user: 这段汇编代码用C语言表示是什么样的？

```asm
<trap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jg     L9
  mov    $0x0,%eax
  jmp    L20
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L77:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L3
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L3:
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L77
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L49
L88:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L66
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L66:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
L46:
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L88
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L123
L98:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L30
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L118
L30:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
L118:
  subl   $0x1,-0x10(%rbp)
L123:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L98
  mov    -0x4(%rbp),%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int trap(int *height, int heightSize) {
  if (heightSize < 2)
    return 0;
  int i, heightest, pos, water;
  heightest = height[0];
  pos = 0;
  for (i = 1; i < heightSize; ++i) {
    if (heightest < height[i]) {
      heightest = height[i];
      pos = i;
    }
  }
  water = 0;
  heightest = height[0];
  for (i = 1; i < pos; ++i) {
    if (height[i] > heightest)
      heightest = height[i];
    else
      water += heightest - height[i];
  }
  heightest = height[heightSize - 1];
  for (i = heightSize - 2; i > pos; --i) {
    if (height[i] > heightest)
      heightest = height[i];
    else
      water += heightest - height[i];
  }
  return water;
}
```