user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D99(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D87(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  imul   $0x59,%eax,%ecx
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  add    %edx,%eax
  add    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x151d07eb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x61,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    $0x61,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D87
type_infered: string
name: unpack_data
arguments: data_label: D99
type_infered: string
name: unpack_data
arguments: data_label: D60
type_infered: string
name: unpack_data
arguments: data_label: D58
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D12: Program for find the RIB key - programming by Lyes Belhadj

tool: D8: 
Enter bank code: 

tool: D87: %d

tool: D99: 
Enter guichet code: 

tool: D60: 
Enter the first part of number account (it's the five number of number account): 

tool: D58: 
Enter the second part of number account (it's the six fallowing number of number account): 

tool: D10: The key of RIB is: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int bank_code = 0, guichet_code = 0, account_num1 = 0, account_num2 = 0, key_rib = 0;
  printf("Program for find the RIB key - programming by Lyes Belhadj\n");
  printf("\nEnter bank code: ");
  scanf("%d", &bank_code);
  printf("\nEnter guichet code: ");
  scanf("%d", &guichet_code);
  printf("\nEnter the first part of number account (it's the five number of number account): ");
  scanf("%d", &account_num1);
  printf("\nEnter the second part of number account (it's the six fallowing number of number account): ");
  scanf("%d", &account_num2);
  key_rib = 97 - (89 * bank_code + 15 * guichet_code + 81 * account_num1 + 3 * account_num2) % 97;
  printf("The key of RIB is: %d", key_rib);
  return 0;
}
```