ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<print_tree_uncondensed>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <print_tree_nexus@plt>
  mov    %ebx,%r8d
  mov    %r14,%rcx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <print_tree_genomes_uncondensed@plt>
```

assistant: ```c
void print_tree_uncondensed(struct tNode *tree, int num_genes, int *condense_succ, int *condense_decode, int orig_num_genes) {
  print_tree_nexus(tree);
  print_tree_genomes_uncondensed(tree, num_genes, condense_succ, condense_decode, orig_num_genes);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_tree_uncondensed>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <print_tree_nexus@plt>
  mov    %ebx,%r8d
  mov    %r14,%rcx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <print_tree_genomes_uncondensed@plt>
```

assistant: ```c
void print_tree_uncondensed(struct tNode *tree, int num_genes, int *condense_succ, int *condense_decode, int orig_num_genes) {
  print_tree_nexus(tree);
  print_tree_genomes_uncondensed(tree, num_genes, condense_succ, condense_decode, orig_num_genes);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  jmp    L8
L3:
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x30(%rbp)
L8:
  cmpl   $0x5,-0x30(%rbp)
  jle    L3
  movl   $0x0,-0x2c(%rbp)
  jmp    L4
L35:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,-0x24(%rbp)
  mov    $0x5,%eax
  sub    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    $0x5,%eax
  sub    -0x2c(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x2c(%rbp)
L4:
  cmpl   $0x2,-0x2c(%rbp)
  jle    L35
  movl   $0x0,-0x28(%rbp)
  jmp    L65
L57:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L65:
  cmpl   $0x5,-0x28(%rbp)
  jle    L57
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D21
data_type: string

tool: D26: Informe a posicao %d: 

tool: D2: %d

tool: D21: %d 

assistant: ```c
void main() {
  int vetor[6], aux;
  for (int i = 0; i < 6; i++) {
    printf("Informe a posicao %d: ", i + 1);
    scanf("%d", &vetor[i]);
  }
  for (int i = 0; i < 6 / 2; i++) {
    aux = vetor[i];
    vetor[i] = vetor[(6 - 1) - i];
    vetor[(6 - 1) - i] = aux;
  }
  for (int i = 0; i < 6; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D27(%rip),%r14
  lea    D23(%rip),%r13
L13:
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    $0x6,%ebp
  jne    L13
  mov    (%rsp),%eax
  mov    0x14(%rsp),%edx
  mov    %edx,(%rsp)
  mov    %eax,0x14(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x10(%rsp),%edx
  mov    %edx,0x4(%rsp)
  mov    %eax,0x10(%rsp)
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  mov    %edx,0x8(%rsp)
  mov    %eax,0xc(%rsp)
  lea    0x18(%rbx),%r12
  lea    D18(%rip),%rbp
L29:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string

tool: D27: Informe a posicao %d: 

tool: D23: %d

tool: D18: %d 

assistant: ```c
void main() {
  int vetor[6], aux;
  for (int i = 0; i < 6; i++) {
    printf("Informe a posicao %d: ", i + 1);
    scanf("%d", &vetor[i]);
  }
  for (int i = 0; i < 6 / 2; i++) {
    aux = vetor[i];
    vetor[i] = vetor[(6 - 1) - i];
    vetor[(6 - 1) - i] = aux;
  }
  for (int i = 0; i < 6; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x1,%ebp
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    $0x6,%ebp
  jne    L3
  mov    (%rsp),%eax
  mov    0x10(%rsp),%edx
  lea    0x18(%rbx),%r12
  lea    D3(%rip),%rbp
  mov    0x14(%rsp),%esi
  mov    %eax,0x14(%rsp)
  mov    0x4(%rsp),%eax
  mov    %edx,0x4(%rsp)
  mov    0xc(%rsp),%edx
  mov    %eax,0x10(%rsp)
  mov    0x8(%rsp),%eax
  mov    %esi,(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %eax,0xc(%rsp)
  jmp    L36
  xchg   %ax,%ax
L16:
  mov    (%rbx),%esi
L36:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D0
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D9: Informe a posicao %d: 

tool: D0: %d

tool: D3: %d 

assistant: ```c
void main() {
  int vetor[6], aux;
  for (int i = 0; i < 6; i++) {
    printf("Informe a posicao %d: ", i + 1);
    scanf("%d", &vetor[i]);
  }
  for (int i = 0; i < 6 / 2; i++) {
    aux = vetor[i];
    vetor[i] = vetor[(6 - 1) - i];
    vetor[(6 - 1) - i] = aux;
  }
  for (int i = 0; i < 6; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%ebp
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    $0x6,%ebp
  jne    L9
  mov    (%rsp),%eax
  movd   0x14(%rsp),%xmm0
  lea    0x18(%rbx),%r12
  lea    D5(%rip),%rbp
  mov    0x4(%rsp),%edx
  movd   0xc(%rsp),%xmm1
  mov    %eax,0x14(%rsp)
  mov    0x10(%rsp),%eax
  movd   0x8(%rsp),%xmm2
  mov    %edx,0x10(%rsp)
  movd   %eax,%xmm3
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D0: Informe a posicao %d: 

tool: D9: %d

tool: D5: %d 

assistant: ```c
void main() {
  int vetor[6], aux;
  for (int i = 0; i < 6; i++) {
    printf("Informe a posicao %d: ", i + 1);
    scanf("%d", &vetor[i]);
  }
  for (int i = 0; i < 6 / 2; i++) {
    aux = vetor[i];
    vetor[i] = vetor[(6 - 1) - i];
    vetor[(6 - 1) - i] = aux;
  }
  for (int i = 0; i < 6; i++) {
    printf("%d ", vetor[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<double_block_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x87,%edi
  call   <_mm_set_epi32@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1f,%esi
  mov    %eax,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <_mm_slli_epi32@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  leave
  ret
```

assistant: ```c
__m128i double_block_in(__m128i block) {
  const __m128i mask = _mm_set_epi32(135, 1, 1, 1);
  __m128i tmp = _mm_srai_epi32(block, 31);
  tmp = _mm_and_si128(tmp, mask);
  tmp = _mm_shuffle_epi32(tmp, _MM_SHUFFLE(2, 1, 0, 3));
  block = _mm_slli_epi32(block, 1);
  return _mm_xor_si128(block, tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<double_block_in>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x87,%edi
  call   <_mm_set_epi32@plt>
  mov    %eax,%ebp
  mov    $0x1f,%esi
  mov    %ebx,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <_mm_and_si128@plt>
  mov    %eax,%ebp
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,%ebp
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <_mm_slli_epi32@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <_mm_xor_si128@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__m128i double_block_in(__m128i block) {
  const __m128i mask = _mm_set_epi32(135, 1, 1, 1);
  __m128i tmp = _mm_srai_epi32(block, 31);
  tmp = _mm_and_si128(tmp, mask);
  tmp = _mm_shuffle_epi32(tmp, _MM_SHUFFLE(2, 1, 0, 3));
  block = _mm_slli_epi32(block, 1);
  return _mm_xor_si128(block, tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<double_block_in>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x87,%edi
  sub    $0x8,%rsp
  call   <_mm_set_epi32@plt>
  mov    %ebp,%edi
  mov    $0x1f,%esi
  mov    %eax,%r12d
  call   <_mm_srai_epi32@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    $0x3,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <_MM_SHUFFLE@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_shuffle_epi32@plt>
  mov    %ebp,%edi
  mov    $0x1,%esi
  mov    %eax,%r12d
  call   <_mm_slli_epi32@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10c0 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i double_block_in(__m128i block) {
  const __m128i mask = _mm_set_epi32(135, 1, 1, 1);
  __m128i tmp = _mm_srai_epi32(block, 31);
  tmp = _mm_and_si128(tmp, mask);
  tmp = _mm_shuffle_epi32(tmp, _MM_SHUFFLE(2, 1, 0, 3));
  block = _mm_slli_epi32(block, 1);
  return _mm_xor_si128(block, tmp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<double_block_in>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x87,%edi
  sub    $0x8,%rsp
  call   <_mm_set_epi32@plt>
  mov    %ebp,%edi
  mov    $0x1f,%esi
  mov    %eax,%r12d
  call   <_mm_srai_epi32@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <_mm_and_si128@plt>
  mov    $0x3,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <_MM_SHUFFLE@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_shuffle_epi32@plt>
  mov    %ebp,%edi
  mov    $0x1,%esi
  mov    %eax,%r12d
  call   <_mm_slli_epi32@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10c0 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i double_block_in(__m128i block) {
  const __m128i mask = _mm_set_epi32(135, 1, 1, 1);
  __m128i tmp = _mm_srai_epi32(block, 31);
  tmp = _mm_and_si128(tmp, mask);
  tmp = _mm_shuffle_epi32(tmp, _MM_SHUFFLE(2, 1, 0, 3));
  block = _mm_slli_epi32(block, 1);
  return _mm_xor_si128(block, tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: Position of %d is %d


assistant: ```c
int main() {
  int arr[] = {2, 3, 1, 5};
  int size = sizeof(arr) / sizeof(arr[0]);
  int find = 1;
  printf("Position of %d is %d\n", find, search(arr, size, find));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <search@plt>
  mov    %eax,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: Position of %d is %d


assistant: ```c
int main() {
  int arr[] = {2, 3, 1, 5};
  int size = sizeof(arr) / sizeof(arr[0]);
  int find = 1;
  printf("Position of %d is %d\n", find, search(arr, size, find));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000002,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x500000001,%rax
  mov    %rax,0x8(%rsp)
  call   <search@plt>
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: Position of %d is %d


assistant: ```c
int main() {
  int arr[] = {2, 3, 1, 5};
  int size = sizeof(arr) / sizeof(arr[0]);
  int find = 1;
  printf("Position of %d is %d\n", find, search(arr, size, find));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    $0x4,%esi
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <search@plt>
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: byte[16]
name: unpack_data
arguments: data_label: D3
type_infered: string

tool: {"D5": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D3: Position of %d is %d


assistant: ```c
int main() {
  int arr[] = {2, 3, 1, 5};
  int size = sizeof(arr) / sizeof(arr[0]);
  int find = 1;
  printf("Position of %d is %d\n", find, search(arr, size, find));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = localtime_r(&time, &timestruct);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = localtime_r(&time, &timestruct);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = localtime_r(&time, &timestruct);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <localtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = localtime_r(&time, &timestruct);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: syntax: 
direwrite source dest.
source is the path to the source directory while dest is the path to the destination directory.


assistant: ```c
void print_usage() {
  printf("syntax: \ndirewrite source dest.\nsource is the path to the source directory while dest is the path to the destination directory.\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: syntax: 
direwrite source dest.
source is the path to the source directory while dest is the path to the destination directory.


assistant: ```c
void print_usage() {
  printf("syntax: \ndirewrite source dest.\nsource is the path to the source directory while dest is the path to the destination directory.\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: syntax: 
direwrite source dest.
source is the path to the source directory while dest is the path to the destination directory.


assistant: ```c
void print_usage() {
  printf("syntax: \ndirewrite source dest.\nsource is the path to the source directory while dest is the path to the destination directory.\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: syntax: 
direwrite source dest.
source is the path to the source directory while dest is the path to the destination directory.


assistant: ```c
void print_usage() {
  printf("syntax: \ndirewrite source dest.\nsource is the path to the source directory while dest is the path to the destination directory.\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L11
L6:
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*str++) {
    len++;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x0,%eax
L3:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L3
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*str++) {
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L12
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*str++) {
    len++;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L9
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*str++) {
    len++;
  }
  return len;
}
```