ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<print_array>:
  endbr64
  cmp    %edx,%esi
  jge    L1
  sub    $0x1,%edx
  movslq %esi,%rax
  push   %r12
  lea    D1(%rip),%r12
  sub    %esi,%edx
  push   %rbp
  add    %rax,%rdx
  push   %rbx
  lea    (%rdi,%rax,4),%rbx
  lea    (%rdi,%rdx,4),%rbp
  mov    (%rbx),%esi
  cmp    %rbp,%rbx
  je     L18
  nopl   (%rax)
L0:
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  mov    (%rbx),%esi
  cmp    %rbp,%rbx
  jne    L0
L18:
  pop    %rbx
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
L1:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string

tool: D1: %d 

tool: D17: %d


assistant: ```c
void print_array(int a[], int start, int length) {
  for (int i = start; i < length; ++i) {
    if (i + 1 < length) {
      printf("%d ", a[i]);
    } else {
      printf("%d\n", a[i]);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_array>:
  endbr64
  cmp    %edx,%esi
  jge    L10
  mov    %esi,%eax
  movslq %esi,%rcx
  lea    0x1(%rax),%r8d
  mov    (%rdi,%rcx,4),%esi
  lea    0x0(,%rcx,4),%r9
  cmp    %r8d,%edx
  jle    L20
  sub    $0x2,%edx
  push   %r12
  sub    %eax,%edx
  push   %rbp
  lea    D23(%rip),%rbp
  lea    (%rdx,%rcx,1),%rax
  push   %rbx
  lea    0x4(%rdi,%r9,1),%rbx
  lea    0x8(%rdi,%rax,4),%r12
  nop
L12:
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  lea    D20(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L20:
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
L10:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D20
type: string

tool: D23: %d 

tool: D20: %d


assistant: ```c
void print_array(int a[], int start, int length) {
  for (int i = start; i < length; ++i) {
    if (i + 1 < length) {
      printf("%d ", a[i]);
    } else {
      printf("%d\n", a[i]);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_rw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <can_read@plt>
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <can_write@plt>
  test   %rax,%rax
  je     L24
  mov    $0x1,%eax
  jmp    L18
L24:
  mov    $0x0,%eax
  jmp    L18
L0:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

assistant: ```c
int get_rw(char *current_addr) {
  if (can_read(current_addr)) {
    if (can_write(current_addr)) {
      return 1;
    }
    return 0;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_rw>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <can_read@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L3
L4:
  pop    %rbx
  ret
L3:
  mov    %rbx,%rdi
  call   <can_write@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
```

assistant: ```c
int get_rw(char *current_addr) {
  if (can_read(current_addr)) {
    if (can_write(current_addr)) {
      return 1;
    }
    return 0;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_rw>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <can_read@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L4
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  mov    %rbp,%rdi
  call   <can_write@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int get_rw(char *current_addr) {
  if (can_read(current_addr)) {
    if (can_write(current_addr)) {
      return 1;
    }
    return 0;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_rw>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <can_read@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L1
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  call   <can_write@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int get_rw(char *current_addr) {
  if (can_read(current_addr)) {
    if (can_write(current_addr)) {
      return 1;
    }
    return 0;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WatchdogUnlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40000000,-0x4(%rbp)
  je     L11
  cmpl   $0x40001000,-0x4(%rbp)
  jne    L29
L11:
  mov    $0x1,%eax
  jmp    L14
L29:
  mov    $0x0,%eax
L14:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0xc00,%eax
  cltq
  movl   $0x1acce551,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: Translate the below assembly code into C programming language:

```asm
<WatchdogUnlock>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0xc00,%ebx
  movslq %ebx,%rbx
  movl   $0x1acce551,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<WatchdogUnlock>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  add    $0xc00,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  movl   $0x1acce551,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WatchdogUnlock>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  add    $0xc00,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  movl   $0x1acce551,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogUnlock(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000C00))) = 0x1ACCE551;
}
```
user: What is the c source code of the assembly code below?

```asm
<dec2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  movl   $0x0,-0x6c(%rbp)
L31:
  mov    -0x78(%rbp),%rax
  and    $0x1,%eax
  mov    %eax,-0x64(%rbp)
  mov    -0x78(%rbp),%rax
  shr    %rax
  mov    %rax,-0x78(%rbp)
  mov    -0x64(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x70(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x70(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  cmpq   $0x0,-0x78(%rbp)
  jne    L31
  mov    -0x70(%rbp),%eax
  mov    %eax,-0x68(%rbp)
  jmp    L41
L48:
  mov    -0x6c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x6c(%rbp)
  movslq %eax,%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
  addl   $0x1,-0x68(%rbp)
L41:
  cmpl   $0x3f,-0x68(%rbp)
  jle    L48
  jmp    L54
L1:
  subl   $0x1,-0x70(%rbp)
  mov    -0x6c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x6c(%rbp)
  movslq %eax,%rdx
  mov    -0x80(%rbp),%rax
  add    %rax,%rdx
  mov    -0x70(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
L54:
  cmpl   $0x0,-0x70(%rbp)
  jns    L1
  mov    -0x6c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
void dec2bin(unsigned long long decimal, char *binary) {
  int k = 0, n = 0;
  int remain;
  char temp[80];
  do {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  } while (decimal > 0);
  for (int j = k; j < 64; j++)
    binary[n++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dec2bin>:
  endbr64
  sub    $0x68,%rsp
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r10
L6:
  mov    %edi,%edx
  and    $0x1,%edx
  mov    %rdi,%rcx
  shr    %rdi
  mov    %eax,%r8d
  add    $0x30,%edx
  mov    %dl,(%r10,%rax,1)
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    $0x1,%rcx
  ja     L6
  cmp    $0x3f,%r8d
  jg     L68
  mov    %r9,%rax
  mov    $0x3f,%edx
  sub    %r8d,%edx
  lea    0x1(%r9,%rdx,1),%rdx
L31:
  movb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L31
  mov    $0x40,%edi
  sub    %esi,%edi
L0:
  test   %r8d,%r8d
  js     L12
  movslq %r8d,%rax
  lea    (%rsp,%rax,1),%rdx
  movslq %edi,%rcx
  lea    (%r9,%rcx,1),%rax
  mov    %esi,%esi
  lea    0x1(%r9,%rsi,1),%rsi
  add    %rcx,%rsi
L28:
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L28
  lea    0x1(%r8,%rdi,1),%edi
L12:
  movslq %edi,%rdi
  movb   $0x0,-0x1(%r9,%rdi,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x68,%rsp
  ret
L68:
  mov    $0x0,%edi
  jmp    L0
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dec2bin(unsigned long long decimal, char *binary) {
  int k = 0, n = 0;
  int remain;
  char temp[80];
  do {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  } while (decimal > 0);
  for (int j = k; j < 64; j++)
    binary[n++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dec2bin>:
  endbr64
  push   %rbx
  mov    %rsi,%r11
  mov    $0x1,%edx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsp),%r10
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %edi,%eax
  mov    %rdi,%rcx
  mov    %rdx,%rsi
  mov    %edx,%r9d
  and    $0x1,%eax
  movslq %edx,%r8
  shr    %rdi
  add    $0x30,%eax
  mov    %al,(%r10,%rdx,1)
  lea    0x1(%rsi),%rdx
  cmp    $0x1,%rcx
  ja     L18
  cmp    $0x3f,%r9d
  jg     L58
  movabs $0x3030303030303030,%r10
  mov    $0x40,%edx
  sub    %r9d,%edx
  cmp    $0x8,%edx
  jb     L65
  mov    %edx,%ecx
  lea    0x8(%r11),%rdi
  mov    %r10,(%r11)
  and    $0xfffffffffffffff8,%rdi
  mov    %r10,-0x8(%r11,%rcx,1)
  mov    %r11,%rcx
  sub    %rdi,%rcx
  add    %ecx,%edx
  and    $0xfffffff8,%edx
  cmp    $0x8,%edx
  jb     L76
  and    $0xfffffff8,%edx
  xor    %ecx,%ecx
L56:
  mov    %ecx,%ebx
  add    $0x8,%ecx
  mov    %r10,(%rdi,%rbx,1)
  cmp    %edx,%ecx
  jb     L56
L76:
  mov    $0x40,%edx
  sub    %r9d,%edx
L82:
  movslq %edx,%r9
  lea    0x1(%r11,%rsi,1),%rdi
  lea    (%rsp,%r8,1),%rcx
  lea    (%r11,%r9,1),%r10
  add    %r9,%rdi
  mov    %r10,%rdx
  jmp    L25
  xchg   %ax,%ax
L109:
  movzbl -0x1(%rcx),%eax
L25:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %rdi,%rdx
  jne    L109
  movb   $0x0,(%r10,%rsi,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  add    $0x60,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L65:
  test   $0x4,%dl
  jne    L66
  test   %edx,%edx
  je     L76
  movb   $0x30,(%r11)
  test   $0x2,%dl
  je     L76
  mov    $0x3030,%ecx
  mov    %cx,-0x2(%r11,%rdx,1)
  jmp    L76
  nop
L58:
  xor    %edx,%edx
  jmp    L82
L66:
  movl   $0x30303030,(%r11)
  movl   $0x30303030,-0x4(%r11,%rdx,1)
  jmp    L76
L112:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dec2bin(unsigned long long decimal, char *binary) {
  int k = 0, n = 0;
  int remain;
  char temp[80];
  do {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  } while (decimal > 0);
  for (int j = k; j < 64; j++)
    binary[n++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dec2bin>:
  endbr64
  sub    $0x68,%rsp
  mov    %rsi,%r11
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r10
  nopl   0x0(%rax,%rax,1)
L118:
  mov    %edi,%edx
  mov    %rdi,%rsi
  mov    %rax,%rcx
  mov    %eax,%r9d
  and    $0x1,%edx
  movslq %eax,%r8
  shr    %rdi
  add    $0x30,%edx
  mov    %dl,(%r10,%rax,1)
  lea    0x1(%rcx),%rax
  cmp    $0x1,%rsi
  ja     L118
  cmp    $0x3f,%r9d
  jg     L18
  movabs $0x3030303030303030,%rdi
  mov    $0x40,%eax
  sub    %r9d,%eax
  cmp    $0x8,%eax
  jb     L24
  mov    %eax,%edx
  lea    0x8(%r11),%rsi
  mov    %rdi,(%r11)
  and    $0xfffffffffffffff8,%rsi
  mov    %rdi,-0x8(%r11,%rdx,1)
  mov    %r11,%rdx
  sub    %rsi,%rdx
  add    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L68
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L74:
  mov    %edx,%r10d
  add    $0x8,%edx
  mov    %rdi,(%rsi,%r10,1)
  cmp    %eax,%edx
  jb     L74
L68:
  mov    $0x40,%esi
  sub    %r9d,%esi
L102:
  movslq %esi,%rsi
  lea    (%rsp,%r8,1),%rdx
  lea    0x1(%r11,%rcx,1),%rdi
  lea    (%r11,%rsi,1),%r8
  add    %rsi,%rdi
  mov    %r8,%rax
  nopl   (%rax)
L11:
  movzbl -0x1(%rdx),%esi
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %sil,-0x1(%rax)
  cmp    %rdi,%rax
  jne    L11
  movb   $0x0,(%r8,%rcx,1)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  add    $0x68,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  test   $0x4,%al
  jne    L107
  test   %eax,%eax
  je     L68
  movb   $0x30,(%r11)
  test   $0x2,%al
  je     L68
  mov    $0x3030,%edx
  mov    %dx,-0x2(%r11,%rax,1)
  jmp    L68
  nopl   (%rax)
L18:
  xor    %esi,%esi
  jmp    L102
L107:
  movl   $0x30303030,(%r11)
  movl   $0x30303030,-0x4(%r11,%rax,1)
  jmp    L68
L119:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dec2bin(unsigned long long decimal, char *binary) {
  int k = 0, n = 0;
  int remain;
  char temp[80];
  do {
    remain = decimal % 2;
    decimal = decimal / 2;
    temp[k++] = remain + '0';
  } while (decimal > 0);
  for (int j = k; j < 64; j++)
    binary[n++] = '0';
  while (k >= 0)
    binary[n++] = temp[--k];
  binary[n - 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rowswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L56
L41:
  mov    -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <abs@plt>
  test   %eax,%eax
  jle    L42
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L38:
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L38
  jmp    L46
L42:
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L41
  nop
L46:
  nop
  leave
  ret
```

assistant: ```c
void rowswap(float *array, int j, int n) {
  int i, k;
  for (i = j + 1; i < n - 1; i++) {
    if (abs(*(array + (n)*i + j)) > 0.01) {
      for (k = j; k < n; k++) {
        float tmp = *(array + n * j + k);
        *(array + n * j + k) = *(array + n * i + k);
        *(array + n * i + k) = tmp;
      }
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rowswap>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x1(%rsi),%ebp
  lea    -0x1(%rdx),%eax
  cmp    %eax,%ebp
  jge    L33
  mov    %esi,%r15d
  mov    %edx,%r14d
  movslq %edx,%rax
  mov    %rax,(%rsp)
  mov    %ebp,%eax
  imul   %edx,%eax
  mov    %eax,0x14(%rsp)
  movslq %eax,%rbx
  lea    -0x1(%rdx),%r12d
  movslq %esi,%rax
  mov    %rax,0x18(%rsp)
  lea    (%rdi,%rax,4),%r13
L14:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%r13,%rbx,4),%xmm0
  call   <abs@plt>
  test   %eax,%eax
  jg     L48
  add    $0x1,%ebp
  add    (%rsp),%rbx
  cmp    %r12d,%ebp
  jne    L14
L33:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  cmp    %r14d,%r15d
  jge    L33
  mov    0x14(%rsp),%edx
  sub    %r14d,%edx
  movslq %edx,%rdx
  mov    0x18(%rsp),%rcx
  add    %rdx,%rcx
  mov    0x8(%rsp),%rsi
  lea    (%rsi,%rcx,4),%rax
  sub    %r15d,%r12d
  add    %rcx,%r12
  lea    0x4(%rsi,%r12,4),%rcx
  sub    %rdx,%rbx
L43:
  movss  (%rax),%xmm0
  movss  (%rax,%rbx,4),%xmm1
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rax,%rbx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L43
  jmp    L33
```

assistant: ```c
void rowswap(float *array, int j, int n) {
  int i, k;
  for (i = j + 1; i < n - 1; i++) {
    if (abs(*(array + (n)*i + j)) > 0.01) {
      for (k = j; k < n; k++) {
        float tmp = *(array + n * j + k);
        *(array + n * j + k) = *(array + n * i + k);
        *(array + n * i + k) = tmp;
      }
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rowswap>:
  endbr64
  push   %r15
  push   %r14
  lea    0x1(%rsi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x18(%rsp)
  cmp    %ebx,%r14d
  jge    L37
  mov    %r14d,%eax
  movslq %esi,%rcx
  mov    %edx,%r13d
  movslq %edx,%r12
  imul   %edx,%eax
  mov    %rcx,0x10(%rsp)
  lea    (%rdi,%rcx,4),%rbp
  mov    %eax,0x1c(%rsp)
  movslq %eax,%r15
  jmp    L63
  nopl   0x0(%rax)
L60:
  add    $0x1,%r14d
  add    %r12,%r15
  cmp    %ebx,%r14d
  je     L37
L63:
  movss  0x0(%rbp,%r15,4),%xmm1
  pxor   %xmm0,%xmm0
  movss  %xmm1,0x4(%rsp)
  cvtss2sd %xmm1,%xmm0
  call   <abs@plt>
  movss  0x4(%rsp),%xmm1
  test   %eax,%eax
  jle    L60
  mov    0x18(%rsp),%edi
  cmp    %r13d,%edi
  jge    L37
  mov    0x1c(%rsp),%ecx
  mov    0x10(%rsp),%rsi
  sub    %edi,%ebx
  mov    0x8(%rsp),%rdx
  sub    %r13d,%ecx
  movslq %ecx,%rcx
  add    %rcx,%rsi
  add    %rsi,%rbx
  lea    (%rdx,%rsi,4),%rax
  lea    0x4(%rdx,%rbx,4),%rsi
  mov    %r15,%rdx
  sub    %rcx,%rdx
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L62:
  movss  (%rax,%rdx,4),%xmm1
L43:
  movss  (%rax),%xmm0
  movss  %xmm1,(%rax)
  movss  %xmm0,(%rax,%rdx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L62
L37:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void rowswap(float *array, int j, int n) {
  int i, k;
  for (i = j + 1; i < n - 1; i++) {
    if (abs(*(array + (n)*i + j)) > 0.01) {
      for (k = j; k < n; k++) {
        float tmp = *(array + n * j + k);
        *(array + n * j + k) = *(array + n * i + k);
        *(array + n * i + k) = tmp;
      }
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<writeInitDebugLines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D77
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D62
datatype: string
name: disassemble_data
arguments: data_label: D66
datatype: string
name: disassemble_data
arguments: data_label: D20
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D76
datatype: string

tool: D77: Autopuppet v1.0.0

tool: D16: ---

tool: D62: Updates: github.com/williamtdr/autopuppet

tool: 

tool: D20: Waiting for you to start the program.

tool: D25: Place your hand on the joystick and move your robot into position.

tool: D76: When you're ready to start, set the mode to Teleop: Running.

assistant: ```c
void writeInitDebugLines() {
  writeDebugStreamLine("Autopuppet v1.0.0");
  writeDebugStreamLine("---");
  writeDebugStreamLine("Updates: github.com/williamtdr/autopuppet");
  writeDebugStreamLine("");
  writeDebugStreamLine("Waiting for you to start the program.");
  writeDebugStreamLine("Place your hand on the joystick and move your robot into position.");
  writeDebugStreamLine("When you're ready to start, set the mode to Teleop: Running.");
  writeDebugStreamLine("");
}
```