ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<writefullnl>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  movb   $0xa,(%rsi,%rdx,1)
  add    $0x1,%r12
  je     L7
  mov    %edi,%ebp
  mov    %rsi,%rbx
  xor    %eax,%eax
  jmp    L26
  xchg   %ax,%ax
L34:
  cltq
  sub    %rax,%r12
  je     L7
L26:
  mov    %r12,%rdx
  lea    (%rbx,%rax,1),%rsi
  mov    %ebp,%edi
  sub    %rax,%rdx
  call   <write@plt>
  test   %eax,%eax
  jns    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int writefullnl(int fd, char *buf, size_t count) {
  int r = 0;
  *(buf + count++) = '\n';
  while (count > 0) {
    r = write(fd, buf + r, count - r);
    if (r < 0)
      return r;
    count -= r;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writefullnl>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  movb   $0xa,(%rsi,%rdx,1)
  add    $0x1,%r12
  je     L25
  mov    %edi,%ebp
  mov    %rsi,%rbx
  xor    %eax,%eax
  jmp    L29
  xchg   %ax,%ax
L23:
  cltq
  sub    %rax,%r12
  je     L25
L29:
  mov    %r12,%rdx
  lea    (%rbx,%rax,1),%rsi
  mov    %ebp,%edi
  sub    %rax,%rdx
  call   <write@plt>
  test   %eax,%eax
  jns    L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int writefullnl(int fd, char *buf, size_t count) {
  int r = 0;
  *(buf + count++) = '\n';
  while (count > 0) {
    r = write(fd, buf + r, count - r);
    if (r < 0)
      return r;
    count -= r;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<offset_is_aligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
bool offset_is_aligned(void *p, void *q) {
  uintptr_t x, y;
  x = (uintptr_t)p;
  y = (uintptr_t)q;
  assert(x <= y);
  return ((y - x) & (uintptr_t)7) == 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<offset_is_aligned>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmp    %rsi,%rdi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    %rbp,%rbx
  test   $0x7,%bl
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool offset_is_aligned(void *p, void *q) {
  uintptr_t x, y;
  x = (uintptr_t)p;
  y = (uintptr_t)q;
  assert(x <= y);
  return ((y - x) & (uintptr_t)7) == 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<offset_is_aligned>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rbp
  setbe  %dil
  sub    %rbp,%rbx
  call   <assert@plt>
  xor    %eax,%eax
  and    $0x7,%ebx
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool offset_is_aligned(void *p, void *q) {
  uintptr_t x, y;
  x = (uintptr_t)p;
  y = (uintptr_t)q;
  assert(x <= y);
  return ((y - x) & (uintptr_t)7) == 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<offset_is_aligned>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rbp
  setbe  %dil
  sub    %rbp,%rbx
  call   <assert@plt>
  xor    %eax,%eax
  and    $0x7,%ebx
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool offset_is_aligned(void *p, void *q) {
  uintptr_t x, y;
  x = (uintptr_t)p;
  y = (uintptr_t)q;
  assert(x <= y);
  return ((y - x) & (uintptr_t)7) == 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L19:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L26
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L26:
  nop
  leave
  ret
```

assistant: ```c
void get_extension(const char *file_name, char *extension) {
  while (*file_name++ != '.' && *file_name)
    ;
  if (*(--file_name) == '.')
    strcpy(extension, ++file_name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_extension>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
L11:
  add    $0x1,%rax
  cmpb   $0x2e,-0x1(%rax)
  je     L2
  cmpb   $0x0,(%rax)
  jne    L11
  ret
L2:
  sub    $0x8,%rsp
  mov    %rax,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void get_extension(const char *file_name, char *extension) {
  while (*file_name++ != '.' && *file_name)
    ;
  if (*(--file_name) == '.')
    strcpy(extension, ++file_name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_extension>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzbl (%r8),%eax
  jmp    L3
L26:
  movzbl (%r8),%eax
  test   %al,%al
  je     L22
L3:
  add    $0x1,%r8
  cmp    $0x2e,%al
  jne    L26
  mov    %r8,%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax,%rax,1)
L22:
  ret
```

assistant: ```c
void get_extension(const char *file_name, char *extension) {
  while (*file_name++ != '.' && *file_name)
    ;
  if (*(--file_name) == '.')
    strcpy(extension, ++file_name);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_extension>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  jmp    L1
  nopl   0x0(%rax)
L26:
  cmpb   $0x0,(%r8)
  je     L20
L1:
  add    $0x1,%r8
  cmpb   $0x2e,-0x1(%r8)
  jne    L26
  mov    %r8,%rsi
  jmp    1050 <strcpy@plt>
  nopl   0x0(%rax)
L20:
  ret
```

assistant: ```c
void get_extension(const char *file_name, char *extension) {
  while (*file_name++ != '.' && *file_name)
    ;
  if (*(--file_name) == '.')
    strcpy(extension, ++file_name);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtrm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L129
  cmpq   $0x0,-0x40(%rbp)
  jne    L73
L129:
  mov    $0x0,%eax
  jmp    L148
L73:
  mov    -0x38(%rbp),%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x48(%rbp)
  jne    L117
  mov    -0x38(%rbp),%rax
  jmp    L148
L117:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L25
L149:
  addq   $0x1,-0x28(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L123
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L149
L123:
  subq   $0x1,-0x20(%rbp)
  jmp    L132
L141:
  subq   $0x1,-0x20(%rbp)
L132:
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L33
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L141
L33:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L124
L127:
  mov    -0x30(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L5
  mov    -0x30(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L124:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L127
  jmp    L51
L5:
  nop
L51:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
L148:
  leave
  ret
```

assistant: ```c
char *strtrm(char buffer[], unsigned long buflen, const char *str) {
  const char *ps, *pstart, *pend;
  char *pb;
  unsigned long len;
  long unsigned int i;
  if ((!buffer) || (buflen < 1))
    return ((char *)NULL);
  buffer[0] = '\0';
  if (!str)
    return (buffer);
  len = strlen(str);
  pstart = str;
  pend = str + len;
  while ((pstart < pend) && is_white(*pstart))
    pstart++;
  pend--;
  while ((pstart < pend) && is_white(*pend))
    pend--;
  ps = pstart;
  pb = &buffer[0];
  for (i = 1; i < buflen; i++) {
    if (ps > pend)
      break;
    *pb++ = *ps++;
  }
  *pb = '\0';
  return (buffer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtrm>:
  endbr64
  test   %rdi,%rdi
  je     L146
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbx
  test   %rsi,%rsi
  je     L91
  movb   $0x0,(%rdi)
  test   %rdx,%rdx
  je     L108
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L95
L87:
  movsbl (%rbx),%edi
  call   <is_white@plt>
  test   %rax,%rax
  je     L95
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L87
  mov    %rbp,%rbx
L95:
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  jbe    L113
L118:
  movsbl 0x0(%rbp),%edi
  call   <is_white@plt>
  test   %rax,%rax
  je     L113
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L118
  mov    %rbx,%rbp
L113:
  cmp    %rbp,%rbx
  ja     L12
  cmp    $0x1,%r12
  jbe    L12
  mov    %r13,%rcx
  mov    %rbx,%rax
L85:
  add    $0x1,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rcx)
  lea    0x1(%rax),%rdx
  sub    %rbx,%rdx
  cmp    %rdx,%r12
  jbe    L49
  cmp    %rbp,%rax
  jbe    L85
L49:
  movb   $0x0,(%rcx)
  mov    %r13,%rax
L127:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %r13,%rcx
  jmp    L49
L91:
  mov    $0x0,%eax
  jmp    L127
L108:
  mov    %rdi,%rax
  jmp    L127
L146:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strtrm(char buffer[], unsigned long buflen, const char *str) {
  const char *ps, *pstart, *pend;
  char *pb;
  unsigned long len;
  long unsigned int i;
  if ((!buffer) || (buflen < 1))
    return ((char *)NULL);
  buffer[0] = '\0';
  if (!str)
    return (buffer);
  len = strlen(str);
  pstart = str;
  pend = str + len;
  while ((pstart < pend) && is_white(*pstart))
    pstart++;
  pend--;
  while ((pstart < pend) && is_white(*pend))
    pend--;
  ps = pstart;
  pb = &buffer[0];
  for (i = 1; i < buflen; i++) {
    if (ps > pend)
      break;
    *pb++ = *ps++;
  }
  *pb = '\0';
  return (buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strtrm>:
  endbr64
  test   %rdi,%rdi
  je     L37
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L11
  movb   $0x0,(%rdi)
  mov    %rdi,%r13
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L102
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jb     L12
  jmp    L132
  nopl   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L132
L12:
  movsbl (%rbx),%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L46
L132:
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  ja     L97
  jmp    L100
  nopl   0x0(%rax)
L66:
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L100
L97:
  movsbl 0x0(%rbp),%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L66
L100:
  mov    %r13,%rdx
  cmp    $0x1,%r12
  jbe    L119
  cmp    %rbp,%rbx
  ja     L119
  lea    0x1(%rbx),%rax
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L73:
  cmp    %rbp,%rsi
  ja     L119
L101:
  movzbl -0x1(%rax),%ecx
  mov    %rax,%rsi
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  mov    %rax,%rcx
  sub    %rbx,%rcx
  cmp    %rcx,%r12
  ja     L73
L119:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L102:
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strtrm(char buffer[], unsigned long buflen, const char *str) {
  const char *ps, *pstart, *pend;
  char *pb;
  unsigned long len;
  long unsigned int i;
  if ((!buffer) || (buflen < 1))
    return ((char *)NULL);
  buffer[0] = '\0';
  if (!str)
    return (buffer);
  len = strlen(str);
  pstart = str;
  pend = str + len;
  while ((pstart < pend) && is_white(*pstart))
    pstart++;
  pend--;
  while ((pstart < pend) && is_white(*pend))
    pend--;
  ps = pstart;
  pb = &buffer[0];
  for (i = 1; i < buflen; i++) {
    if (ps > pend)
      break;
    *pb++ = *ps++;
  }
  *pb = '\0';
  return (buffer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtrm>:
  endbr64
  test   %rdi,%rdi
  je     L55
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L50
  movb   $0x0,(%rdi)
  mov    %rdi,%r13
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L126
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jb     L44
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L87
L44:
  movsbl (%rbx),%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L12
L87:
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  ja     L130
  jmp    L25
  nopl   0x0(%rax)
L85:
  sub    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L25
L130:
  movsbl 0x0(%rbp),%edi
  call   <is_white@plt>
  test   %rax,%rax
  jne    L85
L25:
  mov    %r13,%rdx
  cmp    $0x1,%r12
  jbe    L78
  cmp    %rbp,%rbx
  ja     L78
  lea    0x1(%rbx),%rax
  jmp    L91
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    %rbp,%rsi
  ja     L78
L91:
  movzbl -0x1(%rax),%ecx
  mov    %rax,%rsi
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  mov    %rax,%rcx
  sub    %rbx,%rcx
  cmp    %rcx,%r12
  ja     L2
L78:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L126:
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strtrm(char buffer[], unsigned long buflen, const char *str) {
  const char *ps, *pstart, *pend;
  char *pb;
  unsigned long len;
  long unsigned int i;
  if ((!buffer) || (buflen < 1))
    return ((char *)NULL);
  buffer[0] = '\0';
  if (!str)
    return (buffer);
  len = strlen(str);
  pstart = str;
  pend = str + len;
  while ((pstart < pend) && is_white(*pstart))
    pstart++;
  pend--;
  while ((pstart < pend) && is_white(*pend))
    pend--;
  ps = pstart;
  pb = &buffer[0];
  for (i = 1; i < buflen; i++) {
    if (ps > pend)
      break;
    *pb++ = *ps++;
  }
  *pb = '\0';
  return (buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  je     L3
  cmpq   $0x0,-0x30(%rbp)
  jne    L104
L3:
  mov    D25(%rip),%rax
  mov    (%rax),%rdx
  mov    D35(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L114
L104:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
L60:
  lea    -0x1d(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L19
  mov    D35(%rip),%rax
  mov    (%rax),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L42
  mov    $0xffffffff,%eax
  jmp    L114
L19:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L108
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L114
L108:
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jae    L85
  addq   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x1d(%rbp),%edx
  mov    %dl,(%rax)
L85:
  movzbl -0x1d(%rbp),%eax
  cmp    $0xa,%al
  je     L136
  jmp    L60
L42:
  nop
  jmp    L60
L15:
  nop
  jmp    L39
L136:
  nop
L39:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L114:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L92
  call   <__stack_chk_fail@plt>
L92:
  leave
  ret
```

assistant: ```c
ssize_t read_line(int fd, void *buffer, size_t n) {
  ssize_t numRead;
  size_t totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  for (;;) {
    numRead = read(fd, &ch, 1);
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L45
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r14
  test   %rsi,%rsi
  je     L45
  mov    $0x0,%ebx
  lea    0x7(%rsp),%r13
  jmp    L86
L45:
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L27
L75:
  mov    D9(%rip),%rcx
  mov    D34(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L86
  jmp    L27
L9:
  test   %rbx,%rbx
  je     L27
L101:
  movb   $0x0,0x0(%rbp)
  mov    %ebx,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L108
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  cmpb   $0xa,0x7(%rsp)
  je     L101
L86:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L75
  test   %eax,%eax
  je     L9
  lea    -0x1(%r14),%rax
  cmp    %rbx,%rax
  jbe    L6
  add    $0x1,%rbx
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L6
L108:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t read_line(int fd, void *buffer, size_t n) {
  ssize_t numRead;
  size_t totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  for (;;) {
    numRead = read(fd, &ch, 1);
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L37
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L37
  mov    %edi,%r12d
  lea    0x7(%rsp),%r13
  lea    -0x1(%rdx),%r14
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L68:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L107
  test   %eax,%eax
  je     L74
  movzbl 0x7(%rsp),%eax
  cmp    %rbx,%r14
  jbe    L54
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
L54:
  cmp    $0xa,%al
  jne    L68
L83:
  movb   $0x0,0x0(%rbp)
  mov    %ebx,%eax
L62:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L85
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L107:
  mov    D7(%rip),%rdx
  mov    D33(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L68
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L74:
  test   %rbx,%rbx
  jne    L83
  jmp    L62
L37:
  mov    D31(%rip),%rax
  mov    (%rax),%rdx
  mov    D33(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L62
L85:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t read_line(int fd, void *buffer, size_t n) {
  ssize_t numRead;
  size_t totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  for (;;) {
    numRead = read(fd, &ch, 1);
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L3
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L3
  mov    %edi,%r12d
  lea    0x7(%rsp),%r13
  lea    -0x1(%rdx),%r14
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L93
  test   %eax,%eax
  je     L8
  movzbl 0x7(%rsp),%eax
  cmp    %rbx,%r14
  jbe    L90
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
L90:
  cmp    $0xa,%al
  jne    L34
L39:
  movb   $0x0,0x0(%rbp)
  mov    %ebx,%eax
L65:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L114
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L93:
  mov    D36(%rip),%rdx
  mov    D12(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L34
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L8:
  test   %rbx,%rbx
  jne    L39
  jmp    L65
L3:
  mov    D30(%rip),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L65
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t read_line(int fd, void *buffer, size_t n) {
  ssize_t numRead;
  size_t totRead;
  char *buf;
  char ch;
  if (n <= 0 || buffer == NULL) {
    errno = EINVAL;
    return -1;
  }
  buf = buffer;
  totRead = 0;
  for (;;) {
    numRead = read(fd, &ch, 1);
    if (numRead == -1) {
      if (errno == EINTR)
        continue;
      else
        return -1;
    } else if (numRead == 0) {
      if (totRead == 0)
        return 0;
      else
        break;
    } else {
      if (totRead < n - 1) {
        totRead++;
        *buf++ = ch;
      }
      if (ch == '\n')
        break;
    }
  }
  *buf = '\0';
  return totRead;
}
```