user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hist_omp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %edx,-0x50(%rbp)
  mov    -0x4c(%rbp),%eax
  imul   -0x50(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    $0x400,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L80
L3:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x38(%rbp)
L80:
  cmpl   $0xff,-0x38(%rbp)
  jle    L3
  movl   $0x100,-0x34(%rbp)
  movl   $0xffffffff,-0x30(%rbp)
  mov    $0x400,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L137
L32:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x2c(%rbp)
L137:
  cmpl   $0xff,-0x2c(%rbp)
  jle    L32
  movl   $0x0,-0x28(%rbp)
  jmp    L94
L133:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x28(%rbp)
L94:
  mov    -0x28(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L133
  movl   $0x0,-0x24(%rbp)
  jmp    L116
L20:
  addl   $0x1,-0x24(%rbp)
L116:
  cmpl   $0xff,-0x24(%rbp)
  jg     L150
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L20
L150:
  movl   $0xff,-0x20(%rbp)
  jmp    L136
L152:
  subl   $0x1,-0x20(%rbp)
L136:
  cmpl   $0x0,-0x20(%rbp)
  js     L86
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L152
L86:
  mov    -0x34(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L103
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x34(%rbp)
L103:
  mov    -0x30(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L55
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x30(%rbp)
L55:
  mov    -0x30(%rbp),%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xff,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L153
L159:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rsi
  mov    -0x48(%rbp),%rdx
  add    %rsi,%rdx
  imul   %rcx,%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L153:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L159
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void hist_omp2(uint8_t *pixels, int height, int width) {
  uint64_t npixels = height * width;
  int *h = xmalloc(sizeof(*h) * 256);
  for (int i = 0; i < 256; i++)
    h[i] = 0;
  int mini = 256, maxi = -1;
#pragma omp parallel
  {
    int *hloc = xmalloc(sizeof(*hloc) * 256);
    for (int i = 0; i < 256; i++)
      hloc[i] = 0;
#pragma omp for nowait
    for (int i = 0; i < npixels; i++)
      hloc[pixels[i]]++;
    int mini_loc, maxi_loc;
    for (mini_loc = 0; mini_loc < 256 && hloc[mini_loc] == 0; mini_loc++)
      ;
    for (maxi_loc = 255; maxi_loc >= 0 && hloc[maxi_loc] == 0; maxi_loc--)
      ;
#pragma omp critical
    {
      if (mini > mini_loc)
        mini = mini_loc;
      if (maxi < maxi_loc)
        maxi = maxi_loc;
    }
    int q = 255 / (maxi - mini);
#pragma omp for
    for (int i = 0; i < npixels; i++)
      pixels[i] = (pixels[i] - mini) * q;
    free(hloc);
  }
  free(h);
}
```