user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L112
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L27
L112:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L66
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L16
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L106
L16:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L106:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  jmp    L27
L66:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L94
  subl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
  jmp    L66
L94:
  nop
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
L69:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L60
  subl   $0x1,-0x2c(%rbp)
  subl   $0x1,-0x24(%rbp)
  jmp    L69
L60:
  nop
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L102
L35:
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L102:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L35
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
L27:
  leave
  ret
```

assistant: ```c
char *str_trim(char *string) {
  int final_len = strlen(string);
  int i = 0;
  const int len = strlen(string);
  if (len == 0) {
    char *output = malloc(sizeof(char));
    output[0] = '\0';
    return output;
  }
  if (len == 1) {
    char *output;
    if (string[0] != ' ') {
      output = malloc(sizeof(char) * 2);
      output[0] = string[0];
      output[1] = '\0';
    } else {
      output = malloc(sizeof(char));
      output[0] = '\0';
    }
    free(string);
    return output;
  }
  while (true) {
    if (string[i] != ' ') {
      break;
    } else {
      final_len -= 1;
      i += 1;
    }
  }
  int k = len - 1;
  while (true) {
    if (string[k] != ' ') {
      break;
    } else {
      final_len -= 1;
      k -= 1;
    }
  }
  char *output = malloc(sizeof(char) * (final_len + 1));
  for (int l = 0; l < final_len; l += 1) {
    output[l] = string[l + i];
  }
  output[final_len] = '\0';
  free(string);
  return output;
}
```