ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<metersToFeetAndInches>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mulsd  D36(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <floor@plt>
  test   %r12,%r12
  movsd  (%rsp),%xmm1
  mov    %rax,%rbx
  je     L1
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %r12,%rsi
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %rax,%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  mov    %ebx,(%r12)
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
L17:
  test   %rbp,%rbp
  je     L23
  subsd  %xmm0,%xmm1
  mulsd  D27(%rip),%xmm1
  mov    %rbp,%rsi
  mov    $0x1,%eax
  lea    D12(%rip),%rdi
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm1,0x0(%rbp)
L23:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: tag: D36
type_infered: f64
name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: f64
name: retrieve_data
arguments: tag: D12
type_infered: string

tool: D36: 3.281

tool: D3: Storeing %u to the address %p


tool: D27: 12

tool: D12: Storing %.2f to the address %p


assistant: ```c
void metersToFeetAndInches(double meters, unsigned int *ftPtr, double *inPtr) {
  double rawFeet = meters * 3.281;
  unsigned int feet = (unsigned int)floor(rawFeet);
  if (ftPtr) {
    printf("Storeing %u to the address %p\n", feet, ftPtr);
    *ftPtr = feet;
  }
  double fractionalFoot = rawFeet - feet;
  double inches = fractionalFoot * 12.0;
  if (inPtr) {
    printf("Storing %.2f to the address %p\n", inches, inPtr);
    *inPtr = inches;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<metersToFeetAndInches>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mulsd  D33(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  call   <floor@plt>
  test   %r12,%r12
  movsd  (%rsp),%xmm1
  mov    %rax,%rbx
  je     L26
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %r12,%rsi
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %rax,%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  mov    %ebx,(%r12)
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
L19:
  test   %rbp,%rbp
  je     L22
  subsd  %xmm0,%xmm1
  mulsd  D14(%rip),%xmm1
  mov    %rbp,%rsi
  mov    $0x1,%eax
  lea    D22(%rip),%rdi
  movapd %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm1,0x0(%rbp)
L22:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  jmp    L19
```

tool_calls: name: unpack_data
arguments: tag: D33
datatype: f64
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D14
datatype: f64
name: unpack_data
arguments: tag: D22
datatype: string

tool: D33: 3.281

tool: D13: Storeing %u to the address %p


tool: D14: 12

tool: D22: Storing %.2f to the address %p


assistant: ```c
void metersToFeetAndInches(double meters, unsigned int *ftPtr, double *inPtr) {
  double rawFeet = meters * 3.281;
  unsigned int feet = (unsigned int)floor(rawFeet);
  if (ftPtr) {
    printf("Storeing %u to the address %p\n", feet, ftPtr);
    *ftPtr = feet;
  }
  double fractionalFoot = rawFeet - feet;
  double inches = fractionalFoot * 12.0;
  if (inPtr) {
    printf("Storing %.2f to the address %p\n", inches, inPtr);
    *inPtr = inches;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<processCommandLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L7
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: sniffer <interface>


assistant: ```c
void processCommandLine(int argc, char *argv[], char **device) {
  if (argc != 2) {
    printf("sniffer <interface>\n");
    exit(1);
  }
  *device = argv[1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<processCommandLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  cmp    $0x2,%edi
  jne    L17
L4:
  mov    0x8(%rbp),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: sniffer <interface>


assistant: ```c
void processCommandLine(int argc, char *argv[], char **device) {
  if (argc != 2) {
    printf("sniffer <interface>\n");
    exit(1);
  }
  *device = argv[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<processCommandLine>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L2
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    0x8(%rbp),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: sniffer <interface>


assistant: ```c
void processCommandLine(int argc, char *argv[], char **device) {
  if (argc != 2) {
    printf("sniffer <interface>\n");
    exit(1);
  }
  *device = argv[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<processCommandLine>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L2
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    0x8(%rbp),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: sniffer <interface>


assistant: ```c
void processCommandLine(int argc, char *argv[], char **device) {
  if (argc != 2) {
    printf("sniffer <interface>\n");
    exit(1);
  }
  *device = argv[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L4
L39:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    $0x1,%eax
  jmp    L0
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L39
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int equal(char *s1, char *s2) {
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<equal>:
  endbr64
  mov    $0x0,%eax
L4:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  jne    L7
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
  mov    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int equal(char *s1, char *s2) {
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<equal>:
  endbr64
  xor    %eax,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  test   %dl,%dl
  je     L19
L2:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  je     L1
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal(char *s1, char *s2) {
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<equal>:
  endbr64
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  test   %dl,%dl
  je     L28
L14:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  je     L20
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal(char *s1, char *s2) {
  while (*s1 == *s2++) {
    if (*s1++ == '\0')
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raid_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L22
L14:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x14(%rbp)
L22:
  cmpl   $0x0,-0x14(%rbp)
  jle    L8
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L14
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void raid_insert(int n, int *v, int i) {
  v[n] = i;
  while (n > 0 && v[n - 1] > v[n]) {
    int t = v[n - 1];
    v[n - 1] = v[n];
    v[n] = t;
    --n;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<raid_insert>:
  endbr64
  mov    %edx,%ecx
  movslq %edi,%rdx
  shl    $0x2,%rdx
  lea    (%rsi,%rdx,1),%rax
  mov    %ecx,(%rax)
  test   %edi,%edi
  jle    L8
  lea    -0x4(%rsi,%rdx,1),%rsi
  lea    -0x1(%rdi),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rsi
L1:
  mov    -0x4(%rax),%ecx
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L8
  mov    %edx,-0x4(%rax)
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L1
L8:
  ret
```

assistant: ```c
void raid_insert(int n, int *v, int i) {
  v[n] = i;
  while (n > 0 && v[n - 1] > v[n]) {
    int t = v[n - 1];
    v[n - 1] = v[n];
    v[n] = t;
    --n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<raid_insert>:
  endbr64
  movslq %edi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    %edx,(%rax)
  test   %edi,%edi
  jle    L4
  lea    -0x1(%rdi),%ecx
  mov    %rax,%rsi
  shl    $0x2,%rcx
  sub    %rcx,%rsi
  jmp    L2
L26:
  mov    %edx,-0x4(%rax)
  mov    %ecx,(%rax)
  cmp    %rsi,%rax
  je     L4
  sub    $0x4,%rax
L2:
  mov    -0x4(%rax),%ecx
  cmp    %edx,%ecx
  jg     L26
L4:
  ret
```

assistant: ```c
void raid_insert(int n, int *v, int i) {
  v[n] = i;
  while (n > 0 && v[n - 1] > v[n]) {
    int t = v[n - 1];
    v[n - 1] = v[n];
    v[n] = t;
    --n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<raid_insert>:
  endbr64
  movslq %edi,%rax
  mov    %edx,%r8d
  shl    $0x2,%rax
  lea    (%rsi,%rax,1),%rdx
  mov    %r8d,(%rdx)
  test   %edi,%edi
  jle    L0
  lea    -0x4(%rsi,%rax,1),%rsi
  lea    -0x1(%rdi),%eax
  shl    $0x2,%rax
  sub    %rax,%rsi
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L20:
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rsi,%rdx
  je     L0
L17:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jg     L20
L0:
  ret
```

assistant: ```c
void raid_insert(int n, int *v, int i) {
  v[n] = i;
  while (n > 0 && v[n - 1] > v[n]) {
    int t = v[n - 1];
    v[n - 1] = v[n];
    v[n] = t;
    --n;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<DPMaxSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %rdx,-0x1c8(%rbp)
  mov    %rcx,-0x1d0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c0(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x1a8(%rbp)
  mov    -0x1c0(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x19c(%rbp)
  movl   $0x2,-0x1a4(%rbp)
  jmp    L15
L39:
  mov    -0x1a4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L8
  mov    -0x1a4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x1c0(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  jmp    L52
L8:
  mov    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1c0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1c8(%rbp),%rax
  mov    -0x1a4(%rbp),%edx
  mov    %edx,(%rax)
L52:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1a8(%rbp)
  jge    L48
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a8(%rbp)
  mov    -0x1d0(%rbp),%rax
  mov    -0x1a4(%rbp),%edx
  mov    %edx,(%rax)
L48:
  addl   $0x1,-0x1a4(%rbp)
L15:
  mov    -0x1a4(%rbp),%eax
  cmp    -0x1b4(%rbp),%eax
  jle    L39
  mov    -0x1a8(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int DPMaxSum(int n, int data[], int *besti, int *bestj) {
  int sum = data[1];
  int b[100];
  b[1] = data[1];
  for (int i = 2; i <= n; ++i) {
    if (b[i - 1] > 0)
      b[i] = b[i - 1] + data[i];
    else {
      b[i] = data[i];
      *besti = i;
    }
    if (b[i] > sum) {
      sum = b[i];
      *bestj = i;
    }
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DPMaxSum>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsi),%r8d
  mov    %r8d,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L31
  mov    %rsi,%r10
  mov    %rdx,%rbx
  lea    0x8(%rsp),%rdx
  lea    0x1(%rdi),%r11d
  mov    $0x2,%eax
  jmp    L52
L53:
  mov    (%r10,%rax,4),%esi
  mov    %esi,(%rdx)
  mov    %eax,(%rbx)
  jmp    L68
L41:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    %r11,%rax
  je     L31
L52:
  mov    %eax,%r9d
  mov    %rdx,%rdi
  mov    -0x4(%rdx),%esi
  test   %esi,%esi
  jle    L53
  add    (%r10,%rax,4),%esi
  mov    %esi,(%rdx)
L68:
  mov    (%rdi),%esi
  cmp    %r8d,%esi
  jle    L41
  mov    %r9d,(%rcx)
  mov    %esi,%r8d
  jmp    L41
L31:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    %r8d,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  ret
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DPMaxSum(int n, int data[], int *besti, int *bestj) {
  int sum = data[1];
  int b[100];
  b[1] = data[1];
  for (int i = 2; i <= n; ++i) {
    if (b[i - 1] > 0)
      b[i] = b[i - 1] + data[i];
    else {
      b[i] = data[i];
      *besti = i;
    }
    if (b[i] > sum) {
      sum = b[i];
      *bestj = i;
    }
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DPMaxSum>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    0x4(%rsi),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %r9d,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L28
  mov    %rsi,%r11
  lea    0x8(%rsp),%r8
  lea    0x1(%rdi),%ebx
  mov    %r9d,%r10d
  mov    $0x2,%eax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L53:
  add    %r9d,%esi
  mov    %esi,(%r8)
L66:
  cmp    %esi,%r10d
  jge    L25
  mov    %edi,(%rcx)
  mov    %esi,%r10d
L25:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L26
  mov    (%r8),%r9d
  add    $0x4,%r8
L34:
  mov    (%r11,%rax,4),%esi
  mov    %eax,%edi
  test   %r9d,%r9d
  jg     L53
  mov    %esi,(%r8)
  mov    %eax,(%rdx)
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r9d,%r10d
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x1a0,%rsp
  mov    %r10d,%eax
  pop    %rbx
  ret
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DPMaxSum(int n, int data[], int *besti, int *bestj) {
  int sum = data[1];
  int b[100];
  b[1] = data[1];
  for (int i = 2; i <= n; ++i) {
    if (b[i - 1] > 0)
      b[i] = b[i - 1] + data[i];
    else {
      b[i] = data[i];
      *besti = i;
    }
    if (b[i] > sum) {
      sum = b[i];
      *bestj = i;
    }
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DPMaxSum>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  sub    $0x1a0,%rsp
  mov    0x4(%rsi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  cmp    $0x1,%edi
  jle    L67
  lea    0x1(%rdi),%ebx
  mov    %esi,%r8d
  mov    $0x2,%eax
  mov    %rsp,%r11
  jmp    L36
  xchg   %ax,%ax
L57:
  add    %edi,%esi
L31:
  mov    %esi,(%r11,%rax,4)
  cmp    %r8d,%esi
  jle    L56
  mov    %r9d,(%rcx)
  mov    %esi,%r8d
L56:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L63
L36:
  mov    (%r10,%rax,4),%edi
  mov    %eax,%r9d
  test   %esi,%esi
  jg     L57
  mov    %eax,(%rdx)
  mov    %edi,%esi
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %esi,%r8d
  nopl   0x0(%rax,%rax,1)
L63:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x1a0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int DPMaxSum(int n, int data[], int *besti, int *bestj) {
  int sum = data[1];
  int b[100];
  b[1] = data[1];
  for (int i = 2; i <= n; ++i) {
    if (b[i - 1] > 0)
      b[i] = b[i - 1] + data[i];
    else {
      b[i] = data[i];
      *besti = i;
    }
    if (b[i] > sum) {
      sum = b[i];
      *bestj = i;
    }
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<html_cvt_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <html_cvt_long@plt>
  test   %rax,%rax
  je     L11
  mov    $0x1,%eax
  jmp    L8
L11:
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int html_cvt_date(const char *data, int len, void *dst, void *closure) {
  if (data) {
    if (html_cvt_long(data, len, dst, closure))
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<html_cvt_date>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <html_cvt_long@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L9:
  ret
```

assistant: ```c
int html_cvt_date(const char *data, int len, void *dst, void *closure) {
  if (data) {
    if (html_cvt_long(data, len, dst, closure))
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<html_cvt_date>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <html_cvt_long@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int html_cvt_date(const char *data, int len, void *dst, void *closure) {
  if (data) {
    if (html_cvt_long(data, len, dst, closure))
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<html_cvt_date>:
  endbr64
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  call   <html_cvt_long@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int html_cvt_date(const char *data, int len, void *dst, void *closure) {
  if (data) {
    if (html_cvt_long(data, len, dst, closure))
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<end_option>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  addl   $0x1,-0x4(%rbp)
  jmp    L3
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x2,%eax
  add    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xff,%al
  jne    L38
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int end_option(unsigned char *optionptr) {
  int i = 0;
  while (optionptr[i] != 0xFF) {
    if (optionptr[i] == 0x00)
      i++;
    else
      i += optionptr[i + 1] + 2;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<end_option>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xff,%al
  je     L43
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L6
L42:
  movzbl 0x1(%rdi,%rcx,1),%eax
  lea    0x2(%rdx,%rax,1),%edx
L3:
  movslq %edx,%rcx
  movzbl (%rdi,%rcx,1),%eax
  cmp    $0xff,%al
  je     L41
L6:
  test   %al,%al
  jne    L42
  add    $0x1,%edx
  jmp    L3
L43:
  mov    $0x0,%edx
L41:
  mov    %edx,%eax
  ret
```

assistant: ```c
int end_option(unsigned char *optionptr) {
  int i = 0;
  while (optionptr[i] != 0xFF) {
    if (optionptr[i] == 0x00)
      i++;
    else
      i += optionptr[i + 1] + 2;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<end_option>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0xff,%al
  je     L32
  xor    %edx,%edx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%r8d
  movslq %r8d,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0xff,%al
  je     L32
L17:
  test   %al,%al
  je     L39
  movzbl 0x1(%rdi,%rdx,1),%eax
  lea    0x2(%r8,%rax,1),%r8d
  movslq %r8d,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0xff,%al
  jne    L17
L32:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int end_option(unsigned char *optionptr) {
  int i = 0;
  while (optionptr[i] != 0xFF) {
    if (optionptr[i] == 0x00)
      i++;
    else
      i += optionptr[i + 1] + 2;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<end_option>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0xff,%al
  je     L15
  xor    %edx,%edx
L1:
  test   %al,%al
  jne    L30
  add    $0x1,%r8d
  movslq %r8d,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0xff,%al
  jne    L1
L15:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl 0x1(%rdi,%rdx,1),%eax
  lea    0x2(%r8,%rax,1),%r8d
  movslq %r8d,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0xff,%al
  jne    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
int end_option(unsigned char *optionptr) {
  int i = 0;
  while (optionptr[i] != 0xFF) {
    if (optionptr[i] == 0x00)
      i++;
    else
      i += optionptr[i + 1] + 2;
  }
  return i;
}
```