ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<pasm_clean_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L210
  cmp    $0x20,%al
  jne    L65
  cs nopw 0x0(%rax,%rax,1)
L210:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    $0x20,%al
  je     L210
  cmp    $0x9,%al
  je     L210
L65:
  mov    %r12,%rdi
  xor    %ebp,%ebp
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L136
L207:
  movzbl (%r12,%rbp,1),%eax
  lea    0x1(%rbp),%rdx
  cmp    $0x3b,%al
  je     L82
  cmp    $0x23,%al
  je     L82
  mov    %rdx,%rbp
L136:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L207
  movslq %ebx,%rax
  add    %r12,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L153
  cmp    $0x9,%dl
  jne    L197
L153:
  cmp    %r12,%rax
  jbe    L197
L165:
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  test   $0xdf,%dl
  je     L27
  cmp    $0x9,%dl
  jne    L197
L27:
  cmp    %r12,%rax
  jne    L165
L191:
  movb   $0x0,(%r12)
L146:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L197:
  movb   $0x0,(%rax)
  cmp    %rax,%r12
  je     L146
L6:
  mov    %r12,%rcx
  jmp    L12
  nopl   (%rax)
L129:
  sub    $0x9,%edx
  cmp    $0x1,%dl
  ja     L142
  movb   $0x20,(%rcx)
L142:
  add    $0x1,%rcx
  cmp    %rax,%rcx
  je     L146
L12:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L129
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L82:
  lea    -0x1(%r12,%rbp,1),%rax
  cmp    %r12,%rax
  jbe    L191
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L165
  cmp    $0x9,%dl
  je     L165
  movb   $0x0,(%rax)
  jmp    L6
```

assistant: ```c
char *pasm_clean_line(char *str) {
  while (*str == ' ' || *str == '\t')
    str++;
  char *end = str + strlen(str);
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == ';' || str[i] == '#') {
      end = str + i - 1;
      if (end <= str) {
        *str = 0;
        return str;
      }
      break;
    }
  }
  while ((!*end || *end == ' ' || *end == '\t') && end > str) {
    end--;
  }
  *end = 0;
  for (char *c = str; c != end && *c; c++) {
    if (*c == '\t' || *c == '\n') {
      *c = ' ';
    }
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pasm_clean_line>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L65
  cmp    $0x20,%al
  jne    L200
  cs nopw 0x0(%rax,%rax,1)
L65:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    $0x20,%al
  je     L65
  cmp    $0x9,%al
  je     L65
L200:
  mov    %r12,%rdi
  xor    %ebp,%ebp
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L92
L224:
  movzbl (%r12,%rbp,1),%eax
  lea    0x1(%rbp),%rdx
  cmp    $0x3b,%al
  je     L48
  cmp    $0x23,%al
  je     L48
  mov    %rdx,%rbp
L92:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L224
  movslq %ebx,%rax
  add    %r12,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L148
  cmp    $0x9,%dl
  jne    L197
L148:
  cmp    %r12,%rax
  jbe    L197
L217:
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  test   $0xdf,%dl
  je     L110
  cmp    $0x9,%dl
  jne    L197
L110:
  cmp    %r12,%rax
  jne    L217
L228:
  movb   $0x0,(%r12)
L73:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L197:
  movb   $0x0,(%rax)
  cmp    %rax,%r12
  je     L73
L102:
  mov    %r12,%rcx
  jmp    L16
  nopl   (%rax)
L60:
  sub    $0x9,%edx
  cmp    $0x1,%dl
  ja     L86
  movb   $0x20,(%rcx)
L86:
  add    $0x1,%rcx
  cmp    %rax,%rcx
  je     L73
L16:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L60
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  lea    -0x1(%r12,%rbp,1),%rax
  cmp    %r12,%rax
  jbe    L228
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L217
  cmp    $0x9,%dl
  je     L217
  movb   $0x0,(%rax)
  jmp    L102
```

assistant: ```c
char *pasm_clean_line(char *str) {
  while (*str == ' ' || *str == '\t')
    str++;
  char *end = str + strlen(str);
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == ';' || str[i] == '#') {
      end = str + i - 1;
      if (end <= str) {
        *str = 0;
        return str;
      }
      break;
    }
  }
  while ((!*end || *end == ' ' || *end == '\t') && end > str) {
    end--;
  }
  *end = 0;
  for (char *c = str; c != end && *c; c++) {
    if (*c == '\t' || *c == '\n') {
      *c = ' ';
    }
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sock_receive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L10
L29:
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L10
  mov    -0x4(%rbp),%eax
  jmp    L9
L10:
  mov    -0x38(%rbp),%r8
  mov    -0x30(%rbp),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L29
  mov    -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *srcaddrlen) {
  int n;
  *srcaddrlen = sizeof(struct sockaddr);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, srcaddrlen)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sock_receive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %r8,%rbx
  mov    %r9,%rbp
  movl   $0x4,(%r9)
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %r8,%rdi
  call   <memset@plt>
L7:
  mov    %rbp,%r9
  mov    %rbx,%r8
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  jns    L19
  mov    D17(%rip),%rcx
  mov    D9(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L7
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *srcaddrlen) {
  int n;
  *srcaddrlen = sizeof(struct sockaddr);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, srcaddrlen)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sock_receive>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %r8,%rdi
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  movl   $0x4,(%r9)
  call   <memset@plt>
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L17:
  mov    D19(%rip),%rdx
  mov    D15(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L25
L5:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  js     L17
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *srcaddrlen) {
  int n;
  *srcaddrlen = sizeof(struct sockaddr);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, srcaddrlen)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_receive>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %r8,%rdi
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  movl   $0x4,(%r9)
  call   <memset@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L3:
  mov    D12(%rip),%rdx
  mov    D2(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L25
L23:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  js     L3
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *srcaddrlen) {
  int n;
  *srcaddrlen = sizeof(struct sockaddr);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, srcaddrlen)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L44
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L15
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  jmp    L6
L15:
  cmpl   $0x0,-0x8(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L6
L58:
  subq   $0x1,-0x28(%rbp)
L44:
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((pure)) strncmp(const char *s1, const char *s2, size_t n) {
  unsigned int a, b;
  while (n != 0) {
    a = *s1++;
    b = *s2++;
    if (a != b)
      return a - b;
    if (a == '\0')
      return 0;
    n--;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncmp>:
  endbr64
  test   %rdx,%rdx
  je     L32
  mov    $0x0,%ecx
L4:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8d,%eax
  jne    L37
  test   %eax,%eax
  je     L16
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L4
  mov    $0x0,%eax
  ret
L37:
  sub    %r8d,%eax
  ret
L32:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __attribute__((pure)) strncmp(const char *s1, const char *s2, size_t n) {
  unsigned int a, b;
  while (n != 0) {
    a = *s1++;
    b = *s2++;
    if (a != b)
      return a - b;
    if (a == '\0')
      return 0;
    n--;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncmp>:
  endbr64
  test   %rdx,%rdx
  je     L3
  xor    %ecx,%ecx
  jmp    L31
  nopl   (%rax)
L46:
  test   %eax,%eax
  je     L3
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L3
L31:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8d,%eax
  je     L46
  sub    %r8d,%eax
  ret
  nop
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int __attribute__((pure)) strncmp(const char *s1, const char *s2, size_t n) {
  unsigned int a, b;
  while (n != 0) {
    a = *s1++;
    b = *s2++;
    if (a != b)
      return a - b;
    if (a == '\0')
      return 0;
    n--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncmp>:
  endbr64
  test   %rdx,%rdx
  je     L20
  xor    %ecx,%ecx
  jmp    L34
  nopl   (%rax)
L38:
  test   %eax,%eax
  je     L20
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L20
L34:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8d,%eax
  je     L38
  sub    %r8d,%eax
  ret
  nop
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int __attribute__((pure)) strncmp(const char *s1, const char *s2, size_t n) {
  unsigned int a, b;
  while (n != 0) {
    a = *s1++;
    b = *s2++;
    if (a != b)
      return a - b;
    if (a == '\0')
      return 0;
    n--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rsi
  mov    %rsi,-0x18(%rbp)
  xor    %esi,%esi
  mov    %rsp,%rsi
  mov    %rsi,%r12
  movl   $0x5,-0x2c(%rbp)
  mov    -0x2c(%rbp),%esi
  movslq %esi,%rdi
  sub    $0x1,%rdi
  mov    %rdi,-0x28(%rbp)
  movslq %esi,%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  imul   $0x148,%rdx,%r8
  imul   $0x0,%rax,%rdi
  add    %r8,%rdi
  mov    $0x148,%r8d
  mul    %r8
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %esi,%rax
  mov    %rax,%rcx
  mov    $0x0,%ebx
  imul   $0x148,%rbx,%rdx
  imul   $0x0,%rcx,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    $0x148,%eax
  mul    %rcx
  lea    (%rdi,%rdx,1),%rcx
  mov    %rcx,%rdx
  movslq %esi,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L2:
  cmp    %rdx,%rsp
  je     L51
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L51:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L31
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L31:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L49
L8:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L49:
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L8
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x30(%rbp)
  jmp    L72
L26:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <afficheMot@plt>
  subl   $0x1,-0x30(%rbp)
L72:
  cmpl   $0x0,-0x30(%rbp)
  jns    L26
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %r12,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
datatype: string
name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D13: %s

tool: D3: 


assistant: ```c
int main() {
  int nbMots = 5;
  char mots[nbMots][41];
  for (int mot = 0; mot < nbMots; mot++) {
    scanf("%s", mots[mot]);
  }
  for (int i = nbMots - 1; i > -1; i--) {
    afficheMot(mots[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xcd(%rsp),%r13
  mov    %rbp,%rbx
  lea    D13(%rip),%r12
L27:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x29,%rbx
  cmp    %r13,%rbx
  jne    L27
  lea    0xa4(%rsp),%rbx
L0:
  mov    %rbx,%rdi
  call   <afficheMot@plt>
  mov    %rbx,%rax
  sub    $0x29,%rbx
  cmp    %rbp,%rax
  jne    L0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D13: %s

tool: D7: 


assistant: ```c
int main() {
  int nbMots = 5;
  char mots[nbMots][41];
  for (int mot = 0; mot < nbMots; mot++) {
    scanf("%s", mots[mot]);
  }
  for (int i = nbMots - 1; i > -1; i--) {
    afficheMot(mots[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xcd(%rsp),%r13
  mov    %rbp,%rbx
L18:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x29,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L18
  lea    0xa4(%rsp),%rbx
L14:
  mov    %rbx,%rdi
  call   <afficheMot@plt>
  mov    %rbx,%rax
  sub    $0x29,%rbx
  cmp    %rbp,%rax
  jne    L14
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D8
datatype: string

tool: D12: %s

tool: D8: 


assistant: ```c
int main() {
  int nbMots = 5;
  char mots[nbMots][41];
  for (int mot = 0; mot < nbMots; mot++) {
    scanf("%s", mots[mot]);
  }
  for (int i = nbMots - 1; i > -1; i--) {
    afficheMot(mots[i]);
  }
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xcd(%rsp),%r13
  mov    %rbp,%rbx
L24:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x29,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L24
  lea    0xa4(%rsp),%rbx
L11:
  mov    %rbx,%rdi
  call   <afficheMot@plt>
  mov    %rbx,%rax
  sub    $0x29,%rbx
  cmp    %rbp,%rax
  jne    L11
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D11: %s

tool: D4: 


assistant: ```c
int main() {
  int nbMots = 5;
  char mots[nbMots][41];
  for (int mot = 0; mot < nbMots; mot++) {
    scanf("%s", mots[mot]);
  }
  for (int i = nbMots - 1; i > -1; i--) {
    afficheMot(mots[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find_wave_pid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x30(%rbp)
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edx
  lea    -0x20(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x38(%rbp)
  jmp    L3
L8:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x38(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L3
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
L3:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    -0x3c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D9: /tmp

tool: D10: .wave.%d.

assistant: ```c
int find_wave_pid() {
  DIR *dir;
  struct dirent *dir_entry;
  char pattern[16];
  int i, imax = 0, pl;
  dir = opendir("/tmp");
  sprintf(pattern, ".wave.%d.", (int)getuid());
  pl = strlen(pattern);
  while (dir_entry = readdir(dir)) {
    if (strncmp(dir_entry->d_name, pattern, pl) == 0) {
      i = atoi(dir_entry->d_name + pl);
      if (i > imax)
        imax = i;
    }
  }
  closedir(dir);
  return (imax);
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_wave_pid>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rsp,%rbx
  mov    %eax,%edx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x0,%r14d
  mov    %rsp,%r13
L33:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    (%rbx),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  movslq %r12d,%rdi
  add    (%rbx),%rdi
  call   <atoi@plt>
  cmp    %eax,%r14d
  cmovl  %eax,%r14d
  jmp    L33
L28:
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %r14d,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D19: /tmp

tool: D18: .wave.%d.

assistant: ```c
int find_wave_pid() {
  DIR *dir;
  struct dirent *dir_entry;
  char pattern[16];
  int i, imax = 0, pl;
  dir = opendir("/tmp");
  sprintf(pattern, ".wave.%d.", (int)getuid());
  pl = strlen(pattern);
  while (dir_entry = readdir(dir)) {
    if (strncmp(dir_entry->d_name, pattern, pl) == 0) {
      i = atoi(dir_entry->d_name + pl);
      if (i > imax)
        imax = i;
    }
  }
  closedir(dir);
  return (imax);
}
```