ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<display_anagrams>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L5
L14:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <faire_combi@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void display_anagrams(char *s1) {
  int len = length(s1);
  char *tmp = calloc(len + 1, sizeof(char));
  char *util = calloc(len + 1, sizeof(char));
  int i;
  for (i = 0; i < len; i++)
    util[i] = s1[i];
  faire_combi(util, tmp, len, 0);
  free(tmp);
  free(util);
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_anagrams>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <length@plt>
  mov    %eax,%r12d
  lea    0x1(%rax),%ebx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  jle    L8
  mov    %r12d,%ecx
  mov    $0x0,%eax
L6:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L8:
  mov    $0x0,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <faire_combi@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void display_anagrams(char *s1) {
  int len = length(s1);
  char *tmp = calloc(len + 1, sizeof(char));
  char *util = calloc(len + 1, sizeof(char));
  int i;
  for (i = 0; i < len; i++)
    util[i] = s1[i];
  faire_combi(util, tmp, len, 0);
  free(tmp);
  free(util);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<display_anagrams>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <length@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%ebp
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %ebp,%edi
  mov    $0x1,%esi
  mov    %rax,%r13
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L10
  movslq %r12d,%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L9:
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L9
L10:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  call   <faire_combi@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
```

assistant: ```c
void display_anagrams(char *s1) {
  int len = length(s1);
  char *tmp = calloc(len + 1, sizeof(char));
  char *util = calloc(len + 1, sizeof(char));
  int i;
  for (i = 0; i < len; i++)
    util[i] = s1[i];
  faire_combi(util, tmp, len, 0);
  free(tmp);
  free(util);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<display_anagrams>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <length@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%ebp
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %ebp,%edi
  mov    $0x1,%esi
  mov    %rax,%r13
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L165
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdx
  lea    -0x1(%r12),%eax
  mov    %r12d,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L65
  cmp    $0x6,%eax
  jbe    L65
  cmp    $0xe,%eax
  jbe    L137
  mov    %r12d,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopl   (%rax)
L96:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,0x0(%rbp,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L96
  mov    %r12d,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%r12d
  je     L165
  mov    %r12d,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L48
L102:
  mov    (%rbx,%rdx,1),%rsi
  mov    %rsi,0x0(%rbp,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L165
L48:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L165
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%r12d
  jle    L165
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%r12d
  jle    L165
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%r12d
  jle    L165
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%r12d
  jle    L165
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  cmp    %eax,%r12d
  jle    L165
  cltq
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
L165:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %ecx,%ecx
  call   <faire_combi@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %r12d,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L154:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L154
  jmp    L165
L137:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L102
```

assistant: ```c
void display_anagrams(char *s1) {
  int len = length(s1);
  char *tmp = calloc(len + 1, sizeof(char));
  char *util = calloc(len + 1, sizeof(char));
  int i;
  for (i = 0; i < len; i++)
    util[i] = s1[i];
  faire_combi(util, tmp, len, 0);
  free(tmp);
  free(util);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<modf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   D5(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd D11(%rip),%xmm0
  jb     L3
  mov    -0x10(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  jmp    L2
L3:
  movsd  -0x8(%rbp),%xmm0
  movq   D5(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L8
  mov    -0x10(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm0
  jmp    L2
L8:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
L2:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: qword
name: disassemble_data
arguments: tag: D11
data_type: f64[2]
name: disassemble_data
arguments: tag: D0
data_type: f64

tool: D5: 9223372036854775807

tool: {"D11": [4503599627370496.0,1.0]}

tool: D0: 1

assistant: ```c
double modf(double x, double *iptr) {
  if (fabs(x) >= 4503599627370496.0) {
    *iptr = x;
    return 0.0;
  } else if (fabs(x) < 1.0) {
    *iptr = 0.0;
    return x;
  } else {
    *iptr = (double)(int64_t)x;
    return (x - *iptr);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modf>:
  endbr64
  movapd %xmm0,%xmm1
  andpd  D18(%rip),%xmm1
  comisd D22(%rip),%xmm1
  jae    L8
  movsd  D29(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L37
  cvttsd2si %xmm0,%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
L10:
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
L8:
  pxor   %xmm1,%xmm1
  jmp    L10
L37:
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  jmp    L10
```

tool_calls: name: read_data
arguments: data_label: D18
datatype: qword[2]
name: read_data
arguments: data_label: D22
datatype: f64[2]
name: read_data
arguments: data_label: D29
datatype: f64

tool: {"D18": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D22": [4503599627370496.0,1.0]}

tool: D29: 1

assistant: ```c
double modf(double x, double *iptr) {
  if (fabs(x) >= 4503599627370496.0) {
    *iptr = x;
    return 0.0;
  } else if (fabs(x) < 1.0) {
    *iptr = 0.0;
    return x;
  } else {
    *iptr = (double)(int64_t)x;
    return (x - *iptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<modf>:
  endbr64
  movapd %xmm0,%xmm1
  andpd  D18(%rip),%xmm1
  comisd D8(%rip),%xmm1
  jae    L7
  movsd  D17(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L13
  cvttsd2si %xmm0,%rax
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  cvtsi2sd %rax,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L7:
  pxor   %xmm1,%xmm1
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: qword[2]
name: read_data
arguments: data_tag: D8
data_type: f64[2]
name: read_data
arguments: data_tag: D17
data_type: f64

tool: {"D18": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D8": [4503599627370496.0,1.0]}

tool: D17: 1

assistant: ```c
double modf(double x, double *iptr) {
  if (fabs(x) >= 4503599627370496.0) {
    *iptr = x;
    return 0.0;
  } else if (fabs(x) < 1.0) {
    *iptr = 0.0;
    return x;
  } else {
    *iptr = (double)(int64_t)x;
    return (x - *iptr);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<modf>:
  endbr64
  movapd %xmm0,%xmm1
  andpd  D20(%rip),%xmm1
  comisd D28(%rip),%xmm1
  jae    L19
  movsd  D0(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L14
  cvttsd2si %xmm0,%rax
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  cvtsi2sd %rax,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm1,%xmm1
  movsd  %xmm0,(%rdi)
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D20
data_type: qword[2]
name: parse_data
arguments: label: D28
data_type: f64[2]
name: parse_data
arguments: label: D0
data_type: f64

tool: {"D20": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D28": [4503599627370496.0,1.0]}

tool: D0: 1

assistant: ```c
double modf(double x, double *iptr) {
  if (fabs(x) >= 4503599627370496.0) {
    *iptr = x;
    return 0.0;
  } else if (fabs(x) < 1.0) {
    *iptr = 0.0;
    return x;
  } else {
    *iptr = (double)(int64_t)x;
    return (x - *iptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cfg_parse_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    D44(%rip),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L14
  mov    D44(%rip),%rax
  mov    (%rax),%edx
  mov    D57(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L9
L14:
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L33
  mov    D44(%rip),%rax
  mov    (%rax),%edx
  mov    $0xfb303040,%eax
  sub    %edx,%eax
  jmp    L17
L33:
  mov    D44(%rip),%rax
  mov    (%rax),%eax
L17:
  mov    D44(%rip),%rdx
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  jmp    L29
L9:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int cfg_parse_port(char *tok, int *port) {
  assert(tok != NULL);
  assert(port != NULL);
  errno = 0;
  *port = strtol(tok, NULL, 10);
  if (*port < 0 || errno == ERANGE) {
    do {
      errno = errno < 0 ? errno : (-1 * ((((8) * 10000 + (728))) * 1000 + (errno)));
    } while (0);
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cfg_parse_port>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    D40(%rip),%rax
  movl   $0x0,(%rax)
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  js     L16
  mov    D40(%rip),%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  je     L16
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    D40(%rip),%rax
  mov    (%rax),%eax
  mov    $0xfb303040,%edx
  sub    %eax,%edx
  test   %eax,%eax
  cmovns %edx,%eax
  mov    D40(%rip),%rdx
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int cfg_parse_port(char *tok, int *port) {
  assert(tok != NULL);
  assert(port != NULL);
  errno = 0;
  *port = strtol(tok, NULL, 10);
  if (*port < 0 || errno == ERANGE) {
    do {
      errno = errno < 0 ? errno : (-1 * ((((8) * 10000 + (728))) * 1000 + (errno)));
    } while (0);
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cfg_parse_port>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    D13(%rip),%r12
  movl   $0x0,(%r12)
  call   <strtol@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  js     L13
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%r12)
  je     L17
  xor    %eax,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    (%r12),%eax
L17:
  mov    $0xfb303040,%edx
  sub    %eax,%edx
  test   %eax,%eax
  cmovns %edx,%eax
  mov    %eax,(%r12)
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int cfg_parse_port(char *tok, int *port) {
  assert(tok != NULL);
  assert(port != NULL);
  errno = 0;
  *port = strtol(tok, NULL, 10);
  if (*port < 0 || errno == ERANGE) {
    do {
      errno = errno < 0 ? errno : (-1 * ((((8) * 10000 + (728))) * 1000 + (errno)));
    } while (0);
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cfg_parse_port>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  push   %rbp
  mov    %rdi,%rbp
  setne  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    D18(%rip),%r12
  movl   $0x0,(%r12)
  call   <strtol@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  js     L9
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%r12)
  je     L18
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    (%r12),%eax
L18:
  mov    $0xfb303040,%edx
  sub    %eax,%edx
  test   %eax,%eax
  cmovns %edx,%eax
  mov    %eax,(%r12)
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int cfg_parse_port(char *tok, int *port) {
  assert(tok != NULL);
  assert(port != NULL);
  errno = 0;
  *port = strtol(tok, NULL, 10);
  if (*port < 0 || errno == ERANGE) {
    do {
      errno = errno < 0 ? errno : (-1 * ((((8) * 10000 + (728))) * 1000 + (errno)));
    } while (0);
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: Hello Master Falindir


assistant: ```c
int main(void) {
  printf("Hello Master Falindir\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: Hello Master Falindir


assistant: ```c
int main(void) {
  printf("Hello Master Falindir\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: Hello Master Falindir


assistant: ```c
int main(void) {
  printf("Hello Master Falindir\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: Hello Master Falindir


assistant: ```c
int main(void) {
  printf("Hello Master Falindir\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D55(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x7b,-0xc(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D55
type_guessed: f64
name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D68
type_guessed: string
name: retrieve_data
arguments: label: D50
type_guessed: string
name: retrieve_data
arguments: label: D59
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D43
type_guessed: string

tool: D55: 1234.2568

tool: D17: %.5f


tool: D68: %10.3f


tool: D50: %012f


tool: D59: %2f


tool: D14: %d


tool: D12: %10d


tool: D43: %-10d! 


assistant: ```c
int main() {
  double sayi1 = 1234.2568;
  int sayi2 = 123;
  printf("%.5f\n", sayi1);
  printf("%10.3f\n", sayi1);
  printf("%012f\n", sayi1);
  printf("%2f\n", sayi1);
  printf("%d\n", sayi2);
  printf("%10d\n", sayi2);
  printf("%-10d! \n", sayi2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4d2,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D63(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: string
name: disassemble_data
arguments: data_tag: D53
type_guessed: string
name: disassemble_data
arguments: data_tag: D56
type_guessed: string
name: disassemble_data
arguments: data_tag: D63
type_guessed: string

tool: D10: %.5f


tool: D0: %10.3f


tool: D11: %012f


tool: D24: %2f


tool: D53: %d


tool: D56: %10d


tool: D63: %-10d! 


assistant: ```c
int main() {
  double sayi1 = 1234.2568;
  int sayi2 = 123;
  printf("%.5f\n", sayi1);
  printf("%10.3f\n", sayi1);
  printf("%012f\n", sayi1);
  printf("%2f\n", sayi1);
  printf("%d\n", sayi2);
  printf("%10d\n", sayi2);
  printf("%-10d! \n", sayi2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4d2,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    $0x4d2,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D54
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D69
type_infered: string
name: parse_data
arguments: data_tag: D38
type_infered: string
name: parse_data
arguments: data_tag: D49
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D54: %.5f


tool: D4: %10.3f


tool: D69: %012f


tool: D38: %2f


tool: D49: %d


tool: D24: %10d


tool: D7: %-10d! 


assistant: ```c
int main() {
  double sayi1 = 1234.2568;
  int sayi2 = 123;
  printf("%.5f\n", sayi1);
  printf("%10.3f\n", sayi1);
  printf("%012f\n", sayi1);
  printf("%2f\n", sayi1);
  printf("%d\n", sayi2);
  printf("%10d\n", sayi2);
  printf("%-10d! \n", sayi2);
  return 0;
}
```