ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  test   %esi,%esi
  je     1060 <foo.cold>
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no)) int foo(int a, unsigned b) {
  unsigned c = 1;
  if (b >= 1 && b <= ((unsigned)(-1) - 1))
    return 0;
  c = b >> 4;
  if (c == 268435455)
    ;
  else
    __builtin_abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  test   %esi,%esi
  je     1060 <foo.cold>
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((no)) int foo(int a, unsigned b) {
  unsigned c = 1;
  if (b >= 1 && b <= ((unsigned)(-1) - 1))
    return 0;
  c = b >> 4;
  if (c == 268435455)
    ;
  else
    __builtin_abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <list_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_append_list@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct list *list_copy(const struct list *l) {
  struct list *n = list_new(0);
  list_append_list(n, l);
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<list_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <list_new@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <list_append_list@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct list *list_copy(const struct list *l) {
  struct list *n = list_new(0);
  list_append_list(n, l);
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<list_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <list_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <list_append_list@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct list *list_copy(const struct list *l) {
  struct list *n = list_new(0);
  list_append_list(n, l);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <list_new@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <list_append_list@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct list *list_copy(const struct list *l) {
  struct list *n = list_new(0);
  list_append_list(n, l);
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <createStack@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L1:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <push@plt>
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <checkStackPairOrder@plt>
  test   %rax,%rax
  je     L49
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L49:
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D46
type_infered: string
name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D56
type_infered: string
name: read_data
arguments: label: D51
type_infered: string

tool: D16: Enter the size of the stack : 


tool: D46: %d

tool: D0: Enter Element : 


tool: D56: pairwise


tool: D51: not

assistant: ```c
int main() {
  int n, i;
  printf("Enter the size of the stack : \n");
  scanf("%d", &n);
  struct arrayStack *S = createStack(n);
  int d;
  for (i = 0; i < n; i++) {
    printf("Enter Element : \n");
    scanf("%d", &d);
    push(S, d);
  }
  if (checkStackPairOrder(S))
    printf("pairwise\n");
  else
    printf("not");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  cmpl   $0x0,(%rsp)
  jle    L1
  mov    $0x0,%ebx
  lea    D51(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D5(%rip),%r12
L31:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <push@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L31
L1:
  mov    %rbp,%rdi
  call   <checkStackPairOrder@plt>
  test   %rax,%rax
  je     L26
  lea    D33(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D51
datatype: string
name: retrieve_data
arguments: label: D33
datatype: string
name: retrieve_data
arguments: label: D43
datatype: string

tool: D8: Enter the size of the stack : 


tool: D5: %d

tool: D51: Enter Element : 


tool: D33: pairwise


tool: D43: not

assistant: ```c
int main() {
  int n, i;
  printf("Enter the size of the stack : \n");
  scanf("%d", &n);
  struct arrayStack *S = createStack(n);
  int d;
  for (i = 0; i < n; i++) {
    printf("Enter Element : \n");
    scanf("%d", &d);
    push(S, d);
  }
  if (checkStackPairOrder(S))
    printf("pairwise\n");
  else
    printf("not");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%rdi
  push   %r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L46
  xor    %ebx,%ebx
  lea    D21(%rip),%r14
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L44:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <push@plt>
  cmp    %ebx,(%rsp)
  jg     L44
L46:
  mov    %rbp,%rdi
  call   <checkStackPairOrder@plt>
  test   %rax,%rax
  je     L0
  lea    D5(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D48
type: string
name: retrieve_data
arguments: data_label: D21
type: string
name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D45
type: string

tool: D3: Enter the size of the stack : 


tool: D48: %d

tool: D21: Enter Element : 


tool: D5: pairwise


tool: D45: not

assistant: ```c
int main() {
  int n, i;
  printf("Enter the size of the stack : \n");
  scanf("%d", &n);
  struct arrayStack *S = createStack(n);
  int d;
  for (i = 0; i < n; i++) {
    printf("Enter Element : \n");
    scanf("%d", &d);
    push(S, d);
  }
  if (checkStackPairOrder(S))
    printf("pairwise\n");
  else
    printf("not");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D41(%rip),%rdi
  push   %r13
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  call   <createStack@plt>
  mov    %rax,%rbp
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %ebx,%ebx
  lea    D32(%rip),%r14
  lea    0x4(%rsp),%r13
  xchg   %ax,%ax
L38:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <push@plt>
  cmp    %ebx,(%rsp)
  jg     L38
L0:
  mov    %rbp,%rdi
  call   <checkStackPairOrder@plt>
  test   %rax,%rax
  je     L6
  lea    D20(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D41
type_infered: string
name: read_data
arguments: tag: D44
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D47
type_infered: string

tool: D41: Enter the size of the stack : 


tool: D44: %d

tool: D32: Enter Element : 


tool: D20: pairwise


tool: D47: not

assistant: ```c
int main() {
  int n, i;
  printf("Enter the size of the stack : \n");
  scanf("%d", &n);
  struct arrayStack *S = createStack(n);
  int d;
  for (i = 0; i < n; i++) {
    printf("Enter Element : \n");
    scanf("%d", &d);
    push(S, d);
  }
  if (checkStackPairOrder(S))
    printf("pairwise\n");
  else
    printf("not");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd21da0c4,%edi
  call   <srand@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L14:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x63,-0x4(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int i;
  srand(19034525245636);
  for (i = 0; i < 100; i++)
    printf("%d\n", rand() % 1000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xd21da0c4,%edi
  call   <srand@plt>
  mov    $0x64,%ebx
  lea    D8(%rip),%rbp
L1:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int main(void) {
  int i;
  srand(19034525245636);
  for (i = 0; i < 100; i++)
    printf("%d\n", rand() % 1000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd21da0c4,%edi
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <srand@plt>
L3:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(void) {
  int i;
  srand(19034525245636);
  for (i = 0; i < 100; i++)
    printf("%d\n", rand() % 1000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd21da0c4,%edi
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <srand@plt>
L1:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main(void) {
  int i;
  srand(19034525245636);
  for (i = 0; i < 100; i++)
    printf("%d\n", rand() % 1000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int puts(const char *string) {
  while (*string) {
    putchar(*string++);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L4:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L4
L19:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *string) {
  while (*string) {
    putchar(*string++);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L19:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L19
L5:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *string) {
  while (*string) {
    putchar(*string++);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L6:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L6
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *string) {
  while (*string) {
    putchar(*string++);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x2710,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: f64
name: read_data
arguments: data_label: D19
type_infered: string

tool: D5: 12344321

tool: D19: Div: %f


assistant: ```c
int main() {
  double f = 12344321.0;
  int p = 10000;
  printf("Div: %f\n", f / p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D18(%rip),%xmm0
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: byte[8]
name: parse_data
arguments: data_label: D9
type_infered: string

tool: {"D18": [0x68,0x22,0x6c,0x78,0xba,0x49,0x93,0x40]}

tool: D9: Div: %f


assistant: ```c
int main() {
  double f = 12344321.0;
  int p = 10000;
  printf("Div: %f\n", f / p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: byte[8]
name: unpack_data
arguments: tag: D9
type_infered: string

tool: {"D7": [0x68,0x22,0x6c,0x78,0xba,0x49,0x93,0x40]}

tool: D9: Div: %f


assistant: ```c
int main() {
  double f = 12344321.0;
  int p = 10000;
  printf("Div: %f\n", f / p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: {"D7": [0x68,0x22,0x6c,0x78,0xba,0x49,0x93,0x40]}

tool: D14: Div: %f


assistant: ```c
int main() {
  double f = 12344321.0;
  int p = 10000;
  printf("Div: %f\n", f / p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<deal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  movl   $0x4,-0x38(%rbp)
  movl   $0x5,-0x34(%rbp)
  movl   $0x6,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0xa,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0xb,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int deal(void) {
  int deck[] = {2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 11};
  return deck[rand() % 13];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deal>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x6,0x10(%rsp)
  movl   $0x7,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  movl   $0xa,0x28(%rsp)
  movl   $0xa,0x2c(%rsp)
  movl   $0xb,0x30(%rsp)
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deal(void) {
  int deck[] = {2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 11};
  return deck[rand() % 13];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deal>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000002,%rax
  movl   $0xb,0x30(%rsp)
  mov    %rax,(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa0000000a,%rax
  mov    %rax,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deal(void) {
  int deck[] = {2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 11};
  return deck[rand() % 13];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deal>:
  endbr64
  sub    $0x48,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xb,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x48,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: byte[16]
name: read_data
arguments: data_label: D1
data_type: byte[16]
name: read_data
arguments: data_label: D10
data_type: byte[16]

tool: {"D5": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D1": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D10": [0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

assistant: ```c
int deal(void) {
  int deck[] = {2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 11};
  return deck[rand() % 13];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  not    %eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn6(int a, int b, int m) {
  int tem1 = m & b;
  int tem2 = a & ~m;
  return tem1 | tem2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn6>:
  endbr64
  xor    %edi,%esi
  and    %edx,%esi
  mov    %esi,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b, int m) {
  int tem1 = m & b;
  int tem2 = a & ~m;
  return tem1 | tem2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn6>:
  endbr64
  xor    %edi,%esi
  and    %edx,%esi
  mov    %esi,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b, int m) {
  int tem1 = m & b;
  int tem2 = a & ~m;
  return tem1 | tem2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fn6>:
  endbr64
  xor    %edi,%esi
  and    %edx,%esi
  mov    %esi,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b, int m) {
  int tem1 = m & b;
  int tem2 = a & ~m;
  return tem1 | tem2;
}
```