ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dump_trace>:
  endbr64
  push   %r14
  mov    $0x10,%ecx
  mov    $0x10,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <backtrace@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <backtrace_symbols@plt>
  test   %rax,%rax
  je     L18
  lea    D21(%rip),%rdi
  mov    %rax,%r14
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L45
  mov    %r14,%rbp
  xor    %ebx,%ebx
  lea    D23(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x0(%rbp),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L30
L45:
  mov    %r14,%rdi
  call   <free@plt>
L1:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L18:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D21
data_type: string
name: unpack_data
arguments: data_tag: D23
data_type: string
name: unpack_data
arguments: data_tag: D12
data_type: string

tool: D21:  Stack Trace: 

tool: D23:  [%d] %s 


tool: D12:  Memory is not enough while dump Stack Trace! 

assistant: ```c
void dump_trace() {
  void *stack_trace[16] = {0};
  char **stack_strings = NULL;
  int stack_depth = 0;
  int i = 0;
  stack_depth = backtrace(stack_trace, 16);
  stack_strings = (char **)backtrace_symbols(stack_trace, stack_depth);
  if (NULL == stack_strings) {
    printf(" Memory is not enough while dump Stack Trace! \r\n");
    return;
  }
  printf(" Stack Trace: \r\n");
  for (i = 0; i < stack_depth; ++i) {
    printf(" [%d] %s \r\n", i, stack_strings[i]);
  }
  free(stack_strings);
  stack_strings = NULL;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x8,%esi
  mov    $0x4,%edi
  call   <rec_eukl@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D11
type: string

tool: D14: %d


tool: D11: pause

assistant: ```c
int main() {
  int result;
  result = rec_eukl(4, 8);
  printf("%d\n", result);
  system("pause");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0x4,%edi
  call   <rec_eukl@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string

tool: D15: %d


tool: D11: pause

assistant: ```c
int main() {
  int result;
  result = rec_eukl(4, 8);
  printf("%d\n", result);
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0x4,%edi
  call   <rec_eukl@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D12: %d


tool: D2: pause

assistant: ```c
int main() {
  int result;
  result = rec_eukl(4, 8);
  printf("%d\n", result);
  system("pause");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0x4,%edi
  call   <rec_eukl@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D18: %d


tool: D0: pause

assistant: ```c
int main() {
  int result;
  result = rec_eukl(4, 8);
  printf("%d\n", result);
  system("pause");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arrayread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x3fffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  subl   $0x2,-0x8(%rbp)
L3:
  cmpl   $0x0,-0x8(%rbp)
  jns    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int arrayread(char *arr) {
  int i = 1024 * 1024 * 1024 - 1, r = 0;
  for (; i >= 0; i -= 2) {
    r += arr[i];
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arrayread>:
  endbr64
  lea    0x3fffffff(%rdi),%rax
  lea    -0x1(%rdi),%rsi
  mov    $0x0,%edx
L4:
  movsbl (%rax),%ecx
  add    %ecx,%edx
  sub    $0x2,%rax
  cmp    %rsi,%rax
  jne    L4
  mov    %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int arrayread(char *arr) {
  int i = 1024 * 1024 * 1024 - 1, r = 0;
  for (; i >= 0; i -= 2) {
    r += arr[i];
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arrayread>:
  endbr64
  lea    0x3fffffff(%rdi),%rax
  lea    -0x1(%rdi),%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl (%rax),%edx
  sub    $0x2,%rax
  add    %edx,%r8d
  cmp    %rcx,%rax
  jne    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
__attribute__((no)) int arrayread(char *arr) {
  int i = 1024 * 1024 * 1024 - 1, r = 0;
  for (; i >= 0; i -= 2) {
    r += arr[i];
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arrayread>:
  endbr64
  lea    0x3fffffff(%rdi),%rax
  lea    -0x1(%rdi),%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl (%rax),%edx
  sub    $0x2,%rax
  add    %edx,%r8d
  cmp    %rax,%rcx
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
__attribute__((no)) int arrayread(char *arr) {
  int i = 1024 * 1024 * 1024 - 1, r = 0;
  for (; i >= 0; i -= 2) {
    r += arr[i];
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__SSAT16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L86
  cmpl   $0x20,-0x18(%rbp)
  ja     L86
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L32
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L4
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L4
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  sar    $0x10,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L6
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L57
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L57
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L57:
  mov    -0x10(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  or     %edx,%eax
  jmp    L33
L86:
  mov    -0x14(%rbp),%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int32_t __SSAT16(int32_t val, uint32_t sat) {
  if ((sat >= 1U) && (sat <= 32U)) {
    const int32_t max = (int32_t)((1U << (sat - 1U)) - 1U);
    const int32_t min = -1 - max;
    int32_t valHi = val >> 16;
    if (valHi > max) {
      valHi = max;
    } else if (valHi < min) {
      valHi = min;
    }
    int32_t valLo = (val << 16) >> 16;
    if (valLo > max) {
      valLo = max;
    } else if (valLo < min) {
      valLo = min;
    }
    return (valHi << 16) | (valLo & 0xFFFF);
  }
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__SSAT16>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rsi),%ecx
  cmp    $0x1f,%ecx
  jbe    L1
L19:
  ret
L1:
  mov    $0x1,%edx
  shl    %cl,%edx
  lea    -0x1(%rdx),%ecx
  neg    %edx
  sar    $0x10,%edi
  cmp    %edi,%edx
  mov    %edi,%esi
  cmovge %edx,%esi
  cmp    %edi,%ecx
  cmovl  %ecx,%esi
  cwtl
  cmp    %eax,%edx
  cmovl  %eax,%edx
  cmp    %eax,%ecx
  cmovge %edx,%ecx
  shl    $0x10,%esi
  movzwl %cx,%eax
  or     %esi,%eax
  jmp    L19
```

assistant: ```c
__attribute__((always_)) int32_t __SSAT16(int32_t val, uint32_t sat) {
  if ((sat >= 1U) && (sat <= 32U)) {
    const int32_t max = (int32_t)((1U << (sat - 1U)) - 1U);
    const int32_t min = -1 - max;
    int32_t valHi = val >> 16;
    if (valHi > max) {
      valHi = max;
    } else if (valHi < min) {
      valHi = min;
    }
    int32_t valLo = (val << 16) >> 16;
    if (valLo > max) {
      valLo = max;
    } else if (valLo < min) {
      valLo = min;
    }
    return (valHi << 16) | (valLo & 0xFFFF);
  }
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__SSAT16>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %edi,%eax
  cmp    $0x1f,%ecx
  jbe    L6
  ret
  nop
L6:
  mov    $0x1,%edx
  sar    $0x10,%edi
  cwtl
  shl    %cl,%edx
  mov    %edi,%esi
  lea    -0x1(%rdx),%ecx
  neg    %edx
  cmp    %edi,%edx
  cmovge %edx,%esi
  cmp    %edi,%ecx
  cmovl  %ecx,%esi
  cmp    %eax,%edx
  cmovl  %eax,%edx
  cmp    %eax,%ecx
  cmovge %edx,%ecx
  shl    $0x10,%esi
  movzwl %cx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int32_t __SSAT16(int32_t val, uint32_t sat) {
  if ((sat >= 1U) && (sat <= 32U)) {
    const int32_t max = (int32_t)((1U << (sat - 1U)) - 1U);
    const int32_t min = -1 - max;
    int32_t valHi = val >> 16;
    if (valHi > max) {
      valHi = max;
    } else if (valHi < min) {
      valHi = min;
    }
    int32_t valLo = (val << 16) >> 16;
    if (valLo > max) {
      valLo = max;
    } else if (valLo < min) {
      valLo = min;
    }
    return (valHi << 16) | (valLo & 0xFFFF);
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__SSAT16>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %edi,%eax
  cmp    $0x1f,%ecx
  jbe    L5
  ret
  nop
L5:
  mov    $0x1,%edx
  sar    $0x10,%edi
  cwtl
  shl    %cl,%edx
  mov    %edi,%esi
  lea    -0x1(%rdx),%ecx
  neg    %edx
  cmp    %edi,%edx
  cmovge %edx,%esi
  cmp    %edi,%ecx
  cmovl  %ecx,%esi
  cmp    %eax,%edx
  cmovl  %eax,%edx
  cmp    %eax,%ecx
  cmovge %edx,%ecx
  shl    $0x10,%esi
  movzwl %cx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int32_t __SSAT16(int32_t val, uint32_t sat) {
  if ((sat >= 1U) && (sat <= 32U)) {
    const int32_t max = (int32_t)((1U << (sat - 1U)) - 1U);
    const int32_t min = -1 - max;
    int32_t valHi = val >> 16;
    if (valHi > max) {
      valHi = max;
    } else if (valHi < min) {
      valHi = min;
    }
    int32_t valLo = (val << 16) >> 16;
    if (valLo > max) {
      valLo = max;
    } else if (valLo < min) {
      valLo = min;
    }
    return (valHi << 16) | (valLo & 0xFFFF);
  }
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D21: Soma de valores

tool: D8: %d

tool: D17: 
 O resultado %d

assistant: ```c
main() {
  int a;
  printf("Soma de valores\n");
  scanf("%d", &a);
  printf("\n O resultado %d", a + a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string

tool: D4: Soma de valores

tool: D21: %d

tool: D13: 
 O resultado %d

assistant: ```c
main() {
  int a;
  printf("Soma de valores\n");
  scanf("%d", &a);
  printf("\n O resultado %d", a + a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D20(%rip),%rdi
  lea    (%rax,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string

tool: D1: Soma de valores

tool: D29: %d

tool: D20: 
 O resultado %d

assistant: ```c
main() {
  int a;
  printf("Soma de valores\n");
  scanf("%d", &a);
  printf("\n O resultado %d", a + a);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D15(%rip),%rdi
  lea    (%rax,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D15
type: string

tool: D4: Soma de valores

tool: D24: %d

tool: D15: 
 O resultado %d

assistant: ```c
main() {
  int a;
  printf("Soma de valores\n");
  scanf("%d", &a);
  printf("\n O resultado %d", a + a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_bool@plt>
  mov    $0x0,%eax
  call   <test_float@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_bool();
  test_float();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_bool@plt>
  mov    $0x0,%eax
  call   <test_float@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_bool();
  test_float();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_bool@plt>
  xor    %eax,%eax
  call   <test_float@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_bool();
  test_float();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_bool@plt>
  xor    %eax,%eax
  call   <test_float@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_bool();
  test_float();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BinaryOperator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  flds   -0x4(%rbp)
  fldt   0x10(%rbp)
  fmulp  %st,%st(1)
  fstps  -0x4(%rbp)
  flds   -0x4(%rbp)
  fldt   0x10(%rbp)
  fmulp  %st,%st(1)
  fstps  -0x4(%rbp)
  fldl   -0x10(%rbp)
  fldt   0x10(%rbp)
  fmulp  %st,%st(1)
  fstpl  -0x10(%rbp)
  fldl   -0x10(%rbp)
  fldt   0x10(%rbp)
  fmulp  %st,%st(1)
  fstpl  -0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BinaryOperator(float f, double d, long double ld) {
  f = f * d;
  f = d * f;
  f = f * ld;
  f = ld * f;
  d = d * ld;
  d = ld * d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BinaryOperator>:
  endbr64
  ret
```

assistant: ```c
void BinaryOperator(float f, double d, long double ld) {
  f = f * d;
  f = d * f;
  f = f * ld;
  f = ld * f;
  d = d * ld;
  d = ld * d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BinaryOperator>:
  endbr64
  ret
```

assistant: ```c
void BinaryOperator(float f, double d, long double ld) {
  f = f * d;
  f = d * f;
  f = f * ld;
  f = ld * f;
  d = d * ld;
  d = ld * d;
}
```
user: What is the c source code of the assembly code below?

```asm
<BinaryOperator>:
  endbr64
  ret
```

assistant: ```c
void BinaryOperator(float f, double d, long double ld) {
  f = f * d;
  f = d * f;
  f = f * ld;
  f = ld * f;
  d = d * ld;
  d = ld * d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%r12
  mov    $0x0,%r13d
L46:
  mov    $0x0,%ebx
L26:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%r12,%rbx,1)
  cmp    $0xa,%al
  je     L15
  add    $0x1,%rbx
  cmp    $0x20,%al
  jne    L26
  movslq %ebp,%rbp
  movslq %r13d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%rbp,%rax,1)
  add    $0x1,%r13d
  add    $0x64,%r12
  jmp    L46
L15:
  movslq %ebx,%rbp
  movslq %r13d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%rbp,%rax,1)
  test   %r13d,%r13d
  jle    L13
  movslq %r13d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    (%rsp,%rax,1),%rbx
  lea    -0x64(%r14,%rax,1),%rbp
  lea    -0x1(%r13),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  sub    %rax,%rbp
  lea    D7(%rip),%r12
L16:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x64,%rbx
  cmp    %rbp,%rbx
  jne    L16
L13:
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x2720,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string

tool: D7: %s 

tool: D17: %s

assistant: ```c
int main() {
  char a[100][100];
  int len = 0;
  int i = 0;
  while ((a[len][i++] = getchar()) != '\n') {
    if (a[len][i - 1] == ' ') {
      a[len][i - 1] = '\0';
      i = 0;
      len++;
    }
  }
  a[len][i - 1] = '\0';
  for (int j = len; j > 0; j--)
    printf("%s ", a[j]);
  printf("%s", a[0]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rbp
L12:
  xor    %r14d,%r14d
  jmp    L63
  nopl   0x0(%rax)
L37:
  add    $0x1,%r14
  cmp    $0x20,%al
  je     L62
L63:
  xor    %eax,%eax
  movslq %r14d,%rbx
  call   <getchar@plt>
  mov    %al,0x0(%rbp,%r14,1)
  cmp    $0xa,%al
  jne    L37
  movslq %r12d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    0x2720(%rax),%rcx
  lea    (%rsp,%rcx,1),%rdx
  movb   $0x0,-0x2720(%rbx,%rdx,1)
  test   %r12d,%r12d
  je     L33
  lea    -0x64(%r13,%rax,1),%rbp
  lea    0x0(%r13,%rax,1),%rbx
  lea    -0x1(%r12),%eax
  lea    D8(%rip),%r12
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  sub    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  sub    $0x64,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L18
L33:
  mov    %r13,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x2720,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  movslq %r12d,%rax
  add    $0x64,%rbp
  add    $0x1,%r12d
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%rbx,%rax,1)
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string

tool: D8: %s 

tool: D11: %s

assistant: ```c
int main() {
  char a[100][100];
  int len = 0;
  int i = 0;
  while ((a[len][i++] = getchar()) != '\n') {
    if (a[len][i - 1] == ' ') {
      a[len][i - 1] = '\0';
      i = 0;
      len++;
    }
  }
  a[len][i - 1] = '\0';
  for (int j = len; j > 0; j--)
    printf("%s ", a[j]);
  printf("%s", a[0]);
  return 0;
}
```