ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<strrev>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L0
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  mov    %rsp,%r12
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
L3:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <strcat@plt>
  cmp    %rbp,%rbx
  jne    L3
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strrev(char input_string[25])) {
  int str_len = strlen(input_string);
  char new_str[25];
  for (int i = str_len - 1; i >= 0; i--) {
    strcat(new_str, input_string[i]);
  }
  return new_str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strrev>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L29
  movslq %edx,%rbx
  cltq
  mov    %edx,%edx
  mov    %rsp,%r12
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
L6:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <strcat@plt>
  cmp    %rbp,%rbx
  jne    L6
L29:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *(strrev(char input_string[25])) {
  int str_len = strlen(input_string);
  char new_str[25];
  for (int i = str_len - 1; i >= 0; i--) {
    strcat(new_str, input_string[i]);
  }
  return new_str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<replace_dots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L11
  mov    -0x8(%rbp),%rax
  movb   $0x5f,(%rax)
L11:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void replace_dots(char *s) {
  while (*s) {
    if (*s == '.')
      *s = '_';
    s++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<replace_dots>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
L25:
  ret
L33:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
L26:
  cmp    $0x2e,%al
  jne    L33
  movb   $0x5f,(%rdi)
  jmp    L33
```

assistant: ```c
void replace_dots(char *s) {
  while (*s) {
    if (*s == '.')
      *s = '_';
    s++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<replace_dots>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L10:
  cmp    $0x2e,%al
  jne    L22
  movb   $0x5f,(%rdi)
L22:
  add    $0x1,%rdi
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  ret
```

assistant: ```c
void replace_dots(char *s) {
  while (*s) {
    if (*s == '.')
      *s = '_';
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<replace_dots>:
  endbr64
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%rdi
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
L26:
  cmp    $0x2e,%al
  jne    L22
  movb   $0x5f,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L26
  ret
  nop
L13:
  ret
```

assistant: ```c
void replace_dots(char *s) {
  while (*s) {
    if (*s == '.')
      *s = '_';
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x17,%esi
  mov    $0x16,%edi
  call   <foo@plt>
  cmp    $0x2d,%eax
  je     L20
  mov    $0x0,%eax
  call   <abort@plt>
L20:
  mov    $0x0,%eax
  call   <bar@plt>
  cmp    $0x64,%eax
  je     L21
  mov    $0x0,%eax
  call   <abort@plt>
L21:
  mov    $0x0,%eax
  call   <baz@plt>
  cmp    $0x24,%eax
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(22, 23) != 45)
    abort();
  if (bar() != 100)
    abort();
  if (baz() != 36)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  mov    $0x16,%edi
  call   <foo@plt>
  cmp    $0x2d,%eax
  jne    L31
L34:
  mov    $0x0,%eax
  call   <bar@plt>
  cmp    $0x64,%eax
  jne    L8
L21:
  mov    $0x0,%eax
  call   <baz@plt>
  cmp    $0x24,%eax
  jne    L7
L51:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L31:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L34
L8:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L21
L7:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L51
```

assistant: ```c
int main() {
  if (foo(22, 23) != 45)
    abort();
  if (bar() != 100)
    abort();
  if (baz() != 36)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  mov    $0x16,%edi
  call   <foo@plt>
  cmp    $0x2d,%eax
  je     L3
  xor    %eax,%eax
  call   <abort@plt>
L3:
  xor    %eax,%eax
  call   <bar@plt>
  cmp    $0x64,%eax
  je     L2
  xor    %eax,%eax
  call   <abort@plt>
L2:
  xor    %eax,%eax
  call   <baz@plt>
  cmp    $0x24,%eax
  je     L26
  xor    %eax,%eax
  call   <abort@plt>
L26:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(22, 23) != 45)
    abort();
  if (bar() != 100)
    abort();
  if (baz() != 36)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%esi
  mov    $0x16,%edi
  call   <foo@plt>
  cmp    $0x2d,%eax
  je     L18
  xor    %eax,%eax
  call   <abort@plt>
L18:
  xor    %eax,%eax
  call   <bar@plt>
  cmp    $0x64,%eax
  je     L7
  xor    %eax,%eax
  call   <abort@plt>
L7:
  xor    %eax,%eax
  call   <baz@plt>
  cmp    $0x24,%eax
  je     L12
  xor    %eax,%eax
  call   <abort@plt>
L12:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(22, 23) != 45)
    abort();
  if (bar() != 100)
    abort();
  if (baz() != 36)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gererOptions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  lea    -0x24(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recupererInputOutput@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <recupererInputOutput@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%r8d
  mov    -0x24(%rbp),%ecx
  mov    -0x10(%rbp),%rdi
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <appelerFonction@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int gererOptions(int argc, char **argv) {
  int nombreInput;
  int nombreOutput;
  int int_result;
  char **input;
  char **output;
  int_result = 0;
  input = recupererInputOutput(argc, argv, 1, &nombreInput);
  output = recupererInputOutput(argc, argv, 0, &nombreOutput);
  appelerFonction(argc, argv, input, nombreInput, output, nombreOutput);
  return int_result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gererOptions>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    $0x1,%edx
  call   <recupererInputOutput@plt>
  mov    %rax,%r12
  lea    0x4(%rsp),%rcx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recupererInputOutput@plt>
  mov    %rax,%r8
  mov    0x4(%rsp),%r9d
  mov    (%rsp),%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <appelerFonction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gererOptions(int argc, char **argv) {
  int nombreInput;
  int nombreOutput;
  int int_result;
  char **input;
  char **output;
  int_result = 0;
  input = recupererInputOutput(argc, argv, 1, &nombreInput);
  output = recupererInputOutput(argc, argv, 0, &nombreOutput);
  appelerFonction(argc, argv, input, nombreInput, output, nombreOutput);
  return int_result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gererOptions>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <recupererInputOutput@plt>
  xor    %edx,%edx
  lea    0x4(%rsp),%rcx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <recupererInputOutput@plt>
  mov    0x4(%rsp),%r9d
  mov    (%rsp),%ecx
  mov    %r13,%rdx
  mov    %rax,%r8
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <appelerFonction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gererOptions(int argc, char **argv) {
  int nombreInput;
  int nombreOutput;
  int int_result;
  char **input;
  char **output;
  int_result = 0;
  input = recupererInputOutput(argc, argv, 1, &nombreInput);
  output = recupererInputOutput(argc, argv, 0, &nombreOutput);
  appelerFonction(argc, argv, input, nombreInput, output, nombreOutput);
  return int_result;
}
```
user: What is the c source code of the assembly code below?

```asm
<gererOptions>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <recupererInputOutput@plt>
  xor    %edx,%edx
  lea    0x4(%rsp),%rcx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <recupererInputOutput@plt>
  mov    0x4(%rsp),%r9d
  mov    (%rsp),%ecx
  mov    %r13,%rdx
  mov    %rax,%r8
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <appelerFonction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gererOptions(int argc, char **argv) {
  int nombreInput;
  int nombreOutput;
  int int_result;
  char **input;
  char **output;
  int_result = 0;
  input = recupererInputOutput(argc, argv, 1, &nombreInput);
  output = recupererInputOutput(argc, argv, 0, &nombreOutput);
  appelerFonction(argc, argv, input, nombreInput, output, nombreOutput);
  return int_result;
}
```
user: What is the c source code of the assembly code below?

```asm
<mongo_server_hash_to_pid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3b,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  leave
  ret
```

assistant: ```c
int mongo_server_hash_to_pid(char *hash) {
  char *ptr;
  ptr = strrchr(hash, ';');
  return atoi(ptr + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mongo_server_hash_to_pid>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mongo_server_hash_to_pid(char *hash) {
  char *ptr;
  ptr = strrchr(hash, ';');
  return atoi(ptr + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mongo_server_hash_to_pid>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b,%esi
  call   <strrchr@plt>
  add    $0x8,%rsp
  lea    0x1(%rax),%rdi
  jmp    1070 <atoi@plt>
```

assistant: ```c
int mongo_server_hash_to_pid(char *hash) {
  char *ptr;
  ptr = strrchr(hash, ';');
  return atoi(ptr + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mongo_server_hash_to_pid>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b,%esi
  call   <strrchr@plt>
  add    $0x8,%rsp
  lea    0x1(%rax),%rdi
  jmp    1070 <atoi@plt>
```

assistant: ```c
int mongo_server_hash_to_pid(char *hash) {
  char *ptr;
  ptr = strrchr(hash, ';');
  return atoi(ptr + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memdup(const void *mem, int nbytes) {
  void *p = malloc(nbytes);
  memcpy(p, mem, nbytes);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(const void *mem, int nbytes) {
  void *p = malloc(nbytes);
  memcpy(p, mem, nbytes);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *mem, int nbytes) {
  void *p = malloc(nbytes);
  memcpy(p, mem, nbytes);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *mem, int nbytes) {
  void *p = malloc(nbytes);
  memcpy(p, mem, nbytes);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L11
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void inverse(char str[]) {
  char t;
  int i, j;
  for (i = 0, j = strlen(str); i < strlen(str) / 2; i++, j--) {
    t = str[i];
    str[i] = str[j - 1];
    str[j - 1] = t;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inverse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbp
  mov    $0x0,%ebx
  jmp    L0
L3:
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%r12,%rbx,1)
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  sub    $0x1,%rbp
L0:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rax,1),%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void inverse(char str[]) {
  char t;
  int i, j;
  for (i = 0, j = strlen(str); i < strlen(str) / 2; i++, j--) {
    t = str[i];
    str[i] = str[j - 1];
    str[j - 1] = t;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbp
  mov    %dl,(%r12,%rbx,1)
  add    $0x1,%rbx
  mov    %al,0x1(%rbp)
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void inverse(char str[]) {
  char t;
  int i, j;
  for (i = 0, j = strlen(str); i < strlen(str) / 2; i++, j--) {
    t = str[i];
    str[i] = str[j - 1];
    str[j - 1] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%rbp),%edx
  sub    $0x1,%rbp
  mov    %dl,(%r12,%rbx,1)
  add    $0x1,%rbx
  mov    %al,0x1(%rbp)
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void inverse(char str[]) {
  char t;
  int i, j;
  for (i = 0, j = strlen(str); i < strlen(str) / 2; i++, j--) {
    t = str[i];
    str[i] = str[j - 1];
    str[j - 1] = t;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<if_i_j>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L23
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L11
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  jmp    L29
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  jmp    L29
L23:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int if_i_j(n1, n2, n3, mid) {
  if (n3 > n2) {
    if (n3 < n1) {
      mid = n3;
      return (mid);
    } else {
      mid = n1;
      return (mid);
    }
  } else {
    mid = n2;
    return (mid);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<if_i_j>:
  endbr64
  cmp    %edi,%edx
  cmovle %edx,%edi
  cmp    %esi,%edx
  mov    %esi,%eax
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int if_i_j(n1, n2, n3, mid) {
  if (n3 > n2) {
    if (n3 < n1) {
      mid = n3;
      return (mid);
    } else {
      mid = n1;
      return (mid);
    }
  } else {
    mid = n2;
    return (mid);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<if_i_j>:
  endbr64
  cmp    %edi,%edx
  mov    %esi,%eax
  cmovle %edx,%edi
  cmp    %esi,%edx
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int if_i_j(n1, n2, n3, mid) {
  if (n3 > n2) {
    if (n3 < n1) {
      mid = n3;
      return (mid);
    } else {
      mid = n1;
      return (mid);
    }
  } else {
    mid = n2;
    return (mid);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<if_i_j>:
  endbr64
  cmp    %edi,%edx
  mov    %esi,%eax
  cmovle %edx,%edi
  cmp    %esi,%edx
  cmovg  %edi,%eax
  ret
```

assistant: ```c
int if_i_j(n1, n2, n3, mid) {
  if (n3 > n2) {
    if (n3 < n1) {
      mid = n3;
      return (mid);
    } else {
      mid = n1;
      return (mid);
    }
  } else {
    mid = n2;
    return (mid);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GenericInterface_RestoreRomSettings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  jmp    L49
L72:
  mov    -0x40(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <Settings_GetString@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L0
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x38(%rbp),%rdx
  mov    -0x40(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <GenericInterface_LoadRom@plt>
  test   %rax,%rax
  je     L0
  mov    -0x40(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <Settings_GetInt@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  je     L26
  mov    -0x40(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <ExpansionRom_SetActiveState@plt>
  jmp    L0
L26:
  mov    -0x40(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <ExpansionRom_SetActiveState@plt>
L0:
  addl   $0x1,-0x40(%rbp)
L49:
  cmpl   $0x10,-0x40(%rbp)
  jle    L72
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D15
data_type: string

tool: D14: sRom%2d

tool: D15: iRom%2dActive

assistant: ```c
void GenericInterface_RestoreRomSettings(void) {
  int i;
  for (i = 1; i < 17; i++) {
    char SettingsKey[32];
    char *pCurrentRomFilename;
    sprintf(SettingsKey, "sRom%2d", i);
    pCurrentRomFilename = Settings_GetString(SettingsKey);
    if (pCurrentRomFilename != 0) {
      if (strlen(pCurrentRomFilename) != 0) {
        if (GenericInterface_LoadRom(i, pCurrentRomFilename)) {
          int ActiveFlag;
          sprintf(SettingsKey, "iRom%2dActive", i);
          ActiveFlag = Settings_GetInt(SettingsKey);
          if (ActiveFlag != 0) {
            ExpansionRom_SetActiveState(i, (1 == 1));
          } else {
            ExpansionRom_SetActiveState(i, (1 == 0));
          }
        }
      }
    }
  }
}
```