ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time_cb>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <time@plt>
  lea    D3(%rip),%rdi
  movslq %eax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  mov    $0x1388,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D7
type: string

tool: D3: now is %ld


tool: D7: I'm time_cb,here [EventLoop: %p],[id : %lld],[data: %p] 


assistant: ```c
int time_cb(struct aeEventLoop *l, long long id, void *data) {
  printf("now is %ld\n", time(NULL));
  printf("I'm time_cb,here [EventLoop: %p],[id : %lld],[data: %p] \n", l, id, data);
  return 5 * 1000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: %d 

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 1000; i++)
    printf("%d ", i);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 1000; i++)
    printf("%d ", i);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d 

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 1000; i++)
    printf("%d ", i);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x3e8,%ebx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: %d 

assistant: ```c
int main(int argc, char **argv) {
  for (int i = 0; i < 1000; i++)
    printf("%d ", i);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<model_>:
  endbr64
  mov    0x18(%rsp),%rax
  mov    0x30(%rsp),%rsi
  movsd  (%rax),%xmm4
  movsd  0x8(%rax),%xmm5
  movsd  0x10(%rax),%xmm6
  movapd %xmm5,%xmm0
  divsd  %xmm6,%xmm0
  mov    0x20(%rsp),%rax
  movsd  %xmm0,(%rax)
  cmpl   $0x0,(%rcx)
  jle    L21
  mov    0x28(%rsp),%rdx
  mov    $0x0,%eax
  jmp    L15
L44:
  movsd  (%rdx),%xmm2
  subsd  -0x10(%rdx),%xmm2
  movsd  -0x8(%rsi,%rax,8),%xmm1
  movsd  -0x8(%rdx),%xmm7
  movsd  0x8(%rdx),%xmm0
  subsd  %xmm7,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm5,%xmm3
  mulsd  %xmm2,%xmm3
  mulsd  %xmm7,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm6,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
L3:
  add    $0x1,%rax
  add    $0x10,%rdx
  cmp    %eax,(%rcx)
  jle    L21
L15:
  test   %eax,%eax
  jg     L44
  movapd %xmm4,%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  jmp    L3
L21:
  ret
```

assistant: ```c
void model_(int *CurSet, int *NoOfParams, int *NoOfDerived, int *TotalDataValues, int *MaxNoOfDataValues, int *NoOfDataCols, int *NoOfAdirissaCols, int *NoOfModelVectors, double Params[], double Derived[], double Adirissa[], double Signal[]) {
  int CurEntry, tindex, cindex;
  double R, K2, k2a, dt, DVR;
  R = Params[0];
  K2 = Params[1];
  k2a = Params[2];
  DVR = K2 / k2a;
  Derived[0] = DVR;
  for (CurEntry = 0; CurEntry < *TotalDataValues; CurEntry++) {
    tindex = 2 * CurEntry;
    cindex = 2 * CurEntry + 1;
    if (CurEntry < 1) {
      dt = Adirissa[tindex];
      Signal[CurEntry] = R * (Adirissa[cindex]);
    } else {
      dt = Adirissa[tindex] - Adirissa[tindex - 2];
      Signal[CurEntry] = Signal[CurEntry - 1] + R * (Adirissa[cindex] - Adirissa[cindex - 2]) + K2 * dt * Adirissa[cindex - 2] - dt * Signal[CurEntry - 1] * k2a;
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<model_>:
  endbr64
  mov    0x18(%rsp),%rax
  mov    %rcx,%r8
  mov    0x28(%rsp),%rdx
  movslq (%r8),%rsi
  mov    0x30(%rsp),%rcx
  movsd  0x8(%rax),%xmm6
  movsd  0x10(%rax),%xmm5
  movsd  (%rax),%xmm4
  mov    0x20(%rsp),%rax
  movapd %xmm6,%xmm0
  divsd  %xmm5,%xmm0
  movsd  %xmm0,(%rax)
  xor    %eax,%eax
  test   %esi,%esi
  jg     L47
  jmp    L27
L21:
  movsd  0x8(%rdx),%xmm0
  add    $0x1,%rax
  add    $0x10,%rdx
  mulsd  %xmm4,%xmm0
  movsd  %xmm0,(%rcx)
  cmp    %rax,%rsi
  je     L27
L47:
  test   %rax,%rax
  je     L21
  movsd  -0x8(%rdx),%xmm7
  movsd  (%rdx),%xmm2
  movapd %xmm6,%xmm3
  add    $0x10,%rdx
  movsd  -0x8(%rdx),%xmm0
  subsd  -0x20(%rdx),%xmm2
  movsd  -0x8(%rcx,%rax,8),%xmm1
  subsd  %xmm7,%xmm0
  mulsd  %xmm2,%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm7,%xmm3
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm0
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L47
L27:
  ret
```

assistant: ```c
void model_(int *CurSet, int *NoOfParams, int *NoOfDerived, int *TotalDataValues, int *MaxNoOfDataValues, int *NoOfDataCols, int *NoOfAdirissaCols, int *NoOfModelVectors, double Params[], double Derived[], double Adirissa[], double Signal[]) {
  int CurEntry, tindex, cindex;
  double R, K2, k2a, dt, DVR;
  R = Params[0];
  K2 = Params[1];
  k2a = Params[2];
  DVR = K2 / k2a;
  Derived[0] = DVR;
  for (CurEntry = 0; CurEntry < *TotalDataValues; CurEntry++) {
    tindex = 2 * CurEntry;
    cindex = 2 * CurEntry + 1;
    if (CurEntry < 1) {
      dt = Adirissa[tindex];
      Signal[CurEntry] = R * (Adirissa[cindex]);
    } else {
      dt = Adirissa[tindex] - Adirissa[tindex - 2];
      Signal[CurEntry] = Signal[CurEntry - 1] + R * (Adirissa[cindex] - Adirissa[cindex - 2]) + K2 * dt * Adirissa[cindex - 2] - dt * Signal[CurEntry - 1] * k2a;
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<model_>:
  endbr64
  mov    0x18(%rsp),%rax
  mov    %rcx,%r8
  mov    0x28(%rsp),%rdx
  movslq (%r8),%rsi
  mov    0x30(%rsp),%rcx
  movsd  0x8(%rax),%xmm6
  movsd  0x10(%rax),%xmm5
  movsd  (%rax),%xmm4
  mov    0x20(%rsp),%rax
  movapd %xmm6,%xmm0
  divsd  %xmm5,%xmm0
  movsd  %xmm0,(%rax)
  xor    %eax,%eax
  test   %esi,%esi
  jg     L41
  jmp    L17
L25:
  movsd  0x8(%rdx),%xmm0
  add    $0x1,%rax
  add    $0x10,%rdx
  mulsd  %xmm4,%xmm0
  movsd  %xmm0,(%rcx)
  cmp    %rax,%rsi
  je     L17
L41:
  test   %rax,%rax
  je     L25
  movsd  -0x8(%rdx),%xmm7
  movsd  (%rdx),%xmm2
  movapd %xmm6,%xmm3
  add    $0x10,%rdx
  movsd  -0x8(%rdx),%xmm0
  subsd  -0x20(%rdx),%xmm2
  movsd  -0x8(%rcx,%rax,8),%xmm1
  subsd  %xmm7,%xmm0
  mulsd  %xmm2,%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm7,%xmm3
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm0
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L41
L17:
  ret
```

assistant: ```c
void model_(int *CurSet, int *NoOfParams, int *NoOfDerived, int *TotalDataValues, int *MaxNoOfDataValues, int *NoOfDataCols, int *NoOfAdirissaCols, int *NoOfModelVectors, double Params[], double Derived[], double Adirissa[], double Signal[]) {
  int CurEntry, tindex, cindex;
  double R, K2, k2a, dt, DVR;
  R = Params[0];
  K2 = Params[1];
  k2a = Params[2];
  DVR = K2 / k2a;
  Derived[0] = DVR;
  for (CurEntry = 0; CurEntry < *TotalDataValues; CurEntry++) {
    tindex = 2 * CurEntry;
    cindex = 2 * CurEntry + 1;
    if (CurEntry < 1) {
      dt = Adirissa[tindex];
      Signal[CurEntry] = R * (Adirissa[cindex]);
    } else {
      dt = Adirissa[tindex] - Adirissa[tindex - 2];
      Signal[CurEntry] = Signal[CurEntry - 1] + R * (Adirissa[cindex] - Adirissa[cindex - 2]) + K2 * dt * Adirissa[cindex - 2] - dt * Signal[CurEntry - 1] * k2a;
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L2
L12:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *stpcpy(char *a, const char *b) {
  while (*b)
    *a++ = *b++;
  *a = 0;
  return (char *)a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stpcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L18
L8:
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L8
L18:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *stpcpy(char *a, const char *b) {
  while (*b)
    *a++ = *b++;
  *a = 0;
  return (char *)a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stpcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L19
  xchg   %ax,%ax
L4:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L4
L19:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *stpcpy(char *a, const char *b) {
  while (*b)
    *a++ = *b++;
  *a = 0;
  return (char *)a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stpcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L2
  xchg   %ax,%ax
L8:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L8
L2:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *stpcpy(char *a, const char *b) {
  while (*b)
    *a++ = *b++;
  *a = 0;
  return (char *)a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %edi,-0x1a4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x1a4(%rbp),%eax
  mov    %eax,-0x1a0(%rbp)
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void test9(int X) {
  int Arr[100] = {X};
  bar(Arr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test9>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %edx,(%rsp)
  mov    %rsp,%rdi
  call   <bar@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1a8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test9(int X) {
  int Arr[100] = {X};
  bar(Arr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test9>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%r8d
  mov    $0x32,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  mov    %r8d,(%rsp)
  call   <bar@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1a8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test9(int X) {
  int Arr[100] = {X};
  bar(Arr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test9>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %edi,%r8d
  mov    $0x32,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  mov    %r8d,(%rsp)
  call   <bar@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x1a8,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test9(int X) {
  int Arr[100] = {X};
  bar(Arr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<twhlist_del_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <twhlist_unhashed@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__twhlist_del@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <TWINIT_HLIST_NODE@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void twhlist_del_init(struct twhlist_node *n) {
  if (!twhlist_unhashed(n)) {
    __twhlist_del(n);
    TWINIT_HLIST_NODE(n);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<twhlist_del_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <twhlist_unhashed@plt>
  test   %eax,%eax
  je     L19
L5:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <__twhlist_del@plt>
  mov    %rbx,%rdi
  call   <TWINIT_HLIST_NODE@plt>
  jmp    L5
```

assistant: ```c
void twhlist_del_init(struct twhlist_node *n) {
  if (!twhlist_unhashed(n)) {
    __twhlist_del(n);
    TWINIT_HLIST_NODE(n);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<twhlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <twhlist_unhashed@plt>
  test   %eax,%eax
  je     L8
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <__twhlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <TWINIT_HLIST_NODE@plt>
```

assistant: ```c
void twhlist_del_init(struct twhlist_node *n) {
  if (!twhlist_unhashed(n)) {
    __twhlist_del(n);
    TWINIT_HLIST_NODE(n);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<twhlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <twhlist_unhashed@plt>
  test   %eax,%eax
  je     L7
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <__twhlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <TWINIT_HLIST_NODE@plt>
```

assistant: ```c
void twhlist_del_init(struct twhlist_node *n) {
  if (!twhlist_unhashed(n)) {
    __twhlist_del(n);
    TWINIT_HLIST_NODE(n);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cur_us_ts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
uint64_t cur_us_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * (uint64_t)tv.tv_sec + tv.tv_usec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cur_us_ts>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t cur_us_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * (uint64_t)tv.tv_sec + tv.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cur_us_ts>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t cur_us_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * (uint64_t)tv.tv_sec + tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cur_us_ts>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  add    (%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t cur_us_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return 1000000 * (uint64_t)tv.tv_sec + tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isBeginningOf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L34
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L34
  mov    $0x0,%eax
  jmp    L13
L34:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int isBeginningOf(char *s, char *scode) {
  while (*scode) {
    if (*s++ != *scode++)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isBeginningOf>:
  endbr64
  mov    $0x0,%eax
L17:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L15
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %dl,%cl
  je     L17
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isBeginningOf(char *s, char *scode) {
  while (*scode) {
    if (*s++ != *scode++)
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isBeginningOf>:
  endbr64
  xor    %eax,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L0:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %dl,%cl
  jne    L8
L2:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L0
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isBeginningOf(char *s, char *scode) {
  while (*scode) {
    if (*s++ != *scode++)
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isBeginningOf>:
  endbr64
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %dl,%cl
  jne    L22
L8:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L12
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isBeginningOf(char *s, char *scode) {
  while (*scode) {
    if (*s++ != *scode++)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x1,%esi
  mov    $0x3e,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L0:
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L9
  movl   $0x1,-0x10(%rbp)
L9:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x3c,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D43(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L51
L6:
  mov    -0x8(%rbp),%rax
  lea    D49(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x14(%rbp)
L51:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L6
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L45:
  mov    -0x8(%rbp),%rax
  lea    D49(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L45
  mov    -0x8(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
type: string
name: read_data
arguments: data_label: D43
type: string
name: read_data
arguments: data_label: D49
type: string
name: read_data
arguments: data_label: D23
type: string

tool: D20: print_info(): Out of memory !

tool: D43: *

tool: D49:  

tool: D23: *


assistant: ```c
char *output_line(char *string) {
  char *tmp;
  if (NULL == (tmp = (calloc(62, sizeof(char))))) {
    error("print_info(): Out of memory !");
  }
  int x, i, y;
  y = 0;
  if (strlen(string) % 2 == 0)
    y = 1;
  x = (60 - strlen(string)) / 2;
  strcat(tmp, "*");
  for (i = 0; i != x - y; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, string);
  for (i = 0; i != x - 1; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, "*\n");
  free(string);
  string = &(tmp[0]);
  return string;
}
```