ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    %rsp,%rbp
  movl   $0x7,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <rotate3@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D44
data_type: string
name: parse_data
arguments: data_label: D4
data_type: byte[16]
name: parse_data
arguments: data_label: D17
data_type: byte[8]
name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string

tool: D44: Origin:


tool: {"D4": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D17": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D7: 


tool: D24: After rotating:


assistant: ```c
int main(void) {
  int size, k;
  int nums[] = {1, 2, 3, 4, 5, 6, 7};
  size = sizeof(nums) / sizeof(int);
  printf("Origin:\n");
  print_array(nums, size);
  printf("\n");
  k = 5;
  rotate3(nums, size, k);
  printf("After rotating:\n");
  print_array(nums, size);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ftpmap_draw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L10:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L10
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: D19: +

tool: D16: +


assistant: ```c
void ftpmap_draw(int ch, int times) {
  int i = 0;
  printf("+");
  for (i = 0; i <= times; i++) {
    putchar(ch);
  }
  printf("+\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ftpmap_draw>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  js     L6
  mov    $0x0,%ebx
L14:
  mov    %r12d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L14
L6:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D18: +

tool: D5: +


assistant: ```c
void ftpmap_draw(int ch, int times) {
  int i = 0;
  printf("+");
  for (i = 0; i <= times; i++) {
    putchar(ch);
  }
  printf("+\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<ftpmap_draw>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D10(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  js     L17
  xor    %ebx,%ebx
  nop
L6:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L6
L17:
  pop    %rbx
  lea    D16(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D16
data_type: string

tool: D10: +

tool: D16: +


assistant: ```c
void ftpmap_draw(int ch, int times) {
  int i = 0;
  printf("+");
  for (i = 0; i <= times; i++) {
    putchar(ch);
  }
  printf("+\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<ftpmap_draw>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D6(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <printf@plt>
  test   %ebp,%ebp
  js     L8
  xor    %ebx,%ebx
  nop
L16:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L16
L8:
  pop    %rbx
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string

tool: D6: +

tool: D15: +


assistant: ```c
void ftpmap_draw(int ch, int times) {
  int i = 0;
  printf("+");
  for (i = 0; i <= times; i++) {
    putchar(ch);
  }
  printf("+\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <create_matrix@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy_matrix@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(char argc, char **argv) {
  int **matrix;
  int rows, cols, init;
  rows = 3;
  cols = 4;
  init = 5;
  matrix = create_matrix(rows, cols, init);
  destroy_matrix(matrix);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <create_matrix@plt>
  mov    %rax,%rdi
  call   <destroy_matrix@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(char argc, char **argv) {
  int **matrix;
  int rows, cols, init;
  rows = 3;
  cols = 4;
  init = 5;
  matrix = create_matrix(rows, cols, init);
  destroy_matrix(matrix);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <create_matrix@plt>
  mov    %rax,%rdi
  call   <destroy_matrix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(char argc, char **argv) {
  int **matrix;
  int rows, cols, init;
  rows = 3;
  cols = 4;
  init = 5;
  matrix = create_matrix(rows, cols, init);
  destroy_matrix(matrix);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <create_matrix@plt>
  mov    %rax,%rdi
  call   <destroy_matrix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(char argc, char **argv) {
  int **matrix;
  int rows, cols, init;
  rows = 3;
  cols = 4;
  init = 5;
  matrix = create_matrix(rows, cols, init);
  destroy_matrix(matrix);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_anagram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0xe0(%rbp),%rax
  mov    $0x68,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0xe0(%rbp),%rdx
  mov    -0xf8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fill_buckets@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x100(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fill_buckets@plt>
  movl   $0x0,-0xe4(%rbp)
  jmp    L28
L47:
  mov    -0xe4(%rbp),%eax
  mov    -0xe0(%rbp,%rax,4),%edx
  mov    -0xe4(%rbp),%eax
  mov    -0x70(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  je     L38
  mov    $0x0,%eax
  jmp    L13
L38:
  addl   $0x1,-0xe4(%rbp)
L28:
  cmpl   $0x19,-0xe4(%rbp)
  jbe    L47
  mov    $0x1,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int is_anagram(char const *str, char const *other) {
  int bucket[26];
  int other_bucket[26] = {0};
  unsigned int index;
  memset(bucket, 0, 26 * sizeof(int));
  fill_buckets(str, bucket);
  fill_buckets(other, other_bucket);
  for (index = 0; index < 26; index++) {
    if (bucket[index] != other_bucket[index])
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_anagram>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%r12
  mov    $0x68,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fill_buckets@plt>
  lea    0x70(%rsp),%rsi
  mov    %rbx,%rdi
  call   <fill_buckets@plt>
  mov    $0x0,%eax
  lea    0x70(%rsp),%rdx
L35:
  mov    (%rdx,%rax,1),%ecx
  cmp    %ecx,(%rsp,%rax,1)
  jne    L28
  add    $0x4,%rax
  cmp    $0x68,%rax
  jne    L35
  mov    $0x1,%eax
  jmp    L2
L28:
  mov    $0x0,%eax
L2:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_anagram(char const *str, char const *other) {
  int bucket[26];
  int other_bucket[26] = {0};
  unsigned int index;
  memset(bucket, 0, 26 * sizeof(int));
  fill_buckets(str, bucket);
  fill_buckets(other, other_bucket);
  for (index = 0; index < 26; index++) {
    if (bucket[index] != other_bucket[index])
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_anagram>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  mov    $0x68,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x70(%rsp),%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  lea    0x70(%rsp),%rbp
  call   <fill_buckets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fill_buckets@plt>
  xor    %eax,%eax
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x4,%rax
  cmp    $0x68,%rax
  je     L13
L12:
  mov    0x0(%rbp,%rax,1),%edx
  cmp    %edx,(%rbx,%rax,1)
  je     L2
  xor    %eax,%eax
L47:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x1,%eax
  jmp    L47
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_anagram(char const *str, char const *other) {
  int bucket[26];
  int other_bucket[26] = {0};
  unsigned int index;
  memset(bucket, 0, 26 * sizeof(int));
  fill_buckets(str, bucket);
  fill_buckets(other, other_bucket);
  for (index = 0; index < 26; index++) {
    if (bucket[index] != other_bucket[index])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_anagram>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  mov    $0x68,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x70(%rsp),%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  lea    0x70(%rsp),%rbp
  call   <fill_buckets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fill_buckets@plt>
  xor    %eax,%eax
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x4,%rax
  cmp    $0x68,%rax
  je     L34
L41:
  mov    0x0(%rbp,%rax,1),%edx
  cmp    %edx,(%rbx,%rax,1)
  je     L37
  xor    %eax,%eax
L0:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  mov    $0x1,%eax
  jmp    L0
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_anagram(char const *str, char const *other) {
  int bucket[26];
  int other_bucket[26] = {0};
  unsigned int index;
  memset(bucket, 0, 26 * sizeof(int));
  fill_buckets(str, bucket);
  fill_buckets(other, other_bucket);
  for (index = 0; index < 26; index++) {
    if (bucket[index] != other_bucket[index])
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getRegex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L3:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L49
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  jmp    L45
L49:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L30
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  jmp    L45
L30:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
L45:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jb     L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D19: \w

tool: D3: \d

tool: D0: \S

assistant: ```c
char *getRegex(char *match) {
  char *regex = (char *)malloc(strlen(match) * 2);
  for (unsigned i = 0; i < strlen(match); i++) {
    if (isalpha(match[i])) {
      strncat(regex, "\\w", 2);
    } else if (isdigit(match[i])) {
      strncat(regex, "\\d", 2);
    } else {
      strncat(regex, "\\S", 2);
    }
  }
  return regex;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getRegex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebp
  lea    D16(%rip),%r15
  lea    D28(%rip),%r14
  jmp    L2
L7:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L12
  mov    $0x2,%edx
  lea    D7(%rip),%rsi
  mov    %r13,%rdi
  call   <strncat@plt>
L42:
  add    $0x1,%ebp
L2:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jbe    L55
  mov    %ebp,%ebx
  add    %r12,%rbx
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L7
  mov    $0x2,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncat@plt>
  jmp    L42
L12:
  mov    $0x2,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strncat@plt>
  jmp    L42
L55:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D7
datatype: string

tool: D16: \S

tool: D28: \w

tool: D7: \d

assistant: ```c
char *getRegex(char *match) {
  char *regex = (char *)malloc(strlen(match) * 2);
  for (unsigned i = 0; i < strlen(match); i++) {
    if (isalpha(match[i])) {
      strncat(regex, "\\w", 2);
    } else if (isdigit(match[i])) {
      strncat(regex, "\\d", 2);
    } else {
      strncat(regex, "\\S", 2);
    }
  }
  return regex;
}
```
user: What is the c source code of the assembly code below?

```asm
<getRegex>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0x2,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
L15:
  add    $0x1,%ebx
L33:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L17
  mov    %ebx,%edx
  lea    0x0(%rbp,%rdx,1),%r14
  movsbl (%r14),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L39
  movsbl (%r14),%edi
  call   <isdigit@plt>
  mov    $0x2,%edx
  test   %rax,%rax
  je     L20
  lea    D20(%rip),%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  jmp    L15
  nopl   (%rax)
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D7: \S

tool: D26: \w

tool: D20: \d

assistant: ```c
char *getRegex(char *match) {
  char *regex = (char *)malloc(strlen(match) * 2);
  for (unsigned i = 0; i < strlen(match); i++) {
    if (isalpha(match[i])) {
      strncat(regex, "\\w", 2);
    } else if (isdigit(match[i])) {
      strncat(regex, "\\d", 2);
    } else {
      strncat(regex, "\\S", 2);
    }
  }
  return regex;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getRegex>:
  endbr64
  push   %r15
  lea    D29(%rip),%r15
  push   %r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0x2,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
L37:
  add    $0x1,%ebx
L34:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L36
  mov    %ebx,%edx
  lea    0x0(%rbp,%rdx,1),%r14
  movsbl (%r14),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L42
  movsbl (%r14),%edi
  call   <isdigit@plt>
  mov    $0x2,%edx
  test   %rax,%rax
  je     L35
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  jmp    L37
  nopl   (%rax)
L36:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D29: \S

tool: D4: \w

tool: D10: \d

assistant: ```c
char *getRegex(char *match) {
  char *regex = (char *)malloc(strlen(match) * 2);
  for (unsigned i = 0; i < strlen(match); i++) {
    if (isalpha(match[i])) {
      strncat(regex, "\\w", 2);
    } else if (isdigit(match[i])) {
      strncat(regex, "\\d", 2);
    } else {
      strncat(regex, "\\S", 2);
    }
  }
  return regex;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shrq   %cl,-0x8(%rbp)
  cmpl   $0x3e,-0xc(%rbp)
  jbe    L10
  mov    $0xffffffff,%eax
  jmp    L5
L10:
  andq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int get_bit(unsigned long int n, unsigned int index) {
  n = n >> index;
  if (index >= 63)
    return (-1);
  n = n % 2;
  return (n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_bit>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%rdi
  cmp    $0x3e,%esi
  ja     L8
  mov    %edi,%eax
  and    $0x1,%eax
  ret
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_bit(unsigned long int n, unsigned int index) {
  n = n >> index;
  if (index >= 63)
    return (-1);
  n = n % 2;
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_bit>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%rdi
  cmp    $0x3e,%esi
  ja     L3
  mov    %edi,%eax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_bit(unsigned long int n, unsigned int index) {
  n = n >> index;
  if (index >= 63)
    return (-1);
  n = n % 2;
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_bit>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%rdi
  cmp    $0x3e,%esi
  ja     L0
  mov    %edi,%eax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_bit(unsigned long int n, unsigned int index) {
  n = n >> index;
  if (index >= 63)
    return (-1);
  n = n % 2;
  return (n);
}
```