ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getPtrInLineForProject>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
  mov    $0x0,%eax
  ret
L2:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L13
L1:
  lea    -0x9(%rdx),%eax
  cmp    $0x1,%al
  jbe    L2
  cmp    $0x20,%dl
  je     L2
  mov    %rdi,%rax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
const char *getPtrInLineForProject(const char *const line) {
  int i = 0;
  bool retval = false;
  while (line[i] != '\0') {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\n') {
      i++;
    } else {
      return &line[i];
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getPtrInLineForProject>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L28:
  lea    -0x9(%rdx),%eax
  cmp    $0x1,%al
  jbe    L0
  cmp    $0x20,%dl
  jne    L20
L0:
  add    $0x1,%rdi
L23:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L28
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *getPtrInLineForProject(const char *const line) {
  int i = 0;
  bool retval = false;
  while (line[i] != '\0') {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\n') {
      i++;
    } else {
      return &line[i];
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getPtrInLineForProject>:
  endbr64
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    -0x9(%rdx),%eax
  cmp    $0x1,%al
  jbe    L31
  cmp    $0x20,%dl
  jne    L35
L31:
  add    $0x1,%rdi
L3:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *getPtrInLineForProject(const char *const line) {
  int i = 0;
  bool retval = false;
  while (line[i] != '\0') {
    if (line[i] == ' ' || line[i] == '\t' || line[i] == '\n') {
      i++;
    } else {
      return &line[i];
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm2
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D47
data_type: string
name: read_data
arguments: data_tag: D49
data_type: string
name: read_data
arguments: data_tag: D45
data_type: string
name: read_data
arguments: data_tag: D46
data_type: string

tool: D3: Numero 1: 

tool: D47: %f

tool: D49: Numero 2: 

tool: D45: Numero 3: 

tool: D46: Soma dos quadrados: %.2f

assistant: ```c
int main() {
  float num1, num2, num3;
  printf("Numero 1: ");
  scanf("%f", &num1);
  printf("Numero 2: ");
  scanf("%f", &num2);
  printf("Numero 3: ");
  scanf("%f", &num3);
  printf("Soma dos quadrados: %.2f", num1 * num1 + num2 * num2 + num3 * num3);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm2
  movss  0x14(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D49
datatype: string
name: extract_symbolic_data
arguments: label: D36
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string

tool: D10: Numero 1: 

tool: D5: %f

tool: D49: Numero 2: 

tool: D36: Numero 3: 

tool: D17: Soma dos quadrados: %.2f

assistant: ```c
int main() {
  float num1, num2, num3;
  printf("Numero 1: ");
  scanf("%f", &num1);
  printf("Numero 2: ");
  scanf("%f", &num2);
  printf("Numero 3: ");
  scanf("%f", &num3);
  printf("Soma dos quadrados: %.2f", num1 * num1 + num2 * num2 + num3 * num3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  lea    D16(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm2
  lea    D14(%rip),%rdi
  movss  0x14(%rsp),%xmm1
  mov    $0x1,%eax
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  mulss  %xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D44
datatype: string
name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D41
datatype: string
name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D14
datatype: string

tool: D44: Numero 1: 

tool: D16: %f

tool: D41: Numero 2: 

tool: D23: Numero 3: 

tool: D14: Soma dos quadrados: %.2f

assistant: ```c
int main() {
  float num1, num2, num3;
  printf("Numero 1: ");
  scanf("%f", &num1);
  printf("Numero 2: ");
  scanf("%f", &num2);
  printf("Numero 3: ");
  scanf("%f", &num3);
  printf("Soma dos quadrados: %.2f", num1 * num1 + num2 * num2 + num3 * num3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  lea    D40(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm2
  lea    D2(%rip),%rdi
  movss  0x14(%rsp),%xmm1
  mov    $0x1,%eax
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  mulss  %xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D40
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string

tool: D14: Numero 1: 

tool: D40: %f

tool: D29: Numero 2: 

tool: D48: Numero 3: 

tool: D2: Soma dos quadrados: %.2f

assistant: ```c
int main() {
  float num1, num2, num3;
  printf("Numero 1: ");
  scanf("%f", &num1);
  printf("Numero 2: ");
  scanf("%f", &num2);
  printf("Numero 3: ");
  scanf("%f", &num3);
  printf("Soma dos quadrados: %.2f", num1 * num1 + num2 * num2 + num3 * num3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x74,%ecx
  mov    $0x64,%edx
  mov    $0x73,%esi
  mov    $0x5,%edi
  call   <towers_of_hanoi@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  towers_of_hanoi(5, 's', 'd', 't');
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x74,%ecx
  mov    $0x64,%edx
  mov    $0x73,%esi
  mov    $0x5,%edi
  call   <towers_of_hanoi@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  towers_of_hanoi(5, 's', 'd', 't');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x74,%ecx
  mov    $0x64,%edx
  mov    $0x73,%esi
  mov    $0x5,%edi
  call   <towers_of_hanoi@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  towers_of_hanoi(5, 's', 'd', 't');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x74,%ecx
  mov    $0x64,%edx
  mov    $0x73,%esi
  mov    $0x5,%edi
  call   <towers_of_hanoi@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  towers_of_hanoi(5, 's', 'd', 't');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<MMS_BTSN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L11:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  jg     L11
  mov    $0x20,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    -0x28(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x20,%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
MMS_BTSN(s, b, m, n, w) int *s, b, m, n, w;
{
  int i, v;
  i = n - m + 1;
  v = 0;
  while (i > 0) {
    v = 2 * v + 1;
    i = i - 1;
  };
  *(s) = (~(v << (32 - n)) & b) | ((w & v) << (32 - n));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MMS_BTSN>:
  endbr64
  mov    %esi,%r9d
  mov    %ecx,%esi
  mov    %ecx,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  test   %eax,%eax
  jle    L23
  mov    $0x0,%edx
L2:
  lea    0x1(%rdx,%rdx,1),%edx
  sub    $0x1,%eax
  jne    L2
L18:
  mov    $0x20,%ecx
  sub    %esi,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  not    %eax
  and    %r9d,%eax
  and    %edx,%r8d
  shl    %cl,%r8d
  or     %r8d,%eax
  mov    %eax,(%rdi)
  ret
L23:
  mov    $0x0,%edx
  jmp    L18
```

assistant: ```c
MMS_BTSN(s, b, m, n, w) int *s, b, m, n, w;
{
  int i, v;
  i = n - m + 1;
  v = 0;
  while (i > 0) {
    v = 2 * v + 1;
    i = i - 1;
  };
  *(s) = (~(v << (32 - n)) & b) | ((w & v) << (32 - n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MMS_BTSN>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%eax
  mov    %ecx,%edx
  mov    $0x20,%ecx
  sub    %r9d,%eax
  sub    %edx,%ecx
  add    $0x1,%eax
  test   %eax,%eax
  jle    L3
  xor    %edx,%edx
  xchg   %ax,%ax
L0:
  lea    0x1(%rdx,%rdx,1),%edx
  sub    $0x1,%eax
  jne    L0
  mov    %edx,%eax
  and    %edx,%r8d
  shl    %cl,%eax
  shl    %cl,%r8d
  not    %eax
  and    %esi,%eax
  or     %r8d,%eax
  mov    %eax,%esi
L3:
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
MMS_BTSN(s, b, m, n, w) int *s, b, m, n, w;
{
  int i, v;
  i = n - m + 1;
  v = 0;
  while (i > 0) {
    v = 2 * v + 1;
    i = i - 1;
  };
  *(s) = (~(v << (32 - n)) & b) | ((w & v) << (32 - n));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<MMS_BTSN>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%eax
  mov    %ecx,%edx
  mov    $0x20,%ecx
  sub    %r9d,%eax
  sub    %edx,%ecx
  add    $0x1,%eax
  test   %eax,%eax
  jle    L17
  xor    %edx,%edx
  xchg   %ax,%ax
L18:
  lea    0x1(%rdx,%rdx,1),%edx
  sub    $0x1,%eax
  jne    L18
  mov    %edx,%eax
  and    %edx,%r8d
  shl    %cl,%eax
  shl    %cl,%r8d
  not    %eax
  and    %esi,%eax
  or     %r8d,%eax
  mov    %eax,%esi
L17:
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
MMS_BTSN(s, b, m, n, w) int *s, b, m, n, w;
{
  int i, v;
  i = n - m + 1;
  v = 0;
  while (i > 0) {
    v = 2 * v + 1;
    i = i - 1;
  };
  *(s) = (~(v << (32 - n)) & b) | ((w & v) << (32 - n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    -0x3f60a4d(%rdx),%eax
  test   $0x1,%dl
  jne    L35
  shl    $0x2,%eax
L12:
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
L35:
  test   $0x10,%al
  je     L33
  rol    $0x10,%eax
  add    %eax,%eax
  jmp    L12
L33:
  mov    %eax,%ecx
  shl    $0x8,%ecx
  and    $0xff000000,%ecx
  movzwl %ax,%edx
  shr    $0x18,%eax
  shl    $0x10,%eax
  or     %ecx,%edx
  or     %edx,%eax
  jmp    L12
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      } else {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy13 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy13;
      state[0UL] += state[0UL];
    } else {
      copy14 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy14;
      copy14 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy14;
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy15;
    }
    output[0UL] = (state[0UL] + 882016446UL) + 1338648495U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    -0x3f60a4d(%rax),%edx
  test   $0x1,%al
  jne    L6
  lea    0x0(,%rdx,4),%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
  nop
L6:
  test   $0x10,%dl
  je     L1
  mov    %edx,%eax
  rol    $0x10,%eax
  add    %eax,%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L1:
  mov    %edx,%ecx
  movzwl %dx,%eax
  shr    $0x18,%edx
  shl    $0x8,%ecx
  shl    $0x10,%edx
  and    $0xff000000,%ecx
  or     %ecx,%eax
  or     %edx,%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      } else {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy13 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy13;
      state[0UL] += state[0UL];
    } else {
      copy14 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy14;
      copy14 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy14;
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy15;
    }
    output[0UL] = (state[0UL] + 882016446UL) + 1338648495U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,%ecx
  test   $0x1,%al
  je     L2
  shl    $0x2,%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L2:
  test   $0x10,%al
  je     L15
  rol    $0x10,%eax
  add    %eax,%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L15:
  mov    %eax,%edi
  mov    %al,%cl
  xor    %edx,%edx
  shl    $0x8,%eax
  sar    $0x18,%edi
  sar    $0x18,%eax
  mov    %dil,%dl
  mov    %al,%dh
  movzwl %cx,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  sub    $0x7ba35793,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      } else {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy13 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy13;
      state[0UL] += state[0UL];
    } else {
      copy14 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy14;
      copy14 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy14;
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy15;
    }
    output[0UL] = (state[0UL] + 882016446UL) + 1338648495U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<extra_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void extra_die(const char *msg, ...) {
  va_list args;
  va_start(args, msg);
  vfprintf(stderr, msg, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<extra_die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void extra_die(const char *msg, ...) {
  va_list args;
  va_start(args, msg);
  vfprintf(stderr, msg, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extra_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void extra_die(const char *msg, ...) {
  va_list args;
  va_start(args, msg);
  vfprintf(stderr, msg, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extra_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D18(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void extra_die(const char *msg, ...) {
  va_list args;
  va_start(args, msg);
  vfprintf(stderr, msg, args);
  va_end(args);
  exit(EXIT_FAILURE);
}
```