ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <process_syscall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D4: Esperant rpc al port 8181...


assistant: ```c
int main(int argc, char **argv) {
  printf("Esperant rpc al port 8181...\n");
  process_syscall();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BatchInterpolatedGradX2DTranZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  movsd  %xmm0,-0x58(%rbp)
  movsd  %xmm1,-0x60(%rbp)
  movsd  %xmm2,-0x68(%rbp)
  movsd  %xmm3,-0x70(%rbp)
  movsd  %xmm4,-0x78(%rbp)
  movsd  %xmm5,-0x80(%rbp)
  mov    %r8,-0x88(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L60
L30:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x28(%rbp)
L60:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x28(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x70(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L30
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L59:
  movq   $0x0,-0x20(%rbp)
  jmp    L47
L8:
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x20(%rbp),%xmm0
  subsd  -0x60(%rbp),%xmm0
  divsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x18(%rbp),%xmm0
  subsd  -0x78(%rbp),%xmm0
  divsd  -0x80(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x88(%rbp),%rcx
  movsd  -0x8(%rbp),%xmm3
  movsd  -0x10(%rbp),%xmm2
  movsd  -0x70(%rbp),%xmm0
  mov    -0x58(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <InterpolatedGradXTranZero@plt>
  addq   $0x1,-0x20(%rbp)
L47:
  mov    -0x20(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jl     L8
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jl     L59
  movq   $0x0,-0x28(%rbp)
  jmp    L67
L65:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  -0x68(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x28(%rbp)
L67:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x28(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x70(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L65
  nop
  nop
  leave
  ret
```

assistant: ```c
extern void BatchInterpolatedGradX2DTranZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = 0;
  idx = 0;
  for (idcoordy = 0; idcoordy < Height; idcoordy++) {
    for (idcoordx = 0; idcoordx < Width; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      InterpolatedGradXTranZero(Bout, nx, ny, Bcoeff[idx++], x, y, SplineDegree);
    }
  }
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = Bout[idx] / mx;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BatchInterpolatedGradX2DTranZero>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x68,%rsp
  movsd  %xmm0,0x20(%rsp)
  mulsd  %xmm3,%xmm0
  movsd  %xmm2,0x18(%rsp)
  pxor   %xmm2,%xmm2
  movsd  %xmm1,0x28(%rsp)
  movapd %xmm3,%xmm1
  mov    %rsi,0x48(%rsp)
  mov    %rcx,0x40(%rsp)
  comisd %xmm2,%xmm0
  movsd  %xmm4,0x50(%rsp)
  movsd  %xmm5,0x58(%rsp)
  movsd  %xmm0,0x30(%rsp)
  jbe    L76
  xor    %eax,%eax
  nopl   0x0(%rax)
L96:
  movl   $0x0,(%r15,%rax,4)
  pxor   %xmm0,%xmm0
  add    $0x1,%rax
  movsd  0x30(%rsp),%xmm5
  cvtsi2sd %rax,%xmm0
  comisd %xmm0,%xmm5
  ja     L96
  cmpq   $0x0,0x40(%rsp)
  jle    L31
L22:
  movq   $0x0,0x38(%rsp)
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L47:
  test   %rbx,%rbx
  jle    L21
  mov    0x48(%rsp),%rax
  mov    0x38(%rsp),%rdx
  pxor   %xmm4,%xmm4
  xor    %r14d,%r14d
  cvtsi2sd %r13,%xmm4
  subsd  0x50(%rsp),%xmm4
  divsd  0x58(%rsp),%xmm4
  lea    (%rax,%rdx,4),%rbp
  nopl   0x0(%rax,%rax,1)
L77:
  movsd  0x20(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  mov    %r12,%rsi
  mov    %r15,%rdi
  movss  0x0(%rbp,%r14,4),%xmm2
  cvtsi2sd %r14,%xmm3
  add    $0x1,%r14
  subsd  0x28(%rsp),%xmm3
  movsd  %xmm4,0x10(%rsp)
  divsd  0x18(%rsp),%xmm3
  movsd  %xmm1,0x8(%rsp)
  call   <InterpolatedGradXTranZero@plt>
  cmp    %r14,%rbx
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm4
  jne    L77
  add    %rbx,0x38(%rsp)
L21:
  add    $0x1,%r13
  cmp    %r13,0x40(%rsp)
  jg     L47
L84:
  movsd  0x30(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm2
  jbe    L16
L31:
  xor    %eax,%eax
  nopl   0x0(%rax)
L56:
  pxor   %xmm0,%xmm0
  movsd  0x30(%rsp),%xmm5
  cvtss2sd (%r15,%rax,4),%xmm0
  divsd  0x18(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r15,%rax,4)
  add    $0x1,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  comisd %xmm0,%xmm5
  ja     L56
L16:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  cmpq   $0x0,0x40(%rsp)
  jg     L22
  jmp    L84
```

assistant: ```c
extern void BatchInterpolatedGradX2DTranZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = 0;
  idx = 0;
  for (idcoordy = 0; idcoordy < Height; idcoordy++) {
    for (idcoordx = 0; idcoordx < Width; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      InterpolatedGradXTranZero(Bout, nx, ny, Bcoeff[idx++], x, y, SplineDegree);
    }
  }
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = Bout[idx] / mx;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BatchInterpolatedGradX2DTranZero>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  movsd  %xmm0,0x18(%rsp)
  mulsd  %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  pxor   %xmm2,%xmm2
  movsd  %xmm1,0x20(%rsp)
  movapd %xmm3,%xmm1
  mov    %rcx,0x30(%rsp)
  movsd  %xmm4,0x38(%rsp)
  comisd %xmm2,%xmm0
  movsd  %xmm5,0x40(%rsp)
  movsd  %xmm0,0x28(%rsp)
  jbe    L7
  xor    %eax,%eax
  nop
L8:
  movl   $0x0,(%r14,%rax,4)
  pxor   %xmm0,%xmm0
  add    $0x1,%rax
  movsd  0x28(%rsp),%xmm5
  cvtsi2sd %rax,%xmm0
  comisd %xmm0,%xmm5
  ja     L8
  cmpq   $0x0,0x30(%rsp)
  jle    L84
  test   %rbp,%rbp
  jle    L84
L40:
  lea    0x0(,%rbp,4),%rax
  xor    %r13d,%r13d
  mov    %rax,0x48(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L5:
  pxor   %xmm4,%xmm4
  xor    %r15d,%r15d
  cvtsi2sd %r13,%xmm4
  subsd  0x38(%rsp),%xmm4
  divsd  0x40(%rsp),%xmm4
  nopl   0x0(%rax,%rax,1)
L22:
  movss  (%rbx,%r15,4),%xmm2
  pxor   %xmm3,%xmm3
  mov    %r12,%rsi
  mov    %r14,%rdi
  movsd  0x18(%rsp),%xmm0
  cvtsi2sd %r15,%xmm3
  add    $0x1,%r15
  subsd  0x20(%rsp),%xmm3
  movsd  %xmm4,0x8(%rsp)
  divsd  0x10(%rsp),%xmm3
  movsd  %xmm1,(%rsp)
  call   <InterpolatedGradXTranZero@plt>
  cmp    %r15,%rbp
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm4
  jne    L22
  add    $0x1,%r13
  add    0x48(%rsp),%rbx
  cmp    %r13,0x30(%rsp)
  jg     L5
L101:
  movsd  0x28(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm2
  jbe    L61
L84:
  xor    %eax,%eax
  nopl   (%rax)
L42:
  pxor   %xmm0,%xmm0
  movsd  0x28(%rsp),%xmm5
  cvtss2sd (%r14,%rax,4),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r14,%rax,4)
  add    $0x1,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  comisd %xmm0,%xmm5
  ja     L42
L61:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  cmpq   $0x0,0x30(%rsp)
  jle    L101
  test   %rdx,%rdx
  jg     L40
  jmp    L101
```

assistant: ```c
extern void BatchInterpolatedGradX2DTranZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = 0;
  idx = 0;
  for (idcoordy = 0; idcoordy < Height; idcoordy++) {
    for (idcoordx = 0; idcoordx < Width; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      InterpolatedGradXTranZero(Bout, nx, ny, Bcoeff[idx++], x, y, SplineDegree);
    }
  }
  for (idx = 0; idx < nx * ny; idx++)
    Bout[idx] = Bout[idx] / mx;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<exit_bo_good_unreachable_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <exit@plt>
  movl   $0x2a,0x9c(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void exit_bo_good_unreachable_bad() {
  int arr[1];
  exit(1);
  arr[42] = 42;
}
```
user: What is the c source code of the assembly code below:

```asm
<exit_bo_good_unreachable_bad>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void exit_bo_good_unreachable_bad() {
  int arr[1];
  exit(1);
  arr[42] = 42;
}
```
user: What is the c source code of the assembly code below:

```asm
<exit_bo_good_unreachable_bad>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void exit_bo_good_unreachable_bad() {
  int arr[1];
  exit(1);
  arr[42] = 42;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exit_bo_good_unreachable_bad>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void exit_bo_good_unreachable_bad() {
  int arr[1];
  exit(1);
  arr[42] = 42;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L51
L35:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%esi
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x18(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L40
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  je     L54
L40:
  addl   $0x1,-0x14(%rbp)
  jmp    L9
L54:
  nop
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  je     L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D0: %d


tool: D1: %d%d%d

assistant: ```c
int main() {
  int base, c, b;
  int a;
  int i;
  int carry;
  while (scanf("%d%d%d", &base, &c, &b) == 3) {
    a = c;
    carry = 0;
    for (i = 0; 1; ++i) {
      int t = (a * b + carry);
      carry = t / base;
      a = t % base;
      if (carry == 0 && a == c)
        break;
    }
    printf("%d\n", i + 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D2(%rip),%rbx
  lea    D6(%rip),%r13
  jmp    L0
L13:
  mov    $0x0,%esi
L65:
  add    $0x1,%esi
  imul   %r9d,%ecx
  lea    (%rcx,%r10,1),%eax
  cltd
  idiv   %edi
  mov    %eax,%r10d
  mov    %edx,%ecx
  cmp    %edx,%r8d
  jne    L65
  test   %eax,%eax
  jne    L65
L44:
  add    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L0:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L74
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%r9d
  mov    %r8d,%eax
  imul   %r9d,%eax
  mov    0xc(%rsp),%edi
  cltd
  idiv   %edi
  mov    %eax,%r10d
  mov    %edx,%ecx
  cmp    %edx,%r8d
  jne    L13
  test   %eax,%eax
  jne    L13
  mov    $0x0,%esi
  jmp    L44
L74:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D6
type_infered: string

tool: D2: %d%d%d

tool: D6: %d


assistant: ```c
int main() {
  int base, c, b;
  int a;
  int i;
  int carry;
  while (scanf("%d%d%d", &base, &c, &b) == 3) {
    a = c;
    carry = 0;
    for (i = 0; 1; ++i) {
      int t = (a * b + carry);
      carry = t / base;
      a = t % base;
      if (carry == 0 && a == c)
        break;
    }
    printf("%d\n", i + 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  nopl   (%rax)
L7:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L41
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    %edi,%eax
  imul   %r8d,%eax
  cltd
  idiv   %ecx
  cmp    %edx,%edi
  jne    L17
  test   %eax,%eax
  je     L47
L17:
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L13:
  imul   %r8d,%edx
  add    $0x1,%esi
  add    %edx,%eax
  cltd
  idiv   %ecx
  cmp    %edx,%edi
  jne    L13
  test   %eax,%eax
  jne    L13
L16:
  add    $0x1,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L7
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  xor    %esi,%esi
  jmp    L16
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D13: %d


tool: D12: %d%d%d

assistant: ```c
int main() {
  int base, c, b;
  int a;
  int i;
  int carry;
  while (scanf("%d%d%d", &base, &c, &b) == 3) {
    a = c;
    carry = 0;
    for (i = 0; 1; ++i) {
      int t = (a * b + carry);
      carry = t / base;
      a = t % base;
      if (carry == 0 && a == c)
        break;
    }
    printf("%d\n", i + 1);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  nopl   (%rax)
L52:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L26
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    %edi,%eax
  imul   %r8d,%eax
  cltd
  idiv   %ecx
  cmp    %edx,%edi
  jne    L78
  test   %eax,%eax
  je     L21
L78:
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L15:
  imul   %r8d,%edx
  add    $0x1,%esi
  add    %edx,%eax
  cltd
  idiv   %ecx
  cmp    %edx,%edi
  jne    L15
  test   %eax,%eax
  jne    L15
L49:
  add    $0x1,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L52
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  xor    %esi,%esi
  jmp    L49
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string

tool: D16: %d


tool: D0: %d%d%d

assistant: ```c
int main() {
  int base, c, b;
  int a;
  int i;
  int carry;
  while (scanf("%d%d%d", &base, &c, &b) == 3) {
    a = c;
    carry = 0;
    for (i = 0; 1; ++i) {
      int t = (a * b + carry);
      carry = t / base;
      a = t % base;
      if (carry == 0 && a == c)
        break;
    }
    printf("%d\n", i + 1);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    $0x0,%eax
  jmp    L67
L31:
  mov    -0x18(%rbp),%rax
  jmp    L67
L33:
  movl   $0x0,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  mov    -0x18(%rbp),%rax
  jmp    L67
L69:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L79
  addl   $0x1,-0x4(%rbp)
  jmp    L28
L79:
  nop
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
L67:
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *searchee, const char *lookfor) {
  if (*searchee == 0) {
    if (*lookfor)
      return (char *)((void *)0);
    return (char *)searchee;
  }
  while (*searchee) {
    unsigned int i;
    i = 0;
    while (1) {
      if (lookfor[i] == 0) {
        return (char *)searchee;
      }
      if (lookfor[i] != searchee[i]) {
        break;
      }
      i++;
    }
    searchee++;
  }
  return (char *)((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strstr>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L23
  movzbl (%rsi),%edi
  mov    $0x0,%r9d
L41:
  test   %dil,%dil
  je     L10
  mov    %edi,%ecx
  mov    $0x0,%r8d
  mov    %r9,%rdx
L25:
  cmp    %cl,(%rax,%rdx,1)
  jne    L21
  add    $0x1,%r8d
  mov    %r8d,%edx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L25
  ret
L23:
  cmpb   $0x0,(%rsi)
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
L21:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L41
  mov    $0x0,%eax
  ret
L10:
  ret
```

assistant: ```c
char *strstr(const char *searchee, const char *lookfor) {
  if (*searchee == 0) {
    if (*lookfor)
      return (char *)((void *)0);
    return (char *)searchee;
  }
  while (*searchee) {
    unsigned int i;
    i = 0;
    while (1) {
      if (lookfor[i] == 0) {
        return (char *)searchee;
      }
      if (lookfor[i] != searchee[i]) {
        break;
      }
      i++;
    }
    searchee++;
  }
  return (char *)((void *)0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  movzbl (%rsi),%eax
  jne    L46
  test   %al,%al
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L13
L46:
  test   %al,%al
  je     L55
  mov    %eax,%ecx
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L67
  cs nopw 0x0(%rax,%rax,1)
L26:
  lea    0x1(%r8),%edx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %rdx,%r8
  test   %cl,%cl
  je     L55
L67:
  cmp    %cl,(%rdi,%rdx,1)
  je     L26
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %rdi,%rax
  ret
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strstr(const char *searchee, const char *lookfor) {
  if (*searchee == 0) {
    if (*lookfor)
      return (char *)((void *)0);
    return (char *)searchee;
  }
  while (*searchee) {
    unsigned int i;
    i = 0;
    while (1) {
      if (lookfor[i] == 0) {
        return (char *)searchee;
      }
      if (lookfor[i] != searchee[i]) {
        break;
      }
      i++;
    }
    searchee++;
  }
  return (char *)((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strstr>:
  endbr64
  movzbl (%rdi),%r8d
  movzbl (%rsi),%eax
  test   %r8b,%r8b
  jne    L39
  test   %al,%al
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
  nopl   0x0(%rax)
L12:
  movzbl 0x1(%rdi),%r8d
  add    $0x1,%rdi
  test   %r8b,%r8b
  je     L33
L39:
  test   %al,%al
  je     L19
  mov    %eax,%edx
  xor    %ecx,%ecx
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L60:
  lea    0x1(%rcx),%r8d
  movzbl (%rsi,%r8,1),%edx
  mov    %r8,%rcx
  test   %dl,%dl
  je     L19
  movzbl (%rdi,%r8,1),%r8d
L6:
  cmp    %r8b,%dl
  je     L60
  jmp    L12
  nopl   0x0(%rax)
L19:
  mov    %rdi,%rax
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strstr(const char *searchee, const char *lookfor) {
  if (*searchee == 0) {
    if (*lookfor)
      return (char *)((void *)0);
    return (char *)searchee;
  }
  while (*searchee) {
    unsigned int i;
    i = 0;
    while (1) {
      if (lookfor[i] == 0) {
        return (char *)searchee;
      }
      if (lookfor[i] != searchee[i]) {
        break;
      }
      i++;
    }
    searchee++;
  }
  return (char *)((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void sleep(long sec, long nano) {
  long seconds = sec;
  long nanoseconds = nano;
  struct timespec reqDelay = {seconds, nanoseconds};
  nanosleep(&reqDelay, (struct timespec *)NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sleep>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep(long sec, long nano) {
  long seconds = sec;
  long nanoseconds = nano;
  struct timespec reqDelay = {seconds, nanoseconds};
  nanosleep(&reqDelay, (struct timespec *)NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sleep>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  mov    %rsi,0x8(%rsp)
  xor    %esi,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep(long sec, long nano) {
  long seconds = sec;
  long nanoseconds = nano;
  struct timespec reqDelay = {seconds, nanoseconds};
  nanosleep(&reqDelay, (struct timespec *)NULL);
}
```