ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<get_input>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  mov    $0x64,%edi
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L43
  mov    $0x1,%ebx
  jmp    L15
  nopl   0x0(%rax)
L10:
  add    $0x1,%rbx
  cmp    $0x65,%rbx
  je     L77
L15:
  mov    %al,-0x1(%r13,%rbx,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  jne    L10
  cmp    $0x64,%ebx
  je     L8
L43:
  mov    %r13,%rdi
  call   <parse_raw_input@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpb   $0xa,0x7(%rsp)
  jne    L77
L8:
  lea    D5(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L39
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: D10: %c

tool: D5: Error: Input length exceeds 100 characters.

assistant: ```c
int get_input(void) {
  char c;
  char *input = calloc(100, sizeof(char));
  int j = 0;
  scanf("%c", &c);
  while (c != '\n' && j < 100) {
    input[j++] = c;
    scanf("%c", &c);
  }
  if (j >= 100) {
    while (c != '\n')
      scanf("%c", &c);
    puts("Error: Input length exceeds 100 characters.");
    free(input);
    return 1;
  }
  int return_val = parse_raw_input(input);
  free(input);
  return return_val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_input>:
  endbr64
  push   %r14
  mov    $0x1,%esi
  mov    $0x64,%edi
  push   %r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L59
  mov    $0x1,%ebx
  jmp    L40
  nopl   0x0(%rax)
L52:
  add    $0x1,%rbx
  cmp    $0x65,%rbx
  je     L36
L40:
  mov    %al,-0x1(%r13,%rbx,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  jne    L52
  cmp    $0x64,%ebx
  je     L13
L59:
  mov    %r13,%rdi
  call   <parse_raw_input@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpb   $0xa,0x7(%rsp)
  jne    L36
L13:
  lea    D4(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L10
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D8: %c

tool: D4: Error: Input length exceeds 100 characters.

assistant: ```c
int get_input(void) {
  char c;
  char *input = calloc(100, sizeof(char));
  int j = 0;
  scanf("%c", &c);
  while (c != '\n' && j < 100) {
    input[j++] = c;
    scanf("%c", &c);
  }
  if (j >= 100) {
    while (c != '\n')
      scanf("%c", &c);
    puts("Error: Input length exceeds 100 characters.");
    free(input);
    return 1;
  }
  int return_val = parse_raw_input(input);
  free(input);
  return return_val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<threadscan_util_randomize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L9:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x1f,%eax
  sub    %edx,%eax
  mov    -0x1c(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L26
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L26:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jb     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void threadscan_util_randomize(size_t *addrs, int n) {
  unsigned int i;
  for (i = 0; i < n; ++i) {
    unsigned int tmp = (i * 2147483647) % n;
    if (i != tmp) {
      swap(addrs, i, tmp);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<threadscan_util_randomize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  test   %esi,%esi
  jne    L21
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <swap@plt>
L21:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  je     L28
  mov    %ebx,%eax
  shl    $0x1f,%eax
  sub    %ebx,%eax
  mov    $0x0,%edx
  div    %ebp
  cmp    %ebx,%edx
  jne    L27
  jmp    L21
```

assistant: ```c
void threadscan_util_randomize(size_t *addrs, int n) {
  unsigned int i;
  for (i = 0; i < n; ++i) {
    unsigned int tmp = (i * 2147483647) % n;
    if (i != tmp) {
      swap(addrs, i, tmp);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<threadscan_util_randomize>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  test   %esi,%esi
  je     L5
L31:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  je     L5
L13:
  mov    %ebx,%eax
  xor    %edx,%edx
  shl    $0x1f,%eax
  sub    %ebx,%eax
  div    %ebp
  cmp    %ebx,%edx
  je     L31
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <swap@plt>
  cmp    %ebp,%ebx
  jne    L13
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void threadscan_util_randomize(size_t *addrs, int n) {
  unsigned int i;
  for (i = 0; i < n; ++i) {
    unsigned int tmp = (i * 2147483647) % n;
    if (i != tmp) {
      swap(addrs, i, tmp);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<threadscan_util_randomize>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  cmp    $0x1,%esi
  jbe    L18
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%eax
  xor    %edx,%edx
  shl    $0x1f,%eax
  sub    %ebx,%eax
  div    %ebp
  cmp    %edx,%ebx
  je     L10
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <swap@plt>
  cmp    %ebp,%ebx
  jne    L4
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void threadscan_util_randomize(size_t *addrs, int n) {
  unsigned int i;
  for (i = 0; i < n; ++i) {
    unsigned int tmp = (i * 2147483647) % n;
    if (i != tmp) {
      swap(addrs, i, tmp);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove_bad4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void memmove_bad4() {
  int src[1];
  int buff[1];
  int *dst = &buff[0];
  memmove(dst, src, sizeof(dst));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove_bad4>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  call   <memmove@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_bad4() {
  int src[1];
  int buff[1];
  int *dst = &buff[0];
  memmove(dst, src, sizeof(dst));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove_bad4>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  call   <memmove@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_bad4() {
  int src[1];
  int buff[1];
  int *dst = &buff[0];
  memmove(dst, src, sizeof(dst));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memmove_bad4>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  call   <memmove@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void memmove_bad4() {
  int src[1];
  int buff[1];
  int *dst = &buff[0];
  memmove(dst, src, sizeof(dst));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  call   <challenge_any_one@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  adainit();
  challenge_run();
  challenge_run();
  challenge_any_one();
  challenge_run();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  call   <challenge_any_one@plt>
  mov    $0x0,%eax
  call   <challenge_run@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  adainit();
  challenge_run();
  challenge_run();
  challenge_any_one();
  challenge_run();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <adainit@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  call   <challenge_any_one@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  adainit();
  challenge_run();
  challenge_run();
  challenge_any_one();
  challenge_run();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <adainit@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  call   <challenge_any_one@plt>
  xor    %eax,%eax
  call   <challenge_run@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  adainit();
  challenge_run();
  challenge_run();
  challenge_any_one();
  challenge_run();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mem_init@plt>
  mov    $0x0,%eax
  call   <DO_STH_PRODUCTIVE@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  mem_init();
  DO_STH_PRODUCTIVE();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mem_init@plt>
  mov    $0x0,%eax
  call   <DO_STH_PRODUCTIVE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mem_init();
  DO_STH_PRODUCTIVE();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mem_init@plt>
  xor    %eax,%eax
  call   <DO_STH_PRODUCTIVE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mem_init();
  DO_STH_PRODUCTIVE();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mem_init@plt>
  xor    %eax,%eax
  call   <DO_STH_PRODUCTIVE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  mem_init();
  DO_STH_PRODUCTIVE();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <acc_init@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <acc_init@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  acc_device_t devtype = acc_device_host;
  acc_init(devtype);
  acc_init(devtype);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rax
  mov    (%rax),%ebx
  mov    %ebx,%edi
  call   <acc_init@plt>
  mov    %ebx,%edi
  call   <acc_init@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  acc_device_t devtype = acc_device_host;
  acc_init(devtype);
  acc_init(devtype);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    D6(%rip),%rax
  push   %rbp
  mov    (%rax),%ebp
  mov    %ebp,%edi
  call   <acc_init@plt>
  mov    %ebp,%edi
  call   <acc_init@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  acc_device_t devtype = acc_device_host;
  acc_init(devtype);
  acc_init(devtype);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    D5(%rip),%rax
  push   %rbp
  mov    (%rax),%ebp
  mov    %ebp,%edi
  call   <acc_init@plt>
  mov    %ebp,%edi
  call   <acc_init@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  acc_device_t devtype = acc_device_host;
  acc_init(devtype);
  acc_init(devtype);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x20(%rbp)
  jge    L55
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L14
L24:
  mov    -0xc(%rbp),%eax
  jmp    L36
L14:
  mov    -0x8(%rbp),%eax
L36:
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L1
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swp@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <heapify>
  jmp    L1
L55:
  nop
L1:
  leave
  ret
```

assistant: ```c
void heapify(int *a, int len, int i) {
  if (i >= len / 2)
    return;
  int il = 2 * i + 1;
  int ir = 2 * i + 2;
  int im = ir >= len || a[il] > a[ir] ? il : ir;
  if (a[i] < a[im]) {
    swp(a, i, im);
    heapify(a, len, im);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %edx,%eax
  jle    L8
  mov    %rdi,%rbp
  mov    %edx,%esi
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%r12d
  add    $0x2,%eax
  cmp    %eax,%ebx
  jle    L21
  movslq %r12d,%rcx
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  cmovle %eax,%r12d
L21:
  movslq %esi,%rax
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jl     L4
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <swp@plt>
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <heapify>
  jmp    L8
```

assistant: ```c
void heapify(int *a, int len, int i) {
  if (i >= len / 2)
    return;
  int il = 2 * i + 1;
  int ir = 2 * i + 2;
  int im = ir >= len || a[il] > a[ir] ? il : ir;
  if (a[i] < a[im]) {
    swp(a, i, im);
    heapify(a, len, im);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heapify>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  mov    %esi,%ebp
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    %r12d,%edx
  jge    L21
  mov    %rdi,%r13
  mov    %edx,%esi
  jmp    L54
  nopl   0x0(%rax)
L16:
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <swp@plt>
  cmp    %r12d,%ebx
  jge    L21
  mov    %ebx,%esi
L54:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%ebx
  add    $0x2,%eax
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %eax,%ebp
  jle    L50
  movslq %eax,%rcx
  mov    0x0(%r13,%rcx,4),%ecx
  cmp    %edx,%ecx
  jl     L50
  mov    %ecx,%edx
  mov    %eax,%ebx
L50:
  movslq %esi,%rax
  cmp    %edx,0x0(%r13,%rax,4)
  jl     L16
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapify(int *a, int len, int i) {
  if (i >= len / 2)
    return;
  int il = 2 * i + 1;
  int ir = 2 * i + 2;
  int im = ir >= len || a[il] > a[ir] ? il : ir;
  if (a[i] < a[im]) {
    swp(a, i, im);
    heapify(a, len, im);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapify>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  mov    %esi,%ebp
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    %r12d,%edx
  jge    L34
  mov    %rdi,%r13
  mov    %edx,%esi
  jmp    L44
  nopl   0x0(%rax)
L43:
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <swp@plt>
  cmp    %r12d,%ebx
  jge    L34
  mov    %ebx,%esi
L44:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%ebx
  add    $0x2,%eax
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %eax,%ebp
  jle    L36
  movslq %eax,%rcx
  mov    0x0(%r13,%rcx,4),%ecx
  cmp    %edx,%ecx
  jl     L36
  mov    %ecx,%edx
  mov    %eax,%ebx
L36:
  movslq %esi,%rax
  cmp    %edx,0x0(%r13,%rax,4)
  jl     L43
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void heapify(int *a, int len, int i) {
  if (i >= len / 2)
    return;
  int il = 2 * i + 1;
  int ir = 2 * i + 2;
  int im = ir >= len || a[il] > a[ir] ? il : ir;
  if (a[i] < a[im]) {
    swp(a, i, im);
    heapify(a, len, im);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rdi
  mov    -0x50(%rbp),%ecx
  mov    -0x58(%rbp),%rdx
  mov    -0x4c(%rbp),%esi
  mov    -0x48(%rbp),%rax
  mov    $0x10,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <hmac_md5@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    $0x21,%ecx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <tohex@plt>
  movb   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  lea    -0x30(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L13:
  lea    -0x30(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D13: md5 cannot pass digst: %s, md5: %s


tool: D3: md5 pass digst: %s, md5: %s


assistant: ```c
void check(char *k, int klen, char *text, int textlen, char *digst) {
  char buff[16];
  char hex[33];
  hmac_md5(k, klen, text, textlen, buff, sizeof(buff));
  tohex(buff, sizeof(buff), hex, sizeof(hex));
  hex[32] = '\0';
  if (strcmp(digst, hex) != 0) {
    printf("md5 cannot pass digst: %s, md5: %s\n", digst, hex);
    return;
  }
  printf("md5 pass digst: %s, md5: %s\n", digst, hex);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x10,%r9d
  mov    %rbp,%r8
  call   <hmac_md5@plt>
  lea    0x10(%rsp),%r12
  mov    $0x21,%ecx
  mov    %r12,%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <tohex@plt>
  movb   $0x0,0x30(%rsp)
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L13
  lea    0x10(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D14: md5 pass digst: %s, md5: %s


tool: D6: md5 cannot pass digst: %s, md5: %s


assistant: ```c
void check(char *k, int klen, char *text, int textlen, char *digst) {
  char buff[16];
  char hex[33];
  hmac_md5(k, klen, text, textlen, buff, sizeof(buff));
  tohex(buff, sizeof(buff), hex, sizeof(hex));
  hex[32] = '\0';
  if (strcmp(digst, hex) != 0) {
    printf("md5 cannot pass digst: %s, md5: %s\n", digst, hex);
    return;
  }
  printf("md5 pass digst: %s, md5: %s\n", digst, hex);
}
```