ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<getnum_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  cmp    %rax,%rsi
  jb     L136
  mov    %rdi,%rbx
  mov    %rsi,%r12
  xor    %r13d,%r13d
  xor    %r14d,%r14d
L1:
  mov    (%rax),%ebp
  mov    %ebp,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L187
  test   %ebp,%ebp
  jne    L140
L187:
  test   %r13d,%r13d
  je     L169
L98:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L140:
  cmp    $0x3b,%ebp
  je     L164
  lea    -0x30(%rbp),%edx
  cmp    $0x9,%edx
  ja     L143
  mov    (%rbx),%rax
  lea    (%r14,%r14,4),%ecx
  mov    $0x1,%r13d
  lea    (%rdx,%rcx,2),%r14d
  add    $0x4,%rax
  mov    %rax,(%rbx)
L78:
  cmp    %rax,%r12
  jae    L1
  jmp    L98
  nopl   0x0(%rax)
L169:
  mov    (%rbx),%rax
  add    $0x4,%rax
  mov    %rax,(%rbx)
  jmp    L78
  nopl   0x0(%rax)
L164:
  mov    (%rbx),%rax
  cmp    %rax,%r12
  jae    L33
  jmp    L177
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x4,%rax
  mov    %rax,(%rbx)
  cmp    %r12,%rax
  ja     L177
L33:
  cmpl   $0xa,(%rax)
  jne    L2
L177:
  test   %r13d,%r13d
  jne    L98
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L136:
  xor    %r14d,%r14d
  jmp    L98
L143:
  cmp    $0x29,%ebp
  jne    L41
  test   %r13d,%r13d
  je     L41
  subq   $0x4,(%rbx)
  jmp    L98
L41:
  or     $0xffffffff,%r14d
  jmp    L98
```

assistant: ```c
int getnum_str(u_char **startpp, u_char *endp) {
  int c, n;
  int seendigit = 0;
  int m = 0;
  for (n = 0; *startpp <= endp;) {
    c = **startpp;
    if (isspace(c) || c == '\0') {
      if (seendigit)
        break;
      else {
        (*startpp)++;
        continue;
      }
    }
    if (c == ';') {
      while ((*startpp <= endp) && ((c = **startpp) != '\n'))
        (*startpp)++;
      if (seendigit)
        break;
      continue;
    }
    if (!isdigit(c)) {
      if (c == ')' && seendigit) {
        (*startpp)--;
        break;
      }
      return (-1);
    }
    (*startpp)++;
    n = n * 10 + (c - '0');
    seendigit = 1;
  }
  return (n + m);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<putchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
L7:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <ASM@plt>
  and    $0x2,%eax
  test   %eax,%eax
  jne    L7
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <ASM@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <ASM@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D24:  IN (IN_STATUS), RU

tool: D10:  MOVE 2(SP), RU

tool: D4:  OUT  R, (OUT_TX_DATA)

assistant: ```c
int putchr(char c) {
  while (ASM(" IN (IN_STATUS), RU") & 0x02)
    ;
  ASM(" MOVE 2(SP), RU");
  ASM(" OUT  R, (OUT_TX_DATA)");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<putchr>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
L3:
  mov    %rbx,%rdi
  call   <ASM@plt>
  test   $0x2,%al
  jne    L3
  lea    D3(%rip),%rdi
  call   <ASM@plt>
  lea    D2(%rip),%rdi
  call   <ASM@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D4:  IN (IN_STATUS), RU

tool: D3:  MOVE 2(SP), RU

tool: D2:  OUT  R, (OUT_TX_DATA)

assistant: ```c
int putchr(char c) {
  while (ASM(" IN (IN_STATUS), RU") & 0x02)
    ;
  ASM(" MOVE 2(SP), RU");
  ASM(" OUT  R, (OUT_TX_DATA)");
}
```
user: What is the c source code of the assembly code below?

```asm
<putchr>:
  endbr64
  push   %rbx
  lea    D28(%rip),%rbx
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <ASM@plt>
  test   $0x2,%al
  jne    L4
  lea    D1(%rip),%rdi
  call   <ASM@plt>
  lea    D22(%rip),%rdi
  pop    %rbx
  jmp    1050 <ASM@plt>
```

tool_calls: name: parse_data
arguments: label: D28
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D22
type: string

tool: D28:  IN (IN_STATUS), RU

tool: D1:  MOVE 2(SP), RU

tool: D22:  OUT  R, (OUT_TX_DATA)

assistant: ```c
int putchr(char c) {
  while (ASM(" IN (IN_STATUS), RU") & 0x02)
    ;
  ASM(" MOVE 2(SP), RU");
  ASM(" OUT  R, (OUT_TX_DATA)");
}
```
user: What is the c source code of the assembly code below:

```asm
<putchr>:
  endbr64
  push   %rbx
  lea    D20(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdi
  call   <ASM@plt>
  test   $0x2,%al
  jne    L2
  lea    D17(%rip),%rdi
  call   <ASM@plt>
  lea    D2(%rip),%rdi
  pop    %rbx
  jmp    1050 <ASM@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D20:  IN (IN_STATUS), RU

tool: D17:  MOVE 2(SP), RU

tool: D2:  OUT  R, (OUT_TX_DATA)

assistant: ```c
int putchr(char c) {
  while (ASM(" IN (IN_STATUS), RU") & 0x02)
    ;
  ASM(" MOVE 2(SP), RU");
  ASM(" OUT  R, (OUT_TX_DATA)");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x67706a2e796d6f64,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x47504a,-0x15(%rbp)
  lea    -0x15(%rbp),%rdx
  lea    -0x11(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <test_extension@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main(void) {
  char f[] = "domy.jpg";
  char ext[] = "JPG";
  printf("%d\n", test_extension(f, ext));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x67706a2e796d6f64,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x0,0x17(%rsp)
  movl   $0x47504a,0xb(%rsp)
  lea    0xb(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  call   <test_extension@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(void) {
  char f[] = "domy.jpg";
  char ext[] = "JPG";
  printf("%d\n", test_extension(f, ext));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x67706a2e796d6f64,%rax
  lea    0xb(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  movl   $0x47504a,0xb(%rsp)
  mov    %rax,0xf(%rsp)
  call   <test_extension@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: %d


assistant: ```c
int main(void) {
  char f[] = "domy.jpg";
  char ext[] = "JPG";
  printf("%d\n", test_extension(f, ext));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x67706a2e796d6f64,%rax
  lea    0xb(%rsp),%rsi
  lea    0xf(%rsp),%rdi
  movb   $0x0,0x17(%rsp)
  movl   $0x47504a,0xb(%rsp)
  mov    %rax,0xf(%rsp)
  call   <test_extension@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(void) {
  char f[] = "domy.jpg";
  char ext[] = "JPG";
  printf("%d\n", test_extension(f, ext));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L20:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L41
  movss  -0x4(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L41:
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x80]}

assistant: ```c
normal(s, n, dt, scl) float *s, *dt, *scl;
int n;
{
  int i;
  float sum = 0.0;
  for (i = 0; i < n; i++)
    sum = sum + s[i] * (*dt);
  sum = (*scl) / sum;
  if (sum < 0.0)
    sum = -sum;
  for (i = 0; i < n; i++)
    s[i] = s[i] * sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<normal>:
  endbr64
  test   %esi,%esi
  jle    L43
  movss  (%rdx),%xmm2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L5:
  movaps %xmm2,%xmm1
  mulss  (%rax),%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
  movss  (%rcx),%xmm1
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L44
L3:
  mov    $0x0,%eax
L16:
  movaps %xmm1,%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L16
L43:
  mov    $0x0,%eax
  ret
L44:
  xorps  D3(%rip),%xmm1
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
normal(s, n, dt, scl) float *s, *dt, *scl;
int n;
{
  int i;
  float sum = 0.0;
  for (i = 0; i < n; i++)
    sum = sum + s[i] * (*dt);
  sum = (*scl) / sum;
  if (sum < 0.0)
    sum = -sum;
  for (i = 0; i < n; i++)
    s[i] = s[i] * sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<normal>:
  endbr64
  movss  (%rcx),%xmm2
  test   %esi,%esi
  jle    L12
  movss  (%rdx),%xmm3
  pxor   %xmm4,%xmm4
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rdx,4),%rdx
  movaps %xmm4,%xmm0
  nopw   0x0(%rax,%rax,1)
L33:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L33
  divss  %xmm0,%xmm2
  comiss %xmm2,%xmm4
  movaps %xmm2,%xmm1
  ja     L26
L31:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L28:
  movss  (%rdi,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L28
L12:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L26:
  xorps  D6(%rip),%xmm1
  jmp    L31
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
normal(s, n, dt, scl) float *s, *dt, *scl;
int n;
{
  int i;
  float sum = 0.0;
  for (i = 0; i < n; i++)
    sum = sum + s[i] * (*dt);
  sum = (*scl) / sum;
  if (sum < 0.0)
    sum = -sum;
  for (i = 0; i < n; i++)
    s[i] = s[i] * sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normal>:
  endbr64
  movss  (%rcx),%xmm2
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  movss  (%rdx),%xmm5
  cmp    $0x2,%eax
  jbe    L27
  mov    %esi,%edx
  pxor   %xmm6,%xmm6
  movaps %xmm5,%xmm4
  mov    %rdi,%rax
  shr    $0x2,%edx
  movaps %xmm6,%xmm1
  shufps $0x0,%xmm4,%xmm4
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L2:
  movups (%rax),%xmm0
  add    $0x10,%rax
  mulps  %xmm4,%xmm0
  addss  %xmm0,%xmm1
  movaps %xmm0,%xmm3
  shufps $0x55,%xmm0,%xmm3
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  unpckhps %xmm0,%xmm3
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L2
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L63
L127:
  movslq %eax,%rdx
  movss  (%rdi,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  mulss  %xmm5,%xmm0
  addss  %xmm0,%xmm1
  cmp    %esi,%edx
  jge    L63
  movss  0x4(%rdi,%rcx,1),%xmm0
  add    $0x2,%eax
  mulss  %xmm5,%xmm0
  addss  %xmm0,%xmm1
  cmp    %eax,%esi
  jle    L63
  mulss  0x8(%rdi,%rcx,1),%xmm5
  addss  %xmm5,%xmm1
L63:
  divss  %xmm1,%xmm2
  comiss %xmm2,%xmm6
  movaps %xmm2,%xmm0
  jbe    L68
  xorps  D6(%rip),%xmm0
L68:
  test   %esi,%esi
  mov    $0x1,%edx
  cmovg  %esi,%edx
  cmp    $0x3,%esi
  jle    L98
  mov    %edx,%ecx
  movaps %xmm0,%xmm2
  mov    %rdi,%rax
  shr    $0x2,%ecx
  shufps $0x0,%xmm2,%xmm2
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L114:
  movups (%rax),%xmm1
  add    $0x10,%rax
  mulps  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L114
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %edx,%ecx
  je     L19
L125:
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L62
  lea    (%rdi,%rcx,4),%rcx
  movaps %xmm0,%xmm2
  movq   (%rcx),%xmm1
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm1
  movlps %xmm1,(%rcx)
  mov    %edx,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%edx
  je     L19
L62:
  cltq
  lea    (%rdi,%rax,4),%rax
  mulss  (%rax),%xmm0
  movss  %xmm0,(%rax)
L19:
  xor    %eax,%eax
  ret
L27:
  pxor   %xmm6,%xmm6
  xor    %eax,%eax
  movaps %xmm6,%xmm1
  jmp    L127
L98:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L125
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
normal(s, n, dt, scl) float *s, *dt, *scl;
int n;
{
  int i;
  float sum = 0.0;
  for (i = 0; i < n; i++)
    sum = sum + s[i] * (*dt);
  sum = (*scl) / sum;
  if (sum < 0.0)
    sum = -sum;
  for (i = 0; i < n; i++)
    s[i] = s[i] * sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<drop_nl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  nop
  leave
  ret
```

assistant: ```c
void drop_nl(char *str) {
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drop_nl>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L11
L0:
  pop    %rbx
  ret
L11:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L0
```

assistant: ```c
void drop_nl(char *str) {
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<drop_nl>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L1
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void drop_nl(char *str) {
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drop_nl>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L0
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void drop_nl(char *str) {
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<terminal_discard_first_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L33:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L15
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L33
L15:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void terminal_discard_first_line(char *string, unsigned int row_length) {
  unsigned int i;
  for (i = 0; string[i] && string[i] != '\n' && i < row_length - 1; i++)
    ;
  strcpy(string, string + i + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<terminal_discard_first_line>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L47
  cmp    $0xa,%al
  je     L47
  cmp    $0x1,%esi
  je     L54
  lea    -0x2(%rsi),%ecx
  add    $0x2,%rcx
  mov    $0x1,%eax
  jmp    L42
L20:
  mov    %rdx,%rax
L42:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L65
  cmp    $0xa,%dl
  je     L65
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rdx
  jne    L20
L65:
  lea    0x1(%rdi,%rax,1),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
L47:
  mov    $0x0,%eax
  jmp    L65
L54:
  mov    $0x0,%eax
  jmp    L65
```

assistant: ```c
void terminal_discard_first_line(char *string, unsigned int row_length) {
  unsigned int i;
  for (i = 0; string[i] && string[i] != '\n' && i < row_length - 1; i++)
    ;
  strcpy(string, string + i + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<terminal_discard_first_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  cmp    $0xa,%al
  je     L30
  cmp    $0x1,%esi
  je     L30
  sub    $0x2,%esi
  mov    $0x1,%eax
  add    $0x2,%rsi
L15:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L36
  cmp    $0xa,%dl
  je     L36
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L15
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
  xchg   %ax,%ax
L36:
  lea    0x1(%rax),%rsi
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax)
L30:
  mov    $0x1,%esi
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
```

assistant: ```c
void terminal_discard_first_line(char *string, unsigned int row_length) {
  unsigned int i;
  for (i = 0; string[i] && string[i] != '\n' && i < row_length - 1; i++)
    ;
  strcpy(string, string + i + 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<terminal_discard_first_line>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  cmp    $0xa,%al
  je     L10
  cmp    $0x1,%esi
  je     L10
  sub    $0x2,%esi
  mov    $0x1,%eax
  add    $0x2,%rsi
L30:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L35
  cmp    $0xa,%dl
  je     L35
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L30
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
  xchg   %ax,%ax
L35:
  lea    0x1(%rax),%rsi
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax)
L10:
  mov    $0x1,%esi
  add    %rdi,%rsi
  jmp    1050 <strcpy@plt>
```

assistant: ```c
void terminal_discard_first_line(char *string, unsigned int row_length) {
  unsigned int i;
  for (i = 0; string[i] && string[i] != '\n' && i < row_length - 1; i++)
    ;
  strcpy(string, string + i + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<galfa_sendpkt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write_socket@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write_socket@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void galfa_sendpkt(int fd, void *pkt, int len) {
  int hlen = htonl(len);
  write_socket(fd, &hlen, 4);
  write_socket(fd, pkt, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<galfa_sendpkt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edx,%edi
  call   <htonl@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <write_socket@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <write_socket@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void galfa_sendpkt(int fd, void *pkt, int len) {
  int hlen = htonl(len);
  write_socket(fd, &hlen, 4);
  write_socket(fd, pkt, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<galfa_sendpkt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %edx,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <htonl@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  mov    %eax,0x4(%rsp)
  call   <write_socket@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write_socket@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void galfa_sendpkt(int fd, void *pkt, int len) {
  int hlen = htonl(len);
  write_socket(fd, &hlen, 4);
  write_socket(fd, pkt, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<galfa_sendpkt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %edx,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <htonl@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  mov    %eax,0x4(%rsp)
  call   <write_socket@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write_socket@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void galfa_sendpkt(int fd, void *pkt, int len) {
  int hlen = htonl(len);
  write_socket(fd, &hlen, 4);
  write_socket(fd, pkt, len);
}
```