ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x430(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x430(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x420(%rbp)
  mov    -0x430(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x41c(%rbp)
  mov    -0x430(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x420(%rbp),%eax
  imul   -0x41c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x418(%rbp)
  mov    -0x418(%rbp),%rcx
  mov    -0x41c(%rbp),%edx
  mov    -0x420(%rbp),%esi
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <read_data_int@plt>
  mov    -0x418(%rbp),%rcx
  mov    -0x41c(%rbp),%edx
  mov    -0x420(%rbp),%esi
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <write_data_int@plt>
  mov    -0x41c(%rbp),%edx
  mov    -0x420(%rbp),%ecx
  mov    -0x418(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <print_data_int@plt>
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  char output_file1[512];
  int N, M;
  int *data;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  M = (int)atoi(argv[3]);
  strcpy(output_file1, argv[4]);
  data = (int *)malloc(N * M * sizeof(int));
  read_data_int(input_file, N, M, data);
  write_data_int(output_file1, N, M, data);
  print_data_int(data, N, M);
  free(data);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rsi
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    0x10(%r13),%rdi
  call   <atoi@plt>
  mov    %rax,%r15
  mov    0x18(%r13),%rdi
  call   <atoi@plt>
  mov    %rax,%rbx
  mov    %eax,%r12d
  mov    0x20(%r13),%rsi
  lea    0x200(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  imul   %r15d,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <read_data_int@plt>
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <write_data_int@plt>
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <print_data_int@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  char output_file1[512];
  int N, M;
  int *data;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  M = (int)atoi(argv[3]);
  strcpy(output_file1, argv[4]);
  data = (int *)malloc(N * M * sizeof(int));
  read_data_int(input_file, N, M, data);
  write_data_int(output_file1, N, M, data);
  print_data_int(data, N, M);
  free(data);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbp),%rdi
  call   <atoi@plt>
  mov    0x18(%rbp),%rdi
  mov    %rax,%r12
  call   <atoi@plt>
  lea    0x210(%rsp),%r8
  mov    0x20(%rbp),%rsi
  mov    %rax,%rbx
  mov    %r8,%rdi
  mov    %r8,0x8(%rsp)
  mov    %eax,%r15d
  call   <strcpy@plt>
  imul   %r12d,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <read_data_int@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <write_data_int@plt>
  mov    %rbp,%rdi
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <print_data_int@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  char output_file1[512];
  int N, M;
  int *data;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  M = (int)atoi(argv[3]);
  strcpy(output_file1, argv[4]);
  data = (int *)malloc(N * M * sizeof(int));
  read_data_int(input_file, N, M, data);
  write_data_int(output_file1, N, M, data);
  print_data_int(data, N, M);
  free(data);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbp),%rdi
  call   <atoi@plt>
  mov    0x18(%rbp),%rdi
  mov    %rax,%r12
  call   <atoi@plt>
  lea    0x210(%rsp),%r8
  mov    0x20(%rbp),%rsi
  mov    %rax,%rbx
  mov    %r8,%rdi
  mov    %r8,0x8(%rsp)
  mov    %eax,%r15d
  call   <strcpy@plt>
  imul   %r12d,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <read_data_int@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <write_data_int@plt>
  mov    %rbp,%rdi
  mov    %r15d,%edx
  mov    %r12d,%esi
  call   <print_data_int@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  char output_file1[512];
  int N, M;
  int *data;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  M = (int)atoi(argv[3]);
  strcpy(output_file1, argv[4]);
  data = (int *)malloc(N * M * sizeof(int));
  read_data_int(input_file, N, M, data);
  write_data_int(output_file1, N, M, data);
  print_data_int(data, N, M);
  free(data);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffi_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jbe    L3
  mov    $0xffffffff,%edi
  call   <exit@plt>
L3:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int ffi_send(unsigned int sock, unsigned int n, char *buffer) {
  ssize_t ret;
  ret = send(sock, buffer, n, 0);
  if (ret < 0 || ret > n) {
    exit(-1);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ffi_send>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  mov    $0x0,%ecx
  mov    %ebp,%edx
  call   <send@plt>
  mov    %eax,%ebx
  cmp    %eax,%ebp
  jb     L15
L12:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L12
```

assistant: ```c
unsigned int ffi_send(unsigned int sock, unsigned int n, char *buffer) {
  ssize_t ret;
  ret = send(sock, buffer, n, 0);
  if (ret < 0 || ret > n) {
    exit(-1);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ffi_send>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <send@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jb     L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int ffi_send(unsigned int sock, unsigned int n, char *buffer) {
  ssize_t ret;
  ret = send(sock, buffer, n, 0);
  if (ret < 0 || ret > n) {
    exit(-1);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ffi_send>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  mov    %ebx,%edx
  sub    $0x8,%rsp
  call   <send@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jb     L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int ffi_send(unsigned int sock, unsigned int n, char *buffer) {
  ssize_t ret;
  ret = send(sock, buffer, n, 0);
  if (ret < 0 || ret > n) {
    exit(-1);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<serverRunning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getMutex@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L31
L24:
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x11c(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L42
  mov    $0x0,%eax
  jmp    L31
L42:
  mov    -0x118(%rbp),%rax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: /proc/%d

assistant: ```c
pid_t serverRunning() {
  char procPath[256];
  struct stat st;
  pid_t serverPid = getMutex();
  if (serverPid == 0) {
    return 0;
  }
  snprintf(procPath, sizeof(procPath), "/proc/%d", serverPid);
  if (stat(procPath, &st)) {
    return 0;
  }
  return serverPid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serverRunning>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <getMutex@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L10
L19:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rbx,%rax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    0x10(%rsp),%rbp
  mov    %rax,%rcx
  lea    D8(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%rbx
  jmp    L19
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: /proc/%d

assistant: ```c
pid_t serverRunning() {
  char procPath[256];
  struct stat st;
  pid_t serverPid = getMutex();
  if (serverPid == 0) {
    return 0;
  }
  snprintf(procPath, sizeof(procPath), "/proc/%d", serverPid);
  if (stat(procPath, &st)) {
    return 0;
  }
  return serverPid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serverRunning>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <getMutex@plt>
  test   %rax,%rax
  jne    L3
L37:
  xor    %r12d,%r12d
L2:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x128,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L3:
  lea    0x10(%rsp),%rbp
  mov    $0x100,%esi
  mov    %rax,%rcx
  mov    %rax,%r12
  mov    %rbp,%rdi
  lea    D3(%rip),%rdx
  call   <snprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L2
  jmp    L37
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: /proc/%d

assistant: ```c
pid_t serverRunning() {
  char procPath[256];
  struct stat st;
  pid_t serverPid = getMutex();
  if (serverPid == 0) {
    return 0;
  }
  snprintf(procPath, sizeof(procPath), "/proc/%d", serverPid);
  if (stat(procPath, &st)) {
    return 0;
  }
  return serverPid;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<serverRunning>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <getMutex@plt>
  test   %rax,%rax
  jne    L20
L9:
  xor    %r12d,%r12d
L5:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x128,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L20:
  lea    0x10(%rsp),%rbp
  mov    $0x100,%esi
  mov    %rax,%rcx
  mov    %rax,%r12
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L5
  jmp    L9
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: /proc/%d

assistant: ```c
pid_t serverRunning() {
  char procPath[256];
  struct stat st;
  pid_t serverPid = getMutex();
  if (serverPid == 0) {
    return 0;
  }
  snprintf(procPath, sizeof(procPath), "/proc/%d", serverPid);
  if (stat(procPath, &st)) {
    return 0;
  }
  return serverPid;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L59
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L14
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L14
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  addq   $0x4,-0x18(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L45
L14:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L45:
  addl   $0x1,-0x1c(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: %2x

assistant: ```c
int unescape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<unescape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  je     L24
  mov    %rsi,%rbp
  add    $0x1,%rdi
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r14
  lea    D6(%rip),%r13
  mov    $0x1,%r12d
  sub    %edi,%r12d
  jmp    L4
L11:
  add    $0x1,%rbp
L40:
  mov    %al,-0x1(%rbx)
  lea    (%r12,%rbx,1),%edx
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L27
L4:
  cmp    $0x5c,%al
  jne    L11
  cmpb   $0x78,0x1(%rbp)
  jne    L11
  lea    0x2(%rbp),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <sscanf@plt>
  add    $0x4,%rbp
  movzbl 0x4(%rsp),%eax
  jmp    L40
L24:
  mov    $0x0,%edx
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: %2x

assistant: ```c
int unescape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<unescape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  je     L54
  mov    $0x1,%r12d
  mov    %rsi,%rbp
  lea    0x4(%rsp),%r14
  mov    %rdi,%rbx
  lea    D4(%rip),%r13
  sub    %edi,%r12d
  jmp    L46
  nopl   0x0(%rax)
L52:
  add    $0x1,%rbp
L28:
  mov    %al,(%rbx)
  movzbl 0x0(%rbp),%eax
  lea    (%r12,%rbx,1),%r8d
  add    $0x1,%rbx
  test   %al,%al
  je     L42
L46:
  cmp    $0x5c,%al
  jne    L52
  cmpb   $0x78,0x1(%rbp)
  jne    L52
  lea    0x2(%rbp),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  add    $0x4,%rbp
  call   <sscanf@plt>
  movzbl 0x4(%rsp),%eax
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: %2x

assistant: ```c
int unescape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unescape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  je     L31
  mov    $0x1,%r12d
  mov    %rsi,%rbp
  lea    0x4(%rsp),%r14
  mov    %rdi,%rbx
  lea    D4(%rip),%r13
  sub    %edi,%r12d
  jmp    L64
  nopl   0x0(%rax)
L34:
  add    $0x1,%rbp
L8:
  mov    %al,(%rbx)
  movzbl 0x0(%rbp),%eax
  lea    (%r12,%rbx,1),%r8d
  add    $0x1,%rbx
  test   %al,%al
  je     L5
L64:
  cmp    $0x5c,%al
  jne    L34
  cmpb   $0x78,0x1(%rbp)
  jne    L34
  lea    0x2(%rbp),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  add    $0x4,%rbp
  call   <sscanf@plt>
  movzbl 0x4(%rsp),%eax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %2x

assistant: ```c
int unescape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<gbk_wctomb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x30fb,-0x1c(%rbp)
  je     L96
  cmpl   $0x2015,-0x1c(%rbp)
  je     L96
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <gb2312_wctomb_zint@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L96
  mov    -0x4(%rbp),%eax
  jmp    L79
L96:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <gbkext_inv_wctomb@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  mov    -0x4(%rbp),%eax
  jmp    L79
L11:
  cmpl   $0x216f,-0x1c(%rbp)
  jbe    L99
  cmpl   $0x2179,-0x1c(%rbp)
  ja     L99
  mov    -0x1c(%rbp),%eax
  lea    0x8131(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x2,%eax
  jmp    L79
L99:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cp936ext_wctomb@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L37
  mov    -0x4(%rbp),%eax
  jmp    L79
L37:
  mov    $0x0,%eax
L79:
  leave
  ret
```

assistant: ```c
int gbk_wctomb(unsigned int *r, const unsigned int wc) {
  int ret;
  if (wc != 0x30fb && wc != 0x2015) {
    ret = gb2312_wctomb_zint(r, wc);
    if (ret) {
      return ret;
    }
  }
  ret = gbkext_inv_wctomb(r, wc);
  if (ret) {
    return ret;
  }
  if (wc >= 0x2170 && wc <= 0x2179) {
    *r = 0xa2a1 + (wc - 0x2170);
    return 2;
  }
  ret = cp936ext_wctomb(r, wc);
  if (ret) {
    return ret;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gbk_wctomb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  cmp    $0x30fb,%esi
  je     L47
  cmp    $0x2015,%esi
  je     L47
  call   <gb2312_wctomb_zint@plt>
  test   %eax,%eax
  jne    L4
L47:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <gbkext_inv_wctomb@plt>
  test   %eax,%eax
  jne    L4
  lea    -0x2170(%rbx),%eax
  cmp    $0x9,%eax
  jbe    L8
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <cp936ext_wctomb@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  add    $0x8131,%ebx
  mov    %ebx,0x0(%rbp)
  mov    $0x2,%eax
  jmp    L4
```

assistant: ```c
int gbk_wctomb(unsigned int *r, const unsigned int wc) {
  int ret;
  if (wc != 0x30fb && wc != 0x2015) {
    ret = gb2312_wctomb_zint(r, wc);
    if (ret) {
      return ret;
    }
  }
  ret = gbkext_inv_wctomb(r, wc);
  if (ret) {
    return ret;
  }
  if (wc >= 0x2170 && wc <= 0x2179) {
    *r = 0xa2a1 + (wc - 0x2170);
    return 2;
  }
  ret = cp936ext_wctomb(r, wc);
  if (ret) {
    return ret;
  }
  return 0;
}
```