user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L45
  nopl   (%rax)
L96:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L96
L45:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  lea    0x60(%rsp),%rbp
  xor    %ebx,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L51
  nopl   0x0(%rax)
L34:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L34
L51:
  mov    0x8(%rsp),%r9d
  lea    (%r9,%rcx,1),%r11d
  test   %r11d,%r11d
  jle    L22
  lea    -0x1(%r11),%r8d
  mov    %r11d,%r10d
  mov    $0x1,%eax
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0xb0(%rsp),%rbp
  nopl   0x0(%rax)
L86:
  mov    %eax,%edi
  cmp    %esi,%r9d
  jg     L31
  lea    0x1(%rdx),%ecx
  movslq %edx,%rdx
  mov    0x60(%rsp,%rdx,4),%edx
  mov    %edx,0xac(%rsp,%rax,4)
  cmp    %rax,%r10
  je     L43
  cltq
  movslq %ecx,%rcx
  lea    0x0(%rbp,%rax,4),%r9
  mov    %r8d,%eax
  lea    0x60(%rsp,%rcx,4),%rsi
  sub    %edi,%eax
  cmp    %r11d,%edi
  mov    %r9,%rdi
  lea    0x4(,%rax,4),%rdx
  mov    $0x4,%eax
  cmovge %rax,%rdx
  call   <memcpy@plt>
L43:
  xor    %ebx,%ebx
  lea    D18(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L121:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L121
L22:
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L111
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L31:
  movslq %esi,%rdi
  mov    0x10(%rsp,%rdi,4),%edi
  cmp    %edx,%ecx
  jle    L41
  movslq %edx,%rbx
  mov    0x60(%rsp,%rbx,4),%ebx
  cmp    %edi,%ebx
  jg     L41
  add    $0x1,%edx
  mov    %ebx,%edi
L70:
  mov    %edi,-0x4(%rbp,%rax,4)
  cmp    %rax,%r10
  je     L43
  add    $0x1,%rax
  jmp    L86
  nopl   (%rax)
L41:
  add    $0x1,%esi
  jmp    L70
L111:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string

tool: D9: %d

tool: D18: %d


assistant: ```c
int main() {
  int N1, N2;
  int A1[20], A2[20], ANS[2 * 20];
  int A1_index = 0, A2_index = 0, index_sum = 0;
  int i;
  scanf("%d", &N1);
  for (i = 0; i < N1; i++) {
    scanf("%d", &A1[i]);
  }
  scanf("%d", &N2);
  for (i = 0; i < N2; i++) {
    scanf("%d", &A2[i]);
  }
  while (index_sum < N1 + N2) {
    if (A1_index >= N1) {
      ANS[index_sum] = A2[A2_index];
      A2_index++;
      index_sum++;
    } else if (A2_index >= N2) {
      ANS[index_sum] = A1[A1_index];
      A1_index++;
      index_sum++;
    } else {
      if (A1[A1_index] < A2[A2_index]) {
        ANS[index_sum] = A1[A1_index];
        A1_index++;
        index_sum++;
      } else {
        ANS[index_sum] = A2[A2_index];
        A2_index++;
        index_sum++;
      }
    }
  }
  for (i = 0; i < N1 + N2; i++) {
    printf("%d\n", ANS[i]);
  }
  return 0;
}
```