ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim_whitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L26
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%r12
  movslq %eax,%r13
  mov    %r13,%rbx
  test   %r13d,%r13d
  jg     L59
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12
  sub    $0x1,%ebx
  je     L69
L59:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  lea    -0x1(%rbp,%r13,1),%rbp
  jmp    L37
  nop
L32:
  sub    $0x1,%rbp
  sub    $0x1,%ebx
  je     L69
L37:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
  movslq %ebx,%r13
L57:
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L69:
  xor    %r13d,%r13d
  jmp    L57
  nopl   (%rax)
L26:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim_whitespace(char *s) {
  char *end;
  int len;
  if (s == NULL)
    return NULL;
  len = strlen(s);
  end = s + len - 1;
  while (len > 0 && isspace(*s)) {
    s++;
    len--;
  }
  while (len > 0 && isspace(*end)) {
    end--;
    len--;
  }
  s[len] = '\0';
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_whitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L72
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%r12
  movslq %eax,%r13
  mov    %r13,%rbx
  test   %r13d,%r13d
  jg     L2
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L85:
  add    $0x1,%r12
  sub    $0x1,%ebx
  je     L14
L2:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L85
  lea    -0x1(%rbp,%r13,1),%rbp
  jmp    L0
  nop
L17:
  sub    $0x1,%rbp
  sub    $0x1,%ebx
  je     L14
L0:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  movslq %ebx,%r13
L9:
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  xor    %r13d,%r13d
  jmp    L9
  nopl   (%rax)
L72:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim_whitespace(char *s) {
  char *end;
  int len;
  if (s == NULL)
    return NULL;
  len = strlen(s);
  end = s + len - 1;
  while (len > 0 && isspace(*s)) {
    s++;
    len--;
  }
  while (len > 0 && isspace(*end)) {
    end--;
    len--;
  }
  s[len] = '\0';
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<frasenove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  mov    $0x0,%eax
  call   <limpamlc@plt>
  movsbl -0x4(%rbp),%eax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sprintf@plt>
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <LCD_Out@plt>
  movsbl -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mostrapenter@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: 9: Agua

assistant: ```c
void frasenove(char plinha, char penter) {
  limpamlc();
  sprintf(plinha, "9: Agua");
  LCD_Out(1, 5, plinha);
  mostrapenter(penter);
}
```
user: Translate the below assembly code into C programming language:

```asm
<frasenove>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <limpamlc@plt>
  movsbl %bl,%ebx
  lea    D0(%rip),%rsi
  mov    %ebx,%edi
  call   <sprintf@plt>
  mov    %ebx,%edx
  mov    $0x5,%esi
  mov    $0x1,%edi
  call   <LCD_Out@plt>
  movsbl %bpl,%edi
  call   <mostrapenter@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: 9: Agua

assistant: ```c
void frasenove(char plinha, char penter) {
  limpamlc();
  sprintf(plinha, "9: Agua");
  LCD_Out(1, 5, plinha);
  mostrapenter(penter);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<frasenove>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %eax,%eax
  push   %rbx
  movsbl %r12b,%r12d
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <limpamlc@plt>
  mov    %r12d,%edi
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    $0x5,%esi
  call   <LCD_Out@plt>
  add    $0x8,%rsp
  movsbl %bl,%edi
  pop    %rbx
  pop    %r12
  jmp    10b0 <mostrapenter@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: 9: Agua

assistant: ```c
void frasenove(char plinha, char penter) {
  limpamlc();
  sprintf(plinha, "9: Agua");
  LCD_Out(1, 5, plinha);
  mostrapenter(penter);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<frasenove>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  xor    %eax,%eax
  push   %rbx
  movsbl %r12b,%r12d
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <limpamlc@plt>
  mov    %r12d,%edi
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    $0x5,%esi
  call   <LCD_Out@plt>
  add    $0x8,%rsp
  movsbl %bl,%edi
  pop    %rbx
  pop    %r12
  jmp    10b0 <mostrapenter@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: 9: Agua

assistant: ```c
void frasenove(char plinha, char penter) {
  limpamlc();
  sprintf(plinha, "9: Agua");
  LCD_Out(1, 5, plinha);
  mostrapenter(penter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<log2_floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L12:
  shrl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int log2_floor(unsigned int v) {
  unsigned int x = 0;
  while (v) {
    v >>= 1;
    x += 1;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log2_floor>:
  endbr64
  test   %edi,%edi
  je     L11
  mov    $0x0,%eax
L5:
  add    $0x1,%eax
  shr    %edi
  jne    L5
  ret
L11:
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned int log2_floor(unsigned int v) {
  unsigned int x = 0;
  while (v) {
    v >>= 1;
    x += 1;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log2_floor>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L0
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%eax
  shr    %edi
  jne    L13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
unsigned int log2_floor(unsigned int v) {
  unsigned int x = 0;
  while (v) {
    v >>= 1;
    x += 1;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<log2_floor>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L4
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%eax
  shr    %edi
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
unsigned int log2_floor(unsigned int v) {
  unsigned int x = 0;
  while (v) {
    v >>= 1;
    x += 1;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tlv_iter_decode_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tlv_iter_get_len@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tlv_iter_get_data@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  je     L13
  mov    $0xffffffff,%eax
  jmp    L8
L13:
  mov    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int tlv_iter_decode_u32(struct tlv_iterator *tlv_iter, uint32_t *res) {
  const char *opt_data;
  uint16_t opt_len;
  uint32_t nu32;
  opt_len = tlv_iter_get_len(tlv_iter);
  opt_data = tlv_iter_get_data(tlv_iter);
  if (opt_len != sizeof(nu32)) {
    return (-1);
  }
  memcpy(&nu32, opt_data, sizeof(nu32));
  *res = ntohl(nu32);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tlv_iter_decode_u32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <tlv_iter_get_len@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <tlv_iter_get_data@plt>
  cmp    $0x4,%ebp
  jne    L24
  mov    %rax,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%r12)
  mov    $0x0,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L25
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tlv_iter_decode_u32(struct tlv_iterator *tlv_iter, uint32_t *res) {
  const char *opt_data;
  uint16_t opt_len;
  uint32_t nu32;
  opt_len = tlv_iter_get_len(tlv_iter);
  opt_data = tlv_iter_get_data(tlv_iter);
  if (opt_len != sizeof(nu32)) {
    return (-1);
  }
  memcpy(&nu32, opt_data, sizeof(nu32));
  *res = ntohl(nu32);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tlv_iter_decode_u32>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <tlv_iter_get_len@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tlv_iter_get_data@plt>
  cmp    $0x4,%ebx
  jne    L12
  mov    %rax,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%r12)
  xor    %eax,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L19
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tlv_iter_decode_u32(struct tlv_iterator *tlv_iter, uint32_t *res) {
  const char *opt_data;
  uint16_t opt_len;
  uint32_t nu32;
  opt_len = tlv_iter_get_len(tlv_iter);
  opt_data = tlv_iter_get_data(tlv_iter);
  if (opt_len != sizeof(nu32)) {
    return (-1);
  }
  memcpy(&nu32, opt_data, sizeof(nu32));
  *res = ntohl(nu32);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tlv_iter_decode_u32>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <tlv_iter_get_len@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tlv_iter_get_data@plt>
  cmp    $0x4,%ebx
  jne    L22
  mov    %rax,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%r12)
  xor    %eax,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    $0xffffffff,%eax
  jmp    L27
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int tlv_iter_decode_u32(struct tlv_iterator *tlv_iter, uint32_t *res) {
  const char *opt_data;
  uint16_t opt_len;
  uint32_t nu32;
  opt_len = tlv_iter_get_len(tlv_iter);
  opt_data = tlv_iter_get_data(tlv_iter);
  if (opt_len != sizeof(nu32)) {
    return (-1);
  }
  memcpy(&nu32, opt_data, sizeof(nu32));
  *res = ntohl(nu32);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<freadi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int freadi(FILE *fIn) {
  int iTemp;
  fread(&iTemp, sizeof(int), 1, fIn);
  return iTemp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<freadi>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freadi(FILE *fIn) {
  int iTemp;
  fread(&iTemp, sizeof(int), 1, fIn);
  return iTemp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<freadi>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freadi(FILE *fIn) {
  int iTemp;
  fread(&iTemp, sizeof(int), 1, fIn);
  return iTemp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<freadi>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int freadi(FILE *fIn) {
  int iTemp;
  fread(&iTemp, sizeof(int), 1, fIn);
  return iTemp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<free_sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L18
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x8,-0x4(%rbp)
  jle    L26
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int free_sec(unsigned char **clone_sec) {
  int i;
  for (i = 0; i < 9; i++) {
    if (clone_sec[i])
      free(clone_sec[i]);
    clone_sec[i] = NULL;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_sec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x48(%rdi),%r12
  jmp    L8
L28:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L26
L8:
  mov    %rbx,%rbp
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L28
  call   <free@plt>
  jmp    L28
L26:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int free_sec(unsigned char **clone_sec) {
  int i;
  for (i = 0; i < 9; i++) {
    if (clone_sec[i])
      free(clone_sec[i]);
    clone_sec[i] = NULL;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_sec>:
  endbr64
  push   %rbp
  lea    0x48(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L0
  call   <free@plt>
L0:
  movq   $0x0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int free_sec(unsigned char **clone_sec) {
  int i;
  for (i = 0; i < 9; i++) {
    if (clone_sec[i])
      free(clone_sec[i]);
    clone_sec[i] = NULL;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<free_sec>:
  endbr64
  push   %rbp
  lea    0x48(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L21:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L19
  call   <free@plt>
  add    $0x8,%rbx
  movq   $0x0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L21
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L19:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L21
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int free_sec(unsigned char **clone_sec) {
  int i;
  for (i = 0; i < 9; i++) {
    if (clone_sec[i])
      free(clone_sec[i]);
    clone_sec[i] = NULL;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checkConflict>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %edx,%esi
  call   <getPosition@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  test   %r13d,%r13d
  js     L22
  test   %r12d,%r12d
  jle    L249
  mov    $0x0,%ebx
  jmp    L167
L74:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L249
L167:
  cmp    %ebx,%ebp
  je     L74
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  cmp    %r13d,%eax
  jne    L74
  mov    $0x1,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L249:
  cmp    $0x1,%ebp
  jg     L258
  lea    -0x2(%r12),%eax
  cmp    %ebp,%eax
  jg     L18
L103:
  test   %ebp,%ebp
  jg     L28
L226:
  sub    $0x1,%r12d
  mov    $0x0,%eax
  cmp    %ebp,%r12d
  jle    L22
  lea    0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  js     L22
  lea    0x2(%r13),%ecx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  je     L22
  sub    $0x2,%r13d
  cmp    %edx,%r13d
  sete   %al
  movzbl %al,%eax
  jmp    L22
L258:
  lea    -0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L158
  lea    0x1(%r13),%ecx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  je     L22
  lea    -0x1(%r13),%ecx
  cmp    %edx,%ecx
  je     L22
L158:
  lea    -0x2(%r12),%eax
  cmp    %eax,%ebp
  jl     L90
L28:
  lea    -0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L226
  lea    0x2(%r13),%ecx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  je     L22
  lea    -0x2(%r13),%ecx
  cmp    %edx,%ecx
  jne    L226
  jmp    L22
L18:
  lea    0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L103
L168:
  lea    0x1(%r13),%ecx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  je     L22
  lea    -0x1(%r13),%ecx
  cmp    %edx,%ecx
  jne    L103
  jmp    L22
L90:
  lea    0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L168
  jmp    L28
```

assistant: ```c
int checkConflict(int *board, int n, int x) {
  int y = getPosition(board, x);
  int i;
  int t;
  if (y < 0)
    return 0;
  for (i = 0; i < n; i++)
    if (x != i && getPosition(board, i) == y)
      return 1;
  if (x > 1) {
    t = getPosition(board, x - 2);
    if (t >= 0 && (t == y + 1 || t == y - 1))
      return 1;
  }
  if (x < n - 2) {
    t = getPosition(board, x + 2);
    if (t >= 0 && (t == y + 1 || t == y - 1))
      return 1;
  }
  if (x > 0) {
    t = getPosition(board, x - 1);
    if (t >= 0 && (t == y + 2 || t == y - 2))
      return 1;
  }
  if (x < n - 1) {
    t = getPosition(board, x + 1);
    if (t >= 0 && (t == y + 2 || t == y - 2))
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkConflict>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  call   <getPosition@plt>
  test   %eax,%eax
  js     L178
  mov    %eax,%r13d
  test   %r12d,%r12d
  jle    L133
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L55:
  cmp    %ebx,%ebp
  je     L74
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  cmp    %r13d,%eax
  je     L210
L74:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L55
L133:
  cmp    $0x1,%ebp
  jg     L79
  lea    -0x2(%r12),%eax
  cmp    %ebp,%eax
  jg     L67
L228:
  test   %ebp,%ebp
  jg     L175
L237:
  sub    $0x1,%r12d
  cmp    %ebp,%r12d
  jg     L198
L178:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L79:
  lea    -0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  test   %eax,%eax
  js     L201
  lea    0x1(%r13),%edx
  cmp    %eax,%edx
  je     L210
  lea    -0x1(%r13),%edx
  cmp    %eax,%edx
  je     L210
L201:
  lea    -0x2(%r12),%eax
  cmp    %eax,%ebp
  jl     L98
L175:
  lea    -0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  test   %eax,%eax
  js     L237
  lea    0x2(%r13),%edx
  cmp    %eax,%edx
  je     L210
  lea    -0x2(%r13),%edx
  cmp    %eax,%edx
  jne    L237
L210:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L198:
  lea    0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  test   %eax,%eax
  js     L178
  lea    0x2(%r13),%edx
  cmp    %eax,%edx
  je     L210
  sub    $0x2,%r13d
  cmp    %eax,%r13d
  jne    L178
  jmp    L210
  nopw   0x0(%rax,%rax,1)
L67:
  lea    0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  test   %eax,%eax
  js     L228
L52:
  lea    0x1(%r13),%edx
  cmp    %eax,%edx
  je     L210
  lea    -0x1(%r13),%edx
  cmp    %eax,%edx
  jne    L228
  jmp    L210
L98:
  lea    0x2(%rbp),%esi
  mov    %r14,%rdi
  call   <getPosition@plt>
  test   %eax,%eax
  jns    L52
  jmp    L175
```

assistant: ```c
int checkConflict(int *board, int n, int x) {
  int y = getPosition(board, x);
  int i;
  int t;
  if (y < 0)
    return 0;
  for (i = 0; i < n; i++)
    if (x != i && getPosition(board, i) == y)
      return 1;
  if (x > 1) {
    t = getPosition(board, x - 2);
    if (t >= 0 && (t == y + 1 || t == y - 1))
      return 1;
  }
  if (x < n - 2) {
    t = getPosition(board, x + 2);
    if (t >= 0 && (t == y + 1 || t == y - 1))
      return 1;
  }
  if (x > 0) {
    t = getPosition(board, x - 1);
    if (t >= 0 && (t == y + 2 || t == y - 2))
      return 1;
  }
  if (x < n - 1) {
    t = getPosition(board, x + 1);
    if (t >= 0 && (t == y + 2 || t == y - 2))
      return 1;
  }
  return 0;
}
```