ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movabs $0xffff0000ffffffff,%rax
  mov    (%rdi),%rdx
  sub    $0x3f60a4d,%rdx
  movzwl %dx,%ecx
  and    %rdx,%rax
  shr    $0x20,%rdx
  shl    $0x20,%rcx
  or     %rcx,%rax
  mov    %dx,%ax
  sub    $0x34ab128b,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
          *((char *)(&state[0UL]) + 7) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 6);
          *((char *)(&state[local1]) + 6) = copy12;
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 307931096UL) + 0xffffffffddaf954dUL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  movabs $0xffff0000ffffffff,%rax
  mov    (%rdi),%rdx
  sub    $0x3f60a4d,%rdx
  movzwl %dx,%ecx
  and    %rdx,%rax
  shr    $0x20,%rdx
  shl    $0x20,%rcx
  or     %rcx,%rax
  mov    %dx,%ax
  sub    $0x34ab128b,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
          *((char *)(&state[0UL]) + 7) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 6);
          *((char *)(&state[local1]) + 6) = copy12;
          state[0UL] = state[local1] + state[0UL];
        }
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 307931096UL) + 0xffffffffddaf954dUL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L121
  mov    $0x1,%eax
  jmp    L88
L121:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L60
  mov    $0xffffffff,%eax
  jmp    L88
L60:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jle    L125
  mov    $0x1,%eax
  jmp    L88
L125:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jge    L230
  mov    $0xffffffff,%eax
  jmp    L88
L230:
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  cmp    %rax,%rdx
  jle    L215
  mov    $0x1,%eax
  jmp    L88
L215:
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  cmp    %rax,%rdx
  jge    L32
  mov    $0xffffffff,%eax
  jmp    L88
L32:
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%rax
  cmp    %rax,%rdx
  jle    L192
  mov    $0x1,%eax
  jmp    L88
L192:
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%rax
  cmp    %rax,%rdx
  jge    L198
  mov    $0xffffffff,%eax
  jmp    L88
L198:
  mov    -0x8(%rbp),%rax
  mov    0x20(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x20(%rax),%rax
  cmp    %rax,%rdx
  jle    L128
  mov    $0x1,%eax
  jmp    L88
L128:
  mov    -0x8(%rbp),%rax
  mov    0x20(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x20(%rax),%rax
  cmp    %rax,%rdx
  jge    L160
  mov    $0xffffffff,%eax
  jmp    L88
L160:
  mov    -0x8(%rbp),%rax
  mov    0x28(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x28(%rax),%rax
  cmp    %rax,%rdx
  jle    L167
  mov    $0x1,%eax
  jmp    L88
L167:
  mov    -0x8(%rbp),%rax
  mov    0x28(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x28(%rax),%rax
  cmp    %rax,%rdx
  jge    L72
  mov    $0xffffffff,%eax
  jmp    L88
L72:
  mov    $0x0,%eax
L88:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_date(const struct tm *left, const struct tm *right) {
  if (left->tm_year > right->tm_year)
    return 1;
  else if (left->tm_year < right->tm_year)
    return -1;
  if (left->tm_mon > right->tm_mon)
    return 1;
  else if (left->tm_mon < right->tm_mon)
    return -1;
  if (left->tm_mday > right->tm_mday)
    return 1;
  else if (left->tm_mday < right->tm_mday)
    return -1;
  if (left->tm_hour > right->tm_hour)
    return 1;
  else if (left->tm_hour < right->tm_hour)
    return -1;
  if (left->tm_min > right->tm_min)
    return 1;
  else if (left->tm_min < right->tm_min)
    return -1;
  if (left->tm_sec > right->tm_sec)
    return 1;
  else if (left->tm_sec < right->tm_sec)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmp_date>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  mov    $0xffffffff,%eax
  jl     L62
  mov    0x8(%rdi),%rcx
  mov    0x8(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  mov    $0xffffffff,%eax
  jl     L62
  mov    0x10(%rdi),%rcx
  mov    0x10(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  mov    $0xffffffff,%eax
  jl     L62
  mov    0x18(%rdi),%rcx
  mov    0x18(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  mov    $0xffffffff,%eax
  jl     L62
  mov    0x20(%rdi),%rcx
  mov    0x20(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  mov    $0xffffffff,%eax
  jl     L62
  mov    0x28(%rdi),%rcx
  mov    0x28(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L62
  setl   %al
  movzbl %al,%eax
  neg    %eax
L62:
  ret
```

assistant: ```c
int cmp_date(const struct tm *left, const struct tm *right) {
  if (left->tm_year > right->tm_year)
    return 1;
  else if (left->tm_year < right->tm_year)
    return -1;
  if (left->tm_mon > right->tm_mon)
    return 1;
  else if (left->tm_mon < right->tm_mon)
    return -1;
  if (left->tm_mday > right->tm_mday)
    return 1;
  else if (left->tm_mday < right->tm_mday)
    return -1;
  if (left->tm_hour > right->tm_hour)
    return 1;
  else if (left->tm_hour < right->tm_hour)
    return -1;
  if (left->tm_min > right->tm_min)
    return 1;
  else if (left->tm_min < right->tm_min)
    return -1;
  if (left->tm_sec > right->tm_sec)
    return 1;
  else if (left->tm_sec < right->tm_sec)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp_date>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jg     L100
  mov    $0xffffffff,%eax
  jl     L100
  mov    0x8(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x8(%rdi)
  jg     L100
  mov    $0xffffffff,%eax
  jl     L100
  mov    0x10(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x10(%rdi)
  jg     L100
  mov    $0xffffffff,%eax
  jl     L100
  mov    0x18(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x18(%rdi)
  jg     L100
  mov    $0xffffffff,%eax
  jl     L100
  mov    0x20(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x20(%rdi)
  jg     L100
  mov    $0xffffffff,%eax
  jl     L100
  mov    0x28(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x28(%rdi)
  jg     L100
  setl   %al
  movzbl %al,%eax
  neg    %eax
L100:
  ret
```

assistant: ```c
int cmp_date(const struct tm *left, const struct tm *right) {
  if (left->tm_year > right->tm_year)
    return 1;
  else if (left->tm_year < right->tm_year)
    return -1;
  if (left->tm_mon > right->tm_mon)
    return 1;
  else if (left->tm_mon < right->tm_mon)
    return -1;
  if (left->tm_mday > right->tm_mday)
    return 1;
  else if (left->tm_mday < right->tm_mday)
    return -1;
  if (left->tm_hour > right->tm_hour)
    return 1;
  else if (left->tm_hour < right->tm_hour)
    return -1;
  if (left->tm_min > right->tm_min)
    return 1;
  else if (left->tm_min < right->tm_min)
    return -1;
  if (left->tm_sec > right->tm_sec)
    return 1;
  else if (left->tm_sec < right->tm_sec)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_date>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jg     L22
  mov    $0xffffffff,%eax
  jl     L22
  mov    0x8(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x8(%rdi)
  jg     L22
  mov    $0xffffffff,%eax
  jl     L22
  mov    0x10(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x10(%rdi)
  jg     L22
  mov    $0xffffffff,%eax
  jl     L22
  mov    0x18(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x18(%rdi)
  jg     L22
  mov    $0xffffffff,%eax
  jl     L22
  mov    0x20(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x20(%rdi)
  jg     L22
  mov    $0xffffffff,%eax
  jl     L22
  mov    0x28(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x28(%rdi)
  jg     L22
  setl   %al
  movzbl %al,%eax
  neg    %eax
L22:
  ret
```

assistant: ```c
int cmp_date(const struct tm *left, const struct tm *right) {
  if (left->tm_year > right->tm_year)
    return 1;
  else if (left->tm_year < right->tm_year)
    return -1;
  if (left->tm_mon > right->tm_mon)
    return 1;
  else if (left->tm_mon < right->tm_mon)
    return -1;
  if (left->tm_mday > right->tm_mday)
    return 1;
  else if (left->tm_mday < right->tm_mday)
    return -1;
  if (left->tm_hour > right->tm_hour)
    return 1;
  else if (left->tm_hour < right->tm_hour)
    return -1;
  if (left->tm_min > right->tm_min)
    return 1;
  else if (left->tm_min < right->tm_min)
    return -1;
  if (left->tm_sec > right->tm_sec)
    return 1;
  else if (left->tm_sec < right->tm_sec)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squareofsums>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L15
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int squareofsums(int num) {
  int sum;
  int i;
  for (i = 1, sum = 0; i <= num; ++i)
    sum += i;
  return sum * sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<squareofsums>:
  endbr64
  test   %edi,%edi
  jle    L7
  add    $0x1,%edi
  mov    $0x1,%edx
  mov    $0x0,%eax
L8:
  add    %edx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L8
L15:
  imul   %eax,%eax
  ret
L7:
  mov    $0x0,%eax
  jmp    L15
```

assistant: ```c
int squareofsums(int num) {
  int sum;
  int i;
  for (i = 1, sum = 0; i <= num; ++i)
    sum += i;
  return sum * sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<squareofsums>:
  endbr64
  test   %edi,%edi
  jle    L15
  add    $0x1,%edi
  mov    $0x1,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  add    %edx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L2
  imul   %eax,%eax
  ret
  nopl   (%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int squareofsums(int num) {
  int sum;
  int i;
  for (i = 1, sum = 0; i <= num; ++i)
    sum += i;
  return sum * sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<squareofsums>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  jle    L76
  lea    -0x1(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L86
  mov    %edi,%ecx
  movdqa D3(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D10(%rip),%xmm3
  shr    $0x2,%ecx
  nopl   (%rax)
L39:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L39
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  lea    0x1(%rsi),%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L122
L66:
  lea    0x1(%rcx),%esi
  add    %ecx,%eax
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x2(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x6(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x7(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  lea    0x8(%rcx),%esi
  cmp    %esi,%edx
  jl     L122
  add    %esi,%eax
  add    $0x9,%ecx
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  cmovge %esi,%eax
L122:
  imul   %eax,%eax
  ret
  xchg   %ax,%ax
L76:
  xor    %eax,%eax
  ret
L86:
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L66
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: byte[16]
name: read_data
arguments: data_label: D10
type_infered: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D10": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int squareofsums(int num) {
  int sum;
  int i;
  for (i = 1, sum = 0; i <= num; ++i)
    sum += i;
  return sum * sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<partialSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void partialSort(int *A, int *B, int factor) {
  for (int i = 0; i < factor; i++) {
    A[i] = B[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partialSort>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L2:
  ret
```

assistant: ```c
void partialSort(int *A, int *B, int factor) {
  for (int i = 0; i < factor; i++) {
    A[i] = B[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<partialSort>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L12:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L12
L10:
  ret
```

assistant: ```c
void partialSort(int *A, int *B, int factor) {
  for (int i = 0; i < factor; i++) {
    A[i] = B[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partialSort>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L61
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L48
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L48
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L73:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L73
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L61
  mov    %eax,%r8d
  mov    (%rsi,%r8,4),%r9d
  lea    0x0(,%r8,4),%rdi
  mov    %r9d,(%rcx,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edx
  jle    L61
  mov    0x4(%rsi,%rdi,1),%r8d
  add    $0x2,%eax
  mov    %r8d,0x4(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L61
  mov    0x8(%rsi,%rdi,1),%eax
  mov    %eax,0x8(%rcx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L50:
  mov    (%rsi,%rax,4),%edi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L50
L61:
  ret
```

assistant: ```c
void partialSort(int *A, int *B, int factor) {
  for (int i = 0; i < factor; i++) {
    A[i] = B[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<celciusToFahrenheit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D3
type_guessed: f64

tool: {"D18": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D3: 32

assistant: ```c
float celciusToFahrenheit(float Tc) {
  float Tf = ((float)9.0 / 5.0) * Tc + 32.0;
  return (Tf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<celciusToFahrenheit>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  mulsd  D6(%rip),%xmm0
  addsd  D11(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: f64

tool: {"D6": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D11: 32

assistant: ```c
float celciusToFahrenheit(float Tc) {
  float Tf = ((float)9.0 / 5.0) * Tc + 32.0;
  return (Tf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<celciusToFahrenheit>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  D15(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: byte[8]
name: read_data
arguments: tag: D15
data_type: f64

tool: {"D5": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D15: 32

assistant: ```c
float celciusToFahrenheit(float Tc) {
  float Tf = ((float)9.0 / 5.0) * Tc + 32.0;
  return (Tf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<celciusToFahrenheit>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  mulsd  D14(%rip),%xmm0
  addsd  D2(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: byte[8]
name: read_data
arguments: data_label: D2
data_type: f64

tool: {"D14": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D2: 32

assistant: ```c
float celciusToFahrenheit(float Tc) {
  float Tf = ((float)9.0 / 5.0) * Tc + 32.0;
  return (Tf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoll@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    %rax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <eratosthenes_sieve@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long unsigned n = atoll(argv[1]);
  int *sieve = (int *)malloc(sizeof(int) * (n / 2));
  eratosthenes_sieve(sieve, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoll@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  shr    %rdi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <eratosthenes_sieve@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long unsigned n = atoll(argv[1]);
  int *sieve = (int *)malloc(sizeof(int) * (n / 2));
  eratosthenes_sieve(sieve, n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rdi
  call   <atoll@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  shr    %rdi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <eratosthenes_sieve@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long unsigned n = atoll(argv[1]);
  int *sieve = (int *)malloc(sizeof(int) * (n / 2));
  eratosthenes_sieve(sieve, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rdi
  call   <atoll@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  shr    %rdi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <eratosthenes_sieve@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long unsigned n = atoll(argv[1]);
  int *sieve = (int *)malloc(sizeof(int) * (n / 2));
  eratosthenes_sieve(sieve, n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L25
  mov    $0x2,%eax
  jmp    L17
L25:
  cmpl   $0x7f,-0x4(%rbp)
  jle    L26
  cmpl   $0xff,-0x4(%rbp)
  jg     L26
  mov    $0x3,%eax
  jmp    L17
L26:
  mov    $0x4,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int skip(int len) {
  if (len < 128)
    return 2;
  if (len >= 128 && len < 256)
    return 3;
  return 4;
}
```
user: What is the c source code of the assembly code below?

```asm
<skip>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x7f,%edi
  jle    L9
  add    $0xffffff80,%edi
  cmp    $0x7f,%edi
  seta   %al
  movzbl %al,%eax
  add    $0x3,%eax
L9:
  ret
```

assistant: ```c
int skip(int len) {
  if (len < 128)
    return 2;
  if (len >= 128 && len < 256)
    return 3;
  return 4;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x7f,%edi
  jle    L3
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x7f,%edi
  seta   %al
  add    $0x3,%eax
L3:
  ret
```

assistant: ```c
int skip(int len) {
  if (len < 128)
    return 2;
  if (len >= 128 && len < 256)
    return 3;
  return 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip>:
  endbr64
  mov    $0x2,%eax
  cmp    $0x7f,%edi
  jle    L6
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x7f,%edi
  seta   %al
  add    $0x3,%eax
L6:
  ret
```

assistant: ```c
int skip(int len) {
  if (len < 128)
    return 2;
  if (len >= 128 && len < 256)
    return 3;
  return 4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fdimf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L35
  movss  -0x4(%rbp),%xmm0
  jmp    L22
L35:
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L33
  movss  -0x8(%rbp),%xmm0
  jmp    L22
L33:
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L37
  movss  -0x4(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  jmp    L22
L37:
  pxor   %xmm0,%xmm0
L22:
  leave
  ret
```

assistant: ```c
float fdimf(float x, float y) {
  if (isnan(x))
    return x;
  if (isnan(y))
    return y;
  return x > y ? x - y : 0;
}
```