ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x9,%eax
  je     L6
  cmp    $0xa,%eax
  je     L2
  jmp    L42
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5c,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x74,(%rax)
  addl   $0x1,-0x4(%rbp)
  jmp    L59
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5c,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6e,(%rax)
  addl   $0x1,-0x4(%rbp)
  jmp    L59
L42:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  nop
L59:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void escape(char *s, char *t) {
  int i = 0;
  int j = 0;
  while (t[i] != '\0') {
    switch (t[i]) {
    case '\t':
      s[j] = '\\';
      s[j + 1] = 't';
      j++;
      break;
    case '\n':
      s[j] = '\\';
      s[j + 1] = 'n';
      j++;
      break;
    default:
      s[j] = t[i];
      break;
    }
    j++;
    i++;
  }
  s[j++] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<escape>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L47
  add    $0x1,%rsi
  mov    $0x0,%eax
  jmp    L41
L27:
  movslq %eax,%rdx
  movb   $0x5c,(%rdi,%rdx,1)
  movb   $0x74,0x1(%rdi,%rdx,1)
  add    $0x1,%eax
L69:
  add    $0x1,%eax
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  test   %dl,%dl
  je     L7
L41:
  cmp    $0x9,%dl
  je     L27
  cmp    $0xa,%dl
  je     L15
  movslq %eax,%rcx
  mov    %dl,(%rdi,%rcx,1)
  jmp    L69
L15:
  movslq %eax,%rdx
  movb   $0x5c,(%rdi,%rdx,1)
  movb   $0x6e,0x1(%rdi,%rdx,1)
  add    $0x1,%eax
  jmp    L69
L47:
  mov    $0x0,%eax
L7:
  cltq
  movb   $0x0,(%rdi,%rax,1)
  ret
```

assistant: ```c
void escape(char *s, char *t) {
  int i = 0;
  int j = 0;
  while (t[i] != '\0') {
    switch (t[i]) {
    case '\t':
      s[j] = '\\';
      s[j + 1] = 't';
      j++;
      break;
    case '\n':
      s[j] = '\\';
      s[j + 1] = 'n';
      j++;
      break;
    default:
      s[j] = t[i];
      break;
    }
    j++;
    i++;
  }
  s[j++] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<escape>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L18
  add    $0x1,%rsi
  xor    %edx,%edx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %al,(%r9)
  mov    %edx,%r8d
L65:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  lea    0x1(%r8),%edx
  test   %al,%al
  je     L62
L24:
  movslq %edx,%rcx
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rcx,1),%r9
  cmp    $0x9,%al
  je     L9
  cmp    $0xa,%al
  jne    L54
  add    $0x1,%rsi
  movb   $0x5c,(%r9)
  lea    0x1(%r8),%edx
  movb   $0x6e,0x1(%rdi,%rcx,1)
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L24
L62:
  movslq %edx,%rdx
  add    %rdx,%rdi
L18:
  movb   $0x0,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movb   $0x5c,(%r9)
  movb   $0x74,0x1(%rdi,%rcx,1)
  jmp    L65
```

assistant: ```c
void escape(char *s, char *t) {
  int i = 0;
  int j = 0;
  while (t[i] != '\0') {
    switch (t[i]) {
    case '\t':
      s[j] = '\\';
      s[j + 1] = 't';
      j++;
      break;
    case '\n':
      s[j] = '\\';
      s[j + 1] = 'n';
      j++;
      break;
    default:
      s[j] = t[i];
      break;
    }
    j++;
    i++;
  }
  s[j++] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<escape>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rsi
  xor    %edx,%edx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %al,(%r9)
  mov    %edx,%r8d
L59:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  lea    0x1(%r8),%edx
  test   %al,%al
  je     L45
L10:
  movslq %edx,%rcx
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rcx,1),%r9
  cmp    $0x9,%al
  je     L6
  cmp    $0xa,%al
  jne    L17
  add    $0x1,%rsi
  movb   $0x5c,(%r9)
  lea    0x1(%r8),%edx
  movb   $0x6e,0x1(%rdi,%rcx,1)
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L10
L45:
  movslq %edx,%rdx
  add    %rdx,%rdi
L7:
  movb   $0x0,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movb   $0x5c,(%r9)
  movb   $0x74,0x1(%rdi,%rcx,1)
  jmp    L59
```

assistant: ```c
void escape(char *s, char *t) {
  int i = 0;
  int j = 0;
  while (t[i] != '\0') {
    switch (t[i]) {
    case '\t':
      s[j] = '\\';
      s[j + 1] = 't';
      j++;
      break;
    case '\n':
      s[j] = '\\';
      s[j + 1] = 'n';
      j++;
      break;
    default:
      s[j] = t[i];
      break;
    }
    j++;
    i++;
  }
  s[j++] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <call_lua@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: calling: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("calling: %s\n", argv[1]);
  call_lua(argv[1]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <call_lua@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: calling: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("calling: %s\n", argv[1]);
  call_lua(argv[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <call_lua@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: calling: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("calling: %s\n", argv[1]);
  call_lua(argv[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rbx),%rdi
  call   <call_lua@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: calling: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("calling: %s\n", argv[1]);
  call_lua(argv[1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<led_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <cap1166_get_leds@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x4(%rbp)
  jmp    L8
L19:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cap1166_leds@plt>
  nop
  leave
  ret
```

assistant: ```c
void led_state(int i, int s) {
  unsigned int l, j;
  l = cap1166_get_leds();
  if (s == 0) {
    l &= ~(1 << (i));
  } else {
    l |= (1 << (i));
  };
  cap1166_leds(l);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<led_state>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <cap1166_get_leds@plt>
  mov    %eax,%edi
  test   %ebp,%ebp
  jne    L5
  btr    %ebx,%edi
L13:
  call   <cap1166_leds@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  bts    %ebx,%edi
  jmp    L13
```

assistant: ```c
void led_state(int i, int s) {
  unsigned int l, j;
  l = cap1166_get_leds();
  if (s == 0) {
    l &= ~(1 << (i));
  } else {
    l |= (1 << (i));
  };
  cap1166_leds(l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<led_state>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <cap1166_get_leds@plt>
  mov    %ebp,%ecx
  mov    $0x1,%edi
  shl    %cl,%edi
  mov    %edi,%edx
  or     %eax,%edi
  not    %edx
  and    %eax,%edx
  test   %ebx,%ebx
  cmove  %edx,%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <cap1166_leds@plt>
```

assistant: ```c
void led_state(int i, int s) {
  unsigned int l, j;
  l = cap1166_get_leds();
  if (s == 0) {
    l &= ~(1 << (i));
  } else {
    l |= (1 << (i));
  };
  cap1166_leds(l);
}
```
user: What is the c source code of the assembly code below:

```asm
<led_state>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <cap1166_get_leds@plt>
  mov    %ebp,%ecx
  mov    $0x1,%edi
  shl    %cl,%edi
  mov    %edi,%edx
  or     %eax,%edi
  not    %edx
  and    %eax,%edx
  test   %ebx,%ebx
  cmove  %edx,%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <cap1166_leds@plt>
```

assistant: ```c
void led_state(int i, int s) {
  unsigned int l, j;
  l = cap1166_get_leds();
  if (s == 0) {
    l &= ~(1 << (i));
  } else {
    l |= (1 << (i));
  };
  cap1166_leds(l);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <pcs@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  pcs();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <pcs@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  pcs();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pcs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  pcs();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <pcs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  pcs();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<core___core__Bool___Object__hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movswl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <core___core__Bool___to_i@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long core___core__Bool___Object__hash(short int self) {
  long var;
  long var1;
  { var1 = core___core__Bool___to_i(self); }
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<core___core__Bool___Object__hash>:
  endbr64
  sub    $0x8,%rsp
  movswl %di,%edi
  call   <core___core__Bool___to_i@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long core___core__Bool___Object__hash(short int self) {
  long var;
  long var1;
  { var1 = core___core__Bool___to_i(self); }
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<core___core__Bool___Object__hash>:
  endbr64
  movswl %di,%edi
  jmp    1050 <core___core__Bool___to_i@plt>
```

assistant: ```c
long core___core__Bool___Object__hash(short int self) {
  long var;
  long var1;
  { var1 = core___core__Bool___to_i(self); }
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Translate the below assembly code into C programming language:

```asm
<core___core__Bool___Object__hash>:
  endbr64
  movswl %di,%edi
  jmp    1050 <core___core__Bool___to_i@plt>
```

assistant: ```c
long core___core__Bool___Object__hash(short int self) {
  long var;
  long var1;
  { var1 = core___core__Bool___to_i(self); }
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x6c(%rbp)
  jmp    L34
L93:
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x6c(%rbp)
L34:
  cmpl   $0x13,-0x6c(%rbp)
  jle    L93
  movl   $0x1,-0x6c(%rbp)
  jmp    L31
L17:
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,-0x64(%rbp)
  mov    -0x6c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  jmp    L42
L124:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,-0x64(%rbp)
  jg     L109
  mov    -0x68(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0x60(%rbp,%rax,4)
  cmpl   $0x0,-0x68(%rbp)
  jne    L92
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x64(%rbp),%edx
  mov    %edx,-0x60(%rbp,%rax,4)
  jmp    L92
L109:
  mov    -0x68(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x64(%rbp),%edx
  mov    %edx,-0x60(%rbp,%rax,4)
  jmp    L26
L92:
  subl   $0x1,-0x68(%rbp)
L42:
  cmpl   $0x0,-0x68(%rbp)
  jns    L124
L26:
  addl   $0x1,-0x6c(%rbp)
L31:
  cmpl   $0x13,-0x6c(%rbp)
  jle    L17
  movl   $0x0,-0x6c(%rbp)
  jmp    L129
L105:
  mov    -0x6c(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x6c(%rbp)
L129:
  cmpl   $0x13,-0x6c(%rbp)
  jle    L105
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D4: %d

tool: D11: %d 

assistant: ```c
int main() {
  int arr[20], i;
  for (i = 0; i < 20; i++)
    scanf("%d", &arr[i]);
  int j;
  for (i = 1; i < 20; i++) {
    int temp = arr[i];
    for (j = i - 1; j >= 0; j--) {
      if (arr[j] >= temp) {
        arr[j + 1] = arr[j];
        if (j == 0)
          arr[j] = temp;
      } else {
        arr[j + 1] = temp;
        break;
      }
    }
  }
  for (i = 0; i < 20; i++)
    printf("%d ", arr[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
  mov    %rbx,%r12
  lea    D13(%rip),%r13
L109:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L109
  lea    0x4(%rsp),%r8
  mov    $0x0,%edi
  jmp    L38
L63:
  add    $0x1,%eax
  cltq
  mov    %esi,(%rsp,%rax,4)
  jmp    L51
L95:
  sub    $0x1,%eax
  sub    $0x4,%rdx
  cmp    $0xffffffff,%eax
  je     L51
L59:
  mov    -0x4(%rdx),%ecx
  cmp    %esi,%ecx
  jl     L63
  mov    %ecx,(%rdx)
  test   %eax,%eax
  jne    L95
  mov    %esi,(%rsp)
L51:
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    $0x13,%rdi
  je     L54
L38:
  mov    (%r8),%esi
  mov    %edi,%eax
  test   %edi,%edi
  js     L51
  mov    %r8,%rdx
  jmp    L59
L54:
  lea    D3(%rip),%r12
L49:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L49
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D3
type: string

tool: D13: %d

tool: D3: %d 

assistant: ```c
int main() {
  int arr[20], i;
  for (i = 0; i < 20; i++)
    scanf("%d", &arr[i]);
  int j;
  for (i = 1; i < 20; i++) {
    int temp = arr[i];
    for (j = i - 1; j >= 0; j--) {
      if (arr[j] >= temp) {
        arr[j + 1] = arr[j];
        if (j == 0)
          arr[j] = temp;
      } else {
        arr[j + 1] = temp;
        break;
      }
    }
  }
  for (i = 0; i < 20; i++)
    printf("%d ", arr[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
  mov    %rbx,%r12
L44:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L44
  lea    0x4(%rsp),%r8
  mov    $0x1,%edi
  xchg   %ax,%ax
L75:
  mov    (%r8),%esi
  mov    %edi,%edx
  mov    %r8,%rax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L28:
  sub    $0x1,%edx
  sub    $0x4,%rax
L12:
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jl     L27
  mov    %ecx,(%rax)
  cmp    $0x1,%edx
  jne    L28
  mov    %esi,(%rsp)
L63:
  add    $0x1,%edi
  add    $0x4,%r8
  cmp    $0x14,%edi
  jne    L75
  lea    D8(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L8
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  movslq %edx,%rdx
  mov    %esi,(%rsp,%rdx,4)
  jmp    L63
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D19: %d

tool: D8: %d 

assistant: ```c
int main() {
  int arr[20], i;
  for (i = 0; i < 20; i++)
    scanf("%d", &arr[i]);
  int j;
  for (i = 1; i < 20; i++) {
    int temp = arr[i];
    for (j = i - 1; j >= 0; j--) {
      if (arr[j] >= temp) {
        arr[j + 1] = arr[j];
        if (j == 0)
          arr[j] = temp;
      } else {
        arr[j + 1] = temp;
        break;
      }
    }
  }
  for (i = 0; i < 20; i++)
    printf("%d ", arr[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
  mov    %rbx,%r12
L34:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L34
  lea    0x4(%rsp),%r8
  mov    $0x1,%edi
  xchg   %ax,%ax
L28:
  mov    (%r8),%esi
  mov    %edi,%edx
  mov    %r8,%rax
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L31:
  sub    $0x1,%edx
  sub    $0x4,%rax
L40:
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jl     L66
  mov    %ecx,(%rax)
  cmp    $0x1,%edx
  jne    L31
  mov    %esi,(%rsp)
L73:
  add    $0x1,%edi
  add    $0x4,%r8
  cmp    $0x14,%edi
  jne    L28
  lea    D8(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  movslq %edx,%rdx
  mov    %esi,(%rsp,%rdx,4)
  jmp    L73
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D11: %d

tool: D8: %d 

assistant: ```c
int main() {
  int arr[20], i;
  for (i = 0; i < 20; i++)
    scanf("%d", &arr[i]);
  int j;
  for (i = 1; i < 20; i++) {
    int temp = arr[i];
    for (j = i - 1; j >= 0; j--) {
      if (arr[j] >= temp) {
        arr[j + 1] = arr[j];
        if (j == 0)
          arr[j] = temp;
      } else {
        arr[j + 1] = temp;
        break;
      }
    }
  }
  for (i = 0; i < 20; i++)
    printf("%d ", arr[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thrd_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void thrd_exit(int res) {
  void *pres = malloc(sizeof(int));
  if (pres != NULL)
    *(int *)pres = res;
  pthread_exit(pres);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thrd_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L9
  mov    %ebx,(%rax)
L9:
  call   <pthread_exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void thrd_exit(int res) {
  void *pres = malloc(sizeof(int));
  if (pres != NULL)
    *(int *)pres = res;
  pthread_exit(pres);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thrd_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L5
  mov    %ebx,(%rax)
L5:
  pop    %rbx
  jmp    1060 <pthread_exit@plt>
```

assistant: ```c
void thrd_exit(int res) {
  void *pres = malloc(sizeof(int));
  if (pres != NULL)
    *(int *)pres = res;
  pthread_exit(pres);
}
```
user: What is the c source code of the assembly code below:

```asm
<thrd_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L4
  mov    %ebx,(%rax)
L4:
  pop    %rbx
  jmp    1060 <pthread_exit@plt>
```

assistant: ```c
void thrd_exit(int res) {
  void *pres = malloc(sizeof(int));
  if (pres != NULL)
    *(int *)pres = res;
  pthread_exit(pres);
}
```