ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_substr_with_gap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L36
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  jmp    L90
L36:
  mov    -0x20(%rbp),%rax
L90:
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L98
L60:
  addq   $0x1,-0x18(%rbp)
L98:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L86
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
L86:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    -0x18(%rbp),%rax
  jmp    L75
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L116
  mov    $0x0,%eax
  jmp    L75
L116:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L23
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L116
L23:
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L116
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    -0x18(%rbp),%rax
  jmp    L75
L77:
  mov    $0x0,%eax
L75:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: Find subpattern |%7s| in |%15s|: 

assistant: ```c
char *find_substr_with_gap(char *s_ptr, char *sub_pattern) {
  char *sp_ptr = (sub_pattern[0] == '*') ? sub_pattern + 1 : sub_pattern;
  char *s_init = sp_ptr;
  printf("Find subpattern |%7s| in |%15s|: ", sub_pattern, s_ptr);
  while (*s_ptr != *sp_ptr && *s_ptr != '\0') {
    (s_ptr)++;
  }
  if (*s_ptr == '\0' && *sp_ptr == '\0') {
    return s_ptr;
  } else if (*s_ptr == '\0') {
    return NULL;
  } else {
    while (1) {
      if (*sp_ptr == '\0' || *s_ptr == '\0') {
        break;
      } else if (*s_ptr == *sp_ptr) {
        (s_ptr)++;
        sp_ptr++;
      } else {
        (s_ptr)++;
        sp_ptr = s_init;
        ;
      }
    }
    if (*sp_ptr == '\0') {
      return s_ptr;
    } else {
      return NULL;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_substr_with_gap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x2a,(%rsi)
  sete   %bpl
  movzbl %bpl,%ebp
  add    %rsi,%rbp
  mov    %rdi,%rdx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%esi
  test   %al,%al
  je     L68
  cmp    %sil,%al
  je     L68
L8:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L68
  cmp    %sil,%al
  jne    L8
L68:
  mov    %esi,%edi
  or     %al,%dil
  je     L103
  test   %al,%al
  je     L1
  test   %sil,%sil
  je     L78
  lea    0x1(%rbx),%rdx
  mov    %rbp,%r8
  mov    %esi,%edi
  jmp    L140
L43:
  mov    %esi,%edi
  mov    %rbp,%r8
L5:
  add    $0x1,%rdx
L140:
  lea    -0x1(%rdx),%r9
  mov    %rdx,%rax
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  je     L104
  cmp    %dil,%cl
  jne    L43
  lea    0x1(%r8),%rcx
  movzbl 0x1(%r8),%edi
  test   %dil,%dil
  je     L113
  mov    %rcx,%r8
  jmp    L5
L104:
  test   %dil,%dil
  mov    $0x0,%ebx
  mov    %rbx,%rax
  cmove  %r9,%rax
L113:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L103:
  mov    %rbx,%rax
  jmp    L113
L1:
  mov    $0x0,%eax
  jmp    L113
L78:
  mov    %rbx,%rax
  jmp    L113
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Find subpattern |%7s| in |%15s|: 

assistant: ```c
char *find_substr_with_gap(char *s_ptr, char *sub_pattern) {
  char *sp_ptr = (sub_pattern[0] == '*') ? sub_pattern + 1 : sub_pattern;
  char *s_init = sp_ptr;
  printf("Find subpattern |%7s| in |%15s|: ", sub_pattern, s_ptr);
  while (*s_ptr != *sp_ptr && *s_ptr != '\0') {
    (s_ptr)++;
  }
  if (*s_ptr == '\0' && *sp_ptr == '\0') {
    return s_ptr;
  } else if (*s_ptr == '\0') {
    return NULL;
  } else {
    while (1) {
      if (*sp_ptr == '\0' || *s_ptr == '\0') {
        break;
      } else if (*s_ptr == *sp_ptr) {
        (s_ptr)++;
        sp_ptr++;
      } else {
        (s_ptr)++;
        sp_ptr = s_init;
        ;
      }
    }
    if (*sp_ptr == '\0') {
      return s_ptr;
    } else {
      return NULL;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_substr_with_gap>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rdi,%rdx
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  cmpb   $0x2a,(%rsi)
  sete   %bpl
  add    %rsi,%rbp
  call   <printf@plt>
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%edx
  cmp    %al,%dl
  jne    L29
  jmp    L96
  nopl   (%rax)
L7:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    %dl,%al
  je     L96
L29:
  test   %al,%al
  jne    L7
  xor    %eax,%eax
  test   %dl,%dl
  cmove  %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  test   %dl,%dl
  je     L4
  mov    %rbp,%rsi
  mov    %edx,%ecx
L9:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L57
L27:
  add    $0x1,%rbx
  cmp    %cl,%al
  je     L75
  movzbl (%rbx),%eax
  mov    %edx,%ecx
  mov    %rbp,%rsi
  test   %al,%al
  jne    L27
L57:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L75:
  movzbl 0x1(%rsi),%ecx
  lea    0x1(%rsi),%rax
  test   %cl,%cl
  je     L4
  mov    %rax,%rsi
  jmp    L9
  nopl   0x0(%rax)
L4:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: Find subpattern |%7s| in |%15s|: 

assistant: ```c
char *find_substr_with_gap(char *s_ptr, char *sub_pattern) {
  char *sp_ptr = (sub_pattern[0] == '*') ? sub_pattern + 1 : sub_pattern;
  char *s_init = sp_ptr;
  printf("Find subpattern |%7s| in |%15s|: ", sub_pattern, s_ptr);
  while (*s_ptr != *sp_ptr && *s_ptr != '\0') {
    (s_ptr)++;
  }
  if (*s_ptr == '\0' && *sp_ptr == '\0') {
    return s_ptr;
  } else if (*s_ptr == '\0') {
    return NULL;
  } else {
    while (1) {
      if (*sp_ptr == '\0' || *s_ptr == '\0') {
        break;
      } else if (*s_ptr == *sp_ptr) {
        (s_ptr)++;
        sp_ptr++;
      } else {
        (s_ptr)++;
        sp_ptr = s_init;
        ;
      }
    }
    if (*sp_ptr == '\0') {
      return s_ptr;
    } else {
      return NULL;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_substr_with_gap>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %rdi,%rdx
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  sub    $0x8,%rsp
  cmpb   $0x2a,(%rsi)
  sete   %bpl
  add    %rsi,%rbp
  call   <printf@plt>
  movzbl (%rbx),%eax
  movzbl 0x0(%rbp),%edx
  cmp    %al,%dl
  jne    L65
  jmp    L5
  nopl   (%rax)
L85:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    %dl,%al
  je     L5
L65:
  test   %al,%al
  jne    L85
  xor    %eax,%eax
  test   %dl,%dl
  cmove  %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  test   %dl,%dl
  je     L81
  mov    %rbp,%rsi
  mov    %edx,%ecx
L19:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L44
L86:
  add    $0x1,%rbx
  cmp    %cl,%al
  je     L96
  movzbl (%rbx),%eax
  mov    %edx,%ecx
  mov    %rbp,%rsi
  test   %al,%al
  jne    L86
L44:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L96:
  movzbl 0x1(%rsi),%ecx
  lea    0x1(%rsi),%rax
  test   %cl,%cl
  je     L81
  mov    %rax,%rsi
  jmp    L19
  nopl   0x0(%rax)
L81:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: Find subpattern |%7s| in |%15s|: 

assistant: ```c
char *find_substr_with_gap(char *s_ptr, char *sub_pattern) {
  char *sp_ptr = (sub_pattern[0] == '*') ? sub_pattern + 1 : sub_pattern;
  char *s_init = sp_ptr;
  printf("Find subpattern |%7s| in |%15s|: ", sub_pattern, s_ptr);
  while (*s_ptr != *sp_ptr && *s_ptr != '\0') {
    (s_ptr)++;
  }
  if (*s_ptr == '\0' && *sp_ptr == '\0') {
    return s_ptr;
  } else if (*s_ptr == '\0') {
    return NULL;
  } else {
    while (1) {
      if (*sp_ptr == '\0' || *s_ptr == '\0') {
        break;
      } else if (*s_ptr == *sp_ptr) {
        (s_ptr)++;
        sp_ptr++;
      } else {
        (s_ptr)++;
        sp_ptr = s_init;
        ;
      }
    }
    if (*sp_ptr == '\0') {
      return s_ptr;
    } else {
      return NULL;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<__reloc_self>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xc4(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %rax,-0xd0(%rbp)
  jmp    L104
L47:
  addq   $0x8,-0xd0(%rbp)
L104:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L47
  addq   $0x8,-0xd0(%rbp)
  jmp    L34
L33:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x13,%rax
  ja     L40
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xd0(%rbp),%rdx
  mov    0x8(%rdx),%rdx
  mov    %rdx,-0xb0(%rbp,%rax,8)
L40:
  addq   $0x10,-0xd0(%rbp)
L34:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L33
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    %rax,-0xc0(%rbp)
  cmpq   $0x0,-0xc0(%rbp)
  jne    L107
  mov    D39(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rdx
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  mov    -0xb0(%rbp,%rax,8),%rax
  neg    %rax
  and    %rdx,%rax
  mov    %rax,-0xc0(%rbp)
L107:
  mov    -0xd8(%rbp),%rax
  mov    %rax,-0xd0(%rbp)
  jmp    L116
L51:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x70000000,%rax
  cmp    $0x13,%rax
  ja     L53
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  and    $0x1f,%eax
  mov    %rax,%rdx
  mov    -0xd0(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0xb0(%rbp,%rdx,8)
L53:
  addq   $0x10,-0xd0(%rbp)
L116:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L51
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  sub    $0x70000000,%eax
  cltq
  mov    -0xb0(%rbp,%rax,8),%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0xe0(%rbp),%rax
  mov    %rax,-0xd0(%rbp)
  jmp    L81
L83:
  mov    -0xd0(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc0(%rbp),%rax
  add    %rax,%rdx
  mov    -0xd0(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0xd0(%rbp)
  subq   $0x1,-0xb8(%rbp)
L81:
  cmpq   $0x0,-0xb8(%rbp)
  jne    L83
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv, size_t *got) {
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a - 0x70000000UL < 20)
      t[*a & 31] = a[1];
  n = t[DT_MIPS_LOCAL_GOTNO - 0x70000000];
  for (a = got; n; a++, n--)
    *a += (size_t)base;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %fs:0x28,%rcx
  mov    %rcx,0xa8(%rsp)
  xor    %ecx,%ecx
  movslq %edi,%rdi
  lea    0x8(%rax,%rdi,8),%rax
  cmpq   $0x0,(%rax)
  je     L81
L95:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L95
L81:
  lea    0x8(%rax),%rcx
  mov    0x8(%rax),%rax
  test   %rax,%rax
  jne    L1
L116:
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  test   %rdi,%rdi
  jne    L122
  mov    D31(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  neg    %rdi
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  and    (%rsp,%rax,8),%rdi
L122:
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L6
L68:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  sub    $0x70000000,%eax
  cltq
  mov    (%rsp,%rax,8),%rax
  test   %rax,%rax
  je     L120
L112:
  add    %rdi,(%rdx)
  add    $0x8,%rdx
  sub    $0x1,%rax
  jne    L112
L120:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0xb8,%rsp
  ret
L32:
  add    $0x10,%rcx
  mov    (%rcx),%rax
  test   %rax,%rax
  je     L116
L1:
  cmp    $0x13,%rax
  ja     L32
  mov    0x8(%rcx),%rdi
  mov    %rdi,(%rsp,%rax,8)
  jmp    L32
L8:
  add    $0x10,%rsi
  mov    (%rsi),%rax
  test   %rax,%rax
  je     L68
L6:
  lea    -0x70000000(%rax),%rcx
  cmp    $0x13,%rcx
  ja     L8
  and    $0x1f,%eax
  mov    0x8(%rsi),%rcx
  mov    %rcx,(%rsp,%rax,8)
  jmp    L8
L108:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv, size_t *got) {
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a - 0x70000000UL < 20)
      t[*a & 31] = a[1];
  n = t[DT_MIPS_LOCAL_GOTNO - 0x70000000];
  for (a = got; n; a++, n--)
    *a += (size_t)base;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rsi,%r8
  movslq %edi,%rdi
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x8(%r8,%rdi,8),%rax
  mov    %rcx,%rdx
  cmpq   $0x0,(%rax)
  je     L73
  nopl   (%rax)
L78:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L78
L73:
  lea    0x8(%rax),%rcx
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L116
  nop
L81:
  cmp    $0x13,%rax
  ja     L23
  mov    0x8(%rcx),%rdi
  mov    %rdi,(%rsp,%rax,8)
L23:
  mov    0x10(%rcx),%rax
  add    $0x10,%rcx
  test   %rax,%rax
  jne    L81
L116:
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  test   %rdi,%rdi
  jne    L31
  mov    D35(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  neg    %rdi
  and    (%rsp,%rax,8),%rdi
  jmp    L31
  nop
L18:
  lea    -0x70000000(%rax),%rcx
  cmp    $0x13,%rcx
  ja     L71
  mov    0x8(%rsi),%rcx
  and    $0x1f,%eax
  mov    %rcx,(%rsp,%rax,8)
L71:
  add    $0x10,%rsi
L31:
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L18
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  sub    $0x70000000,%eax
  cltq
  mov    (%rsp,%rax,8),%rax
  test   %rax,%rax
  je     L111
  nopl   (%rax)
L106:
  add    %rdi,(%rdx)
  add    $0x8,%rdx
  sub    $0x1,%rax
  jne    L106
L111:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xb8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv, size_t *got) {
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a - 0x70000000UL < 20)
      t[*a & 31] = a[1];
  n = t[DT_MIPS_LOCAL_GOTNO - 0x70000000];
  for (a = got; n; a++, n--)
    *a += (size_t)base;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__reloc_self>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rsi,%r8
  movslq %edi,%rdi
  mov    %rcx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x8(%r8,%rdi,8),%rax
  cmpq   $0x0,(%rax)
  je     L72
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L0
L72:
  lea    0x8(%rax),%rcx
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L14
  nop
L144:
  cmp    $0x13,%rax
  ja     L34
  mov    0x8(%rcx),%rdi
  add    $0x10,%rcx
  mov    %rdi,(%rsp,%rax,8)
  mov    (%rcx),%rax
  test   %rax,%rax
  jne    L144
L14:
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  test   %rdi,%rdi
  jne    L96
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  mov    (%rsp,%rax,8),%rdi
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  neg    %rdi
  and    (%rsp,%rax,8),%rdi
L96:
  mov    (%rdx),%rax
  test   %rax,%rax
  je     L145
L132:
  lea    -0x70000000(%rax),%rcx
  cmp    $0x13,%rcx
  ja     L85
  mov    0x8(%rdx),%rcx
  and    $0x1f,%eax
  add    $0x10,%rdx
  mov    %rcx,(%rsp,%rax,8)
  mov    (%rdx),%rax
  test   %rax,%rax
  jne    L132
L145:
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  sub    $0x70000000,%eax
  cltq
  mov    (%rsp,%rax,8),%r8
  test   %r8,%r8
  je     L41
  cmp    $0x1,%r8
  je     L67
  mov    %r8,%rcx
  movq   %rdi,%xmm1
  mov    %rsi,%rax
  xor    %edx,%edx
  shr    %rcx
  punpcklqdq %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L138:
  movdqu (%rax),%xmm0
  add    $0x1,%rdx
  add    $0x10,%rax
  paddq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rcx
  jne    L138
  mov    %r8,%rax
  and    $0xfffffffffffffffe,%rax
  lea    (%rsi,%rax,8),%rsi
  cmp    %rax,%r8
  je     L41
L67:
  add    %rdi,(%rsi)
L41:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0xb8,%rsp
  ret
  nop
L34:
  mov    0x10(%rcx),%rax
  add    $0x10,%rcx
  test   %rax,%rax
  jne    L144
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L85:
  add    $0x10,%rdx
  jmp    L96
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __reloc_self(int c, size_t *a, size_t *dynv, size_t *got) {
  char *base;
  size_t t[20], n;
  for (a += c + 1; *a; a++)
    ;
  for (a++; *a; a += 2)
    if (*a < 20)
      t[*a] = a[1];
  base = (char *)t[AT_BASE];
  if (!base)
    base = (char *)(t[AT_PHDR] & -t[AT_PAGESZ]);
  for (a = dynv; *a; a += 2)
    if (*a - 0x70000000UL < 20)
      t[*a & 31] = a[1];
  n = t[DT_MIPS_LOCAL_GOTNO - 0x70000000];
  for (a = got; n; a++, n--)
    *a += (size_t)base;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L1
  mov    D5(%rip),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D2(%rip)
L1:
  mov    D2(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int fun_d(int argd) {
  static int locd = 0;
  if (argd > 0)
    locd += argd;
  return locd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fun_d>:
  endbr64
  test   %edi,%edi
  jle    L7
  add    %edi,D2(%rip)
L7:
  mov    D2(%rip),%eax
  ret
```

assistant: ```c
__attribute__((always_)) int fun_d(int argd) {
  static int locd = 0;
  if (argd > 0)
    locd += argd;
  return locd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun_d>:
  endbr64
  mov    D6(%rip),%eax
  test   %edi,%edi
  jle    L5
  add    %edi,%eax
  mov    %eax,D3(%rip)
L5:
  ret
```

assistant: ```c
__attribute__((always_)) int fun_d(int argd) {
  static int locd = 0;
  if (argd > 0)
    locd += argd;
  return locd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun_d>:
  endbr64
  mov    D8(%rip),%eax
  test   %edi,%edi
  jle    L9
  add    %edi,%eax
  mov    %eax,D17(%rip)
L9:
  ret
```

assistant: ```c
__attribute__((always_)) int fun_d(int argd) {
  static int locd = 0;
  if (argd > 0)
    locd += argd;
  return locd;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<waitinput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x34(%rbp)
  jns    L3
  mov    $0x0,%eax
  jmp    L13
L3:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x28(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%ecx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <inpselect@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x24(%rbp)
  je     L3
  mov    -0x24(%rbp),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int waitinput(int fd, unsigned ms) {
  fd_set set;
  struct timeval tmv;
  int ret;
  if (fd < 0)
    return 0;
  do {
    FD_ZERO(&set);
    FD_SET(fd, &set);
    tmv.tv_sec = 0;
    tmv.tv_usec = 1000 * ms;
    ret = inpselect(fd + 1, &set, &tmv);
  } while (ret == -1);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<waitinput>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L0
  mov    %edi,%ebp
  imul   $0x3e8,%esi,%r12d
  lea    0xc(%rsp),%rbx
L2:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  movq   $0x0,0x18(%rsp)
  mov    %r12d,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x1(%rbp),%edi
  mov    %rbx,%rsi
  call   <inpselect@plt>
  cmp    $0xffffffff,%eax
  je     L2
L0:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitinput(int fd, unsigned ms) {
  fd_set set;
  struct timeval tmv;
  int ret;
  if (fd < 0)
    return 0;
  do {
    FD_ZERO(&set);
    FD_SET(fd, &set);
    tmv.tv_sec = 0;
    tmv.tv_usec = 1000 * ms;
    ret = inpselect(fd + 1, &set, &tmv);
  } while (ret == -1);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<waitinput>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L5
  imul   $0x3e8,%esi,%r12d
  mov    %edi,%ebp
  lea    0x1(%rdi),%r14d
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  movq   $0x0,0x18(%rsp)
  mov    %r12d,0x10(%rsp)
  call   <inpselect@plt>
  cmp    $0xffffffff,%eax
  je     L9
L5:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int waitinput(int fd, unsigned ms) {
  fd_set set;
  struct timeval tmv;
  int ret;
  if (fd < 0)
    return 0;
  do {
    FD_ZERO(&set);
    FD_SET(fd, &set);
    tmv.tv_sec = 0;
    tmv.tv_usec = 1000 * ms;
    ret = inpselect(fd + 1, &set, &tmv);
  } while (ret == -1);
  return ret;
}
```