user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L56
L22:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edi
  call   <pr_argv@plt>
L56:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L22
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L30
L23:
  addl   $0x1,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x8,%rax
  mov    %rax,-0x30(%rbp)
L30:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L20
L19:
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy_my@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L78
L66:
  addl   $0x1,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x8,%rax
  mov    %rax,-0x30(%rbp)
L78:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L66
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <arr_ops@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D36
type: string
name: read_data
arguments: tag: D55
type: string
name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D24
type: string
name: read_data
arguments: tag: D34
type: string

tool: D36: * argv = '%s';


tool: D55: end of first cycle.

tool: D25: 
after ending of first cycle argc = %d, and * argv = '%s';


tool: D1: before begining of second cycle argc = %d, and * argv = '%s';


tool: D24: result string = '%s';


tool: D34: end of second cycle.


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int j = argc;
  char *f;
  char **arr;
  while (j-- > 0) {
    printf("* argv = '%s';\n", *argv);
    pr_argv(*argv++);
  }
  printf("end of first cycle.\n");
  printf("\nafter ending of first cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++, *argv--) {
  }
  printf("before begining of second cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++) {
    strcpy_my(f, *argv++);
    printf("result string = '%s';\n", f);
  }
  printf("end of second cycle.\n\n");
  for (i = 0; i < argc; i++, *argv--) {
  }
  arr_ops(arr, argc, argv);
  return 0;
}
```