ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L65
L35:
  addl   $0x1,-0xc(%rbp)
L65:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jg     L35
  jmp    L73
L38:
  subl   $0x1,-0x8(%rbp)
L73:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L38
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L50
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L65
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L62
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
L62:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L42
  mov    -0x20(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  nop
L42:
  nop
  leave
  ret
```

assistant: ```c
void quickSort(char *stringToSort, int left, int right) {
  char pom;
  int i = left;
  int j = right;
  int pivot = stringToSort[(i + j) / 2];
  do {
    while (stringToSort[i] < pivot) {
      i = i + 1;
    }
    while (stringToSort[j] > pivot) {
      j = j - 1;
    }
    if (i <= j) {
      pom = stringToSort[i];
      stringToSort[i] = stringToSort[j];
      stringToSort[j] = pom;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (left < j)
    quickSort(stringToSort, left, j);
  if (i < right)
    quickSort(stringToSort, i, right);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  movzbl (%rdi,%rax,1),%esi
  movslq %r13d,%r8
  add    %rdi,%r8
  mov    %r13d,%r9d
  lea    0x1(%r13),%r10d
  mov    %r12d,%edx
  jmp    L97
L91:
  mov    %cl,(%r14)
  mov    %r11b,(%rdi)
  mov    %r10d,%ebx
  sub    $0x1,%edx
  cmp    %edx,%r10d
  jg     L48
L21:
  add    $0x1,%r8
  add    $0x1,%r10d
  add    $0x1,%r9d
L97:
  mov    %r9d,%ebx
  mov    %r8,%r14
  movzbl (%r8),%r11d
  cmp    %r11b,%sil
  jg     L21
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  movzbl (%rdi),%ecx
  cmp    %cl,%sil
  jge    L76
  lea    -0x1(%rbp,%rax,1),%rcx
  mov    %rcx,%rax
  sub    $0x1,%edx
  sub    %ecx,%edx
  mov    %edx,%r15d
L98:
  lea    (%r15,%rax,1),%edx
  mov    %rax,%rdi
  sub    $0x1,%rax
  movzbl 0x1(%rax),%ecx
  cmp    %cl,%sil
  jl     L98
L76:
  cmp    %edx,%ebx
  jle    L91
L48:
  cmp    %edx,%r13d
  jl     L95
L26:
  cmp    %ebx,%r12d
  jg     L84
L64:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quickSort>
  jmp    L26
L84:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <quickSort>
  jmp    L64
```

assistant: ```c
void quickSort(char *stringToSort, int left, int right) {
  char pom;
  int i = left;
  int j = right;
  int pivot = stringToSort[(i + j) / 2];
  do {
    while (stringToSort[i] < pivot) {
      i = i + 1;
    }
    while (stringToSort[j] > pivot) {
      j = j - 1;
    }
    if (i <= j) {
      pom = stringToSort[i];
      stringToSort[i] = stringToSort[j];
      stringToSort[j] = pom;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (left < j)
    quickSort(stringToSort, left, j);
  if (i < right)
    quickSort(stringToSort, i, right);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quickSort>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
L62:
  lea    0x0(%r13,%rbp,1),%edx
  movslq %r13d,%r9
  lea    0x1(%r13),%r14d
  mov    %r13d,%r10d
  mov    %edx,%eax
  add    %r12,%r9
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  sar    %eax
  cltq
  movzbl (%r12,%rax,1),%edi
  movslq %ebp,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl (%r9),%r11d
  lea    (%r12,%rax,1),%rsi
  mov    %r10d,%ebx
  movzbl (%rsi),%ecx
  cmp    %r11b,%dil
  jg     L5
  cmp    %cl,%dil
  jge    L53
  lea    -0x1(%r12,%rax,1),%rax
  lea    -0x1(%rdx),%r8d
  sub    %eax,%r8d
  nopl   0x0(%rax)
L76:
  lea    (%r8,%rax,1),%edx
  mov    %rax,%rsi
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  cmp    %cl,%dil
  jl     L76
L53:
  cmp    %r10d,%edx
  jge    L11
L91:
  cmp    %edx,%r13d
  jl     L71
L70:
  cmp    %ebx,%ebp
  jle    L88
  mov    %ebx,%r13d
  jmp    L62
  xchg   %ax,%ax
L11:
  sub    $0x1,%edx
  mov    %cl,(%r9)
  mov    %r14d,%ebx
  mov    %r11b,(%rsi)
  cmp    %edx,%r14d
  jg     L91
  movslq %edx,%rax
L5:
  add    $0x1,%r9
  add    $0x1,%r14d
  add    $0x1,%r10d
  jmp    L37
L88:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L71:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSort>
  jmp    L70
```

assistant: ```c
void quickSort(char *stringToSort, int left, int right) {
  char pom;
  int i = left;
  int j = right;
  int pivot = stringToSort[(i + j) / 2];
  do {
    while (stringToSort[i] < pivot) {
      i = i + 1;
    }
    while (stringToSort[j] > pivot) {
      j = j - 1;
    }
    if (i <= j) {
      pom = stringToSort[i];
      stringToSort[i] = stringToSort[j];
      stringToSort[j] = pom;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (left < j)
    quickSort(stringToSort, left, j);
  if (i < right)
    quickSort(stringToSort, i, right);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LastChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L5:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *LastChar(strpt)
char *strpt;
{
  char *c;
  c = strpt;
  while (*c != '\0')
    c++;
  return (--c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<LastChar>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
L18:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L18
L19:
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *LastChar(strpt)
char *strpt;
{
  char *c;
  c = strpt;
  while (*c != '\0')
    c++;
  return (--c);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LastChar>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  nopl   0x0(%rax)
L16:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L16
  ret
  nopl   (%rax)
L17:
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *LastChar(strpt)
char *strpt;
{
  char *c;
  c = strpt;
  while (*c != '\0')
    c++;
  return (--c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LastChar>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  nopl   0x0(%rax)
L19:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L19
  ret
  nopl   (%rax)
L10:
  lea    -0x1(%rdi),%rax
  ret
```

assistant: ```c
char *LastChar(strpt)
char *strpt;
{
  char *c;
  c = strpt;
  while (*c != '\0')
    c++;
  return (--c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ImageKit_Colorspace_RGB2HSV>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movapd %xmm0,%xmm3
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  movapd %xmm1,%xmm5
  maxsd  %xmm0,%xmm5
  movapd %xmm2,%xmm6
  maxsd  %xmm5,%xmm6
  movq   %xmm6,%rbx
  movapd %xmm1,%xmm0
  minsd  %xmm3,%xmm0
  movapd %xmm2,%xmm7
  minsd  %xmm0,%xmm7
  movapd %xmm6,%xmm4
  subsd  %xmm7,%xmm4
  mov    D60(%rip),%r14
  comisd D60(%rip),%xmm6
  jbe    L81
  movapd %xmm4,%xmm7
  divsd  %xmm6,%xmm7
  movq   %xmm7,%r14
L81:
  ucomisd D60(%rip),%xmm4
  jp     L79
  pxor   %xmm0,%xmm0
  jne    L79
L67:
  divsd  D63(%rip),%xmm0
  movsd  %xmm0,0x0(%r13)
  mov    %r14,(%r12)
  mov    %rbx,0x0(%rbp)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L79:
  movq   %rbx,%xmm7
  ucomisd %xmm3,%xmm7
  jp     L54
  je     L69
L54:
  movq   %rbx,%xmm7
  ucomisd %xmm1,%xmm7
  jp     L64
  jne    L64
  subsd  %xmm3,%xmm2
  divsd  %xmm4,%xmm2
  addsd  D3(%rip),%xmm2
  movapd %xmm2,%xmm0
  jmp    L67
L69:
  subsd  %xmm2,%xmm1
  divsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  movsd  D63(%rip),%xmm1
  call   <fmod@plt>
  jmp    L67
L64:
  subsd  %xmm1,%xmm3
  divsd  %xmm4,%xmm3
  addsd  D49(%rip),%xmm3
  movapd %xmm3,%xmm0
  jmp    L67
```

tool_calls: name: read_data
arguments: data_tag: D60
datatype: f64[2]
name: read_data
arguments: data_tag: D63
datatype: f64
name: read_data
arguments: data_tag: D3
datatype: f64
name: read_data
arguments: data_tag: D49
datatype: f64

tool: {"D60": [0.0,6.0]}

tool: D63: 6

tool: D3: 2

tool: D49: 4

assistant: ```c
int ImageKit_Colorspace_RGB2HSV(double r, double g, double b, double *oh, double *os, double *ov) {
  double hue;
  double saturation;
  double value;
  double M;
  double m;
  double C;
  M = r;
  if (M < g)
    M = g;
  if (M < b)
    M = b;
  m = r;
  if (m > g)
    m = g;
  if (m > b)
    m = b;
  C = M - m;
  value = M;
  saturation = ((M > 0) ? C / M : 0.0);
  if (C == 0) {
    hue = 0.0;
  } else if (M == r) {
    hue = fmod((g - b) / C, 6.0);
  } else if (M == g) {
    hue = (b - r) / C + 2.0;
  } else {
    hue = (r - g) / C + 4.0;
  }
  *oh = hue / 6.0;
  *os = saturation;
  *ov = value;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ImageKit_Colorspace_RGB2HSV>:
  endbr64
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm7
  sub    $0x38,%rsp
  maxsd  %xmm0,%xmm3
  minsd  %xmm0,%xmm4
  movapd %xmm2,%xmm6
  maxsd  %xmm3,%xmm7
  minsd  %xmm4,%xmm6
  pxor   %xmm4,%xmm4
  comisd %xmm4,%xmm7
  movapd %xmm7,%xmm5
  movapd %xmm7,%xmm3
  subsd  %xmm6,%xmm5
  movapd %xmm4,%xmm6
  jbe    L8
  movapd %xmm5,%xmm6
  divsd  %xmm7,%xmm6
L8:
  ucomisd %xmm4,%xmm5
  jp     L89
  jne    L89
L50:
  movsd  %xmm4,(%rdi)
  xor    %eax,%eax
  movsd  %xmm6,(%rsi)
  movsd  %xmm3,(%rdx)
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L89:
  ucomisd %xmm0,%xmm3
  jp     L71
  je     L20
L71:
  ucomisd %xmm1,%xmm3
  jp     L42
  jne    L42
  subsd  %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  addsd  D47(%rip),%xmm2
  divsd  D52(%rip),%xmm2
  movapd %xmm2,%xmm4
  jmp    L50
  cs nopw 0x0(%rax,%rax,1)
L42:
  subsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  addsd  D18(%rip),%xmm0
  divsd  D52(%rip),%xmm0
  movapd %xmm0,%xmm4
  jmp    L50
  xchg   %ax,%ax
L20:
  subsd  %xmm2,%xmm1
  mov    D52(%rip),%rax
  mov    %rdx,0x28(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %rdi,0x18(%rsp)
  divsd  %xmm5,%xmm1
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
  call   <fmod@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm6
  divsd  D52(%rip),%xmm0
  mov    0x18(%rsp),%rdi
  mov    0x20(%rsp),%rsi
  movapd %xmm0,%xmm4
  mov    0x28(%rsp),%rdx
  jmp    L50
```

tool_calls: name: extract_symbolic_data
arguments: tag: D47
data_type: f64
name: extract_symbolic_data
arguments: tag: D52
data_type: f64
name: extract_symbolic_data
arguments: tag: D18
data_type: f64

tool: D47: 2

tool: D52: 6

tool: D18: 4

assistant: ```c
int ImageKit_Colorspace_RGB2HSV(double r, double g, double b, double *oh, double *os, double *ov) {
  double hue;
  double saturation;
  double value;
  double M;
  double m;
  double C;
  M = r;
  if (M < g)
    M = g;
  if (M < b)
    M = b;
  m = r;
  if (m > g)
    m = g;
  if (m > b)
    m = b;
  C = M - m;
  value = M;
  saturation = ((M > 0) ? C / M : 0.0);
  if (C == 0) {
    hue = 0.0;
  } else if (M == r) {
    hue = fmod((g - b) / C, 6.0);
  } else if (M == g) {
    hue = (b - r) / C + 2.0;
  } else {
    hue = (r - g) / C + 4.0;
  }
  *oh = hue / 6.0;
  *os = saturation;
  *ov = value;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ImageKit_Colorspace_RGB2HSV>:
  endbr64
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  movapd %xmm2,%xmm7
  sub    $0x38,%rsp
  maxsd  %xmm0,%xmm3
  minsd  %xmm0,%xmm4
  movapd %xmm2,%xmm6
  maxsd  %xmm3,%xmm7
  minsd  %xmm4,%xmm6
  pxor   %xmm4,%xmm4
  comisd %xmm4,%xmm7
  movapd %xmm7,%xmm5
  movapd %xmm7,%xmm3
  subsd  %xmm6,%xmm5
  movapd %xmm4,%xmm6
  jbe    L92
  movapd %xmm5,%xmm6
  divsd  %xmm7,%xmm6
L92:
  ucomisd %xmm4,%xmm5
  jp     L70
  jne    L70
L28:
  movsd  %xmm4,(%rdi)
  xor    %eax,%eax
  movsd  %xmm6,(%rsi)
  movsd  %xmm3,(%rdx)
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L70:
  ucomisd %xmm0,%xmm3
  jp     L90
  je     L69
L90:
  ucomisd %xmm1,%xmm3
  jp     L87
  jne    L87
  subsd  %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  addsd  D49(%rip),%xmm2
  divsd  D14(%rip),%xmm2
  movapd %xmm2,%xmm4
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L87:
  subsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  addsd  D43(%rip),%xmm0
  divsd  D14(%rip),%xmm0
  movapd %xmm0,%xmm4
  jmp    L28
  xchg   %ax,%ax
L69:
  subsd  %xmm2,%xmm1
  mov    D14(%rip),%rax
  mov    %rdx,0x28(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %rdi,0x18(%rsp)
  divsd  %xmm5,%xmm1
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
  call   <fmod@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm6
  divsd  D14(%rip),%xmm0
  mov    0x18(%rsp),%rdi
  mov    0x20(%rsp),%rsi
  movapd %xmm0,%xmm4
  mov    0x28(%rsp),%rdx
  jmp    L28
```

tool_calls: name: retrieve_data
arguments: label: D49
datatype: f64
name: retrieve_data
arguments: label: D14
datatype: f64
name: retrieve_data
arguments: label: D43
datatype: f64

tool: D49: 2

tool: D14: 6

tool: D43: 4

assistant: ```c
int ImageKit_Colorspace_RGB2HSV(double r, double g, double b, double *oh, double *os, double *ov) {
  double hue;
  double saturation;
  double value;
  double M;
  double m;
  double C;
  M = r;
  if (M < g)
    M = g;
  if (M < b)
    M = b;
  m = r;
  if (m > g)
    m = g;
  if (m > b)
    m = b;
  C = M - m;
  value = M;
  saturation = ((M > 0) ? C / M : 0.0);
  if (C == 0) {
    hue = 0.0;
  } else if (M == r) {
    hue = fmod((g - b) / C, 6.0);
  } else if (M == g) {
    hue = (b - r) / C + 2.0;
  } else {
    hue = (r - g) / C + 4.0;
  }
  *oh = hue / 6.0;
  *os = saturation;
  *ov = value;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_numb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x9,-0x4(%rbp)
  jle    L5
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *init_numb(int *v) {
  int i = 0;
  for (i = 0; i < 10; i++)
    v[i] = i;
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_numb>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L7:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    $0xa,%rdx
  jne    L7
  ret
```

assistant: ```c
int *init_numb(int *v) {
  int i = 0;
  for (i = 0; i < 10; i++)
    v[i] = i;
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<init_numb>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L4:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    $0xa,%rdx
  jne    L4
  ret
```

assistant: ```c
int *init_numb(int *v) {
  int i = 0;
  for (i = 0; i < 10; i++)
    v[i] = i;
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_numb>:
  endbr64
  movdqa D24(%rip),%xmm0
  mov    D9(%rip),%rdx
  mov    %rdi,%rax
  movups %xmm0,(%rdi)
  movdqa D22(%rip),%xmm0
  mov    %rdx,0x20(%rdi)
  movups %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: byte[16]
name: retrieve_data
arguments: tag: D9
datatype: byte[8]
name: retrieve_data
arguments: tag: D22
datatype: byte[16]

tool: {"D24": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D9": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D22": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int *init_numb(int *v) {
  int i = 0;
  for (i = 0; i < 10; i++)
    v[i] = i;
  return v;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L43
  mov    $0x0,%eax
  jmp    L2
L43:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  jmp    L35
L37:
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L45
  mov    -0x10(%rbp),%rax
  jmp    L2
L45:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L66
  mov    -0x8(%rbp),%rax
  sub    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x11(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L37
L66:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
unsigned char *memmem(unsigned char *haystack, size_t hlen, const unsigned char *needle, size_t nlen) {
  unsigned char needle_first;
  unsigned char *p = haystack;
  size_t plen = hlen;
  if (!nlen)
    return NULL;
  needle_first = *(unsigned char *)needle;
  while (plen >= nlen && (p = (unsigned char *)memchr(p, needle_first, plen - nlen + 1))) {
    if (!memcmp(p, needle, nlen))
      return p;
    p++;
    plen = hlen - (p - haystack);
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rcx,%rcx
  je     L54
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%rbp
  movzbl (%rdx),%r15d
  mov    %rsi,%rdx
  mov    $0x1,%eax
  sub    %rcx,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%ebx
  cmp    %rcx,%rsi
  jb     L21
L37:
  add    0x8(%rsp),%rdx
  movzbl %r15b,%esi
  call   <memchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L21
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L21
  lea    0x1(%rbx),%rdi
  mov    %rdi,%rax
  sub    %r14,%rax
  mov    %r12,%rdx
  sub    %rax,%rdx
  cmp    %rdx,%rbp
  jbe    L37
  mov    $0x0,%ebx
L21:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  mov    $0x0,%ebx
  jmp    L21
```

assistant: ```c
unsigned char *memmem(unsigned char *haystack, size_t hlen, const unsigned char *needle, size_t nlen) {
  unsigned char needle_first;
  unsigned char *p = haystack;
  size_t plen = hlen;
  if (!nlen)
    return NULL;
  needle_first = *(unsigned char *)needle;
  while (plen >= nlen && (p = (unsigned char *)memchr(p, needle_first, plen - nlen + 1))) {
    if (!memcmp(p, needle, nlen))
      return p;
    p++;
    plen = hlen - (p - haystack);
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %rcx,%rcx
  je     L23
  movzbl (%rdx),%r13d
  mov    %rdx,%rbp
  mov    (%rsp),%rdx
  mov    %rcx,%rbx
  cmp    %rcx,%rdx
  jb     L23
  mov    $0x1,%r14d
  mov    %rdi,%r12
  sub    %rcx,%r14
  mov    %r14,0x8(%rsp)
  jmp    L42
  nopl   0x0(%rax)
L14:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L55
  lea    0x1(%r14),%rdi
  mov    (%rsp),%rdx
  mov    %rdi,%rax
  sub    %r12,%rax
  sub    %rax,%rdx
  cmp    %rdx,%rbx
  ja     L23
L42:
  add    0x8(%rsp),%rdx
  mov    %r13d,%esi
  call   <memchr@plt>
  mov    %rax,%r14
  mov    %rax,%r15
  test   %rax,%rax
  jne    L14
L23:
  xor    %r15d,%r15d
L55:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *memmem(unsigned char *haystack, size_t hlen, const unsigned char *needle, size_t nlen) {
  unsigned char needle_first;
  unsigned char *p = haystack;
  size_t plen = hlen;
  if (!nlen)
    return NULL;
  needle_first = *(unsigned char *)needle;
  while (plen >= nlen && (p = (unsigned char *)memchr(p, needle_first, plen - nlen + 1))) {
    if (!memcmp(p, needle, nlen))
      return p;
    p++;
    plen = hlen - (p - haystack);
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memmem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %rcx,%rcx
  je     L31
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %rsi,%rdx
  movzbl 0x0(%rbp),%r13d
  cmp    %rcx,%rsi
  jb     L31
  mov    $0x1,%r14d
  mov    %rdi,%r12
  sub    %rcx,%r14
  mov    %r14,0x8(%rsp)
  jmp    L3
  nopl   0x0(%rax)
L19:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L1
  lea    0x1(%r14),%rdi
  mov    (%rsp),%rdx
  mov    %rdi,%rax
  sub    %r12,%rax
  sub    %rax,%rdx
  cmp    %rdx,%rbx
  ja     L31
L3:
  add    0x8(%rsp),%rdx
  mov    %r13d,%esi
  call   <memchr@plt>
  mov    %rax,%r14
  mov    %rax,%r15
  test   %rax,%rax
  jne    L19
L31:
  xor    %r15d,%r15d
L1:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *memmem(unsigned char *haystack, size_t hlen, const unsigned char *needle, size_t nlen) {
  unsigned char needle_first;
  unsigned char *p = haystack;
  size_t plen = hlen;
  if (!nlen)
    return NULL;
  needle_first = *(unsigned char *)needle;
  while (plen >= nlen && (p = (unsigned char *)memchr(p, needle_first, plen - nlen + 1))) {
    if (!memcmp(p, needle, nlen))
      return p;
    p++;
    plen = hlen - (p - haystack);
  }
  return NULL;
}
```