ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <check_obstack_printf_int@plt>
  xor    %eax,%eax
  call   <check_obstack_printf_typical@plt>
  xor    %eax,%eax
  call   <check_obstack_printf_two_times@plt>
  mov    $0x2,%ecx
  movsd  D12(%rip),%xmm0
  lea    D28(%rip),%rdx
  lea    D39(%rip),%rsi
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <check_obstack_vprintf@plt>
  lea    D21(%rip),%rdx
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  lea    D60(%rip),%rdi
  call   <check_obstack_vprintf@plt>
  xor    %eax,%eax
  call   <check_open_obstack_stream@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: f64
name: retrieve_data
arguments: label: D28
data_type: string
name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D38
data_type: string
name: retrieve_data
arguments: label: D60
data_type: string

tool: D12: 3.4

tool: D28: one

tool: D39: %s and %d then %.1f

tool: D24: one and 2 then 3.4

tool: D21: two
three

tool: D38: one
%s

tool: D60: one
two
three

assistant: ```c
int main(int argc, char *argv[]) {
  check_obstack_printf_int();
  check_obstack_printf_typical();
  check_obstack_printf_two_times();
  check_obstack_vprintf("one and 2 then 3.4", "%s and %d then %.1f", "one", 2, 3.4);
  check_obstack_vprintf("one\ntwo\nthree", "one\n%s", "two\nthree");
  check_open_obstack_stream();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rd_fd_set_nonblocking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L25
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D22(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L23
L25:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L19
L23:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
__attribute__((unused)) int rd_fd_set_nonblocking(int fd) {
  int fl = fcntl(fd, F_GETFL, 0);
  if (fl == -1 || fcntl(fd, F_SETFL, fl | O_NONBLOCK) == -1)
    return errno;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rd_fd_set_nonblocking>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D38(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    D35(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D33(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L15
L14:
  pop    %rbx
  ret
L15:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jmp    L14
```

assistant: ```c
__attribute__((unused)) int rd_fd_set_nonblocking(int fd) {
  int fl = fcntl(fd, F_GETFL, 0);
  if (fl == -1 || fcntl(fd, F_SETFL, fl | O_NONBLOCK) == -1)
    return errno;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rd_fd_set_nonblocking>:
  endbr64
  mov    D28(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    D9(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L15
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  mov    D12(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
```

assistant: ```c
__attribute__((unused)) int rd_fd_set_nonblocking(int fd) {
  int fl = fcntl(fd, F_GETFL, 0);
  if (fl == -1 || fcntl(fd, F_SETFL, fl | O_NONBLOCK) == -1)
    return errno;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rd_fd_set_nonblocking>:
  endbr64
  mov    D5(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L10
  mov    D33(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L10
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  mov    D32(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
```

assistant: ```c
__attribute__((unused)) int rd_fd_set_nonblocking(int fd) {
  int fl = fcntl(fd, F_GETFL, 0);
  if (fl == -1 || fcntl(fd, F_SETFL, fl | O_NONBLOCK) == -1)
    return errno;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L77
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L22
L77:
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
  jmp    L46
L22:
  nop
L46:
  cmpl   $0x0,-0xc(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L35
L31:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L78
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L78:
  mov    -0x8(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
char *get_line(char *tmp) {
  char *ptr = tmp;
  int len = 0;
  while (*ptr != '\n') {
    if (*ptr++ == '\r' && *ptr == '\n')
      break;
    len++;
  }
  if (len == 0)
    return NULL;
  ptr = (char *)malloc(len + 1);
  if (ptr) {
    memcpy(ptr, tmp, len);
    *(ptr + len) = '\0';
  }
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%edx
  cmp    $0xa,%dl
  je     L88
  mov    %rdi,%r12
  mov    %rdi,%rcx
  mov    $0x1,%eax
  jmp    L42
L84:
  movzbl (%rcx),%edx
  cmp    $0xa,%dl
  je     L78
L79:
  add    $0x1,%eax
L42:
  lea    -0x1(%rax),%ebx
  add    $0x1,%rcx
  cmp    $0xd,%dl
  je     L84
  mov    %eax,%ebx
  movzbl (%rcx),%edx
  cmp    $0xa,%dl
  jne    L79
L78:
  mov    $0x0,%ebp
  test   %ebx,%ebx
  je     L22
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L56
L22:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L22
L88:
  mov    $0x0,%ebp
  jmp    L22
```

assistant: ```c
char *get_line(char *tmp) {
  char *ptr = tmp;
  int len = 0;
  while (*ptr != '\n') {
    if (*ptr++ == '\r' && *ptr == '\n')
      break;
    len++;
  }
  if (len == 0)
    return NULL;
  ptr = (char *)malloc(len + 1);
  if (ptr) {
    memcpy(ptr, tmp, len);
    *(ptr + len) = '\0';
  }
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_line>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  cmp    $0xa,%dil
  jne    L45
  jmp    L64
  nopl   (%rax)
L60:
  movslq %ecx,%rbx
  cmp    $0xa,%dl
  je     L57
L3:
  add    $0x1,%rax
  add    $0x1,%ecx
  mov    %edx,%edi
L45:
  movzbl 0x1(%rbp,%rax,1),%edx
  movslq %eax,%rbx
  cmp    $0xd,%dil
  jne    L60
  cmp    $0xa,%dl
  jne    L3
  test   %ebx,%ebx
  jne    L57
L64:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L64
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_line(char *tmp) {
  char *ptr = tmp;
  int len = 0;
  while (*ptr != '\n') {
    if (*ptr++ == '\r' && *ptr == '\n')
      break;
    len++;
  }
  if (len == 0)
    return NULL;
  ptr = (char *)malloc(len + 1);
  if (ptr) {
    memcpy(ptr, tmp, len);
    *(ptr + len) = '\0';
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_line>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  cmp    $0xa,%dil
  jne    L5
  jmp    L38
  nopl   (%rax)
L53:
  movslq %ecx,%rbx
  cmp    $0xa,%dl
  je     L56
L11:
  add    $0x1,%rax
  add    $0x1,%ecx
  mov    %edx,%edi
L5:
  movzbl 0x1(%rbp,%rax,1),%edx
  movslq %eax,%rbx
  cmp    $0xd,%dil
  jne    L53
  cmp    $0xa,%dl
  jne    L11
  test   %ebx,%ebx
  jne    L56
L38:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L38
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_line(char *tmp) {
  char *ptr = tmp;
  int len = 0;
  while (*ptr != '\n') {
    if (*ptr++ == '\r' && *ptr == '\n')
      break;
    len++;
  }
  if (len == 0)
    return NULL;
  ptr = (char *)malloc(len + 1);
  if (ptr) {
    memcpy(ptr, tmp, len);
    *(ptr + len) = '\0';
  }
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ast_hashtab_compare_shorts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jge    L14
  mov    $0xffffffff,%eax
  jmp    L16
L14:
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jne    L10
  mov    $0x0,%eax
  jmp    L16
L10:
  mov    $0x1,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int ast_hashtab_compare_shorts(const void *a, const void *b) {
  short as = *((short *)a);
  short bs = *((short *)b);
  if (as < bs)
    return -1;
  else if (as == bs)
    return 0;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ast_hashtab_compare_shorts>:
  endbr64
  movzwl (%rdi),%ecx
  movzwl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dx,%cx
  jl     L8
  setne  %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int ast_hashtab_compare_shorts(const void *a, const void *b) {
  short as = *((short *)a);
  short bs = *((short *)b);
  if (as < bs)
    return -1;
  else if (as == bs)
    return 0;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ast_hashtab_compare_shorts>:
  endbr64
  movzwl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dx,(%rdi)
  jl     L0
  setne  %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int ast_hashtab_compare_shorts(const void *a, const void *b) {
  short as = *((short *)a);
  short bs = *((short *)b);
  if (as < bs)
    return -1;
  else if (as == bs)
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ast_hashtab_compare_shorts>:
  endbr64
  movzwl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dx,(%rdi)
  jl     L8
  setne  %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int ast_hashtab_compare_shorts(const void *a, const void *b) {
  short as = *((short *)a);
  short bs = *((short *)b);
  if (as < bs)
    return -1;
  else if (as == bs)
    return 0;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L3
  cmpl   $0x0,-0x14(%rbp)
  je     L19
  jmp    L10
L3:
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L19:
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x0,0x4(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L10:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L39:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<map_timeout>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  cmp    $0xffffffff,%ebx
  je     L28
  test   %ebx,%ebx
  jne    L20
  movl   $0x0,0x0(%rbp)
  movl   $0x0,0x4(%rbp)
  mov    %rbp,%rax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  movslq %ebx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  mov    %rbp,%rax
  jmp    L28
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L16
  test   %ebx,%ebx
  jne    L12
  movq   $0x0,0x0(%rbp)
  mov    %rbp,%rax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  mov    %rbp,%rax
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<map_timeout>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  cmp    $0xffffffff,%ebx
  je     L4
  test   %ebx,%ebx
  jne    L9
  movq   $0x0,0x0(%rbp)
  mov    %rbp,%rax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  mov    %rbp,%rax
  sub    %edx,%ebx
  imul   $0x3e8,%ebx,%ebx
  movd   %ebx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval *map_timeout(int poll_timeout, struct timeval *pSelTimeout) {
  struct timeval *pResult;
  assert(pSelTimeout != (struct timeval *)NULL);
  switch (poll_timeout) {
  case -1:
    pResult = (struct timeval *)NULL;
    break;
  case 0:
    pSelTimeout->tv_sec = 0;
    pSelTimeout->tv_usec = 0;
    pResult = pSelTimeout;
    break;
  default:
    pSelTimeout->tv_sec = poll_timeout / 1000;
    poll_timeout %= 1000;
    pSelTimeout->tv_usec = poll_timeout * 1000;
    pResult = pSelTimeout;
    break;
  }
  return pResult;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<packet_crc_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movzbl -0x1c(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %eax,%edx
  movzwl -0x6(%rbp),%eax
  shl    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L11:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jns    L5
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%eax
  xor    $0x8005,%ax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  jmp    L23
L5:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
L23:
  addl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0x7,-0x4(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void packet_crc_process(unsigned short *context, unsigned char ch) {
  unsigned short uch = (unsigned short)ch;
  int i;
  *context ^= (uch << 8);
  for (i = 0; i < 8; i++) {
    if (*context & 0x8000)
      *context = (*context << 1) ^ 0x8005;
    else
      *context <<= 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<packet_crc_process>:
  endbr64
  shl    $0x8,%esi
  xor    (%rdi),%si
  mov    $0x8,%edx
L1:
  lea    (%rsi,%rsi,1),%eax
  xor    $0x8005,%ax
  lea    (%rsi,%rsi,1),%ecx
  test   %si,%si
  cmovns %ecx,%eax
  mov    %eax,%esi
  sub    $0x1,%edx
  jne    L1
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void packet_crc_process(unsigned short *context, unsigned char ch) {
  unsigned short uch = (unsigned short)ch;
  int i;
  *context ^= (uch << 8);
  for (i = 0; i < 8; i++) {
    if (*context & 0x8000)
      *context = (*context << 1) ^ 0x8005;
    else
      *context <<= 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packet_crc_process>:
  endbr64
  shl    $0x8,%esi
  mov    $0x8,%edx
  xor    (%rdi),%si
  nop
L3:
  lea    (%rsi,%rsi,1),%eax
  lea    (%rsi,%rsi,1),%ecx
  xor    $0x8005,%ax
  test   %si,%si
  cmovns %ecx,%eax
  mov    %eax,%esi
  sub    $0x1,%edx
  jne    L3
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void packet_crc_process(unsigned short *context, unsigned char ch) {
  unsigned short uch = (unsigned short)ch;
  int i;
  *context ^= (uch << 8);
  for (i = 0; i < 8; i++) {
    if (*context & 0x8000)
      *context = (*context << 1) ^ 0x8005;
    else
      *context <<= 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<packet_crc_process>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  shl    $0x8,%eax
  xor    (%rdi),%ax
  js     L4
  add    %eax,%eax
L16:
  lea    (%rax,%rax,1),%esi
  mov    %esi,%edx
  xor    $0x8005,%dx
  test   %ax,%ax
  cmovns %esi,%edx
  lea    (%rdx,%rdx,1),%esi
  mov    %esi,%eax
  xor    $0x8005,%ax
  test   %dx,%dx
  cmovns %esi,%eax
  lea    (%rax,%rax,1),%esi
  mov    %esi,%edx
  xor    $0x8005,%dx
  test   %ax,%ax
  cmovns %esi,%edx
  lea    (%rdx,%rdx,1),%esi
  mov    %esi,%eax
  xor    $0x8005,%ax
  test   %dx,%dx
  cmovns %esi,%eax
  lea    (%rax,%rax,1),%esi
  mov    %esi,%edx
  xor    $0x8005,%dx
  test   %ax,%ax
  cmovns %esi,%edx
  lea    (%rdx,%rdx,1),%esi
  mov    %esi,%eax
  xor    $0x8005,%ax
  test   %dx,%dx
  cmovns %esi,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%esi
  xor    $0x8005,%si
  test   %ax,%ax
  cmovs  %esi,%edx
  mov    %dx,(%rcx)
  ret
  nopl   0x0(%rax)
L4:
  add    %eax,%eax
  xor    $0x8005,%ax
  jmp    L16
```

assistant: ```c
void packet_crc_process(unsigned short *context, unsigned char ch) {
  unsigned short uch = (unsigned short)ch;
  int i;
  *context ^= (uch << 8);
  for (i = 0; i < 8; i++) {
    if (*context & 0x8000)
      *context = (*context << 1) ^ 0x8005;
    else
      *context <<= 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readOptionInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L35
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L12
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x38(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
  jmp    L40
L12:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  lea    D11(%rip),%rcx
  mov    %eax,%edi
  call   <clParseError@plt>
  mov    $0x0,%eax
  jmp    L40
L35:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  lea    D7(%rip),%rcx
  mov    %eax,%edi
  call   <clParseError@plt>
L6:
  mov    $0x0,%eax
L40:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D7
data_type: string

tool: D11: Option expects one argument

tool: D7: Error parsing command line.

assistant: ```c
int readOptionInt(int argc, char **argv, int *i, char const *opt, int *arg) {
  int tmp;
  {
    if (*i < argc) {
      tmp = strcasecmp((char const *)*(argv + *i), opt);
      if (tmp == 0) {
        (*i)++;
        if (*i < argc) {
          *arg = atoi((char const *)*(argv + *i));
          return (1);
        } else {
          clParseError(argc, argv, *i, (char *)"Option expects one argument");
        }
        return (0);
      }
    } else {
      clParseError(argc, argv, *i, (char *)"Error parsing command line.");
    }
    return (0);
  }
}
```