ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<write_float4_array>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <flip4@plt>
  lea    0x0(,%r12,4),%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <flip4@plt>
  mov    %ebx,%eax
  xor    %edx,%edx
  sar    $0x2,%eax
  test   %ebx,%ebx
  cmovle %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_float4_array(int f, const float *x, int n) {
  int nwritten;
  flip4((const unsigned int *)x, (unsigned int *)x, n);
  nwritten = write(f, x, 4 * n);
  flip4((const unsigned int *)x, (unsigned int *)x, n);
  if (nwritten <= 0)
    return 0;
  else
    return nwritten / 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  call   <fork@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  je     L48
  cmpl   $0x0,-0x1c(%rbp)
  je     L16
  jmp    L51
L48:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L16:
  lea    D15(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x20(%rbp)
  jmp    L1
L51:
  lea    D4(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x3,-0x20(%rbp)
  nop
L1:
  jmp    L5
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  subl   $0x1,-0x20(%rbp)
L5:
  cmpl   $0x0,-0x20(%rbp)
  jg     L24
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D40
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D9: fork program starting

tool: D38: fork failed

tool: D15: This is the child

tool: D40: child PID:%d Child PPID:%d


tool: D4: This is the parent

tool: D13: Parent PID:%d Parent PPID:%d


assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program starting\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    printf("child PID:%d Child PPID:%d\n", getpid(), getppid());
    n = 5;
    break;
  default:
    message = "This is the parent";
    printf("Parent PID:%d Parent PPID:%d\n", getpid(), getppid());
    n = 3;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D35(%rip),%rdi
  call   <puts@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L12
  test   %eax,%eax
  je     L26
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%ebx
  lea    D15(%rip),%rbp
  jmp    L2
L12:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L26:
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%ebx
  lea    D27(%rip),%rbp
L2:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D35
data_type: string
name: parse_data
arguments: data_label: D55
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D32
data_type: string
name: parse_data
arguments: data_label: D27
data_type: string

tool: D35: fork program starting

tool: D55: Parent PID:%d Parent PPID:%d


tool: D15: This is the parent

tool: D5: fork failed

tool: D32: child PID:%d Child PPID:%d


tool: D27: This is the child

assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program starting\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    printf("child PID:%d Child PPID:%d\n", getpid(), getppid());
    n = 5;
    break;
  default:
    message = "This is the parent";
    printf("Parent PID:%d Parent PPID:%d\n", getpid(), getppid());
    n = 3;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <puts@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L26
  test   %eax,%eax
  je     L29
  xor    %eax,%eax
  mov    $0x3,%ebx
  lea    D51(%rip),%rbp
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D46(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L28
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D56(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L29:
  xor    %eax,%eax
  mov    $0x5,%ebx
  lea    D39(%rip),%rbp
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L28
```

tool_calls: name: read_data
arguments: tag: D38
type_infered: string
name: read_data
arguments: tag: D51
type_infered: string
name: read_data
arguments: tag: D46
type_infered: string
name: read_data
arguments: tag: D56
type_infered: string
name: read_data
arguments: tag: D39
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string

tool: D38: fork program starting

tool: D51: This is the parent

tool: D46: Parent PID:%d Parent PPID:%d


tool: D56: fork failed

tool: D39: This is the child

tool: D32: child PID:%d Child PPID:%d


assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program starting\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    printf("child PID:%d Child PPID:%d\n", getpid(), getppid());
    n = 5;
    break;
  default:
    message = "This is the parent";
    printf("Parent PID:%d Parent PPID:%d\n", getpid(), getppid());
    n = 3;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D54(%rip),%rdi
  push   %rbp
  push   %rbx
  call   <puts@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L10
  test   %eax,%eax
  je     L29
  xor    %eax,%eax
  mov    $0x3,%ebx
  lea    D5(%rip),%rbp
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L9
  xor    %edi,%edi
  call   <exit@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    D50(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L29:
  xor    %eax,%eax
  mov    $0x5,%ebx
  lea    D33(%rip),%rbp
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D41(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D54
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D50
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D41
type_guessed: string

tool: D54: fork program starting

tool: D5: This is the parent

tool: D16: Parent PID:%d Parent PPID:%d


tool: D50: fork failed

tool: D33: This is the child

tool: D41: child PID:%d Child PPID:%d


assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program starting\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    printf("child PID:%d Child PPID:%d\n", getpid(), getppid());
    n = 5;
    break;
  default:
    message = "This is the parent";
    printf("Parent PID:%d Parent PPID:%d\n", getpid(), getppid());
    n = 3;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<berictl_test_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <berictl_pause@plt>
  mov    %eax,-0x2c(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <berictl_stream_trace@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L14
  mov    -0x2c(%rbp),%eax
  jmp    L64
L14:
  lea    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <berictl_setpc@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L31
  mov    -0x2c(%rbp),%eax
  jmp    L64
L31:
  movl   $0x10,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <berictl_stream_trace@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L42
  mov    -0x2c(%rbp),%eax
  jmp    L64
L42:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <berictl_pause@plt>
L64:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D15: 9000000040000000

tool: D16: Draining trace buffer:


assistant: ```c
int berictl_test_run(struct beri_debug *bdp) {
  int ret;
  char pc[20];
  strcpy(pc, "9000000040000000");
  ret = berictl_pause(bdp);
  printf("Draining trace buffer:\n");
  ret = berictl_stream_trace(bdp, 1, 0, 0);
  if (ret != 0)
    return (ret);
  ret = berictl_setpc(bdp, pc);
  if (ret != 0)
    return (ret);
  int streamTimes = 16;
  int binary = 0;
  ret = berictl_stream_trace(bdp, streamTimes, binary, 0);
  if (ret != 0)
    return (ret);
  return (berictl_pause(bdp));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<berictl_test_run>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D19(%rip),%rsi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <berictl_pause@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  je     L24
L37:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <berictl_setpc@plt>
  test   %eax,%eax
  jne    L37
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  jne    L37
  mov    %rbx,%rdi
  call   <berictl_pause@plt>
  jmp    L37
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string

tool: D19: 9000000040000000

tool: D16: Draining trace buffer:


assistant: ```c
int berictl_test_run(struct beri_debug *bdp) {
  int ret;
  char pc[20];
  strcpy(pc, "9000000040000000");
  ret = berictl_pause(bdp);
  printf("Draining trace buffer:\n");
  ret = berictl_stream_trace(bdp, 1, 0, 0);
  if (ret != 0)
    return (ret);
  ret = berictl_setpc(bdp, pc);
  if (ret != 0)
    return (ret);
  int streamTimes = 16;
  int binary = 0;
  ret = berictl_stream_trace(bdp, streamTimes, binary, 0);
  if (ret != 0)
    return (ret);
  return (berictl_pause(bdp));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<berictl_test_run>:
  endbr64
  push   %r12
  lea    D10(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <berictl_pause@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  je     L26
L40:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <berictl_setpc@plt>
  test   %eax,%eax
  jne    L40
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  jne    L40
  mov    %rbp,%rdi
  call   <berictl_pause@plt>
  jmp    L40
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string

tool: D10: 9000000040000000

tool: D14: Draining trace buffer:


assistant: ```c
int berictl_test_run(struct beri_debug *bdp) {
  int ret;
  char pc[20];
  strcpy(pc, "9000000040000000");
  ret = berictl_pause(bdp);
  printf("Draining trace buffer:\n");
  ret = berictl_stream_trace(bdp, 1, 0, 0);
  if (ret != 0)
    return (ret);
  ret = berictl_setpc(bdp, pc);
  if (ret != 0)
    return (ret);
  int streamTimes = 16;
  int binary = 0;
  ret = berictl_stream_trace(bdp, streamTimes, binary, 0);
  if (ret != 0)
    return (ret);
  return (berictl_pause(bdp));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<berictl_test_run>:
  endbr64
  push   %r12
  lea    D11(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <berictl_pause@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  je     L26
L30:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <berictl_setpc@plt>
  test   %eax,%eax
  jne    L30
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <berictl_stream_trace@plt>
  test   %eax,%eax
  jne    L30
  mov    %rbp,%rdi
  call   <berictl_pause@plt>
  jmp    L30
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D11: 9000000040000000

tool: D9: Draining trace buffer:


assistant: ```c
int berictl_test_run(struct beri_debug *bdp) {
  int ret;
  char pc[20];
  strcpy(pc, "9000000040000000");
  ret = berictl_pause(bdp);
  printf("Draining trace buffer:\n");
  ret = berictl_stream_trace(bdp, 1, 0, 0);
  if (ret != 0)
    return (ret);
  ret = berictl_setpc(bdp, pc);
  if (ret != 0)
    return (ret);
  int streamTimes = 16;
  int binary = 0;
  ret = berictl_stream_trace(bdp, streamTimes, binary, 0);
  if (ret != 0)
    return (ret);
  return (berictl_pause(bdp));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drawRectangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cx,-0x14(%rbp)
  mov    %esi,%ecx
  mov    %cx,-0x18(%rbp)
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    %r8d,%eax
  mov    %al,-0x24(%rbp)
  movswl -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L69
L14:
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L20:
  movsbl -0x24(%rbp),%edx
  movswl -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <setPixel@plt>
  addl   $0x1,-0x8(%rbp)
L9:
  movswl -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L20
  movswl -0x20(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L69:
  cmpl   $0x1,-0xc(%rbp)
  jle    L14
  movswl -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L79
L40:
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L33:
  movsbl -0x24(%rbp),%edx
  movswl -0x18(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %eax,%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setPixel@plt>
  addl   $0x1,-0x4(%rbp)
L54:
  movswl -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L33
  movswl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L79:
  cmpl   $0x1,-0xc(%rbp)
  jle    L40
  nop
  nop
  leave
  ret
```

assistant: ```c
void drawRectangle(short x, short y, short width, short height, char c) {
  int i;
  int newX;
  int newY;
  newY = y;
  for (i = 0; i < 2; i++) {
    for (newX = 0; newX < width; newX++) {
      setPixel(newX + x, newY, c);
    }
    newY += height - 1;
  }
  newX = x;
  for (i = 0; i < 2; i++) {
    for (newY = 0; newY < height; newY++) {
      setPixel(newX, newY + y, c);
    }
    newX += width - 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drawRectangle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,%ebp
  movswl %dx,%r15d
  test   %r15d,%r15d
  jle    L56
  movswl %si,%r13d
  movswl %di,%ebx
  mov    %r15d,%r12d
  add    %ebx,%r12d
  movsbl %r8b,%r14d
L64:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <setPixel@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L64
  movswl 0xc(%rsp),%eax
  mov    %eax,0x18(%rsp)
  lea    -0x1(%r13,%rax,1),%r14d
  movswl 0x10(%rsp),%ebx
  movswl 0x1c(%rsp),%r12d
  add    %ebx,%r12d
  movsbl %bpl,%r13d
L25:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <setPixel@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L25
L21:
  movswl 0x10(%rsp),%r13d
  cmpl   $0x0,0x18(%rsp)
  jle    L53
  movswl 0x14(%rsp),%ebx
  movswl 0xc(%rsp),%r12d
  add    %ebx,%r12d
  movsbl %bpl,%r14d
L69:
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <setPixel@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L69
  lea    -0x1(%r13,%r15,1),%r13d
  movswl 0x14(%rsp),%ebx
  movswl 0xc(%rsp),%r12d
  add    %ebx,%r12d
  movsbl %bpl,%ebp
L3:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <setPixel@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L3
L53:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  movswl 0xc(%rsp),%eax
  mov    %eax,0x18(%rsp)
  jmp    L21
```

assistant: ```c
void drawRectangle(short x, short y, short width, short height, char c) {
  int i;
  int newX;
  int newY;
  newY = y;
  for (i = 0; i < 2; i++) {
    for (newX = 0; newX < width; newX++) {
      setPixel(newX + x, newY, c);
    }
    newY += height - 1;
  }
  newX = x;
  for (i = 0; i < 2; i++) {
    for (newY = 0; newY < height; newY++) {
      setPixel(newX, newY + y, c);
    }
    newX += width - 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drawRectangle>:
  endbr64
  push   %r15
  movswl %dx,%eax
  movswl %cx,%ecx
  push   %r14
  push   %r13
  movswl %di,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  movswl %si,%ebx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  mov    %ecx,0x4(%rsp)
  test   %eax,%eax
  jle    L0
  mov    0x8(%rsp),%eax
  movsbl 0xc(%rsp),%ebp
  mov    %r13d,%r15d
  mov    %r13d,%r14d
  lea    (%rax,%r13,1),%r12d
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r14d,%edi
  mov    %ebp,%edx
  mov    %ebx,%esi
  add    $0x1,%r14d
  call   <setPixel@plt>
  cmp    %r12d,%r14d
  jne    L47
  mov    0x4(%rsp),%eax
  lea    -0x1(%rbx,%rax,1),%r14d
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    %r15d,%edi
  mov    %ebp,%edx
  mov    %r14d,%esi
  add    $0x1,%r15d
  call   <setPixel@plt>
  cmp    %r12d,%r15d
  jne    L58
L0:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L33
  mov    0x4(%rsp),%r14d
  movsbl 0xc(%rsp),%ebp
  mov    %ebx,%r12d
  add    %ebx,%r14d
  xchg   %ax,%ax
L39:
  mov    %r12d,%esi
  mov    %ebp,%edx
  mov    %r13d,%edi
  add    $0x1,%r12d
  call   <setPixel@plt>
  cmp    %r12d,%r14d
  jne    L39
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax,%r13,1),%r12d
  nop
L1:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <setPixel@plt>
  cmp    %r14d,%ebx
  jne    L1
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void drawRectangle(short x, short y, short width, short height, char c) {
  int i;
  int newX;
  int newY;
  newY = y;
  for (i = 0; i < 2; i++) {
    for (newX = 0; newX < width; newX++) {
      setPixel(newX + x, newY, c);
    }
    newY += height - 1;
  }
  newX = x;
  for (i = 0; i < 2; i++) {
    for (newY = 0; newY < height; newY++) {
      setPixel(newX, newY + y, c);
    }
    newX += width - 1;
  }
}
```