ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uppercase>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L3:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L3
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *uppercase(char *parm) {
  int parm_length = strlen(parm);
  for (int i = 0; i < parm_length; i++) {
    parm[i] = toupper((int)parm[i]);
  }
  return parm;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uppercase>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L14
  sub    $0x1,%eax
  mov    %r12,%rbx
  lea    0x1(%r12,%rax,1),%rbp
  nop
L17:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L17
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *uppercase(char *parm) {
  int parm_length = strlen(parm);
  for (int i = 0; i < parm_length; i++) {
    parm[i] = toupper((int)parm[i]);
  }
  return parm;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L9:
  cmpl   $0x3de,-0x4(%rbp)
  jle    L6
  mov    $0x10,%edi
  call   <foo@plt>
  jmp    L19
L6:
  mov    $0x8,%edi
  call   <foo@plt>
L19:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++) {
    if (i > 990)
      foo(16);
    else
      foo(8);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
L12:
  lea    -0x1(%rbx),%eax
  cmp    $0x3de,%eax
  jg     L19
  mov    $0x8,%edi
  call   <foo@plt>
L13:
  add    $0x1,%ebx
  jmp    L12
L19:
  mov    $0x10,%edi
  call   <foo@plt>
  cmp    $0x3e7,%ebx
  jle    L13
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++) {
    if (i > 990)
      foo(16);
    else
      foo(8);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  push   %rbx
  lea    0x1(%rax),%ebx
  cmp    $0x3de,%eax
  ja     L28
  nopl   0x0(%rax)
L25:
  mov    $0x8,%edi
  call   <foo@plt>
L22:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cmp    $0x3de,%eax
  jbe    L25
L28:
  mov    $0x10,%edi
  call   <foo@plt>
  cmp    $0x3e8,%ebx
  jne    L22
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++) {
    if (i > 990)
      foo(16);
    else
      foo(8);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  push   %rbx
  lea    0x1(%rax),%ebx
  cmp    $0x3de,%eax
  ja     L19
  nopl   0x0(%rax)
L8:
  mov    $0x8,%edi
  call   <foo@plt>
L18:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cmp    $0x3de,%eax
  jbe    L8
L19:
  mov    $0x10,%edi
  call   <foo@plt>
  cmp    $0x3e8,%ebx
  jne    L18
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++) {
    if (i > 990)
      foo(16);
    else
      foo(8);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: Programar es divertido.


assistant: ```c
int main(void) {
  printf("Programar es divertido.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: Programar es divertido.


assistant: ```c
int main(void) {
  printf("Programar es divertido.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D2: Programar es divertido.


assistant: ```c
int main(void) {
  printf("Programar es divertido.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: Programar es divertido.


assistant: ```c
int main(void) {
  printf("Programar es divertido.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_fwscanf_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfwscanf_s@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int my_fwscanf_s(FILE *stream, const wchar_t *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vfwscanf_s(stream, fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_fwscanf_s>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vfwscanf_s@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int my_fwscanf_s(FILE *stream, const wchar_t *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vfwscanf_s(stream, fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: What is the c source code of the assembly code below?

```asm
<my_fwscanf_s>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfwscanf_s@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_fwscanf_s(FILE *stream, const wchar_t *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vfwscanf_s(stream, fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_fwscanf_s>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfwscanf_s@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int my_fwscanf_s(FILE *stream, const wchar_t *fmt, ...) {
  va_list arg;
  int rc;
  va_start(arg, fmt);
  rc = vfwscanf_s(stream, fmt, arg);
  va_end(arg);
  return (rc);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cache_line_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  movq   $0x40,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const size_t cache_line_size() {
  size_t size;
  size = sysconf(_SC_LEVEL1_DCACHE_LINESIZE);
  if (size == 0)
    size = 64;
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cache_line_size>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  test   %rax,%rax
  mov    $0x40,%edx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
const size_t cache_line_size() {
  size_t size;
  size = sysconf(_SC_LEVEL1_DCACHE_LINESIZE);
  if (size == 0)
    size = 64;
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<cache_line_size>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x40,%edx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
const size_t cache_line_size() {
  size_t size;
  size = sysconf(_SC_LEVEL1_DCACHE_LINESIZE);
  if (size == 0)
    size = 64;
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cache_line_size>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x40,%edx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
const size_t cache_line_size() {
  size_t size;
  size = sysconf(_SC_LEVEL1_DCACHE_LINESIZE);
  if (size == 0)
    size = 64;
  return size;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L60
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L38
L60:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L19
L38:
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L53
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L31
L53:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L85
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edi
  cltd
  idiv   %edi
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L85:
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edi
  cltd
  idiv   %edi
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %ecx,%edx
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L31:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    %ecx,%esi
  imul   %edx,%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  imul   %ecx,%edx
  lea    (%rsi,%rdx,1),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D49
type: string
name: retrieve_data
arguments: tag: D39
type: string
name: retrieve_data
arguments: tag: D28
type: string

tool: D49: %d/%d + %d/%d

tool: D39: entrada invalida!

tool: D28: %d/%d


assistant: ```c
int main() {
  int a, b, c, d;
  scanf("%d/%d + %d/%d", &a, &b, &c, &d);
  if (b == 0 || d == 0)
    printf("entrada invalida!\n");
  else {
    if ((b % d == 0) || (d % b == 0)) {
      if (b > d)
        printf("%d/%d\n", (((b / b) * a) + ((b / d) * c)), b);
      else
        printf("%d/%d\n", (((d / b) * a) + ((d / d) * c)), d);
    } else
      printf("%d/%d\n", (a * d + c * b), (b * d));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D48(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  je     L7
  mov    0x14(%rsp),%edi
  test   %edi,%edi
  jne    L28
L7:
  lea    D47(%rip),%rdi
  call   <puts@plt>
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L28:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L58
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L0
L58:
  cmp    %edi,%ecx
  jle    L32
  mov    %ecx,%eax
  cltd
  idiv   %edi
  imul   0x10(%rsp),%eax
  add    0x8(%rsp),%eax
  mov    %eax,%esi
  mov    %ecx,%edx
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L32:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  imul   0x8(%rsp),%eax
  add    0x10(%rsp),%eax
  mov    %eax,%esi
  mov    %edi,%edx
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L0:
  mov    %ecx,%edx
  imul   %edi,%edx
  imul   0x8(%rsp),%edi
  imul   0x10(%rsp),%ecx
  lea    (%rdi,%rcx,1),%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D48
datatype: string
name: unpack_data
arguments: data_tag: D47
datatype: string
name: unpack_data
arguments: data_tag: D32
datatype: string

tool: D48: %d/%d + %d/%d

tool: D47: entrada invalida!

tool: D32: %d/%d


assistant: ```c
int main() {
  int a, b, c, d;
  scanf("%d/%d + %d/%d", &a, &b, &c, &d);
  if (b == 0 || d == 0)
    printf("entrada invalida!\n");
  else {
    if ((b % d == 0) || (d % b == 0)) {
      if (b > d)
        printf("%d/%d\n", (((b / b) * a) + ((b / d) * c)), b);
      else
        printf("%d/%d\n", (((d / b) * a) + ((d / d) * c)), d);
    } else
      printf("%d/%d\n", (a * d + c * b), (b * d));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D29(%rip),%rdi
  lea    0x14(%rsp),%r8
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  je     L88
  mov    0x14(%rsp),%r9d
  test   %r9d,%r9d
  jne    L81
L88:
  lea    D1(%rip),%rdi
  call   <puts@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L81:
  mov    %r8d,%eax
  mov    0x8(%rsp),%edi
  mov    0x10(%rsp),%ecx
  cltd
  idiv   %r9d
  mov    %eax,%esi
  test   %edx,%edx
  je     L4
  mov    %r9d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L4
  mov    %r8d,%edx
  imul   %ecx,%r8d
  xor    %eax,%eax
  imul   %r9d,%edx
  imul   %edi,%r9d
  lea    D45(%rip),%rdi
  lea    (%r9,%r8,1),%esi
  call   <printf@plt>
  jmp    L0
L4:
  cmp    %r9d,%r8d
  jle    L57
  imul   %ecx,%esi
  mov    %r8d,%edx
  xor    %eax,%eax
  add    %edi,%esi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L57:
  mov    %r9d,%eax
  cltd
  idiv   %r8d
  mov    %r9d,%edx
  imul   %edi,%eax
  lea    D45(%rip),%rdi
  lea    (%rax,%rcx,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D45
type_infered: string

tool: D29: %d/%d + %d/%d

tool: D1: entrada invalida!

tool: D45: %d/%d


assistant: ```c
int main() {
  int a, b, c, d;
  scanf("%d/%d + %d/%d", &a, &b, &c, &d);
  if (b == 0 || d == 0)
    printf("entrada invalida!\n");
  else {
    if ((b % d == 0) || (d % b == 0)) {
      if (b > d)
        printf("%d/%d\n", (((b / b) * a) + ((b / d) * c)), b);
      else
        printf("%d/%d\n", (((d / b) * a) + ((d / d) * c)), d);
    } else
      printf("%d/%d\n", (a * d + c * b), (b * d));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D32(%rip),%rdi
  lea    0x14(%rsp),%r8
  lea    0x10(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  je     L1
  mov    0x14(%rsp),%r9d
  test   %r9d,%r9d
  jne    L28
L1:
  lea    D22(%rip),%rdi
  call   <puts@plt>
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L28:
  mov    %r8d,%eax
  mov    0x8(%rsp),%edi
  mov    0x10(%rsp),%ecx
  cltd
  idiv   %r9d
  mov    %eax,%esi
  test   %edx,%edx
  je     L35
  mov    %r9d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L35
  mov    %r8d,%edx
  imul   %ecx,%r8d
  xor    %eax,%eax
  imul   %r9d,%edx
  imul   %edi,%r9d
  lea    D17(%rip),%rdi
  lea    (%r9,%r8,1),%esi
  call   <printf@plt>
  jmp    L43
L35:
  cmp    %r9d,%r8d
  jle    L48
  imul   %ecx,%esi
  mov    %r8d,%edx
  xor    %eax,%eax
  add    %edi,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L48:
  mov    %r9d,%eax
  cltd
  idiv   %r8d
  mov    %r9d,%edx
  imul   %edi,%eax
  lea    D17(%rip),%rdi
  lea    (%rax,%rcx,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D22
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string

tool: D32: %d/%d + %d/%d

tool: D22: entrada invalida!

tool: D17: %d/%d


assistant: ```c
int main() {
  int a, b, c, d;
  scanf("%d/%d + %d/%d", &a, &b, &c, &d);
  if (b == 0 || d == 0)
    printf("entrada invalida!\n");
  else {
    if ((b % d == 0) || (d % b == 0)) {
      if (b > d)
        printf("%d/%d\n", (((b / b) * a) + ((b / d) * c)), b);
      else
        printf("%d/%d\n", (((d / b) * a) + ((d / d) * c)), d);
    } else
      printf("%d/%d\n", (a * d + c * b), (b * d));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isValueInIntArr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L14
  mov    $0x1,%eax
  jmp    L1
L14:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L28
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int isValueInIntArr(int val, const int *arr, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (*(arr + i) == val)
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isValueInIntArr>:
  endbr64
  test   %edx,%edx
  jle    L25
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%rdx
L3:
  cmp    %edi,(%rax)
  je     L28
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
  mov    $0x0,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isValueInIntArr(int val, const int *arr, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (*(arr + i) == val)
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isValueInIntArr>:
  endbr64
  test   %edx,%edx
  jle    L14
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x4,%rsi
  cmp    %rax,%rsi
  je     L14
L9:
  cmp    %edi,(%rsi)
  jne    L17
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isValueInIntArr(int val, const int *arr, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (*(arr + i) == val)
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isValueInIntArr>:
  endbr64
  test   %edx,%edx
  jle    L27
  lea    -0x1(%rdx),%eax
  lea    0x4(%rsi,%rax,4),%rax
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x4,%rsi
  cmp    %rax,%rsi
  je     L27
L31:
  cmp    %edi,(%rsi)
  jne    L1
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isValueInIntArr(int val, const int *arr, int size) {
  int i;
  for (i = 0; i < size; i++)
    if (*(arr + i) == val)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int g(int j) {
  int a[10];
  return a[j + 1];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<g>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  add    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(int j) {
  int a[10];
  return a[j + 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  sub    $0x38,%rsp
  add    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(int j) {
  int a[10];
  return a[j + 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<g>:
  endbr64
  sub    $0x38,%rsp
  add    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(int j) {
  int a[10];
  return a[j + 1];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6548,-0xe(%rbp)
  movw   $0x6f,-0xa(%rbp)
  movw   $0x6f79,-0x11(%rbp)
  movb   $0x0,-0xf(%rbp)
  lea    -0x11(%rbp),%rdx
  lea    -0xe(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <squeeze@plt>
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %s


assistant: ```c
int main() {
  char s1[] = "Hello";
  char s2[] = "yo";
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```