user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L26
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L26:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <getgrnam@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L42
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L42:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rax
  test   %rax,%rax
  je     L52
  movl   $0x0,-0xc(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L28:
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rax
  test   %rax,%rax
  je     L36
  mov    $0x2c,%edi
  call   <putchar@plt>
L36:
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
L52:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D74
type_guessed: string
name: extract_symbolic_data
arguments: label: D62
type_guessed: string
name: extract_symbolic_data
arguments: label: D53
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D74: ERROR: no arg specified

tool: D62: FAIL: group %s does not exist


tool: D53: PASS: group %s exists


tool: D32: gr_name = %s


tool: D29: gr_passwd = %s


tool: D25: gr_gid = %d


tool: D3: gr_mem = 

tool: D15: %s

assistant: ```c
int main(int argc, char **argv) {
  struct group *gr;
  if (argc != 2) {
    printf("ERROR: no arg specified\n");
    exit(1);
  }
  if ((gr = getgrnam(argv[1])) == NULL) {
    printf("FAIL: group %s does not exist\n", argv[1]);
    exit(1);
  }
  printf("PASS: group %s exists\n", argv[1]);
  printf("gr_name = %s\n", gr->gr_name);
  printf("gr_passwd = %s\n", gr->gr_passwd);
  printf("gr_gid = %d\n", gr->gr_gid);
  if (gr->gr_mem != NULL) {
    int i = 0;
    printf("gr_mem = ");
    while (gr->gr_mem[i] != NULL) {
      printf("%s", gr->gr_mem[i]);
      i++;
      if (gr->gr_mem != NULL) {
        printf(",");
      }
    }
    printf("\n");
  }
  exit(0);
}
```