ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <getidx@plt>
  cltq
  movl   $0x7,(%rsp,%rax,4)
  cmpl   $0x7,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <test_assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int array[5];
  int idx = getidx();
  array[idx] = 7;
  test_assert(array[2] == 7);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <getidx@plt>
  xor    %edi,%edi
  cltq
  movl   $0x7,(%rsp,%rax,4)
  cmpl   $0x7,0x8(%rsp)
  sete   %dil
  call   <test_assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int array[5];
  int idx = getidx();
  array[idx] = 7;
  test_assert(array[2] == 7);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <getidx@plt>
  xor    %edi,%edi
  cltq
  movl   $0x7,(%rsp,%rax,4)
  cmpl   $0x7,0x8(%rsp)
  sete   %dil
  call   <test_assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int array[5];
  int idx = getidx();
  array[idx] = 7;
  test_assert(array[2] == 7);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_sort_partion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L2:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L8
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L2
L8:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L8
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L40
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L2
L40:
  nop
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int quick_sort_partion(int array[], int start, int end) {
  int pivot, i, j, t;
  pivot = array[start];
  i = start;
  j = end + 1;
  while (1) {
    do
      ++i;
    while (array[i] <= pivot && i <= end);
    do
      --j;
    while (array[j] > pivot);
    if (i >= j)
      break;
    t = array[i];
    array[i] = array[j];
    array[j] = t;
  }
  t = array[start];
  array[start] = array[j];
  array[j] = t;
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<quick_sort_partion>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %edx,%ebx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbp
  mov    0x0(%rbp),%r8d
  lea    0x1(%rdx),%ecx
  add    $0x1,%esi
  movslq %esi,%r9
  jmp    L13
L22:
  movslq %ecx,%rax
  lea    -0x4(%r10,%rax,4),%rax
L34:
  sub    $0x1,%ecx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%esi
  cmp    %r8d,%esi
  jg     L34
  cmp    %edx,%ecx
  jle    L55
  mov    %esi,(%r10,%r9,4)
  mov    %r11d,(%rdi)
L23:
  add    $0x1,%r9
L13:
  mov    (%r10,%r9,4),%r11d
  mov    %r9d,%edx
  cmp    %r9d,%ebx
  jl     L22
  cmp    %r8d,%r11d
  jg     L22
  jmp    L23
L55:
  mov    0x0(%rbp),%eax
  mov    %esi,0x0(%rbp)
  mov    %eax,(%rdi)
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int quick_sort_partion(int array[], int start, int end) {
  int pivot, i, j, t;
  pivot = array[start];
  i = start;
  j = end + 1;
  while (1) {
    do
      ++i;
    while (array[i] <= pivot && i <= end);
    do
      --j;
    while (array[j] > pivot);
    if (i >= j)
      break;
    t = array[i];
    array[i] = array[j];
    array[j] = t;
  }
  t = array[start];
  array[start] = array[j];
  array[j] = t;
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_sort_partion>:
  endbr64
  movslq %esi,%rax
  push   %rbp
  mov    %rdi,%r10
  add    $0x1,%esi
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  lea    0x1(%rdx),%r8d
  mov    %edx,%ebx
  mov    0x0(%rbp),%edi
  movslq %esi,%r9
  nop
L7:
  mov    (%r10,%r9,4),%r11d
  mov    %r9d,%edx
  cmp    %edi,%r11d
  jg     L18
  cmp    %r9d,%ebx
  jge    L26
L18:
  movslq %r8d,%rax
  lea    -0x4(%r10,%rax,4),%rax
  nopl   0x0(%rax)
L29:
  mov    %rax,%rsi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%r8d
  cmp    %edi,%ecx
  jg     L29
  cmp    %edx,%r8d
  jle    L49
  mov    %ecx,(%r10,%r9,4)
  mov    %r11d,(%rsi)
L26:
  add    $0x1,%r9
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L49:
  mov    0x0(%rbp),%eax
  mov    %ecx,0x0(%rbp)
  mov    %eax,(%rsi)
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int quick_sort_partion(int array[], int start, int end) {
  int pivot, i, j, t;
  pivot = array[start];
  i = start;
  j = end + 1;
  while (1) {
    do
      ++i;
    while (array[i] <= pivot && i <= end);
    do
      --j;
    while (array[j] > pivot);
    if (i >= j)
      break;
    t = array[i];
    array[i] = array[j];
    array[j] = t;
  }
  t = array[start];
  array[start] = array[j];
  array[j] = t;
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quick_sort_partion>:
  endbr64
  movslq %esi,%rax
  push   %rbp
  mov    %rdi,%r10
  add    $0x1,%esi
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  lea    0x1(%rdx),%r8d
  mov    %edx,%ebx
  mov    0x0(%rbp),%edi
  movslq %esi,%r9
  nop
L18:
  mov    (%r10,%r9,4),%r11d
  mov    %r9d,%edx
  cmp    %edi,%r11d
  jg     L31
  cmp    %r9d,%ebx
  jge    L20
L31:
  movslq %r8d,%rax
  lea    -0x4(%r10,%rax,4),%rax
  nopl   0x0(%rax)
L44:
  mov    %rax,%rsi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%r8d
  cmp    %edi,%ecx
  jg     L44
  cmp    %edx,%r8d
  jle    L10
  mov    %ecx,(%r10,%r9,4)
  mov    %r11d,(%rsi)
L20:
  add    $0x1,%r9
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp),%eax
  mov    %ecx,0x0(%rbp)
  mov    %eax,(%rsi)
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int quick_sort_partion(int array[], int start, int end) {
  int pivot, i, j, t;
  pivot = array[start];
  i = start;
  j = end + 1;
  while (1) {
    do
      ++i;
    while (array[i] <= pivot && i <= end);
    do
      --j;
    while (array[j] > pivot);
    if (i >= j)
      break;
    t = array[i];
    array[i] = array[j];
    array[j] = t;
  }
  t = array[start];
  array[start] = array[j];
  array[j] = t;
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<ttyslot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__sysconf@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  movq   $0x20,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__setttyent@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L42
L65:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <__ttyname_r@plt>
  test   %rax,%rax
  jne    L52
  mov    -0x10(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L57
  addq   $0x1,-0x20(%rbp)
  jmp    L44
L57:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L44:
  movl   $0x1,-0x28(%rbp)
  jmp    L22
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  call   <__endttyent@plt>
  mov    -0x28(%rbp),%eax
  jmp    L16
L15:
  addl   $0x1,-0x28(%rbp)
L22:
  mov    $0x0,%eax
  call   <__getttyent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  jmp    L102
L52:
  addl   $0x1,-0x24(%rbp)
L42:
  cmpl   $0x2,-0x24(%rbp)
  jle    L65
L102:
  mov    $0x0,%eax
  call   <__endttyent@plt>
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int ttyslot(void) {
  struct ttyent *ttyp;
  int slot;
  char *p;
  int cnt;
  size_t buflen = __sysconf(_SC_TTY_NAME_MAX) + 1;
  char *name;
  if (buflen == 0)
    buflen = 32;
  name = __alloca(buflen);
  __setttyent();
  for (cnt = 0; cnt < 3; ++cnt)
    if (__ttyname_r(cnt, name, buflen) == 0) {
      if ((p = rindex(name, '/')))
        ++p;
      else
        p = name;
      for (slot = 1; (ttyp = __getttyent()); ++slot)
        if (!strcmp(ttyp->ty_name, p)) {
          __endttyent();
          return (slot);
        }
      break;
    }
  __endttyent();
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ttyslot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  test   %rbx,%rbx
  mov    $0x20,%eax
  cmove  %rax,%rbx
  mov    %rbx,%rdi
  call   <__alloca@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  call   <__setttyent@plt>
  mov    $0x0,%ebp
L20:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <__ttyname_r@plt>
  test   %rax,%rax
  je     L41
  add    $0x1,%ebp
  cmp    $0x3,%ebp
  jne    L20
L15:
  mov    $0x0,%eax
  call   <__endttyent@plt>
  mov    $0x0,%ebx
L29:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  mov    $0x1,%ebx
L12:
  mov    $0x0,%eax
  call   <__getttyent@plt>
  test   %rax,%rax
  je     L15
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L53
  add    $0x1,%ebx
  jmp    L12
L53:
  call   <__endttyent@plt>
  jmp    L29
```

assistant: ```c
int ttyslot(void) {
  struct ttyent *ttyp;
  int slot;
  char *p;
  int cnt;
  size_t buflen = __sysconf(_SC_TTY_NAME_MAX) + 1;
  char *name;
  if (buflen == 0)
    buflen = 32;
  name = __alloca(buflen);
  __setttyent();
  for (cnt = 0; cnt < 3; ++cnt)
    if (__ttyname_r(cnt, name, buflen) == 0) {
      if ((p = rindex(name, '/')))
        ++p;
      else
        p = name;
      for (slot = 1; (ttyp = __getttyent()); ++slot)
        if (!strcmp(ttyp->ty_name, p)) {
          __endttyent();
          return (slot);
        }
      break;
    }
  __endttyent();
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ttyslot>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  lea    0x1(%rax),%ebx
  mov    $0x20,%eax
  movslq %ebx,%rbx
  test   %rbx,%rbx
  cmove  %rax,%rbx
  xor    %ebp,%ebp
  mov    %rbx,%rdi
  call   <__alloca@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <__setttyent@plt>
L46:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <__ttyname_r@plt>
  test   %rax,%rax
  je     L7
  add    $0x1,%ebp
  cmp    $0x3,%ebp
  jne    L46
L13:
  xor    %eax,%eax
  xor    %r13d,%r13d
  call   <__endttyent@plt>
L4:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    %r12,%rdi
  mov    $0x2f,%esi
  mov    $0x1,%r13d
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L59:
  mov    (%rax),%edi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L30
  add    $0x1,%r13d
L66:
  xor    %eax,%eax
  call   <__getttyent@plt>
  test   %rax,%rax
  jne    L59
  jmp    L13
L30:
  call   <__endttyent@plt>
  jmp    L4
```

assistant: ```c
int ttyslot(void) {
  struct ttyent *ttyp;
  int slot;
  char *p;
  int cnt;
  size_t buflen = __sysconf(_SC_TTY_NAME_MAX) + 1;
  char *name;
  if (buflen == 0)
    buflen = 32;
  name = __alloca(buflen);
  __setttyent();
  for (cnt = 0; cnt < 3; ++cnt)
    if (__ttyname_r(cnt, name, buflen) == 0) {
      if ((p = rindex(name, '/')))
        ++p;
      else
        p = name;
      for (slot = 1; (ttyp = __getttyent()); ++slot)
        if (!strcmp(ttyp->ty_name, p)) {
          __endttyent();
          return (slot);
        }
      break;
    }
  __endttyent();
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ttyslot>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__sysconf@plt>
  lea    0x1(%rax),%ebx
  mov    $0x20,%eax
  movslq %ebx,%rbx
  test   %rbx,%rbx
  cmove  %rax,%rbx
  xor    %ebp,%ebp
  mov    %rbx,%rdi
  call   <__alloca@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <__setttyent@plt>
L25:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <__ttyname_r@plt>
  test   %rax,%rax
  je     L59
  add    $0x1,%ebp
  cmp    $0x3,%ebp
  jne    L25
L54:
  xor    %eax,%eax
  xor    %r13d,%r13d
  call   <__endttyent@plt>
L62:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L59:
  mov    %r12,%rdi
  mov    $0x2f,%esi
  mov    $0x1,%r13d
  call   <rindex@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L66:
  mov    (%rax),%edi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L20
  add    $0x1,%r13d
L19:
  xor    %eax,%eax
  call   <__getttyent@plt>
  test   %rax,%rax
  jne    L66
  jmp    L54
L20:
  call   <__endttyent@plt>
  jmp    L62
```

assistant: ```c
int ttyslot(void) {
  struct ttyent *ttyp;
  int slot;
  char *p;
  int cnt;
  size_t buflen = __sysconf(_SC_TTY_NAME_MAX) + 1;
  char *name;
  if (buflen == 0)
    buflen = 32;
  name = __alloca(buflen);
  __setttyent();
  for (cnt = 0; cnt < 3; ++cnt)
    if (__ttyname_r(cnt, name, buflen) == 0) {
      if ((p = rindex(name, '/')))
        ++p;
      else
        p = name;
      for (slot = 1; (ttyp = __getttyent()); ++slot)
        if (!strcmp(ttyp->ty_name, p)) {
          __endttyent();
          return (slot);
        }
      break;
    }
  __endttyent();
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<realloc_chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <memcheck@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *realloc_chk(void *reallocMe, size_t memsize) {
  void *tmp = realloc(reallocMe, memsize);
  memcheck(tmp);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<realloc_chk>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memcheck@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *realloc_chk(void *reallocMe, size_t memsize) {
  void *tmp = realloc(reallocMe, memsize);
  memcheck(tmp);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<realloc_chk>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcheck@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *realloc_chk(void *reallocMe, size_t memsize) {
  void *tmp = realloc(reallocMe, memsize);
  memcheck(tmp);
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<realloc_chk>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcheck@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *realloc_chk(void *reallocMe, size_t memsize) {
  void *tmp = realloc(reallocMe, memsize);
  memcheck(tmp);
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x7296,%dx
  movzwl %dx,%eax
  shl    $0x9,%eax
  shr    $0x7,%dx
  movzwl %dx,%edx
  or     %edx,%eax
  lea    (%rax,%rax,1),%edx
  sar    $0xf,%eax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          state[0UL] = state[local1] | state[0UL];
        } else {
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) << (unsigned short)1) | (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) >> (unsigned short)15);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  movzwl %ax,%edx
  shr    $0x7,%ax
  shl    $0x9,%edx
  movzwl %ax,%eax
  or     %edx,%eax
  lea    (%rax,%rax,1),%edx
  sar    $0xf,%eax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          state[0UL] = state[local1] | state[0UL];
        } else {
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) << (unsigned short)1) | (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) >> (unsigned short)15);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  movzwl %ax,%edx
  shr    $0x7,%ax
  shl    $0x9,%edx
  movzwl %ax,%eax
  or     %edx,%eax
  lea    (%rax,%rax,1),%edx
  sar    $0xf,%eax
  or     %edx,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          state[0UL] = state[local1] | state[0UL];
        } else {
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) << (unsigned short)1) | (((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) >> (unsigned short)15);
  }
}
```