ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_usectime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_usectime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((uint64_t)(tv.tv_sec)) * 1000000 + tv.tv_usec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_usectime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_usectime() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((uint64_t)(tv.tv_sec)) * 1000000 + tv.tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usb_lld_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <st103_set_btable@plt>
  mov    $0x0,%edi
  call   <st103_set_daddr@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usb_lld_reset(void) {
  st103_set_btable();
  st103_set_daddr(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usb_lld_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <st103_set_btable@plt>
  mov    $0x0,%edi
  call   <st103_set_daddr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usb_lld_reset(void) {
  st103_set_btable();
  st103_set_daddr(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usb_lld_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <st103_set_btable@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <st103_set_daddr@plt>
```

assistant: ```c
void usb_lld_reset(void) {
  st103_set_btable();
  st103_set_daddr(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<usb_lld_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <st103_set_btable@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <st103_set_daddr@plt>
```

assistant: ```c
void usb_lld_reset(void) {
  st103_set_btable();
  st103_set_daddr(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NmiSR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  jmp    L6
```

assistant: ```c
void NmiSR(void) {
  for (;;) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NmiSR>:
  endbr64
L7:
  jmp    L7
```

assistant: ```c
void NmiSR(void) {
  for (;;) {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NmiSR>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void NmiSR(void) {
  for (;;) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<NmiSR>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
void NmiSR(void) {
  for (;;) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L24
L26:
  addq   $0x1,-0x8(%rbp)
L24:
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jbe    L26
L22:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *skip(const char *in) {
  while (in && *in && ((unsigned char)*in <= 32)) {
    in++;
  }
  return in;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skip>:
  endbr64
  test   %rdi,%rdi
  je     L11
L2:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  ja     L14
  add    $0x1,%rdi
  jmp    L2
L11:
  mov    %rdi,%rax
  ret
L14:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *skip(const char *in) {
  while (in && *in && ((unsigned char)*in <= 32)) {
    in++;
  }
  return in;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skip>:
  endbr64
  test   %rdi,%rdi
  jne    L1
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
L1:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L13
  mov    %rdi,%rax
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *skip(const char *in) {
  while (in && *in && ((unsigned char)*in <= 32)) {
    in++;
  }
  return in;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip>:
  endbr64
  test   %rdi,%rdi
  je     L14
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L26
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L24
L26:
  mov    %rdi,%rax
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *skip(const char *in) {
  while (in && *in && ((unsigned char)*in <= 32)) {
    in++;
  }
  return in;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vector_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L11:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L11
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vector_up(float equation[], int ivar, int idim, float low_vector[], float vector[]) {
  int i;
  vector[ivar] = 0.0;
  for (i = 0; i < ivar; i++) {
    vector[i] = low_vector[i];
    vector[ivar] -= equation[i] * low_vector[i];
  }
  for (i = ivar + 1; i <= idim; i++) {
    vector[i] = low_vector[i - 1];
    vector[ivar] -= equation[i] * low_vector[i - 1];
  }
  vector[ivar] /= equation[ivar];
}
```
user: Translate the below assembly code into C programming language:

```asm
<vector_up>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %rcx,%r9
  movslq %eax,%r11
  lea    (%r8,%r11,4),%rcx
  movl   $0x0,(%rcx)
  test   %eax,%eax
  jle    L21
  mov    %eax,%r10d
  mov    $0x0,%edx
L17:
  movss  (%r9,%rdx,4),%xmm0
  movss  %xmm0,(%r8,%rdx,4)
  mulss  (%rdi,%rdx,4),%xmm0
  movss  (%rcx),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  add    $0x1,%rdx
  cmp    %r10,%rdx
  jne    L17
L21:
  add    $0x1,%eax
  cmp    %esi,%eax
  jg     L5
  cltq
L23:
  movss  -0x4(%r9,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  mulss  (%rdi,%rax,4),%xmm0
  movss  (%rcx),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L23
L5:
  movss  (%rcx),%xmm0
  divss  (%rdi,%r11,4),%xmm0
  movss  %xmm0,(%rcx)
  ret
```

assistant: ```c
void vector_up(float equation[], int ivar, int idim, float low_vector[], float vector[]) {
  int i;
  vector[ivar] = 0.0;
  for (i = 0; i < ivar; i++) {
    vector[i] = low_vector[i];
    vector[ivar] -= equation[i] * low_vector[i];
  }
  for (i = ivar + 1; i <= idim; i++) {
    vector[i] = low_vector[i - 1];
    vector[ivar] -= equation[i] * low_vector[i - 1];
  }
  vector[ivar] /= equation[ivar];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vector_up>:
  endbr64
  movslq %esi,%r9
  mov    %edx,%esi
  xor    %eax,%eax
  lea    (%r8,%r9,4),%rdx
  mov    %r9,%r10
  movl   $0x0,(%rdx)
  test   %r9d,%r9d
  jle    L32
  nopl   (%rax)
L21:
  movss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  mulss  (%rdi,%rax,4),%xmm0
  movss  (%rdx),%xmm1
  add    $0x1,%rax
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %rax,%r9
  jne    L21
L32:
  add    $0x1,%r10d
  movslq %r10d,%rax
  cmp    %esi,%r10d
  jg     L28
  nopl   0x0(%rax)
L18:
  movss  -0x4(%rcx,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  mulss  (%rdi,%rax,4),%xmm0
  movss  (%rdx),%xmm1
  add    $0x1,%rax
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %eax,%esi
  jge    L18
  divss  (%rdi,%r9,4),%xmm1
  movss  %xmm1,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movss  (%rdx),%xmm1
  divss  (%rdi,%r9,4),%xmm1
  movss  %xmm1,(%rdx)
  ret
```

assistant: ```c
void vector_up(float equation[], int ivar, int idim, float low_vector[], float vector[]) {
  int i;
  vector[ivar] = 0.0;
  for (i = 0; i < ivar; i++) {
    vector[i] = low_vector[i];
    vector[ivar] -= equation[i] * low_vector[i];
  }
  for (i = ivar + 1; i <= idim; i++) {
    vector[i] = low_vector[i - 1];
    vector[ivar] -= equation[i] * low_vector[i - 1];
  }
  vector[ivar] /= equation[ivar];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_up>:
  endbr64
  movslq %esi,%r10
  mov    %edx,%r9d
  lea    (%r8,%r10,4),%rsi
  mov    %r10,%rax
  movl   $0x0,(%rsi)
  test   %r10d,%r10d
  jle    L44
  xor    %edx,%edx
  xchg   %ax,%ax
L7:
  movss  (%rcx,%rdx,4),%xmm1
  movss  %xmm1,(%r8,%rdx,4)
  mulss  (%rdi,%rdx,4),%xmm1
  movss  (%rsi),%xmm0
  add    $0x1,%rdx
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rsi)
  cmp    %rdx,%r10
  jne    L7
L49:
  add    $0x1,%eax
  cmp    %r9d,%eax
  jg     L36
  cltq
  nop
L34:
  movss  -0x4(%rcx,%rax,4),%xmm1
  movss  %xmm1,(%r8,%rax,4)
  mulss  (%rdi,%rax,4),%xmm1
  movss  (%rsi),%xmm0
  add    $0x1,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rsi)
  cmp    %eax,%r9d
  jge    L34
L36:
  divss  (%rdi,%r10,4),%xmm0
  movss  %xmm0,(%rsi)
  ret
  nopl   0x0(%rax)
L44:
  pxor   %xmm0,%xmm0
  jmp    L49
```

assistant: ```c
void vector_up(float equation[], int ivar, int idim, float low_vector[], float vector[]) {
  int i;
  vector[ivar] = 0.0;
  for (i = 0; i < ivar; i++) {
    vector[i] = low_vector[i];
    vector[ivar] -= equation[i] * low_vector[i];
  }
  for (i = ivar + 1; i <= idim; i++) {
    vector[i] = low_vector[i - 1];
    vector[ivar] -= equation[i] * low_vector[i - 1];
  }
  vector[ivar] /= equation[ivar];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mem_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  return mem;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mem_alloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  return mem;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  return mem;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *mem_alloc(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  return mem;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x2c(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <inputData@plt>
  mov    $0x0,%eax
  call   <selectChoice@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L12
  cmpl   $0x3,-0x14(%rbp)
  jg     L25
  cmpl   $0x1,-0x14(%rbp)
  je     L22
  cmpl   $0x2,-0x14(%rbp)
  je     L26
  jmp    L25
L22:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaLeft@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L26:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaMid@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L12:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaRight@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  nop
L25:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <printData@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  int init;
  int final;
  int rectNum;
  int ch;
  double area;
  inputData(&a, &b, &c, &init, &final, &rectNum);
  ch = selectChoice();
  switch (ch) {
  case 1:
    area = findAreaLeft(a, b, c, init, final, rectNum);
    break;
  case 2:
    area = findAreaMid(a, b, c, init, final, rectNum);
    break;
  case 3:
    area = findAreaRight(a, b, c, init, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <inputData@plt>
  mov    $0x0,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L56
  cmp    $0x3,%eax
  je     L51
  cmp    $0x1,%eax
  je     L3
L55:
  movq   %rbx,%xmm0
  call   <printData@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaLeft@plt>
  movq   %xmm0,%rbx
  jmp    L55
L56:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaMid@plt>
  movq   %xmm0,%rbx
  jmp    L55
L51:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaRight@plt>
  movq   %xmm0,%rbx
  jmp    L55
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  int init;
  int final;
  int rectNum;
  int ch;
  double area;
  inputData(&a, &b, &c, &init, &final, &rectNum);
  ch = selectChoice();
  switch (ch) {
  case 1:
    area = findAreaLeft(a, b, c, init, final, rectNum);
    break;
  case 2:
    area = findAreaMid(a, b, c, init, final, rectNum);
    break;
  case 3:
    area = findAreaRight(a, b, c, init, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <inputData@plt>
  xor    %eax,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L14
  cmp    $0x3,%eax
  je     L12
  cmp    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  je     L27
L42:
  call   <printData@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L14:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaMid@plt>
  jmp    L42
L27:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaLeft@plt>
  jmp    L42
L12:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaRight@plt>
  jmp    L42
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  int init;
  int final;
  int rectNum;
  int ch;
  double area;
  inputData(&a, &b, &c, &init, &final, &rectNum);
  ch = selectChoice();
  switch (ch) {
  case 1:
    area = findAreaLeft(a, b, c, init, final, rectNum);
    break;
  case 2:
    area = findAreaMid(a, b, c, init, final, rectNum);
    break;
  case 3:
    area = findAreaRight(a, b, c, init, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <inputData@plt>
  xor    %eax,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L40
  cmp    $0x3,%eax
  je     L51
  cmp    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  je     L65
L19:
  call   <printData@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L40:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaMid@plt>
  jmp    L19
L65:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaLeft@plt>
  jmp    L19
L51:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaRight@plt>
  jmp    L19
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  int init;
  int final;
  int rectNum;
  int ch;
  double area;
  inputData(&a, &b, &c, &init, &final, &rectNum);
  ch = selectChoice();
  switch (ch) {
  case 1:
    area = findAreaLeft(a, b, c, init, final, rectNum);
    break;
  case 2:
    area = findAreaMid(a, b, c, init, final, rectNum);
    break;
  case 3:
    area = findAreaRight(a, b, c, init, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BetterMaxSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L40
L14:
  movl   $0x0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L47
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
L47:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L18
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L14
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int BetterMaxSum(int size, int data[], int *besti, int *bestj) {
  int sum = -1;
  for (int i = 1; i <= size; ++i) {
    int thissum = 0;
    for (int j = i; j <= size; ++j) {
      thissum += data[j];
      if (thissum > sum) {
        sum = thissum;
        *besti = i, *bestj = j;
      }
    }
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<BetterMaxSum>:
  endbr64
  test   %edi,%edi
  jle    L62
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r9d
  mov    %rsi,%r10
  mov    %rdx,%rbx
  lea    0x1(%rdi),%r12d
  mov    $0x1,%r11d
  mov    $0xffffffff,%r8d
  mov    $0x0,%ebp
  jmp    L22
L55:
  add    $0x1,%rax
  cmp    %eax,%r9d
  jl     L15
L6:
  add    (%r10,%rax,4),%edi
  cmp    %r8d,%edi
  jle    L55
  mov    %edx,(%rbx)
  mov    %eax,(%rcx)
  mov    %edi,%r8d
  jmp    L55
L15:
  add    $0x1,%r11
  cmp    %r12,%r11
  je     L34
L22:
  mov    %r11d,%edx
  mov    %r11,%rax
  mov    %ebp,%edi
  cmp    %r11d,%r9d
  jge    L6
  jmp    L15
L62:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
L34:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int BetterMaxSum(int size, int data[], int *besti, int *bestj) {
  int sum = -1;
  for (int i = 1; i <= size; ++i) {
    int thissum = 0;
    for (int j = i; j <= size; ++j) {
      thissum += data[j];
      if (thissum > sum) {
        sum = thissum;
        *besti = i, *bestj = j;
      }
    }
  }
  return sum;
}
```