ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_bubble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L36
L69:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L36:
  cmpl   $0x6,-0x10(%rbp)
  jle    L69
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L16
L46:
  cmpl   $0x6,-0x8(%rbp)
  jg     L11
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L11
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0xc(%rbp)
  jle    L16
  subl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
  jmp    L16
L11:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x6,-0xc(%rbp)
  jle    L46
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_bubble(int input[], int output[]) {
  for (int i = 0; i < 7; ++i) {
    output[i] = input[i];
  }
  int current = 0;
  int next = 1;
  while (current < 7) {
    if (next < 7 && output[current] > output[next]) {
      int swap = output[current];
      output[current] = output[next];
      output[next] = swap;
      if (current > 0) {
        --current;
        --next;
      }
    } else {
      ++current;
      ++next;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_bubble>:
  endbr64
  mov    $0x0,%eax
L24:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    $0x1c,%rax
  jne    L24
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L31
L33:
  add    $0x1,%eax
  add    $0x1,%edx
L36:
  cmp    $0x6,%eax
  jg     L37
L31:
  cmp    $0x6,%edx
  jg     L33
  movslq %eax,%rcx
  lea    (%rsi,%rcx,4),%r8
  mov    (%r8),%edi
  movslq %edx,%rcx
  lea    (%rsi,%rcx,4),%rcx
  mov    (%rcx),%r9d
  cmp    %r9d,%edi
  jle    L33
  mov    %r9d,(%r8)
  mov    %edi,(%rcx)
  test   %eax,%eax
  jle    L36
  sub    $0x1,%eax
  sub    $0x1,%edx
  jmp    L36
L37:
  ret
```

assistant: ```c
void sort_bubble(int input[], int output[]) {
  for (int i = 0; i < 7; ++i) {
    output[i] = input[i];
  }
  int current = 0;
  int next = 1;
  while (current < 7) {
    if (next < 7 && output[current] > output[next]) {
      int swap = output[current];
      output[current] = output[next];
      output[next] = swap;
      if (current > 0) {
        --current;
        --next;
      }
    } else {
      ++current;
      ++next;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort_bubble>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    $0x1c,%rax
  jne    L5
  mov    $0x1,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  cmp    $0x6,%edx
  jg     L45
  movslq %eax,%rcx
  lea    (%rsi,%rcx,4),%r8
  movslq %edx,%rcx
  lea    (%rsi,%rcx,4),%rcx
  mov    (%r8),%edi
  mov    (%rcx),%r9d
  cmp    %r9d,%edi
  jle    L45
  mov    %r9d,(%r8)
  mov    %edi,(%rcx)
  test   %eax,%eax
  je     L9
  sub    $0x1,%eax
  sub    $0x1,%edx
  nopl   (%rax)
L11:
  cmp    $0x7,%eax
  jne    L9
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  add    $0x1,%eax
  add    $0x1,%edx
  jmp    L11
```

assistant: ```c
void sort_bubble(int input[], int output[]) {
  for (int i = 0; i < 7; ++i) {
    output[i] = input[i];
  }
  int current = 0;
  int next = 1;
  while (current < 7) {
    if (next < 7 && output[current] > output[next]) {
      int swap = output[current];
      output[current] = output[next];
      output[next] = swap;
      if (current > 0) {
        --current;
        --next;
      }
    } else {
      ++current;
      ++next;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_bubble>:
  endbr64
  lea    0x4(%rdi),%rcx
  mov    %rsi,%rdx
  mov    %rsi,%rax
  sub    %rcx,%rdx
  cmp    $0x8,%rdx
  jbe    L12
  movdqu (%rdi),%xmm0
  movups %xmm0,(%rsi)
  mov    0x10(%rdi),%rdx
  mov    %rdx,0x10(%rsi)
  mov    0x18(%rdi),%edx
  mov    %edx,0x18(%rsi)
L63:
  mov    $0x1,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    $0x6,%ecx
  jg     L46
  movslq %edx,%rsi
  lea    (%rax,%rsi,4),%r8
  movslq %ecx,%rsi
  lea    (%rax,%rsi,4),%rsi
  mov    (%r8),%edi
  mov    (%rsi),%r9d
  cmp    %r9d,%edi
  jle    L46
  mov    %r9d,(%r8)
  mov    %edi,(%rsi)
  test   %edx,%edx
  je     L26
  sub    $0x1,%edx
  sub    $0x1,%ecx
  nopl   (%rax)
L30:
  cmp    $0x7,%edx
  jne    L26
  ret
  xchg   %ax,%ax
L46:
  add    $0x1,%edx
  add    $0x1,%ecx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    0x4(%rdi),%edx
  mov    %edx,0x4(%rsi)
  mov    0x8(%rdi),%edx
  mov    %edx,0x8(%rsi)
  mov    0xc(%rdi),%edx
  mov    %edx,0xc(%rsi)
  mov    0x10(%rdi),%edx
  mov    %edx,0x10(%rsi)
  mov    0x14(%rdi),%edx
  mov    %edx,0x14(%rsi)
  mov    0x18(%rdi),%edx
  mov    %edx,0x18(%rsi)
  jmp    L63
```

assistant: ```c
void sort_bubble(int input[], int output[]) {
  for (int i = 0; i < 7; ++i) {
    output[i] = input[i];
  }
  int current = 0;
  int next = 1;
  while (current < 7) {
    if (next < 7 && output[current] > output[next]) {
      int swap = output[current];
      output[current] = output[next];
      output[next] = swap;
      if (current > 0) {
        --current;
        --next;
      }
    } else {
      ++current;
      ++next;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_base64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rsi
  mov    $0x12,%ecx
  mov    $0x0,%edi
  mov    $0x40,%ebx
  mov    $0x60,%r11d
  mov    $0x2f,%r10d
  mov    $0x2a,%r9d
  mov    $0x2e,%r8d
L9:
  movsbl (%rsi),%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  lea    -0x5b(%rax),%edx
  and    %edx,%ebp
  sar    $0x8,%ebp
  lea    -0x40(%rax),%edx
  and    %edx,%ebp
  mov    %r11d,%edx
  sub    %eax,%edx
  lea    -0x7b(%rax),%r12d
  and    %r12d,%edx
  sar    $0x8,%edx
  lea    -0x46(%rax),%r12d
  and    %r12d,%edx
  lea    -0x1(%rbp,%rdx,1),%edx
  mov    %r10d,%ebp
  sub    %eax,%ebp
  lea    -0x3a(%rax),%r12d
  and    %r12d,%ebp
  sar    $0x8,%ebp
  lea    0x5(%rax),%r12d
  and    %r12d,%ebp
  add    %ebp,%edx
  mov    %r9d,%ebp
  sub    %eax,%ebp
  lea    -0x2c(%rax),%r12d
  and    %r12d,%ebp
  shr    $0x1a,%ebp
  add    %ebp,%edx
  mov    %r8d,%ebp
  sub    %eax,%ebp
  sub    $0x30,%eax
  and    %ebp,%eax
  sar    $0x8,%eax
  and    $0x40,%eax
  add    %edx,%eax
  shl    %cl,%eax
  or     %eax,%edi
  add    $0x1,%rsi
  sub    $0x6,%ecx
  cmp    $0xfffffffa,%ecx
  jne    L9
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int decode_base64(const char src[4]) {
  int val = 0;
  for (unsigned int i = 0; i < 4; ++i)
    val |= (-1 + ((((('A' - 1) - src[i]) & (src[i] - ('Z' + 1))) >> 8) & (src[i] - 64)) + ((((('a' - 1) - src[i]) & (src[i] - ('z' + 1))) >> 8) & (src[i] - 70)) + ((((('0' - 1) - src[i]) & (src[i] - ('9' + 1))) >> 8) & (src[i] + 5)) + ((((('+' - 1) - src[i]) & (src[i] - ('+' + 1))) >> 8) & 63) + ((((('/' - 1) - src[i]) & (src[i] - ('/' + 1))) >> 8) & 64)) << (18 - 6 * i);
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decode_base64>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x12,%ecx
  xor    %r8d,%r8d
  push   %rbp
  mov    $0x60,%r11d
  mov    $0x2e,%edi
  mov    $0x2f,%r10d
  push   %rbx
  mov    $0x2a,%r9d
  mov    $0x40,%ebx
L7:
  movsbl (%rsi),%eax
  mov    %ebx,%ebp
  add    $0x1,%rsi
  lea    -0x5b(%rax),%edx
  sub    %eax,%ebp
  lea    -0x7b(%rax),%r12d
  and    %edx,%ebp
  lea    -0x40(%rax),%edx
  sar    $0x8,%ebp
  and    %edx,%ebp
  mov    %r11d,%edx
  sub    %eax,%edx
  and    %r12d,%edx
  lea    -0x46(%rax),%r12d
  sar    $0x8,%edx
  and    %r12d,%edx
  lea    -0x3a(%rax),%r12d
  lea    -0x1(%rbp,%rdx,1),%edx
  mov    %r10d,%ebp
  sub    %eax,%ebp
  and    %r12d,%ebp
  lea    0x5(%rax),%r12d
  sar    $0x8,%ebp
  and    %r12d,%ebp
  lea    -0x2c(%rax),%r12d
  add    %ebp,%edx
  mov    %r9d,%ebp
  sub    %eax,%ebp
  and    %r12d,%ebp
  sar    $0x8,%ebp
  and    $0x3f,%ebp
  add    %ebp,%edx
  mov    %edi,%ebp
  sub    %eax,%ebp
  sub    $0x30,%eax
  and    %ebp,%eax
  sar    $0x8,%eax
  and    $0x40,%eax
  add    %edx,%eax
  shl    %cl,%eax
  sub    $0x6,%ecx
  or     %eax,%r8d
  cmp    $0xfffffffa,%ecx
  jne    L7
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int decode_base64(const char src[4]) {
  int val = 0;
  for (unsigned int i = 0; i < 4; ++i)
    val |= (-1 + ((((('A' - 1) - src[i]) & (src[i] - ('Z' + 1))) >> 8) & (src[i] - 64)) + ((((('a' - 1) - src[i]) & (src[i] - ('z' + 1))) >> 8) & (src[i] - 70)) + ((((('0' - 1) - src[i]) & (src[i] - ('9' + 1))) >> 8) & (src[i] + 5)) + ((((('+' - 1) - src[i]) & (src[i] - ('+' + 1))) >> 8) & 63) + ((((('/' - 1) - src[i]) & (src[i] - ('/' + 1))) >> 8) & 64)) << (18 - 6 * i);
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mul_splitl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  fldt   0x10(%rbp)
  fldt   0x20(%rbp)
  fmulp  %st,%st(1)
  mov    -0x48(%rbp),%rax
  fstpt  (%rax)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x58(%rbp)
  fildll -0x58(%rbp)
  fldt   0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x40(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x58(%rbp)
  fildll -0x58(%rbp)
  fldt   0x20(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x30(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x40(%rbp)
  fsubrp %st,%st(1)
  fldt   -0x40(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x40(%rbp)
  fldt   0x20(%rbp)
  fldt   -0x30(%rbp)
  fsubrp %st,%st(1)
  fldt   -0x30(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x30(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x40(%rbp)
  fsubrp %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   0x20(%rbp)
  fldt   -0x30(%rbp)
  fsubrp %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   -0x40(%rbp)
  fldt   -0x30(%rbp)
  fmulp  %st,%st(1)
  mov    -0x48(%rbp),%rax
  fldt   (%rax)
  fsubrp %st,%st(1)
  fldt   -0x40(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fldt   -0x20(%rbp)
  fldt   -0x30(%rbp)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fldt   -0x20(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  mov    -0x50(%rbp),%rax
  fstpt  (%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mul_splitl(long double *hi, long double *lo, long double x, long double y) {
  *hi = x * y;
  long double x1 = x * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  long double y1 = y * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  x1 = (x - x1) + x1;
  y1 = (y - y1) + y1;
  long double x2 = x - x1;
  long double y2 = y - y1;
  *lo = (((x1 * y1 - *hi) + x1 * y2) + x2 * y1) + x2 * y2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mul_splitl>:
  endbr64
  fldt   0x8(%rsp)
  fldt   0x18(%rsp)
  fld    %st(1)
  fmul   %st(1),%st
  fld    %st(0)
  fstpt  (%rdi)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  fld    %st(0)
  fmul   %st(4),%st
  fxch   %st(1)
  fmul   %st(3),%st
  fld    %st(4)
  fsub   %st(2),%st
  faddp  %st,%st(2)
  fld    %st(3)
  fsub   %st(1),%st
  faddp  %st,%st(1)
  fxch   %st(4)
  fsub   %st(1),%st
  fxch   %st(3)
  fsub   %st(4),%st
  fld    %st(1)
  fmul   %st(5),%st
  fsubp  %st,%st(3)
  fmul   %st,%st(1)
  fxch   %st(2)
  faddp  %st,%st(1)
  fxch   %st(3)
  fmul   %st(2),%st
  faddp  %st,%st(3)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fstpt  (%rsi)
  ret
```

assistant: ```c
void mul_splitl(long double *hi, long double *lo, long double x, long double y) {
  *hi = x * y;
  long double x1 = x * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  long double y1 = y * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  x1 = (x - x1) + x1;
  y1 = (y - y1) + y1;
  long double x2 = x - x1;
  long double y2 = y - y1;
  *lo = (((x1 * y1 - *hi) + x1 * y2) + x2 * y1) + x2 * y2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mul_splitl>:
  endbr64
  mov    D7(%rip),%rax
  fldt   0x8(%rsp)
  mov    (%rax),%eax
  fldt   0x18(%rsp)
  add    $0x1,%eax
  mov    %eax,%ecx
  fld    %st(1)
  shr    $0x1f,%ecx
  fmul   %st(1),%st
  add    %eax,%ecx
  mov    $0x1,%eax
  sar    %ecx
  shl    %cl,%rax
  add    $0x1,%rax
  fld    %st(0)
  fstpt  (%rdi)
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  fld    %st(0)
  fmul   %st(4),%st
  fxch   %st(1)
  fmul   %st(3),%st
  fld    %st(4)
  fsub   %st(2),%st
  faddp  %st,%st(2)
  fld    %st(3)
  fsub   %st(1),%st
  faddp  %st,%st(1)
  fxch   %st(4)
  fsub   %st(1),%st
  fxch   %st(3)
  fsub   %st(4),%st
  fld    %st(1)
  fmul   %st(5),%st
  fsubp  %st,%st(3)
  fmul   %st,%st(1)
  fxch   %st(2)
  faddp  %st,%st(1)
  fxch   %st(3)
  fmul   %st(2),%st
  faddp  %st,%st(3)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fstpt  (%rsi)
  ret
```

assistant: ```c
void mul_splitl(long double *hi, long double *lo, long double x, long double y) {
  *hi = x * y;
  long double x1 = x * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  long double y1 = y * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  x1 = (x - x1) + x1;
  y1 = (y - y1) + y1;
  long double x2 = x - x1;
  long double y2 = y - y1;
  *lo = (((x1 * y1 - *hi) + x1 * y2) + x2 * y1) + x2 * y2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mul_splitl>:
  endbr64
  mov    D5(%rip),%rax
  fldt   0x8(%rsp)
  mov    (%rax),%eax
  fldt   0x18(%rsp)
  add    $0x1,%eax
  mov    %eax,%ecx
  fld    %st(1)
  shr    $0x1f,%ecx
  fmul   %st(1),%st
  add    %eax,%ecx
  mov    $0x1,%eax
  sar    %ecx
  shl    %cl,%rax
  add    $0x1,%rax
  fld    %st(0)
  fstpt  (%rdi)
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  fld    %st(0)
  fmul   %st(4),%st
  fxch   %st(1)
  fmul   %st(3),%st
  fld    %st(4)
  fsub   %st(2),%st
  faddp  %st,%st(2)
  fld    %st(3)
  fsub   %st(1),%st
  faddp  %st,%st(1)
  fxch   %st(4)
  fsub   %st(1),%st
  fxch   %st(3)
  fsub   %st(4),%st
  fld    %st(1)
  fmul   %st(5),%st
  fsubp  %st,%st(3)
  fmul   %st,%st(1)
  fxch   %st(2)
  faddp  %st,%st(1)
  fxch   %st(3)
  fmul   %st(2),%st
  faddp  %st,%st(3)
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  fstpt  (%rsi)
  ret
```

assistant: ```c
void mul_splitl(long double *hi, long double *lo, long double x, long double y) {
  *hi = x * y;
  long double x1 = x * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  long double y1 = y * ((1LL << (LDBL_MANT_DIG + 1) / 2) + 1);
  x1 = (x - x1) + x1;
  y1 = (y - y1) + y1;
  long double x2 = x - x1;
  long double y2 = y - y1;
  *lo = (((x1 * y1 - *hi) + x1 * y2) + x2 * y1) + x2 * y2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gnomeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L48:
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L20
  addl   $0x1,-0x4(%rbp)
  jmp    L39
L20:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L48
  nop
  leave
  ret
```

assistant: ```c
void gnomeSort(int arr[], int n) {
  int index = 0;
  while (index < n) {
    if (index == 0)
      ++index;
    if (arr[index] >= arr[index - 1])
      ++index;
    else {
      swap(&arr[index], &arr[index - 1]);
      --index;
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<gnomeSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x1,%ebx
  mov    $0x1,%r13d
  test   %esi,%esi
  jg     L24
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  add    $0x1,%ebx
L32:
  cmp    %r12d,%ebx
  jge    L38
  test   %ebx,%ebx
  cmove  %r13d,%ebx
L24:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  lea    -0x4(%rbp,%rax,1),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jge    L31
  call   <swap@plt>
  sub    $0x1,%ebx
  jmp    L32
```

assistant: ```c
void gnomeSort(int arr[], int n) {
  int index = 0;
  while (index < n) {
    if (index == 0)
      ++index;
    if (arr[index] >= arr[index - 1])
      ++index;
    else {
      swap(&arr[index], &arr[index - 1]);
      --index;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gnomeSort>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  test   %esi,%esi
  jle    L34
  nopw   0x0(%rax,%rax,1)
L17:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  lea    -0x4(%rbp,%rax,1),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jl     L26
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L17
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  call   <swap@plt>
  sub    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L34
  test   %ebx,%ebx
  jne    L17
  mov    $0x1,%ebx
  jmp    L17
```

assistant: ```c
void gnomeSort(int arr[], int n) {
  int index = 0;
  while (index < n) {
    if (index == 0)
      ++index;
    if (arr[index] >= arr[index - 1])
      ++index;
    else {
      swap(&arr[index], &arr[index - 1]);
      --index;
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gnomeSort>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  test   %esi,%esi
  jle    L14
  nopw   0x0(%rax,%rax,1)
L25:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  lea    -0x4(%rbp,%rax,1),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jl     L58
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L25
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L58:
  call   <swap@plt>
  sub    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L14
  test   %ebx,%ebx
  jne    L25
  mov    $0x1,%ebx
  jmp    L25
```

assistant: ```c
void gnomeSort(int arr[], int n) {
  int index = 0;
  while (index < n) {
    if (index == 0)
      ++index;
    if (arr[index] >= arr[index - 1])
      ++index;
    else {
      swap(&arr[index], &arr[index - 1]);
      --index;
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stdlib_strided_snanmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jg     L195
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L34
L195:
  cmpq   $0x1,-0x28(%rbp)
  je     L120
  cmpq   $0x0,-0x38(%rbp)
  jne    L30
L120:
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  jmp    L34
L30:
  cmpq   $0x0,-0x38(%rbp)
  jns    L64
  mov    $0x1,%eax
  sub    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L35
L64:
  movq   $0x0,-0x10(%rbp)
L35:
  movq   $0x0,-0x8(%rbp)
  jmp    L206
L66:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  ucomiss -0x14(%rbp),%xmm0
  jnp    L169
  mov    -0x38(%rbp),%rax
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L206:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L66
  jmp    L17
L169:
  nop
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L180
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L34
L180:
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L163
L111:
  mov    -0x38(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <stdlib_base_is_nanf@plt>
  test   %rax,%rax
  jne    L32
  movss  -0x14(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  ja     L23
  movss  -0x14(%rbp),%xmm0
  ucomiss -0x18(%rbp),%xmm0
  jp     L95
  movss  -0x14(%rbp),%xmm0
  ucomiss -0x18(%rbp),%xmm0
  jne    L95
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <stdlib_base_is_positive_zerof@plt>
  test   %rax,%rax
  je     L95
L23:
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L95
L32:
  nop
L95:
  addq   $0x1,-0x8(%rbp)
L163:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L111
  movss  -0x18(%rbp),%xmm0
L34:
  leave
  ret
```

assistant: ```c
float stdlib_strided_snanmax(const int64_t N, const float *X, const int64_t stride) {
  int64_t ix;
  int64_t i;
  float max;
  float v;
  if (N <= 0) {
    return 0.0f / 0.0f;
  }
  if (N == 1 || stride == 0) {
    return X[0];
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    v = X[ix];
    if (v == v) {
      break;
    }
    ix += stride;
  }
  if (i == N) {
    return 0.0f / 0.0f;
  }
  max = v;
  i += 1;
  for (; i < N; i++) {
    ix += stride;
    v = X[ix];
    if (stdlib_base_is_nanf(v)) {
      continue;
    }
    if (v > max || (v == max && stdlib_base_is_positive_zerof(v))) {
      max = v;
    }
  }
  return max;
}
```