user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D26(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebp
  cmp    $0x1,%ebp
  jle    L31
  lea    -0x2(%rax),%ecx
  sub    $0x3,%eax
  cmp    $0x7,%eax
  jbe    L57
  mov    %ecx,%edx
  movdqa D6(%rip),%xmm2
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D35(%rip),%xmm4
  shr    $0x2,%edx
  pcmpeqd %xmm3,%xmm3
  nopl   0x0(%rax,%rax,1)
L122:
  movdqa %xmm2,%xmm1
  paddd  %xmm3,%xmm0
  paddd  %xmm4,%xmm2
  add    $0x1,%eax
  pslld  $0x1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %eax,%edx
  jne    L122
  movdqa %xmm0,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  lea    0x1(%rdx),%eax
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  cmp    %ecx,%edx
  je     L220
L103:
  lea    (%rax,%rax,1),%edx
  lea    0x1(%rax),%ecx
  lea    -0x1(%rsi,%rdx,1),%esi
  cmp    %ebp,%ecx
  jge    L220
  lea    0x2(%rax),%ecx
  lea    0x1(%rsi,%rdx,1),%esi
  cmp    %ecx,%ebp
  jle    L220
  lea    0x3(%rax),%ecx
  lea    0x3(%rsi,%rdx,1),%esi
  cmp    %ecx,%ebp
  jle    L220
  lea    0x4(%rax),%ecx
  lea    0x5(%rsi,%rdx,1),%esi
  cmp    %ecx,%ebp
  jle    L220
  lea    0x5(%rax),%ecx
  lea    0x7(%rsi,%rdx,1),%esi
  cmp    %ecx,%ebp
  jle    L220
  lea    0x6(%rax),%ecx
  lea    0x9(%rsi,%rdx,1),%esi
  cmp    %ecx,%ebp
  jle    L220
  add    $0x7,%eax
  lea    0xb(%rsi,%rdx,1),%esi
  cmp    %eax,%ebp
  jle    L220
  lea    0xd(%rsi,%rdx,1),%esi
L220:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L13
  nopl   0x0(%rax)
L205:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L205
L13:
  mov    $0x2a,%edi
  jmp    L160
  nopw   0x0(%rax,%rax,1)
L138:
  mov    $0x20,%edi
L160:
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jg     L138
  mov    $0xa,%edi
  mov    $0x1,%ebp
  mov    $0x1,%r12d
  call   <putchar@plt>
  mov    0x4(%rsp),%ebx
  cmp    $0x2,%ebx
  jle    L257
  nopw   0x0(%rax,%rax,1)
L183:
  sub    %r12d,%ebx
  sub    $0x1,%ebx
  je     L207
  nopl   0x0(%rax,%rax,1)
L249:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L249
L207:
  mov    $0x2a,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L117:
  mov    $0x23,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L117
  mov    $0x2a,%edi
  mov    %r12d,%ebx
  call   <putchar@plt>
  not    %ebx
  add    0x4(%rsp),%ebx
  je     L185
  cs nopw 0x0(%rax,%rax,1)
L266:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L266
L185:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x2,%ebp
  call   <putchar@plt>
  mov    0x4(%rsp),%ebx
  lea    -0x1(%rbx),%eax
  cmp    %r12d,%eax
  jg     L183
L257:
  add    %ebx,%ebx
  xor    %ebp,%ebp
  cmp    $0x1,%ebx
  jle    L22
  nopl   0x0(%rax)
L12:
  mov    $0x2a,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rax,1),%eax
  cmp    %ebp,%eax
  jg     L12
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  xor    %esi,%esi
  mov    $0x1,%ebp
  jmp    L220
L57:
  xor    %esi,%esi
  mov    $0x1,%eax
  jmp    L103
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D6
datatype: byte[16]
name: retrieve_data
arguments: label: D35
datatype: byte[16]
name: retrieve_data
arguments: label: D5
datatype: string

tool: D26: %d

tool: {"D6": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D35": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D5: %d


assistant: ```c
int main() {
  int i, n, k, l;
  l = 0;
  scanf("%d", &n);
  for (k = 1; k < n - 1; k++)
    for (i = 0; i < k * 2 - 1; i++) {
      l++;
    }
  printf("%d\n", l);
  for (i = 0; i < n - 1; i++)
    printf(" ");
  printf("*");
  for (i = 0; k < n - 1; i++)
    printf(" ");
  printf("\n");
  for (k = 1; k < n - 1; k++) {
    for (i = n - k - 1; i != 0; i--)
      printf(" ");
    { printf("*"); }
    for (i = 0; i < k * 2 - 1; i++)
      printf("#");
    { printf("*"); }
    for (i = n - k - 1; i != 0; i--)
      printf(" ");
    { printf("\n"); }
  }
  for (i = 0; i < n * 2 - 1; i++) {
    printf("*");
  }
  return 0;
}
```