user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x33c(%rbp),%rdx
  lea    -0x340(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x338(%rbp)
  jmp    L125
L3:
  movl   $0x0,-0x334(%rbp)
  jmp    L108
L10:
  lea    -0x330(%rbp),%rcx
  mov    -0x334(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x338(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x334(%rbp)
L108:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jl     L10
  addl   $0x1,-0x338(%rbp)
L125:
  mov    -0x340(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L3
  movl   $0x0,-0x338(%rbp)
  jmp    L33
L39:
  movl   $0x0,-0x334(%rbp)
  jmp    L57
L53:
  mov    -0x334(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x338(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x330(%rbp,%rax,4),%edx
  mov    -0x338(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x334(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x334(%rbp)
L57:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jl     L53
  addl   $0x1,-0x338(%rbp)
L33:
  mov    -0x340(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L39
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x338(%rbp)
  jmp    L35
L4:
  movl   $0x0,-0x334(%rbp)
  jmp    L23
L74:
  mov    -0x334(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x338(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x334(%rbp)
L23:
  mov    -0x340(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jl     L74
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x338(%rbp)
L35:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D56
type: string
name: disassemble_data
arguments: label: D51
type: string

tool: D14: Vyvedi broi redove i koloni na matircata 

tool: D19: %d%d

tool: D4: Vyvedete elementite na matricata

tool: D8: %d

tool: D56: Transponiranata matrica :-

tool: D51: %d	

assistant: ```c
int main() {
  int m, n, c, d, matrix[10][10], transpose[10][10];
  printf("Vyvedi broi redove i koloni na matircata \n");
  scanf("%d%d", &m, &n);
  printf("Vyvedete elementite na matricata\n");
  for (c = 0; c < m; c++)
    for (d = 0; d < n; d++)
      scanf("%d", &matrix[c][d]);
  for (c = 0; c < m; c++)
    for (d = 0; d < n; d++)
      transpose[d][c] = matrix[c][d];
  printf("Transponiranata matrica :-\n");
  for (c = 0; c < n; c++) {
    for (d = 0; d < m; d++)
      printf("%d\t", transpose[c][d]);
    printf("\n");
  }
  return 0;
}
```