ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReverseNumber>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    %r13d,%ebp
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L0
  movslq %eax,%rdx
  movslq %ebp,%rcx
  mov    %eax,%eax
  add    %rcx,%rax
  lea    (%rbx,%rdx,1),%rdi
  lea    (%r12,%rcx,4),%rdx
  lea    0x4(%r12,%rax,4),%rcx
  xchg   %ax,%ax
L35:
  movsbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L29
  sub    $0x30,%eax
  add    $0x4,%rdx
  sub    $0x1,%rdi
  mov    %eax,-0x4(%rdx)
  cmp    %rdx,%rcx
  jne    L35
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  movl   $0x2e,(%rdx)
  add    $0x4,%rdx
  sub    $0x1,%rdi
  cmp    %rdx,%rcx
  jne    L35
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ReverseNumber(char *inNumber, int *operateNumber, int smallLength, int maxSmallLength) {
  int length = (int)strlen(inNumber);
  for (int i = maxSmallLength - smallLength, j = length - 1; j >= 0; --j, ++i) {
    if (inNumber[j] != '.') {
      operateNumber[i] = inNumber[j] - '0';
    } else {
      operateNumber[i] = '.';
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NumberPairs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L13
  mov    $0xffffffff,%eax
  jmp    L1
L13:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int NumberPairs(int n) {
  if (n < 1)
    return -1;
  return (((n - 1) * n) / 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NumberPairs>:
  endbr64
  test   %edi,%edi
  jle    L4
  lea    -0x1(%rdi),%edx
  imul   %edi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int NumberPairs(int n) {
  if (n < 1)
    return -1;
  return (((n - 1) * n) / 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<NumberPairs>:
  endbr64
  test   %edi,%edi
  jle    L9
  lea    -0x1(%rdi),%eax
  imul   %edi,%eax
  sar    %eax
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int NumberPairs(int n) {
  if (n < 1)
    return -1;
  return (((n - 1) * n) / 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<NumberPairs>:
  endbr64
  test   %edi,%edi
  jle    L9
  lea    -0x1(%rdi),%eax
  imul   %edi,%eax
  sar    %eax
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int NumberPairs(int n) {
  if (n < 1)
    return -1;
  return (((n - 1) * n) / 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<twiddle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L18:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0xd,%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x11,%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x5,%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x8,-0x4(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void twiddle(uint32_t *v) {
  int i;
  for (i = 0; i < 9; ++i) {
    *v ^= *v << 13;
    *v ^= *v >> 17;
    *v ^= *v << 5;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<twiddle>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x9,%ecx
L2:
  mov    %eax,%edx
  shl    $0xd,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  sar    $0x11,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  xor    %edx,%eax
  sub    $0x1,%ecx
  jne    L2
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void twiddle(uint32_t *v) {
  int i;
  for (i = 0; i < 9; ++i) {
    *v ^= *v << 13;
    *v ^= *v >> 17;
    *v ^= *v << 5;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<twiddle>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x9,%ecx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edx
  shl    $0xd,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  sar    $0x11,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  xor    %edx,%eax
  sub    $0x1,%ecx
  jne    L5
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void twiddle(uint32_t *v) {
  int i;
  for (i = 0; i < 9; ++i) {
    *v ^= *v << 13;
    *v ^= *v >> 17;
    *v ^= *v << 5;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<twiddle>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%ecx
  shl    $0xd,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x11,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0xd,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  sar    $0x11,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0x5,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xd,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x11,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0xd,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  sar    $0x11,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0x5,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xd,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x11,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0xd,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  sar    $0x11,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0x5,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xd,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x11,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0xd,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  sar    $0x11,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  shl    $0x5,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0xd,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x11,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %ecx,%edx
  mov    %edx,(%rdi)
  ret
```

assistant: ```c
void twiddle(uint32_t *v) {
  int i;
  for (i = 0; i < 9; ++i) {
    *v ^= *v << 13;
    *v ^= *v >> 17;
    *v ^= *v << 5;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split_by_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L0
L28:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
L0:
  cmpq   $0x0,-0x10(%rbp)
  jne    L28
L18:
  cmpq   $0x0,-0x38(%rbp)
  je     L27
  mov    -0x38(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L27:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **split_by_char(char *str, char *delimeter, int *num) {
  char **final = NULL;
  char *token;
  char *input = str;
  int n = 0;
  input = strdup(str);
  final = (char **)malloc(sizeof(char *));
  if (input != NULL) {
    token = strtok(input, delimeter);
    while (token != NULL) {
      final = (char **)realloc(final, (sizeof(char *) * (n + 1)));
      final[n] = token;
      n++;
      token = strtok(NULL, delimeter);
    }
  }
  if (num != NULL)
    *num = n;
  return final;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split_by_char>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  mov    %rdx,%r15
  call   <strdup@plt>
  mov    %rax,%rbp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L17
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    $0x0,%r12d
L0:
  lea    0x1(%r12),%r13d
  lea    0x0(,%r13,8),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rbp,(%rax,%r12,8)
  mov    %r14,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  add    $0x1,%r12
  test   %rax,%rax
  jne    L0
L42:
  test   %r15,%r15
  je     L51
  mov    %r13d,(%r15)
L51:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%r13d
  jmp    L42
L16:
  mov    $0x0,%r13d
  jmp    L42
```

assistant: ```c
char **split_by_char(char *str, char *delimeter, int *num) {
  char **final = NULL;
  char *token;
  char *input = str;
  int n = 0;
  input = strdup(str);
  final = (char **)malloc(sizeof(char *));
  if (input != NULL) {
    token = strtok(input, delimeter);
    while (token != NULL) {
      final = (char **)realloc(final, (sizeof(char *) * (n + 1)));
      final[n] = token;
      n++;
      token = strtok(NULL, delimeter);
    }
  }
  if (num != NULL)
    *num = n;
  return final;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split_by_char>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    $0x8,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r14,%r14
  je     L27
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L26:
  lea    0x1(%r14),%r15d
  mov    %rbp,%rdi
  lea    0x0(,%r15,8),%esi
  call   <realloc@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  mov    %rbx,(%rax,%r14,8)
  mov    %rax,%rbp
  add    $0x1,%r14
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L26
L31:
  test   %r13,%r13
  je     L40
  mov    %r15d,0x0(%r13)
L40:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L27:
  xor    %r15d,%r15d
  jmp    L31
```

assistant: ```c
char **split_by_char(char *str, char *delimeter, int *num) {
  char **final = NULL;
  char *token;
  char *input = str;
  int n = 0;
  input = strdup(str);
  final = (char **)malloc(sizeof(char *));
  if (input != NULL) {
    token = strtok(input, delimeter);
    while (token != NULL) {
      final = (char **)realloc(final, (sizeof(char *) * (n + 1)));
      final[n] = token;
      n++;
      token = strtok(NULL, delimeter);
    }
  }
  if (num != NULL)
    *num = n;
  return final;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split_by_char>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    $0x8,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r14,%r14
  je     L35
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L35
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L10:
  lea    0x1(%r14),%r15d
  mov    %rbp,%rdi
  lea    0x0(,%r15,8),%esi
  call   <realloc@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  mov    %rbx,(%rax,%r14,8)
  mov    %rax,%rbp
  add    $0x1,%r14
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L10
L39:
  test   %r13,%r13
  je     L28
  mov    %r15d,0x0(%r13)
L28:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L35:
  xor    %r15d,%r15d
  jmp    L39
```

assistant: ```c
char **split_by_char(char *str, char *delimeter, int *num) {
  char **final = NULL;
  char *token;
  char *input = str;
  int n = 0;
  input = strdup(str);
  final = (char **)malloc(sizeof(char *));
  if (input != NULL) {
    token = strtok(input, delimeter);
    while (token != NULL) {
      final = (char **)realloc(final, (sizeof(char *) * (n + 1)));
      final[n] = token;
      n++;
      token = strtok(NULL, delimeter);
    }
  }
  if (num != NULL)
    *num = n;
  return final;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rand_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   $0xbb38435,%eax,%eax
  lea    0x3619636b(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rand_int(unsigned int *seed) {
  *seed = *seed * 196314165 + 907633515;
  return *seed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rand_int>:
  endbr64
  imul   $0xbb38435,(%rdi),%eax
  add    $0x3619636b,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
int rand_int(unsigned int *seed) {
  *seed = *seed * 196314165 + 907633515;
  return *seed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rand_int>:
  endbr64
  imul   $0xbb38435,(%rdi),%eax
  add    $0x3619636b,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
int rand_int(unsigned int *seed) {
  *seed = *seed * 196314165 + 907633515;
  return *seed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DoCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %edx,-0x234(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x230(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,-0x220(%rbp)
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x220(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x230(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x218(%rbp)
  jne    L11
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  jmp    L34
L11:
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
L34:
  mov    -0x220(%rbp),%rcx
  mov    -0x228(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  cmpl   $0x0,-0x234(%rbp)
  je     L1
  mov    -0x230(%rbp),%rdx
  mov    -0x228(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D10: mkdir -p "%s"

tool: D18: cp "%s" "%s"

tool: D5: %s==>%s


assistant: ```c
void DoCopy(const char *ccFn, const char *ccFnto, int iListFile) {
  char cTemp[256];
  strcpy(cTemp, ccFnto);
  char *cPathNsf = dirname(cTemp);
  char cCmd[256] = "";
  sprintf(cCmd, "mkdir -p \"%s\"", cPathNsf);
  DIR *df;
  if ((df = opendir(ccFnto)) == NULL)
    system(cCmd);
  else
    closedir(df);
  sprintf(cCmd, "cp \"%s\" \"%s\"", ccFn, cPathNsf);
  system(cCmd);
  if (iListFile)
    printf("%s==>%s\n", ccFn, ccFnto);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DoCopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <dirname@plt>
  mov    %rax,%rbp
  movq   $0x0,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  movq   $0x0,0x110(%rsp)
  movq   $0x0,0x118(%rsp)
  movq   $0x0,0x120(%rsp)
  movq   $0x0,0x128(%rsp)
  movq   $0x0,0x130(%rsp)
  movq   $0x0,0x138(%rsp)
  movq   $0x0,0x140(%rsp)
  movq   $0x0,0x148(%rsp)
  movq   $0x0,0x150(%rsp)
  movq   $0x0,0x158(%rsp)
  movq   $0x0,0x160(%rsp)
  movq   $0x0,0x168(%rsp)
  movq   $0x0,0x170(%rsp)
  movq   $0x0,0x178(%rsp)
  movq   $0x0,0x180(%rsp)
  movq   $0x0,0x188(%rsp)
  movq   $0x0,0x190(%rsp)
  movq   $0x0,0x198(%rsp)
  movq   $0x0,0x1a0(%rsp)
  movq   $0x0,0x1a8(%rsp)
  movq   $0x0,0x1b0(%rsp)
  movq   $0x0,0x1b8(%rsp)
  movq   $0x0,0x1c0(%rsp)
  movq   $0x0,0x1c8(%rsp)
  movq   $0x0,0x1d0(%rsp)
  movq   $0x0,0x1d8(%rsp)
  movq   $0x0,0x1e0(%rsp)
  movq   $0x0,0x1e8(%rsp)
  movq   $0x0,0x1f0(%rsp)
  movq   $0x0,0x1f8(%rsp)
  lea    0x100(%rsp),%rdi
  mov    %rax,%rdx
  lea    D8(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  call   <closedir@plt>
L7:
  lea    0x100(%rsp),%r14
  mov    %rbp,%rcx
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r14,%rdi
  call   <system@plt>
  test   %r13d,%r13d
  jne    L10
L33:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  lea    0x100(%rsp),%rdi
  call   <system@plt>
  jmp    L7
L10:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D8: mkdir -p "%s"

tool: D10: cp "%s" "%s"

tool: D12: %s==>%s


assistant: ```c
void DoCopy(const char *ccFn, const char *ccFnto, int iListFile) {
  char cTemp[256];
  strcpy(cTemp, ccFnto);
  char *cPathNsf = dirname(cTemp);
  char cCmd[256] = "";
  sprintf(cCmd, "mkdir -p \"%s\"", cPathNsf);
  DIR *df;
  if ((df = opendir(ccFnto)) == NULL)
    system(cCmd);
  else
    closedir(df);
  sprintf(cCmd, "cp \"%s\" \"%s\"", ccFn, cPathNsf);
  system(cCmd);
  if (iListFile)
    printf("%s==>%s\n", ccFn, ccFnto);
}
```
user: What is the c source code of the assembly code below?

```asm
<DoCopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x100(%rsp),%r14
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <dirname@plt>
  pxor   %xmm0,%xmm0
  mov    %r14,%rdi
  lea    D8(%rip),%rsi
  mov    %rax,%rdx
  mov    %rax,%r13
  xor    %eax,%eax
  movaps %xmm0,0x100(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  movaps %xmm0,0x190(%rsp)
  movaps %xmm0,0x1a0(%rsp)
  movaps %xmm0,0x1b0(%rsp)
  movaps %xmm0,0x1c0(%rsp)
  movaps %xmm0,0x1d0(%rsp)
  movaps %xmm0,0x1e0(%rsp)
  movaps %xmm0,0x1f0(%rsp)
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L24
  mov    %rax,%rdi
  call   <closedir@plt>
L17:
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D27(%rip),%rsi
  call   <sprintf@plt>
  mov    %r14,%rdi
  call   <system@plt>
  test   %ebx,%ebx
  jne    L27
L22:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L27:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L22
  nopl   0x0(%rax)
L24:
  mov    %r14,%rdi
  call   <system@plt>
  jmp    L17
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D23
datatype: string

tool: D8: mkdir -p "%s"

tool: D27: cp "%s" "%s"

tool: D23: %s==>%s


assistant: ```c
void DoCopy(const char *ccFn, const char *ccFnto, int iListFile) {
  char cTemp[256];
  strcpy(cTemp, ccFnto);
  char *cPathNsf = dirname(cTemp);
  char cCmd[256] = "";
  sprintf(cCmd, "mkdir -p \"%s\"", cPathNsf);
  DIR *df;
  if ((df = opendir(ccFnto)) == NULL)
    system(cCmd);
  else
    closedir(df);
  sprintf(cCmd, "cp \"%s\" \"%s\"", ccFn, cPathNsf);
  system(cCmd);
  if (iListFile)
    printf("%s==>%s\n", ccFn, ccFnto);
}
```