ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  mov    $0x10,%ebp
  cmp    $0x1,%edi
  jg     L33
L36:
  mov    $0x1,%r12d
  cmp    $0x2,%ebx
  jg     L19
L0:
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  lea    (%rbx,%rbp,1),%rax
  cmp    %rax,%rbx
  jae    L40
L49:
  movb   $0xd,(%rbx)
  add    %r12,%rbx
  cmp    %rax,%rbx
  jb     L49
L40:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    0x8(%rsi),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtoull@plt>
  mov    %rax,%rbp
  jmp    L36
L19:
  mov    0x10(%r13),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtoull@plt>
  mov    %rax,%r12
  jmp    L0
```

assistant: ```c
int main(int argc, char **argv) {
  size_t nbytes, step;
  if (argc > 1) {
    nbytes = strtoull(argv[1], NULL, 0);
  } else {
    nbytes = 0x10;
  }
  if (argc > 2) {
    step = strtoull(argv[2], NULL, 0);
  } else {
    step = 1;
  }
  char *base = malloc(nbytes);
  assert(base);
  char *i = base;
  while (i < base + nbytes) {
    *i = 13;
    i += step;
  }
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    $0x10,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jg     L39
L48:
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  lea    (%rbx,%rbp,1),%rax
  cmp    %rbx,%rax
  jbe    L23
  nopw   0x0(%rax,%rax,1)
L40:
  movb   $0xd,(%rbx)
  add    %r12,%rbx
  cmp    %rbx,%rax
  ja     L40
L23:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    %edi,%ebx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%r13
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %rax,%rbp
  cmp    $0x2,%ebx
  je     L48
  mov    0x10(%r13),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %rax,%r12
  jmp    L48
```

assistant: ```c
int main(int argc, char **argv) {
  size_t nbytes, step;
  if (argc > 1) {
    nbytes = strtoull(argv[1], NULL, 0);
  } else {
    nbytes = 0x10;
  }
  if (argc > 2) {
    step = strtoull(argv[2], NULL, 0);
  } else {
    step = 1;
  }
  char *base = malloc(nbytes);
  assert(base);
  char *i = base;
  while (i < base + nbytes) {
    *i = 13;
    i += step;
  }
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x10,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jg     L17
L44:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  lea    0x0(%rbp,%r12,1),%rax
  cmp    %rax,%rbp
  jae    L47
L10:
  mov    %r12,%rdx
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L47:
  mov    D8(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
L17:
  mov    %edi,%ebp
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %rax,%r12
  cmp    $0x2,%ebp
  je     L44
  mov    0x10(%rbx),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  lea    0x0(%rbp,%r12,1),%rax
  cmp    %rbp,%rax
  jbe    L47
  cmp    $0x1,%rbx
  je     L10
L35:
  movb   $0xd,0x0(%rbp)
  add    %rbx,%rbp
  cmp    %rbp,%rax
  jbe    L47
  movb   $0xd,0x0(%rbp)
  add    %rbx,%rbp
  cmp    %rbp,%rax
  ja     L35
  jmp    L47
```

assistant: ```c
int main(int argc, char **argv) {
  size_t nbytes, step;
  if (argc > 1) {
    nbytes = strtoull(argv[1], NULL, 0);
  } else {
    nbytes = 0x10;
  }
  if (argc > 2) {
    step = strtoull(argv[2], NULL, 0);
  } else {
    step = 1;
  }
  char *base = malloc(nbytes);
  assert(base);
  char *i = base;
  while (i < base + nbytes) {
    *i = 13;
    i += step;
  }
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readlength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x15(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  je     L6
  mov    $0xffffffff,%eax
  jmp    L0
L6:
  movzbl -0xc(%rbp),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int readlength(FILE *f) {
  char s = 0;
  unsigned char buf[4];
  int length;
  int t;
  t = fread(buf, 1, 4, f);
  if (t != 4) {
    return -1;
  }
  length = (((int)buf[0]) << 24) | (((int)buf[1]) << 16) | (((int)buf[2]) << 8) | buf[3];
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readlength>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    $0x4,%eax
  jne    L27
  movzbl 0x4(%rsp),%eax
  shl    $0x18,%eax
  movzbl 0x5(%rsp),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl 0x7(%rsp),%edx
  or     %edx,%eax
  movzbl 0x6(%rsp),%edx
  shl    $0x8,%edx
  or     %edx,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L27:
  mov    $0xffffffff,%eax
  jmp    L2
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlength(FILE *f) {
  char s = 0;
  unsigned char buf[4];
  int length;
  int t;
  t = fread(buf, 1, 4, f);
  if (t != 4) {
    return -1;
  }
  length = (((int)buf[0]) << 24) | (((int)buf[1]) << 16) | (((int)buf[2]) << 8) | buf[3];
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readlength>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  cmp    $0x4,%eax
  jne    L21
  mov    0x4(%rsp),%eax
  bswap  %eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  ret
  nop
L21:
  mov    $0xffffffff,%eax
  jmp    L28
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlength(FILE *f) {
  char s = 0;
  unsigned char buf[4];
  int length;
  int t;
  t = fread(buf, 1, 4, f);
  if (t != 4) {
    return -1;
  }
  length = (((int)buf[0]) << 24) | (((int)buf[1]) << 16) | (((int)buf[2]) << 8) | buf[3];
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readlength>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  cmp    $0x4,%eax
  jne    L13
  mov    0x4(%rsp),%eax
  bswap  %eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
  nop
L13:
  mov    $0xffffffff,%eax
  jmp    L23
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlength(FILE *f) {
  char s = 0;
  unsigned char buf[4];
  int length;
  int t;
  t = fread(buf, 1, 4, f);
  if (t != 4) {
    return -1;
  }
  length = (((int)buf[0]) << 24) | (((int)buf[1]) << 16) | (((int)buf[2]) << 8) | buf[3];
  return length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmemcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L15:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L24
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  jmp    L30
L24:
  addq   $0x8,-0x10(%rbp)
  addq   $0x8,-0x8(%rbp)
L12:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t xmemcmp(const void *a, const void *b, int len) {
  const uint8_t *pa = a;
  const uint8_t *pb = b;
  while (len--) {
    if (*pa - *pb)
      return *pa - *pb;
    ++pa;
    ++pb;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmemcmp>:
  endbr64
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  mov    $0x0,%ecx
L20:
  mov    (%rdi,%rcx,8),%rax
  mov    (%rsi,%rcx,8),%r8
  cmp    %r8,%rax
  jne    L18
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L20
  mov    $0x0,%eax
  ret
L18:
  sub    %r8,%rax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint8_t xmemcmp(const void *a, const void *b, int len) {
  const uint8_t *pa = a;
  const uint8_t *pb = b;
  while (len--) {
    if (*pa - *pb)
      return *pa - *pb;
    ++pa;
    ++pb;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmemcmp>:
  endbr64
  test   %edx,%edx
  je     L32
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L11
  xchg   %ax,%ax
L18:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L32
L11:
  mov    (%rdi,%rcx,8),%rax
  mov    (%rsi,%rcx,8),%r8
  cmp    %r8,%rax
  je     L18
  sub    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t xmemcmp(const void *a, const void *b, int len) {
  const uint8_t *pa = a;
  const uint8_t *pb = b;
  while (len--) {
    if (*pa - *pb)
      return *pa - *pb;
    ++pa;
    ++pb;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmemcmp>:
  endbr64
  test   %edx,%edx
  je     L33
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L2
  xchg   %ax,%ax
L30:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L33
L2:
  mov    (%rdi,%rcx,8),%rax
  mov    (%rsi,%rcx,8),%r8
  cmp    %r8,%rax
  je     L30
  sub    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t xmemcmp(const void *a, const void *b, int len) {
  const uint8_t *pa = a;
  const uint8_t *pb = b;
  while (len--) {
    if (*pa - *pb)
      return *pa - *pb;
    ++pa;
    ++pb;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cvt_s_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <set_rounding@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void cvt_s_l(const uint32_t *fcr31, const int64_t *source, float *dest) {
  set_rounding(fcr31);
  *dest = (float)*source;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cvt_s_l>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  call   <set_rounding@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq 0x0(%rbp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cvt_s_l(const uint32_t *fcr31, const int64_t *source, float *dest) {
  set_rounding(fcr31);
  *dest = (float)*source;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cvt_s_l>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <set_rounding@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq 0x0(%rbp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cvt_s_l(const uint32_t *fcr31, const int64_t *source, float *dest) {
  set_rounding(fcr31);
  *dest = (float)*source;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cvt_s_l>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <set_rounding@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq 0x0(%rbp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cvt_s_l(const uint32_t *fcr31, const int64_t *source, float *dest) {
  set_rounding(fcr31);
  *dest = (float)*source;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numberOfTrailingZeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L57
  mov    $0x20,%eax
  jmp    L1
L57:
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L16:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L38
  mov    -0x4(%rbp),%eax
  jmp    L1
L38:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x1e,-0x4(%rbp)
  jle    L16
  mov    $0x20,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int numberOfTrailingZeros(int a) {
  if (a == 0) {
    return 32;
  }
  int i = 0;
  for (; i < 31; i++) {
    if ((a & 1) == 1) {
      return i;
    }
    a = a >> 1;
  }
  return 32;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<numberOfTrailingZeros>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L23
  test   $0x1,%dil
  jne    L32
  sar    %edi
  mov    $0x1,%eax
L39:
  test   $0x1,%dil
  jne    L23
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1f,%eax
  jne    L39
  mov    $0x20,%eax
  ret
L32:
  mov    $0x0,%eax
  ret
L23:
  ret
```

assistant: ```c
int numberOfTrailingZeros(int a) {
  if (a == 0) {
    return 32;
  }
  int i = 0;
  for (; i < 31; i++) {
    if ((a & 1) == 1) {
      return i;
    }
    a = a >> 1;
  }
  return 32;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numberOfTrailingZeros>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L26
  xor    %eax,%eax
  jmp    L6
  nopl   0x0(%rax)
L12:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x1f,%eax
  je     L16
L6:
  test   $0x1,%dil
  je     L12
L26:
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int numberOfTrailingZeros(int a) {
  if (a == 0) {
    return 32;
  }
  int i = 0;
  for (; i < 31; i++) {
    if ((a & 1) == 1) {
      return i;
    }
    a = a >> 1;
  }
  return 32;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<numberOfTrailingZeros>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L32
  xor    %eax,%eax
  jmp    L35
  nopl   0x0(%rax)
L10:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x1f,%eax
  je     L34
L35:
  test   $0x1,%dil
  je     L10
L32:
  ret
  nopl   0x0(%rax)
L34:
  mov    $0x20,%eax
  ret
```

assistant: ```c
int numberOfTrailingZeros(int a) {
  if (a == 0) {
    return 32;
  }
  int i = 0;
  for (; i < 31; i++) {
    if ((a & 1) == 1) {
      return i;
    }
    a = a >> 1;
  }
  return 32;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_Comma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rbx
  jmp    L19
L28:
  add    $0x1,%rbx
L19:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  movzbl (%rbx),%eax
  cmp    $0x2c,%al
  jne    L26
  add    $0x1,%rbx
  jmp    L26
L42:
  add    $0x1,%rbx
L26:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
  mov    -0x18(%rbp),%rax
  mov    %rbx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void skip_Comma(char **pp) {
  register char *p;
  assert(pp != NULL);
  assert(*pp != NULL);
  p = *pp;
  while (isspace((int)*p))
    ++p;
  if (*p == ',')
    ++p;
  while (isspace((int)*p))
    ++p;
  *pp = p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skip_Comma>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%rbx
  jmp    L29
L19:
  add    $0x1,%rbx
L29:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  cmpb   $0x2c,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  jmp    L31
L20:
  add    $0x1,%rbx
L31:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_Comma(char **pp) {
  register char *p;
  assert(pp != NULL);
  assert(*pp != NULL);
  p = *pp;
  while (isspace((int)*p))
    ++p;
  if (*p == ',')
    ++p;
  while (isspace((int)*p))
    ++p;
  *pp = p;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip_Comma>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  mov    0x0(%rbp),%rbx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
L15:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  movsbl (%rbx),%edi
  cmp    $0x2c,%dil
  jne    L5
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  je     L38
  nopl   0x0(%rax)
L42:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L5:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
L38:
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_Comma(char **pp) {
  register char *p;
  assert(pp != NULL);
  assert(*pp != NULL);
  p = *pp;
  while (isspace((int)*p))
    ++p;
  if (*p == ',')
    ++p;
  while (isspace((int)*p))
    ++p;
  *pp = p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_Comma>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  mov    0x0(%rbp),%rbx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
L28:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  xor    %eax,%eax
  cmpb   $0x2c,(%rbx)
  sete   %al
  add    %rax,%rbx
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L33:
  add    $0x1,%rbx
L18:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L33
  mov    %rbx,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void skip_Comma(char **pp) {
  register char *p;
  assert(pp != NULL);
  assert(*pp != NULL);
  p = *pp;
  while (isspace((int)*p))
    ++p;
  if (*p == ',')
    ++p;
  while (isspace((int)*p))
    ++p;
  *pp = p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_search_v2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L10
  mov    $0xffffffff,%eax
  jmp    L59
L10:
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L99
L67:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L114
  mov    -0x4(%rbp),%eax
  jmp    L59
L114:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L44
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L99
L44:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L99:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L67
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L62
  mov    -0xc(%rbp),%eax
  jmp    L59
L62:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L29
  mov    -0x8(%rbp),%eax
  jmp    L59
L29:
  mov    $0xffffffff,%eax
L59:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search_v2(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low + 1 < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid;
    } else {
      high = mid;
    }
  }
  if (nums[low] == target) {
    return low;
  }
  if (nums[high] == target) {
    return high;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary_search_v2>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  jle    L14
  sub    $0x1,%esi
  mov    $0x0,%ecx
L20:
  lea    0x1(%rcx),%eax
  cmp    %eax,%esi
  jle    L27
  mov    %esi,%edi
  sub    %ecx,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %edx,%edi
  je     L32
  cmovge %eax,%esi
  cmovl  %eax,%ecx
  jmp    L20
L27:
  movslq %ecx,%rdi
  mov    %ecx,%eax
  cmp    %edx,(%r8,%rdi,4)
  je     L32
  movslq %esi,%rax
  cmp    %edx,(%r8,%rax,4)
  mov    $0xffffffff,%eax
  cmove  %esi,%eax
  ret
L14:
  mov    $0xffffffff,%eax
L32:
  ret
```

assistant: ```c
int binary_search_v2(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low + 1 < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid;
    } else {
      high = mid;
    }
  }
  if (nums[low] == target) {
    return low;
  }
  if (nums[high] == target) {
    return high;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<binary_search_v2>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L3
  sub    $0x1,%esi
  xor    %ecx,%ecx
  mov    $0x1,%r8d
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %esi,%edi
  sub    %ecx,%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%rdi
  cmp    %edx,(%r9,%rdi,4)
  je     L57
  jge    L28
  mov    %eax,%ecx
  lea    0x1(%rax),%r8d
L44:
  cmp    %r8d,%esi
  jg     L18
  movslq %ecx,%rdi
  mov    %ecx,%eax
  cmp    %edx,(%r9,%rdi,4)
  je     L57
  movslq %esi,%rax
  cmp    %edx,(%r9,%rax,4)
  mov    $0xffffffff,%eax
  cmove  %esi,%eax
  ret
L3:
  mov    $0xffffffff,%eax
L57:
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %eax,%esi
  jmp    L44
```

assistant: ```c
int binary_search_v2(int *nums, int nums_size, int target) {
  if (nums_size < 1) {
    return -1;
  }
  int low = 0, high = nums_size - 1, mid;
  while (low + 1 < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] == target) {
      return mid;
    } else if (nums[mid] < target) {
      low = mid;
    } else {
      high = mid;
    }
  }
  if (nums[low] == target) {
    return low;
  }
  if (nums[high] == target) {
    return high;
  }
  return -1;
}
```