ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<rfile_fn_rel2abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  mov    (%rax),%r15d
  add    %r15d,%r15d
  movslq %r15d,%r14
  lea    0xf(%r14),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L113:
  cmp    %rdx,%rsp
  je     L79
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L113
L79:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L56
  orq    $0x0,-0x8(%rsp,%rax,1)
L56:
  mov    %rsp,%r13
  mov    %r12,%rdi
  call   <rfile_fn_is_abs@plt>
  test   %rax,%rax
  jne    L75
  test   %rbx,%rbx
  je     L68
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <rfile_fn_rel2abs>
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%rax
  cmp    %rax,%r14
  jb     L112
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdi
  call   <free@plt>
L51:
  cmpb   $0x2f,-0x1(%r13,%rbx,1)
  je     L100
  movb   $0x2f,0x0(%r13,%rbx,1)
  lea    0x1(%rbx),%rbx
  jmp    L100
L112:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L50
L68:
  lea    -0x1(%r15),%esi
  mov    %r13,%rdi
  call   <getcwd@plt>
  mov    %eax,%edx
  mov    %rbx,%rax
  test   %edx,%edx
  je     L50
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  jmp    L51
L75:
  mov    $0x0,%ebx
L100:
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rax
  cmp    %rax,%r14
  jb     L103
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <rfile_fn_tidy@plt>
L50:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L103:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L50
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rfile_fn_rel2abs(const char *rel, const char *base) {
  char bd[MAXPATHLEN * 2];
  size_t blen, rlen;
  if (rfile_fn_is_abs(rel)) {
    blen = 0;
  } else {
    if (base) {
      char *ab = rfile_fn_rel2abs(base, NULL);
      blen = strlen(ab);
      if (blen + 1 > sizeof(bd)) {
        errno = EINVAL;
        return NULL;
      }
      memcpy(bd, ab, blen);
      free(ab);
    } else {
      if (!getcwd(bd, sizeof(bd) - 1))
        return NULL;
      blen = strlen(bd);
    }
    if (bd[blen - 1] != '/')
      bd[blen++] = '/';
  }
  bd[blen] = '\0';
  rlen = strlen(rel) + 1;
  if (blen + rlen > sizeof(bd)) {
    errno = EINVAL;
    return NULL;
  }
  memcpy(bd + blen, rel, rlen);
  return rfile_fn_tidy(bd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfile_fn_rel2abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D3(%rip),%rax
  mov    %rsp,%rcx
  mov    (%rax),%ebx
  add    %ebx,%ebx
  movslq %ebx,%r14
  lea    0xf(%r14),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L100
L111:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L111
L100:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L75
L109:
  mov    %r12,%rdi
  mov    %rsp,%r13
  call   <rfile_fn_is_abs@plt>
  test   %rax,%rax
  jne    L8
  test   %r15,%r15
  je     L20
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <rfile_fn_rel2abs>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%rax
  cmp    %rax,%r14
  jb     L76
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  mov    %r15,%rdi
  call   <free@plt>
L71:
  cmpb   $0x2f,-0x1(%r13,%rbx,1)
  je     L44
  movb   $0x2f,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L44:
  mov    %r12,%rdi
  movb   $0x0,0x0(%r13,%rbx,1)
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rax
  cmp    %rax,%r14
  jb     L76
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <rfile_fn_tidy@plt>
L29:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L110
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nop
L76:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %ebx,%ebx
  jmp    L44
  nopl   0x0(%rax)
L20:
  lea    -0x1(%rbx),%esi
  mov    %rsp,%rdi
  call   <getcwd@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L29
  mov    %rsp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  jmp    L71
  nopl   (%rax)
L75:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L109
L110:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rfile_fn_rel2abs(const char *rel, const char *base) {
  char bd[MAXPATHLEN * 2];
  size_t blen, rlen;
  if (rfile_fn_is_abs(rel)) {
    blen = 0;
  } else {
    if (base) {
      char *ab = rfile_fn_rel2abs(base, NULL);
      blen = strlen(ab);
      if (blen + 1 > sizeof(bd)) {
        errno = EINVAL;
        return NULL;
      }
      memcpy(bd, ab, blen);
      free(ab);
    } else {
      if (!getcwd(bd, sizeof(bd) - 1))
        return NULL;
      blen = strlen(bd);
    }
    if (bd[blen - 1] != '/')
      bd[blen++] = '/';
  }
  bd[blen] = '\0';
  rlen = strlen(rel) + 1;
  if (blen + rlen > sizeof(bd)) {
    errno = EINVAL;
    return NULL;
  }
  memcpy(bd + blen, rel, rlen);
  return rfile_fn_tidy(bd);
}
```
user: What is the c source code of the assembly code below?

```asm
<rfile_fn_rel2abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D11(%rip),%rax
  mov    %rsp,%rcx
  mov    (%rax),%ebx
  add    %ebx,%ebx
  movslq %ebx,%r14
  lea    0xf(%r14),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L114
L58:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L58
L114:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L0
L91:
  mov    %r12,%rdi
  mov    %rsp,%r13
  call   <rfile_fn_is_abs@plt>
  test   %rax,%rax
  jne    L13
  test   %r15,%r15
  je     L28
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <rfile_fn_rel2abs>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%rax
  cmp    %rax,%r14
  jb     L1
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  mov    %r15,%rdi
  call   <free@plt>
L57:
  cmpb   $0x2f,-0x1(%r13,%rbx,1)
  je     L123
  movb   $0x2f,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L123:
  mov    %r12,%rdi
  movb   $0x0,0x0(%r13,%rbx,1)
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rax
  cmp    %rax,%r14
  jb     L1
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <rfile_fn_tidy@plt>
L52:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L121
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nop
L1:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %ebx,%ebx
  jmp    L123
  nopl   0x0(%rax)
L28:
  lea    -0x1(%rbx),%esi
  mov    %rsp,%rdi
  call   <getcwd@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L52
  mov    %rsp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  jmp    L57
  nopl   (%rax)
L0:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L91
L121:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *rfile_fn_rel2abs(const char *rel, const char *base) {
  char bd[MAXPATHLEN * 2];
  size_t blen, rlen;
  if (rfile_fn_is_abs(rel)) {
    blen = 0;
  } else {
    if (base) {
      char *ab = rfile_fn_rel2abs(base, NULL);
      blen = strlen(ab);
      if (blen + 1 > sizeof(bd)) {
        errno = EINVAL;
        return NULL;
      }
      memcpy(bd, ab, blen);
      free(ab);
    } else {
      if (!getcwd(bd, sizeof(bd) - 1))
        return NULL;
      blen = strlen(bd);
    }
    if (bd[blen - 1] != '/')
      bd[blen++] = '/';
  }
  bd[blen] = '\0';
  rlen = strlen(rel) + 1;
  if (blen + rlen > sizeof(bd)) {
    errno = EINVAL;
    return NULL;
  }
  memcpy(bd + blen, rel, rlen);
  return rfile_fn_tidy(bd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <errx@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: xfree: NULL pointer given as argument

assistant: ```c
void xfree(void *ptr) {
  if (ptr == NULL)
    errx(1, "xfree: NULL pointer given as argument");
  free(ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xfree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L12
L0:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L12:
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: xfree: NULL pointer given as argument

assistant: ```c
void xfree(void *ptr) {
  if (ptr == NULL)
    errx(1, "xfree: NULL pointer given as argument");
  free(ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L3
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0x1,%edi
  lea    D7(%rip),%rsi
  call   <errx@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: xfree: NULL pointer given as argument

assistant: ```c
void xfree(void *ptr) {
  if (ptr == NULL)
    errx(1, "xfree: NULL pointer given as argument");
  free(ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0x1,%edi
  lea    D0(%rip),%rsi
  call   <errx@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: xfree: NULL pointer given as argument

assistant: ```c
void xfree(void *ptr) {
  if (ptr == NULL)
    errx(1, "xfree: NULL pointer given as argument");
  free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readfd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L19
  jmp    L25
L9:
  nop
L25:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t readfd(int fd, char *buf, size_t size) {
  size_t len = size;
  ssize_t rlen;
  do {
    rlen = read(fd, buf, len);
    if (rlen < 0) {
      if (errno == EINTR)
        continue;
      perror("read()");
      goto fail;
    }
    if (rlen == 0)
      break;
    buf += rlen;
    len -= rlen;
  } while (len > 0);
  rlen = size - len;
fail:
  return rlen;
}
```
user: What is the c source code of the assembly code below?

```asm
<readfd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdx,%rbx
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L9
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L5
L9:
  mov    %r13,%rax
  sub    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readfd(int fd, char *buf, size_t size) {
  size_t len = size;
  ssize_t rlen;
  do {
    rlen = read(fd, buf, len);
    if (rlen < 0) {
      if (errno == EINTR)
        continue;
      perror("read()");
      goto fail;
    }
    if (rlen == 0)
      break;
    buf += rlen;
    len -= rlen;
  } while (len > 0);
  rlen = size - len;
fail:
  return rlen;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readfd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L21
  nopl   0x0(%rax)
L29:
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L22
L21:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L29
  add    $0x8,%rsp
  mov    %r13,%rax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readfd(int fd, char *buf, size_t size) {
  size_t len = size;
  ssize_t rlen;
  do {
    rlen = read(fd, buf, len);
    if (rlen < 0) {
      if (errno == EINTR)
        continue;
      perror("read()");
      goto fail;
    }
    if (rlen == 0)
      break;
    buf += rlen;
    len -= rlen;
  } while (len > 0);
  rlen = size - len;
fail:
  return rlen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readfd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L23
  nopl   0x0(%rax)
L1:
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L0
L23:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  mov    %r13,%rax
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readfd(int fd, char *buf, size_t size) {
  size_t len = size;
  ssize_t rlen;
  do {
    rlen = read(fd, buf, len);
    if (rlen < 0) {
      if (errno == EINTR)
        continue;
      perror("read()");
      goto fail;
    }
    if (rlen == 0)
      break;
    buf += rlen;
    len -= rlen;
  } while (len > 0);
  rlen = size - len;
fail:
  return rlen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply117>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L35
L23:
  movl   $0x0,-0x3c(%rbp)
  jmp    L28
L0:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L28:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  addl   $0x1,-0x40(%rbp)
L35:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L23
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply117(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply117>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L12:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L16:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L16
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

assistant: ```c
void multiply117(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply117>:
  endbr64
  test   %edi,%edi
  jle    L6
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L9
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L10
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void multiply117(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply117>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L18
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L52:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L84
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L84
  nopl   0x0(%rax)
L74:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L74
  cmp    -0x24(%rsp),%r11d
  je     L77
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L77
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L77
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L77:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L52
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L84:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L9:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L9
  mov    -0x18(%rsp),%r8
  jmp    L77
```

assistant: ```c
void multiply117(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BKDRHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x83,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L8:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L8
  mov    -0xc(%rbp),%edx
  mov    %edx,%ecx
  mov    $0xd2487055,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0xd,%eax
  imul   $0x26f5,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  leave
  ret
```

assistant: ```c
unsigned int BKDRHash(char *str) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  int i = 0;
  while (i < strlen(str)) {
    hash = hash * seed + *str++;
  }
  return (hash % 9973);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BKDRHash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L2
L19:
  imul   $0x83,%ebp,%ebp
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%eax
  add    %eax,%ebp
L2:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L19
  mov    %ebp,%eax
  mov    $0xd2487055,%edx
  imul   %rdx,%rax
  shr    $0x2d,%rax
  imul   $0x26f5,%eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int BKDRHash(char *str) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  int i = 0;
  while (i < strlen(str)) {
    hash = hash * seed + *str++;
  }
  return (hash % 9973);
}
```