user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xb8,%rsp
  lea    D35(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x10a8(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  je     L37
  lea    0x870(%rsp),%rax
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0x18(%rsp),%r15
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  mov    %r15,%rsi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  movslq %eax,%r13
  lea    0x1(%r13),%r14d
  lea    0x0(,%r14,4),%edi
  call   <malloc@plt>
  test   %r13d,%r13d
  movdqa D26(%rip),%xmm2
  mov    %rax,%r15
  js     L144
  cmp    $0x2,%r13d
  jle    L19
  mov    %r14d,%edx
  movdqa D0(%rip),%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rax,%rdx,1),%rdx
  nopl   (%rax)
L11:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L11
  mov    %r14d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r14b
  je     L69
L2:
  movslq %eax,%rdx
  mov    %eax,(%r15,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r13d
  jl     L69
  add    $0x2,%eax
  mov    %edx,0x4(%r15,%rcx,1)
  cmp    %eax,%r13d
  jl     L69
  mov    %eax,0x8(%r15,%rcx,1)
L69:
  movslq %r14d,%rax
L108:
  test   %ebp,%ebp
  jle    L38
  lea    0x1(%rbp),%eax
  movslq %r14d,%r14
  mov    0x18(%rsp),%r11
  mov    %eax,0xc(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x8(%r15,%rax,4),%rbp
  lea    -0x4(%r15,%r14,4),%rax
  mov    $0x1,%r14d
  mov    %rax,0x10(%rsp)
  nopl   (%rax)
L131:
  mov    %r15,%rax
  mov    %r14d,%edx
  test   %r13d,%r13d
  jle    L57
  mov    (%r15),%r9d
  mov    %r12,%r8
  lea    0x4(%r15),%rax
  mov    %r14d,%edi
  jmp    L164
  nopw   0x0(%rax,%rax,1)
L48:
  cmp    %edi,%esi
  lea    0x1(%rsi),%ebx
  mov    %edi,(%r10)
  cmovle %ebx,%ecx
  cmp    %edx,%ecx
  cmovle %ecx,%edx
  add    $0x4,%rax
  add    $0x1,%r8
  cmp    %rbp,%rax
  je     L9
L155:
  mov    %edx,%edi
L164:
  mov    %r9d,%esi
  mov    (%rax),%r9d
  movzbl (%r11),%ebx
  lea    -0x4(%rax),%r10
  lea    0x1(%rdi),%ecx
  lea    0x1(%r9),%edx
  cmp    %bl,(%r8)
  jne    L48
  cmp    %ecx,%esi
  mov    %edi,(%r10)
  cmovg  %ecx,%esi
  cmp    %edx,%esi
  cmovle %esi,%edx
  add    $0x4,%rax
  add    $0x1,%r8
  cmp    %rbp,%rax
  jne    L155
L9:
  mov    0x10(%rsp),%rax
L57:
  mov    %edx,(%rax)
  add    $0x1,%r14d
  add    $0x1,%r11
  cmp    0xc(%rsp),%r14d
  jne    L131
  mov    %edx,%ebx
L20:
  mov    %ebx,(%rax)
  mov    (%r15,%r13,4),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  subl   $0x1,0x2c(%rsp)
  jne    L1
L37:
  mov    0x10a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x10b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  lea    -0x4(%r15,%rax,4),%rax
  jmp    L20
L144:
  xor    %eax,%eax
  jmp    L108
L19:
  xor    %eax,%eax
  jmp    L2
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
datatype: string
name: extract_symbolic_data
arguments: data_label: D57
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D0
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D21
datatype: string

tool: D35: %d

tool: D57: %s

tool: {"D26": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D21: %d


assistant: ```c
int main() {
  int T, i, j;
  char s1[2100], s2[2100];
  int *Val;
  scanf("%d", &T);
  while (T != 0) {
    scanf("%s", s1);
    scanf("%s", s2);
    int l1 = strlen(s1);
    int l2 = strlen(s2);
    Val = (int *)malloc((l2 + 1) * sizeof(int));
    for (j = 0; j <= l2; j++) {
      Val[j] = j;
    }
    int curr;
    for (i = 1; i <= l1; i++) {
      curr = i;
      int curr2;
      for (j = 1; j <= l2; j++) {
        if (s1[i - 1] == s2[j - 1]) {
          int min = Val[j - 1];
          if (min > (curr + 1)) {
            min = curr + 1;
          }
          if (min > (Val[j] + 1)) {
            min = Val[j] + 1;
          }
          curr2 = min;
        } else {
          int min = Val[j - 1] + 1;
          if (min > (curr + 1)) {
            min = curr + 1;
          }
          if (min > (Val[j] + 1)) {
            min = Val[j] + 1;
          }
          curr2 = min;
        }
        Val[j - 1] = curr;
        curr = curr2;
      }
      Val[j - 1] = curr;
    }
    Val[j - 1] = curr;
    printf("%d\n", Val[l2]);
    T--;
  }
  return 0;
}
```