ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<status_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%eax
  mov    $0x46,%esi
  cmp    $0x1,%eax
  je     L1
  cmp    $0x2,%eax
  sete   %sil
  movzbl %sil,%esi
  lea    0x43(%rsi,%rsi,1),%esi
L1:
  lea    D22(%rip),%rdx
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1d,%eax
  jle    L21
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  pop    %rbx
  ret
L21:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D22:  

tool: D14: %c%48s

tool: D18: %.26s...


assistant: ```c
void status_line(const char *fname, int status) {
  switch (status) {
  case 1:
    status = 'F';
    break;
  case 2:
    status = 'E';
    break;
  default:
    status = 'C';
  }
  printf("%c%48s", status, " ");
  if (strlen(fname) >= 30)
    printf("%.26s...\n", fname);
  else
    printf("%s\n", fname);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<status_line>:
  endbr64
  mov    %esi,%eax
  push   %rbp
  mov    $0x46,%esi
  mov    %rdi,%rbp
  cmp    $0x1,%eax
  je     L16
  xor    %esi,%esi
  cmp    $0x2,%eax
  sete   %sil
  lea    0x43(%rsi,%rsi,1),%esi
L16:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  lea    D10(%rip),%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1d,%eax
  jle    L10
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <printf@plt>
  nopl   (%rax)
L10:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D10
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D9: %c%48s

tool: D10:  

tool: D7: %.26s...


assistant: ```c
void status_line(const char *fname, int status) {
  switch (status) {
  case 1:
    status = 'F';
    break;
  case 2:
    status = 'E';
    break;
  default:
    status = 'C';
  }
  printf("%c%48s", status, " ");
  if (strlen(fname) >= 30)
    printf("%.26s...\n", fname);
  else
    printf("%s\n", fname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<status_line>:
  endbr64
  mov    %esi,%eax
  push   %rbp
  mov    $0x46,%esi
  mov    %rdi,%rbp
  cmp    $0x1,%eax
  je     L12
  xor    %esi,%esi
  cmp    $0x2,%eax
  sete   %sil
  lea    0x43(%rsi,%rsi,1),%esi
L12:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  lea    D16(%rip),%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1d,%eax
  jle    L15
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <printf@plt>
  nopl   (%rax)
L15:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D22
type: string
name: disassemble_data
arguments: data_label: D16
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D22: %c%48s

tool: D16:  

tool: D27: %.26s...


assistant: ```c
void status_line(const char *fname, int status) {
  switch (status) {
  case 1:
    status = 'F';
    break;
  case 2:
    status = 'E';
    break;
  default:
    status = 'C';
  }
  printf("%c%48s", status, " ");
  if (strlen(fname) >= 30)
    printf("%.26s...\n", fname);
  else
    printf("%s\n", fname);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quickstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <getmem@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *quickstrdup(char *s) {
  char *r = getmem(strlen(s) + 1);
  return strcpy(r, s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quickstrdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <getmem@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *quickstrdup(char *s) {
  char *r = getmem(strlen(s) + 1);
  return strcpy(r, s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quickstrdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <getmem@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *quickstrdup(char *s) {
  char *r = getmem(strlen(s) + 1);
  return strcpy(r, s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quickstrdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <getmem@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *quickstrdup(char *s) {
  char *r = getmem(strlen(s) + 1);
  return strcpy(r, s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L60:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L17
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L24
L17:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L33
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L60
  jmp    L33
L68:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L68
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void merge(int *A, int size, int m) {
  int *X;
  int i, j, k;
  X = malloc(size * sizeof(int));
  memcpy(X, A, size * sizeof(int));
  i = 0;
  j = m;
  k = 0;
  while ((i < m) && (j < size)) {
    if (A[j] < X[i])
      A[k++] = A[j++];
    else
      A[k++] = X[i++];
  }
  while (i < m)
    A[k++] = X[i++];
  free(X);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<merge>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  lea    0x0(,%rsi,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L67
  cmp    %ebx,%r13d
  jle    L67
  mov    %r12,%rcx
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L57
L7:
  add    $0x1,%eax
  mov    %edx,%r9d
  mov    %edi,(%rcx)
L66:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %ebx,%eax
  jge    L70
  cmp    %r13d,%esi
  jge    L70
L57:
  movslq %esi,%rdi
  mov    (%r12,%rdi,4),%r8d
  movslq %eax,%rdi
  mov    0x0(%rbp,%rdi,4),%edi
  cmp    %edi,%r8d
  jge    L7
  add    $0x1,%esi
  mov    %edx,%r9d
  mov    %r8d,(%rcx)
  jmp    L66
L67:
  mov    $0x0,%r9d
  mov    $0x0,%eax
L70:
  cmp    %eax,%ebx
  jle    L61
  cltq
  movslq %r9d,%r9
  sub    %rax,%r9
  lea    (%r12,%r9,4),%rcx
L68:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L68
L61:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void merge(int *A, int size, int m) {
  int *X;
  int i, j, k;
  X = malloc(size * sizeof(int));
  memcpy(X, A, size * sizeof(int));
  i = 0;
  j = m;
  k = 0;
  while ((i < m) && (j < size)) {
    if (A[j] < X[i])
      A[k++] = A[j++];
    else
      A[k++] = X[i++];
  }
  while (i < m)
    A[k++] = X[i++];
  free(X);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<merge>:
  endbr64
  push   %r14
  lea    0x0(,%rsi,4),%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r14d,%edi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L75
  cmp    %ebx,%r13d
  jle    L75
  mov    %ebx,%esi
  mov    $0x1,%edx
  xor    %eax,%eax
  jmp    L35
  nopl   (%rax)
L46:
  mov    %ecx,-0x4(%r12,%rdx,4)
  add    $0x1,%esi
  add    $0x1,%rdx
  cmp    %ebx,%eax
  jge    L29
L82:
  cmp    %r13d,%esi
  jge    L29
L35:
  movslq %esi,%rcx
  movslq %eax,%rdi
  movslq %edx,%r8
  mov    (%r12,%rcx,4),%ecx
  mov    0x0(%rbp,%rdi,4),%edi
  cmp    %edi,%ecx
  jl     L46
  mov    %edi,%ecx
  add    $0x1,%eax
  mov    %ecx,-0x4(%r12,%rdx,4)
  add    $0x1,%rdx
  cmp    %ebx,%eax
  jl     L82
L29:
  cmp    %eax,%ebx
  jle    L60
  cltq
  sub    %rax,%r8
  lea    (%r12,%r8,4),%rcx
  nopl   0x0(%rax)
L55:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L55
L60:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
  nop
L75:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
void merge(int *A, int size, int m) {
  int *X;
  int i, j, k;
  X = malloc(size * sizeof(int));
  memcpy(X, A, size * sizeof(int));
  i = 0;
  j = m;
  k = 0;
  while ((i < m) && (j < size)) {
    if (A[j] < X[i])
      A[k++] = A[j++];
    else
      A[k++] = X[i++];
  }
  while (i < m)
    A[k++] = X[i++];
  free(X);
}
```
user: What is the c source code of the assembly code below?

```asm
<merge>:
  endbr64
  push   %r14
  lea    0x0(,%rsi,4),%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L105
  cmp    %ebp,%r13d
  jle    L105
  mov    %ebp,%ecx
  mov    $0x1,%eax
  xor    %edx,%edx
  movslq %ebp,%r10
  xor    %r9d,%r9d
  nopl   (%rax)
L88:
  mov    (%rbx,%r10,4),%edi
  mov    (%r12,%r9,4),%esi
  mov    %eax,%r8d
  cmp    %edi,%esi
  jle    L159
L108:
  add    $0x1,%ecx
  mov    %edi,-0x4(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %ecx,%r13d
  jle    L94
  cmp    %edx,%ebp
  jle    L166
  movslq %ecx,%r10
  mov    (%r12,%r9,4),%esi
  mov    %eax,%r8d
  mov    (%rbx,%r10,4),%edi
  cmp    %edi,%esi
  jg     L108
L159:
  add    $0x1,%edx
  mov    %esi,-0x4(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %edx,%ebp
  jle    L166
  cmp    %ecx,%r13d
  jle    L94
  movslq %edx,%r9
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L105:
  xor    %r8d,%r8d
  xor    %edx,%edx
  nopl   (%rax)
L94:
  cmp    %edx,%ebp
  jle    L166
  movslq %r8d,%rdi
  movslq %edx,%rcx
  mov    %ebp,%r9d
  shl    $0x2,%rdi
  lea    0x1(%rcx),%rax
  sub    %edx,%r9d
  lea    (%rbx,%rdi,1),%rsi
  lea    0x0(,%rax,4),%r10
  lea    (%r12,%r10,1),%r13
  mov    %rsi,%r11
  sub    %r13,%r11
  cmp    $0x8,%r11
  jbe    L156
  lea    -0x1(%r9),%r11d
  cmp    $0x2,%r11d
  jbe    L156
  mov    %r9d,%ecx
  lea    -0x4(%r12,%r10,1),%rdi
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L77:
  movdqu (%rdi,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L77
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%edx
  add    %eax,%r8d
  cmp    %eax,%r9d
  je     L166
  movslq %edx,%rsi
  lea    0x1(%r8),%ecx
  lea    0x1(%rdx),%eax
  movslq %r8d,%r8
  mov    (%r12,%rsi,4),%esi
  mov    %esi,(%rbx,%r8,4)
  cmp    %eax,%ebp
  jle    L166
  cltq
  movslq %ecx,%rcx
  add    $0x2,%edx
  lea    0x0(,%rax,4),%rdi
  mov    (%r12,%rax,4),%eax
  lea    0x0(,%rcx,4),%rsi
  mov    %eax,(%rbx,%rcx,4)
  cmp    %edx,%ebp
  jle    L166
  mov    0x4(%r12,%rdi,1),%eax
  mov    %eax,0x4(%rbx,%rsi,1)
L166:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
  nop
L156:
  mov    %rcx,%rdx
  neg    %rdx
  lea    (%rdi,%rdx,4),%rdx
  add    %rdx,%rbx
  jmp    L124
  nop
L122:
  add    $0x1,%rax
L124:
  mov    (%r12,%rcx,4),%edx
  mov    %edx,(%rbx,%rcx,4)
  mov    %rax,%rcx
  cmp    %eax,%ebp
  jg     L122
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
```

assistant: ```c
void merge(int *A, int size, int m) {
  int *X;
  int i, j, k;
  X = malloc(size * sizeof(int));
  memcpy(X, A, size * sizeof(int));
  i = 0;
  j = m;
  k = 0;
  while ((i < m) && (j < size)) {
    if (A[j] < X[i])
      A[k++] = A[j++];
    else
      A[k++] = X[i++];
  }
  while (i < m)
    A[k++] = X[i++];
  free(X);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<loop_w_7>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L98:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L98
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
L48:
  mov    %eax,0x10(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x8000,%rax
  jne    L48
  lea    0x10(%rsp),%r11
  mov    %r11,%rbx
  mov    $0x0,%r10d
L50:
  lea    0x80(%rbx),%rcx
  mov    %rbx,%r8
  mov    $0x0,%r9d
  mov    $0x0,%edi
L14:
  mov    %r10d,%esi
  xor    %edi,%esi
  mov    %r8,%rax
  mov    $0x0,%edx
L30:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L30
  mov    %r10d,%esi
  or     %r9d,%esi
  mov    %r8,%rax
  mov    $0x0,%edx
L69:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L69
  add    $0x3,%edi
  sub    $0xffffffffffffff80,%r8
  sub    $0xffffffffffffff80,%rcx
  add    $0x5,%r9d
  cmp    $0x60,%edi
  jne    L14
  add    $0x1,%r10d
  add    $0x1000,%rbx
  cmp    $0x20,%r10d
  jne    L50
  lea    0x80(%r11),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
L7:
  mov    0x4(%rsp),%r15d
  shl    $0xa,%r15d
  mov    0x8(%rsp),%r12
  mov    $0x0,%r14d
L75:
  lea    -0x80(%r12),%rbx
  lea    (%r14,%r14,2),%edx
  mov    0x4(%rsp),%ecx
  xor    %ecx,%edx
  lea    (%r14,%r14,4),%eax
  or     %ecx,%eax
  lea    0x1(%rdx,%rax,1),%r13d
  mov    %r15d,%ebp
L65:
  cmp    %ebp,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  add    %r13d,%ebp
  cmp    %r12,%rbx
  jne    L65
  add    $0x1,%r14d
  add    $0x20,%r15d
  sub    $0xffffffffffffff80,%r12
  cmp    $0x20,%r14d
  jne    L75
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  addq   $0x1000,0x8(%rsp)
  cmp    $0x20,%eax
  jne    L7
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x20028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_w_7() {
  int i, arr[32 * 32 * 32];
  int pt[2];
  for (i = 0; i < 32 * 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(32) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (i = 0; i < 32; i++) {
#pragma acc loop worker private(pt)
      for (j = 0; j < 32; j++) {
        int k;
        pt[0] = i ^ j * 3;
#pragma acc loop vector
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[0] * k;
        pt[1] = i | j * 5;
#pragma acc loop vector
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[1] * k;
      }
    }
  }
  for (i = 0; i < 32; i++)
    for (int j = 0; j < 32; j++)
      for (int k = 0; k < 32; k++) {
        int idx = i * 1024 + j * 32 + k;
        assert(arr[idx] == idx + (i ^ j * 3) * k + (i | j * 5) * k);
      }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<loop_w_7>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L84:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L84
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
L41:
  mov    %eax,(%r15,%rax,4)
  add    $0x1,%rax
  cmp    $0x8000,%rax
  jne    L41
  mov    %r15,%r11
  xor    %r10d,%r10d
L70:
  lea    0x80(%r11),%rcx
  mov    %r11,%r8
  xor    %r9d,%r9d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r10d,%esi
  mov    %r8,%rax
  xor    %edx,%edx
  xor    %edi,%esi
  nopw   0x0(%rax,%rax,1)
L92:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L92
  mov    %r10d,%esi
  mov    %r8,%rax
  xor    %edx,%edx
  or     %r9d,%esi
  nopl   0x0(%rax,%rax,1)
L94:
  add    %edx,(%rax)
  add    $0x4,%rax
  add    %esi,%edx
  cmp    %rcx,%rax
  jne    L94
  add    $0x3,%edi
  sub    $0xffffffffffffff80,%r8
  lea    0x80(%rax),%rcx
  add    $0x5,%r9d
  cmp    $0x60,%edi
  jne    L5
  add    $0x1,%r10d
  add    $0x1000,%r11
  cmp    $0x20,%r10d
  jne    L70
  lea    0x80(%r15),%rax
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
L33:
  mov    0x4(%rsp),%r13d
  mov    0x8(%rsp),%rbx
  xor    %r12d,%r12d
  shl    $0xa,%r13d
  nopw   0x0(%rax,%rax,1)
L11:
  mov    0x4(%rsp),%esi
  lea    (%r12,%r12,2),%ecx
  lea    (%r12,%r12,4),%eax
  mov    %r13d,%r15d
  lea    -0x80(%rbx),%r14
  xor    %esi,%ecx
  or     %esi,%eax
  lea    0x1(%rcx,%rax,1),%ebp
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %edi,%edi
  cmp    %r15d,(%r14)
  sete   %dil
  add    $0x4,%r14
  add    %ebp,%r15d
  call   <assert@plt>
  cmp    %r14,%rbx
  jne    L10
  add    $0x1,%r12d
  add    $0x20,%r13d
  sub    $0xffffffffffffff80,%rbx
  cmp    $0x20,%r12d
  jne    L11
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  addq   $0x1000,0x8(%rsp)
  cmp    $0x20,%eax
  jne    L33
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x20028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void loop_w_7() {
  int i, arr[32 * 32 * 32];
  int pt[2];
  for (i = 0; i < 32 * 32 * 32; i++)
    arr[i] = i;
#pragma acc parallel copy(arr) num_gangs(32) num_workers(32) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (i = 0; i < 32; i++) {
#pragma acc loop worker private(pt)
      for (j = 0; j < 32; j++) {
        int k;
        pt[0] = i ^ j * 3;
#pragma acc loop vector
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[0] * k;
        pt[1] = i | j * 5;
#pragma acc loop vector
        for (k = 0; k < 32; k++)
          arr[i * 1024 + j * 32 + k] += pt[1] * k;
      }
    }
  }
  for (i = 0; i < 32; i++)
    for (int j = 0; j < 32; j++)
      for (int k = 0; k < 32; k++) {
        int idx = i * 1024 + j * 32 + k;
        assert(arr[idx] == idx + (i ^ j * 3) * k + (i | j * 5) * k);
      }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<signal_callback_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: Caught signal %d


assistant: ```c
void signal_callback_handler(int signum) {
  printf("Caught signal %d\n", signum);
  exit(signum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<signal_callback_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: Caught signal %d


assistant: ```c
void signal_callback_handler(int signum) {
  printf("Caught signal %d\n", signum);
  exit(signum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<signal_callback_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: Caught signal %d


assistant: ```c
void signal_callback_handler(int signum) {
  printf("Caught signal %d\n", signum);
  exit(signum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<signal_callback_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: Caught signal %d


assistant: ```c
void signal_callback_handler(int signum) {
  printf("Caught signal %d\n", signum);
  exit(signum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rect_to_polar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hypot@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
L18:
  cmpq   $0x0,-0x20(%rbp)
  je     L5
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <atan2@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L5:
  nop
  leave
  ret
```

assistant: ```c
void rect_to_polar(const int a[2], const int b[2], double *r, double *th) {
  if (r)
    *r = hypot(b[0] - a[0], b[1] - a[1]);
  if (th)
    *th = atan2(b[0] - a[0], b[1] - a[1]);
}
```