ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L13
L8:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  sar    %eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int parent(int i) {
  if (i == 0)
    return 0;
  else
    return ((i - 1) >> 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parent>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rdi),%edx
  sar    %edx
  test   %edi,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int parent(int i) {
  if (i == 0)
    return 0;
  else
    return ((i - 1) >> 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parent>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    %edi,%eax
  sar    %edx
  test   %edi,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int parent(int i) {
  if (i == 0)
    return 0;
  else
    return ((i - 1) >> 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parent>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    %edi,%eax
  sar    %edx
  test   %edi,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int parent(int i) {
  if (i == 0)
    return 0;
  else
    return ((i - 1) >> 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L35
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%esi
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  xor    %eax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x7,-0xc(%rbp)
  jle    L21
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int result = 0x00;
  char *iter;
  int i;
  for (i = 0; i < 8; i++) {
    iter = s;
    while (*iter) {
      result ^= (*iter & 0xFF) << (i * 3);
      iter++;
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%r9d
  mov    $0x0,%r8d
  mov    $0x0,%esi
L11:
  mov    %r8d,%ecx
  mov    %rdi,%rdx
  mov    %r9d,%eax
  test   %r9b,%r9b
  je     L13
L28:
  movzbl %al,%eax
  shl    %cl,%eax
  xor    %eax,%esi
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L28
L13:
  add    $0x3,%r8d
  cmp    $0x18,%r8d
  jne    L11
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int result = 0x00;
  char *iter;
  int i;
  for (i = 0; i < 8; i++) {
    iter = s;
    while (*iter) {
      result ^= (*iter & 0xFF) << (i * 3);
      iter++;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash>:
  endbr64
  movzbl (%rdi),%esi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %rdi,%rdx
  movzbl %sil,%eax
  test   %sil,%sil
  je     L17
  nopl   0x0(%rax)
L9:
  shl    %cl,%eax
  add    $0x1,%rdx
  xor    %eax,%r8d
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L9
L17:
  add    $0x3,%ecx
  cmp    $0x18,%ecx
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int result = 0x00;
  char *iter;
  int i;
  for (i = 0; i < 8; i++) {
    iter = s;
    while (*iter) {
      result ^= (*iter & 0xFF) << (i * 3);
      iter++;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%esi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %rdi,%rdx
  movzbl %sil,%eax
  test   %sil,%sil
  je     L22
  nopl   0x0(%rax)
L18:
  shl    %cl,%eax
  add    $0x1,%rdx
  xor    %eax,%r8d
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L18
L22:
  add    $0x3,%ecx
  cmp    $0x18,%ecx
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int result = 0x00;
  char *iter;
  int i;
  for (i = 0; i < 8; i++) {
    iter = s;
    while (*iter) {
      result ^= (*iter & 0xFF) << (i * 3);
      iter++;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<load_filemap_contents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0xfffffffe,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L11
  movl   $0xfffffffd,-0x18(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  js     L47
  movl   $0xffffffff,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L80
  movl   $0xfffffffc,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0x1c(%rbp),%edx
  cmp    %edx,%eax
  jne    L1
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L7
L11:
  nop
  jmp    L61
L47:
  nop
  jmp    L61
L80:
  nop
  jmp    L61
L1:
  nop
L61:
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L83
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L83:
  cmpq   $0x0,-0x10(%rbp)
  je     L70
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L70:
  mov    -0x18(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  leave
  ret
```

assistant: ```c
int load_filemap_contents(const char *file, char **area, int *size) {
  struct stat st;
  char *p = NULL;
  int status = 0;
  int fd = -1;
  status = -2;
  if ((fd = open(file, 0)) < 0)
    goto err;
  status = -3;
  if (fstat(fd, &st) < 0)
    goto err;
  status = -1;
  if ((p = (char *)malloc(st.st_size)) == NULL)
    goto err;
  status = -4;
  if (read(fd, p, st.st_size) != st.st_size)
    goto err;
  close(fd);
  *area = p;
  *size = st.st_size;
  return 0;
err:
  if (fd != -1)
    close(fd);
  if (p != NULL)
    free(p);
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load_filemap_contents>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L116
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  js     L10
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L102
  mov    %ebx,%edi
  call   <close@plt>
  test   %r13,%r13
  je     L118
  mov    $0xffffffff,%ebx
L84:
  mov    %r13,%rdi
  call   <free@plt>
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L102:
  mov    0x4(%rsp),%edx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    0x4(%rsp),%eax
  je     L18
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xfffffffc,%ebx
  jmp    L84
L18:
  mov    %ebx,%edi
  call   <close@plt>
  mov    %r13,(%r12)
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%ebx
  jmp    L69
L118:
  mov    $0xffffffff,%ebx
  jmp    L69
L116:
  cmp    $0xffffffff,%eax
  jne    L86
  mov    $0xfffffffe,%ebx
  jmp    L69
L86:
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xfffffffe,%ebx
  jmp    L69
L10:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xfffffffd,%ebx
  jmp    L69
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int load_filemap_contents(const char *file, char **area, int *size) {
  struct stat st;
  char *p = NULL;
  int status = 0;
  int fd = -1;
  status = -2;
  if ((fd = open(file, 0)) < 0)
    goto err;
  status = -3;
  if (fstat(fd, &st) < 0)
    goto err;
  status = -1;
  if ((p = (char *)malloc(st.st_size)) == NULL)
    goto err;
  status = -4;
  if (read(fd, p, st.st_size) != st.st_size)
    goto err;
  close(fd);
  *area = p;
  *size = st.st_size;
  return 0;
err:
  if (fd != -1)
    close(fd);
  if (p != NULL)
    free(p);
  return status;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<load_filemap_contents>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L106
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  js     L51
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L87
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L0
  nopl   0x0(%rax)
L51:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffd,%eax
  nopl   0x0(%rax)
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L106:
  cmp    $0xffffffff,%eax
  jne    L17
  mov    $0xfffffffe,%eax
  jmp    L0
  nopl   0x0(%rax)
L87:
  mov    0x4(%rsp),%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  call   <read@plt>
  mov    %ebp,%edi
  cmp    0x4(%rsp),%eax
  je     L98
  call   <close@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0xfffffffc,%eax
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L98:
  call   <close@plt>
  mov    0x4(%rsp),%eax
  mov    %r13,(%r12)
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L0
L48:
  call   <__stack_chk_fail@plt>
L17:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffe,%eax
  jmp    L0
```

assistant: ```c
int load_filemap_contents(const char *file, char **area, int *size) {
  struct stat st;
  char *p = NULL;
  int status = 0;
  int fd = -1;
  status = -2;
  if ((fd = open(file, 0)) < 0)
    goto err;
  status = -3;
  if (fstat(fd, &st) < 0)
    goto err;
  status = -1;
  if ((p = (char *)malloc(st.st_size)) == NULL)
    goto err;
  status = -4;
  if (read(fd, p, st.st_size) != st.st_size)
    goto err;
  close(fd);
  *area = p;
  *size = st.st_size;
  return 0;
err:
  if (fd != -1)
    close(fd);
  if (p != NULL)
    free(p);
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<load_filemap_contents>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L92
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  js     L56
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L78
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L105
  nopl   0x0(%rax)
L56:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffd,%eax
  nopl   0x0(%rax)
L105:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  cmp    $0xffffffff,%eax
  jne    L3
  mov    $0xfffffffe,%eax
  jmp    L105
  nopl   0x0(%rax)
L78:
  mov    0x4(%rsp),%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  call   <read@plt>
  mov    %ebp,%edi
  cmp    0x4(%rsp),%eax
  je     L50
  call   <close@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0xfffffffc,%eax
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L50:
  call   <close@plt>
  mov    0x4(%rsp),%eax
  mov    %r13,(%r12)
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L105
L70:
  call   <__stack_chk_fail@plt>
L3:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffe,%eax
  jmp    L105
```

assistant: ```c
int load_filemap_contents(const char *file, char **area, int *size) {
  struct stat st;
  char *p = NULL;
  int status = 0;
  int fd = -1;
  status = -2;
  if ((fd = open(file, 0)) < 0)
    goto err;
  status = -3;
  if (fstat(fd, &st) < 0)
    goto err;
  status = -1;
  if ((p = (char *)malloc(st.st_size)) == NULL)
    goto err;
  status = -4;
  if (read(fd, p, st.st_size) != st.st_size)
    goto err;
  close(fd);
  *area = p;
  *size = st.st_size;
  return 0;
err:
  if (fd != -1)
    close(fd);
  if (p != NULL)
    free(p);
  return status;
}
```
user: What is the c source code of the assembly code below:

```asm
<kol_screen_get_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xe,%eax
  int    $0x40
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kol_screen_get_size(unsigned *w, unsigned *h) {
  unsigned size;
  asm("int $0x40" : "=a"(size) : "a"(14));
  *w = size / 65536;
  *h = size % 65536;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kol_screen_get_size>:
  endbr64
  mov    $0xe,%eax
  int    $0x40
  mov    %eax,%edx
  shr    $0x10,%edx
  mov    %edx,(%rdi)
  and    $0xffff,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void kol_screen_get_size(unsigned *w, unsigned *h) {
  unsigned size;
  asm("int $0x40" : "=a"(size) : "a"(14));
  *w = size / 65536;
  *h = size % 65536;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kol_screen_get_size>:
  endbr64
  mov    $0xe,%eax
  int    $0x40
  mov    %eax,%edx
  and    $0xffff,%eax
  shr    $0x10,%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void kol_screen_get_size(unsigned *w, unsigned *h) {
  unsigned size;
  asm("int $0x40" : "=a"(size) : "a"(14));
  *w = size / 65536;
  *h = size % 65536;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kol_screen_get_size>:
  endbr64
  mov    $0xe,%eax
  int    $0x40
  mov    %eax,%edx
  and    $0xffff,%eax
  shr    $0x10,%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void kol_screen_get_size(unsigned *w, unsigned *h) {
  unsigned size;
  asm("int $0x40" : "=a"(size) : "a"(14));
  *w = size / 65536;
  *h = size % 65536;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<del>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <search@plt>
  test   %rax,%rax
  jne    L48
  movsbl -0x1c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L63
L28:
  movl   $0x0,-0xc(%rbp)
  jmp    L69
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L13
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L56:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L56
L13:
  addl   $0x1,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
L48:
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <search@plt>
  test   %rax,%rax
  jne    L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L63:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D15: Not found %c in "%s"

tool: D0: %s

assistant: ```c
void del(char *p, char c) {
  const int length = strlen(p);
  if (search(p, c) == 0)
    printf("Not found %c in \"%s\"", c, p);
  else {
    while (search(p, c) != 0) {
      for (int i = 0; p[i] != '\0'; i++) {
        if (p[i] == c) {
          for (int j = i; j < length; j++)
            p[j] = p[j + 1];
        }
      }
    }
    printf("%s", p);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<del>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%r13d
  movsbl %r12b,%r12d
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <search@plt>
  lea    -0x1(%r13),%r14d
  test   %rax,%rax
  je     L99
L16:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <search@plt>
  test   %rax,%rax
  je     L47
  movzbl 0x0(%rbp),%eax
  mov    %rbp,%rdx
  mov    $0x0,%esi
  test   %al,%al
  jne    L24
  jmp    L16
L99:
  mov    %rbp,%rdx
  mov    %r12d,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L88:
  add    $0x1,%esi
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L16
L24:
  cmp    %al,%bl
  jne    L88
  cmp    %esi,%r13d
  jle    L88
  mov    %r14d,%eax
  sub    %esi,%eax
  lea    0x1(%rdx,%rax,1),%rdi
  mov    %rdx,%rax
L42:
  movzbl 0x1(%rax),%ecx
  mov    %cl,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L42
  jmp    L88
L47:
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D15: Not found %c in "%s"

tool: D16: %s

assistant: ```c
void del(char *p, char c) {
  const int length = strlen(p);
  if (search(p, c) == 0)
    printf("Not found %c in \"%s\"", c, p);
  else {
    while (search(p, c) != 0) {
      for (int i = 0; p[i] != '\0'; i++) {
        if (p[i] == c) {
          for (int j = i; j < length; j++)
            p[j] = p[j + 1];
        }
      }
    }
    printf("%s", p);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<del>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  movsbl %r14b,%r14d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <search@plt>
  test   %rax,%rax
  je     L19
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <search@plt>
  test   %rax,%rax
  je     L15
  movzbl (%r15),%eax
  lea    0x1(%r15),%rbx
  mov    $0x1,%ebp
  test   %al,%al
  jne    L17
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L72:
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %al,%al
  je     L20
L17:
  cmp    %al,%r12b
  jne    L72
  lea    -0x1(%rbp),%eax
  cmp    %eax,%r13d
  jle    L72
  mov    %r13d,%edx
  lea    -0x1(%rbx),%rdi
  mov    %rbx,%rsi
  sub    %ebp,%edx
  add    $0x1,%rdx
  call   <memmove@plt>
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    %r15,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
L19:
  add    $0x8,%rsp
  mov    %r15,%rdx
  mov    %r14d,%esi
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D15: %s

tool: D13: Not found %c in "%s"

assistant: ```c
void del(char *p, char c) {
  const int length = strlen(p);
  if (search(p, c) == 0)
    printf("Not found %c in \"%s\"", c, p);
  else {
    while (search(p, c) != 0) {
      for (int i = 0; p[i] != '\0'; i++) {
        if (p[i] == c) {
          for (int j = i; j < length; j++)
            p[j] = p[j + 1];
        }
      }
    }
    printf("%s", p);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<del>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  movsbl %r14b,%r14d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14d,%esi
  mov    %r15,%rdi
  mov    %eax,%r13d
  call   <search@plt>
  test   %rax,%rax
  je     L29
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <search@plt>
  test   %rax,%rax
  je     L76
  movzbl (%r15),%eax
  lea    0x1(%r15),%rbx
  mov    $0x1,%ebp
  test   %al,%al
  jne    L37
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L47:
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %al,%al
  je     L14
L37:
  cmp    %al,%r12b
  jne    L47
  lea    -0x1(%rbp),%eax
  cmp    %r13d,%eax
  jge    L47
  mov    %r13d,%edx
  lea    -0x1(%rbx),%rdi
  mov    %rbx,%rsi
  sub    %ebp,%edx
  add    $0x1,%rdx
  call   <memmove@plt>
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L76:
  add    $0x8,%rsp
  mov    %r15,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
L29:
  add    $0x8,%rsp
  mov    %r15,%rdx
  mov    %r14d,%esi
  pop    %rbx
  lea    D12(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string

tool: D11: %s

tool: D12: Not found %c in "%s"

assistant: ```c
void del(char *p, char c) {
  const int length = strlen(p);
  if (search(p, c) == 0)
    printf("Not found %c in \"%s\"", c, p);
  else {
    while (search(p, c) != 0) {
      for (int i = 0; p[i] != '\0'; i++) {
        if (p[i] == c) {
          for (int j = i; j < length; j++)
            p[j] = p[j + 1];
        }
      }
    }
    printf("%s", p);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x64,-0x10(%rbp)
  movl   $0xc8,-0xc(%rbp)
  movl   $0x1e,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  cmp    %eax,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a = 100, b = 200, c = 30, result;
  result = b < a < c;
  printf("%d\n", result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a = 100, b = 200, c = 30, result;
  result = b < a < c;
  printf("%d\n", result);
  return 0;
}
```