ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x6,-0x14(%rbp)
  jne    L9
  mov    $0x7,%edi
  call   <bar@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L8
L9:
  mov    $0x7,%edi
  call   <bar@plt>
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(int y) {
  int a;
  if (y == 6)
    a = bar(7);
  else
    a = bar(7);
  baz(a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x6,%edi
  je     L10
  mov    $0x7,%edi
  call   <bar@plt>
  mov    %eax,%edi
L14:
  call   <baz@plt>
  add    $0x8,%rsp
  ret
L10:
  mov    $0x7,%edi
  call   <bar@plt>
  mov    %eax,%edi
  jmp    L14
```

assistant: ```c
void foo(int y) {
  int a;
  if (y == 6)
    a = bar(7);
  else
    a = bar(7);
  baz(a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edi
  call   <bar@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <baz@plt>
```

assistant: ```c
void foo(int y) {
  int a;
  if (y == 6)
    a = bar(7);
  else
    a = bar(7);
  baz(a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<store_standard_gamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  jmp    L20
L16:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2c,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp)
L20:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jg     L16
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int store_standard_gamma(int n, double *re_gamma, double *im_gamma) {
  int fail, i;
  int *b;
  double r[2];
  for (i = 0; i < n; i++) {
    r[0] = re_gamma[i];
    r[1] = im_gamma[i];
    fail = _ada_use_c2phc4c(44, &i, b, r, 0);
  }
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<store_standard_gamma>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  test   %edi,%edi
  jle    L11
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%edx
  lea    0x10(%rsp),%r13
L3:
  movslq %edx,%rdx
  movsd  0x0(%rbp,%rdx,8),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  (%r12,%rdx,8),%xmm0
  movsd  %xmm0,0x18(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    %r13,%rcx
  mov    $0x0,%edx
  mov    $0x2c,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0xc(%rsp),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,0xc(%rsp)
  cmp    %ebx,%edx
  jl     L3
L29:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0x0,%eax
  jmp    L29
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int store_standard_gamma(int n, double *re_gamma, double *im_gamma) {
  int fail, i;
  int *b;
  double r[2];
  for (i = 0; i < n; i++) {
    r[0] = re_gamma[i];
    r[1] = im_gamma[i];
    fail = _ada_use_c2phc4c(44, &i, b, r, 0);
  }
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<store_standard_gamma>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  test   %edi,%edi
  jle    L18
  mov    %rdx,%r14
  mov    %edi,%ebx
  mov    %rsi,%r13
  xor    %edx,%edx
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
L37:
  movslq %edx,%rdx
  mov    %r12,%rcx
  xor    %r8d,%r8d
  mov    %rbp,%rsi
  movsd  0x0(%r13,%rdx,8),%xmm0
  mov    $0x2c,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  (%r14,%rdx,8),%xmm0
  xor    %edx,%edx
  movsd  %xmm0,0x18(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0xc(%rsp),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,0xc(%rsp)
  cmp    %ebx,%edx
  jl     L37
L31:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L18:
  xor    %eax,%eax
  jmp    L31
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int store_standard_gamma(int n, double *re_gamma, double *im_gamma) {
  int fail, i;
  int *b;
  double r[2];
  for (i = 0; i < n; i++) {
    r[0] = re_gamma[i];
    r[1] = im_gamma[i];
    fail = _ada_use_c2phc4c(44, &i, b, r, 0);
  }
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<store_standard_gamma>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  test   %edi,%edi
  jle    L38
  mov    %rdx,%rbp
  mov    %edi,%ebx
  mov    %rsi,%r14
  xor    %edx,%edx
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
L5:
  movslq %edx,%rdx
  mov    %r13,%rcx
  xor    %r8d,%r8d
  mov    %r12,%rsi
  movsd  (%r14,%rdx,8),%xmm0
  mov    $0x2c,%edi
  movhpd 0x0(%rbp,%rdx,8),%xmm0
  xor    %edx,%edx
  movaps %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0xc(%rsp),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,0xc(%rsp)
  cmp    %ebx,%edx
  jl     L5
L2:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  jmp    L2
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int store_standard_gamma(int n, double *re_gamma, double *im_gamma) {
  int fail, i;
  int *b;
  double r[2];
  for (i = 0; i < n; i++) {
    r[0] = re_gamma[i];
    r[1] = im_gamma[i];
    fail = _ada_use_c2phc4c(44, &i, b, r, 0);
  }
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_sorted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L1:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <less_than@plt>
  test   %rax,%rax
  je     L20
  mov    $0x0,%eax
  jmp    L28
L20:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  mov    $0x1,%eax
L28:
  leave
  ret
```

assistant: ```c
int is_sorted(int n, int *x) {
  int i = 1;
  for (i; i < n; ++i)
    if (less_than(x[i], x[i - 1]))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x2(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
L36:
  mov    0x4(%rbx),%edi
  mov    (%rbx),%esi
  call   <less_than@plt>
  test   %rax,%rax
  jne    L9
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L36
  mov    $0x1,%eax
  jmp    L30
L7:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_sorted(int n, int *x) {
  int i = 1;
  for (i; i < n; ++i)
    if (less_than(x[i], x[i - 1]))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L32
  nopl   0x0(%rax)
L16:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L10
L32:
  mov    0x4(%rbx),%edi
  mov    (%rbx),%esi
  call   <less_than@plt>
  test   %rax,%rax
  je     L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_sorted(int n, int *x) {
  int i = 1;
  for (i; i < n; ++i)
    if (less_than(x[i], x[i - 1]))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_sorted>:
  endbr64
  cmp    $0x1,%edi
  jle    L24
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L27
  nopl   0x0(%rax)
L2:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L12
L27:
  mov    0x4(%rbx),%edi
  mov    (%rbx),%esi
  call   <less_than@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_sorted(int n, int *x) {
  int i = 1;
  for (i; i < n; ++i)
    if (less_than(x[i], x[i - 1]))
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LTE246QV_WriteWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  sar    $0x8,%ax
  cwtl
  mov    %eax,%edi
  call   <LTE246QV_WriteByte@plt>
  movswl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <LTE246QV_WriteByte@plt>
  nop
  leave
  ret
```

assistant: ```c
void LTE246QV_WriteWord(short data) {
  LTE246QV_WriteByte(data >> 8);
  LTE246QV_WriteByte(data & 0xff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LTE246QV_WriteWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0x8,%di
  movswl %di,%edi
  call   <LTE246QV_WriteByte@plt>
  movzbl %bl,%edi
  call   <LTE246QV_WriteByte@plt>
  pop    %rbx
  ret
```

assistant: ```c
void LTE246QV_WriteWord(short data) {
  LTE246QV_WriteByte(data >> 8);
  LTE246QV_WriteByte(data & 0xff);
}
```
user: What is the c source code of the assembly code below:

```asm
<LTE246QV_WriteWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0x8,%di
  movswl %di,%edi
  call   <LTE246QV_WriteByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <LTE246QV_WriteByte@plt>
```

assistant: ```c
void LTE246QV_WriteWord(short data) {
  LTE246QV_WriteByte(data >> 8);
  LTE246QV_WriteByte(data & 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LTE246QV_WriteWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sar    $0x8,%di
  movswl %di,%edi
  call   <LTE246QV_WriteByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <LTE246QV_WriteByte@plt>
```

assistant: ```c
void LTE246QV_WriteWord(short data) {
  LTE246QV_WriteByte(data >> 8);
  LTE246QV_WriteByte(data & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_grat_trie_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L46:
  addq   $0x1,-0x20(%rbp)
L25:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L44
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
L44:
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L12
L24:
  cmpq   $0x1,-0x10(%rbp)
  je     L39
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L39:
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L12:
  leave
  ret
```

assistant: ```c
size_t _grat_trie_strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_grat_trie_strlcat>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L16
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
L82:
  cmpb   $0x0,(%rax)
  je     L23
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L82
  mov    %rcx,%rax
L23:
  mov    %rax,%rbx
  sub    %r8,%rbx
  sub    %rbx,%rdx
  je     L74
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  test   %r8b,%r8b
  jne    L40
L34:
  movb   $0x0,(%rax)
  sub    %rsi,%rcx
  lea    (%rcx,%rbx,1),%rax
L47:
  pop    %rbx
  ret
L16:
  mov    %rdx,%rbx
L74:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  jmp    L47
L21:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L34
L40:
  cmp    $0x1,%rdx
  je     L21
  mov    %r8b,(%rax)
  sub    $0x1,%rdx
  lea    0x1(%rax),%rax
  jmp    L21
```

assistant: ```c
size_t _grat_trie_strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_grat_trie_strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L7
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L33
L85:
  cmpb   $0x0,(%rax)
  jne    L20
L33:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L16
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L66
  jmp    L37
  nopl   (%rax)
L69:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L48:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L79
L66:
  cmp    $0x1,%rdx
  jne    L69
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L48
  sub    %rsi,%rcx
  add    %rcx,%r12
L37:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L79:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L37
L7:
  xor    %r12d,%r12d
L16:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t _grat_trie_strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_grat_trie_strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L70
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L61
L86:
  cmpb   $0x0,(%rax)
  jne    L6
L61:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L30
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L36
  jmp    L81
  nopl   (%rax)
L75:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L67:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L34
L36:
  cmp    $0x1,%rdx
  jne    L75
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L67
  sub    %rsi,%rcx
  add    %rcx,%r12
L81:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L81
L70:
  xor    %r12d,%r12d
L30:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t _grat_trie_strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  size_t dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x5,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type: string

tool: D11: %d

assistant: ```c
int main(void) {
  int num;
  scanf("%d", &num);
  printf("%d", (num >> 5) & 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  sar    $0x5,%esi
  and    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
int main(void) {
  int num;
  scanf("%d", &num);
  printf("%d", (num >> 5) & 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  sar    $0x5,%esi
  and    $0x1,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %d

assistant: ```c
int main(void) {
  int num;
  scanf("%d", &num);
  printf("%d", (num >> 5) & 1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  sar    $0x5,%esi
  and    $0x1,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: %d

assistant: ```c
int main(void) {
  int num;
  scanf("%d", &num);
  printf("%d", (num >> 5) & 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <debug@plt>
  mov    -0x14(%rbp),%eax
  imul   $0x64,%eax,%eax
  mov    %eax,%edi
  call   <compute@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L72
  mov    $0x0,%eax
  movl   $0x0,(%rax)
L72:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  je     L1
  cmp    $0x2,%eax
  jg     L33
  test   %eax,%eax
  je     L69
  cmp    $0x1,%eax
  je     L20
  jmp    L33
L69:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <func1>
  jmp    L33
L20:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <func2@plt>
  jmp    L33
L1:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <func3@plt>
  nop
L33:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string

tool: D4: func1(%d)


assistant: ```c
void func1(int a) {
  debug("func1(%d)\n", a);
  compute(100 * a);
  int alea = rand() % 7;
  if (!alea)
    *(int *)0 = 0;
  switch (a % 3) {
  case 0:
    func1(a - 1);
    break;
  case 1:
    func2(a - 1);
    break;
  case 2:
    func3(a - 1);
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<func1>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <debug@plt>
  imul   $0x64,%ebx,%edi
  call   <compute@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  cmp    %ecx,%eax
  jne    L65
  movl   $0x0,0x0
L65:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L41
  cmp    $0x2,%eax
  je     L6
  test   %eax,%eax
  je     L54
L61:
  pop    %rbx
  ret
L54:
  lea    -0x1(%rbx),%edi
  call   <func1>
  jmp    L61
L41:
  lea    -0x1(%rbx),%edi
  call   <func2@plt>
  jmp    L61
L6:
  lea    -0x1(%rbx),%edi
  call   <func3@plt>
  jmp    L61
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: func1(%d)


assistant: ```c
void func1(int a) {
  debug("func1(%d)\n", a);
  compute(100 * a);
  int alea = rand() % 7;
  if (!alea)
    *(int *)0 = 0;
  switch (a % 3) {
  case 0:
    func1(a - 1);
    break;
  case 1:
    func2(a - 1);
    break;
  case 2:
    func3(a - 1);
    break;
  }
}
```