ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ped2lfmm>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <nb_cols_lfmm@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  lea    -0x6(%rax),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,(%rbx)
  call   <nb_lines@plt>
  mov    %eax,0x0(%rbp)
  imul   (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rbx),%edx
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    %rax,%rcx
  mov    %rax,%r12
  call   <read_ped@plt>
  mov    (%rbx),%edx
  mov    0x0(%rbp),%esi
  mov    %r14,%rdi
  mov    %r12,%rcx
  call   <write_data_int@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <free@plt>
```

assistant: ```c
void ped2lfmm(char *input_file, char *output_file, int *N, int *M) {
  int *data;
  int nb;
  nb = nb_cols_lfmm(input_file);
  *M = (nb - 6) / 2;
  *N = nb_lines(input_file, nb);
  data = (int *)malloc((*N) * (*M) * sizeof(int));
  read_ped(input_file, *N, *M, data);
  write_data_int(output_file, *N, *M, data);
  free(data);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpuid_eax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <cpuid@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_eax(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return eax;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpuid_eax>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_eax(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return eax;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpuid_eax>:
  endbr64
  sub    $0x28,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_eax(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return eax;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpuid_eax>:
  endbr64
  sub    $0x28,%rsp
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x8(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) unsigned int cpuid_eax(unsigned int op) {
  unsigned int eax, ebx, ecx, edx;
  cpuid(op, &eax, &ebx, &ecx, &edx);
  return eax;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<generer_brute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L8:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <g_pointeur_fonction_generer_brute_rec@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void generer_brute(int maxLen) {
  char *buf = malloc(maxLen + 1);
  for (int i = 1; i <= maxLen; ++i) {
    memset(buf, 0, maxLen + 1);
    g_pointeur_fonction_generer_brute_rec(buf, 0, i);
  }
  free(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generer_brute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    0x1(%rdi),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L17
  mov    $0x1,%ebx
L1:
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <g_pointeur_fonction_generer_brute_rec@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L1
L17:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void generer_brute(int maxLen) {
  char *buf = malloc(maxLen + 1);
  for (int i = 1; i <= maxLen; ++i) {
    memset(buf, 0, maxLen + 1);
    g_pointeur_fonction_generer_brute_rec(buf, 0, i);
  }
  free(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generer_brute>:
  endbr64
  push   %r13
  lea    0x1(%rdi),%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L12
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <g_pointeur_fonction_generer_brute_rec@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L13
L12:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void generer_brute(int maxLen) {
  char *buf = malloc(maxLen + 1);
  for (int i = 1; i <= maxLen; ++i) {
    memset(buf, 0, maxLen + 1);
    g_pointeur_fonction_generer_brute_rec(buf, 0, i);
  }
  free(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generer_brute>:
  endbr64
  push   %r13
  lea    0x1(%rdi),%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %r13d,%edi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L10
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <g_pointeur_fonction_generer_brute_rec@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L19
L10:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void generer_brute(int maxLen) {
  char *buf = malloc(maxLen + 1);
  for (int i = 1; i <= maxLen; ++i) {
    memset(buf, 0, maxLen + 1);
    g_pointeur_fonction_generer_brute_rec(buf, 0, i);
  }
  free(buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_four>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L7:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L10:
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target
#pragma omp teams distribute collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_four>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jg     L39
  ret
L37:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L37
L48:
  add    $0x1,%edx
  cmp    %edx,%edi
  je     L49
L39:
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L37
  jmp    L48
L49:
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target
#pragma omp teams distribute collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_four>:
  endbr64
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target
#pragma omp teams distribute collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_four>:
  endbr64
  ret
```

assistant: ```c
void test_four(int x, int y) {
#pragma omp target
#pragma omp teams distribute collapse(2)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0xa,-0x8(%rbp)
  movl   $0xa,-0xc(%rbp)
  jmp    L12
L24:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0xfffffff7,-0x4(%rbp)
  jl     L44
  cmpl   $0x9,-0x4(%rbp)
  jg     L44
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L66
L44:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L62
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L66
L62:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %eax,%edx
  jle    L29
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L66
L29:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L66:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cmp    %eax,%edx
  jg     L24
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
data_type: string

tool: D26: 
%d

assistant: ```c
int list_digits(int num) {
  int i, j;
  int digit;
  j = 10;
  for (i = 10; abs(num) > (i / 10); i *= 10) {
    digit = num % i;
    if (abs(digit) < 10) {
      printf("\n%d", abs(digit));
    } else {
      digit = digit / j;
      digit = floor(digit);
      if (abs(num) == num) {
        printf("\n%d", digit);
        j = j * 10;
      } else {
        if (abs(num / 10) > (i / 10)) {
          printf("\n%d", abs(digit));
          j = j * 10;
        } else {
          printf("\n%d", digit);
        }
      }
    }
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<list_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  neg    %r13d
  cmovs  %edi,%r13d
  cmp    $0x1,%r13d
  jle    L46
  mov    %edi,%ebp
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,0xc(%rsp)
  mov    $0xa,%r12d
  mov    $0xa,%ebx
  mov    $0x1,%r14d
  lea    D9(%rip),%r15
  jmp    L57
L73:
  cltd
  idiv   %r12d
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    %r13d,%ebp
  je     L28
  cmp    %r14d,0xc(%rsp)
  jle    L64
  neg    %eax
  cmovns %eax,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  lea    (%r12,%r12,4),%r12d
  add    %r12d,%r12d
L10:
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebx,%r14d
  cmp    %ebx,%r13d
  jle    L46
  mov    %eax,%ebx
L57:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  lea    0x9(%rdx),%ecx
  cmp    $0x12,%ecx
  ja     L73
  mov    %edx,%esi
  neg    %esi
  cmovs  %edx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L10
L28:
  mov    %r15,%rdi
  call   <printf@plt>
  lea    (%r12,%r12,4),%r12d
  add    %r12d,%r12d
  jmp    L10
L64:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L10
L46:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: 
%d

assistant: ```c
int list_digits(int num) {
  int i, j;
  int digit;
  j = 10;
  for (i = 10; abs(num) > (i / 10); i *= 10) {
    digit = num % i;
    if (abs(digit) < 10) {
      printf("\n%d", abs(digit));
    } else {
      digit = digit / j;
      digit = floor(digit);
      if (abs(num) == num) {
        printf("\n%d", digit);
        j = j * 10;
      } else {
        if (abs(num / 10) > (i / 10)) {
          printf("\n%d", abs(digit));
          j = j * 10;
        } else {
          printf("\n%d", digit);
        }
      }
    }
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<list_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  neg    %r13d
  cmovs  %edi,%r13d
  cmp    $0x1,%r13d
  jle    L41
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %edi,%ebp
  mov    $0xa,%r12d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  mov    $0xa,%ebx
  lea    D2(%rip),%r14
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%r15d
  neg    %r15d
  cmovns %r15d,%eax
  mov    $0x1,%r15d
  mov    %eax,0xc(%rsp)
  jmp    L22
  nopl   (%rax)
L19:
  mov    %edx,%esi
  mov    %r14,%rdi
  neg    %esi
  cmovs  %edx,%esi
  call   <printf@plt>
L57:
  lea    (%rbx,%rbx,4),%eax
  mov    %ebx,%r15d
  add    %eax,%eax
  cmp    %ebx,%r13d
  jle    L41
L51:
  mov    %eax,%ebx
L22:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  jbe    L19
  mov    %edx,%eax
  cltd
  idiv   %r12d
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    %r13d,%ebp
  je     L50
  cmp    %r15d,0xc(%rsp)
  jle    L52
  neg    %eax
  cmovns %eax,%esi
L50:
  mov    %r14,%rdi
  lea    (%r12,%r12,4),%r12d
  mov    %ebx,%r15d
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  add    %r12d,%r12d
  add    %eax,%eax
  cmp    %ebx,%r13d
  jg     L51
L41:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L57
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: 
%d

assistant: ```c
int list_digits(int num) {
  int i, j;
  int digit;
  j = 10;
  for (i = 10; abs(num) > (i / 10); i *= 10) {
    digit = num % i;
    if (abs(digit) < 10) {
      printf("\n%d", abs(digit));
    } else {
      digit = digit / j;
      digit = floor(digit);
      if (abs(num) == num) {
        printf("\n%d", digit);
        j = j * 10;
      } else {
        if (abs(num / 10) > (i / 10)) {
          printf("\n%d", abs(digit));
          j = j * 10;
        } else {
          printf("\n%d", digit);
        }
      }
    }
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_digits>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  neg    %r12d
  cmovs  %edi,%r12d
  cmp    $0x1,%r12d
  jle    L73
  movslq %edi,%rax
  mov    %edi,%edx
  mov    %edi,%ebp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%r15d
  neg    %r15d
  cmovns %r15d,%eax
  mov    %eax,0xc(%rsp)
  cmp    %r12d,%edi
  je     L63
  mov    $0xa,%r13d
  mov    $0xa,%ebx
  mov    $0x1,%r15d
  lea    D4(%rip),%r14
  jmp    L91
  xchg   %ax,%ax
L54:
  mov    %edx,%eax
  cltd
  idiv   %r13d
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    %r15d,0xc(%rsp)
  jle    L96
  neg    %eax
  mov    %r14,%rdi
  lea    0x0(%r13,%r13,4),%r13d
  mov    %ebx,%r15d
  cmovns %eax,%esi
  add    %r13d,%r13d
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  cmp    %ebx,%r12d
  jle    L73
L74:
  mov    %eax,%ebx
L91:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  ja     L54
  mov    %edx,%esi
  neg    %esi
  cmovs  %edx,%esi
L96:
  mov    %r14,%rdi
  mov    %ebx,%r15d
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  cmp    %ebx,%r12d
  jg     L74
L73:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L63:
  mov    $0xa,%ebp
  mov    $0xa,%ebx
  lea    D4(%rip),%r14
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %edx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L29:
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  cmp    %ebx,%r12d
  jle    L73
  mov    %eax,%ebx
L30:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  jbe    L59
  mov    %edx,%eax
  cltd
  idiv   %ebp
  lea    0x0(%rbp,%rbp,4),%ebp
  add    %ebp,%ebp
  mov    %eax,%edi
  call   <floor@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L29
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: 
%d

assistant: ```c
int list_digits(int num) {
  int i, j;
  int digit;
  j = 10;
  for (i = 10; abs(num) > (i / 10); i *= 10) {
    digit = num % i;
    if (abs(digit) < 10) {
      printf("\n%d", abs(digit));
    } else {
      digit = digit / j;
      digit = floor(digit);
      if (abs(num) == num) {
        printf("\n%d", digit);
        j = j * 10;
      } else {
        if (abs(num / 10) > (i / 10)) {
          printf("\n%d", abs(digit));
          j = j * 10;
        } else {
          printf("\n%d", digit);
        }
      }
    }
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L15:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void delay(int n) {
  glutPostRedisplay();
  int i = 0;
  while (i < n) {
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<delay>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  test   %ebx,%ebx
  jle    L16
  mov    $0x0,%eax
L8:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L8
L16:
  pop    %rbx
  ret
```

assistant: ```c
void delay(int n) {
  glutPostRedisplay();
  int i = 0;
  while (i < n) {
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delay>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <glutPostRedisplay@plt>
```

assistant: ```c
void delay(int n) {
  glutPostRedisplay();
  int i = 0;
  while (i < n) {
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <glutPostRedisplay@plt>
```

assistant: ```c
void delay(int n) {
  glutPostRedisplay();
  int i = 0;
  while (i < n) {
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L8:
  movl   $0x2,-0x14(%rbp)
  movl   $0x7b,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x3b9ac9fe,-0xc(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; i < 999999999; i++) {
    int a = 2;
    int b = 123;
    swap(&a, &b);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3b9ac9ff,%ebx
  lea    0x4(%rsp),%rbp
L3:
  movl   $0x2,(%rsp)
  movl   $0x7b,0x4(%rsp)
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <swap@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; i < 999999999; i++) {
    int a = 2;
    int b = 123;
    swap(&a, &b);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x3b9ac9ff,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L6:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x2,(%rsp)
  movl   $0x7b,0x4(%rsp)
  call   <swap@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; i < 999999999; i++) {
    int a = 2;
    int b = 123;
    swap(&a, &b);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x3b9ac9ff,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x2,(%rsp)
  movl   $0x7b,0x4(%rsp)
  call   <swap@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; i < 999999999; i++) {
    int a = 2;
    int b = 123;
    swap(&a, &b);
  }
  return 0;
}
```