ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<FS460_get_sync_invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L45
  cmpq   $0x0,-0x30(%rbp)
  je     L45
  cmpq   $0x0,-0x38(%rbp)
  jne    L54
L45:
  mov    $0x1000,%eax
  jmp    L50
L54:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3c,%edi
  call   <sio_read_reg@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L6
  mov    -0x14(%rbp),%eax
  jmp    L50
L6:
  mov    -0x10(%rbp),%rax
  shr    $0xe,%rax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x5,%rax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0xf,%rax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int FS460_get_sync_invert(int *p_hsync_invert, int *p_vsync_invert, int *p_field_invert) {
  int err;
  unsigned long mux1;
  if (!p_hsync_invert || !p_vsync_invert || !p_field_invert)
    return 0x1000;
  err = sio_read_reg(0x3C, &mux1);
  if (err)
    return err;
  *p_hsync_invert = ((1 << 14) & mux1) ? 1 : 0;
  *p_vsync_invert = ((1 << 5) & mux1) ? 1 : 0;
  *p_field_invert = ((1 << 15) & mux1) ? 1 : 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FS460_get_sync_invert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L6
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L6
  mov    %rsp,%rsi
  mov    $0x3c,%edi
  call   <sio_read_reg@plt>
  test   %eax,%eax
  jne    L46
  mov    (%rsp),%rdx
  mov    %rdx,%rcx
  shr    $0xe,%rcx
  and    $0x1,%ecx
  mov    %ecx,(%r12)
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  and    $0x1,%ecx
  mov    %ecx,0x0(%rbp)
  shr    $0xf,%rdx
  and    $0x1,%edx
  mov    %edx,(%rbx)
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x1000,%eax
  jmp    L46
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_get_sync_invert(int *p_hsync_invert, int *p_vsync_invert, int *p_field_invert) {
  int err;
  unsigned long mux1;
  if (!p_hsync_invert || !p_vsync_invert || !p_field_invert)
    return 0x1000;
  err = sio_read_reg(0x3C, &mux1);
  if (err)
    return err;
  *p_hsync_invert = ((1 << 14) & mux1) ? 1 : 0;
  *p_vsync_invert = ((1 << 5) & mux1) ? 1 : 0;
  *p_field_invert = ((1 << 15) & mux1) ? 1 : 0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FS460_get_sync_invert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L39
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%r12
  mov    $0x3c,%edi
  mov    %rsp,%rsi
  call   <sio_read_reg@plt>
  test   %eax,%eax
  jne    L13
  mov    (%rsp),%rdx
  mov    %rdx,%rcx
  shr    $0xe,%rcx
  and    $0x1,%ecx
  mov    %ecx,0x0(%rbp)
  mov    %rdx,%rcx
  shr    $0xf,%rdx
  shr    $0x5,%rcx
  and    $0x1,%edx
  and    $0x1,%ecx
  mov    %ecx,(%r12)
  mov    %edx,(%rbx)
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  mov    $0x1000,%eax
  jmp    L13
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_get_sync_invert(int *p_hsync_invert, int *p_vsync_invert, int *p_field_invert) {
  int err;
  unsigned long mux1;
  if (!p_hsync_invert || !p_vsync_invert || !p_field_invert)
    return 0x1000;
  err = sio_read_reg(0x3C, &mux1);
  if (err)
    return err;
  *p_hsync_invert = ((1 << 14) & mux1) ? 1 : 0;
  *p_vsync_invert = ((1 << 5) & mux1) ? 1 : 0;
  *p_field_invert = ((1 << 15) & mux1) ? 1 : 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FS460_get_sync_invert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L18
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%r12
  mov    $0x3c,%edi
  mov    %rsp,%rsi
  call   <sio_read_reg@plt>
  test   %eax,%eax
  jne    L31
  mov    (%rsp),%rdx
  mov    %rdx,%rcx
  shr    $0xe,%rcx
  and    $0x1,%ecx
  mov    %ecx,0x0(%rbp)
  mov    %rdx,%rcx
  shr    $0xf,%rdx
  shr    $0x5,%rcx
  and    $0x1,%edx
  and    $0x1,%ecx
  mov    %ecx,(%r12)
  mov    %edx,(%rbx)
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1000,%eax
  jmp    L31
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FS460_get_sync_invert(int *p_hsync_invert, int *p_vsync_invert, int *p_field_invert) {
  int err;
  unsigned long mux1;
  if (!p_hsync_invert || !p_vsync_invert || !p_field_invert)
    return 0x1000;
  err = sio_read_reg(0x3C, &mux1);
  if (err)
    return err;
  *p_hsync_invert = ((1 << 14) & mux1) ? 1 : 0;
  *p_vsync_invert = ((1 << 5) & mux1) ? 1 : 0;
  *p_field_invert = ((1 << 15) & mux1) ? 1 : 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strreverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L12
L13:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x29(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x29(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x28(%rbp)
  subq   $0x1,-0x20(%rbp)
L12:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L13
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strreverse(char *s) {
  char *str = strdup(s);
  char temp;
  size_t len = strlen(str) - 1;
  size_t stop = len / 2;
  size_t i, k;
  for (i = 0, k = len; i <= stop; i++, k--) {
    temp = str[k];
    str[k] = str[i];
    str[i] = temp;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strreverse>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdx
  shr    %rax
  lea    0x1(%rbx,%rax,1),%rdi
L6:
  movzbl (%rcx),%eax
  movzbl (%rdx),%esi
  mov    %sil,(%rcx)
  mov    %al,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L6
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strreverse(char *s) {
  char *str = strdup(s);
  char temp;
  size_t len = strlen(str) - 1;
  size_t stop = len / 2;
  size_t i, k;
  for (i = 0, k = len; i <= stop; i++, k--) {
    temp = str[k];
    str[k] = str[i];
    str[i] = temp;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strreverse>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdx
  sub    $0x1,%eax
  cltq
  lea    (%r12,%rax,1),%rcx
  shr    %rax
  lea    0x1(%r12,%rax,1),%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%rcx),%eax
  movzbl (%rdx),%esi
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %sil,0x1(%rcx)
  mov    %al,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L2
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strreverse(char *s) {
  char *str = strdup(s);
  char temp;
  size_t len = strlen(str) - 1;
  size_t stop = len / 2;
  size_t i, k;
  for (i = 0, k = len; i <= stop; i++, k--) {
    temp = str[k];
    str[k] = str[i];
    str[i] = temp;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strreverse>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdx
  sub    $0x1,%eax
  cltq
  lea    (%r12,%rax,1),%rcx
  shr    %rax
  lea    0x1(%r12,%rax,1),%rdi
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%rcx),%eax
  movzbl (%rdx),%esi
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %sil,0x1(%rcx)
  mov    %al,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L8
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strreverse(char *s) {
  char *str = strdup(s);
  char temp;
  size_t len = strlen(str) - 1;
  size_t stop = len / 2;
  size_t i, k;
  for (i = 0, k = len; i <= stop; i++, k--) {
    temp = str[k];
    str[k] = str[i];
    str[i] = temp;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x20(%rbp),%ecx
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D27: Enter two integers> 

tool: D6: %d%d

tool: D3: The result is %.3f


assistant: ```c
int main(void) {
  int first, second;
  double temp, ans;
  printf("Enter two integers> ");
  scanf("%d%d", &first, &second);
  temp = second / first;
  ans = first / temp;
  printf("The result is %.3f\n", ans);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D12: Enter two integers> 

tool: D24: %d%d

tool: D25: The result is %.3f


assistant: ```c
int main(void) {
  int first, second;
  double temp, ans;
  printf("Enter two integers> ");
  scanf("%d%d", &first, &second);
  temp = second / first;
  ans = first / temp;
  printf("The result is %.3f\n", ans);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  lea    D6(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D23(%rip),%rdi
  cltd
  cvtsi2sd %ecx,%xmm0
  idiv   %ecx
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string

tool: D17: Enter two integers> 

tool: D6: %d%d

tool: D23: The result is %.3f


assistant: ```c
int main(void) {
  int first, second;
  double temp, ans;
  printf("Enter two integers> ");
  scanf("%d%d", &first, &second);
  temp = second / first;
  ans = first / temp;
  printf("The result is %.3f\n", ans);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  lea    D0(%rip),%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    (%rsp),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D1(%rip),%rdi
  cltd
  cvtsi2sd %ecx,%xmm0
  idiv   %ecx
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D10: Enter two integers> 

tool: D0: %d%d

tool: D1: The result is %.3f


assistant: ```c
int main(void) {
  int first, second;
  double temp, ans;
  printf("Enter two integers> ");
  scanf("%d%d", &first, &second);
  temp = second / first;
  ans = first / temp;
  printf("The result is %.3f\n", ans);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_strupcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L37
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L37:
  addl   $0x1,-0x4(%rbp)
L30:
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L18:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strupcase(char *str) {
  int i;
  i = 0;
  while (str && str[i]) {
    if (str[i] > 96 && str[i] < 123)
      str[i] -= 32;
    i++;
  }
  return (str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strupcase>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L16
  mov    %rdi,%rcx
  jmp    L23
L20:
  add    $0x1,%rcx
L23:
  mov    %rcx,%r8
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L16
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L20
  sub    $0x20,%edx
  mov    %dl,(%r8)
  jmp    L20
L16:
  ret
```

assistant: ```c
char *ft_strupcase(char *str) {
  int i;
  i = 0;
  while (str && str[i]) {
    if (str[i] > 96 && str[i] < 123)
      str[i] -= 32;
    i++;
  }
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strupcase>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L30
  mov    %rdi,%rcx
  jmp    L36
  nopl   0x0(%rax)
L3:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L0
  sub    $0x20,%edx
  mov    %dl,(%rcx)
L0:
  add    $0x1,%rcx
L36:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L3
L30:
  ret
```

assistant: ```c
char *ft_strupcase(char *str) {
  int i;
  i = 0;
  while (str && str[i]) {
    if (str[i] > 96 && str[i] < 123)
      str[i] -= 32;
    i++;
  }
  return (str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strupcase>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  test   %dl,%dl
  je     L19
  cs nopw 0x0(%rax,%rax,1)
L9:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L18
  sub    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L9
L19:
  ret
```

assistant: ```c
char *ft_strupcase(char *str) {
  int i;
  i = 0;
  while (str && str[i]) {
    if (str[i] > 96 && str[i] < 123)
      str[i] -= 32;
    i++;
  }
  return (str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sineInOut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  D42(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L9
  movss  -0xc(%rbp),%xmm0
  movss  D11(%rip),%xmm1
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
  cvttss2si %xmm0,%eax
  mov    -0x8(%rbp),%edx
  movaps %xmm2,%xmm1
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <sineIn@plt>
  jmp    L12
L9:
  movss  -0xc(%rbp),%xmm0
  movss  D11(%rip),%xmm1
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movss  -0xc(%rbp),%xmm0
  movss  D11(%rip),%xmm1
  divss  %xmm1,%xmm0
  addss  -0x8(%rbp),%xmm0
  movd   %xmm0,%edx
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  D7(%rip),%xmm1
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  movaps %xmm2,%xmm1
  movd   %edx,%xmm0
  mov    %eax,%edi
  call   <sineOut@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D42
type: f32
name: disassemble_data
arguments: tag: D11
type: byte[4]
name: disassemble_data
arguments: tag: D7
type: byte[4]

tool: D42: 0.5

tool: {"D11": [0x00,0x00,0x00,0x40]}

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float sineInOut(float fraction, float start, float delta) {
  if (fraction < 0.5)
    return sineIn(2 * fraction, start, delta / 2);
  return sineOut(2 * fraction - 1, start + delta / 2, delta / 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sineInOut>:
  endbr64
  sub    $0x8,%rsp
  movaps %xmm0,%xmm3
  movaps %xmm1,%xmm0
  movss  D23(%rip),%xmm1
  comiss %xmm3,%xmm1
  ja     L1
  mulss  D23(%rip),%xmm2
  movaps %xmm2,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm3,%xmm3
  subss  D4(%rip),%xmm3
  cvttss2si %xmm3,%edi
  call   <sineOut@plt>
L8:
  add    $0x8,%rsp
  ret
L1:
  addss  %xmm3,%xmm3
  cvttss2si %xmm3,%edi
  mulss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  call   <sineIn@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D23
data_type: f32
name: unpack_data
arguments: data_label: D4
data_type: byte[4]

tool: D23: 0.5

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float sineInOut(float fraction, float start, float delta) {
  if (fraction < 0.5)
    return sineIn(2 * fraction, start, delta / 2);
  return sineOut(2 * fraction - 1, start + delta / 2, delta / 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sineInOut>:
  endbr64
  movss  D15(%rip),%xmm4
  movaps %xmm0,%xmm3
  movaps %xmm1,%xmm0
  mulss  %xmm4,%xmm2
  comiss %xmm3,%xmm4
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  addss  %xmm3,%xmm2
  ja     L4
  subss  D10(%rip),%xmm2
  addss  %xmm1,%xmm0
  cvttss2si %xmm2,%edi
  jmp    1070 <sineOut@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  cvttss2si %xmm2,%edi
  jmp    1060 <sineIn@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: f32
name: extract_symbolic_data
arguments: label: D10
type_infered: byte[4]

tool: D15: 0.5

tool: {"D10": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float sineInOut(float fraction, float start, float delta) {
  if (fraction < 0.5)
    return sineIn(2 * fraction, start, delta / 2);
  return sineOut(2 * fraction - 1, start + delta / 2, delta / 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sineInOut>:
  endbr64
  movss  D9(%rip),%xmm4
  movaps %xmm0,%xmm3
  movaps %xmm1,%xmm0
  mulss  %xmm4,%xmm2
  comiss %xmm3,%xmm4
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm2
  addss  %xmm3,%xmm2
  ja     L9
  subss  D15(%rip),%xmm2
  addss  %xmm1,%xmm0
  cvttss2si %xmm2,%edi
  jmp    1070 <sineOut@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  cvttss2si %xmm2,%edi
  jmp    1060 <sineIn@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: f32
name: disassemble_data
arguments: label: D15
datatype: byte[4]

tool: D9: 0.5

tool: {"D15": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float sineInOut(float fraction, float start, float delta) {
  if (fraction < 0.5)
    return sineIn(2 * fraction, start, delta / 2);
  return sineOut(2 * fraction - 1, start + delta / 2, delta / 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L12:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movsbq %al,%rax
  mov    %rax,(%rdx)
L8:
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char fill(uint8_t *entry, char *string, unsigned int len) {
  int i;
  i = len;
  while (i != 0) {
    i--;
    entry[i] = (uint8_t)string[i];
  }
  return 0x00;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill>:
  endbr64
  test   %edx,%edx
  je     L15
  movslq %edx,%rdx
L9:
  movsbq -0x1(%rsi,%rdx,1),%rax
  mov    %rax,-0x8(%rdi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L9
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char fill(uint8_t *entry, char *string, unsigned int len) {
  int i;
  i = len;
  while (i != 0) {
    i--;
    entry[i] = (uint8_t)string[i];
  }
  return 0x00;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill>:
  endbr64
  test   %edx,%edx
  je     L7
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L11:
  movsbq -0x1(%rsi,%rdx,1),%rax
  mov    %rax,-0x8(%rdi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L11
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
char fill(uint8_t *entry, char *string, unsigned int len) {
  int i;
  i = len;
  while (i != 0) {
    i--;
    entry[i] = (uint8_t)string[i];
  }
  return 0x00;
}
```
user: What is the c source code of the assembly code below?

```asm
<fill>:
  endbr64
  test   %edx,%edx
  je     L9
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  movsbq -0x1(%rsi,%rdx,1),%rax
  mov    %rax,-0x8(%rdi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L2
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
char fill(uint8_t *entry, char *string, unsigned int len) {
  int i;
  i = len;
  while (i != 0) {
    i--;
    entry[i] = (uint8_t)string[i];
  }
  return 0x00;
}
```