ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_json>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <print_str_encoded@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_str_encoded@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_str_encoded@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <print_str_encoded@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D3
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D15: {"folder": "

tool: D35: ", "path": "

tool: D3: ", "from": "

tool: D9: ", "subject": "

tool: D1: "}


assistant: ```c
void print_json(const char *folder, const char *path, const char *from, const char *subject) {
  printf("{\"folder\": \"");
  print_str_encoded(folder);
  printf("\", \"path\": \"");
  print_str_encoded(path);
  printf("\", \"from\": \"");
  print_str_encoded(from);
  printf("\", \"subject\": \"");
  print_str_encoded(subject);
  printf("\"}\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_json>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  lea    D41(%rip),%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r14,%rdi
  call   <print_str_encoded@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <print_str_encoded@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_str_encoded@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_str_encoded@plt>
  add    $0x8,%rsp
  lea    D44(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D41
type_guessed: string
name: extract_symbolic_data
arguments: label: D17
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string

tool: D41: {"folder": "

tool: D17: ", "path": "

tool: D18: ", "from": "

tool: D4: ", "subject": "

tool: D44: "}


assistant: ```c
void print_json(const char *folder, const char *path, const char *from, const char *subject) {
  printf("{\"folder\": \"");
  print_str_encoded(folder);
  printf("\", \"path\": \"");
  print_str_encoded(path);
  printf("\", \"from\": \"");
  print_str_encoded(from);
  printf("\", \"subject\": \"");
  print_str_encoded(subject);
  printf("\"}\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_json>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  lea    D28(%rip),%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r14,%rdi
  call   <print_str_encoded@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <print_str_encoded@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <print_str_encoded@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_str_encoded@plt>
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D39
type_infered: string
name: retrieve_data
arguments: data_label: D40
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D28: {"folder": "

tool: D20: ", "path": "

tool: D39: ", "from": "

tool: D40: ", "subject": "

tool: D8: "}


assistant: ```c
void print_json(const char *folder, const char *path, const char *from, const char *subject) {
  printf("{\"folder\": \"");
  print_str_encoded(folder);
  printf("\", \"path\": \"");
  print_str_encoded(path);
  printf("\", \"from\": \"");
  print_str_encoded(from);
  printf("\", \"subject\": \"");
  print_str_encoded(subject);
  printf("\"}\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,-0x12c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x12c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x12c(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  lea    -0x114(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  movss  -0x114(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: %f

assistant: ```c
float get_float(string, length)
char *string;
int length;
{
  char buffer[256];
  float val;
  strncpy(buffer, string, length);
  buffer[length] = '\0';
  sscanf(buffer, "%f", &val);
  return (val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_float>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movslq %esi,%rbx
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rdx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x10(%rsp,%rbx,1)
  lea    0xc(%rsp),%rdx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: %f

assistant: ```c
float get_float(string, length)
char *string;
int length;
{
  char buffer[256];
  float val;
  strncpy(buffer, string, length);
  buffer[length] = '\0';
  sscanf(buffer, "%f", &val);
  return (val);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_float>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  movslq %esi,%rbx
  mov    %rbx,%rdx
  mov    %r8,%rsi
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <strncpy@plt>
  lea    0xc(%rsp),%rdx
  movb   $0x0,0x10(%rsp,%rbx,1)
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sscanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x120,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: %f

assistant: ```c
float get_float(string, length)
char *string;
int length;
{
  char buffer[256];
  float val;
  strncpy(buffer, string, length);
  buffer[length] = '\0';
  sscanf(buffer, "%f", &val);
  return (val);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_float>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  movslq %esi,%rbx
  mov    %rbx,%rdx
  mov    %r8,%rsi
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <strncpy@plt>
  lea    0xc(%rsp),%rdx
  movb   $0x0,0x10(%rsp,%rbx,1)
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sscanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x120,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: %f

assistant: ```c
float get_float(string, length)
char *string;
int length;
{
  char buffer[256];
  float val;
  strncpy(buffer, string, length);
  buffer[length] = '\0';
  sscanf(buffer, "%f", &val);
  return (val);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply200>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L3
L2:
  movl   $0x0,-0x3c(%rbp)
  jmp    L23
L12:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L23:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L12
  addl   $0x1,-0x40(%rbp)
L3:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L2
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply200(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply200>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L20:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L24:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L24
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void multiply200(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply200>:
  endbr64
  test   %edi,%edi
  jle    L12
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L24
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L29
  pop    %rbx
  ret
L12:
  ret
```

assistant: ```c
void multiply200(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply200>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L37
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L52:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L92
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L92
  nopl   0x0(%rax)
L5:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L5
  cmp    -0x24(%rsp),%r11d
  je     L91
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L91
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L91
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L91:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L52
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L92:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L86:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L86
  mov    -0x18(%rsp),%r8
  jmp    L91
```

assistant: ```c
void multiply200(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  add    $0x1,%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L13
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L13:
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getval(int i, int j) {
  int amval = (i + j) * (i + j + 1) / 2;
  if ((i + j) % 2 == 0) {
    amval = amval + j + 1;
  } else {
    amval = amval + i + 1;
  }
  return amval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getval>:
  endbr64
  lea    (%rdi,%rsi,1),%ecx
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rdi,%rax,1),%edx
  test   $0x1,%cl
  jne    L1
  lea    0x1(%rsi,%rax,1),%edx
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
int getval(int i, int j) {
  int amval = (i + j) * (i + j + 1) / 2;
  if ((i + j) % 2 == 0) {
    amval = amval + j + 1;
  } else {
    amval = amval + i + 1;
  }
  return amval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getval>:
  endbr64
  lea    (%rdi,%rsi,1),%ecx
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  and    $0x1,%ecx
  lea    0x1(%rdi,%rax,1),%r8d
  jne    L2
  lea    0x1(%rsi,%rax,1),%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getval(int i, int j) {
  int amval = (i + j) * (i + j + 1) / 2;
  if ((i + j) % 2 == 0) {
    amval = amval + j + 1;
  } else {
    amval = amval + i + 1;
  }
  return amval;
}
```
user: What is the c source code of the assembly code below:

```asm
<getval>:
  endbr64
  lea    (%rdi,%rsi,1),%ecx
  lea    0x1(%rcx),%edx
  imul   %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  and    $0x1,%ecx
  lea    0x1(%rdi,%rax,1),%r8d
  jne    L0
  lea    0x1(%rsi,%rax,1),%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getval(int i, int j) {
  int amval = (i + j) * (i + j + 1) / 2;
  if ((i + j) % 2 == 0) {
    amval = amval + j + 1;
  } else {
    amval = amval + i + 1;
  }
  return amval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x676e6974736574,%rax
  mov    %rax,-0x1f(%rbp)
  movabs $0x7474747474746574,%rax
  mov    %rax,-0x17(%rbp)
  movl   $0x73747474,-0xf(%rbp)
  movw   $0x69,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x17(%rbp),%rdx
  lea    -0x1f(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <squeeze_alt@plt>
  lea    -0x1f(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: string after squeezing - '%s'


assistant: ```c
int main(void) {
  char str[8] = "testing";
  char _str[15] = "tetttttttttsi";
  squeeze_alt(str, _str);
  printf("string after squeezing - \'%s\'\n", str);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x676e6974736574,%rax
  mov    %rax,0x1(%rsp)
  movabs $0x7474747474746574,%rax
  mov    %rax,0x9(%rsp)
  movl   $0x73747474,0x11(%rsp)
  movw   $0x69,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x9(%rsp),%rsi
  lea    0x1(%rsp),%rbx
  mov    %rbx,%rdi
  call   <squeeze_alt@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: string after squeezing - '%s'


assistant: ```c
int main(void) {
  char str[8] = "testing";
  char _str[15] = "tetttttttttsi";
  squeeze_alt(str, _str);
  printf("string after squeezing - \'%s\'\n", str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x676e6974736574,%rax
  lea    0x1(%rsp),%rbp
  lea    0x9(%rsp),%rsi
  movl   $0x73747474,0x11(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0x1(%rsp)
  movabs $0x7474747474746574,%rax
  mov    %rax,0x9(%rsp)
  mov    $0x69,%eax
  mov    %ax,0x15(%rsp)
  call   <squeeze_alt@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: string after squeezing - '%s'


assistant: ```c
int main(void) {
  char str[8] = "testing";
  char _str[15] = "tetttttttttsi";
  squeeze_alt(str, _str);
  printf("string after squeezing - \'%s\'\n", str);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x676e6974736574,%rax
  lea    0x1(%rsp),%rbp
  lea    0x9(%rsp),%rsi
  movl   $0x73747474,0x11(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0x1(%rsp)
  movabs $0x7474747474746574,%rax
  mov    %rax,0x9(%rsp)
  mov    $0x69,%eax
  mov    %ax,0x15(%rsp)
  call   <squeeze_alt@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: string after squeezing - '%s'


assistant: ```c
int main(void) {
  char str[8] = "testing";
  char _str[15] = "tetttttttttsi";
  squeeze_alt(str, _str);
  printf("string after squeezing - \'%s\'\n", str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bubble_sort_N>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L44
L31:
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L42:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L9
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L9:
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L42
  subl   $0x1,-0x18(%rbp)
L44:
  cmpl   $0x0,-0x18(%rbp)
  jg     L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort_N(int *N_array, int N) {
  int *N_array_next;
  int *N_array_next_next;
  for (int i = N - 1; i > 0; i--) {
    for (int j = 0; j < i; j++) {
      N_array_next = N_array + j;
      N_array_next_next = N_array_next + 1;
      if (*N_array_next >= *N_array_next_next) {
        *N_array_next += *N_array_next_next;
        *N_array_next_next = *N_array_next - *N_array_next_next;
        *N_array_next = *N_array_next - *N_array_next_next;
      }
    }
  }
}
```