ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findNthFirstIndexOfWord>:
  endbr64
  test   %rdi,%rdi
  je     L78
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%rbx
  mov    %edx,%r13d
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  test   %r12d,%r12d
  jle    L27
  movslq %r12d,%r8
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %r10d,%r10d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L27
L5:
  movslq %esi,%rdi
  mov    %ecx,%r9d
  add    $0x1,%esi
  movzbl 0x0(%rbp,%rdi,1),%edx
  cmp    %dl,(%rbx,%rcx,1)
  je     L35
  xor    %esi,%esi
L35:
  cmp    %eax,%esi
  jne    L42
  cmp    %r10d,%r13d
  je     L57
  add    $0x1,%rcx
  add    $0x1,%r10d
  xor    %esi,%esi
  cmp    %r8,%rcx
  jne    L5
L27:
  mov    $0xffffffff,%eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L78:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x8,%rsp
  lea    0x1(%r9),%eax
  pop    %rbx
  sub    %esi,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findNthFirstIndexOfWord(const char *buff, const char *word, int indexN) {
  int count = 0;
  int index = 0;
  int wordLength = 0;
  int buffLength = 0;
  int index2 = 0;
  if (buff == NULL || word == NULL) {
    return 0;
  } else {
  }
  buffLength = strlen(buff);
  wordLength = strlen(word);
  for (index = 0; index < buffLength; index++) {
    if (buff[index] == word[index2]) {
      index2++;
    } else {
      index2 = 0;
    }
    if (index2 == wordLength) {
      if (count == indexN) {
        return 1 + index - wordLength;
      } else {
        count++;
        index2 = 0;
      }
    } else {
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findNthFirstIndexOfWord>:
  endbr64
  test   %rdi,%rdi
  je     L32
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L70
  mov    %rdi,%rbx
  mov    %edx,%r13d
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  test   %r12d,%r12d
  jle    L59
  movslq %r12d,%r8
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %r10d,%r10d
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rcx
  cmp    %rcx,%r8
  je     L59
L69:
  movslq %esi,%rdi
  mov    %ecx,%r9d
  add    $0x1,%esi
  movzbl 0x0(%rbp,%rdi,1),%edx
  cmp    %dl,(%rbx,%rcx,1)
  je     L27
  xor    %esi,%esi
L27:
  cmp    %eax,%esi
  jne    L1
  cmp    %r10d,%r13d
  je     L84
  add    $0x1,%rcx
  add    $0x1,%r10d
  xor    %esi,%esi
  cmp    %rcx,%r8
  jne    L69
L59:
  mov    $0xffffffff,%eax
L70:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L84:
  add    $0x8,%rsp
  lea    0x1(%r9),%eax
  pop    %rbx
  sub    %esi,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findNthFirstIndexOfWord(const char *buff, const char *word, int indexN) {
  int count = 0;
  int index = 0;
  int wordLength = 0;
  int buffLength = 0;
  int index2 = 0;
  if (buff == NULL || word == NULL) {
    return 0;
  } else {
  }
  buffLength = strlen(buff);
  wordLength = strlen(word);
  for (index = 0; index < buffLength; index++) {
    if (buff[index] == word[index2]) {
      index2++;
    } else {
      index2 = 0;
    }
    if (index2 == wordLength) {
      if (count == indexN) {
        return 1 + index - wordLength;
      } else {
        count++;
        index2 = 0;
      }
    } else {
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RtoF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: f64

tool: D3: 459.69

assistant: ```c
double RtoF(double R) {
  double f = R - 459.69;
  return f;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RtoF>:
  endbr64
  subsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: f64

tool: D0: 459.69

assistant: ```c
double RtoF(double R) {
  double f = R - 459.69;
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RtoF>:
  endbr64
  subsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: f64

tool: D4: 459.69

assistant: ```c
double RtoF(double R) {
  double f = R - 459.69;
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RtoF>:
  endbr64
  subsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: f64

tool: D7: 459.69

assistant: ```c
double RtoF(double R) {
  double f = R - 459.69;
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exact_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L42
L54:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L3
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L3:
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L54
L4:
  cmpl   $0x1,-0x4(%rbp)
  jne    L13
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  cmpl   $0x0,-0x4(%rbp)
  jne    L24
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D13: 
 1

tool: D25: 
 %d=%d^2

tool: D32: 
 0

tool: D14: 
 This number does not have an exact root

assistant: ```c
void exact_square(int n) {
  int i = 0, result = 0;
  for (i = 0; i < n; i++) {
    if (i * i == n) {
      result = 1;
      break;
    }
  }
  if (result == 1) {
    printf("\n 1");
    printf("\n %d=%d^2", n, i);
  }
  if (result == 0) {
    printf("\n 0");
    printf("\n This number does not have an exact root");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<exact_square>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
  test   %edi,%edi
  jle    L21
L23:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L21
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %ebp,%eax
  jne    L23
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L21:
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
data_type: string
name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D5
data_type: string

tool: D18: 
 1

tool: D12: 
 %d=%d^2

tool: D11: 
 0

tool: D5: 
 This number does not have an exact root

assistant: ```c
void exact_square(int n) {
  int i = 0, result = 0;
  for (i = 0; i < n; i++) {
    if (i * i == n) {
      result = 1;
      break;
    }
  }
  if (result == 1) {
    printf("\n 1");
    printf("\n %d=%d^2", n, i);
  }
  if (result == 0) {
    printf("\n 0");
    printf("\n This number does not have an exact root");
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exact_square>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edi,%edi
  jg     L39
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r12d,%eax
  imul   %r12d,%eax
  cmp    %ebp,%eax
  je     L17
L39:
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jne    L8
L38:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L46:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L17:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L46
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D7: 
 0

tool: D31: 
 This number does not have an exact root

tool: D23: 
 1

tool: D1: 
 %d=%d^2

assistant: ```c
void exact_square(int n) {
  int i = 0, result = 0;
  for (i = 0; i < n; i++) {
    if (i * i == n) {
      result = 1;
      break;
    }
  }
  if (result == 1) {
    printf("\n 1");
    printf("\n %d=%d^2", n, i);
  }
  if (result == 0) {
    printf("\n 0");
    printf("\n This number does not have an exact root");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exact_square>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edi,%edi
  jg     L19
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %r12d,%eax
  imul   %r12d,%eax
  cmp    %ebp,%eax
  je     L43
L19:
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jne    L46
L47:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L10:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L43:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D31
datatype: string

tool: D18: 
 0

tool: D2: 
 This number does not have an exact root

tool: D10: 
 1

tool: D31: 
 %d=%d^2

assistant: ```c
void exact_square(int n) {
  int i = 0, result = 0;
  for (i = 0; i < n; i++) {
    if (i * i == n) {
      result = 1;
      break;
    }
  }
  if (result == 1) {
    printf("\n 1");
    printf("\n %d=%d^2", n, i);
  }
  if (result == 0) {
    printf("\n 0");
    printf("\n This number does not have an exact root");
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show_oemsdr_hp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x5,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  cmp    $0x2,%al
  jne    L20
  movl   $0x12,-0x8(%rbp)
L20:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x8,-0x4(%rbp)
  jmp    L22
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L33
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  cmp    $0x2,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  add    $0x12,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L29:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D25: HP: 

tool: D3: %02x 

tool: D19: %s

assistant: ```c
void show_oemsdr_hp(unsigned char *sdr) {
  int len, i;
  len = sdr[4] + 5;
  if (sdr[8] == 0x02)
    len = 18;
  printf("HP: ");
  for (i = 8; i < len; i++)
    printf("%02x ", sdr[i]);
  if (sdr[8] == 0x02)
    printf("%s", &sdr[18]);
  printf("\n");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show_oemsdr_hp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl 0x4(%rdi),%r12d
  cmpb   $0x2,0x8(%rdi)
  je     L7
  movzbl %r12b,%r12d
  add    $0x5,%r12d
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x8,%r12d
  jle    L23
L25:
  mov    $0x8,%ebx
  lea    D33(%rip),%r13
L17:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L17
L23:
  cmpb   $0x2,0x8(%rbp)
  je     L59
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  lea    0x12(%rbp),%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L7:
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x12,%r12d
  jmp    L25
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string

tool: D0: HP: 

tool: D33: %02x 

tool: D32: %s

assistant: ```c
void show_oemsdr_hp(unsigned char *sdr) {
  int len, i;
  len = sdr[4] + 5;
  if (sdr[8] == 0x02)
    len = 18;
  printf("HP: ");
  for (i = 8; i < len; i++)
    printf("%02x ", sdr[i]);
  if (sdr[8] == 0x02)
    printf("%s", &sdr[18]);
  printf("\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_oemsdr_hp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x2,0x8(%rdi)
  movzbl 0x4(%rdi),%r12d
  je     L2
  add    $0x5,%r12d
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  cmp    $0x8,%r12d
  jle    L56
L4:
  mov    $0x8,%ebx
  lea    D16(%rip),%r13
L32:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jg     L32
L56:
  cmpb   $0x2,0x8(%rbp)
  je     L55
L3:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    $0x12,%r12d
  call   <printf@plt>
  jmp    L4
  xchg   %ax,%ax
L55:
  lea    0x12(%rbp),%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string

tool: D0: HP: 

tool: D16: %02x 

tool: D27: %s

assistant: ```c
void show_oemsdr_hp(unsigned char *sdr) {
  int len, i;
  len = sdr[4] + 5;
  if (sdr[8] == 0x02)
    len = 18;
  printf("HP: ");
  for (i = 8; i < len; i++)
    printf("%02x ", sdr[i]);
  if (sdr[8] == 0x02)
    printf("%s", &sdr[18]);
  printf("\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<show_oemsdr_hp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x2,0x8(%rdi)
  movzbl 0x4(%rdi),%r12d
  je     L9
  add    $0x5,%r12d
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  cmp    $0x8,%r12d
  jle    L12
L58:
  mov    $0x8,%ebx
  lea    D4(%rip),%r13
L48:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jg     L48
L12:
  cmpb   $0x2,0x8(%rbp)
  je     L56
L41:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  mov    $0x12,%r12d
  call   <printf@plt>
  jmp    L58
  xchg   %ax,%ax
L56:
  lea    0x12(%rbp),%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L41
```

tool_calls: name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D39
type_guessed: string

tool: D26: HP: 

tool: D4: %02x 

tool: D39: %s

assistant: ```c
void show_oemsdr_hp(unsigned char *sdr) {
  int len, i;
  len = sdr[4] + 5;
  if (sdr[8] == 0x02)
    len = 18;
  printf("HP: ");
  for (i = 8; i < len; i++)
    printf("%02x ", sdr[i]);
  if (sdr[8] == 0x02)
    printf("%s", &sdr[18]);
  printf("\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scan_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L112
L73:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L128
  mov    $0x0,%eax
  jmp    L112
L128:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L104
L66:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  je     L43
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L43
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L135
L43:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L116
L135:
  addl   $0x1,-0x4(%rbp)
L104:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
L116:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L128
L71:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L85
  mov    $0x0,%eax
  jmp    L112
L85:
  mov    $0xffffffff,%eax
L112:
  leave
  ret
```

assistant: ```c
int scan_line(FILE *fid, char *line) {
  int i;
  if (fid == NULL) {
    return 0;
  }
  if (feof(fid)) {
    return 0;
  }
  do {
    fgets(line, 256, fid);
    for (i = 0; line[i] != '\0'; i++) {
      if (line[i] == '#' || line[i] == '\n' || line[i] == '\r') {
        line[i] = '\0';
        break;
      }
    }
  } while (line[0] == '\0' && feof(fid) == 0);
  if (feof(fid))
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scan_line>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <feof@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L87
  movabs $0x800002400,%rbx
  jmp    L44
L99:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L90
L12:
  cmp    $0x23,%al
  ja     L99
  bt     %rax,%rbx
  jae    L99
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  jne    L90
L74:
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L90
L44:
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L74
  mov    %rbp,%rdx
  jmp    L12
L90:
  mov    %r12,%rdi
  call   <feof@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
L87:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

assistant: ```c
int scan_line(FILE *fid, char *line) {
  int i;
  if (fid == NULL) {
    return 0;
  }
  if (feof(fid)) {
    return 0;
  }
  do {
    fgets(line, 256, fid);
    for (i = 0; line[i] != '\0'; i++) {
      if (line[i] == '#' || line[i] == '\n' || line[i] == '\r') {
        line[i] = '\0';
        break;
      }
    }
  } while (line[0] == '\0' && feof(fid) == 0);
  if (feof(fid))
    return 0;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scan_line>:
  endbr64
  test   %rdi,%rdi
  je     L66
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <feof@plt>
  test   %rax,%rax
  jne    L40
  movabs $0x800002400,%rbx
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L87
  mov    %rbp,%rdx
  jmp    L74
  nopl   (%rax)
L16:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L17
L74:
  cmp    $0x23,%al
  ja     L16
  bt     %rax,%rbx
  jae    L16
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  jne    L17
L87:
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L38
L17:
  mov    %r12,%rdi
  call   <feof@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0x1,%rax
  pop    %r12
  sbb    %eax,%eax
  ret
L40:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L66:
  xor    %eax,%eax
  ret
```

assistant: ```c
int scan_line(FILE *fid, char *line) {
  int i;
  if (fid == NULL) {
    return 0;
  }
  if (feof(fid)) {
    return 0;
  }
  do {
    fgets(line, 256, fid);
    for (i = 0; line[i] != '\0'; i++) {
      if (line[i] == '#' || line[i] == '\n' || line[i] == '\r') {
        line[i] = '\0';
        break;
      }
    }
  } while (line[0] == '\0' && feof(fid) == 0);
  if (feof(fid))
    return 0;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scan_line>:
  endbr64
  test   %rdi,%rdi
  je     L82
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <feof@plt>
  test   %rax,%rax
  jne    L74
  movabs $0x800002400,%rbx
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %r12,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L47
  mov    %rbp,%rdx
  jmp    L25
  nopl   (%rax)
L85:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L61
L25:
  cmp    $0x23,%al
  ja     L85
  bt     %rax,%rbx
  jae    L85
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  jne    L61
L47:
  mov    %r12,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L37
L61:
  mov    %r12,%rdi
  call   <feof@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0x1,%rax
  pop    %r12
  sbb    %eax,%eax
  ret
L74:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L82:
  xor    %eax,%eax
  ret
```

assistant: ```c
int scan_line(FILE *fid, char *line) {
  int i;
  if (fid == NULL) {
    return 0;
  }
  if (feof(fid)) {
    return 0;
  }
  do {
    fgets(line, 256, fid);
    for (i = 0; line[i] != '\0'; i++) {
      if (line[i] == '#' || line[i] == '\n' || line[i] == '\r') {
        line[i] = '\0';
        break;
      }
    }
  } while (line[0] == '\0' && feof(fid) == 0);
  if (feof(fid))
    return 0;
  else
    return -1;
}
```