user: Translate the below assembly code into C programming language:

```asm
<booth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  andl   $0xff,-0x14(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  shll   -0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <println@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x28(%rbp),%eax
  shl    $0x9,%eax
  and    $0x1fe00,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  neg    %eax
  shl    $0x9,%eax
  and    $0x1fe00,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L49
L58:
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L55
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    D32(%rip),%rsi
  mov    %eax,%edi
  call   <println@plt>
  jmp    L54
L55:
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  jne    L33
  mov    -0x8(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    D30(%rip),%rsi
  mov    %eax,%edi
  call   <println@plt>
  jmp    L54
L33:
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    D36(%rip),%rsi
  mov    %eax,%edi
  call   <println@plt>
L54:
  andl   $0x1ffff,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x10000,%eax
  test   %eax,%eax
  je     L22
  addl   $0x20000,-0x14(%rbp)
L22:
  shrl   -0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    D95(%rip),%rsi
  mov    %eax,%edi
  call   <println@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x10(%rbp)
L49:
  cmpl   $0x8,-0x10(%rbp)
  jle    L58
  shrl   -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <printbin@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D54
type_infered: string
name: unpack_data
arguments: label: D90
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D95
type_infered: string
name: unpack_data
arguments: label: D83
type_infered: string

tool: D54: 
____________________________________________________________________________________________________________________

tool: D90: | Iteration  |     Operation    | 		Multiplicand		 |    		 Product 		   |

tool: D18: |____________|__________________|________________________________________|_________________________________________|

tool: D28: Initialization

tool: D32: prod=prod+mcand

tool: D30: prod=prod-mcand

tool: D36: No Operation

tool: D95: Shift Right

tool: D83: 

The answer is: %d

Binary: 

assistant: ```c
void booth(unsigned int multiplier, int multiplicand) {
  unsigned int product = multiplier;
  product &= 0xFF;
  printf("\n____________________________________________________________________________________________________________________\n");
  printf("| Iteration  |     Operation    | \t\tMultiplicand\t\t |    \t\t Product \t\t   |\n");
  printf("|____________|__________________|________________________________________|_________________________________________|\n");
  product <<= 1;
  println(0, "Initialization", multiplicand, product);
  printf("|____________|__________________|________________________________________|_________________________________________|\n");
  unsigned int add = (multiplicand << (8 + 1)) & 130560;
  unsigned int sub = (-multiplicand << (8 + 1)) & 130560;
  for (int i = 1; i <= 8; i++) {
    if ((product & 3) == 1) {
      product += add;
      println(i, "prod=prod+mcand", multiplicand, product);
    } else if ((product & 3) == 2) {
      product += sub;
      println(i, "prod=prod-mcand", multiplicand, product);
    } else
      println(i, "No Operation", multiplicand, product);
    product &= 0x1FFFF;
    if ((product & 65536) == 65536)
      product += 131072;
    product >>= 1;
    println(i, "Shift Right", multiplicand, product);
    printf("|____________|__________________|________________________________________|_________________________________________|\n");
  }
  product = product >> 1;
  int val = product;
  printf("\n\nThe answer is: %d\n\nBinary: ", multiplicand * multiplier);
  printbin(product, 0, 32);
}
```