ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<orient3dfast>:
  endbr64
  movsd  (%rcx),%xmm7
  movsd  0x8(%rcx),%xmm0
  movsd  0x8(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  0x8(%rsi),%xmm3
  subsd  %xmm0,%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm0,%xmm2
  movsd  0x10(%rcx),%xmm0
  movsd  0x10(%rdi),%xmm5
  subsd  %xmm0,%xmm5
  movsd  0x10(%rsi),%xmm6
  subsd  %xmm0,%xmm6
  movsd  0x10(%rdx),%xmm4
  subsd  %xmm0,%xmm4
  movapd %xmm3,%xmm0
  mulsd  %xmm4,%xmm0
  movapd %xmm2,%xmm8
  mulsd  %xmm6,%xmm8
  subsd  %xmm8,%xmm0
  movsd  (%rdi),%xmm8
  subsd  %xmm7,%xmm8
  mulsd  %xmm8,%xmm0
  mulsd  %xmm5,%xmm2
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  movsd  (%rsi),%xmm4
  subsd  %xmm7,%xmm4
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm3,%xmm1
  movsd  (%rdx),%xmm2
  subsd  %xmm7,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double orient3dfast(double *pa, double *pb, double *pc, double *pd) {
  double adx, bdx, cdx;
  double ady, bdy, cdy;
  double adz, bdz, cdz;
  adx = pa[0] - pd[0];
  bdx = pb[0] - pd[0];
  cdx = pc[0] - pd[0];
  ady = pa[1] - pd[1];
  bdy = pb[1] - pd[1];
  cdy = pc[1] - pd[1];
  adz = pa[2] - pd[2];
  bdz = pb[2] - pd[2];
  cdz = pc[2] - pd[2];
  return adx * (bdy * cdz - bdz * cdy) + bdx * (cdy * adz - cdz * ady) + cdx * (ady * bdz - adz * bdy);
}
```
user: What is the c source code of the assembly code below:

```asm
<orient3dfast>:
  endbr64
  movsd  0x8(%rcx),%xmm0
  movsd  0x8(%rdi),%xmm1
  movsd  0x8(%rsi),%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm6
  movsd  0x10(%rsi),%xmm7
  subsd  %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  movsd  0x10(%rdx),%xmm4
  movsd  (%rcx),%xmm5
  movsd  0x10(%rcx),%xmm0
  subsd  %xmm0,%xmm6
  subsd  %xmm0,%xmm7
  movapd %xmm2,%xmm8
  subsd  %xmm0,%xmm4
  movapd %xmm3,%xmm0
  mulsd  %xmm7,%xmm8
  mulsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm2
  mulsd  %xmm1,%xmm4
  mulsd  %xmm6,%xmm3
  mulsd  %xmm7,%xmm1
  subsd  %xmm8,%xmm0
  movsd  (%rdi),%xmm8
  subsd  %xmm4,%xmm2
  movsd  (%rsi),%xmm4
  subsd  %xmm5,%xmm8
  subsd  %xmm5,%xmm4
  subsd  %xmm3,%xmm1
  mulsd  %xmm8,%xmm0
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  movsd  (%rdx),%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double orient3dfast(double *pa, double *pb, double *pc, double *pd) {
  double adx, bdx, cdx;
  double ady, bdy, cdy;
  double adz, bdz, cdz;
  adx = pa[0] - pd[0];
  bdx = pb[0] - pd[0];
  cdx = pc[0] - pd[0];
  ady = pa[1] - pd[1];
  bdy = pb[1] - pd[1];
  cdy = pc[1] - pd[1];
  adz = pa[2] - pd[2];
  bdz = pb[2] - pd[2];
  cdz = pc[2] - pd[2];
  return adx * (bdy * cdz - bdz * cdy) + bdx * (cdy * adz - cdz * ady) + cdx * (ady * bdz - adz * bdy);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<orient3dfast>:
  endbr64
  movsd  0x8(%rcx),%xmm0
  movsd  0x8(%rdi),%xmm1
  movsd  0x8(%rsi),%xmm3
  movsd  0x8(%rdx),%xmm2
  subsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm6
  movsd  0x10(%rsi),%xmm7
  subsd  %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  movsd  0x10(%rdx),%xmm4
  movsd  (%rcx),%xmm5
  movsd  0x10(%rcx),%xmm0
  subsd  %xmm0,%xmm6
  subsd  %xmm0,%xmm7
  movapd %xmm2,%xmm8
  subsd  %xmm0,%xmm4
  movapd %xmm3,%xmm0
  mulsd  %xmm7,%xmm8
  mulsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm2
  mulsd  %xmm1,%xmm4
  mulsd  %xmm6,%xmm3
  mulsd  %xmm7,%xmm1
  subsd  %xmm8,%xmm0
  movsd  (%rdi),%xmm8
  subsd  %xmm4,%xmm2
  movsd  (%rsi),%xmm4
  subsd  %xmm5,%xmm8
  subsd  %xmm5,%xmm4
  subsd  %xmm3,%xmm1
  mulsd  %xmm8,%xmm0
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  movsd  (%rdx),%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double orient3dfast(double *pa, double *pb, double *pc, double *pd) {
  double adx, bdx, cdx;
  double ady, bdy, cdy;
  double adz, bdz, cdz;
  adx = pa[0] - pd[0];
  bdx = pb[0] - pd[0];
  cdx = pc[0] - pd[0];
  ady = pa[1] - pd[1];
  bdy = pb[1] - pd[1];
  cdy = pc[1] - pd[1];
  adz = pa[2] - pd[2];
  bdz = pb[2] - pd[2];
  cdz = pc[2] - pd[2];
  return adx * (bdy * cdz - bdz * cdy) + bdx * (cdy * adz - cdz * ady) + cdx * (ady * bdz - adz * bdy);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L29:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x2d,-0x18(%rbp)
  je     L54
  cmpl   $0x2b,-0x18(%rbp)
  jne    L28
L54:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
L28:
  movq   $0x0,-0x10(%rbp)
  jmp    L7
L1:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
L7:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L1
  cmpl   $0x2d,-0x14(%rbp)
  jne    L25
  mov    -0x10(%rbp),%rax
  neg    %rax
  jmp    L71
L25:
  mov    -0x10(%rbp),%rax
L71:
  leave
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  jmp    L45
L1:
  add    $0x1,%rbp
L45:
  movzbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L1
  movzbl 0x0(%rbp),%eax
  movzbl %al,%r13d
  sub    $0x2b,%eax
  test   $0xfd,%al
  je     L36
  lea    0x1(%rbp),%r12
  mov    %r13d,%ebp
  jmp    L50
L36:
  lea    0x2(%rbp),%r12
  movzbl 0x1(%rbp),%ebp
  jmp    L50
L3:
  lea    (%rbx,%rbx,4),%rax
  sub    $0x30,%ebp
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%rbx
  add    $0x1,%r12
  movzbl -0x1(%r12),%ebp
L50:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbx,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%rbx
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  test   %r12,%r12
  jne    L1
  movzbl (%rax),%r13d
  mov    %r13d,%edx
  mov    %r13d,%ebp
  sub    $0x2b,%edx
  and    $0xfd,%edx
  jne    L9
  movzbl 0x1(%rax),%ebp
  lea    0x2(%rax),%rbx
  jmp    L9
  xchg   %ax,%ax
L2:
  sub    $0x30,%ebp
  lea    (%r12,%r12,4),%rax
  add    $0x1,%rbx
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%r12
  movzbl -0x1(%rbx),%ebp
L9:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  mov    %rbx,%rax
  add    $0x1,%rbx
  test   %r12,%r12
  jne    L10
  movzbl (%rax),%r13d
  mov    %r13d,%edx
  mov    %r13d,%ebp
  sub    $0x2b,%edx
  and    $0xfd,%edx
  jne    L33
  movzbl 0x1(%rax),%ebp
  lea    0x2(%rax),%rbx
  jmp    L33
  xchg   %ax,%ax
L35:
  sub    $0x30,%ebp
  lea    (%r12,%r12,4),%rax
  add    $0x1,%rbx
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rax,2),%r12
  movzbl -0x1(%rbx),%ebp
L33:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L35
  mov    %r12,%rax
  neg    %rax
  cmp    $0x2d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long atol(const char *nptr) {
  int c;
  int sign;
  long total;
  const unsigned char *p = (const unsigned char *)nptr;
  while (isspace(*p))
    ++p;
  c = *p++;
  sign = c;
  if (c == '-' || c == '+')
    c = *p++;
  total = 0;
  while (isdigit(c)) {
    total = 10 * total + (c - '0');
    c = *p++;
  }
  if (sign == '-') {
    return -total;
  } else {
    return total;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  movsd  %xmm0,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wcsutil_double2str@plt>
  lea    -0x30(%rbp),%rsi
  mov    -0x40(%rbp),%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rsi,%r8
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D2: %04.1f

tool: D8: T%.2d:%.2d:%s

assistant: ```c
void write_date(char *buf, int hour, int minute, double sec) {
  char ctmp[32];
  wcsutil_double2str(ctmp, "%04.1f", sec);
  sprintf(buf, "T%.2d:%.2d:%s", hour, minute, ctmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_date>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    D10(%rip),%rsi
  mov    %r13,%rdi
  call   <wcsutil_double2str@plt>
  mov    %r13,%r8
  mov    %r12d,%ecx
  mov    %ebp,%edx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string

tool: D10: %04.1f

tool: D15: T%.2d:%.2d:%s

assistant: ```c
void write_date(char *buf, int hour, int minute, double sec) {
  char ctmp[32];
  wcsutil_double2str(ctmp, "%04.1f", sec);
  sprintf(buf, "T%.2d:%.2d:%s", hour, minute, ctmp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_date>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  lea    D3(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <wcsutil_double2str@plt>
  mov    %rbx,%r8
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D3: %04.1f

tool: D1: T%.2d:%.2d:%s

assistant: ```c
void write_date(char *buf, int hour, int minute, double sec) {
  char ctmp[32];
  wcsutil_double2str(ctmp, "%04.1f", sec);
  sprintf(buf, "T%.2d:%.2d:%s", hour, minute, ctmp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_date>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  lea    D16(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <wcsutil_double2str@plt>
  mov    %rbx,%r8
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D16: %04.1f

tool: D3: T%.2d:%.2d:%s

assistant: ```c
void write_date(char *buf, int hour, int minute, double sec) {
  char ctmp[32];
  wcsutil_double2str(ctmp, "%04.1f", sec);
  sprintf(buf, "T%.2d:%.2d:%s", hour, minute, ctmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<eatBlockComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L42:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x2(%rbp)
  mov    D10(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2(%rbp)
  je     L25
  cmpb   $0x2a,-0x2(%rbp)
  jne    L42
L25:
  cmpb   $0x2a,-0x2(%rbp)
  jne    L65
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x2f,-0x1(%rbp)
  jne    L59
  mov    $0x2f,%eax
  jmp    L1
L59:
  mov    D10(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L21
  mov    D10(%rip),%rax
  movzbl (%rax),%eax
  jmp    L1
L21:
  mov    $0x0,%eax
  call   <eatBlockComment>
  jmp    L1
L65:
  mov    D10(%rip),%rax
  movzbl (%rax),%eax
L1:
  leave
  ret
```

assistant: ```c
char eatBlockComment() {
  char e, f;
  while ((e = getchar()) != EOF && e != '*')
    ;
  if (e == '*') {
    f = getchar();
    if (f == '/')
      return '/';
    else if (f == EOF)
      return EOF;
    else
      return eatBlockComment();
  } else
    return EOF;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eatBlockComment>:
  endbr64
  sub    $0x8,%rsp
L38:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D3(%rip),%rdx
  movzbl (%rdx),%edx
  cmp    $0x2a,%al
  je     L47
  cmp    %al,%dl
  jne    L38
L47:
  cmp    $0x2a,%al
  je     L2
L21:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edx
  cmp    $0x2f,%al
  je     L21
  mov    D3(%rip),%rax
  cmp    %dl,(%rax)
  je     L21
  mov    $0x0,%eax
  call   <eatBlockComment>
  mov    %eax,%edx
  jmp    L21
```

assistant: ```c
char eatBlockComment() {
  char e, f;
  while ((e = getchar()) != EOF && e != '*')
    ;
  if (e == '*') {
    f = getchar();
    if (f == '/')
      return '/';
    else if (f == EOF)
      return EOF;
    else
      return eatBlockComment();
  } else
    return EOF;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eatBlockComment>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  jmp    L41
  xchg   %ax,%ax
L55:
  cmp    $0x2a,%al
  je     L18
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L55
  cmp    $0x2a,%al
  jne    L48
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2f,%al
  je     L48
  cmp    %al,(%rbx)
  jne    L41
L48:
  pop    %rbx
  ret
```

assistant: ```c
char eatBlockComment() {
  char e, f;
  while ((e = getchar()) != EOF && e != '*')
    ;
  if (e == '*') {
    f = getchar();
    if (f == '/')
      return '/';
    else if (f == EOF)
      return EOF;
    else
      return eatBlockComment();
  } else
    return EOF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<eatBlockComment>:
  endbr64
  push   %rbx
  mov    D0(%rip),%rbx
  jmp    L32
  xchg   %ax,%ax
L2:
  cmp    $0x2a,%al
  je     L31
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L2
  cmp    $0x2a,%al
  jne    L29
L31:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2f,%al
  je     L29
  cmp    %al,(%rbx)
  jne    L32
L29:
  pop    %rbx
  ret
```

assistant: ```c
char eatBlockComment() {
  char e, f;
  while ((e = getchar()) != EOF && e != '*')
    ;
  if (e == '*') {
    f = getchar();
    if (f == '/')
      return '/';
    else if (f == EOF)
      return EOF;
    else
      return eatBlockComment();
  } else
    return EOF;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<work_once>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L13:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movsbl -0x11(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff8c08c08d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0xea,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L9:
  cmpl   $0xe9,-0x10(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void work_once(void *const addr) {
  char *const buffer = addr;
  for (int b = 0; b < 234; ++b) {
    const char byte = buffer[b];
    const int offset = (b + byte) % 234;
    buffer[b] ^= buffer[offset];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<work_once>:
  endbr64
  mov    $0x0,%ecx
L0:
  movzbl (%rdi,%rcx,1),%esi
  movsbl %sil,%edx
  add    %ecx,%edx
  movslq %edx,%rax
  imul   $0xffffffff8c08c08d,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x7,%eax
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  imul   $0xea,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%sil
  mov    %sil,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    $0xea,%rcx
  jne    L0
  ret
```

assistant: ```c
void work_once(void *const addr) {
  char *const buffer = addr;
  for (int b = 0; b < 234; ++b) {
    const char byte = buffer[b];
    const int offset = (b + byte) % 234;
    buffer[b] ^= buffer[offset];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<work_once>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L9:
  movsbl (%rdi,%rcx,1),%edx
  mov    %edx,%esi
  add    %ecx,%edx
  movslq %edx,%rax
  mov    %edx,%r8d
  imul   $0xffffffff8c08c08d,%rax,%rax
  sar    $0x1f,%r8d
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x7,%eax
  sub    %r8d,%eax
  imul   $0xea,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%sil
  mov    %sil,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    $0xea,%rcx
  jne    L9
  ret
```

assistant: ```c
void work_once(void *const addr) {
  char *const buffer = addr;
  for (int b = 0; b < 234; ++b) {
    const char byte = buffer[b];
    const int offset = (b + byte) % 234;
    buffer[b] ^= buffer[offset];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<work_once>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L2:
  movsbl (%rdi,%rcx,1),%edx
  mov    %edx,%esi
  add    %ecx,%edx
  movslq %edx,%rax
  mov    %edx,%r8d
  imul   $0xffffffff8c08c08d,%rax,%rax
  sar    $0x1f,%r8d
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x7,%eax
  sub    %r8d,%eax
  imul   $0xea,%eax,%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%sil
  mov    %sil,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    $0xea,%rcx
  jne    L2
  ret
```

assistant: ```c
void work_once(void *const addr) {
  char *const buffer = addr;
  for (int b = 0; b < 234; ++b) {
    const char byte = buffer[b];
    const int offset = (b + byte) % 234;
    buffer[b] ^= buffer[offset];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L29
L17:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L4
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L17
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  for (i = n1; i <= n2; i++) {
    if (check_prime(i))
      printf("%d ", i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_prime>:
  endbr64
  cmp    %esi,%edi
  jg     L43
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D2(%rip),%r12
  jmp    L26
L45:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L40
L26:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L45
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L45
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  for (i = n1; i <= n2; i++) {
    if (check_prime(i))
      printf("%d ", i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_prime>:
  endbr64
  cmp    %esi,%edi
  jg     L45
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  jmp    L39
  nopl   0x0(%rax)
L37:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L33
L39:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L37
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L39
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L45:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string

tool: D5: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  for (i = n1; i <= n2; i++) {
    if (check_prime(i))
      printf("%d ", i);
  }
}
```