ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0xfb,%ecx
  lea    D17(%rip),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <libcgi_error@plt>
  mov    $0x0,%eax
  jmp    L1
L7:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D17: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c

tool: D9: %s, line %s

assistant: ```c
char *substr(char *src, const int start, const int count) {
  char *tmp;
  tmp = (char *)malloc(count + 1);
  if (tmp == NULL) {
    libcgi_error(4, "%s, line %s", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c", 251);
    return NULL;
  }
  strncpy(tmp, src + start, count);
  tmp[count] = '\0';
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<substr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L6
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%r13,%rbx,1)
L15:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    $0xfb,%ecx
  lea    D9(%rip),%rdx
  lea    D18(%rip),%rsi
  mov    $0x4,%edi
  call   <libcgi_error@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c

tool: D18: %s, line %s

assistant: ```c
char *substr(char *src, const int start, const int count) {
  char *tmp;
  tmp = (char *)malloc(count + 1);
  if (tmp == NULL) {
    libcgi_error(4, "%s, line %s", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c", 251);
    return NULL;
  }
  strncpy(tmp, src + start, count);
  tmp[count] = '\0';
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substr>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    $0xfb,%ecx
  lea    D2(%rip),%rdx
  mov    $0x4,%edi
  lea    D16(%rip),%rsi
  call   <libcgi_error@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c

tool: D16: %s, line %s

assistant: ```c
char *substr(char *src, const int start, const int count) {
  char *tmp;
  tmp = (char *)malloc(count + 1);
  if (tmp == NULL) {
    libcgi_error(4, "%s, line %s", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c", 251);
    return NULL;
  }
  strncpy(tmp, src + start, count);
  tmp[count] = '\0';
  return tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<substr>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x1(%rbx),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xfb,%ecx
  lea    D3(%rip),%rdx
  mov    $0x4,%edi
  lea    D14(%rip),%rsi
  call   <libcgi_error@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D14
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c

tool: D14: %s, line %s

assistant: ```c
char *substr(char *src, const int start, const int count) {
  char *tmp;
  tmp = (char *)malloc(count + 1);
  if (tmp == NULL) {
    libcgi_error(4, "%s, line %s", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/ingran/balzac/refs/heads/master/package/libs/libcgi-1.0/src/string.c", 251);
    return NULL;
  }
  strncpy(tmp, src + start, count);
  tmp[count] = '\0';
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x50(%rbp)
  movl   $0x2,-0x4c(%rbp)
  movl   $0x4,-0x48(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0x6,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  lea    -0x30(%rbp),%rsi
  lea    -0x50(%rbp),%rax
  mov    $0x6,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <buildTree@plt>
  mov    %rax,-0x58(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <printInorder@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: Inorder traversal of the constructed tree is 


assistant: ```c
int main() {
  int in[] = {3, 2, 4, 1, 6, 5, 7};
  int pre[] = {1, 2, 3, 4, 5, 6, 7};
  struct node *root = buildTree(in, pre, 0, 6);
  printf("Inorder traversal of the constructed tree is \n");
  printInorder(root);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x6,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x2,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x4,0x2c(%rsp)
  movl   $0x5,0x30(%rsp)
  movl   $0x6,0x34(%rsp)
  movl   $0x7,0x38(%rsp)
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x6,%ecx
  mov    $0x0,%edx
  call   <buildTree@plt>
  mov    %rax,%rbx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printInorder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: Inorder traversal of the constructed tree is 


assistant: ```c
int main() {
  int in[] = {3, 2, 4, 1, 6, 5, 7};
  int pre[] = {1, 2, 3, 4, 5, 6, 7};
  struct node *root = buildTree(in, pre, 0, 6);
  printf("Inorder traversal of the constructed tree is \n");
  printInorder(root);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x6,%ecx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000003,%rax
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x7,0x18(%rsp)
  movl   $0x7,0x38(%rsp)
  mov    %rax,(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000006,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x30(%rsp)
  call   <buildTree@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printInorder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: Inorder traversal of the constructed tree is 


assistant: ```c
int main() {
  int in[] = {3, 2, 4, 1, 6, 5, 7};
  int pre[] = {1, 2, 3, 4, 5, 6, 7};
  struct node *root = buildTree(in, pre, 0, 6);
  printf("Inorder traversal of the constructed tree is \n");
  printInorder(root);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x6,%ecx
  sub    $0x50,%rsp
  movdqa D30(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D43(%rip),%rax
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  mov    D42(%rip),%rax
  movaps %xmm0,0x20(%rsp)
  movl   $0x7,0x18(%rsp)
  mov    %rax,0x30(%rsp)
  movl   $0x7,0x38(%rsp)
  call   <buildTree@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printInorder@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D30
type: byte[16]
name: read_data
arguments: tag: D43
type: byte[8]
name: read_data
arguments: tag: D26
type: byte[16]
name: read_data
arguments: tag: D42
type: byte[8]
name: read_data
arguments: tag: D6
type: string

tool: {"D30": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D43": [0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D26": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D42": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D6: Inorder traversal of the constructed tree is 


assistant: ```c
int main() {
  int in[] = {3, 2, 4, 1, 6, 5, 7};
  int pre[] = {1, 2, 3, 4, 5, 6, 7};
  struct node *root = buildTree(in, pre, 0, 6);
  printf("Inorder traversal of the constructed tree is \n");
  printInorder(root);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <pint@plt>
  mov    $0x0,%eax
  call   <pch@plt>
  mov    $0x0,%eax
  call   <pflt@plt>
  mov    $0x0,%eax
  call   <pdbl@plt>
  mov    $0x0,%eax
  call   <plong@plt>
  mov    $0x0,%eax
  call   <pstruct@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  pint();
  pch();
  pflt();
  pdbl();
  plong();
  pstruct();
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pint@plt>
  mov    $0x0,%eax
  call   <pch@plt>
  mov    $0x0,%eax
  call   <pflt@plt>
  mov    $0x0,%eax
  call   <pdbl@plt>
  mov    $0x0,%eax
  call   <plong@plt>
  mov    $0x0,%eax
  call   <pstruct@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  pint();
  pch();
  pflt();
  pdbl();
  plong();
  pstruct();
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pint@plt>
  xor    %eax,%eax
  call   <pch@plt>
  xor    %eax,%eax
  call   <pflt@plt>
  xor    %eax,%eax
  call   <pdbl@plt>
  xor    %eax,%eax
  call   <plong@plt>
  xor    %eax,%eax
  call   <pstruct@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  pint();
  pch();
  pflt();
  pdbl();
  plong();
  pstruct();
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pint@plt>
  xor    %eax,%eax
  call   <pch@plt>
  xor    %eax,%eax
  call   <pflt@plt>
  xor    %eax,%eax
  call   <pdbl@plt>
  xor    %eax,%eax
  call   <plong@plt>
  xor    %eax,%eax
  call   <pstruct@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  pint();
  pch();
  pflt();
  pdbl();
  plong();
  pstruct();
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<position_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  jmp    L22
L17:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <equal_list@plt>
  test   %rax,%rax
  je     L22
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L31
L22:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int position_list(int *matrix, int m, int *row, int n) {
  while (m--) {
    if (equal_list(matrix + m * n, row, n))
      return (m + 1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<position_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r14
  mov    %ecx,%r12d
  mov    %esi,%ebx
  mov    %ecx,%r13d
  neg    %r13d
  movslq %r13d,%r13
  shl    $0x2,%r13
  sub    $0x1,%esi
  imul   %ecx,%esi
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rbp
L22:
  mov    %ebx,%r15d
  test   %ebx,%ebx
  je     L4
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <equal_list@plt>
  sub    $0x1,%ebx
  add    %r13,%rbp
  test   %rax,%rax
  je     L22
  jmp    L5
L4:
  mov    $0x0,%r15d
L5:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int position_list(int *matrix, int m, int *row, int n) {
  while (m--) {
    if (equal_list(matrix + m * n, row, n))
      return (m + 1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<position_list>:
  endbr64
  lea    -0x1(%rsi),%eax
  push   %r15
  imul   %ecx,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  neg    %r13d
  mov    %ecx,%r12d
  push   %rbp
  movslq %r13d,%r13
  cltq
  push   %rbx
  shl    $0x2,%r13
  mov    %esi,%ebx
  lea    (%rdi,%rax,4),%rbp
  sub    $0x8,%rsp
  jmp    L17
  nopl   (%rax)
L26:
  mov    %rbp,%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  sub    $0x1,%ebx
  call   <equal_list@plt>
  add    %r13,%rbp
  test   %rax,%rax
  jne    L6
L17:
  mov    %ebx,%r15d
  test   %ebx,%ebx
  jne    L26
L6:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int position_list(int *matrix, int m, int *row, int n) {
  while (m--) {
    if (equal_list(matrix + m * n, row, n))
      return (m + 1);
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<position_list>:
  endbr64
  lea    -0x1(%rsi),%eax
  push   %r15
  imul   %ecx,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  neg    %r13d
  mov    %ecx,%r12d
  push   %rbp
  movslq %r13d,%r13
  cltq
  push   %rbx
  shl    $0x2,%r13
  mov    %esi,%ebx
  lea    (%rdi,%rax,4),%rbp
  sub    $0x8,%rsp
  jmp    L21
  nopl   (%rax)
L2:
  mov    %rbp,%rdi
  mov    %r12d,%edx
  mov    %r14,%rsi
  sub    $0x1,%ebx
  call   <equal_list@plt>
  add    %r13,%rbp
  test   %rax,%rax
  jne    L12
L21:
  mov    %ebx,%r15d
  test   %ebx,%ebx
  jne    L2
L12:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int position_list(int *matrix, int m, int *row, int n) {
  while (m--) {
    if (equal_list(matrix + m * n, row, n))
      return (m + 1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int *ip = (int *)malloc(50 * sizeof(int));
  double *dp = malloc(1000 * sizeof(double));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *ip = (int *)malloc(50 * sizeof(int));
  double *dp = malloc(1000 * sizeof(double));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    $0x1f40,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *ip = (int *)malloc(50 * sizeof(int));
  double *dp = malloc(1000 * sizeof(double));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    $0x1f40,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *ip = (int *)malloc(50 * sizeof(int));
  double *dp = malloc(1000 * sizeof(double));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reallocUint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L24
L15:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L24:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8: Memory allocation error.


assistant: ```c
uint32_t *reallocUint(uint32_t *old, uintptr_t numUints) {
  {};
  uint32_t *new = NULL;
  if (numUints == 0) {
    free(old);
  } else {
    new = realloc(old, numUints * sizeof(uint32_t));
    if (new == NULL) {
      fatal("Memory allocation error.\n");
    }
  }
  {};
  return new;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reallocUint>:
  endbr64
  push   %rbx
  test   %rsi,%rsi
  je     L33
  shl    $0x2,%rsi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L29:
  mov    %rbx,%rax
  pop    %rbx
  ret
L33:
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L29
L28:
  lea    D1(%rip),%rdi
  call   <fatal@plt>
  jmp    L29
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: Memory allocation error.


assistant: ```c
uint32_t *reallocUint(uint32_t *old, uintptr_t numUints) {
  {};
  uint32_t *new = NULL;
  if (numUints == 0) {
    free(old);
  } else {
    new = realloc(old, numUints * sizeof(uint32_t));
    if (new == NULL) {
      fatal("Memory allocation error.\n");
    }
  }
  {};
  return new;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reallocUint>:
  endbr64
  push   %r12
  test   %rsi,%rsi
  je     L7
  shl    $0x2,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L17:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  call   <free@plt>
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  lea    D1(%rip),%rdi
  call   <fatal@plt>
  jmp    L17
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: Memory allocation error.


assistant: ```c
uint32_t *reallocUint(uint32_t *old, uintptr_t numUints) {
  {};
  uint32_t *new = NULL;
  if (numUints == 0) {
    free(old);
  } else {
    new = realloc(old, numUints * sizeof(uint32_t));
    if (new == NULL) {
      fatal("Memory allocation error.\n");
    }
  }
  {};
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reallocUint>:
  endbr64
  push   %r12
  test   %rsi,%rsi
  je     L1
  shl    $0x2,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
L15:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  call   <free@plt>
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  lea    D8(%rip),%rdi
  call   <fatal@plt>
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: Memory allocation error.


assistant: ```c
uint32_t *reallocUint(uint32_t *old, uintptr_t numUints) {
  {};
  uint32_t *new = NULL;
  if (numUints == 0) {
    free(old);
  } else {
    new = realloc(old, numUints * sizeof(uint32_t));
    if (new == NULL) {
      fatal("Memory allocation error.\n");
    }
  }
  {};
  return new;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x20,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x20(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int setbits(unsigned int x, int p, int n, unsigned int y) {
  int t1, t2, t3;
  int bits;
  bits = sizeof(int) * 8;
  t1 = x >> (bits - p);
  t2 = x << (bits - p - n) >> (bits - p - n);
  t3 = y << (bits - n) >> p;
  x = t1 | t2 | t3;
  return x;
}
```