user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_decode_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %esi,-0x8c(%rbp)
  mov    %edx,-0x90(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x8c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x74(%rbp)
  mov    -0x8c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x8c(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x7c(%rbp)
  movl   $0x1,-0x78(%rbp)
  jmp    L37
L12:
  mov    -0x78(%rbp),%eax
  cmp    -0x90(%rbp),%eax
  jl     L23
  lea    -0x70(%rbp),%rdx
  mov    -0x7c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    D27(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L45
L23:
  mov    -0x8c(%rbp),%edx
  mov    -0x78(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    -0x70(%rbp),%rcx
  mov    -0x7c(%rbp),%edx
  movslq %edx,%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x74(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8c(%rbp),%edx
  mov    -0x78(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x74(%rbp)
L45:
  lea    -0x70(%rbp),%rdx
  mov    -0x7c(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,-0x7c(%rbp)
  addl   $0x1,-0x78(%rbp)
L37:
  cmpl   $0x3,-0x78(%rbp)
  jle    L12
  lea    -0x70(%rbp),%rdx
  mov    -0x7c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x74(%rbp),%eax
  mov    %eax,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x98(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D27
type: string
name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D25
type: string

tool: D8:  %05x: %02x

tool: D27:    

tool: D4:  %02x

tool: D17:    %10u

tool: D25: %s  %s


assistant: ```c
unsigned print_decode_line(const unsigned char *aData, int ofst, int nByte, const char *zMsg) {
  int i, j;
  unsigned val = aData[ofst];
  char zBuf[100];
  sprintf(zBuf, " %05x: %02x", ofst, aData[ofst]);
  i = strlen(zBuf);
  for (j = 1; j < 4; j++) {
    if (j >= nByte) {
      sprintf(&zBuf[i], "   ");
    } else {
      sprintf(&zBuf[i], " %02x", aData[ofst + j]);
      val = val * 256 + aData[ofst + j];
    }
    i += strlen(&zBuf[i]);
  }
  sprintf(&zBuf[i], "   %10u", val);
  printf("%s  %s\n", zBuf, zMsg);
  return val;
}
```