ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<explicit_bzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__explicit_bzero_hook@plt>
  nop
  leave
  ret
```

assistant: ```c
void explicit_bzero(void *buf, size_t len) {
  memset(buf, 0, len);
  __explicit_bzero_hook(buf, len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<explicit_bzero>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__explicit_bzero_hook@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void explicit_bzero(void *buf, size_t len) {
  memset(buf, 0, len);
  __explicit_bzero_hook(buf, len);
}
```
user: What is the c source code of the assembly code below?

```asm
<explicit_bzero>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <__explicit_bzero_hook@plt>
```

assistant: ```c
void explicit_bzero(void *buf, size_t len) {
  memset(buf, 0, len);
  __explicit_bzero_hook(buf, len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<explicit_bzero>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <__explicit_bzero_hook@plt>
```

assistant: ```c
void explicit_bzero(void *buf, size_t len) {
  memset(buf, 0, len);
  __explicit_bzero_hook(buf, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L26
L17:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L29
  mov    $0xffffffff,%eax
  jmp    L32
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  setne  %al
  movzbl %al,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1 != '\0' && (*str1++ == *str2++))
    ;
  if ((*(unsigned char *)--str1) < (*(unsigned char *)--str2))
    return (-1);
  return ((*(unsigned char *)str1) != (*(unsigned char *)str2));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmp>:
  endbr64
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    -0x1(%rsi),%al
  je     L13
L0:
  movzbl -0x1(%rdi),%ecx
  movzbl -0x1(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jb     L21
  setne  %al
  movzbl %al,%eax
L21:
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1 != '\0' && (*str1++ == *str2++))
    ;
  if ((*(unsigned char *)--str1) < (*(unsigned char *)--str2))
    return (-1);
  return ((*(unsigned char *)str1) != (*(unsigned char *)str2));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmp>:
  endbr64
  nopl   0x0(%rax)
L22:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  add    $0x1,%rsi
  add    $0x1,%rdi
  cmp    -0x1(%rsi),%al
  je     L22
L18:
  movzbl -0x1(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,-0x1(%rdi)
  jb     L2
  setne  %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1 != '\0' && (*str1++ == *str2++))
    ;
  if ((*(unsigned char *)--str1) < (*(unsigned char *)--str2))
    return (-1);
  return ((*(unsigned char *)str1) != (*(unsigned char *)str2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  nopl   0x0(%rax)
L8:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  add    $0x1,%rsi
  add    $0x1,%rdi
  cmp    -0x1(%rsi),%al
  je     L8
L1:
  movzbl -0x1(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,-0x1(%rdi)
  jb     L29
  setne  %al
  movzbl %al,%eax
L29:
  ret
```

assistant: ```c
int strcmp(const char *str1, const char *str2) {
  while (*str1 != '\0' && (*str1++ == *str2++))
    ;
  if ((*(unsigned char *)--str1) < (*(unsigned char *)--str2))
    return (-1);
  return ((*(unsigned char *)str1) != (*(unsigned char *)str2));
}
```
user: What is the c source code of the assembly code below:

```asm
<CopyString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_Error@plt>
L4:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: No memory

assistant: ```c
const char *CopyString(const char *s) {
  int len;
  char *s2;
  len = strlen(s) - 2;
  if (!(s2 = malloc(len + 1)))
    Sys_Error("No memory");
  strncpy(s2, s + 1, len);
  s2[len] = '\0';
  return s2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CopyString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    -0x2(%rax),%r12d
  lea    -0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L5:
  lea    0x1(%rbp),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x0,(%rbx,%r12,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  lea    D4(%rip),%rdi
  call   <Sys_Error@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: No memory

assistant: ```c
const char *CopyString(const char *s) {
  int len;
  char *s2;
  len = strlen(s) - 2;
  if (!(s2 = malloc(len + 1)))
    Sys_Error("No memory");
  strncpy(s2, s + 1, len);
  s2[len] = '\0';
  return s2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CopyString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edi
  lea    -0x2(%rax),%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L12:
  lea    0x1(%rbx),%rsi
  mov    %ebp,%edx
  mov    %r12,%rdi
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  lea    D0(%rip),%rdi
  call   <Sys_Error@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: No memory

assistant: ```c
const char *CopyString(const char *s) {
  int len;
  char *s2;
  len = strlen(s) - 2;
  if (!(s2 = malloc(len + 1)))
    Sys_Error("No memory");
  strncpy(s2, s + 1, len);
  s2[len] = '\0';
  return s2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CopyString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edi
  lea    -0x2(%rax),%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L4:
  lea    0x1(%rbx),%rsi
  mov    %ebp,%edx
  mov    %r12,%rdi
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  lea    D7(%rip),%rdi
  call   <Sys_Error@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: No memory

assistant: ```c
const char *CopyString(const char *s) {
  int len;
  char *s2;
  len = strlen(s) - 2;
  if (!(s2 = malloc(len + 1)))
    Sys_Error("No memory");
  strncpy(s2, s + 1, len);
  s2[len] = '\0';
  return s2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lexer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <readIntoBuffer@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D15: r

tool: D6: testing.txt

assistant: ```c
void lexer() {
  FILE *fp;
  fp = fopen("testing.txt", "r");
  readIntoBuffer(fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lexer>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <readIntoBuffer@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string

tool: D7: r

tool: D13: testing.txt

assistant: ```c
void lexer() {
  FILE *fp;
  fp = fopen("testing.txt", "r");
  readIntoBuffer(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lexer>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <readIntoBuffer@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D10
type_infered: string

tool: D9: testing.txt

tool: D10: r

assistant: ```c
void lexer() {
  FILE *fp;
  fp = fopen("testing.txt", "r");
  readIntoBuffer(fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lexer>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <readIntoBuffer@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string

tool: D8: testing.txt

tool: D13: r

assistant: ```c
void lexer() {
  FILE *fp;
  fp = fopen("testing.txt", "r");
  readIntoBuffer(fp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_fast_math>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  stmxcsr -0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  orl    $0x8040,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  ldmxcsr -0x14(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set_fast_math>:
  endbr64
  stmxcsr -0x4(%rsp)
  orl    $0x8040,-0x4(%rsp)
  ldmxcsr -0x4(%rsp)
  ret
```

assistant: ```c
void __attribute__((constructor)) set_fast_math(void) {
  unsigned int mxcsr = __builtin_ia32_stmxcsr();
  mxcsr |= (1 << 6) | (1 << 15);
  __builtin_ia32_ldmxcsr(mxcsr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_new_seed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x1a,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  shl    $0x14,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  shl    $0xf,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%eax
  shl    $0xa,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%eax
  shl    $0x6,%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x14(%rax),%eax
  shl    $0xd,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%eax
  shl    $0xa,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x1c(%rax),%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    0x20(%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  xor    -0x14(%rbp),%eax
  xor    %eax,-0x18(%rbp)
  mov    D38(%rip),%eax
  imul   $0xeeee,%eax,%ecx
  mov    %ecx,%edx
  mov    %rdx,%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  shl    $0xf,%rax
  add    %rdx,%rax
  shr    $0x20,%rax
  shr    $0xf,%eax
  mov    %eax,%edx
  shl    $0x10,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,D22(%rip)
  mov    D22(%rip),%eax
  shl    $0x10,%eax
  xor    %eax,-0x18(%rbp)
  mov    D22(%rip),%eax
  imul   $0xaeee,%eax,%ecx
  mov    %ecx,%edx
  mov    %rdx,%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  shl    $0xf,%rax
  add    %rdx,%rax
  shr    $0x20,%rax
  shr    $0xf,%eax
  mov    %eax,%edx
  shl    $0x10,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,D22(%rip)
  mov    D22(%rip),%eax
  xor    %eax,-0x18(%rbp)
  andl   $0x7fffffff,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int make_new_seed() {
  time_t tp;
  struct tm *temp;
  unsigned int temp2, temp3;
  static unsigned int temp4 = 0xe0e1;
  time(&tp);
  temp = localtime(&tp);
  temp2 = (temp->tm_sec << 26) + (temp->tm_min << 20) + (temp->tm_hour << 15) + (temp->tm_mday << 10) + (temp->tm_mon << 6);
  temp3 = (temp->tm_year << 13) + (temp->tm_wday << 10) + (temp->tm_yday << 1) + temp->tm_isdst;
  temp2 ^= clock() ^ temp3;
  temp4 = (temp4 * 0xeeee) % 0xffff;
  temp2 ^= temp4 << 16;
  temp4 = (temp4 * 0xaeee) % 0xffff;
  temp2 ^= temp4;
  temp2 &= 0x7fffffff;
  return temp2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<make_new_seed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    (%rax),%ebx
  shl    $0x1a,%ebx
  mov    0x4(%rax),%edx
  shl    $0x14,%edx
  add    %edx,%ebx
  mov    0x8(%rax),%edx
  shl    $0xf,%edx
  add    %edx,%ebx
  mov    0xc(%rax),%edx
  shl    $0xa,%edx
  add    %edx,%ebx
  mov    0x10(%rax),%edx
  shl    $0x6,%edx
  add    %edx,%ebx
  mov    0x14(%rax),%edx
  shl    $0xd,%edx
  mov    0x18(%rax),%ecx
  shl    $0xa,%ecx
  add    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rdx,%rcx,2),%ebp
  add    0x20(%rax),%ebp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%ecx
  imul   $0xeeee,0x2e46(%rip),%esi        # 4040 <temp4.0>
  mov    %esi,%eax
  mov    %rax,%rdx
  shl    $0x10,%rdx
  add    %rax,%rdx
  shl    $0xf,%rdx
  add    %rax,%rdx
  shr    $0x2f,%rdx
  mov    %edx,%eax
  shl    $0x10,%eax
  sub    %edx,%eax
  sub    %eax,%esi
  mov    %esi,%edx
  imul   $0xaeee,%esi,%edi
  mov    %edi,%esi
  mov    %rsi,%rax
  shl    $0x10,%rax
  add    %rsi,%rax
  shl    $0xf,%rax
  add    %rsi,%rax
  shr    $0x2f,%rax
  mov    %eax,%esi
  shl    $0x10,%esi
  sub    %eax,%esi
  mov    %edi,%eax
  sub    %esi,%eax
  mov    %eax,D9(%rip)
  shl    $0x10,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  xor    %ecx,%eax
  xor    %ebp,%eax
  xor    %ebx,%eax
  and    $0x7fffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_new_seed() {
  time_t tp;
  struct tm *temp;
  unsigned int temp2, temp3;
  static unsigned int temp4 = 0xe0e1;
  time(&tp);
  temp = localtime(&tp);
  temp2 = (temp->tm_sec << 26) + (temp->tm_min << 20) + (temp->tm_hour << 15) + (temp->tm_mday << 10) + (temp->tm_mon << 6);
  temp3 = (temp->tm_year << 13) + (temp->tm_wday << 10) + (temp->tm_yday << 1) + temp->tm_isdst;
  temp2 ^= clock() ^ temp3;
  temp4 = (temp4 * 0xeeee) % 0xffff;
  temp2 ^= temp4 << 16;
  temp4 = (temp4 * 0xaeee) % 0xffff;
  temp2 ^= temp4;
  temp2 &= 0x7fffffff;
  return temp2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_new_seed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    (%rax),%ebx
  mov    0x4(%rax),%edx
  mov    0x18(%rax),%ecx
  shl    $0x14,%edx
  shl    $0x1a,%ebx
  add    %edx,%ebx
  mov    0x8(%rax),%edx
  shl    $0xa,%ecx
  shl    $0xf,%edx
  add    %edx,%ebx
  mov    0xc(%rax),%edx
  shl    $0xa,%edx
  add    %edx,%ebx
  mov    0x10(%rax),%edx
  shl    $0x6,%edx
  add    %edx,%ebx
  mov    0x14(%rax),%edx
  shl    $0xd,%edx
  add    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rdx,%rcx,2),%ebp
  add    0x20(%rax),%ebp
  xor    %eax,%eax
  call   <clock@plt>
  mov    %eax,%r8d
  imul   $0xeeee,0x2e41(%rip),%eax        # 4040 <temp4.0>
  mov    %rax,%rdx
  mov    %rax,%rcx
  shl    $0x10,%rdx
  add    %rax,%rdx
  shl    $0xf,%rdx
  add    %rax,%rdx
  shr    $0x2f,%rdx
  mov    %edx,%eax
  shl    $0x10,%eax
  sub    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  imul   $0xaeee,%ecx,%ecx
  mov    %rcx,%rax
  mov    %rcx,%rsi
  shl    $0x10,%rax
  add    %rcx,%rax
  shl    $0xf,%rax
  add    %rcx,%rax
  shl    $0x10,%edx
  shr    $0x2f,%rax
  mov    %eax,%ecx
  shl    $0x10,%ecx
  sub    %eax,%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  xor    %eax,%edx
  mov    %eax,D8(%rip)
  mov    %edx,%eax
  xor    %r8d,%eax
  xor    %ebp,%eax
  xor    %ebx,%eax
  and    $0x7fffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_new_seed() {
  time_t tp;
  struct tm *temp;
  unsigned int temp2, temp3;
  static unsigned int temp4 = 0xe0e1;
  time(&tp);
  temp = localtime(&tp);
  temp2 = (temp->tm_sec << 26) + (temp->tm_min << 20) + (temp->tm_hour << 15) + (temp->tm_mday << 10) + (temp->tm_mon << 6);
  temp3 = (temp->tm_year << 13) + (temp->tm_wday << 10) + (temp->tm_yday << 1) + temp->tm_isdst;
  temp2 ^= clock() ^ temp3;
  temp4 = (temp4 * 0xeeee) % 0xffff;
  temp2 ^= temp4 << 16;
  temp4 = (temp4 * 0xaeee) % 0xffff;
  temp2 ^= temp4;
  temp2 &= 0x7fffffff;
  return temp2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<make_new_seed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    (%rax),%ebx
  mov    0x4(%rax),%edx
  mov    0x18(%rax),%ecx
  shl    $0x14,%edx
  shl    $0x1a,%ebx
  add    %edx,%ebx
  mov    0x8(%rax),%edx
  shl    $0xa,%ecx
  shl    $0xf,%edx
  add    %edx,%ebx
  mov    0xc(%rax),%edx
  shl    $0xa,%edx
  add    %edx,%ebx
  mov    0x10(%rax),%edx
  shl    $0x6,%edx
  add    %edx,%ebx
  mov    0x14(%rax),%edx
  shl    $0xd,%edx
  add    %ecx,%edx
  mov    0x1c(%rax),%ecx
  lea    (%rdx,%rcx,2),%ebp
  add    0x20(%rax),%ebp
  xor    %eax,%eax
  call   <clock@plt>
  mov    %eax,%r8d
  imul   $0xeeee,0x2e41(%rip),%eax        # 4040 <temp4.0>
  mov    %rax,%rdx
  mov    %rax,%rcx
  shl    $0x10,%rdx
  add    %rax,%rdx
  shl    $0xf,%rdx
  add    %rax,%rdx
  shr    $0x2f,%rdx
  mov    %edx,%eax
  shl    $0x10,%eax
  sub    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  imul   $0xaeee,%ecx,%ecx
  mov    %rcx,%rax
  mov    %rcx,%rsi
  shl    $0x10,%rax
  add    %rcx,%rax
  shl    $0xf,%rax
  add    %rcx,%rax
  shl    $0x10,%edx
  shr    $0x2f,%rax
  mov    %eax,%ecx
  shl    $0x10,%ecx
  sub    %eax,%ecx
  mov    %esi,%eax
  sub    %ecx,%eax
  xor    %eax,%edx
  mov    %eax,D3(%rip)
  mov    %edx,%eax
  xor    %r8d,%eax
  xor    %ebp,%eax
  xor    %ebx,%eax
  and    $0x7fffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int make_new_seed() {
  time_t tp;
  struct tm *temp;
  unsigned int temp2, temp3;
  static unsigned int temp4 = 0xe0e1;
  time(&tp);
  temp = localtime(&tp);
  temp2 = (temp->tm_sec << 26) + (temp->tm_min << 20) + (temp->tm_hour << 15) + (temp->tm_mday << 10) + (temp->tm_mon << 6);
  temp3 = (temp->tm_year << 13) + (temp->tm_wday << 10) + (temp->tm_yday << 1) + temp->tm_isdst;
  temp2 ^= clock() ^ temp3;
  temp4 = (temp4 * 0xeeee) % 0xffff;
  temp2 ^= temp4 << 16;
  temp4 = (temp4 * 0xaeee) % 0xffff;
  temp2 ^= temp4;
  temp2 &= 0x7fffffff;
  return temp2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L88
L86:
  addq   $0x1,-0x18(%rbp)
L88:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L86
  jmp    L56
L107:
  addq   $0x1,-0x20(%rbp)
L56:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L107
  jmp    L93
L101:
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L131
L29:
  mov    $0x1,%eax
  jmp    L10
L131:
  mov    $0x0,%eax
L10:
  cltq
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L20
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L93:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L101
  jmp    L61
L20:
  nop
L61:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L51
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L51
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L51
  mov    $0x1,%eax
  jmp    L37
L51:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  char *bs = s;
  char *bt = t;
  for (; *s; s++)
    ;
  for (; *t; t++)
    ;
  for (; *s == *t; s--, t--)
    if (t = bt || s == bs)
      break;
  if (*s == *t && t == bt && *s != '\0')
    return 1;
  else
    return 0;
}
```