ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<grepline>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  call   <ftell@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L1
  mov    0x0(%rbp),%rdi
  call   <free@plt>
L1:
  xor    %r12d,%r12d
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L76:
  cmp    $0xa,%bl
  je     L40
  cmp    $0xd,%bl
  je     L40
L9:
  mov    %r14,%rdi
  mov    %r12,%r15
  add    $0x1,%r12
  call   <fgetc@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L76
L40:
  lea    0x2(%r15),%r8
  cmp    $0xd,%bl
  je     L64
L66:
  mov    D19(%rip),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <fread@plt>
L46:
  mov    (%rsp),%rax
  movb   $0xa,(%rbx,%r15,1)
  movb   $0x0,(%rbx,%r12,1)
  mov    %r12,(%rax)
  mov    %r12,%rax
  mov    %rbx,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  call   <fgetc@plt>
  mov    0x8(%rsp),%r8
  cmp    $0xa,%al
  jne    L66
  mov    D19(%rip),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <fread@plt>
  mov    %r14,%rdi
  call   <fgetc@plt>
  jmp    L46
```

assistant: ```c
size_t grepline(char **lineptr, size_t *n, FILE *stream) {
  size_t len = 0;
  size_t offset = ftell(stream);
  char trash = 0;
  char *buf = NULL;
  char sizeofnewline = 0;
  if (lineptr != NULL) {
    free(*lineptr);
  }
  do {
    trash = fgetc(stream);
    ++len;
  } while (!feof(stream) && trash != '\n' && trash != '\r');
  if (trash == '\r') {
    trash = fgetc(stream);
    if (trash == '\n') {
      ++sizeofnewline;
    }
  }
  fseek(stream, offset, SEEK_SET);
  buf = (char *)malloc(len + 1);
  fread(buf, len, 1, stream);
  if (sizeofnewline) {
    trash = fgetc(stream);
  }
  buf[len - 1] = '\n';
  buf[len] = '\0';
  *n = len;
  *lineptr = buf;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<grepline>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  call   <ftell@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L78
  mov    0x0(%rbp),%rdi
  call   <free@plt>
L78:
  xor    %r12d,%r12d
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L32:
  cmp    $0xa,%bl
  je     L75
  cmp    $0xd,%bl
  je     L75
L68:
  mov    %r14,%rdi
  mov    %r12,%r15
  add    $0x1,%r12
  call   <fgetc@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <feof@plt>
  test   %eax,%eax
  je     L32
L75:
  lea    0x2(%r15),%r8
  cmp    $0xd,%bl
  je     L41
L70:
  mov    D7(%rip),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <fread@plt>
L43:
  mov    (%rsp),%rax
  movb   $0xa,(%rbx,%r15,1)
  movb   $0x0,(%rbx,%r12,1)
  mov    %r12,(%rax)
  mov    %r12,%rax
  mov    %rbx,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  call   <fgetc@plt>
  mov    0x8(%rsp),%r8
  cmp    $0xa,%al
  jne    L70
  mov    D7(%rip),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <fread@plt>
  mov    %r14,%rdi
  call   <fgetc@plt>
  jmp    L43
```

assistant: ```c
size_t grepline(char **lineptr, size_t *n, FILE *stream) {
  size_t len = 0;
  size_t offset = ftell(stream);
  char trash = 0;
  char *buf = NULL;
  char sizeofnewline = 0;
  if (lineptr != NULL) {
    free(*lineptr);
  }
  do {
    trash = fgetc(stream);
    ++len;
  } while (!feof(stream) && trash != '\n' && trash != '\r');
  if (trash == '\r') {
    trash = fgetc(stream);
    if (trash == '\n') {
      ++sizeofnewline;
    }
  }
  fseek(stream, offset, SEEK_SET);
  buf = (char *)malloc(len + 1);
  fread(buf, len, 1, stream);
  if (sizeofnewline) {
    trash = fgetc(stream);
  }
  buf[len - 1] = '\n';
  buf[len] = '\0';
  *n = len;
  *lineptr = buf;
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<net_hashmap_core_module_inside_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1505,-0xc(%rbp)
  jmp    L4
L2:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L2
  mov    -0xc(%rbp),%eax
  and    $0x3ff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int net_hashmap_core_module_inside_hash(const char *str, int len) {
  const char *p = str;
  uint32_t hash = 5381;
  while (len--)
    hash = (((hash << 5) + hash) + *p++);
  return (hash & ((1 << 10) - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<net_hashmap_core_module_inside_hash>:
  endbr64
  test   %esi,%esi
  je     L5
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rcx
  mov    $0x1505,%eax
L29:
  mov    %eax,%edx
  shl    $0x5,%edx
  add    %edx,%eax
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L29
L28:
  and    $0x3ff,%eax
  ret
L5:
  mov    $0x1505,%eax
  jmp    L28
```

assistant: ```c
int net_hashmap_core_module_inside_hash(const char *str, int len) {
  const char *p = str;
  uint32_t hash = 5381;
  while (len--)
    hash = (((hash << 5) + hash) + *p++);
  return (hash & ((1 << 10) - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<net_hashmap_core_module_inside_hash>:
  endbr64
  test   %esi,%esi
  je     L4
  mov    %esi,%esi
  mov    $0x1505,%eax
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L5
  and    $0x3ff,%eax
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x105,%eax
  ret
```

assistant: ```c
int net_hashmap_core_module_inside_hash(const char *str, int len) {
  const char *p = str;
  uint32_t hash = 5381;
  while (len--)
    hash = (((hash << 5) + hash) + *p++);
  return (hash & ((1 << 10) - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<net_hashmap_core_module_inside_hash>:
  endbr64
  test   %esi,%esi
  je     L17
  mov    %esi,%esi
  mov    $0x1505,%eax
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L7
  and    $0x3ff,%eax
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x105,%eax
  ret
```

assistant: ```c
int net_hashmap_core_module_inside_hash(const char *str, int len) {
  const char *p = str;
  uint32_t hash = 5381;
  while (len--)
    hash = (((hash << 5) + hash) + *p++);
  return (hash & ((1 << 10) - 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <timedriver@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  timedriver();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <timedriver@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  timedriver();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <timedriver@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  timedriver();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <timedriver@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  timedriver();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<legible_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L53
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
  addq   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L2:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
L8:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L39
L60:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L66
  cmpl   $0x0,-0x18(%rbp)
  je     L66
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2c,(%rax)
L66:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D10(%rip),%rax
  leave
  ret
```

assistant: ```c
char *legible_1(const char *repr) {
  static char outbuf[128];
  int i, i1, mod;
  char *outptr;
  const char *inptr;
  outptr = outbuf;
  inptr = repr;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<legible_1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D29(%rip),%rbx
  cmpb   $0x2d,(%rdi)
  je     L7
L92:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rsi
  cltd
  sub    %edx,%esi
  lea    (%rsi,%rsi,2),%edx
  sub    %edx,%eax
  mov    %eax,%esi
  test   %eax,%eax
  jle    L40
  movzbl 0x0(%rbp),%eax
  mov    %al,(%rbx)
  cmp    $0x1,%esi
  jle    L90
  movzbl 0x1(%rbp),%eax
  mov    %al,0x1(%rbx)
L90:
  mov    %esi,%eax
  add    %rax,%rbx
L61:
  movslq %esi,%rax
  lea    0x0(%rbp,%rax,1),%rcx
  cmpb   $0x0,(%rcx)
  je     L70
  mov    $0x0,%eax
  jmp    L14
L7:
  movb   $0x2d,D29(%rip)
  add    $0x1,%rbp
  lea    0x1(%rbx),%rbx
  jmp    L92
L40:
  mov    $0x0,%esi
  jmp    L61
L26:
  mov    %rbx,%rdx
L25:
  lea    0x1(%rdx),%rbx
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rdx)
  add    $0x1,%rax
  cmpb   $0x0,(%rcx,%rax,1)
  je     L70
L14:
  mov    %esi,%edi
  add    %eax,%edi
  je     L26
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %eax,%edx
  jne    L26
  lea    0x1(%rbx),%rdx
  movb   $0x2c,(%rbx)
  jmp    L25
L70:
  movb   $0x0,(%rbx)
  lea    D29(%rip),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *legible_1(const char *repr) {
  static char outbuf[128];
  int i, i1, mod;
  char *outptr;
  const char *inptr;
  outptr = outbuf;
  inptr = repr;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<legible_1>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  cmpb   $0x2d,(%rdi)
  mov    %rdi,%rbx
  jne    L35
  movb   $0x2d,D17(%rip)
  add    $0x1,%rbx
  add    $0x1,%rbp
L35:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  cltd
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,2),%edx
  sub    %edx,%eax
  mov    %eax,%esi
  test   %eax,%eax
  jle    L80
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  cmp    $0x2,%esi
  jne    L95
  movzbl 0x1(%rbx),%eax
  mov    %al,0x1(%rbp)
L95:
  movslq %esi,%rdi
  add    %rdi,%rbp
  add    %rbx,%rdi
L61:
  cmpb   $0x0,(%rdi)
  je     L58
  lea    0x1(%rsi),%eax
  xor    %edx,%edx
  cltq
  add    %rbx,%rax
  jmp    L0
  nopl   (%rax)
L44:
  mov    %rbp,%rcx
L13:
  movzbl (%rdi),%edi
  add    $0x1,%edx
  lea    0x1(%rcx),%rbp
  mov    %dil,(%rcx)
  mov    %rax,%rdi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L58
L0:
  mov    %esi,%ebx
  add    %edx,%ebx
  je     L44
  imul   $0xaaaaaaab,%edx,%ecx
  cmp    $0x55555555,%ecx
  ja     L44
  movb   $0x2c,0x0(%rbp)
  lea    0x1(%rbp),%rcx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L58:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L80:
  mov    %rbx,%rdi
  xor    %esi,%esi
  jmp    L61
```

assistant: ```c
char *legible_1(const char *repr) {
  static char outbuf[128];
  int i, i1, mod;
  char *outptr;
  const char *inptr;
  outptr = outbuf;
  inptr = repr;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<legible_1>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  cmpb   $0x2d,(%rdi)
  mov    %rdi,%rbx
  jne    L95
  movb   $0x2d,D14(%rip)
  add    $0x1,%rbx
  add    $0x1,%rbp
L95:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  cltd
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,2),%edx
  sub    %edx,%eax
  mov    %eax,%esi
  test   %eax,%eax
  jle    L5
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  cmp    $0x2,%esi
  jne    L84
  movzbl 0x1(%rbx),%eax
  mov    %al,0x1(%rbp)
L84:
  movslq %esi,%r8
  add    %r8,%rbp
  add    %rbx,%r8
L72:
  movzbl (%r8),%ecx
  test   %cl,%cl
  je     L58
  lea    0x1(%rsi),%eax
  xor    %edx,%edx
  cltq
  add    %rbx,%rax
  jmp    L46
L26:
  mov    %cl,0x0(%rbp)
  lea    0x1(%rbp),%rdi
L82:
  mov    %rax,%r8
  movzbl (%rax),%ecx
  add    $0x1,%rax
  add    $0x1,%edx
  test   %cl,%cl
  je     L7
  mov    %rdi,%rbp
L46:
  mov    %esi,%ebx
  add    %edx,%ebx
  je     L26
  imul   $0xaaaaaaab,%edx,%edi
  cmp    $0x55555555,%edi
  ja     L26
  movb   $0x2c,0x0(%rbp)
  movzbl (%r8),%ecx
  lea    0x2(%rbp),%rdi
  mov    %cl,0x1(%rbp)
  jmp    L82
L58:
  mov    %rbp,%rdi
L7:
  movb   $0x0,(%rdi)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L5:
  mov    %rbx,%r8
  xor    %esi,%esi
  jmp    L72
```

assistant: ```c
char *legible_1(const char *repr) {
  static char outbuf[128];
  int i, i1, mod;
  char *outptr;
  const char *inptr;
  outptr = outbuf;
  inptr = repr;
  if (*inptr == '-') {
    *outptr++ = '-';
    ++inptr;
  }
  mod = strlen(inptr) % 3;
  for (i = 0; i < mod; i++)
    *outptr++ = inptr[i];
  for (i1 = i, i = 0; inptr[i1]; i++, i1++) {
    if (i % 3 == 0 && i1 != 0)
      *outptr++ = ',';
    *outptr++ = inptr[i1];
  }
  *outptr = '\0';
  return outbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__panic_assert3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    0x10(%rbp),%r8d
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string

tool: D2: user panic: %s:%d


tool: D6: assertion failed: %s %s %s


tool: D5: %s=%08x, %s=%08x


assistant: ```c
void __panic_assert3(const char *file, int line, const char *c_a, uint32_t v_a, const char *op, const char *c_b, uint32_t v_b) {
  printf("user panic: %s:%d\n", file, line);
  printf("assertion failed: %s %s %s\n", c_a, op, c_b);
  printf("%s=%08x, %s=%08x\n", c_a, v_a, c_b, v_b);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__panic_assert3>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    %r8,%r13
  mov    %r9,%rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x30(%rsp),%r8d
  mov    %rbp,%rcx
  mov    %r12d,%edx
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D25
type_infered: string

tool: D20: user panic: %s:%d


tool: D9: assertion failed: %s %s %s


tool: D25: %s=%08x, %s=%08x


assistant: ```c
void __panic_assert3(const char *file, int line, const char *c_a, uint32_t v_a, const char *op, const char *c_b, uint32_t v_b) {
  printf("user panic: %s:%d\n", file, line);
  printf("assertion failed: %s %s %s\n", c_a, op, c_b);
  printf("%s=%08x, %s=%08x\n", c_a, v_a, c_b, v_b);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__panic_assert3>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %r8,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  push   %rbx
  lea    D14(%rip),%rdi
  mov    0x30(%rsp),%ebx
  call   <printf@plt>
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string

tool: D14: user panic: %s:%d


tool: D9: assertion failed: %s %s %s


tool: D10: %s=%08x, %s=%08x


assistant: ```c
void __panic_assert3(const char *file, int line, const char *c_a, uint32_t v_a, const char *op, const char *c_b, uint32_t v_b) {
  printf("user panic: %s:%d\n", file, line);
  printf("assertion failed: %s %s %s\n", c_a, op, c_b);
  printf("%s=%08x, %s=%08x\n", c_a, v_a, c_b, v_b);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__panic_assert3>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %r8,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  push   %rbx
  lea    D21(%rip),%rdi
  mov    0x30(%rsp),%ebx
  call   <printf@plt>
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string

tool: D21: user panic: %s:%d


tool: D5: assertion failed: %s %s %s


tool: D19: %s=%08x, %s=%08x


assistant: ```c
void __panic_assert3(const char *file, int line, const char *c_a, uint32_t v_a, const char *op, const char *c_b, uint32_t v_b) {
  printf("user panic: %s:%d\n", file, line);
  printf("assertion failed: %s %s %s\n", c_a, op, c_b);
  printf("%s=%08x, %s=%08x\n", c_a, v_a, c_b, v_b);
  exit(0);
}
```