ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<Polynomial_Extrapolation_to_Zero>:
  endbr64
  mov    %rsi,%r8
  test   %ecx,%ecx
  je     L52
  movslq %ecx,%r11
  pxor   %xmm5,%xmm5
  lea    (%rdx,%r11,8),%r9
  ucomisd (%r9),%xmm5
  jp     L8
  je     L23
L8:
  movsd  (%r8),%xmm3
  movsd  %xmm0,(%r8)
  test   %ecx,%ecx
  jle    L10
  lea    -0x1(%rcx),%eax
  mov    %r9,%r10
  lea    0x8(%r8),%rsi
  mov    %r9,%rdx
  shl    $0x3,%rax
  movapd %xmm5,%xmm1
  xor    %ecx,%ecx
  sub    %rax,%r10
  jmp    L74
  nopl   (%rax)
L82:
  mulsd  %xmm4,%xmm2
  movsd  (%rsi),%xmm6
  divsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsi)
  cmp    %r10,%rdx
  je     L10
  movapd %xmm3,%xmm1
  add    $0x8,%rsi
  movapd %xmm6,%xmm3
  sub    $0x8,%rdx
L74:
  ucomisd %xmm5,%xmm3
  setnp  %al
  cmovne %ecx,%eax
  test   %al,%al
  je     L75
  ucomisd %xmm5,%xmm0
  setnp  %al
  cmovne %ecx,%eax
  test   %al,%al
  jne    L11
L75:
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm4
  subsd  %xmm3,%xmm2
  movsd  -0x8(%rdx),%xmm1
  divsd  (%r9),%xmm1
  movapd %xmm4,%xmm6
  subsd  %xmm2,%xmm6
  mulsd  %xmm6,%xmm1
  subsd  %xmm4,%xmm1
  ucomisd %xmm5,%xmm1
  jp     L82
  jne    L82
  mov    $0xffffffff,%eax
  ret
  nopl   (%rax)
L52:
  movsd  %xmm0,(%rsi)
  xor    %eax,%eax
  ret
  nop
L10:
  movsd  (%r8,%r11,8),%xmm5
  xor    %eax,%eax
  movsd  %xmm5,(%rdi)
  ret
  nopl   (%rax)
L11:
  movq   $0x0,(%r8,%r11,8)
  xor    %eax,%eax
  movsd  %xmm5,(%rdi)
  ret
L23:
  movsd  %xmm0,(%rdi)
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int Polynomial_Extrapolation_to_Zero(double *fzero, double tableau[], double x[], double f, int n) {
  double back_two_columns;
  double old_aux;
  double new_value;
  double vertical_diff;
  double backslant_diff;
  double forwardslant_diff;
  double denominator;
  int i;
  if (n == 0) {
    tableau[0] = f;
    return 0;
  }
  if (x[n] == 0.0) {
    *fzero = f;
    return -2;
  }
  back_two_columns = 0.0;
  old_aux = tableau[0];
  tableau[0] = f;
  for (i = 0; i < n; i++) {
    if (tableau[i] == 0 && old_aux == 0) {
      tableau[n] = 0.0;
      break;
    }
    vertical_diff = tableau[i] - old_aux;
    backslant_diff = tableau[i] - back_two_columns;
    forwardslant_diff = backslant_diff - vertical_diff;
    denominator = (x[n - i - 1] / x[n]) * forwardslant_diff - backslant_diff;
    if (denominator == 0.0)
      return -1;
    back_two_columns = old_aux;
    old_aux = tableau[i + 1];
    tableau[i + 1] = tableau[i] + vertical_diff * backslant_diff / denominator;
  }
  *fzero = tableau[n];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Polynomial_Extrapolation_to_Zero>:
  endbr64
  mov    %rsi,%r9
  test   %ecx,%ecx
  je     L45
  movslq %ecx,%r11
  pxor   %xmm5,%xmm5
  lea    (%rdx,%r11,8),%r8
  ucomisd (%r8),%xmm5
  jp     L79
  je     L12
L79:
  movsd  (%r9),%xmm3
  movsd  %xmm0,(%r9)
  test   %ecx,%ecx
  jle    L3
  lea    -0x1(%rcx),%edx
  mov    %r8,%rsi
  lea    0x8(%r9),%rax
  xor    %ecx,%ecx
  lea    0x10(%r9,%rdx,8),%r10
  movapd %xmm5,%xmm0
  jmp    L50
L11:
  mulsd  %xmm4,%xmm1
  movsd  (%rax),%xmm6
  add    $0x8,%rax
  sub    $0x8,%rsi
  divsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rax,%r10
  je     L3
  movapd %xmm6,%xmm3
L50:
  ucomisd %xmm5,%xmm3
  movsd  -0x8(%rax),%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %dl,%dl
  je     L70
  ucomisd %xmm5,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %dl,%dl
  jne    L2
L70:
  movapd %xmm2,%xmm4
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm4
  subsd  %xmm3,%xmm1
  movsd  -0x8(%rsi),%xmm0
  divsd  (%r8),%xmm0
  movapd %xmm4,%xmm6
  subsd  %xmm1,%xmm6
  mulsd  %xmm6,%xmm0
  subsd  %xmm4,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L11
  jne    L11
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  %xmm0,(%rsi)
  xor    %eax,%eax
  ret
  nop
L3:
  movsd  (%r9,%r11,8),%xmm5
  xor    %eax,%eax
  movsd  %xmm5,(%rdi)
  ret
  nopl   (%rax)
L2:
  movq   $0x0,(%r9,%r11,8)
  xor    %eax,%eax
  movsd  %xmm5,(%rdi)
  ret
L12:
  movsd  %xmm0,(%rdi)
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int Polynomial_Extrapolation_to_Zero(double *fzero, double tableau[], double x[], double f, int n) {
  double back_two_columns;
  double old_aux;
  double new_value;
  double vertical_diff;
  double backslant_diff;
  double forwardslant_diff;
  double denominator;
  int i;
  if (n == 0) {
    tableau[0] = f;
    return 0;
  }
  if (x[n] == 0.0) {
    *fzero = f;
    return -2;
  }
  back_two_columns = 0.0;
  old_aux = tableau[0];
  tableau[0] = f;
  for (i = 0; i < n; i++) {
    if (tableau[i] == 0 && old_aux == 0) {
      tableau[n] = 0.0;
      break;
    }
    vertical_diff = tableau[i] - old_aux;
    backslant_diff = tableau[i] - back_two_columns;
    forwardslant_diff = backslant_diff - vertical_diff;
    denominator = (x[n - i - 1] / x[n]) * forwardslant_diff - backslant_diff;
    if (denominator == 0.0)
      return -1;
    back_two_columns = old_aux;
    old_aux = tableau[i + 1];
    tableau[i + 1] = tableau[i] + vertical_diff * backslant_diff / denominator;
  }
  *fzero = tableau[n];
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D14
type: string

tool: D12: %s

tool: D14: Your input : %s

assistant: ```c
int main() {
  char input[5];
  scanf("%s", input);
  printf("Your input : %s", input);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D1: %s

tool: D15: Your input : %s

assistant: ```c
int main() {
  char input[5];
  scanf("%s", input);
  printf("Your input : %s", input);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D9: %s

tool: D6: Your input : %s

assistant: ```c
int main() {
  char input[5];
  scanf("%s", input);
  printf("Your input : %s", input);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D6: %s

tool: D7: Your input : %s

assistant: ```c
int main() {
  char input[5];
  scanf("%s", input);
  printf("Your input : %s", input);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<IsIpv6Fragment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int IsIpv6Fragment(struct ip6_hdr *hdr __attribute__((unused))) {
  assert(hdr != NULL);
  if (0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IsIpv6Fragment>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int IsIpv6Fragment(struct ip6_hdr *hdr __attribute__((unused))) {
  assert(hdr != NULL);
  if (0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IsIpv6Fragment>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int IsIpv6Fragment(struct ip6_hdr *hdr __attribute__((unused))) {
  assert(hdr != NULL);
  if (0)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IsIpv6Fragment>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int IsIpv6Fragment(struct ip6_hdr *hdr __attribute__((unused))) {
  assert(hdr != NULL);
  if (0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L44
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    $0x1,%eax
  jmp    L19
L44:
  mov    $0x0,%eax
L19:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rbx
  movzbl (%rbx),%eax
  movsbl %al,%r12d
  jmp    L14
L42:
  mov    %r12d,%eax
  shl    $0x5,%eax
  sub    %r12d,%eax
  add    %r13d,%eax
  and    $0x3ff,%eax
  mov    %eax,%r12d
L14:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  movsbl %al,%r13d
  test   %r13d,%r13d
  jne    L42
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int hash(char *name) {
  register char *s;
  register int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = *++s))
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  test   %rbx,%rbx
  je     L8
  cmpb   $0x0,(%rbx)
  setne  %dil
  movzbl %dil,%edi
L8:
  call   <assert@plt>
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  movsbl 0x1(%rbx),%ecx
  test   %ecx,%ecx
  je     L4
L6:
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  and    $0x3ff,%eax
  add    $0x1,%rsi
  movsbl (%rsi),%ecx
  test   %ecx,%ecx
  jne    L6
L4:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  register char *s;
  register int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = *++s))
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L6
  xor    %edi,%edi
  cmpb   $0x0,(%rbx)
  setne  %dil
L6:
  call   <assert@plt>
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  test   %ecx,%ecx
  je     L11
  nopl   0x0(%rax)
L26:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rsi),%ecx
  and    $0x3ff,%eax
  test   %ecx,%ecx
  jne    L26
L11:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  register char *s;
  register int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = *++s))
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  je     L2
  xor    %edi,%edi
  cmpb   $0x0,(%rbx)
  setne  %dil
L2:
  call   <assert@plt>
  movsbl 0x1(%rbx),%ecx
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%rsi
  test   %ecx,%ecx
  je     L7
  nopl   0x0(%rax)
L29:
  mov    %eax,%edx
  add    $0x1,%rsi
  shl    $0x5,%edx
  sub    %eax,%edx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rsi),%ecx
  and    $0x3ff,%eax
  test   %ecx,%ecx
  jne    L29
L7:
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *name) {
  register char *s;
  register int c, k;
  assert(name && *name);
  s = name;
  k = *s;
  while ((c = *++s))
    k = (31 * k + c) & (1024 - 1);
  return (k);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<really>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x7a,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  jle    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x7a,(%rax)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movb   $0x7a,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void really(char *p) {
  int i;
  for (i = 0; i < 1; i++)
    p[i] = 'z';
  free(p);
  p[1] = 'z';
  p = malloc(10);
  p[2] = 'z';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<really>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movb   $0x7a,(%rdi)
  call   <free@plt>
  movb   $0x7a,0x1(%rbx)
  mov    $0xa,%edi
  call   <malloc@plt>
  movb   $0x7a,0x2(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void really(char *p) {
  int i;
  for (i = 0; i < 1; i++)
    p[i] = 'z';
  free(p);
  p[1] = 'z';
  p = malloc(10);
  p[2] = 'z';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<really>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movb   $0x7a,(%rdi)
  call   <free@plt>
  movb   $0x7a,0x1(%rbx)
  mov    $0xa,%edi
  call   <malloc@plt>
  movb   $0x7a,0x2(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void really(char *p) {
  int i;
  for (i = 0; i < 1; i++)
    p[i] = 'z';
  free(p);
  p[1] = 'z';
  p = malloc(10);
  p[2] = 'z';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D35: 
Entre com num1:

tool: D23: %d

tool: D6: 
Entre com num2:

tool: D0: 
Soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  printf("\nEntre com num1:");
  scanf("%d", &num1);
  printf("\nEntre com num2:");
  scanf("%d", &num2);
  soma = num1 + num2;
  printf("\nSoma = %d\n", soma);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D34
type: string
name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D36
type: string

tool: D34: 
Entre com num1:

tool: D8: %d

tool: D38: 
Entre com num2:

tool: D36: 
Soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  printf("\nEntre com num1:");
  scanf("%d", &num1);
  printf("\nEntre com num2:");
  scanf("%d", &num2);
  soma = num1 + num2;
  printf("\nSoma = %d\n", soma);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  lea    D14(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D32
datatype: string

tool: D24: 
Entre com num1:

tool: D14: %d

tool: D29: 
Entre com num2:

tool: D32: 
Soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  printf("\nEntre com num1:");
  scanf("%d", &num1);
  printf("\nEntre com num2:");
  scanf("%d", &num2);
  soma = num1 + num2;
  printf("\nSoma = %d\n", soma);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D4(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D31
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D27: 
Entre com num1:

tool: D4: %d

tool: D31: 
Entre com num2:

tool: D13: 
Soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  printf("\nEntre com num1:");
  scanf("%d", &num1);
  printf("\nEntre com num2:");
  scanf("%d", &num2);
  soma = num1 + num2;
  printf("\nSoma = %d\n", soma);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: %d %s


assistant: ```c
void printStrings(char **strings, int size) {
  for (int i = 0; i < size; i++)
    printf("%d %s\n", i, strings[i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printStrings>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
L9:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %d %s


assistant: ```c
void printStrings(char **strings, int size) {
  for (int i = 0; i < size; i++)
    printf("%d %s\n", i, strings[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printStrings>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: %d %s


assistant: ```c
void printStrings(char **strings, int size) {
  for (int i = 0; i < size; i++)
    printf("%d %s\n", i, strings[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printStrings>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: %d %s


assistant: ```c
void printStrings(char **strings, int size) {
  for (int i = 0; i < size; i++)
    printf("%d %s\n", i, strings[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pchisq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L5
  cmpl   $0x0,-0xc(%rbp)
  jns    L18
L5:
  mov    D4(%rip),%rax
  jmp    L10
L18:
  movsd  -0x8(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  call   <gammp@plt>
  movq   %xmm0,%rax
L10:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: f64
name: unpack_data
arguments: tag: D9
type_guessed: f32[2]

tool: D4: 1

tool: {"D9": [0.0,2.0]}

assistant: ```c
double pchisq(const double x, const int df) {
  if (x < 0.0 || df < 0.0)
    return 1.0;
  return gammp(((double)df) / 2, x / 2);
}
```