ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<mygetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L13:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L32:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L6
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L6
  cmpl   $0xa,-0x8(%rbp)
  jne    L13
L6:
  cmpl   $0xa,-0x8(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<mygetline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L67
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L22:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L11
  cmp    $0xa,%eax
  je     L11
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L22
  mov    %r12d,%ebx
  jmp    L59
L67:
  mov    $0x0,%ebx
L11:
  cmp    $0xa,%eax
  je     L18
L59:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L59
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mygetline>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L44
  mov    D6(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L54:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L59
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %ebp,%edx
  je     L30
  mov    %edx,%r14d
L55:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L54
  cmp    $0xa,%eax
  je     L5
L44:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  lea    0x1(%r14),%edx
L59:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mygetline>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L42
  mov    D1(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L43:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L57
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %ebp,%edx
  je     L51
  mov    %edx,%r14d
L22:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L43
  cmp    $0xa,%eax
  je     L56
L42:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  lea    0x1(%r14),%edx
L57:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L51:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mygetline(char s[], int lim) {
  int c, i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lelomemset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *lelomemset(void *s, int c, int n) {
  int i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lelomemset>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L4
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%r8d
  add    %rdi,%r8
L17:
  mov    %sil,(%rcx)
  mov    %rcx,%rdx
  add    $0x1,%rcx
  cmp    %r8,%rdx
  jne    L17
L4:
  ret
```

assistant: ```c
void *lelomemset(void *s, int c, int n) {
  int i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lelomemset>:
  endbr64
  test   %edx,%edx
  jle    L1
  sub    $0x8,%rsp
  movslq %edx,%rdx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *lelomemset(void *s, int c, int n) {
  int i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lelomemset>:
  endbr64
  test   %edx,%edx
  jle    L6
  sub    $0x8,%rsp
  movslq %edx,%rdx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *lelomemset(void *s, int c, int n) {
  int i;
  char *ss = (char *)s;
  for (i = 0; i < n; i++)
    ss[i] = c;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: e:	edit blank diff
eb:	edit both diffs concatenated
el:	edit left diff
er:	edit right diff
l | 1:	choose left diff
r | 2:	choose right diff
s:	silent mode--don't print identical lines
v:	verbose mode--print identical lines
q:	quit

assistant: ```c
void int_usage(void) {
  puts("e:\tedit blank diff\n"
       "eb:\tedit both diffs concatenated\n"
       "el:\tedit left diff\n"
       "er:\tedit right diff\n"
       "l | 1:\tchoose left diff\n"
       "r | 2:\tchoose right diff\n"
       "s:\tsilent mode--don't print identical lines\n"
       "v:\tverbose mode--print identical lines\n"
       "q:\tquit");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<int_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: e:	edit blank diff
eb:	edit both diffs concatenated
el:	edit left diff
er:	edit right diff
l | 1:	choose left diff
r | 2:	choose right diff
s:	silent mode--don't print identical lines
v:	verbose mode--print identical lines
q:	quit

assistant: ```c
void int_usage(void) {
  puts("e:\tedit blank diff\n"
       "eb:\tedit both diffs concatenated\n"
       "el:\tedit left diff\n"
       "er:\tedit right diff\n"
       "l | 1:\tchoose left diff\n"
       "r | 2:\tchoose right diff\n"
       "s:\tsilent mode--don't print identical lines\n"
       "v:\tverbose mode--print identical lines\n"
       "q:\tquit");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<int_usage>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: e:	edit blank diff
eb:	edit both diffs concatenated
el:	edit left diff
er:	edit right diff
l | 1:	choose left diff
r | 2:	choose right diff
s:	silent mode--don't print identical lines
v:	verbose mode--print identical lines
q:	quit

assistant: ```c
void int_usage(void) {
  puts("e:\tedit blank diff\n"
       "eb:\tedit both diffs concatenated\n"
       "el:\tedit left diff\n"
       "er:\tedit right diff\n"
       "l | 1:\tchoose left diff\n"
       "r | 2:\tchoose right diff\n"
       "s:\tsilent mode--don't print identical lines\n"
       "v:\tverbose mode--print identical lines\n"
       "q:\tquit");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<int_usage>:
  endbr64
  lea    D8(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: e:	edit blank diff
eb:	edit both diffs concatenated
el:	edit left diff
er:	edit right diff
l | 1:	choose left diff
r | 2:	choose right diff
s:	silent mode--don't print identical lines
v:	verbose mode--print identical lines
q:	quit

assistant: ```c
void int_usage(void) {
  puts("e:\tedit blank diff\n"
       "eb:\tedit both diffs concatenated\n"
       "el:\tedit left diff\n"
       "er:\tedit right diff\n"
       "l | 1:\tchoose left diff\n"
       "r | 2:\tchoose right diff\n"
       "s:\tsilent mode--don't print identical lines\n"
       "v:\tverbose mode--print identical lines\n"
       "q:\tquit");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trees>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  ja     L27
  mov    $0x1,%eax
  jmp    L3
L27:
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L32
L33:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <trees>
  mov    %rax,%rbx
  mov    -0x24(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <trees>
  imul   %rbx,%rax
  add    %rax,%rax
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L33
  mov    -0x18(%rbp),%rax
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long long trees(unsigned n) {
  if (n <= 1) {
    return 1;
  }
  unsigned long long res = 0;
  unsigned i;
  for (i = 0; i < n; i++) {
    res += 2 * trees(i) * trees(n - i - 1);
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trees>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r12d
  cmp    $0x1,%edi
  jbe    L3
  mov    %edi,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    -0x1(%rdi),%r14d
L8:
  mov    %ebp,%edi
  call   <trees>
  mov    %rax,%rbx
  mov    %r14d,%edi
  sub    %ebp,%edi
  call   <trees>
  imul   %rax,%rbx
  lea    (%r12,%rbx,2),%r12
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L8
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long trees(unsigned n) {
  if (n <= 1) {
    return 1;
  }
  unsigned long long res = 0;
  unsigned i;
  for (i = 0; i < n; i++) {
    res += 2 * trees(i) * trees(n - i - 1);
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inner_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double inner_2d(double *p0, double *p1) {
  double out = *(p0++) * *(p1++);
  return out + (*p0 * *p1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inner_2d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double inner_2d(double *p0, double *p1) {
  double out = *(p0++) * *(p1++);
  return out + (*p0 * *p1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<inner_2d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double inner_2d(double *p0, double *p1) {
  double out = *(p0++) * *(p1++);
  return out + (*p0 * *p1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inner_2d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double inner_2d(double *p0, double *p1) {
  double out = *(p0++) * *(p1++);
  return out + (*p0 * *p1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rdx
  mov    %rsi,%rax
  jmp    L15
L8:
  test   %bl,%bl
  jne    L15
  mov    $0x1,%eax
  jmp    L38
L15:
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movzbl (%rcx),%ebx
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  movzbl (%rcx),%ecx
  cmp    %cl,%bl
  je     L8
  test   %bl,%bl
  sete   %al
  movzbl %al,%eax
L38:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int prefix(s1, s2)
register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return (1);
  return (c == '\0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prefix>:
  endbr64
  mov    $0x0,%eax
L1:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  jne    L6
  add    $0x1,%rax
  test   %dl,%dl
  jne    L1
  mov    $0x1,%eax
  ret
L6:
  test   %dl,%dl
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int prefix(s1, s2)
register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return (1);
  return (c == '\0');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rax
  test   %dl,%dl
  je     L4
L25:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  je     L2
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int prefix(s1, s2)
register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return (1);
  return (c == '\0');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rax
  test   %dl,%dl
  je     L7
L16:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  je     L11
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int prefix(s1, s2)
register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return (1);
  return (c == '\0');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setModule>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x14,-0x10(%rbp)
  jle    L59
  cmpl   $0xb1,-0x10(%rbp)
  jg     L59
  cmpl   $0x0,-0x1c(%rbp)
  js     L59
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L59
  cmpl   $0x0,-0x20(%rbp)
  js     L59
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L59
  mov    $0x1,%eax
  jmp    L32
L59:
  mov    $0x0,%eax
L32:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  jmp    L41
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  xor    $0xff,%al
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
L41:
  nop
  leave
  ret
```

assistant: ```c
void setModule(uint8_t qrcode[], int x, int y, bool isBlack) {
  int qrsize = qrcode[0];
  assert(21 <= qrsize && qrsize <= 177 && 0 <= x && x < qrsize && 0 <= y && y < qrsize);
  int index = y * qrsize + x;
  int bitIndex = index & 7;
  int byteIndex = (index >> 3) + 1;
  if (isBlack)
    qrcode[byteIndex] |= 1 << bitIndex;
  else
    qrcode[byteIndex] &= (1 << bitIndex) ^ 0xFF;
}
```
user: What is the c source code of the assembly code below?

```asm
<setModule>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %ecx,%r12d
  mov    (%rdi),%ebx
  lea    -0x15(%rbx),%eax
  mov    $0x0,%edi
  cmp    $0x9c,%eax
  ja     L55
  mov    %esi,%eax
  or     %edx,%eax
  js     L43
  cmp    %esi,%ebx
  jle    L43
  cmp    %edx,%ebx
  setg   %dil
  movzbl %dil,%edi
  jmp    L55
L43:
  mov    $0x0,%edi
L55:
  call   <assert@plt>
  imul   %r14d,%ebx
  add    %r13d,%ebx
  mov    %ebx,%ecx
  and    $0x7,%ecx
  sar    $0x3,%ebx
  add    $0x1,%ebx
  test   %r12d,%r12d
  je     L39
  movslq %ebx,%rbx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,0x0(%rbp,%rbx,4)
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  movslq %ebx,%rbx
  mov    $0x1,%eax
  shl    %cl,%eax
  xor    $0xff,%al
  and    %eax,0x0(%rbp,%rbx,4)
  jmp    L29
```

assistant: ```c
void setModule(uint8_t qrcode[], int x, int y, bool isBlack) {
  int qrsize = qrcode[0];
  assert(21 <= qrsize && qrsize <= 177 && 0 <= x && x < qrsize && 0 <= y && y < qrsize);
  int index = y * qrsize + x;
  int bitIndex = index & 7;
  int byteIndex = (index >> 3) + 1;
  if (isBlack)
    qrcode[byteIndex] |= 1 << bitIndex;
  else
    qrcode[byteIndex] &= (1 << bitIndex) ^ 0xFF;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setModule>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%ebx
  xor    %edi,%edi
  lea    -0x15(%rbx),%eax
  cmp    $0x9c,%eax
  ja     L6
  mov    %esi,%eax
  or     %edx,%eax
  js     L5
  cmp    %esi,%ebx
  jle    L5
  xor    %edi,%edi
  cmp    %edx,%ebx
  setg   %dil
L6:
  call   <assert@plt>
  imul   %r14d,%ebx
  lea    (%rbx,%r12,1),%ecx
  mov    %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  add    $0x1,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %r13d,%r13d
  je     L42
  or     (%rdx),%eax
  mov    %eax,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  xor    $0xff,%al
  and    (%rdx),%eax
  mov    %eax,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L5:
  xor    %edi,%edi
  jmp    L6
```

assistant: ```c
void setModule(uint8_t qrcode[], int x, int y, bool isBlack) {
  int qrsize = qrcode[0];
  assert(21 <= qrsize && qrsize <= 177 && 0 <= x && x < qrsize && 0 <= y && y < qrsize);
  int index = y * qrsize + x;
  int bitIndex = index & 7;
  int byteIndex = (index >> 3) + 1;
  if (isBlack)
    qrcode[byteIndex] |= 1 << bitIndex;
  else
    qrcode[byteIndex] &= (1 << bitIndex) ^ 0xFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setModule>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%ebx
  xor    %edi,%edi
  lea    -0x15(%rbx),%eax
  cmp    $0x9c,%eax
  ja     L26
  mov    %esi,%eax
  or     %edx,%eax
  js     L6
  cmp    %esi,%ebx
  jle    L6
  xor    %edi,%edi
  cmp    %edx,%ebx
  setg   %dil
L26:
  call   <assert@plt>
  imul   %r14d,%ebx
  lea    (%rbx,%r12,1),%ecx
  mov    %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  add    $0x1,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  test   %r13d,%r13d
  je     L32
  or     (%rdx),%eax
  mov    %eax,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  xor    $0xff,%al
  and    (%rdx),%eax
  mov    %eax,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L6:
  xor    %edi,%edi
  jmp    L26
```

assistant: ```c
void setModule(uint8_t qrcode[], int x, int y, bool isBlack) {
  int qrsize = qrcode[0];
  assert(21 <= qrsize && qrsize <= 177 && 0 <= x && x < qrsize && 0 <= y && y < qrsize);
  int index = y * qrsize + x;
  int bitIndex = index & 7;
  int byteIndex = (index >> 3) + 1;
  if (isBlack)
    qrcode[byteIndex] |= 1 << bitIndex;
  else
    qrcode[byteIndex] &= (1 << bitIndex) ^ 0xFF;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<aligned_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x48,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  and    $0xffffffffffffffc0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L3:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *aligned_calloc(size_t size) {
  void *mem = calloc(size + 64 + sizeof(void *), 1);
  void **ptr = NULL;
  if (mem != NULL) {
    ptr = (void **)((uintptr_t)(mem + 64 + sizeof(void *)) & ~(uintptr_t)(64 - 1));
    ptr[-1] = mem;
  }
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aligned_calloc>:
  endbr64
  sub    $0x8,%rsp
  add    $0x48,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L13
  lea    0x48(%rax),%rdx
  and    $0xffffffffffffffc0,%rdx
  mov    %rax,-0x8(%rdx)
L12:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
L13:
  mov    %rax,%rdx
  jmp    L12
```

assistant: ```c
void *aligned_calloc(size_t size) {
  void *mem = calloc(size + 64 + sizeof(void *), 1);
  void **ptr = NULL;
  if (mem != NULL) {
    ptr = (void **)((uintptr_t)(mem + 64 + sizeof(void *)) & ~(uintptr_t)(64 - 1));
    ptr[-1] = mem;
  }
  return ptr;
}
```