ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<concat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    (%rbx,%rax,1),%r13
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L22
  mov    $0x0,%edx
L17:
  movzbl (%r14,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L17
L22:
  test   %rbp,%rbp
  je     L12
  mov    $0x0,%edx
  add    %rax,%rbx
L11:
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rbp,%rdx
  jne    L11
L12:
  movb   $0x0,(%rax,%r13,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *concat(const char *a, const char *b) {
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  size_t size = len_a + len_b;
  char *s = malloc(size + 1);
  int i;
  for (i = 0; i < len_a; ++i)
    s[i] = a[i];
  for (i = 0; i < len_b; ++i)
    s[len_a + i] = b[i];
  s[size] = 0;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r13
  mov    %rax,%r14
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L16
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L16:
  test   %r14,%r14
  je     L4
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L4:
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *concat(const char *a, const char *b) {
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  size_t size = len_a + len_b;
  char *s = malloc(size + 1);
  int i;
  for (i = 0; i < len_a; ++i)
    s[i] = a[i];
  for (i = 0; i < len_b; ++i)
    s[len_a + i] = b[i];
  s[size] = 0;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r13
  mov    %rax,%r14
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L19
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L19:
  test   %r14,%r14
  je     L18
  lea    (%r12,%rbx,1),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L18:
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *concat(const char *a, const char *b) {
  size_t len_a = strlen(a);
  size_t len_b = strlen(b);
  size_t size = len_a + len_b;
  char *s = malloc(size + 1);
  int i;
  for (i = 0; i < len_a; ++i)
    s[i] = a[i];
  for (i = 0; i < len_b; ++i)
    s[len_a + i] = b[i];
  s[size] = 0;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L5
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shift(int a[], int n, int max_index) {
  int i;
  for (i = max_index + 1; i < n; i++) {
    a[i - 1] = a[i];
  }
  a[n - 1] = a[max_index];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shift>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    0x1(%rdx),%eax
  cmp    %esi,%eax
  jge    L19
  cltq
  lea    (%r8,%rax,4),%rax
  lea    -0x2(%rsi),%ecx
  sub    %edx,%ecx
  movslq %edx,%rsi
  add    %rsi,%rcx
  lea    0x8(%r8,%rcx,4),%rsi
L7:
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L7
L19:
  movslq %edx,%rdx
  mov    (%r8,%rdx,4),%eax
  movslq %edi,%rdi
  mov    %eax,-0x4(%r8,%rdi,4)
  ret
```

assistant: ```c
void shift(int a[], int n, int max_index) {
  int i;
  for (i = max_index + 1; i < n; i++) {
    a[i - 1] = a[i];
  }
  a[n - 1] = a[max_index];
}
```
user: What is the c source code of the assembly code below:

```asm
<shift>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    0x1(%rbp),%eax
  movslq %esi,%rbx
  cmp    %ebx,%eax
  jge    L5
  cltq
  lea    -0x2(%rbx),%edx
  shl    $0x2,%rax
  sub    %ebp,%edx
  lea    (%rdi,%rax,1),%rsi
  lea    0x4(,%rdx,4),%rdx
  lea    -0x4(%rdi,%rax,1),%rdi
  call   <memmove@plt>
L5:
  mov    (%r12,%rbp,4),%eax
  mov    %eax,-0x4(%r12,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void shift(int a[], int n, int max_index) {
  int i;
  for (i = max_index + 1; i < n; i++) {
    a[i - 1] = a[i];
  }
  a[n - 1] = a[max_index];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    0x1(%rbp),%eax
  movslq %esi,%rbx
  cmp    %ebx,%eax
  jge    L7
  cltq
  lea    -0x2(%rbx),%edx
  shl    $0x2,%rax
  sub    %ebp,%edx
  lea    (%rdi,%rax,1),%rsi
  lea    0x4(,%rdx,4),%rdx
  lea    -0x4(%rdi,%rax,1),%rdi
  call   <memmove@plt>
L7:
  mov    (%r12,%rbp,4),%eax
  mov    %eax,-0x4(%r12,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void shift(int a[], int n, int max_index) {
  int i;
  for (i = max_index + 1; i < n; i++) {
    a[i - 1] = a[i];
  }
  a[n - 1] = a[max_index];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pyi_test_temp_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L8
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L8:
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mkdtemp@plt>
  test   %rax,%rax
  je     L16
  mov    $0x1,%eax
  jmp    L10
L16:
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string

tool: D10: /

tool: D0: _MEIXXXXXX

assistant: ```c
int pyi_test_temp_path(char *buff) {
  if (buff[strlen(buff) - 1] != '/') {
    strcat(buff, "/");
  }
  strcat(buff, "_MEIXXXXXX");
  if (mkdtemp(buff)) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pyi_test_temp_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbx,%rax,1)
  jne    L14
L0:
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <mkdtemp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
L14:
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D6: _MEIXXXXXX

tool: D3: /

assistant: ```c
int pyi_test_temp_path(char *buff) {
  if (buff[strlen(buff) - 1] != '/') {
    strcat(buff, "/");
  }
  strcat(buff, "_MEIXXXXXX");
  if (mkdtemp(buff)) {
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pyi_test_temp_path>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L6
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L6:
  mov    %rbp,%rdi
  lea    D19(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <mkdtemp@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D8: /

tool: D19: _MEIXXXXXX

assistant: ```c
int pyi_test_temp_path(char *buff) {
  if (buff[strlen(buff) - 1] != '/') {
    strcat(buff, "/");
  }
  strcat(buff, "_MEIXXXXXX");
  if (mkdtemp(buff)) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pyi_test_temp_path>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x2f,-0x1(%rbp,%rax,1)
  je     L7
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L7:
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <mkdtemp@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string

tool: D5: /

tool: D7: _MEIXXXXXX

assistant: ```c
int pyi_test_temp_path(char *buff) {
  if (buff[strlen(buff) - 1] != '/') {
    strcat(buff, "/");
  }
  strcat(buff, "_MEIXXXXXX");
  if (mkdtemp(buff)) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lookup_anid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x18(%rbp),%rax
  jmp    L17
L29:
  addq   $0x1,-0x18(%rbp)
  jmp    L12
L7:
  nop
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    -0x18(%rbp),%rax
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t lookup_anid(char **anids, const char *nid) {
  size_t i = 0;
  while (1) {
    if (anids[i] == NULL)
      break;
    if (strcmp(anids[i], nid) == 0)
      return i;
    i++;
  }
  anids[i] = strdup(nid);
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lookup_anid>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L15
  lea    0x8(%r12),%rbx
  mov    $0x0,%ebp
L8:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L4
  add    $0x1,%rbp
  mov    %rbx,%r12
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L8
L19:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
L4:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%ebp
  jmp    L19
```

assistant: ```c
size_t lookup_anid(char **anids, const char *nid) {
  size_t i = 0;
  while (1) {
    if (anids[i] == NULL)
      break;
    if (strcmp(anids[i], nid) == 0)
      return i;
    i++;
  }
  anids[i] = strdup(nid);
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lookup_anid>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L36
  lea    0x8(%rbp),%rbx
  xor    %r12d,%r12d
  jmp    L3
  nopl   (%rax)
L2:
  mov    %rbx,%rbp
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  add    $0x1,%r12
  test   %rdi,%rdi
  je     L14
L3:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  xor    %r12d,%r12d
L14:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t lookup_anid(char **anids, const char *nid) {
  size_t i = 0;
  while (1) {
    if (anids[i] == NULL)
      break;
    if (strcmp(anids[i], nid) == 0)
      return i;
    i++;
  }
  anids[i] = strdup(nid);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lookup_anid>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L20
  lea    0x8(%rbp),%rbx
  xor    %r12d,%r12d
  jmp    L4
  nopl   (%rax)
L19:
  mov    %rbx,%rbp
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  add    $0x1,%r12
  test   %rdi,%rdi
  je     L3
L4:
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  xor    %r12d,%r12d
L3:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t lookup_anid(char **anids, const char *nid) {
  size_t i = 0;
  while (1) {
    if (anids[i] == NULL)
      break;
    if (strcmp(anids[i], nid) == 0)
      return i;
    i++;
  }
  anids[i] = strdup(nid);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<contar_perguntas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %edx,-0x1b8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1ac(%rbp)
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L50
L39:
  mov    -0x1a8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1c0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x1a0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a8(%rbp)
L50:
  mov    -0x1a8(%rbp),%eax
  cmp    -0x1b4(%rbp),%eax
  jl     L39
  movl   $0x0,-0x1a4(%rbp)
  jmp    L58
L48:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,-0x1b8(%rbp)
  jg     L24
  addl   $0x1,-0x1ac(%rbp)
L24:
  addl   $0x1,-0x1a4(%rbp)
L58:
  cmpl   $0x63,-0x1a4(%rbp)
  jle    L48
  mov    -0x1ac(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int contar_perguntas(int n, int p[n], int k) {
  int c = 0, ac[100] = {0};
  for (int i = 0; i < n; i++)
    ac[p[i] - 1]++;
  for (int i = 0; i < 100; i++)
    if (ac[i] >= k)
      c++;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contar_perguntas>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%r9d
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r9d,%r9d
  jle    L36
  mov    %rsi,%rdx
  lea    -0x1(%r9),%eax
  lea    0x4(%rsi,%rax,4),%rcx
L33:
  mov    (%rdx),%eax
  sub    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L33
L36:
  mov    %rsp,%rax
  lea    0x190(%rsp),%rsi
  mov    $0x0,%edx
L30:
  cmp    %r8d,(%rax)
  setge  %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L30
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %edx,%eax
  add    $0x1a8,%rsp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contar_perguntas(int n, int p[n], int k) {
  int c = 0, ac[100] = {0};
  for (int i = 0; i < n; i++)
    ac[p[i] - 1]++;
  for (int i = 0; i < 100; i++)
    if (ac[i] >= k)
      c++;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<contar_perguntas>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%r8d
  mov    $0x32,%ecx
  mov    %edx,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r8d,%r8d
  jle    L31
  lea    -0x1(%r8),%eax
  lea    0x4(%rsi,%rax,4),%rdx
  nopl   (%rax)
L18:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  sub    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rsi
  jne    L18
  mov    (%rsp),%edx
L19:
  lea    0x4(%rsp),%rax
  lea    0x190(%rsp),%rcx
  xor    %r8d,%r8d
  jmp    L48
  nopl   0x0(%rax)
L38:
  mov    (%rax),%edx
  add    $0x4,%rax
L48:
  cmp    %edx,%r9d
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%r8d
  cmp    %rax,%rcx
  jne    L38
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %r8d,%eax
  add    $0x1a8,%rsp
  ret
L31:
  xor    %edx,%edx
  jmp    L19
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contar_perguntas(int n, int p[n], int k) {
  int c = 0, ac[100] = {0};
  for (int i = 0; i < n; i++)
    ac[p[i] - 1]++;
  for (int i = 0; i < 100; i++)
    if (ac[i] >= k)
      c++;
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<contar_perguntas>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%r9d
  mov    $0x32,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  mov    %r8,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r9d,%r9d
  jle    L3
  lea    -0x1(%r9),%eax
  lea    0x4(%rsi,%rax,4),%rcx
  nopl   (%rax)
L32:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  sub    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rcx,%rsi
  jne    L32
L3:
  movd   %edx,%xmm4
  pxor   %xmm1,%xmm1
  mov    %r8,%rdi
  pshufd $0x0,%xmm4,%xmm2
  lea    0x190(%rsp),%rax
  movdqa %xmm1,%xmm3
L24:
  movdqa %xmm2,%xmm0
  add    $0x10,%rdi
  pcmpgtd -0x10(%rdi),%xmm0
  pcmpeqd %xmm3,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L24
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x1a8,%rsp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int contar_perguntas(int n, int p[n], int k) {
  int c = 0, ac[100] = {0};
  for (int i = 0; i < n; i++)
    ac[p[i] - 1]++;
  for (int i = 0; i < 100; i++)
    if (ac[i] >= k)
      c++;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_phy_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L49
L13:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L15
  mov    $0x1,%eax
  jmp    L49
L15:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    $0x1,%eax
  jmp    L49
L44:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mdio_phy_id_c45@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x0,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int parse_phy_id(char *text, uint16_t *phy_id) {
  unsigned long port, dev;
  char *end;
  port = strtoul(text, &end, 0);
  if (!end[0]) {
    *phy_id = port;
    return 0;
  }
  if (end[0] != ':') {
    return 1;
  }
  dev = strtoul(end + 1, &end, 0);
  if (end[0])
    return 1;
  *phy_id = mdio_phy_id_c45(port, dev);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_phy_id>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <strtoul@plt>
  mov    %rax,%rbp
  mov    (%rsp),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  mov    $0x1,%edx
  cmp    $0x3a,%al
  je     L43
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,(%rbx)
  mov    $0x0,%edx
  jmp    L2
L43:
  mov    %rsp,%rsi
  add    $0x1,%rdi
  mov    $0x0,%edx
  call   <strtoul@plt>
  mov    $0x1,%edx
  mov    (%rsp),%rcx
  cmpb   $0x0,(%rcx)
  jne    L2
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <mdio_phy_id_c45@plt>
  mov    %rax,(%rbx)
  mov    $0x0,%edx
  jmp    L2
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_phy_id(char *text, uint16_t *phy_id) {
  unsigned long port, dev;
  char *end;
  port = strtoul(text, &end, 0);
  if (!end[0]) {
    *phy_id = port;
    return 0;
  }
  if (end[0] != ':') {
    return 1;
  }
  dev = strtoul(end + 1, &end, 0);
  if (end[0])
    return 1;
  *phy_id = mdio_phy_id_c45(port, dev);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_phy_id>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <strtoul@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  cmp    $0x3a,%al
  je     L51
L29:
  mov    $0x1,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L51:
  add    $0x1,%rdi
  xor    %edx,%edx
  mov    %r12,%rsi
  call   <strtoul@plt>
  mov    %rax,%rsi
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  jne    L29
  mov    %rbp,%rdi
  call   <mdio_phy_id_c45@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  jmp    L34
  nopl   0x0(%rax)
L28:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  jmp    L34
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_phy_id(char *text, uint16_t *phy_id) {
  unsigned long port, dev;
  char *end;
  port = strtoul(text, &end, 0);
  if (!end[0]) {
    *phy_id = port;
    return 0;
  }
  if (end[0] != ':') {
    return 1;
  }
  dev = strtoul(end + 1, &end, 0);
  if (end[0])
    return 1;
  *phy_id = mdio_phy_id_c45(port, dev);
  return 0;
}
```