user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_dynmem>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  lea    D36(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x40,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <dynmem_free@plt>
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x64,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <dynmem_free@plt>
  mov    %rbx,%rdi
  call   <dynmem_free@plt>
  mov    $0xf8,%edi
  call   <dynmem_alloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <dynmem_free@plt>
L0:
  mov    $0x3c,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbp
  mov    $0x3c,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbx
  mov    $0x3c,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <dynmem_free@plt>
  mov    $0x48,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rbx
  mov    $0x82,%edi
  call   <dynmem_alloc@plt>
  mov    %rax,%rdi
  call   <dynmem_free@plt>
  mov    %r12,%rdi
  call   <dynmem_free@plt>
  mov    %rbp,%rdi
  call   <dynmem_free@plt>
  mov    %rbx,%rdi
  call   <dynmem_free@plt>
  mov    $0x0,%eax
  call   <dynmem_avail@plt>
  mov    %eax,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D34
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D36: [ free mem: %i ]


tool: D0: 11111111

tool: D34: 2222222222222

tool: D14: 333

tool: D9: success

assistant: ```c
void test_dynmem(void) {
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
  char *test1 = dynmem_alloc(64);
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
  char *test2 = dynmem_alloc(64);
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
  strcpy(test1, "11111111");
  strcpy(test2, "2222222222222");
  puts(test1);
  puts(test2);
  dynmem_free(test1);
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
  char *test3 = dynmem_alloc(100);
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
  strcpy(test3, "333");
  puts(test2);
  puts(test3);
  dynmem_free(test3);
  dynmem_free(test2);
  if ((test1 = dynmem_alloc(248))) {
    puts("success");
    dynmem_free(test1);
  }
  test1 = dynmem_alloc(60);
  test2 = dynmem_alloc(60);
  test3 = dynmem_alloc(60);
  dynmem_free(test2);
  test2 = dynmem_alloc(72);
  dynmem_free(dynmem_alloc(130));
  dynmem_free(test3);
  dynmem_free(test1);
  dynmem_free(test2);
  printf("[ free mem: %i ]\n", (int)dynmem_avail());
}
```