ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parseCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <countFields@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <str_split@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **parseCommand(char *command) {
  int num_of_args = countFields(command, ' ');
  char **args = malloc(sizeof(char *) * num_of_args);
  str_split(command, ' ', args);
  free(command);
  return args;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parseCommand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x20,%esi
  call   <countFields@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <str_split@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char **parseCommand(char *command) {
  int num_of_args = countFields(command, ' ');
  char **args = malloc(sizeof(char *) * num_of_args);
  str_split(command, ' ', args);
  free(command);
  return args;
}
```
user: What is the c source code of the assembly code below?

```asm
<parseCommand>:
  endbr64
  push   %r12
  mov    $0x20,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <countFields@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    $0x20,%esi
  mov    %rax,%rdx
  mov    %rax,%r12
  call   <str_split@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **parseCommand(char *command) {
  int num_of_args = countFields(command, ' ');
  char **args = malloc(sizeof(char *) * num_of_args);
  str_split(command, ' ', args);
  free(command);
  return args;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parseCommand>:
  endbr64
  push   %r12
  mov    $0x20,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <countFields@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    $0x20,%esi
  mov    %rax,%rdx
  mov    %rax,%r12
  call   <str_split@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **parseCommand(char *command) {
  int num_of_args = countFields(command, ' ');
  char **args = malloc(sizeof(char *) * num_of_args);
  str_split(command, ' ', args);
  free(command);
  return args;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L41:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  movss  -0x18(%rbp),%xmm1
  movss  D28(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L41
  movss  -0x1c(%rbp),%xmm0
  divss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  comiss D42(%rip),%xmm0
  jb     L6
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L48
L6:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L48:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: byte[4]
name: parse_data
arguments: data_tag: D42
type_infered: f32
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D34
type_infered: string

tool: D24: %d

tool: {"D28": [0x00,0x00,0x80,0x3f]}

tool: D42: 7

tool: D27: heavy


tool: D34: light


assistant: ```c
int main() {
  int a, b;
  float sum, count;
  scanf("%d", &a);
  int clone = a;
  int i = 0;
  for (; i < a; i++) {
    b = clone % 10;
    sum += b;
    a /= 10;
    count += 1;
  }
  sum = sum / count;
  if (sum >= 7.00)
    printf("heavy\n");
  else
    printf("light\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L3
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  mov    $0x0,%ecx
  movss  D48(%rip),%xmm0
L29:
  movd   %ebx,%xmm2
  addss  %xmm1,%xmm2
  movd   %xmm2,%ebx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  movss  0xc(%rsp),%xmm3
  addss  %xmm0,%xmm3
  movss  %xmm3,0xc(%rsp)
  add    $0x1,%ecx
  cmp    %ecx,%eax
  jg     L29
  mov    %eax,0x14(%rsp)
L3:
  movd   %ebx,%xmm0
  divss  0xc(%rsp),%xmm0
  comiss D35(%rip),%xmm0
  jb     L5
  lea    D20(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D39
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: byte[4]
name: read_data
arguments: data_label: D35
type_infered: f32
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D29
type_infered: string

tool: D39: %d

tool: {"D48": [0x00,0x00,0x80,0x3f]}

tool: D35: 7

tool: D20: heavy


tool: D29: light


assistant: ```c
int main() {
  int a, b;
  float sum, count;
  scanf("%d", &a);
  int clone = a;
  int i = 0;
  for (; i < a; i++) {
    b = clone % 10;
    sum += b;
    a /= 10;
    count += 1;
  }
  sum = sum / count;
  if (sum >= 7.00)
    printf("heavy\n");
  else
    printf("light\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D40(%rip),%rdi
  movss  %xmm1,0xc(%rsp)
  lea    0x14(%rsp),%rsi
  movss  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  test   %eax,%eax
  jle    L37
  movslq %eax,%rdx
  mov    %eax,%ecx
  pxor   %xmm3,%xmm3
  movss  D48(%rip),%xmm2
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  xor    %edx,%edx
  cvtsi2ss %ecx,%xmm3
  mov    $0xcccccccd,%ecx
  xchg   %ax,%ax
L5:
  mov    %eax,%eax
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm1
  add    $0x1,%edx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    %edx,%eax
  jg     L5
  mov    %eax,0x14(%rsp)
L37:
  divss  %xmm1,%xmm0
  comiss D28(%rip),%xmm0
  jb     L29
  lea    D20(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L29:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
type: string
name: extract_symbolic_data
arguments: data_tag: D48
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D28
type: f32
name: extract_symbolic_data
arguments: data_tag: D20
type: string
name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D40: %d

tool: {"D48": [0x00,0x00,0x80,0x3f]}

tool: D28: 7

tool: D20: heavy


tool: D1: light


assistant: ```c
int main() {
  int a, b;
  float sum, count;
  scanf("%d", &a);
  int clone = a;
  int i = 0;
  for (; i < a; i++) {
    b = clone % 10;
    sum += b;
    a /= 10;
    count += 1;
  }
  sum = sum / count;
  if (sum >= 7.00)
    printf("heavy\n");
  else
    printf("light\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  movss  %xmm1,0xc(%rsp)
  lea    0x14(%rsp),%rsi
  movss  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  test   %eax,%eax
  jle    L37
  movslq %eax,%rdx
  mov    %eax,%ecx
  pxor   %xmm3,%xmm3
  movss  D34(%rip),%xmm2
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  xor    %edx,%edx
  cvtsi2ss %ecx,%xmm3
  mov    $0xcccccccd,%ecx
  xchg   %ax,%ax
L9:
  mov    %eax,%eax
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm1
  add    $0x1,%edx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    %edx,%eax
  jg     L9
  mov    %eax,0x14(%rsp)
L37:
  divss  %xmm1,%xmm0
  comiss D15(%rip),%xmm0
  jb     L47
  lea    D31(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L47:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D34
type_infered: byte[4]
name: unpack_data
arguments: data_label: D15
type_infered: f32
name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string

tool: D2: %d

tool: {"D34": [0x00,0x00,0x80,0x3f]}

tool: D15: 7

tool: D31: heavy


tool: D38: light


assistant: ```c
int main() {
  int a, b;
  float sum, count;
  scanf("%d", &a);
  int clone = a;
  int i = 0;
  for (; i < a; i++) {
    b = clone % 10;
    sum += b;
    a /= 10;
    count += 1;
  }
  sum = sum / count;
  if (sum >= 7.00)
    printf("heavy\n");
  else
    printf("light\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L24
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <ParseInput@plt>
  jmp    L24
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int getInput(void) {
  char iString[255];
  if (gets(iString) != NULL) {
    return ParseInput(iString);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getInput>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L28
L24:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x118,%rsp
  ret
L28:
  mov    %rsp,%rdi
  call   <ParseInput@plt>
  jmp    L24
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput(void) {
  char iString[255];
  if (gets(iString) != NULL) {
    return ParseInput(iString);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getInput>:
  endbr64
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L1
  mov    %rbp,%rdi
  call   <ParseInput@plt>
L1:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x110,%rsp
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput(void) {
  char iString[255];
  if (gets(iString) != NULL) {
    return ParseInput(iString);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getInput>:
  endbr64
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L11
  mov    %rbp,%rdi
  call   <ParseInput@plt>
L11:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x110,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput(void) {
  char iString[255];
  if (gets(iString) != NULL) {
    return ParseInput(iString);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <nodelay@plt>
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <nonl@plt>
  mov    $0x0,%eax
  call   <raw@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int init(void) {
  initscr();
  start_color();
  nodelay(stdscr, TRUE);
  keypad(stdscr, TRUE);
  nonl();
  raw();
  noecho();
  curs_set(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    D1(%rip),%rbp
  mov    D18(%rip),%rbx
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <nodelay@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <keypad@plt>
  mov    $0x0,%eax
  call   <nonl@plt>
  mov    $0x0,%eax
  call   <raw@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int init(void) {
  initscr();
  start_color();
  nodelay(stdscr, TRUE);
  keypad(stdscr, TRUE);
  nonl();
  raw();
  noecho();
  curs_set(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <initscr@plt>
  xor    %eax,%eax
  call   <start_color@plt>
  mov    D17(%rip),%rbp
  mov    D15(%rip),%rbx
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <nodelay@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <nonl@plt>
  xor    %eax,%eax
  call   <raw@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int init(void) {
  initscr();
  start_color();
  nodelay(stdscr, TRUE);
  keypad(stdscr, TRUE);
  nonl();
  raw();
  noecho();
  curs_set(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <initscr@plt>
  xor    %eax,%eax
  call   <start_color@plt>
  mov    D15(%rip),%rbp
  mov    D3(%rip),%rbx
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <nodelay@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <keypad@plt>
  xor    %eax,%eax
  call   <nonl@plt>
  xor    %eax,%eax
  call   <raw@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %edi,%edi
  call   <curs_set@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int init(void) {
  initscr();
  start_color();
  nodelay(stdscr, TRUE);
  keypad(stdscr, TRUE);
  nonl();
  raw();
  noecho();
  curs_set(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encode_alpha_block_DXT5>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edx,%rdx
  lea    (%rsi,%rdx,1),%r10
  movzbl 0x3(%r10),%ecx
  lea    0x3(%r10),%r8
  add    $0x43,%r10
  mov    %r8,%rdx
  mov    %ecx,%esi
L43:
  movzbl (%rdx),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %eax,%ecx
  cmovg  %eax,%ecx
  add    $0x4,%rdx
  cmp    %r10,%rdx
  jne    L43
  mov    %sil,(%rdi)
  lea    0x2(%rdi),%rbp
  mov    %cl,0x1(%rdi)
  sub    %ecx,%esi
  lea    0x0(,%rcx,8),%r12d
  sub    %ecx,%r12d
  mov    %esi,%eax
  sar    %eax
  sub    %eax,%r12d
  lea    0x0(,%rsi,4),%ebx
  lea    (%rsi,%rsi,1),%r11d
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  jmp    L21
L1:
  mov    %eax,%ecx
L2:
  add    $0x4,%r8
  cmp    %r10,%r8
  je     L12
L21:
  movzbl (%r8),%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  sub    %r12d,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  sar    $0x1f,%edx
  mov    %edx,%r13d
  and    $0x4,%r13d
  and    %ebx,%edx
  sub    %edx,%eax
  mov    %r11d,%edx
  sub    %eax,%edx
  sar    $0x1f,%edx
  mov    %edx,%edi
  and    $0x2,%edi
  or     %r13d,%edi
  and    %r11d,%edx
  sub    %edx,%eax
  mov    %eax,%r13d
  mov    %esi,%eax
  sub    %r13d,%eax
  sar    $0x1f,%eax
  sub    %edi,%eax
  mov    %eax,%edx
  and    $0x7,%edx
  test   $0x6,%al
  sete   %al
  movzbl %al,%eax
  xor    %edx,%eax
  shl    %cl,%eax
  or     %eax,%r9d
  lea    0x3(%rcx),%eax
  cmp    $0x7,%eax
  jle    L1
  mov    %r9b,0x0(%rbp)
  sar    $0x8,%r9d
  sub    $0x5,%ecx
  lea    0x1(%rbp),%rbp
  jmp    L2
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void encode_alpha_block_DXT5(unsigned char *dst, const unsigned char *block, const int offset) {
  int i, v, mn, mx;
  int dist, bias, dist2, dist4, bits, mask;
  int a, idx, t;
  block += offset;
  block += 3;
  mn = mx = block[0];
  for (i = 0; i < 16; ++i) {
    v = block[4 * i];
    if (v > mx)
      mx = v;
    if (v < mn)
      mn = v;
  }
  *dst++ = mx;
  *dst++ = mn;
  dist = mx - mn;
  bias = mn * 7 - (dist >> 1);
  dist4 = dist * 4;
  dist2 = dist * 2;
  bits = 0;
  mask = 0;
  for (i = 0; i < 16; ++i) {
    a = block[4 * i] * 7 - bias;
    t = (dist4 - a) >> 31;
    idx = t & 4;
    a -= dist4 & t;
    t = (dist2 - a) >> 31;
    idx += t & 2;
    a -= dist2 & t;
    t = (dist - a) >> 31;
    idx += t & 1;
    idx = -idx & 7;
    idx ^= (2 > idx);
    mask |= idx << bits;
    if ((bits += 3) >= 8) {
      *dst++ = mask;
      mask >>= 8;
      bits -= 8;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encode_alpha_block_DXT5>:
  endbr64
  movslq %edx,%rdx
  push   %r13
  mov    %rdi,%r9
  lea    (%rsi,%rdx,1),%rcx
  push   %r12
  push   %rbp
  lea    0x3(%rcx),%rdi
  lea    0x7(%rcx),%r8
  add    $0x43,%rcx
  push   %rbx
  movzbl -0x40(%rcx),%eax
  mov    %eax,%esi
  mov    %eax,%edx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl (%r8),%eax
  add    $0x4,%r8
L9:
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %eax,%edx
  cmovg  %eax,%edx
  cmp    %r8,%rcx
  jne    L38
  mov    %sil,(%r9)
  sub    %edx,%esi
  lea    0x0(,%rdx,8),%r12d
  xor    %r10d,%r10d
  mov    %esi,%eax
  sub    %edx,%r12d
  mov    %dl,0x1(%r9)
  lea    0x2(%r9),%rbp
  sar    %eax
  lea    0x0(,%rsi,4),%ebx
  lea    (%rsi,%rsi,1),%r11d
  xor    %ecx,%ecx
  sub    %eax,%r12d
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rdi
  mov    %r10b,0x0(%rbp)
  sub    $0x5,%ecx
  sar    $0x8,%r10d
  add    $0x1,%rbp
  cmp    %rdi,%r8
  je     L16
L35:
  movzbl (%rdi),%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ebx,%edx
  sub    %r12d,%eax
  sub    %eax,%edx
  sar    $0x1f,%edx
  mov    %edx,%r13d
  and    %ebx,%edx
  sub    %edx,%eax
  mov    %r11d,%edx
  and    $0x4,%r13d
  sub    %eax,%edx
  sar    $0x1f,%edx
  mov    %edx,%r9d
  and    %r11d,%edx
  sub    %edx,%eax
  and    $0x2,%r9d
  or     %r13d,%r9d
  mov    %eax,%r13d
  mov    %esi,%eax
  sub    %r13d,%eax
  sar    $0x1f,%eax
  sub    %r9d,%eax
  mov    %eax,%edx
  and    $0x7,%edx
  test   $0x6,%al
  sete   %al
  movzbl %al,%eax
  xor    %edx,%eax
  shl    %cl,%eax
  or     %eax,%r10d
  lea    0x3(%rcx),%eax
  cmp    $0x7,%eax
  jg     L11
  add    $0x4,%rdi
  mov    %eax,%ecx
  cmp    %rdi,%r8
  jne    L35
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void encode_alpha_block_DXT5(unsigned char *dst, const unsigned char *block, const int offset) {
  int i, v, mn, mx;
  int dist, bias, dist2, dist4, bits, mask;
  int a, idx, t;
  block += offset;
  block += 3;
  mn = mx = block[0];
  for (i = 0; i < 16; ++i) {
    v = block[4 * i];
    if (v > mx)
      mx = v;
    if (v < mn)
      mn = v;
  }
  *dst++ = mx;
  *dst++ = mn;
  dist = mx - mn;
  bias = mn * 7 - (dist >> 1);
  dist4 = dist * 4;
  dist2 = dist * 2;
  bits = 0;
  mask = 0;
  for (i = 0; i < 16; ++i) {
    a = block[4 * i] * 7 - bias;
    t = (dist4 - a) >> 31;
    idx = t & 4;
    a -= dist4 & t;
    t = (dist2 - a) >> 31;
    idx += t & 2;
    a -= dist2 & t;
    t = (dist - a) >> 31;
    idx += t & 1;
    idx = -idx & 7;
    idx ^= (2 > idx);
    mask |= idx << bits;
    if ((bits += 3) >= 8) {
      *dst++ = mask;
      mask >>= 8;
      bits -= 8;
    }
  }
}
```