ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <ft_safestrlen@plt>
  mov    %rsp,%rsi
  add    $0x1,%eax
  cltq
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L117
L135:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L135
L117:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L93
L170:
  lea    0x3(%rsp),%r9
  mov    %r9,%rdx
  and    $0xfffffffffffffffc,%r9
  shr    $0x2,%rdx
  cmp    $0x4,%rax
  je     L21
  movzbl (%r12),%esi
  cmp    %r13b,%sil
  je     L168
  movl   $0x0,0x0(,%rdx,4)
  mov    $0x1,%r8d
  test   %sil,%sil
  je     L30
L179:
  lea    0x1(%r12),%rdx
  xor    %ecx,%ecx
  jmp    L55
  nopl   0x0(%rax)
L130:
  test   %al,%al
  je     L134
  cmp    %al,%bl
  je     L134
L41:
  add    $0x1,%rdx
L6:
  mov    %edi,%ecx
  mov    %eax,%esi
L55:
  movzbl (%rdx),%eax
  lea    0x1(%rcx),%edi
  cmp    %sil,%bl
  jne    L130
  cmp    %al,%bl
  je     L81
  test   %al,%al
  je     L81
  movslq %r8d,%rcx
  add    $0x1,%r8d
  mov    %edi,(%r9,%rcx,4)
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L134:
  movslq %r8d,%rsi
  add    $0x1,%r8d
  mov    %ecx,(%r9,%rsi,4)
L81:
  add    $0x1,%rdx
  test   %al,%al
  jne    L6
  test   %r8d,%r8d
  je     L21
L30:
  mov    %r8d,%edx
  mov    %r9,%rsi
  mov    %r12,%rdi
  call   <filled_strarray@plt>
L43:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L150
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L168:
  xor    %r8d,%r8d
  test   %r13b,%r13b
  jne    L179
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  call   <empty_strarray@plt>
  jmp    L43
  nopl   0x0(%rax)
L93:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L170
L150:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **ft_strsplit(char const *s, char c) {
  int pos[ft_safestrlen(s) + 1];
  int i;
  int numpos;
  if (sizeof(pos) == sizeof(int))
    return (empty_strarray());
  i = 0;
  numpos = 0;
  if (i == 0 && s[0] != c)
    pos[numpos++] = 0;
  while (s[i])
    if (s[i] != c && (s[i + 1] == c || s[i + 1] == 0))
      pos[numpos++] = i++;
    else if (s[i] == c && s[i + 1] != c && s[i + 1] != 0)
      pos[numpos++] = ++i;
    else
      i++;
  if (numpos == 0)
    return (empty_strarray());
  return (filled_strarray(s, pos, numpos));
}
```
user: What is the c source code of the assembly code below?

```asm
<cst_downcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <cst_strdup@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L16
L4:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L21
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
L21:
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char *cst_downcase(const unsigned char *str) {
  unsigned char *dc;
  int i;
  dc = cst_strdup(str);
  for (i = 0; str[i] != '\0'; i++) {
    if (isupper((int)str[i]))
      dc[i] = tolower((int)str[i]);
  }
  return dc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cst_downcase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <cst_strdup@plt>
  mov    %rax,%r12
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L30
  mov    %rax,%rbp
  jmp    L5
L35:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L30
L5:
  movzbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L35
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  jmp    L35
L30:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *cst_downcase(const unsigned char *str) {
  unsigned char *dc;
  int i;
  dc = cst_strdup(str);
  for (i = 0; str[i] != '\0'; i++) {
    if (isupper((int)str[i]))
      dc[i] = tolower((int)str[i]);
  }
  return dc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cst_downcase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <cst_strdup@plt>
  movzbl (%rbx),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L16
  mov    %rax,%rbp
  jmp    L45
L14:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  test   %dil,%dil
  je     L16
L45:
  call   <isupper@plt>
  test   %rax,%rax
  je     L14
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *cst_downcase(const unsigned char *str) {
  unsigned char *dc;
  int i;
  dc = cst_strdup(str);
  for (i = 0; str[i] != '\0'; i++) {
    if (isupper((int)str[i]))
      dc[i] = tolower((int)str[i]);
  }
  return dc;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cst_downcase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <cst_strdup@plt>
  movzbl (%rbx),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L37
  mov    %rax,%rbp
  jmp    L28
L8:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  test   %dil,%dil
  je     L37
L28:
  call   <isupper@plt>
  test   %rax,%rax
  je     L8
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <tolower@plt>
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L28
L37:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char *cst_downcase(const unsigned char *str) {
  unsigned char *dc;
  int i;
  dc = cst_strdup(str);
  for (i = 0; str[i] != '\0'; i++) {
    if (isupper((int)str[i]))
      dc[i] = tolower((int)str[i]);
  }
  return dc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Assign_State>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  ja     L39
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x0,-0x14(%rbp)
  jmp    L213
  movl   $0x1,-0x14(%rbp)
  jmp    L213
  movl   $0x2,-0x14(%rbp)
  jmp    L213
  movl   $0x3,-0x14(%rbp)
  jmp    L213
  movl   $0x4,-0x14(%rbp)
  jmp    L213
  movl   $0x5,-0x14(%rbp)
  jmp    L213
  movl   $0x6,-0x14(%rbp)
  jmp    L213
  movl   $0x7,-0x14(%rbp)
  jmp    L213
  movl   $0x8,-0x14(%rbp)
  jmp    L213
  movl   $0x9,-0x14(%rbp)
  jmp    L213
  movl   $0xa,-0x14(%rbp)
  jmp    L213
  movl   $0xb,-0x14(%rbp)
  jmp    L213
  movl   $0xc,-0x14(%rbp)
  jmp    L213
  movl   $0xd,-0x14(%rbp)
  jmp    L213
  movl   $0xe,-0x14(%rbp)
  jmp    L213
  movl   $0xf,-0x14(%rbp)
  jmp    L213
  movl   $0x10,-0x14(%rbp)
  jmp    L213
  movl   $0x11,-0x14(%rbp)
  jmp    L213
  movl   $0x12,-0x14(%rbp)
  jmp    L213
  movl   $0x13,-0x14(%rbp)
  jmp    L213
  movl   $0x2,-0x14(%rbp)
  jmp    L213
  movl   $0x5,-0x14(%rbp)
  jmp    L213
L39:
  movl   $0xffffffff,-0x14(%rbp)
  nop
L213:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L103
  call   <__stack_chk_fail@plt>
L103:
  leave
  ret
```

assistant: ```c
int Assign_State(char *c) {
  int state[3];
  state[0] = state[1] = state[2] = -1;
  switch (c[0]) {
  case 'A': {
    state[0] = 0;
    break;
  }
  case 'R': {
    state[0] = 1;
    break;
  }
  case 'N': {
    state[0] = 2;
    break;
  }
  case 'D': {
    state[0] = 3;
    break;
  }
  case 'C': {
    state[0] = 4;
    break;
  }
  case 'Q': {
    state[0] = 5;
    break;
  }
  case 'E': {
    state[0] = 6;
    break;
  }
  case 'G': {
    state[0] = 7;
    break;
  }
  case 'H': {
    state[0] = 8;
    break;
  }
  case 'I': {
    state[0] = 9;
    break;
  }
  case 'L': {
    state[0] = 10;
    break;
  }
  case 'K': {
    state[0] = 11;
    break;
  }
  case 'M': {
    state[0] = 12;
    break;
  }
  case 'F': {
    state[0] = 13;
    break;
  }
  case 'P': {
    state[0] = 14;
    break;
  }
  case 'S': {
    state[0] = 15;
    break;
  }
  case 'T': {
    state[0] = 16;
    break;
  }
  case 'W': {
    state[0] = 17;
    break;
  }
  case 'Y': {
    state[0] = 18;
    break;
  }
  case 'V': {
    state[0] = 19;
    break;
  }
  case 'B': {
    state[0] = 2;
    break;
  }
  case 'Z': {
    state[0] = 5;
    break;
  }
  default: {
    state[0] = -1;
    break;
  }
  }
  return state[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Assign_State>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L1
  movzbl %al,%eax
  lea    D6(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0x11,%eax
  ret
  mov    $0x12,%eax
  ret
  mov    $0x13,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x5,%eax
  ret
L1:
  mov    $0xffffffff,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Assign_State(char *c) {
  int state[3];
  state[0] = state[1] = state[2] = -1;
  switch (c[0]) {
  case 'A': {
    state[0] = 0;
    break;
  }
  case 'R': {
    state[0] = 1;
    break;
  }
  case 'N': {
    state[0] = 2;
    break;
  }
  case 'D': {
    state[0] = 3;
    break;
  }
  case 'C': {
    state[0] = 4;
    break;
  }
  case 'Q': {
    state[0] = 5;
    break;
  }
  case 'E': {
    state[0] = 6;
    break;
  }
  case 'G': {
    state[0] = 7;
    break;
  }
  case 'H': {
    state[0] = 8;
    break;
  }
  case 'I': {
    state[0] = 9;
    break;
  }
  case 'L': {
    state[0] = 10;
    break;
  }
  case 'K': {
    state[0] = 11;
    break;
  }
  case 'M': {
    state[0] = 12;
    break;
  }
  case 'F': {
    state[0] = 13;
    break;
  }
  case 'P': {
    state[0] = 14;
    break;
  }
  case 'S': {
    state[0] = 15;
    break;
  }
  case 'T': {
    state[0] = 16;
    break;
  }
  case 'W': {
    state[0] = 17;
    break;
  }
  case 'Y': {
    state[0] = 18;
    break;
  }
  case 'V': {
    state[0] = 19;
    break;
  }
  case 'B': {
    state[0] = 2;
    break;
  }
  case 'Z': {
    state[0] = 5;
    break;
  }
  default: {
    state[0] = -1;
    break;
  }
  }
  return state[0];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Assign_State>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffff,%r8d
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L9
  movzbl %al,%eax
  lea    D3(%rip),%rdx
  mov    (%rdx,%rax,4),%r8d
L9:
  mov    %r8d,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: 

assistant: ```c
int Assign_State(char *c) {
  int state[3];
  state[0] = state[1] = state[2] = -1;
  switch (c[0]) {
  case 'A': {
    state[0] = 0;
    break;
  }
  case 'R': {
    state[0] = 1;
    break;
  }
  case 'N': {
    state[0] = 2;
    break;
  }
  case 'D': {
    state[0] = 3;
    break;
  }
  case 'C': {
    state[0] = 4;
    break;
  }
  case 'Q': {
    state[0] = 5;
    break;
  }
  case 'E': {
    state[0] = 6;
    break;
  }
  case 'G': {
    state[0] = 7;
    break;
  }
  case 'H': {
    state[0] = 8;
    break;
  }
  case 'I': {
    state[0] = 9;
    break;
  }
  case 'L': {
    state[0] = 10;
    break;
  }
  case 'K': {
    state[0] = 11;
    break;
  }
  case 'M': {
    state[0] = 12;
    break;
  }
  case 'F': {
    state[0] = 13;
    break;
  }
  case 'P': {
    state[0] = 14;
    break;
  }
  case 'S': {
    state[0] = 15;
    break;
  }
  case 'T': {
    state[0] = 16;
    break;
  }
  case 'W': {
    state[0] = 17;
    break;
  }
  case 'Y': {
    state[0] = 18;
    break;
  }
  case 'V': {
    state[0] = 19;
    break;
  }
  case 'B': {
    state[0] = 2;
    break;
  }
  case 'Z': {
    state[0] = 5;
    break;
  }
  default: {
    state[0] = -1;
    break;
  }
  }
  return state[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Assign_State>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffff,%r8d
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L8
  movzbl %al,%eax
  lea    D8(%rip),%rdx
  mov    (%rdx,%rax,4),%r8d
L8:
  mov    %r8d,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: 

assistant: ```c
int Assign_State(char *c) {
  int state[3];
  state[0] = state[1] = state[2] = -1;
  switch (c[0]) {
  case 'A': {
    state[0] = 0;
    break;
  }
  case 'R': {
    state[0] = 1;
    break;
  }
  case 'N': {
    state[0] = 2;
    break;
  }
  case 'D': {
    state[0] = 3;
    break;
  }
  case 'C': {
    state[0] = 4;
    break;
  }
  case 'Q': {
    state[0] = 5;
    break;
  }
  case 'E': {
    state[0] = 6;
    break;
  }
  case 'G': {
    state[0] = 7;
    break;
  }
  case 'H': {
    state[0] = 8;
    break;
  }
  case 'I': {
    state[0] = 9;
    break;
  }
  case 'L': {
    state[0] = 10;
    break;
  }
  case 'K': {
    state[0] = 11;
    break;
  }
  case 'M': {
    state[0] = 12;
    break;
  }
  case 'F': {
    state[0] = 13;
    break;
  }
  case 'P': {
    state[0] = 14;
    break;
  }
  case 'S': {
    state[0] = 15;
    break;
  }
  case 'T': {
    state[0] = 16;
    break;
  }
  case 'W': {
    state[0] = 17;
    break;
  }
  case 'Y': {
    state[0] = 18;
    break;
  }
  case 'V': {
    state[0] = 19;
    break;
  }
  case 'B': {
    state[0] = 2;
    break;
  }
  case 'Z': {
    state[0] = 5;
    break;
  }
  default: {
    state[0] = -1;
    break;
  }
  }
  return state[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movw   $0x6261,-0xf(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0x616263,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <__asan_poison_memory_region@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0xf(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasestr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *r = 0;
  char s1[] = "ab";
  char s2[4] = "cba";
  __asan_poison_memory_region((char *)&s2[2], 2);
  r = strcasestr(s1, s2);
  assert(r == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x6261,0x1(%rsp)
  movb   $0x0,0x3(%rsp)
  movl   $0x616263,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  lea    0x6(%rsp),%rdi
  mov    $0x2,%esi
  call   <__asan_poison_memory_region@plt>
  lea    0x1(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcasestr@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r = 0;
  char s1[] = "ab";
  char s2[4] = "cba";
  __asan_poison_memory_region((char *)&s2[2], 2);
  r = strcasestr(s1, s2);
  assert(r == 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    $0x6261,%eax
  lea    0x4(%rsp),%rbp
  mov    %ax,0x1(%rsp)
  movb   $0x0,0x3(%rsp)
  movl   $0x616263,0x4(%rsp)
  call   <__asan_poison_memory_region@plt>
  lea    0x1(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcasestr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r = 0;
  char s1[] = "ab";
  char s2[4] = "cba";
  __asan_poison_memory_region((char *)&s2[2], 2);
  r = strcasestr(s1, s2);
  assert(r == 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    $0x6261,%eax
  lea    0x4(%rsp),%rbp
  mov    %ax,0x1(%rsp)
  movb   $0x0,0x3(%rsp)
  movl   $0x616263,0x4(%rsp)
  call   <__asan_poison_memory_region@plt>
  lea    0x1(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcasestr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r = 0;
  char s1[] = "ab";
  char s2[4] = "cba";
  __asan_poison_memory_region((char *)&s2[2], 2);
  r = strcasestr(s1, s2);
  assert(r == 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  unsigned u = 2;
  printf("%d %d\n", i, u);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  unsigned u = 2;
  printf("%d %d\n", i, u);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  unsigned u = 2;
  printf("%d %d\n", i, u);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  unsigned u = 2;
  printf("%d %d\n", i, u);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_raw2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L10
  movq   $0x0,-0x10(%rbp)
  jmp    L4
L7:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L7
  mov    -0x10(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L10:
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: 0123456789abcdef

assistant: ```c
int str_raw2hex(char *dst, const unsigned char *src, size_t slen) {
  size_t i;
  const char *hexmap = "0123456789abcdef";
  if (slen) {
    for (i = 0; i < slen; i++) {
      dst[i * 2] = hexmap[src[i] >> 4];
      dst[i * 2 + 1] = hexmap[src[i] & 0x0F];
    }
    dst[i * 2] = '\0';
  }
  return slen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_raw2hex>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  je     L6
  mov    $0x0,%ecx
  lea    D5(%rip),%rdx
L9:
  movzbl (%rsi,%rcx,1),%r8d
  shr    $0x4,%r8b
  movzbl %r8b,%r8d
  movzbl (%rdx,%r8,1),%r8d
  mov    %r8b,(%rdi,%rcx,2)
  movzbl (%rsi,%rcx,1),%r8d
  and    $0xf,%r8d
  movzbl (%rdx,%r8,1),%r8d
  mov    %r8b,0x1(%rdi,%rcx,2)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L9
  movb   $0x0,(%rdi,%rcx,2)
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: 0123456789abcdef

assistant: ```c
int str_raw2hex(char *dst, const unsigned char *src, size_t slen) {
  size_t i;
  const char *hexmap = "0123456789abcdef";
  if (slen) {
    for (i = 0; i < slen; i++) {
      dst[i * 2] = hexmap[src[i] >> 4];
      dst[i * 2 + 1] = hexmap[src[i] & 0x0F];
    }
    dst[i * 2] = '\0';
  }
  return slen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_raw2hex>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  je     L3
  xor    %ecx,%ecx
  lea    D3(%rip),%rdx
  nopl   (%rax)
L13:
  movzbl (%rsi,%rcx,1),%r8d
  shr    $0x4,%r8b
  movzbl %r8b,%r8d
  movzbl (%rdx,%r8,1),%r8d
  mov    %r8b,(%rdi,%rcx,2)
  movzbl (%rsi,%rcx,1),%r8d
  and    $0xf,%r8d
  movzbl (%rdx,%r8,1),%r8d
  mov    %r8b,0x1(%rdi,%rcx,2)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L13
  movb   $0x0,(%rdi,%rax,2)
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: 0123456789abcdef

assistant: ```c
int str_raw2hex(char *dst, const unsigned char *src, size_t slen) {
  size_t i;
  const char *hexmap = "0123456789abcdef";
  if (slen) {
    for (i = 0; i < slen; i++) {
      dst[i * 2] = hexmap[src[i] >> 4];
      dst[i * 2 + 1] = hexmap[src[i] & 0x0F];
    }
    dst[i * 2] = '\0';
  }
  return slen;
}
```