ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x38,0xe(%rsp)
  movb   $0x36,0xf(%rsp)
  movb   $0x31,0x10(%rsp)
  lea    0xe(%rsp),%rbx
  lea    0xb(%rsp),%r12
  lea    D2(%rip),%rbp
L15:
  movsbl 0x2(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L15
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D2: %c

tool: 

assistant: ```c
int main(void) {
  int data = 168;
  char num[10];
  int i = 0;
  while (1) {
    num[i++] = data % 10 + '0';
    data /= 10;
    if (data == 0)
      break;
  }
  for (i -= 1; i >= 0; --i) {
    printf("%c", num[i]);
  }
  puts("");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x31,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3638,%eax
  movb   $0x31,0x10(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %ax,0xe(%rsp)
  lea    0xb(%rsp),%r12
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl 0x2(%rbx),%esi
L14:
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L10
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D0: %c

tool: 

assistant: ```c
int main(void) {
  int data = 168;
  char num[10];
  int i = 0;
  while (1) {
    num[i++] = data % 10 + '0';
    data /= 10;
    if (data == 0)
      break;
  }
  for (i -= 1; i >= 0; --i) {
    printf("%c", num[i]);
  }
  puts("");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3638,%eax
  movb   $0x31,0x10(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %ax,0xe(%rsp)
  lea    0xb(%rsp),%r12
  nopl   0x0(%rax)
L11:
  movsbl 0x2(%rbx),%esi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L11
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D16: %c

tool: 

assistant: ```c
int main(void) {
  int data = 168;
  char num[10];
  int i = 0;
  while (1) {
    num[i++] = data % 10 + '0';
    data /= 10;
    if (data == 0)
      break;
  }
  for (i -= 1; i >= 0; --i) {
    printf("%c", num[i]);
  }
  puts("");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L69
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L7
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L34
L7:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L34
L69:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L55
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L34
L55:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L34:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D42
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D49
type: string

tool: D42: %d%d%d

tool: D1: EQUALOATOR

tool: D19: iso

tool: D49: scal

assistant: ```c
main() {
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  if (a == b) {
    if (b == c)
      printf("EQUALOATOR");
    else
      printf("iso");
  } else {
    if (b == c)
      printf("iso");
    else
      printf("scal");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  je     L12
  cmp    0x14(%rsp),%eax
  je     L60
  lea    D26(%rip),%rdi
  call   <printf@plt>
L53:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L12:
  cmp    0x14(%rsp),%eax
  je     L33
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L33:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L60:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D35
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D35: %d%d%d

tool: D26: scal

tool: D17: iso

tool: D11: EQUALOATOR

assistant: ```c
main() {
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  if (a == b) {
    if (b == c)
      printf("EQUALOATOR");
    else
      printf("iso");
  } else {
    if (b == c)
      printf("iso");
    else
      printf("scal");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  je     L32
  cmp    0x14(%rsp),%eax
  je     L21
  lea    D16(%rip),%rdi
  call   <printf@plt>
L57:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L32:
  cmp    0x14(%rsp),%eax
  je     L20
L21:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L20:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D35
type_guessed: string

tool: D18: %d%d%d

tool: D16: scal

tool: D15: iso

tool: D35: EQUALOATOR

assistant: ```c
main() {
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  if (a == b) {
    if (b == c)
      printf("EQUALOATOR");
    else
      printf("iso");
  } else {
    if (b == c)
      printf("iso");
    else
      printf("scal");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  je     L23
  cmp    0x14(%rsp),%eax
  je     L48
  lea    D11(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L23:
  cmp    0x14(%rsp),%eax
  je     L47
L48:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L47:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D4: %d%d%d

tool: D11: scal

tool: D18: iso

tool: D0: EQUALOATOR

assistant: ```c
main() {
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  if (a == b) {
    if (b == c)
      printf("EQUALOATOR");
    else
      printf("iso");
  } else {
    if (b == c)
      printf("iso");
    else
      printf("scal");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dynamicLibraryBFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dynamicLibraryAFunction@plt>
  mov    %rax,%rdx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D9(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
datatype: string

tool: D19: FromDynamicLibraryB, but also calling '%s'

assistant: ```c
char *dynamicLibraryBFunction() {
  static char buffer[256];
  sprintf(buffer, "FromDynamicLibraryB, but also calling '%s'", dynamicLibraryAFunction());
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dynamicLibraryBFunction>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <dynamicLibraryAFunction@plt>
  mov    %rax,%rdx
  lea    D17(%rip),%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D17: FromDynamicLibraryB, but also calling '%s'

assistant: ```c
char *dynamicLibraryBFunction() {
  static char buffer[256];
  sprintf(buffer, "FromDynamicLibraryB, but also calling '%s'", dynamicLibraryAFunction());
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dynamicLibraryBFunction>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D4(%rip),%r12
  call   <dynamicLibraryAFunction@plt>
  mov    %r12,%rdi
  lea    D16(%rip),%rsi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string

tool: D16: FromDynamicLibraryB, but also calling '%s'

assistant: ```c
char *dynamicLibraryBFunction() {
  static char buffer[256];
  sprintf(buffer, "FromDynamicLibraryB, but also calling '%s'", dynamicLibraryAFunction());
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dynamicLibraryBFunction>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D1(%rip),%r12
  call   <dynamicLibraryAFunction@plt>
  mov    %r12,%rdi
  lea    D6(%rip),%rsi
  mov    %rax,%rdx
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: FromDynamicLibraryB, but also calling '%s'

assistant: ```c
char *dynamicLibraryBFunction() {
  static char buffer[256];
  sprintf(buffer, "FromDynamicLibraryB, but also calling '%s'", dynamicLibraryAFunction());
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10c(%rbp)
  jmp    L60
L68:
  lea    -0x100(%rbp),%rdx
  mov    -0x10c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x10c(%rbp),%eax
  cltq
  mov    %rdx,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0x10c(%rbp)
L60:
  mov    -0x110(%rbp),%eax
  cmp    %eax,-0x10c(%rbp)
  jl     L68
  mov    -0x110(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10c(%rbp)
  jmp    L57
L39:
  mov    -0x10c(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x10c(%rbp)
L57:
  mov    -0x110(%rbp),%eax
  cmp    %eax,-0x10c(%rbp)
  jl     L39
  lea    -0xb0(%rbp),%rax
  mov    %rax,-0x108(%rbp)
  mov    -0x110(%rbp),%edx
  mov    -0x108(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10c(%rbp)
  jmp    L27
L35:
  mov    -0x10c(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10c(%rbp)
L27:
  mov    -0x110(%rbp),%eax
  cmp    %eax,-0x10c(%rbp)
  jl     L35
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
data_type: string
name: extract_symbolic_data
arguments: data_tag: D34
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string
name: extract_symbolic_data
arguments: data_tag: D22
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string

tool: D35: input n:

tool: D34: %d

tool: D4: input %d integer numbers:

tool: D22: Now,the sequence is:

tool: D36: %d  

assistant: ```c
int main() {
  void sort(int **p, int n);
  int i, n;
  int data[20], *pstr[20], **p;
  printf("input n:\n");
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    pstr[i] = &data[i];
  printf("input %d integer numbers:", n);
  for (i = 0; i < n; i++)
    scanf("%d", pstr[i]);
  p = pstr;
  sort(p, n);
  printf("Now,the sequence is:\n");
  for (i = 0; i < n; i++)
    printf("%d  ", *pstr[i]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L58
  lea    0x10(%rsp),%rax
  lea    0x60(%rsp),%rdx
  lea    -0x1(%rsi),%ecx
  lea    0x14(%rsp,%rcx,4),%rcx
L67:
  mov    %rax,(%rdx)
  add    $0x4,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L67
L58:
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L41
  mov    $0x0,%ebx
  lea    D31(%rip),%rbp
L5:
  mov    0x60(%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  add    $0x1,%rbx
  cmp    %ebx,%esi
  jg     L5
L41:
  lea    0x60(%rsp),%rdi
  call   <sort@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L19
  mov    $0x0,%ebx
  lea    D11(%rip),%rbp
L6:
  mov    0x60(%rsp,%rbx,8),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L6
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D31
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D21
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string

tool: D8: input n:

tool: D31: %d

tool: D39: input %d integer numbers:

tool: D21: Now,the sequence is:

tool: D11: %d  

assistant: ```c
int main() {
  void sort(int **p, int n);
  int i, n;
  int data[20], *pstr[20], **p;
  printf("input n:\n");
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    pstr[i] = &data[i];
  printf("input %d integer numbers:", n);
  for (i = 0; i < n; i++)
    scanf("%d", pstr[i]);
  p = pstr;
  sort(p, n);
  printf("Now,the sequence is:\n");
  for (i = 0; i < n; i++)
    printf("%d  ", *pstr[i]);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D46(%rip),%rdi
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L27
  lea    0x60(%rsp),%rbp
  lea    -0x1(%rsi),%ecx
  lea    0x10(%rsp),%rax
  mov    %rbp,%rdx
  lea    0x14(%rsp,%rcx,4),%rcx
  nopl   0x0(%rax)
L36:
  mov    %rax,(%rdx)
  add    $0x4,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L36
L27:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L67
  xor    %ebx,%ebx
L47:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L47
L67:
  mov    %rbp,%rdi
  call   <sort@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %ebx,%ebx
  lea    D39(%rip),%r12
  xchg   %ax,%ax
L55:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L55
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D46
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D39
data_type: string

tool: D46: input n:

tool: D5: %d

tool: D18: input %d integer numbers:

tool: D14: Now,the sequence is:

tool: D39: %d  

assistant: ```c
int main() {
  void sort(int **p, int n);
  int i, n;
  int data[20], *pstr[20], **p;
  printf("input n:\n");
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    pstr[i] = &data[i];
  printf("input %d integer numbers:", n);
  for (i = 0; i < n; i++)
    scanf("%d", pstr[i]);
  p = pstr;
  sort(p, n);
  printf("Now,the sequence is:\n");
  for (i = 0; i < n; i++)
    printf("%d  ", *pstr[i]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dont_look_at_this_either>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,-0x28(%rbp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  mov    %rcx,%r14
  movl   $0x5,-0x44(%rbp)
  mov    -0x44(%rbp),%ecx
  lea    (%rcx,%rcx,1),%ebx
  mov    -0x44(%rbp),%ecx
  movslq %ebx,%r12
  sub    $0x1,%r12
  mov    %r12,-0x40(%rbp)
  movslq %ebx,%r12
  mov    %r12,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movslq %ecx,%r12
  sub    $0x1,%r12
  mov    %r12,-0x38(%rbp)
  movslq %ebx,%r12
  mov    %r12,%r10
  mov    $0x0,%r11d
  movslq %ecx,%r12
  mov    %r12,%rax
  mov    $0x0,%edx
  mov    %r11,%r13
  imul   %rax,%r13
  mov    %rdx,%r12
  imul   %r10,%r12
  add    %r13,%r12
  mul    %r10
  lea    (%r12,%rdx,1),%r10
  mov    %r10,%rdx
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ecx,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    %r9,%rdx
  imul   %rsi,%rdx
  mov    %rdi,%rax
  imul   %r8,%rax
  lea    (%rdx,%rax,1),%r10
  mov    %r8,%rax
  mul    %rsi
  lea    (%r10,%rdx,1),%rsi
  mov    %rsi,%rdx
  movslq %ebx,%rdx
  movslq %ecx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L21:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L21
L15:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L39
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L39:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <show@plt>
  mov    $0x4,%edi
  call   <show@plt>
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <show@plt>
  addl   $0x1,-0x44(%rbp)
  movslq %ebx,%rax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <show@plt>
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <show@plt>
  mov    %r14,%rsp
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
void dont_look_at_this_either() {
  int c = 5;
  int v[c][2 * c];
  show(c);
  show(sizeof ++c);
  show(c);
  show(sizeof v[++c]);
  show(c);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dont_look_at_this_either>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x4,%edi
  call   <show@plt>
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x28,%edi
  call   <show@plt>
  mov    $0x6,%edi
  call   <show@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dont_look_at_this_either() {
  int c = 5;
  int v[c][2 * c];
  show(c);
  show(sizeof ++c);
  show(c);
  show(sizeof v[++c]);
  show(c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dont_look_at_this_either>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x4,%edi
  call   <show@plt>
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x28,%edi
  call   <show@plt>
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1050 <show@plt>
```

assistant: ```c
void dont_look_at_this_either() {
  int c = 5;
  int v[c][2 * c];
  show(c);
  show(sizeof ++c);
  show(c);
  show(sizeof v[++c]);
  show(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dont_look_at_this_either>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x4,%edi
  call   <show@plt>
  mov    $0x5,%edi
  call   <show@plt>
  mov    $0x28,%edi
  call   <show@plt>
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1050 <show@plt>
```

assistant: ```c
void dont_look_at_this_either() {
  int c = 5;
  int v[c][2 * c];
  show(c);
  show(sizeof ++c);
  show(c);
  show(sizeof v[++c]);
  show(c);
}
```