ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<parity6>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  movzbl %dl,%eax
  add    %eax,%r8d
  cmp    %rcx,%rdi
  jne    L18
  mov    %r8d,%eax
  ret
  nop
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity6(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    asm("mov         %[x], %%edx     \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "movzx       %%dl, %[x]      \n\t"
        : [x] "+r"(x)
        :
        : "edx");
    result += x;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parity6>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  shr    $0x8,%edx
  xor    %edx,%eax
  setnp  %dl
  movzbl %dl,%eax
  add    %eax,%r8d
  cmp    %rcx,%rdi
  jne    L16
  mov    %r8d,%eax
  ret
  nop
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity6(unsigned *array, int len) {
  int i, j, val, result = 0;
  unsigned x;
  for (i = 0; i < len; i++) {
    x = array[i];
    asm("mov         %[x], %%edx     \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "shr           $8, %%edx     \n\t"
        "xor        %%edx, %[x]      \n\t"
        "setnp        %%dl           \n\t"
        "movzx       %%dl, %[x]      \n\t"
        : [x] "+r"(x)
        :
        : "edx");
    result += x;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xff0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x40,-0xfe0(%rbp)
  movl   $0x8,-0xfdc(%rbp)
  movl   $0xd8,-0xfd8(%rbp)
  movl   $0x200,-0xfd4(%rbp)
  movl   $0x1b,-0xfd0(%rbp)
  movl   $0x2d9,-0xfcc(%rbp)
  movl   $0x0,-0xfc8(%rbp)
  movl   $0x1,-0xfc4(%rbp)
  movl   $0x157,-0xfc0(%rbp)
  movl   $0x7d,-0xfbc(%rbp)
  lea    -0xfb0(%rbp),%rax
  mov    $0xf9c,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0xfe4(%rbp)
  jmp    L20
L33:
  mov    -0xfe4(%rbp),%eax
  cltq
  mov    -0xfe0(%rbp,%rax,4),%eax
  cltq
  movl   $0x1,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfe4(%rbp)
L20:
  cmpl   $0x9,-0xfe4(%rbp)
  jle    L33
  movl   $0x0,-0xfe4(%rbp)
  jmp    L12
L39:
  mov    -0xfe4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L1
  mov    -0xfe4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  addl   $0x1,-0xfe4(%rbp)
L12:
  cmpl   $0x3e6,-0xfe4(%rbp)
  jle    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: %-4d

assistant: ```c
int main() {
  int count[999], i;
  int array[10] = {64, 8, 216, 512, 27, 729, 0, 1, 343, 125};
  memset(count, 0, 999 * sizeof(int));
  for (i = 0; i < 10; ++i)
    count[array[i]] = 1;
  for (i = 0; i < 999; ++i)
    if (count[i] == 1)
      printf("%-4d", i);
  putchar('\n');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfd8(%rsp)
  xor    %eax,%eax
  movl   $0x40,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0xd8,0x8(%rsp)
  movl   $0x200,0xc(%rsp)
  movl   $0x1b,0x10(%rsp)
  movl   $0x2d9,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x157,0x20(%rsp)
  movl   $0x7d,0x24(%rsp)
  lea    0x30(%rsp),%rdi
  mov    $0xf9c,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rsp,%rax
  lea    0x28(%rsp),%rcx
L12:
  movslq (%rax),%rdx
  movl   $0x1,0x30(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L12
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
  jmp    L48
L29:
  add    $0x1,%rbx
  cmp    $0x3e7,%rbx
  je     L15
L48:
  mov    %ebx,%esi
  cmpl   $0x1,0x30(%rsp,%rbx,4)
  jne    L29
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L29
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0xfe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %-4d

assistant: ```c
int main() {
  int count[999], i;
  int array[10] = {64, 8, 216, 512, 27, 729, 0, 1, 343, 125};
  memset(count, 0, 999 * sizeof(int));
  for (i = 0; i < 10; ++i)
    count[array[i]] = 1;
  for (i = 0; i < 999; ++i)
    if (count[i] == 1)
      printf("%-4d", i);
  putchar('\n');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xf9c,%edx
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0xfe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfd8(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbp
  movl   $0x8,0x4(%rsp)
  movabs $0x200000000d8,%rax
  mov    %rax,0x8(%rsp)
  mov    %rbp,%rdi
  movabs $0x2d90000001b,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x7d00000157,%rax
  mov    %rax,0x20(%rsp)
  call   <memset@plt>
  lea    0x4(%rsp),%rdx
  lea    0x28(%rsp),%rcx
  mov    $0x40,%eax
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L1:
  movslq (%rdx),%rax
  add    $0x4,%rdx
L62:
  movl   $0x1,0x30(%rsp,%rax,4)
  cmp    %rcx,%rdx
  jne    L1
  xor    %ebx,%ebx
  lea    D8(%rip),%r12
  jmp    L51
  nop
L48:
  add    $0x1,%rbx
  cmp    $0x3e7,%rbx
  je     L57
L51:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%esi
  jne    L48
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3e7,%rbx
  jne    L51
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xfe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: %-4d

assistant: ```c
int main() {
  int count[999], i;
  int array[10] = {64, 8, 216, 512, 27, 729, 0, 1, 343, 125};
  memset(count, 0, 999 * sizeof(int));
  for (i = 0; i < 10; ++i)
    count[array[i]] = 1;
  for (i = 0; i < 999; ++i)
    if (count[i] == 1)
      printf("%-4d", i);
  putchar('\n');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xf9c,%edx
  xor    %esi,%esi
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D18(%rip),%rax
  movl   $0x1,0x100(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x360(%rsp)
  movl   $0x1,0x800(%rsp)
  movl   $0x1,0x6c(%rsp)
  movl   $0x1,0xb64(%rsp)
  mov    %rax,(%rsp)
  movl   $0x1,0x55c(%rsp)
  movl   $0x1,0x1f4(%rsp)
  jmp    L21
  nopl   0x0(%rax)
L45:
  add    $0x1,%rbx
  cmp    $0x3e7,%rbx
  je     L27
L21:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  mov    %ebx,%esi
  jne    L45
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3e7,%rbx
  jne    L21
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: byte[8]

tool: D16: %-4d

tool: {"D18": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int count[999], i;
  int array[10] = {64, 8, 216, 512, 27, 729, 0, 1, 343, 125};
  memset(count, 0, 999 * sizeof(int));
  for (i = 0; i < 10; ++i)
    count[array[i]] = 1;
  for (i = 0; i < 999; ++i)
    if (count[i] == 1)
      printf("%-4d", i);
  putchar('\n');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <f@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: TESTING

assistant: ```c
int g(void) {
  f("TESTING");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: TESTING

assistant: ```c
int g(void) {
  f("TESTING");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: TESTING

assistant: ```c
int g(void) {
  f("TESTING");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: TESTING

assistant: ```c
int g(void) {
  f("TESTING");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lla2ecef>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  movsd  %xmm2,0x20(%rsp)
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  movsd  D5(%rip),%xmm3
  mulsd  %xmm3,%xmm0
  movsd  D0(%rip),%xmm2
  divsd  %xmm2,%xmm0
  movsd  %xmm0,0x10(%rsp)
  fldl   0x10(%rsp)
  mulsd  %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  movsd  %xmm1,0x10(%rsp)
  fldl   0x10(%rsp)
  fstpt  0x30(%rsp)
  fldl   0x20(%rsp)
  fstpt  0x40(%rsp)
  fld    %st(0)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <sin@plt>
  fld    %st(0)
  fmull  0xe46(%rip)        # 2010 <_fini+0xd68>
  fmulp  %st,%st(1)
  fld1
  fsubp  %st,%st(1)
  fnstcw 0x7e(%rsp)
  movzwl 0x7e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x7c(%rsp)
  fldcw  0x7c(%rsp)
  fistpl 0x20(%rsp)
  fldcw  0x7e(%rsp)
  mov    0x20(%rsp),%edi
  call   <sqrt@plt>
  fdivrs 0xe1c(%rip)        # 2018 <_fini+0xd70>
  fldt   0x40(%rsp)
  fxch   %st(1)
  fld    %st(0)
  fstpt  0x60(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x60(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <cos@plt>
  fldt   0x50(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%r12)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x30(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <sin@plt>
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fstpl  0x0(%rbp)
  fldt   0xda9(%rip)        # 2020 <_fini+0xd78>
  fldt   0x60(%rsp)
  fmulp  %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <sin@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%rbx)
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: f64
name: unpack_data
arguments: label: D0
datatype: byte[8]

tool: D5: 3.141592653589793

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void lla2ecef(double lat, double lng, double alt, double *ecef_x, double *ecef_y, double *ecef_z) {
  long double n;
  long double a = 6378137.0;
  long double esqr = 6.69437999014e-3;
  long double s;
  long double llat, llng, lalt;
  llat = lat * 3.14159265358979323846 / 180;
  llng = lng * 3.14159265358979323846 / 180;
  lalt = alt;
  s = sin(llat);
  n = a / sqrt(1 - esqr * s * s);
  *ecef_x = (double)((n + lalt) * cos(llat) * cos(llng));
  *ecef_y = (double)((n + lalt) * cos(llat) * sin(llng));
  *ecef_z = (double)((n * (1 - esqr) + lalt) * sin(llat));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lla2ecef>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  add    $0xffffffffffffff80,%rsp
  movsd  D1(%rip),%xmm3
  movsd  %xmm2,0x20(%rsp)
  movsd  D3(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  divsd  %xmm2,%xmm0
  divsd  %xmm2,%xmm1
  movsd  %xmm0,0x10(%rsp)
  fldl   0x10(%rsp)
  movsd  %xmm1,0x10(%rsp)
  fldl   0x10(%rsp)
  fstpt  0x30(%rsp)
  fldl   0x20(%rsp)
  fstpt  0x40(%rsp)
  fld    %st(0)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <sin@plt>
  fnstcw 0x7e(%rsp)
  fld    %st(0)
  fmull  0xe3b(%rip)        # 2010 <_fini+0xd60>
  movzwl 0x7e(%rsp),%eax
  or     $0xc,%ah
  fmulp  %st,%st(1)
  mov    %ax,0x7c(%rsp)
  fld1
  fsubp  %st,%st(1)
  fldcw  0x7c(%rsp)
  fistpl 0x20(%rsp)
  fldcw  0x7e(%rsp)
  mov    0x20(%rsp),%edi
  call   <sqrt@plt>
  fdivrs 0xe15(%rip)        # 2018 <_fini+0xd68>
  fldt   0x40(%rsp)
  fadd   %st(1),%st
  fxch   %st(1)
  fstpt  0x60(%rsp)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x60(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <cos@plt>
  fldt   0x50(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%r12)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x30(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <sin@plt>
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fstpl  0x0(%rbp)
  fldt   0xda4(%rip)        # 2020 <_fini+0xd70>
  fldt   0x60(%rsp)
  fmulp  %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <sin@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%rbx)
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type: f64
name: parse_data
arguments: label: D3
type: byte[8]

tool: D1: 3.141592653589793

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void lla2ecef(double lat, double lng, double alt, double *ecef_x, double *ecef_y, double *ecef_z) {
  long double n;
  long double a = 6378137.0;
  long double esqr = 6.69437999014e-3;
  long double s;
  long double llat, llng, lalt;
  llat = lat * 3.14159265358979323846 / 180;
  llng = lng * 3.14159265358979323846 / 180;
  lalt = alt;
  s = sin(llat);
  n = a / sqrt(1 - esqr * s * s);
  *ecef_x = (double)((n + lalt) * cos(llat) * cos(llng));
  *ecef_y = (double)((n + lalt) * cos(llat) * sin(llng));
  *ecef_z = (double)((n * (1 - esqr) + lalt) * sin(llat));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lla2ecef>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  add    $0xffffffffffffff80,%rsp
  movsd  D6(%rip),%xmm3
  movsd  %xmm2,0x20(%rsp)
  movsd  D9(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  divsd  %xmm2,%xmm0
  divsd  %xmm2,%xmm1
  movsd  %xmm0,0x10(%rsp)
  fldl   0x10(%rsp)
  movsd  %xmm1,0x10(%rsp)
  fldl   0x10(%rsp)
  fstpt  0x30(%rsp)
  fldl   0x20(%rsp)
  fstpt  0x40(%rsp)
  fld    %st(0)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <sin@plt>
  fnstcw 0x7e(%rsp)
  fld    %st(0)
  fmull  0xe3b(%rip)        # 2010 <_fini+0xd60>
  movzwl 0x7e(%rsp),%eax
  or     $0xc,%ah
  fmulp  %st,%st(1)
  mov    %ax,0x7c(%rsp)
  fld1
  fsubp  %st,%st(1)
  fldcw  0x7c(%rsp)
  fistpl 0x20(%rsp)
  fldcw  0x7e(%rsp)
  mov    0x20(%rsp),%edi
  call   <sqrt@plt>
  fdivrs 0xe15(%rip)        # 2018 <_fini+0xd68>
  fldt   0x40(%rsp)
  fadd   %st(1),%st
  fxch   %st(1)
  fstpt  0x60(%rsp)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x60(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <cos@plt>
  fldt   0x50(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%r12)
  call   <cos@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpt  0x30(%rsp)
  add    $0x20,%rsp
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <sin@plt>
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fstpl  0x0(%rbp)
  fldt   0xda4(%rip)        # 2020 <_fini+0xd70>
  fldt   0x60(%rsp)
  fmulp  %st,%st(1)
  fldt   0x40(%rsp)
  faddp  %st,%st(1)
  fstpt  0x20(%rsp)
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <sin@plt>
  fldt   0x30(%rsp)
  fmulp  %st,%st(1)
  fstpl  (%rbx)
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: f64
name: unpack_data
arguments: tag: D9
type_infered: byte[8]

tool: D6: 3.141592653589793

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
void lla2ecef(double lat, double lng, double alt, double *ecef_x, double *ecef_y, double *ecef_z) {
  long double n;
  long double a = 6378137.0;
  long double esqr = 6.69437999014e-3;
  long double s;
  long double llat, llng, lalt;
  llat = lat * 3.14159265358979323846 / 180;
  llng = lng * 3.14159265358979323846 / 180;
  lalt = alt;
  s = sin(llat);
  n = a / sqrt(1 - esqr * s * s);
  *ecef_x = (double)((n + lalt) * cos(llat) * cos(llng));
  *ecef_y = (double)((n + lalt) * cos(llat) * sin(llng));
  *ecef_z = (double)((n * (1 - esqr) + lalt) * sin(llat));
}
```
user: What is the c source code of the assembly code below?

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x430(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x418(%rbp)
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x414(%rbp)
  lea    -0x410(%rbp),%rdx
  mov    -0x418(%rbp),%ecx
  mov    -0x430(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <searchwrongchar@plt>
  movl   $0x0,-0x420(%rbp)
  jmp    L28
L24:
  mov    -0x418(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x41c(%rbp)
  jmp    L37
L20:
  subl   $0x1,-0x41c(%rbp)
L37:
  cmpl   $0x0,-0x41c(%rbp)
  js     L16
  mov    -0x41c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x430(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x420(%rbp),%ecx
  mov    -0x41c(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x428(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L20
L16:
  cmpl   $0x0,-0x41c(%rbp)
  jns    L2
  mov    -0x420(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x420(%rbp),%edx
  mov    -0x418(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x414(%rbp)
  jle    L8
  mov    -0x420(%rbp),%edx
  mov    -0x418(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  mov    -0x418(%rbp),%eax
  sub    %edx,%eax
  jmp    L66
L8:
  mov    $0x1,%eax
L66:
  add    %eax,-0x420(%rbp)
  jmp    L28
L2:
  mov    -0x420(%rbp),%edx
  mov    -0x41c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  mov    -0x41c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <findmax@plt>
  mov    %eax,%edx
  mov    -0x420(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x420(%rbp)
L28:
  mov    -0x414(%rbp),%eax
  sub    -0x418(%rbp),%eax
  cmp    %eax,-0x420(%rbp)
  jle    L24
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: D7: 

Pattern Matches at shift of = %d.

assistant: ```c
void search(char *text, char *pattern) {
  int patLen = strlen(pattern);
  int txtLen = strlen(text);
  int extra[256];
  searchwrongchar(pattern, patLen, extra);
  int s = 0;
  while (s <= (txtLen - patLen)) {
    int j = patLen - 1;
    while (j >= 0 && pattern[j] == text[s + j])
      j--;
    if (j < 0) {
      printf("\n\nPattern Matches at shift of = %d.", s);
      s += (s + patLen < txtLen) ? patLen - extra[text[s + patLen]] : 1;
    } else
      s += findmax(1, j - extra[text[s + j]]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<search>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %rsp,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <searchwrongchar@plt>
  mov    %r15d,%r14d
  sub    %r12d,%r14d
  js     L55
  mov    $0x0,%ebp
  jmp    L37
L89:
  test   %eax,%eax
  js     L59
  lea    0x0(%rbp,%rax,1),%eax
  cltq
  movsbq 0x0(%r13,%rax,1),%rax
  sub    (%rsp,%rax,4),%esi
  mov    $0x1,%edi
  call   <findmax@plt>
  add    %eax,%ebp
L26:
  cmp    %r14d,%ebp
  jg     L55
L37:
  mov    %r12d,%eax
  sub    $0x1,%eax
  js     L59
  cltq
  movslq %ebp,%rdx
  add    %r13,%rdx
L8:
  mov    %eax,%esi
  movzbl (%rdx,%rax,1),%ecx
  cmp    %cl,(%rbx,%rax,1)
  jne    L89
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L8
L59:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    (%r12,%rbp,1),%eax
  mov    $0x1,%edx
  cmp    %r15d,%eax
  jge    L80
  cltq
  movsbq 0x0(%r13,%rax,1),%rax
  mov    %r12d,%edx
  sub    (%rsp,%rax,4),%edx
L80:
  add    %edx,%ebp
  jmp    L26
L55:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: 

Pattern Matches at shift of = %d.

assistant: ```c
void search(char *text, char *pattern) {
  int patLen = strlen(pattern);
  int txtLen = strlen(text);
  int extra[256];
  searchwrongchar(pattern, patLen, extra);
  int s = 0;
  while (s <= (txtLen - patLen)) {
    int j = patLen - 1;
    while (j >= 0 && pattern[j] == text[s + j])
      j--;
    if (j < 0) {
      printf("\n\nPattern Matches at shift of = %d.", s);
      s += (s + patLen < txtLen) ? patLen - extra[text[s + patLen]] : 1;
    } else
      s += findmax(1, j - extra[text[s + j]]);
  }
}
```