user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x271000(%rsp),%r11
L67:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L67
  sub    $0x48,%rsp
  mov    $0x138800,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x271038(%rsp)
  xor    %eax,%eax
  lea    0x138830(%rsp),%rax
  lea    0x2c(%rsp),%rbx
  mov    %rax,%rdi
  mov    %rax,0x10(%rsp)
  call   <memset@plt>
  lea    0x28(%rsp),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x28(%rsp),%eax
  mov    %rbx,0x18(%rsp)
  lea    -0x1(%rax),%edx
  mov    %edx,0x28(%rsp)
  test   %eax,%eax
  je     L154
L158:
  mov    0x18(%rsp),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L59
  lea    0x30(%rsp),%r12
  xor    %ebx,%ebx
  mov    %r12,%rbp
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %rbp,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x2c(%rsp),%r9d
  add    $0x8,%rbp
  cmp    %ebx,%r9d
  jg     L54
  lea    -0x1(%r9),%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x7,%rax
  add    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  cmp    $0x1,%r9d
  jle    L148
  xor    %r14d,%r14d
  mov    $0xfffffffffffff380,%rbx
  lea    0x1(%r9),%r15d
  xor    %edi,%edi
  lea    0x1394b0(%rsp),%rax
  lea    0xcb0(%rsp),%r13
  mov    $0x1,%ebp
  mov    %rax,(%rsp)
  mov    %rax,%r10
  nopl   0x0(%rax)
L68:
  mov    %ebp,%r8d
  mov    $0x1,%r11d
  nopl   0x0(%rax)
L137:
  mov    %rdi,(%r10)
  cmp    $0x1,%ebp
  je     L0
  lea    (%r10,%rbx,1),%rsi
  mov    %r11d,%ecx
  nop
L129:
  mov    %ecx,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rax
  mov    %r8d,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  add    %rax,%rdx
  mov    (%rsi),%rax
  add    0x138830(%rsp,%rdx,8),%rax
  cmp    %rdi,%rax
  jge    L104
  mov    %rax,(%r10)
  mov    %rax,%rdi
L104:
  add    $0x1,%ecx
  add    $0xc80,%rsi
  cmp    %ecx,%r8d
  jne    L129
L0:
  mov    %r8d,%eax
  add    $0x8,%r10
  add    $0x1,%r8d
  cltd
  idiv   %r9d
  mov    -0x8(%r12,%r11,8),%rax
  movslq %edx,%rdx
  add    0x30(%rsp,%rdx,8),%rax
  mov    %rax,-0x8(%r13,%r11,8)
  add    %rdi,%rax
  add    $0x1,%r11
  mov    %rax,-0x8(%r10)
  cmp    %r15,%r11
  je     L125
  lea    (%r10,%rbx,1),%rax
  mov    (%rax,%r14,1),%rdi
  jmp    L137
  nopl   0x0(%rax,%rax,1)
L125:
  add    $0x1,%ebp
  add    $0xc80,%r12
  add    $0xc80,%r13
  add    $0xc80,%r14
  cmp    %ebp,%r9d
  je     L136
  mov    (%rsp),%rax
  sub    $0xc80,%rbx
  mov    (%rax),%rdi
  add    $0xc80,%rax
  mov    %rax,(%rsp)
  mov    %rax,%r10
  jmp    L68
L136:
  mov    0x8(%rsp),%rbx
  lea    -0x2(%r9),%edx
  mov    (%rbx),%rsi
  lea    0x8(%rbx),%rax
  lea    0x10(%rbx,%rdx,8),%rcx
  nopw   0x0(%rax,%rax,1)
L64:
  mov    (%rax),%rdx
  cmp    %rdx,%rsi
  cmovg  %rdx,%rsi
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L64
L147:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x28(%rsp)
  test   %eax,%eax
  jne    L158
L154:
  mov    0x271038(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x271048,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  sub    $0x1,%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x7,%rax
  add    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
L148:
  mov    (%rax),%rsi
  jmp    L147
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
type_infered: string
name: parse_data
arguments: label: D38
type_infered: string
name: parse_data
arguments: label: D24
type_infered: string

tool: D31: %d

tool: D38: %lld

tool: D24: %lld


assistant: ```c
int main() {
  int t, n, i, j, k;
  long long tmp, a[400][400], p[400][400] = {};
  for (scanf("%d", &t); t--; printf("%lld\n", tmp)) {
    scanf("%d", &n);
    for (i = 0; i < n; ++i)
      scanf("%lld", *a + i);
    for (i = 1; i < n; ++i)
      for (j = 0; j < n; ++j) {
        p[i][j] = p[i - 1][j];
        for (k = 1; k < i; ++k) {
          tmp = p[k - 1][j] + p[i - k][(j + k) % n];
          if (tmp < p[i][j])
            p[i][j] = tmp;
        }
        p[i][j] += a[i][j] = a[i - 1][j] + a[0][(i + j) % n];
      }
    long long *m = p[n - 1];
    tmp = *m;
    for (i = 1; i < n; ++i)
      if (m[i] < tmp)
        tmp = m[i];
  }
  return 0;
}
```