ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LRU_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <list_length@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L92:
  cmpl   $0x0,-0x8(%rbp)
  js     L25
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L22
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dump@plt>
  jmp    L9
L22:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L103
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L103
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L108
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L103:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L92
  cmpl   $0x4,-0x4(%rbp)
  jg     L99
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L44
L99:
  mov    -0x18(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dump@plt>
  jmp    L9
L108:
  nop
L9:
  leave
  ret
```

assistant: ```c
void LRU_set(int *list, int val) {
  int i = 0;
  int size = list_length(list);
  int tmp_val = -1;
  for (i = 0; i < size; i++) {
    if (tmp_val >= 0) {
      if (i == size - 1) {
        list[i] = tmp_val;
        dump(list);
        return;
      }
      list[i] = list[i + 1];
    } else if (list[i] == val) {
      if (i == size - 1)
        return;
      tmp_val = list[i];
      list[i] = list[i + 1];
    }
  }
  if (size < 5)
    list[size] = val;
  else
    list[0] = val;
  dump(list);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LRU_set>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <list_length@plt>
  test   %eax,%eax
  jle    L85
  mov    %rbx,%rdx
  mov    $0xffffffff,%esi
  mov    $0x0,%ecx
  lea    -0x1(%rax),%r8d
  jmp    L88
L63:
  movslq %ecx,%rcx
  mov    %esi,(%rbx,%rcx,4)
  mov    %rbx,%rdi
  call   <dump@plt>
  jmp    L78
L9:
  cmp    %ebp,(%rdx)
  je     L26
L21:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %ecx,%eax
  je     L85
L88:
  test   %esi,%esi
  js     L9
  cmp    %ecx,%r8d
  je     L63
  mov    0x4(%rdx),%edi
  mov    %edi,(%rdx)
  jmp    L21
L26:
  cmp    %ecx,%r8d
  je     L78
  mov    0x4(%rdx),%esi
  mov    %esi,(%rdx)
  mov    %ebp,%esi
  jmp    L21
L85:
  cmp    $0x4,%eax
  jg     L51
  cltq
  mov    %ebp,(%rbx,%rax,4)
L68:
  mov    %rbx,%rdi
  call   <dump@plt>
L78:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  mov    %ebp,(%rbx)
  jmp    L68
```

assistant: ```c
void LRU_set(int *list, int val) {
  int i = 0;
  int size = list_length(list);
  int tmp_val = -1;
  for (i = 0; i < size; i++) {
    if (tmp_val >= 0) {
      if (i == size - 1) {
        list[i] = tmp_val;
        dump(list);
        return;
      }
      list[i] = list[i + 1];
    } else if (list[i] == val) {
      if (i == size - 1)
        return;
      tmp_val = list[i];
      list[i] = list[i + 1];
    }
  }
  if (size < 5)
    list[size] = val;
  else
    list[0] = val;
  dump(list);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LRU_set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <list_length@plt>
  test   %eax,%eax
  jle    L71
  mov    %rbp,%rdx
  mov    $0xffffffff,%r8d
  lea    -0x1(%rax),%r10d
  xor    %ecx,%ecx
  jmp    L68
  nopl   0x0(%rax)
L67:
  cmp    %ecx,%r10d
  je     L48
  mov    0x4(%rdx),%r9d
  mov    %r9d,(%rdx)
L70:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %ecx,%eax
  je     L75
L68:
  test   %r8d,%r8d
  jns    L67
  cmp    %ebx,(%rdx)
  jne    L70
  cmp    %ecx,%r10d
  je     L45
  mov    0x4(%rdx),%esi
  add    $0x1,%ecx
  mov    %ebx,%r8d
  add    $0x4,%rdx
  mov    %esi,-0x4(%rdx)
  cmp    %ecx,%eax
  jne    L68
  nopl   0x0(%rax)
L75:
  cmp    $0x4,%eax
  jle    L71
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
  cs nopw 0x0(%rax,%rax,1)
L71:
  cltq
  mov    %rbp,%rdi
  mov    %ebx,0x0(%rbp,%rax,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
  nopl   0x0(%rax)
L48:
  mov    %r8d,(%rdx)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void LRU_set(int *list, int val) {
  int i = 0;
  int size = list_length(list);
  int tmp_val = -1;
  for (i = 0; i < size; i++) {
    if (tmp_val >= 0) {
      if (i == size - 1) {
        list[i] = tmp_val;
        dump(list);
        return;
      }
      list[i] = list[i + 1];
    } else if (list[i] == val) {
      if (i == size - 1)
        return;
      tmp_val = list[i];
      list[i] = list[i + 1];
    }
  }
  if (size < 5)
    list[size] = val;
  else
    list[0] = val;
  dump(list);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LRU_set>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <list_length@plt>
  test   %eax,%eax
  jle    L94
  mov    %rbp,%rcx
  mov    $0xffffffff,%r8d
  lea    -0x1(%rax),%r9d
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rcx,%rdi
  test   %r8d,%r8d
  js     L115
  lea    -0x1(%rax),%esi
  cmp    %edx,%esi
  je     L5
  mov    0x4(%rcx),%edi
  add    $0x1,%edx
  mov    %edi,(%rcx)
  movslq %edx,%rcx
  lea    0x0(%rbp,%rcx,4),%rcx
  cmp    %edx,%eax
  jne    L37
  jmp    L75
  nopl   (%rax)
L125:
  mov    0x4(%rcx),%edi
  add    $0x1,%edx
  add    $0x4,%rcx
  mov    %edi,-0x4(%rcx)
  cmp    %edx,%eax
  jle    L75
L37:
  mov    %rcx,%rdi
  cmp    %edx,%esi
  jne    L125
L5:
  mov    %r8d,(%rdi)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
  nopl   0x0(%rax)
L115:
  cmp    %ebx,(%rcx)
  je     L109
L128:
  add    $0x1,%edx
  cmp    %edx,%eax
  je     L75
  add    $0x4,%rcx
  jmp    L23
  nopl   0x0(%rax)
L109:
  cmp    %edx,%r9d
  je     L12
  mov    0x4(%rcx),%esi
  mov    %ebx,%r8d
  mov    %esi,(%rcx)
  jmp    L128
  nop
L75:
  cmp    $0x4,%eax
  jle    L94
  mov    %ebx,0x0(%rbp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
  cs nopw 0x0(%rax,%rax,1)
L94:
  cltq
  mov    %rbp,%rdi
  mov    %ebx,0x0(%rbp,%rax,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <dump@plt>
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void LRU_set(int *list, int val) {
  int i = 0;
  int size = list_length(list);
  int tmp_val = -1;
  for (i = 0; i < size; i++) {
    if (tmp_val >= 0) {
      if (i == size - 1) {
        list[i] = tmp_val;
        dump(list);
        return;
      }
      list[i] = list[i + 1];
    } else if (list[i] == val) {
      if (i == size - 1)
        return;
      tmp_val = list[i];
      list[i] = list[i + 1];
    }
  }
  if (size < 5)
    list[size] = val;
  else
    list[0] = val;
  dump(list);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inputnumstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
L105:
  jmp    L62
L45:
  cmpb   $0x3,-0x5(%rbp)
  jne    L34
  mov    $0x0,%edi
  call   <exit@plt>
L34:
  cmpb   $0x7f,-0x5(%rbp)
  je     L81
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L102
  jmp    L105
L102:
  cmpb   $0x2f,-0x5(%rbp)
  jle    L62
  cmpb   $0x39,-0x5(%rbp)
  jg     L62
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  jmp    L62
L81:
  cmpl   $0x0,-0x4(%rbp)
  jle    L62
  subl   $0x1,-0x4(%rbp)
  mov    $0x8,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x8,%edi
  call   <putchar@plt>
L62:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0xd,-0x5(%rbp)
  jne    L45
  cmpl   $0x0,-0x4(%rbp)
  jne    L97
  jmp    L105
L97:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void inputnumstr(char *a, int len) {
  int i = 0;
  char b;
getchnumstr:
  while ((b = getch()) != 13) {
    if (b == 3) {
      exit(0);
    }
    if (b != 127) {
      if (i > len) {
        goto getchnumstr;
      }
      if (b >= '0' && b <= '9') {
        putchar(b);
        a[i] = b;
        i++;
      }
    } else {
      if (i > 0) {
        i--;
        putchar('\b');
        putchar(' ');
        putchar('\b');
      }
    }
  }
  if (i == 0) {
    goto getchnumstr;
  }
  a[i] = '\0';
  putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inputnumstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    $0x0,%ebp
  jmp    L60
L63:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L60
L39:
  test   %ebp,%ebp
  jle    L60
  sub    $0x1,%ebp
  mov    $0x8,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x8,%edi
  call   <putchar@plt>
  jmp    L60
L9:
  test   %ebp,%ebp
  jne    L52
L60:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L9
  cmp    $0x3,%bl
  je     L63
  cmp    $0x7f,%bl
  je     L39
  cmp    %r12d,%ebp
  jg     L60
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L60
  movsbl %bl,%edi
  call   <putchar@plt>
  movslq %ebp,%rax
  mov    %bl,0x0(%r13,%rax,1)
  add    $0x1,%ebp
  jmp    L60
L52:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void inputnumstr(char *a, int len) {
  int i = 0;
  char b;
getchnumstr:
  while ((b = getch()) != 13) {
    if (b == 3) {
      exit(0);
    }
    if (b != 127) {
      if (i > len) {
        goto getchnumstr;
      }
      if (b >= '0' && b <= '9') {
        putchar(b);
        a[i] = b;
        i++;
      }
    } else {
      if (i > 0) {
        i--;
        putchar('\b');
        putchar(' ');
        putchar('\b');
      }
    }
  }
  if (i == 0) {
    goto getchnumstr;
  }
  a[i] = '\0';
  putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inputnumstr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L120:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L132
L121:
  cmp    $0x3,%bl
  je     L147
L65:
  cmp    $0x7f,%bl
  je     L135
L60:
  cmp    %ebp,%r12d
  jl     L120
L143:
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L120
  movsbl %bl,%edi
  call   <putchar@plt>
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %bl,0x0(%r13,%rax,1)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  jne    L121
  nopl   0x0(%rax,%rax,1)
L132:
  test   %ebp,%ebp
  jne    L79
L19:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L67
  cmp    $0x3,%bl
  je     L147
  cmp    $0x7f,%bl
  je     L67
  test   %r12d,%r12d
  jns    L143
  nopl   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L19
  cmp    $0x3,%bl
  jne    L65
L147:
  xor    %edi,%edi
  mov    $0x3,%ebx
  call   <exit@plt>
  jmp    L60
L135:
  test   %ebp,%ebp
  jle    L120
  mov    $0x8,%edi
  sub    $0x1,%ebp
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x8,%edi
  call   <putchar@plt>
  jmp    L120
  xchg   %ax,%ax
L79:
  movslq %ebp,%rbp
  mov    $0xa,%edi
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

assistant: ```c
void inputnumstr(char *a, int len) {
  int i = 0;
  char b;
getchnumstr:
  while ((b = getch()) != 13) {
    if (b == 3) {
      exit(0);
    }
    if (b != 127) {
      if (i > len) {
        goto getchnumstr;
      }
      if (b >= '0' && b <= '9') {
        putchar(b);
        a[i] = b;
        i++;
      }
    } else {
      if (i > 0) {
        i--;
        putchar('\b');
        putchar(' ');
        putchar('\b');
      }
    }
  }
  if (i == 0) {
    goto getchnumstr;
  }
  a[i] = '\0';
  putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<inputnumstr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L41
L18:
  cmp    $0x3,%bl
  je     L156
L21:
  cmp    $0x7f,%bl
  je     L62
L86:
  cmp    %ebp,%r12d
  jl     L69
L7:
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L69
  movsbl %bl,%edi
  call   <putchar@plt>
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %bl,0x0(%r13,%rax,1)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  jne    L18
  nopl   0x0(%rax,%rax,1)
L41:
  test   %ebp,%ebp
  jne    L65
L61:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L106
  cmp    $0x3,%bl
  je     L156
  cmp    $0x7f,%bl
  je     L106
  test   %r12d,%r12d
  jns    L7
  nopl   0x0(%rax,%rax,1)
L106:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0xd,%al
  je     L61
  cmp    $0x3,%bl
  jne    L21
L156:
  xor    %edi,%edi
  mov    $0x3,%ebx
  call   <exit@plt>
  jmp    L86
L62:
  test   %ebp,%ebp
  jle    L69
  mov    $0x8,%edi
  sub    $0x1,%ebp
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x8,%edi
  call   <putchar@plt>
  jmp    L69
  xchg   %ax,%ax
L65:
  movslq %ebp,%rbp
  mov    $0xa,%edi
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

assistant: ```c
void inputnumstr(char *a, int len) {
  int i = 0;
  char b;
getchnumstr:
  while ((b = getch()) != 13) {
    if (b == 3) {
      exit(0);
    }
    if (b != 127) {
      if (i > len) {
        goto getchnumstr;
      }
      if (b >= '0' && b <= '9') {
        putchar(b);
        a[i] = b;
        i++;
      }
    } else {
      if (i > 0) {
        i--;
        putchar('\b');
        putchar(' ');
        putchar('\b');
      }
    }
  }
  if (i == 0) {
    goto getchnumstr;
  }
  a[i] = '\0';
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psvec4i_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vec4i_multiply@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_multiply(struct vec4i *result, struct vec4i *a, struct vec4i *b) {
  vec4i_multiply((int32_t *)result, (int32_t *)a, (int32_t *)b);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<psvec4i_multiply>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec4i_multiply@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_multiply(struct vec4i *result, struct vec4i *a, struct vec4i *b) {
  vec4i_multiply((int32_t *)result, (int32_t *)a, (int32_t *)b);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<psvec4i_multiply>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4i_multiply@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_multiply(struct vec4i *result, struct vec4i *a, struct vec4i *b) {
  vec4i_multiply((int32_t *)result, (int32_t *)a, (int32_t *)b);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<psvec4i_multiply>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4i_multiply@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4i *psvec4i_multiply(struct vec4i *result, struct vec4i *a, struct vec4i *b) {
  vec4i_multiply((int32_t *)result, (int32_t *)a, (int32_t *)b);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getitimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getitimer(int which, struct itimerval *value) {
  errno = EPERM;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<getitimer>:
  endbr64
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getitimer(int which, struct itimerval *value) {
  errno = EPERM;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getitimer>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getitimer(int which, struct itimerval *value) {
  errno = EPERM;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getitimer>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getitimer(int which, struct itimerval *value) {
  errno = EPERM;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dos_unix_sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    (%rdi),%rax
  mov    (%rax),%r12
  mov    (%rsi),%rax
  mov    (%rax),%rbp
L103:
  movsbl (%r12),%edi
  call   <dos_valid_char@plt>
  mov    %eax,%ebx
  movsbl 0x0(%rbp),%edi
  call   <dos_valid_char@plt>
  test   %bl,%bl
  je     L133
  cmp    %al,%bl
  je     L146
L133:
  movzbl (%r12),%edx
  test   %dl,%dl
  je     L92
  cmp    0x0(%rbp),%dl
  je     L146
  movzbl 0x0(%rbp),%esi
  mov    $0x1,%ecx
  test   %sil,%sil
  je     L181
  cmp    $0x2e,%dl
  je     L4
  cmp    $0x2e,%sil
  je     L181
  cmp    $0x7e,%dl
  je     L69
  cmp    $0x7e,%sil
  je     L181
  mov    %ebx,%ecx
  or     %al,%cl
  je     L128
  mov    $0x1,%ecx
  test   %bl,%bl
  je     L181
  test   %al,%al
  je     L177
  movsbl %bl,%ecx
  movsbl %al,%edx
  sub    %edx,%ecx
  jmp    L181
L92:
  mov    $0xffffffff,%ecx
  cmpb   $0x0,0x0(%rbp)
  je     L132
L181:
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L132:
  mov    (%r14),%rdx
  mov    0x0(%r13),%rax
  mov    (%rdx),%rsi
  mov    (%rax),%rdi
  call   <strcmp@plt>
  mov    %eax,%ecx
  jmp    L181
L128:
  movsbl %dl,%ecx
  movsbl %sil,%esi
  sub    %esi,%ecx
  jmp    L181
L146:
  add    $0x1,%r12
  add    $0x1,%rbp
  jmp    L103
L4:
  mov    $0xffffffff,%ecx
  jmp    L181
L69:
  mov    $0xffffffff,%ecx
  jmp    L181
L177:
  mov    $0xffffffff,%ecx
  jmp    L181
```

assistant: ```c
int dos_unix_sort(const struct dirent **s1, const struct dirent **s2) {
  const char *n1 = (*s1)->d_name;
  const char *n2 = (*s2)->d_name;
  for (;; n1++, n2++) {
    char c1 = dos_valid_char(*n1);
    char c2 = dos_valid_char(*n2);
    if (c1 && c1 == c2)
      continue;
    if (*n1 && *n1 == *n2)
      continue;
    if (!*n1 && !*n2) {
      return strcmp((*s1)->d_name, (*s2)->d_name);
    }
    if (!*n1)
      return -1;
    if (!*n2)
      return 1;
    if (*n1 == '.')
      return -1;
    if (*n2 == '.')
      return 1;
    if (*n1 == '~')
      return -1;
    if (*n2 == '~')
      return 1;
    if (!c1 && !c2)
      return *n1 - *n2;
    if (!c1)
      return 1;
    if (!c2)
      return -1;
    return c1 - c2;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dos_unix_sort>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    (%rax),%r14
  mov    (%rsi),%rax
  mov    (%rax),%rbp
L25:
  movsbl (%r14),%edi
  call   <dos_valid_char@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <dos_valid_char@plt>
  test   %bl,%bl
  je     L125
  cmp    %al,%bl
  jne    L125
L11:
  add    $0x1,%r14
  add    $0x1,%rbp
  jmp    L25
  nopl   0x0(%rax)
L125:
  movzbl (%r14),%ecx
  movsbl 0x0(%rbp),%edx
  test   %cl,%cl
  je     L90
  cmp    %dl,%cl
  je     L11
  mov    $0x1,%r8d
  test   %dl,%dl
  je     L77
  cmp    $0x2e,%cl
  je     L47
  cmp    $0x2e,%dl
  je     L77
  cmp    $0x7e,%cl
  je     L47
  cmp    $0x7e,%dl
  je     L77
  mov    %ebx,%esi
  or     %al,%sil
  je     L135
  test   %bl,%bl
  je     L77
  test   %al,%al
  je     L47
  movsbl %bl,%r8d
  movsbl %al,%edx
  sub    %edx,%r8d
L77:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L90:
  test   %dl,%dl
  je     L114
L47:
  mov    $0xffffffff,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L114:
  mov    0x0(%r13),%rdx
  mov    (%r12),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rdx),%rsi
  mov    (%rax),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L135:
  movsbl %cl,%r8d
  pop    %rbx
  pop    %rbp
  sub    %edx,%r8d
  pop    %r12
  pop    %r13
  mov    %r8d,%eax
  pop    %r14
  ret
```

assistant: ```c
int dos_unix_sort(const struct dirent **s1, const struct dirent **s2) {
  const char *n1 = (*s1)->d_name;
  const char *n2 = (*s2)->d_name;
  for (;; n1++, n2++) {
    char c1 = dos_valid_char(*n1);
    char c2 = dos_valid_char(*n2);
    if (c1 && c1 == c2)
      continue;
    if (*n1 && *n1 == *n2)
      continue;
    if (!*n1 && !*n2) {
      return strcmp((*s1)->d_name, (*s2)->d_name);
    }
    if (!*n1)
      return -1;
    if (!*n2)
      return 1;
    if (*n1 == '.')
      return -1;
    if (*n2 == '.')
      return 1;
    if (*n1 == '~')
      return -1;
    if (*n2 == '~')
      return 1;
    if (!c1 && !c2)
      return *n1 - *n2;
    if (!c1)
      return 1;
    if (!c2)
      return -1;
    return c1 - c2;
  }
}
```