user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add_internal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L33
L28:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shr    %cl,%esi
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  xor    %esi,%eax
  and    $0x1,%eax
  xor    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x18(%rbp)
L33:
  cmpl   $0xf,-0x18(%rbp)
  jbe    L28
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <registerSgn@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <registerSgn@plt>
  cmp    %rax,%rbx
  jne    L22
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <registerSgn@plt>
  mov    %rax,%rbx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <registerSgn@plt>
  cmp    %rax,%rbx
  je     L8
  mov    -0x48(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L54
L8:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  shr    $0xf,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  shr    $0xf,%eax
  xor    %eax,%edx
  mov    -0x1c(%rbp),%eax
  shr    $0xf,%eax
  xor    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L54
L22:
  mov    -0x48(%rbp),%rax
  movl   $0x0,(%rax)
L54:
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x1c(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void add_internal(unsigned int *v1, unsigned int *v2, int *carry, int *zero, int *error) {
  unsigned int retenue = 0U;
  unsigned int resultat = 0U;
  unsigned int i;
  for (i = 0U; i < (8U * 2U); ++i) {
    resultat |= ((((1U << i) & *v1) ? 1U : 0U) ^ (((1U << i) & *v2) ? 1U : 0U) ^ retenue) << i;
    retenue = ((((1U << i) & *v1) ? 1U : 0U) + (((1U << i) & *v2) ? 1U : 0U) + retenue) > 1;
  }
  if (registerSgn(*v1) == registerSgn(*v2)) {
    if (registerSgn(*v1) != registerSgn(resultat))
      *error = 1U;
    else {
      unsigned int s;
      s = ((((1U << ((8U * 2U) - 1)) & *v1) ? 1U : 0U) ^ (((1U << ((8U * 2U) - 1)) & *v2) ? 1U : 0U)) != (((1U << ((8U * 2U) - 1)) & resultat) ? 1U : 0U);
      *error = (s != retenue);
    }
  } else
    *error = 0;
  *carry = (int)retenue;
  *zero = resultat == 0U;
  *v1 = resultat;
}
```