ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sais>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L28
  cmpq   $0x0,-0x10(%rbp)
  je     L28
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  cmpl   $0x0,-0x1c(%rbp)
  jns    L24
L28:
  mov    $0xffffffff,%eax
  jmp    L11
L24:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L64
  cmpl   $0x1,-0x1c(%rbp)
  jne    L46
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L46:
  mov    $0x0,%eax
  jmp    L11
L64:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x1
  push   $0x0
  push   $0x1
  mov    $0x100,%r9d
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <sais_main@plt>
  add    $0x20,%rsp
L11:
  leave
  ret
```

assistant: ```c
int sais(const unsigned char *T, int *SA, int *LCP, int n) {
  if ((T == NULL) || (SA == NULL) || (LCP == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
      LCP[0] = 0;
    }
    return 0;
  }
  return sais_main(T, SA, LCP, 0, n, 256, sizeof(unsigned char), 0, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sais>:
  endbr64
  test   %rdi,%rdi
  je     L17
  mov    %ecx,%r8d
  test   %rsi,%rsi
  je     L17
  test   %rdx,%rdx
  je     L2
  test   %ecx,%ecx
  js     L2
  cmp    $0x1,%ecx
  jle    L53
  sub    $0x10,%rsp
  push   $0x1
  push   $0x0
  push   $0x1
  mov    $0x100,%r9d
  mov    $0x0,%ecx
  call   <sais_main@plt>
  add    $0x28,%rsp
  ret
L53:
  mov    $0x0,%eax
  je     L37
  ret
L37:
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  ret
L17:
  mov    $0xffffffff,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sais(const unsigned char *T, int *SA, int *LCP, int n) {
  if ((T == NULL) || (SA == NULL) || (LCP == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
      LCP[0] = 0;
    }
    return 0;
  }
  return sais_main(T, SA, LCP, 0, n, 256, sizeof(unsigned char), 0, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sais>:
  endbr64
  test   %rdi,%rdi
  je     L39
  test   %rsi,%rsi
  je     L39
  test   %rdx,%rdx
  je     L39
  mov    %ecx,%r8d
  test   %ecx,%ecx
  js     L39
  cmp    $0x1,%ecx
  jle    L7
  sub    $0x10,%rsp
  mov    $0x100,%r9d
  xor    %ecx,%ecx
  push   $0x1
  push   $0x0
  push   $0x1
  call   <sais_main@plt>
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x0,%eax
  je     L10
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  ret
  nopl   (%rax)
L39:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sais(const unsigned char *T, int *SA, int *LCP, int n) {
  if ((T == NULL) || (SA == NULL) || (LCP == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
      LCP[0] = 0;
    }
    return 0;
  }
  return sais_main(T, SA, LCP, 0, n, 256, sizeof(unsigned char), 0, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sais>:
  endbr64
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L19
  test   %rdx,%rdx
  je     L19
  mov    %ecx,%r8d
  test   %ecx,%ecx
  js     L19
  cmp    $0x1,%ecx
  jle    L15
  sub    $0x10,%rsp
  mov    $0x100,%r9d
  xor    %ecx,%ecx
  push   $0x1
  push   $0x0
  push   $0x1
  call   <sais_main@plt>
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x0,%eax
  je     L52
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  ret
  nopl   (%rax)
L19:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sais(const unsigned char *T, int *SA, int *LCP, int n) {
  if ((T == NULL) || (SA == NULL) || (LCP == NULL) || (n < 0)) {
    return -1;
  }
  if (n <= 1) {
    if (n == 1) {
      SA[0] = 0;
      LCP[0] = 0;
    }
    return 0;
  }
  return sais_main(T, SA, LCP, 0, n, 256, sizeof(unsigned char), 0, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_ack_seqid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  jmp    L3
L17:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D11: ACK

tool: D18: warning : Corrupt acknowledgement


assistant: ```c
int get_ack_seqid(char *buffer) {
  if (memcmp(buffer, "ACK", 3) == 0) {
    return atoi(buffer + 3) - 1;
  } else {
    printf("warning : Corrupt acknowledgement\n");
    return -1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_ack_seqid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x3,%edx
  lea    D15(%rip),%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L7
  lea    0x3(%rbx),%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
L17:
  pop    %rbx
  ret
L7:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D15: ACK

tool: D19: warning : Corrupt acknowledgement


assistant: ```c
int get_ack_seqid(char *buffer) {
  if (memcmp(buffer, "ACK", 3) == 0) {
    return atoi(buffer + 3) - 1;
  } else {
    printf("warning : Corrupt acknowledgement\n");
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_ack_seqid>:
  endbr64
  push   %rbx
  mov    $0x3,%edx
  lea    D3(%rip),%rsi
  mov    %rdi,%rbx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L3
  lea    0x3(%rbx),%rdi
  call   <atoi@plt>
  pop    %rbx
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D3: ACK

tool: D6: warning : Corrupt acknowledgement


assistant: ```c
int get_ack_seqid(char *buffer) {
  if (memcmp(buffer, "ACK", 3) == 0) {
    return atoi(buffer + 3) - 1;
  } else {
    printf("warning : Corrupt acknowledgement\n");
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_ack_seqid>:
  endbr64
  push   %rbx
  mov    $0x3,%edx
  lea    D9(%rip),%rsi
  mov    %rdi,%rbx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L5
  lea    0x3(%rbx),%rdi
  call   <atoi@plt>
  pop    %rbx
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax)
L5:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D9: ACK

tool: D14: warning : Corrupt acknowledgement


assistant: ```c
int get_ack_seqid(char *buffer) {
  if (memcmp(buffer, "ACK", 3) == 0) {
    return atoi(buffer + 3) - 1;
  } else {
    printf("warning : Corrupt acknowledgement\n");
    return -1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn_ii_va>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  leave
  ret
```

assistant: ```c
int fn_ii_va(int i, ...) {
  (void)i;
  abort();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn_ii_va>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_ii_va(int i, ...) {
  (void)i;
  abort();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn_ii_va>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_ii_va(int i, ...) {
  (void)i;
  abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn_ii_va>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_ii_va(int i, ...) {
  (void)i;
  abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x68(%rbp)
  jmp    L40
L47:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x68(%rbp)
L40:
  cmpl   $0x13,-0x68(%rbp)
  jle    L47
  lea    -0x60(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x6c(%rbp),%ecx
  lea    -0x60(%rbp),%rax
  mov    $0x14,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mid_search@plt>
  mov    %eax,-0x64(%rbp)
  cmpl   $0xffffffff,-0x64(%rbp)
  jne    L13
  mov    -0x6c(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L35
L13:
  mov    -0x64(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x6c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L35:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string

tool: D22: Please input the element to search:

tool: D18: %d

tool: D3: not found %d


tool: D17: %d is located at %d

assistant: ```c
int main() {
  int a[20], i, element, index;
  for (i = 0; i < 20; i++)
    a[i] = rand() % 10;
  bubble_sort(a, 20);
  printf("Please input the element to search:\n");
  scanf("%d", &element);
  index = mid_search(a, element, 20);
  if (-1 == index)
    printf("not found %d\n", element);
  else
    printf("%d is located at %d", element, index + 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x60(%rsp),%rbp
L33:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L33
  lea    0x10(%rsp),%rbx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <bubble_sort@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    $0x14,%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <mid_search@plt>
  cmp    $0xffffffff,%eax
  je     L29
  lea    0x1(%rax),%edx
  mov    0xc(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    0xc(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D30
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string

tool: D30: Please input the element to search:

tool: D9: %d

tool: D4: %d is located at %d

tool: D1: not found %d


assistant: ```c
int main() {
  int a[20], i, element, index;
  for (i = 0; i < 20; i++)
    a[i] = rand() % 10;
  bubble_sort(a, 20);
  printf("Please input the element to search:\n");
  scanf("%d", &element);
  index = mid_search(a, element, 20);
  if (-1 == index)
    printf("not found %d\n", element);
  else
    printf("%d is located at %d", element, index + 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x60(%rsp),%rbx
  mov    %rbp,%r12
  nopl   0x0(%rax)
L36:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L36
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <bubble_sort@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x14,%edx
  mov    %rbp,%rdi
  call   <mid_search@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    0xc(%rsp),%esi
  lea    0x1(%rax),%edx
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L33
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D31
type: string
name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D8
type: string

tool: D31: Please input the element to search:

tool: D16: %d

tool: D34: %d is located at %d

tool: D8: not found %d


assistant: ```c
int main() {
  int a[20], i, element, index;
  for (i = 0; i < 20; i++)
    a[i] = rand() % 10;
  bubble_sort(a, 20);
  printf("Please input the element to search:\n");
  scanf("%d", &element);
  index = mid_search(a, element, 20);
  if (-1 == index)
    printf("not found %d\n", element);
  else
    printf("%d is located at %d", element, index + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x60(%rsp),%rbx
  mov    %rbp,%r12
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L6
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <bubble_sort@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x14,%edx
  mov    %rbp,%rdi
  call   <mid_search@plt>
  cmp    $0xffffffff,%eax
  je     L29
  mov    0xc(%rsp),%esi
  lea    0x1(%rax),%edx
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    0xc(%rsp),%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D9
type: string

tool: D1: Please input the element to search:

tool: D22: %d

tool: D4: %d is located at %d

tool: D9: not found %d


assistant: ```c
int main() {
  int a[20], i, element, index;
  for (i = 0; i < 20; i++)
    a[i] = rand() % 10;
  bubble_sort(a, 20);
  printf("Please input the element to search:\n");
  scanf("%d", &element);
  index = mid_search(a, element, 20);
  if (-1 == index)
    printf("not found %d\n", element);
  else
    printf("%d is located at %d", element, index + 1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BatchInterpolatedValue2DZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  movsd  %xmm0,-0x68(%rbp)
  movsd  %xmm1,-0x70(%rbp)
  movsd  %xmm2,-0x78(%rbp)
  movsd  %xmm3,-0x80(%rbp)
  movsd  %xmm4,-0x88(%rbp)
  movsd  %xmm5,-0x90(%rbp)
  mov    %r8,-0x98(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L2
L22:
  movq   $0x0,-0x30(%rbp)
  jmp    L9
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x30(%rbp),%xmm0
  subsd  -0x70(%rbp),%xmm0
  divsd  -0x78(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x28(%rbp),%xmm0
  subsd  -0x88(%rbp),%xmm0
  divsd  -0x90(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x98(%rbp),%rcx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rdi
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  mov    -0x50(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <InterpolatedValueZero@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addq   $0x1,-0x30(%rbp)
L9:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x30(%rbp),%xmm1
  movsd  -0x68(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L3
  addq   $0x1,-0x28(%rbp)
L2:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x28(%rbp),%xmm1
  movsd  -0x80(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L22
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
extern void BatchInterpolatedValue2DZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  idx = 0;
  for (idcoordy = 0; idcoordy < ny; idcoordy++) {
    for (idcoordx = 0; idcoordx < nx; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      Bout[idx++] = InterpolatedValueZero(Bcoeff, Width, Height, x, y, SplineDegree);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<BatchInterpolatedValue2DZero>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  movsd  %xmm3,0x40(%rsp)
  movsd  %xmm5,0x58(%rsp)
  movapd %xmm3,%xmm5
  pxor   %xmm3,%xmm3
  comisd %xmm3,%xmm5
  mov    %rdi,0x48(%rsp)
  movq   $0x0,0x38(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm4,0x50(%rsp)
  jbe    L9
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,%r12
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  0x10(%rsp),%xmm4
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm4
  jbe    L36
  mov    0x48(%rsp),%rax
  xor    %ebp,%ebp
  pxor   %xmm0,%xmm0
  subsd  0x50(%rsp),%xmm1
  divsd  0x58(%rsp),%xmm1
  lea    (%rax,%rbx,4),%rax
  mov    %rax,0x18(%rsp)
  lea    0x1(%rbx),%rax
  mov    %rbp,%rbx
  mov    %rax,0x20(%rsp)
L11:
  mov    0x20(%rsp),%rax
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  subsd  0x28(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  divsd  0x30(%rsp),%xmm0
  lea    (%rax,%rbx,1),%rbp
  call   <InterpolatedValueZero@plt>
  mov    0x18(%rsp),%rax
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x1,%rbx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  comisd %xmm0,%xmm2
  ja     L11
  mov    %rbp,%rbx
L36:
  addq   $0x1,0x38(%rsp)
  mov    0x38(%rsp),%rax
  pxor   %xmm1,%xmm1
  movsd  0x40(%rsp),%xmm3
  cvtsi2sd %rax,%xmm1
  comisd %xmm1,%xmm3
  ja     L16
L9:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
extern void BatchInterpolatedValue2DZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  idx = 0;
  for (idcoordy = 0; idcoordy < ny; idcoordy++) {
    for (idcoordx = 0; idcoordx < nx; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      Bout[idx++] = InterpolatedValueZero(Bcoeff, Width, Height, x, y, SplineDegree);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BatchInterpolatedValue2DZero>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  movsd  %xmm4,0x50(%rsp)
  pxor   %xmm4,%xmm4
  comisd %xmm4,%xmm3
  mov    %rdi,0x48(%rsp)
  movsd  %xmm0,0x20(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm3,0x40(%rsp)
  movsd  %xmm5,0x58(%rsp)
  jbe    L38
  xor    %ebx,%ebx
  comisd %xmm4,%xmm0
  mov    %rsi,%r12
  mov    %rdx,%r13
  movq   $0x0,0x38(%rsp)
  mov    %rcx,%r14
  mov    %r8,%r15
  pxor   %xmm1,%xmm1
  jbe    L38
  xchg   %ax,%ax
L32:
  mov    0x48(%rsp),%rax
  xor    %ebp,%ebp
  pxor   %xmm0,%xmm0
  subsd  0x50(%rsp),%xmm1
  divsd  0x58(%rsp),%xmm1
  lea    (%rax,%rbx,4),%rax
  mov    %rax,0x10(%rsp)
  lea    0x1(%rbx),%rax
  mov    %rbp,%rbx
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L0:
  mov    0x18(%rsp),%rax
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  subsd  0x28(%rsp),%xmm0
  movsd  %xmm1,0x8(%rsp)
  divsd  0x30(%rsp),%xmm0
  lea    (%rax,%rbx,1),%rbp
  call   <InterpolatedValueZero@plt>
  mov    0x10(%rsp),%rax
  movsd  0x20(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x1,%rbx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  comisd %xmm0,%xmm2
  ja     L0
  addq   $0x1,0x38(%rsp)
  mov    0x38(%rsp),%rax
  pxor   %xmm1,%xmm1
  mov    %rbp,%rbx
  movsd  0x40(%rsp),%xmm3
  cvtsi2sd %rax,%xmm1
  comisd %xmm1,%xmm3
  ja     L32
L38:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
extern void BatchInterpolatedValue2DZero(float *Bout, float *Bcoeff, long Width, long Height, double nx, double offx, double mx, double ny, double offy, double my, long SplineDegree) {
  double x, y;
  long idx;
  long idcoordx, idcoordy;
  idx = 0;
  for (idcoordy = 0; idcoordy < ny; idcoordy++) {
    for (idcoordx = 0; idcoordx < nx; idcoordx++) {
      x = (idcoordx - offx) / mx;
      y = (idcoordy - offy) / my;
      Bout[idx++] = InterpolatedValueZero(Bcoeff, Width, Height, x, y, SplineDegree);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char *c) {
  int n = 0;
  while (*c) {
    c++;
    n++;
  }
  return (n);
}
```