user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x3c(%rbp)
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x2faf0800,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L15
L26:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x6b5fca6b,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x16,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x989680,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x3c(%rbp)
L15:
  cmpl   $0x5f5e0ff,-0x3c(%rbp)
  jle    L26
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L6
L1:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x3c(%rbp)
L6:
  cmpl   $0x5f5e0ff,-0x3c(%rbp)
  jle    L1
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D0
type_infered: f64
name: read_data
arguments: tag: D4
type_infered: string

tool: D20: %lf


tool: D0: 0.01

tool: D4: Vector Division Complete - %lf Seconds


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int i = 0;
  double *mainVector = malloc(100000000 * sizeof(double));
  double *divVector = malloc(100000000 * sizeof(double));
  double *solVector = malloc(100000000 * sizeof(double));
  double x = rand();
  printf("%lf\n", x);
  for (i = 0; i < 100000000; i++) {
    mainVector[i] = (rand() % 10000000) * 0.01;
    divVector[i] = (rand() % 1000) * 0.01;
    solVector[i] = 0;
  }
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %5.2lf %1.2lf\n", mainVector[i], divVector[i]);
    }
  }
  double start = omp_get_wtime();
#pragma omp parallel for shared(mainVector, divVector, solVector) private(i) schedule(static, 10) num_threads(4)
  for (i = 0; i < 100000000; i++) {
    solVector[i] = mainVector[i] / divVector[i];
  }
  double end = omp_get_wtime();
  if (0) {
    for (i = 0; i < 100000000; i++) {
      printf("  %1.2lf\n", solVector[i]);
    }
  }
  double solTime = end - start;
  printf("Vector Division Complete - %lf Seconds\n", solTime);
  return 0;
}
```