ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  lea    D2(%rip),%rbp
  call   <repeticiones@plt>
  mov    $0x4,%r8d
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    $0x1,%r8d
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    $0x1,%r8d
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <repeticiones@plt>
  mov    %rbp,%rdi
  mov    $0x3,%r8d
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x3,%edx
  mov    $0x3,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: El numero de numeros iguales en(%d,%d,%d,%d)==%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 2;
  c = 3;
  d = 4;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  d = 1;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  c = 2;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  a = 3;
  b = 3;
  d = 3;
  c = 3;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  lea    D7(%rip),%rbp
  call   <repeticiones@plt>
  mov    $0x4,%r8d
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    $0x1,%r8d
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <repeticiones@plt>
  mov    $0x1,%r8d
  mov    %rbp,%rdi
  mov    $0x2,%ecx
  mov    %eax,%r9d
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <repeticiones@plt>
  mov    %rbp,%rdi
  mov    $0x3,%r8d
  mov    $0x3,%ecx
  mov    %eax,%r9d
  mov    $0x3,%edx
  mov    $0x3,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: El numero de numeros iguales en(%d,%d,%d,%d)==%d


assistant: ```c
int main() {
  int a, b, c, d;
  a = 1;
  b = 2;
  c = 3;
  d = 4;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  d = 1;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  c = 2;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  a = 3;
  b = 3;
  d = 3;
  c = 3;
  printf("El numero de numeros iguales en(%d,%d,%d,%d)==%d\n", a, b, c, d, repeticiones(a, b, c, d));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lighting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    $0x1,%esi
  mov    $0x4b0,%edi
  mov    $0x0,%eax
  call   <lmbind@plt>
  jmp    L19
L3:
  mov    $0x0,%esi
  mov    $0x4b0,%edi
  mov    $0x0,%eax
  call   <lmbind@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
lighting(b) int b;
{
  if (b)
    lmbind(1200, 1);
  else
    lmbind(1200, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lighting>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L11
  mov    $0x1,%esi
  mov    $0x4b0,%edi
  mov    $0x0,%eax
  call   <lmbind@plt>
L16:
  add    $0x8,%rsp
  ret
L11:
  mov    $0x0,%esi
  mov    $0x4b0,%edi
  mov    $0x0,%eax
  call   <lmbind@plt>
  jmp    L16
```

assistant: ```c
lighting(b) int b;
{
  if (b)
    lmbind(1200, 1);
  else
    lmbind(1200, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lighting>:
  endbr64
  test   %edi,%edi
  je     L8
  mov    $0x1,%esi
  mov    $0x4b0,%edi
  xor    %eax,%eax
  jmp    1050 <lmbind@plt>
  nopl   0x0(%rax)
L8:
  xor    %esi,%esi
  mov    $0x4b0,%edi
  xor    %eax,%eax
  jmp    1050 <lmbind@plt>
```

assistant: ```c
lighting(b) int b;
{
  if (b)
    lmbind(1200, 1);
  else
    lmbind(1200, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lighting>:
  endbr64
  test   %edi,%edi
  je     L5
  mov    $0x1,%esi
  mov    $0x4b0,%edi
  xor    %eax,%eax
  jmp    1050 <lmbind@plt>
  nopl   0x0(%rax)
L5:
  xor    %esi,%esi
  mov    $0x4b0,%edi
  xor    %eax,%eax
  jmp    1050 <lmbind@plt>
```

assistant: ```c
lighting(b) int b;
{
  if (b)
    lmbind(1200, 1);
  else
    lmbind(1200, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CMUTIL_StrSkipSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rbx
  jmp    L3
L19:
  add    $0x1,%rbx
L3:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L21
  movzbl (%rbx),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L19
L21:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *CMUTIL_StrSkipSpaces(char *line, const char *spaces) {
  register char *p = line;
  while (*p && strchr(spaces, *p))
    p++;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CMUTIL_StrSkipSpaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rdi),%esi
  mov    %rdi,%rax
  test   %sil,%sil
  je     L30
L1:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L1
  mov    %rbx,%rax
  jmp    L30
L21:
  mov    %rbx,%rax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *CMUTIL_StrSkipSpaces(char *line, const char *spaces) {
  register char *p = line;
  while (*p && strchr(spaces, *p))
    p++;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CMUTIL_StrSkipSpaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L7
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L24:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L2
L7:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L24
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *CMUTIL_StrSkipSpaces(char *line, const char *spaces) {
  register char *p = line;
  while (*p && strchr(spaces, *p))
    p++;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CMUTIL_StrSkipSpaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  jne    L31
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L21:
  movsbl 0x1(%r12),%esi
  add    $0x1,%r12
  test   %sil,%sil
  je     L10
L31:
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L21
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *CMUTIL_StrSkipSpaces(char *line, const char *spaces) {
  register char *p = line;
  while (*p && strchr(spaces, *p))
    p++;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printCombi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L12
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L12:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L11
  movl   $0x0,-0x4(%rbp)
  mov    $0x23,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L65
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L65:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L36
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L36
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printCombi>
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printCombi>
L36:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string

tool: D4: %3d


tool: D6: %2d

tool: 

tool: D24: *%2d

assistant: ```c
void printCombi(int list[], int size, int i) {
  if (i == 0) {
    printf("%3d\n", list[size]);
    return;
  }
  if (size == i) {
    int j = 0;
    printf("#");
    for (j = 0; j < size; j++) {
      printf("%2d", list[j]);
    }
    puts("");
    return;
  } else if (size != i) {
    printCombi(list, size - 1, i);
    printf("*%2d", list[i]);
    printCombi(list, size - 1, i - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printCombi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  test   %edx,%edx
  je     L32
  mov    %edx,%ebx
  cmp    %esi,%edx
  je     L31
  sub    $0x1,%ebp
  mov    %ebp,%esi
  call   <printCombi>
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbx),%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printCombi>
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  movslq %esi,%rbp
  mov    (%rdi,%rbp,4),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L31:
  mov    $0x23,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L5
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D27(%rip),%rbp
L39:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L39
L5:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string

tool: D19: *%2d

tool: D4: %3d


tool: D27: %2d

tool: 

assistant: ```c
void printCombi(int list[], int size, int i) {
  if (i == 0) {
    printf("%3d\n", list[size]);
    return;
  }
  if (size == i) {
    int j = 0;
    printf("#");
    for (j = 0; j < size; j++) {
      printf("%2d", list[j]);
    }
    puts("");
    return;
  } else if (size != i) {
    printCombi(list, size - 1, i);
    printf("*%2d", list[i]);
    printCombi(list, size - 1, i - 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printCombi>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L42
  mov    %edx,%r13d
  cmp    %edx,%esi
  je     L45
  sub    $0x1,%r13d
  lea    D13(%rip),%r15
  movslq %r13d,%rbx
L15:
  mov    %ebp,%r14d
  sub    $0x1,%ebp
  lea    0x1(%rbx),%edx
  mov    %r12,%rdi
  mov    %ebp,%esi
  mov    %ebx,%r13d
  call   <printCombi>
  mov    0x4(%r12,%rbx,4),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L42
  sub    $0x1,%rbx
  lea    0x2(%rbx),%eax
  cmp    %eax,%r14d
  jne    L15
L45:
  mov    $0x23,%edi
  call   <putchar@plt>
  test   %r13d,%r13d
  jle    L21
  lea    -0x1(%r13),%eax
  mov    %r12,%rbx
  lea    D34(%rip),%rbp
  lea    0x4(%r12,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L38
L21:
  add    $0x8,%rsp
  lea    D38(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nop
L42:
  movslq %ebp,%rbp
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  mov    (%r12,%rbp,4),%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string

tool: D13: *%2d

tool: D34: %2d

tool: 

tool: D12: %3d


assistant: ```c
void printCombi(int list[], int size, int i) {
  if (i == 0) {
    printf("%3d\n", list[size]);
    return;
  }
  if (size == i) {
    int j = 0;
    printf("#");
    for (j = 0; j < size; j++) {
      printf("%2d", list[j]);
    }
    puts("");
    return;
  } else if (size != i) {
    printCombi(list, size - 1, i);
    printf("*%2d", list[i]);
    printCombi(list, size - 1, i - 1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printCombi>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L1
  mov    %edx,%r13d
  cmp    %edx,%esi
  je     L35
  sub    $0x1,%r13d
  lea    D22(%rip),%r15
  movslq %r13d,%rbx
L50:
  mov    %ebp,%r14d
  sub    $0x1,%ebp
  lea    0x1(%rbx),%edx
  mov    %r12,%rdi
  mov    %ebp,%esi
  mov    %ebx,%r13d
  call   <printCombi>
  mov    0x4(%r12,%rbx,4),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L1
  sub    $0x1,%rbx
  lea    0x2(%rbx),%eax
  cmp    %r14d,%eax
  jne    L50
L35:
  mov    $0x23,%edi
  call   <putchar@plt>
  test   %r13d,%r13d
  jle    L44
  lea    -0x1(%r13),%eax
  mov    %r12,%rbx
  lea    D2(%rip),%rbp
  lea    0x4(%r12,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L57:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L57
L44:
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nop
L1:
  movslq %ebp,%rbp
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  mov    (%r12,%rbp,4),%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D5
type: string

tool: D22: *%2d

tool: D2: %2d

tool: 

tool: D5: %3d


assistant: ```c
void printCombi(int list[], int size, int i) {
  if (i == 0) {
    printf("%3d\n", list[size]);
    return;
  }
  if (size == i) {
    int j = 0;
    printf("#");
    for (j = 0; j < size; j++) {
      printf("%2d", list[j]);
    }
    puts("");
    return;
  } else if (size != i) {
    printCombi(list, size - 1, i);
    printf("*%2d", list[i]);
    printCombi(list, size - 1, i - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trimmer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L71:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L70
  addq   $0x1,-0x18(%rbp)
L70:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L71
  movl   $0x2,-0xc(%rbp)
  jmp    L8
L47:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L47
  movl   $0x0,-0xc(%rbp)
  jmp    L46
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L72
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L72
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L72:
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L6
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void trimmer(char *number, int dimensions_array[], int size, int position) {
  int i, count = 0, mul = 1;
  do
    if (number[0] == '0')
      number++;
  while (number[0] == '0');
  for (i = 2; i < (int)strlen(number); i++)
    mul *= 10;
  for (i = 0; i < (int)strlen(number); i++)
    if (number[i] >= '0' && number[i] <= '9') {
      count += (mul * (number[i] - 48));
      mul /= 10;
    }
  dimensions_array[position] = count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trimmer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %ecx,%ebx
  jmp    L9
L46:
  add    $0x1,%r12
  cmpb   $0x30,(%r12)
  jne    L11
L9:
  cmpb   $0x30,(%r12)
  je     L46
L11:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  mov    $0x2,%ecx
  jmp    L55
L21:
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  add    $0x1,%ecx
L55:
  cmp    %ecx,%esi
  jg     L21
  test   %eax,%eax
  jle    L79
  mov    %r12,%rcx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r8
  mov    $0x0,%edi
  jmp    L73
L65:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L59
L73:
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L65
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   %edx,%eax
  add    %eax,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  jmp    L65
L79:
  mov    $0x0,%edi
L59:
  movslq %ebx,%rbx
  mov    %edi,0x0(%rbp,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trimmer(char *number, int dimensions_array[], int size, int position) {
  int i, count = 0, mul = 1;
  do
    if (number[0] == '0')
      number++;
  while (number[0] == '0');
  for (i = 2; i < (int)strlen(number); i++)
    mul *= 10;
  for (i = 0; i < (int)strlen(number); i++)
    if (number[i] >= '0' && number[i] <= '9') {
      count += (mul * (number[i] - 48));
      mul /= 10;
    }
  dimensions_array[position] = count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trimmer>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  cmp    $0x30,%bl
  je     L41
L72:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    %eax,%esi
  jmp    L30
  nopl   (%rax)
L58:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%ecx
  add    %edx,%edx
L30:
  cmp    %ecx,%esi
  jg     L58
  test   %eax,%eax
  jle    L84
  sub    $0x1,%eax
  mov    %rbp,%rcx
  xor    %esi,%esi
  mov    $0xcccccccd,%edi
  add    %rbp,%rax
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rcx),%ebx
  add    $0x1,%rcx
L79:
  sub    $0x30,%ebx
  cmp    $0x9,%bl
  ja     L26
  movsbl %bl,%ebx
  imul   %edx,%ebx
  mov    %edx,%edx
  imul   %rdi,%rdx
  add    %ebx,%esi
  shr    $0x23,%rdx
L26:
  cmp    %rax,%rcx
  jne    L1
  mov    %esi,0x0(%r13,%r12,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    %rbp,%rax
  add    $0x1,%rbp
  movzbl 0x1(%rax),%ebx
  cmp    $0x30,%bl
  jne    L72
  mov    %rbp,%rax
  add    $0x1,%rbp
  movzbl 0x1(%rax),%ebx
  cmp    $0x30,%bl
  je     L41
  jmp    L72
L84:
  xor    %esi,%esi
  mov    %esi,0x0(%r13,%r12,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void trimmer(char *number, int dimensions_array[], int size, int position) {
  int i, count = 0, mul = 1;
  do
    if (number[0] == '0')
      number++;
  while (number[0] == '0');
  for (i = 2; i < (int)strlen(number); i++)
    mul *= 10;
  for (i = 0; i < (int)strlen(number); i++)
    if (number[i] >= '0' && number[i] <= '9') {
      count += (mul * (number[i] - 48));
      mul /= 10;
    }
  dimensions_array[position] = count;
}
```