ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<jac_zeros_grjm>:
  endbr64
  mov    D10(%rip),%rax
  addsd  D3(%rip),%xmm1
  sub    $0x1,%esi
  add    $0x8,%rdi
  mov    %rax,-0x8(%rdi)
  jmp    1050 <jac_jacobi_zeros@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: byte[8]
name: retrieve_data
arguments: label: D3
type_guessed: f64

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D3: 1

assistant: ```c
int jac_zeros_grjm(double *z, const int Q, double alpha, double beta) {
  z[0] = -1.0;
  return jac_jacobi_zeros(z + 1, Q - 1, alpha, beta + 1.0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_matrix@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rotate@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_matrix@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string

tool: D16: The original matrix is :


tool: D14: The rotated matrix is :


assistant: ```c
void test(void (*func4test)(int **, int), int **matrix, int n) {
  printf("The original matrix is :\n");
  print_matrix(matrix, n);
  rotate(matrix, n);
  printf("The rotated matrix is :\n");
  print_matrix(matrix, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <print_matrix@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <rotate@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <print_matrix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D15: The original matrix is :


tool: D0: The rotated matrix is :


assistant: ```c
void test(void (*func4test)(int **, int), int **matrix, int n) {
  printf("The original matrix is :\n");
  print_matrix(matrix, n);
  rotate(matrix, n);
  printf("The rotated matrix is :\n");
  print_matrix(matrix, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <print_matrix@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <rotate@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <print_matrix@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D9: The original matrix is :


tool: D16: The rotated matrix is :


assistant: ```c
void test(void (*func4test)(int **, int), int **matrix, int n) {
  printf("The original matrix is :\n");
  print_matrix(matrix, n);
  rotate(matrix, n);
  printf("The rotated matrix is :\n");
  print_matrix(matrix, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <print_matrix@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <rotate@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <print_matrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D9: The original matrix is :


tool: D5: The rotated matrix is :


assistant: ```c
void test(void (*func4test)(int **, int), int **matrix, int n) {
  printf("The original matrix is :\n");
  print_matrix(matrix, n);
  rotate(matrix, n);
  printf("The rotated matrix is :\n");
  print_matrix(matrix, n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<circulate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x1,%esi
  mov    $0x7,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L6:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
L16:
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L6
  mov    -0xc(%rbp),%eax
  cltq
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *circulate(char *buff) {
  char *returnString = calloc(7, sizeof(char));
  char first = *buff;
  buff++;
  int i, count = 0;
  for (i = 0; i < strlen(buff); i++) {
    *returnString = buff[i];
    returnString++;
    count++;
    if (i == strlen(buff) - 1) {
      *returnString = first;
    }
  }
  returnString -= count;
  return returnString;
}
```
user: Translate the below assembly code into C programming language:

```asm
<circulate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x1,%esi
  mov    $0x7,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  movzbl 0x0(%r13),%r14d
  lea    0x1(%r13),%r12
  mov    $0x0,%ebx
  jmp    L33
L35:
  add    $0x1,%rbx
L33:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L5
  movzbl 0x1(%r13,%rbx,1),%eax
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L35
  mov    %r14b,0x0(%rbp)
  jmp    L35
L5:
  movslq %ebx,%r15
  mov    %rbp,%rax
  sub    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *circulate(char *buff) {
  char *returnString = calloc(7, sizeof(char));
  char first = *buff;
  buff++;
  int i, count = 0;
  for (i = 0; i < strlen(buff); i++) {
    *returnString = buff[i];
    returnString++;
    count++;
    if (i == strlen(buff) - 1) {
      *returnString = first;
    }
  }
  returnString -= count;
  return returnString;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<circulate>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  push   %r13
  mov    %rdi,%r13
  mov    $0x7,%edi
  push   %r12
  lea    0x1(%r13),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <calloc@plt>
  movzbl 0x0(%r13),%r14d
  mov    %rax,%rbp
  jmp    L25
  xchg   %ax,%ax
L5:
  movzbl 0x1(%r13,%rbx,1),%eax
  mov    %r12,%rdi
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L8
  mov    %r14b,0x0(%rbp)
L8:
  add    $0x1,%rbx
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  mov    %rbp,%rax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *circulate(char *buff) {
  char *returnString = calloc(7, sizeof(char));
  char first = *buff;
  buff++;
  int i, count = 0;
  for (i = 0; i < strlen(buff); i++) {
    *returnString = buff[i];
    returnString++;
    count++;
    if (i == strlen(buff) - 1) {
      *returnString = first;
    }
  }
  returnString -= count;
  return returnString;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<circulate>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  push   %r13
  mov    %rdi,%r13
  mov    $0x7,%edi
  push   %r12
  lea    0x1(%r13),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <calloc@plt>
  movzbl 0x0(%r13),%r14d
  mov    %rax,%rbp
  jmp    L8
  xchg   %ax,%ax
L28:
  movzbl 0x1(%r13,%rbx,1),%eax
  mov    %r12,%rdi
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,%ebx
  jne    L29
  mov    %r14b,0x0(%rbp)
L29:
  add    $0x1,%rbx
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L28
  mov    %rbp,%rax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *circulate(char *buff) {
  char *returnString = calloc(7, sizeof(char));
  char first = *buff;
  buff++;
  int i, count = 0;
  for (i = 0; i < strlen(buff); i++) {
    *returnString = buff[i];
    returnString++;
    count++;
    if (i == strlen(buff) - 1) {
      *returnString = first;
    }
  }
  returnString -= count;
  return returnString;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compute_gold>:
  endbr64
  test   %esi,%esi
  je     L69
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %esi,%r9d
  lea    0x1(%rsi),%r14d
  lea    (%rsi,%rsi,1),%r13d
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm3
L21:
  lea    0x1(%rax),%ebp
  cmp    %ebp,%r9d
  je     L10
  mov    %r12d,%eax
  lea    (%rcx,%rax,4),%rsi
  mov    %ebp,%eax
L47:
  movss  (%rsi),%xmm0
  ucomiss %xmm2,%xmm0
  jp     L17
  ucomiss %xmm3,%xmm0
  je     L23
L17:
  lea    (%rax,%rbx,1),%edx
  lea    (%rcx,%rdx,4),%rdx
  movss  (%rdx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  add    $0x1,%eax
  cmp    %eax,%r9d
  ja     L47
  movss  D0(%rip),%xmm4
  movss  %xmm4,(%rsi)
  lea    (%r9,%r12,1),%r10d
  mov    %r9d,%edi
  neg    %edi
  add    %r13d,%ebx
  mov    %ebx,%esi
  mov    %ebp,%r11d
L84:
  mov    %r10d,%eax
  lea    (%rcx,%rax,4),%r8
  lea    0x1(%r10),%eax
L2:
  mov    %eax,%edx
  lea    (%rcx,%rdx,4),%rdx
  lea    (%rdi,%rax,1),%r15d
  movss  (%rcx,%r15,4),%xmm1
  mulss  (%r8),%xmm1
  movss  (%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L2
  movl   $0x0,(%r8)
  add    $0x1,%r11d
  add    %r9d,%r10d
  sub    %r9d,%edi
  add    %r9d,%esi
  cmp    %r11d,%r9d
  jne    L84
  add    %r14d,%r12d
  sub    %r11d,%ebx
  mov    %ebp,%eax
  jmp    L21
L23:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  mov    $0x1,%eax
  ret
L10:
  lea    0x2(%rax),%edx
  imul   %edx,%eax
  movl   $0x3f800000,(%rcx,%rax,4)
  mov    $0x1,%eax
  jmp    L46
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: byte[4]
name: retrieve_data
arguments: data_label: D4
type: string

tool: {"D0": [0x00,0x00,0x80,0x3f]}

tool: D4: Numerical instability detected. The principal diagonal element is zero. 


assistant: ```c
int compute_gold(float *U, unsigned int num_elements) {
  unsigned int i, j, k;
  for (k = 0; k < num_elements; k++) {
    for (j = (k + 1); j < num_elements; j++) {
      if (U[num_elements * k + k] == 0) {
        printf("Numerical instability detected. The principal diagonal element is zero. \n");
        return 0;
      }
      U[num_elements * k + j] = (float)(U[num_elements * k + j] / U[num_elements * k + k]);
    }
    U[num_elements * k + k] = 1;
    for (i = (k + 1); i < num_elements; i++) {
      for (j = (k + 1); j < num_elements; j++)
        U[num_elements * i + j] = U[num_elements * i + j] - (U[num_elements * i + k] * U[num_elements * k + j]);
      U[num_elements * i + k] = 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compute_gold>:
  endbr64
  test   %esi,%esi
  je     L5
  push   %r15
  lea    (%rsi,%rsi,1),%eax
  mov    %rdi,%rcx
  mov    %esi,%r10d
  push   %r14
  lea    0x1(%rsi),%r15d
  mov    %esi,%r14d
  pxor   %xmm2,%xmm2
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  add    $0x1,%r12d
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  mov    %r13d,%eax
  lea    (%rcx,%rax,4),%rsi
  cmp    %r12d,%r10d
  je     L59
L64:
  mov    %r12d,%eax
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L72:
  lea    (%rax,%rbp,1),%edx
  add    $0x1,%eax
  lea    (%rcx,%rdx,4),%rdx
  movss  (%rdx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  cmp    %eax,%r10d
  jbe    L44
L79:
  movss  (%rsi),%xmm1
  ucomiss %xmm2,%xmm1
  jp     L72
  jne    L72
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  mov    0xc(%rsp),%eax
  mov    %r10d,%edi
  movl   $0x3f800000,(%rsi)
  mov    %r14d,%r9d
  neg    %edi
  mov    %r12d,%r11d
  lea    (%rax,%rbp,1),%ebx
  mov    %ebx,%esi
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r9d,%eax
  lea    (%rcx,%rax,4),%r8
  lea    0x1(%r9),%eax
  nopl   0x0(%rax,%rax,1)
L57:
  lea    (%rdi,%rax,1),%ebp
  mov    %eax,%edx
  add    $0x1,%eax
  movss  (%rcx,%rbp,4),%xmm1
  mulss  (%r8),%xmm1
  lea    (%rcx,%rdx,4),%rdx
  movss  (%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  cmp    %eax,%esi
  jne    L57
  add    $0x1,%r11d
  add    %r10d,%r9d
  sub    %r10d,%edi
  add    %r10d,%esi
  movl   $0x0,(%r8)
  cmp    %r11d,%r10d
  jne    L55
  add    %r15d,%r13d
  sub    %r10d,%ebx
  add    $0x1,%r12d
  add    %r15d,%r14d
  mov    %r13d,%eax
  mov    %ebx,%ebp
  lea    (%rcx,%rax,4),%rsi
  cmp    %r12d,%r10d
  jne    L64
L59:
  movl   $0x3f800000,(%rsi)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: Numerical instability detected. The principal diagonal element is zero. 


assistant: ```c
int compute_gold(float *U, unsigned int num_elements) {
  unsigned int i, j, k;
  for (k = 0; k < num_elements; k++) {
    for (j = (k + 1); j < num_elements; j++) {
      if (U[num_elements * k + k] == 0) {
        printf("Numerical instability detected. The principal diagonal element is zero. \n");
        return 0;
      }
      U[num_elements * k + j] = (float)(U[num_elements * k + j] / U[num_elements * k + k]);
    }
    U[num_elements * k + k] = 1;
    for (i = (k + 1); i < num_elements; i++) {
      for (j = (k + 1); j < num_elements; j++)
        U[num_elements * i + j] = U[num_elements * i + j] - (U[num_elements * i + k] * U[num_elements * k + j]);
      U[num_elements * i + k] = 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_gold>:
  endbr64
  test   %esi,%esi
  je     L58
  push   %r15
  lea    (%rsi,%rsi,1),%eax
  mov    %rdi,%rcx
  mov    %esi,%r10d
  push   %r14
  lea    0x1(%rsi),%r15d
  mov    %esi,%r14d
  pxor   %xmm2,%xmm2
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  add    $0x1,%r12d
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  mov    %r13d,%eax
  lea    (%rcx,%rax,4),%rsi
  cmp    %r12d,%r10d
  je     L80
L33:
  mov    %r12d,%eax
  jmp    L82
  nopl   0x0(%rax,%rax,1)
L75:
  lea    (%rax,%rbp,1),%edx
  add    $0x1,%eax
  lea    (%rcx,%rdx,4),%rdx
  movss  (%rdx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  cmp    %eax,%r10d
  jbe    L76
L82:
  movss  (%rsi),%xmm1
  ucomiss %xmm2,%xmm1
  jp     L75
  jne    L75
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  mov    0xc(%rsp),%eax
  mov    %r10d,%edi
  movl   $0x3f800000,(%rsi)
  mov    %r14d,%r9d
  neg    %edi
  mov    %r12d,%r11d
  lea    (%rax,%rbp,1),%ebx
  mov    %ebx,%esi
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r9d,%eax
  lea    (%rcx,%rax,4),%r8
  lea    0x1(%r9),%eax
  nopl   0x0(%rax,%rax,1)
L89:
  lea    (%rdi,%rax,1),%ebp
  mov    %eax,%edx
  add    $0x1,%eax
  movss  (%rcx,%rbp,4),%xmm1
  mulss  (%r8),%xmm1
  lea    (%rcx,%rdx,4),%rdx
  movss  (%rdx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  cmp    %eax,%esi
  jne    L89
  add    $0x1,%r11d
  add    %r10d,%r9d
  sub    %r10d,%edi
  add    %r10d,%esi
  movl   $0x0,(%r8)
  cmp    %r11d,%r10d
  jne    L55
  add    %r15d,%r13d
  sub    %r10d,%ebx
  add    $0x1,%r12d
  add    %r15d,%r14d
  mov    %r13d,%eax
  mov    %ebx,%ebp
  lea    (%rcx,%rax,4),%rsi
  cmp    %r12d,%r10d
  jne    L33
L80:
  movl   $0x3f800000,(%rsi)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string

tool: D4: Numerical instability detected. The principal diagonal element is zero. 


assistant: ```c
int compute_gold(float *U, unsigned int num_elements) {
  unsigned int i, j, k;
  for (k = 0; k < num_elements; k++) {
    for (j = (k + 1); j < num_elements; j++) {
      if (U[num_elements * k + k] == 0) {
        printf("Numerical instability detected. The principal diagonal element is zero. \n");
        return 0;
      }
      U[num_elements * k + j] = (float)(U[num_elements * k + j] / U[num_elements * k + k]);
    }
    U[num_elements * k + k] = 1;
    for (i = (k + 1); i < num_elements; i++) {
      for (j = (k + 1); j < num_elements; j++)
        U[num_elements * i + j] = U[num_elements * i + j] - (U[num_elements * i + k] * U[num_elements * k + j]);
      U[num_elements * i + k] = 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ResetISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000ed88,%eax
  mov    (%rax),%edx
  mov    $0xe000ed88,%eax
  or     $0xf00000,%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ResetISR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: What is the c source code of the assembly code below:

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<escolha_simb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L11:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x78,%al
  jne    L12
  mov    -0x20(%rbp),%rax
  movb   $0x58,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x4f,(%rax)
  jmp    L16
L12:
  movzbl -0x9(%rbp),%eax
  cmp    $0x6f,%al
  jne    L11
  mov    -0x20(%rbp),%rax
  movb   $0x4f,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x58,(%rax)
L16:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D13: 
jogador 1, escolha X ou O 


tool: D2: %c

assistant: ```c
void escolha_simb(char *jog1, char *jog2) {
  while (1) {
    printf("\njogador 1, escolha X ou O \n");
    char esc;
    scanf("%c", &esc);
    if (esc == 'x') {
      *jog2 = 'X';
      *jog1 = 'O';
      break;
    } else if (esc == 'o') {
      *jog2 = 'O';
      *jog1 = 'X';
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<escolha_simb>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%r12
  lea    0x7(%rsp),%rbp
  lea    D5(%rip),%rbx
L31:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x78,%al
  je     L22
  cmp    $0x6f,%al
  jne    L31
  mov    $0x4f,%edx
  mov    $0x58,%eax
  jmp    L8
L22:
  mov    $0x58,%edx
  mov    $0x4f,%eax
L8:
  mov    %dl,(%r14)
  mov    %al,0x0(%r13)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D5
type: string

tool: D9: 
jogador 1, escolha X ou O 


tool: D5: %c

assistant: ```c
void escolha_simb(char *jog1, char *jog2) {
  while (1) {
    printf("\njogador 1, escolha X ou O \n");
    char esc;
    scanf("%c", &esc);
    if (esc == 'x') {
      *jog2 = 'X';
      *jog1 = 'O';
      break;
    } else if (esc == 'o') {
      *jog2 = 'O';
      *jog1 = 'X';
      break;
    }
  }
}
```