ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  cmpl   $0x1,-0x1c(%rbp)
  jle    L19
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <build_max_heap@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swap@plt>
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_heapify@plt>
  subl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x0,-0x4(%rbp)
  jg     L28
  jmp    L13
L19:
  nop
L13:
  leave
  ret
```

assistant: ```c
void heap_sort(int arr[], int len) {
  int i = 0;
  if (arr == NULL || len <= 1) {
    return;
  }
  build_max_heap(arr, len);
  for (i = len - 1; i >= 1; --i) {
    swap(arr[0], arr[i]);
    max_heapify(arr, --len, 0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heap_sort>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  cmp    $0x1,%esi
  jle    L2
  call   <build_max_heap@plt>
  sub    $0x1,%ebx
  movslq %ebx,%rbx
L29:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x0(%rbp),%edi
  call   <swap@plt>
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L29
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  ret
```

assistant: ```c
void heap_sort(int arr[], int len) {
  int i = 0;
  if (arr == NULL || len <= 1) {
    return;
  }
  build_max_heap(arr, len);
  for (i = len - 1; i >= 1; --i) {
    swap(arr[0], arr[i]);
    max_heapify(arr, --len, 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<heap_sort>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L12
  sub    $0x1,%ebx
  mov    %rdi,%rbp
  call   <build_max_heap@plt>
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L3:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x0(%rbp),%edi
  call   <swap@plt>
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jne    L3
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L15:
  ret
```

assistant: ```c
void heap_sort(int arr[], int len) {
  int i = 0;
  if (arr == NULL || len <= 1) {
    return;
  }
  build_max_heap(arr, len);
  for (i = len - 1; i >= 1; --i) {
    swap(arr[0], arr[i]);
    max_heapify(arr, --len, 0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heap_sort>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L20
  sub    $0x1,%ebx
  mov    %rdi,%rbp
  call   <build_max_heap@plt>
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    0x0(%rbp),%edi
  call   <swap@plt>
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jne    L28
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L2:
  ret
```

assistant: ```c
void heap_sort(int arr[], int len) {
  int i = 0;
  if (arr == NULL || len <= 1) {
    return;
  }
  build_max_heap(arr, len);
  for (i = len - 1; i >= 1; --i) {
    swap(arr[0], arr[i]);
    max_heapify(arr, --len, 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_q_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x30,%edi
  call   <output_char@plt>
  mov    $0x78,%edi
  call   <output_char@plt>
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L35:
  mov    -0x20(%rbp),%rax
  and    $0xf,%eax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0xf(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x4,%rax
  mov    %rax,-0x20(%rbp)
  shlq   $0x4,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  cmpq   $0xe,-0x8(%rbp)
  jg     L33
  jmp    L35
L33:
  movq   $0x0,-0x8(%rbp)
L46:
  mov    -0x10(%rbp),%rax
  and    $0xf,%eax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0xf(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x9,-0x18(%rbp)
  jg     L49
  addq   $0x30,-0x18(%rbp)
  jmp    L11
L49:
  addq   $0x37,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <output_char@plt>
  addq   $0x1,-0x8(%rbp)
  cmpq   $0xe,-0x8(%rbp)
  jg     L29
  jmp    L46
L29:
  nop
  leave
  ret
```

assistant: ```c
void output_q_hex(long n) {
  long num;
  long c;
  long num2;
  long i;
  num = n;
  num2 = n;
  output_char((long)'0');
  output_char((long)'x');
  num2 = 0;
  i = 0;
output_q_hex_j1:
  c = num & 0xF;
  num = num / 16;
  num2 = num2 * 16;
  num2 = num2 + c;
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j1;
  }
  i = 0;
output_q_hex_j2:
  c = num2 & 0xF;
  num2 = num2 / 16;
  if (c < 10) {
    c = c + 48;
  } else {
    c = c + 55;
  }
  output_char((long)c);
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j2;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_q_hex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x30,%edi
  call   <output_char@plt>
  mov    $0x78,%edi
  call   <output_char@plt>
  mov    $0xf,%eax
  mov    $0x0,%ebx
L5:
  mov    %rbp,%rdx
  and    $0xf,%edx
  lea    0xf(%rbp),%rcx
  test   %rbp,%rbp
  cmovs  %rcx,%rbp
  sar    $0x4,%rbp
  shl    $0x4,%rbx
  add    %rdx,%rbx
  sub    $0x1,%rax
  jne    L5
  mov    $0xf,%ebp
L9:
  mov    %rbx,%rax
  and    $0xf,%eax
  lea    0xf(%rbx),%rdx
  test   %rbx,%rbx
  cmovns %rbx,%rdx
  mov    %rdx,%rbx
  sar    $0x4,%rbx
  lea    0x30(%rax),%rdx
  lea    0x37(%rax),%rdi
  cmp    $0x9,%rax
  cmovle %rdx,%rdi
  call   <output_char@plt>
  sub    $0x1,%rbp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_q_hex(long n) {
  long num;
  long c;
  long num2;
  long i;
  num = n;
  num2 = n;
  output_char((long)'0');
  output_char((long)'x');
  num2 = 0;
  i = 0;
output_q_hex_j1:
  c = num & 0xF;
  num = num / 16;
  num2 = num2 * 16;
  num2 = num2 + c;
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j1;
  }
  i = 0;
output_q_hex_j2:
  c = num2 & 0xF;
  num2 = num2 / 16;
  if (c < 10) {
    c = c + 48;
  } else {
    c = c + 55;
  }
  output_char((long)c);
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j2;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_q_hex>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x30,%edi
  sub    $0x8,%rsp
  call   <output_char@plt>
  mov    $0x78,%edi
  call   <output_char@plt>
  mov    $0xf,%eax
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdx
  lea    0xf(%rbx),%rcx
  and    $0xf,%edx
  test   %rbx,%rbx
  cmovs  %rcx,%rbx
  shl    $0x4,%rbp
  add    %rdx,%rbp
  sar    $0x4,%rbx
  sub    $0x1,%rax
  jne    L11
  mov    $0xf,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rax
  sar    $0x4,%rbp
  and    $0xf,%eax
  cmp    $0x9,%rax
  lea    0x30(%rax),%rdx
  lea    0x37(%rax),%rdi
  cmovle %rdx,%rdi
  call   <output_char@plt>
  sub    $0x1,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_q_hex(long n) {
  long num;
  long c;
  long num2;
  long i;
  num = n;
  num2 = n;
  output_char((long)'0');
  output_char((long)'x');
  num2 = 0;
  i = 0;
output_q_hex_j1:
  c = num & 0xF;
  num = num / 16;
  num2 = num2 * 16;
  num2 = num2 + c;
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j1;
  }
  i = 0;
output_q_hex_j2:
  c = num2 & 0xF;
  num2 = num2 / 16;
  if (c < 10) {
    c = c + 48;
  } else {
    c = c + 55;
  }
  output_char((long)c);
  i = i + 1;
  if (i < 15) {
    goto output_q_hex_j2;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RDTSC_BARRIER>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mfence
  lfence
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RDTSC_BARRIER(void) {
  __asm__ __volatile__("mfence \n\t"
                       "lfence \n\t" ::
                           : "memory");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RDTSC_BARRIER>:
  endbr64
  mfence
  lfence
  ret
```

assistant: ```c
void RDTSC_BARRIER(void) {
  __asm__ __volatile__("mfence \n\t"
                       "lfence \n\t" ::
                           : "memory");
}
```
user: Translate the below assembly code into C programming language:

```asm
<RDTSC_BARRIER>:
  endbr64
  mfence
  lfence
  ret
```

assistant: ```c
void RDTSC_BARRIER(void) {
  __asm__ __volatile__("mfence \n\t"
                       "lfence \n\t" ::
                           : "memory");
}
```
user: What is the c source code of the assembly code below:

```asm
<Heap_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Build_Heap@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Heapify@plt>
  subl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x0,-0x8(%rbp)
  jg     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void Heap_Sort(int array[], int size) {
  Build_Heap(array, size);
  int temp, i;
  for (i = size - 1; i > 0; i--) {
    temp = array[0];
    array[0] = array[i];
    array[i] = temp;
    Heapify(array, 0, i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Heap_Sort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <Build_Heap@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L13
  movslq %ebx,%rbx
L1:
  mov    0x0(%rbp),%eax
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,0x0(%rbp,%rbx,4)
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <Heapify@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L1
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Heap_Sort(int array[], int size) {
  Build_Heap(array, size);
  int temp, i;
  for (i = size - 1; i > 0; i--) {
    temp = array[0];
    array[0] = array[i];
    array[i] = temp;
    Heapify(array, 0, i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Heap_Sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <Build_Heap@plt>
  test   %ebx,%ebx
  jle    L0
  movslq %ebx,%rbx
  xchg   %ax,%ax
L18:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  mov    %ebx,%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <Heapify@plt>
  test   %ebx,%ebx
  jg     L18
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Heap_Sort(int array[], int size) {
  Build_Heap(array, size);
  int temp, i;
  for (i = size - 1; i > 0; i--) {
    temp = array[0];
    array[0] = array[i];
    array[i] = temp;
    Heapify(array, 0, i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Heap_Sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  sub    $0x8,%rsp
  call   <Build_Heap@plt>
  test   %ebx,%ebx
  jle    L18
  movslq %ebx,%rbx
  xchg   %ax,%ax
L1:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    0x0(%rbp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp)
  mov    %ebx,%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <Heapify@plt>
  test   %ebx,%ebx
  jg     L1
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Heap_Sort(int array[], int size) {
  Build_Heap(array, size);
  int temp, i;
  for (i = size - 1; i > 0; i--) {
    temp = array[0];
    array[0] = array[i];
    array[i] = temp;
    Heapify(array, 0, i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RemoveCR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L12:
  nop
  leave
  ret
```

assistant: ```c
void RemoveCR(char *text) {
  if (text[strlen(text) - 2] == '\n')
    text[strlen(text) - 2] = '\0';
  if (text[strlen(text) - 1] == '\n')
    text[strlen(text) - 1] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RemoveCR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x2(%rbx,%rax,1)
  je     L3
L34:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L39
L14:
  pop    %rbx
  ret
L3:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbx,%rax,1)
  jmp    L34
L39:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L14
```

assistant: ```c
void RemoveCR(char *text) {
  if (text[strlen(text) - 2] == '\n')
    text[strlen(text) - 2] = '\0';
  if (text[strlen(text) - 1] == '\n')
    text[strlen(text) - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RemoveCR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x2(%rbx,%rax,1)
  je     L25
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L28
  pop    %rbx
  ret
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L25:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbx,%rax,1)
  jmp    L1
```

assistant: ```c
void RemoveCR(char *text) {
  if (text[strlen(text) - 2] == '\n')
    text[strlen(text) - 2] = '\0';
  if (text[strlen(text) - 1] == '\n')
    text[strlen(text) - 1] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RemoveCR>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x2(%rbx,%rax,1)
  je     L12
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L4
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x2(%rbx,%rax,1)
  jmp    L1
```

assistant: ```c
void RemoveCR(char *text) {
  if (text[strlen(text) - 2] == '\n')
    text[strlen(text) - 2] = '\0';
  if (text[strlen(text) - 1] == '\n')
    text[strlen(text) - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<internal_fiat_poly1305_relax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    -0x90(%rbp),%rax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_br2_load@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x90(%rbp),%rax
  add    $0x4,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_br2_load@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x90(%rbp),%rax
  add    $0x8,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_br2_load@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x90(%rbp),%rax
  add    $0xc,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_br2_load@plt>
  mov    %rax,-0x60(%rbp)
  mov    -0x90(%rbp),%rax
  add    $0x10,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_br2_load@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x88(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <_br2_store@plt>
  mov    -0x88(%rbp),%rax
  add    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <_br2_store@plt>
  mov    -0x88(%rbp),%rax
  add    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <_br2_store@plt>
  mov    -0x88(%rbp),%rax
  add    $0xc,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <_br2_store@plt>
  mov    -0x88(%rbp),%rax
  add    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <_br2_store@plt>
  nop
  leave
  ret
```

assistant: ```c
void internal_fiat_poly1305_relax(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)4ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x3 = _br2_load((in0) + ((uintptr_t)12ULL), sizeof(uintptr_t));
  x4 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x5 = x0;
  x6 = x1;
  x7 = x2;
  x8 = x3;
  x9 = x4;
  x10 = x5;
  x11 = x6;
  x12 = x7;
  x13 = x8;
  x14 = x9;
  _br2_store((out0) + ((uintptr_t)0ULL), x10, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)4ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)12ULL), x13, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x14, sizeof(uintptr_t));
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<internal_fiat_poly1305_relax>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <_br2_load@plt>
  mov    %rax,%r15
  lea    0x4(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%r14
  lea    0x8(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%r13
  lea    0xc(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%r12
  lea    0x10(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%rbp
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %ebx,%edi
  call   <_br2_store@plt>
  lea    0x4(%rbx),%edi
  mov    $0x8,%edx
  mov    %r14,%rsi
  call   <_br2_store@plt>
  lea    0x8(%rbx),%edi
  mov    $0x8,%edx
  mov    %r13,%rsi
  call   <_br2_store@plt>
  lea    0xc(%rbx),%edi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <_br2_store@plt>
  lea    0x10(%rbx),%edi
  mov    $0x8,%edx
  mov    %rbp,%rsi
  call   <_br2_store@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void internal_fiat_poly1305_relax(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)4ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x3 = _br2_load((in0) + ((uintptr_t)12ULL), sizeof(uintptr_t));
  x4 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x5 = x0;
  x6 = x1;
  x7 = x2;
  x8 = x3;
  x9 = x4;
  x10 = x5;
  x11 = x6;
  x12 = x7;
  x13 = x8;
  x14 = x9;
  _br2_store((out0) + ((uintptr_t)0ULL), x10, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)4ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)12ULL), x13, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x14, sizeof(uintptr_t));
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<internal_fiat_poly1305_relax>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <_br2_load@plt>
  lea    0x4(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r15
  call   <_br2_load@plt>
  lea    0x8(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r14
  call   <_br2_load@plt>
  lea    0xc(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r13
  call   <_br2_load@plt>
  lea    0x10(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r12
  call   <_br2_load@plt>
  mov    %r15,%rsi
  mov    %ebx,%edi
  mov    $0x8,%edx
  mov    %rax,%rbp
  call   <_br2_store@plt>
  lea    0x4(%rbx),%edi
  mov    %r14,%rsi
  mov    $0x8,%edx
  call   <_br2_store@plt>
  lea    0x8(%rbx),%edi
  mov    %r13,%rsi
  mov    $0x8,%edx
  call   <_br2_store@plt>
  lea    0xc(%rbx),%edi
  mov    %r12,%rsi
  mov    $0x8,%edx
  call   <_br2_store@plt>
  add    $0x8,%rsp
  lea    0x10(%rbx),%edi
  mov    %rbp,%rsi
  pop    %rbx
  mov    $0x8,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <_br2_store@plt>
```

assistant: ```c
void internal_fiat_poly1305_relax(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)4ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x3 = _br2_load((in0) + ((uintptr_t)12ULL), sizeof(uintptr_t));
  x4 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x5 = x0;
  x6 = x1;
  x7 = x2;
  x8 = x3;
  x9 = x4;
  x10 = x5;
  x11 = x6;
  x12 = x7;
  x13 = x8;
  x14 = x9;
  _br2_store((out0) + ((uintptr_t)0ULL), x10, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)4ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)12ULL), x13, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x14, sizeof(uintptr_t));
  return;
}
```