ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fitfun>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jle    L15
  lea    -0x2(%rsi),%eax
  pxor   %xmm6,%xmm6
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%r12
  movsd  %xmm6,0x8(%rsp)
  nopl   (%rax)
L17:
  movsd  (%rbx),%xmm0
  movsd  0x8(%rbx),%xmm1
  mov    $0x2,%edi
  add    $0x8,%rbx
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mulsd  D6(%rip),%xmm0
  mov    $0x2,%edi
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  -0x8(%rbx),%xmm0
  subsd  D18(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm3
  addsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  cmp    %rbx,%r12
  jne    L17
L4:
  mov    $0x64,%edi
  call   <usleep@plt>
  movsd  0x8(%rsp),%xmm5
  movsd  %xmm5,0x0(%rbp)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: f64
name: parse_data
arguments: tag: D18
datatype: f64

tool: D6: 100

tool: D18: 1

assistant: ```c
void fitfun(double const *x, int N, double *res) {
  int i;
  double f = 0.0;
  for (i = 0; i < N - 1; i++)
    f = f + 100.0 * pow((x[i + 1] - x[i] * x[i]), 2) + pow((x[i] - 1.0), 2);
  usleep(100);
  *res = f;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sampler_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D2(%rip),%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  cvttsd2si %xmm0,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void sampler_i(int n, int m, int *x) {
  int i;
  for (i = 0; i < m; i++)
    x[i] = (int)((double)rand() / RAND_MAX * (double)(n - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sampler_i>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdx,%rax,4),%r12
  lea    -0x1(%rdi),%ebp
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D0(%rip),%rax
  divsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

assistant: ```c
void sampler_i(int n, int m, int *x) {
  int i;
  for (i = 0; i < m; i++)
    x[i] = (int)((double)rand() / RAND_MAX * (double)(n - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sampler_i>:
  endbr64
  test   %esi,%esi
  jle    L10
  sub    $0x1,%edi
  pxor   %xmm2,%xmm2
  push   %r12
  lea    -0x1(%rsi),%eax
  push   %rbp
  cvtsi2sd %edi,%xmm2
  lea    0x4(%rdx,%rax,4),%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    D9(%rip),%rbp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  0x0(%rbp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void sampler_i(int n, int m, int *x) {
  int i;
  for (i = 0; i < m; i++)
    x[i] = (int)((double)rand() / RAND_MAX * (double)(n - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sampler_i>:
  endbr64
  test   %esi,%esi
  jle    L4
  sub    $0x1,%edi
  pxor   %xmm2,%xmm2
  push   %r12
  lea    -0x1(%rsi),%eax
  push   %rbp
  cvtsi2sd %edi,%xmm2
  lea    0x4(%rdx,%rax,4),%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    D6(%rip),%rbp
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  0x0(%rbp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void sampler_i(int n, int m, int *x) {
  int i;
  for (i = 0; i < m; i++)
    x[i] = (int)((double)rand() / RAND_MAX * (double)(n - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<estimate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L0
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double estimate(elen, e)
int elen;
double *e;
{
  double Q;
  int eindex;
  Q = e[0];
  for (eindex = 1; eindex < elen; eindex++) {
    Q += e[eindex];
  }
  return Q;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<estimate>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L4
  lea    0x8(%rsi),%rax
  lea    -0x2(%rdi),%edx
  lea    0x10(%rsi,%rdx,8),%rdx
L2:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L2
L4:
  ret
```

assistant: ```c
double estimate(elen, e)
int elen;
double *e;
{
  double Q;
  int eindex;
  Q = e[0];
  for (eindex = 1; eindex < elen; eindex++) {
    Q += e[eindex];
  }
  return Q;
}
```
user: Translate the below assembly code into C programming language:

```asm
<estimate>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L9
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax)
L6:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
L9:
  ret
```

assistant: ```c
double estimate(elen, e)
int elen;
double *e;
{
  double Q;
  int eindex;
  Q = e[0];
  for (eindex = 1; eindex < elen; eindex++) {
    Q += e[eindex];
  }
  return Q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<estimate>:
  endbr64
  movsd  (%rsi),%xmm0
  cmp    $0x1,%edi
  jle    L29
  lea    -0x1(%rdi),%ecx
  cmp    $0x2,%edi
  je     L4
  mov    %ecx,%edx
  lea    0x8(%rsi),%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax)
L35:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L35
  mov    %ecx,%eax
  or     $0x1,%eax
  and    $0x1,%ecx
  je     L36
L15:
  cltq
  addsd  (%rsi,%rax,8),%xmm0
L29:
  ret
  nopl   0x0(%rax)
L36:
  ret
L4:
  mov    $0x1,%eax
  jmp    L15
```

assistant: ```c
double estimate(elen, e)
int elen;
double *e;
{
  double Q;
  int eindex;
  Q = e[0];
  for (eindex = 1; eindex < elen; eindex++) {
    Q += e[eindex];
  }
  return Q;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <square@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: f64
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D15: 5

tool: D11: %f squared is %f


assistant: ```c
int main(int argc, char *argv[]) {
  double a[1];
  double b[1];
  a[0] = 5.0;
  b[0] = 0.0;
  square(a, b);
  printf("%f squared is %f\n", a[0], b[0]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <square@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: f64
name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D5: 5

tool: D4: %f squared is %f


assistant: ```c
int main(int argc, char *argv[]) {
  double a[1];
  double b[1];
  a[0] = 5.0;
  b[0] = 0.0;
  square(a, b);
  printf("%f squared is %f\n", a[0], b[0]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <square@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: f64
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D8: 5

tool: D1: %f squared is %f


assistant: ```c
int main(int argc, char *argv[]) {
  double a[1];
  double b[1];
  a[0] = 5.0;
  b[0] = 0.0;
  square(a, b);
  printf("%f squared is %f\n", a[0], b[0]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <square@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D18: 5

tool: D8: %f squared is %f


assistant: ```c
int main(int argc, char *argv[]) {
  double a[1];
  double b[1];
  a[0] = 5.0;
  b[0] = 0.0;
  square(a, b);
  printf("%f squared is %f\n", a[0], b[0]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_time_interval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D2
type_guessed: string

tool: D9: Enter the amount of time (min.) it took to reach the final velocity


tool: D23: given the initial velocity you entered: 

tool: D2: %lf

assistant: ```c
double get_time_interval(void) {
  double time_interval = 0.0;
  printf("Enter the amount of time (min.) it took to reach the final velocity\n");
  printf("given the initial velocity you entered: ");
  scanf("%lf", &time_interval);
  return time_interval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_time_interval>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string

tool: D28: Enter the amount of time (min.) it took to reach the final velocity


tool: D13: given the initial velocity you entered: 

tool: D11: %lf

assistant: ```c
double get_time_interval(void) {
  double time_interval = 0.0;
  printf("Enter the amount of time (min.) it took to reach the final velocity\n");
  printf("given the initial velocity you entered: ");
  scanf("%lf", &time_interval);
  return time_interval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_time_interval>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D21
data_type: string

tool: D18: Enter the amount of time (min.) it took to reach the final velocity


tool: D11: given the initial velocity you entered: 

tool: D21: %lf

assistant: ```c
double get_time_interval(void) {
  double time_interval = 0.0;
  printf("Enter the amount of time (min.) it took to reach the final velocity\n");
  printf("given the initial velocity you entered: ");
  scanf("%lf", &time_interval);
  return time_interval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_time_interval>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D2
datatype: string

tool: D6: Enter the amount of time (min.) it took to reach the final velocity


tool: D25: given the initial velocity you entered: 

tool: D2: %lf

assistant: ```c
double get_time_interval(void) {
  double time_interval = 0.0;
  printf("Enter the amount of time (min.) it took to reach the final velocity\n");
  printf("given the initial velocity you entered: ");
  scanf("%lf", &time_interval);
  return time_interval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<invalid_host>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L26
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L44
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L15
L44:
  mov    $0x1,%eax
  jmp    L1
L15:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: .-?*

assistant: ```c
int invalid_host(const char *p) {
  while (*p) {
    if (!isalnum(*p) || !strchr(".-?*", *p))
      return 1;
    p++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<invalid_host>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L37
  lea    D5(%rip),%rbp
L8:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L38
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L42
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
  mov    $0x0,%eax
  jmp    L23
L37:
  mov    $0x0,%eax
  jmp    L23
L38:
  mov    $0x1,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  mov    $0x1,%eax
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: .-?*

assistant: ```c
int invalid_host(const char *p) {
  while (*p) {
    if (!isalnum(*p) || !strchr(".-?*", *p))
      return 1;
    p++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invalid_host>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
  lea    D9(%rip),%rbp
  jmp    L31
  xchg   %ax,%ax
L40:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L5
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L18
L31:
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L40
L5:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: .-?*

assistant: ```c
int invalid_host(const char *p) {
  while (*p) {
    if (!isalnum(*p) || !strchr(".-?*", *p))
      return 1;
    p++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<invalid_host>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L30
  lea    D7(%rip),%rbp
  jmp    L45
  xchg   %ax,%ax
L33:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L14
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L30
L45:
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L33
L14:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: .-?*

assistant: ```c
int invalid_host(const char *p) {
  while (*p) {
    if (!isalnum(*p) || !strchr(".-?*", *p))
      return 1;
    p++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<spec_replicators>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <spec_total@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,-0x40(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <spec_score@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void spec_replicators(int N, double x, double y[], double result[], void *data) {
  double tot = spec_total(y);
  int i;
  for (i = 0; i < N; i++) {
    result[i] = y[i] * (spec_score(i, y) - tot);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<spec_replicators>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rsi,%rdi
  call   <spec_total@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %r12d,%r12d
  jle    L0
  mov    %r12d,%r12d
  mov    $0x0,%ebx
L7:
  mov    0x0(%rbp,%rbx,8),%r14
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <spec_score@plt>
  subsd  0x8(%rsp),%xmm0
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L7
L0:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void spec_replicators(int N, double x, double y[], double result[], void *data) {
  double tot = spec_total(y);
  int i;
  for (i = 0; i < N; i++) {
    result[i] = y[i] * (spec_score(i, y) - tot);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spec_replicators>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movslq %edi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <spec_total@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %r12d,%r12d
  jle    L3
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  movsd  0x0(%rbp,%rbx,8),%xmm1
  mov    %ebx,%edi
  mov    %rbp,%rsi
  movsd  %xmm1,(%rsp)
  call   <spec_score@plt>
  subsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L6
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void spec_replicators(int N, double x, double y[], double result[], void *data) {
  double tot = spec_total(y);
  int i;
  for (i = 0; i < N; i++) {
    result[i] = y[i] * (spec_score(i, y) - tot);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spec_replicators>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movslq %edi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <spec_total@plt>
  movsd  %xmm0,0x8(%rsp)
  test   %r12d,%r12d
  jle    L7
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  movsd  0x0(%rbp,%rbx,8),%xmm1
  mov    %ebx,%edi
  mov    %rbp,%rsi
  movsd  %xmm1,(%rsp)
  call   <spec_score@plt>
  subsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L4
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void spec_replicators(int N, double x, double y[], double result[], void *data) {
  double tot = spec_total(y);
  int i;
  for (i = 0; i < N; i++) {
    result[i] = y[i] * (spec_score(i, y) - tot);
  }
}
```