ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<open_file_test>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L0
  ret
L0:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_screen@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5:  Erro ao abrir o arquivo!



assistant: ```c
int open_file_test(FILE *file) {
  if (file == NULL) {
    clear_screen();
    printf(" Erro ao abrir o arquivo!\n\n");
    return 0;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<open_file_test>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    $0x1,%eax
  ret
  nop
L5:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_screen@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1:  Erro ao abrir o arquivo!



assistant: ```c
int open_file_test(FILE *file) {
  if (file == NULL) {
    clear_screen();
    printf(" Erro ao abrir o arquivo!\n\n");
    return 0;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open_file_test>:
  endbr64
  test   %rdi,%rdi
  je     L8
  mov    $0x1,%eax
  ret
  nop
L8:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_screen@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6:  Erro ao abrir o arquivo!



assistant: ```c
int open_file_test(FILE *file) {
  if (file == NULL) {
    clear_screen();
    printf(" Erro ao abrir o arquivo!\n\n");
    return 0;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L93
L107:
  addq   $0x1,-0x18(%rbp)
L93:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L107
  movq   $0x0,-0x8(%rbp)
  movb   $0x39,-0xb(%rbp)
  movb   $0x30,-0xa(%rbp)
  movb   $0x39,-0x9(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L38
  movl   $0xa,-0x24(%rbp)
  jmp    L136
L38:
  cmpl   $0xa,-0x24(%rbp)
  jg     L6
  mov    -0x24(%rbp),%eax
  add    $0x2f,%eax
  mov    %al,-0xb(%rbp)
  jmp    L136
L6:
  movb   $0x41,-0xa(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x36,%eax
  mov    %al,-0x9(%rbp)
  jmp    L136
L145:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L120
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jge    L70
L120:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jg     L58
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jl     L58
L70:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L141
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jl     L141
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L61
L141:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rax,-0x8(%rbp)
L61:
  addq   $0x1,-0x18(%rbp)
L136:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L145
L58:
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long strtol(const char *str, char **stringPtr, int base) {
  while (str[0] == 32)
    str++;
  long result = 0;
  char maxNum = '9';
  char minChar = '0', maxChar = '9';
  if (base == 0)
    base = 10;
  else if (base <= 10)
    maxNum = '0' + base - 1;
  else {
    minChar = 'A';
    maxChar = 'A' + (base - 11);
  }
  while (*str) {
    if (!((*str >= '0' && *str <= maxNum) || (*str >= minChar && *str <= maxChar)))
      break;
    result *= base;
    if ('A' <= *str && *str <= maxChar)
      result += *str - 'A' + 10;
    else
      result += *str - '0';
    str++;
  }
  stringPtr[0] = str;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtol>:
  endbr64
  mov    %rsi,%r9
  cmpb   $0x20,(%rdi)
  jne    L114
L68:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L68
L114:
  test   %edx,%edx
  je     L109
  cmp    $0xa,%edx
  jg     L55
  lea    0x2f(%rdx),%r8d
  mov    $0x39,%esi
  mov    $0x30,%r10d
  jmp    L75
L55:
  lea    0x36(%rdx),%esi
  mov    $0x41,%r10d
  mov    $0x39,%r8d
  jmp    L75
L59:
  movsbl %cl,%ecx
  sub    $0x30,%ecx
  movslq %ecx,%rcx
  add    %rcx,%rax
L21:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L125
L56:
  cmp    %cl,%r8b
  jl     L73
  cmp    $0x2f,%cl
  jg     L138
L73:
  cmp    %cl,%sil
  jl     L125
  cmp    %cl,%r10b
  jg     L125
L138:
  imul   %rdx,%rax
  cmp    %cl,%sil
  jl     L59
  cmp    $0x40,%cl
  jle    L59
  movsbl %cl,%ecx
  sub    $0x37,%ecx
  movslq %ecx,%rcx
  add    %rcx,%rax
  jmp    L21
L109:
  mov    $0x39,%esi
  mov    $0x30,%r10d
  mov    $0x39,%r8d
  mov    $0xa,%edx
L75:
  movzbl (%rdi),%ecx
  mov    $0x0,%eax
  movslq %edx,%rdx
  test   %cl,%cl
  jne    L56
L125:
  mov    %rdi,(%r9)
  ret
```

assistant: ```c
long strtol(const char *str, char **stringPtr, int base) {
  while (str[0] == 32)
    str++;
  long result = 0;
  char maxNum = '9';
  char minChar = '0', maxChar = '9';
  if (base == 0)
    base = 10;
  else if (base <= 10)
    maxNum = '0' + base - 1;
  else {
    minChar = 'A';
    maxChar = 'A' + (base - 11);
  }
  while (*str) {
    if (!((*str >= '0' && *str <= maxNum) || (*str >= minChar && *str <= maxChar)))
      break;
    result *= base;
    if ('A' <= *str && *str <= maxChar)
      result += *str - 'A' + 10;
    else
      result += *str - '0';
    str++;
  }
  stringPtr[0] = str;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strtol>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%r9
  cmp    $0x20,%cl
  jne    L43
  nop
L116:
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  cmp    $0x20,%cl
  je     L116
L43:
  test   %edx,%edx
  je     L131
  cmp    $0xa,%edx
  jg     L55
  lea    0x2f(%rdx),%r10d
  mov    $0x39,%r8d
  mov    $0x30,%r11d
  jmp    L48
  nopl   0x0(%rax)
L131:
  mov    $0x39,%r8d
  mov    $0x30,%r11d
  mov    $0x39,%r10d
  mov    $0xa,%edx
L48:
  xor    %eax,%eax
  movslq %edx,%rdx
  test   %cl,%cl
  jne    L74
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L157:
  sub    $0x30,%esi
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  movslq %esi,%rsi
  add    %rsi,%rax
  test   %cl,%cl
  je     L67
L74:
  cmp    %cl,%r10b
  jl     L72
  cmp    $0x2f,%cl
  jg     L93
L72:
  cmp    %cl,%r8b
  jl     L67
  cmp    %cl,%r11b
  jg     L67
L93:
  imul   %rdx,%rax
  movsbl %cl,%esi
  cmp    %cl,%r8b
  jl     L157
  cmp    $0x40,%cl
  jle    L157
  sub    $0x37,%esi
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  movslq %esi,%rsi
  add    %rsi,%rax
  test   %cl,%cl
  jne    L74
L67:
  mov    %rdi,(%r9)
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  lea    0x36(%rdx),%r8d
  mov    $0x41,%r11d
  mov    $0x39,%r10d
  jmp    L48
```

assistant: ```c
long strtol(const char *str, char **stringPtr, int base) {
  while (str[0] == 32)
    str++;
  long result = 0;
  char maxNum = '9';
  char minChar = '0', maxChar = '9';
  if (base == 0)
    base = 10;
  else if (base <= 10)
    maxNum = '0' + base - 1;
  else {
    minChar = 'A';
    maxChar = 'A' + (base - 11);
  }
  while (*str) {
    if (!((*str >= '0' && *str <= maxNum) || (*str >= minChar && *str <= maxChar)))
      break;
    result *= base;
    if ('A' <= *str && *str <= maxChar)
      result += *str - 'A' + 10;
    else
      result += *str - '0';
    str++;
  }
  stringPtr[0] = str;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strtol>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%r9
  cmp    $0x20,%cl
  jne    L127
  nop
L15:
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  cmp    $0x20,%cl
  je     L15
L127:
  test   %edx,%edx
  je     L38
  cmp    $0xa,%edx
  jg     L67
  lea    0x2f(%rdx),%r10d
  mov    $0x39,%r8d
  mov    $0x30,%r11d
  jmp    L49
  nopl   0x0(%rax)
L38:
  mov    $0x39,%r8d
  mov    $0x30,%r11d
  mov    $0x39,%r10d
  mov    $0xa,%edx
L49:
  xor    %eax,%eax
  movslq %edx,%rdx
  test   %cl,%cl
  jne    L94
  jmp    L150
  nopw   0x0(%rax,%rax,1)
L82:
  sub    $0x30,%esi
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  movslq %esi,%rsi
  add    %rsi,%rax
  test   %cl,%cl
  je     L150
L94:
  cmp    %cl,%r10b
  jl     L45
  cmp    $0x2f,%cl
  jg     L125
L45:
  cmp    %cl,%r8b
  jl     L150
  cmp    %cl,%r11b
  jg     L150
L125:
  imul   %rdx,%rax
  movsbl %cl,%esi
  cmp    %cl,%r8b
  jl     L82
  cmp    $0x40,%cl
  jle    L82
  sub    $0x37,%esi
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  movslq %esi,%rsi
  add    %rsi,%rax
  test   %cl,%cl
  jne    L94
L150:
  mov    %rdi,(%r9)
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  lea    0x36(%rdx),%r8d
  mov    $0x41,%r11d
  mov    $0x39,%r10d
  jmp    L49
```

assistant: ```c
long strtol(const char *str, char **stringPtr, int base) {
  while (str[0] == 32)
    str++;
  long result = 0;
  char maxNum = '9';
  char minChar = '0', maxChar = '9';
  if (base == 0)
    base = 10;
  else if (base <= 10)
    maxNum = '0' + base - 1;
  else {
    minChar = 'A';
    maxChar = 'A' + (base - 11);
  }
  while (*str) {
    if (!((*str >= '0' && *str <= maxNum) || (*str >= minChar && *str <= maxChar)))
      break;
    result *= base;
    if ('A' <= *str && *str <= maxChar)
      result += *str - 'A' + 10;
    else
      result += *str - '0';
    str++;
  }
  stringPtr[0] = str;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mpz_init2@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mpz_init2@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mpz_init2@plt>
  mov    -0x38(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mpz_init2@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  jmp    L13
L17:
  mov    -0x24(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_tdiv_qr@plt>
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_powm@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x30(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_addmul@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jg     L17
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_powm@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x30(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_addmul@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int crypt(mpz_t n, mpz_t e, mpz_t message, mpz_t cipher, size_t length) {
  int i = 1;
  mpz_t t1, t2, t3, m;
  mpz_init2(t1, length);
  mpz_init2(t2, length);
  mpz_init2(t3, length);
  mpz_init2(m, length);
  mpz_set(m, message);
  while (mpz_cmp(m, n) > 0) {
    mpz_tdiv_qr(t1, t2, m, n);
    mpz_powm(t3, t2, e, n);
    mpz_addmul(t3, cipher, n);
    mpz_set(cipher, t3);
    mpz_set(m, t1);
    ++i;
  }
  mpz_powm(t3, m, e, n);
  mpz_addmul(t3, cipher, n);
  mpz_set(cipher, t3);
  mpz_clear(t1);
  mpz_clear(t2);
  mpz_clear(t3);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,0xc(%rsp)
  mov    %edx,%r15d
  mov    %ecx,%r14d
  mov    %r8,%rbx
  mov    %r8,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <mpz_init2@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <mpz_init2@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init2@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init2@plt>
  mov    %r15d,%esi
  mov    %ebx,%edi
  call   <mpz_set@plt>
  mov    $0x1,%r15d
  jmp    L19
L4:
  mov    %r12d,%ecx
  mov    $0x0,%ebx
  mov    %ebx,%edx
  mov    $0x0,%ebp
  mov    %ebp,%esi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <mpz_tdiv_qr@plt>
  mov    %r12d,%ecx
  mov    0xc(%rsp),%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_powm@plt>
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <mpz_addmul@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <mpz_set@plt>
  add    $0x1,%r15d
L19:
  mov    %r12d,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jg     L4
  mov    %r12d,%ecx
  mov    0xc(%rsp),%edx
  mov    %ebx,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_powm@plt>
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <mpz_addmul@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <mpz_clear@plt>
  mov    $0x0,%edi
  call   <mpz_clear@plt>
  mov    %ebp,%edi
  call   <mpz_clear@plt>
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int crypt(mpz_t n, mpz_t e, mpz_t message, mpz_t cipher, size_t length) {
  int i = 1;
  mpz_t t1, t2, t3, m;
  mpz_init2(t1, length);
  mpz_init2(t2, length);
  mpz_init2(t3, length);
  mpz_init2(m, length);
  mpz_set(m, message);
  while (mpz_cmp(m, n) > 0) {
    mpz_tdiv_qr(t1, t2, m, n);
    mpz_powm(t3, t2, e, n);
    mpz_addmul(t3, cipher, n);
    mpz_set(cipher, t3);
    mpz_set(m, t1);
    ++i;
  }
  mpz_powm(t3, m, e, n);
  mpz_addmul(t3, cipher, n);
  mpz_set(cipher, t3);
  mpz_clear(t1);
  mpz_clear(t2);
  mpz_clear(t3);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crypt>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %r8,%rsi
  sub    $0x18,%rsp
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init2@plt>
  mov    %r15d,%esi
  mov    %ebp,%edi
  mov    $0x1,%r15d
  call   <mpz_set@plt>
  jmp    L5
  nopl   0x0(%rax)
L15:
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  mov    %r9d,%esi
  mov    %r10d,%edi
  mov    %ebp,%edx
  mov    %r9d,0xc(%rsp)
  mov    %r10d,0x8(%rsp)
  add    $0x1,%r15d
  call   <mpz_tdiv_qr@plt>
  mov    0xc(%rsp),%esi
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <mpz_powm@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <mpz_addmul@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  call   <mpz_set@plt>
L5:
  xor    %ebp,%ebp
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %r13d,%ecx
  test   %rax,%rax
  jg     L15
  xor    %r12d,%r12d
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <mpz_powm@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <mpz_addmul@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  xor    %edi,%edi
  call   <mpz_clear@plt>
  xor    %edi,%edi
  call   <mpz_clear@plt>
  mov    %r12d,%edi
  call   <mpz_clear@plt>
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int crypt(mpz_t n, mpz_t e, mpz_t message, mpz_t cipher, size_t length) {
  int i = 1;
  mpz_t t1, t2, t3, m;
  mpz_init2(t1, length);
  mpz_init2(t2, length);
  mpz_init2(t3, length);
  mpz_init2(m, length);
  mpz_set(m, message);
  while (mpz_cmp(m, n) > 0) {
    mpz_tdiv_qr(t1, t2, m, n);
    mpz_powm(t3, t2, e, n);
    mpz_addmul(t3, cipher, n);
    mpz_set(cipher, t3);
    mpz_set(m, t1);
    ++i;
  }
  mpz_powm(t3, m, e, n);
  mpz_addmul(t3, cipher, n);
  mpz_set(cipher, t3);
  mpz_clear(t1);
  mpz_clear(t2);
  mpz_clear(t3);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypt>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %r8,%rsi
  sub    $0x18,%rsp
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <mpz_init2@plt>
  mov    %rbp,%rsi
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init2@plt>
  mov    %r15d,%esi
  mov    %ebp,%edi
  mov    $0x1,%r15d
  call   <mpz_set@plt>
  jmp    L10
  nopl   0x0(%rax)
L3:
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  mov    %r9d,%esi
  mov    %r10d,%edi
  mov    %ebp,%edx
  mov    %r9d,0xc(%rsp)
  mov    %r10d,0x8(%rsp)
  add    $0x1,%r15d
  call   <mpz_tdiv_qr@plt>
  mov    0xc(%rsp),%esi
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <mpz_powm@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <mpz_addmul@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  call   <mpz_set@plt>
L10:
  xor    %ebp,%ebp
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %r13d,%ecx
  test   %rax,%rax
  jg     L3
  xor    %r12d,%r12d
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <mpz_powm@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <mpz_addmul@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <mpz_set@plt>
  xor    %edi,%edi
  call   <mpz_clear@plt>
  xor    %edi,%edi
  call   <mpz_clear@plt>
  mov    %r12d,%edi
  call   <mpz_clear@plt>
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int crypt(mpz_t n, mpz_t e, mpz_t message, mpz_t cipher, size_t length) {
  int i = 1;
  mpz_t t1, t2, t3, m;
  mpz_init2(t1, length);
  mpz_init2(t2, length);
  mpz_init2(t3, length);
  mpz_init2(m, length);
  mpz_set(m, message);
  while (mpz_cmp(m, n) > 0) {
    mpz_tdiv_qr(t1, t2, m, n);
    mpz_powm(t3, t2, e, n);
    mpz_addmul(t3, cipher, n);
    mpz_set(cipher, t3);
    mpz_set(m, t1);
    ++i;
  }
  mpz_powm(t3, m, e, n);
  mpz_addmul(t3, cipher, n);
  mpz_set(cipher, t3);
  mpz_clear(t1);
  mpz_clear(t2);
  mpz_clear(t3);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main(void) {
  const int x = 0;
  const int *p = &x;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  const int x = 0;
  const int *p = &x;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  const int x = 0;
  const int *p = &x;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  const int x = 0;
  const int *p = &x;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<doubleToWord64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t doubleToWord64(double input) {
  union {
    double d;
    uint64_t l;
  } u;
  u.d = input;
  return u.l;
}
```
user: What is the c source code of the assembly code below:

```asm
<doubleToWord64>:
  endbr64
  movq   %xmm0,%rax
  ret
```

assistant: ```c
uint64_t doubleToWord64(double input) {
  union {
    double d;
    uint64_t l;
  } u;
  u.d = input;
  return u.l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<doubleToWord64>:
  endbr64
  movq   %xmm0,%rax
  ret
```

assistant: ```c
uint64_t doubleToWord64(double input) {
  union {
    double d;
    uint64_t l;
  } u;
  u.d = input;
  return u.l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <f@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <k@plt>
  movabs $0x32206f6c6c6568,%rax
  mov    $0x0,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  movabs $0x33206f6c6c6568,%rax
  mov    $0x0,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <h@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <m@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string

tool: D5: hello 1

tool: D18: hello 4

assistant: ```c
int main() {
  f("hello 1");
  k("hello 1");
  char hello2[16] = "hello 2";
  g(hello2);
  char hello3[16] = "hello 3";
  h(hello3);
  m("hello 4");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <f@plt>
  mov    %rbx,%rdi
  call   <k@plt>
  movabs $0x32206f6c6c6568,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rsp,%rdi
  call   <g@plt>
  movabs $0x33206f6c6c6568,%rax
  mov    $0x0,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x10(%rsp),%rdi
  call   <h@plt>
  lea    D7(%rip),%rdi
  call   <m@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string

tool: D13: hello 1

tool: D7: hello 4

assistant: ```c
int main() {
  f("hello 1");
  k("hello 1");
  char hello2[16] = "hello 2";
  g(hello2);
  char hello3[16] = "hello 3";
  h(hello3);
  m("hello 4");
  return 0;
}
```