ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_block>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rcx,%r15
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x4(%rsp)
  mov    0xa0(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%ecx
  cmp    $0x1,%edx
  jle    L41
  lea    0x4(%rdi),%rbx
  lea    -0x2(%rdx),%eax
  lea    0x8(%rdi,%rax,4),%rbp
  mov    %rbx,%rax
L37:
  cmp    %ecx,(%rax)
  jl     L76
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L37
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  movslq (%r14),%rax
  mov    0x0(%r13,%rax,8),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    D5(%rip),%r14
L7:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  movslq (%rbx),%rax
  mov    0x0(%r13,%rax,8),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L7
L43:
  lea    0x10(%rsp),%rbp
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbp,%r8
  mov    %ebx,%ecx
  mov    %r15,%rdx
  mov    %r12,%rdi
  call   <apply_rule_cpu@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    0x4(%rsp),%edx
  jne    L28
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L76:
  mov    $0x0,%eax
L28:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  movslq (%r14),%rax
  mov    0x0(%r13,%rax,8),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L43
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5:  

assistant: ```c
int process_block(int o[64], char *block_ptr[64], int block_cnt, char *word_buf, char final_buf[64], int final_len, char rule_buf[64]) {
  int last_o = o[0];
  for (int i = 1; i < block_cnt; i++) {
    if (o[i] < last_o)
      return (0);
  }
  memset(rule_buf, 0, 64);
  strcat(rule_buf, block_ptr[o[0]]);
  int i;
  for (i = 1; i < block_cnt; i++) {
    strcat(rule_buf, " ");
    strcat(rule_buf, block_ptr[o[i]]);
  }
  char out_buf[64];
  memset(out_buf, 0, sizeof(out_buf));
  int out_len = apply_rule_cpu(rule_buf, strlen(rule_buf), word_buf, strlen(word_buf), out_buf);
  if (out_len == final_len) {
    if (memcmp(final_buf, out_buf, out_len) == 0)
      return (1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_block>:
  endbr64
  push   %r15
  mov    %edx,%eax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %r8,0x8(%rsp)
  mov    0xa0(%rsp),%r14
  mov    %r9d,0x4(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  mov    (%rdi),%edx
  cmp    $0x1,%eax
  jle    L74
  sub    $0x2,%eax
  lea    0x4(%rdi),%rbx
  lea    0x8(%rdi,%rax,4),%r13
  mov    %rbx,%rax
  jmp    L22
  nopl   0x0(%rax)
L8:
  add    $0x4,%rax
  cmp    %r13,%rax
  je     L28
L22:
  cmp    %edx,(%rax)
  jge    L8
L68:
  xor    %eax,%eax
L66:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movslq (%r15),%rax
  mov    %r14,%rdi
  lea    D2(%rip),%r15
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  xchg   %ax,%ax
L69:
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbx
  call   <strcat@plt>
  movslq -0x4(%rbx),%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L69
L27:
  lea    0x10(%rsp),%rbp
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r15d
  call   <strlen@plt>
  mov    %rbp,%r8
  mov    %r15d,%ecx
  mov    %r12,%rdx
  mov    %eax,%esi
  mov    %r14,%rdi
  call   <apply_rule_cpu@plt>
  cmp    0x4(%rsp),%eax
  jne    L68
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L66
L74:
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    $0x40,%edx
  call   <memset@plt>
  movslq (%r15),%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  jmp    L27
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2:  

assistant: ```c
int process_block(int o[64], char *block_ptr[64], int block_cnt, char *word_buf, char final_buf[64], int final_len, char rule_buf[64]) {
  int last_o = o[0];
  for (int i = 1; i < block_cnt; i++) {
    if (o[i] < last_o)
      return (0);
  }
  memset(rule_buf, 0, 64);
  strcat(rule_buf, block_ptr[o[0]]);
  int i;
  for (i = 1; i < block_cnt; i++) {
    strcat(rule_buf, " ");
    strcat(rule_buf, block_ptr[o[i]]);
  }
  char out_buf[64];
  memset(out_buf, 0, sizeof(out_buf));
  int out_len = apply_rule_cpu(rule_buf, strlen(rule_buf), word_buf, strlen(word_buf), out_buf);
  if (out_len == final_len) {
    if (memcmp(final_buf, out_buf, out_len) == 0)
      return (1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_block>:
  endbr64
  push   %r15
  mov    %edx,%eax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %r8,0x8(%rsp)
  mov    0xa0(%rsp),%r14
  mov    %r9d,0x4(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  mov    (%rdi),%edx
  cmp    $0x1,%eax
  jle    L25
  sub    $0x2,%eax
  lea    0x4(%rdi),%rbx
  lea    0x8(%rdi,%rax,4),%r13
  mov    %rbx,%rax
  jmp    L50
  nopl   0x0(%rax)
L86:
  add    $0x4,%rax
  cmp    %r13,%rax
  je     L46
L50:
  cmp    %edx,(%rax)
  jge    L86
L49:
  xor    %eax,%eax
L44:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movslq (%r15),%rax
  mov    %r14,%rdi
  lea    D5(%rip),%r15
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  xchg   %ax,%ax
L18:
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbx
  call   <strcat@plt>
  movslq -0x4(%rbx),%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L18
L6:
  lea    0x10(%rsp),%rbp
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r15d
  call   <strlen@plt>
  mov    %rbp,%r8
  mov    %r15d,%ecx
  mov    %r12,%rdx
  mov    %eax,%esi
  mov    %r14,%rdi
  call   <apply_rule_cpu@plt>
  cmp    0x4(%rsp),%eax
  jne    L49
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L44
L25:
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    $0x40,%edx
  call   <memset@plt>
  movslq (%r15),%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,8),%rsi
  call   <strcat@plt>
  jmp    L6
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5:  

assistant: ```c
int process_block(int o[64], char *block_ptr[64], int block_cnt, char *word_buf, char final_buf[64], int final_len, char rule_buf[64]) {
  int last_o = o[0];
  for (int i = 1; i < block_cnt; i++) {
    if (o[i] < last_o)
      return (0);
  }
  memset(rule_buf, 0, 64);
  strcat(rule_buf, block_ptr[o[0]]);
  int i;
  for (i = 1; i < block_cnt; i++) {
    strcat(rule_buf, " ");
    strcat(rule_buf, block_ptr[o[i]]);
  }
  char out_buf[64];
  memset(out_buf, 0, sizeof(out_buf));
  int out_len = apply_rule_cpu(rule_buf, strlen(rule_buf), word_buf, strlen(word_buf), out_buf);
  if (out_len == final_len) {
    if (memcmp(final_buf, out_buf, out_len) == 0)
      return (1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<generic_unplug_device>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__generic_unplug_device@plt>
  nop
  leave
  ret
```

assistant: ```c
void generic_unplug_device(struct request_queue *q) {
  unsigned long temp;
  unsigned long temp___0;
  __generic_unplug_device(q);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generic_unplug_device>:
  endbr64
  sub    $0x8,%rsp
  call   <__generic_unplug_device@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void generic_unplug_device(struct request_queue *q) {
  unsigned long temp;
  unsigned long temp___0;
  __generic_unplug_device(q);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generic_unplug_device>:
  endbr64
  jmp    1050 <__generic_unplug_device@plt>
```

assistant: ```c
void generic_unplug_device(struct request_queue *q) {
  unsigned long temp;
  unsigned long temp___0;
  __generic_unplug_device(q);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generic_unplug_device>:
  endbr64
  jmp    1050 <__generic_unplug_device@plt>
```

assistant: ```c
void generic_unplug_device(struct request_queue *q) {
  unsigned long temp;
  unsigned long temp___0;
  __generic_unplug_device(q);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0xa,-0x4(%rbp)
  jle    L8
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0xa,-0x4(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D16: En el do while... El numero es: %d


tool: D14: en el for ... El numero es: %d


assistant: ```c
int main() {
  int i = 0;
  do {
    printf("En el do while... El numero es: %d\n", i++);
  } while (i <= 10);
  for (i = 0; i <= 10; i++) {
    printf("en el for ... El numero es: %d\n", i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D18(%rip),%rbp
L0:
  mov    %ebx,%esi
  add    $0x1,%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  mov    $0x0,%ebx
  lea    D12(%rip),%rbp
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L17
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D12
datatype: string

tool: D18: En el do while... El numero es: %d


tool: D12: en el for ... El numero es: %d


assistant: ```c
int main() {
  int i = 0;
  do {
    printf("En el do while... El numero es: %d\n", i++);
  } while (i <= 10);
  for (i = 0; i <= 10; i++) {
    printf("en el for ... El numero es: %d\n", i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L16
  xor    %ebx,%ebx
  lea    D4(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D2: En el do while... El numero es: %d


tool: D4: en el for ... El numero es: %d


assistant: ```c
int main() {
  int i = 0;
  do {
    printf("En el do while... El numero es: %d\n", i++);
  } while (i <= 10);
  for (i = 0; i <= 10; i++) {
    printf("en el for ... El numero es: %d\n", i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L13
  xor    %ebx,%ebx
  lea    D7(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D4: En el do while... El numero es: %d


tool: D7: en el for ... El numero es: %d


assistant: ```c
int main() {
  int i = 0;
  do {
    printf("En el do while... El numero es: %d\n", i++);
  } while (i <= 10);
  for (i = 0; i <= 10; i++) {
    printf("en el for ... El numero es: %d\n", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x84(%rbp)
  je     L13
  cmpl   $0x1e,-0x84(%rbp)
  jmp    L25
L13:
  nop
L25:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void f1(int v) {
  int a1[30];
  switch (v) {
  case 1:
    break;
  case 30:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
void f1(int v) {
  int a1[30];
  switch (v) {
  case 1:
    break;
  case 30:
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
void f1(int v) {
  int a1[30];
  switch (v) {
  case 1:
    break;
  case 30:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f1>:
  endbr64
  ret
```

assistant: ```c
void f1(int v) {
  int a1[30];
  switch (v) {
  case 1:
    break;
  case 30:
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<save_snapshot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <put_msg@plt>
  mov    $0x0,%eax
  call   <spif_get_filename@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <save_snapshot_file@plt>
  jmp    L4
L1:
  nop
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: Enter name of snapshot file to save:

assistant: ```c
void save_snapshot(void) {
  char *name;
  put_msg("Enter name of snapshot file to save:");
  name = spif_get_filename();
  if (name == NULL)
    return;
  save_snapshot_file(name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<save_snapshot>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <put_msg@plt>
  mov    $0x0,%eax
  call   <spif_get_filename@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <save_snapshot_file@plt>
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9: Enter name of snapshot file to save:

assistant: ```c
void save_snapshot(void) {
  char *name;
  put_msg("Enter name of snapshot file to save:");
  name = spif_get_filename();
  if (name == NULL)
    return;
  save_snapshot_file(name);
}
```
user: Translate the below assembly code into C programming language:

```asm
<save_snapshot>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <put_msg@plt>
  xor    %eax,%eax
  call   <spif_get_filename@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1080 <save_snapshot_file@plt>
  nopl   0x0(%rax)
L7:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: Enter name of snapshot file to save:

assistant: ```c
void save_snapshot(void) {
  char *name;
  put_msg("Enter name of snapshot file to save:");
  name = spif_get_filename();
  if (name == NULL)
    return;
  save_snapshot_file(name);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<save_snapshot>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <put_msg@plt>
  xor    %eax,%eax
  call   <spif_get_filename@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1080 <save_snapshot_file@plt>
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: Enter name of snapshot file to save:

assistant: ```c
void save_snapshot(void) {
  char *name;
  put_msg("Enter name of snapshot file to save:");
  name = spif_get_filename();
  if (name == NULL)
    return;
  save_snapshot_file(name);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x1,-0x30(%rbp)
  jbe    L25
  movq   $0x0,-0x10(%rbp)
  jmp    L11
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rcx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  sub    -0x10(%rbp),%rsi
  mov    $0x0,%edx
  div    %rsi
  lea    0x1(%rax),%rdi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x10(%rbp)
L11:
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L6
L25:
  nop
  leave
  ret
```

assistant: ```c
void shuffle(int *array, size_t n) {
  size_t i, j;
  int t;
  if (n > 1) {
    for (i = 0; i < n - 1; i++) {
      j = i + rand() / (RAND_MAX / (n - i) + 1);
      t = array[j];
      array[j] = array[i];
      array[i] = t;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  lea    -0x1(%rsi),%r13
  mov    $0x0,%ebx
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rsi
  mov    %r12,%rcx
  sub    %rbx,%rcx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  div    %rcx
  lea    0x1(%rax),%rcx
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    %rbx,%rax
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%edx
  mov    0x0(%rbp,%rbx,4),%ecx
  mov    %ecx,(%rax)
  mov    %edx,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

assistant: ```c
void shuffle(int *array, size_t n) {
  size_t i, j;
  int t;
  if (n > 1) {
    for (i = 0; i < n - 1; i++) {
      j = i + rand() / (RAND_MAX / (n - i) + 1);
      t = array[j];
      array[j] = array[i];
      array[i] = t;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L10
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    -0x1(%rsi),%r13
  push   %r12
  mov    D2(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L13:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rcx
  xor    %edx,%edx
  mov    %rax,%r8
  mov    (%r12),%rax
  sub    %rbx,%rcx
  div    %rcx
  xor    %edx,%edx
  lea    0x1(%rax),%rcx
  mov    %r8,%rax
  div    %rcx
  mov    (%r14,%rbx,4),%ecx
  add    %rbx,%rax
  lea    (%r14,%rax,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %edx,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void shuffle(int *array, size_t n) {
  size_t i, j;
  int t;
  if (n > 1) {
    for (i = 0; i < n - 1; i++) {
      j = i + rand() / (RAND_MAX / (n - i) + 1);
      t = array[j];
      array[j] = array[i];
      array[i] = t;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L19
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    -0x1(%rsi),%r13
  push   %r12
  mov    D2(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rcx
  xor    %edx,%edx
  mov    %rax,%r8
  mov    (%r12),%rax
  sub    %rbx,%rcx
  div    %rcx
  xor    %edx,%edx
  lea    0x1(%rax),%rcx
  mov    %r8,%rax
  div    %rcx
  mov    (%r14,%rbx,4),%ecx
  add    %rbx,%rax
  lea    (%r14,%rax,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %edx,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void shuffle(int *array, size_t n) {
  size_t i, j;
  int t;
  if (n > 1) {
    for (i = 0; i < n - 1; i++) {
      j = i + rand() / (RAND_MAX / (n - i) + 1);
      t = array[j];
      array[j] = array[i];
      array[i] = t;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L14
  mov    -0x8(%rbp),%rax
  jmp    L9
L14:
  mov    -0x10(%rbp),%rax
L9:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t max(uint32_t a, uint32_t b) {
  if (a > b)
    return a;
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovge %rdi,%rax
  ret
```

assistant: ```c
uint32_t max(uint32_t a, uint32_t b) {
  if (a > b)
    return a;
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovge %rdi,%rax
  ret
```

assistant: ```c
uint32_t max(uint32_t a, uint32_t b) {
  if (a > b)
    return a;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovge %rdi,%rax
  ret
```

assistant: ```c
uint32_t max(uint32_t a, uint32_t b) {
  if (a > b)
    return a;
  return b;
}
```