ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    D47(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L109
  nop
L40:
  movsd  D61(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  comisd %xmm1,%xmm2
  jb     L5
  mulsd  D26(%rip),%xmm0
  comisd %xmm0,%xmm1
  jae    L44
L5:
  mov    %r13,%rdi
  call   <printf@plt>
L81:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L109:
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  ucomisd %xmm3,%xmm0
  jp     L22
  jne    L22
  ucomisd %xmm3,%xmm1
  jp     L22
  je     L101
L22:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  jbe    L40
  movsd  D26(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  comisd %xmm1,%xmm2
  jb     L5
  mulsd  D61(%rip),%xmm0
  comisd %xmm0,%xmm1
  jb     L5
L44:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L101:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string
name: extract_symbolic_data
arguments: data_tag: D47
datatype: string
name: extract_symbolic_data
arguments: data_tag: D44
datatype: string
name: extract_symbolic_data
arguments: data_tag: D61
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D26
datatype: byte[8]

tool: D3: INTERIOR


tool: D47: EXTERIOR


tool: D44: %lf %lf

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x60,0x55,0x55,0xd5,0x3f]}

assistant: ```c
int main() {
  double x, y;
  scanf("%lf %lf", &x, &y);
  while (x != 0 || y != 0) {
    if (x < 0) {
      if (y <= (1 / (float)3) * x && y >= 3 * x)
        printf("INTERIOR\n");
      else
        printf("EXTERIOR\n");
    } else {
      if (y <= 3 * x && y >= (1 / (float)3) * x)
        printf("INTERIOR\n");
      else
        printf("EXTERIOR\n");
    }
    scanf("%lf %lf", &x, &y);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D53(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  jmp    L105
  nop
L82:
  movsd  D51(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  comisd %xmm1,%xmm2
  jb     L15
  mulsd  D39(%rip),%xmm0
  comisd %xmm0,%xmm1
  jae    L91
L15:
  mov    %r13,%rdi
  call   <printf@plt>
L49:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L105:
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  ucomisd %xmm3,%xmm0
  jp     L102
  jne    L102
  ucomisd %xmm3,%xmm1
  jp     L102
  je     L41
L102:
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  jbe    L82
  movsd  D39(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  comisd %xmm1,%xmm2
  jb     L15
  mulsd  D51(%rip),%xmm0
  comisd %xmm0,%xmm1
  jb     L15
L91:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
data_type: string
name: disassemble_data
arguments: data_label: D45
data_type: string
name: disassemble_data
arguments: data_label: D53
data_type: string
name: disassemble_data
arguments: data_label: D51
data_type: byte[8]
name: disassemble_data
arguments: data_label: D39
data_type: byte[8]

tool: D12: INTERIOR


tool: D45: EXTERIOR


tool: D53: %lf %lf

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x60,0x55,0x55,0xd5,0x3f]}

assistant: ```c
int main() {
  double x, y;
  scanf("%lf %lf", &x, &y);
  while (x != 0 || y != 0) {
    if (x < 0) {
      if (y <= (1 / (float)3) * x && y >= 3 * x)
        printf("INTERIOR\n");
      else
        printf("EXTERIOR\n");
    } else {
      if (y <= 3 * x && y >= (1 / (float)3) * x)
        printf("INTERIOR\n");
      else
        printf("EXTERIOR\n");
    }
    scanf("%lf %lf", &x, &y);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D19
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D0: Content-type: text/html



tool: D19: <html><head><title>Hello CGI</title></head>

tool: D15: <body><h1>Hello CGI</h1></body></html>

assistant: ```c
int main() {
  printf("Content-type: text/html\n\n");
  printf("<html><head><title>Hello CGI</title></head>");
  printf("<body><h1>Hello CGI</h1></body></html>");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D27
data_type: string

tool: D15: Content-type: text/html



tool: D17: <html><head><title>Hello CGI</title></head>

tool: D27: <body><h1>Hello CGI</h1></body></html>

assistant: ```c
int main() {
  printf("Content-type: text/html\n\n");
  printf("<html><head><title>Hello CGI</title></head>");
  printf("<body><h1>Hello CGI</h1></body></html>");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D7
type: string

tool: D21: Content-type: text/html



tool: D0: <html><head><title>Hello CGI</title></head>

tool: D7: <body><h1>Hello CGI</h1></body></html>

assistant: ```c
int main() {
  printf("Content-type: text/html\n\n");
  printf("<html><head><title>Hello CGI</title></head>");
  printf("<body><h1>Hello CGI</h1></body></html>");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D16
type_infered: string

tool: D29: Content-type: text/html



tool: D12: <html><head><title>Hello CGI</title></head>

tool: D16: <body><h1>Hello CGI</h1></body></html>

assistant: ```c
int main() {
  printf("Content-type: text/html\n\n");
  printf("<html><head><title>Hello CGI</title></head>");
  printf("<body><h1>Hello CGI</h1></body></html>");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x24(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <max_value@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: %d 

assistant: ```c
void main() {
  int array[5] = {-1, 2, 1, 3, 0}, max = 0;
  max_value(array, 5, &max);
  printf("%d ", max);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    $0x5,%esi
  call   <max_value@plt>
  mov    0xc(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %d 

assistant: ```c
void main() {
  int array[5] = {-1, 2, 1, 3, 0}, max = 0;
  max_value(array, 5, &max);
  printf("%d ", max);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2ffffffff,%rax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rdx
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  add    $0x2,%rax
  mov    %rax,0x18(%rsp)
  call   <max_value@plt>
  mov    0xc(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d 

assistant: ```c
void main() {
  int array[5] = {-1, 2, 1, 3, 0}, max = 0;
  max_value(array, 5, &max);
  printf("%d ", max);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D15(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rdx
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0xc(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <max_value@plt>
  mov    0xc(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: {"D15": [0xff,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D7: %d 

assistant: ```c
void main() {
  int array[5] = {-1, 2, 1, 3, 0}, max = 0;
  max_value(array, 5, &max);
  printf("%d ", max);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printCPUtype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D7: 

-- CPU type and model:


tool: D2: cat /proc/cpuinfo | grep model

assistant: ```c
int printCPUtype() {
  printf("\n\n-- CPU type and model:\n");
  system("cat /proc/cpuinfo | grep model");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printCPUtype>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D12: 

-- CPU type and model:


tool: D4: cat /proc/cpuinfo | grep model

assistant: ```c
int printCPUtype() {
  printf("\n\n-- CPU type and model:\n");
  system("cat /proc/cpuinfo | grep model");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<printCPUtype>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D16: 

-- CPU type and model:


tool: D15: cat /proc/cpuinfo | grep model

assistant: ```c
int printCPUtype() {
  printf("\n\n-- CPU type and model:\n");
  system("cat /proc/cpuinfo | grep model");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printCPUtype>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string

tool: D3: 

-- CPU type and model:


tool: D14: cat /proc/cpuinfo | grep model

assistant: ```c
int printCPUtype() {
  printf("\n\n-- CPU type and model:\n");
  system("cat /proc/cpuinfo | grep model");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SLib_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L17
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void SLib_toupper(char *output, const char *input) {
  for (; *input != 0; input++, output++) {
    *output = toupper(*input);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SLib_toupper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L5
L17:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SLib_toupper(char *output, const char *input) {
  for (; *input != 0; input++, output++) {
    *output = toupper(*input);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<SLib_toupper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L1
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L12:
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SLib_toupper(char *output, const char *input) {
  for (; *input != 0; input++, output++) {
    *output = toupper(*input);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SLib_toupper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L17
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L19:
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SLib_toupper(char *output, const char *input) {
  for (; *input != 0; input++, output++) {
    *output = toupper(*input);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <test_f@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <test_f@plt>
  nop
  leave
  ret
```

assistant: ```c
void floats(float x) {
  test_f(x * 1.0);
  test_f(x * 1.0F);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floats>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <test_f@plt>
  movss  0xc(%rsp),%xmm0
  call   <test_f@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void floats(float x) {
  test_f(x * 1.0);
  test_f(x * 1.0F);
}
```
user: Translate the below assembly code into C programming language:

```asm
<floats>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <test_f@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1050 <test_f@plt>
```

assistant: ```c
void floats(float x) {
  test_f(x * 1.0);
  test_f(x * 1.0F);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<floats>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <test_f@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1050 <test_f@plt>
```

assistant: ```c
void floats(float x) {
  test_f(x * 1.0);
  test_f(x * 1.0F);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<horizontalAccumulate16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    -0x28(%rbp),%rbx
  mov    -0x2c(%rbp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
  mov    %edx,%r12d
  cmp    %eax,%r12d
  jle    L9
  sub    %eax,%r12d
L16:
  cmp    $0x4,%eax
  ja     L31
  mov    %eax,%edx
  lea    0x0(,%rdx,4),%rcx
  lea    D7(%rip),%rdx
  mov    (%rcx,%rdx,1),%edx
  movslq %edx,%rdx
  lea    D7(%rip),%rcx
  add    %rcx,%rdx
  notrack jmp *%rdx
L31:
  lea    -0x4(%rax),%edx
  mov    %edx,-0x14(%rbp)
  jmp    L27
L26:
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  movzwl (%rdx),%edx
  mov    %edx,%ecx
  movzwl (%rbx),%edx
  add    %edx,%ecx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  mov    %cx,(%rdx)
  add    $0x2,%rbx
  subl   $0x1,-0x14(%rbp)
L27:
  cmpl   $0x0,-0x14(%rbp)
  jg     L26
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  movzwl (%rdx),%edx
  mov    %edx,%ecx
  movzwl (%rbx),%edx
  add    %edx,%ecx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  mov    %cx,(%rdx)
  add    $0x2,%rbx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  movzwl (%rdx),%edx
  mov    %edx,%ecx
  movzwl (%rbx),%edx
  add    %edx,%ecx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  mov    %cx,(%rdx)
  add    $0x2,%rbx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  movzwl (%rdx),%edx
  mov    %edx,%ecx
  movzwl (%rbx),%edx
  add    %edx,%ecx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  mov    %cx,(%rdx)
  add    $0x2,%rbx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  movzwl (%rdx),%edx
  mov    %edx,%ecx
  movzwl (%rbx),%edx
  add    %edx,%ecx
  movslq %eax,%rdx
  add    %rdx,%rdx
  add    %rbx,%rdx
  mov    %cx,(%rdx)
  add    $0x2,%rbx
  sub    %eax,%r12d
  test   %r12d,%r12d
  jg     L16
L9:
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void horizontalAccumulate16(char *cp, int cc, register int stride) {
  register short *wp = (short *)cp;
  register int wc = cc / 2;
  if (wc > stride) {
    wc -= stride;
    do {
      switch (stride) {
      default: {
        int i;
        for (i = stride - 4; i > 0; i--) {
          wp[stride] += wp[0];
          wp++;
        }
      }
      case 4:
        wp[stride] += wp[0];
        wp++;
      case 3:
        wp[stride] += wp[0];
        wp++;
      case 2:
        wp[stride] += wp[0];
        wp++;
      case 1:
        wp[stride] += wp[0];
        wp++;
      case 0:;
      }
      wc -= stride;
    } while (wc > 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<horizontalAccumulate16>:
  endbr64
  mov    %edx,%r11d
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rsi,1),%esi
  sar    %esi
  cmp    %r11d,%esi
  jle    L47
  push   %rbx
  mov    %rdi,%rax
  sub    %r11d,%esi
  movslq %r11d,%rcx
  add    %rcx,%rcx
  lea    -0x5(%r11),%edx
  lea    0x2(%rdx,%rdx,1),%rbx
  mov    %r11d,%r10d
  lea    D0(%rip),%r8
  jmp    L55
L8:
  jle    L13
  lea    (%rax,%rbx,1),%r9
  mov    %rax,%rdx
L33:
  movzwl (%rdx),%edi
  add    %di,(%rdx,%rcx,1)
  add    $0x2,%rdx
  cmp    %r9,%rdx
  jne    L33
  add    %rbx,%rax
L13:
  movzwl (%rax),%edx
  add    %dx,(%rax,%rcx,1)
  add    $0x2,%rax
  movzwl (%rax),%edx
  add    %dx,(%rax,%rcx,1)
  add    $0x2,%rax
  movzwl (%rax),%edx
  add    %dx,(%rax,%rcx,1)
  add    $0x2,%rax
  movzwl (%rax),%edx
  add    %dx,(%rax,%rcx,1)
  add    $0x2,%rax
  sub    %r11d,%esi
  test   %esi,%esi
  jle    L9
L55:
  cmp    $0x4,%r11d
  ja     L8
  movslq (%r8,%r10,4),%rdx
  add    %r8,%rdx
  notrack jmp *%rdx
L9:
  pop    %rbx
  ret
L47:
  ret
```

assistant: ```c
void horizontalAccumulate16(char *cp, int cc, register int stride) {
  register short *wp = (short *)cp;
  register int wc = cc / 2;
  if (wc > stride) {
    wc -= stride;
    do {
      switch (stride) {
      default: {
        int i;
        for (i = stride - 4; i > 0; i--) {
          wp[stride] += wp[0];
          wp++;
        }
      }
      case 4:
        wp[stride] += wp[0];
        wp++;
      case 3:
        wp[stride] += wp[0];
        wp++;
      case 2:
        wp[stride] += wp[0];
        wp++;
      case 1:
        wp[stride] += wp[0];
        wp++;
      case 0:;
      }
      wc -= stride;
    } while (wc > 0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<horizontalAccumulate16>:
  endbr64
  mov    %edx,%r10d
  mov    %esi,%edx
  mov    %rdi,%rax
  shr    $0x1f,%edx
  lea    (%rdx,%rsi,1),%ecx
  sar    %ecx
  cmp    %r10d,%ecx
  jle    L35
  movslq %r10d,%rdx
  lea    -0x5(%r10),%esi
  sub    %r10d,%ecx
  mov    %r10d,%r9d
  add    %rdx,%rdx
  lea    0x2(%rsi,%rsi,1),%r11
  lea    D0(%rip),%rdi
  nopl   (%rax)
L9:
  cmp    $0x4,%r10d
  ja     L18
  movslq (%rdi,%r9,4),%rsi
  add    %rdi,%rsi
  notrack jmp *%rsi
L18:
  jle    L22
  lea    (%rax,%r11,1),%r8
  xchg   %ax,%ax
L16:
  movzwl (%rax),%esi
  add    %si,(%rax,%rdx,1)
  add    $0x2,%rax
  cmp    %r8,%rax
  jne    L16
L22:
  movzwl (%rax),%esi
  add    %si,(%rax,%rdx,1)
  add    $0x2,%rax
  movzwl (%rax),%esi
  add    %si,(%rax,%rdx,1)
  add    $0x2,%rax
  movzwl (%rax),%esi
  add    %si,(%rax,%rdx,1)
  add    $0x2,%rax
  movzwl (%rax),%esi
  add    %si,(%rax,%rdx,1)
  add    $0x2,%rax
  sub    %r10d,%ecx
  test   %ecx,%ecx
  jg     L9
L35:
  ret
```

assistant: ```c
void horizontalAccumulate16(char *cp, int cc, register int stride) {
  register short *wp = (short *)cp;
  register int wc = cc / 2;
  if (wc > stride) {
    wc -= stride;
    do {
      switch (stride) {
      default: {
        int i;
        for (i = stride - 4; i > 0; i--) {
          wp[stride] += wp[0];
          wp++;
        }
      }
      case 4:
        wp[stride] += wp[0];
        wp++;
      case 3:
        wp[stride] += wp[0];
        wp++;
      case 2:
        wp[stride] += wp[0];
        wp++;
      case 1:
        wp[stride] += wp[0];
        wp++;
      case 0:;
      }
      wc -= stride;
    } while (wc > 0);
  }
}
```