ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  ret
L1:
  mov    $0x18,%edx
  lea    D3(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: out of memory in alloca


assistant: ```c
void *xmalloc(s)
unsigned long s;
{
  void *p = (void *)malloc(s);
  if (!p) {
    const char *meld = "out of memory in alloca\n";
    write(2, meld, strlen(meld));
    exit(1);
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  add    $0x8,%rsp
  ret
L6:
  mov    $0x2,%edi
  mov    $0x18,%edx
  lea    D6(%rip),%rsi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: out of memory in alloca


assistant: ```c
void *xmalloc(s)
unsigned long s;
{
  void *p = (void *)malloc(s);
  if (!p) {
    const char *meld = "out of memory in alloca\n";
    write(2, meld, strlen(meld));
    exit(1);
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  ret
L8:
  mov    $0x2,%edi
  mov    $0x18,%edx
  lea    D5(%rip),%rsi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: out of memory in alloca


assistant: ```c
void *xmalloc(s)
unsigned long s;
{
  void *p = (void *)malloc(s);
  if (!p) {
    const char *meld = "out of memory in alloca\n";
    write(2, meld, strlen(meld));
    exit(1);
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %1.2f


assistant: ```c
void printarray(double *array, int lenarray) {
  for (int i = 0; i < lenarray; i++) {
    printf("%1.2f\n", array[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printarray>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D2(%rip),%rbp
L6:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: %1.2f


assistant: ```c
void printarray(double *array, int lenarray) {
  for (int i = 0; i < lenarray; i++) {
    printf("%1.2f\n", array[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printarray>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L17:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %1.2f


assistant: ```c
void printarray(double *array, int lenarray) {
  for (int i = 0; i < lenarray; i++) {
    printf("%1.2f\n", array[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<printarray>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: %1.2f


assistant: ```c
void printarray(double *array, int lenarray) {
  for (int i = 0; i < lenarray; i++) {
    printf("%1.2f\n", array[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unrecognized_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,%eax
  mov    %al,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6e676f6365726e55,%rax
  movabs $0x6168632064657a69,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x203a726574636172,%rax
  mov    $0x3f,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movzbl -0x34(%rbp),%eax
  mov    %al,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <yyerror@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void unrecognized_char(char c) {
  char buf[32] = "Unrecognized character: ?";
  buf[24] = c;
  yyerror(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unrecognized_char>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6e676f6365726e55,%rax
  movabs $0x6168632064657a69,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x203a726574636172,%rax
  mov    $0x3f,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %dil,0x18(%rsp)
  mov    %rsp,%rdi
  call   <yyerror@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unrecognized_char(char c) {
  char buf[32] = "Unrecognized character: ?";
  buf[24] = c;
  yyerror(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unrecognized_char>:
  endbr64
  sub    $0x38,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D6(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  mov    %dil,0x18(%rsp)
  mov    %rsp,%rdi
  call   <yyerror@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: byte[16]
name: unpack_data
arguments: label: D6
data_type: byte[16]

tool: {"D17": [0x55,0x6e,0x72,0x65,0x63,0x6f,0x67,0x6e,0x69,0x7a,0x65,0x64,0x20,0x63,0x68,0x61]}

tool: {"D6": [0x72,0x61,0x63,0x74,0x65,0x72,0x3a,0x20,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void unrecognized_char(char c) {
  char buf[32] = "Unrecognized character: ?";
  buf[24] = c;
  yyerror(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unrecognized_char>:
  endbr64
  sub    $0x38,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  mov    %dil,0x18(%rsp)
  mov    %rsp,%rdi
  call   <yyerror@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D14": [0x55,0x6e,0x72,0x65,0x63,0x6f,0x67,0x6e,0x69,0x7a,0x65,0x64,0x20,0x63,0x68,0x61]}

tool: {"D0": [0x72,0x61,0x63,0x74,0x65,0x72,0x3a,0x20,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void unrecognized_char(char c) {
  char buf[32] = "Unrecognized character: ?";
  buf[24] = c;
  yyerror(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hexascii_to_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L1:
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <hex_to_bin@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <hex_to_bin@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  or     %ebx,%edx
  mov    %edx,(%rax)
  addl   $0x2,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L1
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int hexascii_to_binary(uint8_t bin_buf[], uint8_t hex_buf[], int n_hex) {
  int i, j;
  for (i = 0, j = 0; i < n_hex; i += 2, j++) {
    bin_buf[j] = (hex_to_bin(hex_buf[i + 1]) << 4) | hex_to_bin(hex_buf[i]);
  }
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexascii_to_binary>:
  endbr64
  test   %edx,%edx
  jle    L17
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x4(%rsi),%rbp
  lea    -0x1(%rdx),%r13d
  shr    %r13d
  mov    %r13d,%eax
  lea    0x4(%rdi,%rax,4),%r14
L2:
  mov    0x0(%rbp),%edi
  call   <hex_to_bin@plt>
  mov    %eax,%ebx
  mov    -0x4(%rbp),%edi
  call   <hex_to_bin@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  mov    %ebx,(%r12)
  add    $0x4,%r12
  add    $0x8,%rbp
  cmp    %r14,%r12
  jne    L2
  lea    0x1(%r13),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hexascii_to_binary(uint8_t bin_buf[], uint8_t hex_buf[], int n_hex) {
  int i, j;
  for (i = 0, j = 0; i < n_hex; i += 2, j++) {
    bin_buf[j] = (hex_to_bin(hex_buf[i + 1]) << 4) | hex_to_bin(hex_buf[i]);
  }
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hexascii_to_binary>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r14
  lea    0x4(%rsi),%r14
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  shr    %r12d
  mov    %rdi,%rbp
  push   %rbx
  mov    %r12d,%eax
  lea    0x4(%rdi,%rax,4),%r13
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    (%r14),%edi
  add    $0x4,%rbp
  add    $0x8,%r14
  call   <hex_to_bin@plt>
  mov    -0xc(%r14),%edi
  mov    %eax,%ebx
  call   <hex_to_bin@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  mov    %ebx,-0x4(%rbp)
  cmp    %r13,%rbp
  jne    L14
  pop    %rbx
  lea    0x1(%r12),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hexascii_to_binary(uint8_t bin_buf[], uint8_t hex_buf[], int n_hex) {
  int i, j;
  for (i = 0, j = 0; i < n_hex; i += 2, j++) {
    bin_buf[j] = (hex_to_bin(hex_buf[i + 1]) << 4) | hex_to_bin(hex_buf[i]);
  }
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hexascii_to_binary>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r14
  lea    0x4(%rsi),%r14
  push   %r13
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  shr    %r12d
  mov    %rdi,%rbp
  push   %rbx
  mov    %r12d,%eax
  lea    0x4(%rdi,%rax,4),%r13
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    (%r14),%edi
  add    $0x4,%rbp
  add    $0x8,%r14
  call   <hex_to_bin@plt>
  mov    -0xc(%r14),%edi
  mov    %eax,%ebx
  call   <hex_to_bin@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  mov    %ebx,-0x4(%rbp)
  cmp    %r13,%rbp
  jne    L1
  pop    %rbx
  lea    0x1(%r12),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hexascii_to_binary(uint8_t bin_buf[], uint8_t hex_buf[], int n_hex) {
  int i, j;
  for (i = 0, j = 0; i < n_hex; i += 2, j++) {
    bin_buf[j] = (hex_to_bin(hex_buf[i + 1]) << 4) | hex_to_bin(hex_buf[i]);
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L31
L20:
  mov    -0x18(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L31
L30:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
  mov    -0x8(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *result;
  if (size == 0)
    return (NULL);
  result = malloc(sizeof(void *) * size);
  if (result == NULL)
    return (NULL);
  ft_bzero(result, size);
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rbp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *result;
  if (size == 0)
    return (NULL);
  result = malloc(sizeof(void *) * size);
  if (result == NULL)
    return (NULL);
  ft_bzero(result, size);
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_memalloc>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L14
  mov    %rdi,%rbp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *result;
  if (size == 0)
    return (NULL);
  result = malloc(sizeof(void *) * size);
  if (result == NULL)
    return (NULL);
  ft_bzero(result, size);
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_memalloc>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *result;
  if (size == 0)
    return (NULL);
  result = malloc(sizeof(void *) * size);
  if (result == NULL)
    return (NULL);
  ft_bzero(result, size);
  return (result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_longlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L33
L37:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L33:
  cmpl   $0x1fff,-0x24(%rbp)
  jle    L37
  movl   $0x0,-0x24(%rbp)
  jmp    L1
L52:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  cmp    $0x2000,%rax
  je     L8
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  jmp    L53
L8:
  addl   $0x1,-0x24(%rbp)
L1:
  cmpl   $0x1,-0x24(%rbp)
  jle    L52
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int test_longlong() {
  int i;
  long long sums[2] = {0};
#pragma acc parallel loop
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sums[0]++;
#pragma acc atomic
    ++sums[1];
  }
  for (i = 0; i < 2; i++) {
    if (sums[i] != (8192)) {
      return i + 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_longlong>:
  endbr64
  mov    $0x1,%eax
  mov    $0x2001,%ecx
  mov    $0x0,%edx
L2:
  lea    (%rdx,%rax,1),%rdi
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L2
  cmp    $0x2000,%rdi
  jne    L16
  mov    $0x0,%eax
  cmp    $0x2000,%rsi
  jne    L0
L43:
  ret
L0:
  mov    $0x1,%eax
  jmp    L17
L16:
  mov    $0x0,%eax
L17:
  add    $0x1,%eax
  jmp    L43
```

assistant: ```c
int test_longlong() {
  int i;
  long long sums[2] = {0};
#pragma acc parallel loop
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sums[0]++;
#pragma acc atomic
    ++sums[1];
  }
  for (i = 0; i < 2; i++) {
    if (sums[i] != (8192)) {
      return i + 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_longlong>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_longlong() {
  int i;
  long long sums[2] = {0};
#pragma acc parallel loop
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sums[0]++;
#pragma acc atomic
    ++sums[1];
  }
  for (i = 0; i < 2; i++) {
    if (sums[i] != (8192)) {
      return i + 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_longlong>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test_longlong() {
  int i;
  long long sums[2] = {0};
#pragma acc parallel loop
  for (i = 0; i < 8192; i++) {
#pragma acc atomic
    sums[0]++;
#pragma acc atomic
    ++sums[1];
  }
  for (i = 0; i < 2; i++) {
    if (sums[i] != (8192)) {
      return i + 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unsigned_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jae    L32
  mov    $0xffffffff,%eax
  jmp    L14
L32:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jbe    L15
  mov    $0x1,%eax
  jmp    L14
L15:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int unsigned_cmp(const void *a, const void *b) {
  const unsigned *pa = (const unsigned *)a;
  const unsigned *pb = (const unsigned *)b;
  if (*pa < *pb)
    return -1;
  else if (*pa > *pb)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unsigned_cmp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jb     L7
  seta   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int unsigned_cmp(const void *a, const void *b) {
  const unsigned *pa = (const unsigned *)a;
  const unsigned *pb = (const unsigned *)b;
  if (*pa < *pb)
    return -1;
  else if (*pa > *pb)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unsigned_cmp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int unsigned_cmp(const void *a, const void *b) {
  const unsigned *pa = (const unsigned *)a;
  const unsigned *pb = (const unsigned *)b;
  if (*pa < *pb)
    return -1;
  else if (*pa > *pb)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<unsigned_cmp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int unsigned_cmp(const void *a, const void *b) {
  const unsigned *pa = (const unsigned *)a;
  const unsigned *pb = (const unsigned *)b;
  if (*pa < *pb)
    return -1;
  else if (*pa > *pb)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_rules>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x81c(%rbp)
  mov    -0x828(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x818(%rbp)
  cmpq   $0x0,-0x818(%rbp)
  jne    L26
  mov    -0x828(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L26
L7:
  mov    -0x81c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x830(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x810(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x81c(%rbp)
L26:
  mov    -0x818(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    $0x800,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x81c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D10
type_infered: string

tool: D5: rb

tool: D10: 
Error in open: %s 



assistant: ```c
int read_rules(char *filename, char **p) {
  int i = 0;
  char buf[2048];
  FILE *fin;
  fin = fopen(filename, "rb");
  if (fin == NULL) {
    printf("\nError in open: %s \n\n", filename);
    exit(1);
  }
  while (fgets(buf, 2048, fin) != NULL) {
    strcpy(p[i], buf);
    i++;
  }
  fclose(fin);
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_rules>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
L24:
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L22
L39:
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
L3:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  add    $0x1,%rbx
L22:
  mov    %r12,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L3
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %ebx,%eax
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D13: rb

tool: D12: 
Error in open: %s 



assistant: ```c
int read_rules(char *filename, char **p) {
  int i = 0;
  char buf[2048];
  FILE *fin;
  fin = fopen(filename, "rb");
  if (fin == NULL) {
    printf("\nError in open: %s \n\n", filename);
    exit(1);
  }
  while (fgets(buf, 2048, fin) != NULL) {
    strcpy(p[i], buf);
    i++;
  }
  fclose(fin);
  return i;
}
```