ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_rules>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D14(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L33
L40:
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L39:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <strcpy@plt>
L9:
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L39
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x810,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D14: rb

tool: D10: 
Error in open: %s 



assistant: ```c
int read_rules(char *filename, char **p) {
  int i = 0;
  char buf[2048];
  FILE *fin;
  fin = fopen(filename, "rb");
  if (fin == NULL) {
    printf("\nError in open: %s \n\n", filename);
    exit(1);
  }
  while (fgets(buf, 2048, fin) != NULL) {
    strcpy(p[i], buf);
    i++;
  }
  fclose(fin);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_rules>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D10(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L44
L47:
  xor    %ebx,%ebx
  mov    %rsp,%rbp
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L12:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <strcpy@plt>
L33:
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L12
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x810,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L47
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D10: rb

tool: D4: 
Error in open: %s 



assistant: ```c
int read_rules(char *filename, char **p) {
  int i = 0;
  char buf[2048];
  FILE *fin;
  fin = fopen(filename, "rb");
  if (fin == NULL) {
    printf("\nError in open: %s \n\n", filename);
    exit(1);
  }
  while (fgets(buf, 2048, fin) != NULL) {
    strcpy(p[i], buf);
    i++;
  }
  fclose(fin);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<settabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L84
  movl   $0x1,-0x4(%rbp)
  jmp    L53
L9:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  sete   %cl
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L53:
  cmpl   $0xfa,-0x4(%rbp)
  jle    L9
  jmp    L75
L84:
  movl   $0x1,-0x4(%rbp)
  jmp    L69
L93:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L69:
  cmpl   $0xfa,-0x4(%rbp)
  jle    L93
  jmp    L66
L28:
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L66
  cmpl   $0xfa,-0x4(%rbp)
  jg     L66
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x1,(%rax)
L66:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L28
L75:
  leave
  ret
```

assistant: ```c
void settabs(int argc, char *argv[], char *tabstop) {
  int i;
  if (argc < 2) {
    for (i = 1; i <= 250; i++)
      tabstop[i] = ((i % 4) == 0 ? 1 : 0);
    return;
  }
  for (i = 1; i <= 250; i++)
    tabstop[i] = false;
  while (--argc > 0) {
    i = atoi(*++argv);
    if (0 < i && i <= 250)
      tabstop[i] = 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<settabs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  lea    0x1(%rdx),%rax
  lea    0xfb(%rdx),%rdx
  cmp    $0x1,%edi
  jle    L54
L40:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L40
  lea    -0x1(%rdi),%eax
  lea    0x0(%rbp,%rax,8),%r12
  jmp    L61
L54:
  mov    $0x1,%eax
L42:
  test   $0x3,%al
  sete   (%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0xfb,%rax
  jne    L42
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  cmp    %rbp,%r12
  je     L3
L61:
  add    $0x8,%rbp
  mov    0x0(%rbp),%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%edx
  cmp    $0xf9,%edx
  ja     L50
  cltq
  movb   $0x1,(%rbx,%rax,1)
  jmp    L50
```

assistant: ```c
void settabs(int argc, char *argv[], char *tabstop) {
  int i;
  if (argc < 2) {
    for (i = 1; i <= 250; i++)
      tabstop[i] = ((i % 4) == 0 ? 1 : 0);
    return;
  }
  for (i = 1; i <= 250; i++)
    tabstop[i] = false;
  while (--argc > 0) {
    i = atoi(*++argv);
    if (0 < i && i <= 250)
      tabstop[i] = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<settabs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x1,%edi
  jle    L35
  mov    %edi,%r8d
  lea    0x9(%rdx),%rdi
  mov    %edx,%eax
  mov    %rsi,%rbp
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x1(%rdx)
  movq   $0x0,0xf3(%rdx)
  sub    %edi,%eax
  lea    0xfb(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    -0x1(%r8),%eax
  lea    (%rsi,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L32:
  mov    0x8(%rbp),%rdi
  add    $0x8,%rbp
  call   <atoi@plt>
  lea    -0x1(%rax),%edx
  cmp    $0xf9,%edx
  ja     L39
  cltq
  movb   $0x1,(%rbx,%rax,1)
L39:
  cmp    %r12,%rbp
  jne    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x1,%eax
  nopl   (%rax)
L20:
  test   $0x3,%al
  sete   (%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0xfb,%rax
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void settabs(int argc, char *argv[], char *tabstop) {
  int i;
  if (argc < 2) {
    for (i = 1; i <= 250; i++)
      tabstop[i] = ((i % 4) == 0 ? 1 : 0);
    return;
  }
  for (i = 1; i <= 250; i++)
    tabstop[i] = false;
  while (--argc > 0) {
    i = atoi(*++argv);
    if (0 < i && i <= 250)
      tabstop[i] = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modehprob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <nnint@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: f64

tool: D7: 0.5

assistant: ```c
int modehprob(int n, int a, int m) {
  double v;
  int mode;
  v = (double)(a + 1) * (m + 1) / (double)(n + 2);
  mode = nnint(v - 0.5);
  return mode;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modehprob>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  add    $0x1,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  add    $0x2,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D7(%rip),%xmm0
  call   <nnint@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: f64

tool: D7: 0.5

assistant: ```c
int modehprob(int n, int a, int m) {
  double v;
  int mode;
  v = (double)(a + 1) * (m + 1) / (double)(n + 2);
  mode = nnint(v - 0.5);
  return mode;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<modehprob>:
  endbr64
  add    $0x1,%esi
  pxor   %xmm0,%xmm0
  add    $0x1,%edx
  add    $0x2,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm0
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D4(%rip),%xmm0
  jmp    1050 <nnint@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 0.5

assistant: ```c
int modehprob(int n, int a, int m) {
  double v;
  int mode;
  v = (double)(a + 1) * (m + 1) / (double)(n + 2);
  mode = nnint(v - 0.5);
  return mode;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<modehprob>:
  endbr64
  add    $0x1,%esi
  pxor   %xmm0,%xmm0
  add    $0x1,%edx
  add    $0x2,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm0
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D7(%rip),%xmm0
  jmp    1050 <nnint@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: f64

tool: D7: 0.5

assistant: ```c
int modehprob(int n, int a, int m) {
  double v;
  int mode;
  v = (double)(a + 1) * (m + 1) / (double)(n + 2);
  mode = nnint(v - 0.5);
  return mode;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L31:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L23
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L10
L23:
  mov    -0x4(%rbp),%eax
  jmp    L18
L10:
  mov    $0x0,%eax
L18:
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L31
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  int sum, i;
  for (i = 0; i < 1000; ++i)
    sum += (i % 3 == 0) || (i % 5 == 0) ? i : 0;
  printf("%d\n", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  mov    $0x0,%edi
  jmp    L29
L19:
  add    %edx,%esi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  je     L33
L29:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  mov    %eax,%edx
  cmp    %ecx,%eax
  je     L19
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %edx,%eax
  mov    %edi,%edx
  cmove  %eax,%edx
  jmp    L19
L33:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main(void) {
  int sum, i;
  for (i = 0; i < 1000; ++i)
    sum += (i % 3 == 0) || (i % 5 == 0) ? i : 0;
  printf("%d\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  imul   $0xaaaaaaab,%eax,%edx
  cmp    $0x55555555,%edx
  jbe    L29
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  ja     L15
L29:
  add    %eax,%esi
L15:
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L18
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main(void) {
  int sum, i;
  for (i = 0; i < 1000; ++i)
    sum += (i % 3 == 0) || (i % 5 == 0) ? i : 0;
  printf("%d\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm11,%xmm11
  movdqa D41(%rip),%xmm7
  xor    %eax,%eax
  movdqa %xmm11,%xmm13
  movdqa %xmm11,%xmm12
  movdqa D39(%rip),%xmm8
  movdqa D8(%rip),%xmm10
  pcmpgtd %xmm7,%xmm12
  movdqa %xmm11,%xmm14
  pcmpgtd %xmm8,%xmm13
  nopw   0x0(%rax,%rax,1)
L5:
  movdqa %xmm10,%xmm3
  movdqa %xmm14,%xmm5
  movdqa %xmm13,%xmm2
  add    $0x1,%eax
  movdqa %xmm3,%xmm0
  movdqa %xmm14,%xmm4
  movdqa %xmm13,%xmm15
  paddd  D10(%rip),%xmm10
  punpckldq %xmm3,%xmm0
  pcmpgtd %xmm0,%xmm5
  pmuludq %xmm0,%xmm2
  movdqa %xmm0,%xmm6
  pmuludq %xmm8,%xmm6
  movdqa %xmm5,%xmm1
  pmuludq %xmm7,%xmm5
  pmuludq %xmm8,%xmm1
  paddq  %xmm2,%xmm1
  movdqa %xmm3,%xmm2
  punpckhdq %xmm3,%xmm2
  psllq  $0x20,%xmm1
  pcmpgtd %xmm2,%xmm4
  paddq  %xmm1,%xmm6
  movdqa %xmm2,%xmm9
  pmuludq %xmm2,%xmm15
  pmuludq %xmm8,%xmm9
  movdqa %xmm4,%xmm1
  pmuludq %xmm7,%xmm4
  pmuludq %xmm8,%xmm1
  paddq  %xmm15,%xmm1
  psllq  $0x20,%xmm1
  paddq  %xmm9,%xmm1
  shufps $0xdd,%xmm1,%xmm6
  psrad  $0x1,%xmm6
  movdqa %xmm6,%xmm1
  pslld  $0x2,%xmm1
  paddd  %xmm6,%xmm1
  movdqa %xmm12,%xmm6
  pmuludq %xmm0,%xmm6
  pmuludq %xmm7,%xmm0
  pcmpeqd %xmm3,%xmm1
  paddq  %xmm6,%xmm5
  psllq  $0x20,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm12,%xmm5
  pmuludq %xmm2,%xmm5
  pmuludq %xmm7,%xmm2
  paddq  %xmm5,%xmm4
  psllq  $0x20,%xmm4
  paddq  %xmm4,%xmm2
  shufps $0xdd,%xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pslld  $0x1,%xmm2
  paddd  %xmm2,%xmm0
  pcmpeqd %xmm3,%xmm0
  por    %xmm0,%xmm1
  pand   %xmm3,%xmm1
  paddd  %xmm1,%xmm11
  cmp    $0xfa,%eax
  jne    L5
  movdqa %xmm11,%xmm0
  lea    D13(%rip),%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm11
  movdqa %xmm11,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm11
  movd   %xmm11,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D39
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: {"D41": [0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55]}

tool: {"D39": [0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D10": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D13: %d


assistant: ```c
int main(void) {
  int sum, i;
  for (i = 0; i < 1000; ++i)
    sum += (i % 3 == 0) || (i % 5 == 0) ? i : 0;
  printf("%d\n", sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<m68k_op_bkpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <m68ki_exception_illegal@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void m68k_op_bkpt(void) {
  if (0) {
    ;
  }
  m68ki_exception_illegal();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<m68k_op_bkpt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m68ki_exception_illegal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m68k_op_bkpt(void) {
  if (0) {
    ;
  }
  m68ki_exception_illegal();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<m68k_op_bkpt>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_illegal@plt>
```

assistant: ```c
void m68k_op_bkpt(void) {
  if (0) {
    ;
  }
  m68ki_exception_illegal();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m68k_op_bkpt>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_illegal@plt>
```

assistant: ```c
void m68k_op_bkpt(void) {
  if (0) {
    ;
  }
  m68ki_exception_illegal();
}
```
user: Translate the below assembly code into C programming language:

```asm
<UART_putbin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x80,-0x19(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L0:
  movzbl -0x24(%rbp),%eax
  cmp    -0x19(%rbp),%al
  jb     L46
  movzbl -0x19(%rbp),%eax
  sub    %al,-0x24(%rbp)
  mov    -0x18(%rbp),%eax
  movb   $0x31,-0x11(%rbp,%rax,1)
  jmp    L38
L46:
  mov    -0x18(%rbp),%eax
  movb   $0x30,-0x11(%rbp,%rax,1)
L38:
  shrb   -0x19(%rbp)
  addl   $0x1,-0x18(%rbp)
L3:
  cmpl   $0x7,-0x18(%rbp)
  jbe    L0
  movb   $0x0,-0x9(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <UART_put@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void UART_putbin(unsigned char num) {
  unsigned char c[9];
  unsigned char waarde = 128;
  unsigned int i = 0;
  while (i < 8) {
    if (num >= waarde) {
      num = num - waarde;
      c[i] = '1';
    } else
      c[i] = '0';
    waarde >>= 1;
    i++;
  }
  c[8] = '\0';
  UART_put((char *)c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UART_putbin>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rax
  lea    0x17(%rsp),%r8
  mov    $0xffffff80,%edx
  mov    $0x30,%esi
  mov    $0x31,%r9d
  jmp    L27
L1:
  mov    %cl,(%rax)
  shr    %dl
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L36
L27:
  mov    %esi,%ecx
  cmp    %dl,%dil
  jb     L1
  sub    %edx,%edi
  mov    %r9d,%ecx
  jmp    L1
L36:
  movb   $0x0,0x17(%rsp)
  lea    0xf(%rsp),%rdi
  call   <UART_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UART_putbin(unsigned char num) {
  unsigned char c[9];
  unsigned char waarde = 128;
  unsigned int i = 0;
  while (i < 8) {
    if (num >= waarde) {
      num = num - waarde;
      c[i] = '1';
    } else
      c[i] = '0';
    waarde >>= 1;
    i++;
  }
  c[8] = '\0';
  UART_put((char *)c);
}
```
user: What is the c source code of the assembly code below:

```asm
<UART_putbin>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xffffff80,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%r8
  lea    0x17(%rsp),%rsi
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x30,%ecx
  cmp    %dl,%dil
  jb     L17
  sub    %edx,%edi
  mov    $0x31,%ecx
L17:
  mov    %cl,(%rax)
  add    $0x1,%rax
  shr    %dl
  cmp    %rsi,%rax
  jne    L23
  mov    %r8,%rdi
  movb   $0x0,0x17(%rsp)
  call   <UART_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UART_putbin(unsigned char num) {
  unsigned char c[9];
  unsigned char waarde = 128;
  unsigned int i = 0;
  while (i < 8) {
    if (num >= waarde) {
      num = num - waarde;
      c[i] = '1';
    } else
      c[i] = '0';
    waarde >>= 1;
    i++;
  }
  c[8] = '\0';
  UART_put((char *)c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UART_putbin>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %dil,%dil
  jns    L7
  lea    -0x80(%rdi),%eax
  mov    $0x31,%edx
L74:
  mov    %dl,0xf(%rsp)
  mov    $0x30,%edx
  cmp    $0x3f,%al
  jbe    L5
  sub    $0x40,%eax
  mov    $0x31,%edx
L5:
  mov    %dl,0x10(%rsp)
  mov    $0x30,%edx
  cmp    $0x1f,%al
  jbe    L8
  sub    $0x20,%eax
  mov    $0x31,%edx
L8:
  mov    %dl,0x11(%rsp)
  mov    $0x30,%edx
  cmp    $0xf,%al
  jbe    L10
  sub    $0x10,%eax
  mov    $0x31,%edx
L10:
  mov    %dl,0x12(%rsp)
  mov    $0x30,%edx
  cmp    $0x7,%al
  jbe    L34
  sub    $0x8,%eax
  mov    $0x31,%edx
L34:
  mov    %dl,0x13(%rsp)
  mov    $0x30,%edx
  cmp    $0x3,%al
  jbe    L47
  sub    $0x4,%eax
  mov    $0x31,%edx
L47:
  mov    %dl,0x14(%rsp)
  mov    $0x30,%edx
  cmp    $0x1,%al
  jbe    L87
  sub    $0x2,%eax
  mov    $0x31,%edx
L87:
  add    $0x30,%eax
  lea    0xf(%rsp),%rdi
  mov    %dl,0x15(%rsp)
  mov    %al,0x16(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <UART_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %edi,%eax
  mov    $0x30,%edx
  jmp    L74
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UART_putbin(unsigned char num) {
  unsigned char c[9];
  unsigned char waarde = 128;
  unsigned int i = 0;
  while (i < 8) {
    if (num >= waarde) {
      num = num - waarde;
      c[i] = '1';
    } else
      c[i] = '0';
    waarde >>= 1;
    i++;
  }
  c[8] = '\0';
  UART_put((char *)c);
}
```