ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L19
  xor    %eax,%eax
  ret
L19:
  push   %rbx
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <input_data_correct@plt>
  test   %eax,%eax
  je     L6
  mov    0x10(%rbx),%rax
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rdi
  movsbl (%rax),%esi
  call   <calculate@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L6:
  mov    $0x2,%edx
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1070 <write@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: 0


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4)
    return (0);
  if (!input_data_correct(argv))
    return (write(1, "0\n", 2));
  calculate(argv[1], argv[2][0], argv[3]);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L0
  xor    %eax,%eax
  ret
L0:
  push   %rbx
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <input_data_correct@plt>
  test   %eax,%eax
  je     L9
  mov    0x10(%rbx),%rax
  mov    0x18(%rbx),%rdx
  mov    0x8(%rbx),%rdi
  movsbl (%rax),%esi
  call   <calculate@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  mov    $0x2,%edx
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1070 <write@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: 0


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4)
    return (0);
  if (!input_data_correct(argv))
    return (write(1, "0\n", 2));
  calculate(argv[1], argv[2][0], argv[3]);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AddBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L7:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  and    %rdx,%rax
  test   %rax,%rax
  jne    L52
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L36
  mov    $0x1,%edi
  call   <malloc@plt>
  jmp    L13
L36:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L13:
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
L52:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L42:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x1,%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void AddBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> i) & 1;
    if (*bp == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << *bp;
    *bp = (*bp + 1) & 7;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<AddBits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %esi,%esi
  je     L22
  mov    %esi,%r15d
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %r8,%r13
  mov    $0x0,%r12d
  jmp    L60
L5:
  add    %rsi,%rsi
  mov    (%r14),%rdi
  call   <realloc@plt>
L32:
  mov    %rax,(%r14)
L14:
  mov    (%r14),%rdx
  mov    0x0(%r13),%rax
  movb   $0x0,(%rdx,%rax,1)
  addq   $0x1,0x0(%r13)
L67:
  mov    0x0(%r13),%rax
  mov    (%r14),%rdx
  movzbl 0x0(%rbp),%ecx
  shl    %cl,%ebx
  or     %bl,-0x1(%rdx,%rax,1)
  movzbl 0x0(%rbp),%eax
  add    $0x1,%eax
  and    $0x7,%eax
  mov    %al,0x0(%rbp)
  add    $0x1,%r12d
  cmp    %r12d,%r15d
  je     L22
L60:
  mov    0xc(%rsp),%ebx
  mov    %r12d,%ecx
  shr    %cl,%ebx
  and    $0x1,%ebx
  cmpb   $0x0,0x0(%rbp)
  jne    L67
  mov    0x0(%r13),%rsi
  lea    -0x1(%rsi),%rax
  test   %rsi,%rax
  jne    L14
  test   %rsi,%rsi
  jne    L5
  mov    $0x1,%edi
  call   <malloc@plt>
  jmp    L32
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AddBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> i) & 1;
    if (*bp == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << *bp;
    *bp = (*bp + 1) & 7;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AddBits>:
  endbr64
  test   %esi,%esi
  je     L10
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdx),%eax
  jmp    L68
  nopl   (%rax)
L70:
  mov    (%r15),%rax
L17:
  movb   $0x0,(%rax,%rsi,1)
  mov    (%r8),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%r8)
  movzbl (%r12),%eax
L18:
  add    (%r15),%rdx
  mov    %eax,%ecx
  add    $0x1,%ebp
  shl    %cl,%ebx
  or     %bl,(%rdx)
  movzbl (%r12),%eax
  add    $0x1,%eax
  and    $0x7,%eax
  mov    %al,(%r12)
  cmp    %ebp,%r13d
  je     L13
L68:
  mov    (%r8),%rsi
  mov    %r14d,%ebx
  mov    %ebp,%ecx
  shr    %cl,%ebx
  and    $0x1,%ebx
  lea    -0x1(%rsi),%rdx
  test   %al,%al
  jne    L18
  test   %rdx,%rsi
  jne    L70
  mov    %r8,0x8(%rsp)
  test   %rsi,%rsi
  jne    L26
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
L76:
  mov    %rax,(%r15)
  mov    (%r8),%rsi
  jmp    L17
  nopl   0x0(%rax)
L26:
  mov    (%r15),%rdi
  add    %rsi,%rsi
  call   <realloc@plt>
  mov    0x8(%rsp),%r8
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L10:
  ret
```

assistant: ```c
void AddBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> i) & 1;
    if (*bp == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << *bp;
    *bp = (*bp + 1) & 7;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AddBits>:
  endbr64
  test   %esi,%esi
  je     L25
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdx),%eax
  jmp    L0
  nopl   (%rax)
L16:
  mov    (%r15),%rax
L21:
  movb   $0x0,(%rax,%rsi,1)
  mov    (%r8),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%r8)
  movzbl (%r12),%eax
L78:
  add    (%r15),%rdx
  mov    %eax,%ecx
  add    $0x1,%ebp
  shl    %cl,%ebx
  or     %bl,(%rdx)
  movzbl (%r12),%eax
  add    $0x1,%eax
  and    $0x7,%eax
  mov    %al,(%r12)
  cmp    %ebp,%r13d
  je     L66
L0:
  mov    (%r8),%rsi
  mov    %r14d,%ebx
  mov    %ebp,%ecx
  shr    %cl,%ebx
  and    $0x1,%ebx
  lea    -0x1(%rsi),%rdx
  test   %al,%al
  jne    L78
  test   %rdx,%rsi
  jne    L16
  mov    %r8,0x8(%rsp)
  test   %rsi,%rsi
  jne    L5
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
L2:
  mov    %rax,(%r15)
  mov    (%r8),%rsi
  jmp    L21
  nopl   0x0(%rax)
L5:
  mov    (%r15),%rdi
  add    %rsi,%rsi
  call   <realloc@plt>
  mov    0x8(%rsp),%r8
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L66:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L25:
  ret
```

assistant: ```c
void AddBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> i) & 1;
    if (*bp == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << *bp;
    *bp = (*bp + 1) & 7;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SHPGetLenWithoutExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L38
  mov    -0x8(%rbp),%eax
  jmp    L16
L38:
  subl   $0x1,-0x8(%rbp)
L47:
  cmpl   $0x0,-0x8(%rbp)
  jle    L41
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L41
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L29
L41:
  mov    -0x4(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int SHPGetLenWithoutExtension(const char *pszBasename) {
  int i;
  int nLen = ((int)(strlen(pszBasename)));
  for (i = nLen - 1; i > 0 && pszBasename[i] != '/' && pszBasename[i] != '\\'; i--) {
    if (pszBasename[i] == '.') {
      return i;
    }
  }
  return nLen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SHPGetLenWithoutExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L54
  cltq
L34:
  mov    %eax,%ecx
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x5c,%dl
  je     L54
  cmp    $0x2f,%dl
  je     L54
  cmp    $0x2e,%dl
  je     L10
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L34
  jmp    L54
L10:
  mov    %ecx,%esi
L54:
  mov    %esi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int SHPGetLenWithoutExtension(const char *pszBasename) {
  int i;
  int nLen = ((int)(strlen(pszBasename)));
  for (i = nLen - 1; i > 0 && pszBasename[i] != '/' && pszBasename[i] != '\\'; i--) {
    if (pszBasename[i] == '.') {
      return i;
    }
  }
  return nLen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SHPGetLenWithoutExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L26
  cltq
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L22:
  cmp    $0x2f,%dl
  je     L26
  cmp    $0x2e,%dl
  je     L56
  sub    $0x1,%rax
  test   %eax,%eax
  jle    L26
L19:
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x5c,%dl
  jne    L22
L26:
  mov    %r8d,%eax
  pop    %rbx
  ret
L56:
  mov    %eax,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SHPGetLenWithoutExtension(const char *pszBasename) {
  int i;
  int nLen = ((int)(strlen(pszBasename)));
  for (i = nLen - 1; i > 0 && pszBasename[i] != '/' && pszBasename[i] != '\\'; i--) {
    if (pszBasename[i] == '.') {
      return i;
    }
  }
  return nLen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SHPGetLenWithoutExtension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L24
  cltq
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L6:
  cmp    $0x2f,%dl
  je     L24
  cmp    $0x2e,%dl
  je     L27
  sub    $0x1,%rax
  test   %eax,%eax
  jle    L24
L2:
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x5c,%dl
  jne    L6
L24:
  mov    %r8d,%eax
  pop    %rbx
  ret
L27:
  mov    %eax,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int SHPGetLenWithoutExtension(const char *pszBasename) {
  int i;
  int nLen = ((int)(strlen(pszBasename)));
  for (i = nLen - 1; i > 0 && pszBasename[i] != '/' && pszBasename[i] != '\\'; i--) {
    if (pszBasename[i] == '.') {
      return i;
    }
  }
  return nLen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L3
  jmp    L1
L16:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <extract@plt>
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  jmp    L0
L3:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: unu
(c) 2013, 2016 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013, 2016 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L24
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L9:
  mov    (%rbx),%rdi
  call   <extract@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L9
L2:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string

tool: D5: unu
(c) 2013, 2016 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013, 2016 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L4
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <extract@plt>
  cmp    %rbp,%rbx
  jne    L26
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: unu
(c) 2013, 2016 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013, 2016 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L6
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <extract@plt>
  cmp    %rbp,%rbx
  jne    L23
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: unu
(c) 2013, 2016 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013, 2016 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L13:
  mov    -0x14(%rbp),%eax
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pow(const int base, const unsigned int exponent) {
  unsigned int i;
  unsigned int res = 1;
  for (i = 0; i < exponent; ++i) {
    res *= base;
  }
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<pow>:
  endbr64
  test   %esi,%esi
  je     L13
  mov    $0x1,%edx
  mov    $0x0,%eax
L19:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L19
L22:
  mov    %edx,%eax
  ret
L13:
  mov    $0x1,%edx
  jmp    L22
```

assistant: ```c
int pow(const int base, const unsigned int exponent) {
  unsigned int i;
  unsigned int res = 1;
  for (i = 0; i < exponent; ++i) {
    res *= base;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L7
  xor    %edx,%edx
  nop
L18:
  add    $0x1,%edx
  imul   %edi,%eax
  cmp    %edx,%esi
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int pow(const int base, const unsigned int exponent) {
  unsigned int i;
  unsigned int res = 1;
  for (i = 0; i < exponent; ++i) {
    res *= base;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L7
  xor    %edx,%edx
  nop
L14:
  add    $0x1,%edx
  imul   %edi,%eax
  cmp    %edx,%esi
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int pow(const int base, const unsigned int exponent) {
  unsigned int i;
  unsigned int res = 1;
  for (i = 0; i < exponent; ++i) {
    res *= base;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_config_alt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D2
type: string

tool: D16: Configuration at %d 


tool: D2: %d

assistant: ```c
void print_config_alt(int spin[], int itime) {
  int i;
  printf("Configuration at %d \n", itime);
  for (i = 0; i < 1000; i++) {
    printf("%d", spin[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_config_alt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  add    $0xfa0,%rbp
  lea    D8(%rip),%r12
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: D4: Configuration at %d 


tool: D8: %d

assistant: ```c
void print_config_alt(int spin[], int itime) {
  int i;
  printf("Configuration at %d \n", itime);
  for (i = 0; i < 1000; i++) {
    printf("%d", spin[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_config_alt>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D14(%rip),%rdi
  lea    0xfa0(%rbx),%r12
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D3: %d

tool: D14: Configuration at %d 


assistant: ```c
void print_config_alt(int spin[], int itime) {
  int i;
  printf("Configuration at %d \n", itime);
  for (i = 0; i < 1000; i++) {
    printf("%d", spin[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_config_alt>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D11(%rip),%rdi
  lea    0xfa0(%rbx),%r12
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string

tool: D1: %d

tool: D11: Configuration at %d 


assistant: ```c
void print_config_alt(int spin[], int itime) {
  int i;
  printf("Configuration at %d \n", itime);
  for (i = 0; i < 1000; i++) {
    printf("%d", spin[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_o>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  lea    D2(%rip),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvprintw@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    D8(%rip),%rdx
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <mvprintw@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D2: /\

tool: D8: \/

assistant: ```c
void print_o(int y, int x) {
  mvprintw(y, x, "/\\");
  mvprintw(y + 1, x, "\\/");
}
```