ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dectoe>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <ecleaz@plt>
  movzwl (%rbx),%eax
  test   %ax,%ax
  jns    L0
  mov    $0xffffffff,%edx
  mov    %dx,(%rsp)
L0:
  mov    %eax,%edx
  and    $0x7fff,%dx
  je     L23
  and    $0x7f,%eax
  shr    $0x7,%dx
  mov    %r12,%rdi
  or     $0x80,%al
  add    $0x3f7e,%dx
  mov    %ax,0x4(%rsp)
  movzwl 0x2(%rbx),%eax
  mov    %dx,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  mov    0x4(%rbx),%eax
  mov    %eax,0x8(%rsp)
  xor    %eax,%eax
  call   <eshdn8@plt>
L23:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <emovo@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dectoe(d, e) unsigned short *d;
unsigned short *e;
{
  unsigned short y[(10 + 3)];
  register unsigned short r, *p;
  ecleaz(y);
  p = y;
  r = *d;
  if (*d & (unsigned int)0x8000)
    *p = 0xffff;
  ++p;
  r &= 0x7fff;
  if (r == 0)
    goto done;
  r >>= 7;
  r += (0x3fff) - 0201;
  *p++ = r;
  r = *d++;
  r &= 0177;
  r |= 0200;
  *p++ = r;
  *p++ = *d++;
  *p++ = *d++;
  *p = *d;
  eshdn8(y);
done:
  emovo(y, e);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dectoe>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <ecleaz@plt>
  movzwl (%rbx),%eax
  test   %ax,%ax
  jns    L20
  mov    $0xffffffff,%edx
  mov    %dx,(%rsp)
L20:
  mov    %eax,%edx
  and    $0x7fff,%dx
  je     L28
  shr    $0x7,%dx
  movzwl 0x2(%rbx),%esi
  mov    %r12,%rdi
  lea    0x3f7e(%rdx),%ecx
  mov    %rax,%rdx
  movzwl 0x4(%rbx),%eax
  and    $0x7f,%edx
  shl    $0x10,%rax
  or     $0x80,%dl
  or     %rsi,%rax
  shl    $0x10,%rax
  or     %rdx,%rax
  movzwl %cx,%edx
  shl    $0x10,%rax
  or     %rdx,%rax
  mov    %rax,0x2(%rsp)
  movzwl 0x6(%rbx),%eax
  mov    %ax,0xa(%rsp)
  xor    %eax,%eax
  call   <eshdn8@plt>
L28:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <emovo@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dectoe(d, e) unsigned short *d;
unsigned short *e;
{
  unsigned short y[(10 + 3)];
  register unsigned short r, *p;
  ecleaz(y);
  p = y;
  r = *d;
  if (*d & (unsigned int)0x8000)
    *p = 0xffff;
  ++p;
  r &= 0x7fff;
  if (r == 0)
    goto done;
  r >>= 7;
  r += (0x3fff) - 0201;
  *p++ = r;
  r = *d++;
  r &= 0177;
  r |= 0200;
  *p++ = r;
  *p++ = *d++;
  *p++ = *d++;
  *p = *d;
  eshdn8(y);
done:
  emovo(y, e);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<b_ethernet_rx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,%rdi
  call   *0x100028
  mov    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long b_ethernet_rx(void *mem, unsigned long iid) {
  unsigned long tlong;
  asm volatile("call *0x00100028" : "=c"(tlong) : "D"(mem), "d"(iid));
  return tlong;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<b_ethernet_rx>:
  endbr64
  mov    %rsi,%rdx
  call   *0x100028
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_ethernet_rx(void *mem, unsigned long iid) {
  unsigned long tlong;
  asm volatile("call *0x00100028" : "=c"(tlong) : "D"(mem), "d"(iid));
  return tlong;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<b_ethernet_rx>:
  endbr64
  mov    %rsi,%rdx
  call   *0x100028
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_ethernet_rx(void *mem, unsigned long iid) {
  unsigned long tlong;
  asm volatile("call *0x00100028" : "=c"(tlong) : "D"(mem), "d"(iid));
  return tlong;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<b_ethernet_rx>:
  endbr64
  mov    %rsi,%rdx
  call   *0x100028
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_ethernet_rx(void *mem, unsigned long iid) {
  unsigned long tlong;
  asm volatile("call *0x00100028" : "=c"(tlong) : "D"(mem), "d"(iid));
  return tlong;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  or     $0x61bab5,%rdx
  mov    %rdx,%rsi
  shl    $0x18,%rsi
  sar    $0x38,%rsi
  mov    %rdx,%rax
  shr    $0x38,%rax
  shl    $0x20,%rax
  movabs $0xffffff00ffffffff,%rdi
  and    %rdi,%rdx
  or     %rdx,%rax
  shl    $0x38,%rdx
  movabs $0xffffffffffffff,%rdi
  and    %rdi,%rax
  or     %rdx,%rax
  mov    %sil,%al
  test   %rax,%rax
  je     L1
  mov    %eax,%edx
  mov    %rax,%rsi
  shr    $0x30,%rsi
  mov    %si,%ax
  shl    $0x30,%rdx
  movabs $0xffffffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
L17:
  shr    $0x3,%rax
  xor    $0x1d64e56,%rax
  mov    %rax,(%rcx)
  ret
L1:
  mov    %eax,%esi
  sar    $0x18,%esi
  movzbl %sil,%esi
  shl    $0x20,%rsi
  movabs $0xffffff00ffffffff,%rdx
  and    %rax,%rdx
  or     %rsi,%rdx
  shr    $0x8,%rax
  and    $0xff000000,%eax
  movabs $0xffffffff00ffffff,%rsi
  and    %rsi,%rdx
  or     %rdx,%rax
  jmp    L17
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy11;
        copy11 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy12;
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 246575798UL) >> 3UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffff00ffffffff,%rax
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  movabs $0xffffffffffffff,%r8
  shr    $0x3,%rdx
  mov    %rdx,%rsi
  shr    $0x38,%rdx
  or     $0x61bab5,%rsi
  mov    %rdx,%rdi
  shl    $0x20,%rdi
  and    %rsi,%rax
  or     %rdi,%rax
  mov    %rsi,%rdi
  shl    $0x38,%rdi
  and    %r8,%rax
  or     %rdi,%rax
  mov    %rsi,%rdi
  shl    $0x18,%rdi
  sar    $0x38,%rdi
  mov    %dil,%al
  test   %rax,%rax
  je     L1
  mov    %rax,%rsi
  mov    %eax,%edx
  shr    $0x30,%rsi
  shl    $0x30,%rdx
  mov    %si,%ax
  movabs $0xffffffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  shr    $0x3,%rax
  xor    $0x1d64e56,%rax
  mov    %rax,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %esi,%eax
  shl    $0x18,%rdx
  sar    $0x18,%eax
  movzbl %al,%eax
  shl    $0x20,%rax
  or     %rdx,%rax
  shr    $0x3,%rax
  xor    $0x1d64e56,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy11;
        copy11 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy12;
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 246575798UL) >> 3UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffff00ffffffff,%rax
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  movabs $0xffffffffffffff,%r8
  shr    $0x3,%rdx
  mov    %rdx,%rsi
  shr    $0x38,%rdx
  or     $0x61bab5,%rsi
  mov    %rdx,%rdi
  shl    $0x20,%rdi
  and    %rsi,%rax
  or     %rdi,%rax
  mov    %rsi,%rdi
  shl    $0x18,%rdi
  sar    $0x38,%rdi
  mov    %dil,%al
  mov    %rsi,%rdi
  and    %r8,%rax
  shl    $0x38,%rdi
  or     %rax,%rdi
  mov    %rdi,%rax
  je     L0
  movabs $0xffffffffffff,%rsi
  mov    %rdi,%rdx
  shl    $0x30,%rdi
  shr    $0x30,%rdx
  mov    %dx,%ax
  and    %rsi,%rax
  or     %rdi,%rax
  shr    $0x3,%rax
  xor    $0x1d64e56,%rax
  mov    %rax,(%rcx)
  ret
  nopl   0x0(%rax)
L0:
  mov    %esi,%eax
  shl    $0x18,%rdx
  sar    $0x18,%eax
  movzbl %al,%eax
  shl    $0x20,%rax
  or     %rdx,%rax
  shr    $0x3,%rax
  xor    $0x1d64e56,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 4);
        *((char *)(&state[local1]) + 4) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy11;
        copy11 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = copy12;
        copy12 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy13;
      } else {
        copy14 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 246575798UL) >> 3UL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<doubles_quat_slerp>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movsd  %xmm0,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edx
  call   <doubles_dot@plt>
  movq   %xmm0,%r14
  lea    0x10(%rsp),%rdi
  mov    $0x20,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  pxor   %xmm0,%xmm0
  movq   %r14,%xmm3
  comisd %xmm3,%xmm0
  ja     L53
L0:
  mov    $0x0,%eax
  movq   %r14,%xmm4
  comisd D42(%rip),%xmm4
  jbe    L12
  movsd  D16(%rip),%xmm2
  subsd  (%rsp),%xmm2
  lea    0x10(%rsp),%rdx
L41:
  movapd %xmm2,%xmm0
  mulsd  (%rbx,%rax,1),%xmm0
  movsd  (%rsp),%xmm1
  mulsd  (%rax,%rdx,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L41
L31:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L53:
  xorpd  D30(%rip),%xmm3
  movq   %xmm3,%r14
  lea    0x10(%rsp),%rax
  lea    0x30(%rsp),%rdx
  movq   D30(%rip),%xmm1
L49:
  movsd  (%rax),%xmm0
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L49
  jmp    L0
L12:
  movq   %r14,%xmm0
  call   <acos@plt>
  pxor   %xmm6,%xmm6
  cvtsi2sd %rax,%xmm6
  movsd  D16(%rip),%xmm0
  subsd  (%rsp),%xmm0
  movsd  %xmm6,0x8(%rsp)
  mulsd  %xmm6,%xmm0
  call   <sin@plt>
  pxor   %xmm5,%xmm5
  cvtsi2sd %rax,%xmm5
  movq   %xmm5,%r12
  movsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  call   <sin@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  mov    $0x0,%eax
  lea    0x10(%rsp),%rdx
L74:
  movq   %r12,%xmm0
  mulsd  (%rbx,%rax,1),%xmm0
  movapd %xmm2,%xmm1
  mulsd  (%rax,%rdx,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L74
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <doubles_normalize@plt>
  jmp    L31
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D42
data_type: f64[2]
name: unpack_data
arguments: data_label: D16
data_type: f64
name: unpack_data
arguments: data_label: D30
data_type: byte[16]

tool: {"D42": [0.95,1.0]}

tool: D16: 1

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_quat_slerp(const double q0[4], const double _q1[4], double r[4], double w) {
  double dot = doubles_dot(q0, _q1, 4);
  double q1[4];
  memcpy(q1, _q1, sizeof(double) * 4);
  if (dot < 0) {
    dot = -dot;
    for (int i = 0; i < 4; i++)
      q1[i] *= -1;
  }
  if (dot > 0.95) {
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * (1 - w) + q1[i] * w;
  } else {
    double angle = (double)acos(dot);
    double w0 = (double)sin(angle * (1 - w)), w1 = (double)sin(angle * w);
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * w0 + q1[i] * w1;
    doubles_normalize(r, 4, r);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<doubles_quat_slerp>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x4,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x58,%rsp
  movsd  %xmm0,0x10(%rsp)
  lea    0x20(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <doubles_dot@plt>
  mov    $0x20,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <memcpy@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm2
  ja     L21
  comisd D0(%rip),%xmm0
  jbe    L58
L77:
  movsd  D21(%rip),%xmm3
  xor    %eax,%eax
  subsd  %xmm1,%xmm3
L13:
  movsd  (%rbx,%rax,1),%xmm0
  movsd  0x0(%r13,%rax,1),%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L13
L55:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  movq   D23(%rip),%xmm3
  mov    %r13,%rax
  lea    0x40(%rsp),%rdx
  xorpd  %xmm3,%xmm0
L43:
  movsd  (%rax),%xmm2
  add    $0x8,%rax
  xorpd  %xmm3,%xmm2
  movsd  %xmm2,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L43
  comisd D0(%rip),%xmm0
  ja     L77
L58:
  movsd  %xmm1,0x8(%rsp)
  call   <acos@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  movsd  D21(%rip),%xmm0
  cvtsi2sd %rax,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  mulsd  %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <sin@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2sd %rax,%xmm3
  mulsd  %xmm1,%xmm2
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <sin@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm3
  cvtsi2sd %rax,%xmm2
  xor    %eax,%eax
L56:
  movsd  (%rbx,%rax,1),%xmm0
  movsd  0x0(%r13,%rax,1),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    $0x20,%rax
  jne    L56
  mov    %rbp,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <doubles_normalize@plt>
  jmp    L55
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: f64[2]
name: disassemble_data
arguments: data_tag: D21
datatype: f64
name: disassemble_data
arguments: data_tag: D23
datatype: byte[8]

tool: {"D0": [0.95,1.0]}

tool: D21: 1

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void doubles_quat_slerp(const double q0[4], const double _q1[4], double r[4], double w) {
  double dot = doubles_dot(q0, _q1, 4);
  double q1[4];
  memcpy(q1, _q1, sizeof(double) * 4);
  if (dot < 0) {
    dot = -dot;
    for (int i = 0; i < 4; i++)
      q1[i] *= -1;
  }
  if (dot > 0.95) {
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * (1 - w) + q1[i] * w;
  } else {
    double angle = (double)acos(dot);
    double w0 = (double)sin(angle * (1 - w)), w1 = (double)sin(angle * w);
    for (int i = 0; i < 4; i++)
      r[i] = q0[i] * w0 + q1[i] * w1;
    doubles_normalize(r, 4, r);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<testswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: D14: %d %d


assistant: ```c
void testswap() {
  int a = 1, b = 2;
  printf("%d %d\n", a, b);
  swap(&a, &b);
  printf("%d %d\n", a, b);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<testswap>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: %d %d


assistant: ```c
void testswap() {
  int a = 1, b = 2;
  printf("%d %d\n", a, b);
  swap(&a, &b);
  printf("%d %d\n", a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testswap>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: %d %d


assistant: ```c
void testswap() {
  int a = 1, b = 2;
  printf("%d %d\n", a, b);
  swap(&a, &b);
  printf("%d %d\n", a, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testswap>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d %d


assistant: ```c
void testswap() {
  int a = 1, b = 2;
  printf("%d %d\n", a, b);
  swap(&a, &b);
  printf("%d %d\n", a, b);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    $0x30,%edi
  call   <write_on_console@plt>
  jmp    L19
L7:
  cmpl   $0x0,-0x14(%rbp)
  jle    L19
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <itohex@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <write_str_on_console@plt>
L19:
  leave
  ret
```

assistant: ```c
void print_hex(int a) {
  if (a == 0) {
    write_on_console('0');
    return;
  }
  if (a > 0) {
    char *num_str = itohex(a);
    write_str_on_console(num_str);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_hex>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L2
  jg     L15
L39:
  add    $0x8,%rsp
  ret
L2:
  mov    $0x30,%edi
  call   <write_on_console@plt>
  jmp    L39
L15:
  call   <itohex@plt>
  mov    %rax,%rdi
  call   <write_str_on_console@plt>
  jmp    L39
```

assistant: ```c
void print_hex(int a) {
  if (a == 0) {
    write_on_console('0');
    return;
  }
  if (a > 0) {
    char *num_str = itohex(a);
    write_str_on_console(num_str);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_hex>:
  endbr64
  test   %edi,%edi
  je     L19
  jg     L13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  sub    $0x8,%rsp
  call   <itohex@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <write_str_on_console@plt>
  nopl   (%rax)
L19:
  mov    $0x30,%edi
  jmp    1090 <write_on_console@plt>
```

assistant: ```c
void print_hex(int a) {
  if (a == 0) {
    write_on_console('0');
    return;
  }
  if (a > 0) {
    char *num_str = itohex(a);
    write_str_on_console(num_str);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_hex>:
  endbr64
  test   %edi,%edi
  je     L14
  jg     L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  call   <itohex@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <write_str_on_console@plt>
  nopl   (%rax)
L14:
  mov    $0x30,%edi
  jmp    1090 <write_on_console@plt>
```

assistant: ```c
void print_hex(int a) {
  if (a == 0) {
    write_on_console('0');
    return;
  }
  if (a > 0) {
    char *num_str = itohex(a);
    write_str_on_console(num_str);
  }
}
```