ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L33
  mov    0x10(%rsi),%r12
  mov    0x8(%rsi),%rbp
  lea    D33(%rip),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <printf@plt>
L4:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <isStringPermutationAnother@plt>
  test   %rax,%rax
  je     L23
  lea    D35(%rip),%rdi
  call   <puts@plt>
L22:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x118,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L33:
  lea    D5(%rip),%rdi
  mov    %rsp,%rbp
  lea    0x80(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  jmp    L4
L23:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L22
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D33
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D33: First string is '%s'
Second string is '%s'


tool: D35: We can get one string from the other by a permutation of symbols.

tool: D5: Input string 1:

tool: D13: Input string 2:

tool: D6: We can't get one string from the other by a permutation of symbols.

assistant: ```c
int main(int argc, char *argv[]) {
  char buf1[128];
  char buf2[128];
  char *str1;
  char *str2;
  if (argc > 2) {
    str1 = argv[1];
    str2 = argv[2];
    printf("First string is '%s'\nSecond string is '%s'\n", str1, str2);
  } else {
    str1 = buf1;
    str2 = buf2;
    puts("Input string 1:");
    gets(str1);
    puts("Input string 2:");
    gets(str2);
  }
  if (isStringPermutationAnother(str1, str2))
    puts("We can get one string from the other by a permutation of symbols.");
  else
    puts("We can't get one string from the other by a permutation of symbols.");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Conf1quita_espacios_iniciales>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L52:
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L43
L7:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L27
L43:
  nop
L27:
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L52
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
Conf1quita_espacios_iniciales(char *buf, int len) {
  int i;
  int lenp = 0;
  for (i = 0; i < len; i++) {
    if (lenp == 0 && buf[i] == ' ')
      continue;
    buf[lenp] = buf[i];
    lenp++;
  }
  for (i = lenp; i < len; i++)
    buf[i] = 0;
  return (lenp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Conf1quita_espacios_iniciales>:
  endbr64
  test   %esi,%esi
  jle    L69
  mov    %rdi,%rax
  lea    -0x1(%rsi),%r11d
  lea    0x1(%rdi),%r9
  mov    %r11d,%r10d
  add    %r9,%r10
  mov    $0x0,%edx
  jmp    L11
L60:
  movzbl (%rax),%r8d
  movslq %edx,%rcx
  mov    %r8b,(%rdi,%rcx,1)
  add    $0x1,%edx
L14:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L62
L11:
  test   %edx,%edx
  jne    L60
  cmpb   $0x20,(%rax)
  jne    L60
  jmp    L14
L62:
  cmp    %esi,%edx
  jge    L54
  movslq %edx,%rax
  add    %rax,%rdi
  add    %r9,%rax
  sub    %edx,%r11d
  add    %r11,%rax
L65:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L65
L54:
  mov    %edx,%eax
  ret
L69:
  mov    $0x0,%edx
  jmp    L54
```

assistant: ```c
Conf1quita_espacios_iniciales(char *buf, int len) {
  int i;
  int lenp = 0;
  for (i = 0; i < len; i++) {
    if (lenp == 0 && buf[i] == ' ')
      continue;
    buf[lenp] = buf[i];
    lenp++;
  }
  for (i = lenp; i < len; i++)
    buf[i] = 0;
  return (lenp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Conf1quita_espacios_iniciales>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %esi,%esi
  jle    L54
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax)
L49:
  movslq %r12d,%rdx
  add    $0x1,%eax
  add    $0x1,%r12d
  add    %rdi,%rdx
  mov    %cl,(%rdx)
  cmp    %eax,%esi
  jle    L0
L5:
  movslq %eax,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  test   %r12d,%r12d
  jne    L49
L22:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %edx,%eax
  cmp    $0x20,%cl
  je     L42
  mov    %rdi,%rdx
  add    $0x1,%eax
  mov    $0x1,%r12d
  mov    %cl,(%rdx)
  cmp    %eax,%esi
  jg     L5
L0:
  cmp    %r12d,%esi
  jle    L54
L80:
  lea    -0x1(%rsi),%edx
  mov    $0x1,%eax
  sub    %r12d,%edx
  add    $0x1,%rdx
  cmp    %esi,%r12d
  cmovge %rax,%rdx
  movslq %r12d,%rax
  xor    %esi,%esi
  add    %rax,%rdi
  call   <memset@plt>
L54:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L22
  jmp    L80
```

assistant: ```c
Conf1quita_espacios_iniciales(char *buf, int len) {
  int i;
  int lenp = 0;
  for (i = 0; i < len; i++) {
    if (lenp == 0 && buf[i] == ' ')
      continue;
    buf[lenp] = buf[i];
    lenp++;
  }
  for (i = lenp; i < len; i++)
    buf[i] = 0;
  return (lenp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Conf1quita_espacios_iniciales>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %esi,%esi
  jle    L59
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax)
L43:
  movslq %r12d,%rdx
  add    $0x1,%eax
  add    $0x1,%r12d
  add    %rdi,%rdx
  mov    %cl,(%rdx)
  cmp    %eax,%esi
  jle    L50
L0:
  movslq %eax,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  test   %r12d,%r12d
  jne    L43
L31:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %edx,%eax
  cmp    $0x20,%cl
  je     L14
  mov    %rdi,%rdx
  add    $0x1,%eax
  mov    $0x1,%r12d
  mov    %cl,(%rdx)
  cmp    %eax,%esi
  jg     L0
L50:
  cmp    %r12d,%esi
  jle    L59
L21:
  lea    -0x1(%rsi),%edx
  mov    $0x1,%eax
  sub    %r12d,%edx
  add    $0x1,%rdx
  cmp    %esi,%r12d
  cmovge %rax,%rdx
  movslq %r12d,%rax
  xor    %esi,%esi
  add    %rax,%rdi
  call   <memset@plt>
L59:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L31
  jmp    L21
```

assistant: ```c
Conf1quita_espacios_iniciales(char *buf, int len) {
  int i;
  int lenp = 0;
  for (i = 0; i < len; i++) {
    if (lenp == 0 && buf[i] == ' ')
      continue;
    buf[lenp] = buf[i];
    lenp++;
  }
  for (i = lenp; i < len; i++)
    buf[i] = 0;
  return (lenp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fastrange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L34
  negq   -0x10(%rbp)
L34:
  cmpq   $0x0,-0x8(%rbp)
  jns    L24
  negq   -0x8(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L17
  mov    -0x10(%rbp),%rax
  jmp    L31
L17:
  mov    -0x8(%rbp),%rax
L31:
  pop    %rbp
  ret
```

assistant: ```c
signed long fastrange(signed long argx, signed long argy) {
  signed long rs0, rs1;
  rs0 = argx;
  rs1 = argy;
  if (rs0 < 0) {
    rs0 = -rs0;
  }
  if (rs1 < 0) {
    rs1 = -rs1;
  }
  if (rs0 > rs1) {
    return rs0;
  } else {
    return rs1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fastrange>:
  endbr64
  mov    %rsi,%rax
  neg    %rax
  cmovs  %rsi,%rax
  mov    %rdi,%rdx
  neg    %rdx
  cmovs  %rdi,%rdx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
signed long fastrange(signed long argx, signed long argy) {
  signed long rs0, rs1;
  rs0 = argx;
  rs1 = argy;
  if (rs0 < 0) {
    rs0 = -rs0;
  }
  if (rs1 < 0) {
    rs1 = -rs1;
  }
  if (rs0 > rs1) {
    return rs0;
  } else {
    return rs1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fastrange>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rdx
  neg    %rax
  cmovs  %rsi,%rax
  neg    %rdx
  cmovs  %rdi,%rdx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
signed long fastrange(signed long argx, signed long argy) {
  signed long rs0, rs1;
  rs0 = argx;
  rs1 = argy;
  if (rs0 < 0) {
    rs0 = -rs0;
  }
  if (rs1 < 0) {
    rs1 = -rs1;
  }
  if (rs0 > rs1) {
    return rs0;
  } else {
    return rs1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fastrange>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rdx
  neg    %rax
  cmovs  %rsi,%rax
  neg    %rdx
  cmovs  %rdi,%rdx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  ret
```

assistant: ```c
signed long fastrange(signed long argx, signed long argy) {
  signed long rs0, rs1;
  rs0 = argx;
  rs1 = argy;
  if (rs0 < 0) {
    rs0 = -rs0;
  }
  if (rs1 < 0) {
    rs1 = -rs1;
  }
  if (rs0 > rs1) {
    return rs0;
  } else {
    return rs1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x807060504030201,%rax
  mov    %rax,-0x1c(%rbp)
  movw   $0xa09,-0x14(%rbp)
  mov    %rax,-0x12(%rbp)
  movw   $0xa09,-0xa(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  lea    0x3(%rax),%rcx
  lea    -0x1c(%rbp),%rax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  movzbl -0x1c(%rbp),%eax
  cmp    $0x4,%al
  je     L5
  mov    $0x1,%eax
  jmp    L91
L5:
  movzbl -0x16(%rbp),%eax
  cmp    $0xa,%al
  je     L76
  mov    $0x1,%eax
  jmp    L91
L76:
  lea    -0x12(%rbp),%rax
  lea    -0x12(%rbp),%rdx
  lea    0x3(%rdx),%rcx
  mov    $0x7,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  movzbl -0x12(%rbp),%eax
  cmp    $0x1,%al
  je     L14
  mov    $0x1,%eax
  jmp    L91
L14:
  movzbl -0xf(%rbp),%eax
  cmp    $0x1,%al
  je     L95
  mov    $0x1,%eax
  jmp    L91
L95:
  movzbl -0x9(%rbp),%eax
  cmp    $0x7,%al
  je     L6
  mov    $0x1,%eax
  jmp    L91
L6:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L91:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string

tool: D2: 	memmove

tool: D12: 	passed.


assistant: ```c
int test_memmove(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("\tmemmove");
  memmove(&value0[0], &value0[3], 7);
  if (value0[0] != 4)
    return 1;
  if (value0[6] != 10)
    return 1;
  memmove(&value1[3], &value1[0], 7);
  if (value1[0] != 1)
    return 1;
  if (value1[3] != 1)
    return 1;
  if (value1[9] != 7)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_memmove>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x807060504030201,%rax
  mov    %rax,0x4(%rsp)
  movw   $0xa09,0xc(%rsp)
  mov    %rax,0xe(%rsp)
  movw   $0xa09,0x16(%rsp)
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x7,%edx
  call   <memmove@plt>
  mov    $0x1,%eax
  cmpb   $0x4,0x4(%rsp)
  jne    L35
  cmpb   $0xa,0xa(%rsp)
  je     L65
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x28,%rsp
  ret
L65:
  lea    0xe(%rsp),%rsi
  lea    0x11(%rsp),%rdi
  mov    $0x7,%edx
  call   <memmove@plt>
  mov    $0x1,%eax
  cmpb   $0x1,0xe(%rsp)
  jne    L35
  cmpb   $0x1,0x11(%rsp)
  jne    L35
  cmpb   $0x7,0x17(%rsp)
  jne    L35
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L35
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D8: 	memmove

tool: D7: 	passed.


assistant: ```c
int test_memmove(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("\tmemmove");
  memmove(&value0[0], &value0[3], 7);
  if (value0[0] != 4)
    return 1;
  if (value0[6] != 10)
    return 1;
  memmove(&value1[3], &value1[0], 7);
  if (value1[0] != 1)
    return 1;
  if (value1[3] != 1)
    return 1;
  if (value1[9] != 7)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_memmove>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa09,%edx
  mov    $0xa09,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x807060504030201,%rax
  lea    D6(%rip),%rdi
  mov    %dx,0xc(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0xe(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x7,%edx
  call   <memmove@plt>
  cmpb   $0x4,0x4(%rsp)
  jne    L39
  cmpb   $0xa,0xa(%rsp)
  je     L18
L39:
  mov    $0x1,%eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  lea    0xe(%rsp),%rsi
  lea    0x11(%rsp),%rdi
  mov    $0x7,%edx
  call   <memmove@plt>
  cmpb   $0x1,0xe(%rsp)
  jne    L39
  cmpb   $0x1,0x11(%rsp)
  jne    L39
  cmpb   $0x7,0x17(%rsp)
  jne    L39
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L29
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D6: 	memmove

tool: D2: 	passed.


assistant: ```c
int test_memmove(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("\tmemmove");
  memmove(&value0[0], &value0[3], 7);
  if (value0[0] != 4)
    return 1;
  if (value0[6] != 10)
    return 1;
  memmove(&value1[3], &value1[0], 7);
  if (value1[0] != 1)
    return 1;
  if (value1[3] != 1)
    return 1;
  if (value1[9] != 7)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_memmove>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa09,%edx
  mov    $0xa09,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x807060504030201,%rax
  lea    D16(%rip),%rdi
  mov    %dx,0xc(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0x4(%rsp)
  mov    %rax,0xe(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  lea    0x7(%rsp),%rsi
  mov    $0x7,%edx
  call   <memmove@plt>
  cmpb   $0x4,0x4(%rsp)
  jne    L66
  cmpb   $0xa,0xa(%rsp)
  je     L41
L66:
  mov    $0x1,%eax
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  lea    0xe(%rsp),%rsi
  lea    0x11(%rsp),%rdi
  mov    $0x7,%edx
  call   <memmove@plt>
  cmpb   $0x1,0xe(%rsp)
  jne    L66
  cmpb   $0x1,0x11(%rsp)
  jne    L66
  cmpb   $0x7,0x17(%rsp)
  jne    L66
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L35
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D11
type_infered: string

tool: D16: 	memmove

tool: D11: 	passed.


assistant: ```c
int test_memmove(void) {
  char value0[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  char value1[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  printf("\tmemmove");
  memmove(&value0[0], &value0[3], 7);
  if (value0[0] != 4)
    return 1;
  if (value0[6] != 10)
    return 1;
  memmove(&value1[3], &value1[0], 7);
  if (value1[0] != 1)
    return 1;
  if (value1[3] != 1)
    return 1;
  if (value1[9] != 7)
    return 1;
  printf("\tpassed.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<con_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <con_goto@plt>
  mov    $0x0,%eax
  call   <con_clear_to_bottom@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void con_clear(void) {
  con_goto(0, 0);
  con_clear_to_bottom();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<con_clear>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <con_goto@plt>
  mov    $0x0,%eax
  call   <con_clear_to_bottom@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void con_clear(void) {
  con_goto(0, 0);
  con_clear_to_bottom();
}
```
user: What is the c source code of the assembly code below?

```asm
<con_clear>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <con_goto@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <con_clear_to_bottom@plt>
```

assistant: ```c
void con_clear(void) {
  con_goto(0, 0);
  con_clear_to_bottom();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<con_clear>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <con_goto@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <con_clear_to_bottom@plt>
```

assistant: ```c
void con_clear(void) {
  con_goto(0, 0);
  con_clear_to_bottom();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pairToLong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L8
  cmpq   $0x0,-0x30(%rbp)
  jne    L103
L8:
  mov    $0x0,%eax
  call   <abort@plt>
L103:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L126
L129:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L64
  addq   $0x1,-0x10(%rbp)
L126:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L129
  jmp    L90
L64:
  nop
L90:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L110
  movl   $0x0,-0x1c(%rbp)
L110:
  cmpl   $0x0,-0x1c(%rbp)
  je     L60
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <base24_pairToInt@plt>
  mov    %eax,-0x1c(%rbp)
L60:
  cmpl   $0x0,-0x1c(%rbp)
  je     L28
  addq   $0x2,-0x10(%rbp)
  jmp    L78
L70:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L147
  movl   $0x0,-0x1c(%rbp)
  jmp    L28
L147:
  addq   $0x1,-0x10(%rbp)
L78:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
L28:
  cmpl   $0x0,-0x1c(%rbp)
  je     L88
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L88:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
bool pairToLong(const char *str, long *pLong) {
  bool result = true;
  int32_t i = 0;
  const char *pc = NULL;
  if ((str == NULL) || (pLong == NULL)) {
    abort();
  }
  pc = str;
  while (*pc != 0) {
    if (!isspace(*pc)) {
      break;
    }
    pc++;
  }
  if (*pc == 0) {
    result = false;
  }
  if (result) {
    result = base24_pairToInt(pc, &i);
  }
  if (result) {
    pc = pc + 2;
    while (*pc != 0) {
      if (!isspace(*pc)) {
        result = false;
        break;
      }
      pc++;
    }
  }
  if (result) {
    *pLong = (long)i;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pairToLong>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L22
  test   %rsi,%rsi
  je     L22
L74:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L105
L19:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L88
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L105:
  mov    $0x0,%r13d
  jmp    L112
L22:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L74
L88:
  cmpb   $0x0,(%rbx)
  je     L105
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <base24_pairToInt@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L105
  lea    0x2(%rbx),%r12
  movzbl 0x2(%rbx),%edi
  test   %dil,%dil
  je     L48
L75:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L105
  add    $0x1,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L75
L48:
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
L112:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L118:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool pairToLong(const char *str, long *pLong) {
  bool result = true;
  int32_t i = 0;
  const char *pc = NULL;
  if ((str == NULL) || (pLong == NULL)) {
    abort();
  }
  pc = str;
  while (*pc != 0) {
    if (!isspace(*pc)) {
      break;
    }
    pc++;
  }
  if (*pc == 0) {
    result = false;
  }
  if (result) {
    result = base24_pairToInt(pc, &i);
  }
  if (result) {
    pc = pc + 2;
    while (*pc != 0) {
      if (!isspace(*pc)) {
        result = false;
        break;
      }
      pc++;
    }
  }
  if (result) {
    *pLong = (long)i;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pairToLong>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L32
  test   %rsi,%rsi
  je     L32
L82:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L20
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L100:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L34
L20:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L100
  cmpb   $0x0,(%rbx)
  je     L34
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <base24_pairToInt@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L34
  movsbl 0x2(%rbx),%edi
  lea    0x2(%rbx),%r12
  test   %dil,%dil
  jne    L33
  jmp    L51
  nopl   0x0(%rax)
L8:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L51
L33:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L8
L34:
  xor    %r13d,%r13d
L110:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L51:
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L82
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool pairToLong(const char *str, long *pLong) {
  bool result = true;
  int32_t i = 0;
  const char *pc = NULL;
  if ((str == NULL) || (pLong == NULL)) {
    abort();
  }
  pc = str;
  while (*pc != 0) {
    if (!isspace(*pc)) {
      break;
    }
    pc++;
  }
  if (*pc == 0) {
    result = false;
  }
  if (result) {
    result = base24_pairToInt(pc, &i);
  }
  if (result) {
    pc = pc + 2;
    while (*pc != 0) {
      if (!isspace(*pc)) {
        result = false;
        break;
      }
      pc++;
    }
  }
  if (result) {
    *pLong = (long)i;
  }
  return result;
}
```