ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jge    L98
  sub    %r12d,%eax
  mov    %rsp,%rdx
  lea    -0x1(%rax),%ecx
  lea    0x1(%rsp,%rcx,1),%rcx
L51:
  movb   $0x30,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L51
  lea    -0x1(%r12),%r8d
  test   %r12d,%r12d
  je     L29
  lea    -0x1(%r12),%edi
  mov    $0x0,%edx
  movslq %eax,%rcx
  lea    (%rsp,%rcx,1),%rsi
L65:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L65
  lea    0x1(%rax,%r8,1),%eax
L29:
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rbx
L22:
  mov    $0x0,%eax
L37:
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L20
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    $0x30,%dl
  jne    L143
  cmp    $0x31,%cl
  je     L85
L143:
  add    $0x1,%rax
  cmp    $0x31,%dl
  jne    L37
  cmp    $0x30,%cl
  jne    L37
  mov    $0x0,%eax
  jmp    L16
L98:
  jle    L22
  sub    %eax,%r12d
  mov    %rsp,%rdx
  lea    -0x1(%r12),%ecx
  lea    0x1(%rsp,%rcx,1),%rcx
L41:
  movb   $0x30,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L41
  lea    -0x1(%rax),%edi
  test   %eax,%eax
  je     L32
  lea    -0x1(%rax),%esi
  mov    $0x0,%eax
  movslq %r12d,%rdx
  lea    (%rsp,%rdx,1),%rcx
L117:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L117
  lea    0x1(%rdi,%r12,1),%r12d
L32:
  movslq %r12d,%r12
  movb   $0x0,(%rsp,%r12,1)
  mov    %rsp,%rbp
  jmp    L22
L20:
  mov    $0x1,%eax
L16:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L85:
  mov    $0x0,%eax
  jmp    L16
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char bitcmp(char *bitstrm1, char *bitstrm2) {
  int i, l1, l2, ldiff;
  char stream[256];
  char chr1, chr2;
  l1 = strlen(bitstrm1);
  l2 = strlen(bitstrm2);
  if (l1 < l2) {
    ldiff = l2 - l1;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l1--)
      stream[i++] = *(bitstrm1++);
    stream[i] = '\0';
    bitstrm1 = stream;
  } else if (l2 < l1) {
    ldiff = l1 - l2;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l2--)
      stream[i++] = *(bitstrm2++);
    stream[i] = '\0';
    bitstrm2 = stream;
  }
  while ((chr1 = *(bitstrm1++))) {
    chr2 = *(bitstrm2++);
    if (((chr1 == '0') && (chr2 == '1')) || ((chr1 == '1') && (chr2 == '0')))
      return (0);
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r13d
  cmp    %eax,%ebx
  jge    L34
  sub    %ebx,%r13d
  lea    0x10(%rsp),%r15
  mov    $0x30,%esi
  movslq %r13d,%r14
  mov    %r15,%rdi
  mov    %r14,%rdx
  call   <memset@plt>
  lea    -0x1(%rbx),%ecx
  mov    %ecx,0xc(%rsp)
  test   %ebx,%ebx
  je     L5
  lea    (%r15,%r14,1),%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    0xc(%rsp),%ecx
  lea    0x1(%r13,%rcx,1),%r13d
  movslq %r13d,%r14
L5:
  movb   $0x0,0x10(%rsp,%r14,1)
  mov    %r15,%rbp
L59:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L46:
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  je     L2
  movzbl (%r12,%rax,1),%ecx
  cmp    $0x30,%dl
  jne    L60
  cmp    $0x31,%cl
  je     L104
L60:
  add    $0x1,%rax
  cmp    $0x31,%dl
  jne    L46
  cmp    $0x30,%cl
  jne    L46
L104:
  xor    %eax,%eax
L106:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L34:
  jle    L59
  sub    %eax,%ebx
  lea    0x10(%rsp),%r15
  mov    $0x30,%esi
  movslq %ebx,%r14
  mov    %r15,%rdi
  mov    %r14,%rdx
  call   <memset@plt>
  lea    -0x1(%r13),%ecx
  mov    %ecx,0xc(%rsp)
  test   %r13d,%r13d
  je     L70
  lea    (%r15,%r14,1),%rdi
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    0xc(%rsp),%ecx
  lea    0x1(%rcx,%rbx,1),%ebx
  movslq %ebx,%r14
L70:
  movb   $0x0,0x10(%rsp,%r14,1)
  mov    %r15,%r12
  jmp    L59
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  jmp    L106
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char bitcmp(char *bitstrm1, char *bitstrm2) {
  int i, l1, l2, ldiff;
  char stream[256];
  char chr1, chr2;
  l1 = strlen(bitstrm1);
  l2 = strlen(bitstrm2);
  if (l1 < l2) {
    ldiff = l2 - l1;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l1--)
      stream[i++] = *(bitstrm1++);
    stream[i] = '\0';
    bitstrm1 = stream;
  } else if (l2 < l1) {
    ldiff = l1 - l2;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l2--)
      stream[i++] = *(bitstrm2++);
    stream[i] = '\0';
    bitstrm2 = stream;
  }
  while ((chr1 = *(bitstrm1++))) {
    chr2 = *(bitstrm2++);
    if (((chr1 == '0') && (chr2 == '1')) || ((chr1 == '1') && (chr2 == '0')))
      return (0);
  }
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r13d
  jge    L51
  sub    %r13d,%ebx
  mov    %rsp,%r15
  mov    $0x30,%esi
  movslq %ebx,%r14
  mov    %r15,%rdi
  mov    %r14,%rdx
  call   <memset@plt>
  test   %r13d,%r13d
  je     L7
  lea    -0x1(%r13),%edx
  lea    (%r15,%r14,1),%rdi
  mov    %rbp,%rsi
  mov    %rdx,%r13
  add    $0x1,%rdx
  call   <memcpy@plt>
  lea    0x1(%r13,%rbx,1),%ebx
  movslq %ebx,%r14
L7:
  movb   $0x0,(%rsp,%r14,1)
  mov    %r15,%rbp
L16:
  xor    %eax,%eax
L42:
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  je     L24
  movzbl (%r12,%rax,1),%ecx
  cmp    $0x30,%dl
  jne    L36
  cmp    $0x31,%cl
  je     L65
L36:
  add    $0x1,%rax
  cmp    $0x31,%dl
  jne    L42
  cmp    $0x30,%cl
  jne    L42
L65:
  xor    %eax,%eax
L87:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L103
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L51:
  jle    L16
  sub    %eax,%r13d
  mov    %rsp,%r15
  mov    $0x30,%esi
  movslq %r13d,%r14
  mov    %r15,%rdi
  mov    %r14,%rdx
  call   <memset@plt>
  test   %ebx,%ebx
  je     L66
  lea    -0x1(%rbx),%edx
  lea    (%r15,%r14,1),%rdi
  mov    %r12,%rsi
  mov    %rdx,%rbx
  add    $0x1,%rdx
  call   <memcpy@plt>
  lea    0x1(%rbx,%r13,1),%r13d
  movslq %r13d,%r14
L66:
  movb   $0x0,(%rsp,%r14,1)
  mov    %r15,%r12
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  jmp    L87
L103:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char bitcmp(char *bitstrm1, char *bitstrm2) {
  int i, l1, l2, ldiff;
  char stream[256];
  char chr1, chr2;
  l1 = strlen(bitstrm1);
  l2 = strlen(bitstrm2);
  if (l1 < l2) {
    ldiff = l2 - l1;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l1--)
      stream[i++] = *(bitstrm1++);
    stream[i] = '\0';
    bitstrm1 = stream;
  } else if (l2 < l1) {
    ldiff = l1 - l2;
    i = 0;
    while (ldiff--)
      stream[i++] = '0';
    while (l2--)
      stream[i++] = *(bitstrm2++);
    stream[i] = '\0';
    bitstrm2 = stream;
  }
  while ((chr1 = *(bitstrm1++))) {
    chr2 = *(bitstrm2++);
    if (((chr1 == '0') && (chr2 == '1')) || ((chr1 == '1') && (chr2 == '0')))
      return (0);
  }
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASN1_TIME_set_string_internal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <asn1_time_parse@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L56
  mov    $0x0,%eax
  jmp    L12
L56:
  cmpl   $0x0,-0x24(%rbp)
  je     L16
  mov    -0x24(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L16
  mov    $0x0,%eax
  jmp    L12
L16:
  cmpq   $0x0,-0x18(%rbp)
  jne    L77
  mov    $0x1,%eax
  jmp    L12
L77:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L12
L50:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,0xc(%rdx)
  mov    -0x18(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,0x8(%rax)
  mov    $0x1,%eax
L12:
  leave
  ret
```

assistant: ```c
int ASN1_TIME_set_string_internal(ASN1_TIME *s, const char *str, int mode) {
  int type;
  char *tmp;
  if ((type = asn1_time_parse(str, strlen(str), NULL, mode)) == -1)
    return (0);
  if (mode != 0 && mode != type)
    return (0);
  if (s == NULL)
    return (1);
  if ((tmp = strdup(str)) == NULL)
    return (0);
  free(s->data);
  s->data = tmp;
  s->length = strlen(tmp);
  s->type = type;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASN1_TIME_set_string_internal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %ebp,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <asn1_time_parse@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  cmp    $0xffffffff,%r13d
  je     L34
  test   %ebp,%ebp
  je     L49
  cmp    %r13d,%ebp
  jne    L34
L49:
  mov    $0x1,%eax
  test   %r12,%r12
  je     L34
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbx,(%r12)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%r12)
  mov    %r13d,0x8(%r12)
  mov    $0x1,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    $0x0,%eax
  jmp    L34
```

assistant: ```c
int ASN1_TIME_set_string_internal(ASN1_TIME *s, const char *str, int mode) {
  int type;
  char *tmp;
  if ((type = asn1_time_parse(str, strlen(str), NULL, mode)) == -1)
    return (0);
  if (mode != 0 && mode != type)
    return (0);
  if (s == NULL)
    return (1);
  if ((tmp = strdup(str)) == NULL)
    return (0);
  free(s->data);
  s->data = tmp;
  s->length = strlen(tmp);
  s->type = type;
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ASN1_TIME_set_string_internal>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <asn1_time_parse@plt>
  cmp    $0xffffffff,%eax
  je     L25
  mov    %eax,%r13d
  test   %ebx,%ebx
  je     L1
  cmp    %eax,%ebx
  je     L1
L25:
  xor    %r14d,%r14d
L27:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%r14d
  test   %r12,%r12
  je     L27
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L25
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbp,(%r12)
  mov    %rbp,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  mov    %r13d,0x8(%r12)
  mov    %eax,0xc(%r12)
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ASN1_TIME_set_string_internal(ASN1_TIME *s, const char *str, int mode) {
  int type;
  char *tmp;
  if ((type = asn1_time_parse(str, strlen(str), NULL, mode)) == -1)
    return (0);
  if (mode != 0 && mode != type)
    return (0);
  if (s == NULL)
    return (1);
  if ((tmp = strdup(str)) == NULL)
    return (0);
  free(s->data);
  s->data = tmp;
  s->length = strlen(tmp);
  s->type = type;
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASN1_TIME_set_string_internal>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edx,%edx
  mov    %r13d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <asn1_time_parse@plt>
  cmp    $0xffffffff,%eax
  je     L19
  mov    %eax,%ebx
  test   %r13d,%r13d
  je     L36
  cmp    %eax,%r13d
  je     L36
L19:
  xor    %r13d,%r13d
L34:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    $0x1,%r13d
  test   %r12,%r12
  je     L34
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbp,(%r12)
  mov    %rbp,%rdi
  call   <strlen@plt>
  movd   %ebx,%xmm0
  movd   %eax,%xmm1
  mov    %r13d,%eax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ASN1_TIME_set_string_internal(ASN1_TIME *s, const char *str, int mode) {
  int type;
  char *tmp;
  if ((type = asn1_time_parse(str, strlen(str), NULL, mode)) == -1)
    return (0);
  if (mode != 0 && mode != type)
    return (0);
  if (s == NULL)
    return (1);
  if ((tmp = strdup(str)) == NULL)
    return (0);
  free(s->data);
  s->data = tmp;
  s->length = strlen(tmp);
  s->type = type;
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nlmsg_nest_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  cmpq   $0x0,-0x10(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <NLMSG_ALIGN@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L15
L11:
  mov    $0xffffffff,%eax
  jmp    L23
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <NLMSG_ALIGN@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
int nlmsg_nest_end(struct nlmsghdr *nlmsg, struct rtattr *start) {
  if (nlmsg == NULL || start == NULL || (char *)start >= (char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))))
    return -1;
  start->rta_len = (unsigned short)((char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))) - (char *)start);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<nlmsg_nest_end>:
  endbr64
  test   %rdi,%rdi
  je     L46
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L37
  mov    (%rdi),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbp
  jae    L26
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rax,%rbx
  sub    %rbp,%rbx
  mov    %bx,0x0(%rbp)
  mov    $0x0,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    $0xffffffff,%eax
  jmp    L10
L26:
  mov    $0xffffffff,%eax
  jmp    L10
L46:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int nlmsg_nest_end(struct nlmsghdr *nlmsg, struct rtattr *start) {
  if (nlmsg == NULL || start == NULL || (char *)start >= (char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))))
    return -1;
  start->rta_len = (unsigned short)((char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))) - (char *)start);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nlmsg_nest_end>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L20
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbp
  jae    L20
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rax,%rbx
  xor    %eax,%eax
  sub    %rbp,%rbx
  mov    %bx,0x0(%rbp)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0xffffffff,%eax
  jmp    L0
L29:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int nlmsg_nest_end(struct nlmsghdr *nlmsg, struct rtattr *start) {
  if (nlmsg == NULL || start == NULL || (char *)start >= (char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))))
    return -1;
  start->rta_len = (unsigned short)((char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))) - (char *)start);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nlmsg_nest_end>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L25
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbp
  jae    L25
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  cltq
  add    %rax,%rbx
  xor    %eax,%eax
  sub    %rbp,%rbx
  mov    %bx,0x0(%rbp)
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
  jmp    L14
L16:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int nlmsg_nest_end(struct nlmsghdr *nlmsg, struct rtattr *start) {
  if (nlmsg == NULL || start == NULL || (char *)start >= (char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))))
    return -1;
  start->rta_len = (unsigned short)((char *)((struct rtattr *)(((char *)(nlmsg)) + NLMSG_ALIGN((nlmsg)->nlmsg_len))) - (char *)start);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply65>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L5
L2:
  movl   $0x0,-0x3c(%rbp)
  jmp    L35
L9:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L35:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L9
  addl   $0x1,-0x40(%rbp)
L5:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L2
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply65(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply65>:
  endbr64
  test   %edi,%edi
  jle    L20
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L17:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L28:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L28
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  ret
```

assistant: ```c
void multiply65(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply65>:
  endbr64
  test   %edi,%edi
  jle    L7
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L14
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L4
  pop    %rbx
  ret
L7:
  ret
```

assistant: ```c
void multiply65(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```