ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L46
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L81
  addq   $0x1,-0x18(%rbp)
L81:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L80
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
L80:
  mov    $0x0,%eax
  jmp    L44
L62:
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L51
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L26
  mov    $0x0,%eax
  jmp    L44
L26:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  je     L49
  mov    $0x0,%eax
  jmp    L44
L49:
  mov    $0x1,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int check_name(char *name, int size) {
  char *start = name;
  if (name[0] == '.') {
    if (name[1] == '.')
      name++;
    if (name[1] == '/' || name[1] == '\0')
      return 0;
  }
  while (name[0] != '/' && name[0] != '\0')
    name++;
  if (name[0] == '/')
    return 0;
  if ((name - start) != size)
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_name>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x2e,(%rdi)
  je     L99
L65:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L127
  test   %dl,%dl
  je     L127
L44:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L127
  test   %dl,%dl
  jne    L44
L127:
  mov    $0x0,%ecx
  cmp    $0x2f,%dl
  je     L64
  sub    %rdi,%rax
  movslq %esi,%rsi
  cmp    %rsi,%rax
  sete   %cl
  movzbl %cl,%ecx
L64:
  mov    %ecx,%eax
  ret
L99:
  movzbl 0x1(%rdi),%eax
  cmp    $0x2e,%al
  je     L91
  cmp    $0x2f,%al
  je     L4
  test   %al,%al
  je     L4
  mov    %rdi,%rax
  jmp    L44
L91:
  movzbl 0x2(%rdi),%eax
  cmp    $0x2f,%al
  je     L55
  test   %al,%al
  je     L55
  lea    0x1(%rdi),%rax
  jmp    L65
L55:
  mov    $0x0,%ecx
  jmp    L64
L4:
  mov    $0x0,%ecx
  jmp    L64
```

assistant: ```c
int check_name(char *name, int size) {
  char *start = name;
  if (name[0] == '.') {
    if (name[1] == '.')
      name++;
    if (name[1] == '/' || name[1] == '\0')
      return 0;
  }
  while (name[0] != '/' && name[0] != '\0')
    name++;
  if (name[0] == '/')
    return 0;
  if ((name - start) != size)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_name>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L115
  cmp    $0x2f,%al
  je     L74
  mov    %rdi,%rdx
  test   %al,%al
  je     L74
  cs nopw 0x0(%rax,%rax,1)
L24:
  movzbl 0x1(%rdx),%eax
L43:
  add    $0x1,%rdx
  cmp    $0x2f,%al
  je     L134
  test   %al,%al
  jne    L24
L134:
  xor    %r8d,%r8d
  cmp    $0x2f,%al
  je     L69
  sub    %rdi,%rdx
  movslq %esi,%rsi
  xor    %r8d,%r8d
  cmp    %rsi,%rdx
  sete   %r8b
L69:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L115:
  movzbl 0x1(%rdi),%eax
  cmp    $0x2e,%al
  je     L67
  cmp    $0x2f,%al
  je     L82
  test   %al,%al
  je     L82
  mov    %rdi,%rdx
  jmp    L43
  nopl   (%rax)
L82:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nop
L67:
  movzbl 0x2(%rdi),%eax
  cmp    $0x2f,%al
  je     L82
  test   %al,%al
  je     L82
  lea    0x1(%rdi),%rdx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %rdi,%rdx
  jmp    L134
```

assistant: ```c
int check_name(char *name, int size) {
  char *start = name;
  if (name[0] == '.') {
    if (name[1] == '.')
      name++;
    if (name[1] == '/' || name[1] == '\0')
      return 0;
  }
  while (name[0] != '/' && name[0] != '\0')
    name++;
  if (name[0] == '/')
    return 0;
  if ((name - start) != size)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_name>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L60
  cmp    $0x2f,%al
  je     L121
  mov    %rdi,%rdx
  test   %al,%al
  je     L121
  cs nopw 0x0(%rax,%rax,1)
L35:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    $0x2f,%al
  je     L23
  test   %al,%al
  jne    L35
L23:
  xor    %r8d,%r8d
  cmp    $0x2f,%al
  je     L102
  sub    %rdi,%rdx
  movslq %esi,%rsi
  xor    %r8d,%r8d
  cmp    %rsi,%rdx
  sete   %r8b
L102:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  movzbl 0x1(%rdi),%eax
  cmp    $0x2e,%al
  je     L22
  cmp    $0x2f,%al
  je     L50
  test   %al,%al
  je     L50
  mov    %rdi,%rdx
  jmp    L35
  nopl   (%rax)
L50:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nop
L22:
  movzbl 0x2(%rdi),%eax
  cmp    $0x2f,%al
  je     L50
  test   %al,%al
  je     L50
  lea    0x1(%rdi),%rdx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L121:
  mov    %rdi,%rdx
  jmp    L23
```

assistant: ```c
int check_name(char *name, int size) {
  char *start = name;
  if (name[0] == '.') {
    if (name[1] == '.')
      name++;
    if (name[1] == '/' || name[1] == '\0')
      return 0;
  }
  while (name[0] != '/' && name[0] != '\0')
    name++;
  if (name[0] == '/')
    return 0;
  if ((name - start) != size)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<digit_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L12:
  cmpq   $0x0,-0x18(%rbp)
  jne    L46
  cmpl   $0x0,-0x1c(%rbp)
  je     L25
L46:
  cmpl   $0x0,-0x1c(%rbp)
  je     L41
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L25
L41:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L12
L25:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int digit_usage(long long n, int d) {
  int i = 0, v = 0;
  while (1) {
    if ((n == 0 && d == 0) || (d != 0 && i == d))
      break;
    v |= 1 << (n % 10);
    n /= 10;
    i++;
  }
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<digit_usage>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%r8d
  test   %esi,%esi
  sete   %r11b
  test   %rdi,%rdi
  jne    L54
  test   %r11b,%r11b
  jne    L50
L54:
  push   %rbx
  test   %r8d,%r8d
  setne  %bl
  mov    $0x0,%edi
  mov    $0x0,%esi
  movabs $0x6666666666666667,%r10
  mov    $0x1,%r9d
L55:
  mov    %rcx,%rax
  imul   %r10
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r9d,%eax
  shl    %cl,%eax
  or     %eax,%edi
  mov    %rdx,%rcx
  add    $0x1,%esi
  test   %rdx,%rdx
  jne    L17
  test   %r11b,%r11b
  jne    L22
L17:
  cmp    %esi,%r8d
  jne    L55
  test   %bl,%bl
  je     L55
L22:
  mov    %edi,%eax
  pop    %rbx
  ret
L50:
  mov    $0x0,%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
int digit_usage(long long n, int d) {
  int i = 0, v = 0;
  while (1) {
    if ((n == 0 && d == 0) || (d != 0 && i == d))
      break;
    v |= 1 << (n % 10);
    n /= 10;
    i++;
  }
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<digit_usage>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  mov    %esi,%edi
  sete   %r11b
  test   %rcx,%rcx
  jne    L22
  test   %r11b,%r11b
  jne    L14
L22:
  test   %edi,%edi
  push   %rbx
  mov    $0x1,%r9d
  movabs $0x6666666666666667,%r10
  setne  %bl
  xor    %r8d,%r8d
  xor    %esi,%esi
  nopl   0x0(%rax)
L41:
  mov    %rcx,%rax
  add    $0x1,%esi
  imul   %r10
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r9d,%eax
  shl    %cl,%eax
  mov    %rdx,%rcx
  or     %eax,%r8d
  test   %rdx,%rdx
  jne    L54
  test   %r11b,%r11b
  jne    L23
L54:
  cmp    %esi,%edi
  jne    L41
  test   %bl,%bl
  je     L41
L23:
  mov    %r8d,%eax
  pop    %rbx
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int digit_usage(long long n, int d) {
  int i = 0, v = 0;
  while (1) {
    if ((n == 0 && d == 0) || (d != 0 && i == d))
      break;
    v |= 1 << (n % 10);
    n /= 10;
    i++;
  }
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<digit_usage>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  mov    %esi,%edi
  sete   %r11b
  test   %rcx,%rcx
  jne    L25
  test   %r11b,%r11b
  jne    L37
L25:
  test   %edi,%edi
  push   %rbx
  mov    $0x1,%r9d
  movabs $0x6666666666666667,%r10
  setne  %bl
  xor    %r8d,%r8d
  xor    %esi,%esi
  nopl   0x0(%rax)
L1:
  mov    %rcx,%rax
  add    $0x1,%esi
  imul   %r10
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r9d,%eax
  shl    %cl,%eax
  mov    %rdx,%rcx
  or     %eax,%r8d
  test   %rdx,%rdx
  jne    L27
  test   %r11b,%r11b
  jne    L30
L27:
  cmp    %esi,%edi
  jne    L1
  test   %bl,%bl
  je     L1
L30:
  mov    %r8d,%eax
  pop    %rbx
  ret
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
int digit_usage(long long n, int d) {
  int i = 0, v = 0;
  while (1) {
    if ((n == 0 && d == 0) || (d != 0 && i == d))
      break;
    v |= 1 << (n % 10);
    n /= 10;
    i++;
  }
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<EPINonBlockingReadConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x20,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x24,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EPINonBlockingReadConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDataSize, unsigned long ulAddress) {
  unsigned long ulOffset;
  ;
  ;
  ;
  ;
  ulOffset = ulChannel * (0x00000030 - 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000020 + ulOffset))) = ulDataSize;
  (*((volatile unsigned long *)(ulBase + 0x00000024 + ulOffset))) = ulAddress;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EPINonBlockingReadConfigure>:
  endbr64
  shl    $0x4,%rsi
  add    %rdi,%rsi
  mov    %rdx,0x20(%rsi)
  mov    %rcx,0x24(%rsi)
  ret
```

assistant: ```c
void EPINonBlockingReadConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDataSize, unsigned long ulAddress) {
  unsigned long ulOffset;
  ;
  ;
  ;
  ;
  ulOffset = ulChannel * (0x00000030 - 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000020 + ulOffset))) = ulDataSize;
  (*((volatile unsigned long *)(ulBase + 0x00000024 + ulOffset))) = ulAddress;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EPINonBlockingReadConfigure>:
  endbr64
  shl    $0x4,%rsi
  add    %rdi,%rsi
  mov    %rdx,0x20(%rsi)
  mov    %rcx,0x24(%rsi)
  ret
```

assistant: ```c
void EPINonBlockingReadConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDataSize, unsigned long ulAddress) {
  unsigned long ulOffset;
  ;
  ;
  ;
  ;
  ulOffset = ulChannel * (0x00000030 - 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000020 + ulOffset))) = ulDataSize;
  (*((volatile unsigned long *)(ulBase + 0x00000024 + ulOffset))) = ulAddress;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EPINonBlockingReadConfigure>:
  endbr64
  shl    $0x4,%rsi
  add    %rdi,%rsi
  mov    %rdx,0x20(%rsi)
  mov    %rcx,0x24(%rsi)
  ret
```

assistant: ```c
void EPINonBlockingReadConfigure(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDataSize, unsigned long ulAddress) {
  unsigned long ulOffset;
  ;
  ;
  ;
  ;
  ulOffset = ulChannel * (0x00000030 - 0x00000020);
  (*((volatile unsigned long *)(ulBase + 0x00000020 + ulOffset))) = ulDataSize;
  (*((volatile unsigned long *)(ulBase + 0x00000024 + ulOffset))) = ulAddress;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<___compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L9
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L2
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  leave
  ret
```

assistant: ```c
int ___compare(const char *a, const char *b) {
  if (*a == '.')
    ++a;
  if (*b == '.')
    ++b;
  return strcasecmp(a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<___compare>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x2e,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  cmpb   $0x2e,(%rsi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rsi
  call   <strcasecmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ___compare(const char *a, const char *b) {
  if (*a == '.')
    ++a;
  if (*b == '.')
    ++b;
  return strcasecmp(a, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<___compare>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x2e,(%rdi)
  sete   %al
  add    %rax,%rdi
  xor    %eax,%eax
  cmpb   $0x2e,(%rsi)
  sete   %al
  add    %rax,%rsi
  jmp    1050 <strcasecmp@plt>
```

assistant: ```c
int ___compare(const char *a, const char *b) {
  if (*a == '.')
    ++a;
  if (*b == '.')
    ++b;
  return strcasecmp(a, b);
}
```
user: What is the c source code of the assembly code below:

```asm
<simple_hash_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x21,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L12:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x10(%rbp),%eax
  shr    $0x5,%eax
  add    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int simple_hash_str(const char *str) {
  const int MULTIPLIER = 33;
  unsigned int h;
  unsigned const char *p;
  h = 0;
  for (p = (unsigned const char *)str; *p != '\0'; p++)
    h = MULTIPLIER * h + *p;
  h += (h >> 5);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<simple_hash_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
  mov    $0x0,%edx
L6:
  mov    %edx,%ecx
  shl    $0x5,%ecx
  add    %ecx,%edx
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L18:
  mov    %edx,%eax
  shr    $0x5,%eax
  add    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L18
```

assistant: ```c
unsigned int simple_hash_str(const char *str) {
  const int MULTIPLIER = 33;
  unsigned int h;
  unsigned const char *p;
  h = 0;
  for (p = (unsigned const char *)str; *p != '\0'; p++)
    h = MULTIPLIER * h + *p;
  h += (h >> 5);
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<simple_hash_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  xor    %edx,%edx
  nopl   (%rax)
L5:
  mov    %edx,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
  mov    %edx,%eax
  shr    $0x5,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int simple_hash_str(const char *str) {
  const int MULTIPLIER = 33;
  unsigned int h;
  unsigned const char *p;
  h = 0;
  for (p = (unsigned const char *)str; *p != '\0'; p++)
    h = MULTIPLIER * h + *p;
  h += (h >> 5);
  return h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simple_hash_str>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  xor    %edx,%edx
  nopl   (%rax)
L2:
  mov    %edx,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%edx
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
  mov    %edx,%eax
  shr    $0x5,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int simple_hash_str(const char *str) {
  const int MULTIPLIER = 33;
  unsigned int h;
  unsigned const char *p;
  h = 0;
  for (p = (unsigned const char *)str; *p != '\0'; p++)
    h = MULTIPLIER * h + *p;
  h += (h >> 5);
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<routine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: Hello from thread #%d


assistant: ```c
void *routine(void *arg) {
  int thrd_id = (int)arg;
  printf("Hello from thread #%d\n", thrd_id);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<routine>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: Hello from thread #%d


assistant: ```c
void *routine(void *arg) {
  int thrd_id = (int)arg;
  printf("Hello from thread #%d\n", thrd_id);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<routine>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: Hello from thread #%d


assistant: ```c
void *routine(void *arg) {
  int thrd_id = (int)arg;
  printf("Hello from thread #%d\n", thrd_id);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<routine>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: Hello from thread #%d


assistant: ```c
void *routine(void *arg) {
  int thrd_id = (int)arg;
  printf("Hello from thread #%d\n", thrd_id);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rw_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L30
L45:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L55
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x54(%rbp)
  cltq
  lea    -0x50(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x20,(%rax)
  jmp    L22
L55:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  je     L21
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x54(%rbp)
  cltq
  lea    -0x50(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L22
L21:
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x54(%rbp)
  cltq
  lea    -0x50(%rbp),%rcx
  lea    (%rcx,%rax,1),%rbx
  mov    %rdx,%rdi
  call   <rw_get_hexa@plt>
  mov    %al,(%rbx)
  addl   $0x2,-0x58(%rbp)
L22:
  addl   $0x1,-0x58(%rbp)
L30:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  mov    -0x54(%rbp),%eax
  cltq
  lea    -0x50(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    -0x50(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    $0x32,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void rw_decode(char *s) {
  char buf[50];
  int i, j;
  for (i = 0, j = 0; *(s + i) != '\0'; i++) {
    if (*(s + i) == '+')
      *(buf + j++) = ' ';
    else if (*(s + i) != '%')
      *(buf + j++) = *(s + i);
    else {
      *(buf + j++) = rw_get_hexa(s + i + 1);
      i += 2;
    }
  }
  *(buf + j) = '\0';
  strncpy(s, buf, 50);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rw_decode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L62
  mov    %rsp,%r12
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%edx
  jmp    L64
L8:
  mov    %ebp,%r14d
  movb   $0x20,(%r12)
L11:
  add    $0x1,%ebx
  movslq %ebx,%rdx
  movzbl 0x0(%r13,%rdx,1),%eax
  add    $0x1,%ebp
  add    $0x1,%r12
  test   %al,%al
  je     L9
L64:
  cmp    $0x2b,%al
  je     L8
  cmp    $0x25,%al
  je     L13
  mov    %ebp,%r14d
  mov    %al,(%r12)
  jmp    L11
L13:
  mov    %ebp,%r14d
  lea    0x1(%r13,%rdx,1),%rdi
  call   <rw_get_hexa@plt>
  mov    %al,(%r12)
  add    $0x2,%ebx
  jmp    L11
L62:
  mov    $0x0,%r14d
L9:
  movslq %r14d,%r14
  movb   $0x0,(%rsp,%r14,1)
  mov    %rsp,%rsi
  mov    $0x32,%edx
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rw_decode(char *s) {
  char buf[50];
  int i, j;
  for (i = 0, j = 0; *(s + i) != '\0'; i++) {
    if (*(s + i) == '+')
      *(buf + j++) = ' ';
    else if (*(s + i) != '%')
      *(buf + j++) = *(s + i);
    else {
      *(buf + j++) = rw_get_hexa(s + i + 1);
      i += 2;
    }
  }
  *(buf + j) = '\0';
  strncpy(s, buf, 50);
}
```