ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movw   $0x1,-0x12(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzwl -0x12(%rbp),%ecx
  movswl %cx,%eax
  imul   $0x6667,%eax,%eax
  shr    $0x10,%eax
  sar    $0x2,%ax
  mov    %ecx,%esi
  sar    $0xf,%si
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %dx,%dx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
L29:
  movzwl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x12(%rbp)
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: %x 

assistant: ```c
void print_buffer(unsigned char *buf, unsigned size) {
  short step = 1;
  unsigned char *i = buf;
  unsigned char *end = buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  add    %rdi,%r12
  cmp    %r12,%rdi
  jae    L15
  mov    %rdi,%rbp
  movzbl (%rdi),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  mov    $0x2,%r13d
  sub    %ebp,%r13d
  lea    D3(%rip),%r14
L13:
  lea    0x0(%r13,%rbx,1),%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L15
  movzbl (%rbx),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movswl %bp,%eax
  imul   $0x6667,%eax,%eax
  sar    $0x12,%eax
  mov    %ebp,%edx
  sar    $0xf,%dx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %ax,%bp
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L13
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: %x 

assistant: ```c
void print_buffer(unsigned char *buf, unsigned size) {
  short step = 1;
  unsigned char *i = buf;
  unsigned char *end = buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  add    %rdi,%rbp
  push   %rbx
  cmp    %rbp,%rdi
  jae    L25
  movzbl (%rdi),%esi
  lea    D8(%rip),%r13
  mov    %rdi,%r14
  xor    %eax,%eax
  mov    %r13,%rdi
  mov    $0x2,%r12d
  call   <printf@plt>
  sub    %r14d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L36:
  lea    (%r12,%r14,1),%ebx
  add    $0x1,%r14
  cmp    %r14,%rbp
  je     L25
L5:
  imul   $0xcccd,%bx,%bx
  movzbl (%r14),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1998,%bx
  ror    %bx
  cmp    $0x1998,%bx
  ja     L36
  mov    $0xa,%edi
  lea    (%r12,%r14,1),%ebx
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L5
L25:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: %x 

assistant: ```c
void print_buffer(unsigned char *buf, unsigned size) {
  short step = 1;
  unsigned char *i = buf;
  unsigned char *end = buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  add    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  jae    L29
  movzbl (%rdi),%esi
  mov    %rdi,%r13
  lea    D4(%rip),%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  add    $0x1,%r13
  mov    $0x2,%ebp
  call   <printf@plt>
  sub    %r13d,%ebp
  cmp    %rbx,%r13
  jae    L29
L24:
  movzbl 0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x0(%rbp,%r13,1),%eax
  imul   $0xcccd,%ax,%ax
  add    $0x1998,%ax
  ror    %ax
  cmp    $0x1998,%ax
  ja     L2
  mov    $0xa,%edi
  call   <putchar@plt>
L2:
  add    $0x1,%r13
  cmp    %r13,%rbx
  jne    L24
L29:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: %x 

assistant: ```c
void print_buffer(unsigned char *buf, unsigned size) {
  short step = 1;
  unsigned char *i = buf;
  unsigned char *end = buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_options>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    (%rdi),%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x1,%r15d
  jmp    L56
L64:
  movsbl (%r12,%rbx,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L45
  cmpb   $0x22,(%r12,%rbx,1)
  je     L82
  movb   $0x20,0x0(%rbp)
  movb   $0x22,0x1(%rbp)
  lea    0x2(%rbp),%rbp
L2:
  movsbl (%r12,%rbx,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L7
  movzbl (%r12,%rbx,1),%eax
  cmp    $0x22,%al
  je     L11
  mov    %r15d,%r13d
L93:
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
L45:
  add    $0x1,%rbx
L56:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L32
  test   %r13d,%r13d
  je     L64
  cmp    $0x1,%r13d
  je     L2
  movzbl (%r12,%rbx,1),%eax
  cmp    $0x22,%al
  jne    L93
  movb   $0x22,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  mov    $0x0,%r13d
  jmp    L45
L82:
  movb   $0x20,0x0(%rbp)
  movb   $0x22,0x1(%rbp)
  lea    0x2(%rbp),%rbp
  mov    $0x2,%r13d
  jmp    L45
L7:
  movb   $0x22,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  mov    $0x0,%r13d
  jmp    L45
L32:
  test   %r13d,%r13d
  je     L106
  movb   $0x22,0x0(%rbp)
  lea    0x1(%rbp),%rbp
L106:
  mov    %rbp,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  movb   $0x22,0x0(%rbp)
  movb   $0x20,0x1(%rbp)
  movb   $0x22,0x2(%rbp)
  lea    0x3(%rbp),%rbp
  mov    $0x2,%r13d
  jmp    L45
```

assistant: ```c
void copy_options(char **dst, char *src) {
  int i = -1;
  int j = 0;
  char *s = *dst;
  while (++i < (int)strlen(src)) {
    if (!j) {
      if (isblank(src[i]))
        continue;
      if (src[i] == '"') {
        j = 2;
        *s++ = ' ';
        *s++ = '"';
        continue;
      }
      *s++ = ' ';
      *s++ = '"';
      j = 1;
    }
    if (j == 1 && isblank(src[i])) {
      *s++ = '"';
      j = 0;
      continue;
    }
    if (src[i] == '"') {
      *s++ = '"';
      if (j == 1) {
        *s++ = ' ';
        *s++ = '"';
        j = 2;
      } else
        j = 0;
      continue;
    }
    *s++ = src[i];
  }
  if (j)
    *s++ = '"';
  *dst = s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_options>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    (%rdi),%rbp
  jmp    L56
  nopl   0x0(%rax)
L18:
  cmp    $0x1,%r12d
  je     L14
  mov    $0x2,%r12d
  cmp    $0x22,%dil
  je     L103
L29:
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L41:
  add    $0x1,%rbx
L56:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L78
  movsbl (%r14,%rbx,1),%edi
  test   %r12d,%r12d
  jne    L18
  call   <isblank@plt>
  test   %rax,%rax
  jne    L41
  lea    0x2(%rbp),%rax
  cmpb   $0x22,(%r14,%rbx,1)
  mov    $0x2220,%edx
  mov    %dx,0x0(%rbp)
  mov    %rax,%rbp
  je     L15
L14:
  movsbl (%r14,%rbx,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L103
  movzbl (%r14,%rbx,1),%edi
  mov    $0x1,%r12d
  cmp    $0x22,%dil
  jne    L29
  mov    $0x2022,%eax
  movb   $0x22,0x2(%rbp)
  add    $0x3,%rbp
  mov    %ax,-0x3(%rbp)
L15:
  mov    $0x2,%r12d
  jmp    L41
  xchg   %ax,%ax
L103:
  movb   $0x22,0x0(%rbp)
  xor    %r12d,%r12d
  add    $0x1,%rbp
  jmp    L41
L78:
  test   %r12d,%r12d
  je     L59
  movb   $0x22,0x0(%rbp)
  add    $0x1,%rbp
L59:
  pop    %rbx
  mov    %rbp,0x0(%r13)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void copy_options(char **dst, char *src) {
  int i = -1;
  int j = 0;
  char *s = *dst;
  while (++i < (int)strlen(src)) {
    if (!j) {
      if (isblank(src[i]))
        continue;
      if (src[i] == '"') {
        j = 2;
        *s++ = ' ';
        *s++ = '"';
        continue;
      }
      *s++ = ' ';
      *s++ = '"';
      j = 1;
    }
    if (j == 1 && isblank(src[i])) {
      *s++ = '"';
      j = 0;
      continue;
    }
    if (src[i] == '"') {
      *s++ = '"';
      if (j == 1) {
        *s++ = ' ';
        *s++ = '"';
        j = 2;
      } else
        j = 0;
      continue;
    }
    *s++ = src[i];
  }
  if (j)
    *s++ = '"';
  *dst = s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copy_options>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    (%rdi),%rbp
  jmp    L22
  nopl   0x0(%rax)
L79:
  cmp    $0x1,%r12d
  je     L86
  mov    $0x2,%r12d
  cmp    $0x22,%dil
  je     L75
L21:
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
L26:
  add    $0x1,%rbx
L22:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L106
  movsbl (%r14,%rbx,1),%edi
  test   %r12d,%r12d
  jne    L79
  call   <isblank@plt>
  test   %rax,%rax
  jne    L26
  lea    0x2(%rbp),%rax
  cmpb   $0x22,(%r14,%rbx,1)
  mov    $0x2220,%edx
  mov    %dx,0x0(%rbp)
  mov    %rax,%rbp
  je     L84
L86:
  movsbl (%r14,%rbx,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L75
  movzbl (%r14,%rbx,1),%edi
  mov    $0x1,%r12d
  cmp    $0x22,%dil
  jne    L21
  mov    $0x2022,%eax
  movb   $0x22,0x2(%rbp)
  add    $0x3,%rbp
  mov    %ax,-0x3(%rbp)
L84:
  mov    $0x2,%r12d
  jmp    L26
  xchg   %ax,%ax
L75:
  movb   $0x22,0x0(%rbp)
  xor    %r12d,%r12d
  add    $0x1,%rbp
  jmp    L26
L106:
  test   %r12d,%r12d
  je     L65
  movb   $0x22,0x0(%rbp)
  add    $0x1,%rbp
L65:
  pop    %rbx
  mov    %rbp,0x0(%r13)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void copy_options(char **dst, char *src) {
  int i = -1;
  int j = 0;
  char *s = *dst;
  while (++i < (int)strlen(src)) {
    if (!j) {
      if (isblank(src[i]))
        continue;
      if (src[i] == '"') {
        j = 2;
        *s++ = ' ';
        *s++ = '"';
        continue;
      }
      *s++ = ' ';
      *s++ = '"';
      j = 1;
    }
    if (j == 1 && isblank(src[i])) {
      *s++ = '"';
      j = 0;
      continue;
    }
    if (src[i] == '"') {
      *s++ = '"';
      if (j == 1) {
        *s++ = ' ';
        *s++ = '"';
        j = 2;
      } else
        j = 0;
      continue;
    }
    *s++ = src[i];
  }
  if (j)
    *s++ = '"';
  *dst = s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rsi
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <syscall@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct perf_event_attr attr = {
      .use_clockid = 1,
      .clockid = CLOCK_MONOTONIC,
  };
  syscall(SYS_perf_event_open, &attr, 0, -1, -1, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct perf_event_attr attr = {
      .use_clockid = 1,
      .clockid = CLOCK_MONOTONIC,
  };
  syscall(SYS_perf_event_open, &attr, 0, -1, -1, 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %edx,%edx
  mov    $0xffffffff,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rsi
  mov    $0xffffffff,%ecx
  movl   $0x1,(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct perf_event_attr attr = {
      .use_clockid = 1,
      .clockid = CLOCK_MONOTONIC,
  };
  syscall(SYS_perf_event_open, &attr, 0, -1, -1, 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %edx,%edx
  mov    $0xffffffff,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D13(%rip),%rax
  mov    %rsp,%rsi
  mov    $0xffffffff,%ecx
  movl   $0x1,(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct perf_event_attr attr = {
      .use_clockid = 1,
      .clockid = CLOCK_MONOTONIC,
  };
  syscall(SYS_perf_event_open, &attr, 0, -1, -1, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdi,%rax
  mov    %rdx,%r8
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    %rsp,%rdx
  lea    0x20(%rsp),%rcx
L77:
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L77
  mov    $0x1,%r9d
L106:
  movzbl (%rsi),%edi
  mov    %edi,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  mov    %edi,%ecx
  and    $0x7,%ecx
  mov    %r9d,%r10d
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  add    $0x1,%rsi
  test   %dil,%dil
  jne    L106
  test   %rax,%rax
  je     L31
L49:
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  movsbl (%rsp,%rdx,1),%esi
  mov    %ecx,%edx
  and    $0x7,%edx
  bt     %edx,%esi
  jae    L136
  test   %cl,%cl
  je     L136
L118:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  sar    $0x3,%dl
  movsbq %dl,%rdx
  movsbl (%rsp,%rdx,1),%esi
  mov    %ecx,%edx
  and    $0x7,%edx
  bt     %edx,%esi
  jae    L136
  test   %cl,%cl
  jne    L118
L136:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L72
  mov    %rax,%rsi
L107:
  mov    %edx,%ecx
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
  and    $0x7,%edx
  bt     %edx,%ecx
  jb     L139
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L107
  jmp    L25
L31:
  mov    (%r8),%rax
  jmp    L49
L139:
  movb   $0x0,(%rsi)
  lea    0x1(%rsi),%rsi
L25:
  cmp    %rax,%rsi
  mov    $0x0,%edx
  cmove  %rdx,%rax
L40:
  mov    %rsi,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x38,%rsp
  ret
L72:
  mov    %rax,%rsi
  mov    $0x0,%eax
  jmp    L40
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string)
    str = string;
  else
    str = *lasts;
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str)
    return NULL;
  else
    return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  mov    %rdx,%r8
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    $0x1,%r9d
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L11:
  movzbl (%rsi),%edi
  mov    %r9d,%r10d
  add    $0x1,%rsi
  mov    %edi,%edx
  mov    %edi,%ecx
  sar    $0x3,%dl
  and    $0x7,%ecx
  movsbq %dl,%rdx
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  test   %dil,%dil
  jne    L11
  test   %rax,%rax
  jne    L116
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L97:
  test   %dl,%dl
  je     L66
  add    $0x1,%rax
L116:
  movzbl (%rax),%edx
  mov    %edx,%ecx
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%esi
  mov    %edx,%ecx
  and    $0x7,%ecx
  bt     %ecx,%esi
  jb     L97
  test   %dl,%dl
  je     L66
  mov    %rax,%rcx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L40:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L41
L12:
  mov    %edx,%esi
  and    $0x7,%edx
  mov    %rcx,%rdi
  add    $0x1,%rcx
  sar    $0x3,%sil
  movsbq %sil,%rsi
  movsbl (%rsp,%rsi,1),%esi
  bt     %edx,%esi
  jae    L40
  movb   $0x0,(%rdi)
L41:
  xor    %edx,%edx
  cmp    %rcx,%rax
  cmove  %rdx,%rax
L51:
  mov    %rcx,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x38,%rsp
  ret
L69:
  mov    (%r8),%rax
  jmp    L116
  nopl   (%rax)
L66:
  mov    %rax,%rcx
  xor    %eax,%eax
  jmp    L51
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string)
    str = string;
  else
    str = *lasts;
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str)
    return NULL;
  else
    return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtok_r>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  mov    %rdx,%r8
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    $0x1,%r9d
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L60:
  movzbl (%rsi),%edi
  mov    %r9d,%r10d
  add    $0x1,%rsi
  mov    %edi,%edx
  mov    %edi,%ecx
  sar    $0x3,%dl
  and    $0x7,%ecx
  movsbq %dl,%rdx
  shl    %cl,%r10d
  or     %r10b,(%rsp,%rdx,1)
  test   %dil,%dil
  jne    L60
  test   %rax,%rax
  jne    L17
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L72:
  test   %dl,%dl
  je     L81
  add    $0x1,%rax
L17:
  movzbl (%rax),%edx
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x3,%cl
  and    $0x7,%esi
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
  bt     %esi,%ecx
  jb     L72
  test   %dl,%dl
  je     L81
  mov    %rax,%rsi
  jmp    L104
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl 0x1(%rsi),%edx
  test   %dl,%dl
  je     L20
  mov    %edx,%ecx
  mov    %rdi,%rsi
  sar    $0x3,%cl
  movsbq %cl,%rcx
  movsbl (%rsp,%rcx,1),%ecx
L104:
  and    $0x7,%edx
  lea    0x1(%rsi),%rdi
  bt     %edx,%ecx
  jae    L37
  movb   $0x0,(%rsi)
L20:
  xor    %edx,%edx
  cmp    %rdi,%rax
  cmove  %rdx,%rax
L107:
  mov    %rdi,(%r8)
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x38,%rsp
  ret
L6:
  mov    (%r8),%rax
  jmp    L17
  nopl   (%rax)
L81:
  mov    %rax,%rdi
  xor    %eax,%eax
  jmp    L107
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *strtok_r(char *string, const char *control, char **lasts) {
  char *str;
  const char *ctrl = control;
  char map[32];
  int n;
  for (n = 0; n < 32; n++)
    map[n] = 0;
  do {
    map[*ctrl >> 3] |= (1 << (*ctrl & 7));
  } while (*ctrl++);
  if (string)
    str = string;
  else
    str = *lasts;
  while ((map[*str >> 3] & (1 << (*str & 7))) && *str)
    str++;
  string = str;
  for (; *str; str++) {
    if (map[*str >> 3] & (1 << (*str & 7))) {
      *str++ = '\0';
      break;
    }
  }
  *lasts = str;
  if (string == (char *)str)
    return NULL;
  else
    return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<join_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: /

assistant: ```c
char *join_path(char *part1, char *part2) {
  char *path = malloc(strlen(part1) + strlen(part2) + 3);
  strcpy(path, part1);
  strcat(path, "/");
  strcat(path, part2);
  return path;
}
```
user: Translate the below assembly code into C programming language:

```asm
<join_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x3(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: /

assistant: ```c
char *join_path(char *part1, char *part2) {
  char *path = malloc(strlen(part1) + strlen(part2) + 3);
  strcpy(path, part1);
  strcat(path, "/");
  strcat(path, part2);
  return path;
}
```
user: What is the c source code of the assembly code below?

```asm
<join_path>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x3(%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D3(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: /

assistant: ```c
char *join_path(char *part1, char *part2) {
  char *path = malloc(strlen(part1) + strlen(part2) + 3);
  strcpy(path, part1);
  strcat(path, "/");
  strcat(path, part2);
  return path;
}
```