ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<goodgbid>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L25
  xor    %ebx,%ebx
L34:
  call   <whatch@plt>
  cmp    $0x1,%eax
  je     L94
  cmp    $0x2,%eax
  je     L98
  test   %eax,%eax
  je     L36
L96:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L34
  mov    $0x1,%eax
  sub    %ebx,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L98:
  test   %ebx,%ebx
  je     L106
L74:
  xor    $0x1,%ebx
  jmp    L96
  nopl   0x0(%rax)
L94:
  test   %ebx,%ebx
  je     L96
  xor    %eax,%eax
  jmp    L36
L106:
  movsbl 0x0(%rbp),%edi
  call   <goodq@plt>
  test   %eax,%eax
  jne    L74
  xor    %eax,%eax
  jmp    L36
L25:
  mov    $0x1,%eax
  jmp    L36
```

assistant: ```c
int goodgbid(const char *userid) {
  int q = 0;
  const char *s;
  for (s = userid; *s != '\0'; s++) {
    switch (whatch(*s)) {
    case 0:
      return 0;
    case 1:
      if (q)
        return 0;
      break;
    case 2:
      if (!q && !goodq(*s))
        return 0;
      q = !q;
      break;
    }
  }
  if (q)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <tmp_name@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: Name: %s


assistant: ```c
int main() {
  char *tmp_name(void);
  printf("Name: %s\n", tmp_name());
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tmp_name@plt>
  mov    %rax,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: Name: %s


assistant: ```c
int main() {
  char *tmp_name(void);
  printf("Name: %s\n", tmp_name());
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tmp_name@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: Name: %s


assistant: ```c
int main() {
  char *tmp_name(void);
  printf("Name: %s\n", tmp_name());
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <tmp_name@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: Name: %s


assistant: ```c
int main() {
  char *tmp_name(void);
  printf("Name: %s\n", tmp_name());
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<merge_parts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %esi,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L63:
  cmp    %rdx,%rsp
  je     L50
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L63
L50:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L47
  orq    $0x0,-0x8(%rsp,%rax,1)
L47:
  mov    %rsp,%r10
  mov    %r11d,%r8d
  shr    $0x1f,%r8d
  add    %r11d,%r8d
  sar    %r8d
  test   %r8d,%r8d
  mov    $0x1,%eax
  cmovg  %r8d,%eax
  cmp    %eax,%r11d
  jle    L81
  mov    %r8d,%edx
  mov    $0x1,%esi
  mov    $0x0,%eax
  jmp    L22
L129:
  add    $0x1,%edx
  mov    %r9d,%edi
L106:
  mov    %esi,%r9d
  mov    %edi,-0x4(%r10,%rsi,4)
  add    $0x1,%rsi
  cmp    %r8d,%eax
  jge    L128
  cmp    %r11d,%edx
  jge    L128
L22:
  movslq %eax,%rdi
  mov    (%rcx,%rdi,4),%edi
  movslq %edx,%r9
  mov    (%rcx,%r9,4),%r9d
  cmp    %r9d,%edi
  jge    L129
  add    $0x1,%eax
  jmp    L106
L81:
  mov    %r8d,%edx
  mov    $0x0,%r9d
  mov    $0x0,%eax
L128:
  cmp    %eax,%r8d
  jle    L36
  cltq
  movslq %r9d,%r9
  sub    %rax,%r9
  lea    (%r10,%r9,4),%rdi
L23:
  mov    (%rcx,%rax,4),%esi
  mov    %esi,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L23
L36:
  test   %edx,%edx
  jle    L83
  mov    %edx,%edx
  mov    $0x0,%eax
L110:
  mov    (%r10,%rax,4),%esi
  mov    %esi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L110
L83:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  leave
  ret
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_parts(int arr[], int length) {
  int ans[length];
  int mid = length / 2;
  int i = 0, k = 0, j = mid;
  while (i < mid && j < length) {
    ans[k++] = (arr[i] < arr[j]) ? arr[i++] : arr[j++];
  }
  while (i < mid) {
    ans[k++] = arr[i++];
  }
  for (i = 0; i < j; i++) {
    arr[i] = ans[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<merge_parts>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L61
L27:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L27
L61:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L53
L117:
  mov    %r8d,%edi
  mov    $0x1,%eax
  mov    %rsp,%r13
  shr    $0x1f,%edi
  add    %r8d,%edi
  sar    %edi
  test   %edi,%edi
  mov    %edi,%ebx
  cmovg  %edi,%eax
  cmp    %eax,%r8d
  jle    L100
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L8
  nopl   0x0(%rax)
L102:
  add    $0x1,%edx
  mov    %ecx,-0x4(%r13,%rax,4)
  movslq %eax,%rsi
  add    $0x1,%rax
  cmp    %edi,%edx
  jge    L64
L119:
  cmp    %r8d,%ebx
  jge    L64
L8:
  movslq %edx,%rcx
  movslq %ebx,%rsi
  mov    (%r12,%rcx,4),%ecx
  mov    (%r12,%rsi,4),%esi
  cmp    %esi,%ecx
  jl     L102
  mov    %esi,%ecx
  add    $0x1,%ebx
  movslq %eax,%rsi
  mov    %ecx,-0x4(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %edi,%edx
  jl     L119
L64:
  cmp    %edx,%edi
  jle    L63
  sub    $0x1,%edi
  lea    0x0(%r13,%rsi,4),%r8
  sub    %edx,%edi
  movslq %edx,%rdx
  lea    0x4(,%rdi,4),%r9
  lea    (%r12,%rdx,4),%rsi
  mov    %r8,%rdi
  mov    %r9,%rdx
  call   <memcpy@plt>
L63:
  test   %ebx,%ebx
  jle    L116
  movslq %ebx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L116:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L117
L100:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L64
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_parts(int arr[], int length) {
  int ans[length];
  int mid = length / 2;
  int i = 0, k = 0, j = mid;
  while (i < mid && j < length) {
    ans[k++] = (arr[i] < arr[j]) ? arr[i++] : arr[j++];
  }
  while (i < mid) {
    ans[k++] = arr[i++];
  }
  for (i = 0; i < j; i++) {
    arr[i] = ans[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<merge_parts>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L102
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L102:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L27:
  mov    %r8d,%edi
  mov    $0x1,%eax
  mov    %rsp,%r13
  shr    $0x1f,%edi
  add    %r8d,%edi
  sar    %edi
  test   %edi,%edi
  mov    %edi,%ebx
  cmovg  %edi,%eax
  cmp    %eax,%r8d
  jle    L2
  mov    $0x1,%eax
  xor    %edx,%edx
  xor    %r10d,%r10d
  movslq %edi,%r9
  nopl   0x0(%rax)
L94:
  mov    (%r12,%r10,4),%esi
  mov    (%r12,%r9,4),%ecx
  cmp    %esi,%ecx
  jle    L116
L147:
  mov    %esi,-0x4(%r13,%rax,4)
  movslq %eax,%r11
  add    $0x1,%edx
  add    $0x1,%rax
  cmp    %r8d,%ebx
  jge    L61
  cmp    %edi,%edx
  jge    L61
  movslq %edx,%r10
  mov    (%r12,%r9,4),%ecx
  mov    (%r12,%r10,4),%esi
  cmp    %esi,%ecx
  jg     L147
L116:
  mov    %ecx,-0x4(%r13,%rax,4)
  movslq %eax,%r11
  add    $0x1,%ebx
  add    $0x1,%rax
  cmp    %edx,%edi
  jle    L44
  cmp    %r8d,%ebx
  jge    L61
  movslq %ebx,%r9
  jmp    L94
L2:
  xor    %r11d,%r11d
  xor    %edx,%edx
  nopl   (%rax)
L61:
  cmp    %edx,%edi
  jle    L44
  sub    $0x1,%edi
  lea    0x0(%r13,%r11,4),%r8
  sub    %edx,%edi
  movslq %edx,%rdx
  lea    0x4(,%rdi,4),%r9
  lea    (%r12,%rdx,4),%rsi
  mov    %r8,%rdi
  mov    %r9,%rdx
  call   <memcpy@plt>
L44:
  test   %ebx,%ebx
  jle    L114
  movslq %ebx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L114:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L27
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge_parts(int arr[], int length) {
  int ans[length];
  int mid = length / 2;
  int i = 0, k = 0, j = mid;
  while (i < mid && j < length) {
    ans[k++] = (arr[i] < arr[j]) ? arr[i++] : arr[j++];
  }
  while (i < mid) {
    ans[k++] = arr[i++];
  }
  for (i = 0; i < j; i++) {
    arr[i] = ans[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<emit_cmpeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0xfffffffe,%esi
  mov    %eax,%edi
  call   <emit_andimm@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmp@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_orreq_imm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_cmpeq(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s1, s2);
  emit_orreq_imm(sr, 1, sr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<emit_cmpeq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    $0xfffffffe,%esi
  mov    %edx,%edi
  call   <emit_andimm@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <emit_cmp@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_orreq_imm@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void emit_cmpeq(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s1, s2);
  emit_orreq_imm(sr, 1, sr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_cmpeq>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xfffffffe,%esi
  push   %r12
  mov    %edi,%r12d
  mov    %edx,%edi
  push   %rbp
  mov    %edx,%ebp
  call   <emit_andimm@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmp@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <emit_orreq_imm@plt>
```

assistant: ```c
void emit_cmpeq(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s1, s2);
  emit_orreq_imm(sr, 1, sr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<emit_cmpeq>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0xfffffffe,%esi
  push   %r12
  mov    %edi,%r12d
  mov    %edx,%edi
  push   %rbp
  mov    %edx,%ebp
  call   <emit_andimm@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmp@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <emit_orreq_imm@plt>
```

assistant: ```c
void emit_cmpeq(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s1, s2);
  emit_orreq_imm(sr, 1, sr);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L39:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L19:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L34:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L34
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D44
type: string
name: unpack_data
arguments: data_tag: D21
type: string

tool: D0: %d

tool: D5: %d %d

tool: D44: yes


tool: D21: no


assistant: ```c
int main(void) {
  int T;
  scanf("%d", &T);
  for (int i = 0; i < T; i++) {
    int n, m;
    scanf("%d %d", &n, &m);
    if (n % 2 == 0) {
      printf("yes\n");
    } else {
      printf("no\n");
    }
    for (int j = 0; j < m; j++) {
      int u, v;
      scanf("%d %d", &u, &v);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L77
  mov    $0x0,%r12d
  lea    0xc(%rsp),%r13
  lea    D33(%rip),%rbp
  lea    D10(%rip),%r15
  lea    D11(%rip),%r14
  jmp    L76
L5:
  mov    %r15,%rdi
  call   <printf@plt>
L62:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jle    L55
L46:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L46
L55:
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jle    L77
L76:
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  testb  $0x1,0x8(%rsp)
  jne    L5
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L62
L77:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D33
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D11
data_type: string

tool: D4: %d

tool: D33: %d %d

tool: D10: no


tool: D11: yes


assistant: ```c
int main(void) {
  int T;
  scanf("%d", &T);
  for (int i = 0; i < T; i++) {
    int n, m;
    scanf("%d %d", &n, &m);
    if (n % 2 == 0) {
      printf("yes\n");
    } else {
      printf("no\n");
    }
    for (int j = 0; j < m; j++) {
      int u, v;
      scanf("%d %d", &u, &v);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L19
  lea    0x18(%rsp),%rax
  xor    %r13d,%r13d
  lea    0x1c(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%rbp
  lea    D3(%rip),%rbx
  xchg   %ax,%ax
L64:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    %r15,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  testb  $0x1,0x18(%rsp)
  jne    L9
  lea    D39(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x1c(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  jle    L21
L4:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jg     L4
L21:
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jg     L64
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D32
type_guessed: string
name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D39
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D32: %d

tool: D3: %d %d

tool: D39: yes


tool: D13: no


assistant: ```c
int main(void) {
  int T;
  scanf("%d", &T);
  for (int i = 0; i < T; i++) {
    int n, m;
    scanf("%d %d", &n, &m);
    if (n % 2 == 0) {
      printf("yes\n");
    } else {
      printf("no\n");
    }
    for (int j = 0; j < m; j++) {
      int u, v;
      scanf("%d %d", &u, &v);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L49
  lea    0x18(%rsp),%rax
  xor    %r13d,%r13d
  lea    0x1c(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%rbp
  lea    D31(%rip),%rbx
  xchg   %ax,%ax
L57:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    %r15,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  testb  $0x1,0x18(%rsp)
  jne    L61
  lea    D34(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x1c(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  jle    L51
L45:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jg     L45
L51:
  add    $0x1,%r13d
  cmp    %r13d,0x14(%rsp)
  jg     L57
L49:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D31
datatype: string
name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string

tool: D12: %d

tool: D31: %d %d

tool: D34: yes


tool: D6: no


assistant: ```c
int main(void) {
  int T;
  scanf("%d", &T);
  for (int i = 0; i < T; i++) {
    int n, m;
    scanf("%d %d", &n, &m);
    if (n % 2 == 0) {
      printf("yes\n");
    } else {
      printf("no\n");
    }
    for (int j = 0; j < m; j++) {
      int u, v;
      scanf("%d %d", &u, &v);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<file_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x2d0,%rsp
  mov    %rdi,-0x2c8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c0(%rbp)
  movl   $0x0,-0x2bc(%rbp)
  mov    -0x2c8(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x2c8(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x2b8(%rbp)
  cmpq   $0x0,-0x2b8(%rbp)
  je     L52
  jmp    L43
L22:
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rdi
  call   <check_upper_case@plt>
  mov    %eax,-0x2bc(%rbp)
  cmpl   $0x0,-0x2bc(%rbp)
  je     L15
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L51
L15:
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rdi
  call   <convert_to_int@plt>
L43:
  mov    -0x2b8(%rbp),%rdx
  lea    -0x2b0(%rbp),%rax
  mov    $0x2a8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L22
L51:
  mov    -0x2b8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  jmp    L65
L52:
  mov    -0x2c8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L65:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string

tool: D39: config file is: %s


tool: D25: r

tool: D22: Error!!!there is a upper case 'X' in config file 
Line: %s


tool: D19: can not open file in:%s

assistant: ```c
int file_parse(char *path) {
  FILE *filed;
  char tmp[680];
  int test = 0;
  int ret = 0;
  printf("config file is: %s\n", path);
  filed = fopen(path, "r");
  if (filed != NULL) {
    while (fgets(tmp, 680, filed) != NULL) {
      ret = check_upper_case(tmp);
      if (ret != 0) {
        printf("Error!!!there is a upper case 'X' in config file \nLine: %s\n", tmp);
        break;
      } else
        convert_to_int(tmp);
    }
    fclose(filed);
    return 0;
  } else {
    printf("can not open file in:%s", path);
    return 0;
  }
}
```