ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<stacksort>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  shl    $0x3,%rdx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  jle    L45
L94:
  mov    (%rbx,%rdi,8),%rsi
  mov    0x8(%rbx,%rdi,8),%rdx
  lea    0x1(%rdi),%rax
  mov    %rax,%r8
  cmp    %rdx,%rsi
  jle    L75
  cmp    %rax,%rbp
  jg     L71
  jmp    L45
  nopl   0x0(%rax)
L87:
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rbp
  je     L91
  mov    %rcx,%rax
L71:
  mov    %rdx,-0x8(%rbx,%rax,8)
  mov    0x8(%rbx,%rax,8),%rdx
  cmp    %rsi,%rdx
  jl     L87
L91:
  mov    %rsi,(%rbx,%rax,8)
  cmp    %rdi,%rax
  je     L10
L56:
  cmp    %rbp,%rdi
  jl     L94
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %r8,%rdi
  jmp    L94
L75:
  mov    %rax,%rdi
  jmp    L56
```

assistant: ```c
void stacksort(long *u, long *w, long len) {
  long i = 0;
  long j = 0;
  long y;
  long size = len * sizeof(*w);
  memcpy(u, w, size);
  while (i < len) {
    j = i;
    y = u[j];
    while (y > u[j + 1] && j + 1 < len) {
      u[j] = u[j + 1];
      j++;
    }
    u[j] = y;
    if (j == i)
      i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stacksort>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  shl    $0x3,%rdx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  jle    L69
L67:
  mov    (%rbx,%rdi,8),%rsi
  mov    0x8(%rbx,%rdi,8),%rdx
  lea    0x1(%rdi),%rax
  mov    %rax,%r8
  cmp    %rdx,%rsi
  jle    L12
  cmp    %rax,%rbp
  jg     L61
  jmp    L69
  nopl   0x0(%rax)
L74:
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rbp
  je     L20
  mov    %rcx,%rax
L61:
  mov    %rdx,-0x8(%rbx,%rax,8)
  mov    0x8(%rbx,%rax,8),%rdx
  cmp    %rsi,%rdx
  jl     L74
L20:
  mov    %rsi,(%rbx,%rax,8)
  cmp    %rdi,%rax
  je     L99
L0:
  cmp    %rbp,%rdi
  jl     L67
L69:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L99:
  mov    %r8,%rdi
  jmp    L67
L12:
  mov    %rax,%rdi
  jmp    L0
```

assistant: ```c
void stacksort(long *u, long *w, long len) {
  long i = 0;
  long j = 0;
  long y;
  long size = len * sizeof(*w);
  memcpy(u, w, size);
  while (i < len) {
    j = i;
    y = u[j];
    while (y > u[j + 1] && j + 1 < len) {
      u[j] = u[j + 1];
      j++;
    }
    u[j] = y;
    if (j == i)
      i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L45:
  mov    -0x10(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L15
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  mov    %al,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdi
  call   <scan@plt>
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x100,-0x10(%rbp)
  jne    L52
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  jmp    L49
L52:
  mov    -0x10(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L53
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L45
L53:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L49:
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D47
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D66
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D62
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D8: const uint asc2asc[256] =

tool: D47:     {

tool: D33:         

tool: D66: 0x%02x

tool: D16:     };

tool: D62: ,

tool: D9: , 

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buf[2];
  unsigned int ch = 0;
  buf[1] = 0u;
  printf("const uint asc2asc[256] =\n");
  printf("    {\n");
  for (;;) {
    if (ch % 16 == 0) {
      printf("        ");
    }
    buf[0] = ch++;
    printf("0x%02x", scan(buf));
    if (ch == 256) {
      printf("\n");
      break;
    }
    if (ch % 16 == 0) {
      printf(",\n");
    } else {
      printf(", ");
    }
  }
  printf("    };\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D64(%rip),%r14
  lea    D1(%rip),%rbp
  lea    D19(%rip),%r13
  lea    D66(%rip),%r12
  jmp    L25
L68:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L52
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  test   $0xf,%bl
  je     L68
L52:
  add    $0x1,%ebx
  lea    -0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  lea    0x6(%rsp),%rdi
  call   <scan@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  je     L15
  test   $0xf,%bl
  jne    L14
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L25
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D46
data_type: string
name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D64
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D66
data_type: string
name: unpack_data
arguments: label: D60
data_type: string

tool: D46: const uint asc2asc[256] =

tool: D7:     {

tool: D64:         

tool: D1: 0x%02x

tool: D19: , 

tool: D66: ,

tool: D60:     };

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buf[2];
  unsigned int ch = 0;
  buf[1] = 0u;
  printf("const uint asc2asc[256] =\n");
  printf("    {\n");
  for (;;) {
    if (ch % 16 == 0) {
      printf("        ");
    }
    buf[0] = ch++;
    printf("0x%02x", scan(buf));
    if (ch == 256) {
      printf("\n");
      break;
    }
    if (ch % 16 == 0) {
      printf(",\n");
    } else {
      printf(", ");
    }
  }
  printf("    };\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D61(%rip),%rdi
  lea    D14(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D63(%rip),%r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%r12
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L60:
  test   $0xf,%bl
  je     L27
L58:
  add    $0x1,%ebx
  mov    %r12,%rdi
  lea    -0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  call   <scan@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  je     L15
  test   $0xf,%bl
  jne    L19
  mov    %r13,%rdi
  call   <puts@plt>
  test   $0xf,%bl
  jne    L58
L27:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
  nopl   0x0(%rax)
L19:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L60
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D61
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D15
datatype: string
name: unpack_data
arguments: label: D63
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D47
datatype: string

tool: D61: const uint asc2asc[256] =

tool: D14:         

tool: D15: , 

tool: D63: ,

tool: D4: 0x%02x

tool: D11:     {

tool: D47:     };

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buf[2];
  unsigned int ch = 0;
  buf[1] = 0u;
  printf("const uint asc2asc[256] =\n");
  printf("    {\n");
  for (;;) {
    if (ch % 16 == 0) {
      printf("        ");
    }
    buf[0] = ch++;
    printf("0x%02x", scan(buf));
    if (ch == 256) {
      printf("\n");
      break;
    }
    if (ch % 16 == 0) {
      printf(",\n");
    } else {
      printf(", ");
    }
  }
  printf("    };\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D62(%rip),%rdi
  lea    D44(%rip),%r15
  push   %r14
  lea    D38(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%r12
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  test   $0xf,%bl
  je     L15
L8:
  add    $0x1,%ebx
  mov    %r12,%rdi
  lea    -0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  call   <scan@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x100,%ebx
  je     L62
  test   $0xf,%bl
  jne    L20
  mov    %r13,%rdi
  call   <puts@plt>
  test   $0xf,%bl
  jne    L8
L15:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
  nopl   0x0(%rax)
L20:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
L62:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D62
type: string
name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D47
type: string
name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D46
type: string

tool: D62: const uint asc2asc[256] =

tool: D44:         

tool: D38: , 

tool: D14: ,

tool: D47: 0x%02x

tool: D26:     {

tool: D46:     };

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buf[2];
  unsigned int ch = 0;
  buf[1] = 0u;
  printf("const uint asc2asc[256] =\n");
  printf("    {\n");
  for (;;) {
    if (ch % 16 == 0) {
      printf("        ");
    }
    buf[0] = ch++;
    printf("0x%02x", scan(buf));
    if (ch == 256) {
      printf("\n");
      break;
    }
    if (ch % 16 == 0) {
      printf(",\n");
    } else {
      printf(", ");
    }
  }
  printf("    };\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<htond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <ntohl@plt>
  cmp    $0x1,%rax
  jne    L13
  movsd  -0x28(%rbp),%xmm0
  jmp    L18
L13:
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L47
L21:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  mov    %al,-0x15(%rbp)
  mov    $0x7,%eax
  sub    -0x14(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %dl,-0x10(%rbp,%rax,1)
  mov    $0x7,%eax
  sub    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0x10(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L47:
  cmpl   $0x3,-0x14(%rbp)
  jle    L21
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0xc(%rbp)
  movsd  -0x10(%rbp),%xmm0
L18:
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double htond(double host_double) {
  union {
    double whole_thing;
    unsigned int words[2];
    unsigned char bytes[8];
  } conv_rec;
  unsigned char scratch;
  int i;
  if (ntohl(1L) == 1L) {
    return (host_double);
  }
  conv_rec.whole_thing = host_double;
  for (i = 0; i <= 3; i++) {
    scratch = conv_rec.bytes[i];
    conv_rec.bytes[i] = conv_rec.bytes[7 - i];
    conv_rec.bytes[7 - i] = scratch;
  }
  conv_rec.words[0] = htonl(conv_rec.words[0]);
  conv_rec.words[1] = htonl(conv_rec.words[1]);
  return (conv_rec.whole_thing);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<htond>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <ntohl@plt>
  movq   %rbx,%xmm0
  cmp    $0x1,%rax
  je     L2
  mov    %rbx,(%rsp)
  mov    %rsp,%rdx
  lea    -0x4(%rsp),%rdi
  mov    %rdx,%rax
L6:
  movzbl (%rdx),%ecx
  movzbl 0x7(%rax),%esi
  mov    %sil,(%rdx)
  mov    %cl,0x7(%rax)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L6
  mov    (%rsp),%edi
  call   <htonl@plt>
  mov    %eax,(%rsp)
  mov    0x4(%rsp),%edi
  call   <htonl@plt>
  mov    %eax,0x4(%rsp)
  movsd  (%rsp),%xmm0
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double htond(double host_double) {
  union {
    double whole_thing;
    unsigned int words[2];
    unsigned char bytes[8];
  } conv_rec;
  unsigned char scratch;
  int i;
  if (ntohl(1L) == 1L) {
    return (host_double);
  }
  conv_rec.whole_thing = host_double;
  for (i = 0; i <= 3; i++) {
    scratch = conv_rec.bytes[i];
    conv_rec.bytes[i] = conv_rec.bytes[7 - i];
    conv_rec.bytes[7 - i] = scratch;
  }
  conv_rec.words[0] = htonl(conv_rec.words[0]);
  conv_rec.words[1] = htonl(conv_rec.words[1]);
  return (conv_rec.whole_thing);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<htond>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <ntohl@plt>
  movsd  0x8(%rsp),%xmm0
  movapd %xmm0,%xmm1
  cmp    $0x1,%rax
  je     L18
  lea    0x10(%rsp),%rdx
  movsd  %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rdx,%rax
L1:
  movzbl (%rdx),%ecx
  movzbl 0x7(%rax),%esi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  mov    %cl,0x8(%rax)
  cmp    %rdi,%rax
  jne    L1
  mov    0x10(%rsp),%edi
  call   <htonl@plt>
  mov    0x14(%rsp),%edi
  mov    %eax,0x10(%rsp)
  call   <htonl@plt>
  mov    %eax,0x14(%rsp)
  movsd  0x10(%rsp),%xmm1
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double htond(double host_double) {
  union {
    double whole_thing;
    unsigned int words[2];
    unsigned char bytes[8];
  } conv_rec;
  unsigned char scratch;
  int i;
  if (ntohl(1L) == 1L) {
    return (host_double);
  }
  conv_rec.whole_thing = host_double;
  for (i = 0; i <= 3; i++) {
    scratch = conv_rec.bytes[i];
    conv_rec.bytes[i] = conv_rec.bytes[7 - i];
    conv_rec.bytes[7 - i] = scratch;
  }
  conv_rec.words[0] = htonl(conv_rec.words[0]);
  conv_rec.words[1] = htonl(conv_rec.words[1]);
  return (conv_rec.whole_thing);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<htond>:
  endbr64
  push   %r14
  mov    $0x1,%edi
  push   %rbx
  movq   %xmm0,%rbx
  sub    $0x8,%rsp
  call   <ntohl@plt>
  movq   %rbx,%xmm0
  cmp    $0x1,%rax
  je     L2
  movzbl %bl,%edi
  mov    %rbx,%rax
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  mov    %rbx,%rsi
  mov    %rbx,%r8
  mov    %rbx,%r9
  shl    $0x8,%rdi
  shr    $0x10,%r9
  movzbl %bh,%ebx
  shr    $0x18,%r8
  or     %rbx,%rdi
  movzbl %r9b,%r9d
  movzbl %r8b,%r8d
  shr    $0x20,%rsi
  shl    $0x8,%rdi
  movzbl %sil,%esi
  shr    $0x28,%rcx
  shr    $0x30,%rdx
  or     %r9,%rdi
  movzbl %cl,%ecx
  shr    $0x38,%rax
  shl    $0x8,%rdi
  movzbl %dl,%edx
  or     %r8,%rdi
  shl    $0x8,%rdi
  or     %rsi,%rdi
  shl    $0x8,%rdi
  or     %rcx,%rdi
  shl    $0x8,%rdi
  or     %rdx,%rdi
  shl    $0x8,%rdi
  or     %rax,%rdi
  mov    %rdi,%r14
  call   <htonl@plt>
  movq   %r14,%xmm2
  pshufd $0xe5,%xmm2,%xmm1
  movd   %xmm1,%edi
  mov    %eax,%ebx
  call   <htonl@plt>
  shl    $0x20,%rax
  or     %rax,%rbx
  movq   %rbx,%xmm0
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double htond(double host_double) {
  union {
    double whole_thing;
    unsigned int words[2];
    unsigned char bytes[8];
  } conv_rec;
  unsigned char scratch;
  int i;
  if (ntohl(1L) == 1L) {
    return (host_double);
  }
  conv_rec.whole_thing = host_double;
  for (i = 0; i <= 3; i++) {
    scratch = conv_rec.bytes[i];
    conv_rec.bytes[i] = conv_rec.bytes[7 - i];
    conv_rec.bytes[7 - i] = scratch;
  }
  conv_rec.words[0] = htonl(conv_rec.words[0]);
  conv_rec.words[1] = htonl(conv_rec.words[1]);
  return (conv_rec.whole_thing);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <yyparse@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv) {
  yyparse();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <yyparse@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv) {
  yyparse();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <yyparse@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv) {
  yyparse();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <yyparse@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv) {
  yyparse();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<put32bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void put32bits(uint8_t **buffer, uint32_t value) {
  value = htonl(value);
  memcpy(*buffer, &value, 4);
  *buffer += 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<put32bits>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    (%rbx),%rdi
  call   <memcpy@plt>
  addq   $0x10,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put32bits(uint8_t **buffer, uint32_t value) {
  value = htonl(value);
  memcpy(*buffer, &value, 4);
  *buffer += 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<put32bits>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x10,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put32bits(uint8_t **buffer, uint32_t value) {
  value = htonl(value);
  memcpy(*buffer, &value, 4);
  *buffer += 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<put32bits>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x10,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put32bits(uint8_t **buffer, uint32_t value) {
  value = htonl(value);
  memcpy(*buffer, &value, 4);
  *buffer += 4;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0xf,-0x1c(%rbp)
  movl   $0x15,-0x18(%rbp)
  movl   $0x1c,-0x14(%rbp)
  movl   $0x24,-0x10(%rbp)
  movl   $0x9,-0x4c(%rbp)
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <binsearch1@plt>
  mov    %eax,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <binsearch2@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x15,%edi
  call   <binsearch1@plt>
  mov    %eax,-0x40(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x15,%edi
  call   <binsearch2@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <binsearch1@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <binsearch2@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D41
type_infered: string

tool: D41: %d


assistant: ```c
int main() {
  int w[] = {0, 1, 3, 6, 10, 15, 21, 28, 36};
  int m = sizeof(w) / sizeof(int);
  int i1, i2;
  int j1, j2;
  int k1, k2;
  i1 = binsearch1(3, w, m);
  printf("%d\n", i1);
  i2 = binsearch2(3, w, m);
  printf("%d\n", i2);
  j1 = binsearch1(21, w, m);
  printf("%d\n", j1);
  j2 = binsearch2(21, w, m);
  printf("%d\n", j2);
  k1 = binsearch1(5, w, m);
  printf("%d\n", k1);
  k2 = binsearch2(5, w, m);
  printf("%d\n", k2);
  return 0;
}
```