ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TEMP_ac_turn_on>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  call   <system@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L1
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L1:
  lea    D1(%rip),%rcx
  mov    $0x1c,%edx
  mov    $0x2,%edi
  lea    D12(%rip),%rsi
  call   <TEMP_LOG@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D12
datatype: string

tool: D15: irsend SEND_ONCE AC ON_27

tool: D1: Turn on AC failed!


tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cugfeng/Home_Automation/refs/heads/master/temperature/source/ac.c

assistant: ```c
int TEMP_ac_turn_on(void) {
  int ret;
  ret = system("irsend SEND_ONCE AC ON_27");
  if (ret < 0) {
    TEMP_LOG((2), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cugfeng/Home_Automation/refs/heads/master/temperature/source/ac.c", 28, "Turn on AC failed!\n");
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<debug_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    $0x0,%r9d
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug_print@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug_addpointer@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    $0x1,%r9d
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug_print@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: strdup

assistant: ```c
char *debug_strdup(const char *str, const char *file, int line) {
  void *ptr;
  int len = strlen(str);
  debug_print(file, line, "strdup", str, len, 0);
  ptr = strdup(str);
  debug_addpointer(ptr, len, file, line);
  debug_print(file, line, "strdup", ptr, len, 1);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<debug_strdup>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <strlen@plt>
  mov    %rax,%r13
  mov    $0x0,%r9d
  mov    %eax,%r8d
  mov    %rbx,%rcx
  lea    D6(%rip),%r14
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <debug_print@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug_addpointer@plt>
  mov    $0x1,%r9d
  mov    %r13d,%r8d
  mov    %rbx,%rcx
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <debug_print@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: strdup

assistant: ```c
char *debug_strdup(const char *str, const char *file, int line) {
  void *ptr;
  int len = strlen(str);
  debug_print(file, line, "strdup", str, len, 0);
  ptr = strdup(str);
  debug_addpointer(ptr, len, file, line);
  debug_print(file, line, "strdup", ptr, len, 1);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_strdup>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %r9d,%r9d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %eax,%r8d
  mov    %rax,%rbx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <debug_print@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %r13d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <debug_addpointer@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    $0x1,%r9d
  xor    %eax,%eax
  call   <debug_print@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: strdup

assistant: ```c
char *debug_strdup(const char *str, const char *file, int line) {
  void *ptr;
  int len = strlen(str);
  debug_print(file, line, "strdup", str, len, 0);
  ptr = strdup(str);
  debug_addpointer(ptr, len, file, line);
  debug_print(file, line, "strdup", ptr, len, 1);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_strdup>:
  endbr64
  push   %r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %r9d,%r9d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %eax,%r8d
  mov    %rax,%rbx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <debug_print@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %r13d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <debug_addpointer@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    $0x1,%r9d
  xor    %eax,%eax
  call   <debug_print@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: strdup

assistant: ```c
char *debug_strdup(const char *str, const char *file, int line) {
  void *ptr;
  int len = strlen(str);
  debug_print(file, line, "strdup", str, len, 0);
  ptr = strdup(str);
  debug_addpointer(ptr, len, file, line);
  debug_print(file, line, "strdup", ptr, len, 1);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  jmp    L38
L29:
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    $0xa,%eax
  je     L38
  mov    $0xffffffff,%eax
  jmp    L36
L38:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jne    L29
  mov    $0x0,%eax
L36:
  leave
  ret
```

assistant: ```c
int tone(int fd, int cycles, const signed char *pattern) {
  while (cycles--) {
    if (write(fd, pattern, 10) != 10)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tone>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rdx,%rbp
  mov    %esi,%ebx
L23:
  test   %ebx,%ebx
  je     L25
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  sub    $0x1,%ebx
  cmp    $0xa,%eax
  je     L23
  mov    $0xffffffff,%eax
  jmp    L2
L25:
  mov    $0x0,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int tone(int fd, int cycles, const signed char *pattern) {
  while (cycles--) {
    if (write(fd, pattern, 10) != 10)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tone>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    $0x1,%ebx
  call   <write@plt>
  cmp    $0xa,%eax
  jne    L4
L12:
  test   %ebx,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int tone(int fd, int cycles, const signed char *pattern) {
  while (cycles--) {
    if (write(fd, pattern, 10) != 10)
      return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tone>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    $0x1,%ebx
  call   <write@plt>
  cmp    $0xa,%eax
  jne    L11
L18:
  test   %ebx,%ebx
  jne    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int tone(int fd, int cycles, const signed char *pattern) {
  while (cycles--) {
    if (write(fd, pattern, 10) != 10)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<g_last_fileobject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <btree_lastkey@plt>
  test   %eax,%eax
  jne    L0
  mov    $0xffffffff,%eax
  jmp    L8
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <btree_keyval@plt>
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int g_last_fileobject(int file_id, char *label) {
  if (!btree_lastkey(file_id, 0))
    return -1;
  btree_keyval(file_id, 0, label);
  label[32] = '\0';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<g_last_fileobject>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%esi
  call   <btree_lastkey@plt>
  test   %eax,%eax
  je     L14
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <btree_keyval@plt>
  movb   $0x0,0x20(%rbp)
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int g_last_fileobject(int file_id, char *label) {
  if (!btree_lastkey(file_id, 0))
    return -1;
  btree_keyval(file_id, 0, label);
  label[32] = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g_last_fileobject>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <btree_lastkey@plt>
  test   %eax,%eax
  je     L18
  mov    %rbx,%rdx
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <btree_keyval@plt>
  movb   $0x0,0x20(%rbx)
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int g_last_fileobject(int file_id, char *label) {
  if (!btree_lastkey(file_id, 0))
    return -1;
  btree_keyval(file_id, 0, label);
  label[32] = '\0';
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g_last_fileobject>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <btree_lastkey@plt>
  test   %eax,%eax
  je     L10
  mov    %rbx,%rdx
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <btree_keyval@plt>
  movb   $0x0,0x20(%rbx)
  xor    %eax,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int g_last_fileobject(int file_id, char *label) {
  if (!btree_lastkey(file_id, 0))
    return -1;
  btree_keyval(file_id, 0, label);
  label[32] = '\0';
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<XTeaDecryptCBC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L53
  mov    -0x40(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L99
L53:
  mov    $0xffffffff,%eax
  jmp    L94
L99:
  mov    -0x58(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L52
L30:
  mov    -0x38(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x60(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <XTeaDecrypt@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L56
L6:
  mov    -0x24(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x24(%rbp),%eax
  movzbl -0x10(%rbp,%rax,1),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x48(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x24(%rbp)
L56:
  cmpl   $0x7,-0x24(%rbp)
  jbe    L6
  addq   $0x8,-0x38(%rbp)
  subl   $0x8,-0x28(%rbp)
  addq   $0x8,-0x48(%rbp)
  lea    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L52:
  cmpl   $0x0,-0x28(%rbp)
  jg     L30
  mov    -0x48(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L105
  mov    -0x1c(%rbp),%eax
  cmp    $0x8,%eax
  jbe    L43
L105:
  mov    $0xffffffff,%eax
  jmp    L94
L43:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
L94:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
ssize_t XTeaDecryptCBC(const unsigned char *src, size_t srcLen, unsigned char *dst, size_t dstSize, const unsigned char ivec[8], const unsigned char key[16]) {
  ssize_t remaining = srcLen;
  ssize_t dstLen = srcLen;
  if (dstSize < srcLen || srcLen % 8 != 0) {
    return -1;
  }
  unsigned char temp[8];
  unsigned char iv[8];
  memcpy(iv, ivec, 8);
  while (remaining > 0) {
    memcpy(temp, src, 8);
    XTeaDecrypt(src, dst, key);
    unsigned int i;
    for (i = 0; i < 8; ++i) {
      dst[i] = (unsigned char)dst[i] ^ iv[i];
    }
    src += 8;
    remaining -= 8;
    dst += 8;
    memcpy(iv, temp, 8);
  }
  int padding = *(dst - 1) - '0';
  if (padding < 1 || (unsigned int)padding > 8) {
    return -1;
  }
  return dstLen - padding;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<XTeaDecryptCBC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    %rcx,%rsi
  ja     L43
  mov    %rdx,%rbx
  mov    %r8,%rsi
  mov    %r9,%r13
  mov    %r15,%r14
  and    $0x7,%r14d
  jne    L78
  lea    0x30(%rsp),%rdi
  mov    $0x8,%edx
  call   <memcpy@plt>
  test   %r15d,%r15d
  jle    L92
  mov    %r15d,%eax
  sub    $0x1,%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
  lea    0x0(%rbp,%rax,1),%r15
  lea    0x28(%rsp),%r12
  jmp    L46
L23:
  add    $0x8,%rbp
  add    $0x8,%rbx
  lea    0x30(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  cmp    %r15,%rbp
  je     L56
L46:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <XTeaDecrypt@plt>
  mov    %r14,%rax
L14:
  movzbl 0x30(%rsp,%rax,1),%edx
  xor    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L14
  jmp    L23
L56:
  mov    0x18(%rsp),%rcx
  add    %rcx,0x8(%rsp)
L92:
  mov    0x8(%rsp),%rax
  movzbl -0x1(%rax),%eax
  lea    -0x30(%rax),%edx
  sub    $0x31,%eax
  cmp    $0x7,%eax
  ja     L17
  mov    0x10(%rsp),%eax
  sub    %edx,%eax
L94:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    $0xffffffff,%eax
  jmp    L94
L78:
  mov    $0xffffffff,%eax
  jmp    L94
L17:
  mov    $0xffffffff,%eax
  jmp    L94
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t XTeaDecryptCBC(const unsigned char *src, size_t srcLen, unsigned char *dst, size_t dstSize, const unsigned char ivec[8], const unsigned char key[16]) {
  ssize_t remaining = srcLen;
  ssize_t dstLen = srcLen;
  if (dstSize < srcLen || srcLen % 8 != 0) {
    return -1;
  }
  unsigned char temp[8];
  unsigned char iv[8];
  memcpy(iv, ivec, 8);
  while (remaining > 0) {
    memcpy(temp, src, 8);
    XTeaDecrypt(src, dst, key);
    unsigned int i;
    for (i = 0; i < 8; ++i) {
      dst[i] = (unsigned char)dst[i] ^ iv[i];
    }
    src += 8;
    remaining -= 8;
    dst += 8;
    memcpy(iv, temp, 8);
  }
  int padding = *(dst - 1) - '0';
  if (padding < 1 || (unsigned int)padding > 8) {
    return -1;
  }
  return dstLen - padding;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<XTeaDecryptCBC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    %rcx,%rsi
  ja     L46
  mov    0x8(%rsp),%rbp
  test   $0x7,%bpl
  jne    L46
  lea    0x20(%rsp),%r14
  mov    %rdx,%r15
  mov    %r8,%rsi
  mov    $0x8,%edx
  mov    %r14,%rdi
  mov    %r9,%r12
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %ebp,%eax
  lea    0x18(%rsp),%rbp
  sub    $0x1,%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  lea    (%r15,%rax,8),%r13
  nopl   0x0(%rax)
L13:
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <XTeaDecrypt@plt>
  xor    %eax,%eax
L84:
  movzbl (%r14,%rax,1),%edx
  xor    %dl,(%r15,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L84
  add    $0x8,%r15
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x8,%rbx
  call   <memcpy@plt>
  cmp    %r13,%r15
  jne    L13
L2:
  movzbl -0x1(%r13),%eax
  lea    -0x30(%rax),%edx
  sub    $0x31,%eax
  cmp    $0x7,%eax
  ja     L46
  mov    0x8(%rsp),%eax
  sub    %edx,%eax
L47:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    %r15,%r13
  jmp    L2
L46:
  mov    $0xffffffff,%eax
  jmp    L47
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t XTeaDecryptCBC(const unsigned char *src, size_t srcLen, unsigned char *dst, size_t dstSize, const unsigned char ivec[8], const unsigned char key[16]) {
  ssize_t remaining = srcLen;
  ssize_t dstLen = srcLen;
  if (dstSize < srcLen || srcLen % 8 != 0) {
    return -1;
  }
  unsigned char temp[8];
  unsigned char iv[8];
  memcpy(iv, ivec, 8);
  while (remaining > 0) {
    memcpy(temp, src, 8);
    XTeaDecrypt(src, dst, key);
    unsigned int i;
    for (i = 0; i < 8; ++i) {
      dst[i] = (unsigned char)dst[i] ^ iv[i];
    }
    src += 8;
    remaining -= 8;
    dst += 8;
    memcpy(iv, temp, 8);
  }
  int padding = *(dst - 1) - '0';
  if (padding < 1 || (unsigned int)padding > 8) {
    return -1;
  }
  return dstLen - padding;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<XTeaDecryptCBC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    %rcx,%rsi
  ja     L18
  mov    %rsi,%r15
  test   $0x7,%sil
  jne    L18
  lea    0x28(%rsp),%r13
  mov    %r8,%rsi
  mov    $0x8,%edx
  mov    %r9,%r12
  mov    %r13,%rdi
  call   <memcpy@plt>
  test   %r15d,%r15d
  jle    L32
  mov    %r15d,%eax
  mov    0x8(%rsp),%r14
  lea    0x30(%rsp),%rbp
  sub    $0x1,%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
  lea    (%rbx,%rax,1),%r15
  nopl   0x0(%rax)
L42:
  mov    %rbx,%rsi
  mov    $0x8,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %r12,%rdx
  call   <XTeaDecrypt@plt>
  movq   (%r14),%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  movq   0x28(%rsp),%xmm1
  add    $0x8,%rbx
  mov    $0x8,%edx
  add    $0x8,%r14
  pxor   %xmm1,%xmm0
  movq   %xmm0,-0x8(%r14)
  call   <memcpy@plt>
  cmp    %r15,%rbx
  jne    L42
  mov    0x18(%rsp),%rcx
  add    %rcx,0x8(%rsp)
L32:
  mov    0x8(%rsp),%rax
  movzbl -0x1(%rax),%eax
  lea    -0x30(%rax),%edx
  sub    $0x31,%eax
  cmp    $0x7,%eax
  ja     L18
  mov    0x10(%rsp),%eax
  sub    %edx,%eax
L37:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L37
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t XTeaDecryptCBC(const unsigned char *src, size_t srcLen, unsigned char *dst, size_t dstSize, const unsigned char ivec[8], const unsigned char key[16]) {
  ssize_t remaining = srcLen;
  ssize_t dstLen = srcLen;
  if (dstSize < srcLen || srcLen % 8 != 0) {
    return -1;
  }
  unsigned char temp[8];
  unsigned char iv[8];
  memcpy(iv, ivec, 8);
  while (remaining > 0) {
    memcpy(temp, src, 8);
    XTeaDecrypt(src, dst, key);
    unsigned int i;
    for (i = 0; i < 8; ++i) {
      dst[i] = (unsigned char)dst[i] ^ iv[i];
    }
    src += 8;
    remaining -= 8;
    dst += 8;
    memcpy(iv, temp, 8);
  }
  int padding = *(dst - 1) - '0';
  if (padding < 1 || (unsigned int)padding > 8) {
    return -1;
  }
  return dstLen - padding;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kotlinclib_println_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <kotlinclib_print_int@plt>
  mov    $0x0,%eax
  call   <kotlinclib_println@plt>
  nop
  leave
  ret
```

assistant: ```c
void kotlinclib_println_int(int message) {
  kotlinclib_print_int(message);
  kotlinclib_println();
}
```
user: Translate the below assembly code into C programming language:

```asm
<kotlinclib_println_int>:
  endbr64
  sub    $0x8,%rsp
  call   <kotlinclib_print_int@plt>
  mov    $0x0,%eax
  call   <kotlinclib_println@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void kotlinclib_println_int(int message) {
  kotlinclib_print_int(message);
  kotlinclib_println();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kotlinclib_println_int>:
  endbr64
  sub    $0x8,%rsp
  call   <kotlinclib_print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <kotlinclib_println@plt>
```

assistant: ```c
void kotlinclib_println_int(int message) {
  kotlinclib_print_int(message);
  kotlinclib_println();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kotlinclib_println_int>:
  endbr64
  sub    $0x8,%rsp
  call   <kotlinclib_print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <kotlinclib_println@plt>
```

assistant: ```c
void kotlinclib_println_int(int message) {
  kotlinclib_print_int(message);
  kotlinclib_println();
}
```