ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<lineCoincide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L112:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L78
  movl   $0x0,-0x4(%rbp)
  jmp    L79
L35:
  cmpl   $0x0,-0x4(%rbp)
  jne    L125
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  and    $0xf,%eax
  mov    %al,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  and    $0xf,%eax
  mov    %al,-0xd(%rbp)
  jmp    L137
L125:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  mov    %al,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  mov    %al,-0xd(%rbp)
L137:
  movzbl -0xe(%rbp),%eax
  or     -0xd(%rbp),%al
  cmp    $0xc,%al
  jne    L84
  movl   $0x0,-0x8(%rbp)
  jmp    L65
L84:
  movzbl -0xe(%rbp),%eax
  cmp    -0xd(%rbp),%al
  je     L65
  cmpb   $0x4,-0xe(%rbp)
  je     L65
  cmpb   $0x8,-0xd(%rbp)
  je     L65
  cmpb   $0x4,-0xd(%rbp)
  je     L65
  cmpb   $0x8,-0xe(%rbp)
  je     L65
  movl   $0x0,-0x8(%rbp)
L65:
  addl   $0x1,-0x4(%rbp)
L79:
  cmpl   $0x1,-0x4(%rbp)
  jle    L35
L78:
  addl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L112
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lineCoincide(start1, start2)
unsigned char *start1, *start2;
{
  int i, count, split;
  unsigned char val_11, val_12;
  count = 1;
  for (i = 0; i < 64; i++) {
    if (start1[i] != start2[i]) {
      for (split = 0; split < 2; split++) {
        if (split == 0) {
          val_11 = (start1[i]) & 0x0f;
          val_12 = (start2[i]) & 0x0f;
        } else {
          val_11 = (start1[i] >> 4) & 0x0f;
          val_12 = (start2[i] >> 4) & 0x0f;
        }
        if ((val_11 | val_12) == (0x04 | 0x08)) {
          count = 0;
        } else if ((val_11 != val_12) && (val_11 != 0x04 && val_12 != 0x08 && val_12 != 0x04 && val_11 != 0x08)) {
          count = 0;
        }
      }
    }
  }
  return (count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lineCoincide>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r11
  mov    $0x0,%eax
  mov    $0x1,%r12d
  mov    $0x0,%r13d
  jmp    L43
L47:
  cmp    $0xc,%dil
  je     L36
  mov    %ecx,%r8d
  mov    %edx,%r14d
  cmp    %dl,%cl
  jne    L30
  jmp    L75
L41:
  mov    $0x0,%r12d
L132:
  cmp    $0x1,%esi
  jg     L107
L75:
  add    $0x1,%esi
L122:
  cmp    $0x1,%esi
  je     L47
  cmp    $0xc,%bpl
  je     L41
  cmp    %r9b,%r10b
  je     L132
  mov    %r9d,%r14d
  mov    %r10d,%r8d
L30:
  sub    $0x4,%r8d
  test   $0xfb,%r8b
  je     L132
  sub    $0x4,%r14d
  test   $0xfb,%r14b
  cmovne %r13d,%r12d
  jmp    L132
L36:
  mov    $0x0,%r12d
  jmp    L75
L107:
  add    $0x1,%rax
  cmp    $0x40,%rax
  je     L92
L43:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%r11,%rax,1),%edx
  cmp    %dl,%cl
  je     L107
  mov    %ecx,%r10d
  shr    $0x4,%r10b
  mov    %edx,%r9d
  shr    $0x4,%r9b
  mov    %r10d,%ebp
  or     %r9d,%ebp
  mov    $0x1,%esi
  mov    %ecx,%edi
  or     %edx,%edi
  and    $0xf,%edi
  and    $0xf,%ecx
  and    $0xf,%edx
  jmp    L122
L92:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int lineCoincide(start1, start2)
unsigned char *start1, *start2;
{
  int i, count, split;
  unsigned char val_11, val_12;
  count = 1;
  for (i = 0; i < 64; i++) {
    if (start1[i] != start2[i]) {
      for (split = 0; split < 2; split++) {
        if (split == 0) {
          val_11 = (start1[i]) & 0x0f;
          val_12 = (start2[i]) & 0x0f;
        } else {
          val_11 = (start1[i] >> 4) & 0x0f;
          val_12 = (start2[i] >> 4) & 0x0f;
        }
        if ((val_11 | val_12) == (0x04 | 0x08)) {
          count = 0;
        } else if ((val_11 != val_12) && (val_11 != 0x04 && val_12 != 0x08 && val_12 != 0x04 && val_11 != 0x08)) {
          count = 0;
        }
      }
    }
  }
  return (count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lineCoincide>:
  endbr64
  push   %r14
  mov    %rsi,%r11
  xor    %eax,%eax
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L42
  nop
L85:
  add    $0x1,%rax
  cmp    $0x40,%rax
  je     L15
L42:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%r11,%rax,1),%edx
  cmp    %dl,%cl
  je     L85
  mov    %ecx,%r10d
  mov    %edx,%r9d
  mov    %ecx,%edi
  xor    %esi,%esi
  shr    $0x4,%r10b
  or     %edx,%edi
  shr    $0x4,%r9b
  and    $0xf,%ecx
  mov    %r10d,%ebp
  and    $0xf,%edi
  and    $0xf,%edx
  or     %r9d,%ebp
L120:
  add    $0x1,%esi
  cmp    $0x1,%esi
  je     L30
  cmp    $0xc,%bpl
  je     L91
  cmp    %r9b,%r10b
  je     L108
  mov    %r9d,%r14d
  mov    %r10d,%r8d
L76:
  sub    $0x4,%r8d
  and    $0xfb,%r8d
  je     L108
  sub    $0x4,%r14d
  and    $0xfb,%r14d
  cmovne %r13d,%r12d
L108:
  cmp    $0x2,%esi
  jne    L120
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L42
L15:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    $0xc,%dil
  je     L51
  mov    %ecx,%r8d
  mov    %edx,%r14d
  cmp    %dl,%cl
  jne    L76
  jmp    L120
  nopw   0x0(%rax,%rax,1)
L91:
  xor    %r12d,%r12d
  jmp    L108
  nopl   (%rax)
L51:
  xor    %r12d,%r12d
  jmp    L120
```

assistant: ```c
int lineCoincide(start1, start2)
unsigned char *start1, *start2;
{
  int i, count, split;
  unsigned char val_11, val_12;
  count = 1;
  for (i = 0; i < 64; i++) {
    if (start1[i] != start2[i]) {
      for (split = 0; split < 2; split++) {
        if (split == 0) {
          val_11 = (start1[i]) & 0x0f;
          val_12 = (start2[i]) & 0x0f;
        } else {
          val_11 = (start1[i] >> 4) & 0x0f;
          val_12 = (start2[i] >> 4) & 0x0f;
        }
        if ((val_11 | val_12) == (0x04 | 0x08)) {
          count = 0;
        } else if ((val_11 != val_12) && (val_11 != 0x04 && val_12 != 0x08 && val_12 != 0x04 && val_11 != 0x08)) {
          count = 0;
        }
      }
    }
  }
  return (count);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lineCoincide>:
  endbr64
  mov    %rdi,%r8
  xor    %eax,%eax
  mov    %rsi,%rdi
  mov    $0x1,%r9d
  xor    %r10d,%r10d
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L97:
  add    $0x1,%rax
  cmp    $0x40,%rax
  je     L21
L50:
  movzbl (%r8,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L97
  mov    %edx,%esi
  or     %ecx,%esi
  and    $0xf,%esi
  cmp    $0xc,%sil
  je     L105
  mov    %edx,%esi
  mov    %ecx,%r11d
  and    $0xf,%esi
  and    $0xf,%r11d
  cmp    %r11b,%sil
  je     L19
  sub    $0x4,%esi
  and    $0xfb,%esi
  je     L19
  sub    $0x4,%r11d
  and    $0xfb,%r11d
  cmovne %r10d,%r9d
L19:
  shr    $0x4,%dl
  shr    $0x4,%cl
  mov    %edx,%esi
  or     %ecx,%esi
  cmp    $0xc,%sil
  je     L10
L106:
  cmp    %cl,%dl
  je     L97
  sub    $0x4,%edx
  and    $0xfb,%edx
  je     L97
  sub    $0x4,%ecx
  and    $0xfb,%ecx
  cmovne %r10d,%r9d
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L50
L21:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L105:
  shr    $0x4,%dl
  shr    $0x4,%cl
  xor    %r9d,%r9d
  mov    %edx,%esi
  or     %ecx,%esi
  cmp    $0xc,%sil
  jne    L106
L10:
  xor    %r9d,%r9d
  jmp    L97
```

assistant: ```c
int lineCoincide(start1, start2)
unsigned char *start1, *start2;
{
  int i, count, split;
  unsigned char val_11, val_12;
  count = 1;
  for (i = 0; i < 64; i++) {
    if (start1[i] != start2[i]) {
      for (split = 0; split < 2; split++) {
        if (split == 0) {
          val_11 = (start1[i]) & 0x0f;
          val_12 = (start2[i]) & 0x0f;
        } else {
          val_11 = (start1[i] >> 4) & 0x0f;
          val_12 = (start2[i] >> 4) & 0x0f;
        }
        if ((val_11 | val_12) == (0x04 | 0x08)) {
          count = 0;
        } else if ((val_11 != val_12) && (val_11 != 0x04 && val_12 != 0x08 && val_12 != 0x04 && val_11 != 0x08)) {
          count = 0;
        }
      }
    }
  }
  return (count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <set_tail@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  ;
  void *ptr = malloc(sizeof(char) * 100);
  set_tail(ptr, 0);
  free(ptr);
  ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <set_tail@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  ;
  void *ptr = malloc(sizeof(char) * 100);
  set_tail(ptr, 0);
  free(ptr);
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <set_tail@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  ;
  void *ptr = malloc(sizeof(char) * 100);
  set_tail(ptr, 0);
  free(ptr);
  ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <set_tail@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  ;
  void *ptr = malloc(sizeof(char) * 100);
  set_tail(ptr, 0);
  free(ptr);
  ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crypto_aes_key_expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x10,-0x20(%rbp)
  je     L14
  cmpq   $0x20,-0x20(%rbp)
  jne    L8
L14:
  mov    $0x1,%eax
  jmp    L5
L8:
  mov    $0x0,%eax
L5:
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  mov    -0x8(%rbp),%rax
  jmp    L35
L7:
  nop
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
struct crypto_aes_key *crypto_aes_key_expand(const uint8_t *key, size_t len) {
  AES_KEY *kexp;
  assert((len == 16) || (len == 32));
  if ((kexp = malloc(sizeof(AES_KEY))) == NULL)
    goto err0;
  AES_set_encrypt_key(key, len * 8, kexp);
  return ((void *)kexp);
err0:
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypto_aes_key_expand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    -0x10(%rsi),%rax
  test   $0xffffffffffffffef,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L0
  lea    0x0(,%rbx,8),%rsi
  mov    %rax,%rdx
  mov    %r12,%rdi
  call   <AES_set_encrypt_key@plt>
L0:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct crypto_aes_key *crypto_aes_key_expand(const uint8_t *key, size_t len) {
  AES_KEY *kexp;
  assert((len == 16) || (len == 32));
  if ((kexp = malloc(sizeof(AES_KEY))) == NULL)
    goto err0;
  AES_set_encrypt_key(key, len * 8, kexp);
  return ((void *)kexp);
err0:
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crypto_aes_key_expand>:
  endbr64
  push   %r12
  lea    -0x10(%rsi),%rax
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   $0xffffffffffffffef,%rax
  push   %rbx
  sete   %dil
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  lea    0x0(,%rbx,8),%rsi
  mov    %rax,%rdx
  mov    %rbp,%rdi
  call   <AES_set_encrypt_key@plt>
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct crypto_aes_key *crypto_aes_key_expand(const uint8_t *key, size_t len) {
  AES_KEY *kexp;
  assert((len == 16) || (len == 32));
  if ((kexp = malloc(sizeof(AES_KEY))) == NULL)
    goto err0;
  AES_set_encrypt_key(key, len * 8, kexp);
  return ((void *)kexp);
err0:
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crypto_aes_key_expand>:
  endbr64
  push   %r12
  lea    -0x10(%rsi),%rax
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   $0xffffffffffffffef,%rax
  push   %rbx
  sete   %dil
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  lea    0x0(,%rbx,8),%rsi
  mov    %rax,%rdx
  mov    %rbp,%rdi
  call   <AES_set_encrypt_key@plt>
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct crypto_aes_key *crypto_aes_key_expand(const uint8_t *key, size_t len) {
  AES_KEY *kexp;
  assert((len == 16) || (len == 32));
  if ((kexp = malloc(sizeof(AES_KEY))) == NULL)
    goto err0;
  AES_set_encrypt_key(key, len * 8, kexp);
  return ((void *)kexp);
err0:
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <input@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string

tool: D4: Enter the string: 

tool: D13: The space character was encountered at position %d.


assistant: ```c
int main() {
  printf("Enter the string: ");
  printf("The space character was encountered at position %d.\n", input(1));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <input@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D16: Enter the string: 

tool: D10: The space character was encountered at position %d.


assistant: ```c
int main() {
  printf("Enter the string: ");
  printf("The space character was encountered at position %d.\n", input(1));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <input@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D12
type: string

tool: D18: Enter the string: 

tool: D12: The space character was encountered at position %d.


assistant: ```c
int main() {
  printf("Enter the string: ");
  printf("The space character was encountered at position %d.\n", input(1));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <input@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D19
type_guessed: string

tool: D2: Enter the string: 

tool: D19: The space character was encountered at position %d.


assistant: ```c
int main() {
  printf("Enter the string: ");
  printf("The space character was encountered at position %d.\n", input(1));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vde_chain_nm9_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int vde_chain_nm9_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vde_chain_nm9_free>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int vde_chain_nm9_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<vde_chain_nm9_free>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int vde_chain_nm9_free(void *mem) {
  (void)mem;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_debug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x400,%edi
  call   <vlog@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int log_debug(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(1024, msg, ap);
  va_end(ap);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_debug>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x400,%edi
  call   <vlog@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int log_debug(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(1024, msg, ap);
  va_end(ap);
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_debug>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    $0x400,%edi
  call   <vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int log_debug(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(1024, msg, ap);
  va_end(ap);
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_debug>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    $0x400,%edi
  call   <vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int log_debug(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(1024, msg, ap);
  va_end(ap);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getAlphanumeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L142
  cmpb   $0x39,-0x4(%rbp)
  jg     L142
  movzbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L7
L142:
  cmpb   $0x40,-0x4(%rbp)
  jle    L17
  cmpb   $0x5a,-0x4(%rbp)
  jg     L17
  movzbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L7
L17:
  movsbl -0x4(%rbp),%eax
  sub    $0x20,%eax
  cmp    $0x1a,%eax
  ja     L119
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x24,%eax
  jmp    L7
  mov    $0x25,%eax
  jmp    L7
  mov    $0x26,%eax
  jmp    L7
  mov    $0x27,%eax
  jmp    L7
  mov    $0x28,%eax
  jmp    L7
  mov    $0x29,%eax
  jmp    L7
  mov    $0x2a,%eax
  jmp    L7
  mov    $0x2b,%eax
  jmp    L7
  mov    $0x2c,%eax
  jmp    L7
L119:
  mov    $0xffffffff,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int8_t getAlphanumeric(char c) {
  if (c >= '0' && c <= '9') {
    return (c - '0');
  }
  if (c >= 'A' && c <= 'Z') {
    return (c - 'A' + 10);
  }
  switch (c) {
  case ' ':
    return 36;
  case '$':
    return 37;
  case '%':
    return 38;
  case '*':
    return 39;
  case '+':
    return 40;
  case '-':
    return 41;
  case '.':
    return 42;
  case '/':
    return 43;
  case ':':
    return 44;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getAlphanumeric>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L1
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L22
  sub    $0x20,%edi
  cmp    $0x1a,%dil
  ja     L3
  movzbl %dil,%edi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L22:
  lea    -0x37(%rdi),%eax
  ret
  mov    $0x25,%eax
  ret
  mov    $0x26,%eax
  ret
  mov    $0x27,%eax
  ret
  mov    $0x28,%eax
  ret
  mov    $0x29,%eax
  ret
  mov    $0x2a,%eax
  ret
  mov    $0x2b,%eax
  ret
  mov    $0x2c,%eax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
  mov    $0x24,%eax
L1:
  ret
```

assistant: ```c
int8_t getAlphanumeric(char c) {
  if (c >= '0' && c <= '9') {
    return (c - '0');
  }
  if (c >= 'A' && c <= 'Z') {
    return (c - 'A' + 10);
  }
  switch (c) {
  case ' ':
    return 36;
  case '$':
    return 37;
  case '%':
    return 38;
  case '*':
    return 39;
  case '+':
    return 40;
  case '-':
    return 41;
  case '.':
    return 42;
  case '/':
    return 43;
  case ':':
    return 44;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getAlphanumeric>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L1
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L11
  sub    $0x20,%edi
  mov    $0xffffffff,%eax
  cmp    $0x1a,%dil
  ja     L1
  movzbl %dil,%edi
  lea    D1(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L1:
  ret
L11:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int8_t getAlphanumeric(char c) {
  if (c >= '0' && c <= '9') {
    return (c - '0');
  }
  if (c >= 'A' && c <= 'Z') {
    return (c - 'A' + 10);
  }
  switch (c) {
  case ' ':
    return 36;
  case '$':
    return 37;
  case '%':
    return 38;
  case '*':
    return 39;
  case '+':
    return 40;
  case '-':
    return 41;
  case '.':
    return 42;
  case '/':
    return 43;
  case ':':
    return 44;
  }
  return -1;
}
```