ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<msk_calc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0xff,-0x1b(%rbp)
  movabs $0xfefcf8f0e0c08000,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0xff,-0x9(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L29
  cmpb   $0x80,-0x24(%rbp)
  jbe    L29
  mov    $0xffffffff,%eax
  jmp    L47
L29:
  cmpl   $0x0,-0x28(%rbp)
  jne    L73
  cmpb   $0x20,-0x24(%rbp)
  jbe    L73
  mov    $0xffffffff,%eax
  jmp    L47
L73:
  movzbl -0x24(%rbp),%eax
  shr    $0x3,%al
  mov    %al,-0x1a(%rbp)
  movzbl -0x24(%rbp),%eax
  and    $0x7,%eax
  mov    %al,-0x19(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L105
  mov    -0x30(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  jmp    L1
L105:
  mov    -0x30(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
L1:
  movl   $0x0,-0x18(%rbp)
  jmp    L68
L63:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1b(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L68:
  movzbl -0x1a(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L63
  cmpb   $0x0,-0x19(%rbp)
  je     L75
  movzbl -0x19(%rbp),%eax
  movzbl -0x1a(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  movzbl -0x11(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
L75:
  mov    $0x0,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int msk_calc(unsigned char prefix, int is_ipv6, unsigned char *res) {
  unsigned char a, b, constant = 0xff;
  unsigned char tables[] = {0, 128, 192, 224, 240, 248, 252, 254, 255};
  if (is_ipv6 && prefix > 128)
    return -1;
  if (!is_ipv6 && prefix > 32)
    return -1;
  a = prefix / 8;
  b = prefix % 8;
  if (is_ipv6)
    bzero(res, 16);
  else
    bzero(res, 4);
  for (int n = 0; n < a; n++) {
    res[n] = constant;
  }
  if (b)
    res[a] = tables[b];
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<msk_calc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0xfefcf8f0e0c08000,%rax
  mov    %rax,0xf(%rsp)
  movb   $0xff,0x17(%rsp)
  test   %esi,%esi
  je     L29
  cmp    $0x80,%dil
  ja     L84
L29:
  test   %esi,%esi
  jne    L55
  cmp    $0x20,%bl
  ja     L68
L55:
  mov    %ebx,%r13d
  shr    $0x3,%r13b
  mov    %ebx,%r12d
  and    $0x7,%r12d
  test   %esi,%esi
  je     L13
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
L100:
  cmp    $0x7,%bl
  jbe    L99
  mov    %rbp,%rax
  movzbl %r13b,%edx
  lea    -0x1(%rdx),%edx
  lea    0x1(%rbp,%rdx,1),%rdx
L112:
  movb   $0xff,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L112
L99:
  mov    $0x0,%eax
  test   %r12b,%r12b
  je     L67
  movzbl %r13b,%r13d
  and    $0x7,%r12d
  movzbl 0xf(%rsp,%r12,1),%eax
  mov    %al,0x0(%rbp,%r13,1)
  mov    $0x0,%eax
L67:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  jmp    L100
L84:
  mov    $0xffffffff,%eax
  jmp    L67
L68:
  mov    $0xffffffff,%eax
  jmp    L67
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msk_calc(unsigned char prefix, int is_ipv6, unsigned char *res) {
  unsigned char a, b, constant = 0xff;
  unsigned char tables[] = {0, 128, 192, 224, 240, 248, 252, 254, 255};
  if (is_ipv6 && prefix > 128)
    return -1;
  if (!is_ipv6 && prefix > 32)
    return -1;
  a = prefix / 8;
  b = prefix % 8;
  if (is_ipv6)
    bzero(res, 16);
  else
    bzero(res, 4);
  for (int n = 0; n < a; n++) {
    res[n] = constant;
  }
  if (b)
    res[a] = tables[b];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<msk_calc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xfefcf8f0e0c08000,%rax
  movb   $0xff,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  test   %esi,%esi
  je     L1
  cmp    $0x80,%dil
  ja     L82
  test   %esi,%esi
  je     L1
L186:
  mov    %edi,%r12d
  mov    %edi,%ebx
  shr    $0x3,%r12b
  and    $0x7,%ebx
  test   %esi,%esi
  je     L14
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
L55:
  test   %r12b,%r12b
  je     L30
  movzbl %r12b,%eax
  mov    $0xffffffffffffffff,%rdi
  cmp    $0x8,%eax
  jae    L38
  test   $0x4,%al
  jne    L167
  test   %eax,%eax
  jne    L144
L30:
  xor    %r8d,%r8d
  test   %bl,%bl
  je     L31
  mov    %rbx,%rdi
  movzbl %r12b,%eax
  and    $0x7,%edi
  movzbl 0xf(%rsp,%rdi,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x20,%dil
  jbe    L186
L82:
  mov    $0xffffffff,%r8d
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L38:
  lea    0x8(%rbp),%rcx
  mov    %rbp,%rdx
  movq   $0xffffffffffffffff,0x0(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp,%rax,1)
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L30
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L3:
  mov    %edx,%esi
  add    $0x8,%edx
  mov    %rdi,(%rcx,%rsi,1)
  cmp    %eax,%edx
  jb     L3
  jmp    L30
  nopl   0x0(%rax)
L144:
  movb   $0xff,0x0(%rbp)
  test   $0x2,%al
  je     L30
  mov    $0xffffffff,%edx
  mov    %dx,-0x2(%rbp,%rax,1)
  jmp    L30
L167:
  movl   $0xffffffff,0x0(%rbp)
  movl   $0xffffffff,-0x4(%rbp,%rax,1)
  jmp    L30
L113:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msk_calc(unsigned char prefix, int is_ipv6, unsigned char *res) {
  unsigned char a, b, constant = 0xff;
  unsigned char tables[] = {0, 128, 192, 224, 240, 248, 252, 254, 255};
  if (is_ipv6 && prefix > 128)
    return -1;
  if (!is_ipv6 && prefix > 32)
    return -1;
  a = prefix / 8;
  b = prefix % 8;
  if (is_ipv6)
    bzero(res, 16);
  else
    bzero(res, 4);
  for (int n = 0; n < a; n++) {
    res[n] = constant;
  }
  if (b)
    res[a] = tables[b];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<msk_calc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xfefcf8f0e0c08000,%rax
  movb   $0xff,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  test   %esi,%esi
  je     L148
  cmp    $0x80,%dil
  ja     L114
  test   %esi,%esi
  je     L148
L117:
  mov    %edi,%r12d
  mov    %edi,%ebx
  shr    $0x3,%r12b
  and    $0x7,%ebx
  test   %esi,%esi
  je     L56
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
L67:
  test   %r12b,%r12b
  je     L173
  movzbl %r12b,%eax
  mov    $0xffffffffffffffff,%rdi
  cmp    $0x8,%eax
  jae    L185
  test   $0x4,%al
  jne    L47
  test   %eax,%eax
  jne    L45
L173:
  xor    %r8d,%r8d
  test   %bl,%bl
  je     L115
  mov    %rbx,%rdi
  movzbl %r12b,%eax
  and    $0x7,%edi
  movzbl 0xf(%rsp,%rdi,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
L115:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L148:
  cmp    $0x20,%dil
  jbe    L117
L114:
  mov    $0xffffffff,%r8d
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L56:
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L185:
  lea    0x8(%rbp),%rcx
  mov    %rbp,%rdx
  movq   $0xffffffffffffffff,0x0(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp,%rax,1)
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L173
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L161:
  mov    %edx,%esi
  add    $0x8,%edx
  mov    %rdi,(%rcx,%rsi,1)
  cmp    %eax,%edx
  jb     L161
  jmp    L173
  nopl   0x0(%rax)
L45:
  movb   $0xff,0x0(%rbp)
  test   $0x2,%al
  je     L173
  mov    $0xffffffff,%edx
  mov    %dx,-0x2(%rbp,%rax,1)
  jmp    L173
L47:
  movl   $0xffffffff,0x0(%rbp)
  movl   $0xffffffff,-0x4(%rbp,%rax,1)
  jmp    L173
L102:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msk_calc(unsigned char prefix, int is_ipv6, unsigned char *res) {
  unsigned char a, b, constant = 0xff;
  unsigned char tables[] = {0, 128, 192, 224, 240, 248, 252, 254, 255};
  if (is_ipv6 && prefix > 128)
    return -1;
  if (!is_ipv6 && prefix > 32)
    return -1;
  a = prefix / 8;
  b = prefix % 8;
  if (is_ipv6)
    bzero(res, 16);
  else
    bzero(res, 4);
  for (int n = 0; n < a; n++) {
    res[n] = constant;
  }
  if (b)
    res[a] = tables[b];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<countBlocksOfLower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L25
L32:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L18
  cmpl   $0x0,-0xc(%rbp)
  jne    L18
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L25:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int countBlocksOfLower(char *s, int size) {
  int i;
  int isLower, lastIsLower = 0;
  int blockCount = 0;
  for (i = 0; i < size; ++i) {
    isLower = islower(s[i]);
    if (isLower && !lastIsLower)
      ++blockCount;
    lastIsLower = isLower;
  }
  return blockCount;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<countBlocksOfLower>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r13
  mov    $0x0,%r12d
  mov    $0x0,%eax
  jmp    L18
L19:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L25
L18:
  mov    %eax,%ebp
  movsbl (%rbx),%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L19
  test   %ebp,%ebp
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%r12d
  jmp    L19
L9:
  mov    $0x0,%r12d
L25:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int countBlocksOfLower(char *s, int size) {
  int i;
  int isLower, lastIsLower = 0;
  int blockCount = 0;
  for (i = 0; i < size; ++i) {
    isLower = islower(s[i]);
    if (isLower && !lastIsLower)
      ++blockCount;
    lastIsLower = isLower;
  }
  return blockCount;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<countBlocksOfLower>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movsbl (%rbx),%edi
  mov    %eax,%r13d
  call   <islower@plt>
  cmp    $0x1,%r13d
  mov    %r12d,%edx
  adc    $0x0,%r12d
  test   %eax,%eax
  cmove  %edx,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int countBlocksOfLower(char *s, int size) {
  int i;
  int isLower, lastIsLower = 0;
  int blockCount = 0;
  for (i = 0; i < size; ++i) {
    isLower = islower(s[i]);
    if (isLower && !lastIsLower)
      ++blockCount;
    lastIsLower = isLower;
  }
  return blockCount;
}
```
user: What is the c source code of the assembly code below?

```asm
<countBlocksOfLower>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%edi
  mov    %eax,%r13d
  call   <islower@plt>
  cmp    $0x1,%r13d
  mov    %r12d,%edx
  adc    $0x0,%r12d
  test   %eax,%eax
  cmove  %edx,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int countBlocksOfLower(char *s, int size) {
  int i;
  int isLower, lastIsLower = 0;
  int blockCount = 0;
  for (i = 0; i < size; ++i) {
    isLower = islower(s[i]);
    if (isLower && !lastIsLower)
      ++blockCount;
    lastIsLower = isLower;
  }
  return blockCount;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5fffeca,%eax
  movb   $0x0,(%rax)
  mov    $0x5fffec8,%eax
  movb   $0x0,(%rax)
  mov    $0x5fffec9,%eax
  movb   $0x9,(%rax)
  mov    $0x5fffeca,%eax
  movzbl (%rax),%eax
  mov    $0x5fffeca,%edx
  and    $0xfffffffc,%eax
  mov    %al,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L6:
  mov    $0x0,%eax
  call   <nop@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L6
  mov    $0x5fffeca,%eax
  movzbl (%rax),%eax
  mov    $0x5fffeca,%edx
  or     $0x30,%eax
  mov    %al,(%rdx)
  mov    $0x5ffffcc,%eax
  movzwl (%rax),%eax
  mov    $0x5ffffcc,%edx
  and    $0x5f,%al
  mov    %ax,(%rdx)
  mov    $0x5ffffcc,%eax
  movzwl (%rax),%eax
  mov    $0x5ffffcc,%edx
  or     $0xa0,%al
  mov    %ax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void init_serial(void) {
  int i;
  (*((volatile unsigned char *)0x05FFFECA)) = 0;
  (*((volatile unsigned char *)0x05FFFEC8)) = 0;
  (*((volatile unsigned char *)0x05FFFEC9)) = 9;
  (*((volatile unsigned char *)0x05FFFECA)) &= ~(0x02 | 0x01);
  for (i = 0; i < 1000; i++)
    nop();
  (*((volatile unsigned char *)0x05FFFECA)) |= 0x10 | 0x20;
  (*((volatile unsigned short *)0x05FFFFCC)) &= ~(0x0080 | 0x0020);
  (*((volatile unsigned short *)0x05FFFFCC)) |= 0x0080 | 0x0020;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_serial>:
  endbr64
  push   %rbx
  movb   $0x0,0x5fffeca
  movb   $0x0,0x5fffec8
  movb   $0x9,0x5fffec9
  movzbl 0x5fffeca,%eax
  and    $0xfffffffc,%eax
  mov    %al,0x5fffeca
  mov    $0x3e8,%ebx
L1:
  mov    $0x0,%eax
  call   <nop@plt>
  sub    $0x1,%ebx
  jne    L1
  movzbl 0x5fffeca,%eax
  or     $0x30,%eax
  mov    %al,0x5fffeca
  movzwl 0x5ffffcc,%eax
  and    $0x5f,%al
  mov    %ax,0x5ffffcc
  movzwl 0x5ffffcc,%eax
  or     $0xa0,%al
  mov    %ax,0x5ffffcc
  pop    %rbx
  ret
```

assistant: ```c
void init_serial(void) {
  int i;
  (*((volatile unsigned char *)0x05FFFECA)) = 0;
  (*((volatile unsigned char *)0x05FFFEC8)) = 0;
  (*((volatile unsigned char *)0x05FFFEC9)) = 9;
  (*((volatile unsigned char *)0x05FFFECA)) &= ~(0x02 | 0x01);
  for (i = 0; i < 1000; i++)
    nop();
  (*((volatile unsigned char *)0x05FFFECA)) |= 0x10 | 0x20;
  (*((volatile unsigned short *)0x05FFFFCC)) &= ~(0x0080 | 0x0020);
  (*((volatile unsigned short *)0x05FFFFCC)) |= 0x0080 | 0x0020;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<init_serial>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  movb   $0x0,0x5fffeca
  movb   $0x0,0x5fffec8
  movb   $0x9,0x5fffec9
  movzbl 0x5fffeca,%eax
  and    $0xfffffffc,%eax
  mov    %al,0x5fffeca
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <nop@plt>
  sub    $0x1,%ebx
  jne    L6
  movzbl 0x5fffeca,%eax
  or     $0x30,%eax
  mov    %al,0x5fffeca
  movzwl 0x5ffffcc,%eax
  and    $0x5f,%al
  mov    %ax,0x5ffffcc
  movzwl 0x5ffffcc,%eax
  or     $0xa0,%al
  mov    %ax,0x5ffffcc
  pop    %rbx
  ret
```

assistant: ```c
void init_serial(void) {
  int i;
  (*((volatile unsigned char *)0x05FFFECA)) = 0;
  (*((volatile unsigned char *)0x05FFFEC8)) = 0;
  (*((volatile unsigned char *)0x05FFFEC9)) = 9;
  (*((volatile unsigned char *)0x05FFFECA)) &= ~(0x02 | 0x01);
  for (i = 0; i < 1000; i++)
    nop();
  (*((volatile unsigned char *)0x05FFFECA)) |= 0x10 | 0x20;
  (*((volatile unsigned short *)0x05FFFFCC)) &= ~(0x0080 | 0x0020);
  (*((volatile unsigned short *)0x05FFFFCC)) |= 0x0080 | 0x0020;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init_serial>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  movb   $0x0,0x5fffeca
  movb   $0x0,0x5fffec8
  movb   $0x9,0x5fffec9
  movzbl 0x5fffeca,%eax
  and    $0xfffffffc,%eax
  mov    %al,0x5fffeca
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <nop@plt>
  sub    $0x1,%ebx
  jne    L0
  movzbl 0x5fffeca,%eax
  or     $0x30,%eax
  mov    %al,0x5fffeca
  movzwl 0x5ffffcc,%eax
  and    $0x5f,%al
  mov    %ax,0x5ffffcc
  movzwl 0x5ffffcc,%eax
  or     $0xa0,%al
  mov    %ax,0x5ffffcc
  pop    %rbx
  ret
```

assistant: ```c
void init_serial(void) {
  int i;
  (*((volatile unsigned char *)0x05FFFECA)) = 0;
  (*((volatile unsigned char *)0x05FFFEC8)) = 0;
  (*((volatile unsigned char *)0x05FFFEC9)) = 9;
  (*((volatile unsigned char *)0x05FFFECA)) &= ~(0x02 | 0x01);
  for (i = 0; i < 1000; i++)
    nop();
  (*((volatile unsigned char *)0x05FFFECA)) |= 0x10 | 0x20;
  (*((volatile unsigned short *)0x05FFFFCC)) &= ~(0x0080 | 0x0020);
  (*((volatile unsigned short *)0x05FFFFCC)) |= 0x0080 | 0x0020;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L7
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L7:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L23
  mov    $0x0,%eax
  jmp    L31
L23:
  movl   $0x3,-0x8(%rbp)
  jmp    L48
L22:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L45
  mov    $0x0,%eax
  jmp    L31
L45:
  addl   $0x2,-0x8(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L22
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: %d is a prime number


assistant: ```c
int isPrime(int n) {
  int high = (int)sqrt(n);
  int i;
  if (n <= 2) {
    printf("%d is a prime number\n", n);
    return 1;
  }
  if (n % 2 == 0)
    return 0;
  for (i = 3; i <= high; i += 2) {
    if (n % i == 0)
      return 0;
  }
  printf("%d is a prime number\n", n);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPrime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  cmp    $0x2,%ebx
  jle    L51
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   $0x1,%bl
  je     L39
  mov    %edx,%esi
  cmp    $0x2,%edx
  jle    L20
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L39
  mov    $0x3,%ecx
L21:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jl     L20
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L21
  jmp    L39
L51:
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L39
L20:
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L39:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: %d is a prime number


assistant: ```c
int isPrime(int n) {
  int high = (int)sqrt(n);
  int i;
  if (n <= 2) {
    printf("%d is a prime number\n", n);
    return 1;
  }
  if (n % 2 == 0)
    return 0;
  for (i = 3; i <= high; i += 2) {
    if (n % i == 0)
      return 0;
  }
  printf("%d is a prime number\n", n);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x2,%r12d
  jle    L6
  xor    %edx,%edx
  test   $0x1,%r12b
  je     L48
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L6
  movslq %r12d,%rdx
  mov    %r12d,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  je     L48
  mov    $0x3,%ecx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L48
L38:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L33
L6:
  mov    %r12d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
L48:
  mov    %edx,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %d is a prime number


assistant: ```c
int isPrime(int n) {
  int high = (int)sqrt(n);
  int i;
  if (n <= 2) {
    printf("%d is a prime number\n", n);
    return 1;
  }
  if (n % 2 == 0)
    return 0;
  for (i = 3; i <= high; i += 2) {
    if (n % i == 0)
      return 0;
  }
  printf("%d is a prime number\n", n);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x2,%r12d
  jle    L46
  xor    %edx,%edx
  test   $0x1,%r12b
  je     L65
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L46
  movslq %r12d,%rdx
  mov    %r12d,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  je     L65
  mov    $0x3,%ecx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L65
L9:
  add    $0x2,%ecx
  cmp    %ecx,%esi
  jge    L56
L46:
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
L65:
  mov    %edx,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d is a prime number


assistant: ```c
int isPrime(int n) {
  int high = (int)sqrt(n);
  int i;
  if (n <= 2) {
    printf("%d is a prime number\n", n);
    return 1;
  }
  if (n % 2 == 0)
    return 0;
  for (i = 3; i <= high; i += 2) {
    if (n % i == 0)
      return 0;
  }
  printf("%d is a prime number\n", n);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Vec_BitCountWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Vec_BitCountWord(unsigned uWord) {
  uWord = (uWord & 0x55555555) + ((uWord >> 1) & 0x55555555);
  uWord = (uWord & 0x33333333) + ((uWord >> 2) & 0x33333333);
  uWord = (uWord & 0x0F0F0F0F) + ((uWord >> 4) & 0x0F0F0F0F);
  uWord = (uWord & 0x00FF00FF) + ((uWord >> 8) & 0x00FF00FF);
  return (uWord & 0x0000FFFF) + (uWord >> 16);
}
```