user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D18(%rip),%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movq   $0x2a,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x2a,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  call   <puts@plt>
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %al,0x60(%rsp,%rbp,1)
  add    $0x1,%rbp
L13:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L46
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  test   %ebp,%ebp
  je     L28
  mov    0xc(%rsp),%edi
  lea    -0x1(%rbp),%r12d
  xor    %edx,%edx
  lea    0x60(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  jmp    L104
  cs nopw 0x0(%rax,%rax,1)
L83:
  movsbl %al,%eax
  add    %edi,%eax
  movslq %eax,%rcx
  mov    %eax,%r8d
  imul   $0x4ec4ec4f,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x23,%rcx
  sub    %r8d,%ecx
  imul   $0x1a,%ecx,%ecx
  sub    %ecx,%eax
  lea    0x61(%rax),%ecx
L102:
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rbp,%rdx
  je     L91
L104:
  movzbl (%rsi,%rdx,1),%ecx
  lea    -0x61(%rcx),%eax
  cmp    $0x19,%al
  jbe    L83
  lea    -0x41(%rcx),%eax
  cmp    $0x19,%al
  ja     L102
  movsbl %al,%eax
  add    %edi,%eax
  movslq %eax,%rcx
  mov    %eax,%r8d
  imul   $0x4ec4ec4f,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x23,%rcx
  sub    %r8d,%ecx
  imul   $0x1a,%ecx,%ecx
  sub    %ecx,%eax
  lea    0x41(%rax),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rbp,%rdx
  jne    L104
L91:
  lea    D49(%rip),%rdi
  lea    0x11(%rsp,%r12,1),%rbp
  call   <puts@plt>
  nopl   (%rax)
L68:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L68
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L22
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string

tool: D18: enter message to be encrypted:

tool: D13: enter shift amount(1-25)

tool: D19: %d

tool: D49: encrypted message:

assistant: ```c
int main(void) {
  char encrypted_ms[80] = {'*'}, unencrypted_ms[80] = {'*'}, ch;
  int shift_amount = 0, index = 0;
  printf("enter message to be encrypted:\n");
  while ((ch = getchar()) != '\n') {
    unencrypted_ms[index] = ch;
    index++;
  }
  printf("enter shift amount(1-25)\n");
  scanf("%d", &shift_amount);
  for (int i = 0; i < index; i++) {
    if (unencrypted_ms[i] >= 'a' && unencrypted_ms[i] <= 'z') {
      encrypted_ms[i] = ((unencrypted_ms[i] - 'a') + shift_amount) % 26 + 'a';
    } else if (unencrypted_ms[i] >= 'A' && unencrypted_ms[i] <= 'Z') {
      encrypted_ms[i] = ((unencrypted_ms[i] - 'A') + shift_amount) % 26 + 'A';
    } else {
      encrypted_ms[i] = unencrypted_ms[i];
    }
  }
  printf("encrypted message:\n");
  for (int j = 0; j < index; j++) {
    printf("%c", encrypted_ms[j]);
  }
  printf("\n");
  return 0;
}
```