ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <readUI@plt>
  mov    (%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <writeDO@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <writeDO@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <writeUO@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <writeUO@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    $0x3,%edi
  mov    $0x32,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <writeUO@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: Resistance Input 1 : %i


assistant: ```c
int main(int argc, char *argv[]) {
  signed long retvalue;
  int i;
  readUI(2, 1, 0, &retvalue);
  printf("Resistance Input 1 : %i\n", retvalue);
  sleep(2);
  writeDO(1, 1, 0);
  sleep(2);
  writeDO(1, 1, 0);
  sleep(2);
  writeUO(3, 1, 0, 0);
  sleep(2);
  writeUO(3, 1, 0, 1);
  sleep(2);
  writeUO(3, 1, 1, 50);
  sleep(2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<drv_RB_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <drv_RB_outw@plt>
  mov    $0x3c,%edi
  call   <ndelay@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <drv_RB_outw@plt>
  mov    -0x8(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%edi
  call   <ndelay@plt>
  nop
  leave
  ret
```

assistant: ```c
void drv_RB_command(const unsigned char cmd, const int delay) {
  drv_RB_outw(0x0100 | cmd);
  ndelay(60);
  drv_RB_outw(cmd);
  ndelay(delay * 1000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<drv_RB_command>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  movzbl %dil,%ebp
  mov    %ebp,%edi
  call   <drv_RB_outw@plt>
  mov    $0x3c,%edi
  call   <ndelay@plt>
  mov    %ebp,%edi
  call   <drv_RB_outw@plt>
  imul   $0x3e8,%ebx,%edi
  call   <ndelay@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void drv_RB_command(const unsigned char cmd, const int delay) {
  drv_RB_outw(0x0100 | cmd);
  ndelay(60);
  drv_RB_outw(cmd);
  ndelay(delay * 1000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<drv_RB_command>:
  endbr64
  push   %rbp
  movzbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <drv_RB_outw@plt>
  mov    $0x3c,%edi
  call   <ndelay@plt>
  mov    %ebp,%edi
  call   <drv_RB_outw@plt>
  imul   $0x3e8,%ebx,%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <ndelay@plt>
```

assistant: ```c
void drv_RB_command(const unsigned char cmd, const int delay) {
  drv_RB_outw(0x0100 | cmd);
  ndelay(60);
  drv_RB_outw(cmd);
  ndelay(delay * 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drv_RB_command>:
  endbr64
  push   %rbp
  movzbl %dil,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <drv_RB_outw@plt>
  mov    $0x3c,%edi
  call   <ndelay@plt>
  mov    %ebp,%edi
  call   <drv_RB_outw@plt>
  imul   $0x3e8,%ebx,%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <ndelay@plt>
```

assistant: ```c
void drv_RB_command(const unsigned char cmd, const int delay) {
  drv_RB_outw(0x0100 | cmd);
  ndelay(60);
  drv_RB_outw(cmd);
  ndelay(delay * 1000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L13
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jle    L13
  fildl  -0x28(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x44(%rbp)
  fildl  -0x44(%rbp)
  fadd   %st(0),%st
  faddp  %st,%st(1)
  fstpl  -0x20(%rbp)
L13:
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double subtract(time_t time1, time_t time0) {
  if (!((time_t)-1 < 0))
    return time1 - time0;
  else {
    uintmax_t dt = (uintmax_t)time1 - (uintmax_t)time0;
    double delta = dt;
    if (UINTMAX_MAX / 2 < INTMAX_MAX) {
      uintmax_t hdt = dt / 2;
      time_t ht1 = time1 / 2;
      time_t ht0 = time0 / 2;
      time_t dht = ht1 - ht0;
      if (2 < dht - hdt + 1) {
        delta = dt + 2.0L * (UINTMAX_MAX - UINTMAX_MAX / 2);
      }
    }
    return delta;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subtract>:
  endbr64
  mov    %edi,%r9d
  sub    %esi,%r9d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r9d,%xmm0
  mov    D4(%rip),%rax
  mov    (%rax),%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  mov    D7(%rip),%rdx
  cmp    (%rdx),%eax
  jge    L11
  mov    %rdi,%rdx
  shr    $0x3f,%rdx
  add    %rdi,%rdx
  sar    %rdx
  mov    %rsi,%rcx
  shr    $0x3f,%rcx
  add    %rsi,%rcx
  sar    %rcx
  sub    %rcx,%rdx
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  add    %r9d,%ecx
  sar    %ecx
  movslq %ecx,%rcx
  sub    %rcx,%rdx
  cmp    $0x1,%rdx
  jle    L11
  sub    %eax,%r8d
  mov    %r8d,-0x10(%rsp)
  fildl  -0x10(%rsp)
  fadd   %st(0),%st
  mov    %r9d,-0x10(%rsp)
  fildl  -0x10(%rsp)
  faddp  %st,%st(1)
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
L11:
  ret
```

assistant: ```c
double subtract(time_t time1, time_t time0) {
  if (!((time_t)-1 < 0))
    return time1 - time0;
  else {
    uintmax_t dt = (uintmax_t)time1 - (uintmax_t)time0;
    double delta = dt;
    if (UINTMAX_MAX / 2 < INTMAX_MAX) {
      uintmax_t hdt = dt / 2;
      time_t ht1 = time1 / 2;
      time_t ht0 = time0 / 2;
      time_t dht = ht1 - ht0;
      if (2 < dht - hdt + 1) {
        delta = dt + 2.0L * (UINTMAX_MAX - UINTMAX_MAX / 2);
      }
    }
    return delta;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<subtract>:
  endbr64
  mov    D1(%rip),%rax
  mov    %edi,%r9d
  mov    D11(%rip),%rdx
  pxor   %xmm0,%xmm0
  sub    %esi,%r9d
  mov    (%rax),%r8d
  cvtsi2sd %r9d,%xmm0
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  cmp    (%rdx),%eax
  jge    L14
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  shr    $0x3f,%rdx
  shr    $0x3f,%rcx
  add    %rdi,%rdx
  add    %rsi,%rcx
  sar    %rcx
  sar    %rdx
  sub    %rcx,%rdx
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  add    %r9d,%ecx
  sar    %ecx
  movslq %ecx,%rcx
  sub    %rcx,%rdx
  cmp    $0x1,%rdx
  jle    L14
  sub    %eax,%r8d
  mov    %r8d,-0x10(%rsp)
  fildl  -0x10(%rsp)
  mov    %r9d,-0x10(%rsp)
  fadd   %st(0),%st
  fildl  -0x10(%rsp)
  faddp  %st,%st(1)
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
L14:
  ret
```

assistant: ```c
double subtract(time_t time1, time_t time0) {
  if (!((time_t)-1 < 0))
    return time1 - time0;
  else {
    uintmax_t dt = (uintmax_t)time1 - (uintmax_t)time0;
    double delta = dt;
    if (UINTMAX_MAX / 2 < INTMAX_MAX) {
      uintmax_t hdt = dt / 2;
      time_t ht1 = time1 / 2;
      time_t ht0 = time0 / 2;
      time_t dht = ht1 - ht0;
      if (2 < dht - hdt + 1) {
        delta = dt + 2.0L * (UINTMAX_MAX - UINTMAX_MAX / 2);
      }
    }
    return delta;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<subtract>:
  endbr64
  mov    D13(%rip),%rax
  mov    %edi,%r9d
  mov    D7(%rip),%rdx
  pxor   %xmm0,%xmm0
  sub    %esi,%r9d
  mov    (%rax),%r8d
  cvtsi2sd %r9d,%xmm0
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  cmp    (%rdx),%eax
  jge    L10
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  shr    $0x3f,%rdx
  shr    $0x3f,%rcx
  add    %rdi,%rdx
  add    %rsi,%rcx
  sar    %rcx
  sar    %rdx
  sub    %rcx,%rdx
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  add    %r9d,%ecx
  sar    %ecx
  movslq %ecx,%rcx
  sub    %rcx,%rdx
  cmp    $0x1,%rdx
  jle    L10
  sub    %eax,%r8d
  mov    %r8d,-0x10(%rsp)
  fildl  -0x10(%rsp)
  mov    %r9d,-0x10(%rsp)
  fadd   %st(0),%st
  fildl  -0x10(%rsp)
  faddp  %st,%st(1)
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
L10:
  ret
```

assistant: ```c
double subtract(time_t time1, time_t time0) {
  if (!((time_t)-1 < 0))
    return time1 - time0;
  else {
    uintmax_t dt = (uintmax_t)time1 - (uintmax_t)time0;
    double delta = dt;
    if (UINTMAX_MAX / 2 < INTMAX_MAX) {
      uintmax_t hdt = dt / 2;
      time_t ht1 = time1 / 2;
      time_t ht0 = time0 / 2;
      time_t dht = ht1 - ht0;
      if (2 < dht - hdt + 1) {
        delta = dt + 2.0L * (UINTMAX_MAX - UINTMAX_MAX / 2);
      }
    }
    return delta;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HighSpeed_Read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  mov    $0x0,%eax
  call   <CE_Low@plt>
  mov    $0xb,%edi
  call   <Send_Byte@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <Send_Byte@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <Send_Byte@plt>
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <Send_Byte@plt>
  mov    $0xff,%edi
  call   <Send_Byte@plt>
  mov    $0x0,%eax
  call   <Get_Byte@plt>
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  call   <CE_High@plt>
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char HighSpeed_Read(unsigned long Dst) {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x0B);
  Send_Byte(((Dst & 0xFFFFFF) >> 16));
  Send_Byte(((Dst & 0xFFFF) >> 8));
  Send_Byte(Dst & 0xFF);
  Send_Byte(0xFF);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: What is the c source code of the assembly code below:

```asm
<HighSpeed_Read>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <CE_Low@plt>
  mov    $0xb,%edi
  call   <Send_Byte@plt>
  mov    %rbx,%rdi
  shr    $0x10,%rdi
  movzbl %dil,%edi
  call   <Send_Byte@plt>
  movzbl %bh,%edi
  call   <Send_Byte@plt>
  movzbl %bl,%edi
  call   <Send_Byte@plt>
  mov    $0xff,%edi
  call   <Send_Byte@plt>
  mov    $0x0,%eax
  call   <Get_Byte@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <CE_High@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned char HighSpeed_Read(unsigned long Dst) {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x0B);
  Send_Byte(((Dst & 0xFFFFFF) >> 16));
  Send_Byte(((Dst & 0xFFFF) >> 8));
  Send_Byte(Dst & 0xFF);
  Send_Byte(0xFF);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HighSpeed_Read>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <CE_Low@plt>
  mov    $0xb,%edi
  call   <Send_Byte@plt>
  mov    %rbx,%rdi
  shr    $0x10,%rdi
  movzbl %dil,%edi
  call   <Send_Byte@plt>
  movzbl %bh,%edi
  call   <Send_Byte@plt>
  movzbl %bl,%edi
  call   <Send_Byte@plt>
  mov    $0xff,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  call   <Get_Byte@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <CE_High@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned char HighSpeed_Read(unsigned long Dst) {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x0B);
  Send_Byte(((Dst & 0xFFFFFF) >> 16));
  Send_Byte(((Dst & 0xFFFF) >> 8));
  Send_Byte(Dst & 0xFF);
  Send_Byte(0xFF);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HighSpeed_Read>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <CE_Low@plt>
  mov    $0xb,%edi
  call   <Send_Byte@plt>
  mov    %rbx,%rdi
  shr    $0x10,%rdi
  movzbl %dil,%edi
  call   <Send_Byte@plt>
  movzbl %bh,%edi
  call   <Send_Byte@plt>
  movzbl %bl,%edi
  call   <Send_Byte@plt>
  mov    $0xff,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  call   <Get_Byte@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <CE_High@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned char HighSpeed_Read(unsigned long Dst) {
  unsigned char byte = 0;
  CE_Low();
  Send_Byte(0x0B);
  Send_Byte(((Dst & 0xFFFFFF) >> 16));
  Send_Byte(((Dst & 0xFFFF) >> 8));
  Send_Byte(Dst & 0xFF);
  Send_Byte(0xFF);
  byte = Get_Byte();
  CE_High();
  return byte;
}
```
user: What is the c source code of the assembly code below:

```asm
<cellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movsbq -0x1c(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movsbl -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    $0x0,%eax
  jmp    L17
L22:
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x3(%rbp)
  movzbl -0x3(%rbp),%eax
  mov    %al,-0x4(%rbp)
  movb   $0x1,-0x2(%rbp)
  jmp    L49
L60:
  movsbq -0x1c(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  movsbl -0x20(%rbp),%eax
  movsbl -0x2(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  movzbl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x4(%rbp)
  jmp    L44
L27:
  movzbl -0x2(%rbp),%eax
  mov    %al,-0x3(%rbp)
L44:
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L49:
  cmpb   $0x9,-0x2(%rbp)
  jle    L60
  cmpb   $0x8,-0x4(%rbp)
  jne    L56
  movsbq -0x1c(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movsbl -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    (%rcx,%rax,1),%rdx
  movzbl -0x3(%rbp),%eax
  mov    %al,(%rdx)
  movb   $0x1,-0x1(%rbp)
L56:
  movsbl -0x1(%rbp),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int cellsort(char grid[9][9][10], char m, char n) {
  if (grid[m][n][0])
    return 0;
  char i, j, k, f = 0;
  for (i = j = 0, k = 1; k < 10; ++k)
    if (!grid[m][n][k])
      ++i;
    else
      j = k;
  if (i == 8)
    grid[m][n][0] = j, f = 1;
  return f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cellsort>:
  endbr64
  movsbq %sil,%rsi
  imul   $0x5a,%rsi,%rsi
  add    %rsi,%rdi
  movsbq %dl,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,2),%r8
  movzbl (%r8),%esi
  mov    $0x0,%eax
  test   %sil,%sil
  jne    L16
  mov    %r8,%rcx
  mov    %esi,%edi
  mov    %esi,%edx
  mov    $0x1,%eax
  jmp    L32
L21:
  mov    %eax,%edi
L51:
  add    $0x1,%rax
  cmp    $0xa,%rax
  je     L44
L32:
  cmpb   $0x0,(%rcx,%rax,1)
  jne    L21
  add    $0x1,%edx
  jmp    L51
L44:
  cmp    $0x8,%dl
  je     L60
L42:
  movsbl %sil,%eax
L16:
  ret
L60:
  mov    %dil,(%r8)
  mov    $0x1,%esi
  jmp    L42
```

assistant: ```c
int cellsort(char grid[9][9][10], char m, char n) {
  if (grid[m][n][0])
    return 0;
  char i, j, k, f = 0;
  for (i = j = 0, k = 1; k < 10; ++k)
    if (!grid[m][n][k])
      ++i;
    else
      j = k;
  if (i == 8)
    grid[m][n][0] = j, f = 1;
  return f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cellsort>:
  endbr64
  movsbq %sil,%rsi
  movsbq %dl,%rdx
  imul   $0x5a,%rsi,%rsi
  lea    (%rdx,%rdx,4),%rax
  lea    (%rsi,%rax,2),%rax
  add    %rax,%rdi
  xor    %eax,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  xor    %ecx,%ecx
  mov    $0x1,%eax
  jmp    L16
  nopl   (%rax)
L49:
  add    $0x1,%rax
  add    $0x1,%edx
  cmp    $0xa,%rax
  je     L13
L16:
  cmpb   $0x0,(%rdi,%rax,1)
  je     L49
  mov    %eax,%ecx
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L16
L13:
  xor    %eax,%eax
  cmp    $0x8,%dl
  je     L44
L12:
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %cl,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cellsort(char grid[9][9][10], char m, char n) {
  if (grid[m][n][0])
    return 0;
  char i, j, k, f = 0;
  for (i = j = 0, k = 1; k < 10; ++k)
    if (!grid[m][n][k])
      ++i;
    else
      j = k;
  if (i == 8)
    grid[m][n][0] = j, f = 1;
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cellsort>:
  endbr64
  movsbq %sil,%rsi
  movsbq %dl,%rax
  movsbq %dl,%rdx
  xor    %r8d,%r8d
  imul   $0x5a,%rsi,%rsi
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdi,%rsi,1),%rcx
  lea    (%rcx,%rdx,2),%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L52
  lea    (%rax,%rax,4),%rsi
  movzbl 0x1(%rcx,%rsi,2),%esi
  test   %sil,%sil
  je     L91
  lea    (%rax,%rax,4),%r8
  mov    $0x1,%esi
  cmpb   $0x0,0x2(%rcx,%r8,2)
  jne    L75
L103:
  lea    (%rax,%rax,4),%r8
  add    $0x1,%edx
  cmpb   $0x0,0x3(%rcx,%r8,2)
  jne    L167
L95:
  lea    (%rax,%rax,4),%r8
  add    $0x1,%edx
  cmpb   $0x0,0x4(%rcx,%r8,2)
  jne    L30
L32:
  lea    (%rax,%rax,4),%r8
  add    $0x1,%edx
  cmpb   $0x0,0x5(%rcx,%r8,2)
  jne    L145
L189:
  lea    (%rax,%rax,4),%r8
  add    $0x1,%edx
  cmpb   $0x0,0x6(%rcx,%r8,2)
  jne    L138
L62:
  lea    (%rax,%rax,4),%r8
  add    $0x1,%edx
  cmpb   $0x0,0x7(%rcx,%r8,2)
  jne    L199
L154:
  lea    (%rax,%rax,4),%rax
  add    $0x1,%edx
  lea    (%rcx,%rax,2),%rax
  cmpb   $0x0,0x8(%rax)
  jne    L190
L119:
  add    $0x1,%edx
  cmpb   $0x0,0x9(%rax)
  je     L112
  mov    $0x9,%esi
  xor    %r8d,%r8d
  cmp    $0x8,%dl
  je     L66
L52:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L91:
  lea    (%rax,%rax,4),%r8
  mov    $0x1,%edx
  cmpb   $0x0,0x2(%rcx,%r8,2)
  je     L103
L75:
  lea    (%rax,%rax,4),%r8
  mov    $0x2,%esi
  cmpb   $0x0,0x3(%rcx,%r8,2)
  je     L95
L167:
  lea    (%rax,%rax,4),%r8
  mov    $0x3,%esi
  cmpb   $0x0,0x4(%rcx,%r8,2)
  je     L32
L30:
  lea    (%rax,%rax,4),%r8
  mov    $0x4,%esi
  cmpb   $0x0,0x5(%rcx,%r8,2)
  je     L189
L145:
  lea    (%rax,%rax,4),%r8
  mov    $0x5,%esi
  cmpb   $0x0,0x6(%rcx,%r8,2)
  je     L62
L138:
  lea    (%rax,%rax,4),%r8
  mov    $0x6,%esi
  cmpb   $0x0,0x7(%rcx,%r8,2)
  je     L154
L199:
  lea    (%rax,%rax,4),%rax
  mov    $0x7,%esi
  lea    (%rcx,%rax,2),%rax
  cmpb   $0x0,0x8(%rax)
  je     L119
L190:
  cmpb   $0x0,0x9(%rax)
  jne    L114
  mov    $0x8,%esi
L112:
  add    $0x1,%edx
  xor    %r8d,%r8d
  cmp    $0x8,%dl
  jne    L52
L66:
  mov    $0x1,%r8d
  mov    %sil,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L114:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cellsort(char grid[9][9][10], char m, char n) {
  if (grid[m][n][0])
    return 0;
  char i, j, k, f = 0;
  for (i = j = 0, k = 1; k < 10; ++k)
    if (!grid[m][n][k])
      ++i;
    else
      j = k;
  if (i == 8)
    grid[m][n][0] = j, f = 1;
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ECAPCounterControl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  add    $0x2a,%eax
  mov    %eax,%eax
  movzwl (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x2a,%edx
  mov    %edx,%edx
  or     $0x10,%eax
  mov    %ax,(%rdx)
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  add    $0x2a,%eax
  mov    %eax,%eax
  movzwl (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x2a,%edx
  mov    %edx,%edx
  and    $0xffffffef,%eax
  mov    %ax,(%rdx)
L11:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ECAPCounterControl(unsigned int baseAdd, unsigned int flag) {
  if (flag) {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) |= (0x0010u);
  } else {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) &= ~(0x0010u);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ECAPCounterControl>:
  endbr64
  test   %esi,%esi
  je     L6
  movzwl 0x2a(%edi),%eax
  or     $0x10,%eax
  mov    %ax,0x2a(%edi)
  ret
L6:
  movzwl 0x2a(%edi),%eax
  and    $0xffffffef,%eax
  mov    %ax,0x2a(%edi)
  ret
```

assistant: ```c
void ECAPCounterControl(unsigned int baseAdd, unsigned int flag) {
  if (flag) {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) |= (0x0010u);
  } else {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) &= ~(0x0010u);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ECAPCounterControl>:
  endbr64
  movzwl 0x2a(%edi),%eax
  test   %esi,%esi
  je     L0
  or     $0x10,%eax
  mov    %ax,0x2a(%edi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  and    $0xffffffef,%eax
  mov    %ax,0x2a(%edi)
  ret
```

assistant: ```c
void ECAPCounterControl(unsigned int baseAdd, unsigned int flag) {
  if (flag) {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) |= (0x0010u);
  } else {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) &= ~(0x0010u);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ECAPCounterControl>:
  endbr64
  movzwl 0x2a(%edi),%eax
  test   %esi,%esi
  je     L3
  or     $0x10,%eax
  mov    %ax,0x2a(%edi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  and    $0xffffffef,%eax
  mov    %ax,0x2a(%edi)
  ret
```

assistant: ```c
void ECAPCounterControl(unsigned int baseAdd, unsigned int flag) {
  if (flag) {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) |= (0x0010u);
  } else {
    (*((volatile unsigned short *)(baseAdd + (0x2A)))) &= ~(0x0010u);
  }
}
```