ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_phy_id>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <strtoul@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L42
  cmp    $0x3a,%al
  je     L13
L30:
  mov    $0x1,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  add    $0x1,%rdi
  xor    %edx,%edx
  mov    %r12,%rsi
  call   <strtoul@plt>
  mov    %rax,%rsi
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  jne    L30
  mov    %rbp,%rdi
  call   <mdio_phy_id_c45@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  jmp    L32
  nopl   0x0(%rax)
L42:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  jmp    L32
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_phy_id(char *text, uint16_t *phy_id) {
  unsigned long port, dev;
  char *end;
  port = strtoul(text, &end, 0);
  if (!end[0]) {
    *phy_id = port;
    return 0;
  }
  if (end[0] != ':') {
    return 1;
  }
  dev = strtoul(end + 1, &end, 0);
  if (end[0])
    return 1;
  *phy_id = mdio_phy_id_c45(port, dev);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xc02200e4,%eax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L12:
  mov    -0x8(%rbp),%rax
  movq   $0x46,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L29:
  nop
  nop
  addl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x1fffff,-0xc(%rbp)
  jle    L29
  mov    -0x8(%rbp),%rax
  movq   $0x44,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L50
L51:
  nop
  nop
  addl   $0x1,-0xc(%rbp)
L50:
  cmpl   $0x1fffff,-0xc(%rbp)
  jle    L51
  subl   $0x1,-0x14(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jg     L12
  mov    $0x0,%eax
  call   <shutdown@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  volatile long *p = (void *)0xc02200E4;
  int i;
  for (; cnt > 0; cnt--) {
    p[0] = 0x46;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    p[0] = 0x44;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L31
  mov    %edi,%edx
  mov    $0xc02200e4,%ecx
L25:
  movq   $0x46,(%rcx)
  mov    $0x200000,%eax
L28:
  nop
  nop
  sub    $0x1,%eax
  jne    L28
  movq   $0x44,(%rcx)
  mov    $0x200000,%eax
L22:
  nop
  nop
  sub    $0x1,%eax
  jne    L22
  sub    $0x1,%edx
  jne    L25
L31:
  mov    $0x0,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  volatile long *p = (void *)0xc02200E4;
  int i;
  for (; cnt > 0; cnt--) {
    p[0] = 0x46;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    p[0] = 0x44;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L13
  mov    %edi,%edx
L35:
  mov    $0xc02200e4,%eax
  movq   $0x46,(%rax)
  mov    $0x200000,%eax
  nopl   0x0(%rax)
L31:
  nop
  nop
  sub    $0x1,%eax
  jne    L31
  mov    $0xc02200e4,%eax
  movq   $0x44,(%rax)
  mov    $0x200000,%eax
L9:
  nop
  nop
  sub    $0x1,%eax
  jne    L9
  sub    $0x1,%edx
  jne    L35
L13:
  xor    %eax,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  volatile long *p = (void *)0xc02200E4;
  int i;
  for (; cnt > 0; cnt--) {
    p[0] = 0x46;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    p[0] = 0x44;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<panic>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L14
  mov    %edi,%edx
L33:
  mov    $0xc02200e4,%eax
  movq   $0x46,(%rax)
  mov    $0x200000,%eax
  nopl   0x0(%rax)
L13:
  nop
  nop
  sub    $0x1,%eax
  jne    L13
  mov    $0xc02200e4,%eax
  movq   $0x44,(%rax)
  mov    $0x200000,%eax
L15:
  nop
  nop
  sub    $0x1,%eax
  jne    L15
  sub    $0x1,%edx
  jne    L33
L14:
  xor    %eax,%eax
  call   <shutdown@plt>
```

assistant: ```c
void __attribute__((noreturn)) panic(int cnt) {
  volatile long *p = (void *)0xc02200E4;
  int i;
  for (; cnt > 0; cnt--) {
    p[0] = 0x46;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
    p[0] = 0x44;
    for (i = 0; i < 0x200000; i++) {
      asm("nop\n");
      asm("nop\n");
    }
  }
  shutdown();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printmatwl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L40:
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L15:
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L55
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L55
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L55:
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L40
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string

tool: D16: %15.9f 

tool: D15:   ...

assistant: ```c
void printmatwl(double *a, int m, int n, int w) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%15.9f ", a[i * n + j]);
      jmod = (j + 1) % w;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printmatwl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L4
  mov    %ecx,%ebp
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x8(%rsp)
  lea    D5(%rip),%r14
  lea    -0x1(%rdx),%r15d
  jmp    L78
L85:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L24
L59:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L85
  cmp    %ebx,%r15d
  jle    L85
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L85
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  add    %esi,0x10(%rsp)
  cmp    %eax,0x14(%rsp)
  je     L4
L78:
  cmpl   $0x0,0xc(%rsp)
  jle    L24
  mov    0xc(%rsp),%r13d
  movslq 0x10(%rsp),%rax
  mov    0x18(%rsp),%rcx
  lea    (%rcx,%rax,8),%r12
  mov    $0x0,%ebx
  jmp    L59
L4:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D14
data_type: string

tool: D5: %15.9f 

tool: D14:   ...

assistant: ```c
void printmatwl(double *a, int m, int n, int w) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%15.9f ", a[i * n + j]);
      jmod = (j + 1) % w;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printmatwl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L59
  movl   $0x0,0x10(%rsp)
  mov    %ecx,%ebx
  lea    -0x1(%rdx),%r14d
  lea    D13(%rip),%r13
  movl   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L36:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L72
  movslq 0x10(%rsp),%rax
  mov    0x18(%rsp),%rcx
  mov    %r14d,%r12d
  xor    %r15d,%r15d
  lea    (%rcx,%rax,8),%rbp
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L79:
  lea    0x1(%r15),%rax
  cmp    %r12,%r15
  je     L72
L57:
  mov    %rax,%r15
L49:
  movsd  0x0(%rbp,%r15,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%r15),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L79
  cmp    %r15d,%r14d
  jle    L79
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x1(%r15),%rax
  cmp    %r12,%r15
  jne    L57
  nopl   (%rax)
L72:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x8(%rsp)
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%eax
  add    %esi,0x10(%rsp)
  cmp    %eax,0x14(%rsp)
  jne    L36
L59:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D13: %15.9f 

tool: D14:   ...

assistant: ```c
void printmatwl(double *a, int m, int n, int w) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%15.9f ", a[i * n + j]);
      jmod = (j + 1) % w;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printmatwl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %esi,0x28(%rsp)
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rdx),%eax
  movl   $0x0,0x14(%rsp)
  mov    %edx,%r13d
  mov    %ecx,%ebp
  cmp    %eax,%edx
  mov    %eax,0x2c(%rsp)
  lea    D8(%rip),%r12
  lea    D0(%rip),%r15
  cmovle %edx,%eax
  movl   $0x0,0x10(%rsp)
  mov    %eax,0xc(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L13:
  test   %r13d,%r13d
  jle    L30
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L9
  movslq 0x14(%rsp),%rax
  mov    0x20(%rsp),%rsi
  xor    %r14d,%r14d
  mov    %rax,0x18(%rsp)
  lea    (%rsi,%rax,8),%rbx
  nopl   0x0(%rax,%rax,1)
L35:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%r14d
  call   <printf@plt>
  mov    %r14d,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L59
  mov    %r15,%rdi
  call   <puts@plt>
L59:
  add    $0x8,%rbx
  cmp    0xc(%rsp),%r14d
  jl     L35
  cmp    %r13d,%r14d
  jge    L30
L50:
  mov    0x20(%rsp),%rax
  mov    0x18(%rsp),%rcx
  movslq %r14d,%rbx
  lea    (%rax,%rcx,8),%r14
  nopl   0x0(%rax,%rax,1)
L27:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jg     L27
L30:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  add    %r13d,0x14(%rsp)
  cmp    %eax,0x28(%rsp)
  jne    L13
L10:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L9:
  movslq 0x14(%rsp),%rax
  xor    %r14d,%r14d
  mov    %rax,0x18(%rsp)
  jmp    L50
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D0
data_type: string

tool: D8: %15.9f 

tool: D0:   ...

assistant: ```c
void printmatwl(double *a, int m, int n, int w) {
  int i, j, jmod;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("%15.9f ", a[i * n + j]);
      jmod = (j + 1) % w;
      if ((jmod == 0) && (j < (n - 1))) {
        printf("  ...\n");
      }
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shmctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <StubBug@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: STUB:shmctl

assistant: ```c
int shmctl(int shmid, int cmd, struct shmid_ds *buf) {
  StubBug("STUB:"
          "shmctl");
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shmctl>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <StubBug@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: STUB:shmctl

assistant: ```c
int shmctl(int shmid, int cmd, struct shmid_ds *buf) {
  StubBug("STUB:"
          "shmctl");
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shmctl>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <StubBug@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: STUB:shmctl

assistant: ```c
int shmctl(int shmid, int cmd, struct shmid_ds *buf) {
  StubBug("STUB:"
          "shmctl");
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shmctl>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <StubBug@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: STUB:shmctl

assistant: ```c
int shmctl(int shmid, int cmd, struct shmid_ds *buf) {
  StubBug("STUB:"
          "shmctl");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmdDiskPrintFtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <diskInit@plt>
  test   %eax,%eax
  leave
  ret
```

assistant: ```c
void cmdDiskPrintFtime(char *path) {
  if (!diskInit()) {
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmdDiskPrintFtime>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <diskInit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmdDiskPrintFtime(char *path) {
  if (!diskInit()) {
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmdDiskPrintFtime>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <diskInit@plt>
```

assistant: ```c
void cmdDiskPrintFtime(char *path) {
  if (!diskInit()) {
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmdDiskPrintFtime>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <diskInit@plt>
```

assistant: ```c
void cmdDiskPrintFtime(char *path) {
  if (!diskInit()) {
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<TestP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x1,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  add    $0x2,%al
  setp   %dl
  mov    %dl,-0x1(%rbp)
  mov    %al,-0x2(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L20
  movzbl -0x2(%rbp),%eax
  add    $0x1,%al
  setnp  %dl
  mov    %dl,-0x1(%rbp)
  mov    %al,-0x2(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L20
  mov    $0x1,%eax
  jmp    L11
L20:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
char TestP() {
  char r, res = 1;
  __asm__("addb $2, %1" : "=@ccp"(r), "+r"(res));
  if (r) {
    __asm__("addb $1, %1" : "=@ccnp"(r), "+r"(res));
    if (r)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TestP>:
  endbr64
  mov    $0x1,%eax
  add    $0x2,%al
  setp   %dl
  jnp    L2
  add    $0x1,%al
  setnp  %dl
L2:
  mov    %edx,%eax
  ret
```

assistant: ```c
char TestP() {
  char r, res = 1;
  __asm__("addb $2, %1" : "=@ccp"(r), "+r"(res));
  if (r) {
    __asm__("addb $1, %1" : "=@ccnp"(r), "+r"(res));
    if (r)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TestP>:
  endbr64
  mov    $0x1,%eax
  add    $0x2,%al
  setp   %r8b
  jnp    L8
  add    $0x1,%al
  setnp  %r8b
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char TestP() {
  char r, res = 1;
  __asm__("addb $2, %1" : "=@ccp"(r), "+r"(res));
  if (r) {
    __asm__("addb $1, %1" : "=@ccnp"(r), "+r"(res));
    if (r)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TestP>:
  endbr64
  mov    $0x1,%eax
  add    $0x2,%al
  setp   %r8b
  jnp    L4
  add    $0x1,%al
  setnp  %r8b
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char TestP() {
  char r, res = 1;
  __asm__("addb $2, %1" : "=@ccp"(r), "+r"(res));
  if (r) {
    __asm__("addb $1, %1" : "=@ccnp"(r), "+r"(res));
    if (r)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parseeseq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x9(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int parseeseq(const char *s) {
  char tmp[4];
  memcpy(tmp, s + 2, 3);
  tmp[3] = '\0';
  return (int)strtol(tmp, NULL, 8);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parseeseq>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rdi),%rsi
  lea    0x4(%rsp),%rbx
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x7(%rsp)
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseeseq(const char *s) {
  char tmp[4];
  memcpy(tmp, s + 2, 3);
  tmp[3] = '\0';
  return (int)strtol(tmp, NULL, 8);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parseeseq>:
  endbr64
  push   %rbp
  lea    0x2(%rdi),%rsi
  mov    $0x3,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtol@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseeseq(const char *s) {
  char tmp[4];
  memcpy(tmp, s + 2, 3);
  tmp[3] = '\0';
  return (int)strtol(tmp, NULL, 8);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parseeseq>:
  endbr64
  push   %rbp
  lea    0x2(%rdi),%rsi
  mov    $0x3,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtol@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parseeseq(const char *s) {
  char tmp[4];
  memcpy(tmp, s + 2, 3);
  tmp[3] = '\0';
  return (int)strtol(tmp, NULL, 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa4(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L66
L63:
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L88
L64:
  lea    -0x90(%rbp),%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x9c(%rbp)
L88:
  mov    -0xa0(%rbp),%eax
  cmp    %eax,-0x9c(%rbp)
  jl     L64
  movl   $0x64,-0x98(%rbp)
  movl   $0x0,-0x94(%rbp)
  movl   $0x0,-0x9c(%rbp)
  jmp    L89
L34:
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  cmp    %eax,-0x98(%rbp)
  jle    L59
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    %eax,-0x98(%rbp)
L59:
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  cmp    %eax,-0x94(%rbp)
  jge    L22
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    %eax,-0x94(%rbp)
L22:
  addl   $0x1,-0x9c(%rbp)
L89:
  mov    -0xa0(%rbp),%eax
  cmp    %eax,-0x9c(%rbp)
  jl     L34
  mov    -0x94(%rbp),%eax
  sub    -0x98(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L66:
  mov    -0xa4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xa4(%rbp)
  test   %eax,%eax
  jg     L63
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D10
type_infered: string

tool: D28: %d


tool: D10: %d

assistant: ```c
int main() {
  int num_cases, num_items;
  int i, item[32];
  int min, max;
  scanf("%d\n", &num_cases);
  while (num_cases-- > 0) {
    scanf("%d\n", &num_items);
    for (i = 0; i < num_items; i++) {
      scanf("%d", &item[i]);
    }
    min = 100, max = 0;
    for (i = 0; i < num_items; i++) {
      if (min > item[i])
        min = item[i];
      if (max < item[i])
        max = item[i];
    }
    printf("%d\n", 2 * (max - min));
  }
  return 0;
}
```