ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<outstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L19
L14:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <outchar@plt>
L19:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void outstring(const char *s, int len) {
  while (len--)
    outchar(*s++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outstring>:
  endbr64
  test   %esi,%esi
  je     L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L17:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <outchar@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void outstring(const char *s, int len) {
  while (len--)
    outchar(*s++);
}
```
user: What is the c source code of the assembly code below:

```asm
<outstring>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <outchar@plt>
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void outstring(const char *s, int len) {
  while (len--)
    outchar(*s++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<outstring>:
  endbr64
  test   %esi,%esi
  je     L13
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <outchar@plt>
  cmp    %rbx,%rbp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void outstring(const char *s, int len) {
  while (len--)
    outchar(*s++);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Rnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x24(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    $0x0,%eax
  call   <Random@plt>
  mov    %ax,-0x12(%rbp)
  movzwl -0x28(%rbp),%eax
  add    $0x1,%eax
  movzwl -0x24(%rbp),%edx
  sub    %edx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  movzwl -0x12(%rbp),%eax
  imul   -0x10(%rbp),%rax
  lea    0xffff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x10,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  movzwl -0x24(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
unsigned short Rnd(unsigned short min, unsigned short max) {
  unsigned short qdRdm;
  long range, t;
  qdRdm = Random();
  range = max + 1 - min;
  t = (qdRdm * range) / 65536;
  return (t + min);
}
```
user: What is the c source code of the assembly code below?

```asm
<Rnd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <Random@plt>
  mov    %eax,%edx
  movzwl %bx,%eax
  add    $0x1,%eax
  movzwl %bp,%ecx
  sub    %ecx,%eax
  cltq
  movzwl %dx,%edx
  imul   %rdx,%rax
  lea    0xffff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x10,%rax
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short Rnd(unsigned short min, unsigned short max) {
  unsigned short qdRdm;
  long range, t;
  qdRdm = Random();
  range = max + 1 - min;
  t = (qdRdm * range) / 65536;
  return (t + min);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Rnd>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <Random@plt>
  movzwl %bp,%edx
  mov    %eax,%r8d
  movzwl %bx,%eax
  add    $0x1,%eax
  sub    %edx,%eax
  movzwl %r8w,%edx
  cltq
  imul   %rdx,%rax
  test   %rax,%rax
  lea    0xffff(%rax),%rdx
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  sar    $0x10,%rax
  add    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short Rnd(unsigned short min, unsigned short max) {
  unsigned short qdRdm;
  long range, t;
  qdRdm = Random();
  range = max + 1 - min;
  t = (qdRdm * range) / 65536;
  return (t + min);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rnd>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <Random@plt>
  movzwl %bp,%edx
  mov    %eax,%r8d
  movzwl %bx,%eax
  add    $0x1,%eax
  sub    %edx,%eax
  movzwl %r8w,%edx
  cltq
  imul   %rdx,%rax
  test   %rax,%rax
  lea    0xffff(%rax),%rdx
  cmovs  %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  sar    $0x10,%rax
  add    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short Rnd(unsigned short min, unsigned short max) {
  unsigned short qdRdm;
  long range, t;
  qdRdm = Random();
  range = max + 1 - min;
  t = (qdRdm * range) / 65536;
  return (t + min);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2ip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L56
L8:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L63
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L66
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L66
L63:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x40(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x40(%rbp)
L66:
  addq   $0x1,-0x38(%rbp)
L29:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  cmpl   $0x1f,-0x40(%rbp)
  jle    L8
L28:
  mov    -0x40(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_addr@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0xffffffff,-0x3c(%rbp)
  jne    L92
  mov    $0xffffffff,%eax
  jmp    L56
L92:
  mov    $0x1,%eax
L56:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
unsigned int str2ip(char *ip_str) {
  int i = 0;
  int ip = 0;
  char tmp[32];
  char *p = ip_str;
  if (ip_str == NULL) {
    return -1;
  }
  while (*p != 0 && i < 32) {
    if (*p == '.' || (*p >= '0' && *p <= '9')) {
      tmp[i] = *p;
      i++;
    }
    p++;
  }
  tmp[i] = 0;
  ip = inet_addr(tmp);
  if (ip == -1) {
    return -1;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str2ip>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  mov    $0x0,%edx
  jmp    L70
L8:
  movslq %edx,%rcx
  mov    %al,(%rsp,%rcx,1)
  add    $0x1,%edx
L91:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x1f,%edx
  jg     L92
  test   %al,%al
  je     L92
L70:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L8
  cmp    $0x2e,%al
  jne    L91
  jmp    L8
L48:
  mov    $0x0,%edx
L92:
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  mov    %rsp,%rdi
  call   <inet_addr@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L5:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x38,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L5
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int str2ip(char *ip_str) {
  int i = 0;
  int ip = 0;
  char tmp[32];
  char *p = ip_str;
  if (ip_str == NULL) {
    return -1;
  }
  while (*p != 0 && i < 32) {
    if (*p == '.' || (*p >= '0' && *p <= '9')) {
      tmp[i] = *p;
      i++;
    }
    p++;
  }
  tmp[i] = 0;
  ip = inet_addr(tmp);
  if (ip == -1) {
    return -1;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str2ip>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L92
  movzbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L89
  jmp    L94
  nopl   0x0(%rax,%rax,1)
L76:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L94
L96:
  cmp    $0x20,%edx
  je     L94
L89:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L72
  cmp    $0x2e,%al
  jne    L76
L72:
  movslq %edx,%rcx
  add    $0x1,%rdi
  add    $0x1,%edx
  mov    %al,(%rsp,%rcx,1)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L96
L94:
  movslq %edx,%rdx
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <inet_addr@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0xffffffff,%r8d
  je     L92
L55:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  mov    $0xffffffff,%eax
  jmp    L55
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int str2ip(char *ip_str) {
  int i = 0;
  int ip = 0;
  char tmp[32];
  char *p = ip_str;
  if (ip_str == NULL) {
    return -1;
  }
  while (*p != 0 && i < 32) {
    if (*p == '.' || (*p >= '0' && *p <= '9')) {
      tmp[i] = *p;
      i++;
    }
    p++;
  }
  tmp[i] = 0;
  ip = inet_addr(tmp);
  if (ip == -1) {
    return -1;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str2ip>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L58
  movzbl (%rdi),%eax
  xor    %edx,%edx
  test   %al,%al
  jne    L25
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L52:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L27
L84:
  cmp    $0x20,%edx
  je     L27
L25:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L85
  cmp    $0x2e,%al
  jne    L52
L85:
  movslq %edx,%rcx
  add    $0x1,%rdi
  add    $0x1,%edx
  mov    %al,(%rsp,%rcx,1)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L84
L27:
  movslq %edx,%rdx
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <inet_addr@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0xffffffff,%r8d
  je     L58
L43:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    $0xffffffff,%eax
  jmp    L43
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int str2ip(char *ip_str) {
  int i = 0;
  int ip = 0;
  char tmp[32];
  char *p = ip_str;
  if (ip_str == NULL) {
    return -1;
  }
  while (*p != 0 && i < 32) {
    if (*p == '.' || (*p >= '0' && *p <= '9')) {
      tmp[i] = *p;
      i++;
    }
    p++;
  }
  tmp[i] = 0;
  ip = inet_addr(tmp);
  if (ip == -1) {
    return -1;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_imgfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fatfs_read_rootdir@plt>
  test   %eax,%eax
  je     L17
  mov    $0x1,%eax
  jmp    L1
L17:
  mov    $0x0,%eax
  call   <fatfs_reset_filename@plt>
  mov    $0x0,%eax
  call   <fatfs_read_rootdir@plt>
L1:
  pop    %rbp
  ret
```

assistant: ```c
bool find_imgfile() {
  if (fatfs_read_rootdir())
    return true;
  fatfs_reset_filename();
  return fatfs_read_rootdir();
}
```
user: What is the c source code of the assembly code below:

```asm
<find_imgfile>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fatfs_read_rootdir@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L7
L15:
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%eax
  call   <fatfs_reset_filename@plt>
  mov    $0x0,%eax
  call   <fatfs_read_rootdir@plt>
  jmp    L15
```

assistant: ```c
bool find_imgfile() {
  if (fatfs_read_rootdir())
    return true;
  fatfs_reset_filename();
  return fatfs_read_rootdir();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_imgfile>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fatfs_read_rootdir@plt>
  test   %eax,%eax
  je     L3
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L3:
  call   <fatfs_reset_filename@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <fatfs_read_rootdir@plt>
```

assistant: ```c
bool find_imgfile() {
  if (fatfs_read_rootdir())
    return true;
  fatfs_reset_filename();
  return fatfs_read_rootdir();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_imgfile>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fatfs_read_rootdir@plt>
  test   %eax,%eax
  je     L5
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L5:
  call   <fatfs_reset_filename@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <fatfs_read_rootdir@plt>
```

assistant: ```c
bool find_imgfile() {
  if (fatfs_read_rootdir())
    return true;
  fatfs_reset_filename();
  return fatfs_read_rootdir();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L37
  mov    $0xffffffff,%eax
  jmp    L26
L37:
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L33
  mov    $0x1,%eax
  jmp    L26
L33:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int fcmp(const void *v1, const void *v2) {
  float f1, f2;
  f1 = *(float *)v1;
  f2 = *(float *)v2;
  if (f1 < f2)
    return (-1);
  else if (f1 > f2)
    return (1);
  else
    return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcmp>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L7
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int fcmp(const void *v1, const void *v2) {
  float f1, f2;
  f1 = *(float *)v1;
  f2 = *(float *)v2;
  if (f1 < f2)
    return (-1);
  else if (f1 > f2)
    return (1);
  else
    return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcmp>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L4
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L4:
  ret
```

assistant: ```c
int fcmp(const void *v1, const void *v2) {
  float f1, f2;
  f1 = *(float *)v1;
  f2 = *(float *)v2;
  if (f1 < f2)
    return (-1);
  else if (f1 > f2)
    return (1);
  else
    return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcmp>:
  endbr64
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L9
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L9:
  ret
```

assistant: ```c
int fcmp(const void *v1, const void *v2) {
  float f1, f2;
  f1 = *(float *)v1;
  f2 = *(float *)v2;
  if (f1 < f2)
    return (-1);
  else if (f1 > f2)
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L14
L27:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0xa,-0xc(%rbp)
  jle    L27
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D38
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D30
type_guessed: string
name: disassemble_data
arguments: tag: D36
type_guessed: string

tool: D38: Digite um inteiro: 

tool: D13: %d

tool: D30: 
Tabuada de %d:


tool: D36: %d * %d = %d


assistant: ```c
void main() {
  int a, i;
  printf("Digite um inteiro: ");
  scanf("%d", &a);
  printf("\nTabuada de %d:\n", a);
  for (i = 1; i <= 10; i++) {
    printf("%d * %d = %d\n", a, i, a * i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
L12:
  mov    0x4(%rsp),%esi
  mov    %esi,%ecx
  imul   %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D1: Digite um inteiro: 

tool: D12: %d

tool: D26: 
Tabuada de %d:


tool: D5: %d * %d = %d


assistant: ```c
void main() {
  int a, i;
  printf("Digite um inteiro: ");
  scanf("%d", &a);
  printf("\nTabuada de %d:\n", a);
  for (i = 1; i <= 10; i++) {
    printf("%d * %d = %d\n", a, i, a * i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D33(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   (%rax)
L12:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string

tool: D0: Digite um inteiro: 

tool: D33: %d * %d = %d


tool: D36: %d

tool: D25: 
Tabuada de %d:


assistant: ```c
void main() {
  int a, i;
  printf("Digite um inteiro: ");
  scanf("%d", &a);
  printf("\nTabuada de %d:\n", a);
  for (i = 1; i <= 10; i++) {
    printf("%d * %d = %d\n", a, i, a * i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  lea    D25(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   (%rax)
L0:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D25
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string

tool: D2: Digite um inteiro: 

tool: D25: %d * %d = %d


tool: D18: %d

tool: D27: 
Tabuada de %d:


assistant: ```c
void main() {
  int a, i;
  printf("Digite um inteiro: ");
  scanf("%d", &a);
  printf("\nTabuada de %d:\n", a);
  for (i = 1; i <= 10; i++) {
    printf("%d * %d = %d\n", a, i, a * i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D64
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D0: r+w

tool: D4: /dev/mod_openclose

tool: D64: /dev/mod_hello

tool: D2: /dev/mod_zero0

tool: D9: /dev/mod_null

assistant: ```c
int main() {
  int retVal;
  test("/dev/mod_openclose", "r+w");
  test("/dev/mod_hello", "r+w");
  test("/dev/mod_zero0", "r+w");
  test("/dev/mod_null", "r+w");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  call   <test@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <test@plt>
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <test@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D18
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D8: r+w

tool: D19: /dev/mod_openclose

tool: D1: /dev/mod_hello

tool: D18: /dev/mod_zero0

tool: D0: /dev/mod_null

assistant: ```c
int main() {
  int retVal;
  test("/dev/mod_openclose", "r+w");
  test("/dev/mod_hello", "r+w");
  test("/dev/mod_zero0", "r+w");
  test("/dev/mod_null", "r+w");
  return 0;
}
```