user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D65(%rip),%rdi
  lea    D37(%rip),%r13
  push   %r12
  lea    D47(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L39:
  movss  0x14(%rsp),%xmm4
  comiss %xmm4,%xmm3
  movaps %xmm4,%xmm0
  unpcklps %xmm3,%xmm0
  ja     L43
L77:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %rbx,%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm4,%xmm2
  cvtss2sd %xmm3,%xmm1
  call   <printf@plt>
L3:
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm2
  comiss %xmm0,%xmm1
  jb     L66
  comiss %xmm1,%xmm2
  jae    L55
L66:
  mov    %rbp,%rdi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm2
  mov    $0x3,%eax
  call   <printf@plt>
  movq   0xc(%rsp),%xmm3
  movaps %xmm3,%xmm1
  movaps %xmm3,%xmm0
  shufps $0xe5,%xmm3,%xmm3
  comiss %xmm3,%xmm1
  shufps $0xe1,%xmm0,%xmm0
  jbe    L39
  movlps %xmm0,0xc(%rsp)
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm2
  call   <printf@plt>
  movss  0x10(%rsp),%xmm3
  movss  0xc(%rsp),%xmm1
  jmp    L39
  nopl   0x0(%rax)
L43:
  movlps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %r12,%rdi
  cvtss2sd %xmm1,%xmm0
  mov    $0x3,%eax
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm3,%xmm2
  cvtss2sd %xmm4,%xmm1
  call   <printf@plt>
  movss  0x14(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  movss  0xc(%rsp),%xmm1
  jmp    L77
  nopl   0x0(%rax)
L55:
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D65
data_type: string
name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D47
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: D65: Please enter three numbers separated by spaces > 

tool: D37: Swap 2 & 1 for %f, %f, %f


tool: D47: Swap 2 & 3 for %f, %f, %f


tool: D14: Before swaps:  %f, %f, %f


tool: D8: After swaps: %f, %f, %f


tool: D29: %f%f%f

tool: D12: %.0f is the median


assistant: ```c
int main() {
  float data[3], temp = 0;
  printf("Please enter three numbers separated by spaces > ");
  scanf("%f%f%f", &data[1], &data[2], &data[3]);
  while (!((data[1] <= data[2]) && (data[2] <= data[3]))) {
    printf("Before swaps:  %f, %f, %f\n", data[1], data[2], data[3]);
    if (data[2] < data[1]) {
      temp = data[2];
      data[2] = data[1];
      data[1] = temp;
      printf("Swap 2 & 1 for %f, %f, %f\n", data[1], data[2], data[3]);
    }
    if (data[3] < data[2]) {
      temp = data[2];
      data[2] = data[3];
      data[3] = temp;
      printf("Swap 2 & 3 for %f, %f, %f\n", data[1], data[2], data[3]);
    }
    printf("After swaps: %f, %f, %f\n", data[1], data[2], data[3]);
  }
  printf("%.0f is the median\n", data[2]);
  return 0;
}
```