ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <testIsSQL@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x7a11f,%ebx
  jg     L10
  mov    $0x7a120,%edx
  mov    %ebx,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L1:
  pop    %rbx
  ret
L10:
  mov    $0x7a120,%edx
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: label: D20
type_guessed: string
name: disassemble_data
arguments: label: D26
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D20: 
TPS : %d



tool: D26: FAIL: %d < %d


tool: D0: OK: %d > %d


assistant: ```c
int main() {
  const int mintps = 500000;
  int tps = testIsSQL();
  printf("\nTPS : %d\n\n", tps);
  if (tps < 500000) {
    printf("FAIL: %d < %d\n", tps, mintps);
    return 1;
  } else {
    printf("OK: %d > %d\n", tps, mintps);
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <testIsSQL@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7a120,%edx
  mov    %ebp,%esi
  cmp    $0x7a11f,%ebp
  jg     L2
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
L2:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D3: 
TPS : %d



tool: D23: FAIL: %d < %d


tool: D1: OK: %d > %d


assistant: ```c
int main() {
  const int mintps = 500000;
  int tps = testIsSQL();
  printf("\nTPS : %d\n\n", tps);
  if (tps < 500000) {
    printf("FAIL: %d < %d\n", tps, mintps);
    return 1;
  } else {
    printf("OK: %d > %d\n", tps, mintps);
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <testIsSQL@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7a120,%edx
  mov    %ebp,%esi
  cmp    $0x7a11f,%ebp
  jg     L3
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
L3:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string

tool: D15: 
TPS : %d



tool: D4: FAIL: %d < %d


tool: D20: OK: %d > %d


assistant: ```c
int main() {
  const int mintps = 500000;
  int tps = testIsSQL();
  printf("\nTPS : %d\n\n", tps);
  if (tps < 500000) {
    printf("FAIL: %d < %d\n", tps, mintps);
    return 1;
  } else {
    printf("OK: %d > %d\n", tps, mintps);
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<time_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: PASS: test22


assistant: ```c
void time_end(int value) {
  printf("PASS: test22\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<time_end>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string

tool: D4: PASS: test22


assistant: ```c
void time_end(int value) {
  printf("PASS: test22\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<time_end>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: PASS: test22


assistant: ```c
void time_end(int value) {
  printf("PASS: test22\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<time_end>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: PASS: test22


assistant: ```c
void time_end(int value) {
  printf("PASS: test22\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L56
L51:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L19
  mov    $0xffffffff,%eax
  jmp    L10
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L52
  mov    $0x1,%eax
  jmp    L10
L52:
  addl   $0x1,-0x4(%rbp)
L56:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L51
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int compare(int *a, int *b, int dim) {
  int j;
  for (j = 0; j < dim; j++) {
    if (a[j] < b[j])
      return -1;
    else if (a[j] > b[j])
      return +1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L31
  mov    %edx,%edx
  mov    $0x0,%eax
L14:
  mov    (%rdi,%rax,4),%r8d
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,%r8d
  jl     L1
  jg     L23
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    $0x0,%eax
  ret
L31:
  mov    $0x0,%eax
  ret
L1:
  mov    $0xffffffff,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(int *a, int *b, int dim) {
  int j;
  for (j = 0; j < dim; j++) {
    if (a[j] < b[j])
      return -1;
    else if (a[j] > b[j])
      return +1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L40
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L6
  nop
L27:
  jg     L26
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L40
L6:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jge    L27
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(int *a, int *b, int dim) {
  int j;
  for (j = 0; j < dim; j++) {
    if (a[j] < b[j])
      return -1;
    else if (a[j] > b[j])
      return +1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L49
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L38
  nop
L21:
  jg     L26
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L49
L38:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jge    L21
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(int *a, int *b, int dim) {
  int j;
  for (j = 0; j < dim; j++) {
    if (a[j] < b[j])
      return -1;
    else if (a[j] > b[j])
      return +1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_MM_MIN_EPI8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_cmpgt_epi8@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_andnot_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_or_si128@plt>
  leave
  ret
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) __m128i _MM_MIN_EPI8(__m128i a, __m128i b) {
  __m128i cmp, resa, resb;
  cmp = _mm_cmpgt_epi8(b, a);
  resa = _mm_and_si128(cmp, a);
  resb = _mm_andnot_si128(cmp, b);
  return _mm_or_si128(resa, resb);
}
```
user: What is the c source code of the assembly code below?

```asm
<_MM_MIN_EPI8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <_mm_cmpgt_epi8@plt>
  mov    %eax,%ebx
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,%r12d
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <_mm_andnot_si128@plt>
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <_mm_or_si128@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) __m128i _MM_MIN_EPI8(__m128i a, __m128i b) {
  __m128i cmp, resa, resb;
  cmp = _mm_cmpgt_epi8(b, a);
  resa = _mm_and_si128(cmp, a);
  resb = _mm_andnot_si128(cmp, b);
  return _mm_or_si128(resa, resb);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_MM_MIN_EPI8>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %r12d,%edi
  call   <_mm_cmpgt_epi8@plt>
  mov    %r13d,%esi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <_mm_andnot_si128@plt>
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    10a0 <_mm_or_si128@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) __m128i _MM_MIN_EPI8(__m128i a, __m128i b) {
  __m128i cmp, resa, resb;
  cmp = _mm_cmpgt_epi8(b, a);
  resa = _mm_and_si128(cmp, a);
  resb = _mm_andnot_si128(cmp, b);
  return _mm_or_si128(resa, resb);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_MM_MIN_EPI8>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %r12d,%edi
  call   <_mm_cmpgt_epi8@plt>
  mov    %r13d,%esi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <_mm_andnot_si128@plt>
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    10a0 <_mm_or_si128@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) __m128i _MM_MIN_EPI8(__m128i a, __m128i b) {
  __m128i cmp, resa, resb;
  cmp = _mm_cmpgt_epi8(b, a);
  resa = _mm_and_si128(cmp, a);
  resb = _mm_andnot_si128(cmp, b);
  return _mm_or_si128(resa, resb);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ta_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L0
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ta_alloc_size@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L17:
  mov    -0x8(%rbp),%rax
  jmp    L5
L0:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
char *ta_strdup(void *ta_parent, const char *str) {
  if (str) {
    size_t len = strlen(str) + 1;
    char *dup = ta_alloc_size(ta_parent, len);
    if (dup)
      memcpy(dup, str, len);
    return dup;
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ta_strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <ta_alloc_size@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L5:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ta_strdup(void *ta_parent, const char *str) {
  if (str) {
    size_t len = strlen(str) + 1;
    char *dup = ta_alloc_size(ta_parent, len);
    if (dup)
      memcpy(dup, str, len);
    return dup;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ta_strdup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L0
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  lea    0x1(%rax),%r13d
  movslq %r13d,%r13
  mov    %r13,%rsi
  call   <ta_alloc_size@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ta_strdup(void *ta_parent, const char *str) {
  if (str) {
    size_t len = strlen(str) + 1;
    char *dup = ta_alloc_size(ta_parent, len);
    if (dup)
      memcpy(dup, str, len);
    return dup;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ta_strdup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  lea    0x1(%rax),%r13d
  movslq %r13d,%r13
  mov    %r13,%rsi
  call   <ta_alloc_size@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ta_strdup(void *ta_parent, const char *str) {
  if (str) {
    size_t len = strlen(str) + 1;
    char *dup = ta_alloc_size(ta_parent, len);
    if (dup)
      memcpy(dup, str, len);
    return dup;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L89
  mov    $0x0,%eax
  jmp    L100
L44:
  cmpb   $0x0,-0x11(%rbp)
  jne    L133
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <undefine@plt>
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  jmp    L100
L133:
  addq   $0x1,-0x28(%rbp)
L89:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  test   %al,%al
  js     L119
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L128
L119:
  cmpb   $0x2d,-0x11(%rbp)
  je     L128
  cmpb   $0x2b,-0x11(%rbp)
  jne    L44
  jmp    L128
L24:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <undefine@plt>
L78:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L38
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L100
L38:
  movzbl -0x11(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <parse_pattern_letter@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L78
  jmp    L55
L115:
  nop
L55:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
L128:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0x0,%eax
L100:
  leave
  ret
```

assistant: ```c
char const *parse_prefix(char const *str, char const **patterns, struct partime *t) {
  char const *pat = *patterns;
  unsigned char c;
  if (!pat)
    return 0;
  while (!(((unsigned)(c = *str) <= 0177) && isalnum(c = *str)) && c != '-' && c != '+') {
    if (!c) {
      undefine(t);
      *patterns = 0;
      return str;
    }
    str++;
  }
  while (*pat) {
    char const *s = str;
    undefine(t);
    do {
      if (!(c = *pat++)) {
        *patterns = pat;
        return s;
      }
    } while ((s = parse_pattern_letter(s, c, t)) != 0);
    while (*pat++)
      continue;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_prefix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    (%rsi),%rbp
  test   %rbp,%rbp
  jne    L16
  mov    %rbp,%rdi
  jmp    L78
L107:
  mov    %r12,%rdi
  call   <undefine@plt>
  movq   $0x0,0x0(%r13)
  mov    %rbx,%rdi
  jmp    L78
L124:
  lea    -0x2b(%r14),%eax
  test   $0xfd,%al
  je     L79
  test   %r14b,%r14b
  je     L107
  add    $0x1,%rbx
L16:
  movzbl (%rbx),%r14d
  test   %r14b,%r14b
  js     L124
  movzbl %r14b,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L124
L79:
  mov    $0x0,%edi
  cmpb   $0x0,0x0(%rbp)
  je     L78
L23:
  mov    %r12,%rdi
  call   <undefine@plt>
  mov    %rbx,%rdi
L74:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%esi
  test   %sil,%sil
  je     L61
  movzbl %sil,%esi
  mov    %r12,%rdx
  call   <parse_pattern_letter@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L74
L91:
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  jne    L91
  cmpb   $0x0,0x0(%rbp)
  jne    L23
  jmp    L78
L61:
  mov    %rbp,0x0(%r13)
L78:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char const *parse_prefix(char const *str, char const **patterns, struct partime *t) {
  char const *pat = *patterns;
  unsigned char c;
  if (!pat)
    return 0;
  while (!(((unsigned)(c = *str) <= 0177) && isalnum(c = *str)) && c != '-' && c != '+') {
    if (!c) {
      undefine(t);
      *patterns = 0;
      return str;
    }
    str++;
  }
  while (*pat) {
    char const *s = str;
    undefine(t);
    do {
      if (!(c = *pat++)) {
        *patterns = pat;
        return s;
      }
    } while ((s = parse_pattern_letter(s, c, t)) != 0);
    while (*pat++)
      continue;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_prefix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%r14
  test   %r14,%r14
  jne    L55
  jmp    L114
  nopw   0x0(%rax,%rax,1)
L16:
  lea    -0x2b(%rbx),%eax
  test   $0xfd,%al
  je     L104
  test   %bl,%bl
  je     L42
  add    $0x1,%r13
L55:
  movzbl 0x0(%r13),%ebx
  test   %bl,%bl
  js     L16
  movzbl %bl,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L16
  nopl   (%rax)
L104:
  cmpb   $0x0,(%r14)
  je     L114
  mov    %rbp,%rdi
  call   <undefine@plt>
  mov    %r13,%rdi
  jmp    L107
  nopl   0x0(%rax,%rax,1)
L70:
  mov    %rbp,%rdx
  call   <parse_pattern_letter@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L94
L107:
  movzbl (%r14),%esi
  add    $0x1,%r14
  test   %sil,%sil
  jne    L70
  mov    %r14,(%r12)
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L94:
  add    $0x1,%r14
  cmpb   $0x0,-0x1(%r14)
  je     L104
  add    $0x1,%r14
  cmpb   $0x0,-0x1(%r14)
  je     L104
  jmp    L94
L42:
  mov    %rbp,%rdi
  call   <undefine@plt>
  mov    %r13,%rdi
  movq   $0x0,(%r12)
  pop    %rbx
  mov    %rdi,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L114:
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  mov    %rdi,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char const *parse_prefix(char const *str, char const **patterns, struct partime *t) {
  char const *pat = *patterns;
  unsigned char c;
  if (!pat)
    return 0;
  while (!(((unsigned)(c = *str) <= 0177) && isalnum(c = *str)) && c != '-' && c != '+') {
    if (!c) {
      undefine(t);
      *patterns = 0;
      return str;
    }
    str++;
  }
  while (*pat) {
    char const *s = str;
    undefine(t);
    do {
      if (!(c = *pat++)) {
        *patterns = pat;
        return s;
      }
    } while ((s = parse_pattern_letter(s, c, t)) != 0);
    while (*pat++)
      continue;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_prefix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%r14
  test   %r14,%r14
  jne    L52
  jmp    L90
  nopw   0x0(%rax,%rax,1)
L46:
  lea    -0x2b(%rbx),%eax
  test   $0xfd,%al
  je     L12
  test   %bl,%bl
  je     L28
  add    $0x1,%r13
L52:
  movzbl 0x0(%r13),%ebx
  test   %bl,%bl
  js     L46
  movzbl %bl,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L46
  nopl   (%rax)
L12:
  cmpb   $0x0,(%r14)
  je     L90
  mov    %rbp,%rdi
  call   <undefine@plt>
  mov    %r13,%rdi
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdx
  call   <parse_pattern_letter@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L20
L3:
  movzbl (%r14),%esi
  add    $0x1,%r14
  test   %sil,%sil
  jne    L18
  mov    %r14,(%r12)
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L20:
  add    $0x1,%r14
  cmpb   $0x0,-0x1(%r14)
  je     L12
  add    $0x1,%r14
  cmpb   $0x0,-0x1(%r14)
  je     L12
  jmp    L20
L28:
  mov    %rbp,%rdi
  call   <undefine@plt>
  mov    %r13,%rdi
  movq   $0x0,(%r12)
  pop    %rbx
  mov    %rdi,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L90:
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  mov    %rdi,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char const *parse_prefix(char const *str, char const **patterns, struct partime *t) {
  char const *pat = *patterns;
  unsigned char c;
  if (!pat)
    return 0;
  while (!(((unsigned)(c = *str) <= 0177) && isalnum(c = *str)) && c != '-' && c != '+') {
    if (!c) {
      undefine(t);
      *patterns = 0;
      return str;
    }
    str++;
  }
  while (*pat) {
    char const *s = str;
    undefine(t);
    do {
      if (!(c = *pat++)) {
        *patterns = pat;
        return s;
      }
    } while ((s = parse_pattern_letter(s, c, t)) != 0);
    while (*pat++)
      continue;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<svs_size_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x28,-0x4(%rbp)
  jg     L10
  mov    $0x31,%eax
  jmp    L36
L10:
  cmpl   $0x80,-0x4(%rbp)
  jg     L49
  mov    $0x32,%eax
  jmp    L36
L49:
  cmpl   $0xa0,-0x4(%rbp)
  jg     L8
  mov    $0x33,%eax
  jmp    L36
L8:
  cmpl   $0x140,-0x4(%rbp)
  jg     L61
  mov    $0x34,%eax
  jmp    L36
L61:
  cmpl   $0x280,-0x4(%rbp)
  jg     L74
  mov    $0x37,%eax
  jmp    L36
L74:
  mov    $0x39,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char svs_size_code(int w) {
  if (w <= 40) {
    return '1';
  }
  if (w <= 128) {
    return '2';
  }
  if (w <= 160) {
    return '3';
  }
  if (w <= 320) {
    return '4';
  }
  if (w <= 640) {
    return '7';
  }
  return '9';
}
```