user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D20(%rip),%rsi
  xor    %edx,%edx
  push   %r13
  lea    D85(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%r12
  mov    %rsi,0x20(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  lea    D72(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D116(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D27(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D48(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D30(%rip),%rax
  mov    %rax,0x48(%rsp)
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L82:
  mov    (%r12,%rbp,1),%edx
  mov    (%rbx,%rbp,2),%rsi
L66:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x18,%rbp
  jne    L82
  lea    D1(%rip),%r14
  xor    %ebp,%ebp
  mov    %r14,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rsi
  xor    %edx,%edx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L33:
  mov    (%r12,%rbp,1),%edx
  mov    (%rbx,%rbp,2),%rsi
L18:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x18,%rbp
  jne    L33
  mov    %r14,%rdi
  xor    %ebp,%ebp
  call   <puts@plt>
  lea    D20(%rip),%rsi
  xor    %edx,%edx
  jmp    L89
  nopl   0x0(%rax)
L2:
  mov    (%r12,%rbp,1),%edx
  mov    (%rbx,%rbp,2),%rsi
L89:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x18,%rbp
  jne    L2
  mov    %r14,%rdi
  mov    %r12,%rbp
  lea    D115(%rip),%r13
  call   <puts@plt>
  lea    D20(%rip),%rsi
  xor    %edx,%edx
  jmp    L14
  nopl   0x0(%rax)
L27:
  mov    0x0(%rbp),%edx
  mov    (%rbx),%rsi
L14:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rax
  sub    %r12,%rax
  cmp    $0x14,%rax
  jle    L27
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D85
data_type: string
name: disassemble_data
arguments: data_tag: D72
data_type: string
name: disassemble_data
arguments: data_tag: D116
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D48
data_type: string
name: disassemble_data
arguments: data_tag: D30
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string
name: disassemble_data
arguments: data_tag: D115
data_type: string

tool: D20: Nope

tool: D85: %s, is %d old.


tool: D72: Allice

tool: D116: Bob

tool: D27: Charlie

tool: D48: Dog

tool: D30: Europe

tool: D1: -------------NEWLINE-------------

tool: D115: %s,is%dold.


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {0, 1, 2, 3, 4, 5};
  char *names[] = {"Nope", "Allice", "Bob", "Charlie", "Dog", "Europe"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%s, is %d old.\n", names[i], ages[i]);
  }
  printf("-------------NEWLINE-------------\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count; i++) {
    printf("%s, is %d old.\n", *(cur_name + i), *(cur_age + i));
  }
  printf("-------------NEWLINE-------------\n");
  for (i = 0; i < count; i++) {
    printf("%s, is %d old.\n", cur_name[i], cur_age[i]);
  }
  printf("-------------NEWLINE-------------\n");
  for (cur_name = names, cur_age = ages; (cur_age - ages) < count; cur_name++, cur_age++) {
    printf("%s,is%dold.\n", *cur_name, *cur_age);
  }
  return 0;
}
```