ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ecx,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  movslq %ecx,%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L30:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L2
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L2:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x28(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L29
  lea    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L29
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L19
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L19:
  mov    -0x20(%rbp),%rax
  mov    %rbx,%rsp
  jmp    L60
L29:
  mov    %rbx,%rsp
L60:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int readInt() {
  char buf[BUFSIZ];
  char *p;
  long int i;
  if (fgets(buf, sizeof(buf), stdin) != NULL) {
    i = strtol(buf, &p, 10);
    if (buf[0] != '\n' && (*p == '\n' || *p == '\0'))
      return i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L60:
  cmp    %rdx,%rsp
  je     L42
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L42:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L54
  orq    $0x0,-0x8(%rsp,%rax,1)
L54:
  mov    %rsp,%rbx
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    %rsp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L49
  lea    -0x20(%rbp),%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  cmpb   $0xa,(%rbx)
  je     L49
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    $0xa,%dl
  je     L49
  test   %dl,%dl
L49:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  mov    -0x8(%rbp),%rbx
  leave
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readInt() {
  char buf[BUFSIZ];
  char *p;
  long int i;
  if (fgets(buf, sizeof(buf), stdin) != NULL) {
    i = strtol(buf, &p, 10);
    if (buf[0] != '\n' && (*p == '\n' || *p == '\0'))
      return i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L41
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L78:
  mov    D2(%rip),%rax
  mov    %rsp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  test   %rax,%rax
  je     L48
  lea    -0x10(%rbp),%rsi
  mov    $0xa,%edx
  mov    %rsp,%rdi
  call   <strtol@plt>
  cmpb   $0xa,(%rsp)
  je     L48
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    $0xa,%dl
  je     L48
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  leave
  ret
  nop
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L78
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readInt() {
  char buf[BUFSIZ];
  char *p;
  long int i;
  if (fgets(buf, sizeof(buf), stdin) != NULL) {
    i = strtol(buf, &p, 10);
    if (buf[0] != '\n' && (*p == '\n' || *p == '\0'))
      return i;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<readInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  mov    D8(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L41
L71:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L71
L41:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L17
L48:
  mov    D19(%rip),%rax
  mov    %rsp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  test   %rax,%rax
  je     L76
  lea    -0x10(%rbp),%rsi
  mov    $0xa,%edx
  mov    %rsp,%rdi
  call   <strtol@plt>
  cmpb   $0xa,(%rsp)
  je     L76
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    $0xa,%dl
  je     L76
L76:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  leave
  ret
  nop
L17:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readInt() {
  char buf[BUFSIZ];
  char *p;
  long int i;
  if (fgets(buf, sizeof(buf), stdin) != NULL) {
    i = strtol(buf, &p, 10);
    if (buf[0] != '\n' && (*p == '\n' || *p == '\0'))
      return i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myStrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L33:
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L58:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L53
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L58
  jmp    L16
L53:
  nop
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L78
  mov    -0x10(%rbp),%eax
  jmp    L71
L78:
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L33
  mov    $0xffffffff,%eax
L71:
  leave
  ret
```

assistant: ```c
int myStrstr(char *line, char *s) {
  int i, j, llen, slen;
  llen = strlen(line);
  slen = strlen(s);
  for (i = 0; i <= llen - slen; i++) {
    for (j = 0; j < slen; j++) {
      if (line[i + j] != s[j]) {
        break;
      }
    }
    if (j == slen) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myStrstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12d,%r9d
  sub    %eax,%r9d
  js     L51
  mov    %eax,%r8d
  mov    %rbx,%rsi
  mov    $0x0,%eax
  mov    %r8d,%edi
  mov    $0x0,%r10d
  jmp    L86
L70:
  cmp    %ecx,%r8d
  je     L21
  add    $0x1,%eax
  add    $0x1,%rsi
  cmp    %r9d,%eax
  jg     L48
L86:
  mov    $0x0,%edx
  mov    %r10d,%ecx
  test   %r8d,%r8d
  jle    L70
L55:
  mov    %edx,%ecx
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rsi,%rdx,1)
  jne    L70
  lea    0x1(%rdx),%ecx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L55
  jmp    L70
L51:
  mov    $0xffffffff,%eax
  jmp    L21
L48:
  mov    $0xffffffff,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int myStrstr(char *line, char *s) {
  int i, j, llen, slen;
  llen = strlen(line);
  slen = strlen(s);
  for (i = 0; i <= llen - slen; i++) {
    for (j = 0; j < slen; j++) {
      if (line[i + j] != s[j]) {
        break;
      }
    }
    if (j == slen) {
      return i;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<myStrstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r12d,%r9d
  sub    %eax,%r9d
  js     L34
  mov    %eax,%r8d
  mov    %rbx,%rdi
  xor    %eax,%eax
  lea    0x1(%r8),%esi
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0x1,%edx
  xor    %ecx,%ecx
  test   %r8d,%r8d
  jg     L16
  jmp    L66
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %edx,%ecx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L66
L16:
  movzbl -0x1(%rbp,%rdx,1),%ebx
  cmp    %bl,-0x1(%rdx,%rdi,1)
  je     L8
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%r9d
  jge    L52
L34:
  mov    $0xffffffff,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L66:
  cmp    %ecx,%r8d
  je     L26
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%r9d
  jge    L52
  jmp    L34
```

assistant: ```c
int myStrstr(char *line, char *s) {
  int i, j, llen, slen;
  llen = strlen(line);
  slen = strlen(s);
  for (i = 0; i <= llen - slen; i++) {
    for (j = 0; j < slen; j++) {
      if (line[i + j] != s[j]) {
        break;
      }
    }
    if (j == slen) {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<myStrstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r12d,%r9d
  sub    %eax,%r9d
  js     L25
  mov    %eax,%r8d
  mov    %rbx,%rdi
  xor    %eax,%eax
  lea    0x1(%r8),%esi
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%edx
  xor    %ecx,%ecx
  test   %r8d,%r8d
  jg     L19
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %edx,%ecx
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L11
L19:
  movzbl -0x1(%rbp,%rdx,1),%ebx
  cmp    %bl,-0x1(%rdi,%rdx,1)
  je     L79
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%r9d
  jge    L41
L25:
  mov    $0xffffffff,%eax
L71:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  cmp    %ecx,%r8d
  je     L71
  add    $0x1,%eax
  add    $0x1,%rdi
  cmp    %eax,%r9d
  jge    L41
  jmp    L25
```

assistant: ```c
int myStrstr(char *line, char *s) {
  int i, j, llen, slen;
  llen = strlen(line);
  slen = strlen(s);
  for (i = 0; i <= llen - slen; i++) {
    for (j = 0; j < slen; j++) {
      if (line[i + j] != s[j]) {
        break;
      }
    }
    if (j == slen) {
      return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memcpy_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L11:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L11
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy_(void *dest, const void *src, size_t count) {
  char *tmp = (char *)dest;
  const char *s = (char *)src;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memcpy_>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L14
  mov    $0x0,%ecx
L8:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L8
L14:
  ret
```

assistant: ```c
void *memcpy_(void *dest, const void *src, size_t count) {
  char *tmp = (char *)dest;
  const char *s = (char *)src;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy_>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L18
  xor    %ecx,%ecx
  xchg   %ax,%ax
L8:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L8
L18:
  ret
```

assistant: ```c
void *memcpy_(void *dest, const void *src, size_t count) {
  char *tmp = (char *)dest;
  const char *s = (char *)src;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcpy_>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  lea    -0x1(%rdx),%rsi
  test   %rdx,%rdx
  je     L8
  lea    0x1(%rcx),%rdi
  mov    %r8,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L37
  cmp    $0x6,%rsi
  jbe    L37
  cmp    $0xe,%rsi
  jbe    L44
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  nopl   0x0(%rax,%rax,1)
L66:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L66
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  lea    (%r8,%rax,1),%rdi
  lea    (%rcx,%rax,1),%r9
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L8
  sub    %rax,%rdx
  lea    -0x1(%rdx),%r10
  cmp    $0x6,%r10
  jbe    L148
L150:
  mov    (%rcx,%rax,1),%rcx
  mov    %rcx,(%r8,%rax,1)
  mov    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  add    %rax,%rdi
  add    %rax,%r9
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L8
L148:
  movzbl (%r9),%eax
  mov    %al,(%rdi)
  test   %rsi,%rsi
  je     L8
  movzbl 0x1(%r9),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x1,%rsi
  je     L8
  movzbl 0x2(%r9),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x2,%rsi
  je     L8
  movzbl 0x3(%r9),%eax
  mov    %al,0x3(%rdi)
  cmp    $0x3,%rsi
  je     L8
  movzbl 0x4(%r9),%eax
  mov    %al,0x4(%rdi)
  cmp    $0x4,%rsi
  je     L8
  movzbl 0x5(%r9),%eax
  mov    %al,0x5(%rdi)
  cmp    $0x5,%rsi
  je     L8
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
L8:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L37:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L136:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L136
  mov    %r8,%rax
  ret
L44:
  mov    %rcx,%r9
  mov    %r8,%rdi
  xor    %eax,%eax
  jmp    L150
```

assistant: ```c
void *memcpy_(void *dest, const void *src, size_t count) {
  char *tmp = (char *)dest;
  const char *s = (char *)src;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sdbm@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
data_type: string
name: parse_data
arguments: tag: D11
data_type: string

tool: D13: Hello World

tool: D11: 
The hash is %lu

assistant: ```c
int main(int argc, char *argv[]) {
  const char *str = "Hello World";
  printf("\nThe hash is %lu", sdbm(str));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <sdbm@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D10
datatype: string

tool: D16: Hello World

tool: D10: 
The hash is %lu

assistant: ```c
int main(int argc, char *argv[]) {
  const char *str = "Hello World";
  printf("\nThe hash is %lu", sdbm(str));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <sdbm@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string

tool: D9: Hello World

tool: D12: 
The hash is %lu

assistant: ```c
int main(int argc, char *argv[]) {
  const char *str = "Hello World";
  printf("\nThe hash is %lu", sdbm(str));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <sdbm@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D2
type: string

tool: D13: Hello World

tool: D2: 
The hash is %lu

assistant: ```c
int main(int argc, char *argv[]) {
  const char *str = "Hello World";
  printf("\nThe hash is %lu", sdbm(str));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pread_in_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L37
L11:
  mov    -0x28(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <xpread@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jg     L3
  cmpq   $0x0,-0x18(%rbp)
  jle    L7
  mov    -0x18(%rbp),%rax
  jmp    L59
L7:
  mov    $0xffffffffffffffff,%rax
  jmp    L59
L3:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x38(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
L37:
  cmpq   $0x0,-0x38(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
L59:
  leave
  ret
```

assistant: ```c
ssize_t pread_in_full(int fd, void *buf, size_t count, off_t offset) {
  ssize_t total = 0;
  char *p = buf;
  while (count > 0) {
    ssize_t nr;
    nr = xpread(fd, p, count, offset);
    if (nr <= 0) {
      if (total > 0)
        return total;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pread_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L44
  mov    %edi,%r14d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    $0x0,%r13d
L26:
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <xpread@plt>
  test   %rax,%rax
  jle    L20
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r12d
  sub    %rax,%rbx
  jne    L26
  jmp    L59
L20:
  test   %r13,%r13
  jle    L60
L59:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L60:
  mov    $0xffffffffffffffff,%r13
  jmp    L59
L44:
  mov    $0x0,%r13d
  jmp    L59
```

assistant: ```c
ssize_t pread_in_full(int fd, void *buf, size_t count, off_t offset) {
  ssize_t total = 0;
  char *p = buf;
  while (count > 0) {
    ssize_t nr;
    nr = xpread(fd, p, count, offset);
    if (nr <= 0) {
      if (total > 0)
        return total;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pread_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L29
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  xor    %r13d,%r13d
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L64:
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r14d
  sub    %rax,%rbx
  je     L3
L58:
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xpread@plt>
  test   %rax,%rax
  jg     L64
  test   %r13,%r13
  je     L33
L3:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  xor    %r13d,%r13d
  jmp    L3
L33:
  mov    $0xffffffffffffffff,%r13
  jmp    L3
```

assistant: ```c
ssize_t pread_in_full(int fd, void *buf, size_t count, off_t offset) {
  ssize_t total = 0;
  char *p = buf;
  while (count > 0) {
    ssize_t nr;
    nr = xpread(fd, p, count, offset);
    if (nr <= 0) {
      if (total > 0)
        return total;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pread_in_full>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L11
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  xor    %r13d,%r13d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L13:
  add    %rax,%r13
  add    %rax,%rbp
  add    %eax,%r14d
  sub    %rax,%rbx
  je     L60
L22:
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xpread@plt>
  test   %rax,%rax
  jg     L13
  test   %r13,%r13
  je     L0
L60:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  xor    %r13d,%r13d
  jmp    L60
L0:
  mov    $0xffffffffffffffff,%r13
  jmp    L60
```

assistant: ```c
ssize_t pread_in_full(int fd, void *buf, size_t count, off_t offset) {
  ssize_t total = 0;
  char *p = buf;
  while (count > 0) {
    ssize_t nr;
    nr = xpread(fd, p, count, offset);
    if (nr <= 0) {
      if (total > 0)
        return total;
      return -1;
    }
    count -= nr;
    total += nr;
    p += nr;
    offset += nr;
  }
  return total;
}
```
user: What is the c source code of the assembly code below:

```asm
<ROL64_49>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0x31,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_49(uint64_t x) {
  __asm__("rolq $49, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ROL64_49>:
  endbr64
  mov    %rdi,%rax
  rol    $0x31,%rax
  ret
```

assistant: ```c
uint64_t ROL64_49(uint64_t x) {
  __asm__("rolq $49, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ROL64_49>:
  endbr64
  mov    %rdi,%rax
  rol    $0x31,%rax
  ret
```

assistant: ```c
uint64_t ROL64_49(uint64_t x) {
  __asm__("rolq $49, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ROL64_49>:
  endbr64
  mov    %rdi,%rax
  rol    $0x31,%rax
  ret
```

assistant: ```c
uint64_t ROL64_49(uint64_t x) {
  __asm__("rolq $49, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<int_bounds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,%ecx
  mov    (%rax),%esi
  cmp    %esi,%ecx
  jle    L10
  mov    %ecx,(%rax)
  jmp    L13
L10:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jge    L13
  mov    %edx,(%rax)
L13:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void int_bounds(register int *what, register int lower_limit, register int upper_limit) {
  if (*what < lower_limit)
    *what = lower_limit;
  else if (*what > upper_limit)
    *what = upper_limit;
}
```