ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<CHECK_SCORE>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  test   %edx,%edx
  jg     L19
  test   %ecx,%ecx
  jle    L24
L19:
  xor    %eax,%eax
  xor    %r10d,%r10d
  xor    %edi,%edi
  xor    %esi,%esi
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L65:
  mov    (%r8),%edx
  add    $0x4,%r8
  test   %edx,%edx
  jne    L75
  add    $0x1,%esi
  lea    0x0(%rbp,%rcx,1),%edx
  add    $0x1,%edi
  add    $0x1,%ecx
  movslq %edx,%rdx
  movslq %esi,%r11
  movzbl (%r12,%r11,1),%r11d
  mov    (%r9,%rdx,8),%rdx
  mov    (%rdx,%r11,4),%edx
  add    %edx,%r10d
  add    %edx,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
L31:
  cmp    %r13d,%ecx
  jl     L65
  cmp    %esi,%r14d
  jg     L65
L80:
  mov    0x48(%rsp),%rax
  mov    %edi,(%rax)
  mov    0x50(%rsp),%rax
  mov    %ebx,(%rax)
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  mov    0x40(%rsp),%r11d
  imul   %edx,%r11d
  test   %edx,%edx
  jle    L21
  add    0x38(%rsp),%r11d
  add    %edx,%esi
  add    %edx,%edi
  mov    $0x0,%edx
  sub    %r11d,%r10d
  sub    %r11d,%eax
  cmovs  %edx,%eax
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    0x38(%rsp),%r15d
  sub    %edx,%ecx
  sub    %edx,%edi
  mov    $0x0,%edx
  sub    %r11d,%r15d
  sub    %r15d,%r10d
  sub    %r15d,%eax
  cmovs  %edx,%eax
  jmp    L31
  nopl   0x0(%rax)
L24:
  xor    %r10d,%r10d
  xor    %edi,%edi
  jmp    L80
```

assistant: ```c
int CHECK_SCORE(int iw, const unsigned char *B, int M, int N, int *S, int **w, int g, int h, int *NC, int *sw_score) {
  register int i, j, op, nc;
  int itmp;
  int score;
  int l_score, mx_l_score;
  score = i = j = nc = l_score = mx_l_score = 0;
  while (i < M || j < N) {
    op = *S++;
    if (op == 0) {
      itmp = w[iw + i][B[++j]];
      score += itmp;
      i++;
      nc++;
      l_score += itmp;
      if (l_score < 0)
        l_score = 0;
      if (l_score > mx_l_score)
        mx_l_score = l_score;
    } else if (op > 0) {
      score = score - (g + op * h);
      j += op;
      nc += op;
      l_score -= (g + op * h);
      if (l_score < 0)
        l_score = 0;
    } else {
      score = score - (g - op * h);
      i -= op;
      nc -= op;
      l_score -= (g - op * h);
      if (l_score < 0)
        l_score = 0;
    }
  }
  *NC = nc;
  *sw_score = mx_l_score;
  return score;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calclen_l1a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L46
  mov    $0x1,%eax
  jmp    L4
L46:
  movl   $0x1f,-0x8(%rbp)
  jmp    L28
L11:
  shll   -0x14(%rbp)
  subl   $0x1,-0x8(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L11
L40:
  shll   -0x14(%rbp)
  addl   $0x2,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L40
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
const int calclen_l1a(unsigned int i) {
  int j, l = 0;
  if (i == 1)
    return 1;
  j = 31;
  while ((i & 0x80000000) == 0) {
    i <<= 1;
    j--;
  }
  do {
    i <<= 1;
    l += 2;
  } while (--j);
  return l + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<calclen_l1a>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L45
  test   %edi,%edi
  js     L22
  mov    $0x1f,%edx
L41:
  sub    $0x1,%edx
  add    %edi,%edi
  jns    L41
L4:
  mov    %edx,%eax
L47:
  sub    $0x1,%eax
  jne    L47
  lea    0x1(%rdx,%rdx,1),%eax
L45:
  ret
L22:
  mov    $0x1f,%edx
  jmp    L4
```

assistant: ```c
const int calclen_l1a(unsigned int i) {
  int j, l = 0;
  if (i == 1)
    return 1;
  j = 31;
  while ((i & 0x80000000) == 0) {
    i <<= 1;
    j--;
  }
  do {
    i <<= 1;
    l += 2;
  } while (--j);
  return l + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calclen_l1a>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L3
  mov    $0x1f,%eax
  test   %edi,%edi
  js     L5
  nopw   0x0(%rax,%rax,1)
L29:
  sub    $0x1,%eax
  add    %edi,%edi
  jns    L29
L5:
  lea    0x1(%rax,%rax,1),%eax
L3:
  ret
```

assistant: ```c
const int calclen_l1a(unsigned int i) {
  int j, l = 0;
  if (i == 1)
    return 1;
  j = 31;
  while ((i & 0x80000000) == 0) {
    i <<= 1;
    j--;
  }
  do {
    i <<= 1;
    l += 2;
  } while (--j);
  return l + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calclen_l1a>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L20
  mov    $0x1f,%eax
  test   %edi,%edi
  js     L28
  nopw   0x0(%rax,%rax,1)
L11:
  sub    $0x1,%eax
  add    %edi,%edi
  jns    L11
L28:
  lea    0x1(%rax,%rax,1),%eax
L20:
  ret
```

assistant: ```c
const int calclen_l1a(unsigned int i) {
  int j, l = 0;
  if (i == 1)
    return 1;
  j = 31;
  while ((i & 0x80000000) == 0) {
    i <<= 1;
    j--;
  }
  do {
    i <<= 1;
    l += 2;
  } while (--j);
  return l + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<var_column_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
L8:
  mov    -0x40(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void var_column_p(size_t n, int a[n][n], size_t j, int *dest) {
  int *ap = &a[0][j];
  int *dend = &dest[n];
  while (dest != dend) {
    *dest = *ap;
    dest++;
    ap += n;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<var_column_p>:
  endbr64
  shl    $0x2,%rdi
  lea    (%rsi,%rdx,4),%rax
  lea    (%rcx,%rdi,1),%rsi
  cmp    %rsi,%rcx
  je     L12
L0:
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  add    $0x4,%rcx
  add    %rdi,%rax
  cmp    %rcx,%rsi
  jne    L0
L12:
  ret
```

assistant: ```c
void var_column_p(size_t n, int a[n][n], size_t j, int *dest) {
  int *ap = &a[0][j];
  int *dend = &dest[n];
  while (dest != dend) {
    *dest = *ap;
    dest++;
    ap += n;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<var_column_p>:
  endbr64
  shl    $0x2,%rdi
  lea    (%rsi,%rdx,4),%rax
  lea    (%rcx,%rdi,1),%rsi
  cmp    %rsi,%rcx
  je     L8
  nopl   (%rax)
L14:
  mov    (%rax),%edx
  add    $0x4,%rcx
  add    %rdi,%rax
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%rsi
  jne    L14
L8:
  ret
```

assistant: ```c
void var_column_p(size_t n, int a[n][n], size_t j, int *dest) {
  int *ap = &a[0][j];
  int *dend = &dest[n];
  while (dest != dend) {
    *dest = *ap;
    dest++;
    ap += n;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<var_column_p>:
  endbr64
  mov    %rdx,%r8
  lea    0x0(,%rdi,4),%rdx
  lea    (%rsi,%r8,4),%rax
  lea    (%rcx,%rdx,1),%rsi
  cmp    %rsi,%rcx
  je     L8
  cmp    $0x1,%rdi
  jne    L0
  nopw   0x0(%rax,%rax,1)
L27:
  mov    (%rax),%edx
  add    $0x4,%rcx
  add    $0x4,%rax
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%rsi
  jne    L27
L8:
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rax),%edi
  add    $0x4,%rcx
  add    %rdx,%rax
  mov    %edi,-0x4(%rcx)
  cmp    %rcx,%rsi
  jne    L0
  ret
```

assistant: ```c
void var_column_p(size_t n, int a[n][n], size_t j, int *dest) {
  int *ap = &a[0][j];
  int *dend = &dest[n];
  while (dest != dend) {
    *dest = *ap;
    dest++;
    ap += n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<QRinput_estimateBitsModeAn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L4
  addl   $0x6,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int QRinput_estimateBitsModeAn(int size) {
  int w;
  int bits;
  w = size / 2;
  bits = w * 11;
  if (size & 1) {
    bits += 6;
  }
  return bits;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<QRinput_estimateBitsModeAn>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  lea    0x6(%rdx),%eax
  test   $0x1,%dil
  cmove  %edx,%eax
  ret
```

assistant: ```c
int QRinput_estimateBitsModeAn(int size) {
  int w;
  int bits;
  w = size / 2;
  bits = w * 11;
  if (size & 1) {
    bits += 6;
  }
  return bits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QRinput_estimateBitsModeAn>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  and    $0x1,%edi
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  lea    0x6(%rdx),%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int QRinput_estimateBitsModeAn(int size) {
  int w;
  int bits;
  w = size / 2;
  bits = w * 11;
  if (size & 1) {
    bits += 6;
  }
  return bits;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<QRinput_estimateBitsModeAn>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  and    $0x1,%edi
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  lea    0x6(%rdx),%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int QRinput_estimateBitsModeAn(int size) {
  int w;
  int bits;
  w = size / 2;
  bits = w * 11;
  if (size & 1) {
    bits += 6;
  }
  return bits;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check>:
  endbr64
  mov    %rdi,%r9
  mov    %edx,%edi
  mov    %ecx,%edx
  movslq %esi,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%r9,%rax,4),%r10
  movslq %edi,%rax
  lea    (%r9,%rax,4),%rcx
  mov    $0x0,%eax
  jmp    L58
L98:
  add    $0x1,%rax
  add    $0x24,%rcx
  cmp    $0x9,%rax
  je     L129
L58:
  mov    %eax,%r8d
  cmp    %eax,%esi
  je     L11
  cmp    %edx,(%rcx)
  je     L49
L11:
  cmp    %r8d,%edi
  je     L98
  cmp    %edx,(%r10,%rax,4)
  jne    L98
  mov    $0x0,%eax
  ret
L129:
  push   %rbx
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%r11d
  lea    0x2(%rcx),%ebx
  movslq %ecx,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%r9,%rax,4),%r10
  lea    0x2(%r11),%r8d
  jmp    L128
L126:
  cmp    %edx,(%r9,%rax,4)
  je     L93
L78:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jl     L88
L73:
  cmp    %ecx,%esi
  jne    L126
  cmp    %eax,%edi
  jne    L126
  jmp    L78
L88:
  add    $0x1,%ecx
  add    $0x24,%r10
  cmp    %ebx,%ecx
  jg     L63
L128:
  mov    %r10,%r9
  movslq %r11d,%rax
  jmp    L73
L49:
  mov    $0x0,%eax
  ret
L93:
  mov    $0x0,%eax
L146:
  pop    %rbx
  ret
L63:
  mov    $0x1,%eax
  jmp    L146
```

assistant: ```c
int check(int (*a)[9], int x, int y, int b) {
  int i;
  int j;
  for (j = 0; j < 9; ++j) {
    if (j != x) {
      if (b == a[j][y])
        return 0;
    }
    if (j != y) {
      if (b == a[x][j])
        return 0;
    }
  }
  i = x - x % 3;
  j = y - y % 3;
  int loo1 = i;
  int loo2 = j;
  for (i = loo1; i < loo1 + 3; ++i)
    for (j = loo2; j < loo2 + 3; ++j) {
      if (i == x && j == y)
        continue;
      if (b == a[i][j])
        return 0;
    }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check>:
  endbr64
  movslq %esi,%r9
  movslq %edx,%r11
  push   %rbx
  mov    %rdi,%r10
  lea    (%r9,%r9,8),%rax
  mov    %r9,%r8
  lea    (%rdi,%r11,4),%rsi
  lea    (%rdi,%rax,4),%rbx
  xor    %eax,%eax
  nop
L56:
  mov    %eax,%edi
  cmp    %eax,%r8d
  je     L45
  cmp    %ecx,(%rsi)
  je     L76
L45:
  cmp    %edi,%edx
  je     L32
  cmp    %ecx,(%rbx,%rax,4)
  je     L76
L32:
  add    $0x1,%rax
  add    $0x24,%rsi
  cmp    $0x9,%rax
  jne    L56
  imul   $0x55555556,%r9,%r9
  mov    %r8d,%eax
  imul   $0x55555556,%r11,%r11
  sar    $0x1f,%eax
  shr    $0x20,%r9
  sub    %eax,%r9d
  mov    %edx,%eax
  shr    $0x20,%r11
  lea    (%r9,%r9,2),%ebx
  sar    $0x1f,%eax
  sub    %eax,%r11d
  movslq %ebx,%rdi
  lea    (%r11,%r11,2),%eax
  lea    (%rdi,%rdi,8),%rdi
  lea    (%r10,%rdi,4),%rdi
  lea    0x2(%rbx),%r11d
  movslq %eax,%r10
  lea    0x2(%rax),%esi
L62:
  cmp    %ebx,%r8d
  mov    %r10,%rax
  sete   %r9b
  nopl   0x0(%rax,%rax,1)
L66:
  cmp    %eax,%edx
  jne    L0
  test   %r9b,%r9b
  jne    L21
L0:
  cmp    %ecx,(%rdi,%rax,4)
  je     L76
L21:
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L66
  add    $0x1,%ebx
  add    $0x24,%rdi
  cmp    %r11d,%ebx
  jle    L62
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L76:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int check(int (*a)[9], int x, int y, int b) {
  int i;
  int j;
  for (j = 0; j < 9; ++j) {
    if (j != x) {
      if (b == a[j][y])
        return 0;
    }
    if (j != y) {
      if (b == a[x][j])
        return 0;
    }
  }
  i = x - x % 3;
  j = y - y % 3;
  int loo1 = i;
  int loo2 = j;
  for (i = loo1; i < loo1 + 3; ++i)
    for (j = loo2; j < loo2 + 3; ++j) {
      if (i == x && j == y)
        continue;
      if (b == a[i][j])
        return 0;
    }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm5
  movss  0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm0
  movaps %xmm2,%xmm4
  divss  %xmm5,%xmm4
  movaps %xmm1,%xmm3
  divss  %xmm0,%xmm3
  ucomiss %xmm3,%xmm4
  jp     L110
  je     L65
L110:
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm1
  setnp  %al
  mov    $0x0,%ecx
  cmovne %ecx,%eax
  ucomiss %xmm3,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %al,%al
  je     L97
  test   %dl,%dl
  jne    L65
L97:
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm0
  setnp  %cl
  mov    $0x0,%edi
  cmovne %edi,%ecx
  ucomiss %xmm3,%xmm5
  setnp  %sil
  cmovne %edi,%esi
  test   %cl,%cl
  je     L48
  test   %sil,%sil
  jne    L65
L48:
  test   %dl,%dl
  je     L94
  test   %sil,%sil
  jne    L65
L94:
  test   %al,%al
  je     L68
  test   %cl,%cl
  je     L68
L65:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L68:
  movaps %xmm2,%xmm3
  mulss  %xmm0,%xmm3
  movaps %xmm5,%xmm4
  mulss  %xmm1,%xmm4
  subss  %xmm2,%xmm1
  movaps %xmm4,%xmm2
  subss  %xmm3,%xmm2
  divss  %xmm2,%xmm1
  subss  %xmm5,%xmm0
  subss  %xmm4,%xmm3
  divss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D8(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L25
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D7: %f%f%f%f

tool: D27: INF

tool: D8: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2, c1, c2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  if (a1 / b1 == a2 / b2 || a1 == 0 && a2 == 0 || b1 == 0 && b2 == 0 || a1 == 0 && b1 == 0 || a2 == 0 && b2 == 0) {
    printf("INF");
  } else {
    c1 = ((b2 - b1) / (a1 * b2 - a2 * b1));
    c2 = ((a2 - a1) / (a2 * b1 - a1 * b2));
    printf("(%.3f,%.3f)", c1, c2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm4
  movss  0x14(%rsp),%xmm0
  movaps %xmm2,%xmm5
  movaps %xmm1,%xmm3
  divss  %xmm4,%xmm5
  divss  %xmm0,%xmm3
  ucomiss %xmm3,%xmm5
  jp     L72
  je     L58
L72:
  pxor   %xmm3,%xmm3
  mov    $0x0,%ecx
  ucomiss %xmm3,%xmm1
  setnp  %al
  cmovne %ecx,%eax
  ucomiss %xmm3,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %al,%al
  je     L22
  test   %dl,%dl
  jne    L58
L22:
  ucomiss %xmm3,%xmm0
  mov    $0x0,%edi
  setnp  %cl
  cmovne %edi,%ecx
  ucomiss %xmm3,%xmm4
  setnp  %sil
  cmovne %edi,%esi
  test   %cl,%cl
  je     L20
  test   %sil,%sil
  jne    L58
L20:
  test   %dl,%dl
  je     L106
  test   %sil,%sil
  jne    L58
L106:
  test   %al,%al
  je     L10
  test   %cl,%cl
  jne    L58
L10:
  movaps %xmm4,%xmm5
  movaps %xmm2,%xmm3
  mov    $0x2,%eax
  mulss  %xmm1,%xmm5
  subss  %xmm2,%xmm1
  lea    D16(%rip),%rdi
  mulss  %xmm0,%xmm3
  subss  %xmm4,%xmm0
  movaps %xmm5,%xmm2
  subss  %xmm3,%xmm2
  subss  %xmm5,%xmm3
  divss  %xmm2,%xmm1
  divss  %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L58:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D22
type_infered: string

tool: D13: %f%f%f%f

tool: D16: (%.3f,%.3f)

tool: D22: INF

assistant: ```c
int main() {
  float a1, b1, a2, b2, c1, c2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  if (a1 / b1 == a2 / b2 || a1 == 0 && a2 == 0 || b1 == 0 && b2 == 0 || a1 == 0 && b1 == 0 || a2 == 0 && b2 == 0) {
    printf("INF");
  } else {
    c1 = ((b2 - b1) / (a1 * b2 - a2 * b1));
    c2 = ((a2 - a1) / (a2 * b1 - a1 * b2));
    printf("(%.3f,%.3f)", c1, c2);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D25(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0x10(%rsp),%xmm1
  movss  0xc(%rsp),%xmm4
  movss  0x14(%rsp),%xmm0
  movaps %xmm2,%xmm5
  movaps %xmm1,%xmm3
  divss  %xmm4,%xmm5
  divss  %xmm0,%xmm3
  ucomiss %xmm3,%xmm5
  jp     L99
  je     L68
L99:
  pxor   %xmm3,%xmm3
  mov    $0x0,%ecx
  ucomiss %xmm3,%xmm1
  setnp  %al
  cmovne %ecx,%eax
  ucomiss %xmm3,%xmm2
  setnp  %dl
  cmovne %ecx,%edx
  test   %al,%al
  je     L65
  test   %dl,%dl
  jne    L68
L65:
  ucomiss %xmm3,%xmm0
  mov    $0x0,%edi
  setnp  %cl
  cmovne %edi,%ecx
  ucomiss %xmm3,%xmm4
  setnp  %sil
  cmovne %edi,%esi
  test   %cl,%cl
  je     L24
  test   %sil,%sil
  jne    L68
L24:
  test   %dl,%dl
  je     L13
  test   %sil,%sil
  jne    L68
L13:
  test   %al,%al
  je     L17
  test   %cl,%cl
  jne    L68
L17:
  movaps %xmm4,%xmm5
  movaps %xmm2,%xmm3
  mov    $0x2,%eax
  mulss  %xmm1,%xmm5
  subss  %xmm2,%xmm1
  lea    D1(%rip),%rdi
  mulss  %xmm0,%xmm3
  subss  %xmm4,%xmm0
  movaps %xmm5,%xmm2
  subss  %xmm3,%xmm2
  subss  %xmm5,%xmm3
  divss  %xmm2,%xmm1
  divss  %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L68:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string

tool: D25: %f%f%f%f

tool: D1: (%.3f,%.3f)

tool: D22: INF

assistant: ```c
int main() {
  float a1, b1, a2, b2, c1, c2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  if (a1 / b1 == a2 / b2 || a1 == 0 && a2 == 0 || b1 == 0 && b2 == 0 || a1 == 0 && b1 == 0 || a2 == 0 && b2 == 0) {
    printf("INF");
  } else {
    c1 = ((b2 - b1) / (a1 * b2 - a2 * b1));
    c2 = ((a2 - a1) / (a2 * b1 - a1 * b2));
    printf("(%.3f,%.3f)", c1, c2);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x20(%rbp),%rcx
  cmp    -0x18(%rbp),%rcx
  jne    L42
  test   %eax,%eax
  je     L42
  mov    $0x0,%ebx
  jmp    L59
L16:
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rdx,%rcx
  mov    (%rcx),%ecx
  cmp    %ecx,%eax
  jle    L13
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rdx,%rcx
  mov    (%rcx),%ecx
  sub    %ecx,%eax
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rdx,%rcx
  movl   $0x0,(%rcx)
  jmp    L11
L13:
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rdx,%rcx
  mov    (%rcx),%esi
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  add    %rdx,%rcx
  sub    %eax,%esi
  mov    %esi,(%rcx)
  mov    $0x0,%eax
L11:
  add    $0x1,%ebx
L59:
  cmp    $0x2,%ebx
  jle    L16
  lea    0x8(%rdx),%rax
  mov    (%rax),%esi
  lea    0x4(%rdx),%rax
  mov    (%rax),%ecx
  mov    (%rdx),%edx
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <Write@plt>
  add    $0x10,%rsp
  nop
  jmp    L44
L42:
  test   %eax,%eax
  je     L44
  sub    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0xf,%edi
  mov    $0x0,%eax
  call   <Write@plt>
  add    $0x10,%rsp
L44:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void subtract(from, totalfrom, crewfrom, fromcap, pcfrom) struct ship *from, *fromcap;
int pcfrom;
register int totalfrom, crewfrom[3];
{
  register int n;
  if (fromcap == from && totalfrom) {
    for (n = 0; n < 3; n++) {
      if (totalfrom > crewfrom[n]) {
        totalfrom -= crewfrom[n];
        crewfrom[n] = 0;
      } else {
        crewfrom[n] -= totalfrom;
        totalfrom = 0;
      }
    }
    Write(4, from, 0, crewfrom[0], crewfrom[1], crewfrom[2], 0);
  } else if (totalfrom) {
    pcfrom -= totalfrom;
    pcfrom = pcfrom < 0 ? 0 : pcfrom;
    Write(15, from, 0, pcfrom, 0, 0, 0);
  }
}
```