ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    0x4(%rsp),%eax
  xor    $0x4,%eax
  mov    %eax,0x8(%rsp)
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main() {
  volatile uint8_t a = 0, b = 1, c = 0;
  b = a ^ 4;
  c = b + 1;
  printf("%d\n", b);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    0x4(%rsp),%eax
  xor    $0x4,%eax
  mov    %eax,0x8(%rsp)
  mov    0x8(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: %d


assistant: ```c
int main() {
  volatile uint8_t a = 0, b = 1, c = 0;
  b = a ^ 4;
  c = b + 1;
  printf("%d\n", b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prompt_minimum_speed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D9: Minimum Speed (RPM) of the Gearbox? 

tool: D16: %lf

assistant: ```c
double prompt_minimum_speed(void) {
  double value = 0.0;
  printf("Minimum Speed (RPM) of the Gearbox? ");
  scanf("%lf", &value);
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prompt_minimum_speed>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D5: Minimum Speed (RPM) of the Gearbox? 

tool: D1: %lf

assistant: ```c
double prompt_minimum_speed(void) {
  double value = 0.0;
  printf("Minimum Speed (RPM) of the Gearbox? ");
  scanf("%lf", &value);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prompt_minimum_speed>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D8: Minimum Speed (RPM) of the Gearbox? 

tool: D0: %lf

assistant: ```c
double prompt_minimum_speed(void) {
  double value = 0.0;
  printf("Minimum Speed (RPM) of the Gearbox? ");
  scanf("%lf", &value);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prompt_minimum_speed>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D18: Minimum Speed (RPM) of the Gearbox? 

tool: D13: %lf

assistant: ```c
double prompt_minimum_speed(void) {
  double value = 0.0;
  printf("Minimum Speed (RPM) of the Gearbox? ");
  scanf("%lf", &value);
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_str_to_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D53(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L36
  mov    D53(%rip),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L46
L36:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L42
  mov    D53(%rip),%rax
  mov    (%rax),%rdx
  mov    D28(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L42
L46:
  mov    $0xffffffff,%eax
  jmp    L45
L42:
  mov    $0x0,%eax
L45:
  leave
  ret
```

assistant: ```c
int m_str_to_uint(const char *str, unsigned int *val) {
  errno = 0;
  *val = strtoul(str, NULL, 10);
  if ((*val == 0 && errno == EINVAL) || (*val == ULONG_MAX && errno == ERANGE)) {
    return -1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_str_to_uint>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    D35(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  jne    L29
  mov    D35(%rip),%rcx
  mov    D40(%rip),%rdx
  mov    (%rdx),%rbx
  cmp    %rbx,(%rcx)
  je     L13
L29:
  mov    $0x0,%edx
  mov    D3(%rip),%rcx
  cmp    (%rcx),%eax
  jne    L26
  mov    D35(%rip),%rdx
  mov    D49(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %dl
  movzbl %dl,%edx
  neg    %edx
L26:
  mov    %edx,%eax
  pop    %rbx
  ret
L13:
  mov    $0xffffffff,%edx
  jmp    L26
```

assistant: ```c
int m_str_to_uint(const char *str, unsigned int *val) {
  errno = 0;
  *val = strtoul(str, NULL, 10);
  if ((*val == 0 && errno == EINVAL) || (*val == ULONG_MAX && errno == ERANGE)) {
    return -1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<m_str_to_uint>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x8,%rsp
  mov    D13(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  call   <strtoul@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  jne    L38
  mov    D18(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,0x0(%rbp)
  je     L35
L38:
  mov    D29(%rip),%rdx
  xor    %r8d,%r8d
  cmp    (%rdx),%eax
  jne    L2
  mov    D11(%rip),%rax
  xor    %r8d,%r8d
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %r8b
  neg    %r8d
L2:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0xffffffff,%r8d
  jmp    L2
```

assistant: ```c
int m_str_to_uint(const char *str, unsigned int *val) {
  errno = 0;
  *val = strtoul(str, NULL, 10);
  if ((*val == 0 && errno == EINVAL) || (*val == ULONG_MAX && errno == ERANGE)) {
    return -1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m_str_to_uint>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x8,%rsp
  mov    D7(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  call   <strtoul@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  jne    L9
  mov    D12(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,0x0(%rbp)
  je     L33
L9:
  mov    D16(%rip),%rdx
  xor    %r8d,%r8d
  cmp    (%rdx),%eax
  jne    L36
  mov    D32(%rip),%rax
  xor    %r8d,%r8d
  mov    (%rax),%rax
  cmp    %rax,0x0(%rbp)
  sete   %r8b
  neg    %r8d
L36:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  mov    $0xffffffff,%r8d
  jmp    L36
```

assistant: ```c
int m_str_to_uint(const char *str, unsigned int *val) {
  errno = 0;
  *val = strtoul(str, NULL, 10);
  if ((*val == 0 && errno == EINVAL) || (*val == ULONG_MAX && errno == ERANGE)) {
    return -1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  je     L17
  cmpb   $0x9,-0x4(%rbp)
  je     L17
  cmpb   $0xa,-0x4(%rbp)
  je     L17
  cmpb   $0xd,-0x4(%rbp)
  jne    L36
L17:
  mov    $0x1,%eax
  jmp    L37
L36:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_isspace>:
  endbr64
  cmp    $0x20,%dil
  ja     L7
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_isspace>:
  endbr64
  cmp    $0x20,%dil
  ja     L5
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_isspace>:
  endbr64
  cmp    $0x20,%dil
  ja     L2
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isspace(char c) {
  if (c == ' ' || c == '\t' || c == '\n' || c == '\r')
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rescale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
L15:
  movl   $0x10,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  jmp    L25
L17:
  mov    -0x38(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x48(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x48(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x48(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,-0x20(%rbp)
  addq   $0x6,-0x38(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L17
  addq   $0x6,-0x38(%rbp)
  subl   $0x7,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jg     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rescale(short const *in, int count, short *out) {
  do {
    int const accuracy = 16;
    int const unit = 1 << accuracy;
    int const step = unit / 8;
    int left = unit - step;
    int right = step;
    int n = 7;
    while (n--) {
      int r = (in[0] * left + in[3] * right) >> accuracy;
      int g = (in[1] * left + in[4] * right) >> accuracy;
      int b = (in[2] * left + in[5] * right) >> accuracy;
      *out++ = r;
      *out++ = g;
      *out++ = b;
      left -= step;
      right += step;
      in += 3;
    }
    in += 3;
  } while ((count -= 7) > 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rescale>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r11d
  mov    %rdx,%rbx
  mov    $0x10000,%r9d
  jmp    L32
L12:
  add    $0x2a,%rbx
  add    $0x30,%r10
  sub    $0x7,%r11d
  test   %r11d,%r11d
  jle    L1
L32:
  mov    %rbx,%r8
  mov    %r10,%rax
  mov    $0x2000,%edi
L22:
  mov    %r9d,%ebp
  sub    %edi,%ebp
  movswl 0x2(%rax),%esi
  imul   %ebp,%esi
  movswl 0x8(%rax),%edx
  imul   %edi,%edx
  add    %edx,%esi
  sar    $0x10,%esi
  movswl 0x4(%rax),%edx
  imul   %ebp,%edx
  movswl 0xa(%rax),%ecx
  imul   %edi,%ecx
  add    %ecx,%edx
  sar    $0x10,%edx
  movswl (%rax),%ecx
  imul   %ebp,%ecx
  movswl 0x6(%rax),%ebp
  imul   %edi,%ebp
  add    %ebp,%ecx
  sar    $0x10,%ecx
  mov    %cx,(%r8)
  mov    %si,0x2(%r8)
  add    $0x6,%r8
  mov    %dx,-0x2(%r8)
  add    $0x2000,%edi
  add    $0x6,%rax
  cmp    $0x10000,%edi
  jne    L22
  jmp    L12
L1:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rescale(short const *in, int count, short *out) {
  do {
    int const accuracy = 16;
    int const unit = 1 << accuracy;
    int const step = unit / 8;
    int left = unit - step;
    int right = step;
    int n = 7;
    while (n--) {
      int r = (in[0] * left + in[3] * right) >> accuracy;
      int g = (in[1] * left + in[4] * right) >> accuracy;
      int b = (in[2] * left + in[5] * right) >> accuracy;
      *out++ = r;
      *out++ = g;
      *out++ = b;
      left -= step;
      right += step;
      in += 3;
    }
    in += 3;
  } while ((count -= 7) > 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<rescale>:
  endbr64
  push   %rbp
  mov    %rdi,%r10
  mov    %esi,%r11d
  mov    $0x10000,%r9d
  push   %rbx
  mov    %rdx,%rbx
  nopl   (%rax)
L3:
  mov    %rbx,%r8
  mov    %r10,%rax
  mov    $0x2000,%edi
  nopl   0x0(%rax,%rax,1)
L15:
  movswl 0x2(%rax),%esi
  movswl 0x8(%rax),%edx
  mov    %r9d,%ebp
  add    $0x6,%r8
  sub    %edi,%ebp
  movswl 0xa(%rax),%ecx
  add    $0x6,%rax
  imul   %edi,%edx
  imul   %ebp,%esi
  imul   %edi,%ecx
  add    %edx,%esi
  movswl -0x2(%rax),%edx
  sar    $0x10,%esi
  imul   %ebp,%edx
  add    %ecx,%edx
  movswl -0x6(%rax),%ecx
  sar    $0x10,%edx
  imul   %ebp,%ecx
  movswl (%rax),%ebp
  mov    %si,-0x4(%r8)
  imul   %edi,%ebp
  add    $0x2000,%edi
  add    %ebp,%ecx
  sar    $0x10,%ecx
  mov    %cx,-0x6(%r8)
  mov    %dx,-0x2(%r8)
  cmp    $0x10000,%edi
  jne    L15
  sub    $0x7,%r11d
  add    $0x2a,%rbx
  add    $0x30,%r10
  test   %r11d,%r11d
  jg     L3
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rescale(short const *in, int count, short *out) {
  do {
    int const accuracy = 16;
    int const unit = 1 << accuracy;
    int const step = unit / 8;
    int left = unit - step;
    int right = step;
    int n = 7;
    while (n--) {
      int r = (in[0] * left + in[3] * right) >> accuracy;
      int g = (in[1] * left + in[4] * right) >> accuracy;
      int b = (in[2] * left + in[5] * right) >> accuracy;
      *out++ = r;
      *out++ = g;
      *out++ = b;
      left -= step;
      right += step;
      in += 3;
    }
    in += 3;
  } while ((count -= 7) > 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isMatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L111
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L111
  mov    $0x1,%eax
  jmp    L18
L111:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L142
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L142
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L69
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L83
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L83
  mov    $0x0,%eax
  jmp    L18
L83:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <isMatch>
  jmp    L18
L69:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_isMatch@plt>
  jmp    L18
L142:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L22
  mov    $0x0,%eax
  jmp    L18
L22:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <isMatch>
  jmp    L18
L26:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
bool isMatch(char *s, char *p) {
  if (p[0] == '\0' && s[0] == '\0')
    return true;
  if (p[0] != '\0' && s[0] != '\0') {
    if (p[1] != '*') {
      if (p[0] != '.' && p[0] != s[0])
        return false;
      return isMatch(&s[1], &p[1]);
    }
    return _isMatch(s, &p[2], p[0]);
  }
  if (p[0] != '\0' && s[0] == '\0') {
    if (p[1] != '*')
      return false;
    return isMatch(s, &p[2]);
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isMatch>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L87
  cmpb   $0x0,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
L87:
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L58
  cmpb   $0x2a,0x1(%rsi)
  je     L64
  cmp    %al,%dl
  je     L53
  mov    $0x0,%eax
  cmp    $0x2e,%dl
  jne    L60
L53:
  add    $0x1,%rsi
  add    $0x1,%rdi
  call   <isMatch>
  jmp    L60
L64:
  movsbl %dl,%edx
  add    $0x2,%rsi
  call   <_isMatch@plt>
  jmp    L60
L58:
  mov    $0x0,%eax
  cmpb   $0x2a,0x1(%rsi)
  je     L40
L60:
  add    $0x8,%rsp
  ret
L40:
  add    $0x2,%rsi
  call   <isMatch>
  jmp    L60
```

assistant: ```c
bool isMatch(char *s, char *p) {
  if (p[0] == '\0' && s[0] == '\0')
    return true;
  if (p[0] != '\0' && s[0] != '\0') {
    if (p[1] != '*') {
      if (p[0] != '.' && p[0] != s[0])
        return false;
      return isMatch(&s[1], &p[1]);
    }
    return _isMatch(s, &p[2], p[0]);
  }
  if (p[0] != '\0' && s[0] == '\0') {
    if (p[1] != '*')
      return false;
    return isMatch(s, &p[2]);
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isMatch>:
  endbr64
  movzbl (%rsi),%eax
  movzbl (%rdi),%ecx
  test   %al,%al
  jne    L69
L45:
  xor    %eax,%eax
  test   %cl,%cl
  sete   %al
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmp    $0x2a,%dl
  je     L55
  cmp    %cl,%al
  je     L26
  cmp    $0x2e,%al
  jne    L18
L26:
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rsi
  mov    %edx,%eax
  add    $0x1,%rdi
L41:
  test   %al,%al
  je     L45
L69:
  movzbl 0x1(%rsi),%edx
  test   %cl,%cl
  jne    L13
  cmp    $0x2a,%dl
  jne    L18
  movzbl 0x2(%rsi),%eax
  add    $0x2,%rsi
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
L55:
  movsbl %al,%edx
  add    $0x2,%rsi
  jmp    1050 <_isMatch@plt>
```

assistant: ```c
bool isMatch(char *s, char *p) {
  if (p[0] == '\0' && s[0] == '\0')
    return true;
  if (p[0] != '\0' && s[0] != '\0') {
    if (p[1] != '*') {
      if (p[0] != '.' && p[0] != s[0])
        return false;
      return isMatch(&s[1], &p[1]);
    }
    return _isMatch(s, &p[2], p[0]);
  }
  if (p[0] != '\0' && s[0] == '\0') {
    if (p[1] != '*')
      return false;
    return isMatch(s, &p[2]);
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isMatch>:
  endbr64
  movzbl (%rsi),%ecx
  movzbl (%rdi),%eax
  test   %cl,%cl
  jne    L49
L101:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  movzbl 0x1(%rsi),%edx
  test   %al,%al
  je     L87
L77:
  cmp    $0x2a,%dl
  je     L88
  cmp    %al,%cl
  je     L86
  cmp    $0x2e,%cl
  jne    L14
L86:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rsi
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L101
  mov    %rcx,%rdi
  mov    %edx,%ecx
  movzbl 0x1(%rsi),%edx
  test   %al,%al
  jne    L77
L87:
  cmp    $0x2a,%dl
  jne    L14
  movzbl 0x2(%rsi),%eax
  lea    0x2(%rsi),%rdx
  test   %al,%al
  je     L101
L61:
  cmpb   $0x2a,0x1(%rdx)
  jne    L14
  movzbl 0x2(%rdx),%eax
  add    $0x2,%rdx
  test   %al,%al
  jne    L61
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nop
L14:
  xor    %eax,%eax
  ret
L88:
  movsbl %cl,%edx
  add    $0x2,%rsi
  jmp    1050 <_isMatch@plt>
```

assistant: ```c
bool isMatch(char *s, char *p) {
  if (p[0] == '\0' && s[0] == '\0')
    return true;
  if (p[0] != '\0' && s[0] != '\0') {
    if (p[1] != '*') {
      if (p[0] != '.' && p[0] != s[0])
        return false;
      return isMatch(&s[1], &p[1]);
    }
    return _isMatch(s, &p[2], p[0]);
  }
  if (p[0] != '\0' && s[0] == '\0') {
    if (p[1] != '*')
      return false;
    return isMatch(s, &p[2]);
  }
  return false;
}
```