ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x80000000,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <divide@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D1: %d


tool: D7: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  int a = -2147483648, b = -1;
  printf("%d\n", divide(a, b));
  printf("%u\n", 0 - a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0x80000000,%edi
  call   <divide@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x80000000,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D16: %d


tool: D19: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  int a = -2147483648, b = -1;
  printf("%d\n", divide(a, b));
  printf("%u\n", 0 - a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0x80000000,%edi
  call   <divide@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x80000000,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D18
type_guessed: string

tool: D4: %d


tool: D18: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  int a = -2147483648, b = -1;
  printf("%d\n", divide(a, b));
  printf("%u\n", 0 - a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0x80000000,%edi
  call   <divide@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x80000000,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D13
type: string

tool: D7: %d


tool: D13: %u


assistant: ```c
int main(int argc, char const *argv[]) {
  int a = -2147483648, b = -1;
  printf("%d\n", divide(a, b));
  printf("%u\n", 0 - a);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <reverse@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D18: %d

tool: D3: %d


assistant: ```c
int main(void) {
  int input;
  scanf("%d", &input);
  int a = reverse(input);
  printf("%d\n", a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <reverse@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D10: %d

tool: D0: %d


assistant: ```c
int main(void) {
  int input;
  scanf("%d", &input);
  int a = reverse(input);
  printf("%d\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <reverse@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D5
type: string

tool: D19: %d

tool: D5: %d


assistant: ```c
int main(void) {
  int input;
  scanf("%d", &input);
  int a = reverse(input);
  printf("%d\n", a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <reverse@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D17: %d

tool: D3: %d


assistant: ```c
int main(void) {
  int input;
  scanf("%d", &input);
  int a = reverse(input);
  printf("%d\n", a);
}
```
user: What is the c source code of the assembly code below:

```asm
<k_utf8chp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
L5:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *k_utf8chp(const char *s) {
  for (;;) {
    s--;
    if ((*s & 0xC0) != 0x80)
      return (char *)s;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<k_utf8chp>:
  endbr64
  mov    %rdi,%rax
L3:
  sub    $0x1,%rax
  movsbl (%rax),%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L3
  ret
```

assistant: ```c
char *k_utf8chp(const char *s) {
  for (;;) {
    s--;
    if ((*s & 0xC0) != 0x80)
      return (char *)s;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<k_utf8chp>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl -0x1(%rax),%edx
  sub    $0x1,%rax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L4
  ret
```

assistant: ```c
char *k_utf8chp(const char *s) {
  for (;;) {
    s--;
    if ((*s & 0xC0) != 0x80)
      return (char *)s;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<k_utf8chp>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl -0x1(%rax),%edx
  sub    $0x1,%rax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L4
  ret
```

assistant: ```c
char *k_utf8chp(const char *s) {
  for (;;) {
    s--;
    if ((*s & 0xC0) != 0x80)
      return (char *)s;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rsi
  mov    %r9d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  movslq (%rax),%rax
  shl    $0x5,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rdi
  mov    %rsp,%rdx
  sub    %rdi,%rdx
L43:
  cmp    %rdx,%rsp
  je     L109
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L109:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L0
  orq    $0x0,-0x8(%rsp,%rdx,1)
L0:
  lea    0x3(%rsp),%r15
  mov    %r15,%rdi
  shr    $0x2,%rdi
  and    $0xfffffffffffffffc,%r15
  mov    %ecx,%ecx
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %edx,0x0(,%rdi,4)
  cmp    %rcx,%rsi
  jb     L101
  mov    $0x2,%edi
L61:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%r9
  mov    %rax,%rsi
  mov    %edi,%r14d
  mov    $0x0,%edx
  div    %rcx
  mov    %edx,-0x4(%r15,%rdi,4)
  add    $0x1,%rdi
  cmp    %rcx,%r9
  jae    L61
  lea    -0x1(%r8),%ebx
  cmp    %r8d,%r14d
  jge    L96
L66:
  mov    %r13,%rsi
  mov    -0x44(%rbp),%edi
  call   *%r12
  mov    %ebx,%eax
  sub    $0x1,%ebx
  cmp    %eax,%r14d
  jl     L66
L96:
  lea    -0x1(%r14),%ebx
  test   %r14d,%r14d
  jle    L70
L85:
  movslq %ebx,%rbx
L74:
  mov    (%r15,%rbx,4),%edx
  cmp    $0xa,%edx
  sbb    %eax,%eax
  and    $0xffffffd9,%eax
  lea    0x57(%rdx,%rax,1),%edi
  mov    %r13,%rsi
  call   *%r12
  sub    $0x1,%rbx
  lea    0x1(%rbx),%eax
  test   %eax,%eax
  jg     L74
L70:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L101:
  lea    -0x1(%r8),%ebx
  mov    $0x1,%r14d
  cmp    $0x1,%r8d
  jg     L66
  mov    $0x0,%ebx
  jmp    L85
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnum(void (*putch)(int, void **), void **putdat, unsigned long long num, unsigned base, int width, int padc) {
  unsigned digs[sizeof(num) * CHAR_BIT];
  int pos = 0;
  for (;;) {
    digs[pos++] = num % base;
    if (num < base)
      break;
    num /= base;
  }
  while (width-- > pos) {
    putch(padc, putdat);
  }
  while (pos-- > 0) {
    putch(digs[pos] + (digs[pos] >= 10 ? 'a' - 10 : '0'), putdat);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D1(%rip),%rax
  mov    %rsp,%rdx
  movslq (%rax),%rax
  shl    $0x5,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rdi
  sub    %rdi,%rdx
  cmp    %rdx,%rsp
  je     L24
L45:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L45
L24:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L62
L52:
  mov    %ecx,%ecx
  mov    %rsi,%rax
  xor    %edx,%edx
  mov    $0x1,%r14d
  div    %rcx
  lea    0x3(%rsp),%r13
  mov    %r13,%rdi
  mov    %r13,%r10
  shr    $0x2,%rdi
  and    $0xfffffffffffffffc,%r10
  mov    %r10,-0x50(%rbp)
  mov    %edx,0x0(,%rdi,4)
  mov    %edx,%eax
  lea    0x4(%r10),%rdi
  cmp    %rcx,%rsi
  jb     L116
  nopl   0x0(%rax)
L108:
  mov    %rsi,%rax
  xor    %edx,%edx
  mov    %r14d,-0x44(%rbp)
  add    $0x4,%rdi
  div    %rcx
  xor    %edx,%edx
  add    $0x1,%r14d
  mov    %rax,%rsi
  div    %rcx
  mov    %edx,-0x4(%rdi)
  mov    %edx,%eax
  cmp    %rcx,%rsi
  jae    L108
  cmp    %r8d,%r14d
  jge    L10
L128:
  mov    %r8d,%r13d
  nopw   0x0(%rax,%rax,1)
L87:
  sub    $0x1,%r13d
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   *%rbx
  cmp    %r13d,%r14d
  jl     L87
  movslq -0x44(%rbp),%r14
  mov    -0x50(%rbp),%rax
  mov    (%rax,%r14,4),%eax
L122:
  mov    -0x50(%rbp),%rcx
  lea    (%rcx,%r14,4),%r14
  lea    -0x4(%rcx),%r13
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L129:
  mov    (%r14),%eax
L41:
  cmp    $0xa,%eax
  mov    %r12,%rsi
  sbb    %edx,%edx
  sub    $0x4,%r14
  and    $0xffffffd9,%edx
  lea    0x57(%rdx,%rax,1),%edi
  call   *%rbx
  cmp    %r14,%r13
  jne    L129
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L52
L116:
  movl   $0x0,-0x44(%rbp)
  cmp    $0x1,%r8d
  jg     L128
  xor    %r14d,%r14d
  jmp    L122
  nopl   0x0(%rax)
L10:
  movslq -0x44(%rbp),%r14
  jmp    L122
L102:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnum(void (*putch)(int, void **), void **putdat, unsigned long long num, unsigned base, int width, int padc) {
  unsigned digs[sizeof(num) * CHAR_BIT];
  int pos = 0;
  for (;;) {
    digs[pos++] = num % base;
    if (num < base)
      break;
    num /= base;
  }
  while (width-- > pos) {
    putch(padc, putdat);
  }
  while (pos-- > 0) {
    putch(digs[pos] + (digs[pos] >= 10 ? 'a' - 10 : '0'), putdat);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D8(%rip),%rax
  mov    %rsp,%rdx
  movslq (%rax),%rax
  shl    $0x5,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rdi
  sub    %rdi,%rdx
  cmp    %rdx,%rsp
  je     L109
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L40
L109:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L22
L33:
  mov    %ecx,%ecx
  mov    %rsi,%rax
  xor    %edx,%edx
  mov    $0x1,%r15d
  div    %rcx
  lea    0x3(%rsp),%r13
  mov    %r13,%rdi
  mov    %r13,%r10
  shr    $0x2,%rdi
  and    $0xfffffffffffffffc,%r10
  mov    %r10,-0x50(%rbp)
  mov    %edx,0x0(,%rdi,4)
  lea    0x4(%r10),%rdi
  cmp    %rcx,%rsi
  jb     L16
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %rsi,%rax
  xor    %edx,%edx
  mov    %r15d,-0x44(%rbp)
  add    $0x4,%rdi
  div    %rcx
  xor    %edx,%edx
  add    $0x1,%r15d
  mov    %rax,%rsi
  div    %rcx
  mov    %edx,-0x4(%rdi)
  cmp    %rcx,%rsi
  jae    L50
  cmp    %r8d,%r15d
  jge    L144
L91:
  mov    %r8d,%r13d
  nopl   0x0(%rax)
L58:
  sub    $0x1,%r13d
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   *%rbx
  cmp    %r13d,%r15d
  jl     L58
L144:
  mov    -0x50(%rbp),%rax
  movslq -0x44(%rbp),%r15
  lea    -0x4(%rax),%r13
  lea    (%rax,%r15,4),%r14
  nopl   0x0(%rax)
L139:
  mov    (%r14),%edi
  cmp    $0x9,%edi
  ja     L41
  sub    $0x4,%r14
  add    $0x30,%edi
  mov    %r12,%rsi
  call   *%rbx
  cmp    %r13,%r14
  jne    L139
L86:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  sub    $0x4,%r14
  add    $0x57,%edi
  mov    %r12,%rsi
  call   *%rbx
  cmp    %r14,%r13
  jne    L139
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L22:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L33
L16:
  movl   $0x0,-0x44(%rbp)
  cmp    $0x1,%r8d
  jg     L91
  jmp    L144
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnum(void (*putch)(int, void **), void **putdat, unsigned long long num, unsigned base, int width, int padc) {
  unsigned digs[sizeof(num) * CHAR_BIT];
  int pos = 0;
  for (;;) {
    digs[pos++] = num % base;
    if (num < base)
      break;
    num /= base;
  }
  while (width-- > pos) {
    putch(padc, putdat);
  }
  while (pos-- > 0) {
    putch(digs[pos] + (digs[pos] >= 10 ? 'a' - 10 : '0'), putdat);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_eqep_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  movl   $0x1f09000,-0x4(%rbp)
  jmp    L0
L16:
  cmpl   $0x1,-0x14(%rbp)
  jne    L0
  movl   $0x1f0a000,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t get_eqep_base(uint8_t num) {
  uint32_t base = 0;
  if (num == 0)
    base = (0x01f09000);
  else if (num == 1)
    base = (0x01f0A000);
  return base;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_eqep_base>:
  endbr64
  mov    $0x1f09000,%eax
  test   %edi,%edi
  je     L3
  cmp    $0x1,%edi
  mov    $0x0,%eax
  mov    $0x1f0a000,%edx
  cmove  %edx,%eax
L3:
  ret
```

assistant: ```c
uint32_t get_eqep_base(uint8_t num) {
  uint32_t base = 0;
  if (num == 0)
    base = (0x01f09000);
  else if (num == 1)
    base = (0x01f0A000);
  return base;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_eqep_base>:
  endbr64
  mov    $0x1f09000,%eax
  test   %edi,%edi
  je     L5
  xor    %eax,%eax
  mov    $0x1f0a000,%edx
  cmp    $0x1,%edi
  cmove  %edx,%eax
L5:
  ret
```

assistant: ```c
uint32_t get_eqep_base(uint8_t num) {
  uint32_t base = 0;
  if (num == 0)
    base = (0x01f09000);
  else if (num == 1)
    base = (0x01f0A000);
  return base;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_eqep_base>:
  endbr64
  mov    $0x1f09000,%eax
  test   %edi,%edi
  je     L1
  xor    %eax,%eax
  mov    $0x1f0a000,%edx
  cmp    $0x1,%edi
  cmove  %edx,%eax
L1:
  ret
```

assistant: ```c
uint32_t get_eqep_base(uint8_t num) {
  uint32_t base = 0;
  if (num == 0)
    base = (0x01f09000);
  else if (num == 1)
    base = (0x01f0A000);
  return base;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insert_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L43:
  cmpl   $0x0,-0x8(%rbp)
  js     L39
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L33
L39:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_sort(int a[], int size) {
  int i = 0;
  int j = 0;
  int key = 0;
  for (i = 1; i < size; i++) {
    key = a[i];
    j = i - 1;
    while ((j >= 0) && (a[j] > key)) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = key;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L44
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L18
L0:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L44
L18:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L0
L41:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L0
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L41
  jmp    L0
L44:
  ret
```

assistant: ```c
void insert_sort(int a[], int size) {
  int i = 0;
  int j = 0;
  int key = 0;
  for (i = 1; i < size; i++) {
    key = a[i];
    j = i - 1;
    while ((j >= 0) && (a[j] > key)) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = key;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_sort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L14
L49:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L40
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L9
  mov    %rdi,%rax
L27:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L49
L14:
  ret
  nopl   (%rax)
L40:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L27
```

assistant: ```c
void insert_sort(int a[], int size) {
  int i = 0;
  int j = 0;
  int key = 0;
  for (i = 1; i < size; i++) {
    key = a[i];
    j = i - 1;
    while ((j >= 0) && (a[j] > key)) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = key;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_sort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L39
L41:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L5
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L38
  mov    %rdi,%rax
L36:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L41
L39:
  ret
  nopl   (%rax)
L5:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L36
```

assistant: ```c
void insert_sort(int a[], int size) {
  int i = 0;
  int j = 0;
  int key = 0;
  for (i = 1; i < size; i++) {
    key = a[i];
    j = i - 1;
    while ((j >= 0) && (a[j] > key)) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = key;
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rdmsrl_safe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <paravirt_read_msr@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int rdmsrl_safe(unsigned msr, unsigned long long *p) {
  int err;
  *p = paravirt_read_msr(msr, &err);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdmsrl_safe>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <paravirt_read_msr@plt>
  mov    %rax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int rdmsrl_safe(unsigned msr, unsigned long long *p) {
  int err;
  *p = paravirt_read_msr(msr, &err);
  return err;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rdmsrl_safe>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <paravirt_read_msr@plt>
  mov    %rax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int rdmsrl_safe(unsigned msr, unsigned long long *p) {
  int err;
  *p = paravirt_read_msr(msr, &err);
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rdmsrl_safe>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <paravirt_read_msr@plt>
  mov    %rax,(%rbx)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int rdmsrl_safe(unsigned msr, unsigned long long *p) {
  int err;
  *p = paravirt_read_msr(msr, &err);
  return err;
}
```