user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<izracun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x18(%rsp)
  mov    %ecx,%r15d
  mov    %r8,0x20(%rsp)
  cmp    $0x56,%dil
  je     L78
  cmp    $0x4f,%dil
  je     L92
L121:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  test   %edx,%edx
  jle    L121
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  mov    %eax,0x1c(%rsp)
  mov    0x70(%rsp),%eax
  shr    $0x1f,%eax
  add    0x70(%rsp),%eax
  sar    %eax
  mov    %eax,0x28(%rsp)
  mov    0x78(%rsp),%eax
  shr    $0x1f,%eax
  add    0x78(%rsp),%eax
  sar    %eax
  mov    %eax,0x2c(%rsp)
  lea    -0x1(%rcx),%eax
  mov    %rax,0x10(%rsp)
  lea    0x1(%rsi,%rax,1),%rbx
  mov    $0x0,%ecx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L280
L63:
  add    $0x1,%ebp
L257:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L318
L30:
  movzbl (%rax),%edx
  cmp    $0x4d,%dl
  je     L63
  cmp    $0x50,%dl
  jne    L35
  add    $0x1,%r12d
  jmp    L257
L35:
  cmp    $0x47,%dl
  jne    L257
  add    $0x1,%r13d
  jmp    L257
L318:
  lea    0x1(%rcx),%r14d
  cmp    %ebp,0x1c(%rsp)
  je     L251
L166:
  add    $0x64,%rbx
  cmp    %r14d,0x18(%rsp)
  je     L121
  mov    %r14d,%ecx
L280:
  mov    %rbx,%rax
  sub    0x10(%rsp),%rax
  sub    $0x1,%rax
  test   %r15d,%r15d
  jg     L30
  jmp    L318
L251:
  cmp    %r12d,0x28(%rsp)
  jne    L166
  cmp    %r13d,0x2c(%rsp)
  jne    L166
  mov    0x20(%rsp),%rax
  mov    (%rax),%esi
  mov    %esi,0x8(%rsp)
  add    $0x1,%esi
  mov    %esi,(%rax)
  add    $0x2,%ecx
  mov    %r14d,%edx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L166
L92:
  test   %ecx,%ecx
  jle    L121
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  mov    %eax,0x10(%rsp)
  mov    0x70(%rsp),%eax
  shr    $0x1f,%eax
  add    0x70(%rsp),%eax
  sar    %eax
  mov    %eax,0x1c(%rsp)
  mov    0x78(%rsp),%eax
  shr    $0x1f,%eax
  add    0x78(%rsp),%eax
  sar    %eax
  mov    %eax,0x28(%rsp)
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  mov    0x8(%rsp),%rsi
  lea    0x64(%rsi,%rax,4),%rbx
  mov    %ecx,%r15d
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L310
L136:
  add    $0x1,%ebp
L45:
  add    $0x64,%rax
  cmp    %rbx,%rax
  je     L41
L199:
  movzbl (%rax),%edx
  cmp    $0x4d,%dl
  je     L136
  cmp    $0x50,%dl
  jne    L250
  add    $0x1,%r13d
  jmp    L45
L250:
  cmp    $0x47,%dl
  jne    L45
  add    $0x1,%r14d
  jmp    L45
L41:
  lea    0x1(%r12),%edx
  cmp    %ebp,0x10(%rsp)
  je     L235
L299:
  add    $0x1,%r12
  add    $0x1,%rbx
  cmp    %r15,%r12
  je     L121
L310:
  mov    0x8(%rsp),%rax
  add    %r12,%rax
  cmpl   $0x0,0x18(%rsp)
  jg     L199
  jmp    L41
L235:
  cmp    %r13d,0x1c(%rsp)
  jne    L299
  cmp    %r14d,0x28(%rsp)
  jne    L299
  mov    0x20(%rsp),%rdi
  mov    (%rdi),%esi
  mov    %esi,0x2c(%rsp)
  add    $0x1,%esi
  mov    %esi,(%rdi)
  lea    0x2(%r12),%ecx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L299
```

tool_calls: name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D13: %d. Vodoravno, izmedju retka br. %d i br. %d


tool: D10: %d. Okomito, izmedju stupca br. %d i br. %d


assistant: ```c
void izracun(char orijentacija, char imanje[][100], int visina, int sirina, int *br_podjela, int M, int P, int G) {
  int i, j, tmpM = 0, tmpP = 0, tmpG = 0, granica = 0;
  if (orijentacija == 'V') {
    for (i = 0; i < visina; i++) {
      for (j = 0; j < sirina; j++) {
        if (imanje[i][j] == 'M')
          tmpM++;
        if (imanje[i][j] == 'P')
          tmpP++;
        if (imanje[i][j] == 'G')
          tmpG++;
      }
      granica++;
      if (tmpM == M / 2 && tmpP == P / 2 && tmpG == G / 2) {
        (*br_podjela)++;
        printf("%d. Vodoravno, izmedju retka br. %d i br. %d\n", *br_podjela, granica, granica + 1);
      }
    }
  } else if (orijentacija == 'O') {
    for (i = 0; i < sirina; i++) {
      for (j = 0; j < visina; j++) {
        if (imanje[j][i] == 'M')
          tmpM++;
        if (imanje[j][i] == 'P')
          tmpP++;
        if (imanje[j][i] == 'G')
          tmpG++;
      }
      granica++;
      if (tmpM == M / 2 && tmpP == P / 2 && tmpG == G / 2) {
        (*br_podjela)++;
        printf("%d. Okomito, izmedju stupca br. %d i br. %d\n", *br_podjela, granica, granica + 1);
      }
    }
  }
}
```