ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<_make_safe_start_end>:
  endbr64
  mov    (%rsi),%rax
  test   %rax,%rax
  js     L50
  cmp    %rdi,%rax
  jle    L39
  mov    %rdi,(%rsi)
  mov    %rdi,%rax
L39:
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  js     L29
  cmp    %rax,%rcx
  jge    L35
  mov    %rax,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  movq   $0x0,(%rsi)
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  js     L29
L35:
  cmp    %rcx,%rdi
  jge    L4
L29:
  mov    %rdi,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void _make_safe_start_end(long in_limit, long *io_start, long *io_end) {
  if (*io_start < 0)
    *io_start = 0;
  else if (*io_start > in_limit)
    *io_start = in_limit;
  if (*io_end < 0)
    *io_end = in_limit;
  else if (*io_end < *io_start)
    *io_end = *io_start;
  else if (*io_end > in_limit)
    *io_end = in_limit;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L10
L5:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  D58(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  D58(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L5
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  D58(%rip),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D45
type: string
name: parse_data
arguments: data_label: D29
type: string
name: parse_data
arguments: data_label: D58
type: byte[4]
name: parse_data
arguments: data_label: D41
type: string

tool: D45: %d

tool: D29: %f

tool: {"D58": [0x00,0x00,0x80,0x3f]}

tool: D41: %.2f

assistant: ```c
int main() {
  int n, i;
  float soma = 0;
  float m;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%f", &m);
    soma = soma + (1 / (m + 1));
  }
  soma = n / soma;
  printf("%.2f", soma - 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L6
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r12
  lea    D49(%rip),%rbp
L0:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  D31(%rip),%xmm1
  addss  0x14(%rsp),%xmm1
  movss  D31(%rip),%xmm0
  divss  %xmm1,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  mov    0x10(%rsp),%eax
  cmp    %ebx,%eax
  jge    L0
L4:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  divss  0xc(%rsp),%xmm0
  subss  D31(%rip),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  pxor   %xmm5,%xmm5
  movss  %xmm5,0xc(%rsp)
  jmp    L4
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D35
type_infered: string
name: read_data
arguments: data_tag: D49
type_infered: string
name: read_data
arguments: data_tag: D31
type_infered: byte[4]
name: read_data
arguments: data_tag: D1
type_infered: string

tool: D35: %d

tool: D49: %f

tool: {"D31": [0x00,0x00,0x80,0x3f]}

tool: D1: %.2f

assistant: ```c
int main() {
  int n, i;
  float soma = 0;
  float m;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%f", &m);
    soma = soma + (1 / (m + 1));
  }
  soma = n / soma;
  printf("%.2f", soma - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm2,%xmm2
  test   %eax,%eax
  jle    L3
  movss  D44(%rip),%xmm1
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r12
  lea    D27(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x14(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  mov    0x10(%rsp),%eax
  addss  %xmm1,%xmm3
  movaps %xmm1,%xmm0
  divss  %xmm3,%xmm0
  addss  %xmm0,%xmm2
  cmp    %ebx,%eax
  jge    L33
L10:
  pxor   %xmm0,%xmm0
  lea    D0(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  divss  %xmm2,%xmm0
  subss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  movss  D44(%rip),%xmm1
  jmp    L10
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D44
type_guessed: byte[4]
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D2: %d

tool: {"D44": [0x00,0x00,0x80,0x3f]}

tool: D27: %f

tool: D0: %.2f

assistant: ```c
int main() {
  int n, i;
  float soma = 0;
  float m;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%f", &m);
    soma = soma + (1 / (m + 1));
  }
  soma = n / soma;
  printf("%.2f", soma - 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm2,%xmm2
  test   %eax,%eax
  jle    L6
  movss  D36(%rip),%xmm1
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r12
  lea    D39(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x14(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  mov    0x10(%rsp),%eax
  addss  %xmm1,%xmm3
  movaps %xmm1,%xmm0
  divss  %xmm3,%xmm0
  addss  %xmm0,%xmm2
  cmp    %ebx,%eax
  jge    L36
L32:
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  divss  %xmm2,%xmm0
  subss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  movss  D36(%rip),%xmm1
  jmp    L32
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D36
type: byte[4]
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D7: %d

tool: {"D36": [0x00,0x00,0x80,0x3f]}

tool: D39: %f

tool: D1: %.2f

assistant: ```c
int main() {
  int n, i;
  float soma = 0;
  float m;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%f", &m);
    soma = soma + (1 / (m + 1));
  }
  soma = n / soma;
  printf("%.2f", soma - 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edx
  lea    D62(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  lea    D91(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D74(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D90(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D62
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D91
type: string
name: unpack_data
arguments: label: D74
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D90
type: string

tool: D0: 


tool: D62: char

tool: D16: 	  %10s  %4d 


tool: D91: int

tool: D74: long

tool: D7: double

tool: D90: int*

assistant: ```c
int main(int argc, char *argv[]) {
  printf("\n\n");
  printf("\t  %10s  %4d \n", "char", sizeof(char));
  printf("\t  %10s  %4d \n", "int", sizeof(int));
  printf("\t  %10s  %4d \n", "long", sizeof(long long));
  printf("\t  %10s  %4d \n", "double", sizeof(double));
  printf("\t  %10s  %4d \n", "int*", sizeof(int *));
  printf("\n\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edx
  lea    D10(%rip),%rsi
  lea    D52(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  lea    D57(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D53(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D52
data_type: string
name: extract_symbolic_data
arguments: tag: D57
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D53
data_type: string

tool: D0: 


tool: D10: char

tool: D52: 	  %10s  %4d 


tool: D57: int

tool: D37: long

tool: D33: double

tool: D53: int*

assistant: ```c
int main(int argc, char *argv[]) {
  printf("\n\n");
  printf("\t  %10s  %4d \n", "char", sizeof(char));
  printf("\t  %10s  %4d \n", "int", sizeof(int));
  printf("\t  %10s  %4d \n", "long", sizeof(long long));
  printf("\t  %10s  %4d \n", "double", sizeof(double));
  printf("\t  %10s  %4d \n", "int*", sizeof(int *));
  printf("\n\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D45(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D21(%rip),%rbp
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  xor    %eax,%eax
  lea    D48(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  xor    %eax,%eax
  lea    D11(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D60(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D18(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D45
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D60
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D45: 


tool: D21: 	  %10s  %4d 


tool: D48: char

tool: D11: int

tool: D60: long

tool: D18: double

tool: D5: int*

assistant: ```c
int main(int argc, char *argv[]) {
  printf("\n\n");
  printf("\t  %10s  %4d \n", "char", sizeof(char));
  printf("\t  %10s  %4d \n", "int", sizeof(int));
  printf("\t  %10s  %4d \n", "long", sizeof(long long));
  printf("\t  %10s  %4d \n", "double", sizeof(double));
  printf("\t  %10s  %4d \n", "int*", sizeof(int *));
  printf("\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D40(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D48(%rip),%rbp
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  xor    %eax,%eax
  lea    D14(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  xor    %eax,%eax
  lea    D56(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D64(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D12(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  lea    D28(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
data_type: string
name: extract_symbolic_data
arguments: data_tag: D48
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D56
data_type: string
name: extract_symbolic_data
arguments: data_tag: D64
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D28
data_type: string

tool: D40: 


tool: D48: 	  %10s  %4d 


tool: D14: char

tool: D56: int

tool: D64: long

tool: D12: double

tool: D28: int*

assistant: ```c
int main(int argc, char *argv[]) {
  printf("\n\n");
  printf("\t  %10s  %4d \n", "char", sizeof(char));
  printf("\t  %10s  %4d \n", "int", sizeof(int));
  printf("\t  %10s  %4d \n", "long", sizeof(long long));
  printf("\t  %10s  %4d \n", "double", sizeof(double));
  printf("\t  %10s  %4d \n", "int*", sizeof(int *));
  printf("\n\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<io_get_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %eax,%edi
  call   <chomp@plt>
  mov    %eax,%edi
  call   <trim@plt>
  test   %rax,%rax
  je     L2
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L3
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *io_get_string(char *output, int maxlength, const char *use) {
  char *value = NULL;
  strcpy(output, use);
  if (trim(chomp(fgets(output, maxlength, stdin))) != NULL) {
    if (!strcmp(output, ""))
      strcpy(output, use);
    value = output;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<io_get_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <strcpy@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %eax,%edi
  call   <chomp@plt>
  mov    %eax,%edi
  call   <trim@plt>
  test   %rax,%rax
  je     L22
  cmpb   $0x0,(%rbx)
  je     L24
L5:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L5
L22:
  mov    %rax,%rbx
  jmp    L5
```

assistant: ```c
char *io_get_string(char *output, int maxlength, const char *use) {
  char *value = NULL;
  strcpy(output, use);
  if (trim(chomp(fgets(output, maxlength, stdin))) != NULL) {
    if (!strcmp(output, ""))
      strcpy(output, use);
    value = output;
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<io_get_string>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strcpy@plt>
  mov    D2(%rip),%rax
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %eax,%edi
  call   <chomp@plt>
  mov    %eax,%edi
  call   <trim@plt>
  test   %rax,%rax
  je     L19
  cmpb   $0x0,(%r12)
  je     L0
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *io_get_string(char *output, int maxlength, const char *use) {
  char *value = NULL;
  strcpy(output, use);
  if (trim(chomp(fgets(output, maxlength, stdin))) != NULL) {
    if (!strcmp(output, ""))
      strcpy(output, use);
    value = output;
  }
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<io_get_string>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strcpy@plt>
  mov    D5(%rip),%rax
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %eax,%edi
  call   <chomp@plt>
  mov    %eax,%edi
  call   <trim@plt>
  test   %rax,%rax
  je     L8
  cmpb   $0x0,(%r12)
  je     L15
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *io_get_string(char *output, int maxlength, const char *use) {
  char *value = NULL;
  strcpy(output, use);
  if (trim(chomp(fgets(output, maxlength, stdin))) != NULL) {
    if (!strcmp(output, ""))
      strcpy(output, use);
    value = output;
  }
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L23:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L6
  addl   $0x1,-0x10(%rbp)
  addl   $0x64,-0xc(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L14
L6:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L13
  cmpl   $0x3,-0x10(%rbp)
  jle    L40
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
L40:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L14
L13:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L14
  mov    -0x10(%rbp),%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L14
  negl   -0xc(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
L14:
  addl   $0x1,-0x4(%rbp)
  addl   $0xa,-0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
L27:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L23
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int main_test() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
      assert(0);
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
        assert(0);
      }
      assert(0);
    } else if (y > 10 * w)
      if (z >= 100 * x) {
        y = -y;
        assert(0);
      }
    w = w + 1;
    z = z + 10;
    assert(0);
  }
  assert(0);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L16
L73:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L13
  cmp    $0x3,%ebp
  jg     L18
L56:
  mov    $0x0,%edi
  call   <assert@plt>
L47:
  add    $0xa,%ebx
  mov    $0x0,%edi
  call   <assert@plt>
L16:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L63
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L73
  add    $0x1,%ebp
  add    $0x64,%r12d
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L47
L18:
  add    $0x1,%ebp
  add    $0x1,%r12d
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L56
L13:
  cmp    %ebx,%r12d
  jle    L47
  imul   $0x64,%ebp,%eax
  cmp    %ebx,%eax
  jg     L47
  neg    %r12d
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L47
L63:
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main_test() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
      assert(0);
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
        assert(0);
      }
      assert(0);
    } else if (y > 10 * w)
      if (z >= 100 * x) {
        y = -y;
        assert(0);
      }
    w = w + 1;
    z = z + 10;
    assert(0);
  }
  assert(0);
  return 1;
}
```