ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<GOLDBACHp>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  lea    0x2(%rdi),%ebp
  mov    $0x2,%ebx
  jmp    L21
L59:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L51
L21:
  mov    %ebx,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L59
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <MINUS@plt>
  mov    %eax,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L59
  mov    $0x1,%eax
  jmp    L23
L51:
  mov    $0x0,%eax
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int GOLDBACHp(int N) {
  int output = 0;
  int cell0 = 0;
  cell0 = 2;
  {
    int ctr1;
    for (ctr1 = N; ctr1 > 0; ctr1--) {
      if ((PRIMEp(cell0)) && (PRIMEp(MINUS(N, cell0)))) {
        output = 1;
        goto quit0;
      }
      cell0 = (cell0 + 1);
    }
  }
quit0:
  return output;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GOLDBACHp>:
  endbr64
  test   %edi,%edi
  jle    L21
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x2(%rdi),%ebp
  push   %rbx
  mov    $0x2,%ebx
  jmp    L8
  nopl   0x0(%rax)
L28:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  je     L49
L8:
  mov    %ebx,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L28
  mov    %r12d,%edi
  mov    %ebx,%esi
  call   <MINUS@plt>
  mov    %eax,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L28
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int GOLDBACHp(int N) {
  int output = 0;
  int cell0 = 0;
  cell0 = 2;
  {
    int ctr1;
    for (ctr1 = N; ctr1 > 0; ctr1--) {
      if ((PRIMEp(cell0)) && (PRIMEp(MINUS(N, cell0)))) {
        output = 1;
        goto quit0;
      }
      cell0 = (cell0 + 1);
    }
  }
quit0:
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GOLDBACHp>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x2(%rdi),%ebp
  push   %rbx
  mov    $0x2,%ebx
  jmp    L43
  nopl   0x0(%rax)
L38:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  je     L41
L43:
  mov    %ebx,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L38
  mov    %r12d,%edi
  mov    %ebx,%esi
  call   <MINUS@plt>
  mov    %eax,%edi
  call   <PRIMEp@plt>
  test   %rax,%rax
  je     L38
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int GOLDBACHp(int N) {
  int output = 0;
  int cell0 = 0;
  cell0 = 2;
  {
    int ctr1;
    for (ctr1 = N; ctr1 > 0; ctr1--) {
      if ((PRIMEp(cell0)) && (PRIMEp(MINUS(N, cell0)))) {
        output = 1;
        goto quit0;
      }
      cell0 = (cell0 + 1);
    }
  }
quit0:
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strLen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L14:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strLen(const char *str) {
  size_t result = 0;
  while (str[result] != 0)
    result++;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strLen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x0,%eax
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L8
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strLen(const char *str) {
  size_t result = 0;
  while (str[result] != 0)
    result++;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strLen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L16
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
size_t strLen(const char *str) {
  size_t result = 0;
  while (str[result] != 0)
    result++;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strLen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L3
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
size_t strLen(const char *str) {
  size_t result = 0;
  while (str[result] != 0)
    result++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x16,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xc,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
signed int f3(signed int v_foo) {
  signed int v_shr = ((unsigned int)v_foo) >> 22;
  signed int v_and = v_shr & 12;
  return v_and;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  shr    $0x16,%eax
  and    $0xc,%eax
  ret
```

assistant: ```c
signed int f3(signed int v_foo) {
  signed int v_shr = ((unsigned int)v_foo) >> 22;
  signed int v_and = v_shr & 12;
  return v_and;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  shr    $0x16,%eax
  and    $0xc,%eax
  ret
```

assistant: ```c
signed int f3(signed int v_foo) {
  signed int v_shr = ((unsigned int)v_foo) >> 22;
  signed int v_and = v_shr & 12;
  return v_and;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f3>:
  endbr64
  mov    %edi,%eax
  shr    $0x16,%eax
  and    $0xc,%eax
  ret
```

assistant: ```c
signed int f3(signed int v_foo) {
  signed int v_shr = ((unsigned int)v_foo) >> 22;
  signed int v_and = v_shr & 12;
  return v_and;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parsehexbyte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x4,-0x4(%rbp)
  jmp    L119
L61:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L4
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L4
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L42
L4:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L54
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L54
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x57(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L42
L54:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L11
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x37(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L42
L11:
  mov    $0xffffffff,%eax
  jmp    L103
L42:
  subl   $0x4,-0x4(%rbp)
  addq   $0x1,-0x20(%rbp)
L119:
  cmpl   $0x0,-0x4(%rbp)
  jns    L61
  mov    $0x0,%eax
L103:
  pop    %rbp
  ret
```

assistant: ```c
int parsehexbyte(char *dst, char *src) {
  int off;
  *dst = 0x00;
  for (off = 4; off >= 0; off -= 4, src++)
    if (*src >= '0' && *src <= '9')
      *dst |= (*src - '0' + 0x00) << off;
    else if (*src >= 'a' && *src <= 'f')
      *dst |= (*src - 'a' + 0x0a) << off;
    else if (*src >= 'A' && *src <= 'F')
      *dst |= (*src - 'A' + 0x0A) << off;
    else
      return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parsehexbyte>:
  endbr64
  mov    %rsi,%rdx
  movb   $0x0,(%rdi)
  mov    $0x4,%ecx
  jmp    L49
L18:
  lea    -0x61(%rax),%esi
  cmp    $0x5,%sil
  ja     L1
  movsbl %al,%eax
  sub    $0x57,%eax
  shl    %cl,%eax
  or     (%rdi),%al
L17:
  mov    %al,(%rdi)
  sub    $0x4,%ecx
  add    $0x1,%rdx
  cmp    $0xfffffffc,%ecx
  je     L25
L49:
  movzbl (%rdx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L18
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    %cl,%eax
  or     (%rdi),%al
  jmp    L17
L1:
  lea    -0x41(%rax),%esi
  cmp    $0x5,%sil
  ja     L23
  movsbl %al,%eax
  sub    $0x37,%eax
  shl    %cl,%eax
  or     (%rdi),%al
  jmp    L17
L25:
  mov    $0x0,%eax
  ret
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int parsehexbyte(char *dst, char *src) {
  int off;
  *dst = 0x00;
  for (off = 4; off >= 0; off -= 4, src++)
    if (*src >= '0' && *src <= '9')
      *dst |= (*src - '0' + 0x00) << off;
    else if (*src >= 'a' && *src <= 'f')
      *dst |= (*src - 'a' + 0x0a) << off;
    else if (*src >= 'A' && *src <= 'F')
      *dst |= (*src - 'A' + 0x0A) << off;
    else
      return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parsehexbyte>:
  endbr64
  movb   $0x0,(%rdi)
  mov    %rsi,%rdx
  mov    $0x4,%ecx
L4:
  movzbl (%rdx),%esi
  lea    -0x30(%rsi),%eax
  cmp    $0x9,%al
  ja     L20
  movsbl %al,%eax
  shl    %cl,%eax
  or     (%rdi),%al
L15:
  sub    $0x4,%ecx
  mov    %al,(%rdi)
  add    $0x1,%rdx
  cmp    $0xfffffffc,%ecx
  jne    L4
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L20:
  lea    -0x61(%rsi),%eax
  cmp    $0x5,%al
  jbe    L14
  lea    -0x41(%rsi),%eax
  cmp    $0x5,%al
  ja     L40
  sub    $0x37,%esi
  movsbl %sil,%eax
  shl    %cl,%eax
  or     (%rdi),%al
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x57,%esi
  movsbl %sil,%eax
  shl    %cl,%eax
  or     (%rdi),%al
  jmp    L15
L40:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int parsehexbyte(char *dst, char *src) {
  int off;
  *dst = 0x00;
  for (off = 4; off >= 0; off -= 4, src++)
    if (*src >= '0' && *src <= '9')
      *dst |= (*src - '0' + 0x00) << off;
    else if (*src >= 'a' && *src <= 'f')
      *dst |= (*src - 'a' + 0x0a) << off;
    else if (*src >= 'A' && *src <= 'F')
      *dst |= (*src - 'A' + 0x0A) << off;
    else
      return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parsehexbyte>:
  endbr64
  movb   $0x0,(%rdi)
  movzbl (%rsi),%ecx
  mov    %rdi,%rdx
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  jbe    L42
  lea    -0x61(%rcx),%eax
  cmp    $0x5,%al
  jbe    L29
  lea    -0x41(%rcx),%eax
  cmp    $0x5,%al
  ja     L13
  lea    -0x37(%rcx),%eax
  shl    $0x4,%eax
L74:
  mov    %al,(%rdx)
  movzbl 0x1(%rsi),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L66
L3:
  or     %esi,%eax
  mov    %al,(%rdx)
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L29:
  lea    -0x57(%rcx),%eax
  shl    $0x4,%eax
  mov    %al,(%rdx)
  movzbl 0x1(%rsi),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L3
L66:
  lea    -0x61(%rcx),%esi
  cmp    $0x5,%sil
  ja     L18
  sub    $0x57,%ecx
  or     %ecx,%eax
  mov    %al,(%rdx)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  shl    $0x4,%eax
  jmp    L74
  nopl   (%rax)
L18:
  lea    -0x41(%rcx),%esi
  cmp    $0x5,%sil
  ja     L13
  sub    $0x37,%ecx
  or     %ecx,%eax
  mov    %al,(%rdx)
  xor    %eax,%eax
  ret
L13:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int parsehexbyte(char *dst, char *src) {
  int off;
  *dst = 0x00;
  for (off = 4; off >= 0; off -= 4, src++)
    if (*src >= '0' && *src <= '9')
      *dst |= (*src - '0' + 0x00) << off;
    else if (*src >= 'a' && *src <= 'f')
      *dst |= (*src - 'a' + 0x0a) << off;
    else if (*src >= 'A' && *src <= 'F')
      *dst |= (*src - 'A' + 0x0A) << off;
    else
      return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L15
L19:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
char *getptr(char *s, char *id) {
  char *c;
  c = strstr(s, id);
  if (c)
    return (c + strlen(id));
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getptr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getptr(char *s, char *id) {
  char *c;
  c = strstr(s, id);
  if (c)
    return (c + strlen(id));
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getptr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r12
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getptr(char *s, char *id) {
  char *c;
  c = strstr(s, id);
  if (c)
    return (c + strlen(id));
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getptr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r12
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getptr(char *s, char *id) {
  char *c;
  c = strstr(s, id);
  if (c)
    return (c + strlen(id));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerMatchGet64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
L1:
  mov    -0x28(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x34,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    $0x20,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%rax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t TimerMatchGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
    ui32Low = (*((volatile uint32_t *)(ui32Base + 0x00000030)));
    ui32High2 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: What is the c source code of the assembly code below?

```asm
<TimerMatchGet64>:
  endbr64
L2:
  mov    0x34(%rdi),%rcx
  mov    0x30(%rdi),%rax
  mov    0x34(%rdi),%rdx
  cmp    %rdx,%rcx
  jne    L2
  ret
```

assistant: ```c
uint64_t TimerMatchGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
    ui32Low = (*((volatile uint32_t *)(ui32Base + 0x00000030)));
    ui32High2 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerMatchGet64>:
  endbr64
  lea    0x34(%rdi),%rdx
  add    $0x30,%rdi
  nopl   0x0(%rax)
L7:
  mov    (%rdx),%rsi
  mov    (%rdi),%rax
  mov    (%rdx),%rcx
  cmp    %rcx,%rsi
  jne    L7
  ret
```

assistant: ```c
uint64_t TimerMatchGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
    ui32Low = (*((volatile uint32_t *)(ui32Base + 0x00000030)));
    ui32High2 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerMatchGet64>:
  endbr64
  lea    0x34(%rdi),%rdx
  add    $0x30,%rdi
  nopl   0x0(%rax)
L7:
  mov    (%rdx),%rsi
  mov    (%rdi),%rax
  mov    (%rdx),%rcx
  cmp    %rcx,%rsi
  jne    L7
  ret
```

assistant: ```c
uint64_t TimerMatchGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
    ui32Low = (*((volatile uint32_t *)(ui32Base + 0x00000030)));
    ui32High2 = (*((volatile uint32_t *)(ui32Base + 0x00000034)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func() {
#pragma omp ordered
  {
#pragma omp barrier
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func>:
  endbr64
  ret
```

assistant: ```c
void func() {
#pragma omp ordered
  {
#pragma omp barrier
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<func>:
  endbr64
  ret
```

assistant: ```c
void func() {
#pragma omp ordered
  {
#pragma omp barrier
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func>:
  endbr64
  ret
```

assistant: ```c
void func() {
#pragma omp ordered
  {
#pragma omp barrier
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UnComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <uncomment_cstyle@plt>
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Str_TrimRight@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: /*

assistant: ```c
void UnComment(char *s) {
  char *p;
  if ((p = strstr(s, "/*")))
    uncomment_cstyle(p);
  Str_TrimRight(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<UnComment>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  call   <uncomment_cstyle@plt>
L9:
  mov    %rbx,%rdi
  call   <Str_TrimRight@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: /*

assistant: ```c
void UnComment(char *s) {
  char *p;
  if ((p = strstr(s, "/*")))
    uncomment_cstyle(p);
  Str_TrimRight(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UnComment>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  call   <uncomment_cstyle@plt>
L4:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <Str_TrimRight@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: /*

assistant: ```c
void UnComment(char *s) {
  char *p;
  if ((p = strstr(s, "/*")))
    uncomment_cstyle(p);
  Str_TrimRight(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UnComment>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rsi
  mov    %rdi,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  call   <uncomment_cstyle@plt>
L2:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <Str_TrimRight@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: /*

assistant: ```c
void UnComment(char *s) {
  char *p;
  if ((p = strstr(s, "/*")))
    uncomment_cstyle(p);
  Str_TrimRight(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x667267632d746e69,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0x61642e73,-0xe(%rbp)
  movw   $0x74,-0xa(%rbp)
  lea    -0x16(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L36
L22:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  fldt   (%rax)
  fldz
  fucomip %st(1),%st
  jp     L24
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  je     L16
  jmp    L40
L24:
  fstp   %st(0)
L40:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  fldt   (%rax)
  mov    -0x20(%rbp),%rax
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  add    $0x10,%rsp
L16:
  addl   $0x1,-0x24(%rbp)
L36:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D1
type: string

tool: D9: w

tool: D1: %Lf


assistant: ```c
void counter(long double *array) {
  FILE *fp;
  char output[] = "int-cgrfs.dat";
  int q;
  fp = fopen(output, "w");
  for (q = 0; q < 1000000; q++) {
    if (array[q] != 0) {
      fprintf(fp, "%Lf\n", array[q]);
    }
  }
  fclose(fp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<counter>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x667267632d746e69,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x61642e73,0x12(%rsp)
  movw   $0x74,0x16(%rsp)
  lea    0xa(%rsp),%rdi
  lea    D17(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    %rbp,%rbx
  add    $0xf42400,%rbp
  lea    D19(%rip),%r13
  jmp    L55
L61:
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x10,%rsp
  jmp    L4
L54:
  fstp   %st(0)
L4:
  add    $0x10,%rbx
  cmp    %rbp,%rbx
  je     L20
L55:
  fldz
  fldt   (%rbx)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L61
  je     L54
  jmp    L61
L20:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D19
type: string

tool: D17: w

tool: D19: %Lf


assistant: ```c
void counter(long double *array) {
  FILE *fp;
  char output[] = "int-cgrfs.dat";
  int q;
  fp = fopen(output, "w");
  for (q = 0; q < 1000000; q++) {
    if (array[q] != 0) {
      fprintf(fp, "%Lf\n", array[q]);
    }
  }
  fclose(fp);
}
```