ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<checker_ucs4_tolower>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  js     L18
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L25
  lea    -0x410(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L13
  cmp    $0x401,%edi
  mov    $0x451,%edx
  cmove  %edx,%eax
L18:
  ret
L25:
  add    $0x20,%eax
  ret
L13:
  add    $0x20,%eax
  ret
```

assistant: ```c
int checker_ucs4_tolower(int c) {
  if (c < 0)
    return c;
  if (c >= 'A' && c <= 'Z')
    return c + 0x20;
  if (c >= 0x410 && c <= 0x42f)
    return c + 0x20;
  if (c == 0x401)
    return c + 0x50;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checker_ucs4_tolower>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  test   %edi,%edi
  js     L22
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L10
  lea    -0x410(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L10
  cmp    $0x401,%edi
  mov    $0x451,%edx
  cmove  %edx,%eax
L22:
  ret
  xchg   %ax,%ax
L10:
  lea    0x20(%rcx),%eax
  ret
```

assistant: ```c
int checker_ucs4_tolower(int c) {
  if (c < 0)
    return c;
  if (c >= 'A' && c <= 'Z')
    return c + 0x20;
  if (c >= 0x410 && c <= 0x42f)
    return c + 0x20;
  if (c == 0x401)
    return c + 0x50;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<checker_ucs4_tolower>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%ecx
  test   %edi,%edi
  js     L19
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L9
  lea    -0x410(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L9
  cmp    $0x401,%edi
  mov    $0x451,%edx
  cmove  %edx,%eax
L19:
  ret
  xchg   %ax,%ax
L9:
  lea    0x20(%rcx),%eax
  ret
```

assistant: ```c
int checker_ucs4_tolower(int c) {
  if (c < 0)
    return c;
  if (c >= 'A' && c <= 'Z')
    return c + 0x20;
  if (c >= 0x410 && c <= 0x42f)
    return c + 0x20;
  if (c == 0x401)
    return c + 0x50;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L6
L20:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D26
datatype: string
name: read_data
arguments: tag: D7
datatype: string

tool: D3: Enter a limit on maximum square: 

tool: D26: %d

tool: D7: %d


assistant: ```c
int main(void) {
  int n, i;
  printf("Enter a limit on maximum square: ");
  scanf("%d", &n);
  for (i = 2; i * i <= n; i += 2)
    printf("%d\n", i * i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L20
  mov    $0x2,%ebx
  mov    $0x4,%esi
  lea    D6(%rip),%rbp
L27:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  mov    %ebx,%esi
  imul   %ebx,%esi
  cmp    0x4(%rsp),%esi
  jle    L27
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D9: Enter a limit on maximum square: 

tool: D7: %d

tool: D6: %d


assistant: ```c
int main(void) {
  int n, i;
  printf("Enter a limit on maximum square: ");
  scanf("%d", &n);
  for (i = 2; i * i <= n; i += 2)
    printf("%d\n", i * i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L13
  mov    $0x2,%ebx
  mov    $0x4,%esi
  lea    D14(%rip),%rbp
  nop
L6:
  add    $0x2,%ebx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  imul   %ebx,%esi
  cmp    0x4(%rsp),%esi
  jle    L6
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string
name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string

tool: D3: Enter a limit on maximum square: 

tool: D20: %d

tool: D14: %d


assistant: ```c
int main(void) {
  int n, i;
  printf("Enter a limit on maximum square: ");
  scanf("%d", &n);
  for (i = 2; i * i <= n; i += 2)
    printf("%d\n", i * i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x3,0x4(%rsp)
  jle    L1
  mov    $0x2,%ebx
  mov    $0x4,%esi
  lea    D10(%rip),%rbp
  nop
L17:
  add    $0x2,%ebx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  imul   %ebx,%esi
  cmp    0x4(%rsp),%esi
  jle    L17
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D11: Enter a limit on maximum square: 

tool: D0: %d

tool: D10: %d


assistant: ```c
int main(void) {
  int n, i;
  printf("Enter a limit on maximum square: ");
  scanf("%d", &n);
  for (i = 2; i * i <= n; i += 2)
    printf("%d\n", i * i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L41
L38:
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L5:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L5
  jmp    L27
L14:
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L14
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L41:
  leave
  ret
```

assistant: ```c
char *get_value(char *string) {
  char *retval;
  int i;
  if (string == NULL)
    return NULL;
  i = 0;
  while (string[i] != ':')
    i++;
  while (!isalnum(string[i]))
    i++;
  retval = (string + i);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  cmpb   $0x3a,(%rdi)
  je     L6
  mov    $0x1,%eax
L35:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%rdi,%rax,1)
  jne    L35
L13:
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rbx
L59:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  je     L59
L47:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x0,%edx
  jmp    L13
L8:
  mov    %rdi,%rbp
  jmp    L47
```

assistant: ```c
char *get_value(char *string) {
  char *retval;
  int i;
  if (string == NULL)
    return NULL;
  i = 0;
  while (string[i] != ':')
    i++;
  while (!isalnum(string[i]))
    i++;
  retval = (string + i);
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_value>:
  endbr64
  test   %rdi,%rdi
  je     L43
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x3a,(%rdi)
  je     L58
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L44:
  movslq %edx,%rbx
  add    $0x1,%rdx
  cmpb   $0x3a,-0x1(%rbp,%rdx,1)
  jne    L44
L55:
  mov    $0x3a,%edi
  jmp    L1
  nopl   (%rax)
L15:
  movsbl 0x0(%rbp,%rbx,1),%edi
L1:
  call   <isalnum@plt>
  movslq %ebx,%r12
  add    $0x1,%rbx
  test   %eax,%eax
  je     L15
  lea    0x0(%rbp,%r12,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  xor    %ebx,%ebx
  jmp    L55
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *get_value(char *string) {
  char *retval;
  int i;
  if (string == NULL)
    return NULL;
  i = 0;
  while (string[i] != ':')
    i++;
  while (!isalnum(string[i]))
    i++;
  retval = (string + i);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_value>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L5
  cmpb   $0x3a,(%rdi)
  je     L56
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L43:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%rdi,%rax,1)
  jne    L43
L25:
  lea    (%rdi,%rdx,1),%rbx
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isalnum@plt>
  test   %eax,%eax
  je     L17
L29:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  xor    %edx,%edx
  jmp    L25
L5:
  xor    %r12d,%r12d
  jmp    L29
```

assistant: ```c
char *get_value(char *string) {
  char *retval;
  int i;
  if (string == NULL)
    return NULL;
  i = 0;
  while (string[i] != ':')
    i++;
  while (!isalnum(string[i]))
    i++;
  retval = (string + i);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x1,-0x20(%rbp)
  movw   $0x1,-0x1e(%rbp)
  movw   $0x1,-0x1c(%rbp)
  movw   $0x1,-0x1a(%rbp)
  movw   $0x1,-0x18(%rbp)
  movw   $0x1,-0x16(%rbp)
  movw   $0x1,-0x14(%rbp)
  movw   $0x1,-0x12(%rbp)
  movw   $0x1,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <bar@plt>
  cmp    $0x24,%eax
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(void) {
  short stuff[9] = {1, 1, 1, 1, 1, 1, 1, 1, 1};
  if (bar(stuff, 9) != 36)
    abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x1,(%rsp)
  movw   $0x1,0x2(%rsp)
  movw   $0x1,0x4(%rsp)
  movw   $0x1,0x6(%rsp)
  movw   $0x1,0x8(%rsp)
  movw   $0x1,0xa(%rsp)
  movw   $0x1,0xc(%rsp)
  movw   $0x1,0xe(%rsp)
  movw   $0x1,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x9,%esi
  call   <bar@plt>
  cmp    $0x24,%eax
  jne    L9
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  ret
L9:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(void) {
  short stuff[9] = {1, 1, 1, 1, 1, 1, 1, 1, 1};
  if (bar(stuff, 9) != 36)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1000100010001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    $0x1,%eax
  mov    %ax,0x10(%rsp)
  call   <bar@plt>
  cmp    $0x24,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(void) {
  short stuff[9] = {1, 1, 1, 1, 1, 1, 1, 1, 1};
  if (bar(stuff, 9) != 36)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  movdqa D9(%rip),%xmm0
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%eax
  mov    %ax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <bar@plt>
  cmp    $0x24,%eax
  je     L19
  xor    %eax,%eax
  call   <abort@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: byte[16]

tool: {"D9": [0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00]}

assistant: ```c
__attribute__((no, noclone)) void foo(void) {
  short stuff[9] = {1, 1, 1, 1, 1, 1, 1, 1, 1};
  if (bar(stuff, 9) != 36)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mtvm3x3>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  movapd %xmm3,%xmm4
  mulsd  (%rdi),%xmm4
  movsd  (%rdx),%xmm0
  subsd  %xmm4,%xmm0
  movapd %xmm2,%xmm4
  mulsd  0x8(%rdi),%xmm4
  subsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  mulsd  0x10(%rdi),%xmm4
  subsd  %xmm4,%xmm0
  movsd  %xmm0,(%rdx)
  movapd %xmm3,%xmm4
  mulsd  0x18(%rdi),%xmm4
  movsd  0x8(%rdx),%xmm0
  subsd  %xmm4,%xmm0
  movapd %xmm2,%xmm4
  mulsd  0x20(%rdi),%xmm4
  subsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  mulsd  0x28(%rdi),%xmm4
  subsd  %xmm4,%xmm0
  movsd  %xmm0,0x8(%rdx)
  mulsd  0x30(%rdi),%xmm3
  movsd  0x10(%rdx),%xmm0
  subsd  %xmm3,%xmm0
  mulsd  0x38(%rdi),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  0x40(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void mtvm3x3(double *restrict a, double *restrict v, double *restrict r) {
  double *pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r -= *a * *pv;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mtvm3x3>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  (%rdi),%xmm4
  movsd  (%rdx),%xmm0
  movsd  0x8(%rsi),%xmm2
  mulsd  %xmm3,%xmm4
  movsd  0x10(%rsi),%xmm1
  subsd  %xmm4,%xmm0
  movsd  0x8(%rdi),%xmm4
  mulsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm0
  movsd  0x10(%rdi),%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm0
  movsd  0x18(%rdi),%xmm4
  mulsd  %xmm3,%xmm4
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdx),%xmm0
  mulsd  0x30(%rdi),%xmm3
  subsd  %xmm4,%xmm0
  movsd  0x20(%rdi),%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  0x38(%rdi),%xmm2
  subsd  %xmm4,%xmm0
  movsd  0x28(%rdi),%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  0x40(%rdi),%xmm1
  subsd  %xmm4,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdx),%xmm0
  subsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void mtvm3x3(double *restrict a, double *restrict v, double *restrict r) {
  double *pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r -= *a * *pv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mtvm3x3>:
  endbr64
  movupd (%rsi),%xmm0
  movupd 0x10(%rdi),%xmm2
  movupd 0x20(%rdi),%xmm5
  movsd  0x10(%rsi),%xmm3
  movapd %xmm0,%xmm1
  movlpd (%rdi),%xmm2
  movapd %xmm0,%xmm4
  unpcklpd %xmm0,%xmm1
  unpckhpd %xmm0,%xmm4
  mulpd  %xmm1,%xmm2
  movupd (%rdx),%xmm1
  subpd  %xmm2,%xmm1
  movupd (%rdi),%xmm2
  shufpd $0x1,%xmm5,%xmm2
  mulpd  %xmm4,%xmm2
  movapd %xmm3,%xmm4
  mulsd  0x40(%rdi),%xmm3
  unpcklpd %xmm4,%xmm4
  subpd  %xmm2,%xmm1
  movapd %xmm5,%xmm2
  movlpd 0x10(%rdi),%xmm2
  mulpd  %xmm4,%xmm2
  subpd  %xmm2,%xmm1
  movsd  0x30(%rdi),%xmm2
  mulsd  %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  movups %xmm1,(%rdx)
  mulsd  0x38(%rdi),%xmm0
  movsd  0x10(%rdx),%xmm1
  subsd  %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x10(%rdx)
  ret
```

assistant: ```c
void mtvm3x3(double *restrict a, double *restrict v, double *restrict r) {
  double *pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r++ -= *a++ * *pv;
  pv = v;
  *r -= *a++ * *pv++;
  *r -= *a++ * *pv++;
  *r -= *a * *pv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcnchrnul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L58
  mov    -0x8(%rbp),%rax
  jmp    L2
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x10(%rbp)
  je     L59
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L68
L59:
  mov    -0x8(%rbp),%rax
  jmp    L2
L68:
  addq   $0x1,-0x8(%rbp)
  jmp    L41
L2:
  pop    %rbp
  ret
```

assistant: ```c
char *(strcnchrnul)(const char *string, int c, int stop, size_t maxlen) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop) || !maxlen--)
      return string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcnchrnul>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%r9d
  mov    %edx,%r8d
  movzbl (%rdi),%edi
  movsbl %dil,%esi
  cmp    %esi,%r9d
  sete   %dl
  cmp    %esi,%r8d
  sete   %sil
  or     %sil,%dl
  jne    L27
  test   %dil,%dil
  je     L27
  test   %rcx,%rcx
  je     L27
  add    %rax,%rcx
L44:
  add    $0x1,%rax
  movzbl (%rax),%edx
  movsbl %dl,%esi
  test   %dl,%dl
  sete   %dl
  cmp    %r8d,%esi
  sete   %dil
  or     %dil,%dl
  jne    L27
  cmp    %r9d,%esi
  je     L42
  cmp    %rcx,%rax
  jne    L44
  mov    %rcx,%rax
L27:
  ret
L42:
  ret
```

assistant: ```c
char *(strcnchrnul)(const char *string, int c, int stop, size_t maxlen) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop) || !maxlen--)
      return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcnchrnul>:
  endbr64
  mov    %esi,%r9d
  movsbl (%rdi),%esi
  mov    %edx,%r8d
  mov    %rdi,%rax
  cmp    %esi,%r9d
  mov    %esi,%edi
  sete   %dl
  cmp    %esi,%r8d
  sete   %sil
  or     %sil,%dl
  jne    L47
  test   %dil,%dil
  je     L47
  test   %rcx,%rcx
  je     L47
  add    %rax,%rcx
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L53:
  cmp    %r9d,%esi
  je     L47
  cmp    %rcx,%rax
  je     L47
L0:
  movsbl 0x1(%rax),%esi
  add    $0x1,%rax
  test   %sil,%sil
  sete   %dl
  cmp    %r8d,%esi
  sete   %dil
  or     %dil,%dl
  je     L53
L47:
  ret
```

assistant: ```c
char *(strcnchrnul)(const char *string, int c, int stop, size_t maxlen) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop) || !maxlen--)
      return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcnchrnul>:
  endbr64
  mov    %esi,%r9d
  movsbl (%rdi),%esi
  mov    %edx,%r8d
  mov    %rdi,%rax
  cmp    %esi,%r9d
  mov    %esi,%edi
  sete   %dl
  cmp    %esi,%r8d
  sete   %sil
  or     %sil,%dl
  jne    L17
  test   %dil,%dil
  je     L17
  test   %rcx,%rcx
  je     L17
  add    %rax,%rcx
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    %r9d,%esi
  je     L17
  cmp    %rcx,%rax
  je     L17
L47:
  movsbl 0x1(%rax),%esi
  add    $0x1,%rax
  test   %sil,%sil
  sete   %dl
  cmp    %r8d,%esi
  sete   %dil
  or     %dil,%dl
  je     L44
L17:
  ret
```

assistant: ```c
char *(strcnchrnul)(const char *string, int c, int stop, size_t maxlen) {
  for (;; string++)
    if (*string == c)
      return string;
    else if (!*string || (*string == stop) || !maxlen--)
      return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlib_config_switch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x2,-0x8(%rbp)
  jne    L58
  mov    -0x18(%rbp),%rax
  lea    D45(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L107
L58:
  cmpq   $0x3,-0x8(%rbp)
  jne    L131
  mov    -0x18(%rbp),%rax
  lea    D41(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L107
L131:
  cmpq   $0x4,-0x8(%rbp)
  jne    L98
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L98
L107:
  mov    $0x1,%eax
  jmp    L30
L98:
  cmpq   $0x3,-0x8(%rbp)
  jne    L43
  mov    -0x18(%rbp),%rax
  lea    D48(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L78
L43:
  cmpq   $0x2,-0x8(%rbp)
  jne    L115
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L78
L115:
  cmpq   $0x5,-0x8(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L22
L78:
  mov    $0x0,%eax
  jmp    L30
L22:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D45
type_guessed: string
name: unpack_data
arguments: tag: D41
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D39
type_guessed: string

tool: D45: on

tool: D41: yes

tool: D9: true

tool: D48: off

tool: D5: no

tool: D39: false

assistant: ```c
int strlib_config_switch(const char *str) {
  size_t len = strlen(str);
  if ((len == 2 && strcasecmp(str, "on") == 0) || (len == 3 && strcasecmp(str, "yes") == 0) || (len == 4 && strcasecmp(str, "true") == 0))
    return 1;
  if ((len == 3 && strcasecmp(str, "off") == 0) || (len == 2 && strcasecmp(str, "no") == 0) || (len == 5 && strcasecmp(str, "false") == 0))
    return 0;
  return (int)strtol(str, (void *)0, 0);
}
```