user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x3e8000(%rsp),%r11
L108:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L108
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3e8028(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x3e801c(%rbp)
  movl   $0x0,-0x3e8018(%rbp)
  movl   $0x0,-0x3e8014(%rbp)
  jmp    L111
L132:
  mov    -0x3e8018(%rbp),%edx
  mov    -0x3e801c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3e8024(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3e8024(%rbp),%eax
  cmp    $0x1,%eax
  jne    L125
  lea    -0x3e8020(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3e801c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3e801c(%rbp)
  mov    -0x3e8020(%rbp),%edx
  cltq
  mov    %edx,-0x3e8010(%rbp,%rax,4)
  mov    -0x3e8020(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L125:
  mov    -0x3e8024(%rbp),%eax
  cmp    $0x2,%eax
  jne    L105
  cmpl   $0x0,-0x3e8018(%rbp)
  jne    L116
  jmp    L91
L21:
  subl   $0x1,-0x3e801c(%rbp)
  mov    -0x3e8018(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3e8018(%rbp)
  mov    -0x3e801c(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x3e8010(%rbp,%rdx,4),%edx
  cltq
  mov    %edx,-0x1f4010(%rbp,%rax,4)
L91:
  cmpl   $0x0,-0x3e801c(%rbp)
  jg     L21
L116:
  subl   $0x1,-0x3e8018(%rbp)
  jmp    L2
L105:
  cmpl   $0x0,-0x3e8018(%rbp)
  jne    L92
  jmp    L85
L99:
  subl   $0x1,-0x3e801c(%rbp)
  mov    -0x3e8018(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3e8018(%rbp)
  mov    -0x3e801c(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x3e8010(%rbp,%rdx,4),%edx
  cltq
  mov    %edx,-0x1f4010(%rbp,%rax,4)
L85:
  cmpl   $0x0,-0x3e801c(%rbp)
  jg     L99
L92:
  mov    -0x3e8018(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1f4010(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  addl   $0x1,-0x3e8014(%rbp)
L111:
  mov    -0x3e8028(%rbp),%eax
  cmp    %eax,-0x3e8014(%rbp)
  jl     L132
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D57
type_guessed: string

tool: D21: %d

tool: D20: INBOX_I = %d, OUTBOX_I = %d


tool: D15: ADDED = %d


tool: D57: %d


assistant: ```c
int main() {
  int q;
  scanf("%d", &q);
  int inbox[512000];
  int inbox_i = 0;
  int outbox[512000];
  int outbox_i = 0;
  for (int i = 0; i < q; i++) {
    printf("INBOX_I = %d, OUTBOX_I = %d\n", inbox_i, outbox_i);
    int action;
    scanf("%d", &action);
    if (action == 1) {
      int n;
      scanf("%d", &n);
      inbox[inbox_i++] = n;
      printf("ADDED = %d\n", n);
    } else if (action == 2) {
      if (outbox_i == 0)
        while (inbox_i > 0)
          outbox[outbox_i++] = inbox[--inbox_i];
      outbox_i--;
    } else {
      if (outbox_i == 0)
        while (inbox_i > 0)
          outbox[outbox_i++] = inbox[--inbox_i];
      printf("%d\n", outbox[outbox_i - 1]);
    }
  }
  return 0;
}
```