ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%ecx
  mov    $0x14,%edx
  mov    $0xb,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D19
type_infered: string

tool: D24: 
after *p++: arr[0]=%d arr[1]=%d *p=%d


tool: D4: 
after *++p: arr[0]=%d arr[1]=%d *p=%d


tool: D19: 
after ++*p: arr[0]=%d arr[1]=%d *p=%d


assistant: ```c
int main() {
  int arr[] = {10, 20};
  int *p = arr;
  *p++;
  printf("\nafter *p++: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  p = arr;
  *++p;
  printf("\nafter *++p: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  p = arr;
  ++*p;
  printf("\nafter ++*p: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xb,%ecx
  mov    $0x14,%edx
  mov    $0xb,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string

tool: D27: 
after *p++: arr[0]=%d arr[1]=%d *p=%d


tool: D2: 
after *++p: arr[0]=%d arr[1]=%d *p=%d


tool: D22: 
after ++*p: arr[0]=%d arr[1]=%d *p=%d


assistant: ```c
int main() {
  int arr[] = {10, 20};
  int *p = arr;
  *p++;
  printf("\nafter *p++: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  p = arr;
  *++p;
  printf("\nafter *++p: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  p = arr;
  ++*p;
  printf("\nafter ++*p: arr[0]=%d arr[1]=%d *p=%d\n", arr[0], arr[1], *p);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L0:
  mov    -0x40(%rbp),%r8
  mov    -0x18(%rbp),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <merge@plt>
  shlq   -0x18(%rbp)
  mov    -0x40(%rbp),%r8
  mov    -0x18(%rbp),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <merge@plt>
  shlq   -0x18(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void merge_sort(void *base, size_t n, size_t width, int (*cmp)(const void *, const void *)) {
  size_t length = 1;
  char *temp = malloc(width * n);
  char *base1 = (char *)base;
  while (length <= n) {
    merge(base1, temp, n, width, length, cmp);
    length *= 2;
    merge(temp, base1, n, width, length, cmp);
    length *= 2;
  }
  free(temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<merge_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r15
  mov    %rdx,%rdi
  imul   %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L10
  mov    $0x1,%ebx
L8:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  mov    %r15,%r9
  lea    (%rbx,%rbx,1),%r8
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <merge@plt>
  shl    $0x2,%rbx
  cmp    %rbx,%rbp
  jae    L8
L10:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void merge_sort(void *base, size_t n, size_t width, int (*cmp)(const void *, const void *)) {
  size_t length = 1;
  char *temp = malloc(width * n);
  char *base1 = (char *)base;
  while (length <= n) {
    merge(base1, temp, n, width, length, cmp);
    length *= 2;
    merge(temp, base1, n, width, length, cmp);
    length *= 2;
  }
  free(temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge_sort>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  imul   %rsi,%rdi
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L4
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%r8
  mov    %r15,%r9
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  lea    (%rbx,%rbx,1),%r8
  mov    %r15,%r9
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  shl    $0x2,%rbx
  call   <merge@plt>
  cmp    %rbx,%rbp
  jae    L15
L4:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void merge_sort(void *base, size_t n, size_t width, int (*cmp)(const void *, const void *)) {
  size_t length = 1;
  char *temp = malloc(width * n);
  char *base1 = (char *)base;
  while (length <= n) {
    merge(base1, temp, n, width, length, cmp);
    length *= 2;
    merge(temp, base1, n, width, length, cmp);
    length *= 2;
  }
  free(temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge_sort>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  imul   %rsi,%rdi
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L6
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbx,%r8
  mov    %r15,%r9
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  lea    (%rbx,%rbx,1),%r8
  mov    %r15,%r9
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  shl    $0x2,%rbx
  call   <merge@plt>
  cmp    %rbx,%rbp
  jae    L16
L6:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void merge_sort(void *base, size_t n, size_t width, int (*cmp)(const void *, const void *)) {
  size_t length = 1;
  char *temp = malloc(width * n);
  char *base1 = (char *)base;
  while (length <= n) {
    merge(base1, temp, n, width, length, cmp);
    length *= 2;
    merge(temp, base1, n, width, length, cmp);
    length *= 2;
  }
  free(temp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Fraction_of_Day>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  D29(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: f64
name: read_data
arguments: label: D29
type: f64

tool: D2: 60

tool: D29: 24

assistant: ```c
double Fraction_of_Day(int hr, int mi, double se) {
  double dhr, dmi;
  dhr = (double)hr;
  dmi = (double)mi;
  return ((dhr + (dmi + se / 60.0) / 60.0) / 24.0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Fraction_of_Day>:
  endbr64
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  addsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  addsd  %xmm1,%xmm0
  divsd  D6(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_guessed: f64
name: retrieve_data
arguments: data_label: D6
type_guessed: f64

tool: D17: 60

tool: D6: 24

assistant: ```c
double Fraction_of_Day(int hr, int mi, double se) {
  double dhr, dmi;
  dhr = (double)hr;
  dmi = (double)mi;
  return ((dhr + (dmi + se / 60.0) / 60.0) / 24.0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Fraction_of_Day>:
  endbr64
  movsd  D12(%rip),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  addsd  %xmm1,%xmm0
  divsd  D3(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: f64
name: extract_symbolic_data
arguments: data_tag: D3
type: f64

tool: D12: 60

tool: D3: 24

assistant: ```c
double Fraction_of_Day(int hr, int mi, double se) {
  double dhr, dmi;
  dhr = (double)hr;
  dmi = (double)mi;
  return ((dhr + (dmi + se / 60.0) / 60.0) / 24.0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Fraction_of_Day>:
  endbr64
  movsd  D0(%rip),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  addsd  %xmm1,%xmm0
  divsd  D15(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: f64
name: unpack_data
arguments: tag: D15
type: f64

tool: D0: 60

tool: D15: 24

assistant: ```c
double Fraction_of_Day(int hr, int mi, double se) {
  double dhr, dmi;
  dhr = (double)hr;
  dmi = (double)mi;
  return ((dhr + (dmi + se / 60.0) / 60.0) / 24.0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<begin_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <declare_function@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: M68K_FUNCTION(%s)
{


assistant: ```c
int begin_function(const char *name) {
  int func_id = declare_function(name);
  if (func_id >= 0)
    printf("M68K_FUNCTION(%s)\n{\n", name);
  return func_id;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<begin_function>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <declare_function@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L15
L12:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: M68K_FUNCTION(%s)
{


assistant: ```c
int begin_function(const char *name) {
  int func_id = declare_function(name);
  if (func_id >= 0)
    printf("M68K_FUNCTION(%s)\n{\n", name);
  return func_id;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<begin_function>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <declare_function@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L8
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: M68K_FUNCTION(%s)
{


assistant: ```c
int begin_function(const char *name) {
  int func_id = declare_function(name);
  if (func_id >= 0)
    printf("M68K_FUNCTION(%s)\n{\n", name);
  return func_id;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<begin_function>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <declare_function@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: M68K_FUNCTION(%s)
{


assistant: ```c
int begin_function(const char *name) {
  int func_id = declare_function(name);
  if (func_id >= 0)
    printf("M68K_FUNCTION(%s)\n{\n", name);
  return func_id;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<softfloat_normRoundPackMToF128M>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L25
  addl   $0x20,-0x10(%rbp)
  cmpl   $0x9f,-0x10(%rbp)
  jle    L29
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mov    -0x14(%rbp),%edx
  shl    $0x1f,%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L19
L29:
  subq   $0x4,-0x8(%rbp)
  jmp    L11
L25:
  nop
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <softfloat_countLeadingZeros32@plt>
  sub    $0xf,%eax
  add    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <softfloat_shiftLeftM@plt>
L38:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <softfloat_roundPackMToF128M@plt>
L19:
  leave
  ret
```

assistant: ```c
void softfloat_normRoundPackMToF128M(bool sign, int32_t exp, uint32_t *extSigPtr, uint32_t *zWPtr) {
  const uint32_t *ptr;
  int_fast16_t shiftCount;
  uint32_t wordSig;
  ptr = extSigPtr + ((5) - 1);
  shiftCount = 0;
  for (;;) {
    wordSig = *ptr;
    if (wordSig)
      break;
    shiftCount += 32;
    if (160 <= shiftCount) {
      zWPtr[((4) - 1)] = (((uint32_t)(sign) << 31) + ((uint32_t)(0) << 16) + (0));
      zWPtr[(2)] = 0;
      zWPtr[(1)] = 0;
      zWPtr[(0)] = 0;
      return;
    }
    ptr -= 1;
  }
  shiftCount += softfloat_countLeadingZeros32(wordSig) - 15;
  if (shiftCount) {
    exp -= shiftCount;
    softfloat_shiftLeftM(5, extSigPtr, shiftCount, extSigPtr);
  }
  softfloat_roundPackMToF128M(sign, exp, extSigPtr, zWPtr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<softfloat_normRoundPackMToF128M>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    0x10(%rdx),%edi
  test   %edi,%edi
  jne    L23
  lea    0x10(%rdx),%rax
  mov    $0x20,%ebx
L1:
  sub    $0x4,%rax
  mov    (%rax),%edi
  test   %edi,%edi
  jne    L48
  add    $0x20,%ebx
  cmp    $0xa0,%ebx
  jne    L1
  shl    $0x1f,%r12d
  mov    %r12d,0xc(%rbp)
  movl   $0x0,0x8(%rbp)
  movl   $0x0,0x4(%rbp)
  movl   $0x0,0x0(%rbp)
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0x0,%ebx
L48:
  call   <softfloat_countLeadingZeros32@plt>
  lea    -0xf(%rbx,%rax,1),%edx
  test   %edx,%edx
  jne    L17
L20:
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <softfloat_roundPackMToF128M@plt>
  jmp    L42
L17:
  sub    %edx,%r14d
  mov    %r13,%rcx
  mov    %r13,%rsi
  mov    $0x5,%edi
  call   <softfloat_shiftLeftM@plt>
  jmp    L20
```

assistant: ```c
void softfloat_normRoundPackMToF128M(bool sign, int32_t exp, uint32_t *extSigPtr, uint32_t *zWPtr) {
  const uint32_t *ptr;
  int_fast16_t shiftCount;
  uint32_t wordSig;
  ptr = extSigPtr + ((5) - 1);
  shiftCount = 0;
  for (;;) {
    wordSig = *ptr;
    if (wordSig)
      break;
    shiftCount += 32;
    if (160 <= shiftCount) {
      zWPtr[((4) - 1)] = (((uint32_t)(sign) << 31) + ((uint32_t)(0) << 16) + (0));
      zWPtr[(2)] = 0;
      zWPtr[(1)] = 0;
      zWPtr[(0)] = 0;
      return;
    }
    ptr -= 1;
  }
  shiftCount += softfloat_countLeadingZeros32(wordSig) - 15;
  if (shiftCount) {
    exp -= shiftCount;
    softfloat_shiftLeftM(5, extSigPtr, shiftCount, extSigPtr);
  }
  softfloat_roundPackMToF128M(sign, exp, extSigPtr, zWPtr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<softfloat_normRoundPackMToF128M>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    0x10(%rdx),%edi
  test   %edi,%edi
  jne    L7
  lea    0x10(%rdx),%rax
  mov    $0x20,%ebx
L12:
  mov    -0x4(%rax),%edi
  sub    $0x4,%rax
  test   %edi,%edi
  jne    L28
  add    $0x20,%ebx
  cmp    $0xa0,%ebx
  jne    L12
  shl    $0x1f,%ebp
  pop    %rbx
  movq   $0x0,(%r12)
  mov    %ebp,0xc(%r12)
  pop    %rbp
  movl   $0x0,0x8(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L7:
  xor    %ebx,%ebx
L28:
  call   <softfloat_countLeadingZeros32@plt>
  lea    -0xf(%rbx,%rax,1),%edx
  test   %edx,%edx
  jne    L24
L32:
  pop    %rbx
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <softfloat_roundPackMToF128M@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r13,%rcx
  mov    %r13,%rsi
  mov    $0x5,%edi
  sub    %edx,%r14d
  call   <softfloat_shiftLeftM@plt>
  jmp    L32
```

assistant: ```c
void softfloat_normRoundPackMToF128M(bool sign, int32_t exp, uint32_t *extSigPtr, uint32_t *zWPtr) {
  const uint32_t *ptr;
  int_fast16_t shiftCount;
  uint32_t wordSig;
  ptr = extSigPtr + ((5) - 1);
  shiftCount = 0;
  for (;;) {
    wordSig = *ptr;
    if (wordSig)
      break;
    shiftCount += 32;
    if (160 <= shiftCount) {
      zWPtr[((4) - 1)] = (((uint32_t)(sign) << 31) + ((uint32_t)(0) << 16) + (0));
      zWPtr[(2)] = 0;
      zWPtr[(1)] = 0;
      zWPtr[(0)] = 0;
      return;
    }
    ptr -= 1;
  }
  shiftCount += softfloat_countLeadingZeros32(wordSig) - 15;
  if (shiftCount) {
    exp -= shiftCount;
    softfloat_shiftLeftM(5, extSigPtr, shiftCount, extSigPtr);
  }
  softfloat_roundPackMToF128M(sign, exp, extSigPtr, zWPtr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<softfloat_normRoundPackMToF128M>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    0x10(%rdx),%edi
  test   %edi,%edi
  jne    L73
  mov    0xc(%rdx),%edi
  test   %edi,%edi
  jne    L83
  mov    0x8(%rdx),%edi
  test   %edi,%edi
  jne    L20
  mov    0x4(%rdx),%edi
  test   %edi,%edi
  jne    L17
  mov    (%rdx),%edi
  mov    $0x80,%ebx
  test   %edi,%edi
  jne    L41
  shl    $0x1f,%ebp
  pop    %rbx
  movl   $0x0,0x8(%r13)
  mov    %ebp,0xc(%r13)
  pop    %rbp
  movq   $0x0,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  xor    %ebx,%ebx
L41:
  call   <softfloat_countLeadingZeros32@plt>
  lea    -0xf(%rbx,%rax,1),%edx
  test   %edx,%edx
  jne    L52
L30:
  pop    %rbx
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <softfloat_roundPackMToF128M@plt>
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %r12,%rcx
  mov    %r12,%rsi
  mov    $0x5,%edi
  sub    %edx,%r14d
  call   <softfloat_shiftLeftM@plt>
  jmp    L30
  nopl   (%rax)
L83:
  mov    $0x20,%ebx
  jmp    L41
  nop
L20:
  mov    $0x40,%ebx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x60,%ebx
  jmp    L41
```

assistant: ```c
void softfloat_normRoundPackMToF128M(bool sign, int32_t exp, uint32_t *extSigPtr, uint32_t *zWPtr) {
  const uint32_t *ptr;
  int_fast16_t shiftCount;
  uint32_t wordSig;
  ptr = extSigPtr + ((5) - 1);
  shiftCount = 0;
  for (;;) {
    wordSig = *ptr;
    if (wordSig)
      break;
    shiftCount += 32;
    if (160 <= shiftCount) {
      zWPtr[((4) - 1)] = (((uint32_t)(sign) << 31) + ((uint32_t)(0) << 16) + (0));
      zWPtr[(2)] = 0;
      zWPtr[(1)] = 0;
      zWPtr[(0)] = 0;
      return;
    }
    ptr -= 1;
  }
  shiftCount += softfloat_countLeadingZeros32(wordSig) - 15;
  if (shiftCount) {
    exp -= shiftCount;
    softfloat_shiftLeftM(5, extSigPtr, shiftCount, extSigPtr);
  }
  softfloat_roundPackMToF128M(sign, exp, extSigPtr, zWPtr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<auth_parsetoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L2
L15:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int auth_parsetoken(char **line, char *buf, int len) {
  char *colon;
  colon = strchr(*line, ':');
  if (colon == NULL)
    return (1);
  *colon = 0;
  buf[len - 1] = 0;
  strncpy(buf, *line, len - 1);
  *line = colon + 1;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<auth_parsetoken>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x3a,%esi
  mov    (%rdi),%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L5
  movb   $0x0,(%rbx)
  movslq %r13d,%rax
  movb   $0x0,-0x1(%r12,%rax,1)
  lea    -0x1(%r13),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  add    $0x1,%rbx
  mov    %rbx,0x0(%rbp)
  mov    $0x0,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int auth_parsetoken(char **line, char *buf, int len) {
  char *colon;
  colon = strchr(*line, ':');
  if (colon == NULL)
    return (1);
  *colon = 0;
  buf[len - 1] = 0;
  strncpy(buf, *line, len - 1);
  *line = colon + 1;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<auth_parsetoken>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x3a,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L2
  movslq %ebp,%rax
  movb   $0x0,(%rbx)
  lea    -0x1(%rbp),%edx
  mov    %r13,%rdi
  movb   $0x0,-0x1(%r13,%rax,1)
  mov    (%r12),%rsi
  add    $0x1,%rbx
  call   <strncpy@plt>
  mov    %rbx,(%r12)
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int auth_parsetoken(char **line, char *buf, int len) {
  char *colon;
  colon = strchr(*line, ':');
  if (colon == NULL)
    return (1);
  *colon = 0;
  buf[len - 1] = 0;
  strncpy(buf, *line, len - 1);
  *line = colon + 1;
  return (0);
}
```