ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmp9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L52
  mov    -0x14(%rbp),%eax
  jmp    L83
L52:
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L74
  mov    -0x14(%rbp),%eax
  jmp    L83
L74:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L59
  mov    -0x14(%rbp),%eax
  jmp    L83
L59:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L92
  mov    -0x14(%rbp),%eax
  jmp    L83
L92:
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L17
  mov    -0x14(%rbp),%eax
  jmp    L83
L17:
  mov    $0x0,%eax
L83:
  pop    %rbp
  ret
```

assistant: ```c
int cmp9(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp9>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L23
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L23
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L23
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L23
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L23:
  ret
```

assistant: ```c
int cmp9(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp9>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L2
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L2
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L2
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L2
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L2:
  ret
```

assistant: ```c
int cmp9(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp9>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L21
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L21
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L21
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L21
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L21:
  ret
```

assistant: ```c
int cmp9(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_snp_round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x8(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd D4(%rip),%xmm0
  jb     L9
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: f64

tool: D4: 0.5

assistant: ```c
long _snp_round(double value) {
  long intpart;
  intpart = value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_snp_round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D0(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: f64

tool: D0: 0.5

assistant: ```c
long _snp_round(double value) {
  long intpart;
  intpart = value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_snp_round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D4(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: f64

tool: D4: 0.5

assistant: ```c
long _snp_round(double value) {
  long intpart;
  intpart = value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_snp_round>:
  endbr64
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
  comisd D5(%rip),%xmm0
  sbb    $0xffffffffffffffff,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: f64

tool: D5: 0.5

assistant: ```c
long _snp_round(double value) {
  long intpart;
  intpart = value;
  value = value - intpart;
  if (value >= 0.5)
    intpart++;
  return intpart;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L124
  mov    $0x1,%r15d
  jmp    L7
L115:
  movslq %ecx,%rsi
  mov    0x10(%rsp,%rsi,4),%edi
  lea    (%rdi,%rdi,4),%edi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdi,2),%eax
  mov    %eax,0x10(%rsp,%rsi,4)
L72:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L104
L119:
  movzbl (%rdx),%eax
  lea    -0x41(%rax),%esi
  cmp    $0x19,%sil
  ja     L115
  movslq %ebx,%rsi
  mov    %al,0x350(%rsp,%rsi,1)
  add    $0x1,%ebx
  add    $0x1,%ecx
  movslq %ecx,%rax
  movl   $0x0,0x10(%rsp,%rax,4)
  jmp    L72
L104:
  mov    %r15d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L15
  lea    0x14(%rsp),%r13
  lea    0x350(%rsp),%rbp
  lea    -0x1(%rbx),%eax
  lea    0x351(%rsp,%rax,1),%r14
  jmp    L4
L144:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L144
L55:
  add    $0x4,%r13
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L15
L4:
  mov    0x0(%r13),%r12d
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L144
  jmp    L55
L124:
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  mov    %r15d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15d
  cmp    %r15d,0xc(%rsp)
  jl     L124
L7:
  lea    0x270(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L60
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x271(%rsp,%rax,1),%r8
  mov    $0x0,%ecx
  mov    $0x0,%ebx
  jmp    L119
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D19
data_type: string

tool: D25: %d

tool: D19: Case %d: 

assistant: ```c
int main() {
  int i, j, k, l, m, len, n, c[150];
  char a[210], b[210], dec[210];
  scanf("%d", &n);
  getchar();
  for (i = 1; i <= n; i++) {
    gets(a);
    len = strlen(a);
    k = 0, l = 0;
    for (j = 0; j < len; j++) {
      if (a[j] >= 'A' && a[j] <= 'Z') {
        b[k] = a[j];
        k++;
        l++;
        c[l] = 0;
      } else {
        c[l] = c[l] * 10 + a[j] - '0';
      }
    }
    l = 1;
    printf("Case %d: ", i);
    for (j = 0; j < k; j++) {
      for (m = 0; m < c[l]; m++) {
        printf("%c", b[j]);
      }
      l++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x458,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x290(%rsp),%rax
  movl   $0x1,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x291(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0x36f(%rsp),%rax
  mov    %rax,(%rsp)
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L28
  nopw   0x0(%rax,%rax,1)
L51:
  mov    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L111
  mov    %rbx,%rdx
  lea    -0x1(%rax),%edi
  xor    %ebx,%ebx
  add    0x18(%rsp),%rdi
  xor    %ecx,%ecx
  jmp    L55
  xchg   %ax,%ax
L69:
  add    $0x1,%ebx
  mov    %al,0x370(%rsp,%rcx,1)
  add    $0x1,%rdx
  movslq %ebx,%rcx
  movl   $0x0,0x30(%rsp,%rcx,4)
  cmp    %rdi,%rdx
  je     L114
L55:
  movsbl (%rdx),%eax
  lea    -0x41(%rax),%esi
  cmp    $0x19,%sil
  jbe    L69
  mov    0x30(%rsp,%rcx,4),%esi
  add    $0x1,%rdx
  lea    (%rsi,%rsi,4),%esi
  lea    -0x30(%rax,%rsi,2),%eax
  mov    %eax,0x30(%rsp,%rcx,4)
  cmp    %rdi,%rdx
  jne    L55
L114:
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L106
  lea    0x1(%rbx),%r14d
  mov    $0x1,%r12d
  lea    0x30(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L116:
  mov    0x0(%r13,%r12,4),%ebx
  test   %ebx,%ebx
  jle    L63
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  movsbl (%rax,%r12,1),%ebp
  nopl   (%rax)
L123:
  mov    %ebp,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jne    L123
L63:
  add    $0x1,%r12
  cmp    %r12,%r14
  jne    L116
L106:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jge    L51
L28:
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x458,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L111:
  mov    0xc(%rsp),%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L106
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D14: %d

tool: D9: Case %d: 

assistant: ```c
int main() {
  int i, j, k, l, m, len, n, c[150];
  char a[210], b[210], dec[210];
  scanf("%d", &n);
  getchar();
  for (i = 1; i <= n; i++) {
    gets(a);
    len = strlen(a);
    k = 0, l = 0;
    for (j = 0; j < len; j++) {
      if (a[j] >= 'A' && a[j] <= 'Z') {
        b[k] = a[j];
        k++;
        l++;
        c[l] = 0;
      } else {
        c[l] = c[l] * 10 + a[j] - '0';
      }
    }
    l = 1;
    printf("Case %d: ", i);
    for (j = 0; j < k; j++) {
      for (m = 0; m < c[l]; m++) {
        printf("%c", b[j]);
      }
      l++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x458,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x290(%rsp),%rax
  movl   $0x1,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x291(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0x36f(%rsp),%rax
  mov    %rax,(%rsp)
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L37
  nopw   0x0(%rax,%rax,1)
L116:
  mov    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  mov    %rbx,%rdx
  lea    -0x1(%rax),%edi
  xor    %ebx,%ebx
  add    0x18(%rsp),%rdi
  xor    %ecx,%ecx
  jmp    L57
  xchg   %ax,%ax
L7:
  add    $0x1,%ebx
  mov    %al,0x370(%rsp,%rcx,1)
  add    $0x1,%rdx
  movslq %ebx,%rcx
  movl   $0x0,0x30(%rsp,%rcx,4)
  cmp    %rdi,%rdx
  je     L113
L57:
  movsbl (%rdx),%eax
  lea    -0x41(%rax),%esi
  cmp    $0x19,%sil
  jbe    L7
  mov    0x30(%rsp,%rcx,4),%esi
  add    $0x1,%rdx
  lea    (%rsi,%rsi,4),%esi
  lea    -0x30(%rax,%rsi,2),%eax
  mov    %eax,0x30(%rsp,%rcx,4)
  cmp    %rdi,%rdx
  jne    L57
L113:
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L86
  lea    0x1(%rbx),%r14d
  mov    $0x1,%r12d
  lea    0x30(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L106:
  mov    0x0(%r13,%r12,4),%ebx
  test   %ebx,%ebx
  jle    L58
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  movsbl (%rax,%r12,1),%ebp
  nopl   (%rax)
L70:
  mov    %ebp,%edi
  add    $0x1,%r15d
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jne    L70
L58:
  add    $0x1,%r12
  cmp    %r12,%r14
  jne    L106
L86:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jge    L116
L37:
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x458,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    0xc(%rsp),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L86
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D19
type: string

tool: D8: %d

tool: D19: Case %d: 

assistant: ```c
int main() {
  int i, j, k, l, m, len, n, c[150];
  char a[210], b[210], dec[210];
  scanf("%d", &n);
  getchar();
  for (i = 1; i <= n; i++) {
    gets(a);
    len = strlen(a);
    k = 0, l = 0;
    for (j = 0; j < len; j++) {
      if (a[j] >= 'A' && a[j] <= 'Z') {
        b[k] = a[j];
        k++;
        l++;
        c[l] = 0;
      } else {
        c[l] = c[l] * 10 + a[j] - '0';
      }
    }
    l = 1;
    printf("Case %d: ", i);
    for (j = 0; j < k; j++) {
      for (m = 0; m < c[l]; m++) {
        printf("%c", b[j]);
      }
      l++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<to_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jle    L18
  cmpl   $0xf,-0x14(%rbp)
  jg     L18
  movzbl -0x1(%rbp),%eax
  add    $0x27,%eax
  mov    %al,-0x1(%rbp)
L18:
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char to_char(int x) {
  char h = (char)(x + '0');
  if ((x >= 10) && (x <= 15)) {
    h += 39;
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<to_char>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x6,%edx
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char to_char(int x) {
  char h = (char)(x + '0');
  if ((x >= 10) && (x <= 15)) {
    h += 39;
  }
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to_char>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x6,%edx
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char to_char(int x) {
  char h = (char)(x + '0');
  if ((x >= 10) && (x <= 15)) {
    h += 39;
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<to_char>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x30(%rdi),%eax
  add    $0x57,%edi
  cmp    $0x6,%edx
  cmovb  %edi,%eax
  ret
```

assistant: ```c
char to_char(int x) {
  char h = (char)(x + '0');
  if ((x >= 10) && (x <= 15)) {
    h += 39;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<utils_dtofixstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%r12d
  movq   %xmm0,%rbp
  ucomisd %xmm0,%xmm0
  setnp  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movq   %rbp,%xmm0
  andpd  D5(%rip),%xmm0
  ucomisd D1(%rip),%xmm0
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%edi
  movq   %rbp,%xmm0
  call   <utils_roundd@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <utils_dtostr@plt>
  lea    0x1(%r13),%rbp
  cmpb   $0x0,0x1(%r13)
  je     L11
  mov    %rbp,%rax
  mov    $0x1,%edx
  sub    %ebp,%edx
L137:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L137
L47:
  cmp    %ecx,%ebx
  jl     L37
  mov    %ebx,%edx
  sub    %ecx,%edx
  lea    0x1(%rax,%rdx,1),%rdx
L81:
  add    $0x1,%rax
  movb   $0x30,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L81
L15:
  movb   $0x0,(%rdx)
  cmpb   $0x2d,0x0(%r13)
  jne    L138
L101:
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
  lea    0x1(%rax),%rcx
  cmpb   $0x0,0x1(%rax)
  je     L35
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L62:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L62
L32:
  mov    %ecx,%esi
  sub    %r12d,%esi
  test   %esi,%esi
  jle    L25
  mov    %rbp,%rdi
  call   <_shift_right_nstr@plt>
L74:
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %rbp,%rax
  mov    $0x0,%ecx
  jmp    L47
L37:
  mov    %rax,%rdx
  jmp    L15
L138:
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <_shift_right_nstr@plt>
  movb   $0x20,0x0(%r13)
  jmp    L101
L35:
  mov    $0x0,%ecx
  jmp    L32
L25:
  jns    L74
  mov    %r12d,%esi
  sub    %ecx,%esi
  mov    %rbp,%rdi
  call   <_shift_left_nstr@plt>
  jmp    L74
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D1
data_type: byte[8]

tool: {"D5": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D1": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

assistant: ```c
void utils_dtofixstr(char *buff, int digits, int dplaces, double value) {
  assert(!isnan(value));
  assert(!isinf(value));
  value = utils_roundd(value, dplaces);
  utils_dtostr(buff, digits, value);
  char *out = buff;
  int i = 0;
  while (*++out)
    i++;
  while (i++ <= digits)
    *out++ = '0';
  *out = 0;
  out = buff;
  if (*out++ != '-') {
    _shift_right_nstr(buff, 1);
    *buff = ' ';
  }
  char *dp = strchr(out, '.');
  i = 0;
  if (!dp) {
    i = dplaces;
  } else {
    while (*++dp)
      i++;
  }
  int shift = i - dplaces;
  if (shift > 0) {
    _shift_right_nstr(out, shift);
  } else if (shift < 0) {
    _shift_left_nstr(out, -1 * shift);
  }
  out[digits + 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *range(int *arr, int arrlen) {
  int i;
  for (i = 0; i < arrlen; ++i)
    arr[i] = i;
  return arr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<range>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L19
  mov    %esi,%esi
  mov    $0x0,%edx
L11:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L11
L19:
  ret
```

assistant: ```c
int *range(int *arr, int arrlen) {
  int i;
  for (i = 0; i < arrlen; ++i)
    arr[i] = i;
  return arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<range>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L13
  movslq %esi,%rsi
  xor    %edx,%edx
L15:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L15
L13:
  ret
```

assistant: ```c
int *range(int *arr, int arrlen) {
  int i;
  for (i = 0; i < arrlen; ++i)
    arr[i] = i;
  return arr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<range>:
  endbr64
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L55
  lea    -0x1(%rsi),%edx
  cmp    $0x2,%edx
  jbe    L38
  mov    %esi,%ecx
  movdqa D19(%rip),%xmm0
  movdqa D12(%rip),%xmm2
  mov    %rdi,%rdx
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L27:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rdx)
  cmp    %rcx,%rdx
  jne    L27
  mov    %esi,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%sil
  je     L59
L1:
  movslq %edx,%rcx
  mov    %edx,(%rax,%rcx,4)
  lea    0x0(,%rcx,4),%rdi
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%esi
  jle    L55
  add    $0x2,%edx
  mov    %ecx,0x4(%rax,%rdi,1)
  cmp    %edx,%esi
  jle    L55
  mov    %edx,0x8(%rax,%rdi,1)
L55:
  ret
  nopl   (%rax)
L59:
  ret
L38:
  xor    %edx,%edx
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D12
type_guessed: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *range(int *arr, int arrlen) {
  int i;
  for (i = 0; i < arrlen; ++i)
    arr[i] = i;
  return arr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printDate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: %s

assistant: ```c
void printDate(int taskid) {
  time_t t = time(NULL);
  printf("%s", ctime(&t));
}
```