user: 请从给定的汇编指令推导出C源代码:

```asm
<thirdMax>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmp    $0x1,%esi
  je     L222
  cmp    $0x2,%esi
  je     L183
  mov    $0x0,%r13d
  mov    $0xfffffc54,%ecx
  mov    $0xfffffc54,%edx
  cmp    $0x1,%esi
  jle    L88
  lea    0x4(%rdi),%rbp
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%r15
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0xfffffc54,%r8d
  mov    $0xfffffc54,%ecx
  lea    D8(%rip),%r14
  jmp    L101
L222:
  mov    (%rdi),%eax
  jmp    L242
L183:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  jmp    L242
L203:
  jle    L186
  test   %r12,%r12
  je     L142
  mov    (%r12),%edx
  cmp    %edx,%eax
  jg     L89
  jge    L186
  test   %r13,%r13
  je     L220
  cmp    0x0(%r13),%eax
  jle    L226
  mov    %rbx,%rax
  mov    %r12,%rbx
  mov    %rbp,%r12
  jmp    L105
L142:
  mov    %rbp,%r12
  jmp    L186
L89:
  mov    %rbx,%rax
  mov    %rbp,%rbx
L105:
  cmp    %rbp,%r15
  je     L150
  add    $0x4,%rbp
  mov    %r12,%r13
  mov    %rbx,%r12
  mov    %rax,%rbx
L135:
  mov    0x0(%r13),%r8d
L234:
  mov    $0xfffffc54,%ecx
  test   %r12,%r12
  je     L101
  mov    (%r12),%ecx
L101:
  mov    $0xfffffc54,%edx
  test   %rbx,%rbx
  je     L91
  mov    (%rbx),%edx
L91:
  mov    0x0(%rbp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%edx
  mov    0x0(%rbp),%eax
  cmp    %eax,%edx
  jge    L203
  mov    %rbp,%rax
  test   %r12,%r12
  jne    L105
  mov    %rbx,%r12
  mov    %rbp,%rbx
L186:
  cmp    %rbp,%r15
  je     L194
  add    $0x4,%rbp
  mov    $0xfffffc54,%r8d
  test   %r13,%r13
  jne    L135
  jmp    L234
L220:
  mov    %rbx,%rax
  mov    %r12,%rbx
  mov    %rbp,%r12
  jmp    L105
L226:
  mov    %rbx,%rax
  mov    %r12,%rbx
  mov    %r13,%r12
  jmp    L105
L150:
  mov    %r12,%r13
  mov    %rbx,%r12
  mov    %rax,%rbx
L194:
  mov    $0xfffffc54,%ecx
  test   %r13,%r13
  je     L67
  mov    0x0(%r13),%ecx
L67:
  mov    $0xfffffc54,%edx
  test   %r12,%r12
  je     L50
  mov    (%r12),%edx
L88:
  mov    $0xfffffc54,%esi
  test   %rbx,%rbx
  je     L48
L50:
  mov    (%rbx),%esi
L48:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r13,%r13
  cmovne %r13,%rbx
  mov    (%rbx),%eax
L242:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string

tool: D8: item %d, m %d, s %d, t %d


tool: D13: m %d, s %d, t %d


assistant: ```c
int thirdMax(int *nums, int numsSize) {
  int *max = NULL, *sec = NULL, *third = NULL;
  if (numsSize == 1)
    return nums[0];
  if (numsSize == 2)
    return (nums[0] < nums[1]) ? nums[1] : nums[0];
  max = nums;
  for (int i = 1; i < numsSize; i++) {
    int *p = nums + i;
    printf("item %d, m %d, s %d, t %d\n", *p, max ? *max : -940, sec ? *sec : -940, third ? *third : -940);
    if (*max < *p) {
      if (sec == NULL) {
        sec = max;
        max = p;
      } else {
        third = sec;
        sec = max;
        max = p;
      }
    } else if (*max > *p) {
      if (sec == NULL) {
        sec = p;
      } else {
        if (*sec < *p) {
          third = sec;
          sec = p;
        } else if (*sec > *p) {
          if (third == NULL) {
            third = p;
          } else {
            if (*third < *p)
              third = p;
          }
        }
      }
    }
  }
  printf("m %d, s %d, t %d\n", max ? *max : -940, sec ? *sec : -940, third ? *third : -940);
  if (third == NULL)
    return *max;
  return *third;
}
```