ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ball>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  movsd  %xmm3,(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <glPushMatrix@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  call   <glTranslated@plt>
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm2
  movapd %xmm3,%xmm1
  call   <glScaled@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <glColor3f@plt>
  mov    $0x10,%esi
  mov    $0x10,%edi
  movsd  D1(%rip),%xmm0
  call   <glutSolidSphere@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <glPopMatrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
void ball(double x, double y, double z, double r, int red, int green, int blue) {
  glPushMatrix();
  glTranslated(x, y, z);
  glScaled(r, r, r);
  glColor3f(red, green, blue);
  glutSolidSphere(1.0, 16, 16);
  glPopMatrix();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<has_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2e,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  mov    $0x1,%eax
  jmp    L10
L3:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int has_extension(const char *str) {
  int dot = (int)'.';
  if (strchr(str, dot))
    return (1);
  else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<has_extension>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int has_extension(const char *str) {
  int dot = (int)'.';
  if (strchr(str, dot))
    return (1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<has_extension>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int has_extension(const char *str) {
  int dot = (int)'.';
  if (strchr(str, dot))
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<has_extension>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int has_extension(const char *str) {
  int dot = (int)'.';
  if (strchr(str, dot))
    return (1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<section_by_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <read_header@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_section_table@plt>
  test   %rax,%rax
  je     L57
L22:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L65
L57:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x30(%rbp)
  jae    L33
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L51
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L65
L51:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L65
L33:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
L65:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
int section_by_index(int d, size_t const index, Elf64_Shdr **section) {
  Elf64_Ehdr *header = NULL;
  Elf64_Shdr *sections = NULL;
  *section = NULL;
  if (read_header(d, &header) || read_section_table(d, header, &sections))
    return errno;
  if (index < header->e_shnum) {
    *section = (Elf64_Shdr *)malloc(sizeof(Elf64_Shdr));
    if (NULL == *section) {
      free(header);
      free(sections);
      return errno;
    }
    memcpy(*section, sections + index, sizeof(Elf64_Shdr));
  } else
    return EINVAL;
  free(header);
  free(sections);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<section_by_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,(%rdx)
  lea    0x8(%rsp),%rsi
  call   <read_header@plt>
  test   %rax,%rax
  je     L7
L51:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L50:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edi
  call   <read_section_table@plt>
  test   %rax,%rax
  jne    L51
  mov    0x8(%rsp),%rax
  cmp    %r12,(%rax)
  ja     L46
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L50
L46:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L59
  mov    0x10(%rsp),%rax
  lea    (%rax,%r12,8),%rsi
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L50
L59:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L50
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int section_by_index(int d, size_t const index, Elf64_Shdr **section) {
  Elf64_Ehdr *header = NULL;
  Elf64_Shdr *sections = NULL;
  *section = NULL;
  if (read_header(d, &header) || read_section_table(d, header, &sections))
    return errno;
  if (index < header->e_shnum) {
    *section = (Elf64_Shdr *)malloc(sizeof(Elf64_Shdr));
    if (NULL == *section) {
      free(header);
      free(sections);
      return errno;
    }
    memcpy(*section, sections + index, sizeof(Elf64_Shdr));
  } else
    return EINVAL;
  free(header);
  free(sections);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<section_by_index>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <read_header@plt>
  test   %rax,%rax
  je     L16
L56:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
L68:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %ebp,%edi
  call   <read_section_table@plt>
  test   %rax,%rax
  jne    L56
  mov    0x8(%rsp),%rax
  cmp    %r12,(%rax)
  ja     L32
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L44
  mov    0x10(%rsp),%rax
  mov    $0x8,%edx
  lea    (%rax,%r12,8),%rsi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L44:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  jmp    L56
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int section_by_index(int d, size_t const index, Elf64_Shdr **section) {
  Elf64_Ehdr *header = NULL;
  Elf64_Shdr *sections = NULL;
  *section = NULL;
  if (read_header(d, &header) || read_section_table(d, header, &sections))
    return errno;
  if (index < header->e_shnum) {
    *section = (Elf64_Shdr *)malloc(sizeof(Elf64_Shdr));
    if (NULL == *section) {
      free(header);
      free(sections);
      return errno;
    }
    memcpy(*section, sections + index, sizeof(Elf64_Shdr));
  } else
    return EINVAL;
  free(header);
  free(sections);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<section_by_index>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <read_header@plt>
  test   %rax,%rax
  je     L36
L31:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %ebp,%edi
  call   <read_section_table@plt>
  test   %rax,%rax
  jne    L31
  mov    0x8(%rsp),%rax
  cmp    %r12,(%rax)
  ja     L78
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L78:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L53
  mov    0x10(%rsp),%rax
  mov    $0x8,%edx
  lea    (%rax,%r12,8),%rsi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L53:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  jmp    L31
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int section_by_index(int d, size_t const index, Elf64_Shdr **section) {
  Elf64_Ehdr *header = NULL;
  Elf64_Shdr *sections = NULL;
  *section = NULL;
  if (read_header(d, &header) || read_section_table(d, header, &sections))
    return errno;
  if (index < header->e_shnum) {
    *section = (Elf64_Shdr *)malloc(sizeof(Elf64_Shdr));
    if (NULL == *section) {
      free(header);
      free(sections);
      return errno;
    }
    memcpy(*section, sections + index, sizeof(Elf64_Shdr));
  } else
    return EINVAL;
  free(header);
  free(sections);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tech_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <tech_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <tech_free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *tech_realloc(void *ptr, unsigned long size) {
  void *new_ptr;
  new_ptr = tech_malloc(size);
  memcpy(new_ptr, ptr, size);
  tech_free(ptr);
  return new_ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tech_realloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <tech_malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <tech_free@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *tech_realloc(void *ptr, unsigned long size) {
  void *new_ptr;
  new_ptr = tech_malloc(size);
  memcpy(new_ptr, ptr, size);
  tech_free(ptr);
  return new_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tech_realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <tech_malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <tech_free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *tech_realloc(void *ptr, unsigned long size) {
  void *new_ptr;
  new_ptr = tech_malloc(size);
  memcpy(new_ptr, ptr, size);
  tech_free(ptr);
  return new_ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tech_realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <tech_malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <tech_free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *tech_realloc(void *ptr, unsigned long size) {
  void *new_ptr;
  new_ptr = tech_malloc(size);
  memcpy(new_ptr, ptr, size);
  tech_free(ptr);
  return new_ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xb,-0x1a8(%rbp)
  mov    -0x1a8(%rbp),%eax
  mov    %eax,-0x1ac(%rbp)
  jmp    L17
L26:
  mov    -0x1ac(%rbp),%eax
  add    $0x5,%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1a4(%rbp),%eax
  add    $0x2,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1ac(%rbp)
L17:
  cmpl   $0x31,-0x1ac(%rbp)
  jle    L26
  mov    -0x19c(%rbp),%eax
  mov    %eax,%edi
  call   <bar@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int foo(void) {
  int a;
  int parm = 11;
  int x;
  int c[100];
  for (a = parm; a < 50; a++) {
    x = a + 5;
    c[x] = c[x + 2] + c[x - 1];
  }
  bar(c[1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  lea    0x3c(%rsp),%rax
  lea    0xd8(%rsp),%rcx
L8:
  mov    (%rax),%edx
  add    0xc(%rax),%edx
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
  mov    0x4(%rsp),%edi
  call   <bar@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int a;
  int parm = 11;
  int x;
  int c[100];
  for (a = parm; a < 50; a++) {
    x = a + 5;
    c[x] = c[x + 2] + c[x - 1];
  }
  bar(c[1]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    0x4(%rsp),%edi
  add    $0x1a8,%rsp
  jmp    1060 <bar@plt>
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int a;
  int parm = 11;
  int x;
  int c[100];
  for (a = parm; a < 50; a++) {
    x = a + 5;
    c[x] = c[x + 2] + c[x - 1];
  }
  bar(c[1]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    0x4(%rsp),%edi
  add    $0x1a8,%rsp
  jmp    1060 <bar@plt>
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int a;
  int parm = 11;
  int x;
  int c[100];
  for (a = parm; a < 50; a++) {
    x = a + 5;
    c[x] = c[x + 2] + c[x - 1];
  }
  bar(c[1]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printDoubleVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  je     L25
  mov    $0x20,%edi
  call   <putchar@plt>
L25:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string

tool: D4: %g

assistant: ```c
void printDoubleVector(double *arr, int start, int end) {
  int i;
  for (i = start; i < end; i++) {
    printf("%g", arr[i]);
    if (i != end - 1)
      printf(" ");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printDoubleVector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jge    L31
  mov    %esi,%ebx
  mov    %edx,%r12d
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbp
  lea    D7(%rip),%r13
  jmp    L14
L5:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  je     L31
L14:
  movsd  0x0(%rbp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  je     L5
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L5
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: %g

assistant: ```c
void printDoubleVector(double *arr, int start, int end) {
  int i;
  for (i = start; i < end; i++) {
    printf("%g", arr[i]);
    if (i != end - 1)
      printf(" ");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printDoubleVector>:
  endbr64
  cmp    %edx,%esi
  jge    L10
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %r12d,%r14d
  movslq %esi,%rbp
  push   %rbx
  sub    %esi,%r14d
  lea    0x1(%rbp),%rbx
  add    %rbx,%r14
  sub    $0x8,%rsp
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x1,%rbx
L27:
  movsd  0x0(%r13,%rbp,8),%xmm0
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebp,%r12d
  je     L14
  mov    $0x20,%edi
  call   <putchar@plt>
L14:
  mov    %rbx,%rbp
  cmp    %r14,%rbx
  jne    L33
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %g

assistant: ```c
void printDoubleVector(double *arr, int start, int end) {
  int i;
  for (i = start; i < end; i++) {
    printf("%g", arr[i]);
    if (i != end - 1)
      printf(" ");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printDoubleVector>:
  endbr64
  cmp    %edx,%esi
  jge    L15
  push   %r15
  lea    D6(%rip),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %r12d,%r14d
  movslq %esi,%rbp
  push   %rbx
  sub    %esi,%r14d
  lea    0x1(%rbp),%rbx
  add    %rbx,%r14
  sub    $0x8,%rsp
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rbx
L38:
  movsd  0x0(%r13,%rbp,8),%xmm0
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebp,%r12d
  je     L24
  mov    $0x20,%edi
  call   <putchar@plt>
L24:
  mov    %rbx,%rbp
  cmp    %r14,%rbx
  jne    L37
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %g

assistant: ```c
void printDoubleVector(double *arr, int start, int end) {
  int i;
  for (i = start; i < end; i++) {
    printf("%g", arr[i]);
    if (i != end - 1)
      printf(" ");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<num_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int num_digits(int i, int base) {
  int res = 0;
  do {
    i /= base;
    res++;
  } while (i);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<num_digits>:
  endbr64
  mov    $0x0,%ecx
L4:
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  add    $0x1,%ecx
  test   %eax,%eax
  jne    L4
  mov    %ecx,%eax
  ret
```

assistant: ```c
int num_digits(int i, int base) {
  int res = 0;
  do {
    i /= base;
    res++;
  } while (i);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<num_digits>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L1:
  cltd
  add    $0x1,%r8d
  idiv   %esi
  test   %eax,%eax
  jne    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_digits(int i, int base) {
  int res = 0;
  do {
    i /= base;
    res++;
  } while (i);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<num_digits>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L5:
  cltd
  add    $0x1,%r8d
  idiv   %esi
  test   %eax,%eax
  jne    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_digits(int i, int base) {
  int res = 0;
  do {
    i /= base;
    res++;
  } while (i);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<bitindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  test   %eax,%eax
  je     L11
  addl   $0x8,-0x4(%rbp)
  sarl   $0x8,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  test   %eax,%eax
  je     L2
  addl   $0x4,-0x4(%rbp)
  sarl   $0x4,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  test   %eax,%eax
  je     L42
  addl   $0x2,-0x4(%rbp)
  sarl   $0x2,-0x14(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  sar    %eax
  test   %eax,%eax
  je     L1
  addl   $0x1,-0x4(%rbp)
  sarl   -0x14(%rbp)
L1:
  cmpl   $0x0,-0x14(%rbp)
  je     L28
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitindex(uint16_t x) {
  int n = 0;
  if (x >> 8) {
    n += 8;
    x >>= 8;
  }
  if (x >> 4) {
    n += 4;
    x >>= 4;
  }
  if (x >> 2) {
    n += 2;
    x >>= 2;
  }
  if (x >> 1) {
    n += 1;
    x >>= 1;
  }
  if (x)
    n += 1;
  return n;
}
```