ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<colocaordem>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    %ecx,%esi
  test   %ecx,%ecx
  jle    L65
  movslq %ecx,%rdx
  xor    %eax,%eax
  jmp    L173
  nopw   0x0(%rax,%rax,1)
L92:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L65
L173:
  cmpl   $0x1,(%rdi,%rax,4)
  mov    %eax,%ecx
  je     L92
  cmp    %eax,%esi
  jle    L65
  movzbl (%r8,%rax,1),%edx
  movzbl (%r9,%rax,1),%eax
  xor    %r10d,%r10d
  nopw   0x0(%rax,%rax,1)
L74:
  cmp    %dl,%al
  jg     L116
  cmp    %al,%dl
  jne    L64
L14:
  add    $0x1,%ecx
  movslq %ecx,%rax
  jmp    L164
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rdx,%rax
L164:
  mov    %eax,%ecx
  cmp    %eax,%esi
  jle    L116
  cmpl   $0x1,(%rdi,%rax,4)
  lea    0x1(%rax),%rdx
  je     L9
  movzbl (%r8,%rax,1),%edx
  movzbl (%r9,%rax,1),%eax
  cmp    %al,%dl
  je     L14
L64:
  jg     L76
  cmp    %ecx,%esi
  jg     L74
  jmp    L116
  nopl   0x0(%rax)
L65:
  xor    %r10d,%r10d
L116:
  mov    %r10d,%eax
  ret
L76:
  movslq %ecx,%rax
  add    $0x1,%ecx
  movl   $0x1,(%rdi,%rax,4)
  movslq %ecx,%rax
  jmp    L21
  nopl   0x0(%rax)
L105:
  cmpl   $0x1,(%rdi,%rax,4)
  lea    0x1(%rax),%rdx
  jne    L62
  mov    %rdx,%rax
L21:
  mov    %eax,%ecx
  cmp    %eax,%esi
  jg     L105
  mov    $0x1,%r10d
  mov    %r10d,%eax
  ret
L62:
  movzbl (%r8,%rax,1),%edx
  mov    $0x1,%r10d
  movzbl (%r9,%rax,1),%eax
  jmp    L74
```

assistant: ```c
int colocaordem(char *vetora, char *vetorb, void *remov, int m) {
  int i, removeu = 0;
  int *removidos = (int *)remov;
  if (0) {
    printf("vetor removidos recebido em colocaordem:\n");
    for (i = 0; i < m; i++) {
      printf("%d ", removidos[i]);
    }
    printf("\n");
  }
  i = 0;
  while (i < m && removidos[i] == 1)
    i++;
  if (0) {
    printf("%d<=0== i\n", i);
  }
  while (i < m && vetora[i] >= vetorb[i]) {
    if (0) {
      printf("%d<=1== i\n", i);
      printf("teste executado: %c == %c\n", vetora[i], vetorb[i]);
      printf("resultado: %d\n", vetora[i] == vetorb[i]);
    }
    while (i < m && vetora[i] == vetorb[i])
      do {
        i++;
      } while (i < m && removidos[i] == 1);
    if (0) {
      printf("%d<=2== i\n", i);
    }
    if (i < m && vetora[i] > vetorb[i]) {
      removidos[i] = 1;
      removeu = 1;
      do {
        i++;
      } while (i < m && removidos[i] == 1);
    }
    if (0) {
      printf("%d<=3== i\n", i);
      printf("teste executado: %c >= %c\n", vetora[i], vetorb[i]);
      printf("resultado: %d\n", vetora[i] >= vetorb[i]);
    }
  }
  return removeu;
}
```
user: What is the c source code of the assembly code below:

```asm
<colocaordem>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    %ecx,%esi
  test   %ecx,%ecx
  jle    L4
  movslq %ecx,%rdx
  xor    %eax,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L4
L35:
  cmpl   $0x1,(%rdi,%rax,4)
  mov    %eax,%ecx
  je     L22
  cmp    %eax,%esi
  jle    L4
  movzbl (%r8,%rax,1),%edx
  movzbl (%r9,%rax,1),%eax
  xor    %r10d,%r10d
  nopw   0x0(%rax,%rax,1)
L49:
  cmp    %al,%dl
  jl     L15
  cmp    %dl,%al
  jne    L131
L44:
  add    $0x1,%ecx
  movslq %ecx,%rax
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rdx,%rax
L117:
  mov    %eax,%ecx
  cmp    %eax,%esi
  jle    L15
  cmpl   $0x1,(%rdi,%rax,4)
  lea    0x1(%rax),%rdx
  je     L58
  movzbl (%r8,%rax,1),%edx
  movzbl (%r9,%rax,1),%eax
  cmp    %dl,%al
  je     L44
L131:
  jl     L12
  cmp    %ecx,%esi
  jg     L49
  jmp    L15
  nopl   0x0(%rax)
L4:
  xor    %r10d,%r10d
L15:
  mov    %r10d,%eax
  ret
L12:
  movslq %ecx,%rax
  add    $0x1,%ecx
  movl   $0x1,(%rdi,%rax,4)
  movslq %ecx,%rax
  jmp    L25
  nopl   0x0(%rax)
L2:
  cmpl   $0x1,(%rdi,%rax,4)
  lea    0x1(%rax),%rdx
  jne    L10
  mov    %rdx,%rax
L25:
  mov    %eax,%ecx
  cmp    %eax,%esi
  jg     L2
  mov    $0x1,%r10d
  mov    %r10d,%eax
  ret
L10:
  movzbl (%r8,%rax,1),%edx
  mov    $0x1,%r10d
  movzbl (%r9,%rax,1),%eax
  jmp    L49
```

assistant: ```c
int colocaordem(char *vetora, char *vetorb, void *remov, int m) {
  int i, removeu = 0;
  int *removidos = (int *)remov;
  if (0) {
    printf("vetor removidos recebido em colocaordem:\n");
    for (i = 0; i < m; i++) {
      printf("%d ", removidos[i]);
    }
    printf("\n");
  }
  i = 0;
  while (i < m && removidos[i] == 1)
    i++;
  if (0) {
    printf("%d<=0== i\n", i);
  }
  while (i < m && vetora[i] >= vetorb[i]) {
    if (0) {
      printf("%d<=1== i\n", i);
      printf("teste executado: %c == %c\n", vetora[i], vetorb[i]);
      printf("resultado: %d\n", vetora[i] == vetorb[i]);
    }
    while (i < m && vetora[i] == vetorb[i])
      do {
        i++;
      } while (i < m && removidos[i] == 1);
    if (0) {
      printf("%d<=2== i\n", i);
    }
    if (i < m && vetora[i] > vetorb[i]) {
      removidos[i] = 1;
      removeu = 1;
      do {
        i++;
      } while (i < m && removidos[i] == 1);
    }
    if (0) {
      printf("%d<=3== i\n", i);
      printf("teste executado: %c >= %c\n", vetora[i], vetorb[i]);
      printf("resultado: %d\n", vetora[i] >= vetorb[i]);
    }
  }
  return removeu;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DetectInputStreamFormat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <CheckTSPacket@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L34
  movb   $0x1,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  jmp    L95
L34:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <CheckMPEGPacket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L55
  cmpl   $0x3ff,-0x4(%rbp)
  jg     L55
  mov    $0x2,%eax
  jmp    L95
L55:
  cmpl   $0x0,-0x4(%rbp)
  jne    L80
  cmpl   $0x0,-0x8(%rbp)
  jne    L80
  mov    $0x0,%eax
  jmp    L95
L80:
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  movb   $0x1,-0x9(%rbp)
  jmp    L13
L4:
  cmpl   $0x0,-0x8(%rbp)
  jne    L135
  movb   $0x2,-0x9(%rbp)
  jmp    L13
L135:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L102
  movb   $0x2,-0x9(%rbp)
  jmp    L13
L102:
  movb   $0x1,-0x9(%rbp)
L13:
  movzbl -0x9(%rbp),%eax
L95:
  leave
  ret
```

assistant: ```c
int DetectInputStreamFormat(unsigned char *pData, long dwSize) {
  int proTS = 0;
  int proPES = 0;
  unsigned char uType = 0;
  proTS = CheckTSPacket(pData, dwSize);
  if (proTS) {
    uType = 1;
    return uType;
  }
  proPES = CheckMPEGPacket(pData, dwSize);
  if (proPES && proPES < 1024)
    return 2;
  if (proPES == 0 && proTS == 0)
    return 0;
  if (proPES == 0)
    uType = 1;
  else if (proTS == 0)
    uType = 2;
  else if (proTS > proPES)
    uType = 2;
  else
    uType = 1;
  return uType;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DetectInputStreamFormat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <CheckTSPacket@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L6
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <CheckMPEGPacket@plt>
  test   %eax,%eax
  setne  %dl
  cmp    $0x3ff,%eax
  jg     L28
  mov    $0x2,%eax
  test   %dl,%dl
  jne    L19
L28:
  movzbl %dl,%edx
  lea    (%rdx,%rdx,1),%eax
  jmp    L19
```

assistant: ```c
int DetectInputStreamFormat(unsigned char *pData, long dwSize) {
  int proTS = 0;
  int proPES = 0;
  unsigned char uType = 0;
  proTS = CheckTSPacket(pData, dwSize);
  if (proTS) {
    uType = 1;
    return uType;
  }
  proPES = CheckMPEGPacket(pData, dwSize);
  if (proPES && proPES < 1024)
    return 2;
  if (proPES == 0 && proTS == 0)
    return 0;
  if (proPES == 0)
    uType = 1;
  else if (proTS == 0)
    uType = 2;
  else if (proTS > proPES)
    uType = 2;
  else
    uType = 1;
  return uType;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<DetectInputStreamFormat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <CheckTSPacket@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L6
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <CheckMPEGPacket@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int DetectInputStreamFormat(unsigned char *pData, long dwSize) {
  int proTS = 0;
  int proPES = 0;
  unsigned char uType = 0;
  proTS = CheckTSPacket(pData, dwSize);
  if (proTS) {
    uType = 1;
    return uType;
  }
  proPES = CheckMPEGPacket(pData, dwSize);
  if (proPES && proPES < 1024)
    return 2;
  if (proPES == 0 && proTS == 0)
    return 0;
  if (proPES == 0)
    uType = 1;
  else if (proTS == 0)
    uType = 2;
  else if (proTS > proPES)
    uType = 2;
  else
    uType = 1;
  return uType;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DetectInputStreamFormat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <CheckTSPacket@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  jne    L7
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <CheckMPEGPacket@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int DetectInputStreamFormat(unsigned char *pData, long dwSize) {
  int proTS = 0;
  int proPES = 0;
  unsigned char uType = 0;
  proTS = CheckTSPacket(pData, dwSize);
  if (proTS) {
    uType = 1;
    return uType;
  }
  proPES = CheckMPEGPacket(pData, dwSize);
  if (proPES && proPES < 1024)
    return 2;
  if (proPES == 0 && proTS == 0)
    return 0;
  if (proPES == 0)
    uType = 1;
  else if (proTS == 0)
    uType = 2;
  else if (proTS > proPES)
    uType = 2;
  else
    uType = 1;
  return uType;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L6
L32:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L53
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jne    L55
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L28
L55:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L28
L53:
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
L28:
  addb   $0x2,-0xa(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L32
  movzbl -0x9(%rbp),%eax
  lea    0x1f(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] = state[0UL] + state[local1];
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[0UL] *= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 883537325UL) + (unsigned char)204;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L0
  mov    $0x0,%edx
  jmp    L49
L7:
  imul   %eax,%eax
L44:
  add    $0x2,%edx
  cmp    %cl,%dl
  jae    L0
L49:
  cmp    %al,%dl
  jbe    L7
  add    %eax,%eax
  jmp    L44
L0:
  add    $0x1f,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] = state[0UL] + state[local1];
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[0UL] *= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 883537325UL) + (unsigned char)204;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  sub    $0x6a,%eax
  test   %cl,%cl
  je     L31
  xor    %edx,%edx
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L21:
  add    $0x2,%edx
  add    %eax,%eax
  cmp    %cl,%dl
  jae    L31
L33:
  cmp    %al,%dl
  ja     L21
  add    $0x2,%edx
  imul   %eax,%eax
  cmp    %cl,%dl
  jb     L33
L31:
  add    $0x1f,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] = state[0UL] + state[local1];
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[0UL] *= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 883537325UL) + (unsigned char)204;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  sub    $0x6a,%eax
  test   %cl,%cl
  je     L40
  xor    %edx,%edx
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x2,%edx
  add    %eax,%eax
  cmp    %dl,%cl
  jbe    L40
L38:
  cmp    %dl,%al
  jb     L11
  add    $0x2,%edx
  imul   %eax,%eax
  cmp    %dl,%cl
  ja     L38
L40:
  add    $0x1f,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] = state[0UL] + state[local1];
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[0UL] *= state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 883537325UL) + (unsigned char)204;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<free_cstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L7:
  nop
  leave
  ret
```

assistant: ```c
void free_cstr(char **str) {
  if (*str != NULL) {
    free(*str);
    *str = NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<free_cstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
  movq   $0x0,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void free_cstr(char **str) {
  if (*str != NULL) {
    free(*str);
    *str = NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_cstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  call   <free@plt>
  movq   $0x0,(%rbx)
L7:
  pop    %rbx
  ret
```

assistant: ```c
void free_cstr(char **str) {
  if (*str != NULL) {
    free(*str);
    *str = NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_cstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  call   <free@plt>
  movq   $0x0,(%rbx)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void free_cstr(char **str) {
  if (*str != NULL) {
    free(*str);
    *str = NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func_d_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: 

assistant: ```c
size_t func_d_idx(size_t a, size_t b) {
  enum { xx = 0, yy, zz, xy, xz, yz };
  static const size_t idx[] = {xx, xy, xz, xy, yy, yz, xz, yz, zz};
  return idx[3 * a + b];
}
```
user: What is the c source code of the assembly code below:

```asm
<func_d_idx>:
  endbr64
  lea    (%rdi,%rdi,2),%rax
  add    %rsi,%rax
  lea    D0(%rip),%rdx
  mov    (%rdx,%rax,8),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: 

assistant: ```c
size_t func_d_idx(size_t a, size_t b) {
  enum { xx = 0, yy, zz, xy, xz, yz };
  static const size_t idx[] = {xx, xy, xz, xy, yy, yz, xz, yz, zz};
  return idx[3 * a + b];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func_d_idx>:
  endbr64
  lea    (%rdi,%rdi,2),%rax
  lea    D1(%rip),%rdx
  add    %rsi,%rax
  mov    (%rdx,%rax,8),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: 

assistant: ```c
size_t func_d_idx(size_t a, size_t b) {
  enum { xx = 0, yy, zz, xy, xz, yz };
  static const size_t idx[] = {xx, xy, xz, xy, yy, yz, xz, yz, zz};
  return idx[3 * a + b];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func_d_idx>:
  endbr64
  lea    (%rdi,%rdi,2),%rax
  lea    D4(%rip),%rdx
  add    %rsi,%rax
  mov    (%rdx,%rax,8),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: 

assistant: ```c
size_t func_d_idx(size_t a, size_t b) {
  enum { xx = 0, yy, zz, xy, xz, yz };
  static const size_t idx[] = {xx, xy, xz, xy, yy, yz, xz, yz, zz};
  return idx[3 * a + b];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fgets_or_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fgets_or_exit(char *buffer, int size, FILE *stream) {
  char *buff;
  if ((buff = fgets(buffer, size, stream)) == NULL) {
    exit(1);
  }
  return buff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fgets_or_exit>:
  endbr64
  push   %rbx
  call   <fgets@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
L1:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
```

assistant: ```c
char *fgets_or_exit(char *buffer, int size, FILE *stream) {
  char *buff;
  if ((buff = fgets(buffer, size, stream)) == NULL) {
    exit(1);
  }
  return buff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgets_or_exit>:
  endbr64
  push   %r12
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *fgets_or_exit(char *buffer, int size, FILE *stream) {
  char *buff;
  if ((buff = fgets(buffer, size, stream)) == NULL) {
    exit(1);
  }
  return buff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fgets_or_exit>:
  endbr64
  push   %r12
  call   <fgets@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *fgets_or_exit(char *buffer, int size, FILE *stream) {
  char *buff;
  if ((buff = fgets(buffer, size, stream)) == NULL) {
    exit(1);
  }
  return buff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    0x7(%rsp),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  lea    (%rsi,%rdx,1),%ecx
  lea    D68(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x7(%rsp),%esi
  mov    %esi,%edx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm1,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D19(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm1,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D63(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D85
type_guessed: string
name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D53
type_guessed: string
name: parse_data
arguments: tag: D68
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D63
type_guessed: string

tool: D85: 
Enter Character:

tool: D23: %c

tool: D24: 
Enter two number :

tool: D13: %d %d

tool: D10: 
Enter two floating point number :

tool: D53: %f %f

tool: D68: 
Sum of %d and %d is %d


tool: D1: 
ASCII value of %c is %d


tool: D19: 
%f * %f = %f


tool: D63: 
%0.2f * %0.3f = %0.4f


assistant: ```c
int main() {
  int a, b;
  char ch;
  float f1, f2;
  printf("\nEnter Character:\n");
  scanf("%c", &ch);
  printf("\nEnter two number :\n");
  scanf("%d %d", &a, &b);
  printf("\nEnter two floating point number :\n");
  scanf("%f %f", &f1, &f2);
  printf("\nSum of %d and %d is %d\n", a, b, a + b);
  printf("\nASCII value of %c is %d\n", ch, ch);
  printf("\n%f * %f = %f\n", f1, f2, f1 * f2);
  printf("\n%0.2f * %0.3f = %0.4f\n", f1, f2, f1 * f2);
  return 0;
}
```