ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rgb565_to_rgb888>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %rcx,%rcx
  je     L1
  test   %esi,%esi
  jle    L1
  test   %edx,%edx
  jle    L1
  imul   %edx,%esi
  mov    %rdi,%rax
  movslq %esi,%rsi
  lea    (%rdi,%rsi,2),%rsi
  cmp    %rsi,%rdi
  jae    L31
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rax),%edi
  add    $0x3,%rcx
  add    $0x2,%rax
  lea    0x0(,%rdi,8),%edx
  mov    %dl,-0x3(%rcx)
  movzwl -0x2(%rax),%edx
  shr    $0x5,%dx
  shl    $0x2,%edx
  mov    %dl,-0x2(%rcx)
  movzwl -0x2(%rax),%edx
  shr    $0xb,%dx
  shl    $0x3,%edx
  mov    %dl,-0x1(%rcx)
  cmp    %rax,%rsi
  ja     L17
L31:
  xor    %eax,%eax
  ret
L1:
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: rgb888_to_rgb565 : parameter error


assistant: ```c
int rgb565_to_rgb888(const void *p565, int w, int h, void *p888) {
  unsigned char *p888end = NULL;
  unsigned char *p888line = NULL;
  const unsigned short *p565end = NULL;
  const unsigned short *p565line = NULL;
  if (p565 && p888 && w > 0 && h > 0) {
    p565line = (unsigned short *)p565;
    p565end = (unsigned short *)p565 + w * h;
    p888line = (unsigned char *)p888;
    while (p565line < p565end) {
      *p888line++ = (unsigned char)(((*p565line) >> 0) << 3);
      *p888line++ = (unsigned char)(((*p565line) >> 5) << 2);
      *p888line++ = (unsigned char)(((*p565line) >> 11) << 3);
      p565line++;
    }
    return 0;
  } else {
    printf("rgb888_to_rgb565 : parameter error\n");
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_at_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,-0x12c(%rbp)
  mov    %edx,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x120(%rbp)
  jmp    L17
L39:
  mov    -0x120(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x128(%rbp)
  mov    -0x128(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x120(%rbp)
L17:
  cmpq   $0x0,-0x120(%rbp)
  jne    L39
  mov    -0x12c(%rbp),%ecx
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  je     L12
  mov    -0x118(%rbp),%rdx
  lea    -0x130(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: string

tool: D4: /tmp/%s%d.pid

tool: D14: w

assistant: ```c
void write_at_log(char *name, int i, pid_t cpid) {
  char folder[255];
  char *tmp = strchr(name, '/');
  while (tmp != NULL) {
    name = tmp + 1;
    tmp = strchr(name, '/');
  }
  sprintf(folder, "/tmp/%s%d.pid", name, i);
  FILE *fp = fopen(folder, "w");
  if (fp != NULL) {
    fwrite(&cpid, sizeof(pid_t), 1, fp);
    fclose(fp);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_at_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L13
L19:
  lea    0x1(%rax),%rbx
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L19
L13:
  lea    0x10(%rsp),%r12
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  lea    D13(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  lea    0xc(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L3:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D13: /tmp/%s%d.pid

tool: D8: w

assistant: ```c
void write_at_log(char *name, int i, pid_t cpid) {
  char folder[255];
  char *tmp = strchr(name, '/');
  while (tmp != NULL) {
    name = tmp + 1;
    tmp = strchr(name, '/');
  }
  sprintf(folder, "/tmp/%s%d.pid", name, i);
  FILE *fp = fopen(folder, "w");
  if (fp != NULL) {
    fwrite(&cpid, sizeof(pid_t), 1, fp);
    fclose(fp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_at_log>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x2f,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L32
  nopl   0x0(%rax)
L10:
  lea    0x1(%rax),%r12
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
L32:
  lea    0x10(%rsp),%rbp
  mov    %r12,%rdx
  mov    %r13d,%ecx
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  lea    0xc(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
L15:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string

tool: D12: /tmp/%s%d.pid

tool: D13: w

assistant: ```c
void write_at_log(char *name, int i, pid_t cpid) {
  char folder[255];
  char *tmp = strchr(name, '/');
  while (tmp != NULL) {
    name = tmp + 1;
    tmp = strchr(name, '/');
  }
  sprintf(folder, "/tmp/%s%d.pid", name, i);
  FILE *fp = fopen(folder, "w");
  if (fp != NULL) {
    fwrite(&cpid, sizeof(pid_t), 1, fp);
    fclose(fp);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_at_log>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x2f,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  nopl   0x0(%rax)
L22:
  lea    0x1(%rax),%r12
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L22
L12:
  lea    0x10(%rsp),%rbp
  mov    %r12,%rdx
  mov    %r13d,%ecx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L21
  lea    0xc(%rsp),%rdi
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
L21:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string

tool: D15: /tmp/%s%d.pid

tool: D3: w

assistant: ```c
void write_at_log(char *name, int i, pid_t cpid) {
  char folder[255];
  char *tmp = strchr(name, '/');
  while (tmp != NULL) {
    name = tmp + 1;
    tmp = strchr(name, '/');
  }
  sprintf(folder, "/tmp/%s%d.pid", name, i);
  FILE *fp = fopen(folder, "w");
  if (fp != NULL) {
    fwrite(&cpid, sizeof(pid_t), 1, fp);
    fclose(fp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PruneAmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  nop
  leave
  ret
```

assistant: ```c
void PruneAmp(char *sPost) {
  if (sPost[strlen(sPost) - 1] == '&') {
    sPost[strlen(sPost) - 1] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PruneAmp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x26,-0x1(%rbx,%rax,1)
  je     L7
L10:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L10
```

assistant: ```c
void PruneAmp(char *sPost) {
  if (sPost[strlen(sPost) - 1] == '&') {
    sPost[strlen(sPost) - 1] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PruneAmp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x26,-0x1(%rbx,%rax,1)
  je     L8
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void PruneAmp(char *sPost) {
  if (sPost[strlen(sPost) - 1] == '&') {
    sPost[strlen(sPost) - 1] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PruneAmp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x26,-0x1(%rbx,%rax,1)
  je     L1
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void PruneAmp(char *sPost) {
  if (sPost[strlen(sPost) - 1] == '&') {
    sPost[strlen(sPost) - 1] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L11:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    -0x1c(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jb     L11
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hash_t(char *s, int t) {
  unsigned int i, j = 0;
  for (i = 0; i < strlen(s); i++)
    j = (j * 256 + s[i]) % t;
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_t>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L12
L4:
  mov    %ebx,%eax
  movsbl 0x0(%rbp,%rax,1),%eax
  shl    $0x8,%r13d
  add    %r13d,%eax
  mov    $0x0,%edx
  div    %r12d
  mov    %edx,%r13d
  add    $0x1,%ebx
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L4
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hash_t(char *s, int t) {
  unsigned int i, j = 0;
  for (i = 0; i < strlen(s); i++)
    j = (j * 256 + s[i]) % t;
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_t>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%eax
  shl    $0x8,%r12d
  xor    %edx,%edx
  add    $0x1,%ebx
  movsbl 0x0(%r13,%rax,1),%eax
  add    %r12d,%eax
  div    %ebp
  mov    %edx,%r12d
L2:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L13
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hash_t(char *s, int t) {
  unsigned int i, j = 0;
  for (i = 0; i < strlen(s); i++)
    j = (j * 256 + s[i]) % t;
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_t>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%eax
  shl    $0x8,%r12d
  xor    %edx,%edx
  add    $0x1,%ebx
  movsbl 0x0(%r13,%rax,1),%eax
  add    %r12d,%eax
  div    %ebp
  mov    %edx,%r12d
L6:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L13
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hash_t(char *s, int t) {
  unsigned int i, j = 0;
  for (i = 0; i < strlen(s); i++)
    j = (j * 256 + s[i]) % t;
  return j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LowestBitSet32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L1
L10:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <CountBits32@plt>
  sub    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int LowestBitSet32(uint32_t val) {
  if (val == 0)
    return -1;
  return CountBits32(val ^ val - 1) - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LowestBitSet32>:
  endbr64
  test   %edi,%edi
  je     L0
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%eax
  xor    %eax,%edi
  call   <CountBits32@plt>
  sub    $0x1,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet32(uint32_t val) {
  if (val == 0)
    return -1;
  return CountBits32(val ^ val - 1) - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LowestBitSet32>:
  endbr64
  test   %edi,%edi
  je     L3
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  xor    %eax,%edi
  call   <CountBits32@plt>
  add    $0x8,%rsp
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet32(uint32_t val) {
  if (val == 0)
    return -1;
  return CountBits32(val ^ val - 1) - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LowestBitSet32>:
  endbr64
  test   %edi,%edi
  je     L7
  lea    -0x1(%rdi),%eax
  sub    $0x8,%rsp
  xor    %eax,%edi
  call   <CountBits32@plt>
  add    $0x8,%rsp
  sub    $0x1,%eax
  ret
  xchg   %ax,%ax
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int LowestBitSet32(uint32_t val) {
  if (val == 0)
    return -1;
  return CountBits32(val ^ val - 1) - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xb,-0xc(%rbp)
  movl   $0x3b,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: Total minute: %d


assistant: ```c
int main(void) {
  int hour, minute;
  int total_minute;
  hour = 11, minute = 59;
  total_minute = hour * 60 + minute;
  printf("Total minute: %d\n", total_minute);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2cf,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: Total minute: %d


assistant: ```c
int main(void) {
  int hour, minute;
  int total_minute;
  hour = 11, minute = 59;
  total_minute = hour * 60 + minute;
  printf("Total minute: %d\n", total_minute);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2cf,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: Total minute: %d


assistant: ```c
int main(void) {
  int hour, minute;
  int total_minute;
  hour = 11, minute = 59;
  total_minute = hour * 60 + minute;
  printf("Total minute: %d\n", total_minute);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2cf,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: Total minute: %d


assistant: ```c
int main(void) {
  int hour, minute;
  int total_minute;
  hour = 11, minute = 59;
  total_minute = hour * 60 + minute;
  printf("Total minute: %d\n", total_minute);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<marklocationdegree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%r8d
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0xc(%rbp),%rdi
  push   %rdi
  lea    -0x10(%rbp),%rdi
  push   %rdi
  mov    0x18(%rbp),%edi
  push   %rdi
  mov    0x10(%rbp),%r9d
  mov    %rax,%rdi
  call   <hgtmapcoord@plt>
  add    $0x20,%rsp
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0xff,%ecx
  mov    %rax,%rdi
  call   <drawdot@plt>
  mov    -0xc(%rbp),%eax
  lea    0x5(%rax),%edi
  mov    -0x10(%rbp),%esi
  mov    0x28(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  push   $0x64
  push   $0x64
  mov    $0x64,%r9d
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <drawctext@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void marklocationdegree(struct raster *ra, struct hgt *hgt, int ng, int nf, int ns, int eg, int ef, int es, char *name, int size) {
  int x, y;
  hgtmapcoord(hgt, ng, nf, ns, eg, ef, es, &x, &y);
  drawdot(ra, x, y, 255, 0, 0);
  drawctext(ra, x, y + 5, name, size, 100, 100, 100);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<marklocationdegree>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  mov    0x48(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  push   %rax
  lea    0x10(%rsp),%rax
  push   %rax
  mov    0x50(%rsp),%eax
  push   %rax
  mov    0x50(%rsp),%r9d
  call   <hgtmapcoord@plt>
  add    $0x20,%rsp
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0xff,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <drawdot@plt>
  mov    0x4(%rsp),%eax
  lea    0x5(%rax),%edx
  push   $0x64
  push   $0x64
  mov    $0x64,%r9d
  mov    0x58(%rsp),%r8d
  mov    %rbp,%rcx
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  call   <drawctext@plt>
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void marklocationdegree(struct raster *ra, struct hgt *hgt, int ng, int nf, int ns, int eg, int ef, int es, char *name, int size) {
  int x, y;
  hgtmapcoord(hgt, ng, nf, ns, eg, ef, es, &x, &y);
  drawdot(ra, x, y, 255, 0, 0);
  drawctext(ra, x, y + 5, name, size, 100, 100, 100);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<marklocationdegree>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    0x48(%rsp),%r12
  push   %rax
  lea    0x10(%rsp),%rax
  push   %rax
  mov    0x50(%rsp),%eax
  push   %rax
  mov    0x50(%rsp),%r9d
  call   <hgtmapcoord@plt>
  mov    0x24(%rsp),%edx
  mov    0x20(%rsp),%esi
  xor    %r9d,%r9d
  add    $0x20,%rsp
  xor    %r8d,%r8d
  mov    $0xff,%ecx
  mov    %rbp,%rdi
  call   <drawdot@plt>
  mov    0x4(%rsp),%eax
  push   $0x64
  mov    %r12,%rcx
  push   $0x64
  mov    0x58(%rsp),%r8d
  mov    $0x64,%r9d
  mov    %rbp,%rdi
  mov    0x10(%rsp),%esi
  lea    0x5(%rax),%edx
  call   <drawctext@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void marklocationdegree(struct raster *ra, struct hgt *hgt, int ng, int nf, int ns, int eg, int ef, int es, char *name, int size) {
  int x, y;
  hgtmapcoord(hgt, ng, nf, ns, eg, ef, es, &x, &y);
  drawdot(ra, x, y, 255, 0, 0);
  drawctext(ra, x, y + 5, name, size, 100, 100, 100);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<marklocationdegree>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  mov    0x48(%rsp),%r12
  push   %rax
  lea    0x10(%rsp),%rax
  push   %rax
  mov    0x50(%rsp),%eax
  push   %rax
  mov    0x50(%rsp),%r9d
  call   <hgtmapcoord@plt>
  mov    0x24(%rsp),%edx
  mov    0x20(%rsp),%esi
  xor    %r9d,%r9d
  add    $0x20,%rsp
  xor    %r8d,%r8d
  mov    $0xff,%ecx
  mov    %rbp,%rdi
  call   <drawdot@plt>
  mov    0x4(%rsp),%eax
  push   $0x64
  mov    %r12,%rcx
  push   $0x64
  mov    0x58(%rsp),%r8d
  mov    $0x64,%r9d
  mov    %rbp,%rdi
  mov    0x10(%rsp),%esi
  lea    0x5(%rax),%edx
  call   <drawctext@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void marklocationdegree(struct raster *ra, struct hgt *hgt, int ng, int nf, int ns, int eg, int ef, int es, char *name, int size) {
  int x, y;
  hgtmapcoord(hgt, ng, nf, ns, eg, ef, es, &x, &y);
  drawdot(ra, x, y, 255, 0, 0);
  drawctext(ra, x, y + 5, name, size, 100, 100, 100);
}
```