user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  test   %ebx,%ebx
  jle    L22
  lea    0x1a0(%rsp),%r14
  xor    %ebp,%ebp
  lea    D22(%rip),%r13
  mov    %r14,%r12
  nopl   0x0(%rax)
L12:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  add    $0x4,%r12
  cmp    %ebp,%ebx
  jg     L12
  movslq 0xc(%rsp),%rbp
  cmp    %ebp,%ebx
  jle    L18
  test   %ebp,%ebp
  js     L72
  lea    0x10(%rsp),%rdi
  lea    0x4(,%rbp,4),%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
L72:
  mov    0x10(%rsp,%rbp,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  lea    0x10(%rsp),%rcx
  movslq %ebx,%r12
  test   %ebx,%ebx
  jle    L57
  mov    %rcx,%rdi
  lea    0x0(,%r12,4),%rdx
  mov    %r14,%rsi
  call   <memcpy@plt>
  mov    %rax,%rcx
L57:
  mov    %ebx,%eax
  mov    %ebx,%r10d
  mov    $0xfffffffffffffff0,%r8
  mov    %ebx,%esi
  shr    $0x2,%eax
  and    $0xfffffffc,%r10d
  lea    -0x10(%rcx,%r12,4),%rdi
  xor    %edx,%edx
  sub    $0x1,%eax
  lea    0x1(%rbp),%r9d
  lea    -0x1(%rbx),%r11d
  shl    $0x4,%rax
  lea    0x1(%r10),%r12d
  sub    %rax,%r8
  nopw   0x0(%rax,%rax,1)
L135:
  test   %ebx,%ebx
  jle    L142
  cmp    $0x2,%r11d
  jbe    L163
  lea    (%r8,%rdi,1),%rcx
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L137:
  movdqu (%rax),%xmm2
  sub    $0x10,%rax
  pshufd $0x1b,%xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L137
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  add    %eax,%edx
  mov    %r12d,%eax
  cmp    %ebx,%r10d
  je     L142
L2:
  mov    %esi,%ecx
  lea    0x1(%rax),%r14d
  sub    %eax,%ecx
  movslq %ecx,%rcx
  add    0x10(%rsp,%rcx,4),%edx
  cmp    %ebx,%r14d
  jg     L142
  mov    %esi,%ecx
  add    $0x2,%eax
  sub    %r14d,%ecx
  movslq %ecx,%rcx
  add    0x10(%rsp,%rcx,4),%edx
  cmp    %eax,%ebx
  jl     L142
  mov    %esi,%ecx
  sub    %eax,%ecx
  movslq %ecx,%rax
  add    0x10(%rsp,%rax,4),%edx
L142:
  add    $0x1,%esi
  mov    %edx,0x10(%rdi)
  add    $0x4,%rdi
  cmp    %r9d,%esi
  jne    L135
  jmp    L72
L163:
  mov    $0x1,%eax
  jmp    L2
L22:
  movslq 0xc(%rsp),%rbp
  lea    D22(%rip),%r13
  cmp    %ebp,%ebx
  jg     L72
  lea    0x10(%rsp),%rcx
  movslq %ebx,%r12
  jmp    L57
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D22
type_guessed: string

tool: D5: %d %d

tool: D22: %d

assistant: ```c
int main() {
  int sum = 0, d, N, a[100], b[100];
  scanf("%d %d", &d, &N);
  for (int i = 0; i < d; i++)
    scanf("%d", &b[i]);
  if (N < d) {
    for (int i = 0; i <= N; i++) {
      a[i] = b[i];
    }
    printf("%d", a[N]);
  } else {
    int i;
    for (i = 0; i < d; i++) {
      a[i] = b[i];
    }
    for (i = d; i <= N; i++) {
      for (int j = 1; j <= d; j++)
        sum = sum + a[i - j];
      a[i] = sum;
    }
    printf("%d", a[N]);
  }
  return 0;
}
```