ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<CG_FitTextToWidth2>:
  endbr64
  push   %r15
  mov    $0x400,%edx
  movd   %xmm0,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  mov    %r14,%rbx
  sub    $0x428,%rsp
  lea    0x10(%rsp),%rbp
  movss  %xmm1,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <Q_strncpyz@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L13
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rbp
  cmp    $0x20,%al
  mov    %al,(%rbx)
  lea    0x1(%rbx),%r13
  cmove  %rbx,%r12
  cmpb   $0xa,0x0(%rbp)
  jne    L28
  lea    0x2(%rbx),%r14
  mov    $0xa,%eax
  mov    %r13,%rbx
  jmp    L30
  nopl   0x0(%rax)
L28:
  xor    %esi,%esi
  movd   %r15d,%xmm0
  mov    %r14,%rdi
  call   <CG_Text_Width@plt>
  comiss 0xc(%rsp),%xmm0
  jbe    L38
  test   %r12,%r12
  je     L99
  movb   $0xa,(%r12)
  lea    0x1(%r12),%r14
  mov    %r13,%rbx
  xor    %r12d,%r12d
L59:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L30
L13:
  cmpb   $0xa,-0x1(%rbx)
  je     L0
  movb   $0xa,(%rbx)
  add    $0x1,%rbx
L0:
  movb   $0x0,(%rbx)
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  mov    %r13,%rbx
  jmp    L59
  nopl   (%rax)
L99:
  movzbl (%rbx),%eax
  mov    %r13,%r14
  movb   $0xa,(%rbx)
  add    $0x2,%rbx
  mov    %al,-0x1(%rbx)
  jmp    L59
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CG_FitTextToWidth2(char *instr, float scale, float w, int size) {
  char buffer[1024];
  char *s, *p, *c, *ls;
  int l;
  Q_strncpyz(buffer, instr, 1024);
  memset(instr, 0, size);
  c = s = instr;
  p = buffer;
  ls = ((void *)0);
  l = 0;
  while (*p) {
    *c = *p++;
    l++;
    if (*c == ' ') {
      ls = c;
    }
    c++;
    if (*p == '\n') {
      s = c + 1;
      l = 0;
    } else if (CG_Text_Width(s, scale, 0) > w) {
      if (ls) {
        *ls = '\n';
        s = ls + 1;
      } else {
        *c = *(c - 1);
        *(c - 1) = '\n';
        s = c++;
      }
      ls = ((void *)0);
      l = 0;
    }
  }
  if (c != buffer && (*(c - 1) != '\n')) {
    *c++ = '\n';
  }
  *c = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  mov    %rsp,%rbx
  lea    0x8(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D60(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D75(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D45
data_type: string
name: parse_data
arguments: tag: D48
data_type: string
name: parse_data
arguments: tag: D8
data_type: string
name: parse_data
arguments: tag: D76
data_type: string
name: parse_data
arguments: tag: D60
data_type: string
name: parse_data
arguments: tag: D75
data_type: string
name: parse_data
arguments: tag: D56
data_type: string

tool: D12:               pz = %p, pz + 1 = %p


tool: D45:            pz[0] = %p, pz[0] + 1 = %p


tool: D48:              *pz = %p, *pz + 1 = %p


tool: D8:         pz[0][0] = %d


tool: D76:           *pz[0] = %d


tool: D60:             **pz = %d


tool: D75:         pz[2][1] = %d


tool: D56: *(*(pz + 2) + 1) = %d


assistant: ```c
int main(void) {
  int zippo[4][2] = {{2, 4}, {6, 8}, {1, 3}, {5, 7}};
  int(*pz)[2];
  pz = zippo;
  printf("              pz = %p, pz + 1 = %p\n", pz, pz + 1);
  printf("           pz[0] = %p, pz[0] + 1 = %p\n", pz[0], pz[0] + 1);
  printf("             *pz = %p, *pz + 1 = %p\n", *pz, *pz + 1);
  printf("        pz[0][0] = %d\n", pz[0][0]);
  printf("          *pz[0] = %d\n", *pz[0]);
  printf("            **pz = %d\n", **pz);
  printf("        pz[2][1] = %d\n", pz[2][1]);
  printf("*(*(pz + 2) + 1) = %d\n", *(*(pz + 2) + 1));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000002,%rax
  mov    %rsp,%rbp
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%r12
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x300000001,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D55
type: string
name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D60
type: string
name: disassemble_data
arguments: data_tag: D68
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D3
type: string

tool: D7:               pz = %p, pz + 1 = %p


tool: D55:            pz[0] = %p, pz[0] + 1 = %p


tool: D24:              *pz = %p, *pz + 1 = %p


tool: D60:         pz[0][0] = %d


tool: D68:           *pz[0] = %d


tool: D22:             **pz = %d


tool: D1:         pz[2][1] = %d


tool: D3: *(*(pz + 2) + 1) = %d


assistant: ```c
int main(void) {
  int zippo[4][2] = {{2, 4}, {6, 8}, {1, 3}, {5, 7}};
  int(*pz)[2];
  pz = zippo;
  printf("              pz = %p, pz + 1 = %p\n", pz, pz + 1);
  printf("           pz[0] = %p, pz[0] + 1 = %p\n", pz[0], pz[0] + 1);
  printf("             *pz = %p, *pz + 1 = %p\n", *pz, *pz + 1);
  printf("        pz[0][0] = %d\n", pz[0][0]);
  printf("          *pz[0] = %d\n", *pz[0]);
  printf("            **pz = %d\n", **pz);
  printf("        pz[2][1] = %d\n", pz[2][1]);
  printf("*(*(pz + 2) + 1) = %d\n", *(*(pz + 2) + 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D49(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  movdqa D91(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D61(%rip),%xmm0
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D49
data_type: string
name: disassemble_data
arguments: data_label: D91
data_type: byte[16]
name: disassemble_data
arguments: data_label: D61
data_type: byte[16]
name: disassemble_data
arguments: data_label: D33
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D75
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D47
data_type: string
name: disassemble_data
arguments: data_label: D42
data_type: string
name: disassemble_data
arguments: data_label: D48
data_type: string

tool: D49:               pz = %p, pz + 1 = %p


tool: {"D91": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D61": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: D33:            pz[0] = %p, pz[0] + 1 = %p


tool: D0:              *pz = %p, *pz + 1 = %p


tool: D75:         pz[0][0] = %d


tool: D23:           *pz[0] = %d


tool: D47:             **pz = %d


tool: D42:         pz[2][1] = %d


tool: D48: *(*(pz + 2) + 1) = %d


assistant: ```c
int main(void) {
  int zippo[4][2] = {{2, 4}, {6, 8}, {1, 3}, {5, 7}};
  int(*pz)[2];
  pz = zippo;
  printf("              pz = %p, pz + 1 = %p\n", pz, pz + 1);
  printf("           pz[0] = %p, pz[0] + 1 = %p\n", pz[0], pz[0] + 1);
  printf("             *pz = %p, *pz + 1 = %p\n", *pz, *pz + 1);
  printf("        pz[0][0] = %d\n", pz[0][0]);
  printf("          *pz[0] = %d\n", *pz[0]);
  printf("            **pz = %d\n", **pz);
  printf("        pz[2][1] = %d\n", pz[2][1]);
  printf("*(*(pz + 2) + 1) = %d\n", *(*(pz + 2) + 1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<head>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string

tool: D13: 


r4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor


tool: D1: Copyright 2014


tool: D22: All Rights Reserved


tool: D39: --------------------------------------------------------------


assistant: ```c
void head() {
  printf("\n\n\nr4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor\n");
  printf("Copyright 2014\n");
  printf("All Rights Reserved\n");
  printf("--------------------------------------------------------------\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<head>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D17
type: string
name: parse_data
arguments: tag: D24
type: string

tool: D4: 


r4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor


tool: D11: Copyright 2014


tool: D17: All Rights Reserved


tool: D24: --------------------------------------------------------------


assistant: ```c
void head() {
  printf("\n\n\nr4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor\n");
  printf("Copyright 2014\n");
  printf("All Rights Reserved\n");
  printf("--------------------------------------------------------------\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<head>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D38
datatype: string

tool: D39: 


r4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor


tool: D37: Copyright 2014


tool: D17: All Rights Reserved


tool: D38: --------------------------------------------------------------


assistant: ```c
void head() {
  printf("\n\n\nr4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor\n");
  printf("Copyright 2014\n");
  printf("All Rights Reserved\n");
  printf("--------------------------------------------------------------\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<head>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D17
type: string
name: unpack_data
arguments: label: D0
type: string

tool: D20: 


r4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor


tool: D28: Copyright 2014


tool: D17: All Rights Reserved


tool: D0: --------------------------------------------------------------


assistant: ```c
void head() {
  printf("\n\n\nr4iD-ftw's Columnar Transposition Cipher Encryptor/Decryptor\n");
  printf("Copyright 2014\n");
  printf("All Rights Reserved\n");
  printf("--------------------------------------------------------------\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_irq_nr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2020(%rbp)
  movl   $0x4,-0x201c(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x2018(%rbp)
  cmpq   $0x0,-0x2018(%rbp)
  jne    L43
  mov    $0x0,%eax
  jmp    L4
L69:
  lea    -0x2010(%rbp),%rax
  mov    $0x5,%edx
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L43
  jmp    L7
L18:
  addl   $0x1,-0x2020(%rbp)
  mov    -0x201c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  lea    -0x2010(%rbp),%rax
  add    %rdx,%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,%edx
  mov    -0x201c(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x201c(%rbp)
L7:
  lea    -0x2010(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x201c(%rbp)
  jl     L18
L43:
  mov    -0x2018(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    $0x2000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L69
  mov    -0x2018(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x2020(%rbp),%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D20
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string

tool: D2: r

tool: D27: /proc/stat

tool: D20: intr 

tool: D10:  

assistant: ```c
int get_irq_nr(void) {
  FILE *fp;
  char line[8192];
  int in = 0;
  int pos = 4;
  if ((fp = fopen("/proc/stat", "r")) == NULL)
    return 0;
  while (fgets(line, 8192, fp) != NULL) {
    if (!strncmp(line, "intr ", 5)) {
      while (pos < strlen(line)) {
        in++;
        pos += strcspn(line + pos + 1, " ") + 1;
      }
    }
  }
  fclose(fp);
  return in;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_irq_nr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L39
  mov    %rax,%r12
  mov    $0x4,%ebp
  mov    $0x0,%r14d
  lea    D13(%rip),%r13
  mov    %rsp,%rbx
  lea    D14(%rip),%r15
L28:
  mov    %r12,%rdx
  mov    $0x2000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L0
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L28
  jmp    L45
L52:
  add    $0x1,%r14d
  movslq %ebp,%rax
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %r15,%rsi
  call   <strcspn@plt>
  lea    0x1(%rbp,%rax,1),%ebp
L45:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L52
  jmp    L28
L0:
  mov    %r12,%rdi
  call   <fclose@plt>
L2:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  mov    %r14d,%eax
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    $0x0,%r14d
  jmp    L2
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D8: r

tool: D0: /proc/stat

tool: D13: intr 

tool: D14:  

assistant: ```c
int get_irq_nr(void) {
  FILE *fp;
  char line[8192];
  int in = 0;
  int pos = 4;
  if ((fp = fopen("/proc/stat", "r")) == NULL)
    return 0;
  while (fgets(line, 8192, fp) != NULL) {
    if (!strncmp(line, "intr ", 5)) {
      while (pos < strlen(line)) {
        in++;
        pos += strcspn(line + pos + 1, " ") + 1;
      }
    }
  }
  fclose(fp);
  return in;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_irq_nr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D26(%rip),%rsi
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%r12
  mov    $0x4,%ebp
  xor    %r14d,%r14d
  mov    %rsp,%rbx
  lea    D25(%rip),%r13
  lea    D35(%rip),%r15
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L23
L55:
  mov    %r12,%rdx
  mov    $0x2000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L20
  mov    %r12,%rdi
  call   <fclose@plt>
L68:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x2018,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  movslq %ebp,%rax
  mov    %r15,%rsi
  add    $0x1,%r14d
  lea    0x1(%rbx,%rax,1),%rdi
  call   <strcspn@plt>
  lea    0x1(%rbp,%rax,1),%ebp
L23:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L16
  jmp    L55
  cs nopw 0x0(%rax,%rax,1)
L6:
  xor    %r14d,%r14d
  jmp    L68
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D26
type: string
name: disassemble_data
arguments: tag: D29
type: string
name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D35
type: string

tool: D26: r

tool: D29: /proc/stat

tool: D25: intr 

tool: D35:  

assistant: ```c
int get_irq_nr(void) {
  FILE *fp;
  char line[8192];
  int in = 0;
  int pos = 4;
  if ((fp = fopen("/proc/stat", "r")) == NULL)
    return 0;
  while (fgets(line, 8192, fp) != NULL) {
    if (!strncmp(line, "intr ", 5)) {
      while (pos < strlen(line)) {
        in++;
        pos += strcspn(line + pos + 1, " ") + 1;
      }
    }
  }
  fclose(fp);
  return in;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_irq_nr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D11(%rip),%rsi
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L77
  mov    %rax,%r12
  mov    $0x4,%ebp
  xor    %r14d,%r14d
  mov    %rsp,%rbx
  lea    D14(%rip),%r13
  lea    D28(%rip),%r15
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L53
L39:
  mov    %r12,%rdx
  mov    $0x2000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12,%rdi
  call   <fclose@plt>
L75:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x2018,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L59:
  movslq %ebp,%rax
  mov    %r15,%rsi
  add    $0x1,%r14d
  lea    0x1(%rbx,%rax,1),%rdi
  call   <strcspn@plt>
  lea    0x1(%rbp,%rax,1),%ebp
L53:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L59
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L77:
  xor    %r14d,%r14d
  jmp    L75
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D28
type: string

tool: D11: r

tool: D8: /proc/stat

tool: D14: intr 

tool: D28:  

assistant: ```c
int get_irq_nr(void) {
  FILE *fp;
  char line[8192];
  int in = 0;
  int pos = 4;
  if ((fp = fopen("/proc/stat", "r")) == NULL)
    return 0;
  while (fgets(line, 8192, fp) != NULL) {
    if (!strncmp(line, "intr ", 5)) {
      while (pos < strlen(line)) {
        in++;
        pos += strcspn(line + pos + 1, " ") + 1;
      }
    }
  }
  fclose(fp);
  return in;
}
```
user: What is the c source code of the assembly code below?

```asm
<mat2_identity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  D10(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  D10(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: byte[4]

tool: {"D10": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat2_identity(float *dst) {
  dst[0] = 1;
  dst[3] = 1;
}
```