ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L51
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L6
  jmp    L51
L29:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x24(%rbp)
  addq   $0x1,-0x38(%rbp)
L51:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L29
  jmp    L10
L6:
  addq   $0x1,-0x38(%rbp)
L10:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: Token: %s 


assistant: ```c
void test(char *data) {
  char tok[20];
  int i = 0;
  if (isalpha(*data) || *data == '_') {
    while (isalnum(*data) || *data == '_') {
      tok[i] = *data;
      i++;
      data++;
    }
  } else
    data++;
  printf("Token: %s \n", tok);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L4
L23:
  mov    %rsp,%rbp
  jmp    L7
L4:
  cmpb   $0x5f,(%rbx)
  jne    L50
  jmp    L23
L22:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
L7:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L22
  cmpb   $0x5f,(%rbx)
  je     L22
L50:
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: Token: %s 


assistant: ```c
void test(char *data) {
  char tok[20];
  int i = 0;
  if (isalpha(*data) || *data == '_') {
    while (isalnum(*data) || *data == '_') {
      tok[i] = *data;
      i++;
      data++;
    }
  } else
    data++;
  printf("Token: %s \n", tok);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  movsbl (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <isalpha@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  jne    L32
  cmp    $0x5f,%dil
  je     L32
  mov    %rsp,%r12
L54:
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    %rsp,%r12
  mov    %r12,%rbp
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L43:
  movsbl 0x1(%rbx),%edi
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
L59:
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl (%rbx),%eax
  jne    L43
  cmp    $0x5f,%al
  je     L43
  jmp    L54
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: Token: %s 


assistant: ```c
void test(char *data) {
  char tok[20];
  int i = 0;
  if (isalpha(*data) || *data == '_') {
    while (isalnum(*data) || *data == '_') {
      tok[i] = *data;
      i++;
      data++;
    }
  } else
    data++;
  printf("Token: %s \n", tok);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  movsbl (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L31
  cmpb   $0x5f,(%rbx)
  mov    %rsp,%r12
  je     L31
L11:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  mov    %rsp,%r12
  mov    %r12,%rbp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
L23:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl (%rbx),%eax
  jne    L58
  cmp    $0x5f,%al
  je     L58
  jmp    L11
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: Token: %s 


assistant: ```c
void test(char *data) {
  char tok[20];
  int i = 0;
  if (isalpha(*data) || *data == '_') {
    while (isalnum(*data) || *data == '_') {
      tok[i] = *data;
      i++;
      data++;
    }
  } else
    data++;
  printf("Token: %s \n", tok);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L23
L30:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L34:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x2,-0x14(%rbp)
  jle    L34
  addl   $0x1,-0x18(%rbp)
L23:
  cmpl   $0x6,-0x18(%rbp)
  jle    L30
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
data_type: string
name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string

tool: D10: dmean

tool: D22: # c::%s:len=%d


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D0(%rip),%r15
  jmp    L39
L22:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L31
L39:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L13:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L13
  jmp    L22
L31:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string

tool: D0: dmean

tool: D1: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D22(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L15:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L16:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L16
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L15
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
type: string
name: read_data
arguments: data_tag: D29
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D22: dmean

tool: D29: # c::%s:len=%d


tool: D18: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D0(%rip),%r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L5:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L10:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L10
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L5
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D0: dmean

tool: D16: # c::%s:len=%d


tool: D9: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmean", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L45
  mov    $0xffffffff,%eax
  jmp    L19
L45:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  jmp    L19
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L16
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binarySearch>
  jmp    L19
L16:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <binarySearch>
L19:
  leave
  ret
```

assistant: ```c
int binarySearch(int arr[], int key, int low, int high) {
  int mid;
  if (low > high)
    return (-1);
  mid = (low + high) / 2;
  if (arr[mid] == key)
    return (mid);
  if (arr[mid] > key)
    return (binarySearch(arr, key, low, mid - 1));
  else
    return (binarySearch(arr, key, mid + 1, high));
}
```
user: Translate the below assembly code into C programming language:

```asm
<binarySearch>:
  endbr64
  cmp    %ecx,%edx
  jg     L2
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    (%rdx,%rcx,1),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %esi,%eax
  movslq %esi,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %edi,%r9d
  je     L3
  jle    L8
  lea    -0x1(%rsi),%ecx
  mov    %edi,%esi
  mov    %r8,%rdi
  call   <binarySearch>
L3:
  add    $0x8,%rsp
  ret
L8:
  lea    0x1(%rsi),%edx
  mov    %edi,%esi
  mov    %r8,%rdi
  call   <binarySearch>
  jmp    L3
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binarySearch(int arr[], int key, int low, int high) {
  int mid;
  if (low > high)
    return (-1);
  mid = (low + high) / 2;
  if (arr[mid] == key)
    return (mid);
  if (arr[mid] > key)
    return (binarySearch(arr, key, low, mid - 1));
  else
    return (binarySearch(arr, key, mid + 1, high));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binarySearch>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L36
  jmp    L14
  nopl   (%rax)
L44:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L14
L36:
  lea    (%rdx,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %esi,(%r8,%rdi,4)
  je     L10
  jg     L44
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L36
L14:
  mov    $0xffffffff,%r9d
L10:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int binarySearch(int arr[], int key, int low, int high) {
  int mid;
  if (low > high)
    return (-1);
  mid = (low + high) / 2;
  if (arr[mid] == key)
    return (mid);
  if (arr[mid] > key)
    return (binarySearch(arr, key, low, mid - 1));
  else
    return (binarySearch(arr, key, mid + 1, high));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binarySearch>:
  endbr64
  nopl   0x0(%rax)
L2:
  cmp    %ecx,%edx
  jg     L36
L17:
  lea    (%rdx,%rcx,1),%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %esi,(%rdi,%r8,4)
  je     L26
  jle    L27
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jge    L17
L36:
  mov    $0xffffffff,%eax
L26:
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    0x1(%rax),%edx
  jmp    L2
```

assistant: ```c
int binarySearch(int arr[], int key, int low, int high) {
  int mid;
  if (low > high)
    return (-1);
  mid = (low + high) / 2;
  if (arr[mid] == key)
    return (mid);
  if (arr[mid] > key)
    return (binarySearch(arr, key, low, mid - 1));
  else
    return (binarySearch(arr, key, mid + 1, high));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parsenum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0x6b,%al
  je     L58
  sub    $0x47,%eax
  cmp    $0x26,%al
  ja     L45
  movzbl %al,%eax
  lea    D3(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L58:
  movb   $0x0,(%rdx)
  mov    $0x3e8,%r12d
  jmp    L86
  movb   $0x0,(%rdx)
  mov    $0xf4240,%r12d
  jmp    L86
  movb   $0x0,(%rdx)
  mov    $0x3b9aca00,%r12d
  jmp    L86
  movb   $0x0,(%rdx)
  mov    $0x400,%r12d
  jmp    L86
  movb   $0x0,(%rdx)
  mov    $0x100000,%r12d
  jmp    L86
  movb   $0x0,(%rdx)
  mov    $0x40000000,%r12d
  jmp    L86
L45:
  mov    $0x1,%r12d
L86:
  mov    %rbp,%rdx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L12
  mov    $0x0,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  imul   0x0(%rbp),%r12d
  mov    %r12d,0x0(%rbp)
  jmp    L7
```

tool_calls: name: parse_data
arguments: tag: D13
type: string

tool: D13: %i

assistant: ```c
bool parsenum(char *str, int *out) {
  int len = strlen(str);
  int multiplier = 1;
  if (str[len - 1] == 'k') {
    multiplier = 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'm') {
    multiplier = 1000 * 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'g') {
    multiplier = 1000 * 1000 * 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'K') {
    multiplier = 1024;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'M') {
    multiplier = 1024 * 1024;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'G') {
    multiplier = 1024 * 1024 * 1024;
    str[len - 1] = '\0';
  }
  if (sscanf(str, "%i", out) == 1) {
    *out = *out * multiplier;
    return true;
  } else {
    return false;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parsenum>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0x6b,%al
  je     L68
  sub    $0x47,%eax
  cmp    $0x26,%al
  ja     L60
  lea    D12(%rip),%rcx
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L60:
  mov    $0x1,%r12d
L29:
  mov    %rbx,%rdx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L22
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L68:
  movb   $0x0,(%rdx)
  mov    $0x3e8,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L22:
  imul   (%rbx),%r12d
  mov    %r12d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  movb   $0x0,(%rdx)
  mov    $0xf4240,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  movb   $0x0,(%rdx)
  mov    $0x3b9aca00,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  movb   $0x0,(%rdx)
  mov    $0x100000,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  movb   $0x0,(%rdx)
  mov    $0x400,%r12d
  jmp    L29
  nopl   0x0(%rax,%rax,1)
  movb   $0x0,(%rdx)
  mov    $0x40000000,%r12d
  jmp    L29
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %i

assistant: ```c
bool parsenum(char *str, int *out) {
  int len = strlen(str);
  int multiplier = 1;
  if (str[len - 1] == 'k') {
    multiplier = 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'm') {
    multiplier = 1000 * 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'g') {
    multiplier = 1000 * 1000 * 1000;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'K') {
    multiplier = 1024;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'M') {
    multiplier = 1024 * 1024;
    str[len - 1] = '\0';
  } else if (str[len - 1] == 'G') {
    multiplier = 1024 * 1024 * 1024;
    str[len - 1] = '\0';
  }
  if (sscanf(str, "%i", out) == 1) {
    *out = *out * multiplier;
    return true;
  } else {
    return false;
  }
}
```