ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<num_active_dice>:
  endbr64
  cmpl   $0xffffffff,(%rdi)
  je     L8
  cmpl   $0xffffffff,0x4(%rdi)
  je     L16
  cmpl   $0xffffffff,0x8(%rdi)
  je     L6
  cmpl   $0xffffffff,0xc(%rdi)
  je     L29
  cmpl   $0xffffffff,0x10(%rdi)
  je     L43
  xor    %eax,%eax
  cmpl   $0xffffffff,0x14(%rdi)
  setne  %al
  add    $0x5,%eax
  ret
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x2,%eax
  ret
L29:
  mov    $0x3,%eax
  ret
L43:
  mov    $0x4,%eax
  ret
```

assistant: ```c
int num_active_dice(int *dice) {
  int i;
  for (i = 0; i < 6; i++) {
    if (dice[i] == -1) {
      return i;
    }
  }
  return 6;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<close_full_2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x1,-0x4(%rbp)
  jle    L10
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void close_full_2D(float **wt_tensor, float **v, float *w, double *rv1) {
  int z;
  for (z = 0; z < 2; z++) {
    free((void *)wt_tensor[z]);
    free((void *)v[z]);
  }
  free(w);
  free(rv1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<close_full_2D>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    0x8(%rbp),%rdi
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void close_full_2D(float **wt_tensor, float **v, float *w, double *rv1) {
  int z;
  for (z = 0; z < 2; z++) {
    free((void *)wt_tensor[z]);
    free((void *)v[z]);
  }
  free(w);
  free(rv1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<close_full_2D>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    0x8(%rbp),%rdi
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void close_full_2D(float **wt_tensor, float **v, float *w, double *rv1) {
  int z;
  for (z = 0; z < 2; z++) {
    free((void *)wt_tensor[z]);
    free((void *)v[z]);
  }
  free(w);
  free(rv1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<close_full_2D>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    0x8(%rbp),%rdi
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void close_full_2D(float **wt_tensor, float **v, float *w, double *rv1) {
  int z;
  for (z = 0; z < 2; z++) {
    free((void *)wt_tensor[z]);
    free((void *)v[z]);
  }
  free(w);
  free(rv1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <ex6@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: LISTA DE FDA 07


assistant: ```c
int main() {
  printf("LISTA DE FDA 07\n");
  srand(time(NULL));
  ex6();
  getchar();
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <ex6@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: LISTA DE FDA 07


assistant: ```c
int main() {
  printf("LISTA DE FDA 07\n");
  srand(time(NULL));
  ex6();
  getchar();
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <ex6@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: LISTA DE FDA 07


assistant: ```c
int main() {
  printf("LISTA DE FDA 07\n");
  srand(time(NULL));
  ex6();
  getchar();
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <ex6@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: LISTA DE FDA 07


assistant: ```c
int main() {
  printf("LISTA DE FDA 07\n");
  srand(time(NULL));
  ex6();
  getchar();
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_u16_from_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  leave
  ret
```

assistant: ```c
uint16_t read_u16_from_buffer(const char *read) {
  uint16_t n_u16 = *((uint16_t *)read);
  return ntohs(n_u16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_u16_from_buffer>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <ntohs@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t read_u16_from_buffer(const char *read) {
  uint16_t n_u16 = *((uint16_t *)read);
  return ntohs(n_u16);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_u16_from_buffer>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <ntohs@plt>
```

assistant: ```c
uint16_t read_u16_from_buffer(const char *read) {
  uint16_t n_u16 = *((uint16_t *)read);
  return ntohs(n_u16);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_u16_from_buffer>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <ntohs@plt>
```

assistant: ```c
uint16_t read_u16_from_buffer(const char *read) {
  uint16_t n_u16 = *((uint16_t *)read);
  return ntohs(n_u16);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movl   $0x3e8,-0x40(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D29(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x320,-0x3c(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  divsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%edx
  mov    -0x10(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <initial_condition@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L11
L12:
  mov    -0x18(%rbp),%rsi
  mov    -0x40(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <update_u@plt>
  mov    -0x40(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  addl   $0x1,-0x44(%rbp)
L11:
  mov    -0x44(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L12
  mov    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_u@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: f64
name: unpack_data
arguments: tag: D29
type_guessed: byte[8]
name: unpack_data
arguments: tag: D5
type_guessed: f64

tool: D26: 2

tool: {"D29": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D5: 1

assistant: ```c
int main() {
  double x_f = 2.0;
  int n_x = 1000;
  double delta_x = x_f / n_x;
  double delta_t = 1E-3;
  int n_t = 800.0;
  double c = 1.0;
  double r = c * delta_t / delta_x;
  double *u_past = malloc(n_x * sizeof(double));
  double *u_present = malloc(n_x * sizeof(double));
  initial_condition(u_past, n_x, delta_x);
  int i;
  for (i = 0; i < n_t; i++) {
    update_u(u_present, u_past, n_x, r);
    copy(u_present, u_past, n_x);
  }
  print_u(u_present, n_x, delta_x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1f40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movsd  D22(%rip),%xmm0
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <initial_condition@plt>
  mov    $0x320,%ebx
L3:
  mov    D18(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <update_u@plt>
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  sub    $0x1,%ebx
  jne    L3
  movsd  D22(%rip),%xmm0
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <print_u@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
data_type: byte[8]
name: unpack_data
arguments: label: D18
data_type: byte[8]

tool: {"D22": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x60,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double x_f = 2.0;
  int n_x = 1000;
  double delta_x = x_f / n_x;
  double delta_t = 1E-3;
  int n_t = 800.0;
  double c = 1.0;
  double r = c * delta_t / delta_x;
  double *u_past = malloc(n_x * sizeof(double));
  double *u_present = malloc(n_x * sizeof(double));
  initial_condition(u_past, n_x, delta_x);
  int i;
  for (i = 0; i < n_t; i++) {
    update_u(u_present, u_past, n_x, r);
    copy(u_present, u_past, n_x);
  }
  print_u(u_present, n_x, delta_x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1f40,%edi
  push   %rbp
  push   %rbx
  mov    $0x320,%ebx
  call   <malloc@plt>
  mov    $0x1f40,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    D1(%rip),%rax
  movq   %rax,%xmm0
  call   <initial_condition@plt>
L5:
  mov    D19(%rip),%rax
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <update_u@plt>
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    D1(%rip),%rax
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  movq   %rax,%xmm0
  call   <print_u@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D19
datatype: byte[8]

tool: {"D1": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x60,0x3f]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double x_f = 2.0;
  int n_x = 1000;
  double delta_x = x_f / n_x;
  double delta_t = 1E-3;
  int n_t = 800.0;
  double c = 1.0;
  double r = c * delta_t / delta_x;
  double *u_past = malloc(n_x * sizeof(double));
  double *u_present = malloc(n_x * sizeof(double));
  initial_condition(u_past, n_x, delta_x);
  int i;
  for (i = 0; i < n_t; i++) {
    update_u(u_present, u_past, n_x, r);
    copy(u_present, u_past, n_x);
  }
  print_u(u_present, n_x, delta_x);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1f40,%edi
  push   %rbp
  push   %rbx
  mov    $0x320,%ebx
  call   <malloc@plt>
  mov    $0x1f40,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    D26(%rip),%rax
  movq   %rax,%xmm0
  call   <initial_condition@plt>
L9:
  mov    D13(%rip),%rax
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <update_u@plt>
  mov    $0x3e8,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    D26(%rip),%rax
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  movq   %rax,%xmm0
  call   <print_u@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
datatype: byte[8]
name: parse_data
arguments: data_tag: D13
datatype: byte[8]

tool: {"D26": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x60,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  double x_f = 2.0;
  int n_x = 1000;
  double delta_x = x_f / n_x;
  double delta_t = 1E-3;
  int n_t = 800.0;
  double c = 1.0;
  double r = c * delta_t / delta_x;
  double *u_past = malloc(n_x * sizeof(double));
  double *u_present = malloc(n_x * sizeof(double));
  initial_condition(u_past, n_x, delta_x);
  int i;
  for (i = 0; i < n_t; i++) {
    update_u(u_present, u_past, n_x, r);
    copy(u_present, u_past, n_x);
  }
  print_u(u_present, n_x, delta_x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uint_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x100,-0x4(%rbp)
  movl   $0x100,-0x4(%rbp)
  jmp    L29
L8:
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x8,-0x8(%rbp)
  je     L21
  shll   $0x8,-0x4(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L8
  jmp    L19
L21:
  nop
L19:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int uint_size(uint64_t value) {
  int size = 1;
  uint64_t max_value = 1 << 8;
  for (max_value = 1 << 8; value >= max_value; max_value <<= 8) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uint_size>:
  endbr64
  mov    $0x2,%eax
  mov    $0x100,%edx
  cmp    $0xff,%edi
  jle    L23
L12:
  shl    $0x8,%edx
  cmp    %edx,%edi
  jl     L27
  add    $0x1,%eax
  cmp    $0x8,%eax
  jne    L12
L27:
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uint_size(uint64_t value) {
  int size = 1;
  uint64_t max_value = 1 << 8;
  for (max_value = 1 << 8; value >= max_value; max_value <<= 8) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uint_size>:
  endbr64
  mov    $0x2,%eax
  mov    $0x100,%edx
  cmp    $0xff,%edi
  jle    L12
L24:
  shl    $0x8,%edx
  cmp    %edx,%edi
  jl     L14
  add    $0x1,%eax
  cmp    $0x8,%eax
  jne    L24
L14:
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uint_size(uint64_t value) {
  int size = 1;
  uint64_t max_value = 1 << 8;
  for (max_value = 1 << 8; value >= max_value; max_value <<= 8) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uint_size>:
  endbr64
  cmp    $0xff,%edi
  jle    L15
  cmp    $0xffff,%edi
  jle    L17
  xor    %eax,%eax
  cmp    $0xffffff,%edi
  setg   %al
  lea    0x3(%rax,%rax,4),%eax
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x1,%eax
  ret
L17:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int uint_size(uint64_t value) {
  int size = 1;
  uint64_t max_value = 1 << 8;
  for (max_value = 1 << 8; value >= max_value; max_value <<= 8) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cbmap_default_allocator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L5
L0:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
void *cbmap_default_allocator(void *data, size_t data_len) {
  void *data_copy = malloc((data_len));
  if (data_copy == NULL) {
    return NULL;
  }
  memcpy(data_copy, data, data_len);
  return data_copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cbmap_default_allocator>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L4:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *cbmap_default_allocator(void *data, size_t data_len) {
  void *data_copy = malloc((data_len));
  if (data_copy == NULL) {
    return NULL;
  }
  memcpy(data_copy, data, data_len);
  return data_copy;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cbmap_default_allocator>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *cbmap_default_allocator(void *data, size_t data_len) {
  void *data_copy = malloc((data_len));
  if (data_copy == NULL) {
    return NULL;
  }
  memcpy(data_copy, data, data_len);
  return data_copy;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cbmap_default_allocator>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *cbmap_default_allocator(void *data, size_t data_len) {
  void *data_copy = malloc((data_len));
  if (data_copy == NULL) {
    return NULL;
  }
  memcpy(data_copy, data, data_len);
  return data_copy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  jmp    L9
L67:
  mov    -0x3c(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
L9:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L67
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L73
L30:
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x30(%rbp,%rdx,4),%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp,%rdx,4)
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x38(%rbp)
L73:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jne    L30
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L46
L38:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jle    L70
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L70:
  addl   $0x1,-0x3c(%rbp)
L46:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L38
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
type: string
name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D21
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D43
type: string

tool: D31: 
Vavedi chislo:

tool: D8: %lli

tool: D21: 
Tsifrite, koito se povtariat sa: 

tool: D34: %d, 

tool: D43: .

assistant: ```c
void main() {
  int i, a[10];
  long long int n;
  for (i = 0; i < 10; i++)
    a[i] = 0;
  printf("\nVavedi chislo:");
  scanf("%lli", &n);
  while (n != 0) {
    a[n % 10]++;
    n /= 10;
  }
  printf("\nTsifrite, koito se povtariat sa: ");
  for (i = 0; i < 10; i++)
    if (a[i] > 1)
      printf("%d, ", i);
  printf("\b\b.");
}
```