ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x5,%esi
  movabs $0x400000000,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  movl   $0x5,0x10(%rsp)
  movq   $0x3,0x28(%rsp)
  movl   $0x5,0x30(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x20(%rsp)
  call   <wypisz@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x5,%esi
  call   <wypisz@plt>
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0xc,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: x=%d, y=%d, z=%d


assistant: ```c
int main() {
  int tmp, a = 2;
  int tab1[5] = {1, 2, 3, 4, 5};
  int tab2[5] = {1, 2, 3, 4, 5};
  tmp = a;
  tab1[a++] = 0;
  a = tmp;
  tab2[++a] = 0;
  wypisz(tab1, 5);
  wypisz(tab2, 5);
  int y, z, x = 10;
  y = (x += 2);
  z = (x %= 3) + (x %= 4);
  printf("x=%d, y=%d, z=%d\n", x, y, z);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movdqa D28(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x5,0x10(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D14(%rip),%xmm0
  movl   $0x5,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <wypisz@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x5,%esi
  call   <wypisz@plt>
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0xc,%edx
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D14
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D24
data_type: string

tool: {"D28": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D14": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D24: x=%d, y=%d, z=%d


assistant: ```c
int main() {
  int tmp, a = 2;
  int tab1[5] = {1, 2, 3, 4, 5};
  int tab2[5] = {1, 2, 3, 4, 5};
  tmp = a;
  tab1[a++] = 0;
  a = tmp;
  tab2[++a] = 0;
  wypisz(tab1, 5);
  wypisz(tab2, 5);
  int y, z, x = 10;
  y = (x += 2);
  z = (x %= 3) + (x %= 4);
  printf("x=%d, y=%d, z=%d\n", x, y, z);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  va_list va;
  va_start(va, format);
  int ret = vfprintf(stdout, format, va);
  va_end(va);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  va_list va;
  va_start(va, format);
  int ret = vfprintf(stdout, format, va);
  va_end(va);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  va_list va;
  va_start(va, format);
  int ret = vfprintf(stdout, format, va);
  va_end(va);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transform_to_log_area_ratios>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L31
L73:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <saturated_abs16@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x5665,-0x8(%rbp)
  jg     L53
  sarl   -0x8(%rbp)
  jmp    L8
L53:
  cmpl   $0x7999,-0x8(%rbp)
  jg     L69
  cmpl   $0x2b32,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  subl   $0x2b33,-0x8(%rbp)
  jmp    L8
L69:
  cmpl   $0x65ff,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  subl   $0x6600,-0x8(%rbp)
  shll   $0x2,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L79
  mov    -0x8(%rbp),%eax
  neg    %eax
  jmp    L1
L79:
  mov    -0x8(%rbp),%eax
L1:
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x4(%rbp)
  addq   $0x4,-0x18(%rbp)
L31:
  cmpl   $0x8,-0x4(%rbp)
  jle    L73
  nop
  nop
  leave
  ret
```

assistant: ```c
void transform_to_log_area_ratios(int16_t r[8]) {
  int16_t temp;
  int i;
  for (i = 1; i <= 8; i++, r++) {
    temp = saturated_abs16(*r);
    assert(temp >= 0);
    if (temp < 22118) {
      temp >>= 1;
    } else if (temp < 31130) {
      assert(temp >= 11059);
      temp -= 11059;
    } else {
      assert(temp >= 26112);
      temp -= 26112;
      temp <<= 2;
    }
    *r = (*r < 0) ? -temp : temp;
    assert(*r != INT16_MIN);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transform_to_log_area_ratios>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    0x20(%rdi),%r12
  jmp    L46
L18:
  cmp    $0x7999,%ebx
  jg     L44
  mov    $0x1,%edi
  call   <assert@plt>
  lea    -0x2b33(%rbx),%eax
L13:
  mov    %eax,%edx
  neg    %edx
  cmpl   $0x0,0x0(%rbp)
  cmovs  %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbp
  cmp    %rbp,%r12
  je     L16
L46:
  mov    0x0(%rbp),%edi
  call   <saturated_abs16@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0x5665,%ebx
  jg     L18
  mov    %ebx,%eax
  sar    %eax
  jmp    L13
L44:
  mov    $0x1,%edi
  call   <assert@plt>
  lea    -0x19800(,%rbx,4),%eax
  jmp    L13
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void transform_to_log_area_ratios(int16_t r[8]) {
  int16_t temp;
  int i;
  for (i = 1; i <= 8; i++, r++) {
    temp = saturated_abs16(*r);
    assert(temp >= 0);
    if (temp < 22118) {
      temp >>= 1;
    } else if (temp < 31130) {
      assert(temp >= 11059);
      temp -= 11059;
    } else {
      assert(temp >= 26112);
      temp -= 26112;
      temp <<= 2;
    }
    *r = (*r < 0) ? -temp : temp;
    assert(*r != INT16_MIN);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transform_to_log_area_ratios>:
  endbr64
  push   %r13
  lea    0x20(%rdi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%r12
  jmp    L7
  xchg   %ax,%ax
L3:
  mov    %ebx,%eax
  sar    %eax
L4:
  mov    0x0(%rbp),%ecx
  mov    %eax,%edx
  neg    %edx
  test   %ecx,%ecx
  cmovs  %edx,%eax
  xor    %edi,%edi
  mov    %eax,0x0(%rbp)
  cmp    %eax,(%r12)
  setne  %dil
  add    $0x4,%rbp
  call   <assert@plt>
  cmp    %rbp,%r13
  je     L24
L7:
  mov    0x0(%rbp),%edi
  call   <saturated_abs16@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0x5665,%ebx
  jle    L3
  mov    $0x1,%edi
  cmp    $0x7999,%ebx
  jg     L11
  call   <assert@plt>
  lea    -0x2b33(%rbx),%eax
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L11:
  call   <assert@plt>
  lea    -0x19800(,%rbx,4),%eax
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void transform_to_log_area_ratios(int16_t r[8]) {
  int16_t temp;
  int i;
  for (i = 1; i <= 8; i++, r++) {
    temp = saturated_abs16(*r);
    assert(temp >= 0);
    if (temp < 22118) {
      temp >>= 1;
    } else if (temp < 31130) {
      assert(temp >= 11059);
      temp -= 11059;
    } else {
      assert(temp >= 26112);
      temp -= 26112;
      temp <<= 2;
    }
    *r = (*r < 0) ? -temp : temp;
    assert(*r != INT16_MIN);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<transform_to_log_area_ratios>:
  endbr64
  push   %r13
  lea    0x20(%rdi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%r12
  jmp    L35
  xchg   %ax,%ax
L10:
  mov    %ebx,%eax
  sar    %eax
L48:
  mov    0x0(%rbp),%ecx
  mov    %eax,%edx
  neg    %edx
  test   %ecx,%ecx
  cmovs  %edx,%eax
  xor    %edi,%edi
  mov    %eax,0x0(%rbp)
  cmp    %eax,(%r12)
  setne  %dil
  add    $0x4,%rbp
  call   <assert@plt>
  cmp    %r13,%rbp
  je     L44
L35:
  mov    0x0(%rbp),%edi
  call   <saturated_abs16@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  cmp    $0x5665,%ebx
  jle    L10
  mov    $0x1,%edi
  cmp    $0x7999,%ebx
  jg     L22
  call   <assert@plt>
  lea    -0x2b33(%rbx),%eax
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L22:
  call   <assert@plt>
  lea    -0x19800(,%rbx,4),%eax
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void transform_to_log_area_ratios(int16_t r[8]) {
  int16_t temp;
  int i;
  for (i = 1; i <= 8; i++, r++) {
    temp = saturated_abs16(*r);
    assert(temp >= 0);
    if (temp < 22118) {
      temp >>= 1;
    } else if (temp < 31130) {
      assert(temp >= 11059);
      temp -= 11059;
    } else {
      assert(temp >= 26112);
      temp -= 26112;
      temp <<= 2;
    }
    *r = (*r < 0) ? -temp : temp;
    assert(*r != INT16_MIN);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x32,%eax
  cmp    $0x22,%eax
  ja     L12
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xd,%eax
  jmp    L8
  mov    $0xc,%eax
  jmp    L8
  mov    $0xb,%eax
  jmp    L8
  mov    $0xa,%eax
  jmp    L8
  mov    $0x9,%eax
  jmp    L8
  mov    $0x8,%eax
  jmp    L8
  mov    $0x7,%eax
  jmp    L8
  mov    $0x6,%eax
  jmp    L8
  mov    $0x5,%eax
  jmp    L8
  mov    $0x4,%eax
  jmp    L8
  mov    $0x3,%eax
  jmp    L8
  mov    $0x2,%eax
  jmp    L8
  mov    $0x1,%eax
  jmp    L8
L12:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  cmp    $0x22,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D5(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xc,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
  mov    $0xd,%eax
  ret
```

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  xor    %eax,%eax
  cmp    $0x22,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D6(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L7:
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: 

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<number>:
  endbr64
  sub    $0x32,%edi
  xor    %eax,%eax
  cmp    $0x22,%dil
  ja     L4
  movzbl %dil,%edi
  lea    D7(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L4:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: 

assistant: ```c
int number(char order) {
  switch (order) {
  case 'A':
    return 13;
  case 'K':
    return 12;
  case 'Q':
    return 11;
  case 'J':
    return 10;
  case 'T':
    return 9;
  case '9':
    return 8;
  case '8':
    return 7;
  case '7':
    return 6;
  case '6':
    return 5;
  case '5':
    return 4;
  case '4':
    return 3;
  case '3':
    return 2;
  case '2':
    return 1;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<virt_to_phys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xc,%eax
  mov    %eax,%edi
  call   <virt_to_phys_page@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L7
L11:
  mov    -0x8(%rbp),%eax
  shl    $0xc,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfff,%eax
  or     -0x4(%rbp),%eax
L7:
  leave
  ret
```

assistant: ```c
uint32_t virt_to_phys(uint32_t vaddr) {
  int pg;
  uint32_t pgaddr;
  if ((pg = virt_to_phys_page(((uint32_t)(vaddr) >> 12))) == -1) {
    return 0;
  }
  pgaddr = ((uint32_t)(pg) << 12);
  return pgaddr | ((uint32_t)(vaddr)&0xfff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<virt_to_phys>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0xc,%edi
  call   <virt_to_phys_page@plt>
  mov    $0x0,%edx
  cmp    $0xffffffff,%eax
  je     L7
  and    $0xfff,%ebx
  shl    $0xc,%eax
  mov    %ebx,%edx
  or     %eax,%edx
L7:
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t virt_to_phys(uint32_t vaddr) {
  int pg;
  uint32_t pgaddr;
  if ((pg = virt_to_phys_page(((uint32_t)(vaddr) >> 12))) == -1) {
    return 0;
  }
  pgaddr = ((uint32_t)(pg) << 12);
  return pgaddr | ((uint32_t)(vaddr)&0xfff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<virt_to_phys>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0xc,%edi
  call   <virt_to_phys_page@plt>
  xor    %r8d,%r8d
  cmp    $0xffffffff,%eax
  je     L2
  and    $0xfff,%ebx
  shl    $0xc,%eax
  or     %eax,%ebx
  mov    %ebx,%r8d
L2:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t virt_to_phys(uint32_t vaddr) {
  int pg;
  uint32_t pgaddr;
  if ((pg = virt_to_phys_page(((uint32_t)(vaddr) >> 12))) == -1) {
    return 0;
  }
  pgaddr = ((uint32_t)(pg) << 12);
  return pgaddr | ((uint32_t)(vaddr)&0xfff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<virt_to_phys>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0xc,%edi
  call   <virt_to_phys_page@plt>
  xor    %r8d,%r8d
  cmp    $0xffffffff,%eax
  je     L7
  and    $0xfff,%ebx
  shl    $0xc,%eax
  or     %eax,%ebx
  mov    %ebx,%r8d
L7:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t virt_to_phys(uint32_t vaddr) {
  int pg;
  uint32_t pgaddr;
  if ((pg = virt_to_phys_page(((uint32_t)(vaddr) >> 12))) == -1) {
    return 0;
  }
  pgaddr = ((uint32_t)(pg) << 12);
  return pgaddr | ((uint32_t)(vaddr)&0xfff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <check_vect@plt>
  movl   $0x0,-0xc8(%rbp)
  jmp    L33
L1:
  mov    -0xc8(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  sub    $0x7e,%eax
  mov    %eax,%edx
  mov    -0xc8(%rbp),%eax
  cltq
  mov    %dl,-0x80(%rbp,%rax,1)
  mov    -0xc8(%rbp),%eax
  shl    $0x2,%eax
  sub    $0x65,%eax
  mov    %eax,%edx
  mov    -0xc8(%rbp),%eax
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
  addl   $0x1,-0xc8(%rbp)
L33:
  cmpl   $0x31,-0xc8(%rbp)
  jle    L1
  lea    -0x40(%rbp),%rdx
  lea    -0x80(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <f@plt>
  movl   $0x0,-0xc4(%rbp)
  jmp    L0
L23:
  mov    -0xc4(%rbp),%eax
  cltq
  movzbl -0xc0(%rbp,%rax,1),%eax
  movsbl %al,%ecx
  mov    -0xc4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  sub    $0xe2,%eax
  sar    %eax
  cmp    %eax,%ecx
  je     L49
  call   <abort@plt>
L49:
  addl   $0x1,-0xc4(%rbp)
L0:
  cmpl   $0x31,-0xc4(%rbp)
  jle    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int main(void) {
  check_vect();
  signed char a[50], b[50], c[50];
  for (int i = 0; i < 50; ++i) {
    b[i] = ((signed int)-1 < 0 ? -126 : 4) + i * 5;
    c[i] = ((signed int)-1 < 0 ? -101 : 26) + i * 4;
    asm volatile("" ::: "memory");
  }
  f(a, b, c);
  for (int i = 0; i < 50; ++i)
    if (a[i] != ((((signed int)-1 < 0 ? -126 : 4) + ((signed int)-1 < 0 ? -101 : 26) + i * 9 + 1) >> 1))
      __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  mov    $0xffffff9b,%ecx
  mov    $0xffffff82,%edx
  mov    $0x0,%eax
L27:
  mov    %dl,0x40(%rsp,%rax,1)
  mov    %cl,0x80(%rsp,%rax,1)
  add    $0x1,%rax
  add    $0x5,%edx
  add    $0x4,%ecx
  cmp    $0x32,%rax
  jne    L27
  lea    0x80(%rsp),%rdx
  lea    0x40(%rsp),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <f@plt>
  mov    %rbx,%rax
  lea    0x32(%rsp),%rdi
  mov    $0xffffff1e,%edx
L3:
  movsbl (%rax),%esi
  mov    %edx,%ecx
  sar    %ecx
  cmp    %ecx,%esi
  jne    L6
  add    $0x1,%rax
  add    $0x9,%edx
  cmp    %rdi,%rax
  jne    L3
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0xc0,%rsp
  pop    %rbx
  ret
L6:
  call   <abort@plt>
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  check_vect();
  signed char a[50], b[50], c[50];
  for (int i = 0; i < 50; ++i) {
    b[i] = ((signed int)-1 < 0 ? -126 : 4) + i * 5;
    c[i] = ((signed int)-1 < 0 ? -101 : 26) + i * 4;
    asm volatile("" ::: "memory");
  }
  f(a, b, c);
  for (int i = 0; i < 50; ++i)
    if (a[i] != ((((signed int)-1 < 0 ? -126 : 4) + ((signed int)-1 < 0 ? -101 : 26) + i * 9 + 1) >> 1))
      __builtin_abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  mov    $0xffffff9b,%ecx
  mov    $0xffffff82,%edx
  xor    %eax,%eax
  lea    0x40(%rsp),%rsi
  lea    0x80(%rsp),%r8
  nopl   (%rax)
L20:
  mov    %dl,(%rsi,%rax,1)
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  add    $0x5,%edx
  add    $0x4,%ecx
  cmp    $0x32,%rax
  jne    L20
  mov    %rsp,%rbx
  mov    %r8,%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <f@plt>
  mov    %rbx,%rax
  lea    0x32(%rsp),%rdi
  mov    $0xffffff1e,%edx
  nopl   0x0(%rax)
L12:
  mov    %edx,%ecx
  movsbl (%rax),%esi
  sar    %ecx
  cmp    %ecx,%esi
  jne    10c0 <main.cold>
  add    $0x1,%rax
  add    $0x9,%edx
  cmp    %rdi,%rax
  jne    L12
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  check_vect();
  signed char a[50], b[50], c[50];
  for (int i = 0; i < 50; ++i) {
    b[i] = ((signed int)-1 < 0 ? -126 : 4) + i * 5;
    c[i] = ((signed int)-1 < 0 ? -101 : 26) + i * 4;
    asm volatile("" ::: "memory");
  }
  f(a, b, c);
  for (int i = 0; i < 50; ++i)
    if (a[i] != ((((signed int)-1 < 0 ? -126 : 4) + ((signed int)-1 < 0 ? -101 : 26) + i * 9 + 1) >> 1))
      __builtin_abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  mov    $0xffffff9b,%ecx
  mov    $0xffffff82,%edx
  xor    %eax,%eax
  lea    0x40(%rsp),%rsi
  lea    0x80(%rsp),%r8
  nopl   (%rax)
L0:
  mov    %dl,(%rsi,%rax,1)
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  add    $0x5,%edx
  add    $0x4,%ecx
  cmp    $0x32,%rax
  jne    L0
  mov    %rsp,%rbx
  mov    %r8,%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <f@plt>
  mov    %rbx,%rax
  lea    0x32(%rsp),%rdi
  mov    $0xffffff1e,%edx
  nopl   0x0(%rax)
L13:
  mov    %edx,%ecx
  movsbl (%rax),%esi
  sar    %ecx
  cmp    %ecx,%esi
  jne    10c0 <main.cold>
  add    $0x1,%rax
  add    $0x9,%edx
  cmp    %rax,%rdi
  jne    L13
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  check_vect();
  signed char a[50], b[50], c[50];
  for (int i = 0; i < 50; ++i) {
    b[i] = ((signed int)-1 < 0 ? -126 : 4) + i * 5;
    c[i] = ((signed int)-1 < 0 ? -101 : 26) + i * 4;
    asm volatile("" ::: "memory");
  }
  f(a, b, c);
  for (int i = 0; i < 50; ++i)
    if (a[i] != ((((signed int)-1 < 0 ? -126 : 4) + ((signed int)-1 < 0 ? -101 : 26) + i * 9 + 1) >> 1))
      __builtin_abort();
  return 0;
}
```