ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<chl_posti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <chl_post@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L53
  mov    $0xffffffff,%eax
  jmp    L40
L53:
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  je     L57
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  je     L57
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L2
L57:
  mov    $0xffffffff,%eax
  jmp    L40
L2:
  mov    -0x10(%rbp),%rax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int chl_posti(char *name) {
  char *val, *err;
  long int ret;
  if (!(val = chl_post(name)))
    return -1;
  ret = strtol(val, &err, 10);
  if ((val == err) || (ret == LONG_MIN) || (ret == LONG_MAX))
    return -1;
  return (int)ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chl_posti>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <chl_post@plt>
  test   %rax,%rax
  je     L52
  mov    %rax,%rbx
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rax,%rdi
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  je     L31
  mov    D14(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L40
  mov    D4(%rip),%rdx
  cmp    %rax,(%rdx)
  mov    $0xffffffff,%edx
  cmove  %edx,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x10,%rsp
  pop    %rbx
  ret
L52:
  mov    $0xffffffff,%eax
  jmp    L7
L31:
  mov    $0xffffffff,%eax
  jmp    L7
L40:
  mov    $0xffffffff,%eax
  jmp    L7
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int chl_posti(char *name) {
  char *val, *err;
  long int ret;
  if (!(val = chl_post(name)))
    return -1;
  ret = strtol(val, &err, 10);
  if ((val == err) || (ret == LONG_MIN) || (ret == LONG_MAX))
    return -1;
  return (int)ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chl_posti>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <chl_post@plt>
  test   %rax,%rax
  je     L18
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  je     L18
  mov    D9(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L18
  mov    D15(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L18
L42:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  jmp    L42
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int chl_posti(char *name) {
  char *val, *err;
  long int ret;
  if (!(val = chl_post(name)))
    return -1;
  ret = strtol(val, &err, 10);
  if ((val == err) || (ret == LONG_MIN) || (ret == LONG_MAX))
    return -1;
  return (int)ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chl_posti>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <chl_post@plt>
  test   %rax,%rax
  je     L21
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  je     L21
  mov    D1(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L21
  mov    D17(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L21
L30:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%eax
  jmp    L30
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int chl_posti(char *name) {
  char *val, *err;
  long int ret;
  if (!(val = chl_post(name)))
    return -1;
  ret = strtol(val, &err, 10);
  if ((val == err) || (ret == LONG_MIN) || (ret == LONG_MAX))
    return -1;
  return (int)ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x98(%rbp)
  lea    -0x90(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0xa0(%rbp)
  movl   $0x0,-0x9c(%rbp)
  jmp    L1
L84:
  mov    -0xa0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L63
  mov    -0xa0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x9c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x9c(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x90(%rbp,%rax,1)
  cmpl   $0x7f,-0x9c(%rbp)
  jne    L24
  jmp    L69
L63:
  mov    -0xa0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L47
L24:
  addl   $0x1,-0xa0(%rbp)
L1:
  mov    -0xa0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L84
  jmp    L69
L47:
  nop
L69:
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jne    L43
  lea    -0x90(%rbp),%rax
  add    $0x1,%rax
  lea    -0x90(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  movb   $0x31,-0x90(%rbp)
L43:
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D2: 448080000105

tool: D8: Test after: %s


assistant: ```c
int main() {
  int i, j;
  char phone_number[128];
  char *username = strdup("448080000105");
  memset(phone_number, 0, sizeof(phone_number));
  for (i = 0, j = 0; username[i]; i++) {
    if (isdigit(username[i])) {
      phone_number[j++] = username[i];
      if (j == sizeof(phone_number) - 1)
        break;
    } else if (username[i] == '*') {
      break;
    };
  };
  free(username);
  if (strlen(phone_number) == 10) {
    memmove(phone_number + 1, phone_number, 10);
    phone_number[0] = '1';
  };
  printf("Test after: %s\n", phone_number);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L53
  mov    %r12,%rbx
  mov    $0x0,%ebp
  jmp    L3
L83:
  cmpb   $0x2a,(%rbx)
  je     L53
L59:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L53
L3:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L83
  lea    0x1(%rbp),%ecx
  movslq %ebp,%rax
  movzbl (%rbx),%edx
  mov    %dl,(%rsp,%rax,1)
  cmp    $0x7e,%ebp
  je     L53
  mov    %ecx,%ebp
  jmp    L59
L53:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L88
L13:
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L88:
  mov    %rsp,%rsi
  lea    0x1(%rsp),%rdi
  mov    $0xa,%edx
  call   <memmove@plt>
  movb   $0x31,(%rsp)
  jmp    L13
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D6: 448080000105

tool: D19: Test after: %s


assistant: ```c
int main() {
  int i, j;
  char phone_number[128];
  char *username = strdup("448080000105");
  memset(phone_number, 0, sizeof(phone_number));
  for (i = 0, j = 0; username[i]; i++) {
    if (isdigit(username[i])) {
      phone_number[j++] = username[i];
      if (j == sizeof(phone_number) - 1)
        break;
    } else if (username[i] == '*') {
      break;
    };
  };
  free(username);
  if (strlen(phone_number) == 10) {
    memmove(phone_number + 1, phone_number, 10);
    phone_number[0] = '1';
  };
  printf("Test after: %s\n", phone_number);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    $0x80,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  call   <memset@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L67
  mov    %r12,%rbx
  xor    %ebp,%ebp
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L72:
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  lea    0x1(%rbp),%ecx
  mov    %dl,(%rsp,%rax,1)
  cmp    $0x7e,%ebp
  je     L67
  mov    %ecx,%ebp
L62:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L67
L18:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L72
  cmpb   $0x2a,(%rbx)
  jne    L62
L67:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L27
L66:
  mov    %r13,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    0x1(%rsp),%rdi
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  movb   $0x31,(%rsp)
  jmp    L66
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string

tool: D7: 448080000105

tool: D4: Test after: %s


assistant: ```c
int main() {
  int i, j;
  char phone_number[128];
  char *username = strdup("448080000105");
  memset(phone_number, 0, sizeof(phone_number));
  for (i = 0, j = 0; username[i]; i++) {
    if (isdigit(username[i])) {
      phone_number[j++] = username[i];
      if (j == sizeof(phone_number) - 1)
        break;
    } else if (username[i] == '*') {
      break;
    };
  };
  free(username);
  if (strlen(phone_number) == 10) {
    memmove(phone_number + 1, phone_number, 10);
    phone_number[0] = '1';
  };
  printf("Test after: %s\n", phone_number);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    $0x80,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  call   <memset@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L82
  mov    %r12,%rbx
  xor    %ebp,%ebp
  jmp    L83
  cs nopw 0x0(%rax,%rax,1)
L85:
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  lea    0x1(%rbp),%ecx
  mov    %dl,(%rsp,%rax,1)
  cmp    $0x7e,%ebp
  je     L82
  mov    %ecx,%ebp
L16:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L82
L83:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L85
  cmpb   $0x2a,(%rbx)
  jne    L16
L82:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L80
L78:
  mov    %r13,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L80:
  lea    0x1(%rsp),%rdi
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  movb   $0x31,(%rsp)
  jmp    L78
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string

tool: D7: 448080000105

tool: D14: Test after: %s


assistant: ```c
int main() {
  int i, j;
  char phone_number[128];
  char *username = strdup("448080000105");
  memset(phone_number, 0, sizeof(phone_number));
  for (i = 0, j = 0; username[i]; i++) {
    if (isdigit(username[i])) {
      phone_number[j++] = username[i];
      if (j == sizeof(phone_number) - 1)
        break;
    } else if (username[i] == '*') {
      break;
    };
  };
  free(username);
  if (strlen(phone_number) == 10) {
    memmove(phone_number + 1, phone_number, 10);
    phone_number[0] = '1';
  };
  printf("Test after: %s\n", phone_number);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x14,%eax
  or     %eax,-0xc(%rbp)
  andl   $0xfe0fe00,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long foo(unsigned char c) {
  unsigned long l;
  unsigned int i;
  i = ((unsigned int)c) << 8;
  i |= ((unsigned int)c) << 20;
  asm volatile("" :::);
  i = i & 0x0fe0fe00;
  asm volatile("" :::);
  l = (unsigned long)i;
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  shl    $0x8,%edx
  mov    %edi,%eax
  shl    $0x14,%eax
  or     %edx,%eax
  and    $0xfe0fe00,%eax
  ret
```

assistant: ```c
unsigned long foo(unsigned char c) {
  unsigned long l;
  unsigned int i;
  i = ((unsigned int)c) << 8;
  i |= ((unsigned int)c) << 20;
  asm volatile("" :::);
  i = i & 0x0fe0fe00;
  asm volatile("" :::);
  l = (unsigned long)i;
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x8,%edx
  shl    $0x14,%eax
  or     %edx,%eax
  and    $0xfe0fe00,%eax
  ret
```

assistant: ```c
unsigned long foo(unsigned char c) {
  unsigned long l;
  unsigned int i;
  i = ((unsigned int)c) << 8;
  i |= ((unsigned int)c) << 20;
  asm volatile("" :::);
  i = i & 0x0fe0fe00;
  asm volatile("" :::);
  l = (unsigned long)i;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x8,%edx
  shl    $0x14,%eax
  or     %edx,%eax
  and    $0xfe0fe00,%eax
  ret
```

assistant: ```c
unsigned long foo(unsigned char c) {
  unsigned long l;
  unsigned int i;
  i = ((unsigned int)c) << 8;
  i |= ((unsigned int)c) << 20;
  asm volatile("" :::);
  i = i & 0x0fe0fe00;
  asm volatile("" :::);
  l = (unsigned long)i;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x64,%edi
  call   <plus@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  plus(100);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <plus@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  plus(100);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <plus@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  plus(100);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <plus@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  plus(100);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<checkEndianness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L14:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D19: little endian


tool: D1: big endian


assistant: ```c
void checkEndianness() {
  unsigned int i = 1;
  char *c = (char *)&i;
  if (*c) {
    printf("little endian\n");
  } else {
    printf("big endian\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checkEndianness>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: little endian


assistant: ```c
void checkEndianness() {
  unsigned int i = 1;
  char *c = (char *)&i;
  if (*c) {
    printf("little endian\n");
  } else {
    printf("big endian\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checkEndianness>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: little endian


assistant: ```c
void checkEndianness() {
  unsigned int i = 1;
  char *c = (char *)&i;
  if (*c) {
    printf("little endian\n");
  } else {
    printf("big endian\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkEndianness>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string

tool: D5: little endian


assistant: ```c
void checkEndianness() {
  unsigned int i = 1;
  char *c = (char *)&i;
  if (*c) {
    printf("little endian\n");
  } else {
    printf("big endian\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<comments_get_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <keyvals_get_val@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L68
  mov    $0xffffffff,%eax
  jmp    L113
L68:
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x3e7,-0x2c(%rbp)
  jle    L158
  cmpl   $0x270f,-0x2c(%rbp)
  jle    L131
L158:
  mov    $0xffffffff,%eax
  jmp    L113
L131:
  mov    -0x2c(%rbp),%eax
  imul   $0x2710,%eax,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L79
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L79
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L27
L79:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtol@plt>
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L94
  cmpl   $0xc,-0x28(%rbp)
  jle    L0
L94:
  mov    -0x18(%rbp),%rax
  jmp    L113
L0:
  mov    -0x28(%rbp),%eax
  imul   $0x64,%eax,%eax
  cltq
  add    %rax,-0x18(%rbp)
L27:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L51
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L51
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L15
L51:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtol@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L174
  cmpl   $0x1f,-0x24(%rbp)
  jle    L118
L174:
  mov    -0x18(%rbp),%rax
  jmp    L113
L118:
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
L113:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L140
  call   <__stack_chk_fail@plt>
L140:
  leave
  ret
```

assistant: ```c
int comments_get_date(const struct keyval *comments, const char *key) {
  const char *val;
  char *endptr;
  int year, month, day;
  long int ival;
  val = keyvals_get_val(comments, key);
  if (val == NULL)
    return -1;
  year = strtol(val, &endptr, 10);
  if (year < 1000 || year > 9999)
    return -1;
  ival = year * 10000;
  if (*endptr == '-' || *endptr == ' ' || *endptr == '/') {
    month = strtol(endptr + 1, &endptr, 10);
    if (month < 1 || month > 12)
      return ival;
    ival += month * 100;
  }
  if (*endptr == '-' || *endptr == ' ' || *endptr == '/') {
    day = strtol(endptr + 1, &endptr, 10);
    if (day < 1 || day > 31)
      return ival;
    ival += day;
  }
  return ival;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comments_get_date>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <keyvals_get_val@plt>
  test   %rax,%rax
  je     L69
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  lea    -0x3e8(%rax),%edx
  cmp    $0x2327,%edx
  ja     L37
  imul   $0x2710,%eax,%ebx
  movslq %ebx,%rbp
  mov    (%rsp),%rdi
  movzbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xfffffffd,%edx
  cmp    $0x2d,%dl
  je     L7
  cmp    $0x20,%al
  je     L7
L73:
  mov    %ebp,%ebx
L94:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L91
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rsp,%rsi
  add    $0x1,%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  lea    -0x1(%rax),%edx
  cmp    $0xb,%edx
  ja     L94
  imul   $0x64,%eax,%eax
  cltq
  add    %rax,%rbp
  mov    (%rsp),%rdi
  movzbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xfffffffd,%edx
  cmp    $0x2d,%dl
  je     L66
  cmp    $0x20,%al
  jne    L73
L66:
  mov    %rsp,%rsi
  add    $0x1,%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  lea    -0x1(%rax),%edx
  mov    %ebp,%ebx
  cmp    $0x1e,%edx
  ja     L94
  cltq
  add    %rax,%rbp
  jmp    L73
L69:
  mov    $0xffffffff,%ebx
  jmp    L94
L37:
  mov    $0xffffffff,%ebx
  jmp    L94
L91:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int comments_get_date(const struct keyval *comments, const char *key) {
  const char *val;
  char *endptr;
  int year, month, day;
  long int ival;
  val = keyvals_get_val(comments, key);
  if (val == NULL)
    return -1;
  year = strtol(val, &endptr, 10);
  if (year < 1000 || year > 9999)
    return -1;
  ival = year * 10000;
  if (*endptr == '-' || *endptr == ' ' || *endptr == '/') {
    month = strtol(endptr + 1, &endptr, 10);
    if (month < 1 || month > 12)
      return ival;
    ival += month * 100;
  }
  if (*endptr == '-' || *endptr == ' ' || *endptr == '/') {
    day = strtol(endptr + 1, &endptr, 10);
    if (day < 1 || day > 31)
      return ival;
    ival += day;
  }
  return ival;
}
```