ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<af_sockaddr_eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L46
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x80,%eax
  je     L39
  cmp    $0x81,%eax
  jne    L25
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L46
L39:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <IN6_ARE_ADDR_EQUAL@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L46
L25:
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
  nop
L46:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: Unknown sockaddr family

assistant: ```c
int af_sockaddr_eq(const struct sockaddr *sa1, const struct sockaddr *sa2) {
  int res;
  res = 0;
  if (sa1->sa_family == sa2->sa_family) {
    switch (sa1->sa_family) {
    case AF_INET:
      res = (((struct sockaddr_in *)sa1)->sin_addr.s_addr == ((struct sockaddr_in *)sa2)->sin_addr.s_addr);
      break;
    case AF_INET6:
      res = IN6_ARE_ADDR_EQUAL(&((struct sockaddr_in6 *)sa1)->sin6_addr, &((struct sockaddr_in6 *)sa2)->sin6_addr);
      break;
    default:
      err(1, "Unknown sockaddr family");
      break;
    }
  }
  return (res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<af_sockaddr_eq>:
  endbr64
  mov    (%rdi),%edx
  mov    $0x0,%eax
  cmp    (%rsi),%edx
  je     L19
  ret
L19:
  sub    $0x8,%rsp
  cmp    $0x80,%edx
  je     L4
  mov    $0x1,%eax
  cmp    $0x81,%edx
  je     L16
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  mov    $0x0,%eax
  jmp    L16
L4:
  call   <IN6_ARE_ADDR_EQUAL@plt>
L16:
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: Unknown sockaddr family

assistant: ```c
int af_sockaddr_eq(const struct sockaddr *sa1, const struct sockaddr *sa2) {
  int res;
  res = 0;
  if (sa1->sa_family == sa2->sa_family) {
    switch (sa1->sa_family) {
    case AF_INET:
      res = (((struct sockaddr_in *)sa1)->sin_addr.s_addr == ((struct sockaddr_in *)sa2)->sin_addr.s_addr);
      break;
    case AF_INET6:
      res = IN6_ARE_ADDR_EQUAL(&((struct sockaddr_in6 *)sa1)->sin6_addr, &((struct sockaddr_in6 *)sa2)->sin6_addr);
      break;
    default:
      err(1, "Unknown sockaddr family");
      break;
    }
  }
  return (res);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<af_sockaddr_eq>:
  endbr64
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  cmp    (%rsi),%eax
  je     L24
L10:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  cmp    $0x80,%eax
  je     L25
  mov    $0x1,%r8d
  cmp    $0x81,%eax
  je     L10
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  jmp    1060 <IN6_ARE_ADDR_EQUAL@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type: string

tool: D1: Unknown sockaddr family

assistant: ```c
int af_sockaddr_eq(const struct sockaddr *sa1, const struct sockaddr *sa2) {
  int res;
  res = 0;
  if (sa1->sa_family == sa2->sa_family) {
    switch (sa1->sa_family) {
    case AF_INET:
      res = (((struct sockaddr_in *)sa1)->sin_addr.s_addr == ((struct sockaddr_in *)sa2)->sin_addr.s_addr);
      break;
    case AF_INET6:
      res = IN6_ARE_ADDR_EQUAL(&((struct sockaddr_in6 *)sa1)->sin6_addr, &((struct sockaddr_in6 *)sa2)->sin6_addr);
      break;
    default:
      err(1, "Unknown sockaddr family");
      break;
    }
  }
  return (res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<af_sockaddr_eq>:
  endbr64
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  cmp    (%rsi),%eax
  je     L26
L13:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  cmp    $0x80,%eax
  je     L17
  mov    $0x1,%r8d
  cmp    $0x81,%eax
  je     L13
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  jmp    1060 <IN6_ARE_ADDR_EQUAL@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: Unknown sockaddr family

assistant: ```c
int af_sockaddr_eq(const struct sockaddr *sa1, const struct sockaddr *sa2) {
  int res;
  res = 0;
  if (sa1->sa_family == sa2->sa_family) {
    switch (sa1->sa_family) {
    case AF_INET:
      res = (((struct sockaddr_in *)sa1)->sin_addr.s_addr == ((struct sockaddr_in *)sa2)->sin_addr.s_addr);
      break;
    case AF_INET6:
      res = IN6_ARE_ADDR_EQUAL(&((struct sockaddr_in6 *)sa1)->sin6_addr, &((struct sockaddr_in6 *)sa2)->sin6_addr);
      break;
    default:
      err(1, "Unknown sockaddr family");
      break;
    }
  }
  return (res);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <exe@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D2: %lld%lld%lld

tool: D19: %lld

assistant: ```c
int main(int argc, char **argv) {
  long long a, b, m;
  scanf("%lld%lld%lld", &a, &b, &m);
  printf("%lld", exe(a, b, m));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <exe@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D6: %lld%lld%lld

tool: D1: %lld

assistant: ```c
int main(int argc, char **argv) {
  long long a, b, m;
  scanf("%lld%lld%lld", &a, &b, &m);
  printf("%lld", exe(a, b, m));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  mov    0x10(%rsp),%rdx
  call   <exe@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D6: %lld%lld%lld

tool: D2: %lld

assistant: ```c
int main(int argc, char **argv) {
  long long a, b, m;
  scanf("%lld%lld%lld", &a, &b, &m);
  printf("%lld", exe(a, b, m));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  mov    0x10(%rsp),%rdx
  call   <exe@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: D7: %lld%lld%lld

tool: D13: %lld

assistant: ```c
int main(int argc, char **argv) {
  long long a, b, m;
  scanf("%lld%lld%lld", &a, &b, &m);
  printf("%lld", exe(a, b, m));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L11:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L9:
  cmpl   $0x0,-0x14(%rbp)
  jg     L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rev(int product) {
  int rev_pro = 0;
  while (product > 0) {
    rev_pro *= 10;
    rev_pro += (product % 10);
    product = product / 10;
  }
  return rev_pro;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rev>:
  endbr64
  test   %edi,%edi
  jle    L8
  mov    $0x0,%edx
L23:
  lea    (%rdx,%rdx,4),%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  lea    (%rcx,%rsi,2),%edx
  mov    %edi,%ecx
  mov    %eax,%edi
  cmp    $0x9,%ecx
  jg     L23
L12:
  mov    %edx,%eax
  ret
L8:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int rev(int product) {
  int rev_pro = 0;
  while (product > 0) {
    rev_pro *= 10;
    rev_pro += (product % 10);
    product = product / 10;
  }
  return rev_pro;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rev>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L5
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L17:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L17
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int rev(int product) {
  int rev_pro = 0;
  while (product > 0) {
    rev_pro *= 10;
    rev_pro += (product % 10);
    product = product / 10;
  }
  return rev_pro;
}
```
user: What is the c source code of the assembly code below:

```asm
<rev>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L14
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L5:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L5
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int rev(int product) {
  int rev_pro = 0;
  while (product > 0) {
    rev_pro *= 10;
    rev_pro += (product % 10);
    product = product / 10;
  }
  return rev_pro;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
L54:
  lea    -0x38(%rbp),%rdx
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  test   %eax,%eax
  js     L54
  mov    -0x3c(%rbp),%eax
  cmp    $0x7,%eax
  jg     L54
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  js     L54
  mov    -0x38(%rbp),%eax
  cmp    $0xc8,%eax
  jg     L54
  jmp    L34
L16:
  mov    -0x38(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L34:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jg     L16
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D11: %d %d

tool: D18: %d

assistant: ```c
int main() {
  int a, b, i = 0, array[8];
  do {
    scanf("%d %d", &a, &b);
  } while (a < 0 || a > 7 || b < 0 || b > 200);
  while (b > 0) {
    array[i] = b % 2;
    b = b / 2;
    i++;
  }
  printf("%d", array[a]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rbx
L25:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  cmp    $0x7,%edx
  ja     L25
  mov    0xc(%rsp),%eax
  cmp    $0xc8,%eax
  ja     L25
  test   %eax,%eax
  jle    L18
  lea    0x10(%rsp),%rsi
L36:
  mov    %eax,%edi
  shr    $0x1f,%edi
  lea    (%rax,%rdi,1),%ecx
  and    $0x1,%ecx
  sub    %edi,%ecx
  mov    %ecx,(%rsi)
  mov    %eax,%ecx
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %edi,%eax
  sar    %eax
  add    $0x4,%rsi
  cmp    $0x1,%ecx
  jg     L36
  mov    %eax,0xc(%rsp)
L18:
  movslq %edx,%rdx
  mov    0x10(%rsp,%rdx,4),%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D16
datatype: string

tool: D8: %d %d

tool: D16: %d

assistant: ```c
int main() {
  int a, b, i = 0, array[8];
  do {
    scanf("%d %d", &a, &b);
  } while (a < 0 || a > 7 || b < 0 || b > 200);
  while (b > 0) {
    array[i] = b % 2;
    b = b / 2;
    i++;
  }
  printf("%d", array[a]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopl   (%rax)
L23:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  cmp    $0x7,%eax
  ja     L23
  mov    0xc(%rsp),%edx
  cmp    $0xc8,%edx
  ja     L23
  test   %edx,%edx
  je     L30
  lea    0x10(%rsp),%rcx
  nopl   (%rax)
L43:
  mov    %edx,%esi
  add    $0x4,%rcx
  and    $0x1,%esi
  mov    %esi,-0x4(%rcx)
  sar    %edx
  jne    L43
  movl   $0x0,0xc(%rsp)
L30:
  mov    0x10(%rsp,%rax,4),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string

tool: D3: %d %d

tool: D6: %d

assistant: ```c
int main() {
  int a, b, i = 0, array[8];
  do {
    scanf("%d %d", &a, &b);
  } while (a < 0 || a > 7 || b < 0 || b > 200);
  while (b > 0) {
    array[i] = b % 2;
    b = b / 2;
    i++;
  }
  printf("%d", array[a]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  nopl   (%rax)
L58:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  cmp    $0x7,%eax
  ja     L58
  mov    0xc(%rsp),%edx
  cmp    $0xc8,%edx
  ja     L58
  test   %edx,%edx
  je     L101
  mov    %edx,%ecx
  and    $0x1,%ecx
  mov    %ecx,0x10(%rsp)
  mov    %edx,%ecx
  sar    %ecx
  je     L95
  and    $0x1,%ecx
  mov    %ecx,0x14(%rsp)
  mov    %edx,%ecx
  sar    $0x2,%ecx
  je     L95
  and    $0x1,%ecx
  mov    %ecx,0x18(%rsp)
  mov    %edx,%ecx
  sar    $0x3,%ecx
  je     L95
  and    $0x1,%ecx
  mov    %ecx,0x1c(%rsp)
  mov    %edx,%ecx
  sar    $0x4,%ecx
  je     L95
  and    $0x1,%ecx
  mov    %ecx,0x20(%rsp)
  mov    %edx,%ecx
  sar    $0x5,%ecx
  je     L95
  and    $0x1,%ecx
  mov    %ecx,0x24(%rsp)
  mov    %edx,%ecx
  sar    $0x6,%ecx
  je     L95
  sar    $0x7,%edx
  and    $0x1,%ecx
  sub    $0x1,%edx
  mov    %ecx,0x28(%rsp)
  jne    L95
  movl   $0x1,0x2c(%rsp)
L95:
  movl   $0x0,0xc(%rsp)
L101:
  mov    0x10(%rsp,%rax,4),%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D18: %d %d

tool: D19: %d

assistant: ```c
int main() {
  int a, b, i = 0, array[8];
  do {
    scanf("%d %d", &a, &b);
  } while (a < 0 || a > 7 || b < 0 || b > 200);
  while (b > 0) {
    array[i] = b % 2;
    b = b / 2;
    i++;
  }
  printf("%d", array[a]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crc8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edi
  call   <_crc8@plt>
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L2
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int crc8(unsigned int crc, const unsigned char *vptr, int len) {
  int i;
  for (i = 0; i < len; i++)
    crc = _crc8((crc ^ vptr[i]) << 8);
  return crc;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<crc8>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  jle    L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%edx
  lea    0x1(%rsi,%rdx,1),%rbp
L19:
  movzbl (%rbx),%edi
  xor    %eax,%edi
  shl    $0x8,%edi
  call   <_crc8@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
unsigned int crc8(unsigned int crc, const unsigned char *vptr, int len) {
  int i;
  for (i = 0; i < len; i++)
    crc = _crc8((crc ^ vptr[i]) << 8);
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc8>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  jle    L1
  push   %rbp
  sub    $0x1,%edx
  mov    %rsi,%rbp
  push   %rbx
  lea    0x1(%rsi,%rdx,1),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  xor    %eax,%edi
  shl    $0x8,%edi
  call   <_crc8@plt>
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
unsigned int crc8(unsigned int crc, const unsigned char *vptr, int len) {
  int i;
  for (i = 0; i < len; i++)
    crc = _crc8((crc ^ vptr[i]) << 8);
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crc8>:
  endbr64
  mov    %edi,%eax
  test   %edx,%edx
  jle    L9
  push   %rbp
  sub    $0x1,%edx
  mov    %rsi,%rbp
  push   %rbx
  lea    0x1(%rsi,%rdx,1),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  xor    %eax,%edi
  shl    $0x8,%edi
  call   <_crc8@plt>
  cmp    %rbx,%rbp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
unsigned int crc8(unsigned int crc, const unsigned char *vptr, int len) {
  int i;
  for (i = 0; i < len; i++)
    crc = _crc8((crc ^ vptr[i]) << 8);
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_bytes_tun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xbe0,%rsp
  mov    %edi,-0xbd4(%rbp)
  mov    %rsi,-0xbe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xbb8,-0xbc8(%rbp)
L16:
  mov    -0xbc8(%rbp),%edx
  lea    -0xbc0(%rbp),%rcx
  mov    -0xbd4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xbc4(%rbp)
  cmpl   $0x0,-0xbc4(%rbp)
  jns    L5
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <raise_error@plt>
L5:
  mov    -0xbe0(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xbc4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string

tool: D7: read() failed

tool: D15: Read %d bytes from tun device %s from: 


assistant: ```c
void read_bytes_tun(int tun_fd, struct ifreq *ifr) {
  int stat;
  char buff[3000];
  int buff_size = 3000;
  while (1) {
    stat = read(tun_fd, buff, buff_size);
    if (stat < 0)
      raise_error("read() failed");
    printf("Read %d bytes from tun device %s from: \n", stat, ifr->ifr_name);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_bytes_tun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xbc8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    D1(%rip),%r15
  lea    D8(%rip),%r13
  jmp    L21
L19:
  mov    %r15,%rdi
  call   <raise_error@plt>
L14:
  mov    0x0(%rbp),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L21:
  mov    $0xbb8,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L19
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D8
datatype: string

tool: D1: read() failed

tool: D8: Read %d bytes from tun device %s from: 


assistant: ```c
void read_bytes_tun(int tun_fd, struct ifreq *ifr) {
  int stat;
  char buff[3000];
  int buff_size = 3000;
  while (1) {
    stat = read(tun_fd, buff, buff_size);
    if (stat < 0)
      raise_error("read() failed");
    printf("Read %d bytes from tun device %s from: \n", stat, ifr->ifr_name);
  }
}
```