user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x6c(%rbp)
  jmp    L39
L7:
  mov    -0x6c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x6c(%rbp)
L39:
  cmpl   $0x9,-0x6c(%rbp)
  jle    L7
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L47
L55:
  mov    -0x68(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x68(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x68(%rbp)
L47:
  cmpl   $0x9,-0x68(%rbp)
  jle    L55
  movl   $0x0,-0x64(%rbp)
  jmp    L13
L57:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    $0x9,%eax
  sub    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    $0x9,%eax
  sub    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    $0x9,%eax
  sub    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x70(%rbp)
  addl   $0x1,-0x64(%rbp)
L13:
  cmpl   $0x9,-0x64(%rbp)
  jle    L57
  mov    -0x70(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D43
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D64
datatype: string
name: disassemble_data
arguments: data_label: D50
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D32
datatype: string

tool: D43: Vetor A

tool: D41: Posicao %d: 

tool: D64: %d

tool: D50: Vetor B

tool: D13: %d - %d = %d


tool: D32: Soma: %d


assistant: ```c
void main() {
  int A[10], B[10], soma = 0;
  printf("Vetor A\n");
  for (int i = 0; i < 10; i++) {
    printf("Posicao %d: ", i + 1);
    scanf("%d", &A[i]);
  }
  printf("Vetor B\n");
  for (int i = 0; i < 10; i++) {
    printf("Posicao %d: ", i + 1);
    scanf("%d", &B[i]);
  }
  for (int i = 0; i < (10); i++) {
    printf("%d - %d = %d\n", A[i], B[(10 - 1) - i], A[i] - B[(10 - 1) - i]);
    soma += (A[i] - B[(10 - 1) - i]);
  }
  printf("Soma: %d\n", soma);
}
```