ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    0x10(%rbp),%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L27
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addl   $0x1,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
  mov    -0x38(%rbp),%r8
  mov    -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <search>
  add    $0x10,%rsp
  subl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void search(int *nums, int size, int begin, int *stack, int top, int **columnSizes, int *count, int **table) {
  (*columnSizes)[*count] = top + 1;
  table[*count] = (int *)malloc(sizeof(int) * (top + 1));
  for (int i = 0; i <= top; i++)
    table[*count][i] = stack[i];
  (*count)++;
  for (int i = begin; i < size; i++) {
    stack[++top] = nums[i];
    search(nums, size, ++begin, stack, top, columnSizes, count, table);
    top--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %esi,0x8(%rsp)
  mov    %edx,%r15d
  mov    %rcx,%r12
  mov    %r8d,%ebx
  mov    %r9,0x10(%rsp)
  mov    0x60(%rsp),%rbp
  mov    0x68(%rsp),%r13
  lea    0x1(%r8),%edi
  mov    %edi,0xc(%rsp)
  movslq 0x0(%rbp),%rdx
  mov    (%r9),%rax
  mov    %edi,(%rax,%rdx,4)
  movslq %edi,%rsi
  mov    %rsi,0x18(%rsp)
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  movslq 0x0(%rbp),%rax
  mov    %rdx,0x0(%r13,%rax,8)
  test   %ebx,%ebx
  js     L33
  lea    0x1(%rbx),%esi
  shl    $0x2,%rsi
  mov    $0x0,%eax
L39:
  mov    (%r12,%rax,1),%ecx
  movslq 0x0(%rbp),%rdx
  mov    0x0(%r13,%rdx,8),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L39
L33:
  addl   $0x1,0x0(%rbp)
  mov    0x8(%rsp),%eax
  cmp    %eax,%r15d
  jge    L18
  mov    0x18(%rsp),%rsi
  lea    (%r12,%rsi,4),%rbx
  mov    %rbx,0x18(%rsp)
  lea    0x1(%r15),%ebx
  movslq %ebx,%rbx
  sub    $0x1,%eax
  sub    %r15d,%eax
  movslq %r15d,%r15
  lea    0x2(%rax,%r15,1),%r15
L28:
  mov    -0x4(%r14,%rbx,4),%eax
  mov    0x18(%rsp),%rdi
  mov    %eax,(%rdi)
  push   %r13
  push   %rbp
  mov    0x20(%rsp),%r9
  mov    0x1c(%rsp),%r8d
  mov    %r12,%rcx
  mov    %ebx,%edx
  mov    0x18(%rsp),%esi
  mov    %r14,%rdi
  call   <search>
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    %r15,%rbx
  jne    L28
L18:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void search(int *nums, int size, int begin, int *stack, int top, int **columnSizes, int *count, int **table) {
  (*columnSizes)[*count] = top + 1;
  table[*count] = (int *)malloc(sizeof(int) * (top + 1));
  for (int i = 0; i <= top; i++)
    table[*count][i] = stack[i];
  (*count)++;
  for (int i = begin; i < size; i++) {
    stack[++top] = nums[i];
    search(nums, size, ++begin, stack, top, columnSizes, count, table);
    top--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<search>:
  endbr64
  push   %r15
  movslq %r8d,%r15
  push   %r14
  lea    0x1(%r15),%r8d
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%r8,4),%edi
  movslq %r8d,%r14
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%r9),%rax
  mov    0x60(%rsp),%rbx
  mov    %esi,(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    0x68(%rsp),%r12
  movslq (%rbx),%rcx
  mov    %r9,0x10(%rsp)
  mov    %r8d,0x8(%rsp)
  mov    %r8d,(%rax,%rcx,4)
  call   <malloc@plt>
  movslq (%rbx),%rsi
  test   %r15d,%r15d
  mov    0x8(%rsp),%r8d
  mov    0x10(%rsp),%r9
  movslq 0x1c(%rsp),%rdx
  mov    %rax,%rcx
  mov    %rax,(%r12,%rsi,8)
  js     L53
  lea    0x4(,%r15,4),%rdi
  xor    %eax,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L2:
  movslq (%rbx),%rcx
  mov    (%r12,%rcx,8),%rcx
L11:
  mov    0x0(%rbp,%rax,1),%esi
  mov    %esi,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L2
  mov    (%rbx),%eax
L21:
  mov    (%rsp),%edi
  add    $0x1,%eax
  mov    %eax,(%rbx)
  cmp    %edi,%edx
  jge    L33
  lea    -0x1(%rdi),%ecx
  lea    0x1(%rdx),%eax
  mov    %rbx,0x60(%rsp)
  mov    %r8d,%ebx
  sub    %edx,%ecx
  lea    0x0(%rbp,%r14,4),%r15
  movslq %eax,%r14
  mov    %edi,%eax
  lea    0x2(%rcx,%rdx,1),%rsi
  mov    %r13,%rdi
  mov    %r15,0x8(%rsp)
  mov    %r14,%r13
  mov    %rsi,(%rsp)
  mov    %r9,%r15
  mov    %rdi,%r14
  mov    %r12,0x68(%rsp)
  mov    %rbp,%r12
  mov    %eax,%ebp
L18:
  mov    -0x4(%r14,%r13,4),%edx
  mov    0x8(%rsp),%rax
  mov    %r15,%r9
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    %edx,(%rax)
  mov    %r13d,%edx
  add    $0x1,%r13
  push   0x68(%rsp)
  push   0x68(%rsp)
  call   <search>
  pop    %rax
  pop    %rdx
  cmp    (%rsp),%r13
  jne    L18
L33:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  mov    %rsi,%rax
  jmp    L21
```

assistant: ```c
void search(int *nums, int size, int begin, int *stack, int top, int **columnSizes, int *count, int **table) {
  (*columnSizes)[*count] = top + 1;
  table[*count] = (int *)malloc(sizeof(int) * (top + 1));
  for (int i = 0; i <= top; i++)
    table[*count][i] = stack[i];
  (*count)++;
  for (int i = begin; i < size; i++) {
    stack[++top] = nums[i];
    search(nums, size, ++begin, stack, top, columnSizes, count, table);
    top--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<search>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %r8d,%r14d
  add    $0x1,%r8d
  push   %r13
  lea    0x0(,%r8,4),%edi
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%r9),%rax
  mov    0x60(%rsp),%rbx
  mov    0x68(%rsp),%r12
  mov    %edx,0x14(%rsp)
  mov    %r9,0x8(%rsp)
  movslq (%rbx),%rcx
  mov    %r8d,(%rsp)
  mov    %r8d,(%rax,%rcx,4)
  movslq %r8d,%rax
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  movslq (%rbx),%rsi
  test   %r14d,%r14d
  mov    (%rsp),%r8d
  mov    0x8(%rsp),%r9
  movslq 0x14(%rsp),%rdx
  mov    %rax,(%r12,%rsi,8)
  js     L0
  mov    0x0(%rbp),%ecx
  mov    %r8d,%edi
  shl    $0x2,%rdi
  mov    %ecx,(%rax)
  mov    $0x4,%eax
  test   %r14d,%r14d
  je     L29
  nopl   0x0(%rax)
L56:
  movslq (%rbx),%rcx
  mov    0x0(%rbp,%rax,1),%esi
  mov    (%r12,%rcx,8),%rcx
  mov    %esi,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L56
L29:
  mov    (%rbx),%ecx
L17:
  add    $0x1,%ecx
  mov    %ecx,(%rbx)
  cmp    %r13d,%edx
  jge    L35
  mov    0x18(%rsp),%rax
  lea    -0x1(%r13),%ecx
  mov    %rbx,0x60(%rsp)
  mov    %r8d,%ebx
  sub    %edx,%ecx
  mov    %r12,0x68(%rsp)
  mov    %rbp,%r12
  lea    0x0(%rbp,%rax,4),%rax
  mov    %rax,(%rsp)
  lea    0x1(%rdx),%eax
  movslq %eax,%r14
  lea    0x2(%rcx,%rdx,1),%rax
  mov    %rax,0x8(%rsp)
  mov    %r14,%rbp
  mov    %r15,%r14
  mov    %r9,%r15
L39:
  mov    -0x4(%r14,%rbp,4),%edx
  mov    (%rsp),%rax
  mov    %r15,%r9
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %edx,(%rax)
  mov    %ebp,%edx
  add    $0x1,%rbp
  push   0x68(%rsp)
  push   0x68(%rsp)
  call   <search>
  pop    %rax
  pop    %rdx
  cmp    %rbp,0x8(%rsp)
  jne    L39
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L0:
  mov    %rsi,%rcx
  jmp    L17
```

assistant: ```c
void search(int *nums, int size, int begin, int *stack, int top, int **columnSizes, int *count, int **table) {
  (*columnSizes)[*count] = top + 1;
  table[*count] = (int *)malloc(sizeof(int) * (top + 1));
  for (int i = 0; i <= top; i++)
    table[*count][i] = stack[i];
  (*count)++;
  for (int i = begin; i < size; i++) {
    stack[++top] = nums[i];
    search(nums, size, ++begin, stack, top, columnSizes, count, table);
    top--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<userinput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <tty_event@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    -0x4(%rbp),%eax
  jmp    L9
L2:
  cmpl   $0x2,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  call   <parseinput@plt>
L18:
  mov    -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int userinput(void) {
  int err = tty_event();
  if (err < 0)
    return err;
  if (err == 2) {
    parseinput();
  }
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<userinput>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <tty_event@plt>
  mov    %eax,%ebx
  cmp    $0x2,%eax
  je     L1
L6:
  mov    %ebx,%eax
  pop    %rbx
  ret
L1:
  mov    $0x0,%eax
  call   <parseinput@plt>
  jmp    L6
```

assistant: ```c
int userinput(void) {
  int err = tty_event();
  if (err < 0)
    return err;
  if (err == 2) {
    parseinput();
  }
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<userinput>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <tty_event@plt>
  mov    %eax,%r12d
  cmp    $0x2,%eax
  je     L2
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <parseinput@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int userinput(void) {
  int err = tty_event();
  if (err < 0)
    return err;
  if (err == 2) {
    parseinput();
  }
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<userinput>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <tty_event@plt>
  mov    %eax,%r12d
  cmp    $0x2,%eax
  je     L3
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <parseinput@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int userinput(void) {
  int err = tty_event();
  if (err < 0)
    return err;
  if (err == 2) {
    parseinput();
  }
  return err;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <fib@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main() {
  printf("%d\n", fib(5));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fib@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  printf("%d\n", fib(5));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fib@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main() {
  printf("%d\n", fib(5));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fib@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main() {
  printf("%d\n", fib(5));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L3:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L11:
  cmpq   $0x0,-0x28(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *dest, int ch, size_t count) {
  char *temp = (char *)dest;
  for (; count != 0; count--)
    *temp++ = ch;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  add    %rdi,%rdx
  mov    %rdi,%rcx
L19:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L19
L3:
  ret
```

assistant: ```c
void *memset(void *dest, int ch, size_t count) {
  char *temp = (char *)dest;
  for (; count != 0; count--)
    *temp++ = ch;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L1
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int ch, size_t count) {
  char *temp = (char *)dest;
  for (; count != 0; count--)
    *temp++ = ch;
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L8
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int ch, size_t count) {
  char *temp = (char *)dest;
  for (; count != 0; count--)
    *temp++ = ch;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pre_kmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L36:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L41
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L23
L41:
  cmpl   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pre_kmp(char *pat, int pat_len, int *lps) {
  int len = 0;
  int i;
  lps[0] = 0;
  i = 1;
  while (i < pat_len) {
    if (pat[i] == pat[len]) {
      len++;
      lps[i] = len;
      i++;
    } else {
      if (len != 0) {
        len = lps[len - 1];
      } else {
        lps[i] = 0;
        i++;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pre_kmp>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L41
  mov    $0x1,%eax
  mov    $0x0,%ecx
  jmp    L65
L58:
  add    $0x1,%ecx
  mov    %ecx,(%rdx,%r8,4)
  add    $0x1,%eax
L28:
  cmp    %esi,%eax
  jge    L41
L65:
  movslq %eax,%r8
  movslq %ecx,%r9
  movzbl (%rdi,%r9,1),%r10d
  cmp    %r10b,(%rdi,%r8,1)
  je     L58
  test   %ecx,%ecx
  je     L24
  mov    -0x4(%rdx,%r9,4),%ecx
  jmp    L28
L24:
  movl   $0x0,(%rdx,%r8,4)
  add    $0x1,%eax
  jmp    L28
L41:
  ret
```

assistant: ```c
void pre_kmp(char *pat, int pat_len, int *lps) {
  int len = 0;
  int i;
  lps[0] = 0;
  i = 1;
  while (i < pat_len) {
    if (pat[i] == pat[len]) {
      len++;
      lps[i] = len;
      i++;
    } else {
      if (len != 0) {
        len = lps[len - 1];
      } else {
        lps[i] = 0;
        i++;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pre_kmp>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L57
  mov    $0x1,%eax
  xor    %ecx,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L65:
  test   %ecx,%ecx
  je     L4
  mov    -0x4(%rdx,%r9,4),%ecx
L34:
  cmp    %esi,%eax
  jge    L57
L23:
  movslq %ecx,%r9
  movslq %eax,%r8
  movzbl (%rdi,%r9,1),%r10d
  cmp    %r10b,(%rdi,%r8,1)
  jne    L65
  add    $0x1,%ecx
  add    $0x1,%eax
  mov    %ecx,(%rdx,%r8,4)
  cmp    %esi,%eax
  jl     L23
L57:
  ret
  nopl   (%rax)
L4:
  movl   $0x0,(%rdx,%r8,4)
  add    $0x1,%eax
  jmp    L34
```

assistant: ```c
void pre_kmp(char *pat, int pat_len, int *lps) {
  int len = 0;
  int i;
  lps[0] = 0;
  i = 1;
  while (i < pat_len) {
    if (pat[i] == pat[len]) {
      len++;
      lps[i] = len;
      i++;
    } else {
      if (len != 0) {
        len = lps[len - 1];
      } else {
        lps[i] = 0;
        i++;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pre_kmp>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L49
  mov    $0x1,%eax
  xor    %ecx,%ecx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L62:
  test   %ecx,%ecx
  je     L50
  mov    -0x4(%rdx,%r9,4),%ecx
L23:
  cmp    %esi,%eax
  jge    L49
L41:
  movslq %ecx,%r9
  movslq %eax,%r8
  movzbl (%rdi,%r9,1),%r10d
  cmp    %r10b,(%rdi,%r8,1)
  jne    L62
  add    $0x1,%ecx
  add    $0x1,%eax
  mov    %ecx,(%rdx,%r8,4)
  cmp    %esi,%eax
  jl     L41
L49:
  ret
  nopl   (%rax)
L50:
  movl   $0x0,(%rdx,%r8,4)
  add    $0x1,%eax
  jmp    L23
```

assistant: ```c
void pre_kmp(char *pat, int pat_len, int *lps) {
  int len = 0;
  int i;
  lps[0] = 0;
  i = 1;
  while (i < pat_len) {
    if (pat[i] == pat[len]) {
      len++;
      lps[i] = len;
      i++;
    } else {
      if (len != 0) {
        len = lps[len - 1];
      } else {
        lps[i] = 0;
        i++;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L12
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int Align(int l) {
  if (l & 1)
    return l + 1;
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Align>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int Align(int l) {
  if (l & 1)
    return l + 1;
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Align>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int Align(int l) {
  if (l & 1)
    return l + 1;
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Align>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
int Align(int l) {
  if (l & 1)
    return l + 1;
  return l;
}
```
user: What is the c source code of the assembly code below:

```asm
<read32_part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x3,-0x20(%rbp)
  jne    L35
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  jmp    L31
L35:
  cmpq   $0x2,-0x20(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  jmp    L31
L26:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t read32_part(const void *p, size_t len) {
  const uint8_t *b = p;
  if (len == 3)
    return b[0] | (b[1] << 8) | (b[2] << 16);
  else if (len == 2)
    return b[0] | (b[1] << 8);
  return b[0];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read32_part>:
  endbr64
  cmp    $0x3,%rsi
  je     L15
  cmp    $0x2,%rsi
  je     L14
  mov    (%rdi),%eax
  ret
L15:
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  mov    0x8(%rdi),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  or     (%rdi),%eax
  ret
L14:
  mov    0x4(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint32_t read32_part(const void *p, size_t len) {
  const uint8_t *b = p;
  if (len == 3)
    return b[0] | (b[1] << 8) | (b[2] << 16);
  else if (len == 2)
    return b[0] | (b[1] << 8);
  return b[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read32_part>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x3,%rsi
  je     L16
  cmp    $0x2,%rsi
  je     L18
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x4(%rdi),%edx
  mov    0x8(%rdi),%ecx
  shl    $0x8,%edx
  shl    $0x10,%ecx
  or     %ecx,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L18:
  mov    0x4(%rdi),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t read32_part(const void *p, size_t len) {
  const uint8_t *b = p;
  if (len == 3)
    return b[0] | (b[1] << 8) | (b[2] << 16);
  else if (len == 2)
    return b[0] | (b[1] << 8);
  return b[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read32_part>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x3,%rsi
  je     L3
  cmp    $0x2,%rsi
  je     L9
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    0x4(%rdi),%edx
  mov    0x8(%rdi),%ecx
  shl    $0x8,%edx
  shl    $0x10,%ecx
  or     %ecx,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    0x4(%rdi),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t read32_part(const void *p, size_t len) {
  const uint8_t *b = p;
  if (len == 3)
    return b[0] | (b[1] << 8) | (b[2] << 16);
  else if (len == 2)
    return b[0] | (b[1] << 8);
  return b[0];
}
```