ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dtrsm_l_u_n_n_3l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L36
  cmpl   $0x0,-0x18(%rbp)
  je     L36
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L25:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L48
L26:
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x24(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L67:
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x24(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L67
  subl   $0x1,-0x4(%rbp)
L48:
  cmpl   $0x0,-0x4(%rbp)
  jns    L26
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L25
  jmp    L33
L36:
  nop
L33:
  pop    %rbp
  ret
```

assistant: ```c
void dtrsm_l_u_n_n_3l(int m, int n, double *A, int lda, double *B, int ldb) {
  if (m == 0 || n == 0)
    return;
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (k = m - 1; k >= 0; k--) {
      B[k + ldb * j] /= A[k + lda * k];
      for (i = 0; i < k; i++) {
        B[i + ldb * j] -= B[k + ldb * j] * A[i + lda * k];
      }
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dtrsm_l_u_n_n_3l>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x1c(%rsp)
  mov    %esi,-0x28(%rsp)
  mov    %r9d,-0x24(%rsp)
  test   %edi,%edi
  je     L26
  mov    %edi,%ebx
  mov    %ecx,%eax
  mov    %r8,%r14
  test   %esi,%esi
  jle    L26
  mov    %ecx,%ebp
  not    %ebp
  movslq %ebp,%rbp
  shl    $0x3,%rbp
  lea    -0x1(%rdi),%ecx
  mov    %ecx,%esi
  imul   %eax,%esi
  movslq %esi,%rsi
  movslq %ecx,%rcx
  add    %rsi,%rcx
  lea    (%rdx,%rcx,8),%rdi
  mov    %rdi,-0x18(%rsp)
  neg    %eax
  cltq
  shl    $0x3,%rax
  mov    %rax,-0x30(%rsp)
  lea    (%rdx,%rsi,8),%rax
  mov    %rax,-0x10(%rsp)
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    -0x1(%rbx),%eax
  mov    %eax,-0x20(%rsp)
  cltq
  mov    %rax,-0x8(%rsp)
  lea    0x8(%r8),%r12
  jmp    L45
L20:
  test   %r8d,%r8d
  jns    L57
L6:
  add    $0x1,%r13d
  add    -0x24(%rsp),%r15d
  cmp    %r13d,-0x28(%rsp)
  je     L26
L45:
  cmpl   $0x0,-0x20(%rsp)
  js     L6
  movslq %r15d,%r11
  mov    -0x8(%rsp),%rax
  add    %r11,%rax
  lea    (%r14,%rax,8),%rdi
  mov    -0x1c(%rsp),%eax
  lea    -0x2(%rax),%r8d
  lea    (%r14,%r11,8),%rbx
  mov    -0x10(%rsp),%r10
  mov    -0x18(%rsp),%r9
L60:
  mov    %rdi,%rcx
  movsd  (%rdi),%xmm0
  divsd  (%r9),%xmm0
  movsd  %xmm0,(%rdi)
  lea    0x1(%r8),%eax
  test   %eax,%eax
  jle    L20
  mov    %r8d,%eax
  add    %r11,%rax
  lea    (%r12,%rax,8),%rsi
  mov    %r10,%rdx
  mov    %rbx,%rax
L58:
  movsd  (%rcx),%xmm1
  mulsd  (%rdx),%xmm1
  movsd  (%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  jne    L58
L57:
  sub    $0x8,%rdi
  add    %rbp,%r9
  sub    $0x1,%r8d
  add    -0x30(%rsp),%r10
  jmp    L60
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dtrsm_l_u_n_n_3l(int m, int n, double *A, int lda, double *B, int ldb) {
  if (m == 0 || n == 0)
    return;
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (k = m - 1; k >= 0; k--) {
      B[k + ldb * j] /= A[k + lda * k];
      for (i = 0; i < k; i++) {
        B[i + ldb * j] -= B[k + ldb * j] * A[i + lda * k];
      }
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dtrsm_l_u_n_n_3l>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,-0x24(%rsp)
  mov    %r9d,-0x20(%rsp)
  test   %edi,%edi
  je     L29
  test   %esi,%esi
  jle    L29
  lea    -0x1(%rdi),%ebx
  mov    %ecx,%eax
  mov    %ecx,%ebp
  mov    %r8,%r14
  mov    %ebx,%ecx
  mov    %ebx,-0x1c(%rsp)
  movslq %ebx,%rbx
  not    %ebp
  imul   %eax,%ecx
  neg    %eax
  mov    %rbx,-0x10(%rsp)
  movslq %ebp,%rbp
  movslq %eax,%r8
  shl    $0x3,%rbp
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  shl    $0x3,%r8
  lea    0x8(%r14),%r12
  movslq %ecx,%rcx
  lea    (%rbx,%rcx,1),%rsi
  lea    (%rdx,%rcx,8),%rax
  lea    (%rdx,%rsi,8),%rbx
  mov    %rax,-0x18(%rsp)
  mov    %rbx,-0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L39:
  mov    -0x1c(%rsp),%esi
  test   %esi,%esi
  js     L10
  mov    -0x10(%rsp),%rax
  movslq %r15d,%r11
  mov    -0x18(%rsp),%r10
  mov    -0x8(%rsp),%rdi
  lea    (%r14,%r11,8),%rbx
  add    %r11,%rax
  lea    (%r14,%rax,8),%rcx
  mov    %esi,%eax
  nopl   0x0(%rax,%rax,1)
L63:
  movsd  (%rcx),%xmm0
  lea    -0x1(%rax),%r9d
  divsd  (%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  test   %eax,%eax
  jle    L12
  mov    %r9d,%eax
  mov    %r10,%rdx
  add    %r11,%rax
  lea    (%r12,%rax,8),%rsi
  mov    %rbx,%rax
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  (%rcx),%xmm0
L32:
  mulsd  (%rdx),%xmm0
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  add    $0x8,%rdx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L3
L89:
  sub    $0x8,%rcx
  add    %rbp,%rdi
  add    %r8,%r10
  mov    %r9d,%eax
  jmp    L63
  nopl   0x0(%rax)
L12:
  test   %r9d,%r9d
  jns    L89
L10:
  add    $0x1,%r13d
  add    -0x20(%rsp),%r15d
  cmp    %r13d,-0x24(%rsp)
  jne    L39
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dtrsm_l_u_n_n_3l(int m, int n, double *A, int lda, double *B, int ldb) {
  if (m == 0 || n == 0)
    return;
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (k = m - 1; k >= 0; k--) {
      B[k + ldb * j] /= A[k + lda * k];
      for (i = 0; i < k; i++) {
        B[i + ldb * j] -= B[k + ldb * j] * A[i + lda * k];
      }
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isalphanum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
  cmpb   $0x40,-0x4(%rbp)
  jle    L43
  cmpb   $0x5a,-0x4(%rbp)
  jle    L10
L43:
  cmpb   $0x5f,-0x4(%rbp)
  jne    L1
L10:
  mov    $0x1,%eax
  jmp    L11
L1:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int isalphanum(char c) {
  c = toupper(c);
  return isdigit(c) || ('A' <= c && c <= 'Z') || c == '_';
}
```
user: What is the c source code of the assembly code below:

```asm
<isalphanum>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  movsbl %al,%edi
  call   <isdigit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L0
  lea    -0x41(%rbx),%eax
  cmp    $0x19,%al
  setbe  %al
  cmp    $0x5f,%bl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L0:
  pop    %rbx
  ret
```

assistant: ```c
int isalphanum(char c) {
  c = toupper(c);
  return isdigit(c) || ('A' <= c && c <= 'Z') || c == '_';
}
```
user: What is the c source code of the assembly code below:

```asm
<isalphanum>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%edi
  mov    %edi,%ebx
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L4
  lea    -0x41(%rbx),%eax
  cmp    $0x19,%al
  setbe  %al
  cmp    $0x5f,%bl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L4:
  pop    %rbx
  ret
```

assistant: ```c
int isalphanum(char c) {
  c = toupper(c);
  return isdigit(c) || ('A' <= c && c <= 'Z') || c == '_';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isalphanum>:
  endbr64
  push   %rbx
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%edi
  mov    %edi,%ebx
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L1
  lea    -0x41(%rbx),%eax
  cmp    $0x19,%al
  setbe  %al
  cmp    $0x5f,%bl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L1:
  pop    %rbx
  ret
```

assistant: ```c
int isalphanum(char c) {
  c = toupper(c);
  return isdigit(c) || ('A' <= c && c <= 'Z') || c == '_';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ldrstdrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  leave
  ret
```

assistant: ```c
void *ldrstdrealloc(void *mem, void *ptr, size_t ob, size_t nb) {
  (void)mem;
  (void)ob;
  return realloc(ptr, nb);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ldrstdrealloc>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rcx,%rsi
  call   <realloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *ldrstdrealloc(void *mem, void *ptr, size_t ob, size_t nb) {
  (void)mem;
  (void)ob;
  return realloc(ptr, nb);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ldrstdrealloc>:
  endbr64
  mov    %rsi,%rdi
  mov    %rcx,%rsi
  jmp    1050 <realloc@plt>
```

assistant: ```c
void *ldrstdrealloc(void *mem, void *ptr, size_t ob, size_t nb) {
  (void)mem;
  (void)ob;
  return realloc(ptr, nb);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ldrstdrealloc>:
  endbr64
  mov    %rsi,%rdi
  mov    %rcx,%rsi
  jmp    1050 <realloc@plt>
```

assistant: ```c
void *ldrstdrealloc(void *mem, void *ptr, size_t ob, size_t nb) {
  (void)mem;
  (void)ob;
  return realloc(ptr, nb);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gps_deg_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <modf@plt>
  imul   $0x3c,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  D45(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  imul   $0x64,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x48(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x34(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x38(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x34(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D44(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x20(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  movsd  D3(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <round@plt>
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D34
type_infered: f64
name: retrieve_data
arguments: data_label: D44
type_infered: f64
name: retrieve_data
arguments: data_label: D3
type_infered: byte[8]

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D34: 1000000

tool: D44: 60

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x20,0xac,0x40]}

assistant: ```c
double gps_deg_dec(double deg_point) {
  double ddeg;
  double sec = modf(deg_point, &ddeg) * 60;
  int deg = (int)(ddeg / 100);
  int min = (int)(deg_point - (deg * 100));
  double absdlat = round(deg * 1000000.);
  double absmlat = round(min * 1000000.);
  double absslat = round(sec * 1000000.);
  return round(absdlat + (absmlat / 60) + (absslat / 3600)) / 1000000;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gps_deg_dec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <modf@plt>
  mov    %eax,%ebp
  movsd  (%rsp),%xmm0
  divsd  D45(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  mulsd  D36(%rip),%xmm0
  call   <round@plt>
  mov    %eax,%r13d
  imul   $0x64,%r12d,%r12d
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D36(%rip),%xmm0
  call   <round@plt>
  mov    %eax,%ebx
  imul   $0x3c,%ebp,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D36(%rip),%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  divsd  D9(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D2(%rip),%xmm1
  addsd  %xmm1,%xmm0
  call   <round@plt>
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D45
type_infered: byte[8]
name: disassemble_data
arguments: tag: D36
type_infered: f64
name: disassemble_data
arguments: tag: D9
type_infered: f64
name: disassemble_data
arguments: tag: D2
type_infered: byte[8]

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D36: 1000000

tool: D9: 60

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x20,0xac,0x40]}

assistant: ```c
double gps_deg_dec(double deg_point) {
  double ddeg;
  double sec = modf(deg_point, &ddeg) * 60;
  int deg = (int)(ddeg / 100);
  int min = (int)(deg_point - (deg * 100));
  double absdlat = round(deg * 1000000.);
  double absmlat = round(min * 1000000.);
  double absslat = round(sec * 1000000.);
  return round(absdlat + (absmlat / 60) + (absslat / 3600)) / 1000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gps_deg_dec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <modf@plt>
  movsd  0x10(%rsp),%xmm0
  divsd  D55(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  pxor   %xmm0,%xmm0
  mov    %eax,%ebx
  imul   $0x3c,%ebx,%ebx
  cvtsi2sd %ebp,%xmm0
  mulsd  D11(%rip),%xmm0
  imul   $0x64,%ebp,%ebp
  call   <round@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %ebp,%xmm0
  mov    %eax,%r12d
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvttsd2si %xmm1,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D11(%rip),%xmm0
  mov    %eax,%ebp
  call   <round@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm1
  cvtsi2sd %ebp,%xmm0
  divsd  D5(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D33(%rip),%xmm1
  addsd  %xmm1,%xmm0
  call   <round@plt>
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sub    %eax,%edx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %edx,%xmm0
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D55
type: byte[8]
name: parse_data
arguments: tag: D11
type: f64
name: parse_data
arguments: tag: D5
type: f64
name: parse_data
arguments: tag: D33
type: byte[8]

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D11: 1000000

tool: D5: 60

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x20,0xac,0x40]}

assistant: ```c
double gps_deg_dec(double deg_point) {
  double ddeg;
  double sec = modf(deg_point, &ddeg) * 60;
  int deg = (int)(ddeg / 100);
  int min = (int)(deg_point - (deg * 100));
  double absdlat = round(deg * 1000000.);
  double absmlat = round(min * 1000000.);
  double absslat = round(sec * 1000000.);
  return round(absdlat + (absmlat / 60) + (absslat / 3600)) / 1000000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gps_deg_dec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <modf@plt>
  movsd  0x10(%rsp),%xmm0
  divsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  pxor   %xmm0,%xmm0
  mov    %eax,%ebx
  imul   $0x3c,%ebx,%ebx
  cvtsi2sd %ebp,%xmm0
  mulsd  D27(%rip),%xmm0
  imul   $0x64,%ebp,%ebp
  call   <round@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %ebp,%xmm0
  mov    %eax,%r12d
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvttsd2si %xmm1,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D27(%rip),%xmm0
  call   <round@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D27(%rip),%xmm0
  mov    %eax,%ebp
  call   <round@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm1
  cvtsi2sd %ebp,%xmm0
  divsd  D15(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  D20(%rip),%xmm1
  addsd  %xmm1,%xmm0
  call   <round@plt>
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  sub    %eax,%edx
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %edx,%xmm0
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
data_type: byte[8]
name: disassemble_data
arguments: data_label: D27
data_type: f64
name: disassemble_data
arguments: data_label: D15
data_type: f64
name: disassemble_data
arguments: data_label: D20
data_type: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D27: 1000000

tool: D15: 60

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x20,0xac,0x40]}

assistant: ```c
double gps_deg_dec(double deg_point) {
  double ddeg;
  double sec = modf(deg_point, &ddeg) * 60;
  int deg = (int)(ddeg / 100);
  int min = (int)(deg_point - (deg * 100));
  double absdlat = round(deg * 1000000.);
  double absmlat = round(min * 1000000.);
  double absslat = round(sec * 1000000.);
  return round(absdlat + (absmlat / 60) + (absslat / 3600)) / 1000000;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<outofstock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <lprcat@plt>
  mov    $0x0,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  call   <nap@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: 
Sorry, but we are out of that item.

assistant: ```c
void outofstock() {
  lprcat("\nSorry, but we are out of that item.");
  lflush();
  nap(2200);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<outofstock>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <lprcat@plt>
  mov    $0x0,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  call   <nap@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: 
Sorry, but we are out of that item.

assistant: ```c
void outofstock() {
  lprcat("\nSorry, but we are out of that item.");
  lflush();
  nap(2200);
}
```
user: Translate the below assembly code into C programming language:

```asm
<outofstock>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <lprcat@plt>
  xor    %eax,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  add    $0x8,%rsp
  jmp    1070 <nap@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: 
Sorry, but we are out of that item.

assistant: ```c
void outofstock() {
  lprcat("\nSorry, but we are out of that item.");
  lflush();
  nap(2200);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<outofstock>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <lprcat@plt>
  xor    %eax,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  add    $0x8,%rsp
  jmp    1070 <nap@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: 
Sorry, but we are out of that item.

assistant: ```c
void outofstock() {
  lprcat("\nSorry, but we are out of that item.");
  lflush();
  nap(2200);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ct_get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
struct timespec ct_get_time() {
  struct timespec ret_val;
  clock_gettime(CLOCK_MONOTONIC, &ret_val);
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ct_get_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec ct_get_time() {
  struct timespec ret_val;
  clock_gettime(CLOCK_MONOTONIC, &ret_val);
  return ret_val;
}
```
user: What is the c source code of the assembly code below?

```asm
<ct_get_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec ct_get_time() {
  struct timespec ret_val;
  clock_gettime(CLOCK_MONOTONIC, &ret_val);
  return ret_val;
}
```