ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%r8d
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %esi,%r8d
  jl     L9
  mov    %r8d,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <max@plt>
  mov    0x14(%rsp),%r8d
  mov    %eax,%esi
  cmp    %eax,%r8d
  jl     L46
  mov    %r8d,%esi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x28,%rsp
  ret
L9:
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L46:
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L44
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D49
type_infered: string
name: unpack_data
arguments: data_tag: D53
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D54
type_infered: string

tool: D49: Enter the x,y,z:

tool: D53: %d %d %d

tool: D43: use define to get max = %d

tool: D54: use function to get max = %d

assistant: ```c
void main() {
  int x, y, z;
  int ch;
  int max(int, int);
  printf("Enter the x,y,z:\n");
  scanf("%d %d %d", &x, &y, &z);
  ch = (x > y) ? x : y;
  if (ch <= z) {
    printf("use define to get max = %d", z);
  } else {
    printf("use define to get max = %d", ch);
  }
  printf("\n");
  ch = max(x, y);
  if (ch <= z) {
    printf("use function to get max = %d", z);
  } else {
    printf("use function to get max = %d", ch);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D50(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%r8d
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %esi,%r8d
  jl     L35
  mov    %r8d,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <max@plt>
  mov    0x14(%rsp),%r8d
  mov    %eax,%esi
  cmp    %eax,%r8d
  jl     L16
  mov    %r8d,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  ret
L35:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L37
L16:
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L5
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D50
datatype: string
name: parse_data
arguments: data_tag: D42
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D43
datatype: string

tool: D50: Enter the x,y,z:

tool: D42: %d %d %d

tool: D19: use define to get max = %d

tool: D43: use function to get max = %d

assistant: ```c
void main() {
  int x, y, z;
  int ch;
  int max(int, int);
  printf("Enter the x,y,z:\n");
  scanf("%d %d %d", &x, &y, &z);
  ch = (x > y) ? x : y;
  if (ch <= z) {
    printf("use define to get max = %d", z);
  } else {
    printf("use define to get max = %d", ch);
  }
  printf("\n");
  ch = max(x, y);
  if (ch <= z) {
    printf("use function to get max = %d", z);
  } else {
    printf("use function to get max = %d", ch);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <reset_tty@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: 

assistant: ```c
void sig(sig) int sig;
{
  reset_tty();
  printf("\r\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<sig>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <reset_tty@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: 

assistant: ```c
void sig(sig) int sig;
{
  reset_tty();
  printf("\r\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<sig>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reset_tty@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: 

assistant: ```c
void sig(sig) int sig;
{
  reset_tty();
  printf("\r\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sig>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reset_tty@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: 

assistant: ```c
void sig(sig) int sig;
{
  reset_tty();
  printf("\r\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_sqlstate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x85ebca98,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0xd,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0xc2b2c41f,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%ecx
  mov    $0xba0cb7df,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0xa,%eax
  imul   $0x581,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_sqlstate(unsigned int s) {
  s ^= s >> 16;
  s *= 0x85ebca6b + 45;
  s ^= s >> 13;
  s *= 0xc2b2ae35 + 5610;
  s ^= s >> 16;
  return s % 1409;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_sqlstate>:
  endbr64
  mov    %edi,%edx
  shr    $0x10,%edx
  xor    %edi,%edx
  imul   $0x85ebca98,%edx,%edx
  mov    %edx,%eax
  shr    $0xd,%eax
  xor    %edx,%eax
  imul   $0xc2b2c41f,%eax,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  mov    $0xba0cb7df,%ecx
  imul   %rcx,%rax
  shr    $0x2a,%rax
  imul   $0x581,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_sqlstate(unsigned int s) {
  s ^= s >> 16;
  s *= 0x85ebca6b + 45;
  s ^= s >> 13;
  s *= 0xc2b2ae35 + 5610;
  s ^= s >> 16;
  return s % 1409;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash_sqlstate>:
  endbr64
  mov    %edi,%edx
  mov    $0xba0cb7df,%ecx
  shr    $0x10,%edx
  xor    %edi,%edx
  imul   $0x85ebca98,%edx,%edx
  mov    %edx,%eax
  shr    $0xd,%eax
  xor    %edx,%eax
  imul   $0xc2b2c41f,%eax,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  imul   %rcx,%rax
  shr    $0x2a,%rax
  imul   $0x581,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_sqlstate(unsigned int s) {
  s ^= s >> 16;
  s *= 0x85ebca6b + 45;
  s ^= s >> 13;
  s *= 0xc2b2ae35 + 5610;
  s ^= s >> 16;
  return s % 1409;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_sqlstate>:
  endbr64
  mov    %edi,%edx
  mov    $0xba0cb7df,%ecx
  shr    $0x10,%edx
  xor    %edi,%edx
  imul   $0x85ebca98,%edx,%edx
  mov    %edx,%eax
  shr    $0xd,%eax
  xor    %edx,%eax
  imul   $0xc2b2c41f,%eax,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  imul   %rcx,%rax
  shr    $0x2a,%rax
  imul   $0x581,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash_sqlstate(unsigned int s) {
  s ^= s >> 16;
  s *= 0x85ebca6b + 45;
  s ^= s >> 13;
  s *= 0xc2b2ae35 + 5610;
  s ^= s >> 16;
  return s % 1409;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strislower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L35
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L32
L9:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    $0x1,%eax
L32:
  leave
  ret
```

assistant: ```c
int strislower(const char *str) {
  for (; *str; str++)
    if (isupper(*str))
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strislower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L45:
  movsbl %dil,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L7
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
  mov    $0x1,%eax
  jmp    L1
L5:
  mov    $0x1,%eax
  jmp    L1
L7:
  mov    $0x0,%eax
L1:
  pop    %rbx
  ret
```

assistant: ```c
int strislower(const char *str) {
  for (; *str; str++)
    if (isupper(*str))
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strislower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L29
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L28
L29:
  call   <isupper@plt>
  test   %rax,%rax
  je     L6
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strislower(const char *str) {
  for (; *str; str++)
    if (isupper(*str))
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strislower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L17
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L38:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L7
L17:
  call   <isupper@plt>
  test   %rax,%rax
  je     L38
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strislower(const char *str) {
  for (; *str; str++)
    if (isupper(*str))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L10:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L10
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <left_rotate@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D4: %d %d

tool: D19: %d

assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &(a[i]));
  }
  left_rotate(a, n, k);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    (%rsp),%esi
  test   %esi,%esi
  jle    L20
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    (%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L0
L20:
  mov    0x4(%rsp),%edx
  mov    %r13,%rdi
  call   <left_rotate@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D9: %d %d

tool: D5: %d

assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &(a[i]));
  }
  left_rotate(a, n, k);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%esi
  mov    %rax,%r13
  test   %esi,%esi
  jle    L2
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D15(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L20
L2:
  mov    0x4(%rsp),%edx
  mov    %r13,%rdi
  call   <left_rotate@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D7: %d %d

tool: D15: %d

assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &(a[i]));
  }
  left_rotate(a, n, k);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%esi
  mov    %rax,%r13
  test   %esi,%esi
  jle    L10
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    (%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L9
L10:
  mov    0x4(%rsp),%edx
  mov    %r13,%rdi
  call   <left_rotate@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D5: %d %d

tool: D3: %d

assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &(a[i]));
  }
  left_rotate(a, n, k);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L37
L4:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  add    %al,-0x1(%rbp)
  subl   $0x2,-0x1c(%rbp)
L37:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L4
  cmpl   $0x0,-0x1c(%rbp)
  jle    L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    %al,-0x1(%rbp)
  jmp    L32
L20:
  movzbl -0x1(%rbp),%eax
  sar    $0x10,%eax
  add    %al,-0x1(%rbp)
L32:
  movzbl -0x1(%rbp),%eax
  sar    $0x10,%eax
  test   %eax,%eax
  jne    L20
  movzbl -0x1(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t checksum(uint16_t *data, int length) {
  uint64_t sum = 0;
  while (length > 1) {
    sum += *data++;
    length -= 2;
  }
  if (length > 0) {
    sum += *(unsigned char *)data;
  }
  while (sum >> 16) {
    sum = (sum & 0xffff) + (sum >> 16);
  }
  return (uint16_t)~sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  mov    $0x0,%eax
L13:
  add    $0x4,%rdi
  add    -0x4(%rdi),%al
  cmp    %rdx,%rdi
  jne    L13
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L26:
  test   %esi,%esi
  jle    L1
  add    (%rdx),%al
L1:
  movzbl %al,%eax
  not    %eax
  ret
L8:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L26
```

assistant: ```c
uint16_t checksum(uint16_t *data, int length) {
  uint64_t sum = 0;
  while (length > 1) {
    sum += *data++;
    length -= 2;
  }
  if (length > 0) {
    sum += *(unsigned char *)data;
  }
  while (sum >> 16) {
    sum = (sum & 0xffff) + (sum >> 16);
  }
  return (uint16_t)~sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  sub    $0x2,%esi
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L32:
  add    $0x4,%rdi
  add    -0x4(%rdi),%al
  cmp    %rdx,%rdi
  jne    L32
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L26:
  cmp    $0x1,%esi
  jne    L3
  add    (%rdx),%al
L3:
  movzbl %al,%eax
  not    %eax
  ret
  xchg   %ax,%ax
L38:
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L26
```

assistant: ```c
uint16_t checksum(uint16_t *data, int length) {
  uint64_t sum = 0;
  while (length > 1) {
    sum += *data++;
    length -= 2;
  }
  if (length > 0) {
    sum += *(unsigned char *)data;
  }
  while (sum >> 16) {
    sum = (sum & 0xffff) + (sum >> 16);
  }
  return (uint16_t)~sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply171>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L20
L14:
  movl   $0x0,-0x3c(%rbp)
  jmp    L38
L22:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L38:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L22
  addl   $0x1,-0x40(%rbp)
L20:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L14
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply171(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply171>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L16:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L29:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L29
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  ret
```

assistant: ```c
void multiply171(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply171>:
  endbr64
  test   %edi,%edi
  jle    L29
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L12
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L18
  pop    %rbx
  ret
L29:
  ret
```

assistant: ```c
void multiply171(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```