ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <srand@plt>
  mov    $0x400000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%edi
  call   <perfPoll@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L46:
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L39:
  cmpl   $0xfffff,-0x10(%rbp)
  jle    L8
  addl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x1387,-0xc(%rbp)
  jle    L46
  mov    $0x0,%edi
  call   <perfPoll@plt>
L41:
  jmp    L41
```

assistant: ```c
void main() {
  srand(0);
  int *array = (int *)malloc(sizeof(int) * 1024 * 1024);
  int i, o;
  perfPoll(0);
  for (o = 0; o < 5000; o++) {
    for (i = 0; i < 1024 * 1024; i++) {
      array[i] = (int)rand();
    }
  }
  perfPoll(0);
  for (;;) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <srand@plt>
  mov    $0x400000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%edi
  call   <perfPoll@plt>
  mov    $0x1388,%r12d
  lea    0x400000(%r13),%rbp
L18:
  mov    %r13,%rbx
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L22
  sub    $0x1,%r12d
  jne    L18
  mov    $0x0,%edi
  call   <perfPoll@plt>
L28:
  jmp    L28
```

assistant: ```c
void main() {
  srand(0);
  int *array = (int *)malloc(sizeof(int) * 1024 * 1024);
  int i, o;
  perfPoll(0);
  for (o = 0; o < 5000; o++) {
    for (i = 0; i < 1024 * 1024; i++) {
      array[i] = (int)rand();
    }
  }
  perfPoll(0);
  for (;;) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  push   %r12
  mov    $0x1388,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <srand@plt>
  mov    $0x400000,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <perfPoll@plt>
  lea    0x400000(%r13),%rbp
L26:
  mov    %r13,%rbx
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L21
  sub    $0x1,%r12d
  jne    L26
  xor    %edi,%edi
  call   <perfPoll@plt>
L15:
  jmp    L15
```

assistant: ```c
void main() {
  srand(0);
  int *array = (int *)malloc(sizeof(int) * 1024 * 1024);
  int i, o;
  perfPoll(0);
  for (o = 0; o < 5000; o++) {
    for (i = 0; i < 1024 * 1024; i++) {
      array[i] = (int)rand();
    }
  }
  perfPoll(0);
  for (;;) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  push   %r12
  mov    $0x1388,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <srand@plt>
  mov    $0x400000,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <perfPoll@plt>
  lea    0x400000(%r13),%rbp
L21:
  mov    %r13,%rbx
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L16
  sub    $0x1,%r12d
  jne    L21
  xor    %edi,%edi
  call   <perfPoll@plt>
L3:
  jmp    L3
```

assistant: ```c
void main() {
  srand(0);
  int *array = (int *)malloc(sizeof(int) * 1024 * 1024);
  int i, o;
  perfPoll(0);
  for (o = 0; o < 5000; o++) {
    for (i = 0; i < 1024 * 1024; i++) {
      array[i] = (int)rand();
    }
  }
  perfPoll(0);
  for (;;) {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L17
L6:
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %lf


assistant: ```c
int main(void) {
  char line[200];
  while (getline(line, 200) != 0) {
    printf("%lf\n", atof(line));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rbx
  jmp    L21
L7:
  mov    %rsp,%rdi
  call   <atof@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L21:
  mov    %rsp,%rdi
  mov    $0xc8,%esi
  call   <getline@plt>
  test   %rax,%rax
  jne    L7
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %lf


assistant: ```c
int main(void) {
  char line[200];
  while (getline(line, 200) != 0) {
    printf("%lf\n", atof(line));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L14
  nopl   0x0(%rax)
L18:
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L14:
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L18
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: %lf


assistant: ```c
int main(void) {
  char line[200];
  while (getline(line, 200) != 0) {
    printf("%lf\n", atof(line));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L4
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rdi
  call   <atof@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L4:
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L28
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: %lf


assistant: ```c
int main(void) {
  char line[200];
  while (getline(line, 200) != 0) {
    printf("%lf\n", atof(line));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dbgPrintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  cmpl   $0x0,-0xc4(%rbp)
  jns    L17
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <dbgAddIndent@plt>
L17:
  mov    $0x0,%eax
  call   <dbgShowIndent@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  cmpl   $0x0,-0xc4(%rbp)
  jle    L14
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <dbgAddIndent@plt>
L14:
  nop
  leave
  ret
```

assistant: ```c
void dbgPrintf(int delta_indent, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  if (delta_indent < 0)
    dbgAddIndent(delta_indent);
  dbgShowIndent();
  vprintf(format, ap);
  if (delta_indent > 0)
    dbgAddIndent(delta_indent);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dbgPrintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%edi
  call   <va_start@plt>
  test   %ebx,%ebx
  js     L17
  mov    $0x0,%eax
  call   <dbgShowIndent@plt>
  mov    $0x0,%edi
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  test   %ebx,%ebx
  jle    L1
  mov    %ebx,%edi
  call   <dbgAddIndent@plt>
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %ebx,%edi
  call   <dbgAddIndent@plt>
  mov    $0x0,%eax
  call   <dbgShowIndent@plt>
  mov    $0x0,%edi
  mov    %edi,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  jmp    L1
```

assistant: ```c
void dbgPrintf(int delta_indent, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  if (delta_indent < 0)
    dbgAddIndent(delta_indent);
  dbgShowIndent();
  vprintf(format, ap);
  if (delta_indent > 0)
    dbgAddIndent(delta_indent);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dbgPrintf>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  test   %ebp,%ebp
  js     L19
  xor    %eax,%eax
  call   <dbgShowIndent@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <vprintf@plt>
  test   %ebp,%ebp
  je     L14
  mov    %ebp,%edi
  call   <dbgAddIndent@plt>
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L19:
  mov    %ebp,%edi
  call   <dbgAddIndent@plt>
  xor    %eax,%eax
  call   <dbgShowIndent@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <vprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void dbgPrintf(int delta_indent, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  if (delta_indent < 0)
    dbgAddIndent(delta_indent);
  dbgShowIndent();
  vprintf(format, ap);
  if (delta_indent > 0)
    dbgAddIndent(delta_indent);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dbgPrintf>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  test   %ebp,%ebp
  js     L4
  xor    %eax,%eax
  call   <dbgShowIndent@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <vprintf@plt>
  test   %ebp,%ebp
  je     L16
  mov    %ebp,%edi
  call   <dbgAddIndent@plt>
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  mov    %ebp,%edi
  call   <dbgAddIndent@plt>
  xor    %eax,%eax
  call   <dbgShowIndent@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <vprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void dbgPrintf(int delta_indent, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  if (delta_indent < 0)
    dbgAddIndent(delta_indent);
  dbgShowIndent();
  vprintf(format, ap);
  if (delta_indent > 0)
    dbgAddIndent(delta_indent);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__imlib_SubCopyToRGBA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  and    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0x14(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __imlib_SubCopyToRGBA(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  ((unsigned char *)(dst))[3] = ((unsigned char *)(&color))[3];
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__imlib_SubCopyToRGBA>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  mov    %rsi,%rax
  mov    %edi,%edx
  shr    $0x18,%edx
  mov    %dl,0x3(%rsi)
  movzbl 0x2(%rsi),%esi
  shr    $0x10,%edi
  movzbl %sil,%edx
  movzbl %dil,%r8d
  sub    %r8d,%edx
  shr    $0x8,%edx
  not    %edx
  sub    %edi,%esi
  and    %esi,%edx
  mov    %dl,0x2(%rax)
  movzbl 0x1(%rax),%esi
  movzbl %ch,%edi
  movzbl %sil,%edx
  sub    %edi,%edx
  shr    $0x8,%edx
  not    %edx
  sub    %edi,%esi
  and    %esi,%edx
  mov    %dl,0x1(%rax)
  movzbl (%rax),%esi
  movzbl %sil,%edx
  movzbl %cl,%edi
  sub    %edi,%edx
  shr    $0x8,%edx
  not    %edx
  sub    %ecx,%esi
  and    %esi,%edx
  mov    %dl,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void __imlib_SubCopyToRGBA(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  ((unsigned char *)(dst))[3] = ((unsigned char *)(&color))[3];
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__imlib_SubCopyToRGBA>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  push   %rbx
  shr    $0x10,%edi
  shr    $0x18,%edx
  movzbl %dil,%r8d
  mov    %rsi,%rax
  mov    %dl,0x3(%rsi)
  movzbl 0x2(%rsi),%edx
  pop    %rbx
  mov    %edx,%esi
  sub    %r8d,%edx
  shr    $0x8,%edx
  sub    %edi,%esi
  movzbl %ch,%edi
  not    %edx
  and    %esi,%edx
  mov    %dl,0x2(%rax)
  movzbl 0x1(%rax),%edx
  mov    %edx,%esi
  sub    %edi,%edx
  shr    $0x8,%edx
  sub    %edi,%esi
  movzbl %cl,%edi
  not    %edx
  and    %esi,%edx
  mov    %dl,0x1(%rax)
  movzbl (%rax),%edx
  mov    %edx,%esi
  sub    %edi,%edx
  shr    $0x8,%edx
  sub    %ecx,%esi
  not    %edx
  and    %esi,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void __imlib_SubCopyToRGBA(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  ((unsigned char *)(dst))[3] = ((unsigned char *)(&color))[3];
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__imlib_SubCopyToRGBA>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  push   %rbx
  shr    $0x10,%edi
  shr    $0x18,%edx
  movzbl %dil,%r8d
  mov    %rsi,%rax
  mov    %dl,0x3(%rsi)
  movzbl 0x2(%rsi),%edx
  pop    %rbx
  mov    %edx,%esi
  sub    %r8d,%edx
  shr    $0x8,%edx
  sub    %edi,%esi
  movzbl %ch,%edi
  not    %edx
  and    %esi,%edx
  mov    %dl,0x2(%rax)
  movzbl 0x1(%rax),%edx
  mov    %edx,%esi
  sub    %edi,%edx
  shr    $0x8,%edx
  sub    %edi,%esi
  movzbl %cl,%edi
  not    %edx
  and    %esi,%edx
  mov    %dl,0x1(%rax)
  movzbl (%rax),%edx
  mov    %edx,%esi
  sub    %edi,%edx
  shr    $0x8,%edx
  sub    %ecx,%esi
  not    %edx
  and    %esi,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void __imlib_SubCopyToRGBA(unsigned int color, unsigned int *dst) {
  unsigned int tmp;
  ((unsigned char *)(dst))[3] = ((unsigned char *)(&color))[3];
  do {
    tmp = (((unsigned char *)(dst))[2]) - (((unsigned char *)(&color))[2]);
    ((unsigned char *)(dst))[2] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[1]) - (((unsigned char *)(&color))[1]);
    ((unsigned char *)(dst))[1] = (tmp & (~(tmp >> 8)));
    ;
    tmp = (((unsigned char *)(dst))[0]) - (((unsigned char *)(&color))[0]);
    ((unsigned char *)(dst))[0] = (tmp & (~(tmp >> 8)));
    ;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<devicetree_raw_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <big_to_little@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xd00dfeed,-0x18(%rbp)
  je     L36
  mov    $0xffffffed,%eax
  jmp    L10
L36:
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <big_to_little@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L2
L17:
  mov    -0x1c(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L15
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
L15:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L2:
  mov    -0x20(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D33
type_infered: string

tool: D25: BEGIN DT DUMP OF SIZE %d


tool: D2: 


tool: D20: %d 

tool: D33: 
END DT DUMP


assistant: ```c
int32_t devicetree_raw_dump(uint32_t *dt_ptr) {
  uint32_t *dt;
  uint32_t magic, size;
  char *ptr;
  int i, count;
  dt = dt_ptr;
  magic = big_to_little(dt[0]);
  if (magic != 0xd00dfeed) {
    return -19;
  }
  size = big_to_little(dt[1]);
  printk("BEGIN DT DUMP OF SIZE %d\n", size);
  count = 0;
  ptr = (char *)dt_ptr;
  for (i = 0; i < size; i++) {
    if ((count & 0xf) == 0)
      printk("\n");
    printk("%d ", ptr[i]);
    count++;
  }
  printk("\nEND DT DUMP\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<devicetree_raw_dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    (%rdi),%edi
  call   <big_to_little@plt>
  cmp    $0xd00dfeed,%eax
  jne    L41
  mov    0x4(%r12),%edi
  call   <big_to_little@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  test   %ebp,%ebp
  jle    L44
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D11(%rip),%r14
  lea    D2(%rip),%r13
  jmp    L27
L69:
  movsbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L44
L27:
  test   $0xf,%bl
  jne    L69
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  jmp    L69
L44:
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%eax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  mov    $0xffffffed,%eax
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D33
data_type: string

tool: D16: BEGIN DT DUMP OF SIZE %d


tool: D11: 


tool: D2: %d 

tool: D33: 
END DT DUMP


assistant: ```c
int32_t devicetree_raw_dump(uint32_t *dt_ptr) {
  uint32_t *dt;
  uint32_t magic, size;
  char *ptr;
  int i, count;
  dt = dt_ptr;
  magic = big_to_little(dt[0]);
  if (magic != 0xd00dfeed) {
    return -19;
  }
  size = big_to_little(dt[1]);
  printk("BEGIN DT DUMP OF SIZE %d\n", size);
  count = 0;
  ptr = (char *)dt_ptr;
  for (i = 0; i < size; i++) {
    if ((count & 0xf) == 0)
      printk("\n");
    printk("%d ", ptr[i]);
    count++;
  }
  printk("\nEND DT DUMP\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<devicetree_raw_dump>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%edi
  call   <big_to_little@plt>
  cmp    $0xd00dfeed,%eax
  jne    L48
  mov    0x4(%r12),%edi
  call   <big_to_little@plt>
  lea    D20(%rip),%rdi
  movslq %eax,%rbp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printk@plt>
  test   %ebp,%ebp
  jle    L41
  xor    %ebx,%ebx
  lea    D18(%rip),%r13
  lea    D10(%rip),%r14
  jmp    L11
L34:
  movsbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printk@plt>
  cmp    %rbp,%rbx
  je     L41
L11:
  test   $0xf,%bl
  jne    L34
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printk@plt>
  jmp    L34
  nopl   0x0(%rax)
L41:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  xor    %eax,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  mov    $0xffffffed,%eax
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string

tool: D20: BEGIN DT DUMP OF SIZE %d


tool: D18: %d 

tool: D10: 


tool: D38: 
END DT DUMP


assistant: ```c
int32_t devicetree_raw_dump(uint32_t *dt_ptr) {
  uint32_t *dt;
  uint32_t magic, size;
  char *ptr;
  int i, count;
  dt = dt_ptr;
  magic = big_to_little(dt[0]);
  if (magic != 0xd00dfeed) {
    return -19;
  }
  size = big_to_little(dt[1]);
  printk("BEGIN DT DUMP OF SIZE %d\n", size);
  count = 0;
  ptr = (char *)dt_ptr;
  for (i = 0; i < size; i++) {
    if ((count & 0xf) == 0)
      printk("\n");
    printk("%d ", ptr[i]);
    count++;
  }
  printk("\nEND DT DUMP\n");
  return 0;
}
```