user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_context>:
  endbr64
  push   %r15
  mov    $0x20,%ecx
  xor    %eax,%eax
  lea    D56(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D61(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0xc8(%r12),%r14
  push   %rbx
  mov    %r12,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r13d
  lea    D1(%rip),%rdi
  sar    %cl,%r13d
  mov    %r13d,%esi
  call   <printf@plt>
  jmp    L27
  nopl   0x0(%rax)
L8:
  add    $0x8,%rbx
  shr    %r13d
  cmp    %r14,%rbx
  je     L37
L27:
  test   $0x1,%r13b
  je     L8
  mov    (%rbx),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  shr    %r13d
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L27
L37:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  lea    D29(%rip),%r13
  call   <putchar@plt>
  lea    D25(%rip),%r15
  lea    D59(%rip),%rsi
  xor    %eax,%eax
  lea    D60(%rip),%r14
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L34:
  movslq (%r14,%rbx,4),%rax
  mov    (%r12,%rax,8),%rsi
L55:
  mov    0x4(%rbp,%rax,4),%eax
  mov    $0x20,%ecx
  mov    %r13,%rdi
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xb,%rbx
  je     L42
  lea    D75(%rip),%rax
  mov    $0x20,%ecx
  movslq (%rax,%rbx,4),%rax
  mov    0x4(%rbp,%rax,4),%edi
  mov    (%r12,%rax,8),%rsi
  xor    %eax,%eax
  mov    %edi,%edx
  sar    %cl,%edx
  mov    %edi,%ecx
  mov    %r15,%rdi
  call   <printf@plt>
L42:
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    $0xc,%rbx
  jne    L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D56
type: string
name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D29
type: string
name: unpack_data
arguments: data_label: D25
type: string
name: unpack_data
arguments: data_label: D59
type: string
name: unpack_data
arguments: data_label: D60
type: string
name: unpack_data
arguments: data_label: D75
type: string

tool: D56:  %s

tool: D1:   valid_regs (%08lx):

tool: D29:   %-8s %08x %08x

tool: D25:       %-8s %08x %08x

tool: D59: ip

tool: 

tool: D75: 

assistant: ```c
void dump_context(uint64_t *context) {
  int i, j;
  unsigned int valid;
  uint64_t val;
  static char *names[] = {"ip", "sp", "bsp", "cfm", "rp", "psp", "pfs", "preds", "priunat", "ar.bspstore", "ar.rnat", "ar.unat", "ar.fpsr", "ar.lc", "ar.pfs", "(pad)", "gr4", "gr5", "gr6", "gr7", "br1", "br2", "br3", "br4", "br5"};
  static int col1[] = {
      0, 1, 2, 3, 4, 5, 6, 10, 11, 12, 13, 14,
  };
  static int col2[] = {
      7, 8, 16, 17, 18, 19, 20, 21, 22, 23, 24,
  };
  valid = (unsigned int)(context[0] >> 32);
  printf("  valid_regs (%08lx):", valid);
  for (i = 0; i <= 24; i++) {
    if (valid & 1)
      printf(" %s", names[i]);
    valid >>= 1;
  }
  printf("\n");
  for (i = 0; i < ((sizeof(col1) / sizeof(int)) > (sizeof(col2) / sizeof(int)) ? (sizeof(col1) / sizeof(int)) : (sizeof(col2) / sizeof(int))); i++) {
    if (i < (sizeof(col1) / sizeof(int))) {
      j = col1[i];
      val = context[j + 1];
      printf("  %-8s %08x %08x", names[j], (unsigned int)(val >> 32), (unsigned int)val);
    } else
      printf("                            ");
    if (i < (sizeof(col2) / sizeof(int))) {
      j = col2[i];
      val = context[j + 1];
      printf("      %-8s %08x %08x", names[j], (unsigned int)(val >> 32), (unsigned int)val);
    }
    putchar('\n');
  }
}
```