ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6a,%eax
  mov    $0xffffffa2,%edx
  imul   %edx,%eax
  sub    $0x28,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[0UL];
        state[0UL] += state[0UL];
      }
      if (state[0UL] == local1) {
        state[local1] += state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 649632930UL - (unsigned char)40;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffa2,%edx
  sub    $0x6a,%eax
  imul   %edx,%eax
  sub    $0x28,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[0UL];
        state[0UL] += state[0UL];
      }
      if (state[0UL] == local1) {
        state[local1] += state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 649632930UL - (unsigned char)40;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffa2,%edx
  sub    $0x6a,%eax
  imul   %edx,%eax
  sub    $0x28,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[0UL];
        state[0UL] += state[0UL];
      }
      if (state[0UL] == local1) {
        state[local1] += state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 649632930UL - (unsigned char)40;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x3(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string

tool: D13: %d %d


assistant: ```c
int main() {
  int a, b, *p1, *p2;
  a = 4;
  b = 3;
  p1 = &a;
  p2 = p1;
  *p2 = *p1 + 3;
  b = b * (*p1);
  (*p2)++;
  p1 = &b;
  printf("%d %d\n", *p1, *p2);
  printf("%d %d\n", a, b);
  getch();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x8,%edx
  mov    $0x15,%esi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x15,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: %d %d


assistant: ```c
int main() {
  int a, b, *p1, *p2;
  a = 4;
  b = 3;
  p1 = &a;
  p2 = p1;
  *p2 = *p1 + 3;
  b = b * (*p1);
  (*p2)++;
  p1 = &b;
  printf("%d %d\n", *p1, *p2);
  printf("%d %d\n", a, b);
  getch();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x8,%edx
  mov    $0x15,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x15,%edx
  mov    $0x8,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: %d %d


assistant: ```c
int main() {
  int a, b, *p1, *p2;
  a = 4;
  b = 3;
  p1 = &a;
  p2 = p1;
  *p2 = *p1 + 3;
  b = b * (*p1);
  (*p2)++;
  p1 = &b;
  printf("%d %d\n", *p1, *p2);
  printf("%d %d\n", a, b);
  getch();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    $0x8,%edx
  mov    $0x15,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x15,%edx
  mov    $0x8,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %d %d


assistant: ```c
int main() {
  int a, b, *p1, *p2;
  a = 4;
  b = 3;
  p1 = &a;
  p2 = p1;
  *p2 = *p1 + 3;
  b = b * (*p1);
  (*p2)++;
  p1 = &b;
  printf("%d %d\n", *p1, *p2);
  printf("%d %d\n", a, b);
  getch();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L5
L1:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0xc8,-0x8(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: The 200th triangular number is %i


assistant: ```c
int main(void) {
  int n;
  int triangularNumber = 0;
  for (n = 1; n <= 200; n++) {
    triangularNumber += n;
  }
  printf("The 200th triangular number is %i\n", triangularNumber);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc8,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  mov    $0x4e84,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5: The 200th triangular number is %i


assistant: ```c
int main(void) {
  int n;
  int triangularNumber = 0;
  for (n = 1; n <= 200; n++) {
    triangularNumber += n;
  }
  printf("The 200th triangular number is %i\n", triangularNumber);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4e84,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: The 200th triangular number is %i


assistant: ```c
int main(void) {
  int n;
  int triangularNumber = 0;
  for (n = 1; n <= 200; n++) {
    triangularNumber += n;
  }
  printf("The 200th triangular number is %i\n", triangularNumber);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4e84,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: The 200th triangular number is %i


assistant: ```c
int main(void) {
  int n;
  int triangularNumber = 0;
  for (n = 1; n <= 200; n++) {
    triangularNumber += n;
  }
  printf("The 200th triangular number is %i\n", triangularNumber);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ultoe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ecleaz@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x30,%rax
  mov    %ax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x20,%rax
  mov    %ax,-0x1a(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x10,%rax
  mov    %ax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %ax,-0x16(%rbp)
  movw   $0x402e,-0x1e(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <enormlz@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x50,-0x2c(%rbp)
  jle    L10
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ecleaz@plt>
  jmp    L21
L10:
  movzwl -0x1e(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  sub    %edx,%eax
  mov    %ax,-0x1e(%rbp)
L21:
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <emovo@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void ultoe(lp, y) unsigned long *lp;
unsigned short *y;
{
  unsigned short yi[(6 + 3)];
  unsigned long ll;
  int k;
  ecleaz(yi);
  ll = *lp;
  if (sizeof(long) == 8) {
    yi[2] = (unsigned short)(ll >> ((8 * sizeof(long)) - 16));
    yi[2 + 1] = (unsigned short)(ll >> ((8 * sizeof(long)) - 32));
    yi[2 + 2] = (unsigned short)(ll >> 16);
    yi[2 + 3] = (unsigned short)ll;
    yi[1] = (0x3fff) + 47;
  } else {
    yi[2] = (unsigned short)(ll >> 16);
    yi[2 + 1] = (unsigned short)ll;
    yi[1] = (0x3fff) + 15;
  }
  if ((k = enormlz(yi)) > (((6 + 3) - 4) * 16))
    ecleaz(yi);
  else
    yi[1] -= (unsigned short)k;
  emovo(yi, y);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ultoe>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <ecleaz@plt>
  mov    0x0(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x30,%rdx
  mov    %dx,0x4(%rsp)
  mov    %rax,%rdx
  shr    $0x20,%rdx
  mov    %dx,0x6(%rsp)
  mov    %rax,%rdx
  shr    $0x10,%rdx
  mov    %dx,0x8(%rsp)
  mov    %ax,0xa(%rsp)
  movw   $0x402e,0x2(%rsp)
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <enormlz@plt>
  cmp    $0x50,%eax
  jg     L22
  sub    %ax,0x2(%rsp)
L0:
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  mov    $0x0,%eax
  call   <emovo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <ecleaz@plt>
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ultoe(lp, y) unsigned long *lp;
unsigned short *y;
{
  unsigned short yi[(6 + 3)];
  unsigned long ll;
  int k;
  ecleaz(yi);
  ll = *lp;
  if (sizeof(long) == 8) {
    yi[2] = (unsigned short)(ll >> ((8 * sizeof(long)) - 16));
    yi[2 + 1] = (unsigned short)(ll >> ((8 * sizeof(long)) - 32));
    yi[2 + 2] = (unsigned short)(ll >> 16);
    yi[2 + 3] = (unsigned short)ll;
    yi[1] = (0x3fff) + 47;
  } else {
    yi[2] = (unsigned short)(ll >> 16);
    yi[2 + 1] = (unsigned short)ll;
    yi[1] = (0x3fff) + 15;
  }
  if ((k = enormlz(yi)) > (((6 + 3) - 4) * 16))
    ecleaz(yi);
  else
    yi[1] -= (unsigned short)k;
  emovo(yi, y);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ultoe>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <ecleaz@plt>
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  mov    %rax,%rdx
  mov    %ax,0xa(%rsp)
  shr    $0x30,%rdx
  mov    %dx,0x4(%rsp)
  mov    %rax,%rdx
  shr    $0x20,%rdx
  mov    %dx,0x6(%rsp)
  mov    %rax,%rdx
  mov    $0x402e,%eax
  shr    $0x10,%rdx
  mov    %ax,0x2(%rsp)
  xor    %eax,%eax
  mov    %dx,0x8(%rsp)
  call   <enormlz@plt>
  cmp    $0x50,%eax
  jg     L8
  sub    %ax,0x2(%rsp)
L0:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <emovo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <ecleaz@plt>
  jmp    L0
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ultoe(lp, y) unsigned long *lp;
unsigned short *y;
{
  unsigned short yi[(6 + 3)];
  unsigned long ll;
  int k;
  ecleaz(yi);
  ll = *lp;
  if (sizeof(long) == 8) {
    yi[2] = (unsigned short)(ll >> ((8 * sizeof(long)) - 16));
    yi[2 + 1] = (unsigned short)(ll >> ((8 * sizeof(long)) - 32));
    yi[2 + 2] = (unsigned short)(ll >> 16);
    yi[2 + 3] = (unsigned short)ll;
    yi[1] = (0x3fff) + 47;
  } else {
    yi[2] = (unsigned short)(ll >> 16);
    yi[2 + 1] = (unsigned short)ll;
    yi[1] = (0x3fff) + 15;
  }
  if ((k = enormlz(yi)) > (((6 + 3) - 4) * 16))
    ecleaz(yi);
  else
    yi[1] -= (unsigned short)k;
  emovo(yi, y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ultoe>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <ecleaz@plt>
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  mov    %rax,%rdx
  mov    %ax,0xa(%rsp)
  shr    $0x30,%rdx
  mov    %dx,0x4(%rsp)
  mov    %rax,%rdx
  shr    $0x20,%rdx
  mov    %dx,0x6(%rsp)
  mov    %rax,%rdx
  mov    $0x402e,%eax
  shr    $0x10,%rdx
  mov    %ax,0x2(%rsp)
  xor    %eax,%eax
  mov    %dx,0x8(%rsp)
  call   <enormlz@plt>
  cmp    $0x50,%eax
  jg     L15
  sub    %ax,0x2(%rsp)
L12:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <emovo@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L15:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <ecleaz@plt>
  jmp    L12
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ultoe(lp, y) unsigned long *lp;
unsigned short *y;
{
  unsigned short yi[(6 + 3)];
  unsigned long ll;
  int k;
  ecleaz(yi);
  ll = *lp;
  if (sizeof(long) == 8) {
    yi[2] = (unsigned short)(ll >> ((8 * sizeof(long)) - 16));
    yi[2 + 1] = (unsigned short)(ll >> ((8 * sizeof(long)) - 32));
    yi[2 + 2] = (unsigned short)(ll >> 16);
    yi[2 + 3] = (unsigned short)ll;
    yi[1] = (0x3fff) + 47;
  } else {
    yi[2] = (unsigned short)(ll >> 16);
    yi[2 + 1] = (unsigned short)ll;
    yi[1] = (0x3fff) + 15;
  }
  if ((k = enormlz(yi)) > (((6 + 3) - 4) * 16))
    ecleaz(yi);
  else
    yi[1] -= (unsigned short)k;
  emovo(yi, y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D17
type_guessed: byte[8]
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D14: %d

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D19: %d minutos


assistant: ```c
int main() {
  int d;
  scanf("%d", &d);
  int t = d / ((90 / 60.0) - (60 / 60.0));
  printf("%d minutos\n", t);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x4(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D17
type: string

tool: D19: %d

tool: D17: %d minutos


assistant: ```c
int main() {
  int d;
  scanf("%d", &d);
  int t = d / ((90 / 60.0) - (60 / 60.0));
  printf("%d minutos\n", t);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  lea    D11(%rip),%rdi
  cvtsi2sdl 0x4(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D19: %d

tool: D11: %d minutos


assistant: ```c
int main() {
  int d;
  scanf("%d", &d);
  int t = d / ((90 / 60.0) - (60 / 60.0));
  printf("%d minutos\n", t);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  cvtsi2sdl 0x4(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string

tool: D2: %d

tool: D12: %d minutos


assistant: ```c
int main() {
  int d;
  scanf("%d", &d);
  int t = d / ((90 / 60.0) - (60 / 60.0));
  printf("%d minutos\n", t);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x2(%rax),%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: supercalifragilisticoespialidoso

assistant: ```c
char a() {
  char *x = "supercalifragilisticoespialidoso";
  return x[2];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<a>:
  endbr64
  mov    $0x70,%eax
  ret
```

assistant: ```c
char a() {
  char *x = "supercalifragilisticoespialidoso";
  return x[2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<a>:
  endbr64
  mov    $0x70,%eax
  ret
```

assistant: ```c
char a() {
  char *x = "supercalifragilisticoespialidoso";
  return x[2];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<a>:
  endbr64
  mov    $0x70,%eax
  ret
```

assistant: ```c
char a() {
  char *x = "supercalifragilisticoespialidoso";
  return x[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<operation_finder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L57
  mov    $0x0,%eax
  jmp    L27
L57:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L110
  mov    $0x1,%eax
  jmp    L27
L110:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L17
  mov    $0x2,%eax
  jmp    L27
L17:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L72
  mov    $0x3,%eax
  jmp    L27
L72:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L115
  mov    $0x4,%eax
  jmp    L27
L115:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L39
  mov    $0x5,%eax
  jmp    L27
L39:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D69
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D24: =

tool: D32: <=

tool: D69: >=

tool: D17: >

tool: D49: <

tool: D25: !=

tool: D7: You did not enter a valid operation


assistant: ```c
int operation_finder(char *operation) {
  if (strncmp("=", operation, 1) == 0) {
    return 0;
  } else if (strncmp("<=", operation, 2) == 0) {
    return 1;
  } else if (strncmp(">=", operation, 2) == 0) {
    return 2;
  } else if (strncmp(">", operation, 1) == 0) {
    return 3;
  } else if (strncmp("<", operation, 1) == 0) {
    return 4;
  } else if (strncmp("!=", operation, 2) == 0) {
    return 5;
  }
  printf("You did not enter a valid operation\n");
  exit(1);
}
```