ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D51(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D49(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  movss  (%rsp),%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D51
datatype: string
name: extract_symbolic_data
arguments: data_tag: D58
datatype: string
name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string

tool: D28: what is the first float?

tool: D51:  %f

tool: D58: what is the second float?

tool: D39: sum is %f


tool: D49: product is %f


tool: D35: quotient is %f


tool: D36: difference is %f


assistant: ```c
int main() {
  float float1;
  float float2;
  printf("what is the first float?\n");
  scanf(" %f", &float1);
  printf("what is the second float?\n");
  scanf(" %f", &float2);
  printf("sum is %f\n", float1 + float2);
  printf("product is %f\n", float1 * float2);
  printf("quotient is %f\n", float1 / float2);
  printf("difference is %f\n", float1 - float2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D17(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D47(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  movss  (%rsp),%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D45
datatype: string
name: unpack_data
arguments: data_tag: D47
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D41
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string

tool: D25: what is the first float?

tool: D17:  %f

tool: D45: what is the second float?

tool: D47: sum is %f


tool: D28: product is %f


tool: D41: quotient is %f


tool: D27: difference is %f


assistant: ```c
int main() {
  float float1;
  float float2;
  printf("what is the first float?\n");
  scanf(" %f", &float1);
  printf("what is the second float?\n");
  scanf(" %f", &float2);
  printf("sum is %f\n", float1 + float2);
  printf("product is %f\n", float1 * float2);
  printf("quotient is %f\n", float1 / float2);
  printf("difference is %f\n", float1 - float2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_dec_byte_content>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: 
Decimal (unsigned int) content of pointer[%d] is %d


assistant: ```c
void print_dec_byte_content(char *pointer, int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf("\nDecimal (unsigned int) content of pointer[%d] is %d\n", i, (unsigned int)pointer[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_dec_byte_content>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L1:
  movsbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: 
Decimal (unsigned int) content of pointer[%d] is %d


assistant: ```c
void print_dec_byte_content(char *pointer, int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf("\nDecimal (unsigned int) content of pointer[%d] is %d\n", i, (unsigned int)pointer[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_dec_byte_content>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  movsbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: 
Decimal (unsigned int) content of pointer[%d] is %d


assistant: ```c
void print_dec_byte_content(char *pointer, int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf("\nDecimal (unsigned int) content of pointer[%d] is %d\n", i, (unsigned int)pointer[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_dec_byte_content>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  movsbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: 
Decimal (unsigned int) content of pointer[%d] is %d


assistant: ```c
void print_dec_byte_content(char *pointer, int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf("\nDecimal (unsigned int) content of pointer[%d] is %d\n", i, (unsigned int)pointer[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x48(%rbp)
  jmp    L84
L64:
  mov    -0x48(%rbp),%eax
  cltq
  movl   $0x0,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x48(%rbp)
L84:
  cmpl   $0xa,-0x48(%rbp)
  jle    L64
  movl   $0x1,-0x48(%rbp)
  jmp    L6
L28:
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x48(%rbp)
L6:
  cmpl   $0x5,-0x48(%rbp)
  jle    L28
  movl   $0x0,-0x48(%rbp)
  jmp    L72
L8:
  movl   $0x1,-0x44(%rbp)
  jmp    L71
L85:
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L71:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,-0x44(%rbp)
  jle    L85
  addl   $0x1,-0x48(%rbp)
L72:
  cmpl   $0xa,-0x48(%rbp)
  jle    L8
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: string

tool: D13: %d

assistant: ```c
int main() {
  int a[11], i, j, t;
  for (i = 0; i <= 10; i++) {
    a[i] = 0;
  }
  for (i = 1; i <= 5; i++) {
    scanf("%d", &t);
    a[t]++;
  }
  for (i = 0; i <= 10; i++) {
    for (j = 1; j <= a[i]; j++)
      printf("%d", i);
  }
  getchar();
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x3c(%rsp),%rdx
L43:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L43
  mov    $0x5,%ebx
  lea    D15(%rip),%rbp
L75:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L75
  mov    $0x0,%r14d
  lea    D15(%rip),%r13
  jmp    L38
L34:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L34
L16:
  add    $0x1,%r14
  cmp    $0xb,%r14
  je     L21
L38:
  mov    %r14d,%r12d
  mov    0x10(%rsp,%r14,4),%ebp
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L34
  jmp    L16
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D15: %d

assistant: ```c
int main() {
  int a[11], i, j, t;
  for (i = 0; i <= 10; i++) {
    a[i] = 0;
  }
  for (i = 1; i <= 5; i++) {
    scanf("%d", &t);
    a[t]++;
  }
  for (i = 0; i <= 10; i++) {
    for (j = 1; j <= a[i]; j++)
      printf("%d", i);
  }
  getchar();
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x38(%rsp)
  lea    0xc(%rsp),%rbp
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L15
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r15
  nopl   0x0(%rax)
L11:
  mov    (%r15,%r14,4),%ebp
  mov    %r14d,%r12d
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L33
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L9
L33:
  add    $0x1,%r14
  cmp    $0xb,%r14
  jne    L11
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: %d

assistant: ```c
int main() {
  int a[11], i, j, t;
  for (i = 0; i <= 10; i++) {
    a[i] = 0;
  }
  for (i = 1; i <= 5; i++) {
    scanf("%d", &t);
    a[t]++;
  }
  for (i = 0; i <= 10; i++) {
    for (j = 1; j <= a[i]; j++)
      printf("%d", i);
  }
  getchar();
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x38(%rsp)
  lea    0xc(%rsp),%rbp
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
L29:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  addl   $0x1,0x10(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L29
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r15
  nopl   0x0(%rax)
L45:
  mov    (%r15,%r14,4),%ebp
  mov    %r14d,%r12d
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L24
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L18
L24:
  add    $0x1,%r14
  cmp    $0xb,%r14
  jne    L45
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  int a[11], i, j, t;
  for (i = 0; i <= 10; i++) {
    a[i] = 0;
  }
  for (i = 1; i <= 5; i++) {
    scanf("%d", &t);
    a[t]++;
  }
  for (i = 0; i <= 10; i++) {
    for (j = 1; j <= a[i]; j++)
      printf("%d", i);
  }
  getchar();
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TranspMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L1:
  mov    -0x28(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TranspMat(float A_T[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      A_T[m * i + j] = A[n * j + i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TranspMat>:
  endbr64
  test   %ecx,%ecx
  jle    L15
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%r11d
  mov    %ecx,%ebx
  movslq %ecx,%rdi
  shl    $0x2,%rdi
  mov    $0x0,%r10d
  mov    $0x0,%r8d
  lea    -0x1(%rdx),%r12d
  lea    0x4(%r9),%rbp
  jmp    L42
L24:
  movslq %r10d,%rdx
  lea    (%r9,%rdx,4),%rax
  add    %r12,%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
  mov    %rsi,%rdx
L8:
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  add    %rdi,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L35:
  add    $0x1,%r8d
  add    $0x4,%rsi
  add    %r11d,%r10d
  cmp    %r8d,%ebx
  je     L30
L42:
  test   %r11d,%r11d
  jg     L24
  jmp    L35
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  ret
```

assistant: ```c
void TranspMat(float A_T[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      A_T[m * i + j] = A[n * j + i];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TranspMat>:
  endbr64
  test   %ecx,%ecx
  jle    L26
  mov    %rdi,%r9
  movslq %ecx,%rdi
  push   %r12
  mov    %edx,%r11d
  push   %rbp
  shl    $0x2,%rdi
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  push   %rbx
  lea    -0x1(%rdx),%r12d
  mov    %ecx,%ebx
  lea    0x4(%r9),%rbp
  nopl   0x0(%rax)
L34:
  test   %r11d,%r11d
  jle    L22
  movslq %r10d,%rdx
  lea    (%r9,%rdx,4),%rax
  add    %r12,%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
  mov    %rsi,%rdx
  nopw   0x0(%rax,%rax,1)
L29:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rdi,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L29
L22:
  add    $0x1,%r8d
  add    $0x4,%rsi
  add    %r11d,%r10d
  cmp    %r8d,%ebx
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  ret
```

assistant: ```c
void TranspMat(float A_T[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      A_T[m * i + j] = A[n * j + i];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TranspMat>:
  endbr64
  mov    %ecx,%r9d
  test   %ecx,%ecx
  jle    L8
  test   %edx,%edx
  jle    L8
  lea    -0x1(%rdx),%eax
  mov    %rsi,%r8
  movslq %edx,%r11
  movslq %r9d,%rsi
  shl    $0x2,%rax
  mov    $0xfffffffffffffffc,%r10
  shl    $0x2,%r11
  lea    0x4(%rdi,%rax,1),%rcx
  shl    $0x2,%rsi
  xor    %edi,%edi
  sub    %rax,%r10
  nopl   0x0(%rax,%rax,1)
L10:
  lea    (%r10,%rcx,1),%rax
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rsi,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L11
  add    $0x1,%edi
  add    $0x4,%r8
  add    %r11,%rcx
  cmp    %edi,%r9d
  jne    L10
L8:
  ret
```

assistant: ```c
void TranspMat(float A_T[], float A[], int m, int n) {
  int i;
  int j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      A_T[m * i + j] = A[n * j + i];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x9,-0x4(%rbp)
  jle    L2
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: %d

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("%d", i);
  }
  if (i == 0) {
    printf("%d", i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("%d", i);
  }
  if (i == 0) {
    printf("%d", i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %d

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("%d", i);
  }
  if (i == 0) {
    printf("%d", i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: %d

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("%d", i);
  }
  if (i == 0) {
    printf("%d", i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Mergesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L3
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L9
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rsi,%r8
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <Mergesortd@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *Mergesort(int n, int (*CFun)(int, int)) {
  int a;
  int *order = (int *)malloc((n + 1) * sizeof(int));
  int *t = (int *)malloc(n * sizeof(int));
  for (a = 1; a <= n; a++)
    order[a] = a;
  Mergesortd(1, n, CFun, order, t);
  free(t);
  return order;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Mergesort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L4
  lea    0x4(%rbp),%rdx
  lea    0x1(%rbx),%ecx
  mov    $0x1,%eax
L7:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L7
L4:
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <Mergesortd@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *Mergesort(int n, int (*CFun)(int, int)) {
  int a;
  int *order = (int *)malloc((n + 1) * sizeof(int));
  int *t = (int *)malloc(n * sizeof(int));
  for (a = 1; a <= n; a++)
    order[a] = a;
  Mergesortd(1, n, CFun, order, t);
  free(t);
  return order;
}
```