user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  push   %r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%r12
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L134
  nopw   0x0(%rax,%rax,1)
L155:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L155
L134:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    D4(%rip),%r12
  xor    %edx,%edx
  test   %eax,%eax
  je     L91
  nopl   0x0(%rax)
L43:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rdx,%rax
  cmp    %rbx,%rdx
  ja     L43
  cmp    $0x1,%edx
  je     L5
L91:
  mov    %rbp,%rcx
  xor    %edi,%edi
  lea    -0x1(%rax),%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L90:
  mov    %r13,%r14
  add    $0x1,%r13
  lea    0x4(%rcx),%r15
  cmp    %rdx,%r13
  jae    L54
  mov    %r13,%rbx
  lea    0x4(%rcx),%r15
  jmp    L80
  nopl   0x0(%rax)
L86:
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  jbe    L54
L80:
  mov    0x10(%rsp,%rbx,4),%esi
  cmp    %esi,(%rcx)
  jne    L86
  cmp    %r14,%rdx
  jbe    L84
  sub    %r14,%rdx
  mov    %rcx,%rdi
  mov    %r15,%rsi
  shl    $0x2,%rdx
  call   <memmove@plt>
  mov    %rax,%rcx
L84:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    $0x1,%edi
  sub    $0x1,%r12d
  cmp    %rbx,%rdx
  ja     L80
  nopw   0x0(%rax,%rax,1)
L54:
  movslq %r12d,%rsi
  mov    %r15,%rcx
  cmp    %r13,%rsi
  ja     L90
  test   %dil,%dil
  je     L5
  mov    %eax,0xc(%rsp)
L5:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    D4(%rip),%r12
  test   %eax,%eax
  je     L55
  nopl   0x0(%rax,%rax,1)
L117:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movslq 0xc(%rsp),%rax
  cmp    %rbx,%rax
  ja     L117
L55:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L156
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L156:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
datatype: string
name: parse_data
arguments: tag: D27
datatype: string
name: parse_data
arguments: tag: D38
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D0
datatype: string

tool: D26: Enter a number of array: 

tool: D27: %d

tool: D38: Before: 

tool: D4: %d 

tool: D0: After: 

assistant: ```c
int main(void) {
  int arr[100], number, i;
  printf("Enter a number of array: ");
  scanf("%d", &number);
  for (i = 0; i < number; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Before: ");
  for (size_t i = 0; i < number; i++) {
    printf("%d ", arr[i]);
  }
  for (size_t i = 0; i < number - 1; i++) {
    for (size_t j = i + 1; j < number; j++) {
      if (arr[i] == arr[j]) {
        for (size_t k = i; k < number; k++) {
          arr[k] = arr[k + 1];
        }
        number--;
        j--;
      }
    }
  }
  printf("After: ");
  for (size_t i = 0; i < number; i++) {
    printf("%d ", arr[i]);
  }
  return 0;
}
```