ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utils_full_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L31
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r13d
L30:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <utils_safe_write@plt>
  test   %rax,%rax
  js     L8
  add    %rax,%r13
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L30
  jmp    L37
L8:
  test   %r13,%r13
  cmove  %rax,%r13
L37:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    $0x0,%r13d
  jmp    L37
```

assistant: ```c
ssize_t utils_full_write(int fd, const void *buf, size_t len) {
  ssize_t cc;
  ssize_t total;
  total = 0;
  while (len) {
    cc = utils_safe_write(fd, buf, len);
    if (cc < 0) {
      if (total) {
        return total;
      }
      return cc;
    }
    total += cc;
    buf = ((const char *)buf) + cc;
    len -= cc;
  }
  return total;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utils_full_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L8
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  xor    %r13d,%r13d
  jmp    L3
  nopl   0x0(%rax)
L28:
  add    %rax,%r13
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L30
L3:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <utils_safe_write@plt>
  test   %rax,%rax
  jns    L28
  test   %r13,%r13
  cmove  %rax,%r13
L30:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  xor    %r13d,%r13d
  jmp    L30
```

assistant: ```c
ssize_t utils_full_write(int fd, const void *buf, size_t len) {
  ssize_t cc;
  ssize_t total;
  total = 0;
  while (len) {
    cc = utils_safe_write(fd, buf, len);
    if (cc < 0) {
      if (total) {
        return total;
      }
      return cc;
    }
    total += cc;
    buf = ((const char *)buf) + cc;
    len -= cc;
  }
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utils_full_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L30
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  xor    %r13d,%r13d
  jmp    L7
  nopl   0x0(%rax)
L48:
  add    %rax,%r13
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L3
L7:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <utils_safe_write@plt>
  test   %rax,%rax
  jns    L48
  test   %r13,%r13
  cmove  %rax,%r13
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  xor    %r13d,%r13d
  jmp    L3
```

assistant: ```c
ssize_t utils_full_write(int fd, const void *buf, size_t len) {
  ssize_t cc;
  ssize_t total;
  total = 0;
  while (len) {
    cc = utils_safe_write(fd, buf, len);
    if (cc < 0) {
      if (total) {
        return total;
      }
      return cc;
    }
    total += cc;
    buf = ((const char *)buf) + cc;
    len -= cc;
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<open_lsocket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    D29(%rip),%rax
  mov    %edx,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L73
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
L73:
  mov    $0xffffffff,%eax
  jmp    L82
L61:
  mov    D54(%rip),%rax
  mov    (%rax),%ecx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L82
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strncpy@plt>
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L87
  mov    -0x14(%rbp),%eax
  mov    $0xffffffff,%esi
  mov    %eax,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  jne    L51
L87:
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L82
L51:
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D60(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x14(%rbp),%eax
L82:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int open_lsocket(const char *filename) {
  struct sockaddr_un sockaddr;
  int sock;
  errno = EINVAL;
  if (filename == NULL || !*filename)
    return -1;
  sock = socket(PF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(filename);
  sockaddr.sun_family = AF_UNIX;
  strncpy(sockaddr.sun_path, filename, sizeof(sockaddr.sun_path));
  if (bind(sock, (struct sockaddr *)&sockaddr, sizeof(sockaddr)) == -1 || listen(sock, -1) == -1) {
    shutdown(sock, SHUT_RDWR);
    close(sock);
    return -1;
  }
  fcntl(sock, F_SETFD, FD_CLOEXEC);
  return sock;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<open_lsocket>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D79(%rip),%rax
  mov    (%rax),%edx
  mov    D57(%rip),%rax
  mov    %edx,(%rax)
  test   %rdi,%rdi
  je     L58
  mov    %rdi,%rbp
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x0,%edx
  mov    D36(%rip),%rax
  mov    (%rax),%esi
  mov    D70(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L72
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    (%rsp),%edi
  call   <strncpy@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %ebx,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L44
  mov    $0xffffffff,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L44
  mov    D69(%rip),%rax
  mov    (%rax),%edx
  mov    D74(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
L72:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <shutdown@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L72
L58:
  mov    $0xffffffff,%ebx
  jmp    L72
L18:
  mov    $0xffffffff,%ebx
  jmp    L72
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_lsocket(const char *filename) {
  struct sockaddr_un sockaddr;
  int sock;
  errno = EINVAL;
  if (filename == NULL || !*filename)
    return -1;
  sock = socket(PF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(filename);
  sockaddr.sun_family = AF_UNIX;
  strncpy(sockaddr.sun_path, filename, sizeof(sockaddr.sun_path));
  if (bind(sock, (struct sockaddr *)&sockaddr, sizeof(sockaddr)) == -1 || listen(sock, -1) == -1) {
    shutdown(sock, SHUT_RDWR);
    close(sock);
    return -1;
  }
  fcntl(sock, F_SETFD, FD_CLOEXEC);
  return sock;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<open_lsocket>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D71(%rip),%rax
  mov    %edx,(%rax)
  test   %rdi,%rdi
  je     L23
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L23
  mov    D3(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L23
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    (%rsp),%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <strncpy@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %r12d,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L52
  mov    $0xffffffff,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L52
  mov    D4(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    D65(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <shutdown@plt>
  mov    %r12d,%edi
  call   <close@plt>
L23:
  mov    $0xffffffff,%r12d
  jmp    L63
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_lsocket(const char *filename) {
  struct sockaddr_un sockaddr;
  int sock;
  errno = EINVAL;
  if (filename == NULL || !*filename)
    return -1;
  sock = socket(PF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(filename);
  sockaddr.sun_family = AF_UNIX;
  strncpy(sockaddr.sun_path, filename, sizeof(sockaddr.sun_path));
  if (bind(sock, (struct sockaddr *)&sockaddr, sizeof(sockaddr)) == -1 || listen(sock, -1) == -1) {
    shutdown(sock, SHUT_RDWR);
    close(sock);
    return -1;
  }
  fcntl(sock, F_SETFD, FD_CLOEXEC);
  return sock;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<open_lsocket>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D43(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
  test   %rdi,%rdi
  je     L12
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L12
  mov    D8(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L12
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    (%rsp),%edi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  call   <strncpy@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %r12d,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    $0xffffffff,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    D47(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%edx
  mov    D40(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    D57(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <shutdown@plt>
  mov    %r12d,%edi
  call   <close@plt>
L12:
  mov    $0xffffffff,%r12d
  jmp    L67
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int open_lsocket(const char *filename) {
  struct sockaddr_un sockaddr;
  int sock;
  errno = EINVAL;
  if (filename == NULL || !*filename)
    return -1;
  sock = socket(PF_UNIX, SOCK_STREAM, 0);
  if (sock == -1)
    return -1;
  unlink(filename);
  sockaddr.sun_family = AF_UNIX;
  strncpy(sockaddr.sun_path, filename, sizeof(sockaddr.sun_path));
  if (bind(sock, (struct sockaddr *)&sockaddr, sizeof(sockaddr)) == -1 || listen(sock, -1) == -1) {
    shutdown(sock, SHUT_RDWR);
    close(sock);
    return -1;
  }
  fcntl(sock, F_SETFD, FD_CLOEXEC);
  return sock;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diediedie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: Goodbye cruel world...


assistant: ```c
void diediedie(int sig) {
  puts("Goodbye cruel world...\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<diediedie>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: Goodbye cruel world...


assistant: ```c
void diediedie(int sig) {
  puts("Goodbye cruel world...\n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<diediedie>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: Goodbye cruel world...


assistant: ```c
void diediedie(int sig) {
  puts("Goodbye cruel world...\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<diediedie>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: Goodbye cruel world...


assistant: ```c
void diediedie(int sig) {
  puts("Goodbye cruel world...\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L2:
  nop
  jmp    L2
```

assistant: ```c
int main() {
def:
  goto abc;
abc:
  goto def;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
L2:
  jmp    L2
```

assistant: ```c
int main() {
def:
  goto abc;
abc:
  goto def;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
int main() {
def:
  goto abc;
abc:
  goto def;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L3:
  jmp    L3
```

assistant: ```c
int main() {
def:
  goto abc;
abc:
  goto def;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calc_response_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    $0x1234567,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  lea    -0x90(%rbp),%rax
  add    $0x4,%rax
  mov    $0x89abcdef,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  lea    -0x90(%rbp),%rax
  add    $0x8,%rax
  mov    $0xfedcba98,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  lea    -0x90(%rbp),%rax
  add    $0xc,%rax
  mov    $0x76543210,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  lea    -0x90(%rbp),%rax
  add    $0x10,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  lea    -0x90(%rbp),%rax
  add    $0x14,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <put32_be@plt>
  mov    -0xd0(%rbp),%rcx
  lea    -0x90(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <call_hash@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calc_response@plt>
  movl   $0x0,-0xb4(%rbp)
  jmp    L5
L7:
  mov    -0xb4(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  shr    $0x4,%al
  mov    %al,-0xb6(%rbp)
  mov    -0xb4(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  and    $0xf,%eax
  mov    %al,-0xb5(%rbp)
  cmpb   $0x9,-0xb6(%rbp)
  jg     L24
  movzbl -0xb6(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  jmp    L34
L24:
  movzbl -0xb6(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%edx
L34:
  mov    -0xb4(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rcx
  mov    -0xc8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  cmpb   $0x9,-0xb5(%rbp)
  jg     L44
  movzbl -0xb5(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  jmp    L27
L44:
  movzbl -0xb5(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%edx
L27:
  mov    -0xb4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0xc8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0xb4(%rbp)
L5:
  cmpl   $0xf,-0xb4(%rbp)
  jle    L7
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void calc_response_string(char *result, char *challenge) {
  char field[128];
  char zres[20];
  int i;
  put32_be(field, 0x01234567);
  put32_be(field + 4, 0x89abcdef);
  put32_be(field + 8, 0xfedcba98);
  put32_be(field + 12, 0x76543210);
  put32_be(field + 16, 0x00000000);
  put32_be(field + 20, 0x00000000);
  call_hash(field, challenge, 64);
  calc_response(zres, field);
  for (i = 0; i < 16; i++) {
    char a, b;
    a = (zres[i] >> 4) & 0x0f;
    b = zres[i] & 0x0f;
    result[i * 2] = ((a < 10) ? (a + 48) : (a + 87)) & 0xff;
    result[i * 2 + 1] = ((b < 10) ? (b + 48) : (b + 87)) & 0xff;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calc_response_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    $0x1234567,%esi
  mov    %rbp,%rdi
  call   <put32_be@plt>
  lea    0x24(%rsp),%rdi
  mov    $0x89abcdef,%esi
  call   <put32_be@plt>
  lea    0x28(%rsp),%rdi
  mov    $0xfedcba98,%esi
  call   <put32_be@plt>
  lea    0x2c(%rsp),%rdi
  mov    $0x76543210,%esi
  call   <put32_be@plt>
  lea    0x30(%rsp),%rdi
  mov    $0x0,%esi
  call   <put32_be@plt>
  lea    0x34(%rsp),%rdi
  mov    $0x0,%esi
  call   <put32_be@plt>
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <calc_response@plt>
  mov    $0x0,%edx
L7:
  movzbl (%rsp,%rdx,1),%eax
  mov    %eax,%esi
  shr    $0x4,%sil
  and    $0xf,%eax
  lea    0x30(%rsi),%edi
  lea    0x57(%rsi),%ecx
  cmp    $0x9,%sil
  cmovle %edi,%ecx
  mov    %cl,(%rbx,%rdx,2)
  lea    0x30(%rax),%esi
  lea    0x57(%rax),%ecx
  cmp    $0x9,%al
  mov    %esi,%eax
  cmovg  %ecx,%eax
  mov    %al,0x1(%rbx,%rdx,2)
  add    $0x1,%rdx
  cmp    $0x10,%rdx
  jne    L7
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void calc_response_string(char *result, char *challenge) {
  char field[128];
  char zres[20];
  int i;
  put32_be(field, 0x01234567);
  put32_be(field + 4, 0x89abcdef);
  put32_be(field + 8, 0xfedcba98);
  put32_be(field + 12, 0x76543210);
  put32_be(field + 16, 0x00000000);
  put32_be(field + 20, 0x00000000);
  call_hash(field, challenge, 64);
  calc_response(zres, field);
  for (i = 0; i < 16; i++) {
    char a, b;
    a = (zres[i] >> 4) & 0x0f;
    b = zres[i] & 0x0f;
    result[i * 2] = ((a < 10) ? (a + 48) : (a + 87)) & 0xff;
    result[i * 2 + 1] = ((b < 10) ? (b + 48) : (b + 87)) & 0xff;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc_response_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1234567,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%rdi
  call   <put32_be@plt>
  lea    0x24(%rsp),%rdi
  mov    $0x89abcdef,%esi
  call   <put32_be@plt>
  lea    0x28(%rsp),%rdi
  mov    $0xfedcba98,%esi
  call   <put32_be@plt>
  lea    0x2c(%rsp),%rdi
  mov    $0x76543210,%esi
  call   <put32_be@plt>
  lea    0x30(%rsp),%rdi
  xor    %esi,%esi
  call   <put32_be@plt>
  lea    0x34(%rsp),%rdi
  xor    %esi,%esi
  call   <put32_be@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <call_hash@plt>
  mov    %rsp,%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <calc_response@plt>
  xor    %edx,%edx
  nop
L12:
  movzbl 0x0(%rbp,%rdx,1),%eax
  mov    %eax,%esi
  and    $0xf,%eax
  shr    $0x4,%sil
  cmp    $0x9,%sil
  lea    0x30(%rsi),%edi
  lea    0x57(%rsi),%ecx
  cmovbe %edi,%ecx
  lea    0x30(%rax),%esi
  cmp    $0x9,%al
  mov    %cl,(%rbx,%rdx,2)
  lea    0x57(%rax),%ecx
  mov    %esi,%eax
  cmovg  %ecx,%eax
  mov    %al,0x1(%rbx,%rdx,2)
  add    $0x1,%rdx
  cmp    $0x10,%rdx
  jne    L12
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void calc_response_string(char *result, char *challenge) {
  char field[128];
  char zres[20];
  int i;
  put32_be(field, 0x01234567);
  put32_be(field + 4, 0x89abcdef);
  put32_be(field + 8, 0xfedcba98);
  put32_be(field + 12, 0x76543210);
  put32_be(field + 16, 0x00000000);
  put32_be(field + 20, 0x00000000);
  call_hash(field, challenge, 64);
  calc_response(zres, field);
  for (i = 0; i < 16; i++) {
    char a, b;
    a = (zres[i] >> 4) & 0x0f;
    b = zres[i] & 0x0f;
    result[i * 2] = ((a < 10) ? (a + 48) : (a + 87)) & 0xff;
    result[i * 2 + 1] = ((b < 10) ? (b + 48) : (b + 87)) & 0xff;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_response_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x1234567,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rdi
  call   <put32_be@plt>
  lea    0x24(%rsp),%rdi
  mov    $0x89abcdef,%esi
  call   <put32_be@plt>
  lea    0x28(%rsp),%rdi
  mov    $0xfedcba98,%esi
  call   <put32_be@plt>
  lea    0x2c(%rsp),%rdi
  mov    $0x76543210,%esi
  call   <put32_be@plt>
  lea    0x30(%rsp),%rdi
  xor    %esi,%esi
  call   <put32_be@plt>
  lea    0x34(%rsp),%rdi
  xor    %esi,%esi
  call   <put32_be@plt>
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <calc_response@plt>
  movdqa (%rsp),%xmm3
  movdqa D36(%rip),%xmm0
  movdqa D5(%rip),%xmm6
  movdqa D13(%rip),%xmm2
  psrlw  $0x4,%xmm3
  movdqa D16(%rip),%xmm4
  pand   %xmm0,%xmm3
  pand   (%rsp),%xmm0
  movdqa %xmm3,%xmm1
  movdqa %xmm3,%xmm7
  movdqa %xmm3,%xmm5
  pminub %xmm6,%xmm1
  paddb  %xmm2,%xmm7
  pcmpeqb %xmm3,%xmm1
  paddb  %xmm4,%xmm5
  paddb  %xmm0,%xmm2
  paddb  %xmm0,%xmm4
  pcmpgtb %xmm6,%xmm0
  pand   %xmm1,%xmm5
  pandn  %xmm7,%xmm1
  pand   %xmm0,%xmm2
  por    %xmm5,%xmm1
  pandn  %xmm4,%xmm0
  por    %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  punpcklbw %xmm0,%xmm2
  punpckhbw %xmm0,%xmm1
  movups %xmm2,(%rbx)
  movups %xmm1,0x10(%rbx)
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D36
datatype: byte[16]
name: parse_data
arguments: data_tag: D5
datatype: byte[16]
name: parse_data
arguments: data_tag: D13
datatype: byte[16]
name: parse_data
arguments: data_tag: D16
datatype: byte[16]

tool: {"D36": [0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f,0x0f]}

tool: {"D5": [0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09]}

tool: {"D13": [0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57,0x57]}

tool: {"D16": [0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30]}

assistant: ```c
void calc_response_string(char *result, char *challenge) {
  char field[128];
  char zres[20];
  int i;
  put32_be(field, 0x01234567);
  put32_be(field + 4, 0x89abcdef);
  put32_be(field + 8, 0xfedcba98);
  put32_be(field + 12, 0x76543210);
  put32_be(field + 16, 0x00000000);
  put32_be(field + 20, 0x00000000);
  call_hash(field, challenge, 64);
  calc_response(zres, field);
  for (i = 0; i < 16; i++) {
    char a, b;
    a = (zres[i] >> 4) & 0x0f;
    b = zres[i] & 0x0f;
    result[i * 2] = ((a < 10) ? (a + 48) : (a + 87)) & 0xff;
    result[i * 2 + 1] = ((b < 10) ? (b + 48) : (b + 87)) & 0xff;
  }
}
```