user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L90:
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x7f0(%rbp),%rdx
  lea    -0x7f4(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x7f4(%rbp),%eax
  test   %eax,%eax
  jne    L92
  mov    -0x7f0(%rbp),%eax
  test   %eax,%eax
  je     L56
L92:
  mov    -0x7f4(%rbp),%eax
  mov    %eax,-0x7ec(%rbp)
  jmp    L83
L166:
  cmpl   $0x1,-0x7ec(%rbp)
  jle    L78
  movl   $0x1,-0x7e4(%rbp)
  movl   $0x2,-0x7e8(%rbp)
  jmp    L95
L66:
  mov    -0x7ec(%rbp),%eax
  cltd
  idivl  -0x7e8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L65
  movl   $0x0,-0x7e4(%rbp)
  jmp    L39
L65:
  addl   $0x1,-0x7e8(%rbp)
L95:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x7ec(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x7e8(%rbp)
  jle    L66
L39:
  cmpl   $0x1,-0x7e4(%rbp)
  jne    L78
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  mov    -0x7ec(%rbp),%edx
  mov    %edx,-0x7e0(%rbp,%rax,4)
L78:
  addl   $0x1,-0x7ec(%rbp)
L83:
  mov    -0x7f0(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x7ec(%rbp)
  jne    L166
  movl   $0x0,-0x7ec(%rbp)
  jmp    L88
L26:
  mov    -0x7ec(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x7e8(%rbp)
  jmp    L159
L116:
  mov    -0x7e8(%rbp),%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%edx
  mov    -0x7ec(%rbp),%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  jg     L3
  mov    -0x7e8(%rbp),%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%edx
  mov    -0x7ec(%rbp),%eax
  cltq
  mov    -0x7e0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L3:
  addl   $0x1,-0x7e8(%rbp)
L159:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x7e8(%rbp)
  jl     L116
  addl   $0x1,-0x7ec(%rbp)
L88:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x7ec(%rbp)
  jl     L26
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L90
L56:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string

tool: D10: %d,%d

tool: D3: %d %d


tool: D21: %d


assistant: ```c
int main() {
  int n, m, i, j, flag, num[500];
  do {
    num[498] = 0;
    num[499] = 0;
    scanf("%d,%d", &n, &m);
    if (n == 0 && m == 0)
      break;
    for (i = n; i != m + 1; ++i) {
      if (i > 1) {
        flag = 1;
        for (j = 2; j <= (int)sqrt(i * 1.0); ++j)
          if (i % j == 0) {
            flag = 0;
            break;
          }
        if (flag == 1)
          num[num[499]++] = i;
      }
    }
    for (i = 0; i < num[499] - 1; ++i)
      for (j = i + 1; j < num[499]; ++j)
        if (num[j] - num[i] <= 2) {
          printf("%d %d\n", num[i], num[j]);
          ++num[498];
        }
    printf("%d\n", num[498]);
  } while (1);
  return 0;
}
```