ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VolumeAveragedVOFCoefficientsEvaluate>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    0x30(%rsp),%r13
  mov    0x38(%rsp),%r14
  mov    0x40(%rsp),%r10
  mov    0x48(%rsp),%r11
  test   %ebp,%ebp
  jle    L1
  lea    -0x1(%rsi),%r12d
  mov    %rdx,%rcx
  mov    %r9,%rdi
  mov    %r8,%rdx
  mov    %esi,%ebx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  add    $0x1,%r12
  nopl   0x0(%rax)
L13:
  movsd  (%rdi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,0x0(%r13,%r8,8)
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%r14,%r8,8)
  test   %ebx,%ebx
  jle    L26
  movslq %r9d,%rsi
  lea    0x0(,%rsi,8),%rax
  add    %r12,%rsi
  shl    $0x3,%rsi
  nopw   0x0(%rax,%rax,1)
L28:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,(%r10,%rax,1)
  movsd  (%rdx),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%r11,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L28
L26:
  add    $0x1,%r8
  add    $0x8,%rdi
  add    $0x8,%rdx
  add    %ebx,%r9d
  cmp    %rbp,%r8
  jne    L13
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void VolumeAveragedVOFCoefficientsEvaluate(int nPoints, int nSpace, double eps, double *v, double *phi, double *porosity, double *u, double *m, double *dm, double *f, double *df) {
  int i, I;
  for (i = 0; i < nPoints; i++) {
    m[i] = u[i] * porosity[i];
    dm[i] = porosity[i];
    for (I = 0; I < nSpace; I++) {
      f[i * nSpace + I] = porosity[i] * v[i * nSpace + I] * u[i];
      df[i * nSpace + I] = porosity[i] * v[i * nSpace + I];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtod_buffer_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L3:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <valid_number_character@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int strtod_buffer_size(const char *s) {
  const char *p = s;
  while (valid_number_character(*p))
    p++;
  return (int)(p - s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtod_buffer_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L18
L16:
  add    $0x1,%rbx
L18:
  movsbl (%rbx),%edi
  call   <valid_number_character@plt>
  test   %rax,%rax
  jne    L16
  mov    %ebx,%eax
  sub    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strtod_buffer_size(const char *s) {
  const char *p = s;
  while (valid_number_character(*p))
    p++;
  return (int)(p - s);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtod_buffer_size>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rbx
L18:
  movsbl (%rbx),%edi
  call   <valid_number_character@plt>
  test   %rax,%rax
  jne    L6
  mov    %ebx,%eax
  add    $0x8,%rsp
  sub    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strtod_buffer_size(const char *s) {
  const char *p = s;
  while (valid_number_character(*p))
    p++;
  return (int)(p - s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtod_buffer_size>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rbx
L5:
  movsbl (%rbx),%edi
  call   <valid_number_character@plt>
  test   %rax,%rax
  jne    L13
  mov    %ebx,%eax
  add    $0x8,%rsp
  sub    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strtod_buffer_size(const char *s) {
  const char *p = s;
  while (valid_number_character(*p))
    p++;
  return (int)(p - s);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unl@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: cannot %s


assistant: ```c
err(c) char c[];
{
  register j;
  printf("cannot %s\n", c);
  unl();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <unl@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: cannot %s


assistant: ```c
err(c) char c[];
{
  register j;
  printf("cannot %s\n", c);
  unl();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <unl@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: cannot %s


assistant: ```c
err(c) char c[];
{
  register j;
  printf("cannot %s\n", c);
  unl();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <unl@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: cannot %s


assistant: ```c
err(c) char c[];
{
  register j;
  printf("cannot %s\n", c);
  unl();
}
```
user: Translate the below assembly code into C programming language:

```asm
<rb_genrand_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rb_genrand_int32@plt>
  sar    $0x5,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rb_genrand_int32@plt>
  sar    $0x6,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  js     L33
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L28
L33:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L28:
  movsd  D8(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L2
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L32
L2:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L32:
  addsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: f64
name: parse_data
arguments: data_tag: D0
data_type: byte[8]

tool: D8: 67108864

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xa0,0x3c]}

assistant: ```c
double rb_genrand_real(void) {
  unsigned long a = rb_genrand_int32() >> 5, b = rb_genrand_int32() >> 6;
  return (a * 67108864.0 + b) * (1.0 / 9007199254740992.0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rb_genrand_real>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rb_genrand_int32@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rb_genrand_int32@plt>
  sar    $0x5,%ebx
  movslq %ebx,%rdx
  test   %rdx,%rdx
  js     L9
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L4:
  mulsd  D12(%rip),%xmm0
  sar    $0x6,%eax
  cltq
  test   %rax,%rax
  js     L15
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
L17:
  addsd  %xmm1,%xmm0
  mulsd  D13(%rip),%xmm0
  pop    %rbx
  ret
L9:
  mov    %rdx,%rcx
  shr    %rcx
  and    $0x1,%edx
  or     %rdx,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L4
L15:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type: f64
name: extract_symbolic_data
arguments: data_label: D13
type: byte[8]

tool: D12: 67108864

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xa0,0x3c]}

assistant: ```c
double rb_genrand_real(void) {
  unsigned long a = rb_genrand_int32() >> 5, b = rb_genrand_int32() >> 6;
  return (a * 67108864.0 + b) * (1.0 / 9007199254740992.0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rb_genrand_real>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <rb_genrand_int32@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rb_genrand_int32@plt>
  sar    $0x5,%ebx
  movslq %ebx,%rdx
  test   %rdx,%rdx
  js     L9
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L24:
  mulsd  D1(%rip),%xmm0
  sar    $0x6,%eax
  cltq
  test   %rax,%rax
  js     L22
  pxor   %xmm1,%xmm1
  pop    %rbx
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D11(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rdx,%rcx
  and    $0x1,%edx
  pxor   %xmm0,%xmm0
  shr    %rcx
  or     %rdx,%rcx
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  pop    %rbx
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm1
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D11(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: f64
name: read_data
arguments: label: D11
type_infered: byte[8]

tool: D1: 67108864

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xa0,0x3c]}

assistant: ```c
double rb_genrand_real(void) {
  unsigned long a = rb_genrand_int32() >> 5, b = rb_genrand_int32() >> 6;
  return (a * 67108864.0 + b) * (1.0 / 9007199254740992.0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rb_genrand_real>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <rb_genrand_int32@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rb_genrand_int32@plt>
  sar    $0x5,%ebx
  movslq %ebx,%rdx
  test   %rdx,%rdx
  js     L11
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L14:
  mulsd  D26(%rip),%xmm0
  sar    $0x6,%eax
  cltq
  test   %rax,%rax
  js     L29
  pxor   %xmm1,%xmm1
  pop    %rbx
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D21(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rdx,%rcx
  and    $0x1,%edx
  pxor   %xmm0,%xmm0
  shr    %rcx
  or     %rdx,%rcx
  cvtsi2sd %rcx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  pop    %rbx
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm1
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D21(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D21
type_guessed: byte[8]

tool: D26: 67108864

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xa0,0x3c]}

assistant: ```c
double rb_genrand_real(void) {
  unsigned long a = rb_genrand_int32() >> 5, b = rb_genrand_int32() >> 6;
  return (a * 67108864.0 + b) * (1.0 / 9007199254740992.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L24:
  cmpl   $0x1fc0,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L39
L8:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L39:
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L24
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argv[1][0]; i++) {
    if (sum > 8128)
      sum *= i;
    else
      sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  movsbl (%rax),%edx
  test   %edx,%edx
  jle    L7
  mov    $0x0,%esi
  mov    $0x0,%eax
  jmp    L46
L14:
  add    %eax,%esi
L23:
  add    $0x1,%eax
  cmp    %edx,%eax
  je     L0
L46:
  cmp    $0x1fc0,%esi
  jle    L14
  imul   %eax,%esi
  jmp    L23
L7:
  mov    $0x0,%esi
L0:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argv[1][0]; i++) {
    if (sum > 8128)
      sum *= i;
    else
      sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  xor    %esi,%esi
  movsbl (%rax),%edx
  test   %edx,%edx
  jle    L11
  xor    %eax,%eax
  jmp    L45
  nopl   0x0(%rax)
L44:
  imul   %eax,%esi
  add    $0x1,%eax
  cmp    %edx,%eax
  je     L11
L45:
  cmp    $0x1fc0,%esi
  jg     L44
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L45
L11:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argv[1][0]; i++) {
    if (sum > 8128)
      sum *= i;
    else
      sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rax
  xor    %esi,%esi
  movsbl (%rax),%edx
  test   %edx,%edx
  jle    L7
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax)
L2:
  imul   %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edx
  je     L7
L0:
  cmp    $0x1fc0,%esi
  jg     L2
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L0
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argv[1][0]; i++) {
    if (sum > 8128)
      sum *= i;
    else
      sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<safe_fclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  test   %rax,%rax
  je     L2
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perrordie@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: fclose

assistant: ```c
void safe_fclose(FILE *f) {
  if (fclose(f) != 0)
    perrordie("fclose");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<safe_fclose>:
  endbr64
  sub    $0x8,%rsp
  call   <fclose@plt>
  test   %rax,%rax
  jne    L19
L11:
  add    $0x8,%rsp
  ret
L19:
  lea    D3(%rip),%rdi
  call   <perrordie@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: fclose

assistant: ```c
void safe_fclose(FILE *f) {
  if (fclose(f) != 0)
    perrordie("fclose");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_fclose>:
  endbr64
  sub    $0x8,%rsp
  call   <fclose@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perrordie@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: fclose

assistant: ```c
void safe_fclose(FILE *f) {
  if (fclose(f) != 0)
    perrordie("fclose");
}
```
user: Translate the below assembly code into C programming language:

```asm
<safe_fclose>:
  endbr64
  sub    $0x8,%rsp
  call   <fclose@plt>
  test   %rax,%rax
  jne    L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perrordie@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: fclose

assistant: ```c
void safe_fclose(FILE *f) {
  if (fclose(f) != 0)
    perrordie("fclose");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EEPROMIntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400fd014,%eax
  movq   $0x4,(%rax)
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  and    $0x70ff0000,%eax
  cmp    $0x10050000,%rax
  jne    L4
  mov    $0x400fe000,%eax
  mov    (%rax),%rax
  movzwl %ax,%eax
  test   %rax,%rax
  jne    L4
  mov    $0x0,%eax
  call   <EEPROMClearSectorMask@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void EEPROMIntClear(unsigned long ulIntFlags) {
  (*((volatile unsigned long *)(0x400FD014))) = 0x00000004;
  if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00050000)) && (((*((volatile unsigned long *)(0x400FE000))) & (0x0000FF00 | 0x000000FF)) == (0x00000000 | 0x00000000))) {
    EEPROMClearSectorMask();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EEPROMIntClear>:
  endbr64
  movq   $0x4,0x400fd014
  mov    0x400fe000,%rax
  and    $0x70ff0000,%eax
  cmp    $0x10050000,%rax
  je     L2
L18:
  ret
L2:
  mov    0x400fe000,%rax
  test   %ax,%ax
  jne    L18
  sub    $0x8,%rsp
  call   <EEPROMClearSectorMask@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void EEPROMIntClear(unsigned long ulIntFlags) {
  (*((volatile unsigned long *)(0x400FD014))) = 0x00000004;
  if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00050000)) && (((*((volatile unsigned long *)(0x400FE000))) & (0x0000FF00 | 0x000000FF)) == (0x00000000 | 0x00000000))) {
    EEPROMClearSectorMask();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<EEPROMIntClear>:
  endbr64
  movq   $0x4,0x400fd014
  mov    0x400fe000,%rax
  and    $0x70ff0000,%eax
  cmp    $0x10050000,%rax
  je     L8
L13:
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    0x400fe000,%rax
  test   %ax,%ax
  jne    L13
  jmp    1050 <EEPROMClearSectorMask@plt>
```

assistant: ```c
void EEPROMIntClear(unsigned long ulIntFlags) {
  (*((volatile unsigned long *)(0x400FD014))) = 0x00000004;
  if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00050000)) && (((*((volatile unsigned long *)(0x400FE000))) & (0x0000FF00 | 0x000000FF)) == (0x00000000 | 0x00000000))) {
    EEPROMClearSectorMask();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<EEPROMIntClear>:
  endbr64
  movq   $0x4,0x400fd014
  mov    0x400fe000,%rax
  and    $0x70ff0000,%eax
  cmp    $0x10050000,%rax
  je     L17
L1:
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    0x400fe000,%rax
  test   %ax,%ax
  jne    L1
  jmp    1050 <EEPROMClearSectorMask@plt>
```

assistant: ```c
void EEPROMIntClear(unsigned long ulIntFlags) {
  (*((volatile unsigned long *)(0x400FD014))) = 0x00000004;
  if ((((*((volatile unsigned long *)(0x400FE000))) & (0x70000000 | 0x00FF0000)) == (0x10000000 | 0x00050000)) && (((*((volatile unsigned long *)(0x400FE000))) & (0x0000FF00 | 0x000000FF)) == (0x00000000 | 0x00000000))) {
    EEPROMClearSectorMask();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<count_encoded_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L14
  mov    $0x1,%eax
  jmp    L6
L14:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L32
L7:
  shrq   $0x7,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L32:
  cmpq   $0x7f,-0x18(%rbp)
  ja     L7
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
size_t count_encoded_length(size_t n, size_t prefix) {
  size_t k = (size_t)((1 << prefix) - 1);
  size_t len = 0;
  if (n < k) {
    return 1;
  }
  n -= k;
  ++len;
  for (; n >= 128; n >>= 7, ++len)
    ;
  return len + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_encoded_length>:
  endbr64
  mov    $0x1,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  mov    $0x1,%eax
  cmp    %rdi,%rdx
  ja     L38
  sub    %rdx,%rdi
  cmp    $0x7f,%rdi
  jbe    L21
L19:
  shr    $0x7,%rdi
  add    $0x1,%rax
  cmp    $0x7f,%rdi
  ja     L19
L29:
  add    $0x1,%rax
L38:
  ret
L21:
  mov    $0x1,%eax
  jmp    L29
```

assistant: ```c
size_t count_encoded_length(size_t n, size_t prefix) {
  size_t k = (size_t)((1 << prefix) - 1);
  size_t len = 0;
  if (n < k) {
    return 1;
  }
  n -= k;
  ++len;
  for (; n >= 128; n >>= 7, ++len)
    ;
  return len + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_encoded_length>:
  endbr64
  mov    $0x1,%eax
  mov    %esi,%ecx
  mov    $0x1,%r8d
  shl    %cl,%eax
  sub    $0x1,%eax
  cltq
  cmp    %rdi,%rax
  ja     L14
  sub    %rax,%rdi
  cmp    $0x7f,%rdi
  jbe    L8
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  shr    $0x7,%rdi
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    $0x7f,%rdi
  ja     L4
  lea    0x2(%rax),%r8
L14:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x2,%r8d
  jmp    L14
```

assistant: ```c
size_t count_encoded_length(size_t n, size_t prefix) {
  size_t k = (size_t)((1 << prefix) - 1);
  size_t len = 0;
  if (n < k) {
    return 1;
  }
  n -= k;
  ++len;
  for (; n >= 128; n >>= 7, ++len)
    ;
  return len + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_encoded_length>:
  endbr64
  mov    $0x1,%eax
  mov    %esi,%ecx
  mov    $0x1,%r8d
  shl    %cl,%eax
  sub    $0x1,%eax
  cltq
  cmp    %rdi,%rax
  ja     L9
  sub    %rax,%rdi
  cmp    $0x7f,%rdi
  jbe    L11
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L28:
  shr    $0x7,%rdi
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    $0x7f,%rdi
  ja     L28
  lea    0x2(%rax),%r8
L9:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x2,%r8d
  jmp    L9
```

assistant: ```c
size_t count_encoded_length(size_t n, size_t prefix) {
  size_t k = (size_t)((1 << prefix) - 1);
  size_t len = 0;
  if (n < k) {
    return 1;
  }
  n -= k;
  ++len;
  for (; n >= 128; n >>= 7, ++len)
    ;
  return len + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfffffff5,%edi
  call   <close@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: X


assistant: ```c
int main(void) {
  printf("X\n");
  close(-11);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffff5,%edi
  call   <close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: X


assistant: ```c
int main(void) {
  printf("X\n");
  close(-11);
  return 0;
}
```