ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<_internal_login_tty>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    $0x0,%eax
  call   <setsid@plt>
  lea    0xc(%rsp),%rdi
  mov    $0x1,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <_internal_get_tty@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%esi
  mov    0xc(%rsp),%edi
  call   <dup2@plt>
  mov    $0x1,%esi
  mov    0xc(%rsp),%edi
  call   <dup2@plt>
  mov    $0x2,%esi
  mov    0xc(%rsp),%edi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  mov    $0x0,%eax
  cmp    $0x2,%edi
  jg     L16
L5:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <close@plt>
  mov    $0x0,%eax
  jmp    L5
L10:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int _internal_login_tty(int fd, const char *path, struct termios *termp, struct winsize *winp) {
  setsid();
  if (_internal_get_tty(&fd, path, termp, winp, 1) != 0)
    return -1;
  dup2(fd, 0);
  dup2(fd, 1);
  dup2(fd, 2);
  if (fd > 2)
    close(fd);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_internal_login_tty>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  call   <setsid@plt>
  lea    0xc(%rsp),%rdi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    $0x1,%r8d
  mov    %rbp,%rsi
  call   <_internal_get_tty@plt>
  test   %rax,%rax
  jne    L13
  mov    0xc(%rsp),%edi
  xor    %esi,%esi
  xor    %r12d,%r12d
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  mov    $0x2,%esi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  cmp    $0x2,%edi
  jg     L12
L22:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L12:
  call   <close@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%r12d
  jmp    L22
```

assistant: ```c
int _internal_login_tty(int fd, const char *path, struct termios *termp, struct winsize *winp) {
  setsid();
  if (_internal_get_tty(&fd, path, termp, winp, 1) != 0)
    return -1;
  dup2(fd, 0);
  dup2(fd, 1);
  dup2(fd, 2);
  if (fd > 2)
    close(fd);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_internal_login_tty>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  call   <setsid@plt>
  lea    0xc(%rsp),%rdi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    $0x1,%r8d
  mov    %rbp,%rsi
  call   <_internal_get_tty@plt>
  test   %rax,%rax
  jne    L10
  mov    0xc(%rsp),%edi
  xor    %esi,%esi
  xor    %r12d,%r12d
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  mov    $0x2,%esi
  call   <dup2@plt>
  mov    0xc(%rsp),%edi
  cmp    $0x2,%edi
  jg     L13
L5:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  call   <close@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%r12d
  jmp    L5
```

assistant: ```c
int _internal_login_tty(int fd, const char *path, struct termios *termp, struct winsize *winp) {
  setsid();
  if (_internal_get_tty(&fd, path, termp, winp, 1) != 0)
    return -1;
  dup2(fd, 0);
  dup2(fd, 1);
  dup2(fd, 2);
  if (fd > 2)
    close(fd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L12:
  mov    $0x0,%eax
  call   <dropping@plt>
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    dropping();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L10
  mov    $0x0,%ebx
L1:
  mov    $0x0,%eax
  call   <dropping@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L1
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    dropping();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L28
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <dropping@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L22
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    dropping();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <dropping@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L23
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    dropping();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L6
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rax
  movzbl (%rax),%edx
  mov    $0x0,%ebx
  lea    D56(%rip),%r14
  lea    D84(%rip),%r12
  lea    D9(%rip),%r15
  lea    D30(%rip),%r13
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L114
  jmp    L52
L6:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L52
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L77:
  add    $0x1,%rbx
  mov    0x8(%rbp),%rax
  movzbl (%rax,%rbx,1),%edx
  test   %dl,%dl
  je     L123
L114:
  mov    %ebx,%esi
  lea    -0x41(%rdx),%eax
  cmp    $0x38,%al
  ja     L38
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
  lea    D85(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
  cmp    $0x2,%ebx
  jle    L77
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
L38:
  movsbl %dl,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
L123:
  mov    $0x0,%eax
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D56
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D63
type_infered: string
name: unpack_data
arguments: label: D85
type_infered: string

tool: D56: %d: %c is not a vowel


tool: D9: %d: 'Y'


tool: D30: %d: 'U'


tool: D10: ERROR: You need exactly one argument.

tool: D48: %d: 'A'


tool: D25: %d: 'E'


tool: D63: %d: 'I'


tool: D85: %d: 'O'


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("ERROR: You need exactly one argument.\n");
    return 1;
  }
  int i = 0;
  for (i = 0; argv[1][i] != '\0'; i++) {
    char letter = argv[1][i];
    switch (letter) {
    case 'a':
    case 'A':
      printf("%d: 'A'\n", i);
      break;
    case 'e':
    case 'E':
      printf("%d: 'E'\n", i);
      break;
    case 'i':
    case 'I':
      printf("%d: 'I'\n", i);
      break;
    case 'o':
    case 'O':
      printf("%d: 'O'\n", i);
      break;
    case 'u':
    case 'U':
      printf("%d: 'U'\n", i);
      break;
    case 'y':
    case 'Y':
      if (i > 2) {
        printf("%d: 'Y'\n", i);
      }
      break;
    default:
      printf("%d: %c is not a vowel\n", i, letter);
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L0:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x4,-0x8(%rbp)
  jle    L0
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int counter = 0;
  for (; counter < 5; counter++) {
    int a;
    a++;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter = 0;
  for (; counter < 5; counter++) {
    int a;
    a++;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter = 0;
  for (; counter < 5; counter++) {
    int a;
    a++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int counter = 0;
  for (; counter < 5; counter++) {
    int a;
    a++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L2
L0:
  cmpl   $0x0,-0x14(%rbp)
  jns    L26
  negl   -0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int numcount(int integer) {
  if (integer == 0) {
    return 1;
  }
  if (integer < 0) {
    integer = integer * -1;
  }
  int count = (int)floor(log10(integer)) + 1;
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numcount>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  mov    %edi,%eax
  neg    %eax
  cmovns %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int numcount(int integer) {
  if (integer == 0) {
    return 1;
  }
  if (integer < 0) {
    integer = integer * -1;
  }
  int count = (int)floor(log10(integer)) + 1;
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<numcount>:
  endbr64
  test   %edi,%edi
  jne    L5
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L5:
  mov    %edi,%eax
  sub    $0x8,%rsp
  neg    %eax
  cmovns %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  ret
```

assistant: ```c
int numcount(int integer) {
  if (integer == 0) {
    return 1;
  }
  if (integer < 0) {
    integer = integer * -1;
  }
  int count = (int)floor(log10(integer)) + 1;
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<numcount>:
  endbr64
  test   %edi,%edi
  jne    L9
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L9:
  mov    %edi,%eax
  sub    $0x8,%rsp
  neg    %eax
  cmovns %eax,%edi
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  add    $0x1,%eax
  ret
```

assistant: ```c
int numcount(int integer) {
  if (integer == 0) {
    return 1;
  }
  if (integer < 0) {
    integer = integer * -1;
  }
  int count = (int)floor(log10(integer)) + 1;
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_padding_md>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0x1,%eax
  jmp    L21
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_MD_type@plt>
  mov    %eax,-0x4(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L34
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L21
L34:
  mov    D60(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L30
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <RSA_X931_hash_id@plt>
  cmp    $0xffffffff,%eax
  jne    L64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L21
L30:
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0xa,%eax
  ja     L8
  mov    $0x1,%eax
  jmp    L21
L8:
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RSAerr@plt>
  mov    $0x0,%eax
  jmp    L21
L64:
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
int check_padding_md(const EVP_MD *md, int padding) {
  int mdnid;
  if (!md)
    return 1;
  mdnid = EVP_MD_type(md);
  if (padding == RSA_NO_PADDING) {
    RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_PADDING_MODE);
    return 0;
  }
  if (padding == RSA_X931_PADDING) {
    if (RSA_X931_hash_id(mdnid) == -1) {
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_X931_DIGEST);
      return 0;
    }
  } else {
    switch (mdnid) {
    case NID_sha1:
    case NID_sha224:
    case NID_sha256:
    case NID_sha384:
    case NID_sha512:
    case NID_md5:
    case NID_md5_sha1:
    case NID_md2:
    case NID_md4:
    case NID_mdc2:
    case NID_ripemd160:
      return 1;
    default:
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_DIGEST);
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_padding_md>:
  endbr64
  mov    $0x1,%edx
  test   %rdi,%rdi
  je     L19
  push   %rbx
  mov    %esi,%ebx
  call   <EVP_MD_type@plt>
  mov    D29(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L36
  mov    D33(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L15
  add    $0xffffff80,%eax
  mov    $0x1,%edx
  cmp    $0xa,%eax
  ja     L79
L26:
  mov    %edx,%eax
  pop    %rbx
  ret
L36:
  mov    D56(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%edx
  jmp    L26
L15:
  mov    %eax,%edi
  call   <RSA_X931_hash_id@plt>
  mov    $0x1,%edx
  cmp    $0xffffffff,%eax
  jne    L26
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%edx
  jmp    L26
L79:
  mov    D63(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  mov    $0x0,%edx
  jmp    L26
L19:
  mov    %edx,%eax
  ret
```

assistant: ```c
int check_padding_md(const EVP_MD *md, int padding) {
  int mdnid;
  if (!md)
    return 1;
  mdnid = EVP_MD_type(md);
  if (padding == RSA_NO_PADDING) {
    RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_PADDING_MODE);
    return 0;
  }
  if (padding == RSA_X931_PADDING) {
    if (RSA_X931_hash_id(mdnid) == -1) {
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_X931_DIGEST);
      return 0;
    }
  } else {
    switch (mdnid) {
    case NID_sha1:
    case NID_sha224:
    case NID_sha256:
    case NID_sha384:
    case NID_sha512:
    case NID_md5:
    case NID_md5_sha1:
    case NID_md2:
    case NID_md4:
    case NID_mdc2:
    case NID_ripemd160:
      return 1;
    default:
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_DIGEST);
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_padding_md>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %rbx
  mov    %esi,%ebx
  call   <EVP_MD_type@plt>
  mov    D28(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L62
  mov    D44(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L30
  add    $0xffffff80,%eax
  cmp    $0xa,%eax
  ja     L66
L18:
  mov    $0x1,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %eax,%edi
  call   <RSA_X931_hash_id@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    D45(%rip),%rax
  jmp    L48
  nopl   (%rax)
L66:
  mov    D52(%rip),%rax
L48:
  mov    (%rax),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  mov    D42(%rip),%rax
  jmp    L48
```

assistant: ```c
int check_padding_md(const EVP_MD *md, int padding) {
  int mdnid;
  if (!md)
    return 1;
  mdnid = EVP_MD_type(md);
  if (padding == RSA_NO_PADDING) {
    RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_PADDING_MODE);
    return 0;
  }
  if (padding == RSA_X931_PADDING) {
    if (RSA_X931_hash_id(mdnid) == -1) {
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_X931_DIGEST);
      return 0;
    }
  } else {
    switch (mdnid) {
    case NID_sha1:
    case NID_sha224:
    case NID_sha256:
    case NID_sha384:
    case NID_sha512:
    case NID_md5:
    case NID_md5_sha1:
    case NID_md2:
    case NID_md4:
    case NID_mdc2:
    case NID_ripemd160:
      return 1;
    default:
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_DIGEST);
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_padding_md>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %esi,%ebx
  call   <EVP_MD_type@plt>
  mov    D20(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L14
  mov    D5(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L13
  add    $0xffffff80,%eax
  cmp    $0xa,%eax
  ja     L56
L62:
  mov    $0x1,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %eax,%edi
  call   <RSA_X931_hash_id@plt>
  cmp    $0xffffffff,%eax
  jne    L62
  mov    D19(%rip),%rax
  jmp    L30
  nopl   (%rax)
L56:
  mov    D47(%rip),%rax
L30:
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <RSAerr@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    D42(%rip),%rax
  jmp    L30
```

assistant: ```c
int check_padding_md(const EVP_MD *md, int padding) {
  int mdnid;
  if (!md)
    return 1;
  mdnid = EVP_MD_type(md);
  if (padding == RSA_NO_PADDING) {
    RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_PADDING_MODE);
    return 0;
  }
  if (padding == RSA_X931_PADDING) {
    if (RSA_X931_hash_id(mdnid) == -1) {
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_X931_DIGEST);
      return 0;
    }
  } else {
    switch (mdnid) {
    case NID_sha1:
    case NID_sha224:
    case NID_sha256:
    case NID_sha384:
    case NID_sha512:
    case NID_md5:
    case NID_md5_sha1:
    case NID_md2:
    case NID_md4:
    case NID_mdc2:
    case NID_ripemd160:
      return 1;
    default:
      RSAerr(RSA_F_CHECK_PADDING_MD, RSA_R_INVALID_DIGEST);
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utils_strcat4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *utils_strcat4(char *_str1, char *_str2, char *_str3, char *_str4) {
  char *str5 = (char *)calloc((strlen(_str1) + strlen(_str2) + strlen(_str3) + strlen(_str4)), sizeof(char));
  str5 = strcat(str5, _str1);
  str5 = strcat(str5, _str2);
  str5 = strcat(str5, _str3);
  str5 = strcat(str5, _str4);
  return str5;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utils_strcat4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rbx,%r15,1),%rdi
  add    0x8(%rsp),%rdi
  add    %rax,%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <strcat@plt>
  mov    %rax,%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <strcat@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *utils_strcat4(char *_str1, char *_str2, char *_str3, char *_str4) {
  char *str5 = (char *)calloc((strlen(_str1) + strlen(_str2) + strlen(_str3) + strlen(_str4)), sizeof(char));
  str5 = strcat(str5, _str1);
  str5 = strcat(str5, _str2);
  str5 = strcat(str5, _str3);
  str5 = strcat(str5, _str4);
  return str5;
}
```