ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ReadLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdi,%rbx
L29:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xd,%eax
  je     L29
  mov    %rbx,%rcx
  mov    %al,(%rbx)
  cmp    $0xa,%eax
  je     L27
  add    $0x1,%rbx
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L29
L27:
  movb   $0x0,(%rcx)
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ReadLine(char *Buffer, FILE *InputFile) {
  int i = 0, j;
  while (1) {
    j = fgetc(InputFile);
    if (j == '\r')
      continue;
    Buffer[i++] = j;
    if (j == '\n' || j == EOF) {
      Buffer[i - 1] = 0;
      if (j == EOF)
        return 1;
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ReadLine>:
  endbr64
  push   %r12
  mov    D1(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L22:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xd,%eax
  je     L22
  mov    %al,(%rbx)
  mov    %rbx,%rdx
  cmp    $0xa,%eax
  je     L12
  add    $0x1,%rbx
  cmp    %eax,(%r12)
  jne    L22
L12:
  movb   $0x0,(%rdx)
  cmp    %eax,(%r12)
  sete   %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
```

assistant: ```c
int ReadLine(char *Buffer, FILE *InputFile) {
  int i = 0, j;
  while (1) {
    j = fgetc(InputFile);
    if (j == '\r')
      continue;
    Buffer[i++] = j;
    if (j == '\n' || j == EOF) {
      Buffer[i - 1] = 0;
      if (j == EOF)
        return 1;
      break;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ReadLine>:
  endbr64
  push   %r12
  mov    D4(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L22:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xd,%eax
  je     L22
  mov    %al,(%rbx)
  mov    %rbx,%rdx
  cmp    $0xa,%eax
  je     L13
  add    $0x1,%rbx
  cmp    %eax,(%r12)
  jne    L22
L13:
  movb   $0x0,(%rdx)
  cmp    %eax,(%r12)
  sete   %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
```

assistant: ```c
int ReadLine(char *Buffer, FILE *InputFile) {
  int i = 0, j;
  while (1) {
    j = fgetc(InputFile);
    if (j == '\r')
      continue;
    Buffer[i++] = j;
    if (j == '\n' || j == EOF) {
      Buffer[i - 1] = 0;
      if (j == EOF)
        return 1;
      break;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  nop
L7:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rdx,%rax
  lea    0x1(%rax),%rdx
  movzbl (%rsi),%esi
  mov    %sil,(%rax)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy(dest, src) register char *dest, *src;
{
  while ((*dest++ = *src++) != '\n')
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L8
  ret
```

assistant: ```c
void copy(dest, src) register char *dest, *src;
{
  while ((*dest++ = *src++) != '\n')
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L7
  ret
```

assistant: ```c
void copy(dest, src) register char *dest, *src;
{
  while ((*dest++ = *src++) != '\n')
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L7
  ret
```

assistant: ```c
void copy(dest, src) register char *dest, *src;
{
  while ((*dest++ = *src++) != '\n')
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sca_fopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
L5:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
FILE *sca_fopen(char *file, char *mode) {
  FILE *fptr = (FILE *)NULL;
  do {
    fptr = fopen(file, mode);
  } while (errno == EINTR);
  return fptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sca_fopen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
L8:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    D8(%rip),%rcx
  mov    D9(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
FILE *sca_fopen(char *file, char *mode) {
  FILE *fptr = (FILE *)NULL;
  do {
    fptr = fopen(file, mode);
  } while (errno == EINTR);
  return fptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sca_fopen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D12(%rip),%r13
  mov    D0(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    (%r12),%rdx
  cmp    %rdx,0x0(%r13)
  je     L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
FILE *sca_fopen(char *file, char *mode) {
  FILE *fptr = (FILE *)NULL;
  do {
    fptr = fopen(file, mode);
  } while (errno == EINTR);
  return fptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<sca_fopen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%r13
  mov    D19(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    (%r12),%rdx
  cmp    %rdx,0x0(%r13)
  je     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
FILE *sca_fopen(char *file, char *mode) {
  FILE *fptr = (FILE *)NULL;
  do {
    fptr = fopen(file, mode);
  } while (errno == EINTR);
  return fptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xpacket_print_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %02x

assistant: ```c
void xpacket_print_raw(unsigned char *packet, int len) {
  int i;
  for (i = 0; i < len; i++) {
    printf("%02x", packet[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xpacket_print_raw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D6(%rip),%rbp
L5:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L5
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: %02x

assistant: ```c
void xpacket_print_raw(unsigned char *packet, int len) {
  int i;
  for (i = 0; i < len; i++) {
    printf("%02x", packet[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<xpacket_print_raw>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L6:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %02x

assistant: ```c
void xpacket_print_raw(unsigned char *packet, int len) {
  int i;
  for (i = 0; i < len; i++) {
    printf("%02x", packet[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xpacket_print_raw>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L11:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L19:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: %02x

assistant: ```c
void xpacket_print_raw(unsigned char *packet, int len) {
  int i;
  for (i = 0; i < len; i++) {
    printf("%02x", packet[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testAllAsicc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L12:
  mov    -0x1c(%rbp),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <alpha2_encode@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x1c(%rbp)
L26:
  cmpl   $0xff,-0x1c(%rbp)
  jle    L12
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: tmp[0]=0x%02x   ==>  

assistant: ```c
void testAllAsicc() {
  unsigned char tmp[1];
  unsigned char *ret;
  int i = 0;
  for (i = 0x00; i <= 0xFF; i++) {
    tmp[0] = i;
    printf("tmp[0]=0x%02x   ==>  ", tmp[0]);
    ret = alpha2_encode(tmp, 1);
    printf("%s\n", ret);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testAllAsicc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D2(%rip),%rbp
L5:
  mov    %bl,0x7(%rsp)
  movzbl %bl,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rdi
  mov    $0x1,%esi
  call   <alpha2_encode@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: tmp[0]=0x%02x   ==>  

assistant: ```c
void testAllAsicc() {
  unsigned char tmp[1];
  unsigned char *ret;
  int i = 0;
  for (i = 0x00; i <= 0xFF; i++) {
    tmp[0] = i;
    printf("tmp[0]=0x%02x   ==>  ", tmp[0]);
    ret = alpha2_encode(tmp, 1);
    printf("%s\n", ret);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testAllAsicc>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %bl,0x7(%rsp)
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <alpha2_encode@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  cmp    $0x100,%ebx
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: tmp[0]=0x%02x   ==>  

assistant: ```c
void testAllAsicc() {
  unsigned char tmp[1];
  unsigned char *ret;
  int i = 0;
  for (i = 0x00; i <= 0xFF; i++) {
    tmp[0] = i;
    printf("tmp[0]=0x%02x   ==>  ", tmp[0]);
    ret = alpha2_encode(tmp, 1);
    printf("%s\n", ret);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testAllAsicc>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %bl,0x7(%rsp)
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <alpha2_encode@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  cmp    $0x100,%ebx
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: tmp[0]=0x%02x   ==>  

assistant: ```c
void testAllAsicc() {
  unsigned char tmp[1];
  unsigned char *ret;
  int i = 0;
  for (i = 0x00; i <= 0xFF; i++) {
    tmp[0] = i;
    printf("tmp[0]=0x%02x   ==>  ", tmp[0]);
    ret = alpha2_encode(tmp, 1);
    printf("%s\n", ret);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L39
L14:
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,%rbx
  subl   $0x2,-0x2c(%rbp)
L39:
  cmpl   $0x1,-0x2c(%rbp)
  jg     L14
  cmpl   $0x1,-0x2c(%rbp)
  jne    L21
  movw   $0x0,-0x1a(%rbp)
  lea    -0x1a(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  movzwl -0x1a(%rbp),%eax
  movzwl %ax,%eax
  add    %rax,%rbx
L21:
  mov    %rbx,%rdx
  sar    $0x10,%rdx
  movzwl %bx,%eax
  lea    (%rdx,%rax,1),%rbx
  mov    %rbx,%rax
  sar    $0x10,%rax
  add    %rax,%rbx
  mov    %ebx,%eax
  not    %eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned short Checksum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: What is the c source code of the assembly code below?

```asm
<Checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L41
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L28:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L28
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L22:
  cmp    $0x1,%esi
  je     L1
L27:
  mov    %rax,%rdx
  sar    $0x10,%rdx
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L41:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L22
L1:
  movzwl (%rcx),%edx
  add    %rdx,%rax
  jmp    L27
```

assistant: ```c
unsigned short Checksum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: What is the c source code of the assembly code below:

```asm
<Checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L10
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L6:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L6
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L27:
  cmp    $0x1,%esi
  jne    L33
  movzwl (%rcx),%edx
  add    %rdx,%rax
L33:
  mov    %rax,%rdx
  movzwl %ax,%eax
  sar    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L27
```

assistant: ```c
unsigned short Checksum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Checksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L51
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0xd,%r10d
  jbe    L21
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  pxor   %xmm3,%xmm3
  mov    %rdi,%rax
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax,%rax,1)
L98:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  punpckhwd %xmm4,%xmm1
  punpcklwd %xmm4,%xmm2
  movdqa %xmm2,%xmm5
  punpckhdq %xmm3,%xmm2
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm0
  paddq  %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  punpckhdq %xmm3,%xmm1
  punpckldq %xmm3,%xmm2
  paddq  %xmm2,%xmm0
  paddq  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L98
  mov    %ecx,%r8d
  movdqa %xmm0,%xmm1
  and    $0xfffffff8,%r8d
  psrldq $0x8,%xmm1
  mov    %r8d,%r11d
  paddq  %xmm1,%xmm0
  mov    %r8d,%edi
  neg    %r11d
  movq   %xmm0,%rax
  lea    (%rdx,%rdi,2),%rdi
  lea    (%rsi,%r11,2),%esi
  cmp    %ecx,%r8d
  je     L22
L114:
  movzwl (%rdi),%r8d
  add    %r8,%rax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L22
  movzwl 0x2(%rdi),%r8d
  add    %r8,%rax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L22
  movzwl 0x4(%rdi),%r8d
  add    %r8,%rax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L22
  movzwl 0x6(%rdi),%r8d
  add    %r8,%rax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L22
  movzwl 0x8(%rdi),%r8d
  add    %r8,%rax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L22
  movzwl 0xa(%rdi),%r8d
  add    %r8,%rax
  cmp    $0xd,%esi
  jle    L22
  movzwl 0xc(%rdi),%esi
  add    %rsi,%rax
L22:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r10,%rcx,2),%esi
L99:
  cmp    $0x1,%esi
  jne    L91
  movzwl (%rdx),%edx
  add    %rdx,%rax
L91:
  mov    %rax,%rdx
  movzwl %ax,%eax
  sar    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  jmp    L99
L21:
  xor    %eax,%eax
  jmp    L114
```

assistant: ```c
unsigned short Checksum(unsigned short *ptr, int nbytes) {
  register long sum;
  unsigned short oddbyte;
  register short answer;
  sum = 0;
  while (nbytes > 1) {
    sum += *ptr++;
    nbytes -= 2;
  }
  if (nbytes == 1) {
    oddbyte = 0;
    *((u_char *)&oddbyte) = *(u_char *)ptr;
    sum += oddbyte;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum = sum + (sum >> 16);
  answer = (short)~sum;
  return (answer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L41
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L43:
  cmpl   $0x0,-0x8(%rbp)
  js     L13
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L30
L13:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int *arr, int n) {
  int i, j, item;
  for (i = 1; i < n; i++) {
    item = arr[i];
    j = i - 1;
    while (j > -1 && arr[j] > item) {
      arr[j + 1] = arr[j];
      j--;
    }
    arr[j + 1] = item;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L56
L13:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L5
L56:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L13
L35:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L13
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L35
  jmp    L13
L5:
  ret
```

assistant: ```c
void insertion_sort(int *arr, int n) {
  int i, j, item;
  for (i = 1; i < n; i++) {
    item = arr[i];
    j = i - 1;
    while (j > -1 && arr[j] > item) {
      arr[j + 1] = arr[j];
      j--;
    }
    arr[j + 1] = item;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insertion_sort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L7
L3:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L43
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L34
  mov    %rdi,%rax
L5:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L3
L7:
  ret
  nopl   (%rax)
L43:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L5
```

assistant: ```c
void insertion_sort(int *arr, int n) {
  int i, j, item;
  for (i = 1; i < n; i++) {
    item = arr[i];
    j = i - 1;
    while (j > -1 && arr[j] > item) {
      arr[j + 1] = arr[j];
      j--;
    }
    arr[j + 1] = item;
  }
}
```