user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D53(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x2d,%al
  je     L48
  jg     L54
  cmp    $0x2a,%al
  je     L62
  cmp    $0x2b,%al
  jne    L64
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%eax
  lea    D55(%rip),%rdi
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  call   <printf@plt>
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L54:
  cmp    $0x2f,%al
  jne    L64
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%eax
  lea    D52(%rip),%rdi
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  call   <printf@plt>
  jmp    L31
L48:
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%eax
  lea    D62(%rip),%rdi
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  call   <printf@plt>
  jmp    L31
L64:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L31
L62:
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%eax
  lea    D35(%rip),%rdi
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  call   <printf@plt>
  jmp    L31
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D53
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string
name: unpack_data
arguments: data_tag: D41
datatype: string
name: unpack_data
arguments: data_tag: D31
datatype: string
name: unpack_data
arguments: data_tag: D55
datatype: string
name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D62
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D35
datatype: string

tool: D53: Enter an operator (+, -, *,/): 

tool: D16: %c

tool: D41: Enter two numbers: 

tool: D31: %lf %lf

tool: D55: The result of the operation %.1lf + %.1lf = %.1lf

tool: D52: The result of the operation %.1lf / %.1lf = %.1lf

tool: D62: The result of the operation %.1lf - %.1lf = %.1lf

tool: D26: Error! The entered operator is invalid

tool: D35: The result of the operation %.1lf * %.1lf = %.1lf

assistant: ```c
int main() {
  char op;
  double num1, num2;
  printf("Enter an operator (+, -, *,/): ");
  scanf("%c", &op);
  printf("Enter two numbers: ");
  scanf("%lf %lf", &num1, &num2);
  switch (op) {
  case '+':
    printf("The result of the operation %.1lf + %.1lf = %.1lf", num1, num2, num1 + num2);
    break;
  case '-':
    printf("The result of the operation %.1lf - %.1lf = %.1lf", num1, num2, num1 - num2);
    break;
  case '*':
    printf("The result of the operation %.1lf * %.1lf = %.1lf", num1, num2, num1 * num2);
    break;
  case '/':
    printf("The result of the operation %.1lf / %.1lf = %.1lf", num1, num2, num1 / num2);
    break;
  default:
    printf("Error! The entered operator is invalid");
  }
  return 0;
}
```