ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<BN_GF2m_mod_exp_arr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rdi
  call   <bn_check_top@plt>
  mov    %rbx,%rdi
  call   <bn_check_top@plt>
  mov    %rbx,%rdi
  call   <BN_is_zero@plt>
  test   %rax,%rax
  jne    L62
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <BN_abs_is_word@plt>
  test   %rax,%rax
  jne    L119
  mov    %r12,%rdi
  call   <BN_CTX_start@plt>
  mov    %r12,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L6
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <BN_GF2m_mod_arr@plt>
  test   %eax,%eax
  jne    L105
L6:
  xor    %r13d,%r13d
L83:
  mov    %r12,%rdi
  call   <BN_CTX_end@plt>
  jmp    L56
  nopl   (%rax)
L119:
  mov    0x8(%rsp),%rdi
  mov    %r14,%rsi
  xor    %r13d,%r13d
  call   <BN_copy@plt>
  test   %rax,%rax
  setne  %r13b
L56:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L62:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    11c0 <BN_one@plt>
  nopl   0x0(%rax,%rax,1)
L105:
  mov    %rbx,%rdi
  call   <BN_num_bits@plt>
  sub    $0x2,%eax
  mov    %eax,%ebp
  jns    L5
  jmp    L82
  nopl   0x0(%rax)
L35:
  sub    $0x1,%ebp
  jb     L82
L5:
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %r15,%rdi
  call   <BN_GF2m_mod_sqr_arr@plt>
  test   %eax,%eax
  je     L6
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <BN_is_bit_set@plt>
  test   %rax,%rax
  je     L35
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %r15,%rdi
  call   <BN_GF2m_mod_mul_arr@plt>
  test   %eax,%eax
  jne    L35
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L82:
  mov    0x8(%rsp),%rbx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <BN_copy@plt>
  test   %rax,%rax
  je     L6
  mov    %rbx,%rdi
  mov    $0x1,%r13d
  call   <bn_check_top@plt>
  jmp    L83
```

assistant: ```c
int BN_GF2m_mod_exp_arr(BIGNUM *r, const BIGNUM *a, const BIGNUM *b, const int p[], BN_CTX *ctx) {
  int ret = 0, i, n;
  BIGNUM *u;
  bn_check_top(a);
  bn_check_top(b);
  if (BN_is_zero(b))
    return (BN_one(r));
  if (BN_abs_is_word(b, 1))
    return (BN_copy(r, a) != NULL);
  BN_CTX_start(ctx);
  if ((u = BN_CTX_get(ctx)) == NULL)
    goto err;
  if (!BN_GF2m_mod_arr(u, a, p))
    goto err;
  n = BN_num_bits(b) - 1;
  for (i = n - 1; i >= 0; i--) {
    if (!BN_GF2m_mod_sqr_arr(u, u, p, ctx))
      goto err;
    if (BN_is_bit_set(b, i)) {
      if (!BN_GF2m_mod_mul_arr(u, u, a, p, ctx))
        goto err;
    }
  }
  if (!BN_copy(r, u))
    goto err;
  bn_check_top(r);
  ret = 1;
err:
  BN_CTX_end(ctx);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L3:
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x2,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L6:
  cmpl   $0xa,-0x8(%rbp)
  jle    L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: %d x %d = %d 


assistant: ```c
int main() {
  int multi = 1, ans;
  while (multi <= 10) {
    ans = 2 * multi;
    printf("%d x %d = %d \n", 2, multi, ans);
    multi++;
    ans = 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D4(%rip),%rbp
L0:
  lea    (%rbx,%rbx,1),%ecx
  mov    %ebx,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: %d x %d = %d 


assistant: ```c
int main() {
  int multi = 1, ans;
  while (multi <= 10) {
    ans = 2 * multi;
    printf("%d x %d = %d \n", 2, multi, ans);
    multi++;
    ans = 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    (%rbx,%rbx,1),%ecx
  mov    %ebx,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: %d x %d = %d 


assistant: ```c
int main() {
  int multi = 1, ans;
  while (multi <= 10) {
    ans = 2 * multi;
    printf("%d x %d = %d \n", 2, multi, ans);
    multi++;
    ans = 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    (%rbx,%rbx,1),%ecx
  mov    %ebx,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: %d x %d = %d 


assistant: ```c
int main() {
  int multi = 1, ans;
  while (multi <= 10) {
    ans = 2 * multi;
    printf("%d x %d = %d \n", 2, multi, ans);
    multi++;
    ans = 0;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<apple___sccl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x5e,-0xc(%rbp)
  jne    L127
  movl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L28
L127:
  movl   $0x0,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x100,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L88
  mov    -0x20(%rbp),%rax
  sub    $0x4,%rax
  jmp    L167
L88:
  mov    $0x1,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L148:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L169:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5d,-0x4(%rbp)
  je     L62
  cmpl   $0x5d,-0x4(%rbp)
  jg     L140
  cmpl   $0x0,-0x4(%rbp)
  je     L32
  cmpl   $0x2d,-0x4(%rbp)
  je     L79
  jmp    L140
L32:
  mov    -0x20(%rbp),%rax
  sub    $0x4,%rax
  jmp    L167
L79:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5d,-0x4(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L115
L15:
  movl   $0x2d,-0xc(%rbp)
  jmp    L93
L115:
  addq   $0x4,-0x20(%rbp)
L42:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L42
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L169
L62:
  mov    -0x20(%rbp),%rax
  jmp    L167
L140:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  nop
L93:
  jmp    L148
L167:
  leave
  ret
```

assistant: ```c
const u_char *apple___sccl(char *tab, const u_char *fmt) {
  int c, n, v;
  c = *fmt++;
  if (c == '^') {
    v = 1;
    c = *fmt++;
  } else
    v = 0;
  (void)memset(tab, v, 256);
  if (c == 0)
    return (fmt - 1);
  v = 1 - v;
  for (;;) {
    tab[c] = v;
  doswitch:
    n = *fmt++;
    switch (n) {
    case 0:
      return (fmt - 1);
    case '-':
      n = *fmt;
      if (n == ']' || n < c) {
        c = '-';
        break;
      }
      fmt++;
      do {
        tab[++c] = v;
      } while (c < n);
      c = n;
      goto doswitch;
      break;
    case ']':
      return (fmt);
    default:
      c = n;
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<apple___sccl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    (%rsi),%ebx
  cmp    $0x5e,%ebx
  je     L22
  lea    0x4(%rsi),%rbp
  mov    $0x0,%r13d
L110:
  mov    $0x100,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x1,%edx
  sub    %r13d,%edx
  mov    %edx,%esi
  test   %ebx,%ebx
  je     L27
L86:
  movslq %ebx,%rax
  mov    %dl,(%r12,%rax,1)
L43:
  lea    0x4(%rbp),%rdi
  mov    0x0(%rbp),%eax
  cmp    $0x2d,%eax
  je     L112
  cmp    $0x5d,%eax
  je     L20
  test   %eax,%eax
  je     L13
L16:
  mov    %eax,%ebx
  mov    %rdi,%rbp
  jmp    L86
L22:
  lea    0x8(%rsi),%rbp
  mov    0x4(%rsi),%ebx
  mov    $0x1,%r13d
  jmp    L110
L27:
  sub    $0x4,%rbp
  jmp    L13
L112:
  mov    0x4(%rbp),%ecx
  cmp    $0x5d,%ecx
  je     L16
  cmp    %ecx,%ebx
  jg     L16
  lea    0x8(%rbp),%rbp
  movslq %ebx,%rax
L37:
  mov    %sil,0x1(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L37
  mov    %ecx,%ebx
  jmp    L43
L20:
  mov    %rdi,%rbp
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const u_char *apple___sccl(char *tab, const u_char *fmt) {
  int c, n, v;
  c = *fmt++;
  if (c == '^') {
    v = 1;
    c = *fmt++;
  } else
    v = 0;
  (void)memset(tab, v, 256);
  if (c == 0)
    return (fmt - 1);
  v = 1 - v;
  for (;;) {
    tab[c] = v;
  doswitch:
    n = *fmt++;
    switch (n) {
    case 0:
      return (fmt - 1);
    case '-':
      n = *fmt;
      if (n == ']' || n < c) {
        c = '-';
        break;
      }
      fmt++;
      do {
        tab[++c] = v;
      } while (c < n);
      c = n;
      goto doswitch;
      break;
    case ']':
      return (fmt);
    default:
      c = n;
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<apple___sccl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq (%rsi),%rbx
  cmp    $0x5e,%ebx
  je     L64
  lea    0x4(%rsi),%r12
  xor    %r14d,%r14d
L83:
  mov    $0x100,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L19
  mov    $0x1,%r13d
  mov    $0x1,%ecx
  sub    %r14d,%r13d
  mov    %r13d,%r15d
L33:
  movslq %ebx,%rax
  mov    %r15b,0x0(%rbp,%rax,1)
L26:
  mov    (%r12),%eax
  lea    0x4(%r12),%rdx
  cmp    $0x2d,%eax
  je     L3
  cmp    $0x5d,%eax
  je     L70
  test   %eax,%eax
  je     L98
L43:
  movslq %eax,%rbx
  mov    %rdx,%r12
  jmp    L33
L70:
  mov    %rdx,%r12
L98:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L19:
  sub    $0x4,%r12
  jmp    L98
  xchg   %ax,%ax
L64:
  movslq 0x4(%rsi),%rbx
  lea    0x8(%rsi),%r12
  mov    $0x1,%r14d
  jmp    L83
L3:
  mov    0x4(%r12),%r14d
  cmp    $0x5d,%r14d
  je     L43
  cmp    %r14d,%ebx
  jg     L43
  mov    %r14d,%eax
  add    $0x8,%r12
  lea    0x1(%rbp,%rbx,1),%rdi
  mov    %r13d,%esi
  sub    %ebx,%eax
  lea    -0x1(%rax),%edx
  add    $0x1,%rdx
  cmp    %r14d,%ebx
  movslq %r14d,%rbx
  cmovge %rcx,%rdx
  call   <memset@plt>
  mov    $0x1,%ecx
  jmp    L26
```

assistant: ```c
const u_char *apple___sccl(char *tab, const u_char *fmt) {
  int c, n, v;
  c = *fmt++;
  if (c == '^') {
    v = 1;
    c = *fmt++;
  } else
    v = 0;
  (void)memset(tab, v, 256);
  if (c == 0)
    return (fmt - 1);
  v = 1 - v;
  for (;;) {
    tab[c] = v;
  doswitch:
    n = *fmt++;
    switch (n) {
    case 0:
      return (fmt - 1);
    case '-':
      n = *fmt;
      if (n == ']' || n < c) {
        c = '-';
        break;
      }
      fmt++;
      do {
        tab[++c] = v;
      } while (c < n);
      c = n;
      goto doswitch;
      break;
    case ']':
      return (fmt);
    default:
      c = n;
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<apple___sccl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq (%rsi),%rbx
  cmp    $0x5e,%ebx
  je     L9
  lea    0x4(%rsi),%r12
  mov    $0x1,%r13d
  xor    %esi,%esi
L20:
  mov    $0x100,%edx
  mov    %rbp,%rdi
  mov    $0x1,%r15d
  call   <memset@plt>
  test   %ebx,%ebx
  je     L68
L0:
  movslq %ebx,%rax
  mov    %r13b,0x0(%rbp,%rax,1)
L80:
  mov    (%r12),%eax
  lea    0x4(%r12),%rdx
  cmp    $0x2d,%eax
  je     L55
  cmp    $0x5d,%eax
  je     L98
  test   %eax,%eax
  je     L28
L109:
  movslq %eax,%rbx
  mov    %rdx,%r12
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L98:
  mov    %rdx,%r12
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L68:
  sub    $0x4,%r12
  jmp    L28
  xchg   %ax,%ax
L9:
  movslq 0x4(%rsi),%rbx
  lea    0x8(%rsi),%r12
  xor    %r13d,%r13d
  mov    $0x1,%esi
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x4(%r12),%r14d
  cmp    $0x5d,%r14d
  je     L109
  cmp    %r14d,%ebx
  jg     L109
  mov    %r14d,%eax
  add    $0x8,%r12
  lea    0x1(%rbp,%rbx,1),%rdi
  movsbl %r13b,%esi
  sub    %ebx,%eax
  lea    -0x1(%rax),%edx
  add    $0x1,%rdx
  cmp    %r14d,%ebx
  movslq %r14d,%rbx
  cmovge %r15,%rdx
  call   <memset@plt>
  jmp    L80
```

assistant: ```c
const u_char *apple___sccl(char *tab, const u_char *fmt) {
  int c, n, v;
  c = *fmt++;
  if (c == '^') {
    v = 1;
    c = *fmt++;
  } else
    v = 0;
  (void)memset(tab, v, 256);
  if (c == 0)
    return (fmt - 1);
  v = 1 - v;
  for (;;) {
    tab[c] = v;
  doswitch:
    n = *fmt++;
    switch (n) {
    case 0:
      return (fmt - 1);
    case '-':
      n = *fmt;
      if (n == ']' || n < c) {
        c = '-';
        break;
      }
      fmt++;
      do {
        tab[++c] = v;
      } while (c < n);
      c = n;
      goto doswitch;
      break;
    case ']':
      return (fmt);
    default:
      c = n;
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0xfffffffe,-0x2c(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%edx
  lea    -0x20(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_interval@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: f64
name: extract_symbolic_data
arguments: label: D19
type_infered: f64

tool: D18: 1

tool: D19: 0.5

assistant: ```c
int test2() {
  const int nt = 2;
  double t[] = {0.0, 1.0};
  double treq = 0.5;
  int i = -2;
  i = (int)get_interval(t, nt, treq);
  return (i == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    D1(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    %rsp,%rdi
  movsd  D8(%rip),%xmm0
  mov    $0x2,%esi
  call   <get_interval@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: f64
name: disassemble_data
arguments: label: D8
data_type: f64

tool: D1: 1

tool: D8: 0.5

assistant: ```c
int test2() {
  const int nt = 2;
  double t[] = {0.0, 1.0};
  double treq = 0.5;
  int i = -2;
  i = (int)get_interval(t, nt, treq);
  return (i == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  movsd  D10(%rip),%xmm0
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <get_interval@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: f64

tool: D10: 0.5

tool: D6: 1

assistant: ```c
int test2() {
  const int nt = 2;
  double t[] = {0.0, 1.0};
  double treq = 0.5;
  int i = -2;
  i = (int)get_interval(t, nt, treq);
  return (i == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test2>:
  endbr64
  sub    $0x28,%rsp
  movapd D9(%rip),%xmm0
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movsd  D6(%rip),%xmm0
  call   <get_interval@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: f64[2]
name: read_data
arguments: tag: D6
type_infered: f64

tool: {"D9": [0.0,1.0]}

tool: D6: 0.5

assistant: ```c
int test2() {
  const int nt = 2;
  double t[] = {0.0, 1.0};
  double treq = 0.5;
  int i = -2;
  i = (int)get_interval(t, nt, treq);
  return (i == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readpoints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L29:
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jg     L42
  mov    $0x1,%eax
  jmp    L3
L42:
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L30
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L29
  mov    $0x0,%eax
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: %lf %lf


assistant: ```c
int readpoints(FILE *stream, double **gridx, double **gridy, int xsize, int ysize) {
  int ix, iy;
  for (iy = 0; iy <= ysize; iy++) {
    for (ix = 0; ix <= xsize; ix++) {
      if (fscanf(stream, "%lf %lf\n", &gridx[ix][iy], &gridy[ix][iy]) < 2) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readpoints>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %r8d,0x1c(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D4(%rip),%r15
  mov    $0x0,%eax
  test   %r8d,%r8d
  js     L42
L3:
  mov    0x10(%rsp),%rax
  lea    0x0(,%rax,8),%rbp
  mov    $0x0,%ebx
  test   %r12d,%r12d
  js     L14
L30:
  mov    %rbp,%rcx
  add    0x0(%r13,%rbx,8),%rcx
  mov    %rbp,%rdx
  add    (%r14,%rbx,8),%rdx
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jle    L51
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L30
L14:
  addq   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%rax
  cmp    %eax,0x1c(%rsp)
  jge    L3
  mov    $0x0,%eax
  jmp    L42
L51:
  mov    $0x1,%eax
L42:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %lf %lf


assistant: ```c
int readpoints(FILE *stream, double **gridx, double **gridy, int xsize, int ysize) {
  int ix, iy;
  for (iy = 0; iy <= ysize; iy++) {
    for (ix = 0; ix <= xsize; ix++) {
      if (fscanf(stream, "%lf %lf\n", &gridx[ix][iy], &gridy[ix][iy]) < 2) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readpoints>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  movq   $0x0,(%rsp)
  test   %r8d,%r8d
  js     L18
  mov    %rdi,%r13
  mov    %rsi,%r12
  lea    D4(%rip),%r14
  mov    %rdx,%rbp
L26:
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  lea    0x0(,%rax,8),%rbx
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jns    L14
  jmp    L44
  nopl   (%rax)
L49:
  add    $0x1,%r15
  cmp    %r15d,0x8(%rsp)
  jl     L44
L14:
  mov    0x0(%rbp,%r15,8),%rcx
  mov    (%r12,%r15,8),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    %rbx,%rcx
  add    %rbx,%rdx
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jg     L49
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  cmp    %eax,0xc(%rsp)
  jge    L26
L18:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %lf %lf


assistant: ```c
int readpoints(FILE *stream, double **gridx, double **gridy, int xsize, int ysize) {
  int ix, iy;
  for (iy = 0; iy <= ysize; iy++) {
    for (ix = 0; ix <= xsize; ix++) {
      if (fscanf(stream, "%lf %lf\n", &gridx[ix][iy], &gridy[ix][iy]) < 2) {
        return 1;
      }
    }
  }
  return 0;
}
```