ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<make_dir_needed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x114(%rbp)
  mov    -0x114(%rbp),%edx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movl   $0x0,-0x118(%rbp)
  jmp    L19
L28:
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jne    L0
  lea    -0x11c(%rbp),%rdx
  mov    -0x128(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    -0x11c(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L0
  mov    -0x118(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  lea    -0x110(%rbp),%rax
  mov    $0x1ed,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x114(%rbp),%edx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
L0:
  addl   $0x1,-0x118(%rbp)
L19:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jl     L28
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
void make_dir_needed(const char *szFileSpec) {
  char strDir[256] = {0};
  int len = strlen(szFileSpec);
  strncpy(strDir, szFileSpec, len);
  for (int nIndex = 0; nIndex < len; nIndex++) {
    if ('/' == strDir[nIndex]) {
      struct stat info;
      stat(szFileSpec, &info);
      if (!S_ISDIR(info.st_mode)) {
        strDir[nIndex] = 0;
        mkdir(strDir, 0755);
        memset(strDir, 0x00, 256);
        strncpy(strDir, szFileSpec, len);
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_dir_needed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  movq   $0x0,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x10(%rsp),%rdi
  mov    %eax,%edx
  mov    %r13,%rsi
  call   <strncpy@plt>
  test   %r14d,%r14d
  jle    L21
  lea    0x10(%rsp),%rbx
  lea    -0x1(%r14),%eax
  lea    0x11(%rsp,%rax,1),%rbp
  lea    0xc(%rsp),%r15
  jmp    L0
L7:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L21
L0:
  cmpb   $0x2f,(%rbx)
  jne    L7
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <stat@plt>
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L7
  movb   $0x0,(%rbx)
  lea    0x10(%rsp),%r12
  mov    $0x1ed,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  jmp    L7
L21:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void make_dir_needed(const char *szFileSpec) {
  char strDir[256] = {0};
  int len = strlen(szFileSpec);
  strncpy(strDir, szFileSpec, len);
  for (int nIndex = 0; nIndex < len; nIndex++) {
    if ('/' == strDir[nIndex]) {
      struct stat info;
      stat(szFileSpec, &info);
      if (!S_ISDIR(info.st_mode)) {
        strDir[nIndex] = 0;
        mkdir(strDir, 0755);
        memset(strDir, 0x00, 256);
        strncpy(strDir, szFileSpec, len);
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_dir_needed>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %eax,%r13d
  mov    %eax,%edx
  call   <strncpy@plt>
  test   %r13d,%r13d
  jle    L51
  lea    -0x1(%r13),%eax
  mov    %r14,%rbx
  lea    0xc(%rsp),%r15
  lea    0x11(%rsp,%rax,1),%rbp
  jmp    L64
  nopl   0x0(%rax)
L29:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L51
L64:
  cmpb   $0x2f,(%rbx)
  jne    L29
  mov    %r12,%rdi
  mov    %r15,%rsi
  call   <stat@plt>
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L29
  movb   $0x0,(%rbx)
  mov    $0x1ed,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  mov    $0x100,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  cmp    %rbp,%rbx
  jne    L64
  nopl   0x0(%rax)
L51:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void make_dir_needed(const char *szFileSpec) {
  char strDir[256] = {0};
  int len = strlen(szFileSpec);
  strncpy(strDir, szFileSpec, len);
  for (int nIndex = 0; nIndex < len; nIndex++) {
    if ('/' == strDir[nIndex]) {
      struct stat info;
      stat(szFileSpec, &info);
      if (!S_ISDIR(info.st_mode)) {
        strDir[nIndex] = 0;
        mkdir(strDir, 0755);
        memset(strDir, 0x00, 256);
        strncpy(strDir, szFileSpec, len);
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_dir_needed>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %eax,%r13d
  mov    %eax,%edx
  call   <strncpy@plt>
  test   %r13d,%r13d
  jle    L54
  lea    -0x1(%r13),%eax
  mov    %r14,%rbx
  lea    0xc(%rsp),%r15
  lea    0x11(%rsp,%rax,1),%rbp
  jmp    L22
  nopl   0x0(%rax)
L44:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L54
L22:
  cmpb   $0x2f,(%rbx)
  jne    L44
  mov    %r12,%rdi
  mov    %r15,%rsi
  call   <stat@plt>
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L44
  movb   $0x0,(%rbx)
  mov    $0x1ed,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <mkdir@plt>
  mov    $0x100,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  cmp    %rbp,%rbx
  jne    L22
  nopl   0x0(%rax)
L54:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void make_dir_needed(const char *szFileSpec) {
  char strDir[256] = {0};
  int len = strlen(szFileSpec);
  strncpy(strDir, szFileSpec, len);
  for (int nIndex = 0; nIndex < len; nIndex++) {
    if ('/' == strDir[nIndex]) {
      struct stat info;
      stat(szFileSpec, &info);
      if (!S_ISDIR(info.st_mode)) {
        strDir[nIndex] = 0;
        mkdir(strDir, 0755);
        memset(strDir, 0x00, 256);
        strncpy(strDir, szFileSpec, len);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L17
L21:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getCount@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string

tool: D21: %d

tool: D17: %d %d

tool: D27: %d


assistant: ```c
int main(void) {
  int nTests;
  scanf("%d", &nTests);
  while (nTests--) {
    int n, m;
    scanf("%d %d", &n, &m);
    printf("%d\n", getCount(n, m));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L7
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D23(%rip),%rbp
  lea    D7(%rip),%rbx
L10:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <getCount@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L10
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D19: %d

tool: D23: %d %d

tool: D7: %d


assistant: ```c
int main(void) {
  int nTests;
  scanf("%d", &nTests);
  while (nTests--) {
    int n, m;
    scanf("%d %d", &n, &m);
    printf("%d\n", getCount(n, m));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L24
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D15(%rip),%rbp
  lea    D20(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <getCount@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L14
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string

tool: D1: %d

tool: D15: %d %d

tool: D20: %d


assistant: ```c
int main(void) {
  int nTests;
  scanf("%d", &nTests);
  while (nTests--) {
    int n, m;
    scanf("%d %d", &n, &m);
    printf("%d\n", getCount(n, m));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L17
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D16(%rip),%rbp
  lea    D25(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <getCount@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L0
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D8: %d

tool: D16: %d %d

tool: D25: %d


assistant: ```c
int main(void) {
  int nTests;
  scanf("%d", &nTests);
  while (nTests--) {
    int n, m;
    scanf("%d %d", &n, &m);
    printf("%d\n", getCount(n, m));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TableOp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L45
  cmpl   $0x3,-0x4(%rbp)
  jg     L44
  cmpl   $0x2,-0x4(%rbp)
  je     L32
  cmpl   $0x2,-0x4(%rbp)
  jg     L44
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  cmpl   $0x1,-0x4(%rbp)
  jmp    L44
L32:
  movl   $0x0,D18(%rip)
  jmp    L44
L45:
  mov    D18(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D31(%rip)
  mov    D31(%rip),%eax
  cmp    $0x31,%eax
  jg     L44
  mov    $0x0,%eax
  jmp    L86
L29:
  nop
L44:
  mov    $0x1,%eax
L86:
  pop    %rbp
  ret
```

assistant: ```c
int TableOp(int op) {
  static int queryCnt = 0;
  switch (op) {
  case 0:
    break;
  case 1:
    break;
  case 2:
    queryCnt = 0;
    break;
  case 3:
    queryCnt++;
    if (queryCnt < 50)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TableOp>:
  endbr64
  cmp    $0x2,%edi
  je     L7
  cmp    $0x3,%edi
  je     L12
  mov    $0x1,%eax
  ret
L7:
  movl   $0x0,D22(%rip)
  mov    $0x1,%eax
  ret
L12:
  mov    D22(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  cmp    $0x31,%eax
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int TableOp(int op) {
  static int queryCnt = 0;
  switch (op) {
  case 0:
    break;
  case 1:
    break;
  case 2:
    queryCnt = 0;
    break;
  case 3:
    queryCnt++;
    if (queryCnt < 50)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TableOp>:
  endbr64
  cmp    $0x2,%edi
  je     L3
  cmp    $0x3,%edi
  jne    L15
  mov    D13(%rip),%eax
  add    $0x1,%eax
  cmp    $0x31,%eax
  mov    %eax,D12(%rip)
  setg   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movl   $0x0,D12(%rip)
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int TableOp(int op) {
  static int queryCnt = 0;
  switch (op) {
  case 0:
    break;
  case 1:
    break;
  case 2:
    queryCnt = 0;
    break;
  case 3:
    queryCnt++;
    if (queryCnt < 50)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TableOp>:
  endbr64
  cmp    $0x2,%edi
  je     L10
  cmp    $0x3,%edi
  jne    L8
  mov    D1(%rip),%eax
  add    $0x1,%eax
  cmp    $0x31,%eax
  mov    %eax,D16(%rip)
  setg   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  movl   $0x0,D16(%rip)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int TableOp(int op) {
  static int queryCnt = 0;
  switch (op) {
  case 0:
    break;
  case 1:
    break;
  case 2:
    queryCnt = 0;
    break;
  case 3:
    queryCnt++;
    if (queryCnt < 50)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L109
L21:
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L47
L32:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x44,%al
  je     L28
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4a,%al
  je     L28
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  jne    L9
L28:
  movl   $0x1,-0x78(%rbp)
  jmp    L103
L9:
  addl   $0x1,-0x7c(%rbp)
L47:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L32
L103:
  cmpl   $0x1,-0x78(%rbp)
  jne    L3
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L109
L3:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L109:
  mov    -0x80(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x80(%rbp)
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D39
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D11: %d

tool: D39: %s

tool: D30: YES


tool: D12: NO


assistant: ```c
int main() {
  int t, i, len;
  scanf("%d", &t);
  while (t--) {
    char str[100];
    int flag = 0;
    scanf("%s", &str);
    len = strlen(str);
    for (i = 0; i < len; i++) {
      if (str[i] == 'D' || str[i] == 'J' || str[i] == 'O') {
        flag = 1;
        break;
      }
    }
    if (flag == 1)
      printf("YES\n");
    else
      printf("NO\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L5
  lea    D15(%rip),%rbp
  lea    D9(%rip),%r12
  mov    $0x841,%ebx
  jmp    L97
L92:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L32
L63:
  movzbl (%rdx),%eax
  sub    $0x44,%eax
  cmp    $0xb,%al
  ja     L92
  bt     %rax,%rbx
  jae    L92
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L5:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %r12,%rdi
  call   <printf@plt>
L23:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L5
L97:
  lea    0x10(%rsp),%r13
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L32
  mov    %r13,%rdx
  lea    -0x1(%rax),%eax
  lea    0x11(%rsp,%rax,1),%rcx
  jmp    L63
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string

tool: D1: %d

tool: D15: %s

tool: D9: NO


tool: D17: YES


assistant: ```c
int main() {
  int t, i, len;
  scanf("%d", &t);
  while (t--) {
    char str[100];
    int flag = 0;
    scanf("%s", &str);
    len = strlen(str);
    for (i = 0; i < len; i++) {
      if (str[i] == 'D' || str[i] == 'J' || str[i] == 'O') {
        flag = 1;
        break;
      }
    }
    if (flag == 1)
      printf("YES\n");
    else
      printf("NO\n");
  }
}
```