ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<correctInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L8
L40:
  movl   $0x0,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x2c(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <correct@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L20
L4:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <checkPTRALLOC@plt>
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x2c(%rbp),%edx
  mov    $0x64,%eax
  sub    %edx,%eax
  cltd
  idivl  -0x44(%rbp)
  sub    %eax,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L8:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L40
  mov    -0x40(%rbp),%rax
  mov    -0x28(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
L20:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int correctInput(char **in, int *understoodPercent, int numwords) {
  int understood = 100, likeness, i;
  char *corrected_word;
  for (i = 0; i < numwords; i++) {
    likeness = 0;
    corrected_word = correct(in[i], &likeness);
    if (corrected_word == NULL) {
      return 0;
    }
    free(in[i]);
    in[i] = malloc((1 + strlen(corrected_word)) * sizeof(char));
    checkPTRALLOC((void **)&in[i]);
    strcpy(in[i], corrected_word);
    free(corrected_word);
    understood -= (100 - likeness) / numwords;
  }
  *understoodPercent = understood;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<correctInput>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L36
  mov    %edx,%r12d
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rdi,%rax,8),%r15
  mov    $0x64,%r13d
  lea    0x14(%rsp),%r14
L6:
  movl   $0x0,0x14(%rsp)
  mov    %r14,%rsi
  mov    (%rbx),%rdi
  call   <correct@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L0
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rbx,%rdi
  call   <checkPTRALLOC@plt>
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x64,%eax
  sub    0x14(%rsp),%eax
  cltd
  idiv   %r12d
  sub    %eax,%r13d
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L6
L24:
  mov    0x8(%rsp),%rax
  mov    %r13d,(%rax)
  mov    $0x1,%eax
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0x64,%r13d
  jmp    L24
L0:
  mov    $0x0,%eax
  jmp    L26
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int correctInput(char **in, int *understoodPercent, int numwords) {
  int understood = 100, likeness, i;
  char *corrected_word;
  for (i = 0; i < numwords; i++) {
    likeness = 0;
    corrected_word = correct(in[i], &likeness);
    if (corrected_word == NULL) {
      return 0;
    }
    free(in[i]);
    in[i] = malloc((1 + strlen(corrected_word)) * sizeof(char));
    checkPTRALLOC((void **)&in[i]);
    strcpy(in[i], corrected_word);
    free(corrected_word);
    understood -= (100 - likeness) / numwords;
  }
  *understoodPercent = understood;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<correctInput>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L27
  lea    -0x1(%rdx),%eax
  mov    %edx,%ebx
  mov    %rdi,%r15
  mov    $0x64,%ebp
  lea    0x8(%rdi,%rax,8),%rax
  lea    0x14(%rsp),%r12
  mov    $0x64,%r13d
  mov    %rax,(%rsp)
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L33:
  mov    (%r15),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r15,%rdi
  add    $0x8,%r15
  mov    %rax,-0x8(%r15)
  call   <checkPTRALLOC@plt>
  mov    -0x8(%r15),%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13d,%eax
  sub    0x14(%rsp),%eax
  cltd
  idiv   %ebx
  sub    %eax,%ebp
  cmp    (%rsp),%r15
  je     L53
L2:
  mov    (%r15),%rdi
  mov    %r12,%rsi
  movl   $0x0,0x14(%rsp)
  call   <correct@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L33
  xor    %eax,%eax
  jmp    L39
L27:
  mov    $0x64,%ebp
  nopw   0x0(%rax,%rax,1)
L53:
  mov    0x8(%rsp),%rax
  mov    %ebp,(%rax)
  mov    $0x1,%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int correctInput(char **in, int *understoodPercent, int numwords) {
  int understood = 100, likeness, i;
  char *corrected_word;
  for (i = 0; i < numwords; i++) {
    likeness = 0;
    corrected_word = correct(in[i], &likeness);
    if (corrected_word == NULL) {
      return 0;
    }
    free(in[i]);
    in[i] = malloc((1 + strlen(corrected_word)) * sizeof(char));
    checkPTRALLOC((void **)&in[i]);
    strcpy(in[i], corrected_word);
    free(corrected_word);
    understood -= (100 - likeness) / numwords;
  }
  *understoodPercent = understood;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<correctInput>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L20
  lea    -0x1(%rdx),%eax
  mov    %edx,%ebx
  mov    %rdi,%r15
  mov    $0x64,%ebp
  lea    0x8(%rdi,%rax,8),%rax
  lea    0x14(%rsp),%r12
  mov    $0x64,%r13d
  mov    %rax,(%rsp)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%r15),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r15,%rdi
  add    $0x8,%r15
  mov    %rax,-0x8(%r15)
  call   <checkPTRALLOC@plt>
  mov    -0x8(%r15),%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13d,%eax
  sub    0x14(%rsp),%eax
  cltd
  idiv   %ebx
  sub    %eax,%ebp
  cmp    (%rsp),%r15
  je     L22
L33:
  mov    (%r15),%rdi
  mov    %r12,%rsi
  movl   $0x0,0x14(%rsp)
  call   <correct@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L16
  xor    %eax,%eax
  jmp    L25
L20:
  mov    $0x64,%ebp
  nopw   0x0(%rax,%rax,1)
L22:
  mov    0x8(%rsp),%rax
  mov    %ebp,(%rax)
  mov    $0x1,%eax
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int correctInput(char **in, int *understoodPercent, int numwords) {
  int understood = 100, likeness, i;
  char *corrected_word;
  for (i = 0; i < numwords; i++) {
    likeness = 0;
    corrected_word = correct(in[i], &likeness);
    if (corrected_word == NULL) {
      return 0;
    }
    free(in[i]);
    in[i] = malloc((1 + strlen(corrected_word)) * sizeof(char));
    checkPTRALLOC((void **)&in[i]);
    strcpy(in[i], corrected_word);
    free(corrected_word);
    understood -= (100 - likeness) / numwords;
  }
  *understoodPercent = understood;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_cool_obj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D2(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

assistant: ```c
double calc_cool_obj(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  value = (temp * temp) / (tempcrit * tempcrit * 8);
  return (value);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_cool_obj>:
  endbr64
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

assistant: ```c
double calc_cool_obj(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  value = (temp * temp) / (tempcrit * tempcrit * 8);
  return (value);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calc_cool_obj>:
  endbr64
  mulsd  %xmm1,%xmm1
  mulsd  D4(%rip),%xmm1
  mulsd  %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

assistant: ```c
double calc_cool_obj(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  value = (temp * temp) / (tempcrit * tempcrit * 8);
  return (value);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_cool_obj>:
  endbr64
  mulsd  %xmm1,%xmm1
  mulsd  D2(%rip),%xmm1
  mulsd  %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

assistant: ```c
double calc_cool_obj(temp, tempcrit)
double temp, tempcrit;
{
  double value;
  value = (temp * temp) / (tempcrit * tempcrit * 8);
  return (value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CreatePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L11
  addq   $0x2,-0x428(%rbp)
L11:
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x418(%rbp)
  jmp    L7
L51:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x419(%rbp)
  cmpb   $0x2f,-0x419(%rbp)
  je     L30
  cmpb   $0x5c,-0x419(%rbp)
  jne    L40
L30:
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  mov    %eax,%edx
  mov    -0x428(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_mkdir@plt>
L40:
  addq   $0x1,-0x418(%rbp)
L7:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmpb   $0x3a,0x1(%rdi)
  je     L70
L41:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L25
  mov    %rsp,%r13
  jmp    L84
L70:
  add    $0x2,%rbp
  jmp    L41
L65:
  mov    %rbx,%r12
  sub    %rbp,%r12
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%r12,1)
  mov    %r13,%rdi
  call   <Q_mkdir@plt>
L60:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L25
L84:
  cmp    $0x2f,%al
  je     L65
  cmp    $0x5c,%al
  jne    L60
  jmp    L65
L25:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L30
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L30:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  jne    L73
  jmp    L55
  nopl   0x0(%rax)
L79:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L55
L73:
  cmp    $0x2f,%al
  je     L6
  cmp    $0x5c,%al
  jne    L79
L6:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L73
L55:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L29
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L29:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  je     L44
  nopw   0x0(%rax,%rax,1)
L55:
  cmp    $0x2f,%al
  je     L61
  cmp    $0x5c,%al
  je     L61
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L55
L44:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L61:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L55
  jmp    L44
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<re_escape_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x7f,-0x1c(%rbp)
  ja     L11
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L6
L11:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <re_log2floor@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x7,%eax
  sub    -0xc(%rbp),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  lea    (%rsi,%rax,1),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L7
L18:
  mov    -0x10(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x3f,%eax
  lea    -0x80(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L7:
  subl   $0x6,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L18
L6:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void re_escape_utf8(char **sp, unsigned int c) {
  char *s = *sp;
  if (c < 128)
    *s++ = c;
  else {
    int n = re_log2floor((unsigned)c) / 6;
    int m = 6 * n;
    *s++ = (0xff << (7 - n)) + (c >> m);
    while ((m -= 6) >= 0)
      *s++ = 0x80 + ((c >> m) & 0x3F);
  }
  *sp = s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<re_escape_utf8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    (%rdi),%r12
  cmp    $0x7f,%esi
  ja     L36
  lea    0x1(%r12),%rdx
  mov    %sil,(%r12)
L10:
  mov    %rdx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %esi,%edi
  call   <re_log2floor@plt>
  movslq %eax,%rsi
  imul   $0x2aaaaaab,%rsi,%rsi
  shr    $0x20,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    (%rsi,%rsi,2),%ecx
  lea    (%rcx,%rcx,1),%eax
  lea    0x1(%r12),%rdx
  mov    $0x7,%ecx
  sub    %esi,%ecx
  mov    $0xff,%esi
  shl    %cl,%esi
  mov    %ebx,%edi
  mov    %eax,%ecx
  shr    %cl,%edi
  add    %edi,%esi
  mov    %sil,(%r12)
  sub    $0x6,%eax
  mov    %eax,%ecx
  js     L10
L21:
  add    $0x1,%rdx
  mov    %ebx,%eax
  shr    %cl,%eax
  and    $0x3f,%eax
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rdx)
  sub    $0x6,%ecx
  jns    L21
  jmp    L10
```

assistant: ```c
void re_escape_utf8(char **sp, unsigned int c) {
  char *s = *sp;
  if (c < 128)
    *s++ = c;
  else {
    int n = re_log2floor((unsigned)c) / 6;
    int m = 6 * n;
    *s++ = (0xff << (7 - n)) + (c >> m);
    while ((m -= 6) >= 0)
      *s++ = 0x80 + ((c >> m) & 0x3F);
  }
  *sp = s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<re_escape_utf8>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r13
  lea    0x1(%r13),%rbx
  cmp    $0x7f,%esi
  ja     L18
  mov    %sil,0x0(%r13)
L10:
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %esi,%edi
  call   <re_log2floor@plt>
  mov    %ebp,%esi
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rcx,%rcx,1),%eax
  mov    $0x7,%ecx
  sub    %edx,%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  mov    %eax,%ecx
  shr    %cl,%esi
  add    %esi,%edx
  sub    $0x6,%eax
  mov    %dl,0x0(%r13)
  mov    %eax,%ecx
  js     L10
  nopl   0x0(%rax)
L29:
  mov    %ebp,%eax
  add    $0x1,%rbx
  shr    %cl,%eax
  and    $0x3f,%eax
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rbx)
  sub    $0x6,%ecx
  jns    L29
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void re_escape_utf8(char **sp, unsigned int c) {
  char *s = *sp;
  if (c < 128)
    *s++ = c;
  else {
    int n = re_log2floor((unsigned)c) / 6;
    int m = 6 * n;
    *s++ = (0xff << (7 - n)) + (c >> m);
    while ((m -= 6) >= 0)
      *s++ = 0x80 + ((c >> m) & 0x3F);
  }
  *sp = s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<re_escape_utf8>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r13
  lea    0x1(%r13),%rbx
  cmp    $0x7f,%esi
  ja     L13
  mov    %sil,0x0(%r13)
L16:
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %esi,%edi
  call   <re_log2floor@plt>
  mov    %ebp,%esi
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rcx,%rcx,1),%eax
  mov    $0x7,%ecx
  sub    %edx,%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  mov    %eax,%ecx
  shr    %cl,%esi
  add    %esi,%edx
  sub    $0x6,%eax
  mov    %dl,0x0(%r13)
  mov    %eax,%ecx
  js     L16
  nopl   0x0(%rax)
L17:
  mov    %ebp,%eax
  add    $0x1,%rbx
  shr    %cl,%eax
  and    $0x3f,%eax
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rbx)
  sub    $0x6,%ecx
  jns    L17
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void re_escape_utf8(char **sp, unsigned int c) {
  char *s = *sp;
  if (c < 128)
    *s++ = c;
  else {
    int n = re_log2floor((unsigned)c) / 6;
    int m = 6 * n;
    *s++ = (0xff << (7 - n)) + (c >> m);
    while ((m -= 6) >= 0)
      *s++ = 0x80 + ((c >> m) & 0x3F);
  }
  *sp = s;
}
```