ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xfffffc19,0x4(%rsp)
  lea    D13(%rip),%rbp
  lea    D31(%rip),%rbx
  lea    D26(%rip),%r13
  lea    D81(%rip),%r12
  jmp    L115
L62:
  lea    D39(%rip),%rdi
  call   <printf@plt>
L126:
  cmpl   $0x64,0x4(%rsp)
  jbe    L98
L115:
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jg     L62
  test   %eax,%eax
  js     L20
  cmp    $0x59,%eax
  jg     L128
  lea    -0x50(%rax),%edx
  cmp    $0x9,%edx
  jbe    L33
  lea    -0x46(%rax),%edx
  cmp    $0x9,%edx
  jbe    L69
  sub    $0x3c,%eax
  cmp    $0x9,%eax
  jbe    L84
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L126
L20:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L126
L128:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L126
L33:
  lea    D85(%rip),%rdi
  call   <printf@plt>
  jmp    L126
L69:
  lea    D67(%rip),%rdi
  call   <printf@plt>
  jmp    L126
L84:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L126
L98:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L130
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L130:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type: string
name: unpack_data
arguments: label: D31
type: string
name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D81
type: string
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D85
type: string
name: unpack_data
arguments: label: D67
type: string

tool: D13: Please input the numerical grade. 


tool: D31: %d

tool: D26: Letter grade is: F


tool: D81: Letter grade is: D


tool: D39: Invalid grade; Please input a valid grade.


tool: D11: Letter grade is: A


tool: D85: Letter grade is: B


tool: D67: Letter grade is: C


assistant: ```c
int main() {
  int grade = -999;
  while (grade > 100 || grade < 0) {
    printf("Please input the numerical grade. \n");
    scanf("%d", &grade);
    if (grade > 100) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade < 0) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade > 89) {
      printf("Letter grade is: A\n");
    } else if (grade > 79 && grade < 90) {
      printf("Letter grade is: B\n");
    } else if (grade > 69 && grade < 80) {
      printf("Letter grade is: C\n");
    } else if (grade > 59 && grade < 70) {
      printf("Letter grade is: D\n");
    } else if (grade < 60) {
      printf("Letter grade is: F\n");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%r15
  push   %r14
  lea    D32(%rip),%r14
  push   %r13
  lea    D42(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D52(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0xfffffc19,0x4(%rsp)
  jmp    L92
  nopl   0x0(%rax)
L58:
  cmp    $0x59,%eax
  jg     L24
  lea    -0x50(%rax),%edx
  cmp    $0x9,%edx
  jbe    L12
  lea    -0x46(%rax),%edx
  cmp    $0x9,%edx
  jbe    L38
  sub    $0x3c,%eax
  cmp    $0x9,%eax
  ja     L47
  mov    %r14,%rdi
  call   <printf@plt>
  nopl   (%rax)
L30:
  cmpl   $0x64,0x4(%rsp)
  jbe    L34
L92:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jbe    L58
  lea    D18(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x64,0x4(%rsp)
  ja     L92
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L30
  xchg   %ax,%ax
L12:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L30
L47:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L30
L38:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L124:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D32
data_type: string
name: retrieve_data
arguments: label: D42
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string
name: retrieve_data
arguments: label: D52
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D34
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D12: Letter grade is: F


tool: D32: Letter grade is: D


tool: D42: Letter grade is: B


tool: D13: Please input the numerical grade. 


tool: D52: %d

tool: D18: Invalid grade; Please input a valid grade.


tool: D34: Letter grade is: A


tool: D2: Letter grade is: C


assistant: ```c
int main() {
  int grade = -999;
  while (grade > 100 || grade < 0) {
    printf("Please input the numerical grade. \n");
    scanf("%d", &grade);
    if (grade > 100) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade < 0) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade > 89) {
      printf("Letter grade is: A\n");
    } else if (grade > 79 && grade < 90) {
      printf("Letter grade is: B\n");
    } else if (grade > 69 && grade < 80) {
      printf("Letter grade is: C\n");
    } else if (grade > 59 && grade < 70) {
      printf("Letter grade is: D\n");
    } else if (grade < 60) {
      printf("Letter grade is: F\n");
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D21(%rip),%r15
  push   %r14
  lea    D54(%rip),%r14
  push   %r13
  lea    D40(%rip),%r13
  push   %r12
  lea    D30(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D44(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0xfffffc19,0x4(%rsp)
  jmp    L19
  nopl   0x0(%rax)
L66:
  cmp    $0x59,%eax
  jg     L100
  lea    -0x50(%rax),%edx
  cmp    $0x9,%edx
  jbe    L107
  lea    -0x46(%rax),%edx
  cmp    $0x9,%edx
  jbe    L73
  sub    $0x3c,%eax
  cmp    $0x9,%eax
  ja     L46
  mov    %r14,%rdi
  call   <printf@plt>
  nopl   (%rax)
L18:
  cmpl   $0x64,0x4(%rsp)
  jbe    L67
L19:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x64,%eax
  jbe    L66
  lea    D55(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x64,0x4(%rsp)
  ja     L19
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L100:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L18
  xchg   %ax,%ax
L107:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L18
L46:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L18
L73:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D54
data_type: string
name: read_data
arguments: tag: D40
data_type: string
name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D44
data_type: string
name: read_data
arguments: tag: D55
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D21: Letter grade is: F


tool: D54: Letter grade is: D


tool: D40: Letter grade is: B


tool: D30: Please input the numerical grade. 


tool: D44: %d

tool: D55: Invalid grade; Please input a valid grade.


tool: D7: Letter grade is: A


tool: D9: Letter grade is: C


assistant: ```c
int main() {
  int grade = -999;
  while (grade > 100 || grade < 0) {
    printf("Please input the numerical grade. \n");
    scanf("%d", &grade);
    if (grade > 100) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade < 0) {
      printf("Invalid grade; Please input a valid grade.\n");
    } else if (grade > 89) {
      printf("Letter grade is: A\n");
    } else if (grade > 79 && grade < 90) {
      printf("Letter grade is: B\n");
    } else if (grade > 69 && grade < 80) {
      printf("Letter grade is: C\n");
    } else if (grade > 59 && grade < 70) {
      printf("Letter grade is: D\n");
    } else if (grade < 60) {
      printf("Letter grade is: F\n");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: hello


assistant: ```c
int foo(void *arg) {
  printf("hello\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: hello


assistant: ```c
int foo(void *arg) {
  printf("hello\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: hello


assistant: ```c
int foo(void *arg) {
  printf("hello\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: hello


assistant: ```c
int foo(void *arg) {
  printf("hello\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<plot9>:
  endbr64
  sub    $0xd8,%rsp
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movslq %esi,%rsi
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x3,0x2c(%rsp)
  movl   $0x3,0x30(%rsp)
  movl   $0x3,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x4,0x3c(%rsp)
  movl   $0x5,0x40(%rsp)
  movl   $0x6,0x44(%rsp)
  movl   $0x6,0x48(%rsp)
  movl   $0x6,0x4c(%rsp)
  movl   $0x6,0x50(%rsp)
  movl   $0x6,0x54(%rsp)
  movl   $0x6,0x58(%rsp)
  lea    0x1(%rdi),%r11d
  mov    %r11d,0x60(%rsp)
  lea    0x2(%rdi),%r10d
  mov    %r10d,0x64(%rsp)
  lea    0x3(%rdi),%r9d
  mov    %r9d,0x68(%rsp)
  lea    0x4(%rdi),%ecx
  mov    %ecx,0x6c(%rsp)
  lea    0x5(%rdi),%edx
  mov    %edx,0x70(%rsp)
  mov    %edi,0x74(%rsp)
  lea    0x6(%rdi),%eax
  mov    %eax,0x78(%rsp)
  mov    %edi,0x7c(%rsp)
  mov    %eax,0x80(%rsp)
  mov    %r11d,0x84(%rsp)
  mov    %r10d,0x88(%rsp)
  mov    %r9d,0x8c(%rsp)
  mov    %ecx,0x90(%rsp)
  mov    %edx,0x94(%rsp)
  mov    %eax,0x98(%rsp)
  mov    %eax,0x9c(%rsp)
  mov    %eax,0xa0(%rsp)
  mov    %edi,0xa4(%rsp)
  mov    %r11d,0xa8(%rsp)
  mov    %r10d,0xac(%rsp)
  mov    %r9d,0xb0(%rsp)
  mov    %ecx,0xb4(%rsp)
  mov    %edx,0xb8(%rsp)
  mov    $0x0,%edx
L12:
  movslq (%rsp,%rdx,1),%rax
  imul   %rsi,%rax
  movslq 0x60(%rsp,%rdx,1),%rcx
  add    %r8,%rax
  movb   $0x39,(%rax,%rcx,1)
  add    $0x4,%rdx
  cmp    $0x5c,%rdx
  jne    L12
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xd8,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plot9(int posicao, int colunas, char matriz[7][colunas]) {
  int cx = 0;
  int cy = 0;
  int p = posicao;
  int x[] = {0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 6, 6, 6, 6, 6};
  int y[] = {p + 1, p + 2, p + 3, p + 4, p + 5, p + 0, p + 6, p + 0, p + 6, p + 1, p + 2, p + 3, p + 4, p + 5, p + 6, p + 6, p + 6, p + 0, p + 1, p + 2, p + 3, p + 4, p + 5};
  int points = sizeof(x) / sizeof(int);
  for (cx = 0; cx < points; ++cx) {
    matriz[x[cx]][y[cx]] = '9';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<plot9>:
  endbr64
  sub    $0xd8,%rsp
  mov    %edi,%eax
  mov    %rdx,%rdi
  movslq %esi,%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0xc8(%rsp)
  xor    %edx,%edx
  lea    0x2(%rax),%r11d
  lea    0x3(%rax),%r10d
  mov    %eax,0x74(%rsp)
  lea    0x4(%rax),%r9d
  lea    0x5(%rax),%r8d
  mov    %eax,0x7c(%rsp)
  movabs $0x100000001,%rcx
  movabs $0x300000003,%rdx
  mov    %rcx,0x14(%rsp)
  movabs $0x200000002,%rcx
  mov    %rcx,0x1c(%rsp)
  movabs $0x500000004,%rcx
  mov    %rdx,0x24(%rsp)
  mov    %rdx,0x2c(%rsp)
  mov    %rdx,0x34(%rsp)
  movabs $0x600000006,%rdx
  mov    %rcx,0x3c(%rsp)
  lea    0x1(%rax),%ecx
  mov    %rdx,0x44(%rsp)
  mov    %rdx,0x4c(%rsp)
  mov    %rdx,0x54(%rsp)
  lea    0x6(%rax),%edx
  mov    %edx,0x78(%rsp)
  mov    %edx,0x80(%rsp)
  mov    %edx,0x98(%rsp)
  mov    %edx,0x9c(%rsp)
  mov    %edx,0xa0(%rsp)
  xor    %edx,%edx
  mov    %eax,0xa4(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x4(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    %r11d,0x64(%rsp)
  mov    %r10d,0x68(%rsp)
  mov    %r9d,0x6c(%rsp)
  mov    %r8d,0x70(%rsp)
  mov    %ecx,0x84(%rsp)
  mov    %r11d,0x88(%rsp)
  mov    %r10d,0x8c(%rsp)
  mov    %r9d,0x90(%rsp)
  mov    %r8d,0x94(%rsp)
  mov    %ecx,0xa8(%rsp)
  mov    %r11d,0xac(%rsp)
  mov    %r10d,0xb0(%rsp)
  mov    %r9d,0xb4(%rsp)
  mov    %r8d,0xb8(%rsp)
  jmp    L7
  nopl   0x0(%rax)
L13:
  movslq (%rsp,%rdx,1),%rax
  mov    0x60(%rsp,%rdx,1),%ecx
L7:
  imul   %rsi,%rax
  movslq %ecx,%rcx
  add    $0x4,%rdx
  add    %rdi,%rax
  movb   $0x39,(%rax,%rcx,1)
  cmp    $0x5c,%rdx
  jne    L13
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xd8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void plot9(int posicao, int colunas, char matriz[7][colunas]) {
  int cx = 0;
  int cy = 0;
  int p = posicao;
  int x[] = {0, 0, 0, 0, 0, 1, 1, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 6, 6, 6, 6, 6};
  int y[] = {p + 1, p + 2, p + 3, p + 4, p + 5, p + 0, p + 6, p + 0, p + 6, p + 1, p + 2, p + 3, p + 4, p + 5, p + 6, p + 6, p + 6, p + 0, p + 1, p + 2, p + 3, p + 4, p + 5};
  int points = sizeof(x) / sizeof(int);
  for (cx = 0; cx < points; ++cx) {
    matriz[x[cx]][y[cx]] = '9';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<command_ARGS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L5:
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    -0x4(%rbp),%eax
  jmp    L46
L25:
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L43
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
L43:
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x4(%rbp),%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int command_ARGS(char *line) {
  int i, j;
  i = 0;
  j = 0;
  while (1) {
    while (line[i] == ' ')
      i++;
    if (line[i] == '\0')
      return j;
    while ((line[i] != ' ') && (line[i] != '\0'))
      i++;
    j++;
    if (line[i] == '\0')
      return j;
  };
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<command_ARGS>:
  endbr64
  mov    $0x0,%esi
  mov    $0x0,%ecx
  jmp    L63
L18:
  add    $0x1,%ecx
  jmp    L63
L64:
  add    $0x1,%esi
  test   %dl,%dl
  je     L38
L63:
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L18
  test   %al,%al
  je     L38
  add    $0x1,%ecx
  movslq %ecx,%rax
L39:
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L39
  jmp    L64
L38:
  mov    %esi,%eax
  ret
```

assistant: ```c
int command_ARGS(char *line) {
  int i, j;
  i = 0;
  j = 0;
  while (1) {
    while (line[i] == ' ')
      i++;
    if (line[i] == '\0')
      return j;
    while ((line[i] != ' ') && (line[i] != '\0'))
      i++;
    j++;
    if (line[i] == '\0')
      return j;
  };
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<command_ARGS>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L18:
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L49
  test   %al,%al
  je     L8
  add    $0x1,%ecx
  movslq %ecx,%rax
  nopl   (%rax)
L24:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%ecx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L24
  add    $0x1,%r8d
  test   %dl,%dl
  jne    L18
L8:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%ecx
  jmp    L18
```

assistant: ```c
int command_ARGS(char *line) {
  int i, j;
  i = 0;
  j = 0;
  while (1) {
    while (line[i] == ' ')
      i++;
    if (line[i] == '\0')
      return j;
    while ((line[i] != ' ') && (line[i] != '\0'))
      i++;
    j++;
    if (line[i] == '\0')
      return j;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<command_ARGS>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L0:
  movslq %ecx,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x20,%al
  je     L49
  test   %al,%al
  je     L39
  add    $0x1,%ecx
  movslq %ecx,%rax
  nopl   (%rax)
L29:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%ecx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L29
  add    $0x1,%r8d
  test   %dl,%dl
  jne    L0
L39:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%ecx
  jmp    L0
```

assistant: ```c
int command_ARGS(char *line) {
  int i, j;
  i = 0;
  j = 0;
  while (1) {
    while (line[i] == ' ')
      i++;
    if (line[i] == '\0')
      return j;
    while ((line[i] != ' ') && (line[i] != '\0'))
      i++;
    j++;
    if (line[i] == '\0')
      return j;
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sub_lo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double sub_lo(double x, double y) {
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  return (x - y);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sub_lo>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <mpfr_set_default_rounding_mode@plt>
  movq   %rbx,%xmm0
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double sub_lo(double x, double y) {
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  return (x - y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sub_lo>:
  endbr64
  sub    $0x18,%rsp
  mov    D5(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mov    (%rax),%edi
  movsd  %xmm1,(%rsp)
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double sub_lo(double x, double y) {
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  return (x - y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sub_lo>:
  endbr64
  sub    $0x18,%rsp
  mov    D2(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  mov    (%rax),%edi
  movsd  %xmm1,(%rsp)
  call   <mpfr_set_default_rounding_mode@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double sub_lo(double x, double y) {
  mpfr_set_default_rounding_mode(GMP_RNDD);
  ;
  return (x - y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ReportUsage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D112(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D109(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <PrintStdOpts@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D112
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D53
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D35
type_infered: string
name: parse_data
arguments: data_tag: D109
type_infered: string
name: parse_data
arguments: data_tag: D51
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D78
type_infered: string
name: parse_data
arguments: data_tag: D58
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D7: 
USAGE: LGCopy [options] map <[mult] file ....>



tool: D112:  Option                                       Default



tool: D11:  -a n    allow up to 'n' new classes          100


tool: D53:  -b n    set ngram buffer size to 'n'         2000000


tool: D20:  -d s    database directory 's'               current


tool: D35:  -i n    set output gram file start index     0


tool: D109:  -m fn   save new word map to 'fn'            off


tool: D51:  -n n    create n-grams of size 'n'           max


tool: D27:  -o      output class mappings only           off


tool: D44:  -r s    set root data base file name 's'     data


tool: D78:  -w fn   load class map from 'fn'             none


tool: 

tool: D28: 



assistant: ```c
void ReportUsage(void) {
  printf("\nUSAGE: LGCopy [options] map <[mult] file ....>\n\n");
  printf(" Option                                       Default\n\n");
  printf(" -a n    allow up to 'n' new classes          100\n");
  printf(" -b n    set ngram buffer size to 'n'         2000000\n");
  printf(" -d s    database directory 's'               current\n");
  printf(" -i n    set output gram file start index     0\n");
  printf(" -m fn   save new word map to 'fn'            off\n");
  printf(" -n n    create n-grams of size 'n'           max\n");
  printf(" -o      output class mappings only           off\n");
  printf(" -r s    set root data base file name 's'     data\n");
  printf(" -w fn   load class map from 'fn'             none\n");
  PrintStdOpts("");
  printf("\n\n");
}
```