ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jle    L4
  nopl   0x0(%rax)
L6:
  lea    -0x1(%rax),%edx
  test   %eax,%eax
  lea    0x1(%rax),%ecx
  mov    %edx,%eax
  cmovns %ecx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jg     L6
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = __VERIFIER_nondet_int();
  while (i * i > 9) {
    if (i < 0) {
      i = i - 1;
    } else {
      i = i + 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jle    L4
  nopl   0x0(%rax)
L17:
  lea    -0x1(%rax),%edx
  test   %eax,%eax
  lea    0x1(%rax),%ecx
  mov    %edx,%eax
  cmovns %ecx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jg     L17
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = __VERIFIER_nondet_int();
  while (i * i > 9) {
    if (i < 0) {
      i = i - 1;
    } else {
      i = i + 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tst_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L54
  cmpl   $0x2,-0x4(%rbp)
  jg     L65
  cmpl   $0x0,-0x4(%rbp)
  je     L30
  cmpl   $0x1,-0x4(%rbp)
  je     L55
  jmp    L65
L30:
  lea    D32(%rip),%rax
  jmp    L52
L55:
  lea    D39(%rip),%rax
  jmp    L52
L54:
  lea    D17(%rip),%rax
  jmp    L52
L65:
  lea    D27(%rip),%rax
L52:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
datatype: string
name: extract_symbolic_data
arguments: tag: D39
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: string

tool: D32: Unsynchronized

tool: D39: Synchronized

tool: D17: Physical clock stopped

tool: D27: unknown

assistant: ```c
const char *tst_to_str(int mode) {
  switch (mode) {
  case 0:
    return "Unsynchronized";
  case 1:
    return "Synchronized";
  case 2:
    return "Physical clock stopped";
  default:
    return "unknown";
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tst_to_str>:
  endbr64
  lea    D17(%rip),%rax
  cmp    $0x1,%edi
  je     L14
  lea    D3(%rip),%rax
  cmp    $0x2,%edi
  je     L14
  test   %edi,%edi
  lea    D0(%rip),%rax
  lea    D14(%rip),%rdx
  cmove  %rdx,%rax
L14:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D17: Synchronized

tool: D3: Physical clock stopped

tool: D0: unknown

tool: D14: Unsynchronized

assistant: ```c
const char *tst_to_str(int mode) {
  switch (mode) {
  case 0:
    return "Unsynchronized";
  case 1:
    return "Synchronized";
  case 2:
    return "Physical clock stopped";
  default:
    return "unknown";
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tst_to_str>:
  endbr64
  lea    D21(%rip),%rax
  cmp    $0x1,%edi
  je     L14
  lea    D23(%rip),%rax
  cmp    $0x2,%edi
  je     L14
  test   %edi,%edi
  lea    D2(%rip),%rax
  lea    D12(%rip),%rdx
  cmove  %rdx,%rax
L14:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string

tool: D21: Synchronized

tool: D23: Physical clock stopped

tool: D2: unknown

tool: D12: Unsynchronized

assistant: ```c
const char *tst_to_str(int mode) {
  switch (mode) {
  case 0:
    return "Unsynchronized";
  case 1:
    return "Synchronized";
  case 2:
    return "Physical clock stopped";
  default:
    return "unknown";
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tst_to_str>:
  endbr64
  lea    D30(%rip),%rax
  cmp    $0x1,%edi
  je     L11
  lea    D34(%rip),%rax
  cmp    $0x2,%edi
  je     L11
  test   %edi,%edi
  lea    D18(%rip),%rax
  lea    D25(%rip),%rdx
  cmove  %rdx,%rax
L11:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string
name: retrieve_data
arguments: data_tag: D25
data_type: string

tool: D30: Synchronized

tool: D34: Physical clock stopped

tool: D18: unknown

tool: D25: Unsynchronized

assistant: ```c
const char *tst_to_str(int mode) {
  switch (mode) {
  case 0:
    return "Unsynchronized";
  case 1:
    return "Synchronized";
  case 2:
    return "Physical clock stopped";
  default:
    return "unknown";
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<geralinha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0xb,%eax
  mov    %eax,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L19:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D29
type: string

tool: D4:           =

tool: D3: =

tool: D29: =


assistant: ```c
void geralinha(char s[]) {
  int larg = strlen(s) + 11;
  int i;
  printf("          =");
  for (i = 0; i < larg; i++)
    printf("=");
  printf("=\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<geralinha>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  cmp    $0xfffffff6,%ebp
  jl     L4
  add    $0xb,%ebp
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
L9:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L9
L4:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string

tool: D1:           =

tool: D3: =

tool: D21: =


assistant: ```c
void geralinha(char s[]) {
  int larg = strlen(s) + 11;
  int i;
  printf("          =");
  for (i = 0; i < larg; i++)
    printf("=");
  printf("=\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<geralinha>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    D26(%rip),%rdi
  lea    0xb(%rax),%ebp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  xor    %ebx,%ebx
  lea    D14(%rip),%r12
  nopl   0x0(%rax)
L13:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L13
L15:
  pop    %rbx
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D26
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D26:           =

tool: D14: =

tool: D5: =


assistant: ```c
void geralinha(char s[]) {
  int larg = strlen(s) + 11;
  int i;
  printf("          =");
  for (i = 0; i < larg; i++)
    printf("=");
  printf("=\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<geralinha>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    D17(%rip),%rdi
  lea    0xb(%rax),%ebp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L2
  xor    %ebx,%ebx
  lea    D0(%rip),%r12
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L12
L2:
  pop    %rbx
  lea    D24(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D24
type_guessed: string

tool: D17:           =

tool: D0: =

tool: D24: =


assistant: ```c
void geralinha(char s[]) {
  int larg = strlen(s) + 11;
  int i;
  printf("          =");
  for (i = 0; i < larg; i++)
    printf("=");
  printf("=\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_ull@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writen@plt>
  nop
  leave
  ret
```

assistant: ```c
void send_str(int chan, const char *s) {
  size_t len = strlen(s) + 1;
  send_ull(chan, len);
  writen(chan, s, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send_ull@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <writen@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void send_str(int chan, const char *s) {
  size_t len = strlen(s) + 1;
  send_ull(chan, len);
  writen(chan, s, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<send_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rsi
  call   <send_ull@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <writen@plt>
```

assistant: ```c
void send_str(int chan, const char *s) {
  size_t len = strlen(s) + 1;
  send_ull(chan, len);
  writen(chan, s, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rsi
  call   <send_ull@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <writen@plt>
```

assistant: ```c
void send_str(int chan, const char *s) {
  size_t len = strlen(s) + 1;
  send_ull(chan, len);
  writen(chan, s, len);
}
```
user: What is the c source code of the assembly code below:

```asm
<word_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L18
L43:
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L43
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L43
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L43
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L35
L17:
  addq   $0x1,-0x10(%rbp)
L35:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L77
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L77
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L17
L77:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void word_to_string(const char *const word, char **str) {
  uint32_t i = 0;
  while (word[i] == ' ' || word[i] == '\r' || word[i] == '\n' || word[i] == '\0')
    ++i;
  uint32_t start = i;
  while (word[i] != ' ' && word[i] != '\r' && word[i] != '\n')
    ++i;
  *str = (char *)malloc(i - start + 1);
  (*str)[i - start] = '\0';
  memcpy(*str, &word[start], i - start);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<word_to_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movzbl (%rdi),%ecx
  cmp    $0x20,%cl
  ja     L67
  movabs $0x100002401,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  je     L66
  mov    $0x0,%eax
  movabs $0x100002401,%rcx
  jmp    L36
L39:
  bt     %rdx,%rcx
  jae    L48
L36:
  add    $0x1,%rax
  lea    (%rdi,%rax,1),%rbp
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  jbe    L39
L48:
  mov    %rax,%rdx
  movabs $0x100002400,%rsi
L8:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  cmp    $0x20,%cl
  ja     L8
  bt     %rcx,%rsi
  jae    L8
  sub    %rax,%rdx
  mov    %rdx,%r12
  lea    0x1(%rdx),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movb   $0x0,(%rax,%r12,1)
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  mov    %rdi,%rbp
  mov    $0x0,%eax
  jmp    L48
L66:
  mov    %rdi,%rbp
  jmp    L48
```

assistant: ```c
void word_to_string(const char *const word, char **str) {
  uint32_t i = 0;
  while (word[i] == ' ' || word[i] == '\r' || word[i] == '\n' || word[i] == '\0')
    ++i;
  uint32_t start = i;
  while (word[i] != ' ' && word[i] != '\r' && word[i] != '\n')
    ++i;
  *str = (char *)malloc(i - start + 1);
  (*str)[i - start] = '\0';
  memcpy(*str, &word[start], i - start);
}
```
user: Translate the below assembly code into C programming language:

```asm
<word_to_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    %rsi,%rbx
  cmp    $0x20,%al
  ja     L46
  movabs $0xfffffffeffffdbfe,%rcx
  bt     %rax,%rcx
  jb     L46
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  lea    (%rdi,%rax,1),%rbp
  cmp    $0x20,%dl
  ja     L5
  bt     %rdx,%rcx
  jae    L12
  jmp    L5
  nopl   0x0(%rax)
L46:
  mov    %rdi,%rbp
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movabs $0xfffffffeffffdbff,%rsi
  mov    %rax,%rdx
  nopl   (%rax)
L65:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  cmp    $0x20,%cl
  ja     L65
  bt     %rcx,%rsi
  jb     L65
  sub    %rax,%rdx
  lea    0x1(%rdx),%rdi
  mov    %rdx,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x0,(%rax,%r12,1)
  mov    (%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void word_to_string(const char *const word, char **str) {
  uint32_t i = 0;
  while (word[i] == ' ' || word[i] == '\r' || word[i] == '\n' || word[i] == '\0')
    ++i;
  uint32_t start = i;
  while (word[i] != ' ' && word[i] != '\r' && word[i] != '\n')
    ++i;
  *str = (char *)malloc(i - start + 1);
  (*str)[i - start] = '\0';
  memcpy(*str, &word[start], i - start);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<word_to_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    %rsi,%rbx
  cmp    $0x20,%al
  ja     L3
  movabs $0xfffffffeffffdbfe,%rcx
  bt     %rax,%rcx
  jb     L3
  xor    %eax,%eax
  nopl   0x0(%rax)
L68:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  lea    (%rdi,%rax,1),%rbp
  cmp    $0x20,%dl
  ja     L8
  bt     %rdx,%rcx
  jae    L68
  jmp    L8
  nopl   0x0(%rax)
L3:
  mov    %rdi,%rbp
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movabs $0xfffffffeffffdbff,%rsi
  mov    %rax,%rdx
  nopl   (%rax)
L0:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  cmp    $0x20,%cl
  ja     L0
  bt     %rcx,%rsi
  jb     L0
  sub    %rax,%rdx
  lea    0x1(%rdx),%rdi
  mov    %rdx,%r12
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x0,(%rax,%r12,1)
  mov    (%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void word_to_string(const char *const word, char **str) {
  uint32_t i = 0;
  while (word[i] == ' ' || word[i] == '\r' || word[i] == '\n' || word[i] == '\0')
    ++i;
  uint32_t start = i;
  while (word[i] != ' ' && word[i] != '\r' && word[i] != '\n')
    ++i;
  *str = (char *)malloc(i - start + 1);
  (*str)[i - start] = '\0';
  memcpy(*str, &word[start], i - start);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getCacheApp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getCacheHome@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmcat@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmcat@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: /

assistant: ```c
void getCacheApp(char **path, char *app_name) {
  getCacheHome(path);
  if (*path) {
    strmcat(path, "/");
    strmcat(path, app_name);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<getCacheApp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <getCacheHome@plt>
  cmpq   $0x0,(%rbx)
  je     L4
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strmcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strmcat@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: /

assistant: ```c
void getCacheApp(char **path, char *app_name) {
  getCacheHome(path);
  if (*path) {
    strmcat(path, "/");
    strmcat(path, app_name);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getCacheApp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getCacheHome@plt>
  cmpq   $0x0,0x0(%rbp)
  je     L2
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <strmcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strmcat@plt>
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: /

assistant: ```c
void getCacheApp(char **path, char *app_name) {
  getCacheHome(path);
  if (*path) {
    strmcat(path, "/");
    strmcat(path, app_name);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getCacheApp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getCacheHome@plt>
  cmpq   $0x0,0x0(%rbp)
  je     L6
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <strmcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strmcat@plt>
  xchg   %ax,%ax
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: /

assistant: ```c
void getCacheApp(char **path, char *app_name) {
  getCacheHome(path);
  if (*path) {
    strmcat(path, "/");
    strmcat(path, app_name);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x63,-0x1a4(%rbp)
  ja     L11
  mov    -0x1a4(%rbp),%eax
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L11
  addl   $0x1,-0x1a8(%rbp)
L11:
  cmpl   $0x63,-0x1a8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__CPROVER_assume@plt>
  cmpl   $0x0,-0x1a8(%rbp)
  js     L16
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L16
  addl   $0x1,-0x1a8(%rbp)
L16:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int main() {
  unsigned x;
  int i;
  int a[100];
  if (x < 100 && a[x]) {
    i++;
  }
  __CPROVER_assume(i < 100);
  if (i >= 0 && a[i]) {
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x198(%rsp)
  xor    %edx,%edx
  cmpl   $0x0,(%rsp)
  mov    $0x1,%edx
  cmovne %edx,%eax
  cmp    $0x63,%eax
  setle  %dil
  movzbl %dil,%edi
  call   <__CPROVER_assume@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  unsigned x;
  int i;
  int a[100];
  if (x < 100 && a[x]) {
    i++;
  }
  __CPROVER_assume(i < 100);
  if (i >= 0 && a[i]) {
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L9
  mov    $0x1,%edx
L9:
  xor    %edi,%edi
  cmp    $0x63,%edx
  setle  %dil
  call   <__CPROVER_assume@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  unsigned x;
  int i;
  int a[100];
  if (x < 100 && a[x]) {
    i++;
  }
  __CPROVER_assume(i < 100);
  if (i >= 0 && a[i]) {
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L4
  mov    $0x1,%edx
L4:
  xor    %edi,%edi
  cmp    $0x63,%edx
  setle  %dil
  call   <__CPROVER_assume@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  unsigned x;
  int i;
  int a[100];
  if (x < 100 && a[x]) {
    i++;
  }
  __CPROVER_assume(i < 100);
  if (i >= 0 && a[i]) {
    i++;
  }
}
```