ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<cmdline_parser_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_given@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_args@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <init_args_info@plt>
  nop
  leave
  ret
```

assistant: ```c
void cmdline_parser_init(struct gengetopt_args_info *args_info) {
  clear_given(args_info);
  clear_args(args_info);
  init_args_info(args_info);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmdline_parser_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <clear_given@plt>
  mov    %rbx,%rdi
  call   <clear_args@plt>
  mov    %rbx,%rdi
  call   <init_args_info@plt>
  pop    %rbx
  ret
```

assistant: ```c
void cmdline_parser_init(struct gengetopt_args_info *args_info) {
  clear_given(args_info);
  clear_args(args_info);
  init_args_info(args_info);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmdline_parser_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <clear_given@plt>
  mov    %rbp,%rdi
  call   <clear_args@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <init_args_info@plt>
```

assistant: ```c
void cmdline_parser_init(struct gengetopt_args_info *args_info) {
  clear_given(args_info);
  clear_args(args_info);
  init_args_info(args_info);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmdline_parser_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <clear_given@plt>
  mov    %rbp,%rdi
  call   <clear_args@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <init_args_info@plt>
```

assistant: ```c
void cmdline_parser_init(struct gengetopt_args_info *args_info) {
  clear_given(args_info);
  clear_args(args_info);
  init_args_info(args_info);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partitionEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x40(%rbp),%rax
  lea    -0x40(%rbp),%rdx
  movl   $0xfa1e0ff3,(%rax)
  movw   $0xbb49,0x4(%rax)
  lea    -0x68(%rip),%rcx        # 1139 <_acceptEven.0>
  mov    %rcx,0x6(%rax)
  movw   $0xba49,0xe(%rax)
  mov    %rdx,0x10(%rax)
  movl   $0x90e3ff49,0x18(%rax)
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L14:
  cmp    %rdx,%rsp
  je     L16
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L16:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L22
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L22:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x48(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rsi
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <partitionGeneric@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void partitionEven(int value) {
  int _acceptEven(int nextValue, int *partition, int offset) { return nextValue % 2 == 0; }
  int partition[value];
  partitionGeneric(value, partition, 0, _acceptEven);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<partitionEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L33:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L0:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L31
  orq    $0x0,-0x8(%rsp,%rax,1)
L31:
  mov    %rsp,%rsi
  lea    -0x7d(%rip),%rcx        # 1139 <_acceptEven.0>
  mov    $0x0,%edx
  mov    $0x0,%eax
  call   <partitionGeneric@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  leave
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void partitionEven(int value) {
  int _acceptEven(int nextValue, int *partition, int offset) { return nextValue % 2 == 0; }
  int partition[value];
  partitionGeneric(value, partition, 0, _acceptEven);
}
```
user: What is the c source code of the assembly code below:

```asm
<partitionEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L24
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L3
L24:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L41:
  xor    %edx,%edx
  xor    %eax,%eax
  lea    -0x7c(%rip),%rcx        # 1140 <_acceptEven.0>
  mov    %rsp,%rsi
  call   <partitionGeneric@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  leave
  ret
  nopl   (%rax)
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L41
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void partitionEven(int value) {
  int _acceptEven(int nextValue, int *partition, int offset) { return nextValue % 2 == 0; }
  int partition[value];
  partitionGeneric(value, partition, 0, _acceptEven);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partitionEven>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L30
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L22
L30:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L11
L4:
  xor    %edx,%edx
  xor    %eax,%eax
  lea    -0x7c(%rip),%rcx        # 1140 <_acceptEven.0>
  mov    %rsp,%rsi
  call   <partitionGeneric@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  leave
  ret
  nopl   (%rax)
L11:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L4
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void partitionEven(int value) {
  int _acceptEven(int nextValue, int *partition, int offset) { return nextValue % 2 == 0; }
  int partition[value];
  partitionGeneric(value, partition, 0, _acceptEven);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L22
L11:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%ecx
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x28(%rbp)
L22:
  mov    -0x28(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L11
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int bin2hex(const unsigned char *bin, char *hex, const int len) {
  int i, idx;
  char hex_char[] = "0123456789ABCDEF";
  for (i = 0, idx = 0; i < len; i++) {
    hex[idx++] = hex_char[(bin[i] & 0xf0) >> 4];
    hex[idx++] = hex_char[bin[i] & 0x0f];
  }
  hex[idx] = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bin2hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%r9
  movabs $0x4645444342413938,%r10
  mov    %r9,(%rsp)
  mov    %r10,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  test   %edx,%edx
  jle    L34
  mov    %rdi,%r8
  mov    %edx,%edi
L8:
  movzbl (%r8,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rsi,%rax,2)
  movzbl (%r8,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L8
  add    %edx,%edx
L33:
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L34:
  mov    $0x0,%edx
  jmp    L33
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bin2hex(const unsigned char *bin, char *hex, const int len) {
  int i, idx;
  char hex_char[] = "0123456789ABCDEF";
  for (i = 0, idx = 0; i < len; i++) {
    hex[idx++] = hex_char[(bin[i] & 0xf0) >> 4];
    hex[idx++] = hex_char[bin[i] & 0x0f];
  }
  hex[idx] = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bin2hex>:
  endbr64
  sub    $0x28,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L22
  mov    %rdi,%r8
  movslq %edx,%rdi
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl (%r8,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rsi,%rax,2)
  movzbl (%r8,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L1
  add    %edx,%edx
  movslq %edx,%rdx
  add    %rdx,%rsi
L22:
  movb   $0x0,(%rsi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: byte[16]

tool: {"D9": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
int bin2hex(const unsigned char *bin, char *hex, const int len) {
  int i, idx;
  char hex_char[] = "0123456789ABCDEF";
  for (i = 0, idx = 0; i < len; i++) {
    hex[idx++] = hex_char[(bin[i] & 0xf0) >> 4];
    hex[idx++] = hex_char[bin[i] & 0x0f];
  }
  hex[idx] = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bin2hex>:
  endbr64
  sub    $0x28,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L1
  mov    %rdi,%r8
  movslq %edx,%rdi
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%r8,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rsi,%rax,2)
  movzbl (%r8,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%rsi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L9
  add    %edx,%edx
  movslq %edx,%rdx
  add    %rdx,%rsi
L1:
  movb   $0x0,(%rsi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: byte[16]

tool: {"D5": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
int bin2hex(const unsigned char *bin, char *hex, const int len) {
  int i, idx;
  char hex_char[] = "0123456789ABCDEF";
  for (i = 0, idx = 0; i < len; i++) {
    hex[idx++] = hex_char[(bin[i] & 0xf0) >> 4];
    hex[idx++] = hex_char[bin[i] & 0x0f];
  }
  hex[idx] = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    $0x0,%eax
  jmp    L11
L16:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <fun>
  add    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
int fun(char *a) {
  if (!*a)
    return 0;
  return fun(a + 1) + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  add    $0x1,%rdi
  call   <fun>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fun(char *a) {
  if (!*a)
    return 0;
  return fun(a + 1) + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fun>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L19
  nopl   0x0(%rax)
L3:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L3
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun(char *a) {
  if (!*a)
    return 0;
  return fun(a + 1) + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L7
  nopl   0x0(%rax)
L12:
  add    $0x1,%rdi
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,(%rdi)
  jne    L12
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun(char *a) {
  if (!*a)
    return 0;
  return fun(a + 1) + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SupportedLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L23
  cmpl   $0x200,-0x4(%rbp)
  jle    L0
L23:
  mov    $0x0,%eax
  jmp    L12
L0:
  mov    $0x1,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int SupportedLength(int hashbitlen) {
  if (hashbitlen <= 0 || hashbitlen > 512)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SupportedLength>:
  endbr64
  sub    $0x1,%edi
  cmp    $0x1ff,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int SupportedLength(int hashbitlen) {
  if (hashbitlen <= 0 || hashbitlen > 512)
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SupportedLength>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x1ff,%edi
  setbe  %al
  ret
```

assistant: ```c
int SupportedLength(int hashbitlen) {
  if (hashbitlen <= 0 || hashbitlen > 512)
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SupportedLength>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x1ff,%edi
  setbe  %al
  ret
```

assistant: ```c
int SupportedLength(int hashbitlen) {
  if (hashbitlen <= 0 || hashbitlen > 512)
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<THMemoryFile_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x72,%al
  jne    L77
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L78
L77:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x77,%al
  jne    L12
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L78
L42:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x72,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x77,%al
  jne    L12
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L78
L12:
  mov    $0x0,%eax
L78:
  leave
  ret
```

assistant: ```c
int THMemoryFile_mode(const char *mode, int *isReadable, int *isWritable) {
  *isReadable = 0;
  *isWritable = 0;
  if (strlen(mode) == 1) {
    if (*mode == 'r') {
      *isReadable = 1;
      return 1;
    } else if (*mode == 'w') {
      *isWritable = 1;
      return 1;
    }
  } else if (strlen(mode) == 2) {
    if (mode[0] == 'r' && mode[1] == 'w') {
      *isReadable = 1;
      *isWritable = 1;
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<THMemoryFile_mode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L68
  movzbl (%rbx),%edx
  cmp    $0x72,%dl
  je     L18
  cmp    $0x77,%dl
  je     L61
  mov    $0x0,%eax
  jmp    L53
L18:
  movl   $0x1,0x0(%rbp)
  jmp    L53
L61:
  movl   $0x1,(%r12)
  jmp    L53
L68:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x2,%edx
  je     L1
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  cmpb   $0x72,(%rbx)
  jne    L53
  cmpb   $0x77,0x1(%rbx)
  jne    L53
  movl   $0x1,0x0(%rbp)
  movl   $0x1,(%r12)
  mov    $0x1,%eax
  jmp    L53
```

assistant: ```c
int THMemoryFile_mode(const char *mode, int *isReadable, int *isWritable) {
  *isReadable = 0;
  *isWritable = 0;
  if (strlen(mode) == 1) {
    if (*mode == 'r') {
      *isReadable = 1;
      return 1;
    } else if (*mode == 'w') {
      *isWritable = 1;
      return 1;
    }
  } else if (strlen(mode) == 2) {
    if (mode[0] == 'r' && mode[1] == 'w') {
      *isReadable = 1;
      *isWritable = 1;
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<THMemoryFile_mode>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L51
  movzbl (%rbx),%edx
  cmp    $0x72,%dl
  je     L47
  cmp    $0x77,%dl
  je     L26
L5:
  xor    %eax,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L5
  cmpb   $0x72,(%rbx)
  jne    L5
  cmpb   $0x77,0x1(%rbx)
  jne    L5
  movl   $0x1,0x0(%rbp)
  mov    $0x1,%eax
  movl   $0x1,(%r12)
  jmp    L13
  xchg   %ax,%ax
L47:
  pop    %rbx
  movl   $0x1,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  movl   $0x1,(%r12)
  jmp    L13
```

assistant: ```c
int THMemoryFile_mode(const char *mode, int *isReadable, int *isWritable) {
  *isReadable = 0;
  *isWritable = 0;
  if (strlen(mode) == 1) {
    if (*mode == 'r') {
      *isReadable = 1;
      return 1;
    } else if (*mode == 'w') {
      *isWritable = 1;
      return 1;
    }
  } else if (strlen(mode) == 2) {
    if (mode[0] == 'r' && mode[1] == 'w') {
      *isReadable = 1;
      *isWritable = 1;
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<THMemoryFile_mode>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L51
  movzbl (%rbx),%edx
  cmp    $0x72,%dl
  je     L69
  cmp    $0x77,%dl
  je     L67
L26:
  xor    %eax,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jne    L26
  cmpb   $0x72,(%rbx)
  jne    L26
  cmpb   $0x77,0x1(%rbx)
  jne    L26
  movl   $0x1,0x0(%rbp)
  mov    $0x1,%eax
  movl   $0x1,(%r12)
  jmp    L28
  xchg   %ax,%ax
L69:
  pop    %rbx
  movl   $0x1,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L67:
  movl   $0x1,(%r12)
  jmp    L28
```

assistant: ```c
int THMemoryFile_mode(const char *mode, int *isReadable, int *isWritable) {
  *isReadable = 0;
  *isWritable = 0;
  if (strlen(mode) == 1) {
    if (*mode == 'r') {
      *isReadable = 1;
      return 1;
    } else if (*mode == 'w') {
      *isWritable = 1;
      return 1;
    }
  } else if (strlen(mode) == 2) {
    if (mode[0] == 'r' && mode[1] == 'w') {
      *isReadable = 1;
      *isWritable = 1;
      return 1;
    }
  }
  return 0;
}
```