ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<cdflib_negative_binomial_cdf_values>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    (%rax),%ecx
  lea    0x1(%rcx),%r9d
  mov    %r9d,(%rax)
  cmp    $0x1b,%r9d
  jle    L3
  movl   $0x0,(%rax)
  movl   $0x0,(%rdi)
  movl   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  pxor   %xmm0,%xmm0
L8:
  movsd  %xmm0,(%r8)
  ret
L3:
  movslq %ecx,%rcx
  lea    D24(%rip),%r9
  mov    (%r9,%rcx,4),%ecx
  mov    %ecx,(%rdi)
  mov    (%rax),%edi
  lea    -0x1(%rdi),%ecx
  movslq %ecx,%rcx
  lea    D4(%rip),%rdi
  mov    (%rdi,%rcx,4),%ecx
  mov    %ecx,(%rsi)
  mov    (%rax),%esi
  lea    -0x1(%rsi),%ecx
  movslq %ecx,%rcx
  lea    D29(%rip),%rsi
  movsd  (%rsi,%rcx,8),%xmm0
  movsd  %xmm0,(%rdx)
  mov    (%rax),%eax
  sub    $0x1,%eax
  cltq
  lea    D38(%rip),%rdx
  movsd  (%rdx,%rax,8),%xmm0
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: tag: D24
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D29
datatype: f64
name: disassemble_data
arguments: tag: D38
datatype: f64

tool: D24: 

tool: D4: 

tool: D29: 0.5

tool: D38: 0.6367

assistant: ```c
void cdflib_negative_binomial_cdf_values(int *n_data, int *f, int *s, double *p, double *cdf) {
  enum { N_MAX = 27 };
  static const double cdf_vec[N_MAX] = {0.6367, 0.3633, 0.1445, 0.5000, 0.2266, 0.0625, 0.3438, 0.1094, 0.0156, 0.1792, 0.0410, 0.0041, 0.0705, 0.0109, 0.0007, 0.9862, 0.9150, 0.7472, 0.8499, 0.5497, 0.2662, 0.6513, 0.2639, 0.0702, 1.0000, 0.0199, 0.0001};
  static const int f_vec[N_MAX] = {4, 3, 2, 3, 2, 1, 2, 1, 0, 2, 1, 0, 2, 1, 0, 11, 10, 9, 17, 16, 15, 9, 8, 7, 2, 1, 0};
  static const double p_vec[N_MAX] = {0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.40, 0.40, 0.40, 0.30, 0.30, 0.30, 0.30, 0.30, 0.30, 0.10, 0.10, 0.10, 0.10, 0.10, 0.10, 0.01, 0.01, 0.01};
  static const int s_vec[N_MAX] = {4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 1, 2, 3, 1, 2, 3, 1, 2, 3, 0, 1, 2};
  if (n_data < 0) {
    *n_data = 0;
  }
  *n_data = *n_data + 1;
  if (N_MAX < *n_data) {
    *n_data = 0;
    *f = 0;
    *s = 0;
    *p = 0.0E+00;
    *cdf = 0.0E+00;
  } else {
    *f = f_vec[*n_data - 1];
    *s = s_vec[*n_data - 1];
    *p = p_vec[*n_data - 1];
    *cdf = cdf_vec[*n_data - 1];
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cdflib_negative_binomial_cdf_values>:
  endbr64
  mov    %rcx,%r9
  movslq (%rdi),%rcx
  mov    %rdi,%rax
  lea    0x1(%rcx),%edi
  mov    %edi,(%rax)
  cmp    $0x1b,%edi
  jle    L6
  pxor   %xmm0,%xmm0
  movl   $0x0,(%rax)
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  movq   $0x0,(%r9)
  movsd  %xmm0,(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D28(%rip),%rdi
  mov    (%rdi,%rcx,4),%ecx
  mov    %ecx,(%rsi)
  mov    (%rax),%esi
  lea    -0x1(%rsi),%ecx
  lea    D9(%rip),%rsi
  movslq %ecx,%rcx
  mov    (%rsi,%rcx,4),%ecx
  mov    %ecx,(%rdx)
  mov    (%rax),%eax
  lea    D35(%rip),%rdx
  sub    $0x1,%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  lea    D12(%rip),%rdx
  movsd  %xmm0,(%r9)
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%r8)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D35
data_type: f64
name: unpack_data
arguments: data_label: D12
data_type: f64

tool: D28: 

tool: D9: 

tool: D35: 0.5

tool: D12: 0.6367

assistant: ```c
void cdflib_negative_binomial_cdf_values(int *n_data, int *f, int *s, double *p, double *cdf) {
  enum { N_MAX = 27 };
  static const double cdf_vec[N_MAX] = {0.6367, 0.3633, 0.1445, 0.5000, 0.2266, 0.0625, 0.3438, 0.1094, 0.0156, 0.1792, 0.0410, 0.0041, 0.0705, 0.0109, 0.0007, 0.9862, 0.9150, 0.7472, 0.8499, 0.5497, 0.2662, 0.6513, 0.2639, 0.0702, 1.0000, 0.0199, 0.0001};
  static const int f_vec[N_MAX] = {4, 3, 2, 3, 2, 1, 2, 1, 0, 2, 1, 0, 2, 1, 0, 11, 10, 9, 17, 16, 15, 9, 8, 7, 2, 1, 0};
  static const double p_vec[N_MAX] = {0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.40, 0.40, 0.40, 0.30, 0.30, 0.30, 0.30, 0.30, 0.30, 0.10, 0.10, 0.10, 0.10, 0.10, 0.10, 0.01, 0.01, 0.01};
  static const int s_vec[N_MAX] = {4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 1, 2, 3, 1, 2, 3, 1, 2, 3, 0, 1, 2};
  if (n_data < 0) {
    *n_data = 0;
  }
  *n_data = *n_data + 1;
  if (N_MAX < *n_data) {
    *n_data = 0;
    *f = 0;
    *s = 0;
    *p = 0.0E+00;
    *cdf = 0.0E+00;
  } else {
    *f = f_vec[*n_data - 1];
    *s = s_vec[*n_data - 1];
    *p = p_vec[*n_data - 1];
    *cdf = cdf_vec[*n_data - 1];
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<cdflib_negative_binomial_cdf_values>:
  endbr64
  mov    %rcx,%r9
  movslq (%rdi),%rcx
  mov    %rdi,%rax
  lea    0x1(%rcx),%edi
  mov    %edi,(%rax)
  cmp    $0x1b,%edi
  jle    L5
  pxor   %xmm0,%xmm0
  movl   $0x0,(%rax)
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdx)
  movq   $0x0,(%r9)
  movsd  %xmm0,(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D10(%rip),%rdi
  mov    (%rdi,%rcx,4),%ecx
  mov    %ecx,(%rsi)
  mov    (%rax),%esi
  lea    -0x1(%rsi),%ecx
  lea    D34(%rip),%rsi
  movslq %ecx,%rcx
  mov    (%rsi,%rcx,4),%ecx
  mov    %ecx,(%rdx)
  mov    (%rax),%eax
  lea    D35(%rip),%rdx
  sub    $0x1,%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  lea    D28(%rip),%rdx
  movsd  %xmm0,(%r9)
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%r8)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
datatype: string
name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D35
datatype: f64
name: disassemble_data
arguments: tag: D28
datatype: f64

tool: D10: 

tool: D34: 

tool: D35: 0.5

tool: D28: 0.6367

assistant: ```c
void cdflib_negative_binomial_cdf_values(int *n_data, int *f, int *s, double *p, double *cdf) {
  enum { N_MAX = 27 };
  static const double cdf_vec[N_MAX] = {0.6367, 0.3633, 0.1445, 0.5000, 0.2266, 0.0625, 0.3438, 0.1094, 0.0156, 0.1792, 0.0410, 0.0041, 0.0705, 0.0109, 0.0007, 0.9862, 0.9150, 0.7472, 0.8499, 0.5497, 0.2662, 0.6513, 0.2639, 0.0702, 1.0000, 0.0199, 0.0001};
  static const int f_vec[N_MAX] = {4, 3, 2, 3, 2, 1, 2, 1, 0, 2, 1, 0, 2, 1, 0, 11, 10, 9, 17, 16, 15, 9, 8, 7, 2, 1, 0};
  static const double p_vec[N_MAX] = {0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.50, 0.40, 0.40, 0.40, 0.30, 0.30, 0.30, 0.30, 0.30, 0.30, 0.10, 0.10, 0.10, 0.10, 0.10, 0.10, 0.01, 0.01, 0.01};
  static const int s_vec[N_MAX] = {4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 4, 5, 6, 1, 2, 3, 1, 2, 3, 1, 2, 3, 0, 1, 2};
  if (n_data < 0) {
    *n_data = 0;
  }
  *n_data = *n_data + 1;
  if (N_MAX < *n_data) {
    *n_data = 0;
    *f = 0;
    *s = 0;
    *p = 0.0E+00;
    *cdf = 0.0E+00;
  } else {
    *f = f_vec[*n_data - 1];
    *s = s_vec[*n_data - 1];
    *p = p_vec[*n_data - 1];
    *cdf = cdf_vec[*n_data - 1];
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L19:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  and    %esi,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L28:
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L19
  mov    -0x8(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L36
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L36:
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L24
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i, t;
  char *x = malloc(1000);
  for (i = 0; i < 1000; i++)
    x[i] &= (i & 0xff);
  x = realloc(x, 10000);
  for (i = 0; i < 1000; i++)
    t += x[i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x0,%edx
L9:
  and    %dl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x3e8,%rdx
  jne    L9
  mov    $0x2710,%esi
  call   <realloc@plt>
  mov    $0x3e8,%eax
L14:
  sub    $0x1,%eax
  jne    L14
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i, t;
  char *x = malloc(1000);
  for (i = 0; i < 1000; i++)
    x[i] &= (i & 0xff);
  x = realloc(x, 10000);
  for (i = 0; i < 1000; i++)
    t += x[i];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x3e8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edx,%edx
  mov    %rax,%rdi
  nopw   0x0(%rax,%rax,1)
L8:
  and    %dl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x3e8,%rdx
  jne    L8
  mov    $0x2710,%esi
  call   <realloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i, t;
  char *x = malloc(1000);
  for (i = 0; i < 1000; i++)
    x[i] &= (i & 0xff);
  x = realloc(x, 10000);
  for (i = 0; i < 1000; i++)
    t += x[i];
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x3e8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  movdqa D41(%rip),%xmm3
  movdqa D37(%rip),%xmm9
  movdqa D6(%rip),%xmm8
  mov    %rax,%rdi
  mov    %rax,%rdx
  movdqa D43(%rip),%xmm7
  movdqa D45(%rip),%xmm6
  movdqa D33(%rip),%xmm5
  lea    0x3e0(%rax),%rax
  nopl   0x0(%rax)
L3:
  movdqa %xmm3,%xmm2
  add    $0x10,%rdx
  paddd  %xmm9,%xmm3
  movdqa %xmm2,%xmm4
  movdqa %xmm2,%xmm0
  movdqa %xmm2,%xmm1
  paddd  %xmm8,%xmm4
  punpcklwd %xmm4,%xmm0
  punpckhwd %xmm4,%xmm1
  movdqa %xmm0,%xmm4
  punpcklwd %xmm1,%xmm0
  punpckhwd %xmm1,%xmm4
  movdqa %xmm2,%xmm1
  paddd  %xmm6,%xmm2
  paddd  %xmm7,%xmm1
  punpcklwd %xmm4,%xmm0
  movdqa %xmm1,%xmm4
  punpcklwd %xmm2,%xmm1
  pand   %xmm5,%xmm0
  punpckhwd %xmm2,%xmm4
  movdqa %xmm1,%xmm2
  punpckhwd %xmm4,%xmm2
  punpcklwd %xmm4,%xmm1
  punpcklwd %xmm2,%xmm1
  movdqu -0x10(%rdx),%xmm2
  pand   %xmm5,%xmm1
  packuswb %xmm1,%xmm0
  pand   %xmm2,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rdx,%rax
  jne    L3
  movabs $0xe7e6e5e4e3e2e1e0,%rax
  mov    $0x2710,%esi
  and    %rax,0x3e0(%rdi)
  call   <realloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D41
datatype: byte[16]
name: retrieve_data
arguments: label: D37
datatype: byte[16]
name: retrieve_data
arguments: label: D6
datatype: byte[16]
name: retrieve_data
arguments: label: D43
datatype: byte[16]
name: retrieve_data
arguments: label: D45
datatype: byte[16]
name: retrieve_data
arguments: label: D33
datatype: byte[16]

tool: {"D41": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D37": [0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D43": [0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D45": [0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D33": [0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00]}

assistant: ```c
int main(void) {
  int i, t;
  char *x = malloc(1000);
  for (i = 0; i < 1000; i++)
    x[i] &= (i & 0xff);
  x = realloc(x, 10000);
  for (i = 0; i < 1000; i++)
    t += x[i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dyadup_1D_feed_odd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dyadup_1D_feed_odd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength) {
  int count = 0;
  for (count = 0; count < sigInLength - 1; count++) {
    sigOut[count * 2 + 1] = 0;
    sigOut[count * 2] = sigIn[count];
  }
  sigOut[sigOutLength - 1] = sigIn[sigInLength - 1];
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dyadup_1D_feed_odd>:
  endbr64
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L10
  mov    %rdx,%rax
  lea    -0x2(%rsi),%r8d
  shl    $0x4,%r8
  lea    0x10(%rdx,%r8,1),%r8
L5:
  movq   $0x0,0x8(%rax)
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x10,%rax
  add    $0x8,%rdi
  cmp    %r8,%rax
  jne    L5
L10:
  movslq %esi,%rsi
  movsd  -0x8(%r9,%rsi,8),%xmm0
  movslq %ecx,%rcx
  movsd  %xmm0,-0x8(%rdx,%rcx,8)
  ret
```

assistant: ```c
void dyadup_1D_feed_odd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength) {
  int count = 0;
  for (count = 0; count < sigInLength - 1; count++) {
    sigOut[count * 2 + 1] = 0;
    sigOut[count * 2] = sigIn[count];
  }
  sigOut[sigOutLength - 1] = sigIn[sigInLength - 1];
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dyadup_1D_feed_odd>:
  endbr64
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L3
  lea    -0x2(%rsi),%r8d
  mov    %rdx,%rax
  shl    $0x4,%r8
  lea    0x10(%rdx,%r8,1),%r8
  nopl   0x0(%rax)
L8:
  movq   $0x0,0x8(%rax)
  movsd  (%rdi),%xmm0
  add    $0x10,%rax
  add    $0x8,%rdi
  movsd  %xmm0,-0x10(%rax)
  cmp    %r8,%rax
  jne    L8
L3:
  movslq %esi,%rsi
  movslq %ecx,%rcx
  movsd  -0x8(%r9,%rsi,8),%xmm0
  movsd  %xmm0,-0x8(%rdx,%rcx,8)
  ret
```

assistant: ```c
void dyadup_1D_feed_odd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength) {
  int count = 0;
  for (count = 0; count < sigInLength - 1; count++) {
    sigOut[count * 2 + 1] = 0;
    sigOut[count * 2] = sigIn[count];
  }
  sigOut[sigOutLength - 1] = sigIn[sigInLength - 1];
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dyadup_1D_feed_odd>:
  endbr64
  movslq %ecx,%r8
  cmp    $0x1,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    -0x2(%rsi),%r10d
  lea    (%rdi,%rax,8),%rcx
  mov    %rax,%r9
  cmp    %rcx,%rdx
  setae  %cl
  shl    $0x4,%rax
  add    %rdx,%rax
  cmp    %rax,%rdi
  setae  %al
  or     %al,%cl
  je     L2
  cmp    $0x2,%r10d
  jbe    L2
  mov    %r9d,%ecx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L63:
  movupd (%rdi,%rax,1),%xmm0
  movapd %xmm0,%xmm2
  psrldq $0x8,%xmm0
  unpcklpd %xmm1,%xmm2
  movups %xmm0,0x10(%rdx,%rax,2)
  movups %xmm2,(%rdx,%rax,2)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L63
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%r9d
  je     L12
  lea    (%rcx,%rcx,1),%eax
  movslq %ecx,%rcx
  cltq
  movq   $0x0,0x8(%rdx,%rax,8)
  movsd  (%rdi,%rcx,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
L12:
  movslq %esi,%rsi
  movsd  -0x8(%rdi,%rsi,8),%xmm0
  movsd  %xmm0,-0x8(%rdx,%r8,8)
  ret
  nopl   0x0(%rax)
L2:
  shl    $0x4,%r10
  mov    %rdx,%rax
  mov    %rdi,%rcx
  lea    0x10(%rdx,%r10,1),%r9
  nop
L53:
  movq   $0x0,0x8(%rax)
  movsd  (%rcx),%xmm0
  add    $0x10,%rax
  add    $0x8,%rcx
  movsd  %xmm0,-0x10(%rax)
  cmp    %r9,%rax
  jne    L53
  jmp    L12
```

assistant: ```c
void dyadup_1D_feed_odd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength) {
  int count = 0;
  for (count = 0; count < sigInLength - 1; count++) {
    sigOut[count * 2 + 1] = 0;
    sigOut[count * 2] = sigIn[count];
  }
  sigOut[sigOutLength - 1] = sigIn[sigInLength - 1];
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<libj_fishman>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movzwl %ax,%eax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  sar    $0x10,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  imul   $0xff5,%rax,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  imul   $0xff5,%rax,%rdx
  mov    -0x28(%rbp),%rax
  sar    $0x10,%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x10,%rax
  and    $0x7fff0000,%eax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  movzwl %ax,%eax
  or     %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  sar    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  and    $0x7fff0000,%eax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  movzwl %ax,%eax
  or     %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  shl    $0x10,%rax
  and    $0x7fff0000,%eax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sar    $0xf,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  sar    $0xf,%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  sar    $0xf,%rax
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    $0x7fffffff,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jg     L7
  addq   $0x7fffffff,-0x48(%rbp)
L7:
  mov    -0x48(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long libj_fishman(sn)
long sn;
{
  long L, H;
  long p, q;
  long P;
  long Hi, Lo;
  L = sn & 0xffff;
  H = sn >> 16;
  q = 0xff5 * L;
  p = 0xff5 * H + (q >> 16);
  q = ((p & 0x7fff) << 16) | (q & 0xffff);
  P = H + (L >> 16);
  L = ((P & 0x7fff) << 16) | (L & 0xffff);
  Lo = q + ((L & 0x7fff) << 16);
  Hi = (p >> 15) + (P >> 15) + ((L & 0x7fff8000) >> 15);
  sn = Lo - 0x7fffffff;
  sn += Hi;
  if (sn <= 0) {
    sn += 0x7fffffff;
  }
  return (sn);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<libj_fishman>:
  endbr64
  movzwl %di,%eax
  imul   $0xff5,%rax,%rax
  mov    %rdi,%rdx
  sar    $0x10,%rdx
  imul   $0xff5,%rdx,%rdx
  mov    %rax,%rcx
  sar    $0x10,%rcx
  add    %rcx,%rdx
  movzwl %ax,%esi
  mov    %rdi,%rcx
  and    $0x7fffffff,%ecx
  mov    %rdx,%rax
  sar    $0xf,%rax
  sar    $0x1f,%rdi
  add    %rdi,%rax
  mov    %rcx,%rdi
  sar    $0xf,%rdi
  add    %rdi,%rax
  shl    $0x10,%rdx
  and    $0x7fff0000,%edx
  or     %rsi,%rdx
  shl    $0x10,%rcx
  and    $0x7fff0000,%ecx
  lea    -0x7fffffff(%rdx,%rcx,1),%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long libj_fishman(sn)
long sn;
{
  long L, H;
  long p, q;
  long P;
  long Hi, Lo;
  L = sn & 0xffff;
  H = sn >> 16;
  q = 0xff5 * L;
  p = 0xff5 * H + (q >> 16);
  q = ((p & 0x7fff) << 16) | (q & 0xffff);
  P = H + (L >> 16);
  L = ((P & 0x7fff) << 16) | (L & 0xffff);
  Lo = q + ((L & 0x7fff) << 16);
  Hi = (p >> 15) + (P >> 15) + ((L & 0x7fff8000) >> 15);
  sn = Lo - 0x7fffffff;
  sn += Hi;
  if (sn <= 0) {
    sn += 0x7fffffff;
  }
  return (sn);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libj_fishman>:
  endbr64
  movzwl %di,%eax
  mov    %rdi,%rdx
  imul   $0xff5,%rax,%rax
  sar    $0x10,%rdx
  imul   $0xff5,%rdx,%rdx
  mov    %rax,%rcx
  movzwl %ax,%esi
  sar    $0x10,%rcx
  add    %rcx,%rdx
  mov    %rdi,%rcx
  sar    $0x1f,%rdi
  mov    %rdx,%rax
  and    $0x7fffffff,%ecx
  shl    $0x10,%rdx
  sar    $0xf,%rax
  and    $0x7fff0000,%edx
  add    %rdi,%rax
  mov    %rcx,%rdi
  shl    $0x10,%rcx
  or     %rsi,%rdx
  sar    $0xf,%rdi
  and    $0x7fff0000,%ecx
  add    %rdi,%rax
  lea    -0x7fffffff(%rdx,%rcx,1),%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long libj_fishman(sn)
long sn;
{
  long L, H;
  long p, q;
  long P;
  long Hi, Lo;
  L = sn & 0xffff;
  H = sn >> 16;
  q = 0xff5 * L;
  p = 0xff5 * H + (q >> 16);
  q = ((p & 0x7fff) << 16) | (q & 0xffff);
  P = H + (L >> 16);
  L = ((P & 0x7fff) << 16) | (L & 0xffff);
  Lo = q + ((L & 0x7fff) << 16);
  Hi = (p >> 15) + (P >> 15) + ((L & 0x7fff8000) >> 15);
  sn = Lo - 0x7fffffff;
  sn += Hi;
  if (sn <= 0) {
    sn += 0x7fffffff;
  }
  return (sn);
}
```
user: What is the c source code of the assembly code below:

```asm
<libj_fishman>:
  endbr64
  movzwl %di,%eax
  mov    %rdi,%rdx
  imul   $0xff5,%rax,%rax
  sar    $0x10,%rdx
  imul   $0xff5,%rdx,%rdx
  mov    %rax,%rcx
  movzwl %ax,%esi
  sar    $0x10,%rcx
  add    %rcx,%rdx
  mov    %rdi,%rcx
  sar    $0x1f,%rdi
  mov    %rdx,%rax
  and    $0x7fffffff,%ecx
  shl    $0x10,%rdx
  sar    $0xf,%rax
  and    $0x7fff0000,%edx
  add    %rdi,%rax
  mov    %rcx,%rdi
  shl    $0x10,%rcx
  or     %rsi,%rdx
  sar    $0xf,%rdi
  and    $0x7fff0000,%ecx
  add    %rdi,%rax
  lea    -0x7fffffff(%rdx,%rcx,1),%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  test   %rax,%rax
  cmovle %rdx,%rax
  ret
```

assistant: ```c
long libj_fishman(sn)
long sn;
{
  long L, H;
  long p, q;
  long P;
  long Hi, Lo;
  L = sn & 0xffff;
  H = sn >> 16;
  q = 0xff5 * L;
  p = 0xff5 * H + (q >> 16);
  q = ((p & 0x7fff) << 16) | (q & 0xffff);
  P = H + (L >> 16);
  L = ((P & 0x7fff) << 16) | (L & 0xffff);
  Lo = q + ((L & 0x7fff) << 16);
  Hi = (p >> 15) + (P >> 15) + ((L & 0x7fff8000) >> 15);
  sn = Lo - 0x7fffffff;
  sn += Hi;
  if (sn <= 0) {
    sn += 0x7fffffff;
  }
  return (sn);
}
```