ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<envz_entry>:
  endbr64
  mov    %rdi,%r11
  test   %rsi,%rsi
  je     L93
L107:
  mov    %rdx,%rdi
  mov    %r11,%rax
  jmp    L173
  nopl   0x0(%rax,%rax,1)
L81:
  cmp    $0x3d,%cl
  je     L142
  add    $0x1,%rdi
  lea    0x1(%rax),%rcx
  sub    $0x1,%rsi
  je     L135
  mov    %rcx,%rax
L173:
  movzbl (%rdi),%ecx
  movzbl (%rax),%r8d
  test   %cl,%cl
  setne  %r10b
  cmp    %r8b,%cl
  sete   %r9b
  test   %r9b,%r10b
  jne    L81
L142:
  test   %r8b,%r8b
  je     L157
  cmp    $0x3d,%r8b
  jne    L40
  jmp    L157
  nopl   0x0(%rax)
L8:
  test   %rsi,%rsi
  je     L93
L40:
  movzbl (%rax),%ecx
  sub    $0x1,%rsi
  add    $0x1,%rax
  test   %cl,%cl
  jne    L8
  test   %rsi,%rsi
  je     L93
  mov    %rax,%r11
  jmp    L107
  xchg   %ax,%ax
L135:
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L63
  cmp    $0x3d,%al
  jne    L93
L63:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L162
  cmp    $0x3d,%al
  je     L162
L93:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L157:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L162
  cmp    $0x3d,%cl
  jne    L40
L162:
  mov    %r11,%rax
  ret
```

assistant: ```c
char *envz_entry(const char *envz, size_t envz_len, const char *name) {
  while (envz_len) {
    const char *p = name;
    const char *entry = envz;
    while (envz_len && *p == *envz && *p && *p != '=')
      p++, envz++, envz_len--;
    if ((*envz == '\0' || *envz == '=') && (*p == '\0' || *p == '='))
      return (char *)entry;
    while (envz_len && *envz)
      envz++, envz_len--;
    if (envz_len)
      envz++, envz_len--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <readControl@plt>
  mov    $0x0,%eax
  call   <time_elapsed@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <nextState@plt>
  mov    $0x0,%eax
  call   <writeState@plt>
  mov    $0x0,%eax
  call   <paintRobot@plt>
  mov    $0x0,%eax
  call   <paintTrace@plt>
  mov    $0xa,%edi
  call   <sleep_ms@plt>
  nop
  leave
  ret
```

assistant: ```c
void loop() {
  readControl();
  double dt = time_elapsed();
  nextState(dt);
  writeState();
  paintRobot();
  paintTrace();
  sleep_ms(10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <readControl@plt>
  mov    $0x0,%eax
  call   <time_elapsed@plt>
  call   <nextState@plt>
  mov    $0x0,%eax
  call   <writeState@plt>
  mov    $0x0,%eax
  call   <paintRobot@plt>
  mov    $0x0,%eax
  call   <paintTrace@plt>
  mov    $0xa,%edi
  call   <sleep_ms@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void loop() {
  readControl();
  double dt = time_elapsed();
  nextState(dt);
  writeState();
  paintRobot();
  paintTrace();
  sleep_ms(10);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readControl@plt>
  xor    %eax,%eax
  call   <time_elapsed@plt>
  call   <nextState@plt>
  xor    %eax,%eax
  call   <writeState@plt>
  xor    %eax,%eax
  call   <paintRobot@plt>
  xor    %eax,%eax
  call   <paintTrace@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    10d0 <sleep_ms@plt>
```

assistant: ```c
void loop() {
  readControl();
  double dt = time_elapsed();
  nextState(dt);
  writeState();
  paintRobot();
  paintTrace();
  sleep_ms(10);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<loop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readControl@plt>
  xor    %eax,%eax
  call   <time_elapsed@plt>
  call   <nextState@plt>
  xor    %eax,%eax
  call   <writeState@plt>
  xor    %eax,%eax
  call   <paintRobot@plt>
  xor    %eax,%eax
  call   <paintTrace@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    10d0 <sleep_ms@plt>
```

assistant: ```c
void loop() {
  readControl();
  double dt = time_elapsed();
  nextState(dt);
  writeState();
  paintRobot();
  paintTrace();
  sleep_ms(10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Rename_NEXT_SEQ_OBJ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L47
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Rename_XST_SEQ_OBJ@plt>
  jmp    L48
L34:
  subl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Rename_XST_SEQ_OBJ@plt>
L48:
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  je     L27
  cmpl   $0x0,-0x10(%rbp)
  jne    L34
L27:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L57
L47:
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
L57:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void Rename_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    Rename_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      Rename_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Rename_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdx),%ebp
  mov    %ebp,%ebx
  test   %ebp,%ebp
  jne    L37
L63:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%rdi
  mov    %ebx,%esi
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L63
  test   %ebx,%ebx
  je     L63
  lea    0x4(%rsp),%r14
L29:
  sub    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L63
  test   %ebx,%ebx
  jne    L29
  jmp    L63
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Rename_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    Rename_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      Rename_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Rename_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%edx
  mov    %edx,%ebp
  jne    L52
L34:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L52:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%r14
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  jne    L12
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x1,%ebx
  xor    %eax,%eax
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L34
L12:
  test   %ebx,%ebx
  jne    L14
  xor    %ebx,%ebx
  jmp    L34
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Rename_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    Rename_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      Rename_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Rename_NEXT_SEQ_OBJ>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    $0x1,%edx
  mov    %edx,%ebp
  jne    L18
L33:
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  lea    -0x1(%rcx),%ebx
  lea    0x4(%rsp),%r14
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  jne    L31
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L14:
  sub    $0x1,%ebx
  xor    %eax,%eax
  mov    %r14,%rdi
  mov    %ebx,%esi
  call   <Rename_XST_SEQ_OBJ@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L33
L31:
  test   %ebx,%ebx
  jne    L14
  xor    %ebx,%ebx
  jmp    L33
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Rename_NEXT_SEQ_OBJ(cc, ss, oc, os) int *cc, *ss, oc, os;
{
  int c, i, b;
  c = oc - 1;
  if (c != 0) {
    i = os - 1;
    Rename_XST_SEQ_OBJ(&b, i);
    while (b != 1 && i != 0) {
      i = i - 1;
      Rename_XST_SEQ_OBJ(&b, i);
    }
    *ss = i;
    *cc = c;
  } else {
    *ss = 0;
    *cc = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L35:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x8000,%eax
  jne    L57
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L57:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D11:   MAX

tool: D16: %5d

assistant: ```c
void printData(int *pdata, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      if (*(pdata + (i * size) + j) == 32768) {
        printf("  MAX");
      } else {
        printf("%5d", *(pdata + (i * size) + j));
      }
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L63
  movslq %esi,%rdx
  mov    %rdx,0x10(%rsp)
  lea    0x0(,%rdx,4),%rcx
  mov    %rcx,0x18(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D17(%rip),%r12
  lea    D12(%rip),%r15
  jmp    L31
L34:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L20
L14:
  mov    (%rbx),%esi
  cmp    $0x8000,%esi
  jne    L34
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x18(%rsp),%rbp
  add    0x10(%rsp),%r14
  cmp    %r13d,0xc(%rsp)
  je     L63
L31:
  mov    (%rsp),%rax
  lea    (%rax,%r14,4),%rbx
  jmp    L14
L63:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D12
type: string

tool: D17: %5d

tool: D12:   MAX

assistant: ```c
void printData(int *pdata, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      if (*(pdata + (i * size) + j) == 32768) {
        printf("  MAX");
      } else {
        printf("%5d", *(pdata + (i * size) + j));
      }
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L45
  movslq %esi,%rdx
  mov    %esi,%eax
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  lea    0x0(,%rdx,4),%rcx
  mov    %rdx,0x10(%rsp)
  sub    $0x1,%eax
  lea    D5(%rip),%rbp
  mov    %rcx,0x18(%rsp)
  lea    0x4(%rdi,%rax,4),%rbx
  lea    D15(%rip),%r14
  nopl   (%rax)
L24:
  mov    (%rsp),%rax
  lea    (%rax,%r13,4),%r15
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  je     L13
L9:
  mov    (%r15),%esi
  cmp    $0x8000,%esi
  jne    L22
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L9
L13:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x18(%rsp),%rbx
  add    0x10(%rsp),%r13
  cmp    %r12d,0xc(%rsp)
  jne    L24
L45:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string

tool: D5: %5d

tool: D15:   MAX

assistant: ```c
void printData(int *pdata, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      if (*(pdata + (i * size) + j) == 32768) {
        printf("  MAX");
      } else {
        printf("%5d", *(pdata + (i * size) + j));
      }
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printData>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L29
  movslq %esi,%rdx
  mov    %esi,%eax
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  lea    0x0(,%rdx,4),%rcx
  mov    %rdx,0x10(%rsp)
  sub    $0x1,%eax
  lea    D10(%rip),%rbp
  mov    %rcx,0x18(%rsp)
  lea    0x4(%rdi,%rax,4),%rbx
  lea    D13(%rip),%r14
  nopl   (%rax)
L11:
  mov    (%rsp),%rax
  lea    (%rax,%r13,4),%r15
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  je     L42
L5:
  mov    (%r15),%esi
  cmp    $0x8000,%esi
  jne    L28
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L5
L42:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x18(%rsp),%rbx
  add    0x10(%rsp),%r13
  cmp    %r12d,0xc(%rsp)
  jne    L11
L29:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string

tool: D10: %5d

tool: D13:   MAX

assistant: ```c
void printData(int *pdata, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      if (*(pdata + (i * size) + j) == 32768) {
        printf("  MAX");
      } else {
        printf("%5d", *(pdata + (i * size) + j));
      }
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tr_heapsort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %edx,%r14d
  and    $0x1,%r14d
  jne    L82
  sub    $0x1,%ebx
  mov    %ebx,%r12d
  shr    $0x1f,%r12d
  add    %ebx,%r12d
  sar    %r12d
  movslq %r12d,%rax
  lea    (%rsi,%rax,4),%rax
  mov    (%rax),%esi
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
  mov    (%rcx),%edx
  movslq %esi,%r8
  movslq %edx,%rdi
  mov    0x0(%r13,%rdi,4),%edi
  cmp    %edi,0x0(%r13,%r8,4)
  jge    L44
  mov    %esi,(%rcx)
  mov    %edx,(%rax)
L44:
  sub    $0x1,%r12d
  js     L0
L99:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <tr_fixdown@plt>
  sub    $0x1,%r12d
  jns    L99
  test   %r14d,%r14d
  je     L0
L92:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L89
  movslq %ebx,%rbx
L62:
  mov    0x0(%rbp),%r12d
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %eax,0x0(%rbp)
  mov    %ebx,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <tr_fixdown@plt>
  mov    %r12d,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L62
L89:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  mov    0x0(%rbp),%edx
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp)
  mov    %edx,(%rax)
  mov    %ebx,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <tr_fixdown@plt>
  jmp    L92
L82:
  mov    %edx,%r12d
  shr    $0x1f,%r12d
  add    %edx,%r12d
  sar    %r12d
  sub    $0x1,%r12d
  jns    L99
  jmp    L92
```

assistant: ```c
void tr_heapsort(const int *ISAd, int *SA, int size) {
  int i, m;
  int t;
  m = size;
  if ((size % 2) == 0) {
    m--;
    if (ISAd[SA[m / 2]] < ISAd[SA[m]]) {
      do {
        t = (SA[m]);
        (SA[m]) = (SA[m / 2]);
        (SA[m / 2]) = t;
      } while (0);
    }
  }
  for (i = m / 2 - 1; 0 <= i; --i) {
    tr_fixdown(ISAd, SA, i, m);
  }
  if ((size % 2) == 0) {
    do {
      t = (SA[0]);
      (SA[0]) = (SA[m]);
      (SA[m]) = t;
    } while (0);
    tr_fixdown(ISAd, SA, 0, m);
  }
  for (i = m - 1; 0 < i; --i) {
    t = SA[0], SA[0] = SA[i];
    tr_fixdown(ISAd, SA, 0, i);
    SA[i] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tr_heapsort>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  and    $0x1,%r13d
  jne    L15
  sub    $0x1,%r14d
  mov    %r14d,%ebp
  shr    $0x1f,%ebp
  add    %r14d,%ebp
  sar    %ebp
  movslq %ebp,%rax
  lea    (%rsi,%rax,4),%rdx
  movslq %r14d,%rax
  lea    (%rbx,%rax,4),%rax
  movslq (%rdx),%r8
  movslq (%rax),%rdi
  mov    %rdi,%rcx
  mov    (%r12,%rdi,4),%edi
  cmp    %edi,(%r12,%r8,4)
  jge    L37
  mov    %r8d,(%rax)
  mov    %ecx,(%rdx)
L37:
  sub    $0x1,%ebp
  js     L67
  nopl   0x0(%rax)
L81:
  mov    %ebp,%edx
  mov    %r14d,%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <tr_fixdown@plt>
  sub    $0x1,%ebp
  jae    L81
  test   %r13d,%r13d
  je     L93
L72:
  sub    $0x1,%r14d
  movslq %r14d,%rbp
  test   %r14d,%r14d
  jle    L26
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    (%rbx,%rbp,4),%eax
  mov    (%rbx),%r13d
  mov    %ebp,%ecx
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %eax,(%rbx)
  call   <tr_fixdown@plt>
  mov    %r13d,(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L21
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  mov    %edx,%ebp
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x1,%ebp
  jns    L81
  jmp    L72
L93:
  movslq %r14d,%rax
  lea    (%rbx,%rax,4),%rax
L67:
  mov    (%rbx),%edx
  mov    (%rax),%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %ecx,(%rbx)
  mov    %r14d,%ecx
  mov    %edx,(%rax)
  xor    %edx,%edx
  call   <tr_fixdown@plt>
  jmp    L72
```

assistant: ```c
void tr_heapsort(const int *ISAd, int *SA, int size) {
  int i, m;
  int t;
  m = size;
  if ((size % 2) == 0) {
    m--;
    if (ISAd[SA[m / 2]] < ISAd[SA[m]]) {
      do {
        t = (SA[m]);
        (SA[m]) = (SA[m / 2]);
        (SA[m / 2]) = t;
      } while (0);
    }
  }
  for (i = m / 2 - 1; 0 <= i; --i) {
    tr_fixdown(ISAd, SA, i, m);
  }
  if ((size % 2) == 0) {
    do {
      t = (SA[0]);
      (SA[0]) = (SA[m]);
      (SA[m]) = t;
    } while (0);
    tr_fixdown(ISAd, SA, 0, m);
  }
  for (i = m - 1; 0 < i; --i) {
    t = SA[0], SA[0] = SA[i];
    tr_fixdown(ISAd, SA, 0, i);
    SA[i] = t;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<tr_heapsort>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  and    $0x1,%r13d
  jne    L80
  sub    $0x1,%r14d
  mov    %r14d,%ebp
  shr    $0x1f,%ebp
  add    %r14d,%ebp
  sar    %ebp
  movslq %ebp,%rax
  lea    (%rsi,%rax,4),%rdx
  movslq %r14d,%rax
  lea    (%rbx,%rax,4),%rax
  movslq (%rdx),%r8
  movslq (%rax),%rdi
  mov    %rdi,%rcx
  mov    (%r12,%rdi,4),%edi
  cmp    %edi,(%r12,%r8,4)
  jge    L11
  mov    %r8d,(%rax)
  mov    %ecx,(%rdx)
L11:
  sub    $0x1,%ebp
  js     L24
  nopl   0x0(%rax)
L59:
  mov    %ebp,%edx
  mov    %r14d,%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <tr_fixdown@plt>
  sub    $0x1,%ebp
  jae    L59
  test   %r13d,%r13d
  je     L65
L42:
  sub    $0x1,%r14d
  movslq %r14d,%rbp
  test   %r14d,%r14d
  jle    L4
  cs nopw 0x0(%rax,%rax,1)
L84:
  mov    (%rbx,%rbp,4),%eax
  mov    (%rbx),%r13d
  mov    %ebp,%ecx
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %eax,(%rbx)
  call   <tr_fixdown@plt>
  mov    %r13d,(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L84
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L80:
  mov    %edx,%ebp
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x1,%ebp
  jns    L59
  jmp    L42
L65:
  movslq %r14d,%rax
  lea    (%rbx,%rax,4),%rax
L24:
  mov    (%rbx),%edx
  mov    (%rax),%ecx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %ecx,(%rbx)
  mov    %r14d,%ecx
  mov    %edx,(%rax)
  xor    %edx,%edx
  call   <tr_fixdown@plt>
  jmp    L42
```

assistant: ```c
void tr_heapsort(const int *ISAd, int *SA, int size) {
  int i, m;
  int t;
  m = size;
  if ((size % 2) == 0) {
    m--;
    if (ISAd[SA[m / 2]] < ISAd[SA[m]]) {
      do {
        t = (SA[m]);
        (SA[m]) = (SA[m / 2]);
        (SA[m / 2]) = t;
      } while (0);
    }
  }
  for (i = m / 2 - 1; 0 <= i; --i) {
    tr_fixdown(ISAd, SA, i, m);
  }
  if ((size % 2) == 0) {
    do {
      t = (SA[0]);
      (SA[0]) = (SA[m]);
      (SA[m]) = t;
    } while (0);
    tr_fixdown(ISAd, SA, 0, m);
  }
  for (i = m - 1; 0 < i; --i) {
    t = SA[0], SA[0] = SA[i];
    tr_fixdown(ISAd, SA, 0, i);
    SA[i] = t;
  }
}
```