ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_meta_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  je     L78
  mov    %rdi,%rbp
  mov    %rsi,%r15
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    D8(%rip),%r12
  jmp    L46
  nopl   0x0(%rax)
L12:
  add    %rax,%r13
  add    $0x1,%r14
  cmp    %r14,0x8(%rsp)
  je     L27
L46:
  mov    (%r15,%r14,8),%rsi
  mov    %r12,%rdi
  call   <verbose@plt>
  mov    (%r15,%r14,8),%rdi
  call   <strlen@plt>
  mov    (%r15,%r14,8),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  lea    0x1(%rax),%edx
  call   <fwrite@plt>
  mov    (%r15,%r14,8),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  je     L12
L78:
  xor    %r12d,%r12d
L9:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  lea    0x3(%r13),%r12
  and    $0xfffffffffffffffc,%r12
  cmp    %r13,%r12
  jbe    L16
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  add    $0x1,%r13
  cmp    %r13,%r12
  jne    L19
  jmp    L9
L16:
  mov    %r13,%r12
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D8: SEAMA META data : %s


tool: 

assistant: ```c
size_t write_meta_data(FILE *fh, char *meta[], size_t size) {
  size_t i, j;
  size_t ret = 0;
  for (i = 0; i < size; i++) {
    verbose("SEAMA META data : %s\n", meta[i]);
    j = fwrite(meta[i], sizeof(char), strlen(meta[i]) + 1, fh);
    if (j != strlen(meta[i]) + 1)
      return 0;
    ret += j;
  }
  j = ((ret + 3) / 4) * 4;
  for (; ret < j; ret++)
    fwrite("", sizeof(char), 1, fh);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D44(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D29(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D34
type_infered: f64
name: retrieve_data
arguments: data_label: D44
type_infered: f64
name: retrieve_data
arguments: data_label: D29
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D8: %lf %lf

tool: D34: 3.5

tool: D44: 7.5

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40]}

tool: D10: MEDIA = %.5lf


assistant: ```c
int main() {
  double A, B, average;
  scanf("%lf %lf", &A, &B);
  average = ((A * 3.5) + (B * 7.5)) / (3.5 + 7.5);
  printf("MEDIA = %.5lf\n", average);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movsd  D26(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  D46(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D14(%rip),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: f64
name: disassemble_data
arguments: data_tag: D46
type_guessed: f64
name: disassemble_data
arguments: data_tag: D14
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D15: %lf %lf

tool: D26: 3.5

tool: D46: 7.5

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40]}

tool: D0: MEDIA = %.5lf


assistant: ```c
int main() {
  double A, B, average;
  scanf("%lf %lf", &A, &B);
  average = ((A * 3.5) + (B * 7.5)) / (3.5 + 7.5);
  printf("MEDIA = %.5lf\n", average);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  D25(%rip),%xmm0
  movsd  D43(%rip),%xmm1
  lea    D47(%rip),%rdi
  mulsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D5(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type: string
name: retrieve_data
arguments: data_label: D25
type: f64
name: retrieve_data
arguments: data_label: D43
type: f64
name: retrieve_data
arguments: data_label: D47
type: string
name: retrieve_data
arguments: data_label: D5
type: byte[8]

tool: D45: %lf %lf

tool: D25: 3.5

tool: D43: 7.5

tool: D47: MEDIA = %.5lf


tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40]}

assistant: ```c
int main() {
  double A, B, average;
  scanf("%lf %lf", &A, &B);
  average = ((A * 3.5) + (B * 7.5)) / (3.5 + 7.5);
  printf("MEDIA = %.5lf\n", average);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  D9(%rip),%xmm0
  movsd  D11(%rip),%xmm1
  lea    D47(%rip),%rdi
  mulsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D40(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D9
type: f64
name: unpack_data
arguments: data_label: D11
type: f64
name: unpack_data
arguments: data_label: D47
type: string
name: unpack_data
arguments: data_label: D40
type: byte[8]

tool: D12: %lf %lf

tool: D9: 3.5

tool: D11: 7.5

tool: D47: MEDIA = %.5lf


tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40]}

assistant: ```c
int main() {
  double A, B, average;
  scanf("%lf %lf", &A, &B);
  average = ((A * 3.5) + (B * 7.5)) / (3.5 + 7.5);
  printf("MEDIA = %.5lf\n", average);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ti_qstick>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  cvttsd2si (%rdx),%ebx
  mov    $0x1,%eax
  test   %ebx,%ebx
  jle    L34
  mov    %edi,%r13d
  mov    %rdx,%r14
  mov    (%rsi),%rbp
  mov    0x8(%rsi),%r12
  mov    (%rcx),%r15
  mov    %rdx,%rdi
  call   <ti_qstick_start@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %r13d,%edx
  jge    L34
  mov    %ebx,%edx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L12:
  movsd  (%r12,%rax,8),%xmm1
  subsd  0x0(%rbp,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L12
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  D6(%rip),%xmm2
  divsd  %xmm1,%xmm2
  lea    0x8(%r15),%rsi
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r15)
  cmp    %r13d,%ebx
  jge    L41
  lea    -0x1(%r13),%eax
  sub    %ebx,%eax
  lea    0x8(,%rax,8),%rdx
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  lea    (%r12,%rbx,1),%rcx
  add    %rbp,%rbx
  mov    $0x0,%eax
L30:
  movsd  (%rcx,%rax,1),%xmm1
  subsd  (%rbx,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  (%r12,%rax,1),%xmm1
  subsd  0x0(%rbp,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%r15,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L30
  add    %rdx,%rsi
L41:
  mov    0x8(%rsp),%rax
  sub    (%rax),%rsi
  sar    $0x3,%rsi
  mov    %rsi,%rbx
  mov    %r14,%rdi
  call   <ti_qstick_start@plt>
  sub    %eax,%r13d
  movslq %r13d,%r13
  cmp    %rbx,%r13
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: f64

tool: D6: 1

assistant: ```c
int ti_qstick(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *open = inputs[0];
  const double *close = inputs[1];
  double *output = outputs[0];
  const int period = (int)options[0];
  const double scale = 1.0 / period;
  if (period < 1)
    return 1;
  if (size <= ti_qstick_start(options))
    return 0;
  double sum = 0;
  int i;
  for (i = 0; i < period; ++i) {
    sum += close[i] - open[i];
  }
  *output++ = sum * scale;
  for (i = period; i < size; ++i) {
    sum += close[i] - open[i];
    sum -= close[i - period] - open[i - period];
    *output++ = sum * scale;
  }
  assert(output - outputs[0] == size - ti_qstick_start(options));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ti_qstick>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  mov    $0x1,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cvttsd2si (%rdx),%ecx
  test   %ecx,%ecx
  mov    %ecx,0xc(%rsp)
  jle    L15
  mov    %edi,%r12d
  mov    %rdx,%rdi
  mov    (%rsi),%rbx
  mov    0x8(%rsi),%rbp
  mov    (%r15),%r14
  mov    %rdx,%r13
  call   <ti_qstick_start@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r12d,%r8d
  jge    L15
  movslq 0xc(%rsp),%rdx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %rdx,%rcx
  xchg   %ax,%ax
L19:
  movsd  0x0(%rbp,%rax,8),%xmm1
  subsd  (%rbx,%rax,8),%xmm1
  add    $0x1,%rax
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L19
  pxor   %xmm1,%xmm1
  movsd  D1(%rip),%xmm2
  lea    0x8(%r14),%rsi
  cvtsi2sd %ecx,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r14)
  cmp    %r12d,%ecx
  jge    L38
  lea    -0x1(%r12),%eax
  shl    $0x3,%rdx
  sub    %ecx,%eax
  lea    0x0(%rbp,%rdx,1),%rdi
  add    %rbx,%rdx
  lea    0x8(,%rax,8),%rcx
  xor    %eax,%eax
  nop
L23:
  movsd  (%rdi,%rax,1),%xmm1
  subsd  (%rdx,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x0(%rbp,%rax,1),%xmm1
  subsd  (%rbx,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%r14,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L23
  add    %rcx,%rsi
L38:
  sub    (%r15),%rsi
  mov    %r13,%rdi
  sar    $0x3,%rsi
  mov    %rsi,%rbx
  call   <ti_qstick_start@plt>
  xor    %edi,%edi
  sub    %eax,%r12d
  movslq %r12d,%r12
  cmp    %rbx,%r12
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
L15:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: f64

tool: D1: 1

assistant: ```c
int ti_qstick(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *open = inputs[0];
  const double *close = inputs[1];
  double *output = outputs[0];
  const int period = (int)options[0];
  const double scale = 1.0 / period;
  if (period < 1)
    return 1;
  if (size <= ti_qstick_start(options))
    return 0;
  double sum = 0;
  int i;
  for (i = 0; i < period; ++i) {
    sum += close[i] - open[i];
  }
  *output++ = sum * scale;
  for (i = period; i < size; ++i) {
    sum += close[i] - open[i];
    sum -= close[i - period] - open[i - period];
    *output++ = sum * scale;
  }
  assert(output - outputs[0] == size - ti_qstick_start(options));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ti_qstick>:
  endbr64
  push   %r15
  mov    $0x1,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cvttsd2si (%rdx),%ebx
  test   %ebx,%ebx
  jle    L44
  mov    %edi,%r13d
  mov    %rdx,%rdi
  mov    %rcx,0x8(%rsp)
  mov    (%rsi),%rbp
  mov    0x8(%rsi),%r12
  mov    (%rcx),%r15
  call   <ti_qstick_start@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r13d,%r8d
  jge    L44
  cmp    $0x1,%ebx
  mov    0x8(%rsp),%rdx
  je     L32
  mov    %ebx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L43:
  movupd (%r12,%rax,1),%xmm1
  movupd 0x0(%rbp,%rax,1),%xmm3
  add    $0x10,%rax
  subpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L43
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bl
  je     L69
L5:
  cltq
  movsd  (%r12,%rax,8),%xmm1
  subsd  0x0(%rbp,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
L69:
  pxor   %xmm1,%xmm1
  movsd  D4(%rip),%xmm2
  lea    0x8(%r15),%rsi
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r15)
  cmp    %r13d,%ebx
  jge    L18
  lea    -0x1(%r13),%eax
  sub    %ebx,%eax
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  lea    0x8(,%rax,8),%rcx
  xor    %eax,%eax
  lea    (%r12,%rbx,1),%rdi
  add    %rbp,%rbx
  nopl   0x0(%rax)
L19:
  movsd  (%rdi,%rax,1),%xmm1
  subsd  (%rbx,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  (%r12,%rax,1),%xmm1
  subsd  0x0(%rbp,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%r15,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L19
  add    %rax,%rsi
L18:
  sub    (%rdx),%rsi
  mov    %r14,%rdi
  sar    $0x3,%rsi
  mov    %rsi,%rbx
  call   <ti_qstick_start@plt>
  xor    %edi,%edi
  sub    %eax,%r13d
  movslq %r13d,%r13
  cmp    %rbx,%r13
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
L44:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: f64

tool: D4: 1

assistant: ```c
int ti_qstick(int size, double const *const *inputs, double const *options, double *const *outputs) {
  const double *open = inputs[0];
  const double *close = inputs[1];
  double *output = outputs[0];
  const int period = (int)options[0];
  const double scale = 1.0 / period;
  if (period < 1)
    return 1;
  if (size <= ti_qstick_start(options))
    return 0;
  double sum = 0;
  int i;
  for (i = 0; i < period; ++i) {
    sum += close[i] - open[i];
  }
  *output++ = sum * scale;
  for (i = period; i < size; ++i) {
    sum += close[i] - open[i];
    sum -= close[i - period] - open[i - period];
    *output++ = sum * scale;
  }
  assert(output - outputs[0] == size - ti_qstick_start(options));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<heapDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L42:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L27
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L27
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L59
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jg     L42
  jmp    L39
L59:
  nop
L39:
  pop    %rbp
  ret
```

assistant: ```c
void heapDown(int *heap, int start, int end) {
  int root = start;
  while (root * 2 + 1 < end) {
    int child = 2 * root + 1;
    if ((child + 1 < end) && (heap[child] < heap[child + 1])) {
      child += 1;
    }
    if ((heap[root] < heap[child])) {
      do {
        int t = heap[child];
        heap[child] = heap[root];
        heap[root] = t;
      } while (0);
      root = child;
    } else
      return;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<heapDown>:
  endbr64
  lea    0x1(%rsi,%rsi,1),%ecx
  cmp    %ecx,%edx
  jg     L11
  ret
L7:
  mov    %ecx,%eax
L49:
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%r9d
  movslq %eax,%rsi
  lea    (%rdi,%rsi,4),%r8
  mov    (%r8),%esi
  cmp    %esi,%r9d
  jge    L44
  mov    %r9d,(%r8)
  mov    %esi,(%rcx)
  lea    0x1(%rax,%rax,1),%ecx
  cmp    %edx,%ecx
  jge    L44
  mov    %eax,%esi
L11:
  lea    0x2(%rsi,%rsi,1),%eax
  cmp    %edx,%eax
  jge    L7
  movslq %ecx,%r8
  mov    0x4(%rdi,%r8,4),%r10d
  cmp    %r10d,(%rdi,%r8,4)
  cmovge %ecx,%eax
  jmp    L49
L44:
  ret
```

assistant: ```c
void heapDown(int *heap, int start, int end) {
  int root = start;
  while (root * 2 + 1 < end) {
    int child = 2 * root + 1;
    if ((child + 1 < end) && (heap[child] < heap[child + 1])) {
      child += 1;
    }
    if ((heap[root] < heap[child])) {
      do {
        int t = heap[child];
        heap[child] = heap[root];
        heap[root] = t;
      } while (0);
      root = child;
    } else
      return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heapDown>:
  endbr64
  mov    %rdi,%r10
  lea    0x1(%rsi,%rsi,1),%edi
  cmp    %edi,%edx
  jg     L64
  jmp    L36
  nopl   0x0(%rax)
L66:
  cmp    %r8d,0x4(%r10,%rcx,1)
  jle    L27
  movslq %eax,%rcx
  movslq %esi,%rsi
  lea    (%r10,%rcx,4),%r9
  lea    (%r10,%rsi,4),%rcx
  mov    (%r9),%r8d
  mov    (%rcx),%esi
  cmp    %r8d,%esi
  jge    L46
L52:
  lea    0x1(%rax,%rax,1),%edi
  mov    %esi,(%r9)
  mov    %r8d,(%rcx)
  cmp    %edx,%edi
  jge    L46
  mov    %eax,%esi
L64:
  movslq %edi,%rcx
  lea    0x2(%rsi,%rsi,1),%eax
  shl    $0x2,%rcx
  lea    (%r10,%rcx,1),%r9
  mov    (%r9),%r8d
  cmp    %edx,%eax
  jl     L66
L27:
  movslq %esi,%rsi
  mov    %edi,%eax
  lea    (%r10,%rsi,4),%rcx
  mov    (%rcx),%esi
  cmp    %r8d,%esi
  jl     L52
L46:
  ret
L36:
  ret
```

assistant: ```c
void heapDown(int *heap, int start, int end) {
  int root = start;
  while (root * 2 + 1 < end) {
    int child = 2 * root + 1;
    if ((child + 1 < end) && (heap[child] < heap[child + 1])) {
      child += 1;
    }
    if ((heap[root] < heap[child])) {
      do {
        int t = heap[child];
        heap[child] = heap[root];
        heap[root] = t;
      } while (0);
      root = child;
    } else
      return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<heapDown>:
  endbr64
  mov    %rdi,%r10
  lea    0x1(%rsi,%rsi,1),%edi
  cmp    %edi,%edx
  jg     L50
  jmp    L61
  nopl   0x0(%rax)
L54:
  cmp    %r8d,0x4(%r10,%rcx,1)
  jle    L28
  movslq %eax,%rcx
  movslq %esi,%rsi
  lea    (%r10,%rcx,4),%r9
  lea    (%r10,%rsi,4),%rcx
  mov    (%r9),%r8d
  mov    (%rcx),%esi
  cmp    %r8d,%esi
  jge    L1
L65:
  lea    0x1(%rax,%rax,1),%edi
  mov    %esi,(%r9)
  mov    %r8d,(%rcx)
  cmp    %edx,%edi
  jge    L1
  mov    %eax,%esi
L50:
  movslq %edi,%rcx
  lea    0x2(%rsi,%rsi,1),%eax
  shl    $0x2,%rcx
  lea    (%r10,%rcx,1),%r9
  mov    (%r9),%r8d
  cmp    %edx,%eax
  jl     L54
L28:
  movslq %esi,%rsi
  mov    %edi,%eax
  lea    (%r10,%rsi,4),%rcx
  mov    (%rcx),%esi
  cmp    %r8d,%esi
  jl     L65
L1:
  ret
L61:
  ret
```

assistant: ```c
void heapDown(int *heap, int start, int end) {
  int root = start;
  while (root * 2 + 1 < end) {
    int child = 2 * root + 1;
    if ((child + 1 < end) && (heap[child] < heap[child + 1])) {
      child += 1;
    }
    if ((heap[root] < heap[child])) {
      do {
        int t = heap[child];
        heap[child] = heap[root];
        heap[root] = t;
      } while (0);
      root = child;
    } else
      return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<semap_post>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L14
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <kill@plt>
L14:
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int semap_post(int sem_id, int nsem, int cnt) {
  struct sembuf op[1];
  op[0].sem_num = nsem;
  op[0].sem_op = cnt;
  op[0].sem_flg = 0;
  int ret;
  ret = semop(sem_id, op, 1);
  if (ret == -1) {
    kill(0, SIGINT);
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<semap_post>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L21
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L21:
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <kill@plt>
  jmp    L11
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int semap_post(int sem_id, int nsem, int cnt) {
  struct sembuf op[1];
  op[0].sem_num = nsem;
  op[0].sem_op = cnt;
  op[0].sem_flg = 0;
  int ret;
  ret = semop(sem_id, op, 1);
  if (ret == -1) {
    kill(0, SIGINT);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<semap_post>:
  endbr64
  push   %r12
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %rsp,%rsi
  mov    %edx,0x4(%rsp)
  mov    $0x1,%edx
  movq   $0x0,0x8(%rsp)
  call   <semop@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L1
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    D6(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <kill@plt>
  jmp    L5
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int semap_post(int sem_id, int nsem, int cnt) {
  struct sembuf op[1];
  op[0].sem_num = nsem;
  op[0].sem_op = cnt;
  op[0].sem_flg = 0;
  int ret;
  ret = semop(sem_id, op, 1);
  if (ret == -1) {
    kill(0, SIGINT);
  }
  return ret;
}
```