user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x94(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x8c(%rbp)
  jmp    L41
L14:
  mov    -0x8c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x80(%rbp),%rdx
  mov    -0x8c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x8c(%rbp)
L41:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8c(%rbp),%xmm1
  movss  -0x94(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L14
  mov    $0x78,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x90(%rbp)
  movl   $0x0,-0x8c(%rbp)
  jmp    L15
L9:
  mov    -0x8c(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  mov    $0xffffffffffffffff,%rsi
  mov    %eax,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x90(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x90(%rbp)
  addl   $0x1,-0x8c(%rbp)
L15:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x8c(%rbp),%xmm1
  movss  -0x94(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L9
  movss  D27(%rip),%xmm0
  divss  -0x90(%rbp),%xmm0
  movss  %xmm0,-0x88(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x88(%rbp),%xmm2
  movq   %xmm2,%rdx
  mov    -0x8c(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x88(%rbp),%xmm1
  movss  D56(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x84(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x84(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd -0x88(%rbp),%xmm3
  movq   %xmm3,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string
name: disassemble_data
arguments: data_label: D48
datatype: string
name: disassemble_data
arguments: data_label: D58
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: byte[4]
name: disassemble_data
arguments: data_label: D77
datatype: string
name: disassemble_data
arguments: data_label: D56
datatype: f32
name: disassemble_data
arguments: data_label: D68
datatype: string

tool: D19: Kac tane musluk olacak: 

tool: D3: %f

tool: D48: %d. musluk kac saatte doldurur: 

tool: D58: %d

tool: D37: %lu

tool: {"D27": [0x00,0x00,0x80,0x3f]}

tool: D77: 
%d musluk %.3f saatte doldurur


tool: D56: 60

tool: D68: %.3f saat = %.3f dakika


assistant: ```c
int main() {
  float musluk, total, size;
  int i, adet[30];
  printf("Kac tane musluk olacak: ");
  scanf("%f", &size);
  for (i = 0; i < size; i++) {
    printf("%d. musluk kac saatte doldurur: ", i + 1);
    scanf("%d", &adet[i]);
  }
  printf("%lu", sizeof(adet));
  musluk = 0;
  for (i = 0; i < size; i++) {
    musluk += pow(adet[i], 0 - 1);
  }
  total = 1 / musluk;
  printf("\n%d musluk %.3f saatte doldurur\n", i, total);
  float dk = 60 * total;
  printf("%.3f saat = %.3f dakika\n", total, dk);
}
```