ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<erfasse_gleitkomma_zahl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
L32:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L7
  movss  -0xc(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L7
  movss  -0x18(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  movss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L24
  movss  -0xc(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  ja     L32
L24:
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D1: 
%f

tool: D3: 
Bitte eine Zahl zwischen %f und %f eingeben!


assistant: ```c
float erfasse_gleitkomma_zahl(float min, float max) {
  float eingabe = 0.0;
  do {
    scanf("\n%f", &eingabe);
    if (eingabe < min && eingabe > max) {
      printf("\nBitte eine Zahl zwischen %f und %f eingeben!\n", min, max);
    } else {
    }
  } while (eingabe < min && eingabe > max);
  return eingabe;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<erfasse_gleitkomma_zahl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%rbp
  lea    D1(%rip),%rbx
  lea    D6(%rip),%r12
  jmp    L25
L46:
  movss  0x14(%rsp),%xmm0
  movss  0x8(%rsp),%xmm4
  comiss %xmm0,%xmm4
  jbe    L5
L49:
  comiss 0xc(%rsp),%xmm0
  jbe    L5
L25:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x8(%rsp),%xmm2
  comiss %xmm0,%xmm2
  jbe    L46
  comiss 0xc(%rsp),%xmm0
  jbe    L49
  movss  0xc(%rsp),%xmm1
  movaps %xmm2,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L46
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string

tool: D1: 
%f

tool: D6: 
Bitte eine Zahl zwischen %f und %f eingeben!


assistant: ```c
float erfasse_gleitkomma_zahl(float min, float max) {
  float eingabe = 0.0;
  do {
    scanf("\n%f", &eingabe);
    if (eingabe < min && eingabe > max) {
      printf("\nBitte eine Zahl zwischen %f und %f eingeben!\n", min, max);
    } else {
    }
  } while (eingabe < min && eingabe > max);
  return eingabe;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<erfasse_gleitkomma_zahl>:
  endbr64
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x28,%rsp
  movss  %xmm1,0xc(%rsp)
  lea    0x14(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  nopl   0x0(%rax)
L51:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movd   %r14d,%xmm2
  comiss %xmm0,%xmm2
  ja     L28
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  xchg   %ax,%ax
L28:
  comiss 0xc(%rsp),%xmm0
  jbe    L46
  movss  0xc(%rsp),%xmm1
  movd   %r14d,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  movd   %r14d,%xmm5
  comiss %xmm0,%xmm5
  jbe    L46
  comiss 0xc(%rsp),%xmm0
  ja     L51
  jmp    L46
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D3
type: string

tool: D1: 
Bitte eine Zahl zwischen %f und %f eingeben!


tool: D3: 
%f

assistant: ```c
float erfasse_gleitkomma_zahl(float min, float max) {
  float eingabe = 0.0;
  do {
    scanf("\n%f", &eingabe);
    if (eingabe < min && eingabe > max) {
      printf("\nBitte eine Zahl zwischen %f und %f eingeben!\n", min, max);
    } else {
    }
  } while (eingabe < min && eingabe > max);
  return eingabe;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<erfasse_gleitkomma_zahl>:
  endbr64
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x28,%rsp
  movss  %xmm1,0xc(%rsp)
  lea    0x14(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  nopl   0x0(%rax)
L46:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movd   %r14d,%xmm2
  comiss %xmm0,%xmm2
  ja     L10
L54:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  xchg   %ax,%ax
L10:
  comiss 0xc(%rsp),%xmm0
  jbe    L54
  movss  0xc(%rsp),%xmm1
  movd   %r14d,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  movd   %r14d,%xmm5
  comiss %xmm0,%xmm5
  jbe    L54
  comiss 0xc(%rsp),%xmm0
  ja     L46
  jmp    L54
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D10: 
Bitte eine Zahl zwischen %f und %f eingeben!


tool: D4: 
%f

assistant: ```c
float erfasse_gleitkomma_zahl(float min, float max) {
  float eingabe = 0.0;
  do {
    scanf("\n%f", &eingabe);
    if (eingabe < min && eingabe > max) {
      printf("\nBitte eine Zahl zwischen %f und %f eingeben!\n", min, max);
    } else {
    }
  } while (eingabe < min && eingabe > max);
  return eingabe;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sgcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sgcd(int x, int y) {
  int cnt = 0;
  int t;
  while (1) {
    t = x;
    x = y;
    y = t % y;
    cnt++;
    if (y == 0)
      return cnt;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sgcd>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%ecx
L1:
  mov    %esi,%edi
  cltd
  idiv   %esi
  mov    %edx,%esi
  add    $0x1,%ecx
  mov    %edi,%eax
  test   %edx,%edx
  jne    L1
  mov    %ecx,%eax
  ret
```

assistant: ```c
int sgcd(int x, int y) {
  int cnt = 0;
  int t;
  while (1) {
    t = x;
    x = y;
    y = t % y;
    cnt++;
    if (y == 0)
      return cnt;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sgcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %edx,%ecx
  cltd
  add    $0x1,%r8d
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L0
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sgcd(int x, int y) {
  int cnt = 0;
  int t;
  while (1) {
    t = x;
    x = y;
    y = t % y;
    cnt++;
    if (y == 0)
      return cnt;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sgcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edx,%ecx
  cltd
  add    $0x1,%r8d
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sgcd(int x, int y) {
  int cnt = 0;
  int t;
  while (1) {
    t = x;
    x = y;
    y = t % y;
    cnt++;
    if (y == 0)
      return cnt;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add_bias_and_relu_flatten>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  cmpl   $0x1,-0x28(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L5:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_bias_and_relu_flatten(float *out, float *bs, int size, int relu) {
  int i;
  for (i = 0; i < size; i++) {
    out[i] += bs[i];
    if (relu == 1) {
      if (out[i] < 0)
        out[i] = 0.0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_bias_and_relu_flatten>:
  endbr64
  test   %edx,%edx
  jle    L20
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  jmp    L13
L11:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L20
L13:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  cmp    $0x1,%ecx
  jne    L11
  comiss %xmm0,%xmm1
  jbe    L11
  movl   $0x0,(%rdi,%rax,4)
  jmp    L11
L20:
  ret
```

assistant: ```c
void add_bias_and_relu_flatten(float *out, float *bs, int size, int relu) {
  int i;
  for (i = 0; i < size; i++) {
    out[i] += bs[i];
    if (relu == 1) {
      if (out[i] < 0)
        out[i] = 0.0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_bias_and_relu_flatten>:
  endbr64
  test   %edx,%edx
  jle    L16
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L16
L7:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  cmp    $0x1,%ecx
  jne    L21
  comiss %xmm0,%xmm1
  jbe    L21
  movl   $0x0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L7
L16:
  ret
```

assistant: ```c
void add_bias_and_relu_flatten(float *out, float *bs, int size, int relu) {
  int i;
  for (i = 0; i < size; i++) {
    out[i] += bs[i];
    if (relu == 1) {
      if (out[i] < 0)
        out[i] = 0.0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vsnprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jae    L1
  mov    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int vsnprintf(char *str, size_t size, const char *format, va_list ap) {
  char *temp = (char *)malloc(16384);
  int ret;
  vsprintf(temp, format, ap);
  ret = strlen(temp);
  if (ret > size)
    ret = size - 1;
  memcpy(str, temp, ret);
  free(temp);
  str[ret] = 0;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vsnprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  movslq %eax,%rdx
  lea    -0x1(%r13),%eax
  cmp    %r13,%rdx
  cmova  %eax,%ebx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vsnprintf(char *str, size_t size, const char *format, va_list ap) {
  char *temp = (char *)malloc(16384);
  int ret;
  vsprintf(temp, format, ap);
  ret = strlen(temp);
  if (ret > size)
    ret = size - 1;
  memcpy(str, temp, ret);
  free(temp);
  str[ret] = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<vsnprintf>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%r14
  mov    %r14,%r12
  cmp    %r13,%r14
  jbe    L2
  lea    -0x1(%r13),%r12d
  movslq %r12d,%r14
L2:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x0,(%rbx,%r14,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vsnprintf(char *str, size_t size, const char *format, va_list ap) {
  char *temp = (char *)malloc(16384);
  int ret;
  vsprintf(temp, format, ap);
  ret = strlen(temp);
  if (ret > size)
    ret = size - 1;
  memcpy(str, temp, ret);
  free(temp);
  str[ret] = 0;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vsnprintf>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%r14
  mov    %r14,%r12
  cmp    %r13,%r14
  jbe    L5
  lea    -0x1(%r13),%r12d
  movslq %r12d,%r14
L5:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x0,(%rbx,%r14,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vsnprintf(char *str, size_t size, const char *format, va_list ap) {
  char *temp = (char *)malloc(16384);
  int ret;
  vsprintf(temp, format, ap);
  ret = strlen(temp);
  if (ret > size)
    ret = size - 1;
  memcpy(str, temp, ret);
  free(temp);
  str[ret] = 0;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_rot42>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L56:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x60,-0x9(%rbp)
  jle    L48
  cmpb   $0x7a,-0x9(%rbp)
  jg     L48
  movl   $0x7a,-0x8(%rbp)
  jmp    L26
L48:
  cmpb   $0x40,-0x9(%rbp)
  jle    L26
  cmpb   $0x5a,-0x9(%rbp)
  jg     L26
  movl   $0x5a,-0x8(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x29,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L10
  mov    -0x8(%rbp),%eax
  sub    $0x19,%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  movzbl -0x9(%rbp),%eax
  mov    -0x8(%rbp),%edx
  sub    %edx,%eax
  add    %ecx,%eax
  lea    0x2a(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L5
L10:
  movb   $0x2a,-0x9(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_rot42(char *str) {
  int new_val;
  int limit;
  char c;
  int i;
  i = 0;
  while (str[i]) {
    c = str[i];
    if (c >= 'a' && c <= 'z')
      limit = 'z';
    else if (c >= 'A' && c <= 'Z')
      limit = 'Z';
    if (str[i] + 42 > limit) {
      c = (limit - 25);
      str[i] += 42 - (limit - c);
    } else
      c = 42;
    str[i] += c;
    i++;
  }
  return (str);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_rot42>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L54
  mov    %rdi,%rcx
  mov    $0x2a,%r10d
  mov    $0x7a,%edi
  mov    $0x5a,%r11d
  jmp    L51
L2:
  mov    %edi,%r9d
L12:
  movsbl %dl,%edx
  add    $0x29,%edx
  mov    %r10d,%r8d
  cmp    %r9d,%edx
  jl     L45
L22:
  lea    -0x19(%r9),%r8d
  add    $0x11,%esi
  mov    %sil,(%rcx)
L45:
  add    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L54
L51:
  mov    %edx,%esi
  lea    -0x61(%rdx),%r8d
  cmp    $0x19,%r8b
  jbe    L2
  lea    -0x41(%rdx),%r8d
  cmp    $0x19,%r8b
  ja     L12
  mov    %r11d,%r9d
  jmp    L22
L54:
  ret
```

assistant: ```c
char *ft_rot42(char *str) {
  int new_val;
  int limit;
  char c;
  int i;
  i = 0;
  while (str[i]) {
    c = str[i];
    if (c >= 'a' && c <= 'z')
      limit = 'z';
    else if (c >= 'A' && c <= 'Z')
      limit = 'Z';
    if (str[i] + 42 > limit) {
      c = (limit - 25);
      str[i] += 42 - (limit - c);
    } else
      c = 42;
    str[i] += c;
    i++;
  }
  return (str);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_rot42>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %dl,%dl
  jne    L56
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L51:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L36
  mov    $0x5a,%r8d
L49:
  lea    -0x19(%r8),%esi
  add    $0x11,%edx
  add    $0x1,%rcx
  add    %esi,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L30
L56:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L51
  mov    $0x7a,%r8d
L36:
  movsbl %dl,%esi
  add    $0x29,%esi
  cmp    %r8d,%esi
  jge    L49
  movzbl (%rcx),%edx
  mov    $0x2a,%esi
  add    $0x1,%rcx
  add    %esi,%edx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L56
L30:
  ret
```

assistant: ```c
char *ft_rot42(char *str) {
  int new_val;
  int limit;
  char c;
  int i;
  i = 0;
  while (str[i]) {
    c = str[i];
    if (c >= 'a' && c <= 'z')
      limit = 'z';
    else if (c >= 'A' && c <= 'Z')
      limit = 'Z';
    if (str[i] + 42 > limit) {
      c = (limit - 25);
      str[i] += 42 - (limit - c);
    } else
      c = 42;
    str[i] += c;
    i++;
  }
  return (str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_rot42>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %dl,%dl
  je     L14
  nopl   0x0(%rax)
L32:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  jbe    L22
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L54
  mov    $0x5a,%r8d
L16:
  lea    -0x8(%rdx,%r8,1),%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L32
L14:
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x7a,%r8d
L54:
  movsbl %dl,%esi
  add    $0x29,%esi
  cmp    %esi,%r8d
  jle    L16
  addb   $0x2a,(%rcx)
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L32
  ret
```

assistant: ```c
char *ft_rot42(char *str) {
  int new_val;
  int limit;
  char c;
  int i;
  i = 0;
  while (str[i]) {
    c = str[i];
    if (c >= 'a' && c <= 'z')
      limit = 'z';
    else if (c >= 'A' && c <= 'Z')
      limit = 'Z';
    if (str[i] + 42 > limit) {
      c = (limit - 25);
      str[i] += 42 - (limit - c);
    } else
      c = 42;
    str[i] += c;
    i++;
  }
  return (str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dgetln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L91
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
L91:
  cmpl   $0x1,-0x28(%rbp)
  jg     L162
  cmpq   $0x0,-0x38(%rbp)
  je     L11
  mov    -0x38(%rbp),%rax
  movb   $0x0,(%rax)
L11:
  mov    $0x0,%eax
  jmp    L79
L162:
  subl   $0x1,-0x28(%rbp)
L14:
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L52
  cmpl   $0x0,-0xc(%rbp)
  jns    L55
  mov    D17(%rip),%rax
  mov    (%rax),%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L71
L55:
  cmpq   $0x0,-0x30(%rbp)
  je     L109
  mov    -0x30(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L109
L52:
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  je     L126
  movzbl -0x11(%rbp),%eax
  test   %al,%al
  je     L98
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L14
  cmpq   $0x0,-0x38(%rbp)
  je     L107
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
L107:
  addl   $0x1,-0x10(%rbp)
  jmp    L14
L71:
  nop
  jmp    L14
L109:
  nop
  jmp    L150
L126:
  nop
  jmp    L150
L98:
  nop
L150:
  cmpq   $0x0,-0x38(%rbp)
  je     L156
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L156:
  mov    -0x10(%rbp),%eax
L79:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int dgetln(int fd, int *opt_eof, int maxlen, char *opt_buf) {
  int got, count = 0;
  char buf;
  if (opt_eof)
    *opt_eof = 0;
  if (maxlen < 2) {
    if (opt_buf)
      *opt_buf = 0;
    return 0;
  }
  maxlen--;
  while (1) {
    got = read(fd, &buf, 1);
    if (got <= 0) {
      if ((got < 0) && (errno == EINTR))
        continue;
      if (opt_eof)
        *opt_eof = 1;
      break;
    }
    if (buf == '\n')
      break;
    if (buf == 0)
      break;
    if (count < maxlen) {
      if (opt_buf)
        *(opt_buf + count) = buf;
      count++;
    }
  }
  if (opt_buf)
    *(opt_buf + count) = 0;
  return count;
}
```