user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0xffffff9e,0x10(%rsp)
  movl   $0xffffff8a,0x14(%rsp)
  movl   $0xffffffa5,0x18(%rsp)
  movl   $0xc,0x1c(%rsp)
  movl   $0xffffffcf,0x20(%rsp)
  movl   $0x23,0x24(%rsp)
  movl   $0x1c,0x28(%rsp)
  movl   $0x5f,0x2c(%rsp)
  movl   $0xc,0x30(%rsp)
  movl   $0xfffffff8,0x34(%rsp)
  movl   $0xfffffff8,0x38(%rsp)
  movl   $0x1e,0x3c(%rsp)
  movl   $0xffffffca,0x40(%rsp)
  movl   $0x7,0x44(%rsp)
  movl   $0xffffffad,0x48(%rsp)
  movl   $0xffffffd8,0x4c(%rsp)
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r9
  lea    0x10(%rsp),%rbx
  lea    0x30(%rsp),%r11
  mov    %rbx,%rsi
  mov    %r11,%rdi
L53:
  mov    $0x0,%eax
  mov    $0x0,%ecx
  mov    %rsi,%r8
L22:
  mov    (%rsi,%rax,4),%edx
  imul   (%rdi,%rax,8),%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L22
  mov    %r9,%r10
  mov    %ecx,(%r9)
  mov    $0x0,%eax
  mov    $0x0,%ecx
L51:
  mov    (%r8,%rax,4),%edx
  imul   0x4(%rdi,%rax,8),%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L51
  mov    %ecx,0x4(%r10)
  add    $0x8,%r9
  add    $0x10,%rsi
  cmp    %r11,%rsi
  jne    L53
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rbx),%r13
  mov    %rbx,%rbp
  lea    D55(%rip),%r12
L56:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L56
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x20(%rsp),%rbp
  add    $0x20,%rbx
  lea    D55(%rip),%r12
L12:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %rbp,%rbx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rbx
  lea    0x50(%rsp),%r12
  lea    D55(%rip),%rbp
L62:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L62
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D77(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  lea    D55(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D42
type: string
name: extract_symbolic_data
arguments: tag: D55
type: string
name: extract_symbolic_data
arguments: tag: D43
type: string
name: extract_symbolic_data
arguments: tag: D77
type: string

tool: D1: Calculando Matriz C:

tool: D42: MatrizA:

tool: D55: %d	

tool: D43: MatrizB:

tool: D77: MatrizC:

assistant: ```c
int main() {
  int matrizA[2][4] = {-98, -118, -91, 12, -49, 35, 28, 95};
  int matrizB[4][2] = {12, -8, -8, 30, -54, 7, -83, -40};
  int matrizC[2][2];
  int soma = 0;
  int linA, linB;
  int colB;
  printf("Calculando Matriz C:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++) {
      soma = 0;
      for (linB = 0; linB < 4; linB++)
        soma += matrizA[linA][linB] * matrizB[linB][colB];
      matrizC[linA][colB] = soma;
    }
  }
  printf("MatrizA:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 4; colB++)
      printf("%d\t", matrizA[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizB:\n");
  for (linA = 0; linA < 4; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizB[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizC:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizC[linA][colB]);
    printf("\n");
  }
  return 0;
}
```