ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_getNext>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <getNext@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rdi
  mov    $0x1,%r14d
  movabs $0xe5032477ae8d46a5,%r12
  movabs $0x1ad7f29abca,%rbx
  call   <free@plt>
  xor    %eax,%eax
  lea    D13(%rip),%r13
  call   <getNext@plt>
  mov    %rax,%rbp
  xchg   %ax,%ax
L29:
  test   %rbp,%rbp
  je     L19
L30:
  mov    %rbp,%rdi
  add    $0x1,%r14
  call   <free@plt>
  xor    %eax,%eax
  call   <getNext@plt>
  mov    %rax,%rbp
  mov    %r14,%rax
  imul   %r12,%rax
  ror    $0x7,%rax
  cmp    %rbx,%rax
  ja     L29
  xor    %eax,%eax
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  jne    L30
L19:
  mov    %r14,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D0
type: string

tool: D13: num %llu  ip   %s


tool: D0: %llu

assistant: ```c
void test_getNext() {
  unsigned long long int counta = 0;
  char *ip = getNext();
  while (ip != NULL) {
    counta++;
    free(ip);
    ip = getNext();
    if (counta % 10000000 == 0) {
      printf("num %llu  ip   %s\n", counta, ip);
    }
  }
  printf("%llu", counta);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L13
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  int i = 2;
  while (i <= n) {
    r *= i;
    i++;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fact>:
  endbr64
  cmp    $0x1,%edi
  jle    L13
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x1,%edx
L18:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L18
L26:
  mov    %edx,%eax
  ret
L13:
  mov    $0x1,%edx
  jmp    L26
```

assistant: ```c
int fact(int n) {
  int r = 1;
  int i = 2;
  while (i <= n) {
    r *= i;
    i++;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fact>:
  endbr64
  cmp    $0x1,%edi
  jle    L18
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L4:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L4
  mov    %r8d,%eax
  ret
  nop
L18:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  int i = 2;
  while (i <= n) {
    r *= i;
    i++;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fact>:
  endbr64
  cmp    $0x1,%edi
  jle    L3
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L18:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L18
  mov    %r8d,%eax
  ret
  nop
L3:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fact(int n) {
  int r = 1;
  int i = 2;
  while (i <= n) {
    r *= i;
    i++;
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pointer_to_pointer@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D23: IN MAIN: 

tool: D8: addr of a = %u, addr of b = %u



tool: D6: a = %d, b = %d


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("IN MAIN: \n");
  printf("addr of a = %u, addr of b = %u\n\n", &a, &b);
  swap(&a, &b);
  printf("a = %d, b = %d\n", a, b);
  pointer_to_pointer();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pointer_to_pointer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type: string
name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D11
type: string

tool: D27: IN MAIN: 

tool: D17: addr of a = %u, addr of b = %u



tool: D11: a = %d, b = %d


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("IN MAIN: \n");
  printf("addr of a = %u, addr of b = %u\n\n", &a, &b);
  swap(&a, &b);
  printf("a = %d, b = %d\n", a, b);
  pointer_to_pointer();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  call   <puts@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pointer_to_pointer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string

tool: D10: IN MAIN: 

tool: D8: addr of a = %u, addr of b = %u



tool: D13: a = %d, b = %d


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("IN MAIN: \n");
  printf("addr of a = %u, addr of b = %u\n\n", &a, &b);
  swap(&a, &b);
  printf("a = %d, b = %d\n", a, b);
  pointer_to_pointer();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  call   <puts@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pointer_to_pointer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string

tool: D25: IN MAIN: 

tool: D13: addr of a = %u, addr of b = %u



tool: D23: a = %d, b = %d


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("IN MAIN: \n");
  printf("addr of a = %u, addr of b = %u\n\n", &a, &b);
  swap(&a, &b);
  printf("a = %d, b = %d\n", a, b);
  pointer_to_pointer();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L55
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L24
L33:
  subl   $0x1,-0x4(%rbp)
L55:
  cmpl   $0x0,-0x4(%rbp)
  jns    L49
  jmp    L3
L24:
  nop
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int trim(char s[]) {
  int n;
  for (n = strlen(s) - 1; n >= 0; n--)
    if (s[n] != ' ' && s[n] != '\t' && s[n] != '\n')
      break;
  s[n + 1] = '\0';
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L11
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L32
L41:
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L11
L32:
  movzbl (%rdx),%ecx
  lea    -0x9(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L41
  cmp    $0x20,%cl
  je     L41
L11:
  movslq %eax,%rdx
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int trim(char s[]) {
  int n;
  for (n = strlen(s) - 1; n >= 0; n--)
    if (s[n] != ' ' && s[n] != '\t' && s[n] != '\n')
      break;
  s[n + 1] = '\0';
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  sub    $0x1,%r8d
  js     L19
  movslq %r8d,%rax
  add    %rbx,%rax
  nopl   0x0(%rax)
L16:
  movzbl (%rax),%edx
  mov    %rax,%rsi
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L27
  cmp    $0x20,%dl
  jne    L5
L27:
  sub    $0x1,%r8d
  sub    $0x1,%rax
  cmp    $0xffffffff,%r8d
  jne    L16
L34:
  movb   $0x0,(%rsi)
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  lea    0x1(%r8),%esi
  mov    %r8d,%eax
  movslq %esi,%rsi
  add    %rbx,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
L19:
  cltq
  lea    (%rbx,%rax,1),%rsi
  jmp    L34
```

assistant: ```c
int trim(char s[]) {
  int n;
  for (n = strlen(s) - 1; n >= 0; n--)
    if (s[n] != ' ' && s[n] != '\t' && s[n] != '\n')
      break;
  s[n + 1] = '\0';
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  sub    $0x1,%r8d
  js     L25
  movslq %r8d,%rax
  add    %rbx,%rax
  nopl   0x0(%rax)
L26:
  movzbl (%rax),%edx
  mov    %rax,%rsi
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L37
  cmp    $0x20,%dl
  jne    L18
L37:
  sub    $0x1,%r8d
  sub    $0x1,%rax
  cmp    $0xffffffff,%r8d
  jne    L26
L2:
  movb   $0x0,(%rsi)
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L18:
  lea    0x1(%r8),%esi
  mov    %r8d,%eax
  movslq %esi,%rsi
  add    %rbx,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
L25:
  cltq
  lea    (%rbx,%rax,1),%rsi
  jmp    L2
```

assistant: ```c
int trim(char s[]) {
  int n;
  for (n = strlen(s) - 1; n >= 0; n--)
    if (s[n] != ' ' && s[n] != '\t' && s[n] != '\n')
      break;
  s[n + 1] = '\0';
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<phint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2e2e2e2e2e2e7830,%rax
  mov    %rax,-0x13(%rbp)
  movw   $0x2e2e,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L8
L2:
  mov    -0x18(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    $0x9,%edx
  mov    %edx,%ecx
  sub    -0x18(%rbp),%ecx
  cltq
  lea    D8(%rip),%rdx
  movzbl (%rax,%rdx,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x13(%rbp,%rax,1)
  addl   $0x1,-0x18(%rbp)
L8:
  cmpl   $0x7,-0x18(%rbp)
  jle    L2
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x400000,%edi
  call   <uputs@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: 0123456789ABCDEF

assistant: ```c
void phint(int x) {
  static const char hex[] = "0123456789ABCDEF";
  char res[] = "0x........";
  int i;
  for (i = 0; i < 8; i++)
    res[2 + 7 - i] = hex[(x >> (i << 2)) & 0xF];
  uputs(0x00400000, res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<phint>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x2e2e2e2e2e2e7830,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x2e2e,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x16(%rsp),%rdx
  mov    $0x0,%ecx
  lea    D3(%rip),%rsi
L6:
  mov    %edi,%eax
  sar    %cl,%eax
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,(%rdx)
  add    $0x4,%ecx
  sub    $0x1,%rdx
  cmp    $0x20,%ecx
  jne    L6
  lea    0xd(%rsp),%rsi
  mov    $0x400000,%edi
  call   <uputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void phint(int x) {
  static const char hex[] = "0123456789ABCDEF";
  char res[] = "0x........";
  int i;
  for (i = 0; i < 8; i++)
    res[2 + 7 - i] = hex[(x >> (i << 2)) & 0xF];
  uputs(0x00400000, res);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<phint>:
  endbr64
  sub    $0x28,%rsp
  xor    %ecx,%ecx
  lea    D7(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2e2e2e2e2e2e7830,%rax
  movb   $0x0,0x17(%rsp)
  lea    0x16(%rsp),%rdx
  mov    %rax,0xd(%rsp)
  mov    $0x2e2e,%eax
  mov    %ax,0x15(%rsp)
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %edi,%eax
  sub    $0x1,%rdx
  sar    %cl,%eax
  add    $0x4,%ecx
  and    $0xf,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,0x1(%rdx)
  cmp    $0x20,%ecx
  jne    L14
  lea    0xd(%rsp),%rsi
  mov    $0x400000,%edi
  call   <uputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: 0123456789ABCDEF

assistant: ```c
void phint(int x) {
  static const char hex[] = "0123456789ABCDEF";
  char res[] = "0x........";
  int i;
  for (i = 0; i < 8; i++)
    res[2 + 7 - i] = hex[(x >> (i << 2)) & 0xF];
  uputs(0x00400000, res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<phint>:
  endbr64
  mov    %edi,%eax
  sub    $0x28,%rsp
  mov    %edi,%esi
  movabs $0x2e2e2e2e2e2e7830,%rcx
  mov    %eax,%r11d
  mov    %eax,%r8d
  mov    %eax,%r9d
  mov    %eax,%r10d
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  sar    $0x4,%r11d
  lea    D5(%rip),%rdx
  and    $0xf,%eax
  movzbl (%rdx,%rax,1),%eax
  and    $0xf,%r11d
  mov    %rcx,0x8(%rsp)
  mov    %edi,%ecx
  movzbl (%rdx,%r11,1),%r11d
  sar    $0x14,%edi
  sar    $0x18,%esi
  movb   $0x0,0x12(%rsp)
  sar    $0x8,%r10d
  shl    $0x8,%rax
  and    $0xf,%edi
  and    $0xf,%esi
  and    $0xf,%r10d
  sar    $0xc,%r9d
  or     %r11,%rax
  movzbl (%rdx,%rdi,1),%edi
  movzbl (%rdx,%r10,1),%r10d
  and    $0xf,%r9d
  movzbl (%rdx,%rsi,1),%esi
  shr    $0x1c,%ecx
  shl    $0x8,%rax
  movzbl (%rdx,%r9,1),%r9d
  sar    $0x10,%r8d
  or     %r10,%rax
  and    $0xf,%r8d
  shl    $0x8,%rax
  movzbl (%rdx,%r8,1),%r8d
  movzbl (%rdx,%rcx,1),%edx
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rdi,%rax
  mov    $0x400000,%edi
  shl    $0x8,%rax
  or     %rsi,%rax
  lea    0x8(%rsp),%rsi
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,0xa(%rsp)
  call   <uputs@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: 0123456789ABCDEF

assistant: ```c
void phint(int x) {
  static const char hex[] = "0123456789ABCDEF";
  char res[] = "0x........";
  int i;
  for (i = 0; i < 8; i++)
    res[2 + 7 - i] = hex[(x >> (i << 2)) & 0xF];
  uputs(0x00400000, res);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L50
L15:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0x14(%rbp)
  je     L47
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L57
L40:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x38(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L40
  mov    $0x0,%eax
  jmp    L23
L47:
  addq   $0x1,-0x10(%rbp)
L50:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L15
  mov    $0x1,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int diff(int arr1[], int arr2[], int res[], size_t sz) {
  for (size_t i = 0; i < sz; i++) {
    int t = arr1[i] - arr2[i];
    res[i] = t;
    if (t != 0) {
      for (size_t j = i + 1; j < sz; j++)
        res[j] = arr1[j] - arr2[j];
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diff>:
  endbr64
  mov    %rdi,%r8
  test   %rcx,%rcx
  je     L24
  mov    $0x0,%eax
L28:
  mov    (%r8,%rax,4),%edi
  sub    (%rsi,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  jne    L7
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L28
  mov    $0x1,%eax
  ret
L7:
  add    $0x1,%rax
  cmp    %rax,%rcx
  jbe    L35
L11:
  mov    (%r8,%rax,4),%edi
  sub    (%rsi,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L11
  mov    $0x0,%eax
  ret
L24:
  mov    $0x1,%eax
  ret
L35:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int diff(int arr1[], int arr2[], int res[], size_t sz) {
  for (size_t i = 0; i < sz; i++) {
    int t = arr1[i] - arr2[i];
    res[i] = t;
    if (t != 0) {
      for (size_t j = i + 1; j < sz; j++)
        res[j] = arr1[j] - arr2[j];
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<diff>:
  endbr64
  xor    %eax,%eax
  test   %rcx,%rcx
  jne    L18
  jmp    L51
  nopl   (%rax)
L54:
  cmp    %rax,%rcx
  je     L51
L18:
  mov    (%rdi,%rax,4),%r8d
  sub    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  test   %r8d,%r8d
  je     L54
  cmp    %rax,%rcx
  jbe    L43
  nop
L37:
  mov    (%rdi,%rax,4),%r8d
  sub    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L37
L43:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int diff(int arr1[], int arr2[], int res[], size_t sz) {
  for (size_t i = 0; i < sz; i++) {
    int t = arr1[i] - arr2[i];
    res[i] = t;
    if (t != 0) {
      for (size_t j = i + 1; j < sz; j++)
        res[j] = arr1[j] - arr2[j];
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<diff>:
  endbr64
  mov    %rdx,%r8
  xor    %eax,%eax
  test   %rcx,%rcx
  jne    L75
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L69:
  cmp    %rax,%rcx
  je     L1
L75:
  mov    (%rdi,%rax,4),%edx
  sub    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  test   %edx,%edx
  je     L69
  cmp    %rax,%rcx
  jbe    L96
  lea    0x0(,%rax,4),%rdx
  push   %rbp
  mov    %rcx,%r9
  lea    0x4(%rdx),%r10
  push   %rbx
  lea    (%r8,%rdx,1),%rbx
  sub    %rax,%r9
  lea    (%rdi,%r10,1),%rbp
  mov    %rbx,%r11
  sub    %rbp,%r11
  mov    %rbx,%rbp
  cmp    $0x8,%r11
  seta   %r11b
  add    %rsi,%r10
  sub    %r10,%rbp
  cmp    $0x8,%rbp
  seta   %r10b
  test   %r10b,%r11b
  je     L14
  cmp    $0x1,%r9
  je     L14
  lea    -0x1(%r9),%rcx
  cmp    $0x2,%rcx
  jbe    L0
  mov    %r9,%r10
  lea    (%rdi,%rdx,1),%r11
  lea    (%rsi,%rdx,1),%rcx
  xor    %edx,%edx
  shr    $0x2,%r10
  shl    $0x4,%r10
  nopl   (%rax)
L92:
  movdqu (%r11,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm2
  psubd  %xmm2,%xmm0
  movups %xmm0,(%rbx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%r10
  jne    L92
  mov    %r9,%rcx
  and    $0xfffffffffffffffc,%rcx
  add    %rcx,%rax
  mov    %rax,%rdx
  cmp    %rcx,%r9
  je     L5
  sub    %rcx,%r9
  cmp    $0x1,%r9
  je     L49
L44:
  movq   (%rdi,%rax,4),%xmm0
  movq   (%rsi,%rax,4),%xmm1
  psubd  %xmm1,%xmm0
  movq   %xmm0,(%r8,%rax,4)
  mov    %r9,%rax
  and    $0xfffffffffffffffe,%rax
  add    %rax,%rdx
  cmp    %rax,%r9
  je     L5
L49:
  mov    (%rdi,%rdx,4),%eax
  sub    (%rsi,%rdx,4),%eax
  mov    %eax,(%r8,%rdx,4)
L5:
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    (%rdi,%rax,4),%edx
  sub    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L14
  jmp    L5
L96:
  xor    %eax,%eax
  ret
L0:
  mov    %rax,%rdx
  jmp    L44
```

assistant: ```c
int diff(int arr1[], int arr2[], int res[], size_t sz) {
  for (size_t i = 0; i < sz; i++) {
    int t = arr1[i] - arr2[i];
    res[i] = t;
    if (t != 0) {
      for (size_t j = i + 1; j < sz; j++)
        res[j] = arr1[j] - arr2[j];
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <f@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  const int x = 0;
  if (!!f() != x)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  const int x = 0;
  if (!!f() != x)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  const int x = 0;
  if (!!f() != x)
    ;
}
```