ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lookupxy>:
  endbr64
  movsd  (%rsi),%xmm1
  comisd %xmm0,%xmm1
  jae    L29
  movslq %edi,%r8
  shl    $0x3,%r8
  movsd  -0x8(%rsi,%r8,1),%xmm2
  comisd %xmm2,%xmm0
  jae    L47
  movsd  (%rdx),%xmm3
  cmp    $0x1,%edi
  jle    L36
  mov    %edi,%edi
  lea    0x0(,%rdi,8),%rcx
  mov    $0x8,%eax
L6:
  movapd %xmm1,%xmm4
  movsd  (%rsi,%rax,1),%xmm1
  comisd %xmm0,%xmm1
  jae    L21
  movsd  (%rdx,%rax,1),%xmm3
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L6
L36:
  movsd  -0x8(%rdx,%r8,1),%xmm0
  ret
L29:
  movsd  (%rdx),%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
L47:
  movsd  -0x8(%rdx,%r8,1),%xmm3
  movsd  -0x10(%rdx,%r8,1),%xmm1
  subsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  -0x10(%rsi,%r8,1),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
L21:
  movsd  (%rdx,%rax,1),%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm4,%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

assistant: ```c
double lookupxy(double x, int n, double *xv, double *yv) {
  double dx, dy, x1, y1, x2, y2;
  int i;
  if (x <= xv[0])
    return (yv[0] + (yv[1] - yv[0]) * (x - xv[0]) / (xv[1] - xv[0]));
  if (x >= xv[n - 1])
    return (yv[n - 1] + (yv[n - 2] - yv[n - 1]) * (x - xv[n - 1]) / (xv[n - 1] - xv[n - 2]));
  x1 = xv[0];
  y1 = yv[0];
  for (i = 1; i < n; i++) {
    if (x <= xv[i]) {
      x2 = xv[i];
      y2 = yv[i];
      dx = x2 - x1;
      dy = y2 - y1;
      return (y1 + dy * (x - x1) / dx);
    }
    x1 = xv[i];
    y1 = yv[i];
  }
  return (yv[n - 1]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lookupxy>:
  endbr64
  movsd  (%rsi),%xmm1
  comisd %xmm0,%xmm1
  jae    L58
  movslq %edi,%rcx
  lea    0x0(,%rcx,8),%r8
  movsd  -0x8(%rsi,%r8,1),%xmm3
  comisd %xmm3,%xmm0
  jae    L25
  movsd  (%rdx),%xmm3
  cmp    $0x1,%edi
  jle    L51
  mov    $0x1,%eax
  jmp    L14
  xchg   %ax,%ax
L9:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L51
L14:
  movapd %xmm1,%xmm4
  movsd  (%rsi,%rax,8),%xmm1
  movapd %xmm3,%xmm2
  movsd  (%rdx,%rax,8),%xmm3
  comisd %xmm0,%xmm1
  jb     L9
  subsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  ret
  xchg   %ax,%ax
L25:
  movsd  -0x8(%rdx,%r8,1),%xmm1
  movsd  -0x10(%rdx,%r8,1),%xmm2
  subsd  %xmm3,%xmm0
  subsd  -0x10(%rsi,%r8,1),%xmm3
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  movsd  (%rdx),%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  movsd  -0x8(%rdx,%r8,1),%xmm0
  ret
```

assistant: ```c
double lookupxy(double x, int n, double *xv, double *yv) {
  double dx, dy, x1, y1, x2, y2;
  int i;
  if (x <= xv[0])
    return (yv[0] + (yv[1] - yv[0]) * (x - xv[0]) / (xv[1] - xv[0]));
  if (x >= xv[n - 1])
    return (yv[n - 1] + (yv[n - 2] - yv[n - 1]) * (x - xv[n - 1]) / (xv[n - 1] - xv[n - 2]));
  x1 = xv[0];
  y1 = yv[0];
  for (i = 1; i < n; i++) {
    if (x <= xv[i]) {
      x2 = xv[i];
      y2 = yv[i];
      dx = x2 - x1;
      dy = y2 - y1;
      return (y1 + dy * (x - x1) / dx);
    }
    x1 = xv[i];
    y1 = yv[i];
  }
  return (yv[n - 1]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lookupxy>:
  endbr64
  movsd  (%rsi),%xmm1
  comisd %xmm0,%xmm1
  jae    L11
  movslq %edi,%rcx
  lea    0x0(,%rcx,8),%r8
  movsd  -0x8(%rsi,%r8,1),%xmm3
  comisd %xmm3,%xmm0
  jae    L48
  movsd  (%rdx),%xmm3
  cmp    $0x1,%edi
  jle    L15
  mov    $0x1,%eax
  jmp    L12
  xchg   %ax,%ax
L0:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L15
L12:
  movapd %xmm1,%xmm4
  movsd  (%rsi,%rax,8),%xmm1
  movapd %xmm3,%xmm2
  movsd  (%rdx,%rax,8),%xmm3
  comisd %xmm0,%xmm1
  jb     L0
  subsd  %xmm4,%xmm0
  subsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm1
  mulsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  ret
  xchg   %ax,%ax
L48:
  movsd  -0x8(%rdx,%r8,1),%xmm1
  movsd  -0x10(%rdx,%r8,1),%xmm2
  subsd  %xmm3,%xmm0
  subsd  -0x10(%rsi,%r8,1),%xmm3
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%rdx),%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  movsd  -0x8(%rdx,%r8,1),%xmm0
  ret
```

assistant: ```c
double lookupxy(double x, int n, double *xv, double *yv) {
  double dx, dy, x1, y1, x2, y2;
  int i;
  if (x <= xv[0])
    return (yv[0] + (yv[1] - yv[0]) * (x - xv[0]) / (xv[1] - xv[0]));
  if (x >= xv[n - 1])
    return (yv[n - 1] + (yv[n - 2] - yv[n - 1]) * (x - xv[n - 1]) / (xv[n - 1] - xv[n - 2]));
  x1 = xv[0];
  y1 = yv[0];
  for (i = 1; i < n; i++) {
    if (x <= xv[i]) {
      x2 = xv[i];
      y2 = yv[i];
      dx = x2 - x1;
      dy = y2 - y1;
      return (y1 + dy * (x - x1) / dx);
    }
    x1 = xv[i];
    y1 = yv[i];
  }
  return (yv[n - 1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_vdso>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L68
L53:
  mov    D1(%rip),%eax
  test   %eax,%eax
  je     L84
  mov    D56(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L84:
  movl   $0x1,D1(%rip)
  mov    $0x0,%eax
  call   <get_vdso_from_aliases@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L32
  mov    -0x8(%rbp),%rax
  mov    %rax,D7(%rip)
  mov    D7(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L32:
  mov    $0x0,%eax
  call   <get_vdso_from_auxv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L91
  mov    -0x8(%rbp),%rax
  mov    %rax,D7(%rip)
  mov    D7(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L91:
  mov    $0x0,%eax
  call   <get_vdso_from_maps@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L72
  mov    -0x8(%rbp),%rax
  mov    %rax,D7(%rip)
  mov    D7(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L68
L72:
  mov    $0x0,%eax
L68:
  leave
  ret
```

assistant: ```c
int is_vdso(struct link_map *map) {
  static int vdso_checked = 0;
  static struct link_map *vdso = NULL;
  struct link_map *result;
  if (!map)
    return 0;
  if (vdso_checked)
    return (map == vdso);
  vdso_checked = 1;
  result = get_vdso_from_aliases();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_auxv();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_maps();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_vdso>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rbx
  mov    D23(%rip),%ebp
  test   %ebp,%ebp
  je     L73
  cmp    %rdi,D34(%rip)
  sete   %bpl
  movzbl %bpl,%ebp
L41:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L73:
  movl   $0x1,D23(%rip)
  mov    $0x0,%eax
  call   <get_vdso_from_aliases@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,D21(%rip)
  cmp    %rax,%rbx
  sete   %bpl
  movzbl %bpl,%ebp
  jmp    L41
L27:
  mov    $0x0,%eax
  call   <get_vdso_from_auxv@plt>
  test   %rax,%rax
  je     L82
  mov    %rax,D21(%rip)
  cmp    %rax,%rbx
  sete   %bpl
  movzbl %bpl,%ebp
  jmp    L41
L82:
  mov    $0x0,%eax
  call   <get_vdso_from_maps@plt>
  test   %rax,%rax
  je     L41
  mov    %rax,D21(%rip)
  cmp    %rax,%rbx
  sete   %bpl
  movzbl %bpl,%ebp
  jmp    L41
L8:
  mov    $0x0,%ebp
  jmp    L41
```

assistant: ```c
int is_vdso(struct link_map *map) {
  static int vdso_checked = 0;
  static struct link_map *vdso = NULL;
  struct link_map *result;
  if (!map)
    return 0;
  if (vdso_checked)
    return (map == vdso);
  vdso_checked = 1;
  result = get_vdso_from_aliases();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_auxv();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_maps();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_vdso>:
  endbr64
  test   %rdi,%rdi
  je     L49
  mov    D24(%rip),%eax
  push   %rbx
  mov    %rdi,%rbx
  test   %eax,%eax
  je     L31
  xor    %eax,%eax
  cmp    %rdi,D20(%rip)
  pop    %rbx
  sete   %al
  ret
  nopl   (%rax)
L31:
  movl   $0x1,D24(%rip)
  xor    %eax,%eax
  call   <get_vdso_from_aliases@plt>
  test   %rax,%rax
  je     L21
L15:
  cmp    %rax,%rbx
  mov    %rax,D29(%rip)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L21:
  xor    %eax,%eax
  call   <get_vdso_from_auxv@plt>
  test   %rax,%rax
  jne    L15
  xor    %eax,%eax
  call   <get_vdso_from_maps@plt>
  test   %rax,%rax
  jne    L15
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_vdso(struct link_map *map) {
  static int vdso_checked = 0;
  static struct link_map *vdso = NULL;
  struct link_map *result;
  if (!map)
    return 0;
  if (vdso_checked)
    return (map == vdso);
  vdso_checked = 1;
  result = get_vdso_from_aliases();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_auxv();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_maps();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_vdso>:
  endbr64
  test   %rdi,%rdi
  je     L35
  mov    D36(%rip),%eax
  push   %rbx
  mov    %rdi,%rbx
  test   %eax,%eax
  je     L31
  xor    %eax,%eax
  cmp    %rdi,D34(%rip)
  pop    %rbx
  sete   %al
  ret
  nopl   (%rax)
L31:
  movl   $0x1,D36(%rip)
  xor    %eax,%eax
  call   <get_vdso_from_aliases@plt>
  test   %rax,%rax
  je     L0
L8:
  cmp    %rax,%rbx
  mov    %rax,D16(%rip)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L0:
  xor    %eax,%eax
  call   <get_vdso_from_auxv@plt>
  test   %rax,%rax
  jne    L8
  xor    %eax,%eax
  call   <get_vdso_from_maps@plt>
  test   %rax,%rax
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_vdso(struct link_map *map) {
  static int vdso_checked = 0;
  static struct link_map *vdso = NULL;
  struct link_map *result;
  if (!map)
    return 0;
  if (vdso_checked)
    return (map == vdso);
  vdso_checked = 1;
  result = get_vdso_from_aliases();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_auxv();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  result = get_vdso_from_maps();
  if (result) {
    vdso = result;
    return (map == vdso);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jle    L5
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L1
L32:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  addl   $0x2,-0x8(%rbp)
L1:
  cmpl   $0x0,-0xc(%rbp)
  je     L5
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L32
L5:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int isPrime(int num) {
  int result = 1, Div, DivMax = sqrt(num);
  if (num > 3) {
    result = num % 2;
    for (Div = 3; result && Div <= DivMax; Div += 2)
      result = num % Div;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<isPrime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%esi
  mov    $0x1,%eax
  cmp    $0x3,%ebx
  jle    L38
  test   $0x1,%bl
  je     L34
  mov    $0x3,%ecx
  cmp    $0x2,%esi
  jle    L34
L54:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  add    $0x2,%ecx
  test   %edx,%edx
  je     L38
  cmp    %ecx,%esi
  jge    L54
L38:
  pop    %rbx
  ret
L34:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  jmp    L38
```

assistant: ```c
int isPrime(int num) {
  int result = 1, Div, DivMax = sqrt(num);
  if (num > 3) {
    result = num % 2;
    for (Div = 3; result && Div <= DivMax; Div += 2)
      result = num % Div;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    $0x1,%edx
  cmp    $0x3,%r12d
  jle    L7
  mov    %r12d,%edx
  mov    %eax,%esi
  and    $0x1,%edx
  cmp    $0x2,%eax
  jle    L7
  test   %dl,%dl
  je     L7
  mov    $0x3,%ecx
  nop
L8:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  test   %edx,%edx
  je     L7
  cmp    %ecx,%esi
  jge    L8
L7:
  mov    %edx,%eax
  pop    %r12
  ret
```

assistant: ```c
int isPrime(int num) {
  int result = 1, Div, DivMax = sqrt(num);
  if (num > 3) {
    result = num % 2;
    for (Div = 3; result && Div <= DivMax; Div += 2)
      result = num % Div;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    $0x1,%edx
  cmp    $0x3,%r12d
  jle    L31
  mov    %r12d,%edx
  mov    %eax,%esi
  and    $0x1,%edx
  cmp    $0x2,%eax
  jle    L31
  test   %dl,%dl
  je     L31
  mov    $0x3,%ecx
  nop
L12:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  add    $0x2,%ecx
  test   %edx,%edx
  je     L31
  cmp    %ecx,%esi
  jge    L12
L31:
  mov    %edx,%eax
  pop    %r12
  ret
```

assistant: ```c
int isPrime(int num) {
  int result = 1, Div, DivMax = sqrt(num);
  if (num > 3) {
    result = num % 2;
    for (Div = 3; result && Div <= DivMax; Div += 2)
      result = num % Div;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fread_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,%edi
  call   <ignoreReturnValue@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int fread_int(FILE *fp) {
  int ret;
  ignoreReturnValue(fread(&ret, 4, 1, fp));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fread_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %eax,%edi
  call   <ignoreReturnValue@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fread_int(FILE *fp) {
  int ret;
  ignoreReturnValue(fread(&ret, 4, 1, fp));
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fread_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%edi
  call   <ignoreReturnValue@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fread_int(FILE *fp) {
  int ret;
  ignoreReturnValue(fread(&ret, 4, 1, fp));
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fread_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%edi
  call   <ignoreReturnValue@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fread_int(FILE *fp) {
  int ret;
  ignoreReturnValue(fread(&ret, 4, 1, fp));
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UARTTXIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x7200,-0x14(%rbp)
  jne    L4
  mov    $0x610902,%eax
  jmp    L19
L4:
  mov    $0x630904,%eax
L19:
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <IntRegister@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void UARTTXIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ;
  ui32Int = ((ui32Base == 0x00007200) ? 0x610902 : 0x630904);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UARTTXIntRegister>:
  endbr64
  push   %rbx
  cmp    $0x7200,%edi
  mov    $0x610902,%ebx
  mov    $0x630904,%eax
  cmovne %eax,%ebx
  mov    %ebx,%edi
  call   <IntRegister@plt>
  mov    %ebx,%edi
  call   <IntEnable@plt>
  pop    %rbx
  ret
```

assistant: ```c
void UARTTXIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ;
  ui32Int = ((ui32Base == 0x00007200) ? 0x610902 : 0x630904);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: What is the c source code of the assembly code below:

```asm
<UARTTXIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x7200,%edi
  mov    $0x630904,%eax
  mov    $0x610902,%ebp
  cmovne %eax,%ebp
  mov    %ebp,%edi
  call   <IntRegister@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void UARTTXIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ;
  ui32Int = ((ui32Base == 0x00007200) ? 0x610902 : 0x630904);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UARTTXIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x7200,%edi
  mov    $0x630904,%eax
  mov    $0x610902,%ebp
  cmovne %eax,%ebp
  mov    %ebp,%edi
  call   <IntRegister@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void UARTTXIntRegister(uint32_t ui32Base, void (*pfnHandler)(void)) {
  uint32_t ui32Int;
  ;
  ui32Int = ((ui32Base == 0x00007200) ? 0x610902 : 0x630904);
  IntRegister(ui32Int, pfnHandler);
  IntEnable(ui32Int);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decodeStringXRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  shr    $0x5,%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%eax
  cmp    %rax,-0x30(%rbp)
  jbe    L34
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L39
L36:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  shl    $0x5,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <num2wordRC@plt>
  subl   $0x1,-0x14(%rbp)
L39:
  cmpl   $0x0,-0x14(%rbp)
  jns    L36
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <num2wordRC@plt>
  mov    -0x30(%rbp),%rax
  and    $0x1f,%eax
  mov    %eax,%ebx
  test   %ebx,%ebx
  jne    L14
  mov    $0x20,%ebx
L14:
  movslq %ebx,%rax
  mov    $0x20,%edx
  sub    %rax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x40(%rbp),%rax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *decodeStringXRC(uint64_t *Seq, uint16_t length, char *word, char *newString) {
  newString[length] = 0;
  unsigned clumps = length / 32;
  if (32 * clumps < length)
    ++clumps;
  int z = clumps - 2;
  for (; z > -1; z--)
    num2wordRC(Seq[z], newString + length - (z + 1) * 32);
  num2wordRC(Seq[clumps - 1], word);
  register int fold = length % 32;
  if (!fold)
    fold = 32;
  memcpy(newString, word + 32 - fold, fold);
  return newString;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decodeStringXRC>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r14
  movb   $0x0,(%rcx,%rsi,1)
  mov    %rsi,%r15
  shr    $0x5,%r15
  mov    %rsi,%rax
  and    $0xffffffe0,%eax
  cmp    %rsi,%rax
  adc    $0x0,%r15d
  mov    %r15d,%ebx
  sub    $0x2,%ebx
  js     L9
  movslq %ebx,%rbx
  lea    -0x1(%r15),%eax
  shl    $0x5,%eax
  cltq
  mov    %rsi,%rbp
  sub    %rax,%rbp
  add    %rcx,%rbp
L19:
  mov    0x0(%r13,%rbx,4),%edi
  mov    %rbp,%rsi
  call   <num2wordRC@plt>
  sub    $0x1,%rbx
  add    $0x20,%rbp
  test   %ebx,%ebx
  jns    L19
L9:
  lea    -0x1(%r15),%eax
  mov    0x0(%r13,%rax,4),%edi
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rsi
  call   <num2wordRC@plt>
  mov    %r12d,%edx
  and    $0x1f,%edx
  mov    $0x20,%eax
  cmove  %eax,%edx
  movslq %edx,%rcx
  mov    %rbx,%rax
  sub    %rcx,%rax
  lea    0x20(%rax),%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *decodeStringXRC(uint64_t *Seq, uint16_t length, char *word, char *newString) {
  newString[length] = 0;
  unsigned clumps = length / 32;
  if (32 * clumps < length)
    ++clumps;
  int z = clumps - 2;
  for (; z > -1; z--)
    num2wordRC(Seq[z], newString + length - (z + 1) * 32);
  num2wordRC(Seq[clumps - 1], word);
  register int fold = length % 32;
  if (!fold)
    fold = 32;
  memcpy(newString, word + 32 - fold, fold);
  return newString;
}
```