ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utf8_strpos_getpos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  jns    L84
  call   <utf8_strlen@plt>
  test   %eax,%eax
  jle    L43
  add    %eax,%ebx
  js     L43
L84:
  cmpb   $0x0,0x0(%rbp)
  je     L43
  mov    %rbp,%rdi
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  jmp    L36
  nop
L66:
  cmp    %r15d,%ebx
  je     L87
  add    %eax,%r14d
  add    $0x1,%r15d
  movslq %r14d,%rdi
  add    %rbp,%rdi
  cmpb   $0x0,(%rdi)
  je     L43
L36:
  call   <utf8_getsize_char@plt>
  test   %eax,%eax
  jns    L66
L43:
  mov    $0xffffffff,%r14d
L20:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L87:
  test   %r12,%r12
  je     L73
  mov    %r14d,(%r12)
L73:
  test   %r13,%r13
  je     L20
  cltq
  mov    %rax,0x0(%r13)
  jmp    L20
```

assistant: ```c
int utf8_strpos_getpos(const char *str, int pos, int *startpos_out, size_t *len_out) {
  int i, n, len;
  if (pos >= 0) {
    for (i = 0, n = 0; str[i];) {
      len = utf8_getsize_char(&str[i]);
      if (len < 0)
        return -1;
      else if (pos == n) {
        if (startpos_out)
          *startpos_out = i;
        if (len_out)
          *len_out = len;
        return i;
      }
      i += len;
      n++;
    }
    return -1;
  } else {
    len = utf8_strlen(str);
    if (len <= 0)
      return -1;
    int newpos = len + pos;
    if (newpos < 0)
      return -1;
    return utf8_strpos_getpos(str, newpos, startpos_out, len_out);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_strpos_getpos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  jns    L30
  call   <utf8_strlen@plt>
  test   %eax,%eax
  jle    L71
  add    %eax,%ebx
  js     L71
L30:
  cmpb   $0x0,0x0(%rbp)
  je     L71
  mov    %rbp,%rdi
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  jmp    L104
  nop
L63:
  cmp    %r15d,%ebx
  je     L90
  add    %eax,%r14d
  add    $0x1,%r15d
  movslq %r14d,%rdi
  add    %rbp,%rdi
  cmpb   $0x0,(%rdi)
  je     L71
L104:
  call   <utf8_getsize_char@plt>
  test   %eax,%eax
  jns    L63
L71:
  mov    $0xffffffff,%r14d
L14:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L90:
  test   %r12,%r12
  je     L108
  mov    %r14d,(%r12)
L108:
  test   %r13,%r13
  je     L14
  cltq
  mov    %rax,0x0(%r13)
  jmp    L14
```

assistant: ```c
int utf8_strpos_getpos(const char *str, int pos, int *startpos_out, size_t *len_out) {
  int i, n, len;
  if (pos >= 0) {
    for (i = 0, n = 0; str[i];) {
      len = utf8_getsize_char(&str[i]);
      if (len < 0)
        return -1;
      else if (pos == n) {
        if (startpos_out)
          *startpos_out = i;
        if (len_out)
          *len_out = len;
        return i;
      }
      i += len;
      n++;
    }
    return -1;
  } else {
    len = utf8_strlen(str);
    if (len <= 0)
      return -1;
    int newpos = len + pos;
    if (newpos < 0)
      return -1;
    return utf8_strpos_getpos(str, newpos, startpos_out, len_out);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DIS_le_codigo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L56
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L56:
  mov    -0x10(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L92
L94:
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L92:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L94
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L94
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L94
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L94
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L94
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L94
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L94
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L94
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L94
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D47
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D56
type_infered: string

tool: D47: Memoria insuficiente!



tool: D7: inf

tool: D18: 
Digite o codigo numerico da disciplina:


tool: D14: %4s

tool: D56: Selecione caracteres validos (0 >= x <=9):

assistant: ```c
*DIS_le_codigo(void) {
  char *cod1 = (char *)calloc(8, sizeof(char));
  char *cod2 = (char *)calloc(5, sizeof(char));
  if (cod1 == NULL) {
    printf("Memoria insuficiente!\n\n");
    exit(1);
  }
  strcat(cod1, "inf");
  printf("\nDigite o codigo numerico da disciplina:\n");
  scanf("%4s", cod2);
  while ((int)cod2[0] < 48 || (int)cod2[0] > 57 || (int)cod2[1] < 48 || (int)cod2[1] > 57 || (int)cod2[2] < 48 || (int)cod2[2] > 57 || (int)cod2[3] < 48 || (int)cod2[3] > 57 || strlen(cod2) < 4) {
    printf("Selecione caracteres validos (0 >= x <=9):");
    scanf("%4s", cod2);
  }
  strcat(cod1, cod2);
  free(cod2);
  return cod1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DIS_le_codigo>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %r13,%r13
  je     L14
L72:
  lea    D6(%rip),%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  lea    D15(%rip),%r12
  lea    D45(%rip),%rbp
  jmp    L67
L14:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L72
L28:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
L67:
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L28
  movzbl 0x1(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L28
  movzbl 0x2(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L28
  movzbl 0x3(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L28
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L28
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string
name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D45
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D29
type_infered: string

tool: D6: inf

tool: D17: 
Digite o codigo numerico da disciplina:


tool: D45: %4s

tool: D15: Selecione caracteres validos (0 >= x <=9):

tool: D29: Memoria insuficiente!



assistant: ```c
*DIS_le_codigo(void) {
  char *cod1 = (char *)calloc(8, sizeof(char));
  char *cod2 = (char *)calloc(5, sizeof(char));
  if (cod1 == NULL) {
    printf("Memoria insuficiente!\n\n");
    exit(1);
  }
  strcat(cod1, "inf");
  printf("\nDigite o codigo numerico da disciplina:\n");
  scanf("%4s", cod2);
  while ((int)cod2[0] < 48 || (int)cod2[0] > 57 || (int)cod2[1] < 48 || (int)cod2[1] > 57 || (int)cod2[2] < 48 || (int)cod2[2] > 57 || (int)cod2[3] < 48 || (int)cod2[3] > 57 || strlen(cod2) < 4) {
    printf("Selecione caracteres validos (0 >= x <=9):");
    scanf("%4s", cod2);
  }
  strcat(cod1, cod2);
  free(cod2);
  return cod1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DIS_le_codigo>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x8,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r12,%r12
  je     L70
L72:
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  lea    D21(%rip),%rbx
  call   <strcat@plt>
  lea    D8(%rip),%rdi
  lea    D29(%rip),%r13
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L73
  nopl   0x0(%rax)
L44:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L73:
  movzbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L44
  movzbl 0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L44
  movzbl 0x2(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L44
  movzbl 0x3(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L44
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L44
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L72
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D21
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D29
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D0: inf

tool: D21: %4s

tool: D8: 
Digite o codigo numerico da disciplina:


tool: D29: Selecione caracteres validos (0 >= x <=9):

tool: D18: Memoria insuficiente!



assistant: ```c
*DIS_le_codigo(void) {
  char *cod1 = (char *)calloc(8, sizeof(char));
  char *cod2 = (char *)calloc(5, sizeof(char));
  if (cod1 == NULL) {
    printf("Memoria insuficiente!\n\n");
    exit(1);
  }
  strcat(cod1, "inf");
  printf("\nDigite o codigo numerico da disciplina:\n");
  scanf("%4s", cod2);
  while ((int)cod2[0] < 48 || (int)cod2[0] > 57 || (int)cod2[1] < 48 || (int)cod2[1] > 57 || (int)cod2[2] < 48 || (int)cod2[2] > 57 || (int)cod2[3] < 48 || (int)cod2[3] > 57 || strlen(cod2) < 4) {
    printf("Selecione caracteres validos (0 >= x <=9):");
    scanf("%4s", cod2);
  }
  strcat(cod1, cod2);
  free(cod2);
  return cod1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<DIS_le_codigo>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x8,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r12,%r12
  je     L29
L53:
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  lea    D44(%rip),%rbx
  call   <strcat@plt>
  lea    D34(%rip),%rdi
  lea    D38(%rip),%r13
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L30
  nopl   0x0(%rax)
L24:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
L30:
  movzbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L24
  movzbl 0x1(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L24
  movzbl 0x2(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L24
  movzbl 0x3(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L24
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jle    L24
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L53
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D44
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D47
type_guessed: string

tool: D18: inf

tool: D44: %4s

tool: D34: 
Digite o codigo numerico da disciplina:


tool: D38: Selecione caracteres validos (0 >= x <=9):

tool: D47: Memoria insuficiente!



assistant: ```c
*DIS_le_codigo(void) {
  char *cod1 = (char *)calloc(8, sizeof(char));
  char *cod2 = (char *)calloc(5, sizeof(char));
  if (cod1 == NULL) {
    printf("Memoria insuficiente!\n\n");
    exit(1);
  }
  strcat(cod1, "inf");
  printf("\nDigite o codigo numerico da disciplina:\n");
  scanf("%4s", cod2);
  while ((int)cod2[0] < 48 || (int)cod2[0] > 57 || (int)cod2[1] < 48 || (int)cod2[1] > 57 || (int)cod2[2] < 48 || (int)cod2[2] > 57 || (int)cod2[3] < 48 || (int)cod2[3] > 57 || strlen(cod2) < 4) {
    printf("Selecione caracteres validos (0 >= x <=9):");
    scanf("%4s", cod2);
  }
  strcat(cod1, cod2);
  free(cod2);
  return cod1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D88(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D81(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L25
  mov    %ebx,%edx
  mov    $0x0,%ebp
L31:
  lea    0x0(%rbp,%rbp,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ebp
  mov    %eax,%edx
  test   %eax,%eax
  jne    L31
  movl   $0x0,0x4(%rsp)
  mov    %ebp,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L35
  mov    %ebx,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x0,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%ebp
L35:
  mov    %ebp,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D88
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D81
type_infered: string
name: unpack_data
arguments: data_tag: D64
type_infered: string
name: unpack_data
arguments: data_tag: D44
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D35
type_infered: string
name: unpack_data
arguments: data_tag: D34
type_infered: string

tool: D88: 
**************************************************************************

tool: D4: 
*	PROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT	 *

tool: D81: **************************************************************************

tool: D64: 
Enter a number

tool: D44: %d

tool: D43: 
Reverse is %d

tool: D35: 
Number %d is not a palindrome


tool: D34: 
Number %d is a palindrome


assistant: ```c
int main(void) {
  int iNum, iRev = 0, iTemp, iRem;
  printf("\n**************************************************************************");
  printf("\n*\tPROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT\t *\n");
  printf("**************************************************************************");
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iTemp = iNum;
  while (iNum != 0) {
    iRem = iNum % 10;
    iRev = iRev * 10 + iRem;
    iNum = iNum / 10;
  }
  printf("\nReverse is %d", iRev);
  if (iRev == iTemp)
    printf("\nNumber %d is a palindrome\n", iTemp);
  else
    printf("\nNumber %d is not a palindrome\n", iTemp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D78(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  je     L46
  mov    %r12d,%edx
  xor    %ebp,%ebp
  nopl   (%rax)
L41:
  movslq %edx,%rax
  mov    %edx,%ecx
  lea    0x0(%rbp,%rbp,4),%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ebp
  mov    %eax,%edx
  test   %eax,%eax
  jne    L41
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D84(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  cmp    %ebp,%r12d
  je     L47
  mov    %r12d,%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L46:
  xor    %esi,%esi
  lea    D84(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
L47:
  mov    %ebp,%esi
  lea    D80(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L22
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D78
type_guessed: string
name: parse_data
arguments: label: D50
type_guessed: string
name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D46
type_guessed: string
name: parse_data
arguments: label: D59
type_guessed: string
name: parse_data
arguments: label: D84
type_guessed: string
name: parse_data
arguments: label: D34
type_guessed: string
name: parse_data
arguments: label: D80
type_guessed: string

tool: D78: 
**************************************************************************

tool: D50: 
*	PROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT	 *

tool: D22: **************************************************************************

tool: D46: 
Enter a number

tool: D59: %d

tool: D84: 
Reverse is %d

tool: D34: 
Number %d is not a palindrome


tool: D80: 
Number %d is a palindrome


assistant: ```c
int main(void) {
  int iNum, iRev = 0, iTemp, iRem;
  printf("\n**************************************************************************");
  printf("\n*\tPROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT\t *\n");
  printf("**************************************************************************");
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iTemp = iNum;
  while (iNum != 0) {
    iRem = iNum % 10;
    iRev = iRev * 10 + iRem;
    iNum = iNum / 10;
  }
  printf("\nReverse is %d", iRev);
  if (iRev == iTemp)
    printf("\nNumber %d is a palindrome\n", iTemp);
  else
    printf("\nNumber %d is not a palindrome\n", iTemp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D86(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D64(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  je     L9
  mov    %r12d,%edx
  xor    %ebp,%ebp
  nopl   (%rax)
L37:
  movslq %edx,%rax
  mov    %edx,%ecx
  lea    0x0(%rbp,%rbp,4),%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ebp
  mov    %eax,%edx
  test   %eax,%eax
  jne    L37
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D71(%rip),%rdi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  cmp    %ebp,%r12d
  je     L5
  mov    %r12d,%esi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  xor    %esi,%esi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
L5:
  mov    %ebp,%esi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D86
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D64
type_infered: string
name: disassemble_data
arguments: data_label: D82
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string
name: disassemble_data
arguments: data_label: D71
type_infered: string
name: disassemble_data
arguments: data_label: D50
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string

tool: D86: 
**************************************************************************

tool: D12: 
*	PROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT	 *

tool: D64: **************************************************************************

tool: D82: 
Enter a number

tool: D9: %d

tool: D71: 
Reverse is %d

tool: D50: 
Number %d is not a palindrome


tool: D48: 
Number %d is a palindrome


assistant: ```c
int main(void) {
  int iNum, iRev = 0, iTemp, iRem;
  printf("\n**************************************************************************");
  printf("\n*\tPROGRAM TO CHECK WHETHER AN INTEGER IS A PALINDROME OR NOT\t *\n");
  printf("**************************************************************************");
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iTemp = iNum;
  while (iNum != 0) {
    iRem = iNum % 10;
    iRev = iRev * 10 + iRem;
    iNum = iNum / 10;
  }
  printf("\nReverse is %d", iRev);
  if (iRev == iTemp)
    printf("\nNumber %d is a palindrome\n", iTemp);
  else
    printf("\nNumber %d is not a palindrome\n", iTemp);
  return 0;
}
```