ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<open_file_int>:
  endbr64
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int open_file_int(char *file_name, char *mode) {
  FILE *f;
  int code = 0;
  f = fopen(file_name, mode);
  if (f)
    fclose(f);
  else
    code = errno;
  return code;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  subq   $0x1,-0x18(%rbp)
  nop
L10:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
strcat(s1, s2) char *s1, *s2;
{
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  *--s1;
  while (*s1++ = *s2++)
    ;
  return (os1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
L11:
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L11
  mov    $0x0,%edx
L0:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L0
  ret
```

assistant: ```c
strcat(s1, s2) char *s1, *s2;
{
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  *--s1;
  while (*s1++ = *s2++)
    ;
  return (os1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdx,%rcx
  lea    0x1(%rdx),%rdx
  cmpb   $0x0,(%rcx)
  jne    L5
  xor    %edx,%edx
  xchg   %ax,%ax
L9:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L9
  ret
```

assistant: ```c
strcat(s1, s2) char *s1, *s2;
{
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  *--s1;
  while (*s1++ = *s2++)
    ;
  return (os1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rdx,%rcx
  lea    0x1(%rdx),%rdx
  cmpb   $0x0,(%rcx)
  jne    L18
  xor    %edx,%edx
  xchg   %ax,%ax
L15:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L15
  ret
```

assistant: ```c
strcat(s1, s2) char *s1, *s2;
{
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  *--s1;
  while (*s1++ = *s2++)
    ;
  return (os1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: %s
usage: ondir [-V] <old-directory> [<new-directory>]

  -V    Displays version information.

  <old-directory> is the last working directory.

  <new-directory> is the current working directory. If <new-directory> is
  omitted, the current working directory is obtained via a call to getcwd().



assistant: ```c
void usage(const char *msg) {
  printf("%s\n"
         "usage: ondir [-V] <old-directory> [<new-directory>]\n"
         "\n"
         "  -V    Displays version information.\n"
         "\n"
         "  <old-directory> is the last working directory.\n"
         "\n"
         "  <new-directory> is the current working directory. If <new-directory> is\n"
         "  omitted, the current working directory is obtained via a call to getcwd().\n"
         "\n",
         msg);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: %s
usage: ondir [-V] <old-directory> [<new-directory>]

  -V    Displays version information.

  <old-directory> is the last working directory.

  <new-directory> is the current working directory. If <new-directory> is
  omitted, the current working directory is obtained via a call to getcwd().



assistant: ```c
void usage(const char *msg) {
  printf("%s\n"
         "usage: ondir [-V] <old-directory> [<new-directory>]\n"
         "\n"
         "  -V    Displays version information.\n"
         "\n"
         "  <old-directory> is the last working directory.\n"
         "\n"
         "  <new-directory> is the current working directory. If <new-directory> is\n"
         "  omitted, the current working directory is obtained via a call to getcwd().\n"
         "\n",
         msg);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: %s
usage: ondir [-V] <old-directory> [<new-directory>]

  -V    Displays version information.

  <old-directory> is the last working directory.

  <new-directory> is the current working directory. If <new-directory> is
  omitted, the current working directory is obtained via a call to getcwd().



assistant: ```c
void usage(const char *msg) {
  printf("%s\n"
         "usage: ondir [-V] <old-directory> [<new-directory>]\n"
         "\n"
         "  -V    Displays version information.\n"
         "\n"
         "  <old-directory> is the last working directory.\n"
         "\n"
         "  <new-directory> is the current working directory. If <new-directory> is\n"
         "  omitted, the current working directory is obtained via a call to getcwd().\n"
         "\n",
         msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %s
usage: ondir [-V] <old-directory> [<new-directory>]

  -V    Displays version information.

  <old-directory> is the last working directory.

  <new-directory> is the current working directory. If <new-directory> is
  omitted, the current working directory is obtained via a call to getcwd().



assistant: ```c
void usage(const char *msg) {
  printf("%s\n"
         "usage: ondir [-V] <old-directory> [<new-directory>]\n"
         "\n"
         "  -V    Displays version information.\n"
         "\n"
         "  <old-directory> is the last working directory.\n"
         "\n"
         "  <new-directory> is the current working directory. If <new-directory> is\n"
         "  omitted, the current working directory is obtained via a call to getcwd().\n"
         "\n",
         msg);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intif_where>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <intif_charposreq@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int intif_where(int account_id, char *name) {
  intif_charposreq(account_id, name, 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intif_where>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  call   <intif_charposreq@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int intif_where(int account_id, char *name) {
  intif_charposreq(account_id, name, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<intif_where>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  call   <intif_charposreq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int intif_where(int account_id, char *name) {
  intif_charposreq(account_id, name, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<intif_where>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  call   <intif_charposreq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int intif_where(int account_id, char *name) {
  intif_charposreq(account_id, name, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_repl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L17
L5:
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    %rax,-0x38(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x48(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x30(%rbp)
  jae    L14
  mov    -0x30(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,%rdx
  cmovae %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x48(%rbp)
L14:
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x48(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  add    %rax,%rsi
  mov    -0x48(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
L17:
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L5
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_repl(char *target, const char *oldstr, const char *newstr) {
  size_t oldstr_len = strlen(oldstr);
  size_t newstr_len = strlen(newstr);
  size_t target_len = strlen(target);
  size_t target_max = target_len;
  size_t s, p;
  char *needle;
  for (s = 0; (needle = strstr(target + s, oldstr)) != NULL; s = p + newstr_len) {
    target_len += newstr_len - oldstr_len;
    p = needle - target;
    if (target_len + 1 > target_max) {
      target_max = (target_len + 1 > target_max * 2) ? target_len + 1 : target_max * 2;
      target = xrealloc(target, target_max);
    }
    memmove(target + p + newstr_len, target + p + oldstr_len, target_len - p - newstr_len + 1);
    memcpy(target + p, newstr, newstr_len);
  }
  target = xrealloc(target, target_len + 1);
  return target;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_repl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r15
  mov    %rdx,0x10(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,0x18(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rax,%r13
  mov    $0x0,%r12d
  mov    %r15,%rcx
  sub    %rbx,%rcx
  mov    %rcx,0x20(%rsp)
  mov    $0x1,%eax
  sub    %r15,%rax
  mov    %rax,0x28(%rsp)
  jmp    L35
L4:
  lea    (%r15,%rbx,1),%r12
  mov    0x28(%rsp),%rax
  lea    (%rax,%r13,1),%rdx
  sub    %rbx,%rdx
  mov    0x18(%rsp),%rax
  lea    (%rax,%rbx,1),%rsi
  add    %rbp,%rsi
  lea    0x0(%rbp,%r12,1),%rdi
  call   <memmove@plt>
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r15,%rdx
  mov    0x10(%rsp),%rsi
  call   <memcpy@plt>
L35:
  lea    0x0(%rbp,%r12,1),%rdi
  mov    0x8(%rsp),%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L32
  add    0x20(%rsp),%r13
  sub    %rbp,%rbx
  lea    0x1(%r13),%rax
  cmp    %rax,%r14
  jae    L4
  add    %r14,%r14
  cmp    %rax,%r14
  cmovb  %rax,%r14
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <xrealloc@plt>
  mov    %rax,%rbp
  jmp    L4
L32:
  lea    0x1(%r13),%rsi
  mov    %rbp,%rdi
  call   <xrealloc@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *str_repl(char *target, const char *oldstr, const char *newstr) {
  size_t oldstr_len = strlen(oldstr);
  size_t newstr_len = strlen(newstr);
  size_t target_len = strlen(target);
  size_t target_max = target_len;
  size_t s, p;
  char *needle;
  for (s = 0; (needle = strstr(target + s, oldstr)) != NULL; s = p + newstr_len) {
    target_len += newstr_len - oldstr_len;
    p = needle - target;
    if (target_len + 1 > target_max) {
      target_max = (target_len + 1 > target_max * 2) ? target_len + 1 : target_max * 2;
      target = xrealloc(target, target_max);
    }
    memmove(target + p + newstr_len, target + p + oldstr_len, target_len - p - newstr_len + 1);
    memcpy(target + p, newstr, newstr_len);
  }
  target = xrealloc(target, target_len + 1);
  return target;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_repl>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %r14,%r10
  mov    %rax,%rbx
  mov    %rax,%rbp
  mov    $0x1,%eax
  sub    %r15,%rdi
  sub    %r12,%rax
  mov    %rdi,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    0x28(%rsp),%rax
  lea    (%r12,%rcx,1),%r10
  add    %r14,%r10
  lea    (%rax,%rbx,1),%rdx
  mov    0x18(%rsp),%rax
  mov    %r10,%rdi
  mov    %r10,0x8(%rsp)
  sub    %rcx,%rdx
  lea    (%rax,%rcx,1),%rsi
  add    %r14,%rsi
  call   <memmove@plt>
  mov    0x10(%rsp),%rsi
  mov    %r12,%rdx
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%r10
L26:
  mov    %r13,%rsi
  mov    %r10,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L34
  add    0x20(%rsp),%rbx
  mov    %r15,%rcx
  lea    0x1(%rbx),%rax
  sub    %r14,%rcx
  cmp    %rax,%rbp
  jae    L24
  add    %rbp,%rbp
  mov    %r14,%rdi
  mov    %rcx,0x8(%rsp)
  cmp    %rax,%rbp
  cmovb  %rax,%rbp
  mov    %rbp,%rsi
  call   <xrealloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %rax,%r14
  lea    (%rax,%rcx,1),%r15
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x38,%rsp
  lea    0x1(%rbx),%rsi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <xrealloc@plt>
```

assistant: ```c
char *str_repl(char *target, const char *oldstr, const char *newstr) {
  size_t oldstr_len = strlen(oldstr);
  size_t newstr_len = strlen(newstr);
  size_t target_len = strlen(target);
  size_t target_max = target_len;
  size_t s, p;
  char *needle;
  for (s = 0; (needle = strstr(target + s, oldstr)) != NULL; s = p + newstr_len) {
    target_len += newstr_len - oldstr_len;
    p = needle - target;
    if (target_len + 1 > target_max) {
      target_max = (target_len + 1 > target_max * 2) ? target_len + 1 : target_max * 2;
      target = xrealloc(target, target_max);
    }
    memmove(target + p + newstr_len, target + p + oldstr_len, target_len - p - newstr_len + 1);
    memcpy(target + p, newstr, newstr_len);
  }
  target = xrealloc(target, target_len + 1);
  return target;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_repl>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rdx,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  mov    %rax,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %r14,%r10
  mov    %rax,%rbx
  mov    %rax,%rbp
  mov    $0x1,%eax
  sub    %r15,%rdi
  sub    %r12,%rax
  mov    %rdi,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    0x28(%rsp),%rax
  lea    (%r12,%rcx,1),%r10
  add    %r14,%r10
  lea    (%rax,%rbx,1),%rdx
  mov    0x18(%rsp),%rax
  mov    %r10,%rdi
  mov    %r10,0x8(%rsp)
  sub    %rcx,%rdx
  lea    (%rax,%rcx,1),%rsi
  add    %r14,%rsi
  call   <memmove@plt>
  mov    0x10(%rsp),%rsi
  mov    %r12,%rdx
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%r10
L11:
  mov    %r13,%rsi
  mov    %r10,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L7
  add    0x20(%rsp),%rbx
  mov    %r15,%rcx
  lea    0x1(%rbx),%rax
  sub    %r14,%rcx
  cmp    %rbp,%rax
  jbe    L37
  add    %rbp,%rbp
  mov    %r14,%rdi
  mov    %rcx,0x8(%rsp)
  cmp    %rax,%rbp
  cmovb  %rax,%rbp
  mov    %rbp,%rsi
  call   <xrealloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %rax,%r14
  lea    (%rax,%rcx,1),%r15
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x38,%rsp
  lea    0x1(%rbx),%rsi
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <xrealloc@plt>
```

assistant: ```c
char *str_repl(char *target, const char *oldstr, const char *newstr) {
  size_t oldstr_len = strlen(oldstr);
  size_t newstr_len = strlen(newstr);
  size_t target_len = strlen(target);
  size_t target_max = target_len;
  size_t s, p;
  char *needle;
  for (s = 0; (needle = strstr(target + s, oldstr)) != NULL; s = p + newstr_len) {
    target_len += newstr_len - oldstr_len;
    p = needle - target;
    if (target_len + 1 > target_max) {
      target_max = (target_len + 1 > target_max * 2) ? target_len + 1 : target_max * 2;
      target = xrealloc(target, target_max);
    }
    memmove(target + p + newstr_len, target + p + oldstr_len, target_len - p - newstr_len + 1);
    memcpy(target + p, newstr, newstr_len);
  }
  target = xrealloc(target, target_len + 1);
  return target;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cstpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L13
L14:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *cstpcpy(char *to, const char *from) {
  for (; (*to = *from) != '\0'; ++from, ++to)
    ;
  return (to);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cstpcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  test   %dl,%dl
  je     L10
L7:
  add    $0x1,%rsi
  add    $0x1,%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L7
L10:
  ret
```

assistant: ```c
char *cstpcpy(char *to, const char *from) {
  for (; (*to = *from) != '\0'; ++from, ++to)
    ;
  return (to);
}
```
user: What is the c source code of the assembly code below?

```asm
<cstpcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  mov    %dl,(%rdi)
  test   %dl,%dl
  je     L5
L3:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L3
L5:
  ret
```

assistant: ```c
char *cstpcpy(char *to, const char *from) {
  for (; (*to = *from) != '\0'; ++from, ++to)
    ;
  return (to);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cstpcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  mov    %dl,(%rdi)
  test   %dl,%dl
  je     L9
L18:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,(%rax)
  test   %dl,%dl
  jne    L18
L9:
  ret
```

assistant: ```c
char *cstpcpy(char *to, const char *from) {
  for (; (*to = *from) != '\0'; ++from, ++to)
    ;
  return (to);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_dstdep_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L22
  mov    -0x1c(%rbp),%eax
  sar    $0x3,%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L4
  andl   $0x3,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L55
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L6
  andl   $0x3,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  shr    $0xc,%rax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0x400000,%eax
  test   %rax,%rax
  je     L3
  orl    $0x200,-0xc(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  and    $0x800000,%eax
  test   %rax,%rax
  je     L64
  orl    $0x200,-0xc(%rbp)
L64:
  mov    -0x18(%rbp),%rax
  and    $0x200000,%eax
  test   %rax,%rax
  je     L63
  orl    $0x110,-0xc(%rbp)
L63:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t get_dstdep_mask(uint64_t data, uint32_t fetchdat, int bit8) {
  uint32_t mask = 0;
  if (data & (1ull << 2)) {
    int reg = (fetchdat >> 3) & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  if (data & (1ull << 3)) {
    int reg = fetchdat & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  mask |= ((data >> 12) & 0xff);
  if (data & (1ull << 22))
    mask |= (1 << 9);
  if (data & (1ull << 23))
    mask |= (1 << 9);
  if (data & (1ull << 21))
    mask |= (1 << 8) | (1 << 4);
  return mask;
}
```