ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printMat>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %esi,%r15d
  push   %r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D29(%rip),%rdi
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  lea    -0x1(%r15),%ecx
  mov    %r15d,%eax
  movl   $0x0,(%rsp)
  mov    %ecx,0x4(%rsp)
  lea    D11(%rip),%r15
  test   %eax,%eax
  jle    L14
  nopw   0x0(%rax,%rax,1)
L67:
  mov    $0x7b,%edi
  xor    %r14d,%r14d
  call   <putchar@plt>
  movslq 0xc(%rsp),%rbp
  lea    -0x1(%rbp),%r12d
  test   %ebp,%ebp
  jg     L24
  jmp    L12
  nopl   0x0(%rax)
L63:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%rbp
  je     L12
L24:
  mov    (%rbx),%rax
  mov    (%rax,%r14,4),%esi
  cmp    %r14d,%r12d
  jg     L63
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%rbp
  jne    L24
L12:
  mov    (%rsp),%ecx
  cmp    %ecx,0x4(%rsp)
  jle    L28
  lea    D3(%rip),%rdi
  call   <puts@plt>
L76:
  addl   $0x1,(%rsp)
  add    $0x8,%rbx
  mov    (%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jne    L67
L14:
  add    $0x18,%rsp
  lea    D54(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L76
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D54
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D13: %2d, 

tool: D29: mat[%d][%d] = {


tool: D11: %2d

tool: D3: },

tool: D54: }


tool: D6: } 

assistant: ```c
void printMat(int **mat, int row, int col) {
  printf("mat[%d][%d] = {\n", row, col);
  for (int i = 0; i < row; i++) {
    printf("{");
    for (int j = 0; j < col; j++) {
      if (j < col - 1)
        printf("%2d, ", mat[i][j]);
      else
        printf("%2d", mat[i][j]);
    }
    if (i < row - 1)
      printf("},\n");
    else
      printf("} ");
  }
  printf("}\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printMat>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D48(%rip),%rdi
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L84
  mov    0x14(%rsp),%eax
  movl   $0x0,0x10(%rsp)
  lea    D22(%rip),%r14
  lea    D27(%rip),%r13
  sub    $0x1,%eax
  mov    %eax,0x18(%rsp)
  lea    -0x1(%rbp),%eax
  mov    %eax,0x1c(%rsp)
  nopl   (%rax)
L60:
  mov    $0x7b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L25
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L66
  cmp    %eax,%ebp
  cmovle %ebp,%eax
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    (%rbx),%rax
  mov    %r13,%rdi
  lea    0x1(%r12),%r15d
  mov    (%rax,%r12,4),%esi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,0xc(%rsp)
  jg     L24
  cmp    %ebp,%r15d
  jge    L25
L53:
  movslq %r15d,%r12
  shl    $0x2,%r12
  nopl   (%rax)
L3:
  mov    (%rbx),%rax
  mov    %r14,%rdi
  add    $0x1,%r15d
  mov    (%rax,%r12,1),%esi
  xor    %eax,%eax
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %ebp,%r15d
  jl     L3
L25:
  mov    0x10(%rsp),%ecx
  cmp    %ecx,0x18(%rsp)
  jle    L61
  lea    D55(%rip),%rdi
  call   <puts@plt>
L12:
  addl   $0x1,0x10(%rsp)
  add    $0x8,%rbx
  mov    0x10(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  jne    L60
L84:
  add    $0x28,%rsp
  lea    D58(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopl   (%rax)
L66:
  xor    %r15d,%r15d
  jmp    L53
  nopl   (%rax)
L61:
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_tag: D48
type_guessed: string
name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D55
type_guessed: string
name: unpack_data
arguments: data_tag: D58
type_guessed: string
name: unpack_data
arguments: data_tag: D57
type_guessed: string

tool: D48: mat[%d][%d] = {


tool: D22: %2d

tool: D27: %2d, 

tool: D55: },

tool: D58: }


tool: D57: } 

assistant: ```c
void printMat(int **mat, int row, int col) {
  printf("mat[%d][%d] = {\n", row, col);
  for (int i = 0; i < row; i++) {
    printf("{");
    for (int j = 0; j < col; j++) {
      if (j < col - 1)
        printf("%2d, ", mat[i][j]);
      else
        printf("%2d", mat[i][j]);
    }
    if (i < row - 1)
      printf("},\n");
    else
      printf("} ");
  }
  printf("}\n\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  lea    -0x24(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L1
L12:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,-0x28(%rbp)
  jle    L26
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0xffffffff,-0x30(%rbp)
L26:
  addl   $0x1,-0x2c(%rbp)
L1:
  cmpl   $0x4,-0x2c(%rbp)
  jle    L12
  mov    -0x30(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: us2 error: index %d, val %d > index %d, val %d


assistant: ```c
int main(int argv, char **argc) {
  int failed = 0;
  int us1[1] = {-1};
  int us2[5] = {4, 3, 2, 1, 2};
  merge_sort(us1, 0, 1);
  merge_sort(us2, 0, 5);
  int prev = us2[0];
  for (int i = 0; i < 5; i++) {
    if (us2[i] < prev) {
      printf("us2 error: index %d, val %d > index %d, val %d\n", i, us2[i], i - 1, prev);
      failed = -1;
    }
  }
  return failed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <merge_sort@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x5,%edx
  mov    $0x0,%esi
  call   <merge_sort@plt>
  mov    0x10(%rsp),%ebp
  mov    $0x1,%ebx
  mov    $0x0,%eax
  lea    D8(%rip),%r12
  jmp    L21
L19:
  add    $0x1,%rbx
L21:
  lea    -0x1(%rbx),%ecx
  mov    %ebx,%esi
  cmp    $0x5,%rbx
  je     L23
  mov    0x10(%rsp,%rbx,4),%edx
  cmp    %ebp,%edx
  jge    L19
  mov    %ebp,%r8d
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L23:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: us2 error: index %d, val %d > index %d, val %d


assistant: ```c
int main(int argv, char **argc) {
  int failed = 0;
  int us1[1] = {-1};
  int us2[5] = {4, 3, 2, 1, 2};
  merge_sort(us1, 0, 1);
  merge_sort(us2, 0, 5);
  int prev = us2[0];
  for (int i = 0; i < 5; i++) {
    if (us2[i] < prev) {
      printf("us2 error: index %d, val %d > index %d, val %d\n", i, us2[i], i - 1, prev);
      failed = -1;
    }
  }
  return failed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  xor    %esi,%esi
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  lea    0x10(%rsp),%r12
  movabs $0x300000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000002,%rax
  movl   $0xffffffff,0xc(%rsp)
  mov    %rax,0x18(%rsp)
  movl   $0x2,0x20(%rsp)
  call   <merge_sort@plt>
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    0x10(%rsp),%ebp
  xor    %eax,%eax
  lea    -0x1(%rbx),%ecx
  mov    %ebx,%esi
  cmp    $0x5,%rbx
  je     L15
L19:
  mov    (%r12,%rbx,4),%edx
  cmp    %ebp,%edx
  jge    L31
  mov    %ebp,%r8d
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
L31:
  add    $0x1,%rbx
  lea    -0x1(%rbx),%ecx
  mov    %ebx,%esi
  cmp    $0x5,%rbx
  jne    L19
L15:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string

tool: D9: us2 error: index %d, val %d > index %d, val %d


assistant: ```c
int main(int argv, char **argc) {
  int failed = 0;
  int us1[1] = {-1};
  int us2[5] = {4, 3, 2, 1, 2};
  merge_sort(us1, 0, 1);
  merge_sort(us2, 0, 5);
  int prev = us2[0];
  for (int i = 0; i < 5; i++) {
    if (us2[i] < prev) {
      printf("us2 error: index %d, val %d > index %d, val %d\n", i, us2[i], i - 1, prev);
      failed = -1;
    }
  }
  return failed;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edx
  xor    %esi,%esi
  sub    $0x30,%rsp
  movdqa D44(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  movl   $0xffffffff,0xc(%rsp)
  movaps %xmm0,0x10(%rsp)
  movl   $0x2,0x20(%rsp)
  call   <merge_sort@plt>
  mov    $0x5,%edx
  lea    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <merge_sort@plt>
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%edx
  xor    %eax,%eax
  cmp    %edx,%ebx
  jle    L42
  mov    %ebx,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
L42:
  mov    0x18(%rsp),%edx
  cmp    %edx,%ebx
  jle    L10
  mov    %ebx,%r8d
  mov    $0x1,%ecx
  mov    $0x2,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
L10:
  mov    0x1c(%rsp),%edx
  cmp    %edx,%ebx
  jle    L26
  mov    %ebx,%r8d
  mov    $0x2,%ecx
  mov    $0x3,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
L26:
  mov    0x20(%rsp),%edx
  cmp    %ebx,%edx
  jge    L27
  mov    %ebx,%r8d
  mov    $0x3,%ecx
  mov    $0x4,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
L27:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D44
datatype: byte[16]
name: extract_symbolic_data
arguments: data_tag: D37
datatype: string

tool: {"D44": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D37: us2 error: index %d, val %d > index %d, val %d


assistant: ```c
int main(int argv, char **argc) {
  int failed = 0;
  int us1[1] = {-1};
  int us2[5] = {4, 3, 2, 1, 2};
  merge_sort(us1, 0, 1);
  merge_sort(us2, 0, 5);
  int prev = us2[0];
  for (int i = 0; i < 5; i++) {
    if (us2[i] < prev) {
      printf("us2 error: index %d, val %d > index %d, val %d\n", i, us2[i], i - 1, prev);
      failed = -1;
    }
  }
  return failed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solcon_write_multprec_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x1c3,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_write_multprec_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(451, a, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solcon_write_multprec_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1c3,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int solcon_write_multprec_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(451, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<solcon_write_multprec_solutions>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1c3,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int solcon_write_multprec_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(451, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_write_multprec_solutions>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1c3,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int solcon_write_multprec_solutions(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(451, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<adaptivereleasecurve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  addss  %xmm1,%xmm0
  addss  -0x24(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float adaptivereleasecurve(float x, float a, float b, float c, float d) {
  float x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<adaptivereleasecurve>:
  endbr64
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  mulss  %xmm5,%xmm1
  mulss  %xmm0,%xmm1
  mulss  %xmm2,%xmm5
  addss  %xmm5,%xmm1
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  addss  %xmm4,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float adaptivereleasecurve(float x, float a, float b, float c, float d) {
  float x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adaptivereleasecurve>:
  endbr64
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  mulss  %xmm5,%xmm1
  mulss  %xmm2,%xmm5
  mulss  %xmm0,%xmm1
  mulss  %xmm3,%xmm0
  addss  %xmm5,%xmm1
  addss  %xmm0,%xmm1
  addss  %xmm4,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float adaptivereleasecurve(float x, float a, float b, float c, float d) {
  float x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<adaptivereleasecurve>:
  endbr64
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  mulss  %xmm5,%xmm1
  mulss  %xmm2,%xmm5
  mulss  %xmm0,%xmm1
  mulss  %xmm3,%xmm0
  addss  %xmm5,%xmm1
  addss  %xmm0,%xmm1
  addss  %xmm4,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float adaptivereleasecurve(float x, float a, float b, float c, float d) {
  float x2 = x * x;
  return a * x2 * x + b * x2 + c * x + d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_rflod_simple>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %r8,%r12
  mov    %r9,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r9
  mov    %rsp,%r8
  call   <calc_RN_simple@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  je     L69
  mov    (%rsp),%r14d
  mov    %r14d,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    %ebp,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  movsd  D26(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd D21(%rip),%xmm0
  ja     L35
  mov    D21(%rip),%rbp
L22:
  movq   %rbx,%xmm3
  comisd D21(%rip),%xmm3
  ja     L13
L38:
  mov    %rbx,0x0(%r13)
  mov    %rbp,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  addsd  %xmm0,%xmm0
  call   <log10@plt>
  sub    %r14d,%ebp
  imul   %eax,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  addsd  D21(%rip),%xmm0
  movq   %xmm0,%rbp
  jmp    L22
L13:
  movq   %rbx,%xmm0
  addsd  %xmm3,%xmm0
  call   <log10@plt>
  imul   (%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %rbp,%xmm4
  addsd  %xmm0,%xmm4
  movq   %xmm4,%rbp
  jmp    L38
L69:
  mov    D34(%rip),%rbx
  mov    %rbx,%rbp
  jmp    L38
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
type: f64
name: extract_symbolic_data
arguments: data_label: D21
type: f64[2]
name: extract_symbolic_data
arguments: data_label: D34
type: byte[8]

tool: D26: 1

tool: {"D21": [0.0,-100.0]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0xc0]}

assistant: ```c
void calc_rflod_simple(struct conf *c, struct marker *m1, struct marker *m2, unsigned x, double *_lod, double *_rf) {
  unsigned R, S, N;
  double r, s, lod;
  calc_RN_simple(c, m1, m2, x, &R, &N);
  if (N == 0) {
    *_rf = -100.0;
    *_lod = -100.0;
    return;
  }
  r = (double)R / N;
  s = 1.0 - r;
  S = N - R;
  lod = 0.0;
  if (s > 0.0)
    lod += S * log10(2.0 * s);
  if (r > 0.0)
    lod += R * log10(2.0 * r);
  *_rf = r;
  *_lod = lod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_rflod_simple>:
  endbr64
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <calc_RN_simple@plt>
  mov    0x14(%rsp),%ebx
  test   %ebx,%ebx
  je     L3
  mov    0x10(%rsp),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  cvtsi2sd %rax,%xmm1
  mov    %rax,%r13
  mov    %ebx,%eax
  cvtsi2sd %rax,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd %xmm3,%xmm0
  ja     L32
  comisd %xmm3,%xmm1
  ja     L18
L52:
  movsd  %xmm1,(%r12)
  movsd  %xmm2,0x0(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log10@plt>
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm2
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L32:
  addsd  %xmm0,%xmm0
  movsd  %xmm1,(%rsp)
  sub    %r13d,%ebx
  call   <log10@plt>
  movsd  (%rsp),%xmm1
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  imul   %eax,%ebx
  comisd %xmm3,%xmm1
  cvtsi2sd %rbx,%xmm2
  addsd  %xmm3,%xmm2
  jbe    L52
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  D8(%rip),%xmm1
  movapd %xmm1,%xmm2
  jmp    L52
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: f64
name: disassemble_data
arguments: label: D8
datatype: f32[2]

tool: D15: 1

tool: {"D8": [0.0,-3.390625]}

assistant: ```c
void calc_rflod_simple(struct conf *c, struct marker *m1, struct marker *m2, unsigned x, double *_lod, double *_rf) {
  unsigned R, S, N;
  double r, s, lod;
  calc_RN_simple(c, m1, m2, x, &R, &N);
  if (N == 0) {
    *_rf = -100.0;
    *_lod = -100.0;
    return;
  }
  r = (double)R / N;
  s = 1.0 - r;
  S = N - R;
  lod = 0.0;
  if (s > 0.0)
    lod += S * log10(2.0 * s);
  if (r > 0.0)
    lod += R * log10(2.0 * r);
  *_rf = r;
  *_lod = lod;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_rflod_simple>:
  endbr64
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <calc_RN_simple@plt>
  mov    0x14(%rsp),%ebx
  test   %ebx,%ebx
  je     L22
  mov    0x10(%rsp),%eax
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  cvtsi2sd %rax,%xmm1
  mov    %rax,%r13
  mov    %ebx,%eax
  cvtsi2sd %rax,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd %xmm3,%xmm0
  ja     L66
  comisd %xmm3,%xmm1
  ja     L11
L7:
  movsd  %xmm1,(%r12)
  movsd  %xmm2,0x0(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  addsd  %xmm1,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log10@plt>
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm2
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L66:
  addsd  %xmm0,%xmm0
  movsd  %xmm1,(%rsp)
  sub    %r13d,%ebx
  call   <log10@plt>
  movsd  (%rsp),%xmm1
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  imul   %eax,%ebx
  comisd %xmm3,%xmm1
  cvtsi2sd %rbx,%xmm2
  addsd  %xmm3,%xmm2
  jbe    L7
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L22:
  movsd  D13(%rip),%xmm1
  movapd %xmm1,%xmm2
  jmp    L7
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D14
data_type: f64
name: read_data
arguments: label: D13
data_type: f32[2]

tool: D14: 1

tool: {"D13": [0.0,-3.390625]}

assistant: ```c
void calc_rflod_simple(struct conf *c, struct marker *m1, struct marker *m2, unsigned x, double *_lod, double *_rf) {
  unsigned R, S, N;
  double r, s, lod;
  calc_RN_simple(c, m1, m2, x, &R, &N);
  if (N == 0) {
    *_rf = -100.0;
    *_lod = -100.0;
    return;
  }
  r = (double)R / N;
  s = 1.0 - r;
  S = N - R;
  lod = 0.0;
  if (s > 0.0)
    lod += S * log10(2.0 * s);
  if (r > 0.0)
    lod += R * log10(2.0 * r);
  *_rf = r;
  *_lod = lod;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L10
L14:
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L10:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  leave
  ret
```

assistant: ```c
int puts(const char *s) {
  int a;
  while ((a = *s++))
    putchar(a);
  return putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<puts>:
  endbr64
  push   %rbx
  lea    0x1(%rdi),%rbx
  movzbl (%rdi),%eax
  movsbl %al,%edi
  test   %al,%al
  je     L8
L2:
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  movsbl %al,%edi
  test   %al,%al
  jne    L2
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *s) {
  int a;
  while ((a = *s++))
    putchar(a);
  return putchar('\n');
}
```