user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  movq   $0x1,-0x30(%rbp)
  jmp    L72
L41:
  addq   $0x1,-0x30(%rbp)
L72:
  sarq   -0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L41
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <F0@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x3,-0x30(%rbp)
  jle    L47
  mov    -0x30(%rbp),%rax
  sub    $0x4,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  jmp    L53
L47:
  mov    $0xffffffffffffffff,%rax
L53:
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0x2,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  and    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x40(%rbp)
  jmp    L21
L66:
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  sub    $0x2,%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L97
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x40(%rbp),%rax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    -0x40(%rbp),%rax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rax
  sub    $0x1,%rax
  and    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <F1@plt>
  add    %rax,-0x38(%rbp)
L97:
  addq   $0x1,-0x40(%rbp)
L21:
  mov    -0x40(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L66
  mov    $0x40,%eax
  sub    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  jmp    L6
L64:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <bitsReverse64@plt>
  mov    -0x18(%rbp),%rdx
  mov    %edx,%ecx
  sar    %cl,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <popcount64@plt>
  add    %rax,-0x38(%rbp)
  addq   $0x1,-0x40(%rbp)
L6:
  mov    -0x48(%rbp),%rax
  cmp    %rax,-0x40(%rbp)
  jle    L64
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string

tool: D7: %ld

tool: D19: %ld


assistant: ```c
int main(void) {
  long n, i, j, d, X, D, P, Q;
  scanf("%ld", &n);
  for (i = n, D = 1; i >>= 1; D++)
    ;
  X = F0(D - 1);
  P = D < 4 ? -1 : (D - 4) / 2;
  Q = n & (~((1L << (D - P - 2)) - 1));
  for (i = 0; i <= P; i++) {
    if ((n >> (D - 2 - i)) & 1) {
      j = (n >> (D - i - 1)) & ((1L << i) - 1);
      X += F1(D, i, j);
    }
  }
  d = 64 - D;
  for (i = Q; i <= n; i++)
    X += popcount64(i + (bitsReverse64(i) >> d));
  printf("%ld\n", X);
  return 0;
}
```