ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deinter_cpu>:
  endbr64
  test   %r8d,%r8d
  jle    L62
  push   %r14
  xor    %r11d,%r11d
  push   %r13
  mov    %r9,%r13
  xor    %r9d,%r9d
  push   %r12
  mov    %r8d,%r12d
  xor    %r8d,%r8d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  mov    %ebx,%r10d
  nopl   (%rax)
L57:
  test   %ebx,%ebx
  jle    L44
  movslq %r11d,%rax
  lea    0x0(%r13,%rax,4),%rdx
  mov    %r9d,%eax
  nop
L2:
  test   %rsi,%rsi
  je     L34
  movslq %eax,%r14
  lea    (%rsi,%r14,4),%r14
  movss  (%r14),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%r14)
L34:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %r10d,%eax
  jne    L2
  add    %ebx,%r11d
L44:
  test   %ebp,%ebp
  jle    L45
  mov    %edi,%eax
  movslq %r11d,%rdx
  sub    %ebp,%eax
  lea    0x0(%r13,%rdx,4),%rdx
  nopl   0x0(%rax)
L76:
  test   %rcx,%rcx
  je     L59
  movslq %eax,%r14
  lea    (%rcx,%r14,4),%r14
  movss  (%r14),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%r14)
L59:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %edi,%eax
  jne    L76
  add    %ebp,%r11d
L45:
  add    $0x1,%r8d
  add    %ebx,%r10d
  add    %ebx,%r9d
  add    %ebp,%edi
  cmp    %r8d,%r12d
  jne    L57
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L62:
  ret
```

assistant: ```c
void deinter_cpu(int NX, float *X, int NY, float *Y, int B, float *OUT) {
  int i, j;
  int index = 0;
  for (j = 0; j < B; ++j) {
    for (i = 0; i < NX; ++i) {
      if (X)
        X[j * NX + i] += OUT[index];
      ++index;
    }
    for (i = 0; i < NY; ++i) {
      if (Y)
        Y[j * NY + i] += OUT[index];
      ++index;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L28
L24:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L24
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x10(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D32
data_type: string
name: retrieve_data
arguments: data_tag: D30
data_type: string

tool: D14: %d

tool: D32: Sum: %d


tool: D30: Avg: %.2f


assistant: ```c
int main() {
  int n, count = 0, a, sum = 0;
  float avg;
  scanf("%d", &n);
  while (count < n) {
    scanf("%d", &a);
    sum = sum + a;
    count = count + 1;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
L13:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L13
L36:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movd   %xmm2,%ebx
  lea    D28(%rip),%rdi
  call   <printf@plt>
  movd   %ebx,%xmm0
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x0,%ebp
  jmp    L36
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D31
type_guessed: string

tool: D6: %d

tool: D28: Sum: %d


tool: D31: Avg: %.2f


assistant: ```c
int main() {
  int n, count = 0, a, sum = 0;
  float avg;
  scanf("%d", &n);
  while (count < n) {
    scanf("%d", &a);
    sum = sum + a;
    count = count + 1;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L12
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L2
L12:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D24(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D1(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string

tool: D5: %d

tool: D24: Sum: %d


tool: D1: Avg: %.2f


assistant: ```c
int main() {
  int n, count = 0, a, sum = 0;
  float avg;
  scanf("%d", &n);
  while (count < n) {
    scanf("%d", &a);
    sum = sum + a;
    count = count + 1;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0x14(%rsp),%ebp
  cmp    %ebx,%eax
  jg     L5
L7:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  lea    D23(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  cvtsi2ss %eax,%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  lea    D16(%rip),%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D16
type_infered: string

tool: D22: %d

tool: D23: Sum: %d


tool: D16: Avg: %.2f


assistant: ```c
int main() {
  int n, count = 0, a, sum = 0;
  float avg;
  scanf("%d", &n);
  while (count < n) {
    scanf("%d", &a);
    sum = sum + a;
    count = count + 1;
  }
  avg = (float)sum / n;
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", avg);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<e_dec_zpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_dec@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_dec_zpx() {
  e_zpx();
  e_dec();
  e_writeback();
}
```
user: Translate the below assembly code into C programming language:

```asm
<e_dec_zpx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_zpx@plt>
  mov    $0x0,%eax
  call   <e_dec@plt>
  mov    $0x0,%eax
  call   <e_writeback@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_dec_zpx() {
  e_zpx();
  e_dec();
  e_writeback();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<e_dec_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  call   <e_dec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e_writeback@plt>
```

assistant: ```c
void e_dec_zpx() {
  e_zpx();
  e_dec();
  e_writeback();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<e_dec_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_zpx@plt>
  xor    %eax,%eax
  call   <e_dec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e_writeback@plt>
```

assistant: ```c
void e_dec_zpx() {
  e_zpx();
  e_dec();
  e_writeback();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L8
L37:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L8
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  lea    -0x1c(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <kopiraj@plt>
L8:
  lea    -0x1c(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <ucitaj_liniju@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jg     L37
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: Najduza do sada je %s


assistant: ```c
int main() {
  char line[10];
  char longest[10];
  int max = 0, len = 0;
  while ((len = ucitaj_liniju(line, 10)) > 0) {
    if (len > max) {
      max = len;
      kopiraj(longest, line);
    }
  }
  printf("Najduza do sada je %s\n", longest);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  lea    0x4(%rsp),%rbp
L12:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <ucitaj_liniju@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L19
  cmp    %ebx,%r12d
  jge    L12
  lea    0xe(%rsp),%rdi
  mov    %rbp,%rsi
  call   <kopiraj@plt>
  mov    %ebx,%r12d
  jmp    L12
L19:
  lea    0xe(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: Najduza do sada je %s


assistant: ```c
int main() {
  char line[10];
  char longest[10];
  int max = 0, len = 0;
  while ((len = ucitaj_liniju(line, 10)) > 0) {
    if (len > max) {
      max = len;
      kopiraj(longest, line);
    }
  }
  printf("Najduza do sada je %s\n", longest);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  lea    0x4(%rsp),%rbp
  jmp    L45
  nopl   (%rax)
L49:
  cmp    %ebx,%r12d
  jl     L4
L45:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <ucitaj_liniju@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L49
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <kopiraj@plt>
  jmp    L45
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: Najduza do sada je %s


assistant: ```c
int main() {
  char line[10];
  char longest[10];
  int max = 0, len = 0;
  while ((len = ucitaj_liniju(line, 10)) > 0) {
    if (len > max) {
      max = len;
      kopiraj(longest, line);
    }
  }
  printf("Najduza do sada je %s\n", longest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  lea    0x4(%rsp),%rbp
  jmp    L30
  nopl   (%rax)
L9:
  cmp    %ebx,%r12d
  jl     L0
L30:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <ucitaj_liniju@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L9
  mov    %r13,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <kopiraj@plt>
  jmp    L30
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Najduza do sada je %s


assistant: ```c
int main() {
  char line[10];
  char longest[10];
  int max = 0, len = 0;
  while ((len = ucitaj_liniju(line, 10)) > 0) {
    if (len > max) {
      max = len;
      kopiraj(longest, line);
    }
  }
  printf("Najduza do sada je %s\n", longest);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_trunc_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %esi,-0x9c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x98(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x98(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x9c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  mov    -0x9c(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x90(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <left_trunc@plt>
  test   %rax,%rax
  je     L24
  mov    -0x9c(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <right_trunc@plt>
  test   %rax,%rax
  je     L24
  mov    $0x1,%eax
  jmp    L13
L24:
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
bool is_trunc_prime(char *s, int len) {
  char left_buf[64];
  char right_buf[64];
  memset(left_buf, '\0', 64);
  memset(right_buf, '\0', 64);
  strcpy(left_buf, &s[1]);
  strcpy(right_buf, s);
  right_buf[len - 1] = '\0';
  return left_trunc(left_buf, len - 1) && right_trunc(right_buf, len - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_trunc_prime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x40(%rsp),%r13
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  lea    0x1(%rbp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  sub    $0x1,%ebx
  movslq %ebx,%rax
  movb   $0x0,0x40(%rsp,%rax,1)
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <left_trunc@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L12
L19:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %r13,%rdi
  mov    %ebx,%esi
  call   <right_trunc@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L19
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_trunc_prime(char *s, int len) {
  char left_buf[64];
  char right_buf[64];
  memset(left_buf, '\0', 64);
  memset(right_buf, '\0', 64);
  strcpy(left_buf, &s[1]);
  strcpy(right_buf, s);
  right_buf[len - 1] = '\0';
  return left_trunc(left_buf, len - 1) && right_trunc(right_buf, len - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_trunc_prime>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  sub    $0x1,%ebp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x40(%rsp),%r14
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x1(%r12),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  movslq %ebp,%rax
  mov    %ebp,%esi
  mov    %r13,%rdi
  movb   $0x0,0x40(%rsp,%rax,1)
  call   <left_trunc@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L22
L20:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L22:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <right_trunc@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L20
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_trunc_prime(char *s, int len) {
  char left_buf[64];
  char right_buf[64];
  memset(left_buf, '\0', 64);
  memset(right_buf, '\0', 64);
  strcpy(left_buf, &s[1]);
  strcpy(right_buf, s);
  right_buf[len - 1] = '\0';
  return left_trunc(left_buf, len - 1) && right_trunc(right_buf, len - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_trunc_prime>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  sub    $0x1,%ebp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x40(%rsp),%r14
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x1(%r12),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  movslq %ebp,%rax
  mov    %ebp,%esi
  mov    %r13,%rdi
  movb   $0x0,0x40(%rsp,%rax,1)
  call   <left_trunc@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L22
L25:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x98,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L22:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <right_trunc@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L25
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_trunc_prime(char *s, int len) {
  char left_buf[64];
  char right_buf[64];
  memset(left_buf, '\0', 64);
  memset(right_buf, '\0', 64);
  strcpy(left_buf, &s[1]);
  strcpy(right_buf, s);
  right_buf[len - 1] = '\0';
  return left_trunc(left_buf, len - 1) && right_trunc(right_buf, len - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: fosread-0.4.0


assistant: ```c
void print_version(void) {
  printf("fosread-"
         "0.4.0"
         "\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_version>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: fosread-0.4.0


assistant: ```c
void print_version(void) {
  printf("fosread-"
         "0.4.0"
         "\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_version>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: fosread-0.4.0


assistant: ```c
void print_version(void) {
  printf("fosread-"
         "0.4.0"
         "\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_version>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string

tool: D7: fosread-0.4.0


assistant: ```c
void print_version(void) {
  printf("fosread-"
         "0.4.0"
         "\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<timlib_latitude_longitude_degrees_minutes_to_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
  pxor   %xmm0,%xmm0
  jmp    L59
L55:
  mov    -0x48(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <column@plt>
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <column@plt>
  movzbl -0x30(%rbp),%eax
  test   %al,%al
  jne    L2
  pxor   %xmm0,%xmm0
  jmp    L59
L2:
  movzbl -0x40(%rbp),%eax
  cmp    $0x2d,%al
  jne    L66
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rbx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  movsd  D0(%rip),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  jmp    L59
L66:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movsd  %xmm0,-0x50(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  movsd  D0(%rip),%xmm1
  movq   %rax,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  addsd  -0x50(%rbp),%xmm0
L59:
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: f64

tool: D0: 60

assistant: ```c
double timlib_latitude_longitude_degrees_minutes_to_decimal(char *latitude_longitude) {
  char degrees[16];
  char decimal[16];
  if (!*latitude_longitude)
    return 0.0;
  column(degrees, 0, latitude_longitude);
  column(decimal, 1, latitude_longitude);
  if (!*decimal)
    return 0.0;
  if (*degrees == '-') {
    return (atof(degrees) - (atof(decimal) / 60.0));
  } else {
    return (atof(degrees) + (atof(decimal) / 60.0));
  }
}
```