ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SendPacket>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <CheckSum@plt>
  lea    0xc(%rsp),%rdi
  mov    $0x1,%esi
  addl   $0x2,0xc(%rsp)
  mov    %eax,0x10(%rsp)
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L54
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L54
  mov    0xc(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x2(%rax),%esi
  mov    %esi,0xc(%rsp)
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L54
  test   %ebx,%ebx
  je     L71
  lea    0x14(%rsp),%rbx
  jmp    L23
  nopl   0x0(%rax)
L79:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L11
L23:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <UARTReceiveData@plt>
  test   %rax,%rax
  je     L79
L54:
  mov    $0xffffffff,%eax
L71:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    $0xcc,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L71
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t SendPacket(uint8_t *pui8Data, uint8_t ui8Size, bool bAck) {
  uint8_t ui8CheckSum;
  uint8_t ui8Ack;
  ui8CheckSum = CheckSum(pui8Data, ui8Size);
  ui8Size += 2;
  if (UARTSendData(&ui8Size, 1)) {
    return (-1);
  }
  if (UARTSendData(&ui8CheckSum, 1)) {
    return (-1);
  }
  ui8Size -= 2;
  if (UARTSendData(pui8Data, ui8Size)) {
    return (-1);
  }
  if (!bAck) {
    return (0);
  }
  do {
    if (UARTReceiveData(&ui8Ack, 1)) {
      return (-1);
    }
  } while (ui8Ack == 0);
  if (ui8Ack != 0xcc) {
    return (-1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SendPacket>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <CheckSum@plt>
  lea    0xc(%rsp),%rdi
  mov    $0x1,%esi
  addl   $0x2,0xc(%rsp)
  mov    %eax,0x10(%rsp)
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L38
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L38
  mov    0xc(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0x2(%rax),%esi
  mov    %esi,0xc(%rsp)
  call   <UARTSendData@plt>
  test   %rax,%rax
  jne    L38
  test   %ebx,%ebx
  je     L48
  lea    0x14(%rsp),%rbx
  jmp    L30
  nopl   0x0(%rax)
L79:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L7
L30:
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <UARTReceiveData@plt>
  test   %rax,%rax
  je     L79
L38:
  mov    $0xffffffff,%eax
L48:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    $0xcc,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L48
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t SendPacket(uint8_t *pui8Data, uint8_t ui8Size, bool bAck) {
  uint8_t ui8CheckSum;
  uint8_t ui8Ack;
  ui8CheckSum = CheckSum(pui8Data, ui8Size);
  ui8Size += 2;
  if (UARTSendData(&ui8Size, 1)) {
    return (-1);
  }
  if (UARTSendData(&ui8CheckSum, 1)) {
    return (-1);
  }
  ui8Size -= 2;
  if (UARTSendData(pui8Data, ui8Size)) {
    return (-1);
  }
  if (!bAck) {
    return (0);
  }
  do {
    if (UARTReceiveData(&ui8Ack, 1)) {
      return (-1);
    }
  } while (ui8Ack == 0);
  if (ui8Ack != 0xcc) {
    return (-1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void my_strcpy(char *dest, const char *src) {
  for (int i = 0; src[i]; i++) {
    dest[i] = src[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L7
  mov    $0x0,%eax
L0:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L0
L7:
  ret
```

assistant: ```c
void my_strcpy(char *dest, const char *src) {
  for (int i = 0; src[i]; i++) {
    dest[i] = src[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L14
  xor    %eax,%eax
  nopl   (%rax)
L13:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L13
L14:
  ret
```

assistant: ```c
void my_strcpy(char *dest, const char *src) {
  for (int i = 0; src[i]; i++) {
    dest[i] = src[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L4
  xor    %eax,%eax
  nopl   (%rax)
L6:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L6
L4:
  ret
```

assistant: ```c
void my_strcpy(char *dest, const char *src) {
  for (int i = 0; src[i]; i++) {
    dest[i] = src[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<send_to_proc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D33(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D33
type_guessed: string

tool: D7: w

tool: D21: /proc/minifirewall

tool: D10: Cannot open /proc/minifirewall for writting


tool: D33: %s

assistant: ```c
void send_to_proc(char *str) {
  FILE *pf;
  pf = fopen("/proc/minifirewall", "w");
  if (pf == NULL) {
    printf("Cannot open /proc/minifirewall for writting\n");
    return;
  } else {
    fprintf(pf, "%s", str);
  }
  fclose(pf);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_to_proc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D24(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D28
data_type: string

tool: D24: w

tool: D17: /proc/minifirewall

tool: D29: %s

tool: D28: Cannot open /proc/minifirewall for writting


assistant: ```c
void send_to_proc(char *str) {
  FILE *pf;
  pf = fopen("/proc/minifirewall", "w");
  if (pf == NULL) {
    printf("Cannot open /proc/minifirewall for writting\n");
    return;
  } else {
    fprintf(pf, "%s", str);
  }
  fclose(pf);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_to_proc>:
  endbr64
  push   %r12
  lea    D36(%rip),%rsi
  mov    %rdi,%r12
  lea    D0(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L7
  mov    %r12,%rdx
  mov    %rax,%rdi
  lea    D37(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <fclose@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D37
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D36: w

tool: D0: /proc/minifirewall

tool: D37: %s

tool: D14: Cannot open /proc/minifirewall for writting


assistant: ```c
void send_to_proc(char *str) {
  FILE *pf;
  pf = fopen("/proc/minifirewall", "w");
  if (pf == NULL) {
    printf("Cannot open /proc/minifirewall for writting\n");
    return;
  } else {
    fprintf(pf, "%s", str);
  }
  fclose(pf);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_to_proc>:
  endbr64
  push   %r12
  lea    D31(%rip),%rsi
  mov    %rdi,%r12
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L3
  mov    %r12,%rdx
  mov    %rax,%rdi
  lea    D10(%rip),%rsi
  mov    %rax,%rbp
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <fclose@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D31
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D8
type_infered: string

tool: D31: w

tool: D5: /proc/minifirewall

tool: D10: %s

tool: D8: Cannot open /proc/minifirewall for writting


assistant: ```c
void send_to_proc(char *str) {
  FILE *pf;
  pf = fopen("/proc/minifirewall", "w");
  if (pf == NULL) {
    printf("Cannot open /proc/minifirewall for writting\n");
    return;
  } else {
    fprintf(pf, "%s", str);
  }
  fclose(pf);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<addm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  addq   $0x1c,-0x20(%rbp)
  addq   $0x1c,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L7:
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%rbx
  mov    %rbx,%rax
  and    $0x10000,%eax
  test   %rax,%rax
  je     L2
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L2:
  movl   $0x0,-0xc(%rbp)
L15:
  mov    %ebx,%edx
  mov    -0x28(%rbp),%rax
  mov    %dx,(%rax)
  subq   $0x2,-0x20(%rbp)
  subq   $0x2,-0x28(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  cmpl   $0xc,-0x10(%rbp)
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int addm(x, y)
unsigned short *x, *y;
{
  register unsigned long a;
  int i;
  unsigned int carry;
  x += 14;
  y += 14;
  carry = 0;
  for (i = 0; i < 14 - 1; i++) {
    a = (unsigned long)(*x) + (unsigned long)(*y) + carry;
    if (a & 0x10000)
      carry = 1;
    else
      carry = 0;
    *y = a;
    --x;
    --y;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<addm>:
  endbr64
  mov    $0x1c,%ecx
  mov    $0x0,%edx
L4:
  movzwl (%rdi,%rcx,1),%eax
  movzwl (%rsi,%rcx,1),%r8d
  add    %r8,%rax
  mov    %edx,%edx
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  and    $0x1,%edx
  mov    %ax,(%rsi,%rcx,1)
  sub    $0x2,%rcx
  cmp    $0x2,%rcx
  jne    L4
  mov    $0x0,%eax
  ret
```

assistant: ```c
int addm(x, y)
unsigned short *x, *y;
{
  register unsigned long a;
  int i;
  unsigned int carry;
  x += 14;
  y += 14;
  carry = 0;
  for (i = 0; i < 14 - 1; i++) {
    a = (unsigned long)(*x) + (unsigned long)(*y) + carry;
    if (a & 0x10000)
      carry = 1;
    else
      carry = 0;
    *y = a;
    --x;
    --y;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<addm>:
  endbr64
  mov    $0x1c,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L6:
  movzwl (%rdi,%rcx,1),%eax
  movzwl (%rsi,%rcx,1),%r8d
  add    %r8,%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  mov    %ax,(%rsi,%rcx,1)
  sub    $0x2,%rcx
  shr    $0x10,%rdx
  and    $0x1,%edx
  cmp    $0x2,%rcx
  jne    L6
  xor    %eax,%eax
  ret
```

assistant: ```c
int addm(x, y)
unsigned short *x, *y;
{
  register unsigned long a;
  int i;
  unsigned int carry;
  x += 14;
  y += 14;
  carry = 0;
  for (i = 0; i < 14 - 1; i++) {
    a = (unsigned long)(*x) + (unsigned long)(*y) + carry;
    if (a & 0x10000)
      carry = 1;
    else
      carry = 0;
    *y = a;
    --x;
    --y;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<addm>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rdx
  movzwl 0x1c(%rsi),%esi
  movzwl 0x1c(%rdi),%edi
  movzwl 0x1a(%rax),%r8d
  lea    (%rdi,%rsi,1),%ecx
  add    %rdi,%rsi
  movzwl 0x18(%rax),%edi
  mov    %cx,0x1c(%rax)
  movzwl 0x1a(%rdx),%ecx
  shr    $0x10,%rsi
  add    %r8,%rcx
  add    %rsi,%rcx
  mov    %cx,0x1a(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x18(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0x16(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0x18(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x16(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0x14(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0x16(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x14(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0x12(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0x14(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x12(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0x10(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0x12(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x10(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0xe(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0x10(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0xe(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0xc(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0xe(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0xc(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0xa(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0xc(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0xa(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  movzwl 0x8(%rax),%edi
  add    %rsi,%rcx
  mov    %cx,0xa(%rax)
  shr    $0x10,%rcx
  mov    %rcx,%rsi
  movzwl 0x8(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  add    %rsi,%rcx
  mov    %cx,0x8(%rax)
  shr    $0x10,%rcx
  movzwl 0x6(%rax),%edi
  mov    %rcx,%rsi
  movzwl 0x6(%rdx),%ecx
  and    $0x1,%esi
  add    %rdi,%rcx
  add    %rsi,%rcx
  movzwl 0x4(%rax),%esi
  mov    %cx,0x6(%rax)
  movzwl 0x4(%rdx),%edx
  shr    $0x10,%rcx
  and    $0x1,%ecx
  add    %rsi,%rdx
  add    %rcx,%rdx
  mov    %dx,0x4(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int addm(x, y)
unsigned short *x, *y;
{
  register unsigned long a;
  int i;
  unsigned int carry;
  x += 14;
  y += 14;
  carry = 0;
  for (i = 0; i < 14 - 1; i++) {
    a = (unsigned long)(*x) + (unsigned long)(*y) + carry;
    if (a & 0x10000)
      carry = 1;
    else
      carry = 0;
    *y = a;
    --x;
    --y;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<writeInBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L15:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc_unlocked@plt>
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    %eax,-0x14(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  sub    %eax,-0x8(%rbp)
L13:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L15
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc_unlocked@plt>
  nop
  leave
  ret
```

assistant: ```c
void writeInBytes(uint_fast32_t Number, uint_fast32_t BitsCount, FILE *OutputFile) {
  int_fast32_t OutputByte = 0;
  for (uint_fast32_t i = (BitsCount - CHAR_BIT); i >= CHAR_BIT; i -= CHAR_BIT) {
    OutputByte = Number >> i;
    putc_unlocked(OutputByte, OutputFile);
    Number -= (OutputByte << i);
  }
  putc_unlocked(Number, OutputFile);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeInBytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rdx,%r13
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  sub    %eax,%esi
  mov    %esi,%ebx
  cmp    %esi,%eax
  jg     L3
L8:
  mov    %r12d,%ebp
  mov    %ebx,%ecx
  sar    %cl,%ebp
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <putc_unlocked@plt>
  mov    %ebx,%ecx
  shl    %cl,%ebp
  sub    %ebp,%r12d
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  sub    %eax,%ebx
  cmp    %ebx,%eax
  jle    L8
L3:
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <putc_unlocked@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void writeInBytes(uint_fast32_t Number, uint_fast32_t BitsCount, FILE *OutputFile) {
  int_fast32_t OutputByte = 0;
  for (uint_fast32_t i = (BitsCount - CHAR_BIT); i >= CHAR_BIT; i -= CHAR_BIT) {
    OutputByte = Number >> i;
    putc_unlocked(OutputByte, OutputFile);
    Number -= (OutputByte << i);
  }
  putc_unlocked(Number, OutputFile);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<writeInBytes>:
  endbr64
  push   %r14
  mov    D6(%rip),%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    (%r14),%eax
  sub    %eax,%esi
  cmp    %esi,%eax
  jg     L3
  mov    %esi,%ebx
  nopl   0x0(%rax)
L19:
  mov    %ebx,%ecx
  mov    %r12d,%ebp
  mov    %r13,%rsi
  sar    %cl,%ebp
  mov    %ebp,%edi
  call   <putc_unlocked@plt>
  mov    (%r14),%eax
  mov    %ebx,%ecx
  shl    %cl,%ebp
  sub    %eax,%ebx
  sub    %ebp,%r12d
  cmp    %ebx,%eax
  jle    L19
L3:
  pop    %rbx
  mov    %r13,%rsi
  pop    %rbp
  mov    %r12d,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <putc_unlocked@plt>
```

assistant: ```c
void writeInBytes(uint_fast32_t Number, uint_fast32_t BitsCount, FILE *OutputFile) {
  int_fast32_t OutputByte = 0;
  for (uint_fast32_t i = (BitsCount - CHAR_BIT); i >= CHAR_BIT; i -= CHAR_BIT) {
    OutputByte = Number >> i;
    putc_unlocked(OutputByte, OutputFile);
    Number -= (OutputByte << i);
  }
  putc_unlocked(Number, OutputFile);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeInBytes>:
  endbr64
  push   %r14
  mov    D8(%rip),%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    (%r14),%eax
  sub    %eax,%esi
  cmp    %esi,%eax
  jg     L8
  mov    %esi,%ebx
  nopl   0x0(%rax)
L7:
  mov    %ebx,%ecx
  mov    %r12d,%ebp
  mov    %r13,%rsi
  sar    %cl,%ebp
  mov    %ebp,%edi
  call   <putc_unlocked@plt>
  mov    (%r14),%eax
  mov    %ebx,%ecx
  shl    %cl,%ebp
  sub    %eax,%ebx
  sub    %ebp,%r12d
  cmp    %ebx,%eax
  jle    L7
L8:
  pop    %rbx
  mov    %r13,%rsi
  pop    %rbp
  mov    %r12d,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <putc_unlocked@plt>
```

assistant: ```c
void writeInBytes(uint_fast32_t Number, uint_fast32_t BitsCount, FILE *OutputFile) {
  int_fast32_t OutputByte = 0;
  for (uint_fast32_t i = (BitsCount - CHAR_BIT); i >= CHAR_BIT; i -= CHAR_BIT) {
    OutputByte = Number >> i;
    putc_unlocked(OutputByte, OutputFile);
    Number -= (OutputByte << i);
  }
  putc_unlocked(Number, OutputFile);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<t_inner_counting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <assert_test@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string

tool: D27: 1.10

tool: D22: 1.2

assistant: ```c
void t_inner_counting(void *context) {
  char *test_case[] = {"1.10", "1.2"};
  char *expected[] = {"1.2", "1.10"};
  assert_test(sizeof(test_case) / sizeof(char *), test_case, expected);
}
```
user: Translate the below assembly code into C programming language:

```asm
<t_inner_counting>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,(%rsp)
  lea    D3(%rip),%rdx
  mov    %rdx,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  mov    $0x2,%edi
  call   <assert_test@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D16: 1.10

tool: D3: 1.2

assistant: ```c
void t_inner_counting(void *context) {
  char *test_case[] = {"1.10", "1.2"};
  char *expected[] = {"1.2", "1.10"};
  assert_test(sizeof(test_case) / sizeof(char *), test_case, expected);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t_inner_counting>:
  endbr64
  sub    $0x38,%rsp
  lea    D2(%rip),%rdx
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D11(%rip),%rax
  mov    %rsp,%rsi
  mov    %rdx,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rax,(%rsp)
  mov    %rax,0x18(%rsp)
  call   <assert_test@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D2: 1.2

tool: D11: 1.10

assistant: ```c
void t_inner_counting(void *context) {
  char *test_case[] = {"1.10", "1.2"};
  char *expected[] = {"1.2", "1.10"};
  assert_test(sizeof(test_case) / sizeof(char *), test_case, expected);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t_inner_counting>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D14(%rip),%rax
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  movq   %rax,%xmm1
  lea    D3(%rip),%rax
  movq   %rax,%xmm0
  movdqa %xmm1,%xmm2
  punpcklqdq %xmm0,%xmm2
  punpcklqdq %xmm1,%xmm0
  movaps %xmm2,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <assert_test@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D3
type: string

tool: D14: 1.10

tool: D3: 1.2

assistant: ```c
void t_inner_counting(void *context) {
  char *test_case[] = {"1.10", "1.2"};
  char *expected[] = {"1.2", "1.10"};
  assert_test(sizeof(test_case) / sizeof(char *), test_case, expected);
}
```