ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L48
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x68(%rbp)
  jmp    L16
L48:
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x68(%rbp)
  jmp    L16
L15:
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  lea    D33(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L15
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D34
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string

tool: D6: w

tool: D34: output_file.txt

tool: D33: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char info[80];
  FILE *output_file;
  if (argv[1] == NULL) {
    output_file = fopen("output_file.txt", "w");
  } else {
    output_file = fopen(argv[1], "w");
  }
  while (scanf("%s\n", info) == 1) {
    fprintf(output_file, "%s\n", info);
    printf("%s\n", info);
  }
  fclose(output_file);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  test   %rdi,%rdi
  je     L24
  lea    D25(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
L11:
  lea    D28(%rip),%rbx
  jmp    L20
L24:
  lea    D25(%rip),%rsi
  lea    D34(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L11
L33:
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L20:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L33
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D28
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string

tool: D25: w

tool: D28: %s


tool: D34: output_file.txt

assistant: ```c
int main(int argc, char *argv[]) {
  char info[80];
  FILE *output_file;
  if (argv[1] == NULL) {
    output_file = fopen("output_file.txt", "w");
  } else {
    output_file = fopen(argv[1], "w");
  }
  while (scanf("%s\n", info) == 1) {
    fprintf(output_file, "%s\n", info);
    printf("%s\n", info);
  }
  fclose(output_file);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    0x8(%rsi),%rdi
  lea    D24(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  call   <fopen@plt>
  mov    %rax,%r12
L39:
  mov    %rsp,%rbp
  lea    D21(%rip),%rbx
  jmp    L3
L14:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %rbp,%rdx
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L14
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D4(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L39
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string

tool: D24: w

tool: D21: %s


tool: D4: output_file.txt

assistant: ```c
int main(int argc, char *argv[]) {
  char info[80];
  FILE *output_file;
  if (argv[1] == NULL) {
    output_file = fopen("output_file.txt", "w");
  } else {
    output_file = fopen(argv[1], "w");
  }
  while (scanf("%s\n", info) == 1) {
    fprintf(output_file, "%s\n", info);
    printf("%s\n", info);
  }
  fclose(output_file);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    0x8(%rsi),%rdi
  lea    D4(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  call   <fopen@plt>
  mov    %rax,%r12
L6:
  mov    %rsp,%rbp
  lea    D0(%rip),%rbx
  jmp    L23
L45:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %rbp,%rdx
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L23:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L45
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D9(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D4: w

tool: D0: %s


tool: D9: output_file.txt

assistant: ```c
int main(int argc, char *argv[]) {
  char info[80];
  FILE *output_file;
  if (argv[1] == NULL) {
    output_file = fopen("output_file.txt", "w");
  } else {
    output_file = fopen(argv[1], "w");
  }
  while (scanf("%s\n", info) == 1) {
    fprintf(output_file, "%s\n", info);
    printf("%s\n", info);
  }
  fclose(output_file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getTrimmedString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L33
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L1
L30:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
  jmp    L35
L43:
  subl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L43
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  leave
  ret
```

assistant: ```c
void getTrimmedString(const char *src, char *dest) {
  int start = 0;
  int end = strlen(src) - 1;
  if (end < 0) {
    dest[0] = '\0';
    return;
  }
  while (isspace(src[start]))
    start++;
  while (isspace(src[end]))
    end--;
  strncpy(dest, src + start, end + 1);
  if (dest[end + 1] != '\0')
    dest[end + 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getTrimmedString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L28
  mov    %eax,%ebx
  mov    %r12,%rbp
L29:
  mov    %rbp,%r13
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L29
  movslq %ebx,%rbx
L45:
  mov    %ebx,%ebp
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  mov    %rbx,%r15
  sub    $0x1,%rbx
  test   %rax,%rax
  jne    L45
  lea    0x1(%rbp),%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  lea    0x1(%r14,%r15,1),%rax
  cmpb   $0x0,(%rax)
  je     L34
  movb   $0x0,(%rax)
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  movb   $0x0,(%r14)
  jmp    L34
```

assistant: ```c
void getTrimmedString(const char *src, char *dest) {
  int start = 0;
  int end = strlen(src) - 1;
  if (end < 0) {
    dest[0] = '\0';
    return;
  }
  while (isspace(src[start]))
    start++;
  while (isspace(src[end]))
    end--;
  strncpy(dest, src + start, end + 1);
  if (dest[end + 1] != '\0')
    dest[end + 1] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getTrimmedString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L36
  movslq %eax,%rbx
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L30:
  movsbl (%rax),%edi
  mov    %rax,%rbp
  call   <isspace@plt>
  mov    %rax,%r8
  lea    0x1(%rbp),%rax
  test   %r8,%r8
  jne    L30
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%r14d
  mov    %rbx,%r15
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  lea    0x1(%r14),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  lea    0x1(%r13,%r15,1),%rax
  cmpb   $0x0,(%rax)
  je     L37
  movb   $0x0,(%rax)
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L36:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getTrimmedString(const char *src, char *dest) {
  int start = 0;
  int end = strlen(src) - 1;
  if (end < 0) {
    dest[0] = '\0';
    return;
  }
  while (isspace(src[start]))
    start++;
  while (isspace(src[end]))
    end--;
  strncpy(dest, src + start, end + 1);
  if (dest[end + 1] != '\0')
    dest[end + 1] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getTrimmedString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L30
  movslq %eax,%rbx
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  movsbl (%rax),%edi
  mov    %rax,%rbp
  call   <isspace@plt>
  mov    %rax,%r8
  lea    0x1(%rbp),%rax
  test   %r8,%r8
  jne    L37
  nopw   0x0(%rax,%rax,1)
L38:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%r14d
  mov    %rbx,%r15
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  lea    0x1(%r14),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  lea    0x1(%r13,%r15,1),%rax
  cmpb   $0x0,(%rax)
  je     L26
  movb   $0x0,(%rax)
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L30:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getTrimmedString(const char *src, char *dest) {
  int start = 0;
  int end = strlen(src) - 1;
  if (end < 0) {
    dest[0] = '\0';
    return;
  }
  while (isspace(src[start]))
    start++;
  while (isspace(src[end]))
    end--;
  strncpy(dest, src + start, end + 1);
  if (dest[end + 1] != '\0')
    dest[end + 1] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rec_allocation_lc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L10
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  shl    $0x3,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
unsigned rec_allocation_lc(unsigned lc) {
  if (lc == 0)
    return (0);
  else
    return (((lc - 1) / 8 + 1) * 8);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rec_allocation_lc>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L4
  sub    $0x1,%eax
  shr    $0x3,%eax
  lea    0x8(,%rax,8),%eax
L4:
  ret
```

assistant: ```c
unsigned rec_allocation_lc(unsigned lc) {
  if (lc == 0)
    return (0);
  else
    return (((lc - 1) / 8 + 1) * 8);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rec_allocation_lc>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L7
  sub    $0x1,%eax
  shr    $0x3,%eax
  lea    0x8(,%rax,8),%eax
L7:
  ret
```

assistant: ```c
unsigned rec_allocation_lc(unsigned lc) {
  if (lc == 0)
    return (0);
  else
    return (((lc - 1) / 8 + 1) * 8);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rec_allocation_lc>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L0
  sub    $0x1,%eax
  shr    $0x3,%eax
  lea    0x8(,%rax,8),%eax
L0:
  ret
```

assistant: ```c
unsigned rec_allocation_lc(unsigned lc) {
  if (lc == 0)
    return (0);
  else
    return (((lc - 1) / 8 + 1) * 8);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xt_core_note_maximum_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L17
  jmp    L12
L17:
  mov    -0x8(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L12:
  nop
  leave
  ret
```

assistant: ```c
void xt_core_note_maximum_double(double *maximum, double candidate) {
  assert(maximum);
  if (candidate > *maximum) {
    *maximum = candidate;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xt_core_note_maximum_double>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movq   %xmm0,%rbp
  call   <assert@plt>
  movq   %rbp,%xmm1
  comisd (%rbx),%xmm1
  jbe    L2
  mov    %rbp,(%rbx)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xt_core_note_maximum_double(double *maximum, double candidate) {
  assert(maximum);
  if (candidate > *maximum) {
    *maximum = candidate;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xt_core_note_maximum_double>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  comisd (%rbx),%xmm0
  jbe    L5
  movsd  %xmm0,(%rbx)
L5:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void xt_core_note_maximum_double(double *maximum, double candidate) {
  assert(maximum);
  if (candidate > *maximum) {
    *maximum = candidate;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xt_core_note_maximum_double>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  movsd  0x8(%rsp),%xmm0
  comisd (%rbx),%xmm0
  jbe    L3
  movsd  %xmm0,(%rbx)
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void xt_core_note_maximum_double(double *maximum, double candidate) {
  assert(maximum);
  if (candidate > *maximum) {
    *maximum = candidate;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getGroupDetails>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  cmp    $0x800,%eax
  jle    L123
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  cltq
  jmp    L75
L123:
  mov    $0x800,%eax
L75:
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L39
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  jmp    L108
L39:
  mov    -0x18(%rbp),%rax
  lea    -0x4(%rax),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  lea    -0x20(%rbp),%rdi
  mov    -0x10(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <getgrgid_r@plt>
  mov    %eax,-0x24(%rbp)
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L97
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  shlq   -0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L39
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  jmp    L108
L97:
  nop
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L53
  cmpl   $0x0,-0x24(%rbp)
  jne    L53
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D51(%rip),%rax
  mov    (%rax),%eax
  jmp    L108
L53:
  cmpl   $0x0,-0x24(%rbp)
  je     L38
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x24(%rbp),%eax
  jmp    L108
L38:
  mov    -0x40(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L108:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
int getGroupDetails(gid_t group, char **grpBuf) {
  struct group *grp = NULL;
  size_t currBufferSize = (sysconf(_SC_GETGR_R_SIZE_MAX) > 2048 ? sysconf(_SC_GETGR_R_SIZE_MAX) : 2048);
  *grpBuf = NULL;
  char *buf = (char *)malloc(sizeof(char) * currBufferSize);
  if (!buf) {
    return ENOMEM;
  }
  int error;
  for (;;) {
    error = getgrgid_r(group, (struct group *)buf, buf + sizeof(struct group), currBufferSize - sizeof(struct group), &grp);
    if (error != ERANGE) {
      break;
    }
    free(buf);
    currBufferSize *= 2;
    buf = malloc(sizeof(char) * currBufferSize);
    if (!buf) {
      return ENOMEM;
    }
  }
  if (!grp && !error) {
    free(buf);
    return ENOENT;
  } else if (error) {
    free(buf);
    return error;
  }
  *grpBuf = buf;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getGroupDetails>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x800,%r12d
  cmp    $0x800,%eax
  jg     L94
L31:
  movq   $0x0,(%r15)
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%r14
  test   %rax,%rax
  je     L14
L54:
  lea    -0x4(%r12),%rcx
  lea    0x4(%rbx),%rdx
  mov    %r14,%r8
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <getgrgid_r@plt>
  mov    %eax,%ebp
  mov    D19(%rip),%rax
  cmp    %ebp,(%rax)
  jne    L107
  mov    %rbx,%rdi
  call   <free@plt>
  add    %r12,%r12
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L54
  mov    D57(%rip),%rax
  mov    (%rax),%ebp
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L114
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  movslq %eax,%r12
  jmp    L31
L14:
  mov    D57(%rip),%rax
  mov    (%rax),%ebp
  jmp    L37
L107:
  cmpq   $0x0,(%rsp)
  jne    L1
  test   %ebp,%ebp
  je     L67
L1:
  test   %ebp,%ebp
  jne    L57
  mov    %rbx,(%r15)
  jmp    L37
L67:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%ebp
  jmp    L37
L57:
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L37
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getGroupDetails(gid_t group, char **grpBuf) {
  struct group *grp = NULL;
  size_t currBufferSize = (sysconf(_SC_GETGR_R_SIZE_MAX) > 2048 ? sysconf(_SC_GETGR_R_SIZE_MAX) : 2048);
  *grpBuf = NULL;
  char *buf = (char *)malloc(sizeof(char) * currBufferSize);
  if (!buf) {
    return ENOMEM;
  }
  int error;
  for (;;) {
    error = getgrgid_r(group, (struct group *)buf, buf + sizeof(struct group), currBufferSize - sizeof(struct group), &grp);
    if (error != ERANGE) {
      break;
    }
    free(buf);
    currBufferSize *= 2;
    buf = malloc(sizeof(char) * currBufferSize);
    if (!buf) {
      return ENOMEM;
    }
  }
  if (!grp && !error) {
    free(buf);
    return ENOENT;
  } else if (error) {
    free(buf);
    return error;
  }
  *grpBuf = buf;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getGroupDetails>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    $0x800,%ebx
  sub    $0x28,%rsp
  mov    D33(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  mov    0x0(%rbp),%edi
  call   <sysconf@plt>
  mov    $0x800,%edi
  cmp    $0x800,%eax
  jg     L73
L94:
  movq   $0x0,(%r15)
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L119
  mov    D2(%rip),%r13
  lea    0x10(%rsp),%r14
  jmp    L121
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  add    %rbx,%rbx
  call   <free@plt>
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L119
L121:
  mov    %r14,%r8
  lea    -0x4(%rbx),%rcx
  lea    0x4(%rbp),%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <getgrgid_r@plt>
  mov    %eax,%r8d
  cmp    %eax,0x0(%r13)
  je     L28
  cmpq   $0x0,0x10(%rsp)
  je     L91
  test   %eax,%eax
  jne    L97
  mov    %rbp,(%r15)
  jmp    L102
  nopw   0x0(%rax,%rax,1)
L119:
  mov    D3(%rip),%rax
  mov    (%rax),%r8d
L102:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x28,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L73:
  mov    0x0(%rbp),%edi
  call   <sysconf@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdi
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L91:
  test   %eax,%eax
  je     L79
L97:
  mov    %rbp,%rdi
  mov    %r8d,0xc(%rsp)
  call   <free@plt>
  mov    0xc(%rsp),%r8d
  jmp    L102
L79:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    D35(%rip),%rax
  mov    (%rax),%r8d
  jmp    L102
L85:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getGroupDetails(gid_t group, char **grpBuf) {
  struct group *grp = NULL;
  size_t currBufferSize = (sysconf(_SC_GETGR_R_SIZE_MAX) > 2048 ? sysconf(_SC_GETGR_R_SIZE_MAX) : 2048);
  *grpBuf = NULL;
  char *buf = (char *)malloc(sizeof(char) * currBufferSize);
  if (!buf) {
    return ENOMEM;
  }
  int error;
  for (;;) {
    error = getgrgid_r(group, (struct group *)buf, buf + sizeof(struct group), currBufferSize - sizeof(struct group), &grp);
    if (error != ERANGE) {
      break;
    }
    free(buf);
    currBufferSize *= 2;
    buf = malloc(sizeof(char) * currBufferSize);
    if (!buf) {
      return ENOMEM;
    }
  }
  if (!grp && !error) {
    free(buf);
    return ENOENT;
  } else if (error) {
    free(buf);
    return error;
  }
  *grpBuf = buf;
  return 0;
}
```