ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<Q_toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int Q_toupper(int c) {
  if (((c) >= 'a' && (c) <= 'z')) {
    c -= ('a' - 'A');
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Q_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int Q_toupper(int c) {
  if (((c) >= 'a' && (c) <= 'z')) {
    c -= ('a' - 'A');
  }
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<Q_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int Q_toupper(int c) {
  if (((c) >= 'a' && (c) <= 'z')) {
    c -= ('a' - 'A');
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_file_duration>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  movaps %xmm0,0x190(%rsp)
  movaps %xmm0,0x1a0(%rsp)
  movaps %xmm0,0x1b0(%rsp)
  movaps %xmm0,0x1c0(%rsp)
  movaps %xmm0,0x1d0(%rsp)
  movaps %xmm0,0x1e0(%rsp)
  movaps %xmm0,0x1f0(%rsp)
  test   %rdi,%rdi
  je     L22
  mov    %rsp,%r12
  mov    %rdi,%rdx
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  lea    0x100(%rsp),%rbp
  call   <sprintf@plt>
  mov    $0x100,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <get_shell_stdout@plt>
  test   %eax,%eax
  js     L25
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <strtof@plt>
  lea    D26(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x218,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    $0xffffffff,%r12d
  jmp    L14
L25:
  lea    D27(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <puts@plt>
  jmp    L14
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D27
type: string

tool: D21: ffprobe -i %s -show_format -v quiet | sed -n 's/duration=//p'

tool: D26: %d


tool: D27: ###ERR: Exec Cmd Err.

assistant: ```c
int get_file_duration(const char *file_name) {
  int ret = 0, i_duration = 0;
  char cmd[(256)] = {0}, str_duration[(256)] = {0};
  if (file_name == NULL)
    return -1;
  sprintf(cmd, "ffprobe -i %s -show_format -v quiet | sed -n \'s/duration=//p\'", file_name);
  ret = get_shell_stdout(cmd, str_duration, sizeof(str_duration));
  if (ret < 0) {
    printf("###ERR: Exec Cmd Err.\r\n");
    return -2;
  }
  i_duration = (int)strtof(str_duration, NULL);
  printf("%d\r\n", i_duration);
  return i_duration;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_file_duration>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  movaps %xmm0,0x190(%rsp)
  movaps %xmm0,0x1a0(%rsp)
  movaps %xmm0,0x1b0(%rsp)
  movaps %xmm0,0x1c0(%rsp)
  movaps %xmm0,0x1d0(%rsp)
  movaps %xmm0,0x1e0(%rsp)
  movaps %xmm0,0x1f0(%rsp)
  test   %rdi,%rdi
  je     L40
  mov    %rsp,%r12
  mov    %rdi,%rdx
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  lea    0x100(%rsp),%rbp
  call   <sprintf@plt>
  mov    $0x100,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <get_shell_stdout@plt>
  test   %eax,%eax
  js     L3
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <strtof@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%r12d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x218,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    $0xffffffff,%r12d
  jmp    L14
L3:
  lea    D21(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <puts@plt>
  jmp    L14
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string

tool: D0: ffprobe -i %s -show_format -v quiet | sed -n 's/duration=//p'

tool: D11: %d


tool: D21: ###ERR: Exec Cmd Err.

assistant: ```c
int get_file_duration(const char *file_name) {
  int ret = 0, i_duration = 0;
  char cmd[(256)] = {0}, str_duration[(256)] = {0};
  if (file_name == NULL)
    return -1;
  sprintf(cmd, "ffprobe -i %s -show_format -v quiet | sed -n \'s/duration=//p\'", file_name);
  ret = get_shell_stdout(cmd, str_duration, sizeof(str_duration));
  if (ret < 0) {
    printf("###ERR: Exec Cmd Err.\r\n");
    return -2;
  }
  i_duration = (int)strtof(str_duration, NULL);
  printf("%d\r\n", i_duration);
  return i_duration;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ovl_do_whiteout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ovl_do_whiteout_v2@plt>
  leave
  ret
```

assistant: ```c
int ovl_do_whiteout(struct inode *dir, struct dentry *dentry, struct dentry *ovlentry) {
  if ((0))
    return ovl_do_whiteout_v1(dir, dentry);
  return ovl_do_whiteout_v2(dir, dentry);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ovl_do_whiteout>:
  endbr64
  sub    $0x8,%rsp
  call   <ovl_do_whiteout_v2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ovl_do_whiteout(struct inode *dir, struct dentry *dentry, struct dentry *ovlentry) {
  if ((0))
    return ovl_do_whiteout_v1(dir, dentry);
  return ovl_do_whiteout_v2(dir, dentry);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ovl_do_whiteout>:
  endbr64
  jmp    1050 <ovl_do_whiteout_v2@plt>
```

assistant: ```c
int ovl_do_whiteout(struct inode *dir, struct dentry *dentry, struct dentry *ovlentry) {
  if ((0))
    return ovl_do_whiteout_v1(dir, dentry);
  return ovl_do_whiteout_v2(dir, dentry);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseComplement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <complement@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverseComplement(char *string) {
  char *complementString = complement(string);
  char *reverseComplement = reverse(complementString);
  free(complementString);
  return reverseComplement;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverseComplement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <complement@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverseComplement(char *string) {
  char *complementString = complement(string);
  char *reverseComplement = reverse(complementString);
  free(complementString);
  return reverseComplement;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverseComplement>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <complement@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reverseComplement(char *string) {
  char *complementString = complement(string);
  char *reverseComplement = reverse(complementString);
  free(complementString);
  return reverseComplement;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverseComplement>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <complement@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *reverseComplement(char *string) {
  char *complementString = complement(string);
  char *reverseComplement = reverse(complementString);
  free(complementString);
  return reverseComplement;
}
```
user: What is the c source code of the assembly code below?

```asm
<xor_8regs_4>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  shr    $0x6,%rdi
L9:
  mov    (%rax),%rcx
  xor    (%rsi),%rcx
  xor    (%rdx),%rcx
  xor    (%r8),%rcx
  mov    %rcx,(%rax)
  mov    0x8(%rax),%rcx
  xor    0x8(%rsi),%rcx
  xor    0x8(%rdx),%rcx
  xor    0x8(%r8),%rcx
  mov    %rcx,0x8(%rax)
  mov    0x10(%rax),%rcx
  xor    0x10(%rsi),%rcx
  xor    0x10(%rdx),%rcx
  xor    0x10(%r8),%rcx
  mov    %rcx,0x10(%rax)
  mov    0x18(%rax),%rcx
  xor    0x18(%rsi),%rcx
  xor    0x18(%rdx),%rcx
  xor    0x18(%r8),%rcx
  mov    %rcx,0x18(%rax)
  mov    0x20(%rax),%rcx
  xor    0x20(%rsi),%rcx
  xor    0x20(%rdx),%rcx
  xor    0x20(%r8),%rcx
  mov    %rcx,0x20(%rax)
  mov    0x28(%rax),%rcx
  xor    0x28(%rsi),%rcx
  xor    0x28(%rdx),%rcx
  xor    0x28(%r8),%rcx
  mov    %rcx,0x28(%rax)
  mov    0x30(%rax),%rcx
  xor    0x30(%rsi),%rcx
  xor    0x30(%rdx),%rcx
  xor    0x30(%r8),%rcx
  mov    %rcx,0x30(%rax)
  mov    0x38(%rax),%rcx
  xor    0x38(%rsi),%rcx
  xor    0x38(%rdx),%rcx
  xor    0x38(%r8),%rcx
  mov    %rcx,0x38(%rax)
  add    $0x40,%rax
  add    $0x40,%rsi
  add    $0x40,%rdx
  add    $0x40,%r8
  sub    $0x1,%rdi
  test   %rdi,%rdi
  jg     L9
  ret
```

assistant: ```c
void xor_8regs_4(unsigned long bytes, unsigned long *p1, unsigned long *p2, unsigned long *p3, unsigned long *p4) {
  long lines = bytes / (sizeof(long)) / 8;
  do {
    p1[0] ^= p2[0] ^ p3[0] ^ p4[0];
    p1[1] ^= p2[1] ^ p3[1] ^ p4[1];
    p1[2] ^= p2[2] ^ p3[2] ^ p4[2];
    p1[3] ^= p2[3] ^ p3[3] ^ p4[3];
    p1[4] ^= p2[4] ^ p3[4] ^ p4[4];
    p1[5] ^= p2[5] ^ p3[5] ^ p4[5];
    p1[6] ^= p2[6] ^ p3[6] ^ p4[6];
    p1[7] ^= p2[7] ^ p3[7] ^ p4[7];
    p1 += 8;
    p2 += 8;
    p3 += 8;
    p4 += 8;
  } while (--lines > 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xor_8regs_4>:
  endbr64
  mov    %rsi,%rax
  shr    $0x6,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  nopl   0x0(%rax)
L8:
  mov    (%rax),%rcx
  xor    (%rsi),%rcx
  sub    $0x1,%rdi
  add    $0x40,%rax
  xor    (%rdx),%rcx
  xor    (%r8),%rcx
  add    $0x40,%rsi
  add    $0x40,%rdx
  mov    %rcx,-0x40(%rax)
  mov    -0x38(%rax),%rcx
  add    $0x40,%r8
  xor    -0x38(%rsi),%rcx
  xor    -0x38(%rdx),%rcx
  xor    -0x38(%r8),%rcx
  mov    %rcx,-0x38(%rax)
  mov    -0x30(%rax),%rcx
  xor    -0x30(%rsi),%rcx
  xor    -0x30(%rdx),%rcx
  xor    -0x30(%r8),%rcx
  mov    %rcx,-0x30(%rax)
  mov    -0x28(%rax),%rcx
  xor    -0x28(%rsi),%rcx
  xor    -0x28(%rdx),%rcx
  xor    -0x28(%r8),%rcx
  mov    %rcx,-0x28(%rax)
  mov    -0x20(%rax),%rcx
  xor    -0x20(%rsi),%rcx
  xor    -0x20(%rdx),%rcx
  xor    -0x20(%r8),%rcx
  mov    %rcx,-0x20(%rax)
  mov    -0x18(%rax),%rcx
  xor    -0x18(%rsi),%rcx
  xor    -0x18(%rdx),%rcx
  xor    -0x18(%r8),%rcx
  mov    %rcx,-0x18(%rax)
  mov    -0x10(%rax),%rcx
  xor    -0x10(%rsi),%rcx
  xor    -0x10(%rdx),%rcx
  xor    -0x10(%r8),%rcx
  mov    %rcx,-0x10(%rax)
  mov    -0x8(%rax),%rcx
  xor    -0x8(%rsi),%rcx
  xor    -0x8(%rdx),%rcx
  xor    -0x8(%r8),%rcx
  mov    %rcx,-0x8(%rax)
  test   %rdi,%rdi
  jg     L8
  ret
```

assistant: ```c
void xor_8regs_4(unsigned long bytes, unsigned long *p1, unsigned long *p2, unsigned long *p3, unsigned long *p4) {
  long lines = bytes / (sizeof(long)) / 8;
  do {
    p1[0] ^= p2[0] ^ p3[0] ^ p4[0];
    p1[1] ^= p2[1] ^ p3[1] ^ p4[1];
    p1[2] ^= p2[2] ^ p3[2] ^ p4[2];
    p1[3] ^= p2[3] ^ p3[3] ^ p4[3];
    p1[4] ^= p2[4] ^ p3[4] ^ p4[4];
    p1[5] ^= p2[5] ^ p3[5] ^ p4[5];
    p1[6] ^= p2[6] ^ p3[6] ^ p4[6];
    p1[7] ^= p2[7] ^ p3[7] ^ p4[7];
    p1 += 8;
    p2 += 8;
    p3 += 8;
    p4 += 8;
  } while (--lines > 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xor_8regs_4>:
  endbr64
  mov    %rsi,%rax
  shr    $0x6,%rdi
  lea    0x3f(%rax),%r9
  mov    %rdi,%rsi
  mov    %r9,%r10
  sub    %rcx,%r10
  cmp    $0x7e,%r10
  mov    %r9,%r10
  seta   %r11b
  sub    %rdx,%r10
  cmp    $0x7e,%r10
  seta   %r10b
  test   %r10b,%r11b
  je     L23
  sub    %r8,%r9
  cmp    $0x7e,%r9
  jbe    L23
  test   %rdi,%rdi
  mov    $0x1,%edi
  cmovle %rdi,%rsi
  shl    $0x6,%rsi
  add    %r8,%rsi
  nopw   0x0(%rax,%rax,1)
L30:
  movdqu 0x10(%rdx),%xmm5
  movdqu 0x10(%rcx),%xmm6
  add    $0x40,%r8
  add    $0x40,%rcx
  movdqu -0x30(%r8),%xmm0
  movdqu 0x10(%rax),%xmm2
  add    $0x40,%rdx
  add    $0x40,%rax
  movdqu -0x20(%rdx),%xmm7
  movdqu -0x20(%rax),%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm2
  movdqu -0x20(%rcx),%xmm5
  movdqu -0x10(%rdx),%xmm6
  pxor   %xmm0,%xmm2
  movdqu -0x20(%r8),%xmm0
  pxor   %xmm7,%xmm1
  movdqu -0x10(%r8),%xmm3
  movdqu -0x10(%rcx),%xmm7
  movdqu -0x40(%r8),%xmm4
  pxor   %xmm5,%xmm0
  movdqu -0x40(%rdx),%xmm5
  pxor   %xmm0,%xmm1
  movdqu -0x10(%rax),%xmm0
  pxor   %xmm7,%xmm3
  pxor   %xmm6,%xmm0
  movdqu -0x40(%rcx),%xmm6
  movups %xmm2,-0x30(%rax)
  pxor   %xmm3,%xmm0
  movdqu -0x40(%rax),%xmm3
  movups %xmm1,-0x20(%rax)
  pxor   %xmm6,%xmm4
  movups %xmm0,-0x10(%rax)
  pxor   %xmm5,%xmm3
  pxor   %xmm4,%xmm3
  movups %xmm3,-0x40(%rax)
  cmp    %r8,%rsi
  jne    L30
  ret
  xchg   %ax,%ax
L23:
  mov    (%rdx),%rsi
  xor    (%rax),%rsi
  sub    $0x1,%rdi
  add    $0x40,%rax
  xor    (%rcx),%rsi
  xor    (%r8),%rsi
  add    $0x40,%rdx
  add    $0x40,%rcx
  mov    %rsi,-0x40(%rax)
  mov    -0x38(%rdx),%rsi
  add    $0x40,%r8
  xor    -0x38(%rax),%rsi
  xor    -0x38(%rcx),%rsi
  xor    -0x38(%r8),%rsi
  mov    %rsi,-0x38(%rax)
  mov    -0x30(%rax),%rsi
  xor    -0x30(%rdx),%rsi
  xor    -0x30(%rcx),%rsi
  xor    -0x30(%r8),%rsi
  mov    %rsi,-0x30(%rax)
  mov    -0x28(%rax),%rsi
  xor    -0x28(%rdx),%rsi
  xor    -0x28(%rcx),%rsi
  xor    -0x28(%r8),%rsi
  mov    %rsi,-0x28(%rax)
  mov    -0x20(%rax),%rsi
  xor    -0x20(%rdx),%rsi
  xor    -0x20(%rcx),%rsi
  xor    -0x20(%r8),%rsi
  mov    %rsi,-0x20(%rax)
  mov    -0x18(%rax),%rsi
  xor    -0x18(%rdx),%rsi
  xor    -0x18(%rcx),%rsi
  xor    -0x18(%r8),%rsi
  mov    %rsi,-0x18(%rax)
  mov    -0x10(%rax),%rsi
  xor    -0x10(%rdx),%rsi
  xor    -0x10(%rcx),%rsi
  xor    -0x10(%r8),%rsi
  mov    %rsi,-0x10(%rax)
  mov    -0x8(%rax),%rsi
  xor    -0x8(%rdx),%rsi
  xor    -0x8(%rcx),%rsi
  xor    -0x8(%r8),%rsi
  mov    %rsi,-0x8(%rax)
  test   %rdi,%rdi
  jg     L23
  ret
```

assistant: ```c
void xor_8regs_4(unsigned long bytes, unsigned long *p1, unsigned long *p2, unsigned long *p3, unsigned long *p4) {
  long lines = bytes / (sizeof(long)) / 8;
  do {
    p1[0] ^= p2[0] ^ p3[0] ^ p4[0];
    p1[1] ^= p2[1] ^ p3[1] ^ p4[1];
    p1[2] ^= p2[2] ^ p3[2] ^ p4[2];
    p1[3] ^= p2[3] ^ p3[3] ^ p4[3];
    p1[4] ^= p2[4] ^ p3[4] ^ p4[4];
    p1[5] ^= p2[5] ^ p3[5] ^ p4[5];
    p1[6] ^= p2[6] ^ p3[6] ^ p4[6];
    p1[7] ^= p2[7] ^ p3[7] ^ p4[7];
    p1 += 8;
    p2 += 8;
    p3 += 8;
    p4 += 8;
  } while (--lines > 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fromwho>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  mov    $0xd,%esi
  mov    $0x15,%edi
  call   <mvaddstr@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: Mark Hessling - (M.Hessling@gu.edu.au)

assistant: ```c
int fromwho(void) {
  mvaddstr(21, 13, "Mark Hessling - (M.Hessling@gu.edu.au)");
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fromwho>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdx
  mov    $0xd,%esi
  mov    $0x15,%edi
  call   <mvaddstr@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: Mark Hessling - (M.Hessling@gu.edu.au)

assistant: ```c
int fromwho(void) {
  mvaddstr(21, 13, "Mark Hessling - (M.Hessling@gu.edu.au)");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fromwho>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0x15,%edi
  lea    D1(%rip),%rdx
  call   <mvaddstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: Mark Hessling - (M.Hessling@gu.edu.au)

assistant: ```c
int fromwho(void) {
  mvaddstr(21, 13, "Mark Hessling - (M.Hessling@gu.edu.au)");
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fromwho>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0x15,%edi
  lea    D7(%rip),%rdx
  call   <mvaddstr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: Mark Hessling - (M.Hessling@gu.edu.au)

assistant: ```c
int fromwho(void) {
  mvaddstr(21, 13, "Mark Hessling - (M.Hessling@gu.edu.au)");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__pause@plt>
  mov    $0x0,%eax
  call   <__exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: Bruno!


assistant: ```c
main() {
  printf("Bruno!\n");
  __pause();
  __exit();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__pause@plt>
  mov    $0x0,%eax
  call   <__exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Bruno!


assistant: ```c
main() {
  printf("Bruno!\n");
  __pause();
  __exit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__pause@plt>
  xor    %eax,%eax
  call   <__exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: Bruno!


assistant: ```c
main() {
  printf("Bruno!\n");
  __pause();
  __exit();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__pause@plt>
  xor    %eax,%eax
  call   <__exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: Bruno!


assistant: ```c
main() {
  printf("Bruno!\n");
  __pause();
  __exit();
}
```
user: Translate the below assembly code into C programming language:

```asm
<LePalavra>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D11(%rip),%rdx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L3
  lea    D11(%rip),%rax
  jmp    L0
L3:
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type: string

tool: D19: %s

assistant: ```c
char *LePalavra(FILE *f) {
  static char palavra[100];
  if (fscanf(f, "%s", palavra) == 1)
    return (palavra);
  else
    return ((char *)NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LePalavra>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdx
  lea    D6(%rip),%rsi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  lea    D21(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %s

assistant: ```c
char *LePalavra(FILE *f) {
  static char palavra[100];
  if (fscanf(f, "%s", palavra) == 1)
    return (palavra);
  else
    return ((char *)NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LePalavra>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rbx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdx
  call   <fscanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
type_infered: string

tool: D11: %s

assistant: ```c
char *LePalavra(FILE *f) {
  static char palavra[100];
  if (fscanf(f, "%s", palavra) == 1)
    return (palavra);
  else
    return ((char *)NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LePalavra>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdx
  call   <fscanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type: string

tool: D15: %s

assistant: ```c
char *LePalavra(FILE *f) {
  static char palavra[100];
  if (fscanf(f, "%s", palavra) == 1)
    return (palavra);
  else
    return ((char *)NULL);
}
```