ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  lea    0xc8(%rsp),%r12
  mov    %rbx,%rbp
  lea    D7(%rip),%r13
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rsi
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  cltd
  sub    %edx,%esi
  imul   $0x3e8,%esi,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %eax,0x0(%rbp)
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x32,%esi
  call   <heap_sort@plt>
  lea    D7(%rip),%rbp
L22:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[50];
  srand(time(NULL));
  int i;
  for (i = 0; i < 50; i++) {
    a[i] = rand() % (1000 - 0) + 0;
    printf("%d ", a[i]);
  }
  printf("\n");
  heap_sort(a, 50);
  for (i = 0; i < 50; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0xc8(%rsp),%r12
  call   <time@plt>
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  mov    %r13,%rdi
  movslq %eax,%rsi
  cltd
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  sub    %edx,%esi
  imul   $0x3e8,%esi,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x32,%esi
  mov    %r14,%rdi
  call   <heap_sort@plt>
  nop
L13:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[50];
  srand(time(NULL));
  int i;
  for (i = 0; i < 50; i++) {
    a[i] = rand() % (1000 - 0) + 0;
    printf("%d ", a[i]);
  }
  printf("\n");
  heap_sort(a, 50);
  for (i = 0; i < 50; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0xc8(%rsp),%r12
  call   <time@plt>
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  mov    %r13,%rdi
  movslq %eax,%rsi
  cltd
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  sub    %edx,%esi
  imul   $0x3e8,%esi,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x32,%esi
  mov    %r14,%rdi
  call   <heap_sort@plt>
  nop
L15:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: %d 

assistant: ```c
int main(int argc, char **argv) {
  int a[50];
  srand(time(NULL));
  int i;
  for (i = 0; i < 50; i++) {
    a[i] = rand() % (1000 - 0) + 0;
    printf("%d ", a[i]);
  }
  printf("\n");
  heap_sort(a, 50);
  for (i = 0; i < 50; i++) {
    printf("%d ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x2,%edi
  call   <setDebuggingLevel@plt>
  mov    $0x0,%eax
  call   <testListCreation@plt>
  mov    $0x0,%eax
  call   <testListAddition@plt>
  mov    $0x0,%eax
  call   <testListRemoval@plt>
  mov    $0x0,%eax
  call   <testListResizing@plt>
  mov    $0x0,%eax
  call   <testLargeVectors@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setDebuggingLevel(2);
  testListCreation();
  testListAddition();
  testListRemoval();
  testListResizing();
  testLargeVectors();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <setDebuggingLevel@plt>
  mov    $0x0,%eax
  call   <testListCreation@plt>
  mov    $0x0,%eax
  call   <testListAddition@plt>
  mov    $0x0,%eax
  call   <testListRemoval@plt>
  mov    $0x0,%eax
  call   <testListResizing@plt>
  mov    $0x0,%eax
  call   <testLargeVectors@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setDebuggingLevel(2);
  testListCreation();
  testListAddition();
  testListRemoval();
  testListResizing();
  testLargeVectors();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <setDebuggingLevel@plt>
  xor    %eax,%eax
  call   <testListCreation@plt>
  xor    %eax,%eax
  call   <testListAddition@plt>
  xor    %eax,%eax
  call   <testListRemoval@plt>
  xor    %eax,%eax
  call   <testListResizing@plt>
  xor    %eax,%eax
  call   <testLargeVectors@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setDebuggingLevel(2);
  testListCreation();
  testListAddition();
  testListRemoval();
  testListResizing();
  testLargeVectors();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <setDebuggingLevel@plt>
  xor    %eax,%eax
  call   <testListCreation@plt>
  xor    %eax,%eax
  call   <testListAddition@plt>
  xor    %eax,%eax
  call   <testListRemoval@plt>
  xor    %eax,%eax
  call   <testListResizing@plt>
  xor    %eax,%eax
  call   <testLargeVectors@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  setDebuggingLevel(2);
  testListCreation();
  testListAddition();
  testListRemoval();
  testListResizing();
  testLargeVectors();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x79,%eax
  je     L62
  cmp    $0x79,%eax
  jg     L24
  cmp    $0x6e,%eax
  je     L53
  cmp    $0x6e,%eax
  jg     L24
  cmp    $0x4e,%eax
  je     L53
  cmp    $0x59,%eax
  jne    L24
L62:
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L53:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L24:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D45
datatype: string
name: retrieve_data
arguments: data_label: D43
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D24: Is SP an easy course? (Y/N): 

tool: D17: %c

tool: D45: I think so too!


tool: D43: Really?


tool: D4: Is this Yes or No?


assistant: ```c
int main() {
  char answer;
  printf("Is SP an easy course? (Y/N): ");
  scanf("%c", &answer);
  switch (answer) {
  case 'Y':
  case 'y':
    printf("I think so too!\n");
    break;
  case 'N':
  case 'n':
    printf("Really?\n");
    break;
  default:
    printf("Is this Yes or No?\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x6e,%al
  je     L68
  jg     L39
  cmp    $0x4e,%al
  je     L68
  cmp    $0x59,%al
  jne    L72
L32:
  lea    D7(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L39:
  cmp    $0x79,%al
  je     L32
L72:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L68:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string
name: unpack_data
arguments: data_tag: D33
datatype: string

tool: D39: Is SP an easy course? (Y/N): 

tool: D8: %c

tool: D7: I think so too!


tool: D16: Is this Yes or No?


tool: D33: Really?


assistant: ```c
int main() {
  char answer;
  printf("Is SP an easy course? (Y/N): ");
  scanf("%c", &answer);
  switch (answer) {
  case 'Y':
  case 'y':
    printf("I think so too!\n");
    break;
  case 'N':
  case 'n':
    printf("Really?\n");
    break;
  default:
    printf("Is this Yes or No?\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D42(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x6e,%al
  je     L43
  jg     L25
  cmp    $0x4e,%al
  je     L43
  cmp    $0x59,%al
  jne    L4
L62:
  lea    D48(%rip),%rdi
  call   <printf@plt>
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    $0x79,%al
  je     L62
L4:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L43:
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D48
type: string
name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D46
type: string

tool: D42: Is SP an easy course? (Y/N): 

tool: D13: %c

tool: D48: I think so too!


tool: D18: Is this Yes or No?


tool: D46: Really?


assistant: ```c
int main() {
  char answer;
  printf("Is SP an easy course? (Y/N): ");
  scanf("%c", &answer);
  switch (answer) {
  case 'Y':
  case 'y':
    printf("I think so too!\n");
    break;
  case 'N':
  case 'n':
    printf("Really?\n");
    break;
  default:
    printf("Is this Yes or No?\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D48(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x6e,%al
  je     L47
  jg     L50
  cmp    $0x4e,%al
  je     L47
  cmp    $0x59,%al
  jne    L57
L73:
  lea    D22(%rip),%rdi
  call   <printf@plt>
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  cmp    $0x79,%al
  je     L73
L57:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L47:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D31
data_type: string
name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D49
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D48: Is SP an easy course? (Y/N): 

tool: D31: %c

tool: D22: I think so too!


tool: D49: Is this Yes or No?


tool: D2: Really?


assistant: ```c
int main() {
  char answer;
  printf("Is SP an easy course? (Y/N): ");
  scanf("%c", &answer);
  switch (answer) {
  case 'Y':
  case 'y':
    printf("I think so too!\n");
    break;
  case 'N':
  case 'n':
    printf("Really?\n");
    break;
  default:
    printf("Is this Yes or No?\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rop3_106_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_106_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk1 = *D ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_106_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  and    %esi,%edx
  xor    (%rdi),%dl
  mov    %eax,%ecx
  not    %ecx
  and    %ecx,%edx
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_106_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk1 = *D ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_106_1_1>:
  endbr64
  mov    %edx,%eax
  and    %esi,%edx
  xor    (%rdi),%dl
  or     %esi,%eax
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_106_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk1 = *D ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rop3_106_1_1>:
  endbr64
  mov    %edx,%eax
  and    %esi,%edx
  xor    (%rdi),%dl
  or     %esi,%eax
  mov    %eax,%ecx
  and    (%rdi),%al
  not    %ecx
  and    %ecx,%edx
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_106_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk1 = *D ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L3
  mov    $0x1,%eax
  jmp    L14
L3:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int add_ok(int x, int y) {
  int sum = x + y;
  return (sum - x == y) && (sum - y == x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_ok>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_ok(int x, int y) {
  int sum = x + y;
  return (sum - x == y) && (sum - y == x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add_ok>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_ok(int x, int y) {
  int sum = x + y;
  return (sum - x == y) && (sum - y == x);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add_ok>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int add_ok(int x, int y) {
  int sum = x + y;
  return (sum - x == y) && (sum - y == x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VecAdd3fv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void VecAdd3fv(float v[3], const int a[3], const int b[3]) {
  v[0] = ((float)(a[0])) + ((float)(b[0]));
  v[1] = ((float)(a[1])) + ((float)(b[1]));
  v[2] = ((float)(a[2])) + ((float)(b[2]));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<VecAdd3fv>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rsi),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x4(%rsi),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x8(%rsi),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void VecAdd3fv(float v[3], const int a[3], const int b[3]) {
  v[0] = ((float)(a[0])) + ((float)(b[0]));
  v[1] = ((float)(a[1])) + ((float)(b[1]));
  v[2] = ((float)(a[2])) + ((float)(b[2]));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VecAdd3fv>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rdx),%xmm1
  cvtsi2ssl (%rsi),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x4(%rdx),%xmm1
  movss  %xmm0,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x4(%rsi),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rdx),%xmm1
  movss  %xmm0,0x4(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x8(%rsi),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void VecAdd3fv(float v[3], const int a[3], const int b[3]) {
  v[0] = ((float)(a[0])) + ((float)(b[0]));
  v[1] = ((float)(a[1])) + ((float)(b[1]));
  v[2] = ((float)(a[2])) + ((float)(b[2]));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VecAdd3fv>:
  endbr64
  movq   (%rsi),%xmm0
  movq   (%rdx),%xmm1
  cvtdq2ps %xmm0,%xmm0
  cvtdq2ps %xmm1,%xmm1
  addps  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rdx),%xmm1
  movlps %xmm0,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x8(%rsi),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void VecAdd3fv(float v[3], const int a[3], const int b[3]) {
  v[0] = ((float)(a[0])) + ((float)(b[0]));
  v[1] = ((float)(a[1])) + ((float)(b[1]));
  v[2] = ((float)(a[2])) + ((float)(b[2]));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<learnFrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L15
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reportError@plt>
  mov    $0xffffffea,%eax
  jmp    L1
L15:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  if (b < 0) {
    reportError(&s);
    return -22;
  }
  return b + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<learnFrom>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <fstat@plt>
  test   %eax,%eax
  js     L12
  add    $0x1,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L12:
  lea    0x4(%rsp),%rdi
  call   <reportError@plt>
  mov    $0xffffffea,%eax
  jmp    L17
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  if (b < 0) {
    reportError(&s);
    return -22;
  }
  return b + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<learnFrom>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <fstat@plt>
  test   %eax,%eax
  js     L15
  add    $0x1,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbp
  ret
L15:
  mov    %rbp,%rdi
  call   <reportError@plt>
  mov    $0xffffffea,%eax
  jmp    L25
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  if (b < 0) {
    reportError(&s);
    return -22;
  }
  return b + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<learnFrom>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <fstat@plt>
  test   %eax,%eax
  js     L24
  add    $0x1,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbp
  ret
L24:
  mov    %rbp,%rdi
  call   <reportError@plt>
  mov    $0xffffffea,%eax
  jmp    L27
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int learnFrom(int fd) {
  struct stat s;
  int b = fstat(fd, &s);
  if (b < 0) {
    reportError(&s);
    return -22;
  }
  return b + 1;
}
```