ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2d,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <term@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D14: SUB (SP)+,D0

tool: D3: NEG D0

assistant: ```c
void subtract(void) {
  match('-');
  term();
  emitln("SUB (SP)+,D0");
  emitln("NEG D0");
}
```
user: Translate the below assembly code into C programming language:

```asm
<subtract>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2d,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <term@plt>
  lea    D13(%rip),%rdi
  call   <emitln@plt>
  lea    D10(%rip),%rdi
  call   <emitln@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D13: SUB (SP)+,D0

tool: D10: NEG D0

assistant: ```c
void subtract(void) {
  match('-');
  term();
  emitln("SUB (SP)+,D0");
  emitln("NEG D0");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<subtract>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2d,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <term@plt>
  lea    D18(%rip),%rdi
  call   <emitln@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <emitln@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D18: SUB (SP)+,D0

tool: D1: NEG D0

assistant: ```c
void subtract(void) {
  match('-');
  term();
  emitln("SUB (SP)+,D0");
  emitln("NEG D0");
}
```
user: What is the c source code of the assembly code below?

```asm
<subtract>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2d,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <term@plt>
  lea    D9(%rip),%rdi
  call   <emitln@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <emitln@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string

tool: D9: SUB (SP)+,D0

tool: D18: NEG D0

assistant: ```c
void subtract(void) {
  match('-');
  term();
  emitln("SUB (SP)+,D0");
  emitln("NEG D0");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_62_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_62_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_62_1_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  mov    %edx,%edi
  or     %esi,%edi
  not    %esi
  and    (%rcx),%sil
  or     %edx,%esi
  xor    %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %eax,%esi
  mov    %edi,%eax
  and    (%rcx),%al
  or     %eax,%esi
  mov    %sil,(%rcx)
  ret
```

assistant: ```c
void rop3_62_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_62_1_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %esi,%eax
  or     %esi,%edi
  not    %esi
  and    (%rcx),%sil
  or     %edx,%esi
  xor    %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %eax,%esi
  movzbl (%rcx),%eax
  and    %edi,%eax
  or     %eax,%esi
  mov    %sil,(%rcx)
  ret
```

assistant: ```c
void rop3_62_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_62_1_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %esi,%eax
  or     %esi,%edi
  not    %esi
  and    (%rcx),%sil
  or     %edx,%esi
  xor    %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %eax,%esi
  movzbl (%rcx),%eax
  and    %edi,%eax
  or     %eax,%esi
  mov    %sil,(%rcx)
  ret
```

assistant: ```c
void rop3_62_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isOffset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L67
L46:
  movzbl -0x19(%rbp),%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L14
  mov    $0x0,%eax
  jmp    L52
L14:
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  movzbl -0x19(%rbp),%eax
  mov    %eax,%edi
  call   <hexToInt@plt>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L67:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L55
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  cmpb   $0x5d,-0x19(%rbp)
  jne    L46
L55:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L68
  mov    $0x0,%eax
  jmp    L52
L68:
  mov    -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L52:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int isOffset(const unsigned char *zIn, int nIn, unsigned int *pK, unsigned int *pI) {
  int i;
  unsigned int k = 0;
  unsigned char c;
  for (i = 1; i < nIn && (c = zIn[i]) != ']'; i++) {
    if (!isxdigit(c))
      return 0;
    k = k * 16 + hexToInt(c);
  }
  if (i == nIn)
    return 0;
  *pK = 2 * k;
  *pI += i;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isOffset>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r14d
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r15
  cmp    $0x1,%esi
  jle    L23
  lea    0x1(%rdi),%r12
  mov    $0x0,%ebp
  mov    $0x1,%r13d
L18:
  movzbl (%r12),%ebx
  cmp    $0x5d,%bl
  je     L28
  movzbl %bl,%ebx
  mov    %ebx,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L50
  shl    $0x4,%ebp
  mov    %ebx,%edi
  call   <hexToInt@plt>
  add    %eax,%ebp
  add    $0x1,%r13d
  add    $0x1,%r12
  cmp    %r13d,%r14d
  jne    L18
  mov    $0x0,%eax
  jmp    L50
L23:
  mov    $0x0,%ebp
  mov    $0x1,%r13d
L28:
  cmp    %r13d,%r14d
  je     L68
  add    %ebp,%ebp
  mov    0x8(%rsp),%rax
  mov    %ebp,(%rax)
  add    %r13d,(%r15)
  mov    $0x1,%eax
L50:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  mov    $0x0,%eax
  jmp    L50
```

assistant: ```c
int isOffset(const unsigned char *zIn, int nIn, unsigned int *pK, unsigned int *pI) {
  int i;
  unsigned int k = 0;
  unsigned char c;
  for (i = 1; i < nIn && (c = zIn[i]) != ']'; i++) {
    if (!isxdigit(c))
      return 0;
    k = k * 16 + hexToInt(c);
  }
  if (i == nIn)
    return 0;
  *pK = 2 * k;
  *pI += i;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isOffset>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  cmp    $0x1,%esi
  jle    L23
  mov    %esi,%r13d
  lea    0x1(%rdi),%rbp
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L32
L37:
  movzbl %dil,%r15d
  mov    %r15d,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L18
  mov    %r15d,%edi
  shl    $0x4,%ebx
  add    $0x1,%r12d
  add    $0x1,%rbp
  call   <hexToInt@plt>
  add    %eax,%ebx
  cmp    %r12d,%r13d
  je     L18
L32:
  movzbl 0x0(%rbp),%edi
  cmp    $0x5d,%dil
  jne    L37
L38:
  mov    0x8(%rsp),%rax
  add    %ebx,%ebx
  mov    %ebx,(%rax)
  mov    $0x1,%eax
  add    %r12d,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L18:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  je     L18
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L38
```

assistant: ```c
int isOffset(const unsigned char *zIn, int nIn, unsigned int *pK, unsigned int *pI) {
  int i;
  unsigned int k = 0;
  unsigned char c;
  for (i = 1; i < nIn && (c = zIn[i]) != ']'; i++) {
    if (!isxdigit(c))
      return 0;
    k = k * 16 + hexToInt(c);
  }
  if (i == nIn)
    return 0;
  *pK = 2 * k;
  *pI += i;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isOffset>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  cmp    $0x1,%esi
  jle    L4
  mov    %esi,%r13d
  lea    0x1(%rdi),%rbp
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L40
L67:
  movzbl %dil,%r15d
  mov    %r15d,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L50
  mov    %r15d,%edi
  shl    $0x4,%ebx
  add    $0x1,%r12d
  add    $0x1,%rbp
  call   <hexToInt@plt>
  add    %eax,%ebx
  cmp    %r12d,%r13d
  je     L50
L40:
  movzbl 0x0(%rbp),%edi
  cmp    $0x5d,%dil
  jne    L67
L6:
  mov    0x8(%rsp),%rax
  add    %ebx,%ebx
  mov    %ebx,(%rax)
  mov    $0x1,%eax
  add    %r12d,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L50:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  je     L50
  xor    %ebx,%ebx
  mov    $0x1,%r12d
  jmp    L6
```

assistant: ```c
int isOffset(const unsigned char *zIn, int nIn, unsigned int *pK, unsigned int *pI) {
  int i;
  unsigned int k = 0;
  unsigned char c;
  for (i = 1; i < nIn && (c = zIn[i]) != ']'; i++) {
    if (!isxdigit(c))
      return 0;
    k = k * 16 + hexToInt(c);
  }
  if (i == nIn)
    return 0;
  *pK = 2 * k;
  *pI += i;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<byte_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L73
L60:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L81
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L74
  mov    $0x0,%eax
  jmp    L73
L74:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L7
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L73
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L110
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L76
  mov    $0x0,%eax
  jmp    L73
L76:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L131
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  jmp    L1
L81:
  nop
  jmp    L28
L7:
  nop
  jmp    L28
L110:
  nop
  jmp    L28
L131:
  nop
L28:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
int byte_diff(const void *S, unsigned int n, const void *T) {
  const char *s = S;
  const char *t = T;
  for (;;) {
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
  }
  return ((int)(unsigned int)(unsigned char)*s) - ((int)(unsigned int)(unsigned char)*t);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byte_diff>:
  endbr64
  test   %esi,%esi
  je     L59
L104:
  movzbl (%rdx),%eax
  cmp    %al,(%rdi)
  jne    L84
  cmp    $0x1,%esi
  je     L30
  movzbl 0x1(%rdx),%eax
  cmp    %al,0x1(%rdi)
  jne    L25
  cmp    $0x2,%esi
  je     L28
  movzbl 0x2(%rdx),%eax
  cmp    %al,0x2(%rdi)
  jne    L99
  cmp    $0x3,%esi
  je     L21
  movzbl 0x3(%rdx),%eax
  cmp    %al,0x3(%rdi)
  jne    L34
  add    $0x4,%rdi
  add    $0x4,%rdx
  sub    $0x4,%esi
  jne    L104
  mov    $0x0,%eax
  ret
L25:
  add    $0x1,%rdi
  add    $0x1,%rdx
L84:
  movzbl (%rdi),%eax
  movzbl (%rdx),%edx
  sub    %edx,%eax
  ret
L99:
  add    $0x2,%rdi
  add    $0x2,%rdx
  jmp    L84
L34:
  add    $0x3,%rdi
  add    $0x3,%rdx
  jmp    L84
L59:
  mov    $0x0,%eax
  ret
L30:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int byte_diff(const void *S, unsigned int n, const void *T) {
  const char *s = S;
  const char *t = T;
  for (;;) {
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
  }
  return ((int)(unsigned int)(unsigned char)*s) - ((int)(unsigned int)(unsigned char)*t);
}
```
user: What is the c source code of the assembly code below:

```asm
<byte_diff>:
  endbr64
  test   %esi,%esi
  jne    L14
  jmp    L97
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    $0x1,%esi
  je     L97
  movzbl 0x1(%rdi),%eax
  movzbl 0x1(%rdx),%ecx
  cmp    %cl,%al
  jne    L63
  cmp    $0x2,%esi
  je     L97
  movzbl 0x2(%rdi),%eax
  movzbl 0x2(%rdx),%ecx
  cmp    %cl,%al
  jne    L63
  cmp    $0x3,%esi
  je     L97
  movzbl 0x3(%rdi),%eax
  movzbl 0x3(%rdx),%ecx
  cmp    %cl,%al
  jne    L63
  add    $0x4,%rdi
  add    $0x4,%rdx
  sub    $0x4,%esi
  je     L97
L14:
  movzbl (%rdi),%eax
  movzbl (%rdx),%ecx
  cmp    %cl,%al
  je     L8
L63:
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L97:
  xor    %eax,%eax
  ret
```

assistant: ```c
int byte_diff(const void *S, unsigned int n, const void *T) {
  const char *s = S;
  const char *t = T;
  for (;;) {
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
  }
  return ((int)(unsigned int)(unsigned char)*s) - ((int)(unsigned int)(unsigned char)*t);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<byte_diff>:
  endbr64
  test   %esi,%esi
  jne    L26
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    $0x1,%esi
  je     L83
  movzbl 0x1(%rdi),%eax
  movzbl 0x1(%rdx),%ecx
  cmp    %cl,%al
  jne    L56
  cmp    $0x2,%esi
  je     L83
  movzbl 0x2(%rdi),%eax
  movzbl 0x2(%rdx),%ecx
  cmp    %cl,%al
  jne    L56
  cmp    $0x3,%esi
  je     L83
  movzbl 0x3(%rdi),%eax
  movzbl 0x3(%rdx),%ecx
  cmp    %cl,%al
  jne    L56
  add    $0x4,%rdi
  add    $0x4,%rdx
  sub    $0x4,%esi
  je     L83
L26:
  movzbl (%rdi),%eax
  movzbl (%rdx),%ecx
  cmp    %cl,%al
  je     L24
L56:
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L83:
  xor    %eax,%eax
  ret
```

assistant: ```c
int byte_diff(const void *S, unsigned int n, const void *T) {
  const char *s = S;
  const char *t = T;
  for (;;) {
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
    if (!n)
      return 0;
    if (*s != *t)
      break;
    ++s;
    ++t;
    --n;
  }
  return ((int)(unsigned int)(unsigned char)*s) - ((int)(unsigned int)(unsigned char)*t);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DSTcorrect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x3,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x3,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  movslq %edx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  imul   $0xe10,%rax,%rax
  add    %rcx,%rax
  leave
  ret
```

assistant: ```c
time_t DSTcorrect(time_t Start, time_t Future) {
  time_t StartDay;
  time_t FutureDay;
  StartDay = (localtime(&Start)->tm_hour + 1) % 24;
  FutureDay = (localtime(&Future)->tm_hour + 1) % 24;
  return (Future - Start) + (StartDay - FutureDay) * 60L * 60L;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DSTcorrect>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,(%rsp)
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x3,%eax
  sub    %eax,%ebx
  movslq %ebx,%rbx
  mov    %rsp,%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  cltq
  sub    %rax,%rbx
  imul   $0xe10,%rbx,%rax
  add    (%rsp),%rax
  sub    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
time_t DSTcorrect(time_t Start, time_t Future) {
  time_t StartDay;
  time_t FutureDay;
  StartDay = (localtime(&Start)->tm_hour + 1) % 24;
  FutureDay = (localtime(&Future)->tm_hour + 1) % 24;
  return (Future - Start) + (StartDay - FutureDay) * 60L * 60L;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<DSTcorrect>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  mov    %rsi,(%rsp)
  call   <localtime@plt>
  mov    %rsp,%rdi
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x3,%eax
  sub    %eax,%ebx
  call   <localtime@plt>
  movslq %ebx,%rbx
  mov    (%rax),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  cltq
  sub    %rax,%rbx
  imul   $0xe10,%rbx,%rax
  add    (%rsp),%rax
  sub    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
time_t DSTcorrect(time_t Start, time_t Future) {
  time_t StartDay;
  time_t FutureDay;
  StartDay = (localtime(&Start)->tm_hour + 1) % 24;
  FutureDay = (localtime(&Future)->tm_hour + 1) % 24;
  return (Future - Start) + (StartDay - FutureDay) * 60L * 60L;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DSTcorrect>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  mov    %rsi,(%rsp)
  call   <localtime@plt>
  mov    %rsp,%rdi
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x3,%eax
  sub    %eax,%ebx
  call   <localtime@plt>
  movslq %ebx,%rbx
  mov    (%rax),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  shl    $0x3,%edx
  sub    %edx,%eax
  cltq
  sub    %rax,%rbx
  imul   $0xe10,%rbx,%rax
  add    (%rsp),%rax
  sub    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
time_t DSTcorrect(time_t Start, time_t Future) {
  time_t StartDay;
  time_t FutureDay;
  StartDay = (localtime(&Start)->tm_hour + 1) % 24;
  FutureDay = (localtime(&Future)->tm_hour + 1) % 24;
  return (Future - Start) + (StartDay - FutureDay) * 60L * 60L;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HibernateRTCDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fc010,%eax
  mov    (%rax),%eax
  mov    $0x400fc010,%edx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <_HibernateWriteComplete@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void HibernateRTCDisable(void) {
  (*((volatile uint32_t *)(0x400FC010))) &= ~0x00000001;
  _HibernateWriteComplete();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<HibernateRTCDisable>:
  endbr64
  sub    $0x8,%rsp
  mov    0x400fc010,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x400fc010
  mov    $0x0,%eax
  call   <_HibernateWriteComplete@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void HibernateRTCDisable(void) {
  (*((volatile uint32_t *)(0x400FC010))) &= ~0x00000001;
  _HibernateWriteComplete();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HibernateRTCDisable>:
  endbr64
  mov    0x400fc010,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x400fc010
  xor    %eax,%eax
  jmp    1050 <_HibernateWriteComplete@plt>
```

assistant: ```c
void HibernateRTCDisable(void) {
  (*((volatile uint32_t *)(0x400FC010))) &= ~0x00000001;
  _HibernateWriteComplete();
}
```