user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gethd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3d,(%rax)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x2,-0x2c(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L82
L42:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L103
L106:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x30(%rbp)
L103:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L56
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L106
L56:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L58
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L58:
  addq   $0x1,-0x28(%rbp)
L82:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7d,%al
  jne    L42
  cmpq   $0x0,-0x20(%rbp)
  jne    L7
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L52
L7:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L47
L100:
  addq   $0x1,-0x28(%rbp)
L47:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L100
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L60
L79:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L60:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L115
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L79
L115:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L52:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void gethd(char *field, char *value, char *header) {
  char *hp, *lhp, *fp, *vp;
  int l, j;
  char *newfield;
  l = strlen(field);
  newfield = (char *)malloc(l + 3);
  *newfield = 10;
  strncpy(newfield + 1, field, l);
  *(newfield + l + 1) = '=';
  *(newfield + l + 2) = (char)0;
  l += 2;
  lhp = 0;
  for (hp = header; *hp != '}'; hp++) {
    for (fp = newfield, j = 0; j < l && *(hp + j) == *fp; fp++, j++)
      ;
    if (j == l)
      lhp = hp;
  }
  if (lhp == 0)
    value[0] = 0;
  else {
    for (hp = lhp; *hp != '='; hp++)
      ;
    for (lhp = hp + 1, vp = value; *lhp != ';' && *lhp != 0; lhp++, vp++)
      *vp = *lhp;
    *(vp++) = 0;
  }
  free(newfield);
}
```