ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<aaa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffff9d,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%ecx
  lea    D5(%rip),%rdx
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: %d

assistant: ```c
aaa() {
  int i = -99;
  char buf[12];
  snprintf(buf, 12, "%d", i);
  puts(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<aaa>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    $0xffffff9d,%ecx
  lea    D2(%rip),%rdx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
aaa() {
  int i = -99;
  char buf[12];
  snprintf(buf, 12, "%d", i);
  puts(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aaa>:
  endbr64
  push   %rbp
  mov    $0xffffff9d,%ecx
  mov    $0xc,%esi
  lea    D8(%rip),%rdx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
aaa() {
  int i = -99;
  char buf[12];
  snprintf(buf, 12, "%d", i);
  puts(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aaa>:
  endbr64
  push   %rbp
  mov    $0xffffff9d,%ecx
  mov    $0xc,%esi
  lea    D0(%rip),%rdx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %d

assistant: ```c
aaa() {
  int i = -99;
  char buf[12];
  snprintf(buf, 12, "%d", i);
  puts(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string

tool: D23: Usage:

tool: D22: %s <dldi> <app>


tool: D28:    <dldi>        the dldi patch file to apply

tool: D33:    <app>         the application binary to apply the patch to

assistant: ```c
void printUsage(char *programName) {
  printf("Usage:\n");
  printf("%s <dldi> <app>\n", programName);
  printf("   <dldi>        the dldi patch file to apply\n");
  printf("   <app>         the application binary to apply the patch to\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printUsage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string

tool: D17: Usage:

tool: D31: %s <dldi> <app>


tool: D34:    <dldi>        the dldi patch file to apply

tool: D36:    <app>         the application binary to apply the patch to

assistant: ```c
void printUsage(char *programName) {
  printf("Usage:\n");
  printf("%s <dldi> <app>\n", programName);
  printf("   <dldi>        the dldi patch file to apply\n");
  printf("   <app>         the application binary to apply the patch to\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printUsage>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D31: Usage:

tool: D15: %s <dldi> <app>


tool: D5:    <dldi>        the dldi patch file to apply

tool: D28:    <app>         the application binary to apply the patch to

assistant: ```c
void printUsage(char *programName) {
  printf("Usage:\n");
  printf("%s <dldi> <app>\n", programName);
  printf("   <dldi>        the dldi patch file to apply\n");
  printf("   <app>         the application binary to apply the patch to\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printUsage>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D36
type: string

tool: D27: Usage:

tool: D24: %s <dldi> <app>


tool: D7:    <dldi>        the dldi patch file to apply

tool: D36:    <app>         the application binary to apply the patch to

assistant: ```c
void printUsage(char *programName) {
  printf("Usage:\n");
  printf("%s <dldi> <app>\n", programName);
  printf("   <dldi>        the dldi patch file to apply\n");
  printf("   <app>         the application binary to apply the patch to\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sRealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <die@plt>
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <die@plt>
L14:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D2
type: string

tool: D8: unable to reallocate 0 bytes

tool: D2: out of memory: failed to reallocate %zu bytes

assistant: ```c
void *sRealloc(void *ptr, size_t size) {
  if (size == 0) {
    die("unable to reallocate 0 bytes");
  }
  void *data = realloc(ptr, size);
  if (data == NULL) {
    die("out of memory: failed to reallocate %zu bytes", size);
  }
  return data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sRealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L14
L18:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
L8:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <die@plt>
  jmp    L18
L16:
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <die@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D6
type: string

tool: D9: unable to reallocate 0 bytes

tool: D6: out of memory: failed to reallocate %zu bytes

assistant: ```c
void *sRealloc(void *ptr, size_t size) {
  if (size == 0) {
    die("unable to reallocate 0 bytes");
  }
  void *data = realloc(ptr, size);
  if (data == NULL) {
    die("out of memory: failed to reallocate %zu bytes", size);
  }
  return data;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sRealloc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L25
L3:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L3
L7:
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D7: unable to reallocate 0 bytes

tool: D13: out of memory: failed to reallocate %zu bytes

assistant: ```c
void *sRealloc(void *ptr, size_t size) {
  if (size == 0) {
    die("unable to reallocate 0 bytes");
  }
  void *data = realloc(ptr, size);
  if (data == NULL) {
    die("out of memory: failed to reallocate %zu bytes", size);
  }
  return data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sRealloc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L34
L30:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L22
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L30
L22:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <die@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D14: unable to reallocate 0 bytes

tool: D1: out of memory: failed to reallocate %zu bytes

assistant: ```c
void *sRealloc(void *ptr, size_t size) {
  if (size == 0) {
    die("unable to reallocate 0 bytes");
  }
  void *data = realloc(ptr, size);
  if (data == NULL) {
    die("out of memory: failed to reallocate %zu bytes", size);
  }
  return data;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xf4240,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <calculate_primes@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int n = 1000000;
  int *p = calculate_primes(n);
  if (p != NULL)
    free(p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <calculate_primes@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  call   <free@plt>
L9:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 1000000;
  int *p = calculate_primes(n);
  if (p != NULL)
    free(p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <calculate_primes@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  call   <free@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 1000000;
  int *p = calculate_primes(n);
  if (p != NULL)
    free(p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <calculate_primes@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <free@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = 1000000;
  int *p = calculate_primes(n);
  if (p != NULL)
    free(p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L11
L23:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jae    L34
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1e(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  movzwl -0x1e(%rbp),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L46
L34:
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  imul   %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
L46:
  addq   $0x1,-0x18(%rbp)
L11:
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  mov    -0x10(%rbp),%rax
  rol    $0xd,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
        state[local1] = state[0UL] * state[0UL];
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 13UL) | (state[0UL] >> 51UL);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rcx
  lea    0x3686696a(%rcx),%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,%rdx
  cmp    $0xffffffff97d696a1,%rcx
  je     L5
  mov    %rax,%rcx
  shr    $0x10,%rcx
  mov    %cx,%dx
  movzwl %ax,%eax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  shr    $0x20,%rdx
  shl    $0x20,%rax
  or     %rax,%rdx
L5:
  rol    $0xd,%rdx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
        state[local1] = state[0UL] * state[0UL];
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 13UL) | (state[0UL] >> 51UL);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    0x3686696a(%rax),%rdx
  xor    $0xffffffffce5d000b,%rdx
  cmp    $0xffffffff97d696a1,%rax
  je     L2
  mov    %rdx,%rax
  movzwl %dx,%ecx
  shr    $0x20,%rdx
  shr    $0x10,%rax
  shl    $0x10,%rcx
  movzwl %ax,%eax
  or     %rcx,%rax
  shl    $0x20,%rax
  or     %rax,%rdx
L2:
  rol    $0xd,%rdx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
        state[local1] = state[0UL] * state[0UL];
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 13UL) | (state[0UL] >> 51UL);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  lea    0x3686696a(%rdx),%rax
  xor    $0xffffffffce5d000b,%rax
  cmp    $0xffffffff97d696a1,%rdx
  je     L5
  mov    %rax,%rdx
  rol    $0x10,%eax
  shr    $0x20,%rdx
  movd   %eax,%xmm1
  movd   %edx,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,%rax
L5:
  rol    $0xd,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31UL) << 4UL;
        state[local1] = state[0UL] * state[0UL];
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 13UL) | (state[0UL] >> 51UL);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<identifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *identifier(char *str) {
  str = NULL;
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<identifier>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *identifier(char *str) {
  str = NULL;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<identifier>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *identifier(char *str) {
  str = NULL;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<identifier>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *identifier(char *str) {
  str = NULL;
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x4,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  sub    $0x1,%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  div    %rcx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L49:
  cmp    %rdx,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
L48:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L34
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L34:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  sub    $0x1,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L52:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L52
L39:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L47
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L47:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <init_int_buff@plt>
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cpy_int_buff@plt>
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x54(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <gen_sort@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void test_sort() {
  const int len = 4;
  int arr[len], origin[len], *res;
  init_int_buff(arr, len);
  cpy_int_buff(origin, arr, len);
  res = sort(arr, len);
  gen_sort(origin, len, res);
}
```