ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <report_start@plt>
  xor    %eax,%eax
  call   <regtest@plt>
  xor    %eax,%eax
  call   <report_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  report_start();
  regtest();
  report_end();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <report_start@plt>
  xor    %eax,%eax
  call   <regtest@plt>
  xor    %eax,%eax
  call   <report_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  report_start();
  regtest();
  report_end();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trimLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  cmpq   $0x0,-0x20(%rbp)
  jne    L100
L8:
  mov    $0xffffffff,%eax
  jmp    L72
L100:
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    $0xffffffff,%eax
  jmp    L72
L104:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    $0x1,%eax
  jmp    L0
L18:
  mov    $0x0,%eax
L0:
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L104
  jmp    L55
L115:
  subl   $0x1,-0x4(%rbp)
L55:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L42
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
L42:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L72:
  leave
  ret
```

assistant: ```c
int trimLength(char *p, int *n) {
  if (p == NULL || n == NULL) {
    return -1;
  }
  int begin = 0;
  int end = strlen(p) - 1;
  if (end < 0) {
    return -1;
  }
  while (isspace((p[begin]) && p[begin] != 0)) {
    begin++;
  }
  while (isspace(p[end]) && p[end] != 0) {
    end--;
  }
  *n = end - begin + 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trimLength>:
  endbr64
  test   %rdi,%rdi
  je     L63
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L23
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,%ebx
  js     L19
  mov    $0x0,%ebp
L26:
  mov    %ebp,%r13d
  cmpb   $0x0,(%r12,%rbp,1)
  setne  %dil
  movzbl %dil,%edi
  call   <isspace@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L26
  movslq %ebx,%rbx
L46:
  mov    %ebx,%ebp
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L36
  sub    $0x1,%rbx
  cmpb   $0x0,0x1(%r12,%rbx,1)
  jne    L46
L36:
  sub    %r13d,%ebp
  add    $0x1,%ebp
  mov    %ebp,(%r14)
  mov    $0x0,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L13
L19:
  mov    $0xffffffff,%eax
  jmp    L13
L63:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int trimLength(char *p, int *n) {
  if (p == NULL || n == NULL) {
    return -1;
  }
  int begin = 0;
  int end = strlen(p) - 1;
  if (end < 0) {
    return -1;
  }
  while (isspace((p[begin]) && p[begin] != 0)) {
    begin++;
  }
  while (isspace(p[end]) && p[end] != 0) {
    end--;
  }
  *n = end - begin + 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trimLength>:
  endbr64
  test   %rdi,%rdi
  je     L50
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L8
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rbx
  js     L8
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L62:
  xor    %edi,%edi
  cmpb   $0x0,(%r12,%rbp,1)
  mov    %ebp,%r13d
  setne  %dil
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
  jmp    L67
  xchg   %ax,%ax
L29:
  sub    $0x1,%rbx
  cmpb   $0x0,0x1(%r12,%rbx,1)
  je     L44
L67:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%ebp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
L44:
  sub    %r13d,%ebp
  xor    %eax,%eax
  add    $0x1,%ebp
  mov    %ebp,(%r14)
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L42
L50:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int trimLength(char *p, int *n) {
  if (p == NULL || n == NULL) {
    return -1;
  }
  int begin = 0;
  int end = strlen(p) - 1;
  if (end < 0) {
    return -1;
  }
  while (isspace((p[begin]) && p[begin] != 0)) {
    begin++;
  }
  while (isspace(p[end]) && p[end] != 0) {
    end--;
  }
  *n = end - begin + 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trimLength>:
  endbr64
  test   %rdi,%rdi
  je     L50
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L38
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rbx
  js     L38
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %edi,%edi
  cmpb   $0x0,(%r12,%rbp,1)
  mov    %ebp,%r13d
  setne  %dil
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
  jmp    L67
  xchg   %ax,%ax
L68:
  sub    $0x1,%rbx
  cmpb   $0x0,0x1(%r12,%rbx,1)
  je     L34
L67:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%ebp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
L34:
  sub    %r13d,%ebp
  xor    %eax,%eax
  add    $0x1,%ebp
  mov    %ebp,(%r14)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0xffffffff,%eax
  jmp    L1
L50:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int trimLength(char *p, int *n) {
  if (p == NULL || n == NULL) {
    return -1;
  }
  int begin = 0;
  int end = strlen(p) - 1;
  if (end < 0) {
    return -1;
  }
  while (isspace((p[begin]) && p[begin] != 0)) {
    begin++;
  }
  while (isspace(p[end]) && p[end] != 0) {
    end--;
  }
  *n = end - begin + 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L40:
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L23
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
L23:
  addl   $0x1,-0x4(%rbp)
L43:
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L4
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L40
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubbleSort(char arr[], int n) {
  int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (arr[j] > arr[j + 1]) {
        char temp;
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L51
  lea    0x1(%rdi),%r9
  jmp    L13
L3:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L65
L64:
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%edx
  cmp    %dl,%cl
  jle    L3
  mov    %cl,0x1(%rax)
  mov    %dl,(%rax)
  jmp    L3
L65:
  sub    $0x1,%r8d
  je     L51
L13:
  test   %r8d,%r8d
  jle    L65
  mov    %rdi,%rax
  lea    -0x1(%r8),%esi
  add    %r9,%rsi
  jmp    L64
L51:
  ret
```

assistant: ```c
void bubbleSort(char arr[], int n) {
  int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (arr[j] > arr[j + 1]) {
        char temp;
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L8
  lea    0x1(%rdi),%r9
  nop
L28:
  lea    -0x1(%rdx),%esi
  mov    %rdi,%rax
  mov    %rsi,%r8
  add    %r9,%rsi
  nopl   0x0(%rax)
L4:
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%edx
  cmp    %dl,%cl
  jle    L22
  mov    %cl,0x1(%rax)
  mov    %dl,(%rax)
L22:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L4
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L28
L8:
  ret
```

assistant: ```c
void bubbleSort(char arr[], int n) {
  int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (arr[j] > arr[j + 1]) {
        char temp;
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L33
  lea    0x1(%rdi),%r9
  nop
L5:
  lea    -0x1(%rdx),%esi
  mov    %rdi,%rax
  mov    %rsi,%r8
  add    %r9,%rsi
  nopl   0x0(%rax)
L38:
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%edx
  cmp    %dl,%cl
  jle    L12
  mov    %cl,0x1(%rax)
  mov    %dl,(%rax)
L12:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L38
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L5
L33:
  ret
```

assistant: ```c
void bubbleSort(char arr[], int n) {
  int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (arr[j] > arr[j + 1]) {
        char temp;
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xfffffffa,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xff,-0x8(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xff,-0x8(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string

tool: D16: 0X%.8X can be represented by %d bits: %d


assistant: ```c
int main(void) {
  int x, n;
  x = 3;
  n = 3;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = -6;
  n = 5;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 8;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 9;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xfffffffa,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    $0x5,%edx
  mov    $0xfffffffa,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    $0x8,%edx
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    %eax,%ecx
  mov    $0x9,%edx
  mov    $0xff,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: 0X%.8X can be represented by %d bits: %d


assistant: ```c
int main(void) {
  int x, n;
  x = 3;
  n = 3;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = -6;
  n = 5;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 8;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 9;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0x3,%edi
  lea    D3(%rip),%rbp
  call   <fits_bits@plt>
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x3,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xfffffffa,%edi
  call   <fits_bits@plt>
  mov    $0x5,%edx
  mov    %rbp,%rdi
  mov    $0xfffffffa,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    $0x8,%edx
  mov    %rbp,%rdi
  mov    $0xff,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    %rbp,%rdi
  mov    $0x9,%edx
  mov    $0xff,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: 0X%.8X can be represented by %d bits: %d


assistant: ```c
int main(void) {
  int x, n;
  x = 3;
  n = 3;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = -6;
  n = 5;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 8;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 9;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%esi
  mov    $0x3,%edi
  lea    D8(%rip),%rbp
  call   <fits_bits@plt>
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x3,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xfffffffa,%edi
  call   <fits_bits@plt>
  mov    $0x5,%edx
  mov    %rbp,%rdi
  mov    $0xfffffffa,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x8,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    $0x8,%edx
  mov    %rbp,%rdi
  mov    $0xff,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  mov    $0x9,%esi
  mov    $0xff,%edi
  call   <fits_bits@plt>
  mov    %rbp,%rdi
  mov    $0x9,%edx
  mov    $0xff,%esi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: 0X%.8X can be represented by %d bits: %d


assistant: ```c
int main(void) {
  int x, n;
  x = 3;
  n = 3;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = -6;
  n = 5;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 8;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  x = 0xFF;
  n = 9;
  printf("0X%.8X can be represented by %d bits: %d\n", x, n, fits_bits(x, n));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <__isnan@plt>
  test   %rax,%rax
  je     L86
  movsd  -0x20(%rbp),%xmm0
  jmp    L99
L86:
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <__isnan@plt>
  test   %rax,%rax
  je     L24
  movsd  -0x18(%rbp),%xmm0
  jmp    L99
L24:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <__signbit@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <__signbit@plt>
  cmp    %rax,%rbx
  je     L10
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <__signbit@plt>
  test   %rax,%rax
  je     L94
  movsd  -0x20(%rbp),%xmm0
  jmp    L99
L94:
  movsd  -0x18(%rbp),%xmm0
  jmp    L99
L10:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L96
  movsd  -0x18(%rbp),%xmm0
  jmp    L99
L96:
  movsd  -0x20(%rbp),%xmm0
L99:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double fmax(double x, double y) {
  if (((sizeof(x) == sizeof(float)) ? __isnanf(x) : (sizeof(x) == sizeof(double)) ? __isnan(x) : __isnanl(x)))
    return (y);
  if (((sizeof(y) == sizeof(float)) ? __isnanf(y) : (sizeof(y) == sizeof(double)) ? __isnan(y) : __isnanl(y)))
    return (x);
  if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)) != ((sizeof(y) == sizeof(float)) ? __signbitf(y) : (sizeof(y) == sizeof(double)) ? __signbit(y) : __signbitl(y)))
    if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)))
      return (y);
    else
      return (x);
  return (x > y ? x : y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fmax>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbp
  movq   %xmm1,%rbx
  call   <__isnan@plt>
  test   %rax,%rax
  je     L10
L11:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  movq   %rbx,%xmm0
  call   <__isnan@plt>
  test   %rax,%rax
  je     L46
  mov    %rbp,%rbx
  jmp    L11
L46:
  movq   %rbp,%xmm0
  call   <__signbit@plt>
  mov    %rax,%r12
  movq   %rbx,%xmm0
  call   <__signbit@plt>
  cmp    %rax,%r12
  jne    L4
  movq   %rbp,%xmm2
  movq   %rbx,%xmm3
  maxsd  %xmm3,%xmm2
  movq   %xmm2,%rbx
  jmp    L11
L4:
  movq   %rbp,%xmm0
  call   <__signbit@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbp,%rbx
  jmp    L11
```

assistant: ```c
double fmax(double x, double y) {
  if (((sizeof(x) == sizeof(float)) ? __isnanf(x) : (sizeof(x) == sizeof(double)) ? __isnan(x) : __isnanl(x)))
    return (y);
  if (((sizeof(y) == sizeof(float)) ? __isnanf(y) : (sizeof(y) == sizeof(double)) ? __isnan(y) : __isnanl(y)))
    return (x);
  if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)) != ((sizeof(y) == sizeof(float)) ? __signbitf(y) : (sizeof(y) == sizeof(double)) ? __signbit(y) : __signbitl(y)))
    if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)))
      return (y);
    else
      return (x);
  return (x > y ? x : y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fmax>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <__isnan@plt>
  test   %rax,%rax
  je     L34
L20:
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L34:
  movsd  (%rsp),%xmm0
  call   <__isnan@plt>
  movsd  0x8(%rsp),%xmm2
  test   %rax,%rax
  jne    L37
  movapd %xmm2,%xmm0
  call   <__signbit@plt>
  movsd  (%rsp),%xmm0
  mov    %rax,%rbx
  call   <__signbit@plt>
  movsd  0x8(%rsp),%xmm2
  cmp    %rax,%rbx
  jne    L45
  comisd (%rsp),%xmm2
  jbe    L20
L37:
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  movapd %xmm2,%xmm0
  call   <__signbit@plt>
  movsd  0x8(%rsp),%xmm2
  test   %rax,%rax
  jne    L20
  jmp    L37
```

assistant: ```c
double fmax(double x, double y) {
  if (((sizeof(x) == sizeof(float)) ? __isnanf(x) : (sizeof(x) == sizeof(double)) ? __isnan(x) : __isnanl(x)))
    return (y);
  if (((sizeof(y) == sizeof(float)) ? __isnanf(y) : (sizeof(y) == sizeof(double)) ? __isnan(y) : __isnanl(y)))
    return (x);
  if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)) != ((sizeof(y) == sizeof(float)) ? __signbitf(y) : (sizeof(y) == sizeof(double)) ? __signbit(y) : __signbitl(y)))
    if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)))
      return (y);
    else
      return (x);
  return (x > y ? x : y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fmax>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <__isnan@plt>
  test   %rax,%rax
  je     L47
L52:
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L47:
  movsd  (%rsp),%xmm0
  call   <__isnan@plt>
  movsd  0x8(%rsp),%xmm2
  test   %rax,%rax
  jne    L32
  movapd %xmm2,%xmm0
  call   <__signbit@plt>
  movsd  (%rsp),%xmm0
  mov    %rax,%rbx
  call   <__signbit@plt>
  movsd  0x8(%rsp),%xmm2
  cmp    %rax,%rbx
  jne    L19
  comisd (%rsp),%xmm2
  jbe    L52
L32:
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movapd %xmm2,%xmm0
  call   <__signbit@plt>
  movsd  0x8(%rsp),%xmm2
  test   %rax,%rax
  jne    L52
  jmp    L32
```

assistant: ```c
double fmax(double x, double y) {
  if (((sizeof(x) == sizeof(float)) ? __isnanf(x) : (sizeof(x) == sizeof(double)) ? __isnan(x) : __isnanl(x)))
    return (y);
  if (((sizeof(y) == sizeof(float)) ? __isnanf(y) : (sizeof(y) == sizeof(double)) ? __isnan(y) : __isnanl(y)))
    return (x);
  if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)) != ((sizeof(y) == sizeof(float)) ? __signbitf(y) : (sizeof(y) == sizeof(double)) ? __signbit(y) : __signbitl(y)))
    if (((sizeof(x) == sizeof(float)) ? __signbitf(x) : (sizeof(x) == sizeof(double)) ? __signbit(x) : __signbitl(x)))
      return (y);
    else
      return (x);
  return (x > y ? x : y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<acu_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <acu_new_unique@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *acu_malloc(size_t s) {
  void *p = malloc(s);
  if (p)
    (void)acu_new_unique(p, free);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<acu_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <acu_new_unique@plt>
L7:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *acu_malloc(size_t s) {
  void *p = malloc(s);
  if (p)
    (void)acu_new_unique(p, free);
  return p;
}
```