ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_vendor>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0x0,%edi
  call   <__get_cpuid@plt>
  test   %eax,%eax
  jne    L11
  lea    D5(%rip),%rdi
  call   <puts@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x14(%rsp),%rsi
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rbx),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  jmp    L4
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: =(

assistant: ```c
char *get_vendor(char *s) {
  unsigned int a = 0;
  unsigned int b, c, d = 0;
  if (!__get_cpuid(0, &a, &b, &c, &d))
    puts("=(");
  else {
    memcpy(s, &b, 4);
    memcpy(s + 4, &d, 4);
    memcpy(s + 8, &c, 4);
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_vendor>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%rsi
  mov    %r13,%r8
  mov    %rbp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r14,%rdx
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <__get_cpuid@plt>
  test   %eax,%eax
  jne    L11
  lea    D2(%rip),%rdi
  call   <puts@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L11:
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x4(%r12),%rdi
  mov    %r13,%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x8(%r12),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: =(

assistant: ```c
char *get_vendor(char *s) {
  unsigned int a = 0;
  unsigned int b, c, d = 0;
  if (!__get_cpuid(0, &a, &b, &c, &d))
    puts("=(");
  else {
    memcpy(s, &b, 4);
    memcpy(s + 4, &d, 4);
    memcpy(s + 8, &c, 4);
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_vendor>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%rsi
  mov    %r13,%r8
  mov    %rbp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r14,%rdx
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <__get_cpuid@plt>
  test   %eax,%eax
  jne    L13
  lea    D7(%rip),%rdi
  call   <puts@plt>
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L13:
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x4(%r12),%rdi
  mov    %r13,%rsi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x8(%r12),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L12
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: =(

assistant: ```c
char *get_vendor(char *s) {
  unsigned int a = 0;
  unsigned int b, c, d = 0;
  if (!__get_cpuid(0, &a, &b, &c, &d))
    puts("=(");
  else {
    memcpy(s, &b, 4);
    memcpy(s + 4, &d, 4);
    memcpy(s + 8, &c, 4);
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<absy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %rcx,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%esi
  mov    -0x128(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x130(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %esi,%r8d
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rcx
  mov    -0x128(%rbp),%rdx
  mov    -0x120(%rbp),%rsi
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <lineprint3@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: %-4s $%02X%02X,Y

assistant: ```c
void absy(char *outf, long ctr, unsigned char *op, char *str) {
  char buf[256];
  sprintf(buf, "%-4s $%02X%02X,Y", str, *(op + 2), *(op + 1));
  lineprint3(outf, ctr, op, buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<absy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movzbl 0x2(%rbx),%ecx
  mov    %rsp,%r13
  movzbl 0x1(%rbx),%r8d
  lea    D5(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lineprint3@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: %-4s $%02X%02X,Y

assistant: ```c
void absy(char *outf, long ctr, unsigned char *op, char *str) {
  char buf[256];
  sprintf(buf, "%-4s $%02X%02X,Y", str, *(op + 2), *(op + 1));
  lineprint3(outf, ctr, op, buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<absy>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D2(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  mov    %rcx,%rdx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  movzbl 0x2(%r12),%ecx
  movzbl 0x1(%r12),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <lineprint3@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string

tool: D2: %-4s $%02X%02X,Y

assistant: ```c
void absy(char *outf, long ctr, unsigned char *op, char *str) {
  char buf[256];
  sprintf(buf, "%-4s $%02X%02X,Y", str, *(op + 2), *(op + 1));
  lineprint3(outf, ctr, op, buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<absy>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D9(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  mov    %rcx,%rdx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  movzbl 0x2(%r12),%ecx
  movzbl 0x1(%r12),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <lineprint3@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %-4s $%02X%02X,Y

assistant: ```c
void absy(char *outf, long ctr, unsigned char *op, char *str) {
  char buf[256];
  sprintf(buf, "%-4s $%02X%02X,Y", str, *(op + 2), *(op + 1));
  lineprint3(outf, ctr, op, buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L23
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L31
  addl   $0x1,-0xc(%rbp)
  jmp    L47
L31:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L9
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
L23:
  nop
  leave
  ret
```

assistant: ```c
void sort(int arr[], int beg, int end) {
  if (end > beg + 1) {
    int piv = arr[beg], l = beg + 1, r = end;
    while (l < r) {
      if (arr[l] <= piv)
        l++;
      else
        swap(&arr[l], &arr[--r]);
    }
    swap(&arr[--l], &arr[beg]);
    sort(arr, beg, l);
    sort(arr, r, end);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    0x1(%rsi),%ebx
  cmp    %edx,%ebx
  jge    L16
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r13d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    (%rax),%r15d
  mov    %edx,%r12d
  jmp    L40
L39:
  add    $0x1,%ebx
L5:
  cmp    %ebx,%r12d
  jle    L20
L40:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  cmp    %r15d,(%rdi)
  jle    L39
  sub    $0x1,%r12d
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swap@plt>
  jmp    L5
L20:
  sub    $0x1,%ebx
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  mov    0x8(%rsp),%rsi
  call   <swap@plt>
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <sort>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sort>
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(int arr[], int beg, int end) {
  if (end > beg + 1) {
    int piv = arr[beg], l = beg + 1, r = end;
    while (l < r) {
      if (arr[l] <= piv)
        l++;
      else
        swap(&arr[l], &arr[--r]);
    }
    swap(&arr[--l], &arr[beg]);
    sort(arr, beg, l);
    sort(arr, r, end);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi),%ebx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%ebx
  jge    L60
L19:
  movslq %r13d,%rax
  mov    0xc(%rsp),%ebp
  lea    (%r14,%rax,4),%r15
  mov    (%r15),%r12d
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jle    L21
L58:
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rdi
  cmp    %r12d,(%rdi)
  jle    L35
  sub    $0x1,%ebp
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%rsi
  call   <swap@plt>
  cmp    %ebx,%ebp
  jg     L58
L21:
  lea    -0x1(%rbx),%r12d
  mov    %r15,%rsi
  lea    0x1(%rbp),%ebx
  movslq %r12d,%rax
  lea    (%r14,%rax,4),%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <sort>
  cmp    0xc(%rsp),%ebx
  jge    L60
  mov    %ebp,%r13d
  jmp    L19
  nopl   (%rax)
L60:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(int arr[], int beg, int end) {
  if (end > beg + 1) {
    int piv = arr[beg], l = beg + 1, r = end;
    while (l < r) {
      if (arr[l] <= piv)
        l++;
      else
        swap(&arr[l], &arr[--r]);
    }
    swap(&arr[--l], &arr[beg]);
    sort(arr, beg, l);
    sort(arr, r, end);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x9(%rbp),%eax
  sub    $0x20,%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  sub    $0x20,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string

tool: D17: %c

tool: D24: %c %d


assistant: ```c
int main() {
  char ch;
  scanf("%c", &ch);
  printf("%c %d\n", ch, ch);
  printf("%c %d\n", ch - 32, ch - 32);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %esi,%edx
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  mov    %esi,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string

tool: D4: %c

tool: D13: %c %d


assistant: ```c
int main() {
  char ch;
  scanf("%c", &ch);
  printf("%c %d\n", ch, ch);
  printf("%c %d\n", ch - 32, ch - 32);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %rbp,%rdi
  mov    %esi,%edx
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string

tool: D18: %c

tool: D10: %c %d


assistant: ```c
int main() {
  char ch;
  scanf("%c", &ch);
  printf("%c %d\n", ch, ch);
  printf("%c %d\n", ch - 32, ch - 32);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D5(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %rbp,%rdi
  mov    %esi,%edx
  call   <printf@plt>
  movzbl 0x7(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x20(%rax),%esi
  movsbl %sil,%esi
  mov    %esi,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D0: %c

tool: D5: %c %d


assistant: ```c
int main() {
  char ch;
  scanf("%c", &ch);
  printf("%c %d\n", ch, ch);
  printf("%c %d\n", ch - 32, ch - 32);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L26:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  imul   -0x10(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x2,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L26
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string

tool: D28: Enter the number of terms you want to sum up: 

tool: D27: %d

tool: D29: 
The sum of the series is %d

assistant: ```c
int main(void) {
  int n, sum = 0, num = 1;
  printf("Enter the number of terms you want to sum up: ");
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    sum += (num * (num + 1));
    num += 2;
  }
  printf("\nThe sum of the series is %d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  lea    0x1(%rax,%rax,1),%ecx
  mov    $0x1,%eax
  mov    $0x0,%esi
L3:
  lea    0x1(%rax),%edx
  imul   %eax,%edx
  add    %edx,%esi
  add    $0x2,%eax
  cmp    %ecx,%eax
  jne    L3
L9:
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L30:
  mov    $0x0,%esi
  jmp    L9
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string

tool: D16: Enter the number of terms you want to sum up: 

tool: D0: %d

tool: D21: 
The sum of the series is %d

assistant: ```c
int main(void) {
  int n, sum = 0, num = 1;
  printf("Enter the number of terms you want to sum up: ");
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    sum += (num * (num + 1));
    num += 2;
  }
  printf("\nThe sum of the series is %d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L4
  lea    0x1(%rax,%rax,1),%ecx
  xor    %esi,%esi
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x1(%rax),%edx
  imul   %eax,%edx
  add    $0x2,%eax
  add    %edx,%esi
  cmp    %ecx,%eax
  jne    L29
L39:
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  xor    %esi,%esi
  jmp    L39
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D12: Enter the number of terms you want to sum up: 

tool: D1: %d

tool: D7: 
The sum of the series is %d

assistant: ```c
int main(void) {
  int n, sum = 0, num = 1;
  printf("Enter the number of terms you want to sum up: ");
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    sum += (num * (num + 1));
    num += 2;
  }
  printf("\nThe sum of the series is %d", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L3
  mov    -0x4(%rbp),%eax
  jmp    L18
L3:
  mov    -0x8(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max(int a, int b) {
  if (a > b)
    return a;
  else
    return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L3:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x8,%rax
  mov    %rax,%rcx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int load_long(unsigned char *c, int nbytes, unsigned long *l) {
  int i;
  *l = 0;
  for (i = 0; i < nbytes; i++)
    *l = (*l << 8) + (c[i] & 0xff);
  return nbytes;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<load_long>:
  endbr64
  mov    %esi,%eax
  movq   $0x0,(%rdx)
  test   %esi,%esi
  jle    L16
  mov    %rdi,%r8
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%r9
L2:
  mov    (%rdx),%rcx
  shl    $0x8,%rcx
  movzbl (%r8),%edi
  add    %rdi,%rcx
  mov    %rcx,(%rdx)
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L2
L16:
  ret
```

assistant: ```c
int load_long(unsigned char *c, int nbytes, unsigned long *l) {
  int i;
  *l = 0;
  for (i = 0; i < nbytes; i++)
    *l = (*l << 8) + (c[i] & 0xff);
  return nbytes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_long>:
  endbr64
  movq   $0x0,(%rdx)
  mov    %esi,%eax
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%r9
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L15:
  movzbl (%rdi),%r8d
  shl    $0x8,%rcx
  add    $0x1,%rdi
  add    %r8,%rcx
  mov    %rcx,(%rdx)
  cmp    %r9,%rdi
  jne    L15
L12:
  ret
```

assistant: ```c
int load_long(unsigned char *c, int nbytes, unsigned long *l) {
  int i;
  *l = 0;
  for (i = 0; i < nbytes; i++)
    *l = (*l << 8) + (c[i] & 0xff);
  return nbytes;
}
```