ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  je     L44
  mov    %ebp,%eax
  mov    %ebp,%r12d
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    %eax,%ebp
  mov    %r13,%rsi
  mov    %r14,%rdi
  cmovl  %eax,%ebp
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  add    %eax,%r15d
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L26
  pxor   %xmm0,%xmm0
  test   %r15d,%r15d
  je     L30
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r15d,%xmm0
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
L30:
  mov    %r15d,%ecx
  mov    %r12d,%edx
  lea    D5(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  xor    %r12d,%r12d
  xor    %r15d,%r15d
  pxor   %xmm0,%xmm0
  jmp    L30
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string

tool: D4: Digite uma sequencia de numeros: 

tool: D16: %d

tool: D5: 
 Maior: %d
 Menor: %d
 Soma: %d
 Media: %.2f

assistant: ```c
main() {
  int soma = 0, maior = 0, menor = 0, numero, count = 0;
  float media = 0;
  int flag = 1;
  puts("Digite uma sequencia de numeros: ");
  scanf("%d", &numero);
  while (numero != 0) {
    maior = flag ? numero : maior;
    menor = flag ? numero : menor;
    maior = numero > maior ? numero : maior;
    menor = numero < menor ? numero : menor;
    soma += numero;
    count++;
    flag = 0;
    scanf("%d", &numero);
  }
  media = soma == 0 ? 0 : (float)soma / count;
  printf("\n Maior: %d\n Menor: %d\n Soma: %d\n Media: %.2f", maior, menor, soma, media);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  lea    D7(%rip),%rdi
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  je     L43
  mov    %ebp,%eax
  mov    %ebp,%r12d
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L28:
  cmp    %eax,%ebp
  mov    %r13,%rsi
  mov    %r14,%rdi
  cmovl  %eax,%ebp
  cmp    %eax,%r12d
  cmovg  %eax,%r12d
  add    %eax,%r15d
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L28
  pxor   %xmm0,%xmm0
  test   %r15d,%r15d
  je     L15
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r15d,%xmm0
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
L15:
  mov    %r15d,%ecx
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  xor    %r12d,%r12d
  xor    %r15d,%r15d
  pxor   %xmm0,%xmm0
  jmp    L15
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D9
type: string

tool: D7: Digite uma sequencia de numeros: 

tool: D12: %d

tool: D9: 
 Maior: %d
 Menor: %d
 Soma: %d
 Media: %.2f

assistant: ```c
main() {
  int soma = 0, maior = 0, menor = 0, numero, count = 0;
  float media = 0;
  int flag = 1;
  puts("Digite uma sequencia de numeros: ");
  scanf("%d", &numero);
  while (numero != 0) {
    maior = flag ? numero : maior;
    menor = flag ? numero : menor;
    maior = numero > maior ? numero : maior;
    menor = numero < menor ? numero : menor;
    soma += numero;
    count++;
    flag = 0;
    scanf("%d", &numero);
  }
  media = soma == 0 ? 0 : (float)soma / count;
  printf("\n Maior: %d\n Menor: %d\n Soma: %d\n Media: %.2f", maior, menor, soma, media);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x60(%rbp)
  jmp    L71
L28:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L6
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%edx
  mov    -0x5c(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x5c(%rbp)
L6:
  addl   $0x1,-0x60(%rbp)
L71:
  cmpl   $0x1d,-0x60(%rbp)
  jle    L28
  movl   $0x0,-0x60(%rbp)
  jmp    L27
L73:
  addl   $0x1,-0x58(%rbp)
  addl   $0x1,-0x60(%rbp)
L27:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L73
  movl   $0x0,-0x60(%rbp)
  jmp    L34
L3:
  addl   $0x1,-0x54(%rbp)
  addl   $0x1,-0x60(%rbp)
L34:
  mov    -0x60(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L3
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x58(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string

tool: D15: entre com uma frase: 

tool: D1: tamanho da string ENT: %d


tool: D16: tamanho da string SAI: %d


assistant: ```c
int main() {
  int i, j = 0, cont = 0, cont2 = 0;
  char ent[30], sai[30];
  printf("entre com uma frase: \n");
  gets(ent);
  for (i = 0; i < 30; i++) {
    if (ent[i] != 32) {
      sai[j] = ent[i];
      j++;
    }
  }
  for (i = 0; ent[i] != '\0'; i++)
    cont++;
  for (i = 0; sai[i] != '\0'; i++)
    cont2++;
  printf("%s\n", sai);
  printf("tamanho da string ENT: %d\n", cont);
  printf("tamanho da string SAI: %d\n", cont2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rax
  lea    0x1e(%rsp),%rdi
  mov    $0x0,%ecx
  jmp    L70
L15:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L83
L70:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L15
  movslq %ecx,%rsi
  mov    %dl,0x20(%rsp,%rsi,1)
  add    $0x1,%ecx
  jmp    L15
L83:
  cmpb   $0x0,(%rsp)
  je     L109
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
L28:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L28
L103:
  cmpb   $0x0,0x20(%rsp)
  je     L106
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rdx
L101:
  mov    %eax,%ebx
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L101
L53:
  lea    0x20(%rsp),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L109:
  mov    $0x0,%ebp
  jmp    L103
L106:
  mov    $0x0,%ebx
  jmp    L53
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D23: entre com uma frase: 

tool: D4: tamanho da string ENT: %d


tool: D16: tamanho da string SAI: %d


assistant: ```c
int main() {
  int i, j = 0, cont = 0, cont2 = 0;
  char ent[30], sai[30];
  printf("entre com uma frase: \n");
  gets(ent);
  for (i = 0; i < 30; i++) {
    if (ent[i] != 32) {
      sai[j] = ent[i];
      j++;
    }
  }
  for (i = 0; ent[i] != '\0'; i++)
    cont++;
  for (i = 0; sai[i] != '\0'; i++)
    cont2++;
  printf("%s\n", sai);
  printf("tamanho da string ENT: %d\n", cont);
  printf("tamanho da string SAI: %d\n", cont2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rax
  lea    0x1e(%rsp),%rdi
  xor    %ecx,%ecx
  nopl   (%rax)
L21:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L2
  movslq %ecx,%rsi
  add    $0x1,%ecx
  mov    %dl,0x20(%rsp,%rsi,1)
L2:
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L21
  cmpb   $0x0,(%rsp)
  je     L11
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
  nop
L49:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L49
L32:
  cmpb   $0x0,0x20(%rsp)
  je     L59
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rdx
  xchg   %ax,%ax
L66:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L66
L44:
  lea    0x20(%rsp),%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  xor    %r12d,%r12d
  jmp    L32
L59:
  xor    %ebp,%ebp
  jmp    L44
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D28
type_infered: string

tool: D3: entre com uma frase: 

tool: D1: tamanho da string ENT: %d


tool: D28: tamanho da string SAI: %d


assistant: ```c
int main() {
  int i, j = 0, cont = 0, cont2 = 0;
  char ent[30], sai[30];
  printf("entre com uma frase: \n");
  gets(ent);
  for (i = 0; i < 30; i++) {
    if (ent[i] != 32) {
      sai[j] = ent[i];
      j++;
    }
  }
  for (i = 0; ent[i] != '\0'; i++)
    cont++;
  for (i = 0; sai[i] != '\0'; i++)
    cont2++;
  printf("%s\n", sai);
  printf("tamanho da string ENT: %d\n", cont);
  printf("tamanho da string SAI: %d\n", cont2);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rax
  lea    0x1e(%rsp),%rdi
  xor    %ecx,%ecx
  nopl   (%rax)
L4:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L11
  movslq %ecx,%rsi
  add    $0x1,%ecx
  mov    %dl,0x20(%rsp,%rsi,1)
L11:
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L4
  cmpb   $0x0,(%rsp)
  je     L48
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
  nop
L54:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L54
L33:
  cmpb   $0x0,0x20(%rsp)
  je     L62
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rdx
  xchg   %ax,%ax
L87:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L87
L55:
  lea    0x20(%rsp),%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  xor    %r12d,%r12d
  jmp    L33
L62:
  xor    %ebp,%ebp
  jmp    L55
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D27: entre com uma frase: 

tool: D15: tamanho da string ENT: %d


tool: D16: tamanho da string SAI: %d


assistant: ```c
int main() {
  int i, j = 0, cont = 0, cont2 = 0;
  char ent[30], sai[30];
  printf("entre com uma frase: \n");
  gets(ent);
  for (i = 0; i < 30; i++) {
    if (ent[i] != 32) {
      sai[j] = ent[i];
      j++;
    }
  }
  for (i = 0; ent[i] != '\0'; i++)
    cont++;
  for (i = 0; sai[i] != '\0'; i++)
    cont2++;
  printf("%s\n", sai);
  printf("tamanho da string ENT: %d\n", cont);
  printf("tamanho da string SAI: %d\n", cont2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L23:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L23
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string

tool: D18: %d %d %d %d

tool: D4: %d %d %d 

assistant: ```c
int main() {
  int rot, a, b, c, i = 0;
  scanf("%d %d %d %d", &a, &b, &c, &rot);
  for (i = 0; i < rot; i++)
    rotr(&a, &b, &c);
  printf("%d %d %d ", a, b, c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%r8
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L15
  mov    $0x0,%ebx
  lea    0x14(%rsp),%rbp
L27:
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L27
L15:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D13: %d %d %d %d

tool: D0: %d %d %d 

assistant: ```c
int main() {
  int rot, a, b, c, i = 0;
  scanf("%d %d %d %d", &a, &b, &c, &rot);
  for (i = 0; i < rot; i++)
    rotr(&a, &b, &c);
  printf("%d %d %d ", a, b, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L18
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L12
L18:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D12(%rip),%rdi
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D19: %d %d %d %d

tool: D12: %d %d %d 

assistant: ```c
int main() {
  int rot, a, b, c, i = 0;
  scanf("%d %d %d %d", &a, &b, &c, &rot);
  for (i = 0; i < rot; i++)
    rotr(&a, &b, &c);
  printf("%d %d %d ", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L26:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L26
L0:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D3(%rip),%rdi
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D12: %d %d %d %d

tool: D3: %d %d %d 

assistant: ```c
int main() {
  int rot, a, b, c, i = 0;
  scanf("%d %d %d %d", &a, &b, &c, &rot);
  for (i = 0; i < rot; i++)
    rotr(&a, &b, &c);
  printf("%d %d %d ", a, b, c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ParseLatency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L33
  mov    -0x38(%rbp),%rax
  mov    %rax,%rcx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <kapi_Error_pch1@plt>
  jmp    L35
L33:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  je     L68
  cmpq   $0x0,-0x20(%rbp)
  je     L56
  mov    -0x20(%rbp),%rax
  jmp    L28
L56:
  lea    D28(%rip),%rax
L28:
  mov    %rax,%rcx
  lea    D10(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <kapi_Error_pch1@plt>
  jmp    L35
L68:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x50(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    -0x40(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L35
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    -0x48(%rbp),%rdx
  mov    %rax,(%rdx)
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D28
type: string
name: read_data
arguments: tag: D10
type: string
name: read_data
arguments: tag: D19
type: string

tool: D4: Malformed latency attribute '%s' -- '=' required

tool: D15: 0123456789-

tool: D28: Null

tool: D10: Badly formed bypass:  latency value '%s' not valid

tool: D19:  /

assistant: ```c
void ParseLatency(char *pch, char **ppchFcSrc, char **ppchOppSrc, int *piLatency) {
  char *pchSrc, *pchVal, *pchLatency;
  pchVal = (char *)strchr(pch, '=');
  if (pchVal == NULL) {
    kapi_Error_pch1(-1, 0, "Malformed latency attribute '%s' -- '=' required", pch);
    return;
  }
  *pchVal = '\0';
  pchLatency = pchVal + 1;
  if (strspn(pchLatency, "0123456789-") != strlen(pchLatency)) {
    kapi_Error_pch1(-1, 0, "Badly formed bypass:  latency value '%s' not valid", ((pchLatency) ? (pchLatency) : "Null"));
    return;
  }
  *piLatency = atoi(pchLatency);
  pchSrc = pch;
  *ppchFcSrc = NULL;
  *ppchOppSrc = NULL;
  *ppchFcSrc = strtok(pchSrc, " /");
  if (*ppchFcSrc) {
    *ppchOppSrc = strtok(NULL, " /");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ParseLatency>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    $0x3d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbx
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  mov    %rax,%r15
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %rax,%r15
  je     L22
  mov    %rbx,%rcx
  lea    D11(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <kapi_Error_pch1@plt>
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    %rbp,%rcx
  lea    D14(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <kapi_Error_pch1@plt>
  jmp    L41
L22:
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,(%r14)
  movq   $0x0,(%r12)
  movq   $0x0,0x0(%r13)
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L41
  lea    D45(%rip),%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,0x0(%r13)
  jmp    L41
```

tool_calls: name: read_data
arguments: label: D37
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D45
type_guessed: string

tool: D37: 0123456789-

tool: D11: Badly formed bypass:  latency value '%s' not valid

tool: D14: Malformed latency attribute '%s' -- '=' required

tool: D45:  /

assistant: ```c
void ParseLatency(char *pch, char **ppchFcSrc, char **ppchOppSrc, int *piLatency) {
  char *pchSrc, *pchVal, *pchLatency;
  pchVal = (char *)strchr(pch, '=');
  if (pchVal == NULL) {
    kapi_Error_pch1(-1, 0, "Malformed latency attribute '%s' -- '=' required", pch);
    return;
  }
  *pchVal = '\0';
  pchLatency = pchVal + 1;
  if (strspn(pchLatency, "0123456789-") != strlen(pchLatency)) {
    kapi_Error_pch1(-1, 0, "Badly formed bypass:  latency value '%s' not valid", ((pchLatency) ? (pchLatency) : "Null"));
    return;
  }
  *piLatency = atoi(pchLatency);
  pchSrc = pch;
  *ppchFcSrc = NULL;
  *ppchOppSrc = NULL;
  *ppchFcSrc = strtok(pchSrc, " /");
  if (*ppchFcSrc) {
    *ppchOppSrc = strtok(NULL, " /");
  }
}
```