ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<Encode_Hexa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    %edx,%r15d
  mov    %rcx,%rbp
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%r12
  cmpb   $0x0,(%rdi)
  jne    L35
L11:
  mov    %r13,%rdi
  call   <String_Needs_Encoding@plt>
  mov    %eax,%r14d
  movb   $0x58,0x0(%rbp)
  lea    0x30(%rax),%eax
  mov    %al,0x1(%rbp)
  lea    0x3(%rbp),%rbx
  movb   $0x5f,0x2(%rbp)
L32:
  test   %r14d,%r14d
  jne    L87
  mov    %r13,%rdx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%rbx
L58:
  test   %r15d,%r15d
  jns    L69
L18:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <String_Needs_Encoding@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,0xc(%rsp)
  mov    %r13,%rdi
  call   <String_Needs_Encoding@plt>
  mov    %eax,%r14d
  movb   $0x58,0x0(%rbp)
  mov    %ebx,%ecx
  lea    (%rbx,%rbx,1),%eax
  or     %r14d,%eax
  add    $0x30,%eax
  mov    %al,0x1(%rbp)
  lea    0x3(%rbp),%rbx
  movb   $0x5f,0x2(%rbp)
  cmp    $0x1,%ecx
  jne    L38
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%rbx
  jmp    L32
L38:
  cmpl   $0x2,0xc(%rsp)
  jne    L32
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <Encode_String@plt>
  movb   $0x5f,(%rax)
  lea    0x2(%rax),%rbx
  movb   $0x5f,0x1(%rax)
  jmp    L32
L87:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <Encode_String@plt>
  mov    %rax,%rbx
  jmp    L58
L69:
  mov    %r15d,%edx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%rbx
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D13: %s

tool: D2: %s__

tool: D7: __a%d

assistant: ```c
char *Encode_Hexa(char *module, char *pred, int arity, char *str) {
  int module_encode = (module == NULL || *module == '\0') ? 0 : String_Needs_Encoding(module) + 1;
  int pred_encode = String_Needs_Encoding(pred);
  *str++ = 'X';
  *str++ = '0' + ((module_encode << 1) | pred_encode);
  *str++ = '_';
  if (module_encode == 1)
    str += sprintf(str, "%s__", module);
  else if (module_encode == 2) {
    str = Encode_String(module, str);
    *str++ = '_';
    *str++ = '_';
  }
  if (pred_encode == 0)
    str += sprintf(str, "%s", pred);
  else
    str = Encode_String(pred, str);
  if (arity >= 0)
    str += sprintf(str, "__a%d", arity);
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Encode_Hexa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  lea    0x3(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L86
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r14
  jne    L57
L86:
  mov    %r15,%rdi
  call   <String_Needs_Encoding@plt>
  movb   $0x58,(%r12)
  mov    %eax,%ebx
  lea    0x30(%rax),%eax
  movb   $0x5f,0x2(%r12)
  mov    %al,0x1(%r12)
L19:
  test   %ebx,%ebx
  jne    L58
  mov    %r15,%rdx
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  lea    0x0(%rbp,%rax,1),%r12
L83:
  test   %r13d,%r13d
  js     L15
  mov    %r12,%rdi
  mov    %r13d,%edx
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%r12
L15:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L58:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <Encode_String@plt>
  mov    %rax,%r12
  jmp    L83
L57:
  call   <String_Needs_Encoding@plt>
  mov    %r15,%rdi
  lea    0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  call   <String_Needs_Encoding@plt>
  mov    0xc(%rsp),%edx
  movb   $0x58,(%r12)
  mov    %eax,%ebx
  movb   $0x5f,0x2(%r12)
  lea    (%rdx,%rdx,1),%eax
  or     %ebx,%eax
  add    $0x30,%eax
  mov    %al,0x1(%r12)
  cmp    $0x1,%edx
  jne    L87
  mov    %rbp,%rdi
  mov    %r14,%rdx
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%rbp
  jmp    L19
  nopl   (%rax)
L87:
  cmp    $0x2,%edx
  jne    L19
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <Encode_String@plt>
  mov    $0x5f5f,%edx
  mov    %dx,(%rax)
  lea    0x2(%rax),%rbp
  jmp    L19
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D1
datatype: string

tool: D12: %s

tool: D19: __a%d

tool: D1: %s__

assistant: ```c
char *Encode_Hexa(char *module, char *pred, int arity, char *str) {
  int module_encode = (module == NULL || *module == '\0') ? 0 : String_Needs_Encoding(module) + 1;
  int pred_encode = String_Needs_Encoding(pred);
  *str++ = 'X';
  *str++ = '0' + ((module_encode << 1) | pred_encode);
  *str++ = '_';
  if (module_encode == 1)
    str += sprintf(str, "%s__", module);
  else if (module_encode == 2) {
    str = Encode_String(module, str);
    *str++ = '_';
    *str++ = '_';
  }
  if (pred_encode == 0)
    str += sprintf(str, "%s", pred);
  else
    str = Encode_String(pred, str);
  if (arity >= 0)
    str += sprintf(str, "__a%d", arity);
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<Encode_Hexa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  lea    0x3(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L24
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r14
  jne    L21
L24:
  mov    %r15,%rdi
  call   <String_Needs_Encoding@plt>
  movb   $0x58,(%r12)
  mov    %eax,%ebx
  lea    0x30(%rax),%eax
  movb   $0x5f,0x2(%r12)
  mov    %al,0x1(%r12)
L12:
  test   %ebx,%ebx
  jne    L63
  mov    %r15,%rdx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  lea    0x0(%rbp,%rax,1),%r12
L30:
  test   %r13d,%r13d
  js     L17
  mov    %r12,%rdi
  mov    %r13d,%edx
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%r12
L17:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L63:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <Encode_String@plt>
  mov    %rax,%r12
  jmp    L30
L21:
  call   <String_Needs_Encoding@plt>
  mov    %r15,%rdi
  lea    0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  call   <String_Needs_Encoding@plt>
  mov    0xc(%rsp),%edx
  movb   $0x58,(%r12)
  mov    %eax,%ebx
  movb   $0x5f,0x2(%r12)
  lea    (%rdx,%rdx,1),%eax
  or     %ebx,%eax
  add    $0x30,%eax
  mov    %al,0x1(%r12)
  cmp    $0x1,%edx
  jne    L46
  mov    %rbp,%rdi
  mov    %r14,%rdx
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  cltq
  add    %rax,%rbp
  jmp    L12
  nopl   (%rax)
L46:
  cmp    $0x2,%edx
  jne    L12
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <Encode_String@plt>
  mov    $0x5f5f,%edx
  mov    %dx,(%rax)
  lea    0x2(%rax),%rbp
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string

tool: D27: %s

tool: D8: __a%d

tool: D19: %s__

assistant: ```c
char *Encode_Hexa(char *module, char *pred, int arity, char *str) {
  int module_encode = (module == NULL || *module == '\0') ? 0 : String_Needs_Encoding(module) + 1;
  int pred_encode = String_Needs_Encoding(pred);
  *str++ = 'X';
  *str++ = '0' + ((module_encode << 1) | pred_encode);
  *str++ = '_';
  if (module_encode == 1)
    str += sprintf(str, "%s__", module);
  else if (module_encode == 2) {
    str = Encode_String(module, str);
    *str++ = '_';
    *str++ = '_';
  }
  if (pred_encode == 0)
    str += sprintf(str, "%s", pred);
  else
    str = Encode_String(pred, str);
  if (arity >= 0)
    str += sprintf(str, "__a%d", arity);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xffffffec,%eax
  movl   $0x12,(%rax)
  mov    $0x0,%eax
  call   <SuperDelay@plt>
  mov    $0xffffffec,%eax
  movl   $0x2,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void Start(int row) {
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 16 | 2;
  SuperDelay();
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 2;
}
```
user: What is the c source code of the assembly code below:

```asm
<Start>:
  endbr64
  push   %rbx
  mov    $0xffffffec,%ebx
  movl   $0x12,(%rbx)
  mov    $0x0,%eax
  call   <SuperDelay@plt>
  movl   $0x2,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Start(int row) {
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 16 | 2;
  SuperDelay();
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Start>:
  endbr64
  push   %rbx
  mov    $0xffffffec,%ebx
  xor    %eax,%eax
  movl   $0x12,(%rbx)
  call   <SuperDelay@plt>
  movl   $0x2,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Start(int row) {
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 16 | 2;
  SuperDelay();
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Start>:
  endbr64
  push   %rbx
  mov    $0xffffffec,%ebx
  xor    %eax,%eax
  movl   $0x12,(%rbx)
  call   <SuperDelay@plt>
  movl   $0x2,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void Start(int row) {
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 16 | 2;
  SuperDelay();
  *(volatile unsigned int *)(0xFFFFFFE0 + 0x0C) = 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vlq_read_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xb(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  jne    L49
  mov    $0x0,%eax
  jmp    L33
L49:
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %ax,-0xa(%rbp)
  movzbl -0xb(%rbp),%eax
  test   %al,%al
  jns    L14
  movzwl -0xa(%rbp),%eax
  sub    $0x40,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  mov    $0x1,%eax
  jmp    L33
L14:
  mov    -0x18(%rbp),%rdx
  lea    -0xb(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  jne    L60
  mov    $0x0,%eax
  jmp    L33
L60:
  movswl -0xa(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  sub    $0x4000,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  mov    $0x1,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int vlq_read_short(FILE *fp, short *v) {
  unsigned char c;
  short s;
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = c & 0x7f;
  if (c & 0x80) {
    *v = s - 64;
    return 1;
  }
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = (s << 8) | (c & 0xff);
  *v = s - 16384;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vlq_read_short>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  mov    %rbx,%rsi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L21
  movzbl 0x7(%rsp),%eax
  mov    %eax,%ebp
  and    $0x7f,%ebp
  test   %al,%al
  js     L6
  lea    0x7(%rsp),%rdi
  mov    %rbx,%rsi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L21
  shl    $0x8,%ebp
  movzbl 0x7(%rsp),%eax
  or     %eax,%ebp
  sub    $0x4000,%bp
  mov    %bp,(%r12)
  mov    $0x1,%eax
  jmp    L21
L6:
  movzbl %bpl,%ebp
  sub    $0x40,%ebp
  mov    %bp,(%r12)
  mov    $0x1,%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vlq_read_short(FILE *fp, short *v) {
  unsigned char c;
  short s;
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = c & 0x7f;
  if (c & 0x80) {
    *v = s - 64;
    return 1;
  }
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = (s << 8) | (c & 0xff);
  *v = s - 16384;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vlq_read_short>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  mov    %r13,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L21
  movzbl 0x7(%rsp),%eax
  mov    %eax,%ebx
  and    $0x7f,%ebx
  test   %al,%al
  js     L13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L21
  movzbl 0x7(%rsp),%eax
  shl    $0x8,%ebx
  or     %eax,%ebx
  mov    $0x1,%eax
  sub    $0x4000,%bx
  mov    %bx,(%r12)
L42:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  movzbl %bl,%ebx
  mov    $0x1,%eax
  sub    $0x40,%ebx
  mov    %bx,(%r12)
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  jmp    L42
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vlq_read_short(FILE *fp, short *v) {
  unsigned char c;
  short s;
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = c & 0x7f;
  if (c & 0x80) {
    *v = s - 64;
    return 1;
  }
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = (s << 8) | (c & 0xff);
  *v = s - 16384;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vlq_read_short>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  mov    %r13,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L52
  movzbl 0x7(%rsp),%eax
  mov    %eax,%ebx
  and    $0x7f,%ebx
  test   %al,%al
  js     L59
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <IO_Read_UBYTE@plt>
  test   %eax,%eax
  je     L52
  movzbl 0x7(%rsp),%eax
  shl    $0x8,%ebx
  or     %eax,%ebx
  mov    $0x1,%eax
  sub    $0x4000,%bx
  mov    %bx,(%r12)
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L59:
  movzbl %bl,%ebx
  mov    $0x1,%eax
  sub    $0x40,%ebx
  mov    %bx,(%r12)
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L52:
  xor    %eax,%eax
  jmp    L3
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vlq_read_short(FILE *fp, short *v) {
  unsigned char c;
  short s;
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = c & 0x7f;
  if (c & 0x80) {
    *v = s - 64;
    return 1;
  }
  if (!IO_Read_UBYTE(&c, fp))
    return 0;
  s = (s << 8) | (c & 0xff);
  *v = s - 16384;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<divisionBy10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: f64

tool: D7: 10

assistant: ```c
double divisionBy10(int inputNum) {
  double result = inputNum / 10.0;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<divisionBy10>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: f64

tool: D4: 10

assistant: ```c
double divisionBy10(int inputNum) {
  double result = inputNum / 10.0;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<divisionBy10>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D3(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: f64

tool: D3: 10

assistant: ```c
double divisionBy10(int inputNum) {
  double result = inputNum / 10.0;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divisionBy10>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: f64

tool: D7: 10

assistant: ```c
double divisionBy10(int inputNum) {
  double result = inputNum / 10.0;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<posix_spawnattr_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L18
L8:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int posix_spawnattr_destroy(posix_spawnattr_t *sa) {
  if (sa == NULL)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<posix_spawnattr_destroy>:
  endbr64
  cmp    $0x1,%rdi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int posix_spawnattr_destroy(posix_spawnattr_t *sa) {
  if (sa == NULL)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<posix_spawnattr_destroy>:
  endbr64
  cmp    $0x1,%rdi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int posix_spawnattr_destroy(posix_spawnattr_t *sa) {
  if (sa == NULL)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<posix_spawnattr_destroy>:
  endbr64
  cmp    $0x1,%rdi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int posix_spawnattr_destroy(posix_spawnattr_t *sa) {
  if (sa == NULL)
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L1
  mov    -0x4(%rbp),%eax
  jmp    L10
L1:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L10:
  pop    %rbp
  ret
```

assistant: ```c
int get_point(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return i;
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_point>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  mov    $0x0,%eax
L16:
  mov    %eax,%ecx
  cmp    $0x2e,%dl
  je     L15
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L16
L15:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int get_point(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return i;
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_point>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L20
  xor    %eax,%eax
  jmp    L28
  nop
L2:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L20
L28:
  mov    %eax,%r8d
  cmp    $0x2e,%dl
  jne    L2
L20:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_point(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return i;
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_point>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L8
  xor    %eax,%eax
  jmp    L28
  nop
L30:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L8
L28:
  mov    %eax,%r8d
  cmp    $0x2e,%dl
  jne    L30
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_point(char a[]) {
  int i = 0;
  while (a[i] != '\0') {
    if (a[i] == '.')
      return i;
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  endbr64
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  endbr64
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  endbr64
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  nop
  jmp    *%rax
  endbr64
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D50
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string

tool: D7: A

tool: D43: B

tool: D50: C

tool: D33: D

tool: D21: E

assistant: ```c
int main() {
  static const void *L[] = {&&L1, &&L2, &&L3, &&L4, 0};
  unsigned i = 0;
  printf("A\n");
L1:
  printf("B\n");
L2:
  printf("C\n");
L3:
  printf("D\n");
  goto *L[i++];
L4:
  printf("E\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  endbr64
  lea    D31(%rip),%rdi
  call   <puts@plt>
  endbr64
  lea    D10(%rip),%rdi
  call   <puts@plt>
  endbr64
  lea    D40(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  lea    D38(%rip),%rdx
  mov    %eax,%eax
  jmp    *(%rdx,%rax,8)
  endbr64
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D31
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D40
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string

tool: D6: A

tool: D31: B

tool: D10: C

tool: D40: D

tool: D32: E

assistant: ```c
int main() {
  static const void *L[] = {&&L1, &&L2, &&L3, &&L4, 0};
  unsigned i = 0;
  printf("A\n");
L1:
  printf("B\n");
L2:
  printf("C\n");
L3:
  printf("D\n");
  goto *L[i++];
L4:
  printf("E\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  lea    D50(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  endbr64
  lea    D49(%rip),%rdi
  call   <puts@plt>
  endbr64
  lea    D54(%rip),%rdi
  call   <puts@plt>
  endbr64
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  jmp    *0x0(%rbp,%rax,8)
  endbr64
  lea    D15(%rip),%rdi
  call   <puts@plt>
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D31
datatype: string
name: parse_data
arguments: data_tag: D49
datatype: string
name: parse_data
arguments: data_tag: D54
datatype: string
name: parse_data
arguments: data_tag: D43
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D31: A

tool: D49: B

tool: D54: C

tool: D43: D

tool: D15: E

assistant: ```c
int main() {
  static const void *L[] = {&&L1, &&L2, &&L3, &&L4, 0};
  unsigned i = 0;
  printf("A\n");
L1:
  printf("B\n");
L2:
  printf("C\n");
L3:
  printf("D\n");
  goto *L[i++];
L4:
  printf("E\n");
  return 0;
}
```