ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_a>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %ebp,%ebp
  jle    L51
  mov    %ebp,%r12d
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x8,%esi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L16
L51:
  mov    %r13,%rdi
  lea    0x38(%rsp),%r15
  lea    D2(%rip),%rsi
  call   <get_fp@plt>
  mov    $0x1,%esi
  mov    $0x1000,%edi
  movq   $0x1000,0x28(%rsp)
  mov    %rax,(%rsp)
  lea    0x40(%rsp),%r13
  lea    D13(%rip),%r12
  call   <calloc@plt>
  mov    0x18(%rsp),%rbp
  lea    D20(%rip),%r14
  mov    %rax,0x30(%rsp)
  lea    0x28(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L42:
  mov    (%rsp),%rdx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    0x30(%rsp),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L35
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r15,%rdx
  mov    %r14,%rsi
  call   <sscanf@plt>
  mov    0x0(%rbp),%rax
  xor    %edi,%edi
  mov    %r13,%rdx
  movsd  0x38(%rsp),%xmm0
  mov    %r12,%rsi
  movsd  %xmm0,(%rax,%rbx,1)
  add    $0x8,%rbx
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L25
L35:
  add    $0x8,%rbp
  jmp    L42
  nopl   0x0(%rax)
L32:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    0x18(%rsp),%rax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string

tool: D2: r

tool: D13:  

tool: D20: %lf

assistant: ```c
double **get_a(char *filename, int dim) {
  double **a = calloc(dim, sizeof(double *));
  for (int row = 0; row < dim; row++) {
    a[row] = calloc(dim, sizeof(double));
  }
  FILE *fp = get_fp(filename, "r");
  size_t m = 4096;
  char *line_buf = calloc(m, sizeof(char));
  double result;
  int cur_row = 0;
  int cur_element;
  char *tok;
  char *tok_ptr;
  while (getline(&line_buf, &m, fp) != -1) {
    cur_element = 0;
    for (tok = strtok_r(line_buf, " ", &tok_ptr); tok; tok = strtok_r(NULL, " ", &tok_ptr)) {
      sscanf(tok, "%lf", &result);
      a[cur_row][cur_element] = result;
      cur_element++;
    }
    cur_row++;
  }
  return (a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0xa,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x3,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0xa,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D47
datatype: string
name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D0
datatype: string

tool: D45: resultado: %d


tool: D47: b : %d


tool: D11: puntero1 : %d


tool: D0: *puntero1 : %d


assistant: ```c
int main(void) {
  int b = 5;
  int *puntero1;
  int resultado;
  puntero1 = &b;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 3;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 5;
  printf("b : %d\n", b);
  printf("puntero1 : %d\n", puntero1);
  printf("*puntero1 : %d\n", *puntero1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  mov    $0xf,%esi
  lea    D31(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movl   $0x3,0x4(%rsp)
  mov    $0xd,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,0x4(%rsp)
  mov    $0x5,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D0
type: string

tool: D31: resultado: %d


tool: D16: b : %d


tool: D17: puntero1 : %d


tool: D0: *puntero1 : %d


assistant: ```c
int main(void) {
  int b = 5;
  int *puntero1;
  int resultado;
  puntero1 = &b;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 3;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 5;
  printf("b : %d\n", b);
  printf("puntero1 : %d\n", puntero1);
  printf("*puntero1 : %d\n", *puntero1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0xf,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movl   $0x3,0x4(%rsp)
  call   <printf@plt>
  mov    $0x5,%esi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D12
data_type: string

tool: D1: resultado: %d


tool: D30: b : %d


tool: D17: puntero1 : %d


tool: D12: *puntero1 : %d


assistant: ```c
int main(void) {
  int b = 5;
  int *puntero1;
  int resultado;
  puntero1 = &b;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 3;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 5;
  printf("b : %d\n", b);
  printf("puntero1 : %d\n", puntero1);
  printf("*puntero1 : %d\n", *puntero1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0xf,%esi
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movl   $0x3,0x4(%rsp)
  call   <printf@plt>
  mov    $0x5,%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D8: resultado: %d


tool: D20: b : %d


tool: D37: puntero1 : %d


tool: D7: *puntero1 : %d


assistant: ```c
int main(void) {
  int b = 5;
  int *puntero1;
  int resultado;
  puntero1 = &b;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 3;
  resultado = 10 + *puntero1;
  printf("resultado: %d\n", resultado);
  b = 5;
  printf("b : %d\n", b);
  printf("puntero1 : %d\n", puntero1);
  printf("*puntero1 : %d\n", *puntero1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_substr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rcx,0x18(%rsp)
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rsi,%r13
  mov    $0x0,%ebx
  jmp    L56
L27:
  add    $0x1,%r13
  movsbl 0x0(%r13),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L27
  add    $0x1,%ebx
L56:
  mov    %r13,%rdi
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L75
  cmp    %ebx,0xc(%rsp)
  jg     L27
  mov    $0x0,%r15d
  jmp    L133
L5:
  test   %r14d,%r14d
  je     L68
L84:
  add    $0x1,%r13
  movsbl 0x0(%r13),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L84
  add    $0x1,%r15d
L133:
  mov    %r13,%rdi
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L94
  mov    %r13,%rbp
  mov    0x10(%rsp),%rbx
L123:
  mov    %rbx,%rdi
  call   <sqlite3ReadUtf8@plt>
  mov    %rax,%r12
  mov    %eax,%r14d
  mov    %rbp,%rdi
  call   <sqlite3ReadUtf8@plt>
L168:
  add    $0x1,%rbx
  movsbl (%rbx),%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L168
L146:
  add    $0x1,%rbp
  movsbl 0x0(%rbp),%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L146
  cmp    %eax,%r12d
  sete   %cl
  test   %r12d,%r12d
  setne  %dl
  test   %dl,%cl
  je     L5
  test   %eax,%eax
  jne    L123
  jmp    L5
L75:
  mov    $0x0,%r15d
  jmp    L133
L68:
  cmpq   $0x0,0x18(%rsp)
  jne    L164
  jmp    L22
L23:
  mov    $0xffffffff,%r15d
  jmp    L140
L94:
  mov    $0xffffffff,%r15d
  cmpq   $0x0,0x18(%rsp)
  je     L140
L164:
  mov    0x18(%rsp),%rax
  mov    %r13,(%rax)
L22:
  mov    0xc(%rsp),%eax
  add    %r15d,%eax
  test   %r15d,%r15d
  cmovns %eax,%r15d
L140:
  mov    %r15d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _substr(const char *z1, const char *z2, int s, const char **p) {
  int c = 0;
  int rVal = -1;
  const char *zt1;
  const char *zt2;
  int c1, c2;
  if ('\0' == *z1) {
    return -1;
  }
  while ((sqlite3ReadUtf8((unsigned char *)z2) != 0) && (c++) < s) {
    while ((0xc0 & *++(z2)) == 0x80) {
    };
  }
  c = 0;
  while ((sqlite3ReadUtf8((unsigned char *)z2)) != 0) {
    zt1 = z1;
    zt2 = z2;
    do {
      c1 = sqlite3ReadUtf8((unsigned char *)zt1);
      c2 = sqlite3ReadUtf8((unsigned char *)zt2);
      while ((0xc0 & *++(zt1)) == 0x80) {
      };
      while ((0xc0 & *++(zt2)) == 0x80) {
      };
    } while (c1 == c2 && c1 != 0 && c2 != 0);
    if (c1 == 0) {
      rVal = c;
      break;
    }
    while ((0xc0 & *++(z2)) == 0x80) {
    };
    ++c;
  }
  if (p) {
    *p = z2;
  }
  return rVal >= 0 ? rVal + s : rVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_substr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmpb   $0x0,(%rdi)
  mov    %rdi,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rcx,0x18(%rsp)
  je     L44
  mov    %rsi,%r14
  xor    %ebx,%ebx
  mov    %r14,%rdi
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L82
  nopl   0x0(%rax,%rax,1)
L147:
  cmp    %ebx,0xc(%rsp)
  jle    L82
  cs nopw 0x0(%rax,%rax,1)
L97:
  movsbl 0x1(%r14),%eax
  add    $0x1,%r14
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L97
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  jne    L147
L82:
  mov    %r14,%rdi
  xor    %ebp,%ebp
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L146
  nopl   0x0(%rax,%rax,1)
L121:
  mov    0x10(%rsp),%r15
  mov    %r14,%r12
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %r15,%rdi
  call   <sqlite3ReadUtf8@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  mov    %eax,%ebx
  call   <sqlite3ReadUtf8@plt>
  nopl   (%rax)
L16:
  movsbl 0x1(%r15),%edx
  add    $0x1,%r15
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L16
  nop
L128:
  movsbl 0x1(%r12),%edx
  add    $0x1,%r12
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L128
  cmp    %eax,%r13d
  jne    L52
  test   %r13d,%r13d
  jne    L59
L52:
  test   %ebx,%ebx
  je     L115
  cs nopw 0x0(%rax,%rax,1)
L133:
  movsbl 0x1(%r14),%eax
  add    $0x1,%r14
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L133
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  jne    L121
L146:
  cmpq   $0x0,0x18(%rsp)
  je     L44
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
L44:
  add    $0x28,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L115:
  cmpq   $0x0,0x18(%rsp)
  je     L85
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
L85:
  mov    0xc(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _substr(const char *z1, const char *z2, int s, const char **p) {
  int c = 0;
  int rVal = -1;
  const char *zt1;
  const char *zt2;
  int c1, c2;
  if ('\0' == *z1) {
    return -1;
  }
  while ((sqlite3ReadUtf8((unsigned char *)z2) != 0) && (c++) < s) {
    while ((0xc0 & *++(z2)) == 0x80) {
    };
  }
  c = 0;
  while ((sqlite3ReadUtf8((unsigned char *)z2)) != 0) {
    zt1 = z1;
    zt2 = z2;
    do {
      c1 = sqlite3ReadUtf8((unsigned char *)zt1);
      c2 = sqlite3ReadUtf8((unsigned char *)zt2);
      while ((0xc0 & *++(zt1)) == 0x80) {
      };
      while ((0xc0 & *++(zt2)) == 0x80) {
      };
    } while (c1 == c2 && c1 != 0 && c2 != 0);
    if (c1 == 0) {
      rVal = c;
      break;
    }
    while ((0xc0 & *++(z2)) == 0x80) {
    };
    ++c;
  }
  if (p) {
    *p = z2;
  }
  return rVal >= 0 ? rVal + s : rVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_substr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmpb   $0x0,(%rdi)
  mov    %rdi,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %rcx,0x18(%rsp)
  je     L4
  mov    %rsi,%r14
  xor    %ebx,%ebx
  mov    %r14,%rdi
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L90
  nopl   0x0(%rax,%rax,1)
L120:
  cmp    %ebx,0xc(%rsp)
  jle    L90
  cs nopw 0x0(%rax,%rax,1)
L35:
  movsbl 0x1(%r14),%eax
  add    $0x1,%r14
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L35
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  jne    L120
L90:
  mov    %r14,%rdi
  xor    %ebp,%ebp
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  je     L74
  nopl   0x0(%rax,%rax,1)
L144:
  mov    0x10(%rsp),%r15
  mov    %r14,%r12
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r15,%rdi
  call   <sqlite3ReadUtf8@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  mov    %eax,%ebx
  call   <sqlite3ReadUtf8@plt>
  nopl   (%rax)
L130:
  movsbl 0x1(%r15),%edx
  add    $0x1,%r15
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L130
  nop
L143:
  movsbl 0x1(%r12),%edx
  add    $0x1,%r12
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L143
  cmp    %eax,%r13d
  jne    L16
  test   %r13d,%r13d
  jne    L25
L16:
  test   %ebx,%ebx
  je     L66
  cs nopw 0x0(%rax,%rax,1)
L122:
  movsbl 0x1(%r14),%eax
  add    $0x1,%r14
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L122
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <sqlite3ReadUtf8@plt>
  test   %rax,%rax
  jne    L144
L74:
  cmpq   $0x0,0x18(%rsp)
  je     L4
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
L4:
  add    $0x28,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  cmpq   $0x0,0x18(%rsp)
  je     L11
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
L11:
  mov    0xc(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _substr(const char *z1, const char *z2, int s, const char **p) {
  int c = 0;
  int rVal = -1;
  const char *zt1;
  const char *zt2;
  int c1, c2;
  if ('\0' == *z1) {
    return -1;
  }
  while ((sqlite3ReadUtf8((unsigned char *)z2) != 0) && (c++) < s) {
    while ((0xc0 & *++(z2)) == 0x80) {
    };
  }
  c = 0;
  while ((sqlite3ReadUtf8((unsigned char *)z2)) != 0) {
    zt1 = z1;
    zt2 = z2;
    do {
      c1 = sqlite3ReadUtf8((unsigned char *)zt1);
      c2 = sqlite3ReadUtf8((unsigned char *)zt2);
      while ((0xc0 & *++(zt1)) == 0x80) {
      };
      while ((0xc0 & *++(zt2)) == 0x80) {
      };
    } while (c1 == c2 && c1 != 0 && c2 != 0);
    if (c1 == 0) {
      rVal = c;
      break;
    }
    while ((0xc0 & *++(z2)) == 0x80) {
    };
    ++c;
  }
  if (p) {
    *p = z2;
  }
  return rVal >= 0 ? rVal + s : rVal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x3,%eax
  ja     L5
  mov    $0x386,%edi
  call   <close_gpio_channel@plt>
  mov    $0x37d,%edi
  call   <close_gpio_channel@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L5:
  nop
  nop
  leave
  ret
```

assistant: ```c
void signal_handler(int sig) {
  switch (sig) {
  case SIGTERM:
  case SIGHUP:
  case SIGQUIT:
  case SIGINT:
    close_gpio_channel(902);
    close_gpio_channel(893);
    exit(0);
  default:
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signal_handler>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x3,%edi
  jbe    L2
  ret
L2:
  sub    $0x8,%rsp
  mov    $0x386,%edi
  call   <close_gpio_channel@plt>
  mov    $0x37d,%edi
  call   <close_gpio_channel@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void signal_handler(int sig) {
  switch (sig) {
  case SIGTERM:
  case SIGHUP:
  case SIGQUIT:
  case SIGINT:
    close_gpio_channel(902);
    close_gpio_channel(893);
    exit(0);
  default:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<signal_handler>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x3,%edi
  jbe    L2
  ret
  nopl   (%rax)
L2:
  sub    $0x8,%rsp
  mov    $0x386,%edi
  call   <close_gpio_channel@plt>
  mov    $0x37d,%edi
  call   <close_gpio_channel@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void signal_handler(int sig) {
  switch (sig) {
  case SIGTERM:
  case SIGHUP:
  case SIGQUIT:
  case SIGINT:
    close_gpio_channel(902);
    close_gpio_channel(893);
    exit(0);
  default:
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<signal_handler>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x3,%edi
  jbe    L2
  ret
  nopl   (%rax)
L2:
  sub    $0x8,%rsp
  mov    $0x386,%edi
  call   <close_gpio_channel@plt>
  mov    $0x37d,%edi
  call   <close_gpio_channel@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void signal_handler(int sig) {
  switch (sig) {
  case SIGTERM:
  case SIGHUP:
  case SIGQUIT:
  case SIGINT:
    close_gpio_channel(902);
    close_gpio_channel(893);
    exit(0);
  default:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trasmetti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L33:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L7
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  jmp    L17
L7:
  mov    $0x1,%eax
  jmp    L49
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L33
  mov    $0x0,%eax
L49:
  leave
  ret
```

assistant: ```c
int trasmetti(int id_connessione, void *buffer, int dimensione) {
  int count = 0;
  int byte_scritti = 0;
  while (count < dimensione) {
    if ((byte_scritti = write(id_connessione, buffer, dimensione - count)) > 0) {
      count += byte_scritti;
      buffer += byte_scritti;
    } else
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<trasmetti>:
  endbr64
  test   %edx,%edx
  jle    L29
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0x0,%ebx
L2:
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L37
  add    %eax,%ebx
  cltq
  add    %rax,%rbp
  cmp    %ebx,%r12d
  jg     L2
  mov    $0x0,%eax
  jmp    L12
L29:
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int trasmetti(int id_connessione, void *buffer, int dimensione) {
  int count = 0;
  int byte_scritti = 0;
  while (count < dimensione) {
    if ((byte_scritti = write(id_connessione, buffer, dimensione - count)) > 0) {
      count += byte_scritti;
      buffer += byte_scritti;
    } else
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<trasmetti>:
  endbr64
  test   %edx,%edx
  jle    L3
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L30
  xchg   %ax,%ax
L34:
  add    %eax,%ebx
  cltq
  add    %rax,%r13
  cmp    %ebx,%ebp
  jle    L14
L30:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  sub    %ebx,%edx
  call   <write@plt>
  test   %eax,%eax
  jg     L34
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int trasmetti(int id_connessione, void *buffer, int dimensione) {
  int count = 0;
  int byte_scritti = 0;
  while (count < dimensione) {
    if ((byte_scritti = write(id_connessione, buffer, dimensione - count)) > 0) {
      count += byte_scritti;
      buffer += byte_scritti;
    } else
      return 1;
  }
  return 0;
}
```