ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intio_write>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
L9:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %bl,0x7(%rsp)
  sar    $0x8,%ebx
  call   <fwrite@plt>
  sub    $0x1,%ebp
  jne    L9
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    %bl,0x7(%rsp)
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void intio_write(FILE *f, int v) {
  unsigned char b;
  int i;
  for (i = 0; i < 3; i++) {
    b = v & 0xff;
    fwrite(&b, 1, 1, f);
    v >>= 8;
  }
  b = v > 0 ? v : v + 256;
  fwrite(&b, 1, 1, f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_quaddobl_start_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L43:
  cmp    %rdx,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L34:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L45
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L45:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L48
L32:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L48:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L32
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x222,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_quaddobl_start_system_from_file(int n, char *filename) {
  int b[n], i, fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc4c(546, &n, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_quaddobl_start_system_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L43:
  cmp    %rdx,%rsp
  je     L37
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L37:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L13
  orq    $0x0,-0x8(%rsp,%rax,1)
L13:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L19
  mov    %ecx,%ecx
  mov    $0x0,%eax
L18:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L18
L19:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x222,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  leave
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_quaddobl_start_system_from_file(int n, char *filename) {
  int b[n], i, fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc4c(546, &n, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_quaddobl_start_system_from_file>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L15
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L63
L15:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L35
L69:
  mov    %rsp,%r9
  test   %edx,%edx
  jle    L39
  xor    %eax,%eax
L46:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L46
L39:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x222,%edi
  lea    -0x14(%rbp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L69
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_quaddobl_start_system_from_file(int n, char *filename) {
  int b[n], i, fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)filename[i];
  fail = _ada_use_c2phc4c(546, &n, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<current_timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
long long current_timestamp(void) {
  struct timeval te;
  gettimeofday(&te, NULL);
  long long milliseconds = te.tv_sec * 1000LL + te.tv_usec / 1000;
  return milliseconds;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<current_timestamp>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%rax
  mov    0x8(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long current_timestamp(void) {
  struct timeval te;
  gettimeofday(&te, NULL);
  long long milliseconds = te.tv_sec * 1000LL + te.tv_usec / 1000;
  return milliseconds;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<current_timestamp>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long current_timestamp(void) {
  struct timeval te;
  gettimeofday(&te, NULL);
  long long milliseconds = te.tv_sec * 1000LL + te.tv_usec / 1000;
  return milliseconds;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<current_timestamp>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long current_timestamp(void) {
  struct timeval te;
  gettimeofday(&te, NULL);
  long long milliseconds = te.tv_sec * 1000LL + te.tv_usec / 1000;
  return milliseconds;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L18:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  subl   $0x2,-0x1c(%rbp)
L5:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L18
  cmpl   $0x1,-0x1c(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t checksum(void *buf, int len) {
  uint16_t *word = buf;
  uint32_t sum = 0;
  for (; len > 1; len -= 2) {
    sum += *word++;
  }
  if (len == 1)
    sum += *(uint8_t *)word;
  sum = (sum >> 16) + (sum & 0xFFFF);
  return ~sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L32
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rax
  mov    $0x0,%edx
L46:
  add    $0x4,%rdi
  add    -0x4(%rdi),%edx
  cmp    %rax,%rdi
  jne    L46
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L6:
  cmp    $0x1,%esi
  je     L7
L42:
  mov    %edx,%eax
  sar    $0x10,%eax
  movzwl %dx,%edx
  add    %edx,%eax
  not    %eax
  ret
L32:
  mov    %rdi,%rax
  mov    $0x0,%edx
  jmp    L6
L7:
  add    (%rax),%edx
  jmp    L42
```

assistant: ```c
uint16_t checksum(void *buf, int len) {
  uint16_t *word = buf;
  uint32_t sum = 0;
  for (; len > 1; len -= 2) {
    sum += *word++;
  }
  if (len == 1)
    sum += *(uint8_t *)word;
  sum = (sum >> 16) + (sum & 0xFFFF);
  return ~sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L24
  sub    $0x2,%esi
  xor    %edx,%edx
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L39:
  add    $0x4,%rdi
  add    -0x4(%rdi),%edx
  cmp    %rax,%rdi
  jne    L39
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L27:
  cmp    $0x1,%esi
  jne    L18
  add    (%rax),%edx
L18:
  mov    %edx,%eax
  movzwl %dx,%edx
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   (%rax)
L24:
  mov    %rdi,%rax
  xor    %edx,%edx
  jmp    L27
```

assistant: ```c
uint16_t checksum(void *buf, int len) {
  uint16_t *word = buf;
  uint32_t sum = 0;
  for (; len > 1; len -= 2) {
    sum += *word++;
  }
  if (len == 1)
    sum += *(uint8_t *)word;
  sum = (sum >> 16) + (sum & 0xFFFF);
  return ~sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<checksum>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%esi
  jle    L47
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%edi
  cmp    $0x5,%r10d
  jbe    L77
  mov    %edi,%edx
  mov    %rcx,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rcx,%rdx,1),%rdx
L51:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L51
  movdqa %xmm0,%xmm1
  mov    %edi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  mov    %eax,%r8d
  movdqa %xmm0,%xmm1
  neg    %r8d
  psrldq $0x4,%xmm1
  lea    (%rsi,%r8,2),%esi
  mov    %eax,%r8d
  paddd  %xmm1,%xmm0
  lea    (%rcx,%r8,4),%r8
  movd   %xmm0,%edx
  cmp    %eax,%edi
  je     L0
L39:
  lea    -0x2(%rsi),%eax
  add    (%r8),%edx
  cmp    $0x1,%eax
  jle    L0
  add    0x4(%r8),%edx
  cmp    $0x5,%esi
  jle    L0
  add    0x8(%r8),%edx
L0:
  mov    %r9d,%eax
  lea    (%rcx,%rdi,4),%rcx
  neg    %eax
  lea    (%r10,%rax,2),%esi
L78:
  cmp    $0x1,%esi
  jne    L34
  add    (%rcx),%edx
L34:
  mov    %edx,%eax
  movzwl %dx,%edx
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %edx,%edx
  jmp    L78
L77:
  mov    %rcx,%r8
  xor    %edx,%edx
  jmp    L39
```

assistant: ```c
uint16_t checksum(void *buf, int len) {
  uint16_t *word = buf;
  uint32_t sum = 0;
  for (; len > 1; len -= 2) {
    sum += *word++;
  }
  if (len == 1)
    sum += *(uint8_t *)word;
  sum = (sum >> 16) + (sum & 0xFFFF);
  return ~sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ADCComparatorIntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x40038000,-0x4(%rbp)
  je     L19
  cmpl   $0x40039000,-0x4(%rbp)
  jne    L28
L19:
  mov    $0x1,%eax
  jmp    L7
L28:
  mov    $0x0,%eax
L7:
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x3,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  mov    $0x10000,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    %rax,%rdx
  mov    %esi,%eax
  and    %ecx,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void ADCComparatorIntDisable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x10000 << ui32SequenceNum);
}
```
user: What is the c source code of the assembly code below?

```asm
<ADCComparatorIntDisable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x40038000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x3,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x8,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%edx
  mov    $0x10000,%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADCComparatorIntDisable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x10000 << ui32SequenceNum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ADCComparatorIntDisable>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %esi,%ebp
  push   %rbx
  and    $0xef,%ah
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x40038000,%eax
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%ebp
  setle  %dil
  add    $0x8,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    %ebp,%ecx
  mov    $0x10000,%eax
  mov    (%rbx),%edx
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADCComparatorIntDisable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x10000 << ui32SequenceNum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ADCComparatorIntDisable>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %esi,%ebp
  push   %rbx
  and    $0xef,%ah
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x40038000,%eax
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%ebp
  setle  %dil
  add    $0x8,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    %ebp,%ecx
  mov    $0x10000,%eax
  mov    (%rbx),%edx
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ADCComparatorIntDisable(uint32_t ui32Base, uint32_t ui32SequenceNum) {
  ASSERT((ui32Base == 0x40038000) || (ui32Base == 0x40039000));
  ASSERT(ui32SequenceNum < 4);
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) &= ~(0x10000 << ui32SequenceNum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<oblRozwKwad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  D28(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L29
  movsd  -0x20(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x1,%eax
  jmp    L36
L29:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L22
  mov    $0x0,%eax
  jmp    L36
L22:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x20(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x40(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x2,%eax
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_infered: f64
name: parse_data
arguments: label: D1
type_infered: byte[8]

tool: D28: 4

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
int oblRozwKwad(double a, double b, double c, double *t1, double *t2) {
  double delta = b * b - 4 * a * c;
  if (fabs(delta) < 1e-5) {
    *t1 = (-1) * (b) / (2 * a);
    return 1;
  } else if (delta < 0) {
    return 0;
  } else {
    *t1 = ((-1) * (b) + sqrt(delta)) / (2 * a);
    *t2 = ((-1) * (b)-sqrt(delta)) / (2 * a);
    return 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<oblRozwKwad>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%rbx
  movsd  %xmm1,0x10(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm3,%xmm1
  mulsd  D24(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <fabs@plt>
  test   %eax,%eax
  jle    L26
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  jbe    L8
L31:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  movsd  0x10(%rsp),%xmm0
  xorpd  D23(%rip),%xmm0
  movq   %rbx,%xmm1
  addsd  %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L31
L8:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  movq   %rbx,%xmm5
  addsd  %xmm5,%xmm5
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  0x10(%rsp),%xmm0
  movsd  %xmm5,0x18(%rsp)
  divsd  %xmm5,%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm0
  xorpd  D23(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,(%r12)
  mov    $0x2,%eax
  jmp    L31
```

tool_calls: name: read_data
arguments: label: D24
data_type: f64
name: read_data
arguments: label: D23
data_type: byte[16]

tool: D24: 4

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int oblRozwKwad(double a, double b, double c, double *t1, double *t2) {
  double delta = b * b - 4 * a * c;
  if (fabs(delta) < 1e-5) {
    *t1 = (-1) * (b) / (2 * a);
    return 1;
  } else if (delta < 0) {
    return 0;
  } else {
    *t1 = ((-1) * (b) + sqrt(delta)) / (2 * a);
    *t2 = ((-1) * (b)-sqrt(delta)) / (2 * a);
    return 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oblRozwKwad>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mov    %rsi,%rbp
  push   %rbx
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm4
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mulsd  D20(%rip),%xmm4
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  mulsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <fabs@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm3
  test   %eax,%eax
  movsd  0x18(%rsp),%xmm1
  jle    L13
  pxor   %xmm2,%xmm2
  xor    %eax,%eax
  comisd %xmm0,%xmm2
  jbe    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  addsd  %xmm3,%xmm3
  xorpd  D22(%rip),%xmm1
  mov    $0x1,%eax
  divsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  cvtsi2sd %rax,%xmm2
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm3,%xmm3
  subsd  %xmm1,%xmm2
  movsd  %xmm3,0x8(%rsp)
  divsd  %xmm3,%xmm2
  movsd  %xmm2,(%rbx)
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm1
  xorpd  D22(%rip),%xmm1
  cvtsi2sd %rax,%xmm0
  movsd  0x8(%rsp),%xmm3
  mov    $0x2,%eax
  subsd  %xmm0,%xmm1
  divsd  %xmm3,%xmm1
  movsd  %xmm1,0x0(%rbp)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
type_guessed: f64
name: read_data
arguments: data_label: D22
type_guessed: byte[16]

tool: D20: 4

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int oblRozwKwad(double a, double b, double c, double *t1, double *t2) {
  double delta = b * b - 4 * a * c;
  if (fabs(delta) < 1e-5) {
    *t1 = (-1) * (b) / (2 * a);
    return 1;
  } else if (delta < 0) {
    return 0;
  } else {
    *t1 = ((-1) * (b) + sqrt(delta)) / (2 * a);
    *t2 = ((-1) * (b)-sqrt(delta)) / (2 * a);
    return 2;
  }
}
```