ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<format_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    $0x0,%edi
  call   <va_copy@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %rax,%rbx
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
L2:
  mov    $0x0,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *format_str(const char format[], ...) {
  va_list ap;
  va_list aq;
  size_t len;
  char *result_buf;
  va_start(ap, format);
  va_copy(aq, ap);
  len = vsnprintf(NULL, 0, format, ap);
  va_end(ap);
  if ((result_buf = malloc(len + 1)) != NULL) {
    (void)vsprintf(result_buf, format, aq);
  }
  va_end(aq);
  return result_buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<format_str>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    %r12d,%esi
  xor    %edi,%edi
  call   <va_copy@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
L8:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *format_str(const char format[], ...) {
  va_list ap;
  va_list aq;
  size_t len;
  char *result_buf;
  va_start(ap, format);
  va_copy(aq, ap);
  len = vsnprintf(NULL, 0, format, ap);
  va_end(ap);
  if ((result_buf = malloc(len + 1)) != NULL) {
    (void)vsprintf(result_buf, format, aq);
  }
  va_end(aq);
  return result_buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<format_str>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    %r12d,%esi
  xor    %edi,%edi
  call   <va_copy@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
L4:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *format_str(const char format[], ...) {
  va_list ap;
  va_list aq;
  size_t len;
  char *result_buf;
  va_start(ap, format);
  va_copy(aq, ap);
  len = vsnprintf(NULL, 0, format, ap);
  va_end(ap);
  if ((result_buf = malloc(len + 1)) != NULL) {
    (void)vsprintf(result_buf, format, aq);
  }
  va_end(aq);
  return result_buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prime_factors_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <prime_factors@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  je     L20
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L26
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L48
L59:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L37
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L26
L37:
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L59
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string

tool: D2: Incorrect factorization of prime %d: %d factors given instead of %d.



tool: D13: Incorrect 0th factor of %d: %d given.


tool: D26: %d factored correctly.



assistant: ```c
int prime_factors_test(long num, long *expected_factors, int num_of_expected_factors) {
  long *factor_list = prime_factors(num);
  int i;
  if (factor_list[0] != num_of_expected_factors) {
    printf("Incorrect factorization of prime %d: %d factors given instead of %d.\n\n", num, factor_list[0], num_of_expected_factors);
    return 1;
  } else {
    for (i = 0; i < num_of_expected_factors; i++) {
      if (factor_list[i + 1] != expected_factors[i]) {
        printf("Incorrect 0th factor of %d: %d given.\n\b", num, factor_list[1]);
        return 1;
      }
    }
  }
  printf("%d factored correctly.\n\n", num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime_factors_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  call   <prime_factors@plt>
  mov    (%rax),%rdx
  movslq %ebp,%rcx
  cmp    %rcx,%rdx
  jne    L3
  lea    0x1(%rbp),%ecx
  mov    $0x1,%edx
  test   %ebp,%ebp
  jle    L59
L12:
  mov    -0x8(%rbx,%rdx,8),%rsi
  cmp    %rsi,(%rax,%rdx,8)
  jne    L27
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L12
L59:
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %ebp,%ecx
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L15
L27:
  mov    0x8(%rax),%rdx
  mov    %r12,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string

tool: D6: %d factored correctly.



tool: D7: Incorrect factorization of prime %d: %d factors given instead of %d.



tool: D21: Incorrect 0th factor of %d: %d given.


assistant: ```c
int prime_factors_test(long num, long *expected_factors, int num_of_expected_factors) {
  long *factor_list = prime_factors(num);
  int i;
  if (factor_list[0] != num_of_expected_factors) {
    printf("Incorrect factorization of prime %d: %d factors given instead of %d.\n\n", num, factor_list[0], num_of_expected_factors);
    return 1;
  } else {
    for (i = 0; i < num_of_expected_factors; i++) {
      if (factor_list[i + 1] != expected_factors[i]) {
        printf("Incorrect 0th factor of %d: %d given.\n\b", num, factor_list[1]);
        return 1;
      }
    }
  }
  printf("%d factored correctly.\n\n", num);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<prime_factors_test>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <prime_factors@plt>
  movslq %r12d,%rcx
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L31
  lea    0x1(%r12),%esi
  mov    $0x1,%edi
  test   %r12d,%r12d
  jg     L33
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  je     L18
L33:
  mov    -0x8(%rbx,%rdi,8),%rcx
  cmp    %rcx,(%rax,%rdi,8)
  je     L40
  mov    0x8(%rax),%rdx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D9: Incorrect 0th factor of %d: %d given.


tool: D16: %d factored correctly.



tool: D8: Incorrect factorization of prime %d: %d factors given instead of %d.



assistant: ```c
int prime_factors_test(long num, long *expected_factors, int num_of_expected_factors) {
  long *factor_list = prime_factors(num);
  int i;
  if (factor_list[0] != num_of_expected_factors) {
    printf("Incorrect factorization of prime %d: %d factors given instead of %d.\n\n", num, factor_list[0], num_of_expected_factors);
    return 1;
  } else {
    for (i = 0; i < num_of_expected_factors; i++) {
      if (factor_list[i + 1] != expected_factors[i]) {
        printf("Incorrect 0th factor of %d: %d given.\n\b", num, factor_list[1]);
        return 1;
      }
    }
  }
  printf("%d factored correctly.\n\n", num);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prime_factors_test>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <prime_factors@plt>
  movslq %r12d,%rcx
  mov    (%rax),%rdx
  cmp    %rcx,%rdx
  jne    L3
  lea    0x1(%r12),%esi
  mov    $0x1,%edi
  test   %r12d,%r12d
  jg     L10
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  je     L31
L10:
  mov    -0x8(%rbx,%rdi,8),%rcx
  cmp    %rcx,(%rax,%rdi,8)
  je     L18
  mov    0x8(%rax),%rdx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%ecx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D3: Incorrect 0th factor of %d: %d given.


tool: D18: %d factored correctly.



tool: D1: Incorrect factorization of prime %d: %d factors given instead of %d.



assistant: ```c
int prime_factors_test(long num, long *expected_factors, int num_of_expected_factors) {
  long *factor_list = prime_factors(num);
  int i;
  if (factor_list[0] != num_of_expected_factors) {
    printf("Incorrect factorization of prime %d: %d factors given instead of %d.\n\n", num, factor_list[0], num_of_expected_factors);
    return 1;
  } else {
    for (i = 0; i < num_of_expected_factors; i++) {
      if (factor_list[i + 1] != expected_factors[i]) {
        printf("Incorrect 0th factor of %d: %d given.\n\b", num, factor_list[1]);
        return 1;
      }
    }
  }
  printf("%d factored correctly.\n\n", num);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rbp),%rdx
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <modf@plt>
  movsd  -0x8(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L2
  movsd  -0x8(%rbp),%xmm0
  movsd  D4(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L2:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
double floor(double x) {
  modf(x, &x);
  if (x < 0.0)
    x -= 1.0;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<floor>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <modf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L11
L16:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
L11:
  subsd  D0(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: f64

tool: D0: 1

assistant: ```c
double floor(double x) {
  modf(x, &x);
  if (x < 0.0)
    x -= 1.0;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<floor>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <modf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L0
  subsd  D3(%rip),%xmm0
L0:
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: f64

tool: D3: 1

assistant: ```c
double floor(double x) {
  modf(x, &x);
  if (x < 0.0)
    x -= 1.0;
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<floor>:
  endbr64
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <modf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L3
  subsd  D1(%rip),%xmm0
L3:
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: f64

tool: D1: 1

assistant: ```c
double floor(double x) {
  modf(x, &x);
  if (x < 0.0)
    x -= 1.0;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bb_xfopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <bb_perror_msg_and_die@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: %s

assistant: ```c
FILE *bb_xfopen(const char *path, const char *mode) {
  FILE *fp;
  if ((fp = fopen(path, mode)) == NULL)
    bb_perror_msg_and_die("%s", path);
  return fp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bb_xfopen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <bb_perror_msg_and_die@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string

tool: D2: %s

assistant: ```c
FILE *bb_xfopen(const char *path, const char *mode) {
  FILE *fp;
  if ((fp = fopen(path, mode)) == NULL)
    bb_perror_msg_and_die("%s", path);
  return fp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bb_xfopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <bb_perror_msg_and_die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %s

assistant: ```c
FILE *bb_xfopen(const char *path, const char *mode) {
  FILE *fp;
  if ((fp = fopen(path, mode)) == NULL)
    bb_perror_msg_and_die("%s", path);
  return fp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bb_xfopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <bb_perror_msg_and_die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %s

assistant: ```c
FILE *bb_xfopen(const char *path, const char *mode) {
  FILE *fp;
  if ((fp = fopen(path, mode)) == NULL)
    bb_perror_msg_and_die("%s", path);
  return fp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,%ebx
  mov    %ecx,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rcx),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L156:
  cmp    %rdx,%rsp
  je     L150
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L156
L150:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L36
  orq    $0x0,-0x8(%rsp,%rax,1)
L36:
  mov    %rsp,%r11
  lea    0x1(%rbx),%edx
  cmp    %ebx,%esi
  jg     L113
  cmp    %edx,%r9d
  jl     L113
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rcx
  mov    %esi,%eax
  jmp    L65
L8:
  add    $0x1,%edx
  mov    %r10d,%r8d
L115:
  mov    %r8d,-0x4(%r11,%rcx,4)
  mov    %ecx,%r8d
  add    $0x1,%rcx
  cmp    %ebx,%eax
  jg     L0
  cmp    %r9d,%edx
  jg     L0
L65:
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  movslq %edx,%r10
  mov    (%rdi,%r10,4),%r10d
  cmp    %r10d,%r8d
  jg     L8
  add    $0x1,%eax
  jmp    L115
L113:
  mov    %esi,%eax
  mov    %esi,%r8d
L0:
  cmp    %eax,%ebx
  jl     L92
  cltq
  movslq %r8d,%r8
  sub    %rax,%r8
  lea    (%r11,%r8,4),%rcx
L32:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L32
  jmp    L61
L92:
  cmp    %edx,%r9d
  jl     L61
  movslq %edx,%rdx
  movslq %r8d,%r8
  sub    %rdx,%r8
  lea    (%r11,%r8,4),%rcx
L165:
  mov    (%rdi,%rdx,4),%eax
  mov    %eax,(%rcx,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r9d
  jge    L165
L61:
  cmp    %esi,%r9d
  jl     L49
  movslq %esi,%rax
L72:
  mov    (%r11,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L72
L49:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    -0x8(%rbp),%rbx
  leave
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int low, int mid, int high) {
  int i, m, k, l, temp[high + 1];
  l = low;
  i = low;
  m = mid + 1;
  while ((l <= mid) && (m <= high)) {
    if (arr[l] <= arr[m]) {
      temp[i] = arr[l];
      l++;
    } else {
      temp[i] = arr[m];
      m++;
    }
    i++;
  }
  if (l > mid) {
    for (k = m; k <= high; k++) {
      temp[i] = arr[k];
      i++;
    }
  } else {
    for (k = l; k <= mid; k++) {
      temp[i] = arr[k];
      i++;
    }
  }
  for (k = low; k <= high; k++) {
    arr[k] = temp[k];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %edx,%r8d
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x1(%rcx),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L42
L2:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L2
L42:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L55
L60:
  lea    0x1(%r8),%esi
  mov    %rsp,%r14
  cmp    %esi,%r12d
  jl     L36
  cmp    %r8d,%r13d
  jg     L36
  lea    0x1(%r13),%eax
  mov    %r13d,%ecx
  cltq
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L106:
  add    $0x1,%ecx
L153:
  mov    %edx,-0x4(%r14,%rax,4)
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %r8d,%ecx
  jg     L136
  cmp    %r12d,%esi
  jg     L136
L17:
  movslq %ecx,%rdx
  movslq %esi,%rdi
  mov    (%rbx,%rdx,4),%edx
  mov    (%rbx,%rdi,4),%edi
  cmp    %edi,%edx
  jle    L106
  add    $0x1,%esi
  mov    %edi,%edx
  jmp    L153
L36:
  mov    %r13d,%ecx
  movslq %r13d,%rdx
  cs nopw 0x0(%rax,%rax,1)
L136:
  cmp    %ecx,%r8d
  jge    L156
  cmp    %esi,%r12d
  jl     L33
  mov    %r12d,%eax
  lea    (%r14,%rdx,4),%rdi
  sub    %esi,%eax
  movslq %esi,%rsi
  lea    0x4(,%rax,4),%rdx
  lea    (%rbx,%rsi,4),%rsi
  call   <memcpy@plt>
L33:
  cmp    %r13d,%r12d
  jl     L58
  movslq %r13d,%rax
  sub    %r13d,%r12d
  shl    $0x2,%rax
  lea    0x4(,%r12,4),%rdx
  lea    (%rbx,%rax,1),%rdi
  lea    (%r14,%rax,1),%rsi
  call   <memcpy@plt>
L58:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L156:
  sub    %ecx,%r8d
  movslq %ecx,%rcx
  lea    (%r14,%rdx,4),%rdi
  lea    (%rbx,%rcx,4),%rsi
  lea    0x4(,%r8,4),%rdx
  call   <memcpy@plt>
  jmp    L33
  nopl   (%rax)
L55:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L60
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int low, int mid, int high) {
  int i, m, k, l, temp[high + 1];
  l = low;
  i = low;
  m = mid + 1;
  while ((l <= mid) && (m <= high)) {
    if (arr[l] <= arr[m]) {
      temp[i] = arr[l];
      l++;
    } else {
      temp[i] = arr[m];
      m++;
    }
    i++;
  }
  if (l > mid) {
    for (k = m; k <= high; k++) {
      temp[i] = arr[k];
      i++;
    }
  } else {
    for (k = l; k <= mid; k++) {
      temp[i] = arr[k];
      i++;
    }
  }
  for (k = low; k <= high; k++) {
    arr[k] = temp[k];
  }
}
```