ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dcl_rvc1@plt>
  xor    %eax,%eax
  call   <dcl_rvc2@plt>
  xor    %eax,%eax
  call   <dcl_rvc4@plt>
  xor    %eax,%eax
  call   <dcl_rvc8@plt>
  xor    %eax,%eax
  call   <dcl_rvs1@plt>
  xor    %eax,%eax
  call   <dcl_rvs2@plt>
  xor    %eax,%eax
  call   <dcl_rvs4@plt>
  xor    %eax,%eax
  call   <dcl_rvs8@plt>
  xor    %eax,%eax
  call   <dcl_rvi1@plt>
  xor    %eax,%eax
  call   <dcl_rvi2@plt>
  xor    %eax,%eax
  call   <dcl_rvi4@plt>
  xor    %eax,%eax
  call   <dcl_rvi8@plt>
  xor    %eax,%eax
  call   <dcl_rvll1@plt>
  xor    %eax,%eax
  call   <dcl_rvll2@plt>
  xor    %eax,%eax
  call   <dcl_rvll4@plt>
  xor    %eax,%eax
  call   <dcl_rvll8@plt>
  xor    %eax,%eax
  call   <dcl_rvf1@plt>
  xor    %eax,%eax
  call   <dcl_rvf2@plt>
  xor    %eax,%eax
  call   <dcl_rvf4@plt>
  xor    %eax,%eax
  call   <dcl_rvf8@plt>
  xor    %eax,%eax
  call   <dcl_rvd1@plt>
  xor    %eax,%eax
  call   <dcl_rvd2@plt>
  xor    %eax,%eax
  call   <dcl_rvd4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1310 <dcl_rvd8@plt>
```

assistant: ```c
void test_1(void) {
  dcl_rvc1();
  dcl_rvc2();
  dcl_rvc4();
  dcl_rvc8();
  dcl_rvs1();
  dcl_rvs2();
  dcl_rvs4();
  dcl_rvs8();
  dcl_rvi1();
  dcl_rvi2();
  dcl_rvi4();
  dcl_rvi8();
  dcl_rvll1();
  dcl_rvll2();
  dcl_rvll4();
  dcl_rvll8();
  dcl_rvf1();
  dcl_rvf2();
  dcl_rvf4();
  dcl_rvf8();
  dcl_rvd1();
  dcl_rvd2();
  dcl_rvd4();
  dcl_rvd8();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dcl_rvc1@plt>
  xor    %eax,%eax
  call   <dcl_rvc2@plt>
  xor    %eax,%eax
  call   <dcl_rvc4@plt>
  xor    %eax,%eax
  call   <dcl_rvc8@plt>
  xor    %eax,%eax
  call   <dcl_rvs1@plt>
  xor    %eax,%eax
  call   <dcl_rvs2@plt>
  xor    %eax,%eax
  call   <dcl_rvs4@plt>
  xor    %eax,%eax
  call   <dcl_rvs8@plt>
  xor    %eax,%eax
  call   <dcl_rvi1@plt>
  xor    %eax,%eax
  call   <dcl_rvi2@plt>
  xor    %eax,%eax
  call   <dcl_rvi4@plt>
  xor    %eax,%eax
  call   <dcl_rvi8@plt>
  xor    %eax,%eax
  call   <dcl_rvll1@plt>
  xor    %eax,%eax
  call   <dcl_rvll2@plt>
  xor    %eax,%eax
  call   <dcl_rvll4@plt>
  xor    %eax,%eax
  call   <dcl_rvll8@plt>
  xor    %eax,%eax
  call   <dcl_rvf1@plt>
  xor    %eax,%eax
  call   <dcl_rvf2@plt>
  xor    %eax,%eax
  call   <dcl_rvf4@plt>
  xor    %eax,%eax
  call   <dcl_rvf8@plt>
  xor    %eax,%eax
  call   <dcl_rvd1@plt>
  xor    %eax,%eax
  call   <dcl_rvd2@plt>
  xor    %eax,%eax
  call   <dcl_rvd4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1310 <dcl_rvd8@plt>
```

assistant: ```c
void test_1(void) {
  dcl_rvc1();
  dcl_rvc2();
  dcl_rvc4();
  dcl_rvc8();
  dcl_rvs1();
  dcl_rvs2();
  dcl_rvs4();
  dcl_rvs8();
  dcl_rvi1();
  dcl_rvi2();
  dcl_rvi4();
  dcl_rvi8();
  dcl_rvll1();
  dcl_rvll2();
  dcl_rvll4();
  dcl_rvll8();
  dcl_rvf1();
  dcl_rvf2();
  dcl_rvf4();
  dcl_rvf8();
  dcl_rvd1();
  dcl_rvd2();
  dcl_rvd4();
  dcl_rvd8();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<greeting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %rdi,-0x1a8(%rbp)
  mov    %rsi,-0x1b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rax
  mov    $0x190,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x1b0(%rbp),%rdx
  lea    -0x1a0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: Hi %s %s


assistant: ```c
greeting(char *temp1, char *temp2) {
  char name[400];
  memset(name, 0, 400);
  strcpy(name, temp2);
  printf("Hi %s %s\n", temp1, name);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<greeting>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x190,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: Hi %s %s


assistant: ```c
greeting(char *temp1, char *temp2) {
  char name[400];
  memset(name, 0, 400);
  strcpy(name, temp2);
  printf("Hi %s %s\n", temp1, name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<greeting>:
  endbr64
  push   %r13
  mov    $0x190,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: Hi %s %s


assistant: ```c
greeting(char *temp1, char *temp2) {
  char name[400];
  memset(name, 0, 400);
  strcpy(name, temp2);
  printf("Hi %s %s\n", temp1, name);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<greeting>:
  endbr64
  push   %r13
  mov    $0x190,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: Hi %s %s


assistant: ```c
greeting(char *temp1, char *temp2) {
  char name[400];
  memset(name, 0, 400);
  strcpy(name, temp2);
  printf("Hi %s %s\n", temp1, name);
}
```
user: Translate the below assembly code into C programming language:

```asm
<initDoubleMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <mCalloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L14:
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <mCalloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L29:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **initDoubleMatrix(int d) {
  int i, j;
  double **A;
  A = (double **)mCalloc(d, sizeof(double *));
  for (i = 0; i < d; i++) {
    A[i] = (double *)mCalloc(d, sizeof(double));
    for (j = 0; j < d; j++)
      A[i][j] = 0.0;
  }
  return (A);
}
```
user: What is the c source code of the assembly code below:

```asm
<initDoubleMatrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x8,%esi
  call   <mCalloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L1
  mov    %rax,%rbp
  mov    %r12d,%ebx
  shl    $0x3,%rbx
  lea    (%rbx,%rax,1),%r13
L14:
  mov    $0x8,%esi
  mov    %r12d,%edi
  call   <mCalloc@plt>
  mov    %rbp,%rcx
  mov    %rax,0x0(%rbp)
  mov    $0x0,%eax
L3:
  mov    (%rcx),%rdx
  movq   $0x0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rbx,%rax
  jne    L3
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L14
L1:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **initDoubleMatrix(int d) {
  int i, j;
  double **A;
  A = (double **)mCalloc(d, sizeof(double *));
  for (i = 0; i < d; i++) {
    A[i] = (double *)mCalloc(d, sizeof(double));
    for (j = 0; j < d; j++)
      A[i][j] = 0.0;
  }
  return (A);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<initDoubleMatrix>:
  endbr64
  push   %r14
  mov    $0x8,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  call   <mCalloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L17
  mov    %ebx,%ebp
  mov    %rax,%r14
  shl    $0x3,%rbp
  lea    0x0(%rbp,%rax,1),%r12
  nopl   (%rax)
L18:
  mov    $0x8,%esi
  mov    %ebx,%edi
  call   <mCalloc@plt>
  mov    %rax,(%r14)
  lea    (%rax,%rbp,1),%rdx
  nopl   0x0(%rax,%rax,1)
L13:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L18
L17:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **initDoubleMatrix(int d) {
  int i, j;
  double **A;
  A = (double **)mCalloc(d, sizeof(double *));
  for (i = 0; i < d; i++) {
    A[i] = (double *)mCalloc(d, sizeof(double));
    for (j = 0; j < d; j++)
      A[i][j] = 0.0;
  }
  return (A);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initDoubleMatrix>:
  endbr64
  push   %r15
  mov    $0x8,%esi
  mov    %edi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mCalloc@plt>
  mov    %rax,%r13
  test   %r15d,%r15d
  jle    L28
  mov    %rax,%r14
  mov    %r15d,%eax
  mov    %r15d,%ebx
  lea    0x0(%r13,%rax,8),%r12
  mov    %r15d,%eax
  and    $0xfffffffe,%ebx
  shr    %eax
  lea    -0x1(%rax),%ebp
  add    $0x1,%rbp
  shl    $0x4,%rbp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x8,%esi
  mov    %r15d,%edi
  call   <mCalloc@plt>
  cmp    $0x1,%r15d
  pxor   %xmm0,%xmm0
  mov    %rax,(%r14)
  je     L29
  mov    %rax,%rdx
  lea    0x0(%rbp,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L1:
  movups %xmm0,(%rdx)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jne    L1
  movslq %ebx,%rdx
  cmp    %ebx,%r15d
  je     L48
L59:
  movq   $0x0,(%rax,%rdx,8)
L48:
  add    $0x8,%r14
  cmp    %r12,%r14
  jne    L8
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L29:
  xor    %edx,%edx
  jmp    L59
```

assistant: ```c
double **initDoubleMatrix(int d) {
  int i, j;
  double **A;
  A = (double **)mCalloc(d, sizeof(double *));
  for (i = 0; i < d; i++) {
    A[i] = (double *)mCalloc(d, sizeof(double));
    for (j = 0; j < d; j++)
      A[i][j] = 0.0;
  }
  return (A);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<M605_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D10: M605_f(const char *s) is not yet implemented!


tool: D9: %s


assistant: ```c
int M605_f(char *s) {
  debug("M605_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<M605_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D5: M605_f(const char *s) is not yet implemented!


tool: D8: %s


assistant: ```c
int M605_f(char *s) {
  debug("M605_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<M605_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D12
data_type: string

tool: D7: M605_f(const char *s) is not yet implemented!


tool: D12: %s


assistant: ```c
int M605_f(char *s) {
  debug("M605_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<M605_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string

tool: D2: M605_f(const char *s) is not yet implemented!


tool: D14: %s


assistant: ```c
int M605_f(char *s) {
  debug("M605_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getData@plt>
  mov    $0x0,%eax
  call   <sortData@plt>
  mov    $0x0,%eax
  call   <printData@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  getData();
  sortData();
  printData();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getData@plt>
  mov    $0x0,%eax
  call   <sortData@plt>
  mov    $0x0,%eax
  call   <printData@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  getData();
  sortData();
  printData();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getData@plt>
  xor    %eax,%eax
  call   <sortData@plt>
  xor    %eax,%eax
  call   <printData@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  getData();
  sortData();
  printData();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getData@plt>
  xor    %eax,%eax
  call   <sortData@plt>
  xor    %eax,%eax
  call   <printData@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  getData();
  sortData();
  printData();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
L23:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2e,%eax
  jg     L42
  cmp    $0x2d,%eax
  jge    L26
  jmp    L58
L42:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L58
L26:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x18(%rbp),%rdx
  lea    (%rax,%rdx,1),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L62
L58:
  movl   $0x0,-0xc(%rbp)
L62:
  cmpq   $0xe,-0x8(%rbp)
  ja     L36
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
L36:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getnum(const char *strnote, size_t *startpointer, char *outstr) {
  size_t numcount = 0;
  bool reading = true;
  do {
    switch (strnote[*startpointer]) {
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
    case '0':
    case '.':
    case '-':
      outstr[numcount++] = strnote[(*startpointer)++];
      break;
    default:
      reading = false;
    }
  } while (numcount < 15 && reading);
  outstr[numcount] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<getnum>:
  endbr64
  mov    $0x0,%r8d
  jmp    L18
L28:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L49
L35:
  add    $0x1,%rcx
  mov    %rcx,(%rsi)
  lea    0x1(%r8),%rax
  movzbl (%r9),%ecx
  mov    %cl,(%rdx,%r8,1)
  cmp    $0xe,%rax
  ja     L0
  mov    %rax,%r8
L18:
  mov    (%rsi),%rcx
  lea    (%rdi,%rcx,1),%r9
  movzbl (%r9),%eax
  cmp    $0x2e,%al
  jg     L28
  cmp    $0x2c,%al
  jg     L35
L49:
  movb   $0x0,(%rdx,%r8,1)
  ret
L0:
  mov    %rax,%r8
  jmp    L49
```

assistant: ```c
void getnum(const char *strnote, size_t *startpointer, char *outstr) {
  size_t numcount = 0;
  bool reading = true;
  do {
    switch (strnote[*startpointer]) {
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
    case '0':
    case '.':
    case '-':
      outstr[numcount++] = strnote[(*startpointer)++];
      break;
    default:
      reading = false;
    }
  } while (numcount < 15 && reading);
  outstr[numcount] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getnum>:
  endbr64
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L46:
  mov    (%rsi),%rcx
  lea    (%rdi,%rcx,1),%r8
  movzbl (%r8),%eax
  cmp    $0x2e,%al
  jg     L47
  cmp    $0x2c,%al
  jg     L11
L42:
  movb   $0x0,(%rdx,%r9,1)
  ret
  nopl   0x0(%rax)
L47:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L42
L11:
  add    $0x1,%rcx
  lea    0x1(%r9),%rax
  mov    %rcx,(%rsi)
  movzbl (%r8),%ecx
  mov    %cl,(%rdx,%r9,1)
  cmp    $0xe,%rax
  ja     L18
  mov    %rax,%r9
  jmp    L46
  nopl   (%rax)
L18:
  mov    $0xf,%r9d
  movb   $0x0,(%rdx,%r9,1)
  ret
```

assistant: ```c
void getnum(const char *strnote, size_t *startpointer, char *outstr) {
  size_t numcount = 0;
  bool reading = true;
  do {
    switch (strnote[*startpointer]) {
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
    case '0':
    case '.':
    case '-':
      outstr[numcount++] = strnote[(*startpointer)++];
      break;
    default:
      reading = false;
    }
  } while (numcount < 15 && reading);
  outstr[numcount] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getnum>:
  endbr64
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rsi),%rcx
  lea    (%rdi,%rcx,1),%r8
  movzbl (%r8),%eax
  cmp    $0x2e,%al
  jg     L25
  cmp    $0x2c,%al
  jg     L18
L39:
  movb   $0x0,(%rdx,%r9,1)
  ret
  nopl   0x0(%rax)
L25:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L39
L18:
  add    $0x1,%rcx
  lea    0x1(%r9),%rax
  mov    %rcx,(%rsi)
  movzbl (%r8),%ecx
  mov    %cl,(%rdx,%r9,1)
  cmp    $0xe,%rax
  ja     L15
  mov    %rax,%r9
  jmp    L2
  nopl   (%rax)
L15:
  mov    $0xf,%r9d
  movb   $0x0,(%rdx,%r9,1)
  ret
```

assistant: ```c
void getnum(const char *strnote, size_t *startpointer, char *outstr) {
  size_t numcount = 0;
  bool reading = true;
  do {
    switch (strnote[*startpointer]) {
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
    case '0':
    case '.':
    case '-':
      outstr[numcount++] = strnote[(*startpointer)++];
      break;
    default:
      reading = false;
    }
  } while (numcount < 15 && reading);
  outstr[numcount] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<odd_ones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x10,%eax
  xor    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x4,%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x2,%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shr    %eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int odd_ones(unsigned x) {
  unsigned p16 = (x >> 16) ^ x;
  unsigned p8 = (p16 >> 8) ^ p16;
  unsigned p4 = (p8 >> 4) ^ p8;
  unsigned p2 = (p4 >> 2) ^ p4;
  unsigned p1 = (p2 >> 1) ^ p2;
  return !!(p1 & 1u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<odd_ones>:
  endbr64
  mov    %edi,%eax
  shr    $0x10,%eax
  xor    %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    %eax
  xor    %edx,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int odd_ones(unsigned x) {
  unsigned p16 = (x >> 16) ^ x;
  unsigned p8 = (p16 >> 8) ^ p16;
  unsigned p4 = (p8 >> 4) ^ p8;
  unsigned p2 = (p4 >> 2) ^ p4;
  unsigned p1 = (p2 >> 1) ^ p2;
  return !!(p1 & 1u);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<odd_ones>:
  endbr64
  mov    %edi,%eax
  shr    $0x10,%eax
  xor    %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    %eax
  xor    %edx,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int odd_ones(unsigned x) {
  unsigned p16 = (x >> 16) ^ x;
  unsigned p8 = (p16 >> 8) ^ p16;
  unsigned p4 = (p8 >> 4) ^ p8;
  unsigned p2 = (p4 >> 2) ^ p4;
  unsigned p1 = (p2 >> 1) ^ p2;
  return !!(p1 & 1u);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<odd_ones>:
  endbr64
  mov    %edi,%eax
  shr    $0x10,%eax
  xor    %edi,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    %eax
  xor    %edx,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int odd_ones(unsigned x) {
  unsigned p16 = (x >> 16) ^ x;
  unsigned p8 = (p16 >> 8) ^ p16;
  unsigned p4 = (p8 >> 4) ^ p8;
  unsigned p2 = (p4 >> 2) ^ p4;
  unsigned p1 = (p2 >> 1) ^ p2;
  return !!(p1 & 1u);
}
```
user: What is the c source code of the assembly code below?

```asm
<wspr_ascii_to_alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  jne    L33
  mov    $0x1a,%eax
  jmp    L16
L33:
  cmpb   $0x40,-0x4(%rbp)
  jle    L15
  cmpb   $0x5a,-0x4(%rbp)
  jg     L15
  movzbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L16
L15:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t wspr_ascii_to_alpha(uint8_t c) {
  if (c == ' ') {
    return 26;
  }
  if (c >= 'A' && c <= 'Z') {
    return c - 'A';
  }
  return 0;
}
```