ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<printBubbleSort>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  call   <printArray@plt>
  mov    0xc(%rsp),%edi
  lea    0x1(%rdi),%ebp
  test   %edi,%edi
  jg     L58
  jmp    L27
  nopl   0x0(%rax)
L16:
  cmp    %r15d,%ebx
  je     L36
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L36:
  add    $0x1,%r15
  cmp    %rbp,%r15
  je     L27
L58:
  lea    -0x1(%r15),%eax
  cmp    %ebx,%eax
  jne    L16
  mov    (%r12,%r15,4),%eax
  lea    D31(%rip),%rsi
  cmp    %eax,-0x4(%r12,%r15,4)
  mov    %r14,%rdi
  cmovle %r13,%rsi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L58
L27:
  add    $0x18,%rsp
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D20:  |%s|  

tool: D3:     

tool: D31: swap

tool: D1: 


assistant: ```c
void printBubbleSort(int len, int array[], int pos) {
  printArray(len, array);
  int i = 0;
  while (i < len) {
    if (i == pos) {
      printf(" |%s|  ", array[i] > array[i + 1] ? "swap" : "    ");
    } else if (i + 1 != pos) {
      printf("    ");
    }
    i++;
  }
  printf("\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printBubbleSort>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  call   <printArray@plt>
  mov    0xc(%rsp),%edi
  lea    0x1(%rdi),%ebp
  test   %edi,%edi
  jg     L11
  jmp    L14
  nopl   0x0(%rax)
L50:
  cmp    %r15d,%ebx
  je     L48
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L48:
  add    $0x1,%r15
  cmp    %rbp,%r15
  je     L14
L11:
  lea    -0x1(%r15),%eax
  cmp    %eax,%ebx
  jne    L50
  mov    (%r12,%r15,4),%eax
  lea    D0(%rip),%rsi
  cmp    %eax,-0x4(%r12,%r15,4)
  mov    %r14,%rdi
  cmovle %r13,%rsi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %rbp,%r15
  jne    L11
L14:
  add    $0x18,%rsp
  lea    D30(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D30
data_type: string

tool: D25:  |%s|  

tool: D16:     

tool: D0: swap

tool: D30: 


assistant: ```c
void printBubbleSort(int len, int array[], int pos) {
  printArray(len, array);
  int i = 0;
  while (i < len) {
    if (i == pos) {
      printf(" |%s|  ", array[i] > array[i + 1] ? "swap" : "    ");
    } else if (i + 1 != pos) {
      printf("    ");
    }
    i++;
  }
  printf("\n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<close_noeintr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  nop
L1:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L14
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L1
L14:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int close_noeintr(int fd) {
  int ret;
  while ((ret = close(fd)) == -1 && errno == EINTR)
    ;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<close_noeintr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L11:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  jne    L19
  mov    D10(%rip),%rcx
  mov    D15(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L11
L19:
  pop    %rbx
  ret
```

assistant: ```c
int close_noeintr(int fd) {
  int ret;
  while ((ret = close(fd)) == -1 && errno == EINTR)
    ;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<close_noeintr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L22
  nopl   0x0(%rax)
L3:
  mov    D10(%rip),%rdx
  mov    D11(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L14
L22:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  je     L3
L14:
  pop    %rbx
  ret
```

assistant: ```c
int close_noeintr(int fd) {
  int ret;
  while ((ret = close(fd)) == -1 && errno == EINTR)
    ;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<close_noeintr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  jmp    L14
  nopl   0x0(%rax)
L3:
  mov    D7(%rip),%rdx
  mov    D6(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L7
L14:
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  je     L3
L7:
  pop    %rbx
  ret
```

assistant: ```c
int close_noeintr(int fd) {
  int ret;
  while ((ret = close(fd)) == -1 && errno == EINTR)
    ;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rte_mov64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rte_mov16@plt>
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rte_mov16@plt>
  mov    -0x10(%rbp),%rax
  lea    0x80(%rax),%rdx
  mov    -0x8(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rte_mov16@plt>
  mov    -0x10(%rbp),%rax
  lea    0xc0(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0xc0,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rte_mov16@plt>
  nop
  leave
  ret
```

assistant: ```c
void rte_mov64(uint8_t *dst, const uint8_t *src) {
  rte_mov16((uint8_t *)dst + 0 * 16, (const uint8_t *)src + 0 * 16);
  rte_mov16((uint8_t *)dst + 1 * 16, (const uint8_t *)src + 1 * 16);
  rte_mov16((uint8_t *)dst + 2 * 16, (const uint8_t *)src + 2 * 16);
  rte_mov16((uint8_t *)dst + 3 * 16, (const uint8_t *)src + 3 * 16);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rte_mov64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <rte_mov16@plt>
  lea    0x40(%rbp),%rsi
  lea    0x40(%rbx),%rdi
  call   <rte_mov16@plt>
  lea    0x80(%rbp),%rsi
  lea    0x80(%rbx),%rdi
  call   <rte_mov16@plt>
  lea    0xc0(%rbp),%rsi
  lea    0xc0(%rbx),%rdi
  call   <rte_mov16@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rte_mov64(uint8_t *dst, const uint8_t *src) {
  rte_mov16((uint8_t *)dst + 0 * 16, (const uint8_t *)src + 0 * 16);
  rte_mov16((uint8_t *)dst + 1 * 16, (const uint8_t *)src + 1 * 16);
  rte_mov16((uint8_t *)dst + 2 * 16, (const uint8_t *)src + 2 * 16);
  rte_mov16((uint8_t *)dst + 3 * 16, (const uint8_t *)src + 3 * 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rte_mov64>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <rte_mov16@plt>
  lea    0x40(%rbp),%rsi
  lea    0x40(%rbx),%rdi
  call   <rte_mov16@plt>
  lea    0x80(%rbp),%rsi
  lea    0x80(%rbx),%rdi
  call   <rte_mov16@plt>
  add    $0x8,%rsp
  lea    0xc0(%rbp),%rsi
  lea    0xc0(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <rte_mov16@plt>
```

assistant: ```c
void rte_mov64(uint8_t *dst, const uint8_t *src) {
  rte_mov16((uint8_t *)dst + 0 * 16, (const uint8_t *)src + 0 * 16);
  rte_mov16((uint8_t *)dst + 1 * 16, (const uint8_t *)src + 1 * 16);
  rte_mov16((uint8_t *)dst + 2 * 16, (const uint8_t *)src + 2 * 16);
  rte_mov16((uint8_t *)dst + 3 * 16, (const uint8_t *)src + 3 * 16);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rte_mov64>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <rte_mov16@plt>
  lea    0x40(%rbp),%rsi
  lea    0x40(%rbx),%rdi
  call   <rte_mov16@plt>
  lea    0x80(%rbp),%rsi
  lea    0x80(%rbx),%rdi
  call   <rte_mov16@plt>
  add    $0x8,%rsp
  lea    0xc0(%rbp),%rsi
  lea    0xc0(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <rte_mov16@plt>
```

assistant: ```c
void rte_mov64(uint8_t *dst, const uint8_t *src) {
  rte_mov16((uint8_t *)dst + 0 * 16, (const uint8_t *)src + 0 * 16);
  rte_mov16((uint8_t *)dst + 1 * 16, (const uint8_t *)src + 1 * 16);
  rte_mov16((uint8_t *)dst + 2 * 16, (const uint8_t *)src + 2 * 16);
  rte_mov16((uint8_t *)dst + 3 * 16, (const uint8_t *)src + 3 * 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  mov    %eax,%edx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  mov    %eax,%edx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  mov    %eax,%edx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L8:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L8
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L16
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L16:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x44(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x44(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void swap_values(void *a, void *b, unsigned size) {
  char tmp[size];
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %edx,%eax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L4
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L4:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L22
  orq    $0x0,-0x8(%rsp,%rdx,1)
L22:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_values(void *a, void *b, unsigned size) {
  char tmp[size];
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %edx,%eax
  mov    %rsp,%rdx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rdx
  cmp    %rdx,%rsp
  je     L41
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L1
L41:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L10
L33:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L33
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_values(void *a, void *b, unsigned size) {
  char tmp[size];
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %edx,%eax
  mov    %rsp,%rdx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rdx
  cmp    %rdx,%rsp
  je     L40
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L1
L40:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L27
L12:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L27:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L12
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_values(void *a, void *b, unsigned size) {
  char tmp[size];
  memcpy(tmp, a, size);
  memcpy(a, b, size);
  memcpy(b, tmp, size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ef_cmp_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int ef_cmp_strings(const void *v1, const void *v2) {
  char *const *s1 = (char *const *)v1;
  char *const *s2 = (char *const *)v2;
  return strcmp(*s1, *s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ef_cmp_strings>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ef_cmp_strings(const void *v1, const void *v2) {
  char *const *s1 = (char *const *)v1;
  char *const *s2 = (char *const *)v2;
  return strcmp(*s1, *s2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ef_cmp_strings>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int ef_cmp_strings(const void *v1, const void *v2) {
  char *const *s1 = (char *const *)v1;
  char *const *s2 = (char *const *)v2;
  return strcmp(*s1, *s2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ef_cmp_strings>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int ef_cmp_strings(const void *v1, const void *v2) {
  char *const *s1 = (char *const *)v1;
  char *const *s2 = (char *const *)v2;
  return strcmp(*s1, *s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<glmATanD3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glmATan3f@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <glmDegrees3f_@plt>
  nop
  leave
  ret
```

assistant: ```c
void glmATanD3f(float out[3], const float x[3]) {
  glmATan3f(out, x);
  glmDegrees3f_(out);
}
```
user: What is the c source code of the assembly code below:

```asm
<glmATanD3f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <glmATan3f@plt>
  mov    %rbx,%rdi
  call   <glmDegrees3f_@plt>
  pop    %rbx
  ret
```

assistant: ```c
void glmATanD3f(float out[3], const float x[3]) {
  glmATan3f(out, x);
  glmDegrees3f_(out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glmATanD3f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmATan3f@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <glmDegrees3f_@plt>
```

assistant: ```c
void glmATanD3f(float out[3], const float x[3]) {
  glmATan3f(out, x);
  glmDegrees3f_(out);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<glmATanD3f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmATan3f@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <glmDegrees3f_@plt>
```

assistant: ```c
void glmATanD3f(float out[3], const float x[3]) {
  glmATan3f(out, x);
  glmDegrees3f_(out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <f2@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x30,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
int f1() {
  int one;
  int two;
  int x;
  one = two;
  assert(one - two == 0);
  assert(one == two);
  x = f2(one, two);
  assert(one - two == 0);
  assert(one == two);
  assert(x == 48);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f1>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  mov    %edi,%esi
  call   <f2@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  cmp    $0x30,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  ret
```

assistant: ```c
int f1() {
  int one;
  int two;
  int x;
  one = two;
  assert(one - two == 0);
  assert(one == two);
  x = f2(one, two);
  assert(one - two == 0);
  assert(one == two);
  assert(x == 48);
}
```
user: What is the c source code of the assembly code below:

```asm
<f1>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  mov    %edi,%esi
  call   <f2@plt>
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x30,%ebx
  pop    %rbx
  sete   %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
int f1() {
  int one;
  int two;
  int x;
  one = two;
  assert(one - two == 0);
  assert(one == two);
  x = f2(one, two);
  assert(one - two == 0);
  assert(one == two);
  assert(x == 48);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f1>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  mov    %edi,%esi
  call   <f2@plt>
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x30,%ebx
  pop    %rbx
  sete   %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
int f1() {
  int one;
  int two;
  int x;
  one = two;
  assert(one - two == 0);
  assert(one == two);
  x = f2(one, two);
  assert(one - two == 0);
  assert(one == two);
  assert(x == 48);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep1@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D7: start.....

tool: D9: end.....

assistant: ```c
int main(void) {
  printf("start.....");
  sleep1(2);
  printf("end.....");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep1@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D8: start.....

tool: D11: end.....

assistant: ```c
int main(void) {
  printf("start.....");
  sleep1(2);
  printf("end.....");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep1@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D12: start.....

tool: D10: end.....

assistant: ```c
int main(void) {
  printf("start.....");
  sleep1(2);
  printf("end.....");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <sleep1@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D19
type: string

tool: D11: start.....

tool: D19: end.....

assistant: ```c
int main(void) {
  printf("start.....");
  sleep1(2);
  printf("end.....");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_quaddobl_target_solutions_to_container>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x109,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_quaddobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(265, a, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_quaddobl_target_solutions_to_container>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x109,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_quaddobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(265, a, b, c, 0);
  return fail;
}
```