ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L27
L31:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  lea    (%rbx,%rax,1),%r12
  cmpb   $0x0,(%r12)
  je     L14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L40
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L40:
  mov    %rdx,D16(%rip)
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  mov    D16(%rip),%rbx
  xor    %r12d,%r12d
  test   %rbx,%rbx
  jne    L31
  jmp    L8
  nopl   0x0(%rax)
L14:
  movq   $0x0,D16(%rip)
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(string, separators)
register char *string;
char *separators;
{
  register char *s1, *s2;
  static char *savestring;
  if (!string)
    string = savestring;
  if (!string)
    return 0;
  if (*(s1 = string + strspn(string, separators)) == '\0') {
    savestring = 0;
    return 0;
  }
  if (s2 = strpbrk(s1, separators)) {
    *s2++ = '\0';
  }
  savestring = s2;
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L28
L25:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  lea    (%rbx,%rax,1),%r12
  cmpb   $0x0,(%r12)
  je     L3
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdx
L7:
  mov    %rdx,D17(%rip)
L27:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  mov    D17(%rip),%rbx
  xor    %r12d,%r12d
  test   %rbx,%rbx
  jne    L25
  jmp    L27
  nopl   0x0(%rax)
L3:
  movq   $0x0,D17(%rip)
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(string, separators)
register char *string;
char *separators;
{
  register char *s1, *s2;
  static char *savestring;
  if (!string)
    string = savestring;
  if (!string)
    return 0;
  if (*(s1 = string + strspn(string, separators)) == '\0') {
    savestring = 0;
    return 0;
  }
  if (s2 = strpbrk(s1, separators)) {
    *s2++ = '\0';
  }
  savestring = s2;
  return s1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<removeComments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L21
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L21:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeComments(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '#') {
      s[i] = '\0';
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<removeComments>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
L27:
  ret
L7:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L27
L20:
  cmp    $0x23,%al
  jne    L7
  movb   $0x0,(%rdi)
  jmp    L7
```

assistant: ```c
void removeComments(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '#') {
      s[i] = '\0';
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<removeComments>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    $0x23,%al
  jne    L11
  movb   $0x0,(%rdi)
L11:
  add    $0x1,%rdi
L1:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L14
  ret
```

assistant: ```c
void removeComments(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '#') {
      s[i] = '\0';
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<removeComments>:
  endbr64
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
L27:
  cmp    $0x23,%al
  jne    L13
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L27
  ret
  nop
L5:
  ret
```

assistant: ```c
void removeComments(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '#') {
      s[i] = '\0';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <utmpname@plt>
L2:
  mov    $0x0,%eax
  call   <setutent@plt>
  jmp    L21
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_entry@plt>
L21:
  mov    $0x0,%eax
  call   <getutent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <endutent@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct utmp *up;
  if (argc > 1)
    utmpname(argv[1]);
  setutent();
  while ((up = getutent()))
    print_entry(up);
  endutent();
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jg     L34
L36:
  mov    $0x0,%eax
  call   <setutent@plt>
  jmp    L24
L34:
  mov    0x8(%rsi),%rdi
  call   <utmpname@plt>
  jmp    L36
L25:
  call   <print_entry@plt>
L24:
  mov    $0x0,%eax
  call   <getutent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L25
  mov    $0x0,%eax
  call   <endutent@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct utmp *up;
  if (argc > 1)
    utmpname(argv[1]);
  setutent();
  while ((up = getutent()))
    print_entry(up);
  endutent();
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rdi
  call   <utmpname@plt>
L7:
  xor    %eax,%eax
  call   <setutent@plt>
  jmp    L16
  nop
L2:
  call   <print_entry@plt>
L16:
  xor    %eax,%eax
  call   <getutent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L2
  xor    %eax,%eax
  call   <endutent@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct utmp *up;
  if (argc > 1)
    utmpname(argv[1]);
  setutent();
  while ((up = getutent()))
    print_entry(up);
  endutent();
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L20
  mov    0x8(%rsi),%rdi
  call   <utmpname@plt>
L20:
  xor    %eax,%eax
  call   <setutent@plt>
  jmp    L22
  nop
L26:
  call   <print_entry@plt>
L22:
  xor    %eax,%eax
  call   <getutent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L26
  xor    %eax,%eax
  call   <endutent@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  struct utmp *up;
  if (argc > 1)
    utmpname(argv[1]);
  setutent();
  while ((up = getutent()))
    print_entry(up);
  endutent();
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lectura_dim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: string

tool: D8: Tamano la matriz %d:
	Filas = 

tool: D2: %d

tool: D21: 	Columnas = 

assistant: ```c
void lectura_dim(int dimensiones[], const int i) {
  printf("Tamano la matriz %d:\n\tFilas = ", i);
  scanf("%d", &dimensiones[1]);
  printf("\tColumnas = ");
  scanf("%d", &dimensiones[0]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lectura_dim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rbx),%rsi
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D3
datatype: string

tool: D13: Tamano la matriz %d:
	Filas = 

tool: D22: %d

tool: D3: 	Columnas = 

assistant: ```c
void lectura_dim(int dimensiones[], const int i) {
  printf("Tamano la matriz %d:\n\tFilas = ", i);
  scanf("%d", &dimensiones[1]);
  printf("\tColumnas = ");
  scanf("%d", &dimensiones[0]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lectura_dim>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D26(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D23(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <scanf@plt>
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D26: %d

tool: D23: Tamano la matriz %d:
	Filas = 

tool: D4: 	Columnas = 

assistant: ```c
void lectura_dim(int dimensiones[], const int i) {
  printf("Tamano la matriz %d:\n\tFilas = ", i);
  scanf("%d", &dimensiones[1]);
  printf("\tColumnas = ");
  scanf("%d", &dimensiones[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lectura_dim>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D28(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D22(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <scanf@plt>
```

tool_calls: name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D24
type_infered: string

tool: D28: %d

tool: D22: Tamano la matriz %d:
	Filas = 

tool: D24: 	Columnas = 

assistant: ```c
void lectura_dim(int dimensiones[], const int i) {
  printf("Tamano la matriz %d:\n\tFilas = ", i);
  scanf("%d", &dimensiones[1]);
  printf("\tColumnas = ");
  scanf("%d", &dimensiones[0]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getipnodebyaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gethostbyaddr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  cmpq   $0x0,-0x30(%rbp)
  je     L19
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L19:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct hostent *getipnodebyaddr(const void *addr, size_t len, int af, int *error_num) {
  struct hostent *hostent = gethostbyaddr(addr, len, af);
  if (!hostent && error_num)
    *error_num = h_errno;
  return hostent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getipnodebyaddr>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gethostbyaddr@plt>
  test   %rax,%rax
  jne    L5
  test   %rbx,%rbx
  je     L5
  mov    D8(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rbx)
L5:
  pop    %rbx
  ret
```

assistant: ```c
struct hostent *getipnodebyaddr(const void *addr, size_t len, int af, int *error_num) {
  struct hostent *hostent = gethostbyaddr(addr, len, af);
  if (!hostent && error_num)
    *error_num = h_errno;
  return hostent;
}
```
user: What is the c source code of the assembly code below:

```asm
<getipnodebyaddr>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gethostbyaddr@plt>
  test   %rax,%rax
  jne    L10
  test   %rbx,%rbx
  je     L10
  mov    D2(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rbx)
L10:
  pop    %rbx
  ret
```

assistant: ```c
struct hostent *getipnodebyaddr(const void *addr, size_t len, int af, int *error_num) {
  struct hostent *hostent = gethostbyaddr(addr, len, af);
  if (!hostent && error_num)
    *error_num = h_errno;
  return hostent;
}
```
user: What is the c source code of the assembly code below:

```asm
<getipnodebyaddr>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gethostbyaddr@plt>
  test   %rax,%rax
  jne    L19
  test   %rbx,%rbx
  je     L19
  mov    D8(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rbx)
L19:
  pop    %rbx
  ret
```

assistant: ```c
struct hostent *getipnodebyaddr(const void *addr, size_t len, int af, int *error_num) {
  struct hostent *hostent = gethostbyaddr(addr, len, af);
  if (!hostent && error_num)
    *error_num = h_errno;
  return hostent;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utl_peg_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L39
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
L39:
  mov    $0xffffffff,%eax
  jmp    L31
L63:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L63
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L74
  mov    -0x4(%rbp),%eax
  jmp    L31
L74:
  mov    $0xffffffff,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int utl_peg_str(const char *pat, const char *str) {
  int k = 0;
  if (!(str && *str))
    return -1;
  while (*str && *pat && (*str == *pat)) {
    str++;
    pat++;
    k++;
  }
  return (*pat == '\0' ? k : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utl_peg_str>:
  endbr64
  test   %rsi,%rsi
  je     L31
  movzbl (%rsi),%eax
  test   %al,%al
  je     L39
  mov    $0x0,%ecx
L46:
  movzbl (%rdi),%edx
  cmp    %al,%dl
  jne    L13
  test   %dl,%dl
  je     L13
  add    $0x1,%rsi
  add    $0x1,%rdi
  add    $0x1,%ecx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L46
L13:
  cmpb   $0x0,(%rdi)
  mov    $0xffffffff,%eax
  cmovne %eax,%ecx
L41:
  mov    %ecx,%eax
  ret
L31:
  mov    $0xffffffff,%ecx
  jmp    L41
L39:
  mov    $0xffffffff,%ecx
  jmp    L41
```

assistant: ```c
int utl_peg_str(const char *pat, const char *str) {
  int k = 0;
  if (!(str && *str))
    return -1;
  while (*str && *pat && (*str == *pat)) {
    str++;
    pat++;
    k++;
  }
  return (*pat == '\0' ? k : -1);
}
```
user: What is the c source code of the assembly code below?

```asm
<utl_peg_str>:
  endbr64
  test   %rsi,%rsi
  je     L30
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L30
  xor    %r8d,%r8d
  jmp    L3
  nopl   (%rax)
L8:
  test   %al,%al
  je     L79
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  lea    0x1(%rdi),%rax
  add    $0x1,%r8d
  test   %dl,%dl
  je     L42
  mov    %rax,%rdi
L3:
  movzbl (%rdi),%eax
  cmp    %dl,%al
  je     L8
L79:
  test   %al,%al
  mov    $0xffffffff,%eax
  cmovne %eax,%r8d
L41:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L42:
  movzbl 0x1(%rdi),%eax
  jmp    L79
L30:
  mov    $0xffffffff,%r8d
  jmp    L41
```

assistant: ```c
int utl_peg_str(const char *pat, const char *str) {
  int k = 0;
  if (!(str && *str))
    return -1;
  while (*str && *pat && (*str == *pat)) {
    str++;
    pat++;
    k++;
  }
  return (*pat == '\0' ? k : -1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utl_peg_str>:
  endbr64
  test   %rsi,%rsi
  je     L24
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L24
  xor    %r8d,%r8d
  jmp    L67
  nopl   (%rax)
L20:
  test   %al,%al
  je     L2
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  lea    0x1(%rdi),%rax
  add    $0x1,%r8d
  test   %dl,%dl
  je     L71
  mov    %rax,%rdi
L67:
  movzbl (%rdi),%eax
  cmp    %dl,%al
  je     L20
L2:
  test   %al,%al
  mov    $0xffffffff,%eax
  cmovne %eax,%r8d
L6:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L71:
  movzbl 0x1(%rdi),%eax
  jmp    L2
L24:
  mov    $0xffffffff,%r8d
  jmp    L6
```

assistant: ```c
int utl_peg_str(const char *pat, const char *str) {
  int k = 0;
  if (!(str && *str))
    return -1;
  while (*str && *pat && (*str == *pat)) {
    str++;
    pat++;
    k++;
  }
  return (*pat == '\0' ? k : -1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sync_word_fuzzy_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L27
  mov    $0x1,%eax
  jmp    L77
L27:
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L77
L5:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L92
  mov    $0x1,%eax
  jmp    L77
L92:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L86
  mov    $0x1,%eax
  jmp    L77
L86:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L55
  mov    $0x1,%eax
  jmp    L77
L55:
  mov    $0x0,%eax
L77:
  pop    %rbp
  ret
```

assistant: ```c
int sync_word_fuzzy_compare(uint64_t word, uint64_t expected) {
  uint64_t diff;
  if (word == expected)
    return 1;
  diff = word ^ expected;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_word_fuzzy_compare>:
  endbr64
  mov    $0x1,%edx
  cmp    %esi,%edi
  je     L6
  xor    %esi,%edi
  lea    -0x1(%rdi),%eax
  and    %edi,%eax
  je     L6
  lea    -0x1(%rax),%ecx
  and    %eax,%ecx
  je     L6
  lea    -0x1(%rcx),%eax
  and    %ecx,%eax
  je     L6
  lea    -0x1(%rax),%edx
  test   %eax,%edx
  sete   %dl
  movzbl %dl,%edx
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int sync_word_fuzzy_compare(uint64_t word, uint64_t expected) {
  uint64_t diff;
  if (word == expected)
    return 1;
  diff = word ^ expected;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_word_fuzzy_compare>:
  endbr64
  mov    $0x1,%r8d
  cmp    %esi,%edi
  je     L1
  xor    %esi,%edi
  lea    -0x1(%rdi),%eax
  and    %edi,%eax
  je     L1
  lea    -0x1(%rax),%edx
  and    %eax,%edx
  je     L1
  lea    -0x1(%rdx),%eax
  and    %edx,%eax
  je     L1
  lea    -0x1(%rax),%edx
  xor    %r8d,%r8d
  test   %eax,%edx
  sete   %r8b
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sync_word_fuzzy_compare(uint64_t word, uint64_t expected) {
  uint64_t diff;
  if (word == expected)
    return 1;
  diff = word ^ expected;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sync_word_fuzzy_compare>:
  endbr64
  mov    $0x1,%r8d
  cmp    %esi,%edi
  je     L34
  xor    %esi,%edi
  lea    -0x1(%rdi),%eax
  and    %edi,%eax
  je     L34
  lea    -0x1(%rax),%edx
  and    %eax,%edx
  je     L34
  lea    -0x1(%rdx),%eax
  and    %edx,%eax
  je     L34
  lea    -0x1(%rax),%edx
  xor    %r8d,%r8d
  test   %eax,%edx
  sete   %r8b
L34:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sync_word_fuzzy_compare(uint64_t word, uint64_t expected) {
  uint64_t diff;
  if (word == expected)
    return 1;
  diff = word ^ expected;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  diff &= (diff - 1);
  if (!diff)
    return 1;
  return 0;
}
```