ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<xilinxcorelib_a_1600189650_0543512595_p_9>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x78e8(%rdi),%rax
  mov    0x38(%rax),%rax
  movb   $0x2,(%rax)
  lea    0x78b0(%rdi),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f10(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1600189650_0543512595_p_9(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t5;
  int t6;
  unsigned char t7;
  unsigned char t8;
  unsigned char t9;
  unsigned char t10;
  char *t11;
  unsigned char t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
LAB0:
  t3 = (0 == 1);
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t9 = (0 == 1);
  if (t9 == 1)
    goto LAB11;
LAB12:
  t8 = (unsigned char)0;
LAB13:
  t1 = t8;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB14:
  t17 = (t0 + 30896);
  t18 = (t17 + 56U);
  t19 = *((char **)t18);
  t20 = (t19 + 56U);
  t21 = *((char **)t20);
  *((unsigned char *)t21) = (unsigned char)2;
  xsi_driver_first_trans_fast(t17);
LAB2:
  t22 = (t0 + 28432);
  *((int *)t22) = 1;
LAB1:
  return;
LAB3:
  t4 = (t0 + 1456U);
  t11 = *((char **)t4);
  t12 = *((unsigned char *)t11);
  t4 = (t0 + 30896);
  t13 = (t4 + 56U);
  t14 = *((char **)t13);
  t15 = (t14 + 56U);
  t16 = *((char **)t15);
  *((unsigned char *)t16) = t12;
  xsi_driver_first_trans_fast(t4);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t4 = (t0 + 19432U);
  t5 = *((char **)t4);
  t6 = *((int *)t5);
  t7 = (t6 == 0);
  t2 = t7;
  goto LAB10;
LAB11:
  t10 = (0 == 1);
  t8 = t10;
  goto LAB13;
LAB15:
  goto LAB2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xilinxcorelib_a_1600189650_0543512595_p_9>:
  endbr64
  push   %rbx
  mov    0x78e8(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x78b0(%rdi),%rdi
  mov    0x38(%rax),%rax
  movb   $0x2,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f10(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1600189650_0543512595_p_9(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t5;
  int t6;
  unsigned char t7;
  unsigned char t8;
  unsigned char t9;
  unsigned char t10;
  char *t11;
  unsigned char t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
LAB0:
  t3 = (0 == 1);
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t9 = (0 == 1);
  if (t9 == 1)
    goto LAB11;
LAB12:
  t8 = (unsigned char)0;
LAB13:
  t1 = t8;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB14:
  t17 = (t0 + 30896);
  t18 = (t17 + 56U);
  t19 = *((char **)t18);
  t20 = (t19 + 56U);
  t21 = *((char **)t20);
  *((unsigned char *)t21) = (unsigned char)2;
  xsi_driver_first_trans_fast(t17);
LAB2:
  t22 = (t0 + 28432);
  *((int *)t22) = 1;
LAB1:
  return;
LAB3:
  t4 = (t0 + 1456U);
  t11 = *((char **)t4);
  t12 = *((unsigned char *)t11);
  t4 = (t0 + 30896);
  t13 = (t4 + 56U);
  t14 = *((char **)t13);
  t15 = (t14 + 56U);
  t16 = *((char **)t15);
  *((unsigned char *)t16) = t12;
  xsi_driver_first_trans_fast(t4);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t4 = (t0 + 19432U);
  t5 = *((char **)t4);
  t6 = *((int *)t5);
  t7 = (t6 == 0);
  t2 = t7;
  goto LAB10;
LAB11:
  t10 = (0 == 1);
  t8 = t10;
  goto LAB13;
LAB15:
  goto LAB2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xilinxcorelib_a_1600189650_0543512595_p_9>:
  endbr64
  push   %rbx
  mov    0x78e8(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x78b0(%rdi),%rdi
  mov    0x38(%rax),%rax
  movb   $0x2,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f10(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_1600189650_0543512595_p_9(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t5;
  int t6;
  unsigned char t7;
  unsigned char t8;
  unsigned char t9;
  unsigned char t10;
  char *t11;
  unsigned char t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
LAB0:
  t3 = (0 == 1);
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t9 = (0 == 1);
  if (t9 == 1)
    goto LAB11;
LAB12:
  t8 = (unsigned char)0;
LAB13:
  t1 = t8;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB14:
  t17 = (t0 + 30896);
  t18 = (t17 + 56U);
  t19 = *((char **)t18);
  t20 = (t19 + 56U);
  t21 = *((char **)t20);
  *((unsigned char *)t21) = (unsigned char)2;
  xsi_driver_first_trans_fast(t17);
LAB2:
  t22 = (t0 + 28432);
  *((int *)t22) = 1;
LAB1:
  return;
LAB3:
  t4 = (t0 + 1456U);
  t11 = *((char **)t4);
  t12 = *((unsigned char *)t11);
  t4 = (t0 + 30896);
  t13 = (t4 + 56U);
  t14 = *((char **)t13);
  t15 = (t14 + 56U);
  t16 = *((char **)t15);
  *((unsigned char *)t16) = t12;
  xsi_driver_first_trans_fast(t4);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t4 = (t0 + 19432U);
  t5 = *((char **)t4);
  t6 = *((int *)t5);
  t7 = (t6 == 0);
  t2 = t7;
  goto LAB10;
LAB11:
  t10 = (0 == 1);
  t8 = t10;
  goto LAB13;
LAB15:
  goto LAB2;
}
```
user: What is the c source code of the assembly code below:

```asm
<_prt8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xf(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L32
L74:
  mov    -0x24(%rbp),%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  mov    %dl,-0xf(%rbp,%rax,1)
  mov    -0x24(%rbp),%eax
  shr    $0x3,%eax
  and    $0x3fff,%eax
  mov    %eax,-0x24(%rbp)
  addl   $0x1,-0x14(%rbp)
L32:
  cmpl   $0x6,-0x14(%rbp)
  jle    L74
  movzbl -0x9(%rbp),%eax
  and    $0x31,%eax
  mov    %al,-0x9(%rbp)
  movl   $0x6,-0x14(%rbp)
  jmp    L27
L0:
  subl   $0x1,-0x14(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xf(%rbp,%rax,1),%eax
  cmp    $0x30,%al
  je     L0
  cmpl   $0x0,-0x14(%rbp)
  jne    L55
  addl   $0x1,-0x14(%rbp)
  jmp    L55
L64:
  mov    -0x14(%rbp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rdx
  movzbl -0xf(%rbp,%rdx,1),%edx
  mov    %dl,(%rax)
L55:
  cmpl   $0x0,-0x14(%rbp)
  jns    L64
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
_prt8(num, str) unsigned int num;
char *str;
{
  int i;
  char c;
  char temp[7];
  temp[0] = '\0';
  for (i = 1; i <= 6; i++) {
    temp[i] = (num & 07) + '0';
    num = (num >> 3) & 0037777;
  }
  temp[6] &= '1';
  for (i = 6; temp[i] == '0'; i--)
    ;
  if (i == 0)
    i++;
  while (i >= 0)
    *str++ = temp[i--];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_prt8>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x1(%rsp)
  lea    0x1(%rsp),%rax
  lea    0x7(%rsp),%rcx
L6:
  mov    %edi,%edx
  and    $0x7,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  shr    $0x3,%edi
  and    $0x3fff,%edi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
  movzbl 0x7(%rsp),%eax
  and    $0x31,%eax
  mov    %al,0x7(%rsp)
  cmp    $0x30,%al
  jne    L52
  mov    $0x5,%edx
  lea    0x2(%rsp),%rcx
L56:
  mov    %edx,%eax
  sub    $0x1,%rdx
  cmpb   $0x30,(%rcx,%rdx,1)
  je     L56
  test   %eax,%eax
  jne    L2
  mov    $0x1,%eax
L78:
  cltq
L80:
  add    $0x1,%rsi
  movzbl 0x1(%rsp,%rax,1),%edx
  mov    %dl,-0x1(%rsi)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L80
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  jns    L78
  jmp    L75
L52:
  mov    $0x6,%eax
  jmp    L78
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_prt8(num, str) unsigned int num;
char *str;
{
  int i;
  char c;
  char temp[7];
  temp[0] = '\0';
  for (i = 1; i <= 6; i++) {
    temp[i] = (num & 07) + '0';
    num = (num >> 3) & 0037777;
  }
  temp[6] &= '1';
  for (i = 6; temp[i] == '0'; i--)
    ;
  if (i == 0)
    i++;
  while (i >= 0)
    *str++ = temp[i--];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_prt8>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x1(%rsp)
  lea    0x1(%rsp),%r8
  lea    0x7(%rsp),%rcx
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %edi,%edx
  add    $0x1,%rax
  shr    $0x3,%edi
  and    $0x7,%edx
  and    $0x3fff,%edi
  add    $0x30,%edx
  mov    %dl,(%rax)
  cmp    %rcx,%rax
  jne    L87
  movzbl 0x7(%rsp),%ecx
  and    $0x31,%ecx
  cmp    $0x30,%cl
  jne    L20
  mov    $0x5,%eax
  lea    0x2(%rsp),%rcx
  nopl   0x0(%rax,%rax,1)
L60:
  movslq %eax,%rdx
  sub    $0x1,%rax
  cmpb   $0x30,(%rcx,%rax,1)
  je     L60
  test   %edx,%edx
  jne    L78
  movzbl 0x2(%rsp),%ecx
  mov    $0x1,%edx
L50:
  lea    -0x1(%r8,%rdx,1),%rax
  add    %rsi,%rdx
  jmp    L47
  nopl   (%rax)
L30:
  movzbl (%rax),%ecx
  add    $0x1,%rsi
  sub    $0x1,%rax
L47:
  mov    %cl,(%rsi)
  cmp    %rdx,%rsi
  jne    L30
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L78:
  movzbl 0x1(%rsp,%rdx,1),%ecx
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x6,%edx
  jmp    L50
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_prt8(num, str) unsigned int num;
char *str;
{
  int i;
  char c;
  char temp[7];
  temp[0] = '\0';
  for (i = 1; i <= 6; i++) {
    temp[i] = (num & 07) + '0';
    num = (num >> 3) & 0037777;
  }
  temp[6] &= '1';
  for (i = 6; temp[i] == '0'; i--)
    ;
  if (i == 0)
    i++;
  while (i >= 0)
    *str++ = temp[i--];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_prt8>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%r8d
  shr    $0x3,%edi
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  and    $0x7,%r8d
  and    $0x7,%edi
  and    $0x3fff,%eax
  add    $0x30,%r8d
  add    $0x30,%edi
  movb   $0x0,0x1(%rsp)
  mov    %eax,%r9d
  mov    %eax,%esi
  mov    %eax,%ecx
  shr    $0xc,%eax
  shr    $0x3,%r9d
  shr    $0x6,%esi
  add    $0x30,%eax
  mov    %r8b,0x2(%rsp)
  shr    $0x9,%ecx
  and    $0x7,%r9d
  and    $0x7,%esi
  and    $0x31,%eax
  and    $0x7,%ecx
  add    $0x30,%r9d
  add    $0x30,%esi
  mov    %dil,0x3(%rsp)
  add    $0x30,%ecx
  mov    %r9b,0x4(%rsp)
  mov    %sil,0x5(%rsp)
  mov    %cl,0x6(%rsp)
  mov    %al,0x7(%rsp)
  cmp    $0x30,%al
  jne    L99
  cmp    $0x30,%cl
  jne    L11
  cmp    $0x30,%sil
  jne    L2
  cmp    $0x30,%r9b
  jne    L145
  cmp    $0x30,%dil
  jne    L149
  movzwl 0x1(%rsp),%eax
  rol    $0x8,%ax
  mov    %ax,(%rdx)
  nopl   0x0(%rax)
L131:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L149:
  mov    $0x2,%eax
L49:
  movslq %eax,%rcx
  lea    -0x3(%rax),%esi
  movzbl 0x1(%rsp,%rcx,1),%ecx
  mov    %cl,(%rdx)
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  movzbl 0x1(%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rdx)
  lea    -0x2(%rax),%ecx
  movslq %ecx,%rcx
  movzbl 0x1(%rsp,%rcx,1),%ecx
  mov    %cl,0x2(%rdx)
  cmp    $0x2,%eax
  je     L131
  movslq %esi,%rsi
  lea    -0x4(%rax),%ecx
  movzbl 0x1(%rsp,%rsi,1),%esi
  mov    %sil,0x3(%rdx)
  cmp    $0x3,%eax
  je     L131
  movslq %ecx,%rcx
  lea    -0x5(%rax),%esi
  movzbl 0x1(%rsp,%rcx,1),%ecx
  mov    %cl,0x4(%rdx)
  cmp    $0x4,%eax
  je     L131
  movslq %esi,%rax
  movzbl 0x1(%rsp,%rax,1),%eax
  mov    %al,0x5(%rdx)
  test   %esi,%esi
  je     L131
  movb   $0x0,0x6(%rdx)
  jmp    L131
  nopl   0x0(%rax)
L99:
  mov    $0x6,%eax
  jmp    L49
  nop
L11:
  mov    $0x5,%eax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x4,%eax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L145:
  mov    $0x3,%eax
  jmp    L49
L104:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_prt8(num, str) unsigned int num;
char *str;
{
  int i;
  char c;
  char temp[7];
  temp[0] = '\0';
  for (i = 1; i <= 6; i++) {
    temp[i] = (num & 07) + '0';
    num = (num >> 3) & 0037777;
  }
  temp[6] &= '1';
  for (i = 6; temp[i] == '0'; i--)
    ;
  if (i == 0)
    i++;
  while (i >= 0)
    *str++ = temp[i--];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <c@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: %s


assistant: ```c
int main(int argc, char **argv) {
  char *str = c();
  printf("%s\n", str);
  free(str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <c@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: %s


assistant: ```c
int main(int argc, char **argv) {
  char *str = c();
  printf("%s\n", str);
  free(str);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <c@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %s


assistant: ```c
int main(int argc, char **argv) {
  char *str = c();
  printf("%s\n", str);
  free(str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <c@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: %s


assistant: ```c
int main(int argc, char **argv) {
  char *str = c();
  printf("%s\n", str);
  free(str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<libc_stold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  movl   $0x0,-0x44(%rbp)
  fldz
  fstpt  -0x10(%rbp)
  fldz
  fstpt  -0x30(%rbp)
  fldz
  fstpt  -0x20(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x58(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L67
  fld1
  fchs
  jmp    L83
L67:
  fld1
L83:
  fstpt  -0x10(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <libc_strlen@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  jmp    L19
L57:
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L18
  addl   $0x1,-0x44(%rbp)
L18:
  fldt   -0x30(%rbp)
  fldt   0xe6b(%rip)        # 2000 <_fini+0xd90>
  fmulp  %st,%st(1)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x5c(%rbp)
  fildl  -0x5c(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x30(%rbp)
  addl   $0x1,-0x44(%rbp)
L19:
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L57
  subl   $0x1,-0x40(%rbp)
  jmp    L85
L6:
  mov    -0x58(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L47
  fldt   -0x20(%rbp)
  fldt   0xe26(%rip)        # 2010 <_fini+0xda0>
  fmulp  %st,%st(1)
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x5c(%rbp)
  fildl  -0x5c(%rbp)
  fsubrp %st,%st(1)
  fstpt  -0x20(%rbp)
  jmp    L50
L47:
  fldt   -0x20(%rbp)
  fldt   0xdf8(%rip)        # 2010 <_fini+0xda0>
  fmulp  %st,%st(1)
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x5c(%rbp)
  fildl  -0x5c(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
L50:
  subl   $0x1,-0x40(%rbp)
L85:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L6
  fldt   -0x20(%rbp)
  fldt   0xdb4(%rip)        # 2010 <_fini+0xda0>
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x10(%rbp)
  fldt   -0x30(%rbp)
  fmulp  %st,%st(1)
  fldt   -0x20(%rbp)
  faddp  %st,%st(1)
  leave
  ret
```

assistant: ```c
long double libc_stold(char *s) {
  int i = 0;
  long double sign = 0, is = 0, si = 0;
  char *sdt = s;
  sign = (s[0] == '-') ? -1.0 : 1.0;
  int len = libc_strlen(s);
  int k = len;
  while (s[i] != '.') {
    if (sdt[i] == '-') {
      i++;
    }
    is = is * 10. + (sdt[i] - '0');
    i++;
  }
  k--;
  while (s[k] != '.') {
    if (s[0] == '-') {
      si = si * .1 - (sdt[k] - '0');
    } else {
      si = si * .1 + (sdt[k] - '0');
    }
    k--;
  }
  si = si * .1;
  return sign * is + si;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libc_stold>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  cmpb   $0x2d,(%rdi)
  je     L12
  fld1
  fstpt  0x10(%rsp)
L41:
  mov    %rbx,%rdi
  call   <libc_strlen@plt>
  movzbl (%rbx),%esi
  cmp    $0x2e,%sil
  je     L37
  mov    %esi,%ecx
  fldz
  mov    $0x0,%edx
  flds   0xeb0(%rip)        # 2000 <_fini+0xdfc>
L31:
  cmp    $0x2d,%cl
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  fmul   %st,%st(1)
  movslq %edx,%rcx
  movsbl (%rbx,%rcx,1),%ecx
  sub    $0x30,%ecx
  mov    %ecx,0xc(%rsp)
  fildl  0xc(%rsp)
  faddp  %st,%st(2)
  add    $0x1,%edx
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  cmp    $0x2e,%cl
  jne    L31
  fstp   %st(0)
L51:
  sub    $0x1,%eax
  cltq
  lea    (%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0x2e,%al
  je     L40
  fldz
  fldl   0xe6e(%rip)        # 2008 <_fini+0xe04>
  jmp    L9
L12:
  fld1
  fchs
  fstpt  0x10(%rsp)
  jmp    L41
L37:
  fldz
  jmp    L51
L99:
  fxch   %st(1)
  fmull  0xe56(%rip)        # 2008 <_fini+0xe04>
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  fsubrp %st,%st(1)
  fxch   %st(1)
L52:
  sub    $0x1,%rdx
  movzbl (%rdx),%eax
  cmp    $0x2e,%al
  je     L23
L9:
  cmp    $0x2d,%sil
  je     L99
  fmul   %st,%st(1)
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  faddp  %st,%st(2)
  jmp    L52
L40:
  fldz
  jmp    L87
L23:
  fstp   %st(0)
L87:
  fldt   0x10(%rsp)
  fmulp  %st,%st(2)
  fmull  0xe0d(%rip)        # 2008 <_fini+0xe04>
  faddp  %st,%st(1)
  add    $0x20,%rsp
  pop    %rbx
  ret
```

assistant: ```c
long double libc_stold(char *s) {
  int i = 0;
  long double sign = 0, is = 0, si = 0;
  char *sdt = s;
  sign = (s[0] == '-') ? -1.0 : 1.0;
  int len = libc_strlen(s);
  int k = len;
  while (s[i] != '.') {
    if (sdt[i] == '-') {
      i++;
    }
    is = is * 10. + (sdt[i] - '0');
    i++;
  }
  k--;
  while (s[k] != '.') {
    if (s[0] == '-') {
      si = si * .1 - (sdt[k] - '0');
    } else {
      si = si * .1 + (sdt[k] - '0');
    }
    k--;
  }
  si = si * .1;
  return sign * is + si;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<libc_stold>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  cmpb   $0x2d,(%rdi)
  je     L24
  fld1
  fstpt  0x10(%rsp)
L31:
  mov    %rbx,%rdi
  call   <libc_strlen@plt>
  movzbl (%rbx),%esi
  cmp    $0x2e,%sil
  je     L70
  fldz
  mov    %esi,%ecx
  xor    %edx,%edx
  fld    %st(0)
  flds   0xea2(%rip)        # 2000 <_fini+0xde4>
  xchg   %ax,%ax
L46:
  cmp    $0x2d,%cl
  fmul   %st,%st(1)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  movslq %edx,%rcx
  add    $0x1,%edx
  movsbl (%rbx,%rcx,1),%ecx
  sub    $0x30,%ecx
  mov    %ecx,0xc(%rsp)
  fildl  0xc(%rsp)
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  faddp  %st,%st(2)
  cmp    $0x2e,%cl
  jne    L46
  fstp   %st(0)
L50:
  sub    $0x1,%eax
  cltq
  lea    (%rbx,%rax,1),%rdi
  movsbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L5
  fldl   0xe60(%rip)        # 2008 <_fini+0xdec>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L60:
  movsbl -0x1(%rdi),%eax
  sub    $0x1,%rdi
  faddp  %st,%st(3)
  cmp    $0x2e,%al
  je     L12
L13:
  sub    $0x30,%eax
  fmul   %st,%st(2)
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  cmp    $0x2d,%sil
  jne    L60
  movsbl -0x1(%rdi),%eax
  fsubrp %st,%st(3)
  sub    $0x1,%rdi
  cmp    $0x2e,%al
  jne    L13
L12:
  fmulp  %st,%st(2)
  fldt   0x10(%rsp)
  add    $0x20,%rsp
  pop    %rbx
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  ret
  nop
L24:
  fld1
  fchs
  fstpt  0x10(%rsp)
  jmp    L31
  nopl   (%rax)
L5:
  fldt   0x10(%rsp)
  add    $0x20,%rsp
  pop    %rbx
  fmulp  %st,%st(1)
  faddp  %st,%st(1)
  ret
  xchg   %ax,%ax
L70:
  fldz
  fld    %st(0)
  jmp    L50
```

assistant: ```c
long double libc_stold(char *s) {
  int i = 0;
  long double sign = 0, is = 0, si = 0;
  char *sdt = s;
  sign = (s[0] == '-') ? -1.0 : 1.0;
  int len = libc_strlen(s);
  int k = len;
  while (s[i] != '.') {
    if (sdt[i] == '-') {
      i++;
    }
    is = is * 10. + (sdt[i] - '0');
    i++;
  }
  k--;
  while (s[k] != '.') {
    if (s[0] == '-') {
      si = si * .1 - (sdt[k] - '0');
    } else {
      si = si * .1 + (sdt[k] - '0');
    }
    k--;
  }
  si = si * .1;
  return sign * is + si;
}
```