ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tests_from_supercop>:
  endbr64
  push   %r15
  mov    $0x1010,%edi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r15
  lea    0x40(%rsp),%rbx
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x10,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <fill@plt>
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <fill@plt>
  lea    0x20(%rsp),%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x28(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L0
  xchg   %ax,%ax
L39:
  add    $0x1,%r14
  cmp    $0x1001,%r14
  je     L24
L0:
  lea    0x10(%r14),%rax
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    %r14,0x28(%rsp)
  mov    %rax,0x20(%rsp)
  call   <fill@plt>
  mov    0x28(%rsp),%rsi
  mov    %rbp,%rdi
  call   <fill@plt>
  sub    $0x8,%rsp
  mov    %r14,%r9
  mov    %r12,%r8
  push   %r15
  mov    %rbp,%rdx
  mov    %r13,%rdi
  push   %rbx
  push   $0x0
  mov    0x48(%rsp),%rcx
  mov    0x30(%rsp),%rsi
  call   <crypto_aead_encrypt@plt>
  add    $0x18,%rsp
  mov    %r12,%r9
  mov    %r13,%rcx
  push   %r15
  xor    %edx,%edx
  mov    %rbp,%rdi
  push   %rbx
  push   %r14
  mov    0x40(%rsp),%r8
  mov    0x38(%rsp),%rsi
  call   <crypto_aead_decrypt@plt>
  or     %eax,0x2c(%rsp)
  add    $0x20,%rsp
  test   %eax,%eax
  je     L39
  mov    %r14,%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  add    $0x1,%r14
  call   <printf@plt>
  cmp    $0x1001,%r14
  jne    L0
L24:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    0xc(%rsp),%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: crypto_aead_decrypt returned %d at %zu


assistant: ```c
int tests_from_supercop() {
  static const size_t MAXTEST_BYTES = 4096;
  unsigned char *c = (unsigned char *)malloc((size_t)MAXTEST_BYTES + 16);
  unsigned char *a = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char *m = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char k[16];
  unsigned char npub[16];
  unsigned char *nsec = 0;
  unsigned long long alen;
  unsigned long long clen;
  unsigned long long mlen;
  int result = 0;
  fill(k, 16);
  fill(npub, 16);
  for (size_t i = 0; i <= MAXTEST_BYTES; ++i) {
    mlen = i;
    alen = i;
    clen = i + 16;
    fill(a, alen);
    fill(m, mlen);
    crypto_aead_encrypt(c, &clen, m, mlen, a, alen, nsec, npub, k);
    const int current_result = crypto_aead_decrypt(m, &mlen, nsec, c, clen, a, alen, npub, k);
    result |= current_result;
    if (current_result) {
      printf("crypto_aead_decrypt returned %d at %zu\n", current_result, i);
    }
  }
  free(a);
  free(c);
  free(m);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tests_from_supercop>:
  endbr64
  push   %r15
  mov    $0x1010,%edi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r15
  lea    0x40(%rsp),%rbx
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x10,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <fill@plt>
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <fill@plt>
  lea    0x20(%rsp),%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  lea    0x28(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L25
  xchg   %ax,%ax
L38:
  add    $0x1,%r14
  cmp    $0x1001,%r14
  je     L13
L25:
  lea    0x10(%r14),%rax
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    %r14,0x28(%rsp)
  mov    %rax,0x20(%rsp)
  call   <fill@plt>
  mov    0x28(%rsp),%rsi
  mov    %rbp,%rdi
  call   <fill@plt>
  sub    $0x8,%rsp
  mov    %r14,%r9
  mov    %r12,%r8
  push   %r15
  mov    %rbp,%rdx
  mov    %r13,%rdi
  push   %rbx
  push   $0x0
  mov    0x48(%rsp),%rcx
  mov    0x30(%rsp),%rsi
  call   <crypto_aead_encrypt@plt>
  add    $0x18,%rsp
  mov    %r12,%r9
  mov    %r13,%rcx
  push   %r15
  xor    %edx,%edx
  mov    %rbp,%rdi
  push   %rbx
  push   %r14
  mov    0x40(%rsp),%r8
  mov    0x38(%rsp),%rsi
  call   <crypto_aead_decrypt@plt>
  or     %eax,0x2c(%rsp)
  add    $0x20,%rsp
  test   %eax,%eax
  je     L38
  mov    %r14,%rdx
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  add    $0x1,%r14
  call   <printf@plt>
  cmp    $0x1001,%r14
  jne    L25
L13:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    0xc(%rsp),%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: crypto_aead_decrypt returned %d at %zu


assistant: ```c
int tests_from_supercop() {
  static const size_t MAXTEST_BYTES = 4096;
  unsigned char *c = (unsigned char *)malloc((size_t)MAXTEST_BYTES + 16);
  unsigned char *a = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char *m = (unsigned char *)malloc((size_t)MAXTEST_BYTES);
  unsigned char k[16];
  unsigned char npub[16];
  unsigned char *nsec = 0;
  unsigned long long alen;
  unsigned long long clen;
  unsigned long long mlen;
  int result = 0;
  fill(k, 16);
  fill(npub, 16);
  for (size_t i = 0; i <= MAXTEST_BYTES; ++i) {
    mlen = i;
    alen = i;
    clen = i + 16;
    fill(a, alen);
    fill(m, mlen);
    crypto_aead_encrypt(c, &clen, m, mlen, a, alen, nsec, npub, k);
    const int current_result = crypto_aead_decrypt(m, &mlen, nsec, c, clen, a, alen, npub, k);
    result |= current_result;
    if (current_result) {
      printf("crypto_aead_decrypt returned %d at %zu\n", current_result, i);
    }
  }
  free(a);
  free(c);
  free(m);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_WLocale_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x460,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %rcx,-0x450(%rbp)
  mov    %r8,-0x458(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x424(%rbp)
  jmp    L0
L58:
  mov    -0x448(%rbp),%rax
  mov    $0x3f,%edx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  mov    %rax,-0x420(%rbp)
  mov    -0x458(%rbp),%rax
  mov    $0x3f,%edx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  mov    %rax,-0x418(%rbp)
  mov    -0x420(%rbp),%rdx
  mov    -0x440(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcsncpy@plt>
  mov    -0x420(%rbp),%rax
  movq   $0x0,-0x410(%rbp,%rax,8)
  mov    -0x418(%rbp),%rdx
  mov    -0x450(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcsncpy@plt>
  mov    -0x418(%rbp),%rax
  movq   $0x0,-0x210(%rbp,%rax,8)
  lea    -0x210(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wcscmp@plt>
  mov    %eax,-0x424(%rbp)
  cmpl   $0x0,-0x424(%rbp)
  je     L41
  cmpl   $0x0,-0x424(%rbp)
  jns    L22
  mov    $0xffffffff,%eax
  jmp    L53
L22:
  mov    $0x1,%eax
  jmp    L53
L41:
  mov    -0x420(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x440(%rbp)
  mov    -0x420(%rbp),%rax
  sub    %rax,-0x448(%rbp)
  mov    -0x418(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x450(%rbp)
  mov    -0x418(%rbp),%rax
  sub    %rax,-0x458(%rbp)
L0:
  cmpq   $0x0,-0x448(%rbp)
  jne    L58
  cmpq   $0x0,-0x458(%rbp)
  jne    L58
  cmpl   $0x0,-0x424(%rbp)
  je     L71
  cmpl   $0x0,-0x424(%rbp)
  jns    L52
  mov    $0xffffffff,%eax
  jmp    L53
L52:
  mov    $0x1,%eax
  jmp    L53
L71:
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
int _WLocale_strcmp(struct _Locale_collate *lcol __attribute__((__unused__)), const wchar_t *s1, size_t n1, const wchar_t *s2, size_t n2) {
  int ret = 0;
  wchar_t buf1[64], buf2[64];
  while (n1 > 0 || n2 > 0) {
    size_t bufsize1 = n1 < 63 ? n1 : 63;
    size_t bufsize2 = n2 < 63 ? n2 : 63;
    wcsncpy(buf1, s1, bufsize1);
    buf1[bufsize1] = 0;
    wcsncpy(buf2, s2, bufsize2);
    buf2[bufsize2] = 0;
    ret = wcscmp(buf1, buf2);
    if (ret != 0)
      return ret < 0 ? -1 : 1;
    s1 += bufsize1;
    n1 -= bufsize1;
    s2 += bufsize2;
    n2 -= bufsize2;
  }
  return ret == 0 ? 0 : (ret < 0 ? -1 : 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_WLocale_strcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rax
  or     %r8,%rax
  je     L29
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r15
  mov    %r8,%r13
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
L7:
  mov    $0x3f,%ebp
  cmp    %rbp,%r12
  cmovbe %r12,%rbp
  mov    $0x3f,%ebx
  cmp    %rbx,%r13
  cmovbe %r13,%rbx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    (%rsp),%rdi
  call   <wcsncpy@plt>
  movq   $0x0,0x10(%rsp,%rbp,8)
  lea    0x210(%rsp),%rax
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  call   <wcsncpy@plt>
  movq   $0x0,0x210(%rsp,%rbx,8)
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <wcscmp@plt>
  test   %eax,%eax
  jne    L31
  lea    (%r14,%rbp,8),%r14
  sub    %rbp,%r12
  lea    (%r15,%rbx,8),%r15
  sub    %rbx,%r13
  mov    %r12,%rax
  or     %r13,%rax
  jne    L7
L29:
  mov    $0x0,%eax
L20:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  sar    $0x1f,%eax
  or     $0x1,%eax
  jmp    L20
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _WLocale_strcmp(struct _Locale_collate *lcol __attribute__((__unused__)), const wchar_t *s1, size_t n1, const wchar_t *s2, size_t n2) {
  int ret = 0;
  wchar_t buf1[64], buf2[64];
  while (n1 > 0 || n2 > 0) {
    size_t bufsize1 = n1 < 63 ? n1 : 63;
    size_t bufsize2 = n2 < 63 ? n2 : 63;
    wcsncpy(buf1, s1, bufsize1);
    buf1[bufsize1] = 0;
    wcsncpy(buf2, s2, bufsize2);
    buf2[bufsize2] = 0;
    ret = wcscmp(buf1, buf2);
    if (ret != 0)
      return ret < 0 ? -1 : 1;
    s1 += bufsize1;
    n1 -= bufsize1;
    s2 += bufsize2;
    n2 -= bufsize2;
  }
  return ret == 0 ? 0 : (ret < 0 ? -1 : 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_WLocale_strcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  mov    %rdx,%rax
  or     %r8,%rax
  je     L8
  mov    %rsi,%r9
  mov    %rdx,%r15
  lea    0x10(%rsp),%r14
  mov    %rcx,%r12
  lea    0x210(%rsp),%r13
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L27:
  sub    %rbp,%r15
  lea    (%r9,%rbp,8),%r9
  lea    (%r12,%rbx,8),%r12
  sub    %rbx,%r8
  mov    %r15,%rax
  or     %r8,%rax
  je     L8
L18:
  mov    $0x3f,%ebp
  mov    $0x3f,%ebx
  mov    %r9,%rsi
  mov    %r14,%rdi
  cmp    %rbp,%r15
  mov    %r8,0x8(%rsp)
  cmovbe %r15,%rbp
  cmp    %rbx,%r8
  mov    %r9,(%rsp)
  cmovbe %r8,%rbx
  mov    %rbp,%rdx
  call   <wcsncpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  movq   $0x0,0x10(%rsp,%rbp,8)
  call   <wcsncpy@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  movq   $0x0,0x210(%rsp,%rbx,8)
  call   <wcscmp@plt>
  mov    (%rsp),%r9
  mov    0x8(%rsp),%r8
  test   %eax,%eax
  je     L27
  sar    $0x1f,%eax
  or     $0x1,%eax
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
L43:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _WLocale_strcmp(struct _Locale_collate *lcol __attribute__((__unused__)), const wchar_t *s1, size_t n1, const wchar_t *s2, size_t n2) {
  int ret = 0;
  wchar_t buf1[64], buf2[64];
  while (n1 > 0 || n2 > 0) {
    size_t bufsize1 = n1 < 63 ? n1 : 63;
    size_t bufsize2 = n2 < 63 ? n2 : 63;
    wcsncpy(buf1, s1, bufsize1);
    buf1[bufsize1] = 0;
    wcsncpy(buf2, s2, bufsize2);
    buf2[bufsize2] = 0;
    ret = wcscmp(buf1, buf2);
    if (ret != 0)
      return ret < 0 ? -1 : 1;
    s1 += bufsize1;
    n1 -= bufsize1;
    s2 += bufsize2;
    n2 -= bufsize2;
  }
  return ret == 0 ? 0 : (ret < 0 ? -1 : 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_WLocale_strcmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  mov    %rdx,%rax
  or     %r8,%rax
  je     L52
  mov    %rsi,%r9
  mov    %rdx,%r15
  lea    0x10(%rsp),%r14
  mov    %rcx,%r12
  lea    0x210(%rsp),%r13
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L12:
  sub    %rbp,%r15
  lea    (%r9,%rbp,8),%r9
  lea    (%r12,%rbx,8),%r12
  sub    %rbx,%r8
  mov    %r15,%rax
  or     %r8,%rax
  je     L52
L39:
  mov    $0x3f,%ebp
  mov    $0x3f,%ebx
  mov    %r9,%rsi
  mov    %r14,%rdi
  cmp    %rbp,%r15
  mov    %r8,0x8(%rsp)
  cmovbe %r15,%rbp
  cmp    %rbx,%r8
  mov    %r9,(%rsp)
  cmovbe %r8,%rbx
  mov    %rbp,%rdx
  call   <wcsncpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  movq   $0x0,0x10(%rsp,%rbp,8)
  call   <wcsncpy@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  movq   $0x0,0x210(%rsp,%rbx,8)
  call   <wcscmp@plt>
  mov    (%rsp),%r9
  mov    0x8(%rsp),%r8
  test   %eax,%eax
  je     L12
  sar    $0x1f,%eax
  or     $0x1,%eax
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L52:
  xor    %eax,%eax
L25:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _WLocale_strcmp(struct _Locale_collate *lcol __attribute__((__unused__)), const wchar_t *s1, size_t n1, const wchar_t *s2, size_t n2) {
  int ret = 0;
  wchar_t buf1[64], buf2[64];
  while (n1 > 0 || n2 > 0) {
    size_t bufsize1 = n1 < 63 ? n1 : 63;
    size_t bufsize2 = n2 < 63 ? n2 : 63;
    wcsncpy(buf1, s1, bufsize1);
    buf1[bufsize1] = 0;
    wcsncpy(buf2, s2, bufsize2);
    buf2[bufsize2] = 0;
    ret = wcscmp(buf1, buf2);
    if (ret != 0)
      return ret < 0 ? -1 : 1;
    s1 += bufsize1;
    n1 -= bufsize1;
    s2 += bufsize2;
    n2 -= bufsize2;
  }
  return ret == 0 ? 0 : (ret < 0 ? -1 : 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L34:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  cmpl   $0x1,-0x4(%rbp)
  je     L24
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L24
  mov    $0x0,%eax
  jmp    L49
L24:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L34
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int main1(int num) {
  int i = 1;
  while (i <= num) {
    if (num % i == 0) {
      if (!((i == 1) || (i == num))) {
        return 0;
      }
    }
    i++;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main1>:
  endbr64
  test   %edi,%edi
  jle    L54
  mov    $0x1,%ecx
  jmp    L3
L20:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jl     L13
L3:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L20
  cmp    $0x1,%ecx
  je     L20
  cmp    %ecx,%edi
  je     L20
L26:
  ret
L13:
  mov    $0x1,%eax
  ret
L54:
  mov    $0x1,%eax
  jmp    L26
```

assistant: ```c
int main1(int num) {
  int i = 1;
  while (i <= num) {
    if (num % i == 0) {
      if (!((i == 1) || (i == num))) {
        return 0;
      }
    }
    i++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main1>:
  endbr64
  test   %edi,%edi
  jle    L39
  mov    $0x1,%ecx
  nopl   (%rax)
L36:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L47
  cmp    $0x1,%ecx
  je     L47
  cmp    %ecx,%edi
  jne    L34
L47:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jge    L36
L39:
  mov    $0x1,%edx
L34:
  mov    %edx,%eax
  ret
```

assistant: ```c
int main1(int num) {
  int i = 1;
  while (i <= num) {
    if (num % i == 0) {
      if (!((i == 1) || (i == num))) {
        return 0;
      }
    }
    i++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main1>:
  endbr64
  test   %edi,%edi
  jle    L44
  mov    $0x1,%ecx
  nopl   (%rax)
L43:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L3
  cmp    $0x1,%ecx
  je     L3
  cmp    %ecx,%edi
  jne    L41
L3:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jge    L43
L44:
  mov    $0x1,%edx
L41:
  mov    %edx,%eax
  ret
```

assistant: ```c
int main1(int num) {
  int i = 1;
  while (i <= num) {
    if (num % i == 0) {
      if (!((i == 1) || (i == num))) {
        return 0;
      }
    }
    i++;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_pandigital>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L20
L8:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L24
  mov    $0x0,%eax
  jmp    L5
L24:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    -0x1(%rdx),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  shll   -0x4(%rbp)
L20:
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  not    %eax
  cmp    %eax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int check_pandigital(unsigned int number) {
  unsigned int temp = 0, mask = 0xFFFFFFFF;
  while (number) {
    if (!(number % 10))
      return 0;
    temp |= 0x1 << (number % 10 - 1);
    number /= 10;
    mask <<= 1;
  }
  return (temp == ~mask);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_pandigital>:
  endbr64
  mov    %edi,%esi
  test   %edi,%edi
  je     L18
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L26
  mov    $0xffffffff,%edi
  mov    $0x0,%r8d
  mov    $0x1,%r10d
  mov    $0xcccccccd,%r9d
L22:
  lea    -0x1(%rax),%ecx
  mov    %r10d,%eax
  shl    %cl,%eax
  or     %eax,%r8d
  mov    %esi,%eax
  mov    %esi,%edx
  imul   %r9,%rdx
  shr    $0x23,%rdx
  mov    %edx,%esi
  add    %edi,%edi
  cmp    $0x9,%eax
  jbe    L31
  mov    %edx,%eax
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jne    L22
  jmp    L26
L18:
  mov    %edi,%r8d
  mov    $0xffffffff,%edi
L31:
  not    %edi
  cmp    %r8d,%edi
  sete   %al
  movzbl %al,%eax
L26:
  ret
```

assistant: ```c
unsigned int check_pandigital(unsigned int number) {
  unsigned int temp = 0, mask = 0xFFFFFFFF;
  while (number) {
    if (!(number % 10))
      return 0;
    temp |= 0x1 << (number % 10 - 1);
    number /= 10;
    mask <<= 1;
  }
  return (temp == ~mask);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_pandigital>:
  endbr64
  mov    %edi,%esi
  test   %edi,%edi
  je     L32
  mov    %edi,%edx
  mov    $0xcccccccd,%r8d
  mov    %rdx,%rax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  je     L48
  mov    $0xffffffff,%edi
  xor    %r9d,%r9d
  mov    $0x1,%r10d
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %esi,%edx
  mov    %rdx,%rax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %esi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  je     L48
L19:
  imul   %r8,%rdx
  lea    -0x1(%rax),%ecx
  mov    %r10d,%eax
  add    %edi,%edi
  shl    %cl,%eax
  or     %eax,%r9d
  mov    %esi,%eax
  shr    $0x23,%rdx
  mov    %rdx,%rsi
  cmp    $0x9,%eax
  ja     L49
  not    %edi
  xor    %eax,%eax
  cmp    %r9d,%edi
  sete   %al
  ret
L32:
  mov    $0x1,%eax
L48:
  ret
```

assistant: ```c
unsigned int check_pandigital(unsigned int number) {
  unsigned int temp = 0, mask = 0xFFFFFFFF;
  while (number) {
    if (!(number % 10))
      return 0;
    temp |= 0x1 << (number % 10 - 1);
    number /= 10;
    mask <<= 1;
  }
  return (temp == ~mask);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_pandigital>:
  endbr64
  mov    %edi,%esi
  test   %edi,%edi
  je     L0
  mov    %edi,%edx
  mov    $0xcccccccd,%r8d
  mov    %rdx,%rax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  je     L46
  mov    $0xffffffff,%edi
  xor    %r9d,%r9d
  mov    $0x1,%r10d
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %esi,%edx
  mov    %rdx,%rax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %esi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  je     L46
L7:
  imul   %r8,%rdx
  lea    -0x1(%rax),%ecx
  mov    %r10d,%eax
  add    %edi,%edi
  shl    %cl,%eax
  or     %eax,%r9d
  mov    %esi,%eax
  shr    $0x23,%rdx
  mov    %rdx,%rsi
  cmp    $0x9,%eax
  ja     L40
  not    %edi
  xor    %eax,%eax
  cmp    %r9d,%edi
  sete   %al
  ret
L0:
  mov    $0x1,%eax
L46:
  ret
```

assistant: ```c
unsigned int check_pandigital(unsigned int number) {
  unsigned int temp = 0, mask = 0xFFFFFFFF;
  while (number) {
    if (!(number % 10))
      return 0;
    temp |= 0x1 << (number % 10 - 1);
    number /= 10;
    mask <<= 1;
  }
  return (temp == ~mask);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string

tool: D14: Unitialized x = %i


tool: D13: x with 1 + 2 = %i


assistant: ```c
int main(int argc, char **argv) {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1 + 2 = %i\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D4: Unitialized x = %i


tool: D2: x with 1 + 2 = %i


assistant: ```c
int main(int argc, char **argv) {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1 + 2 = %i\n", x);
  return 0;
}
```