ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pathconN_nm5_name_out>:
  endbr64
  lea    D10(%rip),%rax
  test   %edi,%edi
  je     L9
  cmp    $0x1,%edi
  lea    D18(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L9:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string

tool: D10: o0

tool: D18: o1

assistant: ```c
const char *pathconN_nm5_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <euklides@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D49
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D49: Wpisz pierwsza liczbe: 

tool: D8: %d

tool: D19: Wpisz druga liczbe: 

tool: D13: Ich najwiekszy wspolny dzielnik to: %d


assistant: ```c
main() {
  int a, b;
  printf("Wpisz pierwsza liczbe: ");
  scanf("%d", &a);
  printf("Wpisz druga liczbe: ");
  scanf("%d", &b);
  printf("Ich najwiekszy wspolny dzielnik to: %d\n", euklides(a, b));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D33(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <euklides@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string

tool: D31: Wpisz pierwsza liczbe: 

tool: D33: %d

tool: D26: Wpisz druga liczbe: 

tool: D24: Ich najwiekszy wspolny dzielnik to: %d


assistant: ```c
main() {
  int a, b;
  printf("Wpisz pierwsza liczbe: ");
  scanf("%d", &a);
  printf("Wpisz druga liczbe: ");
  scanf("%d", &b);
  printf("Ich najwiekszy wspolny dzielnik to: %d\n", euklides(a, b));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  lea    D36(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <euklides@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string

tool: D3: Wpisz pierwsza liczbe: 

tool: D36: %d

tool: D7: Wpisz druga liczbe: 

tool: D5: Ich najwiekszy wspolny dzielnik to: %d


assistant: ```c
main() {
  int a, b;
  printf("Wpisz pierwsza liczbe: ");
  scanf("%d", &a);
  printf("Wpisz druga liczbe: ");
  scanf("%d", &b);
  printf("Ich najwiekszy wspolny dzielnik to: %d\n", euklides(a, b));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  lea    D13(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <euklides@plt>
  lea    D26(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D30
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string

tool: D30: Wpisz pierwsza liczbe: 

tool: D13: %d

tool: D21: Wpisz druga liczbe: 

tool: D26: Ich najwiekszy wspolny dzielnik to: %d


assistant: ```c
main() {
  int a, b;
  printf("Wpisz pierwsza liczbe: ");
  scanf("%d", &a);
  printf("Wpisz druga liczbe: ");
  scanf("%d", &b);
  printf("Ich najwiekszy wspolny dzielnik to: %d\n", euklides(a, b));
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L22
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L22:
  addq   $0x8,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L31
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L31:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  add    $0x4,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L13
L38:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L38
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string

tool: D1: Error(matrix): allocation failure


assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc(((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("Error(matrix): allocation failure\n");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc(((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("Error(matrix): allocation failure\n");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L55
L46:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x4(,%r14,4),%rdi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L39
L21:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x2,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L38
  shl    $0x2,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L37:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L37
L38:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  lea    D13(%rip),%rdi
  call   <nrerror@plt>
  jmp    L46
L39:
  lea    D13(%rip),%rdi
  call   <nrerror@plt>
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_infered: string

tool: D13: Error(matrix): allocation failure


assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc(((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("Error(matrix): allocation failure\n");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc(((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("Error(matrix): allocation failure\n");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L32:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L44
L34:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L51
  lea    0x0(,%rbp,4),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L0
L51:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  jmp    L32
  nopl   0x0(%rax)
L44:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_label: D11
datatype: string

tool: D11: Error(matrix): allocation failure


assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc(((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("Error(matrix): allocation failure\n");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc(((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("Error(matrix): allocation failure\n");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%rdi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L59
L16:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x4(,%r15,4),%rdi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L14
L44:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L29
  lea    0x0(,%rbx,4),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
L51:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L51
L29:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
  jmp    L16
  nopl   0x0(%rax)
L14:
  lea    D5(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: Error(matrix): allocation failure


assistant: ```c
float **matrix(long nrl, long nrh, long ncl, long nch) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc(((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("Error(matrix): allocation failure\n");
  m += 1;
  m -= nrl;
  m[nrl] = (float *)malloc(((nrow * ncol + 1) * sizeof(float)));
  if (!m[nrl])
    nrerror("Error(matrix): allocation failure\n");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<numberOfConnectedIslands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L53
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L67
L53:
  mov    $0x0,%eax
L67:
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L36
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L38
L36:
  mov    $0x0,%eax
L38:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L17
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L72
L17:
  mov    $0x0,%eax
L72:
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L34
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L10
L34:
  mov    $0x0,%eax
L10:
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int numberOfConnectedIslands(int **grid, int gridRowSize, int gridColSize, int i, int j) {
  int up = (i - 1) < 0 ? 0 : grid[i - 1][j];
  int down = (i + 1) >= gridRowSize ? 0 : grid[i + 1][j];
  int left = (j - 1) < 0 ? 0 : grid[i][j - 1];
  int right = (j + 1) >= gridColSize ? 0 : grid[i][j + 1];
  return up + down + left + right;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numberOfConnectedIslands>:
  endbr64
  mov    %esi,%r9d
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    $0x0,%eax
  test   %ecx,%ecx
  jle    L1
  movslq %ecx,%rcx
  movslq %r8d,%rax
  mov    -0x8(%rdi,%rcx,8),%rcx
  mov    (%rcx,%rax,4),%eax
L1:
  lea    0x1(%rdx),%ecx
  mov    $0x0,%r10d
  cmp    %r9d,%ecx
  jge    L24
  movslq %edx,%r9
  movslq %r8d,%rcx
  mov    0x8(%rdi,%r9,8),%r9
  mov    (%r9,%rcx,4),%r10d
L24:
  mov    $0x0,%ecx
  test   %r8d,%r8d
  jle    L32
  movslq %edx,%r9
  movslq %r8d,%rcx
  mov    (%rdi,%r9,8),%r9
  mov    -0x4(%r9,%rcx,4),%ecx
L32:
  lea    0x1(%r8),%r11d
  mov    $0x0,%r9d
  cmp    %esi,%r11d
  jge    L17
  movslq %edx,%rdx
  movslq %r8d,%r8
  mov    (%rdi,%rdx,8),%rdx
  mov    0x4(%rdx,%r8,4),%r9d
L17:
  add    %r10d,%eax
  add    %ecx,%eax
  add    %r9d,%eax
  ret
```

assistant: ```c
int numberOfConnectedIslands(int **grid, int gridRowSize, int gridColSize, int i, int j) {
  int up = (i - 1) < 0 ? 0 : grid[i - 1][j];
  int down = (i + 1) >= gridRowSize ? 0 : grid[i + 1][j];
  int left = (j - 1) < 0 ? 0 : grid[i][j - 1];
  int right = (j + 1) >= gridColSize ? 0 : grid[i][j + 1];
  return up + down + left + right;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numberOfConnectedIslands>:
  endbr64
  movslq %ecx,%rax
  xor    %r9d,%r9d
  test   %eax,%eax
  jle    L15
  movslq %eax,%r9
  movslq %r8d,%rcx
  mov    -0x8(%rdi,%r9,8),%r9
  mov    (%r9,%rcx,4),%r9d
L15:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jge    L36
  movslq %eax,%rsi
  movslq %r8d,%rcx
  mov    0x8(%rdi,%rsi,8),%rsi
  add    (%rsi,%rcx,4),%r9d
L36:
  test   %r8d,%r8d
  jle    L10
  movslq %eax,%rsi
  movslq %r8d,%rcx
  mov    (%rdi,%rsi,8),%rsi
  add    -0x4(%rsi,%rcx,4),%r9d
L10:
  lea    0x1(%r8),%ecx
  cmp    %edx,%ecx
  jge    L29
  mov    (%rdi,%rax,8),%rax
  movslq %r8d,%r8
  add    0x4(%rax,%r8,4),%r9d
L29:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int numberOfConnectedIslands(int **grid, int gridRowSize, int gridColSize, int i, int j) {
  int up = (i - 1) < 0 ? 0 : grid[i - 1][j];
  int down = (i + 1) >= gridRowSize ? 0 : grid[i + 1][j];
  int left = (j - 1) < 0 ? 0 : grid[i][j - 1];
  int right = (j + 1) >= gridColSize ? 0 : grid[i][j + 1];
  return up + down + left + right;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numberOfConnectedIslands>:
  endbr64
  movslq %ecx,%rax
  xor    %r9d,%r9d
  test   %eax,%eax
  jle    L31
  movslq %eax,%r9
  movslq %r8d,%rcx
  mov    -0x8(%rdi,%r9,8),%r9
  mov    (%r9,%rcx,4),%r9d
L31:
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jge    L29
  movslq %eax,%rsi
  movslq %r8d,%rcx
  mov    0x8(%rdi,%rsi,8),%rsi
  add    (%rsi,%rcx,4),%r9d
L29:
  test   %r8d,%r8d
  jle    L9
  movslq %eax,%rsi
  movslq %r8d,%rcx
  mov    (%rdi,%rsi,8),%rsi
  add    -0x4(%rsi,%rcx,4),%r9d
L9:
  lea    0x1(%r8),%ecx
  cmp    %edx,%ecx
  jge    L37
  mov    (%rdi,%rax,8),%rax
  movslq %r8d,%r8
  add    0x4(%rax,%r8,4),%r9d
L37:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int numberOfConnectedIslands(int **grid, int gridRowSize, int gridColSize, int i, int j) {
  int up = (i - 1) < 0 ? 0 : grid[i - 1][j];
  int down = (i + 1) >= gridRowSize ? 0 : grid[i + 1][j];
  int left = (j - 1) < 0 ? 0 : grid[i][j - 1];
  int right = (j + 1) >= gridColSize ? 0 : grid[i][j + 1];
  return up + down + left + right;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x141,%edi
  call   <chega_cliente@plt>
  mov    $0x0,%eax
  call   <cliente@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <chega_cliente@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x4,-0x4(%rbp)
  jle    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  chega_cliente(321);
  cliente();
  for (int i = 0; i < 5; i++) {
    chega_cliente(i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x141,%edi
  call   <chega_cliente@plt>
  mov    $0x0,%eax
  call   <cliente@plt>
  mov    $0x0,%edi
  call   <chega_cliente@plt>
  mov    $0x1,%edi
  call   <chega_cliente@plt>
  mov    $0x2,%edi
  call   <chega_cliente@plt>
  mov    $0x3,%edi
  call   <chega_cliente@plt>
  mov    $0x4,%edi
  call   <chega_cliente@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  chega_cliente(321);
  cliente();
  for (int i = 0; i < 5; i++) {
    chega_cliente(i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x141,%edi
  call   <chega_cliente@plt>
  xor    %eax,%eax
  call   <cliente@plt>
  xor    %edi,%edi
  call   <chega_cliente@plt>
  mov    $0x1,%edi
  call   <chega_cliente@plt>
  mov    $0x2,%edi
  call   <chega_cliente@plt>
  mov    $0x3,%edi
  call   <chega_cliente@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <chega_cliente@plt>
```

assistant: ```c
void main(void) {
  chega_cliente(321);
  cliente();
  for (int i = 0; i < 5; i++) {
    chega_cliente(i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x141,%edi
  call   <chega_cliente@plt>
  xor    %eax,%eax
  call   <cliente@plt>
  xor    %edi,%edi
  call   <chega_cliente@plt>
  mov    $0x1,%edi
  call   <chega_cliente@plt>
  mov    $0x2,%edi
  call   <chega_cliente@plt>
  mov    $0x3,%edi
  call   <chega_cliente@plt>
  mov    $0x4,%edi
  add    $0x8,%rsp
  jmp    1070 <chega_cliente@plt>
```

assistant: ```c
void main(void) {
  chega_cliente(321);
  cliente();
  for (int i = 0; i < 5; i++) {
    chega_cliente(i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<updateSummaryInterval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xea60,%edx
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <isNumericOk@plt>
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <setConfigTextValue@plt>
  mov    $0x1,%eax
  jmp    L7
L8:
  mov    $0x0,%eax
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: web.summary_interval

assistant: ```c
int updateSummaryInterval(char *value) {
  if (isNumericOk(value, 1000, 60000)) {
    setConfigTextValue("web.summary_interval", value);
    return 1;
  } else {
    return 0;
  }
}
```