ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  call   <getNum@plt>
  mov    $0x39,%ebx
  cmp    $0x28,%eax
  je     L82
  mov    %eax,%ebx
  cmp    $0x32,%eax
  je     L96
L82:
  lea    D7(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x0,%r12d
  lea    D25(%rip),%r13
L89:
  cmp    %ebx,%r12d
  je     L84
  mov    %rsp,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  movsbl (%rsp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L89
  mov    %rsp,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  jmp    L89
L96:
  mov    $0x3a,%ebx
  jmp    L82
L84:
  lea    0x20(%rsp),%r12
  mov    %rbp,%rdx
  mov    $0xb4,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L20
  mov    %r12,%rdx
  lea    -0x1(%rax),%eax
  lea    0x21(%rsp,%rax,1),%rcx
L50:
  movzbl 0x1(%rdx),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L50
L20:
  lea    0x20(%rsp),%rdi
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L65
  movb   $0x0,(%rax)
L65:
  lea    0x20(%rsp),%rdi
  mov    %ebx,%esi
  call   <sendMessage@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string

tool: D7: r

tool: D16: quotes.txt

tool: D25: %s

assistant: ```c
int main() {
  char quote[200];
  int num = getNum();
  if (num == 40)
    num = 57;
  if (num == 50)
    num = 58;
  FILE *fp;
  fp = fopen("quotes.txt", "r");
  int currNum = 0;
  char temp[20];
  while (currNum != num) {
    fscanf(fp, "%s", temp);
    if (isdigit(temp[0]) != 0) {
      currNum = atoi(temp);
    }
  }
  fgets(quote, 180, fp);
  fclose(fp);
  int i, len = strlen(quote);
  for (i = 1; i <= len; ++i) {
    quote[i - 1] = quote[i];
  }
  char *pos;
  if ((pos = strchr(quote, '\n')) != NULL)
    *pos = '\0';
  sendMessage(quote, num);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    $0x39,%r12d
  push   %rbp
  push   %rbx
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  call   <getNum@plt>
  cmp    $0x28,%eax
  je     L88
  mov    %eax,%r12d
  cmp    $0x32,%eax
  je     L15
L88:
  lea    D29(%rip),%rsi
  lea    D2(%rip),%rdi
  xor    %ebx,%ebx
  call   <fopen@plt>
  lea    D17(%rip),%r13
  mov    %rax,%r14
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rsp,%rbp
  mov    %r14,%rdi
  mov    %r13,%rsi
  mov    %rbp,%rdx
  call   <fscanf@plt>
  movsbl (%rsp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
L98:
  cmp    %r12d,%ebx
  jne    L9
  lea    0x20(%rsp),%rbp
  mov    %r14,%rdx
  mov    $0xb4,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  movslq %eax,%rdx
  lea    0x21(%rsp),%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
L4:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L44
  movb   $0x0,(%rax)
L44:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sendMessage@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L39:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L98
L15:
  mov    $0x3a,%r12d
  jmp    L88
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type: string
name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D29: r

tool: D2: quotes.txt

tool: D17: %s

assistant: ```c
int main() {
  char quote[200];
  int num = getNum();
  if (num == 40)
    num = 57;
  if (num == 50)
    num = 58;
  FILE *fp;
  fp = fopen("quotes.txt", "r");
  int currNum = 0;
  char temp[20];
  while (currNum != num) {
    fscanf(fp, "%s", temp);
    if (isdigit(temp[0]) != 0) {
      currNum = atoi(temp);
    }
  }
  fgets(quote, 180, fp);
  fclose(fp);
  int i, len = strlen(quote);
  for (i = 1; i <= len; ++i) {
    quote[i - 1] = quote[i];
  }
  char *pos;
  if ((pos = strchr(quote, '\n')) != NULL)
    *pos = '\0';
  sendMessage(quote, num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  call   <getNum@plt>
  cmp    $0x28,%eax
  je     L75
  mov    %eax,%r14d
  lea    D37(%rip),%rsi
  lea    D49(%rip),%rdi
  cmp    $0x32,%eax
  je     L79
  call   <fopen@plt>
  mov    %r14d,%r13d
  mov    %rax,%rbp
  test   %r14d,%r14d
  je     L40
L74:
  mov    %rsp,%rbx
  lea    D33(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  mov    %r12,%rsi
  call   <fscanf@plt>
  movsbl (%rsp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L32
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
  cmp    %r13d,%eax
  jne    L32
L40:
  lea    0x20(%rsp),%r12
  mov    %rbp,%rdx
  mov    $0xb4,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  movslq %eax,%rdx
  lea    0x21(%rsp),%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L3:
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L31
  movb   $0x0,(%rax)
L31:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <sendMessage@plt>
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L79:
  call   <fopen@plt>
  mov    $0x3a,%r13d
  mov    %rax,%rbp
  jmp    L74
L75:
  lea    D37(%rip),%rsi
  lea    D49(%rip),%rdi
  mov    $0x39,%r13d
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L74
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D37
type: string
name: retrieve_data
arguments: data_label: D49
type: string
name: retrieve_data
arguments: data_label: D33
type: string

tool: D37: r

tool: D49: quotes.txt

tool: D33: %s

assistant: ```c
int main() {
  char quote[200];
  int num = getNum();
  if (num == 40)
    num = 57;
  if (num == 50)
    num = 58;
  FILE *fp;
  fp = fopen("quotes.txt", "r");
  int currNum = 0;
  char temp[20];
  while (currNum != num) {
    fscanf(fp, "%s", temp);
    if (isdigit(temp[0]) != 0) {
      currNum = atoi(temp);
    }
  }
  fgets(quote, 180, fp);
  fclose(fp);
  int i, len = strlen(quote);
  for (i = 1; i <= len; ++i) {
    quote[i - 1] = quote[i];
  }
  char *pos;
  if ((pos = strchr(quote, '\n')) != NULL)
    *pos = '\0';
  sendMessage(quote, num);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D56
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D54
type_guessed: string

tool: D2: ************

tool: D5: name	name

tool: D56: name

tool: D33: %8s


tool: D54: %-8s


assistant: ```c
int main(void) {
  printf("************\n");
  printf("name\tname\n");
  printf("%8s\n", "name");
  printf("%-8s\n", "name");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rbx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D38
type: string
name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D39
type: string
name: parse_data
arguments: data_label: D28
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D38: ************

tool: D35: name	name

tool: D39: name

tool: D28: %8s


tool: D11: %-8s


assistant: ```c
int main(void) {
  printf("************\n");
  printf("name\tname\n");
  printf("%8s\n", "name");
  printf("%-8s\n", "name");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D14(%rip),%rbp
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D31
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D15: ************

tool: D14: name

tool: D13: name	name

tool: D31: %8s


tool: D4: %-8s


assistant: ```c
int main(void) {
  printf("************\n");
  printf("name\tname\n");
  printf("%8s\n", "name");
  printf("%-8s\n", "name");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  lea    D31(%rip),%rbp
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D39
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D39: ************

tool: D31: name

tool: D17: name	name

tool: D38: %8s


tool: D9: %-8s


assistant: ```c
int main(void) {
  printf("************\n");
  printf("name\tname\n");
  printf("%8s\n", "name");
  printf("%-8s\n", "name");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<return_alloca>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_alloca@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((noipa)) void *return_alloca(int n) {
  void *p = __builtin_alloca(n);
  sink(p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<return_alloca>:
  endbr64
  push   %rbx
  call   <__builtin_alloca@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((noipa)) void *return_alloca(int n) {
  void *p = __builtin_alloca(n);
  sink(p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<return_alloca>:
  endbr64
  push   %r12
  call   <__builtin_alloca@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((noipa)) void *return_alloca(int n) {
  void *p = __builtin_alloca(n);
  sink(p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<return_alloca>:
  endbr64
  push   %r12
  call   <__builtin_alloca@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((noipa)) void *return_alloca(int n) {
  void *p = __builtin_alloca(n);
  sink(p);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x726f66736b656567,%rax
  mov    %rax,-0x16(%rbp)
  movl   $0x6b656567,-0xe(%rbp)
  movw   $0x73,-0xa(%rbp)
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdi
  call   <countSort@plt>
  lea    -0x16(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: Sorted character array is %sn

assistant: ```c
int main() {
  char arr[] = "geeksforgeeks";
  countSort(arr);
  printf("Sorted character array is %sn", arr);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x726f66736b656567,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x6b656567,0x12(%rsp)
  movw   $0x73,0x16(%rsp)
  lea    0xa(%rsp),%rbx
  mov    %rbx,%rdi
  call   <countSort@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: Sorted character array is %sn

assistant: ```c
int main() {
  char arr[] = "geeksforgeeks";
  countSort(arr);
  printf("Sorted character array is %sn", arr);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f66736b656567,%rax
  lea    0xa(%rsp),%rbp
  movl   $0x6b656567,0x12(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xa(%rsp)
  mov    $0x73,%eax
  mov    %ax,0x16(%rsp)
  call   <countSort@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: Sorted character array is %sn

assistant: ```c
int main() {
  char arr[] = "geeksforgeeks";
  countSort(arr);
  printf("Sorted character array is %sn", arr);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f66736b656567,%rax
  lea    0xa(%rsp),%rbp
  movl   $0x6b656567,0x12(%rsp)
  mov    %rbp,%rdi
  mov    %rax,0xa(%rsp)
  mov    $0x73,%eax
  mov    %ax,0x16(%rsp)
  call   <countSort@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: Sorted character array is %sn

assistant: ```c
int main() {
  char arr[] = "geeksforgeeks";
  countSort(arr);
  printf("Sorted character array is %sn", arr);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D53
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D53: Enter any number :  

tool: D2: %d

tool: D31: 
Enter any number again: 

tool: D23: 
 ------------------------- 

tool: D9: 
 Sum: %d, 	 Difference: %d, 
 Product: %d, 	 Quotient: %d 

assistant: ```c
int main() {
  int numb1, numb2, sum, diff, product, quotient;
  printf("Enter any number :  ");
  scanf("%d", &numb1);
  printf("\nEnter any number again: ");
  scanf("%d", &numb2);
  sum = numb1 + numb2;
  diff = numb1 - numb2;
  product = numb1 * numb2;
  quotient = numb1 / numb2;
  printf("\n ------------------------- ");
  printf("\n Sum: %d, \t Difference: %d, \n Product: %d, \t Quotient: %d ", sum, diff, product, quotient);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%ebp
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%r8d
  mov    %ebx,%ecx
  imul   %ebp,%ecx
  mov    %ebx,%edx
  sub    %ebp,%edx
  lea    (%rbx,%rbp,1),%esi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D41
type: string

tool: D13: Enter any number :  

tool: D22: %d

tool: D6: 
Enter any number again: 

tool: D32: 
 ------------------------- 

tool: D41: 
 Sum: %d, 	 Difference: %d, 
 Product: %d, 	 Quotient: %d 

assistant: ```c
int main() {
  int numb1, numb2, sum, diff, product, quotient;
  printf("Enter any number :  ");
  scanf("%d", &numb1);
  printf("\nEnter any number again: ");
  scanf("%d", &numb2);
  sum = numb1 + numb2;
  diff = numb1 - numb2;
  product = numb1 * numb2;
  quotient = numb1 / numb2;
  printf("\n ------------------------- ");
  printf("\n Sum: %d, \t Difference: %d, \n Product: %d, \t Quotient: %d ", sum, diff, product, quotient);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  xor    %eax,%eax
  mov    0x4(%rsp),%ebp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  mov    %ebx,%ecx
  lea    (%rbx,%rbp,1),%esi
  cltd
  imul   %ebp,%ecx
  lea    D36(%rip),%rdi
  idiv   %ebp
  mov    %ebx,%edx
  sub    %ebp,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D25
data_type: string
name: read_data
arguments: tag: D15
data_type: string
name: read_data
arguments: tag: D43
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D36
data_type: string

tool: D25: Enter any number :  

tool: D15: %d

tool: D43: 
Enter any number again: 

tool: D8: 
 ------------------------- 

tool: D36: 
 Sum: %d, 	 Difference: %d, 
 Product: %d, 	 Quotient: %d 

assistant: ```c
int main() {
  int numb1, numb2, sum, diff, product, quotient;
  printf("Enter any number :  ");
  scanf("%d", &numb1);
  printf("\nEnter any number again: ");
  scanf("%d", &numb2);
  sum = numb1 + numb2;
  diff = numb1 - numb2;
  product = numb1 * numb2;
  quotient = numb1 / numb2;
  printf("\n ------------------------- ");
  printf("\n Sum: %d, \t Difference: %d, \n Product: %d, \t Quotient: %d ", sum, diff, product, quotient);
  return 0;
}
```