ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fib>:
  endbr64
  push   %rbp
  movslq %edi,%rax
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x8(%rbp)
  xor    %edx,%edx
  cmp    $0x1,%eax
  jle    L84
  lea    0x1(%rax),%edx
  mov    %rsp,%rsi
  movslq %edx,%rdx
  lea    0xf(,%rdx,8),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L6
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L42
L6:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L39
L2:
  lea    0x7(%rsp),%rsi
  mov    %rsi,%rdx
  and    $0xfffffffffffffff8,%rsi
  shr    $0x3,%rdx
  movq   $0x1,0x0(,%rdx,8)
  cmp    $0x2,%eax
  je     L88
  cmp    $0x4,%eax
  jle    L56
  mov    0x8(,%rdx,8),%r8
  lea    -0x5(%rax),%edx
  mov    $0x4,%ecx
  mov    $0x1,%edi
  shr    %edx
  lea    0x3(%rdx),%r9d
  add    %r9,%r9
L22:
  add    %r8,%rdi
  movslq %ecx,%rdx
  add    %rdi,%r8
  movq   %rdi,%xmm0
  movq   %r8,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x10(%rsi,%rcx,8)
  add    $0x2,%rcx
  cmp    %rcx,%r9
  jne    L22
  nopw   0x0(%rax,%rax,1)
L32:
  mov    -0x8(%rsi,%rdx,8),%rcx
  add    -0x10(%rsi,%rdx,8),%rcx
  mov    %rcx,(%rsi,%rdx,8)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L32
L88:
  mov    (%rsi,%rax,8),%rax
L84:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L2
L56:
  mov    $0x2,%edx
  jmp    L32
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long fib(int n) {
  if (n <= 1) {
    return n;
  }
  long arr[n + 1];
  arr[0] = 1;
  for (int i = 2; i < n; ++i) {
    arr[i] = arr[i - 1] + arr[i - 2];
  }
  return arr[n];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_new_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <empty_unit_counts@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L2
L0:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <empty_unit_pos_array@plt>
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <random_num@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <map_max_val@plt>
  mov    %eax,%edi
  call   <random_max@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x2c(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,%eax
  cltq
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
L2:
  leave
  ret
```

assistant: ```c
int set_new_num(int **map, int length) {
  int counts, pos, val;
  int *array;
  counts = empty_unit_counts(map, length);
  if (counts == 0) {
    return 0;
  }
  array = (int *)malloc(counts * sizeof(int));
  empty_unit_pos_array(array, map, length);
  pos = random_num(0, counts - 1);
  val = random_max(map_max_val(map, length));
  *(*(map + array[pos] / length) + array[pos] % length) = val;
  free(array);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_new_num>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  call   <empty_unit_counts@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L14
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <empty_unit_pos_array@plt>
  lea    -0x1(%rbx),%esi
  mov    $0x0,%edi
  call   <random_num@plt>
  mov    %eax,%ebx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <map_max_val@plt>
  mov    %eax,%edi
  call   <random_max@plt>
  mov    %eax,%ecx
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,4),%eax
  cltd
  idiv   %ebp
  cltq
  movslq %edx,%rdx
  mov    (%r12,%rax,8),%rax
  mov    %ecx,(%rax,%rdx,4)
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x1,%ebx
  jmp    L18
```

assistant: ```c
int set_new_num(int **map, int length) {
  int counts, pos, val;
  int *array;
  counts = empty_unit_counts(map, length);
  if (counts == 0) {
    return 0;
  }
  array = (int *)malloc(counts * sizeof(int));
  empty_unit_pos_array(array, map, length);
  pos = random_num(0, counts - 1);
  val = random_max(map_max_val(map, length));
  *(*(map + array[pos] / length) + array[pos] % length) = val;
  free(array);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_new_num>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <empty_unit_counts@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <empty_unit_pos_array@plt>
  lea    -0x1(%r12),%esi
  xor    %edi,%edi
  call   <random_num@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <map_max_val@plt>
  mov    %eax,%edi
  call   <random_max@plt>
  mov    %r13,%rdi
  mov    %eax,%r8d
  mov    0x0(%r13,%r12,4),%eax
  mov    $0x1,%r12d
  cltd
  idiv   %ebx
  cltq
  movslq %edx,%rdx
  mov    0x0(%rbp,%rax,8),%rax
  mov    %r8d,(%rax,%rdx,4)
  call   <free@plt>
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int set_new_num(int **map, int length) {
  int counts, pos, val;
  int *array;
  counts = empty_unit_counts(map, length);
  if (counts == 0) {
    return 0;
  }
  array = (int *)malloc(counts * sizeof(int));
  empty_unit_pos_array(array, map, length);
  pos = random_num(0, counts - 1);
  val = random_max(map_max_val(map, length));
  *(*(map + array[pos] / length) + array[pos] % length) = val;
  free(array);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_new_num>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <empty_unit_counts@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L5
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <empty_unit_pos_array@plt>
  lea    -0x1(%r12),%esi
  xor    %edi,%edi
  call   <random_num@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <map_max_val@plt>
  mov    %eax,%edi
  call   <random_max@plt>
  mov    %r13,%rdi
  mov    %eax,%r8d
  mov    0x0(%r13,%r12,4),%eax
  mov    $0x1,%r12d
  cltd
  idiv   %ebx
  cltq
  movslq %edx,%rdx
  mov    0x0(%rbp,%rax,8),%rax
  mov    %r8d,(%rax,%rdx,4)
  call   <free@plt>
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int set_new_num(int **map, int length) {
  int counts, pos, val;
  int *array;
  counts = empty_unit_counts(map, length);
  if (counts == 0) {
    return 0;
  }
  array = (int *)malloc(counts * sizeof(int));
  empty_unit_pos_array(array, map, length);
  pos = random_num(0, counts - 1);
  val = random_max(map_max_val(map, length));
  *(*(map + array[pos] / length) + array[pos] % length) = val;
  free(array);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_modify_job>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%r8
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <_xmit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld TIMELIMIT=10 BANK=test_bank

assistant: ```c
void _modify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld "
           "TIMELIMIT=10 BANK=test_bank",
           (uint32_t)now, my_job_id);
  _xmit(out_msg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_modify_job>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rsp,%rbp
  mov    %rbx,%r8
  mov    %eax,%ecx
  lea    D8(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld TIMELIMIT=10 BANK=test_bank

assistant: ```c
void _modify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld "
           "TIMELIMIT=10 BANK=test_bank",
           (uint32_t)now, my_job_id);
  _xmit(out_msg);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_modify_job>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x100,%esi
  mov    %eax,%ecx
  lea    D9(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld TIMELIMIT=10 BANK=test_bank

assistant: ```c
void _modify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld "
           "TIMELIMIT=10 BANK=test_bank",
           (uint32_t)now, my_job_id);
  _xmit(out_msg);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_modify_job>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %rbx,%r8
  mov    $0x100,%esi
  mov    %eax,%ecx
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <_xmit@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld TIMELIMIT=10 BANK=test_bank

assistant: ```c
void _modify_job(long my_job_id) {
  time_t now = time(NULL);
  char out_msg[256];
  snprintf(out_msg, sizeof(out_msg),
           "TS=%u AUTH=root DT=CMD=MODIFYJOB ARG=%ld "
           "TIMELIMIT=10 BANK=test_bank",
           (uint32_t)now, my_job_id);
  _xmit(out_msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  mov    $0x0,%eax
  call   <min@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D29: %d %d

tool: D19: a=%d,b=%d,max=%d


tool: D28: a=%d,b=%d,min=%d


assistant: ```c
void main() {
  int max(int, int);
  int min(int, int);
  int a, b, c;
  int (*p)();
  scanf("%d %d", &a, &b);
  c = max(a, b);
  p = min;
  printf("a=%d,b=%d,max=%d\n", a, b, c);
  printf("a=%d,b=%d,min=%d\n", a, b, (*p)(a, b));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D25(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  xor    %eax,%eax
  call   <min@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D8(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D8
type: string

tool: D2: %d %d

tool: D25: a=%d,b=%d,max=%d


tool: D8: a=%d,b=%d,min=%d


assistant: ```c
void main() {
  int max(int, int);
  int min(int, int);
  int a, b, c;
  int (*p)();
  scanf("%d %d", &a, &b);
  c = max(a, b);
  p = min;
  printf("a=%d,b=%d,max=%d\n", a, b, c);
  printf("a=%d,b=%d,min=%d\n", a, b, (*p)(a, b));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <max@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D3(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  xor    %eax,%eax
  call   <min@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D22(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string

tool: D1: %d %d

tool: D3: a=%d,b=%d,max=%d


tool: D22: a=%d,b=%d,min=%d


assistant: ```c
void main() {
  int max(int, int);
  int min(int, int);
  int a, b, c;
  int (*p)();
  scanf("%d %d", &a, &b);
  c = max(a, b);
  p = min;
  printf("a=%d,b=%d,max=%d\n", a, b, c);
  printf("a=%d,b=%d,min=%d\n", a, b, (*p)(a, b));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<auto_putter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x410(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x418(%rbp)
L8:
  movl   $0x0,-0x41c(%rbp)
  jmp    L64
L50:
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <buf_put@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x1,-0x414(%rbp)
  je     L73
  cmpl   $0x0,-0x414(%rbp)
  je     L73
  mov    $0xffffffff,%eax
  jmp    L20
L73:
  cmpl   $0x0,-0x414(%rbp)
  je     L50
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x71,%al
  je     L63
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x51,%al
  je     L63
  addl   $0x1,-0x41c(%rbp)
L64:
  mov    -0x41c(%rbp),%eax
  cmp    -0x418(%rbp),%eax
  jl     L50
L63:
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x71,%al
  je     L16
  mov    -0x41c(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x51,%al
  jne    L8
L16:
  mov    $0x0,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D6: auto_putter


tool: D17: Hello World! q

assistant: ```c
int auto_putter() {
  char string[1024 + 1];
  int string_length;
  int return_value;
  int i;
  printf("auto_putter\n");
  strcpy(string, "Hello World! q");
  string_length = strlen(string);
  do {
    for (i = 0; (i < string_length); i++) {
      do {
        return_value = buf_put(string[i]);
        if ((return_value != 1) && (return_value != 0)) {
          return -1;
        }
      } while (return_value == 0);
      if ((string[i] == 'q') || (string[i] == 'Q')) {
        break;
      }
    }
  } while ((string[i] != 'q') && (string[i] != 'Q'));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<auto_putter>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
L31:
  test   %ebp,%ebp
  jle    L12
  mov    %rsp,%rbx
  mov    $0x0,%r12d
L46:
  mov    %rbx,%r13
L81:
  movsbl (%rbx),%edi
  call   <buf_put@plt>
  cmp    $0x1,%eax
  ja     L19
  test   %eax,%eax
  je     L81
  movzbl 0x0(%r13),%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  je     L53
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  jne    L46
  mov    %ebp,%r12d
  jmp    L53
L12:
  mov    $0x0,%r12d
L53:
  movslq %r12d,%r12
  movzbl (%rsp,%r12,1),%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  jne    L31
  mov    $0x0,%eax
  jmp    L8
L19:
  mov    $0xffffffff,%eax
L8:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D17
type: string

tool: D5: auto_putter


tool: D17: Hello World! q

assistant: ```c
int auto_putter() {
  char string[1024 + 1];
  int string_length;
  int return_value;
  int i;
  printf("auto_putter\n");
  strcpy(string, "Hello World! q");
  string_length = strlen(string);
  do {
    for (i = 0; (i < string_length); i++) {
      do {
        return_value = buf_put(string[i]);
        if ((return_value != 1) && (return_value != 0)) {
          return -1;
        }
      } while (return_value == 0);
      if ((string[i] == 'q') || (string[i] == 'Q')) {
        break;
      }
    }
  } while ((string[i] != 'q') && (string[i] != 'Q'));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<auto_putter>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <printf@plt>
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%r14
  mov    %r14,%rbp
L73:
  movzbl (%rsp),%eax
  test   %ebp,%ebp
  jle    L92
  mov    %r12,%rbx
  xor    %r13d,%r13d
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L38:
  test   %eax,%eax
  jne    L50
L79:
  movsbl (%rbx),%edi
  call   <buf_put@plt>
  cmp    $0x1,%eax
  jbe    L38
  mov    $0xffffffff,%eax
L80:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L50:
  movzbl (%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x51,%al
  je     L57
  add    $0x1,%r13d
  add    $0x1,%rbx
  cmp    %r13d,%ebp
  jne    L79
  movzbl (%rsp,%r14,1),%eax
  and    $0xffffffdf,%eax
L18:
  cmp    $0x51,%al
  jne    L73
L57:
  xor    %eax,%eax
  jmp    L80
L92:
  and    $0xffffffdf,%eax
  jmp    L18
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D0: auto_putter


tool: D13: Hello World! q

assistant: ```c
int auto_putter() {
  char string[1024 + 1];
  int string_length;
  int return_value;
  int i;
  printf("auto_putter\n");
  strcpy(string, "Hello World! q");
  string_length = strlen(string);
  do {
    for (i = 0; (i < string_length); i++) {
      do {
        return_value = buf_put(string[i]);
        if ((return_value != 1) && (return_value != 0)) {
          return -1;
        }
      } while (return_value == 0);
      if ((string[i] == 'q') || (string[i] == 'Q')) {
        break;
      }
    }
  } while ((string[i] != 'q') && (string[i] != 'Q'));
  return 0;
}
```