ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x20,-0xa(%rbp)
  movb   $0x20,-0x9(%rbp)
L58:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x32,%eax
  je     L20
  cmp    $0x32,%eax
  jg     L65
  cmp    $0x30,%eax
  je     L70
  cmp    $0x31,%eax
  jne    L65
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L19
L20:
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L65:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L70:
  nop
L19:
  movzbl -0xa(%rbp),%eax
  cmp    $0x30,%al
  jne    L58
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D51
type: string
name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D37
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D16: 
0) Sair            
1) Digite uma letra            
2) Mostre a letra            
Op: 

tool: D51:  %c

tool: D21: 
Letra: 

tool: D37: 
Letra digitada: %c

tool: D39: 
Opcao invalida.

tool: D10: fim

assistant: ```c
int main() {
  char op = ' ';
  char letra = ' ';
  do {
    printf("\n0) Sair            \n1) Digite uma letra            \n2) Mostre a letra            \nOp: ");
    scanf(" %c", &op);
    switch (op) {
    case '0':
      break;
    case '1':
      printf("\nLetra: ");
      scanf(" %c", &letra);
      break;
    case '2':
      printf("\nLetra digitada: %c", letra);
      break;
    default:
      printf("\nOpcao invalida.");
    }
  } while (op != '0');
  printf("fim");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x20,0x6(%rsp)
  movb   $0x20,0x7(%rsp)
  lea    D47(%rip),%rbp
  lea    D33(%rip),%rbx
  lea    D36(%rip),%r13
  lea    D46(%rip),%r12
  jmp    L77
L46:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L30:
  cmpb   $0x30,0x6(%rsp)
  je     L1
L77:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  cmp    $0x31,%al
  je     L46
  cmp    $0x32,%al
  je     L29
  cmp    $0x30,%al
  je     L1
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L29:
  movsbl 0x7(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L1:
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D47
type: string
name: disassemble_data
arguments: label: D33
type: string
name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D46
type: string
name: disassemble_data
arguments: label: D20
type: string
name: disassemble_data
arguments: label: D53
type: string

tool: D47: 
0) Sair            
1) Digite uma letra            
2) Mostre a letra            
Op: 

tool: D33:  %c

tool: D36: 
Letra: 

tool: D46: 
Letra digitada: %c

tool: D20: 
Opcao invalida.

tool: D53: fim

assistant: ```c
int main() {
  char op = ' ';
  char letra = ' ';
  do {
    printf("\n0) Sair            \n1) Digite uma letra            \n2) Mostre a letra            \nOp: ");
    scanf(" %c", &op);
    switch (op) {
    case '0':
      break;
    case '1':
      printf("\nLetra: ");
      scanf(" %c", &letra);
      break;
    case '2':
      printf("\nLetra digitada: %c", letra);
      break;
    default:
      printf("\nOpcao invalida.");
    }
  } while (op != '0');
  printf("fim");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%r15
  push   %r14
  push   %r13
  lea    D50(%rip),%r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D55(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rbp
  movb   $0x20,0x6(%rsp)
  lea    0x7(%rsp),%r14
  movb   $0x20,0x7(%rsp)
  jmp    L16
  nopl   0x0(%rax)
L5:
  cmp    $0x30,%al
  je     L21
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x6(%rsp),%eax
L54:
  cmp    $0x30,%al
  je     L21
L16:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  cmp    $0x31,%al
  je     L74
  cmp    $0x32,%al
  jne    L5
  movsbl 0x7(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x6(%rsp),%eax
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  jmp    L54
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D50
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D55
type_guessed: string
name: unpack_data
arguments: data_label: D49
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string

tool: D16: 
Letra: 

tool: D50: 
Letra digitada: %c

tool: D32: 
0) Sair            
1) Digite uma letra            
2) Mostre a letra            
Op: 

tool: D55:  %c

tool: D49: 
Opcao invalida.

tool: D43: fim

assistant: ```c
int main() {
  char op = ' ';
  char letra = ' ';
  do {
    printf("\n0) Sair            \n1) Digite uma letra            \n2) Mostre a letra            \nOp: ");
    scanf(" %c", &op);
    switch (op) {
    case '0':
      break;
    case '1':
      printf("\nLetra: ");
      scanf(" %c", &letra);
      break;
    case '2':
      printf("\nLetra digitada: %c", letra);
      break;
    default:
      printf("\nOpcao invalida.");
    }
  } while (op != '0');
  printf("fim");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D54(%rip),%r15
  push   %r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rbp
  movb   $0x20,0x6(%rsp)
  lea    0x7(%rsp),%r14
  movb   $0x20,0x7(%rsp)
  jmp    L42
  nopl   0x0(%rax)
L33:
  cmp    $0x30,%al
  je     L5
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x6(%rsp),%eax
L19:
  cmp    $0x30,%al
  je     L5
L42:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  cmp    $0x31,%al
  je     L27
  cmp    $0x32,%al
  jne    L33
  movsbl 0x7(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x6(%rsp),%eax
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  jmp    L19
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D54
data_type: string
name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D32
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string

tool: D54: 
Letra: 

tool: D16: 
Letra digitada: %c

tool: D13: 
0) Sair            
1) Digite uma letra            
2) Mostre a letra            
Op: 

tool: D5:  %c

tool: D32: 
Opcao invalida.

tool: D11: fim

assistant: ```c
int main() {
  char op = ' ';
  char letra = ' ';
  do {
    printf("\n0) Sair            \n1) Digite uma letra            \n2) Mostre a letra            \nOp: ");
    scanf(" %c", &op);
    switch (op) {
    case '0':
      break;
    case '1':
      printf("\nLetra: ");
      scanf(" %c", &letra);
      break;
    case '2':
      printf("\nLetra digitada: %c", letra);
      break;
    default:
      printf("\nOpcao invalida.");
    }
  } while (op != '0');
  printf("fim");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getgrnam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L66
  mov    $0x0,%eax
  jmp    L68
L66:
  mov    -0x18(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L64
  mov    $0x0,%eax
  jmp    L68
L58:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
  jmp    L68
L64:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetgrent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L68:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string

tool: D3: MOCK_GROUP

tool: D19: r

assistant: ```c
struct group *getgrnam(const char *name) {
  const char *path = getenv("MOCK_GROUP");
  if (!path)
    return NULL;
  FILE *stream = fopen(path, "r");
  if (!stream)
    return NULL;
  struct group *entry;
  while ((entry = fgetgrent(stream))) {
    if (strcmp(entry->gr_name, name) == 0) {
      fclose(stream);
      return entry;
    }
  }
  fclose(stream);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getgrnam>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L47
L19:
  mov    %rbp,%rdi
  call   <fgetgrent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L49
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbp,%rdi
  call   <fclose@plt>
  jmp    L8
L49:
  mov    %rbp,%rdi
  call   <fclose@plt>
L8:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %rax,%rbx
  jmp    L8
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D6
datatype: string

tool: D7: MOCK_GROUP

tool: D6: r

assistant: ```c
struct group *getgrnam(const char *name) {
  const char *path = getenv("MOCK_GROUP");
  if (!path)
    return NULL;
  FILE *stream = fopen(path, "r");
  if (!stream)
    return NULL;
  struct group *entry;
  while ((entry = fgetgrent(stream))) {
    if (strcmp(entry->gr_name, name) == 0) {
      fclose(stream);
      return entry;
    }
  }
  fclose(stream);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getgrnam>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L15
  jmp    L1
  nopl   (%rax)
L16:
  mov    (%r12),%edi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L8
L15:
  mov    %rbp,%rdi
  call   <fgetgrent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L16
L8:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D5
type: string

tool: D15: MOCK_GROUP

tool: D5: r

assistant: ```c
struct group *getgrnam(const char *name) {
  const char *path = getenv("MOCK_GROUP");
  if (!path)
    return NULL;
  FILE *stream = fopen(path, "r");
  if (!stream)
    return NULL;
  struct group *entry;
  while ((entry = fgetgrent(stream))) {
    if (strcmp(entry->gr_name, name) == 0) {
      fclose(stream);
      return entry;
    }
  }
  fclose(stream);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getgrnam>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%rdi
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L45
  jmp    L20
  nopl   (%rax)
L23:
  mov    (%r12),%edi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
L45:
  mov    %rbp,%rdi
  call   <fgetgrent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L23
L0:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D4: MOCK_GROUP

tool: D7: r

assistant: ```c
struct group *getgrnam(const char *name) {
  const char *path = getenv("MOCK_GROUP");
  if (!path)
    return NULL;
  FILE *stream = fopen(path, "r");
  if (!stream)
    return NULL;
  struct group *entry;
  while ((entry = fgetgrent(stream))) {
    if (strcmp(entry->gr_name, name) == 0) {
      fclose(stream);
      return entry;
    }
  }
  fclose(stream);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_scale_ps_si16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  mov    %edx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x24(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cvttss2si %xmm0,%edx
  mov    %dx,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convert_scale_ps_si16(short *out, float *in, float scale, int len) {
  for (int i = 0; i < len; i++)
    out[i] = in[i] * scale;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert_scale_ps_si16>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L8:
  movaps %xmm0,%xmm1
  mulss  (%rsi,%rax,4),%xmm1
  cvttss2si %xmm1,%ecx
  mov    %cx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L17:
  ret
```

assistant: ```c
void convert_scale_ps_si16(short *out, float *in, float scale, int len) {
  for (int i = 0; i < len; i++)
    out[i] = in[i] * scale;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_scale_ps_si16>:
  endbr64
  test   %edx,%edx
  jle    L17
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movss  (%rsi,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%ecx
  mov    %cx,(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L3
L17:
  ret
```

assistant: ```c
void convert_scale_ps_si16(short *out, float *in, float scale, int len) {
  for (int i = 0; i < len; i++)
    out[i] = in[i] * scale;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_scale_ps_si16>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L91
  lea    -0x1(%rdx),%eax
  cmp    $0x6,%eax
  jbe    L45
  mov    %edx,%esi
  movaps %xmm0,%xmm4
  xor    %eax,%eax
  shr    $0x3,%esi
  shufps $0x0,%xmm4,%xmm4
  shl    $0x4,%rsi
  nopl   (%rax)
L32:
  movups (%rcx,%rax,2),%xmm1
  movups 0x10(%rcx,%rax,2),%xmm2
  mulps  %xmm4,%xmm1
  mulps  %xmm4,%xmm2
  cvttps2dq %xmm1,%xmm1
  movdqa %xmm1,%xmm3
  cvttps2dq %xmm2,%xmm2
  punpcklwd %xmm2,%xmm1
  punpckhwd %xmm2,%xmm3
  movdqa %xmm1,%xmm2
  punpcklwd %xmm3,%xmm1
  punpckhwd %xmm3,%xmm2
  punpcklwd %xmm2,%xmm1
  movups %xmm1,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L32
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  test   $0x7,%dl
  je     L109
L43:
  movslq %eax,%r9
  movss  (%rcx,%r9,4),%xmm1
  lea    0x0(,%r9,4),%r8
  lea    (%r9,%r9,1),%rsi
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r10d
  mov    %r10w,(%rdi,%r9,2)
  lea    0x1(%rax),%r9d
  cmp    %r9d,%edx
  jle    L91
  movss  0x4(%rcx,%r8,1),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r9d
  mov    %r9w,0x2(%rdi,%rsi,1)
  lea    0x2(%rax),%r9d
  cmp    %r9d,%edx
  jle    L91
  movss  0x8(%rcx,%r8,1),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r9d
  mov    %r9w,0x4(%rdi,%rsi,1)
  lea    0x3(%rax),%r9d
  cmp    %r9d,%edx
  jle    L91
  movss  0xc(%rcx,%r8,1),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r9d
  mov    %r9w,0x6(%rdi,%rsi,1)
  lea    0x4(%rax),%r9d
  cmp    %r9d,%edx
  jle    L91
  movss  0x10(%rcx,%r8,1),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r9d
  mov    %r9w,0x8(%rdi,%rsi,1)
  lea    0x5(%rax),%r9d
  cmp    %r9d,%edx
  jle    L91
  movss  0x14(%rcx,%r8,1),%xmm1
  add    $0x6,%eax
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%r9d
  mov    %r9w,0xa(%rdi,%rsi,1)
  cmp    %eax,%edx
  jle    L91
  mulss  0x18(%rcx,%r8,1),%xmm0
  cvttss2si %xmm0,%eax
  mov    %ax,0xc(%rdi,%rsi,1)
L91:
  ret
  nopl   0x0(%rax)
L109:
  ret
L45:
  xor    %eax,%eax
  jmp    L43
```

assistant: ```c
void convert_scale_ps_si16(short *out, float *in, float scale, int len) {
  for (int i = 0; i < len; i++)
    out[i] = in[i] * scale;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfftf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <rfftf1@plt>
  jmp    L8
L6:
  nop
L8:
  leave
  ret
```

assistant: ```c
void rfftf(int n, double r[], double wsave[]) {
  if (n == 1)
    return;
  rfftf1(n, r, wsave, wsave + n, (int *)(wsave + 2 * n));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rfftf>:
  endbr64
  cmp    $0x1,%edi
  je     L9
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,1),%eax
  cltq
  movslq %edi,%rcx
  lea    (%rdx,%rcx,8),%rcx
  lea    (%rdx,%rax,8),%r8
  call   <rfftf1@plt>
  add    $0x8,%rsp
  ret
L9:
  ret
```

assistant: ```c
void rfftf(int n, double r[], double wsave[]) {
  if (n == 1)
    return;
  rfftf1(n, r, wsave, wsave + n, (int *)(wsave + 2 * n));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rfftf>:
  endbr64
  cmp    $0x1,%edi
  je     L8
  lea    (%rdi,%rdi,1),%eax
  movslq %edi,%rcx
  cltq
  lea    (%rdx,%rcx,8),%rcx
  lea    (%rdx,%rax,8),%r8
  jmp    1050 <rfftf1@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void rfftf(int n, double r[], double wsave[]) {
  if (n == 1)
    return;
  rfftf1(n, r, wsave, wsave + n, (int *)(wsave + 2 * n));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfftf>:
  endbr64
  cmp    $0x1,%edi
  je     L8
  lea    (%rdi,%rdi,1),%eax
  movslq %edi,%rcx
  cltq
  lea    (%rdx,%rcx,8),%rcx
  lea    (%rdx,%rax,8),%r8
  jmp    1050 <rfftf1@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void rfftf(int n, double r[], double wsave[]) {
  if (n == 1)
    return;
  rfftf1(n, r, wsave, wsave + n, (int *)(wsave + 2 * n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dieNeg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edi
  call   <exit@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void dieNeg(int val, char *msg) {
  if (val < 0) {
    perror(msg);
    exit(-val);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dieNeg>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
L9:
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdi
  call   <perror@plt>
  neg    %ebx
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void dieNeg(int val, char *msg) {
  if (val < 0) {
    perror(msg);
    exit(-val);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dieNeg>:
  endbr64
  test   %edi,%edi
  js     L2
  ret
  nopl   0x0(%rax)
L2:
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdi
  neg    %ebx
  call   <perror@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <exit@plt>
```

assistant: ```c
void dieNeg(int val, char *msg) {
  if (val < 0) {
    perror(msg);
    exit(-val);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dieNeg>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
  nopl   0x0(%rax)
L9:
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdi
  neg    %ebx
  call   <perror@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <exit@plt>
```

assistant: ```c
void dieNeg(int val, char *msg) {
  if (val < 0) {
    perror(msg);
    exit(-val);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<posix_spawnattr_getschedparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int posix_spawnattr_getschedparam(const posix_spawnattr_t *attr, struct sched_param *schedparam) {
  ;
  errno = ENOSYS;
  return -1;
  ;
}
```