ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<counter>:
  endbr64
  push   %r13
  mov    $0x74,%ecx
  lea    D2(%rip),%rsi
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0xf42400(%rbx),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x667267632d746e69,%rax
  lea    0xa(%rsp),%rdi
  movl   $0x61642e73,0x12(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0xa(%rsp)
  call   <fopen@plt>
  mov    %rax,%r12
  fldz
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L43:
  fstp   %st(0)
  add    $0x10,%rbx
  cmp    %rbp,%rbx
  je     L40
L63:
  fldt   (%rbx)
  fld    %st(1)
  fxch   %st(1)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L37
  je     L43
  fstp   %st(1)
  jmp    L39
L37:
  fstp   %st(1)
  nop
L39:
  sub    $0x10,%rsp
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x10,%rbx
  fstpt  (%rsp)
  call   <fprintf@plt>
  pop    %rax
  pop    %rdx
  fldz
  cmp    %rbp,%rbx
  jne    L63
  fstp   %st(0)
  jmp    L28
L40:
  fstp   %st(0)
L28:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D2: w

tool: D18: %Lf


assistant: ```c
void counter(long double *array) {
  FILE *fp;
  char output[] = "int-cgrfs.dat";
  int q;
  fp = fopen(output, "w");
  for (q = 0; q < 1000000; q++) {
    if (array[q] != 0) {
      fprintf(fp, "%Lf\n", array[q]);
    }
  }
  fclose(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<counter>:
  endbr64
  push   %r13
  mov    $0x74,%ecx
  lea    D16(%rip),%rsi
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0xf42400(%rbx),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x667267632d746e69,%rax
  lea    0xa(%rsp),%rdi
  movl   $0x61642e73,0x12(%rsp)
  mov    %cx,0x16(%rsp)
  mov    %rax,0xa(%rsp)
  call   <fopen@plt>
  mov    %rax,%r12
  fldz
  jmp    L75
  cs nopw 0x0(%rax,%rax,1)
L78:
  fstp   %st(0)
  add    $0x10,%rbx
  cmp    %rbp,%rbx
  je     L53
L75:
  fldt   (%rbx)
  fld    %st(1)
  fxch   %st(1)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L10
  je     L78
  fstp   %st(1)
  jmp    L62
L10:
  fstp   %st(1)
  nop
L62:
  sub    $0x10,%rsp
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x10,%rbx
  fstpt  (%rsp)
  call   <fprintf@plt>
  pop    %rax
  pop    %rdx
  fldz
  cmp    %rbp,%rbx
  jne    L75
  fstp   %st(0)
  jmp    L16
L53:
  fstp   %st(0)
L16:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D16: w

tool: D11: %Lf


assistant: ```c
void counter(long double *array) {
  FILE *fp;
  char output[] = "int-cgrfs.dat";
  int q;
  fp = fopen(output, "w");
  for (q = 0; q < 1000000; q++) {
    if (array[q] != 0) {
      fprintf(fp, "%Lf\n", array[q]);
    }
  }
  fclose(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6867666564636261,%rax
  movabs $0x706f6e6d6c6b6a69,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x7877767574737271,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x7a79,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x65,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x39(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x39(%rbp),%eax
  movsbl %al,%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L28
  movzbl -0x39(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L28:
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  movzbl -0x39(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string

tool: D40: Character 'e' found at position %d.



tool: D27: Specify character to look for: 

tool: D46: %c

tool: D43: Character '%c' could not be found.



tool: D23: Character '%c' was found at position %d.



assistant: ```c
int main() {
  char str[] = "abcdefghijklmnopqrstuvwxyz";
  char look;
  char *pos;
  pos = strchr(str, 'e');
  printf("Character 'e' found at position %d.\n\n", pos - str);
  printf("Specify character to look for: ");
  scanf("%c", &look);
  pos = strchr(str, look);
  if (pos == NULL)
    printf("Character '%c' could not be found.\n\n", look);
  else
    printf("Character '%c' was found at position %d.\n\n", look, pos - str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x6867666564636261,%rax
  movabs $0x706f6e6d6c6b6a69,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x7877767574737271,%rax
  mov    %rax,0x20(%rsp)
  movw   $0x7a79,0x28(%rsp)
  movb   $0x0,0x2a(%rsp)
  lea    0x10(%rsp),%rbx
  mov    $0x65,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  sub    %rbx,%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L10
  lea    0x10(%rsp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  movsbl 0xf(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L10:
  movsbl 0xf(%rsp),%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string

tool: D36: Character 'e' found at position %d.



tool: D20: Specify character to look for: 

tool: D2: %c

tool: D11: Character '%c' was found at position %d.



tool: D23: Character '%c' could not be found.



assistant: ```c
int main() {
  char str[] = "abcdefghijklmnopqrstuvwxyz";
  char look;
  char *pos;
  pos = strchr(str, 'e');
  printf("Character 'e' found at position %d.\n\n", pos - str);
  printf("Specify character to look for: ");
  scanf("%c", &look);
  pos = strchr(str, look);
  if (pos == NULL)
    printf("Character '%c' could not be found.\n\n", look);
  else
    printf("Character '%c' was found at position %d.\n\n", look, pos - str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x65,%esi
  sub    $0x40,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movb   $0x0,0x2a(%rsp)
  movabs $0x7877767574737271,%rax
  mov    %rax,0x20(%rsp)
  mov    %rbx,%rdi
  mov    $0x7a79,%eax
  movaps %xmm0,0x10(%rsp)
  mov    %ax,0x28(%rsp)
  call   <strchr@plt>
  lea    D33(%rip),%rdi
  sub    %rbx,%rax
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  sub    %rbx,%rax
  movsbl 0xf(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L26:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  movsbl 0xf(%rsp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: byte[16]
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D50
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string

tool: {"D3": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: D33: Character 'e' found at position %d.



tool: D50: Specify character to look for: 

tool: D20: %c

tool: D4: Character '%c' was found at position %d.



tool: D21: Character '%c' could not be found.



assistant: ```c
int main() {
  char str[] = "abcdefghijklmnopqrstuvwxyz";
  char look;
  char *pos;
  pos = strchr(str, 'e');
  printf("Character 'e' found at position %d.\n\n", pos - str);
  printf("Specify character to look for: ");
  scanf("%c", &look);
  pos = strchr(str, look);
  if (pos == NULL)
    printf("Character '%c' could not be found.\n\n", look);
  else
    printf("Character '%c' was found at position %d.\n\n", look, pos - str);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x65,%esi
  sub    $0x40,%rsp
  movdqa D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movb   $0x0,0x2a(%rsp)
  movabs $0x7877767574737271,%rax
  mov    %rax,0x20(%rsp)
  mov    %rbx,%rdi
  mov    $0x7a79,%eax
  movaps %xmm0,0x10(%rsp)
  mov    %ax,0x28(%rsp)
  call   <strchr@plt>
  lea    D22(%rip),%rdi
  sub    %rbx,%rax
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  sub    %rbx,%rax
  movsbl 0xf(%rsp),%esi
  lea    D5(%rip),%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  movsbl 0xf(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D36
datatype: byte[16]
name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D40
datatype: string
name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: {"D36": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: D22: Character 'e' found at position %d.



tool: D4: Specify character to look for: 

tool: D40: %c

tool: D5: Character '%c' was found at position %d.



tool: D17: Character '%c' could not be found.



assistant: ```c
int main() {
  char str[] = "abcdefghijklmnopqrstuvwxyz";
  char look;
  char *pos;
  pos = strchr(str, 'e');
  printf("Character 'e' found at position %d.\n\n", pos - str);
  printf("Specify character to look for: ");
  scanf("%c", &look);
  pos = strchr(str, look);
  if (pos == NULL)
    printf("Character '%c' could not be found.\n\n", look);
  else
    printf("Character '%c' was found at position %d.\n\n", look, pos - str);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    D48(%rip),%rax
  mov    %rax,-0x8(%rbp)
L25:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
  jmp    L12
L33:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,D11(%rip)
  mov    D11(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    D11(%rip),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,D11(%rip)
  movb   $0x0,(%rax)
L32:
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
char *strtok(char *str, const char *delim) {
  static char *tok;
  if (str == 0)
    str = tok;
  str += strspn(str, delim);
  if (*str == '\0')
    return 0;
  tok = str + strcspn(str, delim);
  if (*tok != '\0')
    *(tok)++ = '\0';
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  cmove  D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  je     L14
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,D4(%rip)
  cmpb   $0x0,(%rax)
  je     L12
  lea    0x1(%rax),%rdx
  mov    %rdx,D4(%rip)
  movb   $0x0,(%rax)
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x0,%ebx
  jmp    L12
```

assistant: ```c
char *strtok(char *str, const char *delim) {
  static char *tok;
  if (str == 0)
    str = tok;
  str += strspn(str, delim);
  if (*str == '\0')
    return 0;
  tok = str + strcspn(str, delim);
  if (*tok != '\0')
    *(tok)++ = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtok>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  cmove  D26(%rip),%r12
  mov    %r12,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L17
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcspn@plt>
  cltq
  add    %r12,%rax
  cmpb   $0x0,(%rax)
  mov    %rax,D15(%rip)
  je     L13
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
  mov    %rdx,D15(%rip)
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L17:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *str, const char *delim) {
  static char *tok;
  if (str == 0)
    str = tok;
  str += strspn(str, delim);
  if (*str == '\0')
    return 0;
  tok = str + strcspn(str, delim);
  if (*tok != '\0')
    *(tok)++ = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtok>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  cmove  D13(%rip),%r12
  mov    %r12,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L19
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcspn@plt>
  cltq
  add    %r12,%rax
  cmpb   $0x0,(%rax)
  mov    %rax,D27(%rip)
  je     L10
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
  mov    %rdx,D27(%rip)
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L19:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *str, const char *delim) {
  static char *tok;
  if (str == 0)
    str = tok;
  str += strspn(str, delim);
  if (*str == '\0')
    return 0;
  tok = str + strcspn(str, delim);
  if (*tok != '\0')
    *(tok)++ = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  shl    $0x7,%eax
  and    $0xb500,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x3,%eax
  or     $0x77fa,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL);
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned short)3) | (unsigned short)30714;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  and    $0xb500,%eax
  shl    $0x3,%eax
  or     $0x77fa,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL);
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned short)3) | (unsigned short)30714;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  and    $0xb500,%eax
  shl    $0x3,%eax
  or     $0x77fa,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL);
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned short)3) | (unsigned short)30714;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  and    $0xb500,%eax
  shl    $0x3,%eax
  or     $0x77fa,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy14;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] >>= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] << (((state[local1] >> (unsigned short)3) & (unsigned short)7) | 1UL);
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << (unsigned short)3) | (unsigned short)30714;
  }
}
```