ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Merge_Sort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x0(,%rsi,4),%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  test   %rax,%rax
  jne    L6
  pop    %rbx
  mov    $0xffffffff,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <exit@plt>
  nopl   0x0(%rax)
L6:
  mov    %rax,%rbp
  mov    %r12,%rdi
  lea    -0x1(%rbx),%ecx
  xor    %edx,%edx
  mov    %rax,%rsi
  call   <MSort@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

assistant: ```c
void Merge_Sort(int A[], int N) {
  int *TmpA = (int *)malloc(N * sizeof(int));
  if (NULL == TmpA)
    exit(-1);
  else {
    MSort(A, TmpA, 0, N - 1);
    free(TmpA);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Merge_Sort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    0x0(,%rsi,4),%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  mov    $0xffffffff,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <exit@plt>
  nopl   0x0(%rax)
L8:
  mov    %rax,%rbp
  mov    %r12,%rdi
  lea    -0x1(%rbx),%ecx
  xor    %edx,%edx
  mov    %rax,%rsi
  call   <MSort@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

assistant: ```c
void Merge_Sort(int A[], int N) {
  int *TmpA = (int *)malloc(N * sizeof(int));
  if (NULL == TmpA)
    exit(-1);
  else {
    MSort(A, TmpA, 0, N - 1);
    free(TmpA);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  lea    D4(%rip),%rax
  mov    %rax,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: NULL

assistant: ```c
void fputs(int fd, const char *s) {
  if (!s)
    s = "NULL";
  write(fd, s, strlen(s));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  lea    D4(%rip),%rax
  cmove  %rax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: NULL

assistant: ```c
void fputs(int fd, const char *s) {
  if (!s)
    s = "NULL";
  write(fd, s, strlen(s));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fputs>:
  endbr64
  push   %r12
  lea    D3(%rip),%rax
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  cmove  %rax,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <write@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: NULL

assistant: ```c
void fputs(int fd, const char *s) {
  if (!s)
    s = "NULL";
  write(fd, s, strlen(s));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fputs>:
  endbr64
  push   %r12
  lea    D1(%rip),%rax
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  cmove  %rax,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <write@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: NULL

assistant: ```c
void fputs(int fd, const char *s) {
  if (!s)
    s = "NULL";
  write(fd, s, strlen(s));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CALLOC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *CALLOC(size_t num, size_t size) {
  void *temp = calloc(num, size);
  assert(temp);
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CALLOC>:
  endbr64
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *CALLOC(size_t num, size_t size) {
  void *temp = calloc(num, size);
  assert(temp);
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CALLOC>:
  endbr64
  push   %r12
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *CALLOC(size_t num, size_t size) {
  void *temp = calloc(num, size);
  assert(temp);
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CALLOC>:
  endbr64
  push   %r12
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *CALLOC(size_t num, size_t size) {
  void *temp = calloc(num, size);
  assert(temp);
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L1
L122:
  movl   $0x1,-0x10(%rbp)
  jmp    L115
L48:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L115:
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L48
  movl   $0x1,-0x10(%rbp)
  jmp    L93
L104:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L93:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L104
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L122
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L70
L109:
  movl   $0x1,-0x10(%rbp)
  jmp    L30
L33:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L33
  movl   $0x1,-0x10(%rbp)
  jmp    L88
L94:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L88:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L94
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x14(%rbp)
L70:
  cmpl   $0x0,-0x14(%rbp)
  jg     L109
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: %d

assistant: ```c
int main() {
  int n, i, j, k;
  scanf("%d", &n);
  k = (n + 1) / 2;
  for (i = 1; i <= k; i++) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  for (i = k - 1; i >= 1; i--) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,%r12d
  shr    $0x1f,%r12d
  add    %edx,%r12d
  sar    %r12d
  test   %eax,%eax
  jle    L81
  lea    -0x1(%r12),%r13d
  mov    $0x2,%r14d
  jmp    L5
L77:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L77
L37:
  mov    %r14d,%ebp
  cmp    $0x1,%r14d
  jle    L79
  mov    $0x1,%ebx
L69:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L69
L79:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  add    $0x2,%r14d
  mov    %r12d,%eax
  sub    %r13d,%eax
  cmp    %r12d,%eax
  jg     L81
L5:
  mov    %r13d,%ebp
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jg     L77
  jmp    L37
L81:
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jle    L115
  add    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L105
L89:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L89
L57:
  mov    %r12d,%ebp
  cmp    $0x1,%r12d
  jle    L143
  mov    $0x1,%ebx
L94:
  mov    $0x2a,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L94
L143:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  sub    $0x2,%r12d
  je     L115
L105:
  mov    %r13d,%ebp
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jg     L89
  jmp    L57
L115:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L126
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L126:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  int n, i, j, k;
  scanf("%d", &n);
  k = (n + 1) / 2;
  for (i = 1; i <= k; i++) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  for (i = k - 1; i >= 1; i--) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,%r14d
  shr    $0x1f,%r14d
  add    %edx,%r14d
  sar    %r14d
  lea    -0x1(%r14),%r12d
  mov    %r12d,%ebp
  test   %eax,%eax
  jle    L53
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L76
  nopl   0x0(%rax)
L93:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L93
L76:
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L24
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x2,%r13d
  call   <putchar@plt>
  mov    %r14d,%eax
  sub    %ebp,%eax
  cmp    %eax,%r14d
  jge    L22
L53:
  test   %r12d,%r12d
  jle    L59
  lea    (%r12,%r12,1),%ebp
  mov    $0x1,%r12d
  nopl   0x0(%rax)
L40:
  mov    $0x1,%ebx
  nopl   (%rax)
L27:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jle    L27
  mov    $0x1,%ebx
  nop
L8:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L8
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  sub    $0x2,%ebp
  jne    L40
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: %d

assistant: ```c
int main() {
  int n, i, j, k;
  scanf("%d", &n);
  k = (n + 1) / 2;
  for (i = 1; i <= k; i++) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  for (i = k - 1; i >= 1; i--) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%rdi
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,%r14d
  shr    $0x1f,%r14d
  add    %edx,%r14d
  sar    %r14d
  lea    -0x1(%r14),%r12d
  mov    %r12d,%ebp
  test   %eax,%eax
  jle    L59
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L20
  nopl   0x0(%rax)
L64:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L64
L20:
  mov    $0x1,%ebx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L1
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x2,%r13d
  call   <putchar@plt>
  mov    %r14d,%eax
  sub    %ebp,%eax
  cmp    %eax,%r14d
  jge    L5
L59:
  test   %r12d,%r12d
  jle    L18
  lea    (%r12,%r12,1),%ebp
  mov    $0x1,%r12d
  nopl   0x0(%rax)
L37:
  mov    $0x1,%ebx
  nopl   (%rax)
L21:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L21
  mov    $0x1,%ebx
  nop
L35:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L35
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  sub    $0x2,%ebp
  jne    L37
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %d

assistant: ```c
int main() {
  int n, i, j, k;
  scanf("%d", &n);
  k = (n + 1) / 2;
  for (i = 1; i <= k; i++) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  for (i = k - 1; i >= 1; i--) {
    for (j = 1; j <= k - i; j++)
      putchar(' ');
    for (j = 1; j <= 2 * i - 1; j++)
      putchar('*');
    putchar('\n');
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dmedian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  cmpq   $0x0,-0x30(%rbp)
  jle    L14
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <rangk12@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
L14:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dmedian(double a[], long n) {
  double value = 0.0;
  long k1 = (n - 1) / 2;
  long k2 = n / 2;
  if (a && (n > 0)) {
    value = rangk12(a, n, k1, k2);
  }
  return (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dmedian>:
  endbr64
  test   %rdi,%rdi
  je     L7
  test   %rsi,%rsi
  jg     L0
L7:
  pxor   %xmm0,%xmm0
  ret
L0:
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  shr    $0x3f,%rcx
  add    %rsi,%rcx
  sar    %rcx
  lea    -0x1(%rsi),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rax,%rdx
  sar    %rdx
  call   <rangk12@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double dmedian(double a[], long n) {
  double value = 0.0;
  long k1 = (n - 1) / 2;
  long k2 = n / 2;
  if (a && (n > 0)) {
    value = rangk12(a, n, k1, k2);
  }
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dmedian>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %rsi,%rsi
  jg     L10
L1:
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rsi,%rcx
  lea    -0x1(%rsi),%rdx
  sar    %rcx
  sar    %rdx
  jmp    1050 <rangk12@plt>
```

assistant: ```c
double dmedian(double a[], long n) {
  double value = 0.0;
  long k1 = (n - 1) / 2;
  long k2 = n / 2;
  if (a && (n > 0)) {
    value = rangk12(a, n, k1, k2);
  }
  return (value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dmedian>:
  endbr64
  test   %rdi,%rdi
  je     L14
  test   %rsi,%rsi
  jg     L3
L14:
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rsi,%rcx
  lea    -0x1(%rsi),%rdx
  sar    %rcx
  sar    %rdx
  jmp    1050 <rangk12@plt>
```

assistant: ```c
double dmedian(double a[], long n) {
  double value = 0.0;
  long k1 = (n - 1) / 2;
  long k2 = n / 2;
  if (a && (n > 0)) {
    value = rangk12(a, n, k1, k2);
  }
  return (value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nrf_settx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x12,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <putMessage@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void nrf_settx() {
  unsigned char cmd;
  cmd = 0x12;
  putMessage(&cmd, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nrf_settx>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x12,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  mov    $0x1,%esi
  call   <putMessage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nrf_settx() {
  unsigned char cmd;
  cmd = 0x12;
  putMessage(&cmd, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nrf_settx>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x12,0x7(%rsp)
  call   <putMessage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nrf_settx() {
  unsigned char cmd;
  cmd = 0x12;
  putMessage(&cmd, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nrf_settx>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x12,0x7(%rsp)
  call   <putMessage@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nrf_settx() {
  unsigned char cmd;
  cmd = 0x12;
  putMessage(&cmd, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WidthMoon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x48(%rbp),%xmm1
  movsd  D47(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x50(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  movapd %xmm1,%xmm5
  mulsd  %xmm0,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mov    %eax,%ebx
  movsd  -0x48(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  movapd %xmm1,%xmm6
  mulsd  %xmm0,%xmm6
  movq   %xmm6,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  imul   %ebx,%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x18(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mov    %eax,%ebx
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x30(%rbp),%xmm1
  movsd  D48(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  imul   %ebx,%eax
  mov    $0x1,%edx
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  -0x50(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D47
type: f64
name: read_data
arguments: data_label: D48
type: byte[8]

tool: D47: 0.27245

tool: {"D48": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
double WidthMoon(double AltO, double AziO, double AltS, double AziS, double parallax) {
  double GeoAltO = AltO + parallax;
  return 0.27245 * parallax * (1 + sin(GeoAltO * (3.14159265358979323846 / 180.0)) * sin(parallax * (3.14159265358979323846 / 180.0))) * (1 - cos((AltS - GeoAltO) * (3.14159265358979323846 / 180.0)) * cos((AziS - AziO) * (3.14159265358979323846 / 180.0)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<WidthMoon>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm1,%r14
  movq   %xmm2,%rbp
  movq   %xmm3,%rbx
  movsd  %xmm4,(%rsp)
  addsd  %xmm4,%xmm0
  movapd %xmm0,%xmm5
  movsd  D36(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  mulsd  %xmm5,%xmm0
  call   <sin@plt>
  mov    %eax,%r12d
  movsd  D36(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  call   <sin@plt>
  imul   %eax,%r12d
  add    $0x1,%r12d
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  movsd  (%rsp),%xmm4
  mulsd  D22(%rip),%xmm4
  mulsd  %xmm4,%xmm1
  movsd  %xmm1,(%rsp)
  movq   %rbp,%xmm0
  subsd  0x8(%rsp),%xmm0
  mulsd  D36(%rip),%xmm0
  call   <cos@plt>
  mov    %eax,%ebp
  movq   %rbx,%xmm0
  movq   %r14,%xmm6
  subsd  %xmm6,%xmm0
  mulsd  D36(%rip),%xmm0
  call   <cos@plt>
  imul   %eax,%ebp
  mov    $0x1,%eax
  sub    %ebp,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D36
type: byte[8]
name: extract_symbolic_data
arguments: tag: D22
type: f64

tool: {"D36": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: D22: 0.27245

assistant: ```c
double WidthMoon(double AltO, double AziO, double AltS, double AziS, double parallax) {
  double GeoAltO = AltO + parallax;
  return 0.27245 * parallax * (1 + sin(GeoAltO * (3.14159265358979323846 / 180.0)) * sin(parallax * (3.14159265358979323846 / 180.0))) * (1 - cos((AltS - GeoAltO) * (3.14159265358979323846 / 180.0)) * cos((AziS - AziO) * (3.14159265358979323846 / 180.0)));
}
```