ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<percDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L23
L7:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  je     L49
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L49
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L31
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jg     L7
  jmp    L11
L31:
  nop
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void percDown(int A[], int r, int N) {
  int child;
  int tmp;
  for (tmp = A[r]; (2 * (r) + 1) < N; r = child) {
    child = (2 * (r) + 1);
    if (child != N - 1 && A[child + 1] > A[child]) {
      child++;
    }
    if (A[child] > tmp) {
      A[r] = A[child];
    } else {
      break;
    }
  }
  A[r] = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<percDown>:
  endbr64
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r9d
  lea    0x1(%rsi,%rsi,1),%eax
  cmp    %eax,%edx
  jle    L15
  lea    -0x1(%rdx),%r10d
  jmp    L26
L61:
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jle    L15
  movslq %esi,%rsi
  mov    %eax,(%rdi,%rsi,4)
  lea    0x1(%rcx,%rcx,1),%eax
  cmp    %edx,%eax
  jge    L64
  mov    %ecx,%esi
L26:
  mov    %eax,%ecx
  cmp    %eax,%r10d
  je     L61
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%eax
  cmp    %eax,0x4(%rdi,%r8,4)
  jle    L61
  lea    0x2(%rsi,%rsi,1),%ecx
  jmp    L61
L64:
  mov    %ecx,%esi
L15:
  movslq %esi,%rsi
  mov    %r9d,(%rdi,%rsi,4)
  ret
```

assistant: ```c
void percDown(int A[], int r, int N) {
  int child;
  int tmp;
  for (tmp = A[r]; (2 * (r) + 1) < N; r = child) {
    child = (2 * (r) + 1);
    if (child != N - 1 && A[child + 1] > A[child]) {
      child++;
    }
    if (A[child] > tmp) {
      A[r] = A[child];
    } else {
      break;
    }
  }
  A[r] = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<percDown>:
  endbr64
  movslq %esi,%r11
  lea    0x1(%rsi,%rsi,1),%eax
  push   %rbp
  lea    (%rdi,%r11,4),%rcx
  push   %rbx
  mov    (%rcx),%ebp
  cmp    %eax,%edx
  jle    L26
  mov    %rdi,%r9
  lea    -0x1(%rdx),%ebx
  jmp    L52
  nop
L38:
  lea    0x1(%rdi,%rdi,1),%eax
  mov    %r8d,(%rcx)
  cmp    %edx,%eax
  jge    L23
  movslq %edi,%r11
  mov    %r11,%rsi
L52:
  movslq %eax,%rcx
  mov    %ebx,%edi
  shl    $0x2,%rcx
  lea    (%r9,%rcx,1),%r10
  mov    (%r10),%r8d
  cmp    %ebx,%eax
  je     L14
  mov    %eax,%edi
  cmp    %r8d,0x4(%r9,%rcx,1)
  jle    L14
  lea    0x2(%rsi,%rsi,1),%edi
  movslq %edi,%rax
  lea    (%r9,%rax,4),%r10
  mov    (%r10),%r8d
L14:
  lea    (%r9,%r11,4),%rcx
  cmp    %r8d,%ebp
  jl     L38
L26:
  mov    %ebp,(%rcx)
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r10,%rcx
  mov    %ebp,(%rcx)
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void percDown(int A[], int r, int N) {
  int child;
  int tmp;
  for (tmp = A[r]; (2 * (r) + 1) < N; r = child) {
    child = (2 * (r) + 1);
    if (child != N - 1 && A[child + 1] > A[child]) {
      child++;
    }
    if (A[child] > tmp) {
      A[r] = A[child];
    } else {
      break;
    }
  }
  A[r] = tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<percDown>:
  endbr64
  movslq %esi,%r11
  lea    0x1(%rsi,%rsi,1),%eax
  push   %rbp
  lea    (%rdi,%r11,4),%rcx
  push   %rbx
  mov    (%rcx),%ebp
  cmp    %eax,%edx
  jle    L43
  mov    %rdi,%r9
  lea    -0x1(%rdx),%ebx
  jmp    L38
  nop
L2:
  lea    0x1(%rdi,%rdi,1),%eax
  mov    %r8d,(%rcx)
  cmp    %edx,%eax
  jge    L42
  movslq %edi,%r11
  mov    %r11,%rsi
L38:
  movslq %eax,%rcx
  mov    %ebx,%edi
  shl    $0x2,%rcx
  lea    (%r9,%rcx,1),%r10
  mov    (%r10),%r8d
  cmp    %ebx,%eax
  je     L32
  mov    %eax,%edi
  cmp    %r8d,0x4(%r9,%rcx,1)
  jle    L32
  lea    0x2(%rsi,%rsi,1),%edi
  movslq %edi,%rax
  lea    (%r9,%rax,4),%r10
  mov    (%r10),%r8d
L32:
  lea    (%r9,%r11,4),%rcx
  cmp    %r8d,%ebp
  jl     L2
L43:
  mov    %ebp,(%rcx)
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r10,%rcx
  mov    %ebp,(%rcx)
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void percDown(int A[], int r, int N) {
  int child;
  int tmp;
  for (tmp = A[r]; (2 * (r) + 1) < N; r = child) {
    child = (2 * (r) + 1);
    if (child != N - 1 && A[child + 1] > A[child]) {
      child++;
    }
    if (A[child] > tmp) {
      A[r] = A[child];
    } else {
      break;
    }
  }
  A[r] = tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resample_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void resample_init(int *index, int first, int last) {
  int i;
  for (i = first; i <= last; i++)
    index[i] = i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<resample_init>:
  endbr64
  cmp    %edx,%esi
  jg     L13
  movslq %esi,%rsi
L17:
  mov    %esi,(%rdi,%rsi,4)
  add    $0x1,%rsi
  cmp    %esi,%edx
  jge    L17
L13:
  ret
```

assistant: ```c
void resample_init(int *index, int first, int last) {
  int i;
  for (i = first; i <= last; i++)
    index[i] = i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<resample_init>:
  endbr64
  cmp    %edx,%esi
  jg     L1
  movslq %esi,%rsi
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %esi,(%rdi,%rsi,4)
  add    $0x1,%rsi
  cmp    %esi,%edx
  jge    L0
L1:
  ret
```

assistant: ```c
void resample_init(int *index, int first, int last) {
  int i;
  for (i = first; i <= last; i++)
    index[i] = i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<resample_init>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jg     L37
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r9d
  cmp    $0x2,%eax
  jbe    L55
  movslq %esi,%rax
  movd   %esi,%xmm3
  movdqa D17(%rip),%xmm2
  lea    (%r8,%rax,4),%rdx
  mov    %r9d,%eax
  pshufd $0x0,%xmm3,%xmm0
  shr    $0x2,%eax
  paddd  D7(%rip),%xmm0
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x10,%rax
L52:
  movdqa %xmm0,%xmm1
  paddd  %xmm2,%xmm0
  movups %xmm1,(%rdx)
  mov    %rax,%rdx
  cmp    %rsi,%rax
  jne    L15
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%ecx
  cmp    %eax,%r9d
  je     L37
L55:
  movslq %ecx,%rax
  mov    %ecx,(%r8,%rax,4)
  lea    0x0(,%rax,4),%rdx
  lea    0x1(%rcx),%eax
  cmp    %eax,%edi
  jl     L37
  add    $0x2,%ecx
  mov    %eax,0x4(%r8,%rdx,1)
  cmp    %ecx,%edi
  jl     L37
  mov    %ecx,0x8(%r8,%rdx,1)
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: byte[16]
name: disassemble_data
arguments: label: D7
type_infered: byte[16]

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
void resample_init(int *index, int first, int last) {
  int i;
  for (i = first; i <= last; i++)
    index[i] = i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  movsd  %xmm1,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L7:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  divsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L18:
  cmpq   $0x5,-0x8(%rbp)
  jle    L7
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pa(double e[4], double t, double t2) {
  long j;
  for (j = 0; j < 6; j++) {
    e[0] = (e[0] + e[1] + e[2] - e[3]) * t;
    e[1] = (e[0] + e[1] - e[2] + e[3]) * t;
    e[2] = (e[0] - e[1] + e[2] + e[3]) * t;
    e[3] = (-e[0] + e[1] + e[2] + e[3]) / t2;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pa>:
  endbr64
  movapd %xmm0,%xmm4
  movsd  (%rdi),%xmm2
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm6
  movsd  0x18(%rdi),%xmm5
  mov    $0x6,%eax
L7:
  addsd  %xmm0,%xmm2
  addsd  %xmm6,%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  subsd  %xmm6,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm0
  movapd %xmm2,%xmm3
  subsd  %xmm0,%xmm3
  addsd  %xmm6,%xmm3
  addsd  %xmm5,%xmm3
  movapd %xmm3,%xmm6
  mulsd  %xmm4,%xmm6
  movapd %xmm0,%xmm3
  subsd  %xmm2,%xmm3
  addsd  %xmm6,%xmm3
  addsd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  sub    $0x1,%rax
  jne    L7
  movsd  %xmm2,(%rdi)
  movsd  %xmm0,0x8(%rdi)
  movsd  %xmm6,0x10(%rdi)
  movsd  %xmm5,0x18(%rdi)
  ret
```

assistant: ```c
void pa(double e[4], double t, double t2) {
  long j;
  for (j = 0; j < 6; j++) {
    e[0] = (e[0] + e[1] + e[2] - e[3]) * t;
    e[1] = (e[0] + e[1] - e[2] + e[3]) * t;
    e[2] = (e[0] - e[1] + e[2] + e[3]) * t;
    e[3] = (-e[0] + e[1] + e[2] + e[3]) / t2;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pa>:
  endbr64
  movapd %xmm0,%xmm4
  movsd  (%rdi),%xmm2
  movsd  0x8(%rdi),%xmm0
  mov    $0x6,%eax
  movsd  0x10(%rdi),%xmm6
  movsd  0x18(%rdi),%xmm5
L4:
  addsd  %xmm0,%xmm2
  addsd  %xmm6,%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm3
  subsd  %xmm6,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm3
  addsd  %xmm6,%xmm3
  addsd  %xmm5,%xmm3
  movapd %xmm3,%xmm6
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm6
  subsd  %xmm2,%xmm3
  addsd  %xmm6,%xmm3
  addsd  %xmm3,%xmm5
  divsd  %xmm1,%xmm5
  sub    $0x1,%rax
  jne    L4
  movsd  %xmm2,(%rdi)
  movsd  %xmm0,0x8(%rdi)
  movsd  %xmm6,0x10(%rdi)
  movsd  %xmm5,0x18(%rdi)
  ret
```

assistant: ```c
void pa(double e[4], double t, double t2) {
  long j;
  for (j = 0; j < 6; j++) {
    e[0] = (e[0] + e[1] + e[2] - e[3]) * t;
    e[1] = (e[0] + e[1] - e[2] + e[3]) * t;
    e[2] = (e[0] - e[1] + e[2] + e[3]) * t;
    e[3] = (-e[0] + e[1] + e[2] + e[3]) / t2;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pa>:
  endbr64
  movapd %xmm0,%xmm3
  movsd  (%rdi),%xmm2
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm5
  movsd  0x18(%rdi),%xmm6
  addsd  %xmm0,%xmm2
  addsd  %xmm5,%xmm2
  subsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm4
  subsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm4
  addsd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  subsd  %xmm2,%xmm5
  addsd  %xmm0,%xmm2
  addsd  %xmm6,%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm5
  addsd  %xmm4,%xmm2
  addsd  %xmm6,%xmm5
  divsd  %xmm1,%xmm5
  subsd  %xmm5,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm6
  subsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm6
  addsd  %xmm4,%xmm6
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm4
  addsd  %xmm0,%xmm2
  addsd  %xmm5,%xmm6
  mulsd  %xmm3,%xmm6
  addsd  %xmm6,%xmm4
  addsd  %xmm6,%xmm2
  addsd  %xmm5,%xmm4
  divsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm5
  subsd  %xmm6,%xmm0
  addsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm5
  addsd  %xmm6,%xmm5
  movapd %xmm0,%xmm6
  subsd  %xmm2,%xmm6
  addsd  %xmm0,%xmm2
  addsd  %xmm4,%xmm5
  mulsd  %xmm3,%xmm5
  addsd  %xmm5,%xmm6
  addsd  %xmm5,%xmm2
  addsd  %xmm4,%xmm6
  divsd  %xmm1,%xmm6
  subsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm4
  subsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm4
  addsd  %xmm5,%xmm4
  movapd %xmm0,%xmm5
  subsd  %xmm2,%xmm5
  addsd  %xmm0,%xmm2
  addsd  %xmm6,%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm5
  addsd  %xmm4,%xmm2
  addsd  %xmm6,%xmm5
  divsd  %xmm1,%xmm5
  subsd  %xmm5,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm6
  subsd  %xmm4,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm6
  addsd  %xmm4,%xmm6
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm4
  addsd  %xmm0,%xmm2
  addsd  %xmm5,%xmm6
  mulsd  %xmm3,%xmm6
  addsd  %xmm6,%xmm4
  addsd  %xmm6,%xmm2
  addsd  %xmm5,%xmm4
  divsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  movapd %xmm2,%xmm5
  movsd  %xmm2,(%rdi)
  subsd  %xmm6,%xmm0
  addsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm5
  movsd  %xmm0,0x8(%rdi)
  subsd  %xmm2,%xmm0
  addsd  %xmm6,%xmm5
  addsd  %xmm4,%xmm5
  mulsd  %xmm5,%xmm3
  addsd  %xmm3,%xmm0
  movsd  %xmm3,0x10(%rdi)
  addsd  %xmm4,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void pa(double e[4], double t, double t2) {
  long j;
  for (j = 0; j < 6; j++) {
    e[0] = (e[0] + e[1] + e[2] - e[3]) * t;
    e[1] = (e[0] + e[1] - e[2] + e[3]) * t;
    e[2] = (e[0] - e[1] + e[2] + e[3]) * t;
    e[3] = (-e[0] + e[1] + e[2] + e[3]) / t2;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D98(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  ucomiss D98(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  movss  -0xc(%rbp),%xmm0
  ucomiss D98(%rip),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movsd  D118(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd D118(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  movsd  -0x8(%rbp),%xmm0
  ucomisd D118(%rip),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movss  D72(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  ucomiss D72(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  movss  -0xc(%rbp),%xmm0
  ucomiss D72(%rip),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movss  D26(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  ucomiss D26(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  movss  -0xc(%rbp),%xmm0
  ucomiss D26(%rip),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D98
data_type: f32
name: extract_symbolic_data
arguments: data_label: D118
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D72
data_type: f32
name: extract_symbolic_data
arguments: data_label: D26
data_type: byte[4]

tool: D98: 1.25

tool: {"D118": [0x00,0x00,0x00,0x00,0x00,0x00,0xf4,0x3f]}

tool: D72: 50

tool: {"D26": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float a;
  double b;
  a = 1.25L;
  assert(a == 1.25);
  b = 1.250;
  assert(b == 1.25);
  a = 0.5e2;
  assert(a == 50);
  a = 0x1.4p+4;
  assert(a == 20);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  float a;
  double b;
  a = 1.25L;
  assert(a == 1.25);
  b = 1.250;
  assert(b == 1.25);
  a = 0.5e2;
  assert(a == 50);
  a = 0x1.4p+4;
  assert(a == 20);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  float a;
  double b;
  a = 1.25L;
  assert(a == 1.25);
  b = 1.250;
  assert(b == 1.25);
  a = 0.5e2;
  assert(a == 50);
  a = 0x1.4p+4;
  assert(a == 20);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  float a;
  double b;
  a = 1.25L;
  assert(a == 1.25);
  b = 1.250;
  assert(b == 1.25);
  a = 0.5e2;
  assert(a == 50);
  a = 0x1.4p+4;
  assert(a == 20);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modinv_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3e8,%esi
  mov    $0xff,%edi
  call   <modinv@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x3e8,%esi
  mov    $0x101,%edi
  call   <modinv@plt>
  cmp    $0x189,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void modinv_test() {
  assert(modinv(255, 1000) == 0);
  assert(modinv(257, 1000) == 393);
}
```
user: What is the c source code of the assembly code below?

```asm
<modinv_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0xff,%edi
  call   <modinv@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x3e8,%esi
  mov    $0x101,%edi
  call   <modinv@plt>
  cmp    $0x189,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void modinv_test() {
  assert(modinv(255, 1000) == 0);
  assert(modinv(257, 1000) == 393);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<modinv_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0xff,%edi
  call   <modinv@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x101,%edi
  mov    $0x3e8,%esi
  call   <modinv@plt>
  xor    %edi,%edi
  cmp    $0x189,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
void modinv_test() {
  assert(modinv(255, 1000) == 0);
  assert(modinv(257, 1000) == 393);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modinv_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0xff,%edi
  call   <modinv@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x101,%edi
  mov    $0x3e8,%esi
  call   <modinv@plt>
  xor    %edi,%edi
  cmp    $0x189,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

assistant: ```c
void modinv_test() {
  assert(modinv(255, 1000) == 0);
  assert(modinv(257, 1000) == 393);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L23:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  add    $0x1,%eax
  jmp    L15
L25:
  addq   $0x4,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L23
  mov    $0xffffffff,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int fun(int *a, int n) {
  int *p;
  for (p = a; p < a + 10; p++)
    if (*p == n)
      return p - a + 1;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun>:
  endbr64
  lea    0x28(%rdi),%rdx
  mov    %rdi,%rax
L3:
  cmp    %esi,(%rax)
  je     L7
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
  mov    $0xffffffff,%eax
  ret
L7:
  sub    %rdi,%rax
  sar    $0x2,%rax
  add    $0x1,%eax
  ret
```

assistant: ```c
int fun(int *a, int n) {
  int *p;
  for (p = a; p < a + 10; p++)
    if (*p == n)
      return p - a + 1;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fun>:
  endbr64
  lea    0x28(%rdi),%rdx
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L14:
  cmp    %esi,(%rax)
  je     L17
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  sub    %rdi,%rax
  sar    $0x2,%rax
  add    $0x1,%eax
  ret
```

assistant: ```c
int fun(int *a, int n) {
  int *p;
  for (p = a; p < a + 10; p++)
    if (*p == n)
      return p - a + 1;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fun>:
  endbr64
  cmp    (%rdi),%esi
  je     L11
  lea    0x4(%rdi),%rax
  cmp    0x4(%rdi),%esi
  je     L91
  lea    0x8(%rdi),%rax
  cmp    0x8(%rdi),%esi
  je     L91
  lea    0xc(%rdi),%rax
  cmp    0xc(%rdi),%esi
  je     L91
  lea    0x10(%rdi),%rax
  cmp    0x10(%rdi),%esi
  je     L91
  lea    0x14(%rdi),%rax
  cmp    0x14(%rdi),%esi
  je     L91
  lea    0x18(%rdi),%rax
  cmp    0x18(%rdi),%esi
  je     L91
  lea    0x1c(%rdi),%rax
  cmp    0x1c(%rdi),%esi
  je     L91
  lea    0x20(%rdi),%rax
  cmp    0x20(%rdi),%esi
  je     L91
  lea    0x24(%rdi),%rax
  mov    $0xffffffff,%r8d
  cmp    %esi,0x24(%rdi)
  je     L91
  mov    %r8d,%eax
  ret
L11:
  mov    %rdi,%rax
L91:
  sub    %rdi,%rax
  sar    $0x2,%rax
  lea    0x1(%rax),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun(int *a, int n) {
  int *p;
  for (p = a; p < a + 10; p++)
    if (*p == n)
      return p - a + 1;
  return -1;
}
```