user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x60(%rbp)
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x60(%rbp),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x48(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  movslq %ecx,%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  movslq %ecx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L81:
  cmp    %rdx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L81
L36:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L8
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L8:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movslq %ecx,%rax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x50(%rbp)
  jmp    L77
L3:
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x58(%rbp),%ecx
  mov    -0x40(%rbp),%rax
  mov    -0x50(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x50(%rbp)
L77:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L3
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L46
L54:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x5c(%rbp),%eax
  cmp    %eax,%edx
  je     L47
  addl   $0x1,-0x54(%rbp)
L47:
  addl   $0x1,-0x4c(%rbp)
L46:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L54
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x54(%rbp)
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string

tool: D20: %d

tool: D37: %d


assistant: ```c
int main() {
  int a = 0, b = 0, c = 0, counter = 0;
  scanf("%d", &a);
  int arr[a];
  memset(arr, 0, sizeof(arr));
  for (int count = 0; count < a; ++count) {
    scanf("%d", &c);
    arr[count] = c;
  }
  scanf("%d", &b);
  for (int cc = 0; cc < a; ++cc) {
    if (arr[cc] != b)
      ++counter;
  }
  printf("%d\n", counter);
  counter = 0;
  return 0;
}
```