ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<settz>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  test   %esi,%esi
  je     L3
  mov    $0x2d,%edx
  js     L27
L2:
  mov    %dl,0x18(%rcx)
  mov    %eax,%edx
  mov    $0xcccccccd,%r8d
  imul   $0x1b4e81b5,%rdx,%rsi
  shr    $0x26,%rsi
  add    $0x30,%esi
  mov    %sil,0x19(%rcx)
  mov    $0x88888889,%esi
  imul   %rsi,%rdx
  shr    $0x25,%rdx
  mov    %edx,%esi
  imul   %r8,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%edi
  mov    %edx,%esi
  imul   $0x3c,%edx,%edx
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  sub    %edx,%eax
  mov    %sil,0x1a(%rcx)
  mov    %eax,%edx
  imul   %r8,%rdx
  shr    $0x23,%rdx
  lea    0x30(%rdx),%esi
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %sil,0x1b(%rcx)
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,0x1c(%rcx)
  ret
L27:
  neg    %eax
  mov    $0x2b,%edx
  jmp    L2
  nopl   0x0(%rax)
L3:
  movl   $0x544d47,0x18(%rdi)
  ret
```

assistant: ```c
settz(b, tz) register char *b;
register tz;
{
  if (tz == 0) {
    strcpy(b + 24, "GMT");
    return;
  }
  if (tz < 0) {
    b[24] = '+';
    tz = -tz;
  } else
    b[24] = '-';
  b[25] = tz / 60 / 10 + '0';
  b[26] = tz / 60 % 10 + '0';
  tz %= 60;
  b[27] = tz / 10 + '0';
  b[28] = tz % 10 + '0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D16(%rip),%r13
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  cmpl   $0x0,0x4(%rsp)
  jg     L7
L63:
  sub    %r10d,%r9d
  mov    %r9d,%esi
  neg    %esi
  cmovs  %r9d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L107:
  imul   %ebp,%eax
  cltq
  add    %rbx,%rax
  lea    (%r12,%rax,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L107
L134:
  add    $0x1,%ebp
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jle    L159
L7:
  mov    0x4(%rsp),%eax
  mov    $0x0,%ebx
  test   %eax,%eax
  jg     L107
  jmp    L134
L159:
  test   %edi,%edi
  jle    L154
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  lea    -0x1(%rdi),%r8d
  jmp    L27
L74:
  add    (%rdx),%r9d
  jmp    L4
L53:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%edi
  je     L72
L117:
  cmp    %eax,%ecx
  je     L74
L4:
  lea    (%rax,%rcx,1),%esi
  cmp    %esi,%r8d
  jne    L53
  add    (%rdx),%r10d
  jmp    L53
L72:
  add    $0x1,%ecx
  add    %edi,%r11d
  cmp    %ecx,%edi
  je     L63
L27:
  movslq %r11d,%rax
  lea    (%r12,%rax,4),%rdx
  mov    $0x0,%eax
  jmp    L117
L154:
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  jmp    L63
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string

tool: D16: %d

assistant: ```c
int main() {
  int n, i, j;
  int leftdiagonalSum = 0, rightDiagonalSum = 0, diff = 0;
  scanf("%d", &n);
  int *arr = (int *)malloc(n * n * sizeof(int));
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", (arr + i * n + j));
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (i == j) {
        leftdiagonalSum += *(arr + i * n + j);
      }
      if (i + j == (n - 1)) {
        rightDiagonalSum += *(arr + i * n + j);
      }
    }
  }
  diff = leftdiagonalSum - rightDiagonalSum;
  diff = (diff < 0) ? (-1) * diff : diff;
  printf("%d", diff);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L128
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L59:
  imul   %ebp,%eax
  mov    %r13,%rdi
  cltq
  add    %r12,%rax
  add    $0x1,%r12
  lea    (%rbx,%rax,4),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jg     L59
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jle    L107
  test   %eax,%eax
  jg     L3
L128:
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L105:
  sub    %r10d,%r9d
  mov    %r13,%rdi
  mov    %r9d,%esi
  neg    %esi
  cmovs  %r9d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
L107:
  test   %eax,%eax
  jle    L128
  lea    -0x1(%rax),%r8d
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  xor    %esi,%esi
  nopl   0x0(%rax)
L25:
  movslq %r11d,%rdx
  lea    (%rbx,%rdx,4),%rcx
  xor    %edx,%edx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L130:
  lea    (%rdx,%rsi,1),%edi
  cmp    %r8d,%edi
  je     L61
L1:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%eax
  je     L120
L30:
  cmp    %edx,%esi
  jne    L130
  lea    (%rdx,%rsi,1),%edi
  add    (%rcx),%r9d
  cmp    %r8d,%edi
  jne    L1
L61:
  add    $0x1,%edx
  add    (%rcx),%r10d
  add    $0x4,%rcx
  cmp    %edx,%eax
  jne    L30
L120:
  add    $0x1,%esi
  add    %eax,%r11d
  cmp    %esi,%eax
  jne    L25
  jmp    L105
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int n, i, j;
  int leftdiagonalSum = 0, rightDiagonalSum = 0, diff = 0;
  scanf("%d", &n);
  int *arr = (int *)malloc(n * n * sizeof(int));
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", (arr + i * n + j));
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (i == j) {
        leftdiagonalSum += *(arr + i * n + j);
      }
      if (i + j == (n - 1)) {
        rightDiagonalSum += *(arr + i * n + j);
      }
    }
  }
  diff = leftdiagonalSum - rightDiagonalSum;
  diff = (diff < 0) ? (-1) * diff : diff;
  printf("%d", diff);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  nopw   0x0(%rax,%rax,1)
L90:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L139:
  imul   %ebp,%eax
  mov    %r13,%rdi
  cltq
  add    %r12,%rax
  add    $0x1,%r12
  lea    (%rbx,%rax,4),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jg     L139
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jle    L86
  test   %eax,%eax
  jg     L90
L15:
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L68:
  sub    %r10d,%r9d
  mov    %r13,%rdi
  mov    %r9d,%esi
  neg    %esi
  cmovs  %r9d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L82:
  call   <__stack_chk_fail@plt>
L86:
  test   %eax,%eax
  jle    L15
  lea    -0x1(%rax),%r8d
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  xor    %esi,%esi
  nopl   0x0(%rax)
L66:
  movslq %r11d,%rdx
  lea    (%rbx,%rdx,4),%rcx
  xor    %edx,%edx
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L81:
  lea    (%rsi,%rdx,1),%edi
  cmp    %r8d,%edi
  je     L105
L112:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%eax
  je     L104
L51:
  cmp    %edx,%esi
  jne    L81
  lea    (%rsi,%rdx,1),%edi
  add    (%rcx),%r9d
  cmp    %r8d,%edi
  jne    L112
L105:
  add    $0x1,%edx
  add    (%rcx),%r10d
  add    $0x4,%rcx
  cmp    %edx,%eax
  jne    L51
L104:
  add    $0x1,%esi
  add    %eax,%r11d
  cmp    %esi,%eax
  jne    L66
  jmp    L68
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int n, i, j;
  int leftdiagonalSum = 0, rightDiagonalSum = 0, diff = 0;
  scanf("%d", &n);
  int *arr = (int *)malloc(n * n * sizeof(int));
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%d", (arr + i * n + j));
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (i == j) {
        leftdiagonalSum += *(arr + i * n + j);
      }
      if (i + j == (n - 1)) {
        rightDiagonalSum += *(arr + i * n + j);
      }
    }
  }
  diff = leftdiagonalSum - rightDiagonalSum;
  diff = (diff < 0) ? (-1) * diff : diff;
  printf("%d", diff);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <SSIBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <SSIIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  DEBUG_ASSERT(SSIBaseValid(ulBase));
  ulInt = SSIIntNumberGet(ulBase);
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SSIIntRegister>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <SSIBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,%rdi
  call   <SSIIntNumberGet@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <IntRegister@plt>
  mov    %rbx,%rdi
  call   <IntEnable@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  DEBUG_ASSERT(SSIBaseValid(ulBase));
  ulInt = SSIIntNumberGet(ulBase);
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: What is the c source code of the assembly code below:

```asm
<SSIIntRegister>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <SSIBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rdi
  call   <SSIIntNumberGet@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <IntRegister@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  DEBUG_ASSERT(SSIBaseValid(ulBase));
  ulInt = SSIIntNumberGet(ulBase);
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SSIIntRegister>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <SSIBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rdi
  call   <SSIIntNumberGet@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <IntRegister@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <IntEnable@plt>
```

assistant: ```c
void SSIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  unsigned long ulInt;
  DEBUG_ASSERT(SSIBaseValid(ulBase));
  ulInt = SSIIntNumberGet(ulBase);
  IntRegister(ulInt, pfnHandler);
  IntEnable(ulInt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <longjmp@plt>
L7:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <func2@plt>
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int func3(jmp_buf *env, int x) {
  if (x == 0)
    longjmp(*env, 3);
  return func2(env, x - 1) + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<func3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %esi,%esi
  je     L8
L1:
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <func2@plt>
  add    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x3,%esi
  mov    (%rdi),%edi
  call   <longjmp@plt>
  jmp    L1
```

assistant: ```c
int func3(jmp_buf *env, int x) {
  if (x == 0)
    longjmp(*env, 3);
  return func2(env, x - 1) + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L10
L9:
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <func2@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rdi),%edi
  mov    $0x3,%esi
  call   <longjmp@plt>
  jmp    L9
```

assistant: ```c
int func3(jmp_buf *env, int x) {
  if (x == 0)
    longjmp(*env, 3);
  return func2(env, x - 1) + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func3>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L10
L11:
  lea    -0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <func2@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rdi),%edi
  mov    $0x3,%esi
  call   <longjmp@plt>
  jmp    L11
```

assistant: ```c
int func3(jmp_buf *env, int x) {
  if (x == 0)
    longjmp(*env, 3);
  return func2(env, x - 1) + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetEventFlag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x600000,%eax
  shl    $0x2,%eax
  cltq
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  and    -0x8(%rbp),%rax
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L11
L12:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int GetEventFlag(int efnum) {
  int indx;
  int num;
  unsigned long tmp;
  indx = efnum % 32;
  num = efnum / 32;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)((0x01800000 + (num * 4))));
    __v;
  });
  if (tmp & (1 << indx))
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GetEventFlag>:
  endbr64
  mov    %edi,%ecx
  lea    0x1f(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x1800000(,%rax,4),%eax
  cltq
  mov    (%rax),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  test   %rdx,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int GetEventFlag(int efnum) {
  int indx;
  int num;
  unsigned long tmp;
  indx = efnum % 32;
  num = efnum / 32;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)((0x01800000 + (num * 4))));
    __v;
  });
  if (tmp & (1 << indx))
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetEventFlag>:
  endbr64
  test   %edi,%edi
  lea    0x1f(%rdi),%eax
  mov    %edi,%ecx
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x1800000(,%rax,4),%eax
  cltq
  mov    (%rax),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  test   %rdx,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int GetEventFlag(int efnum) {
  int indx;
  int num;
  unsigned long tmp;
  indx = efnum % 32;
  num = efnum / 32;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)((0x01800000 + (num * 4))));
    __v;
  });
  if (tmp & (1 << indx))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GetEventFlag>:
  endbr64
  test   %edi,%edi
  lea    0x1f(%rdi),%eax
  mov    %edi,%ecx
  cmovns %edi,%eax
  sar    $0x5,%eax
  lea    0x1800000(,%rax,4),%eax
  cltq
  mov    (%rax),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  test   %rdx,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int GetEventFlag(int efnum) {
  int indx;
  int num;
  unsigned long tmp;
  indx = efnum % 32;
  num = efnum / 32;
  tmp = ({
    unsigned long __v = (*(volatile unsigned long *)((0x01800000 + (num * 4))));
    __v;
  });
  if (tmp & (1 << indx))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<random_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  sub    -0x4(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int random_number(int a, int b) {
  b++;
  return rand() % (b - a) + a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<random_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  sub    %ebp,%esi
  cltd
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int random_number(int a, int b) {
  b++;
  return rand() % (b - a) + a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<random_number>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  sub    %ebp,%esi
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int random_number(int a, int b) {
  b++;
  return rand() % (b - a) + a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<random_number>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  sub    %ebp,%esi
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int random_number(int a, int b) {
  b++;
  return rand() % (b - a) + a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mp_invisqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L9
  mov    $0xffffffff,%eax
  jmp    L66
L9:
  mov    -0x18(%rbp),%eax
  mov    0x10(%rbp),%esi
  mov    %eax,%edi
  call   <mp_get_nfft_init@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L62
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L62:
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <mp_invisqrt_init@plt>
  movl   $0x8,-0x8(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L68
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L68:
  mov    -0x38(%rbp),%r9
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x10(%rbp),%eax
  sub    $0x8,%rsp
  push   0x30(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  mov    -0xc(%rbp),%edi
  push   %rdi
  mov    %eax,%edi
  call   <mp_invisqrt_newton@plt>
  add    $0x30,%rsp
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cmp    %eax,0x10(%rbp)
  jg     L29
  movl   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,%edx
  jle    L27
  sarl   -0xc(%rbp)
  jmp    L27
L29:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,%edx
  jge    L27
  sarl   -0xc(%rbp)
L27:
  shll   -0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jle    L15
  mov    $0x0,%eax
L66:
  leave
  ret
```

assistant: ```c
int mp_invisqrt(int n, int radix, int in, int out[], int tmp1[], int tmp2[], int nfft, double tmp1fft[], double tmp2fft[], int ip[], double w[]) {
  int mp_get_nfft_init(int radix, int nfft_max);
  void mp_invisqrt_init(int n, int radix, int in, int out[]);
  int mp_invisqrt_newton(int n, int radix, int in, int inout[], int tmp1[], int tmp2[], int nfft, double tmp1fft[], double tmp2fft[], int ip[], double w[]);
  int n_nwt, nfft_nwt, thr, prc;
  if (in <= 0) {
    return -1;
  }
  nfft_nwt = mp_get_nfft_init(radix, nfft);
  n_nwt = nfft_nwt + 2;
  if (n_nwt > n) {
    n_nwt = n;
  }
  mp_invisqrt_init(n_nwt, radix, in, out);
  thr = 8;
  do {
    n_nwt = nfft_nwt + 2;
    if (n_nwt > n) {
      n_nwt = n;
    }
    prc = mp_invisqrt_newton(n_nwt, radix, in, out, tmp1, tmp2, nfft_nwt, tmp1fft, tmp2fft, ip, w);
    if (thr * nfft_nwt >= nfft) {
      thr = 0;
      if (2 * prc <= n_nwt - 2) {
        nfft_nwt >>= 1;
      }
    } else {
      if (3 * prc < n_nwt - 2) {
        nfft_nwt >>= 1;
      }
    }
    nfft_nwt <<= 1;
  } while (nfft_nwt <= nfft);
  return 0;
}
```