ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D14(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D62(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <pack@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L23
L20:
  mov    $0x4,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <unpack@plt>
  lea    D58(%rip),%rdi
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D76(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L20
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string
name: disassemble_data
arguments: tag: D62
type_infered: string
name: disassemble_data
arguments: tag: D54
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D76
type_infered: string

tool: D14: Sizeof(num1) = %lu


tool: D35: Enter two numbers in HEX : 

tool: D62: %i %i

tool: D54: num1 = %XH	num2 = %XH


tool: D39: sizeof(packed) = %lu


tool: D4: Packed number = %XH or %dD


tool: D58: Unpacked numbers = %XH and %XH


tool: D76: Error: One of the number is greater than 0x0f

assistant: ```c
int main() {
  int num1, num2;
  u_char packed, *unpacked;
  printf("Sizeof(num1) = %lu\n", sizeof(num1));
  printf("Enter two numbers in HEX : ");
  scanf("%i %i", &num1, &num2);
  printf("num1 = %XH\tnum2 = %XH\n", num1, num2);
  packed = pack(num1, num2);
  if (packed == (u_char)-1) {
    printf("Error: One of the number is greater than 0x0f\n");
    exit(1);
  }
  printf("sizeof(packed) = %lu\n", sizeof(packed));
  printf("Packed number = %XH or %dD\n", packed, packed);
  unpacked = unpack(packed);
  printf("Unpacked numbers = %XH and %XH\n", unpacked[0], unpacked[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xc,%edi
  call   <FibonacciAsm@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x90,-0x4(%rbp)
  je     L1
  mov    $0x0,%eax
  call   <abort@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  x = FibonacciAsm(12);
  if (x != 144)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edi
  call   <FibonacciAsm@plt>
  cmp    $0x90,%eax
  jne    L18
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L18:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  x = FibonacciAsm(12);
  if (x != 144)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edi
  call   <FibonacciAsm@plt>
  cmp    $0x90,%eax
  je     L3
  xor    %eax,%eax
  call   <abort@plt>
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  x = FibonacciAsm(12);
  if (x != 144)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edi
  call   <FibonacciAsm@plt>
  cmp    $0x90,%eax
  je     L9
  xor    %eax,%eax
  call   <abort@plt>
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  x = FibonacciAsm(12);
  if (x != 144)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mulvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L17
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mulvec(double *a, double *x, double *y, int m, int n) {
  int i, j;
  for (i = 0; i < m; ++i) {
    y[i] = 0;
    for (j = 0; j < n; ++j)
      y[i] += x[j] * a[i * n + j];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mulvec>:
  endbr64
  test   %ecx,%ecx
  jle    L34
  push   %rbx
  mov    %rdi,%r11
  mov    %rdx,%r9
  lea    -0x1(%rcx),%eax
  lea    0x8(%rdx,%rax,8),%rbx
  mov    $0x0,%r10d
  mov    %r8d,%edi
L37:
  mov    %r9,%rdx
  movq   $0x0,(%r9)
  test   %r8d,%r8d
  jle    L39
  movslq %r10d,%rax
  lea    (%r11,%rax,8),%rcx
  mov    $0x0,%eax
L29:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L29
L39:
  add    $0x8,%r9
  add    %r8d,%r10d
  cmp    %rbx,%r9
  jne    L37
  pop    %rbx
  ret
L34:
  ret
```

assistant: ```c
void mulvec(double *a, double *x, double *y, int m, int n) {
  int i, j;
  for (i = 0; i < m; ++i) {
    y[i] = 0;
    for (j = 0; j < n; ++j)
      y[i] += x[j] * a[i * n + j];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mulvec>:
  endbr64
  test   %ecx,%ecx
  jle    L4
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rdi,%r11
  xor    %r10d,%r10d
  lea    0x8(%rdx,%rax,8),%rbx
  pxor   %xmm2,%xmm2
  lea    -0x1(%r8),%r9d
  mov    %rsi,%rdi
  nopw   0x0(%rax,%rax,1)
L1:
  movq   $0x0,(%rdx)
  test   %r8d,%r8d
  jle    L20
  movslq %r10d,%rax
  movapd %xmm2,%xmm1
  lea    (%r11,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rcx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %r9,%rcx
  jne    L12
L20:
  add    $0x8,%rdx
  add    %r8d,%r10d
  cmp    %rbx,%rdx
  jne    L1
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void mulvec(double *a, double *x, double *y, int m, int n) {
  int i, j;
  for (i = 0; i < m; ++i) {
    y[i] = 0;
    for (j = 0; j < n; ++j)
      y[i] += x[j] * a[i * n + j];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mulvec>:
  endbr64
  test   %ecx,%ecx
  jle    L36
  lea    -0x1(%rcx),%eax
  push   %rbx
  mov    %rdi,%r11
  xor    %r10d,%r10d
  lea    0x8(%rdx,%rax,8),%rbx
  pxor   %xmm2,%xmm2
  lea    -0x1(%r8),%r9d
  mov    %rsi,%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  movq   $0x0,(%rdx)
  test   %r8d,%r8d
  jle    L9
  movslq %r10d,%rax
  movapd %xmm2,%xmm1
  lea    (%r11,%rax,8),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rcx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    %r9,%rcx
  jne    L3
L9:
  add    $0x8,%rdx
  add    %r8d,%r10d
  cmp    %rdx,%rbx
  jne    L5
  pop    %rbx
  ret
L36:
  ret
```

assistant: ```c
void mulvec(double *a, double *x, double *y, int m, int n) {
  int i, j;
  for (i = 0; i < m; ++i) {
    y[i] = 0;
    for (j = 0; j < n; ++j)
      y[i] += x[j] * a[i * n + j];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unhexify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L55
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L61
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L35
L61:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  jmp    L35
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
L35:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L63
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  jmp    L26
L63:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L81
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x37,%eax
  jmp    L26
L81:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  sub    $0x57,%eax
L26:
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x2,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int unhexify(char *in) {
  char *out;
  int i;
  for (i = 0, out = in; *in; in += 2, out++, i++)
    *out = (in[0] <= '9' ? in[0] - '0' : 10 + (in[0] <= 'F' ? in[0] - 'A' : in[0] - 'a')) << 4 | (in[1] <= '9' ? in[1] - '0' : 10 + (in[1] <= 'F' ? in[1] - 'A' : in[1] - 'a'));
  *out = 0;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unhexify>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  mov    %rdi,%rcx
  mov    $0x0,%r8d
  jmp    L81
L54:
  cmp    $0x46,%al
  jg     L7
  shl    $0x4,%eax
  sub    $0x70,%eax
L30:
  movzbl 0x1(%rdi),%edx
  cmp    $0x39,%dl
  jg     L60
  sub    $0x30,%edx
L56:
  or     %edx,%eax
  mov    %al,(%rcx)
  add    $0x2,%rdi
  add    $0x1,%rcx
  add    $0x1,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L71
L81:
  cmp    $0x39,%al
  jg     L54
  shl    $0x4,%eax
  jmp    L30
L7:
  shl    $0x4,%eax
  sub    $0x70,%eax
  jmp    L30
L60:
  lea    -0x37(%rdx),%r9d
  lea    -0x57(%rdx),%esi
  cmp    $0x46,%dl
  mov    %r9d,%edx
  cmovg  %esi,%edx
  jmp    L56
L23:
  mov    %rdi,%rcx
  mov    $0x0,%r8d
L71:
  movb   $0x0,(%rcx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int unhexify(char *in) {
  char *out;
  int i;
  for (i = 0, out = in; *in; in += 2, out++, i++)
    *out = (in[0] <= '9' ? in[0] - '0' : 10 + (in[0] <= 'F' ? in[0] - 'A' : in[0] - 'a')) << 4 | (in[1] <= '9' ? in[1] - '0' : 10 + (in[1] <= 'F' ? in[1] - 'A' : in[1] - 'a'));
  *out = 0;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unhexify>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  test   %al,%al
  jne    L35
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L48:
  sub    $0x30,%edx
L37:
  or     %edx,%eax
  add    $0x2,%rdi
  add    $0x1,%rcx
  add    $0x1,%r8d
  mov    %al,-0x1(%rcx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L70
L35:
  cmp    $0x39,%al
  jle    L7
  cmp    $0x46,%al
  jg     L22
  sub    $0x37,%eax
  shl    $0x4,%eax
L29:
  movzbl 0x1(%rdi),%edx
  cmp    $0x39,%dl
  jle    L48
  lea    -0x37(%rdx),%r9d
  lea    -0x57(%rdx),%esi
  cmp    $0x46,%dl
  mov    %r9d,%edx
  cmovg  %esi,%edx
  jmp    L37
  nopl   0x0(%rax)
L22:
  sub    $0x57,%eax
L7:
  shl    $0x4,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L70:
  movb   $0x0,(%rcx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int unhexify(char *in) {
  char *out;
  int i;
  for (i = 0, out = in; *in; in += 2, out++, i++)
    *out = (in[0] <= '9' ? in[0] - '0' : 10 + (in[0] <= 'F' ? in[0] - 'A' : in[0] - 'a')) << 4 | (in[1] <= '9' ? in[1] - '0' : 10 + (in[1] <= 'F' ? in[1] - 'A' : in[1] - 'a'));
  *out = 0;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unhexify>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  test   %al,%al
  jne    L68
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L71:
  sub    $0x30,%edx
L44:
  or     %edx,%eax
  add    $0x2,%rdi
  add    $0x1,%rcx
  add    $0x1,%r8d
  mov    %al,-0x1(%rcx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
L68:
  cmp    $0x39,%al
  jle    L21
  cmp    $0x46,%al
  jg     L0
  sub    $0x37,%eax
  shl    $0x4,%eax
L77:
  movzbl 0x1(%rdi),%edx
  cmp    $0x39,%dl
  jle    L71
  lea    -0x37(%rdx),%r9d
  lea    -0x57(%rdx),%esi
  cmp    $0x46,%dl
  mov    %r9d,%edx
  cmovg  %esi,%edx
  jmp    L44
  nopl   0x0(%rax)
L0:
  sub    $0x57,%eax
L21:
  shl    $0x4,%eax
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L29:
  movb   $0x0,(%rcx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int unhexify(char *in) {
  char *out;
  int i;
  for (i = 0, out = in; *in; in += 2, out++, i++)
    *out = (in[0] <= '9' ? in[0] - '0' : 10 + (in[0] <= 'F' ? in[0] - 'A' : in[0] - 'a')) << 4 | (in[1] <= '9' ? in[1] - '0' : 10 + (in[1] <= 'F' ? in[1] - 'A' : in[1] - 'a'));
  *out = 0;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xprintf_print_integer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  mov    0x58(%rsp),%r10d
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  je     L79
  test   %ecx,%ecx
  setne  %cl
  cmp    $0xa,%esi
  sete   %dl
  test   %dl,%cl
  je     L48
  test   %eax,%eax
  js     L41
L48:
  mov    %eax,%ecx
  mov    $0x0,%r11d
L26:
  movb   $0x0,0xf(%rsp)
  lea    0xf(%rsp),%rdi
  mov    %esi,%r8d
  mov    0x50(%rsp),%eax
  lea    -0x3a(%rax),%r9d
  jmp    L82
L79:
  test   %r10d,%r10d
  je     L129
  movb   $0x2d,(%rsp)
  mov    $0x1,%r10d
L129:
  movslq %r10d,%rax
  movb   $0x30,(%rsp,%rax,1)
  add    $0x1,%r10d
  movslq %r10d,%r10
  movb   $0x0,(%rsp,%r10,1)
  mov    %rsp,%rsi
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <xprintf_prints@plt>
  jmp    L60
L41:
  neg    %eax
  mov    %eax,%ecx
  mov    $0x1,%r11d
  jmp    L26
L44:
  mov    %eax,%ecx
  mov    %r13,%rdi
L82:
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %esi
  lea    (%rdx,%r9,1),%eax
  cmp    $0x9,%edx
  cmovle %edx,%eax
  lea    -0x1(%rdi),%r13
  add    $0x30,%eax
  mov    %al,-0x1(%rdi)
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %r8d
  cmp    %ecx,%esi
  jbe    L44
  or     %r10d,%r11d
  mov    %r11d,%r14d
  je     L58
  test   %ebx,%ebx
  je     L95
  mov    %ebp,%r14d
  and    $0x1,%r14d
  jne    L72
L95:
  movb   $0x2d,-0x1(%r13)
  lea    -0x2(%rdi),%r13
  mov    $0x0,%r14d
L58:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <xprintf_prints@plt>
  add    %r14d,%eax
L60:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L80
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L72:
  mov    $0x2d,%esi
  mov    %r12,%rdi
  call   <xprintf_putchar@plt>
  sub    $0x1,%ebx
  jmp    L58
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xprintf_print_integer(char **out, int i, int b, int sign, int width, int pad, int base_2nd, int force_neg) {
  char print_buf[16];
  char *s;
  int t, neg = 0, pad_count = 0;
  unsigned int u = i;
  if (i == 0) {
    t = 0;
    if (force_neg) {
      print_buf[t++] = '-';
    }
    print_buf[t++] = '0';
    print_buf[t++] = '\0';
    return xprintf_prints(out, print_buf, width, pad);
  }
  if (sign && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 16 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += base_2nd - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg | force_neg) {
    if (width && (pad & (1 << 0))) {
      xprintf_putchar(out, '-');
      pad_count++;
      width--;
    } else {
      *--s = '-';
    }
  }
  return pad_count + xprintf_prints(out, s, width, pad);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xprintf_print_integer>:
  endbr64
  push   %r14
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq 0x68(%rsp),%rbx
  test   %esi,%esi
  je     L0
  mov    %edx,%edi
  test   %ecx,%ecx
  setne  %dl
  cmp    $0xa,%edi
  sete   %al
  test   %al,%dl
  je     L97
  test   %esi,%esi
  js     L110
L97:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x1f(%rsp)
  lea    0x1f(%rsp),%r10
  lea    -0x3a(%rax),%r8d
  jmp    L76
  xchg   %ax,%ax
L70:
  mov    %eax,%esi
  mov    %r14,%r10
L76:
  xor    %edx,%edx
  mov    %esi,%eax
  lea    -0x1(%r10),%r14
  div    %edi
  cmp    $0x9,%edx
  lea    (%rdx,%r8,1),%ecx
  cmovle %edx,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r10)
  cmp    %esi,%edi
  jbe    L70
  test   %ebx,%ebx
  jne    L57
L52:
  mov    %r9d,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <xprintf_prints@plt>
  add    %ebx,%eax
L120:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  test   %r12d,%r12d
  je     L3
  mov    %r9d,%ebx
  and    $0x1,%ebx
  je     L3
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  mov    %r9d,0xc(%rsp)
  sub    $0x1,%r12d
  call   <xprintf_putchar@plt>
  mov    0xc(%rsp),%r9d
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L3:
  movb   $0x2d,-0x1(%r14)
  xor    %ebx,%ebx
  lea    -0x2(%r10),%r14
  jmp    L52
  nopl   (%rax)
L0:
  mov    $0x1,%eax
  test   %ebx,%ebx
  je     L138
  movb   $0x2d,0x10(%rsp)
  mov    $0x2,%eax
  mov    $0x1,%ebx
L138:
  lea    0x10(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  movb   $0x30,0x10(%rsp,%rbx,1)
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <xprintf_prints@plt>
  jmp    L120
  nopw   0x0(%rax,%rax,1)
L110:
  neg    %esi
  or     $0x1,%ebx
  jmp    L97
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xprintf_print_integer(char **out, int i, int b, int sign, int width, int pad, int base_2nd, int force_neg) {
  char print_buf[16];
  char *s;
  int t, neg = 0, pad_count = 0;
  unsigned int u = i;
  if (i == 0) {
    t = 0;
    if (force_neg) {
      print_buf[t++] = '-';
    }
    print_buf[t++] = '0';
    print_buf[t++] = '\0';
    return xprintf_prints(out, print_buf, width, pad);
  }
  if (sign && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 16 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += base_2nd - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg | force_neg) {
    if (width && (pad & (1 << 0))) {
      xprintf_putchar(out, '-');
      pad_count++;
      width--;
    } else {
      *--s = '-';
    }
  }
  return pad_count + xprintf_prints(out, s, width, pad);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xprintf_print_integer>:
  endbr64
  push   %r13
  mov    %esi,%eax
  mov    %r9d,%r13d
  mov    %edx,%esi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  movslq 0x68(%rsp),%rbx
  test   %eax,%eax
  je     L121
  test   %ecx,%ecx
  setne  %cl
  cmp    $0xa,%esi
  sete   %dl
  test   %dl,%cl
  je     L32
  test   %eax,%eax
  js     L151
L32:
  mov    %eax,%ecx
L131:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x1f(%rsp)
  lea    0x1f(%rsp),%r8
  lea    -0x3a(%rax),%r9d
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L66:
  lea    0x30(%r9,%rdx,1),%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  ja     L34
L149:
  mov    %eax,%ecx
  mov    %rbp,%r8
L67:
  mov    %ecx,%eax
  xor    %edx,%edx
  lea    -0x1(%r8),%rbp
  div    %esi
  cmp    $0x9,%edx
  jg     L66
  add    $0x30,%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  jbe    L149
L34:
  test   %ebx,%ebx
  jne    L109
L148:
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <xprintf_prints@plt>
  add    %ebx,%eax
L157:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L137
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L109:
  test   %r12d,%r12d
  je     L17
  mov    %r13d,%ebx
  and    $0x1,%ebx
  je     L17
  mov    $0x2d,%esi
  mov    %rdi,0x8(%rsp)
  sub    $0x1,%r12d
  call   <xprintf_putchar@plt>
  mov    0x8(%rsp),%rdi
  jmp    L148
  nopw   0x0(%rax,%rax,1)
L17:
  movb   $0x2d,-0x1(%rbp)
  xor    %ebx,%ebx
  lea    -0x2(%r8),%rbp
  jmp    L148
  nopl   0x0(%rax)
L121:
  mov    $0x1,%eax
  test   %ebx,%ebx
  je     L141
  movb   $0x2d,0x10(%rsp)
  mov    $0x2,%eax
  mov    $0x1,%ebx
L141:
  lea    0x10(%rsp),%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  movb   $0x30,0x10(%rsp,%rbx,1)
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <xprintf_prints@plt>
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L151:
  neg    %eax
  or     $0x1,%ebx
  mov    %eax,%ecx
  jmp    L131
L137:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xprintf_print_integer(char **out, int i, int b, int sign, int width, int pad, int base_2nd, int force_neg) {
  char print_buf[16];
  char *s;
  int t, neg = 0, pad_count = 0;
  unsigned int u = i;
  if (i == 0) {
    t = 0;
    if (force_neg) {
      print_buf[t++] = '-';
    }
    print_buf[t++] = '0';
    print_buf[t++] = '\0';
    return xprintf_prints(out, print_buf, width, pad);
  }
  if (sign && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 16 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += base_2nd - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg | force_neg) {
    if (width && (pad & (1 << 0))) {
      xprintf_putchar(out, '-');
      pad_count++;
      width--;
    } else {
      *--s = '-';
    }
  }
  return pad_count + xprintf_prints(out, s, width, pad);
}
```