ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_single_quiet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L32:
  mov    $0x0,%eax
  call   <inkey@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <index@plt>
  test   %rax,%rax
  jne    L22
  cmpl   $0x60,-0x8(%rbp)
  jle    L40
  cmpl   $0x7a,-0x8(%rbp)
  jg     L40
  subl   $0x20,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <index@plt>
  test   %rax,%rax
  jne    L87
L40:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  je     L32
  cmpl   $0x5,-0x4(%rbp)
  jg     L64
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  jmp    L6
L64:
  mov    $0x3,%eax
L6:
  mov    %eax,%edi
  call   <flush_input@plt>
  jmp    L32
L22:
  nop
  jmp    L33
L87:
  nop
L33:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_single_quiet(char *valid_string) {
  int c;
  int invalid = 0;
  for (;;) {
    c = inkey();
    if (index(valid_string, c))
      break;
    if (c >= 'a' && c <= 'z') {
      c -= 32;
      if (index(valid_string, c))
        break;
    }
    if (invalid++)
      flush_input(invalid < 6 ? (invalid / 2) : 3);
  }
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_single_quiet>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebp
  mov    $0x3,%r13d
  jmp    L8
L48:
  sub    $0x20,%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <index@plt>
  test   %rax,%rax
  je     L0
L50:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  call   <flush_input@plt>
L43:
  mov    %ebx,%ebp
L8:
  mov    $0x0,%eax
  call   <inkey@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <index@plt>
  test   %rax,%rax
  jne    L50
  lea    -0x61(%rbx),%eax
  cmp    $0x19,%eax
  jbe    L48
L0:
  lea    0x1(%rbp),%ebx
  test   %ebp,%ebp
  je     L43
  mov    %r13d,%edi
  cmp    $0x5,%ebx
  jg     L52
  mov    %ebx,%edi
  shr    $0x1f,%edi
  add    %ebx,%edi
  sar    %edi
  jmp    L52
```

assistant: ```c
int get_single_quiet(char *valid_string) {
  int c;
  int invalid = 0;
  for (;;) {
    c = inkey();
    if (index(valid_string, c))
      break;
    if (c >= 'a' && c <= 'z') {
      c -= 32;
      if (index(valid_string, c))
        break;
    }
    if (invalid++)
      flush_input(invalid < 6 ? (invalid / 2) : 3);
  }
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_single_quiet>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  call   <inkey@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <index@plt>
  test   %rax,%rax
  jne    L29
  lea    -0x61(%r12),%eax
  cmp    $0x19,%eax
  jbe    L56
L4:
  test   %ebx,%ebx
  jne    L9
  mov    $0x1,%ebx
  jmp    L51
  xchg   %ax,%ax
L9:
  add    $0x1,%ebx
  mov    %ebx,%edi
  sar    %edi
  cmp    $0x6,%ebx
  cmovge %r13d,%edi
  call   <flush_input@plt>
  jmp    L51
  nopl   (%rax)
L56:
  sub    $0x20,%r12d
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L4
L29:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_single_quiet(char *valid_string) {
  int c;
  int invalid = 0;
  for (;;) {
    c = inkey();
    if (index(valid_string, c))
      break;
    if (c >= 'a' && c <= 'z') {
      c -= 32;
      if (index(valid_string, c))
        break;
    }
    if (invalid++)
      flush_input(invalid < 6 ? (invalid / 2) : 3);
  }
  return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_single_quiet>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  call   <inkey@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <index@plt>
  test   %rax,%rax
  jne    L0
  lea    -0x61(%r12),%eax
  cmp    $0x19,%eax
  jbe    L24
L28:
  test   %ebx,%ebx
  jne    L57
  mov    $0x1,%ebx
  jmp    L20
  xchg   %ax,%ax
L57:
  add    $0x1,%ebx
  mov    %ebx,%edi
  sar    %edi
  cmp    $0x6,%ebx
  cmovge %r13d,%edi
  call   <flush_input@plt>
  jmp    L20
  nopl   (%rax)
L24:
  sub    $0x20,%r12d
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L28
L0:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_single_quiet(char *valid_string) {
  int c;
  int invalid = 0;
  for (;;) {
    c = inkey();
    if (index(valid_string, c))
      break;
    if (c >= 'a' && c <= 'z') {
      c -= 32;
      if (index(valid_string, c))
        break;
    }
    if (invalid++)
      flush_input(invalid < 6 ? (invalid / 2) : 3);
  }
  return (c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int main(int argument_antall, char *argument_vektor[]) {
  int x = atoi(argument_vektor[1]);
  return x + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argument_antall, char *argument_vektor[]) {
  int x = atoi(argument_vektor[1]);
  return x + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  ret
```

assistant: ```c
int main(int argument_antall, char *argument_vektor[]) {
  int x = atoi(argument_vektor[1]);
  return x + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  ret
```

assistant: ```c
int main(int argument_antall, char *argument_vektor[]) {
  int x = atoi(argument_vektor[1]);
  return x + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum_of_array_multiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L43
  cmpq   $0x0,-0x20(%rbp)
  je     L43
  cmpl   $0x0,-0x24(%rbp)
  jg     L27
L43:
  mov    -0x4(%rbp),%eax
  jmp    L46
L45:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  mov    -0x4(%rbp),%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int sum_of_array_multiplication(int *pfirst, int *psecond, int number_of_entries) {
  int i = 0;
  int result = 0;
  if (pfirst == NULL || psecond == NULL || number_of_entries <= 0) {
    return result;
  }
  while (i < number_of_entries) {
    result += pfirst[i] * psecond[i];
    i++;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_of_array_multiplication>:
  endbr64
  test   %rsi,%rsi
  sete   %al
  test   %edx,%edx
  setle  %cl
  or     %cl,%al
  jne    L37
  test   %rdi,%rdi
  je     L37
  mov    $0x0,%eax
  mov    $0x0,%r8d
L24:
  mov    (%rdi,%rax,4),%ecx
  imul   (%rsi,%rax,4),%ecx
  add    %ecx,%r8d
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L24
  jmp    L23
L37:
  mov    $0x0,%r8d
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_of_array_multiplication(int *pfirst, int *psecond, int number_of_entries) {
  int i = 0;
  int result = 0;
  if (pfirst == NULL || psecond == NULL || number_of_entries <= 0) {
    return result;
  }
  while (i < number_of_entries) {
    result += pfirst[i] * psecond[i];
    i++;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_of_array_multiplication>:
  endbr64
  test   %rsi,%rsi
  sete   %al
  test   %edx,%edx
  setle  %cl
  or     %cl,%al
  jne    L18
  test   %rdi,%rdi
  je     L18
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   (%rax)
L23:
  mov    (%rdi,%rax,4),%ecx
  imul   (%rsi,%rax,4),%ecx
  add    $0x1,%rax
  add    %ecx,%r8d
  cmp    %eax,%edx
  jg     L23
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_of_array_multiplication(int *pfirst, int *psecond, int number_of_entries) {
  int i = 0;
  int result = 0;
  if (pfirst == NULL || psecond == NULL || number_of_entries <= 0) {
    return result;
  }
  while (i < number_of_entries) {
    result += pfirst[i] * psecond[i];
    i++;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum_of_array_multiplication>:
  endbr64
  test   %rsi,%rsi
  mov    %rsi,%rcx
  sete   %al
  test   %edx,%edx
  setle  %sil
  or     %sil,%al
  jne    L49
  test   %rdi,%rdi
  je     L49
  test   %edx,%edx
  mov    $0x1,%r8d
  cmovg  %edx,%r8d
  cmp    $0x3,%edx
  jle    L71
  mov    %r8d,%esi
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L41:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm2
  movdqu (%rdi,%rax,1),%xmm1
  movdqu (%rcx,%rax,1),%xmm4
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm2
  pmuludq %xmm4,%xmm1
  pmuludq %xmm2,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %rax,%rsi
  jne    L41
  movdqa %xmm3,%xmm0
  mov    %r8d,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  and    $0x3,%r8d
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%eax
  je     L78
L19:
  movslq %esi,%r10
  mov    (%rdi,%r10,4),%r9d
  imul   (%rcx,%r10,4),%r9d
  lea    0x0(,%r10,4),%r8
  add    %r9d,%eax
  lea    0x1(%rsi),%r9d
  cmp    %r9d,%edx
  jle    L62
  mov    0x4(%rdi,%r8,1),%r9d
  imul   0x4(%rcx,%r8,1),%r9d
  add    $0x2,%esi
  add    %r9d,%eax
  cmp    %esi,%edx
  jle    L62
  mov    0x8(%rcx,%r8,1),%edx
  imul   0x8(%rdi,%r8,1),%edx
  add    %edx,%eax
  ret
  xchg   %ax,%ax
L49:
  xor    %eax,%eax
L62:
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  ret
  nopl   0x0(%rax)
L71:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L19
```

assistant: ```c
int sum_of_array_multiplication(int *pfirst, int *psecond, int number_of_entries) {
  int i = 0;
  int result = 0;
  if (pfirst == NULL || psecond == NULL || number_of_entries <= 0) {
    return result;
  }
  while (i < number_of_entries) {
    result += pfirst[i] * psecond[i];
    i++;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<fd_isreg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L15
  mov    $0xffffffff,%eax
  jmp    L24
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int fd_isreg(const char *filename) {
  struct stat st;
  if (stat(filename, &st))
    return -1;
  return S_ISREG(st.st_mode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fd_isreg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L10
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L3
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_isreg(const char *filename) {
  struct stat st;
  if (stat(filename, &st))
    return -1;
  return S_ISREG(st.st_mode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd_isreg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L27
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L27:
  mov    $0xffffffff,%eax
  jmp    L19
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_isreg(const char *filename) {
  struct stat st;
  if (stat(filename, &st))
    return -1;
  return S_ISREG(st.st_mode);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fd_isreg>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  jne    L26
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L26:
  mov    $0xffffffff,%eax
  jmp    L28
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_isreg(const char *filename) {
  struct stat st;
  if (stat(filename, &st))
    return -1;
  return S_ISREG(st.st_mode);
}
```
user: What is the c source code of the assembly code below?

```asm
<GetInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  movb   $0x0,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
L75:
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L58
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L74
L58:
  addl   $0x1,-0x48(%rbp)
L74:
  mov    -0x48(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jle    L38
  mov    -0x4c(%rbp),%eax
  cltq
  movb   $0x0,-0x40(%rbp,%rax,1)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x44(%rbp)
L38:
  mov    -0x48(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jne    L24
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L24
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L24
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4c(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
L24:
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x50(%rbp)
  je     L82
  mov    -0x48(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jg     L82
  addl   $0x1,-0x50(%rbp)
  jmp    L75
L82:
  mov    -0x44(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int GetInt(char *String, int Column) {
  int i, j = 0, flag = 1, IntValue = 0;
  char temp[50];
  temp[0] = '\0';
  for (i = 0;; i++) {
    if (String[i] == '\t' || String[i] == '\n')
      flag++;
    if (flag > Column) {
      temp[j] = '\0';
      IntValue = atoi(temp);
    }
    if (flag == Column && String[i] != '\t' && String[i] != '\n')
      temp[j++] = String[i];
    if (i == strlen(String) || flag > Column)
      break;
  }
  return IntValue;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetInt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%r14d
  jmp    L57
L78:
  movslq %r14d,%r14
  movb   $0x0,(%rsp,%r14,1)
  mov    %rsp,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
L30:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  cmp    %r12d,%ebx
  setg   %al
  cmp    %ebp,%edx
  sete   %dl
  add    $0x1,%rbp
  or     %dl,%al
  jne    L75
L57:
  movzbl 0x0(%r13,%rbp,1),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x2,%al
  adc    $0x0,%ebx
  cmp    %r12d,%ebx
  jg     L78
  jne    L10
  cmp    $0x1,%al
  jbe    L10
  movslq %r14d,%rax
  mov    %dl,(%rsp,%rax,1)
  lea    0x1(%r14),%r14d
  jmp    L10
L75:
  mov    $0x0,%ebx
  jmp    L30
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetInt(char *String, int Column) {
  int i, j = 0, flag = 1, IntValue = 0;
  char temp[50];
  temp[0] = '\0';
  for (i = 0;; i++) {
    if (String[i] == '\t' || String[i] == '\n')
      flag++;
    if (flag > Column) {
      temp[j] = '\0';
      IntValue = atoi(temp);
    }
    if (flag == Column && String[i] != '\t' && String[i] != '\n')
      temp[j++] = String[i];
    if (i == strlen(String) || flag > Column)
      break;
  }
  return IntValue;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetInt>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L66:
  jne    L5
  cmp    $0x1,%al
  jbe    L5
  movslq %r13d,%rax
  add    $0x1,%r13d
  mov    %dl,(%rsp,%rax,1)
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  add    $0x1,%rbx
  cmp    %eax,%r8d
  je     L4
L38:
  movzbl (%r12,%rbx,1),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x2,%al
  adc    $0x0,%ebp
  cmp    %r14d,%ebp
  jle    L66
  movslq %r13d,%r13
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%r13,1)
  call   <atoi@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
L15:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x40,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  xor    %r13d,%r13d
  jmp    L15
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetInt(char *String, int Column) {
  int i, j = 0, flag = 1, IntValue = 0;
  char temp[50];
  temp[0] = '\0';
  for (i = 0;; i++) {
    if (String[i] == '\t' || String[i] == '\n')
      flag++;
    if (flag > Column) {
      temp[j] = '\0';
      IntValue = atoi(temp);
    }
    if (flag == Column && String[i] != '\t' && String[i] != '\n')
      temp[j++] = String[i];
    if (i == strlen(String) || flag > Column)
      break;
  }
  return IntValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetInt>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L44:
  jne    L6
  cmp    $0x1,%al
  jbe    L6
  movslq %r13d,%rax
  add    $0x1,%r13d
  mov    %dl,(%rsp,%rax,1)
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  add    $0x1,%rbx
  cmp    %eax,%r8d
  je     L26
L52:
  movzbl (%r12,%rbx,1),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x2,%al
  adc    $0x0,%ebp
  cmp    %r14d,%ebp
  jle    L44
  movslq %r13d,%r13
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%r13,1)
  call   <atoi@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
L57:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x40,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  xor    %r13d,%r13d
  jmp    L57
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetInt(char *String, int Column) {
  int i, j = 0, flag = 1, IntValue = 0;
  char temp[50];
  temp[0] = '\0';
  for (i = 0;; i++) {
    if (String[i] == '\t' || String[i] == '\n')
      flag++;
    if (flag > Column) {
      temp[j] = '\0';
      IntValue = atoi(temp);
    }
    if (flag == Column && String[i] != '\t' && String[i] != '\n')
      temp[j++] = String[i];
    if (i == strlen(String) || flag > Column)
      break;
  }
  return IntValue;
}
```
user: What is the c source code of the assembly code below?

```asm
<sortBipartitions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <__popcountdi2>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <__popcountdi2>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L15
  mov    $0x0,%eax
  jmp    L18
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L3
  mov    $0xffffffff,%eax
  jmp    L18
L3:
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int sortBipartitions(const void *a, const void *b) {
  int ia = *(int *)(a), ib = *(int *)(b), bits_ia = __builtin_popcount(ia), bits_ib = __builtin_popcount(ib);
  if (bits_ia == bits_ib)
    return 0;
  if (bits_ib > bits_ia)
    return -1;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sortBipartitions>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    (%rdi),%edi
  call   <__popcountdi2>
  mov    %eax,%ebx
  mov    0x0(%rbp),%edi
  call   <__popcountdi2>
  mov    $0x0,%edx
  cmp    %eax,%ebx
  je     L8
  setge  %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx,%rdx,1),%edx
L8:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int sortBipartitions(const void *a, const void *b) {
  int ia = *(int *)(a), ib = *(int *)(b), bits_ia = __builtin_popcount(ia), bits_ib = __builtin_popcount(ib);
  if (bits_ia == bits_ib)
    return 0;
  if (bits_ib > bits_ia)
    return -1;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sortBipartitions>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <__popcountdi2>
  mov    0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <__popcountdi2>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebx
  je     L5
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int sortBipartitions(const void *a, const void *b) {
  int ia = *(int *)(a), ib = *(int *)(b), bits_ia = __builtin_popcount(ia), bits_ib = __builtin_popcount(ib);
  if (bits_ia == bits_ib)
    return 0;
  if (bits_ib > bits_ia)
    return -1;
  else
    return 1;
}
```