ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <lua_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D19(%rip),%xmm0
  divsd  D27(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: f64
name: read_data
arguments: data_label: D27
type_infered: f64

tool: D21: sin

tool: D19: 3.141592653589793

tool: D27: 180

assistant: ```c
void math_sin(void) {
  double d = lua_check_number(1, "sin");
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <lua_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D13(%rip),%xmm0
  divsd  D2(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1070 <lua_pushnumber@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D13
type: f64
name: parse_data
arguments: data_tag: D2
type: f64

tool: D0: sin

tool: D13: 3.141592653589793

tool: D2: 180

assistant: ```c
void math_sin(void) {
  double d = lua_check_number(1, "sin");
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <lua_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D21(%rip),%xmm0
  divsd  D15(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1070 <lua_pushnumber@plt>
```

tool_calls: name: parse_data
arguments: label: D11
type_guessed: string
name: parse_data
arguments: label: D21
type_guessed: f64
name: parse_data
arguments: label: D15
type_guessed: f64

tool: D11: sin

tool: D21: 3.141592653589793

tool: D15: 180

assistant: ```c
void math_sin(void) {
  double d = lua_check_number(1, "sin");
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  jmp    L27
L11:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <trickle_down@plt>
  subl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L11
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <trickle_down@plt>
  subl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L36
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapsort(int *data, int n) {
  int i, t;
  for (i = (n - 2) / 2; i != -1; --i) {
    trickle_down(data, i, n);
  }
  for (i = n - 1; i != -1; --i) {
    t = data[i];
    data[i] = data[0];
    data[0] = t;
    trickle_down(data, 0, i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapsort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  lea    -0x2(%rsi),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L24
L9:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <trickle_down@plt>
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L9
L24:
  lea    -0x1(%r12),%ebp
  test   %r12d,%r12d
  je     L34
  movslq %ebp,%rbp
L36:
  mov    (%rbx,%rbp,4),%eax
  mov    (%rbx),%edx
  mov    %edx,(%rbx,%rbp,4)
  mov    %eax,(%rbx)
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <trickle_down@plt>
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebp
  jne    L36
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(int *data, int n) {
  int i, t;
  for (i = (n - 2) / 2; i != -1; --i) {
    trickle_down(data, i, n);
  }
  for (i = n - 1; i != -1; --i) {
    t = data[i];
    data[i] = data[0];
    data[0] = t;
    trickle_down(data, 0, i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<heapsort>:
  endbr64
  lea    -0x2(%rsi),%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %rdi,%rbx
  add    %eax,%ebp
  sar    %ebp
  cmp    $0xffffffff,%ebp
  je     L0
  nop
L34:
  mov    %ebp,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <trickle_down@plt>
  sub    $0x1,%ebp
  jae    L34
L0:
  lea    -0x1(%r12),%ebp
  test   %r12d,%r12d
  je     L26
  movslq %ebp,%rbp
  nop
L1:
  mov    (%rbx,%rbp,4),%eax
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %edx,(%rbx,%rbp,4)
  mov    %ebp,%edx
  sub    $0x1,%rbp
  mov    %eax,(%rbx)
  call   <trickle_down@plt>
  cmp    $0xffffffff,%ebp
  jne    L1
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(int *data, int n) {
  int i, t;
  for (i = (n - 2) / 2; i != -1; --i) {
    trickle_down(data, i, n);
  }
  for (i = n - 1; i != -1; --i) {
    t = data[i];
    data[i] = data[0];
    data[0] = t;
    trickle_down(data, 0, i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapsort>:
  endbr64
  lea    -0x2(%rsi),%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %rdi,%rbx
  add    %eax,%ebp
  sar    %ebp
  cmp    $0xffffffff,%ebp
  je     L10
  nop
L1:
  mov    %ebp,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <trickle_down@plt>
  sub    $0x1,%ebp
  jae    L1
L10:
  lea    -0x1(%r12),%ebp
  test   %r12d,%r12d
  je     L15
  movslq %ebp,%rbp
  nop
L31:
  mov    (%rbx,%rbp,4),%eax
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %edx,(%rbx,%rbp,4)
  mov    %ebp,%edx
  sub    $0x1,%rbp
  mov    %eax,(%rbx)
  call   <trickle_down@plt>
  cmp    $0xffffffff,%ebp
  jne    L31
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapsort(int *data, int n) {
  int i, t;
  for (i = (n - 2) / 2; i != -1; --i) {
    trickle_down(data, i, n);
  }
  for (i = n - 1; i != -1; --i) {
    t = data[i];
    data[i] = data[0];
    data[0] = t;
    trickle_down(data, 0, i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIO_clear_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x20,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  mov    $0x200040,%edx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
  jmp    L15
L16:
  mov    $0x200044,%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
L15:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPIO_clear_event(uint8_t pin) {
  ;
  int8_t clr1 = pin - 32;
  if (clr1 < 0)
    (*((volatile uint32_t *)(0x00200040))) = (1 << pin);
  else
    (*((volatile uint32_t *)(0x00200044))) = (1 << clr1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GPIO_clear_event>:
  endbr64
  mov    %edi,%ecx
  sub    $0x20,%ecx
  js     L4
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,0x200044
  ret
L4:
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x200040
  ret
```

assistant: ```c
void GPIO_clear_event(uint8_t pin) {
  ;
  int8_t clr1 = pin - 32;
  if (clr1 < 0)
    (*((volatile uint32_t *)(0x00200040))) = (1 << pin);
  else
    (*((volatile uint32_t *)(0x00200044))) = (1 << clr1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GPIO_clear_event>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  sub    $0x20,%ecx
  js     L2
  shl    %cl,%eax
  mov    %eax,0x200044
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x200040
  ret
```

assistant: ```c
void GPIO_clear_event(uint8_t pin) {
  ;
  int8_t clr1 = pin - 32;
  if (clr1 < 0)
    (*((volatile uint32_t *)(0x00200040))) = (1 << pin);
  else
    (*((volatile uint32_t *)(0x00200044))) = (1 << clr1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIO_clear_event>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  sub    $0x20,%ecx
  js     L3
  shl    %cl,%eax
  mov    %eax,0x200044
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,0x200040
  ret
```

assistant: ```c
void GPIO_clear_event(uint8_t pin) {
  ;
  int8_t clr1 = pin - 32;
  if (clr1 < 0)
    (*((volatile uint32_t *)(0x00200040))) = (1 << pin);
  else
    (*((volatile uint32_t *)(0x00200044))) = (1 << clr1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_rotate_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  movss  %xmm0,-0x5c(%rbp)
  movss  %xmm1,-0x60(%rbp)
  movss  %xmm2,-0x64(%rbp)
  movss  %xmm3,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x68(%rbp),%xmm2
  movss  -0x64(%rbp),%xmm1
  movss  -0x60(%rbp),%xmm0
  mov    -0x5c(%rbp),%edx
  lea    -0x50(%rbp),%rax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <matrix_get_rotation@plt>
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matrix_multiply_ext@plt>
  mov    -0x70(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
float *matrix_rotate_ext(const float matrix[4 * 4], const float angle, const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_rotation(matrix_tmp, angle, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix_rotate_ext>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <matrix_get_rotation@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbx,%rax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_rotate_ext(const float matrix[4 * 4], const float angle, const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_rotation(matrix_tmp, angle, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matrix_rotate_ext>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <matrix_get_rotation@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_rotate_ext(const float matrix[4 * 4], const float angle, const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_rotation(matrix_tmp, angle, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_rotate_ext>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <matrix_get_rotation@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_rotate_ext(const float matrix[4 * 4], const float angle, const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_rotation(matrix_tmp, angle, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<I3_remove_quotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L2:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  sub    $0x1,%rax
  add    %rbx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L11
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  sub    $0x1,%rax
  add    %rbx,%rax
  movb   $0x0,(%rax)
L11:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L10
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L27
  addq   $0x1,-0x18(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void I3_remove_quotes(char **ps) {
  char *ps1, *ps2;
  if (*ps[0] == '"')
    (*ps)++;
  if ((*ps)[strlen(*ps) - 1] == '"')
    (*ps)[strlen(*ps) - 1] = 0;
  ps1 = ps2 = *ps;
  while (ps2[0]) {
    if (ps2[0] == '\\') {
      ps2++;
    }
    ps1[0] = ps2[0];
    ps1++;
    ps2++;
  }
  ps1[0] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<I3_remove_quotes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  cmpb   $0x22,(%rax)
  je     L50
L59:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbp,%rax,1)
  je     L39
L21:
  mov    (%rbx),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L8
  mov    %rdx,%rcx
L18:
  cmp    $0x5c,%al
  sete   %al
  movzbl %al,%eax
  add    %rcx,%rax
  movzbl (%rax),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  lea    0x1(%rax),%rcx
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L18
L8:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  add    $0x1,%rax
  mov    %rax,(%rdi)
  jmp    L59
L39:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L21
```

assistant: ```c
void I3_remove_quotes(char **ps) {
  char *ps1, *ps2;
  if (*ps[0] == '"')
    (*ps)++;
  if ((*ps)[strlen(*ps) - 1] == '"')
    (*ps)[strlen(*ps) - 1] = 0;
  ps1 = ps2 = *ps;
  while (ps2[0]) {
    if (ps2[0] == '\\') {
      ps2++;
    }
    ps1[0] = ps2[0];
    ps1++;
    ps2++;
  }
  ps1[0] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<I3_remove_quotes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  cmpb   $0x22,0x0(%rbp)
  jne    L48
  add    $0x1,%rbp
  mov    %rbp,(%rdi)
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbp,%rax,1)
  je     L29
L16:
  mov    (%rbx),%rcx
  movzbl (%rcx),%eax
  mov    %rcx,%rdx
  test   %al,%al
  je     L1
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    $0x5c,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %rcx,%rax
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdx)
  lea    0x1(%rax),%rcx
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L7
L1:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L16
```

assistant: ```c
void I3_remove_quotes(char **ps) {
  char *ps1, *ps2;
  if (*ps[0] == '"')
    (*ps)++;
  if ((*ps)[strlen(*ps) - 1] == '"')
    (*ps)[strlen(*ps) - 1] = 0;
  ps1 = ps2 = *ps;
  while (ps2[0]) {
    if (ps2[0] == '\\') {
      ps2++;
    }
    ps1[0] = ps2[0];
    ps1++;
    ps2++;
  }
  ps1[0] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<I3_remove_quotes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  cmpb   $0x22,0x0(%rbp)
  jne    L26
  add    $0x1,%rbp
  mov    %rbp,(%rdi)
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbp,%rax,1)
  je     L2
L31:
  mov    (%rbx),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L12
  mov    %rdx,%rcx
  jmp    L64
  nopl   (%rax)
L41:
  mov    %al,(%rdx)
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rdx
  lea    0x1(%rcx),%rsi
  test   %al,%al
  je     L12
L48:
  mov    %rsi,%rcx
L64:
  cmp    $0x5c,%al
  jne    L41
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rdx
  lea    0x2(%rcx),%rsi
  mov    %al,-0x1(%rdx)
  movzbl 0x2(%rcx),%eax
  test   %al,%al
  jne    L48
L12:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  jmp    L31
```

assistant: ```c
void I3_remove_quotes(char **ps) {
  char *ps1, *ps2;
  if (*ps[0] == '"')
    (*ps)++;
  if ((*ps)[strlen(*ps) - 1] == '"')
    (*ps)[strlen(*ps) - 1] = 0;
  ps1 = ps2 = *ps;
  while (ps2[0]) {
    if (ps2[0] == '\\') {
      ps2++;
    }
    ps1[0] = ps2[0];
    ps1++;
    ps2++;
  }
  ps1[0] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prev_block_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  movl   $0x32,-0x4(%rbp)
L4:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t prev_block_index(uint8_t block_index) {
  if (block_index == 0) {
    block_index = 50;
  }
  block_index--;
  return (block_index);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prev_block_index>:
  endbr64
  test   %edi,%edi
  mov    $0x32,%eax
  cmove  %eax,%edi
  lea    -0x1(%rdi),%eax
  ret
```

assistant: ```c
uint8_t prev_block_index(uint8_t block_index) {
  if (block_index == 0) {
    block_index = 50;
  }
  block_index--;
  return (block_index);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<prev_block_index>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %edi,%edi
  mov    $0x31,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint8_t prev_block_index(uint8_t block_index) {
  if (block_index == 0) {
    block_index = 50;
  }
  block_index--;
  return (block_index);
}
```
user: What is the c source code of the assembly code below?

```asm
<prev_block_index>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %edi,%edi
  mov    $0x31,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
uint8_t prev_block_index(uint8_t block_index) {
  if (block_index == 0) {
    block_index = 50;
  }
  block_index--;
  return (block_index);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L33:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jb     L25
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L33
L25:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jb     L25
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jae    L30
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L33
L30:
  nop
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(unsigned int a[], int l, int r) {
  unsigned int pivot, i, j, t;
  pivot = a[l];
  i = l;
  j = r + 1;
  while (1) {
    do
      ++i;
    while (a[i] <= pivot && i <= r);
    do
      --j;
    while (a[j] > pivot);
    if (i >= j)
      break;
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
  t = a[l];
  a[l] = a[j];
  a[j] = t;
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partition>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbx
  mov    (%rbx),%r9d
  lea    0x1(%rdx),%eax
  jmp    L16
L55:
  sub    $0x1,%eax
  mov    %eax,%ecx
  lea    (%r8,%rcx,4),%rcx
  mov    (%rcx),%edi
  cmp    %r9d,%edi
  ja     L55
  cmp    %eax,%esi
  jae    L42
  mov    %edi,(%r11)
  mov    %r10d,(%rcx)
L16:
  add    $0x1,%esi
  mov    %esi,%ecx
  lea    (%r8,%rcx,4),%r11
  mov    (%r11),%r10d
  cmp    %r9d,%r10d
  ja     L55
  cmp    %esi,%edx
  jae    L16
  jmp    L55
L42:
  mov    (%rbx),%edx
  mov    %edi,(%rbx)
  mov    %edx,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
int partition(unsigned int a[], int l, int r) {
  unsigned int pivot, i, j, t;
  pivot = a[l];
  i = l;
  j = r + 1;
  while (1) {
    do
      ++i;
    while (a[i] <= pivot && i <= r);
    do
      --j;
    while (a[j] > pivot);
    if (i >= j)
      break;
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
  t = a[l];
  a[l] = a[j];
  a[j] = t;
  return j;
}
```