ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<stat_mean>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L10:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L10
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L8
  addsd  (%rdi,%rax,8),%xmm0
L8:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%rdi),%xmm0
  ret
```

assistant: ```c
double stat_mean(double *data, int size) {
  int i;
  double sum = 0.0;
  if (size > 1) {
    for (i = 0; i < size; i++)
      sum += data[i];
    return sum / (double)size;
  } else {
    return data[0];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myAtoi0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L65
  lea    0x1(%rbx),%rbp
  mov    $0x0,%r12d
L51:
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L113
  add    $0x1,%r12d
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L51
L113:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L108
  cmpb   $0x30,(%rbx)
  je     L91
  cmp    $0x1,%r12d
  jg     L71
  mov    $0x0,%r14d
  mov    $0xa,%r13d
L13:
  cmp    %r12d,%r14d
  jge    L0
L55:
  movslq %r14d,%rax
  add    %rbx,%rax
  mov    %rax,%rbx
  mov    $0x0,%ebp
  sub    %eax,%r14d
  jmp    L151
L65:
  mov    $0x0,%r12d
  jmp    L113
L71:
  mov    $0x0,%r14d
  mov    $0xa,%r13d
L119:
  cmpb   $0x78,0x1(%rbx)
  jne    L55
  mov    $0x2,%r14d
  mov    $0x10,%r13d
  jmp    L13
L24:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L108
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L158
  movsbl (%rbx),%eax
  sub    $0x30,%eax
L42:
  imul   %r13d,%ebp
  add    %eax,%ebp
  add    $0x1,%rbx
  lea    (%r14,%rbx,1),%eax
  cmp    %r12d,%eax
  jge    L108
L151:
  cmp    $0x10,%r13d
  je     L24
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  jmp    L42
L158:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L42
L0:
  mov    $0x0,%ebp
  jmp    L108
L91:
  mov    $0x1,%r14d
  mov    $0x8,%r13d
  cmp    $0x1,%r12d
  jg     L119
  mov    $0x0,%ebp
L108:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int myAtoi0(char *s) {
  int unit = 10;
  int index = 0;
  int size = 0;
  while (*(s + size) != '\0' && isxdigit(*(s + size)))
    size++;
  if (isdigit(*(s))) {
    if (*s - '0' == 0) {
      index = 1;
      unit = 8;
    }
    if (size > 1 && (*(s + 1) == 'x' || *(s + 1) == 'x')) {
      index = 2;
      unit = 16;
    }
  } else {
    return 0;
  }
  int sum = 0;
  int cell = 0;
  for (; index < size; index++) {
    if (unit == 16) {
      if (isxdigit(*(s + index)))
        cell = (isalpha(*(s + index)) ? tolower(*(s + index)) - 'a' + 10 : *(s + index) - '0');
      else
        break;
    } else
      cell = *(s + index) - '0';
    sum = unit * sum + cell;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<myAtoi0>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  movsbl (%rdi),%edi
  lea    0x1(%r13),%rbx
  test   %dil,%dil
  jne    L61
  jmp    L85
  nop
L40:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%ebp
  test   %dil,%dil
  je     L103
L61:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L40
L103:
  movsbl 0x0(%r13),%edi
L85:
  call   <isdigit@plt>
  xor    %r12d,%r12d
  test   %rax,%rax
  je     L48
  cmpb   $0x30,0x0(%r13)
  je     L107
  xor    %eax,%eax
  mov    $0xa,%r14d
  cmp    $0x1,%ebp
  jg     L147
L25:
  cmp    %ebp,%eax
  jge    L63
L34:
  movslq %eax,%rbx
  xor    %r12d,%r12d
  add    %r13,%rbx
  sub    %ebx,%eax
  mov    %eax,%r13d
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L65:
  imul   %r14d,%r12d
  add    $0x1,%rbx
  add    %eax,%r12d
  lea    0x0(%r13,%rbx,1),%eax
  cmp    %ebp,%eax
  jge    L48
L47:
  movsbl (%rbx),%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x10,%r14d
  jne    L65
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L48
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L121
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  jmp    L65
  nop
L107:
  mov    $0x1,%eax
  mov    $0x8,%r14d
  cmp    $0x1,%ebp
  jg     L147
L48:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L147:
  cmpb   $0x78,0x1(%r13)
  jne    L34
  mov    $0x2,%eax
  mov    $0x10,%r14d
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L121:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L65
L63:
  xor    %r12d,%r12d
  jmp    L48
```

assistant: ```c
int myAtoi0(char *s) {
  int unit = 10;
  int index = 0;
  int size = 0;
  while (*(s + size) != '\0' && isxdigit(*(s + size)))
    size++;
  if (isdigit(*(s))) {
    if (*s - '0' == 0) {
      index = 1;
      unit = 8;
    }
    if (size > 1 && (*(s + 1) == 'x' || *(s + 1) == 'x')) {
      index = 2;
      unit = 16;
    }
  } else {
    return 0;
  }
  int sum = 0;
  int cell = 0;
  for (; index < size; index++) {
    if (unit == 16) {
      if (isxdigit(*(s + index)))
        cell = (isalpha(*(s + index)) ? tolower(*(s + index)) - 'a' + 10 : *(s + index) - '0');
      else
        break;
    } else
      cell = *(s + index) - '0';
    sum = unit * sum + cell;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<myAtoi0>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%r13),%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  xor    %ebx,%ebx
  test   %dil,%dil
  jne    L53
  jmp    L139
  nop
L153:
  movsbl (%r12),%edi
  add    $0x1,%r12
  add    $0x1,%ebx
  test   %dil,%dil
  je     L47
L53:
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L153
L47:
  movsbl 0x0(%r13),%edi
L139:
  call   <isdigit@plt>
  xor    %r12d,%r12d
  test   %rax,%rax
  je     L21
  cmpb   $0x30,0x0(%r13)
  je     L15
  cmp    $0x1,%ebx
  jle    L87
  cmpb   $0x78,0x1(%r13)
  je     L193
L22:
  mov    $0xa,%ecx
  xor    %eax,%eax
L8:
  xor    %r12d,%r12d
  xchg   %ax,%ax
L138:
  imul   %ecx,%r12d
  movsbl 0x0(%r13,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x30(%r12,%rdx,1),%r12d
  cmp    %eax,%ebx
  jg     L138
L21:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    $0x1,%ebx
  jle    L21
  cmpb   $0x78,0x1(%r13)
  mov    $0x8,%ecx
  mov    $0x1,%eax
  jne    L8
L193:
  cmp    $0x2,%ebx
  je     L21
  add    $0x2,%r13
  xor    %r12d,%r12d
  mov    $0x2,%r14d
  mov    %r13,%rbp
  nopl   0x0(%rax,%rax,1)
L178:
  movsbl 0x0(%rbp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  movsbl 0x0(%rbp),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L99
  movsbl 0x0(%rbp),%eax
  shl    $0x4,%r12d
  add    $0x1,%rbp
  lea    -0x30(%r12,%rax,1),%r12d
  mov    %r14d,%eax
  sub    %r13d,%eax
  add    %ebp,%eax
  cmp    %eax,%ebx
  jg     L178
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L99:
  movsbl 0x0(%rbp),%edi
  shl    $0x4,%r12d
  add    $0x1,%rbp
  call   <tolower@plt>
  movsbl %al,%eax
  lea    -0x57(%r12,%rax,1),%r12d
  mov    %r14d,%eax
  sub    %r13d,%eax
  add    %ebp,%eax
  cmp    %ebx,%eax
  jl     L178
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L87:
  je     L22
  jmp    L21
```

assistant: ```c
int myAtoi0(char *s) {
  int unit = 10;
  int index = 0;
  int size = 0;
  while (*(s + size) != '\0' && isxdigit(*(s + size)))
    size++;
  if (isdigit(*(s))) {
    if (*s - '0' == 0) {
      index = 1;
      unit = 8;
    }
    if (size > 1 && (*(s + 1) == 'x' || *(s + 1) == 'x')) {
      index = 2;
      unit = 16;
    }
  } else {
    return 0;
  }
  int sum = 0;
  int cell = 0;
  for (; index < size; index++) {
    if (unit == 16) {
      if (isxdigit(*(s + index)))
        cell = (isalpha(*(s + index)) ? tolower(*(s + index)) - 'a' + 10 : *(s + index) - '0');
      else
        break;
    } else
      cell = *(s + index) - '0';
    sum = unit * sum + cell;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpu_info_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cpu_info_strval@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L21
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L21
L17:
  nop
L21:
  leave
  ret
```

assistant: ```c
void cpu_info_strcpy(char *ptr, char *buf, int len) {
  int slen;
  ptr = cpu_info_strval(ptr);
  if (!ptr) {
    return;
  }
  slen = strlen(ptr);
  strncpy(buf, ptr, len);
  buf[len] = '\0';
  if (slen < len) {
    buf[slen - 1] = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpu_info_strcpy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebp
  call   <cpu_info_strval@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  cmp    %ebp,%r13d
  jge    L3
  movslq %r13d,%r13
  movb   $0x0,-0x1(%r12,%r13,1)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void cpu_info_strcpy(char *ptr, char *buf, int len) {
  int slen;
  ptr = cpu_info_strval(ptr);
  if (!ptr) {
    return;
  }
  slen = strlen(ptr);
  strncpy(buf, ptr, len);
  buf[len] = '\0';
  if (slen < len) {
    buf[slen - 1] = '\0';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<cpu_info_strcpy>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <cpu_info_strval@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%r13
  call   <strncpy@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  cmp    %ebx,%r13d
  jge    L15
  movb   $0x0,-0x1(%r12,%r13,1)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void cpu_info_strcpy(char *ptr, char *buf, int len) {
  int slen;
  ptr = cpu_info_strval(ptr);
  if (!ptr) {
    return;
  }
  slen = strlen(ptr);
  strncpy(buf, ptr, len);
  buf[len] = '\0';
  if (slen < len) {
    buf[slen - 1] = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cpu_info_strcpy>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <cpu_info_strval@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movslq %eax,%r13
  call   <strncpy@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  cmp    %ebx,%r13d
  jge    L1
  movb   $0x0,-0x1(%r12,%r13,1)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void cpu_info_strcpy(char *ptr, char *buf, int len) {
  int slen;
  ptr = cpu_info_strval(ptr);
  if (!ptr) {
    return;
  }
  slen = strlen(ptr);
  strncpy(buf, ptr, len);
  buf[len] = '\0';
  if (slen < len) {
    buf[slen - 1] = '\0';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0x10(%rbp)
  jmp    L35
L22:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L18
  movl   $0x0,-0xc(%rbp)
L18:
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L22
  cmpl   $0x1,-0xc(%rbp)
  jne    L46
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L39
L46:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D37
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string

tool: D37: Enter an integer number: 

tool: D11: %d

tool: D29: %d is a prime number.


tool: D28: %d is not a prime number.


assistant: ```c
int main() {
  int i;
  int number;
  int prime = 1;
  printf("Enter an integer number: ");
  scanf("%d", &number);
  for (i = 2; i < number; i++) {
    if ((number % i) == 0) {
      prime = 0;
    }
  }
  if (prime == 1)
    printf("%d is a prime number.\n", number);
  else
    printf("%d is not a prime number.\n", number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L49
  mov    $0x1,%edi
  mov    $0x2,%ecx
L32:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %edx,%edi
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L32
  cmp    $0x1,%edi
  je     L49
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L49:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D27
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D29: Enter an integer number: 

tool: D15: %d

tool: D27: %d is not a prime number.


tool: D10: %d is a prime number.


assistant: ```c
int main() {
  int i;
  int number;
  int prime = 1;
  printf("Enter an integer number: ");
  scanf("%d", &number);
  for (i = 2; i < number; i++) {
    if ((number % i) == 0) {
      prime = 0;
    }
  }
  if (prime == 1)
    printf("%d is a prime number.\n", number);
  else
    printf("%d is not a prime number.\n", number);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x2,%r8d
  jle    L12
  mov    $0x1,%ecx
  mov    $0x2,%esi
  xor    %edi,%edi
  nopl   0x0(%rax)
L45:
  mov    %r8d,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  cmove  %edi,%ecx
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L45
  cmp    $0x1,%ecx
  je     L12
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  mov    %r8d,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D1
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D22
type: string

tool: D15: Enter an integer number: 

tool: D1: %d

tool: D10: %d is not a prime number.


tool: D22: %d is a prime number.


assistant: ```c
int main() {
  int i;
  int number;
  int prime = 1;
  printf("Enter an integer number: ");
  scanf("%d", &number);
  for (i = 2; i < number; i++) {
    if ((number % i) == 0) {
      prime = 0;
    }
  }
  if (prime == 1)
    printf("%d is a prime number.\n", number);
  else
    printf("%d is not a prime number.\n", number);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  cmp    $0x2,%r8d
  jle    L22
  mov    $0x1,%ecx
  mov    $0x2,%esi
  xor    %edi,%edi
  nopl   0x0(%rax)
L16:
  mov    %r8d,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  cmove  %edi,%ecx
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L16
  cmp    $0x1,%ecx
  je     L22
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  mov    %r8d,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D0
type: string

tool: D18: Enter an integer number: 

tool: D12: %d

tool: D21: %d is not a prime number.


tool: D0: %d is a prime number.


assistant: ```c
int main() {
  int i;
  int number;
  int prime = 1;
  printf("Enter an integer number: ");
  scanf("%d", &number);
  for (i = 2; i < number; i++) {
    if ((number % i) == 0) {
      prime = 0;
    }
  }
  if (prime == 1)
    printf("%d is a prime number.\n", number);
  else
    printf("%d is not a prime number.\n", number);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ipacl_request_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ipacl_open@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L8
  mov    -0xc(%rbp),%eax
  jmp    L17
L8:
  mov    -0x10(%rbp),%eax
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <ipacl_do_request_s@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ipacl_close@plt>
  mov    -0xc(%rbp),%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int ipacl_request_s(int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  int fh;
  int rc;
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  if ((rc = ipacl_open(&fh)) != 0)
    return rc;
  rc = ipacl_do_request_s(fh, pfh, ip, protocol, port);
  ipacl_close(fh);
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipacl_request_s>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r13,%r13
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14,%r14
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x4(%rsp),%rdi
  call   <ipacl_open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L7
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    0x4(%rsp),%edi
  call   <ipacl_do_request_s@plt>
  mov    %eax,%ebx
  mov    0x4(%rsp),%edi
  call   <ipacl_close@plt>
  jmp    L22
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipacl_request_s(int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  int fh;
  int rc;
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  if ((rc = ipacl_open(&fh)) != 0)
    return rc;
  rc = ipacl_do_request_s(fh, pfh, ip, protocol, port);
  ipacl_close(fh);
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipacl_request_s>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r13,%r13
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  lea    0x4(%rsp),%rdi
  call   <ipacl_open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L7
  mov    0x4(%rsp),%edi
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <ipacl_do_request_s@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%r12d
  call   <ipacl_close@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipacl_request_s(int *const restrict pfh, const char *const restrict ip, const char *const restrict protocol, const char *const restrict port) {
  int fh;
  int rc;
  assert(pfh != NULL);
  assert(ip != NULL);
  assert(protocol != NULL);
  assert(port != NULL);
  if ((rc = ipacl_open(&fh)) != 0)
    return rc;
  rc = ipacl_do_request_s(fh, pfh, ip, protocol, port);
  ipacl_close(fh);
  return rc;
}
```