ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
  jmp    L64
L8:
  mov    %eax,%edx
L60:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%esi
  sub    %eax,%esi
  cmp    %ebx,%esi
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  cmp    $0x9,%edx
  jg     L8
  test   %ecx,%ecx
  jne    L52
L59:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L72
L64:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L59
  mov    $0x0,%ecx
  jmp    L60
L52:
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L72:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string

tool: D9: Chislo:

tool: D0: %d

tool: D17: Cifrata %d e napisana %d puti


assistant: ```c
int main() {
  int cifra, chislo, neshto, broi;
  printf("Chislo:");
  scanf("%d", &chislo);
  for (cifra = 0; cifra < 10; cifra++) {
    broi = 0;
    neshto = chislo;
    while (neshto >= 1) {
      if (neshto % 10 == cifra)
        broi++;
      neshto /= 10;
    }
    if (broi != 0)
      printf("Cifrata %d e napisana %d puti\n", cifra, broi);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D20(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L58
  xor    %r8d,%r8d
  jmp    L33
  nopl   (%rax)
L21:
  mov    %eax,%edx
L33:
  mov    %edx,%eax
  mov    %edx,%esi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  xor    %ecx,%ecx
  cmp    %r12d,%esi
  sete   %cl
  add    %ecx,%r8d
  cmp    $0x9,%edx
  jg     L21
  test   %r8d,%r8d
  je     L58
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L26
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D20
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D27: Chislo:

tool: D20: Cifrata %d e napisana %d puti


tool: D9: %d

assistant: ```c
int main() {
  int cifra, chislo, neshto, broi;
  printf("Chislo:");
  scanf("%d", &chislo);
  for (cifra = 0; cifra < 10; cifra++) {
    broi = 0;
    neshto = chislo;
    while (neshto >= 1) {
      if (neshto % 10 == cifra)
        broi++;
      neshto /= 10;
    }
    if (broi != 0)
      printf("Cifrata %d e napisana %d puti\n", cifra, broi);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L55
  xor    %r8d,%r8d
  jmp    L58
  nopl   (%rax)
L19:
  mov    %eax,%edx
L58:
  mov    %edx,%eax
  mov    %edx,%esi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  xor    %ecx,%ecx
  cmp    %esi,%r12d
  sete   %cl
  add    %ecx,%r8d
  cmp    $0x9,%edx
  jg     L19
  test   %r8d,%r8d
  je     L35
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L35:
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L15
  nopl   0x0(%rax)
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string

tool: D24: Chislo:

tool: D15: Cifrata %d e napisana %d puti


tool: D20: %d

assistant: ```c
int main() {
  int cifra, chislo, neshto, broi;
  printf("Chislo:");
  scanf("%d", &chislo);
  for (cifra = 0; cifra < 10; cifra++) {
    broi = 0;
    neshto = chislo;
    while (neshto >= 1) {
      if (neshto % 10 == cifra)
        broi++;
      neshto /= 10;
    }
    if (broi != 0)
      printf("Cifrata %d e napisana %d puti\n", cifra, broi);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L30
  mov    -0x18(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L76
L30:
  mov    $0x2,%eax
  jmp    L49
L76:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L70
  mov    $0xffffffff,%eax
  jmp    L49
L70:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L53
  mov    $0x1,%eax
  jmp    L49
L53:
  mov    $0x0,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L74
  call   <__stack_chk_fail@plt>
L74:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D16: .

tool: D17: ..

assistant: ```c
int path_state(char *path) {
  struct stat fs;
  if (!strcmp(path, ".") || !strcmp(path, "..")) {
    return 2;
  }
  if (stat(path, &fs) < 0) {
    return -1;
  }
  if (S_ISDIR(fs.st_mode)) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_state>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L5
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L5
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L7
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L5
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string

tool: D16: .

tool: D12: ..

assistant: ```c
int path_state(char *path) {
  struct stat fs;
  if (!strcmp(path, ".") || !strcmp(path, "..")) {
    return 2;
  }
  if (stat(path, &fs) < 0) {
    return -1;
  }
  if (S_ISDIR(fs.st_mode)) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_state>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x2e,(%rdi)
  jne    L91
  cmpb   $0x0,0x1(%rdi)
  mov    $0x2,%eax
  jne    L91
L58:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L91:
  cmpb   $0x2e,(%rdi)
  je     L16
L1:
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L64
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L16:
  cmpb   $0x2e,0x1(%rdi)
  jne    L1
  cmpb   $0x0,0x2(%rdi)
  mov    $0x2,%eax
  je     L58
  jmp    L1
L64:
  mov    $0xffffffff,%eax
  jmp    L58
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int path_state(char *path) {
  struct stat fs;
  if (!strcmp(path, ".") || !strcmp(path, "..")) {
    return 2;
  }
  if (stat(path, &fs) < 0) {
    return -1;
  }
  if (S_ISDIR(fs.st_mode)) {
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<path_state>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x2e,(%rdi)
  jne    L73
  cmpb   $0x0,0x1(%rdi)
  mov    $0x2,%eax
  jne    L73
L76:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L73:
  cmpb   $0x2e,(%rdi)
  je     L27
L15:
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L32
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L27:
  cmpb   $0x2e,0x1(%rdi)
  jne    L15
  cmpb   $0x0,0x2(%rdi)
  mov    $0x2,%eax
  je     L76
  jmp    L15
L32:
  mov    $0xffffffff,%eax
  jmp    L76
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int path_state(char *path) {
  struct stat fs;
  if (!strcmp(path, ".") || !strcmp(path, "..")) {
    return 2;
  }
  if (stat(path, &fs) < 0) {
    return -1;
  }
  if (S_ISDIR(fs.st_mode)) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L12
  mov    $0x0,%eax
  jmp    L23
L12:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L38
  mov    $0x1,%eax
  jmp    L23
L38:
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
bool strend(const char *str, const char *tail) {
  size_t str_len = strlen(str);
  size_t tail_len = strlen(tail);
  if (tail_len > str_len)
    return false;
  else if (strcmp(tail, str + str_len - tail_len) == 0)
    return true;
  else
    return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strend>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %rax,%rbp
  jae    L9
L8:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L8
```

assistant: ```c
bool strend(const char *str, const char *tail) {
  size_t str_len = strlen(str);
  size_t tail_len = strlen(tail);
  if (tail_len > str_len)
    return false;
  else if (strcmp(tail, str + str_len - tail_len) == 0)
    return true;
  else
    return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strend>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jb     L9
  sub    %rax,%rbp
  mov    %r12,%rdi
  lea    (%rbx,%rbp,1),%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L9:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strend(const char *str, const char *tail) {
  size_t str_len = strlen(str);
  size_t tail_len = strlen(tail);
  if (tail_len > str_len)
    return false;
  else if (strcmp(tail, str + str_len - tail_len) == 0)
    return true;
  else
    return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strend>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jb     L1
  sub    %rax,%rbp
  mov    %r12,%rdi
  lea    (%rbx,%rbp,1),%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L1:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strend(const char *str, const char *tail) {
  size_t str_len = strlen(str);
  size_t tail_len = strlen(tail);
  if (tail_len > str_len)
    return false;
  else if (strcmp(tail, str + str_len - tail_len) == 0)
    return true;
  else
    return false;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  movabs $0xfb93e672fa98528d,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x9,%rdx
  mov    %rdx,%rax
  shl    $0x6,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_uid(const uid_t uid) {
  unsigned long h = (unsigned long)uid;
  return h % (521);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_uid>:
  endbr64
  movabs $0xfb93e672fa98528d,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  add    %rax,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_uid(const uid_t uid) {
  unsigned long h = (unsigned long)uid;
  return h % (521);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_uid>:
  endbr64
  movabs $0xfb93e672fa98528d,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  add    %rax,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_uid(const uid_t uid) {
  unsigned long h = (unsigned long)uid;
  return h % (521);
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_uid>:
  endbr64
  movabs $0xfb93e672fa98528d,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  add    %rax,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long hash_uid(const uid_t uid) {
  unsigned long h = (unsigned long)uid;
  return h % (521);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fibSumEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L18
  mov    -0x20(%rbp),%eax
  jmp    L0
L18:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L21
  mov    -0x4(%rbp),%eax
  add    %eax,-0x20(%rbp)
L21:
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <fibSumEven>
L0:
  leave
  ret
```

assistant: ```c
int fibSumEven(int term1, int term2, int max, int sum) {
  int term = term1 + term2;
  if (term > max)
    return sum;
  if (term % 2 == 0) {
    sum += term;
  }
  return fibSumEven(term2, term, max, sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fibSumEven>:
  endbr64
  mov    %esi,%r8d
  lea    (%rdi,%rsi,1),%esi
  mov    %ecx,%eax
  cmp    %edx,%esi
  jg     L3
  sub    $0x8,%rsp
  lea    (%rcx,%rsi,1),%eax
  test   $0x1,%sil
  cmove  %eax,%ecx
  mov    %r8d,%edi
  call   <fibSumEven>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
int fibSumEven(int term1, int term2, int max, int sum) {
  int term = term1 + term2;
  if (term > max)
    return sum;
  if (term % 2 == 0) {
    sum += term;
  }
  return fibSumEven(term2, term, max, sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fibSumEven>:
  endbr64
  add    %esi,%edi
  mov    %ecx,%eax
  cmp    %edi,%edx
  jge    L2
  jmp    L6
  xchg   %ax,%ax
L25:
  mov    %ecx,%edi
L2:
  lea    (%rax,%rdi,1),%ecx
  test   $0x1,%dil
  cmove  %ecx,%eax
  lea    (%rsi,%rdi,1),%ecx
  mov    %edi,%esi
  cmp    %edx,%ecx
  jle    L25
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
int fibSumEven(int term1, int term2, int max, int sum) {
  int term = term1 + term2;
  if (term > max)
    return sum;
  if (term % 2 == 0) {
    sum += term;
  }
  return fibSumEven(term2, term, max, sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fibSumEven>:
  endbr64
  add    %esi,%edi
  mov    %ecx,%eax
  cmp    %edi,%edx
  jge    L18
  jmp    L5
  xchg   %ax,%ax
L0:
  mov    %ecx,%edi
L18:
  lea    (%rax,%rdi,1),%ecx
  test   $0x1,%dil
  cmove  %ecx,%eax
  lea    (%rdi,%rsi,1),%ecx
  mov    %edi,%esi
  cmp    %ecx,%edx
  jge    L0
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
int fibSumEven(int term1, int term2, int max, int sum) {
  int term = term1 + term2;
  if (term > max)
    return sum;
  if (term % 2 == 0) {
    sum += term;
  }
  return fibSumEven(term2, term, max, sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scanbinfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x120(%rbp)
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x140(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0xfa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x16(%rbp)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x128(%rbp)
  cmpl   $0x1,-0x128(%rbp)
  jle    L32
  mov    -0x128(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  lea    -0x110(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L32
  mov    -0x118(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L32
  mov    -0x118(%rbp),%rax
  movb   $0x0,(%rax)
L32:
  movb   $0x0,D39(%rip)
  lea    -0x110(%rbp),%rdx
  mov    -0x138(%rbp),%rax
  lea    D39(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <read_acqufile_bin@plt>
  mov    %eax,-0x124(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    -0x120(%rbp),%rcx
  mov    -0x138(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fseek@plt>
  cmpl   $0x0,-0x124(%rbp)
  je     L25
  lea    D39(%rip),%rax
  jmp    L23
L25:
  mov    $0x0,%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
char *scanbinfile(FILE *file, char *pattern1) {
  static char resultbuf[250 + 1];
  char *p, pattern[250 + 1], buf[250 + 1];
  int len, ok;
  long pos = ftell(file);
  rewind(file);
  strncpy(pattern, pattern1, 250);
  pattern[250] = '\0';
  len = strlen(pattern);
  if (len >= 2) {
    p = pattern + len - 2;
    if (p[0] == '%' && p[1] == 's')
      *p = '\0';
  }
  resultbuf[0] = '\0';
  ok = read_acqufile_bin(file, resultbuf, pattern);
  fseek(file, pos, SEEK_SET);
  if (ok)
    return resultbuf;
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scanbinfile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <ftell@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    %rsp,%r13
  mov    $0xfa,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0xfa(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L49
  cltq
  lea    -0x2(%rsp,%rax,1),%rax
  cmpb   $0x25,(%rax)
  je     L23
L49:
  movb   $0x0,D8(%rip)
  mov    %rsp,%rdx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <read_acqufile_bin@plt>
  mov    %eax,%ebp
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fseek@plt>
  test   %ebp,%ebp
  lea    D8(%rip),%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  cmpb   $0x73,0x1(%rax)
  jne    L49
  movb   $0x0,(%rax)
  jmp    L49
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *scanbinfile(FILE *file, char *pattern1) {
  static char resultbuf[250 + 1];
  char *p, pattern[250 + 1], buf[250 + 1];
  int len, ok;
  long pos = ftell(file);
  rewind(file);
  strncpy(pattern, pattern1, 250);
  pattern[250] = '\0';
  len = strlen(pattern);
  if (len >= 2) {
    p = pattern + len - 2;
    if (p[0] == '%' && p[1] == 's')
      *p = '\0';
  }
  resultbuf[0] = '\0';
  ok = read_acqufile_bin(file, resultbuf, pattern);
  fseek(file, pos, SEEK_SET);
  if (ok)
    return resultbuf;
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scanbinfile>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <ftell@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <rewind@plt>
  mov    %r13,%rdi
  mov    $0xfa,%edx
  mov    %r14,%rsi
  call   <strncpy@plt>
  mov    %r13,%rdi
  movb   $0x0,0xfa(%rsp)
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L30
  cltq
  lea    -0x2(%r13,%rax,1),%rax
  cmpb   $0x25,(%rax)
  je     L17
L30:
  lea    D11(%rip),%rbx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  movb   $0x0,D11(%rip)
  mov    %rbx,%rsi
  call   <read_acqufile_bin@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  xor    %eax,%eax
  test   %r13d,%r13d
  cmovne %rbx,%rax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L17:
  cmpb   $0x73,0x1(%rax)
  jne    L30
  movb   $0x0,(%rax)
  jmp    L30
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *scanbinfile(FILE *file, char *pattern1) {
  static char resultbuf[250 + 1];
  char *p, pattern[250 + 1], buf[250 + 1];
  int len, ok;
  long pos = ftell(file);
  rewind(file);
  strncpy(pattern, pattern1, 250);
  pattern[250] = '\0';
  len = strlen(pattern);
  if (len >= 2) {
    p = pattern + len - 2;
    if (p[0] == '%' && p[1] == 's')
      *p = '\0';
  }
  resultbuf[0] = '\0';
  ok = read_acqufile_bin(file, resultbuf, pattern);
  fseek(file, pos, SEEK_SET);
  if (ok)
    return resultbuf;
  return NULL;
}
```