ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mystrnchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L36
L12:
  addq   $0x1,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L26
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L12
L26:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L1
  mov    -0x10(%rbp),%rax
  jmp    L44
L1:
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
char *mystrnchr(const char *in, int ch, size_t end) {
  const char *e = in + end;
  const char *p = in;
  while (p != e && *p != ch)
    p++;
  if (p != e)
    return (char *)p;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mystrnchr>:
  endbr64
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  je     L12
L6:
  movsbl (%rdi),%eax
  cmp    %esi,%eax
  je     L19
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  jne    L6
  mov    $0x0,%eax
  ret
L12:
  mov    $0x0,%eax
  ret
L19:
  cmp    %rdi,%rdx
  mov    $0x0,%eax
  cmovne %rdi,%rax
  ret
```

assistant: ```c
char *mystrnchr(const char *in, int ch, size_t end) {
  const char *e = in + end;
  const char *p = in;
  while (p != e && *p != ch)
    p++;
  if (p != e)
    return (char *)p;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mystrnchr>:
  endbr64
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jne    L12
  jmp    L9
  xchg   %ax,%ax
L17:
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  je     L9
L12:
  movsbl (%rdi),%eax
  cmp    %esi,%eax
  jne    L17
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *mystrnchr(const char *in, int ch, size_t end) {
  const char *e = in + end;
  const char *p = in;
  while (p != e && *p != ch)
    p++;
  if (p != e)
    return (char *)p;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mystrnchr>:
  endbr64
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jne    L33
  jmp    L36
  xchg   %ax,%ax
L35:
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  je     L36
L33:
  movsbl (%rdi),%eax
  cmp    %esi,%eax
  jne    L35
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *mystrnchr(const char *in, int ch, size_t end) {
  const char *e = in + end;
  const char *p = in;
  while (p != e && *p != ch)
    p++;
  if (p != e)
    return (char *)p;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  call   <test_write@plt>
L6:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L14
  mov    $0x0,%eax
  call   <test_read@plt>
L14:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D17: %s


tool: D18: write

tool: D14: read

assistant: ```c
int main(int argc, char *argv[]) {
  char *s = strrchr(argv[0], '/');
  s += 1;
  printf("%s\n", s);
  if (!strcmp(s, "write"))
    test_write();
  if (!strcmp(s, "read"))
    test_read();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rax
  mov    $0x2f,%esi
  mov    (%rax),%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rbx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L0
L6:
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L39
L26:
  mov    $0x0,%eax
  pop    %rbx
  ret
L0:
  call   <test_write@plt>
  jmp    L6
L39:
  call   <test_read@plt>
  jmp    L26
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D11: %s


tool: D28: write

tool: D8: read

assistant: ```c
int main(int argc, char *argv[]) {
  char *s = strrchr(argv[0], '/');
  s += 1;
  printf("%s\n", s);
  if (!strcmp(s, "write"))
    test_write();
  if (!strcmp(s, "read"))
    test_read();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%r8
  mov    $0x2f,%esi
  mov    (%r8),%rdi
  call   <strrchr@plt>
  lea    D1(%rip),%rdi
  lea    0x1(%rax),%rbp
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
L37:
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L27
L21:
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <test_write@plt>
  jmp    L37
L27:
  call   <test_read@plt>
  jmp    L21
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string

tool: D1: %s


tool: D6: write

tool: D15: read

assistant: ```c
int main(int argc, char *argv[]) {
  char *s = strrchr(argv[0], '/');
  s += 1;
  printf("%s\n", s);
  if (!strcmp(s, "write"))
    test_write();
  if (!strcmp(s, "read"))
    test_read();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%r8
  mov    $0x2f,%esi
  mov    (%r8),%rdi
  call   <strrchr@plt>
  lea    D22(%rip),%rdi
  lea    0x1(%rax),%rbp
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L4
L1:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L9
L23:
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <test_write@plt>
  jmp    L1
L9:
  call   <test_read@plt>
  jmp    L23
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D22: %s


tool: D23: write

tool: D14: read

assistant: ```c
int main(int argc, char *argv[]) {
  char *s = strrchr(argv[0], '/');
  s += 1;
  printf("%s\n", s);
  if (!strcmp(s, "write"))
    test_write();
  if (!strcmp(s, "read"))
    test_read();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<optarg_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <safe_atoi@plt>
  test   %rax,%rax
  je     L14
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <invalid_argument@plt>
L14:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int optarg_atoi(int opt_index) {
  int out;
  assert(optarg != NULL);
  if (safe_atoi(optarg, &out))
    invalid_argument(opt_index);
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<optarg_atoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rbp
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x4(%rsp),%rsi
  mov    0x0(%rbp),%rdi
  call   <safe_atoi@plt>
  test   %rax,%rax
  jne    L10
L4:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %ebx,%edi
  call   <invalid_argument@plt>
  jmp    L4
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int optarg_atoi(int opt_index) {
  int out;
  assert(optarg != NULL);
  if (safe_atoi(optarg, &out))
    invalid_argument(opt_index);
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<optarg_atoi>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    D4(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rsi
  call   <safe_atoi@plt>
  test   %rax,%rax
  jne    L12
L8:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L12:
  mov    %ebp,%edi
  call   <invalid_argument@plt>
  jmp    L8
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int optarg_atoi(int opt_index) {
  int out;
  assert(optarg != NULL);
  if (safe_atoi(optarg, &out))
    invalid_argument(opt_index);
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<optarg_atoi>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    D4(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rsi
  call   <safe_atoi@plt>
  test   %rax,%rax
  jne    L6
L18:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L6:
  mov    %ebp,%edi
  call   <invalid_argument@plt>
  jmp    L18
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int optarg_atoi(int opt_index) {
  int out;
  assert(optarg != NULL);
  if (safe_atoi(optarg, &out))
    invalid_argument(opt_index);
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<MakeQ_From_S_stdfreq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x24(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L1:
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L36:
  mov    -0x8(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L36
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <DoDiagonalOfQ@plt>
  nop
  leave
  ret
```

assistant: ```c
void MakeQ_From_S_stdfreq(double *mat, const double *pi, const int n) {
  int i, j;
  assert(NULL != mat);
  assert(NULL != pi);
  assert(n > 0);
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      mat[i * n + j] *= pi[j];
  DoDiagonalOfQ(mat, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MakeQ_From_S_stdfreq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebp,%ebp
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L4
  movslq %ebp,%rdi
  shl    $0x3,%rdi
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %ebp,%ecx
L24:
  mov    $0x0,%eax
L17:
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L17
  add    $0x1,%esi
  add    %rdi,%rdx
  cmp    %esi,%ebp
  jne    L24
L4:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <DoDiagonalOfQ@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MakeQ_From_S_stdfreq(double *mat, const double *pi, const int n) {
  int i, j;
  assert(NULL != mat);
  assert(NULL != pi);
  assert(n > 0);
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      mat[i * n + j] *= pi[j];
  DoDiagonalOfQ(mat, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MakeQ_From_S_stdfreq>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %edx,%ebp
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebp,%ebp
  setg   %dil
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L17
  movslq %ebp,%rsi
  mov    %r12,%rcx
  xor    %edi,%edi
  lea    0x0(,%rsi,8),%rdx
  nop
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L11
  add    $0x1,%edi
  add    %rdx,%rcx
  cmp    %edi,%ebp
  jne    L2
L17:
  pop    %rbx
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <DoDiagonalOfQ@plt>
```

assistant: ```c
void MakeQ_From_S_stdfreq(double *mat, const double *pi, const int n) {
  int i, j;
  assert(NULL != mat);
  assert(NULL != pi);
  assert(n > 0);
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      mat[i * n + j] *= pi[j];
  DoDiagonalOfQ(mat, n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MakeQ_From_S_stdfreq>:
  endbr64
  push   %r14
  test   %rdi,%rdi
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12d,%r12d
  setg   %dil
  call   <assert@plt>
  test   %r12d,%r12d
  jle    L13
  mov    %r12d,%eax
  mov    %r12d,%edi
  movslq %r12d,%r11
  mov    %rbp,%rdx
  shr    %eax
  and    $0xfffffffe,%edi
  shl    $0x3,%r11
  xor    %ecx,%ecx
  lea    -0x1(%rax),%esi
  mov    %edi,%eax
  xor    %r9d,%r9d
  mov    %r12d,%r10d
  add    $0x1,%rsi
  lea    (%rbx,%rax,8),%r8
  lea    0x8(%rbx),%r13
  shl    $0x4,%rsi
  lea    -0x1(%r12),%r14d
  nopl   0x0(%rax)
L61:
  cmp    %rdx,%r13
  je     L21
  xor    %eax,%eax
  cmp    $0x1,%r14d
  jbe    L21
  nopl   (%rax)
L23:
  movupd (%rdx,%rax,1),%xmm0
  movupd (%rbx,%rax,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L23
  cmp    %edi,%r12d
  je     L9
  lea    (%rcx,%rdi,1),%eax
  cltq
  lea    0x0(%rbp,%rax,8),%rax
  movsd  (%rax),%xmm0
  mulsd  (%r8),%xmm0
  movsd  %xmm0,(%rax)
L9:
  add    $0x1,%r9d
  add    %r11,%rdx
  add    %r12d,%ecx
  cmp    %r9d,%r12d
  jne    L61
L13:
  pop    %rbx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <DoDiagonalOfQ@plt>
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r10
  jne    L27
  jmp    L9
```

assistant: ```c
void MakeQ_From_S_stdfreq(double *mat, const double *pi, const int n) {
  int i, j;
  assert(NULL != mat);
  assert(NULL != pi);
  assert(n > 0);
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      mat[i * n + j] *= pi[j];
  DoDiagonalOfQ(mat, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sortColors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L76
L94:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L31
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L79
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L25
  addl   $0x1,-0x10(%rbp)
  jmp    L79
L25:
  addl   $0x1,-0xc(%rbp)
L79:
  addl   $0x1,-0x4(%rbp)
L76:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L94
  jmp    L6
L93:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L6:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jg     L93
  jmp    L64
L73:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
L64:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L73
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int white = 0, blue = 0;
  int j = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] == 0) {
      nums[j++] = 0;
    } else if (nums[i] == 1) {
      white++;
    } else {
      blue++;
    }
  }
  while (white-- > 0) {
    nums[j++] = 1;
  }
  while (blue-- > 0) {
    nums[j++] = 2;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sortColors>:
  endbr64
  test   %esi,%esi
  jle    L67
  mov    %rdi,%rax
  lea    0x4(%rdi),%r10
  lea    -0x1(%rsi),%edx
  lea    (%r10,%rdx,4),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  jmp    L56
L72:
  cmp    $0x1,%edx
  je     L66
  add    $0x1,%r8d
L63:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L103
L56:
  mov    (%rax),%edx
  test   %edx,%edx
  jne    L72
  movslq %ecx,%rdx
  movl   $0x0,(%rdi,%rdx,4)
  lea    0x1(%rcx),%ecx
  jmp    L63
L66:
  add    $0x1,%r9d
  jmp    L63
L103:
  lea    -0x1(%r9),%r11d
  test   %r9d,%r9d
  jle    L48
  movslq %ecx,%rsi
  lea    (%rdi,%rsi,4),%rax
  lea    -0x1(%r9),%edx
  add    %rsi,%rdx
  lea    (%r10,%rdx,4),%rdx
L39:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L39
  lea    0x1(%rcx,%r11,1),%ecx
L48:
  test   %r8d,%r8d
  jle    L67
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  lea    -0x1(%r8),%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
L102:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L102
L67:
  ret
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int white = 0, blue = 0;
  int j = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] == 0) {
      nums[j++] = 0;
    } else if (nums[i] == 1) {
      white++;
    } else {
      blue++;
    }
  }
  while (white-- > 0) {
    nums[j++] = 1;
  }
  while (blue-- > 0) {
    nums[j++] = 2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sortColors>:
  endbr64
  test   %esi,%esi
  jle    L45
  lea    0x4(%rdi),%r10
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  xor    %ecx,%ecx
  lea    (%r10,%rdx,4),%rsi
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L67
  nopl   0x0(%rax)
L54:
  movslq %ecx,%rdx
  add    $0x1,%ecx
  movl   $0x0,(%rdi,%rdx,4)
L7:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L100
L67:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L54
  cmp    $0x1,%edx
  je     L25
  add    $0x4,%rax
  add    $0x1,%r8d
  cmp    %rsi,%rax
  jne    L67
L100:
  lea    -0x1(%r9),%esi
  test   %r9d,%r9d
  je     L107
  movslq %ecx,%r9
  mov    %esi,%edx
  add    %r9,%rdx
  lea    (%rdi,%r9,4),%rax
  lea    (%r10,%rdx,4),%rdx
  nop
L102:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L102
  lea    0x1(%rcx,%rsi,1),%ecx
L107:
  test   %r8d,%r8d
  je     L45
  movslq %ecx,%rcx
  lea    -0x1(%r8),%edx
  add    %rcx,%rdx
  lea    (%rdi,%rcx,4),%rax
  lea    (%r10,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L90:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L90
L45:
  ret
L25:
  add    $0x1,%r9d
  jmp    L7
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int white = 0, blue = 0;
  int j = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] == 0) {
      nums[j++] = 0;
    } else if (nums[i] == 1) {
      white++;
    } else {
      blue++;
    }
  }
  while (white-- > 0) {
    nums[j++] = 1;
  }
  while (blue-- > 0) {
    nums[j++] = 2;
  }
}
```