ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mymemcpy>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%rcx
  sub    $0x8,%rsp
  shl    $0x2,%rax
  lea    (%rsi,%rax,1),%rdi
  cmp    %rdi,%rcx
  jae    L165
  cmp    %rcx,%rsi
  jb     L96
L165:
  test   %edx,%edx
  jle    L192
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L91
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L91
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L170:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L170
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L192
  mov    %eax,%r8d
  mov    (%rsi,%r8,4),%r9d
  lea    0x0(,%r8,4),%rdi
  mov    %r9d,(%rcx,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edx
  jle    L192
  mov    0x4(%rsi,%rdi,1),%r8d
  add    $0x2,%eax
  mov    %r8d,0x4(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L192
  mov    0x8(%rsi,%rdi,1),%eax
  mov    %eax,0x8(%rcx,%rdi,1)
L192:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L96:
  mov    %edx,%r10d
  sub    $0x1,%r10d
  js     L192
  mov    %rcx,%rdi
  sub    %rsi,%rdi
  add    $0xc,%rdi
  cmp    $0x8,%rdi
  jbe    L157
  cmp    $0x2,%r10d
  jbe    L157
  mov    %edx,%r8d
  sub    $0x10,%rax
  xor    %edi,%edi
  shr    $0x2,%r8d
  lea    (%rsi,%rax,1),%r9
  add    %rcx,%rax
  neg    %r8
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L53:
  movdqu (%r9,%rdi,1),%xmm1
  movups %xmm1,(%rax,%rdi,1)
  sub    $0x10,%rdi
  cmp    %r8,%rdi
  jne    L53
  mov    %edx,%edi
  mov    %r10d,%eax
  and    $0xfffffffc,%edi
  sub    %edi,%eax
  cmp    %edi,%edx
  je     L192
  movslq %eax,%rdx
  mov    (%rsi,%rdx,4),%edi
  mov    %edi,(%rcx,%rdx,4)
  lea    -0x1(%rax),%edx
  test   %eax,%eax
  je     L192
  movslq %edx,%rdx
  mov    (%rsi,%rdx,4),%r8d
  lea    0x0(,%rdx,4),%rdi
  mov    %r8d,(%rcx,%rdx,4)
  cmp    $0x1,%eax
  je     L192
  mov    -0x4(%rsi,%rdi,1),%eax
  mov    %eax,-0x4(%rcx,%rdi,1)
  jmp    L192
  xchg   %ax,%ax
L91:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L131:
  mov    (%rsi,%rax,4),%edi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L131
  jmp    L192
L157:
  movslq %r10d,%rax
  nop
L130:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L130
  jmp    L192
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: 


assistant: ```c
int mymemcpy(unsigned int *wdst, unsigned int *wsrc, int words) {
  int i;
  if ((wsrc + words > wdst) && (wsrc < wdst)) {
    for (i = words - 1; i >= 0; i--) {
      *(wdst + i) = *(wsrc + i);
    }
  } else {
    for (i = 0; i < words; i++) {
      *(wdst + i) = *(wsrc + i);
    }
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    $0xffffffdb,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L21
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L11
L21:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
L11:
  movzbl -0x9(%rbp),%eax
  shr    $0x7,%al
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
    }
    output[0UL] = state[0UL] >> (unsigned char)7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rdx
  movzbl (%rdi),%eax
  mov    %eax,%ecx
  xor    $0xffffffdb,%ecx
  test   $0x10,%al
  jne    L12
  movzbl %cl,%eax
  shr    $0x3,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  movzbl %al,%eax
  shr    $0x4,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  sar    %cl,%eax
L3:
  shr    $0x7,%al
  mov    %al,(%rdx)
  ret
L12:
  movzbl %cl,%eax
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  jmp    L3
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
    }
    output[0UL] = state[0UL] >> (unsigned char)7;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%rdx
  xor    $0xffffffdb,%ecx
  movzbl %cl,%eax
  test   $0x10,%cl
  je     L8
  shr    $0x3,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  movzbl %al,%esi
  shr    $0x4,%al
  and    $0x6,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  sar    %cl,%esi
  mov    %esi,%eax
  shr    $0x7,%al
  mov    %al,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  shr    $0x7,%al
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
    }
    output[0UL] = state[0UL] >> (unsigned char)7;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%rdx
  xor    $0xffffffdb,%ecx
  movzbl %cl,%eax
  test   $0x10,%cl
  je     L7
  shr    $0x3,%cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  movzbl %al,%esi
  shr    $0x4,%al
  and    $0x6,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  sar    %cl,%esi
  mov    %esi,%eax
  shr    $0x7,%al
  mov    %al,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    %cl
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  shr    $0x7,%al
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] ^ (unsigned char)219;
    if ((state[0UL] >> (unsigned char)4) & (unsigned char)1) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] >>= ((state[0UL] >> (unsigned char)4) & (unsigned char)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      state[0UL] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
    }
    output[0UL] = state[0UL] >> (unsigned char)7;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <foo2@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo1(long long param1) {
  foo2(param1);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo1>:
  endbr64
  sub    $0x8,%rsp
  call   <foo2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo1(long long param1) {
  foo2(param1);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo1>:
  endbr64
  jmp    1050 <foo2@plt>
```

assistant: ```c
void foo1(long long param1) {
  foo2(param1);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo1>:
  endbr64
  jmp    1050 <foo2@plt>
```

assistant: ```c
void foo1(long long param1) {
  foo2(param1);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  je     L99
  lea    0x10(%rsp),%r8
  mov    %r8,%rcx
  mov    $0x0,%esi
L104:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  mov    %edi,(%rcx)
  mov    %eax,%edi
  mov    %esi,%r10d
  add    $0x1,%esi
  add    $0x4,%rcx
  test   %eax,%eax
  jne    L104
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jle    L99
  movslq %r10d,%rax
  shl    $0x2,%rax
  lea    0x10(%rsp,%rax,1),%rbp
  mov    %edi,%r9d
  lea    -0x4(%r8,%rax,1),%rbx
  lea    -0x1(%r10),%r11d
  jmp    L153
L115:
  sub    $0x4,%rax
  cmp    %r8,%rax
  je     L136
L155:
  mov    -0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jle    L115
  mov    %ecx,-0x4(%rax)
  mov    %edx,(%rax)
  jmp    L115
L136:
  lea    0x1(%r9),%eax
  cmp    %r9d,%r10d
  jle    L50
  mov    %eax,%r9d
L153:
  cmp    %r9d,%r10d
  jle    L136
  mov    %r11d,%eax
  sub    %r9d,%eax
  shl    $0x2,%rax
  mov    %rbx,%r8
  sub    %rax,%r8
  mov    %rbp,%rax
  jmp    L155
L50:
  lea    D17(%rip),%rbp
  jmp    L75
L161:
  mov    $0x1,%edx
L126:
  movslq %edi,%rdi
  mov    0x10(%rsp,%rdi,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jle    L99
  mov    %ebx,%edi
L75:
  lea    0x1(%rdi),%ebx
  cmp    %esi,%ebx
  jge    L161
  movslq %edi,%rax
  mov    0x10(%rsp,%rax,4),%ecx
  lea    0x14(%rsp,%rax,4),%rax
  sub    %edi,%esi
  mov    $0x1,%edx
L39:
  cmp    (%rax),%ecx
  jne    L126
  add    $0x1,%edx
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L39
  mov    %esi,%edx
  jmp    L126
L99:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string

tool: D10: %d

tool: D17: 
 %d - %d 


assistant: ```c
int main() {
  int d[100];
  int i, j, a, b, n, count = 1;
  scanf("%d", &n);
  for (i = 0; n != 0; i++) {
    d[i] = n % 10;
    n /= 10;
  }
  n = i;
  for (i = 0; i < n; i++) {
    for (b = n - 1; b > i; b--) {
      if (d[b - 1] > d[b]) {
        a = d[b - 1];
        d[b - 1] = d[b];
        d[b] = a;
      }
    }
  }
  for (i = 0; i < n; i++) {
    for (b = i + 1; b < n; b++) {
      if (d[i] == d[b]) {
        count++;
      } else {
        break;
      }
    }
    printf("\n %d - %d \n", d[i], count);
    i = b - 1;
    count = 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  mov    %rbp,%rcx
  xor    %edi,%edi
  test   %ebx,%ebx
  je     L131
  nopl   0x0(%rax)
L107:
  movslq %ebx,%rax
  mov    %ebx,%edx
  mov    %edi,%r9d
  add    $0x4,%rcx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  add    $0x1,%edi
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  mov    %ebx,-0x4(%rcx)
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L107
  movslq %r9d,%rax
  mov    %edi,0xc(%rsp)
  xor    %r8d,%r8d
  lea    -0x1(%r9),%r11d
  lea    0x0(%rbp,%rax,4),%r10
  lea    -0x4(%r10),%r12
  cs nopw 0x0(%rax,%rax,1)
L56:
  cmp    %r8d,%r9d
  jle    L83
  mov    %r11d,%eax
  mov    %r12,%rsi
  sub    %r8d,%eax
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L25:
  mov    -0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jle    L6
  mov    %ecx,-0x4(%rax)
  mov    %edx,(%rax)
L6:
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L25
L83:
  lea    0x1(%r8),%eax
  cmp    %r8d,%r9d
  je     L98
  mov    %eax,%r8d
  jmp    L56
  nopl   (%rax)
L98:
  lea    D6(%rip),%r12
  nop
L102:
  movslq %ebx,%rax
  lea    0x1(%rbx),%edx
  mov    0x10(%rsp,%rax,4),%esi
  cmp    %edi,%edx
  jge    L120
  movslq %edx,%rax
  sub    %ebx,%edi
  mov    %edx,%ebx
  mov    $0x1,%edx
  lea    0x0(%rbp,%rax,4),%rax
  mov    %edi,%ecx
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%edx
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %edx,%ecx
  je     L44
L125:
  cmp    %esi,(%rax)
  je     L43
L44:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edi
  cmp    %ebx,%edi
  jg     L102
L131:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L120:
  mov    %edx,%ebx
  mov    $0x1,%edx
  jmp    L44
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string

tool: D18: %d

tool: D6: 
 %d - %d 


assistant: ```c
int main() {
  int d[100];
  int i, j, a, b, n, count = 1;
  scanf("%d", &n);
  for (i = 0; n != 0; i++) {
    d[i] = n % 10;
    n /= 10;
  }
  n = i;
  for (i = 0; i < n; i++) {
    for (b = n - 1; b > i; b--) {
      if (d[b - 1] > d[b]) {
        a = d[b - 1];
        d[b - 1] = d[b];
        d[b] = a;
      }
    }
  }
  for (i = 0; i < n; i++) {
    for (b = i + 1; b < n; b++) {
      if (d[i] == d[b]) {
        count++;
      } else {
        break;
      }
    }
    printf("\n %d - %d \n", d[i], count);
    i = b - 1;
    count = 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  mov    %rbp,%rcx
  xor    %esi,%esi
  test   %ebx,%ebx
  je     L94
  nopl   0x0(%rax)
L118:
  movslq %ebx,%rax
  mov    %ebx,%edx
  mov    %esi,%r9d
  add    $0x4,%rcx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  add    $0x1,%esi
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  mov    %ebx,-0x4(%rcx)
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L118
  mov    %esi,0xc(%rsp)
  test   %r9d,%r9d
  je     L26
  movslq %r9d,%rax
  xor    %r8d,%r8d
  lea    0x0(%rbp,%rax,4),%r10
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r10,%rdx
  mov    %r9d,%ecx
  xchg   %ax,%ax
L47:
  movq   -0x4(%rdx),%xmm0
  sub    $0x1,%ecx
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%eax
  movd   %xmm2,%edi
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%edi
  jge    L61
  movq   %xmm1,-0x4(%rdx)
L61:
  sub    $0x4,%rdx
  cmp    %r8d,%ecx
  jg     L47
  add    $0x1,%r8d
  cmp    %r9d,%r8d
  jne    L4
L26:
  lea    D8(%rip),%r12
  nopl   0x0(%rax)
L5:
  movslq %ebx,%rax
  lea    0x1(%rbx),%edx
  mov    0x10(%rsp,%rax,4),%r8d
  cmp    %esi,%edx
  jge    L121
  movslq %edx,%rax
  sub    %ebx,%esi
  mov    %edx,%ebx
  mov    $0x1,%edx
  lea    0x0(%rbp,%rax,4),%rax
  jmp    L117
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%edx
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %esi,%edx
  je     L69
L117:
  cmp    %r8d,(%rax)
  je     L32
L69:
  mov    %r8d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L5
L94:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L121:
  mov    %edx,%ebx
  mov    $0x1,%edx
  jmp    L69
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string

tool: D2: %d

tool: D8: 
 %d - %d 


assistant: ```c
int main() {
  int d[100];
  int i, j, a, b, n, count = 1;
  scanf("%d", &n);
  for (i = 0; n != 0; i++) {
    d[i] = n % 10;
    n /= 10;
  }
  n = i;
  for (i = 0; i < n; i++) {
    for (b = n - 1; b > i; b--) {
      if (d[b - 1] > d[b]) {
        a = d[b - 1];
        d[b - 1] = d[b];
        d[b] = a;
      }
    }
  }
  for (i = 0; i < n; i++) {
    for (b = i + 1; b < n; b++) {
      if (d[i] == d[b]) {
        count++;
      } else {
        break;
      }
    }
    printf("\n %d - %d \n", d[i], count);
    i = b - 1;
    count = 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readflip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L18:
  mov    $0x8f,%eax
  sub    -0x4(%rbp),%eax
  imul   $0xe0,%eax,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0xe0,%esi
  call   <fread@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x8f,-0x4(%rbp)
  jle    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void readflip(FILE *in, char *inbuf) {
  int y;
  for (y = 0; y < 144; y++) {
    fread(inbuf + 224 * (143 - y), 224, 1, in);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readflip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x7d20(%rsi),%rbx
L6:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0xe0,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %rbx,%rax
  sub    $0xe0,%rbx
  cmp    %rbp,%rax
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void readflip(FILE *in, char *inbuf) {
  int y;
  for (y = 0; y < 144; y++) {
    fread(inbuf + 224 * (143 - y), 224, 1, in);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<readflip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    0x7d20(%rsi),%rbx
  nopl   (%rax)
L1:
  mov    %rbx,%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0xe0,%esi
  call   <fread@plt>
  mov    %rbx,%rax
  sub    $0xe0,%rbx
  cmp    %rbp,%rax
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void readflip(FILE *in, char *inbuf) {
  int y;
  for (y = 0; y < 144; y++) {
    fread(inbuf + 224 * (143 - y), 224, 1, in);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readflip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    0x7d20(%rsi),%rbx
  nopl   (%rax)
L3:
  mov    %rbx,%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0xe0,%esi
  call   <fread@plt>
  mov    %rbx,%rax
  sub    $0xe0,%rbx
  cmp    %rax,%rbp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void readflip(FILE *in, char *inbuf) {
  int y;
  for (y = 0; y < 144; y++) {
    fread(inbuf + 224 * (143 - y), 224, 1, in);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_strconcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L12
  cmpq   $0x0,-0x40(%rbp)
  jne    L12
  mov    $0x1,%edi
  call   <ft_strnew@plt>
  jmp    L66
L12:
  cmpq   $0x0,-0x38(%rbp)
  jne    L76
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdup@plt>
  jmp    L66
L76:
  cmpq   $0x0,-0x40(%rbp)
  jne    L15
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdup@plt>
  jmp    L66
L15:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  add    %ebx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L86
L93:
  mov    -0x38(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L86:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L93
  jmp    L38
L25:
  mov    -0x40(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L38:
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L66:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strconcat(char *s1, const char *s2) {
  char *s3;
  int len;
  char *save;
  if (!s1 && !s2)
    return (ft_strnew(1));
  if (!s1)
    return (ft_strdup(s2));
  if (!s2)
    return (ft_strdup(s1));
  len = ft_strlen(s1) + ft_strlen((char *)s2);
  s3 = (char *)malloc(sizeof(char) * len + 1);
  save = s3;
  while (*s1)
    *s3++ = *s1++;
  while (*s2)
    *s3++ = *s2++;
  *s3 = '\0';
  return (save);
}
```