ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L79:
  cmp    %rdx,%rsp
  je     L88
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L88:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L92
  orq    $0x0,-0x8(%rsp,%rax,1)
L92:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L36
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r15
L68:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D19(%rip),%xmm0
  subsd  D32(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L68
L36:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L98
  mov    $0x0,%ebx
L14:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  mov    %r12d,%edi
  call   <stdlib_strided_dnanvarianceyc@plt>
  ucomisd %xmm0,%xmm0
  jp     L70
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L14
L98:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L73:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L70:
  lea    D3(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L73
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type: f64
name: parse_data
arguments: data_tag: D32
type: f64
name: parse_data
arguments: data_tag: D7
type: f64
name: parse_data
arguments: data_tag: D3
type: string

tool: D19: 20000

tool: D32: 10000

tool: D7: 1

tool: D3: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvarianceyc(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L0
L75:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L75
L0:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L115
L50:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L28
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L74:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D17(%rip),%xmm0
  subsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L74
L28:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L33
  xor    %r14d,%r14d
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L119:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L33
L84:
  mov    D34(%rip),%rax
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  movq   %rax,%xmm0
  call   <stdlib_strided_dnanvarianceyc@plt>
  ucomisd %xmm0,%xmm0
  jnp    L119
  lea    D27(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L81:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L33:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L81
  cs nopw 0x0(%rax,%rax,1)
L115:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L50
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: f64
name: disassemble_data
arguments: label: D5
type_guessed: f64
name: disassemble_data
arguments: label: D34
type_guessed: f64
name: disassemble_data
arguments: label: D27
type_guessed: string

tool: D17: 20000

tool: D5: 10000

tool: D34: 1

tool: D27: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvarianceyc(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L60
L6:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L6
L60:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L84
L36:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L114
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L74:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D37(%rip),%xmm0
  subsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L74
L114:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L93
  xor    %r14d,%r14d
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L64:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L93
L89:
  mov    D24(%rip),%rax
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  movq   %rax,%xmm0
  call   <stdlib_strided_dnanvarianceyc@plt>
  ucomisd %xmm0,%xmm0
  jnp    L64
  lea    D2(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L14:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L93:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L84:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L36
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D37
datatype: f64
name: unpack_data
arguments: data_label: D19
datatype: f64
name: unpack_data
arguments: data_label: D24
datatype: f64
name: unpack_data
arguments: data_label: D2
datatype: string

tool: D37: 20000

tool: D19: 10000

tool: D24: 1

tool: D2: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvarianceyc(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: Hello, multithreaded world: thread %d of %d


assistant: ```c
int main(int argc, char **argv) {
#pragma omp parallel num_threads(6)
  {
    printf("Hello, multithreaded world: thread %d of %d\n", omp_get_thread_num(), omp_get_num_threads());
    sleep(30);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: Hello, multithreaded world: thread %d of %d


assistant: ```c
int main(int argc, char **argv) {
#pragma omp parallel num_threads(6)
  {
    printf("Hello, multithreaded world: thread %d of %d\n", omp_get_thread_num(), omp_get_num_threads());
    sleep(30);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: Hello, multithreaded world: thread %d of %d


assistant: ```c
int main(int argc, char **argv) {
#pragma omp parallel num_threads(6)
  {
    printf("Hello, multithreaded world: thread %d of %d\n", omp_get_thread_num(), omp_get_num_threads());
    sleep(30);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: Hello, multithreaded world: thread %d of %d


assistant: ```c
int main(int argc, char **argv) {
#pragma omp parallel num_threads(6)
  {
    printf("Hello, multithreaded world: thread %d of %d\n", omp_get_thread_num(), omp_get_num_threads());
    sleep(30);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L6
L24:
  movl   $0x0,-0x3c(%rbp)
  jmp    L7
L0:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L7:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  addl   $0x1,-0x40(%rbp)
L6:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L24
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply128(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply128>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L1:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L14:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L14
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

assistant: ```c
void multiply128(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<multiply128>:
  endbr64
  test   %edi,%edi
  jle    L20
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L13
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L25
  pop    %rbx
  ret
L20:
  ret
```

assistant: ```c
void multiply128(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply128>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L15
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L27:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L75
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L75
  nopl   0x0(%rax)
L91:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L91
  cmp    -0x24(%rsp),%r11d
  je     L12
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L12
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L12
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L12:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L27
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L75:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L21:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L21
  mov    -0x18(%rsp),%r8
  jmp    L12
```

assistant: ```c
void multiply128(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fromFPtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L3
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L3:
  cmpq   $0x7,-0x20(%rbp)
  jbe    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
unsigned char *fromFPtr(int (*fptr)(int, int, int)) {
  size_t i;
  unsigned char *p = (unsigned char *)&fptr;
  unsigned char out[sizeof fptr];
  for (i = 0; i < sizeof fptr; i++) {
    out[i] = p[i];
  }
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fromFPtr>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char *fromFPtr(int (*fptr)(int, int, int)) {
  size_t i;
  unsigned char *p = (unsigned char *)&fptr;
  unsigned char out[sizeof fptr];
  for (i = 0; i < sizeof fptr; i++) {
    out[i] = p[i];
  }
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fromFPtr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *fromFPtr(int (*fptr)(int, int, int)) {
  size_t i;
  unsigned char *p = (unsigned char *)&fptr;
  unsigned char out[sizeof fptr];
  for (i = 0; i < sizeof fptr; i++) {
    out[i] = p[i];
  }
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fromFPtr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *fromFPtr(int (*fptr)(int, int, int)) {
  size_t i;
  unsigned char *p = (unsigned char *)&fptr;
  unsigned char out[sizeof fptr];
  for (i = 0; i < sizeof fptr; i++) {
    out[i] = p[i];
  }
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<std_char_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void std_char_str(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (self)
    fputc(*(const char *)self, stream);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<std_char_str>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  mov    %rdx,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void std_char_str(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (self)
    fputc(*(const char *)self, stream);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<std_char_str>:
  endbr64
  mov    %rdx,%rsi
  test   %rdi,%rdi
  je     L9
  movsbl (%rdi),%edi
  jmp    1050 <fputc@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void std_char_str(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (self)
    fputc(*(const char *)self, stream);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<std_char_str>:
  endbr64
  mov    %rdx,%rsi
  test   %rdi,%rdi
  je     L6
  movsbl (%rdi),%edi
  jmp    1050 <fputc@plt>
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void std_char_str(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (self)
    fputc(*(const char *)self, stream);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x40000000,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x40000000,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x16,%edx
  add    %edx,%eax
  and    $0x3ff,%eax
  sub    %edx,%eax
  shl    $0x14,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  addl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0x3fffffff,-0x14(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: long: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  char *mem = (char *)malloc(1024 * 1024 * 1024);
  bzero(mem, 1024 * 1024 * 1024);
  char tinybyte;
  unsigned long addr = 0;
  printf("long: %lu\n", addr - 1);
  int i;
  for (i = 0; i < 1024 * 1024 * 1024; ++i) {
    addr = rand() % 1024 * 1024 * 1024;
    tinybyte = mem[i];
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x40000000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x40000000,%esi
  call   <bzero@plt>
  mov    $0xffffffffffffffff,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x40000000,%ebx
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: long: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  char *mem = (char *)malloc(1024 * 1024 * 1024);
  bzero(mem, 1024 * 1024 * 1024);
  char tinybyte;
  unsigned long addr = 0;
  printf("long: %lu\n", addr - 1);
  int i;
  for (i = 0; i < 1024 * 1024 * 1024; ++i) {
    addr = rand() % 1024 * 1024 * 1024;
    tinybyte = mem[i];
  }
  return 0;
}
```