ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<bin_coeff_off>:
  endbr64
  sub    $0x3,%edi
  imul   %edi,%edi
  sar    $0x2,%edi
  lea    -0x2(%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int bin_coeff_off(int n, int k) {
  int np = n - 3;
  return ((np * np) / 4) + (k - 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin_coeff_off>:
  endbr64
  sub    $0x3,%edi
  imul   %edi,%edi
  sar    $0x2,%edi
  lea    -0x2(%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int bin_coeff_off(int n, int k) {
  int np = n - 3;
  return ((np * np) / 4) + (k - 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DMA_Wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xe,-0x4(%rbp)
  jbe    L33
  mov    $0x1,%eax
  jmp    L25
L33:
  nop
L29:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%eax
  add    $0x20007000,%rax
  mov    (%rax),%eax
  and    $0x104,%eax
  test   %eax,%eax
  je     L29
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%eax
  add    $0x20007000,%rax
  mov    (%rax),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L25
  mov    $0x2,%eax
  jmp    L25
L25:
  pop    %rbp
  ret
```

assistant: ```c
int DMA_Wait(unsigned int Channel) {
  if (Channel > 14)
    return 1;
  while ((*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & (1 << 2 | 1 << 8)) == 0)
    ;
  if (*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & 1 << 8)
    return 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<DMA_Wait>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xe,%edi
  ja     L6
  shl    $0x8,%edi
  mov    %edi,%edi
  lea    0x20007000(%rdi),%rdx
L9:
  mov    (%rdx),%eax
  test   $0x104,%eax
  je     L9
  mov    0x20007000(%rdi),%edx
  mov    $0x2,%eax
  test   $0x1,%dh
L6:
  ret
```

assistant: ```c
int DMA_Wait(unsigned int Channel) {
  if (Channel > 14)
    return 1;
  while ((*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & (1 << 2 | 1 << 8)) == 0)
    ;
  if (*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & 1 << 8)
    return 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DMA_Wait>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xe,%edi
  ja     L17
  shl    $0x8,%edi
  lea    0x20007000(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rdx),%eax
  test   $0x104,%eax
  je     L9
  mov    0x20007000(%rdi),%edx
  mov    $0x2,%eax
L17:
  ret
```

assistant: ```c
int DMA_Wait(unsigned int Channel) {
  if (Channel > 14)
    return 1;
  while ((*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & (1 << 2 | 1 << 8)) == 0)
    ;
  if (*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & 1 << 8)
    return 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DMA_Wait>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xe,%edi
  ja     L10
  shl    $0x8,%edi
  lea    0x20007000(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdx),%eax
  test   $0x104,%eax
  je     L2
  mov    0x20007000(%rdi),%edx
  mov    $0x2,%eax
L10:
  ret
```

assistant: ```c
int DMA_Wait(unsigned int Channel) {
  if (Channel > 14)
    return 1;
  while ((*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & (1 << 2 | 1 << 8)) == 0)
    ;
  if (*(volatile int *)((volatile void *)(0x20007000) + (Channel)*0x100 + 0x00) & 1 << 8)
    return 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L40
  mov    $0x1,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L40:
  movl   $0x0,-0x1c(%rbp)
  jmp    L45
L55:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L45:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L55
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x29b3ce2e,%eax
  jne    L29
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L29:
  movl   $0x0,-0x18(%rbp)
  jmp    L35
L66:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L35:
  cmpl   $0x0,-0x18(%rbp)
  jle    L66
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D28
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string

tool: D8: Call this program with %i arguments


tool: D28: You win!

tool: D10: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 699649582U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L16
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x29b3ce2e,0x4(%rsp)
  je     L43
L5:
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L0
L43:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string

tool: D19: %u


tool: D17: Call this program with %i arguments


tool: D16: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 699649582U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L34
  lea    D0(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L34:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x29b3ce2e,%esi
  je     L7
L15:
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L15
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D0: Call this program with %i arguments


tool: D1: %u


tool: D25: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 699649582U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L30
  lea    D7(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L30:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x29b3ce2e,%esi
  je     L26
L24:
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L24
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D12
data_type: string

tool: D7: Call this program with %i arguments


tool: D10: %u


tool: D12: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 699649582U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L47
  mov    -0x18(%rbp),%eax
  jmp    L115
L47:
  cmpl   $0x0,-0x18(%rbp)
  jne    L65
  mov    -0x14(%rbp),%eax
  jmp    L115
L65:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L22
L106:
  mov    -0xc(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L35
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L74
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L86
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L86:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L22
L74:
  sarl   -0x8(%rbp)
  jmp    L22
L35:
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L38
  sarl   -0xc(%rbp)
  jmp    L22
L38:
  shll   -0x4(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L106
  mov    -0xc(%rbp),%eax
L115:
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int x, int y) {
  int a;
  int b;
  int lsbMask;
  if (x == 0)
    return (y);
  if (y == 0)
    return (x);
  a = x;
  b = y;
  lsbMask = 1;
  while (a != b) {
    if (a & lsbMask) {
      if (b & lsbMask) {
        if (a < b) {
          b = (b - a) >> 1;
        } else {
          a = (a - b) >> 1;
        }
      } else {
        b >>= 1;
      }
    } else {
      if (b & lsbMask) {
        a >>= 1;
      } else {
        lsbMask <<= 1;
      }
    }
  }
  return (a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  je     L61
  mov    %edi,%eax
  test   %esi,%esi
  je     L61
  cmp    %esi,%edi
  je     L118
  mov    $0x1,%eax
  jmp    L123
L41:
  sub    %esi,%edi
  sar    %edi
  jmp    L129
L4:
  sar    %esi
L129:
  cmp    %edi,%esi
  je     L55
L123:
  test   %eax,%edi
  je     L29
  test   %eax,%esi
  je     L4
  cmp    %esi,%edi
  jge    L41
  sub    %edi,%esi
  sar    %esi
  jmp    L129
L29:
  test   %eax,%esi
  je     L53
  sar    %edi
  jmp    L129
L53:
  add    %eax,%eax
  jmp    L129
L55:
  mov    %edi,%eax
  ret
L118:
  mov    %esi,%eax
L61:
  ret
```

assistant: ```c
int gcd(int x, int y) {
  int a;
  int b;
  int lsbMask;
  if (x == 0)
    return (y);
  if (y == 0)
    return (x);
  a = x;
  b = y;
  lsbMask = 1;
  while (a != b) {
    if (a & lsbMask) {
      if (b & lsbMask) {
        if (a < b) {
          b = (b - a) >> 1;
        } else {
          a = (a - b) >> 1;
        }
      } else {
        b >>= 1;
      }
    } else {
      if (b & lsbMask) {
        a >>= 1;
      } else {
        lsbMask <<= 1;
      }
    }
  }
  return (a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  test   %edi,%edi
  je     L124
  mov    %edi,%eax
  test   %esi,%esi
  je     L124
  cmp    %esi,%edi
  je     L124
  mov    $0x1,%ecx
  jmp    L50
  nopl   (%rax)
L48:
  test   %esi,%esi
  je     L81
  cmp    %eax,%edx
  jle    L65
  sub    %eax,%edx
  sar    %edx
  nopl   0x0(%rax)
L12:
  cmp    %eax,%edx
  je     L124
L50:
  mov    %edx,%esi
  and    %ecx,%esi
  test   %eax,%ecx
  jne    L48
  test   %esi,%esi
  je     L67
  sar    %eax
  cmp    %eax,%edx
  jne    L50
L124:
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  sar    %edx
  jmp    L12
  nopl   0x0(%rax)
L67:
  add    %ecx,%ecx
  jmp    L12
  nopl   0x0(%rax)
L65:
  sub    %edx,%eax
  sar    %eax
  jmp    L12
```

assistant: ```c
int gcd(int x, int y) {
  int a;
  int b;
  int lsbMask;
  if (x == 0)
    return (y);
  if (y == 0)
    return (x);
  a = x;
  b = y;
  lsbMask = 1;
  while (a != b) {
    if (a & lsbMask) {
      if (b & lsbMask) {
        if (a < b) {
          b = (b - a) >> 1;
        } else {
          a = (a - b) >> 1;
        }
      } else {
        b >>= 1;
      }
    } else {
      if (b & lsbMask) {
        a >>= 1;
      } else {
        lsbMask <<= 1;
      }
    }
  }
  return (a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  test   %edi,%edi
  je     L85
  mov    %edi,%eax
  test   %esi,%esi
  je     L85
  cmp    %esi,%edi
  je     L85
  mov    $0x1,%ecx
  jmp    L44
  nopl   (%rax)
L78:
  test   %esi,%esi
  je     L13
  cmp    %eax,%edx
  jle    L70
  sub    %eax,%edx
  sar    %edx
  nopl   0x0(%rax)
L71:
  cmp    %eax,%edx
  je     L85
L44:
  mov    %edx,%esi
  and    %ecx,%esi
  test   %eax,%ecx
  jne    L78
  test   %esi,%esi
  je     L4
  sar    %eax
  cmp    %eax,%edx
  jne    L44
L85:
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  sar    %edx
  jmp    L71
  nopl   0x0(%rax)
L4:
  add    %ecx,%ecx
  jmp    L71
  nopl   0x0(%rax)
L70:
  sub    %edx,%eax
  sar    %eax
  jmp    L71
```

assistant: ```c
int gcd(int x, int y) {
  int a;
  int b;
  int lsbMask;
  if (x == 0)
    return (y);
  if (y == 0)
    return (x);
  a = x;
  b = y;
  lsbMask = 1;
  while (a != b) {
    if (a & lsbMask) {
      if (b & lsbMask) {
        if (a < b) {
          b = (b - a) >> 1;
        } else {
          a = (a - b) >> 1;
        }
      } else {
        b >>= 1;
      }
    } else {
      if (b & lsbMask) {
        a >>= 1;
      } else {
        lsbMask <<= 1;
      }
    }
  }
  return (a);
}
```
user: What is the c source code of the assembly code below:

```asm
<free_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_buffer(unsigned long *restrict *restrict buffer, unsigned long n) {
  unsigned long i;
  for (i = 0; i < n; i++)
    free(buffer[i]);
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  free((unsigned long **)buffer);
#pragma GCC diagnostic pop
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_buffer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rsi,%rsi
  je     L13
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%rbp
L2:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L2
L13:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_buffer(unsigned long *restrict *restrict buffer, unsigned long n) {
  unsigned long i;
  for (i = 0; i < n; i++)
    free(buffer[i]);
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  free((unsigned long **)buffer);
#pragma GCC diagnostic pop
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_buffer>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L12
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L13
L12:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_buffer(unsigned long *restrict *restrict buffer, unsigned long n) {
  unsigned long i;
  for (i = 0; i < n; i++)
    free(buffer[i]);
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  free((unsigned long **)buffer);
#pragma GCC diagnostic pop
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_buffer>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L19
L4:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_buffer(unsigned long *restrict *restrict buffer, unsigned long n) {
  unsigned long i;
  for (i = 0; i < n; i++)
    free(buffer[i]);
#pragma GCC diagnostic push
#pragma GCC diagnostic ignored "-Wcast-qual"
  free((unsigned long **)buffer);
#pragma GCC diagnostic pop
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <TEMP_main@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  TEMP_main(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <TEMP_main@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  TEMP_main(argc, argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <TEMP_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  TEMP_main(argc, argv);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <TEMP_main@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  TEMP_main(argc, argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcmpi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L48
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  xor    $0x20,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L39
L48:
  nop
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L17
  mov    $0x0,%eax
  jmp    L73
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  cmp    %al,%dl
  jge    L50
  mov    $0xffffffff,%eax
  jmp    L73
L50:
  mov    $0x1,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
int strcmpi(char *s1, char *s2) {
  int i;
  for (i = 0; s1[i] && s2[i]; ++i) {
    if (s1[i] == s2[i] || (s1[i] ^ 32) == s2[i])
      continue;
    else
      break;
  }
  if (s1[i] == s2[i])
    return 0;
  if ((s1[i] | 32) < (s2[i] | 32))
    return -1;
  return 1;
}
```