ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L9:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L9
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  comiss D12(%rip),%xmm0
  jb     L4
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L4:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D12
data_type: byte[4]
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D0
data_type: string

tool: D22: %d

tool: {"D12": [0x00,0x00,0xe0,0x40]}

tool: D21: heavy

tool: D0: light

assistant: ```c
int main() {
  float avg, sum;
  int count, number;
  scanf("%d", &number);
  sum = 0;
  for (count = 0; number != 0; count++) {
    sum = sum + number % 10;
    number = number / 10;
  }
  avg = sum / count;
  if (avg >= 7) {
    printf("heavy");
  } else
    printf("light");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L17
  mov    $0x0,%esi
  pxor   %xmm0,%xmm0
L49:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  mov    %eax,%edx
  add    $0x1,%esi
  test   %eax,%eax
  jne    L49
  movl   $0x0,0x4(%rsp)
L21:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  comiss D12(%rip),%xmm0
  jb     L36
  lea    D13(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L17:
  mov    %edx,%esi
  pxor   %xmm0,%xmm0
  jmp    L21
L36:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D12
type: byte[4]
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D16
type: string

tool: D21: %d

tool: {"D12": [0x00,0x00,0xe0,0x40]}

tool: D13: heavy

tool: D16: light

assistant: ```c
int main() {
  float avg, sum;
  int count, number;
  scanf("%d", &number);
  sum = 0;
  for (count = 0; number != 0; count++) {
    sum = sum + number % 10;
    number = number / 10;
  }
  avg = sum / count;
  if (avg >= 7) {
    printf("heavy");
  } else
    printf("light");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  pxor   %xmm0,%xmm0
  test   %edx,%edx
  je     L43
  nopw   0x0(%rax,%rax,1)
L28:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  addss  %xmm1,%xmm0
  test   %eax,%eax
  jne    L28
  movl   $0x0,0x4(%rsp)
L43:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  comiss D10(%rip),%xmm0
  jb     L23
  lea    D27(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D31
datatype: string
name: retrieve_data
arguments: label: D10
datatype: byte[4]
name: retrieve_data
arguments: label: D27
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string

tool: D31: %d

tool: {"D10": [0x00,0x00,0xe0,0x40]}

tool: D27: heavy

tool: D18: light

assistant: ```c
int main() {
  float avg, sum;
  int count, number;
  scanf("%d", &number);
  sum = 0;
  for (count = 0; number != 0; count++) {
    sum = sum + number % 10;
    number = number / 10;
  }
  avg = sum / count;
  if (avg >= 7) {
    printf("heavy");
  } else
    printf("light");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  pxor   %xmm0,%xmm0
  test   %edx,%edx
  je     L10
  nopw   0x0(%rax,%rax,1)
L38:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  addss  %xmm1,%xmm0
  test   %eax,%eax
  jne    L38
  movl   $0x0,0x4(%rsp)
L10:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  comiss D16(%rip),%xmm0
  jb     L15
  lea    D1(%rip),%rdi
  call   <printf@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D16
type_infered: byte[4]
name: parse_data
arguments: label: D1
type_infered: string
name: parse_data
arguments: label: D33
type_infered: string

tool: D15: %d

tool: {"D16": [0x00,0x00,0xe0,0x40]}

tool: D1: heavy

tool: D33: light

assistant: ```c
int main() {
  float avg, sum;
  int count, number;
  scanf("%d", &number);
  sum = 0;
  for (count = 0; number != 0; count++) {
    sum = sum + number % 10;
    number = number / 10;
  }
  avg = sum / count;
  if (avg >= 7) {
    printf("heavy");
  } else
    printf("light");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void printarray(int a[], int count) {
  for (int i = 0; i < count; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printarray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D8(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: %d 

assistant: ```c
void printarray(int a[], int count) {
  for (int i = 0; i < count; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printarray>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
void printarray(int a[], int count) {
  for (int i = 0; i < count; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printarray>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: %d 

assistant: ```c
void printarray(int a[], int count) {
  for (int i = 0; i < count; ++i)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_242_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_242_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_242_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%ecx
  not    %ecx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  movzbl %cl,%edx
  or     %esi,%edx
  and    %edx,%eax
  and    %ecx,%esi
  movzbl %sil,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_242_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_242_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%ecx
  shl    $0x8,%esi
  not    %ecx
  or     %eax,%esi
  movzbl %cl,%edx
  mov    %esi,%eax
  or     %esi,%edx
  and    %ecx,%esi
  not    %eax
  movzbl %sil,%esi
  or     %edi,%eax
  and    %edx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_242_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_242_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%ecx
  shl    $0x8,%esi
  not    %ecx
  or     %eax,%esi
  movzbl %cl,%edx
  mov    %esi,%eax
  or     %esi,%edx
  and    %ecx,%esi
  not    %eax
  movzbl %sil,%esi
  or     %edi,%eax
  and    %edx,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_242_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = D & stk3;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below?

```asm
<dunno_dec2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xb,%eax
  and    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  je     L6
  mov    -0x14(%rbp),%eax
  sar    $0x15,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x16,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x12,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x11,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  and    $0x7fffff,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L6
  mov    -0x14(%rbp),%eax
  xor    $0x1,%eax
  jmp    L12
L6:
  mov    -0x14(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t dunno_dec2(uint32_t x1, uint32_t x2) {
  uint32_t x;
  if (x2 ^ ((x1 >> 11) & 1)) {
    x = ((x1 >> 0x15) ^ (x1 >> 0x16) ^ (x1 >> 0x12) ^ (x1 >> 0x11));
    x1 = (x1 << 1) & 0x7fffff;
    if (x & 1)
      return (x1 ^ 1);
  }
  return (x1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dunno_dec2>:
  endbr64
  mov    %edi,%edx
  sar    $0xb,%edx
  and    $0x1,%edx
  mov    %edi,%eax
  cmp    %esi,%edx
  je     L5
  lea    (%rdi,%rdi,1),%eax
  and    $0x7fffff,%eax
  mov    %edi,%edx
  sar    $0x15,%edx
  mov    %edi,%ecx
  sar    $0x16,%ecx
  xor    %ecx,%edx
  mov    %edi,%ecx
  sar    $0x12,%ecx
  xor    %ecx,%edx
  sar    $0x11,%edi
  xor    %edi,%edx
  mov    %eax,%ecx
  xor    $0x1,%ecx
  test   $0x1,%dl
  cmovne %ecx,%eax
L5:
  ret
```

assistant: ```c
uint32_t dunno_dec2(uint32_t x1, uint32_t x2) {
  uint32_t x;
  if (x2 ^ ((x1 >> 11) & 1)) {
    x = ((x1 >> 0x15) ^ (x1 >> 0x16) ^ (x1 >> 0x12) ^ (x1 >> 0x11));
    x1 = (x1 << 1) & 0x7fffff;
    if (x & 1)
      return (x1 ^ 1);
  }
  return (x1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dunno_dec2>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  sar    $0xb,%edx
  and    $0x1,%edx
  cmp    %esi,%edx
  je     L1
  mov    %edi,%edx
  mov    %edi,%ecx
  add    %eax,%eax
  sar    $0x16,%ecx
  sar    $0x15,%edx
  and    $0x7fffff,%eax
  xor    %ecx,%edx
  mov    %edi,%ecx
  sar    $0x11,%edi
  sar    $0x12,%ecx
  xor    %ecx,%edx
  mov    %eax,%ecx
  xor    %edi,%edx
  xor    $0x1,%ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
L1:
  ret
```

assistant: ```c
uint32_t dunno_dec2(uint32_t x1, uint32_t x2) {
  uint32_t x;
  if (x2 ^ ((x1 >> 11) & 1)) {
    x = ((x1 >> 0x15) ^ (x1 >> 0x16) ^ (x1 >> 0x12) ^ (x1 >> 0x11));
    x1 = (x1 << 1) & 0x7fffff;
    if (x & 1)
      return (x1 ^ 1);
  }
  return (x1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dunno_dec2>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  sar    $0xb,%edx
  and    $0x1,%edx
  cmp    %esi,%edx
  je     L3
  mov    %edi,%edx
  mov    %edi,%ecx
  add    %eax,%eax
  sar    $0x16,%ecx
  sar    $0x15,%edx
  and    $0x7fffff,%eax
  xor    %ecx,%edx
  mov    %edi,%ecx
  sar    $0x11,%edi
  sar    $0x12,%ecx
  xor    %ecx,%edx
  mov    %eax,%ecx
  xor    %edi,%edx
  xor    $0x1,%ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
L3:
  ret
```

assistant: ```c
uint32_t dunno_dec2(uint32_t x1, uint32_t x2) {
  uint32_t x;
  if (x2 ^ ((x1 >> 11) & 1)) {
    x = ((x1 >> 0x15) ^ (x1 >> 0x16) ^ (x1 >> 0x12) ^ (x1 >> 0x11));
    x1 = (x1 << 1) & 0x7fffff;
    if (x & 1)
      return (x1 ^ 1);
  }
  return (x1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<packforblock6_64>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%r8
  mov    %rdx,%rdi
  mov    (%rdx),%r9
  mov    (%rsi),%rdx
  mov    (%rdx),%r10d
  sub    %eax,%r10d
  mov    0x4(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x6,%ecx
  mov    0x8(%rdx),%esi
  sub    %eax,%esi
  shl    $0xc,%esi
  or     %esi,%ecx
  or     %r10d,%ecx
  mov    0xc(%rdx),%esi
  sub    %eax,%esi
  shl    $0x12,%esi
  or     %esi,%ecx
  mov    0x10(%rdx),%r10d
  sub    %eax,%r10d
  shl    $0x18,%r10d
  or     %ecx,%r10d
  mov    0x28(%rdx),%ecx
  sub    %eax,%ecx
  sar    $0x4,%ecx
  mov    0x2c(%rdx),%esi
  sub    %eax,%esi
  shl    $0x2,%esi
  or     %ecx,%esi
  mov    0x30(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x8,%ecx
  or     %esi,%ecx
  mov    0x34(%rdx),%esi
  sub    %eax,%esi
  shl    $0xe,%esi
  or     %ecx,%esi
  mov    0x38(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x14,%ecx
  or     %esi,%ecx
  mov    0x3c(%rdx),%esi
  sub    %eax,%esi
  shl    $0x1a,%esi
  or     %ecx,%esi
  mov    0x54(%rdx),%r11d
  sub    %eax,%r11d
  sar    $0x2,%r11d
  mov    0x58(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x4,%ecx
  or     %r11d,%ecx
  mov    0x5c(%rdx),%r11d
  sub    %eax,%r11d
  shl    $0xa,%r11d
  or     %ecx,%r11d
  mov    0x60(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x10,%ecx
  or     %r11d,%ecx
  mov    0x64(%rdx),%r11d
  sub    %eax,%r11d
  shl    $0x16,%r11d
  or     %ecx,%r11d
  mov    0x68(%rdx),%ecx
  sub    %eax,%ecx
  shl    $0x1c,%ecx
  or     %r11d,%ecx
  mov    0x14(%rdx),%edx
  sub    %eax,%edx
  mov    %edx,%eax
  shl    $0x1e,%eax
  or     %r10d,%eax
  mov    %eax,(%r9)
  mov    %esi,0x4(%r9)
  mov    %ecx,0x8(%r9)
  subq   $0xffffffffffffff80,(%r8)
  addq   $0x60,(%rdi)
  ret
```

assistant: ```c
void packforblock6_64(const uint64_t base, const uint64_t **pin, uint8_t **pw) {
  uint64_t *pw64 = *(uint64_t **)pw;
  const uint64_t *in = *pin;
  uint64_t w0;
  uint64_t w1;
  uint64_t w2;
  w0 = (in[0] - base);
  w0 |= (in[1] - base) << 6;
  w0 |= (in[2] - base) << 12;
  w0 |= (in[3] - base) << 18;
  w0 |= (in[4] - base) << 24;
  w0 |= (in[5] - base) << 30;
  w0 |= (in[6] - base) << 36;
  w0 |= (in[7] - base) << 42;
  w0 |= (in[8] - base) << 48;
  w0 |= (in[9] - base) << 54;
  w0 |= (in[10] - base) << 60;
  w1 = (in[10] - base) >> 4;
  w1 |= (in[11] - base) << 2;
  w1 |= (in[12] - base) << 8;
  w1 |= (in[13] - base) << 14;
  w1 |= (in[14] - base) << 20;
  w1 |= (in[15] - base) << 26;
  w1 |= (in[16] - base) << 32;
  w1 |= (in[17] - base) << 38;
  w1 |= (in[18] - base) << 44;
  w1 |= (in[19] - base) << 50;
  w1 |= (in[20] - base) << 56;
  w1 |= (in[21] - base) << 62;
  w2 = (in[21] - base) >> 2;
  w2 |= (in[22] - base) << 4;
  w2 |= (in[23] - base) << 10;
  w2 |= (in[24] - base) << 16;
  w2 |= (in[25] - base) << 22;
  w2 |= (in[26] - base) << 28;
  w2 |= (in[27] - base) << 34;
  w2 |= (in[28] - base) << 40;
  w2 |= (in[29] - base) << 46;
  w2 |= (in[30] - base) << 52;
  w2 |= (in[31] - base) << 58;
  pw64[0] = w0;
  pw64[1] = w1;
  pw64[2] = w2;
  *pin += 32;
  *pw += 24;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<packforblock6_64>:
  endbr64
  mov    (%rsi),%rax
  mov    %edi,%ecx
  mov    (%rdx),%r9
  mov    %rsi,%rdi
  mov    %rdx,%r8
  mov    0x8(%rax),%esi
  mov    0x4(%rax),%edx
  mov    (%rax),%r10d
  mov    0x10(%rax),%r11d
  sub    %ecx,%edx
  sub    %ecx,%esi
  shl    $0xc,%esi
  shl    $0x6,%edx
  sub    %ecx,%r10d
  sub    %ecx,%r11d
  or     %esi,%edx
  mov    0xc(%rax),%esi
  shl    $0x18,%r11d
  or     %r10d,%edx
  mov    0x54(%rax),%r10d
  sub    %ecx,%esi
  shl    $0x12,%esi
  sub    %ecx,%r10d
  or     %esi,%edx
  mov    0x2c(%rax),%esi
  sar    $0x2,%r10d
  or     %edx,%r11d
  mov    0x28(%rax),%edx
  sub    %ecx,%esi
  sub    %ecx,%edx
  shl    $0x2,%esi
  sar    $0x4,%edx
  or     %edx,%esi
  mov    0x30(%rax),%edx
  sub    %ecx,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  mov    0x34(%rax),%esi
  sub    %ecx,%esi
  shl    $0xe,%esi
  or     %edx,%esi
  mov    0x38(%rax),%edx
  sub    %ecx,%edx
  shl    $0x14,%edx
  or     %esi,%edx
  mov    0x3c(%rax),%esi
  sub    %ecx,%esi
  shl    $0x1a,%esi
  or     %edx,%esi
  mov    0x58(%rax),%edx
  sub    %ecx,%edx
  sub    $0xffffffffffffff80,%rax
  shl    $0x4,%edx
  or     %r10d,%edx
  mov    -0x24(%rax),%r10d
  sub    %ecx,%r10d
  shl    $0xa,%r10d
  or     %edx,%r10d
  mov    -0x20(%rax),%edx
  sub    %ecx,%edx
  shl    $0x10,%edx
  or     %r10d,%edx
  mov    -0x1c(%rax),%r10d
  sub    %ecx,%r10d
  shl    $0x16,%r10d
  or     %edx,%r10d
  mov    -0x18(%rax),%edx
  sub    %ecx,%edx
  shl    $0x1c,%edx
  or     %r10d,%edx
  mov    -0x6c(%rax),%r10d
  mov    %esi,0x4(%r9)
  mov    %edx,0x8(%r9)
  sub    %ecx,%r10d
  mov    %r10d,%ecx
  shl    $0x1e,%ecx
  or     %r11d,%ecx
  mov    %ecx,(%r9)
  mov    %rax,(%rdi)
  addq   $0x60,(%r8)
  ret
```

assistant: ```c
void packforblock6_64(const uint64_t base, const uint64_t **pin, uint8_t **pw) {
  uint64_t *pw64 = *(uint64_t **)pw;
  const uint64_t *in = *pin;
  uint64_t w0;
  uint64_t w1;
  uint64_t w2;
  w0 = (in[0] - base);
  w0 |= (in[1] - base) << 6;
  w0 |= (in[2] - base) << 12;
  w0 |= (in[3] - base) << 18;
  w0 |= (in[4] - base) << 24;
  w0 |= (in[5] - base) << 30;
  w0 |= (in[6] - base) << 36;
  w0 |= (in[7] - base) << 42;
  w0 |= (in[8] - base) << 48;
  w0 |= (in[9] - base) << 54;
  w0 |= (in[10] - base) << 60;
  w1 = (in[10] - base) >> 4;
  w1 |= (in[11] - base) << 2;
  w1 |= (in[12] - base) << 8;
  w1 |= (in[13] - base) << 14;
  w1 |= (in[14] - base) << 20;
  w1 |= (in[15] - base) << 26;
  w1 |= (in[16] - base) << 32;
  w1 |= (in[17] - base) << 38;
  w1 |= (in[18] - base) << 44;
  w1 |= (in[19] - base) << 50;
  w1 |= (in[20] - base) << 56;
  w1 |= (in[21] - base) << 62;
  w2 = (in[21] - base) >> 2;
  w2 |= (in[22] - base) << 4;
  w2 |= (in[23] - base) << 10;
  w2 |= (in[24] - base) << 16;
  w2 |= (in[25] - base) << 22;
  w2 |= (in[26] - base) << 28;
  w2 |= (in[27] - base) << 34;
  w2 |= (in[28] - base) << 40;
  w2 |= (in[29] - base) << 46;
  w2 |= (in[30] - base) << 52;
  w2 |= (in[31] - base) << 58;
  pw64[0] = w0;
  pw64[1] = w1;
  pw64[2] = w2;
  *pin += 32;
  *pw += 24;
}
```