ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0xa,%edi
  call   <add@plt>
  mov    $0x14,%edi
  call   <add@plt>
  mov    $0x1e,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <front@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <is_empty@plt>
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <size@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L9:
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  call   <is_empty@plt>
  test   %eax,%eax
  je     L9
  mov    $0x0,%eax
  call   <destroy_single_link@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D21
datatype: string
name: disassemble_data
arguments: label: D43
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D30
datatype: string

tool: D21: tmp=%d


tool: D43: is_empty()=%d


tool: D17: size()=%d


tool: D30: %d


assistant: ```c
void main() {
  int tmp = 0;
  add(10);
  add(20);
  add(30);
  tmp = pop();
  printf("tmp=%d\n", tmp);
  tmp = front();
  printf("tmp=%d\n", tmp);
  add(40);
  printf("is_empty()=%d\n", is_empty());
  printf("size()=%d\n", size());
  while (!is_empty()) {
    printf("%d\n", pop());
  }
  destroy_single_link();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <add@plt>
  mov    $0x14,%edi
  call   <add@plt>
  mov    $0x1e,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <front@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <add@plt>
  mov    $0x0,%eax
  call   <is_empty@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <size@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rbx
  jmp    L4
L9:
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  call   <is_empty@plt>
  test   %eax,%eax
  je     L9
  mov    $0x0,%eax
  call   <destroy_single_link@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D38
data_type: string
name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D0
data_type: string

tool: D38: tmp=%d


tool: D21: is_empty()=%d


tool: D3: size()=%d


tool: D0: %d


assistant: ```c
void main() {
  int tmp = 0;
  add(10);
  add(20);
  add(30);
  tmp = pop();
  printf("tmp=%d\n", tmp);
  tmp = front();
  printf("tmp=%d\n", tmp);
  add(40);
  printf("is_empty()=%d\n", is_empty());
  printf("size()=%d\n", size());
  while (!is_empty()) {
    printf("%d\n", pop());
  }
  destroy_single_link();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D17(%rip),%rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x8,%rsp
  call   <add@plt>
  mov    $0x14,%edi
  call   <add@plt>
  mov    $0x1e,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <pop@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <front@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <is_empty@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <size@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L11
  xchg   %ax,%ax
L3:
  call   <pop@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L11:
  xor    %eax,%eax
  call   <is_empty@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  je     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1110 <destroy_single_link@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D27
type: string

tool: D17: tmp=%d


tool: D5: %d


tool: D33: is_empty()=%d


tool: D27: size()=%d


assistant: ```c
void main() {
  int tmp = 0;
  add(10);
  add(20);
  add(30);
  tmp = pop();
  printf("tmp=%d\n", tmp);
  tmp = front();
  printf("tmp=%d\n", tmp);
  add(40);
  printf("is_empty()=%d\n", is_empty());
  printf("size()=%d\n", size());
  while (!is_empty()) {
    printf("%d\n", pop());
  }
  destroy_single_link();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D16(%rip),%rbp
  push   %rbx
  lea    D10(%rip),%rbx
  sub    $0x8,%rsp
  call   <add@plt>
  mov    $0x14,%edi
  call   <add@plt>
  mov    $0x1e,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <pop@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <front@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <add@plt>
  xor    %eax,%eax
  call   <is_empty@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <size@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L1
  xchg   %ax,%ax
L12:
  call   <pop@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L1:
  xor    %eax,%eax
  call   <is_empty@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  je     L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1110 <destroy_single_link@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D16: tmp=%d


tool: D10: %d


tool: D7: is_empty()=%d


tool: D18: size()=%d


assistant: ```c
void main() {
  int tmp = 0;
  add(10);
  add(20);
  add(30);
  tmp = pop();
  printf("tmp=%d\n", tmp);
  tmp = front();
  printf("tmp=%d\n", tmp);
  add(40);
  printf("is_empty()=%d\n", is_empty());
  printf("size()=%d\n", size());
  while (!is_empty()) {
    printf("%d\n", pop());
  }
  destroy_single_link();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ab_equals_ba>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L43
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <a_contains_b@plt>
  test   %rax,%rax
  je     L41
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <a_contains_b@plt>
  test   %rax,%rax
  je     L41
  mov    $0x1,%eax
  jmp    L16
L41:
  mov    $0x0,%eax
  jmp    L16
L43:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int ab_equals_ba(int *a, int n, int *b, int m) {
  if (m == n) {
    if ((a_contains_b(a, n, b, m)) && (a_contains_b(b, m, a, n))) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ab_equals_ba>:
  endbr64
  mov    $0x0,%eax
  cmp    %esi,%ecx
  je     L25
  ret
L25:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %ecx,%ebx
  call   <a_contains_b@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L5
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <a_contains_b@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L13
```

assistant: ```c
int ab_equals_ba(int *a, int n, int *b, int m) {
  if (m == n) {
    if ((a_contains_b(a, n, b, m)) && (a_contains_b(b, m, a, n))) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ab_equals_ba>:
  endbr64
  cmp    %esi,%ecx
  je     L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  push   %r13
  mov    %ecx,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  call   <a_contains_b@plt>
  test   %rax,%rax
  jne    L18
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <a_contains_b@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ab_equals_ba(int *a, int n, int *b, int m) {
  if (m == n) {
    if ((a_contains_b(a, n, b, m)) && (a_contains_b(b, m, a, n))) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ab_equals_ba>:
  endbr64
  cmp    %esi,%ecx
  je     L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  push   %r13
  mov    %ecx,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  call   <a_contains_b@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <a_contains_b@plt>
  pop    %rbp
  pop    %r12
  test   %rax,%rax
  pop    %r13
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ab_equals_ba(int *a, int n, int *b, int m) {
  if (m == n) {
    if ((a_contains_b(a, n, b, m)) && (a_contains_b(b, m, a, n))) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<striptrail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L19
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L35
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x0,-0x8(%rbp)
  jns    L16
  jmp    L10
L35:
  nop
L10:
  leave
  ret
```

assistant: ```c
void striptrail(char *sss, char c) {
  int len, i;
  len = strlen(sss);
  for (i = len - 1; i >= 0; --i) {
    if (sss[i] != c)
      return;
    sss[i] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<striptrail>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L1
  mov    %eax,%ecx
  movslq %edx,%rdx
  add    %rbp,%rdx
  cltq
  lea    -0x2(%rbp,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
L2:
  cmp    %bl,(%rdx)
  jne    L1
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L2
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void striptrail(char *sss, char c) {
  int len, i;
  len = strlen(sss);
  for (i = len - 1; i >= 0; --i) {
    if (sss[i] != c)
      return;
    sss[i] = '\0';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<striptrail>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L21
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rax
  add    %rbp,%rdx
  sub    %rcx,%rax
  jmp    L23
  nop
L22:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L21
L23:
  cmp    %bl,(%rdx)
  je     L22
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void striptrail(char *sss, char c) {
  int len, i;
  len = strlen(sss);
  for (i = len - 1; i >= 0; --i) {
    if (sss[i] != c)
      return;
    sss[i] = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<striptrail>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L37
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rax
  add    %rbp,%rdx
  sub    %rcx,%rax
  jmp    L36
  nop
L28:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L37
L36:
  cmp    %bl,(%rdx)
  je     L28
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void striptrail(char *sss, char c) {
  int len, i;
  len = strlen(sss);
  for (i = len - 1; i >= 0; --i) {
    if (sss[i] != c)
      return;
    sss[i] = '\0';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<arrayf_rms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double arrayf_rms(float *a, int n) {
  int i;
  double sum;
  for (sum = i = 0; i < n; i++)
    sum += a[i] * a[i];
  return (sqrt(sum / n));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arrayf_rms>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L18:
  movss  (%rax),%xmm1
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
L31:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L25
  sqrtsd %xmm0,%xmm0
  ret
L24:
  pxor   %xmm0,%xmm0
  jmp    L31
L25:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double arrayf_rms(float *a, int n) {
  int i;
  double sum;
  for (sum = i = 0; i < n; i++)
    sum += a[i] * a[i];
  return (sqrt(sum / n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<arrayf_rms>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x4(%rdi,%rax,4),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L34:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L34
L3:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L12
  sqrtsd %xmm0,%xmm0
  ret
L9:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  jmp    L3
L12:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double arrayf_rms(float *a, int n) {
  int i;
  double sum;
  for (sum = i = 0; i < n; i++)
    sum += a[i] * a[i];
  return (sqrt(sum / n));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arrayf_rms>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x4(%rdi,%rax,4),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L33:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  mulss  %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L33
L25:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  ja     L10
  sqrtsd %xmm0,%xmm0
  ret
L20:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  jmp    L25
L10:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double arrayf_rms(float *a, int n) {
  int i;
  double sum;
  for (sum = i = 0; i < n; i++)
    sum += a[i] * a[i];
  return (sqrt(sum / n));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *where) {
  perror(where);
  _exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(const char *where) {
  perror(where);
  _exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void die(const char *where) {
  perror(where);
  _exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

assistant: ```c
void die(const char *where) {
  perror(where);
  _exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <readinput@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L68
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L68:
  cmpl   $0x1,-0x18(%rbp)
  jne    L77
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L77:
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L86
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L86:
  cmpl   $0xfffffffe,-0x18(%rbp)
  jne    L37
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L59
L37:
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L59:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D41
datatype: string
name: read_data
arguments: label: D48
datatype: string
name: read_data
arguments: label: D37
datatype: string
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D17
datatype: string

tool: D41: client says %s which means yes


tool: D48: client says %s which means no


tool: D37: can't translate client response %s


tool: D20: message length longer than 10 characters

tool: D17: abort: something is not right


assistant: ```c
main() {
  int x;
  char c[10];
  x = readinput(c);
  if (x == 0) {
    printf("client says %s which means yes\n", c);
  } else if (x == 1) {
    printf("client says %s which means no\n", c);
  } else if (x == -1) {
    printf("can't translate client response %s\n", c);
  } else if (x == -2) {
    printf("message length longer than 10 characters\n");
  } else {
    printf("abort: something is not right\n", c);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <readinput@plt>
  test   %eax,%eax
  je     L52
  cmp    $0x1,%eax
  je     L43
  cmp    $0xffffffff,%eax
  je     L22
  cmp    $0xfffffffe,%eax
  je     L16
  lea    0xe(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L52:
  lea    0xe(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L43:
  lea    0xe(%rsp),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L22:
  lea    0xe(%rsp),%rsi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L82
L16:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L82
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D44
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string

tool: D12: abort: something is not right


tool: D9: client says %s which means yes


tool: D23: client says %s which means no


tool: D44: can't translate client response %s


tool: D17: message length longer than 10 characters

assistant: ```c
main() {
  int x;
  char c[10];
  x = readinput(c);
  if (x == 0) {
    printf("client says %s which means yes\n", c);
  } else if (x == 1) {
    printf("client says %s which means no\n", c);
  } else if (x == -1) {
    printf("can't translate client response %s\n", c);
  } else if (x == -2) {
    printf("message length longer than 10 characters\n");
  } else {
    printf("abort: something is not right\n", c);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <readinput@plt>
  test   %eax,%eax
  je     L48
  cmp    $0x1,%eax
  je     L19
  cmp    $0xffffffff,%eax
  je     L22
  cmp    $0xfffffffe,%eax
  je     L42
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L48:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L22:
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L35
L42:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L35
L19:
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L35
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D39
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string

tool: D39: abort: something is not right


tool: D9: client says %s which means yes


tool: D15: can't translate client response %s


tool: D7: message length longer than 10 characters

tool: D27: client says %s which means no


assistant: ```c
main() {
  int x;
  char c[10];
  x = readinput(c);
  if (x == 0) {
    printf("client says %s which means yes\n", c);
  } else if (x == 1) {
    printf("client says %s which means no\n", c);
  } else if (x == -1) {
    printf("can't translate client response %s\n", c);
  } else if (x == -2) {
    printf("message length longer than 10 characters\n");
  } else {
    printf("abort: something is not right\n", c);
  }
}
```