ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  mov    $0x0,%ebx
  lea    0x6(%rsp),%r12
L14:
  mov    $0x0,%eax
  call   <GetKeypress@plt>
  mov    %al,0x6(%rsp)
  test   %al,%al
  je     L14
  mov    %r12,%rdi
  call   <ConsoleWrite@plt>
  movzbl 0x6(%rsp),%eax
  movslq %ebx,%rdx
  mov    %al,0x0(%rbp,%rdx,1)
  add    $0x1,%ebx
  cmp    $0xa,%al
  jne    L14
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetLine(char *String) {
  int i;
  char Character[2];
  Character[1] = '\0';
  i = 0;
  do {
    Character[0] = GetKeypress();
    if (Character[0] != '\0') {
      ConsoleWrite(Character);
      String[i] = Character[0];
      i++;
    }
  } while (Character[0] != '\n');
  String[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%r12
  nopl   (%rax)
L25:
  xor    %eax,%eax
  call   <GetKeypress@plt>
  mov    %al,0x6(%rsp)
  test   %al,%al
  je     L25
  mov    %r12,%rdi
  lea    0x1(%rbx),%r13d
  call   <ConsoleWrite@plt>
  movzbl 0x6(%rsp),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  cmp    $0xa,%al
  je     L32
  movslq %r13d,%rbx
  jmp    L25
  nopl   (%rax)
L32:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetLine(char *String) {
  int i;
  char Character[2];
  Character[1] = '\0';
  i = 0;
  do {
    Character[0] = GetKeypress();
    if (Character[0] != '\0') {
      ConsoleWrite(Character);
      String[i] = Character[0];
      i++;
    }
  } while (Character[0] != '\n');
  String[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%r12
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <GetKeypress@plt>
  mov    %al,0x6(%rsp)
  test   %al,%al
  je     L7
  mov    %r12,%rdi
  lea    0x1(%rbx),%r13d
  call   <ConsoleWrite@plt>
  movzbl 0x6(%rsp),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  cmp    $0xa,%al
  je     L37
  movslq %r13d,%rbx
  jmp    L7
  nopl   (%rax)
L37:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetLine(char *String) {
  int i;
  char Character[2];
  Character[1] = '\0';
  i = 0;
  do {
    Character[0] = GetKeypress();
    if (Character[0] != '\0') {
      ConsoleWrite(Character);
      String[i] = Character[0];
      i++;
    }
  } while (Character[0] != '\n');
  String[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<associerTableauString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <mallocBis@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L38
L33:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L33
  movl   $0x0,-0x1c(%rbp)
  jmp    L6
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L6:
  mov    -0x1c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L23
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **associerTableauString(char **tab1, char **tab2, int taille1, int taille2) {
  int i;
  int j;
  char **t_str_result;
  t_str_result = mallocBis(sizeof(char *) * (taille1 + taille2));
  for (i = 0; i < taille1; i += 1) {
    t_str_result[i] = strdup(tab1[i]);
  }
  for (j = 0; j < taille2; j += 1, i++) {
    t_str_result[i] = strdup(tab2[j]);
  }
  return t_str_result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<associerTableauString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r14d
  mov    %ecx,%r15d
  lea    (%rdx,%rcx,1),%edi
  shl    $0x3,%edi
  call   <mallocBis@plt>
  mov    %rax,%rbp
  test   %r14d,%r14d
  jle    L4
  mov    %r14d,%r13d
  mov    $0x0,%ebx
L11:
  mov    (%r12,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L11
L49:
  test   %r15d,%r15d
  jle    L35
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rbx
  movslq %r14d,%r14
  lea    0x0(%rbp,%r14,8),%r12
  lea    -0x1(%r15),%eax
  lea    0x8(%rdx,%rax,8),%r13
L45:
  mov    (%rbx),%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  add    $0x8,%rbx
  add    $0x8,%r12
  cmp    %r13,%rbx
  jne    L45
L35:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    $0x0,%r14d
  jmp    L49
```

assistant: ```c
char **associerTableauString(char **tab1, char **tab2, int taille1, int taille2) {
  int i;
  int j;
  char **t_str_result;
  t_str_result = mallocBis(sizeof(char *) * (taille1 + taille2));
  for (i = 0; i < taille1; i += 1) {
    t_str_result[i] = strdup(tab1[i]);
  }
  for (j = 0; j < taille2; j += 1, i++) {
    t_str_result[i] = strdup(tab2[j]);
  }
  return t_str_result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<associerTableauString>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%r14,%rcx,1),%edi
  push   %rbx
  shl    $0x3,%edi
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <mallocBis@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L25
  movslq %r14d,%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L49:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L49
L36:
  test   %r15d,%r15d
  jle    L43
  mov    0x8(%rsp),%rbx
  lea    -0x1(%r15),%eax
  lea    (%r12,%r14,8),%rbp
  lea    0x8(%rbx,%rax,8),%r13
  xchg   %ax,%ax
L22:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbx
  jne    L22
L43:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %r14d,%r14d
  jmp    L36
```

assistant: ```c
char **associerTableauString(char **tab1, char **tab2, int taille1, int taille2) {
  int i;
  int j;
  char **t_str_result;
  t_str_result = mallocBis(sizeof(char *) * (taille1 + taille2));
  for (i = 0; i < taille1; i += 1) {
    t_str_result[i] = strdup(tab1[i]);
  }
  for (j = 0; j < taille2; j += 1, i++) {
    t_str_result[i] = strdup(tab2[j]);
  }
  return t_str_result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<associerTableauString>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    (%r14,%rcx,1),%edi
  push   %rbx
  shl    $0x3,%edi
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <mallocBis@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L49
  movslq %r14d,%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L13:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L13
L3:
  test   %r15d,%r15d
  jle    L37
  mov    0x8(%rsp),%rbx
  lea    -0x1(%r15),%eax
  lea    (%r12,%r14,8),%rbp
  lea    0x8(%rbx,%rax,8),%r13
  xchg   %ax,%ax
L2:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %rbx,%r13
  jne    L2
L37:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %r14d,%r14d
  jmp    L3
```

assistant: ```c
char **associerTableauString(char **tab1, char **tab2, int taille1, int taille2) {
  int i;
  int j;
  char **t_str_result;
  t_str_result = mallocBis(sizeof(char *) * (taille1 + taille2));
  for (i = 0; i < taille1; i += 1) {
    t_str_result[i] = strdup(tab1[i]);
  }
  for (j = 0; j < taille2; j += 1, i++) {
    t_str_result[i] = strdup(tab2[j]);
  }
  return t_str_result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ecx,%rax
  mov    %rax,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x34(%rbp),%esi
  movslq %esi,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    %r15,%rdx
  imul   %r12,%rdx
  mov    %r13,%rax
  imul   %r14,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r14,%rax
  mul    %r12
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %esi,%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %esi,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    %r11,%rdx
  imul   %r8,%rdx
  mov    %r9,%rax
  imul   %r10,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r10,%rax
  mul    %r8
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rdx
  movslq %esi,%rax
  imul   %rdx,%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movslq %ecx,%rdx
  mov    -0x38(%rbp),%eax
  cltq
  imul   %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rdx,%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
long int foo(int n, int i, int j) {
  typedef int T[n];
  struct S {
    int a;
    T b[n];
  };
  return __builtin_offsetof(struct S, b[i][j]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rsi,%rdi
  movslq %edx,%rdx
  lea    0x1(%rdi,%rdx,1),%rax
  shl    $0x2,%rax
  ret
```

assistant: ```c
long int foo(int n, int i, int j) {
  typedef int T[n];
  struct S {
    int a;
    T b[n];
  };
  return __builtin_offsetof(struct S, b[i][j]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  movslq %edx,%rdx
  imul   %rsi,%rdi
  lea    0x1(%rdi,%rdx,1),%rax
  shl    $0x2,%rax
  ret
```

assistant: ```c
long int foo(int n, int i, int j) {
  typedef int T[n];
  struct S {
    int a;
    T b[n];
  };
  return __builtin_offsetof(struct S, b[i][j]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  movslq %edx,%rdx
  imul   %rsi,%rdi
  lea    0x1(%rdi,%rdx,1),%rax
  shl    $0x2,%rax
  ret
```

assistant: ```c
long int foo(int n, int i, int j) {
  typedef int T[n];
  struct S {
    int a;
    T b[n];
  };
  return __builtin_offsetof(struct S, b[i][j]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SkipEquiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <SkipSpaces@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L18
  lea    D7(%rip),%rax
  jmp    L13
L18:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SkipSpaces@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: 

assistant: ```c
char *SkipEquiv(const char *line) {
  char *c = SkipSpaces(line);
  if (*c != '=')
    return "";
  c++;
  return SkipSpaces(c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SkipEquiv>:
  endbr64
  sub    $0x8,%rsp
  call   <SkipSpaces@plt>
  lea    D2(%rip),%rdx
  cmpb   $0x3d,(%rax)
  je     L17
L15:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
L17:
  lea    0x1(%rax),%rdi
  call   <SkipSpaces@plt>
  mov    %rax,%rdx
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: 

assistant: ```c
char *SkipEquiv(const char *line) {
  char *c = SkipSpaces(line);
  if (*c != '=')
    return "";
  c++;
  return SkipSpaces(c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SkipEquiv>:
  endbr64
  sub    $0x8,%rsp
  call   <SkipSpaces@plt>
  cmpb   $0x3d,(%rax)
  je     L6
  lea    D5(%rip),%rax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L6:
  lea    0x1(%rax),%rdi
  add    $0x8,%rsp
  jmp    1050 <SkipSpaces@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: 

assistant: ```c
char *SkipEquiv(const char *line) {
  char *c = SkipSpaces(line);
  if (*c != '=')
    return "";
  c++;
  return SkipSpaces(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SkipEquiv>:
  endbr64
  sub    $0x8,%rsp
  call   <SkipSpaces@plt>
  cmpb   $0x3d,(%rax)
  je     L1
  lea    D7(%rip),%rax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L1:
  lea    0x1(%rax),%rdi
  add    $0x8,%rsp
  jmp    1050 <SkipSpaces@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: 

assistant: ```c
char *SkipEquiv(const char *line) {
  char *c = SkipSpaces(line);
  if (*c != '=')
    return "";
  c++;
  return SkipSpaces(c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocate_bit_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint64_t *allocate_bit_array(int len) {
  uint64_t *ret;
  ret = (uint64_t *)malloc(len * sizeof(uint64_t));
  for (int i = 0; i < len; i++)
    ret[i] = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<allocate_bit_array>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L18
  mov    %rax,%rdx
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%rcx
L2:
  movq   $0x0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L2
L18:
  pop    %rbx
  ret
```

assistant: ```c
uint64_t *allocate_bit_array(int len) {
  uint64_t *ret;
  ret = (uint64_t *)malloc(len * sizeof(uint64_t));
  for (int i = 0; i < len; i++)
    ret[i] = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<allocate_bit_array>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L5
  lea    0x0(,%rbp,8),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L5:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t *allocate_bit_array(int len) {
  uint64_t *ret;
  ret = (uint64_t *)malloc(len * sizeof(uint64_t));
  for (int i = 0; i < len; i++)
    ret[i] = 0;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocate_bit_array>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L2
  lea    0x0(,%rbp,8),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L2:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t *allocate_bit_array(int len) {
  uint64_t *ret;
  ret = (uint64_t *)malloc(len * sizeof(uint64_t));
  for (int i = 0; i < len; i++)
    ret[i] = 0;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<countTasks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x1,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L19
L2:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rsi
  cqto
  idiv   %rsi
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jl     L2
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long countTasks(int n, long max[3], long step[3]) {
  long k, count = 1;
  for (k = 0; k < n; k++)
    count *= max[k] / step[k];
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<countTasks>:
  endbr64
  mov    %rdx,%r8
  movslq %edi,%rdi
  test   %rdi,%rdi
  jle    L16
  mov    $0x1,%r9d
  mov    $0x0,%ecx
L21:
  mov    (%rsi,%rcx,8),%rax
  cqto
  idivq  (%r8,%rcx,8)
  imul   %rax,%r9
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L21
L25:
  mov    %r9,%rax
  ret
L16:
  mov    $0x1,%r9d
  jmp    L25
```

assistant: ```c
long countTasks(int n, long max[3], long step[3]) {
  long k, count = 1;
  for (k = 0; k < n; k++)
    count *= max[k] / step[k];
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<countTasks>:
  endbr64
  movslq %edi,%rdi
  mov    %rdx,%r8
  mov    $0x1,%r9d
  test   %rdi,%rdi
  jle    L17
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rsi,%rcx,8),%rax
  cqto
  idivq  (%r8,%rcx,8)
  add    $0x1,%rcx
  imul   %rax,%r9
  cmp    %rdi,%rcx
  jne    L18
L17:
  mov    %r9,%rax
  ret
```

assistant: ```c
long countTasks(int n, long max[3], long step[3]) {
  long k, count = 1;
  for (k = 0; k < n; k++)
    count *= max[k] / step[k];
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<countTasks>:
  endbr64
  movslq %edi,%rdi
  mov    %rdx,%r8
  mov    $0x1,%r9d
  test   %rdi,%rdi
  jle    L2
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rsi,%rcx,8),%rax
  cqto
  idivq  (%r8,%rcx,8)
  add    $0x1,%rcx
  imul   %rax,%r9
  cmp    %rdi,%rcx
  jne    L15
L2:
  mov    %r9,%rax
  ret
```

assistant: ```c
long countTasks(int n, long max[3], long step[3]) {
  long k, count = 1;
  for (k = 0; k < n; k++)
    count *= max[k] / step[k];
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D46(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L2
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D43(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L2:
  cmpl   $0xf9f,-0x24(%rbp)
  jle    L13
  movsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D46
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D48
type_infered: f64
name: extract_symbolic_data
arguments: tag: D43
type_infered: f64
name: extract_symbolic_data
arguments: tag: D2
type_infered: f64
name: extract_symbolic_data
arguments: tag: D24
type_infered: string

tool: {"D46": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x30,0x3f]}

tool: D48: 0.5

tool: D43: 1

tool: D2: 4

tool: D24: PI: %f


assistant: ```c
int main() {
  double sum = 0, pi;
  double step = 1.0 / (double)4000;
#pragma omp parallel for schedule(static) reduction(+ : sum) check
  for (int i = 0; i < 4000; ++i) {
    double x = (i + 0.5) * step;
    sum = sum + 4.0 / (1.0 + x * x);
  }
  pi = step * sum;
  printf("PI: %f\n", pi);
  return pi;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  movsd  D47(%rip),%xmm6
  movsd  D6(%rip),%xmm5
  movsd  D35(%rip),%xmm4
  movsd  D40(%rip),%xmm3
L9:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm4,%xmm0
  movapd %xmm3,%xmm2
  divsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  add    $0x1,%eax
  cmp    $0xfa0,%eax
  jne    L9
  mulsd  D6(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cvttsd2si 0x8(%rsp),%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D47
datatype: f64
name: extract_symbolic_data
arguments: data_label: D6
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D35
datatype: f64
name: extract_symbolic_data
arguments: data_label: D40
datatype: f64
name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D47: 0.5

tool: {"D6": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x30,0x3f]}

tool: D35: 1

tool: D40: 4

tool: D7: PI: %f


assistant: ```c
int main() {
  double sum = 0, pi;
  double step = 1.0 / (double)4000;
#pragma omp parallel for schedule(static) reduction(+ : sum) check
  for (int i = 0; i < 4000; ++i) {
    double x = (i + 0.5) * step;
    sum = sum + 4.0 / (1.0 + x * x);
  }
  pi = step * sum;
  printf("PI: %f\n", pi);
  return pi;
}
```