ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D66(%rip),%rbx
  jmp    L31
L2:
  lea    D1(%rip),%rdi
  call   <printf@plt>
L31:
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  je     L13
  pxor   %xmm4,%xmm4
  cvtsi2sd %edx,%xmm4
  movapd %xmm4,%xmm0
  divsd  D39(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm2,%xmm5
  subsd  %xmm1,%xmm5
  divsd  D50(%rip),%xmm2
  movapd %xmm4,%xmm1
  mulsd  D0(%rip),%xmm1
  minsd  %xmm1,%xmm2
  movsd  D62(%rip),%xmm1
  movapd %xmm0,%xmm3
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  mulsd  %xmm5,%xmm3
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  comisd %xmm0,%xmm3
  jbe    L2
  movapd %xmm3,%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D66
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: byte[8]
name: retrieve_data
arguments: label: D50
type_infered: byte[8]
name: retrieve_data
arguments: label: D0
type_infered: f32[2]
name: retrieve_data
arguments: label: D62
type_infered: byte[8]

tool: D66: %d %d

tool: D1: %.3lf


tool: {"D39": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D50": [0x8c,0x16,0x22,0xaa,0xfd,0x90,0x20,0x40]}

tool: {"D0": [0.0,1.75]}

tool: {"D62": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

assistant: ```c
int main() {
  int wid, height;
  double r1, h1, r2, h2, v1, v2;
  while (1) {
    scanf("%d %d", &wid, &height);
    if (!wid && !height)
      break;
    r1 = wid / (2.0 * 2.0 * acos(0.0));
    h1 = height - 2 * r1;
    r2 = ((height / (2.0 * (2.0 * acos(0.0) + 1.0))) < (wid / 2.0) ? (height / (2.0 * (2.0 * acos(0.0) + 1.0))) : (wid / 2.0));
    h2 = wid;
    v1 = (2.0 * acos(0.0) * r1 * r1 * h1);
    v2 = (2.0 * acos(0.0) * r2 * r2 * h2);
    if (v1 > v2)
      printf("%.3lf\n", v1);
    else
      printf("%.3lf\n", v2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D54(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  je     L40
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm3
  cvtsi2sd %eax,%xmm1
  movapd %xmm3,%xmm0
  divsd  D33(%rip),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  movapd %xmm1,%xmm4
  divsd  D1(%rip),%xmm1
  subsd  %xmm2,%xmm4
  movsd  D30(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  minsd  %xmm2,%xmm1
  movsd  D26(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D26(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  comisd %xmm0,%xmm2
  jbe    L15
  movapd %xmm2,%xmm0
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L15:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  nopl   0x0(%rax)
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D54
data_type: string
name: unpack_data
arguments: label: D33
data_type: byte[8]
name: unpack_data
arguments: label: D1
data_type: byte[8]
name: unpack_data
arguments: label: D30
data_type: f32[2]
name: unpack_data
arguments: label: D26
data_type: byte[8]
name: unpack_data
arguments: label: D45
data_type: string

tool: D54: %d %d

tool: {"D33": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D1": [0x8c,0x16,0x22,0xaa,0xfd,0x90,0x20,0x40]}

tool: {"D30": [0.0,1.75]}

tool: {"D26": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

tool: D45: %.3lf


assistant: ```c
int main() {
  int wid, height;
  double r1, h1, r2, h2, v1, v2;
  while (1) {
    scanf("%d %d", &wid, &height);
    if (!wid && !height)
      break;
    r1 = wid / (2.0 * 2.0 * acos(0.0));
    h1 = height - 2 * r1;
    r2 = ((height / (2.0 * (2.0 * acos(0.0) + 1.0))) < (wid / 2.0) ? (height / (2.0 * (2.0 * acos(0.0) + 1.0))) : (wid / 2.0));
    h2 = wid;
    v1 = (2.0 * acos(0.0) * r1 * r1 * h1);
    v2 = (2.0 * acos(0.0) * r2 * r2 * h2);
    if (v1 > v2)
      printf("%.3lf\n", v1);
    else
      printf("%.3lf\n", v2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  je     L49
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm3
  cvtsi2sd %eax,%xmm1
  movapd %xmm3,%xmm0
  divsd  D73(%rip),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  movapd %xmm1,%xmm4
  divsd  D31(%rip),%xmm1
  subsd  %xmm2,%xmm4
  movsd  D7(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  minsd  %xmm2,%xmm1
  movsd  D8(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm2
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  comisd %xmm0,%xmm2
  jbe    L40
  movapd %xmm2,%xmm0
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L40:
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  nopl   0x0(%rax)
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D73
type: byte[8]
name: unpack_data
arguments: data_tag: D31
type: byte[8]
name: unpack_data
arguments: data_tag: D7
type: f32[2]
name: unpack_data
arguments: data_tag: D8
type: byte[8]
name: unpack_data
arguments: data_tag: D72
type: string

tool: D17: %d %d

tool: {"D73": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D31": [0x8c,0x16,0x22,0xaa,0xfd,0x90,0x20,0x40]}

tool: {"D7": [0.0,1.75]}

tool: {"D8": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

tool: D72: %.3lf


assistant: ```c
int main() {
  int wid, height;
  double r1, h1, r2, h2, v1, v2;
  while (1) {
    scanf("%d %d", &wid, &height);
    if (!wid && !height)
      break;
    r1 = wid / (2.0 * 2.0 * acos(0.0));
    h1 = height - 2 * r1;
    r2 = ((height / (2.0 * (2.0 * acos(0.0) + 1.0))) < (wid / 2.0) ? (height / (2.0 * (2.0 * acos(0.0) + 1.0))) : (wid / 2.0));
    h2 = wid;
    v1 = (2.0 * acos(0.0) * r1 * r1 * h1);
    v2 = (2.0 * acos(0.0) * r2 * r2 * h2);
    if (v1 > v2)
      printf("%.3lf\n", v1);
    else
      printf("%.3lf\n", v2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_str_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x68(%rbp)
  mov    %al,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movzbl -0x5c(%rbp),%eax
  mov    %al,-0x1a(%rbp)
  movb   $0x0,-0x19(%rbp)
  jmp    L48
L6:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5c(%rbp)
  jne    L32
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
L32:
  addq   $0x1,-0x48(%rbp)
L48:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x40(%rbp)
  setb   %al
  movzbl %al,%edx
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L30
  movq   $0x0,-0x38(%rbp)
  lea    -0x1a(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x30(%rbp)
  jmp    L3
L60:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  lea    -0x1a(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x30(%rbp)
L3:
  cmpq   $0x0,-0x30(%rbp)
  jne    L60
L30:
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **_str_split(char *a_str, const char a_delim, int *count) {
  char **result = 0;
  char *tmp = a_str;
  char *last_delim = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      ++(*count);
      last_delim = tmp;
    }
    ++tmp;
  }
  (*count) += last_delim < (a_str + strlen(a_str) - 1);
  result = calloc((*count), sizeof(char *));
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = strdup(token);
      token = strtok(0, delim);
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<_str_split>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L88
  mov    %esi,%ecx
  mov    %rdi,%rax
  mov    $0x0,%ebp
  jmp    L86
L6:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L26
L86:
  cmp    %dl,%cl
  jne    L6
  addl   $0x1,(%rbx)
  mov    %rax,%rbp
  jmp    L6
L88:
  mov    $0x0,%ebp
L26:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmp    %rax,%rbp
  mov    (%rbx),%edi
  adc    $0x0,%edi
  mov    %edi,(%rbx)
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L58
  lea    0x6(%rsp),%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L58
  mov    %rbp,%rbx
  lea    0x6(%rsp),%r12
L27:
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L27
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **_str_split(char *a_str, const char a_delim, int *count) {
  char **result = 0;
  char *tmp = a_str;
  char *last_delim = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      ++(*count);
      last_delim = tmp;
    }
    ++tmp;
  }
  (*count) += last_delim < (a_str + strlen(a_str) - 1);
  result = calloc((*count), sizeof(char *));
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = strdup(token);
      token = strtok(0, delim);
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_str_split>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  test   %cl,%cl
  je     L61
  mov    %esi,%edx
  mov    %rdi,%rax
  xor    %ebp,%ebp
L76:
  cmp    %cl,%dl
  jne    L63
  addl   $0x1,(%rbx)
  mov    %rax,%rbp
L63:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  jne    L76
L15:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    (%rbx),%edi
  mov    $0x8,%esi
  cltq
  lea    -0x1(%r13,%rax,1),%rax
  cmp    %rax,%rbp
  adc    $0x0,%edi
  mov    %edi,(%rbx)
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
  lea    0x6(%rsp),%rbp
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  mov    %r12,%rbx
  nopl   0x0(%rax)
L25:
  call   <strdup@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L25
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L61:
  xor    %ebp,%ebp
  jmp    L15
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **_str_split(char *a_str, const char a_delim, int *count) {
  char **result = 0;
  char *tmp = a_str;
  char *last_delim = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      ++(*count);
      last_delim = tmp;
    }
    ++tmp;
  }
  (*count) += last_delim < (a_str + strlen(a_str) - 1);
  result = calloc((*count), sizeof(char *));
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = strdup(token);
      token = strtok(0, delim);
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_str_split>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %sil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  test   %cl,%cl
  je     L22
  mov    %esi,%edx
  mov    %rdi,%rax
  xor    %ebp,%ebp
L23:
  cmp    %cl,%dl
  je     L95
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  jne    L23
L18:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    (%rbx),%edi
  mov    $0x8,%esi
  cltq
  lea    -0x1(%r13,%rax,1),%rax
  cmp    %rax,%rbp
  adc    $0x0,%edi
  mov    %edi,(%rbx)
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L59
  lea    0x6(%rsp),%rbp
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L59
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L42:
  call   <strdup@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  add    $0x8,%rbx
  mov    %rax,-0x8(%rbx)
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L42
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L95:
  addl   $0x1,(%rbx)
  movzbl 0x1(%rax),%ecx
  lea    0x1(%rax),%rsi
  mov    %rax,%rbp
  test   %cl,%cl
  je     L18
  mov    %rsi,%rax
  jmp    L23
  xchg   %ax,%ax
L22:
  xor    %ebp,%ebp
  jmp    L18
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **_str_split(char *a_str, const char a_delim, int *count) {
  char **result = 0;
  char *tmp = a_str;
  char *last_delim = 0;
  char delim[2];
  delim[0] = a_delim;
  delim[1] = 0;
  while (*tmp) {
    if (a_delim == *tmp) {
      ++(*count);
      last_delim = tmp;
    }
    ++tmp;
  }
  (*count) += last_delim < (a_str + strlen(a_str) - 1);
  result = calloc((*count), sizeof(char *));
  if (result) {
    size_t idx = 0;
    char *token = strtok(a_str, delim);
    while (token) {
      *(result + idx++) = strdup(token);
      token = strtok(0, delim);
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reservar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: f64

tool: D4: 1

assistant: ```c
double *reservar(int puntos) {
  double *array = malloc(puntos * sizeof(double));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 1.0;
  }
  return array;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reservar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L16
  mov    %rax,%rdx
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%rcx
  movsd  D7(%rip),%xmm0
L2:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L2
L16:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: f64

tool: D7: 1

assistant: ```c
double *reservar(int puntos) {
  double *array = malloc(puntos * sizeof(double));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 1.0;
  }
  return array;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reservar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L13
  movsd  D6(%rip),%xmm0
  mov    %rax,%rdx
  lea    (%rax,%rbx,8),%rcx
  cs nopw 0x0(%rax,%rax,1)
L6:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L6
L13:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double *reservar(int puntos) {
  double *array = malloc(puntos * sizeof(double));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 1.0;
  }
  return array;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reservar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shl    $0x3,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L5
  cmp    $0x1,%ebx
  je     L49
  mov    %ebx,%ecx
  movapd D17(%rip),%xmm0
  mov    %rax,%rdx
  shr    %ecx
  shl    $0x4,%rcx
  add    %rax,%rcx
  xchg   %ax,%ax
L44:
  movups %xmm0,(%rdx)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L44
  mov    %ebx,%edx
  and    $0xfffffffe,%edx
  and    $0x1,%ebx
  je     L5
L47:
  mov    D17(%rip),%rsi
  movslq %edx,%rdx
  mov    %rsi,(%rax,%rdx,8)
L5:
  pop    %rbx
  ret
L49:
  xor    %edx,%edx
  jmp    L47
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type: f64[2]

tool: {"D17": [1.0,1.0]}

assistant: ```c
double *reservar(int puntos) {
  double *array = malloc(puntos * sizeof(double));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 1.0;
  }
  return array;
}
```
user: What is the c source code of the assembly code below:

```asm
<patch_firmware_tcc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %esi,%ebp
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%r13d
  mov    %r8,0x10(%rsp)
  lea    (%rsi,%rcx,1),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  mov    %ebp,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebp,%r14
  lea    (%rbx,%r14,1),%r15
  mov    %r13d,%edx
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <get_uint32le@plt>
  and    $0xfff,%eax
  lea    0x8(%rbx,%rax,1),%r13
  mov    %r13,%rdi
  call   <get_uint32le@plt>
  mov    %eax,0x1c(%rsp)
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x20000008(%rbp),%eax
  mov    %eax,0x8(%rsp)
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    0x1c(%rsp),%edi
  call   <put_uint32le@plt>
  lea    0x4(%rbx,%r14,1),%rsi
  lea    0x20000000(%rbp),%edi
  call   <put_uint32le@plt>
  mov    %r13,%rsi
  mov    0x8(%rsp),%edi
  call   <put_uint32le@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <telechips_encode_crc@plt>
  mov    0x10(%rsp),%rax
  mov    %r12d,(%rax)
L7:
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: string

tool: D5: OF entry point: 0x%08x


tool: D19: New entry point: 0x%08x


assistant: ```c
unsigned char *patch_firmware_tcc(unsigned char *of_buf, int of_size, unsigned char *boot_buf, int boot_size, int *patched_size) {
  unsigned char *patched_buf;
  uint32_t ldr, old_ep_offset, new_ep_offset;
  int of_offset;
  patched_buf = malloc(of_size + boot_size);
  if (!patched_buf)
    return NULL;
  memcpy(patched_buf, of_buf, of_size);
  memcpy(patched_buf + of_size, boot_buf, boot_size);
  ldr = get_uint32le(patched_buf);
  of_offset = (ldr & 0xfff) + 8;
  old_ep_offset = get_uint32le(patched_buf + of_offset);
  new_ep_offset = 0x20000000 + of_size;
  printf("OF entry point: 0x%08x\n", old_ep_offset);
  printf("New entry point: 0x%08x\n", new_ep_offset + 8);
  put_uint32le(old_ep_offset, patched_buf + of_size);
  put_uint32le(new_ep_offset, patched_buf + of_size + 4);
  put_uint32le(new_ep_offset + 8, patched_buf + of_offset);
  telechips_encode_crc(patched_buf, of_size + boot_size);
  *patched_size = of_size + boot_size;
  return patched_buf;
}
```