ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp_a>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stringLength_a@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <stringLength_a@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebx
  jne    L49
  test   %ebx,%ebx
  jle    L48
  movslq %ebx,%rax
  xor    %edx,%edx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L48
L42:
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%rbp,%rdx,1)
  je     L8
  xor    %eax,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: string1 = %s 	 string2 = %s 


assistant: ```c
int strcmp_a(char str1[], char str2[]) {
  printf("string1 = %s \t string2 = %s \n", str1, str2);
  int str1Length = stringLength_a(str1);
  int str2Length = stringLength_a(str2);
  int index = 0;
  int result = 0;
  if (str1Length != str2Length) {
    return result;
  } else {
    while (index < str1Length) {
      if (str1[index] != str2[index]) {
        return result;
      } else {
        index++;
      }
    }
  }
  result = 1;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp_a>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stringLength_a@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <stringLength_a@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebx
  jne    L47
  test   %ebx,%ebx
  jle    L43
  movslq %ebx,%rax
  xor    %edx,%edx
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L43
L48:
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%rbp,%rdx,1)
  je     L21
  xor    %eax,%eax
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: string1 = %s 	 string2 = %s 


assistant: ```c
int strcmp_a(char str1[], char str2[]) {
  printf("string1 = %s \t string2 = %s \n", str1, str2);
  int str1Length = stringLength_a(str1);
  int str2Length = stringLength_a(str2);
  int index = 0;
  int result = 0;
  if (str1Length != str2Length) {
    return result;
  } else {
    while (index < str1Length) {
      if (str1[index] != str2[index]) {
        return result;
      } else {
        index++;
      }
    }
  }
  result = 1;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<write_and_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
L14:
  mov    $0x0,%eax
  jmp    L17
L23:
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <chksum@plt>
L17:
  leave
  ret
```

assistant: ```c
int write_and_sum(void *dat, int size, FILE *f) {
  if (dat == 0 || size == 0)
    return 0;
  fwrite(dat, size, 1, f);
  return chksum(dat, size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_and_sum>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%eax
  test   %esi,%esi
  je     L19
  mov    %rdx,%rcx
  mov    $0x1,%edx
  call   <fwrite@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <chksum@plt>
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int write_and_sum(void *dat, int size, FILE *f) {
  if (dat == 0 || size == 0)
    return 0;
  fwrite(dat, size, 1, f);
  return chksum(dat, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_and_sum>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L12
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rdi,%rbp
  call   <fwrite@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <chksum@plt>
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_and_sum(void *dat, int size, FILE *f) {
  if (dat == 0 || size == 0)
    return 0;
  fwrite(dat, size, 1, f);
  return chksum(dat, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_and_sum>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L18
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rdi,%rbp
  call   <fwrite@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <chksum@plt>
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_and_sum(void *dat, int size, FILE *f) {
  if (dat == 0 || size == 0)
    return 0;
  fwrite(dat, size, 1, f);
  return chksum(dat, size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prv_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x120(%rbp)
  cmpq   $0x0,-0x120(%rbp)
  je     L39
  mov    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  jmp    L69
L39:
  movq   $0x0,-0x128(%rbp)
  mov    -0x138(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rcx
  lea    D2(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jne    L14
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,-0x110(%rbp,%rax,1)
L14:
  lea    -0x110(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x128(%rbp)
  jmp    L27
L16:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L52
  mov    -0x128(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x110(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    -0x128(%rbp),%rax
  movb   $0x2f,(%rax)
L52:
  addq   $0x1,-0x128(%rbp)
L27:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  lea    -0x110(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L69:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: %s

assistant: ```c
void prv_mkdir(const char *dir) {
  DIR *_dir = opendir(dir);
  if (_dir) {
    closedir(_dir);
    return;
  }
  char tmp[256];
  char *p = NULL;
  size_t len;
  snprintf(tmp, sizeof(tmp), "%s", dir);
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = 0;
  for (p = tmp + 1; *p; p++) {
    if (*p == '/') {
      *p = 0;
      mkdir(tmp, 0777);
      *p = '/';
    }
  }
  mkdir(tmp, 0777);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prv_mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L71
  mov    %rax,%rdi
  call   <closedir@plt>
L94:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L71:
  mov    %rsp,%rbp
  mov    %rbx,%rcx
  lea    D3(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  je     L37
L48:
  movzbl 0x1(%rsp),%eax
  test   %al,%al
  je     L95
  lea    0x1(%rsp),%rbx
  mov    %rsp,%rbp
  jmp    L40
L37:
  movb   $0x0,-0x1(%rsp,%rax,1)
  jmp    L48
L11:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L95
L40:
  cmp    $0x2f,%al
  jne    L11
  movb   $0x0,(%rbx)
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  movb   $0x2f,(%rbx)
  jmp    L11
L95:
  mov    %rsp,%rdi
  mov    $0x1ff,%esi
  call   <mkdir@plt>
  jmp    L94
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: %s

assistant: ```c
void prv_mkdir(const char *dir) {
  DIR *_dir = opendir(dir);
  if (_dir) {
    closedir(_dir);
    return;
  }
  char tmp[256];
  char *p = NULL;
  size_t len;
  snprintf(tmp, sizeof(tmp), "%s", dir);
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = 0;
  for (p = tmp + 1; *p; p++) {
    if (*p == '/') {
      *p = 0;
      mkdir(tmp, 0777);
      *p = '/';
    }
  }
  mkdir(tmp, 0777);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prv_mkdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L72
  mov    %rax,%rdi
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <closedir@plt>
  nopl   0x0(%rax)
L72:
  mov    %rsp,%rbp
  mov    %r12,%rcx
  mov    $0x100,%esi
  lea    D0(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  jne    L49
  movb   $0x0,-0x1(%rsp,%rax,1)
L49:
  movzbl 0x1(%rsp),%eax
  test   %al,%al
  je     L70
  lea    0x1(%rsp),%rbx
  jmp    L45
  xchg   %ax,%ax
L74:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L70
L45:
  cmp    $0x2f,%al
  jne    L74
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  movb   $0x0,(%rbx)
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x2f,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L45
  nop
L70:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: %s

assistant: ```c
void prv_mkdir(const char *dir) {
  DIR *_dir = opendir(dir);
  if (_dir) {
    closedir(_dir);
    return;
  }
  char tmp[256];
  char *p = NULL;
  size_t len;
  snprintf(tmp, sizeof(tmp), "%s", dir);
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = 0;
  for (p = tmp + 1; *p; p++) {
    if (*p == '/') {
      *p = 0;
      mkdir(tmp, 0777);
      *p = '/';
    }
  }
  mkdir(tmp, 0777);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prv_mkdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L58
  mov    %rax,%rdi
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <closedir@plt>
  nopl   0x0(%rax)
L58:
  mov    %rsp,%rbp
  mov    %r12,%rcx
  mov    $0x100,%esi
  lea    D2(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  jne    L26
  movb   $0x0,-0x1(%rsp,%rax,1)
L26:
  movzbl 0x1(%rsp),%eax
  test   %al,%al
  je     L71
  lea    0x1(%rsp),%rbx
  nopl   0x0(%rax)
L9:
  cmp    $0x2f,%al
  je     L4
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L9
L71:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  movb   $0x0,(%rbx)
  add    $0x1,%rbx
  call   <mkdir@plt>
  movb   $0x2f,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L9
  jmp    L71
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %s

assistant: ```c
void prv_mkdir(const char *dir) {
  DIR *_dir = opendir(dir);
  if (_dir) {
    closedir(_dir);
    return;
  }
  char tmp[256];
  char *p = NULL;
  size_t len;
  snprintf(tmp, sizeof(tmp), "%s", dir);
  len = strlen(tmp);
  if (tmp[len - 1] == '/')
    tmp[len - 1] = 0;
  for (p = tmp + 1; *p; p++) {
    if (*p == '/') {
      *p = 0;
      mkdir(tmp, 0777);
      *p = '/';
    }
  }
  mkdir(tmp, 0777);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<word2num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    $0xff,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L19:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int word2num(char *word) {
  int length = 0, num = 0, bit = 0, i = 0, l = 0;
  length = (int)strlen(word);
  num = 0xFF - (0x01 << length);
  for (i = 0, l = length; i < l; i++) {
    bit = (word[i] == '.') ? 1 : 0;
    num -= (bit << (length - i - 1));
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<word2num>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%edx
  mov    $0xff,%eax
  sub    %edx,%eax
  test   %ecx,%ecx
  jle    L13
  lea    -0x1(%rcx),%edx
  lea    0x1(%rbx,%rdx,1),%r8
  mov    %rbx,%rdx
  lea    -0x1(%rbx,%rcx,1),%edi
L2:
  cmpb   $0x2e,(%rdx)
  sete   %sil
  movzbl %sil,%esi
  mov    %edi,%ecx
  sub    %edx,%ecx
  shl    %cl,%esi
  sub    %esi,%eax
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L2
L13:
  pop    %rbx
  ret
```

assistant: ```c
int word2num(char *word) {
  int length = 0, num = 0, bit = 0, i = 0, l = 0;
  length = (int)strlen(word);
  num = 0xFF - (0x01 << length);
  for (i = 0, l = length; i < l; i++) {
    bit = (word[i] == '.') ? 1 : 0;
    num -= (bit << (length - i - 1));
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<word2num>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%edx
  mov    $0xff,%eax
  sub    %edx,%eax
  test   %ecx,%ecx
  jle    L6
  lea    -0x1(%rcx),%edx
  mov    %rbx,%rdi
  lea    -0x1(%rbx,%rcx,1),%esi
  lea    0x1(%rbx,%rdx,1),%r8
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %edx,%edx
  mov    %esi,%ecx
  cmpb   $0x2e,(%rdi)
  sete   %dl
  sub    %edi,%ecx
  add    $0x1,%rdi
  shl    %cl,%edx
  sub    %edx,%eax
  cmp    %r8,%rdi
  jne    L0
L6:
  pop    %rbx
  ret
```

assistant: ```c
int word2num(char *word) {
  int length = 0, num = 0, bit = 0, i = 0, l = 0;
  length = (int)strlen(word);
  num = 0xFF - (0x01 << length);
  for (i = 0, l = length; i < l; i++) {
    bit = (word[i] == '.') ? 1 : 0;
    num -= (bit << (length - i - 1));
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<word2num>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%edx
  mov    $0xff,%eax
  sub    %edx,%eax
  test   %ecx,%ecx
  jle    L13
  lea    -0x1(%rcx),%edx
  mov    %rbx,%rdi
  lea    -0x1(%rbx,%rcx,1),%esi
  lea    0x1(%rbx,%rdx,1),%r8
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %edx,%edx
  mov    %esi,%ecx
  cmpb   $0x2e,(%rdi)
  sete   %dl
  sub    %edi,%ecx
  add    $0x1,%rdi
  shl    %cl,%edx
  sub    %edx,%eax
  cmp    %rdi,%r8
  jne    L2
L13:
  pop    %rbx
  ret
```

assistant: ```c
int word2num(char *word) {
  int length = 0, num = 0, bit = 0, i = 0, l = 0;
  length = (int)strlen(word);
  num = 0xFF - (0x01 << length);
  for (i = 0, l = length; i < l; i++) {
    bit = (word[i] == '.') ? 1 : 0;
    num -= (bit << (length - i - 1));
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L30
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L46
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L63
L46:
  lea    -0x10(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x6,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L63
L30:
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L20
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  shl    $0x2,%rax
  and    $0x18,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L63
L20:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%rax
  imul   $0x49c8729f,%rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
      } else {
        copy11 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 6);
        *((char *)(&state[0UL]) + 6) = copy11;
      }
    } else if (state[0UL] & 1UL) {
      state[0UL] |= ((state[0UL] + state[0UL]) & 7UL) << 2UL;
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 1237873311UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rax
  lea    -0x17447d68(%rax),%rdx
  test   $0x8,%al
  jne    L49
  test   $0x1,%dl
  je     L21
  mov    %rdx,%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rdx,%rax
L32:
  imul   $0x49c8729f,%rax,%rax
  mov    %rax,(%rcx)
  ret
L21:
  mov    %rdx,%rsi
  shl    $0x8,%rsi
  shr    $0x38,%rsi
  shl    $0x38,%rsi
  movabs $0xffffffffffffff,%rax
  and    %rdx,%rax
  or     %rsi,%rax
  shr    $0x38,%rdx
  shl    $0x30,%rdx
  movabs $0xff00ffffffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  jmp    L32
L49:
  lea    (%rdx,%rdx,1),%rax
  test   $0x1,%dl
  je     L32
  lea    0x0(,%rdx,8),%rax
  and    $0x18,%eax
  or     %rdx,%rax
  jmp    L32
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
      } else {
        copy11 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 6);
        *((char *)(&state[0UL]) + 6) = copy11;
      }
    } else if (state[0UL] & 1UL) {
      state[0UL] |= ((state[0UL] + state[0UL]) & 7UL) << 2UL;
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 1237873311UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rcx
  mov    %rax,%rsi
  lea    -0x17447d68(%rax),%rdx
  and    $0x1,%esi
  test   $0x8,%al
  jne    L14
  test   %rsi,%rsi
  je     L6
  mov    %rdx,%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rdx,%rax
L28:
  imul   $0x49c8729f,%rax,%rax
  mov    %rax,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  lea    (%rdx,%rdx,1),%rax
  test   %rsi,%rsi
  je     L28
  lea    0x0(,%rdx,8),%rax
  and    $0x18,%eax
  or     %rdx,%rax
  imul   $0x49c8729f,%rax,%rax
  mov    %rax,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movabs $0xffffffffffffff,%rax
  mov    %rdx,%rsi
  shl    $0x8,%rsi
  and    %rdx,%rax
  shr    $0x38,%rdx
  shr    $0x38,%rsi
  shl    $0x30,%rdx
  shl    $0x38,%rsi
  or     %rsi,%rax
  movabs $0xff00ffffffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  imul   $0x49c8729f,%rax,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
      } else {
        copy11 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 6);
        *((char *)(&state[0UL]) + 6) = copy11;
      }
    } else if (state[0UL] & 1UL) {
      state[0UL] |= ((state[0UL] + state[0UL]) & 7UL) << 2UL;
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 1237873311UL;
  }
}
```