ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <pac_nacepin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string

tool: D5: Vavedi broi bidoni c nacepin :


tool: D16:  %d

assistant: ```c
int main() {
  int n;
  printf("Vavedi broi bidoni c nacepin :\n");
  scanf(" %d", &n);
  pac_nacepin(n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <pac_nacepin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string

tool: D2: Vavedi broi bidoni c nacepin :


tool: D8:  %d

assistant: ```c
int main() {
  int n;
  printf("Vavedi broi bidoni c nacepin :\n");
  scanf(" %d", &n);
  pac_nacepin(n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <pac_nacepin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string

tool: D7: Vavedi broi bidoni c nacepin :


tool: D13:  %d

assistant: ```c
int main() {
  int n;
  printf("Vavedi broi bidoni c nacepin :\n");
  scanf(" %d", &n);
  pac_nacepin(n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tamanho>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  D11(%rip),%xmm1
  divss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: f64
name: unpack_data
arguments: data_tag: D11
data_type: byte[4]

tool: D7: 1024

tool: {"D11": [0x00,0x00,0x80,0x44]}

assistant: ```c
void tamanho(int b, float *kb, float *mb) {
  *kb = b / 1024.0;
  *mb = *kb / 1024;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tamanho>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D19(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  mulss  D1(%rip),%xmm0
  movss  %xmm0,(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: byte[8]
name: retrieve_data
arguments: label: D1
type_infered: byte[4]

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: {"D1": [0x00,0x00,0x80,0x3a]}

assistant: ```c
void tamanho(int b, float *kb, float *mb) {
  *kb = b / 1024.0;
  *mb = *kb / 1024;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tamanho>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D15(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  mulss  D13(%rip),%xmm0
  movss  %xmm0,(%rdx)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type: byte[8]
name: unpack_data
arguments: tag: D13
type: byte[4]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: {"D13": [0x00,0x00,0x80,0x3a]}

assistant: ```c
void tamanho(int b, float *kb, float *mb) {
  *kb = b / 1024.0;
  *mb = *kb / 1024;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tamanho>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  mulss  D19(%rip),%xmm0
  movss  %xmm0,(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D19
data_type: byte[4]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: {"D19": [0x00,0x00,0x80,0x3a]}

assistant: ```c
void tamanho(int b, float *kb, float *mb) {
  *kb = b / 1024.0;
  *mb = *kb / 1024;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1f4,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0xfb8(%rbp)
  jmp    L12
L28:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb8(%rbp),%edx
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfb8(%rbp)
L12:
  mov    D9(%rip),%eax
  cmp    %eax,-0xfb8(%rbp)
  jl     L28
  mov    -0xee8(%rbp),%edx
  mov    D9(%rip),%eax
  sub    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,-0xfb4(%rbp)
  mov    -0xfb4(%rbp),%edx
  mov    -0xfb8(%rbp),%eax
  add    %edx,%eax
  cltd
  shr    $0x19,%edx
  add    %edx,%eax
  and    $0x7f,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  static int array_size = 1000;
  int arr[1000] = {0};
  int i;
  for (i = 0; i < array_size; i++) {
    arr[i] = i;
  }
  int sum = arr[50] + arr[array_size - 1];
  return (sum + i) % 128;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
L8:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L8
  mov    0xf9c(%rsp),%eax
  add    0xc8(%rsp),%eax
  add    $0x3e8,%eax
  cltd
  shr    $0x19,%edx
  add    %edx,%eax
  and    $0x7f,%eax
  sub    %edx,%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xfb8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  static int array_size = 1000;
  int arr[1000] = {0};
  int i;
  for (i = 0; i < array_size; i++) {
    arr[i] = i;
  }
  int sum = arr[50] + arr[array_size - 1];
  return (sum + i) % 128;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x1f4,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L0:
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x3e8,%rax
  jne    L0
  mov    0xf9c(%rsp),%eax
  add    0xc8(%rsp),%eax
  add    $0x3e8,%eax
  cltd
  shr    $0x19,%edx
  add    %edx,%eax
  and    $0x7f,%eax
  sub    %edx,%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xfb8,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  static int array_size = 1000;
  int arr[1000] = {0};
  int i;
  for (i = 0; i < array_size; i++) {
    arr[i] = i;
  }
  int sum = arr[50] + arr[array_size - 1];
  return (sum + i) % 128;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x1f4,%ecx
  movdqa D10(%rip),%xmm0
  movdqa D19(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0xfa0(%rsp),%rdx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rax
  nopl   0x0(%rax)
L0:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L0
  mov    0xf9c(%rsp),%eax
  add    0xc8(%rsp),%eax
  add    $0x3e8,%eax
  cltd
  shr    $0x19,%edx
  add    %edx,%eax
  and    $0x7f,%eax
  sub    %edx,%eax
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xfb8,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_infered: byte[16]
name: retrieve_data
arguments: label: D19
type_infered: byte[16]

tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D19": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int main() {
  static int array_size = 1000;
  int arr[1000] = {0};
  int i;
  for (i = 0; i < array_size; i++) {
    arr[i] = i;
  }
  int sum = arr[50] + arr[array_size - 1];
  return (sum + i) % 128;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ptm_util_extract_ipv6_pkt_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    0x4(%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ptm_util_extract_ipv6_pkt_info(void *data, int *ifindex, struct in6_addr *ip6_addr) {
  struct in6_pktinfo *pi6 = (struct in6_pktinfo *)data;
  *ip6_addr = pi6->ipi6_addr;
  *ifindex = pi6->ipi6_ifindex;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ptm_util_extract_ipv6_pkt_info>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rdx)
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ptm_util_extract_ipv6_pkt_info(void *data, int *ifindex, struct in6_addr *ip6_addr) {
  struct in6_pktinfo *pi6 = (struct in6_pktinfo *)data;
  *ip6_addr = pi6->ipi6_addr;
  *ifindex = pi6->ipi6_ifindex;
}
```
user: What is the c source code of the assembly code below:

```asm
<ptm_util_extract_ipv6_pkt_info>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rdx)
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ptm_util_extract_ipv6_pkt_info(void *data, int *ifindex, struct in6_addr *ip6_addr) {
  struct in6_pktinfo *pi6 = (struct in6_pktinfo *)data;
  *ip6_addr = pi6->ipi6_addr;
  *ifindex = pi6->ipi6_ifindex;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ptm_util_extract_ipv6_pkt_info>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rdx)
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void ptm_util_extract_ipv6_pkt_info(void *data, int *ifindex, struct in6_addr *ip6_addr) {
  struct in6_pktinfo *pi6 = (struct in6_pktinfo *)data;
  *ip6_addr = pi6->ipi6_addr;
  *ifindex = pi6->ipi6_ifindex;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_domain_name_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xc0,%eax
  cmp    $0xc0,%eax
  jne    L6
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  and    $0x3f00,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L6:
  cmpl   $0x0,-0x10(%rbp)
  je     L23
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x1,%rax
  add    %rax,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calc_domain_name_size(unsigned char *buf, int buflen, int offset) {
  unsigned char *p = buf + offset;
  int len = 0;
  while (*p) {
    if ((*p & 0xC0) == 0xC0) {
      int newoffset = 0;
      newoffset |= (*p++ & 0x3F) << 8;
      newoffset |= *p;
      p = buf + newoffset;
    } else {
      if (len) {
        len += 1;
      }
      len += *p;
      p += *p + 1;
    }
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_domain_name_size>:
  endbr64
  movslq %edx,%rdx
  add    %rdi,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L5
  mov    $0x0,%esi
  jmp    L7
L27:
  shl    $0x8,%ecx
  and    $0x3f00,%ecx
  movzbl 0x1(%rdx),%eax
  or     %eax,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,1),%rdx
L0:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L12
L7:
  movzbl %al,%ecx
  mov    %eax,%r8d
  and    $0xffffffc0,%r8d
  cmp    $0xc0,%r8b
  je     L27
  cmp    $0x1,%esi
  sbb    $0xffffffff,%esi
  add    %ecx,%esi
  movzbl %al,%eax
  lea    0x1(%rdx,%rax,1),%rdx
  jmp    L0
L5:
  mov    $0x0,%esi
L12:
  mov    %esi,%eax
  ret
```

assistant: ```c
int calc_domain_name_size(unsigned char *buf, int buflen, int offset) {
  unsigned char *p = buf + offset;
  int len = 0;
  while (*p) {
    if ((*p & 0xC0) == 0xC0) {
      int newoffset = 0;
      newoffset |= (*p++ & 0x3F) << 8;
      newoffset |= *p;
      p = buf + newoffset;
    } else {
      if (len) {
        len += 1;
      }
      len += *p;
      p += *p + 1;
    }
  }
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_domain_name_size>:
  endbr64
  movslq %edx,%rdx
  xor    %r8d,%r8d
  add    %rdi,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L44
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L29:
  test   %r8d,%r8d
  lea    0x1(%rcx,%r8,1),%esi
  cmovne %esi,%ecx
  add    $0x1,%eax
  movzbl %al,%eax
  add    %rax,%rdx
  mov    %ecx,%r8d
  movzbl (%rdx),%eax
  test   %al,%al
  je     L23
L44:
  mov    %eax,%esi
  movzbl %al,%ecx
  and    $0xffffffc0,%esi
  cmp    $0xc0,%sil
  jne    L29
  movzbl 0x1(%rdx),%eax
  shl    $0x8,%ecx
  and    $0x3f00,%ecx
  or     %eax,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,1),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L44
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calc_domain_name_size(unsigned char *buf, int buflen, int offset) {
  unsigned char *p = buf + offset;
  int len = 0;
  while (*p) {
    if ((*p & 0xC0) == 0xC0) {
      int newoffset = 0;
      newoffset |= (*p++ & 0x3F) << 8;
      newoffset |= *p;
      p = buf + newoffset;
    } else {
      if (len) {
        len += 1;
      }
      len += *p;
      p += *p + 1;
    }
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calc_domain_name_size>:
  endbr64
  movslq %edx,%rdx
  xor    %r8d,%r8d
  add    %rdi,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L49
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L30:
  test   %r8d,%r8d
  lea    0x1(%rcx,%r8,1),%esi
  cmovne %esi,%ecx
  add    $0x1,%eax
  movzbl %al,%eax
  add    %rax,%rdx
  mov    %ecx,%r8d
  movzbl (%rdx),%eax
  test   %al,%al
  je     L45
L49:
  mov    %eax,%esi
  movzbl %al,%ecx
  and    $0xffffffc0,%esi
  cmp    $0xc0,%sil
  jne    L30
  movzbl 0x1(%rdx),%eax
  shl    $0x8,%ecx
  and    $0x3f00,%ecx
  or     %eax,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,1),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L49
L45:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calc_domain_name_size(unsigned char *buf, int buflen, int offset) {
  unsigned char *p = buf + offset;
  int len = 0;
  while (*p) {
    if ((*p & 0xC0) == 0xC0) {
      int newoffset = 0;
      newoffset |= (*p++ & 0x3F) << 8;
      newoffset |= *p;
      p = buf + newoffset;
    } else {
      if (len) {
        len += 1;
      }
      len += *p;
      p += *p + 1;
    }
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<funcTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  D7(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: f32[2]

tool: {"D7": [0.0,1.875]}

assistant: ```c
double funcTest(int comp, double *xs, void *data) {
  double ans = 0.;
  int i;
  for (i = 0; i < comp; i++)
    ans += (xs[i] - 1) * xs[i];
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<funcTest>:
  endbr64
  test   %edi,%edi
  jle    L22
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
  pxor   %xmm2,%xmm2
  movsd  D3(%rip),%xmm3
L25:
  movsd  (%rax),%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L25
L4:
  movapd %xmm2,%xmm0
  ret
L22:
  pxor   %xmm2,%xmm2
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: f32[2]

tool: {"D3": [0.0,1.875]}

assistant: ```c
double funcTest(int comp, double *xs, void *data) {
  double ans = 0.;
  int i;
  for (i = 0; i < comp; i++)
    ans += (xs[i] - 1) * xs[i];
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<funcTest>:
  endbr64
  test   %edi,%edi
  jle    L18
  lea    -0x1(%rdi),%eax
  movsd  D5(%rip),%xmm3
  pxor   %xmm2,%xmm2
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax)
L5:
  movsd  (%rsi),%xmm1
  add    $0x8,%rsi
  movapd %xmm1,%xmm0
  subsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  cmp    %rax,%rsi
  jne    L5
  movapd %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: f32[2]

tool: {"D5": [0.0,1.875]}

assistant: ```c
double funcTest(int comp, double *xs, void *data) {
  double ans = 0.;
  int i;
  for (i = 0; i < comp; i++)
    ans += (xs[i] - 1) * xs[i];
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<funcTest>:
  endbr64
  test   %edi,%edi
  jle    L43
  cmp    $0x1,%edi
  je     L23
  mov    %edi,%edx
  movapd D7(%rip),%xmm3
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
L10:
  movupd (%rax),%xmm1
  movupd (%rax),%xmm4
  add    $0x10,%rax
  addpd  %xmm3,%xmm1
  mulpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L10
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L20
L4:
  cltq
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm2,%xmm1
  subsd  D6(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  ret
  nopl   0x0(%rax)
L43:
  pxor   %xmm0,%xmm0
  ret
L23:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: f32[4]
name: unpack_data
arguments: data_tag: D6
type_infered: f32[2]

tool: {"D7": [0.0,-1.875,0.0,-1.875]}

tool: {"D6": [0.0,1.875]}

assistant: ```c
double funcTest(int comp, double *xs, void *data) {
  double ans = 0.;
  int i;
  for (i = 0; i < comp; i++)
    ans += (xs[i] - 1) * xs[i];
  return ans;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gc_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <gc1@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <gc2@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string

tool: D14: user requested

assistant: ```c
void gc_() {
  gc1("user requested");
  gc2("user requested");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gc_>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <gc1@plt>
  mov    %rbx,%rdi
  call   <gc2@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: user requested

assistant: ```c
void gc_() {
  gc1("user requested");
  gc2("user requested");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gc_>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <gc1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <gc2@plt>
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: user requested

assistant: ```c
void gc_() {
  gc1("user requested");
  gc2("user requested");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gc_>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <gc1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <gc2@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: user requested

assistant: ```c
void gc_() {
  gc1("user requested");
  gc2("user requested");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
L4:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L4
  mov    %edi,%edx
  mov    %esi,%ecx
  mov    %ecx,-0xc(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) char *strcpy(char *dest, const char *src) {
  int d0, d1, d2;
  __asm__ __volatile__("1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2)
                       : "0"(src), "1"(dest)
                       : "memory");
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rdx
L3:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L3
  mov    %rdx,%rax
  ret
```

assistant: ```c
__attribute__((always_)) char *strcpy(char *dest, const char *src) {
  int d0, d1, d2;
  __asm__ __volatile__("1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2)
                       : "0"(src), "1"(dest)
                       : "memory");
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%r8
L7:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L7
  mov    %r8,%rax
  ret
```

assistant: ```c
__attribute__((always_)) char *strcpy(char *dest, const char *src) {
  int d0, d1, d2;
  __asm__ __volatile__("1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2)
                       : "0"(src), "1"(dest)
                       : "memory");
  return dest;
}
```