ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D33(%rip),%rdi
  lea    D55(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x110(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x220,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D33
type: string
name: read_data
arguments: data_label: D55
type: string
name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D45
type: string
name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D25
type: string

tool: D33: Enter your name (max 255 chars): 

tool: D55: %s

tool: D2: Enter address (max 255 chars): 

tool: D45: Enter age: 

tool: D10: %d

tool: D25: Name: %s; Address: %s; Age: %d


assistant: ```c
int main() {
  char name[255], address[255];
  int age;
  printf("Enter your name (max 255 chars): ");
  scanf("%s", name);
  printf("Enter address (max 255 chars): ");
  scanf("%s", address);
  printf("Enter age: ");
  scanf("%d", &age);
  printf("Name: %s; Address: %s; Age: %d\n", name, address, age);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nseel_asm_assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    (%eax),%ecx
  mov    0x4(%eax),%edx
  mov    %edx,%eax
  add    $0x100000,%eax
  and    $0x7ff00000,%eax
  cmp    $0x100000,%eax
  jg     L1
  sub    %ecx,%ecx
  sub    %edx,%edx
L1:
  mov    %edi,%eax
  mov    %ecx,(%edi)
  mov    %edx,0x4(%edi)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nseel_asm_assign(void) {
  __asm__("movl (%eax), %ecx\n"
          "movl 4(%eax), %edx\n"
          "movl %edx, %eax\n"
          "addl $0x00100000, %eax\n"
          "andl $0x7ff00000, %eax\n"
          "cmpl $0x00100000, %eax\n"
          "jg 0f\n"
          "subl %ecx, %ecx\n"
          "subl %edx, %edx\n"
          "0:\n"
          "movl %edi, %eax\n"
          "movl %ecx, (%edi)\n"
          "movl %edx, 4(%edi)\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nseel_asm_assign>:
  endbr64
  mov    (%eax),%ecx
  mov    0x4(%eax),%edx
  mov    %edx,%eax
  add    $0x100000,%eax
  and    $0x7ff00000,%eax
  cmp    $0x100000,%eax
  jg     L6
  sub    %ecx,%ecx
  sub    %edx,%edx
L6:
  mov    %edi,%eax
  mov    %ecx,(%edi)
  mov    %edx,0x4(%edi)
  ret
```

assistant: ```c
void nseel_asm_assign(void) {
  __asm__("movl (%eax), %ecx\n"
          "movl 4(%eax), %edx\n"
          "movl %edx, %eax\n"
          "addl $0x00100000, %eax\n"
          "andl $0x7ff00000, %eax\n"
          "cmpl $0x00100000, %eax\n"
          "jg 0f\n"
          "subl %ecx, %ecx\n"
          "subl %edx, %edx\n"
          "0:\n"
          "movl %edi, %eax\n"
          "movl %ecx, (%edi)\n"
          "movl %edx, 4(%edi)\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nseel_asm_assign>:
  endbr64
  mov    (%eax),%ecx
  mov    0x4(%eax),%edx
  mov    %edx,%eax
  add    $0x100000,%eax
  and    $0x7ff00000,%eax
  cmp    $0x100000,%eax
  jg     L7
  sub    %ecx,%ecx
  sub    %edx,%edx
L7:
  mov    %edi,%eax
  mov    %ecx,(%edi)
  mov    %edx,0x4(%edi)
  ret
```

assistant: ```c
void nseel_asm_assign(void) {
  __asm__("movl (%eax), %ecx\n"
          "movl 4(%eax), %edx\n"
          "movl %edx, %eax\n"
          "addl $0x00100000, %eax\n"
          "andl $0x7ff00000, %eax\n"
          "cmpl $0x00100000, %eax\n"
          "jg 0f\n"
          "subl %ecx, %ecx\n"
          "subl %edx, %edx\n"
          "0:\n"
          "movl %edi, %eax\n"
          "movl %ecx, (%edi)\n"
          "movl %edx, 4(%edi)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nseel_asm_assign>:
  endbr64
  mov    (%eax),%ecx
  mov    0x4(%eax),%edx
  mov    %edx,%eax
  add    $0x100000,%eax
  and    $0x7ff00000,%eax
  cmp    $0x100000,%eax
  jg     L8
  sub    %ecx,%ecx
  sub    %edx,%edx
L8:
  mov    %edi,%eax
  mov    %ecx,(%edi)
  mov    %edx,0x4(%edi)
  ret
```

assistant: ```c
void nseel_asm_assign(void) {
  __asm__("movl (%eax), %ecx\n"
          "movl 4(%eax), %edx\n"
          "movl %edx, %eax\n"
          "addl $0x00100000, %eax\n"
          "andl $0x7ff00000, %eax\n"
          "cmpl $0x00100000, %eax\n"
          "jg 0f\n"
          "subl %ecx, %ecx\n"
          "subl %edx, %edx\n"
          "0:\n"
          "movl %edi, %eax\n"
          "movl %ecx, (%edi)\n"
          "movl %edx, 4(%edi)\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<n_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <n_vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int n_snprintf(char *str, size_t size, const char *fmt, ...) {
  va_list ap;
  int s;
  va_start(ap, fmt);
  s = n_vsnprintf(str, size, fmt, ap);
  va_end(ap);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<n_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <n_vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int n_snprintf(char *str, size_t size, const char *fmt, ...) {
  va_list ap;
  int s;
  va_start(ap, fmt);
  s = n_vsnprintf(str, size, fmt, ap);
  va_end(ap);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<n_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <n_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int n_snprintf(char *str, size_t size, const char *fmt, ...) {
  va_list ap;
  int s;
  va_start(ap, fmt);
  s = n_vsnprintf(str, size, fmt, ap);
  va_end(ap);
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<n_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <n_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int n_snprintf(char *str, size_t size, const char *fmt, ...) {
  va_list ap;
  int s;
  va_start(ap, fmt);
  s = n_vsnprintf(str, size, fmt, ap);
  va_end(ap);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L18
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
  jmp    L19
L18:
  nop
L19:
  leave
  ret
```

assistant: ```c
void sort(int *a, int l, int r) {
  if (l >= r)
    return;
  int m = (l + r) / 2;
  sort(a, l, m);
  sort(a, m + 1, r);
  merge(a, l, m, r);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort>:
  endbr64
  cmp    %edx,%esi
  jl     L5
  ret
L5:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <sort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <sort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sort(int *a, int l, int r) {
  if (l >= r)
    return;
  int m = (l + r) / 2;
  sort(a, l, m);
  sort(a, m + 1, r);
  merge(a, l, m, r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L49
  movsd  D20(%rip),%xmm0
  jmp    L13
L49:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L25
  movsd  D20(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  negl   -0x1c(%rbp)
L25:
  movsd  D20(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L42
L32:
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
L42:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L32
  movsd  -0x8(%rbp),%xmm0
L13:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_guessed: f64

tool: D20: 1

assistant: ```c
double power(double base, int i) {
  double x;
  if (i == 0)
    return (1.0);
  else if (i < 0) {
    base = 1.0 / base;
    i = -i;
  }
  x = 1.0;
  while (i > 0) {
    x *= base;
    i--;
  }
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L20
  js     L21
L32:
  movsd  D0(%rip),%xmm0
L30:
  mulsd  %xmm1,%xmm0
  sub    $0x1,%edi
  test   %edi,%edi
  jg     L30
  ret
L21:
  movsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  neg    %edi
  jmp    L32
L20:
  movsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
double power(double base, int i) {
  double x;
  if (i == 0)
    return (1.0);
  else if (i < 0) {
    base = 1.0 / base;
    i = -i;
  }
  x = 1.0;
  while (i > 0) {
    x *= base;
    i--;
  }
  return (x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L0
  js     L11
L12:
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  nopw   0x0(%rax,%rax,1)
L34:
  mulsd  %xmm1,%xmm0
  sub    $0x1,%edi
  jne    L34
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  D6(%rip),%xmm2
  neg    %edi
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  jmp    L12
  nopl   0x0(%rax)
L0:
  movsd  D6(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: f64

tool: D6: 1

assistant: ```c
double power(double base, int i) {
  double x;
  if (i == 0)
    return (1.0);
  else if (i < 0) {
    base = 1.0 / base;
    i = -i;
  }
  x = 1.0;
  while (i > 0) {
    x *= base;
    i--;
  }
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<power>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  je     L2
  js     L23
L7:
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  nopw   0x0(%rax,%rax,1)
L0:
  mulsd  %xmm1,%xmm0
  sub    $0x1,%edi
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  movsd  D16(%rip),%xmm2
  neg    %edi
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  jmp    L7
  nopl   0x0(%rax)
L2:
  movsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_infered: f64

tool: D16: 1

assistant: ```c
double power(double base, int i) {
  double x;
  if (i == 0)
    return (1.0);
  else if (i < 0) {
    base = 1.0 / base;
    i = -i;
  }
  x = 1.0;
  while (i > 0) {
    x *= base;
    i--;
  }
  return (x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L41:
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L16:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L36
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L36:
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L16
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *bubble_sort(int *array, int size) {
  int temp, min_value = array[0], i, j;
  for (j = 1; j < size; j++) {
    for (i = 0; i < size - 1; i++) {
      if (array[i] > array[i + 1]) {
        temp = array[i];
        array[i] = array[i + 1];
        array[i + 1] = temp;
      }
    }
  }
  return array;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bubble_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  mov    $0x1,%r9d
  jmp    L59
L53:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L60
L4:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L53
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L53
L60:
  add    $0x1,%r9d
  cmp    %r9d,%esi
  je     L3
L59:
  mov    %rdi,%rax
  jmp    L4
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *bubble_sort(int *array, int size) {
  int temp, min_value = array[0], i, j;
  for (j = 1; j < size; j++) {
    for (i = 0; i < size - 1; i++) {
      if (array[i] > array[i + 1]) {
        temp = array[i];
        array[i] = array[i + 1];
        array[i + 1] = temp;
      }
    }
  }
  return array;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubble_sort>:
  endbr64
  mov    %rdi,%r10
  cmp    $0x1,%esi
  jle    L1
  lea    -0x2(%rsi),%eax
  mov    $0x1,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L28:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L38
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L38:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L28
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L16
L1:
  mov    %r10,%rax
  ret
```

assistant: ```c
int *bubble_sort(int *array, int size) {
  int temp, min_value = array[0], i, j;
  for (j = 1; j < size; j++) {
    for (i = 0; i < size - 1; i++) {
      if (array[i] > array[i + 1]) {
        temp = array[i];
        array[i] = array[i + 1];
        array[i + 1] = temp;
      }
    }
  }
  return array;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bubble_sort>:
  endbr64
  mov    %rdi,%r10
  cmp    $0x1,%esi
  jle    L21
  lea    -0x2(%rsi),%eax
  mov    $0x1,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %r10,%rdx
  nopl   0x0(%rax,%rax,1)
L23:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L19
  movq   %xmm1,(%rdx)
L19:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L23
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L11
L21:
  mov    %r10,%rax
  ret
```

assistant: ```c
int *bubble_sort(int *array, int size) {
  int temp, min_value = array[0], i, j;
  for (j = 1; j < size; j++) {
    for (i = 0; i < size - 1; i++) {
      if (array[i] > array[i + 1]) {
        temp = array[i];
        array[i] = array[i + 1];
        array[i + 1] = temp;
      }
    }
  }
  return array;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L28
L13:
  movzbl -0x3f0(%rbp),%eax
  cmp    $0xa,%al
  je     L28
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getCleanLine@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  char longest[1000];
  while ((len = getCleanLine(line, 1000)) > 0) {
    if (line[0] != '\n')
      printf("%s", line);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rbp
L4:
  mov    %rsp,%rbx
L35:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getCleanLine@plt>
  test   %eax,%eax
  jle    L27
  cmpb   $0xa,(%rsp)
  je     L35
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L4
L27:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  char longest[1000];
  while ((len = getCleanLine(line, 1000)) > 0) {
    if (line[0] != '\n')
      printf("%s", line);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L36
  nopl   0x0(%rax)
L20:
  cmpb   $0xa,(%rsp)
  jne    L46
L36:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getCleanLine@plt>
  test   %eax,%eax
  jg     L20
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L36
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  char longest[1000];
  while ((len = getCleanLine(line, 1000)) > 0) {
    if (line[0] != '\n')
      printf("%s", line);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L8
  nopl   0x0(%rax)
L15:
  cmpb   $0xa,(%rsp)
  jne    L32
L8:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getCleanLine@plt>
  test   %eax,%eax
  jg     L15
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L8
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: %s

assistant: ```c
int main() {
  int len;
  char line[1000];
  char longest[1000];
  while ((len = getCleanLine(line, 1000)) > 0) {
    if (line[0] != '\n')
      printf("%s", line);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<save_cmd_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%ecx
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <uitoa@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <save_var@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string

tool: D3: ?

assistant: ```c
void save_cmd_status(int status) {
  char str_status[4] = {0};
  save_var("?", uitoa((uint)status, 10, str_status, 4));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<save_cmd_status>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  mov    $0xa,%esi
  call   <uitoa@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <save_var@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: ?

assistant: ```c
void save_cmd_status(int status) {
  char str_status[4] = {0};
  save_var("?", uitoa((uint)status, 10, str_status, 4));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<save_cmd_status>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%esi
  mov    $0x4,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  call   <uitoa@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <save_var@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: ?

assistant: ```c
void save_cmd_status(int status) {
  char str_status[4] = {0};
  save_var("?", uitoa((uint)status, 10, str_status, 4));
}
```