ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<mov_preg64preg64_imm8>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xc6,%edi
  call   <put8@plt>
  mov    $0x4,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  mov    %edi,%ebx
  or     %r12d,%ebx
  movzbl %bl,%edi
  call   <put8@plt>
  pop    %rbx
  movzbl %bpl,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <put8@plt>
```

assistant: ```c
void mov_preg64preg64_imm8(int reg1, int reg2, unsigned char imm8) {
  put8(0xC6);
  put8(0x04);
  put8((reg1 << 3) | reg2);
  put8(imm8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_gettid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <syscall@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
pid_t my_gettid() {
  pid_t tid;
  tid = syscall(SYS_gettid);
  return tid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_gettid>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t my_gettid() {
  pid_t tid;
  tid = syscall(SYS_gettid);
  return tid;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_gettid>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <syscall@plt>
```

assistant: ```c
pid_t my_gettid() {
  pid_t tid;
  tid = syscall(SYS_gettid);
  return tid;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_gettid>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <syscall@plt>
```

assistant: ```c
pid_t my_gettid() {
  pid_t tid;
  tid = syscall(SYS_gettid);
  return tid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x3e8,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L4:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x24(%rbp)
L9:
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x20(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fib@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: %d


assistant: ```c
int main() {
  int size = 1000;
  int *f1 = (int *)malloc(size * sizeof(int));
  int *f2 = (int *)malloc(size * sizeof(int));
  int *f3 = (int *)malloc(size * sizeof(int));
  int i;
  for (i = 0; i < size; i++) {
    f1[i] = 0;
    f2[i] = 0;
    f3[i] = 0;
  }
  f1[size - 1] = 1;
  f2[size - 1] = 1;
  int temp = fib(f1, f2, f3, size);
  printf("%d\n", temp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0xfa0,%edi
  call   <malloc@plt>
  lea    0xfa0(%rbx),%rdi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  sub    %rbx,%rsi
  mov    %rax,%rcx
  sub    %rbx,%rcx
L5:
  movl   $0x0,(%rdx)
  movl   $0x0,(%rsi,%rdx,1)
  movl   $0x0,(%rcx,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L5
  movl   $0x1,0xf9c(%rbx)
  movl   $0x1,0xf9c(%rbp)
  mov    $0x3e8,%ecx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fib@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int size = 1000;
  int *f1 = (int *)malloc(size * sizeof(int));
  int *f2 = (int *)malloc(size * sizeof(int));
  int *f3 = (int *)malloc(size * sizeof(int));
  int i;
  for (i = 0; i < size; i++) {
    f1[i] = 0;
    f2[i] = 0;
    f3[i] = 0;
  }
  f1[size - 1] = 1;
  f2[size - 1] = 1;
  int temp = fib(f1, f2, f3, size);
  printf("%d\n", temp);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xfa0,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0xfa0,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0xfa0,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  lea    0xfa0(%rbp),%rdx
  lea    0xfa0(%r12),%rdi
  cmp    %rdx,%r12
  mov    %rax,%r8
  lea    0xfa0(%rax),%rsi
  setae  %cl
  cmp    %rdi,%rbp
  setae  %al
  or     %eax,%ecx
  cmp    %rdx,%r8
  setae  %al
  cmp    %rsi,%rbp
  setae  %r9b
  or     %r9d,%eax
  test   %al,%cl
  je     L10
  cmp    %rdi,%r8
  setae  %al
  cmp    %rsi,%r12
  setae  %cl
  or     %cl,%al
  je     L10
  lea    0x8(%rbp),%rdi
  mov    %rbp,%rcx
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  movq   $0x0,0xf98(%rbp)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r12),%rdi
  mov    %r12,%rcx
  movq   $0x0,(%r12)
  movq   $0x0,0xf98(%r12)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r8),%rdi
  mov    %r8,%rcx
  movq   $0x0,(%r8)
  movq   $0x0,0xf98(%r8)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x3e8,%ecx
  mov    %r8,%rdx
  movl   $0x1,0xf9c(%rbp)
  movl   $0x1,0xf9c(%r12)
  call   <fib@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %r12,%rsi
  mov    %r8,%rcx
  mov    %rbp,%rax
  sub    %rbp,%rsi
  sub    %rbp,%rcx
  nopl   0x0(%rax)
L1:
  movl   $0x0,(%rax)
  movl   $0x0,(%rsi,%rax,1)
  movl   $0x0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L1
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main() {
  int size = 1000;
  int *f1 = (int *)malloc(size * sizeof(int));
  int *f2 = (int *)malloc(size * sizeof(int));
  int *f3 = (int *)malloc(size * sizeof(int));
  int i;
  for (i = 0; i < size; i++) {
    f1[i] = 0;
    f2[i] = 0;
    f3[i] = 0;
  }
  f1[size - 1] = 1;
  f2[size - 1] = 1;
  int temp = fib(f1, f2, f3, size);
  printf("%d\n", temp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xfa0,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0xfa0,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0xfa0,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  lea    0xfa0(%rbp),%rdx
  lea    0xfa0(%r12),%rdi
  cmp    %r12,%rdx
  mov    %rax,%r8
  lea    0xfa0(%rax),%rsi
  setbe  %cl
  cmp    %rdi,%rbp
  setae  %al
  or     %eax,%ecx
  cmp    %r8,%rdx
  setbe  %al
  cmp    %rsi,%rbp
  setae  %r9b
  or     %r9d,%eax
  test   %al,%cl
  je     L34
  cmp    %rdi,%r8
  setae  %al
  cmp    %rsi,%r12
  setae  %cl
  or     %cl,%al
  je     L34
  lea    0x8(%rbp),%rdi
  mov    %rbp,%rcx
  xor    %eax,%eax
  movq   $0x0,0x0(%rbp)
  movq   $0x0,0xf98(%rbp)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r12),%rdi
  mov    %r12,%rcx
  movq   $0x0,(%r12)
  movq   $0x0,0xf98(%r12)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%r8),%rdi
  mov    %r8,%rcx
  movq   $0x0,(%r8)
  movq   $0x0,0xf98(%r8)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0xfa0,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x3e8,%ecx
  mov    %r8,%rdx
  movl   $0x1,0xf9c(%rbp)
  movl   $0x1,0xf9c(%r12)
  call   <fib@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    %r12,%rsi
  mov    %r8,%rcx
  mov    %rbp,%rax
  sub    %rbp,%rsi
  sub    %rbp,%rcx
  nopl   0x0(%rax)
L38:
  movl   $0x0,(%rax)
  movl   $0x0,(%rsi,%rax,1)
  movl   $0x0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L38
  jmp    L5
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main() {
  int size = 1000;
  int *f1 = (int *)malloc(size * sizeof(int));
  int *f2 = (int *)malloc(size * sizeof(int));
  int *f3 = (int *)malloc(size * sizeof(int));
  int i;
  for (i = 0; i < size; i++) {
    f1[i] = 0;
    f2[i] = 0;
    f3[i] = 0;
  }
  f1[size - 1] = 1;
  f2[size - 1] = 1;
  int temp = fib(f1, f2, f3, size);
  printf("%d\n", temp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdist_seuclidean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L29
L39:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L2
L36:
  mov    -0x40(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <seuclidean_distance@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x8,-0x18(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L36
  addl   $0x1,-0x20(%rbp)
L29:
  mov    -0x20(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L39
  nop
  nop
  leave
  ret
```

assistant: ```c
void pdist_seuclidean(const double *X, const double *var, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = seuclidean_distance(var, u, v, n);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pdist_seuclidean>:
  endbr64
  test   %ecx,%ecx
  jle    L36
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%r15
  mov    %rdx,%rbx
  mov    %r8d,%r14d
  lea    -0x2(%rcx),%eax
  mov    %eax,0xc(%rsp)
  movslq %r8d,%rax
  lea    0x0(,%rax,8),%rsi
  mov    %rsi,(%rsp)
  add    %rsi,%rdi
  mov    %rdi,0x10(%rsp)
  neg    %rax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
L35:
  mov    0xc(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L38
  mov    0x10(%rsp),%rbp
  mov    %rbp,%r13
  add    0x18(%rsp),%r13
  mov    %eax,%eax
  lea    0x8(%rbx,%rax,8),%r12
L0:
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <seuclidean_distance@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  add    (%rsp),%rbp
  cmp    %r12,%rbx
  jne    L0
  subl   $0x1,0xc(%rsp)
  mov    (%rsp),%rdx
  add    %rdx,0x10(%rsp)
  mov    %r12,%rbx
  jmp    L35
L38:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  ret
```

assistant: ```c
void pdist_seuclidean(const double *X, const double *var, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = seuclidean_distance(var, u, v, n);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pdist_seuclidean>:
  endbr64
  test   %ecx,%ecx
  jle    L2
  push   %r15
  lea    -0x2(%rcx),%eax
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  movslq %r8d,%rbx
  shl    $0x3,%rbx
  sub    $0x28,%rsp
  mov    %eax,0x14(%rsp)
  lea    (%rdi,%rbx,1),%rax
  mov    %rax,0x18(%rsp)
  mov    0x14(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L39
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x1(%rax),%edx
  mov    0x18(%rsp),%rbp
  lea    (%r15,%rdx,8),%rax
  mov    %rax,0x8(%rsp)
  mov    %rbp,%r12
  sub    %rbx,%r12
  nop
L26:
  mov    %rbp,%rdx
  mov    %r13d,%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <seuclidean_distance@plt>
  add    $0x8,%r15
  add    %rbx,%rbp
  movsd  %xmm0,-0x8(%r15)
  cmp    0x8(%rsp),%r15
  jne    L26
  subl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  add    %rbx,0x18(%rsp)
  cmp    $0xffffffff,%eax
  jne    L11
L39:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  ret
```

assistant: ```c
void pdist_seuclidean(const double *X, const double *var, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = seuclidean_distance(var, u, v, n);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pdist_seuclidean>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %ecx,0x10(%rsp)
  cmp    $0x1,%ecx
  jle    L6
  movslq %r8d,%rbp
  movl   $0x2,0x14(%rsp)
  mov    %rsi,%r14
  mov    %r8d,%r13d
  lea    0x0(,%rbp,8),%rax
  add    %rax,%rdi
  mov    %rax,(%rsp)
  mov    0x14(%rsp),%eax
  mov    %rdi,0x18(%rsp)
  nopl   (%rax)
L1:
  mov    0x18(%rsp),%rbx
  mov    0x8(%rsp),%r15
  lea    -0x1(%rax),%ebp
  mov    %rbx,%r12
  sub    (%rsp),%r12
  nopl   0x0(%rax)
L18:
  mov    %rbx,%rdx
  mov    %r13d,%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <seuclidean_distance@plt>
  add    $0x1,%ebp
  add    $0x8,%r15
  add    (%rsp),%rbx
  movsd  %xmm0,-0x8(%r15)
  cmp    %ebp,0x10(%rsp)
  jg     L18
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  mov    0x8(%rsp),%rdi
  mov    %esi,%eax
  sub    %edx,%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    (%rsp),%rdi
  add    %rdi,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x1(%rdx),%eax
  cmp    %esi,%edx
  je     L6
  mov    %eax,0x14(%rsp)
  jmp    L1
  nopl   0x0(%rax)
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_seuclidean(const double *X, const double *var, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = seuclidean_distance(var, u, v, n);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isKanji>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  andl   $0xff,-0x4(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  jle    L3
  cmpl   $0x9f,-0x4(%rbp)
  jle    L48
L3:
  cmpl   $0xdf,-0x4(%rbp)
  jle    L29
  cmpl   $0xfc,-0x4(%rbp)
  jg     L29
L48:
  mov    $0x1,%eax
  jmp    L36
L29:
  mov    $0x0,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
isKanji(c) {
  c &= 0xff;
  return (c > 0x80 && c < 0xa0 || c > 0xdf && c < 0xfd);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isKanji>:
  endbr64
  movzbl %dil,%edi
  lea    -0x81(%rdi),%eax
  cmp    $0x1e,%eax
  setbe  %al
  sub    $0xe0,%edi
  cmp    $0x1c,%edi
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isKanji(c) {
  c &= 0xff;
  return (c > 0x80 && c < 0xa0 || c > 0xdf && c < 0xfd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isKanji>:
  endbr64
  movzbl %dil,%edi
  lea    -0x81(%rdi),%eax
  cmp    $0x1e,%eax
  setbe  %al
  sub    $0xe0,%edi
  cmp    $0x1c,%edi
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isKanji(c) {
  c &= 0xff;
  return (c > 0x80 && c < 0xa0 || c > 0xdf && c < 0xfd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isKanji>:
  endbr64
  movzbl %dil,%edi
  lea    -0x81(%rdi),%eax
  cmp    $0x1e,%eax
  setbe  %al
  sub    $0xe0,%edi
  cmp    $0x1c,%edi
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isKanji(c) {
  c &= 0xff;
  return (c > 0x80 && c < 0xa0 || c > 0xdf && c < 0xfd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_op>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <any@plt>
  test   %eax,%eax
  je     L13
  mov    $0x1,%eax
  jmp    L6
L13:
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: +-*/&%|^<>

assistant: ```c
is_op(c) char c;
{
  if (any(c, "+-*/&%|^<>"))
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_op>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  lea    D5(%rip),%rsi
  mov    $0x0,%eax
  call   <any@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string

tool: D5: +-*/&%|^<>

assistant: ```c
is_op(c) char c;
{
  if (any(c, "+-*/&%|^<>"))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_op>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  movsbl %dil,%edi
  lea    D4(%rip),%rsi
  call   <any@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: +-*/&%|^<>

assistant: ```c
is_op(c) char c;
{
  if (any(c, "+-*/&%|^<>"))
    return (1);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_op>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  movsbl %dil,%edi
  lea    D9(%rip),%rsi
  call   <any@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: +-*/&%|^<>

assistant: ```c
is_op(c) char c;
{
  if (any(c, "+-*/&%|^<>"))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adfs_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  or     %edx,%eax
  sub    $0x336e996a,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x5,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int adfs_time(unsigned int load, unsigned int exec) {
  unsigned int high, low;
  high = ((load << 24) | (exec >> 8)) - 0x336e996a;
  low = exec & 255;
  return (((high % 100) << 8) + low) / 100 + (high / 100 << 8);
}
```
user: What is the c source code of the assembly code below:

```asm
<adfs_time>:
  endbr64
  shl    $0x18,%edi
  mov    %esi,%eax
  shr    $0x8,%eax
  or     %eax,%edi
  sub    $0x336e996a,%edi
  mov    %edi,%edx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  imul   $0x64,%edx,%eax
  sub    %eax,%edi
  shl    $0x8,%edi
  movzbl %sil,%esi
  lea    (%rdi,%rsi,1),%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  shl    $0x8,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int adfs_time(unsigned int load, unsigned int exec) {
  unsigned int high, low;
  high = ((load << 24) | (exec >> 8)) - 0x336e996a;
  low = exec & 255;
  return (((high % 100) << 8) + low) / 100 + (high / 100 << 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adfs_time>:
  endbr64
  mov    %esi,%eax
  shl    $0x18,%edi
  movzbl %sil,%esi
  shr    $0x8,%eax
  or     %eax,%edi
  lea    -0x336e996a(%rdi),%edx
  mov    %rdx,%rdi
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  imul   $0x64,%edx,%eax
  shl    $0x8,%edx
  sub    %eax,%edi
  shl    $0x8,%edi
  lea    (%rdi,%rsi,1),%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int adfs_time(unsigned int load, unsigned int exec) {
  unsigned int high, low;
  high = ((load << 24) | (exec >> 8)) - 0x336e996a;
  low = exec & 255;
  return (((high % 100) << 8) + low) / 100 + (high / 100 << 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adfs_time>:
  endbr64
  mov    %esi,%eax
  shl    $0x18,%edi
  movzbl %sil,%esi
  shr    $0x8,%eax
  or     %eax,%edi
  lea    -0x336e996a(%rdi),%edx
  mov    %rdx,%rdi
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  imul   $0x64,%edx,%eax
  shl    $0x8,%edx
  sub    %eax,%edi
  shl    $0x8,%edi
  lea    (%rdi,%rsi,1),%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int adfs_time(unsigned int load, unsigned int exec) {
  unsigned int high, low;
  high = ((load << 24) | (exec >> 8)) - 0x336e996a;
  low = exec & 255;
  return (((high % 100) << 8) + low) / 100 + (high / 100 << 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_numbered_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <is_range_in_range@plt>
  test   %rax,%rax
  je     L27
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_numbered_line@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L1
  jmp    L9
L27:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: range outside limits

assistant: ```c
void print_numbered_lines(int start, int end) {
  int i;
  if (is_range_in_range(start, end)) {
    for (i = start; i <= end; i++) {
      print_numbered_line(i);
    }
  } else {
    print_error("range outside limits");
  }
}
```