ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SFX_Playing>:
  endbr64
  sub    $0x8,%rsp
  test   $0x8000,%edi
  jne    L8
  call   <FX_SoundActive@plt>
L3:
  add    $0x8,%rsp
  ret
L8:
  and    $0x7fff,%edi
  call   <PCFX_SoundPlaying@plt>
  jmp    L3
```

assistant: ```c
int SFX_Playing(int handle) {
  if (handle & 0x8000) {
    return PCFX_SoundPlaying(handle & 0x7fff);
  }
  return FX_SoundActive(handle);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SFX_Playing>:
  endbr64
  test   $0x8000,%edi
  jne    L3
  jmp    1070 <FX_SoundActive@plt>
  nopl   0x0(%rax)
L3:
  and    $0x7fff,%edi
  jmp    1060 <PCFX_SoundPlaying@plt>
```

assistant: ```c
int SFX_Playing(int handle) {
  if (handle & 0x8000) {
    return PCFX_SoundPlaying(handle & 0x7fff);
  }
  return FX_SoundActive(handle);
}
```
user: What is the c source code of the assembly code below:

```asm
<SFX_Playing>:
  endbr64
  test   $0x8000,%edi
  jne    L4
  jmp    1070 <FX_SoundActive@plt>
  nopl   0x0(%rax)
L4:
  and    $0x7fff,%edi
  jmp    1060 <PCFX_SoundPlaying@plt>
```

assistant: ```c
int SFX_Playing(int handle) {
  if (handle & 0x8000) {
    return PCFX_SoundPlaying(handle & 0x7fff);
  }
  return FX_SoundActive(handle);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bot_quat_rotate>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movsd  (%rax),%xmm2
  movsd  0x8(%rax),%xmm1
  movapd %xmm2,%xmm5
  mulsd  %xmm1,%xmm5
  movsd  0x10(%rax),%xmm4
  movapd %xmm2,%xmm10
  mulsd  %xmm4,%xmm10
  movsd  0x18(%rax),%xmm6
  mulsd  %xmm6,%xmm2
  movq   D7(%rip),%xmm11
  movapd %xmm1,%xmm3
  xorpd  %xmm11,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm1,%xmm12
  mulsd  %xmm4,%xmm12
  mulsd  %xmm6,%xmm1
  movapd %xmm4,%xmm7
  xorpd  %xmm11,%xmm7
  mulsd  %xmm4,%xmm7
  mulsd  %xmm6,%xmm4
  xorpd  %xmm6,%xmm11
  mulsd  %xmm6,%xmm11
  movsd  (%rsi),%xmm9
  movsd  0x8(%rsi),%xmm8
  movsd  0x10(%rsi),%xmm6
  movapd %xmm7,%xmm0
  addsd  %xmm11,%xmm0
  mulsd  %xmm9,%xmm0
  movapd %xmm12,%xmm13
  subsd  %xmm2,%xmm13
  mulsd  %xmm8,%xmm13
  addsd  %xmm13,%xmm0
  movapd %xmm10,%xmm13
  addsd  %xmm1,%xmm13
  mulsd  %xmm6,%xmm13
  addsd  %xmm13,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm9,%xmm0
  movsd  %xmm0,(%rsp)
  addsd  %xmm12,%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm9,%xmm0
  addsd  %xmm3,%xmm11
  mulsd  %xmm8,%xmm11
  addsd  %xmm11,%xmm0
  movapd %xmm4,%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm6,%xmm2
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm8,%xmm0
  movsd  %xmm0,0x8(%rsp)
  subsd  %xmm10,%xmm1
  mulsd  %xmm9,%xmm1
  addsd  %xmm4,%xmm5
  mulsd  %xmm8,%xmm5
  addsd  %xmm5,%xmm1
  addsd  %xmm7,%xmm3
  mulsd  %xmm6,%xmm3
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm6,%xmm0
  movsd  %xmm0,0x10(%rsp)
  mov    %rsp,%rsi
  mov    $0x18,%edx
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: f32[2]

tool: {"D7": [0.0,-0.0]}

assistant: ```c
void bot_quat_rotate(const double rot[4], double v[3]) {
  double ab = rot[0] * rot[1], ac = rot[0] * rot[2], ad = rot[0] * rot[3];
  double nbb = -rot[1] * rot[1], bc = rot[1] * rot[2], bd = rot[1] * rot[3];
  double ncc = -rot[2] * rot[2], cd = rot[2] * rot[3], ndd = -rot[3] * rot[3];
  double result[] = {2 * ((ncc + ndd) * v[0] + (bc - ad) * v[1] + (ac + bd) * v[2]) + v[0], 2 * ((ad + bc) * v[0] + (nbb + ndd) * v[1] + (cd - ab) * v[2]) + v[1], 2 * ((bd - ac) * v[0] + (ab + cd) * v[1] + (nbb + ncc) * v[2]) + v[2]};
  memcpy(v, result, 3 * sizeof(double));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bot_quat_rotate>:
  endbr64
  mov    %rdi,%rax
  sub    $0x28,%rsp
  movsd  (%rsi),%xmm9
  mov    %rsi,%rdi
  movsd  0x10(%rax),%xmm4
  movsd  0x8(%rax),%xmm1
  movq   D0(%rip),%xmm11
  movsd  0x18(%rax),%xmm6
  movapd %xmm4,%xmm7
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm12
  xorpd  %xmm11,%xmm7
  xorpd  %xmm11,%xmm3
  xorpd  %xmm6,%xmm11
  movsd  0x8(%rsi),%xmm8
  mulsd  %xmm4,%xmm12
  movapd %xmm2,%xmm5
  movapd %xmm2,%xmm10
  mulsd  %xmm4,%xmm7
  mulsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm11
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mulsd  %xmm4,%xmm10
  mov    $0x18,%edx
  mulsd  %xmm1,%xmm5
  movapd %xmm12,%xmm13
  mulsd  %xmm1,%xmm3
  movapd %xmm7,%xmm0
  subsd  %xmm2,%xmm13
  mulsd  %xmm6,%xmm1
  addsd  %xmm12,%xmm2
  addsd  %xmm11,%xmm0
  mulsd  %xmm6,%xmm4
  movsd  0x10(%rsi),%xmm6
  mov    %rsp,%rsi
  mulsd  %xmm8,%xmm13
  mulsd  %xmm9,%xmm0
  addsd  %xmm3,%xmm11
  addsd  %xmm7,%xmm3
  mulsd  %xmm8,%xmm11
  mulsd  %xmm6,%xmm3
  addsd  %xmm13,%xmm0
  movapd %xmm10,%xmm13
  addsd  %xmm1,%xmm13
  subsd  %xmm10,%xmm1
  mulsd  %xmm6,%xmm13
  mulsd  %xmm9,%xmm1
  addsd  %xmm13,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm9,%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  movapd %xmm4,%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm9,%xmm0
  addsd  %xmm4,%xmm5
  mulsd  %xmm6,%xmm2
  mulsd  %xmm8,%xmm5
  addsd  %xmm11,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  addsd  %xmm8,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm6,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: f32[2]

tool: {"D0": [0.0,-0.0]}

assistant: ```c
void bot_quat_rotate(const double rot[4], double v[3]) {
  double ab = rot[0] * rot[1], ac = rot[0] * rot[2], ad = rot[0] * rot[3];
  double nbb = -rot[1] * rot[1], bc = rot[1] * rot[2], bd = rot[1] * rot[3];
  double ncc = -rot[2] * rot[2], cd = rot[2] * rot[3], ndd = -rot[3] * rot[3];
  double result[] = {2 * ((ncc + ndd) * v[0] + (bc - ad) * v[1] + (ac + bd) * v[2]) + v[0], 2 * ((ad + bc) * v[0] + (nbb + ndd) * v[1] + (cd - ab) * v[2]) + v[1], 2 * ((bd - ac) * v[0] + (ab + cd) * v[1] + (nbb + ncc) * v[2]) + v[2]};
  memcpy(v, result, 3 * sizeof(double));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bot_quat_rotate>:
  endbr64
  mov    %rdi,%rax
  sub    $0x28,%rsp
  movsd  (%rsi),%xmm9
  mov    %rsi,%rdi
  movsd  0x10(%rax),%xmm4
  movsd  0x8(%rax),%xmm1
  movq   D9(%rip),%xmm11
  movsd  0x18(%rax),%xmm6
  movapd %xmm4,%xmm7
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm12
  xorpd  %xmm11,%xmm7
  xorpd  %xmm11,%xmm3
  xorpd  %xmm6,%xmm11
  movsd  0x8(%rsi),%xmm8
  mulsd  %xmm4,%xmm12
  movapd %xmm2,%xmm5
  movapd %xmm2,%xmm10
  mulsd  %xmm4,%xmm7
  mulsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm11
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mulsd  %xmm4,%xmm10
  mov    $0x18,%edx
  mulsd  %xmm1,%xmm5
  movapd %xmm12,%xmm13
  mulsd  %xmm1,%xmm3
  movapd %xmm7,%xmm0
  subsd  %xmm2,%xmm13
  mulsd  %xmm6,%xmm1
  addsd  %xmm12,%xmm2
  addsd  %xmm11,%xmm0
  mulsd  %xmm6,%xmm4
  movsd  0x10(%rsi),%xmm6
  mov    %rsp,%rsi
  mulsd  %xmm8,%xmm13
  mulsd  %xmm9,%xmm0
  addsd  %xmm3,%xmm11
  addsd  %xmm7,%xmm3
  mulsd  %xmm8,%xmm11
  mulsd  %xmm6,%xmm3
  addsd  %xmm13,%xmm0
  movapd %xmm10,%xmm13
  addsd  %xmm1,%xmm13
  subsd  %xmm10,%xmm1
  mulsd  %xmm6,%xmm13
  mulsd  %xmm9,%xmm1
  addsd  %xmm13,%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm9,%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  movapd %xmm4,%xmm2
  subsd  %xmm5,%xmm2
  mulsd  %xmm9,%xmm0
  addsd  %xmm4,%xmm5
  mulsd  %xmm6,%xmm2
  mulsd  %xmm8,%xmm5
  addsd  %xmm11,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  addsd  %xmm8,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm6,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: f32[2]

tool: {"D9": [0.0,-0.0]}

assistant: ```c
void bot_quat_rotate(const double rot[4], double v[3]) {
  double ab = rot[0] * rot[1], ac = rot[0] * rot[2], ad = rot[0] * rot[3];
  double nbb = -rot[1] * rot[1], bc = rot[1] * rot[2], bd = rot[1] * rot[3];
  double ncc = -rot[2] * rot[2], cd = rot[2] * rot[3], ndd = -rot[3] * rot[3];
  double result[] = {2 * ((ncc + ndd) * v[0] + (bc - ad) * v[1] + (ac + bd) * v[2]) + v[0], 2 * ((ad + bc) * v[0] + (nbb + ndd) * v[1] + (cd - ab) * v[2]) + v[1], 2 * ((bd - ac) * v[0] + (ab + cd) * v[1] + (nbb + ncc) * v[2]) + v[2]};
  memcpy(v, result, 3 * sizeof(double));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hashstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  imul   $0x43,%eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  sub    $0x71,%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L9
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hashstr(str, len) const char *str;
unsigned int len;
{
  unsigned int n = len;
  unsigned int r = 0;
  const unsigned char *s = (const unsigned char *)str;
  do
    r = r * 67 + (*s++ - 113);
  while (--n);
  return r + len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hashstr>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0x0,%edx
L5:
  add    $0x1,%rdi
  imul   $0x43,%edx,%edx
  movzbl -0x1(%rdi),%ecx
  lea    -0x71(%rdx,%rcx,1),%edx
  cmp    %r8,%rdi
  jne    L5
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
unsigned int hashstr(str, len) const char *str;
unsigned int len;
{
  unsigned int n = len;
  unsigned int r = 0;
  const unsigned char *s = (const unsigned char *)str;
  do
    r = r * 67 + (*s++ - 113);
  while (--n);
  return r + len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hashstr>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  lea    0x1(%rdi,%rax,1),%r8
  xchg   %ax,%ax
L9:
  imul   $0x43,%edx,%edx
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  lea    -0x71(%rdx,%rcx,1),%edx
  cmp    %r8,%rdi
  jne    L9
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
unsigned int hashstr(str, len) const char *str;
unsigned int len;
{
  unsigned int n = len;
  unsigned int r = 0;
  const unsigned char *s = (const unsigned char *)str;
  do
    r = r * 67 + (*s++ - 113);
  while (--n);
  return r + len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hashstr>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  lea    0x1(%rdi,%rax,1),%r8
  xchg   %ax,%ax
L9:
  imul   $0x43,%edx,%edx
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  lea    -0x71(%rdx,%rcx,1),%edx
  cmp    %r8,%rdi
  jne    L9
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
unsigned int hashstr(str, len) const char *str;
unsigned int len;
{
  unsigned int n = len;
  unsigned int r = 0;
  const unsigned char *s = (const unsigned char *)str;
  do
    r = r * 67 + (*s++ - 113);
  while (--n);
  return r + len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flsll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L6
L10:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%edx
  bsr    -0x8(%rbp),%rax
  xor    $0x3f,%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int flsll(long long i) {
  if (i == 0)
    return 0;
  return (sizeof(i) * CHAR_BIT - __builtin_clzll(i));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<flsll>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L8
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  shl    $0x3,%eax
  sub    %edi,%eax
L8:
  ret
```

assistant: ```c
int flsll(long long i) {
  if (i == 0)
    return 0;
  return (sizeof(i) * CHAR_BIT - __builtin_clzll(i));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flsll>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  mov    D7(%rip),%rax
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  mov    (%rax),%eax
  shl    $0x3,%eax
  sub    %edi,%eax
L8:
  ret
```

assistant: ```c
int flsll(long long i) {
  if (i == 0)
    return 0;
  return (sizeof(i) * CHAR_BIT - __builtin_clzll(i));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flsll>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  mov    D6(%rip),%rax
  bsr    %rdi,%rdi
  xor    $0x3f,%rdi
  mov    (%rax),%eax
  shl    $0x3,%eax
  sub    %edi,%eax
L4:
  ret
```

assistant: ```c
int flsll(long long i) {
  if (i == 0)
    return 0;
  return (sizeof(i) * CHAR_BIT - __builtin_clzll(i));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L6:
  movl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L14:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: r

assistant: ```c
int testfile(char *file) {
  FILE *f;
  int flag;
  if ((f = fopen(file, "r")) == NULL) {
    flag = 0;
  } else {
    flag = 1;
    fclose(f);
  }
  return flag;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testfile>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L4
  call   <fclose@plt>
  mov    $0x1,%eax
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: r

assistant: ```c
int testfile(char *file) {
  FILE *f;
  int flag;
  if ((f = fopen(file, "r")) == NULL) {
    flag = 0;
  } else {
    flag = 1;
    fclose(f);
  }
  return flag;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testfile>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  call   <fclose@plt>
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: r

assistant: ```c
int testfile(char *file) {
  FILE *f;
  int flag;
  if ((f = fopen(file, "r")) == NULL) {
    flag = 0;
  } else {
    flag = 1;
    fclose(f);
  }
  return flag;
}
```
user: What is the c source code of the assembly code below:

```asm
<testfile>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  call   <fclose@plt>
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: r

assistant: ```c
int testfile(char *file) {
  FILE *f;
  int flag;
  if ((f = fopen(file, "r")) == NULL) {
    flag = 0;
  } else {
    flag = 1;
    fclose(f);
  }
  return flag;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<USBHostEndpointPing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L2
  mov    $0x40050103,%eax
  mov    (%rax),%eax
  mov    $0x40050103,%edx
  and    $0xfffffff7,%eax
  mov    %eax,(%rdx)
  jmp    L4
L2:
  mov    $0x40050103,%eax
  mov    (%rax),%eax
  mov    $0x40050103,%edx
  or     $0x8,%eax
  mov    %eax,(%rdx)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBHostEndpointPing(uint32_t ui32Base, uint32_t ui32Endpoint, bool bEnable) {
  ;
  ;
  if (bEnable) {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) &= ~0x00000008;
  } else {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) |= 0x00000008;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<USBHostEndpointPing>:
  endbr64
  test   %edx,%edx
  je     L4
  mov    0x40050103,%eax
  and    $0xfffffff7,%eax
  mov    %eax,0x40050103
  ret
L4:
  mov    0x40050103,%eax
  or     $0x8,%eax
  mov    %eax,0x40050103
  ret
```

assistant: ```c
void USBHostEndpointPing(uint32_t ui32Base, uint32_t ui32Endpoint, bool bEnable) {
  ;
  ;
  if (bEnable) {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) &= ~0x00000008;
  } else {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) |= 0x00000008;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBHostEndpointPing>:
  endbr64
  mov    0x40050103,%eax
  test   %edx,%edx
  je     L1
  and    $0xfffffff7,%eax
  mov    %eax,0x40050103
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  or     $0x8,%eax
  mov    %eax,0x40050103
  ret
```

assistant: ```c
void USBHostEndpointPing(uint32_t ui32Base, uint32_t ui32Endpoint, bool bEnable) {
  ;
  ;
  if (bEnable) {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) &= ~0x00000008;
  } else {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) |= 0x00000008;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<USBHostEndpointPing>:
  endbr64
  mov    0x40050103,%eax
  test   %edx,%edx
  je     L0
  and    $0xfffffff7,%eax
  mov    %eax,0x40050103
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  or     $0x8,%eax
  mov    %eax,0x40050103
  ret
```

assistant: ```c
void USBHostEndpointPing(uint32_t ui32Base, uint32_t ui32Endpoint, bool bEnable) {
  ;
  ;
  if (bEnable) {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) &= ~0x00000008;
  } else {
    (*((volatile uint8_t *)(0x40050000 + 0x00000103))) |= 0x00000008;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <do_mesg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0xff,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatal(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  do_mesg(LOG_ERR, fmt, args);
  va_end(args);
  _exit(255);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fatal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <do_mesg@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xff,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fatal(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  do_mesg(LOG_ERR, fmt, args);
  va_end(args);
  _exit(255);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <do_mesg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0xff,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fatal(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  do_mesg(LOG_ERR, fmt, args);
  va_end(args);
  _exit(255);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <do_mesg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0xff,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fatal(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  do_mesg(LOG_ERR, fmt, args);
  va_end(args);
  _exit(255);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Athena_Private_DestroyHandle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L5
L15:
  mov    $0xffffffff,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int Athena_Private_DestroyHandle(void *x) {
  if (x == 1)
    return 0;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Athena_Private_DestroyHandle>:
  endbr64
  cmp    $0x1,%rdi
  setne  %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int Athena_Private_DestroyHandle(void *x) {
  if (x == 1)
    return 0;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Athena_Private_DestroyHandle>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%rdi
  setne  %al
  neg    %eax
  ret
```

assistant: ```c
int Athena_Private_DestroyHandle(void *x) {
  if (x == 1)
    return 0;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Athena_Private_DestroyHandle>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%rdi
  setne  %al
  neg    %eax
  ret
```

assistant: ```c
int Athena_Private_DestroyHandle(void *x) {
  if (x == 1)
    return 0;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quat_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  add    %rax,%rbx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  add    %rax,%rbx
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0x14(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  divss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  divss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  divss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void quat_normalize(float *quat) {
  float norm = sqrt(pow(*((float *)(quat)), 2) + pow(*((float *)(quat + 1)), 2) + pow(*((float *)(quat + 2)), 2) + pow(*((float *)(quat + 3)), 2));
  *quat = *quat / norm;
  *(quat + 1) = *(quat + 1) / norm;
  *(quat + 2) = *(quat + 2) / norm;
  *(quat + 3) = *(quat + 3) / norm;
}
```