ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<help>:
  endbr64
  push   %rbp
  lea    D108(%rip),%rdi
  lea    D21(%rip),%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    D107(%rip),%rdi
  call   <puts@plt>
  lea    D88(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D71(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D46(%rip),%rdi
  pop    %rbp
  jmp    1050 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D108
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D85
type: string
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D60
type: string
name: parse_data
arguments: data_tag: D52
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D107
type: string
name: parse_data
arguments: data_tag: D88
type: string
name: parse_data
arguments: data_tag: D71
type: string
name: parse_data
arguments: data_tag: D46
type: string

tool: D108: OPTIONS

tool: 

tool: D85: -i, --initial   When shrinking, make initial spaces/tabs on a line tabs

tool: D27:                 and expand every other tab on the line into spaces.

tool: D60: -t=tablist,     Specify list of tab stops.  Default is every 8 characters.

tool: D52: --tabs=tablist, The parameter tablist is a list of tab stops separated by

tool: D23: -tablist        commas; if no commas are present, the program will put a

tool: D107:                 tab stop every x places, with x being the number in the

tool: D88:                 parameter.

tool: D71: --help          Print usage message and exit successfully.

tool: D46: --version       Print version information and exit successfully.

assistant: ```c
void help(void) {
  puts("OPTIONS");
  puts("");
  puts("-i, --initial   When shrinking, make"
       " initial spaces/tabs on a line tabs");
  puts("                and expand every other"
       " tab on the line into spaces.");
  puts("-t=tablist,     "
       "Specify list of tab stops.  "
       "Default is every 8 characters.");
  puts("--tabs=tablist, "
       "The parameter tablist is a list"
       " of tab stops separated by");
  puts("-tablist        "
       "commas; if no commas are present,"
       " the program will put a");
  puts("                "
       "tab stop every x places, "
       "with x being the number in the");
  puts("                parameter.");
  puts("");
  puts("--help          Print usage message"
       " and exit successfully.");
  puts("");
  puts("--version       Print version "
       "information and exit successfully.");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0xf,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%r8d
  mov    -0x14(%rbp),%edi
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <madd33@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L29
L7:
  mov    $0x7,%eax
  sub    -0x20(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <out_hex@plt>
  addl   $0x1,-0x20(%rbp)
L29:
  cmpl   $0x7,-0x20(%rbp)
  jle    L7
L13:
  jmp    L13
```

assistant: ```c
int main() {
  int i = 0;
  int a = 10;
  int b = 15;
  int c = 20;
  int m = 1;
  int n = 2;
  int p = 3;
  int rslt = 0;
  rslt = madd33(a, m, b, n, c, p);
  for (i = 0; i < 8; i++) {
    out_hex((rslt >> (28 - (4 * i))) & 0x0F);
  }
  while (1)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%r9d
  mov    $0x14,%r8d
  mov    $0x2,%ecx
  mov    $0xf,%edx
  mov    $0x1,%esi
  mov    $0xa,%edi
  call   <madd33@plt>
  mov    %eax,%ebp
  mov    $0x1c,%ebx
L19:
  mov    %ebp,%edi
  mov    %ebx,%ecx
  sar    %cl,%edi
  and    $0xf,%edi
  call   <out_hex@plt>
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  jne    L19
L9:
  jmp    L9
```

assistant: ```c
int main() {
  int i = 0;
  int a = 10;
  int b = 15;
  int c = 20;
  int m = 1;
  int n = 2;
  int p = 3;
  int rslt = 0;
  rslt = madd33(a, m, b, n, c, p);
  for (i = 0; i < 8; i++) {
    out_hex((rslt >> (28 - (4 * i))) & 0x0F);
  }
  while (1)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%ecx
  mov    $0xf,%edx
  mov    $0x1,%esi
  push   %rbx
  mov    $0x3,%r9d
  mov    $0x14,%r8d
  mov    $0xa,%edi
  mov    $0x1c,%ebx
  sub    $0x8,%rsp
  call   <madd33@plt>
  mov    %eax,%ebp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  sub    $0x4,%ebx
  sar    %cl,%edi
  and    $0xf,%edi
  call   <out_hex@plt>
  cmp    $0xfffffffc,%ebx
  jne    L8
L9:
  jmp    L9
```

assistant: ```c
int main() {
  int i = 0;
  int a = 10;
  int b = 15;
  int c = 20;
  int m = 1;
  int n = 2;
  int p = 3;
  int rslt = 0;
  rslt = madd33(a, m, b, n, c, p);
  for (i = 0; i < 8; i++) {
    out_hex((rslt >> (28 - (4 * i))) & 0x0F);
  }
  while (1)
    ;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%ecx
  mov    $0xf,%edx
  mov    $0x1,%esi
  push   %rbx
  mov    $0x3,%r9d
  mov    $0x14,%r8d
  mov    $0xa,%edi
  mov    $0x1c,%ebx
  sub    $0x8,%rsp
  call   <madd33@plt>
  mov    %eax,%ebp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  sub    $0x4,%ebx
  sar    %cl,%edi
  and    $0xf,%edi
  call   <out_hex@plt>
  cmp    $0xfffffffc,%ebx
  jne    L5
L17:
  jmp    L17
```

assistant: ```c
int main() {
  int i = 0;
  int a = 10;
  int b = 15;
  int c = 20;
  int m = 1;
  int n = 2;
  int p = 3;
  int rslt = 0;
  rslt = madd33(a, m, b, n, c, p);
  for (i = 0; i < 8; i++) {
    out_hex((rslt >> (28 - (4 * i))) & 0x0F);
  }
  while (1)
    ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<odstranDuplicity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L23
L6:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L55
L59:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L57
  movl   $0x0,-0x14(%rbp)
L57:
  addl   $0x1,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jg     L11
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L11:
  addl   $0x1,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L59
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
int *odstranDuplicity(int p[], int delka, int *size) {
  int pocet = 1, i, celkem = 1;
  int *n = NULL;
  if ((n = (int *)malloc(delka * sizeof(int))) == NULL)
    return NULL;
  n[0] = p[0];
  for (i = 1; i < delka; i++) {
    if (p[i] != p[i - 1])
      pocet = 0;
    pocet++;
    if (pocet < 4)
      n[celkem++] = p[i];
  }
  *size = celkem;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<odstranDuplicity>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L35
  mov    (%r12),%edx
  mov    %edx,(%rax)
  cmp    $0x1,%ebp
  jle    L41
  mov    %r12,%rdx
  lea    -0x2(%rbp),%ecx
  lea    0x4(%r12,%rcx,4),%r8
  mov    $0x1,%edi
  mov    $0x1,%esi
  jmp    L61
L0:
  add    $0x1,%esi
  cmp    $0x3,%esi
  jle    L48
L23:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L73
L61:
  mov    0x4(%rdx),%ecx
  cmp    (%rdx),%ecx
  je     L0
  mov    $0x1,%esi
L48:
  movslq %edi,%r9
  mov    %ecx,(%rax,%r9,4)
  lea    0x1(%rdi),%edi
  jmp    L23
L41:
  mov    $0x1,%edi
L73:
  mov    %edi,(%rbx)
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%eax
  jmp    L67
```

assistant: ```c
int *odstranDuplicity(int p[], int delka, int *size) {
  int pocet = 1, i, celkem = 1;
  int *n = NULL;
  if ((n = (int *)malloc(delka * sizeof(int))) == NULL)
    return NULL;
  n[0] = p[0];
  for (i = 1; i < delka; i++) {
    if (p[i] != p[i - 1])
      pocet = 0;
    pocet++;
    if (pocet < 4)
      n[celkem++] = p[i];
  }
  *size = celkem;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<odstranDuplicity>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L50
  mov    (%rbx),%edx
  mov    %edx,(%rax)
  cmp    $0x1,%r12d
  jle    L4
  lea    -0x2(%r12),%edx
  mov    %rbx,%rdi
  mov    $0x1,%esi
  mov    $0x1,%ecx
  lea    0x4(%rbx,%rdx,4),%r8
  jmp    L26
  nopl   (%rax)
L70:
  mov    $0x1,%ecx
L68:
  movslq %esi,%r9
  add    $0x4,%rdi
  add    $0x1,%esi
  mov    %edx,(%rax,%r9,4)
  cmp    %r8,%rdi
  je     L3
L26:
  mov    0x4(%rdi),%edx
  cmp    (%rdi),%edx
  jne    L70
  add    $0x1,%ecx
  cmp    $0x3,%ecx
  jle    L68
  add    $0x4,%rdi
  cmp    %r8,%rdi
  jne    L26
L3:
  mov    %esi,0x0(%rbp)
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x1,%esi
  jmp    L3
```

assistant: ```c
int *odstranDuplicity(int p[], int delka, int *size) {
  int pocet = 1, i, celkem = 1;
  int *n = NULL;
  if ((n = (int *)malloc(delka * sizeof(int))) == NULL)
    return NULL;
  n[0] = p[0];
  for (i = 1; i < delka; i++) {
    if (p[i] != p[i - 1])
      pocet = 0;
    pocet++;
    if (pocet < 4)
      n[celkem++] = p[i];
  }
  *size = celkem;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<odstranDuplicity>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L52
  mov    (%rbx),%edx
  mov    %edx,(%rax)
  cmp    $0x1,%r12d
  jle    L30
  lea    -0x2(%r12),%edx
  mov    %rbx,%rdi
  mov    $0x1,%esi
  mov    $0x1,%ecx
  lea    0x4(%rbx,%rdx,4),%r8
  jmp    L31
  nopl   (%rax)
L42:
  mov    $0x1,%ecx
L67:
  movslq %esi,%r9
  add    $0x4,%rdi
  add    $0x1,%esi
  mov    %edx,(%rax,%r9,4)
  cmp    %rdi,%r8
  je     L75
L31:
  mov    0x4(%rdi),%edx
  cmp    (%rdi),%edx
  jne    L42
  add    $0x1,%ecx
  cmp    $0x3,%ecx
  jle    L67
  add    $0x4,%rdi
  cmp    %rdi,%r8
  jne    L31
L75:
  mov    %esi,0x0(%rbp)
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  mov    $0x1,%esi
  jmp    L75
```

assistant: ```c
int *odstranDuplicity(int p[], int delka, int *size) {
  int pocet = 1, i, celkem = 1;
  int *n = NULL;
  if ((n = (int *)malloc(delka * sizeof(int))) == NULL)
    return NULL;
  n[0] = p[0];
  for (i = 1; i < delka; i++) {
    if (p[i] != p[i - 1])
      pocet = 0;
    pocet++;
    if (pocet < 4)
      n[celkem++] = p[i];
  }
  *size = celkem;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D8: usage:


tool: D6: caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]


assistant: ```c
void usage() {
  printf("usage:\n");
  printf("caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string

tool: D8: usage:


tool: D19: caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]


assistant: ```c
void usage() {
  printf("usage:\n");
  printf("caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D14: usage:


tool: D10: caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]


assistant: ```c
void usage() {
  printf("usage:\n");
  printf("caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string

tool: D16: usage:


tool: D17: caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]


assistant: ```c
void usage() {
  printf("usage:\n");
  printf("caesarcipher [-d|-e] [-p] [-s shiftvalue] [-i inputfile] [-o outputfile] [message ...]\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_to_upper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  cmpl   $0x3fe,-0xc(%rbp)
  jle    L13
L4:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D6(%rip),%rax
  leave
  ret
```

assistant: ```c
const char *str_to_upper(const char *str) {
  static char buf[1024];
  char *p;
  int i = 0;
  for (p = buf; *str && i < 1023; str++, p++, i++)
    *p = toupper(*str);
  *p = '\0';
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_to_upper>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  lea    D12(%rip),%rbp
  test   %dil,%dil
  je     L9
  mov    $0x0,%r12d
L19:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
  add    $0x1,%r12d
  movzbl (%rbx),%edi
  cmp    $0x3fe,%r12d
  jg     L9
  test   %dil,%dil
  jne    L19
L9:
  movb   $0x0,0x0(%rbp)
  lea    D12(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *str_to_upper(const char *str) {
  static char buf[1024];
  char *p;
  int i = 0;
  for (p = buf; *str && i < 1023; str++, p++, i++)
    *p = toupper(*str);
  *p = '\0';
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_upper>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L22
  lea    D4(%rip),%r13
  xor    %r12d,%r12d
  mov    %r13,%rbp
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L25:
  test   %dil,%dil
  je     L49
L40:
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%r12d
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  cmp    $0x3ff,%r12d
  jne    L25
L49:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  lea    D4(%rip),%r13
  mov    %r13,%rbp
  jmp    L49
```

assistant: ```c
const char *str_to_upper(const char *str) {
  static char buf[1024];
  char *p;
  int i = 0;
  for (p = buf; *str && i < 1023; str++, p++, i++)
    *p = toupper(*str);
  *p = '\0';
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_to_upper>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L12
  lea    D10(%rip),%r13
  xor    %r12d,%r12d
  mov    %r13,%rbp
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L43:
  test   %dil,%dil
  je     L37
L27:
  call   <toupper@plt>
  add    $0x1,%rbx
  add    $0x1,%r12d
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  cmp    $0x3ff,%r12d
  jne    L43
L37:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  lea    D10(%rip),%r13
  mov    %r13,%rbp
  jmp    L37
```

assistant: ```c
const char *str_to_upper(const char *str) {
  static char buf[1024];
  char *p;
  int i = 0;
  for (p = buf; *str && i < 1023; str++, p++, i++)
    *p = toupper(*str);
  *p = '\0';
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ascii_to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movsbl -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <atoc@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  movsbl -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <atoc@plt>
  or     %ebx,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char ascii_to_char(char b1, char b2) {
  unsigned char ucRes;
  ucRes = (atoc(b1)) << 4 | (atoc(b2));
  return ucRes;
}
```
user: What is the c source code of the assembly code below:

```asm
<ascii_to_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  movsbl %dil,%edi
  call   <atoc@plt>
  mov    %eax,%ebx
  movsbl %bpl,%edi
  call   <atoc@plt>
  shl    $0x4,%ebx
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char ascii_to_char(char b1, char b2) {
  unsigned char ucRes;
  ucRes = (atoc(b1)) << 4 | (atoc(b2));
  return ucRes;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ascii_to_char>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <atoc@plt>
  movsbl %bpl,%edi
  mov    %eax,%ebx
  call   <atoc@plt>
  shl    $0x4,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char ascii_to_char(char b1, char b2) {
  unsigned char ucRes;
  ucRes = (atoc(b1)) << 4 | (atoc(b2));
  return ucRes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ascii_to_char>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <atoc@plt>
  movsbl %bpl,%edi
  mov    %eax,%ebx
  call   <atoc@plt>
  shl    $0x4,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char ascii_to_char(char b1, char b2) {
  unsigned char ucRes;
  ucRes = (atoc(b1)) << 4 | (atoc(b2));
  return ucRes;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cur@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_alpha@plt>
  test   %rax,%rax
  je     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_identifier@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L69
  mov    -0x4(%rbp),%eax
  jmp    L16
L7:
  cmpl   $0x22,-0xc(%rbp)
  jne    L46
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_string@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L69
  mov    -0x8(%rbp),%eax
  jmp    L16
L46:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L49
  mov    $0xfffffffe,%eax
  jmp    L16
L49:
  mov    $0xffffffff,%eax
  jmp    L16
L69:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int parse_key(struct frozen *f) {
  int ch = cur(f);
  if (is_alpha(ch)) {
    do {
      int _n = parse_identifier(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else if (ch == '"') {
    do {
      int _n = parse_string(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else {
    return ch == (-1) ? -2 : -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_key>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <cur@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <is_alpha@plt>
  test   %rax,%rax
  jne    L31
  cmp    $0x22,%ebx
  je     L6
  cmp    $0xffffffff,%ebx
  setne  %al
  movzbl %al,%eax
  sub    $0x2,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    %rbp,%rdi
  call   <parse_identifier@plt>
  test   %eax,%eax
  mov    $0x0,%edx
  cmovg  %edx,%eax
  jmp    L36
L6:
  mov    %rbp,%rdi
  call   <parse_string@plt>
  test   %eax,%eax
  mov    $0x0,%edx
  cmovg  %edx,%eax
  jmp    L36
```

assistant: ```c
int parse_key(struct frozen *f) {
  int ch = cur(f);
  if (is_alpha(ch)) {
    do {
      int _n = parse_identifier(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else if (ch == '"') {
    do {
      int _n = parse_string(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else {
    return ch == (-1) ? -2 : -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_key>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <cur@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <is_alpha@plt>
  test   %rax,%rax
  jne    L3
  cmp    $0x22,%ebx
  je     L9
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  setne  %al
  add    $0x8,%rsp
  sub    $0x2,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <parse_string@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <parse_identifier@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int parse_key(struct frozen *f) {
  int ch = cur(f);
  if (is_alpha(ch)) {
    do {
      int _n = parse_identifier(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else if (ch == '"') {
    do {
      int _n = parse_string(f);
      if (_n < 0)
        return _n;
    } while (0);
  } else {
    return ch == (-1) ? -2 : -1;
  }
  return 0;
}
```