ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
L9:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L9
  ret
```

assistant: ```c
char *strcpy(register char *to, register const char *from) {
  register char *ret = to;
  while ((*to++ = *from++) != '\0')
    continue;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
L5:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L5
  ret
```

assistant: ```c
char *strcpy(register char *to, register const char *from) {
  register char *ret = to;
  while ((*to++ = *from++) != '\0')
    continue;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dev_is_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  je     L16
  mov    $0x1,%eax
  jmp    L22
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <S_ISLNK@plt>
  test   %rax,%rax
  je     L59
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  je     L59
  mov    $0x1,%eax
  jmp    L22
L59:
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int dev_is_block(struct stat *sb, char *path) {
  if (S_ISBLK(sb->st_mode))
    return 1;
  if (S_ISLNK(sb->st_mode))
    if (!stat(path, sb))
      if (S_ISBLK(sb->st_mode))
        return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dev_is_block>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%edi
  call   <S_ISBLK@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L6
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    (%rbx),%edi
  call   <S_ISLNK@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L26
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L26
  mov    (%rbx),%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L26
```

assistant: ```c
int dev_is_block(struct stat *sb, char *path) {
  if (S_ISBLK(sb->st_mode))
    return 1;
  if (S_ISLNK(sb->st_mode))
    if (!stat(path, sb))
      if (S_ISBLK(sb->st_mode))
        return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dev_is_block>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <S_ISBLK@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L23
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rbx),%edi
  call   <S_ISLNK@plt>
  test   %rax,%rax
  jne    L4
L34:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L34
  mov    (%rbx),%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L22
```

assistant: ```c
int dev_is_block(struct stat *sb, char *path) {
  if (S_ISBLK(sb->st_mode))
    return 1;
  if (S_ISLNK(sb->st_mode))
    if (!stat(path, sb))
      if (S_ISBLK(sb->st_mode))
        return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dev_is_block>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <S_ISBLK@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L33
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    (%rbx),%edi
  call   <S_ISLNK@plt>
  test   %rax,%rax
  jne    L26
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L8
  mov    (%rbx),%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
```

assistant: ```c
int dev_is_block(struct stat *sb, char *path) {
  if (S_ISBLK(sb->st_mode))
    return 1;
  if (S_ISLNK(sb->st_mode))
    if (!stat(path, sb))
      if (S_ISBLK(sb->st_mode))
        return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: %s


assistant: ```c
int main(int argc, const char *argv) {
  argc = 5;
  printf("%s\n", argv[0]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: %s


assistant: ```c
int main(int argc, const char *argv) {
  argc = 5;
  printf("%s\n", argv[0]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: %s


assistant: ```c
int main(int argc, const char *argv) {
  argc = 5;
  printf("%s\n", argv[0]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: %s


assistant: ```c
int main(int argc, const char *argv) {
  argc = 5;
  printf("%s\n", argv[0]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WriteWORDBE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc_err@plt>
  movzwl -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc_err@plt>
  nop
  leave
  ret
```

assistant: ```c
void WriteWORDBE(FILE *outf, unsigned short data) {
  (assert(outf != NULL));
  fputc_err(data >> 8, outf);
  fputc_err(data & 0xFF, outf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<WriteWORDBE>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc_err@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <fputc_err@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void WriteWORDBE(FILE *outf, unsigned short data) {
  (assert(outf != NULL));
  fputc_err(data >> 8, outf);
  fputc_err(data & 0xFF, outf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<WriteWORDBE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc_err@plt>
  add    $0x8,%rsp
  movzbl %bl,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <fputc_err@plt>
```

assistant: ```c
void WriteWORDBE(FILE *outf, unsigned short data) {
  (assert(outf != NULL));
  fputc_err(data >> 8, outf);
  fputc_err(data & 0xFF, outf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<WriteWORDBE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc_err@plt>
  add    $0x8,%rsp
  movzbl %bl,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <fputc_err@plt>
```

assistant: ```c
void WriteWORDBE(FILE *outf, unsigned short data) {
  (assert(outf != NULL));
  fputc_err(data >> 8, outf);
  fputc_err(data & 0xFF, outf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sw_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L12:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *sw_strcpy(char *dest, char *src) {
  while (*src != '\0') {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<sw_strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
L2:
  add    $0x1,%rsi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L2
L3:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *sw_strcpy(char *dest, char *src) {
  while (*src != '\0') {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sw_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L18
  xchg   %ax,%ax
L2:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L2
L18:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *sw_strcpy(char *dest, char *src) {
  while (*src != '\0') {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sw_strcpy>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L3
  xchg   %ax,%ax
L9:
  add    $0x1,%rsi
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L9
L3:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *sw_strcpy(char *dest, char *src) {
  while (*src != '\0') {
    *dest++ = *src++;
  }
  *dest = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <print_hex@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++) {
    print_hex(argv[i]);
    putchar('\n');
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L8:
  mov    (%rbx),%rdi
  call   <print_hex@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L8
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++) {
    print_hex(argv[i]);
    putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <print_hex@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++) {
    print_hex(argv[i]);
    putchar('\n');
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <print_hex@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++) {
    print_hex(argv[i]);
    putchar('\n');
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x5,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fatorial@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: N=%li, F=%li


assistant: ```c
int main(void) {
  long n = 5L;
  long f = fatorial(n);
  printf("N=%li, F=%li\n", n, f);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  mov    %rax,%rdx
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: N=%li, F=%li


assistant: ```c
int main(void) {
  long n = 5L;
  long f = fatorial(n);
  printf("N=%li, F=%li\n", n, f);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  mov    $0x5,%esi
  lea    D4(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: N=%li, F=%li


assistant: ```c
int main(void) {
  long n = 5L;
  long f = fatorial(n);
  printf("N=%li, F=%li\n", n, f);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <fatorial@plt>
  mov    $0x5,%esi
  lea    D9(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: N=%li, F=%li


assistant: ```c
int main(void) {
  long n = 5L;
  long f = fatorial(n);
  printf("N=%li, F=%li\n", n, f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D2(%rip),%rdx
  mov    -0x14(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: f64

tool: D2: 0.75

assistant: ```c
int f(int a) {
  int g = pow(a, 0.75);
  return g;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: f64

tool: D3: 0.75

assistant: ```c
int f(int a) {
  int g = pow(a, 0.75);
  return g;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  movsd  D8(%rip),%xmm0
  jmp    1050 <pow@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: f64

tool: D8: 0.75

assistant: ```c
int f(int a) {
  int g = pow(a, 0.75);
  return g;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  movsd  D2(%rip),%xmm0
  jmp    1050 <pow@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: f64

tool: D2: 0.75

assistant: ```c
int f(int a) {
  int g = pow(a, 0.75);
  return g;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GPMCAddrDataMuxProtocolSelect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x60,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x60,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  and    $0xfc,%ah
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x60,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  shl    $0x8,%eax
  and    $0x300,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x60,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPMCAddrDataMuxProtocolSelect(unsigned int baseAddr, unsigned int csNum, unsigned int protocol) {
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) &= ~(0x00000300u);
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) |= ((protocol << (0x00000008u)) & (0x00000300u));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GPMCAddrDataMuxProtocolSelect>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  shl    $0x4,%eax
  lea    0x60(%rax,%rdi,1),%eax
  mov    (%eax),%ecx
  and    $0xfc,%ch
  mov    %ecx,(%eax)
  mov    (%eax),%ecx
  shl    $0x8,%edx
  and    $0x300,%edx
  or     %ecx,%edx
  mov    %edx,(%eax)
  ret
```

assistant: ```c
void GPMCAddrDataMuxProtocolSelect(unsigned int baseAddr, unsigned int csNum, unsigned int protocol) {
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) &= ~(0x00000300u);
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) |= ((protocol << (0x00000008u)) & (0x00000300u));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GPMCAddrDataMuxProtocolSelect>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  shl    $0x8,%edx
  shl    $0x4,%eax
  and    $0x300,%edx
  lea    0x60(%rax,%rdi,1),%eax
  mov    (%eax),%ecx
  and    $0xfc,%ch
  mov    %ecx,(%eax)
  mov    (%eax),%ecx
  or     %ecx,%edx
  mov    %edx,(%eax)
  ret
```

assistant: ```c
void GPMCAddrDataMuxProtocolSelect(unsigned int baseAddr, unsigned int csNum, unsigned int protocol) {
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) &= ~(0x00000300u);
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) |= ((protocol << (0x00000008u)) & (0x00000300u));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GPMCAddrDataMuxProtocolSelect>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  shl    $0x8,%edx
  shl    $0x4,%eax
  and    $0x300,%edx
  lea    0x60(%rax,%rdi,1),%eax
  mov    (%eax),%ecx
  and    $0xfc,%ch
  mov    %ecx,(%eax)
  mov    (%eax),%ecx
  or     %ecx,%edx
  mov    %edx,(%eax)
  ret
```

assistant: ```c
void GPMCAddrDataMuxProtocolSelect(unsigned int baseAddr, unsigned int csNum, unsigned int protocol) {
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) &= ~(0x00000300u);
  (*((volatile unsigned int *)(baseAddr + (0x60 + (csNum * (0x30)))))) |= ((protocol << (0x00000008u)) & (0x00000300u));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x9,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void b() {
  int i = 9;
  (void)(i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<b>:
  endbr64
  ret
```

assistant: ```c
void b() {
  int i = 9;
  (void)(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<b>:
  endbr64
  ret
```

assistant: ```c
void b() {
  int i = 9;
  (void)(i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<b>:
  endbr64
  ret
```

assistant: ```c
void b() {
  int i = 9;
  (void)(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strextract_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L39
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: 

assistant: ```c
int strextract_name(char *out, char *in) {
  int i;
  for (i = 0; i < strlen(in); i++) {
    if (in[i] == '@') {
      out[i] = 0;
      return strlen(out);
    }
    out[i] = in[i];
  }
  strcpy(out, "");
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strextract_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  jmp    L18
L3:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L19
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x40,%al
  jne    L3
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rdi
  call   <strlen@plt>
  jmp    L8
L19:
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0xffffffff,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: 

assistant: ```c
int strextract_name(char *out, char *in) {
  int i;
  for (i = 0; i < strlen(in); i++) {
    if (in[i] == '@') {
      out[i] = 0;
      return strlen(out);
    }
    out[i] = in[i];
  }
  strcpy(out, "");
  return -1;
}
```