ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<affiche>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: Mon rang est : %d sur %d


assistant: ```c
void affiche() {
#pragma omp parallel
  {
    int id_threadOMP = omp_get_thread_num();
    int nb_threadOMP = omp_get_num_threads();
    printf("Mon rang est : %d sur %d\n", id_threadOMP, nb_threadOMP);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<affiche>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: Mon rang est : %d sur %d


assistant: ```c
void affiche() {
#pragma omp parallel
  {
    int id_threadOMP = omp_get_thread_num();
    int nb_threadOMP = omp_get_num_threads();
    printf("Mon rang est : %d sur %d\n", id_threadOMP, nb_threadOMP);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<c_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L16
L17:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int c_mod(int a, int b) {
  if (a == 0)
    return (0);
  return (b % a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<c_mod>:
  endbr64
  mov    %esi,%eax
  mov    %edi,%edx
  test   %edi,%edi
  je     L6
  cltd
  idiv   %edi
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int c_mod(int a, int b) {
  if (a == 0)
    return (0);
  return (b % a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<c_mod>:
  endbr64
  mov    %esi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L4
  cltd
  idiv   %edi
  mov    %edx,%r8d
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int c_mod(int a, int b) {
  if (a == 0)
    return (0);
  return (b % a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_mod>:
  endbr64
  mov    %esi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L0
  cltd
  idiv   %edi
  mov    %edx,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int c_mod(int a, int b) {
  if (a == 0)
    return (0);
  return (b % a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rightAngledTriangleRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L32
L54:
  movl   $0x1,-0x4(%rbp)
  jmp    L38
L51:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L51
  movl   $0x1,-0x4(%rbp)
  jmp    L52
L28:
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L54
  nop
  nop
  leave
  ret
```

assistant: ```c
void rightAngledTriangleRight(int n, char ch) {
  int row;
  int col;
  for (row = 1; row <= n; row++) {
    for (col = 1; col <= n - row; col++)
      printf(" ");
    for (col = 1; col <= row; col++)
      printf("%c", ch);
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rightAngledTriangleRight>:
  endbr64
  test   %edi,%edi
  jle    L35
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  lea    -0x1(%rdi),%r13d
  mov    $0x1,%ebp
  movsbl %sil,%r12d
  jmp    L67
L62:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jge    L62
L27:
  test   %ebp,%ebp
  jle    L40
  mov    $0x1,%ebx
L13:
  mov    %r12d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L13
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  sub    $0x1,%r13d
  cmp    %ebp,%r14d
  jl     L1
L67:
  mov    %r13d,%r15d
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jg     L62
  jmp    L27
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  ret
```

assistant: ```c
void rightAngledTriangleRight(int n, char ch) {
  int row;
  int col;
  for (row = 1; row <= n; row++) {
    for (col = 1; col <= n - row; col++)
      printf(" ");
    for (col = 1; col <= row; col++)
      printf("%c", ch);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rightAngledTriangleRight>:
  endbr64
  test   %edi,%edi
  jle    L30
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movsbl %sil,%r13d
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L37:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L36
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L38
L36:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L7
  mov    $0xa,%edi
  add    $0x1,%ebp
  sub    $0x1,%r12d
  call   <putchar@plt>
  cmp    %ebp,%r14d
  jge    L37
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  ret
```

assistant: ```c
void rightAngledTriangleRight(int n, char ch) {
  int row;
  int col;
  for (row = 1; row <= n; row++) {
    for (col = 1; col <= n - row; col++)
      printf(" ");
    for (col = 1; col <= row; col++)
      printf("%c", ch);
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rightAngledTriangleRight>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movsbl %sil,%r13d
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L7:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L31
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L25
L31:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L8
  mov    $0xa,%edi
  add    $0x1,%ebp
  sub    $0x1,%r12d
  call   <putchar@plt>
  cmp    %ebp,%r14d
  jge    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

assistant: ```c
void rightAngledTriangleRight(int n, char ch) {
  int row;
  int col;
  for (row = 1; row <= n; row++) {
    for (col = 1; col <= n - row; col++)
      printf(" ");
    for (col = 1; col <= row; col++)
      printf("%c", ch);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x5,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  add    $0x5,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L77
  mov    $0xffffffff,%eax
  jmp    L61
L77:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L37
  mov    $0x0,%eax
  jmp    L61
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L5
  mov    $0x1,%eax
  jmp    L61
L5:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
L61:
  leave
  ret
```

assistant: ```c
int ft_compare(a, b)
char **a;
char **b;
{
  int ax, bx;
  if (!strncmp(*a, *b, 5) && ((*a)[5] != ' ') && ((*b)[5] != ' ') && (ax = atoi(&(*a)[5])) && (bx = atoi(&(*b)[5]))) {
    if (ax < bx)
      return -1;
    if (ax == bx)
      return 0;
    if (ax > bx)
      return 1;
  }
  return strncmp(*a, *b, 8);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_compare>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    (%rsi),%r14
  mov    (%rdi),%r13
  mov    $0x5,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L1
  mov    %eax,%ebx
  cmpb   $0x20,0x5(%r13)
  je     L1
  cmpb   $0x20,0x5(%r14)
  jne    L97
L1:
  mov    $0x8,%edx
  mov    0x0(%rbp),%rsi
  mov    (%r12),%rdi
  call   <strncmp@plt>
  mov    %eax,%ebx
L38:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L97:
  lea    0x5(%r13),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L1
  mov    0x0(%rbp),%rax
  lea    0x5(%rax),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  test   %eax,%eax
  je     L1
  cmp    %eax,%r13d
  jl     L57
  je     L38
  mov    $0x1,%ebx
  jle    L1
  jmp    L38
L57:
  mov    $0xffffffff,%ebx
  jmp    L38
```

assistant: ```c
int ft_compare(a, b)
char **a;
char **b;
{
  int ax, bx;
  if (!strncmp(*a, *b, 5) && ((*a)[5] != ' ') && ((*b)[5] != ' ') && (ax = atoi(&(*a)[5])) && (bx = atoi(&(*b)[5]))) {
    if (ax < bx)
      return -1;
    if (ax == bx)
      return 0;
    if (ax > bx)
      return 1;
  }
  return strncmp(*a, *b, 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_compare>:
  endbr64
  push   %r14
  mov    $0x5,%edx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%r14
  mov    %rsi,%rbx
  mov    (%rdi),%r12
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L61
  cmpb   $0x20,0x5(%r12)
  je     L61
  cmpb   $0x20,0x5(%r14)
  jne    L2
L61:
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r12,%rdi
  mov    $0x8,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strncmp@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  lea    0x5(%r12),%rdi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L39
L15:
  mov    (%rbx),%r14
  mov    0x0(%rbp),%r12
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rbx),%rax
  lea    0x5(%rax),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  test   %eax,%eax
  je     L15
  cmp    %eax,%r12d
  jl     L78
  je     L41
  jle    L15
  mov    $0x1,%r13d
L41:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  or     $0xffffffff,%r13d
  jmp    L41
```

assistant: ```c
int ft_compare(a, b)
char **a;
char **b;
{
  int ax, bx;
  if (!strncmp(*a, *b, 5) && ((*a)[5] != ' ') && ((*b)[5] != ' ') && (ax = atoi(&(*a)[5])) && (bx = atoi(&(*b)[5]))) {
    if (ax < bx)
      return -1;
    if (ax == bx)
      return 0;
    if (ax > bx)
      return 1;
  }
  return strncmp(*a, *b, 8);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_compare>:
  endbr64
  push   %r14
  mov    $0x5,%edx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rsi),%r14
  mov    %rsi,%rbx
  mov    (%rdi),%r12
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L66
  cmpb   $0x20,0x5(%r12)
  je     L66
  cmpb   $0x20,0x5(%r14)
  jne    L62
L66:
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  mov    %r12,%rdi
  mov    $0x8,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <strncmp@plt>
  nopl   0x0(%rax,%rax,1)
L62:
  lea    0x5(%r12),%rdi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L41
L84:
  mov    (%rbx),%r14
  mov    0x0(%rbp),%r12
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L41:
  mov    (%rbx),%rax
  lea    0x5(%rax),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  test   %eax,%eax
  je     L84
  cmp    %eax,%r12d
  jl     L44
  je     L11
  jle    L84
  mov    $0x1,%r13d
L11:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  or     $0xffffffff,%r13d
  jmp    L11
```

assistant: ```c
int ft_compare(a, b)
char **a;
char **b;
{
  int ax, bx;
  if (!strncmp(*a, *b, 5) && ((*a)[5] != ' ') && ((*b)[5] != ' ') && (ax = atoi(&(*a)[5])) && (bx = atoi(&(*b)[5]))) {
    if (ax < bx)
      return -1;
    if (ax == bx)
      return 0;
    if (ax > bx)
      return 1;
  }
  return strncmp(*a, *b, 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <addToList@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <addToList@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <addToList@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <addToList@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <iterateList@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <deleteNode2@plt>
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <iterateList@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct ListNode *list = NULL;
  list = addToList(list, 5);
  list = addToList(list, 4);
  list = addToList(list, 2);
  list = addToList(list, 1);
  iterateList(list);
  deleteNode2(&list, 4);
  if (list) {
    iterateList(list);
    free(list);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    $0x4,%esi
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    $0x2,%esi
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    $0x1,%esi
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <iterateList@plt>
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <deleteNode2@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L8
  call   <iterateList@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *list = NULL;
  list = addToList(list, 5);
  list = addToList(list, 4);
  list = addToList(list, 2);
  list = addToList(list, 1);
  iterateList(list);
  deleteNode2(&list, 4);
  if (list) {
    iterateList(list);
    free(list);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x5,%esi
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <addToList@plt>
  mov    $0x4,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    $0x2,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <iterateList@plt>
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <deleteNode2@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L17
  call   <iterateList@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *list = NULL;
  list = addToList(list, 5);
  list = addToList(list, 4);
  list = addToList(list, 2);
  list = addToList(list, 1);
  iterateList(list);
  deleteNode2(&list, 4);
  if (list) {
    iterateList(list);
    free(list);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x5,%esi
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <addToList@plt>
  mov    $0x4,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    $0x2,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <addToList@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <iterateList@plt>
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <deleteNode2@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  je     L8
  call   <iterateList@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *list = NULL;
  list = addToList(list, 5);
  list = addToList(list, 4);
  list = addToList(list, 2);
  list = addToList(list, 1);
  iterateList(list);
  deleteNode2(&list, 4);
  if (list) {
    iterateList(list);
    free(list);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0xa,(%rax)
  mov    $0xfffd0,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xb,(%rax)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: string

tool: D21: 
---- running test5 ---


tool: D20: NO FREES:


tool: D22: FREE RIGHT:


tool: D35: FREE LEFT:


assistant: ```c
int main(int argc, char **argv) {
  printf("\n---- running test5 ---\n");
  int *mem1 = (int *)malloc(1048576);
  *mem1 = 10;
  int *mem2 = (int *)malloc(1048528);
  *mem2 = 11;
  printf("NO FREES:\n");
  print_list();
  free(mem2);
  printf("FREE RIGHT:\n");
  print_list();
  free(mem1);
  printf("FREE LEFT:\n");
  print_list();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0xa,(%rax)
  mov    $0xfffd0,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movl   $0xb,(%rax)
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <print_list@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string
name: unpack_data
arguments: tag: D34
type_guessed: string

tool: D13: 
---- running test5 ---


tool: D30: NO FREES:


tool: D12: FREE RIGHT:


tool: D34: FREE LEFT:


assistant: ```c
int main(int argc, char **argv) {
  printf("\n---- running test5 ---\n");
  int *mem1 = (int *)malloc(1048576);
  *mem1 = 10;
  int *mem2 = (int *)malloc(1048528);
  *mem2 = 11;
  printf("NO FREES:\n");
  print_list();
  free(mem2);
  printf("FREE RIGHT:\n");
  print_list();
  free(mem1);
  printf("FREE LEFT:\n");
  print_list();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D30(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    $0xfffd0,%edi
  movl   $0xa,(%rax)
  mov    %rax,%rbp
  call   <malloc@plt>
  lea    D13(%rip),%rdi
  movl   $0xb,(%rax)
  mov    %rax,%r12
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_list@plt>
  mov    %r12,%rdi
  call   <free@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_list@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <print_list@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D37
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D30: 
---- running test5 ---


tool: D13: NO FREES:


tool: D37: FREE RIGHT:


tool: D5: FREE LEFT:


assistant: ```c
int main(int argc, char **argv) {
  printf("\n---- running test5 ---\n");
  int *mem1 = (int *)malloc(1048576);
  *mem1 = 10;
  int *mem2 = (int *)malloc(1048528);
  *mem2 = 11;
  printf("NO FREES:\n");
  print_list();
  free(mem2);
  printf("FREE RIGHT:\n");
  print_list();
  free(mem1);
  printf("FREE LEFT:\n");
  print_list();
  exit(0);
}
```