user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D70(%rip),%rdi
  lea    D35(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D106(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xb(%rsp),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D114(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xb(%rsp),%eax
  cmp    $0x33,%al
  je     L93
  jg     L6
  cmp    $0x31,%al
  je     L97
  cmp    $0x32,%al
  jne    L94
  lea    D167(%rip),%rdi
  call   <puts@plt>
  lea    D159(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <modify_bit@plt>
  lea    D149(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x20,%rsp
  pop    %rbp
  ret
L6:
  cmp    $0x34,%al
  jne    L94
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <clear_bit@plt>
  jmp    L25
L93:
  lea    D161(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <isBitset@plt>
  lea    D130(%rip),%rdi
  test   %eax,%eax
  lea    D3(%rip),%rax
  cmove  %rax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L25
L94:
  lea    D104(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L25
L97:
  lea    D102(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <set_bit@plt>
  lea    D160(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L25
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D70
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D106
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D114
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D167
type_guessed: string
name: retrieve_data
arguments: data_tag: D159
type_guessed: string
name: retrieve_data
arguments: data_tag: D149
type_guessed: string
name: retrieve_data
arguments: data_tag: D161
type_guessed: string
name: retrieve_data
arguments: data_tag: D46
type_guessed: string
name: retrieve_data
arguments: data_tag: D130
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D104
type_guessed: string
name: retrieve_data
arguments: data_tag: D102
type_guessed: string
name: retrieve_data
arguments: data_tag: D160
type_guessed: string

tool: D70: Enter the Number : 

tool: D35: %d

tool: D106: 
Enter your choice :

tool: D13: 1.set bit
2.Modify a bit
3.Is bit set
4.Clear bit

tool: D12:  %c

tool: D114: 
Enter the position :

tool: D0:  %d

tool: D167: Inside 2

tool: D159: 
Enter the new state :

tool: D149: After Modification : %d


tool: D161: inside 3

tool: D46: number %x 


tool: D130: SET


tool: D3: NOT SET


tool: D104: Invalid

tool: D102: Inside 1

tool: D160: After Modification : %d 


assistant: ```c
int main() {
  int number, pos;
  char ops;
  int state;
  printf("Enter the Number : ");
  scanf("%d", &number);
  printf("\nEnter your choice :");
  printf("1.set bit\n2.Modify a bit\n3.Is bit set\n4.Clear bit");
  scanf(" %c", &ops);
  printf("\nEnter the position :");
  scanf(" %d", &pos);
  switch (ops) {
  case '1':
    printf("Inside 1\n");
    printf("After Modification : %d \n", set_bit(number, pos));
    break;
  case '2':
    printf("Inside 2\n");
    printf("\nEnter the new state :");
    scanf("%d", &state);
    printf("After Modification : %d\n", modify_bit(number, pos, state));
    break;
  case '3':
    printf("inside 3\n");
    printf("number %x \n", number);
    printf((isBitset(number, pos)) ? "SET\n" : "NOT SET\n");
    break;
  case '4':
    return clear_bit(number, pos);
    break;
  default:
    printf("Invalid\n");
  }
  return 0;
}
```