ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_mem>:
  endbr64
  test   %rsi,%rsi
  je     L4
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L29
  mov    %rsi,%rbp
  call   <objp_to_size@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  mov    %eax,%edx
  and    $0xfffeffff,%edx
  cmp    $0xc8120000,%edx
  mov    $0xc8110000,%edx
  cmove  %edx,%eax
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <ordering_err_2@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  jmp    1080 <ordering_err_2@plt>
```

assistant: ```c
int compare_mem(void *context, const void *check, const void *baseline) {
  size_t n;
  if (!check || !baseline)
    return ordering_err_2();
  n = objp_to_size(context);
  if (n <= 0)
    return (((((((0))) != (((int)-(((int)0x37ED) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))) && ((((0))) != (((int)-(((int)0x37EE) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))))) ? ((0)) : (((((((0)))) <= ((0))) ? ((((((0)))) < ((0))) ? (((((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))) : (((0)))) : (((((int)-(((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))))))));
  return ((((((memcmp(check, baseline, n))) != (((int)-(((int)0x37ED) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))) && (((memcmp(check, baseline, n))) != (((int)-(((int)0x37EE) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))))) ? (memcmp(check, baseline, n)) : ((((((memcmp(check, baseline, n)))) <= ((0))) ? (((((memcmp(check, baseline, n)))) < ((0))) ? (((((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))) : (((0)))) : (((((int)-(((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))))))));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare_mem>:
  endbr64
  test   %rsi,%rsi
  je     L23
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L25
  mov    %rsi,%rbp
  call   <objp_to_size@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L21
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  mov    %eax,%edx
  and    $0xfffeffff,%edx
  cmp    $0xc8120000,%edx
  mov    $0xc8110000,%edx
  cmove  %edx,%eax
L21:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <ordering_err_2@plt>
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  jmp    1080 <ordering_err_2@plt>
```

assistant: ```c
int compare_mem(void *context, const void *check, const void *baseline) {
  size_t n;
  if (!check || !baseline)
    return ordering_err_2();
  n = objp_to_size(context);
  if (n <= 0)
    return (((((((0))) != (((int)-(((int)0x37ED) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))) && ((((0))) != (((int)-(((int)0x37EE) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))))) ? ((0)) : (((((((0)))) <= ((0))) ? ((((((0)))) < ((0))) ? (((((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))) : (((0)))) : (((((int)-(((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))))))));
  return ((((((memcmp(check, baseline, n))) != (((int)-(((int)0x37ED) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))) && (((memcmp(check, baseline, n))) != (((int)-(((int)0x37EE) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1)))))))))) ? (memcmp(check, baseline, n)) : ((((((memcmp(check, baseline, n)))) <= ((0))) ? (((((memcmp(check, baseline, n)))) < ((0))) ? (((((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))) : (((0)))) : (((((int)-(((int)-(((int)0x37EF) << (8 * (((!!(((!!(sizeof(int))) * ((sizeof(int)) - 1)))) * ((((!!(sizeof(int))) * ((sizeof(int)) - 1))) - 1))))))))))))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movzwl -0x3c(%rbp),%eax
  lea    -0x3a(%rbp),%rcx
  mov    %rcx,-0x48(%rbp)
  lea    -0x1(%rax),%edx
  mov    %dx,-0x3c(%rbp)
  test   %ax,%ax
  je     L86
  nopl   0x0(%rax,%rax,1)
L0:
  mov    -0x48(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <scanf@plt>
  movswq -0x3a(%rbp),%rbx
  mov    %rsp,%rsi
  mov    %rbx,%rax
  mov    %rbx,%rcx
  imul   %rbx,%rax
  lea    0xf(%rax,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L26
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L21
L26:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L99
  orq    $0x0,-0x8(%rsp,%rdx,1)
L99:
  mov    %rsp,%r13
  xor    %r15d,%r15d
  test   %cx,%cx
  jle    L89
  nopl   0x0(%rax)
L46:
  mov    %r15d,%edx
  test   %r15w,%r15w
  jne    L12
  nopl   0x0(%rax)
L18:
  movswq %r15w,%rax
  mov    %r12,%rdi
  imul   %rbx,%rax
  lea    0x0(%r13,%rax,2),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%r15w
  jns    L18
  mov    $0xffff8000,%edx
L12:
  lea    0x1(%rdx),%r15d
  cmp    %r15w,-0x3a(%rbp)
  jg     L46
L89:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzwl -0x3c(%rbp),%eax
  mov    %r14,%rsp
  lea    -0x1(%rax),%edx
  mov    %dx,-0x3c(%rbp)
  test   %ax,%ax
  jne    L0
L86:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %sd

assistant: ```c
main() {
  short int i, n, m, k, l, x, s = 0, y, z = 0;
  scanf("%sd", &n);
  while (n--) {
    scanf("%sd", &m);
    short int a[m][m];
    short int b[m];
    for (k = 0; k < m; k++) {
      for (l = 0; l <= k; k++) {
        scanf("%sd", &a[k][l]);
      }
    }
    for (k = 0; k < m; k++) {
      for (l = k; l < m; l++) {
        if (l != k && a[l][k] < a[l][k + 1])
          x = a[l][k + 1];
        else
          x = a[l][k];
        s = s + x;
      }
      if (k == 0) {
        b[z] = s;
        y = b[z];
        z++;
      }
      if (k != 0 && s > b[z - 1]) {
        b[z] = s;
        y = b[z];
        z++;
      }
      s = 0;
    }
    printf("\n");
    printf("%sd", y);
    z = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movzwl -0x3c(%rbp),%eax
  lea    -0x3a(%rbp),%rcx
  mov    %rcx,-0x48(%rbp)
  lea    -0x1(%rax),%edx
  mov    %dx,-0x3c(%rbp)
  test   %ax,%ax
  je     L6
  nopl   0x0(%rax,%rax,1)
L73:
  mov    -0x48(%rbp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <scanf@plt>
  movswq -0x3a(%rbp),%rbx
  mov    %rsp,%rsi
  mov    %rbx,%rdx
  mov    %rbx,%rax
  imul   %rbx,%rdx
  lea    0xf(%rdx,%rdx,1),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L88
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L96
L88:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L1
  orq    $0x0,-0x8(%rsp,%rcx,1)
L1:
  mov    %rsp,%r13
  xor    %r15d,%r15d
  test   %ax,%ax
  jle    L23
  nopw   0x0(%rax,%rax,1)
L84:
  mov    %r15d,%edx
  test   %r15w,%r15w
  jne    L57
  nopl   0x0(%rax)
L56:
  movswq %r15w,%rax
  mov    %r12,%rdi
  imul   %rbx,%rax
  lea    0x0(%r13,%rax,2),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x1,%r15w
  jns    L56
  movzwl -0x3a(%rbp),%eax
  mov    $0xffff8000,%edx
L57:
  lea    0x1(%rdx),%r15d
  cmp    %ax,%r15w
  jl     L84
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzwl -0x3c(%rbp),%eax
  mov    %r14,%rsp
  lea    -0x1(%rax),%edx
  mov    %dx,-0x3c(%rbp)
  test   %ax,%ax
  jne    L73
L6:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: %sd

assistant: ```c
main() {
  short int i, n, m, k, l, x, s = 0, y, z = 0;
  scanf("%sd", &n);
  while (n--) {
    scanf("%sd", &m);
    short int a[m][m];
    short int b[m];
    for (k = 0; k < m; k++) {
      for (l = 0; l <= k; k++) {
        scanf("%sd", &a[k][l]);
      }
    }
    for (k = 0; k < m; k++) {
      for (l = k; l < m; l++) {
        if (l != k && a[l][k] < a[l][k + 1])
          x = a[l][k + 1];
        else
          x = a[l][k];
        s = s + x;
      }
      if (k == 0) {
        b[z] = s;
        y = b[z];
        z++;
      }
      if (k != 0 && s > b[z - 1]) {
        b[z] = s;
        y = b[z];
        z++;
      }
      s = 0;
    }
    printf("\n");
    printf("%sd", y);
    z = 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: %s


assistant: ```c
int main(int argc, char **argv) {
  int c;
  for (c = 0; c < argc; c++) {
    printf("%s\n", argv[c]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  lea    D4(%rip),%rbp
L4:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: %s


assistant: ```c
int main(int argc, char **argv) {
  int c;
  for (c = 0; c < argc; c++) {
    printf("%s\n", argv[c]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L9
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L16:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s


assistant: ```c
int main(int argc, char **argv) {
  int c;
  for (c = 0; c < argc; c++) {
    printf("%s\n", argv[c]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L7
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L14:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: %s


assistant: ```c
int main(int argc, char **argv) {
  int c;
  for (c = 0; c < argc; c++) {
    printf("%s\n", argv[c]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sprint_FAIL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: %s:FAIL####

assistant: ```c
char *sprint_FAIL(char *s, const char *text) {
  sprintf(s, "%s:FAIL####", text);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sprint_FAIL>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string

tool: D2: %s:FAIL####

assistant: ```c
char *sprint_FAIL(char *s, const char *text) {
  sprintf(s, "%s:FAIL####", text);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sprint_FAIL>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rdi,%r12
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: %s:FAIL####

assistant: ```c
char *sprint_FAIL(char *s, const char *text) {
  sprintf(s, "%s:FAIL####", text);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sprint_FAIL>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rdi,%r12
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: %s:FAIL####

assistant: ```c
char *sprint_FAIL(char *s, const char *text) {
  sprintf(s, "%s:FAIL####", text);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <showHelp@plt>
  jmp    L2
L7:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <highest@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  int num, result;
  if (argc != 2) {
    showHelp(argv[0]);
  } else {
    num = atoi(argv[1]);
    result = highest(num);
    printf("%d\n", result);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L2
  mov    (%rsi),%rdi
  call   <showHelp@plt>
L3:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L2:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <highest@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  int num, result;
  if (argc != 2) {
    showHelp(argv[0]);
  } else {
    num = atoi(argv[1]);
    result = highest(num);
    printf("%d\n", result);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L11
  mov    (%rsi),%rdi
  call   <showHelp@plt>
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <highest@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %d


assistant: ```c
int main(int argc, char **argv) {
  int num, result;
  if (argc != 2) {
    showHelp(argv[0]);
  } else {
    num = atoi(argv[1]);
    result = highest(num);
    printf("%d\n", result);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L7
  mov    (%rsi),%rdi
  call   <showHelp@plt>
L11:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <highest@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main(int argc, char **argv) {
  int num, result;
  if (argc != 2) {
    showHelp(argv[0]);
  } else {
    num = atoi(argv[1]);
    result = highest(num);
    printf("%d\n", result);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rf_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L47
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L2
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L2
  cmpl   $0xffffffff,-0x10(%rbp)
  jne    L2
L47:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
L2:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int rf_mod(int *z, int x, int y) {
  if (!y || (-INT_MAX != INT_MIN && x == INT_MIN && y == -1))
    return ERANGE;
  *z = x % y;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rf_mod>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  je     L10
  mov    D12(%rip),%rdx
  mov    (%rdx),%edx
  mov    D14(%rip),%rsi
  mov    %edx,%r8d
  add    (%rsi),%r8d
  setne  %sil
  cmp    %eax,%edx
  sete   %dl
  test   %dl,%sil
  je     L11
  cmp    $0xffffffff,%ecx
  je     L10
L11:
  cltd
  idiv   %ecx
  mov    %edx,(%rdi)
  mov    $0x0,%eax
  ret
L10:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int rf_mod(int *z, int x, int y) {
  if (!y || (-INT_MAX != INT_MIN && x == INT_MIN && y == -1))
    return ERANGE;
  *z = x % y;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rf_mod>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  je     L19
  mov    D14(%rip),%rdx
  mov    D0(%rip),%rsi
  mov    (%rdx),%edx
  mov    %edx,%r8d
  add    (%rsi),%r8d
  setne  %sil
  cmp    %eax,%edx
  sete   %dl
  test   %dl,%sil
  je     L27
  cmp    $0xffffffff,%ecx
  je     L19
L27:
  cltd
  idiv   %ecx
  xor    %eax,%eax
  mov    %edx,(%rdi)
  ret
  nopl   (%rax)
L19:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int rf_mod(int *z, int x, int y) {
  if (!y || (-INT_MAX != INT_MIN && x == INT_MIN && y == -1))
    return ERANGE;
  *z = x % y;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rf_mod>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%ecx
  test   %edx,%edx
  je     L27
  mov    D17(%rip),%rdx
  mov    D9(%rip),%rsi
  mov    (%rdx),%edx
  mov    %edx,%r8d
  add    (%rsi),%r8d
  setne  %sil
  cmp    %eax,%edx
  sete   %dl
  test   %dl,%sil
  je     L28
  cmp    $0xffffffff,%ecx
  je     L27
L28:
  cltd
  idiv   %ecx
  xor    %eax,%eax
  mov    %edx,(%rdi)
  ret
  nopl   (%rax)
L27:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int rf_mod(int *z, int x, int y) {
  if (!y || (-INT_MAX != INT_MIN && x == INT_MIN && y == -1))
    return ERANGE;
  *z = x % y;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <original_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ret = original_malloc(size);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <original_malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ret = original_malloc(size);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmalloc>:
  endbr64
  jmp    1050 <original_malloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ret = original_malloc(size);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xmalloc>:
  endbr64
  jmp    1050 <original_malloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  void *ret = original_malloc(size);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x14(%rbp)
  jg     L29
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L22
L29:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <my_sqrt@plt>
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string

tool: D13: test_mysqrt <num>


tool: D19: %f

assistant: ```c
int main(int argc, char *argv[]) {
  float x;
  if (argc < (1 + 1)) {
    printf("test_mysqrt <num>\n");
    return 0;
  }
  sscanf(argv[1], "%f", &x);
  my_sqrt(x);
  return 0;
}
```