ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply65>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L72
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L82:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L59
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L59
  nopl   0x0(%rax)
L98:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L98
  cmp    -0x24(%rsp),%r11d
  je     L31
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L31
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L31
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L31:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L82
L72:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L46:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L46
  mov    -0x18(%rsp),%r8
  jmp    L31
```

assistant: ```c
void multiply65(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<io_write_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  lea    -0x8(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    $0x1,%eax
  je     L5
  mov    $0xffffffff,%eax
  jmp    L9
L5:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int io_write_byte(int dest, char c) {
  if (write(dest, &c, 1) != 1)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<io_write_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int io_write_byte(int dest, char c) {
  if (write(dest, &c, 1) != 1)
    return -1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<io_write_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int io_write_byte(int dest, char c) {
  if (write(dest, &c, 1) != 1)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<io_write_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int io_write_byte(int dest, char c) {
  if (write(dest, &c, 1) != 1)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<register_sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <sigfillset@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void register_sig_handler(int signal, void (*handler)(int)) {
  struct sigaction sa;
  memset(&sa, 0, sizeof(sa));
  sa.sa_handler = handler;
  sigfillset(&sa.sa_mask);
  sigaction(signal, &sa, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<register_sig_handler>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,(%rsp)
  lea    0x8(%rsp),%rdi
  call   <sigfillset@plt>
  mov    $0x0,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <sigaction@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_sig_handler(int signal, void (*handler)(int)) {
  struct sigaction sa;
  memset(&sa, 0, sizeof(sa));
  sa.sa_handler = handler;
  sigfillset(&sa.sa_mask);
  sigaction(signal, &sa, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<register_sig_handler>:
  endbr64
  push   %r12
  mov    $0x10,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x8(%rsp),%rdi
  mov    %rbx,(%rsp)
  call   <sigfillset@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <sigaction@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_sig_handler(int signal, void (*handler)(int)) {
  struct sigaction sa;
  memset(&sa, 0, sizeof(sa));
  sa.sa_handler = handler;
  sigfillset(&sa.sa_mask);
  sigaction(signal, &sa, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<register_sig_handler>:
  endbr64
  push   %r12
  mov    $0x10,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x8(%rsp),%rdi
  mov    %rbx,(%rsp)
  call   <sigfillset@plt>
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <sigaction@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void register_sig_handler(int signal, void (*handler)(int)) {
  struct sigaction sa;
  memset(&sa, 0, sizeof(sa));
  sa.sa_handler = handler;
  sigfillset(&sa.sa_mask);
  sigaction(signal, &sa, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crami>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  lea    -0x20(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <proutn@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: %*d

assistant: ```c
void crami(int i, int w) {
  char buf[16];
  sprintf(buf, "%*d", w, i);
  proutn(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crami>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <proutn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: %*d

assistant: ```c
void crami(int i, int w) {
  char buf[16];
  sprintf(buf, "%*d", w, i);
  proutn(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<crami>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  mov    %esi,%edx
  lea    D4(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <proutn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D4: %*d

assistant: ```c
void crami(int i, int w) {
  char buf[16];
  sprintf(buf, "%*d", w, i);
  proutn(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crami>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  mov    %esi,%edx
  lea    D8(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <proutn@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: %*d

assistant: ```c
void crami(int i, int w) {
  char buf[16];
  sprintf(buf, "%*d", w, i);
  proutn(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fprint_xrl_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: XRL   A, #0x%02X                  

assistant: ```c
void fprint_xrl_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "XRL   A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: What is the c source code of the assembly code below:

```asm
<fprint_xrl_data>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  lea    D4(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: XRL   A, #0x%02X                  

assistant: ```c
void fprint_xrl_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "XRL   A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fprint_xrl_data>:
  endbr64
  mov    %esi,%edx
  lea    D6(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: XRL   A, #0x%02X                  

assistant: ```c
void fprint_xrl_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "XRL   A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fprint_xrl_data>:
  endbr64
  mov    %esi,%edx
  lea    D7(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: XRL   A, #0x%02X                  

assistant: ```c
void fprint_xrl_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "XRL   A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lu_polish>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %r8,%rbp
  mov    %r9,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%edx
  jg     L16
  test   %edx,%edx
  jle    L68
  lea    0x10(%rsp),%r12
L2:
  mov    $0x0,%ecx
  movq   D4(%rip),%xmm2
L27:
  movsd  (%r14,%rcx,8),%xmm1
  xorpd  %xmm2,%xmm1
  mov    0x0(%r13,%rcx,8),%rdx
  mov    $0x0,%eax
L79:
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  0x0(%rbp,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L79
  movsd  %xmm1,(%r12,%rcx,8)
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jg     L27
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %ebx,%esi
  mov    0x8(%rsp),%rdi
  call   <lu_backsub@plt>
  mov    $0x0,%eax
L86:
  movsd  0x0(%rbp,%rax,8),%xmm0
  subsd  (%r12,%rax,8),%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L86
  lea    0x10(%rsp),%rax
  cmp    %rax,%r12
  je     L41
  lea    -0x1(%rbx),%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <free_dvector@plt>
L41:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  lea    -0x1(%rdx),%esi
  mov    $0x0,%edi
  call   <dvector@plt>
  mov    %rax,%r12
  jmp    L2
L68:
  lea    0x10(%rsp),%rcx
  mov    %r9,%rdx
  mov    %ebx,%esi
  mov    0x8(%rsp),%rdi
  call   <lu_backsub@plt>
  jmp    L41
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void lu_polish(double **a, double **lua, int n, double *b, double *x, int *pivx) {
  int i, j;
  double *r, R[10];
  if (n <= 10)
    r = R;
  else
    r = dvector(0, n - 1);
  for (i = 0; i < n; i++) {
    double sum;
    sum = -b[i];
    for (j = 0; j < n; j++)
      sum += a[i][j] * x[j];
    r[i] = sum;
  }
  lu_backsub(lua, n, pivx, r);
  for (i = 0; i < n; i++)
    x[i] -= r[i];
  if (r != R)
    free_dvector(r, 0, n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lu_polish>:
  endbr64
  push   %r15
  mov    %rcx,%r10
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%edx
  jg     L71
  test   %edx,%edx
  jle    L34
  lea    0x10(%rsp),%r14
  mov    %r14,%r15
L61:
  movq   D8(%rip),%xmm2
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L81:
  movsd  (%r10,%rcx,8),%xmm1
  mov    (%r12,%rcx,8),%rdx
  xor    %eax,%eax
  xorpd  %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L62:
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %eax,%ebp
  jg     L62
  movsd  %xmm1,(%r15,%rcx,8)
  add    $0x1,%rcx
  cmp    %ecx,%ebp
  jg     L81
  mov    %r15,%rcx
  mov    %r9,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <lu_backsub@plt>
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L39:
  movsd  (%rbx,%rax,8),%xmm0
  subsd  (%r15,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L39
  cmp    %r14,%r15
  je     L65
  lea    -0x1(%rbp),%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <free_dvector@plt>
L65:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  lea    -0x1(%rdx),%esi
  xor    %edi,%edi
  mov    %r9,0x8(%rsp)
  lea    0x10(%rsp),%r14
  mov    %rcx,(%rsp)
  call   <dvector@plt>
  mov    (%rsp),%r10
  mov    0x8(%rsp),%r9
  mov    %rax,%r15
  jmp    L61
L34:
  lea    0x10(%rsp),%rcx
  mov    %r9,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <lu_backsub@plt>
  jmp    L65
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void lu_polish(double **a, double **lua, int n, double *b, double *x, int *pivx) {
  int i, j;
  double *r, R[10];
  if (n <= 10)
    r = R;
  else
    r = dvector(0, n - 1);
  for (i = 0; i < n; i++) {
    double sum;
    sum = -b[i];
    for (j = 0; j < n; j++)
      sum += a[i][j] * x[j];
    r[i] = sum;
  }
  lu_backsub(lua, n, pivx, r);
  for (i = 0; i < n; i++)
    x[i] -= r[i];
  if (r != R)
    free_dvector(r, 0, n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<misc_deregister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int misc_deregister(struct miscdevice *misc) {
  int i;
  { return (i); }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<misc_deregister>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int misc_deregister(struct miscdevice *misc) {
  int i;
  { return (i); }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<misc_deregister>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int misc_deregister(struct miscdevice *misc) {
  int i;
  { return (i); }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<misc_deregister>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int misc_deregister(struct miscdevice *misc) {
  int i;
  { return (i); }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ct_fast_cos_impl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D21(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  D23(%rip),%xmm1
  subss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  D3(%rip),%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
type_guessed: byte[4]
name: unpack_data
arguments: tag: D23
type_guessed: byte[4]
name: unpack_data
arguments: tag: D3
type_guessed: byte[4]

tool: {"D21": [0xdf,0xb2,0x16,0x3d]}

tool: {"D23": [0xc2,0xbc,0xfd,0x3e]}

tool: {"D3": [0xe1,0xd8,0x7f,0x3f]}

assistant: ```c
float ct_fast_cos_impl(const float x) {
  const float x2 = x * x;
  return 0.99940307f + x2 * (-0.49558072f + 0.03679168f * x2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ct_fast_cos_impl>:
  endbr64
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  mulss  D4(%rip),%xmm1
  subss  D2(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D25(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: byte[4]
name: retrieve_data
arguments: data_label: D2
datatype: byte[4]
name: retrieve_data
arguments: data_label: D25
datatype: byte[4]

tool: {"D4": [0xdf,0xb2,0x16,0x3d]}

tool: {"D2": [0xc2,0xbc,0xfd,0x3e]}

tool: {"D25": [0xe1,0xd8,0x7f,0x3f]}

assistant: ```c
float ct_fast_cos_impl(const float x) {
  const float x2 = x * x;
  return 0.99940307f + x2 * (-0.49558072f + 0.03679168f * x2);
}
```
user: What is the c source code of the assembly code below?

```asm
<ct_fast_cos_impl>:
  endbr64
  mulss  %xmm0,%xmm0
  movss  D27(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D13(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D18(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type: byte[4]
name: extract_symbolic_data
arguments: label: D13
type: byte[4]
name: extract_symbolic_data
arguments: label: D18
type: byte[4]

tool: {"D27": [0xdf,0xb2,0x16,0x3d]}

tool: {"D13": [0xc2,0xbc,0xfd,0x3e]}

tool: {"D18": [0xe1,0xd8,0x7f,0x3f]}

assistant: ```c
float ct_fast_cos_impl(const float x) {
  const float x2 = x * x;
  return 0.99940307f + x2 * (-0.49558072f + 0.03679168f * x2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ct_fast_cos_impl>:
  endbr64
  mulss  %xmm0,%xmm0
  movss  D28(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D1(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D15(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D28
type_guessed: byte[4]
name: disassemble_data
arguments: label: D1
type_guessed: byte[4]
name: disassemble_data
arguments: label: D15
type_guessed: byte[4]

tool: {"D28": [0xdf,0xb2,0x16,0x3d]}

tool: {"D1": [0xc2,0xbc,0xfd,0x3e]}

tool: {"D15": [0xe1,0xd8,0x7f,0x3f]}

assistant: ```c
float ct_fast_cos_impl(const float x) {
  const float x2 = x * x;
  return 0.99940307f + x2 * (-0.49558072f + 0.03679168f * x2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L7:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x10(%rbp,%rdx,4)
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <generator@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: Arguments: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int restr[2];
  int i;
  for (i = 0; i < 2; i++) {
    restr[i] = atoi(argv[i + 1]);
    printf("Arguments: %d\n", restr[i]);
  }
  generator(restr);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %eax,(%rsp)
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %eax,0x4(%rsp)
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <generator@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: Arguments: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int restr[2];
  int i;
  for (i = 0; i < 2; i++) {
    restr[i] = atoi(argv[i + 1]);
    printf("Arguments: %d\n", restr[i]);
  }
  generator(restr);
  return 0;
}
```