ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_results>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L14
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D9(%rip),%rbp
L5:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L5
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D5: Results;%s;

tool: D9: %f;

assistant: ```c
void print_results(double *records, int num_runs, char *name) {
  printf("Results;%s;", name);
  int i;
  for (i = 0; i < num_runs; i++) {
    printf("%f;", records[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_results>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  lea    D17(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax)
L18:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D6: Results;%s;

tool: D17: %f;

assistant: ```c
void print_results(double *records, int num_runs, char *name) {
  printf("Results;%s;", name);
  int i;
  for (i = 0; i < num_runs; i++) {
    printf("%f;", records[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_results>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%eax
  lea    D7(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax)
L14:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
L10:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D7
data_type: string

tool: D4: Results;%s;

tool: D7: %f;

assistant: ```c
void print_results(double *records, int num_runs, char *name) {
  printf("Results;%s;", name);
  int i;
  for (i = 0; i < num_runs; i++) {
    printf("%f;", records[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L18:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L75
L15:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L75:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L15
L0:
  cmpl   $0x0,-0x4(%rbp)
  jle    L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    -0xc(%rbp),%eax
  jmp    L27
L50:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0xffffffff,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return i;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L60
  movzbl (%rsi),%r9d
  mov    $0x0,%r8d
  jmp    L10
L87:
  add    $0x1,%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L67
L10:
  mov    %r9d,%edx
  mov    $0x0,%eax
  test   %r9b,%r9b
  je     L87
L65:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rax,1)
  jne    L99
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L65
L99:
  test   %dl,%dl
  jne    L87
  test   %ecx,%ecx
  jle    L87
  jmp    L81
L60:
  mov    $0xffffffff,%r8d
  jmp    L81
L67:
  mov    $0xffffffff,%r8d
L81:
  mov    %r8d,%eax
  ret
```

assistant: ```c
strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L16:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L30
  jmp    L17
L46:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L31
L30:
  cmp    %dl,(%rdi,%rax,1)
  je     L46
L17:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L16
L0:
  mov    $0xffffffff,%r9d
L31:
  mov    %r9d,%eax
  ret
```

assistant: ```c
strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  nop
L9:
  mov    %ecx,%r9d
  mov    %rcx,%rax
  mov    %r8d,%edx
  test   %r8b,%r8b
  jne    L36
  jmp    L12
L56:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L48
L36:
  cmp    %dl,(%rdi,%rax,1)
  je     L56
L12:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L9
L10:
  mov    $0xffffffff,%r9d
L48:
  mov    %r9d,%eax
  ret
```

assistant: ```c
strindex(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return i;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_call>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  int    $0x64
  mov    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int do_call(unsigned type) {
  int v = 0;
  __asm__("movl %1,%%eax;							 int $0x64;									 movl "
          "%%eax,%0;		"
          : "=r"(v)
          : "r"(type)
          : "%eax");
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_call>:
  endbr64
  mov    %edi,%eax
  int    $0x64
  mov    %eax,%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
int do_call(unsigned type) {
  int v = 0;
  __asm__("movl %1,%%eax;							 int $0x64;									 movl "
          "%%eax,%0;		"
          : "=r"(v)
          : "r"(type)
          : "%eax");
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_call>:
  endbr64
  mov    %edi,%eax
  int    $0x64
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int do_call(unsigned type) {
  int v = 0;
  __asm__("movl %1,%%eax;							 int $0x64;									 movl "
          "%%eax,%0;		"
          : "=r"(v)
          : "r"(type)
          : "%eax");
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<do_call>:
  endbr64
  mov    %edi,%eax
  int    $0x64
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int do_call(unsigned type) {
  int v = 0;
  __asm__("movl %1,%%eax;							 int $0x64;									 movl "
          "%%eax,%0;		"
          : "=r"(v)
          : "r"(type)
          : "%eax");
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<expand_fascn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movb   $0x0,-0x11(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L28:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L77:
  cmpb   $0x0,-0x12(%rbp)
  jns    L2
  xorb   $0x1,-0x11(%rbp)
L2:
  movsbl -0x12(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x12(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L69
  movsbl -0x11(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <convertCharacter@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0x5a,-0x11(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L30
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  movb   $0x0,-0x11(%rbp)
L69:
  movsbl -0x11(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x11(%rbp)
  addl   $0x1,-0x8(%rbp)
L36:
  cmpl   $0x7,-0x8(%rbp)
  jle    L77
  addl   $0x1,-0x10(%rbp)
L54:
  cmpl   $0x18,-0x10(%rbp)
  jle    L28
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
int expand_fascn(fascn25, fascn40)
char fascn25[25], fascn40[40];
{
  int byte_count, bit_count, bit_index, expanded_index;
  char temp, temp2 = 0;
  for (bit_count = 0, byte_count = 0, expanded_index = 0; byte_count < 25; byte_count++) {
    temp = fascn25[byte_count];
    for (bit_index = 0; bit_index < 8; bit_index++) {
      if (0x80 & temp) {
        temp2 ^= 0x01;
      }
      temp <<= 1;
      bit_count += 1;
      if ((bit_count % 5) == 0) {
        temp2 = convertCharacter(temp2);
        if (temp2 == 'Z') {
          return (1);
        }
        fascn40[expanded_index] = temp2;
        expanded_index += 1;
        temp2 = 0;
      }
      temp2 <<= 1;
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<expand_fascn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r15
  mov    %rdi,%r14
  lea    0x19(%rdi),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%edi
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L42
L17:
  add    %edi,%edi
  cmp    %ebx,%r12d
  je     L46
L5:
  mov    %edi,%eax
  xor    $0x1,%eax
  test   %bpl,%bpl
  cmovs  %eax,%edi
  add    %ebp,%ebp
  add    $0x1,%ebx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L17
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <convertCharacter@plt>
  cmp    $0x5a,%al
  je     L77
  movslq %r13d,%rdx
  mov    %al,(%r15,%rdx,1)
  add    $0x1,%r13d
  mov    $0x0,%edi
  jmp    L17
L46:
  add    $0x1,%r14
  cmp    0x8(%rsp),%r14
  je     L38
L42:
  movzbl (%r14),%ebp
  lea    0x8(%rbx),%r12d
  jmp    L5
L38:
  mov    $0x0,%eax
  jmp    L66
L77:
  mov    $0x1,%eax
L66:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int expand_fascn(fascn25, fascn40)
char fascn25[25], fascn40[40];
{
  int byte_count, bit_count, bit_index, expanded_index;
  char temp, temp2 = 0;
  for (bit_count = 0, byte_count = 0, expanded_index = 0; byte_count < 25; byte_count++) {
    temp = fascn25[byte_count];
    for (bit_index = 0; bit_index < 8; bit_index++) {
      if (0x80 & temp) {
        temp2 ^= 0x01;
      }
      temp <<= 1;
      bit_count += 1;
      if ((bit_count % 5) == 0) {
        temp2 = convertCharacter(temp2);
        if (temp2 == 'Z') {
          return (1);
        }
        fascn40[expanded_index] = temp2;
        expanded_index += 1;
        temp2 = 0;
      }
      temp2 <<= 1;
    }
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<expand_fascn>:
  endbr64
  push   %r15
  lea    0x19(%rdi),%rax
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl 0x0(%rbp),%r14d
  lea    0x8(%rbx),%r15d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L10:
  add    %edi,%edi
  cmp    %ebx,%r15d
  je     L11
L29:
  mov    %edi,%eax
  xor    $0x1,%eax
  test   %r14b,%r14b
  cmovs  %eax,%edi
  add    $0x1,%ebx
  add    %r14d,%r14d
  imul   $0xcccccccd,%ebx,%eax
  movsbl %dil,%edi
  cmp    $0x33333333,%eax
  ja     L10
  xor    %eax,%eax
  call   <convertCharacter@plt>
  cmp    $0x5a,%al
  je     L59
  movslq %r13d,%rcx
  xor    %edi,%edi
  add    $0x1,%r13d
  mov    %al,(%r12,%rcx,1)
  cmp    %ebx,%r15d
  jne    L29
L11:
  add    $0x1,%rbp
  cmp    %rbp,0x8(%rsp)
  jne    L44
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int expand_fascn(fascn25, fascn40)
char fascn25[25], fascn40[40];
{
  int byte_count, bit_count, bit_index, expanded_index;
  char temp, temp2 = 0;
  for (bit_count = 0, byte_count = 0, expanded_index = 0; byte_count < 25; byte_count++) {
    temp = fascn25[byte_count];
    for (bit_index = 0; bit_index < 8; bit_index++) {
      if (0x80 & temp) {
        temp2 ^= 0x01;
      }
      temp <<= 1;
      bit_count += 1;
      if ((bit_count % 5) == 0) {
        temp2 = convertCharacter(temp2);
        if (temp2 == 'Z') {
          return (1);
        }
        fascn40[expanded_index] = temp2;
        expanded_index += 1;
        temp2 = 0;
      }
      temp2 <<= 1;
    }
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getUsername>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D10: Username: 

tool: D2: %s

assistant: ```c
char *getUsername(void) {
  char *username = malloc(sizeof(char) * 100);
  printf("Username: ");
  scanf("%s", username);
  return username;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getUsername>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D2: Username: 

tool: D6: %s

assistant: ```c
char *getUsername(void) {
  char *username = malloc(sizeof(char) * 100);
  printf("Username: ");
  scanf("%s", username);
  return username;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getUsername>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  call   <malloc@plt>
  lea    D13(%rip),%rdi
  mov    %rax,%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D19
type: string

tool: D13: Username: 

tool: D19: %s

assistant: ```c
char *getUsername(void) {
  char *username = malloc(sizeof(char) * 100);
  printf("Username: ");
  scanf("%s", username);
  return username;
}
```
user: What is the c source code of the assembly code below?

```asm
<getUsername>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  call   <malloc@plt>
  lea    D15(%rip),%rdi
  mov    %rax,%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D15: Username: 

tool: D13: %s

assistant: ```c
char *getUsername(void) {
  char *username = malloc(sizeof(char) * 100);
  printf("Username: ");
  scanf("%s", username);
  return username;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vflip1_smatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L28
L2:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L21:
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzwl (%rcx),%eax
  mov    %ax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzwl -0xe(%rbp),%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L21
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vflip1_smatrix(short **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  short t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vflip1_smatrix>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L11
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r8,%rbp
  mov    %edx,%r11d
  lea    (%rdi,%rax,8),%rsi
  lea    0x8(%rdi,%rdx,8),%r13
  movslq %ecx,%r12
  add    %r12,%r12
  lea    0x2(%r8,%r8,1),%r10
  movslq %ecx,%r8
L35:
  cmp    %r8,%rbp
  jl     L25
  movslq %r11d,%rax
  lea    (%rbx,%rax,8),%r9
  mov    %r12,%rax
L21:
  mov    %rax,%rdx
  add    (%r9),%rdx
  movzwl (%rdx),%ecx
  mov    (%rsi),%rdi
  movzwl (%rdi,%rax,1),%edi
  mov    %di,(%rdx)
  mov    (%rsi),%rdx
  mov    %cx,(%rdx,%rax,1)
  add    $0x2,%rax
  cmp    %r10,%rax
  jne    L21
L25:
  add    $0x8,%rsi
  sub    $0x1,%r11d
  cmp    %r13,%rsi
  jne    L35
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  ret
```

assistant: ```c
void vflip1_smatrix(short **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  short t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vflip1_smatrix>:
  endbr64
  movslq %esi,%r10
  push   %r13
  push   %r12
  lea    (%rsi,%rdx,1),%r12d
  push   %rbp
  push   %rbx
  cmp    %r10,%rdx
  jl     L35
  mov    %r8,%rbp
  movslq %ecx,%r8
  mov    %rdi,%r11
  mov    %rdx,%rbx
  lea    (%r8,%r8,1),%r13
  lea    0x2(%rbp,%rbp,1),%r9
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %r8,%rbp
  jl     L40
  mov    %r12d,%eax
  mov    (%r11,%r10,8),%rdx
  sub    %r10d,%eax
  cltq
  mov    (%r11,%rax,8),%rcx
  mov    %r13,%rax
  nopl   0x0(%rax,%rax,1)
L2:
  movzwl (%rcx,%rax,1),%esi
  movzwl (%rdx,%rax,1),%edi
  mov    %di,(%rcx,%rax,1)
  mov    %si,(%rdx,%rax,1)
  add    $0x2,%rax
  cmp    %rax,%r9
  jne    L2
L40:
  lea    0x1(%r10),%rax
  cmp    %r10,%rbx
  je     L35
  mov    %rax,%r10
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void vflip1_smatrix(short **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  short t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<c64WriteBit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x6,%eax
  sub    %eax,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  shl    $0x6,%eax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x9,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <writeBit@plt>
  nop
  leave
  ret
```

assistant: ```c
void c64WriteBit(int8_t *buf, int x, int8_t val) {
  int m = x % 320;
  int xl = m % 8 + ((m / 8) * 64);
  int yl = x / 320;
  int r = yl / 8;
  int idx = ((yl % 8) * 8) + xl + (r * 320 * 8);
  writeBit(buf, idx, val);
}
```