ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<conversion>:
  endbr64
  sub    $0x48,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L6
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rcx
  xor    %eax,%eax
  lea    0x28(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x30(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  lea    0x8(%rsp),%rdi
  movsd  0x20(%rsp),%xmm0
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <yuv2rgb@plt>
  movsd  0x18(%rsp),%xmm5
  mov    $0x6,%eax
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm2
  lea    D63(%rip),%rdi
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  call   <printf@plt>
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D67(%rip),%rdi
  call   <puts@plt>
  lea    0x18(%rsp),%rcx
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  lea    0x20(%rsp),%rdi
  movsd  0x8(%rsp),%xmm0
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  call   <rgb2yuv@plt>
  movsd  0x30(%rsp),%xmm5
  mov    $0x6,%eax
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  lea    D0(%rip),%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  jmp    L7
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D33
type_guessed: string
name: parse_data
arguments: data_tag: D42
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D55
type_guessed: string
name: parse_data
arguments: data_tag: D63
type_guessed: string
name: parse_data
arguments: data_tag: D67
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D33: Conversion rgb->Yuv 1;Yuv->rgb 2
Choix ?=(1 ou 2)

tool: D42: %d

tool: D29: Entrez les valeurs Y,u,v

tool: D55: %lf %lf %lf

tool: D63: Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf


tool: D67: Entrez les valeurs r,g,b

tool: D0: r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf


assistant: ```c
void conversion() {
  int choix;
  double r, g, b, y, u, v;
  printf("Conversion rgb->Yuv 1;Yuv->rgb 2\nChoix ?=(1 ou 2)");
  scanf("%d", &choix);
  printf("\n");
  if (choix == 1) {
    printf("Entrez les valeurs r,g,b\n");
    scanf("%lf %lf %lf", &r, &g, &b);
    printf("\n");
    rgb2yuv(&y, &u, &v, r, g, b);
    printf("r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf\n", r, g, b, y, u, v);
  } else {
    printf("Entrez les valeurs Y,u,v\n");
    scanf("%lf %lf %lf", &y, &u, &v);
    printf("\n");
    yuv2rgb(&r, &g, &b, y, u, v);
    printf("Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf\n", y, u, v, r, g, b);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<conversion>:
  endbr64
  sub    $0x48,%rsp
  lea    D36(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L25
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rcx
  xor    %eax,%eax
  lea    0x28(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x30(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  lea    0x8(%rsp),%rdi
  movsd  0x20(%rsp),%xmm0
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <yuv2rgb@plt>
  movsd  0x18(%rsp),%xmm5
  mov    $0x6,%eax
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm2
  lea    D79(%rip),%rdi
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  call   <printf@plt>
L17:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  lea    D77(%rip),%rdi
  call   <puts@plt>
  lea    0x18(%rsp),%rcx
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  lea    0x20(%rsp),%rdi
  movsd  0x8(%rsp),%xmm0
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  call   <rgb2yuv@plt>
  movsd  0x30(%rsp),%xmm5
  mov    $0x6,%eax
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  lea    D22(%rip),%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  jmp    L17
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D36
type: string
name: read_data
arguments: tag: D74
type: string
name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D65
type: string
name: read_data
arguments: tag: D79
type: string
name: read_data
arguments: tag: D77
type: string
name: read_data
arguments: tag: D22
type: string

tool: D36: Conversion rgb->Yuv 1;Yuv->rgb 2
Choix ?=(1 ou 2)

tool: D74: %d

tool: D17: Entrez les valeurs Y,u,v

tool: D65: %lf %lf %lf

tool: D79: Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf


tool: D77: Entrez les valeurs r,g,b

tool: D22: r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf


assistant: ```c
void conversion() {
  int choix;
  double r, g, b, y, u, v;
  printf("Conversion rgb->Yuv 1;Yuv->rgb 2\nChoix ?=(1 ou 2)");
  scanf("%d", &choix);
  printf("\n");
  if (choix == 1) {
    printf("Entrez les valeurs r,g,b\n");
    scanf("%lf %lf %lf", &r, &g, &b);
    printf("\n");
    rgb2yuv(&y, &u, &v, r, g, b);
    printf("r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf\n", r, g, b, y, u, v);
  } else {
    printf("Entrez les valeurs Y,u,v\n");
    scanf("%lf %lf %lf", &y, &u, &v);
    printf("\n");
    yuv2rgb(&r, &g, &b, y, u, v);
    printf("Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf\n", y, u, v, r, g, b);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cag_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *cag_strdup(const char *s) {
  size_t len = strlen(s) + 1;
  char *output = malloc(sizeof(char) * len);
  strcpy(output, s);
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cag_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *cag_strdup(const char *s) {
  size_t len = strlen(s) + 1;
  char *output = malloc(sizeof(char) * len);
  strcpy(output, s);
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cag_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cag_strdup(const char *s) {
  size_t len = strlen(s) + 1;
  char *output = malloc(sizeof(char) * len);
  strcpy(output, s);
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cag_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cag_strdup(const char *s) {
  size_t len = strlen(s) + 1;
  char *output = malloc(sizeof(char) * len);
  strcpy(output, s);
  return output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insertsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L29
L48:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L38
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L38:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cmp    %eax,-0x1c(%rbp)
  jge    L28
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L27
L28:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertsort(int *array, int s, int e) {
  int i, j, val;
  for (i = s + 1; i <= e; i++) {
    val = array[i];
    j = i;
    while (j-- > s && val < array[j])
      array[j + 1] = array[j];
    array[j + 1] = val;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<insertsort>:
  endbr64
  lea    0x1(%rsi),%r10d
  cmp    %edx,%r10d
  jg     L63
  push   %rbx
  mov    %rdi,%rbx
  movslq %r10d,%r10
  mov    %esi,%r11d
  lea    -0x1(%rsi),%r9d
  jmp    L0
L22:
  movslq %ecx,%rcx
  mov    %r8d,0x4(%rbx,%rcx,4)
  add    $0x1,%r10
  add    $0x1,%r11d
  cmp    %r10d,%edx
  jl     L51
L0:
  mov    (%rbx,%r10,4),%r8d
  mov    %r11d,%ecx
  cmp    %r10d,%esi
  jge    L22
  movslq %r11d,%rax
  lea    (%rbx,%rax,4),%rax
L18:
  mov    (%rax),%edi
  cmp    %r8d,%edi
  jle    L22
  mov    %edi,0x4(%rax)
  sub    $0x1,%ecx
  sub    $0x4,%rax
  cmp    %r9d,%ecx
  jne    L18
  mov    %r9d,%ecx
  jmp    L22
L51:
  pop    %rbx
  ret
L63:
  ret
```

assistant: ```c
void insertsort(int *array, int s, int e) {
  int i, j, val;
  for (i = s + 1; i <= e; i++) {
    val = array[i];
    j = i;
    while (j-- > s && val < array[j])
      array[j + 1] = array[j];
    array[j + 1] = val;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insertsort>:
  endbr64
  lea    0x1(%rsi),%eax
  mov    %esi,%r11d
  mov    %esi,%r10d
  movslq %eax,%r9
  cmp    %edx,%eax
  jg     L61
  nopl   0x0(%rax)
L41:
  mov    (%rdi,%r9,4),%r8d
  lea    -0x1(%r9),%rax
  cmp    %r9d,%r11d
  jge    L32
  mov    %r9d,%ecx
  lea    -0x2(%r9),%rsi
  movslq %r10d,%rax
  sub    %r11d,%ecx
  sub    $0x1,%ecx
  sub    %rcx,%rsi
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %ecx,0x4(%rdi,%rax,4)
  lea    -0x1(%rax),%ecx
  sub    $0x1,%rax
  cmp    %rax,%rsi
  je     L7
L2:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jg     L53
L32:
  add    $0x1,%r9
  mov    %r8d,0x4(%rdi,%rax,4)
  add    $0x1,%r10d
  cmp    %r9d,%edx
  jge    L41
L61:
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  movslq %ecx,%rax
  jmp    L32
```

assistant: ```c
void insertsort(int *array, int s, int e) {
  int i, j, val;
  for (i = s + 1; i <= e; i++) {
    val = array[i];
    j = i;
    while (j-- > s && val < array[j])
      array[j + 1] = array[j];
    array[j + 1] = val;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insertsort>:
  endbr64
  lea    0x1(%rsi),%eax
  movslq %eax,%r10
  cmp    %edx,%eax
  jg     L41
  xchg   %ax,%ax
L46:
  mov    (%rdi,%r10,4),%r8d
  lea    -0x1(%r10),%rax
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %ecx,0x4(%rdi,%rax,4)
  lea    -0x1(%rax),%r9d
  sub    $0x1,%rax
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L15
L18:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jg     L42
  add    $0x1,%r10
  mov    %r8d,0x4(%rdi,%rax,4)
  cmp    %r10d,%edx
  jge    L46
L41:
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %r9d,%rax
  add    $0x1,%r10
  mov    %r8d,0x4(%rdi,%rax,4)
  cmp    %r10d,%edx
  jge    L46
  jmp    L41
```

assistant: ```c
void insertsort(int *array, int s, int e) {
  int i, j, val;
  for (i = s + 1; i <= e; i++) {
    val = array[i];
    j = i;
    while (j-- > s && val < array[j])
      array[j + 1] = array[j];
    array[j + 1] = val;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <getlines@plt>
  movl   $0x0,-0x3f4(%rbp)
  movl   $0x0,-0x3fc(%rbp)
  jmp    L63
L26:
  mov    -0x3fc(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <findnewline@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x50,-0x3f4(%rbp)
  jle    L2
  movl   $0x0,-0x3f8(%rbp)
  jmp    L24
L61:
  mov    -0x3fc(%rbp),%edx
  mov    -0x3f8(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x3f8(%rbp)
L24:
  mov    -0x3f8(%rbp),%eax
  cmp    -0x3f4(%rbp),%eax
  jl     L61
L2:
  mov    -0x3f4(%rbp),%eax
  add    %eax,-0x3fc(%rbp)
L63:
  cmpl   $0x3e6,-0x3fc(%rbp)
  jg     L40
  mov    -0x3fc(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L26
L40:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int main() {
  char userinput[1000];
  int i, j, k;
  getlines(userinput);
  for (j = 0, i = 0; i < 1000 - 1 && userinput[i] != '\0'; i += j) {
    if ((j = findnewline(userinput, i)) > 80) {
      for (k = 0; k < j; k++)
        putchar(userinput[i + k]);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getlines@plt>
  mov    $0x0,%ebp
  mov    %rsp,%r14
  jmp    L20
L64:
  add    %r12d,%ebp
  cmp    $0x3e6,%ebp
  jg     L12
L20:
  movslq %ebp,%rax
  cmpb   $0x0,(%rsp,%rax,1)
  je     L12
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <findnewline@plt>
  mov    %eax,%r12d
  cmp    $0x50,%eax
  jle    L64
  movslq %ebp,%rax
  lea    (%r14,%rax,1),%rbx
  lea    0x1(%rsp,%rax,1),%r13
  lea    -0x1(%r12),%eax
  add    %rax,%r13
L33:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L33
  jmp    L64
L12:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char userinput[1000];
  int i, j, k;
  getlines(userinput);
  for (j = 0, i = 0; i < 1000 - 1 && userinput[i] != '\0'; i += j) {
    if ((j = findnewline(userinput, i)) > 80) {
      for (k = 0; k < j; k++)
        putchar(userinput[i + k]);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x1(%rsp),%r15
  mov    %r14,%rdi
  call   <getlines@plt>
  jmp    L6
  nopl   (%rax)
L23:
  add    %r12d,%r13d
  cmp    $0x3e6,%r13d
  jg     L35
L6:
  movslq %r13d,%rbp
  cmpb   $0x0,(%rsp,%rbp,1)
  je     L35
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <findnewline@plt>
  mov    %eax,%r12d
  cmp    $0x50,%eax
  jle    L23
  lea    (%r14,%rbp,1),%rbx
  lea    -0x1(%rax),%eax
  add    %r15,%rbp
  add    %rax,%rbp
  nopl   (%rax)
L66:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L66
  add    %r12d,%r13d
  cmp    $0x3e6,%r13d
  jle    L6
  nopl   (%rax)
L35:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char userinput[1000];
  int i, j, k;
  getlines(userinput);
  for (j = 0, i = 0; i < 1000 - 1 && userinput[i] != '\0'; i += j) {
    if ((j = findnewline(userinput, i)) > 80) {
      for (k = 0; k < j; k++)
        putchar(userinput[i + k]);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x1(%rsp),%r15
  mov    %r14,%rdi
  call   <getlines@plt>
  jmp    L67
  nopl   (%rax)
L65:
  add    %r12d,%r13d
  cmp    $0x3e6,%r13d
  jg     L48
L67:
  movslq %r13d,%rbp
  cmpb   $0x0,(%rsp,%rbp,1)
  je     L48
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <findnewline@plt>
  mov    %eax,%r12d
  cmp    $0x50,%eax
  jle    L65
  lea    (%r14,%rbp,1),%rbx
  lea    -0x1(%rax),%eax
  add    %r15,%rbp
  add    %rax,%rbp
  nopl   (%rax)
L62:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L62
  add    %r12d,%r13d
  cmp    $0x3e6,%r13d
  jle    L67
  nopl   (%rax)
L48:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char userinput[1000];
  int i, j, k;
  getlines(userinput);
  for (j = 0, i = 0; i < 1000 - 1 && userinput[i] != '\0'; i += j) {
    if ((j = findnewline(userinput, i)) > 80) {
      for (k = 0; k < j; k++)
        putchar(userinput[i + k]);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  ja     L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int __attribute__((noclone, no)) f(unsigned int n, unsigned int *__restrict__ a) {
  int i;
  unsigned int sum = 1;
  for (i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  test   %edi,%edi
  je     L16
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x4(%rsi,%rdx,4),%rcx
  mov    $0x1,%edx
L27:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L27
L24:
  mov    %edx,%eax
  ret
L16:
  mov    $0x1,%edx
  jmp    L24
```

assistant: ```c
unsigned int __attribute__((noclone, no)) f(unsigned int n, unsigned int *__restrict__ a) {
  int i;
  unsigned int sum = 1;
  for (i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  test   %edi,%edi
  je     L8
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rdx
  mov    $0x1,%eax
  nopl   (%rax)
L16:
  add    (%rsi),%eax
  add    $0x4,%rsi
  cmp    %rdx,%rsi
  jne    L16
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((noclone, no)) f(unsigned int n, unsigned int *__restrict__ a) {
  int i;
  unsigned int sum = 1;
  for (i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  je     L32
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L37
  mov    %edi,%ecx
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L28:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L28
  movdqa %xmm0,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    $0x1,%eax
  test   $0x3,%dl
  je     L16
L61:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rsi,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edx,%edi
  jae    L9
  add    $0x2,%ecx
  add    0x4(%rsi,%r8,1),%eax
  cmp    %ecx,%edx
  jbe    L9
  add    0x8(%rsi,%r8,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%eax
L9:
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  ret
L37:
  mov    $0x1,%eax
  xor    %ecx,%ecx
  jmp    L61
```

assistant: ```c
unsigned int __attribute__((noclone, no)) f(unsigned int n, unsigned int *__restrict__ a) {
  int i;
  unsigned int sum = 1;
  for (i = 0; i < n; ++i)
    sum += a[i];
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tbBufferRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  cmp    %eax,%edx
  jbe    L19
  mov    $0x0,%eax
  jmp    L18
L19:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int tbBufferRead(void *Destination, unsigned int ElementSize, const long BufferSize, const char *Buffer, unsigned int *BufferPointer) {
  if ((*BufferPointer + ElementSize) > (unsigned int)BufferSize) {
    return 0;
  } else {
    memcpy(Destination, &Buffer[*BufferPointer], ElementSize);
    *BufferPointer += ElementSize;
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tbBufferRead>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  mov    %r8,%rbx
  mov    (%r8),%eax
  lea    (%rax,%rbp,1),%r8d
  mov    $0x0,%edx
  cmp    %esi,%r8d
  jbe    L5
L8:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %eax,%eax
  lea    (%rcx,%rax,1),%rsi
  mov    %ebp,%edx
  call   <memcpy@plt>
  add    %ebp,(%rbx)
  mov    $0x1,%edx
  jmp    L8
```

assistant: ```c
int tbBufferRead(void *Destination, unsigned int ElementSize, const long BufferSize, const char *Buffer, unsigned int *BufferPointer) {
  if ((*BufferPointer + ElementSize) > (unsigned int)BufferSize) {
    return 0;
  } else {
    memcpy(Destination, &Buffer[*BufferPointer], ElementSize);
    *BufferPointer += ElementSize;
    return 1;
  }
}
```