ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipwhitespace>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  ja     L21
  movabs $0xfffffffeffffd9ff,%rcx
  nopl   0x0(%rax)
L19:
  bt     %rdx,%rcx
  jb     L21
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jbe    L19
L21:
  ret
```

assistant: ```c
char *skipwhitespace(char *str) {
  while (*str == ' ' || *str == '\t' || *str == '\n' || *str == '\r')
    str++;
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quicktime_copy_char32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void quicktime_copy_char32(char *output, char *input) {
  *output++ = *input++;
  *output++ = *input++;
  *output++ = *input++;
  *output = *input;
}
```
user: What is the c source code of the assembly code below?

```asm
<quicktime_copy_char32>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  movzbl 0x1(%rsi),%eax
  mov    %al,0x1(%rdi)
  movzbl 0x2(%rsi),%eax
  mov    %al,0x2(%rdi)
  movzbl 0x3(%rsi),%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void quicktime_copy_char32(char *output, char *input) {
  *output++ = *input++;
  *output++ = *input++;
  *output++ = *input++;
  *output = *input;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quicktime_copy_char32>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  movzbl 0x1(%rsi),%eax
  mov    %al,0x1(%rdi)
  movzbl 0x2(%rsi),%eax
  mov    %al,0x2(%rdi)
  movzbl 0x3(%rsi),%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void quicktime_copy_char32(char *output, char *input) {
  *output++ = *input++;
  *output++ = *input++;
  *output++ = *input++;
  *output = *input;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicktime_copy_char32>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  movzbl 0x1(%rsi),%eax
  mov    %al,0x1(%rdi)
  movzbl 0x2(%rsi),%eax
  mov    %al,0x2(%rdi)
  movzbl 0x3(%rsi),%eax
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void quicktime_copy_char32(char *output, char *input) {
  *output++ = *input++;
  *output++ = *input++;
  *output++ = *input++;
  *output = *input;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AdpcmBlockMashI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L14:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L14
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%r10
  mov    -0x30(%rbp),%r8
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    -0xc(%rbp),%eax
  sub    $0x8,%rsp
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %r8,%r9
  mov    %r10,%r8
  mov    %eax,%edi
  call   <AdpcmMashChannel@plt>
  add    $0x10,%rsp
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void AdpcmBlockMashI(int chans, const short *ip, int n, int *st, unsigned char *obuff, int blockAlign, int opt) {
  int ch;
  unsigned char *p;
  for (p = obuff + 7 * chans; p < obuff + blockAlign; p++)
    *p = 0;
  for (ch = 0; ch < chans; ch++)
    AdpcmMashChannel(ch, chans, ip, n, st + ch, obuff, opt);
}
```
user: What is the c source code of the assembly code below?

```asm
<AdpcmBlockMashI>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r14d
  mov    %rcx,%rbp
  mov    %r8,%r13
  mov    0x50(%rsp),%r15d
  lea    0x0(,%rdi,8),%eax
  sub    %edi,%eax
  cltq
  add    %r8,%rax
  movslq %r9d,%r9
  add    %r8,%r9
  cmp    %r9,%rax
  jae    L19
L16:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L16
L19:
  test   %r12d,%r12d
  jle    L14
  mov    $0x0,%ebx
L1:
  sub    $0x8,%rsp
  push   %r15
  mov    %r13,%r9
  mov    %rbp,%r8
  mov    %r14d,%ecx
  mov    0x18(%rsp),%rdx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <AdpcmMashChannel@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  add    $0x10,%rsp
  cmp    %ebx,%r12d
  jne    L1
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AdpcmBlockMashI(int chans, const short *ip, int n, int *st, unsigned char *obuff, int blockAlign, int opt) {
  int ch;
  unsigned char *p;
  for (p = obuff + 7 * chans; p < obuff + blockAlign; p++)
    *p = 0;
  for (ch = 0; ch < chans; ch++)
    AdpcmMashChannel(ch, chans, ip, n, st + ch, obuff, opt);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AdpcmBlockMashI>:
  endbr64
  lea    0x0(,%rdi,8),%eax
  push   %r15
  mov    %edi,%r15d
  push   %r14
  sub    %edi,%eax
  mov    %edx,%r14d
  movslq %r9d,%rdx
  push   %r13
  cltq
  mov    %rsi,%r13
  push   %r12
  lea    (%r8,%rax,1),%rdi
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  lea    (%r8,%rdx,1),%rcx
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rcx,%rdi
  jae    L13
  sub    %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L13:
  test   %r15d,%r15d
  jle    L26
  xor    %ebx,%ebx
  nopl   (%rax)
L20:
  sub    $0x8,%rsp
  mov    %rbp,%r8
  mov    %r13,%rdx
  mov    %ebx,%edi
  mov    0x48(%rsp),%eax
  mov    %r12,%r9
  mov    %r14d,%ecx
  mov    %r15d,%esi
  add    $0x1,%ebx
  add    $0x4,%rbp
  push   %rax
  call   <AdpcmMashChannel@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,%r15d
  jne    L20
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AdpcmBlockMashI(int chans, const short *ip, int n, int *st, unsigned char *obuff, int blockAlign, int opt) {
  int ch;
  unsigned char *p;
  for (p = obuff + 7 * chans; p < obuff + blockAlign; p++)
    *p = 0;
  for (ch = 0; ch < chans; ch++)
    AdpcmMashChannel(ch, chans, ip, n, st + ch, obuff, opt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AdpcmBlockMashI>:
  endbr64
  lea    0x0(,%rdi,8),%eax
  push   %r15
  mov    %edi,%r15d
  push   %r14
  sub    %edi,%eax
  mov    %edx,%r14d
  movslq %r9d,%rdx
  push   %r13
  cltq
  mov    %rsi,%r13
  push   %r12
  lea    (%r8,%rax,1),%rdi
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  lea    (%r8,%rdx,1),%rcx
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rcx,%rdi
  jae    L9
  sub    %rax,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L9:
  test   %r15d,%r15d
  jle    L4
  xor    %ebx,%ebx
  nopl   (%rax)
L23:
  sub    $0x8,%rsp
  mov    %rbp,%r8
  mov    %r13,%rdx
  mov    %ebx,%edi
  mov    0x48(%rsp),%eax
  mov    %r12,%r9
  mov    %r14d,%ecx
  mov    %r15d,%esi
  add    $0x1,%ebx
  add    $0x4,%rbp
  push   %rax
  call   <AdpcmMashChannel@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,%r15d
  jne    L23
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AdpcmBlockMashI(int chans, const short *ip, int n, int *st, unsigned char *obuff, int blockAlign, int opt) {
  int ch;
  unsigned char *p;
  for (p = obuff + 7 * chans; p < obuff + blockAlign; p++)
    *p = 0;
  for (ch = 0; ch < chans; ch++)
    AdpcmMashChannel(ch, chans, ip, n, st + ch, obuff, opt);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Enter@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %s

assistant: ```c
void main(int argc, char *argv) {
  printf("%s", (char *)argv[0]);
  Enter();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbq (%rsi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Enter@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: %s

assistant: ```c
void main(int argc, char *argv) {
  printf("%s", (char *)argv[0]);
  Enter();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbq (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <Enter@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: %s

assistant: ```c
void main(int argc, char *argv) {
  printf("%s", (char *)argv[0]);
  Enter();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbq (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <Enter@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: %s

assistant: ```c
void main(int argc, char *argv) {
  printf("%s", (char *)argv[0]);
  Enter();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<genGuard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L9
L12:
  cmpb   $0x2e,-0x1(%rbp)
  jne    L16
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x5f,(%rax)
  jmp    L9
L16:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L12
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void genGuard(char *filename, char *guard) {
  char c;
  while ((c = *filename++)) {
    if (c == '.')
      *guard++ = '_';
    else
      *guard++ = toupper(c);
  }
  *guard = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<genGuard>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L30
  lea    0x1(%rsi),%rbx
  mov    $0x5f,%r12d
  jmp    L23
L28:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %rbx,%rsi
L35:
  mov    %al,-0x1(%rbx)
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L30
L23:
  cmp    $0x2e,%dil
  jne    L28
  mov    %rbx,%rsi
  mov    %r12d,%eax
  jmp    L35
L30:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void genGuard(char *filename, char *guard) {
  char c;
  while ((c = *filename++)) {
    if (c == '.')
      *guard++ = '_';
    else
      *guard++ = toupper(c);
  }
  *guard = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<genGuard>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  nopl   0x0(%rax)
L26:
  add    $0x1,%rbx
  mov    $0x5f,%eax
  cmp    $0x2e,%dil
  je     L25
  call   <toupper@plt>
L25:
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx)
  movsbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L26
L6:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void genGuard(char *filename, char *guard) {
  char c;
  while ((c = *filename++)) {
    if (c == '.')
      *guard++ = '_';
    else
      *guard++ = toupper(c);
  }
  *guard = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<genGuard>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  nopl   0x0(%rax)
L39:
  add    $0x1,%rbx
  cmp    $0x2e,%dil
  je     L5
  call   <toupper@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbx)
  movsbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L39
L33:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  add    $0x1,%rbp
  movb   $0x5f,-0x1(%rbx)
  movsbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L39
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void genGuard(char *filename, char *guard) {
  char c;
  while ((c = *filename++)) {
    if (c == '.')
      *guard++ = '_';
    else
      *guard++ = toupper(c);
  }
  *guard = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iowTouchByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x2(%rbp)
  jmp    L2
L16:
  movzbl -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edi
  call   <iowTouchBit@plt>
  movzbl %al,%edx
  movzbl -0x2(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x1(%rbp)
  shrb   -0x14(%rbp)
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L2:
  cmpb   $0x7,-0x2(%rbp)
  jbe    L16
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char iowTouchByte(unsigned char sendbyte) {
  unsigned char i;
  unsigned char result = 0;
  for (i = 0; i < 8; i++) {
    result |= (iowTouchBit(sendbyte & 1) << i);
    sendbyte >>= 1;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iowTouchByte>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
L8:
  mov    %ebp,%edi
  and    $0x1,%edi
  call   <iowTouchBit@plt>
  movzbl %al,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%r12d
  shr    %bpl
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char iowTouchByte(unsigned char sendbyte) {
  unsigned char i;
  unsigned char result = 0;
  for (i = 0; i < 8; i++) {
    result |= (iowTouchBit(sendbyte & 1) << i);
    sendbyte >>= 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<iowTouchByte>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nop
L6:
  mov    %ebp,%edi
  shr    %bpl
  and    $0x1,%edi
  call   <iowTouchBit@plt>
  mov    %ebx,%ecx
  add    $0x1,%ebx
  movzbl %al,%eax
  shl    %cl,%eax
  or     %eax,%r12d
  cmp    $0x8,%ebx
  jne    L6
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char iowTouchByte(unsigned char sendbyte) {
  unsigned char i;
  unsigned char result = 0;
  for (i = 0; i < 8; i++) {
    result |= (iowTouchBit(sendbyte & 1) << i);
    sendbyte >>= 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iowTouchByte>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nop
L7:
  mov    %ebp,%edi
  shr    %bpl
  and    $0x1,%edi
  call   <iowTouchBit@plt>
  mov    %ebx,%ecx
  add    $0x1,%ebx
  movzbl %al,%eax
  shl    %cl,%eax
  or     %eax,%r12d
  cmp    $0x8,%ebx
  jne    L7
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char iowTouchByte(unsigned char sendbyte) {
  unsigned char i;
  unsigned char result = 0;
  for (i = 0; i < 8; i++) {
    result |= (iowTouchBit(sendbyte & 1) << i);
    sendbyte >>= 1;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_ends_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L28
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x1,%eax
  jmp    L18
L28:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int string_ends_with(const char *s, const char *suffix) {
  int sLength = strlen(s);
  int suffixLength = strlen(suffix);
  return (sLength >= suffixLength) && (strcmp(s + (sLength - suffixLength), suffix) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_ends_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%ebx
  jge    L18
L4:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  sub    %eax,%ebx
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L4
```

assistant: ```c
int string_ends_with(const char *s, const char *suffix) {
  int sLength = strlen(s);
  int suffixLength = strlen(suffix);
  return (sLength >= suffixLength) && (strcmp(s + (sLength - suffixLength), suffix) == 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_ends_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jge    L9
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  sub    %eax,%ebx
  mov    %r12,%rsi
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_ends_with(const char *s, const char *suffix) {
  int sLength = strlen(s);
  int suffixLength = strlen(suffix);
  return (sLength >= suffixLength) && (strcmp(s + (sLength - suffixLength), suffix) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_ends_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jge    L6
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  sub    %eax,%ebx
  mov    %r12,%rsi
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_ends_with(const char *s, const char *suffix) {
  int sLength = strlen(s);
  int suffixLength = strlen(suffix);
  return (sLength >= suffixLength) && (strcmp(s + (sLength - suffixLength), suffix) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *get_date() {
  time_t rawtime;
  struct tm *timeinfo;
  char *timechar;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  timechar = asctime(timeinfo);
  timechar[strlen(timechar) - 1] = 0;
  return timechar;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_date>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_date() {
  time_t rawtime;
  struct tm *timeinfo;
  char *timechar;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  timechar = asctime(timeinfo);
  timechar[strlen(timechar) - 1] = 0;
  return timechar;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_date>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_date() {
  time_t rawtime;
  struct tm *timeinfo;
  char *timechar;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  timechar = asctime(timeinfo);
  timechar[strlen(timechar) - 1] = 0;
  return timechar;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_date>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *get_date() {
  time_t rawtime;
  struct tm *timeinfo;
  char *timechar;
  time(&rawtime);
  timeinfo = localtime(&rawtime);
  timechar = asctime(timeinfo);
  timechar[strlen(timechar) - 1] = 0;
  return timechar;
}
```