ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L27
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  mov    $0x0,%ebp
L12:
  mov    (%rbx),%rdi
  call   <atoi@plt>
  add    %eax,%ebp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L12
L2:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    $0x0,%ebp
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, sum = 0;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L13
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L14
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  xor    %r12d,%r12d
  jmp    L15
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, sum = 0;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L0
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  xor    %r12d,%r12d
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L17
L6:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  xor    %r12d,%r12d
  jmp    L6
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, sum = 0;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d_storeuw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,%edx
  mov    %edx,%esi
  mov    %esi,%edi
  shr    $0x8,%di
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rax)
  mov    %edi,%ecx
  mov    %cl,(%rdx)
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rax)
  mov    %esi,%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void d_storeuw(register unsigned char **ptr, register unsigned short data) {
  *(*ptr)++ = (data & 0xff00) >> 8;
  *(*ptr)++ = (data & 0x00ff) >> 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d_storeuw>:
  endbr64
  mov    %esi,%eax
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,(%rdx)
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %sil,(%rdx)
  ret
```

assistant: ```c
void d_storeuw(register unsigned char **ptr, register unsigned short data) {
  *(*ptr)++ = (data & 0xff00) >> 8;
  *(*ptr)++ = (data & 0x00ff) >> 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<d_storeuw>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%eax
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %ah,(%rdx)
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %sil,(%rdx)
  ret
```

assistant: ```c
void d_storeuw(register unsigned char **ptr, register unsigned short data) {
  *(*ptr)++ = (data & 0xff00) >> 8;
  *(*ptr)++ = (data & 0x00ff) >> 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<d_storeuw>:
  endbr64
  mov    (%rdi),%rdx
  mov    %esi,%eax
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %ah,(%rdx)
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rdi)
  mov    %sil,(%rdx)
  ret
```

assistant: ```c
void d_storeuw(register unsigned char **ptr, register unsigned short data) {
  *(*ptr)++ = (data & 0xff00) >> 8;
  *(*ptr)++ = (data & 0x00ff) >> 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cprop_test12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jne    L1
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    $0x19,%eax
  cltd
  idivl  -0x4(%rbp)
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cprop_test12(int *data) {
  int j = data[0];
  if (j == 5)
    j = j * 21 + 25 / j;
  data[1] = j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cprop_test12>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x5,%eax
  mov    $0x6e,%edx
  cmove  %edx,%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void cprop_test12(int *data) {
  int j = data[0];
  if (j == 5)
    j = j * 21 + 25 / j;
  data[1] = j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cprop_test12>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x6e,%edx
  cmp    $0x5,%eax
  cmove  %edx,%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void cprop_test12(int *data) {
  int j = data[0];
  if (j == 5)
    j = j * 21 + 25 / j;
  data[1] = j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cprop_test12>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x6e,%edx
  cmp    $0x5,%eax
  cmove  %edx,%eax
  mov    %eax,0x4(%rdi)
  ret
```

assistant: ```c
void cprop_test12(int *data) {
  int j = data[0];
  if (j == 5)
    j = j * 21 + 25 / j;
  data[1] = j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D74
type_infered: string
name: read_data
arguments: label: D82
type_infered: string
name: read_data
arguments: label: D61
type_infered: string
name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D60
type_infered: string
name: read_data
arguments: label: D38
type_infered: string
name: read_data
arguments: label: D75
type_infered: string

tool: D74: Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]


tool: D82: where - 


tool: D61: 	startx - X position from where to start moving the cursor


tool: D44: 	y_decr - Y value to be subtracted from screen height to get y pos.


tool: D22: 	trials - no. of roundtrips that the cursor will make


tool: D32: 	max_xpos - Max. value of X cursor will move to in forward direction


tool: D60: 	x_step - steps in no. of pixels cursor willmove in X direction


tool: D38: 	display - display name


tool: D75: 	"-h" - will print out this message


assistant: ```c
print_usage() {
  printf("Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]\n");
  printf("where - \n");
  printf("\tstartx - X position from where to start moving the cursor\n");
  printf("\ty_decr - Y value to be subtracted from screen height to get y pos.\n");
  printf("\ttrials - no. of roundtrips that the cursor will make\n");
  printf("\tmax_xpos - Max. value of X cursor will move to in forward direction\n");
  printf("\tx_step - steps in no. of pixels cursor willmove in X direction\n");
  printf("\tdisplay - display name\n");
  printf("\t\"-h\" - will print out this message\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: tag: D79
type_guessed: string
name: extract_symbolic_data
arguments: tag: D59
type_guessed: string
name: extract_symbolic_data
arguments: tag: D42
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string

tool: D27: Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]


tool: D19: where - 


tool: D14: 	startx - X position from where to start moving the cursor


tool: D21: 	y_decr - Y value to be subtracted from screen height to get y pos.


tool: D79: 	trials - no. of roundtrips that the cursor will make


tool: D59: 	max_xpos - Max. value of X cursor will move to in forward direction


tool: D42: 	x_step - steps in no. of pixels cursor willmove in X direction


tool: D17: 	display - display name


tool: D29: 	"-h" - will print out this message


assistant: ```c
print_usage() {
  printf("Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]\n");
  printf("where - \n");
  printf("\tstartx - X position from where to start moving the cursor\n");
  printf("\ty_decr - Y value to be subtracted from screen height to get y pos.\n");
  printf("\ttrials - no. of roundtrips that the cursor will make\n");
  printf("\tmax_xpos - Max. value of X cursor will move to in forward direction\n");
  printf("\tx_step - steps in no. of pixels cursor willmove in X direction\n");
  printf("\tdisplay - display name\n");
  printf("\t\"-h\" - will print out this message\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D67
data_type: string
name: disassemble_data
arguments: data_tag: D60
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D35
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D67: Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]


tool: D60: where - 


tool: D28: 	startx - X position from where to start moving the cursor


tool: D35: 	y_decr - Y value to be subtracted from screen height to get y pos.


tool: D1: 	trials - no. of roundtrips that the cursor will make


tool: D18: 	max_xpos - Max. value of X cursor will move to in forward direction


tool: D17: 	x_step - steps in no. of pixels cursor willmove in X direction


tool: D26: 	display - display name


tool: D7: 	"-h" - will print out this message


assistant: ```c
print_usage() {
  printf("Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]\n");
  printf("where - \n");
  printf("\tstartx - X position from where to start moving the cursor\n");
  printf("\ty_decr - Y value to be subtracted from screen height to get y pos.\n");
  printf("\ttrials - no. of roundtrips that the cursor will make\n");
  printf("\tmax_xpos - Max. value of X cursor will move to in forward direction\n");
  printf("\tx_step - steps in no. of pixels cursor willmove in X direction\n");
  printf("\tdisplay - display name\n");
  printf("\t\"-h\" - will print out this message\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    D89(%rip),%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D46
datatype: string
name: parse_data
arguments: data_tag: D50
datatype: string
name: parse_data
arguments: data_tag: D89
datatype: string
name: parse_data
arguments: data_tag: D84
datatype: string
name: parse_data
arguments: data_tag: D51
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D66
datatype: string
name: parse_data
arguments: data_tag: D27
datatype: string

tool: D46: Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]


tool: D50: where - 


tool: D89: 	startx - X position from where to start moving the cursor


tool: D84: 	y_decr - Y value to be subtracted from screen height to get y pos.


tool: D51: 	trials - no. of roundtrips that the cursor will make


tool: D19: 	max_xpos - Max. value of X cursor will move to in forward direction


tool: D32: 	x_step - steps in no. of pixels cursor willmove in X direction


tool: D66: 	display - display name


tool: D27: 	"-h" - will print out this message


assistant: ```c
print_usage() {
  printf("Usage: focus [-x startx] [-y y_decr] [-n trials] [-m max_xpos] [-s x_step] [-d display] [-h]\n");
  printf("where - \n");
  printf("\tstartx - X position from where to start moving the cursor\n");
  printf("\ty_decr - Y value to be subtracted from screen height to get y pos.\n");
  printf("\ttrials - no. of roundtrips that the cursor will make\n");
  printf("\tmax_xpos - Max. value of X cursor will move to in forward direction\n");
  printf("\tx_step - steps in no. of pixels cursor willmove in X direction\n");
  printf("\tdisplay - display name\n");
  printf("\t\"-h\" - will print out this message\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<oct2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L9:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
L5:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L9
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D18
type: string

tool: D13: %d ** %s


tool: D18: result %d --

assistant: ```c
int oct2int(char *_oct) {
  int oct = atoi(_oct);
  printf("%d ** %s\n", oct, _oct);
  int result = 0;
  int exp = 0;
  while (oct != 0) {
    result = result + (oct % 10) * pow(8, exp);
    exp++;
    oct = oct / 10;
  }
  printf("result %d --", result);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<oct2int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdx
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L15
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L23:
  mov    %ebp,%esi
  mov    $0x8,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %ecx,%ebx
  add    %ebx,%r12d
  add    $0x1,%ebp
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L23
L18:
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %ebx,%r12d
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D19: %d ** %s


tool: D4: result %d --

assistant: ```c
int oct2int(char *_oct) {
  int oct = atoi(_oct);
  printf("%d ** %s\n", oct, _oct);
  int result = 0;
  int exp = 0;
  while (oct != 0) {
    result = result + (oct % 10) * pow(8, exp);
    exp++;
    oct = oct / 10;
  }
  printf("result %d --", result);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<oct2int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <atoi@plt>
  mov    %r12,%rdx
  lea    D7(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L5
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  xchg   %ax,%ax
L21:
  mov    %ebp,%esi
  mov    $0x8,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edx
  mov    %eax,%r8d
  movslq %ebx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %r8d,%ebx
  add    %ebx,%r12d
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L21
L22:
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  xor    %r12d,%r12d
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D19
type_guessed: string

tool: D7: %d ** %s


tool: D19: result %d --

assistant: ```c
int oct2int(char *_oct) {
  int oct = atoi(_oct);
  printf("%d ** %s\n", oct, _oct);
  int result = 0;
  int exp = 0;
  while (oct != 0) {
    result = result + (oct % 10) * pow(8, exp);
    exp++;
    oct = oct / 10;
  }
  printf("result %d --", result);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<oct2int>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <atoi@plt>
  mov    %r12,%rdx
  lea    D4(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L15
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  xchg   %ax,%ax
L21:
  mov    %ebp,%esi
  mov    $0x8,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edx
  mov    %eax,%r8d
  movslq %ebx,%rax
  sar    $0x1f,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  imul   %r8d,%ebx
  add    %ebx,%r12d
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L21
L7:
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  xor    %r12d,%r12d
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D4: %d ** %s


tool: D9: result %d --

assistant: ```c
int oct2int(char *_oct) {
  int oct = atoi(_oct);
  printf("%d ** %s\n", oct, _oct);
  int result = 0;
  int exp = 0;
  while (oct != 0) {
    result = result + (oct % 10) * pow(8, exp);
    exp++;
    oct = oct / 10;
  }
  printf("result %d --", result);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Emmc_ReadBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    $0x0,%eax
  call   <Emmc_ensureDataMode@plt>
  test   %rax,%rax
  je     L34
  mov    $0xffffffff,%eax
  jmp    L30
L34:
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Emmc_doDataCommand@plt>
  test   %rax,%rax
  jns    L24
  mov    $0xffffffff,%eax
  jmp    L30
L24:
  mov    -0xc(%rbp),%eax
L30:
  leave
  ret
```

assistant: ```c
int Emmc_ReadBlock(char *buf, unsigned int buflen, unsigned int block_number) {
  if (Emmc_ensureDataMode() != 0)
    return -1;
  if (Emmc_doDataCommand(buf, 0, buflen, block_number) < 0)
    return -1;
  return buflen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Emmc_ReadBlock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x0,%eax
  call   <Emmc_ensureDataMode@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <Emmc_doDataCommand@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovns %ebx,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int Emmc_ReadBlock(char *buf, unsigned int buflen, unsigned int block_number) {
  if (Emmc_ensureDataMode() != 0)
    return -1;
  if (Emmc_doDataCommand(buf, 0, buflen, block_number) < 0)
    return -1;
  return buflen;
}
```
user: What is the c source code of the assembly code below?

```asm
<Emmc_ReadBlock>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <Emmc_ensureDataMode@plt>
  test   %rax,%rax
  jne    L11
  xor    %esi,%esi
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <Emmc_doDataCommand@plt>
  test   %rax,%rax
  js     L11
  mov    %ebx,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int Emmc_ReadBlock(char *buf, unsigned int buflen, unsigned int block_number) {
  if (Emmc_ensureDataMode() != 0)
    return -1;
  if (Emmc_doDataCommand(buf, 0, buflen, block_number) < 0)
    return -1;
  return buflen;
}
```