user: 这段汇编代码用C语言表示是什么样的?

```asm
<spline1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%r13d
  lea    (%rdx,%rdx,2),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movslq %r13d,%rax
  shl    $0x3,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  lea    (%rdx,%rax,1),%rcx
  cmp    $0x3,%r13d
  jg     L7
  movq   $0x0,0x0(%rbp)
  movsd  D123(%rip),%xmm2
  movsd  %xmm2,(%rdx)
  movsd  D99(%rip),%xmm3
  movsd  %xmm3,(%rcx)
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  movsd  D116(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  movsd  %xmm3,-0x8(%rbp,%rax,1)
  movsd  %xmm2,-0x8(%rdx,%rax,1)
  movq   $0x0,-0x8(%rcx,%rax,1)
  movsd  -0x8(%rbx,%rax,1),%xmm0
  subsd  -0x10(%rbx,%rax,1),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r12,%rax,1)
  cmp    $0x2,%r13d
  jle    L24
  movsd  D99(%rip),%xmm0
  movsd  %xmm0,0x8(%rbp)
  mov    D92(%rip),%rax
  mov    %rax,0x8(%rdx)
  movsd  %xmm0,0x8(%rcx)
  movsd  0x10(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  mulsd  D116(%rip),%xmm0
  movsd  %xmm0,0x8(%r12)
  jmp    L24
L7:
  movq   $0x0,0x0(%rbp)
  movsd  D123(%rip),%xmm2
  movsd  %xmm2,(%rdx)
  movsd  D92(%rip),%xmm1
  movsd  %xmm1,(%rcx)
  movsd  D118(%rip),%xmm0
  mulsd  (%rbx),%xmm0
  movapd %xmm1,%xmm3
  mulsd  0x8(%rbx),%xmm3
  addsd  %xmm3,%xmm0
  addsd  0x10(%rbx),%xmm0
  movsd  %xmm0,(%r12)
  movsd  %xmm1,-0x8(%rbp,%rax,1)
  movsd  %xmm2,-0x8(%rdx,%rax,1)
  movq   $0x0,-0x8(%rcx,%rax,1)
  movsd  D107(%rip),%xmm0
  mulsd  -0x8(%rbx,%rax,1),%xmm0
  mulsd  -0x10(%rbx,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  subsd  -0x18(%rbx,%rax,1),%xmm0
  movsd  %xmm0,-0x8(%r12,%rax,1)
  lea    -0x1(%r13),%esi
  mov    $0x1,%eax
  movsd  D99(%rip),%xmm1
  movsd  D92(%rip),%xmm3
  movsd  D116(%rip),%xmm2
L0:
  movsd  %xmm1,0x0(%rbp,%rax,8)
  movsd  %xmm3,(%rdx,%rax,8)
  movsd  %xmm1,(%rcx,%rax,8)
  movsd  0x8(%rbx,%rax,8),%xmm0
  subsd  -0x8(%rbx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L0
L24:
  mov    %r13d,%r8d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <thomas@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D123
type_infered: byte[8]
name: read_data
arguments: label: D99
type_infered: byte[8]
name: read_data
arguments: label: D116
type_infered: byte[8]
name: read_data
arguments: label: D92
type_infered: byte[8]
name: read_data
arguments: label: D118
type_infered: byte[8]
name: read_data
arguments: label: D107
type_infered: byte[8]

tool: {"D123": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D99": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D116": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D92": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D118": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0xc0]}

tool: {"D107": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

assistant: ```c
void spline1(double *D, const double *y, int n) {
  int i;
  double *a, *b, *c;
  a = malloc(3 * n * sizeof(double));
  b = a + n;
  c = b + n;
  if (n < 4) {
    a[0] = 0;
    b[0] = 2;
    c[0] = 1;
    D[0] = 3 * (y[1] - y[0]);
    a[n - 1] = 1;
    b[n - 1] = 2;
    c[n - 1] = 0;
    D[n - 1] = 3 * (y[n - 1] - y[n - 2]);
  } else {
    a[0] = 0;
    b[0] = 2;
    c[0] = 4;
    D[0] = -5 * y[0] + 4 * y[1] + y[2];
    a[n - 1] = 4;
    b[n - 1] = 2;
    c[n - 1] = 0;
    D[n - 1] = 5 * y[n - 1] - 4 * y[n - 2] - y[n - 3];
  }
  for (i = 1; i < n - 1; ++i) {
    a[i] = 1;
    b[i] = 4;
    c[i] = 1;
    D[i] = 3 * (y[i + 1] - y[i - 1]);
  }
  thomas(D, a, b, c, n);
  free(a);
}
```