ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load_options>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L4:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L4
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edx
  call   <check_options@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <load_command_line@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <preload_options@plt>
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <check_options@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <parse_options@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <free_command_line@plt>
  mov    $0x0,%eax
  call   <clean_config@plt>
  mov    $0x0,%ebp
L32:
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %ebp,%eax
  add    $0x4010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    %eax,%ebp
  mov    %rsp,%rsi
  mov    %ebx,%edi
  call   <free_command_line@plt>
  jmp    L32
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int load_options(int argc, char *const argv[]) {
  char *argv_new[2048];
  int argc_new;
  check_options(argc, argv, 1);
  argc_new = load_command_line(argc, argv, argv_new);
  preload_options(argc_new, argv_new);
  check_options(argc_new, argv_new, 0);
  if (parse_options(argc_new, argv_new) == -1) {
    free_command_line(argc_new, argv_new);
    return -1;
  }
  free_command_line(argc_new, argv_new);
  clean_config();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<load_options>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0x10,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %edi,%ebp
  mov    %rsi,%r13
  call   <check_options@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <load_command_line@plt>
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <preload_options@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <check_options@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <parse_options@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    %r12,%rsi
  mov    %ebp,%edi
  xor    %r13d,%r13d
  call   <free_command_line@plt>
  xor    %eax,%eax
  call   <clean_config@plt>
L26:
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x4010,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <free_command_line@plt>
  jmp    L26
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int load_options(int argc, char *const argv[]) {
  char *argv_new[2048];
  int argc_new;
  check_options(argc, argv, 1);
  argc_new = load_command_line(argc, argv, argv_new);
  preload_options(argc_new, argv_new);
  check_options(argc_new, argv_new, 0);
  if (parse_options(argc_new, argv_new) == -1) {
    free_command_line(argc_new, argv_new);
    return -1;
  }
  free_command_line(argc_new, argv_new);
  clean_config();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<load_options>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0x10,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %edi,%ebp
  mov    %rsi,%r13
  call   <check_options@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <load_command_line@plt>
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <preload_options@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <check_options@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <parse_options@plt>
  cmp    $0xffffffff,%eax
  je     L38
  mov    %r12,%rsi
  mov    %ebp,%edi
  xor    %r13d,%r13d
  call   <free_command_line@plt>
  xor    %eax,%eax
  call   <clean_config@plt>
L26:
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x4010,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <free_command_line@plt>
  jmp    L26
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int load_options(int argc, char *const argv[]) {
  char *argv_new[2048];
  int argc_new;
  check_options(argc, argv, 1);
  argc_new = load_command_line(argc, argv, argv_new);
  preload_options(argc_new, argv_new);
  check_options(argc_new, argv_new, 0);
  if (parse_options(argc_new, argv_new) == -1) {
    free_command_line(argc_new, argv_new);
    return -1;
  }
  free_command_line(argc_new, argv_new);
  clean_config();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L14
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = (int)streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_value>:
  endbr64
  mov    %rdi,%r8
  cmp    %esi,%edx
  jle    L19
  movslq %edx,%rdi
  lea    (%r8,%rdi,1),%rax
  lea    -0x1(%r8,%rdi,1),%rdi
  sub    %esi,%edx
  lea    -0x1(%rdx),%edx
  sub    %rdx,%rdi
L18:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L19:
  movslq %esi,%rsi
  mov    %cl,(%r8,%rsi,1)
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = (int)streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_value>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%edx
  jle    L0
  mov    %edx,%eax
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  sub    $0x1,%eax
  sub    %rax,%rdx
  lea    0x1(%rax),%r8
  sub    %rax,%rsi
  add    %rdi,%rsi
  lea    (%rdi,%rdx,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L0:
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = (int)streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_value>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%edx
  jle    L8
  mov    %edx,%eax
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  sub    $0x1,%eax
  sub    %rax,%rdx
  lea    0x1(%rax),%r8
  sub    %rax,%rsi
  add    %rdi,%rsi
  lea    (%rdi,%rdx,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L8:
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = (int)streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uncomp_mode_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0xb0020,-0x18(%rbp)
  je     L243
  cmpq   $0xb0020,-0x18(%rbp)
  jg     L335
  cmpq   $0xa0040,-0x18(%rbp)
  je     L42
  cmpq   $0xa0040,-0x18(%rbp)
  jg     L335
  cmpq   $0x90080,-0x18(%rbp)
  je     L62
  cmpq   $0x90080,-0x18(%rbp)
  jg     L335
  cmpq   $0x80100,-0x18(%rbp)
  je     L11
  cmpq   $0x80100,-0x18(%rbp)
  jg     L335
  cmpq   $0x70200,-0x18(%rbp)
  je     L183
  cmpq   $0x70200,-0x18(%rbp)
  jg     L335
  cmpq   $0x60400,-0x18(%rbp)
  je     L38
  cmpq   $0x60400,-0x18(%rbp)
  jg     L335
  cmpq   $0x50800,-0x18(%rbp)
  je     L184
  cmpq   $0x50800,-0x18(%rbp)
  jg     L335
  cmpq   $0x41000,-0x18(%rbp)
  je     L220
  cmpq   $0x41000,-0x18(%rbp)
  jg     L335
  cmpq   $0x32000,-0x18(%rbp)
  je     L286
  cmpq   $0x32000,-0x18(%rbp)
  jg     L335
  cmpq   $0x18000,-0x18(%rbp)
  je     L40
  cmpq   $0x24000,-0x18(%rbp)
  je     L317
  jmp    L335
L40:
  mov    $0x2,%eax
  jmp    L26
L317:
  mov    $0x3,%eax
  jmp    L26
L286:
  mov    $0x4,%eax
  jmp    L26
L220:
  mov    $0x5,%eax
  jmp    L26
L184:
  mov    $0x6,%eax
  jmp    L26
L38:
  mov    $0x7,%eax
  jmp    L26
L183:
  mov    $0x8,%eax
  jmp    L26
L11:
  mov    $0x9,%eax
  jmp    L26
L62:
  mov    $0xa,%eax
  jmp    L26
L42:
  mov    $0xb,%eax
  jmp    L26
L243:
  mov    $0xc,%eax
  jmp    L26
L335:
  mov    -0x18(%rbp),%rax
  mov    %ax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x10,%rax
  and    $0xf,%eax
  mov    %ax,-0x2(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  jne    L323
  cmpw   $0xa,-0x2(%rbp)
  jle    L137
L323:
  mov    $0xe,%eax
  jmp    L26
L137:
  mov    $0xffffffff,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
short uncomp_mode_type(long prefix) {
  short code;
  short len;
  switch (prefix) {
  case 0x18000L:
    return (2);
  case 0x24000L:
    return (3);
  case 0x32000L:
    return (4);
  case 0x41000L:
    return (5);
  case 0x50800L:
    return (6);
  case 0x60400L:
    return (7);
  case 0x70200L:
    return (8);
  case 0x80100L:
    return (9);
  case 0x90080L:
    return (10);
  case 0xA0040L:
    return (11);
  case 0xB0020L:
    return (12);
  }
  code = prefix & 0xffffL;
  len = (prefix >> 16) & 0xf;
  return ((code || len > 10) ? 14 : -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uncomp_mode_type>:
  endbr64
  cmp    $0x60400,%rdi
  je     L7
  jle    L63
  cmp    $0x90080,%rdi
  je     L130
  jle    L124
  mov    $0xb,%eax
  cmp    $0xa0040,%rdi
  je     L34
  cmp    $0xb0020,%rdi
  jne    L107
  mov    $0xc,%eax
  ret
L63:
  cmp    $0x32000,%rdi
  je     L114
  jle    L72
  mov    $0x5,%eax
  cmp    $0x41000,%rdi
  je     L34
  cmp    $0x50800,%rdi
  jne    L107
  mov    $0x6,%eax
  ret
L72:
  mov    $0x2,%eax
  cmp    $0x18000,%rdi
  je     L34
  cmp    $0x24000,%rdi
  jne    L107
  mov    $0x3,%eax
  ret
L124:
  mov    $0x8,%eax
  cmp    $0x70200,%rdi
  je     L34
  cmp    $0x80100,%rdi
  jne    L107
  mov    $0x9,%eax
  ret
L107:
  mov    %rdi,%rax
  sar    $0x10,%rax
  and    $0xf,%eax
  cmp    $0xa,%ax
  jg     L158
  test   %di,%di
  je     L117
L158:
  mov    $0xe,%eax
L34:
  ret
L117:
  mov    $0xffffffff,%eax
  ret
L7:
  mov    $0x7,%eax
  ret
L114:
  mov    $0x4,%eax
  ret
L130:
  mov    $0xa,%eax
  ret
```

assistant: ```c
short uncomp_mode_type(long prefix) {
  short code;
  short len;
  switch (prefix) {
  case 0x18000L:
    return (2);
  case 0x24000L:
    return (3);
  case 0x32000L:
    return (4);
  case 0x41000L:
    return (5);
  case 0x50800L:
    return (6);
  case 0x60400L:
    return (7);
  case 0x70200L:
    return (8);
  case 0x80100L:
    return (9);
  case 0x90080L:
    return (10);
  case 0xA0040L:
    return (11);
  case 0xB0020L:
    return (12);
  }
  code = prefix & 0xffffL;
  len = (prefix >> 16) & 0xf;
  return ((code || len > 10) ? 14 : -1);
}
```
user: What is the c source code of the assembly code below:

```asm
<uncomp_mode_type>:
  endbr64
  cmp    $0x60400,%rdi
  je     L7
  jle    L52
  cmp    $0x90080,%rdi
  je     L134
  jle    L95
  mov    $0xb,%eax
  cmp    $0xa0040,%rdi
  je     L58
  cmp    $0xb0020,%rdi
  jne    L46
  mov    $0xc,%eax
  ret
  nop
L52:
  cmp    $0x32000,%rdi
  je     L110
  jle    L118
  mov    $0x5,%eax
  cmp    $0x41000,%rdi
  je     L58
  cmp    $0x50800,%rdi
  jne    L46
  mov    $0x6,%eax
  ret
L46:
  mov    %rdi,%rax
  sar    $0x10,%rax
  and    $0xf,%eax
  cmp    $0xa,%ax
  jle    L54
L39:
  mov    $0xe,%eax
L58:
  ret
  nopw   0x0(%rax,%rax,1)
L95:
  mov    $0x8,%eax
  cmp    $0x70200,%rdi
  je     L58
  cmp    $0x80100,%rdi
  jne    L46
  mov    $0x9,%eax
  ret
  nopl   (%rax)
L118:
  mov    $0x2,%eax
  cmp    $0x18000,%rdi
  je     L58
  cmp    $0x24000,%rdi
  jne    L46
  mov    $0x3,%eax
  ret
  nopl   (%rax)
L134:
  mov    $0xa,%eax
  ret
  xchg   %ax,%ax
L110:
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0x7,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  test   %di,%di
  jne    L39
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
short uncomp_mode_type(long prefix) {
  short code;
  short len;
  switch (prefix) {
  case 0x18000L:
    return (2);
  case 0x24000L:
    return (3);
  case 0x32000L:
    return (4);
  case 0x41000L:
    return (5);
  case 0x50800L:
    return (6);
  case 0x60400L:
    return (7);
  case 0x70200L:
    return (8);
  case 0x80100L:
    return (9);
  case 0x90080L:
    return (10);
  case 0xA0040L:
    return (11);
  case 0xB0020L:
    return (12);
  }
  code = prefix & 0xffffL;
  len = (prefix >> 16) & 0xf;
  return ((code || len > 10) ? 14 : -1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uncomp_mode_type>:
  endbr64
  cmp    $0x60400,%rdi
  je     L117
  jle    L158
  cmp    $0x90080,%rdi
  je     L153
  jle    L141
  mov    $0xb,%eax
  cmp    $0xa0040,%rdi
  je     L115
  cmp    $0xb0020,%rdi
  jne    L126
  mov    $0xc,%eax
  ret
  nop
L158:
  cmp    $0x32000,%rdi
  je     L62
  jle    L70
  mov    $0x5,%eax
  cmp    $0x41000,%rdi
  je     L115
  cmp    $0x50800,%rdi
  jne    L126
  mov    $0x6,%eax
  ret
L126:
  mov    %rdi,%rax
  sar    $0x10,%rax
  and    $0xf,%eax
  cmp    $0xa,%ax
  jle    L146
L30:
  mov    $0xe,%eax
L115:
  ret
  nopw   0x0(%rax,%rax,1)
L141:
  mov    $0x8,%eax
  cmp    $0x70200,%rdi
  je     L115
  cmp    $0x80100,%rdi
  jne    L126
  mov    $0x9,%eax
  ret
  nopl   (%rax)
L70:
  mov    $0x2,%eax
  cmp    $0x18000,%rdi
  je     L115
  cmp    $0x24000,%rdi
  jne    L126
  mov    $0x3,%eax
  ret
  nopl   (%rax)
L153:
  mov    $0xa,%eax
  ret
  xchg   %ax,%ax
L62:
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    $0x7,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L146:
  test   %di,%di
  jne    L30
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
short uncomp_mode_type(long prefix) {
  short code;
  short len;
  switch (prefix) {
  case 0x18000L:
    return (2);
  case 0x24000L:
    return (3);
  case 0x32000L:
    return (4);
  case 0x41000L:
    return (5);
  case 0x50800L:
    return (6);
  case 0x60400L:
    return (7);
  case 0x70200L:
    return (8);
  case 0x80100L:
    return (9);
  case 0x90080L:
    return (10);
  case 0xA0040L:
    return (11);
  case 0xB0020L:
    return (12);
  }
  code = prefix & 0xffffL;
  len = (prefix >> 16) & 0xf;
  return ((code || len > 10) ? 14 : -1);
}
```
user: What is the c source code of the assembly code below:

```asm
<set_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D25(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpf_set_default_prec@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type: byte[8]
name: read_data
arguments: data_label: D25
type: byte[8]
name: read_data
arguments: data_label: D8
type: byte[8]

tool: {"D16": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x02,0x40]}

tool: {"D25": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0xc0,0x72,0x40]}

assistant: ```c
void set_bits(int prec, int nterms) {
  double v = ((double)prec) * log(10.0) / log(2.0);
  int bits = (int)(v + 300 + 3 * nterms);
  mpf_set_default_prec(bits);
}
```
user: What is the c source code of the assembly code below:

```asm
<set_bits>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D3(%rip),%xmm0
  divsd  D7(%rip),%xmm0
  addsd  D16(%rip),%xmm0
  lea    (%rsi,%rsi,2),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <mpf_set_default_prec@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: byte[8]
name: retrieve_data
arguments: data_label: D7
type: byte[8]
name: retrieve_data
arguments: data_label: D16
type: byte[8]

tool: {"D3": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x02,0x40]}

tool: {"D7": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0xc0,0x72,0x40]}

assistant: ```c
void set_bits(int prec, int nterms) {
  double v = ((double)prec) * log(10.0) / log(2.0);
  int bits = (int)(v + 300 + 3 * nterms);
  mpf_set_default_prec(bits);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_bits>:
  endbr64
  pxor   %xmm0,%xmm0
  lea    (%rsi,%rsi,2),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm0
  mulsd  D13(%rip),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  D23(%rip),%xmm0
  addsd  D21(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1050 <mpf_set_default_prec@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: byte[8]
name: disassemble_data
arguments: label: D23
type_guessed: byte[8]
name: disassemble_data
arguments: label: D21
type_guessed: byte[8]

tool: {"D13": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x02,0x40]}

tool: {"D23": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0xc0,0x72,0x40]}

assistant: ```c
void set_bits(int prec, int nterms) {
  double v = ((double)prec) * log(10.0) / log(2.0);
  int bits = (int)(v + 300 + 3 * nterms);
  mpf_set_default_prec(bits);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_bits>:
  endbr64
  pxor   %xmm0,%xmm0
  lea    (%rsi,%rsi,2),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm0
  mulsd  D7(%rip),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  D14(%rip),%xmm0
  addsd  D10(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  jmp    1050 <mpf_set_default_prec@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: byte[8]
name: retrieve_data
arguments: tag: D14
data_type: byte[8]
name: retrieve_data
arguments: tag: D10
data_type: byte[8]

tool: {"D7": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x02,0x40]}

tool: {"D14": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0xc0,0x72,0x40]}

assistant: ```c
void set_bits(int prec, int nterms) {
  double v = ((double)prec) * log(10.0) / log(2.0);
  int bits = (int)(v + 300 + 3 * nterms);
  mpf_set_default_prec(bits);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__sql_text_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x27,%esi
  mov    %rax,%rdi
  call   <__expect@plt>
  test   %eax,%eax
  jne    L30
  mov    $0x0,%eax
  jmp    L37
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
L61:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L61
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  jmp    L37
L0:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L37:
  leave
  ret
```

assistant: ```c
bool __sql_text_parse(const char **sql, char **text) {
  if (!__expect(sql, '\''))
    return (0);
  const char *p = *sql;
  while (*p && *p != '\'')
    ++p;
  if (!*p)
    return (0);
  *text = strndup(*sql, p - *sql);
  *sql = p + 1;
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__sql_text_parse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x27,%esi
  call   <__expect@plt>
  test   %eax,%eax
  je     L18
  mov    0x0(%rbp),%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L64
  cmp    $0x27,%dl
  je     L64
  mov    %rdi,%rbx
L7:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L29
  cmp    $0x27,%dl
  jne    L7
L29:
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L33
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  mov    %rdi,%rbx
  jmp    L29
L33:
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <strndup@plt>
  mov    %rax,(%r12)
  add    $0x1,%rbx
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
bool __sql_text_parse(const char **sql, char **text) {
  if (!__expect(sql, '\''))
    return (0);
  const char *p = *sql;
  while (*p && *p != '\'')
    ++p;
  if (!*p)
    return (0);
  *text = strndup(*sql, p - *sql);
  *sql = p + 1;
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__sql_text_parse>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x27,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <__expect@plt>
  test   %eax,%eax
  je     L52
  mov    0x0(%rbp),%rdi
  movzbl (%rdi),%edx
  mov    %rdi,%rbx
  test   %dl,%dl
  jne    L15
  jmp    L34
  nopl   0x0(%rax)
L25:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  je     L34
L15:
  cmp    $0x27,%dl
  jne    L25
L34:
  xor    %eax,%eax
  test   %dl,%dl
  jne    L8
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %ebx,%esi
  add    $0x1,%rbx
  sub    %edi,%esi
  call   <strndup@plt>
  mov    %rax,(%r12)
  mov    $0x1,%eax
  mov    %rbx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool __sql_text_parse(const char **sql, char **text) {
  if (!__expect(sql, '\''))
    return (0);
  const char *p = *sql;
  while (*p && *p != '\'')
    ++p;
  if (!*p)
    return (0);
  *text = strndup(*sql, p - *sql);
  *sql = p + 1;
  return (1);
}
```