ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_string>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rdx),%eax
  xor    %ebx,%ebx
  lea    -0x1(%rax),%esi
  test   %esi,%esi
  jg     L112
  jmp    L143
  xchg   %ax,%ax
L9:
  mov    %rcx,(%rdi)
  movzbl (%rdx),%eax
  add    $0x1,%ebx
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
L7:
  cmp    %esi,%ebx
  jge    L148
L112:
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L10
  cmp    $0x3a,%al
  jne    L14
  test   $0x1,%r8b
  je     L10
L14:
  lea    0x1(%rdx),%rcx
  cmp    $0x22,%al
  je     L72
  cmp    $0x5c,%al
  jne    L9
  mov    %rcx,(%rdi)
  cmpb   $0x0,0x1(%rdx)
  je     L10
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L115:
  sub    $0x1,%r12
  sub    $0x1,%ebx
  je     L41
L148:
  movzbl -0x1(%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L115
L143:
  movb   $0x0,(%r12)
  mov    %r12,%rax
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L72:
  mov    %rcx,(%rdi)
  xor    $0x1,%r8d
  jmp    L7
  nopl   0x0(%rax)
L10:
  test   %ebx,%ebx
  jne    L148
  jmp    L143
  cs nopw 0x0(%rax,%rax,1)
L41:
  xor    %ebx,%ebx
  movb   $0x0,(%r12)
  mov    %r12,%rax
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_string(char **src, char *dest, unsigned int *length) {
  int n, len, quoteflag;
  quoteflag = 0;
  n = 0;
  len = *length - 1;
  while ((n < len) && (**src)) {
    if (!quoteflag && (**src == ':')) {
      break;
    }
    if (**src == '"') {
      (*src)++;
      quoteflag = !quoteflag;
      continue;
    }
    if (**src == '\\') {
      (*src)++;
      if (!**src) {
        break;
      }
    }
    *dest++ = *(*src)++;
    n++;
  }
  while ((n > 0) && isspace((unsigned char)dest[-1])) {
    dest--;
    n--;
  }
  *dest = '\0';
  *length = n;
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L28
  addl   $0x1,-0x4(%rbp)
L28:
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int count_digits(char *s) {
  int count = 0;
  while (*s) {
    if (isdigit(*s))
      count++;
    s++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count_digits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L8
  mov    $0x0,%ebp
L22:
  movsbl %dil,%edi
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L22
L25:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%ebp
  jmp    L25
```

assistant: ```c
int count_digits(char *s) {
  int count = 0;
  while (*s) {
    if (isdigit(*s))
      count++;
    s++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
  nopl   0x0(%rax)
L1:
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int count_digits(char *s) {
  int count = 0;
  while (*s) {
    if (isdigit(*s))
      count++;
    s++;
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<count_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
  nopl   0x0(%rax)
L14:
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L14
L19:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int count_digits(char *s) {
  int count = 0;
  while (*s) {
    if (isdigit(*s))
      count++;
    s++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: Result: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Result: %d\n", 1 / atoi(argv[1]));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: Result: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Result: %d\n", 1 / atoi(argv[1]));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: Result: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Result: %d\n", 1 / atoi(argv[1]));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: Result: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Result: %d\n", 1 / atoi(argv[1]));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xac(%rbp)
  movl   $0x0,-0xa8(%rbp)
  movl   $0x0,-0xa4(%rbp)
  jmp    L100
L98:
  mov    $0x0,%eax
  call   <getche@plt>
  mov    %al,-0xad(%rbp)
  mov    -0xa8(%rbp),%eax
  cltq
  movzbl -0xad(%rbp),%edx
  mov    %dl,-0xa0(%rbp,%rax,1)
  cmpb   $0x50,-0xad(%rbp)
  jne    L31
  mov    -0xa8(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  jne    L31
  mov    -0xa8(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  cmp    $0x54,%al
  jne    L31
  mov    -0xa8(%rbp),%eax
  sub    $0x3,%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  cmp    $0x53,%al
  jne    L31
  movl   $0x1,-0xac(%rbp)
L31:
  addl   $0x1,-0xa8(%rbp)
L100:
  cmpl   $0x1,-0xac(%rbp)
  jne    L98
  movl   $0x0,-0xa8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x4,%eax
  mov    %eax,-0xa4(%rbp)
  jmp    L53
L56:
  mov    -0xa8(%rbp),%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L79
  mov    -0xa8(%rbp),%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L79
  mov    -0xa8(%rbp),%eax
  cltq
  movzbl -0xa0(%rbp,%rax,1),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0xa8(%rbp),%eax
  cltq
  mov    %dl,-0xa0(%rbp,%rax,1)
L79:
  addl   $0x1,-0xa8(%rbp)
L53:
  mov    -0xa8(%rbp),%eax
  cmp    -0xa4(%rbp),%eax
  jl     L56
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: %s

assistant: ```c
int main() {
  int a = 0, i = 0, basi = 0;
  char c, b[150];
  while (a != 1) {
    c = getche();
    b[i] = c;
    if (c == 'P') {
      if (b[i - 1] == 'O' && b[i - 2] == 'T' && b[i - 3] == 'S')
        a = 1;
    }
    i++;
  }
  i = 0;
  printf("\n");
  basi = strlen(b) - 4;
  while (i < basi) {
    if (b[i] >= 97 && b[i] <= 122)
      b[i] = b[i] - 32;
    i++;
  }
  printf("%s", b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rbp
  jmp    L45
L1:
  add    $0x1,%rbp
L45:
  mov    $0x0,%eax
  call   <getche@plt>
  mov    %al,0x0(%rbp)
  cmp    $0x50,%al
  jne    L1
  cmpb   $0x4f,-0x1(%rbp)
  jne    L1
  cmpb   $0x54,-0x2(%rbp)
  jne    L1
  cmpb   $0x53,-0x3(%rbp)
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  call   <strlen@plt>
  lea    -0x5(%rax),%edx
  lea    0x1(%rbx,%rdx,1),%rcx
  cmp    $0x4,%eax
  jg     L39
L37:
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L63:
  add    $0x1,%rbx
  cmp    %rbx,%rcx
  je     L37
L39:
  movzbl (%rbx),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L63
  sub    $0x20,%eax
  mov    %al,(%rbx)
  jmp    L63
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: %s

assistant: ```c
int main() {
  int a = 0, i = 0, basi = 0;
  char c, b[150];
  while (a != 1) {
    c = getche();
    b[i] = c;
    if (c == 'P') {
      if (b[i - 1] == 'O' && b[i - 2] == 'T' && b[i - 3] == 'S')
        a = 1;
    }
    i++;
  }
  i = 0;
  printf("\n");
  basi = strlen(b) - 4;
  while (i < basi) {
    if (b[i] >= 97 && b[i] <= 122)
      b[i] = b[i] - 32;
    i++;
  }
  printf("%s", b);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
  mov    %rbp,%rbx
  jmp    L19
  nopl   (%rax)
L25:
  add    $0x1,%rbx
L19:
  xor    %eax,%eax
  call   <getche@plt>
  mov    %al,(%rbx)
  cmp    $0x50,%al
  jne    L25
  cmpb   $0x4f,-0x1(%rbx)
  jne    L25
  cmpb   $0x54,-0x2(%rbx)
  jne    L25
  cmpb   $0x53,-0x3(%rbx)
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jle    L59
  lea    -0x5(%rax),%esi
  lea    0x1(%rbp),%rax
  add    %rax,%rsi
  jmp    L61
  cs nopw 0x0(%rax,%rax,1)
L49:
  add    $0x1,%rax
L61:
  movzbl (%r12),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L35
  sub    $0x20,%edx
  mov    %dl,(%r12)
L35:
  mov    %rax,%r12
  cmp    %rax,%rsi
  jne    L49
L59:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: %s

assistant: ```c
int main() {
  int a = 0, i = 0, basi = 0;
  char c, b[150];
  while (a != 1) {
    c = getche();
    b[i] = c;
    if (c == 'P') {
      if (b[i - 1] == 'O' && b[i - 2] == 'T' && b[i - 3] == 'S')
        a = 1;
    }
    i++;
  }
  i = 0;
  printf("\n");
  basi = strlen(b) - 4;
  while (i < basi) {
    if (b[i] >= 97 && b[i] <= 122)
      b[i] = b[i] - 32;
    i++;
  }
  printf("%s", b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r12
  mov    %rbp,%rbx
  jmp    L57
  nopl   (%rax)
L95:
  add    $0x1,%rbx
L57:
  xor    %eax,%eax
  call   <getche@plt>
  mov    %al,(%rbx)
  cmp    $0x50,%al
  jne    L95
  cmpb   $0x4f,-0x1(%rbx)
  jne    L95
  cmpb   $0x54,-0x2(%rbx)
  jne    L95
  cmpb   $0x53,-0x3(%rbx)
  jne    L95
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jle    L76
  lea    -0x5(%rax),%esi
  lea    0x1(%rbp),%rax
  add    %rax,%rsi
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L69:
  add    $0x1,%rax
L24:
  movzbl (%r12),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L10
  sub    $0x20,%edx
  mov    %dl,(%r12)
L10:
  mov    %rax,%r12
  cmp    %rax,%rsi
  jne    L69
L76:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xa0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %s

assistant: ```c
int main() {
  int a = 0, i = 0, basi = 0;
  char c, b[150];
  while (a != 1) {
    c = getche();
    b[i] = c;
    if (c == 'P') {
      if (b[i - 1] == 'O' && b[i - 2] == 'T' && b[i - 3] == 'S')
        a = 1;
    }
    i++;
  }
  i = 0;
  printf("\n");
  basi = strlen(b) - 4;
  while (i < basi) {
    if (b[i] >= 97 && b[i] <= 122)
      b[i] = b[i] - 32;
    i++;
  }
  printf("%s", b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<integerMultipleIndices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L21
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L21:
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int integerMultipleIndices(int length, int a[], int divisor, int indices[]) {
  int i, count = 0;
  for (i = 0; i < length; i += 1)
    if (a[i] % divisor == 0) {
      indices[count] = i;
      count += 1;
    }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<integerMultipleIndices>:
  endbr64
  mov    %edx,%r9d
  test   %edi,%edi
  jle    L13
  mov    %edi,%edi
  mov    $0x0,%r8d
  mov    $0x0,%r10d
  jmp    L36
L31:
  add    $0x1,%r8
  cmp    %rdi,%r8
  je     L32
L36:
  mov    (%rsi,%r8,4),%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L31
  movslq %r10d,%rax
  mov    %r8d,(%rcx,%rax,4)
  add    $0x1,%r10d
  jmp    L31
L13:
  mov    $0x0,%r10d
L32:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int integerMultipleIndices(int length, int a[], int divisor, int indices[]) {
  int i, count = 0;
  for (i = 0; i < length; i += 1)
    if (a[i] % divisor == 0) {
      indices[count] = i;
      count += 1;
    }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<integerMultipleIndices>:
  endbr64
  mov    %edx,%r9d
  test   %edi,%edi
  jle    L25
  movslq %edi,%rdi
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L8:
  mov    (%rsi,%r8,4),%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L16
  movslq %r10d,%rax
  add    $0x1,%r10d
  mov    %r8d,(%rcx,%rax,4)
L16:
  add    $0x1,%r8
  cmp    %rdi,%r8
  jne    L8
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L25:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int integerMultipleIndices(int length, int a[], int divisor, int indices[]) {
  int i, count = 0;
  for (i = 0; i < length; i += 1)
    if (a[i] % divisor == 0) {
      indices[count] = i;
      count += 1;
    }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<integerMultipleIndices>:
  endbr64
  mov    %edx,%r9d
  test   %edi,%edi
  jle    L4
  movslq %edi,%rdi
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L0:
  mov    (%rsi,%r8,4),%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L25
  movslq %r10d,%rax
  add    $0x1,%r10d
  mov    %r8d,(%rcx,%rax,4)
L25:
  add    $0x1,%r8
  cmp    %r8,%rdi
  jne    L0
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int integerMultipleIndices(int length, int a[], int divisor, int indices[]) {
  int i, count = 0;
  for (i = 0; i < length; i += 1)
    if (a[i] % divisor == 0) {
      indices[count] = i;
      count += 1;
    }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yowl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vyowl@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: 

assistant: ```c
void yowl(const char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vyowl(fmt, "", v);
  va_end(v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yowl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <vyowl@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: 

assistant: ```c
void yowl(const char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vyowl(fmt, "", v);
  va_end(v);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<yowl>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <vyowl@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: 

assistant: ```c
void yowl(const char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vyowl(fmt, "", v);
  va_end(v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yowl>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <vyowl@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: 

assistant: ```c
void yowl(const char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vyowl(fmt, "", v);
  va_end(v);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D14
type: string

tool: D16: %s: %s


tool: D14: %s: not in environment


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *val;
  for (i = 1; i < argc; i++) {
    if ((val = getenv(argv[i])) != NULL)
      printf("%s: %s\n", argv[i], val);
    else
      printf("%s: not in environment\n", argv[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L21
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D15(%rip),%r13
  lea    D12(%rip),%r12
  jmp    L7
L29:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L23
L7:
  mov    (%rbx),%rdi
  call   <getenv@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  jne    L29
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L23:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  mov    $0x0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type: string
name: unpack_data
arguments: tag: D12
type: string

tool: D15: %s: not in environment


tool: D12: %s: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *val;
  for (i = 1; i < argc; i++) {
    if ((val = getenv(argv[i])) != NULL)
      printf("%s: %s\n", argv[i], val);
    else
      printf("%s: not in environment\n", argv[i]);
  }
}
```