ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_login>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x458,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  mov    %rsp,%r13
  lea    0x40(%rsp),%r12
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <login_input@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <packet_pack_login_req@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <send_fix_len@plt>
  cmp    $0xffffffff,%eax
  je     L36
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv_packet@plt>
  test   %eax,%eax
  jle    L36
  mov    %r12,%rdi
  call   <packet_unpack_login_resp@plt>
  mov    %eax,%edi
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L24
L36:
  mov    0x448(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x458,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  call   <packet_disp_err@plt>
  mov    $0x2,%eax
  jmp    L36
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_login(int sockfd) {
  int ret = 0;
  char name[32];
  char password[32];
  char packet[1024];
  login_input(name, password);
  ret = packet_pack_login_req(packet, name, password);
  ret = send_fix_len(sockfd, packet, ret);
  if (-1 == ret) {
    goto exit;
  }
  ret = recv_packet(sockfd, packet);
  if (ret <= 0) {
    goto exit;
  }
  ret = packet_unpack_login_resp(packet);
  if (0 == ret) {
    ret = 1;
  } else {
    packet_disp_err(ret);
    ret = 2;
  }
exit:
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xdc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L22
L25:
  lea    -0xd0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xd4(%rbp)
L22:
  mov    -0xdc(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jl     L25
  lea    -0xd8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xd8(%rbp),%edx
  mov    -0xdc(%rbp),%ecx
  lea    -0xd0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <threeSumClosest@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string

tool: D15: %d

tool: D33: %d


assistant: ```c
int main() {
  int a[50];
  int i, n, x;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &x);
  printf("%d\n", threeSumClosest(a, n, x));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L26
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L12
L26:
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <threeSumClosest@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0xe0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string

tool: D16: %d

tool: D17: %d


assistant: ```c
int main() {
  int a[50];
  int i, n, x;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &x);
  printf("%d\n", threeSumClosest(a, n, x));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    %r13,%rbp
  test   %eax,%eax
  jle    L6
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L14
L6:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    %r13,%rdi
  call   <threeSumClosest@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D6: %d

tool: D4: %d


assistant: ```c
int main() {
  int a[50];
  int i, n, x;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &x);
  printf("%d\n", threeSumClosest(a, n, x));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    %r13,%rbp
  test   %eax,%eax
  jle    L11
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L0
L11:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edx
  mov    %r13,%rdi
  call   <threeSumClosest@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string

tool: D11: %d

tool: D13: %d


assistant: ```c
int main() {
  int a[50];
  int i, n, x;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &x);
  printf("%d\n", threeSumClosest(a, n, x));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_box>:
  endbr64
  movsd  0x18(%rdi),%xmm1
  subsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x20(%rdi),%xmm0
  subsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x28(%rdi),%xmm0
  subsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  D4(%rip),%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  %xmm2,(%rdx)
  movapd %xmm0,%xmm1
  divsd  0x8(%rsi),%xmm1
  movsd  %xmm1,0x8(%rdx)
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x38(%rdi),%xmm1
  movsd  %xmm1,0x20(%rsi)
  movsd  0x30(%rdi),%xmm1
  movsd  %xmm1,0x28(%rsi)
  movq   D6(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rsi),%xmm1
  movsd  0x18(%rsi),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movapd %xmm1,%xmm3
  mulsd  0x20(%rsi),%xmm3
  subsd  %xmm3,%xmm0
  mulsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x28(%rsi),%xmm0
  xorpd  %xmm2,%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: f64
name: retrieve_data
arguments: data_label: D6
type_infered: byte[8]

tool: D4: 1

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void set_box(double box[3][3], double *h, double *h_inv) {
  h[0] = box[1][0] - box[0][0];
  h[1] = box[1][1] - box[0][1];
  h[2] = box[1][2] - box[0][2];
  h_inv[0] = 1.0 / h[0];
  h_inv[1] = 1.0 / h[1];
  h_inv[2] = 1.0 / h[2];
  h[3] = box[2][2];
  h[4] = box[2][1];
  h[5] = box[2][0];
  h_inv[3] = -h[3] / (h[1] * h[2]);
  h_inv[4] = (h[3] * h[5] - h[1] * h[4]) / (h[0] * h[1] * h[2]);
  h_inv[5] = -h[5] / (h[0] * h[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_box>:
  endbr64
  movsd  0x18(%rdi),%xmm1
  subsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x20(%rdi),%xmm0
  subsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x28(%rdi),%xmm0
  subsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  D2(%rip),%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movsd  %xmm2,(%rdx)
  divsd  0x8(%rsi),%xmm1
  movq   D14(%rip),%xmm2
  movsd  %xmm1,0x8(%rdx)
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x38(%rdi),%xmm1
  xorpd  %xmm2,%xmm0
  movsd  %xmm1,0x20(%rsi)
  movsd  0x30(%rdi),%xmm1
  movsd  %xmm1,0x28(%rsi)
  movsd  0x8(%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rsi),%xmm1
  movsd  0x20(%rsi),%xmm3
  movsd  0x18(%rsi),%xmm0
  mulsd  0x28(%rsi),%xmm0
  mulsd  %xmm1,%xmm3
  mulsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x28(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  xorpd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f64
name: disassemble_data
arguments: tag: D14
type_guessed: byte[8]

tool: D2: 1

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void set_box(double box[3][3], double *h, double *h_inv) {
  h[0] = box[1][0] - box[0][0];
  h[1] = box[1][1] - box[0][1];
  h[2] = box[1][2] - box[0][2];
  h_inv[0] = 1.0 / h[0];
  h_inv[1] = 1.0 / h[1];
  h_inv[2] = 1.0 / h[2];
  h[3] = box[2][2];
  h[4] = box[2][1];
  h[5] = box[2][0];
  h_inv[3] = -h[3] / (h[1] * h[2]);
  h_inv[4] = (h[3] * h[5] - h[1] * h[4]) / (h[0] * h[1] * h[2]);
  h_inv[5] = -h[5] / (h[0] * h[1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_box>:
  endbr64
  movsd  0x18(%rdi),%xmm1
  subsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x20(%rdi),%xmm0
  subsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x28(%rdi),%xmm0
  subsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  D3(%rip),%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movsd  %xmm2,(%rdx)
  divsd  0x8(%rsi),%xmm1
  movq   D12(%rip),%xmm2
  movsd  %xmm1,0x8(%rdx)
  divsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x38(%rdi),%xmm1
  xorpd  %xmm2,%xmm0
  movsd  %xmm1,0x20(%rsi)
  movsd  0x30(%rdi),%xmm1
  movsd  %xmm1,0x28(%rsi)
  movsd  0x8(%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x8(%rsi),%xmm1
  movsd  0x20(%rsi),%xmm3
  movsd  0x18(%rsi),%xmm0
  mulsd  0x28(%rsi),%xmm0
  mulsd  %xmm1,%xmm3
  mulsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x28(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  xorpd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: f64
name: read_data
arguments: label: D12
type_guessed: byte[8]

tool: D3: 1

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void set_box(double box[3][3], double *h, double *h_inv) {
  h[0] = box[1][0] - box[0][0];
  h[1] = box[1][1] - box[0][1];
  h[2] = box[1][2] - box[0][2];
  h_inv[0] = 1.0 / h[0];
  h_inv[1] = 1.0 / h[1];
  h_inv[2] = 1.0 / h[2];
  h[3] = box[2][2];
  h[4] = box[2][1];
  h[5] = box[2][0];
  h_inv[3] = -h[3] / (h[1] * h[2]);
  h_inv[4] = (h[3] * h[5] - h[1] * h[4]) / (h[0] * h[1] * h[2]);
  h_inv[5] = -h[5] / (h[0] * h[1]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cgi_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <cgi_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: calloc failed for %d values of size %d

assistant: ```c
void *cgi_malloc(size_t cnt, size_t size) {
  void *buf = calloc(cnt, size);
  if (buf == NULL) {
    cgi_error("calloc failed for %d values of size %d", cnt, size);
    exit(1);
  }
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cgi_malloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L10:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <cgi_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: calloc failed for %d values of size %d

assistant: ```c
void *cgi_malloc(size_t cnt, size_t size) {
  void *buf = calloc(cnt, size);
  if (buf == NULL) {
    cgi_error("calloc failed for %d values of size %d", cnt, size);
    exit(1);
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cgi_malloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L5:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <cgi_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: calloc failed for %d values of size %d

assistant: ```c
void *cgi_malloc(size_t cnt, size_t size) {
  void *buf = calloc(cnt, size);
  if (buf == NULL) {
    cgi_error("calloc failed for %d values of size %d", cnt, size);
    exit(1);
  }
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cgi_malloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L18:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <cgi_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: calloc failed for %d values of size %d

assistant: ```c
void *cgi_malloc(size_t cnt, size_t size) {
  void *buf = calloc(cnt, size);
  if (buf == NULL) {
    cgi_error("calloc failed for %d values of size %d", cnt, size);
    exit(1);
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<quantosVaiMaisUm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  cmpl   $0x0,-0x18(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L23
L28:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cmp    $0x9,%eax
  jle    L9
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <quantosVaiMaisUm>
  add    $0x1,%eax
  jmp    L23
L9:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <quantosVaiMaisUm>
L23:
  leave
  ret
```

assistant: ```c
int quantosVaiMaisUm(int a, int b, int carry) {
  int ra, rb;
  ra = a % 10;
  rb = b % 10;
  if (a == 0 && b == 0) {
    return 0;
  } else if (ra + rb + carry > 9) {
    return 1 + quantosVaiMaisUm(a / 10, b / 10, 1);
  } else {
    return quantosVaiMaisUm(a / 10, b / 10, 0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<quantosVaiMaisUm>:
  endbr64
  mov    %edi,%ecx
  mov    %esi,%edi
  mov    %ecx,%eax
  or     %esi,%eax
  je     L7
  sub    $0x8,%rsp
  mov    %edx,%esi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edi,%r8d
  sub    %eax,%r8d
  lea    (%rdx,%r8,1),%eax
  add    %esi,%eax
  cmp    $0x9,%eax
  jle    L24
  movslq %edi,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sar    $0x1f,%edi
  sub    %edi,%esi
  movslq %ecx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%ecx
  sub    %ecx,%edi
  mov    $0x1,%edx
  call   <quantosVaiMaisUm>
  add    $0x1,%eax
L12:
  add    $0x8,%rsp
  ret
L24:
  movslq %edi,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sar    $0x1f,%edi
  sub    %edi,%esi
  movslq %ecx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%ecx
  sub    %ecx,%edi
  mov    $0x0,%edx
  call   <quantosVaiMaisUm>
  jmp    L12
L7:
  ret
```

assistant: ```c
int quantosVaiMaisUm(int a, int b, int carry) {
  int ra, rb;
  ra = a % 10;
  rb = b % 10;
  if (a == 0 && b == 0) {
    return 0;
  } else if (ra + rb + carry > 9) {
    return 1 + quantosVaiMaisUm(a / 10, b / 10, 1);
  } else {
    return quantosVaiMaisUm(a / 10, b / 10, 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quantosVaiMaisUm>:
  endbr64
  mov    %edx,%r9d
  movslq %edi,%rdx
  mov    %edi,%ecx
  mov    %esi,%r8d
  imul   $0x66666667,%rdx,%rax
  sar    $0x1f,%ecx
  mov    %r8d,%r10d
  sar    $0x1f,%r10d
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rsi
  sar    $0x22,%rsi
  sub    %r10d,%esi
  lea    (%rsi,%rsi,4),%r10d
  mov    %r8d,%esi
  add    %r10d,%r10d
  sub    %r10d,%esi
  mov    %edi,%r10d
  or     %r8d,%r10d
  je     L28
  push   %rbp
  xor    %r10d,%r10d
  push   %rbx
  xchg   %ax,%ax
L8:
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x1f,%edi
  add    %esi,%eax
  imul   $0x66666667,%rdx,%rdx
  add    %r9d,%eax
  xor    %r9d,%r9d
  sar    $0x22,%rcx
  mov    %ecx,%ebx
  sar    $0x22,%rdx
  sub    %edi,%edx
  sub    %r8d,%ebx
  mov    %ebx,%r8d
  mov    %edx,%r11d
  mov    %edx,%edi
  cmp    $0x9,%eax
  jle    L23
  add    $0x1,%r10d
  mov    $0x1,%r9d
L23:
  movslq %r11d,%rdx
  mov    %r11d,%ecx
  mov    %ebx,%ebp
  imul   $0x66666667,%rdx,%rax
  sar    $0x1f,%ecx
  sar    $0x1f,%ebp
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %r11d,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %ebx,%rcx
  imul   $0x66666667,%rcx,%rsi
  sar    $0x22,%rsi
  sub    %ebp,%esi
  lea    (%rsi,%rsi,4),%ebp
  mov    %ebx,%esi
  add    %ebp,%ebp
  sub    %ebp,%esi
  or     %ebx,%r11d
  jne    L8
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int quantosVaiMaisUm(int a, int b, int carry) {
  int ra, rb;
  ra = a % 10;
  rb = b % 10;
  if (a == 0 && b == 0) {
    return 0;
  } else if (ra + rb + carry > 9) {
    return 1 + quantosVaiMaisUm(a / 10, b / 10, 1);
  } else {
    return quantosVaiMaisUm(a / 10, b / 10, 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quantosVaiMaisUm>:
  endbr64
  movslq %edi,%rcx
  mov    %edx,%r10d
  movslq %esi,%rdx
  mov    %esi,%r9d
  imul   $0x66666667,%rcx,%rdi
  mov    %ecx,%eax
  sar    $0x1f,%esi
  mov    %ecx,%r11d
  sar    $0x1f,%eax
  sar    $0x22,%rdi
  sub    %eax,%edi
  lea    (%rdi,%rdi,4),%eax
  mov    %ecx,%edi
  add    %eax,%eax
  sub    %eax,%edi
  imul   $0x66666667,%rdx,%rax
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %r9d,%eax
  add    %esi,%esi
  sub    %esi,%eax
  or     %r9d,%r11d
  je     L8
  push   %rbp
  mov    %rcx,%r8
  xor    %r11d,%r11d
  push   %rbx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rcx
L5:
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x1f,%r8d
  add    %edi,%eax
  imul   $0x66666667,%rcx,%rcx
  add    %r10d,%eax
  xor    %r10d,%r10d
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sar    $0x22,%rcx
  sub    %r9d,%ebx
  sub    %r8d,%ecx
  mov    %ebx,%r9d
  mov    %ecx,%r8d
  cmp    $0x9,%eax
  jle    L21
  add    $0x1,%r11d
  mov    $0x1,%r10d
L21:
  movslq %ecx,%rbp
  mov    %ecx,%eax
  movslq %ebx,%rdx
  mov    %ebx,%esi
  imul   $0x66666667,%rbp,%rdi
  sar    $0x1f,%eax
  sar    $0x1f,%esi
  sar    $0x22,%rdi
  sub    %eax,%edi
  lea    (%rdi,%rdi,4),%eax
  mov    %ecx,%edi
  add    %eax,%eax
  sub    %eax,%edi
  imul   $0x66666667,%rdx,%rax
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %ebx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  or     %ebx,%ecx
  jne    L17
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int quantosVaiMaisUm(int a, int b, int carry) {
  int ra, rb;
  ra = a % 10;
  rb = b % 10;
  if (a == 0 && b == 0) {
    return 0;
  } else if (ra + rb + carry > 9) {
    return 1 + quantosVaiMaisUm(a / 10, b / 10, 1);
  } else {
    return quantosVaiMaisUm(a / 10, b / 10, 0);
  }
}
```