user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%r15
  push   %r14
  lea    D70(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbx
  mov    $0x6f,%eax
  movl   $0x6c6c6548,0x2(%rsp)
  mov    %rbx,%rdi
  mov    %ax,0x6(%rsp)
  lea    0x3(%rsp),%r13
  call   <strlen@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edx,%edx
  mov    $0x6,%esi
  xor    %eax,%eax
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jns    L33
  jmp    L65
L60:
  lea    (%rbx,%r12,1),%rcx
  mov    $0x1,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L57:
  add    $0x1,%r12
  cmp    %r12d,%ebp
  jl     L6
L33:
  lea    0x1(%r12),%esi
  test   %r12,%r12
  je     L27
  cmp    $0x1,%r12d
  jne    L60
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,%ebp
  jge    L33
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L54
  lea    -0x1(%rbp),%eax
  lea    D38(%rip),%rbp
  lea    0x3(%rsp,%rax,1),%r12
  nopl   0x0(%rax)
L40:
  movsbl (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L40
L54:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    $0xee1ee,%edi
  call   <exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L57
L65:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L54
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D40
type_infered: string
name: unpack_data
arguments: label: D70
type_infered: string
name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string
name: unpack_data
arguments: label: D73
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string

tool: D40: First element of 'array' is %d byte long and is located at %p adress.


tool: D70: The %dth element of 'array' is %d byte long and is located at %p adress.


tool: D13: 	%s


tool: D5: 



tool: D73: Array 'array' is %d bytes long and is located
	at the adress %p.

tool: D36: 


tool: D29: The %dnd element of 'array' is %d byte long and is located at %p adress.


tool: D38: Adress %p says "%c"


assistant: ```c
int main() {
  char array[] = "Hello";
  int a_len = strlen(array);
  int x = 0;
  char *a, *e;
  printf("\t%s\n", array);
  puts("\n\n");
  printf("Array 'array' is %d bytes long and is located\n\tat the adress %p.", sizeof(array), a);
  puts("\n");
  for (x = 0; x <= a_len; x++) {
    e = &array[x];
    switch (x) {
    case 0:
      printf("First element of 'array' is %d byte long and is located at %p adress.\n", sizeof(array[x]), e);
      break;
    case 1:
      printf("The %dnd element of 'array' is %d byte long and is located at %p adress.\n", x + 1, sizeof(array[x]), e);
      break;
    default:
      printf("The %dth element of 'array' is %d byte long and is located at %p adress.\n", x + 1, sizeof(array[x + 1]), e);
      break;
    }
  }
  x = 0;
  putchar('\n');
  for (x = 0; x < a_len; x++)
    printf("Adress %p says \"%c\"\n", &array[x], array[x]);
  getchar();
  exit(975342);
}
```