ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<decHexString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L0
  movslq %edx,%rdx
  mov    %rdi,%rbp
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbx
  lea    (%rdi,%rdx,1),%r13
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L34:
  movsbl 0x1(%rbx),%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <addHexDigit@plt>
  test   %rax,%rax
  js     L11
  mov    0x4(%rsp),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbp
  je     L0
L52:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  movl   $0x0,0x4(%rsp)
  call   <addHexDigit@plt>
  test   %rax,%rax
  jns    L34
L11:
  mov    $0xffffffff,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  xor    %eax,%eax
  jmp    L19
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decHexString(unsigned char *hex, char *hexString, int len) {
  int val;
  while (len-- > 0) {
    val = 0;
    if (addHexDigit(&val, *hexString++) < 0 || addHexDigit(&val, *hexString++) < 0)
      return -1;
    *hex++ = (unsigned char)val;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decHexString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L59
  movslq %edx,%rdx
  mov    %rdi,%rbp
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbx
  lea    (%rdi,%rdx,1),%r13
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L0:
  movsbl 0x1(%rbx),%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <addHexDigit@plt>
  test   %rax,%rax
  js     L21
  mov    0x4(%rsp),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbp
  je     L59
L26:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  movl   $0x0,0x4(%rsp)
  call   <addHexDigit@plt>
  test   %rax,%rax
  jns    L0
L21:
  mov    $0xffffffff,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L59:
  xor    %eax,%eax
  jmp    L25
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decHexString(unsigned char *hex, char *hexString, int len) {
  int val;
  while (len-- > 0) {
    val = 0;
    if (addHexDigit(&val, *hexString++) < 0 || addHexDigit(&val, *hexString++) < 0)
      return -1;
    *hex++ = (unsigned char)val;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L32:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L32
  sub    $0xd60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30d58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L111
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
L89:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L89
L111:
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  lea    -0x1(%rsi),%eax
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  movl   $0x1,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L95
  movslq %esi,%rax
  lea    0x10(%rsp,%rax,4),%rdx
  lea    0x14(%rsp),%rax
  mov    $0x1,%r11d
  mov    $0x1,%ecx
  jmp    L61
L42:
  cmp    %ecx,%r8d
  jle    L69
L99:
  add    $0x1,%ecx
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    %esi,%ecx
  je     L82
L61:
  mov    %rax,%r10
  mov    -0x4(%rax),%edi
  cmp    %edi,(%rax)
  jle    L57
  add    $0x1,%edi
  mov    %edi,(%rax)
L57:
  mov    %rdx,%r9
  mov    -0x4(%rdx),%edi
  cmp    %edi,-0x8(%rdx)
  jle    L42
  add    $0x1,%edi
  mov    %edi,-0x8(%rdx)
  jmp    L42
L69:
  mov    (%r10),%edi
  mov    -0x8(%r9),%r9d
  cmp    %r9d,%edi
  cmovl  %r9d,%edi
  cmp    %edi,%r11d
  cmovl  %edi,%r11d
  jmp    L99
L95:
  mov    $0x1,%r11d
L82:
  mov    %r11d,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x30d58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30d60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string

tool: D16: %d

tool: D11: %d


assistant: ```c
int main(void) {
  int N, COLUNAS[50000], i, pelaDireita, pelaEsquerda, hN, maiorTriangulo = 1;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", COLUNAS + i);
  }
  hN = N / 2;
  COLUNAS[0] = COLUNAS[N - 1] = 1;
  for (i = 1; i < N; i++) {
    pelaDireita = i;
    pelaEsquerda = N - 1 - i;
    if (COLUNAS[pelaDireita] > COLUNAS[pelaDireita - 1]) {
      COLUNAS[pelaDireita] = COLUNAS[pelaDireita - 1] + 1;
    }
    if (COLUNAS[pelaEsquerda] > COLUNAS[pelaEsquerda + 1]) {
      COLUNAS[pelaEsquerda] = COLUNAS[pelaEsquerda + 1] + 1;
    }
    if (i >= hN) {
      if (COLUNAS[pelaDireita] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaDireita];
      }
      if (COLUNAS[pelaEsquerda] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaEsquerda];
      }
    }
  }
  printf("%d\n", maiorTriangulo);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x30000(%rsp),%r11
L51:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L51
  sub    $0xd68,%rsp
  lea    D16(%rip),%r13
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x30d58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L110
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  mov    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L4
  mov    %esi,%r8d
  lea    -0x1(%rsi),%eax
  shr    $0x1f,%r8d
  cltq
  add    %esi,%r8d
  movl   $0x1,0x10(%rsp,%rax,4)
  sar    %r8d
  movl   $0x1,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L80
  movslq %esi,%rax
  lea    0x14(%rsp),%rdx
  mov    $0x1,%edi
  mov    $0x1,%r9d
  lea    (%r12,%rax,4),%rax
  mov    $0x1,%ecx
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%rdx),%edi
  add    $0x4,%rdx
L46:
  cmp    %edi,(%rdx)
  jle    L103
  add    $0x1,%edi
  mov    %edi,(%rdx)
L103:
  mov    -0x4(%rax),%edi
  cmp    %edi,-0x8(%rax)
  jle    L97
  add    $0x1,%edi
  mov    %edi,-0x8(%rax)
L97:
  cmp    %ecx,%r8d
  jg     L11
  mov    (%rdx),%edi
  mov    -0x8(%rax),%r10d
  cmp    %r10d,%edi
  cmovl  %r10d,%edi
  cmp    %edi,%r9d
  cmovl  %edi,%r9d
L11:
  add    $0x1,%ecx
  sub    $0x4,%rax
  cmp    %ecx,%esi
  jne    L39
L1:
  mov    %r9d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x30d58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x30d68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L110:
  sub    $0x1,%eax
  mov    $0x1,%r9d
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  movl   $0x1,0x10(%rsp)
  jmp    L1
L80:
  mov    $0x1,%r9d
  jmp    L1
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D16: %d

tool: D2: %d


assistant: ```c
int main(void) {
  int N, COLUNAS[50000], i, pelaDireita, pelaEsquerda, hN, maiorTriangulo = 1;
  scanf("%d", &N);
  for (i = 0; i < N; i++) {
    scanf("%d", COLUNAS + i);
  }
  hN = N / 2;
  COLUNAS[0] = COLUNAS[N - 1] = 1;
  for (i = 1; i < N; i++) {
    pelaDireita = i;
    pelaEsquerda = N - 1 - i;
    if (COLUNAS[pelaDireita] > COLUNAS[pelaDireita - 1]) {
      COLUNAS[pelaDireita] = COLUNAS[pelaDireita - 1] + 1;
    }
    if (COLUNAS[pelaEsquerda] > COLUNAS[pelaEsquerda + 1]) {
      COLUNAS[pelaEsquerda] = COLUNAS[pelaEsquerda + 1] + 1;
    }
    if (i >= hN) {
      if (COLUNAS[pelaDireita] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaDireita];
      }
      if (COLUNAS[pelaEsquerda] > maiorTriangulo) {
        maiorTriangulo = COLUNAS[pelaEsquerda];
      }
    }
  }
  printf("%d\n", maiorTriangulo);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L31
L44:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
L37:
  addl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0xf423d,-0x4(%rbp)
  jbe    L44
  mov    $0xf4240,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string

tool: D18: %d


tool: D2: z not found below %d


assistant: ```c
void find_n(unsigned int z) {
  while (z < 1000000 - 2) {
    if ((!is_prime(z)) && (!is_prime(z + 2))) {
      printf("%d\n", z);
      return;
    }
    z++;
  }
  printf("z not found below %d\n", 1000000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_n>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xf423d,%edi
  jbe    L0
L45:
  mov    $0xf4240,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L3:
  pop    %rbx
  ret
L12:
  add    $0x1,%ebx
  cmp    $0xf423e,%ebx
  je     L45
L0:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L12
  lea    0x2(%rbx),%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L12
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D7: z not found below %d


tool: D6: %d


assistant: ```c
void find_n(unsigned int z) {
  while (z < 1000000 - 2) {
    if ((!is_prime(z)) && (!is_prime(z + 2))) {
      printf("%d\n", z);
      return;
    }
    z++;
  }
  printf("z not found below %d\n", 1000000);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_n>:
  endbr64
  push   %rbp
  cmp    $0xf423d,%edi
  ja     L11
  mov    %edi,%ebp
  jmp    L43
  nopl   0x0(%rax)
L1:
  add    $0x1,%ebp
  cmp    $0xf423e,%ebp
  je     L11
L43:
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L1
  lea    0x2(%rbp),%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L1
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L11:
  mov    $0xf4240,%esi
  lea    D8(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D18: %d


tool: D8: z not found below %d


assistant: ```c
void find_n(unsigned int z) {
  while (z < 1000000 - 2) {
    if ((!is_prime(z)) && (!is_prime(z + 2))) {
      printf("%d\n", z);
      return;
    }
    z++;
  }
  printf("z not found below %d\n", 1000000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_n>:
  endbr64
  push   %rbp
  cmp    $0xf423d,%edi
  ja     L33
  mov    %edi,%ebp
  jmp    L34
  nopl   0x0(%rax)
L16:
  add    $0x1,%ebp
  cmp    $0xf423e,%ebp
  je     L33
L34:
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L16
  lea    0x2(%rbp),%edi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L16
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L33:
  mov    $0xf4240,%esi
  lea    D19(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D4: %d


tool: D19: z not found below %d


assistant: ```c
void find_n(unsigned int z) {
  while (z < 1000000 - 2) {
    if ((!is_prime(z)) && (!is_prime(z + 2))) {
      printf("%d\n", z);
      return;
    }
    z++;
  }
  printf("z not found below %d\n", 1000000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <mydup2@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int tmp = mydup2(2, 5);
  printf("%d\n", tmp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <mydup2@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int tmp = mydup2(2, 5);
  printf("%d\n", tmp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <mydup2@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int tmp = mydup2(2, 5);
  printf("%d\n", tmp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0x2,%edi
  call   <mydup2@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int tmp = mydup2(2, 5);
  printf("%d\n", tmp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<displayMax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L7
L18:
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L37:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L9
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x14(%rbp)
L9:
  addl   $0x1,-0x10(%rbp)
L31:
  cmpl   $0x13,-0x10(%rbp)
  jle    L37
  addl   $0x1,-0x18(%rbp)
L7:
  cmpl   $0x9,-0x18(%rbp)
  jle    L18
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L20:
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L39:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L47:
  cmpl   $0x13,-0x8(%rbp)
  jle    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L61:
  cmpl   $0x9,-0xc(%rbp)
  jle    L20
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D6
type: string

tool: D28: 
The maximum value is %d.

tool: D3: 
From our array:

tool: D6: %3d

assistant: ```c
void displayMax(int nums[10][20]) {
  int i = 0, maxVal = 0, max = nums[0][0];
  for (i = 0; i < 10; i++) {
    for (int j = 0; j < 20; ++j)
      if (maxVal < nums[i][j])
        maxVal = nums[i][j];
  }
  printf("\nThe maximum value is %d.", maxVal);
  printf("\nFrom our array:\n");
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 20; ++j) {
      printf("%3d", nums[i][j]);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<displayMax>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x50(%rdi),%rbp
  lea    0x370(%rdi),%r12
  mov    %rbp,%rcx
  mov    $0x0,%esi
L28:
  lea    -0x50(%rcx),%rax
L15:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
  add    $0x50,%rcx
  cmp    %r12,%rcx
  jne    L28
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%r13
L22:
  lea    -0x50(%rbp),%rbx
L7:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x50,%rbp
  cmp    %r12,%rbp
  jne    L22
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D22
datatype: string

tool: D3: 
The maximum value is %d.

tool: D20: 
From our array:

tool: D22: %3d

assistant: ```c
void displayMax(int nums[10][20]) {
  int i = 0, maxVal = 0, max = nums[0][0];
  for (i = 0; i < 10; i++) {
    for (int j = 0; j < 20; ++j)
      if (maxVal < nums[i][j])
        maxVal = nums[i][j];
  }
  printf("\nThe maximum value is %d.", maxVal);
  printf("\nFrom our array:\n");
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 20; ++j) {
      printf("%3d", nums[i][j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<displayMax>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  lea    0x370(%rdi),%r12
  push   %rbp
  lea    0x50(%rdi),%rbp
  push   %rbx
  mov    %rbp,%rcx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L14:
  lea    -0x50(%rcx),%rax
  nopl   0x0(%rax)
L4:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L4
  lea    0x50(%rax),%rcx
  cmp    %r12,%rcx
  jne    L14
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  lea    D23(%rip),%r13
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  lea    -0x50(%rbp),%rbx
  nopl   0x0(%rax)
L35:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L35
  mov    $0xa,%edi
  lea    0x50(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D26
type_infered: string

tool: D16: 
The maximum value is %d.

tool: D23: %3d

tool: D26: 
From our array:

assistant: ```c
void displayMax(int nums[10][20]) {
  int i = 0, maxVal = 0, max = nums[0][0];
  for (i = 0; i < 10; i++) {
    for (int j = 0; j < 20; ++j)
      if (maxVal < nums[i][j])
        maxVal = nums[i][j];
  }
  printf("\nThe maximum value is %d.", maxVal);
  printf("\nFrom our array:\n");
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 20; ++j) {
      printf("%3d", nums[i][j]);
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hash2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x7,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x18,%rax
  add    %rdx,%rax
  add    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash2(const char *rawKey) {
  const unsigned char *s = (const unsigned char *)rawKey;
  unsigned long hash = 0;
  do {
    hash ^= (unsigned long)*s;
    hash += (hash << 1) + (hash << 4) + (hash << 7) + (hash << 8) + (hash << 24);
  } while (*++s);
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash2>:
  endbr64
  mov    $0x0,%eax
L1:
  movzbl (%rdi),%edx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x18,%rax
  mov    %rdx,%rcx
  shl    $0x7,%rcx
  lea    (%rdx,%rdx,8),%rsi
  lea    (%rcx,%rsi,2),%rcx
  add    %rdx,%rcx
  shl    $0x8,%rdx
  add    %rcx,%rdx
  add    %rdx,%rax
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L1
  ret
```

assistant: ```c
unsigned long hash2(const char *rawKey) {
  const unsigned char *s = (const unsigned char *)rawKey;
  unsigned long hash = 0;
  do {
    hash ^= (unsigned long)*s;
    hash += (hash << 1) + (hash << 4) + (hash << 7) + (hash << 8) + (hash << 24);
  } while (*++s);
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash2>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  movzbl %dl,%edx
  add    $0x1,%rdi
  xor    %rax,%rdx
  mov    %rdx,%rcx
  lea    (%rdx,%rdx,8),%rsi
  mov    %rdx,%rax
  shl    $0x7,%rcx
  shl    $0x18,%rax
  lea    (%rcx,%rsi,2),%rcx
  add    %rdx,%rcx
  shl    $0x8,%rdx
  add    %rcx,%rdx
  add    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  ret
```

assistant: ```c
unsigned long hash2(const char *rawKey) {
  const unsigned char *s = (const unsigned char *)rawKey;
  unsigned long hash = 0;
  do {
    hash ^= (unsigned long)*s;
    hash += (hash << 1) + (hash << 4) + (hash << 7) + (hash << 8) + (hash << 24);
  } while (*++s);
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash2>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  movzbl %dl,%edx
  add    $0x1,%rdi
  xor    %rax,%rdx
  mov    %rdx,%rcx
  lea    (%rdx,%rdx,8),%rsi
  mov    %rdx,%rax
  shl    $0x7,%rcx
  shl    $0x18,%rax
  lea    (%rcx,%rsi,2),%rcx
  add    %rdx,%rcx
  shl    $0x8,%rdx
  add    %rcx,%rdx
  add    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  ret
```

assistant: ```c
unsigned long hash2(const char *rawKey) {
  const unsigned char *s = (const unsigned char *)rawKey;
  unsigned long hash = 0;
  do {
    hash ^= (unsigned long)*s;
    hash += (hash << 1) + (hash << 4) + (hash << 7) + (hash << 8) + (hash << 24);
  } while (*++s);
  return hash;
}
```