user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x676e616978696c,%rax
  mov    %rax,0xa(%rsp)
  movw   $0x0,0x12(%rsp)
  movabs $0x676e656e696c,%rcx
  mov    %rcx,0x14(%rsp)
  movw   $0x0,0x1c(%rsp)
  mov    %rax,0x1e(%rsp)
  movw   $0x0,0x26(%rsp)
  mov    $0x1e,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    0xa(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L23
L45:
  lea    0xa(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L19
L46:
  lea    0xa(%rsp),%rsi
  lea    0x1e(%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
  lea    0xa(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdi
  call   <puts@plt>
L39:
  mov    D60(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x1e,%esi
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D60(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x1e,%esi
  lea    D81(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    $0x1e,%edi
  call   <max@plt>
  mov    %eax,%esi
  lea    D88(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movss  D7(%rip),%xmm1
  movss  D79(%rip),%xmm0
  call   <fun@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L23:
  lea    0xa(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rdi
  call   <puts@plt>
  jmp    L45
L19:
  lea    0xa(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rdi
  call   <puts@plt>
  jmp    L46
L0:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L39
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D60
type_guessed: f64
name: unpack_data
arguments: tag: D41
type_guessed: string
name: unpack_data
arguments: tag: D81
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D88
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: f32
name: unpack_data
arguments: tag: D79
type_guessed: byte[4]
name: unpack_data
arguments: tag: D32
type_guessed: string

tool: D6: i	=%d


tool: D13: %s 

tool: D60: 4.5

tool: D41: 
i=%f,m=%d

tool: D81: 
i=%d,m=%f

tool: D30: 
sizeof i=%d,m=%d

tool: D88: 
%d

tool: D7: 5.5

tool: {"D79": [0x00,0x00,0x90,0x40]}

tool: D32: Then are equal.

assistant: ```c
int main(int argc, char **argv) {
  int i = 30, j = -1;
  float m = 4.5, n = 5.5;
  char str1[10] = "lixiang", str2[10] = "lineng", str3[10] = "lixiang";
  if (j) {
    printf("i\t=%d\n", i);
  }
  j = 0;
  if (j) {
    printf("i\t=%d\n", i);
  }
  if (strcmp(str1, str2)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  }
  if (!strcmp(str2, str1)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  }
  if (strcmp(str3, str1)) {
    printf("%s ", str1);
    printf("%s\n", str2);
  } else {
    printf("Then are equal.\n");
  }
  printf("\ni=%f,m=%d", i, m);
  printf("\ni=%d,m=%f", i, m);
  printf("\nsizeof i=%d,m=%d", sizeof(int), sizeof(float));
  printf("\n%d", max(i, j));
  printf("\n%d", fun(m, n));
}
```