ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<pow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pow2>:
  endbr64
  sub    $0x8,%rsp
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pow2>:
  endbr64
  jmp    1050 <pow@plt>
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pow2>:
  endbr64
  jmp    1050 <pow@plt>
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<closePlayLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %esi,-0x128(%rbp)
  mov    %rdx,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D30(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L18
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L18:
  mov    -0x118(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x124(%rbp),%ecx
  mov    -0x130(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L13:
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D30
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D30: data/logs/TripletsLog-%d.txt

tool: D20: at

tool: D1: 
	ERR: Couldn't close %s

tool: D39: # Game closed successfully!


tool: D9: # Winner: %s - %d moves

assistant: ```c
void closePlayLog(int playNumber, int gameCounter, char playerName[]) {
  FILE *playLog;
  char logName[255];
  sprintf(logName, "data/logs/TripletsLog-%d.txt", gameCounter);
  playLog = fopen(logName, "at");
  if (playLog == NULL) {
    printf("\n\tERR: Couldn't close %s", logName);
  } else {
    fprintf(playLog, "# Game closed successfully!\n");
    fprintf(playLog, "# Winner: %s - %d moves", playerName, playNumber);
  }
  fclose(playLog);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<closePlayLog>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %esi,%edx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rax,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D40(%rip),%rdi
  call   <fwrite@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L24:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D47
datatype: string
name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D24
datatype: string
name: unpack_data
arguments: data_label: D18
datatype: string

tool: D7: data/logs/TripletsLog-%d.txt

tool: D47: at

tool: D40: # Game closed successfully!


tool: D24: # Winner: %s - %d moves

tool: D18: 
	ERR: Couldn't close %s

assistant: ```c
void closePlayLog(int playNumber, int gameCounter, char playerName[]) {
  FILE *playLog;
  char logName[255];
  sprintf(logName, "data/logs/TripletsLog-%d.txt", gameCounter);
  playLog = fopen(logName, "at");
  if (playLog == NULL) {
    printf("\n\tERR: Couldn't close %s", logName);
  } else {
    fprintf(playLog, "# Game closed successfully!\n");
    fprintf(playLog, "# Winner: %s - %d moves", playerName, playNumber);
  }
  fclose(playLog);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<closePlayLog>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    %esi,%edx
  lea    D31(%rip),%rsi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  lea    D24(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  mov    %rax,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D25(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
L22:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    %r14,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D21
type: string

tool: D31: data/logs/TripletsLog-%d.txt

tool: D24: at

tool: D16: # Game closed successfully!


tool: D25: # Winner: %s - %d moves

tool: D21: 
	ERR: Couldn't close %s

assistant: ```c
void closePlayLog(int playNumber, int gameCounter, char playerName[]) {
  FILE *playLog;
  char logName[255];
  sprintf(logName, "data/logs/TripletsLog-%d.txt", gameCounter);
  playLog = fopen(logName, "at");
  if (playLog == NULL) {
    printf("\n\tERR: Couldn't close %s", logName);
  } else {
    fprintf(playLog, "# Game closed successfully!\n");
    fprintf(playLog, "# Winner: %s - %d moves", playerName, playNumber);
  }
  fclose(playLog);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<closePlayLog>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    %esi,%edx
  lea    D39(%rip),%rsi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <sprintf@plt>
  lea    D23(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
  mov    %rax,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D30(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
L23:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %r14,%rsi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type: string
name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D7
type: string
name: retrieve_data
arguments: data_tag: D30
type: string
name: retrieve_data
arguments: data_tag: D42
type: string

tool: D39: data/logs/TripletsLog-%d.txt

tool: D23: at

tool: D7: # Game closed successfully!


tool: D30: # Winner: %s - %d moves

tool: D42: 
	ERR: Couldn't close %s

assistant: ```c
void closePlayLog(int playNumber, int gameCounter, char playerName[]) {
  FILE *playLog;
  char logName[255];
  sprintf(logName, "data/logs/TripletsLog-%d.txt", gameCounter);
  playLog = fopen(logName, "at");
  if (playLog == NULL) {
    printf("\n\tERR: Couldn't close %s", logName);
  } else {
    fprintf(playLog, "# Game closed successfully!\n");
    fprintf(playLog, "# Winner: %s - %d moves", playerName, playNumber);
  }
  fclose(playLog);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rl_internal_bitpos>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%r9d
  mov    $0x0,%ecx
  test   %edx,%edx
  jne    L10
  mov    D12(%rip),%rdx
  mov    (%rdx),%rcx
L10:
  test   $0x7,%al
  je     L163
  test   %rsi,%rsi
  je     L163
  mov    $0x0,%r8d
L95:
  movzbl (%rax),%edx
  cmp    %rcx,%rdx
  jne    L178
  add    $0x1,%rax
  sub    $0x1,%rsi
  add    $0x8,%r8
  test   $0x7,%al
  je     L178
  test   %rsi,%rsi
  jne    L95
L178:
  mov    $0x0,%edx
  test   %r9d,%r9d
  jne    L70
  mov    D25(%rip),%rdx
  mov    (%rdx),%rdx
L70:
  cmp    $0x7,%rsi
  jbe    L151
L167:
  cmp    %rdx,(%rax)
  jne    L151
  add    $0x8,%rax
  sub    $0x8,%rsi
  add    $0x40,%r8
  cmp    $0x7,%rsi
  ja     L167
L151:
  mov    $0x8,%ecx
  mov    $0x0,%edx
  jmp    L148
L163:
  mov    $0x0,%r8d
  jmp    L178
L188:
  sub    $0x1,%rcx
  je     L60
L148:
  shl    $0x8,%rdx
  test   %rsi,%rsi
  je     L188
  movzbl (%rax),%edi
  or     %rdi,%rdx
  add    $0x1,%rax
  sub    $0x1,%rsi
  jmp    L188
L60:
  cmp    $0x1,%r9d
  jne    L197
  test   %rdx,%rdx
  je     L36
L197:
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  shr    %rax
  not    %rax
  test   %rax,%rdx
  setne  %cl
  movzbl %cl,%ecx
  cmp    %ecx,%r9d
  je     L47
  add    $0x1,%r8
  shr    %rax
L86:
  test   %rax,%rdx
  setne  %cl
  movzbl %cl,%ecx
  cmp    %r9d,%ecx
  je     L47
  add    $0x1,%r8
  shr    %rax
  jne    L86
  mov    $0xfffffffffffffffe,%r8
L47:
  mov    %r8,%rax
  ret
L36:
  mov    $0xffffffffffffffff,%r8
  jmp    L47
```

assistant: ```c
long rl_internal_bitpos(void *s, unsigned long count, int bit) {
  unsigned long *l;
  unsigned char *c;
  unsigned long skipval, word = 0, one;
  long pos = 0;
  unsigned long j;
  skipval = bit ? 0 : UCHAR_MAX;
  c = (unsigned char *)s;
  while ((unsigned long)c & (sizeof(*l) - 1) && count) {
    if (*c != skipval)
      break;
    c++;
    count--;
    pos += 8;
  }
  skipval = bit ? 0 : ULONG_MAX;
  l = (unsigned long *)c;
  while (count >= sizeof(*l)) {
    if (*l != skipval)
      break;
    l++;
    count -= sizeof(*l);
    pos += sizeof(*l) * 8;
  }
  c = (unsigned char *)l;
  for (j = 0; j < sizeof(*l); j++) {
    word <<= 8;
    if (count) {
      word |= *c;
      c++;
      count--;
    }
  }
  if (bit == 1 && word == 0)
    return -1;
  one = ULONG_MAX;
  one >>= 1;
  one = ~one;
  while (one) {
    if (((one & word) != 0) == bit)
      return pos;
    pos++;
    one >>= 1;
  }
  return -2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rl_internal_bitpos>:
  endbr64
  mov    %edx,%r9d
  mov    %rdi,%rdx
  mov    %rdi,%rax
  and    $0x7,%edx
  test   %r9d,%r9d
  jne    L55
  mov    D11(%rip),%rcx
  xor    %r8d,%r8d
  mov    (%rcx),%rcx
  test   %rdx,%rdx
  je     L201
  test   %rsi,%rsi
  jne    L180
L165:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L90:
  xor    %esi,%esi
L154:
  mov    $0x8,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax)
L161:
  shl    $0x8,%rdx
  test   %rsi,%rsi
  je     L107
  movzbl (%rax),%edi
  sub    $0x1,%rsi
  add    $0x1,%rax
  or     %rdi,%rdx
L107:
  sub    $0x1,%rcx
  jne    L161
  cmp    $0x1,%r9d
  jne    L23
  test   %rdx,%rdx
  je     L118
L23:
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  shr    %rax
  not    %rax
  nopl   0x0(%rax)
L178:
  xor    %ecx,%ecx
  test   %rax,%rdx
  setne  %cl
  cmp    %r9d,%ecx
  je     L15
  add    $0x1,%r8
  shr    %rax
  jne    L178
  mov    $0xfffffffffffffffe,%r8
L15:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L55:
  xor    %r8d,%r8d
  test   %rdx,%rdx
  je     L63
  test   %rsi,%rsi
  je     L165
  xor    %ecx,%ecx
L180:
  xor    %r8d,%r8d
  jmp    L139
L88:
  add    $0x1,%rax
  sub    $0x1,%rsi
  add    $0x8,%r8
  test   $0x7,%al
  je     L39
  test   %rsi,%rsi
  je     L90
L139:
  movzbl (%rax),%edx
  cmp    %rcx,%rdx
  je     L88
L39:
  xor    %edx,%edx
  test   %r9d,%r9d
  jne    L63
L201:
  mov    D2(%rip),%rdx
  mov    (%rdx),%rdx
  jmp    L63
  nopl   0x0(%rax)
L86:
  add    $0x8,%rax
  sub    $0x8,%rsi
  add    $0x40,%r8
L63:
  cmp    $0x7,%rsi
  jbe    L154
  cmp    %rdx,(%rax)
  je     L86
  jmp    L154
L118:
  mov    $0xffffffffffffffff,%r8
  jmp    L15
```

assistant: ```c
long rl_internal_bitpos(void *s, unsigned long count, int bit) {
  unsigned long *l;
  unsigned char *c;
  unsigned long skipval, word = 0, one;
  long pos = 0;
  unsigned long j;
  skipval = bit ? 0 : UCHAR_MAX;
  c = (unsigned char *)s;
  while ((unsigned long)c & (sizeof(*l) - 1) && count) {
    if (*c != skipval)
      break;
    c++;
    count--;
    pos += 8;
  }
  skipval = bit ? 0 : ULONG_MAX;
  l = (unsigned long *)c;
  while (count >= sizeof(*l)) {
    if (*l != skipval)
      break;
    l++;
    count -= sizeof(*l);
    pos += sizeof(*l) * 8;
  }
  c = (unsigned char *)l;
  for (j = 0; j < sizeof(*l); j++) {
    word <<= 8;
    if (count) {
      word |= *c;
      c++;
      count--;
    }
  }
  if (bit == 1 && word == 0)
    return -1;
  one = ULONG_MAX;
  one >>= 1;
  one = ~one;
  while (one) {
    if (((one & word) != 0) == bit)
      return pos;
    pos++;
    one >>= 1;
  }
  return -2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D20(%rip),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <power@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <power@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
type_guessed: byte[8]
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D48
type_guessed: string

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D6: %.0f


tool: D5: Enter n and p (n^p): 

tool: D28: %lf

tool: D3: %d

tool: D48: The pow is: %.0f


assistant: ```c
int main() {
  printf("%.0f\n", power(5, 2));
  printf("Enter n and p (n^p): ");
  double n;
  int p;
  scanf("%lf", &n);
  scanf("%d", &p);
  printf("The pow is: %.0f\n", power(n, p));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edi
  movsd  D23(%rip),%xmm0
  call   <power@plt>
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  movsd  0x10(%rsp),%xmm0
  call   <power@plt>
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type: byte[8]
name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D27
type: string
name: retrieve_data
arguments: data_label: D59
type: string
name: retrieve_data
arguments: data_label: D42
type: string
name: retrieve_data
arguments: data_label: D14
type: string

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D18: %.0f


tool: D27: Enter n and p (n^p): 

tool: D59: %lf

tool: D42: %d

tool: D14: The pow is: %.0f


assistant: ```c
int main() {
  printf("%.0f\n", power(5, 2));
  printf("Enter n and p (n^p): ");
  double n;
  int p;
  scanf("%lf", &n);
  scanf("%d", &p);
  printf("The pow is: %.0f\n", power(n, p));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movsd  D47(%rip),%xmm0
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <power@plt>
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  movsd  0x10(%rsp),%xmm0
  call   <power@plt>
  lea    D50(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D47
type: byte[8]
name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D52
type: string
name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D37
type: string
name: read_data
arguments: label: D50
type: string

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D5: %.0f


tool: D52: Enter n and p (n^p): 

tool: D19: %lf

tool: D37: %d

tool: D50: The pow is: %.0f


assistant: ```c
int main() {
  printf("%.0f\n", power(5, 2));
  printf("Enter n and p (n^p): ");
  double n;
  int p;
  scanf("%lf", &n);
  scanf("%d", &p);
  printf("The pow is: %.0f\n", power(n, p));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movsd  D10(%rip),%xmm0
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <power@plt>
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  movsd  0x10(%rsp),%xmm0
  call   <power@plt>
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_guessed: byte[8]
name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D44
type_guessed: string
name: unpack_data
arguments: data_tag: D48
type_guessed: string
name: unpack_data
arguments: data_tag: D52
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D24: %.0f


tool: D44: Enter n and p (n^p): 

tool: D48: %lf

tool: D52: %d

tool: D3: The pow is: %.0f


assistant: ```c
int main() {
  printf("%.0f\n", power(5, 2));
  printf("Enter n and p (n^p): ");
  double n;
  int p;
  scanf("%lf", &n);
  scanf("%d", &p);
  printf("The pow is: %.0f\n", power(n, p));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scrypt_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x18(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: byte[8]

tool: {"D2": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double scrypt_log2(uint32_t n) {
  double temp;
  temp = log(2);
  return (log((double)n) / temp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scrypt_log2>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  call   <log@plt>
  divsd  D0(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: byte[8]

tool: {"D0": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double scrypt_log2(uint32_t n) {
  double temp;
  temp = log(2);
  return (log((double)n) / temp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scrypt_log2>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2sd %rdi,%xmm0
  call   <log@plt>
  divsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: byte[8]

tool: {"D2": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double scrypt_log2(uint32_t n) {
  double temp;
  temp = log(2);
  return (log((double)n) / temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<scrypt_log2>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2sd %rdi,%xmm0
  call   <log@plt>
  divsd  D3(%rip),%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: byte[8]

tool: {"D3": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double scrypt_log2(uint32_t n) {
  double temp;
  temp = log(2);
  return (log((double)n) / temp);
}
```