user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L55
  mov    0x8(%rsi),%rdi
  lea    D72(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L71
  cmpl   $0x1,0x4(%rsp)
  lea    D34(%rip),%r14
  lea    0x3(%rsp),%r12
  lea    D0(%rip),%rbx
  lea    D22(%rip),%r13
  je     L78
  nopl   0x0(%rax)
L75:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  movsbl 0x3(%rsp),%edi
  cmp    $0x51,%dil
  je     L27
  mov    %rbp,%rsi
  lea    0x4(%rsp),%r15
  call   <putc@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  mov    %dil,0x3(%rsp)
  movsbl %dil,%edi
  call   <putc@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  and    $0xff00,%edi
  mov    %edi,0x4(%rsp)
  sar    $0x8,%edi
  mov    %dil,0x3(%rsp)
  movsbl %dil,%edi
  call   <putc@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  mov    %dil,0x3(%rsp)
  movsbl %dil,%edi
  call   <putc@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  and    $0xff00,%edi
  mov    %edi,0x4(%rsp)
  sar    $0x8,%edi
  mov    %dil,0x3(%rsp)
  movsbl %dil,%edi
  call   <putc@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    %rbp,%rsi
  mov    %dil,0x3(%rsp)
  movsbl %dil,%edi
  call   <putc@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movl   $0x0,0x4(%rsp)
  jmp    L75
  nopl   0x0(%rax)
L27:
  movl   $0x1,0x4(%rsp)
L78:
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L72:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  or     $0xffffffff,%eax
  jmp    L72
L71:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L72
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D72
datatype: string
name: parse_data
arguments: data_tag: D34
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D22
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D39
datatype: string
name: parse_data
arguments: data_tag: D42
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string

tool: D72: w+

tool: D34: Enter type to add: 

tool: D0: %c

tool: D22: %i

tool: D36: X: 

tool: D39: Y: 

tool: D42: Attrib: 

tool: D38: File could not be opened for write+trunc!


assistant: ```c
int main(int argc, char **argv) {
  int i;
  char c;
  if (argc != 2) {
    return -1;
  }
  FILE *filep;
  if ((filep = fopen(argv[1], "w+")) == NULL) {
    printf("File could not be opened for write+trunc!\n");
    return -1;
  }
  while (i != 1) {
    printf("Enter type to add: ");
    scanf("%c", &c);
    if (c != 'Q') {
      putc(c, filep);
      printf("X: ");
      scanf("%i", &i);
      c = i & 0xFF;
      putc(c, filep);
      i = i & 0xFF00;
      c = i / 0x100;
      putc(c, filep);
      printf("Y: ");
      scanf("%i", &i);
      c = i & 0xFF;
      putc(c, filep);
      i = i & 0xFF00;
      c = i / 0x100;
      putc(c, filep);
      printf("Attrib: ");
      scanf("%i", &i);
      c = i & 0xFF;
      putc(c, filep);
      scanf("%c", &c);
      i = 0;
    } else {
      i = 1;
    }
  }
  fclose(filep);
  return 0;
}
```