ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_ori_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <cmp_ori_deinit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free_or_die@plt>
```

assistant: ```c
void cmp_ori_free(struct CmpOri *cmp_ori) {
  cmp_ori_deinit(cmp_ori);
  free_or_die(cmp_ori);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x20(%rbp)
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L36
L44:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L36:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L44
  movl   $0x0,-0x18(%rbp)
L55:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    -0x28(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L14
  subl   $0x3,-0x20(%rbp)
  jmp    L69
L14:
  subl   $0x1,-0x20(%rbp)
L69:
  cmpl   $0x0,-0x14(%rbp)
  je     L18
  jmp    L55
L18:
  nop
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D25: %d %d

tool: D5: %d

assistant: ```c
int main() {
  int n;
  int k;
  int e = 100;
  scanf("%d %d", &n, &k);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  int i = 0;
  while (1) {
    int p = (i + k) % n;
    i = p;
    if (c[p] == 1) {
      e -= 3;
    } else {
      e--;
    }
    if (p == 0) {
      break;
    }
  }
  printf("%d", e);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  jle    L23
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D8(%rip),%r13
L51:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    (%rsp),%ecx
  add    $0x4,%r12
  cmp    %ebp,%ecx
  jg     L51
L23:
  mov    0x4(%rsp),%r8d
  mov    $0x0,%eax
  mov    $0x64,%esi
  jmp    L60
L25:
  sub    $0x1,%esi
L34:
  test   %edx,%edx
  je     L41
L60:
  add    %r8d,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  movslq %edx,%rdi
  cmpl   $0x1,(%rbx,%rdi,4)
  jne    L25
  sub    $0x3,%esi
  jmp    L34
L41:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D11: %d %d

tool: D8: %d

assistant: ```c
int main() {
  int n;
  int k;
  int e = 100;
  scanf("%d %d", &n, &k);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  int i = 0;
  while (1) {
    int p = (i + k) % n;
    i = p;
    if (c[p] == 1) {
      e -= 3;
    } else {
      e--;
    }
    if (p == 0) {
      break;
    }
  }
  printf("%d", e);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%ecx
  mov    %rax,%rbx
  test   %ecx,%ecx
  jle    L59
  mov    %rax,%r12
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    (%rsp),%ecx
  add    $0x4,%r12
  cmp    %ebp,%ecx
  jg     L35
L59:
  mov    0x4(%rsp),%r8d
  xor    %eax,%eax
  mov    $0x64,%esi
  jmp    L13
  nopl   0x0(%rax)
L37:
  sub    $0x1,%esi
  test   %edx,%edx
  je     L36
L13:
  add    %r8d,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdi
  cmpl   $0x1,(%rbx,%rdi,4)
  mov    %rdi,%rax
  jne    L37
  sub    $0x3,%esi
  test   %edx,%edx
  jne    L13
L36:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D7: %d %d

tool: D2: %d

assistant: ```c
int main() {
  int n;
  int k;
  int e = 100;
  scanf("%d %d", &n, &k);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  int i = 0;
  while (1) {
    int p = (i + k) % n;
    i = p;
    if (c[p] == 1) {
      e -= 3;
    } else {
      e--;
    }
    if (p == 0) {
      break;
    }
  }
  printf("%d", e);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%ecx
  mov    %rax,%rbx
  test   %ecx,%ecx
  jle    L27
  mov    %rax,%r12
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    (%rsp),%ecx
  add    $0x4,%r12
  cmp    %ebp,%ecx
  jg     L46
L27:
  mov    0x4(%rsp),%r8d
  xor    %eax,%eax
  mov    $0x64,%esi
  jmp    L68
  nopl   0x0(%rax)
L57:
  sub    $0x1,%esi
  test   %edx,%edx
  je     L51
L68:
  add    %r8d,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdi
  cmpl   $0x1,(%rbx,%rdi,4)
  mov    %rdi,%rax
  jne    L57
  sub    $0x3,%esi
  test   %edx,%edx
  jne    L68
L51:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D9: %d %d

tool: D8: %d

assistant: ```c
int main() {
  int n;
  int k;
  int e = 100;
  scanf("%d %d", &n, &k);
  int *c = malloc(sizeof(int) * n);
  for (int c_i = 0; c_i < n; c_i++) {
    scanf("%d", &c[c_i]);
  }
  int i = 0;
  while (1) {
    int p = (i + k) % n;
    i = p;
    if (c[p] == 1) {
      e -= 3;
    } else {
      e--;
    }
    if (p == 0) {
      break;
    }
  }
  printf("%d", e);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_iswritepg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0x400,%eax
  je     L9
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_isfatal_error@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: write failed

assistant: ```c
void _iswritepg(fd, buf) int fd;
char *buf;
{
  if (write(fd, buf, 1024) != 1024)
    _isfatal_error("write failed");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_iswritepg>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edx
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0x400,%eax
  jne    L14
L11:
  add    $0x8,%rsp
  ret
L14:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <_isfatal_error@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: write failed

assistant: ```c
void _iswritepg(fd, buf) int fd;
char *buf;
{
  if (write(fd, buf, 1024) != 1024)
    _isfatal_error("write failed");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_iswritepg>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  mov    $0x400,%edx
  call   <write@plt>
  cmp    $0x400,%eax
  jne    L6
  add    $0x8,%rsp
  ret
L6:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <_isfatal_error@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: write failed

assistant: ```c
void _iswritepg(fd, buf) int fd;
char *buf;
{
  if (write(fd, buf, 1024) != 1024)
    _isfatal_error("write failed");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_iswritepg>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  mov    $0x400,%edx
  call   <write@plt>
  cmp    $0x400,%eax
  jne    L3
  add    $0x8,%rsp
  ret
L3:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <_isfatal_error@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D9: write failed

assistant: ```c
void _iswritepg(fd, buf) int fd;
char *buf;
{
  if (write(fd, buf, 1024) != 1024)
    _isfatal_error("write failed");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_charmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L42
L36:
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L42
L12:
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L21:
  mov    -0x28(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    -0x10(%rbp),%rax
L42:
  leave
  ret
```

assistant: ```c
char **alloc_charmatrix(int cols, int rows) {
  int i;
  char **m;
  if ((m = (char **)malloc(cols * sizeof(char *))) == NULL) {
    return NULL;
  }
  char *els = (char *)malloc(rows * cols * sizeof(char));
  if (els == NULL) {
    return NULL;
  }
  for (i = 0; i < cols; i++) {
    m[i] = &els[rows * i];
  }
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alloc_charmatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    $0x0,%edi
  test   %rax,%rax
  je     L18
  mov    %rax,%rbp
  mov    %ebx,%edi
  imul   %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdi
  test   %ebx,%ebx
  jle    L18
  movslq %r12d,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,8),%rsi
L35:
  mov    %rax,(%rdx)
  add    %rcx,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L35
L18:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x0,%edi
  jmp    L18
```

assistant: ```c
char **alloc_charmatrix(int cols, int rows) {
  int i;
  char **m;
  if ((m = (char **)malloc(cols * sizeof(char *))) == NULL) {
    return NULL;
  }
  char *els = (char *)malloc(rows * cols * sizeof(char));
  if (els == NULL) {
    return NULL;
  }
  for (i = 0; i < cols; i++) {
    m[i] = &els[rows * i];
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_charmatrix>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L26
  mov    %r12d,%edi
  mov    %rax,%rbx
  imul   %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L26
  mov    %rbx,%rax
  test   %r12d,%r12d
  jle    L38
  movslq %ebp,%rsi
  mov    %rbx,%rdx
  lea    (%rbx,%r12,8),%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  add    %rsi,%rcx
  cmp    %rdi,%rdx
  jne    L2
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **alloc_charmatrix(int cols, int rows) {
  int i;
  char **m;
  if ((m = (char **)malloc(cols * sizeof(char *))) == NULL) {
    return NULL;
  }
  char *els = (char *)malloc(rows * cols * sizeof(char));
  if (els == NULL) {
    return NULL;
  }
  for (i = 0; i < cols; i++) {
    m[i] = &els[rows * i];
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_charmatrix>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x3,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L69
  mov    %ebx,%edi
  mov    %rax,%rbp
  imul   %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L69
  mov    %rbp,%r8
  test   %ebx,%ebx
  jle    L44
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L63
  movd   %r12d,%xmm5
  mov    %ebx,%edx
  movq   %rcx,%xmm3
  mov    %rbp,%rax
  pshufd $0x0,%xmm5,%xmm4
  shr    $0x2,%edx
  punpcklqdq %xmm3,%xmm3
  movdqa D16(%rip),%xmm2
  shl    $0x5,%rdx
  movdqa %xmm4,%xmm6
  movdqa D12(%rip),%xmm7
  pxor   %xmm5,%xmm5
  add    %rbp,%rdx
  psrlq  $0x20,%xmm6
  xchg   %ax,%ax
L3:
  movdqa %xmm2,%xmm1
  movdqa %xmm5,%xmm8
  paddd  %xmm7,%xmm2
  add    $0x20,%rax
  movdqa %xmm1,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm4,%xmm0
  pmuludq %xmm6,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  pcmpgtd %xmm0,%xmm8
  movdqa %xmm0,%xmm1
  punpckldq %xmm8,%xmm1
  punpckhdq %xmm8,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm1,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L3
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L44
L7:
  mov    %r12d,%edx
  movslq %eax,%r9
  imul   %eax,%edx
  lea    0x0(,%r9,8),%rdi
  movslq %edx,%rsi
  add    %rcx,%rsi
  mov    %rsi,0x0(%rbp,%r9,8)
  lea    0x1(%rax),%esi
  cmp    %esi,%ebx
  jle    L44
  add    %r12d,%edx
  add    $0x2,%eax
  movslq %edx,%rsi
  add    %rcx,%rsi
  mov    %rsi,0x8(%rbp,%rdi,1)
  cmp    %eax,%ebx
  jle    L44
  add    %edx,%r12d
  movslq %r12d,%r12
  add    %r12,%rcx
  mov    %rcx,0x10(%rbp,%rdi,1)
L44:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L69:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
L63:
  xor    %eax,%eax
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: byte[16]
name: parse_data
arguments: data_label: D12
type_infered: byte[16]

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
char **alloc_charmatrix(int cols, int rows) {
  int i;
  char **m;
  if ((m = (char **)malloc(cols * sizeof(char *))) == NULL) {
    return NULL;
  }
  char *els = (char *)malloc(rows * cols * sizeof(char));
  if (els == NULL) {
    return NULL;
  }
  for (i = 0; i < cols; i++) {
    m[i] = &els[rows * i];
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L29
L9:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  imul   %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L29:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L9
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D37
datatype: string

tool: D17: %d

tool: D37: %.0f


assistant: ```c
int main() {
  int n, m, k, q, i = 0;
  float sum = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  while (i < n) {
    q = i / k * (2 * m / 100);
    sum = sum + (m - q);
    i++;
  }
  printf("%.0f\n", sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L3
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%r8d
  movslq %r8d,%rdi
  imul   $0x51eb851f,%rdi,%rdi
  sar    $0x24,%rdi
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  pxor   %xmm0,%xmm0
  mov    $0x0,%ecx
L33:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  imul   %edi,%eax
  mov    %r8d,%edx
  sub    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  add    $0x1,%ecx
  cmp    %r9d,%ecx
  jne    L33
L14:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  pxor   %xmm0,%xmm0
  jmp    L14
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D19: %d

tool: D15: %.0f


assistant: ```c
int main() {
  int n, m, k, q, i = 0;
  float sum = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  while (i < n) {
    q = i / k * (2 * m / 100);
    sum = sum + (m - q);
    i++;
  }
  printf("%.0f\n", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L24
  movslq 0x10(%rsp),%rdi
  mov    0x14(%rsp),%esi
  pxor   %xmm0,%xmm0
  xor    %ecx,%ecx
  mov    %rdi,%r8
  imul   $0x51eb851f,%rdi,%rdi
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%rdi
  sub    %eax,%edi
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ecx,%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%ecx
  cltd
  idiv   %esi
  mov    %r8d,%edx
  imul   %edi,%eax
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  cmp    %r9d,%ecx
  jne    L2
L15:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  pxor   %xmm0,%xmm0
  jmp    L15
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D17
data_type: string

tool: D4: %d

tool: D17: %.0f


assistant: ```c
int main() {
  int n, m, k, q, i = 0;
  float sum = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  while (i < n) {
    q = i / k * (2 * m / 100);
    sum = sum + (m - q);
    i++;
  }
  printf("%.0f\n", sum);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L35
  movslq 0x10(%rsp),%rdi
  mov    0x14(%rsp),%esi
  pxor   %xmm0,%xmm0
  xor    %ecx,%ecx
  mov    %rdi,%r8
  imul   $0x51eb851f,%rdi,%rdi
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%rdi
  sub    %eax,%edi
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %ecx,%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%ecx
  cltd
  idiv   %esi
  mov    %r8d,%edx
  imul   %edi,%eax
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  cmp    %r9d,%ecx
  jne    L19
L29:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L35:
  pxor   %xmm0,%xmm0
  jmp    L29
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D10: %d

tool: D17: %.0f


assistant: ```c
int main() {
  int n, m, k, q, i = 0;
  float sum = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  while (i < n) {
    q = i / k * (2 * m / 100);
    sum = sum + (m - q);
    i++;
  }
  printf("%.0f\n", sum);
}
```