ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add_vec_i_3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x10(%rsp)
  sub    %ecx,%r8d
  js     L97
  mov    0x38(%rsp),%eax
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %r9d,%edx
  mov    0x48(%rsp),%r9d
  sub    0x40(%rsp),%r9d
  lea    0x1(%r9),%ecx
  sub    %edx,%eax
  js     L97
  test   %ecx,%ecx
  js     L97
  cltq
  cmp    $0xffffffff,%r9d
  lea    0x2(%r9),%ebp
  movslq %r8d,%r8
  lea    0x8(,%rax,8),%r15
  mov    $0x1,%eax
  mov    %rbx,-0x20(%rsp)
  lea    0x8(%rdi,%r8,8),%rbx
  cmovl  %eax,%ebp
  mov    %rdi,-0x30(%rsp)
  mov    %rsi,-0x28(%rsp)
  mov    %ebp,%eax
  mov    %rbx,-0x18(%rsp)
  mov    %ebp,%ebx
  shr    $0x2,%eax
  and    $0xfffffffc,%ebx
  lea    -0x1(%rax),%r10d
  add    $0x1,%r10
  shl    $0x4,%r10
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    -0x30(%rsp),%rax
  xor    %r8d,%r8d
  mov    (%rax),%r14
  mov    -0x28(%rsp),%rax
  mov    (%rax),%r13
  mov    -0x20(%rsp),%rax
  mov    (%rax),%r12
  nopl   0x0(%rax,%rax,1)
L35:
  mov    (%r14,%r8,1),%rsi
  mov    (%r12,%r8,1),%rcx
  mov    0x0(%r13,%r8,1),%rdx
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  seta   %dil
  cmp    $0xffffffff,%r9d
  setne  %al
  setge  %r11b
  and    %r11d,%eax
  test   %al,%dil
  je     L100
  lea    0x4(%rdx),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L100
  cmp    $0x1,%r9d
  jle    L55
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L92:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%rdx,%rax,1),%xmm2
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %r10,%rax
  jne    L92
  cmp    %ebx,%ebp
  je     L89
  mov    %ebx,%edi
  mov    %ebx,%eax
L148:
  mov    %ebp,%r11d
  sub    %edi,%r11d
  cmp    $0x1,%r11d
  je     L132
  movq   (%rsi,%rdi,4),%xmm0
  movq   (%rdx,%rdi,4),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rcx,%rdi,4)
  mov    %r11d,%edi
  and    $0xfffffffe,%edi
  add    %edi,%eax
  cmp    %edi,%r11d
  je     L89
L132:
  cltq
  mov    (%rdx,%rax,4),%edx
  add    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
L89:
  add    $0x8,%r8
  cmp    %r15,%r8
  jne    L35
  addq   $0x8,-0x30(%rsp)
  mov    -0x30(%rsp),%rax
  addq   $0x8,-0x28(%rsp)
  addq   $0x8,-0x20(%rsp)
  cmp    %rax,-0x18(%rsp)
  jne    L58
L97:
  mov    -0x10(%rsp),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L100:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L133:
  mov    (%rsi,%rax,4),%edi
  add    (%rdx,%rax,4),%edi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  lea    -0x1(%rax),%edi
  cmp    %edi,%r9d
  jge    L133
  jmp    L89
L55:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L148
```

assistant: ```c
int ***add_vec_i_3(int ***res, int ***vec1, int ***vec2, int lo1, int hi1, int lo2, int hi2, int lo3, int hi3) {
  int i, j, k;
  for (i = 0; i <= hi1 - lo1; i++)
    for (j = 0; j <= hi2 - lo2; j++)
      for (k = 0; k <= hi3 - lo3 + 1; k++)
        res[i][j][k] = vec1[i][j][k] + vec2[i][j][k];
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WeekDay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int WeekDay() {
  struct tm *timeptr;
  time_t secsnow;
  time(&secsnow);
  timeptr = localtime(&secsnow);
  return (timeptr->tm_wday);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WeekDay>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WeekDay() {
  struct tm *timeptr;
  time_t secsnow;
  time(&secsnow);
  timeptr = localtime(&secsnow);
  return (timeptr->tm_wday);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<WeekDay>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WeekDay() {
  struct tm *timeptr;
  time_t secsnow;
  time(&secsnow);
  timeptr = localtime(&secsnow);
  return (timeptr->tm_wday);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WeekDay>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WeekDay() {
  struct tm *timeptr;
  time_t secsnow;
  time(&secsnow);
  timeptr = localtime(&secsnow);
  return (timeptr->tm_wday);
}
```
user: Translate the below assembly code into C programming language:

```asm
<readTuple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
  jmp    L21
L10:
  mov    -0x68(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jns    L37
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L37:
  mov    $0x1,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D6: %c %s

tool: D4: read error!


assistant: ```c
int readTuple(FILE *file, char *Msg, char *name) {
  char buf[60];
  if (fgets(buf, 60, file) == NULL)
    return 0;
  if (sscanf(buf, "%c %s", Msg, name) < 0) {
    printf("read error!\n");
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readTuple>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rdx
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L19
  mov    %rsp,%rdi
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  js     L21
L19:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L19
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string

tool: D1: %c %s

tool: D13: read error!


assistant: ```c
int readTuple(FILE *file, char *Msg, char *name) {
  char buf[60];
  if (fgets(buf, 60, file) == NULL)
    return 0;
  if (sscanf(buf, "%c %s", Msg, name) < 0) {
    printf("read error!\n");
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readTuple>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %rdi,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    $0x3c,%esi
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L25
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    $0x1,%r14d
  test   %rax,%rax
  js     L22
L25:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x58,%rsp
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L22:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D14
type_infered: string

tool: D19: %c %s

tool: D14: read error!


assistant: ```c
int readTuple(FILE *file, char *Msg, char *name) {
  char buf[60];
  if (fgets(buf, 60, file) == NULL)
    return 0;
  if (sscanf(buf, "%c %s", Msg, name) < 0) {
    printf("read error!\n");
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readTuple>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %rdi,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    $0x3c,%esi
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L20
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    $0x1,%r14d
  test   %rax,%rax
  js     L5
L20:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x58,%rsp
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L5:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D14: %c %s

tool: D12: read error!


assistant: ```c
int readTuple(FILE *file, char *Msg, char *name) {
  char buf[60];
  if (fgets(buf, 60, file) == NULL)
    return 0;
  if (sscanf(buf, "%c %s", Msg, name) < 0) {
    printf("read error!\n");
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mp2vseqdx_get_horizontal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mp2vseqdx_get_color@plt>
  test   %rax,%rax
  je     L7
  mov    $0x8,%eax
  jmp    L4
L7:
  mov    $0x5,%eax
L4:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  sar    $0x2,%eax
  or     %edx,%eax
  leave
  ret
```

assistant: ```c
uint16_t mp2vseqdx_get_horizontal(const uint8_t *p_mp2vseqdx) {
  unsigned int base = mp2vseqdx_get_color(p_mp2vseqdx) ? 8 : 5;
  return (p_mp2vseqdx[base] << 6) | (p_mp2vseqdx[base + 1] >> 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mp2vseqdx_get_horizontal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mp2vseqdx_get_color@plt>
  cmp    $0x1,%rax
  sbb    %edx,%edx
  and    $0xfffffffd,%edx
  add    $0x8,%edx
  lea    0x1(%rdx),%eax
  mov    (%rbx,%rax,4),%eax
  sar    $0x2,%eax
  mov    %edx,%edx
  mov    (%rbx,%rdx,4),%edx
  shl    $0x6,%edx
  or     %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint16_t mp2vseqdx_get_horizontal(const uint8_t *p_mp2vseqdx) {
  unsigned int base = mp2vseqdx_get_color(p_mp2vseqdx) ? 8 : 5;
  return (p_mp2vseqdx[base] << 6) | (p_mp2vseqdx[base + 1] >> 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mp2vseqdx_get_horizontal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mp2vseqdx_get_color@plt>
  cmp    $0x1,%rax
  sbb    %rdx,%rdx
  and    $0xfffffffffffffff4,%rdx
  mov    0x20(%rbx,%rdx,1),%eax
  mov    0x24(%rbx,%rdx,1),%edx
  pop    %rbx
  shl    $0x6,%eax
  sar    $0x2,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint16_t mp2vseqdx_get_horizontal(const uint8_t *p_mp2vseqdx) {
  unsigned int base = mp2vseqdx_get_color(p_mp2vseqdx) ? 8 : 5;
  return (p_mp2vseqdx[base] << 6) | (p_mp2vseqdx[base + 1] >> 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mp2vseqdx_get_horizontal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mp2vseqdx_get_color@plt>
  cmp    $0x1,%rax
  sbb    %rdx,%rdx
  and    $0xfffffffffffffff4,%rdx
  mov    0x20(%rbx,%rdx,1),%eax
  mov    0x24(%rbx,%rdx,1),%edx
  pop    %rbx
  shl    $0x6,%eax
  sar    $0x2,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint16_t mp2vseqdx_get_horizontal(const uint8_t *p_mp2vseqdx) {
  unsigned int base = mp2vseqdx_get_color(p_mp2vseqdx) ? 8 : 5;
  return (p_mp2vseqdx[base] << 6) | (p_mp2vseqdx[base + 1] >> 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<goertzel_filter_v1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movswq %ax,%rdx
  movswq -0x20(%rbp),%rax
  imul   %rdx,%rax
  sar    $0xe,%rax
  mov    %rax,-0x8(%rbp)
  movzwl -0x1c(%rbp),%eax
  sar    $0x7,%ax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %ax,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  mov    -0x18(%rbp),%rax
  movzwl -0xa(%rbp),%edx
  mov    %dx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void goertzel_filter_v1(short int *delay, short int input, short int coefficient) {
  long product;
  short int sum;
  product = ((long)delay[0] * coefficient) >> 14;
  sum = (short int)((input >> 7) + (short int)product - delay[1]);
  delay[1] = delay[0];
  delay[0] = sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<goertzel_filter_v1>:
  endbr64
  movzwl (%rdi),%ecx
  sar    $0x7,%si
  sub    0x2(%rdi),%si
  movswq %cx,%rax
  movswq %dx,%rdx
  imul   %rdx,%rax
  sar    $0xe,%rax
  add    %eax,%esi
  mov    %cx,0x2(%rdi)
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void goertzel_filter_v1(short int *delay, short int input, short int coefficient) {
  long product;
  short int sum;
  product = ((long)delay[0] * coefficient) >> 14;
  sum = (short int)((input >> 7) + (short int)product - delay[1]);
  delay[1] = delay[0];
  delay[0] = sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<goertzel_filter_v1>:
  endbr64
  movswq (%rdi),%rax
  movswq %dx,%rdx
  sar    $0x7,%si
  sub    0x2(%rdi),%si
  mov    %rax,%rcx
  imul   %rdx,%rax
  mov    %cx,0x2(%rdi)
  sar    $0xe,%rax
  add    %eax,%esi
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void goertzel_filter_v1(short int *delay, short int input, short int coefficient) {
  long product;
  short int sum;
  product = ((long)delay[0] * coefficient) >> 14;
  sum = (short int)((input >> 7) + (short int)product - delay[1]);
  delay[1] = delay[0];
  delay[0] = sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<goertzel_filter_v1>:
  endbr64
  movswq (%rdi),%rax
  movswq %dx,%rdx
  sar    $0x7,%si
  sub    0x2(%rdi),%si
  mov    %rax,%rcx
  imul   %rdx,%rax
  mov    %cx,0x2(%rdi)
  sar    $0xe,%rax
  add    %eax,%esi
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void goertzel_filter_v1(short int *delay, short int input, short int coefficient) {
  long product;
  short int sum;
  product = ((long)delay[0] * coefficient) >> 14;
  sum = (short int)((input >> 7) + (short int)product - delay[1]);
  delay[1] = delay[0];
  delay[0] = sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_stack_stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <check_stack@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L11
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    $0xdeadbeef,%edx
  cmp    %rdx,%rax
  jne    L40
  addq   $0x4,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L5
  jmp    L44
L40:
  nop
L44:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
unsigned long check_stack_stop(unsigned long *base) {
  unsigned long i;
  unsigned long from, to;
  to = check_stack(&from);
  *base = from;
  for (i = from; i < to; i += 4) {
    if ((*(long *)i) != 0xdeadbeef)
      break;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_stack_stop>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <check_stack@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  cmp    %rdx,%rax
  jae    L14
  mov    $0xdeadbeef,%ecx
L39:
  cmp    %rcx,(%rax)
  jne    L14
  add    $0x4,%rax
  cmp    %rax,%rdx
  ja     L39
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long check_stack_stop(unsigned long *base) {
  unsigned long i;
  unsigned long from, to;
  to = check_stack(&from);
  *base = from;
  for (i = from; i < to; i += 4) {
    if ((*(long *)i) != 0xdeadbeef)
      break;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_stack_stop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <check_stack@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  cmp    %rdx,%rax
  jae    L33
  mov    $0xdeadbeef,%ecx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L48:
  add    $0x4,%rax
  cmp    %rax,%rdx
  jbe    L33
L34:
  cmp    %rcx,(%rax)
  je     L48
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long check_stack_stop(unsigned long *base) {
  unsigned long i;
  unsigned long from, to;
  to = check_stack(&from);
  *base = from;
  for (i = from; i < to; i += 4) {
    if ((*(long *)i) != 0xdeadbeef)
      break;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_stack_stop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <check_stack@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
  cmp    %rdx,%rax
  jae    L4
  mov    $0xdeadbeef,%ecx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x4,%rax
  cmp    %rax,%rdx
  jbe    L4
L2:
  cmp    %rcx,(%rax)
  je     L5
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x10,%rsp
  pop    %rbx
  ret
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long check_stack_stop(unsigned long *base) {
  unsigned long i;
  unsigned long from, to;
  to = check_stack(&from);
  *base = from;
  for (i = from; i < to; i += 4) {
    if ((*(long *)i) != 0xdeadbeef)
      break;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yuv_to_mono>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %r8d,-0x4c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x28(%rbp)
  jmp    L46
L56:
  movl   $0x1,-0x24(%rbp)
  jmp    L90
L6:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L84
  movl   $0x0,-0x18(%rbp)
  jmp    L38
L84:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L38
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L38:
  cmpl   $0x8,-0x4c(%rbp)
  jg     L44
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L57
L44:
  cmpl   $0x10,-0x4c(%rbp)
  jg     L57
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
L57:
  addl   $0x1,-0x20(%rbp)
  addl   $0x3,-0x1c(%rbp)
  addl   $0x1,-0x24(%rbp)
L90:
  mov    -0x48(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x24(%rbp)
  jl     L6
  addl   $0x1,-0x28(%rbp)
L46:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x28(%rbp)
  jl     L56
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yuv_to_mono(void *img_mono, const int16_t *img_yuv, const int height, const int width, const int bit_channel) {
  int y, x, index_mono, index_yuv;
  int8_t *out8 = img_mono;
  int16_t *out16 = img_mono;
  const int pix_max = (1 << bit_channel) - 1;
  int value;
  index_mono = 0;
  index_yuv = 0;
  for (y = 1; y < (height - 1); y++) {
    for (x = 1; x < (width - 1); x++) {
      value = img_yuv[index_yuv];
      if (value < 0) {
        value = 0;
      } else if (value > pix_max) {
        value = pix_max;
      }
      if (bit_channel <= 8) {
        out8[index_mono] = value;
      } else if (bit_channel <= 16) {
        out16[index_mono] = value;
      }
      index_mono++;
      index_yuv += 3;
    }
  }
}
```