ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_168_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_168_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_168_1_0>:
  endbr64
  or     %esi,%edx
  and    (%rdi),%dl
  mov    %esi,%eax
  not    %eax
  and    %eax,%edx
  mov    %esi,%eax
  and    (%rdi),%al
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_168_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_168_1_0>:
  endbr64
  mov    %esi,%eax
  or     %esi,%edx
  and    (%rdi),%dl
  not    %eax
  and    %eax,%edx
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_168_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_168_1_0>:
  endbr64
  mov    %esi,%eax
  or     %esi,%edx
  and    (%rdi),%dl
  not    %eax
  and    %eax,%edx
  movzbl (%rdi),%eax
  and    %esi,%eax
  or     %eax,%edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_168_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk1 = *D & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<weq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x20(%rbp),%rbx
  mov    -0x28(%rbp),%r12
  mov    $0x0,%r13d
  jmp    L20
L23:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L35
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L35
  mov    $0x1,%eax
  jmp    L58
L35:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L32
  mov    $0x0,%eax
  jmp    L58
L32:
  add    $0x1,%r13d
L20:
  cmp    $0x4,%r13d
  jle    L23
  mov    $0x1,%eax
L58:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int weq(w1, w2)
char *w1, *w2;
{
  register char *s, *t;
  register int i;
  s = w1;
  t = w2;
  for (i = 0; i < 5; i++) {
    if (*t == 0 && *s == 0)
      return (1);
    if (*s++ != *t++)
      return (0);
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<weq>:
  endbr64
  lea    0x5(%rdi),%rdx
  jmp    L36
L15:
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    -0x1(%rdi),%al
  jne    L17
  cmp    %rdx,%rdi
  je     L9
L36:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L15
  cmpb   $0x0,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
L9:
  mov    $0x1,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int weq(w1, w2)
char *w1, *w2;
{
  register char *s, *t;
  register int i;
  s = w1;
  t = w2;
  for (i = 0; i < 5; i++) {
    if (*t == 0 && *s == 0)
      return (1);
    if (*s++ != *t++)
      return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<weq>:
  endbr64
  xor    %eax,%eax
L17:
  movzbl (%rsi,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  test   %dl,%dl
  jne    L6
  xor    %eax,%eax
  test   %cl,%cl
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  cmp    %cl,%dl
  jne    L15
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L17
  mov    $0x1,%eax
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int weq(w1, w2)
char *w1, *w2;
{
  register char *s, *t;
  register int i;
  s = w1;
  t = w2;
  for (i = 0; i < 5; i++) {
    if (*t == 0 && *s == 0)
      return (1);
    if (*s++ != *t++)
      return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<weq>:
  endbr64
  movzbl (%rsi),%edx
  movzbl (%rdi),%eax
  test   %dl,%dl
  je     L43
  cmp    %dl,%al
  jne    L29
  movzbl 0x1(%rsi),%edx
  movzbl 0x1(%rdi),%eax
  test   %dl,%dl
  je     L43
  cmp    %al,%dl
  jne    L29
  movzbl 0x2(%rsi),%edx
  movzbl 0x2(%rdi),%eax
  test   %dl,%dl
  je     L43
  cmp    %al,%dl
  jne    L29
  movzbl 0x3(%rsi),%edx
  movzbl 0x3(%rdi),%eax
  test   %dl,%dl
  je     L43
  cmp    %al,%dl
  jne    L29
  movzbl 0x4(%rsi),%edx
  movzbl 0x4(%rdi),%eax
  test   %dl,%dl
  jne    L0
L43:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %al,%dl
  sete   %al
  movzbl %al,%eax
  ret
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
int weq(w1, w2)
char *w1, *w2;
{
  register char *s, *t;
  register int i;
  s = w1;
  t = w2;
  for (i = 0; i < 5; i++) {
    if (*t == 0 && *s == 0)
      return (1);
    if (*s++ != *t++)
      return (0);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fltarr3free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L7:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void fltarr3free(float ***aaa, const int n1, const int n2, const int n3) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++)
      free(aaa[i][j]);
    free(aaa[i]);
  }
  free(aaa);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fltarr3free>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  test   %esi,%esi
  jle    L37
  mov    %edx,%r13d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r14
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r12
  jmp    L7
L43:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L43
L9:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L37
L7:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L43
  jmp    L9
L37:
  mov    %r15,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fltarr3free(float ***aaa, const int n1, const int n2, const int n3) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++)
      free(aaa[i][j]);
    free(aaa[i]);
  }
  free(aaa);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fltarr3free>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r15
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L38
  nop
L31:
  mov    (%r15),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L31
L38:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <free@plt>
  cmp    %r13,%r15
  jne    L27
L1:
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <free@plt>
```

assistant: ```c
void fltarr3free(float ***aaa, const int n1, const int n2, const int n3) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++)
      free(aaa[i][j]);
    free(aaa[i]);
  }
  free(aaa);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fltarr3free>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r15
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L14
  nop
L34:
  mov    (%r15),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L34
L14:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <free@plt>
  cmp    %r15,%r13
  jne    L13
L15:
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <free@plt>
```

assistant: ```c
void fltarr3free(float ***aaa, const int n1, const int n2, const int n3) {
  int i, j;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++)
      free(aaa[i][j]);
    free(aaa[i]);
  }
  free(aaa);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  a();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  a();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  a();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  a();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L41
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L28
L41:
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L3:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L45
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L3
L45:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L71:
  subl   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L30
  cmpl   $0x0,-0x8(%rbp)
  jg     L71
L30:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
L28:
  leave
  ret
```

assistant: ```c
char *strip(const char *s) {
  int i, j, len;
  len = strlen(s);
  if (len == 0)
    return strdup(s);
  i = 0;
  while ((isspace(s[i])) && (i < len)) {
    i++;
  }
  j = len - 1;
  while ((isspace(s[j])) && (j > 0)) {
    j--;
  }
  return strndup(s + i, j - i + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  call   <strlen@plt>
  test   %eax,%eax
  je     L53
  mov    %eax,%ebx
  mov    %r13,%rbp
  mov    $0x0,%r12d
L55:
  mov    %rbp,%r14
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  jge    L39
  test   %rax,%rax
  je     L39
  add    $0x1,%r12d
  jmp    L55
L53:
  mov    %r13,%rdi
  call   <strdup@plt>
  jmp    L25
L39:
  sub    $0x1,%ebx
  movslq %ebx,%rbx
L47:
  mov    %ebx,%ebp
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <isspace@plt>
  test   %ebx,%ebx
  setg   %dl
  test   %rax,%rax
  setne  %al
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L47
  sub    %r12d,%ebp
  lea    0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <strndup@plt>
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strip(const char *s) {
  int i, j, len;
  len = strlen(s);
  if (len == 0)
    return strdup(s);
  i = 0;
  while ((isspace(s[i])) && (i < len)) {
    i++;
  }
  j = len - 1;
  while ((isspace(s[j])) && (j > 0)) {
    j--;
  }
  return strndup(s + i, j - i + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L9
  mov    %eax,%ebx
  mov    %r12,%r14
  xor    %ebp,%ebp
  jmp    L33
  nopl   0x0(%rax)
L39:
  test   %rax,%rax
  je     L29
  add    $0x1,%ebp
L33:
  movsbl (%r14),%edi
  mov    %r14,%r13
  add    $0x1,%r14
  call   <isspace@plt>
  cmp    %ebx,%ebp
  jl     L39
L29:
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L24:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%r14d
  call   <isspace@plt>
  test   %rax,%rax
  setne  %dl
  test   %ebx,%ebx
  setg   %al
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L24
  sub    %ebp,%r14d
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  lea    0x1(%r14),%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <strndup@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *strip(const char *s) {
  int i, j, len;
  len = strlen(s);
  if (len == 0)
    return strdup(s);
  i = 0;
  while ((isspace(s[i])) && (i < len)) {
    i++;
  }
  j = len - 1;
  while ((isspace(s[j])) && (j > 0)) {
    j--;
  }
  return strndup(s + i, j - i + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L31
  mov    %eax,%ebx
  mov    %r12,%r14
  xor    %ebp,%ebp
  jmp    L44
  nopl   0x0(%rax)
L47:
  test   %rax,%rax
  je     L48
  add    $0x1,%ebp
L44:
  movsbl (%r14),%edi
  mov    %r14,%r13
  add    $0x1,%r14
  call   <isspace@plt>
  cmp    %ebx,%ebp
  jl     L47
L48:
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L46:
  movsbl (%r12,%rbx,1),%edi
  mov    %ebx,%r14d
  call   <isspace@plt>
  test   %rax,%rax
  setne  %dl
  test   %ebx,%ebx
  setg   %al
  sub    $0x1,%rbx
  test   %al,%dl
  jne    L46
  sub    %ebp,%r14d
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  lea    0x1(%r14),%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <strndup@plt>
  nopw   0x0(%rax,%rax,1)
L31:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strdup@plt>
```

assistant: ```c
char *strip(const char *s) {
  int i, j, len;
  len = strlen(s);
  if (len == 0)
    return strdup(s);
  i = 0;
  while ((isspace(s[i])) && (i < len)) {
    i++;
  }
  j = len - 1;
  while ((isspace(s[j])) && (j > 0)) {
    j--;
  }
  return strndup(s + i, j - i + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hash_find_slot@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hash_delete_at@plt>
  leave
  ret
```

assistant: ```c
void *hash_delete(struct hash_table *ht, const void *item) {
  void **slot = hash_find_slot(ht, item);
  return hash_delete_at(ht, slot);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_delete>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <hash_find_slot@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <hash_delete_at@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *hash_delete(struct hash_table *ht, const void *item) {
  void **slot = hash_find_slot(ht, item);
  return hash_delete_at(ht, slot);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash_delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hash_find_slot@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <hash_delete_at@plt>
```

assistant: ```c
void *hash_delete(struct hash_table *ht, const void *item) {
  void **slot = hash_find_slot(ht, item);
  return hash_delete_at(ht, slot);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_delete>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hash_find_slot@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <hash_delete_at@plt>
```

assistant: ```c
void *hash_delete(struct hash_table *ht, const void *item) {
  void **slot = hash_find_slot(ht, item);
  return hash_delete_at(ht, slot);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x0,%eax
  call   <readInfixExpression@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stringTrim@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <changeStrIfMinusIsFirst@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <infix2postfix@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <caculate@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: result->%d


assistant: ```c
int main(int argc, char **argv) {
  char *infixLine;
  char *trim;
  char *out;
  infixLine = readInfixExpression();
  stringTrim(infixLine);
  trim = changeStrIfMinusIsFirst(infixLine);
  out = infix2postfix(trim);
  printf("%s\n", out);
  int r = caculate(out);
  printf("result->%d\n", r);
  free(out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <readInfixExpression@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <stringTrim@plt>
  mov    %rbx,%rdi
  call   <changeStrIfMinusIsFirst@plt>
  mov    %rax,%rdi
  call   <infix2postfix@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <caculate@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: result->%d


assistant: ```c
int main(int argc, char **argv) {
  char *infixLine;
  char *trim;
  char *out;
  infixLine = readInfixExpression();
  stringTrim(infixLine);
  trim = changeStrIfMinusIsFirst(infixLine);
  out = infix2postfix(trim);
  printf("%s\n", out);
  int r = caculate(out);
  printf("result->%d\n", r);
  free(out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <readInfixExpression@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <stringTrim@plt>
  mov    %rbp,%rdi
  call   <changeStrIfMinusIsFirst@plt>
  mov    %rax,%rdi
  call   <infix2postfix@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <caculate@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: result->%d


assistant: ```c
int main(int argc, char **argv) {
  char *infixLine;
  char *trim;
  char *out;
  infixLine = readInfixExpression();
  stringTrim(infixLine);
  trim = changeStrIfMinusIsFirst(infixLine);
  out = infix2postfix(trim);
  printf("%s\n", out);
  int r = caculate(out);
  printf("result->%d\n", r);
  free(out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <readInfixExpression@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <stringTrim@plt>
  mov    %rbp,%rdi
  call   <changeStrIfMinusIsFirst@plt>
  mov    %rax,%rdi
  call   <infix2postfix@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <caculate@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: result->%d


assistant: ```c
int main(int argc, char **argv) {
  char *infixLine;
  char *trim;
  char *out;
  infixLine = readInfixExpression();
  stringTrim(infixLine);
  trim = changeStrIfMinusIsFirst(infixLine);
  out = infix2postfix(trim);
  printf("%s\n", out);
  int r = caculate(out);
  printf("result->%d\n", r);
  free(out);
}
```