user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Max_Subsequence_Sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,-0x4c(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L163
L79:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L79
L163:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L78
L104:
  lea    0x3(%rsp),%rcx
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rcx
  shr    $0x2,%rax
  mov    %rcx,%rbx
  mov    %rax,-0x58(%rbp)
  mov    -0x4c(%rbp),%eax
  lea    -0x1(%rax),%r12d
  test   %eax,%eax
  jle    L160
  mov    %eax,%r9d
  xor    %edx,%edx
  xor    %eax,%eax
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L1:
  add    (%rdi,%rdx,4),%eax
  mov    $0x0,%esi
  cmovs  %esi,%eax
  cmp    %eax,%r15d
  mov    %eax,(%rbx,%rdx,4)
  cmovl  %eax,%r15d
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L1
  lea    (%rbx,%rdx,4),%rax
  mov    %rbx,%r13
  lea    D33(%rip),%r14
  mov    %rax,-0x48(%rbp)
  nopl   0x0(%rax,%rax,1)
L68:
  mov    0x0(%r13),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    -0x48(%rbp),%r13
  jne    L68
  mov    %r15d,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %r12d,%rax
  cmp    %r15d,(%rbx,%rax,4)
  je     L40
L169:
  mov    -0x4c(%rbp),%r13d
  sub    $0x2,%r13d
  movslq %r13d,%r13
  nopl   (%rax)
L149:
  mov    %r13d,%r12d
  sub    $0x1,%r13
  cmp    %r15d,0x4(%rbx,%r13,4)
  jne    L149
  test   %r12d,%r12d
  js     L89
  movslq %r12d,%rax
L40:
  mov    %r12d,%esi
  mov    %rax,%rdx
  sub    %rsi,%rdx
  jmp    L75
  nopl   0x0(%rax)
L54:
  cmp    %rax,%rdx
  je     L87
  sub    $0x1,%rax
L75:
  mov    (%rbx,%rax,4),%ecx
  mov    %eax,%esi
  test   %ecx,%ecx
  jne    L54
  add    $0x1,%esi
L123:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L167
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L87:
  mov    -0x58(%rbp),%rax
  mov    0x0(,%rax,4),%r15d
L89:
  xor    %esi,%esi
  test   %r15d,%r15d
  sete   %sil
  jmp    L123
  nopw   0x0(%rax,%rax,1)
L78:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L104
L160:
  xor    %esi,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  movslq %r12d,%rax
  mov    (%rbx,%rax,4),%edx
  test   %edx,%edx
  jne    L169
  mov    $0x1,%esi
  test   %r12d,%r12d
  jns    L40
  jmp    L123
L167:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D33
type: string
name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D9
type: string

tool: D33: %d   

tool: D14: 
Max Subsequence Sum Is: %d


tool: D9: 
Left Is: %d 
 Right Is: %d 


assistant: ```c
void Max_Subsequence_Sum(int arr[], int length) {
  int i;
  int left = 0;
  int right = 0;
  int maxsofar = 0;
  int maxendinghere = 0;
  int maxsumhere[length];
  for (i = 0; i < length; i++) {
    maxendinghere = maxendinghere + arr[i] > 0 ? maxendinghere + arr[i] : 0;
    maxsumhere[i] = maxendinghere;
    maxsofar = maxsofar > maxendinghere ? maxsofar : maxendinghere;
  }
  for (i = 0; i < length; i++)
    printf("%d   ", maxsumhere[i]);
  printf("\nMax Subsequence Sum Is: %d\n", maxsofar);
  i = length - 1;
  while (maxsumhere[i] != maxsofar)
    i--;
  right = i;
  for (i; i >= 0; i--) {
    if (maxsumhere[i] == 0 || i == 0) {
      left = i;
      break;
    }
  }
  if (maxsumhere[i] == 0)
    left++;
  printf("\nLeft Is: %d \n Right Is: %d \n", left, right);
}
```