user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x13,%ecx
  push   %r14
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x48(%rsp),%rdi
  mov    %rdi,0x20(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    D6(%rip),%rdi
  movabs $0x100000001,%rax
  mov    %rax,0x40(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x3c(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x3c(%rsp),%eax
  test   %eax,%eax
  jle    L20
  lea    0x40(%rsp),%rax
  mov    $0x1,%edx
  mov    $0x1,%ebp
  movl   $0x0,0x1c(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x44(%rsp),%rax
  mov    $0x1,%r14d
  mov    $0x1,%r15d
  mov    %rax,0x10(%rsp)
  lea    0x3c(%rsp),%rax
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x1c(%rsp),%eax
  mov    0x20(%rsp),%rcx
  lea    (%rcx,%rax,4),%rsi
  mov    0x10(%rsp),%rax
  jmp    L61
  nopl   0x0(%rax)
L57:
  mov    (%rax),%edx
L61:
  imul   %ebp,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L57
  mov    $0x1,%r9d
  jmp    L67
  nopl   0x0(%rax)
L13:
  add    $0x1,%r9
  cmp    %r9d,%r14d
  jl     L66
L67:
  mov    0x8(%rsp),%rax
  cmpl   $0xa,(%rax,%r9,4)
  jle    L13
  mov    0x10(%rsp),%rdx
  mov    $0x1,%edi
  nop
L27:
  cmpl   $0xa,0x40(%rsp,%r15,4)
  jle    L14
  add    $0x1,%r14d
  movslq %r14d,%r15
L14:
  movslq (%rdx),%rax
  add    $0x1,%edi
  mov    %rax,%rsi
  imul   $0x66666667,%rax,%rax
  mov    %esi,%r10d
  sar    $0x1f,%r10d
  sar    $0x22,%rax
  sub    %r10d,%eax
  add    %eax,0x4(%rdx)
  add    $0x4,%rdx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %esi,-0x4(%rdx)
  cmp    %r14d,%edi
  jle    L27
  add    $0x1,%r9
  cmp    %r9d,%r14d
  jge    L67
L66:
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    0x0(,%r15,4),%rbx
  lea    (%rax,%rbx,1),%r12
  lea    -0x1(%r14),%eax
  add    0x28(%rsp),%rbx
  mov    %eax,0x1c(%rsp)
  shl    $0x2,%rax
  sub    %rax,%rbx
  nopl   0x0(%rax)
L44:
  mov    (%r12),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  sub    $0x4,%r12
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L44
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getch@plt>
  cmp    %ebp,0x3c(%rsp)
  jl     L20
  mov    0x44(%rsp),%edx
  jmp    L25
L20:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D6
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string

tool: D24: %d

tool: D6: Enter a number what you want to calculus:

tool: D28: %d!=  

assistant: ```c
void main() {
  int Data[40];
  int Digit;
  int i, j, r, k;
  int N;
  for (i = 0; i < 40; i++)
    Data[i] = 0;
  Data[0] = 1;
  Data[1] = 1;
  Digit = 1;
  printf("Enter a number what you want to calculus:");
  scanf("%d", &N);
  for (i = 1; i < N + 1; i++) {
    for (j = 1; j < Digit + 1; j++)
      Data[j] *= i;
    for (j = 1; j < Digit + 1; j++) {
      if (Data[j] > 10) {
        for (r = 1; r < Digit + 1; r++) {
          if (Data[Digit] > 10)
            Digit++;
          Data[r + 1] += Data[r] / 10;
          Data[r] = Data[r] % 10;
        }
      }
    }
    printf("%d!=  ", i);
    for (k = Digit; k; k--)
      printf("%d", Data[k]);
    printf("\n");
    getch();
  }
}
```