ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<VecBug2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    0x180(%rdi),%r13
L77:
  mov    %rsi,%rcx
  mov    $0x0,%eax
L76:
  movzwl (%rcx,%rax,1),%edx
  mov    %dx,(%rsp,%rax,1)
  add    $0x2,%rax
  cmp    $0x30,%rax
  jne    L76
  add    $0x30,%rsi
  cmp    %r13,%rsi
  jne    L77
  jmp    L66
L21:
  add    $0x2,%rbx
  cmp    $0x30,%rbx
  je     L25
L3:
  movzwl 0x0(%rbp,%rbx,1),%eax
  cmp    %ax,(%rsp,%rbx,1)
  je     L21
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L21
L25:
  add    $0x30,%r12
  cmp    %r13,%r12
  je     L27
L66:
  mov    %r12,%rbp
  mov    $0x0,%ebx
  jmp    L3
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VecBug2(short Kernel[8][24]) {
  int k, i;
  short Kernshort2[24] __attribute__((__aligned__(16)));
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernshort2[i] = Kernel[k][i];
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      if (Kernshort2[i] != Kernel[k][i])
        abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<VecBug2>:
  endbr64
  push   %r13
  lea    0x180(%rdi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rax
  xchg   %ax,%ax
L49:
  movdqu (%rax),%xmm0
  movdqu 0x10(%rax),%xmm1
  add    $0x30,%rax
  movdqu -0x10(%rax),%xmm2
  movaps %xmm0,(%r12)
  movaps %xmm1,0x10(%r12)
  movaps %xmm2,0x20(%r12)
  cmp    %rax,%r13
  jne    L49
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L22:
  movzwl 0x0(%rbp,%rbx,1),%eax
  cmp    %ax,(%r12,%rbx,1)
  je     L30
  xor    %eax,%eax
  call   <abort@plt>
L30:
  add    $0x2,%rbx
  cmp    $0x30,%rbx
  jne    L22
  add    $0x30,%rbp
  cmp    %r13,%rbp
  jne    L4
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VecBug2(short Kernel[8][24]) {
  int k, i;
  short Kernshort2[24] __attribute__((__aligned__(16)));
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernshort2[i] = Kernel[k][i];
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      if (Kernshort2[i] != Kernel[k][i])
        abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<VecBug2>:
  endbr64
  push   %r13
  lea    0x180(%rdi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rax
  xchg   %ax,%ax
L22:
  movdqu (%rax),%xmm0
  movdqu 0x10(%rax),%xmm1
  add    $0x30,%rax
  movdqu -0x10(%rax),%xmm2
  movaps %xmm0,(%r12)
  movaps %xmm1,0x10(%r12)
  movaps %xmm2,0x20(%r12)
  cmp    %rax,%r13
  jne    L22
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  movzwl 0x0(%rbp,%rbx,1),%eax
  cmp    %ax,(%r12,%rbx,1)
  je     L23
  xor    %eax,%eax
  call   <abort@plt>
L23:
  add    $0x2,%rbx
  cmp    $0x30,%rbx
  jne    L0
  add    $0x30,%rbp
  cmp    %r13,%rbp
  jne    L35
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VecBug2(short Kernel[8][24]) {
  int k, i;
  short Kernshort2[24] __attribute__((__aligned__(16)));
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      Kernshort2[i] = Kernel[k][i];
  for (k = 0; k < 8; k++)
    for (i = 0; i < 24; i++)
      if (Kernshort2[i] != Kernel[k][i])
        abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<any>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L46
L21:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L0:
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L60
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L0
L60:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x8(%rbp),%eax
  jmp    L37
L31:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    $0xffffffff,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int any(char s1[], char s2[]) {
  int i, j;
  for (i = 0; s1[i] != '\0'; i++) {
    for (j = 0; s2[j] != '\0' && s2[j] != s1[i]; j++)
      ;
    if (s2[j] != '\0') {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<any>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L47
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  setne  %r11b
  mov    $0x0,%r8d
  jmp    L52
L10:
  mov    %r9d,%edx
L85:
  test   %dl,%dl
  jne    L20
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  je     L19
L52:
  mov    %r8d,%r10d
  cmp    %cl,%r9b
  je     L10
  lea    0x1(%rsi),%rax
  test   %r11b,%r11b
  je     L10
L37:
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L85
  test   %dl,%dl
  jne    L37
  jmp    L85
L47:
  mov    $0xffffffff,%r10d
  jmp    L20
L19:
  mov    $0xffffffff,%r10d
L20:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int any(char s1[], char s2[]) {
  int i, j;
  for (i = 0; s1[i] != '\0'; i++) {
    for (j = 0; s2[j] != '\0' && s2[j] != s1[i]; j++)
      ;
    if (s2[j] != '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<any>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L58
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L13
  lea    0x1(%rsi),%rdx
  mov    %r9d,%eax
  jmp    L4
  nopl   0x0(%rax)
L52:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L13
L4:
  cmp    %cl,%al
  jne    L52
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L27
L58:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int any(char s1[], char s2[]) {
  int i, j;
  for (i = 0; s1[i] != '\0'; i++) {
    for (j = 0; s2[j] != '\0' && s2[j] != s1[i]; j++)
      ;
    if (s2[j] != '\0') {
      return i;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<any>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L33
  movzbl (%rsi),%r9d
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r8d,%r10d
  test   %r9b,%r9b
  je     L52
  lea    0x1(%rsi),%rdx
  mov    %r9d,%eax
  jmp    L2
  nopl   0x0(%rax)
L13:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L52
L2:
  cmp    %cl,%al
  jne    L13
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  add    $0x1,%r8
  movzbl (%rdi,%r8,1),%ecx
  test   %cl,%cl
  jne    L38
L33:
  mov    $0xffffffff,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int any(char s1[], char s2[]) {
  int i, j;
  for (i = 0; s1[i] != '\0'; i++) {
    for (j = 0; s2[j] != '\0' && s2[j] != s1[i]; j++)
      ;
    if (s2[j] != '\0') {
      return i;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  D62(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  D21(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x14(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  addss  -0x18(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm1
  movss  D21(%rip),%xmm0
  addss  %xmm1,%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm0,%xmm1
  movss  D21(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D62
type_infered: byte[4]
name: unpack_data
arguments: label: D21
type_infered: byte[4]
name: unpack_data
arguments: label: D73
type_infered: string
name: unpack_data
arguments: label: D43
type_infered: string
name: unpack_data
arguments: label: D72
type_infered: string

tool: {"D62": [0x00,0x00,0x00,0x80]}

tool: {"D21": [0x00,0x00,0x80,0x3f]}

tool: D73: 
Attempt 1:
(a + b) + c = %f

tool: D43: 
a + (b + c) = %f



tool: D72: 
Attempt 2:
(a + b) + c = %f

assistant: ```c
int main(int argc, const char *argv[]) {
  float a, b, c;
  a = powf(10, 8);
  b = a * (-1);
  c = 1;
  printf("\nAttempt 1:\n(a + b) + c = %f", (a + b) + c);
  printf("\na + (b + c) = %f\n\n", a + (b + c));
  float x, result1, result2;
  x = powf(10, 8);
  result1 = (x * -1) + (x + 1);
  result2 = ((x * -1) + x) + 1;
  printf("\nAttempt 2:\n(a + b) + c = %f", result2);
  printf("\na + (b + c) = %f\n\n", result1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movss  %xmm0,0xc(%rsp)
  subss  %xmm0,%xmm0
  addss  D55(%rip),%xmm0
  lea    D29(%rip),%rdi
  call   <printf@plt>
  movss  D55(%rip),%xmm0
  movss  0xc(%rsp),%xmm2
  subss  %xmm2,%xmm0
  addss  %xmm2,%xmm0
  lea    D57(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movss  D55(%rip),%xmm1
  addss  %xmm0,%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  subss  %xmm0,%xmm0
  addss  D55(%rip),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D55
data_type: byte[4]
name: unpack_data
arguments: label: D29
data_type: string
name: unpack_data
arguments: label: D57
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: {"D55": [0x00,0x00,0x80,0x3f]}

tool: D29: 
Attempt 1:
(a + b) + c = %f

tool: D57: 
a + (b + c) = %f



tool: D1: 
Attempt 2:
(a + b) + c = %f

assistant: ```c
int main(int argc, const char *argv[]) {
  float a, b, c;
  a = powf(10, 8);
  b = a * (-1);
  c = 1;
  printf("\nAttempt 1:\n(a + b) + c = %f", (a + b) + c);
  printf("\na + (b + c) = %f\n\n", a + (b + c));
  float x, result1, result2;
  x = powf(10, 8);
  result1 = (x * -1) + (x + 1);
  result2 = ((x * -1) + x) + 1;
  printf("\nAttempt 2:\n(a + b) + c = %f", result2);
  printf("\na + (b + c) = %f\n\n", result1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    $0xa,%edi
  lea    D64(%rip),%rbp
  sub    $0x10,%rsp
  call   <powf@plt>
  lea    D15(%rip),%rdi
  movaps %xmm0,%xmm1
  subss  %xmm0,%xmm0
  addss  D66(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  movss  D66(%rip),%xmm0
  mov    %rbp,%rdi
  subss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movss  D66(%rip),%xmm1
  lea    D4(%rip),%rdi
  addss  %xmm0,%xmm1
  subss  %xmm0,%xmm1
  subss  %xmm0,%xmm0
  addss  D66(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rbp,%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D64
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D66
type_guessed: byte[4]
name: parse_data
arguments: tag: D4
type_guessed: string

tool: D64: 
a + (b + c) = %f



tool: D15: 
Attempt 1:
(a + b) + c = %f

tool: {"D66": [0x00,0x00,0x80,0x3f]}

tool: D4: 
Attempt 2:
(a + b) + c = %f

assistant: ```c
int main(int argc, const char *argv[]) {
  float a, b, c;
  a = powf(10, 8);
  b = a * (-1);
  c = 1;
  printf("\nAttempt 1:\n(a + b) + c = %f", (a + b) + c);
  printf("\na + (b + c) = %f\n\n", a + (b + c));
  float x, result1, result2;
  x = powf(10, 8);
  result1 = (x * -1) + (x + 1);
  result2 = ((x * -1) + x) + 1;
  printf("\nAttempt 2:\n(a + b) + c = %f", result2);
  printf("\na + (b + c) = %f\n\n", result1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    $0xa,%edi
  lea    D42(%rip),%rbp
  sub    $0x10,%rsp
  call   <powf@plt>
  lea    D1(%rip),%rdi
  movaps %xmm0,%xmm1
  subss  %xmm0,%xmm0
  addss  D52(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  movss  D52(%rip),%xmm0
  mov    %rbp,%rdi
  subss  %xmm1,%xmm0
  addss  %xmm1,%xmm0
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <powf@plt>
  movss  D52(%rip),%xmm1
  lea    D7(%rip),%rdi
  addss  %xmm0,%xmm1
  subss  %xmm0,%xmm1
  subss  %xmm0,%xmm0
  addss  D52(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rbp,%rdi
  movaps %xmm1,%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D42
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D52
type_guessed: byte[4]
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D42: 
a + (b + c) = %f



tool: D1: 
Attempt 1:
(a + b) + c = %f

tool: {"D52": [0x00,0x00,0x80,0x3f]}

tool: D7: 
Attempt 2:
(a + b) + c = %f

assistant: ```c
int main(int argc, const char *argv[]) {
  float a, b, c;
  a = powf(10, 8);
  b = a * (-1);
  c = 1;
  printf("\nAttempt 1:\n(a + b) + c = %f", (a + b) + c);
  printf("\na + (b + c) = %f\n\n", a + (b + c));
  float x, result1, result2;
  x = powf(10, 8);
  result1 = (x * -1) + (x + 1);
  result2 = ((x * -1) + x) + 1;
  printf("\nAttempt 2:\n(a + b) + c = %f", result2);
  printf("\na + (b + c) = %f\n\n", result1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  imul   -0x34(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  movd   %edx,%xmm0
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  ja     L19
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D8
type: string

tool: D9: w

tool: D8: %f


assistant: ```c
void dump_result(float *f, int nx, int ny, int nz, char *out_path) {
  FILE *out = fopen(out_path, "w");
  assert(out);
  size_t nitems = nx * ny * nz;
  int i;
  for (i = 0; i < nitems; ++i) {
    fprintf(out, "%f\n", f[i]);
  }
  fclose(out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_result>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %ecx,%ebx
  mov    %r8,%rdi
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  imul   %r14d,%ebp
  imul   %ebx,%ebp
  movslq %ebp,%rbp
  test   %rbp,%rbp
  je     L6
  mov    $0x0,%ebx
  lea    D14(%rip),%r14
L17:
  movss  0x0(%r13,%rbx,4),%xmm0
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
L6:
  mov    %r12,%rdi
  call   <fclose@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: string

tool: D3: w

tool: D14: %f


assistant: ```c
void dump_result(float *f, int nx, int ny, int nz, char *out_path) {
  FILE *out = fopen(out_path, "w");
  assert(out);
  size_t nitems = nx * ny * nz;
  int i;
  for (i = 0; i < nitems; ++i) {
    fprintf(out, "%f\n", f[i]);
  }
  fclose(out);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_result>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %esi,%ebp
  lea    D19(%rip),%rsi
  imul   %r14d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <fopen@plt>
  imul   %ebx,%ebp
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <assert@plt>
  movslq %ebp,%rbp
  test   %rbp,%rbp
  je     L14
  xor    %ebx,%ebx
  lea    D0(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L11:
  movss  (%r12,%rbx,4),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%rbp
  jne    L11
L14:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <fclose@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D19: w

tool: D0: %f


assistant: ```c
void dump_result(float *f, int nx, int ny, int nz, char *out_path) {
  FILE *out = fopen(out_path, "w");
  assert(out);
  size_t nitems = nx * ny * nz;
  int i;
  for (i = 0; i < nitems; ++i) {
    fprintf(out, "%f\n", f[i]);
  }
  fclose(out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_result>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %esi,%ebp
  lea    D7(%rip),%rsi
  imul   %r14d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <fopen@plt>
  imul   %ebx,%ebp
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <assert@plt>
  movslq %ebp,%rbp
  test   %rbp,%rbp
  je     L5
  xor    %ebx,%ebx
  lea    D19(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L11:
  movss  (%r12,%rbx,4),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%rbp
  jne    L11
L5:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <fclose@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string

tool: D7: w

tool: D19: %f


assistant: ```c
void dump_result(float *f, int nx, int ny, int nz, char *out_path) {
  FILE *out = fopen(out_path, "w");
  assert(out);
  size_t nitems = nx * ny * nz;
  int i;
  for (i = 0; i < nitems; ++i) {
    fprintf(out, "%f\n", f[i]);
  }
  fclose(out);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<log_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  call   <log_print@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list args;
  va_start(args, format);
  log_print(6, format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log_info>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x6,%edi
  call   <log_print@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list args;
  va_start(args, format);
  log_print(6, format, args);
  va_end(args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x6,%edi
  call   <log_print@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list args;
  va_start(args, format);
  log_print(6, format, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x6,%edi
  call   <log_print@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_info(const char *format, ...) {
  va_list args;
  va_start(args, format);
  log_print(6, format, args);
  va_end(args);
}
```