ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<remove_dup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L45
  mov    %r12,%rax
  lea    -0x1(%rbp),%edx
  lea    0x1(%r12,%rdx,1),%r8
  mov    $0x0,%edi
  jmp    L13
L34:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L45
L13:
  movzbl (%rax),%edx
  movsbl %dl,%ecx
  movsbq %dl,%rsi
  cmpl   $0x0,(%rsp,%rsi,4)
  jne    L34
  movslq %edi,%rsi
  mov    %dl,(%rbx,%rsi,1)
  movslq %ecx,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  lea    0x1(%rdi),%edi
  jmp    L34
L45:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %rbx,%rax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_dup(char str[]) {
  int len = strlen(str);
  char *res = (char *)malloc(len + 1);
  int hit[256];
  memset(hit, 0, sizeof(hit));
  for (int i = 0, end = 0; i < len; i++) {
    if (hit[str[i]] == 0) {
      res[end++] = str[i];
      hit[str[i]]++;
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_dup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L30
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  xor    %ecx,%ecx
  lea    0x1(%rbx,%rax,1),%rsi
  nopw   0x0(%rax,%rax,1)
L17:
  movsbq (%rdi),%rax
  mov    (%rsp,%rax,4),%r8d
  test   %r8d,%r8d
  jne    L1
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %al,(%r12,%r8,1)
  addl   $0x1,(%rsp,%rax,4)
L1:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L17
L30:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x410,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_dup(char str[]) {
  int len = strlen(str);
  char *res = (char *)malloc(len + 1);
  int hit[256];
  memset(hit, 0, sizeof(hit));
  for (int i = 0, end = 0; i < len; i++) {
    if (hit[str[i]] == 0) {
      res[end++] = str[i];
      hit[str[i]]++;
    }
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_dup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L18
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  xor    %ecx,%ecx
  lea    0x1(%rbx,%rax,1),%rsi
  nopw   0x0(%rax,%rax,1)
L36:
  movsbq (%rdi),%rax
  mov    (%rsp,%rax,4),%r8d
  test   %r8d,%r8d
  jne    L19
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %al,(%r12,%r8,1)
  addl   $0x1,(%rsp,%rax,4)
L19:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L36
L18:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x410,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *remove_dup(char str[]) {
  int len = strlen(str);
  char *res = (char *)malloc(len + 1);
  int hit[256];
  memset(hit, 0, sizeof(hit));
  for (int i = 0, end = 0; i < len; i++) {
    if (hit[str[i]] == 0) {
      res[end++] = str[i];
      hit[str[i]]++;
    }
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DrawAim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %r9d,%eax
  mov    %al,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    0x10(%rbp),%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <XSetForeground@plt>
  mov    -0x38(%rbp),%eax
  lea    -0x14(%rax),%edi
  mov    -0x34(%rbp),%eax
  lea    -0x14(%rax),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x5a00
  push   $0x0
  push   $0x28
  mov    $0x28,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <XDrawArc@plt>
  add    $0x20,%rsp
  mov    -0x34(%rbp),%eax
  lea    0x1e(%rax),%r9d
  mov    -0x34(%rbp),%eax
  lea    -0x1e(%rax),%ecx
  mov    -0x38(%rbp),%r8d
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x38(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  call   <XDrawLine@plt>
  add    $0x10,%rsp
  mov    -0x38(%rbp),%eax
  lea    0x1e(%rax),%edi
  mov    -0x38(%rbp),%eax
  lea    -0x1e(%rax),%r10d
  mov    -0x34(%rbp),%r8d
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   %rdi
  mov    %r8d,%r9d
  mov    %r10d,%r8d
  mov    %rax,%rdi
  call   <XDrawLine@plt>
  add    $0x10,%rsp
  mov    -0x38(%rbp),%eax
  lea    -0x4(%rax),%r8d
  lea    -0x20(%rbp),%rdi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x1
  mov    %rdi,%r9
  mov    %rax,%rdi
  call   <XDrawText@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void DrawAim(Display *dpy, Window w, GC gc, int x, int y, char c, int color) {
  XTextItem text = {&c, 1, 5, None};
  XSetForeground(dpy, gc, color);
  XDrawArc(dpy, w, gc, x - 40 / 2, y - 40 / 2, 40, 40, 0, 23040);
  XDrawLine(dpy, w, gc, x - 40 / 2 - 10, y, x + 40 / 2 + 10, y);
  XDrawLine(dpy, w, gc, x, y - 40 / 2 - 10, x, y + 40 / 2 + 10);
  XDrawText(dpy, w, gc, x, y - 4, &text, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DrawAim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %r8d,%ebp
  mov    %r9b,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x20(%rsp)
  mov    0x60(%rsp),%edx
  mov    %r13d,%esi
  call   <XSetForeground@plt>
  lea    -0x14(%rbx),%ecx
  sub    $0x8,%rsp
  push   $0x5a00
  push   $0x0
  push   $0x28
  mov    $0x28,%r9d
  lea    -0x14(%rbp),%r8d
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <XDrawArc@plt>
  add    $0x18,%rsp
  lea    -0x1e(%rbx),%ecx
  push   %rbp
  lea    0x1e(%rbx),%r9d
  mov    %ebp,%r8d
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <XDrawLine@plt>
  lea    0x1e(%rbp),%eax
  mov    %eax,(%rsp)
  mov    %ebx,%r9d
  lea    -0x1e(%rbp),%r8d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <XDrawLine@plt>
  movl   $0x1,(%rsp)
  lea    0x20(%rsp),%r9
  lea    -0x4(%rbp),%r8d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <XDrawText@plt>
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DrawAim(Display *dpy, Window w, GC gc, int x, int y, char c, int color) {
  XTextItem text = {&c, 1, 5, None};
  XSetForeground(dpy, gc, color);
  XDrawArc(dpy, w, gc, x - 40 / 2, y - 40 / 2, 40, 40, 0, 23040);
  XDrawLine(dpy, w, gc, x - 40 / 2 - 10, y, x + 40 / 2 + 10, y);
  XDrawLine(dpy, w, gc, x, y - 40 / 2 - 10, x, y + 40 / 2 + 10);
  XDrawText(dpy, w, gc, x, y - 4, &text, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DrawAim>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r13d,%esi
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x30,%rsp
  mov    %r9b,0xc(%rsp)
  mov    0x60(%rsp),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movabs $0x500000001,%rax
  mov    %rax,0x18(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x20(%rsp)
  call   <XSetForeground@plt>
  sub    $0x8,%rsp
  lea    -0x14(%rbx),%r8d
  mov    %r13d,%edx
  push   $0x5a00
  lea    -0x14(%r12),%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  push   $0x0
  mov    $0x28,%r9d
  push   $0x28
  call   <XDrawArc@plt>
  add    $0x18,%rsp
  mov    %ebx,%r8d
  mov    %r13d,%edx
  push   %rbx
  lea    -0x1e(%r12),%ecx
  lea    0x1e(%r12),%r9d
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <XDrawLine@plt>
  lea    0x1e(%rbx),%eax
  mov    %r12d,%r9d
  lea    -0x1e(%rbx),%r8d
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,(%rsp)
  call   <XDrawLine@plt>
  lea    0x20(%rsp),%r9
  mov    %r13d,%edx
  mov    %r12d,%ecx
  lea    -0x4(%rbx),%r8d
  mov    %r14d,%esi
  mov    %rbp,%rdi
  movl   $0x1,(%rsp)
  call   <XDrawText@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DrawAim(Display *dpy, Window w, GC gc, int x, int y, char c, int color) {
  XTextItem text = {&c, 1, 5, None};
  XSetForeground(dpy, gc, color);
  XDrawArc(dpy, w, gc, x - 40 / 2, y - 40 / 2, 40, 40, 0, 23040);
  XDrawLine(dpy, w, gc, x - 40 / 2 - 10, y, x + 40 / 2 + 10, y);
  XDrawLine(dpy, w, gc, x, y - 40 / 2 - 10, x, y + 40 / 2 + 10);
  XDrawText(dpy, w, gc, x, y - 4, &text, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rc4hash_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x0,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x84(%rbp)
  jmp    L21
L1:
  mov    -0x84(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0xa0(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0xb(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0xb(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x84(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x80(%rbp,%rdx,4)
  addl   $0x1,-0x84(%rbp)
L21:
  cmpl   $0x19,-0x84(%rbp)
  jle    L1
  lea    -0x80(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rc4hash_unpack@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void rc4hash_parse(struct rc4hash *hash, const char *input) {
  uint8_t extract[26];
  char n[3] = {0};
  for (int i = 0; i < 26; i++) {
    memcpy(n, input + i * 2, 2);
    extract[i] = strtol(n, NULL, 16);
  }
  rc4hash_unpack(hash, (char *)extract);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rc4hash_parse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movw   $0x0,0x75(%rsp)
  movb   $0x0,0x77(%rsp)
  mov    %rsi,%rbp
  mov    %rsp,%rbx
  lea    0x68(%rsp),%r14
  lea    0x75(%rsp),%r12
L1:
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %eax,(%rbx)
  add    $0x2,%rbp
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L1
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <rc4hash_unpack@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rc4hash_parse(struct rc4hash *hash, const char *input) {
  uint8_t extract[26];
  char n[3] = {0};
  for (int i = 0; i < 26; i++) {
    memcpy(n, input + i * 2, 2);
    extract[i] = strtol(n, NULL, 16);
  }
  rc4hash_unpack(hash, (char *)extract);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rc4hash_parse>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x77(%rsp)
  mov    %rsp,%r15
  mov    %ax,0x75(%rsp)
  mov    %r15,%rbx
  lea    0x68(%rsp),%r13
  lea    0x75(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rsi
  mov    $0x2,%edx
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  add    $0x2,%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbx
  jne    L19
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <rc4hash_unpack@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rc4hash_parse(struct rc4hash *hash, const char *input) {
  uint8_t extract[26];
  char n[3] = {0};
  for (int i = 0; i < 26; i++) {
    memcpy(n, input + i * 2, 2);
    extract[i] = strtol(n, NULL, 16);
  }
  rc4hash_unpack(hash, (char *)extract);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rc4hash_parse>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x77(%rsp)
  mov    %rsp,%r15
  mov    %ax,0x75(%rsp)
  mov    %r15,%rbx
  lea    0x68(%rsp),%r13
  lea    0x75(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    $0x2,%edx
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  add    $0x2,%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbx
  jne    L3
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <rc4hash_unpack@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rc4hash_parse(struct rc4hash *hash, const char *input) {
  uint8_t extract[26];
  char n[3] = {0};
  for (int i = 0; i < 26; i++) {
    memcpy(n, input + i * 2, 2);
    extract[i] = strtol(n, NULL, 16);
  }
  rc4hash_unpack(hash, (char *)extract);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L7
L13:
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    %al,%cl
  je     L30
L7:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  jmp    L35
L5:
  nop
L35:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
find(a, b, c) char (*a[])[];
char b[];
int c;
{
  int i, j;
  i = -1;
  while (++i < c) {
    j = 0;
    while (b[j] == (*a[i])[j]) {
      if (b[j] == '\0')
        goto found;
      j++;
    }
  }
found:
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find>:
  endbr64
  test   %edx,%edx
  jle    L20
  movzbl (%rsi),%r10d
  mov    $0x0,%r9d
L5:
  mov    (%rdi),%r8
  mov    %r10d,%ecx
  mov    $0x1,%eax
  cmp    (%r8),%r10b
  jne    L28
L56:
  test   %cl,%cl
  je     L3
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%r8,%rax,1),%cl
  je     L56
L28:
  add    $0x1,%r9d
  add    $0x8,%rdi
  cmp    %edx,%r9d
  jne    L5
  mov    %edx,%r9d
  jmp    L3
L20:
  mov    $0x0,%r9d
L3:
  mov    %r9d,%eax
  ret
```

assistant: ```c
find(a, b, c) char (*a[])[];
char b[];
int c;
{
  int i, j;
  i = -1;
  while (++i < c) {
    j = 0;
    while (b[j] == (*a[i])[j]) {
      if (b[j] == '\0')
        goto found;
      j++;
    }
  }
found:
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find>:
  endbr64
  test   %edx,%edx
  jle    L12
  movzbl (%rsi),%r10d
  xor    %r9d,%r9d
L3:
  mov    (%rdi),%r8
  mov    %r10d,%ecx
  mov    $0x1,%eax
  cmp    (%r8),%r10b
  je     L53
  jmp    L4
  nopl   0x0(%rax)
L0:
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%r8,%rax,1),%cl
  jne    L4
L53:
  test   %cl,%cl
  jne    L0
L47:
  mov    %r9d,%eax
  ret
  nop
L4:
  add    $0x1,%r9d
  add    $0x8,%rdi
  cmp    %edx,%r9d
  jne    L3
  jmp    L47
L12:
  xor    %r9d,%r9d
  jmp    L47
```

assistant: ```c
find(a, b, c) char (*a[])[];
char b[];
int c;
{
  int i, j;
  i = -1;
  while (++i < c) {
    j = 0;
    while (b[j] == (*a[i])[j]) {
      if (b[j] == '\0')
        goto found;
      j++;
    }
  }
found:
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find>:
  endbr64
  test   %edx,%edx
  jle    L72
  movzbl (%rsi),%r10d
  xor    %r9d,%r9d
L9:
  mov    (%rdi),%r8
  mov    %r10d,%ecx
  mov    $0x1,%eax
  cmp    (%r8),%r10b
  je     L7
  jmp    L75
  nopl   0x0(%rax)
L22:
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%r8,%rax,1),%cl
  jne    L75
L7:
  test   %cl,%cl
  jne    L22
L47:
  mov    %r9d,%eax
  ret
  nop
L75:
  add    $0x1,%r9d
  add    $0x8,%rdi
  cmp    %edx,%r9d
  jne    L9
  jmp    L47
L72:
  xor    %r9d,%r9d
  jmp    L47
```

assistant: ```c
find(a, b, c) char (*a[])[];
char b[];
int c;
{
  int i, j;
  i = -1;
  while (++i < c) {
    j = 0;
    while (b[j] == (*a[i])[j]) {
      if (b[j] == '\0')
        goto found;
      j++;
    }
  }
found:
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0xfffffffe,-0x4(%rbp)
  mov    $0x0,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %d

assistant: ```c
int main(void) {
  int i = -1;
  int i2 = -2;
  printf("%d", i2 - i2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
int main(void) {
  int i = -1;
  int i2 = -2;
  printf("%d", i2 - i2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: %d

assistant: ```c
int main(void) {
  int i = -1;
  int i2 = -2;
  printf("%d", i2 - i2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: %d

assistant: ```c
int main(void) {
  int i = -1;
  int i2 = -2;
  printf("%d", i2 - i2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L29:
  movl   $0x0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L48
L3:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <Isprime@plt>
  test   %rax,%rax
  je     L48
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
L48:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L3
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string

tool: D3: %d

tool: D16: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int gp, i, count;
  scanf("%d", &gp);
  getchar();
  for (i = 0; i < gp; i++) {
    int num, total = 0;
    scanf("%d", &count);
    getchar();
    while (count--) {
      scanf("%d", &num);
      getchar();
      if (Isprime(num))
        total += num;
    }
    printf("%d\n", total);
  }
  return 0;
}
```