ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  mov    (%rsi),%edx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   *%rbx
  add    $0x8,%rsp
  lea    D13(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string

tool: D6: 
in f2 getted pointer p2 = %p, and * p2 = %d;


tool: D13: end of f2;


assistant: ```c
void f2(void f_p(int *), int *p2) {
  printf("\nin f2 getted pointer p2 = %p, and * p2 = %d;\n", p2, *p2);
  f_p(p2);
  printf("end of f2;\n\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  mov    (%rsi),%edx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   *%rbx
  add    $0x8,%rsp
  lea    D10(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D6: 
in f2 getted pointer p2 = %p, and * p2 = %d;


tool: D10: end of f2;


assistant: ```c
void f2(void f_p(int *), int *p2) {
  printf("\nin f2 getted pointer p2 = %p, and * p2 = %d;\n", p2, *p2);
  f_p(p2);
  printf("end of f2;\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isValidConjecture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L16
L9:
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L19:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  mov    $0x1,%eax
  jmp    L16
L0:
  addl   $0x1,-0x24(%rbp)
L11:
  cmpl   $0x1,-0x24(%rbp)
  jle    L19
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D11
type: string

tool: D18: AND

tool: D11: OR

assistant: ```c
bool isValidConjecture(char *con) {
  int i;
  char *conjecture[2] = {"AND", "OR"};
  if (con == NULL)
    return false;
  for (i = 0; i < 2; i++) {
    if ((strcmp(conjecture[i], con) == 0))
      return true;
  }
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isValidConjecture>:
  endbr64
  test   %rdi,%rdi
  je     L19
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L30
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L30
L25:
  pop    %rbx
  ret
L30:
  mov    $0x1,%eax
  jmp    L25
L19:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D3: AND

tool: D6: OR

assistant: ```c
bool isValidConjecture(char *con) {
  int i;
  char *conjecture[2] = {"AND", "OR"};
  if (con == NULL)
    return false;
  for (i = 0; i < 2; i++) {
    if ((strcmp(conjecture[i], con) == 0))
      return true;
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isValidConjecture>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D15(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D15: AND

tool: D0: OR

assistant: ```c
bool isValidConjecture(char *con) {
  int i;
  char *conjecture[2] = {"AND", "OR"};
  if (con == NULL)
    return false;
  for (i = 0; i < 2; i++) {
    if ((strcmp(conjecture[i], con) == 0))
      return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isValidConjecture>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L14
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: string

tool: D0: AND

tool: D11: OR

assistant: ```c
bool isValidConjecture(char *con) {
  int i;
  char *conjecture[2] = {"AND", "OR"};
  if (con == NULL)
    return false;
  for (i = 0; i < 2; i++) {
    if ((strcmp(conjecture[i], con) == 0))
      return true;
  }
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matchdot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int matchdot(char c) {
  (void)c;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matchdot>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int matchdot(char c) {
  (void)c;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matchdot>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int matchdot(char c) {
  (void)c;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matchdot>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int matchdot(char c) {
  (void)c;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D30
type: string
name: disassemble_data
arguments: tag: D42
type: string
name: disassemble_data
arguments: tag: D52
type: string
name: disassemble_data
arguments: tag: D41
type: string
name: disassemble_data
arguments: tag: D26
type: string
name: disassemble_data
arguments: tag: D40
type: string
name: disassemble_data
arguments: tag: D28
type: string

tool: D30: MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)

tool: D42: or destination files (which have to be created if they do not exist, otherwise they will be overwritten).

tool: D52: Usage examples:

tool: D41: mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2

tool: D26: mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time

tool: D40: If the parameter -- is used each element after it will be considered as a filename

tool: D28: Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2

assistant: ```c
void usage(const char *msg) {
  if (msg != NULL) {
    printf("\n");
    printf("%s\n", msg);
    printf("\n");
  }
  printf("\n");
  printf("MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)\n");
  printf("or destination files (which have to be created if they do not exist, otherwise they will be overwritten).\n");
  printf("\n");
  printf("Usage examples:\n");
  printf("mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2\n");
  printf("mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time\n");
  printf("\n");
  printf("If the parameter -- is used each element after it will be considered as a filename\n");
  printf("Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2\n");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    D61(%rip),%rdi
  call   <puts@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D47
type: string
name: retrieve_data
arguments: label: D61
type: string
name: retrieve_data
arguments: label: D64
type: string
name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D14
type: string

tool: D28: MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)

tool: D8: or destination files (which have to be created if they do not exist, otherwise they will be overwritten).

tool: D47: Usage examples:

tool: D61: mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2

tool: D64: mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time

tool: D10: If the parameter -- is used each element after it will be considered as a filename

tool: D14: Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2

assistant: ```c
void usage(const char *msg) {
  if (msg != NULL) {
    printf("\n");
    printf("%s\n", msg);
    printf("\n");
  }
  printf("\n");
  printf("MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)\n");
  printf("or destination files (which have to be created if they do not exist, otherwise they will be overwritten).\n");
  printf("\n");
  printf("Usage examples:\n");
  printf("mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2\n");
  printf("mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time\n");
  printf("\n");
  printf("If the parameter -- is used each element after it will be considered as a filename\n");
  printf("Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2\n");
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D37
data_type: string
name: disassemble_data
arguments: data_tag: D32
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D24: MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)

tool: D20: or destination files (which have to be created if they do not exist, otherwise they will be overwritten).

tool: D37: Usage examples:

tool: D32: mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2

tool: D29: mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time

tool: D6: If the parameter -- is used each element after it will be considered as a filename

tool: D3: Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2

assistant: ```c
void usage(const char *msg) {
  if (msg != NULL) {
    printf("\n");
    printf("%s\n", msg);
    printf("\n");
  }
  printf("\n");
  printf("MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)\n");
  printf("or destination files (which have to be created if they do not exist, otherwise they will be overwritten).\n");
  printf("\n");
  printf("Usage examples:\n");
  printf("mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2\n");
  printf("mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time\n");
  printf("\n");
  printf("If the parameter -- is used each element after it will be considered as a filename\n");
  printf("Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2\n");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D27
data_type: string
name: retrieve_data
arguments: tag: D55
data_type: string
name: retrieve_data
arguments: tag: D42
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string

tool: D21: MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)

tool: D8: or destination files (which have to be created if they do not exist, otherwise they will be overwritten).

tool: D28: Usage examples:

tool: D27: mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2

tool: D55: mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time

tool: D42: If the parameter -- is used each element after it will be considered as a filename

tool: D13: Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2

assistant: ```c
void usage(const char *msg) {
  if (msg != NULL) {
    printf("\n");
    printf("%s\n", msg);
    printf("\n");
  }
  printf("\n");
  printf("MultiCopy (mcp) copies a single file to a specified set of destination directories (which have to exist)\n");
  printf("or destination files (which have to be created if they do not exist, otherwise they will be overwritten).\n");
  printf("\n");
  printf("Usage examples:\n");
  printf("mcp file1 dest1 dest2 : copy file1 to both dest1 and dest2\n");
  printf("mcp -b 2048 file1 dest1 dest2: copy file1 to both dest1 and dest2 reading 2048 bytes at time\n");
  printf("\n");
  printf("If the parameter -- is used each element after it will be considered as a filename\n");
  printf("Example: mcp -- -b dest1 dest2 : copy a file named -b to dest1 and to dest2\n");
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
L59:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  movsbl -0x12(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L64
  mov    $0x0,%eax
  jmp    L51
L64:
  addq   $0x1,-0x28(%rbp)
  movsbl -0x12(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x12(%rbp)
  movzbl -0x12(%rbp),%eax
  cmp    -0x13(%rbp),%al
  jne    L82
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L43:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L57
  mov    $0x1,%eax
  jmp    L51
L57:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x12(%rbp)
  addq   $0x1,-0x8(%rbp)
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jne    L28
  jmp    L43
L82:
  nop
  jmp    L59
L28:
  nop
  jmp    L59
L51:
  leave
  ret
```

assistant: ```c
int match(const char *line, const char *sender) {
  char ch, pch, first;
  const char *p, *t;
  for (first = *sender++;;) {
    if (isspace(ch = *line))
      return (0);
    ++line;
    ch = tolower(ch);
    if (ch != first)
      continue;
    for (p = sender, t = line;;) {
      if (!(pch = *p++))
        return (1);
      ch = tolower(*t);
      t++;
      if (ch != pch)
        break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<match>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    0x1(%rsi),%r15
  movzbl (%rsi),%r14d
L54:
  movsbl 0x0(%r13),%ebx
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  add    $0x1,%r13
  mov    %ebx,%edi
  call   <tolower@plt>
  cmp    %al,%r14b
  jne    L54
  mov    %r13,%r12
  mov    %r15,%rbx
L3:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ebp
  test   %bpl,%bpl
  je     L55
  movsbl (%r12),%edi
  call   <tolower@plt>
  add    $0x1,%r12
  cmp    %al,%bpl
  je     L3
  jmp    L54
L14:
  mov    $0x0,%eax
  jmp    L59
L55:
  mov    $0x1,%eax
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int match(const char *line, const char *sender) {
  char ch, pch, first;
  const char *p, *t;
  for (first = *sender++;;) {
    if (isspace(ch = *line))
      return (0);
    ++line;
    ch = tolower(ch);
    if (ch != first)
      continue;
    for (p = sender, t = line;;) {
      if (!(pch = *p++))
        return (1);
      ch = tolower(*t);
      t++;
      if (ch != pch)
        break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<match>:
  endbr64
  push   %r15
  lea    0x1(%rsi),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r14d
  nopl   (%rax)
L48:
  movsbl 0x0(%r13),%ebp
  mov    %ebp,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    %ebp,%edi
  add    $0x1,%r13
  call   <tolower@plt>
  cmp    %al,%r14b
  jne    L48
  mov    %r13,%r12
  mov    %r15,%rbx
  jmp    L39
  nopl   0x0(%rax)
L37:
  movsbl (%r12),%edi
  add    $0x1,%r12
  call   <tolower@plt>
  cmp    %al,%bpl
  jne    L48
L39:
  movzbl (%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  jne    L37
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int match(const char *line, const char *sender) {
  char ch, pch, first;
  const char *p, *t;
  for (first = *sender++;;) {
    if (isspace(ch = *line))
      return (0);
    ++line;
    ch = tolower(ch);
    if (ch != first)
      continue;
    for (p = sender, t = line;;) {
      if (!(pch = *p++))
        return (1);
      ch = tolower(*t);
      t++;
      if (ch != pch)
        break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<match>:
  endbr64
  push   %r15
  lea    0x1(%rsi),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r14d
  nopl   (%rax)
L38:
  movsbl 0x0(%r13),%ebp
  mov    %ebp,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  mov    %ebp,%edi
  add    $0x1,%r13
  call   <tolower@plt>
  cmp    %al,%r14b
  jne    L38
  mov    %r13,%r12
  mov    %r15,%rbx
  jmp    L32
  nopl   0x0(%rax)
L47:
  movsbl (%r12),%edi
  add    $0x1,%r12
  call   <tolower@plt>
  cmp    %al,%bpl
  jne    L38
L32:
  movzbl (%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  jne    L47
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int match(const char *line, const char *sender) {
  char ch, pch, first;
  const char *p, *t;
  for (first = *sender++;;) {
    if (isspace(ch = *line))
      return (0);
    ++line;
    ch = tolower(ch);
    if (ch != first)
      continue;
    for (p = sender, t = line;;) {
      if (!(pch = *p++))
        return (1);
      ch = tolower(*t);
      t++;
      if (ch != pch)
        break;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L74
L44:
  cmpl   $0x5c,-0x4(%rbp)
  je     L79
  cmpl   $0x5c,-0x4(%rbp)
  jg     L24
  cmpl   $0x8,-0x4(%rbp)
  je     L63
  cmpl   $0x9,-0x4(%rbp)
  jne    L24
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L74
L63:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L74
L79:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L74
L24:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L74:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L44
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int rw;
  while ((rw = getchar()) != EOF) {
    switch (rw) {
    case '\t':
      putchar('\\');
      putchar('t');
      break;
    case '\b':
      putchar('\\');
      putchar('b');
      break;
    case '\\':
      putchar('\\');
      putchar('\\');
      break;
    default:
      putchar(rw);
    }
  }
  return 0;
}
```