ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<weather_nextline>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L39:
  js     L32
  cmpb   $0xa,0x7(%rsp)
  je     L23
L62:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L39
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L32:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  jmp    L48
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: read failed

assistant: ```c
int weather_nextline(int fd) {
  ssize_t n;
  char ch;
  while ((n = read(fd, &ch, 1))) {
    if (n < 0) {
      perror("read failed");
      return -1;
    } else if (n == 0) {
      break;
    } else {
      if (ch == '\n') {
        break;
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<slow_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L84
L32:
  cmpq   $0x1,-0x18(%rbp)
  jne    L89
  mov    $0x0,%eax
  jmp    L84
L89:
  cmpq   $0x2,-0x18(%rbp)
  jne    L38
  mov    $0x1,%eax
  jmp    L84
L38:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L54
  mov    $0x0,%eax
  jmp    L84
L54:
  movq   $0x2,-0x8(%rbp)
  jmp    L104
L2:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L77
  mov    $0x0,%eax
  jmp    L84
L77:
  addq   $0x1,-0x8(%rbp)
L104:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x8(%rbp)
  jle    L2
  mov    $0x1,%eax
L84:
  leave
  ret
```

assistant: ```c
long slow_prime(long n) {
  long i;
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 0;
  }
  if (n == 2) {
    return 1;
  }
  if (n % 2 == 0) {
    return 0;
  }
  for (i = 2; i <= sqrt(n); ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<slow_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rdi
  jbe    L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x1,%eax
  cmp    $0x2,%rdi
  je     L34
  mov    $0x0,%eax
  mov    $0x2,%ebp
  test   $0x1,%dil
  je     L34
L41:
  mov    %rbx,%rdi
  call   <sqrt@plt>
  cmp    %rbp,%rax
  jl     L25
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%rax
  test   %rdx,%rdx
  je     L34
  add    $0x1,%rbp
  jmp    L41
L25:
  mov    $0x1,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  ret
```

assistant: ```c
long slow_prime(long n) {
  long i;
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 0;
  }
  if (n == 2) {
    return 1;
  }
  if (n % 2 == 0) {
    return 0;
  }
  for (i = 2; i <= sqrt(n); ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<slow_prime>:
  endbr64
  cmp    $0x1,%rdi
  jbe    L54
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%rdi
  je     L42
  mov    $0x2,%ebx
  test   $0x1,%dil
  jne    L40
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L33
  add    $0x1,%rbx
L40:
  mov    %r12,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jge    L26
L42:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  ret
```

assistant: ```c
long slow_prime(long n) {
  long i;
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 0;
  }
  if (n == 2) {
    return 1;
  }
  if (n % 2 == 0) {
    return 0;
  }
  for (i = 2; i <= sqrt(n); ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slow_prime>:
  endbr64
  cmp    $0x1,%rdi
  jbe    L56
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%rdi
  je     L35
  mov    $0x2,%ebx
  test   $0x1,%dil
  jne    L58
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L33
  add    $0x1,%rbx
L58:
  mov    %r12,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jge    L16
L35:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  ret
```

assistant: ```c
long slow_prime(long n) {
  long i;
  if (n == 0) {
    return 0;
  }
  if (n == 1) {
    return 0;
  }
  if (n == 2) {
    return 1;
  }
  if (n % 2 == 0) {
    return 0;
  }
  for (i = 2; i <= sqrt(n); ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<div_df>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double div_df(double *p, double *q) {
  double d1 = *p;
  double d2 = *q;
  __asm__("# reg %x0, %x1" : "+v"(d1), "+v"(d2));
  return d1 / d2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<div_df>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double div_df(double *p, double *q) {
  double d1 = *p;
  double d2 = *q;
  __asm__("# reg %x0, %x1" : "+v"(d1), "+v"(d2));
  return d1 / d2;
}
```
user: What is the c source code of the assembly code below:

```asm
<div_df>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double div_df(double *p, double *q) {
  double d1 = *p;
  double d2 = *q;
  __asm__("# reg %x0, %x1" : "+v"(d1), "+v"(d2));
  return d1 / d2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<disableAnalog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  cmp    $0x5,%eax
  ja     L27
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x25,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
  mov    $0x24,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
  mov    $0x17,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
  mov    $0x16,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
  mov    $0x15,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x1d,%edi
  call   <unexportIO@plt>
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
  mov    $0x14,%edi
  call   <unexportIO@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x1d,%edi
  call   <unexportIO@plt>
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L55
L27:
  mov    $0xffffffff,%eax
L55:
  leave
  ret
```

assistant: ```c
int disableAnalog(unsigned char n) {
  int r;
  switch (n) {
  case 0:
    r = unexportIO(37);
    return r;
    break;
  case 1:
    r = unexportIO(36);
    return r;
    break;
  case 2:
    r = unexportIO(23);
    return r;
    break;
  case 3:
    r = unexportIO(22);
    return r;
    break;
  case 4:
    r = unexportIO(21);
    r += unexportIO(29);
    return r;
    break;
  case 5:
    r = unexportIO(20);
    r += unexportIO(29);
    return r;
    break;
  default:
    return -1;
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<disableAnalog>:
  endbr64
  cmp    $0x5,%dil
  ja     L22
  push   %rbx
  movzbl %dil,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x25,%edi
  call   <unexportIO@plt>
L42:
  pop    %rbx
  ret
  mov    $0x24,%edi
  call   <unexportIO@plt>
  jmp    L42
  mov    $0x17,%edi
  call   <unexportIO@plt>
  jmp    L42
  mov    $0x16,%edi
  call   <unexportIO@plt>
  jmp    L42
  mov    $0x15,%edi
  call   <unexportIO@plt>
  mov    %eax,%ebx
  mov    $0x1d,%edi
  call   <unexportIO@plt>
  add    %ebx,%eax
  jmp    L42
  mov    $0x14,%edi
  call   <unexportIO@plt>
  mov    %eax,%ebx
  mov    $0x1d,%edi
  call   <unexportIO@plt>
  add    %ebx,%eax
  jmp    L42
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int disableAnalog(unsigned char n) {
  int r;
  switch (n) {
  case 0:
    r = unexportIO(37);
    return r;
    break;
  case 1:
    r = unexportIO(36);
    return r;
    break;
  case 2:
    r = unexportIO(23);
    return r;
    break;
  case 3:
    r = unexportIO(22);
    return r;
    break;
  case 4:
    r = unexportIO(21);
    r += unexportIO(29);
    return r;
    break;
  case 5:
    r = unexportIO(20);
    r += unexportIO(29);
    return r;
    break;
  default:
    return -1;
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<disableAnalog>:
  endbr64
  push   %rbx
  cmp    $0x5,%dil
  ja     1060 <disableAnalog.cold>
  lea    D7(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    $0x15,%edi
  call   <unexportIO@plt>
  mov    $0x1d,%edi
  mov    %eax,%ebx
  call   <unexportIO@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x14,%edi
  call   <unexportIO@plt>
  mov    $0x1d,%edi
  mov    %eax,%ebx
  call   <unexportIO@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x25,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x24,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x17,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x16,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
```

assistant: ```c
int disableAnalog(unsigned char n) {
  int r;
  switch (n) {
  case 0:
    r = unexportIO(37);
    return r;
    break;
  case 1:
    r = unexportIO(36);
    return r;
    break;
  case 2:
    r = unexportIO(23);
    return r;
    break;
  case 3:
    r = unexportIO(22);
    return r;
    break;
  case 4:
    r = unexportIO(21);
    r += unexportIO(29);
    return r;
    break;
  case 5:
    r = unexportIO(20);
    r += unexportIO(29);
    return r;
    break;
  default:
    return -1;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<disableAnalog>:
  endbr64
  push   %rbx
  cmp    $0x5,%dil
  ja     1060 <disableAnalog.cold>
  lea    D2(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    $0x15,%edi
  call   <unexportIO@plt>
  mov    $0x1d,%edi
  mov    %eax,%ebx
  call   <unexportIO@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x14,%edi
  call   <unexportIO@plt>
  mov    $0x1d,%edi
  mov    %eax,%ebx
  call   <unexportIO@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x25,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x24,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x17,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x16,%edi
  pop    %rbx
  jmp    1050 <unexportIO@plt>
```

assistant: ```c
int disableAnalog(unsigned char n) {
  int r;
  switch (n) {
  case 0:
    r = unexportIO(37);
    return r;
    break;
  case 1:
    r = unexportIO(36);
    return r;
    break;
  case 2:
    r = unexportIO(23);
    return r;
    break;
  case 3:
    r = unexportIO(22);
    return r;
    break;
  case 4:
    r = unexportIO(21);
    r += unexportIO(29);
    return r;
    break;
  case 5:
    r = unexportIO(20);
    r += unexportIO(29);
    return r;
    break;
  default:
    return -1;
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    -0x78(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L5
L1:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L11
L20:
  addl   $0x1,-0x74(%rbp)
L11:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4b,%al
  jne    L20
  mov    -0x74(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <nearest2@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  mov    -0x78(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x78(%rbp)
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D36
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D1: %d

tool: D36: %s

tool: D18: %u

tool: D11: K

assistant: ```c
int main() {
  char req[100];
  int N, i = 0;
  scanf("%d", &N);
  while (N--) {
    scanf("%s", req);
    i = 0;
    while (req[i] != 'K') {
      i++;
    }
    req[i] = '\0';
    printf("%u", nearest2((unsigned int)atoi(req)));
    printf("K\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L57
  lea    0x10(%rsp),%rbx
  lea    D5(%rip),%r13
  lea    D14(%rip),%r12
  lea    D24(%rip),%rbp
L7:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x4b,0x10(%rsp)
  je     L39
  mov    $0x1,%eax
  lea    0xf(%rsp),%rcx
L31:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x4b,(%rcx,%rax,1)
  jne    L31
L53:
  movslq %edx,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <nearest2@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L7
L57:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%edx
  jmp    L53
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D32
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string

tool: D32: %d

tool: D5: %s

tool: D14: %u

tool: D24: K

assistant: ```c
int main() {
  char req[100];
  int N, i = 0;
  scanf("%d", &N);
  while (N--) {
    scanf("%s", req);
    i = 0;
    while (req[i] != 'K') {
      i++;
    }
    req[i] = '\0';
    printf("%u", nearest2((unsigned int)atoi(req)));
    printf("K\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L15
  lea    0x10(%rsp),%rbx
  lea    D14(%rip),%r13
  lea    D12(%rip),%r12
  lea    D11(%rip),%rbp
  nop
L29:
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpb   $0x4b,0x10(%rsp)
  je     L40
  mov    $0x1,%eax
  lea    0xf(%rsp),%rcx
  xchg   %ax,%ax
L57:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmpb   $0x4b,(%rcx,%rax,1)
  jne    L57
L16:
  mov    %rbx,%rdi
  movb   $0x0,0x10(%rsp,%rdx,1)
  call   <atoi@plt>
  mov    %eax,%edi
  call   <nearest2@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L29
L15:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L40:
  xor    %edx,%edx
  jmp    L16
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D12
type: string
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D10: %d

tool: D14: %s

tool: D12: %u

tool: D11: K

assistant: ```c
int main() {
  char req[100];
  int N, i = 0;
  scanf("%d", &N);
  while (N--) {
    scanf("%s", req);
    i = 0;
    while (req[i] != 'K') {
      i++;
    }
    req[i] = '\0';
    printf("%u", nearest2((unsigned int)atoi(req)));
    printf("K\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D33(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L58
  lea    0x10(%rsp),%rbx
  lea    D10(%rip),%r13
  lea    D37(%rip),%r12
  lea    D3(%rip),%rbp
  nop
L9:
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmpb   $0x4b,0x10(%rsp)
  je     L50
  mov    $0x1,%eax
  lea    0xf(%rsp),%rcx
  xchg   %ax,%ax
L55:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmpb   $0x4b,(%rcx,%rax,1)
  jne    L55
L20:
  mov    %rbx,%rdi
  movb   $0x0,0x10(%rsp,%rdx,1)
  call   <atoi@plt>
  mov    %eax,%edi
  call   <nearest2@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L9
L58:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L50:
  xor    %edx,%edx
  jmp    L20
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D37
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D33: %d

tool: D10: %s

tool: D37: %u

tool: D3: K

assistant: ```c
int main() {
  char req[100];
  int N, i = 0;
  scanf("%d", &N);
  while (N--) {
    scanf("%s", req);
    i = 0;
    while (req[i] != 'K') {
      i++;
    }
    req[i] = '\0';
    printf("%u", nearest2((unsigned int)atoi(req)));
    printf("K\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gReallocPtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ReallocPtr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *gReallocPtr(char *thisPtr, int size) {
  unsigned char *p = (unsigned char *)ReallocPtr(thisPtr, size);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<gReallocPtr>:
  endbr64
  sub    $0x8,%rsp
  call   <ReallocPtr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char *gReallocPtr(char *thisPtr, int size) {
  unsigned char *p = (unsigned char *)ReallocPtr(thisPtr, size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gReallocPtr>:
  endbr64
  jmp    1050 <ReallocPtr@plt>
```

assistant: ```c
unsigned char *gReallocPtr(char *thisPtr, int size) {
  unsigned char *p = (unsigned char *)ReallocPtr(thisPtr, size);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gReallocPtr>:
  endbr64
  jmp    1050 <ReallocPtr@plt>
```

assistant: ```c
unsigned char *gReallocPtr(char *thisPtr, int size) {
  unsigned char *p = (unsigned char *)ReallocPtr(thisPtr, size);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sys$clref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %rax,%rdi
  mov    $0x9,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$clref(unsigned int efn) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(9), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sys$clref>:
  endbr64
  mov    %edi,%edi
  mov    $0x9,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$clref(unsigned int efn) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(9), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sys$clref>:
  endbr64
  mov    %edi,%edi
  mov    $0x9,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$clref(unsigned int efn) {
  return ({
    unsigned long resultvar;
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(9), "r"(_a1)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nstrcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L22
L23:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  jmp    L52
L39:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L51
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L51
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L35
L51:
  subq   $0x1,-0x8(%rbp)
L35:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nstrcat(char *t, char *s) {
  for (; '\0' != *t; t++)
    ;
  for (; '\0' != *s; t++, s++) {
    if ('0' <= *s && *s <= '9')
      *t = *s;
    else
      t -= 1;
  }
}
```