ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <xcalloc@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <xcalloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x58(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <xcalloc@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x50(%rbp)
  mov    -0x58(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <adrand@plt>
  mov    -0x58(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x0,-0x48(%rbp)
  jmp    L13
L7:
  mov    $0x0,%eax
  call   <drand48@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sample1@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x58(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sample2@plt>
  mov    -0x58(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <filter1@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <filter2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addq   $0x1,-0x48(%rbp)
L13:
  mov    -0x48(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L7
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void test(size_t n) {
  double *a, *x1, *x2, v1, v2, r;
  size_t i, l, xp;
  a = xcalloc(n, sizeof(*a));
  x1 = xcalloc(n, sizeof(*x1));
  x2 = xcalloc(n, sizeof(*x2));
  xp = 0;
  adrand(a, n);
  l = n * 100;
  for (i = 0; i < l; i++) {
    r = drand48();
    sample1(x1, n, r);
    sample2(x2, n, r, &xp);
    v1 = filter1(x1, a, n);
    v2 = filter2(x2, a, n, xp);
    assert(fabs(v2 - v1) < 1e-6);
  }
  free(a);
  free(x1);
  free(x2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x8,%esi
  call   <xcalloc@plt>
  mov    %rax,%r12
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <xcalloc@plt>
  mov    %rax,%r14
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <xcalloc@plt>
  mov    %rax,%r13
  movq   $0x0,0x10(%rsp)
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <adrand@plt>
  lea    (%rbx,%rbx,4),%rax
  lea    (%rax,%rax,4),%r15
  shl    $0x2,%r15
  je     L1
  mov    $0x0,%ebp
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
L2:
  mov    $0x0,%eax
  call   <drand48@plt>
  movsd  %xmm0,(%rsp)
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <sample1@plt>
  mov    0x8(%rsp),%rdx
  movsd  (%rsp),%xmm0
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <sample2@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <filter1@plt>
  movsd  %xmm0,(%rsp)
  mov    0x10(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <filter2@plt>
  subsd  (%rsp),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r15
  jne    L2
L1:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(size_t n) {
  double *a, *x1, *x2, v1, v2, r;
  size_t i, l, xp;
  a = xcalloc(n, sizeof(*a));
  x1 = xcalloc(n, sizeof(*x1));
  x2 = xcalloc(n, sizeof(*x2));
  xp = 0;
  adrand(a, n);
  l = n * 100;
  for (i = 0; i < l; i++) {
    r = drand48();
    sample1(x1, n, r);
    sample2(x2, n, r, &xp);
    v1 = filter1(x1, a, n);
    v2 = filter2(x2, a, n, xp);
    assert(fabs(v2 - v1) < 1e-6);
  }
  free(a);
  free(x1);
  free(x2);
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  push   %r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <xcalloc@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <xcalloc@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <xcalloc@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movq   $0x0,0x10(%rsp)
  mov    %rax,%r12
  call   <adrand@plt>
  lea    (%rbx,%rbx,4),%rax
  lea    (%rax,%rax,4),%r14
  shl    $0x2,%r14
  mov    %r14,0x8(%rsp)
  je     L22
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r15
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <drand48@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  movsd  %xmm0,(%rsp)
  call   <sample1@plt>
  movsd  (%rsp),%xmm0
  mov    %r15,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <sample2@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <filter1@plt>
  mov    0x10(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,(%rsp)
  call   <filter2@plt>
  subsd  (%rsp),%xmm0
  call   <fabs@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setle  %dil
  add    $0x1,%r14
  call   <assert@plt>
  cmp    %r14,0x8(%rsp)
  jne    L7
L22:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(size_t n) {
  double *a, *x1, *x2, v1, v2, r;
  size_t i, l, xp;
  a = xcalloc(n, sizeof(*a));
  x1 = xcalloc(n, sizeof(*x1));
  x2 = xcalloc(n, sizeof(*x2));
  xp = 0;
  adrand(a, n);
  l = n * 100;
  for (i = 0; i < l; i++) {
    r = drand48();
    sample1(x1, n, r);
    sample2(x2, n, r, &xp);
    v1 = filter1(x1, a, n);
    v2 = filter2(x2, a, n, xp);
    assert(fabs(v2 - v1) < 1e-6);
  }
  free(a);
  free(x1);
  free(x2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <xcalloc@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <xcalloc@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <xcalloc@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movq   $0x0,0x10(%rsp)
  mov    %rax,%r12
  call   <adrand@plt>
  lea    (%rbx,%rbx,4),%rax
  lea    (%rax,%rax,4),%r14
  shl    $0x2,%r14
  mov    %r14,0x8(%rsp)
  je     L21
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r15
  nopl   (%rax)
L9:
  xor    %eax,%eax
  call   <drand48@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  movsd  %xmm0,(%rsp)
  call   <sample1@plt>
  movsd  (%rsp),%xmm0
  mov    %r15,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <sample2@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <filter1@plt>
  mov    0x10(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,(%rsp)
  call   <filter2@plt>
  subsd  (%rsp),%xmm0
  call   <fabs@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setle  %dil
  add    $0x1,%r14
  call   <assert@plt>
  cmp    %r14,0x8(%rsp)
  jne    L9
L21:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(size_t n) {
  double *a, *x1, *x2, v1, v2, r;
  size_t i, l, xp;
  a = xcalloc(n, sizeof(*a));
  x1 = xcalloc(n, sizeof(*x1));
  x2 = xcalloc(n, sizeof(*x2));
  xp = 0;
  adrand(a, n);
  l = n * 100;
  for (i = 0; i < l; i++) {
    r = drand48();
    sample1(x1, n, r);
    sample2(x2, n, r, &xp);
    v1 = filter1(x1, a, n);
    v2 = filter2(x2, a, n, xp);
    assert(fabs(v2 - v1) < 1e-6);
  }
  free(a);
  free(x1);
  free(x2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7473207473726946,%rax
  mov    $0x676e6972,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D17: Second string

tool: D11: str = %s


tool: D9: ptr = %s


assistant: ```c
int main(int argc, const char *argv[]) {
  char str[24] = "First string";
  char *ptr = "Second string";
  printf("str = %s\n", str);
  printf("ptr = %s\n", ptr);
  ptr = ++ptr;
  printf("ptr = %s\n", ptr);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x7473207473726946,%rax
  mov    $0x676e6972,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rsi
  lea    D28(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D35
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string

tool: D1: str = %s


tool: D35: Second string

tool: D28: ptr = %s


tool: D16: econd string

assistant: ```c
int main(int argc, const char *argv[]) {
  char str[24] = "First string";
  char *ptr = "Second string";
  printf("str = %s\n", str);
  printf("ptr = %s\n", ptr);
  ptr = ++ptr;
  printf("ptr = %s\n", ptr);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D9(%rip),%rbp
  sub    $0x20,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D46
type_infered: string
name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: byte[16]
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string

tool: D46: str = %s


tool: D9: ptr = %s


tool: {"D7": [0x46,0x69,0x72,0x73,0x74,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x00,0x00,0x00,0x00]}

tool: D20: Second string

tool: D26: econd string

assistant: ```c
int main(int argc, const char *argv[]) {
  char str[24] = "First string";
  char *ptr = "Second string";
  printf("str = %s\n", str);
  printf("ptr = %s\n", ptr);
  ptr = ++ptr;
  printf("ptr = %s\n", ptr);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D4(%rip),%rbp
  sub    $0x20,%rsp
  movdqa D40(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D40
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string

tool: D27: str = %s


tool: D4: ptr = %s


tool: {"D40": [0x46,0x69,0x72,0x73,0x74,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x00,0x00,0x00,0x00]}

tool: D11: Second string

tool: D23: econd string

assistant: ```c
int main(int argc, const char *argv[]) {
  char str[24] = "First string";
  char *ptr = "Second string";
  printf("str = %s\n", str);
  printf("ptr = %s\n", ptr);
  ptr = ++ptr;
  printf("ptr = %s\n", ptr);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pa_replacenum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L69
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xa65,%ax
  jbe    L22
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xa6f,%ax
  ja     L22
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xa66,%ax
  je     L37
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  sub    $0x66,%eax
  mov    %eax,%edx
  jmp    L95
L37:
  mov    $0x30,%edx
L95:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L22:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x2f,%ax
  jbe    L64
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x39,%ax
  ja     L64
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x30,%ax
  je     L19
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  jmp    L84
L19:
  mov    $0x30,%edx
L84:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L64:
  addl   $0x1,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pa_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0A66 && s[i] <= 0x0A6F)
      numchar[i] = ((s[i] - 0x0A66) == '\0') ? '0' : (s[i] - 0x0A66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pa_replacenum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r9
  test   %ebx,%ebx
  jle    L46
  mov    %ebx,%edi
  add    %rax,%rdi
  mov    %rax,%rdx
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rcx
  mov    $0x30,%r8d
  jmp    L20
L5:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L52
L20:
  movzwl (%rcx,%rax,2),%edx
  lea    -0xa66(%rdx),%esi
  cmp    $0x9,%si
  ja     L40
  lea    -0x66(%rdx),%esi
  cmp    $0xa66,%dx
  cmove  %r8d,%esi
  mov    %sil,(%rax)
L40:
  movzwl (%rcx,%rax,2),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%si
  ja     L5
  lea    -0x30(%rdx),%esi
  cmp    $0x30,%dx
  cmove  %r8d,%esi
  mov    %sil,(%rax)
  jmp    L5
L46:
  mov    $0x0,%ebx
L52:
  movslq %ebx,%rbx
  movb   $0x0,(%r9,%rbx,1)
  mov    %r9,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pa_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0A66 && s[i] <= 0x0A6F)
      numchar[i] = ((s[i] - 0x0A66) == '\0') ? '0' : (s[i] - 0x0A66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pa_replacenum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L38
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%r9
  mov    $0x30,%esi
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rdi
  nopw   0x0(%rax,%rax,1)
L1:
  movzwl (%rdi,%rax,2),%edx
  lea    -0xa66(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L24
  lea    -0x66(%rdx),%ecx
  cmp    $0xa66,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
  movzwl (%rdi,%rax,2),%edx
L24:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L7
  lea    -0x30(%rdx),%ecx
  cmp    $0x30,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
L7:
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L1
  add    %r8,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %rax,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pa_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0A66 && s[i] <= 0x0A6F)
      numchar[i] = ((s[i] - 0x0A66) == '\0') ? '0' : (s[i] - 0x0A66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pa_replacenum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L8
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%r9
  mov    $0x30,%esi
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rdi
  nopw   0x0(%rax,%rax,1)
L27:
  movzwl (%rdi,%rax,2),%edx
  lea    -0xa66(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L10
  lea    -0x66(%rdx),%ecx
  cmp    $0xa66,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
  movzwl (%rdi,%rax,2),%edx
L10:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L35
  lea    -0x30(%rdx),%ecx
  cmp    $0x30,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
L35:
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L27
  add    %r8,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rax,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pa_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0A66 && s[i] <= 0x0A6F)
      numchar[i] = ((s[i] - 0x0A66) == '\0') ? '0' : (s[i] - 0x0A66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: Translate the below assembly code into C programming language:

```asm
<TestC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2000,-0x4(%rbp)
L4:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: C

assistant: ```c
void TestC() {
  int i = 0x2000;
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
L7:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: C

assistant: ```c
void TestC() {
  int i = 0x2000;
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: C

assistant: ```c
void TestC() {
  int i = 0x2000;
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<TestC>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xc8,%edi
  call   <milli_delay@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: C

assistant: ```c
void TestC() {
  int i = 0x2000;
  while (1) {
    printf("C");
    milli_delay(200);
  }
}
```