ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getCounts>:
  endbr64
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  test   %ecx,%ecx
  jle    L37
  movslq %ecx,%rcx
  xor    %esi,%esi
  lea    0x0(,%rcx,4),%rdx
  call   <memset@plt>
  mov    %rax,%rdi
L37:
  test   %ebp,%ebp
  jle    L41
  mov    %rbx,%rax
  lea    -0x1(%rbp),%edx
  cmp    $0x4,%r12d
  je     L36
  lea    0x1(%rbx,%rdx,1),%rcx
  nopl   0x0(%rax)
L14:
  movzbl (%rax),%edx
  add    $0x1,%rax
  addl   $0x1,(%rdi,%rdx,4)
  cmp    %rax,%rcx
  jne    L14
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L36:
  lea    0x4(%rbx,%rdx,4),%rcx
  nopl   (%rax)
L10:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,(%rdi,%rdx,4)
  cmp    %rcx,%rax
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getCounts(const unsigned char *T, int *C, int n, int k, int cs) {
  int i;
  for (i = 0; i < k; ++i) {
    C[i] = 0;
  }
  for (i = 0; i < n; ++i) {
    ++C[(cs == sizeof(int) ? ((const int *)T)[i] : ((const unsigned char *)T)[i])];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<atom_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <lock_atom_add@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  call   <unlock_atom_add@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long atom_add(long long *addr, long long value) {
  long long ret;
  lock_atom_add();
  ret = *addr;
  *addr += value;
  unlock_atom_add();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atom_add>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <lock_atom_add@plt>
  mov    0x0(%rbp),%r12
  add    %r12,%rbx
  mov    %rbx,0x0(%rbp)
  mov    $0x0,%eax
  call   <unlock_atom_add@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long atom_add(long long *addr, long long value) {
  long long ret;
  lock_atom_add();
  ret = *addr;
  *addr += value;
  unlock_atom_add();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<atom_add>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <lock_atom_add@plt>
  mov    0x0(%rbp),%r12
  xor    %eax,%eax
  add    %r12,%rbx
  mov    %rbx,0x0(%rbp)
  call   <unlock_atom_add@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long atom_add(long long *addr, long long value) {
  long long ret;
  lock_atom_add();
  ret = *addr;
  *addr += value;
  unlock_atom_add();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atom_add>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <lock_atom_add@plt>
  mov    0x0(%rbp),%r12
  xor    %eax,%eax
  add    %r12,%rbx
  mov    %rbx,0x0(%rbp)
  call   <unlock_atom_add@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long atom_add(long long *addr, long long value) {
  long long ret;
  lock_atom_add();
  ret = *addr;
  *addr += value;
  unlock_atom_add();
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<flu_rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L68
L37:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x20,-0x9(%rbp)
  je     L39
  cmpb   $0x9,-0x9(%rbp)
  je     L39
  cmpb   $0xa,-0x9(%rbp)
  je     L39
  cmpb   $0xd,-0x9(%rbp)
  jne    L20
L39:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L68:
  cmpq   $0x0,-0x8(%rbp)
  jne    L37
L20:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *flu_rtrim(char *s) {
  if (s)
    for (size_t l = strlen(s); l > 0; l--) {
      char c = s[l - 1];
      if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
        s[l - 1] = 0;
      else
        break;
    }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<flu_rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L2
  call   <strlen@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L2
  movabs $0x100002600,%rcx
  jmp    L7
L14:
  movb   $0x0,(%rbx,%rdx,1)
  test   %rdx,%rdx
  je     L2
L7:
  sub    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%eax
  cmp    $0x20,%al
  ja     L2
  bt     %rax,%rcx
  jb     L14
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *flu_rtrim(char *s) {
  if (s)
    for (size_t l = strlen(s); l > 0; l--) {
      char c = s[l - 1];
      if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
        s[l - 1] = 0;
      else
        break;
    }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flu_rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L5
  call   <strlen@plt>
  test   %rax,%rax
  je     L5
  movabs $0xfffffffeffffd9ff,%rcx
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rax
  movzbl (%r12,%rax,1),%edx
  cmp    $0x20,%dl
  jbe    L45
L5:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L45:
  bt     %rdx,%rcx
  jb     L5
  movb   $0x0,(%r12,%rax,1)
  test   %rax,%rax
  jne    L10
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *flu_rtrim(char *s) {
  if (s)
    for (size_t l = strlen(s); l > 0; l--) {
      char c = s[l - 1];
      if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
        s[l - 1] = 0;
      else
        break;
    }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flu_rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L14
  call   <strlen@plt>
  test   %rax,%rax
  je     L14
  movabs $0xfffffffeffffd9ff,%rcx
  nopw   0x0(%rax,%rax,1)
L24:
  sub    $0x1,%rax
  movzbl (%r12,%rax,1),%edx
  cmp    $0x20,%dl
  jbe    L41
L14:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  bt     %rdx,%rcx
  jb     L14
  movb   $0x0,(%r12,%rax,1)
  test   %rax,%rax
  jne    L24
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *flu_rtrim(char *s) {
  if (s)
    for (size_t l = strlen(s); l > 0; l--) {
      char c = s[l - 1];
      if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
        s[l - 1] = 0;
      else
        break;
    }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sdev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <average@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L20
L23:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  subss  -0xc(%rbp),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0xc(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L23
  cmpl   $0x1,-0x1c(%rbp)
  jle    L12
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x8(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float sdev(a, n)
float *a;
int n;
{
  int i;
  float average(), mean;
  double sum = 0, sqrt();
  mean = average(a, n);
  for (i = 1; i <= n; i++)
    sum += ((a[i] - mean) * (a[i] - mean));
  if (n > 1)
    sum = sum / (n - 1);
  sum = sqrt(sum);
  return ((float)sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<sdev>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <average@plt>
  test   %ebx,%ebx
  jle    L51
  lea    0x4(%rbp),%rax
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,4),%rdx
  pxor   %xmm2,%xmm2
L55:
  movss  (%rax),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L55
  cmp    $0x1,%ebx
  jle    L16
  sub    $0x1,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  divsd  %xmm0,%xmm2
L16:
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L37
L31:
  sqrtsd %xmm2,%xmm2
L56:
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  pxor   %xmm2,%xmm2
  jmp    L31
L37:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L56
```

assistant: ```c
float sdev(a, n)
float *a;
int n;
{
  int i;
  float average(), mean;
  double sum = 0, sqrt();
  mean = average(a, n);
  for (i = 1; i <= n; i++)
    sum += ((a[i] - mean) * (a[i] - mean));
  if (n > 1)
    sum = sum / (n - 1);
  sum = sqrt(sum);
  return ((float)sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sdev>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <average@plt>
  test   %ebx,%ebx
  jle    L5
  lea    -0x1(%rbx),%edx
  pxor   %xmm3,%xmm3
  movaps %xmm0,%xmm2
  mov    %rdx,%rcx
  lea    0x4(%rbp),%rax
  lea    0x8(%rbp,%rdx,4),%rdx
  movapd %xmm3,%xmm0
  nopl   0x0(%rax)
L40:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  subss  %xmm2,%xmm1
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L40
  cmp    $0x1,%ebx
  je     L51
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  %xmm1,%xmm0
L51:
  ucomisd %xmm0,%xmm3
  ja     L12
L7:
  sqrtsd %xmm0,%xmm0
L29:
  add    $0x8,%rsp
  cvtsd2ss %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  pxor   %xmm0,%xmm0
  jmp    L7
L12:
  call   <sqrt@plt>
  jmp    L29
```

assistant: ```c
float sdev(a, n)
float *a;
int n;
{
  int i;
  float average(), mean;
  double sum = 0, sqrt();
  mean = average(a, n);
  for (i = 1; i <= n; i++)
    sum += ((a[i] - mean) * (a[i] - mean));
  if (n > 1)
    sum = sum / (n - 1);
  sum = sqrt(sum);
  return ((float)sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sdev>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <average@plt>
  test   %ebx,%ebx
  jle    L48
  lea    -0x1(%rbx),%edx
  pxor   %xmm3,%xmm3
  movaps %xmm0,%xmm2
  mov    %rdx,%rcx
  lea    0x4(%rbp),%rax
  lea    0x8(%rbp,%rdx,4),%rdx
  movapd %xmm3,%xmm0
  nopl   0x0(%rax)
L7:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  subss  %xmm2,%xmm1
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L7
  cmp    $0x1,%ebx
  je     L15
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  %xmm1,%xmm0
L15:
  ucomisd %xmm0,%xmm3
  ja     L57
L35:
  sqrtsd %xmm0,%xmm0
L21:
  add    $0x8,%rsp
  cvtsd2ss %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  pxor   %xmm0,%xmm0
  jmp    L35
L57:
  call   <sqrt@plt>
  jmp    L21
```

assistant: ```c
float sdev(a, n)
float *a;
int n;
{
  int i;
  float average(), mean;
  double sum = 0, sqrt();
  mean = average(a, n);
  for (i = 1; i <= n; i++)
    sum += ((a[i] - mean) * (a[i] - mean));
  if (n > 1)
    sum = sum / (n - 1);
  sum = sqrt(sum);
  return ((float)sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D45(%rip),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  lea    -0x60(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <linear_interpolate@plt>
  mov    -0x60(%rbp),%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x50(%rbp),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D45
type_guessed: f64
name: read_data
arguments: tag: D22
type_guessed: f64
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string

tool: D45: 1

tool: D22: 3

tool: D23: should be 1.0 is %lf


tool: D13: should be 2.0 is %lf


tool: D1: should be 3.0 is %lf


assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  double array[10];
  array[0] = 1.0;
  array[2] = 3.0;
  linear_interpolate(array, 0, 2);
  printf("should be 1.0 is %lf\n", array[0]);
  printf("should be 2.0 is %lf\n", array[1]);
  printf("should be 3.0 is %lf\n", array[2]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D21(%rip),%rax
  mov    %rax,(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
  call   <linear_interpolate@plt>
  movsd  (%rsp),%xmm0
  lea    D37(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  lea    D30(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_infered: f64
name: disassemble_data
arguments: data_label: D25
type_infered: f64
name: disassemble_data
arguments: data_label: D37
type_infered: string
name: disassemble_data
arguments: data_label: D30
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string

tool: D21: 1

tool: D25: 3

tool: D37: should be 1.0 is %lf


tool: D30: should be 2.0 is %lf


tool: D13: should be 3.0 is %lf


assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  double array[10];
  array[0] = 1.0;
  array[2] = 3.0;
  linear_interpolate(array, 0, 2);
  printf("should be 1.0 is %lf\n", array[0]);
  printf("should be 2.0 is %lf\n", array[1]);
  printf("should be 3.0 is %lf\n", array[2]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  xor    %esi,%esi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    D46(%rip),%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <linear_interpolate@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: f64
name: read_data
arguments: data_tag: D46
datatype: f64
name: read_data
arguments: data_tag: D49
datatype: string
name: read_data
arguments: data_tag: D27
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string

tool: D11: 1

tool: D46: 3

tool: D49: should be 1.0 is %lf


tool: D27: should be 2.0 is %lf


tool: D29: should be 3.0 is %lf


assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  double array[10];
  array[0] = 1.0;
  array[2] = 3.0;
  linear_interpolate(array, 0, 2);
  printf("should be 1.0 is %lf\n", array[0]);
  printf("should be 2.0 is %lf\n", array[1]);
  printf("should be 3.0 is %lf\n", array[2]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  xor    %esi,%esi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    D12(%rip),%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  call   <linear_interpolate@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: f64
name: parse_data
arguments: data_label: D12
type: f64
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D47
type: string

tool: D0: 1

tool: D12: 3

tool: D25: should be 1.0 is %lf


tool: D17: should be 2.0 is %lf


tool: D47: should be 3.0 is %lf


assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{
  double array[10];
  array[0] = 1.0;
  array[2] = 3.0;
  linear_interpolate(array, 0, 2);
  printf("should be 1.0 is %lf\n", array[0]);
  printf("should be 2.0 is %lf\n", array[1]);
  printf("should be 3.0 is %lf\n", array[2]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hflip_usmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L33
L32:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L35
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L13
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hflip_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch, ushort **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hflip_usmatrix>:
  endbr64
  mov    %rdx,%r10
  mov    %rcx,%rdx
  lea    (%rcx,%r8,1),%eax
  movslq %esi,%rcx
  cmp    %rcx,%r10
  jl     L32
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %r8,%rbx
  shl    $0x3,%rcx
  lea    (%rdi,%rcx,1),%rdi
  add    %rcx,%r9
  lea    0x8(%r11,%r10,8),%r12
  movslq %edx,%rbp
  shl    $0x2,%rbp
  lea    0x4(,%r8,4),%r11
  cltq
  lea    0x0(,%rax,4),%r10
  movslq %edx,%r8
L15:
  cmp    %r8,%rbx
  jl     L39
  mov    %rbp,%rax
L13:
  mov    (%rdi),%rdx
  mov    (%rdx,%rax,1),%esi
  mov    %r10,%rdx
  sub    %rax,%rdx
  mov    (%r9),%rcx
  mov    %esi,(%rcx,%rdx,1)
  add    $0x4,%rax
  cmp    %r11,%rax
  jne    L13
L39:
  add    $0x8,%rdi
  add    $0x8,%r9
  cmp    %r12,%rdi
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  ret
```

assistant: ```c
void hflip_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch, ushort **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hflip_usmatrix>:
  endbr64
  push   %r13
  lea    (%rcx,%r8,1),%eax
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movslq %esi,%rdi
  cmp    %rdi,%rdx
  jl     L6
  movslq %ecx,%r10
  cltq
  shl    $0x3,%rdi
  lea    0x8(,%rdx,8),%rbp
  sub    %r10,%rax
  lea    0x0(,%r10,4),%r12
  lea    0x4(,%r8,4),%r13
  lea    0x0(,%rax,4),%r11
  nopl   (%rax)
L16:
  cmp    %r10,%r8
  jl     L5
  mov    (%rbx,%rdi,1),%rsi
  mov    (%r9,%rdi,1),%rdx
  lea    (%rsi,%r12,1),%rax
  add    %r11,%rdx
  add    %r13,%rsi
  nop
L34:
  mov    (%rax),%ecx
  add    $0x4,%rax
  sub    $0x4,%rdx
  mov    %ecx,0x4(%rdx)
  cmp    %rsi,%rax
  jne    L34
L5:
  add    $0x8,%rdi
  cmp    %rbp,%rdi
  jne    L16
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void hflip_usmatrix(ushort **S, long nrl, long nrh, long ncl, long nch, ushort **D) {
  int i, j, n = ncl + nch;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      D[i][n - j] = S[i][j];
    }
  }
}
```