ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vec_swap_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r15
  mov    %ecx,%ebx
  mov    %r8d,%r14d
  mov    %r9d,%ebp
  test   %rdi,%rdi
  je     L18
  test   %rsi,%rsi
  je     L18
  test   %rdx,%rdx
  setne  %al
  test   %ecx,%ecx
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
L6:
  call   <assert@plt>
  mov    %ebx,%ecx
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <vec_expand_@plt>
  mov    D15(%rip),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L34
  mov    %ebx,%eax
  imul   0x0(%r13),%eax
  movslq %eax,%r13
  add    (%r12),%r13
  imul   %ebx,%r14d
  movslq %r14d,%r14
  mov    %r14,%rsi
  add    (%r12),%rsi
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  imul   %ebx,%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rsi
  add    (%r12),%rsi
  mov    %r14,%rdi
  add    (%r12),%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  add    (%r12),%rdi
  mov    %ebx,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0x0,%edi
  jmp    L6
```

assistant: ```c
void vec_swap_(char **data, int *length, int *capacity, int memsz, int idx1, int idx2) {
  assert(data && length && capacity && memsz);
  char *tmp;
  vec_expand_(data, length, capacity, memsz);
  if (errno == ENOMEM)
    return;
  tmp = *data + *length * memsz;
  memcpy(tmp, *data + (idx1 * memsz), memsz);
  memcpy(*data + (idx1 * memsz), *data + (idx2 * memsz), memsz);
  memcpy(*data + (idx2 * memsz), tmp, memsz);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vec_swap_>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L7
  test   %rsi,%rsi
  je     L7
  test   %rdx,%rdx
  setne  %al
  xor    %edi,%edi
  test   %ecx,%ecx
  setne  %dil
  and    %eax,%edi
L2:
  call   <assert@plt>
  mov    %r15,%rdx
  mov    %r12d,%ecx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <vec_expand_@plt>
  mov    D12(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L29
  mov    0x0(%r13),%r15d
  imul   %r12d,%r14d
  mov    (%rbx),%rsi
  mov    %r12d,%edx
  imul   %r12d,%ebp
  imul   %r12d,%r15d
  movslq %r14d,%r14
  add    %r14,%rsi
  movslq %ebp,%rbp
  movslq %r15d,%r15
  add    (%rbx),%r15
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rsi
  mov    (%rbx),%rdi
  mov    %r12d,%edx
  add    %rbp,%rsi
  add    %r14,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  mov    %r12d,%edx
  pop    %rbx
  mov    %r15,%rsi
  add    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %edi,%edi
  jmp    L2
  nop
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vec_swap_(char **data, int *length, int *capacity, int memsz, int idx1, int idx2) {
  assert(data && length && capacity && memsz);
  char *tmp;
  vec_expand_(data, length, capacity, memsz);
  if (errno == ENOMEM)
    return;
  tmp = *data + *length * memsz;
  memcpy(tmp, *data + (idx1 * memsz), memsz);
  memcpy(*data + (idx1 * memsz), *data + (idx2 * memsz), memsz);
  memcpy(*data + (idx2 * memsz), tmp, memsz);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec_swap_>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L18
  test   %rsi,%rsi
  je     L18
  test   %rdx,%rdx
  setne  %al
  xor    %edi,%edi
  test   %ecx,%ecx
  setne  %dil
  and    %eax,%edi
L33:
  call   <assert@plt>
  mov    %r15,%rdx
  mov    %r12d,%ecx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <vec_expand_@plt>
  mov    D14(%rip),%rax
  mov    D4(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L15
  mov    0x0(%r13),%r15d
  imul   %r12d,%r14d
  mov    (%rbx),%rsi
  mov    %r12d,%edx
  imul   %r12d,%ebp
  imul   %r12d,%r15d
  movslq %r14d,%r14
  add    %r14,%rsi
  movslq %ebp,%rbp
  movslq %r15d,%r15
  add    (%rbx),%r15
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rsi
  mov    (%rbx),%rdi
  mov    %r12d,%edx
  add    %rbp,%rsi
  add    %r14,%rdi
  call   <memcpy@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  mov    %r12d,%edx
  pop    %rbx
  mov    %r15,%rsi
  add    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %edi,%edi
  jmp    L33
  nop
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vec_swap_(char **data, int *length, int *capacity, int memsz, int idx1, int idx2) {
  assert(data && length && capacity && memsz);
  char *tmp;
  vec_expand_(data, length, capacity, memsz);
  if (errno == ENOMEM)
    return;
  tmp = *data + *length * memsz;
  memcpy(tmp, *data + (idx1 * memsz), memsz);
  memcpy(*data + (idx1 * memsz), *data + (idx2 * memsz), memsz);
  memcpy(*data + (idx2 * memsz), tmp, memsz);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x2,%eax
  mov    %eax,%edi
  call   <MALLOC@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x2,%eax
  mov    %eax,%edi
  call   <MALLOC@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <split_dir_and_file@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_dirname(const char *in) {
  char *dir = MALLOC(sizeof(char) * (strlen(in) + 2));
  char *file = MALLOC(sizeof(char) * (strlen(in) + 2));
  split_dir_and_file(in, dir, file);
  free(file);
  return dir;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_dirname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %rax,%r12
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <split_dir_and_file@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_dirname(const char *in) {
  char *dir = MALLOC(sizeof(char) * (strlen(in) + 2));
  char *file = MALLOC(sizeof(char) * (strlen(in) + 2));
  split_dir_and_file(in, dir, file);
  free(file);
  return dir;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_dirname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  call   <split_dir_and_file@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dirname(const char *in) {
  char *dir = MALLOC(sizeof(char) * (strlen(in) + 2));
  char *file = MALLOC(sizeof(char) * (strlen(in) + 2));
  split_dir_and_file(in, dir, file);
  free(file);
  return dir;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_dirname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  call   <MALLOC@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    %rax,%rdx
  call   <split_dir_and_file@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dirname(const char *in) {
  char *dir = MALLOC(sizeof(char) * (strlen(in) + 2));
  char *file = MALLOC(sizeof(char) * (strlen(in) + 2));
  split_dir_and_file(in, dir, file);
  free(file);
  return dir;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skynet_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skynet_strdup(const char *str) {
  size_t sz = strlen(str);
  char *ret = malloc(sz + 1);
  memcpy(ret, str, sz + 1);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<skynet_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *skynet_strdup(const char *str) {
  size_t sz = strlen(str);
  char *ret = malloc(sz + 1);
  memcpy(ret, str, sz + 1);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skynet_strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *skynet_strdup(const char *str) {
  size_t sz = strlen(str);
  char *ret = malloc(sz + 1);
  memcpy(ret, str, sz + 1);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skynet_strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *skynet_strdup(const char *str) {
  size_t sz = strlen(str);
  char *ret = malloc(sz + 1);
  memcpy(ret, str, sz + 1);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tranlaste_arguments_to_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <initialize_vectors@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *tranlaste_arguments_to_vector(int integers_amount, char *argv[]) {
  int *arguments_vector = initialize_vectors(integers_amount);
  int argument_counter = 2;
  int vector_counter = 0;
  int current_value = 0;
  while (vector_counter < integers_amount) {
    current_value = atoi(argv[argument_counter]);
    arguments_vector[vector_counter] = current_value;
    vector_counter++;
    argument_counter++;
  }
  return arguments_vector;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tranlaste_arguments_to_vector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  call   <initialize_vectors@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L7
  lea    0x2(%rbx),%r13d
  mov    $0x2,%ebx
L3:
  mov    (%r12,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L3
L7:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *tranlaste_arguments_to_vector(int integers_amount, char *argv[]) {
  int *arguments_vector = initialize_vectors(integers_amount);
  int argument_counter = 2;
  int vector_counter = 0;
  int current_value = 0;
  while (vector_counter < integers_amount) {
    current_value = atoi(argv[argument_counter]);
    arguments_vector[vector_counter] = current_value;
    vector_counter++;
    argument_counter++;
  }
  return arguments_vector;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tranlaste_arguments_to_vector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <initialize_vectors@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L14
  lea    0x2(%rbx),%r13d
  mov    $0x2,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L5
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *tranlaste_arguments_to_vector(int integers_amount, char *argv[]) {
  int *arguments_vector = initialize_vectors(integers_amount);
  int argument_counter = 2;
  int vector_counter = 0;
  int current_value = 0;
  while (vector_counter < integers_amount) {
    current_value = atoi(argv[argument_counter]);
    arguments_vector[vector_counter] = current_value;
    vector_counter++;
    argument_counter++;
  }
  return arguments_vector;
}
```
user: What is the c source code of the assembly code below:

```asm
<tranlaste_arguments_to_vector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <initialize_vectors@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L13
  lea    0x2(%rbx),%r13d
  mov    $0x2,%ebx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L0
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *tranlaste_arguments_to_vector(int integers_amount, char *argv[]) {
  int *arguments_vector = initialize_vectors(integers_amount);
  int argument_counter = 2;
  int vector_counter = 0;
  int current_value = 0;
  while (vector_counter < integers_amount) {
    current_value = atoi(argv[argument_counter]);
    arguments_vector[vector_counter] = current_value;
    vector_counter++;
    argument_counter++;
  }
  return arguments_vector;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D19(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0xa,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  sub    $0x8,%rsp
  push   $0xa
  push   $0x22
  push   -0x8(%rbp)
  push   $0x22
  push   $0xa
  push   $0x22
  push   -0x10(%rbp)
  push   $0x22
  push   $0xa
  push   $0x22
  push   -0x18(%rbp)
  push   $0x22
  push   $0xa
  mov    $0xa,%r9d
  mov    $0xa,%r8d
  mov    $0x25,%ecx
  mov    $0x9,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x70,%rsp
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D16
type: string
name: parse_data
arguments: data_label: D23
type: string

tool: D19: #include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):

tool: D16: %c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c

tool: D23: printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c

assistant: ```c
int main(void) {
  char *s, *t, *u;
  s = "#include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):";
  t = "%c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c";
  u = "printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c";
  printf(s, 10, 10, 10, 10);
  printf(t, 10, 9, 37, 10, 10, 10, 34, s, 34, 10, 34, t, 34, 10, 34, u, 34, 10);
  printf(u, 10, 10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0xa,%edx
  mov    $0xa,%esi
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x8,%rsp
  push   $0xa
  push   $0x22
  lea    D12(%rip),%rbx
  push   %rbx
  push   $0x22
  push   $0xa
  push   $0x22
  lea    D25(%rip),%rdi
  push   %rdi
  push   $0x22
  push   $0xa
  push   $0x22
  push   %rbp
  push   $0x22
  push   $0xa
  mov    $0xa,%r9d
  mov    $0xa,%r8d
  mov    $0x25,%ecx
  mov    $0x9,%edx
  mov    $0xa,%esi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x70,%rsp
  mov    $0xa,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string

tool: D16: #include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):

tool: D12: printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c

tool: D25: %c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c

assistant: ```c
int main(void) {
  char *s, *t, *u;
  s = "#include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):";
  t = "%c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c";
  u = "printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c";
  printf(s, 10, 10, 10, 10);
  printf(t, 10, 9, 37, 10, 10, 10, 34, s, 34, 10, 34, t, 34, 10, 34, u, 34, 10);
  printf(u, 10, 10);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   %rbx
  lea    D23(%rip),%rbx
  mov    $0xa,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  lea    D7(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  sub    $0x8,%rsp
  mov    $0x25,%ecx
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  push   $0xa
  mov    $0x9,%edx
  mov    $0xa,%r9d
  push   $0x22
  mov    $0xa,%r8d
  mov    $0xa,%esi
  push   %rbp
  push   $0x22
  push   $0xa
  push   $0x22
  push   %rdi
  push   $0x22
  push   $0xa
  push   $0x22
  push   %rbx
  push   $0x22
  push   $0xa
  call   <printf@plt>
  add    $0x70,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D21
data_type: string

tool: D23: #include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):

tool: D7: printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c

tool: D21: %c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c

assistant: ```c
int main(void) {
  char *s, *t, *u;
  s = "#include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):";
  t = "%c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c";
  u = "printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c";
  printf(s, 10, 10, 10, 10);
  printf(t, 10, 9, 37, 10, 10, 10, 34, s, 34, 10, 34, t, 34, 10, 34, u, 34, 10);
  printf(u, 10, 10);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   %rbx
  lea    D2(%rip),%rbx
  mov    $0xa,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  lea    D19(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  sub    $0x8,%rsp
  mov    $0x25,%ecx
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  push   $0xa
  mov    $0x9,%edx
  mov    $0xa,%r9d
  push   $0x22
  mov    $0xa,%r8d
  mov    $0xa,%esi
  push   %rbp
  push   $0x22
  push   $0xa
  push   $0x22
  push   %rdi
  push   $0x22
  push   $0xa
  push   $0x22
  push   %rbx
  push   $0x22
  push   $0xa
  call   <printf@plt>
  add    $0x70,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string

tool: D2: #include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):

tool: D19: printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c

tool: D22: %c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c

assistant: ```c
int main(void) {
  char *s, *t, *u;
  s = "#include <stdio.h>%c#define pass int main(void){char*s,*t,*u%c#define None return 0;}%c#/*%cdef printf(s,*args):";
  t = "%c%cprint(s %c args,end='')%c#*/%cpass;%cs=%c%s%c;%ct=%c%s%c;%cu=%c%s%c;%c";
  u = "printf(s,10,10,10,10);printf(t,10,9,37,10,10,10,34,s,34,10,34,t,34,10,34,u,34,10);printf(u,10,10);None%c%c";
  printf(s, 10, 10, 10, 10);
  printf(t, 10, 9, 37, 10, 10, 10, 34, s, 34, 10, 34, t, 34, 10, 34, u, 34, 10);
  printf(u, 10, 10);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_identifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L30:
  mov    $0x7a,%esi
  mov    $0x61,%edi
  call   <read_char_range@plt>
  test   %rax,%rax
  jne    L30
  mov    $0x5a,%esi
  mov    $0x41,%edi
  call   <read_char_range@plt>
  test   %rax,%rax
  jne    L30
  mov    $0x39,%esi
  mov    $0x30,%edi
  call   <read_char_range@plt>
  test   %rax,%rax
  jne    L30
  mov    $0x5f,%edi
  call   <read_char@plt>
  test   %rax,%rax
  jne    L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void read_identifier() {
  while (read_char_range('a', 'z') || read_char_range('A', 'Z') || read_char_range('0', '9') || read_char('_')) {
  }
}
```