ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dojpa>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  mov    $0xf,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: Hello World!


assistant: ```c
int dojpa() {
  int i;
  for (i = 0; i < 15; ++i) {
    printf("Hello World!\n");
    sleep(1);
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dojpa>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  mov    $0xf,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: Hello World!


assistant: ```c
int dojpa() {
  int i;
  for (i = 0; i < 15; ++i) {
    printf("Hello World!\n");
    sleep(1);
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xff,%eax
  jne    L6
  mov    $0x0,%eax
  call   <foo@plt>
L6:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  if (UCHAR_MAX == 255)
    foo();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  cmpl   $0xff,(%rax)
  je     L3
L12:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <foo@plt>
  jmp    L12
```

assistant: ```c
int main(void) {
  if (UCHAR_MAX == 255)
    foo();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  cmpl   $0xff,(%rax)
  je     L7
L13:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  xor    %eax,%eax
  call   <foo@plt>
  jmp    L13
```

assistant: ```c
int main(void) {
  if (UCHAR_MAX == 255)
    foo();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  cmpl   $0xff,(%rax)
  je     L17
L10:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L17:
  xor    %eax,%eax
  call   <foo@plt>
  jmp    L10
```

assistant: ```c
int main(void) {
  if (UCHAR_MAX == 255)
    foo();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_many_elements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x9,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  lea    -0x34(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <find@plt>
  mov    -0x38(%rbp),%eax
  cmp    $0x3,%eax
  jne    L17
  mov    -0x34(%rbp),%eax
  cmp    $0x1,%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L21
L17:
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int test_many_elements() {
  int one = 0;
  int two = 0;
  int array[] = {5, 2, 9, 5, 3, 1, 9, 2};
  find(array, 8, &one, &two);
  return 3 == one && 1 == two;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_many_elements>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x9,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x9,0x28(%rsp)
  movl   $0x2,0x2c(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    $0x8,%esi
  call   <find@plt>
  mov    $0x0,%eax
  cmpl   $0x3,0x8(%rsp)
  je     L8
L28:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x48,%rsp
  ret
L8:
  cmpl   $0x1,0xc(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L28
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_many_elements() {
  int one = 0;
  int two = 0;
  int array[] = {5, 2, 9, 5, 3, 1, 9, 2};
  find(array, 8, &one, &two);
  return 3 == one && 1 == two;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_many_elements>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  movabs $0x200000005,%rax
  lea    0x8(%rsp),%rdx
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  movabs $0x500000009,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000003,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x200000009,%rax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x28(%rsp)
  call   <find@plt>
  xor    %eax,%eax
  cmpl   $0x3,0x8(%rsp)
  jne    L19
  xor    %eax,%eax
  cmpl   $0x1,0xc(%rsp)
  sete   %al
L19:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_many_elements() {
  int one = 0;
  int two = 0;
  int array[] = {5, 2, 9, 5, 3, 1, 9, 2};
  find(array, 8, &one, &two);
  return 3 == one && 1 == two;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_many_elements>:
  endbr64
  sub    $0x48,%rsp
  movdqa D4(%rip),%xmm0
  mov    $0x8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  movl   $0x0,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D14(%rip),%xmm0
  lea    0x10(%rsp),%rdi
  movl   $0x0,0xc(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <find@plt>
  xor    %eax,%eax
  cmpl   $0x3,0x8(%rsp)
  jne    L7
  xor    %eax,%eax
  cmpl   $0x1,0xc(%rsp)
  sete   %al
L7:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x48,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: byte[16]
name: retrieve_data
arguments: data_tag: D14
datatype: byte[16]

tool: {"D4": [0x05,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D14": [0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int test_many_elements() {
  int one = 0;
  int two = 0;
  int array[] = {5, 2, 9, 5, 3, 1, 9, 2};
  find(array, 8, &one, &two);
  return 3 == one && 1 == two;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D0: Input number: 

tool: D14: %d

tool: D6: fibonacci(%d) = %d


assistant: ```c
int main(void) {
  int number, value;
  printf("Input number: ");
  scanf("%d", &number);
  value = fib(number);
  printf("fibonacci(%d) = %d\n", number, value);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D20
type_guessed: string

tool: D6: Input number: 

tool: D24: %d

tool: D20: fibonacci(%d) = %d


assistant: ```c
int main(void) {
  int number, value;
  printf("Input number: ");
  scanf("%d", &number);
  value = fib(number);
  printf("fibonacci(%d) = %d\n", number, value);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D16: Input number: 

tool: D27: %d

tool: D4: fibonacci(%d) = %d


assistant: ```c
int main(void) {
  int number, value;
  printf("Input number: ");
  scanf("%d", &number);
  value = fib(number);
  printf("fibonacci(%d) = %d\n", number, value);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  mov    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D14
datatype: string

tool: D18: Input number: 

tool: D9: %d

tool: D14: fibonacci(%d) = %d


assistant: ```c
int main(void) {
  int number, value;
  printf("Input number: ");
  scanf("%d", &number);
  value = fib(number);
  printf("fibonacci(%d) = %d\n", number, value);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_side_no_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jle    L4
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L17
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_number@plt>
  test   %eax,%eax
  jne    L5
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L17
L5:
  mov    $0x1,%eax
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D5: Side no is too long! (max 4 digits)


tool: D13: Side no has to be number!


assistant: ```c
int is_side_no_valid(char *a_string) {
  if (strlen(a_string) > 4) {
    printf("Side no is too long! (max 4 digits)\n");
    return 0;
  }
  if (!is_number(a_string)) {
    printf("Side no has to be number!\n");
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_side_no_valid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4,%eax
  jg     L37
  mov    %rbx,%rdi
  call   <is_number@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L2
  mov    $0x1,%ebx
L31:
  mov    %ebx,%eax
  pop    %rbx
  ret
L37:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L31
L2:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L31
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D7: Side no is too long! (max 4 digits)


tool: D11: Side no has to be number!


assistant: ```c
int is_side_no_valid(char *a_string) {
  if (strlen(a_string) > 4) {
    printf("Side no is too long! (max 4 digits)\n");
    return 0;
  }
  if (!is_number(a_string)) {
    printf("Side no has to be number!\n");
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_side_no_valid>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x4,%eax
  jg     L5
  mov    %rbp,%rdi
  call   <is_number@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L3
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  lea    D17(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D10
datatype: string

tool: D17: Side no is too long! (max 4 digits)


tool: D10: Side no has to be number!


assistant: ```c
int is_side_no_valid(char *a_string) {
  if (strlen(a_string) > 4) {
    printf("Side no is too long! (max 4 digits)\n");
    return 0;
  }
  if (!is_number(a_string)) {
    printf("Side no has to be number!\n");
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_side_no_valid>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x4,%eax
  jg     L12
  mov    %rbp,%rdi
  call   <is_number@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L16
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    D1(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string
name: retrieve_data
arguments: data_label: D17
type: string

tool: D1: Side no is too long! (max 4 digits)


tool: D17: Side no has to be number!


assistant: ```c
int is_side_no_valid(char *a_string) {
  if (strlen(a_string) > 4) {
    printf("Side no is too long! (max 4 digits)\n");
    return 0;
  }
  if (!is_number(a_string)) {
    printf("Side no has to be number!\n");
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L73
L24:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L73
  mov    -0x10(%rbp),%eax
  add    %eax,-0x18(%rbp)
L73:
  mov    $0x0,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L24
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L39
  mov    -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x8(%rbp)
L39:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L50:
  mov    $0x0,%eax
  call   <unknown2@plt>
  test   %rax,%rax
  je     L63
  addl   $0x1,-0x4(%rbp)
  jmp    L13
L63:
  addl   $0x2,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L50
  cmpl   $0x4,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <static_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int flag) {
  int t = 0;
  int s = 0;
  int a = 0;
  int b = 0;
  while (unknown1()) {
    a++;
    b++;
    s += a;
    t += b;
    if (flag) {
      t += a;
    }
  }
  int x = 1;
  if (flag) {
    x = t - 2 * s + 2;
  }
  int y = 0;
  while (y <= x) {
    if (unknown2())
      y++;
    else
      y += 2;
  }
  static_assert(y <= 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L38
L20:
  add    $0x1,%ebp
  add    %ebp,%r12d
  add    %ebp,%ebx
  lea    (%rbx,%rbp,1),%eax
  test   %r13d,%r13d
  cmovne %eax,%ebx
L38:
  mov    $0x0,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L20
  test   %r13d,%r13d
  je     L11
  add    %r12d,%r12d
  sub    %r12d,%ebx
  add    $0x2,%ebx
  jns    L3
  mov    $0x0,%ebp
  jmp    L15
L11:
  mov    $0x1,%ebx
L3:
  mov    $0x0,%ebp
L48:
  mov    $0x0,%eax
  call   <unknown2@plt>
  cmp    $0x1,%rax
  adc    $0x1,%ebp
  cmp    %ebx,%ebp
  jle    L48
L15:
  cmp    $0x4,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <static_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(int flag) {
  int t = 0;
  int s = 0;
  int a = 0;
  int b = 0;
  while (unknown1()) {
    a++;
    b++;
    s += a;
    t += b;
    if (flag) {
      t += a;
    }
  }
  int x = 1;
  if (flag) {
    x = t - 2 * s + 2;
  }
  int y = 0;
  while (y <= x) {
    if (unknown2())
      y++;
    else
      y += 2;
  }
  static_assert(y <= 4);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%ebp
  add    %ebp,%ebx
  add    %ebp,%r12d
  test   %r13d,%r13d
  lea    (%rbx,%rbp,1),%eax
  cmovne %eax,%ebx
L63:
  xor    %eax,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L14
  test   %r13d,%r13d
  je     L62
  add    %r12d,%r12d
  sub    %r12d,%ebx
  add    $0x2,%ebx
  js     L38
L28:
  xor    %ebp,%ebp
  nop
L10:
  xor    %eax,%eax
  call   <unknown2@plt>
  cmp    $0x1,%rax
  adc    $0x1,%ebp
  cmp    %ebp,%ebx
  jge    L10
L60:
  xor    %edi,%edi
  cmp    $0x4,%ebp
  setle  %dil
  call   <static_assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  mov    $0x1,%ebx
  jmp    L28
L38:
  xor    %ebp,%ebp
  jmp    L60
```

assistant: ```c
int main(int flag) {
  int t = 0;
  int s = 0;
  int a = 0;
  int b = 0;
  while (unknown1()) {
    a++;
    b++;
    s += a;
    t += b;
    if (flag) {
      t += a;
    }
  }
  int x = 1;
  if (flag) {
    x = t - 2 * s + 2;
  }
  int y = 0;
  while (y <= x) {
    if (unknown2())
      y++;
    else
      y += 2;
  }
  static_assert(y <= 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L53
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  jmp    L4
  nopl   (%rax)
L75:
  add    $0x1,%ebx
  add    %ebx,%r12d
  lea    0x0(%rbp,%rbx,2),%ebp
L4:
  xor    %eax,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L75
  add    %r12d,%r12d
  sub    %r12d,%ebp
  add    $0x2,%ebp
  js     L1
L46:
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <unknown2@plt>
  cmp    $0x1,%rax
  adc    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L7
L70:
  xor    %edi,%edi
  cmp    $0x4,%ebx
  setle  %dil
  call   <static_assert@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  xor    %eax,%eax
  call   <unknown1@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x1,%ebp
  jmp    L46
L1:
  xor    %ebx,%ebx
  jmp    L70
```

assistant: ```c
int main(int flag) {
  int t = 0;
  int s = 0;
  int a = 0;
  int b = 0;
  while (unknown1()) {
    a++;
    b++;
    s += a;
    t += b;
    if (flag) {
      t += a;
    }
  }
  int x = 1;
  if (flag) {
    x = t - 2 * s + 2;
  }
  int y = 0;
  while (y <= x) {
    if (unknown2())
      y++;
    else
      y += 2;
  }
  static_assert(y <= 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mean_coverage2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x186000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0xbe0,%rsp
  mov    %rdi,-0x186bc8(%rbp)
  mov    %rsi,-0x186bd0(%rbp)
  mov    %rdx,-0x186bd8(%rbp)
  mov    %ecx,-0x186bdc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x186bb4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x186ba8(%rbp)
  movl   $0x0,-0x186bb0(%rbp)
  jmp    L58
L9:
  movl   $0x1,-0x186bac(%rbp)
  jmp    L23
L43:
  mov    -0x186bb0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x186bd8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x186bac(%rbp),%esi
  mov    -0x186bc8(%rbp),%rdx
  lea    -0x1a0(%rbp),%rax
  mov    %esi,%r8d
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x186ba0(%rbp),%rcx
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <load_locations@plt>
  mov    %eax,-0x186ba4(%rbp)
  mov    -0x186bb0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x186bd8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x186bac(%rbp),%esi
  mov    -0x186bd0(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    %esi,%r8d
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x186ba4(%rbp),%edx
  lea    -0x186ba0(%rbp),%rcx
  lea    -0xd0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <load_locations@plt>
  mov    %eax,-0x186ba4(%rbp)
  lea    -0x186bbc(%rbp),%rdi
  lea    -0x186bc0(%rbp),%rcx
  lea    -0x186bb8(%rbp),%rdx
  mov    -0x186ba4(%rbp),%esi
  lea    -0x186ba0(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <coverage@plt>
  movss  -0x186bb8(%rbp),%xmm0
  movss  -0x186ba8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x186ba8(%rbp)
  addl   $0x1,-0x186bb4(%rbp)
  addl   $0x1,-0x186bac(%rbp)
L23:
  cmpl   $0x6,-0x186bac(%rbp)
  jle    L43
  addl   $0x1,-0x186bb0(%rbp)
L58:
  mov    -0x186bb0(%rbp),%eax
  cmp    -0x186bdc(%rbp),%eax
  jl     L9
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x186bb4(%rbp),%xmm1
  movss  -0x186ba8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: data/%s_%s%d.txt

assistant: ```c
float mean_coverage2(char *opname1, char *opname2, char **imsets, int nimsets) {
  int nfiles = 0, i, fno, nlocs, np, nc;
  float locs[200000][2];
  float csum = 0.0, cov;
  char fn1[200], fn2[200];
  for (i = 0; i < nimsets; i++) {
    for (fno = 1; fno < 7; fno++) {
      sprintf(fn1, "data/%s_%s%d.txt", opname1, imsets[i], fno);
      nlocs = load_locations(fn1, locs, 0);
      sprintf(fn2, "data/%s_%s%d.txt", opname2, imsets[i], fno);
      nlocs = load_locations(fn2, locs, nlocs);
      coverage(locs, nlocs, &cov, &np, &nc);
      csum += cov;
      nfiles += 1;
    }
  }
  return csum / nfiles;
}
```