ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<addrgb>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  lea    (%rax,%rax,1),%edx
  mov    %edx,0xc(%rsp)
  lea    (%rsi,%rsi,1),%edx
  mov    %edx,0x10(%rsp)
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,0x14(%rsp)
  movzbl (%rdi),%edx
  movzbl 0x1(%rdi),%r8d
  add    %r8d,%edx
  movzbl 0x2(%rdi),%r8d
  add    %r8d,%edx
  cmp    $0x1df,%edx
  jle    L35
  mov    %esi,%edx
  neg    %edx
  sub    %ecx,%edx
  mov    %edx,0xc(%rsp)
  neg    %eax
  mov    %eax,%edx
  sub    %ecx,%edx
  mov    %edx,0x10(%rsp)
  sub    %esi,%eax
  mov    %eax,0x14(%rsp)
L35:
  mov    $0x0,%eax
  mov    $0xff,%r9d
  jmp    L26
L52:
  movzbl (%rdi,%rax,1),%ecx
  neg    %edx
  movzbl %cl,%esi
  cmp    %esi,%edx
  cmovg  %esi,%edx
  sub    %edx,%ecx
  mov    %cl,(%rdi,%rax,1)
L14:
  add    $0x1,%rax
  cmp    $0x3,%rax
  je     L47
L26:
  mov    0xc(%rsp,%rax,4),%edx
  test   %edx,%edx
  js     L52
  movzbl (%rdi,%rax,1),%ecx
  movzbl %cl,%r8d
  mov    %r9d,%esi
  sub    %r8d,%esi
  cmp    %edx,%esi
  cmovg  %edx,%esi
  add    %esi,%ecx
  mov    %cl,(%rdi,%rax,1)
  jmp    L14
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x28,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void addrgb(unsigned char rgb[3], int sr, int sg, int sb) {
  int add[3], i;
  add[0] = 2 * sr;
  add[1] = 2 * sg;
  add[2] = 2 * sb;
  if (((int)rgb[0]) + ((int)rgb[1]) + ((int)rgb[2]) >= 3 * 160) {
    add[0] = (-sg - sb);
    add[1] = (-sr - sb);
    add[2] = (-sr - sg);
  }
  for (i = 0; i < 3; i++)
    if (add[i] < 0)
      rgb[i] -= ((rgb[i] < -add[i]) ? rgb[i] : -add[i]);
    else
      rgb[i] += ((255 - rgb[i] < add[i]) ? 255 - rgb[i] : add[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addrgb>:
  endbr64
  sub    $0x28,%rsp
  mov    %edx,%r10d
  add    %edx,%edx
  movzbl (%rdi),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edx,0x10(%rsp)
  lea    (%rcx,%rcx,1),%edx
  movzbl 0x2(%rdi),%r11d
  mov    %edx,0x14(%rsp)
  movzbl 0x1(%rdi),%edx
  mov    %r9d,%r8d
  add    %r9d,%edx
  add    %r11d,%edx
  cmp    $0x1df,%edx
  jle    L55
  neg    %esi
  mov    %r10d,%eax
  mov    %esi,%edx
  sub    %r10d,%esi
  neg    %eax
  sub    %ecx,%edx
  mov    %esi,0x14(%rsp)
  sub    %ecx,%eax
  mov    %edx,0x10(%rsp)
L62:
  xor    %edx,%edx
  mov    $0xff,%esi
  test   %eax,%eax
  js     L11
L36:
  mov    %esi,%ecx
  sub    %r9d,%ecx
  cmp    %eax,%ecx
  cmovg  %eax,%ecx
  add    %r8d,%ecx
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x3,%rdx
  je     L5
L56:
  movzbl (%rdi,%rdx,1),%r9d
  mov    0xc(%rsp,%rdx,4),%eax
  mov    %r9d,%r8d
  test   %eax,%eax
  jns    L36
L11:
  neg    %eax
  mov    %r8d,%ecx
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  sub    %eax,%ecx
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x3,%rdx
  jne    L56
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  lea    (%rsi,%rsi,1),%eax
  jmp    L62
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void addrgb(unsigned char rgb[3], int sr, int sg, int sb) {
  int add[3], i;
  add[0] = 2 * sr;
  add[1] = 2 * sg;
  add[2] = 2 * sb;
  if (((int)rgb[0]) + ((int)rgb[1]) + ((int)rgb[2]) >= 3 * 160) {
    add[0] = (-sg - sb);
    add[1] = (-sr - sb);
    add[2] = (-sr - sg);
  }
  for (i = 0; i < 3; i++)
    if (add[i] < 0)
      rgb[i] -= ((rgb[i] < -add[i]) ? rgb[i] : -add[i]);
    else
      rgb[i] += ((255 - rgb[i] < add[i]) ? 255 - rgb[i] : add[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<addrgb>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  lea    (%rsi,%rsi,1),%ebx
  movd   %ecx,%xmm2
  movd   %ebx,%xmm0
  add    %ecx,%ecx
  sub    $0x20,%rsp
  movzbl (%rax),%r11d
  movzbl 0x1(%rax),%r10d
  mov    %fs:0x28,%rdi
  mov    %rdi,0x18(%rsp)
  xor    %edi,%edi
  lea    (%rdx,%rdx,1),%edi
  mov    %ecx,0x10(%rsp)
  movd   %edi,%xmm3
  movzbl 0x2(%rax),%edi
  lea    (%r11,%r10,1),%ebx
  mov    %r11d,%r9d
  punpckldq %xmm3,%xmm0
  mov    %r10d,%r8d
  add    %edi,%ebx
  movq   %xmm0,0x8(%rsp)
  mov    %edi,%ecx
  cmp    $0x1df,%ebx
  jle    L77
  mov    %edx,%ebx
  neg    %esi
  pshufd $0xe0,%xmm2,%xmm1
  neg    %ebx
  movd   %esi,%xmm4
  sub    %edx,%esi
  movd   %ebx,%xmm0
  mov    %esi,0x10(%rsp)
  punpckldq %xmm4,%xmm0
  psubd  %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
L77:
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  js     L63
  mov    $0xff,%esi
  sub    %r11d,%esi
  cmp    %edx,%esi
  cmovg  %edx,%esi
  mov    0xc(%rsp),%edx
  add    %esi,%r9d
  mov    %r9b,(%rax)
  test   %edx,%edx
  js     L28
L44:
  mov    $0xff,%esi
  sub    %r10d,%esi
  cmp    %edx,%esi
  cmovg  %edx,%esi
  mov    0x10(%rsp),%edx
  add    %esi,%r8d
  mov    %r8b,0x1(%rax)
  test   %edx,%edx
  js     L39
L76:
  mov    $0xff,%esi
  sub    %edi,%esi
  cmp    %edx,%esi
  cmovg  %edx,%esi
  add    %esi,%ecx
L45:
  mov    %cl,0x2(%rax)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L63:
  neg    %edx
  cmp    %r11d,%edx
  cmovg  %r11d,%edx
  sub    %edx,%r9d
  mov    0xc(%rsp),%edx
  mov    %r9b,(%rax)
  test   %edx,%edx
  jns    L44
L28:
  neg    %edx
  cmp    %r10d,%edx
  cmovg  %r10d,%edx
  sub    %edx,%r8d
  mov    0x10(%rsp),%edx
  mov    %r8b,0x1(%rax)
  test   %edx,%edx
  jns    L76
L39:
  neg    %edx
  cmp    %edi,%edx
  cmovg  %edi,%edx
  sub    %edx,%ecx
  jmp    L45
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void addrgb(unsigned char rgb[3], int sr, int sg, int sb) {
  int add[3], i;
  add[0] = 2 * sr;
  add[1] = 2 * sg;
  add[2] = 2 * sb;
  if (((int)rgb[0]) + ((int)rgb[1]) + ((int)rgb[2]) >= 3 * 160) {
    add[0] = (-sg - sb);
    add[1] = (-sr - sb);
    add[2] = (-sr - sg);
  }
  for (i = 0; i < 3; i++)
    if (add[i] < 0)
      rgb[i] -= ((rgb[i] < -add[i]) ? rgb[i] : -add[i]);
    else
      rgb[i] += ((255 - rgb[i] < add[i]) ? 255 - rgb[i] : add[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gettimespecofday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L17
  mov    -0x18(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x20(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L17:
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int gettimespecofday(struct timespec *ts) {
  struct timeval tv = {0, 0};
  int rc;
  rc = gettimeofday(&tv, NULL);
  if (rc >= 0) {
    ts->tv_sec = tv.tv_sec;
    ts->tv_nsec = tv.tv_usec / 1000LL;
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gettimespecofday>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  js     L14
  mov    0x8(%rsp),%eax
  mov    %eax,0x8(%rbx)
  mov    (%rsp),%rsi
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  sar    $0x3f,%rsi
  sub    %rsi,%rdx
  mov    %rdx,(%rbx)
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %ecx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimespecofday(struct timespec *ts) {
  struct timeval tv = {0, 0};
  int rc;
  rc = gettimeofday(&tv, NULL);
  if (rc >= 0) {
    ts->tv_sec = tv.tv_sec;
    ts->tv_nsec = tv.tv_usec / 1000LL;
  }
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gettimespecofday>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  mov    %rdi,%rbx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <gettimeofday@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  js     L9
  mov    0x8(%rsp),%eax
  mov    (%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %eax,0x8(%rbx)
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  mov    %rdx,(%rbx)
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimespecofday(struct timespec *ts) {
  struct timeval tv = {0, 0};
  int rc;
  rc = gettimeofday(&tv, NULL);
  if (rc >= 0) {
    ts->tv_sec = tv.tv_sec;
    ts->tv_nsec = tv.tv_usec / 1000LL;
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gettimespecofday>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  mov    %rdi,%rbx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <gettimeofday@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  js     L18
  mov    0x8(%rsp),%eax
  mov    (%rsp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %eax,0x8(%rbx)
  mov    %rcx,%rax
  sar    $0x3f,%rcx
  imul   %rdx
  sar    $0x7,%rdx
  sub    %rcx,%rdx
  mov    %rdx,(%rbx)
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimespecofday(struct timespec *ts) {
  struct timeval tv = {0, 0};
  int rc;
  rc = gettimeofday(&tv, NULL);
  if (rc >= 0) {
    ts->tv_sec = tv.tv_sec;
    ts->tv_nsec = tv.tv_usec / 1000LL;
  }
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rewrite_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: missing #cpu declaration

assistant: ```c
char *rewrite_null(int code) {
  error("missing #cpu declaration");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rewrite_null>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <error@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: missing #cpu declaration

assistant: ```c
char *rewrite_null(int code) {
  error("missing #cpu declaration");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rewrite_null>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: missing #cpu declaration

assistant: ```c
char *rewrite_null(int code) {
  error("missing #cpu declaration");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rewrite_null>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: missing #cpu declaration

assistant: ```c
char *rewrite_null(int code) {
  error("missing #cpu declaration");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findMaxElem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x1c(%rbp)
  jg     L8
  mov    $0xffffffff,%eax
  jmp    L76
L8:
  movl   $0x0,-0x8(%rbp)
  jmp    L50
L83:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L59:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L43
  addl   $0x1,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0xc(%rbp)
  jl     L43
  mov    -0x4(%rbp),%eax
  jmp    L76
L43:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L59
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L83
  mov    $0xfffffffe,%eax
L76:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: Array Count %d


assistant: ```c
int findMaxElem(int A[], int n) {
  int count = 0;
  printf("Array Count %d\n", n);
  if (n <= 0) {
    return (-1);
  }
  for (int i = 0; i < n; i++) {
    count = 0;
    for (int j = 0; j < n; j++) {
      if (A[j] == A[i]) {
        count++;
        if (count >= n / 2) {
          return j;
        }
      }
    }
  }
  return (-2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findMaxElem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L32
  mov    %ebx,%r8d
  shr    $0x1f,%r8d
  add    %ebx,%r8d
  sar    %r8d
  mov    %rbp,%r9
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%r10
  mov    %ebx,%edx
  jmp    L56
L46:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L45
L27:
  mov    %eax,%edi
  cmp    %esi,0x0(%rbp,%rax,4)
  jne    L46
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jg     L46
L80:
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L45:
  add    $0x4,%r9
  cmp    %r10,%r9
  je     L88
L56:
  mov    (%r9),%esi
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L27
L32:
  mov    $0xffffffff,%edi
  jmp    L80
L88:
  mov    $0xfffffffe,%edi
  jmp    L80
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: Array Count %d


assistant: ```c
int findMaxElem(int A[], int n) {
  int count = 0;
  printf("Array Count %d\n", n);
  if (n <= 0) {
    return (-1);
  }
  for (int i = 0; i < n; i++) {
    count = 0;
    for (int j = 0; j < n; j++) {
      if (A[j] == A[i]) {
        count++;
        if (count >= n / 2) {
          return j;
        }
      }
    }
  }
  return (-2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findMaxElem>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L0
  mov    %ebx,%edi
  lea    -0x1(%rbx),%eax
  mov    %rbp,%r9
  mov    %ebx,%edx
  sar    %edi
  lea    0x4(%rbp,%rax,4),%r10
L58:
  mov    (%r9),%esi
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L7
  nopl   0x0(%rax)
L56:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L38
L7:
  mov    %eax,%r8d
  cmp    %esi,0x0(%rbp,%rax,4)
  jne    L56
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L56
L17:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x4,%r9
  cmp    %r10,%r9
  jne    L58
  add    $0x8,%rsp
  mov    $0xfffffffe,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0xffffffff,%r8d
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: Array Count %d


assistant: ```c
int findMaxElem(int A[], int n) {
  int count = 0;
  printf("Array Count %d\n", n);
  if (n <= 0) {
    return (-1);
  }
  for (int i = 0; i < n; i++) {
    count = 0;
    for (int j = 0; j < n; j++) {
      if (A[j] == A[i]) {
        count++;
        if (count >= n / 2) {
          return j;
        }
      }
    }
  }
  return (-2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findMaxElem>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L14
  mov    %ebx,%edi
  lea    -0x1(%rbx),%eax
  mov    %rbp,%r9
  mov    %ebx,%edx
  sar    %edi
  lea    0x4(%rbp,%rax,4),%r10
L67:
  mov    (%r9),%esi
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L53
  nopl   0x0(%rax)
L50:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L47
L53:
  mov    %eax,%r8d
  cmp    %esi,0x0(%rbp,%rax,4)
  jne    L50
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L50
L42:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x4,%r9
  cmp    %r10,%r9
  jne    L67
  add    $0x8,%rsp
  mov    $0xfffffffe,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%r8d
  jmp    L42
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: Array Count %d


assistant: ```c
int findMaxElem(int A[], int n) {
  int count = 0;
  printf("Array Count %d\n", n);
  if (n <= 0) {
    return (-1);
  }
  for (int i = 0; i < n; i++) {
    count = 0;
    for (int j = 0; j < n; j++) {
      if (A[j] == A[i]) {
        count++;
        if (count >= n / 2) {
          return j;
        }
      }
    }
  }
  return (-2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <tmpnam@plt>
  mov    %rax,%rcx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: %s, s %s


assistant: ```c
int main() {
  char s[20];
  printf("%s, s %s\n", tmpnam(s), s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <tmpnam@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: %s, s %s


assistant: ```c
int main() {
  char s[20];
  printf("%s, s %s\n", tmpnam(s), s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <tmpnam@plt>
  mov    %r12,%rdx
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: %s, s %s


assistant: ```c
int main() {
  char s[20];
  printf("%s, s %s\n", tmpnam(s), s);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <tmpnam@plt>
  mov    %r12,%rdx
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s, s %s


assistant: ```c
int main() {
  char s[20];
  printf("%s, s %s\n", tmpnam(s), s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L12
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  jmp    L9
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    (%rdx),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calc_gcd>
L9:
  leave
  ret
```

assistant: ```c
unsigned int calc_gcd(unsigned int *a, unsigned int *b) {
  if (*b == 0)
    return *a;
  *a = *a - (*b) * ((*a) / (*b));
  return calc_gcd(b, a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calc_gcd>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    (%rsi),%esi
  test   %esi,%esi
  jne    L7
  mov    (%rcx),%eax
  ret
L7:
  sub    $0x8,%rsp
  mov    (%rcx),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %edx,(%rcx)
  mov    %rcx,%rsi
  call   <calc_gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int calc_gcd(unsigned int *a, unsigned int *b) {
  if (*b == 0)
    return *a;
  *a = *a - (*b) * ((*a) / (*b));
  return calc_gcd(b, a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_gcd>:
  endbr64
  mov    (%rsi),%edx
  test   %edx,%edx
  jne    L20
  jmp    L6
  nopl   0x0(%rax)
L15:
  mov    %rax,%rsi
L20:
  mov    (%rdi),%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  div    %ecx
  mov    %rdi,%rax
  mov    %edx,(%rdi)
  mov    %rsi,%rdi
  test   %edx,%edx
  jne    L15
  mov    (%rsi),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rsi
  mov    (%rsi),%eax
  ret
```

assistant: ```c
unsigned int calc_gcd(unsigned int *a, unsigned int *b) {
  if (*b == 0)
    return *a;
  *a = *a - (*b) * ((*a) / (*b));
  return calc_gcd(b, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_gcd>:
  endbr64
  mov    (%rsi),%edx
  test   %edx,%edx
  jne    L0
  jmp    L25
  nopl   0x0(%rax)
L24:
  mov    %rax,%rsi
L0:
  mov    (%rdi),%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  div    %ecx
  mov    %rdi,%rax
  mov    %edx,(%rdi)
  mov    %rsi,%rdi
  test   %edx,%edx
  jne    L24
  mov    (%rsi),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rdi,%rsi
  mov    (%rsi),%eax
  ret
```

assistant: ```c
unsigned int calc_gcd(unsigned int *a, unsigned int *b) {
  if (*b == 0)
    return *a;
  *a = *a - (*b) * ((*a) / (*b));
  return calc_gcd(b, a);
}
```