ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: %d%f%lf

assistant: ```c
int main() {
  int a;
  float b;
  double c;
  scanf("%d%f%lf", &a, &b, &c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: %d%f%lf

assistant: ```c
int main() {
  int a;
  float b;
  double c;
  scanf("%d%f%lf", &a, &b, &c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_svector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L37
L20:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L7
  lea    -0x9(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %ax,(%rdx)
  jmp    L28
L7:
  mov    -0x10(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movw   $0x0,(%rax)
L28:
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void init_svector(short *src, long nl, long nh, char *init) {
  int i;
  char c[1];
  for (i = nl; i <= nh; i++) {
    *c = *init++;
    if (isdigit(*c))
      src[i] = (short)atoi(c);
    else
      src[i] = (short)0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_svector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L38
  mov    %rdi,%r13
  mov    %rdx,%r12
  mov    %rax,%rbx
  sub    %rax,%rcx
  mov    %rcx,%rbp
  jmp    L27
L56:
  movw   $0x0,0x0(%r13,%rbx,2)
L21:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jl     L38
L27:
  movzbl 0x0(%rbp,%rbx,1),%edi
  mov    %dil,0x7(%rsp)
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L56
  lea    0x7(%rsp),%rdi
  call   <atoi@plt>
  mov    %ax,0x0(%r13,%rbx,2)
  jmp    L21
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void init_svector(short *src, long nl, long nh, char *init) {
  int i;
  char c[1];
  for (i = nl; i <= nh; i++) {
    *c = *init++;
    if (isdigit(*c))
      src[i] = (short)atoi(c);
    else
      src[i] = (short)0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_svector>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  sub    %rbx,%r13
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    %rbx,%rdx
  jl     L18
  mov    %rdi,%r12
  mov    %rdx,%rbp
  jmp    L49
  nopl   0x0(%rax)
L36:
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jg     L18
L49:
  movsbl 0x0(%r13,%rbx,1),%edi
  mov    %dil,0x7(%rsp)
  call   <isdigit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L36
  lea    0x7(%rsp),%rdi
  call   <atoi@plt>
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jle    L49
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void init_svector(short *src, long nl, long nh, char *init) {
  int i;
  char c[1];
  for (i = nl; i <= nh; i++) {
    *c = *init++;
    if (isdigit(*c))
      src[i] = (short)atoi(c);
    else
      src[i] = (short)0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_svector>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    %rbx,%r13
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    %rbx,%rdx
  jl     L28
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x0(%r13,%rbx,1),%edi
  mov    %dil,0x7(%rsp)
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L17
  xor    %eax,%eax
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jle    L6
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  lea    0x7(%rsp),%rdi
  call   <atoi@plt>
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L6
  jmp    L28
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void init_svector(short *src, long nl, long nh, char *init) {
  int i;
  char c[1];
  for (i = nl; i <= nh; i++) {
    *c = *init++;
    if (isdigit(*c))
      src[i] = (short)atoi(c);
    else
      src[i] = (short)0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_doubles(const void *a, const void *b) {
  const double *da = (const double *)a;
  const double *db = (const double *)b;
  return (*da > *db) - (*da < *db);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_doubles>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_doubles(const void *a, const void *b) {
  const double *da = (const double *)a;
  const double *db = (const double *)b;
  return (*da > *db) - (*da < *db);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compare_doubles>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_doubles(const void *a, const void *b) {
  const double *da = (const double *)a;
  const double *db = (const double *)b;
  return (*da > *db) - (*da < *db);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_doubles>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_doubles(const void *a, const void *b) {
  const double *da = (const double *)a;
  const double *db = (const double *)b;
  return (*da > *db) - (*da < *db);
}
```
user: What is the c source code of the assembly code below?

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  mulsd  -0x8(%rbp),%xmm3
  movsd  %xmm3,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm4
  mulsd  -0x8(%rbp),%xmm4
  movsd  %xmm4,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void rotate(double x, double y, double theta, double *rx, double *ry) {
  *rx = x * cos(theta) - y * sin(theta);
  *ry = x * sin(theta) + y * cos(theta);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rotate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  movsd  (%rsp),%xmm4
  movapd %xmm4,%xmm2
  mulsd  %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm2
  movsd  %xmm2,0x0(%rbp)
  mulsd  %xmm4,%xmm0
  mulsd  %xmm5,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotate(double x, double y, double theta, double *rx, double *ry) {
  *rx = x * cos(theta) - y * sin(theta);
  *ry = x * sin(theta) + y * cos(theta);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  movapd %xmm2,%xmm0
  lea    0x10(%rsp),%rsi
  movsd  %xmm1,(%rsp)
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm4
  movsd  (%rsp),%xmm1
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm5
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm5
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm3
  subsd  %xmm5,%xmm0
  addsd  %xmm3,%xmm2
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm2,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotate(double x, double y, double theta, double *rx, double *ry) {
  *rx = x * cos(theta) - y * sin(theta);
  *ry = x * sin(theta) + y * cos(theta);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  movapd %xmm2,%xmm0
  lea    0x10(%rsp),%rsi
  movsd  %xmm1,(%rsp)
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm4
  movsd  (%rsp),%xmm1
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm5
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm5
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm3
  subsd  %xmm5,%xmm0
  addsd  %xmm3,%xmm2
  movsd  %xmm0,0x0(%rbp)
  movsd  %xmm2,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotate(double x, double y, double theta, double *rx, double *ry) {
  *rx = x * cos(theta) - y * sin(theta);
  *ry = x * sin(theta) + y * cos(theta);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_sym_key_cache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    D8(%rip),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    D39(%rip),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    D32(%rip),%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    D36(%rip),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x20,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L4:
  mov    -0x10(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  shr    $0x5,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sar    $0x7,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  or     -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D39
data_type: byte[4]
name: extract_symbolic_data
arguments: data_label: D32
data_type: byte[4]
name: extract_symbolic_data
arguments: data_label: D36
data_type: byte[4]

tool: D8: P

tool: {"D39": [0x6d,0x00,0x00,0x00]}

tool: {"D32": [0x50,0x00,0x00,0x00]}

tool: {"D36": [0x6d,0x00,0x00,0x00]}

assistant: ```c
void build_sym_key_cache(uint32_t *cache, int cache_len) {
  static const uint8_t key[] = {0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0xcb, 0x2b, 0x5a, 0x5a, 0xb4, 0x30, 0x7b, 0xae, 0xa3, 0x2d, 0xcb, 0x77, 0x0c, 0xf2, 0x30, 0x80, 0x3b, 0xb7, 0x42, 0x6a, 0xfa, 0x01, 0xac, 0xbe};
  uint32_t result = (((uint32_t)key[0]) << 24) | (((uint32_t)key[1]) << 16) | (((uint32_t)key[2]) << 8) | ((uint32_t)key[3]);
  uint32_t idx = 32;
  int i;
  for (i = 0; i < cache_len; i++, idx++) {
    uint8_t shift = (idx % (sizeof(uint8_t) * 8));
    uint32_t bit;
    cache[i] = result;
    bit = ((key[idx / (sizeof(uint8_t) * 8)] << shift) & 0x80) ? 1 : 0;
    result = ((result << 1) | bit);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<build_sym_key_cache>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    0x20(%rsi),%r8d
  mov    $0x20,%ecx
  mov    $0x506d506d,%eax
  lea    D5(%rip),%rsi
L2:
  mov    %eax,-0x80(%rdi,%rcx,4)
  lea    (%rax,%rax,1),%edx
  mov    %rcx,%rax
  shr    $0x5,%rax
  mov    (%rsi,%rax,4),%eax
  shl    %cl,%eax
  sar    $0x7,%eax
  and    $0x1,%eax
  or     %edx,%eax
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L2
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: P

assistant: ```c
void build_sym_key_cache(uint32_t *cache, int cache_len) {
  static const uint8_t key[] = {0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0xcb, 0x2b, 0x5a, 0x5a, 0xb4, 0x30, 0x7b, 0xae, 0xa3, 0x2d, 0xcb, 0x77, 0x0c, 0xf2, 0x30, 0x80, 0x3b, 0xb7, 0x42, 0x6a, 0xfa, 0x01, 0xac, 0xbe};
  uint32_t result = (((uint32_t)key[0]) << 24) | (((uint32_t)key[1]) << 16) | (((uint32_t)key[2]) << 8) | ((uint32_t)key[3]);
  uint32_t idx = 32;
  int i;
  for (i = 0; i < cache_len; i++, idx++) {
    uint8_t shift = (idx % (sizeof(uint8_t) * 8));
    uint32_t bit;
    cache[i] = result;
    bit = ((key[idx / (sizeof(uint8_t) * 8)] << shift) & 0x80) ? 1 : 0;
    result = ((result << 1) | bit);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<build_sym_key_cache>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    0x20(%rsi),%r8d
  mov    $0x21,%edx
  mov    $0x6d,%eax
  mov    $0x506d506d,%ecx
  lea    D9(%rip),%r9
  jmp    L4
  nopl   0x0(%rax)
L0:
  mov    %rdx,%rax
  add    $0x1,%rdx
  shr    $0x5,%rax
  mov    (%r9,%rax,4),%eax
L4:
  lea    (%rcx,%rcx,1),%esi
  mov    %ecx,-0x84(%rdi,%rdx,4)
  lea    -0x1(%rdx),%ecx
  shl    %cl,%eax
  sar    $0x7,%eax
  and    $0x1,%eax
  or     %esi,%eax
  mov    %eax,%ecx
  cmp    %r8,%rdx
  jne    L0
L20:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: P

assistant: ```c
void build_sym_key_cache(uint32_t *cache, int cache_len) {
  static const uint8_t key[] = {0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0xcb, 0x2b, 0x5a, 0x5a, 0xb4, 0x30, 0x7b, 0xae, 0xa3, 0x2d, 0xcb, 0x77, 0x0c, 0xf2, 0x30, 0x80, 0x3b, 0xb7, 0x42, 0x6a, 0xfa, 0x01, 0xac, 0xbe};
  uint32_t result = (((uint32_t)key[0]) << 24) | (((uint32_t)key[1]) << 16) | (((uint32_t)key[2]) << 8) | ((uint32_t)key[3]);
  uint32_t idx = 32;
  int i;
  for (i = 0; i < cache_len; i++, idx++) {
    uint8_t shift = (idx % (sizeof(uint8_t) * 8));
    uint32_t bit;
    cache[i] = result;
    bit = ((key[idx / (sizeof(uint8_t) * 8)] << shift) & 0x80) ? 1 : 0;
    result = ((result << 1) | bit);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<build_sym_key_cache>:
  endbr64
  test   %esi,%esi
  jle    L20
  movl   $0x506d506d,(%rdi)
  cmp    $0x1,%esi
  je     L20
  lea    0x20(%rsi),%r8d
  mov    $0x21,%ecx
  mov    $0xa0daa0da,%edx
  lea    D1(%rip),%rsi
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rcx,%rax
  mov    %edx,-0x80(%rdi,%rcx,4)
  add    %edx,%edx
  shr    $0x5,%rax
  mov    (%rsi,%rax,4),%eax
  shl    %cl,%eax
  add    $0x1,%rcx
  sar    $0x7,%eax
  and    $0x1,%eax
  or     %eax,%edx
  cmp    %rcx,%r8
  jne    L23
L20:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: P

assistant: ```c
void build_sym_key_cache(uint32_t *cache, int cache_len) {
  static const uint8_t key[] = {0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0x50, 0x6d, 0xcb, 0x2b, 0x5a, 0x5a, 0xb4, 0x30, 0x7b, 0xae, 0xa3, 0x2d, 0xcb, 0x77, 0x0c, 0xf2, 0x30, 0x80, 0x3b, 0xb7, 0x42, 0x6a, 0xfa, 0x01, 0xac, 0xbe};
  uint32_t result = (((uint32_t)key[0]) << 24) | (((uint32_t)key[1]) << 16) | (((uint32_t)key[2]) << 8) | ((uint32_t)key[3]);
  uint32_t idx = 32;
  int i;
  for (i = 0; i < cache_len; i++, idx++) {
    uint8_t shift = (idx % (sizeof(uint8_t) * 8));
    uint32_t bit;
    cache[i] = result;
    bit = ((key[idx / (sizeof(uint8_t) * 8)] << shift) & 0x80) ? 1 : 0;
    result = ((result << 1) | bit);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jg     L16
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x1f4,%ebx
L10:
  mov    $0x0,%eax
L15:
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  ja     L15
  test   %ebx,%ebx
  mov    $0x1,%r13d
  cmovne %ebx,%r13d
L0:
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%r14
  mov    $0x14,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <daxpy@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  mov    %ebx,%eax
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%eax
  mov    %r13d,%r13d
  movsd  0x0(%rbp,%r13,8),%xmm0
  movsd  0x0(%rbp,%rax,8),%xmm1
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    0x0(,%rax,8),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jne    L10
  mov    %ebx,%r13d
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D3: Tiempo(seg.):%11.9f	 / Tam:%u


tool: D4: Primer componente del resultado [%f]
ultimo componente del resultado [%f]


assistant: ```c
int main(int argc, char **argv) {
  unsigned int N = 500, i;
  double start, end, elapsed;
  if (argc >= 2)
    N = atoi(argv[1]);
  double *x, *y;
  x = (double *)malloc(N * sizeof(double));
  y = (double *)malloc(N * sizeof(double));
  for (i = 0; i < N; i++) {
    x[i] = i;
    y[i] = i;
  }
  start = omp_get_wtime();
  daxpy(x, y, N, 20);
  end = omp_get_wtime();
  elapsed = end - start;
  printf("Tiempo(seg.):%11.9f\t / Tam:%u\n", elapsed, N);
  printf("Primer componente del resultado [%f]\nultimo componente del resultado [%f]\n", y[i], y[N - 1]);
  free(x);
  free(y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jg     L20
  mov    $0xfa0,%edi
  mov    $0x1f4,%ebx
  call   <malloc@plt>
  mov    $0xfa0,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
L35:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  ja     L23
  test   %ebx,%ebx
  mov    $0x1,%r13d
  cmovne %rbx,%r13
L31:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    $0x14,%ecx
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <daxpy@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    %ebx,%eax
  pxor   %xmm1,%xmm1
  subsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbx),%eax
  movsd  0x0(%rbp,%r13,8),%xmm0
  lea    D17(%rip),%rdi
  movsd  0x0(%rbp,%rax,8),%xmm1
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    0x0(,%rbx,8),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jne    L35
  xor    %r13d,%r13d
  jmp    L31
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D5: Tiempo(seg.):%11.9f	 / Tam:%u


tool: D17: Primer componente del resultado [%f]
ultimo componente del resultado [%f]


assistant: ```c
int main(int argc, char **argv) {
  unsigned int N = 500, i;
  double start, end, elapsed;
  if (argc >= 2)
    N = atoi(argv[1]);
  double *x, *y;
  x = (double *)malloc(N * sizeof(double));
  y = (double *)malloc(N * sizeof(double));
  for (i = 0; i < N; i++) {
    x[i] = i;
    y[i] = i;
  }
  start = omp_get_wtime();
  daxpy(x, y, N, 20);
  end = omp_get_wtime();
  elapsed = end - start;
  printf("Tiempo(seg.):%11.9f\t / Tam:%u\n", elapsed, N);
  printf("Primer componente del resultado [%f]\nultimo componente del resultado [%f]\n", y[i], y[N - 1]);
  free(x);
  free(y);
}
```
user: What is the c source code of the assembly code below:

```asm
<Operand_label8_ator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_label8_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Operand_label8_ator>:
  endbr64
  sub    %esi,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_label8_ator(unsigned int *valp, unsigned int pc) {
  *valp -= pc;
  return 0;
}
```