ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cdate>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ctime@plt>
  cltq
  movzwl 0x8(%rax),%edx
  movb   $0x2d,0x3(%rax)
  movb   $0x2d,0x7(%rax)
  mov    %dx,0x1(%rax)
  movzwl 0x16(%rax),%edx
  movb   $0x40,0xa(%rax)
  mov    %dx,0x8(%rax)
  movb   $0x0,0x13(%rax)
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
cdate(dataddr) long *dataddr;
{
  register char *cp;
  cp = ctime(dataddr);
  cp[1] = cp[8];
  cp[2] = cp[9];
  cp[3] = '-';
  cp[7] = '-';
  cp[8] = cp[22];
  cp[9] = cp[23];
  cp[10] = '@';
  cp[19] = 0;
  return (cp + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cdate>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ctime@plt>
  cltq
  movzwl 0x8(%rax),%edx
  movb   $0x2d,0x3(%rax)
  movb   $0x2d,0x7(%rax)
  mov    %dx,0x1(%rax)
  movzwl 0x16(%rax),%edx
  movb   $0x40,0xa(%rax)
  mov    %dx,0x8(%rax)
  movb   $0x0,0x13(%rax)
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
cdate(dataddr) long *dataddr;
{
  register char *cp;
  cp = ctime(dataddr);
  cp[1] = cp[8];
  cp[2] = cp[9];
  cp[3] = '-';
  cp[7] = '-';
  cp[8] = cp[22];
  cp[9] = cp[23];
  cp[10] = '@';
  cp[19] = 0;
  return (cp + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<match_ip_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x5b,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  je     L77
  mov    -0x30(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <match_ipv6_address@plt>
  test   %rax,%rax
  je     L33
  movl   $0x3,-0x14(%rbp)
  jmp    L43
L33:
  mov    -0x30(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <match_ipvfuture@plt>
  test   %rax,%rax
  je     L43
  movl   $0x4,-0x14(%rbp)
L43:
  cmpl   $0x0,-0x14(%rbp)
  je     L77
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x5d,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  je     L77
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L74
L77:
  mov    $0x0,%eax
L74:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int match_ip_literal(char const **str, char const *end, int *type) {
  char const *i = *str;
  int temp = 0;
  if (match_char(&i, end, '[')) {
    if (match_ipv6_address(&i, end)) {
      temp = (3);
    } else if (match_ipvfuture(&i, end)) {
      temp = (4);
    }
    if (temp != 0 && match_char(&i, end, ']')) {
      *str = i;
      *type = temp;
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match_ip_literal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  mov    $0x5b,%edx
  call   <match_char@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L40
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <match_ipv6_address@plt>
  test   %rax,%rax
  jne    L27
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <match_ipvfuture@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  mov    $0x4,%r13d
  test   %rdx,%rdx
  jne    L28
  jmp    L48
L27:
  mov    $0x3,%r13d
L28:
  mov    %rsp,%rdi
  mov    $0x5d,%edx
  mov    %rbx,%rsi
  call   <match_char@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L48
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    %r13d,(%r12)
  mov    $0x1,%eax
  jmp    L48
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_ip_literal(char const **str, char const *end, int *type) {
  char const *i = *str;
  int temp = 0;
  if (match_char(&i, end, '[')) {
    if (match_ipv6_address(&i, end)) {
      temp = (3);
    } else if (match_ipvfuture(&i, end)) {
      temp = (4);
    }
    if (temp != 0 && match_char(&i, end, ']')) {
      *str = i;
      *type = temp;
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<match_ip_literal>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x5b,%edx
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    %rsp,%r12
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  call   <match_char@plt>
  test   %rax,%rax
  jne    L12
L38:
  xor    %eax,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <match_ipv6_address@plt>
  test   %rax,%rax
  jne    L40
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x4,%r14d
  call   <match_ipvfuture@plt>
  test   %rax,%rax
  je     L38
L41:
  mov    $0x5d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  je     L38
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  mov    %r14d,0x0(%r13)
  jmp    L16
  nopl   (%rax)
L40:
  mov    $0x3,%r14d
  jmp    L41
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_ip_literal(char const **str, char const *end, int *type) {
  char const *i = *str;
  int temp = 0;
  if (match_char(&i, end, '[')) {
    if (match_ipv6_address(&i, end)) {
      temp = (3);
    } else if (match_ipvfuture(&i, end)) {
      temp = (4);
    }
    if (temp != 0 && match_char(&i, end, ']')) {
      *str = i;
      *type = temp;
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<match_ip_literal>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x5b,%edx
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    %rsp,%r12
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  call   <match_char@plt>
  test   %rax,%rax
  jne    L57
L65:
  xor    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <match_ipv6_address@plt>
  test   %rax,%rax
  jne    L48
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x4,%r14d
  call   <match_ipvfuture@plt>
  test   %rax,%rax
  je     L65
L2:
  mov    $0x5d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <match_char@plt>
  test   %rax,%rax
  je     L65
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  mov    %r14d,0x0(%r13)
  jmp    L13
  nopl   (%rax)
L48:
  mov    $0x3,%r14d
  jmp    L2
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_ip_literal(char const **str, char const *end, int *type) {
  char const *i = *str;
  int temp = 0;
  if (match_char(&i, end, '[')) {
    if (match_ipv6_address(&i, end)) {
      temp = (3);
    } else if (match_ipvfuture(&i, end)) {
      temp = (4);
    }
    if (temp != 0 && match_char(&i, end, ']')) {
      *str = i;
      *type = temp;
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strfry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D53(%rip),%eax
  test   %eax,%eax
  jne    L26
  movq   $0x0,D29(%rip)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  xor    %ebx,%eax
  lea    D29(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x20,%edx
  lea    D5(%rip),%rsi
  mov    %eax,%edi
  call   <__initstate_r@plt>
  movl   $0x1,D53(%rip)
L26:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L35
L14:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <__random_r@plt>
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x31(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x48(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x31(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x28(%rbp)
L35:
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L14
  mov    -0x48(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strfry(char *string) {
  static int init;
  static struct random_data rdata;
  size_t len, i;
  if (!init) {
    static char state[32];
    rdata.state = NULL;
    __initstate_r(time((time_t *)NULL) ^ getpid(), state, sizeof(state), &rdata);
    init = 1;
  }
  len = strlen(string);
  for (i = 0; i < len; ++i) {
    int32_t j;
    char c;
    __random_r(&rdata, &j);
    j %= len;
    c = string[i];
    string[i] = string[j];
    string[j] = c;
  }
  return string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strfry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x0,D37(%rip)
  je     L17
L46:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%r13
  lea    D54(%rip),%r14
L4:
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <__random_r@plt>
  movzbl (%rbx),%ecx
  mov    (%rsp),%rax
  mov    $0x0,%edx
  div    %rbp
  add    %r12,%rdx
  movzbl (%rdx),%eax
  mov    %al,(%rbx)
  mov    %cl,(%rdx)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L4
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  movq   $0x0,D54(%rip)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edi
  xor    %eax,%edi
  lea    D54(%rip),%rcx
  mov    $0x20,%edx
  lea    D42(%rip),%rsi
  call   <__initstate_r@plt>
  movl   $0x1,D37(%rip)
  jmp    L46
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strfry(char *string) {
  static int init;
  static struct random_data rdata;
  size_t len, i;
  if (!init) {
    static char state[32];
    rdata.state = NULL;
    __initstate_r(time((time_t *)NULL) ^ getpid(), state, sizeof(state), &rdata);
    init = 1;
  }
  len = strlen(string);
  for (i = 0; i < len; ++i) {
    int32_t j;
    char c;
    __random_r(&rdata, &j);
    j %= len;
    c = string[i];
    string[i] = string[j];
    string[j] = c;
  }
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strfry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D27(%rip),%eax
  test   %eax,%eax
  je     L49
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%r14
  lea    D29(%rip),%r15
  mov    %rsp,%r13
L22:
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x1,%rbx
  call   <__random_r@plt>
  mov    (%rsp),%rax
  xor    %edx,%edx
  movzbl -0x1(%rbx),%ecx
  div    %rbp
  add    %r12,%rdx
  movzbl (%rdx),%eax
  mov    %al,-0x1(%rbx)
  mov    %cl,(%rdx)
  cmp    %r14,%rbx
  jne    L22
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L49:
  xor    %edi,%edi
  lea    D29(%rip),%r15
  movq   $0x0,D29(%rip)
  call   <time@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebx,%edi
  mov    %r15,%rcx
  mov    $0x20,%edx
  xor    %eax,%edi
  lea    D44(%rip),%rsi
  call   <__initstate_r@plt>
  movl   $0x1,D27(%rip)
  jmp    L1
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strfry(char *string) {
  static int init;
  static struct random_data rdata;
  size_t len, i;
  if (!init) {
    static char state[32];
    rdata.state = NULL;
    __initstate_r(time((time_t *)NULL) ^ getpid(), state, sizeof(state), &rdata);
    init = 1;
  }
  len = strlen(string);
  for (i = 0; i < len; ++i) {
    int32_t j;
    char c;
    __random_r(&rdata, &j);
    j %= len;
    c = string[i];
    string[i] = string[j];
    string[j] = c;
  }
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strfry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D30(%rip),%eax
  test   %eax,%eax
  je     L8
L47:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L33
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%r14
  lea    D26(%rip),%r15
  mov    %rsp,%r13
L48:
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x1,%rbx
  call   <__random_r@plt>
  mov    (%rsp),%rax
  xor    %edx,%edx
  movzbl -0x1(%rbx),%ecx
  div    %rbp
  add    %r12,%rdx
  movzbl (%rdx),%eax
  mov    %al,-0x1(%rbx)
  mov    %cl,(%rdx)
  cmp    %r14,%rbx
  jne    L48
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L8:
  xor    %edi,%edi
  lea    D26(%rip),%r15
  movq   $0x0,D26(%rip)
  call   <time@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %ebx,%edi
  mov    %r15,%rcx
  mov    $0x20,%edx
  xor    %eax,%edi
  lea    D18(%rip),%rsi
  call   <__initstate_r@plt>
  movl   $0x1,D30(%rip)
  jmp    L47
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strfry(char *string) {
  static int init;
  static struct random_data rdata;
  size_t len, i;
  if (!init) {
    static char state[32];
    rdata.state = NULL;
    __initstate_r(time((time_t *)NULL) ^ getpid(), state, sizeof(state), &rdata);
    init = 1;
  }
  len = strlen(string);
  for (i = 0; i < len; ++i) {
    int32_t j;
    char c;
    __random_r(&rdata, &j);
    j %= len;
    c = string[i];
    string[i] = string[j];
    string[j] = c;
  }
  return string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: %*d

assistant: ```c
main() {
  int x = 5;
  printf("%*d", x, x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: %*d

assistant: ```c
main() {
  int x = 5;
  printf("%*d", x, x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %*d

assistant: ```c
main() {
  int x = 5;
  printf("%*d", x, x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %*d

assistant: ```c
main() {
  int x = 5;
  printf("%*d", x, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L39
L64:
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L58
  movl   $0x1,-0xc(%rbp)
L58:
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jae    L59
  cmpl   $0x0,-0xc(%rbp)
  je     L64
L59:
  cmpl   $0x0,-0xc(%rbp)
  jne    L77
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L72
L77:
  subl   $0x1,-0x10(%rbp)
  jmp    L8
L26:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x10(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L26
L72:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D45
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D45:  %u

tool: D29: INEXISTENTE

tool: D8: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned int a, b, c, i = 0, flag = 0;
  scanf(" %u", &a);
  scanf(" %u", &b);
  scanf(" %u", &c);
  for (i = b; i < c && flag == 0; ++i) {
    if (i % a == 0)
      flag = 1;
  }
  if (flag == 0)
    printf("INEXISTENTE\n");
  else {
    for (i--; i <= c; i += a) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%esi
  cmp    %esi,%ebx
  jae    L1
  mov    0xc(%rsp),%ecx
  jmp    L65
L59:
  add    $0x1,%ebx
  cmp    %esi,%ebx
  je     L1
L65:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ecx
  test   %edx,%edx
  jne    L59
  lea    D22(%rip),%rbp
  cmp    %ebx,%esi
  jb     L43
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    0xc(%rsp),%eax
  mov    %eax,%ebx
  cmp    %eax,0x14(%rsp)
  jae    L8
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string

tool: D6:  %u

tool: D22: %d


tool: D29: INEXISTENTE

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned int a, b, c, i = 0, flag = 0;
  scanf(" %u", &a);
  scanf(" %u", &b);
  scanf(" %u", &c);
  for (i = b; i < c && flag == 0; ++i) {
    if (i % a == 0)
      flag = 1;
  }
  if (flag == 0)
    printf("INEXISTENTE\n");
  else {
    for (i--; i <= c; i += a) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%esi
  cmp    %ebx,%esi
  jbe    L48
  mov    0xc(%rsp),%ecx
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %ebx,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L33
  add    $0x1,%ebx
  cmp    %ebx,%esi
  jne    L36
L48:
  lea    D15(%rip),%rdi
  call   <puts@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  cmp    %ebx,%esi
  jb     L0
  lea    D6(%rip),%rbp
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    0xc(%rsp),%ebx
  cmp    %ebx,0x14(%rsp)
  jae    L1
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D6
datatype: string

tool: D24:  %u

tool: D15: INEXISTENTE

tool: D6: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned int a, b, c, i = 0, flag = 0;
  scanf(" %u", &a);
  scanf(" %u", &b);
  scanf(" %u", &c);
  for (i = b; i < c && flag == 0; ++i) {
    if (i % a == 0)
      flag = 1;
  }
  if (flag == 0)
    printf("INEXISTENTE\n");
  else {
    for (i--; i <= c; i += a) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```