user: 这段汇编代码用C语言表示是什么样的？

```asm
<printTimingInfo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <soar_cDetermineTimerResolution@plt>
  movq   %xmm0,%rbp
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D51(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D122(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D118(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D158(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D131(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D101(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D110(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  movq   %rbp,%xmm0
  lea    D177(%rip),%rdi
  mov    $0x1,%eax
  call   <print@plt>
  movsd  0x8(%rsp),%xmm0
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  call   <print@plt>
  movsd  0x10(%rsp),%xmm0
  lea    D115(%rip),%rdi
  mov    $0x1,%eax
  call   <print@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    D138(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <reset_timer@plt>
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <start_timer@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <stop_timer@plt>
  lea    D107(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    %rbp,%rdi
  call   <timer_value@plt>
  mov    %eax,%esi
  lea    D150(%rip),%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <print@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x1,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D48
type_infered: string
name: parse_data
arguments: label: D51
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D122
type_infered: string
name: parse_data
arguments: label: D59
type_infered: string
name: parse_data
arguments: label: D56
type_infered: string
name: parse_data
arguments: label: D61
type_infered: string
name: parse_data
arguments: label: D118
type_infered: string
name: parse_data
arguments: label: D158
type_infered: string
name: parse_data
arguments: label: D131
type_infered: string
name: parse_data
arguments: label: D101
type_infered: string
name: parse_data
arguments: label: D110
type_infered: string
name: parse_data
arguments: label: D177
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D115
type_infered: string
name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D138
type_infered: string
name: parse_data
arguments: label: D107
type_infered: string
name: parse_data
arguments: label: D150
type_infered: string

tool: D48: Using system timers...


tool: D51: ---------------------------------------------------------------


tool: D12: A timing loop is used to obtain the following values.


tool: D122: At least one additional instruction takes place between


tool: D59: starting and stopping the timers, thus a perfectly accurate


tool: D56: timer which costs nothing to invoke would still accumulate


tool: D61: non-zero value. The loop runs for a total of ~2 seconds as 


tool: D118: a result, the Maximum timer value is likely to be relatively 


tool: D158: large, but should be < 2 seconds


tool: D131: ** NOTE: If the code was optimized, the timing loop may yield


tool: D101:          unanticipated results.  If both minimum values are


tool: D110:          zero, it is unclear what the timer resolution is...


tool: D177: Minimum (Non-Zero) Timer Value: %11.5e sec


tool: D27: Minimum Timer Value           : %11.5e sec


tool: D115: Maximum Timer Value           : %11.5e sec



tool: D46: A short delay will be issued using the sleep() command, and 


tool: D138: timed using Soar's timers....


tool: D107: Sleep interval  -->   3 seconds


tool: D150: Timers report   -->  %8.5f seconds


assistant: ```c
int printTimingInfo() {
  struct timeval start, stop;
  double min, max, min_nz;
  min_nz = soar_cDetermineTimerResolution(&min, &max);
  print("Using system timers...\n");
  print("---------------------------------------------------------------\n");
  print("A timing loop is used to obtain the following values.\n");
  print("At least one additional instruction takes place between\n");
  print("starting and stopping the timers, thus a perfectly accurate\n");
  print("timer which costs nothing to invoke would still accumulate\n");
  print("non-zero value. The loop runs for a total of ~2 seconds as \n");
  print("a result, the Maximum timer value is likely to be relatively \n");
  print("large, but should be < 2 seconds\n");
  print("** NOTE: If the code was optimized, the timing loop may yield\n");
  print("         unanticipated results.  If both minimum values are\n");
  print("         zero, it is unclear what the timer resolution is...\n");
  print("---------------------------------------------------------------\n");
  print("Minimum (Non-Zero) Timer Value: %11.5e sec\n", min_nz);
  print("Minimum Timer Value           : %11.5e sec\n", min);
  print("Maximum Timer Value           : %11.5e sec\n\n", max);
  print("---------------------------------------------------------------\n");
  print("A short delay will be issued using the sleep() command, and \n");
  print("timed using Soar's timers....\n");
  reset_timer(&stop);
  start_timer(&start);
  sleep(3);
  stop_timer(&start, &stop);
  print("Sleep interval  -->   3 seconds\n");
  print("Timers report   -->  %8.5f seconds\n", timer_value(&stop));
  print("---------------------------------------------------------------\n");
  return 1;
}
```