ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ShMemAlloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %r8,%r12
  test   %ecx,%ecx
  jne    L42
L75:
  mov    $0x1ff,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <shm_open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L10
  mov    D28(%rip),%rax
  and    (%rax),%ebx
  je     L41
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <ftruncate@plt>
  cmp    $0xffffffff,%eax
  je     L74
L41:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  or     (%rax),%edx
  mov    $0x0,%r9d
  mov    %ebp,%r8d
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  mov    %r13d,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  cmp    $0xffffffff,%eax
  je     L19
  test   %r12,%r12
  je     L36
  mov    %ebp,(%r12)
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  call   <shm_unlink@plt>
  jmp    L75
L74:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0x0,%eax
  jmp    L36
L19:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0x0,%eax
  jmp    L36
L10:
  mov    $0x0,%eax
  jmp    L36
```

assistant: ```c
unsigned char *ShMemAlloc(char *memname, int size, int flags, int unlink, int *fdptr) {
  int s;
  unsigned char *p;
  int fd;
  if (unlink) {
    s = shm_unlink(memname);
  }
  fd = shm_open(memname, flags, 0777);
  if (fd == -1) {
    return NULL;
  }
  if (flags & O_CREAT) {
    s = ftruncate(fd, size);
    if (s == -1) {
      close(fd);
      return NULL;
    }
  }
  p = mmap(0, size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0);
  if ((int)p == -1) {
    close(fd);
    return NULL;
  }
  if (fdptr != NULL)
    *fdptr = fd;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ShMemAlloc>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  jne    L17
L6:
  mov    $0x1ff,%edx
  mov    %ebx,%esi
  call   <shm_open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L2
  mov    D38(%rip),%rax
  and    (%rax),%ebx
  jne    L3
L56:
  mov    D18(%rip),%rax
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %ebp,%r8d
  mov    %r13d,%esi
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  or     (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  call   <mmap@plt>
  cmp    $0xffffffff,%eax
  je     L1
  test   %r12,%r12
  je     L8
  mov    %ebp,(%r12)
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <ftruncate@plt>
  cmp    $0xffffffff,%eax
  jne    L56
L1:
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rdi,0x8(%rsp)
  call   <shm_unlink@plt>
  mov    0x8(%rsp),%rdi
  jmp    L6
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
unsigned char *ShMemAlloc(char *memname, int size, int flags, int unlink, int *fdptr) {
  int s;
  unsigned char *p;
  int fd;
  if (unlink) {
    s = shm_unlink(memname);
  }
  fd = shm_open(memname, flags, 0777);
  if (fd == -1) {
    return NULL;
  }
  if (flags & O_CREAT) {
    s = ftruncate(fd, size);
    if (s == -1) {
      close(fd);
      return NULL;
    }
  }
  p = mmap(0, size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0);
  if ((int)p == -1) {
    close(fd);
    return NULL;
  }
  if (fdptr != NULL)
    *fdptr = fd;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ShMemAlloc>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  jne    L33
L43:
  mov    $0x1ff,%edx
  mov    %ebx,%esi
  call   <shm_open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L85
  mov    D24(%rip),%rax
  and    (%rax),%ebx
  jne    L57
L56:
  mov    D37(%rip),%rax
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %ebp,%r8d
  mov    %r13d,%esi
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  or     (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  call   <mmap@plt>
  cmp    $0xffffffff,%eax
  je     L20
  test   %r12,%r12
  je     L38
  mov    %ebp,(%r12)
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L57:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <ftruncate@plt>
  cmp    $0xffffffff,%eax
  jne    L56
L20:
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rdi,0x8(%rsp)
  call   <shm_unlink@plt>
  mov    0x8(%rsp),%rdi
  jmp    L43
  nopl   0x0(%rax)
L85:
  xor    %eax,%eax
  jmp    L38
```

assistant: ```c
unsigned char *ShMemAlloc(char *memname, int size, int flags, int unlink, int *fdptr) {
  int s;
  unsigned char *p;
  int fd;
  if (unlink) {
    s = shm_unlink(memname);
  }
  fd = shm_open(memname, flags, 0777);
  if (fd == -1) {
    return NULL;
  }
  if (flags & O_CREAT) {
    s = ftruncate(fd, size);
    if (s == -1) {
      close(fd);
      return NULL;
    }
  }
  p = mmap(0, size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0);
  if ((int)p == -1) {
    close(fd);
    return NULL;
  }
  if (fdptr != NULL)
    *fdptr = fd;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<regchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movzbl -0x14(%rbp),%eax
  lea    0x1(%rax),%ebx
  movzbl -0x18(%rbp),%eax
  lea    0x1(%rax),%r12d
  movzbl %bl,%eax
  and    $0x11,%eax
  test   %eax,%eax
  je     L31
  mov    $0x0,%eax
  jmp    L14
L31:
  mov    %r12d,%eax
  and    %ebx,%eax
  test   %al,%al
  je     L28
  mov    $0x1,%eax
  jmp    L14
L28:
  movzbl %bl,%eax
  and    $0x33,%eax
  test   %eax,%eax
  je     L19
  mov    $0x2,%eax
  jmp    L14
L19:
  mov    $0x3,%eax
L14:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int regchar(unsigned char a, unsigned char c) {
  register unsigned char b = a + 1;
  register unsigned char d = c + 1;
  if (b & 0x11)
    return (0);
  else if (b & d)
    return (1);
  else if (b & 0x33)
    return (2);
  else
    return (3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<regchar>:
  endbr64
  add    $0x1,%edi
  mov    $0x0,%eax
  test   $0x11,%dil
  jne    L18
  add    $0x1,%esi
  mov    $0x1,%eax
  test   %dil,%sil
  jne    L18
  test   $0x33,%dil
  sete   %al
  movzbl %al,%eax
  add    $0x2,%eax
L18:
  ret
```

assistant: ```c
int regchar(unsigned char a, unsigned char c) {
  register unsigned char b = a + 1;
  register unsigned char d = c + 1;
  if (b & 0x11)
    return (0);
  else if (b & d)
    return (1);
  else if (b & 0x33)
    return (2);
  else
    return (3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<regchar>:
  endbr64
  add    $0x1,%edi
  xor    %eax,%eax
  test   $0x11,%dil
  jne    L5
  add    $0x1,%esi
  mov    $0x1,%eax
  test   %dil,%sil
  jne    L5
  xor    %eax,%eax
  and    $0x33,%edi
  sete   %al
  add    $0x2,%eax
L5:
  ret
```

assistant: ```c
int regchar(unsigned char a, unsigned char c) {
  register unsigned char b = a + 1;
  register unsigned char d = c + 1;
  if (b & 0x11)
    return (0);
  else if (b & d)
    return (1);
  else if (b & 0x33)
    return (2);
  else
    return (3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<regchar>:
  endbr64
  add    $0x1,%edi
  xor    %eax,%eax
  test   $0x11,%dil
  jne    L12
  add    $0x1,%esi
  mov    $0x1,%eax
  test   %dil,%sil
  jne    L12
  xor    %eax,%eax
  and    $0x33,%edi
  sete   %al
  add    $0x2,%eax
L12:
  ret
```

assistant: ```c
int regchar(unsigned char a, unsigned char c) {
  register unsigned char b = a + 1;
  register unsigned char d = c + 1;
  if (b & 0x11)
    return (0);
  else if (b & d)
    return (1);
  else if (b & 0x33)
    return (2);
  else
    return (3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%edi
  call   <setuid@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: bash

assistant: ```c
int main() {
  char *argv[1] = {NULL};
  setuid(0);
  execvp("bash", argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%edi
  call   <setuid@plt>
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <execvp@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: bash

assistant: ```c
int main() {
  char *argv[1] = {NULL};
  setuid(0);
  execvp("bash", argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <setuid@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <execvp@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: bash

assistant: ```c
int main() {
  char *argv[1] = {NULL};
  setuid(0);
  execvp("bash", argv);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <setuid@plt>
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <execvp@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: bash

assistant: ```c
int main() {
  char *argv[1] = {NULL};
  setuid(0);
  execvp("bash", argv);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L16:
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4:     

assistant: ```c
void print_indent(FILE *stream, int num) {
  int i;
  for (i = 0; i < num; i++) {
    fprintf(stream, "    ");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_indent>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9:     

assistant: ```c
void print_indent(FILE *stream, int num) {
  int i;
  for (i = 0; i < num; i++) {
    fprintf(stream, "    ");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_indent>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8:     

assistant: ```c
void print_indent(FILE *stream, int num) {
  int i;
  for (i = 0; i < num; i++) {
    fprintf(stream, "    ");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_indent>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9:     

assistant: ```c
void print_indent(FILE *stream, int num) {
  int i;
  for (i = 0; i < num; i++) {
    fprintf(stream, "    ");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L13
L24:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  jmp    L39
L4:
  subl   $0x1,-0x24(%rbp)
L13:
  cmpl   $0x0,-0x24(%rbp)
  jne    L24
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int mystrncmp(unsigned char *str1, unsigned char *str2, int len) {
  while (len) {
    int d;
    if ((d = (int)*str1++ - (int)*str2++))
      return d;
    len--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mystrncmp>:
  endbr64
  test   %edx,%edx
  je     L22
  mov    %edx,%edx
  mov    $0x0,%ecx
L18:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  jne    L6
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L18
  ret
L22:
  mov    %edx,%eax
L6:
  ret
```

assistant: ```c
int mystrncmp(unsigned char *str1, unsigned char *str2, int len) {
  while (len) {
    int d;
    if ((d = (int)*str1++ - (int)*str2++))
      return d;
    len--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrncmp>:
  endbr64
  test   %edx,%edx
  je     L11
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L6
  xchg   %ax,%ax
L29:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L35
L6:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  je     L29
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mystrncmp(unsigned char *str1, unsigned char *str2, int len) {
  while (len) {
    int d;
    if ((d = (int)*str1++ - (int)*str2++))
      return d;
    len--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrncmp>:
  endbr64
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L0
  xchg   %ax,%ax
L35:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L37
L0:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  sub    %r8d,%eax
  je     L35
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  ret
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mystrncmp(unsigned char *str1, unsigned char *str2, int len) {
  while (len) {
    int d;
    if ((d = (int)*str1++ - (int)*str2++))
      return d;
    len--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MethodBitsPerPixel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x43,-0x4(%rbp)
  ja     L73
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x8,%eax
  jmp    L97
  mov    $0x8,%eax
  jmp    L97
  mov    $0x8,%eax
  jmp    L97
  mov    $0x10,%eax
  jmp    L97
  mov    $0x10,%eax
  jmp    L97
  mov    $0x10,%eax
  jmp    L97
  mov    $0x10,%eax
  jmp    L97
  mov    $0x18,%eax
  jmp    L97
  mov    $0x18,%eax
  jmp    L97
  mov    $0x18,%eax
  jmp    L97
  mov    $0x18,%eax
  jmp    L97
L73:
  mov    $0x0,%eax
L97:
  pop    %rbp
  ret
```

assistant: ```c
int MethodBitsPerPixel(unsigned int method) {
  switch (method) {
  case 1:
  case 26:
  case 37: {
    return 8;
  }
  case 2:
  case 27:
  case 38: {
    return 8;
  }
  case 3:
  case 28:
  case 39: {
    return 8;
  }
  case 4:
  case 29:
  case 40: {
    return 16;
  }
  case 5:
  case 30:
  case 41: {
    return 16;
  }
  case 6:
  case 31:
  case 42: {
    return 16;
  }
  case 7:
  case 32:
  case 43: {
    return 16;
  }
  case 8:
  case 33:
  case 44: {
    return 24;
  }
  case 9:
  case 34:
  case 45: {
    return 24;
  }
  case 10:
  case 35:
  case 46: {
    return 24;
  }
  case 67:
  case 63:
  case 64: {
    return 24;
  }
  default: {
    return 0;
  }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<MethodBitsPerPixel>:
  endbr64
  cmp    $0x43,%edi
  ja     L8
  mov    %edi,%edi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x10,%eax
  ret
  mov    $0x18,%eax
  ret
  mov    $0x18,%eax
  ret
  mov    $0x18,%eax
  ret
  mov    $0x18,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
  mov    $0x8,%eax
  ret
```

assistant: ```c
int MethodBitsPerPixel(unsigned int method) {
  switch (method) {
  case 1:
  case 26:
  case 37: {
    return 8;
  }
  case 2:
  case 27:
  case 38: {
    return 8;
  }
  case 3:
  case 28:
  case 39: {
    return 8;
  }
  case 4:
  case 29:
  case 40: {
    return 16;
  }
  case 5:
  case 30:
  case 41: {
    return 16;
  }
  case 6:
  case 31:
  case 42: {
    return 16;
  }
  case 7:
  case 32:
  case 43: {
    return 16;
  }
  case 8:
  case 33:
  case 44: {
    return 24;
  }
  case 9:
  case 34:
  case 45: {
    return 24;
  }
  case 10:
  case 35:
  case 46: {
    return 24;
  }
  case 67:
  case 63:
  case 64: {
    return 24;
  }
  default: {
    return 0;
  }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MethodBitsPerPixel>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x42,%edi
  ja     L5
  lea    D9(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: 

assistant: ```c
int MethodBitsPerPixel(unsigned int method) {
  switch (method) {
  case 1:
  case 26:
  case 37: {
    return 8;
  }
  case 2:
  case 27:
  case 38: {
    return 8;
  }
  case 3:
  case 28:
  case 39: {
    return 8;
  }
  case 4:
  case 29:
  case 40: {
    return 16;
  }
  case 5:
  case 30:
  case 41: {
    return 16;
  }
  case 6:
  case 31:
  case 42: {
    return 16;
  }
  case 7:
  case 32:
  case 43: {
    return 16;
  }
  case 8:
  case 33:
  case 44: {
    return 24;
  }
  case 9:
  case 34:
  case 45: {
    return 24;
  }
  case 10:
  case 35:
  case 46: {
    return 24;
  }
  case 67:
  case 63:
  case 64: {
    return 24;
  }
  default: {
    return 0;
  }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<MethodBitsPerPixel>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x42,%edi
  ja     L8
  lea    D1(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: 

assistant: ```c
int MethodBitsPerPixel(unsigned int method) {
  switch (method) {
  case 1:
  case 26:
  case 37: {
    return 8;
  }
  case 2:
  case 27:
  case 38: {
    return 8;
  }
  case 3:
  case 28:
  case 39: {
    return 8;
  }
  case 4:
  case 29:
  case 40: {
    return 16;
  }
  case 5:
  case 30:
  case 41: {
    return 16;
  }
  case 6:
  case 31:
  case 42: {
    return 16;
  }
  case 7:
  case 32:
  case 43: {
    return 16;
  }
  case 8:
  case 33:
  case 44: {
    return 24;
  }
  case 9:
  case 34:
  case 45: {
    return 24;
  }
  case 10:
  case 35:
  case 46: {
    return 24;
  }
  case 67:
  case 63:
  case 64: {
    return 24;
  }
  default: {
    return 0;
  }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__glGetMaterialfv_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x6,%eax
  ja     L9
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L40
  mov    $0x3,%eax
  jmp    L40
  mov    $0x4,%eax
  jmp    L40
  mov    $0x4,%eax
  jmp    L40
  mov    $0x4,%eax
  jmp    L40
  mov    $0x4,%eax
  jmp    L40
  mov    $0x4,%eax
  jmp    L40
L9:
  mov    $0xffffffff,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
GLint __glGetMaterialfv_size(GLenum pname) {
  switch (pname) {
  case GL_SHININESS:
    return 1;
  case GL_COLOR_INDEXES:
    return 3;
  case GL_EMISSION:
    return 4;
  case GL_AMBIENT:
    return 4;
  case GL_DIFFUSE:
    return 4;
  case GL_SPECULAR:
    return 4;
  case GL_AMBIENT_AND_DIFFUSE:
    return 4;
  default:
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__glGetMaterialfv_size>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x6,%edi
  ja     L2
  mov    %edi,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x4,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
  mov    $0x1,%eax
  ret
```

assistant: ```c
GLint __glGetMaterialfv_size(GLenum pname) {
  switch (pname) {
  case GL_SHININESS:
    return 1;
  case GL_COLOR_INDEXES:
    return 3;
  case GL_EMISSION:
    return 4;
  case GL_AMBIENT:
    return 4;
  case GL_DIFFUSE:
    return 4;
  case GL_SPECULAR:
    return 4;
  case GL_AMBIENT_AND_DIFFUSE:
    return 4;
  default:
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__glGetMaterialfv_size>:
  endbr64
  add    $0xffffff80,%edi
  mov    $0xffffffff,%eax
  cmp    $0x6,%edi
  ja     L4
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L4:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: 

assistant: ```c
GLint __glGetMaterialfv_size(GLenum pname) {
  switch (pname) {
  case GL_SHININESS:
    return 1;
  case GL_COLOR_INDEXES:
    return 3;
  case GL_EMISSION:
    return 4;
  case GL_AMBIENT:
    return 4;
  case GL_DIFFUSE:
    return 4;
  case GL_SPECULAR:
    return 4;
  case GL_AMBIENT_AND_DIFFUSE:
    return 4;
  default:
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__glGetMaterialfv_size>:
  endbr64
  add    $0xffffff80,%edi
  mov    $0xffffffff,%eax
  cmp    $0x6,%edi
  ja     L7
  lea    D8(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L7:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: 

assistant: ```c
GLint __glGetMaterialfv_size(GLenum pname) {
  switch (pname) {
  case GL_SHININESS:
    return 1;
  case GL_COLOR_INDEXES:
    return 3;
  case GL_EMISSION:
    return 4;
  case GL_AMBIENT:
    return 4;
  case GL_DIFFUSE:
    return 4;
  case GL_SPECULAR:
    return 4;
  case GL_AMBIENT_AND_DIFFUSE:
    return 4;
  default:
    return -1;
  }
}
```