ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D105(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D120(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D79
type_guessed: string
name: parse_data
arguments: data_label: D69
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string
name: parse_data
arguments: data_label: D105
type_guessed: string
name: parse_data
arguments: data_label: D120
type_guessed: string
name: parse_data
arguments: data_label: D64
type_guessed: string
name: parse_data
arguments: data_label: D81
type_guessed: string
name: parse_data
arguments: data_label: D37
type_guessed: string
name: parse_data
arguments: data_label: D91
type_guessed: string
name: parse_data
arguments: data_label: D70
type_guessed: string

tool: D79: usage: sort-bench [<OPTIONS>] FILE 


tool: D69: 


tool: D11: options:


tool: D17:      --version:  version and legal information


tool: D105:     --help, -h:  usage information


tool: D120:             -v:  verbose


tool: D64:             -q:  quiet


tool: D81:             -l:  list algorithms


tool: D37:   -a ALGORITHM:  use a specific algorithm (default: lib_qsort)


tool: D91:      -t TRIALS:  perform a number of trials (default: 1)


tool: D70: FILE should contain a number of integers, one per line


assistant: ```c
void print_usage() {
  printf("usage: sort-bench [<OPTIONS>] FILE \n");
  printf("\n");
  printf("options:\n");
  printf("     --version:  version and legal information\n");
  printf("    --help, -h:  usage information\n");
  printf("            -v:  verbose\n");
  printf("            -q:  quiet\n");
  printf("            -l:  list algorithms\n");
  printf("  -a ALGORITHM:  use a specific algorithm (default: lib_qsort)\n");
  printf("     -t TRIALS:  perform a number of trials (default: 1)\n");
  printf("\n");
  printf("FILE should contain a number of integers, one per line\n");
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  push   %rbx
  lea    D95(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D96(%rip),%rdi
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D95
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D61
type: string
name: extract_symbolic_data
arguments: data_tag: D96
type: string
name: extract_symbolic_data
arguments: data_tag: D69
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D62
type: string
name: extract_symbolic_data
arguments: data_tag: D57
type: string
name: extract_symbolic_data
arguments: data_tag: D73
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string

tool: D95: usage: sort-bench [<OPTIONS>] FILE 


tool: D5: 


tool: D61: options:


tool: D96:      --version:  version and legal information


tool: D69:     --help, -h:  usage information


tool: D31:             -v:  verbose


tool: D62:             -q:  quiet


tool: D57:             -l:  list algorithms


tool: D73:   -a ALGORITHM:  use a specific algorithm (default: lib_qsort)


tool: D13:      -t TRIALS:  perform a number of trials (default: 1)


tool: D15: FILE should contain a number of integers, one per line


assistant: ```c
void print_usage() {
  printf("usage: sort-bench [<OPTIONS>] FILE \n");
  printf("\n");
  printf("options:\n");
  printf("     --version:  version and legal information\n");
  printf("    --help, -h:  usage information\n");
  printf("            -v:  verbose\n");
  printf("            -q:  quiet\n");
  printf("            -l:  list algorithms\n");
  printf("  -a ALGORITHM:  use a specific algorithm (default: lib_qsort)\n");
  printf("     -t TRIALS:  perform a number of trials (default: 1)\n");
  printf("\n");
  printf("FILE should contain a number of integers, one per line\n");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbp
  lea    D54(%rip),%rdi
  lea    D66(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D81(%rip),%rdi
  call   <printf@plt>
  lea    D76(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D54
data_type: string
name: read_data
arguments: tag: D66
data_type: string
name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D81
data_type: string
name: read_data
arguments: tag: D76
data_type: string
name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D79
data_type: string
name: read_data
arguments: tag: D91
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D36
data_type: string
name: read_data
arguments: tag: D73
data_type: string

tool: D54: usage: sort-bench [<OPTIONS>] FILE 


tool: D66: 


tool: D22: options:


tool: D81:      --version:  version and legal information


tool: D76:     --help, -h:  usage information


tool: D10:             -v:  verbose


tool: D79:             -q:  quiet


tool: D91:             -l:  list algorithms


tool: D6:   -a ALGORITHM:  use a specific algorithm (default: lib_qsort)


tool: D36:      -t TRIALS:  perform a number of trials (default: 1)


tool: D73: FILE should contain a number of integers, one per line


assistant: ```c
void print_usage() {
  printf("usage: sort-bench [<OPTIONS>] FILE \n");
  printf("\n");
  printf("options:\n");
  printf("     --version:  version and legal information\n");
  printf("    --help, -h:  usage information\n");
  printf("            -v:  verbose\n");
  printf("            -q:  quiet\n");
  printf("            -l:  list algorithms\n");
  printf("  -a ALGORITHM:  use a specific algorithm (default: lib_qsort)\n");
  printf("     -t TRIALS:  perform a number of trials (default: 1)\n");
  printf("\n");
  printf("FILE should contain a number of integers, one per line\n");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_usage>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D66(%rip),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D96(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type: string
name: extract_symbolic_data
arguments: label: D66
type: string
name: extract_symbolic_data
arguments: label: D96
type: string
name: extract_symbolic_data
arguments: label: D33
type: string
name: extract_symbolic_data
arguments: label: D35
type: string
name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D40
type: string
name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D25
type: string

tool: D15: usage: sort-bench [<OPTIONS>] FILE 


tool: D66: 


tool: D96: options:


tool: D33:      --version:  version and legal information


tool: D35:     --help, -h:  usage information


tool: D17:             -v:  verbose


tool: D40:             -q:  quiet


tool: D28:             -l:  list algorithms


tool: D14:   -a ALGORITHM:  use a specific algorithm (default: lib_qsort)


tool: D29:      -t TRIALS:  perform a number of trials (default: 1)


tool: D25: FILE should contain a number of integers, one per line


assistant: ```c
void print_usage() {
  printf("usage: sort-bench [<OPTIONS>] FILE \n");
  printf("\n");
  printf("options:\n");
  printf("     --version:  version and legal information\n");
  printf("    --help, -h:  usage information\n");
  printf("            -v:  verbose\n");
  printf("            -q:  quiet\n");
  printf("            -l:  list algorithms\n");
  printf("  -a ALGORITHM:  use a specific algorithm (default: lib_qsort)\n");
  printf("     -t TRIALS:  perform a number of trials (default: 1)\n");
  printf("\n");
  printf("FILE should contain a number of integers, one per line\n");
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_v_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L7:
  mov    -0x20(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x1,-0x8(%rbp)
  jbe    L7
  mov    -0x14(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rax,-0x38(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  add    %rax,0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L12:
  mov    -0x38(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x38(%rbp)
  mov    0x10(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,0x10(%rbp)
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_v_c(unsigned int from_i, unsigned int to_i, float *from_v, float *to_v, unsigned int n_colors, float *from_c, float *to_c) {
  from_v += from_i * 2;
  to_v += to_i * 2;
  for (unsigned int i = 0; i < 2; i++) {
    *to_v++ = *from_v++;
  }
  from_c += from_i * n_colors;
  to_c += to_i * n_colors;
  for (unsigned int i = 0; i < n_colors; i++) {
    *to_c++ = *from_c++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy_v_c>:
  endbr64
  mov    %esi,%eax
  mov    %rdx,%r10
  mov    %rcx,%rsi
  lea    (%rdi,%rdi,1),%edx
  mov    %edx,%edx
  lea    (%r10,%rdx,4),%rcx
  lea    (%rax,%rax,1),%edx
  mov    %edx,%edx
  lea    (%rsi,%rdx,4),%rdx
  movss  (%rcx),%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rcx),%xmm0
  movss  %xmm0,0x4(%rdx)
  imul   %r8d,%edi
  lea    (%r9,%rdi,4),%rcx
  imul   %r8d,%eax
  lea    0x0(,%rax,4),%rdx
  add    0x8(%rsp),%rdx
  test   %r8d,%r8d
  je     L9
  mov    %r8d,%r8d
  mov    $0x0,%eax
L17:
  movss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L17
L9:
  ret
```

assistant: ```c
void copy_v_c(unsigned int from_i, unsigned int to_i, float *from_v, float *to_v, unsigned int n_colors, float *from_c, float *to_c) {
  from_v += from_i * 2;
  to_v += to_i * 2;
  for (unsigned int i = 0; i < 2; i++) {
    *to_v++ = *from_v++;
  }
  from_c += from_i * n_colors;
  to_c += to_i * n_colors;
  for (unsigned int i = 0; i < n_colors; i++) {
    *to_c++ = *from_c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_v_c>:
  endbr64
  mov    %rdx,%r11
  lea    (%rdi,%rdi,1),%edx
  mov    %rcx,%r10
  mov    %esi,%eax
  imul   %r8d,%edi
  lea    (%r11,%rdx,4),%rcx
  movss  (%rcx),%xmm0
  imul   %r8d,%eax
  lea    (%rsi,%rsi,1),%edx
  lea    (%r10,%rdx,4),%rdx
  movss  %xmm0,(%rdx)
  movss  0x4(%rcx),%xmm0
  lea    (%r9,%rdi,4),%rcx
  movss  %xmm0,0x4(%rdx)
  lea    0x0(,%rax,4),%rdx
  add    0x8(%rsp),%rdx
  test   %r8d,%r8d
  je     L10
  mov    %r8d,%r8d
  xor    %eax,%eax
  nop
L13:
  movss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L13
L10:
  ret
```

assistant: ```c
void copy_v_c(unsigned int from_i, unsigned int to_i, float *from_v, float *to_v, unsigned int n_colors, float *from_c, float *to_c) {
  from_v += from_i * 2;
  to_v += to_i * 2;
  for (unsigned int i = 0; i < 2; i++) {
    *to_v++ = *from_v++;
  }
  from_c += from_i * n_colors;
  to_c += to_i * n_colors;
  for (unsigned int i = 0; i < n_colors; i++) {
    *to_c++ = *from_c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_v_c>:
  endbr64
  mov    %rdx,%r11
  lea    (%rdi,%rdi,1),%edx
  mov    %rcx,%r10
  mov    %esi,%eax
  imul   %r8d,%eax
  lea    (%r11,%rdx,4),%rcx
  movss  (%rcx),%xmm0
  lea    (%rsi,%rsi,1),%edx
  lea    (%r10,%rdx,4),%rdx
  movss  %xmm0,(%rdx)
  movss  0x4(%rcx),%xmm0
  mov    %edi,%ecx
  imul   %r8d,%ecx
  movss  %xmm0,0x4(%rdx)
  lea    0x0(,%rax,4),%rdx
  add    0x8(%rsp),%rdx
  shl    $0x2,%rcx
  lea    (%r9,%rcx,1),%rsi
  test   %r8d,%r8d
  je     L4
  lea    0x4(%r9,%rcx,1),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L48
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L48
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L2:
  movups (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L2
  mov    %r8d,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  shl    $0x2,%rax
  add    %rax,%rsi
  add    %rdx,%rax
  cmp    %ecx,%r8d
  je     L4
  movss  (%rsi),%xmm0
  lea    0x1(%rcx),%edx
  movss  %xmm0,(%rax)
  cmp    %edx,%r8d
  jbe    L4
  movss  0x4(%rsi),%xmm0
  add    $0x2,%ecx
  movss  %xmm0,0x4(%rax)
  cmp    %ecx,%r8d
  jbe    L4
  movss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rax)
  ret
  nopl   (%rax)
L48:
  mov    %r8d,%r8d
  xor    %eax,%eax
  nopl   (%rax)
L66:
  movss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L66
L4:
  ret
```

assistant: ```c
void copy_v_c(unsigned int from_i, unsigned int to_i, float *from_v, float *to_v, unsigned int n_colors, float *from_c, float *to_c) {
  from_v += from_i * 2;
  to_v += to_i * 2;
  for (unsigned int i = 0; i < 2; i++) {
    *to_v++ = *from_v++;
  }
  from_c += from_i * n_colors;
  to_c += to_i * n_colors;
  for (unsigned int i = 0; i < n_colors; i++) {
    *to_c++ = *from_c++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xlib_get_prec_from_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L19:
  mov    -0xc(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L28
  addq   $0x1,-0x8(%rbp)
L28:
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x3f,-0xc(%rbp)
  jbe    L19
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long xlib_get_prec_from_mask(unsigned long val) {
  unsigned long retval = 0;
  unsigned int cur_bit = 0;
  while (cur_bit < (sizeof(unsigned long) * 8)) {
    if ((val >> cur_bit) & 0x1) {
      retval++;
    }
    cur_bit++;
  }
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xlib_get_prec_from_mask>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%edx
L9:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rdx
  add    $0x1,%ecx
  cmp    $0x40,%ecx
  jne    L9
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long xlib_get_prec_from_mask(unsigned long val) {
  unsigned long retval = 0;
  unsigned int cur_bit = 0;
  while (cur_bit < (sizeof(unsigned long) * 8)) {
    if ((val >> cur_bit) & 0x1) {
      retval++;
    }
    cur_bit++;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xlib_get_prec_from_mask>:
  endbr64
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L0:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r8
  add    $0x1,%ecx
  cmp    $0x40,%ecx
  jne    L0
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long xlib_get_prec_from_mask(unsigned long val) {
  unsigned long retval = 0;
  unsigned int cur_bit = 0;
  while (cur_bit < (sizeof(unsigned long) * 8)) {
    if ((val >> cur_bit) & 0x1) {
      retval++;
    }
    cur_bit++;
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xlib_get_prec_from_mask>:
  endbr64
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L5:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r8
  add    $0x1,%ecx
  cmp    $0x40,%ecx
  jne    L5
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long xlib_get_prec_from_mask(unsigned long val) {
  unsigned long retval = 0;
  unsigned int cur_bit = 0;
  while (cur_bit < (sizeof(unsigned long) * 8)) {
    if ((val >> cur_bit) & 0x1) {
      retval++;
    }
    cur_bit++;
  }
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <first@plt>
  mov    $0x0,%eax
  call   <second@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  first();
  second();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <first@plt>
  mov    $0x0,%eax
  call   <second@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  first();
  second();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <first@plt>
  xor    %eax,%eax
  call   <second@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  first();
  second();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <first@plt>
  xor    %eax,%eax
  call   <second@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  first();
  second();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pick_fil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x4c8f8d29,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0x6b,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pick_fil() {
  int i;
  i = random() % 107;
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_fil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%edx
  cltq
  imul   $0x4c8f8d29,%rax,%rax
  sar    $0x25,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x6b,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pick_fil() {
  int i;
  i = random() % 107;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_fil>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x4c8f8d29,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rax
  sub    %ecx,%eax
  imul   $0x6b,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int pick_fil() {
  int i;
  i = random() % 107;
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pick_fil>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x4c8f8d29,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rax
  sub    %ecx,%eax
  imul   $0x6b,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int pick_fil() {
  int i;
  i = random() % 107;
  return (i);
}
```
user: What is the c source code of the assembly code below:

```asm
<EPINonBlockingReadStop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x28(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EPINonBlockingReadStop(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  (*((volatile unsigned long *)(ui32Base + 0x00000028 + ui32Offset))) = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EPINonBlockingReadStop>:
  endbr64
  shl    $0x4,%esi
  lea    0x28(%rsi,%rdi,1),%eax
  cltq
  movq   $0x0,(%rax)
  ret
```

assistant: ```c
void EPINonBlockingReadStop(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  (*((volatile unsigned long *)(ui32Base + 0x00000028 + ui32Offset))) = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EPINonBlockingReadStop>:
  endbr64
  shl    $0x4,%esi
  lea    0x28(%rsi,%rdi,1),%eax
  cltq
  movq   $0x0,(%rax)
  ret
```

assistant: ```c
void EPINonBlockingReadStop(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  (*((volatile unsigned long *)(ui32Base + 0x00000028 + ui32Offset))) = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninitvar_wmemset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <wmemset@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_wmemset(void) {
  wchar_t *cs;
  wchar_t c;
  size_t n;
  (void)wmemset(cs, c, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uninitvar_wmemset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <wmemset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_wmemset(void) {
  wchar_t *cs;
  wchar_t c;
  size_t n;
  (void)wmemset(cs, c, n);
}
```