ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r12d
  xor    0x4(%rsp),%r12d
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebp
  mov    $0x8000,%ebx
  lea    D39(%rip),%r13
  jmp    L3
L16:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  sar    %ebx
  add    $0x1,%ebp
  cmp    $0x11,%ebp
  je     L25
L3:
  test   %ebx,%r12d
  jne    L16
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D39
type_guessed: string

tool: D7: Please enter two integers: 

tool: D6: %d %d

tool: D0: The following bits are the same
: 

tool: D39: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Please enter two integers: ");
  int i1, i2;
  scanf("%d %d", &i1, &i2);
  int orEd = (i1 ^ i2);
  printf("The following bits are the same\n: ");
  for (int i = 32768, j = 1; i > 0; i /= 2, j++) {
    if (!(orEd & i)) {
      printf("%d ", j);
    }
  }
  putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D39(%rip),%rdi
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0x8000,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  mov    (%rsp),%r12d
  xor    0x4(%rsp),%r12d
  call   <printf@plt>
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  sar    %ebp
  cmp    $0x11,%ebx
  je     L36
L22:
  test   %ebp,%r12d
  jne    L34
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  sar    %ebp
  cmp    $0x11,%ebx
  jne    L22
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D39
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string

tool: D39: Please enter two integers: 

tool: D0: %d 

tool: D11: %d %d

tool: D4: The following bits are the same
: 

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Please enter two integers: ");
  int i1, i2;
  scanf("%d %d", &i1, &i2);
  int orEd = (i1 ^ i2);
  printf("The following bits are the same\n: ");
  for (int i = 32768, j = 1; i > 0; i /= 2, j++) {
    if (!(orEd & i)) {
      printf("%d ", j);
    }
  }
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<exec_rcr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,%r14d
  movl   $0x0,0x28(%rsp)
  mov    %edi,%r15d
  mov    %edx,%r12d
  jmp    L98
L30:
  addl   $0x1,0x18(%rsp)
  mov    0x18(%rsp),%eax
  cmp    $0x2,%eax
  je     L36
L35:
  cmpl   $0x0,0x18(%rsp)
  setne  %al
  movzbl %al,%eax
  shl    $0x6,%eax
  or     0x24(%rsp),%eax
  mov    %eax,0x1c(%rsp)
  movl   $0x0,0x10(%rsp)
L65:
  cmpl   $0x0,0x10(%rsp)
  setne  %al
  movzbl %al,%eax
  shl    $0x4,%eax
  or     0x1c(%rsp),%eax
  mov    %eax,0x14(%rsp)
  mov    $0x0,%r14d
L13:
  test   %r14d,%r14d
  setne  %al
  movzbl %al,%eax
  or     0x14(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%ebp
L71:
  test   %ebp,%ebp
  setne  %bl
  movzbl %bl,%ebx
  shl    $0x2,%ebx
  or     0xc(%rsp),%ebx
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15d,%edi
  call   <exec_rcrl@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15d,%edi
  call   <exec_rcrw@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <exec_rcrb@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15d,%edi
  call   <exec_rcrl@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15d,%edi
  call   <exec_rcrw@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <exec_rcrb@plt>
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  jne    L71
  add    $0x1,%r14d
  cmp    $0x2,%r14d
  jne    L13
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  cmp    $0x2,%eax
  jne    L65
  jmp    L30
L36:
  mov    %r13d,%r14d
  addl   $0x1,0x20(%rsp)
  mov    0x20(%rsp),%eax
  cmp    $0x2,%eax
  je     L83
L90:
  cmpl   $0x0,0x20(%rsp)
  setne  %al
  movzbl %al,%eax
  shl    $0x7,%eax
  or     0x2c(%rsp),%eax
  mov    %eax,0x24(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    %r14d,%r13d
  jmp    L35
L83:
  addl   $0x1,0x28(%rsp)
  mov    0x28(%rsp),%eax
  cmp    $0x2,%eax
  je     L67
L98:
  cmpl   $0x0,0x28(%rsp)
  setne  %al
  movzbl %al,%eax
  shl    $0xb,%eax
  mov    %eax,0x2c(%rsp)
  movl   $0x0,0x20(%rsp)
  jmp    L90
L67:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void exec_rcr(int s2, int s0, int s1) {
  int o, s, z, a, c, p, flags_in;
  for (o = 0; o < 2; o++) {
    for (s = 0; s < 2; s++) {
      for (z = 0; z < 2; z++) {
        for (a = 0; a < 2; a++) {
          for (c = 0; c < 2; c++) {
            for (p = 0; p < 2; p++) {
              flags_in = (o ? 0x0800 : 0) | (s ? 0x0080 : 0) | (z ? 0x0040 : 0) | (a ? 0x0010 : 0) | (c ? 0x0001 : 0) | (p ? 0x0004 : 0);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
            }
          }
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exec_rcr>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movl   $0x0,0x2c(%rsp)
L100:
  mov    0x2c(%rsp),%eax
  movl   $0x0,0x24(%rsp)
  shl    $0xb,%eax
  mov    %eax,0x28(%rsp)
L17:
  mov    0x24(%rsp),%eax
  movl   $0x0,0x1c(%rsp)
  shl    $0x7,%eax
  or     0x28(%rsp),%eax
  mov    %eax,0x20(%rsp)
L116:
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x14(%rsp)
  shl    $0x6,%eax
  or     0x20(%rsp),%eax
  mov    %eax,0x18(%rsp)
L82:
  mov    0x14(%rsp),%r12d
  xor    %ebp,%ebp
  xor    %r9d,%r9d
  mov    %ebp,0xc(%rsp)
  shl    $0x4,%r12d
  or     0x18(%rsp),%r12d
  mov    %r12d,0x10(%rsp)
  mov    0x10(%rsp),%ebx
  or     %ebp,%ebx
  mov    %r9d,%ebp
L115:
  lea    0x0(,%rbp,4),%r12d
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  or     %ebx,%r12d
  mov    %r12d,%ecx
  call   <exec_rcrl@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <exec_rcrw@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <exec_rcrb@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <exec_rcrl@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  mov    %r12d,%ecx
  call   <exec_rcrw@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <exec_rcrb@plt>
  cmp    $0x1,%ebp
  jne    L97
  mov    0xc(%rsp),%ebp
  cmp    $0x1,%ebp
  je     L43
  mov    0x10(%rsp),%ebx
  mov    $0x1,%ebp
  xor    %r9d,%r9d
  mov    %ebp,0xc(%rsp)
  or     %ebp,%ebx
  mov    %r9d,%ebp
  jmp    L115
  nopl   0x0(%rax)
L97:
  mov    $0x1,%ebp
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L43:
  cmpl   $0x1,0x14(%rsp)
  je     L40
  movl   $0x1,0x14(%rsp)
  jmp    L82
  nopl   0x0(%rax)
L40:
  cmpl   $0x1,0x1c(%rsp)
  je     L58
  movl   $0x1,0x1c(%rsp)
  jmp    L116
  nopl   0x0(%rax)
L58:
  cmpl   $0x1,0x24(%rsp)
  je     L20
  movl   $0x1,0x24(%rsp)
  jmp    L17
  nopl   0x0(%rax)
L20:
  cmpl   $0x1,0x2c(%rsp)
  je     L25
  movl   $0x1,0x2c(%rsp)
  jmp    L100
  nopl   0x0(%rax)
L25:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void exec_rcr(int s2, int s0, int s1) {
  int o, s, z, a, c, p, flags_in;
  for (o = 0; o < 2; o++) {
    for (s = 0; s < 2; s++) {
      for (z = 0; z < 2; z++) {
        for (a = 0; a < 2; a++) {
          for (c = 0; c < 2; c++) {
            for (p = 0; p < 2; p++) {
              flags_in = (o ? 0x0800 : 0) | (s ? 0x0080 : 0) | (z ? 0x0040 : 0) | (a ? 0x0010 : 0) | (c ? 0x0001 : 0) | (p ? 0x0004 : 0);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
            }
          }
        }
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exec_rcr>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movl   $0x0,0x2c(%rsp)
L4:
  mov    0x2c(%rsp),%eax
  movl   $0x0,0x24(%rsp)
  shl    $0xb,%eax
  mov    %eax,0x28(%rsp)
L6:
  mov    0x24(%rsp),%eax
  movl   $0x0,0x1c(%rsp)
  shl    $0x7,%eax
  or     0x28(%rsp),%eax
  mov    %eax,0x20(%rsp)
L27:
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x14(%rsp)
  shl    $0x6,%eax
  or     0x20(%rsp),%eax
  mov    %eax,0x18(%rsp)
L109:
  mov    0x14(%rsp),%r12d
  xor    %ebp,%ebp
  xor    %r9d,%r9d
  mov    %ebp,0xc(%rsp)
  shl    $0x4,%r12d
  or     0x18(%rsp),%r12d
  mov    %r12d,0x10(%rsp)
  mov    0x10(%rsp),%ebx
  or     %ebp,%ebx
  mov    %r9d,%ebp
L13:
  lea    0x0(,%rbp,4),%r12d
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  or     %ebx,%r12d
  mov    %r12d,%ecx
  call   <exec_rcrl@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <exec_rcrw@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <exec_rcrb@plt>
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <exec_rcrl@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  mov    %r12d,%ecx
  call   <exec_rcrw@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <exec_rcrb@plt>
  cmp    $0x1,%ebp
  jne    L3
  mov    0xc(%rsp),%ebp
  cmp    $0x1,%ebp
  je     L17
  mov    0x10(%rsp),%ebx
  mov    $0x1,%ebp
  xor    %r9d,%r9d
  mov    %ebp,0xc(%rsp)
  or     %ebp,%ebx
  mov    %r9d,%ebp
  jmp    L13
  nopl   0x0(%rax)
L3:
  mov    $0x1,%ebp
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L17:
  cmpl   $0x1,0x14(%rsp)
  je     L52
  movl   $0x1,0x14(%rsp)
  jmp    L109
  nopl   0x0(%rax)
L52:
  cmpl   $0x1,0x1c(%rsp)
  je     L111
  movl   $0x1,0x1c(%rsp)
  jmp    L27
  nopl   0x0(%rax)
L111:
  cmpl   $0x1,0x24(%rsp)
  je     L114
  movl   $0x1,0x24(%rsp)
  jmp    L6
  nopl   0x0(%rax)
L114:
  cmpl   $0x1,0x2c(%rsp)
  je     L26
  movl   $0x1,0x2c(%rsp)
  jmp    L4
  nopl   0x0(%rax)
L26:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void exec_rcr(int s2, int s0, int s1) {
  int o, s, z, a, c, p, flags_in;
  for (o = 0; o < 2; o++) {
    for (s = 0; s < 2; s++) {
      for (z = 0; z < 2; z++) {
        for (a = 0; a < 2; a++) {
          for (c = 0; c < 2; c++) {
            for (p = 0; p < 2; p++) {
              flags_in = (o ? 0x0800 : 0) | (s ? 0x0080 : 0) | (z ? 0x0040 : 0) | (a ? 0x0010 : 0) | (c ? 0x0001 : 0) | (p ? 0x0004 : 0);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
              exec_rcrl(s2, s0, s1, flags_in);
              exec_rcrw(s2, s0, s1, flags_in);
              exec_rcrb(s0, s1, flags_in);
            }
          }
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0xa,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,-0x8(%rbp)
  cmp    %eax,%edx
  jge    L5
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  jmp    L7
L5:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
L7:
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xa,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,-0xc(%rbp)
  mov    %edx,%esi
  mov    %eax,%edi
  call   <menor@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: menor = %d, a = %d y b = %d


assistant: ```c
main() {
  int m = 0, a = 10, b = 20;
  m = ((a--) < (b--)) ? (a--) : (b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
  a = 10, b = 20;
  m = menor(a--, b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x13,%ecx
  mov    $0x8,%edx
  mov    $0x9,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <menor@plt>
  mov    %eax,%esi
  mov    $0x13,%ecx
  mov    $0x9,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: menor = %d, a = %d y b = %d


assistant: ```c
main() {
  int m = 0, a = 10, b = 20;
  m = ((a--) < (b--)) ? (a--) : (b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
  a = 10, b = 20;
  m = menor(a--, b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x13,%ecx
  mov    $0x8,%edx
  mov    $0x9,%esi
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <menor@plt>
  mov    %rbp,%rdi
  mov    $0x13,%ecx
  mov    $0x9,%edx
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: menor = %d, a = %d y b = %d


assistant: ```c
main() {
  int m = 0, a = 10, b = 20;
  m = ((a--) < (b--)) ? (a--) : (b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
  a = 10, b = 20;
  m = menor(a--, b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x13,%ecx
  mov    $0x8,%edx
  mov    $0x9,%esi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <menor@plt>
  mov    %rbp,%rdi
  mov    $0x13,%ecx
  mov    $0x9,%edx
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: menor = %d, a = %d y b = %d


assistant: ```c
main() {
  int m = 0, a = 10, b = 20;
  m = ((a--) < (b--)) ? (a--) : (b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
  a = 10, b = 20;
  m = menor(a--, b--);
  printf("menor = %d, a = %d y b = %d\n", m, a, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cleanMemory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void cleanMemory(char **map, char **tmp_map, int side_len) {
  int i = 0;
  int j = 0;
  for (i = 0; i < side_len + 2; ++i) {
    free(map[i]);
    free(tmp_map[i]);
  }
  free(map);
  free(tmp_map);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cleanMemory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  cmp    $0xffffffff,%edx
  jl     L9
  lea    0x1(%rdx),%r13d
  mov    $0x0,%ebx
L4:
  mov    (%r12,%rbx,8),%rdi
  call   <free@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r13,%rax
  jne    L4
L9:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void cleanMemory(char **map, char **tmp_map, int side_len) {
  int i = 0;
  int j = 0;
  for (i = 0; i < side_len + 2; ++i) {
    free(map[i]);
    free(tmp_map[i]);
  }
  free(map);
  free(tmp_map);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cleanMemory>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edx
  jl     L6
  lea    0x1(%rdx),%r12d
  xor    %ebx,%ebx
  nop
L2:
  mov    0x0(%r13,%rbx,8),%rdi
  call   <free@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%r12
  jne    L2
L6:
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void cleanMemory(char **map, char **tmp_map, int side_len) {
  int i = 0;
  int j = 0;
  for (i = 0; i < side_len + 2; ++i) {
    free(map[i]);
    free(tmp_map[i]);
  }
  free(map);
  free(tmp_map);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cleanMemory>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edx
  jl     L19
  lea    0x1(%rdx),%r12d
  xor    %ebx,%ebx
  nop
L5:
  mov    0x0(%r13,%rbx,8),%rdi
  call   <free@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %rax,%r12
  jne    L5
L19:
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void cleanMemory(char **map, char **tmp_map, int side_len) {
  int i = 0;
  int j = 0;
  for (i = 0; i < side_len + 2; ++i) {
    free(map[i]);
    free(tmp_map[i]);
  }
  free(map);
  free(tmp_map);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <foo@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
g(long long i) {
  if (i % 2)
    foo();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  test   $0x1,%dil
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
g(long long i) {
  if (i % 2)
    foo();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<g>:
  endbr64
  and    $0x1,%edi
  jne    L9
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
g(long long i) {
  if (i % 2)
    foo();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<g>:
  endbr64
  and    $0x1,%edi
  jne    L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
g(long long i) {
  if (i % 2)
    foo();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L1:
  mov    $0xa000,%edi
  call   <malloc@plt>
  mov    %eax,%edi
  call   <free@plt>
  addl   $0x1,-0xc(%rbp)
L24:
  cmpl   $0x1869f,-0xc(%rbp)
  jle    L1
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L29:
  mov    $0xa000,%esi
  mov    $0x0,%edi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xc350,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x9c40,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x1869f,-0xc(%rbp)
  jle    L29
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  void *p;
  for (i = 0; i < 100000; i++)
    free(malloc(40960));
  for (i = 0; i < 100000; i++) {
    p = realloc(NULL, 40960);
    p = realloc(p, 50000);
    p = realloc(p, 40000);
    p = realloc(p, 0);
    assert(!p);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x186a0,%ebx
L17:
  mov    $0xa000,%edi
  call   <malloc@plt>
  mov    %eax,%edi
  call   <free@plt>
  sub    $0x1,%ebx
  jne    L17
  mov    $0x186a0,%ebx
L10:
  mov    $0xa000,%esi
  mov    $0x0,%edi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    $0xc350,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    $0x9c40,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    $0x0,%esi
  call   <realloc@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  void *p;
  for (i = 0; i < 100000; i++)
    free(malloc(40960));
  for (i = 0; i < 100000; i++) {
    p = realloc(NULL, 40960);
    p = realloc(p, 50000);
    p = realloc(p, 40000);
    p = realloc(p, 0);
    assert(!p);
  }
  return 0;
}
```