ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<spinel_next_packed_datatype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L49:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x28,%eax
  je     L69
  cmp    $0x29,%eax
  je     L51
  jmp    L5
L69:
  addl   $0x1,-0x4(%rbp)
  jmp    L5
L51:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  addq   $0x1,-0x18(%rbp)
L3:
  nop
L5:
  cmpl   $0x0,-0x4(%rbp)
  jle    L57
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
L57:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *spinel_next_packed_datatype(const char *pack_format) {
  int depth = 0;
  do {
    switch (*++pack_format) {
    case '(':
      depth++;
      break;
    case ')':
      depth--;
      if (depth == 0) {
        pack_format++;
      }
      break;
    }
  } while ((depth > 0) && *pack_format != 0);
  return pack_format;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spinel_next_packed_datatype>:
  endbr64
  mov    $0x0,%edx
  jmp    L11
L75:
  add    $0x1,%edx
L36:
  test   %edx,%edx
  jle    L22
L30:
  mov    %rcx,%rdi
L11:
  lea    0x1(%rdi),%rcx
  movzbl 0x1(%rdi),%eax
  cmp    $0x28,%al
  je     L75
  cmp    $0x29,%al
  je     L58
  test   %edx,%edx
  jle    L22
  test   %al,%al
  jne    L30
  jmp    L22
L58:
  sub    $0x1,%edx
  jne    L36
  lea    0x2(%rdi),%rcx
L22:
  mov    %rcx,%rax
  ret
```

assistant: ```c
const char *spinel_next_packed_datatype(const char *pack_format) {
  int depth = 0;
  do {
    switch (*++pack_format) {
    case '(':
      depth++;
      break;
    case ')':
      depth--;
      if (depth == 0) {
        pack_format++;
      }
      break;
    }
  } while ((depth > 0) && *pack_format != 0);
  return pack_format;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<spinel_next_packed_datatype>:
  endbr64
  xor    %edx,%edx
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L0:
  test   %edx,%edx
  je     L11
  test   %al,%al
  je     L11
L37:
  mov    %r8,%rdi
L67:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  cmp    $0x28,%al
  je     L80
  cmp    $0x29,%al
  jne    L0
  sub    $0x1,%edx
  test   %edx,%edx
  jne    L23
  lea    0x2(%rdi),%r8
L11:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  add    $0x1,%edx
  jmp    L37
  nopl   (%rax)
L23:
  jg     L37
  jmp    L11
```

assistant: ```c
const char *spinel_next_packed_datatype(const char *pack_format) {
  int depth = 0;
  do {
    switch (*++pack_format) {
    case '(':
      depth++;
      break;
    case ')':
      depth--;
      if (depth == 0) {
        pack_format++;
      }
      break;
    }
  } while ((depth > 0) && *pack_format != 0);
  return pack_format;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<spinel_next_packed_datatype>:
  endbr64
  xor    %edx,%edx
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L31:
  test   %edx,%edx
  je     L23
  test   %al,%al
  je     L23
L84:
  mov    %r8,%rdi
L81:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r8
  cmp    $0x28,%al
  je     L8
  cmp    $0x29,%al
  jne    L31
  sub    $0x1,%edx
  test   %edx,%edx
  jne    L65
  lea    0x2(%rdi),%r8
L23:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%edx
  jmp    L84
  nopl   (%rax)
L65:
  jg     L84
  jmp    L23
```

assistant: ```c
const char *spinel_next_packed_datatype(const char *pack_format) {
  int depth = 0;
  do {
    switch (*++pack_format) {
    case '(':
      depth++;
      break;
    case ')':
      depth--;
      if (depth == 0) {
        pack_format++;
      }
      break;
    }
  } while ((depth > 0) && *pack_format != 0);
  return pack_format;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binProb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  setg   %dl
  mov    -0x28(%rbp),%eax
  shr    $0x1f,%eax
  or     %edx,%eax
  test   %al,%al
  je     L3
  pxor   %xmm0,%xmm0
  jmp    L68
L3:
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x24(%rbp)
  jge    L87
  movsd  D10(%rip),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L40
L87:
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L40:
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L59
L94:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L26
  movsd  D10(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L26
  addl   $0x1,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L59
L26:
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L56
  addl   $0x1,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L59
L56:
  addl   $0x1,-0x14(%rbp)
  movsd  D10(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L59:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  cmp    %eax,-0x20(%rbp)
  setg   %dl
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  setl   %al
  or     %edx,%eax
  test   %al,%al
  jne    L94
  movsd  -0x8(%rbp),%xmm0
L68:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
data_type: f64

tool: D10: 1

assistant: ```c
double binProb(int n, double p, int x) {
  double pp, f;
  int xx, j0, j1, j2;
  if ((x > n) | (x < 0))
    return 0.0;
  if (2 * x > n) {
    pp = 1 - p;
    xx = n - x;
  } else {
    pp = p;
    xx = x;
  }
  j0 = j1 = j2 = 0;
  f = 1.0;
  while ((j0 < xx) | (j1 < xx) | (j2 < n - xx)) {
    if ((j0 < xx) && (f < 1)) {
      j0++;
      f *= (double)(n - xx + j0) / (double)j0;
    } else {
      if (j1 < xx) {
        j1++;
        f *= pp;
      } else {
        j2++;
        f *= 1 - pp;
      }
    }
  }
  return (f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binProb>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    %edi,%esi
  jg     L1
  test   %esi,%esi
  js     L1
  lea    (%rsi,%rsi,1),%eax
  cmp    %edi,%eax
  jle    L36
  movsd  D28(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mov    %edi,%eax
  sub    %esi,%eax
  mov    %eax,%esi
L36:
  sub    %esi,%edi
  test   %esi,%esi
  jg     L129
  test   %edi,%edi
  jle    L95
L129:
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x0,%eax
  movsd  D28(%rip),%xmm0
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  jmp    L32
L76:
  cmp    %edx,%esi
  jle    L89
  add    $0x1,%edx
  mulsd  %xmm1,%xmm0
L50:
  cmp    %eax,%edx
  mov    %eax,%ecx
  cmovle %edx,%ecx
  cmp    %esi,%ecx
  jl     L32
  cmp    %edi,%r8d
  jge    L122
L32:
  cmp    %eax,%esi
  jle    L76
  comisd %xmm0,%xmm3
  jbe    L76
  add    $0x1,%eax
  lea    (%rax,%rdi,1),%ecx
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  divsd  %xmm5,%xmm2
  mulsd  %xmm2,%xmm0
  jmp    L50
L89:
  add    $0x1,%r8d
  movapd %xmm4,%xmm2
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  jmp    L50
L122:
  ret
L1:
  pxor   %xmm0,%xmm0
  ret
L95:
  movsd  D28(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D28
datatype: f64

tool: D28: 1

assistant: ```c
double binProb(int n, double p, int x) {
  double pp, f;
  int xx, j0, j1, j2;
  if ((x > n) | (x < 0))
    return 0.0;
  if (2 * x > n) {
    pp = 1 - p;
    xx = n - x;
  } else {
    pp = p;
    xx = x;
  }
  j0 = j1 = j2 = 0;
  f = 1.0;
  while ((j0 < xx) | (j1 < xx) | (j2 < n - xx)) {
    if ((j0 < xx) && (f < 1)) {
      j0++;
      f *= (double)(n - xx + j0) / (double)j0;
    } else {
      if (j1 < xx) {
        j1++;
        f *= pp;
      } else {
        j2++;
        f *= 1 - pp;
      }
    }
  }
  return (f);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binProb>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    %edi,%esi
  jg     L29
  test   %esi,%esi
  js     L29
  mov    %edi,%r8d
  lea    (%rsi,%rsi,1),%eax
  movsd  D2(%rip),%xmm2
  sub    %esi,%r8d
  cmp    %edi,%eax
  jle    L31
  movapd %xmm2,%xmm5
  mov    %esi,%eax
  mov    %r8d,%esi
  subsd  %xmm0,%xmm5
  mov    %eax,%r8d
  movapd %xmm5,%xmm1
L31:
  test   %esi,%esi
  jg     L109
  test   %r8d,%r8d
  jle    L91
L109:
  xor    %edi,%edi
  xor    %edx,%edx
  movapd %xmm2,%xmm0
  xor    %eax,%eax
  nopl   0x0(%rax)
L40:
  cmp    %eax,%esi
  jle    L48
  comisd %xmm0,%xmm2
  ja     L89
L48:
  cmp    %edx,%esi
  jle    L21
  mulsd  %xmm1,%xmm0
  add    $0x1,%edx
L59:
  cmp    %edx,%eax
  mov    %edx,%ecx
  cmovle %eax,%ecx
  cmp    %esi,%ecx
  jl     L40
  cmp    %r8d,%edi
  jl     L40
  ret
  xchg   %ax,%ax
L21:
  movapd %xmm2,%xmm3
  add    $0x1,%edi
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm0
  jmp    L59
  nopl   0x0(%rax)
L89:
  add    $0x1,%eax
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  lea    (%rax,%r8,1),%ecx
  cvtsi2sd %ecx,%xmm3
  divsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm0
  jmp    L59
  nopl   0x0(%rax)
L29:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L91:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: f64

tool: D2: 1

assistant: ```c
double binProb(int n, double p, int x) {
  double pp, f;
  int xx, j0, j1, j2;
  if ((x > n) | (x < 0))
    return 0.0;
  if (2 * x > n) {
    pp = 1 - p;
    xx = n - x;
  } else {
    pp = p;
    xx = x;
  }
  j0 = j1 = j2 = 0;
  f = 1.0;
  while ((j0 < xx) | (j1 < xx) | (j2 < n - xx)) {
    if ((j0 < xx) && (f < 1)) {
      j0++;
      f *= (double)(n - xx + j0) / (double)j0;
    } else {
      if (j1 < xx) {
        j1++;
        f *= pp;
      } else {
        j2++;
        f *= 1 - pp;
      }
    }
  }
  return (f);
}
```
user: What is the c source code of the assembly code below?

```asm
<binProb>:
  endbr64
  movapd %xmm0,%xmm1
  cmp    %edi,%esi
  jg     L77
  test   %esi,%esi
  js     L77
  mov    %edi,%r8d
  lea    (%rsi,%rsi,1),%eax
  movsd  D1(%rip),%xmm2
  sub    %esi,%r8d
  cmp    %edi,%eax
  jle    L50
  movapd %xmm2,%xmm5
  mov    %esi,%eax
  mov    %r8d,%esi
  subsd  %xmm0,%xmm5
  mov    %eax,%r8d
  movapd %xmm5,%xmm1
L50:
  test   %esi,%esi
  jg     L106
  test   %r8d,%r8d
  jle    L86
L106:
  xor    %ecx,%ecx
  xor    %eax,%eax
  movapd %xmm2,%xmm0
  xor    %edx,%edx
L117:
  cmp    %edx,%esi
  jg     L56
L125:
  cmp    %eax,%esi
  jle    L90
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
L188:
  cmp    %edx,%eax
  mov    %edx,%edi
  cmovle %eax,%edi
  cmp    %esi,%edi
  jl     L70
  cmp    %r8d,%ecx
  jge    L161
L70:
  cmp    %edx,%esi
  jle    L76
L56:
  comisd %xmm0,%xmm2
  jbe    L125
  add    $0x1,%edx
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  cvtsi2sd %edx,%xmm4
  lea    (%rdx,%r8,1),%edi
  cmp    %eax,%edx
  cvtsi2sd %edi,%xmm3
  mov    %eax,%edi
  cmovle %edx,%edi
  divsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm0
  cmp    %edi,%esi
  jg     L117
  cmp    %r8d,%ecx
  jl     L117
  ret
  nopl   0x0(%rax)
L85:
  mulsd  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    %eax,%edx
  mov    %eax,%edi
  cmovle %edx,%edi
  cmp    %edi,%esi
  jg     L76
  cmp    %ecx,%r8d
  jle    L92
  nopw   0x0(%rax,%rax,1)
L76:
  cmp    %eax,%esi
  jg     L85
  movapd %xmm2,%xmm3
  add    $0x1,%ecx
  mov    %eax,%edi
  cmp    %eax,%edx
  subsd  %xmm1,%xmm3
  cmovle %edx,%edi
  mulsd  %xmm3,%xmm0
  cmp    %edi,%esi
  jg     L76
  cmp    %ecx,%r8d
  jg     L76
  ret
  nopl   0x0(%rax)
L90:
  movapd %xmm2,%xmm3
  add    $0x1,%ecx
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm0
  jmp    L188
  nopl   0x0(%rax)
L86:
  movapd %xmm2,%xmm0
L161:
  ret
  nopl   (%rax)
L92:
  ret
  nopl   0x0(%rax)
L77:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: f64

tool: D1: 1

assistant: ```c
double binProb(int n, double p, int x) {
  double pp, f;
  int xx, j0, j1, j2;
  if ((x > n) | (x < 0))
    return 0.0;
  if (2 * x > n) {
    pp = 1 - p;
    xx = n - x;
  } else {
    pp = p;
    xx = x;
  }
  j0 = j1 = j2 = 0;
  f = 1.0;
  while ((j0 < xx) | (j1 < xx) | (j2 < n - xx)) {
    if ((j0 < xx) && (f < 1)) {
      j0++;
      f *= (double)(n - xx + j0) / (double)j0;
    } else {
      if (j1 < xx) {
        j1++;
        f *= pp;
      } else {
        j2++;
        f *= 1 - pp;
      }
    }
  }
  return (f);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_lopkt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  cmpq   $0x13,-0x20(%rbp)
  jbe    L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  cmp    $0x4,%eax
  jne    L20
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xd,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xe,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xf,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7fffffff,%eax
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L37
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x11,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x12,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x13,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  and    $0x7fffffff,%eax
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  nop
L20:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_lopkt(const char *datagram, const size_t datagram_sz) {
  int retval = 0;
  unsigned int ip4_addr = 0;
  if (datagram != NULL && datagram_sz >= 20) {
    switch (((*datagram) & 0xf0) >> 4) {
    case 4:
      ip4_addr = (((unsigned int)datagram[12]) << 24) | (((unsigned int)datagram[13]) << 16) | (((unsigned int)datagram[14]) << 8) | ((unsigned int)datagram[15]);
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      if (retval == 0) {
        ip4_addr = (((unsigned int)datagram[16]) << 24) | (((unsigned int)datagram[17]) << 16) | (((unsigned int)datagram[18]) << 8) | ((unsigned int)datagram[19]);
      }
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      break;
    }
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_lopkt>:
  endbr64
  test   %rdi,%rdi
  je     L16
  cmp    $0x13,%rsi
  jbe    L16
  movsbl (%rdi),%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  mov    $0x0,%ecx
  cmp    $0x4,%edx
  jne    L31
  movsbl 0xc(%rdi),%edx
  shl    $0x18,%edx
  movsbl 0xd(%rdi),%ecx
  shl    $0x10,%ecx
  or     %ecx,%edx
  movsbl 0xf(%rdi),%ecx
  or     %ecx,%edx
  movsbl 0xe(%rdi),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  jns    L28
  movsbl 0x10(%rdi),%edx
  shl    $0x18,%edx
  movsbl 0x11(%rdi),%ecx
  shl    $0x10,%ecx
  or     %ecx,%edx
  movsbl 0x13(%rdi),%ecx
  or     %ecx,%edx
  movsbl 0x12(%rdi),%eax
  shl    $0x8,%eax
  or     %eax,%edx
L28:
  test   %edx,%edx
  setns  %cl
  movzbl %cl,%ecx
  jmp    L31
L16:
  mov    $0x0,%ecx
L31:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int is_lopkt(const char *datagram, const size_t datagram_sz) {
  int retval = 0;
  unsigned int ip4_addr = 0;
  if (datagram != NULL && datagram_sz >= 20) {
    switch (((*datagram) & 0xf0) >> 4) {
    case 4:
      ip4_addr = (((unsigned int)datagram[12]) << 24) | (((unsigned int)datagram[13]) << 16) | (((unsigned int)datagram[14]) << 8) | ((unsigned int)datagram[15]);
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      if (retval == 0) {
        ip4_addr = (((unsigned int)datagram[16]) << 24) | (((unsigned int)datagram[17]) << 16) | (((unsigned int)datagram[18]) << 8) | ((unsigned int)datagram[19]);
      }
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      break;
    }
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_lopkt>:
  endbr64
  test   %rdi,%rdi
  je     L2
  cmp    $0x13,%rsi
  jbe    L2
  movsbl (%rdi),%edx
  xor    %r8d,%r8d
  sar    $0x4,%edx
  and    $0xf,%edx
  cmp    $0x4,%edx
  je     L26
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nop
L26:
  movsbl 0xc(%rdi),%edx
  movsbl 0xd(%rdi),%ecx
  shl    $0x18,%edx
  shl    $0x10,%ecx
  or     %ecx,%edx
  movsbl 0xf(%rdi),%ecx
  or     %ecx,%edx
  movsbl 0xe(%rdi),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  mov    %edx,%ecx
  jns    L1
  movsbl 0x10(%rdi),%edx
  movsbl 0x11(%rdi),%ecx
  movsbl 0x12(%rdi),%eax
  shl    $0x10,%ecx
  shl    $0x18,%edx
  or     %ecx,%edx
  movsbl 0x13(%rdi),%ecx
  shl    $0x8,%eax
  or     %ecx,%edx
  or     %eax,%edx
  mov    %edx,%ecx
  and    $0x7fffffff,%ecx
L1:
  xor    %r8d,%r8d
  cmp    %ecx,%edx
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_lopkt(const char *datagram, const size_t datagram_sz) {
  int retval = 0;
  unsigned int ip4_addr = 0;
  if (datagram != NULL && datagram_sz >= 20) {
    switch (((*datagram) & 0xf0) >> 4) {
    case 4:
      ip4_addr = (((unsigned int)datagram[12]) << 24) | (((unsigned int)datagram[13]) << 16) | (((unsigned int)datagram[14]) << 8) | ((unsigned int)datagram[15]);
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      if (retval == 0) {
        ip4_addr = (((unsigned int)datagram[16]) << 24) | (((unsigned int)datagram[17]) << 16) | (((unsigned int)datagram[18]) << 8) | ((unsigned int)datagram[19]);
      }
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      break;
    }
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_lopkt>:
  endbr64
  test   %rdi,%rdi
  je     L24
  cmp    $0x13,%rsi
  jbe    L24
  movsbl (%rdi),%edx
  xor    %r8d,%r8d
  sar    $0x4,%edx
  and    $0xf,%edx
  cmp    $0x4,%edx
  je     L35
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nop
L35:
  movsbl 0xc(%rdi),%edx
  movsbl 0xd(%rdi),%ecx
  shl    $0x18,%edx
  shl    $0x10,%ecx
  or     %ecx,%edx
  movsbl 0xf(%rdi),%ecx
  or     %ecx,%edx
  movsbl 0xe(%rdi),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  mov    %edx,%ecx
  jns    L26
  movsbl 0x10(%rdi),%edx
  movsbl 0x11(%rdi),%ecx
  movsbl 0x12(%rdi),%eax
  shl    $0x10,%ecx
  shl    $0x18,%edx
  or     %ecx,%edx
  movsbl 0x13(%rdi),%ecx
  shl    $0x8,%eax
  or     %ecx,%edx
  or     %eax,%edx
  mov    %edx,%ecx
  and    $0x7fffffff,%ecx
L26:
  xor    %r8d,%r8d
  cmp    %ecx,%edx
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_lopkt(const char *datagram, const size_t datagram_sz) {
  int retval = 0;
  unsigned int ip4_addr = 0;
  if (datagram != NULL && datagram_sz >= 20) {
    switch (((*datagram) & 0xf0) >> 4) {
    case 4:
      ip4_addr = (((unsigned int)datagram[12]) << 24) | (((unsigned int)datagram[13]) << 16) | (((unsigned int)datagram[14]) << 8) | ((unsigned int)datagram[15]);
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      if (retval == 0) {
        ip4_addr = (((unsigned int)datagram[16]) << 24) | (((unsigned int)datagram[17]) << 16) | (((unsigned int)datagram[18]) << 8) | ((unsigned int)datagram[19]);
      }
      retval = ((ip4_addr & 0x7fffffff) == ip4_addr);
      break;
    }
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<shiftL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L5
L8:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%r10
  mov    %rax,%rdi
  call   <_shiftL.0>
L5:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void shiftL(char *argv[]) {
  int i = 0;
  auto void _shiftL(char *s);
  void _shiftL(char *s) {
    argv[i] = argv[i + 1];
    i++;
  }
  ({
    int _i__ = 0;
    while ((argv)[_i__])
      _shiftL((argv)[_i__++]);
  });
}
```
user: Translate the below assembly code into C programming language:

```asm
<shiftL>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L3
  add    $0x8,%rdi
L2:
  mov    (%rdi),%rax
  mov    %rax,-0x8(%rdi)
  add    $0x8,%rdi
  cmpq   $0x0,-0x8(%rdi)
  jne    L2
L3:
  ret
```

assistant: ```c
void shiftL(char *argv[]) {
  int i = 0;
  auto void _shiftL(char *s);
  void _shiftL(char *s) {
    argv[i] = argv[i + 1];
    i++;
  }
  ({
    int _i__ = 0;
    while ((argv)[_i__])
      _shiftL((argv)[_i__++]);
  });
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shiftL>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L18
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
  mov    %rax,-0x8(%rdi)
  test   %rax,%rax
  jne    L16
L18:
  ret
```

assistant: ```c
void shiftL(char *argv[]) {
  int i = 0;
  auto void _shiftL(char *s);
  void _shiftL(char *s) {
    argv[i] = argv[i + 1];
    i++;
  }
  ({
    int _i__ = 0;
    while ((argv)[_i__])
      _shiftL((argv)[_i__++]);
  });
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shiftL>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L6
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x8(%rdi),%rax
  add    $0x8,%rdi
  mov    %rax,-0x8(%rdi)
  test   %rax,%rax
  jne    L9
L6:
  ret
```

assistant: ```c
void shiftL(char *argv[]) {
  int i = 0;
  auto void _shiftL(char *s);
  void _shiftL(char *s) {
    argv[i] = argv[i + 1];
    i++;
  }
  ({
    int _i__ = 0;
    while ((argv)[_i__])
      _shiftL((argv)[_i__++]);
  });
}
```