ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_data_as_json>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  lea    D21(%rip),%rsi
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %r12d,%ecx
  mov    %r15,%rdx
  mov    %rbp,%rdi
  lea    D44(%rip),%r15
  lea    D56(%rip),%rsi
  call   <write_named_array_f64@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %rbp,%rdi
  lea    D45(%rip),%rsi
  call   <write_named_array_f64@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  lea    D19(%rip),%rsi
  call   <write_named_array_f64@plt>
  mov    %rbp,%rdi
  lea    D6(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
data_type: string
name: extract_symbolic_data
arguments: label: D44
data_type: string
name: extract_symbolic_data
arguments: label: D56
data_type: string
name: extract_symbolic_data
arguments: label: D45
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D21: {

tool: D44: ,

tool: D56: x

tool: D45: S

tool: D19: C

tool: D6: }

assistant: ```c
void write_data_as_json(FILE *f, const double *x, const double *S, const double *C, const unsigned int len) {
  fprintf(f, "{");
  write_named_array_f64(f, "x", x, len);
  fprintf(f, ",");
  write_named_array_f64(f, "S", S, len);
  fprintf(f, ",");
  write_named_array_f64(f, "C", C, len);
  fprintf(f, "}");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0xa,-0x14(%rbp)
  jne    L7
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L2
L7:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <fun>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D29
data_type: string

tool: D26: LEVEL %d


tool: D6: SHOULD NOT BE PRINTED 1

tool: D29: SHOULD NOT BE PRINTED 2

assistant: ```c
void fun(int level) {
  void *my_mem = malloc(1000);
  if (0) {
    printf("FREE AT LEVEL %d\n", level);
    free(my_mem);
  }
  if (0) {
    printf("I got destroyed or returned %d\n", level);
  }
  printf("LEVEL %d\n", level);
  if (level == 10) {
    ;
    printf("SHOULD NOT BE PRINTED 1\n");
    return;
  } else {
    fun(level + 1);
    printf("SHOULD NOT BE PRINTED 2\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fun>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %ebx,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0xa,%ebx
  je     L13
  lea    0x1(%rbx),%edi
  call   <fun>
  lea    D29(%rip),%rdi
  call   <puts@plt>
L12:
  pop    %rbx
  ret
L13:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D29
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string

tool: D28: LEVEL %d


tool: D29: SHOULD NOT BE PRINTED 2

tool: D25: SHOULD NOT BE PRINTED 1

assistant: ```c
void fun(int level) {
  void *my_mem = malloc(1000);
  if (0) {
    printf("FREE AT LEVEL %d\n", level);
    free(my_mem);
  }
  if (0) {
    printf("I got destroyed or returned %d\n", level);
  }
  printf("LEVEL %d\n", level);
  if (level == 10) {
    ;
    printf("SHOULD NOT BE PRINTED 1\n");
    return;
  } else {
    fun(level + 1);
    printf("SHOULD NOT BE PRINTED 2\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pattern_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x30(%rbp)
  jne    L78
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <find_percent@plt>
  mov    %rax,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L29
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  je     L20
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L15
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L15
L20:
  mov    $0x1,%eax
  jmp    L39
L15:
  mov    $0x0,%eax
  jmp    L39
L29:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L78:
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%eax
  add    %rcx,%rax
  cmp    %rax,%rdx
  jl     L47
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L41
L47:
  mov    $0x0,%eax
  jmp    L39
L41:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int pattern_matches(const char *pattern, const char *percent, const char *str) {
  unsigned int sfxlen, strlength;
  if (percent == 0) {
    unsigned int len = strlen(pattern) + 1;
    char *new_chars = alloca(len);
    memcpy(new_chars, pattern, len);
    percent = find_percent(new_chars);
    if (percent == 0)
      return ((new_chars) == (str) || (*(new_chars) == *(str) && (*(new_chars) == '\0' || !strcmp((new_chars) + 1, (str) + 1))));
    pattern = new_chars;
  }
  sfxlen = strlen(percent + 1);
  strlength = strlen(str);
  if (strlength < (percent - pattern) + sfxlen || !(strncmp((pattern), (str), (percent - pattern)) == 0))
    return 0;
  return !strcmp(percent + 1, str + (strlength - sfxlen));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pattern_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L16
L59:
  lea    0x1(%rbx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,-0x44(%rbp)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  sub    %r13,%rbx
  mov    %eax,%ecx
  mov    -0x44(%rbp),%eax
  add    %rbx,%rax
  mov    $0x0,%edx
  cmp    %rax,%rcx
  jge    L43
L98:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    %edx,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L16:
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r14,%rdi
  call   <find_percent@plt>
  mov    %rax,%rbx
  mov    %r14,%r13
  test   %rax,%rax
  jne    L59
  mov    $0x1,%edx
  cmp    %r12,%r14
  je     L98
  movzbl (%r14),%eax
  mov    $0x0,%edx
  cmp    (%r12),%al
  jne    L98
  mov    $0x1,%edx
  test   %al,%al
  je     L98
  lea    0x1(%r12),%rsi
  lea    0x1(%r14),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
  jmp    L98
L43:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  jne    L98
  sub    -0x44(%rbp),%r14d
  lea    (%r12,%r14,1),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
  jmp    L98
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pattern_matches(const char *pattern, const char *percent, const char *str) {
  unsigned int sfxlen, strlength;
  if (percent == 0) {
    unsigned int len = strlen(pattern) + 1;
    char *new_chars = alloca(len);
    memcpy(new_chars, pattern, len);
    percent = find_percent(new_chars);
    if (percent == 0)
      return ((new_chars) == (str) || (*(new_chars) == *(str) && (*(new_chars) == '\0' || !strcmp((new_chars) + 1, (str) + 1))));
    pattern = new_chars;
  }
  sfxlen = strlen(percent + 1);
  strlength = strlen(str);
  if (strlength < (percent - pattern) + sfxlen || !(strncmp((pattern), (str), (percent - pattern)) == 0))
    return 0;
  return !strcmp(percent + 1, str + (strlength - sfxlen));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pattern_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L94
L33:
  lea    0x1(%rbx),%r13
  sub    %r14,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,-0x44(%rbp)
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x44(%rbp),%eax
  mov    %rdx,%r15
  add    %rbx,%rax
  cmp    %rax,%rdx
  jge    L6
L24:
  xor    %r13d,%r13d
L39:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L24
  sub    -0x44(%rbp),%r15d
  mov    %r13,%rdi
  xor    %r13d,%r13d
  lea    (%r12,%r15,1),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %r13b
  jmp    L39
  nopl   (%rax)
L94:
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <alloca@plt>
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdi
  mov    %r15,%r14
  call   <find_percent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L33
  mov    $0x1,%r13d
  cmp    %r12,%r15
  je     L39
  movzbl (%r15),%eax
  cmp    (%r12),%al
  jne    L24
  test   %al,%al
  je     L39
  lea    0x1(%r12),%rsi
  lea    0x1(%r15),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L39
  jmp    L24
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pattern_matches(const char *pattern, const char *percent, const char *str) {
  unsigned int sfxlen, strlength;
  if (percent == 0) {
    unsigned int len = strlen(pattern) + 1;
    char *new_chars = alloca(len);
    memcpy(new_chars, pattern, len);
    percent = find_percent(new_chars);
    if (percent == 0)
      return ((new_chars) == (str) || (*(new_chars) == *(str) && (*(new_chars) == '\0' || !strcmp((new_chars) + 1, (str) + 1))));
    pattern = new_chars;
  }
  sfxlen = strlen(percent + 1);
  strlength = strlen(str);
  if (strlength < (percent - pattern) + sfxlen || !(strncmp((pattern), (str), (percent - pattern)) == 0))
    return 0;
  return !strcmp(percent + 1, str + (strlength - sfxlen));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pattern_matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L62
L66:
  lea    0x1(%rbx),%r13
  sub    %r14,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,-0x44(%rbp)
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x44(%rbp),%eax
  mov    %rdx,%r15
  add    %rbx,%rax
  cmp    %rax,%rdx
  jge    L8
L93:
  xor    %r13d,%r13d
L107:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L93
  sub    -0x44(%rbp),%r15d
  mov    %r13,%rdi
  xor    %r13d,%r13d
  lea    (%r12,%r15,1),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %r13b
  jmp    L107
  nopl   (%rax)
L62:
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <alloca@plt>
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r15,%rdi
  mov    %r15,%r14
  call   <find_percent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L66
  mov    $0x1,%r13d
  cmp    %r12,%r15
  je     L107
  movzbl (%r15),%eax
  cmp    (%r12),%al
  jne    L93
  test   %al,%al
  je     L107
  lea    0x1(%r12),%rsi
  lea    0x1(%r15),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L107
  jmp    L93
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pattern_matches(const char *pattern, const char *percent, const char *str) {
  unsigned int sfxlen, strlength;
  if (percent == 0) {
    unsigned int len = strlen(pattern) + 1;
    char *new_chars = alloca(len);
    memcpy(new_chars, pattern, len);
    percent = find_percent(new_chars);
    if (percent == 0)
      return ((new_chars) == (str) || (*(new_chars) == *(str) && (*(new_chars) == '\0' || !strcmp((new_chars) + 1, (str) + 1))));
    pattern = new_chars;
  }
  sfxlen = strlen(percent + 1);
  strlength = strlen(str);
  if (strlength < (percent - pattern) + sfxlen || !(strncmp((pattern), (str), (percent - pattern)) == 0))
    return 0;
  return !strcmp(percent + 1, str + (strlength - sfxlen));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L1:
  movsd  -0x10(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D37(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jae    L1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x14(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: f64
name: disassemble_data
arguments: label: D19
data_type: byte[8]
name: disassemble_data
arguments: label: D37
data_type: byte[8]
name: disassemble_data
arguments: label: D51
data_type: string
name: disassemble_data
arguments: label: D60
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D7: 100

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D37": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: D51: After %d years, Deirdre's investment will exceed the value of Daphne's investment.


tool: D60: Deirdre's investment: %.2lf


tool: D0: Daphne's investment:  %.2lf


assistant: ```c
int main(void) {
  double valueDa = 100.0, valueDe = 100.0;
  int count = 0;
  while (valueDe <= valueDa) {
    valueDa += 100.0 * 0.1;
    valueDe *= (1.0 + 0.05);
    count++;
  }
  printf("After %d years, Deirdre's investment will exceed the value of Daphne's investment.\n", count);
  printf("Deirdre's investment: %.2lf\n", valueDe);
  printf("Daphne's investment:  %.2lf\n", valueDa);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  mov    D61(%rip),%rbx
  mov    %rbx,%rbp
  movsd  D28(%rip),%xmm1
  movsd  D0(%rip),%xmm0
L6:
  movq   %rbp,%xmm2
  addsd  %xmm1,%xmm2
  movq   %xmm2,%rbp
  movq   %rbx,%xmm3
  mulsd  %xmm0,%xmm3
  movq   %xmm3,%rbx
  add    $0x1,%eax
  cmp    $0x1b,%eax
  jne    L6
  movsd  D11(%rip),%xmm0
  lea    D63(%rip),%rdi
  call   <printf@plt>
  movq   %rbx,%xmm0
  lea    D34(%rip),%rdi
  call   <printf@plt>
  movq   %rbp,%xmm0
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D61
data_type: f64
name: parse_data
arguments: label: D28
data_type: byte[8]
name: parse_data
arguments: label: D0
data_type: byte[8]
name: parse_data
arguments: label: D11
data_type: byte[8]
name: parse_data
arguments: label: D63
data_type: string
name: parse_data
arguments: label: D34
data_type: string
name: parse_data
arguments: label: D33
data_type: string

tool: D61: 100

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D0": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x3b,0x40]}

tool: D63: After %d years, Deirdre's investment will exceed the value of Daphne's investment.


tool: D34: Deirdre's investment: %.2lf


tool: D33: Daphne's investment:  %.2lf


assistant: ```c
int main(void) {
  double valueDa = 100.0, valueDe = 100.0;
  int count = 0;
  while (valueDe <= valueDa) {
    valueDa += 100.0 * 0.1;
    valueDe *= (1.0 + 0.05);
    count++;
  }
  printf("After %d years, Deirdre's investment will exceed the value of Daphne's investment.\n", count);
  printf("Deirdre's investment: %.2lf\n", valueDe);
  printf("Daphne's investment:  %.2lf\n", valueDa);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movsd  D31(%rip),%xmm1
  movsd  D23(%rip),%xmm3
  xor    %eax,%eax
  movsd  D3(%rip),%xmm0
  movapd %xmm1,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L7:
  mulsd  %xmm0,%xmm1
  add    $0x1,%eax
  addsd  %xmm3,%xmm2
  cmp    $0x1b,%eax
  jne    L7
  movsd  D61(%rip),%xmm0
  lea    D46(%rip),%rdi
  movsd  %xmm2,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D69(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  (%rsp),%xmm2
  lea    D64(%rip),%rdi
  movapd %xmm2,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D31
datatype: f64
name: retrieve_data
arguments: label: D23
datatype: byte[8]
name: retrieve_data
arguments: label: D3
datatype: byte[8]
name: retrieve_data
arguments: label: D61
datatype: byte[8]
name: retrieve_data
arguments: label: D46
datatype: string
name: retrieve_data
arguments: label: D69
datatype: string
name: retrieve_data
arguments: label: D64
datatype: string

tool: D31: 100

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D3": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x3b,0x40]}

tool: D46: After %d years, Deirdre's investment will exceed the value of Daphne's investment.


tool: D69: Deirdre's investment: %.2lf


tool: D64: Daphne's investment:  %.2lf


assistant: ```c
int main(void) {
  double valueDa = 100.0, valueDe = 100.0;
  int count = 0;
  while (valueDe <= valueDa) {
    valueDa += 100.0 * 0.1;
    valueDe *= (1.0 + 0.05);
    count++;
  }
  printf("After %d years, Deirdre's investment will exceed the value of Daphne's investment.\n", count);
  printf("Deirdre's investment: %.2lf\n", valueDe);
  printf("Daphne's investment:  %.2lf\n", valueDa);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movsd  D3(%rip),%xmm1
  movsd  D2(%rip),%xmm3
  xor    %eax,%eax
  movsd  D60(%rip),%xmm0
  movapd %xmm1,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L5:
  mulsd  %xmm0,%xmm1
  add    $0x1,%eax
  addsd  %xmm3,%xmm2
  cmp    $0x1b,%eax
  jne    L5
  movsd  D63(%rip),%xmm0
  lea    D13(%rip),%rdi
  movsd  %xmm2,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D18(%rip),%rdi
  movapd %xmm1,%xmm0
  call   <printf@plt>
  movsd  (%rsp),%xmm2
  lea    D0(%rip),%rdi
  movapd %xmm2,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: f64
name: unpack_data
arguments: tag: D2
data_type: byte[8]
name: unpack_data
arguments: tag: D60
data_type: byte[8]
name: unpack_data
arguments: tag: D63
data_type: byte[8]
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D3: 100

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D60": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xf0,0x3f]}

tool: {"D63": [0x00,0x00,0x00,0x00,0x00,0x00,0x3b,0x40]}

tool: D13: After %d years, Deirdre's investment will exceed the value of Daphne's investment.


tool: D18: Deirdre's investment: %.2lf


tool: D0: Daphne's investment:  %.2lf


assistant: ```c
int main(void) {
  double valueDa = 100.0, valueDe = 100.0;
  int count = 0;
  while (valueDe <= valueDa) {
    valueDa += 100.0 * 0.1;
    valueDe *= (1.0 + 0.05);
    count++;
  }
  printf("After %d years, Deirdre's investment will exceed the value of Daphne's investment.\n", count);
  printf("Deirdre's investment: %.2lf\n", valueDe);
  printf("Daphne's investment:  %.2lf\n", valueDa);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x5(%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <sub>
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
int sub(int n, int a) {
  if (n > 0) {
    printf("%d ", n);
    sub(n - 5, a);
  }
  if (n <= a)
    printf("%d ", n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sub>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %edi,%edi
  jg     L22
L24:
  cmp    %ebp,%ebx
  jle    L11
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    -0x5(%rbx),%edi
  mov    %ebp,%esi
  call   <sub>
  jmp    L24
L11:
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d 

assistant: ```c
int sub(int n, int a) {
  if (n > 0) {
    printf("%d ", n);
    sub(n - 5, a);
  }
  if (n <= a)
    printf("%d ", n);
}
```