user: What would the C source look like for the assembly code provided here?

```asm
<logicTest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D158(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D133(%rip),%rdi
  call   <puts@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    D66(%rip),%rdi
  call   <puts@plt>
  mov    $0x5,%ebx
  lea    D153(%rip),%rbp
L26:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L26
  lea    D75(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D153(%rip),%rbp
L50:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L50
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D153(%rip),%rbp
  lea    D80(%rip),%r15
  lea    D150(%rip),%r13
  lea    D58(%rip),%r14
  jmp    L46
L76:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x6,%ebx
L46:
  cmp    $0x5,%ebx
  je     L76
  cmp    $0x3,%ebx
  je     L81
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x63,%ebx
  jg     L85
  cmp    $0xa,%ebx
  jne    L46
  lea    D110(%rip),%rdi
  call   <puts@plt>
  lea    D95(%rip),%rdi
  call   <puts@plt>
L44:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
L66:
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    $0x5,%r12d
  jne    L66
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L46
L85:
  lea    D95(%rip),%rdi
  call   <puts@plt>
  jmp    L44
```

tool_calls: name: read_data
arguments: label: D158
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D133
datatype: string
name: read_data
arguments: label: D68
datatype: string
name: read_data
arguments: label: D66
datatype: string
name: read_data
arguments: label: D153
datatype: string
name: read_data
arguments: label: D75
datatype: string
name: read_data
arguments: label: D35
datatype: string
name: read_data
arguments: label: D80
datatype: string
name: read_data
arguments: label: D150
datatype: string
name: read_data
arguments: label: D58
datatype: string
name: read_data
arguments: label: D110
datatype: string
name: read_data
arguments: label: D95
datatype: string
name: read_data
arguments: label: D27
datatype: string

tool: D158: If

tool: D24: Taken

tool: D133: If-Else

tool: D68: Else-Taken

tool: D66: while (simple)

tool: D153: i=%d


tool: D75: for (simple)

tool: D35: while (complicated)

tool: D80: nested-for

tool: D150: j=%d


tool: D58: continue

tool: D110: break

tool: D95: switch

tool: D27: default

assistant: ```c
void logicTest() {
  int i = 5;
  printf("If\n");
  if (i == 5) {
    printf("Taken\n");
  }
  printf("If-Else\n");
  if (i < 5) {
    printf("If-Taken\n");
  } else {
    printf("Else-Taken\n");
  }
  printf("while (simple)\n");
  while (i < 10) {
    printf("i=%d\n", i);
    ++i;
  }
  printf("for (simple)\n");
  i = 0;
  for (i = 0; i < 10; i++) {
    printf("i=%d\n", i);
  }
  printf("while (complicated)\n");
  i = 0;
  while (i < 100) {
    if (i == 10) {
      printf("break\n");
      break;
    }
    if (i == 5) {
      printf("continue\n");
      ++i;
      continue;
    }
    if (i == 3) {
      printf("nested-for\n");
      int j;
      for (j = 0; j < 5; j++) {
        printf("j=%d\n", j);
      }
    }
    printf("i=%d\n", i);
    ++i;
  }
  printf("switch\n");
  switch (i) {
  case 1:
    printf("one\n");
    break;
  case 2:
    printf("two\n");
    break;
  default:
    printf("default\n");
    break;
  }
}
```