ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_vregs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L26
L6:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <dump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    0x8(%rax),%rbx
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    (%rax),%rax
  mov    %rbx,%rsi
  xor    %rdx,%rsi
  xor    %rcx,%rax
  or     %rsi,%rax
  test   %rax,%rax
  je     L11
  movl   $0x0,-0x14(%rbp)
L11:
  addl   $0x1,-0x18(%rbp)
L26:
  cmpl   $0x4,-0x18(%rbp)
  jle    L6
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: # v[%d]:

assistant: ```c
int check_vregs(const __uint128_t vregs[5]) {
  int i;
  int ok = 1;
  for (i = 0; i < 5; ++i) {
    printf("# v[%d]:", i);
    dump(&vregs[i], sizeof vregs[i]);
    putchar('\n');
    if (vregs[i] != vregs[0])
      ok = 0;
  }
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_vregs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
  mov    $0x1,%r13d
  mov    $0x0,%ebp
  lea    D6(%rip),%r14
L8:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <dump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rbx),%rdx
  mov    0x8(%rbx),%rax
  xor    0x8(%r12),%rax
  xor    (%r12),%rdx
  or     %rdx,%rax
  mov    $0x0,%eax
  cmovne %eax,%r13d
  add    $0x1,%ebp
  add    $0x10,%rbx
  cmp    $0x5,%ebp
  jne    L8
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: # v[%d]:

assistant: ```c
int check_vregs(const __uint128_t vregs[5]) {
  int i;
  int ok = 1;
  for (i = 0; i < 5; ++i) {
    printf("# v[%d]:", i);
    dump(&vregs[i], sizeof vregs[i]);
    putchar('\n');
    if (vregs[i] != vregs[0])
      ok = 0;
  }
  return ok;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_vregs>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L1:
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x10,%esi
  xor    %eax,%eax
  call   <dump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rbx),%rdx
  mov    0x8(%rbx),%rax
  xor    (%r14),%rdx
  xor    0x8(%r14),%rax
  or     %rdx,%rax
  cmovne %ebp,%r15d
  add    $0x1,%r13d
  add    $0x10,%rbx
  cmp    $0x5,%r13d
  jne    L1
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: # v[%d]:

assistant: ```c
int check_vregs(const __uint128_t vregs[5]) {
  int i;
  int ok = 1;
  for (i = 0; i < 5; ++i) {
    printf("# v[%d]:", i);
    dump(&vregs[i], sizeof vregs[i]);
    putchar('\n');
    if (vregs[i] != vregs[0])
      ok = 0;
  }
  return ok;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_vregs>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L6:
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x10,%esi
  xor    %eax,%eax
  call   <dump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rbx),%rdx
  mov    0x8(%rbx),%rax
  xor    (%r14),%rdx
  xor    0x8(%r14),%rax
  or     %rdx,%rax
  cmovne %ebp,%r15d
  add    $0x1,%r13d
  add    $0x10,%rbx
  cmp    $0x5,%r13d
  jne    L6
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: # v[%d]:

assistant: ```c
int check_vregs(const __uint128_t vregs[5]) {
  int i;
  int ok = 1;
  for (i = 0; i < 5; ++i) {
    printf("# v[%d]:", i);
    dump(&vregs[i], sizeof vregs[i]);
    putchar('\n');
    if (vregs[i] != vregs[0])
      ok = 0;
  }
  return ok;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<aml_array_int_3d_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L45:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L1:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L22:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L1
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int ***aml_array_int_3d_new(int s1, int s2, int s3, int val) {
  int i, j, k;
  int ***arr = (int ***)malloc(s1 * sizeof(int **));
  for (i = 0; i < s1; i++) {
    arr[i] = (int **)malloc(s2 * sizeof(int *));
    for (j = 0; j < s2; j++) {
      arr[i][j] = (int *)malloc(s3 * sizeof(int));
      for (k = 0; k < s3; k++)
        arr[i][j][k] = val;
    }
  }
  return arr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aml_array_int_3d_new>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %esi,%r15d
  mov    %esi,0x24(%rsp)
  mov    %edx,%r14d
  mov    %ecx,%r12d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x28(%rsp)
  test   %ebx,%ebx
  jle    L10
  lea    0x0(,%r15,8),%ecx
  mov    %ecx,0x20(%rsp)
  lea    0x0(,%r14,4),%ecx
  mov    %ecx,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%rax
  mov    %rax,0x18(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x8(,%rax,8),%r15
  lea    -0x1(%r14),%eax
  lea    0x4(,%rax,4),%r13
L13:
  mov    0x20(%rsp),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%rcx
  mov    %rcx,%rbp
  mov    %rax,(%rcx)
  cmpl   $0x0,0x24(%rsp)
  jle    L21
  mov    $0x0,%ebx
L48:
  mov    0xc(%rsp),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx,%rbx,1)
  test   %r14d,%r14d
  jle    L57
  mov    $0x0,%eax
L30:
  mov    0x0(%rbp),%rdx
  mov    (%rdx,%rbx,1),%rdx
  mov    %r12d,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L30
L57:
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L48
L21:
  addq   $0x8,0x10(%rsp)
  mov    0x10(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L13
L10:
  mov    0x28(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***aml_array_int_3d_new(int s1, int s2, int s3, int val) {
  int i, j, k;
  int ***arr = (int ***)malloc(s1 * sizeof(int **));
  for (i = 0; i < s1; i++) {
    arr[i] = (int **)malloc(s2 * sizeof(int *));
    for (j = 0; j < s2; j++) {
      arr[i][j] = (int *)malloc(s3 * sizeof(int));
      for (k = 0; k < s3; k++)
        arr[i][j][k] = val;
    }
  }
  return arr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aml_array_int_3d_new>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebp,%ebp
  jle    L35
  mov    %r14d,%ecx
  lea    0x0(,%r14,8),%esi
  mov    %rax,%r14
  lea    (%rax,%rbp,8),%rax
  mov    %esi,0x10(%rsp)
  lea    -0x1(%rbx),%r13d
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rcx),%eax
  lea    0x0(,%rbx,4),%r12d
  add    $0x1,%r13
  lea    0x8(,%rax,8),%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x10(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L47
  xor    %ebp,%ebp
  xchg   %ax,%ax
L36:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    (%r14),%rdx
  mov    %rax,(%rdx,%rbp,1)
  test   %ebx,%ebx
  jle    L46
  lea    (%rax,%r13,4),%rdx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r15d,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L29
L46:
  add    $0x8,%rbp
  cmp    (%rsp),%rbp
  jne    L36
L47:
  add    $0x8,%r14
  cmp    0x8(%rsp),%r14
  jne    L15
L35:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***aml_array_int_3d_new(int s1, int s2, int s3, int val) {
  int i, j, k;
  int ***arr = (int ***)malloc(s1 * sizeof(int **));
  for (i = 0; i < s1; i++) {
    arr[i] = (int **)malloc(s2 * sizeof(int *));
    for (j = 0; j < s2; j++) {
      arr[i][j] = (int *)malloc(s3 * sizeof(int));
      for (k = 0; k < s3; k++)
        arr[i][j][k] = val;
    }
  }
  return arr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aml_array_int_3d_new>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %ecx,%ebx
  sub    $0x48,%rsp
  mov    %esi,0x34(%rsp)
  call   <malloc@plt>
  mov    %rax,0x38(%rsp)
  test   %ebp,%ebp
  jle    L77
  mov    %rax,%r12
  lea    (%rax,%rbp,8),%rax
  lea    0x0(,%r15,8),%edi
  mov    %r14d,%ebp
  mov    %rax,0x28(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x0(,%r14,4),%r13d
  and    $0xfffffffc,%ebp
  lea    0x8(,%rax,8),%rax
  mov    %edi,0x30(%rsp)
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r14),%eax
  mov    %eax,0x1c(%rsp)
  mov    %r14d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%r15d
  add    $0x1,%r15
  shl    $0x4,%r15
  mov    %r15,0x20(%rsp)
  nop
L75:
  mov    0x30(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    0x34(%rsp),%eax
  test   %eax,%eax
  jle    L34
  movd   %ebx,%xmm1
  xor    %r15d,%r15d
  mov    %r12,%rbx
  mov    %r14d,%r12d
  pshufd $0x0,%xmm1,%xmm0
  mov    %r15,%r14
  movd   %xmm1,%r15d
  movaps %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L85:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    (%rbx),%rax
  mov    %rdx,(%rax,%r14,1)
  test   %r12d,%r12d
  jle    L71
  cmpl   $0x2,0x1c(%rsp)
  jbe    L10
  mov    0x20(%rsp),%rsi
  movdqa (%rsp),%xmm0
  mov    %rdx,%rax
  lea    (%rsi,%rdx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L8:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L8
  mov    %ebp,%eax
  cmp    %ebp,%r12d
  je     L71
L31:
  movslq %eax,%rcx
  mov    %r15d,(%rdx,%rcx,4)
  lea    0x0(,%rcx,4),%rdi
  lea    0x1(%rax),%ecx
  cmp    %ecx,%r12d
  jle    L71
  add    $0x2,%eax
  mov    %r15d,0x4(%rdx,%rdi,1)
  cmp    %eax,%r12d
  jle    L71
  mov    %r15d,0x8(%rdx,%rdi,1)
L71:
  add    $0x8,%r14
  cmp    0x10(%rsp),%r14
  jne    L85
  mov    %r12d,%r14d
  mov    %rbx,%r12
  mov    %r15d,%ebx
L34:
  add    $0x8,%r12
  cmp    0x28(%rsp),%r12
  jne    L75
L77:
  mov    0x38(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
int ***aml_array_int_3d_new(int s1, int s2, int s3, int val) {
  int i, j, k;
  int ***arr = (int ***)malloc(s1 * sizeof(int **));
  for (i = 0; i < s1; i++) {
    arr[i] = (int **)malloc(s2 * sizeof(int *));
    for (j = 0; j < s2; j++) {
      arr[i][j] = (int *)malloc(s3 * sizeof(int));
      for (k = 0; k < s3; k++)
        arr[i][j][k] = val;
    }
  }
  return arr;
}
```
user: What is the c source code of the assembly code below?

```asm
<deallocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void deallocate(void *value) {
  assert(value);
  free(value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deallocate>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void deallocate(void *value) {
  assert(value);
  free(value);
}
```
user: What is the c source code of the assembly code below?

```asm
<deallocate>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void deallocate(void *value) {
  assert(value);
  free(value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deallocate>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void deallocate(void *value) {
  assert(value);
  free(value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L58
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L58:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    D20(%rip),%rax
  test   %rax,%rax
  jne    L67
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <get_cmdline@plt>
  mov    %rax,-0x1c8(%rbp)
  cmpq   $0x0,-0x1c8(%rbp)
  je     L0
  mov    -0x1c8(%rbp),%rax
  jmp    L34
L0:
  lea    D27(%rip),%rax
L34:
  lea    D30(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,D65(%rip)
  mov    D65(%rip),%rax
  test   %rax,%rax
  je     L29
L67:
  mov    -0x1d8(%rbp),%rdx
  mov    -0x1cc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1cc(%rbp),%ecx
  mov    -0x1d8(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x1cc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D65(%rip),%rax
  lea    -0x1c0(%rbp),%rdx
  lea    D65(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    D65(%rip),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  jmp    L23
L29:
  nop
L23:
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string
name: retrieve_data
arguments: data_label: D30
data_type: string
name: retrieve_data
arguments: data_label: D65
data_type: string

tool: D6: debug_tty

tool: D27: /dev/tty3

tool: D30: a

tool: D65: %s


assistant: ```c
void debug(char const *fmt, ...) {
  static FILE *debug_fh = NULL;
  va_list argv;
  char msgbuf[256];
  if (!debug_fh) {
    char const *path = get_cmdline("debug_tty");
    debug_fh = fopen(path ? path : "/dev/tty3", "a");
    if (!debug_fh) {
      return;
    }
  }
  va_start(argv, fmt);
  vsnprintf(msgbuf, 256, fmt, argv);
  va_end(argv);
  fprintf(debug_fh, "%s\n", msgbuf);
  fflush(debug_fh);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int **pa;
  pa = (int **)malloc(5 * 8);
  free(pa);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int **pa;
  pa = (int **)malloc(5 * 8);
  free(pa);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int **pa;
  pa = (int **)malloc(5 * 8);
  free(pa);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int **pa;
  pa = (int **)malloc(5 * 8);
  free(pa);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x2c(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x24(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x24(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%edi
  call   <log10@plt>
  imul   %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    -0x24(%rbp),%edx
  add    %edx,%eax
  lea    0x1(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  jmp    L27
L0:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
L27:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L0
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D1: %f%d

tool: D0: P=%f


assistant: ```c
main() {
  float x, P;
  int n, N, k;
  k = 1;
  n = 0;
  scanf("%f%d", &x, &N);
  P = (pow(x, k) * log10(k * x)) / (pow(k, 2) + k + 1);
  while (N > n) {
    P == P *P;
    N--;
  }
  printf("P=%f\n", P);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  cvttss2si (%rsp),%edi
  mov    $0x1,%esi
  call   <pow@plt>
  mov    %eax,%ebx
  cvttss2si (%rsp),%edi
  call   <log10@plt>
  imul   %eax,%ebx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <pow@plt>
  lea    0x2(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L26
L9:
  sub    $0x1,%eax
  jne    L9
  movl   $0x0,0x4(%rsp)
L26:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D0
type: string

tool: D3: %f%d

tool: D0: P=%f


assistant: ```c
main() {
  float x, P;
  int n, N, k;
  k = 1;
  n = 0;
  scanf("%f%d", &x, &N);
  P = (pow(x, k) * log10(k * x)) / (pow(k, 2) + k + 1);
  while (N > n) {
    P == P *P;
    N--;
  }
  printf("P=%f\n", P);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  cvttss2si (%rsp),%edi
  mov    $0x1,%esi
  call   <pow@plt>
  cvttss2si (%rsp),%edi
  mov    %eax,%ebx
  call   <log10@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  imul   %eax,%ebx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  lea    0x2(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cvtsi2ss %eax,%xmm0
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L1
  movl   $0x0,0x4(%rsp)
L1:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D9: %f%d

tool: D8: P=%f


assistant: ```c
main() {
  float x, P;
  int n, N, k;
  k = 1;
  n = 0;
  scanf("%f%d", &x, &N);
  P = (pow(x, k) * log10(k * x)) / (pow(k, 2) + k + 1);
  while (N > n) {
    P == P *P;
    N--;
  }
  printf("P=%f\n", P);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  cvttss2si (%rsp),%edi
  mov    $0x1,%esi
  call   <pow@plt>
  cvttss2si (%rsp),%edi
  mov    %eax,%ebx
  call   <log10@plt>
  mov    $0x2,%esi
  mov    $0x1,%edi
  imul   %eax,%ebx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  lea    0x2(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cvtsi2ss %eax,%xmm0
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L19
  movl   $0x0,0x4(%rsp)
L19:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D6
datatype: string

tool: D2: %f%d

tool: D6: P=%f


assistant: ```c
main() {
  float x, P;
  int n, N, k;
  k = 1;
  n = 0;
  scanf("%f%d", &x, &N);
  P = (pow(x, k) * log10(k * x)) / (pow(k, 2) + k + 1);
  while (N > n) {
    P == P *P;
    N--;
  }
  printf("P=%f\n", P);
  return 0;
}
```