ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<Ceil>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D20(%rip),%xmm2
  movsd  D45(%rip),%xmm3
  movapd %xmm0,%xmm1
  andpd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm3
  jbe    L8
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  movapd %xmm0,%xmm3
  movsd  D42(%rip),%xmm4
  andnpd %xmm0,%xmm2
  cvtsi2sd %rax,%xmm1
  cmpnlesd %xmm1,%xmm3
  andpd  %xmm4,%xmm3
  addsd  %xmm3,%xmm1
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
L8:
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D28
data_type: string
name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D20
data_type: byte[8]
name: read_data
arguments: data_label: D45
data_type: byte[8]
name: read_data
arguments: data_label: D42
data_type: byte[8]

tool: D28: Enter a number: 

tool: D4: %lf

tool: {"D20": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double Ceil(double a) {
  printf(gettext("Enter a number: "));
  scanf("%lf", &a);
  return (ceil(a));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_bencode_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L47:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L42
  addl   $0x1,-0x14(%rbp)
L45:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L47
  jmp    L5
L42:
  nop
L5:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <get_substring@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %i

assistant: ```c
char *parse_bencode_string(char *be_str) {
  int i;
  int len_str;
  sscanf(be_str, "%i", &len_str);
  for (i = 0; i < strlen(be_str); i++) {
    if (be_str[i - 1] == ':') {
      break;
    }
  }
  char *ret_str = get_substring(be_str, i, len_str);
  strncpy(ret_str, &be_str[i], len_str);
  return ret_str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_bencode_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D0(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x0,%ebx
L16:
  mov    %ebx,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L7
  add    $0x1,%rbx
  cmpb   $0x3a,-0x2(%rbp,%rbx,1)
  jne    L16
L7:
  mov    0x4(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <get_substring@plt>
  mov    %rax,%rbx
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,1),%rsi
  mov    0x4(%rsp),%edx
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: %i

assistant: ```c
char *parse_bencode_string(char *be_str) {
  int i;
  int len_str;
  sscanf(be_str, "%i", &len_str);
  for (i = 0; i < strlen(be_str); i++) {
    if (be_str[i - 1] == ':') {
      break;
    }
  }
  char *ret_str = get_substring(be_str, i, len_str);
  strncpy(ret_str, &be_str[i], len_str);
  return ret_str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_bencode_string>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  jmp    L26
  nopl   0x0(%rax)
L37:
  cmpb   $0x3a,-0x1(%rbp,%rbx,1)
  lea    0x1(%rbx),%rax
  je     L12
  mov    %rax,%rbx
L26:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L37
L12:
  mov    0x4(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <get_substring@plt>
  mov    0x4(%rsp),%edx
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: %i

assistant: ```c
char *parse_bencode_string(char *be_str) {
  int i;
  int len_str;
  sscanf(be_str, "%i", &len_str);
  for (i = 0; i < strlen(be_str); i++) {
    if (be_str[i - 1] == ':') {
      break;
    }
  }
  char *ret_str = get_substring(be_str, i, len_str);
  strncpy(ret_str, &be_str[i], len_str);
  return ret_str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_bencode_string>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  jmp    L20
  nopl   0x0(%rax)
L27:
  cmpb   $0x3a,-0x1(%rbp,%rbx,1)
  lea    0x1(%rbx),%rax
  je     L1
  mov    %rax,%rbx
L20:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L27
L1:
  mov    0x4(%rsp),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <get_substring@plt>
  mov    0x4(%rsp),%edx
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %i

assistant: ```c
char *parse_bencode_string(char *be_str) {
  int i;
  int len_str;
  sscanf(be_str, "%i", &len_str);
  for (i = 0; i < strlen(be_str); i++) {
    if (be_str[i - 1] == ':') {
      break;
    }
  }
  char *ret_str = get_substring(be_str, i, len_str);
  strncpy(ret_str, &be_str[i], len_str);
  return ret_str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uart_put_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x30,%edi
  call   <uart_putc@plt>
  mov    $0x78,%edi
  call   <uart_putc@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L25:
  mov    -0x14(%rbp),%eax
  shr    $0x1c,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x9,-0x5(%rbp)
  ja     L22
  mov    $0x30,%edx
  jmp    L7
L22:
  mov    $0x37,%edx
L7:
  movzbl -0x5(%rbp),%eax
  add    %edx,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_putc@plt>
  shll   $0x4,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x7,-0x4(%rbp)
  jle    L25
  mov    $0xa,%edi
  call   <uart_putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void uart_put_uint(unsigned int value) {
  int i;
  unsigned char c;
  uart_putc('0');
  uart_putc('x');
  for (i = 0; i < 8; i++) {
    c = (value & 0xf0000000) >> 28;
    uart_putc((c < 10 ? '0' : 'A' - 10) + c);
    value = (value & 0x0fffffff) << 4;
  }
  uart_putc('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uart_put_uint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x30,%edi
  call   <uart_putc@plt>
  mov    $0x78,%edi
  call   <uart_putc@plt>
  mov    $0x8,%ebp
L8:
  mov    %ebx,%eax
  shr    $0x1c,%eax
  cmp    $0xa,%al
  sbb    %edi,%edi
  and    $0xfffffff9,%edi
  lea    0x37(%rdi,%rax,1),%edi
  movsbl %dil,%edi
  call   <uart_putc@plt>
  shl    $0x4,%ebx
  sub    $0x1,%ebp
  jne    L8
  mov    $0xa,%edi
  call   <uart_putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uart_put_uint(unsigned int value) {
  int i;
  unsigned char c;
  uart_putc('0');
  uart_putc('x');
  for (i = 0; i < 8; i++) {
    c = (value & 0xf0000000) >> 28;
    uart_putc((c < 10 ? '0' : 'A' - 10) + c);
    value = (value & 0x0fffffff) << 4;
  }
  uart_putc('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uart_put_uint>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x30,%edi
  sub    $0x8,%rsp
  call   <uart_putc@plt>
  mov    $0x78,%edi
  call   <uart_putc@plt>
  nopl   (%rax)
L7:
  mov    %ebx,%eax
  shr    $0x1c,%eax
  cmp    $0xa,%eax
  sbb    %edi,%edi
  shl    $0x4,%ebx
  and    $0xfffffff9,%edi
  lea    0x37(%rdi,%rax,1),%edi
  movzbl %dil,%edi
  call   <uart_putc@plt>
  sub    $0x1,%ebp
  jne    L7
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <uart_putc@plt>
```

assistant: ```c
void uart_put_uint(unsigned int value) {
  int i;
  unsigned char c;
  uart_putc('0');
  uart_putc('x');
  for (i = 0; i < 8; i++) {
    c = (value & 0xf0000000) >> 28;
    uart_putc((c < 10 ? '0' : 'A' - 10) + c);
    value = (value & 0x0fffffff) << 4;
  }
  uart_putc('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uart_put_uint>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x30,%edi
  sub    $0x8,%rsp
  call   <uart_putc@plt>
  mov    $0x78,%edi
  call   <uart_putc@plt>
  nopl   (%rax)
L18:
  mov    %ebx,%eax
  shr    $0x1c,%eax
  cmp    $0x9fffffff,%ebx
  jbe    L15
  lea    0x37(%rax),%edi
  shl    $0x4,%ebx
  call   <uart_putc@plt>
  sub    $0x1,%ebp
  jne    L18
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <uart_putc@plt>
  nopl   (%rax)
L15:
  lea    0x30(%rax),%edi
  shl    $0x4,%ebx
  call   <uart_putc@plt>
  sub    $0x1,%ebp
  jne    L18
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <uart_putc@plt>
```

assistant: ```c
void uart_put_uint(unsigned int value) {
  int i;
  unsigned char c;
  uart_putc('0');
  uart_putc('x');
  for (i = 0; i < 8; i++) {
    c = (value & 0xf0000000) >> 28;
    uart_putc((c < 10 ? '0' : 'A' - 10) + c);
    value = (value & 0x0fffffff) << 4;
  }
  uart_putc('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generateId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x51,%edi
  call   <calloc@plt>
  mov    %rax,-0x78(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x84(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x84(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x80(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x80(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rcx
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D7: %Y%m%d%H%M%S

tool: D9: %s%ld

assistant: ```c
char *generateId() {
  char *obuf = calloc(81, sizeof(char));
  char tbuf[80] = {0};
  time_t timer;
  struct tm *tm_info;
  time(&timer);
  tm_info = localtime(&timer);
  strftime(tbuf, 80, "%Y%m%d%H%M%S", tm_info);
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long t = tv.tv_usec;
  snprintf(obuf, 80, "%s%ld", tbuf, t);
  return obuf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<generateId>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x51,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    0x10(%rsp),%rbp
  lea    D9(%rip),%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%r8
  mov    %rbp,%rcx
  lea    D3(%rip),%rdx
  mov    $0x50,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rbx,%rax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D9: %Y%m%d%H%M%S

tool: D3: %s%ld

assistant: ```c
char *generateId() {
  char *obuf = calloc(81, sizeof(char));
  char tbuf[80] = {0};
  time_t timer;
  struct tm *tm_info;
  time(&timer);
  tm_info = localtime(&timer);
  strftime(tbuf, 80, "%Y%m%d%H%M%S", tm_info);
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long t = tv.tv_usec;
  snprintf(obuf, 80, "%s%ld", tbuf, t);
  return obuf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<generateId>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x51,%edi
  push   %r12
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <calloc@plt>
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  movaps %xmm0,0x10(%rsp)
  mov    %rax,%r12
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <time@plt>
  mov    %r13,%rdi
  lea    0x10(%rsp),%r13
  call   <localtime@plt>
  lea    D16(%rip),%rdx
  mov    $0x50,%esi
  mov    %r13,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  xor    %esi,%esi
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdi
  lea    D4(%rip),%rdx
  mov    $0x50,%esi
  call   <snprintf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D4
type: string

tool: D16: %Y%m%d%H%M%S

tool: D4: %s%ld

assistant: ```c
char *generateId() {
  char *obuf = calloc(81, sizeof(char));
  char tbuf[80] = {0};
  time_t timer;
  struct tm *tm_info;
  time(&timer);
  tm_info = localtime(&timer);
  strftime(tbuf, 80, "%Y%m%d%H%M%S", tm_info);
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long t = tv.tv_usec;
  snprintf(obuf, 80, "%s%ld", tbuf, t);
  return obuf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<generateId>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x51,%edi
  push   %r12
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <calloc@plt>
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  movaps %xmm0,0x10(%rsp)
  mov    %rax,%r12
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <time@plt>
  mov    %r13,%rdi
  lea    0x10(%rsp),%r13
  call   <localtime@plt>
  lea    D19(%rip),%rdx
  mov    $0x50,%esi
  mov    %r13,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  xor    %esi,%esi
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdi
  lea    D5(%rip),%rdx
  mov    $0x50,%esi
  call   <snprintf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D5
type_guessed: string

tool: D19: %Y%m%d%H%M%S

tool: D5: %s%ld

assistant: ```c
char *generateId() {
  char *obuf = calloc(81, sizeof(char));
  char tbuf[80] = {0};
  time_t timer;
  struct tm *tm_info;
  time(&timer);
  tm_info = localtime(&timer);
  strftime(tbuf, 80, "%Y%m%d%H%M%S", tm_info);
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long t = tv.tv_usec;
  snprintf(obuf, 80, "%s%ld", tbuf, t);
  return obuf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x20(%rbp)
  movl   $0x14,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0x28,-0x14(%rbp)
  movl   $0x32,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  addq   $0xc,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int main() {
  int a[] = {10, 20, 30, 40, 50};
  int *j;
  j = a;
  j = j + 3;
  printf("%d", *j);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int a[] = {10, 20, 30, 40, 50};
  int *j;
  j = a;
  j = j + 3;
  printf("%d", *j);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  int a[] = {10, 20, 30, 40, 50};
  int *j;
  j = a;
  j = j + 3;
  printf("%d", *j);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int a[] = {10, 20, 30, 40, 50};
  int *j;
  j = a;
  j = j + 3;
  printf("%d", *j);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L71
  mov    $0x0,%eax
  jmp    L67
L71:
  cmpl   $0x2,-0x14(%rbp)
  jne    L58
  mov    $0x1,%eax
  jmp    L67
L58:
  movl   $0x2,-0x4(%rbp)
  jmp    L47
L40:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L13
  mov    $0x0,%eax
  jmp    L67
L13:
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L40
L67:
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int n) {
  int i;
  if (n <= 1)
    return 0;
  if (n == 2)
    return 1;
  for (i = 2; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPrime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L21
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L21
  test   $0x1,%dil
  je     L52
  mov    $0x2,%ecx
L50:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jle    L35
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L50
L21:
  ret
L35:
  ret
L52:
  mov    $0x0,%eax
  jmp    L21
```

assistant: ```c
int isPrime(int n) {
  int i;
  if (n <= 1)
    return 0;
  if (n == 2)
    return 1;
  for (i = 2; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isPrime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L37
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L37
  test   $0x1,%dil
  je     L8
  mov    $0x2,%ecx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L37
L19:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L60
L37:
  mov    %edx,%eax
  ret
L8:
  xor    %edx,%edx
  jmp    L37
```

assistant: ```c
int isPrime(int n) {
  int i;
  if (n <= 1)
    return 0;
  if (n == 2)
    return 1;
  for (i = 2; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isPrime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L39
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L39
  test   $0x1,%dil
  je     L37
  mov    $0x2,%ecx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L39
L42:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L25
L39:
  mov    %edx,%eax
  ret
L37:
  xor    %edx,%edx
  jmp    L39
```

assistant: ```c
int isPrime(int n) {
  int i;
  if (n <= 1)
    return 0;
  if (n == 2)
    return 1;
  for (i = 2; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L29
L18:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x40,-0x9(%rbp)
  jle    L23
  cmpb   $0x5a,-0x9(%rbp)
  jg     L23
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L23:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void strlower(char *const str) {
  assert(str);
  for (size_t i = 0; '\0' != str[i]; i++) {
    char const c = str[i];
    if (c >= 'A' && c <= 'Z')
      str[i] += 'a' - 'A';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L29
L37:
  pop    %rbx
  ret
L13:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L37
L29:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L13
  add    $0x20,%eax
  mov    %al,(%rbx)
  jmp    L13
```

assistant: ```c
void strlower(char *const str) {
  assert(str);
  for (size_t i = 0; '\0' != str[i]; i++) {
    char const c = str[i];
    if (c >= 'A' && c <= 'Z')
      str[i] += 'a' - 'A';
  }
}
```