ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D32(%rip),%r12
  mov    %r12,%rsi
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  call   <strcoll@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcoll@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  call   <strcoll@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <strcoll@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x30,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x34,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcoll@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D6
type_infered: string

tool: D32: 1234

tool: D15: 123

tool: D1: %d


tool: D10: 1233

tool: D7: 1230

tool: D6: 12

assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", strcoll("123", "1234"));
  printf("%d\n", strcoll("1234", "123"));
  printf("%d\n", strcoll("1234", "1233"));
  printf("%d\n", strcoll("1230", "123"));
  printf("%d\n", '0');
  printf("%d\n", '4');
  printf("%d\n", strcoll("1230", "12"));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  lea    D23(%rip),%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %r12,%rdi
  lea    D30(%rip),%rbp
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  lea    D56(%rip),%rsi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x30,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x34,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D6(%rip),%rsi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D45
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string
name: unpack_data
arguments: data_label: D30
datatype: string
name: unpack_data
arguments: data_label: D56
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string

tool: D45: 1234

tool: D23: 123

tool: D30: %d


tool: D56: 1233

tool: D1: 1230

tool: D6: 12

assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", strcoll("123", "1234"));
  printf("%d\n", strcoll("1234", "123"));
  printf("%d\n", strcoll("1234", "1233"));
  printf("%d\n", strcoll("1230", "123"));
  printf("%d\n", '0');
  printf("%d\n", '4');
  printf("%d\n", strcoll("1230", "12"));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D40(%rip),%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %r12,%rdi
  lea    D42(%rip),%rbp
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  lea    D2(%rip),%rsi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D51(%rip),%r12
  mov    %r12,%rdi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x30,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x34,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D4(%rip),%rsi
  call   <strcoll@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
datatype: string
name: unpack_data
arguments: label: D40
datatype: string
name: unpack_data
arguments: label: D42
datatype: string
name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D51
datatype: string
name: unpack_data
arguments: label: D4
datatype: string

tool: D21: 1234

tool: D40: 123

tool: D42: %d


tool: D2: 1233

tool: D51: 1230

tool: D4: 12

assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", strcoll("123", "1234"));
  printf("%d\n", strcoll("1234", "123"));
  printf("%d\n", strcoll("1234", "1233"));
  printf("%d\n", strcoll("1230", "123"));
  printf("%d\n", '0');
  printf("%d\n", '4');
  printf("%d\n", strcoll("1230", "12"));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<___pthread_mutex_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <dlock_unlock@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <o_pthread_mutex_unlock@plt>
  leave
  ret
```

assistant: ```c
int ___pthread_mutex_unlock(pthread_mutex_t *mutex, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(mutex, (int)pthread_self());
  return o_pthread_mutex_unlock(mutex);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<___pthread_mutex_unlock>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <dlock_unlock@plt>
  mov    %rbx,%rdi
  call   <o_pthread_mutex_unlock@plt>
  pop    %rbx
  ret
```

assistant: ```c
int ___pthread_mutex_unlock(pthread_mutex_t *mutex, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(mutex, (int)pthread_self());
  return o_pthread_mutex_unlock(mutex);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<___pthread_mutex_unlock>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <dlock_unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <o_pthread_mutex_unlock@plt>
```

assistant: ```c
int ___pthread_mutex_unlock(pthread_mutex_t *mutex, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(mutex, (int)pthread_self());
  return o_pthread_mutex_unlock(mutex);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<___pthread_mutex_unlock>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <dlock_unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <o_pthread_mutex_unlock@plt>
```

assistant: ```c
int ___pthread_mutex_unlock(pthread_mutex_t *mutex, char *lname, char *fn, int ln) {
  ;
  dlock_unlock(mutex, (int)pthread_self());
  return o_pthread_mutex_unlock(mutex);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D37(%rip),%rax
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Socket@plt>
  mov    %eax,-0x2c(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x2695,%edi
  call   <htons@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <Bind@plt>
  mov    -0x2c(%rbp),%eax
  mov    $0x400,%esi
  mov    %eax,%edi
  call   <Listen@plt>
L9:
  movl   $0xc,-0x30(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <Accept@plt>
  mov    %eax,-0x28(%rbp)
  mov    $0x0,%eax
  call   <Fork@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L1
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <Close@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <str_echo@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <Close@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  int listenfd, connfd;
  pid_t childpid;
  socklen_t clilen;
  struct sockaddr_in cliaddr, srvaddr;
  listenfd = Socket(AF_INET, SOCK_STREAM, 0);
  memset(&srvaddr, 0, sizeof(srvaddr));
  srvaddr.sin_family = AF_INET;
  srvaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  srvaddr.sin_port = htons(9877);
  Bind(listenfd, (struct sockaddr *)&srvaddr, sizeof(srvaddr));
  Listen(listenfd, 1024);
  for (;;) {
    clilen = sizeof(cliaddr);
    connfd = Accept(listenfd, (struct sockaddr *)&cliaddr, &clilen);
    if ((childpid = Fork()) == 0) {
      Close(listenfd);
      str_echo(connfd);
      exit(0);
    }
    Close(connfd);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%r12
  mov    $0x0,%edx
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    (%r12),%edi
  call   <Socket@plt>
  mov    %eax,%ebp
  lea    0x1c(%rsp),%rbx
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0x24(%rsp)
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0x20(%rsp)
  mov    $0x2695,%edi
  call   <htons@plt>
  mov    %eax,0x1c(%rsp)
  mov    $0xc,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <Bind@plt>
  mov    $0x400,%esi
  mov    %ebp,%edi
  call   <Listen@plt>
  lea    0xc(%rsp),%r12
  jmp    L15
L14:
  mov    %ebp,%edi
  call   <Close@plt>
  mov    %ebx,%edi
  call   <str_echo@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L7:
  mov    %ebx,%edi
  call   <Close@plt>
L15:
  movl   $0xc,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  mov    %ebp,%edi
  call   <Accept@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <Fork@plt>
  test   %eax,%eax
  je     L14
  jmp    L7
```

assistant: ```c
int main(void) {
  int listenfd, connfd;
  pid_t childpid;
  socklen_t clilen;
  struct sockaddr_in cliaddr, srvaddr;
  listenfd = Socket(AF_INET, SOCK_STREAM, 0);
  memset(&srvaddr, 0, sizeof(srvaddr));
  srvaddr.sin_family = AF_INET;
  srvaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  srvaddr.sin_port = htons(9877);
  Bind(listenfd, (struct sockaddr *)&srvaddr, sizeof(srvaddr));
  Listen(listenfd, 1024);
  for (;;) {
    clilen = sizeof(cliaddr);
    connfd = Accept(listenfd, (struct sockaddr *)&cliaddr, &clilen);
    if ((childpid = Fork()) == 0) {
      Close(listenfd);
      str_echo(connfd);
      exit(0);
    }
    Close(connfd);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    D29(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  lea    0x1c(%rsp),%rbp
  lea    0xc(%rsp),%r13
  mov    (%r12),%edi
  mov    (%rax),%esi
  call   <Socket@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <memset@plt>
  mov    (%r12),%eax
  lea    0x10(%rsp),%r12
  mov    %eax,0x24(%rsp)
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x2695,%edi
  mov    %eax,0x20(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    %eax,0x1c(%rsp)
  call   <Bind@plt>
  mov    $0x400,%esi
  mov    %ebx,%edi
  call   <Listen@plt>
  nopl   0x0(%rax)
L11:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  movl   $0xc,0xc(%rsp)
  call   <Accept@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <Fork@plt>
  test   %eax,%eax
  jne    L8
  mov    %ebx,%edi
  call   <Close@plt>
  mov    %ebp,%edi
  call   <str_echo@plt>
  xor    %edi,%edi
  call   <exit@plt>
L8:
  mov    %ebp,%edi
  call   <Close@plt>
  jmp    L11
```

assistant: ```c
int main(void) {
  int listenfd, connfd;
  pid_t childpid;
  socklen_t clilen;
  struct sockaddr_in cliaddr, srvaddr;
  listenfd = Socket(AF_INET, SOCK_STREAM, 0);
  memset(&srvaddr, 0, sizeof(srvaddr));
  srvaddr.sin_family = AF_INET;
  srvaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  srvaddr.sin_port = htons(9877);
  Bind(listenfd, (struct sockaddr *)&srvaddr, sizeof(srvaddr));
  Listen(listenfd, 1024);
  for (;;) {
    clilen = sizeof(cliaddr);
    connfd = Accept(listenfd, (struct sockaddr *)&cliaddr, &clilen);
    if ((childpid = Fork()) == 0) {
      Close(listenfd);
      str_echo(connfd);
      exit(0);
    }
    Close(connfd);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    D0(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%rax
  lea    0x1c(%rsp),%rbp
  lea    0xc(%rsp),%r13
  mov    (%r12),%edi
  mov    (%rax),%esi
  call   <Socket@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <memset@plt>
  mov    (%r12),%eax
  lea    0x10(%rsp),%r12
  mov    %eax,0x24(%rsp)
  mov    D29(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x2695,%edi
  mov    %eax,0x20(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    %eax,0x1c(%rsp)
  call   <Bind@plt>
  mov    $0x400,%esi
  mov    %ebx,%edi
  call   <Listen@plt>
  nopl   0x0(%rax)
L13:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  movl   $0xc,0xc(%rsp)
  call   <Accept@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <Fork@plt>
  test   %eax,%eax
  jne    L2
  mov    %ebx,%edi
  call   <Close@plt>
  mov    %ebp,%edi
  call   <str_echo@plt>
  xor    %edi,%edi
  call   <exit@plt>
L2:
  mov    %ebp,%edi
  call   <Close@plt>
  jmp    L13
```

assistant: ```c
int main(void) {
  int listenfd, connfd;
  pid_t childpid;
  socklen_t clilen;
  struct sockaddr_in cliaddr, srvaddr;
  listenfd = Socket(AF_INET, SOCK_STREAM, 0);
  memset(&srvaddr, 0, sizeof(srvaddr));
  srvaddr.sin_family = AF_INET;
  srvaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  srvaddr.sin_port = htons(9877);
  Bind(listenfd, (struct sockaddr *)&srvaddr, sizeof(srvaddr));
  Listen(listenfd, 1024);
  for (;;) {
    clilen = sizeof(cliaddr);
    connfd = Accept(listenfd, (struct sockaddr *)&cliaddr, &clilen);
    if ((childpid = Fork()) == 0) {
      Close(listenfd);
      str_echo(connfd);
      exit(0);
    }
    Close(connfd);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L35
L33:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jl     L25
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%esi
  cltd
  idiv   %esi
  mov    %eax,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L6
L25:
  movl   $0x0,-0x10(%rbp)
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D27
type_infered: string

tool: D0: %d

tool: D7: %d %d

tool: D27: %d %d


assistant: ```c
int main(void) {
  int x, k, T, p, q;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d", &x, &k);
    q = x % k;
    if (x >= k)
      p = (x - q) / (x / k) - q;
    else
      p = 0;
    printf("%d %d\n", p, q);
    T--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  je     L17
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D5(%rip),%rbp
  lea    D12(%rip),%rbx
  jmp    L37
L44:
  mov    %r8d,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  je     L17
L37:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  mov    $0x0,%esi
  cmp    %edi,%ecx
  jl     L44
  mov    %ecx,%esi
  sub    %edx,%esi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %eax,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  sub    %r8d,%esi
  jmp    L44
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D12
data_type: string

tool: D2: %d

tool: D5: %d %d

tool: D12: %d %d


assistant: ```c
int main(void) {
  int x, k, T, p, q;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d", &x, &k);
    q = x % k;
    if (x >= k)
      p = (x - q) / (x / k) - q;
    else
      p = 0;
    printf("%d %d\n", p, q);
    T--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L10
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D5(%rip),%rbp
  lea    D23(%rip),%rbx
  nop
L23:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%esi
  xor    %r9d,%r9d
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%r8d
  mov    %eax,%edi
  cmp    %esi,%ecx
  jl     L9
  mov    %ecx,%eax
  sub    %edx,%eax
  cltd
  idiv   %edi
  sub    %r8d,%eax
  mov    %eax,%r9d
L9:
  mov    %r8d,%edx
  mov    %r9d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  subl   $0x1,0x14(%rsp)
  jne    L23
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string

tool: D19: %d

tool: D5: %d %d

tool: D23: %d %d


assistant: ```c
int main(void) {
  int x, k, T, p, q;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d", &x, &k);
    q = x % k;
    if (x >= k)
      p = (x - q) / (x / k) - q;
    else
      p = 0;
    printf("%d %d\n", p, q);
    T--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L22
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D26(%rip),%rbp
  lea    D0(%rip),%rbx
  jmp    L14
  nopl   0x0(%rax)
L44:
  mov    %esi,%eax
  sub    %edx,%eax
  cltd
  idiv   %edi
  mov    %r8d,%edx
  mov    %rbx,%rdi
  sub    %r8d,%eax
  mov    %eax,%esi
  call   <printf@plt>
  subl   $0x1,0x14(%rsp)
  je     L22
L14:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%r8d
  mov    %eax,%edi
  cmp    %ecx,%esi
  jge    L44
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  subl   $0x1,0x14(%rsp)
  jne    L14
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D19: %d

tool: D26: %d %d

tool: D0: %d %d


assistant: ```c
int main(void) {
  int x, k, T, p, q;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d", &x, &k);
    q = x % k;
    if (x >= k)
      p = (x - q) / (x / k) - q;
    else
      p = 0;
    printf("%d %d\n", p, q);
    T--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: TEST_C not defined.


assistant: ```c
int main(int argc, char **argv) {
  printf("TEST_C not defined.\n");
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: TEST_C not defined.


assistant: ```c
int main(int argc, char **argv) {
  printf("TEST_C not defined.\n");
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: TEST_C not defined.


assistant: ```c
int main(int argc, char **argv) {
  printf("TEST_C not defined.\n");
  return 1;
}
```