ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<htoi>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  movzbl (%rdi),%r13d
  cmp    $0x2d,%r13b
  sete   %al
  movzbl %al,%eax
  mov    %rax,0x8(%rsp)
  cmpb   $0x30,(%rdi,%rax,1)
  je     L117
L97:
  test   %r13b,%r13b
  je     L125
  mov    $0x0,%r12d
L99:
  add    $0x1,%r12
  movzbl (%r14,%r12,1),%r15d
  test   %r15b,%r15b
  jne    L99
  cmp    %r12,0x8(%rsp)
  jae    L15
  mov    %r12,%rbp
  mov    %r15d,%r13d
  jmp    L19
L117:
  mov    %rax,%rcx
  movzbl 0x1(%rdi,%rax,1),%eax
  and    $0xffffffdf,%eax
  lea    0x2(%rcx),%rdx
  cmp    $0x58,%al
  cmovne %rcx,%rdx
  mov    %rdx,0x8(%rsp)
  jmp    L97
L37:
  mov    $0x10,%edi
  call   <pow@plt>
  movsbl %bl,%ebx
  sub    $0x30,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
  jmp    L63
L16:
  mov    $0x10,%edi
  call   <pow@plt>
  movsbl %bl,%ebx
  sub    $0x57,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
  jmp    L63
L31:
  mov    $0x10,%edi
  call   <pow@plt>
  movsbl %bl,%ebx
  sub    $0x37,%ebx
  imul   %eax,%ebx
  add    %ebx,%r13d
L63:
  cmp    0x8(%rsp),%rbp
  jbe    L22
L19:
  mov    %r12,%rsi
  sub    %rbp,%rsi
  sub    $0x1,%rbp
  movzbl (%r14,%rbp,1),%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  jbe    L37
  lea    -0x61(%rbx),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x41(%rbx),%eax
  cmp    $0x5,%al
  jbe    L31
  mov    %r15d,%r13d
  jmp    L125
L15:
  mov    %r15d,%r13d
L22:
  mov    %r13d,%eax
  neg    %eax
  cmpb   $0x2d,(%r14)
  cmove  %eax,%r13d
L125:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int32_t htoi(char *string) {
  int32_t value = 0;
  uint32_t start_position = string[0] == '-' ? 1 : 0;
  if (string[start_position] == '0' && (string[start_position + 1] == 'x' || string[start_position + 1] == 'X')) {
    start_position += 2;
  }
  uint32_t i = 0;
  for (; string[i] != '\0'; i++)
    ;
  for (uint32_t j = 0; i > start_position; i--, j++) {
    if (string[i - 1] >= '0' && string[i - 1] <= '9') {
      value += (string[i - 1] - '0') * (int)pow(16, j);
    } else if (string[i - 1] >= 'a' && string[i - 1] <= 'f') {
      value += ((string[i - 1] - 'a') + 10) * (int)pow(16, j);
    } else if (string[i - 1] >= 'A' && string[i - 1] <= 'F') {
      value += ((string[i - 1] - 'A') + 10) * (int)pow(16, j);
    } else {
      return 0;
    }
  }
  return string[0] == '-' ? -(value) : value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<htoi>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%r15d
  cmp    $0x2d,%r15b
  sete   %al
  cmpb   $0x30,(%rdi,%rax,1)
  mov    %rax,0x8(%rsp)
  jne    L75
  mov    %rax,%rdx
  movzbl 0x1(%rdi,%rax,1),%eax
  lea    0x2(%rdx),%rcx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  cmovne %rdx,%rcx
  mov    %rcx,0x8(%rsp)
L75:
  test   %r15b,%r15b
  je     L113
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%r13
  cmpb   $0x0,0x0(%rbp,%r13,1)
  jne    L56
  cmp    %r13,0x8(%rsp)
  jae    L103
  mov    %r13,%r12
  xor    %r15d,%r15d
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L50:
  lea    -0x61(%rbx),%eax
  cmp    $0x5,%al
  jbe    L112
  lea    -0x41(%rbx),%eax
  cmp    $0x5,%al
  ja     L129
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  lea    -0x37(%rbx),%eax
  imul   %r8d,%eax
  add    %eax,%r15d
L124:
  cmp    0x8(%rsp),%r12
  jbe    L17
L89:
  mov    %r13,%rsi
  sub    %r12,%rsi
  sub    $0x1,%r12
  movzbl 0x0(%rbp,%r12,1),%ebx
  lea    -0x30(%rbx),%r14d
  cmp    $0x9,%r14b
  ja     L50
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14d,%eax
  imul   %r8d,%eax
  add    %eax,%r15d
  cmp    0x8(%rsp),%r12
  ja     L89
L17:
  movzbl 0x0(%rbp),%eax
L43:
  mov    %r15d,%edx
  neg    %edx
  cmp    $0x2d,%al
  cmove  %edx,%r15d
L113:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L112:
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  lea    -0x57(%rbx),%eax
  imul   %r8d,%eax
  add    %eax,%r15d
  jmp    L124
  nopl   0x0(%rax)
L129:
  xor    %r15d,%r15d
  jmp    L113
L103:
  mov    %r15d,%eax
  xor    %r15d,%r15d
  jmp    L43
```

assistant: ```c
int32_t htoi(char *string) {
  int32_t value = 0;
  uint32_t start_position = string[0] == '-' ? 1 : 0;
  if (string[start_position] == '0' && (string[start_position + 1] == 'x' || string[start_position + 1] == 'X')) {
    start_position += 2;
  }
  uint32_t i = 0;
  for (; string[i] != '\0'; i++)
    ;
  for (uint32_t j = 0; i > start_position; i--, j++) {
    if (string[i - 1] >= '0' && string[i - 1] <= '9') {
      value += (string[i - 1] - '0') * (int)pow(16, j);
    } else if (string[i - 1] >= 'a' && string[i - 1] <= 'f') {
      value += ((string[i - 1] - 'a') + 10) * (int)pow(16, j);
    } else if (string[i - 1] >= 'A' && string[i - 1] <= 'F') {
      value += ((string[i - 1] - 'A') + 10) * (int)pow(16, j);
    } else {
      return 0;
    }
  }
  return string[0] == '-' ? -(value) : value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<htoi>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%r15d
  cmp    $0x2d,%r15b
  sete   %al
  cmpb   $0x30,(%rdi,%rax,1)
  mov    %rax,0x8(%rsp)
  jne    L72
  mov    %rax,%rdx
  movzbl 0x1(%rdi,%rax,1),%eax
  lea    0x2(%rdx),%rcx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  cmovne %rdx,%rcx
  mov    %rcx,0x8(%rsp)
L72:
  test   %r15b,%r15b
  je     L97
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%r13
  cmpb   $0x0,0x0(%rbp,%r13,1)
  jne    L40
  cmp    %r13,0x8(%rsp)
  jae    L55
  mov    %r13,%r12
  xor    %r15d,%r15d
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L68:
  lea    -0x61(%rbx),%eax
  cmp    $0x5,%al
  jbe    L96
  lea    -0x41(%rbx),%eax
  cmp    $0x5,%al
  ja     L64
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  lea    -0x37(%rbx),%eax
  imul   %r8d,%eax
  add    %eax,%r15d
L109:
  cmp    0x8(%rsp),%r12
  jbe    L27
L70:
  mov    %r13,%rsi
  sub    %r12,%rsi
  sub    $0x1,%r12
  movzbl 0x0(%rbp,%r12,1),%ebx
  lea    -0x30(%rbx),%r14d
  cmp    $0x9,%r14b
  ja     L68
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %r14d,%eax
  imul   %r8d,%eax
  add    %eax,%r15d
  cmp    0x8(%rsp),%r12
  ja     L70
L27:
  movzbl 0x0(%rbp),%eax
L83:
  mov    %r15d,%edx
  neg    %edx
  cmp    $0x2d,%al
  cmove  %edx,%r15d
L97:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L96:
  mov    $0x10,%edi
  call   <pow@plt>
  mov    %rax,%r8
  lea    -0x57(%rbx),%eax
  imul   %r8d,%eax
  add    %eax,%r15d
  jmp    L109
  nopl   0x0(%rax)
L64:
  xor    %r15d,%r15d
  jmp    L97
L55:
  mov    %r15d,%eax
  xor    %r15d,%r15d
  jmp    L83
```

assistant: ```c
int32_t htoi(char *string) {
  int32_t value = 0;
  uint32_t start_position = string[0] == '-' ? 1 : 0;
  if (string[start_position] == '0' && (string[start_position + 1] == 'x' || string[start_position + 1] == 'X')) {
    start_position += 2;
  }
  uint32_t i = 0;
  for (; string[i] != '\0'; i++)
    ;
  for (uint32_t j = 0; i > start_position; i--, j++) {
    if (string[i - 1] >= '0' && string[i - 1] <= '9') {
      value += (string[i - 1] - '0') * (int)pow(16, j);
    } else if (string[i - 1] >= 'a' && string[i - 1] <= 'f') {
      value += ((string[i - 1] - 'a') + 10) * (int)pow(16, j);
    } else if (string[i - 1] >= 'A' && string[i - 1] <= 'F') {
      value += ((string[i - 1] - 'A') + 10) * (int)pow(16, j);
    } else {
      return 0;
    }
  }
  return string[0] == '-' ? -(value) : value;
}
```
user: What is the c source code of the assembly code below:

```asm
<calculate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L8:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L29
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L15
L29:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L15:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calculate(int n) {
  int sum = 0;
  for (int i = 1; i <= n; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculate>:
  endbr64
  test   %edi,%edi
  jle    L26
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x0,%esi
  jmp    L25
L50:
  add    %edx,%esi
L15:
  add    $0x1,%edx
  cmp    %edi,%edx
  je     L49
L25:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  je     L50
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%edx
  jne    L15
  jmp    L50
L26:
  mov    $0x0,%esi
L49:
  mov    %esi,%eax
  ret
```

assistant: ```c
int calculate(int n) {
  int sum = 0;
  for (int i = 1; i <= n; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculate>:
  endbr64
  test   %edi,%edi
  jle    L35
  add    $0x1,%edi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L34:
  imul   $0xaaaaaaab,%eax,%edx
  cmp    $0x55555555,%edx
  jbe    L25
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  ja     L2
L25:
  add    %eax,%r8d
L2:
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L34
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculate(int n) {
  int sum = 0;
  for (int i = 1; i <= n; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      sum += i;
    }
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lstGlue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L53
L23:
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L50
L72:
  cmpq   $0x0,-0x20(%rbp)
  je     L58
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L41
L58:
  mov    $0x0,%eax
L41:
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L53
L43:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  addq   $0x1,-0x18(%rbp)
L50:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L72
  mov    -0x20(%rbp),%rax
L53:
  leave
  ret
```

assistant: ```c
char *lstGlue(char **lst) {
  if (lst == NULL) {
    return NULL;
  }
  char *rval = NULL;
  size_t i = 0;
  while (lst[i]) {
    size_t rlen = rval ? strlen(rval) : 0;
    char *t = realloc(rval, rlen + strlen(lst[i]) + 1);
    if (t == NULL) {
      free(rval);
      errno = ENOMEM;
      return NULL;
    }
    rval = t;
    strcpy(rval + rlen, lst[i]);
    i++;
  }
  return rval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lstGlue>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L64
  mov    (%rdi),%rbp
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  mov    %rbp,%rbx
  test   %rbp,%rbp
  jne    L57
  jmp    L17
L19:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%r14
L57:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rsi
  mov    %r14,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L68
  lea    (%rax,%r12,1),%rdi
  mov    0x0(%r13),%rsi
  call   <strcpy@plt>
  add    $0x8,%r13
  mov    0x0(%r13),%rbp
  test   %rbp,%rbp
  jne    L19
  jmp    L17
L68:
  mov    %r14,%rdi
  call   <free@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
L17:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  mov    %rdi,%rbx
  jmp    L17
```

assistant: ```c
char *lstGlue(char **lst) {
  if (lst == NULL) {
    return NULL;
  }
  char *rval = NULL;
  size_t i = 0;
  while (lst[i]) {
    size_t rlen = rval ? strlen(rval) : 0;
    char *t = realloc(rval, rlen + strlen(lst[i]) + 1);
    if (t == NULL) {
      free(rval);
      errno = ENOMEM;
      return NULL;
    }
    rval = t;
    strcpy(rval + rlen, lst[i]);
    i++;
  }
  return rval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lstGlue>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L25
  mov    (%rdi),%r13
  mov    %rdi,%rbp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  test   %r13,%r13
  jne    L27
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x0(%rbp),%rsi
  lea    (%rax,%rbx,1),%rdi
  add    $0x8,%rbp
  call   <strcpy@plt>
  mov    0x0(%rbp),%r13
  test   %r13,%r13
  je     L18
  mov    %r12,%rdi
  mov    %r12,%r14
  call   <strlen@plt>
  mov    %rax,%rbx
L27:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L21
  mov    %r14,%rdi
  call   <free@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
L18:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *lstGlue(char **lst) {
  if (lst == NULL) {
    return NULL;
  }
  char *rval = NULL;
  size_t i = 0;
  while (lst[i]) {
    size_t rlen = rval ? strlen(rval) : 0;
    char *t = realloc(rval, rlen + strlen(lst[i]) + 1);
    if (t == NULL) {
      free(rval);
      errno = ENOMEM;
      return NULL;
    }
    rval = t;
    strcpy(rval + rlen, lst[i]);
    i++;
  }
  return rval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lstGlue>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L1
  mov    (%rdi),%r13
  mov    %rdi,%rbp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  test   %r13,%r13
  jne    L34
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x0(%rbp),%rsi
  lea    (%rax,%rbx,1),%rdi
  add    $0x8,%rbp
  call   <strcpy@plt>
  mov    0x0(%rbp),%r13
  test   %r13,%r13
  je     L42
  mov    %r12,%rdi
  mov    %r12,%r14
  call   <strlen@plt>
  mov    %rax,%rbx
L34:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L17
  mov    %r14,%rdi
  call   <free@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
L42:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *lstGlue(char **lst) {
  if (lst == NULL) {
    return NULL;
  }
  char *rval = NULL;
  size_t i = 0;
  while (lst[i]) {
    size_t rlen = rval ? strlen(rval) : 0;
    char *t = realloc(rval, rlen + strlen(lst[i]) + 1);
    if (t == NULL) {
      free(rval);
      errno = ENOMEM;
      return NULL;
    }
    rval = t;
    strcpy(rval + rlen, lst[i]);
    i++;
  }
  return rval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L22
L14:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D13
type_infered: string

tool: D3: 	%.2f


tool: D13: %1f

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%1f", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D10(%rip),%rbx
  mov    %rsp,%r12
  lea    D22(%rip),%rbp
  lea    D29(%rip),%r13
  jmp    L7
L5:
  movq   %rbx,%xmm1
  addsd  (%rsp),%xmm1
  movq   %xmm1,%rbx
  movapd %xmm1,%xmm0
  mov    %r13,%rdi
  call   <printf@plt>
L7:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D22
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D22: %1f

tool: D29: 	%.2f


assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%1f", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm2,%xmm2
  push   %r12
  movq   %xmm2,%r14
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L0:
  movq   %r14,%xmm1
  addsd  (%rsp),%xmm1
  mov    %r12,%rdi
  movapd %xmm1,%xmm0
  movq   %xmm1,%r14
  call   <printf@plt>
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D1: 	%.2f


tool: D15: %1f

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%1f", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm2,%xmm2
  push   %r12
  movq   %xmm2,%r14
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L19:
  movq   %r14,%xmm1
  addsd  (%rsp),%xmm1
  mov    %r12,%rdi
  movapd %xmm1,%xmm0
  movq   %xmm1,%r14
  call   <printf@plt>
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D5: 	%.2f


tool: D14: %1f

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%1f", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flush_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L14
  cmpl   $0xa,-0x4(%rbp)
  jne    L3
L14:
  nop
  leave
  ret
```

assistant: ```c
void flush_input(FILE *in) {
  int c;
  while (((c = getc(in)) != EOF) && (c != '\n'))
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<flush_input>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L19:
  mov    %rbx,%rdi
  call   <getc@plt>
  mov    D2(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L5
  cmp    $0xa,%eax
  jne    L19
L5:
  pop    %rbx
  ret
```

assistant: ```c
void flush_input(FILE *in) {
  int c;
  while (((c = getc(in)) != EOF) && (c != '\n'))
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<flush_input>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L18:
  cmp    $0xa,%eax
  je     L20
L4:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L18
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void flush_input(FILE *in) {
  int c;
  while (((c = getc(in)) != EOF) && (c != '\n'))
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<flush_input>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbp
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    $0xa,%eax
  je     L23
L26:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L11
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void flush_input(FILE *in) {
  int c;
  while (((c = getc(in)) != EOF) && (c != '\n'))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    -0x8(%rbp),%rax
  mov    %rax,%rcx
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    $0x0,%eax
  call   <pthread_testcancel@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: thread %ld %d %p


assistant: ```c
void *thread(void *arg) {
  printf("thread %ld %d %p\n", (long)arg, getpid(), &arg);
  while (1) {
    pthread_testcancel();
    sleep(1);
  }
}
```