user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xcd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xcc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
  mov    %rax,%r15
  mov    $0x0,%r12d
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0xc7d(%rsp),%r13
  jmp    L19
L135:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L45
L115:
  cmp    %r12d,%ebp
  jge    L102
  lea    -0x3f(%r15),%r14
  lea    -0x1(%r12),%eax
  sub    %ebp,%eax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  sub    %rax,%rdx
  sub    %rdx,%r14
  mov    %r15,%rdi
L124:
  lea    -0x3f(%rdi),%rbx
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  cmp    %r14,%rbx
  jne    L124
L102:
  movslq %ebp,%rbp
  mov    %rbp,%rax
  shl    $0x6,%rax
  sub    %rbp,%rax
  lea    0x20(%rsp,%rax,1),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    0xc80(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x1,%r12d
  add    $0x3f,%r15
  cmp    $0x32,%r12d
  je     L135
L19:
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  je     L119
  lea    D60(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  lea    0xc80(%rsp),%rdi
  mov    $0x3c,%esi
  call   <readline@plt>
  test   %r12d,%r12d
  jle    L1
  mov    (%rsp),%rbx
  mov    $0x0,%ebp
L29:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L115
  add    $0x1,%ebp
  add    $0x3f,%rbx
  cmp    %r12d,%ebp
  jne    L29
  mov    %r12d,%ebp
  jmp    L102
L119:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L103
L45:
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L74:
  mov    %rbx,%rsi
  shl    $0x6,%rsi
  sub    %rbx,%rsi
  add    (%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L74
L103:
  mov    0xcc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  mov    $0x0,%eax
  add    $0xcd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  mov    $0x0,%ebp
  jmp    L102
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D41
type_infered: string
name: read_data
arguments: tag: D60
type_infered: string
name: read_data
arguments: tag: D3
type_infered: string

tool: D22: -- No space left --

tool: D12: 
Day reminder

tool: D41: Enter day and reminder: 

tool: D60: %2d

tool: D3:  %s


assistant: ```c
int main(void) {
  char reminders[50][60 + 3];
  char day_str[3], msg_str[60 + 1];
  int day, i, j, num_remind = 0;
  for (;;) {
    if (num_remind == 50) {
      printf("-- No space left --\n");
      break;
    }
    printf("Enter day and reminder: ");
    scanf("%2d", &day);
    if (day == 0)
      break;
    sprintf(day_str, "%2d", day);
    readline(msg_str, 60);
    for (i = 0; i < num_remind; i++)
      if (strcmp(day_str, reminders[i]) < 0)
        break;
    for (j = num_remind; j > i; j--)
      strcpy(reminders[j], reminders[j - 1]);
    strcpy(reminders[i], day_str);
    strcat(reminders[i], msg_str);
    num_remind++;
  }
  printf("\nDay reminder\n");
  for (i = 0; i < num_remind; i++) {
    printf(" %s\n", reminders[i]);
  }
  return 0;
}
```