ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printDate>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: %s

assistant: ```c
void printDate(int taskid) {
  time_t t = time(NULL);
  printf("%s", ctime(&t));
}
```
user: Translate the below assembly code into C programming language:

```asm
<printDate>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: %s

assistant: ```c
void printDate(int taskid) {
  time_t t = time(NULL);
  printf("%s", ctime(&t));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printDate>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: %s

assistant: ```c
void printDate(int taskid) {
  time_t t = time(NULL);
  printf("%s", ctime(&t));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tagRemove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L106
L57:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L106:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L57
  movl   $0x0,-0x14(%rbp)
  jmp    L88
L109:
  movl   $0x0,-0x1c(%rbp)
  jmp    L65
L86:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L100
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L100:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L74
  cmpl   $0x0,-0x10(%rbp)
  js     L74
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L113
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L71
L75:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x18(%rbp)
L71:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L75
L113:
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
L74:
  addl   $0x1,-0x1c(%rbp)
L65:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L86
  addl   $0x1,-0x14(%rbp)
L88:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L109
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tagRemove(char **a) {
  int i, j, k;
  int tagStart = -1;
  int tagEnd = -1;
  int size = 0;
  int x = 0;
  while (a[x] != NULL) {
    size++;
    x++;
  }
  for (k = 0; k < size; k++) {
    for (i = 0; a[k][i] != '\0'; i++) {
      if (a[k][i] == '<') {
        tagStart = i;
      }
      if (a[k][i] == '>' && tagStart > -1) {
        tagEnd = i;
        if (tagEnd > -1) {
          for (j = tagStart; j <= tagEnd; j++) {
            a[k][j] = ' ';
          }
        }
        tagStart = -1;
        tagEnd = -1;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tagRemove>:
  endbr64
  mov    %rdi,%r8
  cmpq   $0x0,(%rdi)
  je     L4
  lea    0x8(%rdi),%rdx
  mov    $0x0,%eax
L139:
  mov    %eax,%r10d
  add    $0x1,%eax
  add    $0x8,%rdx
  cmpq   $0x0,-0x8(%rdx)
  jne    L139
  test   %eax,%eax
  jle    L4
  mov    $0xffffffff,%esi
  mov    $0x0,%r9d
  mov    $0xffffffff,%r11d
  jmp    L108
L77:
  cmp    %esi,%eax
  jl     L130
  movslq %esi,%rdx
  sub    %esi,%edi
  lea    0x1(%rdx,%rdi,1),%rdi
L73:
  mov    (%rcx),%rsi
  movb   $0x20,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L73
  mov    %r11d,%esi
  jmp    L16
L11:
  mov    %eax,%esi
L16:
  add    $0x1,%rax
  mov    (%rcx),%rdx
  movzbl (%rdx,%rax,1),%edx
  test   %dl,%dl
  je     L122
L42:
  mov    %eax,%edi
  cmp    $0x3c,%dl
  je     L11
  test   %esi,%esi
  js     L16
  cmp    $0x3e,%dl
  jne    L16
  test   %eax,%eax
  jns    L77
  mov    %r11d,%esi
  jmp    L16
L130:
  mov    %r11d,%esi
  jmp    L16
L122:
  lea    0x1(%r9),%eax
  add    $0x8,%r8
  cmp    %r10d,%r9d
  jge    L4
  mov    %eax,%r9d
L108:
  mov    %r8,%rcx
  mov    (%r8),%rax
  movzbl (%rax),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L42
  jmp    L122
L4:
  ret
```

assistant: ```c
void tagRemove(char **a) {
  int i, j, k;
  int tagStart = -1;
  int tagEnd = -1;
  int size = 0;
  int x = 0;
  while (a[x] != NULL) {
    size++;
    x++;
  }
  for (k = 0; k < size; k++) {
    for (i = 0; a[k][i] != '\0'; i++) {
      if (a[k][i] == '<') {
        tagStart = i;
      }
      if (a[k][i] == '>' && tagStart > -1) {
        tagEnd = i;
        if (tagEnd > -1) {
          for (j = tagStart; j <= tagEnd; j++) {
            a[k][j] = ' ';
          }
        }
        tagStart = -1;
        tagEnd = -1;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tagRemove>:
  endbr64
  mov    (%rdi),%rcx
  test   %rcx,%rcx
  je     L133
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L118:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L118
  lea    (%rdi,%rdx,8),%r10
  mov    $0xffffffff,%r9d
L80:
  movzbl (%rcx),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L62
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L52:
  cmp    $0x3e,%dl
  je     L1
L100:
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  test   %dl,%dl
  je     L45
L62:
  mov    %eax,%esi
  cmp    $0x3c,%dl
  jne    L52
  mov    %eax,%r9d
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  test   %dl,%dl
  jne    L62
L45:
  cmp    %r10,%rdi
  je     L133
  mov    0x8(%rdi),%rcx
  add    $0x8,%rdi
  jmp    L80
  cs nopw 0x0(%rax,%rax,1)
L1:
  cmp    $0xffffffff,%r9d
  je     L100
  cmp    %eax,%r9d
  jg     L148
  movslq %r9d,%r8
  sub    %r9d,%esi
  lea    0x1(%r8),%rdx
  add    %rdx,%rsi
  jmp    L138
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%rdx
L138:
  movb   $0x20,(%rcx,%r8,1)
  mov    %rdx,%r8
  mov    (%rdi),%rcx
  cmp    %rdx,%rsi
  jne    L24
L148:
  mov    $0xffffffff,%r9d
  jmp    L100
  nopl   0x0(%rax)
L133:
  ret
```

assistant: ```c
void tagRemove(char **a) {
  int i, j, k;
  int tagStart = -1;
  int tagEnd = -1;
  int size = 0;
  int x = 0;
  while (a[x] != NULL) {
    size++;
    x++;
  }
  for (k = 0; k < size; k++) {
    for (i = 0; a[k][i] != '\0'; i++) {
      if (a[k][i] == '<') {
        tagStart = i;
      }
      if (a[k][i] == '>' && tagStart > -1) {
        tagEnd = i;
        if (tagEnd > -1) {
          for (j = tagStart; j <= tagEnd; j++) {
            a[k][j] = ' ';
          }
        }
        tagStart = -1;
        tagEnd = -1;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tagRemove>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L57
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L59:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpq   $0x0,(%rdi,%rax,8)
  jne    L59
  lea    (%rdi,%rdx,8),%r10
  mov    $0xffffffff,%r8d
L147:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L95
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L84:
  cmp    $0x3e,%dl
  je     L33
L106:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L16
L95:
  mov    %eax,%ecx
  cmp    $0x3c,%dl
  jne    L84
  mov    %eax,%r8d
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L95
L16:
  cmp    %r10,%rdi
  je     L57
  mov    0x8(%rdi),%rsi
  add    $0x8,%rdi
  jmp    L147
  cs nopw 0x0(%rax,%rax,1)
L33:
  cmp    $0xffffffff,%r8d
  je     L106
  cmp    %r8d,%eax
  jl     L133
  movslq %r8d,%r9
  lea    0x1(%r8),%edx
  movb   $0x20,(%rsi,%r9,1)
  cmp    %edx,%ecx
  jl     L37
  sub    %r8d,%ecx
  movslq %edx,%rdx
  sub    $0x1,%ecx
  lea    0x2(%r9,%rcx,1),%rsi
  nopl   0x0(%rax)
L38:
  mov    (%rdi),%rcx
  movb   $0x20,(%rcx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L38
L37:
  mov    (%rdi),%rsi
  mov    $0xffffffff,%r8d
  jmp    L106
  xchg   %ax,%ax
L57:
  ret
  nopl   0x0(%rax)
L133:
  mov    $0xffffffff,%r8d
  jmp    L106
```

assistant: ```c
void tagRemove(char **a) {
  int i, j, k;
  int tagStart = -1;
  int tagEnd = -1;
  int size = 0;
  int x = 0;
  while (a[x] != NULL) {
    size++;
    x++;
  }
  for (k = 0; k < size; k++) {
    for (i = 0; a[k][i] != '\0'; i++) {
      if (a[k][i] == '<') {
        tagStart = i;
      }
      if (a[k][i] == '>' && tagStart > -1) {
        tagEnd = i;
        if (tagEnd > -1) {
          for (j = tagStart; j <= tagEnd; j++) {
            a[k][j] = ' ';
          }
        }
        tagStart = -1;
        tagEnd = -1;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<psmat2_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat2_negative@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2_negative(struct mat2 *result, struct mat2 *m) {
  mat2_negative((float *)result, (float *)m);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<psmat2_negative>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat2_negative@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2_negative(struct mat2 *result, struct mat2 *m) {
  mat2_negative((float *)result, (float *)m);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<psmat2_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat2_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2_negative(struct mat2 *result, struct mat2 *m) {
  mat2_negative((float *)result, (float *)m);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psmat2_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat2_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat2 *psmat2_negative(struct mat2 *result, struct mat2 *m) {
  mat2_negative((float *)result, (float *)m);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<TextString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L4
L14:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <TextChar@plt>
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void TextString(const char *s) {
  while (*s)
    TextChar(*s++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TextString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L16:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <TextChar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L7:
  pop    %rbx
  ret
```

assistant: ```c
void TextString(const char *s) {
  while (*s)
    TextChar(*s++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TextString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L10:
  call   <TextChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L10
L6:
  pop    %rbx
  ret
```

assistant: ```c
void TextString(const char *s) {
  while (*s)
    TextChar(*s++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TextString>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L15:
  call   <TextChar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L18:
  pop    %rbx
  ret
```

assistant: ```c
void TextString(const char *s) {
  while (*s)
    TextChar(*s++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shell_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <vfork@plt>
  endbr64
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L6
  cmpl   $0x0,-0x8(%rbp)
  je     L16
  jmp    L29
L6:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <tcpd_warn@plt>
  nop
  jmp    L9
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <do_child@plt>
L29:
  nop
L51:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <wait@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L51
L9:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: cannot fork: %m

assistant: ```c
void shell_cmd(command) char *command;
{
  int child_pid;
  int wait_pid;
  switch (child_pid = vfork()) {
  case -1:
    tcpd_warn("cannot fork: %m");
    break;
  case 00:
    do_child(command);
  default:
    while ((wait_pid = wait((int *)0)) != -1 && wait_pid != child_pid)
      ;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shell_cmd>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x0,%eax
  call   <vfork@plt>
  endbr64
  cmp    $0xffffffff,%eax
  je     L28
  mov    %eax,%ebx
  test   %eax,%eax
  je     L52
L8:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <wait@plt>
  cmp    %eax,%ebx
  je     L17
  cmp    $0xffffffff,%eax
  jne    L8
  jmp    L17
L28:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <tcpd_warn@plt>
L17:
  add    $0x10,%rsp
  pop    %rbx
  ret
L52:
  mov    0x8(%rsp),%rdi
  mov    $0x0,%eax
  call   <do_child@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: cannot fork: %m

assistant: ```c
void shell_cmd(command) char *command;
{
  int child_pid;
  int wait_pid;
  switch (child_pid = vfork()) {
  case -1:
    tcpd_warn("cannot fork: %m");
    break;
  case 00:
    do_child(command);
  default:
    while ((wait_pid = wait((int *)0)) != -1 && wait_pid != child_pid)
      ;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shell_cmd>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  call   <vfork@plt>
  endbr64
  cmp    $0xffffffff,%eax
  je     L0
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L6
  mov    0x8(%rsp),%rdi
  xor    %eax,%eax
  call   <do_child@plt>
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L8
  xchg   %ax,%ax
L11:
  cmp    %eax,%ebx
  je     L8
L6:
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L11
L8:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <tcpd_warn@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: cannot fork: %m

assistant: ```c
void shell_cmd(command) char *command;
{
  int child_pid;
  int wait_pid;
  switch (child_pid = vfork()) {
  case -1:
    tcpd_warn("cannot fork: %m");
    break;
  case 00:
    do_child(command);
  default:
    while ((wait_pid = wait((int *)0)) != -1 && wait_pid != child_pid)
      ;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shell_cmd>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  call   <vfork@plt>
  endbr64
  cmp    $0xffffffff,%eax
  je     L12
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L30
  mov    0x8(%rsp),%rdi
  xor    %eax,%eax
  call   <do_child@plt>
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L28
  xchg   %ax,%ax
L37:
  cmp    %eax,%ebx
  je     L28
L30:
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L37
L28:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <tcpd_warn@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: cannot fork: %m

assistant: ```c
void shell_cmd(command) char *command;
{
  int child_pid;
  int wait_pid;
  switch (child_pid = vfork()) {
  case -1:
    tcpd_warn("cannot fork: %m");
    break;
  case 00:
    do_child(command);
  default:
    while ((wait_pid = wait((int *)0)) != -1 && wait_pid != child_pid)
      ;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L9:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L9
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *a;
  unsigned char *b;
  i = 0;
  a = (unsigned char *)dst;
  b = (unsigned char *)src;
  while (i < n) {
    a[i] = b[i];
    i++;
  }
  return (dst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L10
  mov    $0x0,%ecx
L18:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L18
L10:
  ret
```

assistant: ```c
void *ft_memcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *a;
  unsigned char *b;
  i = 0;
  a = (unsigned char *)dst;
  b = (unsigned char *)src;
  while (i < n) {
    a[i] = b[i];
    i++;
  }
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L0
  xor    %ecx,%ecx
  xchg   %ax,%ax
L3:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L3
L0:
  ret
```

assistant: ```c
void *ft_memcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *a;
  unsigned char *b;
  i = 0;
  a = (unsigned char *)dst;
  b = (unsigned char *)src;
  while (i < n) {
    a[i] = b[i];
    i++;
  }
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L31
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rax
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L137
  cmp    $0x6,%rax
  jbe    L137
  mov    %rdx,%rsi
  cmp    $0xe,%rax
  jbe    L42
  and    $0xfffffffffffffff0,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L138:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L138
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%dl
  je     L31
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    -0x1(%rsi),%rdi
  cmp    $0x6,%rdi
  jbe    L134
L82:
  mov    (%rcx,%rax,1),%rdi
  mov    %rdi,(%r8,%rax,1)
  mov    %rsi,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rax
  cmp    %rdi,%rsi
  je     L31
L134:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  lea    0x1(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x1(%rcx,%rax,1),%esi
  mov    %sil,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x2(%rcx,%rax,1),%esi
  mov    %sil,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x3(%rcx,%rax,1),%esi
  mov    %sil,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x4(%rcx,%rax,1),%esi
  mov    %sil,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x5(%rcx,%rax,1),%esi
  mov    %sil,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L31
  movzbl 0x6(%rcx,%rax,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L31:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L137:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L108:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L108
  mov    %r8,%rax
  ret
L42:
  xor    %eax,%eax
  jmp    L82
```

assistant: ```c
void *ft_memcpy(void *dst, const void *src, size_t n) {
  size_t i;
  unsigned char *a;
  unsigned char *b;
  i = 0;
  a = (unsigned char *)dst;
  b = (unsigned char *)src;
  while (i < n) {
    a[i] = b[i];
    i++;
  }
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L26
L40:
  mov    -0x34(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L26:
  cmpl   $0x8,-0x34(%rbp)
  jle    L40
  lea    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,%rdi
  call   <set_ldt1@plt>
  mov    $0x0,%eax
  call   <print_ldt@plt>
  mov    $0x115c,%edx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <ldt_seg_write@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L0
L23:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L0:
  cmpl   $0x8,-0x34(%rbp)
  jle    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: %d 

assistant: ```c
int main(void) {
  int i;
  int arr[9];
  for (i = 0; i < 9; i++)
    arr[i] = 11 * i;
  set_ldt1(&arr[4]);
  print_ldt();
  ldt_seg_write(1, 4, 4444);
  for (i = 0; i < 9; i++)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```