user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r15
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%r14
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L74
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L137
  mov    %rax,%r13
  xor    %r12d,%r12d
  nopl   (%rax)
L18:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  add    $0x4,%r13
  cmp    %r12d,%edx
  jg     L18
L137:
  xor    %esi,%esi
  sub    $0x1,%edx
  mov    %rbp,%rdi
  call   <mergesort@plt>
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  jle    L9
  mov    %esi,%edx
  mov    %rbp,%rax
  xor    %r8d,%r8d
  lea    0x0(%rbp,%rdx,4),%rdx
  nopl   0x0(%rax)
L141:
  add    (%rax),%r8d
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L141
L132:
  mov    0x14(%rsp),%ecx
  lea    -0x1(%rsi),%edx
  sub    %ecx,%esi
  test   %ecx,%ecx
  jle    L95
  lea    0x0(%rbp,%rcx,4),%rdi
  mov    %rbp,%rax
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L24:
  add    (%rax),%ecx
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L24
L17:
  movslq %edx,%rax
  xor    %edi,%edi
  lea    0x0(%rbp,%rax,4),%rax
  nopl   (%rax)
L135:
  sub    $0x1,%edx
  add    (%rax),%edi
  sub    $0x4,%rax
  cmp    %esi,%edx
  jge    L135
  mov    %r8d,%eax
  sub    %edi,%r8d
  sub    %ecx,%eax
L159:
  sub    %eax,%ecx
  mov    %ecx,%r9d
  neg    %r9d
  cmovs  %ecx,%r9d
  sub    %r8d,%edi
  mov    %edi,%esi
  neg    %esi
  cmovs  %edi,%esi
  cmp    %esi,%r9d
  jl     L91
  mov    %r9d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L107:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L25
L74:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L156
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L91:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L107
  cs nopw 0x0(%rax,%rax,1)
L95:
  cmp    %esi,%edx
  jge    L112
  mov    %r8d,%eax
  xor    %ecx,%ecx
  xor    %edi,%edi
  jmp    L159
L9:
  xor    %r8d,%r8d
  jmp    L132
L156:
  call   <__stack_chk_fail@plt>
L112:
  xor    %ecx,%ecx
  jmp    L17
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D37
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D8: %d

tool: D37: %d%d

tool: D5: %d


assistant: ```c
int main() {
  int tc = 0;
  scanf("%d", &tc);
  while (tc--) {
    int t = 1;
    int x = 1;
    int i, j, k, l;
    int *n;
    scanf("%d%d", &t, &x);
    n = (int *)malloc(t * sizeof(int));
    for (i = 0; i < t; i++) {
      scanf("%d", n + i);
    }
    mergesort(n, 0, t - 1);
    int sum, sum1, sum2;
    sum = sum1 = sum2 = 0;
    for (i = 0; i < t; i++)
      sum = sum + n[i];
    for (i = 0; i < x; i++)
      sum1 = sum1 + n[i];
    for (i = t - 1; i > t - x - 1; i--)
      sum2 = sum2 + n[i];
    int sum11 = sum - sum1;
    int sum22 = sum - sum2;
    if (abs(sum1 - sum11) >= abs(sum2 - sum22))
      printf("%d\n", abs(sum1 - sum11));
    else
      printf("%d\n", abs(sum2 - sum22));
    free(n);
  }
  return 0;
}
```