ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <utest@plt>
  xor    %edi,%edi
  call   <utest@plt>
  mov    $0x9,%edi
  call   <stest@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <stest@plt>
```

assistant: ```c
void testTortureExecute(void) {
  utest(9);
  utest(0);
  stest(9);
  stest(0);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testTortureExecute>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <utest@plt>
  xor    %edi,%edi
  call   <utest@plt>
  mov    $0x9,%edi
  call   <stest@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <stest@plt>
```

assistant: ```c
void testTortureExecute(void) {
  utest(9);
  utest(0);
  stest(9);
  stest(0);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoiv2@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D1: 1234

tool: D7: %d

assistant: ```c
int main(void) {
  char *s = "1234";
  int ret;
  ret = atoiv2(s);
  printf("%d", ret);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <atoiv2@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D5: 1234

tool: D10: %d

assistant: ```c
int main(void) {
  char *s = "1234";
  int ret;
  ret = atoiv2(s);
  printf("%d", ret);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <atoiv2@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D19: 1234

tool: D4: %d

assistant: ```c
int main(void) {
  char *s = "1234";
  int ret;
  ret = atoiv2(s);
  printf("%d", ret);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <atoiv2@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D8: 1234

tool: D12: %d

assistant: ```c
int main(void) {
  char *s = "1234";
  int ret;
  ret = atoiv2(s);
  printf("%d", ret);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<four_swap>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  test   %edx,%edx
  je     L3
  movslq (%rsi),%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%esi
  movslq 0x4(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x4(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
L3:
  movslq (%rsi),%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%esi
  movslq 0xc(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0xc(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
```

assistant: ```c
void four_swap(int *a, int *tu, int r) {
  int tmp;
  if (r) {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[1]];
    a[tu[1]] = a[tu[2]];
    a[tu[2]] = a[tu[3]];
    a[tu[3]] = tmp;
  } else {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[3]];
    a[tu[3]] = a[tu[2]];
    a[tu[2]] = a[tu[1]];
    a[tu[1]] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<four_swap>:
  endbr64
  mov    %edx,%r8d
  movslq (%rsi),%rdx
  mov    %rsi,%rcx
  mov    %rdi,%rax
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%esi
  test   %r8d,%r8d
  je     L6
  movslq 0x4(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x4(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movslq 0xc(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0xc(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
```

assistant: ```c
void four_swap(int *a, int *tu, int r) {
  int tmp;
  if (r) {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[1]];
    a[tu[1]] = a[tu[2]];
    a[tu[2]] = a[tu[3]];
    a[tu[3]] = tmp;
  } else {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[3]];
    a[tu[3]] = a[tu[2]];
    a[tu[2]] = a[tu[1]];
    a[tu[1]] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<four_swap>:
  endbr64
  mov    %edx,%r8d
  movslq (%rsi),%rdx
  mov    %rsi,%rcx
  mov    %rdi,%rax
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%esi
  test   %r8d,%r8d
  je     L9
  movslq 0x4(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x4(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0xc(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movslq 0xc(%rcx),%rdi
  mov    (%rax,%rdi,4),%edi
  mov    %edi,(%rdx)
  movslq 0x8(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0xc(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    (%rax,%rdx,4),%edi
  movslq 0x8(%rcx),%rdx
  mov    %edi,(%rax,%rdx,4)
  movslq 0x4(%rcx),%rdx
  mov    %esi,(%rax,%rdx,4)
  ret
```

assistant: ```c
void four_swap(int *a, int *tu, int r) {
  int tmp;
  if (r) {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[1]];
    a[tu[1]] = a[tu[2]];
    a[tu[2]] = a[tu[3]];
    a[tu[3]] = tmp;
  } else {
    tmp = a[tu[0]];
    a[tu[0]] = a[tu[3]];
    a[tu[3]] = a[tu[2]];
    a[tu[2]] = a[tu[1]];
    a[tu[1]] = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<I3_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %al,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x48(%rbp)
  movsbl -0x54(%rbp),%eax
  cmp    $0x4f,%eax
  je     L52
  cmp    $0x4f,%eax
  jg     L43
  cmp    $0x4e,%eax
  je     L103
  cmp    $0x4e,%eax
  jg     L43
  cmp    $0x20,%eax
  je     L96
  cmp    $0x24,%eax
  je     L22
L43:
  movzbl -0x54(%rbp),%eax
  mov    %al,-0x40(%rbp)
  movb   $0x0,-0x3f(%rbp)
  mov    $0x1,%eax
  jmp    L29
L22:
  lea    -0x40(%rbp),%rax
  mov    $0x32,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <i3strlcpy@plt>
  jmp    L80
L96:
  lea    -0x40(%rbp),%rax
  mov    $0x32,%edx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <i3strlcpy@plt>
  jmp    L80
L103:
  mov    -0x68(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x32,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <i3strlcpy@plt>
  jmp    L80
L52:
  mov    -0x70(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x32,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <i3strlcpy@plt>
  nop
L80:
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L12
L101:
  mov    -0x48(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  movzbl (%rax),%edx
  mov    -0x60(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L101
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L94
  call   <__stack_chk_fail@plt>
L94:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D6
datatype: string

tool: D3: $

tool: D6:  

assistant: ```c
int I3_token(char type, char *string, char *oname, char *tname) {
  char code[50];
  char *p = '\0';
  switch (type) {
  default:
    code[0] = type;
    code[1] = '\0';
    return 1;
  case '$':
    i3strlcpy(code, "$", 50);
    break;
  case ' ':
    i3strlcpy(code, " ", 50);
    break;
  case 'N':
    i3strlcpy(code, oname, 50);
    break;
  case 'O':
    i3strlcpy(code, tname, 50);
    break;
  }
  p = code;
  while (*p != '\0') {
    *string = *p++;
    *++string = '\0';
  }
  return (strlen(code));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I3_token>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x4e,%dil
  je     L21
  jg     L9
  cmp    $0x20,%dil
  je     L52
  cmp    $0x24,%dil
  jne    L39
  mov    %rsp,%rdi
  mov    $0x32,%edx
  lea    D15(%rip),%rsi
  call   <i3strlcpy@plt>
L83:
  movzbl (%rsp),%eax
  mov    %rsp,%rdx
  test   %al,%al
  je     L93
L94:
  add    $0x1,%rdx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movb   $0x0,(%rbx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L94
L93:
  mov    %rsp,%rdi
  call   <strlen@plt>
L96:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x40,%rsp
  pop    %rbx
  ret
L39:
  mov    $0x1,%eax
  jmp    L96
L9:
  mov    $0x1,%eax
  cmp    $0x4f,%dil
  jne    L96
  mov    %rsp,%rdi
  mov    $0x32,%edx
  mov    %rcx,%rsi
  call   <i3strlcpy@plt>
  jmp    L83
L52:
  mov    %rsp,%rdi
  mov    $0x32,%edx
  lea    D11(%rip),%rsi
  call   <i3strlcpy@plt>
  jmp    L83
L21:
  mov    %rdx,%rsi
  mov    %rsp,%rdi
  mov    $0x32,%edx
  call   <i3strlcpy@plt>
  jmp    L83
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string
name: unpack_data
arguments: label: D11
datatype: string

tool: D15: $

tool: D11:  

assistant: ```c
int I3_token(char type, char *string, char *oname, char *tname) {
  char code[50];
  char *p = '\0';
  switch (type) {
  default:
    code[0] = type;
    code[1] = '\0';
    return 1;
  case '$':
    i3strlcpy(code, "$", 50);
    break;
  case ' ':
    i3strlcpy(code, " ", 50);
    break;
  case 'N':
    i3strlcpy(code, oname, 50);
    break;
  case 'O':
    i3strlcpy(code, tname, 50);
    break;
  }
  p = code;
  while (*p != '\0') {
    *string = *p++;
    *++string = '\0';
  }
  return (strlen(code));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<I3_token>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x4e,%dil
  je     L118
  jg     L80
  cmp    $0x20,%dil
  je     L45
  cmp    $0x24,%dil
  jne    L40
  mov    %rsp,%rbp
  mov    $0x32,%edx
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
L23:
  movzbl (%rsp),%eax
  mov    %rbp,%rdx
  test   %al,%al
  je     L36
  nopl   0x0(%rax,%rax,1)
L81:
  add    $0x1,%rdx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rdx),%eax
  movb   $0x0,(%rbx)
  test   %al,%al
  jne    L81
L36:
  mov    %rbp,%rdi
  call   <strlen@plt>
L62:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L97
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  cmp    $0x4f,%dil
  jne    L40
  mov    %rsp,%rbp
  mov    $0x32,%edx
  mov    %rcx,%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L40:
  mov    $0x1,%eax
  jmp    L62
  nop
L45:
  mov    %rsp,%rbp
  mov    $0x32,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L23
  nopl   0x0(%rax)
L118:
  mov    %rsp,%rbp
  mov    %rdx,%rsi
  mov    $0x32,%edx
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L23
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D18: $

tool: D7:  

assistant: ```c
int I3_token(char type, char *string, char *oname, char *tname) {
  char code[50];
  char *p = '\0';
  switch (type) {
  default:
    code[0] = type;
    code[1] = '\0';
    return 1;
  case '$':
    i3strlcpy(code, "$", 50);
    break;
  case ' ':
    i3strlcpy(code, " ", 50);
    break;
  case 'N':
    i3strlcpy(code, oname, 50);
    break;
  case 'O':
    i3strlcpy(code, tname, 50);
    break;
  }
  p = code;
  while (*p != '\0') {
    *string = *p++;
    *++string = '\0';
  }
  return (strlen(code));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<I3_token>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x4e,%dil
  je     L88
  jg     L43
  cmp    $0x20,%dil
  je     L60
  cmp    $0x24,%dil
  jne    L73
  mov    %rsp,%rbp
  mov    $0x32,%edx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
L48:
  movzbl (%rsp),%eax
  mov    %rbp,%rdx
  test   %al,%al
  je     L26
  nopl   0x0(%rax,%rax,1)
L97:
  add    $0x1,%rdx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rdx),%eax
  movb   $0x0,(%rbx)
  test   %al,%al
  jne    L97
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
L81:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  cmp    $0x4f,%dil
  jne    L73
  mov    %rsp,%rbp
  mov    $0x32,%edx
  mov    %rcx,%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L73:
  mov    $0x1,%eax
  jmp    L81
  nop
L60:
  mov    %rsp,%rbp
  mov    $0x32,%edx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L48
  nopl   0x0(%rax)
L88:
  mov    %rsp,%rbp
  mov    %rdx,%rsi
  mov    $0x32,%edx
  mov    %rbp,%rdi
  call   <i3strlcpy@plt>
  jmp    L48
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D5: $

tool: D0:  

assistant: ```c
int I3_token(char type, char *string, char *oname, char *tname) {
  char code[50];
  char *p = '\0';
  switch (type) {
  default:
    code[0] = type;
    code[1] = '\0';
    return 1;
  case '$':
    i3strlcpy(code, "$", 50);
    break;
  case ' ':
    i3strlcpy(code, " ", 50);
    break;
  case 'N':
    i3strlcpy(code, oname, 50);
    break;
  case 'O':
    i3strlcpy(code, tname, 50);
    break;
  }
  p = code;
  while (*p != '\0') {
    *string = *p++;
    *++string = '\0';
  }
  return (strlen(code));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TestB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1000,-0x4(%rbp)
L8:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <disp_str@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%edi
  call   <disp_int@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <disp_str@plt>
  mov    $0x1,%edi
  call   <delay@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D4: B

tool: D9: .

assistant: ```c
void TestB() {
  int i = 0x1000;
  while (1) {
    disp_str("B");
    disp_int(i++);
    disp_str(".");
    delay(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TestB>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1000,%ebx
  lea    D8(%rip),%r13
  lea    D15(%rip),%r12
L9:
  mov    %r13,%rdi
  call   <disp_str@plt>
  lea    0x1(%rbx),%ebp
  mov    %ebx,%edi
  call   <disp_int@plt>
  mov    %r12,%rdi
  call   <disp_str@plt>
  mov    $0x1,%edi
  call   <delay@plt>
  mov    %ebp,%ebx
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D8: B

tool: D15: .

assistant: ```c
void TestB() {
  int i = 0x1000;
  while (1) {
    disp_str("B");
    disp_int(i++);
    disp_str(".");
    delay(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TestB>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    $0x1000,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    %r13,%rdi
  lea    0x1(%rbp),%ebx
  call   <disp_str@plt>
  mov    %ebp,%edi
  mov    %ebx,%ebp
  call   <disp_int@plt>
  mov    %r12,%rdi
  call   <disp_str@plt>
  mov    $0x1,%edi
  call   <delay@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D18
type: string

tool: D1: B

tool: D18: .

assistant: ```c
void TestB() {
  int i = 0x1000;
  while (1) {
    disp_str("B");
    disp_int(i++);
    disp_str(".");
    delay(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TestB>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    $0x1000,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    %r13,%rdi
  lea    0x1(%rbp),%ebx
  call   <disp_str@plt>
  mov    %ebp,%edi
  mov    %ebx,%ebp
  call   <disp_int@plt>
  mov    %r12,%rdi
  call   <disp_str@plt>
  mov    $0x1,%edi
  call   <delay@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string

tool: D7: B

tool: D15: .

assistant: ```c
void TestB() {
  int i = 0x1000;
  while (1) {
    disp_str("B");
    disp_int(i++);
    disp_str(".");
    delay(1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<make_ext_salt_para>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <int_to_base64@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D15(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string

tool: D12: _%s%s

assistant: ```c
char *make_ext_salt_para(int rounds, char *saltpara) {
  static char salt[10];
  sprintf(salt, "_%s%s", int_to_base64(rounds), saltpara);
  return salt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_ext_salt_para>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <int_to_base64@plt>
  mov    %rax,%rdx
  mov    %rbx,%rcx
  lea    D18(%rip),%rsi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D18: _%s%s

assistant: ```c
char *make_ext_salt_para(int rounds, char *saltpara) {
  static char salt[10];
  sprintf(salt, "_%s%s", int_to_base64(rounds), saltpara);
  return salt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<make_ext_salt_para>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  call   <int_to_base64@plt>
  mov    %r12,%rcx
  lea    D2(%rip),%r12
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string

tool: D14: _%s%s

assistant: ```c
char *make_ext_salt_para(int rounds, char *saltpara) {
  static char salt[10];
  sprintf(salt, "_%s%s", int_to_base64(rounds), saltpara);
  return salt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_ext_salt_para>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  call   <int_to_base64@plt>
  mov    %r12,%rcx
  lea    D14(%rip),%r12
  lea    D12(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string

tool: D12: _%s%s

assistant: ```c
char *make_ext_salt_para(int rounds, char *saltpara) {
  static char salt[10];
  sprintf(salt, "_%s%s", int_to_base64(rounds), saltpara);
  return salt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <exampleProgram@plt>
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  assert(sizeof(uint32_t) == 4);
  return exampleProgram();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <exampleProgram@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(sizeof(uint32_t) == 4);
  return exampleProgram();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <exampleProgram@plt>
```

assistant: ```c
int main() {
  assert(sizeof(uint32_t) == 4);
  return exampleProgram();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <exampleProgram@plt>
```

assistant: ```c
int main() {
  assert(sizeof(uint32_t) == 4);
  return exampleProgram();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L49
L38:
  addq   $0x1,-0x18(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xc,%al
  je     L38
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xb,%al
  je     L38
  jmp    L77
L46:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
L77:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L74
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L46
L74:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long int atol(const char *str) {
  long int result = 0;
  while (((*str) == ' ' || (*str) == '\t' || (*str) == '\r' || (*str) == '\n' || (*str) == '\f' || (*str) == '\v'))
    str++;
  while (((*str) >= '0' && (*str) <= '9'))
    result = (result * 10) + (*(str++) - '0');
  return result;
}
```