user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xe8(%rbp)
  movl   $0x0,-0xe4(%rbp)
  movl   $0x1,-0xec(%rbp)
  movl   $0x0,-0xe0(%rbp)
  movl   $0x0,-0xdc(%rbp)
  movl   $0x0,-0xd8(%rbp)
  movl   $0x0,-0xd4(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xec(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xe4(%rbp)
  mov    -0xec(%rbp),%edx
  mov    -0xe8(%rbp),%eax
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0xe8(%rbp)
  movl   $0x1,-0xe8(%rbp)
  jmp    L36
L89:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xec(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xec(%rbp),%edx
  mov    -0xe8(%rbp),%eax
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0xe4(%rbp)
  mov    -0xec(%rbp),%eax
  test   %eax,%eax
  je     L38
  mov    -0xec(%rbp),%eax
  cmp    $0x4,%eax
  jle    L4
L38:
  mov    -0xe8(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xec(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xec(%rbp),%eax
  test   %eax,%eax
  je     L39
  mov    -0xec(%rbp),%eax
  cmp    $0x4,%eax
  jle    L4
L39:
  mov    -0xec(%rbp),%edx
  mov    -0xe8(%rbp),%eax
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  mov    -0xe8(%rbp),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xe4(%rbp)
  addl   $0x1,-0xe8(%rbp)
L4:
  addl   $0x1,-0xe8(%rbp)
L36:
  mov    -0xec(%rbp),%eax
  test   %eax,%eax
  jle    L76
  mov    -0xec(%rbp),%eax
  cmp    $0x4,%eax
  jle    L89
L76:
  subl   $0x1,-0xe8(%rbp)
  subl   $0x1,-0xe4(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xe8(%rbp)
  jmp    L99
L11:
  mov    -0xe8(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xe8(%rbp)
L99:
  mov    -0xe8(%rbp),%eax
  cmp    -0xe4(%rbp),%eax
  jl     L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D35
type: string
name: read_data
arguments: data_tag: D32
type: string
name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D74
type: string
name: read_data
arguments: data_tag: D66
type: string
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D48
type: string

tool: D35: 
Input a number, 1 - 4. Where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)

tool: D32: %d

tool: D49: 
Input a number, 1 - 4 where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)

tool: D74: 
Invalid input! you entered '%d'
Please input 1-4 or program will exit


tool: D66: i = %d


tool: D11: 

***END PROGRAM!***

tool: D8: You entered the following items:

tool: D48: %d 

assistant: ```c
int main() {
  int i = 0, itemCount = 0, input = 1, infant = 0, child = 0, teen = 0, adult = 0, PeopleTypes[50];
  printf("\nInput a number, 1 - 4. Where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)\n");
  scanf("%d", &input);
  itemCount++;
  PeopleTypes[i] = input;
  i++;
  for (i = 1; (input > 0) && (input <= 4); i++) {
    printf("\nInput a number, 1 - 4 where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)\n");
    scanf("%d", &input);
    PeopleTypes[i] = input;
    itemCount++;
    if ((input == 0) || (input > 4)) {
      printf("\nInvalid input! you entered '%d'\nPlease input 1-4 or program will exit\n", PeopleTypes[i]);
      scanf("%d", &input);
      if ((input == 0) || (input > 4)) {
        PeopleTypes[i] = input;
        printf("i = %d\n", i);
        itemCount++;
        i++;
      } else
        ;
    }
  }
  i--;
  itemCount--;
  printf("\n\n***END PROGRAM!***\n");
  printf("You entered the following items:\n");
  for (i = 0; i < itemCount; i++) {
    printf("%d ", PeopleTypes[i]);
  }
  return 0;
}
```