ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L73
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L73:
  mov    $0x0,%eax
  jmp    L5
L17:
  mov    -0x20(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L36
  mov    $0x0,%eax
  jmp    L5
L36:
  mov    -0x20(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L56
  mov    $0x0,%eax
  jmp    L5
L56:
  mov    -0x20(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L5
L34:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string

tool: D21: .

tool: D3: /

tool: D12: r

assistant: ```c
char *read_file(int len, char *name) {
  if (!name || !*name)
    return NULL;
  if (strchr(name, "."))
    return NULL;
  else if (strchr(name, "/"))
    return NULL;
  FILE *fp = fopen(name, "r");
  if (!fp)
    return NULL;
  char *buf = calloc(len + 1, 1);
  fread(buf, 1, len, fp);
  fclose(fp);
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L25
  mov    %edi,%r12d
  mov    $0x0,%ebp
  cmpb   $0x0,(%rsi)
  je     L4
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  lea    0x1(%r12),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L4:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %rsi,%rbp
  jmp    L4
L5:
  mov    %rax,%rbp
  jmp    L4
```

tool_calls: name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string

tool: D28: .

tool: D1: /

tool: D26: r

assistant: ```c
char *read_file(int len, char *name) {
  if (!name || !*name)
    return NULL;
  if (strchr(name, "."))
    return NULL;
  else if (strchr(name, "/"))
    return NULL;
  FILE *fp = fopen(name, "r");
  if (!fp)
    return NULL;
  char *buf = calloc(len + 1, 1);
  fread(buf, 1, len, fp);
  fclose(fp);
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rsi,%rsi
  je     L28
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbp
  je     L28
  mov    %edi,%r13d
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L28
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L28
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
  lea    0x1(%r13),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rbp,%rcx
  mov    %r13d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <fread@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D3
data_type: string
name: read_data
arguments: tag: D15
data_type: string

tool: D22: .

tool: D3: /

tool: D15: r

assistant: ```c
char *read_file(int len, char *name) {
  if (!name || !*name)
    return NULL;
  if (strchr(name, "."))
    return NULL;
  else if (strchr(name, "/"))
    return NULL;
  FILE *fp = fopen(name, "r");
  if (!fp)
    return NULL;
  char *buf = calloc(len + 1, 1);
  fread(buf, 1, len, fp);
  fclose(fp);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rsi,%rsi
  je     L15
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbp
  je     L15
  mov    %edi,%r13d
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
  lea    D29(%rip),%rsi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbp,%rdi
  lea    D20(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  lea    0x1(%r13),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rbp,%rcx
  mov    %r13d,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <fread@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D20
datatype: string

tool: D18: .

tool: D29: /

tool: D20: r

assistant: ```c
char *read_file(int len, char *name) {
  if (!name || !*name)
    return NULL;
  if (strchr(name, "."))
    return NULL;
  else if (strchr(name, "/"))
    return NULL;
  FILE *fp = fopen(name, "r");
  if (!fp)
    return NULL;
  char *buf = calloc(len + 1, 1);
  fread(buf, 1, len, fp);
  fclose(fp);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xe,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    %eax
  cmp    $0x7,%eax
  je     L51
  mov    $0x1,%eax
  jmp    L129
L51:
  mov    -0xc(%rbp),%eax
  sar    $0x2,%eax
  cmp    $0x3,%eax
  je     L85
  mov    $0x2,%eax
  jmp    L129
L85:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  cmp    $0x1c,%eax
  je     L116
  mov    $0x3,%eax
  jmp    L129
L116:
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  cmp    $0x38,%eax
  je     L68
  mov    $0x4,%eax
  jmp    L129
L68:
  movl   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  cmp    $0x1,%eax
  je     L137
  mov    $0x5,%eax
  jmp    L129
L137:
  mov    -0x8(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    $0x70,%eax
  je     L91
  mov    $0x6,%eax
  jmp    L129
L91:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L138
  mov    $0x7,%eax
  jmp    L129
L138:
  mov    $0x0,%eax
L129:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 14;
  if (a >> 1 != 7)
    return 1;
  if (a >> 2 != 3)
    return 2;
  if (a << 1 != 28)
    return 3;
  if (a << 2 != 56)
    return 4;
  int b = 3;
  if (a >> b != 1)
    return 5;
  if (a << b != 112)
    return 6;
  int c = a >> (b - 1);
  if (c != 3)
    return 7;
  if ((1 << 16) - 1 != 65535)
    return 8;
  if (3 << 8 != 768)
    return 9;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 14;
  if (a >> 1 != 7)
    return 1;
  if (a >> 2 != 3)
    return 2;
  if (a << 1 != 28)
    return 3;
  if (a << 2 != 56)
    return 4;
  int b = 3;
  if (a >> b != 1)
    return 5;
  if (a << b != 112)
    return 6;
  int c = a >> (b - 1);
  if (c != 3)
    return 7;
  if ((1 << 16) - 1 != 65535)
    return 8;
  if (3 << 8 != 768)
    return 9;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 14;
  if (a >> 1 != 7)
    return 1;
  if (a >> 2 != 3)
    return 2;
  if (a << 1 != 28)
    return 3;
  if (a << 2 != 56)
    return 4;
  int b = 3;
  if (a >> b != 1)
    return 5;
  if (a << b != 112)
    return 6;
  int c = a >> (b - 1);
  if (c != 3)
    return 7;
  if ((1 << 16) - 1 != 65535)
    return 8;
  if (3 << 8 != 768)
    return 9;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 14;
  if (a >> 1 != 7)
    return 1;
  if (a >> 2 != 3)
    return 2;
  if (a << 1 != 28)
    return 3;
  if (a << 2 != 56)
    return 4;
  int b = 3;
  if (a >> b != 1)
    return 5;
  if (a << b != 112)
    return 6;
  int c = a >> (b - 1);
  if (c != 3)
    return 7;
  if ((1 << 16) - 1 != 65535)
    return 8;
  if (3 << 8 != 768)
    return 9;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x1,-0x28(%rbp)
  jle    L18
  cmpl   $0x24,-0x28(%rbp)
  jle    L0
L18:
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L72
L0:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L2
  cmpl   $0xa,-0x28(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2d,(%rax)
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L55:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %edx,%eax
  lea    0x23(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %ecx,%rdx
  lea    D5(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L55
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
  jmp    L39
L79:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
L39:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L79
  mov    -0x8(%rbp),%rax
L72:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int val, char *str, int base) {
  char *rc, *ptr, *low;
  if (base < 2 || base > 36) {
    *str = '\0';
    return str;
  }
  rc = ptr = str;
  if (val < 0 && base == 10)
    *ptr++ = '-';
  low = ptr;
  do {
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmno"
             "pqrstuvwxyz"[35 + val % base];
    val /= base;
  } while (val);
  *ptr-- = '\0';
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%r9d
  lea    -0x2(%rdx),%eax
  cmp    $0x22,%eax
  ja     L58
  test   %edi,%edi
  jns    L37
  cmp    $0xa,%edx
  jne    L37
  lea    0x1(%rsi),%rsi
  movb   $0x2d,(%r10)
L52:
  mov    %rsi,%r8
  lea    D9(%rip),%r11
L18:
  mov    %r8,%rcx
  add    $0x1,%r8
  mov    %edi,%eax
  cltd
  idiv   %r9d
  add    $0x23,%edx
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%edx
  mov    %dl,-0x1(%r8)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L18
  movb   $0x0,(%r8)
  cmp    %rcx,%rsi
  jae    L5
L27:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  movzbl (%rcx),%edx
  mov    %dl,-0x1(%rsi)
  sub    $0x1,%rcx
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L27
L5:
  mov    %r10,%rax
  ret
L58:
  movb   $0x0,(%rsi)
  jmp    L5
L37:
  mov    %r10,%rsi
  jmp    L52
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int val, char *str, int base) {
  char *rc, *ptr, *low;
  if (base < 2 || base > 36) {
    *str = '\0';
    return str;
  }
  rc = ptr = str;
  if (val < 0 && base == 10)
    *ptr++ = '-';
  low = ptr;
  do {
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmno"
             "pqrstuvwxyz"[35 + val % base];
    val /= base;
  } while (val);
  *ptr-- = '\0';
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return rc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  mov    %edx,%r8d
  lea    -0x2(%rdx),%edx
  mov    %edi,%eax
  mov    %rsi,%r9
  cmp    $0x22,%edx
  ja     L33
  test   %edi,%edi
  jns    L77
  cmp    $0xa,%r8d
  jne    L77
  movb   $0x2d,(%r9)
  lea    0x1(%rsi),%rsi
L12:
  mov    %rsi,%rdi
  lea    D1(%rip),%r10
L72:
  cltd
  mov    %rdi,%rcx
  lea    0x1(%rdi),%rdi
  idiv   %r8d
  add    $0x23,%edx
  movslq %edx,%rdx
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rdi)
  test   %eax,%eax
  jne    L72
  movb   $0x0,(%rdi)
  cmp    %rcx,%rsi
  jb     L73
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L63:
  movzbl (%rcx),%edx
L73:
  movzbl (%rsi),%eax
  sub    $0x1,%rcx
  add    $0x1,%rsi
  mov    %dl,-0x1(%rsi)
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L63
L10:
  mov    %r9,%rax
  ret
  nopl   (%rax)
L77:
  mov    %r9,%rsi
  jmp    L12
  nopl   (%rax)
L33:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int val, char *str, int base) {
  char *rc, *ptr, *low;
  if (base < 2 || base > 36) {
    *str = '\0';
    return str;
  }
  rc = ptr = str;
  if (val < 0 && base == 10)
    *ptr++ = '-';
  low = ptr;
  do {
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmno"
             "pqrstuvwxyz"[35 + val % base];
    val /= base;
  } while (val);
  *ptr-- = '\0';
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  mov    %edx,%r8d
  lea    -0x2(%rdx),%edx
  mov    %edi,%eax
  mov    %rsi,%r9
  cmp    $0x22,%edx
  ja     L47
  test   %edi,%edi
  jns    L60
  cmp    $0xa,%r8d
  jne    L60
  movb   $0x2d,(%r9)
  lea    0x1(%rsi),%rsi
L10:
  mov    %rsi,%rdi
  lea    D6(%rip),%r10
L25:
  cltd
  mov    %rdi,%rcx
  lea    0x1(%rdi),%rdi
  idiv   %r8d
  add    $0x23,%edx
  movslq %edx,%rdx
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rdi)
  test   %eax,%eax
  jne    L25
  movb   $0x0,(%rdi)
  cmp    %rcx,%rsi
  jae    L4
  nopl   (%rax)
L26:
  movzbl (%rsi),%eax
  movzbl (%rcx),%edx
  add    $0x1,%rsi
  sub    $0x1,%rcx
  mov    %dl,-0x1(%rsi)
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L26
L4:
  mov    %r9,%rax
  ret
  nopl   (%rax)
L60:
  mov    %r9,%rsi
  jmp    L10
  nopl   (%rax)
L47:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int val, char *str, int base) {
  char *rc, *ptr, *low;
  if (base < 2 || base > 36) {
    *str = '\0';
    return str;
  }
  rc = ptr = str;
  if (val < 0 && base == 10)
    *ptr++ = '-';
  low = ptr;
  do {
    *ptr++ = "zyxwvutsrqponmlkjihgfedcba9876543210123456789abcdefghijklmno"
             "pqrstuvwxyz"[35 + val % base];
    val /= base;
  } while (val);
  *ptr-- = '\0';
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L38
L41:
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L45
L22:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L45:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
L18:
  mov    -0x18(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
char *str_trim(char *ptr) {
  char *end;
  if (!ptr) {
    return NULL;
  }
  while (isspace(*ptr)) {
    ptr++;
  }
  end = ptr + strlen(ptr) - 1;
  while (end > ptr && isspace(*end)) {
    *end-- = 0;
  }
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  jne    L38
  mov    %rdi,%rbx
  jmp    L64
L47:
  add    $0x1,%rbp
L38:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jae    L34
L46:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L43
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L46
  jmp    L64
L34:
  mov    %rbp,%rbx
  jmp    L64
L43:
  mov    %rbp,%rbx
L64:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_trim(char *ptr) {
  char *end;
  if (!ptr) {
    return NULL;
  }
  while (isspace(*ptr)) {
    ptr++;
  }
  end = ptr + strlen(ptr) - 1;
  while (end > ptr && isspace(*end)) {
    *end-- = 0;
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_trim>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L53
  jmp    L37
  nopl   (%rax)
L3:
  add    $0x1,%rbx
L53:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%r12
  cmp    %r12,%rbx
  jb     L39
  jmp    L48
  nop
L26:
  sub    $0x1,%r12
  movb   $0x0,0x1(%r12)
  cmp    %r12,%rbx
  je     L24
L39:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L26
L48:
  mov    %rbx,%r12
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L37:
  xor    %r12d,%r12d
  jmp    L24
```

assistant: ```c
char *str_trim(char *ptr) {
  char *end;
  if (!ptr) {
    return NULL;
  }
  while (isspace(*ptr)) {
    ptr++;
  }
  end = ptr + strlen(ptr) - 1;
  while (end > ptr && isspace(*end)) {
    *end-- = 0;
  }
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_trim>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L9
  jmp    L24
  nopl   (%rax)
L61:
  add    $0x1,%rbx
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L61
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%r12
  cmp    %r12,%rbx
  jb     L14
  jmp    L79
  nop
L45:
  sub    $0x1,%r12
  movb   $0x0,0x1(%r12)
  cmp    %r12,%rbx
  je     L1
L14:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
L79:
  mov    %rbx,%r12
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L24:
  xor    %r12d,%r12d
  jmp    L1
```

assistant: ```c
char *str_trim(char *ptr) {
  char *end;
  if (!ptr) {
    return NULL;
  }
  while (isspace(*ptr)) {
    ptr++;
  }
  end = ptr + strlen(ptr) - 1;
  while (end > ptr && isspace(*end)) {
    *end-- = 0;
  }
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bb_gemm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L34:
  nop
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L22:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L10:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x1,-0xc(%rbp)
  jle    L10
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x1,-0x8(%rbp)
  jle    L22
  addl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x3,-0x10(%rbp)
  jle    L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bb_gemm(int x[4 * 4], int y[4 * 4], int z[4 * 4]) {
  int i, k, j, temp_x;
loopi:
  for (i = 0; i < 4; ++i) {
  loopj:
    for (j = 0; j < 2; ++j) {
      temp_x = 0;
    loopk:
      for (k = 0; k < 2; ++k) {
        temp_x += x[i * 4 + k] * y[k * 4 + j];
      }
      z[i * 4 + j] = temp_x;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bb_gemm>:
  endbr64
  mov    $0x0,%eax
L2:
  mov    (%rdi,%rax,1),%ecx
  imul   (%rsi),%ecx
  mov    0x4(%rdi,%rax,1),%r8d
  imul   0x10(%rsi),%r8d
  add    %r8d,%ecx
  mov    %ecx,(%rdx,%rax,1)
  mov    0x4(%rdi,%rax,1),%ecx
  imul   0x14(%rsi),%ecx
  mov    (%rdi,%rax,1),%r8d
  imul   0x4(%rsi),%r8d
  add    %r8d,%ecx
  mov    %ecx,0x4(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    $0x40,%rax
  jne    L2
  ret
```

assistant: ```c
void bb_gemm(int x[4 * 4], int y[4 * 4], int z[4 * 4]) {
  int i, k, j, temp_x;
loopi:
  for (i = 0; i < 4; ++i) {
  loopj:
    for (j = 0; j < 2; ++j) {
      temp_x = 0;
    loopk:
      for (k = 0; k < 2; ++k) {
        temp_x += x[i * 4 + k] * y[k * 4 + j];
      }
      z[i * 4 + j] = temp_x;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bb_gemm>:
  endbr64
  xor    %eax,%eax
L9:
  mov    (%rdi,%rax,1),%ecx
  mov    0x4(%rdi,%rax,1),%r8d
  imul   (%rsi),%ecx
  imul   0x10(%rsi),%r8d
  add    %r8d,%ecx
  mov    %ecx,(%rdx,%rax,1)
  mov    (%rdi,%rax,1),%ecx
  mov    0x4(%rdi,%rax,1),%r8d
  imul   0x4(%rsi),%ecx
  imul   0x14(%rsi),%r8d
  add    %r8d,%ecx
  mov    %ecx,0x4(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    $0x40,%rax
  jne    L9
  ret
```

assistant: ```c
void bb_gemm(int x[4 * 4], int y[4 * 4], int z[4 * 4]) {
  int i, k, j, temp_x;
loopi:
  for (i = 0; i < 4; ++i) {
  loopj:
    for (j = 0; j < 2; ++j) {
      temp_x = 0;
    loopk:
      for (k = 0; k < 2; ++k) {
        temp_x += x[i * 4 + k] * y[k * 4 + j];
      }
      z[i * 4 + j] = temp_x;
    }
  }
}
```