ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<libamg_sip_get_session_timers_refresher_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L26
  cmpl   $0x2,-0x4(%rbp)
  jne    L10
  lea    D2(%rip),%rax
  jmp    L3
L26:
  lea    D14(%rip),%rax
  jmp    L3
L10:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string

tool: D2: uac

tool: D14: uas

assistant: ```c
char *libamg_sip_get_session_timers_refresher_name(int session_timers_refresher_code) {
  switch (session_timers_refresher_code) {
  case 0x2:
    return "uac";
    break;
  case 0x1:
    return "uas";
    break;
  default:
    return NULL;
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libamg_sip_get_session_timers_refresher_name>:
  endbr64
  lea    D16(%rip),%rax
  cmp    $0x1,%edi
  je     L3
  cmp    $0x2,%edi
  lea    D13(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L3:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string

tool: D16: uas

tool: D13: uac

assistant: ```c
char *libamg_sip_get_session_timers_refresher_name(int session_timers_refresher_code) {
  switch (session_timers_refresher_code) {
  case 0x2:
    return "uac";
    break;
  case 0x1:
    return "uas";
    break;
  default:
    return NULL;
    break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<libamg_sip_get_session_timers_refresher_name>:
  endbr64
  lea    D17(%rip),%rax
  cmp    $0x1,%edi
  je     L0
  cmp    $0x2,%edi
  lea    D11(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string

tool: D17: uas

tool: D11: uac

assistant: ```c
char *libamg_sip_get_session_timers_refresher_name(int session_timers_refresher_code) {
  switch (session_timers_refresher_code) {
  case 0x2:
    return "uac";
    break;
  case 0x1:
    return "uas";
    break;
  default:
    return NULL;
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libamg_sip_get_session_timers_refresher_name>:
  endbr64
  lea    D0(%rip),%rax
  cmp    $0x1,%edi
  je     L0
  cmp    $0x2,%edi
  lea    D15(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D0: uas

tool: D15: uac

assistant: ```c
char *libamg_sip_get_session_timers_refresher_name(int session_timers_refresher_code) {
  switch (session_timers_refresher_code) {
  case 0x2:
    return "uac";
    break;
  case 0x1:
    return "uas";
    break;
  default:
    return NULL;
    break;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L13
  mov    $0x1,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L13:
  movl   $0x0,-0x28(%rbp)
  jmp    L5
L4:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L5:
  cmpl   $0x0,-0x28(%rbp)
  jle    L4
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  cmp    $0xffffffffc2440221,%rax
  jne    L0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L0:
  movl   $0x0,-0x24(%rbp)
  jmp    L24
L56:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L24:
  cmpl   $0x0,-0x24(%rbp)
  jle    L56
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string

tool: D7: Call this program with %i arguments


tool: D16: You win!

tool: D22: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744072673821217UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L46
L40:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpq   $0xffffffffc2440221,0x10(%rsp)
  je     L6
L39:
  mov    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L46:
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L40
L6:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L39
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string

tool: D0: %lu


tool: D10: Call this program with %i arguments


tool: D12: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744072673821217UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L29
  lea    D11(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0xffffffffc2440221,%rsi
  je     L1
L30:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L30
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D20
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D11: Call this program with %i arguments


tool: D20: %lu


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744072673821217UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L0
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0xffffffffc2440221,%rsi
  je     L16
L6:
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L6
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
datatype: string
name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string

tool: D24: Call this program with %i arguments


tool: D10: %lu


tool: D19: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744072673821217UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L15
L16:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
power(base, n) int base, n;
{
  int i, p;
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L9
  add    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
L17:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L17
L13:
  mov    %edx,%eax
  ret
L9:
  mov    $0x1,%edx
  jmp    L13
```

assistant: ```c
power(base, n) int base, n;
{
  int i, p;
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L3
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L1
  mov    %r8d,%eax
  ret
  nop
L3:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
power(base, n) int base, n;
{
  int i, p;
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L13
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L16
  mov    %r8d,%eax
  ret
  nop
L13:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
power(base, n) int base, n;
{
  int i, p;
  p = 1;
  for (i = 1; i <= n; ++i)
    p = p * base;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <SERVER_init@plt>
  test   %eax,%eax
  jne    L38
  mov    $0x1,%eax
  jmp    L27
L38:
  mov    $0x0,%eax
  call   <PLYRMNGR_init@plt>
  mov    $0x0,%eax
  call   <GMRM_init@plt>
L37:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x77,-0x4(%rbp)
  jle    L16
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <PLYRDB_save_to_disk@plt>
L16:
  mov    $0x0,%eax
  call   <PLYRMNGR_tick@plt>
  mov    $0x0,%eax
  call   <GMRM_tick_all@plt>
  mov    $0x3d090,%edi
  call   <usleep@plt>
  jmp    L37
L27:
  leave
  ret
```

assistant: ```c
int main(void) {
  int save_stats_clock = 0;
  if (!SERVER_init())
    return 1;
  PLYRMNGR_init();
  GMRM_init();
  while (~0) {
    save_stats_clock++;
    if (save_stats_clock >= 120) {
      save_stats_clock = 0;
      PLYRDB_save_to_disk();
    }
    PLYRMNGR_tick();
    GMRM_tick_all();
    usleep(250000);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <SERVER_init@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x1,%eax
  pop    %rbx
  ret
L12:
  mov    $0x0,%eax
  call   <PLYRMNGR_init@plt>
  mov    $0x0,%eax
  call   <GMRM_init@plt>
  mov    $0x1,%ebx
L16:
  mov    $0x0,%eax
  call   <PLYRMNGR_tick@plt>
  mov    $0x0,%eax
  call   <GMRM_tick_all@plt>
  mov    $0x3d090,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    $0x77,%ebx
  jle    L16
  mov    $0x0,%eax
  call   <PLYRDB_save_to_disk@plt>
  mov    $0x0,%ebx
  jmp    L16
```

assistant: ```c
int main(void) {
  int save_stats_clock = 0;
  if (!SERVER_init())
    return 1;
  PLYRMNGR_init();
  GMRM_init();
  while (~0) {
    save_stats_clock++;
    if (save_stats_clock >= 120) {
      save_stats_clock = 0;
      PLYRDB_save_to_disk();
    }
    PLYRMNGR_tick();
    GMRM_tick_all();
    usleep(250000);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <SERVER_init@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x1,%eax
  pop    %rbx
  ret
L15:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <PLYRMNGR_init@plt>
  xor    %eax,%eax
  call   <GMRM_init@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <PLYRMNGR_tick@plt>
  xor    %eax,%eax
  call   <GMRM_tick_all@plt>
  mov    $0x3d090,%edi
  call   <usleep@plt>
  cmp    $0x78,%ebx
  jne    L26
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <PLYRDB_save_to_disk@plt>
  jmp    L26
```

assistant: ```c
int main(void) {
  int save_stats_clock = 0;
  if (!SERVER_init())
    return 1;
  PLYRMNGR_init();
  GMRM_init();
  while (~0) {
    save_stats_clock++;
    if (save_stats_clock >= 120) {
      save_stats_clock = 0;
      PLYRDB_save_to_disk();
    }
    PLYRMNGR_tick();
    GMRM_tick_all();
    usleep(250000);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <SERVER_init@plt>
  test   %eax,%eax
  jne    L24
  mov    $0x1,%eax
  pop    %rbx
  ret
L24:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <PLYRMNGR_init@plt>
  xor    %eax,%eax
  call   <GMRM_init@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <PLYRMNGR_tick@plt>
  xor    %eax,%eax
  call   <GMRM_tick_all@plt>
  mov    $0x3d090,%edi
  call   <usleep@plt>
  cmp    $0x78,%ebx
  jne    L16
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <PLYRDB_save_to_disk@plt>
  jmp    L16
```

assistant: ```c
int main(void) {
  int save_stats_clock = 0;
  if (!SERVER_init())
    return 1;
  PLYRMNGR_init();
  GMRM_init();
  while (~0) {
    save_stats_clock++;
    if (save_stats_clock >= 120) {
      save_stats_clock = 0;
      PLYRDB_save_to_disk();
    }
    PLYRMNGR_tick();
    GMRM_tick_all();
    usleep(250000);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movw   $0x1021,-0x8(%rbp)
  movw   $0xffff,-0xa(%rbp)
  movw   $0x0,-0x6(%rbp)
  jmp    L46
L59:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cbtw
  shl    $0x8,%eax
  mov    %ax,-0x6(%rbp)
  movzwl -0x6(%rbp),%eax
  xor    %ax,-0xa(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L48:
  movzwl -0xa(%rbp),%eax
  test   %ax,%ax
  jns    L2
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzwl -0x8(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L1
L2:
  shlw   -0xa(%rbp)
L1:
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x7,-0x4(%rbp)
  jle    L48
L46:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L59
  movzwl -0xa(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int crc16(char *msg, int size) {
  unsigned short poly = 0x1021;
  unsigned short crc = 0xffff;
  unsigned short byte = 0;
  while (--size >= 0) {
    byte = ((unsigned short)*msg++) << 8;
    crc = crc ^ byte;
    int i;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000) {
        crc = (crc << 1) ^ poly;
      } else {
        crc = crc << 1;
      }
    }
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc16>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0xffffffff,%eax
  jmp    L31
L10:
  cmp    %r8,%rdi
  je     L21
L31:
  add    $0x1,%rdi
  movsbw -0x1(%rdi),%dx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L45:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L45
  jmp    L10
L18:
  mov    $0xffffffff,%eax
L21:
  movzwl %ax,%eax
  ret
```

assistant: ```c
int crc16(char *msg, int size) {
  unsigned short poly = 0x1021;
  unsigned short crc = 0xffff;
  unsigned short byte = 0;
  while (--size >= 0) {
    byte = ((unsigned short)*msg++) << 8;
    crc = crc ^ byte;
    int i;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000) {
        crc = (crc << 1) ^ poly;
      } else {
        crc = crc << 1;
      }
    }
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc16>:
  endbr64
  test   %esi,%esi
  jle    L25
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0xffffffff,%eax
  nopl   (%rax)
L13:
  movsbw (%rdi),%dx
  add    $0x1,%rdi
  mov    $0x8,%ecx
  shl    $0x8,%edx
  xor    %edx,%eax
  nopw   0x0(%rax,%rax,1)
L23:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L23
  cmp    %rdi,%r8
  jne    L13
  movzwl %ax,%eax
  ret
L25:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
int crc16(char *msg, int size) {
  unsigned short poly = 0x1021;
  unsigned short crc = 0xffff;
  unsigned short byte = 0;
  while (--size >= 0) {
    byte = ((unsigned short)*msg++) << 8;
    crc = crc ^ byte;
    int i;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000) {
        crc = (crc << 1) ^ poly;
      } else {
        crc = crc << 1;
      }
    }
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc16>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffffffff,%eax
  jmp    L34
  xchg   %ax,%ax
L110:
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L169
L15:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L160
L28:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L73
L21:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L18
L137:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L119
L139:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L11
L38:
  add    %eax,%eax
  mov    %eax,%edx
L102:
  lea    (%rax,%rax,1),%edi
  mov    %edi,%eax
  xor    $0x1021,%ax
  test   %dx,%dx
  cmovns %edi,%eax
  cmp    %rcx,%rsi
  je     L145
L34:
  movsbw (%rcx),%dx
  add    $0x1,%rcx
  shl    $0x8,%edx
  xor    %ax,%dx
  jns    L110
  add    %edx,%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L15
L169:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L28
L160:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L21
L73:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L137
L18:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L139
L119:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L38
L11:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  jmp    L102
  nop
L145:
  movzwl %ax,%eax
  ret
L45:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
int crc16(char *msg, int size) {
  unsigned short poly = 0x1021;
  unsigned short crc = 0xffff;
  unsigned short byte = 0;
  while (--size >= 0) {
    byte = ((unsigned short)*msg++) << 8;
    crc = crc ^ byte;
    int i;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000) {
        crc = (crc << 1) ^ poly;
      } else {
        crc = crc << 1;
      }
    }
  }
  return crc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sshbuf_get_u8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sshbuf_ptr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <sshbuf_consume@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L29
  mov    -0xc(%rbp),%eax
  jmp    L11
L29:
  cmpq   $0x0,-0x20(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L8:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int sshbuf_get_u8(struct sshbuf *buf, u_char *valp) {
  const u_char *p = sshbuf_ptr(buf);
  int r;
  if ((r = sshbuf_consume(buf, 1)) < 0)
    return r;
  if (valp != NULL)
    *valp = (u_int8_t)*p;
  return 0;
}
```