ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<GLeapYear>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  add    $0x51eb850,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  jbe    L0
  and    $0x3,%edi
  sete   %al
  movzbl %al,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int GLeapYear(int year) {
  int T = 0;
  if (year % 4 == 0)
    T = 1;
  if (year % 100 == 0) {
    T = 0;
    if (year % 400 == 0)
      T = 1;
  }
  return (T);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GLeapYear>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  add    $0x51eb850,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  jbe    L2
  and    $0x3,%edi
  sete   %al
  movzbl %al,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int GLeapYear(int year) {
  int T = 0;
  if (year % 4 == 0)
    T = 1;
  if (year % 100 == 0) {
    T = 0;
    if (year % 400 == 0)
      T = 1;
  }
  return (T);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<curs_hilite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    $0x0,%eax
  call   <standout@plt>
  jmp    L12
L9:
  mov    $0x0,%eax
  call   <standend@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
int curs_hilite(int mode) {
  if (mode)
    standout();
  else
    standend();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<curs_hilite>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L2
  mov    $0x0,%eax
  call   <standout@plt>
L4:
  add    $0x8,%rsp
  ret
L2:
  mov    $0x0,%eax
  call   <standend@plt>
  jmp    L4
```

assistant: ```c
int curs_hilite(int mode) {
  if (mode)
    standout();
  else
    standend();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<curs_hilite>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  jmp    1060 <standout@plt>
  nop
L4:
  jmp    1070 <standend@plt>
```

assistant: ```c
int curs_hilite(int mode) {
  if (mode)
    standout();
  else
    standend();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<curs_hilite>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L8
  jmp    1060 <standout@plt>
  nop
L8:
  jmp    1070 <standend@plt>
```

assistant: ```c
int curs_hilite(int mode) {
  if (mode)
    standout();
  else
    standend();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readword_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x6(%rbp)
  jmp    L35
L11:
  nop
L14:
  mov    $0x0,%eax
  call   <blocking_read@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x20,-0x5(%rbp)
  je     L14
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <parse_ascii_hex@plt>
  movsbl %al,%edx
  movsbl -0x6(%rbp),%eax
  shl    $0x3,%eax
  add    $0x4,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  nop
L17:
  mov    $0x0,%eax
  call   <blocking_read@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x20,-0x5(%rbp)
  je     L17
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <parse_ascii_hex@plt>
  movsbl %al,%edx
  movsbl -0x6(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  movzbl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6(%rbp)
L35:
  cmpb   $0x3,-0x6(%rbp)
  jle    L11
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <wload_calc_checksum@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int readword_be() {
  char buf, i;
  int valbuf = 0;
  for (i = 0; i < 4; i++) {
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8 + 4));
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8));
  }
  wload_calc_checksum(valbuf);
  return valbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readword_be>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L13:
  mov    $0x0,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L13
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  mov    %ebp,%r13d
  movsbl %al,%ebx
  lea    0x4(%rbp),%ecx
  shl    %cl,%ebx
L29:
  mov    $0x0,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L29
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  movsbl %al,%eax
  mov    %r13d,%ecx
  shl    %cl,%eax
  or     %ebx,%eax
  or     %eax,%r12d
  add    $0x8,%ebp
  cmp    $0x20,%ebp
  jne    L13
  mov    %r12d,%edi
  call   <wload_calc_checksum@plt>
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int readword_be() {
  char buf, i;
  int valbuf = 0;
  for (i = 0; i < 4; i++) {
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8 + 4));
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8));
  }
  wload_calc_checksum(valbuf);
  return valbuf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readword_be>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L12:
  xor    %eax,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L12
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  lea    0x4(%rbx),%ecx
  movsbl %al,%ebp
  shl    %cl,%ebp
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L11
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  mov    %ebx,%ecx
  add    $0x8,%ebx
  movsbl %al,%eax
  shl    %cl,%eax
  or     %ebp,%eax
  or     %eax,%r12d
  cmp    $0x20,%ebx
  jne    L12
  mov    %r12d,%edi
  call   <wload_calc_checksum@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readword_be() {
  char buf, i;
  int valbuf = 0;
  for (i = 0; i < 4; i++) {
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8 + 4));
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8));
  }
  wload_calc_checksum(valbuf);
  return valbuf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readword_be>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L22:
  xor    %eax,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L22
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  lea    0x4(%rbx),%ecx
  movsbl %al,%ebp
  shl    %cl,%ebp
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <blocking_read@plt>
  cmp    $0x20,%al
  je     L12
  movsbl %al,%edi
  call   <parse_ascii_hex@plt>
  mov    %ebx,%ecx
  add    $0x8,%ebx
  movsbl %al,%eax
  shl    %cl,%eax
  or     %ebp,%eax
  or     %eax,%r12d
  cmp    $0x20,%ebx
  jne    L22
  mov    %r12d,%edi
  call   <wload_calc_checksum@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readword_be() {
  char buf, i;
  int valbuf = 0;
  for (i = 0; i < 4; i++) {
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8 + 4));
    while ((buf = blocking_read()) == ' ')
      ;
    valbuf |= (parse_ascii_hex(buf) << (i * 8));
  }
  wload_calc_checksum(valbuf);
  return valbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculateLessThan1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L1
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <getValue@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x8(%rbp),%xmm0
  movzbl -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double calculateLessThan1(const char *numb, unsigned char base) {
  const char *end;
  double result;
  for (end = numb + strlen(numb) - 1, result = 0.0; end >= numb; end--)
    result = (result + getValue(*end)) / base;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculateLessThan1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L4
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movzbl %r12b,%r12d
L12:
  movsbl (%rbx),%edi
  call   <getValue@plt>
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L12
L7:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L7
```

assistant: ```c
double calculateLessThan1(const char *numb, unsigned char base) {
  const char *end;
  double result;
  for (end = numb + strlen(numb) - 1, result = 0.0; end >= numb; end--)
    result = (result + getValue(*end)) / base;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculateLessThan1>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L8
  movzbl %r12b,%esi
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm3
  movsd  %xmm3,0x8(%rsp)
  nopl   0x0(%rax)
L3:
  movsbl (%rbx),%edi
  movsd  %xmm1,(%rsp)
  sub    $0x1,%rbx
  call   <getValue@plt>
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm1
  divsd  0x8(%rsp),%xmm1
  cmp    %rbx,%rbp
  jbe    L3
  add    $0x10,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x10,%rsp
  pxor   %xmm1,%xmm1
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double calculateLessThan1(const char *numb, unsigned char base) {
  const char *end;
  double result;
  for (end = numb + strlen(numb) - 1, result = 0.0; end >= numb; end--)
    result = (result + getValue(*end)) / base;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculateLessThan1>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L10
  movzbl %r12b,%esi
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm3
  movsd  %xmm3,0x8(%rsp)
  nopl   0x0(%rax)
L18:
  movsbl (%rbx),%edi
  movsd  %xmm1,(%rsp)
  sub    $0x1,%rbx
  call   <getValue@plt>
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm1
  divsd  0x8(%rsp),%xmm1
  cmp    %rbx,%rbp
  jbe    L18
  add    $0x10,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x10,%rsp
  pxor   %xmm1,%xmm1
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double calculateLessThan1(const char *numb, unsigned char base) {
  const char *end;
  double result;
  for (end = numb + strlen(numb) - 1, result = 0.0; end >= numb; end--)
    result = (result + getValue(*end)) / base;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GO_memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L24:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L15
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L26
L15:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L24
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int GO_memcmp(void *d, void *s, size_t sz) {
  char *dp = (char *)d;
  char *sp = (char *)s;
  while (sz--) {
    if (*dp != *sp)
      return *dp - *sp;
    dp++;
    sp++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GO_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L9
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L7
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
  mov    $0x0,%eax
  ret
L7:
  movsbl %cl,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int GO_memcmp(void *d, void *s, size_t sz) {
  char *dp = (char *)d;
  char *sp = (char *)s;
  while (sz--) {
    if (*dp != *sp)
      return *dp - *sp;
    dp++;
    sp++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GO_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L1
  xor    %eax,%eax
  jmp    L39
  nopl   (%rax)
L8:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L1
L39:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L8
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int GO_memcmp(void *d, void *s, size_t sz) {
  char *dp = (char *)d;
  char *sp = (char *)s;
  while (sz--) {
    if (*dp != *sp)
      return *dp - *sp;
    dp++;
    sp++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GO_memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L0
  xor    %eax,%eax
  jmp    L8
  nopl   (%rax)
L12:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L0
L8:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L12
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int GO_memcmp(void *d, void *s, size_t sz) {
  char *dp = (char *)d;
  char *sp = (char *)s;
  while (sz--) {
    if (*dp != *sp)
      return *dp - *sp;
    dp++;
    sp++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serial_put_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L79:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L71
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <serial_write_char@plt>
  cmp    $0xffffffff,%eax
  jne    L19
  addl   $0x1,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jg     L24
  jmp    L59
L19:
  movl   $0x0,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L79
  jmp    L47
L71:
  nop
  jmp    L47
L24:
  nop
L47:
  cmpl   $0x0,-0x8(%rbp)
  jle    L2
  mov    $0x0,%eax
  call   <serial_start_tx@plt>
L2:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int serial_put_string(char *st, int n) {
  int m = 0;
  int retry = 0;
  while (*st != '\0') {
    if (m <= n) {
      if (serial_write_char(*st) == -1) {
        retry++;
        if (retry > 10)
          break;
        continue;
      } else {
        retry = 0;
        st++;
        m++;
      }
    } else
      break;
  }
  if (m > 0)
    serial_start_tx();
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<serial_put_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %esi,%esi
  js     L0
  mov    %esi,%r12d
  test   %dil,%dil
  je     L0
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L25
L90:
  add    $0x1,%rbx
  add    $0x1,%ebp
  mov    $0x0,%r13d
L16:
  movzbl (%rbx),%edi
  cmp    %ebp,%r12d
  jl     L5
  test   %dil,%dil
  je     L5
L25:
  movsbl %dil,%edi
  call   <serial_write_char@plt>
  cmp    $0xffffffff,%eax
  jne    L90
  add    $0x1,%r13d
  cmp    $0xa,%r13d
  jle    L16
L5:
  test   %ebp,%ebp
  jg     L34
L94:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0x0,%eax
  call   <serial_start_tx@plt>
  jmp    L94
L0:
  mov    $0x0,%ebp
  jmp    L94
```

assistant: ```c
int serial_put_string(char *st, int n) {
  int m = 0;
  int retry = 0;
  while (*st != '\0') {
    if (m <= n) {
      if (serial_write_char(*st) == -1) {
        retry++;
        if (retry > 10)
          break;
        continue;
      } else {
        retry = 0;
        st++;
        m++;
      }
    } else
      break;
  }
  if (m > 0)
    serial_start_tx();
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serial_put_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %esi,%esi
  js     L30
  test   %dil,%dil
  je     L30
  mov    %esi,%r13d
  xor    %ebp,%ebp
  xor    %r12d,%r12d
L66:
  call   <serial_write_char@plt>
  cmp    $0xffffffff,%eax
  je     L42
  add    $0x1,%rbx
  add    $0x1,%r12d
  xor    %ebp,%ebp
L83:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L20
  cmp    %r13d,%r12d
  jle    L66
  cs nopw 0x0(%rax,%rax,1)
L20:
  test   %r12d,%r12d
  je     L56
  xor    %eax,%eax
  call   <serial_start_tx@plt>
L56:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  je     L20
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r12d,%r12d
  jmp    L56
```

assistant: ```c
int serial_put_string(char *st, int n) {
  int m = 0;
  int retry = 0;
  while (*st != '\0') {
    if (m <= n) {
      if (serial_write_char(*st) == -1) {
        retry++;
        if (retry > 10)
          break;
        continue;
      } else {
        retry = 0;
        st++;
        m++;
      }
    } else
      break;
  }
  if (m > 0)
    serial_start_tx();
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<serial_put_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %esi,%esi
  js     L30
  test   %dil,%dil
  je     L30
  mov    %esi,%r13d
  xor    %ebp,%ebp
  xor    %r12d,%r12d
L19:
  call   <serial_write_char@plt>
  cmp    $0xffffffff,%eax
  je     L17
  add    $0x1,%rbx
  add    $0x1,%r12d
  xor    %ebp,%ebp
L62:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L29
  cmp    %r13d,%r12d
  jle    L19
  cs nopw 0x0(%rax,%rax,1)
L29:
  test   %r12d,%r12d
  je     L74
  xor    %eax,%eax
  call   <serial_start_tx@plt>
L74:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  je     L29
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r12d,%r12d
  jmp    L74
```

assistant: ```c
int serial_put_string(char *st, int n) {
  int m = 0;
  int retry = 0;
  while (*st != '\0') {
    if (m <= n) {
      if (serial_write_char(*st) == -1) {
        retry++;
        if (retry > 10)
          break;
        continue;
      } else {
        retry = 0;
        st++;
        m++;
      }
    } else
      break;
  }
  if (m > 0)
    serial_start_tx();
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<statistics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x0,-0x20(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x4,-0x4(%rbp)
  jle    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: f64
name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D28: average CPI = %.1lf


tool: D44: average register reads per instruction = %.1lf


tool: D29: 100

tool: D25: fraction of reads that read zero register = %.1lf%%


tool: D9: number of inputs produced %d instructions ahead: %d


assistant: ```c
void statistics(int *cycles, int *regread, int *zeroread, int *cnt, int *count) {
  printf("average CPI = %.1lf\n", (double)*cycles / *count);
  printf("average register reads per instruction = %.1lf\n", (double)*regread / *count);
  if (regread != 0) {
    printf("fraction of reads that read zero register = %.1lf%%\n", 100.0 * *zeroread / *regread);
  }
  int i;
  for (i = 0; i < 6 - 1; i++) {
    printf("number of inputs produced %d instructions ahead: %d\n", i + 1, cnt[i]);
  }
}
```