ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<find_next_bit>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rax
  cmp    %rsi,%rdx
  jae    L78
  mov    %rdx,%rax
  shr    $0x6,%rax
  lea    (%rdi,%rax,8),%rdi
  mov    %rdx,%rax
  and    $0xffffffffffffffc0,%rax
  sub    %rax,%rsi
  and    $0x3f,%ecx
  jne    L69
L0:
  test   $0xffffffffffffffc0,%rsi
  je     L7
  lea    (%rax,%rsi,1),%rcx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x40,%rax
  mov    %rcx,%rsi
  sub    %rax,%rsi
  test   $0xffffffffffffffc0,%rsi
  je     L7
L41:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  test   %rdx,%rdx
  je     L49
L29:
  tzcnt  %rdx,%rdx
  movslq %edx,%rdx
  add    %rdx,%rax
L78:
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  mov    $0xffffffffffffffff,%rdx
  shl    %cl,%rdx
  and    (%rdi),%rdx
  cmp    $0x3f,%rsi
  jbe    L24
  test   %rdx,%rdx
  jne    L29
  add    $0x8,%rdi
  sub    $0x40,%rsi
  add    $0x40,%rax
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L7:
  test   %rsi,%rsi
  je     L78
  mov    (%rdi),%rdx
L24:
  mov    $0x40,%ecx
  mov    $0xffffffffffffffff,%rdi
  sub    %esi,%ecx
  shr    %cl,%rdi
  and    %rdi,%rdx
  jne    L29
  add    %rsi,%rax
  ret
```

assistant: ```c
unsigned long find_next_bit(const unsigned long *addr, unsigned long size, unsigned long offset) {
  const unsigned long *p = addr + ((offset) / ((int)((sizeof(long) * 8))));
  unsigned long result = offset & ~(((int)((sizeof(long) * 8))) - 1);
  unsigned long tmp;
  if (offset >= size)
    return size;
  size -= result;
  offset %= ((int)((sizeof(long) * 8)));
  if (offset) {
    tmp = *(p++);
    tmp &= (~0UL << offset);
    if (size < ((int)((sizeof(long) * 8))))
      goto found_first;
    if (tmp)
      goto found_middle;
    size -= ((int)((sizeof(long) * 8)));
    result += ((int)((sizeof(long) * 8)));
  }
  while (size & ~(((int)((sizeof(long) * 8))) - 1)) {
    if ((tmp = *(p++)))
      goto found_middle;
    result += ((int)((sizeof(long) * 8)));
    size -= ((int)((sizeof(long) * 8)));
  }
  if (!size)
    return result;
  tmp = *p;
found_first:
  tmp &= (~0UL >> (((int)((sizeof(long) * 8))) - size));
  if (tmp == 0UL)
    return result + size;
found_middle:
  return result + (__builtin_ffsl(tmp) - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
void print_arr(int A[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%d\n", A[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D9(%rip),%rbp
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
void print_arr(int A[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%d\n", A[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %d


assistant: ```c
void print_arr(int A[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%d\n", A[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
void print_arr(int A[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%d\n", A[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <Log0@plt>
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <Log1@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <Log2@plt>
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <Log3@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D11: Log 0

tool: D1: Log 1

tool: D20: Log 2

tool: D16: Log 3

assistant: ```c
int main(void) {
  Log0("Log 0");
  Log1("Log 1", 1);
  Log2("Log 2", 1, 2);
  Log3("Log 3", 1, 2, 3);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <Log0@plt>
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <Log1@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <Log2@plt>
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  call   <Log3@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string

tool: D2: Log 0

tool: D3: Log 1

tool: D38: Log 2

tool: D23: Log 3

assistant: ```c
int main(void) {
  Log0("Log 0");
  Log1("Log 1", 1);
  Log2("Log 2", 1, 2);
  Log3("Log 3", 1, 2, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <Log0@plt>
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  call   <Log1@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  call   <Log2@plt>
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <Log3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D33
datatype: string
name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D7
datatype: string

tool: D24: Log 0

tool: D33: Log 1

tool: D29: Log 2

tool: D7: Log 3

assistant: ```c
int main(void) {
  Log0("Log 0");
  Log1("Log 1", 1);
  Log2("Log 2", 1, 2);
  Log3("Log 3", 1, 2, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <Log0@plt>
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  call   <Log1@plt>
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <Log2@plt>
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D22(%rip),%rdi
  call   <Log3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D38
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string

tool: D36: Log 0

tool: D27: Log 1

tool: D38: Log 2

tool: D22: Log 3

assistant: ```c
int main(void) {
  Log0("Log 0");
  Log1("Log 1", 1);
  Log2("Log 2", 1, 2);
  Log3("Log 3", 1, 2, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<id_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L27
  cmpl   $0x10,-0xc(%rbp)
  jle    L47
  movl   $0x10,-0xc(%rbp)
  jmp    L47
L50:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%al
  je     L47
  mov    $0x0,%eax
  jmp    L25
L47:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L50
  mov    $0x1,%eax
  jmp    L25
L27:
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int id_match(char *name, int len, char *id) {
  if (len == id[0]) {
    if (len > 16)
      len = 16;
    while (len--) {
      if (toupper(name[len]) != id[1 + len])
        return (0);
    }
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<id_match>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  movsbl (%rdx),%edx
  mov    $0x0,%eax
  cmp    %esi,%edx
  je     L49
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  mov    %rdi,%r12
  mov    $0x10,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  movslq %esi,%rbx
  mov    %esi,%esi
  mov    %rbx,%r13
  sub    %rsi,%r13
L15:
  cmp    %r13,%rbx
  je     L30
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <toupper@plt>
  sub    $0x1,%rbx
  cmp    0x1(%rbp,%rbx,1),%al
  je     L15
  mov    $0x0,%eax
  jmp    L43
L30:
  mov    $0x1,%eax
  jmp    L43
```

assistant: ```c
int id_match(char *name, int len, char *id) {
  if (len == id[0]) {
    if (len > 16)
      len = 16;
    while (len--) {
      if (toupper(name[len]) != id[1 + len])
        return (0);
    }
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<id_match>:
  endbr64
  movsbl (%rdx),%eax
  cmp    %esi,%eax
  je     L24
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L24:
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x10,%edx
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%eax
  cmovg  %edx,%eax
  movslq %eax,%rbx
  mov    %eax,%eax
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L20:
  movsbl -0x1(%r12,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <toupper@plt>
  cmp    0x1(%rbp,%rbx,1),%al
  jne    L38
L5:
  cmp    %r13,%rbx
  jne    L20
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int id_match(char *name, int len, char *id) {
  if (len == id[0]) {
    if (len > 16)
      len = 16;
    while (len--) {
      if (toupper(name[len]) != id[1 + len])
        return (0);
    }
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<id_match>:
  endbr64
  movsbl (%rdx),%eax
  cmp    %esi,%eax
  je     L0
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L0:
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x10,%edx
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%eax
  cmovg  %edx,%eax
  movslq %eax,%rbx
  mov    %eax,%eax
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl -0x1(%r12,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <toupper@plt>
  cmp    0x1(%rbp,%rbx,1),%al
  jne    L26
L13:
  cmp    %r13,%rbx
  jne    L5
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int id_match(char *name, int len, char *id) {
  if (len == id[0]) {
    if (len > 16)
      len = 16;
    while (len--) {
      if (toupper(name[len]) != id[1 + len])
        return (0);
    }
    return (1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_Pythagorean_triplet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,%edx
  jne    L1
  mov    $0x1,%eax
  jmp    L11
L1:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int is_Pythagorean_triplet(int a, int b, int c) {
  if ((a * a + b * b) == c * c)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_Pythagorean_triplet>:
  endbr64
  imul   %edi,%edi
  imul   %esi,%esi
  add    %esi,%edi
  imul   %edx,%edx
  cmp    %edx,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_Pythagorean_triplet(int a, int b, int c) {
  if ((a * a + b * b) == c * c)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_Pythagorean_triplet>:
  endbr64
  imul   %esi,%esi
  xor    %eax,%eax
  imul   %edi,%edi
  imul   %edx,%edx
  add    %esi,%edi
  cmp    %edx,%edi
  sete   %al
  ret
```

assistant: ```c
int is_Pythagorean_triplet(int a, int b, int c) {
  if ((a * a + b * b) == c * c)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_Pythagorean_triplet>:
  endbr64
  imul   %esi,%esi
  xor    %eax,%eax
  imul   %edi,%edi
  imul   %edx,%edx
  add    %esi,%edi
  cmp    %edx,%edi
  sete   %al
  ret
```

assistant: ```c
int is_Pythagorean_triplet(int a, int b, int c) {
  if ((a * a + b * b) == c * c)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r9
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <tparam1@plt>
  cltq
  leave
  ret
```

assistant: ```c
char *tparam(string, outstring, len, arg0, arg1, arg2, arg3)
char *string;
char *outstring;
int len;
int arg0, arg1, arg2, arg3;
{ return tparam1(string, outstring, len, (char *)0, (char *)0, &arg0); }
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tparam>:
  endbr64
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  lea    0xc(%rsp),%r9
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%eax
  call   <tparam1@plt>
  cltq
  add    $0x18,%rsp
  ret
```

assistant: ```c
char *tparam(string, outstring, len, arg0, arg1, arg2, arg3)
char *string;
char *outstring;
int len;
int arg0, arg1, arg2, arg3;
{ return tparam1(string, outstring, len, (char *)0, (char *)0, &arg0); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tparam>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    %ecx,0xc(%rsp)
  lea    0xc(%rsp),%r9
  xor    %ecx,%ecx
  call   <tparam1@plt>
  add    $0x18,%rsp
  cltq
  ret
```

assistant: ```c
char *tparam(string, outstring, len, arg0, arg1, arg2, arg3)
char *string;
char *outstring;
int len;
int arg0, arg1, arg2, arg3;
{ return tparam1(string, outstring, len, (char *)0, (char *)0, &arg0); }
```
user: Translate the below assembly code into C programming language:

```asm
<tparam>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    %ecx,0xc(%rsp)
  lea    0xc(%rsp),%r9
  xor    %ecx,%ecx
  call   <tparam1@plt>
  add    $0x18,%rsp
  cltq
  ret
```

assistant: ```c
char *tparam(string, outstring, len, arg0, arg1, arg2, arg3)
char *string;
char *outstring;
int len;
int arg0, arg1, arg2, arg3;
{ return tparam1(string, outstring, len, (char *)0, (char *)0, &arg0); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    %r12d,%edi
  call   <omp_set_num_threads@plt>
  mov    %ebp,%edi
  imul   %ebp,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jle    L21
  movslq %ebp,%r12
  lea    0x0(,%r12,8),%r10
  lea    -0x1(%rbp),%eax
  lea    0x8(%rbx,%rax,8),%rcx
  mov    $0x0,%r8d
  mov    %ebp,%edi
  neg    %rdi
  shl    $0x3,%rdi
L47:
  mov    %r8d,%esi
  lea    (%rdi,%rcx,1),%rax
  mov    $0x0,%edx
L86:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  add    %esi,%edx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L86
  lea    0x1(%r8),%r9d
  add    %r10,%rcx
  cmp    %r9d,%ebp
  je     L18
  mov    %r9d,%r8d
  jmp    L47
L18:
  mov    %r9d,%esi
  mov    $0x0,%ebp
  mov    $0x1,%ecx
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  jmp    L2
L61:
  add    $0x1,%eax
  add    %edi,%edx
  cmp    %eax,%esi
  je     L107
L27:
  test   %ecx,%ecx
  je     L61
  movslq %eax,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ucomisd (%rbx,%rcx,8),%xmm0
  setnp  %cl
  movzbl %cl,%ecx
  cmovne %r10d,%ecx
  jmp    L61
L107:
  lea    0x1(%r11),%eax
  add    %r9d,%esi
  add    %r9d,%ebp
  cmp    %r11d,%r8d
  je     L109
  mov    %eax,%r11d
L2:
  mov    %r11d,%edi
  mov    %ebp,%eax
  mov    $0x0,%edx
  jmp    L27
L109:
  test   %ecx,%ecx
  jne    L21
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L21:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L37:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D10: Resultado erroneo 


tool: D11: Resultado correcto


assistant: ```c
main(int argc, char *argv[]) {
  double *A;
  int i, j;
  int check = 1;
  int numThreads = atoi(argv[2]);
  int N = atoi(argv[1]);
  omp_set_num_threads(numThreads);
  A = (double *)malloc(sizeof(double) * N * N);
  for (i = 0; i < N; i++) {
#pragma omp parallel for shared(A) private(i, j)
    for (j = 0; j < N; j++) {
      A[i * N + j] = i * j;
    }
  }
  for (i = 0; i < N; i++) {
    for (j = 0; j < N; j++) {
      check = check && (A[i * N + j] == i * j);
    }
  }
  if (check) {
    printf("Resultado correcto\n");
  } else {
    printf("Resultado erroneo \n");
  }
  free(A);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%edi
  movslq %eax,%r12
  call   <omp_set_num_threads@plt>
  mov    %r12d,%edi
  imul   %r12d,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L144
  lea    -0x1(%r12),%r8d
  lea    0x8(%rbp),%rdi
  mov    %r12,%rbx
  xor    %esi,%esi
  lea    0x0(,%r8,8),%rax
  mov    $0xfffffffffffffff8,%r10
  lea    0x0(,%r12,8),%r9
  lea    (%rdi,%rax,1),%rcx
  sub    %rax,%r10
L134:
  lea    (%r10,%rcx,1),%rax
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L64:
  pxor   %xmm0,%xmm0
  add    $0x8,%rax
  cvtsi2sd %edx,%xmm0
  add    %esi,%edx
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L64
  lea    0x1(%rsi),%eax
  add    %r9,%rcx
  cmp    %eax,%ebx
  je     L60
  mov    %eax,%esi
  jmp    L134
  cs nopw 0x0(%rax,%rax,1)
L60:
  mov    $0x1,%r9d
  xor    %r10d,%r10d
  xor    %ecx,%ecx
  test   %r9d,%r9d
  je     L108
L2:
  movslq %r10d,%rdx
  lea    0x0(%rbp,%rdx,8),%rax
  add    %r8,%rdx
  lea    (%rdi,%rdx,8),%r11
  xor    %edx,%edx
L54:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  ucomisd (%rax),%xmm0
  jp     L83
  jne    L83
  add    $0x8,%rax
  add    %ecx,%edx
  cmp    %rax,%r11
  jne    L54
  nopl   0x0(%rax)
L71:
  lea    0x1(%rcx),%eax
  add    %ebx,%r10d
  cmp    %ecx,%esi
  je     L145
L105:
  mov    %eax,%ecx
  test   %r9d,%r9d
  jne    L2
L108:
  lea    0x1(%rcx),%eax
  add    %ebx,%r10d
  cmp    %ecx,%esi
  je     L17
  mov    %eax,%ecx
  add    %ebx,%r10d
  lea    0x1(%rcx),%eax
  cmp    %ecx,%esi
  jne    L105
L145:
  test   %r9d,%r9d
  je     L17
L144:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L10:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L83:
  xor    %r9d,%r9d
  jmp    L71
L17:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D6
data_type: string

tool: D13: Resultado correcto


tool: D6: Resultado erroneo 


assistant: ```c
main(int argc, char *argv[]) {
  double *A;
  int i, j;
  int check = 1;
  int numThreads = atoi(argv[2]);
  int N = atoi(argv[1]);
  omp_set_num_threads(numThreads);
  A = (double *)malloc(sizeof(double) * N * N);
  for (i = 0; i < N; i++) {
#pragma omp parallel for shared(A) private(i, j)
    for (j = 0; j < N; j++) {
      A[i * N + j] = i * j;
    }
  }
  for (i = 0; i < N; i++) {
    for (j = 0; j < N; j++) {
      check = check && (A[i * N + j] == i * j);
    }
  }
  if (check) {
    printf("Resultado correcto\n");
  } else {
    printf("Resultado erroneo \n");
  }
  free(A);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  lea    -0x20(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x30(%rbp),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%ecx
  mov    D52(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    D36(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    D48(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x34(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int getch(void) {
  struct termios term, oterm;
  int c = 0;
  tcgetattr(0, &oterm);
  memcpy(&term, &oterm, sizeof(term));
  term.c_lflag &= ~(ICANON | ECHO);
  term.c_cc[VMIN] = 1;
  term.c_cc[VTIME] = 0;
  tcsetattr(0, TCSANOW, &term);
  c = getchar();
  tcsetattr(0, TCSANOW, &oterm);
  return c;
}
```