ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<bucketsort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r8d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    0x4(%rdi,%rdx,4),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L35:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L35
  lea    0x1(%rdx),%ebx
  cmp    %ebx,%r12d
  jge    L43
  cmp    $0x1869f,%r12d
  jg     L43
L17:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %r8d,%edx
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <quicksort@plt>
  nopl   0x0(%rax,%rax,1)
L43:
  lea    0x2(%rdx),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  call   <ComputeCount@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <Count2BeginIndex@plt>
  mov    %r13,%rdx
  xor    %ecx,%ecx
  nopl   (%rax)
L60:
  movslq (%rdx),%rax
  add    $0x4,%rdx
  cmp    (%rdx),%eax
  jge    L40
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %eax,(%rdx)
  jg     L62
L40:
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  jne    L60
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
```

assistant: ```c
void bucketsort(int *a, int n) {
  int i, j, max;
  int *aux;
  max = 0;
  for (i = 0; i < n; i++)
    if (a[i] > max)
      max = a[i];
  max++;
  if ((n >= max) || (n >= 100000)) {
    aux = (int *)calloc(max + 1, sizeof(int));
    ComputeCount(a, n, aux);
    Count2BeginIndex(aux, max);
    for (i = 0; i < max; i++)
      for (j = aux[i]; j < aux[i + 1]; j++)
        a[j] = i;
    free(aux);
  } else {
    quicksort(a, 0, n - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bucketsort>:
  endbr64
  push   %r13
  lea    -0x1(%rsi),%r8d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L66
  cmp    $0x2,%r8d
  jbe    L57
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm2,%xmm2
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L1
  movdqa %xmm2,%xmm0
  mov    %r12d,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%r12b
  je     L43
L100:
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%r12d
  jle    L43
  mov    0x4(%rbp,%rsi,1),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x2,%edx
  cmp    %r12d,%edx
  jge    L43
  mov    0x8(%rbp,%rsi,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L43:
  lea    0x1(%rax),%ebx
  cmp    %ebx,%r12d
  jge    L21
  cmp    $0x1869f,%r12d
  jg     L21
L66:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %r8d,%edx
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <quicksort@plt>
  nopl   (%rax)
L21:
  lea    0x2(%rax),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  call   <ComputeCount@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <Count2BeginIndex@plt>
  mov    %r13,%rdx
  xor    %ecx,%ecx
  nopl   (%rax)
L79:
  movslq (%rdx),%rax
  add    $0x4,%rdx
  cmp    (%rdx),%eax
  jge    L32
  nopl   0x0(%rax,%rax,1)
L90:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %eax,(%rdx)
  jg     L90
L32:
  add    $0x1,%ecx
  cmp    %ebx,%ecx
  jne    L79
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <free@plt>
L57:
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L100
```

assistant: ```c
void bucketsort(int *a, int n) {
  int i, j, max;
  int *aux;
  max = 0;
  for (i = 0; i < n; i++)
    if (a[i] > max)
      max = a[i];
  max++;
  if ((n >= max) || (n >= 100000)) {
    aux = (int *)calloc(max + 1, sizeof(int));
    ComputeCount(a, n, aux);
    Count2BeginIndex(aux, max);
    for (i = 0; i < max; i++)
      for (j = aux[i]; j < aux[i + 1]; j++)
        a[j] = i;
    free(aux);
  } else {
    quicksort(a, 0, n - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ptr2intpad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x2,%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  mov    $0x10,%eax
  sub    -0x4(%rbp),%eax
  jmp    L14
L11:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ptr2intpad(int *ptr) {
  int alignment = (((int)ptr) & 63) >> 2;
  if (alignment)
    return 16 - alignment;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ptr2intpad>:
  endbr64
  mov    %edi,%eax
  sar    $0x2,%eax
  and    $0xf,%eax
  mov    $0x10,%edx
  sub    %eax,%edx
  test   %eax,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ptr2intpad(int *ptr) {
  int alignment = (((int)ptr) & 63) >> 2;
  if (alignment)
    return 16 - alignment;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ptr2intpad>:
  endbr64
  mov    %edi,%eax
  mov    $0x10,%edx
  sar    $0x2,%eax
  and    $0xf,%eax
  sub    %eax,%edx
  test   %eax,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ptr2intpad(int *ptr) {
  int alignment = (((int)ptr) & 63) >> 2;
  if (alignment)
    return 16 - alignment;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ptr2intpad>:
  endbr64
  mov    %edi,%eax
  mov    $0x10,%edx
  sar    $0x2,%eax
  and    $0xf,%eax
  sub    %eax,%edx
  test   %eax,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ptr2intpad(int *ptr) {
  int alignment = (((int)ptr) & 63) >> 2;
  if (alignment)
    return 16 - alignment;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xdg_popup_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <wl_proxy_marshal@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wl_proxy_destroy@plt>
  nop
  leave
  ret
```

assistant: ```c
void xdg_popup_destroy(struct xdg_popup *xdg_popup) {
  wl_proxy_marshal((struct wl_proxy *)xdg_popup, 0);
  wl_proxy_destroy((struct wl_proxy *)xdg_popup);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdg_popup_destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%esi
  call   <wl_proxy_marshal@plt>
  mov    %rbx,%rdi
  call   <wl_proxy_destroy@plt>
  pop    %rbx
  ret
```

assistant: ```c
void xdg_popup_destroy(struct xdg_popup *xdg_popup) {
  wl_proxy_marshal((struct wl_proxy *)xdg_popup, 0);
  wl_proxy_destroy((struct wl_proxy *)xdg_popup);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xdg_popup_destroy>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    %rdi,%rbp
  call   <wl_proxy_marshal@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <wl_proxy_destroy@plt>
```

assistant: ```c
void xdg_popup_destroy(struct xdg_popup *xdg_popup) {
  wl_proxy_marshal((struct wl_proxy *)xdg_popup, 0);
  wl_proxy_destroy((struct wl_proxy *)xdg_popup);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<extension_substring_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <extension@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L5
  mov    $0x0,%eax
  jmp    L19
L5:
  mov    $0x1,%eax
L19:
  leave
  ret
```

assistant: ```c
int extension_substring_filter(char *filename, char *textcontent) {
  if (strstr(extension(filename), textcontent) == NULL)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extension_substring_filter>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <extension@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int extension_substring_filter(char *filename, char *textcontent) {
  if (strstr(extension(filename), textcontent) == NULL)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<extension_substring_filter>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <extension@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int extension_substring_filter(char *filename, char *textcontent) {
  if (strstr(extension(filename), textcontent) == NULL)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extension_substring_filter>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <extension@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strstr@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int extension_substring_filter(char *filename, char *textcontent) {
  if (strstr(extension(filename), textcontent) == NULL)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quarticgrad>:
  endbr64
  movsd  (%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  movsd  D31(%rip),%xmm5
  movapd %xmm1,%xmm3
  mulsd  %xmm5,%xmm3
  addsd  %xmm2,%xmm3
  movsd  0x10(%rdi),%xmm0
  movsd  0x18(%rdi),%xmm6
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm4
  subsd  %xmm4,%xmm1
  subsd  %xmm6,%xmm2
  movapd %xmm2,%xmm4
  mulsd  D11(%rip),%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  movapd %xmm3,%xmm2
  addsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm2
  movsd  %xmm2,(%rdx)
  movapd %xmm1,%xmm2
  mulsd  D58(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  D37(%rip),%xmm3
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rdx)
  subsd  %xmm6,%xmm0
  mulsd  %xmm5,%xmm0
  movapd %xmm1,%xmm2
  mulsd  D3(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  movsd  %xmm2,0x10(%rdx)
  xorpd  D22(%rip),%xmm0
  subsd  %xmm4,%xmm0
  movsd  %xmm0,0x18(%rdx)
  ret
```

tool_calls: name: parse_data
arguments: label: D31
type: byte[8]
name: parse_data
arguments: label: D11
type: byte[8]
name: parse_data
arguments: label: D58
type: byte[8]
name: parse_data
arguments: label: D37
type: byte[8]
name: parse_data
arguments: label: D3
type: byte[8]
name: parse_data
arguments: label: D22
type: byte[16]

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x44,0x40]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void quarticgrad(double *x, int N, double *g, void *params) {
  double t1, t2, t3, t4;
  t1 = (x[0] + 10 * x[1]);
  t2 = (x[2] - x[3]);
  t3 = (x[1] - 2 * x[2]);
  t4 = (x[0] - x[3]);
  g[0] = 2 * t1 + 40 * t4 * t4 * t4;
  g[1] = 20 * t1 + 4 * t3 * t3 * t3;
  g[2] = 10 * t2 - 8 * t3 * t3 * t3;
  g[3] = -10 * t2 - 40 * t4 * t4 * t4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quarticgrad>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  movsd  D38(%rip),%xmm5
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm2
  movapd %xmm1,%xmm3
  movsd  0x18(%rdi),%xmm6
  mulsd  %xmm5,%xmm3
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm4
  subsd  %xmm6,%xmm0
  subsd  %xmm4,%xmm1
  movsd  D44(%rip),%xmm4
  mulsd  %xmm5,%xmm0
  addsd  %xmm2,%xmm3
  subsd  %xmm6,%xmm2
  mulsd  %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  movapd %xmm3,%xmm2
  addsd  %xmm3,%xmm2
  mulsd  D49(%rip),%xmm3
  addsd  %xmm4,%xmm2
  movsd  %xmm2,(%rdx)
  movsd  D30(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm3,%xmm2
  movsd  %xmm2,0x8(%rdx)
  movsd  D0(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  xorpd  D4(%rip),%xmm0
  subsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm2
  movsd  %xmm0,0x18(%rdx)
  movsd  %xmm2,0x10(%rdx)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D38
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D44
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D49
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D30
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D0
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D4
type_infered: byte[16]

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x44,0x40]}

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void quarticgrad(double *x, int N, double *g, void *params) {
  double t1, t2, t3, t4;
  t1 = (x[0] + 10 * x[1]);
  t2 = (x[2] - x[3]);
  t3 = (x[1] - 2 * x[2]);
  t4 = (x[0] - x[3]);
  g[0] = 2 * t1 + 40 * t4 * t4 * t4;
  g[1] = 20 * t1 + 4 * t3 * t3 * t3;
  g[2] = 10 * t2 - 8 * t3 * t3 * t3;
  g[3] = -10 * t2 - 40 * t4 * t4 * t4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quarticgrad>:
  endbr64
  movupd (%rdi),%xmm1
  movsd  0x10(%rdi),%xmm0
  movsd  D16(%rip),%xmm4
  movsd  0x18(%rdi),%xmm5
  movapd %xmm1,%xmm7
  movapd %xmm0,%xmm6
  unpckhpd %xmm7,%xmm7
  addsd  %xmm0,%xmm6
  movapd %xmm5,%xmm3
  movapd %xmm7,%xmm2
  subsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm2
  unpcklpd %xmm6,%xmm3
  mulsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm2
  subpd  %xmm3,%xmm1
  movapd D20(%rip),%xmm3
  mulpd  %xmm1,%xmm3
  unpcklpd %xmm2,%xmm2
  mulpd  D39(%rip),%xmm2
  mulpd  %xmm1,%xmm3
  mulpd  %xmm1,%xmm3
  unpckhpd %xmm1,%xmm1
  addpd  %xmm3,%xmm2
  movups %xmm2,(%rdx)
  movsd  D15(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  xorpd  D48(%rip),%xmm0
  subsd  %xmm3,%xmm0
  subsd  %xmm1,%xmm2
  movsd  %xmm0,0x18(%rdx)
  movsd  %xmm2,0x10(%rdx)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D20
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D39
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D15
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D48
type_infered: byte[16]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x44,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void quarticgrad(double *x, int N, double *g, void *params) {
  double t1, t2, t3, t4;
  t1 = (x[0] + 10 * x[1]);
  t2 = (x[2] - x[3]);
  t3 = (x[1] - 2 * x[2]);
  t4 = (x[0] - x[3]);
  g[0] = 2 * t1 + 40 * t4 * t4 * t4;
  g[1] = 20 * t1 + 4 * t3 * t3 * t3;
  g[2] = 10 * t2 - 8 * t3 * t3 * t3;
  g[3] = -10 * t2 - 40 * t4 * t4 * t4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Aprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe0,%rsp
  mov    %rdi,-0x20d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x20d8(%rbp),%rdx
  mov    -0x20c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x20c4(%rbp),%edx
  mov    -0x20d8(%rbp),%rcx
  lea    -0x20c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x20c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x20c0(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x20c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string

tool: D8: 


tool: D16: %s

assistant: ```c
void Aprint(char *format, ...) {
  va_list args;
  char buffer[8192];
  va_start(args, format);
  vsprintf(buffer, format, args);
  va_end(args);
  strcat(buffer, "\n");
  printf("%s", buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Aprint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rbp
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D18
type: string

tool: D4: 


tool: D18: %s

assistant: ```c
void Aprint(char *format, ...) {
  va_list args;
  char buffer[8192];
  va_start(args, format);
  vsprintf(buffer, format, args);
  va_end(args);
  strcat(buffer, "\n");
  printf("%s", buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Aprint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x2010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string

tool: D16: 


tool: D18: %s

assistant: ```c
void Aprint(char *format, ...) {
  va_list args;
  char buffer[8192];
  va_start(args, format);
  vsprintf(buffer, format, args);
  va_end(args);
  strcat(buffer, "\n");
  printf("%s", buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Aprint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string

tool: D5: 


tool: D18: %s

assistant: ```c
void Aprint(char *format, ...) {
  va_list args;
  char buffer[8192];
  va_start(args, format);
  vsprintf(buffer, format, args);
  va_end(args);
  strcat(buffer, "\n");
  printf("%s", buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<moocow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x4(%rbp)
  jmp    L8
L15:
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x2,-0x4(%rbp)
  jle    L15
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x4bda12f7,%rax,%rax
  shr    $0x20,%rax
  sar    $0x4,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x36,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L27
  addl   $0x1,-0x4(%rbp)
  jmp    L30
L27:
  subl   $0x1,-0x4(%rbp)
L30:
  nop
  pop    %rbp
  ret
```

assistant: ```c
int moocow(void) {
  int a;
  a = 3;
  while (a < 3)
    a++;
  if (a % 54 == 0) {
    a++;
  } else {
    a--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<moocow>:
  endbr64
  ret
```

assistant: ```c
int moocow(void) {
  int a;
  a = 3;
  while (a < 3)
    a++;
  if (a % 54 == 0) {
    a++;
  } else {
    a--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<moocow>:
  endbr64
  ret
```

assistant: ```c
int moocow(void) {
  int a;
  a = 3;
  while (a < 3)
    a++;
  if (a % 54 == 0) {
    a++;
  } else {
    a--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<moocow>:
  endbr64
  ret
```

assistant: ```c
int moocow(void) {
  int a;
  a = 3;
  while (a < 3)
    a++;
  if (a % 54 == 0) {
    a++;
  } else {
    a--;
  }
}
```