ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_delim_str>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %ecx,%esi
  sub    $0x10,%rsp
  mov    0x0(%rbp),%r12
  cmp    %rdx,%r12
  jae    L13
L8:
  mov    %r14,%r15
  sub    %r12,%r15
  add    %r13,%r12
  mov    %r15,%rdx
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L24
  movb   $0x0,(%rax)
  mov    0x0(%rbp),%rdx
  sub    %r12,%rax
  lea    0x1(%rdx,%rax,1),%r15
L17:
  mov    %r15,0x0(%rbp)
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  mov    %ecx,0xc(%rsp)
  call   <__builtin_unreachable@plt>
  mov    0xc(%rsp),%esi
  jmp    L8
  nopl   0x0(%rax)
L24:
  movb   $0x0,0x0(%r13,%r14,1)
  add    0x0(%rbp),%r15
  jmp    L17
```

assistant: ```c
__attribute__((__nonnull__)) char *get_delim_str(char *buf, size_t *posp, size_t size, int delim) {
  size_t pos = *posp;
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((pos >= size)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  size_t len = size - pos;
  char *start = buf + pos;
  char *found = memchr(start, delim, len);
  if (found) {
    *found = '\0';
    *posp += (size_t)(found - start) + 1;
  } else {
    start[len] = '\0';
    *posp += len;
  }
  return start;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_delim_str>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %ecx,%esi
  sub    $0x10,%rsp
  mov    0x0(%rbp),%r12
  cmp    %rdx,%r12
  jae    L39
L38:
  mov    %r14,%r15
  sub    %r12,%r15
  add    %r13,%r12
  mov    %r15,%rdx
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L12
  movb   $0x0,(%rax)
  mov    0x0(%rbp),%rdx
  sub    %r12,%rax
  lea    0x1(%rdx,%rax,1),%r15
L21:
  mov    %r15,0x0(%rbp)
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  mov    %ecx,0xc(%rsp)
  call   <__builtin_unreachable@plt>
  mov    0xc(%rsp),%esi
  jmp    L38
  nopl   0x0(%rax)
L12:
  movb   $0x0,0x0(%r13,%r14,1)
  add    0x0(%rbp),%r15
  jmp    L21
```

assistant: ```c
__attribute__((__nonnull__)) char *get_delim_str(char *buf, size_t *posp, size_t size, int delim) {
  size_t pos = *posp;
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((pos >= size)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  size_t len = size - pos;
  char *start = buf + pos;
  char *found = memchr(start, delim, len);
  if (found) {
    *found = '\0';
    *posp += (size_t)(found - start) + 1;
  } else {
    start[len] = '\0';
    *posp += len;
  }
  return start;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arg_present>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
  mov    $0x1,%eax
  jmp    L28
L35:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int arg_present(int argc, char *argv[], char *t) {
  int i;
  for (i = 0; i < argc; i++)
    if (strcmp(argv[i], t) == 0)
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arg_present>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
L36:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L36
  mov    $0x0,%eax
  jmp    L32
L4:
  mov    $0x0,%eax
  ret
L17:
  mov    $0x1,%eax
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int arg_present(int argc, char *argv[], char *t) {
  int i;
  for (i = 0; i < argc; i++)
    if (strcmp(argv[i], t) == 0)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arg_present>:
  endbr64
  test   %edi,%edi
  jle    L34
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L14
  nopl   0x0(%rax)
L5:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L32
L14:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int arg_present(int argc, char *argv[], char *t) {
  int i;
  for (i = 0; i < argc; i++)
    if (strcmp(argv[i], t) == 0)
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arg_present>:
  endbr64
  test   %edi,%edi
  jle    L12
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L13
  nopl   0x0(%rax)
L24:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L28
L13:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L24
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int arg_present(int argc, char *argv[], char *t) {
  int i;
  for (i = 0; i < argc; i++)
    if (strcmp(argv[i], t) == 0)
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ecdsa_address_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L13
L12:
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x15,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base58_decode_check@plt>
  cmp    $0x15,%eax
  sete   %al
  movzbl %al,%eax
L13:
  leave
  ret
```

assistant: ```c
int ecdsa_address_decode(const char *addr, uint8_t *out) {
  if (!addr)
    return 0;
  return base58_decode_check(addr, out, 21) == 21;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ecdsa_address_decode>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  mov    $0x15,%edx
  call   <base58_decode_check@plt>
  cmp    $0x15,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
int ecdsa_address_decode(const char *addr, uint8_t *out) {
  if (!addr)
    return 0;
  return base58_decode_check(addr, out, 21) == 21;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ecdsa_address_decode>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  mov    $0x15,%edx
  call   <base58_decode_check@plt>
  cmp    $0x15,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ecdsa_address_decode(const char *addr, uint8_t *out) {
  if (!addr)
    return 0;
  return base58_decode_check(addr, out, 21) == 21;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ecdsa_address_decode>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  mov    $0x15,%edx
  call   <base58_decode_check@plt>
  cmp    $0x15,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ecdsa_address_decode(const char *addr, uint8_t *out) {
  if (!addr)
    return 0;
  return base58_decode_check(addr, out, 21) == 21;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sheep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x300,-0x1c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x12a,%edi
  call   <syscall@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sheep(uint32_t off) {
  uint64_t buf[10] = {0x4800000001, off, 0, 0, 0, 0x300};
  int fd = syscall(298, buf, 0, -1, -1, 0);
  assert(!close(fd));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sheep>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x1,(%rsp)
  mov    %edi,0x4(%rsp)
  movl   $0x300,0x14(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x0,%edx
  mov    $0x12a,%edi
  call   <syscall@plt>
  mov    %eax,%edi
  call   <close@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sheep(uint32_t off) {
  uint64_t buf[10] = {0x4800000001, off, 0, 0, 0, 0x300};
  int fd = syscall(298, buf, 0, -1, -1, 0);
  assert(!close(fd));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sheep>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  xor    %r9d,%r9d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %edi,0x4(%rsp)
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x12a,%edi
  movups %xmm0,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x300,0x14(%rsp)
  call   <syscall@plt>
  mov    %eax,%edi
  call   <close@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sheep(uint32_t off) {
  uint64_t buf[10] = {0x4800000001, off, 0, 0, 0, 0x300};
  int fd = syscall(298, buf, 0, -1, -1, 0);
  assert(!close(fd));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sheep>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  xor    %r9d,%r9d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %edi,0x4(%rsp)
  mov    $0xffffffff,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x12a,%edi
  movups %xmm0,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x300,0x14(%rsp)
  call   <syscall@plt>
  mov    %eax,%edi
  call   <close@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sheep(uint32_t off) {
  uint64_t buf[10] = {0x4800000001, off, 0, 0, 0, 0x300};
  int fd = syscall(298, buf, 0, -1, -1, 0);
  assert(!close(fd));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L13
  cmpl   $0x0,-0x2c(%rbp)
  jne    L4
L13:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L20
L4:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x30(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L23
L39:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x48(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L23:
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L39
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
L20:
  leave
  ret
```

assistant: ```c
char *replace(const char *str, const char *oldstr, const char *newstr) {
  int len, oldlen, newlen, cnt;
  char *buf, *dst;
  const char *left, *right;
  len = strlen(str);
  oldlen = strlen(oldstr);
  if (len == 0 || oldlen == 0)
    return strdup(str);
  newlen = strlen(newstr);
  buf = malloc(len + (len * newlen) / oldlen + 1);
  dst = buf;
  left = str;
  while (right = strstr(left, oldstr)) {
    cnt = right - left;
    memcpy(dst, left, cnt);
    dst += cnt;
    memcpy(dst, newstr, newlen);
    dst += newlen;
    left = right + oldlen;
  }
  strcpy(dst, left);
  buf = realloc(buf, strlen(buf) + 1);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r15,%rdi
  call   <strlen@plt>
  test   %ebx,%ebx
  je     L3
  mov    %eax,%r14d
  test   %eax,%eax
  je     L3
  mov    (%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %eax,0xc(%rsp)
  imul   %ebx,%eax
  cltd
  idiv   %r14d
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%r13
  movslq %r12d,%rax
  mov    %rax,0x10(%rsp)
  jmp    L35
L3:
  mov    %rbp,%rdi
  call   <strdup@plt>
  jmp    L9
L30:
  mov    %r12,%rbx
  sub    %rbp,%rbx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  add    %rbx,%r13
  mov    0xc(%rsp),%edx
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  add    0x10(%rsp),%r13
  movslq %r14d,%rbp
  add    %r12,%rbp
L35:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L30
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
L9:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *replace(const char *str, const char *oldstr, const char *newstr) {
  int len, oldlen, newlen, cnt;
  char *buf, *dst;
  const char *left, *right;
  len = strlen(str);
  oldlen = strlen(oldstr);
  if (len == 0 || oldlen == 0)
    return strdup(str);
  newlen = strlen(newstr);
  buf = malloc(len + (len * newlen) / oldlen + 1);
  dst = buf;
  left = str;
  while (right = strstr(left, oldstr)) {
    cnt = right - left;
    memcpy(dst, left, cnt);
    dst += cnt;
    memcpy(dst, newstr, newlen);
    dst += newlen;
    left = right + oldlen;
  }
  strcpy(dst, left);
  buf = realloc(buf, strlen(buf) + 1);
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<replace>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  test   %ebp,%ebp
  je     L20
  test   %eax,%eax
  je     L20
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %ebp,%eax
  imul   %r14d,%eax
  cltd
  idivl  0xc(%rsp)
  lea    0x1(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rbp
  movslq %r14d,%rax
  mov    %rax,0x10(%rsp)
  jmp    L21
  nop
L9:
  mov    %rbx,%rcx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%rcx
  mov    %ecx,%edx
  mov    %rcx,(%rsp)
  call   <memcpy@plt>
  mov    (%rsp),%rcx
  mov    %r14d,%edx
  mov    %r13,%rsi
  movslq %ecx,%rcx
  add    %rcx,%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq 0xc(%rsp),%r8
  add    0x10(%rsp),%rbp
  lea    (%rbx,%r8,1),%r15
L21:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L9
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x28,%rsp
  mov    %rbx,%rdi
  lea    0x1(%rax),%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <realloc@plt>
  nopl   0x0(%rax)
L20:
  add    $0x28,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1100 <strdup@plt>
```

assistant: ```c
char *replace(const char *str, const char *oldstr, const char *newstr) {
  int len, oldlen, newlen, cnt;
  char *buf, *dst;
  const char *left, *right;
  len = strlen(str);
  oldlen = strlen(oldstr);
  if (len == 0 || oldlen == 0)
    return strdup(str);
  newlen = strlen(newstr);
  buf = malloc(len + (len * newlen) / oldlen + 1);
  dst = buf;
  left = str;
  while (right = strstr(left, oldstr)) {
    cnt = right - left;
    memcpy(dst, left, cnt);
    dst += cnt;
    memcpy(dst, newstr, newlen);
    dst += newlen;
    left = right + oldlen;
  }
  strcpy(dst, left);
  buf = realloc(buf, strlen(buf) + 1);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replace>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  test   %ebp,%ebp
  je     L1
  test   %eax,%eax
  je     L1
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %ebp,%eax
  imul   %r14d,%eax
  cltd
  idivl  0xc(%rsp)
  lea    0x1(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rbp
  movslq %r14d,%rax
  mov    %rax,0x10(%rsp)
  jmp    L33
  nop
L37:
  mov    %rbx,%rcx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%rcx
  mov    %ecx,%edx
  mov    %rcx,(%rsp)
  call   <memcpy@plt>
  mov    (%rsp),%rcx
  mov    %r14d,%edx
  mov    %r13,%rsi
  movslq %ecx,%rcx
  add    %rcx,%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq 0xc(%rsp),%r8
  add    0x10(%rsp),%rbp
  lea    (%rbx,%r8,1),%r15
L33:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L37
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x28,%rsp
  mov    %rbx,%rdi
  lea    0x1(%rax),%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <realloc@plt>
  nopl   0x0(%rax)
L1:
  add    $0x28,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1100 <strdup@plt>
```

assistant: ```c
char *replace(const char *str, const char *oldstr, const char *newstr) {
  int len, oldlen, newlen, cnt;
  char *buf, *dst;
  const char *left, *right;
  len = strlen(str);
  oldlen = strlen(oldstr);
  if (len == 0 || oldlen == 0)
    return strdup(str);
  newlen = strlen(newstr);
  buf = malloc(len + (len * newlen) / oldlen + 1);
  dst = buf;
  left = str;
  while (right = strstr(left, oldstr)) {
    cnt = right - left;
    memcpy(dst, left, cnt);
    dst += cnt;
    memcpy(dst, newstr, newlen);
    dst += newlen;
    left = right + oldlen;
  }
  strcpy(dst, left);
  buf = realloc(buf, strlen(buf) + 1);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    D1(%rip),%rax
  imul   -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x38(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void copy_dvector(double *src, long nl1, long nh1, double *dst, long nl2, long nh2) {
  long len = nh1 - nl1 + 1;
  static long size = sizeof(double);
  memcpy(dst + nl2, src + nl1, len * size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_dvector>:
  endbr64
  sub    $0x8,%rsp
  sub    %rsi,%rdx
  lea    0x8(,%rdx,8),%rdx
  lea    (%rdi,%rsi,8),%rsi
  lea    (%rcx,%r8,8),%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void copy_dvector(double *src, long nl1, long nh1, double *dst, long nl2, long nh2) {
  long len = nh1 - nl1 + 1;
  static long size = sizeof(double);
  memcpy(dst + nl2, src + nl1, len * size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_dvector>:
  endbr64
  sub    %rsi,%rdx
  lea    (%rdi,%rsi,8),%rsi
  lea    (%rcx,%r8,8),%rdi
  lea    0x8(,%rdx,8),%rdx
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void copy_dvector(double *src, long nl1, long nh1, double *dst, long nl2, long nh2) {
  long len = nh1 - nl1 + 1;
  static long size = sizeof(double);
  memcpy(dst + nl2, src + nl1, len * size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_dvector>:
  endbr64
  sub    %rsi,%rdx
  lea    (%rdi,%rsi,8),%rsi
  lea    (%rcx,%r8,8),%rdi
  lea    0x8(,%rdx,8),%rdx
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void copy_dvector(double *src, long nl1, long nh1, double *dst, long nl2, long nh2) {
  long len = nh1 - nl1 + 1;
  static long size = sizeof(double);
  memcpy(dst + nl2, src + nl1, len * size);
}
```