ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  mov    %edi,%r9d
  mov    %edi,%edx
  mov    %rsi,%r8
  mov    %rsi,%r10
  xor    %edi,%edi
  nopl   0x0(%rax)
L18:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %edi,%esi
  add    $0x1,%edi
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %ecx,%edx
  add    $0x1,%r10
  add    $0x30,%eax
  mov    %al,-0x1(%r10)
  test   %ecx,%ecx
  jne    L18
  test   %r9d,%r9d
  jns    L6
  movslq %edi,%rdi
  movb   $0x2d,(%r8,%rdi,1)
  lea    0x2(%rsi),%edi
L6:
  movslq %edi,%rdi
  movb   $0x0,(%r8,%rdi,1)
  mov    %r8,%rdi
  jmp    1050 <reverse@plt>
```

assistant: ```c
void itoa(int n, char s[]) {
  int i, sign, temp;
  sign = n;
  i = 0;
  do {
    temp = n % 10;
    if (temp < 0)
      temp = -temp;
    s[i++] = temp + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<twlist_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <twlist_test_list_head_init@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_add@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_add_tail@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_del@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_del_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void twlist_test(void) {
  twlist_test_list_head_init();
  twlist_test_list_add();
  twlist_test_list_add_tail();
  twlist_test_list_del();
  twlist_test_list_del_init();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<twlist_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <twlist_test_list_head_init@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_add@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_add_tail@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_del@plt>
  mov    $0x0,%eax
  call   <twlist_test_list_del_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void twlist_test(void) {
  twlist_test_list_head_init();
  twlist_test_list_add();
  twlist_test_list_add_tail();
  twlist_test_list_del();
  twlist_test_list_del_init();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<twlist_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <twlist_test_list_head_init@plt>
  xor    %eax,%eax
  call   <twlist_test_list_add@plt>
  xor    %eax,%eax
  call   <twlist_test_list_add_tail@plt>
  xor    %eax,%eax
  call   <twlist_test_list_del@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <twlist_test_list_del_init@plt>
```

assistant: ```c
void twlist_test(void) {
  twlist_test_list_head_init();
  twlist_test_list_add();
  twlist_test_list_add_tail();
  twlist_test_list_del();
  twlist_test_list_del_init();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<twlist_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <twlist_test_list_head_init@plt>
  xor    %eax,%eax
  call   <twlist_test_list_add@plt>
  xor    %eax,%eax
  call   <twlist_test_list_add_tail@plt>
  xor    %eax,%eax
  call   <twlist_test_list_del@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <twlist_test_list_del_init@plt>
```

assistant: ```c
void twlist_test(void) {
  twlist_test_list_head_init();
  twlist_test_list_add();
  twlist_test_list_add_tail();
  twlist_test_list_del();
  twlist_test_list_del_init();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L54
L33:
  cmpl   $0x2000,-0x1c(%rbp)
  jbe    L73
  mov    $0x0,%eax
  jmp    L54
L73:
  mov    -0x1c(%rbp),%ebx
  mov    -0x18(%rbp),%r12
  jmp    L3
L8:
  movzbl (%r12),%eax
  cmp    $0xa,%al
  jne    L37
  mov    %r12,%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%ebx
  add    $0x1,%ebx
  mov    %ebx,%eax
  jmp    L54
L37:
  add    $0x1,%r12
  sub    $0x1,%ebx
L3:
  test   %ebx,%ebx
  jg     L8
  mov    -0x1c(%rbp),%eax
L54:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned int findline(buf, siz)
char *buf;
unsigned int siz;
{
  register char *p;
  register int x;
  if (!buf)
    return (0);
  if (siz > 8192)
    return (0);
  x = siz;
  for (p = buf; x > 0; x--) {
    if (*p == '\n') {
      x = (int)(p - buf);
      x++;
      return (x);
    }
    p++;
  }
  return (siz);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findline>:
  endbr64
  cmp    $0x2000,%esi
  ja     L26
  test   %rdi,%rdi
  je     L26
  test   %esi,%esi
  jle    L5
  mov    %esi,%eax
  add    %rdi,%rax
  mov    %rdi,%rdx
L7:
  cmpb   $0xa,(%rdx)
  je     L34
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L7
  mov    %esi,%eax
  ret
L34:
  sub    %rdi,%rdx
  lea    0x1(%rdx),%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L5:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int findline(buf, siz)
char *buf;
unsigned int siz;
{
  register char *p;
  register int x;
  if (!buf)
    return (0);
  if (siz > 8192)
    return (0);
  x = siz;
  for (p = buf; x > 0; x--) {
    if (*p == '\n') {
      x = (int)(p - buf);
      x++;
      return (x);
    }
    p++;
  }
  return (siz);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findline>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L47
  lea    -0x1(%rsi),%edx
  cmp    $0x1fff,%edx
  ja     L47
  mov    %esi,%edx
  mov    %rdi,%rax
  add    %rdi,%rdx
  jmp    L23
L25:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L32
L23:
  cmpb   $0xa,(%rax)
  jne    L25
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   (%rax)
L32:
  mov    %esi,%eax
L47:
  ret
```

assistant: ```c
unsigned int findline(buf, siz)
char *buf;
unsigned int siz;
{
  register char *p;
  register int x;
  if (!buf)
    return (0);
  if (siz > 8192)
    return (0);
  x = siz;
  for (p = buf; x > 0; x--) {
    if (*p == '\n') {
      x = (int)(p - buf);
      x++;
      return (x);
    }
    p++;
  }
  return (siz);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findline>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L30
  lea    -0x1(%rsi),%edx
  cmp    $0x1fff,%edx
  ja     L30
  mov    %esi,%edx
  mov    %rdi,%rax
  add    %rdi,%rdx
  jmp    L16
L21:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L6
L16:
  cmpb   $0xa,(%rax)
  jne    L21
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   (%rax)
L6:
  mov    %esi,%eax
L30:
  ret
```

assistant: ```c
unsigned int findline(buf, siz)
char *buf;
unsigned int siz;
{
  register char *p;
  register int x;
  if (!buf)
    return (0);
  if (siz > 8192)
    return (0);
  x = siz;
  for (p = buf; x > 0; x--) {
    if (*p == '\n') {
      x = (int)(p - buf);
      x++;
      return (x);
    }
    p++;
  }
  return (siz);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ofl_buffer_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <open_memstream@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ofl_buffer_print@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *ofl_buffer_to_string(uint32_t buffer) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_buffer_print(stream, buffer);
  fclose(stream);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ofl_buffer_to_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %rax,%rbx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <ofl_buffer_print@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_buffer_to_string(uint32_t buffer) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_buffer_print(stream, buffer);
  fclose(stream);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ofl_buffer_to_string>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %r12d,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ofl_buffer_print@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_buffer_to_string(uint32_t buffer) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_buffer_print(stream, buffer);
  fclose(stream);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ofl_buffer_to_string>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %r12d,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ofl_buffer_print@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_buffer_to_string(uint32_t buffer) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_buffer_print(stream, buffer);
  fclose(stream);
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<r4300_decode_op>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <r4k_disassemble_split_quick@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void r4300_decode_op(uint32_t instr, char *opcode, char *arguments, uint32_t counter) {
  char *_op, *_args;
  _op = NULL;
  _args = NULL;
  r4k_disassemble_split_quick(instr, counter, &_op, &_args);
  strcpy(opcode, _op);
  strcpy(arguments, _args);
  free(_op);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<r4300_decode_op>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <r4k_disassemble_split_quick@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void r4300_decode_op(uint32_t instr, char *opcode, char *arguments, uint32_t counter) {
  char *_op, *_args;
  _op = NULL;
  _args = NULL;
  r4k_disassemble_split_quick(instr, counter, &_op, &_args);
  strcpy(opcode, _op);
  strcpy(arguments, _args);
  free(_op);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<r4300_decode_op>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %ecx,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <r4k_disassemble_split_quick@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void r4300_decode_op(uint32_t instr, char *opcode, char *arguments, uint32_t counter) {
  char *_op, *_args;
  _op = NULL;
  _args = NULL;
  r4k_disassemble_split_quick(instr, counter, &_op, &_args);
  strcpy(opcode, _op);
  strcpy(arguments, _args);
  free(_op);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<r4300_decode_op>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %ecx,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <r4k_disassemble_split_quick@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void r4300_decode_op(uint32_t instr, char *opcode, char *arguments, uint32_t counter) {
  char *_op, *_args;
  _op = NULL;
  _args = NULL;
  r4k_disassemble_split_quick(instr, counter, &_op, &_args);
  strcpy(opcode, _op);
  strcpy(arguments, _args);
  free(_op);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x1,-0x38(%rbp)
  ja     L3
  addq   $0x2,-0x38(%rbp)
L3:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x2,-0x38(%rbp)
  ja     L1
  mov    -0x8(%rbp),%rax
  jmp    L53
L1:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L55:
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L19
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L55
L19:
  nop
  cmpl   $0x1,-0x2c(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L64
L17:
  mov    -0x38(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
L64:
  mov    -0x8(%rbp),%rax
L53:
  leave
  ret
```

assistant: ```c
char *basename(char *str, int mod, size_t str_size) {
  char *s;
  char *tmp;
  if (str_size < 2)
    str_size += 2;
  char *loh = malloc(str_size);
  s = malloc(str_size);
  if (str_size < 3) {
    return s;
  }
  uint64_t b;
  for (tmp = str;; tmp++) {
    tmp = strstr(tmp, "/");
    if (tmp == NULL)
      break;
    b = tmp - str;
  }
  if (mod == 1) {
    strncpy(s, str, b);
    s[b] = '\0';
  } else {
    strncpy(s, str + b + 1, str_size - b);
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<basename>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %rdx,%rbx
  lea    0x2(%rdx),%rax
  cmp    $0x2,%rdx
  cmovb  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x2,%rbx
  jbe    L49
  mov    %rbp,%rdi
  jmp    L24
L31:
  mov    %rax,%r12
  sub    %rbp,%r12
  lea    0x1(%rax),%rdi
L24:
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L31
  cmp    $0x1,%r14d
  je     L43
  mov    %rbx,%rdx
  sub    %r12,%rdx
  lea    0x1(%rbp,%r12,1),%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
L49:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r12,1)
  jmp    L49
```

assistant: ```c
char *basename(char *str, int mod, size_t str_size) {
  char *s;
  char *tmp;
  if (str_size < 2)
    str_size += 2;
  char *loh = malloc(str_size);
  s = malloc(str_size);
  if (str_size < 3) {
    return s;
  }
  uint64_t b;
  for (tmp = str;; tmp++) {
    tmp = strstr(tmp, "/");
    if (tmp == NULL)
      break;
    b = tmp - str;
  }
  if (mod == 1) {
    strncpy(s, str, b);
    s[b] = '\0';
  } else {
    strncpy(s, str + b + 1, str_size - b);
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<basename>:
  endbr64
  push   %r14
  lea    0x2(%rdx),%rax
  cmp    $0x2,%rdx
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmovb  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x2,%rbx
  je     L37
  mov    %rbp,%rdi
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rax,%r12
  lea    0x1(%rax),%rdi
  sub    %rbp,%r12
L1:
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L28
  cmp    $0x1,%r14d
  je     L30
  mov    %rbx,%rdx
  lea    0x1(%rbp,%r12,1),%rsi
  mov    %r13,%rdi
  sub    %r12,%rdx
  call   <strncpy@plt>
L37:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L30:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  pop    %rbx
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *basename(char *str, int mod, size_t str_size) {
  char *s;
  char *tmp;
  if (str_size < 2)
    str_size += 2;
  char *loh = malloc(str_size);
  s = malloc(str_size);
  if (str_size < 3) {
    return s;
  }
  uint64_t b;
  for (tmp = str;; tmp++) {
    tmp = strstr(tmp, "/");
    if (tmp == NULL)
      break;
    b = tmp - str;
  }
  if (mod == 1) {
    strncpy(s, str, b);
    s[b] = '\0';
  } else {
    strncpy(s, str + b + 1, str_size - b);
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basename>:
  endbr64
  push   %r14
  lea    0x2(%rdx),%rax
  cmp    $0x2,%rdx
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmovb  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x2,%rbx
  je     L17
  mov    %rbp,%rdi
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rax,%r12
  lea    0x1(%rax),%rdi
  sub    %rbp,%r12
L8:
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L24
  cmp    $0x1,%r14d
  je     L22
  mov    %rbx,%rdx
  lea    0x1(%rbp,%r12,1),%rsi
  mov    %r13,%rdi
  sub    %r12,%rdx
  call   <strncpy@plt>
L17:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L22:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  pop    %rbx
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *basename(char *str, int mod, size_t str_size) {
  char *s;
  char *tmp;
  if (str_size < 2)
    str_size += 2;
  char *loh = malloc(str_size);
  s = malloc(str_size);
  if (str_size < 3) {
    return s;
  }
  uint64_t b;
  for (tmp = str;; tmp++) {
    tmp = strstr(tmp, "/");
    if (tmp == NULL)
      break;
    b = tmp - str;
  }
  if (mod == 1) {
    strncpy(s, str, b);
    s[b] = '\0';
  } else {
    strncpy(s, str + b + 1, str_size - b);
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  leave
  ret
```

assistant: ```c
void *memdup(void *src, size_t len) {
  void *dst = malloc(len);
  return memcpy(dst, src, len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *memdup(void *src, size_t len) {
  void *dst = malloc(len);
  return memcpy(dst, src, len);
}
```
user: What is the c source code of the assembly code below?

```asm
<memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *memdup(void *src, size_t len) {
  void *dst = malloc(len);
  return memcpy(dst, src, len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memdup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *memdup(void *src, size_t len) {
  void *dst = malloc(len);
  return memcpy(dst, src, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L19
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L39:
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L33
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L33:
  mov    -0x18(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *ltrim(char *s) {
  if (s == NULL)
    return NULL;
  char *ptr = s;
  while (isspace(*ptr))
    ptr++;
  if (s != ptr)
    memmove(s, ptr, strlen(ptr) + 1);
  return s;
}
```