ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hoare_partition>:
  endbr64
  movslq %edx,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  cmp    %edx,%esi
  jge    L35
  sub    $0x1,%edx
  movslq %esi,%rax
  sub    %esi,%edx
  lea    (%rdi,%rax,4),%rbx
  add    %rax,%rdx
  lea    0x4(%rdi,%rdx,4),%r14
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x4,%rbx
  cmp    %rbx,%r14
  je     L35
L47:
  mov    0x0(%rbp),%eax
  cmp    %eax,(%rbx)
  jge    L8
  movslq %r12d,%rax
  mov    %rbx,%rsi
  add    $0x4,%rbx
  add    $0x1,%r12d
  lea    0x0(%r13,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%r14
  jne    L47
L35:
  movslq %r12d,%rax
  mov    %rbp,%rsi
  lea    0x0(%r13,%rax,4),%rdi
  call   <swap@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int hoare_partition(register int a[], register int left, register int right) {
  register int pivot = left;
  while (left < right) {
    if (*(a + left) < *(a + right)) {
      swap(a + pivot, a + left);
      pivot++;
    }
    left++;
  }
  swap((a + pivot), (a + right));
  return pivot;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hoare_partition>:
  endbr64
  movslq %edx,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  cmp    %edx,%esi
  jge    L46
  sub    $0x1,%edx
  movslq %esi,%rax
  sub    %esi,%edx
  lea    (%rdi,%rax,4),%rbx
  add    %rax,%rdx
  lea    0x4(%rdi,%rdx,4),%r14
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x4,%rbx
  cmp    %rbx,%r14
  je     L46
L28:
  mov    0x0(%rbp),%eax
  cmp    %eax,(%rbx)
  jge    L33
  movslq %r12d,%rax
  mov    %rbx,%rsi
  add    $0x4,%rbx
  add    $0x1,%r12d
  lea    0x0(%r13,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%r14
  jne    L28
L46:
  movslq %r12d,%rax
  mov    %rbp,%rsi
  lea    0x0(%r13,%rax,4),%rdi
  call   <swap@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int hoare_partition(register int a[], register int left, register int right) {
  register int pivot = left;
  while (left < right) {
    if (*(a + left) < *(a + right)) {
      swap(a + pivot, a + left);
      pivot++;
    }
    left++;
  }
  swap((a + pivot), (a + right));
  return pivot;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(long long int *p, long long int *q) {
#pragma omp taskgroup task_reduction(* : p[0])
  {
#pragma omp task in_reduction(* : p[0])
    bar(p);
#pragma omp task in_reduction(* : p[0])
    bar(p);
    bar(p);
#pragma omp taskgroup task_reduction(* : q[0])
    {
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
      bar(q);
#pragma omp task in_reduction(* : p[0])
      {
#pragma omp taskgroup task_reduction(* : p[0])
        {
#pragma omp task in_reduction(* : p[0])
          bar(p);
          p[0] *= 2;
#pragma omp task in_reduction(* : p[0])
          bar(p);
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <bar@plt>
  mov    %rbx,%rdi
  call   <bar@plt>
  mov    %rbx,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbx,%rdi
  call   <bar@plt>
  shlq   (%rbx)
  mov    %rbx,%rdi
  call   <bar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo(long long int *p, long long int *q) {
#pragma omp taskgroup task_reduction(* : p[0])
  {
#pragma omp task in_reduction(* : p[0])
    bar(p);
#pragma omp task in_reduction(* : p[0])
    bar(p);
    bar(p);
#pragma omp taskgroup task_reduction(* : q[0])
    {
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
      bar(q);
#pragma omp task in_reduction(* : p[0])
      {
#pragma omp taskgroup task_reduction(* : p[0])
        {
#pragma omp task in_reduction(* : p[0])
          bar(p);
          p[0] *= 2;
#pragma omp task in_reduction(* : p[0])
          bar(p);
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  shlq   0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(long long int *p, long long int *q) {
#pragma omp taskgroup task_reduction(* : p[0])
  {
#pragma omp task in_reduction(* : p[0])
    bar(p);
#pragma omp task in_reduction(* : p[0])
    bar(p);
    bar(p);
#pragma omp taskgroup task_reduction(* : q[0])
    {
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
      bar(q);
#pragma omp task in_reduction(* : p[0])
      {
#pragma omp taskgroup task_reduction(* : p[0])
        {
#pragma omp task in_reduction(* : p[0])
          bar(p);
          p[0] *= 2;
#pragma omp task in_reduction(* : p[0])
          bar(p);
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %r12,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  call   <bar@plt>
  shlq   0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <bar@plt>
```

assistant: ```c
void foo(long long int *p, long long int *q) {
#pragma omp taskgroup task_reduction(* : p[0])
  {
#pragma omp task in_reduction(* : p[0])
    bar(p);
#pragma omp task in_reduction(* : p[0])
    bar(p);
    bar(p);
#pragma omp taskgroup task_reduction(* : q[0])
    {
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
#pragma omp task in_reduction(* : q[0])
      bar(q);
      bar(q);
#pragma omp task in_reduction(* : p[0])
      {
#pragma omp taskgroup task_reduction(* : p[0])
        {
#pragma omp task in_reduction(* : p[0])
          bar(p);
          p[0] *= 2;
#pragma omp task in_reduction(* : p[0])
          bar(p);
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_home_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <get_passwd_entry@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  jmp    L5
L18:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
char *get_home_dir(uid_t uid) {
  struct passwd *passwd_entry = get_passwd_entry(uid);
  if (passwd_entry != NULL) {
    return passwd_entry->pw_dir;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <get_passwd_entry@plt>
  test   %rax,%rax
  je     L6
  mov    (%rax),%rax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_home_dir(uid_t uid) {
  struct passwd *passwd_entry = get_passwd_entry(uid);
  if (passwd_entry != NULL) {
    return passwd_entry->pw_dir;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <get_passwd_entry@plt>
  test   %rax,%rax
  je     L0
  mov    (%rax),%rax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_home_dir(uid_t uid) {
  struct passwd *passwd_entry = get_passwd_entry(uid);
  if (passwd_entry != NULL) {
    return passwd_entry->pw_dir;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <get_passwd_entry@plt>
  test   %rax,%rax
  je     L3
  mov    (%rax),%rax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_home_dir(uid_t uid) {
  struct passwd *passwd_entry = get_passwd_entry(uid);
  if (passwd_entry != NULL) {
    return passwd_entry->pw_dir;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *px, int *py) {
  int tmp = *px;
  *px = *py;
  *py = tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *px, int *py) {
  int tmp = *px;
  *px = *py;
  *py = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *px, int *py) {
  int tmp = *px;
  *px = *py;
  *py = tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *px, int *py) {
  int tmp = *px;
  *px = *py;
  *py = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strisalpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L4
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  jmp    L7
L1:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int strisalpha(const char *str) {
  for (; *str; str++)
    if (!isalpha(*str))
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strisalpha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L15
L4:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L18
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L4
  mov    $0x1,%eax
L18:
  pop    %rbx
  ret
L15:
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
int strisalpha(const char *str) {
  for (; *str; str++)
    if (!isalpha(*str))
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strisalpha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L24
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L26
L24:
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L2
  pop    %rbx
  ret
L26:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strisalpha(const char *str) {
  for (; *str; str++)
    if (!isalpha(*str))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strisalpha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L0
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L28:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L27
L0:
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L28
  pop    %rbx
  ret
L27:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int strisalpha(const char *str) {
  for (; *str; str++)
    if (!isalpha(*str))
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L11
  mov    -0x10(%rbp),%eax
  cmp    $0xc,%eax
  jg     L11
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L11
  mov    -0xc(%rbp),%eax
  cmp    $0x3b,%eax
  jg     L11
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L11:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L39
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L39
  mov    -0xc(%rbp),%eax
  cmp    $0x3b,%eax
  jg     L39
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  lea    0xc(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L39:
  mov    -0x10(%rbp),%eax
  cmp    $0xc,%eax
  jle    L18
  mov    -0x10(%rbp),%eax
  cmp    $0x18,%eax
  jg     L18
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L18
  mov    -0xc(%rbp),%eax
  cmp    $0x3b,%eax
  jg     L18
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  lea    -0xc(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L18:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L81:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L105
  call   <__stack_chk_fail@plt>
L105:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D39
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D39: Enter a 24-hour time: 

tool: D3: %d:%d

tool: D19: Equivalent 12-hour time: %d:%.2d AM


tool: D12: Equivalent 12-hour time: %d:%.2d PM


tool: D14: Not a valid time

assistant: ```c
int main(void) {
  int hrs, mins;
  printf("Enter a 24-hour time: ");
  scanf("%d:%d", &hrs, &mins);
  if (hrs > 0 && hrs <= 12 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs, mins);
  } else if (hrs == 0 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs + 12, mins);
  } else if (hrs > 12 && hrs <= 24 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d PM\n", hrs - 12, mins);
  } else {
    printf("Not a valid time\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L56
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  jbe    L8
L57:
  lea    D37(%rip),%rdi
  call   <puts@plt>
L83:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L56:
  test   %esi,%esi
  jne    L43
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L57
  mov    $0xc,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L43:
  lea    -0xd(%rsi),%eax
  cmp    $0xb,%eax
  ja     L57
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L57
  sub    $0xc,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D59
type_infered: string
name: extract_symbolic_data
arguments: data_label: D37
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D49
type_infered: string

tool: D20: Enter a 24-hour time: 

tool: D59: %d:%d

tool: D37: Not a valid time

tool: D17: Equivalent 12-hour time: %d:%.2d AM


tool: D49: Equivalent 12-hour time: %d:%.2d PM


assistant: ```c
int main(void) {
  int hrs, mins;
  printf("Enter a 24-hour time: ");
  scanf("%d:%d", &hrs, &mins);
  if (hrs > 0 && hrs <= 12 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs, mins);
  } else if (hrs == 0 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs + 12, mins);
  } else if (hrs > 12 && hrs <= 24 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d PM\n", hrs - 12, mins);
  } else {
    printf("Not a valid time\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L3
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  jbe    L13
L82:
  lea    D21(%rip),%rdi
  call   <puts@plt>
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  test   %esi,%esi
  jne    L15
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L82
  mov    $0xc,%esi
L13:
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L34
L15:
  lea    -0xd(%rsi),%eax
  cmp    $0xb,%eax
  ja     L82
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L82
  sub    $0xc,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L34
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D46
datatype: string
name: parse_data
arguments: data_tag: D39
datatype: string

tool: D38: Enter a 24-hour time: 

tool: D8: %d:%d

tool: D21: Not a valid time

tool: D46: Equivalent 12-hour time: %d:%.2d AM


tool: D39: Equivalent 12-hour time: %d:%.2d PM


assistant: ```c
int main(void) {
  int hrs, mins;
  printf("Enter a 24-hour time: ");
  scanf("%d:%d", &hrs, &mins);
  if (hrs > 0 && hrs <= 12 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs, mins);
  } else if (hrs == 0 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs + 12, mins);
  } else if (hrs > 12 && hrs <= 24 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d PM\n", hrs - 12, mins);
  } else {
    printf("Not a valid time\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D35(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L43
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  jbe    L6
L26:
  lea    D16(%rip),%rdi
  call   <puts@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L43:
  test   %esi,%esi
  jne    L59
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L26
  mov    $0xc,%esi
L6:
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L21
L59:
  lea    -0xd(%rsi),%eax
  cmp    $0xb,%eax
  ja     L26
  mov    0x4(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L26
  sub    $0xc,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L21
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D49
data_type: string

tool: D35: Enter a 24-hour time: 

tool: D18: %d:%d

tool: D16: Not a valid time

tool: D46: Equivalent 12-hour time: %d:%.2d AM


tool: D49: Equivalent 12-hour time: %d:%.2d PM


assistant: ```c
int main(void) {
  int hrs, mins;
  printf("Enter a 24-hour time: ");
  scanf("%d:%d", &hrs, &mins);
  if (hrs > 0 && hrs <= 12 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs, mins);
  } else if (hrs == 0 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d AM\n", hrs + 12, mins);
  } else if (hrs > 12 && hrs <= 24 && (mins >= 0 && mins < 60)) {
    printf("Equivalent 12-hour time: %d:%.2d PM\n", hrs - 12, mins);
  } else {
    printf("Not a valid time\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<psvec2i_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vec2i_negative@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_negative(struct vec2i *result, struct vec2i *a) {
  vec2i_negative((int32_t *)result, (int32_t *)a);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<psvec2i_negative>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec2i_negative@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_negative(struct vec2i *result, struct vec2i *a) {
  vec2i_negative((int32_t *)result, (int32_t *)a);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<psvec2i_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2i_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_negative(struct vec2i *result, struct vec2i *a) {
  vec2i_negative((int32_t *)result, (int32_t *)a);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<psvec2i_negative>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2i_negative@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2i *psvec2i_negative(struct vec2i *result, struct vec2i *a) {
  vec2i_negative((int32_t *)result, (int32_t *)a);
  return result;
}
```