ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  lea    D47(%rip),%rcx
  xor    %eax,%eax
  push   %r12
  lea    D40(%rip),%r12
  mov    %r13,%rdx
  push   %rbp
  lea    D28(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D12(%rip),%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D11(%rip),%rcx
  xor    %eax,%eax
  call   <printf@plt>
  lea    D3(%rip),%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D47
datatype: string
name: read_data
arguments: tag: D40
datatype: string
name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D38
datatype: string

tool: D1: some

tool: D47: varargs1(1)


tool: D40: are

tool: D28: here %s %s %s

tool: D12: varargs2(4)


tool: D11: varargs3(5)


tool: 

tool: D38: hello, world


assistant: ```c
int main() {
  if (!(0)) {
    printf("here %s %s %s", "are", "some", "varargs1(1)\n");
  };
  if (!(1)) {
    printf("here %s %s %s", "are", "some", "varargs1(2)\n");
  };
  if ((0)) {
    printf("here %s %s %s", "are", "some", "varargs2(3)\n");
  };
  if ((1)) {
    printf("here %s %s %s", "are", "some", "varargs2(4)\n");
  };
  { printf("here %s %s %s", "are", "some", "varargs3(5)\n"); };
  printf("hello, world\n", "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<product_ops_get_sku>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: product::get_sku()


assistant: ```c
char *product_ops_get_sku(struct product *product) {
  printf("product::get_sku()\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<product_ops_get_sku>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: product::get_sku()


assistant: ```c
char *product_ops_get_sku(struct product *product) {
  printf("product::get_sku()\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<product_ops_get_sku>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: product::get_sku()


assistant: ```c
char *product_ops_get_sku(struct product *product) {
  printf("product::get_sku()\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<product_ops_get_sku>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: product::get_sku()


assistant: ```c
char *product_ops_get_sku(struct product *product) {
  printf("product::get_sku()\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L28
L21:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ItoaHelper@plt>
  movb   $0x0,-0x19(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L19
L12:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x19(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x10(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L12
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int Itoa(int n, char *buffer, size_t bufferLen) {
  if (!buffer) {
    return 1;
  }
  ItoaHelper(n, buffer, bufferLen);
  char temp = 0;
  size_t len = strlen(buffer);
  for (size_t i = 1, j = len; i < j; ++i, --j) {
    temp = buffer[i - 1];
    buffer[i - 1] = buffer[j - 1];
    buffer[j - 1] = temp;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Itoa>:
  endbr64
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L39
  push   %rbx
  mov    %rsi,%rbx
  call   <ItoaHelper@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  cmp    $0x1,%rax
  jbe    L4
  mov    $0x1,%eax
L23:
  movzbl -0x1(%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,-0x1(%rbx,%rax,1)
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  ja     L23
  mov    $0x0,%eax
L20:
  pop    %rbx
  ret
L4:
  mov    $0x0,%eax
  jmp    L20
L39:
  ret
```

assistant: ```c
int Itoa(int n, char *buffer, size_t bufferLen) {
  if (!buffer) {
    return 1;
  }
  ItoaHelper(n, buffer, bufferLen);
  char temp = 0;
  size_t len = strlen(buffer);
  for (size_t i = 1, j = len; i < j; ++i, --j) {
    temp = buffer[i - 1];
    buffer[i - 1] = buffer[j - 1];
    buffer[j - 1] = temp;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Itoa>:
  endbr64
  test   %rsi,%rsi
  je     L7
  push   %rbx
  mov    %rsi,%rbx
  call   <ItoaHelper@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x1,%edx
  cmp    $0x1,%rax
  jbe    L22
  nopl   (%rax)
L4:
  sub    $0x1,%rax
  movzbl -0x1(%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,-0x1(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  cmp    %rdx,%rax
  ja     L4
L22:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Itoa(int n, char *buffer, size_t bufferLen) {
  if (!buffer) {
    return 1;
  }
  ItoaHelper(n, buffer, bufferLen);
  char temp = 0;
  size_t len = strlen(buffer);
  for (size_t i = 1, j = len; i < j; ++i, --j) {
    temp = buffer[i - 1];
    buffer[i - 1] = buffer[j - 1];
    buffer[j - 1] = temp;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Itoa>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %rbx
  mov    %rsi,%rbx
  call   <ItoaHelper@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x1,%edx
  cmp    $0x1,%rax
  jbe    L15
  nopl   (%rax)
L17:
  sub    $0x1,%rax
  movzbl -0x1(%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,-0x1(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  cmp    %rdx,%rax
  ja     L17
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Itoa(int n, char *buffer, size_t bufferLen) {
  if (!buffer) {
    return 1;
  }
  ItoaHelper(n, buffer, bufferLen);
  char temp = 0;
  size_t len = strlen(buffer);
  for (size_t i = 1, j = len; i < j; ++i, --j) {
    temp = buffer[i - 1];
    buffer[i - 1] = buffer[j - 1];
    buffer[j - 1] = temp;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L41
L45:
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x24(%rbp)
L41:
  cmpl   $0x3,-0x24(%rbp)
  jle    L45
  movl   $0x3,-0x24(%rbp)
  jmp    L0
L2:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x24(%rbp)
L0:
  cmpl   $0x0,-0x24(%rbp)
  jns    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D14: %d

tool: D8: %d %d


assistant: ```c
int main() {
  int vector[4];
  int j;
  for (j = 0; j < 4; j++) {
    scanf("%d", &vector[j]);
  }
  for (j = 3; j >= 0; j--) {
    printf("%d %d\n", j, vector[j]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r12
  lea    D14(%rip),%rbp
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0x3,%ebx
  lea    D19(%rip),%rbp
L18:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rbx
  jne    L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string

tool: D14: %d

tool: D19: %d %d


assistant: ```c
int main() {
  int vector[4];
  int j;
  for (j = 0; j < 4; j++) {
    scanf("%d", &vector[j]);
  }
  for (j = 3; j >= 0; j--) {
    printf("%d %d\n", j, vector[j]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%r13
  mov    %rbp,%rbx
L10:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L10
  mov    $0x3,%ebx
  lea    D7(%rip),%r12
L1:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  jae    L1
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D6: %d

tool: D7: %d %d


assistant: ```c
int main() {
  int vector[4];
  int j;
  for (j = 0; j < 4; j++) {
    scanf("%d", &vector[j]);
  }
  for (j = 3; j >= 0; j--) {
    printf("%d %d\n", j, vector[j]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%r13
  mov    %rbp,%rbx
L15:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L15
  mov    $0x3,%ebx
  lea    D15(%rip),%r12
L21:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  jae    L21
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string

tool: D0: %d

tool: D15: %d %d


assistant: ```c
int main() {
  int vector[4];
  int j;
  for (j = 0; j < 4; j++) {
    scanf("%d", &vector[j]);
  }
  for (j = 3; j >= 0; j--) {
    printf("%d %d\n", j, vector[j]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<display_commands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x14,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x15,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x16,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x17,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <prt@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D32
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D39
type: string

tool: D11: You may:

tool: D32:  p) Purchase an item.           b) Browse store's inventory.

tool: D6:  s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.

tool: D39: ESC) Exit from Building.        ^R) Redraw the screen.

assistant: ```c
void display_commands() {
  prt("You may:", 20, 0);
  prt(" p) Purchase an item.           b) Browse store's inventory.", 21, 0);
  prt(" s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.", 22, 0);
  prt("ESC) Exit from Building.        ^R) Redraw the screen.", 23, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<display_commands>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x14,%esi
  lea    D16(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x15,%esi
  lea    D24(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x16,%esi
  lea    D23(%rip),%rdi
  call   <prt@plt>
  mov    $0x0,%edx
  mov    $0x17,%esi
  lea    D32(%rip),%rdi
  call   <prt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string

tool: D16: You may:

tool: D24:  p) Purchase an item.           b) Browse store's inventory.

tool: D23:  s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.

tool: D32: ESC) Exit from Building.        ^R) Redraw the screen.

assistant: ```c
void display_commands() {
  prt("You may:", 20, 0);
  prt(" p) Purchase an item.           b) Browse store's inventory.", 21, 0);
  prt(" s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.", 22, 0);
  prt("ESC) Exit from Building.        ^R) Redraw the screen.", 23, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<display_commands>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x14,%esi
  lea    D1(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x15,%esi
  lea    D14(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x16,%esi
  lea    D16(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x17,%esi
  add    $0x8,%rsp
  lea    D6(%rip),%rdi
  jmp    1050 <prt@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string

tool: D1: You may:

tool: D14:  p) Purchase an item.           b) Browse store's inventory.

tool: D16:  s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.

tool: D6: ESC) Exit from Building.        ^R) Redraw the screen.

assistant: ```c
void display_commands() {
  prt("You may:", 20, 0);
  prt(" p) Purchase an item.           b) Browse store's inventory.", 21, 0);
  prt(" s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.", 22, 0);
  prt("ESC) Exit from Building.        ^R) Redraw the screen.", 23, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display_commands>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x14,%esi
  lea    D11(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x15,%esi
  lea    D10(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x16,%esi
  lea    D24(%rip),%rdi
  call   <prt@plt>
  xor    %edx,%edx
  mov    $0x17,%esi
  add    $0x8,%rsp
  lea    D19(%rip),%rdi
  jmp    1050 <prt@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D11: You may:

tool: D10:  p) Purchase an item.           b) Browse store's inventory.

tool: D24:  s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.

tool: D19: ESC) Exit from Building.        ^R) Redraw the screen.

assistant: ```c
void display_commands() {
  prt("You may:", 20, 0);
  prt(" p) Purchase an item.           b) Browse store's inventory.", 21, 0);
  prt(" s) Sell an item.               i/e/t/w/x) Inventory/Equipment Lists.", 22, 0);
  prt("ESC) Exit from Building.        ^R) Redraw the screen.", 23, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x5,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x6,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x7,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xb,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xc,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xd,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xe,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xf,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x11,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x12,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x13,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x14,%edi
  call   <lcm@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: %lld

assistant: ```c
void main() {
  long long value = lcm(20, lcm(19, lcm(18, lcm(17, lcm(16, lcm(15, lcm(14, lcm(13, lcm(12, lcm(11, lcm(10, lcm(9, lcm(8, lcm(7, lcm(6, lcm(5, lcm(4, lcm(3, lcm(2, 1)))))))))))))))))));
  printf("%lld", value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x5,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x6,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x7,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xb,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xc,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xd,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xe,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0xf,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x11,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x12,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x13,%edi
  call   <lcm@plt>
  mov    %eax,%esi
  mov    $0x14,%edi
  call   <lcm@plt>
  movslq %eax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: %lld

assistant: ```c
void main() {
  long long value = lcm(20, lcm(19, lcm(18, lcm(17, lcm(16, lcm(15, lcm(14, lcm(13, lcm(12, lcm(11, lcm(10, lcm(9, lcm(8, lcm(7, lcm(6, lcm(5, lcm(4, lcm(3, lcm(2, 1)))))))))))))))))));
  printf("%lld", value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <lcm@plt>
  mov    $0x3,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x4,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x5,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x6,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x7,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x8,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x9,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xb,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xc,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xd,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xe,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xf,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x10,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x11,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x12,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x13,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x14,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  movslq %eax,%rsi
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: %lld

assistant: ```c
void main() {
  long long value = lcm(20, lcm(19, lcm(18, lcm(17, lcm(16, lcm(15, lcm(14, lcm(13, lcm(12, lcm(11, lcm(10, lcm(9, lcm(8, lcm(7, lcm(6, lcm(5, lcm(4, lcm(3, lcm(2, 1)))))))))))))))))));
  printf("%lld", value);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <lcm@plt>
  mov    $0x3,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x4,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x5,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x6,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x7,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x8,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x9,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xb,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xc,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xd,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xe,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0xf,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x10,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x11,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x12,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x13,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  mov    $0x14,%edi
  mov    %eax,%esi
  call   <lcm@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  movslq %eax,%rsi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %lld

assistant: ```c
void main() {
  long long value = lcm(20, lcm(19, lcm(18, lcm(17, lcm(16, lcm(15, lcm(14, lcm(13, lcm(12, lcm(11, lcm(10, lcm(9, lcm(8, lcm(7, lcm(6, lcm(5, lcm(4, lcm(3, lcm(2, 1)))))))))))))))))));
  printf("%lld", value);
}
```