ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L10
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbx,%rbp
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
  movb   $0x0,0x0(%rbp)
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *s) {
  if (s == NULL)
    return NULL;
  char *back = s + strlen(s);
  while (isspace(*--back))
    ;
  *(back + 1) = '\0';
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<glmAdd3fv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L15:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L0:
  cmpq   $0x2,-0x8(%rbp)
  jbe    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmAdd3fv(float out[3], const float x[3], const float y[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] + y[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmAdd3fv>:
  endbr64
  mov    $0x0,%eax
L2:
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L2
  ret
```

assistant: ```c
void glmAdd3fv(float out[3], const float x[3], const float y[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] + y[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmAdd3fv>:
  endbr64
  xor    %eax,%eax
L8:
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L8
  ret
```

assistant: ```c
void glmAdd3fv(float out[3], const float x[3], const float y[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] + y[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmAdd3fv>:
  endbr64
  lea    0x4(%rdx),%rcx
  mov    %rdi,%rax
  cmp    %rcx,%rdi
  je     L0
  lea    0x4(%rsi),%rcx
  cmp    %rcx,%rdi
  je     L0
  movq   (%rsi),%xmm0
  movq   (%rdx),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rax)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rax)
  ret
```

assistant: ```c
void glmAdd3fv(float out[3], const float x[3], const float y[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] + y[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64636261,-0x97(%rbp)
  movw   $0x6665,-0x93(%rbp)
  movb   $0x0,-0x91(%rbp)
  lea    -0x97(%rbp),%rax
  add    $0x1,%rax
  lea    -0x90(%rbp),%rcx
  mov    $0x3,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %s


assistant: ```c
int main() {
  char buf[128];
  char test[] = "abcdef";
  strncpy(buf, test + 1, 3);
  printf("%s\n", buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movl   $0x64636261,0x9(%rsp)
  movw   $0x6665,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0xa(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: %s


assistant: ```c
int main() {
  char buf[128];
  char test[] = "abcdef";
  strncpy(buf, test + 1, 3);
  printf("%s\n", buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    $0x6665,%eax
  lea    0xa(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x64636261,0x9(%rsp)
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: %s


assistant: ```c
int main() {
  char buf[128];
  char test[] = "abcdef";
  strncpy(buf, test + 1, 3);
  printf("%s\n", buf);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    $0x6665,%eax
  lea    0xa(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x64636261,0x9(%rsp)
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: %s


assistant: ```c
int main() {
  char buf[128];
  char test[] = "abcdef";
  strncpy(buf, test + 1, 3);
  printf("%s\n", buf);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <testit@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0x2(%rbp)
  cmpl   $0x16,-0x14(%rbp)
  sete   %al
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  jne    L14
  movzbl -0x1(%rbp),%eax
  xor    $0x1,%eax
  test   %al,%al
  je     L11
L14:
  mov    $0x0,%eax
  call   <oof@plt>
L11:
  nop
  leave
  ret
```

assistant: ```c
void test_8(int code) {
  _Bool temp = testit();
  _Bool rotate = (code == 22);
  if (temp == 0 || !rotate)
    oof();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <testit@plt>
  test   %eax,%eax
  je     L2
  cmp    $0x16,%ebx
  jne    L2
L18:
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <oof@plt>
  jmp    L18
```

assistant: ```c
void test_8(int code) {
  _Bool temp = testit();
  _Bool rotate = (code == 22);
  if (temp == 0 || !rotate)
    oof();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_8>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <testit@plt>
  test   %eax,%eax
  je     L13
  cmp    $0x16,%ebx
  jne    L13
  pop    %rbx
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <oof@plt>
```

assistant: ```c
void test_8(int code) {
  _Bool temp = testit();
  _Bool rotate = (code == 22);
  if (temp == 0 || !rotate)
    oof();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_8>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <testit@plt>
  test   %eax,%eax
  je     L12
  cmp    $0x16,%ebx
  jne    L12
  pop    %rbx
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <oof@plt>
```

assistant: ```c
void test_8(int code) {
  _Bool temp = testit();
  _Bool rotate = (code == 22);
  if (temp == 0 || !rotate)
    oof();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<logLevel2Name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L112
  lea    D39(%rip),%rax
  jmp    L79
L112:
  cmpl   $0x2,-0x4(%rbp)
  jne    L73
  lea    D50(%rip),%rax
  jmp    L79
L73:
  cmpl   $0x3,-0x4(%rbp)
  jne    L71
  lea    D27(%rip),%rax
  jmp    L79
L71:
  cmpl   $0x4,-0x4(%rbp)
  jne    L116
  lea    D27(%rip),%rax
  jmp    L79
L116:
  cmpl   $0x5,-0x4(%rbp)
  jne    L24
  lea    D33(%rip),%rax
  jmp    L79
L24:
  cmpl   $0x6,-0x4(%rbp)
  jne    L110
  lea    D33(%rip),%rax
  jmp    L79
L110:
  cmpl   $0x7,-0x4(%rbp)
  jne    L139
  lea    D33(%rip),%rax
  jmp    L79
L139:
  lea    D79(%rip),%rax
L79:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D50
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D33
datatype: string
name: extract_symbolic_data
arguments: data_tag: D79
datatype: string

tool: D39: DEB

tool: D50: INF

tool: D27: WAR

tool: D33: ERR

tool: 

assistant: ```c
char *logLevel2Name(int lvl) {
  if (lvl == 1) {
    return "DEB";
  }
  if (lvl == 2) {
    return "INF";
  }
  if (lvl == 3) {
    return "WAR";
  }
  if (lvl == 4) {
    return "WAR";
  }
  if (lvl == 5) {
    return "ERR";
  }
  if (lvl == 6) {
    return "ERR";
  }
  if (lvl == 7) {
    return "ERR";
  }
  return "";
}
```
user: Translate the below assembly code into C programming language:

```asm
<logLevel2Name>:
  endbr64
  cmp    $0x7,%edi
  ja     L1
  mov    %edi,%edi
  lea    D65(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D59(%rip),%rax
  ret
  lea    D70(%rip),%rax
  ret
  lea    D60(%rip),%rax
  ret
  lea    D60(%rip),%rax
  ret
  lea    D52(%rip),%rax
  ret
  lea    D52(%rip),%rax
  ret
  lea    D52(%rip),%rax
  ret
L1:
  lea    D48(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D59
type_infered: string
name: read_data
arguments: tag: D70
type_infered: string
name: read_data
arguments: tag: D60
type_infered: string
name: read_data
arguments: tag: D52
type_infered: string
name: read_data
arguments: tag: D48
type_infered: string

tool: D59: DEB

tool: D70: INF

tool: D60: WAR

tool: D52: ERR

tool: 

assistant: ```c
char *logLevel2Name(int lvl) {
  if (lvl == 1) {
    return "DEB";
  }
  if (lvl == 2) {
    return "INF";
  }
  if (lvl == 3) {
    return "WAR";
  }
  if (lvl == 4) {
    return "WAR";
  }
  if (lvl == 5) {
    return "ERR";
  }
  if (lvl == 6) {
    return "ERR";
  }
  if (lvl == 7) {
    return "ERR";
  }
  return "";
}
```
user: What is the c source code of the assembly code below:

```asm
<logLevel2Name>:
  endbr64
  cmp    $0x4,%edi
  jg     L7
  lea    D37(%rip),%rax
  cmp    $0x2,%edi
  jg     L14
  lea    D1(%rip),%rax
  cmp    $0x1,%edi
  je     L14
  cmp    $0x2,%edi
  lea    D17(%rip),%rdx
  lea    D46(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  sub    $0x5,%edi
  lea    D13(%rip),%rax
  lea    D46(%rip),%rdx
  cmp    $0x3,%edi
  cmovae %rdx,%rax
L14:
  ret
```

tool_calls: name: parse_data
arguments: tag: D37
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D46
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string

tool: D37: WAR

tool: D1: DEB

tool: D17: INF

tool: 

tool: D13: ERR

assistant: ```c
char *logLevel2Name(int lvl) {
  if (lvl == 1) {
    return "DEB";
  }
  if (lvl == 2) {
    return "INF";
  }
  if (lvl == 3) {
    return "WAR";
  }
  if (lvl == 4) {
    return "WAR";
  }
  if (lvl == 5) {
    return "ERR";
  }
  if (lvl == 6) {
    return "ERR";
  }
  if (lvl == 7) {
    return "ERR";
  }
  return "";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<logLevel2Name>:
  endbr64
  cmp    $0x4,%edi
  jg     L18
  lea    D32(%rip),%rax
  cmp    $0x2,%edi
  jg     L7
  lea    D4(%rip),%rax
  cmp    $0x1,%edi
  je     L7
  cmp    $0x2,%edi
  lea    D9(%rip),%rdx
  lea    D57(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x5,%edi
  lea    D13(%rip),%rax
  lea    D57(%rip),%rdx
  cmp    $0x3,%edi
  cmovae %rdx,%rax
L7:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D32
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D57
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string

tool: D32: WAR

tool: D4: DEB

tool: D9: INF

tool: 

tool: D13: ERR

assistant: ```c
char *logLevel2Name(int lvl) {
  if (lvl == 1) {
    return "DEB";
  }
  if (lvl == 2) {
    return "INF";
  }
  if (lvl == 3) {
    return "WAR";
  }
  if (lvl == 4) {
    return "WAR";
  }
  if (lvl == 5) {
    return "ERR";
  }
  if (lvl == 6) {
    return "ERR";
  }
  if (lvl == 7) {
    return "ERR";
  }
  return "";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bpnn_zero_weights>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L37:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L21
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bpnn_zero_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bpnn_zero_weights>:
  endbr64
  test   %esi,%esi
  js     L38
  mov    %rdi,%r8
  mov    %esi,%esi
  lea    0x8(%rdi,%rsi,8),%rdi
  mov    %edx,%eax
  lea    0x8(,%rax,8),%rsi
  jmp    L24
L53:
  mov    (%r8),%rcx
  movq   $0x0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L53
L45:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L38
L24:
  mov    $0x0,%eax
  test   %edx,%edx
  jns    L53
  jmp    L45
L38:
  ret
```

assistant: ```c
void bpnn_zero_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bpnn_zero_weights>:
  endbr64
  test   %esi,%esi
  js     L6
  push   %r13
  movslq %esi,%rsi
  mov    %edx,%eax
  push   %r12
  lea    0x8(,%rax,8),%r13
  lea    0x8(%rdi,%rsi,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  test   %ebp,%ebp
  js     L25
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L25:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

assistant: ```c
void bpnn_zero_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bpnn_zero_weights>:
  endbr64
  mov    %esi,%eax
  or     %edx,%eax
  js     L14
  mov    %esi,%esi
  mov    %edx,%edx
  push   %r12
  lea    0x8(%rdi,%rsi,8),%r12
  push   %rbp
  lea    0x8(,%rdx,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %rbx,%r12
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

assistant: ```c
void bpnn_zero_weights(w, m, n) double **w;
int m, n;
{
  int i, j;
  for (i = 0; i <= m; i++) {
    for (j = 0; j <= n; j++) {
      w[i][j] = 0.0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_tzcnt_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L14:
  addl   $0x1,-0x4(%rbp)
  sarl   -0x14(%rbp)
L0:
  cmpl   $0x1f,-0x4(%rbp)
  jg     L4
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calc_tzcnt_u32(int src) {
  int i;
  int res = 0;
  while ((res < 32) && ((src & 1) == 0)) {
    ++res;
    src >>= 1;
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calc_tzcnt_u32>:
  endbr64
  mov    %edi,%edx
  sar    %edx
  mov    $0x1,%eax
  test   $0x1,%dil
  jne    L19
L4:
  test   $0x1,%dl
  jne    L9
  add    $0x1,%eax
  sar    %edx
  cmp    $0x20,%eax
  jne    L4
L9:
  ret
L19:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int calc_tzcnt_u32(int src) {
  int i;
  int res = 0;
  while ((res < 32) && ((src & 1) == 0)) {
    ++res;
    src >>= 1;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_tzcnt_u32>:
  endbr64
  xor    %eax,%eax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x20,%eax
  je     L7
L6:
  test   $0x1,%dil
  je     L23
L7:
  ret
```

assistant: ```c
int calc_tzcnt_u32(int src) {
  int i;
  int res = 0;
  while ((res < 32) && ((src & 1) == 0)) {
    ++res;
    src >>= 1;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_tzcnt_u32>:
  endbr64
  xor    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%eax
  sar    %edi
  cmp    $0x20,%eax
  je     L3
L21:
  test   $0x1,%dil
  je     L9
L3:
  ret
```

assistant: ```c
int calc_tzcnt_u32(int src) {
  int i;
  int res = 0;
  while ((res < 32) && ((src & 1) == 0)) {
    ++res;
    src >>= 1;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L50
  mov    -0x20(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x28(%rbp),%rax
  lea    D43(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L92
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  cmpl   $0x0,-0x1c(%rbp)
  jle    L51
  mov    -0x30(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L51
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L54
L51:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L93
L92:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L93:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L75
L6:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L75
L50:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L75:
  mov    $0x0,%eax
L54:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D26
datatype: string
name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D30
datatype: string
name: parse_data
arguments: label: D29
datatype: string

tool: D43: r

tool: D17: w

tool: D26: fopen dest

tool: D1: fopen src

tool: D30: calloc

tool: D29: stat

assistant: ```c
int cp(const char *src, const char *dest) {
  struct stat st;
  int r;
  if (stat(src, &st) == 0) {
    char *buf = calloc(st.st_size, 1);
    if (buf) {
      FILE *fp = fopen(src, "r");
      if (fp) {
        r = fread(buf, 1, st.st_size, fp);
        fclose(fp);
        if (r > 0 && (fp = fopen(dest, "w"))) {
          fwrite(buf, r, 1, fp);
          fclose(fp);
          return 1;
        } else {
          perror("fopen dest");
        }
      } else {
        perror("fopen src");
      }
      free(buf);
    } else {
      perror("calloc");
    }
  } else {
    perror("stat");
  }
  return 0;
}
```