ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<conv_decimate>:
  endbr64
  test   %esi,%esi
  jle    L65
  mov    %esi,%r11d
  mov    %rdx,%r10
  xor    %r9d,%r9d
L68:
  test   %ecx,%ecx
  jle    L18
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r9d,%eax
  mov    %rdi,%rdx
  sar    %eax
  cltq
  lea    (%r8,%rax,4),%rbx
  mov    $0x1,%eax
  movss  (%rbx),%xmm1
  nopw   0x0(%rax,%rax,1)
L57:
  movss  -0x4(%r10,%rax,4),%xmm0
  mulss  (%rdx),%xmm0
  mov    %eax,%esi
  sub    $0x4,%rdx
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %esi,%ecx
  jle    L26
  cmp    %esi,%r9d
  jge    L57
L26:
  add    $0x2,%r9d
  movss  %xmm1,(%rbx)
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jle    L49
L62:
  test   %ecx,%ecx
  jg     L47
  add    $0x2,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jg     L62
L49:
  pop    %rbx
  ret
L18:
  add    $0x2,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jg     L68
L65:
  ret
```

assistant: ```c
void conv_decimate(const float *restrict a, int n, const float *restrict f, int m, float *restrict b) {
  for (int i = 0; i < n; i += 2)
    for (int j = 0; j < m && j <= i; j++)
      b[i / 2] += f[j] * a[i - j];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conv_decimate>:
  endbr64
  test   %esi,%esi
  jle    L42
  mov    %esi,%r11d
  mov    %rdx,%r10
  xor    %r9d,%r9d
L31:
  test   %ecx,%ecx
  jle    L36
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r9d,%eax
  mov    %rdi,%rdx
  sar    %eax
  cltq
  lea    (%r8,%rax,4),%rbx
  mov    $0x1,%eax
  movss  (%rbx),%xmm1
  nopw   0x0(%rax,%rax,1)
L50:
  movss  -0x4(%r10,%rax,4),%xmm0
  mulss  (%rdx),%xmm0
  mov    %eax,%esi
  sub    $0x4,%rdx
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %esi,%ecx
  jle    L37
  cmp    %esi,%r9d
  jge    L50
L37:
  add    $0x2,%r9d
  movss  %xmm1,(%rbx)
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jle    L52
L34:
  test   %ecx,%ecx
  jg     L21
  add    $0x2,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jg     L34
L52:
  pop    %rbx
  ret
L36:
  add    $0x2,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r11d
  jg     L31
L42:
  ret
```

assistant: ```c
void conv_decimate(const float *restrict a, int n, const float *restrict f, int m, float *restrict b) {
  for (int i = 0; i < n; i += 2)
    for (int j = 0; j < m && j <= i; j++)
      b[i / 2] += f[j] * a[i - j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_state_33>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L50
  cmpb   $0x37,-0x4(%rbp)
  jg     L50
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x0,%eax
  jmp    L153
L50:
  movsbl -0x4(%rbp),%eax
  cmp    $0x39,%eax
  jg     L46
  cmp    $0x38,%eax
  jge    L39
  jmp    L57
L74:
  sub    $0x44,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x500000005,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L41
  movabs $0x200000002,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L48
  movabs $0x10000000100,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L33
  jmp    L57
L46:
  cmp    $0x6c,%eax
  jg     L57
  cmp    $0x44,%eax
  jge    L74
  jmp    L57
L39:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  movl   $0x22,(%rax)
  mov    $0x0,%eax
  jmp    L153
L33:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  movl   $0x20,(%rax)
  mov    $0x0,%eax
  jmp    L153
L48:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  movl   $0x1a,(%rax)
  mov    $0x0,%eax
  jmp    L153
L41:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  movl   $0x19,(%rax)
  mov    $0x0,%eax
  jmp    L153
L57:
  mov    $0x1,%eax
L153:
  pop    %rbp
  ret
```

assistant: ```c
int do_state_33(char c, int *state, char *word, int *length) {
  if (c >= '0' && c <= '7') {
    word[(*length)++] = c;
    return 0;
  }
  switch (c) {
  case '8':
  case '9':
    word[(*length)++] = c;
    *state = 34;
    return 0;
  case 'l':
  case 'L':
    word[(*length)++] = c;
    *state = 32;
    return 0;
  case 'e':
  case 'E':
    word[(*length)++] = c;
    *state = 26;
    return 0;
  case 'f':
  case 'F':
  case 'd':
  case 'D':
    word[(*length)++] = c;
    *state = 25;
    return 0;
  default:
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_state_33>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%r8
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  lea    -0x30(%rax),%ecx
  cmp    $0x7,%cl
  jbe    L11
  cmp    $0x39,%al
  jle    L32
  lea    -0x44(%rax),%ecx
  cmp    $0x28,%cl
  ja     L21
  mov    $0x1,%esi
  shl    %cl,%rsi
  mov    %rsi,%rcx
  movabs $0x500000005,%rsi
  test   %rsi,%rcx
  jne    L43
  movabs $0x200000002,%rsi
  test   %rsi,%rcx
  jne    L33
  movabs $0x10000000100,%rsi
  test   %rsi,%rcx
  jne    L55
  mov    $0x1,%eax
  ret
L11:
  mov    (%rdx),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  movslq %ecx,%rcx
  mov    %al,(%rdi,%rcx,1)
  mov    $0x0,%eax
  ret
L32:
  cmp    $0x37,%al
  jg     L30
  mov    $0x1,%eax
  ret
L30:
  mov    (%rdx),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  movslq %ecx,%rcx
  mov    %al,(%rdi,%rcx,1)
  movl   $0x22,(%r8)
  mov    $0x0,%eax
  ret
L55:
  mov    (%rdx),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  movslq %ecx,%rcx
  mov    %al,(%rdi,%rcx,1)
  movl   $0x20,(%r8)
  mov    $0x0,%eax
  ret
L33:
  mov    (%rdx),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  movslq %ecx,%rcx
  mov    %al,(%rdi,%rcx,1)
  movl   $0x1a,(%r8)
  mov    $0x0,%eax
  ret
L43:
  mov    (%rdx),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  movslq %ecx,%rcx
  mov    %al,(%rdi,%rcx,1)
  movl   $0x19,(%r8)
  mov    $0x0,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int do_state_33(char c, int *state, char *word, int *length) {
  if (c >= '0' && c <= '7') {
    word[(*length)++] = c;
    return 0;
  }
  switch (c) {
  case '8':
  case '9':
    word[(*length)++] = c;
    *state = 34;
    return 0;
  case 'l':
  case 'L':
    word[(*length)++] = c;
    *state = 32;
    return 0;
  case 'e':
  case 'E':
    word[(*length)++] = c;
    *state = 26;
    return 0;
  case 'f':
  case 'F':
  case 'd':
  case 'D':
    word[(*length)++] = c;
    *state = 25;
    return 0;
  default:
    return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_state_33>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  mov    %rsi,%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x7,%cl
  jbe    L44
  cmp    $0x39,%al
  jle    L42
  lea    -0x44(%rax),%ecx
  cmp    $0x28,%cl
  ja     L21
  mov    $0x1,%esi
  shl    %cl,%rsi
  mov    %rsi,%rcx
  movabs $0x500000005,%rsi
  test   %rsi,%rcx
  jne    L29
  movabs $0x200000002,%rsi
  test   %rsi,%rcx
  jne    L56
  movabs $0x10000000100,%rsi
  test   %rsi,%rcx
  jne    L59
L21:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L42:
  cmp    $0x37,%al
  jle    L21
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x22,(%r8)
  ret
  nopl   0x0(%rax)
L44:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x1a,(%r8)
  ret
  nopl   (%rax)
L59:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x20,(%r8)
  ret
  nopl   (%rax)
L29:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x19,(%r8)
  ret
```

assistant: ```c
int do_state_33(char c, int *state, char *word, int *length) {
  if (c >= '0' && c <= '7') {
    word[(*length)++] = c;
    return 0;
  }
  switch (c) {
  case '8':
  case '9':
    word[(*length)++] = c;
    *state = 34;
    return 0;
  case 'l':
  case 'L':
    word[(*length)++] = c;
    *state = 32;
    return 0;
  case 'e':
  case 'E':
    word[(*length)++] = c;
    *state = 26;
    return 0;
  case 'f':
  case 'F':
  case 'd':
  case 'D':
    word[(*length)++] = c;
    *state = 25;
    return 0;
  default:
    return 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_state_33>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  mov    %rsi,%r8
  lea    -0x30(%rax),%ecx
  cmp    $0x7,%cl
  jbe    L46
  cmp    $0x39,%al
  jle    L23
  lea    -0x44(%rax),%ecx
  cmp    $0x28,%cl
  ja     L36
  mov    $0x1,%esi
  shl    %cl,%rsi
  mov    %rsi,%rcx
  movabs $0x500000005,%rsi
  test   %rsi,%rcx
  jne    L38
  movabs $0x200000002,%rsi
  test   %rsi,%rcx
  jne    L2
  movabs $0x10000000100,%rsi
  test   %rsi,%rcx
  jne    L33
L36:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L23:
  cmp    $0x37,%al
  jle    L36
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x22,(%r8)
  ret
  nopl   0x0(%rax)
L46:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x1a,(%r8)
  ret
  nopl   (%rax)
L33:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x20,(%r8)
  ret
  nopl   (%rax)
L38:
  movslq (%rdx),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%rdx)
  mov    %al,(%rdi,%rcx,1)
  xor    %eax,%eax
  movl   $0x19,(%r8)
  ret
```

assistant: ```c
int do_state_33(char c, int *state, char *word, int *length) {
  if (c >= '0' && c <= '7') {
    word[(*length)++] = c;
    return 0;
  }
  switch (c) {
  case '8':
  case '9':
    word[(*length)++] = c;
    *state = 34;
    return 0;
  case 'l':
  case 'L':
    word[(*length)++] = c;
    *state = 32;
    return 0;
  case 'e':
  case 'E':
    word[(*length)++] = c;
    *state = 26;
    return 0;
  case 'f':
  case 'F':
  case 'd':
  case 'D':
    word[(*length)++] = c;
    *state = 25;
    return 0;
  default:
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mydup2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L4
  mov    -0x14(%rbp),%eax
  jmp    L7
L4:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L17
  mov    $0xffffffff,%eax
  jmp    L7
L17:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L39
L75:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <dup@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L39
  mov    $0xffffffff,%eax
  jmp    L7
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L75
  mov    -0x18(%rbp),%eax
L7:
  leave
  ret
```

assistant: ```c
int mydup2(int fd, int new_fd) {
  if (fd == new_fd) {
    return fd;
  } else if (fd > new_fd) {
    return -1;
  }
  close(new_fd);
  int tmp_fd = fd;
  while (tmp_fd < new_fd) {
    if ((tmp_fd = dup(fd)) < 0) {
      return -1;
    }
  }
  return new_fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mydup2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  cmp    %esi,%edi
  je     L12
  mov    %edi,%ebp
  jg     L18
  mov    %esi,%edi
  call   <close@plt>
  mov    %ebp,%eax
L25:
  cmp    %ebx,%eax
  jge    L12
  mov    %ebp,%edi
  call   <dup@plt>
  test   %eax,%eax
  jns    L25
  mov    $0xffffffff,%ebx
L12:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0xffffffff,%ebx
  jmp    L12
```

assistant: ```c
int mydup2(int fd, int new_fd) {
  if (fd == new_fd) {
    return fd;
  } else if (fd > new_fd) {
    return -1;
  }
  close(new_fd);
  int tmp_fd = fd;
  while (tmp_fd < new_fd) {
    if ((tmp_fd = dup(fd)) < 0) {
      return -1;
    }
  }
  return new_fd;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mydup2>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  je     L15
  jg     L12
  mov    %edi,%ebp
  mov    %esi,%edi
  call   <close@plt>
  mov    %ebp,%eax
  jmp    L24
  nop
L20:
  mov    %ebp,%edi
  call   <dup@plt>
  test   %eax,%eax
  js     L12
L24:
  cmp    %ebx,%eax
  jl     L20
L15:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mydup2(int fd, int new_fd) {
  if (fd == new_fd) {
    return fd;
  } else if (fd > new_fd) {
    return -1;
  }
  close(new_fd);
  int tmp_fd = fd;
  while (tmp_fd < new_fd) {
    if ((tmp_fd = dup(fd)) < 0) {
      return -1;
    }
  }
  return new_fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mydup2>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  je     L24
  jg     L41
  mov    %edi,%ebp
  mov    %esi,%edi
  call   <close@plt>
  mov    %ebp,%eax
  jmp    L16
  nop
L17:
  mov    %ebp,%edi
  call   <dup@plt>
  test   %eax,%eax
  js     L41
L16:
  cmp    %ebx,%eax
  jl     L17
L24:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mydup2(int fd, int new_fd) {
  if (fd == new_fd) {
    return fd;
  } else if (fd > new_fd) {
    return -1;
  }
  close(new_fd);
  int tmp_fd = fd;
  while (tmp_fd < new_fd) {
    if ((tmp_fd = dup(fd)) < 0) {
      return -1;
    }
  }
  return new_fd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xb8(%rbp)
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xb4(%rbp)
  movl   $0x0,-0xbc(%rbp)
  jmp    L129
L51:
  mov    -0xbc(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  cmp    $0x7a,%eax
  jg     L72
  cmp    $0x71,%eax
  jge    L133
  cmp    $0x20,%eax
  je     L124
  cmp    $0x20,%eax
  jl     L72
  cmp    $0x70,%eax
  jg     L72
  cmp    $0x61,%eax
  jge    L140
  jmp    L72
L133:
  sub    $0x71,%eax
  cmp    $0x9,%eax
  ja     L72
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L140:
  sub    $0x61,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0x9249,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L124
  mov    %rax,%rdx
  and    $0x4924,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L112
  and    $0x2492,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L29
  jmp    L72
L124:
  addl   $0x1,-0xb8(%rbp)
  jmp    L72
L29:
  addl   $0x2,-0xb8(%rbp)
  jmp    L72
L112:
  addl   $0x3,-0xb8(%rbp)
  jmp    L72
  addl   $0x4,-0xb8(%rbp)
  nop
L72:
  addl   $0x1,-0xbc(%rbp)
L129:
  mov    -0xbc(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L51
  mov    -0xb8(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L111
  call   <__stack_chk_fail@plt>
L111:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D39
datatype: string

tool: D5: %[^
]s

tool: D39: %d

assistant: ```c
int main() {
  char sentence[160];
  int i;
  int answer = 0;
  int length;
  scanf("%[^\n]s", sentence);
  length = strlen(sentence);
  for (i = 0; i < length; i++) {
    switch (sentence[i]) {
    case 'a':
    case 'd':
    case ' ':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
      answer += 1;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      answer += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      answer += 3;
      break;
    case 's':
    case 'z':
      answer += 4;
      break;
    }
  }
  printf("%d", answer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L92
  mov    %rsp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%r9
  mov    $0x0,%edi
  lea    D12(%rip),%rsi
  mov    $0x1,%r8d
  jmp    L28
L138:
  cmp    $0x60,%cl
  jg     L34
  cmp    $0x20,%cl
  je     L61
L98:
  add    $0x1,%rdx
  cmp    %r9,%rdx
  je     L139
L28:
  movzbl (%rdx),%ecx
  cmp    $0x70,%cl
  jle    L138
  lea    -0x71(%rcx),%eax
  cmp    $0x9,%al
  ja     L98
  sub    $0x71,%ecx
  cmp    $0x9,%cl
  ja     L98
  movzbl %cl,%ecx
  movslq (%rsi,%rcx,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
L34:
  sub    $0x61,%ecx
  mov    %r8,%rax
  shl    %cl,%rax
  test   $0x9249,%eax
  jne    L61
  test   $0x4924,%eax
  jne    L31
  test   $0x2492,%eax
  je     L98
  add    $0x2,%edi
  jmp    L98
L61:
  add    $0x1,%edi
  jmp    L98
L31:
  add    $0x3,%edi
  jmp    L98
  add    $0x4,%edi
  jmp    L98
L92:
  mov    $0x0,%edi
L139:
  mov    %edi,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D25: %[^
]s

tool: D10: %d

assistant: ```c
int main() {
  char sentence[160];
  int i;
  int answer = 0;
  int length;
  scanf("%[^\n]s", sentence);
  length = strlen(sentence);
  for (i = 0; i < length; i++) {
    switch (sentence[i]) {
    case 'a':
    case 'd':
    case ' ':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
      answer += 1;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      answer += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      answer += 3;
      break;
    case 's':
    case 'z':
      answer += 4;
      break;
    }
  }
  printf("%d", answer);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L83
  sub    $0x1,%eax
  mov    %rbx,%rdx
  xor    %esi,%esi
  mov    $0x1,%r8d
  lea    0x1(%rsp,%rax,1),%r9
  lea    D8(%rip),%rdi
  jmp    L92
  nopl   (%rax)
L11:
  cmp    $0x60,%cl
  jg     L119
  cmp    $0x20,%cl
  je     L54
L86:
  add    $0x1,%rdx
  cmp    %r9,%rdx
  je     L2
L92:
  movzbl (%rdx),%ecx
  cmp    $0x70,%cl
  jle    L11
  lea    -0x71(%rcx),%eax
  cmp    $0x9,%al
  ja     L86
  sub    $0x72,%ecx
  cmp    $0x8,%cl
  ja     L49
  movzbl %cl,%ecx
  movslq (%rdi,%rcx,4),%rax
  add    %rdi,%rax
  notrack jmp *%rax
  nop
L118:
  add    $0x1,%rdx
  add    $0x3,%esi
  cmp    %r9,%rdx
  jne    L92
  nopl   0x0(%rax)
L2:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  add    $0x1,%esi
  jmp    L86
  nopl   (%rax)
  add    $0x4,%esi
  jmp    L86
  nopl   (%rax)
L119:
  sub    $0x61,%ecx
  mov    %r8,%rax
  shl    %cl,%rax
  test   $0x9249,%eax
  jne    L54
  test   $0x4924,%eax
  jne    L118
  test   $0x2492,%eax
  je     L86
L49:
  add    $0x2,%esi
  jmp    L86
L83:
  xor    %esi,%esi
  jmp    L2
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D27
type: string

tool: D12: %[^
]s

tool: D27: %d

assistant: ```c
int main() {
  char sentence[160];
  int i;
  int answer = 0;
  int length;
  scanf("%[^\n]s", sentence);
  length = strlen(sentence);
  for (i = 0; i < length; i++) {
    switch (sentence[i]) {
    case 'a':
    case 'd':
    case ' ':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
      answer += 1;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      answer += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      answer += 3;
      break;
    case 's':
    case 'z':
      answer += 4;
      break;
    }
  }
  printf("%d", answer);
  return 0;
}
```