ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x14(%rsp),%edi
  test   %ecx,%ecx
  jle    L49
  pxor   %xmm2,%xmm2
  movsd  D18(%rip),%xmm4
  mov    %edi,%edx
  xor    %esi,%esi
  cvtsi2ssl 0x10(%rsp),%xmm2
  xor    %r8d,%r8d
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    %eax,%edx
  jne    L51
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm4,%xmm1
  add    %edi,%edx
  mov    $0x1,%r8d
  cvtsd2ss %xmm1,%xmm1
L51:
  movaps %xmm2,%xmm3
  movaps %xmm2,%xmm0
  add    $0x1,%eax
  mulss  %xmm1,%xmm3
  subss  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  cvtsi2ss %esi,%xmm3
  addss  %xmm3,%xmm0
  cvttss2si %xmm0,%esi
  cmp    %ecx,%eax
  jne    L14
  test   %r8b,%r8b
  je     L37
  mov    %edx,0x14(%rsp)
L37:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L49:
  xor    %esi,%esi
  jmp    L37
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: f64
name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D7: %d

tool: D18: 0.02

tool: D8: %d 


assistant: ```c
int main() {
  int n, m, k, k1, i, cost = 0;
  float t = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  k1 = k;
  for (i = 0; i < n; i++) {
    if (i == k) {
      t += 0.02;
      k += k1;
    }
    cost += m - m * t;
  }
  printf("%d \n", cost);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x14(%rsp),%edi
  test   %ecx,%ecx
  jle    L84
  pxor   %xmm2,%xmm2
  movsd  D25(%rip),%xmm4
  mov    %edi,%edx
  xor    %esi,%esi
  cvtsi2ssl 0x10(%rsp),%xmm2
  xor    %r8d,%r8d
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L43:
  cmp    %eax,%edx
  je     L86
  movaps %xmm2,%xmm3
  movaps %xmm2,%xmm1
  add    $0x1,%eax
  mulss  %xmm0,%xmm3
  subss  %xmm3,%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2ss %esi,%xmm3
  addss  %xmm3,%xmm1
  cvttss2si %xmm1,%esi
  cmp    %ecx,%eax
  jne    L43
  test   %r8b,%r8b
  jne    L22
L62:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L22:
  mov    %edx,0x14(%rsp)
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L86:
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm4,%xmm0
  movaps %xmm2,%xmm3
  movaps %xmm2,%xmm1
  add    $0x1,%eax
  add    %edi,%edx
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm3
  subss  %xmm3,%xmm1
  pxor   %xmm3,%xmm3
  cvtsi2ss %esi,%xmm3
  addss  %xmm3,%xmm1
  cvttss2si %xmm1,%esi
  cmp    %eax,%ecx
  je     L22
  mov    $0x1,%r8d
  jmp    L43
L84:
  xor    %esi,%esi
  jmp    L62
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D27
data_type: string
name: read_data
arguments: data_tag: D25
data_type: f64
name: read_data
arguments: data_tag: D12
data_type: string

tool: D27: %d

tool: D25: 0.02

tool: D12: %d 


assistant: ```c
int main() {
  int n, m, k, k1, i, cost = 0;
  float t = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  k1 = k;
  for (i = 0; i < n; i++) {
    if (i == k) {
      t += 0.02;
      k += k1;
    }
    cost += m - m * t;
  }
  printf("%d \n", cost);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wideness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L51
  mov    $0x0,%eax
  jmp    L18
L37:
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <advance_over@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L11
  mov    -0x10(%rbp),%rax
  sub    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x28(%rbp)
L51:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  jmp    L12
L11:
  nop
L12:
  mov    -0x18(%rbp),%rax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
size_t wideness(const char *text, size_t maxlen) {
  size_t width = 0;
  if (maxlen == 0)
    return 0;
  while (*text != '\0') {
    size_t charlen = advance_over(text, &width);
    if (maxlen <= charlen)
      break;
    maxlen -= charlen;
    text += charlen;
  }
  return width;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wideness>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L46
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  je     L37
  mov    %rsp,%r12
L24:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <advance_over@plt>
  cmp    %rbp,%rax
  jae    L37
  sub    %rax,%rbp
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L24
L37:
  mov    (%rsp),%rax
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wideness(const char *text, size_t maxlen) {
  size_t width = 0;
  if (maxlen == 0)
    return 0;
  while (*text != '\0') {
    size_t charlen = advance_over(text, &width);
    if (maxlen <= charlen)
      break;
    maxlen -= charlen;
    text += charlen;
  }
  return width;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wideness>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rsi,%rsi
  je     L38
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L38
  mov    %rsi,%rbp
  mov    %rsp,%r12
  jmp    L13
  nopl   0x0(%rax)
L33:
  add    %rax,%rbx
  sub    %rax,%rbp
  cmpb   $0x0,(%rbx)
  je     L20
L13:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <advance_over@plt>
  cmp    %rbp,%rax
  jb     L33
L20:
  mov    (%rsp),%rax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wideness(const char *text, size_t maxlen) {
  size_t width = 0;
  if (maxlen == 0)
    return 0;
  while (*text != '\0') {
    size_t charlen = advance_over(text, &width);
    if (maxlen <= charlen)
      break;
    maxlen -= charlen;
    text += charlen;
  }
  return width;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wideness>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %rsi,%rsi
  je     L3
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L3
  mov    %rsi,%rbp
  mov    %rsp,%r12
  jmp    L37
  nopl   0x0(%rax)
L15:
  add    %rax,%rbx
  sub    %rax,%rbp
  cmpb   $0x0,(%rbx)
  je     L28
L37:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <advance_over@plt>
  cmp    %rbp,%rax
  jb     L15
L28:
  mov    (%rsp),%rax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t wideness(const char *text, size_t maxlen) {
  size_t width = 0;
  if (maxlen == 0)
    return 0;
  while (*text != '\0') {
    size_t charlen = advance_over(text, &width);
    if (maxlen <= charlen)
      break;
    maxlen -= charlen;
    text += charlen;
  }
  return width;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xdr_uint16_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L0
  cmp    $0x82,%eax
  jg     L97
  cmp    $0x80,%eax
  je     L57
  cmp    $0x81,%eax
  jne    L97
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_PUTINT32@plt>
  jmp    L85
L0:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_GETINT32@plt>
  test   %eax,%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L85
L5:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L85
L57:
  mov    $0x1,%eax
  jmp    L85
L97:
  mov    $0x0,%eax
L85:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

assistant: ```c
int xdr_uint16_t(XDR *xdrs, uint16_t *uip) {
  uint32_t ut;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    ut = (uint32_t)*uip;
    return XDR_PUTINT32(xdrs, (int32_t *)&ut);
  case XDR_DECODE:
    if (!XDR_GETINT32(xdrs, (int32_t *)&ut))
      return 0;
    *uip = (uint16_t)ut;
    return 1;
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdr_uint16_t>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L57
  cmp    $0x82,%eax
  je     L58
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L57:
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <XDR_PUTINT32@plt>
  jmp    L34
L58:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETINT32@plt>
  test   %eax,%eax
  je     L34
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L34
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xdr_uint16_t(XDR *xdrs, uint16_t *uip) {
  uint32_t ut;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    ut = (uint32_t)*uip;
    return XDR_PUTINT32(xdrs, (int32_t *)&ut);
  case XDR_DECODE:
    if (!XDR_GETINT32(xdrs, (int32_t *)&ut))
      return 0;
    *uip = (uint16_t)ut;
    return 1;
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xdr_uint16_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L18
  cmp    $0x82,%eax
  je     L15
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L52:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <XDR_PUTINT32@plt>
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L15:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETINT32@plt>
  test   %eax,%eax
  je     L52
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L52
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xdr_uint16_t(XDR *xdrs, uint16_t *uip) {
  uint32_t ut;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    ut = (uint32_t)*uip;
    return XDR_PUTINT32(xdrs, (int32_t *)&ut);
  case XDR_DECODE:
    if (!XDR_GETINT32(xdrs, (int32_t *)&ut))
      return 0;
    *uip = (uint16_t)ut;
    return 1;
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdr_uint16_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L1
  cmp    $0x82,%eax
  je     L35
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <XDR_PUTINT32@plt>
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L35:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETINT32@plt>
  test   %eax,%eax
  je     L32
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L32
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xdr_uint16_t(XDR *xdrs, uint16_t *uip) {
  uint32_t ut;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    ut = (uint32_t)*uip;
    return XDR_PUTINT32(xdrs, (int32_t *)&ut);
  case XDR_DECODE:
    if (!XDR_GETINT32(xdrs, (int32_t *)&ut))
      return 0;
    *uip = (uint16_t)ut;
    return 1;
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <beep@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <bodymsg@plt>
  mov    $0x0,%eax
  call   <beep@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Two beeps! 

assistant: ```c
void func2(void) {
  beep();
  bodymsg("Two beeps! ");
  beep();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <beep@plt>
  lea    D3(%rip),%rdi
  call   <bodymsg@plt>
  mov    $0x0,%eax
  call   <beep@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: Two beeps! 

assistant: ```c
void func2(void) {
  beep();
  bodymsg("Two beeps! ");
  beep();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <beep@plt>
  lea    D5(%rip),%rdi
  call   <bodymsg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <beep@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: Two beeps! 

assistant: ```c
void func2(void) {
  beep();
  bodymsg("Two beeps! ");
  beep();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <beep@plt>
  lea    D5(%rip),%rdi
  call   <bodymsg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <beep@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: Two beeps! 

assistant: ```c
void func2(void) {
  beep();
  bodymsg("Two beeps! ");
  beep();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3,%edi
  call   <factorial@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(void) {
  int result = factorial(3);
  printf("%d\n", result);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main(void) {
  int result = factorial(3);
  printf("%d\n", result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <factorial@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main(void) {
  int result = factorial(3);
  printf("%d\n", result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <factorial@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main(void) {
  int result = factorial(3);
  printf("%d\n", result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matchInstanceName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L117
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
L117:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L84
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
L84:
  mov    $0x1,%eax
  jmp    L57
L78:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L111
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L111
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L111
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L111
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L81
L111:
  mov    $0x0,%eax
  jmp    L57
L81:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L46
L57:
  pop    %rbp
  ret
```

assistant: ```c
int matchInstanceName(char *p, char *q) {
  for (;; p++, q++) {
    if ((*p == ' ' || *p == '\0') && (*q == ' ' || *q == '\0'))
      return 1;
    if (*p != *q || *p == ' ' || *p == '\0' || *q == ' ' || *q == '\0')
      return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matchInstanceName>:
  endbr64
  jmp    L17
L5:
  movzbl (%rsi),%edx
  test   $0xdf,%dl
  sete   %cl
  or     %r8b,%cl
  jne    L36
  cmp    %al,%dl
  jne    L36
  add    $0x1,%rdi
  add    $0x1,%rsi
L17:
  movzbl (%rdi),%eax
  test   $0xdf,%al
  sete   %r8b
  jne    L5
  testb  $0xdf,(%rsi)
  sete   %al
  movzbl %al,%eax
  ret
L36:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int matchInstanceName(char *p, char *q) {
  for (;; p++, q++) {
    if ((*p == ' ' || *p == '\0') && (*q == ' ' || *q == '\0'))
      return 1;
    if (*p != *q || *p == ' ' || *p == '\0' || *q == ' ' || *q == '\0')
      return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<matchInstanceName>:
  endbr64
  xor    %eax,%eax
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    %dl,%cl
  jne    L31
L36:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   $0xdf,%cl
  mov    %ecx,%r9d
  sete   %r8b
  test   $0xdf,%dl
  sete   %r10b
  or     %edx,%r9d
  and    $0xdf,%r9d
  je     L29
  add    $0x1,%rax
  or     %r10b,%r8b
  je     L16
L31:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int matchInstanceName(char *p, char *q) {
  for (;; p++, q++) {
    if ((*p == ' ' || *p == '\0') && (*q == ' ' || *q == '\0'))
      return 1;
    if (*p != *q || *p == ' ' || *p == '\0' || *q == ' ' || *q == '\0')
      return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matchInstanceName>:
  endbr64
  xor    %eax,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L21:
  cmp    %dl,%cl
  jne    L16
L7:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   $0xdf,%cl
  mov    %ecx,%r9d
  sete   %r8b
  test   $0xdf,%dl
  sete   %r10b
  or     %edx,%r9d
  and    $0xdf,%r9d
  je     L15
  add    $0x1,%rax
  or     %r10b,%r8b
  je     L21
L16:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int matchInstanceName(char *p, char *q) {
  for (;; p++, q++) {
    if ((*p == ' ' || *p == '\0') && (*q == ' ' || *q == '\0'))
      return 1;
    if (*p != *q || *p == ' ' || *p == '\0' || *q == ' ' || *q == '\0')
      return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compCorr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %r9d,%eax
  sub    0x30(%rsp),%eax
  mov    %r9d,%edx
  sub    %r8d,%edx
  cmp    %r8d,%eax
  cmovge 0x30(%rsp),%edx
  test   %edx,%edx
  jle    L39
  movslq %r9d,%r9
  movslq %edx,%rax
  sub    %rax,%r9
  lea    (%rcx,%r9,4),%rax
  lea    -0x1(%rdx),%edx
  add    %r9,%rdx
  lea    0x4(%rcx,%rdx,4),%rcx
  movslq %r8d,%r8
  neg    %r8
  lea    0x0(,%r8,4),%rdx
  pxor   %xmm6,%xmm6
  movss  %xmm6,0xc(%rsp)
  movss  %xmm6,0x4(%rsp)
  movss  %xmm6,0x8(%rsp)
L25:
  movss  (%rax),%xmm0
  movss  (%rax,%rdx,1),%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm1,%xmm2
  addss  0x8(%rsp),%xmm2
  movss  %xmm2,0x8(%rsp)
  mulss  %xmm1,%xmm1
  addss  0x4(%rsp),%xmm1
  movss  %xmm1,0x4(%rsp)
  mulss  %xmm0,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L25
  comiss D9(%rip),%xmm1
  ja     L4
L39:
  movl   $0x0,(%rdi)
  movl   $0x0,0x0(%rbp)
  pxor   %xmm0,%xmm0
L23:
  movss  %xmm0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  movaps %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movaps %xmm2,%xmm3
  divss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x8(%rsp),%xmm0
  call   <fabs@plt>
  mov    %rax,%r12
  movss  0x4(%rsp),%xmm0
  call   <sqrt@plt>
  mov    %rax,%rbp
  movss  0xc(%rsp),%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbp,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %rax,%xmm2
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: f32

tool: D9: 0

assistant: ```c
void compCorr(float *cc, float *gc, float *pm, float *buffer, int lag, int bLen, int sRange) {
  int i;
  float ftmp1, ftmp2, ftmp3;
  if ((bLen - sRange - lag) < 0) {
    sRange = bLen - lag;
  }
  ftmp1 = 0.0;
  ftmp2 = 0.0;
  ftmp3 = 0.0;
  for (i = 0; i < sRange; i++) {
    ftmp1 += buffer[bLen - sRange + i] * buffer[bLen - sRange + i - lag];
    ftmp2 += buffer[bLen - sRange + i - lag] * buffer[bLen - sRange + i - lag];
    ftmp3 += buffer[bLen - sRange + i] * buffer[bLen - sRange + i];
  }
  if (ftmp2 > 0.0) {
    *cc = ftmp1 * ftmp1 / ftmp2;
    *gc = (float)fabs(ftmp1 / ftmp2);
    *pm = (float)fabs(ftmp1) / ((float)sqrt(ftmp2) * (float)sqrt(ftmp3));
  } else {
    *cc = 0.0;
    *gc = 0.0;
    *pm = 0.0;
  }
}
```