user: 请从给定的汇编指令推导出C源代码：

```asm
<preprocessor1>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D4(%rip),%r13
  mov    %r13,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x11,%edx
  lea    D14(%rip),%r12
  mov    %r12,%rsi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x12e,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x18,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1e,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D46
type_infered: string
name: retrieve_data
arguments: data_label: D1
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D50
type_infered: string

tool: D4: preprocessor1

tool: D46: ----- START %s


tool: D1: a= %d	

tool: D14: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c

tool: D3: ** look at %s:%d **


tool: D50: ----- END %s


assistant: ```c
int preprocessor1(void) {
  printf("----- START %s\n", __FUNCTION__);
  {
    int x = 2;
    printf("a= %d\t", (int)(x * 2 + 3.14159));
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 17);
  {
    int ce1;
    for (ce1 = 0; ce1 <= 100; ce1 += 50)
      printf("a= %d\t", (int)(ce1));
    printf("a= %d\t", (int)(9. / 5 * ce1 + 32));
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 24);
  {
    int x = 1, y = 2;
    printf("a= %d\t", (int)((x++ < y ? y : x++)));
    printf("a= %d\t", (int)(x));
    printf("a= %d\t", (int)(y));
    putchar('\n');
    printf("a= %d\t", (int)((x++ < y ? y : x++)));
    printf("a= %d\t", (int)(x));
    printf("a= %d\t", (int)(y));
    putchar('\n');
  }
  printf("** look at %s:%d **\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/reslaurentii/sandbox/refs/heads/master/src/preprocessor.c", 30);
  printf("----- END %s\n", __FUNCTION__);
  return 0;
}
```