ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nextStep>:
  endbr64
  lea    0x1(%rdx),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  test   %esi,%esi
  jle    L16
  cltq
  push   %r15
  imul   $0x2710,%rax,%rax
  push   %r14
  movslq %edx,%r14
  push   %r13
  imul   $0x2710,%r14,%r14
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    %rax,%rbp
  movslq %esi,%rax
  add    %rdi,%r14
  mov    %r14,%r12
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L32:
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edx
  mov    %r15d,%ecx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <numberOfNeighbors@plt>
  xor    %edx,%edx
  cmp    $0x3,%eax
  sete   %dl
  cmpl   $0x1,(%r12,%r15,4)
  jne    L12
  sub    $0x2,%eax
  xor    %edx,%edx
  cmp    $0x1,%eax
  setbe  %dl
L12:
  mov    %edx,0x0(%rbp,%r15,4)
  add    $0x1,%r15
  cmp    %r15,0x8(%rsp)
  jne    L2
  add    $0x1,%ebx
  add    $0xc8,%rbp
  add    $0xc8,%r12
  cmp    %ebx,%r13d
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  ret
```

assistant: ```c
void nextStep(int gamePlane[2][50][50], int size, int currentPlane) {
  int i = 0, j = 0, neighbors = 0, nextPlane = 0;
  nextPlane = (currentPlane + 1) % 2;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      neighbors = numberOfNeighbors(gamePlane[currentPlane], size, i, j);
      if (gamePlane[currentPlane][i][j] == 1) {
        if (neighbors < 2) {
          gamePlane[nextPlane][i][j] = 0;
        } else if (neighbors > 3) {
          gamePlane[nextPlane][i][j] = 0;
        } else {
          gamePlane[nextPlane][i][j] = 1;
        }
      } else {
        if (neighbors == 3) {
          gamePlane[nextPlane][i][j] = 1;
        } else {
          gamePlane[nextPlane][i][j] = 0;
        }
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L12
L106:
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L106
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L81
L71:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L22
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L11:
  addq   $0x1,-0x18(%rbp)
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L55
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
L55:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x22,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L81
L22:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L46
L50:
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L64
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
L64:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L81:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_word(str, word)
char *str, *word;
{
  char *wrd, c;
  while (isspace(*str) && *str)
    str++;
  if (!(*str))
    word[0] = '\0';
  else if (*str == '\"') {
    for (wrd = ++str; *str != '\"' && *str; str++)
      ;
    *str = '\0';
    strcpy(word, wrd);
    *str = '\"';
    str++;
  } else {
    for (wrd = str; !isspace(*str) && *str; str++)
      ;
    c = *str;
    *str = '\0';
    strcpy(word, wrd);
    *str = c;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_word>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
L95:
  movzbl (%rbx),%ebp
  movsbl %bpl,%edi
  call   <isspace@plt>
  test   %bpl,%bpl
  je     L110
  test   %eax,%eax
  je     L110
  add    $0x1,%rbx
  jmp    L95
L110:
  test   %bpl,%bpl
  jne    L11
  movb   $0x0,(%r12)
  mov    %rbx,%r13
L46:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %rbx,%r13
  cmp    $0x22,%bpl
  je     L47
L134:
  movzbl 0x0(%r13),%ebp
  movsbl %bpl,%edi
  call   <isspace@plt>
  test   %bpl,%bpl
  je     L64
  test   %eax,%eax
  jne    L64
  add    $0x1,%r13
  jmp    L134
L47:
  lea    0x1(%rbx),%rsi
  movzbl 0x1(%rbx),%eax
  cmp    $0x22,%al
  je     L39
  test   %al,%al
  je     L39
  mov    %rsi,%r13
L84:
  add    $0x1,%r13
  movzbl 0x0(%r13),%eax
  cmp    $0x22,%al
  je     L25
  test   %al,%al
  jne    L84
L25:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rdi
  call   <strcpy@plt>
  movb   $0x22,0x0(%r13)
  add    $0x1,%r13
  jmp    L46
L39:
  mov    %rsi,%r13
  jmp    L25
L64:
  movb   $0x0,0x0(%r13)
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %bpl,0x0(%r13)
  jmp    L46
```

assistant: ```c
char *get_word(str, word)
char *str, *word;
{
  char *wrd, c;
  while (isspace(*str) && *str)
    str++;
  if (!(*str))
    word[0] = '\0';
  else if (*str == '\"') {
    for (wrd = ++str; *str != '\"' && *str; str++)
      ;
    *str = '\0';
    strcpy(word, wrd);
    *str = '\"';
    str++;
  } else {
    for (wrd = str; !isspace(*str) && *str; str++)
      ;
    c = *str;
    *str = '\0';
    strcpy(word, wrd);
    *str = c;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_word>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L96
  cs nopw 0x0(%rax,%rax,1)
L43:
  test   %bl,%bl
  je     L25
  add    $0x1,%rbp
L96:
  movsbl 0x0(%rbp),%edi
  mov    %edi,%ebx
  call   <isspace@plt>
  test   %eax,%eax
  jne    L43
  test   %bl,%bl
  je     L25
  movzbl 0x1(%rbp),%eax
  mov    %rbp,%r13
  cmp    $0x22,%bl
  jne    L34
  lea    0x1(%rbp),%rsi
  mov    %rsi,%r13
  cmp    $0x22,%al
  jne    L63
  jmp    L104
  nopl   0x0(%rax)
L66:
  movzbl 0x1(%r13),%eax
  add    $0x1,%r13
  cmp    $0x22,%al
  je     L104
L63:
  test   %al,%al
  jne    L66
L104:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rdi
  add    $0x1,%r13
  call   <strcpy@plt>
  movb   $0x22,-0x1(%r13)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L85:
  test   %bl,%bl
  je     L5
L34:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  mov    %edi,%ebx
  call   <isspace@plt>
  test   %eax,%eax
  je     L85
L5:
  movb   $0x0,0x0(%r13)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %bl,0x0(%r13)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%r13
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_word(str, word)
char *str, *word;
{
  char *wrd, c;
  while (isspace(*str) && *str)
    str++;
  if (!(*str))
    word[0] = '\0';
  else if (*str == '\"') {
    for (wrd = ++str; *str != '\"' && *str; str++)
      ;
    *str = '\0';
    strcpy(word, wrd);
    *str = '\"';
    str++;
  } else {
    for (wrd = str; !isspace(*str) && *str; str++)
      ;
    c = *str;
    *str = '\0';
    strcpy(word, wrd);
    *str = c;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_word>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L74
  cs nopw 0x0(%rax,%rax,1)
L34:
  test   %bl,%bl
  je     L19
  add    $0x1,%rbp
L74:
  movsbl 0x0(%rbp),%edi
  mov    %edi,%ebx
  call   <isspace@plt>
  test   %eax,%eax
  jne    L34
  test   %bl,%bl
  je     L19
  movzbl 0x1(%rbp),%eax
  mov    %rbp,%r13
  cmp    $0x22,%bl
  jne    L2
  lea    0x1(%rbp),%rsi
  mov    %rsi,%r13
  cmp    $0x22,%al
  jne    L6
  jmp    L12
  nopl   0x0(%rax)
L28:
  movzbl 0x1(%r13),%eax
  add    $0x1,%r13
  cmp    $0x22,%al
  je     L12
L6:
  test   %al,%al
  jne    L28
L12:
  movb   $0x0,0x0(%r13)
  mov    %r12,%rdi
  add    $0x1,%r13
  call   <strcpy@plt>
  movb   $0x22,-0x1(%r13)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L100:
  test   %bl,%bl
  je     L67
L2:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  mov    %edi,%ebx
  call   <isspace@plt>
  test   %eax,%eax
  je     L100
L67:
  movb   $0x0,0x0(%r13)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %bl,0x0(%r13)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%r13
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_word(str, word)
char *str, *word;
{
  char *wrd, c;
  while (isspace(*str) && *str)
    str++;
  if (!(*str))
    word[0] = '\0';
  else if (*str == '\"') {
    for (wrd = ++str; *str != '\"' && *str; str++)
      ;
    *str = '\0';
    strcpy(word, wrd);
    *str = '\"';
    str++;
  } else {
    for (wrd = str; !isspace(*str) && *str; str++)
      ;
    c = *str;
    *str = '\0';
    strcpy(word, wrd);
    *str = c;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<store4_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store4_little_endian(unsigned char *cp, unsigned int val) {
  cp[0] = (val & 0xff);
  cp[1] = ((val >> 8) & 0xff);
  cp[2] = ((val >> 16) & 0xff);
  cp[3] = ((val >> 24) & 0xff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store4_little_endian>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x2(%rdi)
  shr    $0x18,%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void store4_little_endian(unsigned char *cp, unsigned int val) {
  cp[0] = (val & 0xff);
  cp[1] = ((val >> 8) & 0xff);
  cp[2] = ((val >> 16) & 0xff);
  cp[3] = ((val >> 24) & 0xff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<store4_little_endian>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void store4_little_endian(unsigned char *cp, unsigned int val) {
  cp[0] = (val & 0xff);
  cp[1] = ((val >> 8) & 0xff);
  cp[2] = ((val >> 16) & 0xff);
  cp[3] = ((val >> 24) & 0xff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<store4_little_endian>:
  endbr64
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void store4_little_endian(unsigned char *cp, unsigned int val) {
  cp[0] = (val & 0xff);
  cp[1] = ((val >> 8) & 0xff);
  cp[2] = ((val >> 16) & 0xff);
  cp[3] = ((val >> 24) & 0xff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getTotalSavedLogs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2014(%rbp)
  cmpq   $0x0,-0x2028(%rbp)
  je     L19
  jmp    L39
L18:
  addl   $0x1,-0x2014(%rbp)
L39:
  mov    -0x2028(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    $0x2000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L18
L19:
  mov    -0x2014(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int getTotalSavedLogs(FILE *fp) {
  char line[8192];
  int cnt = 0;
  if (fp) {
    while (fgets(line, 8192, fp)) {
      cnt++;
    }
  }
  return cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getTotalSavedLogs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    %rsp,%r12
  test   %rdi,%rdi
  jne    L2
  jmp    L27
L6:
  add    $0x1,%ebx
L2:
  mov    %rbp,%rdx
  mov    $0x2000,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L6
L27:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %ebx,%eax
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getTotalSavedLogs(FILE *fp) {
  char line[8192];
  int cnt = 0;
  if (fp) {
    while (fgets(line, 8192, fp)) {
      cnt++;
    }
  }
  return cnt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getTotalSavedLogs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbx
  mov    %rsp,%rbp
  test   %rdi,%rdi
  jne    L20
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r12d
L20:
  mov    %rbx,%rdx
  mov    $0x2000,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L6
L0:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x2010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getTotalSavedLogs(FILE *fp) {
  char line[8192];
  int cnt = 0;
  if (fp) {
    while (fgets(line, 8192, fp)) {
      cnt++;
    }
  }
  return cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getTotalSavedLogs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbx
  mov    %rsp,%rbp
  test   %rdi,%rdi
  jne    L38
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%r12d
L38:
  mov    %rbx,%rdx
  mov    $0x2000,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L16
L35:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x2010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getTotalSavedLogs(FILE *fp) {
  char line[8192];
  int cnt = 0;
  if (fp) {
    while (fgets(line, 8192, fp)) {
      cnt++;
    }
  }
  return cnt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L8
L34:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L3:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L48
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
L48:
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result = (int *)malloc(sizeof(int) * 2);
  int i, j;
  for (i = 0; i < numsSize; i++) {
    for (j = i + 1; j < numsSize; j++) {
      if ((nums[i] + nums[j]) == target) {
        result[0] = i;
        result[1] = j;
      }
    }
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<twoSum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L57
  mov    %rbp,%rsi
  lea    -0x1(%rbx),%r9d
  mov    $0x0,%edi
  jmp    L48
L22:
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jle    L65
L17:
  mov    0x0(%rbp,%rdx,4),%ecx
  add    (%rsi),%ecx
  cmp    %r12d,%ecx
  jne    L22
  mov    %r8d,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L22
L65:
  add    $0x4,%rsi
L48:
  mov    %edi,%r8d
  cmp    %r9,%rdi
  je     L57
  add    $0x1,%rdi
  mov    %rdi,%rdx
  jmp    L17
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result = (int *)malloc(sizeof(int) * 2);
  int i, j;
  for (i = 0; i < numsSize; i++) {
    for (j = i + 1; j < numsSize; j++) {
      if ((nums[i] + nums[j]) == target) {
        result[0] = i;
        result[1] = j;
      }
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L13
  xor    %edx,%edx
  lea    -0x1(%rbx),%r9d
  mov    %rbp,%rdi
  mov    %edx,%r8d
  cmp    %r9,%rdx
  je     L13
  nop
L9:
  add    $0x1,%rdx
  mov    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    0x0(%rbp,%rcx,4),%esi
  add    (%rdi),%esi
  cmp    %r12d,%esi
  jne    L41
  mov    %r8d,(%rax)
  mov    %ecx,0x4(%rax)
L41:
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jg     L34
  add    $0x4,%rdi
  mov    %edx,%r8d
  cmp    %r9,%rdx
  jne    L9
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result = (int *)malloc(sizeof(int) * 2);
  int i, j;
  for (i = 0; i < numsSize; i++) {
    for (j = i + 1; j < numsSize; j++) {
      if ((nums[i] + nums[j]) == target) {
        result[0] = i;
        result[1] = j;
      }
    }
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L12
  mov    %rbp,%rdi
  movslq %ebx,%r8
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L23:
  lea    -0x1(%rdx),%esi
  mov    %rdx,%rcx
  movd   %esi,%xmm1
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp,%rcx,4),%esi
  movdqa %xmm1,%xmm0
  movd   %ecx,%xmm2
  add    (%rdi),%esi
  punpckldq %xmm2,%xmm0
  cmp    %r12d,%esi
  jne    L37
  movq   %xmm0,(%rax)
L37:
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jg     L2
  add    $0x1,%rdx
  add    $0x4,%rdi
  cmp    %rdx,%r8
  jne    L23
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result = (int *)malloc(sizeof(int) * 2);
  int i, j;
  for (i = 0; i < numsSize; i++) {
    for (j = i + 1; j < numsSize; j++) {
      if ((nums[i] + nums[j]) == target) {
        result[0] = i;
        result[1] = j;
      }
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getrpcport>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r12
  mov    %esi,-0x74(%rbp)
  mov    %edx,%r14d
  mov    %ecx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L79:
  cmp    %rax,%rsp
  je     L49
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L49:
  sub    $0x410,%rsp
  orq    $0x0,0x408(%rsp)
  lea    0xf(%rsp),%rdx
  and    $0xfffffffffffffff0,%rdx
  mov    $0x400,%ebx
  lea    -0x64(%rbp),%r13
  jmp    L129
L74:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L121
  orq    $0x0,-0x8(%rsp,%rax,1)
L121:
  lea    0xf(%rsp),%rdx
  and    $0xfffffffffffffff0,%rdx
L129:
  lea    -0x58(%rbp),%rsi
  mov    %r13,%r9
  lea    -0x60(%rbp),%r8
  mov    %rbx,%rcx
  mov    %r12,%rdi
  call   <gethostbyname_r@plt>
  test   %rax,%rax
  jne    L44
  mov    -0x60(%rbp),%rax
  test   %rax,%rax
  jne    L57
L44:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x64(%rbp)
  jne    L43
  mov    D33(%rip),%rdx
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L7
  add    %rbx,%rbx
  lea    0x17(%rbx),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L14:
  cmp    %rdx,%rsp
  je     L74
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L57:
  mov    0x4(%rax),%esi
  lea    -0x50(%rbp),%rbx
  lea    -0x44(%rbp),%rdi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x48(%rbp)
  movq   $0x0,-0x50(%rbp)
  mov    %r15d,%ecx
  mov    %r14d,%edx
  mov    -0x74(%rbp),%esi
  mov    %rbx,%rdi
  call   <pmap_getport@plt>
  jmp    L89
L43:
  mov    $0x0,%eax
L89:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L7:
  mov    $0x0,%eax
  jmp    L89
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getrpcport(const char *host, u_long prognum, u_long versnum, u_int proto) {
  struct sockaddr_in addr;
  struct hostent hostbuf, *hp;
  size_t buflen;
  char *buffer;
  int herr;
  buflen = 1024;
  buffer = alloca(buflen);
  while (gethostbyname_r(host, &hostbuf, buffer, buflen, &hp, &herr) != 0 || hp == NULL)
    if (herr != NETDB_INTERNAL || errno != ERANGE)
      return 0;
    else {
      buflen *= 2;
      buffer = alloca(buflen);
    }
  memcpy((char *)&addr.sin_addr, hp->h_addr, hp->h_length);
  addr.sin_family = AF_INET;
  addr.sin_port = 0;
  return pmap_getport(&addr, prognum, versnum, proto);
}
```