ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_optional_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L17
L13:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <trim_whitespace@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5:  	


assistant: ```c
int find_optional_argument(char *line, char **bp, char **ep) {
  *bp = line = strpbrk(line, " \t\r\n");
  if (line == NULL)
    return 0;
  *ep = strchr(*bp, '\0');
  trim_whitespace(bp, ep);
  return *bp != *ep;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_optional_argument>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    D5(%rip),%rsi
  call   <strpbrk@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L5
  mov    $0x0,%esi
  call   <strchr@plt>
  mov    %rax,0x0(%rbp)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <trim_whitespace@plt>
  mov    0x0(%rbp),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5:  	


assistant: ```c
int find_optional_argument(char *line, char **bp, char **ep) {
  *bp = line = strpbrk(line, " \t\r\n");
  if (line == NULL)
    return 0;
  *ep = strchr(*bp, '\0');
  trim_whitespace(bp, ep);
  return *bp != *ep;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_optional_argument>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D1(%rip),%rsi
  sub    $0x8,%rsp
  call   <strpbrk@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  xor    %esi,%esi
  call   <strchr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %rax,0x0(%rbp)
  call   <trim_whitespace@plt>
  mov    0x0(%rbp),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1:  	


assistant: ```c
int find_optional_argument(char *line, char **bp, char **ep) {
  *bp = line = strpbrk(line, " \t\r\n");
  if (line == NULL)
    return 0;
  *ep = strchr(*bp, '\0');
  trim_whitespace(bp, ep);
  return *bp != *ep;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_optional_argument>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  sub    $0x8,%rsp
  call   <strpbrk@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  xor    %esi,%esi
  call   <strchr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %rax,0x0(%rbp)
  call   <trim_whitespace@plt>
  mov    0x0(%rbp),%rax
  cmp    %rax,(%rbx)
  setne  %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9:  	


assistant: ```c
int find_optional_argument(char *line, char **bp, char **ep) {
  *bp = line = strpbrk(line, " \t\r\n");
  if (line == NULL)
    return 0;
  *ep = strchr(*bp, '\0');
  trim_whitespace(bp, ep);
  return *bp != *ep;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  jmp    L11
L12:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r;
  r = a % b;
  while (r != 0) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
  test   %edx,%edx
  je     L5
L22:
  mov    %ecx,%edi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%ecx
  mov    %edi,%esi
  test   %edx,%edx
  jne    L22
L2:
  mov    %edi,%eax
  ret
L5:
  mov    %esi,%edi
  jmp    L2
```

assistant: ```c
int gcd(int a, int b) {
  int r;
  r = a % b;
  while (r != 0) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L6
  nopl   (%rax)
L19:
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  mov    %r8d,%esi
  idiv   %r8d
  test   %edx,%edx
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r;
  r = a % b;
  while (r != 0) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L13
  nopl   (%rax)
L19:
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  mov    %r8d,%esi
  idiv   %r8d
  test   %edx,%edx
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L13:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r;
  r = a % b;
  while (r != 0) {
    a = b;
    b = r;
    r = a % b;
  }
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<timeInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe01fc0c4,%eax
  mov    (%rax),%rdx
  mov    $0xe01fc0c4,%eax
  or     $0x2,%rdx
  mov    %rdx,(%rax)
  mov    $0xe01fc1a8,%eax
  mov    (%rax),%rax
  and    $0xfffffffffffffff3,%rax
  mov    %rax,%rdx
  mov    $0xe01fc1a8,%eax
  or     $0x4,%rdx
  mov    %rdx,(%rax)
  mov    $0xe0004004,%eax
  movq   $0x0,(%rax)
  mov    $0xe000400c,%eax
  movq   $0x2edf,(%rax)
  mov    $0xe0004004,%eax
  movq   $0x2,(%rax)
  mov    $0xe0004004,%eax
  movq   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timeInit() {
  (*(volatile unsigned long *)(0xE01FC000 + 0x0C4)) |= 2;
  (*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) = ((*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) & (~0x0c)) | 0x04;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 0;
  (*(volatile unsigned long *)(0xE0004000 + 0x0C)) = 12000000 / 1000 - 1;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 2;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timeInit>:
  endbr64
  mov    $0xe01fc0c4,%edx
  mov    (%rdx),%rax
  or     $0x2,%rax
  mov    %rax,(%rdx)
  lea    0xe4(%rdx),%rdx
  mov    (%rdx),%rax
  and    $0xfffffffffffffff3,%rax
  or     $0x4,%rax
  mov    %rax,(%rdx)
  mov    $0xe0004004,%eax
  movq   $0x0,(%rax)
  mov    $0xe000400c,%ecx
  movq   $0x2edf,(%rcx)
  movq   $0x2,(%rax)
  movq   $0x1,(%rax)
  ret
```

assistant: ```c
void timeInit() {
  (*(volatile unsigned long *)(0xE01FC000 + 0x0C4)) |= 2;
  (*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) = ((*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) & (~0x0c)) | 0x04;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 0;
  (*(volatile unsigned long *)(0xE0004000 + 0x0C)) = 12000000 / 1000 - 1;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 2;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<timeInit>:
  endbr64
  mov    $0xe01fc0c4,%edx
  mov    $0xe000400c,%ecx
  mov    (%rdx),%rax
  or     $0x2,%rax
  mov    %rax,(%rdx)
  mov    0xe4(%rdx),%rax
  and    $0xfffffffffffffff3,%rax
  or     $0x4,%rax
  mov    %rax,0xe4(%rdx)
  mov    $0xe0004004,%eax
  movq   $0x0,(%rax)
  movq   $0x2edf,(%rcx)
  movq   $0x2,(%rax)
  movq   $0x1,(%rax)
  ret
```

assistant: ```c
void timeInit() {
  (*(volatile unsigned long *)(0xE01FC000 + 0x0C4)) |= 2;
  (*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) = ((*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) & (~0x0c)) | 0x04;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 0;
  (*(volatile unsigned long *)(0xE0004000 + 0x0C)) = 12000000 / 1000 - 1;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 2;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<timeInit>:
  endbr64
  mov    $0xe01fc0c4,%edx
  mov    $0xe000400c,%ecx
  mov    (%rdx),%rax
  or     $0x2,%rax
  mov    %rax,(%rdx)
  mov    0xe4(%rdx),%rax
  and    $0xfffffffffffffff3,%rax
  or     $0x4,%rax
  mov    %rax,0xe4(%rdx)
  mov    $0xe0004004,%eax
  movq   $0x0,(%rax)
  movq   $0x2edf,(%rcx)
  movq   $0x2,(%rax)
  movq   $0x1,(%rax)
  ret
```

assistant: ```c
void timeInit() {
  (*(volatile unsigned long *)(0xE01FC000 + 0x0C4)) |= 2;
  (*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) = ((*(volatile unsigned long *)(0xE01FC000 + 0x1A8)) & (~0x0c)) | 0x04;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 0;
  (*(volatile unsigned long *)(0xE0004000 + 0x0C)) = 12000000 / 1000 - 1;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 2;
  (*(volatile unsigned long *)(0xE0004000 + 0x04)) = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D33
datatype: string
name: parse_data
arguments: label: D52
datatype: string
name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D54
datatype: string
name: parse_data
arguments: label: D14
datatype: string

tool: D33: Enter with two numbers
: 

tool: D52: %d%d

tool: D29: the value of sum  %d


tool: D21: the value of product  %d


tool: D54: the value of difference  %d


tool: D14: the value of rest  %d


assistant: ```c
int main() {
  int num1, num2, sum, product, difference, rest;
  printf("Enter with two numbers\n: ");
  scanf("%d%d", &num1, &num2);
  sum = num1 + num2;
  product = num1 * num2;
  difference = num1 - num2;
  rest = num1 % num2;
  printf("the value of sum  %d\n", sum);
  printf("the value of product  %d\n", product);
  printf("the value of difference  %d\n", difference);
  printf("the value of rest  %d\n", rest);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%ebp
  lea    (%rbx,%rbp,1),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  imul   %ebp,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  sub    %ebp,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %edx,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D51
type: string
name: retrieve_data
arguments: data_tag: D54
type: string
name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D51: Enter with two numbers
: 

tool: D54: %d%d

tool: D2: the value of sum  %d


tool: D36: the value of product  %d


tool: D11: the value of difference  %d


tool: D14: the value of rest  %d


assistant: ```c
int main() {
  int num1, num2, sum, product, difference, rest;
  printf("Enter with two numbers\n: ");
  scanf("%d%d", &num1, &num2);
  sum = num1 + num2;
  product = num1 * num2;
  difference = num1 - num2;
  rest = num1 % num2;
  printf("the value of sum  %d\n", sum);
  printf("the value of product  %d\n", product);
  printf("the value of difference  %d\n", difference);
  printf("the value of rest  %d\n", rest);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%ebp
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  lea    (%rbx,%rbp,1),%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  imul   %ebp,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  sub    %ebp,%esi
  call   <printf@plt>
  mov    %ebx,%eax
  lea    D34(%rip),%rdi
  cltd
  idiv   %ebp
  xor    %eax,%eax
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D42
type_infered: string
name: retrieve_data
arguments: data_tag: D46
type_infered: string
name: retrieve_data
arguments: data_tag: D52
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string

tool: D1: Enter with two numbers
: 

tool: D42: %d%d

tool: D46: the value of sum  %d


tool: D52: the value of product  %d


tool: D41: the value of difference  %d


tool: D34: the value of rest  %d


assistant: ```c
int main() {
  int num1, num2, sum, product, difference, rest;
  printf("Enter with two numbers\n: ");
  scanf("%d%d", &num1, &num2);
  sum = num1 + num2;
  product = num1 * num2;
  difference = num1 - num2;
  rest = num1 % num2;
  printf("the value of sum  %d\n", sum);
  printf("the value of product  %d\n", product);
  printf("the value of difference  %d\n", difference);
  printf("the value of rest  %d\n", rest);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D52(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%ebp
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  lea    (%rbx,%rbp,1),%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  imul   %ebp,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  sub    %ebp,%esi
  call   <printf@plt>
  mov    %ebx,%eax
  lea    D9(%rip),%rdi
  cltd
  idiv   %ebp
  xor    %eax,%eax
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D52
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D47
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D37: Enter with two numbers
: 

tool: D52: %d%d

tool: D29: the value of sum  %d


tool: D24: the value of product  %d


tool: D47: the value of difference  %d


tool: D9: the value of rest  %d


assistant: ```c
int main() {
  int num1, num2, sum, product, difference, rest;
  printf("Enter with two numbers\n: ");
  scanf("%d%d", &num1, &num2);
  sum = num1 + num2;
  product = num1 * num2;
  difference = num1 - num2;
  rest = num1 % num2;
  printf("the value of sum  %d\n", sum);
  printf("the value of product  %d\n", product);
  printf("the value of difference  %d\n", difference);
  printf("the value of rest  %d\n", rest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_getnbr_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L11
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <my_getnbr_base>
  neg    %eax
  jmp    L38
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <whereIsIt@plt>
  imul   -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    -0x8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  mov    -0xc(%rbp),%eax
L38:
  leave
  ret
```

assistant: ```c
int my_getnbr_base(char *str, char *base) {
  int number;
  int object;
  int i;
  number = 0;
  object = 1;
  if (str[0] == '-')
    return (-my_getnbr_base(&str[1], base));
  for (i = my_strlen(str) - 1; i >= 0; i--) {
    number = number + whereIsIt(str[i], base) * object;
    object *= my_strlen(base);
  }
  return (number);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_getnbr_base>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  cmpb   $0x2d,(%rdi)
  je     L30
  call   <my_strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L38
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rdx,1),%r14
  lea    -0x1(%rax),%eax
  sub    %rax,%r14
  mov    $0x1,%ebp
  mov    $0x0,%r13d
L14:
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <whereIsIt@plt>
  imul   %ebp,%eax
  add    %eax,%r13d
  mov    %r12,%rdi
  call   <my_strlen@plt>
  imul   %eax,%ebp
  sub    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L14
L49:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  lea    0x1(%rdi),%rdi
  call   <my_getnbr_base>
  neg    %eax
  mov    %eax,%r13d
  jmp    L49
L38:
  mov    $0x0,%r13d
  jmp    L49
```

assistant: ```c
int my_getnbr_base(char *str, char *base) {
  int number;
  int object;
  int i;
  number = 0;
  object = 1;
  if (str[0] == '-')
    return (-my_getnbr_base(&str[1], base));
  for (i = my_strlen(str) - 1; i >= 0; i--) {
    number = number + whereIsIt(str[i], base) * object;
    object *= my_strlen(base);
  }
  return (number);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_getnbr_base>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x2d,(%rdi)
  jne    L32
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rbp
  neg    %r14d
  cmpb   $0x2d,0x0(%rbp)
  je     L35
L32:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L30
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  xor    %r12d,%r12d
  lea    -0x2(%rbp,%rax,1),%r15
  add    %rbp,%rbx
  mov    $0x1,%ebp
  sub    %rdx,%r15
  xchg   %ax,%ax
L8:
  movsbl (%rbx),%edi
  mov    %r13,%rsi
  sub    $0x1,%rbx
  call   <whereIsIt@plt>
  mov    %r13,%rdi
  imul   %ebp,%eax
  add    %eax,%r12d
  call   <my_strlen@plt>
  imul   %eax,%ebp
  cmp    %r15,%rbx
  jne    L8
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  imul   %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int my_getnbr_base(char *str, char *base) {
  int number;
  int object;
  int i;
  number = 0;
  object = 1;
  if (str[0] == '-')
    return (-my_getnbr_base(&str[1], base));
  for (i = my_strlen(str) - 1; i >= 0; i--) {
    number = number + whereIsIt(str[i], base) * object;
    object *= my_strlen(base);
  }
  return (number);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_getnbr_base>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x2d,(%rdi)
  jne    L20
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rbp
  neg    %r14d
  cmpb   $0x2d,0x0(%rbp)
  je     L3
L20:
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L15
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  xor    %r12d,%r12d
  lea    -0x2(%rbp,%rax,1),%r15
  add    %rbp,%rbx
  mov    $0x1,%ebp
  sub    %rdx,%r15
  xchg   %ax,%ax
L34:
  movsbl (%rbx),%edi
  mov    %r13,%rsi
  sub    $0x1,%rbx
  call   <whereIsIt@plt>
  mov    %r13,%rdi
  imul   %ebp,%eax
  add    %eax,%r12d
  call   <my_strlen@plt>
  imul   %eax,%ebp
  cmp    %r15,%rbx
  jne    L34
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  imul   %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int my_getnbr_base(char *str, char *base) {
  int number;
  int object;
  int i;
  number = 0;
  object = 1;
  if (str[0] == '-')
    return (-my_getnbr_base(&str[1], base));
  for (i = my_strlen(str) - 1; i >= 0; i--) {
    number = number + whereIsIt(str[i], base) * object;
    object *= my_strlen(base);
  }
  return (number);
}
```