ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<DFT_Wfunc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x38(%rsp)
  mov    %esi,0x1c(%rsp)
  movsd  %xmm0,0x20(%rsp)
  test   %esi,%esi
  jle    L61
  sub    $0x1,%esi
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rsi,8),%rsi
  nopl   0x0(%rax,%rax,1)
L55:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L55
L16:
  mov    0x1c(%rsp),%ebx
  pxor   %xmm7,%xmm7
  cvtsi2sd %ebx,%xmm7
  divsd  %xmm7,%xmm0
  movsd  %xmm7,0x28(%rsp)
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  addsd  D26(%rip),%xmm0
  xorpd  D20(%rip),%xmm1
  mulsd  0x20(%rsp),%xmm1
  cvttsd2si %xmm0,%eax
  movsd  %xmm1,0x10(%rsp)
  test   %eax,%eax
  jle    L7
  sub    $0x1,%eax
  mov    %rdx,%r15
  mov    %rcx,%r14
  lea    0x8(%rdx,%rax,8),%rax
  mov    0x38(%rsp),%rdx
  mov    %rax,0x30(%rsp)
  lea    -0x1(%rbx),%eax
  lea    0x8(%rdx,%rax,8),%r12
  nopl   0x0(%rax)
L39:
  mov    0x1c(%rsp),%eax
  movq   $0x0,(%r15)
  movq   $0x0,(%r14)
  test   %eax,%eax
  jle    L59
  mov    0x38(%rsp),%r13
  lea    0x48(%rsp),%rbp
  lea    0x40(%rsp),%rbx
  movsd  D18(%rip),%xmm6
  mulsd  0x10(%rsp),%xmm6
  movsd  %xmm6,(%rsp)
  nopl   0x0(%rax,%rax,1)
L40:
  movsd  0x0(%r13),%xmm0
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x8,%r13
  subsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  call   <sincos@plt>
  movsd  (%r15),%xmm0
  addsd  0x40(%rsp),%xmm0
  movsd  %xmm0,(%r15)
  movsd  (%r14),%xmm0
  addsd  0x48(%rsp),%xmm0
  movsd  %xmm0,(%r14)
  cmp    %r12,%r13
  jne    L40
L59:
  movsd  (%r15),%xmm0
  movsd  0x28(%rsp),%xmm4
  add    $0x8,%r15
  add    $0x8,%r14
  movsd  0x10(%rsp),%xmm5
  addsd  0x20(%rsp),%xmm5
  divsd  %xmm4,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm0,-0x8(%r15)
  movsd  -0x8(%r14),%xmm0
  divsd  %xmm4,%xmm0
  movsd  %xmm0,-0x8(%r14)
  cmp    0x30(%rsp),%r15
  jne    L39
L7:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  pxor   %xmm0,%xmm0
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_infered: f32[2]
name: parse_data
arguments: data_tag: D20
type_infered: f32[4]
name: parse_data
arguments: data_tag: D18
type_infered: byte[8]

tool: {"D26": [0.0,1.875]}

tool: {"D20": [0.0,-0.0,0.0,0.0]}

tool: {"D18": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0xc0]}

assistant: ```c
void DFT_Wfunc(double *x, int N, double df, double Nf, double *W_r, double *W_i) {
  int i, j, Ntot;
  double avx, cosval, sinval, fval, val;
  for (i = 0, avx = 0.; i < N; i++) {
    avx += x[i];
  }
  avx = avx / N;
  Ntot = 2 * Nf + 1;
  for (i = 0, fval = -Nf * df; i < Ntot; i++, fval += df) {
    for (j = 0, W_r[i] = 0., W_i[i] = 0.; j < N; j++) {
      val = -6.28318530717958647692528676656 * fval * (x[j] - avx);
      cosval = cos(val);
      sinval = sin(val);
      W_r[i] += cosval;
      W_i[i] += sinval;
    }
    W_r[i] /= (double)N;
    W_i[i] /= (double)N;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<test_16e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <might_write_to@plt>
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void test_16e(int i) {
  int j;
  j = i;
  __analyzer_eval(j == i);
  might_write_to(&j);
  __analyzer_eval(j == i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_16e>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  lea    0x4(%rsp),%rdi
  call   <might_write_to@plt>
  cmp    %ebx,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <__analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_16e(int i) {
  int j;
  j = i;
  __analyzer_eval(j == i);
  might_write_to(&j);
  __analyzer_eval(j == i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_16e>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  lea    0x4(%rsp),%rdi
  call   <might_write_to@plt>
  xor    %edi,%edi
  cmp    %ebx,0x4(%rsp)
  sete   %dil
  call   <__analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_16e(int i) {
  int j;
  j = i;
  __analyzer_eval(j == i);
  might_write_to(&j);
  __analyzer_eval(j == i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_16e>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  lea    0x4(%rsp),%rdi
  call   <might_write_to@plt>
  xor    %edi,%edi
  cmp    %ebx,0x4(%rsp)
  sete   %dil
  call   <__analyzer_eval@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_16e(int i) {
  int j;
  j = i;
  __analyzer_eval(j == i);
  might_write_to(&j);
  __analyzer_eval(j == i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HardFault_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <led_driver_panic@plt>
L1:
  jmp    L1
```

assistant: ```c
void HardFault_Handler(void) {
  led_driver_panic();
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HardFault_Handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <led_driver_panic@plt>
L3:
  jmp    L3
```

assistant: ```c
void HardFault_Handler(void) {
  led_driver_panic();
  while (1) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<HardFault_Handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <led_driver_panic@plt>
L8:
  jmp    L8
```

assistant: ```c
void HardFault_Handler(void) {
  led_driver_panic();
  while (1) {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HardFault_Handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <led_driver_panic@plt>
L6:
  jmp    L6
```

assistant: ```c
void HardFault_Handler(void) {
  led_driver_panic();
  while (1) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skip_ws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L14
L13:
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int c;
  while (isspace(c = *string))
    string++;
  return (string);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_ws>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L9
L15:
  add    $0x1,%rbx
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int c;
  while (isspace(c = *string))
    string++;
  return (string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skip_ws>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L10:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int c;
  while (isspace(c = *string))
    string++;
  return (string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_ws>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%r12
L2:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_ws(char *string) {
  int c;
  while (isspace(c = *string))
    string++;
  return (string);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<avro_default_allocator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L7
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L12
L7:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L12:
  leave
  ret
```

assistant: ```c
void *avro_default_allocator(void *ud, void *ptr, size_t osize, size_t nsize) {
  (void)ud;
  ;
  (void)osize;
  ;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else {
    return realloc(ptr, nsize);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<avro_default_allocator>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L12
  mov    %rcx,%rsi
  call   <realloc@plt>
L0:
  add    $0x8,%rsp
  ret
L12:
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
void *avro_default_allocator(void *ud, void *ptr, size_t osize, size_t nsize) {
  (void)ud;
  ;
  (void)osize;
  ;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else {
    return realloc(ptr, nsize);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<avro_default_allocator>:
  endbr64
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L0
  mov    %rcx,%rsi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax)
L0:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *avro_default_allocator(void *ud, void *ptr, size_t osize, size_t nsize) {
  (void)ud;
  ;
  (void)osize;
  ;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else {
    return realloc(ptr, nsize);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<avro_default_allocator>:
  endbr64
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L4
  mov    %rcx,%rsi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *avro_default_allocator(void *ud, void *ptr, size_t osize, size_t nsize) {
  (void)ud;
  ;
  (void)osize;
  ;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else {
    return realloc(ptr, nsize);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x8,-0x8(%rbp)
  jle    L0
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    0x48(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int alloc_values(int S[9][9], int **H_arr, int *V_arr[9], int *B_arr[3], int x, int y) {
  int k, l;
  *H_arr = S[x];
  for (k = 0; k < 9; k++) {
    V_arr[k] = &S[k][y];
  }
  k = ((x) / 3) * 3;
  l = ((y) / 3) * 3;
  B_arr[0] = &S[k][l];
  B_arr[1] = &S[k + 1][l];
  B_arr[2] = &S[k + 2][l];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_values>:
  endbr64
  mov    %rsi,%r10
  mov    %rcx,%rsi
  movslq %r8d,%rax
  lea    (%rax,%rax,8),%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,(%r10)
  movslq %r9d,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%rax
  lea    0x144(%rdi,%rcx,1),%rcx
L7:
  mov    %rax,(%rdx)
  add    $0x24,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L7
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,8),%rcx
  shl    $0x2,%rcx
  movslq %r9d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r9d
  sub    %r9d,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%r8
  add    %rdi,%r8
  mov    %r8,(%rsi)
  lea    0x9(%rdx,%rdx,8),%rdx
  lea    (%rax,%rdx,4),%rdx
  add    %rdi,%rdx
  mov    %rdx,0x8(%rsi)
  lea    0x48(%rax,%rcx,1),%rax
  add    %rax,%rdi
  mov    %rdi,0x10(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int alloc_values(int S[9][9], int **H_arr, int *V_arr[9], int *B_arr[3], int x, int y) {
  int k, l;
  *H_arr = S[x];
  for (k = 0; k < 9; k++) {
    V_arr[k] = &S[k][y];
  }
  k = ((x) / 3) * 3;
  l = ((y) / 3) * 3;
  B_arr[0] = &S[k][l];
  B_arr[1] = &S[k + 1][l];
  B_arr[2] = &S[k + 2][l];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alloc_values>:
  endbr64
  mov    %rcx,%r10
  movslq %r8d,%rcx
  lea    (%rcx,%rcx,8),%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,(%rsi)
  movslq %r9d,%rsi
  lea    0x0(,%rsi,4),%r11
  lea    (%rdi,%r11,1),%rax
  lea    0x144(%rdi,%r11,1),%r11
  nopl   0x0(%rax)
L4:
  mov    %rax,(%rdx)
  add    $0x24,%rax
  add    $0x8,%rdx
  cmp    %r11,%rax
  jne    L4
  imul   $0x55555556,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x1f,%r9d
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rcx
  sub    %r8d,%ecx
  shr    $0x20,%rsi
  sub    %r9d,%esi
  lea    (%rcx,%rcx,2),%edx
  movslq %edx,%rdx
  lea    (%rsi,%rsi,2),%eax
  lea    (%rdx,%rdx,8),%rcx
  cltq
  lea    0x9(%rdx,%rdx,8),%rdx
  shl    $0x2,%rax
  shl    $0x2,%rcx
  lea    (%rcx,%rax,1),%rsi
  lea    (%rax,%rdx,4),%rdx
  lea    0x48(%rax,%rcx,1),%rax
  add    %rdi,%rsi
  add    %rdi,%rdx
  add    %rax,%rdi
  mov    %rsi,(%r10)
  xor    %eax,%eax
  mov    %rdx,0x8(%r10)
  mov    %rdi,0x10(%r10)
  ret
```

assistant: ```c
int alloc_values(int S[9][9], int **H_arr, int *V_arr[9], int *B_arr[3], int x, int y) {
  int k, l;
  *H_arr = S[x];
  for (k = 0; k < 9; k++) {
    V_arr[k] = &S[k][y];
  }
  k = ((x) / 3) * 3;
  l = ((y) / 3) * 3;
  B_arr[0] = &S[k][l];
  B_arr[1] = &S[k + 1][l];
  B_arr[2] = &S[k + 2][l];
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_values>:
  endbr64
  movslq %r8d,%rax
  mov    %rsi,%r10
  mov    %rdx,%rsi
  sar    $0x1f,%r8d
  lea    (%rax,%rax,8),%rdx
  movdqa D31(%rip),%xmm2
  movq   %rdi,%xmm1
  punpcklqdq %xmm1,%xmm1
  imul   $0x55555556,%rax,%rax
  lea    (%rdi,%rdx,4),%rdx
  mov    %rdx,(%r10)
  movslq %r9d,%rdx
  sar    $0x1f,%r9d
  lea    0x0(,%rdx,4),%r10
  movq   %r10,%xmm0
  shr    $0x20,%rax
  lea    0x120(%rdi,%r10,1),%r10
  punpcklqdq %xmm0,%xmm0
  sub    %r8d,%eax
  mov    %r10,0x40(%rsi)
  paddq  %xmm0,%xmm2
  paddq  %xmm1,%xmm2
  movups %xmm2,(%rsi)
  movdqa D30(%rip),%xmm2
  paddq  %xmm0,%xmm2
  paddq  %xmm1,%xmm2
  movups %xmm2,0x10(%rsi)
  movdqa D18(%rip),%xmm2
  paddq  %xmm0,%xmm2
  paddq  D9(%rip),%xmm0
  paddq  %xmm1,%xmm2
  paddq  %xmm1,%xmm0
  movups %xmm2,0x20(%rsi)
  movups %xmm0,0x30(%rsi)
  lea    (%rax,%rax,2),%esi
  imul   $0x55555556,%rdx,%rax
  movslq %esi,%rsi
  lea    (%rsi,%rsi,8),%r8
  lea    0x9(%rsi,%rsi,8),%rdx
  shl    $0x2,%r8
  shl    $0x2,%rdx
  shr    $0x20,%rax
  movq   %r8,%xmm0
  movq   %rdx,%xmm3
  sub    %r9d,%eax
  punpcklqdq %xmm3,%xmm0
  lea    (%rax,%rax,2),%eax
  cltq
  shl    $0x2,%rax
  movq   %rax,%xmm2
  lea    0x48(%rax,%r8,1),%rax
  punpcklqdq %xmm2,%xmm2
  add    %rax,%rdi
  xor    %eax,%eax
  paddq  %xmm2,%xmm1
  mov    %rdi,0x10(%rcx)
  paddq  %xmm1,%xmm0
  movups %xmm0,(%rcx)
  ret
```

tool_calls: name: read_data
arguments: label: D31
type: byte[16]
name: read_data
arguments: label: D30
type: byte[16]
name: read_data
arguments: label: D18
type: byte[16]
name: read_data
arguments: label: D9
type: byte[16]

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D30": [0x48,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x6c,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D18": [0x90,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xb4,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D9": [0xd8,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xfc,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int alloc_values(int S[9][9], int **H_arr, int *V_arr[9], int *B_arr[3], int x, int y) {
  int k, l;
  *H_arr = S[x];
  for (k = 0; k < 9; k++) {
    V_arr[k] = &S[k][y];
  }
  k = ((x) / 3) * 3;
  l = ((y) / 3) * 3;
  B_arr[0] = &S[k][l];
  B_arr[1] = &S[k + 1][l];
  B_arr[2] = &S[k + 2][l];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clGetImageInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x3fe,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
cl_int clGetImageInfo(cl_mem image, cl_image_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)image;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1022, sys_args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clGetImageInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %rsp,%rdx
  mov    $0x3fe,%esi
  mov    $0x145,%edi
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetImageInfo(cl_mem image, cl_image_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)image;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1022, sys_args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clGetImageInfo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    $0x145,%edi
  mov    %esi,0x4(%rsp)
  mov    $0x3fe,%esi
  mov    %edx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x10(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetImageInfo(cl_mem image, cl_image_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)image;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1022, sys_args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clGetImageInfo>:
  endbr64
  movd   %edx,%xmm1
  movd   %edi,%xmm0
  movd   %esi,%xmm3
  sub    $0x28,%rsp
  movd   %ecx,%xmm2
  punpckldq %xmm3,%xmm0
  mov    %rsp,%rdx
  mov    $0x3fe,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  punpckldq %xmm2,%xmm1
  mov    $0x145,%edi
  mov    %r8d,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <syscall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
cl_int clGetImageInfo(cl_mem image, cl_image_info param_name, size_t param_value_size, void *param_value, size_t *param_value_size_ret) {
  unsigned int sys_args[5];
  sys_args[0] = (unsigned int)image;
  sys_args[1] = (unsigned int)param_name;
  sys_args[2] = (unsigned int)param_value_size;
  sys_args[3] = (unsigned int)param_value;
  sys_args[4] = (unsigned int)param_value_size_ret;
  return (cl_int)syscall(325, 1022, sys_args);
}
```