ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  xor    %eax,%eax
  mov    0x4(%rsp),%ebp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  mov    %ebx,%ecx
  lea    (%rbx,%rbp,1),%esi
  cltd
  imul   %ebp,%ecx
  lea    D39(%rip),%rdi
  idiv   %ebp
  mov    %ebx,%edx
  sub    %ebp,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D44
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D39
type_infered: string

tool: D22: Enter any number :  

tool: D23: %d

tool: D44: 
Enter any number again: 

tool: D7: 
 ------------------------- 

tool: D39: 
 Sum: %d, 	 Difference: %d, 
 Product: %d, 	 Quotient: %d 

assistant: ```c
int main() {
  int numb1, numb2, sum, diff, product, quotient;
  printf("Enter any number :  ");
  scanf("%d", &numb1);
  printf("\nEnter any number again: ");
  scanf("%d", &numb2);
  sum = numb1 + numb2;
  diff = numb1 - numb2;
  product = numb1 * numb2;
  quotient = numb1 / numb2;
  printf("\n ------------------------- ");
  printf("\n Sum: %d, \t Difference: %d, \n Product: %d, \t Quotient: %d ", sum, diff, product, quotient);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L70
L43:
  cmpl   $0x63,-0x4(%rbp)
  je     L76
  cmpl   $0x63,-0x4(%rbp)
  jg     L48
  cmpl   $0x61,-0x4(%rbp)
  je     L18
  cmpl   $0x62,-0x4(%rbp)
  je     L19
  jmp    L48
L18:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L70
L19:
  mov    $0x7,%edi
  call   <putchar@plt>
  jmp    L70
L76:
  mov    $0x0,%eax
  call   <count@plt>
  jmp    L70
L48:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L70:
  mov    $0x0,%eax
  call   <get_choice@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x71,-0x4(%rbp)
  jne    L43
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string

tool: D22: Buy low, sell high.


tool: D2: Program error!


tool: D24: Bye.


assistant: ```c
int main(void) {
  int choice;
  while ((choice = get_choice()) != 'q') {
    switch (choice) {
    case 'a':
      printf("Buy low, sell high.\n");
      break;
    case 'b':
      putchar('\a');
      break;
    case 'c':
      count();
      break;
    default:
      printf("Program error!\n");
      break;
    }
  }
  printf("Bye.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D8(%rip),%rbp
  lea    D12(%rip),%rbx
  jmp    L40
L28:
  mov    %rbx,%rdi
  call   <printf@plt>
L40:
  mov    $0x0,%eax
  call   <get_choice@plt>
  cmp    $0x71,%eax
  je     L31
  cmp    $0x62,%eax
  je     L71
  cmp    $0x63,%eax
  je     L16
  cmp    $0x61,%eax
  je     L28
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L40
L71:
  mov    $0x7,%edi
  call   <putchar@plt>
  jmp    L40
L16:
  mov    $0x0,%eax
  call   <count@plt>
  jmp    L40
L31:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D6
type: string

tool: D8: Program error!


tool: D12: Buy low, sell high.


tool: D6: Bye.


assistant: ```c
int main(void) {
  int choice;
  while ((choice = get_choice()) != 'q') {
    switch (choice) {
    case 'a':
      printf("Buy low, sell high.\n");
      break;
    case 'b':
      putchar('\a');
      break;
    case 'c':
      count();
      break;
    default:
      printf("Program error!\n");
      break;
    }
  }
  printf("Bye.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  call   <get_choice@plt>
  cmp    $0x71,%eax
  je     L40
L23:
  cmp    $0x62,%eax
  je     L18
  cmp    $0x63,%eax
  je     L75
  cmp    $0x61,%eax
  je     L30
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <get_choice@plt>
  cmp    $0x71,%eax
  jne    L23
L40:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L30:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
  call   <count@plt>
  jmp    L50
  nopl   0x0(%rax)
L18:
  mov    $0x7,%edi
  call   <putchar@plt>
  jmp    L50
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D22
datatype: string

tool: D12: Program error!


tool: D27: Buy low, sell high.


tool: D22: Bye.


assistant: ```c
int main(void) {
  int choice;
  while ((choice = get_choice()) != 'q') {
    switch (choice) {
    case 'a':
      printf("Buy low, sell high.\n");
      break;
    case 'b':
      putchar('\a');
      break;
    case 'c':
      count();
      break;
    default:
      printf("Program error!\n");
      break;
    }
  }
  printf("Bye.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <get_choice@plt>
  cmp    $0x71,%eax
  je     L59
L8:
  cmp    $0x62,%eax
  je     L7
  cmp    $0x63,%eax
  je     L1
  cmp    $0x61,%eax
  je     L72
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <get_choice@plt>
  cmp    $0x71,%eax
  jne    L8
L59:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L72:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <count@plt>
  jmp    L11
  nopl   0x0(%rax)
L7:
  mov    $0x7,%edi
  call   <putchar@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D2
datatype: string

tool: D0: Program error!


tool: D12: Buy low, sell high.


tool: D2: Bye.


assistant: ```c
int main(void) {
  int choice;
  while ((choice = get_choice()) != 'q') {
    switch (choice) {
    case 'a':
      printf("Buy low, sell high.\n");
      break;
    case 'b':
      putchar('\a');
      break;
    case 'c':
      count();
      break;
    default:
      printf("Program error!\n");
      break;
    }
  }
  printf("Bye.\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2a(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x2a(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string

tool: D0: %s

tool: D23: out put sth: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char str[10];
  char str2[20];
  scanf("%s", str);
  getchar();
  gets(str2);
  printf("out put sth: %s\n", str);
  printf("out put sth: %s\n", str2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D7: %s

tool: D1: out put sth: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char str[10];
  char str2[20];
  scanf("%s", str);
  getchar();
  gets(str2);
  printf("out put sth: %s\n", str);
  printf("out put sth: %s\n", str2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D12: %s

tool: D8: out put sth: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char str[10];
  char str2[20];
  scanf("%s", str);
  getchar();
  gets(str2);
  printf("out put sth: %s\n", str);
  printf("out put sth: %s\n", str2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string

tool: D2: %s

tool: D16: out put sth: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char str[10];
  char str2[20];
  scanf("%s", str);
  getchar();
  gets(str2);
  printf("out put sth: %s\n", str);
  printf("out put sth: %s\n", str2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_neighbors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L37:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  movl   $0x0,(%rdx)
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x3,-0xc(%rbp)
  jle    L37
  cmpq   $0x0,-0x30(%rbp)
  je     L26
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    -0x30(%rbp),%rcx
  sub    $0x1,%rcx
  mov    (%rdx,%rcx,4),%edx
  and    $0xf,%edx
  cmp    $0xf,%edx
  jne    L26
  addl   $0x1,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  movl   $0x1,(%rdx)
L26:
  mov    -0x18(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,-0x30(%rbp)
  je     L7
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    -0x30(%rbp),%rcx
  add    $0x1,%rcx
  mov    (%rdx,%rcx,4),%edx
  and    $0xf,%edx
  cmp    $0xf,%edx
  jne    L7
  addl   $0x1,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  add    $0x8,%rdx
  movl   $0x1,(%rdx)
L7:
  cmpq   $0x0,-0x38(%rbp)
  je     L70
  mov    -0x38(%rbp),%rdx
  sub    $0x1,%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x30(%rbp),%rdx
  mov    (%rcx,%rdx,4),%edx
  and    $0xf,%edx
  cmp    $0xf,%edx
  jne    L70
  addl   $0x1,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  add    $0xc,%rdx
  movl   $0x1,(%rdx)
L70:
  mov    -0x28(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,-0x38(%rbp)
  je     L22
  mov    -0x38(%rbp),%rdx
  add    $0x1,%rdx
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rdx,%rax,4),%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L22
  addl   $0x1,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
L22:
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_neighbors(long col, uint16_t (*cell)[col], long row, long sc, long sr, int *dir_good) {
  int neighbor_count = 0;
  for (int i = 0; i < 4; i++)
    dir_good[i] = 0;
  if (sc != 0)
    if ((cell[sr][sc - 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[0] = 1;
    }
  if (sc != (col - 1))
    if ((cell[sr][sc + 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[2] = 1;
    }
  if (sr != 0)
    if ((cell[sr - 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[3] = 1;
    }
  if (sr != (row - 1))
    if ((cell[sr + 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[1] = 1;
    }
  return neighbor_count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_neighbors>:
  endbr64
  mov    %rcx,%rax
  lea    -0x1(%rdi),%r10
  movl   $0x0,(%r9)
  movl   $0x0,0x4(%r9)
  movl   $0x0,0x8(%r9)
  movl   $0x0,0xc(%r9)
  mov    $0x0,%ecx
  test   %rax,%rax
  je     L11
  mov    %r8,%r11
  imul   %rdi,%r11
  lea    -0x4(,%rax,4),%rcx
  lea    (%rcx,%r11,4),%rcx
  mov    (%rsi,%rcx,1),%r11d
  and    $0xf,%r11d
  mov    $0x0,%ecx
  cmp    $0xf,%r11d
  je     L115
L11:
  cmp    %rax,%r10
  je     L96
  mov    %r8,%r11
  imul   %rdi,%r11
  lea    0x4(,%rax,4),%r10
  lea    (%r10,%r11,4),%r10
  mov    (%rsi,%r10,1),%r10d
  and    $0xf,%r10d
  cmp    $0xf,%r10d
  je     L46
L96:
  test   %r8,%r8
  je     L16
  lea    -0x1(%r8),%r10
  imul   %rdi,%r10
  lea    0x0(,%rax,4),%r11
  lea    (%r11,%r10,4),%r10
  mov    (%rsi,%r10,1),%r10d
  and    $0xf,%r10d
  cmp    $0xf,%r10d
  je     L5
L16:
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  je     L53
  add    $0x1,%r8
  imul   %rdi,%r8
  shl    $0x2,%rax
  lea    (%rax,%r8,4),%rax
  mov    (%rsi,%rax,1),%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  je     L55
L53:
  mov    %ecx,%eax
  ret
L115:
  movl   $0x1,(%r9)
  mov    $0x1,%ecx
  jmp    L11
L46:
  add    $0x1,%ecx
  movl   $0x1,0x8(%r9)
  jmp    L96
L5:
  add    $0x1,%ecx
  movl   $0x1,0xc(%r9)
  jmp    L16
L55:
  add    $0x1,%ecx
  movl   $0x1,0x4(%r9)
  jmp    L53
```

assistant: ```c
int find_neighbors(long col, uint16_t (*cell)[col], long row, long sc, long sr, int *dir_good) {
  int neighbor_count = 0;
  for (int i = 0; i < 4; i++)
    dir_good[i] = 0;
  if (sc != 0)
    if ((cell[sr][sc - 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[0] = 1;
    }
  if (sc != (col - 1))
    if ((cell[sr][sc + 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[2] = 1;
    }
  if (sr != 0)
    if ((cell[sr - 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[3] = 1;
    }
  if (sr != (row - 1))
    if ((cell[sr + 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[1] = 1;
    }
  return neighbor_count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_neighbors>:
  endbr64
  mov    %rcx,%rax
  push   %rbx
  lea    -0x1(%rdi),%rcx
  xor    %r10d,%r10d
  movq   $0x0,(%r9)
  movq   $0x0,0x8(%r9)
  test   %rax,%rax
  je     L75
  mov    %r8,%rbx
  lea    -0x4(,%rax,4),%r11
  imul   %rdi,%rbx
  lea    (%r11,%rbx,4),%r11
  mov    (%rsi,%r11,1),%r11d
  and    $0xf,%r11d
  cmp    $0xf,%r11d
  je     L103
L75:
  cmp    %rax,%rcx
  je     L109
  mov    %r8,%r11
  lea    0x4(,%rax,4),%rcx
  imul   %rdi,%r11
  lea    (%rcx,%r11,4),%rcx
  mov    (%rsi,%rcx,1),%ecx
  and    $0xf,%ecx
  cmp    $0xf,%ecx
  je     L59
L109:
  test   %r8,%r8
  je     L79
  lea    -0x1(%r8),%rcx
  lea    0x0(,%rax,4),%r11
  imul   %rdi,%rcx
  lea    (%r11,%rcx,4),%rcx
  mov    (%rsi,%rcx,1),%ecx
  and    $0xf,%ecx
  cmp    $0xf,%ecx
  je     L11
L79:
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  je     L96
  add    $0x1,%r8
  shl    $0x2,%rax
  imul   %rdi,%r8
  lea    (%rax,%r8,4),%rax
  mov    (%rsi,%rax,1),%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  je     L35
L96:
  mov    %r10d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r10d
  movl   $0x1,0x4(%r9)
  pop    %rbx
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L59:
  movl   $0x1,0x8(%r9)
  add    $0x1,%r10d
  jmp    L109
  cs nopw 0x0(%rax,%rax,1)
L11:
  movl   $0x1,0xc(%r9)
  add    $0x1,%r10d
  jmp    L79
  xchg   %ax,%ax
L103:
  movl   $0x1,(%r9)
  mov    $0x1,%r10d
  jmp    L75
```

assistant: ```c
int find_neighbors(long col, uint16_t (*cell)[col], long row, long sc, long sr, int *dir_good) {
  int neighbor_count = 0;
  for (int i = 0; i < 4; i++)
    dir_good[i] = 0;
  if (sc != 0)
    if ((cell[sr][sc - 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[0] = 1;
    }
  if (sc != (col - 1))
    if ((cell[sr][sc + 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[2] = 1;
    }
  if (sr != 0)
    if ((cell[sr - 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[3] = 1;
    }
  if (sr != (row - 1))
    if ((cell[sr + 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[1] = 1;
    }
  return neighbor_count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_neighbors>:
  endbr64
  mov    %rcx,%rax
  pxor   %xmm0,%xmm0
  push   %rbx
  lea    -0x1(%rdi),%rcx
  movups %xmm0,(%r9)
  test   %rax,%rax
  je     L81
  mov    %r8,%r11
  lea    -0x4(,%rax,4),%r10
  mov    $0x1,%ebx
  imul   %rdi,%r11
  lea    (%r10,%r11,4),%r10
  mov    (%rsi,%r10,1),%r11d
  xor    %r10d,%r10d
  and    $0xf,%r11d
  cmp    $0xf,%r11d
  je     L73
L37:
  cmp    %rax,%rcx
  je     L30
  mov    %r8,%r11
  lea    0x4(,%rax,4),%rcx
  imul   %rdi,%r11
  lea    (%rcx,%r11,4),%rcx
  mov    (%rsi,%rcx,1),%ecx
  and    $0xf,%ecx
  cmp    $0xf,%ecx
  je     L21
L30:
  test   %r8,%r8
  je     L64
  lea    -0x1(%r8),%rcx
  lea    0x0(,%rax,4),%r11
  imul   %rdi,%rcx
  lea    (%r11,%rcx,4),%rcx
  mov    (%rsi,%rcx,1),%ecx
  and    $0xf,%ecx
  cmp    $0xf,%ecx
  je     L17
L64:
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  je     L78
  add    $0x1,%r8
  shl    $0x2,%rax
  imul   %rdi,%r8
  lea    (%rax,%r8,4),%rax
  mov    (%rsi,%rax,1),%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  je     L118
L78:
  mov    %r10d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  mov    $0x1,%ebx
  xor    %r10d,%r10d
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L118:
  add    $0x1,%r10d
  movl   $0x1,0x4(%r9)
  pop    %rbx
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L21:
  movl   $0x1,0x8(%r9)
  mov    %ebx,%r10d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L17:
  movl   $0x1,0xc(%r9)
  add    $0x1,%r10d
  jmp    L64
  xchg   %ax,%ax
L73:
  movl   $0x1,(%r9)
  mov    $0x2,%ebx
  mov    $0x1,%r10d
  jmp    L37
```

assistant: ```c
int find_neighbors(long col, uint16_t (*cell)[col], long row, long sc, long sr, int *dir_good) {
  int neighbor_count = 0;
  for (int i = 0; i < 4; i++)
    dir_good[i] = 0;
  if (sc != 0)
    if ((cell[sr][sc - 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[0] = 1;
    }
  if (sc != (col - 1))
    if ((cell[sr][sc + 1] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[2] = 1;
    }
  if (sr != 0)
    if ((cell[sr - 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[3] = 1;
    }
  if (sr != (row - 1))
    if ((cell[sr + 1][sc] & 0x000F) == 0x000F) {
      neighbor_count++;
      dir_good[1] = 1;
    }
  return neighbor_count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x80(%rbp)
  movl   $0x1,-0x7c(%rbp)
  jmp    L27
L38:
  mov    -0x80(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L25
  addl   $0x1,-0x78(%rbp)
  addl   $0x1,-0x80(%rbp)
  jmp    L19
L25:
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x80(%rbp)
L19:
  addl   $0x1,-0x7c(%rbp)
L27:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L38
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d

assistant: ```c
void main() {
  int i, j, n, deg = 0;
  char str[100];
  gets(str);
  n = strlen(str);
  i = 0;
  j = 1;
  while (j < n) {
    if (str[i] == str[j]) {
      deg++;
      i++;
    } else {
      deg = 0;
      i = 0;
    }
    j++;
  }
  printf("%d", deg);
  return 0;
}
```