user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  nopl   0x0(%rax)
L1:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x14,%eax
  ja     L1
  test   %eax,%eax
  je     L88
  lea    0x10(%rsp),%rbx
  xor    %r14d,%r14d
  lea    D59(%rip),%r13
  nop
L81:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpl   $0x1,(%rbx)
  ja     L81
  mov    0xc(%rsp),%eax
  add    $0x1,%r14d
  add    $0x4,%rbx
  cmp    %r14d,%eax
  jg     L81
L88:
  mov    0x10(%rsp),%ecx
  test   %ecx,%ecx
  jne    L95
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  mov    0x10(%rsp,%rdx,4),%edx
  test   %edx,%edx
  jne    L95
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r14
  lea    D49(%rip),%r13
  lea    D52(%rip),%r12
  test   %eax,%eax
  jg     L120
L20:
  lea    -0x1(%rax),%edx
  mov    $0x3e7,%r12d
  lea    0x60(%rsp),%r13
  movl   $0x0,0x60(%rsp)
  movslq %edx,%rdx
  movl   $0x0,0x60(%rsp,%rdx,4)
  mov    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L182:
  cmp    %ebp,%edx
  je     L155
  lea    0x10(%rsp),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <next_generation@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L58
  lea    -0x1(%rdx),%ecx
  mov    %rbx,%rax
  xor    %ebp,%ebp
  lea    0x14(%rsp,%rcx,4),%rcx
  nopl   (%rax)
L57:
  cmpl   $0x1,(%rax)
  adc    $0x0,%ebp
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L57
  sub    $0x1,%r12d
  jne    L182
L155:
  lea    D39(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L90:
  cmp    $0x1,%edx
  je     L196
L136:
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jle    L20
L120:
  mov    (%r14,%rbx,4),%edx
  test   %edx,%edx
  jne    L90
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L136
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %ebp,%ebp
  sub    $0x1,%r12d
  jne    L182
  jmp    L155
L196:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  jmp    L136
L95:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D59
data_type: string
name: retrieve_data
arguments: label: D49
data_type: string
name: retrieve_data
arguments: label: D52
data_type: string
name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D23: Enter length for the cell chain(you can only use a number between 0 and 20):


tool: D10: %d

tool: D59: Enter a number(you can only use 1 or 0):


tool: D49: *

tool: D52: .

tool: D39: 


tool: D13: Error! Cell chain must start and end with 0.


assistant: ```c
int main() {
  int currentGen[20], nextGen[20], n, i, j, temp;
  do {
    printf("Enter length for the cell chain(you can only use a number between 0 and 20):\n");
    scanf("%d", &n);
  } while (n < 0 || n > 20);
  for (i = 0; i < n; i++) {
    do {
      printf("Enter a number(you can only use 1 or 0):\n");
      scanf("%d", &currentGen[i]);
    } while (currentGen[i] != 0 && currentGen[i] != 1);
  }
  if (currentGen[0] != 0 || currentGen[n - 1] != 0) {
    printf("Error! Cell chain must start and end with 0.\n");
    return 0;
  }
  for (i = 0; i < n; i++) {
    if (currentGen[i] == 0) {
      printf(".");
    } else if (currentGen[i] == 1) {
      printf("*");
    }
  }
  nextGen[0] = 0;
  nextGen[n - 1] = 0;
  for (i = 0; i < 999 && temp != n; i++) {
    next_generation(currentGen, nextGen, n);
    for (j = 0, temp = 0; j < n; j++) {
      if (currentGen[j] == 0)
        temp++;
    }
  }
  printf("\n");
  return 0;
}
```