ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<closestpair>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  push   %rbx
  mov    0x4(%rdi),%r8d
  mov    (%rdi),%r11d
  lea    -0x1(%rsi),%edi
  mov    %r8d,%r9d
  sub    %r11d,%r9d
  cmp    $0x1,%edi
  jle    L101
  cmp    $0x4,%esi
  jle    L95
  lea    -0x5(%rsi),%eax
  lea    0x8(%rcx),%r11
  xor    %r10d,%r10d
  mov    $0x1,%edx
  and    $0xfffffffe,%eax
  lea    0x3(%rax),%eax
L66:
  mov    (%r11),%ebx
  mov    %edx,%ebp
  mov    %ebx,%esi
  sub    %r8d,%esi
  cmp    %r9d,%esi
  jge    L8
L44:
  mov    0x4(%r11),%r8d
  lea    0x1(%rdx),%r10d
  mov    %r8d,%r9d
  sub    %ebx,%r9d
  cmp    %r9d,%esi
  jle    L41
  add    $0x2,%edx
  add    $0x8,%r11
  cmp    %eax,%edx
  jne    L66
L42:
  cltq
  nopl   0x0(%rax,%rax,1)
L48:
  mov    0x4(%rcx,%rax,4),%edx
  sub    (%rcx,%rax,4),%edx
  cmp    %r9d,%edx
  jge    L7
  mov    %eax,%r10d
  mov    %edx,%r9d
L7:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L48
  lea    0x1(%r10),%r8d
  movslq %r8d,%rax
  shl    $0x2,%rax
  mov    -0x4(%rcx,%rax,1),%r11d
L17:
  mov    (%rcx,%rax,1),%edx
  pop    %rbx
  mov    %r10d,%ecx
  mov    %r11d,%esi
  lea    D9(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L41:
  add    $0x2,%edx
  mov    %ebp,%r10d
  mov    %esi,%r9d
  add    $0x8,%r11
  cmp    %eax,%edx
  jne    L66
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r10d,%ebp
  mov    %r9d,%esi
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L101:
  mov    $0x4,%eax
  mov    $0x1,%r8d
  xor    %r10d,%r10d
  jmp    L17
L95:
  xor    %r10d,%r10d
  mov    $0x1,%eax
  jmp    L42
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: %d e %d, nas posicoes %d e %d respectivamente. Sua diferenca eh %d.

assistant: ```c
closestpair(int vet[], int n) {
  int i, c, dif, posicao = 0;
  dif = vet[1] - vet[0];
  for (i = 1; i < n - 1; i++) {
    c = vet[i + 1] - vet[i];
    if (c < dif) {
      dif = c;
      posicao = i;
    }
  }
  printf("%d e %d, nas posicoes %d e %d respectivamente. Sua diferenca eh %d.", vet[posicao], vet[posicao + 1], posicao, posicao + 1, dif);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_substring_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L86
  mov    $0xffffffff,%eax
  jmp    L62
L86:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L43
L65:
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L66:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L91
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L91:
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L66
L35:
  cmpl   $0x1,-0xc(%rbp)
  jne    L6
  mov    -0x14(%rbp),%eax
  jmp    L62
L6:
  subl   $0x1,-0x14(%rbp)
L43:
  cmpl   $0x0,-0x14(%rbp)
  jns    L65
  mov    $0xffffffff,%eax
L62:
  leave
  ret
```

assistant: ```c
int get_substring_index(char *haystack, char *needle) {
  int i = 0, d = 0, found, nlen = strlen(needle), hlen = strlen(haystack);
  if (hlen < nlen)
    return -1;
  for (i = hlen - nlen; i >= 0; i--) {
    found = 1;
    for (d = 0; d < nlen; d++) {
      if (haystack[i + d] != needle[d]) {
        found = 0;
        break;
      }
    }
    if (found == 1)
      return i;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_substring_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L35
  sub    %r12d,%eax
  movslq %eax,%rdx
  lea    (%rbx,%rdx,1),%rsi
  lea    -0x1(%r12),%edi
  mov    $0x0,%r8d
  jmp    L42
L47:
  mov    %rcx,%rdx
L49:
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rsi,%rdx,1)
  jne    L50
  lea    0x1(%rdx),%rcx
  cmp    %rdi,%rdx
  jne    L47
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0xffffffff,%eax
  jmp    L23
L50:
  sub    $0x1,%eax
  sub    $0x1,%rsi
  cmp    $0xffffffff,%eax
  je     L23
L42:
  test   %r12d,%r12d
  jle    L23
  mov    %r8,%rdx
  jmp    L49
```

assistant: ```c
int get_substring_index(char *haystack, char *needle) {
  int i = 0, d = 0, found, nlen = strlen(needle), hlen = strlen(haystack);
  if (hlen < nlen)
    return -1;
  for (i = hlen - nlen; i >= 0; i--) {
    found = 1;
    for (d = 0; d < nlen; d++) {
      if (haystack[i + d] != needle[d]) {
        found = 0;
        break;
      }
    }
    if (found == 1)
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_substring_index>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L34
  sub    %r12d,%eax
  movslq %r12d,%rsi
  movslq %eax,%rdx
  lea    (%rbx,%rdx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L8:
  test   %r12d,%r12d
  jle    L28
  xor    %edx,%edx
  jmp    L24
  nopl   0x0(%rax)
L65:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L28
L24:
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rcx,%rdx,1)
  je     L65
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L8
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L28
```

assistant: ```c
int get_substring_index(char *haystack, char *needle) {
  int i = 0, d = 0, found, nlen = strlen(needle), hlen = strlen(haystack);
  if (hlen < nlen)
    return -1;
  for (i = hlen - nlen; i >= 0; i--) {
    found = 1;
    for (d = 0; d < nlen; d++) {
      if (haystack[i + d] != needle[d]) {
        found = 0;
        break;
      }
    }
    if (found == 1)
      return i;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_substring_index>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jg     L11
  sub    %r12d,%eax
  movslq %r12d,%rsi
  movslq %eax,%rdx
  lea    (%rbx,%rdx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L63:
  test   %r12d,%r12d
  jle    L25
  xor    %edx,%edx
  jmp    L67
  nopl   0x0(%rax)
L35:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L25
L67:
  movzbl 0x0(%rbp,%rdx,1),%ebx
  cmp    %bl,(%rcx,%rdx,1)
  je     L35
  sub    $0x1,%eax
  sub    $0x1,%rcx
  cmp    $0xffffffff,%eax
  jne    L63
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L25
```

assistant: ```c
int get_substring_index(char *haystack, char *needle) {
  int i = 0, d = 0, found, nlen = strlen(needle), hlen = strlen(haystack);
  if (hlen < nlen)
    return -1;
  for (i = hlen - nlen; i >= 0; i--) {
    found = 1;
    for (d = 0; d < nlen; d++) {
      if (haystack[i + d] != needle[d]) {
        found = 0;
        break;
      }
    }
    if (found == 1)
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<t2p_normalize_timeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0xf4240(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
L13:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xf423f,%eax
  jg     L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct timeval *t2p_normalize_timeval(struct timeval *tv) {
  while (tv->tv_usec >= 1000000) {
    tv->tv_usec -= 1000000;
    tv->tv_sec++;
  }
  return tv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t2p_normalize_timeval>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edx
  cmp    $0xf423f,%edx
  jle    L7
  mov    0x4(%rdi),%edi
  lea    0x1(%rdi),%ecx
L10:
  sub    $0xf4240,%edx
  mov    %ecx,%esi
  add    $0x1,%ecx
  cmp    $0xf423f,%edx
  jg     L10
  mov    %edx,(%rax)
  mov    %esi,0x4(%rax)
L7:
  ret
```

assistant: ```c
struct timeval *t2p_normalize_timeval(struct timeval *tv) {
  while (tv->tv_usec >= 1000000) {
    tv->tv_usec -= 1000000;
    tv->tv_sec++;
  }
  return tv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t2p_normalize_timeval>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0xf423f,%edx
  jle    L17
  mov    0x4(%rdi),%edi
  lea    0x1(%rdi),%ecx
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0xf4240,%edx
  mov    %ecx,%esi
  add    $0x1,%ecx
  cmp    $0xf423f,%edx
  jg     L12
  mov    %edx,(%rax)
  mov    %esi,0x4(%rax)
L17:
  ret
```

assistant: ```c
struct timeval *t2p_normalize_timeval(struct timeval *tv) {
  while (tv->tv_usec >= 1000000) {
    tv->tv_usec -= 1000000;
    tv->tv_sec++;
  }
  return tv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<t2p_normalize_timeval>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edi
  cmp    $0xf423f,%edi
  jle    L49
  lea    -0xf4240(%rdi),%esi
  mov    0x4(%rax),%r8d
  mov    %rsi,%rdx
  imul   $0x431bde83,%rsi,%rsi
  shr    $0x32,%rsi
  add    $0x1,%esi
  cmp    $0x3d08ff,%edx
  jbe    L4
  movd   %edi,%xmm4
  movd   %r8d,%xmm5
  mov    %esi,%ecx
  xor    %edx,%edx
  pshufd $0x0,%xmm4,%xmm3
  pshufd $0x0,%xmm5,%xmm2
  paddd  D58(%rip),%xmm3
  movdqa D33(%rip),%xmm7
  paddd  D0(%rip),%xmm2
  movdqa D18(%rip),%xmm6
  shr    $0x2,%ecx
  movdqa D55(%rip),%xmm5
  movdqa D10(%rip),%xmm4
  cs nopw 0x0(%rax,%rax,1)
L17:
  movdqa %xmm2,%xmm1
  movdqa %xmm3,%xmm0
  paddd  %xmm7,%xmm2
  add    $0x1,%edx
  paddd  %xmm6,%xmm3
  paddd  %xmm5,%xmm0
  paddd  %xmm4,%xmm1
  cmp    %ecx,%edx
  jne    L17
  mov    %esi,%r9d
  pshufd $0xff,%xmm1,%xmm1
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%r9d
  movd   %xmm1,%ecx
  movd   %xmm0,%edx
  imul   $0xfff0bdc0,%r9d,%r10d
  add    %r9d,%r8d
  add    %r10d,%edi
  cmp    %r9d,%esi
  je     L31
  lea    -0xf4240(%rdi),%edx
L4:
  lea    0x1(%r8),%ecx
  cmp    $0xf423f,%edx
  jle    L31
  lea    -0x1e8480(%rdi),%edx
  lea    0x2(%r8),%ecx
  cmp    $0xf423f,%edx
  jle    L31
  lea    -0x2dc6c0(%rdi),%edx
  lea    0x3(%r8),%ecx
  cmp    $0xf423f,%edx
  jle    L31
  lea    -0x3d0900(%rdi),%edx
  lea    0x4(%r8),%ecx
L31:
  mov    %edx,(%rax)
  mov    %ecx,0x4(%rax)
L49:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D58
type: byte[16]
name: extract_symbolic_data
arguments: label: D33
type: byte[16]
name: extract_symbolic_data
arguments: label: D0
type: byte[16]
name: extract_symbolic_data
arguments: label: D18
type: byte[16]
name: extract_symbolic_data
arguments: label: D55
type: byte[16]
name: extract_symbolic_data
arguments: label: D10
type: byte[16]

tool: {"D58": [0x00,0x00,0x00,0x00,0xc0,0xbd,0xf0,0xff,0x80,0x7b,0xe1,0xff,0x40,0x39,0xd2,0xff]}

tool: {"D33": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D18": [0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff,0x00,0xf7,0xc2,0xff]}

tool: {"D55": [0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff,0xc0,0xbd,0xf0,0xff]}

tool: {"D10": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
struct timeval *t2p_normalize_timeval(struct timeval *tv) {
  while (tv->tv_usec >= 1000000) {
    tv->tv_usec -= 1000000;
    tv->tv_sec++;
  }
  return tv;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_one() {
#pragma omp parallel sections
  { ; }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_one>:
  endbr64
  ret
```

assistant: ```c
void test_one() {
#pragma omp parallel sections
  { ; }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_one>:
  endbr64
  ret
```

assistant: ```c
void test_one() {
#pragma omp parallel sections
  { ; }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_one>:
  endbr64
  ret
```

assistant: ```c
void test_one() {
#pragma omp parallel sections
  { ; }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <accept4@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int res = accept4(0, NULL, NULL, SOCK_NONBLOCK);
  (void)res;
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <accept4@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int res = accept4(0, NULL, NULL, SOCK_NONBLOCK);
  (void)res;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    (%rax),%ecx
  call   <accept4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int res = accept4(0, NULL, NULL, SOCK_NONBLOCK);
  (void)res;
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    (%rax),%ecx
  call   <accept4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int res = accept4(0, NULL, NULL, SOCK_NONBLOCK);
  (void)res;
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <dfs@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: %d%d

assistant: ```c
int main() {
  int n, l;
  scanf("%d%d", &n, &l);
  dfs(0, l, n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    $0x0,%edi
  call   <dfs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: %d%d

assistant: ```c
int main() {
  int n, l;
  scanf("%d%d", &n, &l);
  dfs(0, l, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %edi,%edi
  call   <dfs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %d%d

assistant: ```c
int main() {
  int n, l;
  scanf("%d%d", &n, &l);
  dfs(0, l, n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %edi,%edi
  call   <dfs@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: %d%d

assistant: ```c
int main() {
  int n, l;
  scanf("%d%d", &n, &l);
  dfs(0, l, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<average_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L32:
  cmp    %rdx,%rsp
  je     L70
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L70:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L15
  orq    $0x0,-0x8(%rsp,%rax,1)
L15:
  mov    %rsp,%rbx
  test   %r14d,%r14d
  jle    L99
  mov    %rbx,%r12
  mov    %r14d,%eax
  lea    (%rbx,%rax,4),%r13
  pxor   %xmm6,%xmm6
  movsd  %xmm6,-0x48(%rbp)
  lea    D14(%rip),%r15
L6:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rbx),%xmm0
  addsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L6
  pxor   %xmm4,%xmm4
  cvtsi2sd %r14d,%xmm4
  movsd  -0x48(%rbp),%xmm1
  divsd  %xmm4,%xmm1
  pxor   %xmm0,%xmm0
  movsd  D18(%rip),%xmm3
  jmp    L97
L44:
  add    $0x4,%r12
  cmp    %r13,%r12
  je     L67
L97:
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%r12),%xmm2
  comisd %xmm1,%xmm2
  jbe    L44
  addsd  %xmm3,%xmm0
  jmp    L44
L99:
  pxor   %xmm4,%xmm4
  cvtsi2sd %r14d,%xmm4
  pxor   %xmm0,%xmm0
L67:
  divsd  %xmm4,%xmm0
  mulsd  D3(%rip),%xmm0
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D18
type_infered: f32[2]
name: read_data
arguments: label: D3
type_infered: f32[2]

tool: D14: %d

tool: {"D18": [0.0,1.875]}

tool: {"D3": [0.0,3.390625]}

assistant: ```c
double average_test(int count) {
  double average = 0;
  int arr[count];
  for (int i = 0; i < count; i++) {
    scanf("%d", arr + i);
    average += arr[i];
  }
  average /= count;
  double counter = 0;
  for (int i = 0; i < count; i++) {
    if (arr[i] > average)
      counter++;
  }
  return (counter / count) * 100;
}
```
user: Translate the below assembly code into C programming language:

```asm
<average_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L93:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L93
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L52
L35:
  mov    %rsp,%r12
  test   %r14d,%r14d
  jle    L90
  mov    %r14d,%eax
  mov    %r12,%rbx
  pxor   %xmm0,%xmm0
  lea    (%r12,%rax,4),%r13
  lea    D19(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  movsd  %xmm0,-0x48(%rbp)
  add    $0x4,%rbx
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movsd  -0x48(%rbp),%xmm0
  cvtsi2sdl -0x4(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %r13,%rbx
  jne    L0
  pxor   %xmm4,%xmm4
  movsd  D5(%rip),%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14d,%xmm4
  divsd  %xmm4,%xmm0
  nopl   0x0(%rax)
L72:
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%r12),%xmm2
  comisd %xmm0,%xmm2
  jbe    L51
  addsd  %xmm3,%xmm1
L51:
  add    $0x4,%r12
  cmp    %r13,%r12
  jne    L72
L39:
  divsd  %xmm4,%xmm1
  mulsd  D8(%rip),%xmm1
  movapd %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L35
L90:
  pxor   %xmm4,%xmm4
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14d,%xmm4
  jmp    L39
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D5
data_type: f32[2]
name: parse_data
arguments: data_label: D8
data_type: f32[2]

tool: D19: %d

tool: {"D5": [0.0,1.875]}

tool: {"D8": [0.0,3.390625]}

assistant: ```c
double average_test(int count) {
  double average = 0;
  int arr[count];
  for (int i = 0; i < count; i++) {
    scanf("%d", arr + i);
    average += arr[i];
  }
  average /= count;
  double counter = 0;
  for (int i = 0; i < count; i++) {
    if (arr[i] > average)
      counter++;
  }
  return (counter / count) * 100;
}
```