ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x14,-0x28(%rbp)
  movl   $0xa,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0xe,-0x14(%rbp)
  movl   $0x15,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x1,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <imprimir_arreglo@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L9
L8:
  movl   $0x0,-0x3c(%rbp)
  jmp    L53
L0:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L21
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L21:
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <imprimir_arreglo@plt>
  addl   $0x1,-0x3c(%rbp)
L53:
  cmpl   $0x8,-0x3c(%rbp)
  jle    L0
  addl   $0x1,-0x40(%rbp)
L9:
  cmpl   $0x9,-0x40(%rbp)
  jle    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int iteracion = 1;
  imprimir_arreglo(arreglo);
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= 8; j++) {
      if (arreglo[j] > arreglo[j + 1]) {
        int aux = arreglo[j];
        arreglo[j] = arreglo[j + 1];
        arreglo[j + 1] = aux;
      }
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x14,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x8,0x14(%rsp)
  movl   $0x9,0x18(%rsp)
  movl   $0xe,0x1c(%rsp)
  movl   $0x15,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  mov    %rsp,%rdi
  call   <imprimir_arreglo@plt>
  mov    $0x1,%r13d
  lea    D7(%rip),%r12
  jmp    L35
L39:
  lea    0x1(%rsi),%r14d
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <imprimir_arreglo@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L1
  mov    %r14d,%esi
L30:
  mov    -0x4(%rbx),%eax
  mov    (%rbx),%edx
  cmp    %edx,%eax
  jle    L39
  mov    %edx,-0x4(%rbx)
  mov    %eax,(%rbx)
  jmp    L39
L1:
  add    $0x9,%r13d
  cmp    $0x5b,%r13d
  je     L62
L35:
  lea    0x4(%rsp),%rbx
  lea    0x28(%rsp),%rbp
  mov    %r13d,%esi
  jmp    L30
L62:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int iteracion = 1;
  imprimir_arreglo(arreglo);
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= 8; j++) {
      if (arreglo[j] > arreglo[j + 1]) {
        int aux = arreglo[j];
        arreglo[j] = arreglo[j + 1];
        arreglo[j + 1] = aux;
      }
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x400000001,%rax
  lea    0x10(%rsp),%rbp
  lea    0x38(%rsp),%r12
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  movabs $0xa00000014,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x800000003,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xe00000009,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000015,%rax
  mov    %rax,0x30(%rsp)
  call   <imprimir_arreglo@plt>
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L45:
  mov    0x8(%rsp),%r15
  mov    %r14d,%esi
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%esi
L9:
  mov    -0x4(%r15),%eax
  mov    (%r15),%ecx
  cmp    %ecx,%eax
  jle    L37
  mov    %ecx,-0x4(%r15)
  mov    %eax,(%r15)
L37:
  mov    %r13,%rdi
  lea    0x1(%rsi),%ebx
  add    $0x4,%r15
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <imprimir_arreglo@plt>
  cmp    %r12,%r15
  jne    L19
  add    $0x9,%r14d
  cmp    $0x5b,%r14d
  jne    L45
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: Iteracion #%03d 

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int iteracion = 1;
  imprimir_arreglo(arreglo);
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= 8; j++) {
      if (arreglo[j] > arreglo[j + 1]) {
        int aux = arreglo[j];
        arreglo[j] = arreglo[j + 1];
        arreglo[j + 1] = aux;
      }
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D36(%rip),%rax
  lea    0x24(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <imprimir_arreglo@plt>
  nopl   0x0(%rax)
L36:
  mov    %rbp,%rbx
  mov    %r14d,%esi
  jmp    L12
L16:
  movq   %xmm1,(%rbx)
  mov    %r13,%rdi
  lea    0x1(%rsi),%r15d
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <imprimir_arreglo@plt>
  cmp    %r12,%rbx
  je     L19
L9:
  mov    %r15d,%esi
L12:
  movq   (%rbx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%edx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%edx
  jg     L16
  mov    %r13,%rdi
  lea    0x1(%rsi),%r15d
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <imprimir_arreglo@plt>
  cmp    %rbx,%r12
  jne    L9
L19:
  add    $0x9,%r14d
  cmp    $0x5b,%r14d
  jne    L36
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: byte[16]
name: disassemble_data
arguments: tag: D36
datatype: byte[8]
name: disassemble_data
arguments: tag: D23
datatype: byte[16]

tool: D17: Iteracion #%03d 

tool: {"D2": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D36": [0x15,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D23": [0x03,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arreglo[10] = {1, 4, 20, 10, 3, 8, 9, 14, 21, 6};
  int i;
  int j;
  int iteracion = 1;
  imprimir_arreglo(arreglo);
  for (i = 0; i < 10; i++) {
    for (j = 0; j <= 8; j++) {
      if (arreglo[j] > arreglo[j + 1]) {
        int aux = arreglo[j];
        arreglo[j] = arreglo[j + 1];
        arreglo[j + 1] = aux;
      }
      printf("Iteracion #%03d ", iteracion++);
      imprimir_arreglo(arreglo);
    }
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: Hello Squirrel

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello Squirrel");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: Hello Squirrel

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello Squirrel");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Hello Squirrel

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello Squirrel");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: Hello Squirrel

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello Squirrel");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bstrhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L75
L67:
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  cltq
  movl   $0x0,-0x20(%rbp,%rax,4)
L75:
  mov    -0x2c(%rbp),%eax
  cmp    $0x3,%eax
  jbe    L67
  movl   $0x0,-0x2c(%rbp)
  jmp    L27
L46:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  xor    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  and    $0x3,%eax
  mov    %eax,-0x2c(%rbp)
L27:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L46
  movl   $0x0,-0x2c(%rbp)
  jmp    L13
L22:
  mov    -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  or     %edx,%eax
  mov    %eax,-0x28(%rbp)
  addl   $0x1,-0x2c(%rbp)
L13:
  mov    -0x2c(%rbp),%eax
  cmp    $0x3,%eax
  jbe    L22
  cmpl   $0x0,-0x28(%rbp)
  jns    L41
  mov    -0x28(%rbp),%edx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x28(%rbp)
L41:
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

assistant: ```c
int bstrhash(char *key) {
  int c;
  int i;
  int r = 0;
  int b[sizeof(int)];
  for (i = 0; i < sizeof(int); b[i++] = 0)
    ;
  i = 0;
  while ((c = *key++) != '\0') {
    b[i] ^= c;
    i = (i + 1) % sizeof(int);
  }
  for (i = 0; i < sizeof(int); i++) {
    r = (r << 8) | b[i];
  }
  if (r < 0)
    r -= INT_MIN;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bstrhash>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x1(%rdi),%rcx
  movsbl (%rdi),%edx
  test   %edx,%edx
  je     L53
L57:
  movslq %eax,%rsi
  xor    %edx,(%rsp,%rsi,4)
  add    $0x1,%eax
  and    $0x3,%eax
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%edx
  test   %edx,%edx
  jne    L57
L53:
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rcx
  mov    $0x0,%eax
L47:
  shl    $0x8,%eax
  or     (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L47
  test   %eax,%eax
  js     L4
L56:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x28,%rsp
  ret
L4:
  mov    D3(%rip),%rdx
  sub    (%rdx),%eax
  jmp    L56
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bstrhash(char *key) {
  int c;
  int i;
  int r = 0;
  int b[sizeof(int)];
  for (i = 0; i < sizeof(int); b[i++] = 0)
    ;
  i = 0;
  while ((c = *key++) != '\0') {
    b[i] ^= c;
    i = (i + 1) % sizeof(int);
  }
  for (i = 0; i < sizeof(int); i++) {
    r = (r << 8) | b[i];
  }
  if (r < 0)
    r -= INT_MIN;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bstrhash>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl (%rdi),%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  test   %eax,%eax
  je     L48
  lea    0x1(%rdi),%rcx
  xor    %edx,%edx
  xor    %edi,%edi
  xor    %esi,%esi
  jmp    L17
  nopl   0x0(%rax)
L32:
  movslq %edx,%rsi
  mov    (%rsp,%rsi,4),%edi
L17:
  xor    %edi,%eax
  add    $0x1,%rcx
  add    $0x1,%edx
  mov    %eax,(%rsp,%rsi,4)
  movsbl -0x1(%rcx),%eax
  and    $0x3,%edx
  test   %eax,%eax
  jne    L32
  mov    (%rsp),%eax
  shl    $0x8,%eax
  or     0x4(%rsp),%eax
  shl    $0x8,%eax
  or     0x8(%rsp),%eax
  shl    $0x8,%eax
  or     0xc(%rsp),%eax
  js     L3
L49:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L3:
  mov    D5(%rip),%rdx
  sub    (%rdx),%eax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L48:
  mov    0x4(%rsp),%eax
  shl    $0x8,%eax
  or     0x8(%rsp),%eax
  shl    $0x8,%eax
  or     0xc(%rsp),%eax
  jmp    L49
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bstrhash(char *key) {
  int c;
  int i;
  int r = 0;
  int b[sizeof(int)];
  for (i = 0; i < sizeof(int); b[i++] = 0)
    ;
  i = 0;
  while ((c = *key++) != '\0') {
    b[i] ^= c;
    i = (i + 1) % sizeof(int);
  }
  for (i = 0; i < sizeof(int); i++) {
    r = (r << 8) | b[i];
  }
  if (r < 0)
    r -= INT_MIN;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bstrhash>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl (%rdi),%eax
  movaps %xmm0,(%rsp)
  test   %eax,%eax
  je     L10
  movsbl 0x1(%rdi),%edx
  mov    %eax,(%rsp)
  lea    0x2(%rdi),%rcx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L10
  nopl   0x0(%rax,%rax,1)
L22:
  movslq %eax,%rsi
  add    $0x1,%rcx
  add    $0x1,%eax
  xor    %edx,(%rsp,%rsi,4)
  movsbl -0x1(%rcx),%edx
  and    $0x3,%eax
  test   %edx,%edx
  jne    L22
L10:
  mov    (%rsp),%eax
  shl    $0x8,%eax
  or     0x4(%rsp),%eax
  shl    $0x8,%eax
  or     0x8(%rsp),%eax
  shl    $0x8,%eax
  or     0xc(%rsp),%eax
  jns    L15
  mov    D7(%rip),%rdx
  sub    (%rdx),%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bstrhash(char *key) {
  int c;
  int i;
  int r = 0;
  int b[sizeof(int)];
  for (i = 0; i < sizeof(int); b[i++] = 0)
    ;
  i = 0;
  while ((c = *key++) != '\0') {
    b[i] ^= c;
    i = (i + 1) % sizeof(int);
  }
  for (i = 0; i < sizeof(int); i++) {
    r = (r << 8) | b[i];
  }
  if (r < 0)
    r -= INT_MIN;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dijkstra>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%eax
L54:
  movl   $0x0,0x40(%rsp,%rax,1)
  mov    %edx,0x10(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x30,%rax
  jne    L54
  movslq %r12d,%rax
  movl   $0x1,0x40(%rsp,%rax,4)
  movl   $0x0,0x10(%rsp,%rax,4)
  cmp    %r13d,%r12d
  je     L41
  mov    D6(%rip),%r15
  lea    0x40(%rsp),%rdi
  jmp    L89
L104:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    $0xc,%rax
  je     L76
L74:
  mov    %eax,%ecx
  cmpl   $0x0,(%rdi,%rax,4)
  jne    L104
  mov    %r10d,%esi
  add    (%r8,%rax,4),%esi
  mov    %rdx,%r11
  cmp    %esi,(%rdx)
  jle    L25
  mov    %esi,(%rdx)
  mov    %r12d,(%r14,%rax,4)
L25:
  mov    (%r11),%esi
  cmp    %r9d,%esi
  jge    L104
  mov    %esi,%r9d
  mov    %ecx,%ebx
  jmp    L104
L76:
  movslq %ebx,%rax
  movl   $0x1,0x40(%rsp,%rax,4)
  cmp    %r13d,%ebx
  je     L41
  mov    %ebx,%r12d
L89:
  mov    (%r15),%r9d
  movslq %r12d,%rax
  mov    0x10(%rsp,%rax,4),%r10d
  lea    (%rax,%rax,2),%r8
  shl    $0x4,%r8
  add    %rbp,%r8
  lea    0x10(%rsp),%rdx
  mov    $0x0,%eax
  jmp    L74
L41:
  movslq %r13d,%r13
  mov    0x10(%rsp,%r13,4),%eax
  mov    0x8(%rsp),%rbx
  mov    %eax,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dijkstra(int weight[12][12], int start, int stop, int *dist, int precede[]) {
  int distance[12], visited[12];
  int current, currentIndex, distanceCount;
  int smalldist, newdist;
  for (int i = 0; i < 12; i++) {
    visited[i] = false;
    distance[i] = INT_MAX;
  }
  visited[start] = true;
  distance[start] = 0;
  current = start;
  while (current != stop) {
    smalldist = INT_MAX;
    distanceCount = distance[current];
    for (int i = 0; i < 12; i++) {
      if (visited[i] == false) {
        newdist = distanceCount + weight[current][i];
        if (newdist < distance[i]) {
          distance[i] = newdist;
          precede[i] = current;
        }
        if (distance[i] < smalldist) {
          smalldist = distance[i];
          currentIndex = i;
        }
      }
    }
    current = currentIndex;
    visited[current] = true;
  }
  *dist = distance[stop];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dijkstra>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %r8,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    D1(%rip),%r15
  mov    %rcx,0x8(%rsp)
  lea    0x10(%rsp),%r11
  lea    0x40(%rsp),%rdi
  mov    (%r15),%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x40(%rsp)
  mov    %r11,%rax
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
L49:
  mov    %r9d,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L49
  movslq %r12d,%rax
  movl   $0x1,0x40(%rsp,%rax,4)
  movl   $0x0,0x10(%rsp,%rax,4)
  cmp    %r13d,%r12d
  je     L67
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L18:
  lea    (%rax,%rax,2),%r10
  xor    %eax,%eax
  shl    $0x4,%r10
  add    %rbp,%r10
  nopl   (%rax)
L23:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%esi
  test   %edx,%edx
  jne    L75
  mov    (%r10,%rax,4),%ecx
  mov    (%r11,%rax,4),%edx
  add    %r8d,%ecx
  cmp    %ecx,%edx
  jle    L62
  mov    %ecx,(%r11,%rax,4)
  mov    %ecx,%edx
  mov    %r12d,(%r14,%rax,4)
L62:
  cmp    %r9d,%edx
  jge    L75
  mov    %edx,%r9d
  mov    %esi,%ebx
L75:
  add    $0x1,%rax
  cmp    $0xc,%rax
  jne    L23
  movslq %ebx,%rax
  movl   $0x1,0x40(%rsp,%rax,4)
  cmp    %r13d,%ebx
  je     L67
  mov    (%r15),%r9d
  mov    0x10(%rsp,%rax,4),%r8d
  mov    %ebx,%r12d
  jmp    L18
L67:
  mov    0x10(%rsp,%r13,4),%eax
  mov    0x8(%rsp),%rbx
  mov    %eax,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dijkstra(int weight[12][12], int start, int stop, int *dist, int precede[]) {
  int distance[12], visited[12];
  int current, currentIndex, distanceCount;
  int smalldist, newdist;
  for (int i = 0; i < 12; i++) {
    visited[i] = false;
    distance[i] = INT_MAX;
  }
  visited[start] = true;
  distance[start] = 0;
  current = start;
  while (current != stop) {
    smalldist = INT_MAX;
    distanceCount = distance[current];
    for (int i = 0; i < 12; i++) {
      if (visited[i] == false) {
        newdist = distanceCount + weight[current][i];
        if (newdist < distance[i]) {
          distance[i] = newdist;
          precede[i] = current;
        }
        if (distance[i] < smalldist) {
          smalldist = distance[i];
          currentIndex = i;
        }
      }
    }
    current = currentIndex;
    visited[current] = true;
  }
  *dist = distance[stop];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dijkstra>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    D2(%rip),%r15
  mov    %rcx,0x8(%rsp)
  mov    (%r15),%r11d
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movd   %r11d,%xmm1
  movaps %xmm0,0x40(%rsp)
  movslq %esi,%rax
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  pshufd $0x0,%xmm1,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movl   $0x1,0x40(%rsp,%rax,4)
  movl   $0x0,0x10(%rsp,%rax,4)
  cmp    %r13d,%esi
  je     L64
  mov    %r8,%r14
  mov    %rdi,%rbp
  mov    %esi,%r12d
  xor    %r8d,%r8d
  lea    0x40(%rsp),%r9
  nopl   0x0(%rax)
L36:
  lea    (%rax,%rax,2),%r10
  xor    %eax,%eax
  shl    $0x4,%r10
  add    %rbp,%r10
  nopl   (%rax)
L29:
  mov    (%r9,%rax,4),%edx
  mov    %eax,%esi
  test   %edx,%edx
  jne    L51
  mov    (%r10,%rax,4),%ecx
  lea    0x10(%rsp),%rdi
  mov    (%rdi,%rax,4),%edx
  add    %r8d,%ecx
  cmp    %ecx,%edx
  jle    L8
  mov    %ecx,(%rdi,%rax,4)
  mov    %ecx,%edx
  mov    %r12d,(%r14,%rax,4)
L8:
  cmp    %r11d,%edx
  jge    L51
  mov    %edx,%r11d
  mov    %esi,%ebx
L51:
  add    $0x1,%rax
  cmp    $0xc,%rax
  jne    L29
  movslq %ebx,%rax
  movl   $0x1,0x40(%rsp,%rax,4)
  cmp    %r13d,%ebx
  je     L64
  mov    (%r15),%r11d
  mov    0x10(%rsp,%rax,4),%r8d
  mov    %ebx,%r12d
  jmp    L36
L64:
  mov    0x10(%rsp,%r13,4),%eax
  mov    0x8(%rsp),%rbx
  mov    %eax,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dijkstra(int weight[12][12], int start, int stop, int *dist, int precede[]) {
  int distance[12], visited[12];
  int current, currentIndex, distanceCount;
  int smalldist, newdist;
  for (int i = 0; i < 12; i++) {
    visited[i] = false;
    distance[i] = INT_MAX;
  }
  visited[start] = true;
  distance[start] = 0;
  current = start;
  while (current != stop) {
    smalldist = INT_MAX;
    distanceCount = distance[current];
    for (int i = 0; i < 12; i++) {
      if (visited[i] == false) {
        newdist = distanceCount + weight[current][i];
        if (newdist < distance[i]) {
          distance[i] = newdist;
          precede[i] = current;
        }
        if (distance[i] < smalldist) {
          smalldist = distance[i];
          currentIndex = i;
        }
      }
    }
    current = currentIndex;
    visited[current] = true;
  }
  *dist = distance[stop];
}
```