ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <pipe@plt>
  cmp    $0xffffffff,%eax
  je     L17
L0:
  mov    (%rsp),%r12d
  mov    0x4(%rsp),%ebp
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L17:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L0
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D26
type_infered: string
name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D20: Pipe File Descriptors

tool: D26:   Read end:  %d


tool: D10:   Write end: %d


tool: D6: Couldn't create the pipe

assistant: ```c
int main(void) {
  int pipefd[2];
  if (pipe(pipefd) == -1) {
    perror("Couldn't create the pipe");
  }
  int fd_read = pipefd[0];
  int fd_write = pipefd[1];
  printf("Pipe File Descriptors\n");
  printf("  Read end:  %d\n", fd_read);
  printf("  Write end: %d\n", fd_write);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L26
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L51
L26:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <get_filehash@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L51
L13:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_padblock@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L59
L8:
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
L4:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L59:
  cmpl   $0xff,-0x14(%rbp)
  jbe    L8
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L51:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string

tool: D3: File required!

tool: D13: %02X

tool: D23: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *hash;
  unsigned char *pad_block;
  unsigned int i;
  if (argc < 2) {
    printf("File required!\n");
    return 1;
  }
  hash = get_filehash(argv[1]);
  if (!hash)
    return 1;
  pad_block = get_padblock(hash);
  for (i = 0; i < 2048 / 8; i++) {
    if ((i % 16) == 0)
      printf("\n");
    printf("%02X", pad_block[i]);
  }
  printf("\n\n");
  free(pad_block);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L9
  mov    0x8(%rsi),%rdi
  call   <get_filehash@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L12
  call   <get_padblock@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D15(%rip),%r12
  jmp    L26
L9:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L12
L56:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x100,%rbx
  je     L0
L26:
  test   $0xf,%bl
  jne    L56
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L56
L0:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D12
type: string

tool: D15: %02X

tool: D21: File required!

tool: D12: 


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *hash;
  unsigned char *pad_block;
  unsigned int i;
  if (argc < 2) {
    printf("File required!\n");
    return 1;
  }
  hash = get_filehash(argv[1]);
  if (!hash)
    return 1;
  pad_block = get_padblock(hash);
  for (i = 0; i < 2048 / 8; i++) {
    if ((i % 16) == 0)
      printf("\n");
    printf("%02X", pad_block[i]);
  }
  printf("\n\n");
  free(pad_block);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L57
  mov    0x8(%rsi),%rdi
  call   <get_filehash@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L34
  call   <get_padblock@plt>
  xor    %ebx,%ebx
  lea    D21(%rip),%r12
  mov    %rax,%rbp
  jmp    L53
  cs nopw 0x0(%rax,%rax,1)
L46:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x100,%rbx
  je     L5
L53:
  test   $0xf,%bl
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L46
L5:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L34
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D21: %02X

tool: D11: 


tool: D1: File required!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *hash;
  unsigned char *pad_block;
  unsigned int i;
  if (argc < 2) {
    printf("File required!\n");
    return 1;
  }
  hash = get_filehash(argv[1]);
  if (!hash)
    return 1;
  pad_block = get_padblock(hash);
  for (i = 0; i < 2048 / 8; i++) {
    if ((i % 16) == 0)
      printf("\n");
    printf("%02X", pad_block[i]);
  }
  printf("\n\n");
  free(pad_block);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L59
  mov    0x8(%rsi),%rdi
  call   <get_filehash@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L36
  call   <get_padblock@plt>
  xor    %ebx,%ebx
  lea    D29(%rip),%r12
  mov    %rax,%rbp
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L64:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x100,%rbx
  je     L3
L12:
  test   $0xf,%bl
  jne    L64
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L64
L3:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L36
```

tool_calls: name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D3
type: string

tool: D29: %02X

tool: D4: 


tool: D3: File required!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char *hash;
  unsigned char *pad_block;
  unsigned int i;
  if (argc < 2) {
    printf("File required!\n");
    return 1;
  }
  hash = get_filehash(argv[1]);
  if (!hash)
    return 1;
  pad_block = get_padblock(hash);
  for (i = 0; i < 2048 / 8; i++) {
    if ((i % 16) == 0)
      printf("\n");
    printf("%02X", pad_block[i]);
  }
  printf("\n\n");
  free(pad_block);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<load32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
uint32_t load32(const void *in) {
  uint32_t v;
  memcpy(&v, in, sizeof v);
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t load32(const void *in) {
  uint32_t v;
  memcpy(&v, in, sizeof v);
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<load32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t load32(const void *in) {
  uint32_t v;
  memcpy(&v, in, sizeof v);
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<load32>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t load32(const void *in) {
  uint32_t v;
  memcpy(&v, in, sizeof v);
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x63,%eax
  jne    L4
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: Overflow.


assistant: ```c
void Push(int arr[], int *top, int elem) {
  if (*top == 100 - 1) {
    printf("Overflow.\n");
  }
  arr[++*top] = elem;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Push>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  cmpl   $0x63,(%rsi)
  je     L6
L14:
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  cltq
  mov    %r12d,0x0(%rbp,%rax,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: Overflow.


assistant: ```c
void Push(int arr[], int *top, int elem) {
  if (*top == 100 - 1) {
    printf("Overflow.\n");
  }
  arr[++*top] = elem;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Push>:
  endbr64
  mov    (%rsi),%eax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x63,%eax
  je     L11
L0:
  add    $0x1,%eax
  mov    %eax,(%rbx)
  cltq
  pop    %rbx
  mov    %r12d,0x0(%rbp,%rax,4)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: Overflow.


assistant: ```c
void Push(int arr[], int *top, int elem) {
  if (*top == 100 - 1) {
    printf("Overflow.\n");
  }
  arr[++*top] = elem;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Push>:
  endbr64
  mov    (%rsi),%eax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x63,%eax
  je     L18
L0:
  add    $0x1,%eax
  mov    %eax,(%rbx)
  cltq
  pop    %rbx
  mov    %r12d,0x0(%rbp,%rax,4)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: Overflow.


assistant: ```c
void Push(int arr[], int *top, int elem) {
  if (*top == 100 - 1) {
    printf("Overflow.\n");
  }
  arr[++*top] = elem;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L48
L35:
  addq   $0x1,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L35
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L17
L29:
  subq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L29
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L42
L2:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x30(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L42:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L2
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void trim(char *strIn, char *strOut) {
  char *start, *end, *temp;
  temp = strIn;
  while (*temp == ' ') {
    ++temp;
  }
  start = temp;
  temp = strIn + strlen(strIn) - 1;
  while (*temp == ' ') {
    --temp;
  }
  end = temp;
  for (strIn = start; strIn <= end;) {
    *strOut++ = *strIn++;
  }
  *strOut = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  cmpb   $0x20,(%rdi)
  jne    L12
  mov    %rdi,%rbx
L35:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L35
L27:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L33
L17:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L17
L33:
  cmp    %rax,%rbx
  ja     L60
  sub    %rbx,%rax
  lea    0x1(%rax),%rcx
  mov    $0x0,%eax
L49:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L49
  add    %rcx,%rbp
L60:
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rdi,%rbx
  jmp    L27
```

assistant: ```c
void trim(char *strIn, char *strOut) {
  char *start, *end, *temp;
  temp = strIn;
  while (*temp == ' ') {
    ++temp;
  }
  start = temp;
  temp = strIn + strlen(strIn) - 1;
  while (*temp == ' ') {
    --temp;
  }
  end = temp;
  for (strIn = start; strIn <= end;) {
    *strOut++ = *strIn++;
  }
  *strOut = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  jne    L36
  cs nopw 0x0(%rax,%rax,1)
L43:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L43
L36:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L30
  nopl   (%rax)
L0:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L0
L30:
  cmp    %rax,%rbx
  ja     L32
  sub    %rbx,%rax
  lea    0x1(%rax),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L44
  add    %rax,%rbp
L32:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim(char *strIn, char *strOut) {
  char *start, *end, *temp;
  temp = strIn;
  while (*temp == ' ') {
    ++temp;
  }
  start = temp;
  temp = strIn + strlen(strIn) - 1;
  while (*temp == ' ') {
    --temp;
  }
  end = temp;
  for (strIn = start; strIn <= end;) {
    *strOut++ = *strIn++;
  }
  *strOut = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rbx
  jne    L147
  cs nopw 0x0(%rax,%rax,1)
L190:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L190
L147:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jne    L172
  nopl   (%rax)
L129:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L129
L172:
  cmp    %rax,%rbx
  ja     L112
  lea    0x1(%rbx),%rcx
  mov    %rbp,%rdx
  mov    %rax,%rdi
  sub    %rcx,%rdx
  sub    %rbx,%rdi
  cmp    $0xe,%rdx
  jbe    L27
  cmp    $0x6,%rdi
  jbe    L27
  lea    0x1(%rdi),%r9
  cmp    $0xe,%rdi
  jbe    L194
  lea    -0xf(%rdi),%rdx
  xor    %esi,%esi
  shr    $0x4,%rdx
  lea    0x1(%rdx),%rcx
  xor    %edx,%edx
  nopl   0x0(%rax)
L94:
  movdqu (%rbx,%rdx,1),%xmm0
  add    $0x1,%rsi
  movups %xmm0,0x0(%rbp,%rdx,1)
  add    $0x10,%rdx
  cmp    %rsi,%rcx
  ja     L94
  shl    $0x4,%rcx
  mov    %rcx,%rdx
  lea    (%rbx,%rcx,1),%rcx
  lea    0x0(%rbp,%rdx,1),%rsi
  cmp    %rdx,%r9
  je     L153
  sub    %rdx,%rdi
  lea    0x1(%rdi),%r8
  cmp    $0x6,%rdi
  jbe    L168
L88:
  mov    (%rbx,%rdx,1),%rdi
  mov    %rdi,0x0(%rbp,%rdx,1)
  mov    %r8,%rdx
  and    $0xfffffffffffffff8,%rdx
  add    %rdx,%rcx
  add    %rdx,%rsi
  cmp    %rdx,%r8
  je     L153
L168:
  movzbl (%rcx),%edx
  mov    %dl,(%rsi)
  lea    0x1(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x1(%rcx),%edx
  mov    %dl,0x1(%rsi)
  lea    0x2(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x2(%rcx),%edx
  mov    %dl,0x2(%rsi)
  lea    0x3(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x3(%rcx),%edx
  mov    %dl,0x3(%rsi)
  lea    0x4(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x4(%rcx),%edx
  mov    %dl,0x4(%rsi)
  lea    0x5(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x5(%rcx),%edx
  mov    %dl,0x5(%rsi)
  lea    0x6(%rcx),%rdx
  cmp    %rdx,%rax
  jb     L153
  movzbl 0x6(%rcx),%eax
  mov    %al,0x6(%rsi)
L153:
  add    %r9,%rbp
L112:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  sub    %rbx,%rax
  lea    0x1(%rax),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L205:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L205
  lea    0x1(%rdi),%r9
  jmp    L153
L194:
  mov    %r9,%r8
  mov    %rbp,%rsi
  mov    %rbx,%rcx
  xor    %edx,%edx
  jmp    L88
```

assistant: ```c
void trim(char *strIn, char *strOut) {
  char *start, *end, *temp;
  temp = strIn;
  while (*temp == ' ') {
    ++temp;
  }
  start = temp;
  temp = strIn + strlen(strIn) - 1;
  while (*temp == ' ') {
    --temp;
  }
  end = temp;
  for (strIn = start; strIn <= end;) {
    *strOut++ = *strIn++;
  }
  *strOut = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blossom_path_readable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L76
  mov    $0x0,%eax
  jmp    L79
L76:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L38
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  jne    L38
  mov    $0x0,%eax
  jmp    L79
L38:
  mov    -0xc(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  jne    L53
  mov    $0x0,%eax
  jmp    L79
L53:
  mov    $0x1,%eax
L79:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
int blossom_path_readable(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1)
    return 0;
  if (!S_ISREG(statbuf.st_mode) && !S_ISLNK(statbuf.st_mode))
    return 0;
  if (!(statbuf.st_mode & S_IRUSR))
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<blossom_path_readable>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L27
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L24
L33:
  mov    D5(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L24:
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  jne    L33
  jmp    L27
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blossom_path_readable(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1)
    return 0;
  if (!S_ISREG(statbuf.st_mode) && !S_ISLNK(statbuf.st_mode))
    return 0;
  if (!(statbuf.st_mode & S_IRUSR))
    return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<blossom_path_readable>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L31
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L14
L41:
  mov    D0(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L30:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L14:
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  jne    L41
  nopl   (%rax)
L31:
  xor    %eax,%eax
  jmp    L30
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blossom_path_readable(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1)
    return 0;
  if (!S_ISREG(statbuf.st_mode) && !S_ISLNK(statbuf.st_mode))
    return 0;
  if (!(statbuf.st_mode & S_IRUSR))
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blossom_path_readable>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  je     L30
L23:
  mov    D1(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L48:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L30:
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  jne    L23
  nopl   (%rax)
L13:
  xor    %eax,%eax
  jmp    L48
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blossom_path_readable(const char *path) {
  struct stat statbuf;
  if (stat(path, &statbuf) == -1)
    return 0;
  if (!S_ISREG(statbuf.st_mode) && !S_ISLNK(statbuf.st_mode))
    return 0;
  if (!(statbuf.st_mode & S_IRUSR))
    return 0;
  return 1;
}
```