ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<systemInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <wdtInit@plt>
  mov    $0x0,%eax
  call   <cpuInit@plt>
  mov    $0x8ca0,%edi
  call   <systickInit@plt>
  mov    $0x0,%eax
  call   <gpioInit@plt>
  mov    $0x0,%eax
  call   <pmuInit@plt>
  mov    $0x0,%eax
  call   <adcInit@plt>
  mov    $0x1c200,%edi
  call   <uartInit@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  mov    $0x0,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  mov    $0x0,%eax
  call   <mcp24aaInit@plt>
  lea    D1(%rip),%rsi
  mov    %rsi,%rdx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <cmdInit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D3
type: string

tool: D1: 


tool: D3: %sType '?' for a list of available commands%s

assistant: ```c
void systemInit() {
  wdtInit();
  cpuInit();
  systickInit(((36000000) / 1000) * (1));
  gpioInit();
  pmuInit();
  adcInit();
  uartInit((115200));
  gpioSetDir((1), (5) - 1, 1);
  gpioSetDir((1), (5), 1);
  gpioSetValue((1), (5) - 1, (1));
  gpioSetValue((1), (5), (0));
  mcp24aaInit();
  printf("%sType '?' for a list of available commands%s", "\r\n", "\r\n");
  cmdInit();
}
```
user: Translate the below assembly code into C programming language:

```asm
<systemInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wdtInit@plt>
  xor    %eax,%eax
  call   <cpuInit@plt>
  mov    $0x8ca0,%edi
  call   <systickInit@plt>
  xor    %eax,%eax
  call   <gpioInit@plt>
  xor    %eax,%eax
  call   <pmuInit@plt>
  xor    %eax,%eax
  call   <adcInit@plt>
  mov    $0x1c200,%edi
  call   <uartInit@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  xor    %edx,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  xor    %eax,%eax
  call   <mcp24aaInit@plt>
  lea    D8(%rip),%rsi
  lea    D9(%rip),%rdi
  mov    %rsi,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1100 <cmdInit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D8: 


tool: D9: %sType '?' for a list of available commands%s

assistant: ```c
void systemInit() {
  wdtInit();
  cpuInit();
  systickInit(((36000000) / 1000) * (1));
  gpioInit();
  pmuInit();
  adcInit();
  uartInit((115200));
  gpioSetDir((1), (5) - 1, 1);
  gpioSetDir((1), (5), 1);
  gpioSetValue((1), (5) - 1, (1));
  gpioSetValue((1), (5), (0));
  mcp24aaInit();
  printf("%sType '?' for a list of available commands%s", "\r\n", "\r\n");
  cmdInit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<systemInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wdtInit@plt>
  xor    %eax,%eax
  call   <cpuInit@plt>
  mov    $0x8ca0,%edi
  call   <systickInit@plt>
  xor    %eax,%eax
  call   <gpioInit@plt>
  xor    %eax,%eax
  call   <pmuInit@plt>
  xor    %eax,%eax
  call   <adcInit@plt>
  mov    $0x1c200,%edi
  call   <uartInit@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetDir@plt>
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  xor    %edx,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <gpioSetValue@plt>
  xor    %eax,%eax
  call   <mcp24aaInit@plt>
  lea    D10(%rip),%rsi
  lea    D1(%rip),%rdi
  mov    %rsi,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1100 <cmdInit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D10: 


tool: D1: %sType '?' for a list of available commands%s

assistant: ```c
void systemInit() {
  wdtInit();
  cpuInit();
  systickInit(((36000000) / 1000) * (1));
  gpioInit();
  pmuInit();
  adcInit();
  uartInit((115200));
  gpioSetDir((1), (5) - 1, 1);
  gpioSetDir((1), (5), 1);
  gpioSetValue((1), (5) - 1, (1));
  gpioSetValue((1), (5), (0));
  mcp24aaInit();
  printf("%sType '?' for a list of available commands%s", "\r\n", "\r\n");
  cmdInit();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L7:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L35:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L35
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *my_strcat(int la, char *a, int lb, char *b) {
  char *s = calloc(la + lb + 1, sizeof(char));
  int i, j;
  for (i = 0; i < la; i++) {
    s[i] = a[i];
  }
  for (j = 0; j < lb; j++) {
    s[i + j] = b[j];
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    %rcx,%rbx
  lea    0x1(%rdi,%rdx,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L19
  mov    %ebp,%esi
  mov    $0x0,%edx
L4:
  movzbl 0x0(%r13,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L4
L28:
  test   %r12d,%r12d
  jle    L18
  mov    %r12d,%r12d
  mov    $0x0,%edx
  movslq %ebp,%rsi
  add    %rax,%rsi
L9:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L9
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%ebp
  jmp    L28
```

assistant: ```c
char *my_strcat(int la, char *a, int lb, char *b) {
  char *s = calloc(la + lb + 1, sizeof(char));
  int i, j;
  for (i = 0; i < la; i++) {
    s[i] = a[i];
  }
  for (j = 0; j < lb; j++) {
    s[i + j] = b[j];
  }
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcat>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    0x1(%rdi,%rdx,1),%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L37
  movslq %ebp,%rsi
  xor    %ecx,%ecx
  nop
L30:
  movzbl 0x0(%r13,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L30
L0:
  test   %ebx,%ebx
  jle    L17
  movslq %ebp,%rsi
  movslq %ebx,%rdx
  xor    %ecx,%ecx
  add    %rax,%rsi
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl (%r12,%rcx,1),%edi
  mov    %dil,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L40
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L37:
  xor    %ebp,%ebp
  jmp    L0
```

assistant: ```c
char *my_strcat(int la, char *a, int lb, char *b) {
  char *s = calloc(la + lb + 1, sizeof(char));
  int i, j;
  for (i = 0; i < la; i++) {
    s[i] = a[i];
  }
  for (j = 0; j < lb; j++) {
    s[i + j] = b[j];
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<soma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L3
  mov    $0x0,%eax
  jmp    L12
L3:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <soma>
  add    %ebx,%eax
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int soma(int n, int *v) {
  n--;
  if (n < 0)
    return 0;
  return v[n] + soma(n, v);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<soma>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  mov    %edi,%ebx
  sub    $0x1,%ebx
  js     L9
  mov    %rsi,%rbp
  mov    %ebx,%edi
  call   <soma>
  movslq %ebx,%rdi
  add    0x0(%rbp,%rdi,4),%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int soma(int n, int *v) {
  n--;
  if (n < 0)
    return 0;
  return v[n] + soma(n, v);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<soma>:
  endbr64
  sub    $0x1,%edi
  mov    $0x0,%r8d
  movslq %edi,%rax
  js     L8
  nopw   0x0(%rax,%rax,1)
L4:
  add    (%rsi,%rax,4),%r8d
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L4
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int soma(int n, int *v) {
  n--;
  if (n < 0)
    return 0;
  return v[n] + soma(n, v);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<soma>:
  endbr64
  mov    %edi,%r8d
  sub    $0x1,%r8d
  js     L70
  cmp    $0x2,%r8d
  jbe    L18
  movslq %edi,%rax
  mov    %edi,%ecx
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  lea    -0x10(%rsi,%rax,4),%rdx
  lea    -0x1(%rcx),%r9d
  lea    -0x10(%rdx),%rax
  shl    $0x4,%r9
  mov    %rax,%rcx
  sub    %r9,%rcx
  jmp    L61
L1:
  sub    $0x10,%rax
L61:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L1
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%r8d
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%edi
  je     L4
L17:
  movslq %r8d,%rdx
  mov    %r8d,%edi
  add    (%rsi,%rdx,4),%eax
  sub    $0x1,%edi
  lea    0x0(,%rdx,4),%rcx
  js     L78
  add    -0x4(%rsi,%rcx,1),%eax
  cmp    $0x1,%r8d
  je     L78
  add    -0x8(%rsi,%rcx,1),%eax
L78:
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
  nopl   0x0(%rax)
L70:
  xor    %eax,%eax
  ret
L18:
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
int soma(int n, int *v) {
  n--;
  if (n < 0)
    return 0;
  return v[n] + soma(n, v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HashStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L4:
  mov    -0x18(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rcx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  xor    %rax,-0x18(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L4
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long HashStr(char *Kwd, unsigned int KwdLen) {
  unsigned long h = 0;
  unsigned long g;
  char *KwdEnd = Kwd + KwdLen;
  while (Kwd < KwdEnd) {
    h = (h << 4) + *Kwd++;
    if ((g = (h & 0xF0000000))) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<HashStr>:
  endbr64
  mov    %esi,%esi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L48
  mov    $0x0,%eax
  movabs $0xffffffff0fffffff,%rcx
  jmp    L42
L15:
  cmp    %rdi,%rsi
  je     L38
L42:
  shl    $0x4,%rax
  add    $0x1,%rdi
  movsbq -0x1(%rdi),%rdx
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L15
  and    %rcx,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
  jmp    L15
L38:
  ret
L48:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long HashStr(char *Kwd, unsigned int KwdLen) {
  unsigned long h = 0;
  unsigned long g;
  char *KwdEnd = Kwd + KwdLen;
  while (Kwd < KwdEnd) {
    h = (h << 4) + *Kwd++;
    if ((g = (h & 0xF0000000))) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HashStr>:
  endbr64
  mov    %esi,%esi
  xor    %eax,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L11
  movabs $0xffffffff0fffffff,%rcx
  nopw   0x0(%rax,%rax,1)
L27:
  movsbq (%rdi),%rdx
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L16
  and    %rcx,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
L16:
  cmp    %rdi,%rsi
  jne    L27
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
unsigned long HashStr(char *Kwd, unsigned int KwdLen) {
  unsigned long h = 0;
  unsigned long g;
  char *KwdEnd = Kwd + KwdLen;
  while (Kwd < KwdEnd) {
    h = (h << 4) + *Kwd++;
    if ((g = (h & 0xF0000000))) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HashStr>:
  endbr64
  mov    %esi,%esi
  xor    %eax,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L16
  movabs $0xffffffff0fffffff,%rcx
  nopw   0x0(%rax,%rax,1)
L0:
  movsbq (%rdi),%rdx
  shl    $0x4,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L15
  and    %rcx,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
L15:
  cmp    %rdi,%rsi
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
unsigned long HashStr(char *Kwd, unsigned int KwdLen) {
  unsigned long h = 0;
  unsigned long g;
  char *KwdEnd = Kwd + KwdLen;
  while (Kwd < KwdEnd) {
    h = (h << 4) + *Kwd++;
    if ((g = (h & 0xF0000000))) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ln_get_pluto_phase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_earth_solar_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_pluto_solar_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_pluto_earth_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x10(%rbp),%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <acos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_rad_to_deg@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double ln_get_pluto_phase(double JD) {
  double i, r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_pluto_solar_dist(JD);
  delta = ln_get_pluto_earth_dist(JD);
  i = (r * r + delta * delta - R * R) / (2 * r * delta);
  i = acos(i);
  return ln_rad_to_deg(i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ln_get_pluto_phase>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  call   <ln_get_earth_solar_dist@plt>
  movsd  %xmm0,(%rsp)
  movq   %rbx,%xmm0
  call   <ln_get_pluto_solar_dist@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %rbx,%xmm0
  call   <ln_get_pluto_earth_dist@plt>
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm3
  movapd %xmm3,%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm1,%xmm0
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm3,%xmm1
  addsd  %xmm3,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  call   <acos@plt>
  call   <ln_rad_to_deg@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double ln_get_pluto_phase(double JD) {
  double i, r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_pluto_solar_dist(JD);
  delta = ln_get_pluto_earth_dist(JD);
  i = (r * r + delta * delta - R * R) / (2 * r * delta);
  i = acos(i);
  return ln_rad_to_deg(i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ln_get_pluto_phase>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ln_get_earth_solar_dist@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <ln_get_pluto_solar_dist@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <ln_get_pluto_earth_dist@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  call   <acos@plt>
  add    $0x28,%rsp
  jmp    10b0 <ln_rad_to_deg@plt>
```

assistant: ```c
double ln_get_pluto_phase(double JD) {
  double i, r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_pluto_solar_dist(JD);
  delta = ln_get_pluto_earth_dist(JD);
  i = (r * r + delta * delta - R * R) / (2 * r * delta);
  i = acos(i);
  return ln_rad_to_deg(i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D24
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string

tool: D17: Input your numbers please

tool: D24: %d %d

tool: D18: Here is your Ans %d.4


assistant: ```c
int main() {
  int a, b, c;
  printf("Input your numbers please\n");
  scanf("%d %d", &a, &b);
  printf("Here is your Ans %d.4\n", a / b);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D0
datatype: string

tool: D26: Input your numbers please

tool: D18: %d %d

tool: D0: Here is your Ans %d.4


assistant: ```c
int main() {
  int a, b, c;
  printf("Input your numbers please\n");
  scanf("%d %d", &a, &b);
  printf("Here is your Ans %d.4\n", a / b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    D4(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D6: Input your numbers please

tool: D21: %d %d

tool: D4: Here is your Ans %d.4


assistant: ```c
int main() {
  int a, b, c;
  printf("Input your numbers please\n");
  scanf("%d %d", &a, &b);
  printf("Here is your Ans %d.4\n", a / b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    D7(%rip),%rdi
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D21: Input your numbers please

tool: D11: %d %d

tool: D7: Here is your Ans %d.4


assistant: ```c
int main() {
  int a, b, c;
  printf("Input your numbers please\n");
  scanf("%d %d", &a, &b);
  printf("Here is your Ans %d.4\n", a / b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<japi_delete_grammar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_send@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_idlist@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: DELGRAM


assistant: ```c
void japi_delete_grammar(int sd, char *idlist) {
  do_send(sd, "DELGRAM\n");
  send_idlist(sd, idlist);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<japi_delete_grammar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    D4(%rip),%rsi
  call   <do_send@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_idlist@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: DELGRAM


assistant: ```c
void japi_delete_grammar(int sd, char *idlist) {
  do_send(sd, "DELGRAM\n");
  send_idlist(sd, idlist);
}
```