ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<constant_name_maps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L35
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <constant_lookup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x8(%rbp),%rax
  jmp    L10
L33:
  addq   $0x8,-0x10(%rbp)
L35:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L12
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D17(%rip),%rax
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: <Unknown %d>

assistant: ```c
char *constant_name_maps(struct constant_map **maps, int value) {
  static char tmp[32];
  char *retval;
  struct constant_map **map;
  for (map = maps; *map; map++) {
    retval = constant_lookup(*map, value);
    if (retval)
      return retval;
  }
  snprintf(tmp, sizeof tmp, "<Unknown %d>", value);
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<constant_name_maps>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L22
L16:
  mov    %ebp,%esi
  call   <constant_lookup@plt>
  test   %rax,%rax
  jne    L14
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L16
L22:
  mov    %ebp,%ecx
  lea    D9(%rip),%rdx
  mov    $0x20,%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: <Unknown %d>

assistant: ```c
char *constant_name_maps(struct constant_map **maps, int value) {
  static char tmp[32];
  char *retval;
  struct constant_map **map;
  for (map = maps; *map; map++) {
    retval = constant_lookup(*map, value);
    if (retval)
      return retval;
  }
  snprintf(tmp, sizeof tmp, "<Unknown %d>", value);
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<constant_name_maps>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  jne    L2
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L4
L2:
  mov    %r12d,%esi
  call   <constant_lookup@plt>
  test   %rax,%rax
  je     L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D7(%rip),%rbx
  mov    %r12d,%ecx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  lea    D19(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_infered: string

tool: D19: <Unknown %d>

assistant: ```c
char *constant_name_maps(struct constant_map **maps, int value) {
  static char tmp[32];
  char *retval;
  struct constant_map **map;
  for (map = maps; *map; map++) {
    retval = constant_lookup(*map, value);
    if (retval)
      return retval;
  }
  snprintf(tmp, sizeof tmp, "<Unknown %d>", value);
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<constant_name_maps>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  jne    L13
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L9
L13:
  mov    %r12d,%esi
  call   <constant_lookup@plt>
  test   %rax,%rax
  je     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D16(%rip),%rbx
  mov    %r12d,%ecx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: <Unknown %d>

assistant: ```c
char *constant_name_maps(struct constant_map **maps, int value) {
  static char tmp[32];
  char *retval;
  struct constant_map **map;
  for (map = maps; *map; map++) {
    retval = constant_lookup(*map, value);
    if (retval)
      return retval;
  }
  snprintf(tmp, sizeof tmp, "<Unknown %d>", value);
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<GenPostAddSubIdent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x9,-0x4(%rbp)
  cmpl   $0x53,-0x20(%rbp)
  je     L4
  movl   $0xa,-0x4(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xb,%edi
  call   <GenSelectByteOrWord@plt>
  mov    -0x1c(%rbp),%edx
  mov    %edx,%r9d
  mov    $0x10,%r8d
  mov    $0x0,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <GenExtendRegAIfNeeded@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x14,%edi
  call   <GenSelectByteOrWord@plt>
  mov    %eax,%esi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%r9d
  mov    $0xd,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <GenPrintInstr2Operands@plt>
  nop
  leave
  ret
```

assistant: ```c
void GenPostAddSubIdent(int opSz, int val, int label, int tok) {
  int instr = 0x09;
  if (tok != 'S')
    instr = 0x0A;
  GenPrintInstr2Operands(0x00, 0, GenSelectByteOrWord(0x0B, opSz), 0, 0x10, label);
  GenExtendRegAIfNeeded(opSz);
  GenPrintInstr2Operands(instr, 0, GenSelectByteOrWord(0x14, opSz), label, 0x0D, val);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GenPostAddSubIdent>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%ebp
  cmp    $0x53,%ecx
  setne  %r12b
  movzbl %r12b,%r12d
  add    $0x9,%r12d
  mov    %edi,%esi
  mov    $0xb,%edi
  call   <GenSelectByteOrWord@plt>
  mov    %eax,%edx
  mov    %ebp,%r9d
  mov    $0x10,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    %ebx,%edi
  call   <GenExtendRegAIfNeeded@plt>
  mov    %ebx,%esi
  mov    $0x14,%edi
  call   <GenSelectByteOrWord@plt>
  mov    %eax,%edx
  mov    %r13d,%r9d
  mov    $0xd,%r8d
  mov    %ebp,%ecx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <GenPrintInstr2Operands@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void GenPostAddSubIdent(int opSz, int val, int label, int tok) {
  int instr = 0x09;
  if (tok != 'S')
    instr = 0x0A;
  GenPrintInstr2Operands(0x00, 0, GenSelectByteOrWord(0x0B, opSz), 0, 0x10, label);
  GenExtendRegAIfNeeded(opSz);
  GenPrintInstr2Operands(instr, 0, GenSelectByteOrWord(0x14, opSz), label, 0x0D, val);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GenPostAddSubIdent>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  mov    $0xb,%edi
  sub    $0x8,%rsp
  cmp    $0x53,%ecx
  setne  %r13b
  call   <GenSelectByteOrWord@plt>
  mov    %r12d,%r9d
  mov    $0x10,%r8d
  xor    %ecx,%ecx
  mov    %eax,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x9,%r13d
  call   <GenPrintInstr2Operands@plt>
  mov    %ebp,%edi
  call   <GenExtendRegAIfNeeded@plt>
  mov    %ebp,%esi
  mov    $0x14,%edi
  call   <GenSelectByteOrWord@plt>
  add    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r13d,%edi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  mov    $0xd,%r8d
  xor    %esi,%esi
  pop    %r13
  jmp    1070 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenPostAddSubIdent(int opSz, int val, int label, int tok) {
  int instr = 0x09;
  if (tok != 'S')
    instr = 0x0A;
  GenPrintInstr2Operands(0x00, 0, GenSelectByteOrWord(0x0B, opSz), 0, 0x10, label);
  GenExtendRegAIfNeeded(opSz);
  GenPrintInstr2Operands(instr, 0, GenSelectByteOrWord(0x14, opSz), label, 0x0D, val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GenPostAddSubIdent>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  mov    $0xb,%edi
  sub    $0x8,%rsp
  cmp    $0x53,%ecx
  setne  %r13b
  call   <GenSelectByteOrWord@plt>
  mov    %r12d,%r9d
  mov    $0x10,%r8d
  xor    %ecx,%ecx
  mov    %eax,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x9,%r13d
  call   <GenPrintInstr2Operands@plt>
  mov    %ebp,%edi
  call   <GenExtendRegAIfNeeded@plt>
  mov    %ebp,%esi
  mov    $0x14,%edi
  call   <GenSelectByteOrWord@plt>
  add    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r13d,%edi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  mov    $0xd,%r8d
  xor    %esi,%esi
  pop    %r13
  jmp    1070 <GenPrintInstr2Operands@plt>
```

assistant: ```c
void GenPostAddSubIdent(int opSz, int val, int label, int tok) {
  int instr = 0x09;
  if (tok != 'S')
    instr = 0x0A;
  GenPrintInstr2Operands(0x00, 0, GenSelectByteOrWord(0x0B, opSz), 0, 0x10, label);
  GenExtendRegAIfNeeded(opSz);
  GenPrintInstr2Operands(instr, 0, GenSelectByteOrWord(0x14, opSz), label, 0x0D, val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cad_um_dos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cad_tamanho@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L46:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cad_ocorrencias@plt>
  test   %rax,%rax
  je     L7
  subl   $0x1,-0xc(%rbp)
L7:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L37
  cmpl   $0x0,-0xc(%rbp)
  jne    L46
L37:
  cmpl   $0x0,-0xc(%rbp)
  jne    L8
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  jmp    L54
L8:
  mov    $0xffffffff,%eax
L54:
  leave
  ret
```

assistant: ```c
int cad_um_dos(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int flag = 1;
  int i;
  for (i = 0; i < len1 && flag; i++) {
    if (cad_ocorrencias(s1[i], s2))
      flag--;
  }
  if (!flag)
    return i - 1;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cad_um_dos>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  call   <cad_tamanho@plt>
  test   %eax,%eax
  jle    L20
  mov    %eax,%r13d
  mov    $0x0,%r12d
  mov    $0x1,%ebp
  jmp    L9
L2:
  mov    %eax,%r12d
L9:
  movsbl (%rbx),%edi
  mov    %r14,%rsi
  call   <cad_ocorrencias@plt>
  cmp    $0x1,%rax
  adc    $0xffffffff,%ebp
  lea    0x1(%r12),%eax
  add    $0x1,%rbx
  cmp    %eax,%r13d
  jle    L41
  test   %ebp,%ebp
  jne    L2
L41:
  test   %ebp,%ebp
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
L36:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    $0xffffffff,%r12d
  jmp    L36
```

assistant: ```c
int cad_um_dos(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int flag = 1;
  int i;
  for (i = 0; i < len1 && flag; i++) {
    if (cad_ocorrencias(s1[i], s2))
      flag--;
  }
  if (!flag)
    return i - 1;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cad_um_dos>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <cad_tamanho@plt>
  test   %eax,%eax
  jle    L10
  mov    %eax,%r12d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L22:
  movsbl 0x0(%rbp),%edi
  mov    %r13,%rsi
  add    $0x1,%rbp
  call   <cad_ocorrencias@plt>
  mov    %ebx,%r8d
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L13
  test   %rax,%rax
  je     L22
L21:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  test   %rax,%rax
  jne    L21
L10:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int cad_um_dos(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int flag = 1;
  int i;
  for (i = 0; i < len1 && flag; i++) {
    if (cad_ocorrencias(s1[i], s2))
      flag--;
  }
  if (!flag)
    return i - 1;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cad_um_dos>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <cad_tamanho@plt>
  test   %eax,%eax
  jle    L5
  mov    %eax,%r12d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L38:
  movsbl 0x0(%rbp),%edi
  mov    %r13,%rsi
  add    $0x1,%rbp
  call   <cad_ocorrencias@plt>
  mov    %ebx,%r8d
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L11
  test   %rax,%rax
  je     L38
L7:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  test   %rax,%rax
  jne    L7
L5:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int cad_um_dos(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int flag = 1;
  int i;
  for (i = 0; i < len1 && flag; i++) {
    if (cad_ocorrencias(s1[i], s2))
      flag--;
  }
  if (!flag)
    return i - 1;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<stringCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L9:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jg     L9
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stringCopy(char *string, char *original) {
  uint8_t i = 0;
  while (original[i] > 0) {
    string[i] = original[i];
    i++;
  }
  string[i] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stringCopy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  jle    L8
  mov    $0x0,%eax
L28:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jg     L28
L6:
  movb   $0x0,(%rdi,%rax,1)
  ret
L8:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
void stringCopy(char *string, char *original) {
  uint8_t i = 0;
  while (original[i] > 0) {
    string[i] = original[i];
    i++;
  }
  string[i] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stringCopy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  jle    L7
  xor    %eax,%eax
  nopl   (%rax)
L15:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jg     L15
  add    %rax,%rdi
L7:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void stringCopy(char *string, char *original) {
  uint8_t i = 0;
  while (original[i] > 0) {
    string[i] = original[i];
    i++;
  }
  string[i] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stringCopy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  jle    L5
  xor    %eax,%eax
  nopl   (%rax)
L1:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jg     L1
  add    %rax,%rdi
L5:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void stringCopy(char *string, char *original) {
  uint8_t i = 0;
  while (original[i] > 0) {
    string[i] = original[i];
    i++;
  }
  string[i] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<http_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <http_error_page_init@plt>
  test   %eax,%eax
  jne    L31
  mov    $0x0,%eax
  call   <http_parse_init@plt>
  test   %eax,%eax
  jne    L19
  mov    $0x0,%eax
  call   <http_mime_init@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  jmp    L44
L2:
  nop
  mov    $0x0,%eax
  call   <http_parse_destroy@plt>
  jmp    L37
L19:
  nop
L37:
  mov    $0x0,%eax
  call   <http_error_page_destroy@plt>
  jmp    L3
L31:
  nop
L3:
  mov    $0xfffffffc,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
extern int http_init() {
  if ((0) != http_error_page_init(NULL))
    goto error_page_err;
  if ((0) != http_parse_init())
    goto parse_init_err;
  if ((0) != http_mime_init())
    goto mime_init_err;
  return (0);
mime_init_err:
  http_parse_destroy();
parse_init_err:
  http_error_page_destroy();
error_page_err:
  return (-4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<http_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <http_error_page_init@plt>
  test   %eax,%eax
  jne    L39
  call   <http_parse_init@plt>
  test   %eax,%eax
  jne    L21
  call   <http_mime_init@plt>
  test   %eax,%eax
  jne    L25
L6:
  add    $0x8,%rsp
  ret
L25:
  mov    $0x0,%eax
  call   <http_parse_destroy@plt>
L21:
  mov    $0x0,%eax
  call   <http_error_page_destroy@plt>
  mov    $0xfffffffc,%eax
  jmp    L6
L39:
  mov    $0xfffffffc,%eax
  jmp    L6
```

assistant: ```c
extern int http_init() {
  if ((0) != http_error_page_init(NULL))
    goto error_page_err;
  if ((0) != http_parse_init())
    goto parse_init_err;
  if ((0) != http_mime_init())
    goto mime_init_err;
  return (0);
mime_init_err:
  http_parse_destroy();
parse_init_err:
  http_error_page_destroy();
error_page_err:
  return (-4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<http_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <http_error_page_init@plt>
  test   %eax,%eax
  jne    L47
  call   <http_parse_init@plt>
  test   %eax,%eax
  jne    L9
  call   <http_mime_init@plt>
  test   %eax,%eax
  jne    L45
L29:
  add    $0x8,%rsp
  ret
L45:
  xor    %eax,%eax
  call   <http_parse_destroy@plt>
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <http_error_page_destroy@plt>
  mov    $0xfffffffc,%eax
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L47:
  mov    $0xfffffffc,%eax
  jmp    L29
```

assistant: ```c
extern int http_init() {
  if ((0) != http_error_page_init(NULL))
    goto error_page_err;
  if ((0) != http_parse_init())
    goto parse_init_err;
  if ((0) != http_mime_init())
    goto mime_init_err;
  return (0);
mime_init_err:
  http_parse_destroy();
parse_init_err:
  http_error_page_destroy();
error_page_err:
  return (-4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<http_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <http_error_page_init@plt>
  test   %eax,%eax
  jne    L18
  call   <http_parse_init@plt>
  test   %eax,%eax
  jne    L42
  call   <http_mime_init@plt>
  test   %eax,%eax
  jne    L14
L44:
  add    $0x8,%rsp
  ret
L14:
  xor    %eax,%eax
  call   <http_parse_destroy@plt>
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  call   <http_error_page_destroy@plt>
  mov    $0xfffffffc,%eax
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0xfffffffc,%eax
  jmp    L44
```

assistant: ```c
extern int http_init() {
  if ((0) != http_error_page_init(NULL))
    goto error_page_err;
  if ((0) != http_parse_init())
    goto parse_init_err;
  if ((0) != http_mime_init())
    goto mime_init_err;
  return (0);
mime_init_err:
  http_parse_destroy();
parse_init_err:
  http_error_page_destroy();
error_page_err:
  return (-4);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ROL64_35>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0x23,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_35(uint64_t x) {
  __asm__("rolq $35, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<ROL64_35>:
  endbr64
  mov    %rdi,%rax
  rol    $0x23,%rax
  ret
```

assistant: ```c
uint64_t ROL64_35(uint64_t x) {
  __asm__("rolq $35, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ROL64_35>:
  endbr64
  mov    %rdi,%rax
  rol    $0x23,%rax
  ret
```

assistant: ```c
uint64_t ROL64_35(uint64_t x) {
  __asm__("rolq $35, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ROL64_35>:
  endbr64
  mov    %rdi,%rax
  rol    $0x23,%rax
  ret
```

assistant: ```c
uint64_t ROL64_35(uint64_t x) {
  __asm__("rolq $35, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pmem_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L11
  mov    -0x18(%rbp),%rax
  jmp    L26
L11:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <PMEM_ALLOC@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L26
L28:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <PMEM_FREE@plt>
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

assistant: ```c
void *pmem_realloc(void *ptr, unsigned size, unsigned newsize) {
  if (size >= newsize) {
    return ptr;
  }
  void *newmem = PMEM_ALLOC(newsize);
  if (!newmem) {
    return 0;
  }
  memcpy(newmem, ptr, size);
  PMEM_FREE(ptr, size);
  return newmem;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pmem_realloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    %edx,%esi
  jb     L35
L15:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    %esi,%ebp
  mov    %edx,%edi
  call   <PMEM_ALLOC@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <PMEM_FREE@plt>
  mov    %r12,%rbx
  jmp    L15
L11:
  mov    %rax,%rbx
  jmp    L15
```

assistant: ```c
void *pmem_realloc(void *ptr, unsigned size, unsigned newsize) {
  if (size >= newsize) {
    return ptr;
  }
  void *newmem = PMEM_ALLOC(newsize);
  if (!newmem) {
    return 0;
  }
  memcpy(newmem, ptr, size);
  PMEM_FREE(ptr, size);
  return newmem;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pmem_realloc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  cmp    %edx,%esi
  jb     L9
L23:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edx,%edi
  mov    %esi,%ebp
  call   <PMEM_ALLOC@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L20
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %rbx,%r12
  call   <PMEM_FREE@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %r12d,%r12d
  jmp    L23
```

assistant: ```c
void *pmem_realloc(void *ptr, unsigned size, unsigned newsize) {
  if (size >= newsize) {
    return ptr;
  }
  void *newmem = PMEM_ALLOC(newsize);
  if (!newmem) {
    return 0;
  }
  memcpy(newmem, ptr, size);
  PMEM_FREE(ptr, size);
  return newmem;
}
```