ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<string_cmp>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r13,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L30
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L62:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %dil,%dil
  je     L50
L30:
  cmpb   $0x0,0x0(%rbp)
  je     L50
  call   <isdigit@plt>
  test   %rax,%rax
  je     L62
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L62
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  sub    %r13d,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L62
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strtol@plt>
  mov    $0xffffffff,%edx
  cmp    %rax,%r12
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L50:
  add    $0x8,%rsp
  mov    %r14,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <strcasecmp@plt>
```

assistant: ```c
int string_cmp(char *a, char *b) {
  char *p1, *p2;
  for (p1 = a, p2 = b; *p1 && *p2; p1++, p2++) {
    if (isdigit(*p1) && isdigit(*p2) && (strncmp(a, b, (p1 - a)) == 0)) {
      long int n1 = strtol(p1, NULL, 10);
      long int n2 = strtol(p2, NULL, 10);
      return (n1 < n2) ? (-1) : (n1 > n2) ? (1) : (0);
    }
  }
  return strcasecmp(a, b);
}
```
user: What is the c source code of the assembly code below?

```asm
<XchompConvert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0xa,-0x4(%rbp)
  je     L19
  cmpb   $0x9,-0x4(%rbp)
  je     L19
  cmpb   $0xd,-0x4(%rbp)
  jne    L11
L19:
  mov    $0x20,%eax
  jmp    L12
L11:
  cmpb   $0x1,-0x4(%rbp)
  jne    L38
  mov    $0xa,%eax
  jmp    L12
L38:
  movzbl -0x4(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
XML_Char XchompConvert(XML_Char c) {
  if (c == '\n' || c == '\t' || c == '\r')
    return ' ';
  if (c == 1)
    return '\n';
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<XchompConvert>:
  endbr64
  mov    %edi,%eax
  lea    -0x9(%rdi),%edx
  cmp    $0x1,%dl
  jbe    L2
  cmp    $0xd,%dil
  je     L2
  cmp    $0x1,%dil
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
L2:
  mov    $0x20,%eax
  ret
```

assistant: ```c
XML_Char XchompConvert(XML_Char c) {
  if (c == '\n' || c == '\t' || c == '\r')
    return ' ';
  if (c == 1)
    return '\n';
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<XchompConvert>:
  endbr64
  lea    -0x9(%rdi),%edx
  mov    %edi,%eax
  cmp    $0x1,%dl
  jbe    L8
  cmp    $0xd,%dil
  je     L8
  cmp    $0x1,%dil
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x20,%eax
  ret
```

assistant: ```c
XML_Char XchompConvert(XML_Char c) {
  if (c == '\n' || c == '\t' || c == '\r')
    return ' ';
  if (c == 1)
    return '\n';
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<XchompConvert>:
  endbr64
  lea    -0x9(%rdi),%edx
  mov    %edi,%eax
  cmp    $0x1,%dl
  jbe    L12
  cmp    $0xd,%dil
  je     L12
  cmp    $0x1,%dil
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x20,%eax
  ret
```

assistant: ```c
XML_Char XchompConvert(XML_Char c) {
  if (c == '\n' || c == '\t' || c == '\r')
    return ' ';
  if (c == 1)
    return '\n';
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fc8300_ppi_bytewrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %esi,%ecx
  mov    %cx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movw   $0x1,-0x2(%rbp)
  movb   $0x0,-0x3(%rbp)
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl -0x20(%rbp),%eax
  shr    $0x8,%ax
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzwl -0x20(%rbp),%eax
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzbl -0x3(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzwl -0x2(%rbp),%eax
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzbl -0x24(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fc8300_ppi_bytewrite(void *handle, unsigned short devid, unsigned short addr, unsigned char data) {
  unsigned short length = 1;
  unsigned char command = 0x00;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  outb(data, 0x00);
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fc8300_ppi_bytewrite>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    %ecx,%ebp
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzbl %bh,%edi
  mov    $0x0,%esi
  call   <outb@plt>
  movzbl %bl,%edi
  mov    $0x0,%esi
  call   <outb@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  movzbl %bpl,%edi
  mov    $0x0,%esi
  call   <outb@plt>
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_bytewrite(void *handle, unsigned short devid, unsigned short addr, unsigned char data) {
  unsigned short length = 1;
  unsigned char command = 0x00;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  outb(data, 0x00);
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fc8300_ppi_bytewrite>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzbl %bh,%edi
  xor    %esi,%esi
  call   <outb@plt>
  movzbl %bl,%edi
  xor    %esi,%esi
  call   <outb@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  movzbl %bpl,%edi
  xor    %esi,%esi
  call   <outb@plt>
  xor    %eax,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_bytewrite(void *handle, unsigned short devid, unsigned short addr, unsigned char data) {
  unsigned short length = 1;
  unsigned char command = 0x00;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  outb(data, 0x00);
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fc8300_ppi_bytewrite>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzbl %bh,%edi
  xor    %esi,%esi
  call   <outb@plt>
  movzbl %bl,%edi
  xor    %esi,%esi
  call   <outb@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <outb@plt>
  movzbl %bpl,%edi
  xor    %esi,%esi
  call   <outb@plt>
  xor    %eax,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_bytewrite(void *handle, unsigned short devid, unsigned short addr, unsigned char data) {
  unsigned short length = 1;
  unsigned char command = 0x00;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  outb(data, 0x00);
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gatecappass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm2
  movsd  D35(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D18(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
data_type: f64
name: extract_symbolic_data
arguments: label: D17
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D35
data_type: byte[8]

tool: D18: 0.8

tool: {"D17": [0xd3,0x3c,0x9c,0xd9,0xf1,0x1e,0xda,0x3c]}

tool: {"D35": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xb2,0x3c]}

assistant: ```c
double gatecappass(width, wirelength)
double width;
double wirelength;
{ return (width * 0.8 * 1.45e-15 + wirelength * 0.25e-15 * 0.8); }
```
user: What is the c source code of the assembly code below?

```asm
<gatecappass>:
  endbr64
  movsd  D17(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D5(%rip),%xmm0
  mulsd  D1(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type_infered: f64
name: read_data
arguments: tag: D5
type_infered: byte[8]
name: read_data
arguments: tag: D1
type_infered: byte[8]

tool: D17: 0.8

tool: {"D5": [0xd3,0x3c,0x9c,0xd9,0xf1,0x1e,0xda,0x3c]}

tool: {"D1": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xb2,0x3c]}

assistant: ```c
double gatecappass(width, wirelength)
double width;
double wirelength;
{ return (width * 0.8 * 1.45e-15 + wirelength * 0.25e-15 * 0.8); }
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gatecappass>:
  endbr64
  mulsd  D24(%rip),%xmm1
  movsd  D6(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D25(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
type: byte[8]
name: parse_data
arguments: data_tag: D6
type: f64
name: parse_data
arguments: data_tag: D25
type: byte[8]

tool: {"D24": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xb2,0x3c]}

tool: D6: 0.8

tool: {"D25": [0xd3,0x3c,0x9c,0xd9,0xf1,0x1e,0xda,0x3c]}

assistant: ```c
double gatecappass(width, wirelength)
double width;
double wirelength;
{ return (width * 0.8 * 1.45e-15 + wirelength * 0.25e-15 * 0.8); }
```
user: What is the c source code of the assembly code below:

```asm
<gatecappass>:
  endbr64
  mulsd  D10(%rip),%xmm1
  movsd  D19(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D13(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_infered: byte[8]
name: disassemble_data
arguments: tag: D19
type_infered: f64
name: disassemble_data
arguments: tag: D13
type_infered: byte[8]

tool: {"D10": [0x16,0x56,0xe7,0x9e,0xaf,0x03,0xb2,0x3c]}

tool: D19: 0.8

tool: {"D13": [0xd3,0x3c,0x9c,0xd9,0xf1,0x1e,0xda,0x3c]}

assistant: ```c
double gatecappass(width, wirelength)
double width;
double wirelength;
{ return (width * 0.8 * 1.45e-15 + wirelength * 0.25e-15 * 0.8); }
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movq   $0x6,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  cqto
  idivq  -0x8(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 3, b = 2;
  long c = 6;
  int d = a / b;
  int e = a % b;
  int f = a / c;
  return d + e + f;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3, b = 2;
  long c = 6;
  int d = a / b;
  int e = a % b;
  int f = a / c;
  return d + e + f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3, b = 2;
  long c = 6;
  int d = a / b;
  int e = a % b;
  int f = a / c;
  return d + e + f;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main() {
  int a = 3, b = 2;
  long c = 6;
  int d = a / b;
  int e = a % b;
  int f = a / c;
  return d + e + f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RBTprintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x34(%rbp)
  jle    L68
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L47:
  cmp    %rdx,%rsp
  je     L63
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L47
L63:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L49
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L49:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L12
L11:
  mov    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
  addl   $0x1,-0x2c(%rbp)
L12:
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L11
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  mov    -0x20(%rbp),%rdx
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsp
  jmp    L28
L68:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D11: %s + 

tool: D2:  + 

assistant: ```c
void RBTprintSpaces(int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    printf("%s + ", string);
  } else {
    printf(" + ");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RBTprintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L62
  mov    %rsp,%rbx
  add    %edi,%edi
  lea    0x1(%rdi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L61:
  cmp    %rdx,%rsp
  je     L53
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L61
L53:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L41
  orq    $0x0,-0x8(%rsp,%rax,1)
L41:
  mov    %rsp,%rsi
  mov    %rsp,%rax
  mov    %edi,%edx
  add    %rsp,%rdx
L26:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  movslq %edi,%rdi
  movb   $0x0,(%rsi,%rdi,1)
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsp
L31:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    -0x8(%rbp),%rbx
  leave
  ret
L62:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D8: %s + 

tool: D15:  + 

assistant: ```c
void RBTprintSpaces(int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    printf("%s + ", string);
  } else {
    printf(" + ");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RBTprintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L67
  add    %edi,%edi
  mov    %rsp,%rcx
  mov    %rsp,%r12
  lea    0x1(%rdi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L66
L47:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L47
L66:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L54
L9:
  movslq %edi,%rbx
  mov    $0x20,%esi
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  call   <memset@plt>
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsp
L65:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L54:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L9
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D7
datatype: string

tool: D0: %s + 

tool: D7:  + 

assistant: ```c
void RBTprintSpaces(int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    printf("%s + ", string);
  } else {
    printf(" + ");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RBTprintSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  add    %edi,%edi
  mov    %rsp,%rcx
  mov    %rsp,%r12
  lea    0x1(%rdi),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L50
L43:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L43
L50:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L58
L55:
  movslq %edi,%rbx
  mov    $0x20,%esi
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  call   <memset@plt>
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsp
L10:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L58:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L55
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D13: %s + 

tool: D15:  + 

assistant: ```c
void RBTprintSpaces(int spaces) {
  if (spaces > 0) {
    char string[spaces * 2 + 1];
    for (int i = 0; i < spaces * 2; i++) {
      string[i] = ' ';
    }
    string[spaces * 2] = '\0';
    printf("%s + ", string);
  } else {
    printf(" + ");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x28(%rbp),%r9
  lea    -0x30(%rbp),%r8
  lea    -0x38(%rbp),%rcx
  lea    -0x40(%rbp),%rdx
  lea    -0x48(%rbp),%rsi
  lea    -0x50(%rbp),%rdi
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <JacobiElliptic_complex@plt>
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm7
  movsd  -0x38(%rbp),%xmm6
  movsd  -0x40(%rbp),%xmm5
  movsd  -0x48(%rbp),%xmm4
  movsd  -0x50(%rbp),%xmm3
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm1
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x8(%rsp),%rsp
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: f64
name: unpack_data
arguments: label: D4
data_type: f64
name: unpack_data
arguments: label: D8
data_type: f64
name: unpack_data
arguments: label: D14
data_type: string

tool: D16: 0.5

tool: D4: 0.3

tool: D8: 0.4

tool: D14: %g	%g	%g	%g	%g	%g	%g	%g	%g


assistant: ```c
int main() {
  double k = 0.5;
  double zr = 0.3;
  double zi = 0.4;
  double cnr, cni, snr, sni, dnr, dni;
  JacobiElliptic_complex(zr, zi, k, &cnr, &cni, &snr, &sni, &dnr, &dni);
  printf("%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\n", zr, zi, k, cnr, cni, snr, sni, dnr, dni);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  lea    0x30(%rsp),%r9
  lea    0x28(%rsp),%r8
  mov    D5(%rip),%rax
  movq   %rax,%xmm2
  mov    D3(%rip),%rax
  movq   %rax,%xmm1
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  call   <JacobiElliptic_complex@plt>
  sub    $0x8,%rsp
  push   0x38(%rsp)
  movsd  0x38(%rsp),%xmm7
  movsd  0x30(%rsp),%xmm6
  movsd  0x28(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  mov    D5(%rip),%rax
  movq   %rax,%xmm2
  mov    D3(%rip),%rax
  movq   %rax,%xmm1
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: f64
name: unpack_data
arguments: label: D3
data_type: f64
name: unpack_data
arguments: label: D16
data_type: f64
name: unpack_data
arguments: label: D0
data_type: string

tool: D5: 0.5

tool: D3: 0.4

tool: D16: 0.3

tool: D0: %g	%g	%g	%g	%g	%g	%g	%g	%g


assistant: ```c
int main() {
  double k = 0.5;
  double zr = 0.3;
  double zi = 0.4;
  double cnr, cni, snr, sni, dnr, dni;
  JacobiElliptic_complex(zr, zi, k, &cnr, &cni, &snr, &sni, &dnr, &dni);
  printf("%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\t%g\n", zr, zi, k, cnr, cni, snr, sni, dnr, dni);
}
```