ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L5
  cmp    $0x10000000,%edi
  ja     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x11c,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/binding.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/binding.c", 284));
  return word_ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shiftMul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  sarl   -0x18(%rbp)
  jmp    L8
L23:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <increment@plt>
  sarl   -0x18(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jne    L23
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int shiftMul(int x, int k) {
  int count = 0;
  k >>= 1;
  while (k) {
    increment(&count);
    k >>= 1;
  }
  return x << count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftMul>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  sar    %esi
  je     L15
  mov    %esi,%ebx
  lea    0x4(%rsp),%rbp
L25:
  mov    %rbp,%rdi
  call   <increment@plt>
  sar    %ebx
  jne    L25
L15:
  mov    0x4(%rsp),%ecx
  mov    %r12d,%eax
  shl    %cl,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shiftMul(int x, int k) {
  int count = 0;
  k >>= 1;
  while (k) {
    increment(&count);
    k >>= 1;
  }
  return x << count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shiftMul>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    %esi
  movl   $0x0,0x4(%rsp)
  je     L15
  mov    %esi,%ebx
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <increment@plt>
  sar    %ebx
  jne    L9
  mov    0x4(%rsp),%ecx
  mov    %r12d,%eax
  shl    %cl,%eax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %edi,%eax
  jmp    L38
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shiftMul(int x, int k) {
  int count = 0;
  k >>= 1;
  while (k) {
    increment(&count);
    k >>= 1;
  }
  return x << count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shiftMul>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    %esi
  movl   $0x0,0x4(%rsp)
  je     L22
  mov    %esi,%ebx
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rbp,%rdi
  call   <increment@plt>
  sar    %ebx
  jne    L30
  mov    0x4(%rsp),%ecx
  mov    %r12d,%eax
  shl    %cl,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %edi,%eax
  jmp    L13
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int shiftMul(int x, int k) {
  int count = 0;
  k >>= 1;
  while (k) {
    increment(&count);
    k >>= 1;
  }
  return x << count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mode_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jg     L21
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <logprintf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L21:
  cmpl   $0x3,-0xc(%rbp)
  jle    L33
  mov    -0x18(%rbp),%rax
  mov    0x18(%rax),%rdx
  jmp    L13
L33:
  mov    $0x0,%edx
L13:
  cmpl   $0x2,-0xc(%rbp)
  jle    L16
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  jmp    L3
L16:
  mov    $0x0,%eax
L3:
  mov    -0x18(%rbp),%rcx
  add    $0x8,%rcx
  mov    (%rcx),%rsi
  mov    -0x8(%rbp),%rdi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <sqlite_add_msa@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: Missing arguments


assistant: ```c
int mode_add(sqlite3 *db, int argc, char **argv) {
  if (argc < 2) {
    logprintf(0, "Missing arguments\n");
    return -1;
  }
  return sqlite_add_msa(db, argv[1], (argc > 2) ? argv[2] : NULL, (argc > 3) ? argv[3] : NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mode_add>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L40
  cmp    $0x3,%esi
  jle    L59
  mov    0x18(%rdx),%rcx
L37:
  mov    0x10(%rdx),%rax
  jmp    L36
L40:
  lea    D6(%rip),%rsi
  mov    $0x0,%edi
  call   <logprintf@plt>
  mov    $0xffffffff,%eax
  jmp    L30
L59:
  je     L42
  mov    $0x0,%ecx
  mov    $0x0,%eax
L36:
  mov    0x8(%rdx),%rsi
  mov    %rax,%rdx
  call   <sqlite_add_msa@plt>
L30:
  add    $0x8,%rsp
  ret
L42:
  mov    $0x0,%ecx
  jmp    L37
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: Missing arguments


assistant: ```c
int mode_add(sqlite3 *db, int argc, char **argv) {
  if (argc < 2) {
    logprintf(0, "Missing arguments\n");
    return -1;
  }
  return sqlite_add_msa(db, argv[1], (argc > 2) ? argv[2] : NULL, (argc > 3) ? argv[3] : NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mode_add>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  cmp    $0x3,%esi
  jle    L15
  mov    0x18(%rdx),%rcx
L11:
  mov    0x10(%rdx),%r8
  mov    0x8(%rdx),%rsi
  mov    %r8,%rdx
  jmp    1070 <sqlite_add_msa@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  cmp    $0x2,%esi
  jne    L11
  mov    0x8(%rdx),%rsi
  mov    %r8,%rdx
  jmp    1070 <sqlite_add_msa@plt>
L25:
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  xor    %edi,%edi
  call   <logprintf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: Missing arguments


assistant: ```c
int mode_add(sqlite3 *db, int argc, char **argv) {
  if (argc < 2) {
    logprintf(0, "Missing arguments\n");
    return -1;
  }
  return sqlite_add_msa(db, argv[1], (argc > 2) ? argv[2] : NULL, (argc > 3) ? argv[3] : NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mode_add>:
  endbr64
  cmp    $0x1,%esi
  jle    L26
  cmp    $0x3,%esi
  jle    L27
  mov    0x18(%rdx),%rcx
L12:
  mov    0x10(%rdx),%r8
  mov    0x8(%rdx),%rsi
  mov    %r8,%rdx
  jmp    1070 <sqlite_add_msa@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  cmp    $0x2,%esi
  jne    L12
  mov    0x8(%rdx),%rsi
  mov    %r8,%rdx
  jmp    1070 <sqlite_add_msa@plt>
L26:
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  xor    %edi,%edi
  call   <logprintf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: Missing arguments


assistant: ```c
int mode_add(sqlite3 *db, int argc, char **argv) {
  if (argc < 2) {
    logprintf(0, "Missing arguments\n");
    return -1;
  }
  return sqlite_add_msa(db, argv[1], (argc > 2) ? argv[2] : NULL, (argc > 3) ? argv[3] : NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <warning_prefix@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((noreturn, format(printf, 1, 2))) void error(const char *formatstr, ...) {
  va_list ap;
  va_start(ap, formatstr);
  warning_prefix();
  vfprintf(stderr, formatstr, ap);
  va_end(ap);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x0,%eax
  call   <warning_prefix@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
__attribute__((noreturn, format(printf, 1, 2))) void error(const char *formatstr, ...) {
  va_list ap;
  va_start(ap, formatstr);
  warning_prefix();
  vfprintf(stderr, formatstr, ap);
  va_end(ap);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  xor    %eax,%eax
  call   <warning_prefix@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
__attribute__((noreturn, format(printf, 1, 2))) void error(const char *formatstr, ...) {
  va_list ap;
  va_start(ap, formatstr);
  warning_prefix();
  vfprintf(stderr, formatstr, ap);
  va_end(ap);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  xor    %eax,%eax
  call   <warning_prefix@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
__attribute__((noreturn, format(printf, 1, 2))) void error(const char *formatstr, ...) {
  va_list ap;
  va_start(ap, formatstr);
  warning_prefix();
  vfprintf(stderr, formatstr, ap);
  va_end(ap);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <RightShiftMain@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  RightShiftMain();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <RightShiftMain@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  RightShiftMain();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <RightShiftMain@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  RightShiftMain();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <RightShiftMain@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  RightShiftMain();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlib_e_mail_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x2,-0x10(%rbp)
  jbe    L43
  cmpq   $0x27,-0x10(%rbp)
  jbe    L12
L43:
  mov    $0x0,%eax
  jmp    L11
L12:
  mov    -0x28(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jne    L133
L17:
  mov    $0x0,%eax
  jmp    L11
L133:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L94
  mov    $0x0,%eax
  jmp    L11
L94:
  mov    -0x28(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L176
  mov    -0x8(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L134
L176:
  mov    $0x0,%eax
  jmp    L11
L134:
  movb   $0x1,-0x11(%rbp)
  jmp    L67
L128:
  movsbl -0x11(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L22
  mov    $0x0,%eax
  jmp    L11
L22:
  movzbl -0x11(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x11(%rbp)
L67:
  cmpb   $0x1f,-0x11(%rbp)
  jle    L128
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L165
  mov    -0x8(%rbp),%rax
  mov    $0x3b,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
L165:
  mov    $0x0,%eax
  jmp    L11
L74:
  mov    $0x1,%eax
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D3: @.

tool: D12: ..

assistant: ```c
int strlib_e_mail_check(char *email) {
  char ch;
  char *last_arobas;
  size_t len = strlen(email);
  if (len < 3 || len > 39)
    return 0;
  if (strchr(email, '@') == (void *)0 || email[len - 1] == '@')
    return 0;
  if (email[len - 1] == '.')
    return 0;
  last_arobas = strrchr(email, '@');
  if (strstr(last_arobas, "@.") != (void *)0 || strstr(last_arobas, "..") != (void *)0)
    return 0;
  for (ch = 1; ch < 32; ch++)
    if (strchr(last_arobas, ch) != (void *)0)
      return 0;
  if (strchr(last_arobas, ' ') != (void *)0 || strchr(last_arobas, ';') != (void *)0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlib_e_mail_check>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    -0x3(%rax),%rdx
  mov    $0x0,%eax
  cmp    $0x24,%rdx
  jbe    L47
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L113
  movzbl -0x1(%rbx,%rbp,1),%eax
  cmp    $0x2e,%al
  je     L110
  cmp    $0x40,%al
  je     L110
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbp
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
  mov    $0x1,%ebx
L126:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L114
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  jne    L126
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
  mov    $0x3b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L19
L113:
  mov    $0x0,%eax
  jmp    L19
L110:
  mov    $0x0,%eax
  jmp    L19
L114:
  mov    $0x0,%eax
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D16
type: string

tool: D18: @.

tool: D16: ..

assistant: ```c
int strlib_e_mail_check(char *email) {
  char ch;
  char *last_arobas;
  size_t len = strlen(email);
  if (len < 3 || len > 39)
    return 0;
  if (strchr(email, '@') == (void *)0 || email[len - 1] == '@')
    return 0;
  if (email[len - 1] == '.')
    return 0;
  last_arobas = strrchr(email, '@');
  if (strstr(last_arobas, "@.") != (void *)0 || strstr(last_arobas, "..") != (void *)0)
    return 0;
  for (ch = 1; ch < 32; ch++)
    if (strchr(last_arobas, ch) != (void *)0)
      return 0;
  if (strchr(last_arobas, ' ') != (void *)0 || strchr(last_arobas, ';') != (void *)0)
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlib_e_mail_check>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  sub    $0x3,%rax
  cmp    $0x24,%rax
  jbe    L39
L55:
  xor    %eax,%eax
L97:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L55
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  je     L55
  cmp    $0x40,%al
  je     L55
  mov    %rbp,%rdi
  mov    $0x40,%esi
  call   <strrchr@plt>
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  jne    L55
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L55
  mov    $0x1,%ebx
  jmp    L110
  xchg   %ax,%ax
L103:
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  je     L83
L110:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L103
  jmp    L55
  nopl   0x0(%rax)
L83:
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L55
  mov    $0x3b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L97
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D11
type_guessed: string

tool: D4: @.

tool: D11: ..

assistant: ```c
int strlib_e_mail_check(char *email) {
  char ch;
  char *last_arobas;
  size_t len = strlen(email);
  if (len < 3 || len > 39)
    return 0;
  if (strchr(email, '@') == (void *)0 || email[len - 1] == '@')
    return 0;
  if (email[len - 1] == '.')
    return 0;
  last_arobas = strrchr(email, '@');
  if (strstr(last_arobas, "@.") != (void *)0 || strstr(last_arobas, "..") != (void *)0)
    return 0;
  for (ch = 1; ch < 32; ch++)
    if (strchr(last_arobas, ch) != (void *)0)
      return 0;
  if (strchr(last_arobas, ' ') != (void *)0 || strchr(last_arobas, ';') != (void *)0)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlib_e_mail_check>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  sub    $0x3,%rax
  cmp    $0x24,%rax
  jbe    L24
L53:
  xor    %eax,%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L53
  movzbl -0x1(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  je     L53
  cmp    $0x40,%al
  je     L53
  mov    %rbp,%rdi
  mov    $0x40,%esi
  call   <strrchr@plt>
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  jne    L53
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x1,%ebx
  jmp    L112
  xchg   %ax,%ax
L106:
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  je     L21
L112:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L106
  jmp    L53
  nopl   0x0(%rax)
L21:
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x3b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L46
```

tool_calls: name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D19
type: string

tool: D7: @.

tool: D19: ..

assistant: ```c
int strlib_e_mail_check(char *email) {
  char ch;
  char *last_arobas;
  size_t len = strlen(email);
  if (len < 3 || len > 39)
    return 0;
  if (strchr(email, '@') == (void *)0 || email[len - 1] == '@')
    return 0;
  if (email[len - 1] == '.')
    return 0;
  last_arobas = strrchr(email, '@');
  if (strstr(last_arobas, "@.") != (void *)0 || strstr(last_arobas, "..") != (void *)0)
    return 0;
  for (ch = 1; ch < 32; ch++)
    if (strchr(last_arobas, ch) != (void *)0)
      return 0;
  if (strchr(last_arobas, ' ') != (void *)0 || strchr(last_arobas, ';') != (void *)0)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L27:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L4
  lea    D5(%rip),%rax
  jmp    L32
L4:
  lea    D30(%rip),%rax
L32:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D5: , 

tool: 

tool: D2: %#018llx%s

tool: D10: ]

assistant: ```c
void show(unsigned long long int *a, int cnt) {
  printf("[");
  int i;
  for (i = 0; i < cnt; i++)
    printf("%#018llx%s", a[i], i < cnt - 1 ? ", " : "");
  printf("]\n");
}
```