ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<linsolv>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  imul   %edi,%r14d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r14d,%edi
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L34
L15:
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L21
L24:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <copyarr@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <copyarr@plt>
  mov    0x8(%rsp),%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <linsolvx@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L34:
  mov    %r14d,%esi
  lea    D7(%rip),%rdi
  call   <fatalx@plt>
  jmp    L15
  nopl   0x0(%rax)
L21:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <fatalx@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: Unable to allocate %d unit(s) for item 


assistant: ```c
int linsolv(int n, double *pfMatr, double *pfVect, double *sol) {
  int ret;
  double *a, *rhs;
  if ((a = (double *)calloc((n * n), sizeof(double))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", n * n);
  if ((rhs = (double *)calloc((n), sizeof(double))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", n);
  copyarr(pfMatr, a, n * n);
  copyarr(pfVect, rhs, n);
  ret = linsolvx(n, a, rhs, sol);
  free(a);
  free(rhs);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<linsolv>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  imul   %edi,%r14d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r14d,%edi
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
L31:
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L25:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <copyarr@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <copyarr@plt>
  mov    0x8(%rsp),%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <linsolvx@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  mov    %r14d,%esi
  lea    D12(%rip),%rdi
  call   <fatalx@plt>
  jmp    L31
  nopl   0x0(%rax)
L17:
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  call   <fatalx@plt>
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string

tool: D12: Unable to allocate %d unit(s) for item 


assistant: ```c
int linsolv(int n, double *pfMatr, double *pfVect, double *sol) {
  int ret;
  double *a, *rhs;
  if ((a = (double *)calloc((n * n), sizeof(double))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", n * n);
  if ((rhs = (double *)calloc((n), sizeof(double))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", n);
  copyarr(pfMatr, a, n * n);
  copyarr(pfVect, rhs, n);
  ret = linsolvx(n, a, rhs, sol);
  free(a);
  free(rhs);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: Simplest test program.


assistant: ```c
int main() {
  printf("Simplest test program.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Simplest test program.


assistant: ```c
int main() {
  printf("Simplest test program.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: Simplest test program.


assistant: ```c
int main() {
  printf("Simplest test program.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: Simplest test program.


assistant: ```c
int main() {
  printf("Simplest test program.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eg_indirect_table_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x140,%esi
  mov    %eax,%edi
  call   <egress_reg_tbl_set@plt>
  mov    -0x18(%rbp),%eax
  shl    $0xc,%eax
  or     -0x1c(%rbp),%eax
  or     $0x80000000,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <eg_table_cmd_set@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int eg_indirect_table_set(unsigned int dev_id, unsigned int table_type, unsigned int index, unsigned int entry_len, unsigned int *pentry) {
  unsigned int cmd = 0;
  egress_reg_tbl_set(dev_id, 0x140, pentry, entry_len);
  cmd = (0x2 << 30) | (table_type << 12) | index;
  eg_table_cmd_set(dev_id, (union eg_table_cmd_u *)&cmd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eg_indirect_table_set>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %r8,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    $0x140,%esi
  call   <egress_reg_tbl_set@plt>
  shl    $0xc,%ebx
  or     %r12d,%ebx
  or     $0x80000000,%ebx
  mov    %ebx,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %ebp,%edi
  call   <eg_table_cmd_set@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eg_indirect_table_set(unsigned int dev_id, unsigned int table_type, unsigned int index, unsigned int entry_len, unsigned int *pentry) {
  unsigned int cmd = 0;
  egress_reg_tbl_set(dev_id, 0x140, pentry, entry_len);
  cmd = (0x2 << 30) | (table_type << 12) | index;
  eg_table_cmd_set(dev_id, (union eg_table_cmd_u *)&cmd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eg_indirect_table_set>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %r8,%rdx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x140,%esi
  shl    $0xc,%ebx
  or     %r12d,%ebx
  sub    $0x10,%rsp
  or     $0x80000000,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <egress_reg_tbl_set@plt>
  lea    0x4(%rsp),%rsi
  mov    %ebp,%edi
  mov    %ebx,0x4(%rsp)
  call   <eg_table_cmd_set@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eg_indirect_table_set(unsigned int dev_id, unsigned int table_type, unsigned int index, unsigned int entry_len, unsigned int *pentry) {
  unsigned int cmd = 0;
  egress_reg_tbl_set(dev_id, 0x140, pentry, entry_len);
  cmd = (0x2 << 30) | (table_type << 12) | index;
  eg_table_cmd_set(dev_id, (union eg_table_cmd_u *)&cmd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eg_indirect_table_set>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %r8,%rdx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x140,%esi
  shl    $0xc,%ebx
  or     %r12d,%ebx
  sub    $0x10,%rsp
  or     $0x80000000,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <egress_reg_tbl_set@plt>
  lea    0x4(%rsp),%rsi
  mov    %ebp,%edi
  mov    %ebx,0x4(%rsp)
  call   <eg_table_cmd_set@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int eg_indirect_table_set(unsigned int dev_id, unsigned int table_type, unsigned int index, unsigned int entry_len, unsigned int *pentry) {
  unsigned int cmd = 0;
  egress_reg_tbl_set(dev_id, 0x140, pentry, entry_len);
  cmd = (0x2 << 30) | (table_type << 12) | index;
  eg_table_cmd_set(dev_id, (union eg_table_cmd_u *)&cmd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L0:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    %rax,-0x38(%rbp)
  ja     L0
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *d_vp, void *s_vp, unsigned long n) {
  unsigned i;
  char *d = d_vp, *s = s_vp;
  for (i = 0; i < n; ++i)
    d[i] = s[i];
  return d_vp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L6
  mov    $0x0,%r8d
  mov    $0x0,%ecx
L18:
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rax,%rcx,1)
  add    $0x1,%r8d
  mov    %r8d,%ecx
  cmp    %rdx,%rcx
  jb     L18
L6:
  ret
```

assistant: ```c
void *memcpy(void *d_vp, void *s_vp, unsigned long n) {
  unsigned i;
  char *d = d_vp, *s = s_vp;
  for (i = 0; i < n; ++i)
    d[i] = s[i];
  return d_vp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L12
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L15:
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rax,%rcx,1)
  lea    0x1(%r8),%ecx
  mov    %rcx,%r8
  cmp    %rdx,%rcx
  jb     L15
L12:
  ret
```

assistant: ```c
void *memcpy(void *d_vp, void *s_vp, unsigned long n) {
  unsigned i;
  char *d = d_vp, *s = s_vp;
  for (i = 0; i < n; ++i)
    d[i] = s[i];
  return d_vp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L18
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L13:
  movzbl (%rsi,%rcx,1),%r9d
  mov    %r9b,(%rax,%rcx,1)
  lea    0x1(%r8),%ecx
  mov    %rcx,%r8
  cmp    %rdx,%rcx
  jb     L13
L18:
  ret
```

assistant: ```c
void *memcpy(void *d_vp, void *s_vp, unsigned long n) {
  unsigned i;
  char *d = d_vp, *s = s_vp;
  for (i = 0; i < n; ++i)
    d[i] = s[i];
  return d_vp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x2ff,%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f5(unsigned char x, unsigned char y) {
  int a = x;
  int b = y;
  int c = a + b;
  return c & 0x2ff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f5>:
  endbr64
  add    %esi,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f5(unsigned char x, unsigned char y) {
  int a = x;
  int b = y;
  int c = a + b;
  return c & 0x2ff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f5>:
  endbr64
  add    %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f5(unsigned char x, unsigned char y) {
  int a = x;
  int b = y;
  int c = a + b;
  return c & 0x2ff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f5>:
  endbr64
  add    %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int f5(unsigned char x, unsigned char y) {
  int a = x;
  int b = y;
  int c = a + b;
  return c & 0x2ff;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L35:
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x18(%rbp),%eax
  imul   $0x65,%eax,%ebx
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  add    %ebx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x2c,-0x14(%rbp)
  jbe    L35
  jmp    L1
L2:
  nop
L1:
  mov    -0x18(%rbp),%eax
  shr    $0x10,%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x20,%rax
  shr    $0x7,%eax
  imul   $0x186a0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int hash(const char *key) {
  unsigned int h = 0;
  for (unsigned int i = 0; i < 45; ++i) {
    if (key[i] == '\0') {
      break;
    }
    h = 101 * h + tolower(key[i]);
  }
  return (h ^ (h >> 16)) % 100000;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x2d(%rdi),%r12
  mov    $0x0,%eax
L0:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L16
  imul   $0x65,%eax,%ebp
  movsbl %dil,%edi
  call   <tolower@plt>
  add    %ebp,%eax
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L0
L16:
  mov    %eax,%edx
  shr    $0x10,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0x186a0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int hash(const char *key) {
  unsigned int h = 0;
  for (unsigned int i = 0; i < 45; ++i) {
    if (key[i] == '\0') {
      break;
    }
    h = 101 * h + tolower(key[i]);
  }
  return (h ^ (h >> 16)) % 100000;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    0x2d(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L16:
  imul   $0x65,%eax,%ebp
  add    $0x1,%rbx
  call   <tolower@plt>
  add    %ebp,%eax
  cmp    %r12,%rbx
  je     L14
L6:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L14:
  mov    %eax,%edx
  pop    %rbx
  pop    %rbp
  shr    $0x10,%edx
  pop    %r12
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x5,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0x186a0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash(const char *key) {
  unsigned int h = 0;
  for (unsigned int i = 0; i < 45; ++i) {
    if (key[i] == '\0') {
      break;
    }
    h = 101 * h + tolower(key[i]);
  }
  return (h ^ (h >> 16)) % 100000;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    0x2d(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L11:
  imul   $0x65,%eax,%ebp
  add    $0x1,%rbx
  call   <tolower@plt>
  add    %ebp,%eax
  cmp    %r12,%rbx
  je     L19
L12:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L11
L19:
  mov    %eax,%edx
  pop    %rbx
  pop    %rbp
  shr    $0x10,%edx
  pop    %r12
  xor    %eax,%edx
  mov    %edx,%eax
  shr    $0x5,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0x186a0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned int hash(const char *key) {
  unsigned int h = 0;
  for (unsigned int i = 0; i < 45; ++i) {
    if (key[i] == '\0') {
      break;
    }
    h = 101 * h + tolower(key[i]);
  }
  return (h ^ (h >> 16)) % 100000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubblesort_xor_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xf000(%rsp),%r11
L64:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L64
  sub    $0xa20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfa18(%rbp)
  jmp    L34
L48:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0xfa18(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0xfa10(%rbp,%rdx,4)
  addl   $0x1,-0xfa18(%rbp)
L34:
  cmpl   $0x3e7f,-0xfa18(%rbp)
  jle    L48
  movl   $0x0,-0xfa14(%rbp)
  jmp    L70
L7:
  movl   $0x1,-0xfa14(%rbp)
  movl   $0x0,-0xfa18(%rbp)
  jmp    L88
L41:
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%edx
  mov    -0xfa18(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L10
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%edx
  mov    -0xfa18(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    %edx,-0xfa10(%rbp,%rax,4)
  mov    -0xfa18(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%ecx
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%edx
  mov    -0xfa18(%rbp),%eax
  add    $0x1,%eax
  xor    %ecx,%edx
  cltq
  mov    %edx,-0xfa10(%rbp,%rax,4)
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%edx
  mov    -0xfa18(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfa10(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0xfa18(%rbp),%eax
  cltq
  mov    %edx,-0xfa10(%rbp,%rax,4)
  movl   $0x0,-0xfa14(%rbp)
L10:
  addl   $0x1,-0xfa18(%rbp)
L88:
  cmpl   $0x3e7e,-0xfa18(%rbp)
  jle    L41
L70:
  cmpl   $0x0,-0xfa14(%rbp)
  je     L7
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void bubblesort_xor_swap() {
  int arr[16000];
  int i;
  for (i = 0; i < 16000; ++i) {
    arr[i] = rand();
  }
  int sorted = 0;
  while (!sorted) {
    sorted = 1;
    for (i = 0; i < 16000 - 1; ++i) {
      if (arr[i] > arr[i + 1]) {
        arr[i] ^= arr[i + 1];
        arr[i + 1] ^= arr[i];
        arr[i] ^= arr[i + 1];
        sorted = 0;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bubblesort_xor_swap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xfa00(%rsp),%r12
  mov    %rbx,%rbp
L54:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L54
  lea    0xf9fc(%rbx),%rsi
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  jmp    L47
L71:
  add    $0x4,%rax
  cmp    %rax,%rsi
  je     L21
L51:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L71
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  mov    %r8d,%edi
  jmp    L71
L21:
  test   %edi,%edi
  jne    L44
L47:
  mov    %rbx,%rax
  mov    %r9d,%edi
  jmp    L51
L44:
  mov    0xfa08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0xfa10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bubblesort_xor_swap() {
  int arr[16000];
  int i;
  for (i = 0; i < 16000; ++i) {
    arr[i] = rand();
  }
  int sorted = 0;
  while (!sorted) {
    sorted = 1;
    for (i = 0; i < 16000 - 1; ++i) {
      if (arr[i] > arr[i + 1]) {
        arr[i] ^= arr[i + 1];
        arr[i + 1] ^= arr[i];
        arr[i] ^= arr[i + 1];
        sorted = 0;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubblesort_xor_swap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xfa00(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L41
  lea    0xf9fc(%rbx),%rsi
L52:
  mov    %rbx,%rax
  mov    $0x1,%edi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L33
  mov    %ecx,0x4(%rax)
  xor    %edi,%edi
  mov    %edx,(%rax)
L33:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L2
  test   %edi,%edi
  je     L52
  mov    0xfa08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xfa10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bubblesort_xor_swap() {
  int arr[16000];
  int i;
  for (i = 0; i < 16000; ++i) {
    arr[i] = rand();
  }
  int sorted = 0;
  while (!sorted) {
    sorted = 1;
    for (i = 0; i < 16000 - 1; ++i) {
      if (arr[i] > arr[i + 1]) {
        arr[i] ^= arr[i + 1];
        arr[i + 1] ^= arr[i];
        arr[i] ^= arr[i + 1];
        sorted = 0;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bubblesort_xor_swap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xfa00(%rsp),%r12
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L53
  lea    0xf9fc(%rbx),%rsi
L35:
  mov    %rbx,%rax
  mov    $0x1,%edi
  nopw   0x0(%rax,%rax,1)
L37:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L38
  mov    %ecx,0x4(%rax)
  xor    %edi,%edi
  mov    %edx,(%rax)
L38:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L37
  test   %edi,%edi
  je     L35
  mov    0xfa08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0xfa10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bubblesort_xor_swap() {
  int arr[16000];
  int i;
  for (i = 0; i < 16000; ++i) {
    arr[i] = rand();
  }
  int sorted = 0;
  while (!sorted) {
    sorted = 1;
    for (i = 0; i < 16000 - 1; ++i) {
      if (arr[i] > arr[i + 1]) {
        arr[i] ^= arr[i + 1];
        arr[i + 1] ^= arr[i];
        arr[i] ^= arr[i + 1];
        sorted = 0;
      }
    }
  }
}
```