ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  mov    $0x0,%r9d
  cmp    $0x1,%esi
  jle    L0
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L22:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L22
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L33:
  cmp    $0x1,%esi
  je     L6
L23:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  movzwl %ax,%eax
  ret
L0:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L33
L6:
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
  jmp    L23
```

assistant: ```c
int checksum(unsigned short *addr, int len) {
  int sum = 0;
  int nleft = len;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<checksum>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L10
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nop
L37:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L37
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L8:
  cmp    $0x1,%esi
  jne    L11
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
L11:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  movzwl %ax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
int checksum(unsigned short *addr, int len) {
  int sum = 0;
  int nleft = len;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L126
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L51
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L81:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm3
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L81
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddd  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm0,%eax
  cmp    %r8d,%ecx
  je     L29
L55:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L29
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L29
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L29
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L29
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L29
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L29
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L29:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L76:
  cmp    $0x1,%esi
  jne    L52
  mov    (%rdx),%r10b
  movzwl %r10w,%edx
  add    %edx,%eax
L52:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  movzwl %ax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L126:
  xor    %eax,%eax
  jmp    L76
L51:
  xor    %eax,%eax
  jmp    L55
```

assistant: ```c
int checksum(unsigned short *addr, int len) {
  int sum = 0;
  int nleft = len;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inserirOrdenadoInode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L16:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L17
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L17
  addl   $0x1,-0x10(%rbp)
L33:
  cmpl   $0x63,-0x10(%rbp)
  jle    L16
L17:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L10
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L21
L10:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L22
L77:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L22:
  cmpl   $0x63,-0xc(%rbp)
  jle    L77
L21:
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int inserirOrdenadoInode(int *index_keys, int key) {
  int i, v;
  int aux, anterior;
  for (i = 0; i < 2 * 50; i++) {
    if (key < index_keys[i] || index_keys[i] == 0)
      break;
  }
  if (index_keys[i] == 0) {
    index_keys[i] = key;
  } else {
    anterior = key;
    for (v = i; v < 2 * 50; v++) {
      aux = index_keys[v];
      index_keys[v] = anterior;
      anterior = aux;
    }
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inserirOrdenadoInode>:
  endbr64
  mov    %rdi,%rcx
  mov    $0x0,%eax
L33:
  mov    (%rcx),%edx
  test   %edx,%edx
  je     L36
  cmp    %esi,%edx
  jg     L36
  add    $0x1,%eax
  add    $0x4,%rcx
  cmp    $0x64,%eax
  jne    L33
  lea    0x190(%rdi),%rdx
  cmpl   $0x0,0x190(%rdi)
  jne    L13
L52:
  mov    %esi,(%rdx)
  ret
L36:
  movslq %eax,%r8
  lea    (%rdi,%r8,4),%rdx
  cmpl   $0x0,(%rdx)
  je     L52
  cmp    $0x63,%eax
  jg     L6
  mov    $0x63,%ecx
  sub    %eax,%ecx
  add    %r8,%rcx
  lea    0x4(%rdi,%rcx,4),%rdi
L48:
  mov    %esi,%ecx
  mov    (%rdx),%esi
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L48
  ret
L6:
  ret
L13:
  ret
```

assistant: ```c
int inserirOrdenadoInode(int *index_keys, int key) {
  int i, v;
  int aux, anterior;
  for (i = 0; i < 2 * 50; i++) {
    if (key < index_keys[i] || index_keys[i] == 0)
      break;
  }
  if (index_keys[i] == 0) {
    index_keys[i] = key;
  } else {
    anterior = key;
    for (v = i; v < 2 * 50; v++) {
      aux = index_keys[v];
      index_keys[v] = anterior;
      anterior = aux;
    }
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inserirOrdenadoInode>:
  endbr64
  mov    %rdi,%rax
  xor    %r8d,%r8d
  jmp    L32
  nopl   0x0(%rax)
L6:
  test   %edx,%edx
  je     L5
  add    $0x1,%r8d
  add    $0x4,%rax
  cmp    $0x64,%r8d
  je     L50
L32:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jle    L6
  test   %edx,%edx
  je     L5
  mov    $0x63,%ecx
  movslq %r8d,%r9
  sub    %r8d,%ecx
  lea    (%rdi,%r9,4),%rax
  add    %r9,%rcx
  lea    0x4(%rdi,%rcx,4),%rcx
  jmp    L25
  nopl   (%rax)
L41:
  mov    %edx,%esi
  mov    (%rax),%edx
L25:
  mov    %esi,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L41
  mov    %r8d,%eax
  ret
L50:
  mov    0x190(%rdi),%eax
  test   %eax,%eax
  jne    L38
  lea    0x190(%rdi),%rax
  nopl   0x0(%rax)
L5:
  mov    %esi,(%rax)
L38:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int inserirOrdenadoInode(int *index_keys, int key) {
  int i, v;
  int aux, anterior;
  for (i = 0; i < 2 * 50; i++) {
    if (key < index_keys[i] || index_keys[i] == 0)
      break;
  }
  if (index_keys[i] == 0) {
    index_keys[i] = key;
  } else {
    anterior = key;
    for (v = i; v < 2 * 50; v++) {
      aux = index_keys[v];
      index_keys[v] = anterior;
      anterior = aux;
    }
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inserirOrdenadoInode>:
  endbr64
  mov    %rdi,%rax
  xor    %r8d,%r8d
  jmp    L38
  nopl   0x0(%rax)
L51:
  test   %edx,%edx
  je     L64
  add    $0x1,%r8d
  add    $0x4,%rax
  cmp    $0x64,%r8d
  je     L42
L38:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jle    L51
  test   %edx,%edx
  je     L64
  mov    $0x63,%edx
  movslq %r8d,%rcx
  sub    %r8d,%edx
  lea    (%rdi,%rcx,4),%rax
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %esi,%edx
  add    $0x4,%rax
  mov    -0x4(%rax),%esi
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L68
  mov    %r8d,%eax
  ret
L42:
  mov    0x190(%rdi),%eax
  test   %eax,%eax
  jne    L57
  lea    0x190(%rdi),%rax
  xchg   %ax,%ax
L64:
  mov    %esi,(%rax)
L57:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int inserirOrdenadoInode(int *index_keys, int key) {
  int i, v;
  int aux, anterior;
  for (i = 0; i < 2 * 50; i++) {
    if (key < index_keys[i] || index_keys[i] == 0)
      break;
  }
  if (index_keys[i] == 0) {
    index_keys[i] = key;
  } else {
    anterior = key;
    for (v = i; v < 2 * 50; v++) {
      aux = index_keys[v];
      index_keys[v] = anterior;
      anterior = aux;
    }
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  jmp    L3
L0:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L3:
  leave
  ret
```

assistant: ```c
char *split(char *str, const char *spl) {
  char *pos = str + strcspn(str, spl);
  if (*pos == '\0')
    return NULL;
  *pos = '\0';
  return pos + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<split>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x0,(%rax)
  je     L5
  movb   $0x0,(%rax)
  add    $0x1,%rax
L9:
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
char *split(char *str, const char *spl) {
  char *pos = str + strcspn(str, spl);
  if (*pos == '\0')
    return NULL;
  *pos = '\0';
  return pos + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x0,(%rax)
  je     L1
  movb   $0x0,(%rax)
  add    $0x1,%rax
  pop    %rbx
  ret
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *split(char *str, const char *spl) {
  char *pos = str + strcspn(str, spl);
  if (*pos == '\0')
    return NULL;
  *pos = '\0';
  return pos + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<split>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  cmpb   $0x0,(%rax)
  je     L5
  movb   $0x0,(%rax)
  add    $0x1,%rax
  pop    %rbx
  ret
L5:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *split(char *str, const char *spl) {
  char *pos = str + strcspn(str, spl);
  if (*pos == '\0')
    return NULL;
  *pos = '\0';
  return pos + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x420(%rbp)
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L35
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L44
L35:
  mov    -0x418(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getlogin_r@plt>
  mov    %eax,-0x41c(%rbp)
  cmpl   $0x0,-0x41c(%rbp)
  jne    L54
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L44
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x420(%rbp)
  jmp    L44
L54:
  mov    -0x41c(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rdx
  mov    -0x41c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x420(%rbp)
L44:
  cmpl   $0x0,-0x420(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D33
type_guessed: string
name: retrieve_data
arguments: label: D36
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string

tool: D33: getlogin returned NULL, no further tests

tool: D36: getlogin returned: `%s'


tool: D3: getlogin_r returned: `%s'


tool: D0: Error: getlogin and getlogin_r returned different names

tool: D20: Error: getlogin_r returned: %d (%s)


assistant: ```c
int main(void) {
  char *login;
  int errors = 0;
  login = getlogin();
  if (login == NULL)
    puts("getlogin returned NULL, no further tests");
  else {
    char name[1024];
    int ret;
    printf("getlogin returned: `%s'\n", login);
    ret = getlogin_r(name, sizeof(name));
    if (ret == 0) {
      printf("getlogin_r returned: `%s'\n", name);
      if (strcmp(name, login) != 0) {
        puts("Error: getlogin and getlogin_r returned different names");
        ++errors;
      }
    } else {
      printf("Error: getlogin_r returned: %d (%s)\n", ret, strerror(ret));
      ++errors;
    }
  }
  return errors != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <getlogin@plt>
  test   %rax,%rax
  je     L42
  mov    %rax,%rbp
  mov    %rax,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <getlogin_r@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L59
  mov    %rsp,%r12
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L54
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  jmp    L54
L42:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  jmp    L54
L59:
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rdx
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
L54:
  test   %ebx,%ebx
  setne  %al
  movzbl %al,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D30
datatype: string
name: read_data
arguments: data_label: D6
datatype: string
name: read_data
arguments: data_label: D23
datatype: string
name: read_data
arguments: data_label: D0
datatype: string
name: read_data
arguments: data_label: D20
datatype: string

tool: D30: getlogin returned: `%s'


tool: D6: getlogin_r returned: `%s'


tool: D23: Error: getlogin and getlogin_r returned different names

tool: D0: getlogin returned NULL, no further tests

tool: D20: Error: getlogin_r returned: %d (%s)


assistant: ```c
int main(void) {
  char *login;
  int errors = 0;
  login = getlogin();
  if (login == NULL)
    puts("getlogin returned NULL, no further tests");
  else {
    char name[1024];
    int ret;
    printf("getlogin returned: `%s'\n", login);
    ret = getlogin_r(name, sizeof(name));
    if (ret == 0) {
      printf("getlogin_r returned: `%s'\n", name);
      if (strcmp(name, login) != 0) {
        puts("Error: getlogin and getlogin_r returned different names");
        ++errors;
      }
    } else {
      printf("Error: getlogin_r returned: %d (%s)\n", ret, strerror(ret));
      ++errors;
    }
  }
  return errors != 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <getlogin@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rsi
  lea    D37(%rip),%rdi
  mov    %rax,%rbp
  mov    %rsp,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <getlogin_r@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L44
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %r12d,%esi
  lea    D42(%rip),%rdi
  mov    $0x1,%r12d
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    %r13,%rsi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L29
  lea    D15(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L29
L3:
  lea    D23(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L29
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
data_type: string
name: parse_data
arguments: data_tag: D42
data_type: string
name: parse_data
arguments: data_tag: D47
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string

tool: D37: getlogin returned: `%s'


tool: D42: Error: getlogin_r returned: %d (%s)


tool: D47: getlogin_r returned: `%s'


tool: D15: Error: getlogin and getlogin_r returned different names

tool: D23: getlogin returned NULL, no further tests

assistant: ```c
int main(void) {
  char *login;
  int errors = 0;
  login = getlogin();
  if (login == NULL)
    puts("getlogin returned NULL, no further tests");
  else {
    char name[1024];
    int ret;
    printf("getlogin returned: `%s'\n", login);
    ret = getlogin_r(name, sizeof(name));
    if (ret == 0) {
      printf("getlogin_r returned: `%s'\n", name);
      if (strcmp(name, login) != 0) {
        puts("Error: getlogin and getlogin_r returned different names");
        ++errors;
      }
    } else {
      printf("Error: getlogin_r returned: %d (%s)\n", ret, strerror(ret));
      ++errors;
    }
  }
  return errors != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <getlogin@plt>
  test   %rax,%rax
  je     L32
  mov    %rax,%rsi
  lea    D28(%rip),%rdi
  mov    %rax,%rbp
  mov    %rsp,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x400,%esi
  mov    %r13,%rdi
  call   <getlogin_r@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L24
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %r12d,%esi
  lea    D49(%rip),%rdi
  mov    $0x1,%r12d
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L12:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %r13,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L12
  lea    D20(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L12
L32:
  lea    D41(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L12
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D49
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string

tool: D28: getlogin returned: `%s'


tool: D49: Error: getlogin_r returned: %d (%s)


tool: D12: getlogin_r returned: `%s'


tool: D20: Error: getlogin and getlogin_r returned different names

tool: D41: getlogin returned NULL, no further tests

assistant: ```c
int main(void) {
  char *login;
  int errors = 0;
  login = getlogin();
  if (login == NULL)
    puts("getlogin returned NULL, no further tests");
  else {
    char name[1024];
    int ret;
    printf("getlogin returned: `%s'\n", login);
    ret = getlogin_r(name, sizeof(name));
    if (ret == 0) {
      printf("getlogin_r returned: `%s'\n", name);
      if (strcmp(name, login) != 0) {
        puts("Error: getlogin and getlogin_r returned different names");
        ++errors;
      }
    } else {
      printf("Error: getlogin_r returned: %d (%s)\n", ret, strerror(ret));
      ++errors;
    }
  }
  return errors != 0;
}
```