ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<right_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L89
L31:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x2c(%rbp)
  je     L3
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  jmp    L52
L3:
  mov    $0x0,%eax
L52:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L44
  cmpb   $0x77,-0x11(%rbp)
  jne    L44
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x77,%al
  je     L44
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movl   $0x1,-0x8(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movsbl -0x11(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <is_same_color@plt>
  test   %rax,%rax
  je     L46
  addl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x10(%rbp)
L89:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L31
  jmp    L78
L46:
  nop
L78:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int right_count(char necklace[], int point, int len) {
  int i, count = 1;
  int right_point;
  int is_change = 0;
  char original_color = necklace[point];
  for (i = 0; i < len - 1; i++) {
    right_point = point == len - 1 ? 0 : point + 1;
    if (!is_change && original_color == 'w' && necklace[right_point] != 'w') {
      original_color = necklace[right_point];
      is_change = 1;
    }
    if (is_same_color(original_color, necklace[right_point]))
      count++;
    else
      break;
    point = right_point;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<right_count>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%r12d
  lea    -0x1(%rdx),%r15d
  test   %r15d,%r15d
  jle    L63
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    $0x0,%r14d
  mov    $0x1,%ebp
  jmp    L45
L56:
  movslq %ebx,%rax
  movzbl 0x0(%r13,%rax,1),%r12d
  cmp    $0x77,%r12b
  setne  %r14b
  movzbl %r14b,%r14d
L60:
  movslq %ebx,%rax
  movsbl 0x0(%r13,%rax,1),%esi
  movsbl %r12b,%edi
  call   <is_same_color@plt>
  test   %rax,%rax
  je     L75
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  je     L50
L45:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r15d
  mov    $0x0,%ebx
  cmovne %eax,%ebx
  test   %r14d,%r14d
  jne    L60
  cmp    $0x77,%r12b
  je     L56
  jmp    L60
L50:
  mov    0xc(%rsp),%ebp
L75:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  mov    $0x1,%ebp
  jmp    L75
```

assistant: ```c
int right_count(char necklace[], int point, int len) {
  int i, count = 1;
  int right_point;
  int is_change = 0;
  char original_color = necklace[point];
  for (i = 0; i < len - 1; i++) {
    right_point = point == len - 1 ? 0 : point + 1;
    if (!is_change && original_color == 'w' && necklace[right_point] != 'w') {
      original_color = necklace[right_point];
      is_change = 1;
    }
    if (is_same_color(original_color, necklace[right_point]))
      count++;
    else
      break;
    point = right_point;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<right_count>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi,%rax,1),%r12d
  mov    %edx,0xc(%rsp)
  test   %r13d,%r13d
  jle    L43
  mov    %rdi,%rbp
  mov    %rax,%r14
  xor    %ebx,%ebx
  mov    $0x1,%r15d
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%r14d
  movslq %r14d,%rax
  add    %rbp,%rax
L0:
  movsbl (%rax),%esi
  test   %ebx,%ebx
  jne    L66
  cmp    $0x77,%r12b
  jne    L66
  xor    %ebx,%ebx
  cmp    $0x77,%sil
  mov    %esi,%r12d
  setne  %bl
L66:
  movsbl %r12b,%edi
  call   <is_same_color@plt>
  test   %rax,%rax
  je     L48
  add    $0x1,%r15d
  cmp    %r15d,0xc(%rsp)
  je     L48
L38:
  cmp    %r14d,%r13d
  jne    L30
  mov    %rbp,%rax
  xor    %r14d,%r14d
  jmp    L0
L43:
  mov    $0x1,%r15d
L48:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int right_count(char necklace[], int point, int len) {
  int i, count = 1;
  int right_point;
  int is_change = 0;
  char original_color = necklace[point];
  for (i = 0; i < len - 1; i++) {
    right_point = point == len - 1 ? 0 : point + 1;
    if (!is_change && original_color == 'w' && necklace[right_point] != 'w') {
      original_color = necklace[right_point];
      is_change = 1;
    }
    if (is_same_color(original_color, necklace[right_point]))
      count++;
    else
      break;
    point = right_point;
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<right_count>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  lea    -0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi,%rax,1),%ecx
  test   %r13d,%r13d
  jle    L37
  mov    %rax,%rbx
  mov    %rdi,%r14
  mov    %edx,%r15d
  mov    $0x1,%r12d
  movl   $0x0,0xc(%rsp)
  cmp    %ebx,%r13d
  je     L128
  nopw   0x0(%rax,%rax,1)
L95:
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    %r14,%rax
L104:
  movzbl 0xc(%rsp),%ebp
  movsbl (%rax),%esi
  xor    $0x1,%ebp
  cmp    $0x77,%cl
  sete   %dil
  and    %dil,%bpl
  mov    %bpl,0xb(%rsp)
  je     L34
  xor    %eax,%eax
  cmp    $0x77,%sil
  mov    %esi,%ecx
  setne  %al
  mov    %eax,0xc(%rsp)
L34:
  movsbl %cl,%ebp
  mov    %cl,0xa(%rsp)
  mov    %ebp,%edi
  call   <is_same_color@plt>
  test   %rax,%rax
  je     L15
  add    $0x1,%r12d
  movzbl 0xa(%rsp),%ecx
  cmp    %r12d,%r15d
  je     L122
  cmpb   $0x0,0xb(%rsp)
  je     L86
  cmp    %ebx,%r13d
  jne    L95
L128:
  mov    %r14,%rax
  xor    %ebx,%ebx
  jmp    L104
L2:
  add    $0x1,%ebx
  mov    %ebp,%edi
  movslq %ebx,%rax
  add    %r14,%rax
  movsbl (%rax),%esi
  call   <is_same_color@plt>
  test   %rax,%rax
  je     L15
L4:
  lea    0x1(%r12),%r15d
  cmp    %r13d,%r12d
  jge    L122
  mov    %r15d,%r12d
L86:
  cmp    %r13d,%ebx
  jne    L2
  mov    %r14,%rax
  mov    %ebp,%edi
  xor    %ebx,%ebx
  movsbl (%rax),%esi
  call   <is_same_color@plt>
  test   %rax,%rax
  jne    L4
L15:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L122:
  mov    %r15d,%r12d
  jmp    L15
L37:
  mov    $0x1,%r12d
  jmp    L15
```

assistant: ```c
int right_count(char necklace[], int point, int len) {
  int i, count = 1;
  int right_point;
  int is_change = 0;
  char original_color = necklace[point];
  for (i = 0; i < len - 1; i++) {
    right_point = point == len - 1 ? 0 : point + 1;
    if (!is_change && original_color == 'w' && necklace[right_point] != 'w') {
      original_color = necklace[right_point];
      is_change = 1;
    }
    if (is_same_color(original_color, necklace[right_point]))
      count++;
    else
      break;
    point = right_point;
  }
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L46
  mov    $0x0,%eax
  call   <do_lock@plt>
  jmp    L40
L46:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
  mov    $0x0,%eax
  call   <do_unlock@plt>
  jmp    L40
L49:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L43
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <show_usage@plt>
  mov    $0x0,%eax
L40:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string

tool: D0: -l

tool: D7: -u

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 0; i < argc; i++) {
    if (strcmp("-l", argv[i]) == 0) {
      return do_lock();
    }
    if (strcmp("-u", argv[i]) == 0) {
      return do_unlock();
    }
  }
  show_usage(argv[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  test   %edi,%edi
  jle    L57
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r13
  lea    D2(%rip),%rbp
  lea    D1(%rip),%r12
L16:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L16
L57:
  mov    (%r14),%rdi
  call   <show_usage@plt>
  mov    $0x0,%eax
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <do_lock@plt>
  jmp    L52
L17:
  call   <do_unlock@plt>
  jmp    L52
```

tool_calls: name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D1
type: string

tool: D2: -l

tool: D1: -u

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 0; i < argc; i++) {
    if (strcmp("-l", argv[i]) == 0) {
      return do_lock();
    }
    if (strcmp("-u", argv[i]) == 0) {
      return do_unlock();
    }
  }
  show_usage(argv[0]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L21
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    D16(%rip),%rbp
  lea    0x8(%rsi,%rax,8),%r13
  lea    D12(%rip),%r12
  jmp    L6
  xchg   %ax,%ax
L48:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L26
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L21
L6:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <do_lock@plt>
L21:
  mov    (%r14),%rdi
  call   <show_usage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <do_unlock@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D16: -l

tool: D12: -u

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 0; i < argc; i++) {
    if (strcmp("-l", argv[i]) == 0) {
      return do_lock();
    }
    if (strcmp("-u", argv[i]) == 0) {
      return do_unlock();
    }
  }
  show_usage(argv[0]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L10
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    D5(%rip),%rbp
  lea    0x8(%rsi,%rax,8),%r13
  lea    D16(%rip),%r12
  jmp    L21
  xchg   %ax,%ax
L14:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L12
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L10
L21:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <do_lock@plt>
L10:
  mov    (%r14),%rdi
  call   <show_usage@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <do_unlock@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D5: -l

tool: D16: -u

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 0; i < argc; i++) {
    if (strcmp("-l", argv[i]) == 0) {
      return do_lock();
    }
    if (strcmp("-u", argv[i]) == 0) {
      return do_unlock();
    }
  }
  show_usage(argv[0]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x78(%rsp),%rbp
  mov    %rbx,%r12
L25:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%r12)
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L25
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r12
  mov    $0x1d,%esi
  mov    %r12,%rdi
  call   <print_list@plt>
  mov    $0xf,%ecx
  mov    $0x1d,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <find_kth_element_r@plt>
  mov    0x3c(%rsp),%edx
  mov    $0xf,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L20
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x1d,%esi
  mov    %rbx,%rdi
  call   <print_list@plt>
  mov    $0xf,%ecx
  mov    $0x1d,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <find_kth_element_nr@plt>
  mov    0x3c(%rsp),%edx
  mov    $0xf,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D36
datatype: string

tool: D6: first list (solve recursively):

tool: D2: 
element in position %d is: %d


tool: D36: second list (solve non-recursively):

assistant: ```c
int main() {
  int l[30];
  int size = 30;
  int k = 15;
  int c;
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("first list (solve recursively):\n");
  print_list(l, size - 1);
  find_kth_element_r(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("second list (solve non-recursively):\n");
  print_list(l, size - 1);
  find_kth_element_nr(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x78(%rsp),%rbp
  mov    %r12,%rbx
  mov    %r12,%r13
  nop
L28:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L28
  lea    D21(%rip),%rdi
  lea    D8(%rip),%r13
  call   <puts@plt>
  mov    $0x1d,%esi
  mov    %r12,%rdi
  call   <print_list@plt>
  mov    $0x1d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    $0xf,%ecx
  call   <find_kth_element_r@plt>
  mov    0x3c(%rsp),%edx
  mov    $0xf,%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  nopl   (%rax)
L16:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L16
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x1d,%esi
  mov    %r12,%rdi
  call   <print_list@plt>
  xor    %esi,%esi
  mov    $0x1d,%edx
  mov    %r12,%rdi
  mov    $0xf,%ecx
  call   <find_kth_element_nr@plt>
  mov    0x3c(%rsp),%edx
  xor    %eax,%eax
  mov    $0xf,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D25
datatype: string

tool: D21: first list (solve recursively):

tool: D8: 
element in position %d is: %d


tool: D25: second list (solve non-recursively):

assistant: ```c
int main() {
  int l[30];
  int size = 30;
  int k = 15;
  int c;
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("first list (solve recursively):\n");
  print_list(l, size - 1);
  find_kth_element_r(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("second list (solve non-recursively):\n");
  print_list(l, size - 1);
  find_kth_element_nr(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x78(%rsp),%rbp
  mov    %r12,%rbx
  mov    %r12,%r13
  nop
L22:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L22
  lea    D20(%rip),%rdi
  lea    D5(%rip),%r13
  call   <puts@plt>
  mov    $0x1d,%esi
  mov    %r12,%rdi
  call   <print_list@plt>
  mov    $0x1d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    $0xf,%ecx
  call   <find_kth_element_r@plt>
  mov    0x3c(%rsp),%edx
  mov    $0xf,%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  nopl   (%rax)
L7:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L7
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x1d,%esi
  mov    %r12,%rdi
  call   <print_list@plt>
  xor    %esi,%esi
  mov    $0x1d,%edx
  mov    %r12,%rdi
  mov    $0xf,%ecx
  call   <find_kth_element_nr@plt>
  mov    0x3c(%rsp),%edx
  xor    %eax,%eax
  mov    $0xf,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
data_type: string
name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D20: first list (solve recursively):

tool: D5: 
element in position %d is: %d


tool: D12: second list (solve non-recursively):

assistant: ```c
int main() {
  int l[30];
  int size = 30;
  int k = 15;
  int c;
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("first list (solve recursively):\n");
  print_list(l, size - 1);
  find_kth_element_r(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  for (c = 0; c < size; c++)
    l[c] = rand() % 100;
  printf("second list (solve non-recursively):\n");
  print_list(l, size - 1);
  find_kth_element_nr(l, 0, size - 1, k);
  printf("\nelement in position %d is: %d\n", k, l[k]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<proc_inc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L29
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jne    L35
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jne    L27
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L45
L27:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L45
L35:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L45
L29:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jne    L68
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jne    L13
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L45
L13:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L45
L68:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L45:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void proc_inc(myrow, mycol, nprow, npcol, major) int *myrow, *mycol, nprow, npcol, major;
{
  if (major == 1) {
    if (*mycol == npcol - 1) {
      *mycol = 0;
      if (*myrow == nprow - 1) {
        *myrow = 0;
      } else {
        *myrow = *myrow + 1;
      }
    } else {
      *mycol = *mycol + 1;
    }
  } else {
    if (*myrow == nprow - 1) {
      *myrow = 0;
      if (*mycol == npcol - 1) {
        *mycol = 0;
      } else {
        *mycol = *mycol + 1;
      }
    } else {
      *myrow = *myrow + 1;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<proc_inc>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x1,%r8d
  je     L5
  mov    (%rdi),%edi
  sub    $0x1,%edx
  cmp    %edx,%edi
  je     L3
  add    $0x1,%edi
  mov    %edi,(%rax)
  ret
L5:
  mov    (%rsi),%edi
  sub    $0x1,%ecx
  cmp    %ecx,%edi
  je     L20
  add    $0x1,%edi
  mov    %edi,(%rsi)
  ret
L20:
  movl   $0x0,(%rsi)
  mov    (%rax),%ecx
  sub    $0x1,%edx
  lea    0x1(%rcx),%esi
  cmp    %edx,%ecx
  mov    $0x0,%edx
  cmovne %esi,%edx
  mov    %edx,(%rax)
  ret
L3:
  movl   $0x0,(%rax)
  mov    (%rsi),%eax
  sub    $0x1,%ecx
  lea    0x1(%rax),%edx
  cmp    %ecx,%eax
  mov    $0x0,%eax
  cmovne %edx,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void proc_inc(myrow, mycol, nprow, npcol, major) int *myrow, *mycol, nprow, npcol, major;
{
  if (major == 1) {
    if (*mycol == npcol - 1) {
      *mycol = 0;
      if (*myrow == nprow - 1) {
        *myrow = 0;
      } else {
        *myrow = *myrow + 1;
      }
    } else {
      *mycol = *mycol + 1;
    }
  } else {
    if (*myrow == nprow - 1) {
      *myrow = 0;
      if (*mycol == npcol - 1) {
        *mycol = 0;
      } else {
        *mycol = *mycol + 1;
      }
    } else {
      *myrow = *myrow + 1;
    }
  }
}
```