ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ucase>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L4:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L4
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x5008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %rsp,%r13
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  test   %rbp,%rbp
  je     L8
  xor    %ebx,%ebx
  nopl   (%rax)
L26:
  movsbl (%r12,%rbx,1),%edi
  call   <uch@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L26
L8:
  mov    0x5008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x5018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ucase(char *str) {
  register unsigned long int i, l;
  char uc[20480];
  l = strlen(str);
  memset(uc, '\0', l + 1);
  for (i = 0; i < l; i++)
    uc[i] = uch(str[i]);
  return uc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ucase>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x5008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %rsp,%r13
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  test   %rbp,%rbp
  je     L17
  xor    %ebx,%ebx
  nopl   (%rax)
L0:
  movsbl (%r12,%rbx,1),%edi
  call   <uch@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L0
L17:
  mov    0x5008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x5018,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ucase(char *str) {
  register unsigned long int i, l;
  char uc[20480];
  l = strlen(str);
  memset(uc, '\0', l + 1);
  for (i = 0; i < l; i++)
    uc[i] = uch(str[i]);
  return uc;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fcvt_mp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x8(%rbp),%rdi
  mov    -0xc(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <__dtoa@plt>
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jg     L23
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x34,%al
  jle    L23
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L23
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movb   $0x31,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movb   $0x30,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L23:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  leave
  ret
```

assistant: ```c
char *fcvt_mp(double arg, int ndigits, int *decpt, int *sign, char *buffer) {
  *decpt = __dtoa(buffer, ndigits, arg, 1, 1) + 1;
  if (*decpt + ndigits <= 0 && buffer[1] >= '5' && buffer[1] <= '9') {
    buffer[1] = '1';
    buffer[2] = '0';
    buffer[3] = '\0';
    (*decpt)++;
  }
  *sign = buffer[0] == '-';
  return buffer + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fcvt_mp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %edi,%esi
  mov    %rbx,%rdi
  call   <__dtoa@plt>
  add    $0x1,%eax
  mov    %eax,0x0(%rbp)
  add    %r13d,%eax
  test   %eax,%eax
  jle    L21
L9:
  cmpb   $0x2d,(%rbx)
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%r12)
  lea    0x1(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  movzbl 0x1(%rbx),%eax
  sub    $0x35,%eax
  cmp    $0x4,%al
  ja     L9
  movb   $0x31,0x1(%rbx)
  movb   $0x30,0x2(%rbx)
  movb   $0x0,0x3(%rbx)
  addl   $0x1,0x0(%rbp)
  jmp    L9
```

assistant: ```c
char *fcvt_mp(double arg, int ndigits, int *decpt, int *sign, char *buffer) {
  *decpt = __dtoa(buffer, ndigits, arg, 1, 1) + 1;
  if (*decpt + ndigits <= 0 && buffer[1] >= '5' && buffer[1] <= '9') {
    buffer[1] = '1';
    buffer[2] = '0';
    buffer[3] = '\0';
    (*decpt)++;
  }
  *sign = buffer[0] == '-';
  return buffer + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fcvt_mp>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x1,%edx
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  mov    $0x1,%ecx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <__dtoa@plt>
  add    $0x1,%eax
  mov    %eax,(%r12)
  add    %ebp,%eax
  test   %eax,%eax
  jle    L29
L10:
  xor    %eax,%eax
  cmpb   $0x2d,(%rbx)
  sete   %al
  mov    %eax,0x0(%r13)
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  movzbl 0x1(%rbx),%eax
  sub    $0x35,%eax
  cmp    $0x4,%al
  ja     L10
  mov    $0x3031,%eax
  movb   $0x0,0x3(%rbx)
  mov    %ax,0x1(%rbx)
  addl   $0x1,(%r12)
  jmp    L10
```

assistant: ```c
char *fcvt_mp(double arg, int ndigits, int *decpt, int *sign, char *buffer) {
  *decpt = __dtoa(buffer, ndigits, arg, 1, 1) + 1;
  if (*decpt + ndigits <= 0 && buffer[1] >= '5' && buffer[1] <= '9') {
    buffer[1] = '1';
    buffer[2] = '0';
    buffer[3] = '\0';
    (*decpt)++;
  }
  *sign = buffer[0] == '-';
  return buffer + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fcvt_mp>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x1,%edx
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  mov    $0x1,%ecx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <__dtoa@plt>
  add    $0x1,%eax
  mov    %eax,(%r12)
  add    %ebp,%eax
  test   %eax,%eax
  jle    L18
L2:
  xor    %eax,%eax
  cmpb   $0x2d,(%rbx)
  sete   %al
  mov    %eax,0x0(%r13)
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  movzbl 0x1(%rbx),%eax
  sub    $0x35,%eax
  cmp    $0x4,%al
  ja     L2
  mov    $0x3031,%eax
  movb   $0x0,0x3(%rbx)
  mov    %ax,0x1(%rbx)
  addl   $0x1,(%r12)
  jmp    L2
```

assistant: ```c
char *fcvt_mp(double arg, int ndigits, int *decpt, int *sign, char *buffer) {
  *decpt = __dtoa(buffer, ndigits, arg, 1, 1) + 1;
  if (*decpt + ndigits <= 0 && buffer[1] >= '5' && buffer[1] <= '9') {
    buffer[1] = '1';
    buffer[2] = '0';
    buffer[3] = '\0';
    (*decpt)++;
  }
  *sign = buffer[0] == '-';
  return buffer + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<digittoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L0
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L39
L0:
  cmpl   $0x40,-0x4(%rbp)
  jle    L2
  cmpl   $0x46,-0x4(%rbp)
  jg     L2
  mov    -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L39
L2:
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int digittoint(int c) {
  c = toupper(c);
  if (isdigit(c))
    return c - '0';
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<digittoint>:
  endbr64
  push   %rbx
  call   <toupper@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  lea    -0x41(%rbx),%eax
  sub    $0x37,%ebx
  cmp    $0x6,%eax
  mov    $0x0,%eax
  cmovb  %ebx,%eax
L10:
  pop    %rbx
  ret
L6:
  lea    -0x30(%rbx),%eax
  jmp    L10
```

assistant: ```c
int digittoint(int c) {
  c = toupper(c);
  if (isdigit(c))
    return c - '0';
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<digittoint>:
  endbr64
  push   %rbx
  call   <toupper@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  lea    -0x41(%rbx),%eax
  sub    $0x37,%ebx
  cmp    $0x6,%eax
  mov    $0x0,%eax
  cmovb  %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x30(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int digittoint(int c) {
  c = toupper(c);
  if (isdigit(c))
    return c - '0';
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<digittoint>:
  endbr64
  push   %rbx
  call   <toupper@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L0
  lea    -0x41(%rbx),%eax
  sub    $0x37,%ebx
  cmp    $0x6,%eax
  mov    $0x0,%eax
  cmovb  %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  lea    -0x30(%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int digittoint(int c) {
  c = toupper(c);
  if (isdigit(c))
    return c - '0';
  else if (c >= 'A' && c <= 'F')
    return c - 'A' + 10;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  leave
  ret
```

assistant: ```c
void zero(void *const addr, const size_t len) {
  assert(((addr)) && "Unexpected null pointer.");
  ;
  memset(addr, 0, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zero>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zero(void *const addr, const size_t len) {
  assert(((addr)) && "Unexpected null pointer.");
  ;
  memset(addr, 0, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zero>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    1060 <memset@plt>
```

assistant: ```c
void zero(void *const addr, const size_t len) {
  assert(((addr)) && "Unexpected null pointer.");
  ;
  memset(addr, 0, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  jmp    1060 <memset@plt>
```

assistant: ```c
void zero(void *const addr, const size_t len) {
  assert(((addr)) && "Unexpected null pointer.");
  ;
  memset(addr, 0, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fatShuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1b8,-0xc(%rbp)
  jmp    L12
L14:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0xc(%rbp),%edx
  lea    0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x18(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x30c30c31,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %eax,%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x18(%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x30c30c31,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %eax,%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x18(%rax),%esi
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x30c30c31,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  add    %eax,%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x18(%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x30c30c31,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %eax,%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x0,-0xc(%rbp)
  jg     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void fatShuffle(int X[((21 + 2) * (21 + 2))]) {
  int j, k, tmp;
  for (k = (21 * 21) - 1; k > 0; k--) {
    j = (rand() % (k + 1));
    tmp = X[((21 + 3) + (j) + 2 * ((j) / 21))];
    X[((21 + 3) + (j) + 2 * ((j) / 21))] = X[((21 + 3) + (k) + 2 * ((k) / 21))];
    X[((21 + 3) + (k) + 2 * ((k) / 21))] = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatShuffle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x1b8,%ebx
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%ecx
  cltd
  idiv   %ecx
  movslq %edx,%rax
  imul   $0x30c30c31,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x18(%rdx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdx
  mov    (%rdx),%ecx
  movslq %ebx,%rax
  imul   $0x30c30c31,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    0x18(%rbx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fatShuffle(int X[((21 + 2) * (21 + 2))]) {
  int j, k, tmp;
  for (k = (21 * 21) - 1; k > 0; k--) {
    j = (rand() % (k + 1));
    tmp = X[((21 + 3) + (j) + 2 * ((j) / 21))];
    X[((21 + 3) + (j) + 2 * ((j) / 21))] = X[((21 + 3) + (k) + 2 * ((k) / 21))];
    X[((21 + 3) + (k) + 2 * ((k) / 21))] = tmp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fatShuffle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1b8,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%ecx
  mov    %ebx,%esi
  cltd
  sar    $0x1f,%esi
  idiv   %ecx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x30c30c31,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    0x18(%rdx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdx
  movslq %ebx,%rax
  imul   $0x30c30c31,%rax,%rax
  mov    (%rdx),%ecx
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    0x18(%rbx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fatShuffle(int X[((21 + 2) * (21 + 2))]) {
  int j, k, tmp;
  for (k = (21 * 21) - 1; k > 0; k--) {
    j = (rand() % (k + 1));
    tmp = X[((21 + 3) + (j) + 2 * ((j) / 21))];
    X[((21 + 3) + (j) + 2 * ((j) / 21))] = X[((21 + 3) + (k) + 2 * ((k) / 21))];
    X[((21 + 3) + (k) + 2 * ((k) / 21))] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fatShuffle>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1b8,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%ecx
  mov    %ebx,%esi
  cltd
  sar    $0x1f,%esi
  idiv   %ecx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x30c30c31,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    0x18(%rdx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdx
  movslq %ebx,%rax
  imul   $0x30c30c31,%rax,%rax
  mov    (%rdx),%ecx
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    0x18(%rbx,%rax,2),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fatShuffle(int X[((21 + 2) * (21 + 2))]) {
  int j, k, tmp;
  for (k = (21 * 21) - 1; k > 0; k--) {
    j = (rand() % (k + 1));
    tmp = X[((21 + 3) + (j) + 2 * ((j) / 21))];
    X[((21 + 3) + (j) + 2 * ((j) / 21))] = X[((21 + 3) + (k) + 2 * ((k) / 21))];
    X[((21 + 3) + (k) + 2 * ((k) / 21))] = tmp;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quad_maxheapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  shl    $0x2,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L2
L37:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L22:
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  ja     L28
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L37
L28:
  mov    -0x20(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  je     L23
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x40(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <quad_maxheapify>
  nop
L23:
  nop
  leave
  ret
```

assistant: ```c
void quad_maxheapify(int a[], size_t i, size_t heapsize) {
  size_t largest;
  int temp;
  size_t l = (4 * (i) + 1);
  size_t r = (4 * (i) + 4);
  largest = i;
  for (size_t j = l; j <= heapsize && j <= r; ++j) {
    if (a[j] > a[largest])
      largest = j;
  }
  if (largest != i) {
    temp = a[i];
    a[i] = a[largest];
    a[largest] = temp;
    quad_maxheapify(a, largest, heapsize);
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quad_maxheapify>:
  endbr64
  lea    0x0(,%rsi,4),%r9
  lea    0x1(%r9),%rax
  lea    0x4(%r9),%rcx
  cmp    %rdx,%rcx
  cmova  %rdx,%rcx
  cmp    %rcx,%rax
  ja     L11
  mov    %rsi,%r8
L6:
  mov    (%rdi,%rsi,4),%r10d
  cmp    %r10d,(%rdi,%rax,4)
  cmovg  %rax,%rsi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jbe    L6
  cmp    %r8,%rsi
  je     L11
  sub    $0x8,%rsp
  add    %rdi,%r9
  mov    (%r9),%ecx
  lea    (%rdi,%rsi,4),%rax
  mov    (%rax),%r8d
  mov    %r8d,(%r9)
  mov    %ecx,(%rax)
  call   <quad_maxheapify>
  add    $0x8,%rsp
  ret
L11:
  ret
```

assistant: ```c
void quad_maxheapify(int a[], size_t i, size_t heapsize) {
  size_t largest;
  int temp;
  size_t l = (4 * (i) + 1);
  size_t r = (4 * (i) + 4);
  largest = i;
  for (size_t j = l; j <= heapsize && j <= r; ++j) {
    if (a[j] > a[largest])
      largest = j;
  }
  if (largest != i) {
    temp = a[i];
    a[i] = a[largest];
    a[largest] = temp;
    quad_maxheapify(a, largest, heapsize);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quad_maxheapify>:
  endbr64
  nopl   0x0(%rax)
L26:
  lea    0x0(,%rsi,4),%r9
  lea    0x4(%r9),%r8
  lea    0x1(%r9),%rax
  cmp    %rdx,%r8
  cmova  %rdx,%r8
  cmp    %r8,%rax
  ja     L16
  mov    %rsi,%rcx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rdi,%rcx,4),%r10d
  cmp    %r10d,(%rdi,%rax,4)
  cmovg  %rax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rax
  jbe    L29
  cmp    %rsi,%rcx
  je     L16
  add    %rdi,%r9
  lea    (%rdi,%rcx,4),%rax
  mov    (%r9),%esi
  mov    (%rax),%r8d
  mov    %r8d,(%r9)
  mov    %esi,(%rax)
  mov    %rcx,%rsi
  jmp    L26
  nopl   0x0(%rax)
L16:
  ret
```

assistant: ```c
void quad_maxheapify(int a[], size_t i, size_t heapsize) {
  size_t largest;
  int temp;
  size_t l = (4 * (i) + 1);
  size_t r = (4 * (i) + 4);
  largest = i;
  for (size_t j = l; j <= heapsize && j <= r; ++j) {
    if (a[j] > a[largest])
      largest = j;
  }
  if (largest != i) {
    temp = a[i];
    a[i] = a[largest];
    a[largest] = temp;
    quad_maxheapify(a, largest, heapsize);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quad_maxheapify>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L9:
  lea    0x0(,%rbp,4),%rax
  lea    0x4(%rax),%r8
  lea    0x1(%rax),%rcx
  cmp    %r12,%r8
  cmova  %r12,%r8
  cmp    %r8,%rcx
  ja     L7
  lea    (%rbx,%rax,1),%r11
  mov    %rbp,%r10
  lea    (%rbx,%rcx,4),%rax
  mov    (%r11),%edx
  mov    %edx,%edi
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L58:
  add    $0x1,%rcx
  lea    (%rbx,%r10,4),%r9
  add    $0x4,%rax
  cmp    %r8,%rcx
  ja     L48
L25:
  mov    (%rax),%esi
  mov    %rax,%r9
  cmp    %edi,%esi
  jle    L58
  mov    %rcx,%r10
  add    $0x1,%rcx
  mov    %esi,%edi
  add    $0x4,%rax
  cmp    %r8,%rcx
  jbe    L25
L48:
  cmp    %rbp,%r10
  je     L7
  mov    %edi,(%r11)
  mov    %r10,%rbp
  mov    %edx,(%r9)
  jmp    L9
  nopl   0x0(%rax)
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void quad_maxheapify(int a[], size_t i, size_t heapsize) {
  size_t largest;
  int temp;
  size_t l = (4 * (i) + 1);
  size_t r = (4 * (i) + 4);
  largest = i;
  for (size_t j = l; j <= heapsize && j <= r; ++j) {
    if (a[j] > a[largest])
      largest = j;
  }
  if (largest != i) {
    temp = a[i];
    a[i] = a[largest];
    a[largest] = temp;
    quad_maxheapify(a, largest, heapsize);
  }
  return;
}
```