ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <srandom@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L26:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L49:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L26
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <find@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    $0x1,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L2:
  mov    $0x0,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D41: %d

tool: D6: %d;

assistant: ```c
int main() {
  int s;
  int n;
  int k;
  int x;
  scanf("%d", &s);
  srandom(s);
  scanf("%d", &n);
  scanf("%d", &k);
  scanf("%d", &x);
  int *a = (int *)malloc(n * sizeof(int));
  int i = 0;
  while (i < k) {
    scanf("%d", a + i++);
  }
  if (find(a, n, x, k) != -1) {
    printf("%d;", 1);
  } else {
    printf("%d;", 0);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  call   <srandom@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x10(%rsp),%ecx
  test   %ecx,%ecx
  jle    L15
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L47:
  add    $0x1,%ebx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L47
L15:
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r13,%rdi
  call   <find@plt>
  cmp    $0xffffffff,%eax
  je     L22
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    $0x0,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string

tool: D7: %d

tool: D9: %d;

assistant: ```c
int main() {
  int s;
  int n;
  int k;
  int x;
  scanf("%d", &s);
  srandom(s);
  scanf("%d", &n);
  scanf("%d", &k);
  scanf("%d", &x);
  int *a = (int *)malloc(n * sizeof(int));
  int i = 0;
  while (i < k) {
    scanf("%d", a + i++);
  }
  if (find(a, n, x, k) != -1) {
    printf("%d;", 1);
  } else {
    printf("%d;", 0);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  call   <srandom@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%r13
  test   %ecx,%ecx
  jle    L4
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L44
L4:
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r13,%rdi
  call   <find@plt>
  cmp    $0xffffffff,%eax
  je     L34
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string

tool: D27: %d

tool: D11: %d;

assistant: ```c
int main() {
  int s;
  int n;
  int k;
  int x;
  scanf("%d", &s);
  srandom(s);
  scanf("%d", &n);
  scanf("%d", &k);
  scanf("%d", &x);
  int *a = (int *)malloc(n * sizeof(int));
  int i = 0;
  while (i < k) {
    scanf("%d", a + i++);
  }
  if (find(a, n, x, k) != -1) {
    printf("%d;", 1);
  } else {
    printf("%d;", 0);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  call   <srandom@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%ecx
  mov    %rax,%r13
  test   %ecx,%ecx
  jle    L18
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L10
L18:
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r13,%rdi
  call   <find@plt>
  cmp    $0xffffffff,%eax
  je     L16
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L39:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  xor    %esi,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D15: %d

tool: D9: %d;

assistant: ```c
int main() {
  int s;
  int n;
  int k;
  int x;
  scanf("%d", &s);
  srandom(s);
  scanf("%d", &n);
  scanf("%d", &k);
  scanf("%d", &x);
  int *a = (int *)malloc(n * sizeof(int));
  int i = 0;
  while (i < k) {
    scanf("%d", a + i++);
  }
  if (find(a, n, x, k) != -1) {
    printf("%d;", 1);
  } else {
    printf("%d;", 0);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L19
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <b@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L27
L19:
  cmpl   $0x2,-0x14(%rbp)
  jle    L27
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <c@plt>
  mov    %eax,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int a(int val) {
  int return_value = val;
  if (val <= 1) {
    return_value = b(val);
  } else if (val >= 3) {
    return_value = c(val);
  }
  return return_value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<a>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L4
  mov    %edi,%eax
  cmp    $0x2,%edi
  jg     L12
L23:
  add    $0x8,%rsp
  ret
L4:
  call   <b@plt>
  jmp    L23
L12:
  call   <c@plt>
  jmp    L23
```

assistant: ```c
int a(int val) {
  int return_value = val;
  if (val <= 1) {
    return_value = b(val);
  } else if (val >= 3) {
    return_value = c(val);
  }
  return return_value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<a>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  cmp    $0x2,%edi
  je     L9
  jmp    1070 <c@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L7:
  jmp    1060 <b@plt>
```

assistant: ```c
int a(int val) {
  int return_value = val;
  if (val <= 1) {
    return_value = b(val);
  } else if (val >= 3) {
    return_value = c(val);
  }
  return return_value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  cmp    $0x2,%edi
  je     L2
  jmp    1070 <c@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L14:
  jmp    1060 <b@plt>
```

assistant: ```c
int a(int val) {
  int return_value = val;
  if (val <= 1) {
    return_value = b(val);
  } else if (val >= 3) {
    return_value = c(val);
  }
  return return_value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dpthirdhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L39
  cmpl   $0x0,-0x1c(%rbp)
  js     L39
  mov    $0x1,%eax
  jmp    L49
L39:
  mov    $0x0,%eax
L49:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x2e2eff2d,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L32
L37:
  mov    -0x10(%rbp),%eax
  imul   $0x1d,%eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x0,-0xc(%rbp)
  jns    L37
  mov    -0x10(%rbp),%eax
  imul   $0x4eb3fb,%eax,%eax
  and    $0x7fffffff,%eax
  leave
  ret
```

assistant: ```c
int dpthirdhash(const char *kbuf, int ksiz) {
  const unsigned char *p;
  unsigned int sum;
  int i;
  assert(kbuf && ksiz >= 0);
  p = (const unsigned char *)kbuf;
  sum = 774831917;
  for (i = ksiz - 1; i >= 0; i--) {
    sum = sum * 29 + p[i];
  }
  return (sum * 5157883) & 0x7FFFFFFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dpthirdhash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %rdi,%rdi
  setne  %al
  mov    %esi,%edi
  not    %edi
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %ebx,%edx
  sub    $0x1,%edx
  js     L6
  movslq %edx,%rdx
  add    %rbp,%rdx
  movslq %ebx,%rax
  lea    -0x2(%rbp,%rax,1),%rsi
  lea    -0x1(%rbx),%eax
  sub    %rax,%rsi
  mov    $0x2e2eff2d,%eax
L2:
  imul   $0x1d,%eax,%eax
  movzbl (%rdx),%ecx
  add    %ecx,%eax
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L2
L25:
  imul   $0x4eb3fb,%eax,%eax
  and    $0x7fffffff,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x2e2eff2d,%eax
  jmp    L25
```

assistant: ```c
int dpthirdhash(const char *kbuf, int ksiz) {
  const unsigned char *p;
  unsigned int sum;
  int i;
  assert(kbuf && ksiz >= 0);
  p = (const unsigned char *)kbuf;
  sum = 774831917;
  for (i = ksiz - 1; i >= 0; i--) {
    sum = sum * 29 + p[i];
  }
  return (sum * 5157883) & 0x7FFFFFFF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dpthirdhash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  mov    %ebx,%edi
  not    %edi
  setne  %al
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  sub    $0x1,%eax
  js     L2
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rbx,1),%rsi
  mov    %eax,%eax
  sub    %rax,%rsi
  add    %rbp,%rdx
  mov    $0x2e2eff2d,%eax
L6:
  imul   $0x1d,%eax,%eax
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L6
  imul   $0x4eb3fb,%eax,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  mov    $0x6436a81f,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int dpthirdhash(const char *kbuf, int ksiz) {
  const unsigned char *p;
  unsigned int sum;
  int i;
  assert(kbuf && ksiz >= 0);
  p = (const unsigned char *)kbuf;
  sum = 774831917;
  for (i = ksiz - 1; i >= 0; i--) {
    sum = sum * 29 + p[i];
  }
  return (sum * 5157883) & 0x7FFFFFFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dpthirdhash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  mov    %ebx,%edi
  not    %edi
  setne  %al
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  sub    $0x1,%eax
  js     L7
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rbx,1),%rsi
  mov    %eax,%eax
  sub    %rax,%rsi
  add    %rbp,%rdx
  mov    $0x2e2eff2d,%eax
L16:
  imul   $0x1d,%eax,%eax
  movzbl (%rdx),%ecx
  sub    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L16
  imul   $0x4eb3fb,%eax,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  and    $0x7fffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  mov    $0x6436a81f,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int dpthirdhash(const char *kbuf, int ksiz) {
  const unsigned char *p;
  unsigned int sum;
  int i;
  assert(kbuf && ksiz >= 0);
  p = (const unsigned char *)kbuf;
  sum = 774831917;
  for (i = ksiz - 1; i >= 0; i--) {
    sum = sum * 29 + p[i];
  }
  return (sum * 5157883) & 0x7FFFFFFF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_st_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x56,-0x20(%rbp)
  mov    -0x38(%rbp),%eax
  shl    $0x4,%eax
  movzbl %al,%eax
  or     $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x4,%ecx
  mov    %rax,%rdi
  call   <add_sentence@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void gen_st_date(uint8_t *b, uint32_t *buflen, int YY, int MM, int DD) {
  uint8_t sentence[] = {0x56, ((MM & 0x0F) << 4) | 0x01, DD, YY};
  add_sentence(b, buflen, sentence, 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_st_date>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x56,(%rsp)
  shl    $0x4,%ecx
  movzbl %cl,%ecx
  or     $0x1,%ecx
  mov    %ecx,0x4(%rsp)
  mov    %r8d,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rsp,%rdx
  mov    $0x4,%ecx
  call   <add_sentence@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gen_st_date(uint8_t *b, uint32_t *buflen, int YY, int MM, int DD) {
  uint8_t sentence[] = {0x56, ((MM & 0x0F) << 4) | 0x01, DD, YY};
  add_sentence(b, buflen, sentence, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gen_st_date>:
  endbr64
  shl    $0x4,%ecx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl %cl,%ecx
  mov    %edx,0xc(%rsp)
  mov    %rsp,%rdx
  or     $0x1,%ecx
  movl   $0x56,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    $0x4,%ecx
  mov    %r8d,0x8(%rsp)
  call   <add_sentence@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gen_st_date(uint8_t *b, uint32_t *buflen, int YY, int MM, int DD) {
  uint8_t sentence[] = {0x56, ((MM & 0x0F) << 4) | 0x01, DD, YY};
  add_sentence(b, buflen, sentence, 4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_st_date>:
  endbr64
  shl    $0x4,%ecx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl %cl,%ecx
  mov    %edx,0xc(%rsp)
  mov    %rsp,%rdx
  or     $0x1,%ecx
  movl   $0x56,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    $0x4,%ecx
  mov    %r8d,0x8(%rsp)
  call   <add_sentence@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gen_st_date(uint8_t *b, uint32_t *buflen, int YY, int MM, int DD) {
  uint8_t sentence[] = {0x56, ((MM & 0x0F) << 4) | 0x01, DD, YY};
  add_sentence(b, buflen, sentence, 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_xmm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x7,-0x4(%rbp)
  ja     L19
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D13(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm1
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm2
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm3
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm4
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm5
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm6
  jmp    L19
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm7
  nop
L19:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_xmm(int n, unsigned long val) {
  switch (n) {
  case 0:
    asm volatile("movq %0, %%"
                 "xmm0"
                 :
                 : "r"(val)
                 : "xmm0");
    break;
  case 1:
    asm volatile("movq %0, %%"
                 "xmm1"
                 :
                 : "r"(val)
                 : "xmm1");
    break;
  case 2:
    asm volatile("movq %0, %%"
                 "xmm2"
                 :
                 : "r"(val)
                 : "xmm2");
    break;
  case 3:
    asm volatile("movq %0, %%"
                 "xmm3"
                 :
                 : "r"(val)
                 : "xmm3");
    break;
  case 4:
    asm volatile("movq %0, %%"
                 "xmm4"
                 :
                 : "r"(val)
                 : "xmm4");
    break;
  case 5:
    asm volatile("movq %0, %%"
                 "xmm5"
                 :
                 : "r"(val)
                 : "xmm5");
    break;
  case 6:
    asm volatile("movq %0, %%"
                 "xmm6"
                 :
                 : "r"(val)
                 : "xmm6");
    break;
  case 7:
    asm volatile("movq %0, %%"
                 "xmm7"
                 :
                 : "r"(val)
                 : "xmm7");
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_xmm>:
  endbr64
  cmp    $0x7,%edi
  ja     L4
  mov    %edi,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movq   %rsi,%xmm0
  ret
  movq   %rsi,%xmm1
  ret
  movq   %rsi,%xmm2
  ret
  movq   %rsi,%xmm3
  ret
  movq   %rsi,%xmm4
  ret
  movq   %rsi,%xmm5
  ret
  movq   %rsi,%xmm6
  ret
  movq   %rsi,%xmm7
L4:
  ret
```

assistant: ```c
void set_xmm(int n, unsigned long val) {
  switch (n) {
  case 0:
    asm volatile("movq %0, %%"
                 "xmm0"
                 :
                 : "r"(val)
                 : "xmm0");
    break;
  case 1:
    asm volatile("movq %0, %%"
                 "xmm1"
                 :
                 : "r"(val)
                 : "xmm1");
    break;
  case 2:
    asm volatile("movq %0, %%"
                 "xmm2"
                 :
                 : "r"(val)
                 : "xmm2");
    break;
  case 3:
    asm volatile("movq %0, %%"
                 "xmm3"
                 :
                 : "r"(val)
                 : "xmm3");
    break;
  case 4:
    asm volatile("movq %0, %%"
                 "xmm4"
                 :
                 : "r"(val)
                 : "xmm4");
    break;
  case 5:
    asm volatile("movq %0, %%"
                 "xmm5"
                 :
                 : "r"(val)
                 : "xmm5");
    break;
  case 6:
    asm volatile("movq %0, %%"
                 "xmm6"
                 :
                 : "r"(val)
                 : "xmm6");
    break;
  case 7:
    asm volatile("movq %0, %%"
                 "xmm7"
                 :
                 : "r"(val)
                 : "xmm7");
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_xmm>:
  endbr64
  cmp    $0x7,%edi
  ja     L6
  lea    D7(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  movq   %rsi,%xmm7
L6:
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm6
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm1
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm2
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm3
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm4
  ret
  cs nopw 0x0(%rax,%rax,1)
  movq   %rsi,%xmm5
  ret
```

assistant: ```c
void set_xmm(int n, unsigned long val) {
  switch (n) {
  case 0:
    asm volatile("movq %0, %%"
                 "xmm0"
                 :
                 : "r"(val)
                 : "xmm0");
    break;
  case 1:
    asm volatile("movq %0, %%"
                 "xmm1"
                 :
                 : "r"(val)
                 : "xmm1");
    break;
  case 2:
    asm volatile("movq %0, %%"
                 "xmm2"
                 :
                 : "r"(val)
                 : "xmm2");
    break;
  case 3:
    asm volatile("movq %0, %%"
                 "xmm3"
                 :
                 : "r"(val)
                 : "xmm3");
    break;
  case 4:
    asm volatile("movq %0, %%"
                 "xmm4"
                 :
                 : "r"(val)
                 : "xmm4");
    break;
  case 5:
    asm volatile("movq %0, %%"
                 "xmm5"
                 :
                 : "r"(val)
                 : "xmm5");
    break;
  case 6:
    asm volatile("movq %0, %%"
                 "xmm6"
                 :
                 : "r"(val)
                 : "xmm6");
    break;
  case 7:
    asm volatile("movq %0, %%"
                 "xmm7"
                 :
                 : "r"(val)
                 : "xmm7");
    break;
  }
}
```