user: Demonstrate the C code that generates the assembly output below:

```asm
<ripetizioni>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x28,%edi
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0xa,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movsbl (%r15),%edx
  mov    %rax,%rbp
  test   %dl,%dl
  je     L37
  xor    %ecx,%ecx
  movsbl %dl,%r9d
  jmp    L145
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %r9d,(%r12)
  xor    %ebx,%ebx
  movb   $0x1,0x0(%rbp)
L173:
  add    $0x1,%rcx
  movsbl (%r15,%rcx,1),%edx
  test   %dl,%dl
  je     L37
L145:
  test   %rcx,%rcx
  je     L31
  movslq %ebx,%rdi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L126
  xchg   %ax,%ax
L166:
  mov    %rsi,%rax
L126:
  cmp    %edx,(%r12,%rax,4)
  jne    L144
  addb   $0x1,0x0(%rbp,%rax,1)
  mov    $0x1,%r8d
L144:
  lea    0x1(%rax),%rsi
  cmp    %rdi,%rax
  jne    L166
  test   %r8d,%r8d
  jne    L173
  add    $0x1,%ebx
  add    $0x1,%rcx
  movslq %ebx,%rax
  mov    %edx,(%r12,%rax,4)
  movsbl (%r15,%rcx,1),%edx
  movb   $0x1,0x0(%rbp,%rax,1)
  test   %dl,%dl
  jne    L145
  xchg   %ax,%ax
L37:
  movsbl 0x0(%rbp),%edx
  lea    0x1(%rbp),%rax
  movslq %ebx,%rsi
  add    %rax,%rsi
  mov    %edx,(%r14)
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L132:
  movsbl (%rax),%ecx
  cmp    (%r14),%ecx
  jle    L27
  mov    %ecx,(%r14)
L27:
  add    $0x1,%rax
L28:
  cmp    %rax,%rsi
  jne    L132
  test   %ebx,%ebx
  je     L61
  mov    (%r14),%edi
  lea    -0x1(%rbx),%esi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L169
  nopl   (%rax)
L16:
  lea    0x1(%rax),%rcx
  cmp    %rax,%rsi
  je     L61
L25:
  movsbl 0x1(%rbp,%rax,1),%edx
  mov    %rcx,%rax
L169:
  cmp    %edx,%edi
  jne    L16
  test   %r8d,%r8d
  jne    L66
  movzbl (%r12,%rax,4),%r13d
  mov    $0x1,%r8d
  lea    0x1(%rax),%rcx
  cmp    %rax,%rsi
  jne    L25
L61:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  mov    (%r12,%rax,4),%edx
  movsbl %r13b,%ecx
  cmp    %edx,%ecx
  cmovg  %edx,%r13d
  jmp    L16
```

assistant: ```c
char ripetizioni(char str[], int *rep) {
  int *item = (int *)malloc(sizeof(int) * 10);
  char *freq = (char *)malloc(sizeof(char) * 10);
  char frequent;
  int segno;
  int len = 0;
  int j;
  int i = 0;
  int flag = 0;
  while (str[i] != '\0') {
    if (i == 0) {
      item[0] = str[0];
      freq[0] = 1;
      segno = 0;
    } else {
      for (j = 0; j <= segno; j++) {
        if (item[j] == str[i]) {
          freq[j] = freq[j] + 1;
          flag = 1;
        }
      }
      if (flag == 0) {
        segno = segno + 1;
        item[segno] = str[i];
        freq[segno] = 1;
      }
    }
    i++;
    flag = 0;
  }
  *rep = freq[0];
  for (int i = 0; i <= segno; i++) {
    if (freq[i] > *rep) {
      *rep = freq[i];
    }
  }
  int step = 0;
  for (int i = 0; i < segno; i++) {
    if (*rep == freq[i]) {
      if (step == 0) {
        frequent = item[i];
        step++;
      } else if (((item)[i] < frequent) && (step > 0)) {
        frequent = item[i];
      }
    }
  }
  free(item);
  free(freq);
  return frequent;
}
```