
  if (s == "goodbye") {
    printf("[%s] == 'goodbye'\n", s);
  }
  if (ss == "goodbye") {
    printf("[%s] == 'goodbye'\n", ss);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GrMapISO8859_1_Unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  movq   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
unsigned long GrMapISO8859_1_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  return ((unsigned long)((unsigned char)*pcSrcChar));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GrMapISO8859_1_Unicode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long GrMapISO8859_1_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  return ((unsigned long)((unsigned char)*pcSrcChar));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GrMapISO8859_1_Unicode>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long GrMapISO8859_1_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  return ((unsigned long)((unsigned char)*pcSrcChar));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GrMapISO8859_1_Unicode>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long GrMapISO8859_1_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  return ((unsigned long)((unsigned char)*pcSrcChar));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <get_menu_choice@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: You chose Menu Option %d


assistant: ```c
int main(int argc, char *argv[]) {
  int choice;
  choice = get_menu_choice();
  printf("You chose Menu Option %d\n", choice);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_menu_choice@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: You chose Menu Option %d


assistant: ```c
int main(int argc, char *argv[]) {
  int choice;
  choice = get_menu_choice();
  printf("You chose Menu Option %d\n", choice);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_menu_choice@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: You chose Menu Option %d


assistant: ```c
int main(int argc, char *argv[]) {
  int choice;
  choice = get_menu_choice();
  printf("You chose Menu Option %d\n", choice);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_menu_choice@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: You chose Menu Option %d


assistant: ```c
int main(int argc, char *argv[]) {
  int choice;
  choice = get_menu_choice();
  printf("You chose Menu Option %d\n", choice);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int write_lock(int fd) {
  struct flock lock;
  lock.l_type = F_WRLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  return fcntl(fd, F_SETLKW, &lock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_lock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    %rsp,%rdx
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_lock(int fd) {
  struct flock lock;
  lock.l_type = F_WRLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  return fcntl(fd, F_SETLKW, &lock);
}
```
user: What is the c source code of the assembly code below?

```asm
<write_lock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D11(%rip),%rax
  mov    %rsp,%rdx
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_lock(int fd) {
  struct flock lock;
  lock.l_type = F_WRLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  return fcntl(fd, F_SETLKW, &lock);
}
```
user: What is the c source code of the assembly code below:

```asm
<write_lock>:
  endbr64
  sub    $0x28,%rsp
  mov    D24(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D4(%rip),%rax
  movd   (%rdx),%xmm0
  mov    %rsp,%rdx
  mov    (%rax),%eax
  movd   %eax,%xmm1
  mov    D25(%rip),%rax
  punpckldq %xmm1,%xmm0
  mov    (%rax),%esi
  movq   %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  call   <fcntl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_lock(int fd) {
  struct flock lock;
  lock.l_type = F_WRLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  return fcntl(fd, F_SETLKW, &lock);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L10
L7:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t string_hash(void *key) {
  unsigned char *string_key = key;
  size_t hash = 5381;
  int c;
  while ((c = *(string_key++))) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L1
  mov    $0x1505,%eax
L0:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movzbl %dl,%edx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L0
  ret
L1:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t string_hash(void *key) {
  unsigned char *string_key = key;
  size_t hash = 5381;
  int c;
  while ((c = *(string_key++))) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L16
  nopl   0x0(%rax)
L12:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
size_t string_hash(void *key) {
  unsigned char *string_key = key;
  size_t hash = 5381;
  int c;
  while ((c = *(string_key++))) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L14
  nopl   0x0(%rax)
L5:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L5
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
size_t string_hash(void *key) {
  unsigned char *string_key = key;
  size_t hash = 5381;
  int c;
  while ((c = *(string_key++))) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lstEgrep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  je     L13
  cmpq   $0x0,-0x40(%rbp)
  jne    L63
L13:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D34(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L17
L63:
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L64
L36:
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  je     L118
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lstFree@plt>
  mov    $0x0,%eax
  jmp    L17
L118:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <regexec@plt>
  mov    D35(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L75
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  addq   $0x1,-0x18(%rbp)
  jmp    L64
L75:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstPush@plt>
  cmp    $0xffffffff,%eax
  jne    L55
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lstFree@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  mov    $0x0,%eax
  jmp    L17
L55:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  addq   $0x1,-0x18(%rbp)
L64:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L36
  mov    -0x20(%rbp),%rax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L116
  call   <__stack_chk_fail@plt>
L116:
  leave
  ret
```

assistant: ```c
char **lstEgrep(char *const *lst, const char *regexp) {
  if (!lst || !regexp) {
    errno = EINVAL;
    return NULL;
  }
  char **new_lst = NULL;
  size_t i = 0;
  while (lst[i]) {
    regex_t reg;
    regex_t *preg = &reg;
    memset(preg, 0, sizeof(regex_t));
    if (0 != regcomp(preg, regexp, REG_EXTENDED)) {
      lstFree(new_lst);
      return NULL;
    }
    if (REG_NOMATCH == regexec(preg, lst[i], 0, NULL, 0)) {
      regfree(preg);
      i++;
      continue;
    }
    if (-1 == lstPush(&new_lst, lst[i])) {
      lstFree(new_lst);
      regfree(preg);
      return NULL;
    }
    regfree(preg);
    i++;
  }
  return new_lst;
}
```