ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
L62:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L62
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    %edx,%eax
  jl     L144
  mov    $0x0,%esi
  mov    $0x1,%ecx
  jle    L192
L111:
  mov    0x8(%rsp),%edi
  cmp    %edi,%eax
  jge    L148
  mov    %edi,%eax
  mov    $0x2,%esi
L148:
  cmp    %edi,%edx
  jle    L78
  mov    %edi,%edx
  mov    $0x2,%ecx
L78:
  mov    0xc(%rsp),%edi
  cmp    %edi,%eax
  jge    L160
  mov    %edi,%eax
  mov    $0x3,%esi
L160:
  cmp    %edi,%edx
  jle    L39
  mov    %edi,%edx
  mov    $0x3,%ecx
L39:
  mov    0x10(%rsp),%edi
  cmp    %edi,%eax
  jge    L155
  mov    %edi,%eax
  mov    $0x4,%esi
L155:
  cmp    %edi,%edx
  jle    L92
  mov    %edi,%edx
  mov    $0x4,%ecx
L92:
  mov    0x14(%rsp),%edi
  cmp    %edi,%eax
  jge    L145
  mov    %edi,%eax
  mov    $0x5,%esi
L145:
  cmp    %edi,%edx
  jle    L19
  mov    %edi,%edx
  mov    $0x5,%ecx
L19:
  mov    0x18(%rsp),%edi
  cmp    %edi,%eax
  jge    L186
  mov    %edi,%eax
  mov    $0x6,%esi
L186:
  cmp    %edi,%edx
  jle    L107
  mov    %edi,%edx
  mov    $0x6,%ecx
L107:
  mov    0x1c(%rsp),%edi
  cmp    %edi,%eax
  jge    L14
  mov    %edi,%eax
  mov    $0x7,%esi
L14:
  cmp    %edi,%edx
  jle    L76
  mov    %edi,%edx
  mov    $0x7,%ecx
L76:
  mov    0x20(%rsp),%edi
  cmp    %edi,%eax
  jge    L51
  mov    %edi,%eax
  mov    $0x8,%esi
L51:
  cmp    %edi,%edx
  jle    L50
  mov    %edi,%edx
  mov    $0x8,%ecx
L50:
  mov    0x24(%rsp),%edi
  cmp    %eax,%edi
  jle    L96
  mov    %edi,%eax
  mov    $0x9,%esi
L96:
  cmp    %edx,%edi
  mov    $0x9,%edx
  mov    %eax,0x24(%rsp)
  lea    D1(%rip),%rbp
  cmovl  %rdx,%rcx
  mov    %edi,(%rsp,%rsi,4)
  mov    (%rsp),%eax
  mov    (%rsp,%rcx,4),%edx
  mov    %edx,(%rsp)
  mov    %eax,(%rsp,%rcx,4)
  nopl   (%rax)
L90:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L90
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L144:
  mov    $0x1,%esi
L137:
  xchg   %eax,%edx
  xor    %ecx,%ecx
  jmp    L111
L192:
  mov    %eax,%edx
  jmp    L137
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D6: %d

tool: D1: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, max = 0, min = 0, tmp, a[10];
  for (i = 0; i < 10; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 10; i++) {
    if (a[i] > a[max])
      max = i;
    if (a[i] < a[min])
      min = i;
  }
  tmp = a[9];
  a[9] = a[max];
  a[max] = tmp;
  tmp = a[0];
  a[0] = a[min];
  a[min] = tmp;
  for (i = 0; i < 10; i++) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<diffdays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tmcpy@plt>
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x28(%rbp)
  movl   $0x5,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x38(%rbp),%rax
  movq   $0x0,0x8(%rax)
  mov    -0x38(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x10,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int diffdays(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return difftime(mktime(&ref), mktime(current)) / 86400;
}
```
user: Translate the below assembly code into C programming language:

```asm
<diffdays>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %rax,%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <tmcpy@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x5,(%rsp)
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  movq   $0x0,0x10(%rax)
  movq   $0x0,0x8(%rax)
  movl   $0x5,(%rax)
  call   <mktime@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <difftime@plt>
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x10,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffdays(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return difftime(mktime(&ref), mktime(current)) / 86400;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<diffdays>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <tmcpy@plt>
  mov    %rbp,%rdi
  movl   $0x5,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <localtime@plt>
  movq   $0x0,0x10(%rax)
  mov    %rax,%rdi
  movq   $0x0,0x8(%rax)
  movl   $0x5,(%rax)
  call   <mktime@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <mktime@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0x10,%edx
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffdays(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return difftime(mktime(&ref), mktime(current)) / 86400;
}
```
user: What is the c source code of the assembly code below?

```asm
<diffdays>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <tmcpy@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  movl   $0x5,(%rsp)
  movups %xmm0,0x8(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  movl   $0x5,(%rax)
  mov    %rax,%rdi
  movups %xmm0,0x8(%rax)
  call   <mktime@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <mktime@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0x10,%edx
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int diffdays(const time_t *startDate, const time_t *endDate) {
  struct tm ref, *current;
  current = localtime(endDate);
  tmcpy(&ref, current);
  ref.tm_sec = 0;
  ref.tm_min = 0;
  ref.tm_hour = 5;
  current = localtime(startDate);
  current->tm_sec = 0;
  current->tm_min = 0;
  current->tm_hour = 5;
  return difftime(mktime(&ref), mktime(current)) / 86400;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PerfxAtomicInt_Set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__sync_synchronize@plt>
  nop
  leave
  ret
```

assistant: ```c
void PerfxAtomicInt_Set(int32_t *ptr, int32_t new_int) {
  *ptr = new_int;
  __sync_synchronize();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PerfxAtomicInt_Set>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,(%rdi)
  mov    $0x0,%eax
  call   <__sync_synchronize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void PerfxAtomicInt_Set(int32_t *ptr, int32_t new_int) {
  *ptr = new_int;
  __sync_synchronize();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PerfxAtomicInt_Set>:
  endbr64
  mov    %esi,(%rdi)
  xor    %eax,%eax
  jmp    1050 <__sync_synchronize@plt>
```

assistant: ```c
void PerfxAtomicInt_Set(int32_t *ptr, int32_t new_int) {
  *ptr = new_int;
  __sync_synchronize();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PerfxAtomicInt_Set>:
  endbr64
  mov    %esi,(%rdi)
  xor    %eax,%eax
  jmp    1050 <__sync_synchronize@plt>
```

assistant: ```c
void PerfxAtomicInt_Set(int32_t *ptr, int32_t new_int) {
  *ptr = new_int;
  __sync_synchronize();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cst_ulaw_to_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  notb   -0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x80,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  add    $0x3,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %esi,%eax
  mov    %ax,-0xe(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L2
  movzwl -0xe(%rbp),%eax
  neg    %eax
  mov    %ax,-0xe(%rbp)
L2:
  movzwl -0xe(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: 

assistant: ```c
short cst_ulaw_to_short(unsigned char ulawbyte) {
  static const int exp_lut[8] = {0, 132, 396, 924, 1980, 4092, 8316, 16764};
  int sign, exponent, mantissa;
  short sample;
  ulawbyte = ~ulawbyte;
  sign = (ulawbyte & 0x80);
  exponent = (ulawbyte >> 4) & 0x07;
  mantissa = ulawbyte & 0x0F;
  sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  if (sign != 0)
    sample = -sample;
  return sample;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cst_ulaw_to_short>:
  endbr64
  not    %edi
  mov    %edi,%edx
  shr    $0x4,%dl
  and    $0x7,%edx
  mov    %edi,%eax
  and    $0xf,%eax
  lea    0x3(%rdx),%ecx
  shl    %cl,%eax
  movslq %edx,%rdx
  lea    D7(%rip),%rcx
  add    (%rcx,%rdx,4),%ax
  mov    %eax,%edx
  neg    %edx
  test   %dil,%dil
  cmovs  %edx,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string

tool: 

assistant: ```c
short cst_ulaw_to_short(unsigned char ulawbyte) {
  static const int exp_lut[8] = {0, 132, 396, 924, 1980, 4092, 8316, 16764};
  int sign, exponent, mantissa;
  short sample;
  ulawbyte = ~ulawbyte;
  sign = (ulawbyte & 0x80);
  exponent = (ulawbyte >> 4) & 0x07;
  mantissa = ulawbyte & 0x0F;
  sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  if (sign != 0)
    sample = -sample;
  return sample;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cst_ulaw_to_short>:
  endbr64
  not    %edi
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x4,%dl
  and    $0xf,%eax
  and    $0x7,%edx
  lea    0x3(%rdx),%ecx
  movslq %edx,%rdx
  shl    %cl,%eax
  lea    D9(%rip),%rcx
  add    (%rcx,%rdx,4),%ax
  mov    %eax,%edx
  neg    %edx
  test   %dil,%dil
  cmovs  %edx,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: 

assistant: ```c
short cst_ulaw_to_short(unsigned char ulawbyte) {
  static const int exp_lut[8] = {0, 132, 396, 924, 1980, 4092, 8316, 16764};
  int sign, exponent, mantissa;
  short sample;
  ulawbyte = ~ulawbyte;
  sign = (ulawbyte & 0x80);
  exponent = (ulawbyte >> 4) & 0x07;
  mantissa = ulawbyte & 0x0F;
  sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  if (sign != 0)
    sample = -sample;
  return sample;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cst_ulaw_to_short>:
  endbr64
  not    %edi
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x4,%dl
  and    $0xf,%eax
  and    $0x7,%edx
  lea    0x3(%rdx),%ecx
  movslq %edx,%rdx
  shl    %cl,%eax
  lea    D8(%rip),%rcx
  add    (%rcx,%rdx,4),%ax
  mov    %eax,%edx
  neg    %edx
  test   %dil,%dil
  cmovs  %edx,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: 

assistant: ```c
short cst_ulaw_to_short(unsigned char ulawbyte) {
  static const int exp_lut[8] = {0, 132, 396, 924, 1980, 4092, 8316, 16764};
  int sign, exponent, mantissa;
  short sample;
  ulawbyte = ~ulawbyte;
  sign = (ulawbyte & 0x80);
  exponent = (ulawbyte >> 4) & 0x07;
  mantissa = ulawbyte & 0x0F;
  sample = exp_lut[exponent] + (mantissa << (exponent + 3));
  if (sign != 0)
    sample = -sample;
  return sample;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<output_number_sprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%eax
  mov    %ecx,%r14d
  mov    %r8d,%ebp
  mov    %r9d,%r13d
  cmp    %edx,%ecx
  jbe    L16
L11:
  cmp    %eax,%r14d
  jbe    L98
  test   %ebp,%ebp
  jle    L98
  mov    %ebp,%r8d
  sub    $0x1,%r8d
  je     L98
  mov    %r13d,%edx
  and    $0x1,%edx
  jmp    L41
L16:
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%r15d
  lea    -0x1(%r8),%r8d
  mov    %eax,%edx
  mov    %rbx,%rsi
  call   <output_number_sprintf>
  mov    %r15d,%eax
  jmp    L11
L104:
  mov    (%rbx),%rcx
  movb   $0x20,(%rcx)
  addq   $0x1,(%rbx)
  mov    (%r12),%edi
  lea    0x1(%rdi),%ecx
L84:
  mov    %ecx,(%r12)
  sub    $0x1,%r8d
  je     L98
L41:
  test   %edx,%edx
  je     L104
  mov    (%rbx),%rcx
  movb   $0x30,(%rcx)
  addq   $0x1,(%rbx)
  mov    (%r12),%esi
  lea    0x1(%rsi),%ecx
  jmp    L84
L98:
  test   $0x2,%r13b
  je     L40
  lea    0x30(%rax),%ecx
  lea    0x37(%rax),%edx
  cmp    $0x9,%eax
  cmovbe %ecx,%edx
  mov    (%rbx),%rax
  mov    %dl,(%rax)
  addq   $0x1,(%rbx)
  mov    (%r12),%eax
  add    $0x1,%eax
L26:
  mov    %eax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  lea    0x30(%rax),%ecx
  lea    0x57(%rax),%edx
  cmp    $0x9,%eax
  cmovbe %ecx,%edx
  mov    (%rbx),%rax
  mov    %dl,(%rax)
  addq   $0x1,(%rbx)
  mov    (%r12),%eax
  add    $0x1,%eax
  jmp    L26
```

assistant: ```c
void output_number_sprintf(int *n, char **s, unsigned int x, int base, int min, unsigned int flags) {
  if (x >= base) {
    output_number_sprintf(n, s, x / base, base, min - 1, flags);
    x %= base;
  }
  if (x < base && min > 0) {
    while (--min)
      if (flags & 0x1)
        do {
          size_t bytes;
          char _c = '0';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
      else
        do {
          size_t bytes;
          char _c = ' ';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
  }
  if (flags & 0x2)
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'A'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
  else
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'a'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<output_number_sprintf>:
  endbr64
  push   %r14
  mov    %edx,%eax
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  cmp    %edx,%ecx
  jbe    L40
L14:
  mov    0x0(%rbp),%rcx
  test   %ebx,%ebx
  jle    L43
  sub    $0x1,%ebx
  mov    %ebx,%r8d
  je     L43
  mov    %r13d,%edx
  and    $0x1,%edx
  jmp    L97
  nopw   0x0(%rax,%rax,1)
L87:
  movb   $0x30,(%rcx)
L37:
  mov    0x0(%rbp),%rbx
  mov    (%r12),%edi
  lea    0x1(%rbx),%rcx
  lea    0x1(%rdi),%esi
  mov    %rcx,0x0(%rbp)
  mov    %esi,(%r12)
  sub    $0x1,%r8d
  je     L43
L97:
  test   %edx,%edx
  jne    L87
  movb   $0x20,(%rcx)
  jmp    L37
  nopl   0x0(%rax)
L43:
  mov    %eax,%edx
  and    $0x2,%r13d
  lea    0x30(%rdx),%esi
  je     L17
  add    $0x37,%edx
L11:
  cmp    $0x9,%eax
  cmovbe %esi,%edx
  mov    %dl,(%rcx)
  mov    (%r12),%eax
  pop    %rbx
  addq   $0x1,0x0(%rbp)
  add    $0x1,%eax
  pop    %rbp
  mov    %eax,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L17:
  add    $0x57,%edx
  jmp    L11
  nopl   (%rax)
L40:
  xor    %edx,%edx
  lea    -0x1(%r8),%r8d
  div    %ecx
  mov    %edx,%r14d
  mov    %eax,%edx
  call   <output_number_sprintf>
  mov    %r14d,%eax
  jmp    L14
```

assistant: ```c
void output_number_sprintf(int *n, char **s, unsigned int x, int base, int min, unsigned int flags) {
  if (x >= base) {
    output_number_sprintf(n, s, x / base, base, min - 1, flags);
    x %= base;
  }
  if (x < base && min > 0) {
    while (--min)
      if (flags & 0x1)
        do {
          size_t bytes;
          char _c = '0';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
      else
        do {
          size_t bytes;
          char _c = ' ';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
  }
  if (flags & 0x2)
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'A'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
  else
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'a'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<output_number_sprintf>:
  endbr64
  push   %r14
  mov    %edx,%eax
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  cmp    %edx,%ecx
  jbe    L52
L6:
  mov    0x0(%rbp),%rcx
  test   %ebx,%ebx
  jle    L62
  sub    $0x1,%ebx
  mov    %ebx,%r8d
  je     L62
  test   $0x1,%r13b
  jne    L32
  nopl   0x0(%rax,%rax,1)
L20:
  movb   $0x20,(%rcx)
  mov    0x0(%rbp),%rbx
  lea    0x1(%rbx),%rcx
  mov    %rcx,0x0(%rbp)
  addl   $0x1,(%r12)
  sub    $0x1,%r8d
  jne    L20
L62:
  mov    %eax,%edx
  and    $0x2,%r13d
  lea    0x30(%rdx),%esi
  je     L1
  add    $0x37,%edx
L82:
  cmp    $0x9,%eax
  cmovbe %esi,%edx
  mov    %dl,(%rcx)
  mov    (%r12),%eax
  pop    %rbx
  addq   $0x1,0x0(%rbp)
  add    $0x1,%eax
  pop    %rbp
  mov    %eax,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  add    $0x57,%edx
  jmp    L82
  nopl   (%rax)
L32:
  movb   $0x30,(%rcx)
  mov    0x0(%rbp),%rdi
  lea    0x1(%rdi),%rcx
  mov    %rcx,0x0(%rbp)
  addl   $0x1,(%r12)
  sub    $0x1,%r8d
  jne    L32
  jmp    L62
  nopl   0x0(%rax)
L52:
  xor    %edx,%edx
  lea    -0x1(%r8),%r8d
  div    %ecx
  mov    %edx,%r14d
  mov    %eax,%edx
  call   <output_number_sprintf>
  mov    %r14d,%eax
  jmp    L6
```

assistant: ```c
void output_number_sprintf(int *n, char **s, unsigned int x, int base, int min, unsigned int flags) {
  if (x >= base) {
    output_number_sprintf(n, s, x / base, base, min - 1, flags);
    x %= base;
  }
  if (x < base && min > 0) {
    while (--min)
      if (flags & 0x1)
        do {
          size_t bytes;
          char _c = '0';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
      else
        do {
          size_t bytes;
          char _c = ' ';
          *(*(s)) = _c;
          (*(s))++;
          (*(n))++;
        } while (0);
  }
  if (flags & 0x2)
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'A'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
  else
    do {
      size_t bytes;
      char _c = (((x) < 10 ? (x) + '0' : (x)-10 + 'a'));
      *(*(s)) = _c;
      (*(s))++;
      (*(n))++;
    } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Parse2DMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <COM_MatchToken@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L0:
  mov    -0x4(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Parse1DMatrix@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <COM_MatchToken@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D11: (

tool: D5: )

assistant: ```c
void Parse2DMatrix(const char **buf_p, int y, int x, float *m) {
  int i;
  COM_MatchToken(buf_p, "(");
  for (i = 0; i < y; i++) {
    Parse1DMatrix(buf_p, x, m + i * x);
  }
  COM_MatchToken(buf_p, ")");
}
```
user: What is the c source code of the assembly code below:

```asm
<Parse2DMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,%rbx
  lea    D4(%rip),%rsi
  call   <COM_MatchToken@plt>
  test   %r13d,%r13d
  jle    L14
  movslq %r14d,%r15
  shl    $0x2,%r15
  mov    $0x0,%ebp
L4:
  mov    %rbx,%rdx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <Parse1DMatrix@plt>
  add    $0x1,%ebp
  add    %r15,%rbx
  cmp    %ebp,%r13d
  jne    L4
L14:
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <COM_MatchToken@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D4: (

tool: D16: )

assistant: ```c
void Parse2DMatrix(const char **buf_p, int y, int x, float *m) {
  int i;
  COM_MatchToken(buf_p, "(");
  for (i = 0; i < y; i++) {
    Parse1DMatrix(buf_p, x, m + i * x);
  }
  COM_MatchToken(buf_p, ")");
}
```