ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cpu_adc_flags>:
  endbr64
  mov    %esi,%r8d
  movzbl %dl,%esi
  xor    %ecx,%esi
  movzbl %r8b,%r8d
  xor    %r8d,%esi
  test   %cl,%cl
  mov    %esi,%eax
  sete   %dl
  add    %esi,%esi
  shr    $0x4,%eax
  shl    $0x7,%edx
  and    $0x20,%esi
  and    $0x10,%eax
  or     %eax,%edx
  or     %esi,%edx
  xor    %esi,%esi
  movzbl %dl,%edx
  jmp    1050 <cpu_set_r8@plt>
```

assistant: ```c
void cpu_adc_flags(struct cpu *cpu, unsigned char a, unsigned char b, unsigned int t) {
  unsigned int carries = t ^ a ^ b;
  unsigned char z = t & 0xFF ? 0 : ((unsigned char)(0x80));
  unsigned char n = 0;
  unsigned char h = carries & 0x10 ? ((unsigned char)(0x20)) : 0;
  unsigned char c = carries & 0x100 ? ((unsigned char)(0x10)) : 0;
  cpu_set_r8(cpu, (0), z | n | h | c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SysCtlUSBPLLDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fb980,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x400fb980,%eax
  mov    $0xa5a5a5a5,%ecx
  mov    %rcx,(%rax)
  mov    $0x400fb820,%eax
  mov    (%rax),%rax
  mov    $0x400fb820,%edx
  and    $0xfffffffffffffff9,%rax
  mov    %rax,(%rdx)
  mov    $0x400fb980,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SysCtlUSBPLLDisable(void) {
  unsigned long ulMWRAllow;
  ulMWRAllow = (*((volatile unsigned long *)(0x400FB980)));
  (*((volatile unsigned long *)(0x400FB980))) = 0xA5A5A5A5;
  (*((volatile unsigned long *)(0x400FB820))) &= ~(0x00000004 | 0x00000002);
  (*((volatile unsigned long *)(0x400FB980))) = ulMWRAllow;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SysCtlUSBPLLDisable>:
  endbr64
  mov    0x400fb980,%rdx
  mov    $0xa5a5a5a5,%eax
  mov    %rax,0x400fb980
  mov    0x400fb820,%rax
  and    $0xfffffffffffffff9,%rax
  mov    %rax,0x400fb820
  mov    %rdx,0x400fb980
  ret
```

assistant: ```c
void SysCtlUSBPLLDisable(void) {
  unsigned long ulMWRAllow;
  ulMWRAllow = (*((volatile unsigned long *)(0x400FB980)));
  (*((volatile unsigned long *)(0x400FB980))) = 0xA5A5A5A5;
  (*((volatile unsigned long *)(0x400FB820))) &= ~(0x00000004 | 0x00000002);
  (*((volatile unsigned long *)(0x400FB980))) = ulMWRAllow;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SysCtlUSBPLLDisable>:
  endbr64
  mov    $0xa5a5a5a5,%eax
  mov    0x400fb980,%rdx
  mov    %rax,0x400fb980
  mov    0x400fb820,%rax
  and    $0xfffffffffffffff9,%rax
  mov    %rax,0x400fb820
  mov    %rdx,0x400fb980
  ret
```

assistant: ```c
void SysCtlUSBPLLDisable(void) {
  unsigned long ulMWRAllow;
  ulMWRAllow = (*((volatile unsigned long *)(0x400FB980)));
  (*((volatile unsigned long *)(0x400FB980))) = 0xA5A5A5A5;
  (*((volatile unsigned long *)(0x400FB820))) &= ~(0x00000004 | 0x00000002);
  (*((volatile unsigned long *)(0x400FB980))) = ulMWRAllow;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SysCtlUSBPLLDisable>:
  endbr64
  mov    $0xa5a5a5a5,%eax
  mov    0x400fb980,%rdx
  mov    %rax,0x400fb980
  mov    0x400fb820,%rax
  and    $0xfffffffffffffff9,%rax
  mov    %rax,0x400fb820
  mov    %rdx,0x400fb980
  ret
```

assistant: ```c
void SysCtlUSBPLLDisable(void) {
  unsigned long ulMWRAllow;
  ulMWRAllow = (*((volatile unsigned long *)(0x400FB980)));
  (*((volatile unsigned long *)(0x400FB980))) = 0xA5A5A5A5;
  (*((volatile unsigned long *)(0x400FB820))) &= ~(0x00000004 | 0x00000002);
  (*((volatile unsigned long *)(0x400FB980))) = ulMWRAllow;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L43:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jne    L79
  movl   $0x1,D4(%rip)
  jmp    L123
L79:
  cmpl   $0x3,-0x4(%rbp)
  jne    L138
  movl   $0x0,D4(%rip)
  jmp    L123
L138:
  cmpl   $0x4,-0x4(%rbp)
  jne    L123
  movl   $0x1,D62(%rip)
  addl   $0x1,-0x8(%rbp)
L123:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L159
  cmpl   $0x5c,-0x4(%rbp)
  jne    L28
  cmpl   $0x0,-0x10(%rbp)
  jne    L28
  movl   $0x1,-0x10(%rbp)
  jmp    L101
L28:
  movl   $0x0,-0x10(%rbp)
  mov    D62(%rip),%eax
  test   %eax,%eax
  jne    L136
  mov    D4(%rip),%eax
  test   %eax,%eax
  jne    L136
  addl   $0x1,-0x8(%rbp)
L136:
  mov    D62(%rip),%eax
  test   %eax,%eax
  je     L101
  cmpl   $0x5d,-0x4(%rbp)
  jne    L101
  movl   $0x0,D62(%rip)
  jmp    L101
L159:
  nop
L101:
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L43
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int string_len(char *buffer) {
  static int anchor_flag = 0;
  static int link_flag = 0;
  int backslash_flag = 0;
  int i;
  int c;
  int len = 0;
  for (i = 0; i < strlen(buffer); i++) {
    c = buffer[i];
    if (c == '\02')
      link_flag = 1;
    else if (c == '\03')
      link_flag = 0;
    else if (c == '\04') {
      anchor_flag = 1;
      len++;
    }
    if (c < 32)
      continue;
    if (c == '\\' && !backslash_flag) {
      backslash_flag = 1;
      continue;
    }
    backslash_flag = 0;
    if (!anchor_flag && !link_flag)
      len++;
    if (anchor_flag && c == ']') {
      anchor_flag = 0;
    }
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_len>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  jmp    L74
L57:
  movl   $0x1,D34(%rip)
L36:
  add    $0x1,%rbx
L74:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L137
  movsbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2,%eax
  je     L57
  cmp    $0x3,%eax
  je     L65
  cmp    $0x4,%eax
  je     L75
  cmp    $0x1f,%eax
  jle    L36
  cmp    $0x5c,%eax
  jne    L35
  test   %r12d,%r12d
  mov    $0x1,%r12d
  je     L36
L35:
  mov    D19(%rip),%r12d
  test   %r12d,%r12d
  jne    L100
  cmpl   $0x1,D34(%rip)
  adc    $0x0,%r13d
  jmp    L36
L65:
  mov    %r14d,D4(%rip)
  jmp    L36
L75:
  movl   $0x1,D19(%rip)
  add    $0x1,%r13d
  jmp    L36
L100:
  mov    %r14d,%r12d
  cmp    $0x5d,%eax
  jne    L36
  mov    %r14d,D4(%rip)
  jmp    L36
L137:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_len(char *buffer) {
  static int anchor_flag = 0;
  static int link_flag = 0;
  int backslash_flag = 0;
  int i;
  int c;
  int len = 0;
  for (i = 0; i < strlen(buffer); i++) {
    c = buffer[i];
    if (c == '\02')
      link_flag = 1;
    else if (c == '\03')
      link_flag = 0;
    else if (c == '\04') {
      anchor_flag = 1;
      len++;
    }
    if (c < 32)
      continue;
    if (c == '\\' && !backslash_flag) {
      backslash_flag = 1;
      continue;
    }
    backslash_flag = 0;
    if (!anchor_flag && !link_flag)
      len++;
    if (anchor_flag && c == ']') {
      anchor_flag = 0;
    }
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_len>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L73
  nopl   0x0(%rax)
L6:
  cmp    $0x3,%eax
  je     L104
  cmp    $0x4,%eax
  je     L70
  cmp    $0x1f,%eax
  jle    L74
  cmp    $0x5c,%eax
  jne    L68
  mov    %r12d,%edx
  mov    $0x1,%r12d
  xor    $0x1,%edx
  and    $0x1,%edx
  jne    L74
L68:
  mov    D20(%rip),%r12d
  test   %r12d,%r12d
  jne    L28
  cmpl   $0x1,D24(%rip)
  adc    $0x0,%r13d
  nopl   0x0(%rax)
L74:
  add    $0x1,%rbx
L73:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L105
  movsbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2,%eax
  jne    L6
  movl   $0x1,D24(%rip)
  jmp    L74
  xchg   %ax,%ax
L28:
  cmp    $0x5d,%eax
  jne    L41
  mov    %r14d,D33(%rip)
L41:
  xor    %r12d,%r12d
  jmp    L74
  nopl   0x0(%rax)
L104:
  mov    %r14d,D33(%rip)
  jmp    L74
  nopl   0x0(%rax)
L70:
  movl   $0x1,D33(%rip)
  add    $0x1,%r13d
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L105:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_len(char *buffer) {
  static int anchor_flag = 0;
  static int link_flag = 0;
  int backslash_flag = 0;
  int i;
  int c;
  int len = 0;
  for (i = 0; i < strlen(buffer); i++) {
    c = buffer[i];
    if (c == '\02')
      link_flag = 1;
    else if (c == '\03')
      link_flag = 0;
    else if (c == '\04') {
      anchor_flag = 1;
      len++;
    }
    if (c < 32)
      continue;
    if (c == '\\' && !backslash_flag) {
      backslash_flag = 1;
      continue;
    }
    backslash_flag = 0;
    if (!anchor_flag && !link_flag)
      len++;
    if (anchor_flag && c == ']') {
      anchor_flag = 0;
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_len>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L31
  nopl   0x0(%rax)
L88:
  cmp    $0x3,%eax
  je     L128
  cmp    $0x4,%eax
  je     L1
  cmp    $0x1f,%eax
  jle    L75
  cmp    $0x5c,%eax
  jne    L81
  mov    %r12d,%edx
  mov    $0x1,%r12d
  xor    $0x1,%edx
  and    $0x1,%edx
  jne    L75
L81:
  mov    D18(%rip),%r12d
  test   %r12d,%r12d
  jne    L123
  cmpl   $0x1,D43(%rip)
  adc    $0x0,%r13d
  nopl   0x0(%rax)
L75:
  add    $0x1,%rbx
L31:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L18
  movsbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2,%eax
  jne    L88
  movl   $0x1,D43(%rip)
  jmp    L75
  xchg   %ax,%ax
L123:
  cmp    $0x5d,%eax
  jne    L125
  mov    %r14d,D17(%rip)
L125:
  xor    %r12d,%r12d
  jmp    L75
  nopl   0x0(%rax)
L128:
  mov    %r14d,D17(%rip)
  jmp    L75
  nopl   0x0(%rax)
L1:
  movl   $0x1,D17(%rip)
  add    $0x1,%r13d
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L18:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_len(char *buffer) {
  static int anchor_flag = 0;
  static int link_flag = 0;
  int backslash_flag = 0;
  int i;
  int c;
  int len = 0;
  for (i = 0; i < strlen(buffer); i++) {
    c = buffer[i];
    if (c == '\02')
      link_flag = 1;
    else if (c == '\03')
      link_flag = 0;
    else if (c == '\04') {
      anchor_flag = 1;
      len++;
    }
    if (c < 32)
      continue;
    if (c == '\\' && !backslash_flag) {
      backslash_flag = 1;
      continue;
    }
    backslash_flag = 0;
    if (!anchor_flag && !link_flag)
      len++;
    if (anchor_flag && c == ']') {
      anchor_flag = 0;
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
L1:
  mov    $0x0,%eax
  call   <baz@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  for (;;) {
    baz();
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L0:
  mov    $0x0,%eax
  call   <baz@plt>
  jmp    L0
```

assistant: ```c
int main(int argc, char **argv) {
  for (;;) {
    baz();
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <baz@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  for (;;) {
    baz();
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <baz@plt>
  jmp    L8
```

assistant: ```c
int main(int argc, char **argv) {
  for (;;) {
    baz();
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Options:
-d: decrypt the given string. If this is not present, defaults to encryptions
-p: four hex digit plaintext/ciphertext to encrypt/decrypt
-k: eight hext digit key to be used in encryption/decryption


assistant: ```c
void usage() {
  printf("Options:\n"
         "-d: decrypt the given string. If this is not present, defaults to encryptions\n"
         "-p: four hex digit plaintext/ciphertext to encrypt/decrypt\n"
         "-k: eight hext digit key to be used in encryption/decryption\n");
  abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: Options:
-d: decrypt the given string. If this is not present, defaults to encryptions
-p: four hex digit plaintext/ciphertext to encrypt/decrypt
-k: eight hext digit key to be used in encryption/decryption


assistant: ```c
void usage() {
  printf("Options:\n"
         "-d: decrypt the given string. If this is not present, defaults to encryptions\n"
         "-p: four hex digit plaintext/ciphertext to encrypt/decrypt\n"
         "-k: eight hext digit key to be used in encryption/decryption\n");
  abort();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D9: Options:
-d: decrypt the given string. If this is not present, defaults to encryptions
-p: four hex digit plaintext/ciphertext to encrypt/decrypt
-k: eight hext digit key to be used in encryption/decryption


assistant: ```c
void usage() {
  printf("Options:\n"
         "-d: decrypt the given string. If this is not present, defaults to encryptions\n"
         "-p: four hex digit plaintext/ciphertext to encrypt/decrypt\n"
         "-k: eight hext digit key to be used in encryption/decryption\n");
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: Options:
-d: decrypt the given string. If this is not present, defaults to encryptions
-p: four hex digit plaintext/ciphertext to encrypt/decrypt
-k: eight hext digit key to be used in encryption/decryption


assistant: ```c
void usage() {
  printf("Options:\n"
         "-d: decrypt the given string. If this is not present, defaults to encryptions\n"
         "-p: four hex digit plaintext/ciphertext to encrypt/decrypt\n"
         "-k: eight hext digit key to be used in encryption/decryption\n");
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strupr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L32:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strupr(char s[]) {
  int c = 0;
  while (s[c] != '\0') {
    if (s[c] >= 'a' && s[c] <= 'z') {
      s[c] = s[c] - 32;
    }
    c++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strupr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
L36:
  ret
L16:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
L0:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L16
  sub    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L16
```

assistant: ```c
void strupr(char s[]) {
  int c = 0;
  while (s[c] != '\0') {
    if (s[c] >= 'a' && s[c] <= 'z') {
      s[c] = s[c] - 32;
    }
    c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strupr>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L23:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L9
  sub    $0x20,%eax
  mov    %al,(%rdi)
L9:
  add    $0x1,%rdi
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
  ret
```

assistant: ```c
void strupr(char s[]) {
  int c = 0;
  while (s[c] != '\0') {
    if (s[c] >= 'a' && s[c] <= 'z') {
      s[c] = s[c] - 32;
    }
    c++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strupr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L0
  sub    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L19
L8:
  ret
```

assistant: ```c
void strupr(char s[]) {
  int c = 0;
  while (s[c] != '\0') {
    if (s[c] >= 'a' && s[c] <= 'z') {
      s[c] = s[c] - 32;
    }
    c++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isdetectedkeyword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %edx,-0x134(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x110(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x114(%rbp)
  jmp    L88
L9:
  subl   $0x1,-0x114(%rbp)
L88:
  mov    -0x114(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L9
  mov    -0x114(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  movl   $0x0,-0x114(%rbp)
  jmp    L73
L54:
  mov    -0x114(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  mov    -0x114(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x90(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand_hierarch_keyword@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L46
  mov    -0x114(%rbp),%eax
  jmp    L86
L5:
  mov    -0x114(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L46
  mov    -0x114(%rbp),%eax
  jmp    L86
L46:
  addl   $0x1,-0x114(%rbp)
L73:
  mov    -0x114(%rbp),%eax
  cmp    -0x134(%rbp),%eax
  jl     L54
  mov    $0xffffffff,%eax
L86:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: =

assistant: ```c
int isdetectedkeyword(char *line, char *keywords[], int nkeys) {
  char kw[128];
  char esokw[128];
  int i;
  strcpy(kw, line);
  strtok(kw, "=");
  i = (int)strlen(kw) - 1;
  while (kw[i] == ' ')
    i--;
  kw[i + 1] = (char)0;
  for (i = 0; i < nkeys; i++) {
    if (strstr(keywords[i], ".") != NULL) {
      expand_hierarch_keyword(keywords[i], esokw);
      if (!strcmp(kw, esokw)) {
        return i;
      }
    } else if (!strcmp(kw, keywords[i])) {
      return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isdetectedkeyword>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0x20,0x10(%rsp,%rcx,1)
  jne    L4
  sub    $0x2,%eax
  cltq
  lea    0x11(%rsp),%rcx
L73:
  mov    %eax,%edx
  sub    $0x1,%rax
  cmpb   $0x20,(%rcx,%rax,1)
  je     L73
L4:
  add    $0x1,%edx
  movslq %edx,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  test   %r13d,%r13d
  jle    L53
  mov    %r13d,%r13d
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r15
  jmp    L46
L21:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L13
L83:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L40
L46:
  mov    %ebx,0xc(%rsp)
  mov    (%r14,%rbx,8),%rbp
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  lea    0x90(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <expand_hierarch_keyword@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L83
  jmp    L13
L40:
  movl   $0xffffffff,0xc(%rsp)
L13:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  mov    0xc(%rsp),%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L13
L93:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D9: =

assistant: ```c
int isdetectedkeyword(char *line, char *keywords[], int nkeys) {
  char kw[128];
  char esokw[128];
  int i;
  strcpy(kw, line);
  strtok(kw, "=");
  i = (int)strlen(kw) - 1;
  while (kw[i] == ' ')
    i--;
  kw[i + 1] = (char)0;
  for (i = 0; i < nkeys; i++) {
    if (strstr(keywords[i], ".") != NULL) {
      expand_hierarch_keyword(keywords[i], esokw);
      if (!strcmp(kw, esokw)) {
        return i;
      }
    } else if (!strcmp(kw, keywords[i])) {
      return i;
    }
  }
  return -1;
}
```