ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<h_util_path_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L33
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L44
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rbp,%rbx,1)
  mov    %rbx,%r14
  mov    %eax,%r15d
  je     L9
  cmpb   $0x2f,0x0(%r13)
  jne    L3
L9:
  lea    0x1(%r14,%r15,1),%ecx
  mov    %ecx,%edi
  mov    %ecx,0xc(%rsp)
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
L47:
  mov    %r15d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movslq 0xc(%rsp),%rcx
  movb   $0x0,-0x1(%r12,%rcx,1)
L61:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  lea    0x2(%rbx,%rax,1),%ecx
  mov    %ecx,%edi
  mov    %ecx,0xc(%rsp)
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    $0x1,%edx
  lea    D5(%rip),%rsi
  call   <memcpy@plt>
  lea    0x1(%r12,%rbx,1),%rdi
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L44:
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %eax,%r13d
  mov    %ebx,%edi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L61
  nopl   0x0(%rax)
L33:
  xor    %r12d,%r12d
  jmp    L61
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: /

assistant: ```c
char *h_util_path_join(const char *p1, const char *p2) {
  if (p1 == NULL)
    return NULL;
  else if (p2 == NULL) {
    int len = strlen(p1) + 1;
    char *path = malloc(len);
    memcpy(path, p1, (len - 1) * sizeof(char));
    path[len - 1] = '\0';
    return path;
  }
  int len1 = strlen(p1);
  int len2 = strlen(p2);
  if (p1[len1 - 1] == '/' || p2[0] == '/') {
    int len = len1 + len2 + 1;
    char *path = malloc(len);
    memcpy(path, p1, len1);
    memcpy(path + len1, p2, len2);
    path[len - 1] = '\0';
    return path;
  } else {
    int len = len1 + len2 + 2;
    char *path = malloc(len);
    memcpy(path, p1, len1);
    memcpy(path + len1, "/", 1);
    memcpy(path + len1 + 1, p2, len2);
    path[len - 1] = '\0';
    return path;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h_util_path_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L63
  mov    %rdi,%rbp
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L64
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rbp,%rbx,1)
  mov    %rbx,%r14
  mov    %eax,%r15d
  je     L58
  cmpb   $0x2f,0x0(%r13)
  jne    L56
L58:
  lea    0x1(%r14,%r15,1),%ecx
  mov    %ecx,%edi
  mov    %ecx,0xc(%rsp)
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
L49:
  mov    %r15d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  movslq 0xc(%rsp),%rcx
  movb   $0x0,-0x1(%r12,%rcx,1)
L66:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  lea    0x2(%rbx,%rax,1),%ecx
  mov    %ecx,%edi
  mov    %ecx,0xc(%rsp)
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  call   <memcpy@plt>
  lea    0x1(%r12,%rbx,1),%rdi
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L64:
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %eax,%r13d
  mov    %ebx,%edi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
  jmp    L66
  nopl   0x0(%rax)
L63:
  xor    %r12d,%r12d
  jmp    L66
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: /

assistant: ```c
char *h_util_path_join(const char *p1, const char *p2) {
  if (p1 == NULL)
    return NULL;
  else if (p2 == NULL) {
    int len = strlen(p1) + 1;
    char *path = malloc(len);
    memcpy(path, p1, (len - 1) * sizeof(char));
    path[len - 1] = '\0';
    return path;
  }
  int len1 = strlen(p1);
  int len2 = strlen(p2);
  if (p1[len1 - 1] == '/' || p2[0] == '/') {
    int len = len1 + len2 + 1;
    char *path = malloc(len);
    memcpy(path, p1, len1);
    memcpy(path + len1, p2, len2);
    path[len - 1] = '\0';
    return path;
  } else {
    int len = len1 + len2 + 2;
    char *path = malloc(len);
    memcpy(path, p1, len1);
    memcpy(path + len1, "/", 1);
    memcpy(path + len1 + 1, p2, len2);
    path[len - 1] = '\0';
    return path;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  je     L1
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L1:
  nop
L6:
  cmpl   $0x1,-0x8(%rbp)
  jne    L28
  cmpl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a;
  int s;
  {
    a = 0;
    s = 1;
    if (a == 1) {
      goto ERROR1;
    ERROR1:;
    } else {
      a = 1;
    }
    if (a == 1) {
      if (s == 1) {
      } else {
        goto ERROR2;
      ERROR2:;
      }
    } else {
    }
    if (s == 1) {
    } else {
      goto ERROR3;
    ERROR3:;
    }
    return (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  int s;
  {
    a = 0;
    s = 1;
    if (a == 1) {
      goto ERROR1;
    ERROR1:;
    } else {
      a = 1;
    }
    if (a == 1) {
      if (s == 1) {
      } else {
        goto ERROR2;
      ERROR2:;
      }
    } else {
    }
    if (s == 1) {
    } else {
      goto ERROR3;
    ERROR3:;
    }
    return (0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  int s;
  {
    a = 0;
    s = 1;
    if (a == 1) {
      goto ERROR1;
    ERROR1:;
    } else {
      a = 1;
    }
    if (a == 1) {
      if (s == 1) {
      } else {
        goto ERROR2;
      ERROR2:;
      }
    } else {
    }
    if (s == 1) {
    } else {
      goto ERROR3;
    ERROR3:;
    }
    return (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a;
  int s;
  {
    a = 0;
    s = 1;
    if (a == 1) {
      goto ERROR1;
    ERROR1:;
    } else {
      a = 1;
    }
    if (a == 1) {
      if (s == 1) {
      } else {
        goto ERROR2;
      ERROR2:;
      }
    } else {
    }
    if (s == 1) {
    } else {
      goto ERROR3;
    ERROR3:;
    }
    return (0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L13
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L29
L13:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L31
L29:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L31:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string
name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D35
data_type: string
name: parse_data
arguments: tag: D24
data_type: string

tool: D3: Input a year: 

tool: D9: %d

tool: D35: %d is a leap year.

tool: D24: %d is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Input a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
    printf("%d is a leap year.", year);
  else
    printf("%d is not a leap year.", year);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L13
  mov    $0x64,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L23
L13:
  movslq %esi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%esi
  jne    L33
L23:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L33:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D21: Input a year: 

tool: D22: %d

tool: D17: %d is a leap year.

tool: D5: %d is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Input a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
    printf("%d is a leap year.", year);
  else
    printf("%d is not a leap year.", year);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L10
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L10
L14:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L14
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L24
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string

tool: D15: Input a year: 

tool: D19: %d

tool: D26: %d is a leap year.

tool: D17: %d is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Input a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
    printf("%d is a leap year.", year);
  else
    printf("%d is not a leap year.", year);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L4
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L4
L41:
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L41
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D28: Input a year: 

tool: D7: %d

tool: D37: %d is a leap year.

tool: D11: %d is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Input a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
    printf("%d is a leap year.", year);
  else
    printf("%d is not a leap year.", year);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__signbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <GET_HIGH_WORD@plt>
  mov    -0x8(%rbp),%rax
  shr    $0x3f,%rax
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int __signbit(double x) {
  int32_t hx;
  GET_HIGH_WORD(hx, x);
  return hx < 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__signbit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <GET_HIGH_WORD@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __signbit(double x) {
  int32_t hx;
  GET_HIGH_WORD(hx, x);
  return hx < 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__signbit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <GET_HIGH_WORD@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __signbit(double x) {
  int32_t hx;
  GET_HIGH_WORD(hx, x);
  return hx < 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__signbit>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <GET_HIGH_WORD@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __signbit(double x) {
  int32_t hx;
  GET_HIGH_WORD(hx, x);
  return hx < 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: %d 

assistant: ```c
void printArray(int arr[], int size) {
  int i;
  for (i = 0; i < size; i++)
    printf("%d ", arr[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D9(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: %d 

assistant: ```c
void printArray(int arr[], int size) {
  int i;
  for (i = 0; i < size; i++)
    printf("%d ", arr[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %d 

assistant: ```c
void printArray(int arr[], int size) {
  int i;
  for (i = 0; i < size; i++)
    printf("%d ", arr[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printArray>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d 

assistant: ```c
void printArray(int arr[], int size) {
  int i;
  for (i = 0; i < size; i++)
    printf("%d ", arr[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<recstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <recv@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L54
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L7
L54:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <recv@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L66
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  nop
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L7
L66:
  cmpl   $0x0,-0x14(%rbp)
  je     L56
  mov    -0x14(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L54
  jmp    L14
L56:
  nop
L14:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
L7:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string

tool: D5: recstr received string size: %d


tool: D23: recstr (malloc)

tool: D16: recstr

assistant: ```c
int recstr(int sockfd, char **str) {
  ssize_t numbytes = 0;
  int total = 0, rv = 0, size;
  recv(sockfd, &size, sizeof(size), 0);
  size = ntohl(size);
  printf("recstr received string size: %d\n", size);
  char *s = malloc(size);
  if (!s) {
    perror("recstr (malloc)");
    goto exit;
  }
  do {
    numbytes = recv(sockfd, s, size - total, 0);
    if (numbytes == -1) {
      perror("recstr");
      goto memory_cleanup;
    } else if (numbytes == 0) {
      break;
    }
    total += numbytes;
  } while (total < size);
  rv = total;
  *str = s;
  goto exit;
memory_cleanup:
  free(s);
exit:
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<recstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x4,%edx
  call   <recv@plt>
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,%esi
  mov    %eax,0x4(%rsp)
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L38
L32:
  mov    0x4(%rsp),%edx
  sub    %ebx,%edx
  mov    $0x0,%ecx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <recv@plt>
  cmp    $0xffffffff,%eax
  je     L67
  test   %eax,%eax
  je     L7
  add    %eax,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L32
L7:
  mov    %rbp,0x0(%r13)
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  lea    D29(%rip),%rdi
  call   <perror@plt>
  jmp    L8
L67:
  lea    D15(%rip),%rdi
  call   <perror@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L8
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D20: recstr received string size: %d


tool: D29: recstr (malloc)

tool: D15: recstr

assistant: ```c
int recstr(int sockfd, char **str) {
  ssize_t numbytes = 0;
  int total = 0, rv = 0, size;
  recv(sockfd, &size, sizeof(size), 0);
  size = ntohl(size);
  printf("recstr received string size: %d\n", size);
  char *s = malloc(size);
  if (!s) {
    perror("recstr (malloc)");
    goto exit;
  }
  do {
    numbytes = recv(sockfd, s, size - total, 0);
    if (numbytes == -1) {
      perror("recstr");
      goto memory_cleanup;
    } else if (numbytes == 0) {
      break;
    }
    total += numbytes;
  } while (total < size);
  rv = total;
  *str = s;
  goto exit;
memory_cleanup:
  free(s);
exit:
  return rv;
}
```