ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_in>:
  endbr64
  lea    0x80(%rsi),%r8
  lea    0x200(%rdi),%r9
  nopw   0x0(%rax,%rax,1)
L3:
  lea    -0x80(%r8),%rax
  mov    %rdi,%r10
  nop
L13:
  mov    (%r10),%edx
  mov    $0x20,%ecx
  add    $0x8,%rax
  add    $0x4,%r10
  mov    %edx,%esi
  mov    %dl,-0x8(%rax)
  sar    $0x10,%esi
  mov    %dh,-0x7(%rax)
  mov    %sil,-0x6(%rax)
  mov    %edx,%esi
  sar    $0x18,%esi
  mov    %sil,-0x5(%rax)
  mov    %edx,%esi
  sar    %cl,%esi
  mov    $0x28,%ecx
  mov    %sil,-0x4(%rax)
  mov    %edx,%esi
  sar    %cl,%esi
  mov    $0x30,%ecx
  mov    %sil,-0x3(%rax)
  mov    %edx,%esi
  sar    %cl,%esi
  mov    $0x38,%ecx
  sar    %cl,%edx
  mov    %sil,-0x2(%rax)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%r8
  jne    L13
  add    $0x40,%rdi
  sub    $0xffffffffffffff80,%r8
  cmp    %rdi,%r9
  jne    L3
  ret
```

assistant: ```c
void copy_in(uint64_t *large_A, char *part_buf_A) {
  int i, j;
  for (i = 0; i < ((512) / (64)); i++) {
    for (j = 0; j < 16; j++) {
#pragma HLS PIPELINE
      uint64_t curr = large_A[i * 16 + j];
      part_buf_A[i * 128 + j * 8 + 0] = (uint8_t)(curr >> 0);
      part_buf_A[i * 128 + j * 8 + 1] = (uint8_t)(curr >> 8);
      part_buf_A[i * 128 + j * 8 + 2] = (uint8_t)(curr >> 16);
      part_buf_A[i * 128 + j * 8 + 3] = (uint8_t)(curr >> 24);
      part_buf_A[i * 128 + j * 8 + 4] = (uint8_t)(curr >> 32);
      part_buf_A[i * 128 + j * 8 + 5] = (uint8_t)(curr >> 40);
      part_buf_A[i * 128 + j * 8 + 6] = (uint8_t)(curr >> 48);
      part_buf_A[i * 128 + j * 8 + 7] = (uint8_t)(curr >> 56);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L21
L17:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L2
  addq   $0x1,-0x10(%rbp)
L2:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L17
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long compare_mem(unsigned char *one, unsigned char *two, long long size) {
  long long diff_counter = 0;
  long long counter = 0;
  while (counter < size) {
    if (one[counter] != two[counter]) {
      diff_counter++;
    }
    counter++;
  }
  return diff_counter;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare_mem>:
  endbr64
  test   %rdx,%rdx
  jle    L28
  mov    $0x0,%eax
  mov    $0x0,%ecx
L11:
  movzbl (%rsi,%rax,1),%r9d
  cmp    %r9b,(%rdi,%rax,1)
  setne  %r8b
  movzbl %r8b,%r8d
  add    %r8,%rcx
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L11
L12:
  mov    %rcx,%rax
  ret
L28:
  mov    $0x0,%ecx
  jmp    L12
```

assistant: ```c
long long compare_mem(unsigned char *one, unsigned char *two, long long size) {
  long long diff_counter = 0;
  long long counter = 0;
  while (counter < size) {
    if (one[counter] != two[counter]) {
      diff_counter++;
    }
    counter++;
  }
  return diff_counter;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_mem>:
  endbr64
  test   %rdx,%rdx
  jle    L4
  xor    %eax,%eax
  xor    %r8d,%r8d
  xchg   %ax,%ax
L18:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  setne  %cl
  add    $0x1,%rax
  movzbl %cl,%ecx
  add    %rcx,%r8
  cmp    %rax,%rdx
  jne    L18
  mov    %r8,%rax
  ret
  nopl   (%rax)
L4:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long compare_mem(unsigned char *one, unsigned char *two, long long size) {
  long long diff_counter = 0;
  long long counter = 0;
  while (counter < size) {
    if (one[counter] != two[counter]) {
      diff_counter++;
    }
    counter++;
  }
  return diff_counter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rollover>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L7
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rollover(int min, int max, int step, int input) {
  int output = input + step;
  if (output > max) {
    output = min - 1 + (output % max);
  }
  return (output);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rollover>:
  endbr64
  lea    (%rcx,%rdx,1),%eax
  cmp    %esi,%eax
  jle    L2
  cltd
  idiv   %esi
  lea    -0x1(%rdi,%rdx,1),%eax
L2:
  ret
```

assistant: ```c
int rollover(int min, int max, int step, int input) {
  int output = input + step;
  if (output > max) {
    output = min - 1 + (output % max);
  }
  return (output);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rollover>:
  endbr64
  lea    (%rcx,%rdx,1),%eax
  cmp    %esi,%eax
  jle    L5
  cltd
  idiv   %esi
  lea    -0x1(%rdi,%rdx,1),%eax
L5:
  ret
```

assistant: ```c
int rollover(int min, int max, int step, int input) {
  int output = input + step;
  if (output > max) {
    output = min - 1 + (output % max);
  }
  return (output);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rollover>:
  endbr64
  lea    (%rcx,%rdx,1),%eax
  cmp    %esi,%eax
  jle    L9
  cltd
  idiv   %esi
  lea    -0x1(%rdi,%rdx,1),%eax
L9:
  ret
```

assistant: ```c
int rollover(int min, int max, int step, int input) {
  int output = input + step;
  if (output > max) {
    output = min - 1 + (output % max);
  }
  return (output);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pathconN_nm8_name_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  cmpl   $0x1,-0x4(%rbp)
  je     L42
  jmp    L21
L3:
  lea    D8(%rip),%rax
  jmp    L31
L42:
  lea    D15(%rip),%rax
  jmp    L31
L21:
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string

tool: D8: o0

tool: D15: o1

assistant: ```c
const char *pathconN_nm8_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pathconN_nm8_name_out>:
  endbr64
  lea    D18(%rip),%rax
  test   %edi,%edi
  je     L6
  cmp    $0x1,%edi
  lea    D12(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string

tool: D18: o0

tool: D12: o1

assistant: ```c
const char *pathconN_nm8_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pathconN_nm8_name_out>:
  endbr64
  lea    D19(%rip),%rax
  test   %edi,%edi
  je     L3
  cmp    $0x1,%edi
  lea    D12(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L3:
  ret
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D12
type: string

tool: D19: o0

tool: D12: o1

assistant: ```c
const char *pathconN_nm8_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pathconN_nm8_name_out>:
  endbr64
  lea    D3(%rip),%rax
  test   %edi,%edi
  je     L3
  cmp    $0x1,%edi
  lea    D17(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D17
type: string

tool: D3: o0

tool: D17: o1

assistant: ```c
const char *pathconN_nm8_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D19: Usage: fflisp [--load filename] [--help].


tool: D15:        --load eval code from file.


tool: D8:        --help print help message.


assistant: ```c
void usage(void) {
  printf("Usage: fflisp [--load filename] [--help].\n");
  printf("       --load eval code from file.\n");
  printf("       --help print help message.\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D15
datatype: string

tool: D28: Usage: fflisp [--load filename] [--help].


tool: D17:        --load eval code from file.


tool: D15:        --help print help message.


assistant: ```c
void usage(void) {
  printf("Usage: fflisp [--load filename] [--help].\n");
  printf("       --load eval code from file.\n");
  printf("       --help print help message.\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D28: Usage: fflisp [--load filename] [--help].


tool: D8:        --load eval code from file.


tool: D13:        --help print help message.


assistant: ```c
void usage(void) {
  printf("Usage: fflisp [--load filename] [--help].\n");
  printf("       --load eval code from file.\n");
  printf("       --help print help message.\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string

tool: D14: Usage: fflisp [--load filename] [--help].


tool: D21:        --load eval code from file.


tool: D19:        --help print help message.


assistant: ```c
void usage(void) {
  printf("Usage: fflisp [--load filename] [--help].\n");
  printf("       --load eval code from file.\n");
  printf("       --help print help message.\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mangle_filename>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbp
  lea    D17(%rip),%rdi
  call   <getenv@plt>
  test   %rbp,%rbp
  je     L26
  cmpb   $0x0,0x0(%rbp)
  je     L26
  test   %rax,%rax
  je     L96
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  mov    $0x0,%esi
  cmovns %eax,%esi
  lea    0x1(%rbx),%rdx
  jle    L96
  mov    $0x0,%ecx
  jmp    L74
L26:
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L2
L56:
  add    $0x1,%rdx
  cmp    %ecx,%esi
  jle    L96
L74:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L96
  cmp    $0x2f,%al
  jne    L56
  add    $0x1,%ecx
  mov    %rdx,%rbx
  jmp    L56
L96:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rax,%r15
  lea    0x2(%r14,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpb   $0x2f,-0x1(%rbp,%r13,1)
  je     L22
  movb   $0x2f,(%r12,%r13,1)
  lea    0x1(%r13),%r15
L22:
  lea    0x1(%r14),%rdx
  lea    (%r12,%r15,1),%rdi
  mov    %rbx,%rsi
  call   <memcpy@plt>
L2:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string

tool: D6: GCOV_PREFIX

tool: D17: GCOV_PREFIX_STRIP

assistant: ```c
char *mangle_filename(const char *orig_filename) {
  char *new_filename;
  size_t filename_len, prefix_len;
  int prefix_strip;
  int level = 0;
  const char *fname, *ptr;
  const char *prefix = getenv("GCOV_PREFIX");
  const char *prefix_strip_str = getenv("GCOV_PREFIX_STRIP");
  if (prefix == NULL || prefix[0] == '\0')
    return strdup(orig_filename);
  if (prefix_strip_str) {
    prefix_strip = atoi(prefix_strip_str);
    if (prefix_strip < 0)
      prefix_strip = 0;
  } else {
    prefix_strip = 0;
  }
  fname = orig_filename;
  for (level = 0, ptr = fname + 1; level < prefix_strip; ++ptr) {
    if (*ptr == '\0')
      break;
    if (*ptr != '/')
      continue;
    fname = ptr;
    ++level;
  }
  filename_len = strlen(fname);
  prefix_len = strlen(prefix);
  new_filename = malloc(prefix_len + 1 + filename_len + 1);
  memcpy(new_filename, prefix, prefix_len);
  if (prefix[prefix_len - 1] != '/')
    new_filename[prefix_len++] = '/';
  memcpy(new_filename + prefix_len, fname, filename_len + 1);
  return new_filename;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mangle_filename>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  push   %rbx
  call   <getenv@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rbx
  call   <getenv@plt>
  test   %rbx,%rbx
  je     L40
  cmpb   $0x0,(%rbx)
  je     L40
  test   %rax,%rax
  je     L86
  mov    %rax,%rdi
  call   <atoi@plt>
  xor    %esi,%esi
  lea    0x1(%rbp),%rdx
  test   %eax,%eax
  cmovns %eax,%esi
  jle    L86
  xor    %ecx,%ecx
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L39:
  cmp    $0x2f,%al
  jne    L24
  add    $0x1,%ecx
  mov    %rdx,%rbp
L24:
  add    $0x1,%rdx
  cmp    %esi,%ecx
  jge    L86
L60:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L39
L86:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x2(%rax,%r13,1),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  cmpb   $0x2f,-0x1(%rbx,%r12,1)
  je     L17
  movb   $0x2f,(%r14,%r12,1)
  add    $0x1,%r12
L17:
  lea    (%r14,%r12,1),%rdi
  lea    0x1(%r13),%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10f0 <strdup@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D6: GCOV_PREFIX

tool: D3: GCOV_PREFIX_STRIP

assistant: ```c
char *mangle_filename(const char *orig_filename) {
  char *new_filename;
  size_t filename_len, prefix_len;
  int prefix_strip;
  int level = 0;
  const char *fname, *ptr;
  const char *prefix = getenv("GCOV_PREFIX");
  const char *prefix_strip_str = getenv("GCOV_PREFIX_STRIP");
  if (prefix == NULL || prefix[0] == '\0')
    return strdup(orig_filename);
  if (prefix_strip_str) {
    prefix_strip = atoi(prefix_strip_str);
    if (prefix_strip < 0)
      prefix_strip = 0;
  } else {
    prefix_strip = 0;
  }
  fname = orig_filename;
  for (level = 0, ptr = fname + 1; level < prefix_strip; ++ptr) {
    if (*ptr == '\0')
      break;
    if (*ptr != '/')
      continue;
    fname = ptr;
    ++level;
  }
  filename_len = strlen(fname);
  prefix_len = strlen(prefix);
  new_filename = malloc(prefix_len + 1 + filename_len + 1);
  memcpy(new_filename, prefix, prefix_len);
  if (prefix[prefix_len - 1] != '/')
    new_filename[prefix_len++] = '/';
  memcpy(new_filename + prefix_len, fname, filename_len + 1);
  return new_filename;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mangle_filename>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D17(%rip),%rdi
  push   %rbx
  call   <getenv@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rbx
  call   <getenv@plt>
  test   %rbx,%rbx
  je     L22
  cmpb   $0x0,(%rbx)
  je     L22
  test   %rax,%rax
  je     L71
  mov    %rax,%rdi
  call   <atoi@plt>
  xor    %esi,%esi
  lea    0x1(%rbp),%rdx
  test   %eax,%eax
  cmovns %eax,%esi
  jle    L71
  xor    %ecx,%ecx
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L2:
  cmp    $0x2f,%al
  jne    L6
  add    $0x1,%ecx
  mov    %rdx,%rbp
L6:
  add    $0x1,%rdx
  cmp    %esi,%ecx
  jge    L71
L74:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L2
L71:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x2(%rax,%r13,1),%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  cmpb   $0x2f,-0x1(%rbx,%r12,1)
  je     L9
  movb   $0x2f,(%r14,%r12,1)
  add    $0x1,%r12
L9:
  lea    (%r14,%r12,1),%rdi
  lea    0x1(%r13),%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10f0 <strdup@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string

tool: D17: GCOV_PREFIX

tool: D4: GCOV_PREFIX_STRIP

assistant: ```c
char *mangle_filename(const char *orig_filename) {
  char *new_filename;
  size_t filename_len, prefix_len;
  int prefix_strip;
  int level = 0;
  const char *fname, *ptr;
  const char *prefix = getenv("GCOV_PREFIX");
  const char *prefix_strip_str = getenv("GCOV_PREFIX_STRIP");
  if (prefix == NULL || prefix[0] == '\0')
    return strdup(orig_filename);
  if (prefix_strip_str) {
    prefix_strip = atoi(prefix_strip_str);
    if (prefix_strip < 0)
      prefix_strip = 0;
  } else {
    prefix_strip = 0;
  }
  fname = orig_filename;
  for (level = 0, ptr = fname + 1; level < prefix_strip; ++ptr) {
    if (*ptr == '\0')
      break;
    if (*ptr != '/')
      continue;
    fname = ptr;
    ++level;
  }
  filename_len = strlen(fname);
  prefix_len = strlen(prefix);
  new_filename = malloc(prefix_len + 1 + filename_len + 1);
  memcpy(new_filename, prefix, prefix_len);
  if (prefix[prefix_len - 1] != '/')
    new_filename[prefix_len++] = '/';
  memcpy(new_filename + prefix_len, fname, filename_len + 1);
  return new_filename;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<igray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  js     L20
  mov    -0x28(%rbp),%rax
  shr    %rax
  xor    -0x28(%rbp),%rax
  jmp    L10
L20:
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  xor    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  jbe    L29
  cmpl   $0x10,-0x14(%rbp)
  jne    L8
L29:
  mov    -0x10(%rbp),%rax
  jmp    L10
L8:
  shll   -0x14(%rbp)
  jmp    L9
L10:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long igray(unsigned long n, int is) {
  int ish;
  unsigned long ans, idiv;
  if (is >= 0)
    return n ^ (n >> 1);
  ish = 1;
  ans = n;
  for (;;) {
    ans ^= (idiv = ans >> ish);
    if (idiv <= 1 || ish == 16)
      return ans;
    ish <<= 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<igray>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  js     L18
  mov    %rdi,%rdx
  shr    %rdx
  xor    %rdx,%rax
  ret
L18:
  mov    %rdi,%rdx
  shr    %rdx
  xor    %rdx,%rax
  cmp    $0x1,%rdx
  jbe    L32
  mov    $0x1,%ecx
L35:
  add    %ecx,%ecx
  mov    %rax,%rdx
  shr    %cl,%rdx
  xor    %rdx,%rax
  cmp    $0x1,%rdx
  jbe    L32
  cmp    $0x10,%ecx
  jne    L35
L32:
  ret
```

assistant: ```c
unsigned long igray(unsigned long n, int is) {
  int ish;
  unsigned long ans, idiv;
  if (is >= 0)
    return n ^ (n >> 1);
  ish = 1;
  ans = n;
  for (;;) {
    ans ^= (idiv = ans >> ish);
    if (idiv <= 1 || ish == 16)
      return ans;
    ish <<= 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<igray>:
  endbr64
  mov    %rdi,%rdx
  mov    %rdi,%rax
  shr    %rdx
  xor    %rdx,%rax
  test   %esi,%esi
  js     L31
L25:
  ret
  nopl   (%rax)
L31:
  cmp    $0x1,%rdx
  jbe    L25
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rax,%rdx
  add    %ecx,%ecx
  shr    %cl,%rdx
  xor    %rdx,%rax
  cmp    $0x1,%rdx
  jbe    L25
  cmp    $0x10,%ecx
  jne    L6
  ret
```

assistant: ```c
unsigned long igray(unsigned long n, int is) {
  int ish;
  unsigned long ans, idiv;
  if (is >= 0)
    return n ^ (n >> 1);
  ish = 1;
  ans = n;
  for (;;) {
    ans ^= (idiv = ans >> ish);
    if (idiv <= 1 || ish == 16)
      return ans;
    ish <<= 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<igray>:
  endbr64
  mov    %rdi,%rdx
  mov    %rdi,%rax
  shr    %rdx
  xor    %rdx,%rax
  test   %esi,%esi
  js     L36
L35:
  ret
  nopl   (%rax)
L36:
  cmp    $0x1,%rdx
  jbe    L35
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rax,%rdx
  add    %ecx,%ecx
  shr    %cl,%rdx
  xor    %rdx,%rax
  cmp    $0x1,%rdx
  jbe    L35
  cmp    $0x10,%ecx
  jne    L12
  ret
```

assistant: ```c
unsigned long igray(unsigned long n, int is) {
  int ish;
  unsigned long ans, idiv;
  if (is >= 0)
    return n ^ (n >> 1);
  ish = 1;
  ans = n;
  for (;;) {
    ans ^= (idiv = ans >> ish);
    if (idiv <= 1 || ish == 16)
      return ans;
    ish <<= 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<int_vecSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_vecSum(int *vec, int m) {
  int i;
  int sum = 0;
  for (i = 0; i < m; i++) {
    sum += vec[i];
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<int_vecSum>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L21:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L21
L19:
  mov    %edx,%eax
  ret
L24:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int int_vecSum(int *vec, int m) {
  int i;
  int sum = 0;
  for (i = 0; i < m; i++) {
    sum += vec[i];
  }
  return sum;
}
```