ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fd2ofd>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  push   $0x3
  lea    0x28(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  lea    0x2c(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <fd2i@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    0x1c(%rsp),%eax
  pop    %rdx
  pop    %rcx
  cmp    $0x76b,%eax
  jle    L10
  cmp    $0x7cf,%eax
  jle    L17
  cmp    $0xb53,%eax
  jg     L10
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    %r12,%rdi
  lea    -0x76c(%rax),%r8d
  lea    D26(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L28
  nopl   0x0(%rax)
L10:
  movabs $0x2a2a2065676e6172,%rax
  movdqa D4(%rip),%xmm0
  mov    %rax,0x10(%r12)
  mov    $0x2a,%eax
  mov    %ax,0x18(%r12)
  movups %xmm0,(%r12)
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    %r12,%rdi
  lea    -0x76c(%rax),%r8d
  lea    D17(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L28
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: byte[16]
name: retrieve_data
arguments: data_label: D17
datatype: string

tool: D26: %02d/%02d/%3d

tool: {"D4": [0x2a,0x2a,0x2a,0x20,0x64,0x61,0x74,0x65,0x20,0x6f,0x75,0x74,0x20,0x6f,0x66,0x20]}

tool: D17: %02d/%02d/%02d

assistant: ```c
char *fd2ofd(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  if (iyr < 1900)
    sprintf(string, "*** date out of range ***");
  else if (iyr < 2000)
    sprintf(string, "%02d/%02d/%02d", iday, imon, iyr - 1900);
  else if (iyr < 2900.0)
    sprintf(string, "%02d/%02d/%3d", iday, imon, iyr - 1900);
  else
    sprintf(string, "*** date out of range ***");
  return (string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fd2ofd>:
  endbr64
  push   %r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  push   $0x3
  lea    0x28(%rsp),%rax
  push   %rax
  xor    %eax,%eax
  lea    0x2c(%rsp),%r9
  lea    0x28(%rsp),%r8
  call   <fd2i@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    0x1c(%rsp),%eax
  pop    %rdx
  pop    %rcx
  cmp    $0x76b,%eax
  jle    L6
  cmp    $0x7cf,%eax
  jle    L36
  cmp    $0xb53,%eax
  jg     L6
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    %r12,%rdi
  lea    -0x76c(%rax),%r8d
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L26
  nopl   0x0(%rax)
L6:
  movabs $0x2a2a2065676e6172,%rax
  movdqa D12(%rip),%xmm0
  mov    %rax,0x10(%r12)
  mov    $0x2a,%eax
  mov    %ax,0x18(%r12)
  movups %xmm0,(%r12)
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L36:
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%edx
  mov    %r12,%rdi
  lea    -0x76c(%rax),%r8d
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L26
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string
name: retrieve_data
arguments: data_label: D12
type: byte[16]
name: retrieve_data
arguments: data_label: D1
type: string

tool: D9: %02d/%02d/%3d

tool: {"D12": [0x2a,0x2a,0x2a,0x20,0x64,0x61,0x74,0x65,0x20,0x6f,0x75,0x74,0x20,0x6f,0x66,0x20]}

tool: D1: %02d/%02d/%02d

assistant: ```c
char *fd2ofd(string)
char *string;
{
  int iyr, imon, iday, ihr, imn;
  double sec;
  fd2i(string, &iyr, &imon, &iday, &ihr, &imn, &sec, 3);
  string = (char *)calloc(32, sizeof(char));
  if (iyr < 1900)
    sprintf(string, "*** date out of range ***");
  else if (iyr < 2000)
    sprintf(string, "%02d/%02d/%02d", iday, imon, iyr - 1900);
  else if (iyr < 2900.0)
    sprintf(string, "%02d/%02d/%3d", iday, imon, iyr - 1900);
  else
    sprintf(string, "*** date out of range ***");
  return (string);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<recurring_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x9c40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L18
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  jmp    L2
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L23
L2:
  leave
  ret
```

assistant: ```c
size_t recurring_length(int d, int *in_seq) {
  int n;
  size_t k;
  memset(in_seq, 0, 10000 * sizeof(int));
  k = 1;
  n = 1;
  for (;;) {
    if (in_seq[n])
      return k - in_seq[n];
    in_seq[n] = k;
    n *= 10;
    n = n % d;
    ++k;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recurring_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x9c40,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x4(%rbp),%rdx
  mov    0x4(%rbp),%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L4
L19:
  mov    %ecx,(%rdx)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  add    $0x1,%rcx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  mov    (%rdx),%esi
  test   %esi,%esi
  je     L19
L4:
  movslq %esi,%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t recurring_length(int d, int *in_seq) {
  int n;
  size_t k;
  memset(in_seq, 0, 10000 * sizeof(int));
  k = 1;
  n = 1;
  for (;;) {
    if (in_seq[n])
      return k - in_seq[n];
    in_seq[n] = k;
    n *= 10;
    n = n % d;
    ++k;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recurring_length>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  movslq 0x4(%rbp),%rsi
  mov    $0x1,%ecx
  test   %esi,%esi
  jne    L7
  lea    0x4(%rbp),%rax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L16:
  mov    %ecx,(%rax)
  lea    (%rdx,%rdx,4),%eax
  add    $0x1,%rcx
  add    %eax,%eax
  cltd
  idiv   %ebx
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rax
  movslq (%rax),%rsi
  test   %esi,%esi
  je     L16
L7:
  add    $0x8,%rsp
  mov    %rcx,%rax
  sub    %rsi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t recurring_length(int d, int *in_seq) {
  int n;
  size_t k;
  memset(in_seq, 0, 10000 * sizeof(int));
  k = 1;
  n = 1;
  for (;;) {
    if (in_seq[n])
      return k - in_seq[n];
    in_seq[n] = k;
    n *= 10;
    n = n % d;
    ++k;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recurring_length>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  movslq 0x4(%rbp),%rsi
  mov    $0x1,%ecx
  test   %esi,%esi
  jne    L10
  lea    0x4(%rbp),%rax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  mov    %ecx,(%rax)
  lea    (%rdx,%rdx,4),%eax
  add    $0x1,%rcx
  add    %eax,%eax
  cltd
  idiv   %ebx
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rax
  movslq (%rax),%rsi
  test   %esi,%esi
  je     L4
L10:
  add    $0x8,%rsp
  mov    %rcx,%rax
  sub    %rsi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t recurring_length(int d, int *in_seq) {
  int n;
  size_t k;
  memset(in_seq, 0, 10000 * sizeof(int));
  k = 1;
  n = 1;
  for (;;) {
    if (in_seq[n])
      return k - in_seq[n];
    in_seq[n] = k;
    n *= 10;
    n = n % d;
    ++k;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isheader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L57
L22:
  mov    $0x0,%eax
  jmp    L8
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L19
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  jne    L5
L19:
  mov    $0x0,%eax
  jmp    L8
L5:
  addq   $0x1,-0x18(%rbp)
L57:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L11
  mov    $0x1,%eax
L8:
  leave
  ret
```

assistant: ```c
int isheader(char *s) {
  char *p;
  if (((p = strchr(s, ':')) == 0) || (s == p)) {
    return (0);
  }
  while (s != p) {
    if ((*s < '!') || (*s > '~')) {
      return (0);
    }
    s++;
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isheader>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3a,%esi
  call   <strchr@plt>
  cmp    %rax,%rbx
  je     L12
  test   %rax,%rax
  je     L12
L34:
  movzbl (%rbx),%ecx
  lea    -0x21(%rcx),%edx
  cmp    $0x5d,%dl
  ja     L31
  add    $0x1,%rbx
  cmp    %rbx,%rax
  jne    L34
  mov    $0x1,%eax
  jmp    L38
L12:
  mov    $0x0,%eax
L38:
  pop    %rbx
  ret
L31:
  mov    $0x0,%eax
  jmp    L38
```

assistant: ```c
int isheader(char *s) {
  char *p;
  if (((p = strchr(s, ':')) == 0) || (s == p)) {
    return (0);
  }
  while (s != p) {
    if ((*s < '!') || (*s > '~')) {
      return (0);
    }
    s++;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isheader>:
  endbr64
  push   %rbx
  mov    $0x3a,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L29
  cmp    %rax,%rbx
  je     L29
  nopl   0x0(%rax)
L32:
  movzbl (%rbx),%ecx
  lea    -0x21(%rcx),%edx
  cmp    $0x5d,%dl
  ja     L29
  add    $0x1,%rbx
  cmp    %rbx,%rax
  jne    L32
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isheader(char *s) {
  char *p;
  if (((p = strchr(s, ':')) == 0) || (s == p)) {
    return (0);
  }
  while (s != p) {
    if ((*s < '!') || (*s > '~')) {
      return (0);
    }
    s++;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isheader>:
  endbr64
  push   %rbx
  mov    $0x3a,%esi
  mov    %rdi,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  cmp    %rax,%rbx
  je     L19
  nopl   0x0(%rax)
L18:
  movzbl (%rbx),%ecx
  lea    -0x21(%rcx),%edx
  cmp    $0x5d,%dl
  ja     L19
  add    $0x1,%rbx
  cmp    %rbx,%rax
  jne    L18
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isheader(char *s) {
  char *p;
  if (((p = strchr(s, ':')) == 0) || (s == p)) {
    return (0);
  }
  while (s != p) {
    if ((*s < '!') || (*s > '~')) {
      return (0);
    }
    s++;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L6:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void newline(int indent) {
  int i;
  putchar('\n');
  for (i = 0; i < indent; i++)
    putchar(' ');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<newline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L10
  mov    $0x0,%ebx
L18:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L18
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void newline(int indent) {
  int i;
  putchar('\n');
  for (i = 0; i < indent; i++)
    putchar(' ');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<newline>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xa,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L14
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L8
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void newline(int indent) {
  int i;
  putchar('\n');
  for (i = 0; i < indent; i++)
    putchar(' ');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<newline>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xa,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L0
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L6
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void newline(int indent) {
  int i;
  putchar('\n');
  for (i = 0; i < indent; i++)
    putchar(' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump_stuff_mmx_msg_sepline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <dump_stuff_mmx@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: %s :


assistant: ```c
void dump_stuff_mmx_msg_sepline(const void *msg, void *buf, unsigned int size, unsigned int index) {
  printf("%s :\n", (char *)msg);
  dump_stuff_mmx(buf, size, index);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dump_stuff_mmx_msg_sepline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <dump_stuff_mmx@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %s :


assistant: ```c
void dump_stuff_mmx_msg_sepline(const void *msg, void *buf, unsigned int size, unsigned int index) {
  printf("%s :\n", (char *)msg);
  dump_stuff_mmx(buf, size, index);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_stuff_mmx_msg_sepline>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <dump_stuff_mmx@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: %s :


assistant: ```c
void dump_stuff_mmx_msg_sepline(const void *msg, void *buf, unsigned int size, unsigned int index) {
  printf("%s :\n", (char *)msg);
  dump_stuff_mmx(buf, size, index);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dump_stuff_mmx_msg_sepline>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <dump_stuff_mmx@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: %s :


assistant: ```c
void dump_stuff_mmx_msg_sepline(const void *msg, void *buf, unsigned int size, unsigned int index) {
  printf("%s :\n", (char *)msg);
  dump_stuff_mmx(buf, size, index);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_now_date_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
char *get_now_date_string() {
  long time_now;
  time_now = time(0);
  return ctime(&time_now);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_now_date_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_now_date_string() {
  long time_now;
  time_now = time(0);
  return ctime(&time_now);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_now_date_string>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_now_date_string() {
  long time_now;
  time_now = time(0);
  return ctime(&time_now);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_now_date_string>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_now_date_string() {
  long time_now;
  time_now = time(0);
  return ctime(&time_now);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tests_from_supercop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x1010,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x20(%rsp),%rdi
  mov    $0x10,%esi
  call   <fill@plt>
  lea    0x30(%rsp),%rdi
  mov    $0x10,%esi
  call   <fill@plt>
  mov    $0x0,%ebx
  movl   $0x0,0xc(%rsp)
  jmp    L0
L31:
  add    $0x1,%rbx
  cmp    $0x1001,%rbx
  je     L18
L0:
  mov    %rbx,0x18(%rsp)
  lea    0x10(%rbx),%rax
  mov    %rax,0x10(%rsp)
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <fill@plt>
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  call   <fill@plt>
  lea    0x10(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x28(%rsp),%r14
  push   %r14
  lea    0x40(%rsp),%r13
  push   %r13
  push   $0x0
  mov    %rbx,%r9
  mov    %r12,%r8
  mov    0x38(%rsp),%rcx
  mov    %rbp,%rdx
  mov    %r15,%rdi
  call   <crypto_aead_encrypt@plt>
  add    $0x20,%rsp
  lea    0x18(%rsp),%rsi
  sub    $0x8,%rsp
  push   %r14
  push   %r13
  push   %rbx
  mov    %r12,%r9
  mov    0x30(%rsp),%r8
  mov    %r15,%rcx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <crypto_aead_decrypt@plt>
  or     %eax,0x2c(%rsp)
  add    $0x20,%rsp
  test   %eax,%eax
  je     L31
  mov    %rbx,%rdx
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L18:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    0xc(%rsp),%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: crypto_aead_decrypt returned %d at %zu


assistant: ```c
int tests_from_supercop() {
  static const size_t MAXTEST_BYTES = 4096;
  unsigned char *c = (unsigned char *)malloc((size_t)MAXTEST_BYTES + 16);
  unsigned char *a = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char *m = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char k[16];
  unsigned char npub[16];
  unsigned char *nsec = 0;
  unsigned long long alen;
  unsigned long long clen;
  unsigned long long mlen;
  int result = 0;
  fill(k, 16);
  fill(npub, 16);
  for (size_t i = 0; i <= MAXTEST_BYTES; ++i) {
    mlen = i;
    alen = i;
    clen = i + 16;
    fill(a, alen);
    fill(m, mlen);
    crypto_aead_encrypt(c, &clen, m, mlen, a, alen, nsec, npub, k);
    const int current_result = crypto_aead_decrypt(m, &mlen, nsec, c, clen, a, alen, npub, k);
    result |= current_result;
    if (current_result) {
      printf("crypto_aead_decrypt returned %d at %zu\n", current_result, i);
    }
  }
  free(a);
  free(c);
  free(m);
  return result;
}
```