ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L66
  mov    $0x1,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L66:
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L56:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L64:
  cmpl   $0x0,-0x14(%rbp)
  jle    L56
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0xff,%al
  jne    L53
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L53:
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L29:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L48:
  cmpl   $0x0,-0x10(%rbp)
  jle    L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D22
type: string

tool: D20: Call this program with %i arguments


tool: D12: You win!

tool: D22: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 255) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L8
L34:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %al,0x6(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpb   $0xff,0x7(%rsp)
  je     L10
L13:
  movzbl 0x7(%rsp),%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L34
L10:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L13
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string

tool: D12: %u


tool: D23: Call this program with %i arguments


tool: D6: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 255) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L30
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L30:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0xff,%sil
  je     L22
L3:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L3
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string

tool: D24: Call this program with %i arguments


tool: D20: %u


tool: D25: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 255) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L25
  lea    D19(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L25:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0xff,%sil
  je     L29
L38:
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L38
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string

tool: D19: Call this program with %i arguments


tool: D2: %u


tool: D26: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 255) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<double_to_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8d,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4c(%rbp),%eax
  imul   -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <min_max@plt>
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L10
  ucomisd %xmm1,%xmm0
  je     L6
L10:
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L48
L92:
  movl   $0x0,-0x30(%rbp)
  jmp    L86
L18:
  mov    -0x34(%rbp),%eax
  imul   -0x50(%rbp),%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  js     L97
  mov    -0x2c(%rbp),%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,%edx
  jmp    L59
L97:
  mov    $0x0,%edx
L59:
  mov    -0x34(%rbp),%eax
  imul   -0x5c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x30(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x30(%rbp)
L86:
  mov    -0x30(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L18
  addl   $0x1,-0x34(%rbp)
L48:
  mov    -0x34(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L92
  jmp    L40
L6:
  nop
L40:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: f64
name: disassemble_data
arguments: data_tag: D2
datatype: f64

tool: D1: 255

tool: D2: 0.5

assistant: ```c
void double_to_image(const double *m, int rows, int cols, unsigned char *data, int step) {
  int i, j;
  double mi, ma, scale;
  min_max(m, rows * cols, &mi, &ma);
  if (mi == ma) {
    return;
  }
  scale = 255.0 / (ma - mi);
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      const double s = m[i * cols + j] * scale;
      const int t = ((int)((s) + 0.5));
      data[i * step + j] = ((t) < 0 ? 0 : (t) > 255 ? 255 : (t));
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<double_to_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %r8d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  imul   %ebx,%esi
  call   <min_max@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  ucomisd %xmm0,%xmm1
  jp     L40
  je     L58
L40:
  subsd  %xmm1,%xmm0
  movsd  D19(%rip),%xmm1
  divsd  %xmm0,%xmm1
  test   %ebp,%ebp
  jle    L58
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    %ebx,%r8d
  movsd  D8(%rip),%xmm2
  jmp    L73
L82:
  movslq %r10d,%rax
  lea    (%r12,%rax,8),%rdi
  mov    $0x0,%edx
  movslq %r11d,%rsi
  add    %r14,%rsi
L1:
  movapd %xmm1,%xmm0
  mulsd  (%rdi,%rdx,8),%xmm0
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%eax
  mov    $0xff,%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  test   %eax,%eax
  mov    $0x0,%ecx
  cmovs  %ecx,%eax
  mov    %al,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L1
L86:
  add    $0x1,%r9d
  add    %ebx,%r10d
  add    %r13d,%r11d
  cmp    %r9d,%ebp
  je     L58
L73:
  test   %ebx,%ebx
  jg     L82
  jmp    L86
L58:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_infered: f64
name: disassemble_data
arguments: data_tag: D8
type_infered: f64

tool: D19: 255

tool: D8: 0.5

assistant: ```c
void double_to_image(const double *m, int rows, int cols, unsigned char *data, int step) {
  int i, j;
  double mi, ma, scale;
  min_max(m, rows * cols, &mi, &ma);
  if (mi == ma) {
    return;
  }
  scale = 255.0 / (ma - mi);
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      const double s = m[i * cols + j] * scale;
      const int t = ((int)((s) + 0.5));
      data[i * step + j] = ((t) < 0 ? 0 : (t) > 255 ? 255 : (t));
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<double_to_image>:
  endbr64
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  imul   %ebx,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <min_max@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  ucomisd %xmm0,%xmm1
  jp     L28
  je     L43
L28:
  subsd  %xmm1,%xmm0
  movsd  D16(%rip),%xmm1
  divsd  %xmm0,%xmm1
  test   %ebp,%ebp
  jle    L43
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  lea    -0x1(%rbx),%edi
  xor    %r8d,%r8d
  movsd  D11(%rip),%xmm2
  nop
L33:
  test   %ebx,%ebx
  jle    L60
  movslq %r9d,%rax
  movslq %r10d,%rcx
  xor    %edx,%edx
  lea    (%r12,%rax,8),%rsi
  add    %r13,%rcx
  nopl   0x0(%rax,%rax,1)
L49:
  movsd  (%rsi,%rdx,8),%xmm0
  mov    $0xff,%r11d
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %r11d,%eax
  cmovg  %r11d,%eax
  xor    %r11d,%r11d
  test   %eax,%eax
  cmovs  %r11d,%eax
  mov    %al,(%rcx,%rdx,1)
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rax
  jne    L49
L60:
  add    $0x1,%r8d
  add    %ebx,%r9d
  add    %r14d,%r10d
  cmp    %r8d,%ebp
  jne    L33
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type: f64
name: disassemble_data
arguments: data_tag: D11
type: f64

tool: D16: 255

tool: D11: 0.5

assistant: ```c
void double_to_image(const double *m, int rows, int cols, unsigned char *data, int step) {
  int i, j;
  double mi, ma, scale;
  min_max(m, rows * cols, &mi, &ma);
  if (mi == ma) {
    return;
  }
  scale = 255.0 / (ma - mi);
  for (i = 0; i < rows; ++i) {
    for (j = 0; j < cols; ++j) {
      const double s = m[i * cols + j] * scale;
      const int t = ((int)((s) + 0.5));
      data[i * step + j] = ((t) < 0 ? 0 : (t) > 255 ? 255 : (t));
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recv_byte_unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Serial_read_byte_blocking@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x55,-0x8(%rbp)
  jne    L91
  mov    $0x100,%eax
  jmp    L80
L91:
  cmpl   $0xaa,-0x8(%rbp)
  jne    L33
  mov    $0x0,%eax
  call   <Serial_read_byte_blocking@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L93
  mov    $0xffffffff,%eax
  jmp    L80
L93:
  cmpl   $0x1,-0x4(%rbp)
  jne    L64
  mov    $0x55,%eax
  jmp    L80
L64:
  cmpl   $0x2,-0x4(%rbp)
  jne    L89
  mov    $0xaa,%eax
  jmp    L80
L89:
  mov    $0xffffffff,%eax
  jmp    L80
L33:
  mov    -0x8(%rbp),%eax
L80:
  leave
  ret
```

assistant: ```c
int recv_byte_unescape() {
  int val;
  val = Serial_read_byte_blocking();
  if (val == 0x55)
    return 0x100;
  else if (val == 0xAA) {
    int second_char = Serial_read_byte_blocking();
    if (second_char == -1)
      return -1;
    else if (second_char == 0x01)
      return 0x55;
    else if (second_char == 0x02)
      return 0xAA;
    else
      return -1;
  } else
    return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recv_byte_unescape>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0x55,%eax
  je     L31
  mov    %eax,%ebx
  cmp    $0xaa,%eax
  je     L2
L42:
  mov    %ebx,%eax
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0xffffffff,%eax
  je     L44
  cmp    $0x1,%eax
  je     L50
  cmp    $0x2,%eax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebx
  jmp    L42
L31:
  mov    $0x100,%ebx
  jmp    L42
L44:
  mov    %eax,%ebx
  jmp    L42
L50:
  mov    $0x55,%ebx
  jmp    L42
```

assistant: ```c
int recv_byte_unescape() {
  int val;
  val = Serial_read_byte_blocking();
  if (val == 0x55)
    return 0x100;
  else if (val == 0xAA) {
    int second_char = Serial_read_byte_blocking();
    if (second_char == -1)
      return -1;
    else if (second_char == 0x01)
      return 0x55;
    else if (second_char == 0x02)
      return 0xAA;
    else
      return -1;
  } else
    return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recv_byte_unescape>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0x55,%eax
  je     L53
  mov    %eax,%r12d
  cmp    $0xaa,%eax
  je     L13
L55:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0xffffffff,%eax
  je     L9
  cmp    $0x1,%eax
  je     L33
  cmp    $0x2,%eax
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  mov    $0x100,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L33:
  mov    $0x55,%r12d
  jmp    L55
L9:
  mov    $0xffffffff,%r12d
  jmp    L55
```

assistant: ```c
int recv_byte_unescape() {
  int val;
  val = Serial_read_byte_blocking();
  if (val == 0x55)
    return 0x100;
  else if (val == 0xAA) {
    int second_char = Serial_read_byte_blocking();
    if (second_char == -1)
      return -1;
    else if (second_char == 0x01)
      return 0x55;
    else if (second_char == 0x02)
      return 0xAA;
    else
      return -1;
  } else
    return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<recv_byte_unescape>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0x55,%eax
  je     L23
  mov    %eax,%r12d
  cmp    $0xaa,%eax
  je     L47
L50:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  call   <Serial_read_byte_blocking@plt>
  cmp    $0xffffffff,%eax
  je     L24
  cmp    $0x1,%eax
  je     L27
  cmp    $0x2,%eax
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x100,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  mov    $0x55,%r12d
  jmp    L50
L24:
  mov    $0xffffffff,%r12d
  jmp    L50
```

assistant: ```c
int recv_byte_unescape() {
  int val;
  val = Serial_read_byte_blocking();
  if (val == 0x55)
    return 0x100;
  else if (val == 0xAA) {
    int second_char = Serial_read_byte_blocking();
    if (second_char == -1)
      return -1;
    else if (second_char == 0x01)
      return 0x55;
    else if (second_char == 0x02)
      return 0xAA;
    else
      return -1;
  } else
    return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<VisibleContents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L12
  mov    -0x4(%rbp),%eax
  jmp    L33
L12:
  shll   -0x4(%rbp)
L0:
  cmpl   $0x40,-0x4(%rbp)
  jle    L10
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int VisibleContents(int contents) {
  int i;
  for (i = 1; i <= 64; i <<= 1)
    if (contents & i)
      return i;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<VisibleContents>:
  endbr64
  mov    %edi,%edx
  and    $0x1,%edx
  jne    L35
  mov    $0x2,%eax
L12:
  mov    %edi,%edx
  and    %eax,%edx
  jne    L6
  add    %eax,%eax
  cmp    $0x40,%eax
  jle    L12
L35:
  mov    %edx,%eax
  ret
L6:
  mov    %eax,%edx
  jmp    L35
```

assistant: ```c
int VisibleContents(int contents) {
  int i;
  for (i = 1; i <= 64; i <<= 1)
    if (contents & i)
      return i;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<VisibleContents>:
  endbr64
  mov    $0x7,%edx
  mov    $0x1,%eax
  xchg   %ax,%ax
L16:
  mov    %edi,%r8d
  and    %eax,%r8d
  jne    L3
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L16
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int VisibleContents(int contents) {
  int i;
  for (i = 1; i <= 64; i <<= 1)
    if (contents & i)
      return i;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<VisibleContents>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L49
  test   $0x2,%dil
  jne    L41
  test   $0x4,%dil
  jne    L5
  test   $0x8,%dil
  jne    L17
  test   $0x10,%dil
  jne    L33
  test   $0x20,%dil
  jne    L15
  mov    %edi,%eax
  mov    $0x40,%edx
  and    $0x40,%eax
  cmovne %edx,%eax
  ret
L15:
  mov    $0x20,%eax
L49:
  ret
L41:
  mov    $0x2,%eax
  ret
L5:
  mov    $0x4,%eax
  ret
L17:
  mov    $0x8,%eax
  ret
L33:
  mov    $0x10,%eax
  ret
```

assistant: ```c
int VisibleContents(int contents) {
  int i;
  for (i = 1; i <= 64; i <<= 1)
    if (contents & i)
      return i;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <speed_nothing@plt>
  mov    $0x0,%eax
  call   <speed_empty@plt>
  mov    $0x0,%eax
  call   <speed_bigint_mul136@plt>
  mov    $0x0,%eax
  call   <speed_bigint_mul256@plt>
  mov    $0x0,%eax
  call   <speed_salsa20@plt>
  mov    $0x0,%eax
  call   <speed_poly1305@plt>
  mov    $0x0,%eax
  call   <speed_sha512@plt>
  mov    $0x0,%eax
  call   <speed_curve25519@plt>
  mov    $0x0,%eax
  call   <speed_ed25519@plt>
  mov    $0x0,%eax
  call   <avr_end@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  speed_nothing();
  speed_empty();
  speed_bigint_mul136();
  speed_bigint_mul256();
  speed_salsa20();
  speed_poly1305();
  speed_sha512();
  speed_curve25519();
  speed_ed25519();
  avr_end();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <speed_nothing@plt>
  mov    $0x0,%eax
  call   <speed_empty@plt>
  mov    $0x0,%eax
  call   <speed_bigint_mul136@plt>
  mov    $0x0,%eax
  call   <speed_bigint_mul256@plt>
  mov    $0x0,%eax
  call   <speed_salsa20@plt>
  mov    $0x0,%eax
  call   <speed_poly1305@plt>
  mov    $0x0,%eax
  call   <speed_sha512@plt>
  mov    $0x0,%eax
  call   <speed_curve25519@plt>
  mov    $0x0,%eax
  call   <speed_ed25519@plt>
  mov    $0x0,%eax
  call   <avr_end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  speed_nothing();
  speed_empty();
  speed_bigint_mul136();
  speed_bigint_mul256();
  speed_salsa20();
  speed_poly1305();
  speed_sha512();
  speed_curve25519();
  speed_ed25519();
  avr_end();
  return 0;
}
```