ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x41,-0x4(%rbp)
  jne    L2
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D19: Nhap: 

tool: D7: B


assistant: ```c
main() {
  int c;
  printf("Nhap: ");
  c = getchar();
  if (c == 65)
    printf("B\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x41,%eax
  je     L7
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L7:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D6: Nhap: 

tool: D11: B


assistant: ```c
main() {
  int c;
  printf("Nhap: ");
  c = getchar();
  if (c == 65)
    printf("B\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x41,%eax
  je     L13
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L13:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D5
type: string

tool: D2: Nhap: 

tool: D5: B


assistant: ```c
main() {
  int c;
  printf("Nhap: ");
  c = getchar();
  if (c == 65)
    printf("B\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x41,%eax
  je     L6
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D13: Nhap: 

tool: D7: B


assistant: ```c
main() {
  int c;
  printf("Nhap: ");
  c = getchar();
  if (c == 65)
    printf("B\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fits_calc_tile_rows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L52
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  jmp    L76
L52:
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  movq   $0x1,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L59
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rdx
  sub    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  jle    L46
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L66
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L46
L66:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L46:
  addl   $0x1,-0xc(%rbp)
L59:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L37
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L32
  mov    -0x30(%rbp),%rax
  movq   $0x1,(%rax)
L32:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
L76:
  pop    %rbp
  ret
```

assistant: ```c
int fits_calc_tile_rows(long *tlpixel, long *tfpixel, int ndim, long *trowsize, long *ntrows, int *status) {
  int ii;
  long np;
  if (*status)
    return (*status);
  *trowsize = 0;
  *ntrows = 1;
  for (ii = 0; ii < ndim; ++ii) {
    np = tlpixel[ii] - tfpixel[ii] + 1;
    if (np > 1) {
      if (!(*trowsize))
        *trowsize = np;
      else
        *ntrows *= np;
    }
  }
  if (!(*trowsize)) {
    *trowsize = 1;
  }
  return (*status);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fits_calc_tile_rows>:
  endbr64
  mov    %rsi,%r10
  mov    %rcx,%rsi
  mov    (%r9),%eax
  test   %eax,%eax
  jne    L22
  movq   $0x0,(%rcx)
  movq   $0x1,(%r8)
  test   %edx,%edx
  jle    L72
  mov    %edx,%edx
  mov    $0x0,%ecx
  jmp    L64
L44:
  imul   (%r8),%rax
  mov    %rax,(%r8)
L77:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L72
L64:
  mov    (%rdi,%rcx,8),%rax
  sub    (%r10,%rcx,8),%rax
  add    $0x1,%rax
  cmp    $0x1,%rax
  jle    L77
  cmpq   $0x0,(%rsi)
  jne    L44
  mov    %rax,(%rsi)
  jmp    L77
L72:
  cmpq   $0x0,(%rsi)
  jne    L15
  movq   $0x1,(%rsi)
L15:
  mov    (%r9),%eax
L22:
  ret
```

assistant: ```c
int fits_calc_tile_rows(long *tlpixel, long *tfpixel, int ndim, long *trowsize, long *ntrows, int *status) {
  int ii;
  long np;
  if (*status)
    return (*status);
  *trowsize = 0;
  *ntrows = 1;
  for (ii = 0; ii < ndim; ++ii) {
    np = tlpixel[ii] - tfpixel[ii] + 1;
    if (np > 1) {
      if (!(*trowsize))
        *trowsize = np;
      else
        *ntrows *= np;
    }
  }
  if (!(*trowsize)) {
    *trowsize = 1;
  }
  return (*status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fits_calc_tile_rows>:
  endbr64
  mov    (%r9),%r11d
  mov    %rcx,%r10
  test   %r11d,%r11d
  jne    L32
  movq   $0x0,(%rcx)
  movq   $0x1,(%r8)
  mov    (%rcx),%r9
  test   %edx,%edx
  jle    L57
  movslq %edx,%rdx
  xor    %ecx,%ecx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %rax,(%r10)
  mov    %rax,%r9
L48:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L57
L24:
  mov    (%rdi,%rcx,8),%rax
  sub    (%rsi,%rcx,8),%rax
  add    $0x1,%rax
  cmp    $0x1,%rax
  jle    L48
  test   %r9,%r9
  je     L77
  imul   (%r8),%rax
  add    $0x1,%rcx
  mov    %rax,(%r8)
  mov    (%r10),%r9
  cmp    %rcx,%rdx
  jne    L24
L57:
  test   %r9,%r9
  jne    L32
  movq   $0x1,(%r10)
L32:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int fits_calc_tile_rows(long *tlpixel, long *tfpixel, int ndim, long *trowsize, long *ntrows, int *status) {
  int ii;
  long np;
  if (*status)
    return (*status);
  *trowsize = 0;
  *ntrows = 1;
  for (ii = 0; ii < ndim; ++ii) {
    np = tlpixel[ii] - tfpixel[ii] + 1;
    if (np > 1) {
      if (!(*trowsize))
        *trowsize = np;
      else
        *ntrows *= np;
    }
  }
  if (!(*trowsize)) {
    *trowsize = 1;
  }
  return (*status);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fits_calc_tile_rows>:
  endbr64
  mov    (%r9),%r11d
  mov    %rcx,%r10
  test   %r11d,%r11d
  jne    L59
  movq   $0x0,(%rcx)
  movq   $0x1,(%r8)
  mov    (%rcx),%r9
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %ecx,%ecx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rax,(%r10)
  mov    %rax,%r9
L13:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L14
L34:
  mov    (%rdi,%rcx,8),%rax
  sub    (%rsi,%rcx,8),%rax
  add    $0x1,%rax
  cmp    $0x1,%rax
  jle    L13
  test   %r9,%r9
  je     L9
  imul   (%r8),%rax
  add    $0x1,%rcx
  mov    %rax,(%r8)
  mov    (%r10),%r9
  cmp    %rdx,%rcx
  jne    L34
L14:
  test   %r9,%r9
  jne    L59
  movq   $0x1,(%r10)
L59:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int fits_calc_tile_rows(long *tlpixel, long *tfpixel, int ndim, long *trowsize, long *ntrows, int *status) {
  int ii;
  long np;
  if (*status)
    return (*status);
  *trowsize = 0;
  *ntrows = 1;
  for (ii = 0; ii < ndim; ++ii) {
    np = tlpixel[ii] - tfpixel[ii] + 1;
    if (np > 1) {
      if (!(*trowsize))
        *trowsize = np;
      else
        *ntrows *= np;
    }
  }
  if (!(*trowsize)) {
    *trowsize = 1;
  }
  return (*status);
}
```
user: What is the c source code of the assembly code below:

```asm
<HTS_c2ir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    -0x38(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x1,-0x14(%rbp)
  jmp    L5
L1:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  jmp    L49
L27:
  mov    -0x14(%rbp),%eax
L49:
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L22
L2:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L2
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void HTS_c2ir(double *c, const int nc, double *h, const int leng) {
  int n, k, upl;
  double d;
  h[0] = exp(c[0]);
  for (n = 1; n < leng; n++) {
    d = 0;
    upl = (n >= nc) ? nc - 1 : n;
    for (k = 1; k <= upl; k++)
      d += k * c[k] * h[n - k];
    h[n] = d / n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HTS_c2ir>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %ecx,%ebp
  movsd  (%rdi),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x0(%r13)
  cmp    $0x1,%ebp
  jle    L26
  lea    0x8(%r13),%rdi
  mov    $0x1,%esi
  lea    -0x1(%r12),%r8d
L36:
  cmp    %esi,%r12d
  mov    %esi,%eax
  cmovle %r8d,%eax
  test   %eax,%eax
  jle    L0
  lea    0x1(%rax),%ecx
  mov    %rdi,%rdx
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
L38:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  mulsd  -0x8(%rdx),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  sub    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L38
L25:
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  add    $0x1,%esi
  add    $0x8,%rdi
  cmp    %esi,%ebp
  jne    L36
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  pxor   %xmm1,%xmm1
  jmp    L25
```

assistant: ```c
void HTS_c2ir(double *c, const int nc, double *h, const int leng) {
  int n, k, upl;
  double d;
  h[0] = exp(c[0]);
  for (n = 1; n < leng; n++) {
    d = 0;
    upl = (n >= nc) ? nc - 1 : n;
    for (k = 1; k <= upl; k++)
      d += k * c[k] * h[n - k];
    h[n] = d / n;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HTS_c2ir>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsd  (%rdi),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x0(%rbp)
  cmp    $0x1,%r12d
  jle    L1
  lea    0x8(%rbp),%r8
  mov    $0x1,%edi
  pxor   %xmm2,%xmm2
  lea    -0x1(%r13),%ecx
  nop
L33:
  cmp    %edi,%r13d
  jg     L31
  mov    %ecx,%esi
  movapd %xmm2,%xmm1
  test   %ecx,%ecx
  jle    L39
L51:
  mov    %r8,%rdx
  mov    $0x1,%eax
  movapd %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L42:
  pxor   %xmm0,%xmm0
  sub    $0x8,%rdx
  cvtsi2sd %eax,%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %eax,%esi
  jge    L42
L39:
  pxor   %xmm0,%xmm0
  add    $0x8,%r8
  cvtsi2sd %edi,%xmm0
  add    $0x1,%edi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%r8)
  cmp    %edi,%r12d
  jne    L33
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %edi,%esi
  jmp    L51
```

assistant: ```c
void HTS_c2ir(double *c, const int nc, double *h, const int leng) {
  int n, k, upl;
  double d;
  h[0] = exp(c[0]);
  for (n = 1; n < leng; n++) {
    d = 0;
    upl = (n >= nc) ? nc - 1 : n;
    for (k = 1; k <= upl; k++)
      d += k * c[k] * h[n - k];
    h[n] = d / n;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<HTS_c2ir>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsd  (%rdi),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x0(%r13)
  cmp    $0x1,%ebp
  jle    L55
  lea    -0x1(%r12),%edi
  cmp    $0x1,%r12d
  jle    L72
  cmp    %r12d,%ebp
  mov    %r12d,%r9d
  lea    0x8(%r13),%r8
  mov    $0x2,%ecx
  cmovle %ebp,%r9d
  mov    $0x1,%esi
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax)
L6:
  mov    %r8,%rdx
  movapd %xmm2,%xmm1
  mov    $0x1,%eax
  nopl   0x0(%rax)
L29:
  pxor   %xmm0,%xmm0
  sub    $0x8,%rdx
  cvtsi2sd %eax,%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L29
  pxor   %xmm0,%xmm0
  lea    0x1(%rax),%rcx
  add    $0x8,%r8
  cvtsi2sd %esi,%xmm0
  add    $0x1,%esi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%r8)
  cmp    %r9d,%esi
  jl     L6
  cmp    %esi,%ebp
  jle    L55
L60:
  movslq %esi,%rax
  lea    -0x2(%r12),%ecx
  lea    0x0(%r13,%rax,8),%r8
  add    $0x2,%rcx
  nopl   0x0(%rax)
L69:
  movapd %xmm2,%xmm1
  test   %edi,%edi
  jle    L81
  mov    %r8,%rdx
  mov    $0x1,%eax
L56:
  pxor   %xmm0,%xmm0
  sub    $0x8,%rdx
  cvtsi2sd %eax,%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L56
L81:
  pxor   %xmm0,%xmm0
  add    $0x8,%r8
  cvtsi2sd %esi,%xmm0
  add    $0x1,%esi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%r8)
  cmp    %esi,%ebp
  jg     L69
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L72:
  mov    $0x1,%esi
  pxor   %xmm2,%xmm2
  jmp    L60
```

assistant: ```c
void HTS_c2ir(double *c, const int nc, double *h, const int leng) {
  int n, k, upl;
  double d;
  h[0] = exp(c[0]);
  for (n = 1; n < leng; n++) {
    d = 0;
    upl = (n >= nc) ? nc - 1 : n;
    for (k = 1; k <= upl; k++)
      d += k * c[k] * h[n - k];
    h[n] = d / n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L19
L20:
  movl   $0x2,-0x8(%rbp)
  jmp    L17
L32:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L49
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L49:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L32
  subl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x0,-0xc(%rbp)
  jg     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble(int a[], int N) {
  int i, j, t;
  for (i = N; i >= 1; i--) {
    for (j = 2; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        t = a[j - 1];
        a[j - 1] = a[j];
        a[j] = t;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bubble>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%r8d
  lea    0x8(%rdi),%r9
  jmp    L45
L0:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L22
L9:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L0
L14:
  test   %r8d,%r8d
  jg     L22
L4:
  ret
L22:
  sub    $0x1,%r8d
L45:
  lea    0x1(%r8),%eax
  cmp    $0x1,%eax
  jle    L14
  lea    0x4(%rdi),%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L9
```

assistant: ```c
void bubble(int a[], int N) {
  int i, j, t;
  for (i = N; i >= 1; i--) {
    for (j = 2; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        t = a[j - 1];
        a[j - 1] = a[j];
        a[j] = t;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bubble>:
  endbr64
  lea    0x8(%rdi),%r9
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jle    L42
  nopl   (%rax)
L3:
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    (%r9,%rdx,4),%rsi
  nopl   0x0(%rax,%rax,1)
L48:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L39
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L39:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L48
L17:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jg     L3
L42:
  test   %r8d,%r8d
  jg     L17
  ret
L38:
  ret
```

assistant: ```c
void bubble(int a[], int N) {
  int i, j, t;
  for (i = N; i >= 1; i--) {
    for (j = 2; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        t = a[j - 1];
        a[j - 1] = a[j];
        a[j] = t;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble>:
  endbr64
  lea    0x8(%rdi),%r9
  test   %esi,%esi
  jle    L29
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jle    L9
  nopl   (%rax)
L49:
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rdx
  lea    (%r9,%rax,4),%rsi
  nopl   0x0(%rax,%rax,1)
L47:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L53
  movq   %xmm1,(%rdx)
L53:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L47
L41:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jg     L49
L9:
  test   %r8d,%r8d
  jg     L41
  ret
L29:
  ret
```

assistant: ```c
void bubble(int a[], int N) {
  int i, j, t;
  for (i = N; i >= 1; i--) {
    for (j = 2; j <= i; j++) {
      if (a[j - 1] > a[j]) {
        t = a[j - 1];
        a[j - 1] = a[j];
        a[j] = t;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gang_alloc0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gang_alloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *gang_alloc0(struct gang *m, size_t sz) {
  void *ret;
  ret = gang_alloc(m, sz);
  if (ret != NULL)
    memset(ret, 0, sz);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gang_alloc0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <gang_alloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *gang_alloc0(struct gang *m, size_t sz) {
  void *ret;
  ret = gang_alloc(m, sz);
  if (ret != NULL)
    memset(ret, 0, sz);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gang_alloc0>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <gang_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *gang_alloc0(struct gang *m, size_t sz) {
  void *ret;
  ret = gang_alloc(m, sz);
  if (ret != NULL)
    memset(ret, 0, sz);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gang_alloc0>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <gang_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *gang_alloc0(struct gang *m, size_t sz) {
  void *ret;
  ret = gang_alloc(m, sz);
  if (ret != NULL)
    memset(ret, 0, sz);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dpopcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  jmp    L2
L11:
  mov    $0xffffffff,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int dpopcount(unsigned long x) {
  if (__builtin_popcountl(x))
    return x;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dpopcount>:
  endbr64
  test   %rdi,%rdi
  mov    $0xffffffff,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int dpopcount(unsigned long x) {
  if (__builtin_popcountl(x))
    return x;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dpopcount>:
  endbr64
  test   %rdi,%rdi
  mov    $0xffffffff,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int dpopcount(unsigned long x) {
  if (__builtin_popcountl(x))
    return x;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dpopcount>:
  endbr64
  test   %rdi,%rdi
  mov    $0xffffffff,%eax
  cmovne %edi,%eax
  ret
```

assistant: ```c
int dpopcount(unsigned long x) {
  if (__builtin_popcountl(x))
    return x;
  return -1;
}
```