ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<udev_queue_get_udev_seqnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <open_queue_file@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbp
  lea    0x10(%rsp),%rbx
  nopl   0x0(%rax)
L42:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <udev_queue_read_seqnum@plt>
  test   %rax,%rax
  js     L61
L21:
  mov    %rbp,%rdi
  call   <udev_queue_skip_devpath@plt>
  test   %rax,%rax
  js     L61
  je     L42
  mov    0x10(%rsp),%rax
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  call   <udev_queue_read_seqnum@plt>
  test   %rax,%rax
  jns    L21
L61:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L12:
  xor    %eax,%eax
  jmp    L15
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) unsigned long long int udev_queue_get_udev_seqnum(struct udev_queue *udev_queue) {
  unsigned long long int seqnum_udev;
  FILE *queue_file;
  queue_file = open_queue_file(udev_queue, &seqnum_udev);
  if (queue_file == NULL)
    return 0;
  for (;;) {
    unsigned long long int seqnum;
    ssize_t devpath_len;
    if (udev_queue_read_seqnum(queue_file, &seqnum) < 0)
      break;
    devpath_len = udev_queue_skip_devpath(queue_file);
    if (devpath_len < 0)
      break;
    if (devpath_len > 0)
      seqnum_udev = seqnum;
  }
  fclose(queue_file);
  return seqnum_udev;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c_sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <c_vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int c_sprintf(char *str, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  int ret = c_vsprintf(str, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<c_sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <c_vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int c_sprintf(char *str, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  int ret = c_vsprintf(str, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<c_sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <c_vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int c_sprintf(char *str, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  int ret = c_vsprintf(str, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<c_sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <c_vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int c_sprintf(char *str, const char *fmt, ...) {
  va_list arg;
  va_start(arg, fmt);
  int ret = c_vsprintf(str, fmt, arg);
  va_end(arg);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L51
L2:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x3c(%rbp)
L51:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L2
  movl   $0x0,-0x38(%rbp)
  jmp    L23
L6:
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  jmp    L58
L74:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L12
  addl   $0x1,-0x34(%rbp)
L12:
  addl   $0x1,-0x3c(%rbp)
L58:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L74
  addl   $0x1,-0x38(%rbp)
L23:
  cmpl   $0x9,-0x38(%rbp)
  jle    L6
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string

tool: D20: Digite um numero

tool: D16: %d

tool: D14: aconteceu %d repeticoes

assistant: ```c
int main() {
  int c, i, repit = 0, vetor[10];
  for (c = 0; c <= 9; c++) {
    printf("Digite um numero");
    scanf("%d", &vetor[c]);
  }
  for (i = 0; i <= 9; i++) {
    for (c = i + 1; c <= 9; c++) {
      if (vetor[i] == vetor[c]) {
        repit++;
      }
    }
  }
  printf("aconteceu %d repeticoes", repit);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  lea    D17(%rip),%r12
  lea    D8(%rip),%rbp
L77:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r13
  jne    L77
  mov    $0x0,%esi
  mov    $0x1,%r8d
  mov    $0x0,%edi
  mov    $0x1,%eax
  jmp    L20
L51:
  add    $0x1,%eax
  cmp    $0x9,%eax
  jg     L29
L20:
  movslq %esi,%rdx
  movslq %eax,%rcx
  mov    (%rsp,%rcx,4),%ebx
  cmp    %ebx,(%rsp,%rdx,4)
  jne    L51
  add    $0x1,%edi
  jmp    L51
L14:
  mov    %edi,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  lea    0x1(%r8),%eax
  cmp    $0x9,%eax
  jg     L14
  mov    %r8d,%esi
  mov    %eax,%r8d
  jmp    L20
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D20
type_guessed: string

tool: D17: Digite um numero

tool: D8: %d

tool: D20: aconteceu %d repeticoes

assistant: ```c
int main() {
  int c, i, repit = 0, vetor[10];
  for (c = 0; c <= 9; c++) {
    printf("Digite um numero");
    scanf("%d", &vetor[c]);
  }
  for (i = 0; i <= 9; i++) {
    for (c = i + 1; c <= 9; c++) {
      if (vetor[i] == vetor[c]) {
        repit++;
      }
    }
  }
  printf("aconteceu %d repeticoes", repit);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  nopl   0x0(%rax)
L8:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L8
  mov    $0x1,%edi
  xor    %esi,%esi
  mov    $0x1,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L7:
  movslq %eax,%rdx
  mov    (%rsp,%rdx,4),%ebx
  cmp    %ebx,(%rsp,%rcx,4)
  jne    L20
  add    $0x1,%esi
L20:
  add    $0x1,%eax
  cmp    $0xa,%eax
  jne    L7
  lea    0x1(%rdi),%eax
  cmp    $0x9,%edi
  je     L48
  movslq %edi,%rcx
  mov    %eax,%edi
  jmp    L7
  nopl   (%rax)
L48:
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D22: Digite um numero

tool: D23: %d

tool: D19: aconteceu %d repeticoes

assistant: ```c
int main() {
  int c, i, repit = 0, vetor[10];
  for (c = 0; c <= 9; c++) {
    printf("Digite um numero");
    scanf("%d", &vetor[c]);
  }
  for (i = 0; i <= 9; i++) {
    for (c = i + 1; c <= 9; c++) {
      if (vetor[i] == vetor[c]) {
        repit++;
      }
    }
  }
  printf("aconteceu %d repeticoes", repit);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r13
  nopl   0x0(%rax)
L49:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L49
  mov    $0x1,%edi
  xor    %esi,%esi
  mov    $0x1,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L7:
  movslq %eax,%rdx
  mov    (%rsp,%rdx,4),%ebx
  cmp    %ebx,(%rsp,%rcx,4)
  jne    L59
  add    $0x1,%esi
L59:
  add    $0x1,%eax
  cmp    $0xa,%eax
  jne    L7
  lea    0x1(%rdi),%eax
  cmp    $0x9,%edi
  je     L25
  movslq %edi,%rcx
  mov    %eax,%edi
  jmp    L7
  nopl   (%rax)
L25:
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D9: Digite um numero

tool: D8: %d

tool: D7: aconteceu %d repeticoes

assistant: ```c
int main() {
  int c, i, repit = 0, vetor[10];
  for (c = 0; c <= 9; c++) {
    printf("Digite um numero");
    scanf("%d", &vetor[c]);
  }
  for (i = 0; i <= 9; i++) {
    for (c = i + 1; c <= 9; c++) {
      if (vetor[i] == vetor[c]) {
        repit++;
      }
    }
  }
  printf("aconteceu %d repeticoes", repit);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,D6(%rip)
  mov    D6(%rip),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int foo() {
  static int a;
  __asm__ __volatile__("xorl %%ebx, %%ebx\n"
                       "movl %%ebx, %0\n"
                       : "=m"(a)
                       :
                       : "%ebx");
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,D18(%rip)
  mov    D18(%rip),%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  static int a;
  __asm__ __volatile__("xorl %%ebx, %%ebx\n"
                       "movl %%ebx, %0\n"
                       : "=m"(a)
                       :
                       : "%ebx");
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,D11(%rip)
  mov    D11(%rip),%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  static int a;
  __asm__ __volatile__("xorl %%ebx, %%ebx\n"
                       "movl %%ebx, %0\n"
                       : "=m"(a)
                       :
                       : "%ebx");
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,D5(%rip)
  mov    D5(%rip),%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  static int a;
  __asm__ __volatile__("xorl %%ebx, %%ebx\n"
                       "movl %%ebx, %0\n"
                       : "=m"(a)
                       :
                       : "%ebx");
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <b@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  a();
  b();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <b@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  a();
  b();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  a();
  b();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  a();
  b();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L6:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0xa,-0xc(%rbp)
  jle    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string

tool: D20: Entre com o valor: 

tool: D10: %d

tool: D27: %d x %d = %d


assistant: ```c
int main(void) {
  int n, i = 0;
  printf("Entre com o valor: ");
  scanf("%d", &n);
  for (i = 0; i <= 10; i++) {
    printf("%d x %d = %d\n", n, i, n * i);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L11:
  mov    0x4(%rsp),%esi
  mov    %esi,%ecx
  imul   %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D9: Entre com o valor: 

tool: D24: %d

tool: D8: %d x %d = %d


assistant: ```c
int main(void) {
  int n, i = 0;
  printf("Entre com o valor: ");
  scanf("%d", &n);
  for (i = 0; i <= 10; i++) {
    printf("%d x %d = %d\n", n, i, n * i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
L1:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D21: Entre com o valor: 

tool: D4: %d x %d = %d


tool: D16: %d

assistant: ```c
int main(void) {
  int n, i = 0;
  printf("Entre com o valor: ");
  scanf("%d", &n);
  for (i = 0; i <= 10; i++) {
    printf("%d x %d = %d\n", n, i, n * i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
L17:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D23
type_infered: string

tool: D11: Entre com o valor: 

tool: D14: %d x %d = %d


tool: D23: %d

assistant: ```c
int main(void) {
  int n, i = 0;
  printf("Entre com o valor: ");
  scanf("%d", &n);
  for (i = 0; i <= 10; i++) {
    printf("%d x %d = %d\n", n, i, n * i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fib_rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L20
  cmpl   $0x1,-0x24(%rbp)
  jne    L6
L20:
  movl   $0x1,-0x14(%rbp)
  jmp    L18
L6:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib_rec>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib_rec>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib_rec(int n) {
  int result;
  if (n == 0 || n == 1) {
    result = 1;
  } else {
    result = fib_rec(n - 1) + fib_rec(n - 2);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fib_rec>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L6
  ret
L6:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fib_rec>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib_rec>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fib_rec(int n) {
  int result;
  if (n == 0 || n == 1) {
    result = 1;
  } else {
    result = fib_rec(n - 1) + fib_rec(n - 2);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<h2o_hex_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L27
  mov    $0xffffffff,%eax
  jmp    L45
L26:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <decode_hex@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0xffffffff,-0x10(%rbp)
  je     L12
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <decode_hex@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L0
L12:
  mov    $0xffffffff,%eax
  jmp    L45
L0:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subq   $0x2,-0x28(%rbp)
L27:
  cmpq   $0x0,-0x28(%rbp)
  jne    L26
  mov    $0x0,%eax
L45:
  leave
  ret
```

assistant: ```c
int h2o_hex_decode(void *_dst, const char *src, size_t src_len) {
  unsigned char *dst = _dst;
  if (src_len % 2 != 0)
    return -1;
  for (; src_len != 0; src_len -= 2) {
    int hi, lo;
    if ((hi = decode_hex(*src++)) == -1 || (lo = decode_hex(*src++)) == -1)
      return -1;
    *dst++ = (hi << 4) | lo;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<h2o_hex_decode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   $0x1,%dl
  jne    L45
  mov    %rdi,%r12
  test   %rdx,%rdx
  je     L75
  mov    %rsi,%r13
  lea    (%rsi,%rdx,1),%r14
L61:
  movsbl 0x0(%r13),%edi
  call   <decode_hex@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L9
  lea    0x2(%r13),%rbp
  mov    %rbp,%r13
  movsbl -0x1(%rbp),%edi
  call   <decode_hex@plt>
  cmp    $0xffffffff,%eax
  je     L15
  add    $0x1,%r12
  shl    $0x4,%ebx
  or     %eax,%ebx
  mov    %bl,-0x1(%r12)
  cmp    %rbp,%r14
  jne    L61
  mov    $0x0,%ebx
  jmp    L9
L45:
  mov    $0xffffffff,%ebx
  jmp    L9
L75:
  mov    $0x0,%ebx
  jmp    L9
L15:
  mov    %eax,%ebx
L9:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int h2o_hex_decode(void *_dst, const char *src, size_t src_len) {
  unsigned char *dst = _dst;
  if (src_len % 2 != 0)
    return -1;
  for (; src_len != 0; src_len -= 2) {
    int hi, lo;
    if ((hi = decode_hex(*src++)) == -1 || (lo = decode_hex(*src++)) == -1)
      return -1;
    *dst++ = (hi << 4) | lo;
  }
  return 0;
}
```