ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<path_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L2
L13:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L2:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int path_split(char *path, char **dirname, char **basename) {
  char *slash;
  int relative;
  relative = (path[0] != '/');
  slash = strrchr(path, '/');
  if (slash == NULL) {
    *basename = path;
    *dirname = path + strlen(path);
  } else {
    slash[0] = '\0';
    *dirname = path;
    *basename = slash + 1;
  }
  return relative;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<path_split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  cmpb   $0x2f,(%rdi)
  setne  %r12b
  movzbl %r12b,%r12d
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
  mov    %rbx,0x0(%r13)
  add    $0x1,%rax
  mov    %rax,0x0(%rbp)
L1:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  mov    %rax,0x0(%r13)
  jmp    L1
```

assistant: ```c
int path_split(char *path, char **dirname, char **basename) {
  char *slash;
  int relative;
  relative = (path[0] != '/');
  slash = strrchr(path, '/');
  if (slash == NULL) {
    *basename = path;
    *dirname = path + strlen(path);
  } else {
    slash[0] = '\0';
    *dirname = path;
    *basename = slash + 1;
  }
  return relative;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<path_split>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rdi)
  setne  %r13b
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rbx,(%r12)
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L6:
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  mov    %r13d,%eax
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int path_split(char *path, char **dirname, char **basename) {
  char *slash;
  int relative;
  relative = (path[0] != '/');
  slash = strrchr(path, '/');
  if (slash == NULL) {
    *basename = path;
    *dirname = path + strlen(path);
  } else {
    slash[0] = '\0';
    *dirname = path;
    *basename = slash + 1;
  }
  return relative;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<path_split>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rdi)
  setne  %r13b
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rbx,(%r12)
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbx
  mov    %r13d,%eax
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int path_split(char *path, char **dirname, char **basename) {
  char *slash;
  int relative;
  relative = (path[0] != '/');
  slash = strrchr(path, '/');
  if (slash == NULL) {
    *basename = path;
    *dirname = path + strlen(path);
  } else {
    slash[0] = '\0';
    *dirname = path;
    *basename = slash + 1;
  }
  return relative;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<comparar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L85
L154:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L18
  addl   $0x1,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L150
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L150:
  movl   $0x1,-0xc(%rbp)
  jmp    L119
L18:
  addl   $0x1,-0xc(%rbp)
L119:
  addl   $0x1,-0x8(%rbp)
L85:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L154
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L248
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L248:
  cmpl   $0x3,-0x14(%rbp)
  je     L206
  cmpl   $0x3,-0x14(%rbp)
  jg     L153
  cmpl   $0x2,-0x14(%rbp)
  je     L4
  cmpl   $0x2,-0x14(%rbp)
  jg     L153
  cmpl   $0x0,-0x14(%rbp)
  je     L168
  cmpl   $0x1,-0x14(%rbp)
  je     L149
  jmp    L153
L168:
  mov    $0x6,%eax
  jmp    L32
L149:
  cmpl   $0x4,-0x10(%rbp)
  jne    L183
  mov    $0x5,%eax
  jmp    L32
L183:
  cmpl   $0x3,-0x10(%rbp)
  jne    L61
  mov    $0x4,%eax
  jmp    L32
L4:
  cmpl   $0x3,-0x10(%rbp)
  jne    L51
  mov    $0x3,%eax
  jmp    L32
L51:
  cmpl   $0x2,-0x10(%rbp)
  jne    L166
  mov    $0x2,%eax
  jmp    L32
L206:
  mov    $0x1,%eax
  jmp    L32
L153:
  mov    $0x0,%eax
  jmp    L32
L61:
  nop
  jmp    L32
L166:
  nop
L32:
  pop    %rbp
  ret
```

assistant: ```c
int comparar(int *jugada, int length) {
  int anterior;
  int cambios = 0, posibilidad = 0;
  int max = 0, actual = 1;
  for (int i = 1; i < length; i++) {
    if (jugada[i - 1] != jugada[i]) {
      cambios++;
      if (actual > max)
        max = actual;
      actual = 1;
    } else {
      actual++;
    }
  }
  if (actual > max)
    max = actual;
  switch (cambios) {
  case 0:
    return 6;
    break;
  case 1:
    if (max == 4)
      return 5;
    else if (max == 3)
      return 4;
    break;
  case 2:
    if (max == 3)
      return 3;
    else if (max == 2)
      return 2;
    break;
  case 3:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<comparar>:
  endbr64
  cmp    $0x1,%esi
  jle    L10
  mov    %rdi,%rdx
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x1,%ecx
  mov    $0x0,%eax
  mov    $0x0,%esi
  jmp    L107
L35:
  add    $0x1,%ecx
L120:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L82
L107:
  mov    0x4(%rdx),%r8d
  cmp    %r8d,(%rdx)
  je     L35
  add    $0x1,%esi
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  mov    $0x1,%ecx
  jmp    L120
L82:
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  cmp    $0x2,%esi
  je     L3
  jg     L22
  test   %esi,%esi
  je     L39
  cmp    $0x1,%esi
  jne    L108
  cmp    $0x4,%eax
  je     L9
  cmp    $0x3,%eax
  je     L88
L4:
  ret
L108:
  mov    $0x0,%eax
  ret
L22:
  cmp    $0x3,%esi
  sete   %al
  movzbl %al,%eax
  ret
L3:
  cmp    $0x3,%eax
  je     L45
  cmp    $0x2,%eax
  jne    L4
L45:
  ret
L10:
  mov    $0x6,%eax
  ret
L39:
  mov    $0x6,%eax
  ret
L9:
  mov    $0x5,%eax
  ret
L88:
  mov    $0x4,%eax
  jmp    L45
```

assistant: ```c
int comparar(int *jugada, int length) {
  int anterior;
  int cambios = 0, posibilidad = 0;
  int max = 0, actual = 1;
  for (int i = 1; i < length; i++) {
    if (jugada[i - 1] != jugada[i]) {
      cambios++;
      if (actual > max)
        max = actual;
      actual = 1;
    } else {
      actual++;
    }
  }
  if (actual > max)
    max = actual;
  switch (cambios) {
  case 0:
    return 6;
    break;
  case 1:
    if (max == 4)
      return 5;
    else if (max == 3)
      return 4;
    break;
  case 2:
    if (max == 3)
      return 3;
    else if (max == 2)
      return 2;
    break;
  case 3:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<comparar>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  lea    -0x2(%rsi),%eax
  mov    $0x1,%edx
  xor    %ecx,%ecx
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %eax,%eax
  jmp    L88
  nopl   0x0(%rax)
L47:
  add    $0x1,%ecx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x4,%rdi
  mov    $0x1,%edx
  cmp    %rsi,%rdi
  je     L82
L88:
  mov    0x4(%rdi),%r8d
  cmp    %r8d,(%rdi)
  jne    L47
  add    $0x4,%rdi
  add    $0x1,%edx
  cmp    %rsi,%rdi
  jne    L88
L82:
  cmp    %edx,%eax
  cmovl  %edx,%eax
  cmp    $0x2,%ecx
  je     L14
  jg     L42
  test   %ecx,%ecx
  je     L15
  cmp    $0x1,%ecx
  jne    L120
  cmp    $0x4,%eax
  je     L87
  cmp    $0x3,%eax
  je     L60
L18:
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  cmp    $0x3,%ecx
  sete   %al
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x6,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    $0x3,%eax
  je     L128
  cmp    $0x2,%eax
  jne    L18
L128:
  ret
L87:
  mov    $0x5,%eax
  ret
L60:
  mov    $0x4,%eax
  ret
L120:
  xor    %eax,%eax
  ret
```

assistant: ```c
int comparar(int *jugada, int length) {
  int anterior;
  int cambios = 0, posibilidad = 0;
  int max = 0, actual = 1;
  for (int i = 1; i < length; i++) {
    if (jugada[i - 1] != jugada[i]) {
      cambios++;
      if (actual > max)
        max = actual;
      actual = 1;
    } else {
      actual++;
    }
  }
  if (actual > max)
    max = actual;
  switch (cambios) {
  case 0:
    return 6;
    break;
  case 1:
    if (max == 4)
      return 5;
    else if (max == 3)
      return 4;
    break;
  case 2:
    if (max == 3)
      return 3;
    else if (max == 2)
      return 2;
    break;
  case 3:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comparar>:
  endbr64
  cmp    $0x1,%esi
  jle    L32
  lea    -0x2(%rsi),%eax
  mov    (%rdi),%ecx
  lea    0x4(%rdi),%rdx
  mov    $0x1,%esi
  lea    0x8(%rdi,%rax,4),%r9
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L128
  nopw   0x0(%rax,%rax,1)
L89:
  add    $0x1,%r8d
  cmp    %esi,%eax
  cmovl  %esi,%eax
  add    $0x4,%rdx
  mov    $0x1,%esi
  cmp    %r9,%rdx
  je     L25
L128:
  mov    %ecx,%edi
  mov    (%rdx),%ecx
  cmp    %ecx,%edi
  jne    L89
  add    $0x4,%rdx
  add    $0x1,%esi
  cmp    %r9,%rdx
  jne    L128
L25:
  cmp    %esi,%eax
  cmovl  %esi,%eax
  cmp    $0x2,%r8d
  je     L127
  jg     L107
  test   %r8d,%r8d
  je     L32
  cmp    $0x1,%r8d
  jne    L67
  cmp    $0x4,%eax
  je     L30
  cmp    $0x3,%eax
  je     L59
L125:
  ret
  xchg   %ax,%ax
L107:
  xor    %eax,%eax
  cmp    $0x3,%r8d
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0x6,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L127:
  cmp    $0x3,%eax
  je     L1
  cmp    $0x2,%eax
  jne    L125
L1:
  ret
L30:
  mov    $0x5,%eax
  ret
L59:
  mov    $0x4,%eax
  ret
L67:
  xor    %eax,%eax
  ret
```

assistant: ```c
int comparar(int *jugada, int length) {
  int anterior;
  int cambios = 0, posibilidad = 0;
  int max = 0, actual = 1;
  for (int i = 1; i < length; i++) {
    if (jugada[i - 1] != jugada[i]) {
      cambios++;
      if (actual > max)
        max = actual;
      actual = 1;
    } else {
      actual++;
    }
  }
  if (actual > max)
    max = actual;
  switch (cambios) {
  case 0:
    return 6;
    break;
  case 1:
    if (max == 4)
      return 5;
    else if (max == 3)
      return 4;
    break;
  case 2:
    if (max == 3)
      return 3;
    else if (max == 2)
      return 2;
    break;
  case 3:
    return 1;
    break;
  default:
    return 0;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_create_destroy@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x0,%eax
  call   <test_insert_delete@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x0,%eax
  call   <test_insert_delete_2@plt>
  test   %rax,%rax
  je     L29
L32:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <mmp_trace_print@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L22
L29:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  if (test_create_destroy() != 0 || test_insert_delete() != 0 || test_insert_delete_2() != 0) {
    mmp_trace_print(stdout);
    return EXIT_FAILURE;
  }
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_create_destroy@plt>
  test   %rax,%rax
  jne    L6
  call   <test_insert_delete@plt>
  test   %rax,%rax
  je     L2
L6:
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <mmp_trace_print@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
L19:
  add    $0x8,%rsp
  ret
L2:
  call   <test_insert_delete_2@plt>
  test   %rax,%rax
  jne    L6
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L19
```

assistant: ```c
int main(void) {
  if (test_create_destroy() != 0 || test_insert_delete() != 0 || test_insert_delete_2() != 0) {
    mmp_trace_print(stdout);
    return EXIT_FAILURE;
  }
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_create_destroy@plt>
  test   %rax,%rax
  jne    L1
  xor    %eax,%eax
  call   <test_insert_delete@plt>
  test   %rax,%rax
  je     L12
L1:
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <mmp_trace_print@plt>
  mov    D23(%rip),%rax
  mov    (%rax),%eax
L6:
  add    $0x8,%rsp
  ret
L12:
  call   <test_insert_delete_2@plt>
  test   %rax,%rax
  jne    L1
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L6
```

assistant: ```c
int main(void) {
  if (test_create_destroy() != 0 || test_insert_delete() != 0 || test_insert_delete_2() != 0) {
    mmp_trace_print(stdout);
    return EXIT_FAILURE;
  }
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_create_destroy@plt>
  test   %rax,%rax
  jne    L25
  xor    %eax,%eax
  call   <test_insert_delete@plt>
  test   %rax,%rax
  je     L19
L25:
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <mmp_trace_print@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
L36:
  add    $0x8,%rsp
  ret
L19:
  call   <test_insert_delete_2@plt>
  test   %rax,%rax
  jne    L25
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  jmp    L36
```

assistant: ```c
int main(void) {
  if (test_create_destroy() != 0 || test_insert_delete() != 0 || test_insert_delete_2() != 0) {
    mmp_trace_print(stdout);
    return EXIT_FAILURE;
  }
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<r_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L17
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L8
L17:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
id_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L13:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    D16(%rip),%rcx
  mov    D12(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L13
L3:
  pop    %rbx
  ret
```

assistant: ```c
id_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L12:
  mov    D1(%rip),%rdx
  mov    D18(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L13
L14:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L12
L13:
  pop    %rbx
  ret
```

assistant: ```c
id_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<r_wait>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L23:
  mov    D3(%rip),%rdx
  mov    D12(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L6
L1:
  mov    %rbx,%rdi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  je     L23
L6:
  pop    %rbx
  ret
```

assistant: ```c
id_t r_wait(int *stat_loc) {
  pid_t retval;
  while (((retval = wait(stat_loc)) == -1) && (errno == EINTR))
    ;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int pipe(int pipefd[2]) {
  assert(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pipe>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pipe(int pipefd[2]) {
  assert(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pipe>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pipe(int pipefd[2]) {
  assert(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pipe>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pipe(int pipefd[2]) {
  assert(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sg_get_sense_info_fld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L85
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
L85:
  cmpl   $0x6,-0x1c(%rbp)
  jg     L75
  mov    $0x0,%eax
  jmp    L17
L75:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  cmp    $0x71,%eax
  jg     L19
  cmp    $0x70,%eax
  jge    L36
  jmp    L143
L19:
  sub    $0x72,%eax
  cmp    $0x1,%eax
  ja     L143
  jmp    L104
L36:
  cmpq   $0x0,-0x28(%rbp)
  je     L147
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L147:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sar    $0x7,%al
  movsbl %al,%eax
  and    $0x1,%eax
  jmp    L17
L104:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sg_scsi_sense_desc_find@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L68
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L68
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L84
L42:
  cmpl   $0x0,-0x10(%rbp)
  jle    L142
  shll   $0x8,-0xc(%rbp)
L142:
  mov    -0x10(%rbp),%eax
  add    $0x4,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L84:
  cmpl   $0x7,-0x10(%rbp)
  jle    L42
  cmpq   $0x0,-0x28(%rbp)
  je     L60
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L60:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  jmp    L17
L68:
  mov    $0x0,%eax
  jmp    L17
L143:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int sg_get_sense_info_fld(const unsigned char *sensep, int sb_len, uint64_t *info_outp) {
  int j;
  const unsigned char *ucp;
  uint64_t ull;
  if (info_outp)
    *info_outp = 0;
  if (sb_len < 7)
    return 0;
  switch (sensep[0] & 0x7f) {
  case 0x70:
  case 0x71:
    if (info_outp)
      *info_outp = ((unsigned int)sensep[3] << 24) + (sensep[4] << 16) + (sensep[5] << 8) + sensep[6];
    return (sensep[0] & 0x80) ? 1 : 0;
  case 0x72:
  case 0x73:
    ucp = sg_scsi_sense_desc_find(sensep, sb_len, 0);
    if (ucp && (0xa == ucp[1])) {
      ull = 0;
      for (j = 0; j < 8; ++j) {
        if (j > 0)
          ull <<= 8;
        ull |= ucp[4 + j];
      }
      if (info_outp)
        *info_outp = ull;
      return !!(ucp[2] & 0x80);
    } else
      return 0;
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sg_get_sense_info_fld>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L107
  movl   $0x0,(%rdx)
L107:
  mov    $0x0,%edx
  cmp    $0x6,%esi
  jle    L113
  movzbl (%rdi),%eax
  and    $0x7f,%eax
  cmp    $0x71,%al
  jbe    L32
  sub    $0x72,%eax
  mov    $0x0,%edx
  cmp    $0x1,%al
  ja     L113
  mov    $0x0,%edx
  call   <sg_scsi_sense_desc_find@plt>
  test   %rax,%rax
  je     L90
  mov    $0x0,%edx
  cmpb   $0xa,0x1(%rax)
  jne    L113
  mov    $0x1,%edx
  mov    $0x0,%ecx
  jmp    L82
L32:
  cmp    $0x6f,%al
  ja     L126
L113:
  mov    %edx,%eax
  pop    %rbx
  ret
L126:
  test   %rbx,%rbx
  je     L88
  movzbl 0x3(%rdi),%eax
  shl    $0x18,%eax
  movzbl 0x6(%rdi),%edx
  add    %edx,%eax
  movzbl 0x4(%rdi),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movzbl 0x5(%rdi),%edx
  shl    $0x8,%edx
  add    %edx,%eax
  mov    %eax,(%rbx)
L88:
  movzbl (%rdi),%edx
  shr    $0x7,%dl
  movsbl %dl,%edx
  jmp    L113
L86:
  shl    $0x8,%ecx
L50:
  add    $0x1,%rdx
L82:
  movzbl 0x3(%rax,%rdx,1),%esi
  or     %esi,%ecx
  cmp    $0x8,%rdx
  je     L61
  test   %edx,%edx
  jg     L86
  jmp    L50
L61:
  test   %rbx,%rbx
  je     L95
  mov    %ecx,(%rbx)
L95:
  movsbl 0x2(%rax),%edx
  shr    $0x1f,%edx
  jmp    L113
L90:
  mov    $0x0,%edx
  jmp    L113
```

assistant: ```c
int sg_get_sense_info_fld(const unsigned char *sensep, int sb_len, uint64_t *info_outp) {
  int j;
  const unsigned char *ucp;
  uint64_t ull;
  if (info_outp)
    *info_outp = 0;
  if (sb_len < 7)
    return 0;
  switch (sensep[0] & 0x7f) {
  case 0x70:
  case 0x71:
    if (info_outp)
      *info_outp = ((unsigned int)sensep[3] << 24) + (sensep[4] << 16) + (sensep[5] << 8) + sensep[6];
    return (sensep[0] & 0x80) ? 1 : 0;
  case 0x72:
  case 0x73:
    ucp = sg_scsi_sense_desc_find(sensep, sb_len, 0);
    if (ucp && (0xa == ucp[1])) {
      ull = 0;
      for (j = 0; j < 8; ++j) {
        if (j > 0)
          ull <<= 8;
        ull |= ucp[4 + j];
      }
      if (info_outp)
        *info_outp = ull;
      return !!(ucp[2] & 0x80);
    } else
      return 0;
  default:
    return 0;
  }
}
```