ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0x7d1,%esi
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  call   <Cmonth@plt>
  xor    %edx,%edx
  mov    $0xfa1,%esi
  mov    $0x1,%edi
  lea    -0x1(%rax),%r13d
  call   <Cmonth@plt>
  mov    $0xfa1,%esi
  mov    $0x1,%edi
  mov    %eax,%r12d
  call   <Rmonth@plt>
  mov    $0xfa1,%esi
  mov    $0x7d1,%edi
  sub    $0x2,%eax
  sub    %eax,%r12d
  call   <Cyear@plt>
  lea    0x0(%r13,%r12,1),%ebp
  mov    %r13d,%edx
  mov    $0x1,%esi
  add    %eax,%ebp
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D23: Starting month %d has %d days left in the year!


tool: D4: Ending month %d is %d days into the year!


tool: D3:  %d total days!


assistant: ```c
int main(void) {
  int startmonth = 1, endmonth = 1, startyear = 2001, endyear = 4001, startday = 1, endday = 2, sdays = 0, edays = 0, tdays = 0;
  sdays = Cmonth(startmonth, startyear, 1) - startday;
  edays = Cmonth(endmonth, endyear, 0) - (Rmonth(endmonth, endyear) - endday);
  tdays = Cyear(startyear, endyear) + (sdays + edays);
  printf("Starting month %d has %d days left in the year!\n", startmonth, sdays);
  printf("Ending month %d is %d days into the year!\n", endmonth, edays);
  printf(" %d total days!\n", tdays);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0x7d1,%esi
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  call   <Cmonth@plt>
  xor    %edx,%edx
  mov    $0xfa1,%esi
  mov    $0x1,%edi
  lea    -0x1(%rax),%r13d
  call   <Cmonth@plt>
  mov    $0xfa1,%esi
  mov    $0x1,%edi
  mov    %eax,%r12d
  call   <Rmonth@plt>
  mov    $0xfa1,%esi
  mov    $0x7d1,%edi
  sub    $0x2,%eax
  sub    %eax,%r12d
  call   <Cyear@plt>
  lea    0x0(%r13,%r12,1),%ebp
  mov    %r13d,%edx
  mov    $0x1,%esi
  add    %eax,%ebp
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D29: Starting month %d has %d days left in the year!


tool: D27: Ending month %d is %d days into the year!


tool: D24:  %d total days!


assistant: ```c
int main(void) {
  int startmonth = 1, endmonth = 1, startyear = 2001, endyear = 4001, startday = 1, endday = 2, sdays = 0, edays = 0, tdays = 0;
  sdays = Cmonth(startmonth, startyear, 1) - startday;
  edays = Cmonth(endmonth, endyear, 0) - (Rmonth(endmonth, endyear) - endday);
  tdays = Cyear(startyear, endyear) + (sdays + edays);
  printf("Starting month %d has %d days left in the year!\n", startmonth, sdays);
  printf("Ending month %d is %d days into the year!\n", endmonth, edays);
  printf(" %d total days!\n", tdays);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<maths_median_filter_3x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  -0x18(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L46
  movss  -0x1c(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L46
  movss  -0x1c(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  jb     L69
  movss  -0x18(%rbp),%xmm0
  jmp    L37
L69:
  movss  -0x1c(%rbp),%xmm0
L37:
  movss  %xmm0,-0x4(%rbp)
  jmp    L109
L46:
  movss  -0x14(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  jb     L19
  movss  -0x1c(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  jb     L19
  movss  -0x1c(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L113
  movss  -0x14(%rbp),%xmm0
  jmp    L23
L113:
  movss  -0x1c(%rbp),%xmm0
L23:
  movss  %xmm0,-0x4(%rbp)
  jmp    L109
L19:
  movss  -0x18(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jb     L49
  movss  -0x14(%rbp),%xmm0
  jmp    L14
L49:
  movss  -0x18(%rbp),%xmm0
L14:
  movss  %xmm0,-0x4(%rbp)
L109:
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float maths_median_filter_3x(float a, float b, float c) {
  float middle;
  if ((a <= b) && (a <= c)) {
    middle = (b <= c) ? b : c;
  } else if ((b <= a) && (b <= c)) {
    middle = (a <= c) ? a : c;
  } else {
    middle = (a <= b) ? a : b;
  }
  return middle;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maths_median_filter_3x>:
  endbr64
  movaps %xmm0,%xmm3
  comiss %xmm0,%xmm1
  jb     L66
  comiss %xmm0,%xmm2
  jb     L69
  movaps %xmm1,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm1
  andnps %xmm2,%xmm0
  orps   %xmm1,%xmm0
  ret
L66:
  comiss %xmm1,%xmm0
  jb     L12
  comiss %xmm1,%xmm2
  jb     L12
L15:
  movaps %xmm3,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm2,%xmm0
  orps   %xmm3,%xmm0
  ret
L12:
  movaps %xmm3,%xmm0
  cmpless %xmm1,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm1,%xmm0
  orps   %xmm3,%xmm0
  ret
L35:
  movaps %xmm3,%xmm0
  ret
L69:
  ucomiss %xmm1,%xmm0
  jp     L35
  jne    L35
  comiss %xmm1,%xmm2
  jae    L15
  ret
```

assistant: ```c
float maths_median_filter_3x(float a, float b, float c) {
  float middle;
  if ((a <= b) && (a <= c)) {
    middle = (b <= c) ? b : c;
  } else if ((b <= a) && (b <= c)) {
    middle = (a <= c) ? a : c;
  } else {
    middle = (a <= b) ? a : b;
  }
  return middle;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<maths_median_filter_3x>:
  endbr64
  comiss %xmm0,%xmm1
  movaps %xmm0,%xmm3
  jb     L6
  comiss %xmm0,%xmm2
  jae    L26
  ucomiss %xmm1,%xmm0
  jp     L68
  jne    L68
  comiss %xmm1,%xmm2
  jae    L24
L68:
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L6:
  comiss %xmm1,%xmm0
  jb     L36
  comiss %xmm1,%xmm2
  jb     L36
L24:
  movaps %xmm3,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm2,%xmm0
  orps   %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L36:
  movaps %xmm3,%xmm0
  cmpless %xmm1,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm1,%xmm0
  orps   %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movaps %xmm1,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm1
  andnps %xmm2,%xmm0
  orps   %xmm1,%xmm0
  ret
```

assistant: ```c
float maths_median_filter_3x(float a, float b, float c) {
  float middle;
  if ((a <= b) && (a <= c)) {
    middle = (b <= c) ? b : c;
  } else if ((b <= a) && (b <= c)) {
    middle = (a <= c) ? a : c;
  } else {
    middle = (a <= b) ? a : b;
  }
  return middle;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maths_median_filter_3x>:
  endbr64
  comiss %xmm0,%xmm1
  movaps %xmm0,%xmm3
  jb     L19
  comiss %xmm0,%xmm2
  jae    L6
  ucomiss %xmm1,%xmm0
  jp     L11
  jne    L11
  comiss %xmm1,%xmm2
  jae    L1
L11:
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  comiss %xmm1,%xmm0
  jb     L65
  comiss %xmm1,%xmm2
  jb     L65
L1:
  movaps %xmm3,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm2,%xmm0
  orps   %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L65:
  movaps %xmm3,%xmm0
  cmpless %xmm1,%xmm0
  andps  %xmm0,%xmm3
  andnps %xmm1,%xmm0
  orps   %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movaps %xmm1,%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm1
  andnps %xmm2,%xmm0
  orps   %xmm1,%xmm0
  ret
```

assistant: ```c
float maths_median_filter_3x(float a, float b, float c) {
  float middle;
  if ((a <= b) && (a <= c)) {
    middle = (b <= c) ? b : c;
  } else if ((b <= a) && (b <= c)) {
    middle = (a <= c) ? a : c;
  } else {
    middle = (a <= b) ? a : b;
  }
  return middle;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %rcx,-0x18(%rbp)
  jmp    L42
L14:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sub    %eax,-0x4(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L14
  jmp    L98
L38:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
L98:
  cmpl   $0x0,-0x4(%rbp)
  js     L38
  jmp    L20
L70:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  sub    %eax,-0x8(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L70
  jmp    L85
L59:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
L85:
  cmpl   $0x0,-0x8(%rbp)
  js     L59
  jmp    L84
L75:
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  sub    %eax,-0xc(%rbp)
L84:
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L75
  jmp    L2
L94:
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
L2:
  cmpl   $0x0,-0xc(%rbp)
  js     L94
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int idx(int i, int j, int k, int *dim) {
  while (i >= dim[1])
    i -= dim[1];
  while (i < 0)
    i += dim[1];
  while (j >= dim[2])
    j -= dim[2];
  while (j < 0)
    j += dim[2];
  while (k >= dim[3])
    k -= dim[3];
  while (k < 0)
    k += dim[3];
  return ((i * dim[2] + j) * dim[3] + k);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<idx>:
  endbr64
  mov    0x4(%rcx),%eax
  cmp    %eax,%edi
  jl     L61
L98:
  sub    %eax,%edi
  cmp    %eax,%edi
  jge    L98
L61:
  test   %edi,%edi
  jns    L106
L30:
  add    %eax,%edi
  js     L30
L106:
  mov    0x8(%rcx),%eax
  cmp    %eax,%esi
  jl     L104
L92:
  sub    %eax,%esi
  cmp    %eax,%esi
  jge    L92
L104:
  test   %esi,%esi
  jns    L44
L42:
  add    %eax,%esi
  js     L42
L44:
  mov    0xc(%rcx),%ecx
  cmp    %ecx,%edx
  jl     L48
L24:
  sub    %ecx,%edx
  cmp    %ecx,%edx
  jge    L24
L48:
  test   %edx,%edx
  jns    L36
L21:
  add    %ecx,%edx
  js     L21
L36:
  imul   %edi,%eax
  add    %esi,%eax
  imul   %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int idx(int i, int j, int k, int *dim) {
  while (i >= dim[1])
    i -= dim[1];
  while (i < 0)
    i += dim[1];
  while (j >= dim[2])
    j -= dim[2];
  while (j < 0)
    j += dim[2];
  while (k >= dim[3])
    k -= dim[3];
  while (k < 0)
    k += dim[3];
  return ((i * dim[2] + j) * dim[3] + k);
}
```
user: What is the c source code of the assembly code below?

```asm
<idx>:
  endbr64
  mov    0x4(%rcx),%eax
  cmp    %edi,%eax
  jg     L19
  nopl   0x0(%rax,%rax,1)
L89:
  sub    %eax,%edi
  cmp    %edi,%eax
  jle    L89
L12:
  mov    0x8(%rcx),%eax
  cmp    %esi,%eax
  jg     L44
  nopl   (%rax)
L42:
  sub    %eax,%esi
  cmp    %esi,%eax
  jle    L42
L135:
  mov    0xc(%rcx),%ecx
  cmp    %edx,%ecx
  jg     L49
  nopl   (%rax)
L21:
  sub    %ecx,%edx
  cmp    %edx,%ecx
  jle    L21
L65:
  imul   %edi,%eax
  add    %esi,%eax
  imul   %ecx,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L49:
  test   %edx,%edx
  jns    L65
  nopl   0x0(%rax)
L16:
  add    %ecx,%edx
  js     L16
  imul   %edi,%eax
  add    %esi,%eax
  imul   %ecx,%eax
  add    %edx,%eax
  ret
  nop
L44:
  test   %esi,%esi
  jns    L135
  nopl   0x0(%rax)
L15:
  add    %eax,%esi
  js     L15
  jmp    L135
  xchg   %ax,%ax
L19:
  test   %edi,%edi
  jns    L12
  nopl   0x0(%rax)
L130:
  add    %eax,%edi
  js     L130
  jmp    L12
```

assistant: ```c
int idx(int i, int j, int k, int *dim) {
  while (i >= dim[1])
    i -= dim[1];
  while (i < 0)
    i += dim[1];
  while (j >= dim[2])
    j -= dim[2];
  while (j < 0)
    j += dim[2];
  while (k >= dim[3])
    k -= dim[3];
  while (k < 0)
    k += dim[3];
  return ((i * dim[2] + j) * dim[3] + k);
}
```
user: Translate the below assembly code into C programming language:

```asm
<idx>:
  endbr64
  mov    0x4(%rcx),%eax
  cmp    %edi,%eax
  jg     L112
  nopl   0x0(%rax,%rax,1)
L69:
  sub    %eax,%edi
  cmp    %edi,%eax
  jle    L69
L81:
  mov    0x8(%rcx),%eax
  cmp    %esi,%eax
  jg     L133
  nopl   (%rax)
L111:
  sub    %eax,%esi
  cmp    %esi,%eax
  jle    L111
L92:
  mov    0xc(%rcx),%ecx
  cmp    %edx,%ecx
  jg     L116
  nopl   (%rax)
L117:
  sub    %ecx,%edx
  cmp    %edx,%ecx
  jle    L117
L104:
  imul   %edi,%eax
  add    %esi,%eax
  imul   %ecx,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L116:
  test   %edx,%edx
  jns    L104
  nopl   0x0(%rax)
L11:
  add    %ecx,%edx
  js     L11
  imul   %edi,%eax
  add    %esi,%eax
  imul   %ecx,%eax
  add    %edx,%eax
  ret
  nop
L133:
  test   %esi,%esi
  jns    L92
  nopl   0x0(%rax)
L103:
  add    %eax,%esi
  js     L103
  jmp    L92
  xchg   %ax,%ax
L112:
  test   %edi,%edi
  jns    L81
  nopl   0x0(%rax)
L51:
  add    %eax,%edi
  js     L51
  jmp    L81
```

assistant: ```c
int idx(int i, int j, int k, int *dim) {
  while (i >= dim[1])
    i -= dim[1];
  while (i < 0)
    i += dim[1];
  while (j >= dim[2])
    j -= dim[2];
  while (j < 0)
    j += dim[2];
  while (k >= dim[3])
    k -= dim[3];
  while (k < 0)
    k += dim[3];
  return ((i * dim[2] + j) * dim[3] + k);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quantiUgualiConMergeLoop2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L78:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jne    L39
  addl   $0x1,-0x8(%rbp)
L39:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L12
  cmpl   $0x9,-0x10(%rbp)
  je     L51
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L78
  jmp    L45
L51:
  nop
  jmp    L45
L23:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jne    L72
  addl   $0x1,-0x8(%rbp)
L72:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x9,-0x10(%rbp)
  jne    L45
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x9,-0xc(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop2(int A[][10], int B[][10], int k) {
  int i, j, cont = 0, quanti = 0;
  i = 0;
  j = 0;
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (j == -1) {
      if (i == 10 - 1)
        break;
      j = i;
      i = 0;
    }
  }
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (i == 10 - 1) {
      i = j + 2;
      j = 10 - 1;
    }
  }
  return cont;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quantiUgualiConMergeLoop2>:
  endbr64
  test   %edx,%edx
  jle    L30
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %edx,%r11d
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  jmp    L73
L54:
  cmp    %esi,%r11d
  je     L22
L73:
  movslq %edx,%rax
  lea    (%rax,%rax,4),%r8
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rbx
  add    %r10,%rax
  mov    (%rax,%r8,8),%eax
  cmp    %eax,(%rbx,%r8,8)
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  add    $0x1,%esi
  add    $0x1,%edx
  sub    $0x1,%ecx
  cmp    $0xffffffff,%ecx
  jne    L54
  cmp    $0x9,%edx
  je     L46
  mov    %edx,%ecx
  mov    $0x0,%edx
  jmp    L54
L46:
  cmp    %esi,%r11d
  jg     L35
L22:
  mov    %edi,%eax
  pop    %rbx
  ret
L1:
  lea    0x1(%rcx),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
L34:
  cmp    %esi,%r11d
  je     L22
L35:
  movslq %edx,%rax
  lea    (%rax,%rax,4),%r8
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rbx
  add    %r10,%rax
  mov    (%rax,%r8,8),%eax
  cmp    %eax,(%rbx,%r8,8)
  sete   %al
  movzbl %al,%eax
  add    %eax,%edi
  add    $0x1,%esi
  add    $0x1,%edx
  cmp    $0x9,%edx
  je     L1
  sub    $0x1,%ecx
  jmp    L34
L30:
  mov    $0x0,%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop2(int A[][10], int B[][10], int k) {
  int i, j, cont = 0, quanti = 0;
  i = 0;
  j = 0;
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (j == -1) {
      if (i == 10 - 1)
        break;
      j = i;
      i = 0;
    }
  }
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (i == 10 - 1) {
      i = j + 2;
      j = 10 - 1;
    }
  }
  return cont;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quantiUgualiConMergeLoop2>:
  endbr64
  test   %edx,%edx
  jle    L21
  mov    %rsi,%r10
  mov    %edx,%r11d
  push   %rbx
  mov    %rdi,%r9
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L54
  nopl   0x0(%rax)
L79:
  cmp    %esi,%r11d
  je     L28
L54:
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rdi
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rbx
  add    %r10,%rax
  mov    (%rax,%rdi,8),%eax
  cmp    %eax,(%rbx,%rdi,8)
  sete   %al
  add    $0x1,%esi
  add    $0x1,%ecx
  movzbl %al,%eax
  add    %eax,%r8d
  sub    $0x1,%edx
  jae    L79
  cmp    $0x9,%ecx
  je     L38
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    %esi,%r11d
  jne    L54
L28:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nop
L38:
  cmp    %esi,%r11d
  jle    L28
  nopl   (%rax)
L59:
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rdi
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rbx
  add    %r10,%rax
  mov    (%rax,%rdi,8),%eax
  cmp    %eax,(%rbx,%rdi,8)
  sete   %al
  add    $0x1,%esi
  add    $0x1,%ecx
  sub    $0x1,%edx
  movzbl %al,%eax
  add    %eax,%r8d
  cmp    %r11d,%esi
  jne    L59
  mov    %r8d,%eax
  pop    %rbx
  ret
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop2(int A[][10], int B[][10], int k) {
  int i, j, cont = 0, quanti = 0;
  i = 0;
  j = 0;
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (j == -1) {
      if (i == 10 - 1)
        break;
      j = i;
      i = 0;
    }
  }
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (i == 10 - 1) {
      i = j + 2;
      j = 10 - 1;
    }
  }
  return cont;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quantiUgualiConMergeLoop2>:
  endbr64
  test   %edx,%edx
  jle    L25
  mov    %rsi,%r10
  mov    %edx,%r11d
  push   %rbx
  mov    %rdi,%r9
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L45
  nopl   0x0(%rax)
L50:
  cmp    %esi,%r11d
  je     L57
L45:
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rdi
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%rbx
  add    %r10,%rax
  mov    (%rax,%rdi,8),%eax
  cmp    %eax,(%rbx,%rdi,8)
  sete   %al
  add    $0x1,%esi
  add    $0x1,%ecx
  movzbl %al,%eax
  add    %eax,%r8d
  sub    $0x1,%edx
  jae    L50
  cmp    $0x9,%ecx
  je     L37
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    %esi,%r11d
  jne    L45
L57:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nop
L37:
  cmp    %esi,%r11d
  jle    L57
  nopl   (%rax)
L24:
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rdi
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%r10,%rax,1),%rbx
  add    %r9,%rax
  mov    (%rax,%rdi,8),%eax
  cmp    %eax,(%rbx,%rdi,8)
  sete   %al
  add    $0x1,%esi
  add    $0x1,%ecx
  sub    $0x1,%edx
  movzbl %al,%eax
  add    %eax,%r8d
  cmp    %r11d,%esi
  jne    L24
  mov    %r8d,%eax
  pop    %rbx
  ret
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int quantiUgualiConMergeLoop2(int A[][10], int B[][10], int k) {
  int i, j, cont = 0, quanti = 0;
  i = 0;
  j = 0;
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (j == -1) {
      if (i == 10 - 1)
        break;
      j = i;
      i = 0;
    }
  }
  while (quanti < k) {
    if (A[i][j] == B[i][j])
      cont++;
    quanti++;
    i++;
    j--;
    if (i == 10 - 1) {
      i = j + 2;
      j = 10 - 1;
    }
  }
  return cont;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_to_numerical>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L50
L63:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    $0x54,%eax
  je     L92
  cmp    $0x54,%eax
  jg     L37
  cmp    $0x47,%eax
  je     L15
  cmp    $0x47,%eax
  jg     L37
  cmp    $0x41,%eax
  je     L36
  cmp    $0x43,%eax
  je     L47
  jmp    L37
L36:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x0,(%rax)
  jmp    L69
L47:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x1,(%rax)
  jmp    L69
L15:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x2,(%rax)
  jmp    L69
L92:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x3,(%rax)
  jmp    L69
L37:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movl   $0xffffffff,(%rax)
  nop
L69:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L63
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void convert_to_numerical(char *sLine, long lLen, int **ipSeq) {
  long j = 0;
  for (j = 0; j < lLen; j++) {
    switch (toupper(sLine[j])) {
    case 'A':
      **ipSeq = 0;
      break;
    case 'C':
      **ipSeq = 1;
      break;
    case 'G':
      **ipSeq = 2;
      break;
    case 'T':
      **ipSeq = 3;
      break;
    default:
      **ipSeq = -1;
      break;
    }
    *ipSeq += 1;
  }
  *ipSeq -= lLen;
  return;
}
```