ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L18
  jmp    L23
  nop
L27:
  test   %cl,%cl
  je     L25
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L25
L18:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L27
L25:
  ret
L23:
  ret
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  size_t n;
  for (n = 0; s1[n] != '\0' && s2[n] != '\0'; ++n) {
    if (s1[n] != s2[n]) {
      break;
    }
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L43
  jmp    L1
  nop
L34:
  test   %cl,%cl
  je     L23
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L23
L43:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L34
L23:
  ret
L1:
  ret
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  size_t n;
  for (n = 0; s1[n] != '\0' && s2[n] != '\0'; ++n) {
    if (s1[n] != s2[n]) {
      break;
    }
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  jmp    L9
```

assistant: ```c
void error(void) {
  {
  ERROR:;
    goto ERROR;
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<error>:
  endbr64
L9:
  jmp    L9
```

assistant: ```c
void error(void) {
  {
  ERROR:;
    goto ERROR;
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void error(void) {
  {
  ERROR:;
    goto ERROR;
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void error(void) {
  {
  ERROR:;
    goto ERROR;
    return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memset_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x10,%eax
  or     -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L36
L6:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x10,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L36:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L10:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset_s(void *adr, int val, int count) {
  int i, n, v;
  unsigned int *p;
  unsigned short *q;
  p = adr;
  v = val | (val << 16);
  n = count >> 3;
  for (i = 0; i < n; i++) {
    p[0] = v;
    p[1] = v;
    p[2] = v;
    p[3] = v;
    p += 4;
  }
  q = (unsigned short *)p;
  n = count & 7;
  for (i = 0; i < n; i++)
    *q++ = val;
}
```
user: What is the c source code of the assembly code below?

```asm
<memset_s>:
  endbr64
  mov    %esi,%ecx
  shl    $0x10,%ecx
  or     %esi,%ecx
  mov    %edx,%eax
  sar    $0x3,%eax
  test   %eax,%eax
  jle    L23
  mov    %eax,%eax
  shl    $0x4,%rax
  add    %rdi,%rax
L34:
  mov    %ecx,(%rdi)
  mov    %ecx,0x4(%rdi)
  mov    %ecx,0x8(%rdi)
  mov    %ecx,0xc(%rdi)
  add    $0x10,%rdi
  cmp    %rax,%rdi
  jne    L34
L9:
  and    $0x7,%edx
  je     L5
  mov    %edx,%edx
  lea    (%rax,%rdx,2),%rdx
L37:
  add    $0x2,%rax
  mov    %si,-0x2(%rax)
  cmp    %rdx,%rax
  jne    L37
L5:
  ret
L23:
  mov    %rdi,%rax
  jmp    L9
```

assistant: ```c
void memset_s(void *adr, int val, int count) {
  int i, n, v;
  unsigned int *p;
  unsigned short *q;
  p = adr;
  v = val | (val << 16);
  n = count >> 3;
  for (i = 0; i < n; i++) {
    p[0] = v;
    p[1] = v;
    p[2] = v;
    p[3] = v;
    p += 4;
  }
  q = (unsigned short *)p;
  n = count & 7;
  for (i = 0; i < n; i++)
    *q++ = val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset_s>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%eax
  shl    $0x10,%ecx
  sar    $0x3,%eax
  or     %esi,%ecx
  test   %eax,%eax
  jle    L49
  cltq
  shl    $0x4,%rax
  add    %rdi,%rax
  nopl   (%rax)
L38:
  mov    %ecx,(%rdi)
  add    $0x10,%rdi
  mov    %ecx,-0xc(%rdi)
  mov    %ecx,-0x8(%rdi)
  mov    %ecx,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L38
L11:
  and    $0x7,%edx
  je     L23
  movslq %edx,%rdx
  lea    (%rax,%rdx,2),%rdx
L2:
  add    $0x2,%rax
  mov    %si,-0x2(%rax)
  cmp    %rax,%rdx
  jne    L2
L23:
  ret
  xchg   %ax,%ax
L49:
  mov    %rdi,%rax
  jmp    L11
```

assistant: ```c
void memset_s(void *adr, int val, int count) {
  int i, n, v;
  unsigned int *p;
  unsigned short *q;
  p = adr;
  v = val | (val << 16);
  n = count >> 3;
  for (i = 0; i < n; i++) {
    p[0] = v;
    p[1] = v;
    p[2] = v;
    p[3] = v;
    p += 4;
  }
  q = (unsigned short *)p;
  n = count & 7;
  for (i = 0; i < n; i++)
    *q++ = val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memset_s>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%r8d
  mov    %rdi,%rcx
  mov    %esi,%edi
  shl    $0x10,%eax
  sar    $0x3,%r8d
  or     %esi,%eax
  test   %r8d,%r8d
  jle    L76
  lea    -0x1(%r8),%esi
  movd   %eax,%xmm2
  mov    %rcx,%rax
  shl    $0x4,%rsi
  pshufd $0x0,%xmm2,%xmm0
  lea    0x10(%rcx,%rsi,1),%rsi
  nopl   (%rax)
L58:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L58
  shl    $0x4,%r8
  add    %r8,%rcx
L76:
  and    $0x7,%edx
  je     L23
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L44
  movd   %edi,%xmm1
  add    $0x8,%rcx
  mov    $0x4,%eax
  pshuflw $0x0,%xmm1,%xmm0
  movq   %xmm0,-0x8(%rcx)
  cmp    $0x4,%edx
  je     L47
L16:
  lea    0x1(%rax),%esi
  mov    %di,(%rcx)
  cmp    %esi,%edx
  jle    L23
  add    $0x2,%eax
  mov    %di,0x2(%rcx)
  cmp    %eax,%edx
  jle    L23
  mov    %di,0x4(%rcx)
L23:
  ret
  xchg   %ax,%ax
L47:
  ret
L44:
  xor    %eax,%eax
  jmp    L16
```

assistant: ```c
void memset_s(void *adr, int val, int count) {
  int i, n, v;
  unsigned int *p;
  unsigned short *q;
  p = adr;
  v = val | (val << 16);
  n = count >> 3;
  for (i = 0; i < n; i++) {
    p[0] = v;
    p[1] = v;
    p[2] = v;
    p[3] = v;
    p += 4;
  }
  q = (unsigned short *)p;
  n = count & 7;
  for (i = 0; i < n; i++)
    *q++ = val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bar@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(void) {
#pragma omp target teams
  {
#pragma omp parallel
    {}
    bar();
#pragma omp parallel
    {}
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(void) {
#pragma omp target teams
  {
#pragma omp parallel
    {}
    bar();
#pragma omp parallel
    {}
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(void) {
#pragma omp target teams
  {
#pragma omp parallel
    {}
    bar();
#pragma omp parallel
    {}
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(void) {
#pragma omp target teams
  {
#pragma omp parallel
    {}
    bar();
#pragma omp parallel
    {}
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<splitString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,%edx
  mov    %al,-0x34(%rbp)
  mov    %edx,%eax
  mov    %al,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0x0,%eax
  jmp    L80
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L57:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jne    L94
  mov    -0x20(%rbp),%eax
  jmp    L80
L94:
  nop
L21:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L81
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x34(%rbp)
  je     L73
  addq   $0x1,-0x10(%rbp)
  jmp    L21
L81:
  nop
  jmp    L30
L73:
  nop
L30:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  cmpb   $0x0,-0x40(%rbp)
  je     L127
  cmpl   $0x0,-0x1c(%rbp)
  jle    L97
L127:
  cmpl   $0x0,-0x1c(%rbp)
  je     L99
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L99:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x20(%rbp)
L97:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L79
  mov    -0x20(%rbp),%eax
  jmp    L80
L79:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L53
  jmp    L57
L53:
  mov    -0x20(%rbp),%eax
L80:
  leave
  ret
```

assistant: ```c
int splitString(char **columns, const char *str, const char delimiter, const int maxColumns, const int columnSize, const char multDel) {
  int sizeColumn;
  int ncolumn = 0;
  const char *send = str + strlen(str);
  const char *s = str;
  if (str[0] == '\0')
    return 0;
  const char *ns = s;
PROCESS_COLUMN:
  if (ncolumn + 1 == maxColumns)
    return ncolumn;
FIND_DELIMITER:
  if (ns == send)
    goto FOUND_COLUMN;
  if (*ns != delimiter) {
    ns++;
    goto FIND_DELIMITER;
  }
FOUND_COLUMN:
  sizeColumn = ns - s;
  if ((!multDel) || (sizeColumn > 0)) {
    if (sizeColumn)
      memcpy(columns[ncolumn], s, sizeColumn);
    columns[ncolumn][sizeColumn] = '\0';
    ncolumn++;
  }
  if (ns == send)
    return ncolumn;
  ++ns;
  s = ns;
  if (ns != send)
    goto PROCESS_COLUMN;
  return ncolumn;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<splitString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r13
  mov    %ecx,0x10(%rsp)
  mov    %edx,%r12d
  mov    %r9b,0x17(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    $0x0,%r14d
  cmpb   $0x0,0x0(%r13)
  je     L109
  cltq
  lea    0x0(%r13,%rax,1),%rbp
  jmp    L89
L155:
  mov    %rbx,%rax
  sub    %r13,%rax
  mov    %eax,0xc(%rsp)
  cmpb   $0x0,0x17(%rsp)
  je     L98
  test   %eax,%eax
  jle    L62
L98:
  cmpl   $0x0,0xc(%rsp)
  jne    L75
L36:
  movslq %r14d,%r14
  movslq 0xc(%rsp),%rax
  mov    0x18(%rsp),%rcx
  mov    (%rcx,%r14,8),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    %r15d,%r14d
L62:
  cmp    %rbx,%rbp
  je     L109
  lea    0x1(%rbx),%r13
  cmp    %r13,%rbp
  je     L109
L89:
  lea    0x1(%r14),%r15d
  cmp    0x10(%rsp),%r15d
  je     L109
  cmp    %rbp,%r13
  je     L8
  mov    %r13,%rbx
L92:
  cmp    %r12b,(%rbx)
  je     L155
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L92
  mov    %rbx,%rax
  sub    %r13,%rax
  mov    %eax,0xc(%rsp)
  cmpb   $0x0,0x17(%rsp)
  je     L98
  test   %eax,%eax
  jg     L98
  jmp    L109
L75:
  movslq %r14d,%rax
  mov    0x18(%rsp),%rcx
  mov    (%rcx,%rax,8),%rdi
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  jmp    L36
L95:
  mov    %rbp,%rbx
  movl   $0x0,0xc(%rsp)
  jmp    L36
L8:
  cmpb   $0x0,0x17(%rsp)
  je     L95
L109:
  mov    %r14d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int splitString(char **columns, const char *str, const char delimiter, const int maxColumns, const int columnSize, const char multDel) {
  int sizeColumn;
  int ncolumn = 0;
  const char *send = str + strlen(str);
  const char *s = str;
  if (str[0] == '\0')
    return 0;
  const char *ns = s;
PROCESS_COLUMN:
  if (ncolumn + 1 == maxColumns)
    return ncolumn;
FIND_DELIMITER:
  if (ns == send)
    goto FOUND_COLUMN;
  if (*ns != delimiter) {
    ns++;
    goto FIND_DELIMITER;
  }
FOUND_COLUMN:
  sizeColumn = ns - s;
  if ((!multDel) || (sizeColumn > 0)) {
    if (sizeColumn)
      memcpy(columns[ncolumn], s, sizeColumn);
    columns[ncolumn][sizeColumn] = '\0';
    ncolumn++;
  }
  if (ns == send)
    return ncolumn;
  ++ns;
  s = ns;
  if (ns != send)
    goto PROCESS_COLUMN;
  return ncolumn;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<splitString>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0x8(%rsp)
  mov    %r9d,0x1c(%rsp)
  mov    %r9b,(%rsp)
  call   <strlen@plt>
  movslq %eax,%rdx
  xor    %eax,%eax
  cmpb   $0x0,0x0(%r13)
  je     L178
  mov    0x8(%rsp),%ecx
  movzbl (%rsp),%r9d
  lea    0x0(%r13,%rdx,1),%rbp
  nopw   0x0(%rax,%rax,1)
L10:
  lea    0x1(%rax),%r15d
  cmp    %ecx,%r15d
  je     L178
  test   %r9b,%r9b
  sete   %sil
  cmp    %rbp,%r13
  je     L39
  mov    %r13,%rbx
  jmp    L151
  xchg   %ax,%ax
L91:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L85
L151:
  cmp    %r12b,(%rbx)
  jne    L91
  mov    %rbx,%rdx
  sub    %r13,%rdx
  mov    %edx,%r8d
  test   %edx,%edx
  jg     L12
  test   %sil,%sil
  jne    L12
L135:
  lea    0x1(%rbx),%r13
  cmp    %r13,%rbp
  jne    L10
L178:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  mov    %rbp,%rdx
  sub    %r13,%rdx
  mov    %edx,%r8d
  test   %edx,%edx
  jg     L51
  test   %sil,%sil
  je     L178
L51:
  lea    (%r14,%rax,8),%r10
  movslq %edx,%r11
  test   %edx,%edx
  je     L134
L123:
  mov    (%r10),%rdi
  mov    %r8d,%edx
  mov    %r13,%rsi
  mov    %r9b,0x1b(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r11,0x8(%rsp)
  mov    %r10,(%rsp)
  call   <memcpy@plt>
  mov    (%rsp),%r10
  mov    0x8(%rsp),%r11
  mov    0x14(%rsp),%ecx
  movzbl 0x1b(%rsp),%r9d
L20:
  mov    (%r10),%rax
  movb   $0x0,(%rax,%r11,1)
  cmp    %rbp,%rbx
  je     L78
  movslq %r15d,%rax
  jmp    L135
L39:
  cmpb   $0x0,0x1c(%rsp)
  jne    L178
  mov    (%r14,%rax,8),%rax
  movb   $0x0,(%rax)
L78:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  lea    (%r14,%rax,8),%r10
  movslq %edx,%r11
  test   %edx,%edx
  jne    L123
  xor    %r11d,%r11d
  jmp    L20
L134:
  mov    (%r10),%rax
  movb   $0x0,(%rax)
  mov    %r15d,%eax
  jmp    L178
```

assistant: ```c
int splitString(char **columns, const char *str, const char delimiter, const int maxColumns, const int columnSize, const char multDel) {
  int sizeColumn;
  int ncolumn = 0;
  const char *send = str + strlen(str);
  const char *s = str;
  if (str[0] == '\0')
    return 0;
  const char *ns = s;
PROCESS_COLUMN:
  if (ncolumn + 1 == maxColumns)
    return ncolumn;
FIND_DELIMITER:
  if (ns == send)
    goto FOUND_COLUMN;
  if (*ns != delimiter) {
    ns++;
    goto FIND_DELIMITER;
  }
FOUND_COLUMN:
  sizeColumn = ns - s;
  if ((!multDel) || (sizeColumn > 0)) {
    if (sizeColumn)
      memcpy(columns[ncolumn], s, sizeColumn);
    columns[ncolumn][sizeColumn] = '\0';
    ncolumn++;
  }
  if (ns == send)
    return ncolumn;
  ++ns;
  s = ns;
  if (ns != send)
    goto PROCESS_COLUMN;
  return ncolumn;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<splitString>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0x8(%rsp)
  mov    %r9d,0x1c(%rsp)
  mov    %r9b,(%rsp)
  call   <strlen@plt>
  movslq %eax,%rdx
  xor    %eax,%eax
  cmpb   $0x0,0x0(%r13)
  je     L64
  mov    0x8(%rsp),%ecx
  movzbl (%rsp),%r9d
  lea    0x0(%r13,%rdx,1),%rbp
  nopw   0x0(%rax,%rax,1)
L37:
  lea    0x1(%rax),%r15d
  cmp    %ecx,%r15d
  je     L64
  test   %r9b,%r9b
  sete   %sil
  cmp    %rbp,%r13
  je     L113
  mov    %r13,%rbx
  jmp    L177
  xchg   %ax,%ax
L144:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L90
L177:
  cmp    %r12b,(%rbx)
  jne    L144
  mov    %rbx,%rdx
  sub    %r13,%rdx
  mov    %edx,%r8d
  test   %edx,%edx
  jg     L91
  test   %sil,%sil
  jne    L91
L57:
  lea    0x1(%rbx),%r13
  cmp    %r13,%rbp
  jne    L37
L64:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L90:
  mov    %rbp,%rdx
  sub    %r13,%rdx
  mov    %edx,%r8d
  test   %edx,%edx
  jg     L73
  test   %sil,%sil
  je     L64
L73:
  lea    (%r14,%rax,8),%r10
  movslq %edx,%r11
  test   %edx,%edx
  je     L46
L153:
  mov    (%r10),%rdi
  mov    %r8d,%edx
  mov    %r13,%rsi
  mov    %r9b,0x1b(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r11,0x8(%rsp)
  mov    %r10,(%rsp)
  call   <memcpy@plt>
  mov    (%rsp),%r10
  mov    0x8(%rsp),%r11
  mov    0x14(%rsp),%ecx
  movzbl 0x1b(%rsp),%r9d
L168:
  mov    (%r10),%rax
  movb   $0x0,(%rax,%r11,1)
  cmp    %rbp,%rbx
  je     L100
  movslq %r15d,%rax
  jmp    L57
L113:
  cmpb   $0x0,0x1c(%rsp)
  jne    L64
  mov    (%r14,%rax,8),%rax
  movb   $0x0,(%rax)
L100:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L91:
  lea    (%r14,%rax,8),%r10
  movslq %edx,%r11
  test   %edx,%edx
  jne    L153
  xor    %r11d,%r11d
  jmp    L168
L46:
  mov    (%r10),%rax
  movb   $0x0,(%rax)
  mov    %r15d,%eax
  jmp    L64
```

assistant: ```c
int splitString(char **columns, const char *str, const char delimiter, const int maxColumns, const int columnSize, const char multDel) {
  int sizeColumn;
  int ncolumn = 0;
  const char *send = str + strlen(str);
  const char *s = str;
  if (str[0] == '\0')
    return 0;
  const char *ns = s;
PROCESS_COLUMN:
  if (ncolumn + 1 == maxColumns)
    return ncolumn;
FIND_DELIMITER:
  if (ns == send)
    goto FOUND_COLUMN;
  if (*ns != delimiter) {
    ns++;
    goto FIND_DELIMITER;
  }
FOUND_COLUMN:
  sizeColumn = ns - s;
  if ((!multDel) || (sizeColumn > 0)) {
    if (sizeColumn)
      memcpy(columns[ncolumn], s, sizeColumn);
    columns[ncolumn][sizeColumn] = '\0';
    ncolumn++;
  }
  if (ns == send)
    return ncolumn;
  ++ns;
  s = ns;
  if (ns != send)
    goto PROCESS_COLUMN;
  return ncolumn;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<StrFormatDateMax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  leave
  ret
```

assistant: ```c
size_t StrFormatDateMax(char *target, size_t max, const char *format, const struct tm *datetime) {
  assert((0 != (target)));
  assert((0 != (format)));
  assert((0 != (datetime)));
  assert(max > 0);
  return strftime(target, max, format, datetime);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrFormatDateMax>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r13,%r13
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strftime@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t StrFormatDateMax(char *target, size_t max, const char *format, const struct tm *datetime) {
  assert((0 != (target)));
  assert((0 != (format)));
  assert((0 != (datetime)));
  assert(max > 0);
  return strftime(target, max, format, datetime);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<StrFormatDateMax>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strftime@plt>
```

assistant: ```c
size_t StrFormatDateMax(char *target, size_t max, const char *format, const struct tm *datetime) {
  assert((0 != (target)));
  assert((0 != (format)));
  assert((0 != (datetime)));
  assert(max > 0);
  return strftime(target, max, format, datetime);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<StrFormatDateMax>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strftime@plt>
```

assistant: ```c
size_t StrFormatDateMax(char *target, size_t max, const char *format, const struct tm *datetime) {
  assert((0 != (target)));
  assert((0 != (format)));
  assert((0 != (datetime)));
  assert(max > 0);
  return strftime(target, max, format, datetime);
}
```