ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D61(%rip),%xmm0
  lea    D41(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D45(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x3(%rax),%edx
  cmp    $0xe,%edx
  ja     L15
  movsd  D5(%rip),%xmm1
  mov    $0x2,%esi
  mov    $0x5,%ecx
  xor    %edx,%edx
  xchg   %ax,%ax
L58:
  movslq %esi,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %edi,%eax
  je     L40
L1:
  movslq %edx,%r8
  cmp    0x10(%rsp,%r8,4),%eax
  je     L40
  movslq %ecx,%r8
  cmp    0x10(%rsp,%r8,4),%eax
  je     L40
  cmp    %edi,%eax
  jge    L21
  lea    -0x1(%rsi),%ecx
  pxor   %xmm0,%xmm0
  lea    (%rcx,%rdx,1),%esi
  cvtsi2sd %esi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  cmp    %edx,%ecx
  jg     L58
  nopl   (%rax)
L15:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L69:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x1(%rsi),%edx
  pxor   %xmm0,%xmm0
  lea    (%rdx,%rcx,1),%esi
  cvtsi2sd %esi,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  cmp    %ecx,%edx
  jge    L15
  movslq %esi,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %edi,%eax
  jne    L1
L40:
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D61
datatype: byte[16]
name: read_data
arguments: label: D41
datatype: string
name: read_data
arguments: label: D45
datatype: byte[8]
name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D5
datatype: byte[8]
name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D63
datatype: string

tool: {"D61": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: D41: Enter a number: 

tool: {"D45": [0x0e,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

tool: D9: %d

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D11: It is not found!


tool: D63: It is found!


assistant: ```c
int main() {
  int a[] = {3, 4, 9, 12, 14, 17}, i, n, f = 0, j, k;
  printf("Enter a number: ");
  scanf("%d", &n);
  i = 0;
  j = sizeof(a) / sizeof(int) - 1;
  k = (int)(i + j) / 2.0;
  if (n < a[i] || n > a[j]) {
    printf("It is not found!\n");
    return 0;
  }
  while (i < j) {
    if (a[k] == n || a[i] == n || a[j] == n) {
      f = 1;
      break;
    } else if (a[k] > n) {
      j = k - 1;
      k = (i + j) / 2.0;
    } else {
      i = k + 1;
      k = (i + j) / 2.0;
    }
  }
  if (f == 1)
    printf("It is found!\n");
  else
    printf("It is not found!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiplo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L6:
  movl   $0x0,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int multiplo(int a, int b) {
  int res;
  if ((b % a) == 0)
    res = 1;
  else
    res = 0;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiplo>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int multiplo(int a, int b) {
  int res;
  if ((b % a) == 0)
    res = 1;
  else
    res = 0;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiplo>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int multiplo(int a, int b) {
  int res;
  if ((b % a) == 0)
    res = 1;
  else
    res = 0;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiplo>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int multiplo(int a, int b) {
  int res;
  if ((b % a) == 0)
    res = 1;
  else
    res = 0;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_delay_cycl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  nop
  nop
L9:
  movzwl -0x2(%rbp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  test   %ax,%ax
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _delay_cycl(unsigned short __ticks) {
  volatile unsigned short t;
  t = __ticks;
  __asm__("nop\n nop\n");
  do {
    t--;
  } while (t);
  __asm__("nop\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_delay_cycl>:
  endbr64
  mov    %di,-0x2(%rsp)
  nop
  nop
L6:
  movzwl -0x2(%rsp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x2(%rsp)
  movzwl -0x2(%rsp),%eax
  test   %ax,%ax
  jne    L6
  nop
  ret
```

assistant: ```c
void _delay_cycl(unsigned short __ticks) {
  volatile unsigned short t;
  t = __ticks;
  __asm__("nop\n nop\n");
  do {
    t--;
  } while (t);
  __asm__("nop\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_delay_cycl>:
  endbr64
  mov    %di,-0x2(%rsp)
  nop
  nop
  nopl   0x0(%rax,%rax,1)
L7:
  movzwl -0x2(%rsp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x2(%rsp)
  movzwl -0x2(%rsp),%eax
  test   %ax,%ax
  jne    L7
  nop
  ret
```

assistant: ```c
void _delay_cycl(unsigned short __ticks) {
  volatile unsigned short t;
  t = __ticks;
  __asm__("nop\n nop\n");
  do {
    t--;
  } while (t);
  __asm__("nop\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_delay_cycl>:
  endbr64
  mov    %di,-0x2(%rsp)
  nop
  nop
  nopl   0x0(%rax,%rax,1)
L1:
  movzwl -0x2(%rsp),%eax
  sub    $0x1,%eax
  mov    %ax,-0x2(%rsp)
  movzwl -0x2(%rsp),%eax
  test   %ax,%ax
  jne    L1
  nop
  ret
```

assistant: ```c
void _delay_cycl(unsigned short __ticks) {
  volatile unsigned short t;
  t = __ticks;
  __asm__("nop\n nop\n");
  do {
    t--;
  } while (t);
  __asm__("nop\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<number_of_digits_ulong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L16:
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
L18:
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int number_of_digits_ulong(unsigned long num) {
  int digits = 0;
  while (num != 0) {
    digits += 1;
    num /= 10;
  }
  return digits;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<number_of_digits_ulong>:
  endbr64
  mov    %rdi,%rdx
  test   %rdi,%rdi
  je     L21
  mov    $0x0,%ecx
  movabs $0xcccccccccccccccd,%rdi
L17:
  add    $0x1,%ecx
  mov    %rdx,%rsi
  mov    %rdx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x9,%rsi
  ja     L17
L11:
  mov    %ecx,%eax
  ret
L21:
  mov    $0x0,%ecx
  jmp    L11
```

assistant: ```c
int number_of_digits_ulong(unsigned long num) {
  int digits = 0;
  while (num != 0) {
    digits += 1;
    num /= 10;
  }
  return digits;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<number_of_digits_ulong>:
  endbr64
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L16
  movabs $0xcccccccccccccccd,%rsi
  nopl   0x0(%rax)
L6:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L6
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int number_of_digits_ulong(unsigned long num) {
  int digits = 0;
  while (num != 0) {
    digits += 1;
    num /= 10;
  }
  return digits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<number_of_digits_ulong>:
  endbr64
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L2
  movabs $0xcccccccccccccccd,%rsi
  nopl   0x0(%rax)
L6:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L6
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int number_of_digits_ulong(unsigned long num) {
  int digits = 0;
  while (num != 0) {
    digits += 1;
    num /= 10;
  }
  return digits;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L41
  addq   $0x1,-0x18(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L112
  addq   $0x1,-0x18(%rbp)
L112:
  movl   $0x0,-0x4(%rbp)
  jmp    L97
L101:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L116
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L116
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L116:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L56
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L56
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L31
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L31
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L17:
  addq   $0x1,-0x18(%rbp)
L97:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L101
L31:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atox(const char *nptr) {
  int value;
  if (*nptr == '0')
    ++nptr;
  if (*nptr == 'x')
    ++nptr;
  value = 0;
  while (*nptr) {
    if (*nptr >= '0' && *nptr <= '9') {
      value = (value << 4) + (*nptr - '0');
    } else if (*nptr >= 'A' && *nptr <= 'F') {
      value = (value << 4) + (*nptr - 'A');
    } else if (*nptr >= 'a' && *nptr <= 'f') {
      value = (value << 4) + (*nptr - 'a');
    } else {
      break;
    }
    ++nptr;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atox>:
  endbr64
  cmpb   $0x30,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  cmpb   $0x78,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  mov    $0x0,%eax
  jmp    L72
L12:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L17
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x41(%rax,%rdx,1),%eax
L10:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L66
L72:
  mov    %edx,%esi
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L12
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x30(%rax,%rdx,1),%eax
  jmp    L10
L17:
  sub    $0x61,%esi
  cmp    $0x5,%sil
  ja     L63
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x61(%rax,%rdx,1),%eax
  jmp    L10
L66:
  ret
L5:
  mov    $0x0,%eax
L63:
  ret
```

assistant: ```c
int atox(const char *nptr) {
  int value;
  if (*nptr == '0')
    ++nptr;
  if (*nptr == 'x')
    ++nptr;
  value = 0;
  while (*nptr) {
    if (*nptr >= '0' && *nptr <= '9') {
      value = (value << 4) + (*nptr - '0');
    } else if (*nptr >= 'A' && *nptr <= 'F') {
      value = (value << 4) + (*nptr - 'A');
    } else if (*nptr >= 'a' && *nptr <= 'f') {
      value = (value << 4) + (*nptr - 'a');
    } else {
      break;
    }
    ++nptr;
  }
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atox>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x30,%dl
  jne    L47
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
L47:
  cmp    $0x78,%dl
  jne    L75
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
L75:
  xor    %eax,%eax
  test   %dl,%dl
  jne    L84
  jmp    L71
  nopl   0x0(%rax)
L3:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  jbe    L83
  sub    $0x61,%edx
  cmp    $0x5,%dl
  ja     L71
  movsbl %dl,%edx
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L52
L84:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L3
L83:
  movzbl 0x1(%rdi),%edx
  shl    $0x4,%eax
  movsbl %cl,%ecx
  add    $0x1,%rdi
  add    %ecx,%eax
  test   %dl,%dl
  jne    L84
L52:
  ret
L71:
  ret
```

assistant: ```c
int atox(const char *nptr) {
  int value;
  if (*nptr == '0')
    ++nptr;
  if (*nptr == 'x')
    ++nptr;
  value = 0;
  while (*nptr) {
    if (*nptr >= '0' && *nptr <= '9') {
      value = (value << 4) + (*nptr - '0');
    } else if (*nptr >= 'A' && *nptr <= 'F') {
      value = (value << 4) + (*nptr - 'A');
    } else if (*nptr >= 'a' && *nptr <= 'f') {
      value = (value << 4) + (*nptr - 'a');
    } else {
      break;
    }
    ++nptr;
  }
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<atox>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x30,%dl
  jne    L41
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
L41:
  cmp    $0x78,%dl
  jne    L20
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
L20:
  xor    %eax,%eax
  test   %dl,%dl
  jne    L56
  jmp    L85
  nopl   0x0(%rax)
L0:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  jbe    L77
  sub    $0x61,%edx
  cmp    $0x5,%dl
  ja     L85
  movsbl %dl,%edx
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L67
L56:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L0
L77:
  movzbl 0x1(%rdi),%edx
  shl    $0x4,%eax
  movsbl %cl,%ecx
  add    $0x1,%rdi
  add    %ecx,%eax
  test   %dl,%dl
  jne    L56
L67:
  ret
L85:
  ret
```

assistant: ```c
int atox(const char *nptr) {
  int value;
  if (*nptr == '0')
    ++nptr;
  if (*nptr == 'x')
    ++nptr;
  value = 0;
  while (*nptr) {
    if (*nptr >= '0' && *nptr <= '9') {
      value = (value << 4) + (*nptr - '0');
    } else if (*nptr >= 'A' && *nptr <= 'F') {
      value = (value << 4) + (*nptr - 'A');
    } else if (*nptr >= 'a' && *nptr <= 'f') {
      value = (value << 4) + (*nptr - 'a');
    } else {
      break;
    }
    ++nptr;
  }
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__mltadd__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    $0x0,%ebx
  jmp    L11
L16:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x1,%ebx
L11:
  cmp    -0x24(%rbp),%ebx
  jl     L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void __mltadd__(double *dp1, const double *dp2, double s, int len) {
  register int i;
  for (i = 0; i < len; i++)
    dp1[i] += s * dp2[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__mltadd__>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  (%rdi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L9:
  ret
```

assistant: ```c
void __mltadd__(double *dp1, const double *dp2, double s, int len) {
  register int i;
  for (i = 0; i < len; i++)
    dp1[i] += s * dp2[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__mltadd__>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L13:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rdi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L13
L7:
  ret
```

assistant: ```c
void __mltadd__(double *dp1, const double *dp2, double s, int len) {
  register int i;
  for (i = 0; i < len; i++)
    dp1[i] += s * dp2[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__mltadd__>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L43
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L33
  cmp    $0x1,%edx
  je     L33
  mov    %edx,%edi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  nop
L49:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L49
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L43
  mulsd  (%rsi,%rax,8),%xmm0
  lea    (%rcx,%rax,8),%rdx
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L56:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L56
L43:
  ret
```

assistant: ```c
void __mltadd__(double *dp1, const double *dp2, double s, int len) {
  register int i;
  for (i = 0; i < len; i++)
    dp1[i] += s * dp2[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<h8max_insw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x14(%rbp)
  jmp    L2
L19:
  movzbl -0x14(%rbp),%eax
  add    %eax,%eax
  add    $0x800600,%eax
  cltq
  movzwl (%rax),%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x2(%rbp),%eax
  shr    $0x8,%ax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  subq   $0x1,-0x28(%rbp)
  addq   $0x2,-0x20(%rbp)
L2:
  cmpq   $0x0,-0x28(%rbp)
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void h8max_insw(unsigned char a, unsigned short *p, unsigned long l) {
  unsigned short d;
  for (; l != 0; --l, p++) {
    d = *(unsigned short *)(0x800600 + (a << 1));
    *p = (d << 8) | ((d >> 8) & 0xff);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<h8max_insw>:
  endbr64
  test   %rdx,%rdx
  je     L9
  movzbl %dil,%edi
  lea    0x800600(%rdi,%rdi,1),%rdi
  mov    $0x0,%eax
L10:
  movzwl (%rdi),%ecx
  rol    $0x8,%cx
  mov    %cx,(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L9:
  ret
```

assistant: ```c
void h8max_insw(unsigned char a, unsigned short *p, unsigned long l) {
  unsigned short d;
  for (; l != 0; --l, p++) {
    d = *(unsigned short *)(0x800600 + (a << 1));
    *p = (d << 8) | ((d >> 8) & 0xff);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h8max_insw>:
  endbr64
  test   %rdx,%rdx
  je     L4
  movzbl %dil,%edi
  xor    %eax,%eax
  lea    0x800600(%rdi,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  movzwl (%rdi),%ecx
  rol    $0x8,%cx
  mov    %cx,(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L4:
  ret
```

assistant: ```c
void h8max_insw(unsigned char a, unsigned short *p, unsigned long l) {
  unsigned short d;
  for (; l != 0; --l, p++) {
    d = *(unsigned short *)(0x800600 + (a << 1));
    *p = (d << 8) | ((d >> 8) & 0xff);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h8max_insw>:
  endbr64
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L46
  movzbl %dil,%eax
  lea    (%rsi,%rdx,2),%rsi
  lea    -0x1(%rdx),%r8
  add    %eax,%eax
  lea    0x800600(%rax),%edi
  cltq
  lea    0x800600(%rax),%r9
  movslq %edi,%rdi
  cmp    %r9,%rsi
  setbe  %sil
  add    $0x800602,%rax
  cmp    %rax,%rcx
  setae  %al
  or     %al,%sil
  je     L33
  cmp    $0x2,%r8
  jbe    L33
  cmp    $0x6,%r8
  jbe    L79
  movzwl (%rdi),%eax
  mov    %rdx,%r8
  shr    $0x3,%r8
  rol    $0x8,%ax
  movd   %eax,%xmm0
  xor    %eax,%eax
  punpcklwd %xmm0,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  nopl   (%rax)
L16:
  mov    %rax,%rsi
  add    $0x1,%rax
  shl    $0x4,%rsi
  movups %xmm0,(%rcx,%rsi,1)
  cmp    %rax,%r8
  jne    L16
  mov    %rdx,%r9
  mov    %rdx,%rsi
  and    $0xfffffffffffffff8,%r9
  lea    (%rcx,%r9,2),%r8
  sub    %r9,%rsi
  cmp    %r9,%rdx
  je     L46
  lea    -0x1(%rsi),%rax
  mov    %rsi,%rdx
  cmp    $0x2,%rax
  jbe    L106
L113:
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  movd   %eax,%xmm1
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rax
  pshuflw $0x0,%xmm1,%xmm0
  movq   %xmm0,(%rcx,%r9,2)
  lea    (%r8,%rax,2),%r8
  sub    %rax,%rsi
  cmp    %rdx,%rax
  je     L46
  lea    -0x1(%rsi),%rax
L106:
  movzwl (%rdi),%edx
  rol    $0x8,%dx
  mov    %dx,(%r8)
  test   %rax,%rax
  je     L46
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  mov    %ax,0x2(%r8)
  cmp    $0x2,%rsi
  je     L46
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  mov    %ax,0x4(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  movzwl (%rdi),%esi
  rol    $0x8,%si
  mov    %si,(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L11
L46:
  ret
L79:
  mov    %rdx,%rsi
  mov    %rcx,%r8
  xor    %r9d,%r9d
  jmp    L113
```

assistant: ```c
void h8max_insw(unsigned char a, unsigned short *p, unsigned long l) {
  unsigned short d;
  for (; l != 0; --l, p++) {
    d = *(unsigned short *)(0x800600 + (a << 1));
    *p = (d << 8) | ((d >> 8) & 0xff);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ssc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L29
L0:
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L29
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <dfs@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  call   <empty@plt>
  test   %rax,%rax
  jne    L0
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: 


assistant: ```c
void ssc(int visit[]) {
  int vertex;
  while (empty() != 0) {
    vertex = pop();
    if (visit[vertex] != 1) {
      dfs(vertex, visit);
      printf("\n");
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ssc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D2(%rip),%rbp
L25:
  mov    $0x0,%eax
  call   <empty@plt>
  test   %rax,%rax
  je     L0
  mov    $0x0,%eax
  call   <pop@plt>
  movslq %eax,%rdx
  cmpl   $0x1,(%rbx,%rdx,4)
  je     L25
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <dfs@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L25
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: 


assistant: ```c
void ssc(int visit[]) {
  int vertex;
  while (empty() != 0) {
    vertex = pop();
    if (visit[vertex] != 1) {
      dfs(vertex, visit);
      printf("\n");
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ssc>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  call   <pop@plt>
  movslq %eax,%rdx
  cmpl   $0x1,(%rbx,%rdx,4)
  jne    L36
L10:
  xor    %eax,%eax
  call   <empty@plt>
  test   %rax,%rax
  jne    L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <dfs@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: 


assistant: ```c
void ssc(int visit[]) {
  int vertex;
  while (empty() != 0) {
    vertex = pop();
    if (visit[vertex] != 1) {
      dfs(vertex, visit);
      printf("\n");
    }
  }
}
```