ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<substr>:
  endbr64
  mov    %rdi,%r9
  test   %ecx,%ecx
  jle    L38
  movslq %edx,%rdx
  lea    0x1(%rcx),%r8d
  mov    $0x1,%eax
  add    %rdx,%rsi
  jmp    L20
  nopl   0x0(%rax)
L14:
  mov    %dl,(%rdi)
  movslq %eax,%rdx
  add    $0x1,%rax
  lea    0x1(%rcx),%rdi
  cmp    %r8,%rax
  je     L21
L20:
  movzbl -0x1(%rsi,%rax,1),%edx
  mov    %rdi,%rcx
  test   %dl,%dl
  jne    L14
L48:
  movb   $0x0,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  lea    (%r9,%rdx,1),%rcx
  movb   $0x0,(%rcx)
  ret
L38:
  mov    %rdi,%rcx
  jmp    L48
```

assistant: ```c
substr(char dest[], char src[], int offset, int len) {
  int i;
  for (i = 0; i < len && src[offset + i] != '\0'; i++)
    dest[i] = src[i + offset];
  dest[i] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<to_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L29
  cmpb   $0x5a,-0x4(%rbp)
  jg     L29
  movzbl -0x4(%rbp),%eax
  add    $0x20,%eax
  jmp    L22
L29:
  movzbl -0x4(%rbp),%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
char to_lower(char character) {
  if ((character >= 'A') && (character <= 'Z')) {
    return (char)((uint8_t)character - (uint8_t)('A' - 'a'));
  } else {
    return character;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<to_lower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char to_lower(char character) {
  if ((character >= 'A') && (character <= 'Z')) {
    return (char)((uint8_t)character - (uint8_t)('A' - 'a'));
  } else {
    return character;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<to_lower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char to_lower(char character) {
  if ((character >= 'A') && (character <= 'Z')) {
    return (char)((uint8_t)character - (uint8_t)('A' - 'a'));
  } else {
    return character;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_lower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char to_lower(char character) {
  if ((character >= 'A') && (character <= 'Z')) {
    return (char)((uint8_t)character - (uint8_t)('A' - 'a'));
  } else {
    return character;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<transcross3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  jmp    L18
L22:
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  movsd  %xmm0,-0x40(%rbp,%rax,8)
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x44(%rbp),%eax
  cltq
  movsd  %xmm0,-0x20(%rbp,%rax,8)
  addl   $0x1,-0x44(%rbp)
L18:
  cmpl   $0x2,-0x44(%rbp)
  jle    L22
  mov    -0x70(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cross3@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void transcross3(const double origin[3], const double v0[3], const double v1[3], double result[3]) {
  double u0[3], u1[3];
  int i;
  for (i = 0; i < 3; ++i) {
    u0[i] = v0[i] - origin[i];
    u1[i] = v1[i] - origin[i];
  }
  cross3(u0, u1, result);
}
```
user: What is the c source code of the assembly code below?

```asm
<transcross3>:
  endbr64
  sub    $0x48,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
L6:
  movsd  (%rdi,%rax,1),%xmm1
  movsd  (%rsi,%rax,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsp,%rax,1)
  movsd  (%r8,%rax,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rsp,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L6
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  call   <cross3@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void transcross3(const double origin[3], const double v0[3], const double v1[3], double result[3]) {
  double u0[3], u1[3];
  int i;
  for (i = 0; i < 3; ++i) {
    u0[i] = v0[i] - origin[i];
    u1[i] = v1[i] - origin[i];
  }
  cross3(u0, u1, result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transcross3>:
  endbr64
  sub    $0x48,%rsp
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  lea    0x20(%rsp),%r10
L12:
  movsd  (%r8,%rax,1),%xmm1
  movsd  (%rsi,%rax,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r9,%rax,1)
  movsd  (%rdi,%rax,1),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r10,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L12
  mov    %r10,%rsi
  mov    %r9,%rdi
  call   <cross3@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x48,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void transcross3(const double origin[3], const double v0[3], const double v1[3], double result[3]) {
  double u0[3], u1[3];
  int i;
  for (i = 0; i < 3; ++i) {
    u0[i] = v0[i] - origin[i];
    u1[i] = v1[i] - origin[i];
  }
  cross3(u0, u1, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transcross3>:
  endbr64
  sub    $0x48,%rsp
  movupd (%rdi),%xmm2
  movupd (%rsi),%xmm0
  mov    %rdx,%rax
  mov    %rcx,%rdx
  movsd  0x10(%rdi),%xmm1
  mov    %rsp,%rdi
  mov    %fs:0x28,%rcx
  mov    %rcx,0x38(%rsp)
  xor    %ecx,%ecx
  subpd  %xmm2,%xmm0
  movaps %xmm0,(%rsp)
  movupd (%rax),%xmm0
  subpd  %xmm2,%xmm0
  movaps %xmm0,0x20(%rsp)
  movsd  0x10(%rsi),%xmm0
  lea    0x20(%rsp),%rsi
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x10(%rax),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rsp)
  call   <cross3@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void transcross3(const double origin[3], const double v0[3], const double v1[3], double result[3]) {
  double u0[3], u1[3];
  int i;
  for (i = 0; i < 3; ++i) {
    u0[i] = v0[i] - origin[i];
    u1[i] = v1[i] - origin[i];
  }
  cross3(u0, u1, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Intro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D26: 
Programmer:		 Sam N.

tool: D6: 
Programming Assignment:	 3

tool: D37: 
Due Date:		 March 29, 2015

tool: D8: 
Program Description:	 The program will calculate the amount of
			 property taxes owed.



assistant: ```c
void Intro() {
  printf("\nProgrammer:\t\t Sam N.");
  printf("\nProgramming Assignment:\t 3");
  printf("\nDue Date:\t\t March 29, 2015");
  printf("\nProgram Description:\t The program will calculate the amount of\n\t\t\t property taxes owed.\n\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D0: 
Programmer:		 Sam N.

tool: D14: 
Programming Assignment:	 3

tool: D7: 
Due Date:		 March 29, 2015

tool: D3: 
Program Description:	 The program will calculate the amount of
			 property taxes owed.



assistant: ```c
void Intro() {
  printf("\nProgrammer:\t\t Sam N.");
  printf("\nProgramming Assignment:\t 3");
  printf("\nDue Date:\t\t March 29, 2015");
  printf("\nProgram Description:\t The program will calculate the amount of\n\t\t\t property taxes owed.\n\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string

tool: D24: 
Programmer:		 Sam N.

tool: D29: 
Programming Assignment:	 3

tool: D14: 
Due Date:		 March 29, 2015

tool: D18: 
Program Description:	 The program will calculate the amount of
			 property taxes owed.



assistant: ```c
void Intro() {
  printf("\nProgrammer:\t\t Sam N.");
  printf("\nProgramming Assignment:\t 3");
  printf("\nDue Date:\t\t March 29, 2015");
  printf("\nProgram Description:\t The program will calculate the amount of\n\t\t\t property taxes owed.\n\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string

tool: D13: 
Programmer:		 Sam N.

tool: D17: 
Programming Assignment:	 3

tool: D5: 
Due Date:		 March 29, 2015

tool: D34: 
Program Description:	 The program will calculate the amount of
			 property taxes owed.



assistant: ```c
void Intro() {
  printf("\nProgrammer:\t\t Sam N.");
  printf("\nProgramming Assignment:\t 3");
  printf("\nDue Date:\t\t March 29, 2015");
  printf("\nProgram Description:\t The program will calculate the amount of\n\t\t\t property taxes owed.\n\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<marshal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    -0x40(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
  movl   $0x0,-0x28(%rbp)
  jmp    L70
L35:
  mov    -0x28(%rbp),%edx
  movslq %ebx,%rax
  imul   %rax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jbe    L44
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L44:
  addl   $0x1,-0x28(%rbp)
L70:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x28(%rbp)
  jb     L35
  movl   $0x0,-0x28(%rbp)
  jmp    L33
L12:
  movl   $0x0,-0x24(%rbp)
  jmp    L42
L68:
  mov    -0x28(%rbp),%edx
  movslq %ebx,%rax
  imul   %rax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  je     L87
  mov    -0x28(%rbp),%edx
  movslq %ebx,%rax
  imul   %rax,%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rdx)
  jmp    L77
L87:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x7e,(%rax)
L77:
  addl   $0x1,-0x24(%rbp)
L42:
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x24(%rbp)
  jb     L68
  addl   $0x1,-0x28(%rbp)
L33:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x28(%rbp)
  jb     L12
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *marshal(char *mstr, int rows, int cols, char arr[][cols]) {
  unsigned int a = 0, b = 0, w = 2, ln = 0;
  mstr[0] = rows;
  for (a = 0; a < mstr[0]; a++) {
    ln = strlen(arr[a]);
    if (mstr[1] < ln)
      mstr[1] = ln;
  }
  for (a = 0; a < mstr[0]; a++) {
    for (b = 0; b < mstr[1]; b++) {
      if (arr[a][b])
        mstr[w++] = arr[a][b];
      else
        mstr[w++] = '~';
    }
  }
  mstr[w] = 0;
  return mstr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<marshal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %sil,(%rdi)
  test   %sil,%sil
  je     L69
  mov    %rcx,%r12
  movslq %edx,%rbp
  mov    $0x0,%r13d
  jmp    L131
L84:
  add    $0x1,%r13d
  movzbl (%rbx),%eax
  movsbl %al,%edx
  cmp    %r13d,%edx
  jbe    L88
L131:
  mov    %r13d,%edi
  imul   %rbp,%rdi
  add    %r12,%rdi
  call   <strlen@plt>
  movsbl 0x1(%rbx),%edx
  cmp    %eax,%edx
  jae    L84
  mov    %al,0x1(%rbx)
  jmp    L84
L88:
  test   %al,%al
  je     L115
  mov    $0x2,%ecx
  mov    $0x0,%r8d
  jmp    L83
L115:
  mov    $0x2,%ecx
  jmp    L125
L11:
  mov    %edx,%edx
  movb   $0x7e,(%rbx,%rdx,1)
L116:
  add    $0x1,%eax
  lea    0x1(%rcx),%esi
  movsbl 0x1(%rbx),%edx
  cmp    %eax,%edx
  jbe    L27
  mov    %esi,%ecx
L5:
  lea    -0x1(%rcx),%edx
  mov    %eax,%esi
  movzbl (%rdi,%rsi,1),%esi
  test   %sil,%sil
  je     L11
  mov    %edx,%edx
  mov    %sil,(%rbx,%rdx,1)
  jmp    L116
L27:
  add    $0x1,%r8d
  movsbl (%rbx),%eax
  cmp    %r8d,%eax
  jbe    L125
L83:
  cmpb   $0x0,0x1(%rbx)
  je     L27
  mov    %r8d,%edi
  imul   %rbp,%rdi
  add    %r12,%rdi
  add    $0x1,%ecx
  mov    $0x0,%eax
  jmp    L5
L69:
  mov    $0x2,%ecx
L125:
  mov    %ecx,%ecx
  movb   $0x0,(%rbx,%rcx,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *marshal(char *mstr, int rows, int cols, char arr[][cols]) {
  unsigned int a = 0, b = 0, w = 2, ln = 0;
  mstr[0] = rows;
  for (a = 0; a < mstr[0]; a++) {
    ln = strlen(arr[a]);
    if (mstr[1] < ln)
      mstr[1] = ln;
  }
  for (a = 0; a < mstr[0]; a++) {
    for (b = 0; b < mstr[1]; b++) {
      if (arr[a][b])
        mstr[w++] = arr[a][b];
      else
        mstr[w++] = '~';
    }
  }
  mstr[w] = 0;
  return mstr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<marshal>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %sil,(%rdi)
  test   %sil,%sil
  je     L65
  mov    %rcx,%rbp
  movslq %edx,%rbx
  xor    %r13d,%r13d
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %r13d,%edi
  imul   %rbx,%rdi
  add    %rbp,%rdi
  call   <strlen@plt>
  movsbl 0x1(%r12),%edx
  cmp    %eax,%edx
  jae    L44
  mov    %al,0x1(%r12)
L44:
  movsbl (%r12),%edx
  add    $0x1,%r13d
  cmp    %r13d,%edx
  ja     L79
  test   %dl,%dl
  je     L65
  mov    $0x2,%ecx
  xor    %r9d,%r9d
  mov    $0x7e,%r8d
  xchg   %ax,%ax
L12:
  cmpb   $0x0,0x1(%r12)
  je     L41
  mov    %r9d,%edi
  xor    %edx,%edx
  imul   %rbx,%rdi
  add    %rbp,%rdi
  nopl   0x0(%rax)
L49:
  mov    %edx,%eax
  mov    %ecx,%esi
  add    $0x1,%ecx
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  cmove  %r8d,%eax
  add    $0x1,%edx
  mov    %al,(%r12,%rsi,1)
  movsbl 0x1(%r12),%eax
  cmp    %edx,%eax
  ja     L49
L41:
  movsbl (%r12),%eax
  add    $0x1,%r9d
  cmp    %r9d,%eax
  ja     L12
L76:
  movb   $0x0,(%r12,%rcx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L65:
  mov    $0x2,%ecx
  jmp    L76
```

assistant: ```c
char *marshal(char *mstr, int rows, int cols, char arr[][cols]) {
  unsigned int a = 0, b = 0, w = 2, ln = 0;
  mstr[0] = rows;
  for (a = 0; a < mstr[0]; a++) {
    ln = strlen(arr[a]);
    if (mstr[1] < ln)
      mstr[1] = ln;
  }
  for (a = 0; a < mstr[0]; a++) {
    for (b = 0; b < mstr[1]; b++) {
      if (arr[a][b])
        mstr[w++] = arr[a][b];
      else
        mstr[w++] = '~';
    }
  }
  mstr[w] = 0;
  return mstr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<marshal>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %sil,(%rdi)
  test   %sil,%sil
  je     L11
  mov    %rcx,%rbp
  movslq %edx,%rbx
  xor    %r13d,%r13d
  cs nopw 0x0(%rax,%rax,1)
L97:
  mov    %r13d,%edi
  imul   %rbx,%rdi
  add    %rbp,%rdi
  call   <strlen@plt>
  movsbl 0x1(%r12),%ecx
  mov    %ecx,%edx
  cmp    %eax,%ecx
  jae    L91
  mov    %al,0x1(%r12)
  mov    %eax,%edx
L91:
  movsbl (%r12),%ecx
  add    $0x1,%r13d
  cmp    %r13d,%ecx
  ja     L97
  test   %cl,%cl
  je     L11
  mov    $0x2,%ecx
  xor    %r8d,%r8d
L45:
  test   %dl,%dl
  je     L114
  mov    %r8d,%edi
  xor    %eax,%eax
  imul   %rbx,%rdi
  add    %rbp,%rdi
L85:
  mov    %eax,%edx
  movzbl (%rdi,%rdx,1),%esi
  mov    %ecx,%edx
  add    $0x1,%ecx
  add    %r12,%rdx
  test   %sil,%sil
  jne    L69
  movb   $0x7e,(%rdx)
  movsbl 0x1(%r12),%esi
  add    $0x1,%eax
  mov    %esi,%edx
  cmp    %esi,%eax
  jb     L85
  movsbl (%r12),%eax
  add    $0x1,%r8d
  cmp    %r8d,%eax
  ja     L45
L114:
  movb   $0x0,(%r12,%rcx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %sil,(%rdx)
  movsbl 0x1(%r12),%esi
  add    $0x1,%eax
  mov    %esi,%edx
  cmp    %eax,%esi
  ja     L85
  movsbl (%r12),%eax
  add    $0x1,%r8d
  cmp    %r8d,%eax
  ja     L45
  jmp    L114
L11:
  mov    $0x2,%ecx
  jmp    L114
```

assistant: ```c
char *marshal(char *mstr, int rows, int cols, char arr[][cols]) {
  unsigned int a = 0, b = 0, w = 2, ln = 0;
  mstr[0] = rows;
  for (a = 0; a < mstr[0]; a++) {
    ln = strlen(arr[a]);
    if (mstr[1] < ln)
      mstr[1] = ln;
  }
  for (a = 0; a < mstr[0]; a++) {
    for (b = 0; b < mstr[1]; b++) {
      if (arr[a][b])
        mstr[w++] = arr[a][b];
      else
        mstr[w++] = '~';
    }
  }
  mstr[w] = 0;
  return mstr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L43
L29:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x61,%al
  je     L20
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x65,%al
  je     L20
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x69,%al
  je     L20
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x6f,%al
  je     L20
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x75,%al
  je     L20
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    $0x79,%al
  jne    L59
L20:
  addl   $0x1,-0x28(%rbp)
L59:
  addl   $0x1,-0x2c(%rbp)
L43:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L29
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D24
type: string

tool: D23: Please enter a string > 

tool: D1: %s

tool: D24: The number of syllables is %d.


assistant: ```c
int main() {
  char instr[21];
  int i, len, s;
  s = 0;
  printf("Please enter a string > ");
  scanf("%s", instr);
  len = strlen(instr);
  for (i = 0; i < len; i++) {
    if (instr[i] == 'a' || instr[i] == 'e' || instr[i] == 'i' || instr[i] == 'o' || instr[i] == 'u' || instr[i] == 'y')
      s = s + 1;
  }
  printf("The number of syllables is %d.\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  mov    %rsp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%rdi
  mov    $0x0,%esi
  mov    $0x11041,%r8d
  jmp    L74
L14:
  add    $0x1,%esi
L73:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L30
L74:
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  and    $0xfffffffb,%ecx
  cmp    $0x61,%cl
  je     L14
  sub    $0x69,%eax
  cmp    $0x10,%al
  ja     L73
  bt     %rax,%r8
  jae    L73
  jmp    L14
L16:
  mov    $0x0,%esi
L30:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D29
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D29: Please enter a string > 

tool: D17: %s

tool: D9: The number of syllables is %d.


assistant: ```c
int main() {
  char instr[21];
  int i, len, s;
  s = 0;
  printf("Please enter a string > ");
  scanf("%s", instr);
  len = strlen(instr);
  for (i = 0; i < len; i++) {
    if (instr[i] == 'a' || instr[i] == 'e' || instr[i] == 'i' || instr[i] == 'o' || instr[i] == 'u' || instr[i] == 'y')
      s = s + 1;
  }
  printf("The number of syllables is %d.\n", s);
  return 0;
}
```