ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tag_set_config>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x44(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x48(%rbp),%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7a,%edi
  call   <tag_readblock@plt>
  test   %rax,%rax
  je     L19
  mov    -0x34(%rbp),%eax
  mov    %al,-0x30(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %al,-0x2f(%rbp)
  movb   $0xf8,-0x2e(%rbp)
  mov    -0x50(%rbp),%eax
  mov    %al,-0x2d(%rbp)
  mov    -0x50(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,-0x2c(%rbp)
  movb   $0x1,-0x2b(%rbp)
  lea    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L19
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7a,%edi
  call   <tag_writeblock@plt>
L19:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    $0x0,%edi
  call   <tag_write_sessionreg@plt>
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0xf8,%edx
  mov    $0xff,%esi
  mov    $0x2,%edi
  call   <tag_write_sessionreg@plt>
  mov    -0x50(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    $0x3,%edi
  call   <tag_write_sessionreg@plt>
  mov    -0x50(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    %eax,%edx
  mov    $0xff,%esi
  mov    $0x4,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0x1,%edx
  mov    $0xff,%esi
  mov    $0x5,%edi
  call   <tag_write_sessionreg@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void tag_set_config(int fd_off, int fd_on, int lastndef, int watchdog) {
  char buf[16];
  char buf2[16];
  memcpy(buf2, buf, 16);
  int nc_reg = (fd_off << 4) + (fd_on << 2);
  if (tag_readblock(0x7A, buf)) {
    buf[0] = nc_reg;
    buf[1] = lastndef;
    buf[2] = 0xF8;
    buf[3] = watchdog & 0xFF;
    buf[4] = (watchdog >> 8) & 0xFF;
    buf[5] = 1;
    if (!memcmp(buf2, buf, 16)) {
      tag_writeblock(0x7A, buf);
    }
  }
  tag_write_sessionreg(0, 0xFF, nc_reg);
  tag_write_sessionreg(1, 0xFF, lastndef);
  tag_write_sessionreg(2, 0xFF, 0xF8);
  tag_write_sessionreg(3, 0xFF, watchdog & 0xFF);
  tag_write_sessionreg(4, 0xFF, (watchdog >> 8) & 0xFF);
  tag_write_sessionreg(5, 0xFF, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tag_set_config>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x10(%rsp),%rdi
  mov    $0x10,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  shl    $0x4,%ebp
  lea    0x0(%rbp,%r13,4),%ebp
  mov    %r14,%rsi
  mov    $0x7a,%edi
  call   <tag_readblock@plt>
  test   %rax,%rax
  jne    L29
L24:
  mov    %ebp,%edx
  mov    $0xff,%esi
  mov    $0x0,%edi
  call   <tag_write_sessionreg@plt>
  mov    %r12d,%edx
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0xf8,%edx
  mov    $0xff,%esi
  mov    $0x2,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bl,%edx
  mov    $0xff,%esi
  mov    $0x3,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bh,%edx
  mov    $0xff,%esi
  mov    $0x4,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0x1,%edx
  mov    $0xff,%esi
  mov    $0x5,%edi
  call   <tag_write_sessionreg@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  mov    %bpl,(%rsp)
  mov    %r12b,0x1(%rsp)
  movb   $0xf8,0x2(%rsp)
  mov    %bl,0x3(%rsp)
  movzbl %bh,%eax
  mov    %al,0x4(%rsp)
  movb   $0x1,0x5(%rsp)
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x10,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L24
  mov    %rsp,%rsi
  mov    $0x7a,%edi
  call   <tag_writeblock@plt>
  jmp    L24
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tag_set_config(int fd_off, int fd_on, int lastndef, int watchdog) {
  char buf[16];
  char buf2[16];
  memcpy(buf2, buf, 16);
  int nc_reg = (fd_off << 4) + (fd_on << 2);
  if (tag_readblock(0x7A, buf)) {
    buf[0] = nc_reg;
    buf[1] = lastndef;
    buf[2] = 0xF8;
    buf[3] = watchdog & 0xFF;
    buf[4] = (watchdog >> 8) & 0xFF;
    buf[5] = 1;
    if (!memcmp(buf2, buf, 16)) {
      tag_writeblock(0x7A, buf);
    }
  }
  tag_write_sessionreg(0, 0xFF, nc_reg);
  tag_write_sessionreg(1, 0xFF, lastndef);
  tag_write_sessionreg(2, 0xFF, 0xF8);
  tag_write_sessionreg(3, 0xFF, watchdog & 0xFF);
  tag_write_sessionreg(4, 0xFF, (watchdog >> 8) & 0xFF);
  tag_write_sessionreg(5, 0xFF, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tag_set_config>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  mov    $0x10,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  shl    $0x4,%ebp
  mov    %ecx,%ebx
  lea    0x0(%rbp,%r13,4),%r13d
  mov    %ebx,%ebp
  sar    $0x8,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x10(%rsp),%r15
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %r14,%rsi
  mov    $0x7a,%edi
  call   <tag_readblock@plt>
  test   %rax,%rax
  jne    L28
L29:
  xor    %edi,%edi
  mov    %r13d,%edx
  mov    $0xff,%esi
  call   <tag_write_sessionreg@plt>
  mov    %r12d,%edx
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0xf8,%edx
  mov    $0xff,%esi
  mov    $0x2,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bl,%edx
  mov    $0xff,%esi
  mov    $0x3,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bpl,%edx
  mov    $0xff,%esi
  mov    $0x4,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0x1,%edx
  mov    $0xff,%esi
  mov    $0x5,%edi
  call   <tag_write_sessionreg@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L28:
  mov    $0x10,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    %r13b,(%rsp)
  mov    %r12b,0x1(%rsp)
  movb   $0xf8,0x2(%rsp)
  mov    %bx,0x3(%rsp)
  movb   $0x1,0x5(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L29
  mov    %r14,%rsi
  mov    $0x7a,%edi
  call   <tag_writeblock@plt>
  jmp    L29
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tag_set_config(int fd_off, int fd_on, int lastndef, int watchdog) {
  char buf[16];
  char buf2[16];
  memcpy(buf2, buf, 16);
  int nc_reg = (fd_off << 4) + (fd_on << 2);
  if (tag_readblock(0x7A, buf)) {
    buf[0] = nc_reg;
    buf[1] = lastndef;
    buf[2] = 0xF8;
    buf[3] = watchdog & 0xFF;
    buf[4] = (watchdog >> 8) & 0xFF;
    buf[5] = 1;
    if (!memcmp(buf2, buf, 16)) {
      tag_writeblock(0x7A, buf);
    }
  }
  tag_write_sessionreg(0, 0xFF, nc_reg);
  tag_write_sessionreg(1, 0xFF, lastndef);
  tag_write_sessionreg(2, 0xFF, 0xF8);
  tag_write_sessionreg(3, 0xFF, watchdog & 0xFF);
  tag_write_sessionreg(4, 0xFF, (watchdog >> 8) & 0xFF);
  tag_write_sessionreg(5, 0xFF, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tag_set_config>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  mov    $0x10,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  shl    $0x4,%ebp
  mov    %ecx,%ebx
  lea    0x0(%rbp,%r13,4),%r13d
  mov    %ebx,%ebp
  sar    $0x8,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x10(%rsp),%r15
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %r14,%rsi
  mov    $0x7a,%edi
  call   <tag_readblock@plt>
  test   %rax,%rax
  jne    L14
L0:
  xor    %edi,%edi
  mov    %r13d,%edx
  mov    $0xff,%esi
  call   <tag_write_sessionreg@plt>
  mov    %r12d,%edx
  mov    $0xff,%esi
  mov    $0x1,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0xf8,%edx
  mov    $0xff,%esi
  mov    $0x2,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bl,%edx
  mov    $0xff,%esi
  mov    $0x3,%edi
  call   <tag_write_sessionreg@plt>
  movzbl %bpl,%edx
  mov    $0xff,%esi
  mov    $0x4,%edi
  call   <tag_write_sessionreg@plt>
  mov    $0x1,%edx
  mov    $0xff,%esi
  mov    $0x5,%edi
  call   <tag_write_sessionreg@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  mov    %r12d,%ecx
  mov    $0x10,%edx
  mov    %r14,%rsi
  mov    %r13b,%al
  mov    %r15,%rdi
  movb   $0xf8,0x2(%rsp)
  mov    %cl,%ah
  mov    %bx,0x3(%rsp)
  mov    %ax,(%rsp)
  movb   $0x1,0x5(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L0
  mov    %r14,%rsi
  mov    $0x7a,%edi
  call   <tag_writeblock@plt>
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tag_set_config(int fd_off, int fd_on, int lastndef, int watchdog) {
  char buf[16];
  char buf2[16];
  memcpy(buf2, buf, 16);
  int nc_reg = (fd_off << 4) + (fd_on << 2);
  if (tag_readblock(0x7A, buf)) {
    buf[0] = nc_reg;
    buf[1] = lastndef;
    buf[2] = 0xF8;
    buf[3] = watchdog & 0xFF;
    buf[4] = (watchdog >> 8) & 0xFF;
    buf[5] = 1;
    if (!memcmp(buf2, buf, 16)) {
      tag_writeblock(0x7A, buf);
    }
  }
  tag_write_sessionreg(0, 0xFF, nc_reg);
  tag_write_sessionreg(1, 0xFF, lastndef);
  tag_write_sessionreg(2, 0xFF, 0xF8);
  tag_write_sessionreg(3, 0xFF, watchdog & 0xFF);
  tag_write_sessionreg(4, 0xFF, (watchdog >> 8) & 0xFF);
  tag_write_sessionreg(5, 0xFF, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getLongestPrefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <getMin@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L16
L4:
  addl   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L28
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L4
L28:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int getLongestPrefix(char *nodepath, char *path) {
  int max, i;
  max = getMin(strlen(path), strlen(nodepath));
  i = 0;
  while (i < max && path[i] == nodepath[i])
    i++;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getLongestPrefix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <getMin@plt>
  test   %eax,%eax
  jle    L20
  mov    %eax,%ecx
  mov    $0x0,%edx
L29:
  mov    %edx,%eax
  movzbl (%rbx,%rdx,1),%esi
  cmp    %sil,0x0(%rbp,%rdx,1)
  jne    L39
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L29
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
int getLongestPrefix(char *nodepath, char *path) {
  int max, i;
  max = getMin(strlen(path), strlen(nodepath));
  i = 0;
  while (i < max && path[i] == nodepath[i])
    i++;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getLongestPrefix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <getMin@plt>
  test   %eax,%eax
  jle    L18
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L38:
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L20
L16:
  movzbl (%rbx,%rdx,1),%esi
  mov    %edx,%eax
  cmp    %sil,0x0(%rbp,%rdx,1)
  je     L38
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  xor    %eax,%eax
  jmp    L20
```

assistant: ```c
int getLongestPrefix(char *nodepath, char *path) {
  int max, i;
  max = getMin(strlen(path), strlen(nodepath));
  i = 0;
  while (i < max && path[i] == nodepath[i])
    i++;
  return (i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getLongestPrefix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <getMin@plt>
  test   %eax,%eax
  jle    L13
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L6:
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L31
L32:
  movzbl (%rbx,%rdx,1),%esi
  mov    %edx,%eax
  cmp    %sil,0x0(%rbp,%rdx,1)
  je     L6
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
int getLongestPrefix(char *nodepath, char *path) {
  int max, i;
  max = getMin(strlen(path), strlen(nodepath));
  i = 0;
  while (i < max && path[i] == nodepath[i])
    i++;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<NJ_print_permutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L9:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jl     L9
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D1: %ld,

tool: D11: %ld


assistant: ```c
void NJ_print_permutation(long int *perm, long int size) {
  long int i;
  for (i = 0; i < size - 1; i++) {
    printf("%ld,", perm[i]);
  }
  printf("%ld\n", perm[size - 1]);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NJ_print_permutation>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  cmp    $0x1,%rsi
  jle    L16
  lea    -0x1(%rsi),%r13
  mov    $0x0,%ebx
  lea    D14(%rip),%r12
L13:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L13
L16:
  mov    -0x8(%rbp,%r14,8),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string

tool: D14: %ld,

tool: D12: %ld


assistant: ```c
void NJ_print_permutation(long int *perm, long int size) {
  long int i;
  for (i = 0; i < size - 1; i++) {
    printf("%ld,", perm[i]);
  }
  printf("%ld\n", perm[size - 1]);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NJ_print_permutation>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %r12,%r12
  jle    L3
  xor    %ebx,%ebx
  lea    D8(%rip),%r13
  nopl   0x0(%rax)
L13:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
L3:
  mov    -0x8(%rbp,%r14,8),%rsi
  pop    %rbx
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D8: %ld,

tool: D14: %ld


assistant: ```c
void NJ_print_permutation(long int *perm, long int size) {
  long int i;
  for (i = 0; i < size - 1; i++) {
    printf("%ld,", perm[i]);
  }
  printf("%ld\n", perm[size - 1]);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NJ_print_permutation>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %r12,%r12
  jle    L0
  xor    %ebx,%ebx
  lea    D1(%rip),%r13
  nopl   0x0(%rax)
L10:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
L0:
  mov    -0x8(%rbp,%r14,8),%rsi
  pop    %rbx
  lea    D18(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D18
type: string

tool: D1: %ld,

tool: D18: %ld


assistant: ```c
void NJ_print_permutation(long int *perm, long int size) {
  long int i;
  for (i = 0; i < size - 1; i++) {
    printf("%ld,", perm[i]);
  }
  printf("%ld\n", perm[size - 1]);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_utf16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L16:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x24(%rbp)
L9:
  cmpl   $0x0,-0x24(%rbp)
  jg     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_utf16(void *dst, const char *src, int len) {
  char *p = (char *)dst;
  while (len > 0) {
    *p++ = '\0';
    *p++ = *src++;
    len--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy_utf16>:
  endbr64
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  mov    $0x0,%eax
L7:
  movb   $0x0,(%rdi,%rax,2)
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
L19:
  ret
```

assistant: ```c
void copy_utf16(void *dst, const char *src, int len) {
  char *p = (char *)dst;
  while (len > 0) {
    *p++ = '\0';
    *p++ = *src++;
    len--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_utf16>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L7:
  movb   $0x0,(%rdi,%rax,2)
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
L11:
  ret
```

assistant: ```c
void copy_utf16(void *dst, const char *src, int len) {
  char *p = (char *)dst;
  while (len > 0) {
    *p++ = '\0';
    *p++ = *src++;
    len--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_utf16>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L24
  movslq %edx,%rdi
  lea    (%rcx,%rdi,2),%rax
  lea    (%rsi,%rdi,1),%r8
  cmp    %rax,%rsi
  setae  %al
  cmp    %r8,%rcx
  setae  %r8b
  or     %r8b,%al
  je     L197
  lea    -0x1(%rdx),%eax
  cmp    $0xe,%eax
  jbe    L197
  mov    %edx,%edi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L158:
  movdqu (%rsi,%rax,1),%xmm0
  movdqa %xmm1,%xmm2
  punpcklbw %xmm0,%xmm2
  movups %xmm2,(%rcx,%rax,2)
  movdqa %xmm1,%xmm2
  punpckhbw %xmm0,%xmm2
  movups %xmm2,0x10(%rcx,%rax,2)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L158
  mov    %edx,%r8d
  mov    %edx,%edi
  and    $0xfffffff0,%r8d
  mov    %r8d,%eax
  sub    %r8d,%edi
  add    %rax,%rsi
  lea    (%rcx,%rax,2),%rax
  cmp    %r8d,%edx
  je     L24
  movb   $0x0,(%rax)
  movzbl (%rsi),%edx
  mov    %dl,0x1(%rax)
  cmp    $0x1,%edi
  je     L24
  movb   $0x0,0x2(%rax)
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x3(%rax)
  cmp    $0x2,%edi
  je     L24
  movb   $0x0,0x4(%rax)
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x5(%rax)
  cmp    $0x3,%edi
  je     L24
  movb   $0x0,0x6(%rax)
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x7(%rax)
  cmp    $0x4,%edi
  je     L24
  movb   $0x0,0x8(%rax)
  movzbl 0x4(%rsi),%edx
  mov    %dl,0x9(%rax)
  cmp    $0x5,%edi
  je     L24
  movb   $0x0,0xa(%rax)
  movzbl 0x5(%rsi),%edx
  mov    %dl,0xb(%rax)
  cmp    $0x6,%edi
  je     L24
  movb   $0x0,0xc(%rax)
  movzbl 0x6(%rsi),%edx
  mov    %dl,0xd(%rax)
  cmp    $0x7,%edi
  je     L24
  movb   $0x0,0xe(%rax)
  movzbl 0x7(%rsi),%edx
  mov    %dl,0xf(%rax)
  cmp    $0x8,%edi
  je     L24
  movb   $0x0,0x10(%rax)
  movzbl 0x8(%rsi),%edx
  mov    %dl,0x11(%rax)
  cmp    $0x9,%edi
  je     L24
  movb   $0x0,0x12(%rax)
  movzbl 0x9(%rsi),%edx
  mov    %dl,0x13(%rax)
  cmp    $0xa,%edi
  je     L24
  movb   $0x0,0x14(%rax)
  movzbl 0xa(%rsi),%edx
  mov    %dl,0x15(%rax)
  cmp    $0xb,%edi
  je     L24
  movb   $0x0,0x16(%rax)
  movzbl 0xb(%rsi),%edx
  mov    %dl,0x17(%rax)
  cmp    $0xc,%edi
  je     L24
  movb   $0x0,0x18(%rax)
  movzbl 0xc(%rsi),%edx
  mov    %dl,0x19(%rax)
  cmp    $0xd,%edi
  je     L24
  movb   $0x0,0x1a(%rax)
  movzbl 0xd(%rsi),%edx
  mov    %dl,0x1b(%rax)
  cmp    $0xe,%edi
  je     L24
  movb   $0x0,0x1c(%rax)
  movzbl 0xe(%rsi),%edx
  mov    %dl,0x1d(%rax)
  ret
L197:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  movb   $0x0,(%rcx,%rax,2)
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0x1(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L16
L24:
  ret
```

assistant: ```c
void copy_utf16(void *dst, const char *src, int len) {
  char *p = (char *)dst;
  while (len > 0) {
    *p++ = '\0';
    *p++ = *src++;
    len--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cyc_do_ioeffect_analysis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Cyc_IOEffect_analysis@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int Cyc_do_ioeffect_analysis(struct Cyc_JumpAnalysis_Jump_Anal_Result *tables, struct Cyc_List_List *tds) {
  ({ Cyc_IOEffect_analysis(tables, tds); });
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Cyc_do_ioeffect_analysis>:
  endbr64
  sub    $0x8,%rsp
  call   <Cyc_IOEffect_analysis@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Cyc_do_ioeffect_analysis(struct Cyc_JumpAnalysis_Jump_Anal_Result *tables, struct Cyc_List_List *tds) {
  ({ Cyc_IOEffect_analysis(tables, tds); });
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Cyc_do_ioeffect_analysis>:
  endbr64
  sub    $0x8,%rsp
  call   <Cyc_IOEffect_analysis@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Cyc_do_ioeffect_analysis(struct Cyc_JumpAnalysis_Jump_Anal_Result *tables, struct Cyc_List_List *tds) {
  ({ Cyc_IOEffect_analysis(tables, tds); });
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Cyc_do_ioeffect_analysis>:
  endbr64
  sub    $0x8,%rsp
  call   <Cyc_IOEffect_analysis@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Cyc_do_ioeffect_analysis(struct Cyc_JumpAnalysis_Jump_Anal_Result *tables, struct Cyc_List_List *tds) {
  ({ Cyc_IOEffect_analysis(tables, tds); });
  return 1;
}
```