ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D8(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  lea    0xf(%rsp),%rbp
  lea    0x13(%rsp),%r12
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  movsd  D45(%rip),%xmm0
  mov    $0x1,%eax
  lea    D73(%rip),%rdi
  call   <printf@plt>
  movsd  D69(%rip),%xmm0
  mov    $0x1,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x61,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D45
datatype: byte[8]
name: retrieve_data
arguments: tag: D73
datatype: string
name: retrieve_data
arguments: tag: D69
datatype: f64
name: retrieve_data
arguments: tag: D32
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D60
datatype: string
name: retrieve_data
arguments: tag: D76
datatype: string
name: retrieve_data
arguments: tag: D48
datatype: string

tool: D8: You are %d miles away.


tool: {"D45": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D73: You have %f levels of power.


tool: D69: 56789.4532

tool: D32: You have %f awesome super powers.


tool: D21: I have an initial %c.


tool: D60: I have a first name %s.


tool: D76: I have a last name %s.


tool: D48: My whole name is %s %c. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s.\n", first_name);
  printf("I have a last name %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  printf("a");
  printf("");
  printf("b");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  lea    D12(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0xf(%rsp)
  lea    0xf(%rsp),%rbp
  lea    0x13(%rsp),%r12
  movl   $0x77616853,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <printf@plt>
  movsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  movsd  D4(%rip),%xmm0
  mov    $0x1,%eax
  lea    D89(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    %rbp,%rsi
  lea    D86(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x61,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D8
type: byte[8]
name: retrieve_data
arguments: data_tag: D25
type: string
name: retrieve_data
arguments: data_tag: D4
type: f64
name: retrieve_data
arguments: data_tag: D89
type: string
name: retrieve_data
arguments: data_tag: D46
type: string
name: retrieve_data
arguments: data_tag: D73
type: string
name: retrieve_data
arguments: data_tag: D75
type: string
name: retrieve_data
arguments: data_tag: D86
type: string

tool: D12: You are %d miles away.


tool: {"D8": [0x00,0x00,0x00,0x60,0x8f,0xc2,0x02,0x40]}

tool: D25: You have %f levels of power.


tool: D4: 56789.4532

tool: D89: You have %f awesome super powers.


tool: D46: I have an initial %c.


tool: D73: I have a first name %s.


tool: D75: I have a last name %s.


tool: D86: My whole name is %s %c. %s.


assistant: ```c
int main(int argc, char *argv[]) {
  int distance = 100;
  float power = 2.345f;
  double super_power = 56789.4532;
  char initial = 'A';
  char first_name[] = "Zed";
  char last_name[] = "Shaw";
  printf("You are %d miles away.\n", distance);
  printf("You have %f levels of power.\n", power);
  printf("You have %f awesome super powers.\n", super_power);
  printf("I have an initial %c.\n", initial);
  printf("I have a first name %s.\n", first_name);
  printf("I have a last name %s.\n", last_name);
  printf("My whole name is %s %c. %s.\n", first_name, initial, last_name);
  printf("a");
  printf("");
  printf("b");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D45(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D52(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <zero_out@plt>
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  setnp  %al
  mov    $0x0,%edx
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  setnp  %al
  mov    $0x0,%edx
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  movsd  -0x10(%rbp),%xmm0
  ucomisd D52(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  ucomisd D52(%rip),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D45
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D52
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D40
type_guessed: string
name: retrieve_data
arguments: tag: D61
type_guessed: string
name: retrieve_data
arguments: tag: D32
type_guessed: string

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x80,0x44,0x40]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x45,0x40]}

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x80,0x45,0x40]}

tool: D40: a[0] == 0

tool: D61: a[1] == 0

tool: D32: a[2] == 43

assistant: ```c
void test_double() {
  double a[3];
  a[0] = 41;
  a[1] = 42;
  a[2] = 43;
  zero_out(a, sizeof(double) * 2);
  assertTrue("a[0] == 0", a[0] == 0);
  ;
  assertTrue("a[1] == 0", a[1] == 0);
  ;
  assertTrue("a[2] == 43", a[2] == 43);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_double>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  mov    %rax,(%rsp)
  mov    D60(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x10,%esi
  call   <zero_out@plt>
  pxor   %xmm1,%xmm1
  ucomisd (%rsp),%xmm1
  setnp  %sil
  movzbl %sil,%esi
  mov    $0x0,%ebx
  cmovne %ebx,%esi
  lea    D41(%rip),%rdi
  call   <assertTrue@plt>
  pxor   %xmm2,%xmm2
  ucomisd 0x8(%rsp),%xmm2
  setnp  %sil
  movzbl %sil,%esi
  cmovne %ebx,%esi
  lea    D20(%rip),%rdi
  call   <assertTrue@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd D2(%rip),%xmm0
  setnp  %sil
  movzbl %sil,%esi
  movsd  D2(%rip),%xmm3
  ucomisd %xmm0,%xmm3
  cmovne %ebx,%esi
  lea    D58(%rip),%rdi
  call   <assertTrue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D36
type_guessed: byte[8]
name: parse_data
arguments: tag: D60
type_guessed: byte[8]
name: parse_data
arguments: tag: D2
type_guessed: byte[8]
name: parse_data
arguments: tag: D41
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D58
type_guessed: string

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x80,0x44,0x40]}

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0x45,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x80,0x45,0x40]}

tool: D41: a[0] == 0

tool: D20: a[1] == 0

tool: D58: a[2] == 43

assistant: ```c
void test_double() {
  double a[3];
  a[0] = 41;
  a[1] = 42;
  a[2] = 43;
  zero_out(a, sizeof(double) * 2);
  assertTrue("a[0] == 0", a[0] == 0);
  ;
  assertTrue("a[1] == 0", a[1] == 0);
  ;
  assertTrue("a[2] == 43", a[2] == 43);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_double>:
  endbr64
  push   %rbx
  mov    $0x10,%esi
  mov    $0x0,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D37(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    D39(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D18(%rip),%rax
  mov    %rax,0x10(%rsp)
  call   <zero_out@plt>
  pxor   %xmm1,%xmm1
  xor    %esi,%esi
  lea    D79(%rip),%rdi
  ucomisd (%rsp),%xmm1
  setnp  %sil
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  pxor   %xmm2,%xmm2
  xor    %esi,%esi
  lea    D12(%rip),%rdi
  ucomisd 0x8(%rsp),%xmm2
  setnp  %sil
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  movsd  0x10(%rsp),%xmm0
  xor    %esi,%esi
  ucomisd D18(%rip),%xmm0
  movsd  D18(%rip),%xmm3
  lea    D50(%rip),%rdi
  setnp  %sil
  ucomisd %xmm0,%xmm3
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D39
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D18
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D79
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D50
type_infered: string

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x80,0x44,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x45,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x80,0x45,0x40]}

tool: D79: a[0] == 0

tool: D12: a[1] == 0

tool: D50: a[2] == 43

assistant: ```c
void test_double() {
  double a[3];
  a[0] = 41;
  a[1] = 42;
  a[2] = 43;
  zero_out(a, sizeof(double) * 2);
  assertTrue("a[0] == 0", a[0] == 0);
  ;
  assertTrue("a[1] == 0", a[1] == 0);
  ;
  assertTrue("a[2] == 43", a[2] == 43);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_double>:
  endbr64
  push   %rbx
  mov    $0x10,%esi
  mov    $0x0,%ebx
  sub    $0x20,%rsp
  movapd D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <zero_out@plt>
  pxor   %xmm1,%xmm1
  xor    %esi,%esi
  lea    D49(%rip),%rdi
  ucomisd (%rsp),%xmm1
  setnp  %sil
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  pxor   %xmm2,%xmm2
  xor    %esi,%esi
  lea    D15(%rip),%rdi
  ucomisd 0x8(%rsp),%xmm2
  setnp  %sil
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  movsd  0x10(%rsp),%xmm0
  xor    %esi,%esi
  ucomisd D7(%rip),%xmm0
  movsd  D7(%rip),%xmm3
  lea    D17(%rip),%rdi
  setnp  %sil
  ucomisd %xmm0,%xmm3
  cmovne %ebx,%esi
  call   <assertTrue@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D37
type: byte[16]
name: unpack_data
arguments: data_label: D7
type: byte[8]
name: unpack_data
arguments: data_label: D49
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D17
type: string

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x80,0x44,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x45,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x80,0x45,0x40]}

tool: D49: a[0] == 0

tool: D15: a[1] == 0

tool: D17: a[2] == 43

assistant: ```c
void test_double() {
  double a[3];
  a[0] = 41;
  a[1] = 42;
  a[2] = 43;
  zero_out(a, sizeof(double) * 2);
  assertTrue("a[0] == 0", a[0] == 0);
  ;
  assertTrue("a[1] == 0", a[1] == 0);
  ;
  assertTrue("a[2] == 43", a[2] == 43);
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<prompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x15,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  nop
  leave
  ret
```

assistant: ```c
void prompt(int n, char *f, const char *s) {
  (void)move(21 + n, 0);
  (void)clrtoeol();
  (void)printw(f, s);
  (void)refresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prompt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  add    $0x15,%edi
  mov    $0x0,%esi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void prompt(int n, char *f, const char *s) {
  (void)move(21 + n, 0);
  (void)clrtoeol();
  (void)printw(f, s);
  (void)refresh();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prompt>:
  endbr64
  push   %r12
  add    $0x15,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <move@plt>
  xor    %eax,%eax
  call   <clrtoeol@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printw@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10b0 <refresh@plt>
```

assistant: ```c
void prompt(int n, char *f, const char *s) {
  (void)move(21 + n, 0);
  (void)clrtoeol();
  (void)printw(f, s);
  (void)refresh();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prompt>:
  endbr64
  push   %r12
  add    $0x15,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <move@plt>
  xor    %eax,%eax
  call   <clrtoeol@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printw@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10b0 <refresh@plt>
```

assistant: ```c
void prompt(int n, char *f, const char *s) {
  (void)move(21 + n, 0);
  (void)clrtoeol();
  (void)printw(f, s);
  (void)refresh();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L143:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L143
  sub    $0x6b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  movzbl (%rsp),%edi
  test   %dil,%dil
  je     L114
  mov    $0x1,%ebp
  lea    -0x1(%rsp),%r12
L10:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %ebp,%esi
  add    $0x1,%rbp
  movzbl (%r12,%rbp,1),%edi
  test   %dil,%dil
  jne    L10
L15:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L93
  mov    %rsp,%rcx
  mov    $0x1,%edx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ebp
  mov    $0x0,%r11d
  mov    $0x0,%edi
  lea    D0(%rip),%r10
  jmp    L141
L114:
  mov    $0x0,%esi
  jmp    L15
L42:
  sub    $0x45,%eax
  cmp    $0x30,%al
  ja     L95
  movzbl %al,%eax
  movslq (%r10,%rax,4),%rax
  add    %r10,%rax
  notrack jmp *%rax
  add    $0x1,%r11d
  mov    %edx,%eax
L106:
  add    $0x1,%rcx
  add    $0x1,%edx
  cmp    %ebx,%eax
  jge    L26
L141:
  movzbl (%rcx),%eax
  mov    %eax,%esi
  and    $0xffffffdf,%esi
  cmp    $0x41,%sil
  jne    L42
  add    $0x1,%edi
  mov    %edx,%eax
  jmp    L106
  add    $0x1,%ebp
  mov    %edx,%eax
  jmp    L106
  add    $0x1,%r8d
  mov    %edx,%eax
  jmp    L106
  add    $0x1,%r9d
  mov    %edx,%eax
  jmp    L106
L95:
  mov    %edx,%eax
  jmp    L106
L93:
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ebp
  mov    $0x0,%r11d
  mov    $0x0,%edi
L26:
  mov    %ebp,%ecx
  mov    %r11d,%edx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L148
  mov    $0x0,%eax
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L148:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D5: %d

tool: D6: A(a):%d E(e):%d I(i):%d O(o):%d U(u):%d


assistant: ```c
int main() {
  char str[100000];
  int a = 0, e = 0, i = 0, o = 0, u = 0, j = 0, k, p = 0;
  gets(str);
  k = strlen(str);
  while (str[j] != '\0') {
    switch (toupper(str[j])) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      p++;
    }
    j++;
  }
  printf("%d", j);
  j = 0;
  while (j < k) {
    if (str[j] == 'a' || str[j] == 'A') {
      a++;
      j++;
    } else if (str[j] == 'e' || str[j] == 'E') {
      e++;
      j++;
    } else if (str[j] == 'i' || str[j] == 'I') {
      i++;
      j++;
    } else if (str[j] == 'o' || str[j] == 'O') {
      o++;
      j++;
    } else if (str[j] == 'u' || str[j] == 'U') {
      u++;
      j++;
    } else
      j++;
  }
  printf("A(a):%d E(e):%d I(i):%d O(o):%d U(u):%d\n", a, e, i, o, u);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L23:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L23
  sub    $0x6b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movsbl (%rsp),%edi
  mov    %eax,%r12d
  test   %dil,%dil
  je     L144
  mov    $0x1,%ebp
  lea    -0x1(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L87:
  call   <toupper@plt>
  mov    %ebp,%esi
  add    $0x1,%rbp
  movsbl 0x0(%r13,%rbp,1),%edi
  test   %dil,%dil
  jne    L87
L132:
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L138
  lea    -0x1(%r12),%eax
  mov    %rbx,%rdx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  lea    0x1(%rsp,%rax,1),%rdi
  xor    %r12d,%r12d
  xor    %r11d,%r11d
  xor    %esi,%esi
  lea    D4(%rip),%r10
  jmp    L134
  nopl   0x0(%rax)
L97:
  add    $0x1,%esi
L91:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L63
L134:
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x41,%cl
  je     L97
  sub    $0x45,%eax
  cmp    $0x30,%al
  ja     L91
  movzbl %al,%eax
  movslq (%r10,%rax,4),%rax
  add    %r10,%rax
  notrack jmp *%rax
  nopl   (%rax)
  add    $0x1,%rdx
  add    $0x1,%r9d
  cmp    %rdx,%rdi
  jne    L134
  nopl   (%rax)
L63:
  xor    %eax,%eax
  mov    %r12d,%ecx
  lea    D9(%rip),%rdi
  mov    %r11d,%edx
  call   <printf@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L129
  add    $0x186b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
  add    $0x1,%r8d
  jmp    L91
  cs nopw 0x0(%rax,%rax,1)
  add    $0x1,%r12d
  jmp    L91
  nopl   0x0(%rax)
  add    $0x1,%r11d
  jmp    L91
L144:
  xor    %esi,%esi
  jmp    L132
L138:
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  xor    %r11d,%r11d
  xor    %esi,%esi
  jmp    L63
L129:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D11: %d

tool: D9: A(a):%d E(e):%d I(i):%d O(o):%d U(u):%d


assistant: ```c
int main() {
  char str[100000];
  int a = 0, e = 0, i = 0, o = 0, u = 0, j = 0, k, p = 0;
  gets(str);
  k = strlen(str);
  while (str[j] != '\0') {
    switch (toupper(str[j])) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      p++;
    }
    j++;
  }
  printf("%d", j);
  j = 0;
  while (j < k) {
    if (str[j] == 'a' || str[j] == 'A') {
      a++;
      j++;
    } else if (str[j] == 'e' || str[j] == 'E') {
      e++;
      j++;
    } else if (str[j] == 'i' || str[j] == 'I') {
      i++;
      j++;
    } else if (str[j] == 'o' || str[j] == 'O') {
      o++;
      j++;
    } else if (str[j] == 'u' || str[j] == 'U') {
      u++;
      j++;
    } else
      j++;
  }
  printf("A(a):%d E(e):%d I(i):%d O(o):%d U(u):%d\n", a, e, i, o, u);
  return 0;
}
```