ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remover>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x14(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <teste@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L13
L37:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x2,%ecx
  mov    %rax,%rdi
  call   <seekndestroy@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <teste@plt>
  mov    %eax,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L37
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D8
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string

tool: D19: Deseja remover um elemento? (1. Sim | 0. Nao)

tool: D21: %i

tool: D17: Deseja remover qual elemento? 

tool: D8: O elemento procurado (%i) nao existe.


tool: D39: Deseja eliminar outro elemento? (1. Sim | 0. Nao)

assistant: ```c
void remover(struct end *p, struct end **pon) {
  int metallica, lars = -1;
  struct end *p_aux;
  printf("Deseja remover um elemento? (1. Sim | 0. Nao)\n");
  scanf("%i", &lars);
  lars = teste(lars, 0, 1, 1);
  while (lars != 0) {
    printf("Deseja remover qual elemento? ");
    scanf("%i", &metallica);
    p_aux = seekndestroy(p, pon, metallica, 2);
    if (p_aux == NULL)
      printf("O elemento procurado (%i) nao existe.\n", metallica);
    printf("Deseja eliminar outro elemento? (1. Sim | 0. Nao)\n");
    scanf("%i", &lars);
    lars = teste(lars, 0, 1, 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remover>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    0x4(%rsp),%edi
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L15
  lea    D46(%rip),%r14
  lea    D55(%rip),%rbx
  lea    D10(%rip),%r15
  lea    D54(%rip),%r13
  jmp    L9
L38:
  mov    %r13,%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    0x4(%rsp),%edi
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L15
L9:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x2,%ecx
  mov    (%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <seekndestroy@plt>
  test   %rax,%rax
  jne    L38
  mov    (%rsp),%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L38
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D55
type_infered: string
name: read_data
arguments: data_tag: D46
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D54
type_infered: string

tool: D14: Deseja remover um elemento? (1. Sim | 0. Nao)

tool: D55: %i

tool: D46: Deseja remover qual elemento? 

tool: D10: O elemento procurado (%i) nao existe.


tool: D54: Deseja eliminar outro elemento? (1. Sim | 0. Nao)

assistant: ```c
void remover(struct end *p, struct end **pon) {
  int metallica, lars = -1;
  struct end *p_aux;
  printf("Deseja remover um elemento? (1. Sim | 0. Nao)\n");
  scanf("%i", &lars);
  lars = teste(lars, 0, 1, 1);
  while (lars != 0) {
    printf("Deseja remover qual elemento? ");
    scanf("%i", &metallica);
    p_aux = seekndestroy(p, pon, metallica, 2);
    if (p_aux == NULL)
      printf("O elemento procurado (%i) nao existe.\n", metallica);
    printf("Deseja eliminar outro elemento? (1. Sim | 0. Nao)\n");
    scanf("%i", &lars);
    lars = teste(lars, 0, 1, 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remover>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D42(%rip),%rdi
  push   %rbx
  lea    D37(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  movl   $0xffffffff,0x4(%rsp)
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L7
  lea    D18(%rip),%r15
  mov    %rsp,%r14
  jmp    L28
L59:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L7
L28:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    $0x2,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <seekndestroy@plt>
  test   %rax,%rax
  jne    L59
  mov    (%rsp),%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D42
type_guessed: string
name: parse_data
arguments: data_label: D37
type_guessed: string
name: parse_data
arguments: data_label: D18
type_guessed: string
name: parse_data
arguments: data_label: D36
type_guessed: string
name: parse_data
arguments: data_label: D32
type_guessed: string

tool: D42: Deseja remover um elemento? (1. Sim | 0. Nao)

tool: D37: %i

tool: D18: Deseja remover qual elemento? 

tool: D36: Deseja eliminar outro elemento? (1. Sim | 0. Nao)

tool: D32: O elemento procurado (%i) nao existe.


assistant: ```c
void remover(struct end *p, struct end **pon) {
  int metallica, lars = -1;
  struct end *p_aux;
  printf("Deseja remover um elemento? (1. Sim | 0. Nao)\n");
  scanf("%i", &lars);
  lars = teste(lars, 0, 1, 1);
  while (lars != 0) {
    printf("Deseja remover qual elemento? ");
    scanf("%i", &metallica);
    p_aux = seekndestroy(p, pon, metallica, 2);
    if (p_aux == NULL)
      printf("O elemento procurado (%i) nao existe.\n", metallica);
    printf("Deseja eliminar outro elemento? (1. Sim | 0. Nao)\n");
    scanf("%i", &lars);
    lars = teste(lars, 0, 1, 1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remover>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  movl   $0xffffffff,0x4(%rsp)
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L30
  lea    D23(%rip),%r15
  mov    %rsp,%r14
  jmp    L20
L41:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x1,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  call   <teste@plt>
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  je     L30
L20:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    $0x2,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <seekndestroy@plt>
  test   %rax,%rax
  jne    L41
  mov    (%rsp),%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D23
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D40
data_type: string

tool: D2: Deseja remover um elemento? (1. Sim | 0. Nao)

tool: D18: %i

tool: D23: Deseja remover qual elemento? 

tool: D12: Deseja eliminar outro elemento? (1. Sim | 0. Nao)

tool: D40: O elemento procurado (%i) nao existe.


assistant: ```c
void remover(struct end *p, struct end **pon) {
  int metallica, lars = -1;
  struct end *p_aux;
  printf("Deseja remover um elemento? (1. Sim | 0. Nao)\n");
  scanf("%i", &lars);
  lars = teste(lars, 0, 1, 1);
  while (lars != 0) {
    printf("Deseja remover qual elemento? ");
    scanf("%i", &metallica);
    p_aux = seekndestroy(p, pon, metallica, 2);
    if (p_aux == NULL)
      printf("O elemento procurado (%i) nao existe.\n", metallica);
    printf("Deseja eliminar outro elemento? (1. Sim | 0. Nao)\n");
    scanf("%i", &lars);
    lars = teste(lars, 0, 1, 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<half10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L34:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x0,-0xc(%rbp)
  jg     L34
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L26:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int half10(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 10 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<half10>:
  endbr64
  mov    %rdi,%r8
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L23
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  mov    $0x0,%eax
L39:
  lea    (%rax,%rax,4),%edx
  mov    (%rcx),%eax
  lea    (%rax,%rdx,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,(%rcx)
  sub    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L39
L14:
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L17
  movslq %edx,%rcx
  cmpl   $0x0,(%r8,%rcx,4)
  jne    L17
  sub    $0x1,%edx
  mov    %edx,(%r8)
L17:
  ret
L23:
  mov    $0x0,%eax
  jmp    L14
```

assistant: ```c
int half10(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 10 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<half10>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L31
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  lea    (%rax,%rax,4),%edx
  mov    (%rcx),%eax
  sub    $0x4,%rcx
  lea    (%rax,%rdx,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,0x4(%rcx)
  cmp    %rdi,%rcx
  jne    L25
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L17
  movslq %edx,%rcx
  mov    (%r8,%rcx,4),%ecx
  test   %ecx,%ecx
  jne    L17
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
L17:
  ret
```

assistant: ```c
int half10(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 10 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<half10>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L5
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  lea    (%rax,%rax,4),%edx
  mov    (%rcx),%eax
  sub    $0x4,%rcx
  lea    (%rax,%rdx,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,0x4(%rcx)
  cmp    %rdi,%rcx
  jne    L4
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L1
  movslq %edx,%rcx
  mov    (%r8,%rcx,4),%ecx
  test   %ecx,%ecx
  jne    L1
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
L1:
  ret
```

assistant: ```c
int half10(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 10 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d 

assistant: ```c
int t(int a) {
  printf("%d ", a);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<t>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %d 

assistant: ```c
int t(int a) {
  printf("%d ", a);
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %d 

assistant: ```c
int t(int a) {
  printf("%d ", a);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t>:
  endbr64
  push   %r12
  mov    %edi,%esi
  mov    %edi,%r12d
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d 

assistant: ```c
int t(int a) {
  printf("%d ", a);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L20
  mov    $0xffffffff,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L20:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D17
type: string

tool: D21: %d

tool: D17: %d 


assistant: ```c
int main() {
  int n;
  if (!scanf("%d", &n)) {
    printf("%d \n", -1);
  } else {
    printf("%d \n", is_prime(n));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L13
  mov    $0xffffffff,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L13:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D2: %d

tool: D3: %d 


assistant: ```c
int main() {
  int n;
  if (!scanf("%d", &n)) {
    printf("%d \n", -1);
  } else {
    printf("%d \n", is_prime(n));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L10
  or     $0xffffffff,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L10:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L0
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D22
type_infered: string

tool: D25: %d

tool: D22: %d 


assistant: ```c
int main() {
  int n;
  if (!scanf("%d", &n)) {
    printf("%d \n", -1);
  } else {
    printf("%d \n", is_prime(n));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L2
  or     $0xffffffff,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L1
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: string
name: read_data
arguments: data_label: D14
data_type: string

tool: D15: %d

tool: D14: %d 


assistant: ```c
int main() {
  int n;
  if (!scanf("%d", &n)) {
    printf("%d \n", -1);
  } else {
    printf("%d \n", is_prime(n));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_to_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L19:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L19
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void string_to_lower(char *str, char *result) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    result[i] = tolower(str[i]);
  }
  result[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_to_lower>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  jmp    L0
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  movslq %ebx,%r13
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void string_to_lower(char *str, char *result) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    result[i] = tolower(str[i]);
  }
  result[i] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_to_lower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rbx,1),%rdx
  cmp    %ebx,%eax
  jg     L9
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void string_to_lower(char *str, char *result) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    result[i] = tolower(str[i]);
  }
  result[i] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_to_lower>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L7:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rbx,1),%rdx
  cmp    %ebx,%eax
  jg     L7
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void string_to_lower(char *str, char *result) {
  int i;
  for (i = 0; i < strlen(str); i++) {
    result[i] = tolower(str[i]);
  }
  result[i] = 0;
}
```