ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D27(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm3
  movss  0x10(%rsp),%xmm1
  movss  0x8(%rsp),%xmm4
  movaps %xmm3,%xmm2
  movaps %xmm0,%xmm5
  mulss  %xmm1,%xmm2
  mulss  %xmm4,%xmm5
  ucomiss %xmm5,%xmm2
  jp     L38
  jne    L38
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L38:
  subss  %xmm5,%xmm2
  subss  %xmm4,%xmm1
  mov    $0x2,%eax
  subss  %xmm3,%xmm0
  lea    D17(%rip),%rdi
  divss  %xmm2,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L6
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D9
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D27: %f%f%f%f

tool: D9: INF

tool: D17: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b1 * a2) - (a1 * b2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm3
  movss  0x10(%rsp),%xmm1
  movss  0x8(%rsp),%xmm4
  movaps %xmm3,%xmm2
  movaps %xmm0,%xmm5
  mulss  %xmm1,%xmm2
  mulss  %xmm4,%xmm5
  ucomiss %xmm5,%xmm2
  jp     L6
  jne    L6
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  subss  %xmm5,%xmm2
  subss  %xmm4,%xmm1
  mov    $0x2,%eax
  subss  %xmm3,%xmm0
  lea    D27(%rip),%rdi
  divss  %xmm2,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L29
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D23
datatype: string
name: parse_data
arguments: label: D27
datatype: string

tool: D17: %f%f%f%f

tool: D23: INF

tool: D27: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b1 * a2) - (a1 * b2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<protobuf_append_fixed_impl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  add    $0x5,%rdx
  cmp    %rdx,%rax
  setb   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L15
  mov    $0x0,%eax
  jmp    L3
L15:
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  or     -0x18(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <protobuf_write_varint@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
L3:
  leave
  ret
```

assistant: ```c
int protobuf_append_fixed_impl(const int field, const uint8_t wire_type, const void *value, int value_len, char *restrict buf, int buf_size) {
  if (__builtin_expect(!!(buf_size < sizeof(field) + 1 + value_len), 0)) {
    return 0;
  }
  char *p = protobuf_write_varint(((field << 3) | wire_type), buf);
  memcpy(p, value, value_len);
  return (p - buf) + value_len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<protobuf_append_fixed_impl>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %ecx,%ebp
  mov    %r8,%r12
  movslq %r9d,%r9
  movslq %ecx,%rax
  add    $0x5,%rax
  cmp    %rax,%r9
  setb   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  lea    0x0(,%rbx,8),%edi
  or     %r14d,%edi
  mov    %r12,%rsi
  call   <protobuf_write_varint@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  sub    %r12,%rbx
  lea    0x0(%rbp,%rbx,1),%eax
  jmp    L1
```

assistant: ```c
int protobuf_append_fixed_impl(const int field, const uint8_t wire_type, const void *value, int value_len, char *restrict buf, int buf_size) {
  if (__builtin_expect(!!(buf_size < sizeof(field) + 1 + value_len), 0)) {
    return 0;
  }
  char *p = protobuf_write_varint(((field << 3) | wire_type), buf);
  memcpy(p, value, value_len);
  return (p - buf) + value_len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<protobuf_append_fixed_impl>:
  endbr64
  movslq %ecx,%rax
  push   %r14
  movslq %r9d,%r9
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rax,%rbp
  add    $0x5,%rax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    %rax,%r9
  setb   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  lea    0x0(,%rbx,8),%edi
  mov    %r12,%rsi
  or     %r14d,%edi
  call   <protobuf_write_varint@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  sub    %r12,%rbx
  lea    0x0(%rbp,%rbx,1),%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int protobuf_append_fixed_impl(const int field, const uint8_t wire_type, const void *value, int value_len, char *restrict buf, int buf_size) {
  if (__builtin_expect(!!(buf_size < sizeof(field) + 1 + value_len), 0)) {
    return 0;
  }
  char *p = protobuf_write_varint(((field << 3) | wire_type), buf);
  memcpy(p, value, value_len);
  return (p - buf) + value_len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<protobuf_append_fixed_impl>:
  endbr64
  movslq %ecx,%rax
  push   %r14
  movslq %r9d,%r9
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rax,%rbp
  add    $0x5,%rax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    %rax,%r9
  setb   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
  lea    0x0(,%rbx,8),%edi
  mov    %r12,%rsi
  or     %r14d,%edi
  call   <protobuf_write_varint@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  sub    %r12,%rbx
  lea    0x0(%rbp,%rbx,1),%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int protobuf_append_fixed_impl(const int field, const uint8_t wire_type, const void *value, int value_len, char *restrict buf, int buf_size) {
  if (__builtin_expect(!!(buf_size < sizeof(field) + 1 + value_len), 0)) {
    return 0;
  }
  char *p = protobuf_write_varint(((field << 3) | wire_type), buf);
  memcpy(p, value, value_len);
  return (p - buf) + value_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spkOpenArchive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <spkSetArchive@plt>
  test   %rax,%rax
  je     L10
  mov    $0x1,%eax
  jmp    L2
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <spkLoadHeader@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%eax
  jmp    L2
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <spkGenLUT@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: rb

assistant: ```c
int spkOpenArchive(struct spkState *state, char *filename) {
  if (spkSetArchive(state, fopen(filename, "rb")))
    return 1;
  if (spkLoadHeader(state))
    return 1;
  return spkGenLUT(state);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spkOpenArchive>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <spkSetArchive@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L25
L17:
  pop    %rbx
  ret
L25:
  mov    %rbx,%rdi
  call   <spkLoadHeader@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L17
  mov    %rbx,%rdi
  call   <spkGenLUT@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: rb

assistant: ```c
int spkOpenArchive(struct spkState *state, char *filename) {
  if (spkSetArchive(state, fopen(filename, "rb")))
    return 1;
  if (spkLoadHeader(state))
    return 1;
  return spkGenLUT(state);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spkOpenArchive>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <spkSetArchive@plt>
  test   %rax,%rax
  je     L3
L5:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  mov    %rbp,%rdi
  call   <spkLoadHeader@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <spkGenLUT@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: rb

assistant: ```c
int spkOpenArchive(struct spkState *state, char *filename) {
  if (spkSetArchive(state, fopen(filename, "rb")))
    return 1;
  if (spkLoadHeader(state))
    return 1;
  return spkGenLUT(state);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<spkOpenArchive>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <spkSetArchive@plt>
  test   %rax,%rax
  je     L11
L0:
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L11:
  mov    %rbp,%rdi
  call   <spkLoadHeader@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <spkGenLUT@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: rb

assistant: ```c
int spkOpenArchive(struct spkState *state, char *filename) {
  if (spkSetArchive(state, fopen(filename, "rb")))
    return 1;
  if (spkLoadHeader(state))
    return 1;
  return spkGenLUT(state);
}
```
user: Translate the below assembly code into C programming language:

```asm
<padcon_get_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x35f,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L1
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int padcon_get_dobldobl_solution(int idx, int verbose) {
  int fail;
  int pars[2];
  double *c;
  pars[0] = 1;
  pars[1] = idx;
  fail = _ada_use_c2phc4c(863, pars, &verbose, c, 0);
  if (pars[0] != 0)
    fail = pars[0];
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<padcon_get_dobldobl_solution>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  mov    %edi,0x14(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x35f,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  cmovne %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_dobldobl_solution(int idx, int verbose) {
  int fail;
  int pars[2];
  double *c;
  pars[0] = 1;
  pars[1] = idx;
  fail = _ada_use_c2phc4c(863, pars, &verbose, c, 0);
  if (pars[0] != 0)
    fail = pars[0];
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<padcon_get_dobldobl_solution>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x14(%rsp)
  mov    $0x35f,%edi
  movl   $0x1,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  cmovne %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_dobldobl_solution(int idx, int verbose) {
  int fail;
  int pars[2];
  double *c;
  pars[0] = 1;
  pars[1] = idx;
  fail = _ada_use_c2phc4c(863, pars, &verbose, c, 0);
  if (pars[0] != 0)
    fail = pars[0];
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<padcon_get_dobldobl_solution>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x14(%rsp)
  mov    $0x35f,%edi
  movl   $0x1,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x10(%rsp),%edx
  test   %edx,%edx
  cmovne %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_dobldobl_solution(int idx, int verbose) {
  int fail;
  int pars[2];
  double *c;
  pars[0] = 1;
  pars[1] = idx;
  fail = _ada_use_c2phc4c(863, pars, &verbose, c, 0);
  if (pars[0] != 0)
    fail = pars[0];
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_str_to_wordtab>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  mov    %rax,%rbx
  mov    %eax,%ebp
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  movslq 0x14(%rsp),%rdi
  add    %r12,%rdi
  movzbl (%rdi),%eax
  test   %ebx,%ebx
  jle    L28
  test   %al,%al
  je     L28
  mov    $0x0,%r13d
  lea    0x14(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  jmp    L59
L89:
  movslq %r13d,%rax
  lea    (%r15,%rax,8),%r14
  call   <my_strdup@plt>
  mov    %rax,%rbx
  mov    %rax,(%r14)
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <my_count_char@plt>
  movb   $0x0,(%rbx,%rax,1)
  add    $0x1,%r13d
  sub    $0x1,%ebp
L2:
  mov    0x14(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x14(%rsp)
  cltq
  lea    (%r12,%rax,1),%rdi
  movzbl (%rdi),%eax
  test   %ebp,%ebp
  jle    L28
  test   %al,%al
  je     L28
L59:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L89
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L2
  jmp    L89
L28:
  mov    %r12,%rdi
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  movq   $0x0,(%r15,%rax,8)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    %r15,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **my_str_to_wordtab(char *str) {
  int i;
  int n;
  int word;
  char **tab;
  i = 0;
  n = 0;
  word = my_count_word(my_strdup(str));
  tab = (char **)malloc(sizeof(char *) * word);
  while (str[i] && word > 0) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z') || (str[i] >= '0' && str[i] <= '9')) {
      tab[n] = my_strdup(str + i);
      tab[n][my_count_char(str, &i)] = '\0';
      n++;
      word--;
    }
    i++;
  }
  tab[my_count_word(my_strdup(str))] = NULL;
  return (tab);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_str_to_wordtab>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  lea    0x0(,%rax,8),%edi
  mov    %rax,%rbx
  mov    %eax,%r13d
  call   <malloc@plt>
  movslq 0x14(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  add    %rbp,%rdi
  movzbl (%rdi),%eax
  test   %ebx,%ebx
  jle    L65
  xor    %r14d,%r14d
  lea    0x14(%rsp),%rbx
  test   %al,%al
  jne    L10
  jmp    L65
  xchg   %ax,%ax
L64:
  test   %r13d,%r13d
  jle    L65
L10:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L75
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L39
L75:
  mov    0x8(%rsp),%rcx
  movslq %r14d,%rax
  sub    $0x1,%r13d
  add    $0x1,%r14d
  lea    (%rcx,%rax,8),%r12
  call   <my_strdup@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  mov    %rax,%r15
  call   <my_count_char@plt>
  movb   $0x0,(%r15,%rax,1)
L39:
  mov    0x14(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x14(%rsp)
  cltq
  lea    0x0(%rbp,%rax,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L64
L65:
  mov    %rbp,%rdi
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  mov    0x8(%rsp),%rsi
  movq   $0x0,(%rsi,%rax,8)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **my_str_to_wordtab(char *str) {
  int i;
  int n;
  int word;
  char **tab;
  i = 0;
  n = 0;
  word = my_count_word(my_strdup(str));
  tab = (char **)malloc(sizeof(char *) * word);
  while (str[i] && word > 0) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z') || (str[i] >= '0' && str[i] <= '9')) {
      tab[n] = my_strdup(str + i);
      tab[n][my_count_char(str, &i)] = '\0';
      n++;
      word--;
    }
    i++;
  }
  tab[my_count_word(my_strdup(str))] = NULL;
  return (tab);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_str_to_wordtab>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  lea    0x0(,%rax,8),%edi
  mov    %rax,%rbx
  mov    %eax,%r13d
  call   <malloc@plt>
  movslq 0x14(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  mov    %rdi,%rdx
  add    %rbp,%rdi
  movzbl (%rdi),%eax
  test   %ebx,%ebx
  jle    L44
  xor    %r14d,%r14d
  lea    0x14(%rsp),%rbx
  test   %al,%al
  jne    L57
  jmp    L44
  nopl   0x0(%rax)
L72:
  test   %r13d,%r13d
  jle    L44
L57:
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x19,%cl
  jbe    L56
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L34
L56:
  mov    0x8(%rsp),%rsi
  movslq %r14d,%rax
  sub    $0x1,%r13d
  add    $0x1,%r14d
  lea    (%rsi,%rax,8),%r12
  call   <my_strdup@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  mov    %rax,%r15
  call   <my_count_char@plt>
  movb   $0x0,(%r15,%rax,1)
  mov    0x14(%rsp),%edx
L34:
  add    $0x1,%edx
  movslq %edx,%rdi
  mov    %edx,0x14(%rsp)
  add    %rbp,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L72
L44:
  mov    %rbp,%rdi
  call   <my_strdup@plt>
  mov    %rax,%rdi
  call   <my_count_word@plt>
  mov    0x8(%rsp),%rbx
  movq   $0x0,(%rbx,%rax,8)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **my_str_to_wordtab(char *str) {
  int i;
  int n;
  int word;
  char **tab;
  i = 0;
  n = 0;
  word = my_count_word(my_strdup(str));
  tab = (char **)malloc(sizeof(char *) * word);
  while (str[i] && word > 0) {
    if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z') || (str[i] >= '0' && str[i] <= '9')) {
      tab[n] = my_strdup(str + i);
      tab[n][my_count_char(str, &i)] = '\0';
      n++;
      word--;
    }
    i++;
  }
  tab[my_count_word(my_strdup(str))] = NULL;
  return (tab);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jge    L2
  mov    $0xffffffff,%eax
  jmp    L8
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L16
  mov    $0x1,%eax
  jmp    L8
L16:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  uint64_t ai = *((uint64_t *)a);
  uint64_t bi = *((uint64_t *)b);
  if (ai < bi)
    return -1;
  else if (ai > bi)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compare>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jl     L9
  setg   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  uint64_t ai = *((uint64_t *)a);
  uint64_t bi = *((uint64_t *)b);
  if (ai < bi)
    return -1;
  else if (ai > bi)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  uint64_t ai = *((uint64_t *)a);
  uint64_t bi = *((uint64_t *)b);
  if (ai < bi)
    return -1;
  else if (ai > bi)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  uint64_t ai = *((uint64_t *)a);
  uint64_t bi = *((uint64_t *)b);
  if (ai < bi)
    return -1;
  else if (ai > bi)
    return 1;
  else
    return 0;
}
```