ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<netns_etc_dir>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D26(%rip),%rsi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <asprintf@plt>
  test   %eax,%eax
  jle    L0
  mov    0x8(%rsp),%rax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x210,%rsp
  pop    %rbp
  ret
L0:
  lea    0x10(%rsp),%rbp
  push   %rax
  lea    D42(%rip),%rax
  mov    $0x2b,%r9d
  push   %rax
  lea    D39(%rip),%r8
  mov    $0x1f4,%esi
  mov    %rbp,%rdi
  lea    D33(%rip),%rcx
  lea    D9(%rip),%rdx
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D42
type_guessed: string
name: unpack_data
arguments: tag: D39
type_guessed: string
name: unpack_data
arguments: tag: D33
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D26: /etc/netns/%s

tool: D42: netns_etc_dir

tool: D39: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/netblue30/firejail/refs/heads/master/src/firejail/netns.c

tool: D33: asprintf

tool: D9: Error %s: %s:%d %s

assistant: ```c
char *netns_etc_dir(const char *nsname) {
  char *rv = 0;
  if (asprintf(&rv, "/etc/netns/%s", nsname) <= 0)
    do {
      char msgout[500];
      snprintf(msgout, 500, "Error %s: %s:%d %s", "asprintf", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/netblue30/firejail/refs/heads/master/src/firejail/netns.c", 43, __FUNCTION__);
      perror(msgout);
      exit(1);
    } while (0);
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <capitalizeInverse@plt>
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: %s

assistant: ```c
int main() {
  char input[1000];
  gets(input);
  printf("%s", capitalizeInverse(input));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <capitalizeInverse@plt>
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: %s

assistant: ```c
int main() {
  char input[1000];
  gets(input);
  printf("%s", capitalizeInverse(input));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <capitalizeInverse@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: %s

assistant: ```c
int main() {
  char input[1000];
  gets(input);
  printf("%s", capitalizeInverse(input));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <capitalizeInverse@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %s

assistant: ```c
int main() {
  char input[1000];
  gets(input);
  printf("%s", capitalizeInverse(input));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_step_G>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x18(%rsp)
  mov    %rdx,%r12
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L61
L70:
  mov    %r12,%rbp
  mov    0x10(%rsp),%r13
  add    $0x4000,%r12
  lea    0x24(%rsp),%r14
L56:
  mov    $0x0,%eax
  call   <EVP_sha512@plt>
  mov    %eax,%esi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <EVP_DigestInit_ex@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EVP_DigestUpdate@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <EVP_DigestFinal_ex@plt>
  add    $0x40,%rbp
  add    $0x40,%r13
  cmp    %r12,%rbp
  jne    L56
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  mov    %r8d,%ebp
  mov    $0x10,%edi
  call   <log2@plt>
  mov    %rax,%r13
  mov    $0x10,%edi
  call   <log2@plt>
  mov    $0x1,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  sub    $0x1,%edx
  imul   %ebp,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,0xc(%rsp)
  mov    $0x10,%edi
  call   <log2@plt>
  mov    %ebp,%ecx
  imul   %eax,%ecx
  mov    $0x4,%eax
  shl    %cl,%eax
  mov    %eax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  lea    0x40(%rax),%r14
  mov    $0x0,%r15d
  jmp    L71
L59:
  mov    0xc(%rsp),%eax
  or     %eax,%r15d
  add    $0x1,%r15d
  not    %eax
  and    %eax,%r15d
  add    $0x40,%r14
L71:
  lea    -0x40(%r14),%rbp
  mov    $0x1000,%edi
  call   <log2@plt>
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  cmp    %r15d,%edx
  jbe    L63
  lea    0x0(,%r15,4),%r13d
L50:
  mov    %r13d,%esi
  add    %r12,%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x4,%rbp
  add    0x8(%rsp),%r13d
  cmp    %r14,%rbp
  jne    L50
  jmp    L59
L63:
  mov    0x18(%rsp),%r12
  jmp    L70
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_step_G(EVP_MD_CTX *ctx, unsigned char *buffer, const unsigned char *macro, unsigned char *gout, const unsigned int step) {
  unsigned int outl, off;
  if (step) {
    unsigned int j, off, mask, start, dist;
    unsigned char *bp = buffer;
    mask = ((1 << ((int)log2((64 / 4)))) - 1) << (step * ((int)log2((64 / 4))));
    dist = (1 << (step * ((int)log2((64 / 4))))) * 4;
    for (start = 0; start < (1 << ((int)log2(4096))); start = ((start | mask) + 1) & ~mask) {
      for (j = 0, off = start * 4; j < (64 / 4); ++j, off += dist) {
        memcpy(bp, macro + off, 4);
        bp += 4;
      }
    };
  } else {
    buffer = (unsigned char *)macro;
  }
  for (off = 0; off < (4 * 4096); off += 64) {
    EVP_DigestInit_ex(ctx, EVP_sha512(), NULL);
    EVP_DigestUpdate(ctx, buffer + off, 64);
    EVP_DigestFinal_ex(ctx, gout + off, &outl);
    if (0)
      assert(64 == outl);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_step_G>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L25
L52:
  mov    0x10(%rsp),%r12
  lea    0x4000(%rbx),%r14
  lea    0x24(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L66:
  xor    %eax,%eax
  call   <EVP_sha512@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <EVP_DigestInit_ex@plt>
  mov    %rbx,%rsi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <EVP_DigestUpdate@plt>
  add    $0x40,%rbx
  mov    %r12,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    $0x40,%r12
  call   <EVP_DigestFinal_ex@plt>
  cmp    %r14,%rbx
  jne    L66
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    $0x10,%edi
  mov    %r8d,%r12d
  mov    $0x1,%r15d
  call   <log2@plt>
  mov    $0x10,%edi
  mov    %rax,%r13
  call   <log2@plt>
  mov    %r13d,%ecx
  mov    $0x10,%edi
  mov    $0x4,%r13d
  imul   %r12d,%eax
  shl    %cl,%r15d
  sub    $0x1,%r15d
  mov    %eax,%ecx
  shl    %cl,%r15d
  mov    %r15d,0xc(%rsp)
  call   <log2@plt>
  mov    %r12d,%ecx
  movl   $0x0,0x8(%rsp)
  imul   %eax,%ecx
  mov    0x18(%rsp),%rax
  lea    0x40(%rax),%r12
  shl    %cl,%r13d
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x1000,%edi
  lea    -0x40(%r12),%r15
  call   <log2@plt>
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  cmp    0x8(%rsp),%edx
  jbe    L24
  mov    0x8(%rsp),%eax
  lea    0x0(,%rax,4),%r14d
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    $0x4,%edx
  add    $0x4,%r15
  add    %rbx,%rsi
  add    %r13d,%r14d
  call   <memcpy@plt>
  cmp    %r12,%r15
  jne    L65
  mov    0x8(%rsp),%r14d
  mov    0xc(%rsp),%eax
  add    $0x40,%r12
  or     %eax,%r14d
  not    %eax
  add    $0x1,%r14d
  and    %r14d,%eax
  mov    %eax,0x8(%rsp)
  jmp    L36
L24:
  mov    0x18(%rsp),%rbx
  jmp    L52
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_step_G(EVP_MD_CTX *ctx, unsigned char *buffer, const unsigned char *macro, unsigned char *gout, const unsigned int step) {
  unsigned int outl, off;
  if (step) {
    unsigned int j, off, mask, start, dist;
    unsigned char *bp = buffer;
    mask = ((1 << ((int)log2((64 / 4)))) - 1) << (step * ((int)log2((64 / 4))));
    dist = (1 << (step * ((int)log2((64 / 4))))) * 4;
    for (start = 0; start < (1 << ((int)log2(4096))); start = ((start | mask) + 1) & ~mask) {
      for (j = 0, off = start * 4; j < (64 / 4); ++j, off += dist) {
        memcpy(bp, macro + off, 4);
        bp += 4;
      }
    };
  } else {
    buffer = (unsigned char *)macro;
  }
  for (off = 0; off < (4 * 4096); off += 64) {
    EVP_DigestInit_ex(ctx, EVP_sha512(), NULL);
    EVP_DigestUpdate(ctx, buffer + off, 64);
    EVP_DigestFinal_ex(ctx, gout + off, &outl);
    if (0)
      assert(64 == outl);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_step_G>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L44
L40:
  mov    0x10(%rsp),%r12
  lea    0x4000(%rbx),%r14
  lea    0x24(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <EVP_sha512@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <EVP_DigestInit_ex@plt>
  mov    %rbx,%rsi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <EVP_DigestUpdate@plt>
  add    $0x40,%rbx
  mov    %r12,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  add    $0x40,%r12
  call   <EVP_DigestFinal_ex@plt>
  cmp    %rbx,%r14
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    $0x10,%edi
  mov    %r8d,%r12d
  mov    $0x1,%r15d
  call   <log2@plt>
  mov    $0x10,%edi
  mov    %rax,%r13
  call   <log2@plt>
  mov    %r13d,%ecx
  mov    $0x10,%edi
  mov    $0x4,%r13d
  imul   %r12d,%eax
  shl    %cl,%r15d
  sub    $0x1,%r15d
  mov    %eax,%ecx
  shl    %cl,%r15d
  mov    %r15d,0xc(%rsp)
  call   <log2@plt>
  mov    %r12d,%ecx
  movl   $0x0,0x8(%rsp)
  imul   %eax,%ecx
  mov    0x18(%rsp),%rax
  lea    0x40(%rax),%r12
  shl    %cl,%r13d
  nopl   0x0(%rax,%rax,1)
L55:
  mov    $0x1000,%edi
  lea    -0x40(%r12),%r15
  call   <log2@plt>
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  cmp    0x8(%rsp),%edx
  jbe    L16
  mov    0x8(%rsp),%eax
  lea    0x0(,%rax,4),%r14d
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    $0x4,%edx
  add    $0x4,%r15
  add    %rbx,%rsi
  add    %r13d,%r14d
  call   <memcpy@plt>
  cmp    %r12,%r15
  jne    L33
  mov    0x8(%rsp),%r14d
  mov    0xc(%rsp),%eax
  add    $0x40,%r12
  or     %eax,%r14d
  not    %eax
  add    $0x1,%r14d
  and    %r14d,%eax
  mov    %eax,0x8(%rsp)
  jmp    L55
L16:
  mov    0x18(%rsp),%rbx
  jmp    L40
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_step_G(EVP_MD_CTX *ctx, unsigned char *buffer, const unsigned char *macro, unsigned char *gout, const unsigned int step) {
  unsigned int outl, off;
  if (step) {
    unsigned int j, off, mask, start, dist;
    unsigned char *bp = buffer;
    mask = ((1 << ((int)log2((64 / 4)))) - 1) << (step * ((int)log2((64 / 4))));
    dist = (1 << (step * ((int)log2((64 / 4))))) * 4;
    for (start = 0; start < (1 << ((int)log2(4096))); start = ((start | mask) + 1) & ~mask) {
      for (j = 0, off = start * 4; j < (64 / 4); ++j, off += dist) {
        memcpy(bp, macro + off, 4);
        bp += 4;
      }
    };
  } else {
    buffer = (unsigned char *)macro;
  }
  for (off = 0; off < (4 * 4096); off += 64) {
    EVP_DigestInit_ex(ctx, EVP_sha512(), NULL);
    EVP_DigestUpdate(ctx, buffer + off, 64);
    EVP_DigestFinal_ex(ctx, gout + off, &outl);
    if (0)
      assert(64 == outl);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<GetExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L26:
  subq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L26
L14:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
extern char *GetExt(char *name) {
  char *p;
  p = name + strlen(name);
  while ((p != name) && (*p != '\\') && (*p != '/') && (*p != '.')) {
    p--;
  }
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetExt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  je     L26
L1:
  movzbl (%rax),%edx
  lea    -0x2e(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L26
  cmp    $0x5c,%dl
  je     L26
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L1
L26:
  pop    %rbx
  ret
```

assistant: ```c
extern char *GetExt(char *name) {
  char *p;
  p = name + strlen(name);
  while ((p != name) && (*p != '\\') && (*p != '/') && (*p != '.')) {
    p--;
  }
  return (p);
}
```
user: What is the c source code of the assembly code below?

```asm
<GetExt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jne    L24
  jmp    L16
  nopl   0x0(%rax)
L8:
  cmp    $0x5c,%dl
  je     L16
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L16
L24:
  movzbl (%rax),%edx
  lea    -0x2e(%rdx),%ecx
  cmp    $0x1,%cl
  ja     L8
L16:
  pop    %rbx
  ret
```

assistant: ```c
extern char *GetExt(char *name) {
  char *p;
  p = name + strlen(name);
  while ((p != name) && (*p != '\\') && (*p != '/') && (*p != '.')) {
    p--;
  }
  return (p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetExt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jne    L21
  jmp    L9
  nopl   0x0(%rax)
L5:
  cmp    $0x5c,%dl
  je     L9
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L9
L21:
  movzbl (%rax),%edx
  lea    -0x2e(%rdx),%ecx
  cmp    $0x1,%cl
  ja     L5
L9:
  pop    %rbx
  ret
```

assistant: ```c
extern char *GetExt(char *name) {
  char *p;
  p = name + strlen(name);
  while ((p != name) && (*p != '\\') && (*p != '/') && (*p != '.')) {
    p--;
  }
  return (p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<atofs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L26
L37:
  subl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x1,-0xc(%rbp)
  jle    L4
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movsbl -0xd(%rbp),%eax
  sub    $0x47,%eax
  cmp    $0x26,%eax
  seta   %dl
  test   %dl,%dl
  jne    L71
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x1000000010,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L17
  movabs $0x4000000040,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L23
  movabs $0x100000001,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L71
  movsd  -0x8(%rbp),%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L23:
  movsd  -0x8(%rbp),%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L17:
  movsd  -0x8(%rbp),%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  jmp    L6
L71:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: f64
name: unpack_data
arguments: data_label: D38
type_infered: f64

tool: D1: 1

tool: D38: 1000

assistant: ```c
double atofs(char *s) {
  char last;
  int len;
  double suff = 1.0;
  len = strlen(s);
  while (len > 1 && isspace(s[len - 1]))
    --len;
  last = s[len - 1];
  s[len - 1] = '\0';
  switch (last) {
  case 'g':
  case 'G':
    suff *= 1e3;
  case 'm':
  case 'M':
    suff *= 1e3;
  case 'k':
  case 'K':
    suff *= 1e3;
    suff *= atof(s);
    s[len - 1] = last;
    return suff;
  }
  s[len - 1] = last;
  return atof(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<atofs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jle    L51
  cltq
  lea    -0x1(%r12,%rax,1),%rbp
L22:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L51
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0x1,%ebx
  jne    L22
L51:
  movslq %ebx,%rbx
  lea    -0x1(%r12,%rbx,1),%rbx
  movzbl (%rbx),%ebp
  movb   $0x0,(%rbx)
  lea    -0x47(%rbp),%ecx
  cmp    $0x26,%cl
  ja     L13
  mov    $0x1,%eax
  shl    %cl,%rax
  movabs $0x4000000040,%rdx
  test   %rdx,%rax
  jne    L38
  movabs $0x1000000010,%rdx
  test   %rdx,%rax
  jne    L81
  movabs $0x100000001,%rdx
  movsd  D7(%rip),%xmm0
  test   %rdx,%rax
  jne    L86
L13:
  mov    %bpl,(%rbx)
  mov    %r12,%rdi
  call   <atof@plt>
  jmp    L66
L38:
  movsd  D38(%rip),%xmm0
L86:
  mulsd  D7(%rip),%xmm0
L56:
  mulsd  D7(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %r12,%rdi
  call   <atof@plt>
  mulsd  0x8(%rsp),%xmm0
  mov    %bpl,(%rbx)
L66:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L81:
  movsd  D38(%rip),%xmm0
  jmp    L56
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: f64
name: unpack_data
arguments: label: D38
datatype: f64

tool: D7: 1000

tool: D38: 1

assistant: ```c
double atofs(char *s) {
  char last;
  int len;
  double suff = 1.0;
  len = strlen(s);
  while (len > 1 && isspace(s[len - 1]))
    --len;
  last = s[len - 1];
  s[len - 1] = '\0';
  switch (last) {
  case 'g':
  case 'G':
    suff *= 1e3;
  case 'm':
  case 'M':
    suff *= 1e3;
  case 'k':
  case 'K':
    suff *= 1e3;
    suff *= atof(s);
    s[len - 1] = last;
    return suff;
  }
  s[len - 1] = last;
  return atof(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atofs>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    $0x1,%ebp
  jg     L51
  jmp    L45
  nopl   0x0(%rax)
L63:
  sub    $0x1,%ebp
  sub    $0x1,%rbx
  cmp    $0x1,%ebp
  je     L13
L51:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
L45:
  movzbl (%rbx),%ebp
  movb   $0x0,(%rbx)
  lea    -0x47(%rbp),%ecx
  cmp    $0x26,%cl
  ja     L17
  movabs $0x100000001,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L25
  movabs $0x1000000010,%rdx
  test   %rdx,%rax
  jne    L59
  movabs $0x4000000040,%rdx
  test   %rdx,%rax
  jne    L88
L17:
  mov    %bpl,(%rbx)
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <atof@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rbx
  jmp    L45
L88:
  movsd  D17(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
L58:
  mov    %r12,%rdi
  call   <atof@plt>
  mov    %bpl,(%rbx)
  mulsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  movsd  D13(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L58
L25:
  movsd  D14(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L58
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D13
type_infered: f64
name: disassemble_data
arguments: data_tag: D14
type_infered: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

tool: D13: 1000

tool: {"D14": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
double atofs(char *s) {
  char last;
  int len;
  double suff = 1.0;
  len = strlen(s);
  while (len > 1 && isspace(s[len - 1]))
    --len;
  last = s[len - 1];
  s[len - 1] = '\0';
  switch (last) {
  case 'g':
  case 'G':
    suff *= 1e3;
  case 'm':
  case 'M':
    suff *= 1e3;
  case 'k':
  case 'K':
    suff *= 1e3;
    suff *= atof(s);
    s[len - 1] = last;
    return suff;
  }
  s[len - 1] = last;
  return atof(s);
}
```