ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bits_to_byte>:
  endbr64
  cmpb   $0x0,0x10(%rsp)
  setg   %al
  cmpb   $0x0,0x8(%rsp)
  setg   %r10b
  test   %r9b,%r9b
  setg   %r9b
  lea    (%r10,%rax,2),%eax
  test   %r8b,%r8b
  setg   %r8b
  lea    (%r9,%rax,2),%eax
  test   %cl,%cl
  setg   %cl
  lea    (%r8,%rax,2),%eax
  test   %dl,%dl
  setg   %dl
  lea    (%rcx,%rax,2),%eax
  test   %sil,%sil
  lea    (%rdx,%rax,2),%eax
  setg   %dl
  test   %dil,%dil
  lea    (%rdx,%rax,2),%eax
  setg   %dl
  lea    (%rdx,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bits_to_byte(char bt0, char bt1, char bt2, char bt3, char bt4, char bt5, char bt6, char bt7) {
  unsigned char rbyte;
  if (bt0 > 0)
    bt0 = 1;
  else
    bt0 = 0;
  if (bt1 > 0)
    bt1 = 1;
  else
    bt1 = 0;
  if (bt2 > 0)
    bt2 = 1;
  else
    bt2 = 0;
  if (bt3 > 0)
    bt3 = 1;
  else
    bt3 = 0;
  if (bt4 > 0)
    bt4 = 1;
  else
    bt4 = 0;
  if (bt5 > 0)
    bt5 = 1;
  else
    bt5 = 0;
  if (bt6 > 0)
    bt6 = 1;
  else
    bt6 = 0;
  if (bt7 > 0)
    bt7 = 1;
  else
    bt7 = 0;
  rbyte = (unsigned char)(bt0 + (2 * bt1) + (4 * bt2) + (8 * bt3) + (16 * bt4) + (32 * bt5) + (64 * bt6) + (128 * bt7));
  return (rbyte);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ldexpd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x3f,%rax
  mov    %eax,-0x2c(%rbp)
  lea    0x10(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x34,%rax
  and    $0x7ff,%eax
  mov    %eax,-0x30(%rbp)
  lea    0x10(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xfffffffffffff,%rdx
  and    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jne    L53
  fldz
  jmp    L15
L53:
  cmpl   $0x7ff,-0x30(%rbp)
  jne    L10
  fldt   0x10(%rbp)
  jmp    L15
L10:
  mov    -0x34(%rbp),%eax
  add    %eax,-0x30(%rbp)
  cmpl   $0x7fe,-0x30(%rbp)
  jle    L4
  movl   $0x7ff,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L76
L4:
  cmpl   $0x0,-0x30(%rbp)
  jns    L76
  movl   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
L76:
  lea    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0x2c(%rbp),%eax
  shl    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  shl    $0x14,%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  shr    $0x20,%rax
  mov    %eax,%ecx
  lea    -0x20(%rbp),%rax
  add    $0x4,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  fldt   -0x20(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L60
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

assistant: ```c
long double ldexpd(long double c1, int expo) {
  int xexp, xsign;
  unsigned long long mant;
  long double x;
  xsign = ((*(unsigned long long *)(&c1)) >> (63)) & 1;
  xexp = ((*(unsigned long long *)(&c1)) >> (52)) & 0x7ff;
  mant = ((*(unsigned long long *)(&c1)) & 0xFFFFFFFFFFFFF);
  if (xexp == 0)
    return (0);
  else if (xexp == 2047)
    return (c1);
  xexp += expo;
  if (xexp > 2046) {
    xexp = 0x7FF;
    mant = 0;
  } else if (xexp < 0) {
    xexp = 0;
    mant = 0;
  }
  *((unsigned int *)&x) = (unsigned int)mant;
  *((unsigned int *)&x + 1) = (xsign << 31) + (((unsigned int)xexp) << 20) + (unsigned int)(mant >> (32));
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ldexpd>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x30(%rsp),%rdx
  mov    %rdx,%rax
  shr    $0x34,%rax
  and    $0x7ff,%eax
  je     L10
  fldt   0x30(%rsp)
  cmp    $0x7ff,%eax
  je     L52
  fstp   %st(0)
  add    %edi,%eax
  cmp    $0x7fe,%eax
  jg     L63
  movabs $0xfffffffffffff,%rcx
  and    %rdx,%rcx
  test   %eax,%eax
  jns    L34
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L34
L63:
  mov    $0x0,%ecx
  mov    $0x7ff,%eax
L34:
  mov    %ecx,(%rsp)
  shl    $0x14,%eax
  shr    $0x20,%rcx
  add    %ecx,%eax
  shr    $0x3f,%rdx
  shl    $0x1f,%edx
  add    %edx,%eax
  mov    %eax,0x4(%rsp)
  fldt   (%rsp)
L52:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  ret
L10:
  fldz
  jmp    L52
L12:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double ldexpd(long double c1, int expo) {
  int xexp, xsign;
  unsigned long long mant;
  long double x;
  xsign = ((*(unsigned long long *)(&c1)) >> (63)) & 1;
  xexp = ((*(unsigned long long *)(&c1)) >> (52)) & 0x7ff;
  mant = ((*(unsigned long long *)(&c1)) & 0xFFFFFFFFFFFFF);
  if (xexp == 0)
    return (0);
  else if (xexp == 2047)
    return (c1);
  xexp += expo;
  if (xexp > 2046) {
    xexp = 0x7FF;
    mant = 0;
  } else if (xexp < 0) {
    xexp = 0;
    mant = 0;
  }
  *((unsigned int *)&x) = (unsigned int)mant;
  *((unsigned int *)&x + 1) = (xsign << 31) + (((unsigned int)xexp) << 20) + (unsigned int)(mant >> (32));
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ldexpd>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x30(%rsp),%rdx
  mov    %rdx,%rax
  shr    $0x34,%rax
  and    $0x7ff,%eax
  je     L4
  fldt   0x30(%rsp)
  cmp    $0x7ff,%eax
  je     L12
  fstp   %st(0)
  add    %edi,%eax
  cmp    $0x7fe,%eax
  jle    L71
  mov    $0x7ff00000,%eax
  xor    %esi,%esi
L1:
  shr    $0x3f,%rdx
  mov    %esi,(%rsp)
  shl    $0x1f,%edx
  add    %eax,%edx
  mov    %edx,0x4(%rsp)
  fldt   (%rsp)
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x28,%rsp
  ret
L71:
  test   %eax,%eax
  js     L22
  movabs $0xfffffffffffff,%rcx
  shl    $0x14,%eax
  and    %rdx,%rcx
  mov    %ecx,%esi
  shr    $0x20,%rcx
  add    %ecx,%eax
  jmp    L1
  xchg   %ax,%ax
L4:
  fldz
  jmp    L12
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L1
L74:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double ldexpd(long double c1, int expo) {
  int xexp, xsign;
  unsigned long long mant;
  long double x;
  xsign = ((*(unsigned long long *)(&c1)) >> (63)) & 1;
  xexp = ((*(unsigned long long *)(&c1)) >> (52)) & 0x7ff;
  mant = ((*(unsigned long long *)(&c1)) & 0xFFFFFFFFFFFFF);
  if (xexp == 0)
    return (0);
  else if (xexp == 2047)
    return (c1);
  xexp += expo;
  if (xexp > 2046) {
    xexp = 0x7FF;
    mant = 0;
  } else if (xexp < 0) {
    xexp = 0;
    mant = 0;
  }
  *((unsigned int *)&x) = (unsigned int)mant;
  *((unsigned int *)&x + 1) = (xsign << 31) + (((unsigned int)xexp) << 20) + (unsigned int)(mant >> (32));
  return (x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldexpd>:
  endbr64
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rax
  shr    $0x34,%rax
  and    $0x7ff,%eax
  je     L53
  fldt   0x8(%rsp)
  cmp    $0x7ff,%eax
  je     L13
  fstp   %st(0)
  add    %edi,%eax
  cmp    $0x7fe,%eax
  jle    L24
  mov    $0x7ff00000,%eax
  pxor   %xmm0,%xmm0
L54:
  shr    $0x3f,%rdx
  fldz
  movdqa %xmm0,%xmm1
  shl    $0x1f,%edx
  fstpt  -0x18(%rsp)
  lea    (%rdx,%rax,1),%ecx
  mov    -0x10(%rsp),%edx
  movd   %ecx,%xmm2
  punpckldq %xmm2,%xmm1
  mov    %edx,-0x10(%rsp)
  movq   %xmm1,-0x18(%rsp)
  fldt   -0x18(%rsp)
  ret
  nopl   (%rax)
L53:
  fldz
L13:
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  test   %eax,%eax
  js     L52
  movabs $0xfffffffffffff,%rcx
  shl    $0x14,%eax
  and    %rdx,%rcx
  movd   %ecx,%xmm0
  shr    $0x20,%rcx
  add    %ecx,%eax
  jmp    L54
L52:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L54
```

assistant: ```c
long double ldexpd(long double c1, int expo) {
  int xexp, xsign;
  unsigned long long mant;
  long double x;
  xsign = ((*(unsigned long long *)(&c1)) >> (63)) & 1;
  xexp = ((*(unsigned long long *)(&c1)) >> (52)) & 0x7ff;
  mant = ((*(unsigned long long *)(&c1)) & 0xFFFFFFFFFFFFF);
  if (xexp == 0)
    return (0);
  else if (xexp == 2047)
    return (c1);
  xexp += expo;
  if (xexp > 2046) {
    xexp = 0x7FF;
    mant = 0;
  } else if (xexp < 0) {
    xexp = 0;
    mant = 0;
  }
  *((unsigned int *)&x) = (unsigned int)mant;
  *((unsigned int *)&x + 1) = (xsign << 31) + (((unsigned int)xexp) << 20) + (unsigned int)(mant >> (32));
  return (x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L6
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <recursiveGx@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <iterativeGx@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D33
type: string

tool: D30: %d

tool: D9: 
invalid

tool: D10: 
function value recursive : %d


tool: D33: 
function value iterative : %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n < 0) {
    printf("\ninvalid\n");
    return -1;
  }
  printf("\nfunction value recursive : %d\n", recursiveGx(n));
  printf("\nfunction value iterative : %d\n", iterativeGx(n));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L7
  call   <recursiveGx@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <iterativeGx@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L7:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D37: %d

tool: D4: 
function value recursive : %d


tool: D7: 
function value iterative : %d


tool: D0: 
invalid

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n < 0) {
    printf("\ninvalid\n");
    return -1;
  }
  printf("\nfunction value recursive : %d\n", recursiveGx(n));
  printf("\nfunction value iterative : %d\n", iterativeGx(n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D34(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L1
  call   <recursiveGx@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <iterativeGx@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  ret
L1:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L10
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string

tool: D34: %d

tool: D35: 
function value recursive : %d


tool: D11: 
function value iterative : %d


tool: D12: 
invalid

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n < 0) {
    printf("\ninvalid\n");
    return -1;
  }
  printf("\nfunction value recursive : %d\n", recursiveGx(n));
  printf("\nfunction value iterative : %d\n", iterativeGx(n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  js     L27
  call   <recursiveGx@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <iterativeGx@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L27:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L24
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D38
type: string
name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D14
type: string
name: disassemble_data
arguments: data_tag: D24
type: string

tool: D38: %d

tool: D6: 
function value recursive : %d


tool: D14: 
function value iterative : %d


tool: D24: 
invalid

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n < 0) {
    printf("\ninvalid\n");
    return -1;
  }
  printf("\nfunction value recursive : %d\n", recursiveGx(n));
  printf("\nfunction value iterative : %d\n", iterativeGx(n));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_stpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_stpcpy(char *dest, const char *src) {
  char *d = dest;
  const char *s = src;
  do
    *d++ = *s;
  while (*s++ != '\0');
  return d - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_stpcpy>:
  endbr64
L2:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  mov    %al,-0x1(%rdi)
  add    $0x1,%rsi
  test   %al,%al
  jne    L2
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *my_stpcpy(char *dest, const char *src) {
  char *d = dest;
  const char *s = src;
  do
    *d++ = *s;
  while (*s++ != '\0');
  return d - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_stpcpy>:
  endbr64
  nopl   0x0(%rax)
L9:
  movzbl (%rsi),%eax
  mov    %rdi,%r8
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L9
  mov    %r8,%rax
  ret
```

assistant: ```c
char *my_stpcpy(char *dest, const char *src) {
  char *d = dest;
  const char *s = src;
  do
    *d++ = *s;
  while (*s++ != '\0');
  return d - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_stpcpy>:
  endbr64
  nopl   0x0(%rax)
L6:
  movzbl (%rsi),%eax
  mov    %rdi,%r8
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L6
  mov    %r8,%rax
  ret
```

assistant: ```c
char *my_stpcpy(char *dest, const char *src) {
  char *d = dest;
  const char *s = src;
  do
    *d++ = *s;
  while (*s++ != '\0');
  return d - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dg2ch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movsbl -0x18(%rbp),%edx
  movsbl -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpb   $0x2f,-0x14(%rbp)
  jle    L37
  cmpb   $0x39,-0x14(%rbp)
  jg     L37
  movsbl -0x14(%rbp),%eax
  sub    $0x30,%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L37:
  cmpb   $0x60,-0x14(%rbp)
  jle    L95
  cmpb   $0x7a,-0x14(%rbp)
  jg     L95
  movsbl -0x14(%rbp),%eax
  sub    $0x57,%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L95:
  cmpb   $0x40,-0x14(%rbp)
  jle    L140
  cmpb   $0x5a,-0x14(%rbp)
  jg     L140
  movsbl -0x14(%rbp),%eax
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L140:
  movl   $0x0,-0x4(%rbp)
L10:
  cmpb   $0x2f,-0x18(%rbp)
  jle    L74
  cmpb   $0x39,-0x18(%rbp)
  jg     L74
  movsbl -0x18(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,-0x4(%rbp)
  jmp    L9
L74:
  cmpb   $0x60,-0x18(%rbp)
  jle    L12
  cmpb   $0x7a,-0x18(%rbp)
  jg     L12
  movsbl -0x18(%rbp),%eax
  sub    $0x57,%eax
  add    %eax,-0x4(%rbp)
  jmp    L9
L12:
  cmpb   $0x40,-0x18(%rbp)
  jle    L9
  cmpb   $0x5a,-0x18(%rbp)
  jg     L9
  movsbl -0x18(%rbp),%eax
  sub    $0x37,%eax
  add    %eax,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D14
type: string

tool: D2: dg2ch: %02x %02x


tool: D14: dg2ch: tmp=%02X


assistant: ```c
int dg2ch(char c1, char c2) {
  printf("dg2ch: %02x %02x\n", c1, c2);
  int tmp;
  if (c1 >= '0' && c1 <= '9')
    tmp = (c1 - '0') * 0x10;
  else if (c1 >= 'a' && c1 <= 'z')
    tmp = (c1 - 'a' + 10) * 0x10;
  else if (c1 >= 'A' && c1 <= 'Z')
    tmp = (c1 - 'A' + 10) * 0x10;
  else
    tmp = 0;
  if (c2 >= '0' && c2 <= '9')
    tmp += c2 - '0';
  else if (c2 >= 'a' && c2 <= 'z')
    tmp += c2 - 'a' + 10;
  else if (c2 >= 'A' && c2 <= 'Z')
    tmp += c2 - 'A' + 10;
  printf("dg2ch: tmp=%02X\n", tmp);
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dg2ch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  movsbl %sil,%ebp
  movsbl %dil,%ebx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%r13),%eax
  cmp    $0x9,%al
  ja     L44
  sub    $0x30,%ebx
  shl    $0x4,%ebx
L72:
  lea    -0x30(%r12),%eax
  cmp    $0x9,%al
  ja     L36
  lea    -0x30(%rbp,%rbx,1),%ebx
L46:
  mov    %ebx,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  lea    -0x61(%r13),%eax
  cmp    $0x19,%al
  ja     L9
  sub    $0x57,%ebx
  shl    $0x4,%ebx
  jmp    L72
L9:
  lea    -0x41(%r13),%edx
  sub    $0x37,%ebx
  shl    $0x4,%ebx
  cmp    $0x1a,%dl
  mov    $0x0,%eax
  cmovae %eax,%ebx
  jmp    L72
L36:
  lea    -0x61(%r12),%eax
  cmp    $0x19,%al
  ja     L30
  lea    -0x57(%rbp,%rbx,1),%ebx
  jmp    L46
L30:
  lea    -0x41(%r12),%eax
  lea    -0x37(%rbp,%rbx,1),%edx
  cmp    $0x1a,%al
  cmovb  %edx,%ebx
  jmp    L46
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string

tool: D4: dg2ch: %02x %02x


tool: D10: dg2ch: tmp=%02X


assistant: ```c
int dg2ch(char c1, char c2) {
  printf("dg2ch: %02x %02x\n", c1, c2);
  int tmp;
  if (c1 >= '0' && c1 <= '9')
    tmp = (c1 - '0') * 0x10;
  else if (c1 >= 'a' && c1 <= 'z')
    tmp = (c1 - 'a' + 10) * 0x10;
  else if (c1 >= 'A' && c1 <= 'Z')
    tmp = (c1 - 'A' + 10) * 0x10;
  else
    tmp = 0;
  if (c2 >= '0' && c2 <= '9')
    tmp += c2 - '0';
  else if (c2 >= 'a' && c2 <= 'z')
    tmp += c2 - 'a' + 10;
  else if (c2 >= 'A' && c2 <= 'Z')
    tmp += c2 - 'A' + 10;
  printf("dg2ch: tmp=%02X\n", tmp);
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<dg2ch>:
  endbr64
  push   %r13
  movsbl %sil,%r13d
  xor    %eax,%eax
  push   %r12
  movsbl %dil,%r12d
  mov    %r13d,%edx
  push   %rbp
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  mov    %r12d,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%al
  ja     L50
  sub    $0x30,%r12d
  shl    $0x4,%r12d
L68:
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L57
L23:
  lea    -0x30(%r13,%r12,1),%r12d
L26:
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  lea    -0x61(%rbp),%eax
  cmp    $0x19,%al
  ja     L39
  sub    $0x57,%r12d
  lea    -0x30(%rbx),%eax
  shl    $0x4,%r12d
  cmp    $0x9,%al
  jbe    L23
L57:
  lea    -0x61(%rbx),%eax
  cmp    $0x19,%al
  ja     L61
  lea    -0x57(%r13,%r12,1),%r12d
  jmp    L26
  nopl   0x0(%rax)
L61:
  sub    $0x41,%ebx
  lea    -0x37(%r13,%r12,1),%eax
  cmp    $0x1a,%bl
  cmovb  %eax,%r12d
  jmp    L26
  nopl   0x0(%rax)
L39:
  sub    $0x37,%r12d
  sub    $0x41,%ebp
  xor    %eax,%eax
  shl    $0x4,%r12d
  cmp    $0x1a,%bpl
  cmovae %eax,%r12d
  jmp    L68
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D16
type_infered: string

tool: D1: dg2ch: %02x %02x


tool: D16: dg2ch: tmp=%02X


assistant: ```c
int dg2ch(char c1, char c2) {
  printf("dg2ch: %02x %02x\n", c1, c2);
  int tmp;
  if (c1 >= '0' && c1 <= '9')
    tmp = (c1 - '0') * 0x10;
  else if (c1 >= 'a' && c1 <= 'z')
    tmp = (c1 - 'a' + 10) * 0x10;
  else if (c1 >= 'A' && c1 <= 'Z')
    tmp = (c1 - 'A' + 10) * 0x10;
  else
    tmp = 0;
  if (c2 >= '0' && c2 <= '9')
    tmp += c2 - '0';
  else if (c2 >= 'a' && c2 <= 'z')
    tmp += c2 - 'a' + 10;
  else if (c2 >= 'A' && c2 <= 'Z')
    tmp += c2 - 'A' + 10;
  printf("dg2ch: tmp=%02X\n", tmp);
  return tmp;
}
```