ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ShareMallocM2c>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
L31:
  test   %ebp,%ebp
  jle    L44
  test   %r12d,%r12d
  jle    L44
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
L37:
  mov    %ebp,%edi
  call   <ShareMallocM1c@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L37
L44:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L31
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: char ** malloc error!


assistant: ```c
char **ShareMallocM2c(int size1, int size2) {
  int i;
  char **s = NULL;
  if ((s = (char **)calloc(size1, sizeof(char *))) == NULL) {
    printf("char ** malloc error!\n");
    exit(1);
  }
  if (size2 > 0) {
    for (i = 0; i < size1; i++)
      s[i] = ShareMallocM1c(size2);
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ShareMallocM2c>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L19
L44:
  test   %ebp,%ebp
  jle    L28
  test   %r12d,%r12d
  jle    L28
  mov    %r13,%rbx
  lea    0x0(%r13,%r12,8),%r12
  nopl   0x0(%rax)
L18:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <ShareMallocM1c@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L18
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: char ** malloc error!


assistant: ```c
char **ShareMallocM2c(int size1, int size2) {
  int i;
  char **s = NULL;
  if ((s = (char **)calloc(size1, sizeof(char *))) == NULL) {
    printf("char ** malloc error!\n");
    exit(1);
  }
  if (size2 > 0) {
    for (i = 0; i < size1; i++)
      s[i] = ShareMallocM1c(size2);
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ShareMallocM2c>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L25
L7:
  test   %ebp,%ebp
  jle    L41
  test   %r12d,%r12d
  jle    L41
  mov    %r13,%rbx
  lea    0x0(%r13,%r12,8),%r12
  nopl   0x0(%rax)
L2:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <ShareMallocM1c@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L2
L41:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: char ** malloc error!


assistant: ```c
char **ShareMallocM2c(int size1, int size2) {
  int i;
  char **s = NULL;
  if ((s = (char **)calloc(size1, sizeof(char *))) == NULL) {
    printf("char ** malloc error!\n");
    exit(1);
  }
  if (size2 > 0) {
    for (i = 0; i < size1; i++)
      s[i] = ShareMallocM1c(size2);
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  D69(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  D4(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x10(%rbp),%xmm0
  jb     L7
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L21
L7:
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L21:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D30
type: string
name: read_data
arguments: label: D60
type: string
name: read_data
arguments: label: D34
type: string
name: read_data
arguments: label: D69
type: byte[4]
name: read_data
arguments: label: D4
type: byte[4]
name: read_data
arguments: label: D7
type: string

tool: D30: Enter x

tool: D60: x=

tool: D34: %f

tool: {"D69": [0x00,0x00,0x80,0x40]}

tool: {"D4": [0x00,0x00,0xc0,0x40]}

tool: D7: Expression does not make sense

assistant: ```c
main() {
  float x, y, a;
  printf("Enter x\n");
  printf("x=");
  scanf("%f", &x);
  a = 4 * x - 6;
  if (a <= 0)
    printf("Expression does not make sense\n");
  else {
    y = sqrt(a);
    printf("%f", y);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  movss  D60(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  subss  D1(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  jae    L2
  call   <sqrt@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D61(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D62
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D61
datatype: string
name: unpack_data
arguments: data_label: D60
datatype: byte[4]
name: unpack_data
arguments: data_label: D1
datatype: byte[4]
name: unpack_data
arguments: data_label: D8
datatype: string

tool: D62: Enter x

tool: D6: x=

tool: D61: %f

tool: {"D60": [0x00,0x00,0x80,0x40]}

tool: {"D1": [0x00,0x00,0xc0,0x40]}

tool: D8: Expression does not make sense

assistant: ```c
main() {
  float x, y, a;
  printf("Enter x\n");
  printf("x=");
  scanf("%f", &x);
  a = 4 * x - 6;
  if (a <= 0)
    printf("Expression does not make sense\n");
  else {
    y = sqrt(a);
    printf("%f", y);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D25(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  D47(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  subss  D35(%rip),%xmm0
  comiss %xmm0,%xmm1
  jae    L19
  call   <sqrt@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D49
type_guessed: string
name: disassemble_data
arguments: data_tag: D25
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D47
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D35
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D40
type_guessed: string

tool: D49: Enter x

tool: D25: %f

tool: D17: x=

tool: {"D47": [0x00,0x00,0x80,0x40]}

tool: {"D35": [0x00,0x00,0xc0,0x40]}

tool: D40: Expression does not make sense

assistant: ```c
main() {
  float x, y, a;
  printf("Enter x\n");
  printf("x=");
  scanf("%f", &x);
  a = 4 * x - 6;
  if (a <= 0)
    printf("Expression does not make sense\n");
  else {
    y = sqrt(a);
    printf("%f", y);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D9(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  D49(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  subss  D28(%rip),%xmm0
  comiss %xmm0,%xmm1
  jae    L1
  call   <sqrt@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string
name: extract_symbolic_data
arguments: data_label: D51
datatype: string
name: extract_symbolic_data
arguments: data_label: D49
datatype: byte[4]
name: extract_symbolic_data
arguments: data_label: D28
datatype: byte[4]
name: extract_symbolic_data
arguments: data_label: D24
datatype: string

tool: D39: Enter x

tool: D9: %f

tool: D51: x=

tool: {"D49": [0x00,0x00,0x80,0x40]}

tool: {"D28": [0x00,0x00,0xc0,0x40]}

tool: D24: Expression does not make sense

assistant: ```c
main() {
  float x, y, a;
  printf("Enter x\n");
  printf("x=");
  scanf("%f", &x);
  a = 4 * x - 6;
  if (a <= 0)
    printf("Expression does not make sense\n");
  else {
    y = sqrt(a);
    printf("%f", y);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L4
  cmpl   $0x7a,-0x4(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L14
L4:
  mov    -0x4(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 'a' && c <= 'z')
    return (c - ('a' - 'A'));
  return (c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 'a' && c <= 'z')
    return (c - ('a' - 'A'));
  return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 'a' && c <= 'z')
    return (c - ('a' - 'A'));
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 'a' && c <= 'z')
    return (c - ('a' - 'A'));
  return (c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L31
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L35:
  mov    -0x8(%rbp),%rax
  mov    -0x4(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  subq   $0x4,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L2
  mov    -0x8(%rbp),%rax
  sub    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L35
L2:
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L12
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *sort(int *begin, int *end) {
  int x;
  int *i, *j;
  for (i = begin + 1; i < end; i++) {
    x = *i;
    for (j = i; j != begin && *(j - 1) > x; j--) {
      *j = *(j - 1);
    }
    *j = x;
  }
  return begin;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort>:
  endbr64
  lea    0x4(%rdi),%r8
  cmp    %rsi,%r8
  jb     L57
L16:
  mov    %rdi,%rax
  ret
L38:
  mov    %ecx,(%rax)
  add    $0x4,%r8
  cmp    %r8,%rsi
  jbe    L16
L57:
  mov    (%r8),%ecx
  mov    %r8,%rax
  cmp    %r8,%rdi
  je     L38
L7:
  mov    -0x4(%rax),%edx
  cmp    %ecx,%edx
  jle    L38
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rax,%rdi
  jne    L7
  jmp    L38
```

assistant: ```c
int *sort(int *begin, int *end) {
  int x;
  int *i, *j;
  for (i = begin + 1; i < end; i++) {
    x = *i;
    for (j = i; j != begin && *(j - 1) > x; j--) {
      *j = *(j - 1);
    }
    *j = x;
  }
  return begin;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort>:
  endbr64
  mov    %rdi,%r8
  lea    0x4(%rdi),%rdi
  cmp    %rsi,%rdi
  jae    L53
L56:
  mov    (%rdi),%ecx
  mov    %rdi,%rax
  cmp    %rdi,%r8
  jne    L58
  jmp    L29
  nopl   0x0(%rax)
L47:
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rax,%r8
  je     L29
L58:
  mov    -0x4(%rax),%edx
  cmp    %ecx,%edx
  jg     L47
L29:
  add    $0x4,%rdi
  mov    %ecx,(%rax)
  cmp    %rdi,%rsi
  ja     L56
L53:
  mov    %r8,%rax
  ret
```

assistant: ```c
int *sort(int *begin, int *end) {
  int x;
  int *i, *j;
  for (i = begin + 1; i < end; i++) {
    x = *i;
    for (j = i; j != begin && *(j - 1) > x; j--) {
      *j = *(j - 1);
    }
    *j = x;
  }
  return begin;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort>:
  endbr64
  mov    %rdi,%r8
  lea    0x4(%rdi),%rdi
  cmp    %rsi,%rdi
  jae    L30
L17:
  mov    (%rdi),%ecx
  mov    %rdi,%rax
  cmp    %rdi,%r8
  jne    L48
  jmp    L24
  nopl   0x0(%rax)
L14:
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rax,%r8
  je     L24
L48:
  mov    -0x4(%rax),%edx
  cmp    %ecx,%edx
  jg     L14
L24:
  add    $0x4,%rdi
  mov    %ecx,(%rax)
  cmp    %rdi,%rsi
  ja     L17
L30:
  mov    %r8,%rax
  ret
```

assistant: ```c
int *sort(int *begin, int *end) {
  int x;
  int *i, *j;
  for (i = begin + 1; i < end; i++) {
    x = *i;
    for (j = i; j != begin && *(j - 1) > x; j--) {
      *j = *(j - 1);
    }
    *j = x;
  }
  return begin;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prof_effect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L11:
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x26f5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <effective_transpose@plt>
  addl   $0x1,-0x14(%rbp)
L4:
  cmpl   $0x3e7,-0x14(%rbp)
  jle    L11
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void prof_effect(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  for (int c = 0; c < 1000; c++)
    effective_transpose(d, s, 9973);
  free((void *)d);
  free((void *)s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prof_effect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x17b699e4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x3e8,%ebx
L9:
  mov    $0x26f5,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <effective_transpose@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void prof_effect(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  for (int c = 0; c < 1000; c++)
    effective_transpose(d, s, 9973);
  free((void *)d);
  free((void *)s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prof_effect>:
  endbr64
  push   %r12
  mov    $0x17b699e4,%edi
  push   %rbp
  push   %rbx
  mov    $0x3e8,%ebx
  call   <malloc@plt>
  mov    $0x17b699e4,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x26f5,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <effective_transpose@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void prof_effect(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  for (int c = 0; c < 1000; c++)
    effective_transpose(d, s, 9973);
  free((void *)d);
  free((void *)s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prof_effect>:
  endbr64
  push   %r12
  mov    $0x17b699e4,%edi
  push   %rbp
  push   %rbx
  mov    $0x3e8,%ebx
  call   <malloc@plt>
  mov    $0x17b699e4,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x26f5,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <effective_transpose@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <free@plt>
```

assistant: ```c
void prof_effect(void) {
  int *d = (int *)malloc((sizeof(int) * 9973 * 9973));
  int *s = (int *)malloc((sizeof(int) * 9973 * 9973));
  for (int c = 0; c < 1000; c++)
    effective_transpose(d, s, 9973);
  free((void *)d);
  free((void *)s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reorder_rows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L34
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <new_matrix2@plt>
  jmp    L15
L34:
  mov    -0x18(%rbp),%rax
L15:
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L47:
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L47
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L32
  mov    -0x30(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <matrix_copy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_matrix2@plt>
L32:
  nop
  leave
  ret
```

assistant: ```c
void reorder_rows(double **Y, double **X, int *idx, int n, int m) {
  int i;
  double **Y2 = (X == Y ? new_matrix2(n, m) : Y);
  for (i = 0; i < n; i++)
    memcpy(Y2[i], X[idx[i]], m * sizeof(double));
  if (X == Y) {
    matrix_copy(Y, Y2, n, m);
    free_matrix2(Y2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reorder_rows>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  cmp    %rdi,%rsi
  je     L19
  mov    (%rsp),%r13
  cmpl   $0x0,0x8(%rsp)
  jle    L8
L44:
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,8),%r15d
  mov    0x8(%rsp),%r14d
  mov    $0x0,%ebx
L5:
  movslq (%r12,%rbx,4),%rax
  mov    0x0(%rbp,%rax,8),%rsi
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %r15d,%edx
  call   <memcpy@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L5
  cmp    (%rsp),%rbp
  je     L50
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    %r8d,%esi
  mov    %ecx,%ebx
  mov    %ecx,%edi
  call   <new_matrix2@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jg     L44
L50:
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r13,%rsi
  mov    (%rsp),%rdi
  call   <matrix_copy@plt>
  mov    %r13,%rdi
  call   <free_matrix2@plt>
  jmp    L8
```

assistant: ```c
void reorder_rows(double **Y, double **X, int *idx, int n, int m) {
  int i;
  double **Y2 = (X == Y ? new_matrix2(n, m) : Y);
  for (i = 0; i < n; i++)
    memcpy(Y2[i], X[idx[i]], m * sizeof(double));
  if (X == Y) {
    matrix_copy(Y, Y2, n, m);
    free_matrix2(Y2);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reorder_rows>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %ecx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  cmp    %rdi,%rsi
  je     L41
  mov    0x8(%rsp),%eax
  mov    (%rsp),%r15
  test   %eax,%eax
  jle    L32
L29:
  mov    0xc(%rsp),%eax
  movslq 0x8(%rsp),%r12
  xor    %r14d,%r14d
  lea    0x0(,%rax,8),%r13d
  nopw   0x0(%rax,%rax,1)
L18:
  movslq 0x0(%rbp,%r14,4),%rax
  mov    (%r15,%r14,8),%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  mov    (%rbx,%rax,8),%rsi
  call   <memcpy@plt>
  cmp    %r14,%r12
  jne    L18
  cmp    (%rsp),%rbx
  je     L13
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %r8d,%esi
  mov    %ecx,%edi
  mov    %ecx,%r14d
  call   <new_matrix2@plt>
  mov    %rax,%r15
  test   %r14d,%r14d
  jg     L29
L13:
  mov    (%rsp),%rdi
  mov    0xc(%rsp),%ecx
  mov    %r15,%rsi
  mov    0x8(%rsp),%edx
  call   <matrix_copy@plt>
  add    $0x18,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free_matrix2@plt>
```

assistant: ```c
void reorder_rows(double **Y, double **X, int *idx, int n, int m) {
  int i;
  double **Y2 = (X == Y ? new_matrix2(n, m) : Y);
  for (i = 0; i < n; i++)
    memcpy(Y2[i], X[idx[i]], m * sizeof(double));
  if (X == Y) {
    matrix_copy(Y, Y2, n, m);
    free_matrix2(Y2);
  }
}
```