ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flattenData>:
  endbr64
  movapd %xmm0,%xmm8
  test   %ecx,%ecx
  jle    L35
  lea    0x4(%rdi),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  lea    -0x1(%rcx),%eax
  seta   %r8b
  cmp    $0x2,%eax
  seta   %al
  test   %al,%r8b
  je     L3
  lea    0x4(%rdx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L3
  mov    %ecx,%r8d
  movapd %xmm1,%xmm7
  movapd %xmm0,%xmm6
  xor    %eax,%eax
  shr    $0x2,%r8d
  unpcklpd %xmm7,%xmm7
  unpcklpd %xmm6,%xmm6
  shl    $0x4,%r8
  cs nopw 0x0(%rax,%rax,1)
L29:
  movlps 0x8(%rdx,%rax,1),%xmm5
  cvtps2pd (%rdx,%rax,1),%xmm2
  movlps 0x8(%rdi,%rax,1),%xmm4
  cvtps2pd (%rdi,%rax,1),%xmm0
  mulpd  %xmm7,%xmm2
  cvtps2pd %xmm5,%xmm3
  mulpd  %xmm7,%xmm3
  addpd  %xmm6,%xmm2
  addpd  %xmm6,%xmm3
  subpd  %xmm2,%xmm0
  cvtps2pd %xmm4,%xmm2
  subpd  %xmm3,%xmm2
  cvtpd2ps %xmm0,%xmm0
  cvtpd2ps %xmm2,%xmm2
  movlhps %xmm2,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L29
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  test   $0x3,%cl
  je     L35
  mov    %r8d,%r9d
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx,%r9,4),%xmm2
  mulsd  %xmm1,%xmm2
  cvtss2sd (%rdi,%r9,4),%xmm0
  lea    0x0(,%r9,4),%rax
  addsd  %xmm8,%xmm2
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi,%r9,4)
  lea    0x1(%r8),%r9d
  cmp    %r9d,%ecx
  jle    L35
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  add    $0x2,%r8d
  cvtss2sd 0x4(%rdx,%rax,1),%xmm2
  mulsd  %xmm1,%xmm2
  cvtss2sd 0x4(%rdi,%rax,1),%xmm0
  addsd  %xmm8,%xmm2
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x4(%rsi,%rax,1)
  cmp    %r8d,%ecx
  jle    L35
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rdx,%rax,1),%xmm2
  mulsd  %xmm2,%xmm1
  cvtss2sd 0x8(%rdi,%rax,1),%xmm0
  addsd  %xmm8,%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%rsi,%rax,1)
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L37:
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx,%rax,4),%xmm2
  mulsd  %xmm1,%xmm2
  cvtss2sd (%rdi,%rax,4),%xmm0
  addsd  %xmm8,%xmm2
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L37
L35:
  ret
```

assistant: ```c
void flattenData(data, flat, x, npix, z0, dz) float *data;
float *flat;
float *x;
int npix;
double z0, dz;
{
  register int i;
  for (i = 0; i < npix; i++)
    flat[i] = data[i] - (x[i] * dz + z0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<poly_eval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  jmp    L23
L3:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  call   <abort@plt>
L13:
  movzbl -0x24(%rbp),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x1,(%rax)
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x24(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0xe(%rbp),%edx
  movzbl -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply@plt>
  mov    %al,-0x24(%rbp)
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L34
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <inner_product@plt>
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movzbl -0xd(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
unsigned char poly_eval(unsigned char *poly, size_t len, unsigned char at) {
  if (len == 1)
    return *poly;
  unsigned char *x = malloc(len);
  if (!x)
    abort();
  unsigned char at_copy = at;
  x[0] = 1;
  for (int i = 1; i < len; i++) {
    x[i] = at;
    at = multiply(at, at_copy);
  }
  unsigned char ret = inner_product(poly, x, len);
  free(x);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<poly_eval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %edx,0xc(%rsp)
  cmp    $0x1,%rsi
  je     L47
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L25
L38:
  movb   $0x1,(%r14)
  cmp    $0x1,%r12
  jbe    L35
  lea    0x1(%r14),%rbx
  lea    (%r14,%r12,1),%r13
  movzbl 0xc(%rsp),%eax
  movzbl %bpl,%ebp
L34:
  mov    %al,(%rbx)
  movzbl %al,%edi
  mov    %ebp,%esi
  call   <multiply@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L34
L35:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <inner_product@plt>
  mov    %eax,%ebx
  mov    %r14,%rdi
  call   <free@plt>
L37:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  movzbl (%rdi),%ebx
  jmp    L37
L25:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L38
```

assistant: ```c
unsigned char poly_eval(unsigned char *poly, size_t len, unsigned char at) {
  if (len == 1)
    return *poly;
  unsigned char *x = malloc(len);
  if (!x)
    abort();
  unsigned char at_copy = at;
  x[0] = 1;
  for (int i = 1; i < len; i++) {
    x[i] = at;
    at = multiply(at, at_copy);
  }
  unsigned char ret = inner_product(poly, x, len);
  free(x);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<poly_eval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    $0x1,%rsi
  je     L0
  mov    %rsi,%rdi
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %edx,%ebx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L33
L13:
  movb   $0x1,(%r14)
  movzbl %bpl,%ebp
  lea    0x1(%r14),%r15
  lea    (%r14,%r12,1),%r13
  cmp    $0x1,%r12
  jbe    L2
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %bl,(%r15)
  movzbl %bl,%edi
  mov    %ebp,%esi
  add    $0x1,%r15
  call   <multiply@plt>
  mov    %eax,%ebx
  cmp    %r13,%r15
  jne    L23
L2:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <inner_product@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L16:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L0:
  movzbl (%rdi),%r12d
  jmp    L16
L33:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L13
```

assistant: ```c
unsigned char poly_eval(unsigned char *poly, size_t len, unsigned char at) {
  if (len == 1)
    return *poly;
  unsigned char *x = malloc(len);
  if (!x)
    abort();
  unsigned char at_copy = at;
  x[0] = 1;
  for (int i = 1; i < len; i++) {
    x[i] = at;
    at = multiply(at, at_copy);
  }
  unsigned char ret = inner_product(poly, x, len);
  free(x);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<poly_eval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    $0x1,%rsi
  je     L39
  mov    %rsi,%rdi
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %edx,%ebx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L54
L11:
  movb   $0x1,(%r14)
  movzbl %bpl,%ebp
  lea    0x1(%r14),%r15
  lea    (%r14,%r12,1),%r13
  cmp    $0x1,%r12
  jbe    L28
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %bl,(%r15)
  movzbl %bl,%edi
  mov    %ebp,%esi
  add    $0x1,%r15
  call   <multiply@plt>
  mov    %eax,%ebx
  cmp    %r15,%r13
  jne    L49
L28:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <inner_product@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L50:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L39:
  movzbl (%rdi),%r12d
  jmp    L50
L54:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L11
```

assistant: ```c
unsigned char poly_eval(unsigned char *poly, size_t len, unsigned char at) {
  if (len == 1)
    return *poly;
  unsigned char *x = malloc(len);
  if (!x)
    abort();
  unsigned char at_copy = at;
  x[0] = 1;
  for (int i = 1; i < len; i++) {
    x[i] = at;
    at = multiply(at, at_copy);
  }
  unsigned char ret = inner_product(poly, x, len);
  free(x);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<r_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L17
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L11
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
pid_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L12:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  mov    D8(%rip),%rcx
  mov    D0(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L12
L6:
  pop    %rbx
  ret
```

assistant: ```c
pid_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L17:
  mov    D16(%rip),%rdx
  mov    D18(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L21
L23:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L17
L21:
  pop    %rbx
  ret
```

assistant: ```c
pid_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L8:
  mov    D12(%rip),%rdx
  mov    D18(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L17
L13:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L8
L17:
  pop    %rbx
  ret
```

assistant: ```c
pid_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L82
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L34
L82:
  movl   $0x2,-0xc(%rbp)
  jmp    L71
L6:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L12
  addl   $0x1,-0xc(%rbp)
L71:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L6
  jmp    L48
L12:
  nop
L48:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  je     L7
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L34
L7:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L34:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D41
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D35
type_guessed: string

tool: D17: Enter a number

tool: D41: %d

tool: D22: The number is: %d


tool: D7: Prime number.

tool: D35: Not prime.

assistant: ```c
int main() {
  int n, c;
  printf("Enter a number\n");
  scanf("%d", &n);
  printf("The number is: %d\n", n);
  if (n == 2)
    printf("Prime number.\n");
  else {
    for (c = 2; c <= n - 1; c++) {
      if (n % c == 0)
        break;
    }
    if (c != n)
      printf("Not prime.\n");
    else
      printf("Prime number.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  je     L68
  jle    L32
  test   $0x1,%sil
  je     L32
  mov    $0x2,%ecx
L78:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  je     L77
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L78
L32:
  lea    D34(%rip),%rdi
  call   <puts@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L68:
  lea    D52(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L77:
  lea    D52(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type_infered: string
name: unpack_data
arguments: data_tag: D40
type_infered: string
name: unpack_data
arguments: data_tag: D36
type_infered: string
name: unpack_data
arguments: data_tag: D34
type_infered: string
name: unpack_data
arguments: data_tag: D52
type_infered: string

tool: D22: Enter a number

tool: D40: %d

tool: D36: The number is: %d


tool: D34: Not prime.

tool: D52: Prime number.

assistant: ```c
int main() {
  int n, c;
  printf("Enter a number\n");
  scanf("%d", &n);
  printf("The number is: %d\n", n);
  if (n == 2)
    printf("Prime number.\n");
  else {
    for (c = 2; c <= n - 1; c++) {
      if (n % c == 0)
        break;
    }
    if (c != n)
      printf("Not prime.\n");
    else
      printf("Prime number.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D44(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  je     L13
  jle    L11
  test   $0x1,%sil
  je     L11
  mov    $0x2,%ecx
  jmp    L45
  nop
L62:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L11
L45:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L62
L13:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L46
L11:
  lea    D3(%rip),%rdi
  call   <puts@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D44
type: string
name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D43
type: string
name: unpack_data
arguments: label: D38
type: string
name: unpack_data
arguments: label: D3
type: string

tool: D44: Enter a number

tool: D15: %d

tool: D43: The number is: %d


tool: D38: Prime number.

tool: D3: Not prime.

assistant: ```c
int main() {
  int n, c;
  printf("Enter a number\n");
  scanf("%d", &n);
  printf("The number is: %d\n", n);
  if (n == 2)
    printf("Prime number.\n");
  else {
    for (c = 2; c <= n - 1; c++) {
      if (n % c == 0)
        break;
    }
    if (c != n)
      printf("Not prime.\n");
    else
      printf("Prime number.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  je     L19
  jle    L64
  test   $0x1,%sil
  je     L64
  mov    $0x2,%ecx
  jmp    L48
  nop
L20:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L64
L48:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L20
L19:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  jmp    L13
L64:
  lea    D8(%rip),%rdi
  call   <puts@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string

tool: D15: Enter a number

tool: D17: %d

tool: D27: The number is: %d


tool: D4: Prime number.

tool: D8: Not prime.

assistant: ```c
int main() {
  int n, c;
  printf("Enter a number\n");
  scanf("%d", &n);
  printf("The number is: %d\n", n);
  if (n == 2)
    printf("Prime number.\n");
  else {
    for (c = 2; c <= n - 1; c++) {
      if (n % c == 0)
        break;
    }
    if (c != n)
      printf("Not prime.\n");
    else
      printf("Prime number.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Xorriso_option_read_mkisofsrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Xorriso_read_mkisofsrc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Xorriso_option_read_mkisofsrc(struct XorrisO *xorriso, int flag) {
  int ret;
  ret = Xorriso_read_mkisofsrc(xorriso, 0);
  return (ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<Xorriso_option_read_mkisofsrc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <Xorriso_read_mkisofsrc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Xorriso_option_read_mkisofsrc(struct XorrisO *xorriso, int flag) {
  int ret;
  ret = Xorriso_read_mkisofsrc(xorriso, 0);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Xorriso_option_read_mkisofsrc>:
  endbr64
  xor    %esi,%esi
  jmp    1050 <Xorriso_read_mkisofsrc@plt>
```

assistant: ```c
int Xorriso_option_read_mkisofsrc(struct XorrisO *xorriso, int flag) {
  int ret;
  ret = Xorriso_read_mkisofsrc(xorriso, 0);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Xorriso_option_read_mkisofsrc>:
  endbr64
  xor    %esi,%esi
  jmp    1050 <Xorriso_read_mkisofsrc@plt>
```

assistant: ```c
int Xorriso_option_read_mkisofsrc(struct XorrisO *xorriso, int flag) {
  int ret;
  ret = Xorriso_read_mkisofsrc(xorriso, 0);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L5
L29:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
L34:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' && s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L8
L30:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L6
  cmp    %dl,%cl
  jne    L13
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L30
  mov    $0x0,%eax
  ret
L8:
  ret
L13:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' && s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L47
  jmp    L1
  nop
L19:
  cmp    %dl,%cl
  jne    L48
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L44
L47:
  movsbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L19
L44:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
L1:
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' && s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L25
  jmp    L23
  nop
L36:
  cmp    %dl,%cl
  jne    L39
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L21
L25:
  movsbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L36
L21:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
L23:
  ret
```

assistant: ```c
int ft_strcmp(char *s1, char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' && s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x7,%eax
  cmp    $0x6,%eax
  ja     L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L6
L3:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```