ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcd_disp_inv>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x2520204b4f3a31,%rax
  mov    %rax,0x35(%rsp)
  movl   $0x4b4f3a32,0xe(%rsp)
  movw   $0x25,0x12(%rsp)
  lea    0x2(%rax),%rax
  mov    %rax,0x3d(%rsp)
  movl   $0x4b4f3a34,0x14(%rsp)
  movw   $0x25,0x18(%rsp)
  lea    0x2(%rax),%rax
  mov    %rax,0x45(%rsp)
  movl   $0x4b4f3a36,0x1a(%rsp)
  movw   $0x25,0x1e(%rsp)
  movabs $0x2520204441423a31,%rax
  mov    %rax,0x4d(%rsp)
  movb   $0x0,0x55(%rsp)
  movl   $0x41423a32,0x20(%rsp)
  movw   $0x2544,0x24(%rsp)
  movb   $0x0,0x26(%rsp)
  lea    0x2(%rax),%rax
  mov    %rax,0x56(%rsp)
  movb   $0x0,0x5e(%rsp)
  movl   $0x41423a34,0x27(%rsp)
  movw   $0x2544,0x2b(%rsp)
  movb   $0x0,0x2d(%rsp)
  lea    0x2(%rax),%rax
  mov    %rax,0x5f(%rsp)
  movb   $0x0,0x67(%rsp)
  movl   $0x41423a36,0x2e(%rsp)
  movw   $0x2544,0x32(%rsp)
  movb   $0x0,0x34(%rsp)
  cmp    $0xc,%edi
  ja     L96
  mov    %edi,%edi
  lea    D4(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    0x35(%rsp),%rdi
  call   <lcd_msg@plt>
L96:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x78,%rsp
  ret
  lea    0xe(%rsp),%rdi
  call   <lcd_msg@plt>
  mov    $0xc0,%edi
  call   <lcd_clear@plt>
  jmp    L96
  lea    0x3d(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x14(%rsp),%rdi
  call   <lcd_msg@plt>
  mov    $0x90,%edi
  call   <lcd_clear@plt>
  jmp    L96
  lea    0x45(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x1a(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x4d(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x20(%rsp),%rdi
  call   <lcd_msg@plt>
  mov    $0xc0,%edi
  call   <lcd_clear@plt>
  jmp    L96
  lea    0x56(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x27(%rsp),%rdi
  call   <lcd_msg@plt>
  mov    $0x90,%edi
  call   <lcd_clear@plt>
  jmp    L96
  lea    0x5f(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
  lea    0x2e(%rsp),%rdi
  call   <lcd_msg@plt>
  jmp    L96
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void lcd_disp_inv(int choose) {
  char msg1[] = "1:OK  %";
  char msg2[] = "2:OK%";
  char msg3[] = "3:OK  %";
  char msg4[] = "4:OK%";
  char msg5[] = "5:OK  %";
  char msg6[] = "6:OK%";
  char msg7[] = "1:BAD  %";
  char msg8[] = "2:BAD%";
  char msg9[] = "3:BAD  %";
  char msg10[] = "4:BAD%";
  char msg11[] = "5:BAD  %";
  char msg12[] = "6:BAD%";
  switch (choose) {
  case 1:
    lcd_msg(msg1);
    break;
  case 2:
    lcd_msg(msg2);
    lcd_clear(0xc0);
    break;
  case 3:
    lcd_msg(msg3);
    break;
  case 4:
    lcd_msg(msg4);
    lcd_clear(0x90);
    break;
  case 5:
    lcd_msg(msg5);
    break;
  case 6:
    lcd_msg(msg6);
    break;
  case 7:
    lcd_msg(msg7);
    break;
  case 8:
    lcd_msg(msg8);
    lcd_clear(0xc0);
    break;
  case 9:
    lcd_msg(msg9);
    break;
  case 10:
    lcd_msg(msg10);
    lcd_clear(0x90);
    break;
  case 11:
    lcd_msg(msg11);
    break;
  case 12:
    lcd_msg(msg12);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L2:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  je     L20
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_char@plt>
  test   %rax,%rax
  jne    L2
L20:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int remove_chars(struct current *current, int pos, int n) {
  int removed = 0;
  while (n-- && remove_char(current, pos)) {
    removed++;
  }
  return removed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_chars>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    $0x0,%ebx
  test   %edx,%edx
  je     L3
L24:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <remove_char@plt>
  test   %rax,%rax
  je     L27
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L24
L27:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    %edx,%ebx
  jmp    L27
```

assistant: ```c
int remove_chars(struct current *current, int pos, int n) {
  int removed = 0;
  while (n-- && remove_char(current, pos)) {
    removed++;
  }
  return removed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remove_chars>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L12
  jmp    L38
  xchg   %ax,%ax
L18:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  je     L38
L12:
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <remove_char@plt>
  test   %rax,%rax
  jne    L18
L38:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int remove_chars(struct current *current, int pos, int n) {
  int removed = 0;
  while (n-- && remove_char(current, pos)) {
    removed++;
  }
  return removed;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<remove_chars>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L31
  jmp    L39
  xchg   %ax,%ax
L28:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  je     L39
L31:
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <remove_char@plt>
  test   %rax,%rax
  jne    L28
L39:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int remove_chars(struct current *current, int pos, int n) {
  int removed = 0;
  while (n-- && remove_char(current, pos)) {
    removed++;
  }
  return removed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L14:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <find_size@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x10,-0x4(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i <= 16; i++) {
    find_size(i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
L0:
  mov    %ebx,%edi
  call   <find_size@plt>
  add    $0x1,%ebx
  cmp    $0x11,%ebx
  jne    L0
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i <= 16; i++) {
    find_size(i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <find_size@plt>
  cmp    $0x11,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i <= 16; i++) {
    find_size(i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <find_size@plt>
  cmp    $0x11,%ebx
  jne    L8
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i <= 16; i++) {
    find_size(i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_getwc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
L55:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x20(%rbp,%rdx,1)
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    D22(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L76
  mov    D48(%rip),%rax
  mov    (%rax),%eax
  jmp    L7
L76:
  addl   $0x1,-0x2c(%rbp)
  mov    D0(%rip),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <mbtowc@plt>
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mbtowc@plt>
  mov    %eax,-0x28(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jle    L14
  mov    -0x30(%rbp),%eax
  jmp    L7
L14:
  cmpl   $0x10,-0x2c(%rbp)
  jne    L55
  jmp    L52
L53:
  subl   $0x1,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
L52:
  cmpl   $0x1,-0x2c(%rbp)
  jg     L53
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    D48(%rip),%rax
  mov    (%rax),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
wint_t my_getwc(FILE *s) {
  char i[16];
  int byte = 0;
  int convert;
  int x;
  wchar_t rval;
  while (1) {
    i[byte] = getc(s);
    if (i[byte] == EOF) {
      return WEOF;
    }
    byte++;
    errno = 0;
    mbtowc(NULL, NULL, 0);
    convert = mbtowc(&rval, i, byte);
    x = errno;
    if (convert > 0) {
      return rval;
    }
    if (byte == 16) {
      while (byte > 1) {
        ungetc(i[--byte], s);
      }
      errno = -EILSEQ;
      return WEOF;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_getwc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    0xf(%rsp),%r12
L36:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %al,(%r12,%rbx,1)
  mov    D31(%rip),%rdx
  cmp    (%rdx),%al
  je     L1
  mov    D17(%rip),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <mbtowc@plt>
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %ebx,%edx
  call   <mbtowc@plt>
  test   %eax,%eax
  jg     L48
  add    $0x1,%rbx
  cmp    $0x11,%rbx
  jne    L36
  lea    0x10(%rsp),%r12
  lea    0x1f(%rsp),%rbx
L19:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    D17(%rip),%rdx
  mov    %eax,(%rdx)
  mov    D32(%rip),%rax
  mov    (%rax),%eax
L58:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L48:
  mov    0xc(%rsp),%eax
  jmp    L58
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
wint_t my_getwc(FILE *s) {
  char i[16];
  int byte = 0;
  int convert;
  int x;
  wchar_t rval;
  while (1) {
    i[byte] = getc(s);
    if (i[byte] == EOF) {
      return WEOF;
    }
    byte++;
    errno = 0;
    mbtowc(NULL, NULL, 0);
    convert = mbtowc(&rval, i, byte);
    x = errno;
    if (convert > 0) {
      return rval;
    }
    if (byte == 16) {
      while (byte > 1) {
        ungetc(i[--byte], s);
      }
      errno = -EILSEQ;
      return WEOF;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_getwc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  mov    D24(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xf(%rsp),%r14
  lea    0xc(%rsp),%r15
L12:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %al,(%r14,%rbx,1)
  cmp    0x0(%r13),%al
  je     L22
  mov    D37(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  movl   $0x0,(%rax)
  call   <mbtowc@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <mbtowc@plt>
  test   %eax,%eax
  jg     L18
  add    $0x1,%rbx
  cmp    $0x11,%rbx
  jne    L12
  lea    0x1f(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  sub    $0x1,%rbx
  call   <ungetc@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    D18(%rip),%rax
  mov    D37(%rip),%rcx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rcx)
L22:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L4:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    0xc(%rsp),%eax
  jmp    L4
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
wint_t my_getwc(FILE *s) {
  char i[16];
  int byte = 0;
  int convert;
  int x;
  wchar_t rval;
  while (1) {
    i[byte] = getc(s);
    if (i[byte] == EOF) {
      return WEOF;
    }
    byte++;
    errno = 0;
    mbtowc(NULL, NULL, 0);
    convert = mbtowc(&rval, i, byte);
    x = errno;
    if (convert > 0) {
      return rval;
    }
    if (byte == 16) {
      while (byte > 1) {
        ungetc(i[--byte], s);
      }
      errno = -EILSEQ;
      return WEOF;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_getwc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  mov    D33(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xf(%rsp),%r14
  lea    0xc(%rsp),%r15
L22:
  mov    %rbp,%rdi
  call   <getc@plt>
  mov    %al,(%r14,%rbx,1)
  cmp    0x0(%r13),%al
  je     L1
  mov    D31(%rip),%rax
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  movl   $0x0,(%rax)
  call   <mbtowc@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <mbtowc@plt>
  test   %eax,%eax
  jg     L44
  add    $0x1,%rbx
  cmp    $0x11,%rbx
  jne    L22
  lea    0x1f(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L58:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  sub    $0x1,%rbx
  call   <ungetc@plt>
  cmp    %r12,%rbx
  jne    L58
  mov    D5(%rip),%rax
  mov    D31(%rip),%rcx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rcx)
L1:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
L52:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    0xc(%rsp),%eax
  jmp    L52
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
wint_t my_getwc(FILE *s) {
  char i[16];
  int byte = 0;
  int convert;
  int x;
  wchar_t rval;
  while (1) {
    i[byte] = getc(s);
    if (i[byte] == EOF) {
      return WEOF;
    }
    byte++;
    errno = 0;
    mbtowc(NULL, NULL, 0);
    convert = mbtowc(&rval, i, byte);
    x = errno;
    if (convert > 0) {
      return rval;
    }
    if (byte == 16) {
      while (byte > 1) {
        ungetc(i[--byte], s);
      }
      errno = -EILSEQ;
      return WEOF;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stb_bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stb_bitcount(unsigned int a) {
  a = (a & 0x55555555) + ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  a = (a + (a >> 4)) & 0x0f0f0f0f;
  a = (a + (a >> 8));
  a = (a + (a >> 16));
  return a & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<stb_bitcount>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%eax
  shr    %edi
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  and    $0x33333333,%edx
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stb_bitcount(unsigned int a) {
  a = (a & 0x55555555) + ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  a = (a + (a >> 4)) & 0x0f0f0f0f;
  a = (a + (a >> 8));
  a = (a + (a >> 16));
  return a & 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stb_bitcount>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  shr    $0x2,%eax
  and    $0x33333333,%eax
  and    $0x33333333,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stb_bitcount(unsigned int a) {
  a = (a & 0x55555555) + ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  a = (a + (a >> 4)) & 0x0f0f0f0f;
  a = (a + (a >> 8));
  a = (a + (a >> 16));
  return a & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<stb_bitcount>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %edi,%eax
  mov    %eax,%edx
  shr    $0x2,%eax
  and    $0x33333333,%eax
  and    $0x33333333,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int stb_bitcount(unsigned int a) {
  a = (a & 0x55555555) + ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  a = (a + (a >> 4)) & 0x0f0f0f0f;
  a = (a + (a >> 8));
  a = (a + (a >> 16));
  return a & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %esi,-0x28(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x24(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getmaxyx@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L6
L10:
  lea    -0xa(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvprintw@plt>
  addl   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L10
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void fill(char ch, int row) {
  char c[2] = {ch, '\0'};
  int y, x;
  (void)(y);
  getmaxyx(stdscr, y, x);
  for (int i = 0; i < x; i++) {
    mvprintw(row, i, c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fill>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill(char ch, int row) {
  char c[2] = {ch, '\0'};
  int y, x;
  (void)(y);
  getmaxyx(stdscr, y, x);
  for (int i = 0; i < x; i++) {
    mvprintw(row, i, c);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %dil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill(char ch, int row) {
  char c[2] = {ch, '\0'};
  int y, x;
  (void)(y);
  getmaxyx(stdscr, y, x);
  for (int i = 0; i < x; i++) {
    mvprintw(row, i, c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %dil,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    (%rax),%edi
  call   <getmaxyx@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill(char ch, int row) {
  char c[2] = {ch, '\0'};
  int y, x;
  (void)(y);
  getmaxyx(stdscr, y, x);
  for (int i = 0; i < x; i++) {
    mvprintw(row, i, c);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_object>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x5c,(%rax)
  cmpl   $0x7e,-0x4(%rbp)
  jne    L34
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x7e,(%rax)
  jmp    L18
L34:
  cmpl   $0xffff,-0x4(%rbp)
  jle    L18
  cmpl   $0xffffff,-0x4(%rbp)
  jg     L18
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x3,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L18:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *set_object(int object_id, unsigned char *buffer) {
  *buffer++ = 0x5c;
  if (object_id == 0x7e) {
    *buffer++ = 1;
    *buffer++ = 0x7e;
  } else if (object_id > 0xffff && object_id <= 0xffffff) {
    *buffer++ = 3;
    *buffer++ = (object_id >> 16) & 0xff;
    *buffer++ = (object_id >> 8) & 0xff;
    *buffer++ = object_id & 0xff;
  }
  return buffer;
}
```