ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<Camelback2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L56
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    (%rax,%rax,1),%r13d
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L46
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L35:
  movzbl (%rdi),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L6
  movslq %eax,%rdx
  add    $0x1,%eax
  movb   $0x5f,(%r12,%rdx,1)
  movzbl (%rdi),%ebx
  lea    0x20(%rbx),%edx
L6:
  movslq %eax,%rcx
  add    $0x1,%rdi
  add    $0x1,%eax
  mov    %dl,(%r12,%rcx,1)
  cmp    %rdi,%rsi
  jne    L35
  cltq
  add    %r12,%rax
L42:
  movb   $0x0,(%rax)
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L46:
  mov    %r12,%rax
  jmp    L42
L56:
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: src == NULL


assistant: ```c
char *Camelback2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c = src[i] + 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Camelback2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L45
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    (%rax,%rax,1),%r13d
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L50
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L42:
  movzbl (%rdi),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L5
  movslq %eax,%rdx
  add    $0x1,%rdi
  movb   $0x5f,(%r12,%rdx,1)
  movzbl -0x1(%rdi),%ebx
  lea    0x1(%rax),%edx
  add    $0x2,%eax
  movslq %edx,%rdx
  lea    0x20(%rbx),%ecx
  mov    %cl,(%r12,%rdx,1)
  cmp    %rsi,%rdi
  jne    L42
L79:
  cltq
  add    %r12,%rax
L12:
  movb   $0x0,(%rax)
L62:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movslq %eax,%rcx
  add    $0x1,%rdi
  add    $0x1,%eax
  mov    %dl,(%r12,%rcx,1)
  cmp    %rdi,%rsi
  jne    L42
  jmp    L79
  nopl   (%rax)
L50:
  mov    %r12,%rax
  jmp    L12
L45:
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L62
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: D7: src == NULL


assistant: ```c
char *Camelback2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c = src[i] + 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<guess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L30
L21:
  cmpl   $0x5,-0x4(%rbp)
  jle    L25
  mov    $0x1,%eax
  jmp    L30
L25:
  mov    $0xffffffff,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int guess(int num) {
  if (num == 5)
    return 0;
  if (num > 5)
    return 1;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<guess>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x5,%edi
  je     L9
  cmp    $0x6,%edi
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L9:
  ret
```

assistant: ```c
int guess(int num) {
  if (num == 5)
    return 0;
  if (num > 5)
    return 1;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<guess>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5,%edi
  je     L9
  xor    %eax,%eax
  cmp    $0x6,%edi
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
L9:
  ret
```

assistant: ```c
int guess(int num) {
  if (num == 5)
    return 0;
  if (num > 5)
    return 1;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<guess>:
  endbr64
  xor    %eax,%eax
  cmp    $0x5,%edi
  je     L2
  xor    %eax,%eax
  cmp    $0x6,%edi
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
L2:
  ret
```

assistant: ```c
int guess(int num) {
  if (num == 5)
    return 0;
  if (num > 5)
    return 1;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <suma@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <resta@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <producto@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <division@plt>
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D31
type_infered: string
name: retrieve_data
arguments: data_tag: D38
type_infered: string
name: retrieve_data
arguments: data_tag: D37
type_infered: string

tool: D27: Insert First number: 

tool: D10: %i

tool: D11: Insert Secund number: 

tool: D29: 
 Add: %i

tool: D31: 
 Rest: %i

tool: D38: 
 Multiplication: %i

tool: D37: 
 Div: %i

assistant: ```c
main() {
  char c1;
  int a, b;
  printf("Insert First number: ");
  scanf("%i", &a);
  printf("Insert Secund number: ");
  scanf("%i", &b);
  printf("\n Add: %i", suma(a, b));
  printf("\n Rest: %i", resta(a, b));
  printf("\n Multiplication: %i", producto(a, b));
  printf("\n Div: %i", division(a, b));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <suma@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <resta@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <producto@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <division@plt>
  mov    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D59
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D31
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D40
type: string

tool: D59: Insert First number: 

tool: D38: %i

tool: D31: Insert Secund number: 

tool: D29: 
 Add: %i

tool: D25: 
 Rest: %i

tool: D16: 
 Multiplication: %i

tool: D40: 
 Div: %i

assistant: ```c
main() {
  char c1;
  int a, b;
  printf("Insert First number: ");
  scanf("%i", &a);
  printf("Insert Secund number: ");
  scanf("%i", &b);
  printf("\n Add: %i", suma(a, b));
  printf("\n Rest: %i", resta(a, b));
  printf("\n Multiplication: %i", producto(a, b));
  printf("\n Div: %i", division(a, b));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D43(%rip),%rdi
  lea    D28(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <suma@plt>
  lea    D46(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <resta@plt>
  lea    D41(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <producto@plt>
  lea    D47(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <division@plt>
  lea    D67(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D43
type_guessed: string
name: unpack_data
arguments: data_tag: D28
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D46
type_guessed: string
name: unpack_data
arguments: data_tag: D41
type_guessed: string
name: unpack_data
arguments: data_tag: D47
type_guessed: string
name: unpack_data
arguments: data_tag: D67
type_guessed: string

tool: D43: Insert First number: 

tool: D28: %i

tool: D18: Insert Secund number: 

tool: D46: 
 Add: %i

tool: D41: 
 Rest: %i

tool: D47: 
 Multiplication: %i

tool: D67: 
 Div: %i

assistant: ```c
main() {
  char c1;
  int a, b;
  printf("Insert First number: ");
  scanf("%i", &a);
  printf("Insert Secund number: ");
  scanf("%i", &b);
  printf("\n Add: %i", suma(a, b));
  printf("\n Rest: %i", resta(a, b));
  printf("\n Multiplication: %i", producto(a, b));
  printf("\n Div: %i", division(a, b));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D40(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <suma@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <resta@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <producto@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <division@plt>
  lea    D30(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D34
data_type: string
name: unpack_data
arguments: tag: D40
data_type: string
name: unpack_data
arguments: tag: D58
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string

tool: D34: Insert First number: 

tool: D40: %i

tool: D58: Insert Secund number: 

tool: D0: 
 Add: %i

tool: D38: 
 Rest: %i

tool: D17: 
 Multiplication: %i

tool: D30: 
 Div: %i

assistant: ```c
main() {
  char c1;
  int a, b;
  printf("Insert First number: ");
  scanf("%i", &a);
  printf("Insert Secund number: ");
  scanf("%i", &b);
  printf("\n Add: %i", suma(a, b));
  printf("\n Rest: %i", resta(a, b));
  printf("\n Multiplication: %i", producto(a, b));
  printf("\n Div: %i", division(a, b));
}
```
user: Translate the below assembly code into C programming language:

```asm
<gluBuild1DMipmaps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <checkMipmapArgs@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L37
  mov    -0x10(%rbp),%eax
  jmp    L26
L37:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L1
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L26
L1:
  mov    -0x34(%rbp),%r8d
  mov    -0x30(%rbp),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x24(%rbp),%eax
  lea    -0x14(%rbp),%rcx
  push   %rcx
  lea    -0x18(%rbp),%rcx
  push   %rcx
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <closestFit@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <computeLog@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x34(%rbp),%r9d
  mov    -0x30(%rbp),%r8d
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  push   -0x40(%rbp)
  mov    -0xc(%rbp),%edi
  push   %rdi
  push   $0x0
  push   $0x0
  mov    %eax,%edi
  call   <gluBuild1DMipmapLevelsCore@plt>
  add    $0x20,%rsp
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
GLint gluBuild1DMipmaps(GLenum target, GLint internalFormat, GLsizei width, GLenum format, GLenum type, const void *data) {
  GLint widthPowerOf2;
  int levels;
  GLint dummy;
  int rc = checkMipmapArgs(internalFormat, format, type);
  if (rc != 0)
    return rc;
  if (width < 1) {
    return GLU_INVALID_VALUE;
  }
  closestFit(target, width, 1, internalFormat, format, type, &widthPowerOf2, &dummy);
  levels = computeLog(widthPowerOf2);
  return gluBuild1DMipmapLevelsCore(target, internalFormat, width, widthPowerOf2, format, type, 0, 0, levels, data);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gluBuild1DMipmaps>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %r8d,%r12d
  mov    %r9,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r8d,%edx
  mov    %ecx,%esi
  mov    %ebx,%edi
  call   <checkMipmapArgs@plt>
  test   %eax,%eax
  jne    L0
  test   %r13d,%r13d
  jle    L18
  lea    0x4(%rsp),%rax
  push   %rax
  lea    0x8(%rsp),%rax
  push   %rax
  mov    %r12d,%r9d
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <closestFit@plt>
  mov    0x10(%rsp),%edi
  call   <computeLog@plt>
  push   %r15
  push   %rax
  push   $0x0
  push   $0x0
  mov    %r12d,%r9d
  mov    %ebp,%r8d
  mov    0x30(%rsp),%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <gluBuild1DMipmapLevelsCore@plt>
  add    $0x30,%rsp
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  jmp    L0
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
GLint gluBuild1DMipmaps(GLenum target, GLint internalFormat, GLsizei width, GLenum format, GLenum type, const void *data) {
  GLint widthPowerOf2;
  int levels;
  GLint dummy;
  int rc = checkMipmapArgs(internalFormat, format, type);
  if (rc != 0)
    return rc;
  if (width < 1) {
    return GLU_INVALID_VALUE;
  }
  closestFit(target, width, 1, internalFormat, format, type, &widthPowerOf2, &dummy);
  levels = computeLog(widthPowerOf2);
  return gluBuild1DMipmapLevelsCore(target, internalFormat, width, widthPowerOf2, format, type, 0, 0, levels, data);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gluBuild1DMipmaps>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  mov    %r8d,%edx
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %ecx,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <checkMipmapArgs@plt>
  test   %eax,%eax
  jne    L15
  test   %r15d,%r15d
  jle    L23
  lea    0x4(%rsp),%rax
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  push   %rax
  mov    $0x1,%edx
  mov    %r15d,%esi
  mov    %r12d,%edi
  lea    0x8(%rsp),%rax
  push   %rax
  call   <closestFit@plt>
  mov    0x10(%rsp),%edi
  call   <computeLog@plt>
  push   %r13
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  push   %rax
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  push   $0x0
  push   $0x0
  mov    0x30(%rsp),%ecx
  call   <gluBuild1DMipmapLevelsCore@plt>
  add    $0x30,%rsp
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L23:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jmp    L15
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
GLint gluBuild1DMipmaps(GLenum target, GLint internalFormat, GLsizei width, GLenum format, GLenum type, const void *data) {
  GLint widthPowerOf2;
  int levels;
  GLint dummy;
  int rc = checkMipmapArgs(internalFormat, format, type);
  if (rc != 0)
    return rc;
  if (width < 1) {
    return GLU_INVALID_VALUE;
  }
  closestFit(target, width, 1, internalFormat, format, type, &widthPowerOf2, &dummy);
  levels = computeLog(widthPowerOf2);
  return gluBuild1DMipmapLevelsCore(target, internalFormat, width, widthPowerOf2, format, type, 0, 0, levels, data);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gluBuild1DMipmaps>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  mov    %r8d,%edx
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %ecx,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <checkMipmapArgs@plt>
  test   %eax,%eax
  jne    L30
  test   %r15d,%r15d
  jle    L20
  lea    0x4(%rsp),%rax
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  push   %rax
  mov    $0x1,%edx
  mov    %r15d,%esi
  mov    %r12d,%edi
  lea    0x8(%rsp),%rax
  push   %rax
  call   <closestFit@plt>
  mov    0x10(%rsp),%edi
  call   <computeLog@plt>
  push   %r13
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  push   %rax
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  push   $0x0
  push   $0x0
  mov    0x30(%rsp),%ecx
  call   <gluBuild1DMipmapLevelsCore@plt>
  add    $0x30,%rsp
L30:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L30
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
GLint gluBuild1DMipmaps(GLenum target, GLint internalFormat, GLsizei width, GLenum format, GLenum type, const void *data) {
  GLint widthPowerOf2;
  int levels;
  GLint dummy;
  int rc = checkMipmapArgs(internalFormat, format, type);
  if (rc != 0)
    return rc;
  if (width < 1) {
    return GLU_INVALID_VALUE;
  }
  closestFit(target, width, 1, internalFormat, format, type, &widthPowerOf2, &dummy);
  levels = computeLog(widthPowerOf2);
  return gluBuild1DMipmapLevelsCore(target, internalFormat, width, widthPowerOf2, format, type, 0, 0, levels, data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D15(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  D34(%rip),%xmm1
  andps  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  andpd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type: byte[4]
name: disassemble_data
arguments: label: D16
type: byte[8]
name: disassemble_data
arguments: label: D34
type: dword
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D1
type: qword
name: disassemble_data
arguments: label: D43
type: string

tool: {"D15": [0x00,0x40,0x9a,0xc4]}

tool: {"D16": [0x7c,0x2c,0x7d,0xe8,0x82,0xaa,0x28,0xc0]}

tool: D34: 2147483647

tool: D3: number:%f absolute value:%f


tool: D1: 9223372036854775807

tool: D43: number:%lf absolute value:%lf


assistant: ```c
main() {
  float fn = -1234.0;
  double dn = -12.33303;
  printf("number:%f absolute value:%f\n", fn, fabs(fn));
  printf("number:%lf absolute value:%lf\n", dn, fabs(dn));
  getch();
}
```