ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x17,0x4(%rsp)
  call   <bar@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int test;
  test = 23;
  bar(&test);
  return test;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <st_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_print(const char *str, int fd, int ret) {
  write(fd, str, st_strlen(str));
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  call   <st_strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ft_print(const char *str, int fd, int ret) {
  write(fd, str, st_strlen(str));
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_print>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <st_strlen@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ft_print(const char *str, int fd, int ret) {
  write(fd, str, st_strlen(str));
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_print>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <st_strlen@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ft_print(const char *str, int fd, int ret) {
  write(fd, str, st_strlen(str));
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basic_qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x4,%edx
  mov    $0x0,%eax
  call   <qsort@plt>
  nop
  leave
  ret
```

assistant: ```c
void basic_qsort(table, i, j, compare) int table[];
int i, j;
int (*compare)();
{ qsort(&(table[i]), j - i + 1, sizeof(int), compare); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<basic_qsort>:
  endbr64
  sub    $0x8,%rsp
  sub    %esi,%edx
  lea    0x1(%rdx),%eax
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rdi
  mov    $0x4,%edx
  mov    %eax,%esi
  mov    $0x0,%eax
  call   <qsort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void basic_qsort(table, i, j, compare) int table[];
int i, j;
int (*compare)();
{ qsort(&(table[i]), j - i + 1, sizeof(int), compare); }
```
user: Translate the below assembly code into C programming language:

```asm
<basic_qsort>:
  endbr64
  sub    %esi,%edx
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rsi,4),%rdi
  mov    $0x4,%edx
  mov    %r8d,%esi
  jmp    1050 <qsort@plt>
```

assistant: ```c
void basic_qsort(table, i, j, compare) int table[];
int i, j;
int (*compare)();
{ qsort(&(table[i]), j - i + 1, sizeof(int), compare); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<basic_qsort>:
  endbr64
  sub    %esi,%edx
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rsi,4),%rdi
  mov    $0x4,%edx
  mov    %r8d,%esi
  jmp    1050 <qsort@plt>
```

assistant: ```c
void basic_qsort(table, i, j, compare) int table[];
int i, j;
int (*compare)();
{ qsort(&(table[i]), j - i + 1, sizeof(int), compare); }
```
user: What would the C source look like for the assembly code provided here?

```asm
<qfits_expand_keyword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x78(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L17
L32:
  mov    -0x78(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L68
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <expkey_strupc@plt>
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D70(%rip),%rax
  jmp    L17
L68:
  lea    D72(%rip),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <expkey_strupc@plt>
  mov    %eax,%edx
  lea    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x60(%rbp),%rax
  lea    D37(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x68(%rbp)
  jmp    L46
L25:
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x68(%rbp)
L46:
  cmpq   $0x0,-0x68(%rbp)
  jne    L25
  lea    D70(%rip),%rax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D72
data_type: string
name: retrieve_data
arguments: label: D37
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string

tool: D72: HIERARCH ESO

tool: D37: .

tool: D24:  

assistant: ```c
char *qfits_expand_keyword(const char *keyword) {
  static char expanded[81];
  char ws[81];
  char *token;
  if (keyword == NULL)
    return NULL;
  if (strstr(keyword, ".") == NULL) {
    strcpy(expanded, expkey_strupc(keyword));
    return expanded;
  }
  sprintf(expanded, "HIERARCH ESO");
  strcpy(ws, expkey_strupc(keyword));
  token = strtok(ws, ".");
  while (token != NULL) {
    strcat(expanded, " ");
    strcat(expanded, token);
    token = strtok(NULL, ".");
  }
  return expanded;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<qfits_expand_keyword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  lea    D43(%rip),%rsi
  lea    D72(%rip),%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <expkey_strupc@plt>
  mov    %eax,%esi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D45(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  lea    D72(%rip),%rax
  test   %rbx,%rbx
  je     L22
  lea    D23(%rip),%r13
  mov    %rax,%rbp
  lea    D45(%rip),%r12
L32:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L32
  lea    D72(%rip),%rax
L22:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %rbx,%rdi
  call   <expkey_strupc@plt>
  mov    %eax,%esi
  lea    D72(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  jmp    L22
L0:
  mov    %rdi,%rax
  jmp    L22
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D43
type: string
name: unpack_data
arguments: data_label: D45
type: string
name: unpack_data
arguments: data_label: D23
type: string

tool: D43: HIERARCH ESO

tool: D45: .

tool: D23:  

assistant: ```c
char *qfits_expand_keyword(const char *keyword) {
  static char expanded[81];
  char ws[81];
  char *token;
  if (keyword == NULL)
    return NULL;
  if (strstr(keyword, ".") == NULL) {
    strcpy(expanded, expkey_strupc(keyword));
    return expanded;
  }
  sprintf(expanded, "HIERARCH ESO");
  strcpy(ws, expkey_strupc(keyword));
  token = strtok(ws, ".");
  while (token != NULL) {
    strcat(expanded, " ");
    strcat(expanded, token);
    token = strtok(NULL, ".");
  }
  return expanded;
}
```
user: What is the c source code of the assembly code below:

```asm
<qfits_expand_keyword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L51
  lea    D22(%rip),%rbx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  lea    D18(%rip),%r12
  lea    D29(%rip),%r13
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rbp
  call   <expkey_strupc@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L26
  nopl   0x0(%rax)
L33:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L33
L26:
  lea    D22(%rip),%rax
L62:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %rbp,%rdi
  lea    D22(%rip),%rbx
  call   <expkey_strupc@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbx,%rax
  jmp    L62
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  jmp    L62
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D29
data_type: string

tool: D16: HIERARCH ESO

tool: D18: .

tool: D29:  

assistant: ```c
char *qfits_expand_keyword(const char *keyword) {
  static char expanded[81];
  char ws[81];
  char *token;
  if (keyword == NULL)
    return NULL;
  if (strstr(keyword, ".") == NULL) {
    strcpy(expanded, expkey_strupc(keyword));
    return expanded;
  }
  sprintf(expanded, "HIERARCH ESO");
  strcpy(ws, expkey_strupc(keyword));
  token = strtok(ws, ".");
  while (token != NULL) {
    strcat(expanded, " ");
    strcat(expanded, token);
    token = strtok(NULL, ".");
  }
  return expanded;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qfits_expand_keyword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L50
  lea    D10(%rip),%rbx
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  lea    D29(%rip),%r12
  lea    D11(%rip),%r13
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rbp
  call   <expkey_strupc@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L53
  nopl   0x0(%rax)
L39:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L39
L53:
  lea    D10(%rip),%rax
L65:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %rbp,%rdi
  lea    D10(%rip),%rbx
  call   <expkey_strupc@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %rbx,%rax
  jmp    L65
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  jmp    L65
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D47
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D47: HIERARCH ESO

tool: D29: .

tool: D11:  

assistant: ```c
char *qfits_expand_keyword(const char *keyword) {
  static char expanded[81];
  char ws[81];
  char *token;
  if (keyword == NULL)
    return NULL;
  if (strstr(keyword, ".") == NULL) {
    strcpy(expanded, expkey_strupc(keyword));
    return expanded;
  }
  sprintf(expanded, "HIERARCH ESO");
  strcpy(ws, expkey_strupc(keyword));
  token = strtok(ws, ".");
  while (token != NULL) {
    strcat(expanded, " ");
    strcat(expanded, token);
    token = strtok(NULL, ".");
  }
  return expanded;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parentIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L2
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  shr    %rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t parentIndex(size_t i) {
  if (i % 2)
    ++i;
  return i / 2 - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parentIndex>:
  endbr64
  mov    %rdi,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rdi
  shr    %rdi
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
size_t parentIndex(size_t i) {
  if (i % 2)
    ++i;
  return i / 2 - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parentIndex>:
  endbr64
  mov    %rdi,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rdi
  shr    %rdi
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
size_t parentIndex(size_t i) {
  if (i % 2)
    ++i;
  return i / 2 - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parentIndex>:
  endbr64
  mov    %rdi,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rdi
  shr    %rdi
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
size_t parentIndex(size_t i) {
  if (i % 2)
    ++i;
  return i / 2 - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x10(%rbp)
  movl   $0x1b,-0xc(%rbp)
  movl   $0x63,-0x8(%rbp)
  movl   $0x7,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  uint8_t foo, bar, tor, res;
  foo = 3;
  bar = 27;
  tor = 99;
  res = 3 + 4;
  res = tor * bar;
  res = bar / tor;
  res = bar & foo;
  res = bar % foo;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  uint8_t foo, bar, tor, res;
  foo = 3;
  bar = 27;
  tor = 99;
  res = 3 + 4;
  res = tor * bar;
  res = bar / tor;
  res = bar & foo;
  res = bar % foo;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  uint8_t foo, bar, tor, res;
  foo = 3;
  bar = 27;
  tor = 99;
  res = 3 + 4;
  res = tor * bar;
  res = bar / tor;
  res = bar & foo;
  res = bar % foo;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  uint8_t foo, bar, tor, res;
  foo = 3;
  bar = 27;
  tor = 99;
  res = 3 + 4;
  res = tor * bar;
  res = bar / tor;
  res = bar & foo;
  res = bar % foo;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<esum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L24
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L84
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,D49(%rip)
  movsd  D49(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L20
  mov    D49(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,D81(%rip)
  movsd  D81(%rip),%xmm0
  jmp    L63
L24:
  nop
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,D133(%rip)
  movsd  D133(%rip),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L64
  mov    D133(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,D133(%rip)
  movsd  D133(%rip),%xmm0
  jmp    L63
L84:
  nop
  jmp    L16
L20:
  nop
  jmp    L16
L35:
  nop
  jmp    L16
L64:
  nop
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,D133(%rip)
  mov    D133(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,D133(%rip)
  movsd  D133(%rip),%xmm0
L63:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<esum>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbx
  movq   %rbx,%xmm2
  comisd D13(%rip),%xmm2
  ja     L31
  mov    (%rdi),%eax
  test   %eax,%eax
  js     L27
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm2,%xmm0
  comisd D13(%rip),%xmm0
  jbe    L26
L27:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi),%xmm0
  call   <exp@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  call   <exp@plt>
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
L31:
  mov    (%rdi),%eax
  test   %eax,%eax
  jg     L27
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L27
  call   <exp@plt>
  jmp    L18
L26:
  call   <exp@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: f64

tool: D13: 0

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<esum>:
  endbr64
  movsd  (%rsi),%xmm1
  pxor   %xmm0,%xmm0
  mov    (%rdi),%eax
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm1
  cvtsi2sd %eax,%xmm2
  ja     L7
  test   %eax,%eax
  js     L15
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm0,%xmm3
  jbe    L41
L15:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nop
L7:
  test   %eax,%eax
  jg     L15
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm3,%xmm0
  ja     L15
L41:
  movapd %xmm3,%xmm0
  jmp    1050 <exp@plt>
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<esum>:
  endbr64
  movsd  (%rsi),%xmm1
  pxor   %xmm0,%xmm0
  mov    (%rdi),%eax
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm1
  cvtsi2sd %eax,%xmm2
  ja     L15
  test   %eax,%eax
  js     L43
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm0,%xmm3
  jbe    L2
L43:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nop
L15:
  test   %eax,%eax
  jg     L43
  movapd %xmm1,%xmm3
  addsd  %xmm2,%xmm3
  comisd %xmm3,%xmm0
  ja     L43
L2:
  movapd %xmm3,%xmm0
  jmp    1050 <exp@plt>
```

assistant: ```c
double esum(int *mu, double *x) {
  static double esum, w;
  if (*x > 0.0e0)
    goto S10;
  if (*mu < 0)
    goto S20;
  w = (double)*mu + *x;
  if (w > 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S10:
  if (*mu > 0)
    goto S20;
  w = (double)*mu + *x;
  if (w < 0.0e0)
    goto S20;
  esum = exp(w);
  return esum;
S20:
  w = *mu;
  esum = exp(w) * exp(*x);
  return esum;
}
```
user: What is the c source code of the assembly code below:

```asm
<dfn_rcc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movzbl -0x3(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movb   $0x1,-0x2(%rbp)
  mov    $0x1,%edx
  movzbl -0x3(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %cl,%al
  mov    %dl,%ah
  pop    %rbp
  ret
```

assistant: ```c
_Complex char dfn_rcc(void) {
  return ({
    _Complex char x;
    __real__(x) = (1), __imag__(x) == (2);
    x;
  });
}
```
user: Translate the below assembly code into C programming language:

```asm
<dfn_rcc>:
  endbr64
  mov    $0x1,%al
  mov    $0x0,%ah
  ret
```

assistant: ```c
_Complex char dfn_rcc(void) {
  return ({
    _Complex char x;
    __real__(x) = (1), __imag__(x) == (2);
    x;
  });
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dfn_rcc>:
  endbr64
  mov    $0x1,%al
  mov    $0x0,%ah
  ret
```

assistant: ```c
_Complex char dfn_rcc(void) {
  return ({
    _Complex char x;
    __real__(x) = (1), __imag__(x) == (2);
    x;
  });
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dfn_rcc>:
  endbr64
  mov    $0x1,%al
  mov    $0x0,%ah
  ret
```

assistant: ```c
_Complex char dfn_rcc(void) {
  return ({
    _Complex char x;
    __real__(x) = (1), __imag__(x) == (2);
    x;
  });
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<list_remove_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <list_remove@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  mov    $0x0,%eax
  jmp    L19
L12:
  nop
  mov    $0xffffffff,%eax
L19:
  leave
  ret
```

assistant: ```c
int list_remove_destroy(struct list *list, void *value, int (*cmp)(const void *, const void *), void (*free_func)(void *)) {
  void *result;
  result = list_remove(list, value, cmp);
  if (!(result)) {
    goto error;
  };
  free_func(result);
  return 0;
error:
  return -1;
}
```