ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<dump_trans_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r14d,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L3
  lea    -0x1(%r14),%r15d
  xor    %r12d,%r12d
  lea    D11(%rip),%rbp
  add    $0x1,%r15
  shl    $0x4,%r15
  nopl   (%rax)
L4:
  lea    0x0(%r13,%r15,1),%rbx
  test   %r14d,%r14d
  jle    L7
  nopw   0x0(%rax,%rax,1)
L18:
  push   0x8(%r13)
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x10,%r13
  push   -0x10(%r13)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %rbx,%r13
  jne    L18
L7:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L4
L3:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D25
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D22
type_guessed: string
name: unpack_data
arguments: label: D11
type_guessed: string

tool: D25: transition matrix dump:

tool: D2: nr rows: %d


tool: D22: nr columns: %d


tool: D11: %Lf  

assistant: ```c
void dump_trans_matrix(int nr_rows, int nr_cols, long double *mtx) {
  int i, j;
  printf("transition matrix dump:\n");
  printf("nr rows: %d\n", nr_rows);
  printf("nr columns: %d\n", nr_cols);
  for (i = 0; i < nr_rows; i++) {
    for (j = 0; j < nr_cols; j++) {
      printf("%Lf  ", *mtx);
      mtx++;
    }
    printf("\n");
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dump_trans_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r14d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L11
  lea    -0x1(%r14),%r15d
  xor    %r12d,%r12d
  lea    D21(%rip),%rbp
  add    $0x1,%r15
  shl    $0x4,%r15
  nopl   (%rax)
L23:
  lea    0x0(%r13,%r15,1),%rbx
  test   %r14d,%r14d
  jle    L17
  nopw   0x0(%rax,%rax,1)
L8:
  push   0x8(%r13)
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x10,%r13
  push   -0x10(%r13)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    %rbx,%r13
  jne    L8
L17:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,0xc(%rsp)
  jne    L23
L11:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string

tool: D17: transition matrix dump:

tool: D1: nr rows: %d


tool: D7: nr columns: %d


tool: D21: %Lf  

assistant: ```c
void dump_trans_matrix(int nr_rows, int nr_cols, long double *mtx) {
  int i, j;
  printf("transition matrix dump:\n");
  printf("nr rows: %d\n", nr_rows);
  printf("nr columns: %d\n", nr_cols);
  for (i = 0; i < nr_rows; i++) {
    for (j = 0; j < nr_cols; j++) {
      printf("%Lf  ", *mtx);
      mtx++;
    }
    printf("\n");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<PointNormal>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm1
  movsd  D91(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L9
  movsd  D42(%rip),%xmm1
  movq   %rbx,%xmm4
  subsd  %xmm4,%xmm1
L9:
  movsd  D85(%rip),%xmm0
  movsd  D34(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L34
L10:
  pop    %rbx
  ret
L34:
  mulsd  %xmm1,%xmm1
  movsd  D42(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  mulsd  D38(%rip),%xmm0
  subsd  D71(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D72(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D42(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D26(%rip),%xmm0
  movapd %xmm2,%xmm1
  mulsd  D53(%rip),%xmm1
  addsd  D143(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D37(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D70(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D105(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  D91(%rip),%xmm1
  movq   %rbx,%xmm5
  comisd %xmm5,%xmm1
  jbe    L10
  xorpd  D14(%rip),%xmm0
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: tag: D91
datatype: f64
name: retrieve_data
arguments: tag: D42
datatype: f64
name: retrieve_data
arguments: tag: D85
datatype: f32[2]
name: retrieve_data
arguments: tag: D34
datatype: byte[8]
name: retrieve_data
arguments: tag: D38
datatype: byte[8]
name: retrieve_data
arguments: tag: D71
datatype: byte[8]
name: retrieve_data
arguments: tag: D72
datatype: byte[8]
name: retrieve_data
arguments: tag: D26
datatype: byte[8]
name: retrieve_data
arguments: tag: D53
datatype: byte[8]
name: retrieve_data
arguments: tag: D143
datatype: byte[8]
name: retrieve_data
arguments: tag: D37
datatype: byte[8]
name: retrieve_data
arguments: tag: D70
datatype: byte[8]
name: retrieve_data
arguments: tag: D105
datatype: byte[8]
name: retrieve_data
arguments: tag: D14
datatype: f32[4]

tool: D91: 0.5

tool: D42: 1

tool: {"D85": [0.0,-6.11029052734375]}

tool: {"D34": [0x23,0x42,0x92,0x0c,0xa1,0x9c,0xc7,0x3b]}

tool: {"D38": [0x62,0x1a,0xed,0xc3,0xae,0xc8,0x07,0xbf]}

tool: {"D71": [0x30,0xa8,0x87,0x73,0xcc,0xe9,0x94,0x3f]}

tool: {"D72": [0x46,0xf1,0x67,0x5c,0x4b,0xe7,0xd5,0x3f]}

tool: {"D26": [0x37,0xf2,0x4e,0xc6,0x74,0x9f,0xd4,0x3f]}

tool: {"D53": [0x88,0x45,0x07,0xda,0xc3,0x96,0x6f,0x3f]}

tool: {"D143": [0x68,0x5f,0x64,0x3e,0x73,0x81,0xba,0x3f]}

tool: {"D37": [0x54,0xf0,0x34,0xb0,0xcc,0xfe,0xe0,0x3f]}

tool: {"D70": [0x2f,0xbd,0x89,0x04,0xa9,0xd5,0xe2,0x3f]}

tool: {"D105": [0x54,0xf7,0xcc,0x9d,0xe6,0x6e,0xb9,0x3f]}

tool: {"D14": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double PointNormal(double prob) {
  double a0 = -.322232431088, a1 = -1, a2 = -.342242088547, a3 = -.0204231210245;
  double a4 = -.453642210148e-4, b0 = .0993484626060, b1 = .588581570495;
  double b2 = .531103462366, b3 = .103537752850, b4 = .0038560700634;
  double y, z = 0, p = prob, p1;
  p1 = (p < 0.5 ? p : 1 - p);
  if (p1 < 1e-20)
    return (-9999);
  y = sqrt(log(1 / (p1 * p1)));
  z = y + ((((y * a4 + a3) * y + a2) * y + a1) * y + a0) / ((((y * b4 + b3) * y + b2) * y + b1) * y + b0);
  return (p < 0.5 ? -z : z);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D1: %d

tool: D11: 
%d

assistant: ```c
int main() {
  int a, b, c;
  scanf("%d", &a);
  b = a * a;
  c = a * a * a;
  printf("\n%d", b);
  printf("\n%d", c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %esi,%eax
  mov    %eax,%ebx
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D3
data_type: string

tool: D8: %d

tool: D3: 
%d

assistant: ```c
int main() {
  int a, b, c;
  scanf("%d", &a);
  b = a * a;
  c = a * a * a;
  printf("\n%d", b);
  printf("\n%d", c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  lea    D1(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %esi,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D1
data_type: string

tool: D2: %d

tool: D1: 
%d

assistant: ```c
int main() {
  int a, b, c;
  scanf("%d", &a);
  b = a * a;
  c = a * a * a;
  printf("\n%d", b);
  printf("\n%d", c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  lea    D18(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  imul   %eax,%esi
  imul   %esi,%eax
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string

tool: D15: %d

tool: D18: 
%d

assistant: ```c
int main() {
  int a, b, c;
  scanf("%d", &a);
  b = a * a;
  c = a * a * a;
  printf("\n%d", b);
  printf("\n%d", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TimerLoadGet64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    $0x20,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%rax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t TimerLoadGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
    ui32Low = (*((volatile unsigned long *)(ui32Base + 0x00000028)));
    ui32High2 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TimerLoadGet64>:
  endbr64
L1:
  mov    0x2c(%rdi),%rcx
  mov    0x28(%rdi),%rax
  mov    0x2c(%rdi),%rdx
  cmp    %rdx,%rcx
  jne    L1
  ret
```

assistant: ```c
uint64_t TimerLoadGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
    ui32Low = (*((volatile unsigned long *)(ui32Base + 0x00000028)));
    ui32High2 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: Translate the below assembly code into C programming language:

```asm
<TimerLoadGet64>:
  endbr64
  lea    0x2c(%rdi),%rdx
  add    $0x28,%rdi
  nopl   0x0(%rax)
L5:
  mov    (%rdx),%rsi
  mov    (%rdi),%rax
  mov    (%rdx),%rcx
  cmp    %rcx,%rsi
  jne    L5
  ret
```

assistant: ```c
uint64_t TimerLoadGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
    ui32Low = (*((volatile unsigned long *)(ui32Base + 0x00000028)));
    ui32High2 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TimerLoadGet64>:
  endbr64
  lea    0x2c(%rdi),%rdx
  add    $0x28,%rdi
  nopl   0x0(%rax)
L6:
  mov    (%rdx),%rsi
  mov    (%rdi),%rax
  mov    (%rdx),%rcx
  cmp    %rcx,%rsi
  jne    L6
  ret
```

assistant: ```c
uint64_t TimerLoadGet64(uint32_t ui32Base) {
  uint32_t ui32High1, ui32High2, ui32Low;
  ;
  do {
    ui32High1 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
    ui32Low = (*((volatile unsigned long *)(ui32Base + 0x00000028)));
    ui32High2 = (*((volatile unsigned long *)(ui32Base + 0x0000002C)));
  } while (ui32High1 != ui32High2);
  return (((uint64_t)ui32High1 << 32) | (uint64_t)ui32Low);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<catweasel_usleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <usleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
unsigned int catweasel_usleep(unsigned int _useconds) {
  (void)usleep(_useconds);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<catweasel_usleep>:
  endbr64
  sub    $0x8,%rsp
  call   <usleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int catweasel_usleep(unsigned int _useconds) {
  (void)usleep(_useconds);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<catweasel_usleep>:
  endbr64
  sub    $0x8,%rsp
  call   <usleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int catweasel_usleep(unsigned int _useconds) {
  (void)usleep(_useconds);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<catweasel_usleep>:
  endbr64
  sub    $0x8,%rsp
  call   <usleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int catweasel_usleep(unsigned int _useconds) {
  (void)usleep(_useconds);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checked_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %s:%u: %s: OUT OF MEMORY malloc(%u)


assistant: ```c
void *checked_malloc(size_t size, char *filename, unsigned int line, const char *func) {
  void *p = malloc(size);
  if (!p)
    die("%s:%u: %s: OUT OF MEMORY malloc(%u)\n", filename, line, func, (unsigned)size);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<checked_malloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%r14
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %ebp,%r8d
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <die@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %s:%u: %s: OUT OF MEMORY malloc(%u)


assistant: ```c
void *checked_malloc(size_t size, char *filename, unsigned int line, const char *func) {
  void *p = malloc(size);
  if (!p)
    die("%s:%u: %s: OUT OF MEMORY malloc(%u)\n", filename, line, func, (unsigned)size);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<checked_malloc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L15:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <die@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s:%u: %s: OUT OF MEMORY malloc(%u)


assistant: ```c
void *checked_malloc(size_t size, char *filename, unsigned int line, const char *func) {
  void *p = malloc(size);
  if (!p)
    die("%s:%u: %s: OUT OF MEMORY malloc(%u)\n", filename, line, func, (unsigned)size);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checked_malloc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L13:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <die@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: %s:%u: %s: OUT OF MEMORY malloc(%u)


assistant: ```c
void *checked_malloc(size_t size, char *filename, unsigned int line, const char *func) {
  void *p = malloc(size);
  if (!p)
    die("%s:%u: %s: OUT OF MEMORY malloc(%u)\n", filename, line, func, (unsigned)size);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ieee_p_1242562249_sub_1006216973935617061_1035706684>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8d,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0xc(%rcx),%ecx
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  call   <ieee_p_1242562249_sub_10420449594411817395_1035706684@plt>
  mov    %rax,%r8
  mov    %rsp,%rsi
  mov    %r14,%r9
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <ieee_p_1242562249_sub_2177518728674633585_1035706684@plt>
  mov    %rax,%r12
  mov    0xc(%rsp),%r13d
  mov    %r13d,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%edx
  mov    %ecx,(%rbx)
  mov    %eax,0x4(%rbx)
  mov    %edx,0x8(%rbx)
  sub    %ecx,%eax
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbp,%rax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ieee_p_1242562249_sub_1006216973935617061_1035706684(char *t1, char *t2, char *t3, char *t4, int t5) {
  char t7[24];
  char t12[16];
  char t13[16];
  char *t0;
  char *t8;
  unsigned char t9;
  char *t10;
  char *t11;
  char *t14;
  unsigned int t15;
  char *t16;
  char *t17;
  char *t18;
  unsigned int t19;
  unsigned int t20;
  char *t21;
  int t22;
  char *t23;
  int t24;
  char *t25;
  int t26;
  char *t27;
  char *t28;
  int t29;
  unsigned int t30;
LAB0:
  t8 = (t7 + 4U);
  t9 = (t3 != 0);
  if (t9 == 1)
    goto LAB3;
LAB2:
  t10 = (t7 + 12U);
  *((char **)t10) = t4;
  t11 = (t7 + 20U);
  *((int *)t11) = t5;
  t14 = (t4 + 12U);
  t15 = *((unsigned int *)t14);
  t16 = ieee_p_1242562249_sub_10420449594411817395_1035706684(t1, t13, t5, ((t15)));
  t17 = ieee_p_1242562249_sub_2177518728674633585_1035706684(t1, t12, t3, t4, t16, t13);
  t18 = (t12 + 12U);
  t19 = *((unsigned int *)t18);
  t20 = (1U * t19);
  t0 = xsi_get_transient_memory(t20);
  memcpy(t0, t17, t20);
  t21 = (t12 + 0U);
  t22 = *((int *)t21);
  t23 = (t12 + 4U);
  t24 = *((int *)t23);
  t25 = (t12 + 8U);
  t26 = *((int *)t25);
  t27 = (t2 + 0U);
  t28 = (t27 + 0U);
  *((int *)t28) = t22;
  t28 = (t27 + 4U);
  *((int *)t28) = t24;
  t28 = (t27 + 8U);
  *((int *)t28) = t26;
  t29 = (t24 - t22);
  t30 = (t29 * t26);
  t30 = (t30 + 1);
  t28 = (t27 + 12U);
  *((unsigned int *)t28) = t30;
LAB1:
  return t0;
LAB3:
  *((char **)t8) = t3;
  goto LAB2;
LAB4:;
}
```