ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<f91>:
  endbr64
  mov    %edi,%eax
  cmp    $0x64,%edi
  jg     L164
L327:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L237
L378:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L376
L356:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L201
L71:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L279
L231:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L190
L129:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L312
L381:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L125
L40:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L110
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L157:
  lea    0xb(%rax),%edi
  call   <f91>
  cmp    $0x64,%eax
  jle    L157
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L298
L355:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L157
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L355
L298:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L387
L363:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L355
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L363
L387:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L76
L328:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L363
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L328
L76:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L320
L147:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L328
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L147
L320:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L45
L12:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L147
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L12
L45:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L416
L84:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L12
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L84
L416:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L319
L41:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L84
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L41
L319:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L111
L209:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L41
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L209
L111:
  sub    $0xa,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L110:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L40
L125:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L381
L312:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L129
L190:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L231
L279:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L71
L201:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L356
L376:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L378
L237:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L327
L164:
  sub    $0xa,%eax
  ret
```

assistant: ```c
int f91(int N) {
  if (N <= 100)
    return (f91(f91(N + 11)));
  else
    return (N - 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubblesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L15
L26:
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L8:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L37
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L37:
  addl   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L8
  subl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x0,-0xc(%rbp)
  jns    L26
  nop
  pop    %rbp
  ret
```

assistant: ```c
int bubblesort(int lista[], int n) {
  n = n - 1;
  int temp, x, i;
  for (x = n; x >= 0; x--) {
    for (i = 0; i < x; i++) {
      if (lista[i] > lista[i + 1]) {
        temp = lista[i];
        lista[i] = lista[i + 1];
        lista[i + 1] = temp;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubblesort>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x2(%rsi),%r8d
  lea    0x4(%rdi),%r9
  jmp    L71
L11:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L65
L55:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L11
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L11
L5:
  test   %r8d,%r8d
  jns    L65
L2:
  ret
L65:
  sub    $0x1,%r8d
L71:
  lea    0x1(%r8),%eax
  test   %eax,%eax
  jle    L5
  mov    %rdi,%rax
  mov    %r8d,%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L55
```

assistant: ```c
int bubblesort(int lista[], int n) {
  n = n - 1;
  int temp, x, i;
  for (x = n; x >= 0; x--) {
    for (i = 0; i < x; i++) {
      if (lista[i] > lista[i + 1]) {
        temp = lista[i];
        lista[i] = lista[i + 1];
        lista[i + 1] = temp;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubblesort>:
  endbr64
  lea    0x4(%rdi),%r9
  sub    $0x1,%esi
  js     L20
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L36
  nopl   (%rax)
L59:
  mov    %r8d,%edx
  mov    %rdi,%rax
  lea    (%r9,%rdx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L40:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L21
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L21:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L40
L19:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jg     L59
L36:
  test   %r8d,%r8d
  jns    L19
  ret
L20:
  ret
```

assistant: ```c
int bubblesort(int lista[], int n) {
  n = n - 1;
  int temp, x, i;
  for (x = n; x >= 0; x--) {
    for (i = 0; i < x; i++) {
      if (lista[i] > lista[i + 1]) {
        temp = lista[i];
        lista[i] = lista[i + 1];
        lista[i + 1] = temp;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubblesort>:
  endbr64
  lea    0x4(%rdi),%r9
  sub    $0x1,%esi
  js     L0
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L6
  nopl   (%rax)
L50:
  mov    %r8d,%eax
  mov    %rdi,%rdx
  lea    (%r9,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L4:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L20
  movq   %xmm1,(%rdx)
L20:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L4
L16:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jg     L50
L6:
  test   %r8d,%r8d
  jns    L16
  ret
L0:
  ret
```

assistant: ```c
int bubblesort(int lista[], int n) {
  n = n - 1;
  int temp, x, i;
  for (x = n; x >= 0; x--) {
    for (i = 0; i < x; i++) {
      if (lista[i] > lista[i + 1]) {
        temp = lista[i];
        lista[i] = lista[i + 1];
        lista[i + 1] = temp;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_frozen_tests>:
  endbr64
  ret
```

assistant: ```c
void do_frozen_tests() {
  struct {
    int i;
    struct {
      int j;
      int k;
    } nested;
  } v1 = {1, {2, 3}};
  int v2 = 4;
  v2 = 5;
  v2 = 6;
  v1.i = 7;
  v1.nested.j = 8;
  v1.nested.k = 9;
  v1.i = 10;
  v1.nested.j = 11;
  v1.nested.k = 12;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_frozen_tests>:
  endbr64
  ret
```

assistant: ```c
void do_frozen_tests() {
  struct {
    int i;
    struct {
      int j;
      int k;
    } nested;
  } v1 = {1, {2, 3}};
  int v2 = 4;
  v2 = 5;
  v2 = 6;
  v1.i = 7;
  v1.nested.j = 8;
  v1.nested.k = 9;
  v1.i = 10;
  v1.nested.j = 11;
  v1.nested.k = 12;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x128(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x134(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x130(%rbp)
L31:
  mov    -0x128(%rbp),%rax
  mov    -0x134(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0x130(%rbp),%eax
  cltq
  mov    %edx,-0x120(%rbp,%rax,4)
  addl   $0x1,-0x130(%rbp)
  mov    -0x128(%rbp),%rax
  mov    -0x134(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rax,-0x128(%rbp)
  mov    -0x128(%rbp),%rax
  test   %rax,%rax
  jne    L31
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  subl   $0x1,-0x130(%rbp)
  jmp    L6
L26:
  mov    -0x130(%rbp),%eax
  cltq
  mov    -0x120(%rbp,%rax,4),%eax
  mov    %eax,-0x12c(%rbp)
  mov    -0x12c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x130(%rbp)
L6:
  cmpl   $0x0,-0x130(%rbp)
  jns    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D45
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D22
type_infered: string
name: retrieve_data
arguments: tag: D34
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string

tool: D45: Input a number:

tool: D2: %ld

tool: D22: Input new base(2-16):

tool: D34: %d

tool: D47: Transmite new base:

assistant: ```c
void main() {
  char b[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int c[64], d, i, base;
  long n;
  printf("Input a number:\n");
  scanf("%ld", &n);
  printf("Input new base(2-16):\n");
  scanf("%d", &base);
  i = 0;
  do {
    c[i] = n % base;
    i++;
    n /= base;
  } while (n != 0);
  printf("Transmite new base:\n");
  for (--i; i >= 0; --i) {
    d = c[i];
    printf("%c", b[d]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,0x110(%rsp)
  mov    %rdx,0x118(%rsp)
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rdx
  movslq 0x4(%rsp),%rsi
  mov    $0x0,%ecx
L26:
  mov    %ecx,%ebx
  mov    %rdx,%rax
  cqto
  idiv   %rsi
  mov    %edx,0x10(%rsp,%rcx,4)
  mov    %rax,%rdx
  mov    %rcx,%rbp
  add    $0x1,%rcx
  test   %rax,%rax
  jne    L26
  movq   $0x0,0x8(%rsp)
  lea    D42(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  js     L10
  movslq %ebx,%rbx
  lea    0x0(,%rbx,4),%rax
  lea    0x10(%rsp,%rax,1),%rbx
  lea    0xc(%rsp,%rax,1),%r12
  mov    %ebp,%ebp
  shl    $0x2,%rbp
  sub    %rbp,%r12
L39:
  movslq (%rbx),%rax
  movsbl 0x110(%rsp,%rax,1),%edi
  call   <putchar@plt>
  sub    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L39
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x130,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D42
data_type: string

tool: D11: Input a number:

tool: D0: %ld

tool: D10: Input new base(2-16):

tool: D17: %d

tool: D42: Transmite new base:

assistant: ```c
void main() {
  char b[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int c[64], d, i, base;
  long n;
  printf("Input a number:\n");
  scanf("%ld", &n);
  printf("Input new base(2-16):\n");
  scanf("%d", &base);
  i = 0;
  do {
    c[i] = n % base;
    i++;
    n /= base;
  } while (n != 0);
  printf("Transmite new base:\n");
  for (--i; i >= 0; --i) {
    d = c[i];
    printf("%c", b[d]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x130,%rsp
  movdqa D54(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x110(%rsp)
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  movslq 0x4(%rsp),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L19:
  cqto
  mov    %ecx,%ebx
  idiv   %rsi
  mov    %edx,0x0(%rbp,%rcx,4)
  movslq %edx,%r12
  add    $0x1,%rcx
  test   %rax,%rax
  jne    L19
  lea    D39(%rip),%rdi
  sub    $0x1,%ebx
  movq   $0x0,0x8(%rsp)
  call   <puts@plt>
  movslq %ebx,%rbx
  jmp    L37
  nopl   0x0(%rax)
L22:
  movslq 0x0(%rbp,%rbx,4),%r12
  sub    $0x1,%rbx
L37:
  movsbl 0x110(%rsp,%r12,1),%edi
  call   <putchar@plt>
  cmp    $0xffffffff,%ebx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x130,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D54
type: byte[16]
name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D53
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D39
type: string

tool: D17: Input a number:

tool: {"D54": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D4: %ld

tool: D53: Input new base(2-16):

tool: D14: %d

tool: D39: Transmite new base:

assistant: ```c
void main() {
  char b[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int c[64], d, i, base;
  long n;
  printf("Input a number:\n");
  scanf("%ld", &n);
  printf("Input new base(2-16):\n");
  scanf("%d", &base);
  i = 0;
  do {
    c[i] = n % base;
    i++;
    n /= base;
  } while (n != 0);
  printf("Transmite new base:\n");
  for (--i; i >= 0; --i) {
    d = c[i];
    printf("%c", b[d]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x130,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movaps %xmm0,0x110(%rsp)
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  movslq 0x4(%rsp),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L29:
  cqto
  movslq %ecx,%rbp
  mov    %rcx,%r12
  idiv   %rsi
  mov    %edx,(%rbx,%rcx,4)
  add    $0x1,%rcx
  test   %rax,%rax
  jne    L29
  shl    $0x2,%rbp
  lea    D13(%rip),%rdi
  shl    $0x2,%r12
  movq   $0x0,0x8(%rsp)
  call   <puts@plt>
  add    %rbp,%rbx
  lea    0xc(%rsp,%rbp,1),%rbp
  sub    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  movslq (%rbx),%rax
  sub    $0x4,%rbx
  movsbl 0x110(%rsp,%rax,1),%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x130,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D38
datatype: string
name: unpack_data
arguments: tag: D22
datatype: byte[16]
name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string

tool: D38: Input a number:

tool: {"D22": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: D36: %ld

tool: D35: Input new base(2-16):

tool: D40: %d

tool: D13: Transmite new base:

assistant: ```c
void main() {
  char b[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int c[64], d, i, base;
  long n;
  printf("Input a number:\n");
  scanf("%ld", &n);
  printf("Input new base(2-16):\n");
  scanf("%d", &base);
  i = 0;
  do {
    c[i] = n % base;
    i++;
    n /= base;
  } while (n != 0);
  printf("Transmite new base:\n");
  for (--i; i >= 0; --i) {
    d = c[i];
    printf("%c", b[d]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  jmp    L52
L5:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
L52:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  jmp    L1
L48:
  nop
L1:
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  cmpq   $0x0,-0x38(%rbp)
  je     L62
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L62:
  nop
L66:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
L21:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlcpy(char *__restrict dst, const char *__restrict src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L6
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L31:
  cmp    %rcx,%rdi
  je     L21
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L31
  jmp    L9
L6:
  mov    %rsi,%rax
L57:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L57
L9:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L21:
  movb   $0x0,(%rdi)
  jmp    L57
```

assistant: ```c
size_t strlcpy(char *__restrict dst, const char *__restrict src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L44
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L37
L46:
  movzbl (%rax),%edx
  mov    %rax,%r8
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L26
  mov    %r8,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L35
L37:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L35
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *__restrict dst, const char *__restrict src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L30
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L1
L38:
  movzbl (%rax),%edx
  mov    %rax,%r8
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L40
  mov    %r8,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L35
L1:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L35
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *__restrict dst, const char *__restrict src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<account_irq_enter_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vtime_account_irq_enter@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <irqtime_account_irq@plt>
  nop
  leave
  ret
```

assistant: ```c
void account_irq_enter_time(struct task_struct *tsk) {
  vtime_account_irq_enter(tsk);
  irqtime_account_irq(tsk);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<account_irq_enter_time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vtime_account_irq_enter@plt>
  mov    %rbx,%rdi
  call   <irqtime_account_irq@plt>
  pop    %rbx
  ret
```

assistant: ```c
void account_irq_enter_time(struct task_struct *tsk) {
  vtime_account_irq_enter(tsk);
  irqtime_account_irq(tsk);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<account_irq_enter_time>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <vtime_account_irq_enter@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <irqtime_account_irq@plt>
```

assistant: ```c
void account_irq_enter_time(struct task_struct *tsk) {
  vtime_account_irq_enter(tsk);
  irqtime_account_irq(tsk);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<account_irq_enter_time>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <vtime_account_irq_enter@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <irqtime_account_irq@plt>
```

assistant: ```c
void account_irq_enter_time(struct task_struct *tsk) {
  vtime_account_irq_enter(tsk);
  irqtime_account_irq(tsk);
}
```