ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L3
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L3:
  xor    %edi,%edi
  call   <__builtin_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1, 0x1000000000000003LL) != 3)
    __builtin_abort();
  __builtin_exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L8
  xor    %eax,%eax
  call   <__builtin_abort@plt>
L8:
  xor    %edi,%edi
  call   <__builtin_exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1, 0x1000000000000003LL) != 3)
    __builtin_abort();
  __builtin_exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_error_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x69,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: can not open the file : %s , please check this error --> exit


assistant: ```c
void print_error_5(char *message) {
  printf("can not open the file : %s , please check this error --> exit\n", message);
  exit(105);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_error_5>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x69,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: can not open the file : %s , please check this error --> exit


assistant: ```c
void print_error_5(char *message) {
  printf("can not open the file : %s , please check this error --> exit\n", message);
  exit(105);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_error_5>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x69,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: can not open the file : %s , please check this error --> exit


assistant: ```c
void print_error_5(char *message) {
  printf("can not open the file : %s , please check this error --> exit\n", message);
  exit(105);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_error_5>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x69,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string

tool: D1: can not open the file : %s , please check this error --> exit


assistant: ```c
void print_error_5(char *message) {
  printf("can not open the file : %s , please check this error --> exit\n", message);
  exit(105);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prog_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L24:
  subq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L0
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L24
L0:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  leave
  ret
```

assistant: ```c
char *prog_name(s)
char *s;
{
  char *p = s + strlen(s);
  while (p >= s && *p != '/')
    p--;
  return (p + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<prog_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  add    %rbx,%rax
  jb     L17
L19:
  cmpb   $0x2f,(%rax)
  je     L17
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L19
L17:
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *prog_name(s)
char *s;
{
  char *p = s + strlen(s);
  while (p >= s && *p != '/')
    p--;
  return (p + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<prog_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  add    %rbx,%rax
  jae    L31
  jmp    L16
  nopl   0x0(%rax)
L30:
  lea    -0x1(%rax),%rdx
  cmp    %rdx,%rbx
  ja     L18
  mov    %rdx,%rax
L31:
  cmpb   $0x2f,(%rax)
  jne    L30
L16:
  add    $0x1,%rax
L18:
  pop    %rbx
  ret
```

assistant: ```c
char *prog_name(s)
char *s;
{
  char *p = s + strlen(s);
  while (p >= s && *p != '/')
    p--;
  return (p + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prog_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  add    %rbx,%rax
  jae    L17
  jmp    L19
  nopl   0x0(%rax)
L1:
  lea    -0x1(%rax),%rdx
  cmp    %rdx,%rbx
  ja     L23
  mov    %rdx,%rax
L17:
  cmpb   $0x2f,(%rax)
  jne    L1
L19:
  add    $0x1,%rax
L23:
  pop    %rbx
  ret
```

assistant: ```c
char *prog_name(s)
char *s;
{
  char *p = s + strlen(s);
  while (p >= s && *p != '/')
    p--;
  return (p + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ignorereturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6330362031303032,%rax
  movabs $0x3031312d20306330,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x3130303130313131,%rax
  movabs $0x3030313030313031,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6636783020303030,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x66666666,-0x18(%rbp)
  movb   $0x0,-0x14(%rbp)
  lea    -0x48(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void ignorereturn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ignorereturn>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x6330362031303032,%rax
  movabs $0x3031312d20306330,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x3130303130313131,%rax
  movabs $0x3030313030313031,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6636783020303030,%rax
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ignorereturn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ignorereturn>:
  endbr64
  sub    $0x58,%rsp
  movdqa D3(%rip),%xmm0
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movabs $0x6636783020303030,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D7(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: byte[16]

tool: {"D3": [0x32,0x30,0x30,0x31,0x20,0x36,0x30,0x63,0x30,0x63,0x30,0x20,0x2d,0x31,0x31,0x30]}

tool: {"D7": [0x31,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x30,0x30]}

assistant: ```c
void ignorereturn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ignorereturn>:
  endbr64
  sub    $0x58,%rsp
  movdqa D8(%rip),%xmm0
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movabs $0x6636783020303030,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D14(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movl   $0x66666666,0x38(%rsp)
  movb   $0x0,0x3c(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <strtol@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x58,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: byte[16]
name: disassemble_data
arguments: tag: D14
datatype: byte[16]

tool: {"D8": [0x32,0x30,0x30,0x31,0x20,0x36,0x30,0x63,0x30,0x63,0x30,0x20,0x2d,0x31,0x31,0x30]}

tool: {"D14": [0x31,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x31,0x30,0x31,0x30,0x30,0x31,0x30,0x30]}

assistant: ```c
void ignorereturn(void) {
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char *pEnd;
  strtol(szNumbers, &pEnd, 10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aa_pro_ctr_a04>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rcx
  lea    D28(%rip),%rax
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  mov    $0x0,%eax
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D28
type: string
name: read_data
arguments: tag: D15
type: string

tool: D4: !!!!!!!!

tool: D28: aa_pro_ctr_a04

tool: D15: hu_aap

assistant: ```c
int aa_pro_ctr_a04(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aa_pro_ctr_a04>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rcx
  lea    D11(%rip),%rdx
  lea    D6(%rip),%rsi
  mov    $0x6,%edi
  mov    $0x0,%eax
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D9: !!!!!!!!

tool: D11: aa_pro_ctr_a04

tool: D6: hu_aap

assistant: ```c
int aa_pro_ctr_a04(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aa_pro_ctr_a04>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rcx
  xor    %eax,%eax
  mov    $0x6,%edi
  lea    D3(%rip),%rdx
  lea    D6(%rip),%rsi
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D6
type: string

tool: D16: !!!!!!!!

tool: D3: aa_pro_ctr_a04

tool: D6: hu_aap

assistant: ```c
int aa_pro_ctr_a04(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aa_pro_ctr_a04>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rcx
  xor    %eax,%eax
  mov    $0x6,%edi
  lea    D21(%rip),%rdx
  lea    D28(%rip),%rsi
  call   <hu_log@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: D26: !!!!!!!!

tool: D21: aa_pro_ctr_a04

tool: D28: hu_aap

assistant: ```c
int aa_pro_ctr_a04(int chan, unsigned char *buf, int len) {
  hu_log(6, "hu_aap", __func__, "!!!!!!!!");
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fnQDiffC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L3:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fnQDiffC(int *n, double *u, double *theta, double *w, double *w0) {
  int i;
  w[0] = *w0;
  for (i = 1; i < *n; i++)
    w[i] = u[i - 1] - *theta * w[i - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fnQDiffC>:
  endbr64
  movsd  (%r8),%xmm0
  movsd  %xmm0,(%rcx)
  cmpl   $0x1,(%rdi)
  jle    L16
  mov    $0x1,%eax
L1:
  movsd  (%rdx),%xmm1
  mulsd  -0x8(%rcx,%rax,8),%xmm1
  movsd  -0x8(%rsi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,(%rdi)
  jg     L1
L16:
  ret
```

assistant: ```c
void fnQDiffC(int *n, double *u, double *theta, double *w, double *w0) {
  int i;
  w[0] = *w0;
  for (i = 1; i < *n; i++)
    w[i] = u[i - 1] - *theta * w[i - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fnQDiffC>:
  endbr64
  movsd  (%r8),%xmm0
  mov    (%rdi),%eax
  movsd  %xmm0,(%rcx)
  cmp    $0x1,%eax
  jle    L0
  lea    -0x2(%rax),%edi
  xor    %eax,%eax
  shl    $0x3,%rdi
  jmp    L26
  nop
L5:
  add    $0x8,%rax
L26:
  movsd  (%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  (%rsi,%rax,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx,%rax,1)
  cmp    %rdi,%rax
  jne    L5
L0:
  ret
```

assistant: ```c
void fnQDiffC(int *n, double *u, double *theta, double *w, double *w0) {
  int i;
  w[0] = *w0;
  for (i = 1; i < *n; i++)
    w[i] = u[i - 1] - *theta * w[i - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fnQDiffC>:
  endbr64
  movsd  (%r8),%xmm0
  mov    (%rdi),%eax
  movsd  %xmm0,(%rcx)
  cmp    $0x1,%eax
  jle    L12
  lea    -0x1(%rax),%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  movsd  (%rdx),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  (%rsi,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L10
L12:
  ret
```

assistant: ```c
void fnQDiffC(int *n, double *u, double *theta, double *w, double *w0) {
  int i;
  w[0] = *w0;
  for (i = 1; i < *n; i++)
    w[i] = u[i - 1] - *theta * w[i - 1];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  mov    $0x64,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L55
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D47(%rip),%r12
L79:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L79
L55:
  cmp    $0x1,%eax
  jle    L5
  lea    0x14(%rsp),%r8
  lea    -0x1(%rax),%r9d
  mov    $0x0,%edi
  jmp    L23
L67:
  add    $0x1,%edx
  movslq %edx,%rdx
  mov    %esi,0x10(%rsp,%rdx,4)
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    %r9,%rdi
  je     L5
L23:
  mov    (%r8),%esi
  mov    %edi,%edx
  mov    %r8,%rax
  test   %edi,%edi
  js     L67
L40:
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jl     L67
  mov    %ecx,(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L40
  jmp    L67
L5:
  lea    D37(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L112
  mov    $0x0,%ebx
  lea    D38(%rip),%rbp
L110:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L110
L112:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D47
type_infered: string
name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string

tool: D44: Enter the length of sequence you want to sort (less than %d): 

tool: D47: %d

tool: D43: Enter %d numbers: 

tool: D37: 
The [insertion] sorted sequence follows:

tool: D38: %d 

assistant: ```c
int main() {
  int arr[100], n, i, j, key;
  printf("Enter the length of sequence you want to sort (less than %d): ", 100);
  scanf("%d", &n);
  printf("Enter %d numbers: ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &arr[i]);
  for (j = 1; j < n; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] >= key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
  printf("\nThe [insertion] sorted sequence follows:\n");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D48(%rip),%rdi
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L82
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  cmp    %ebx,%r9d
  jg     L67
  cmp    $0x1,%r9d
  jle    L82
  lea    0x14(%rsp),%r8
  mov    $0x1,%edi
  nopl   0x0(%rax)
L28:
  mov    (%r8),%esi
  mov    %edi,%eax
  mov    %r8,%rdx
  nopl   0x0(%rax,%rax,1)
L63:
  mov    -0x4(%rdx),%ecx
  cmp    %esi,%ecx
  jl     L61
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  sub    $0x1,%eax
  jne    L63
  xor    %eax,%eax
L61:
  cltq
  add    $0x1,%edi
  add    $0x4,%r8
  mov    %esi,0x10(%rsp,%rax,4)
  cmp    %edi,%r9d
  jne    L28
L82:
  lea    D43(%rip),%rdi
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    D4(%rip),%rbp
  test   %eax,%eax
  jle    L9
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L0
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D48
datatype: string
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D43
datatype: string
name: read_data
arguments: label: D4
datatype: string

tool: D48: Enter the length of sequence you want to sort (less than %d): 

tool: D20: %d

tool: D36: Enter %d numbers: 

tool: D43: 
The [insertion] sorted sequence follows:

tool: D4: %d 

assistant: ```c
int main() {
  int arr[100], n, i, j, key;
  printf("Enter the length of sequence you want to sort (less than %d): ", 100);
  scanf("%d", &n);
  printf("Enter %d numbers: ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &arr[i]);
  for (j = 1; j < n; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] >= key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
  printf("\nThe [insertion] sorted sequence follows:\n");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D43(%rip),%rdi
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L24
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  cmp    %ebx,%r9d
  jg     L25
  cmp    $0x1,%r9d
  jle    L24
  lea    0x14(%rsp),%r8
  mov    $0x1,%edi
  nopl   0x0(%rax)
L23:
  mov    (%r8),%esi
  mov    %edi,%eax
  mov    %r8,%rdx
  nopl   0x0(%rax,%rax,1)
L15:
  mov    -0x4(%rdx),%ecx
  cmp    %esi,%ecx
  jl     L62
  mov    %ecx,(%rdx)
  sub    $0x4,%rdx
  sub    $0x1,%eax
  jne    L15
  xor    %eax,%eax
L62:
  cltq
  add    $0x1,%edi
  add    $0x4,%r8
  mov    %esi,0x10(%rsp,%rax,4)
  cmp    %edi,%r9d
  jne    L23
L24:
  lea    D42(%rip),%rdi
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    D6(%rip),%rbp
  test   %eax,%eax
  jle    L42
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L32
L42:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D43
datatype: string
name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D32
datatype: string
name: read_data
arguments: tag: D42
datatype: string
name: read_data
arguments: tag: D6
datatype: string

tool: D43: Enter the length of sequence you want to sort (less than %d): 

tool: D14: %d

tool: D32: Enter %d numbers: 

tool: D42: 
The [insertion] sorted sequence follows:

tool: D6: %d 

assistant: ```c
int main() {
  int arr[100], n, i, j, key;
  printf("Enter the length of sequence you want to sort (less than %d): ", 100);
  scanf("%d", &n);
  printf("Enter %d numbers: ", n);
  for (i = 0; i < n; i++)
    scanf("%d", &arr[i]);
  for (j = 1; j < n; j++) {
    key = arr[j];
    i = j - 1;
    while (i >= 0 && arr[i] >= key) {
      arr[i + 1] = arr[i];
      i -= 1;
    }
    arr[i + 1] = key;
  }
  printf("\nThe [insertion] sorted sequence follows:\n");
  for (i = 0; i < n; i++)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```