ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%edi
  mov    $0x4,%r12d
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    D6(%rip),%rbx
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  jmp    L19
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0x21,%r12d
  je     L20
L19:
  mov    %r12d,%edx
  mov    %r12d,%eax
  lea    -0x3(%r12),%esi
  imul   $0x24924925,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %r12d,%eax
  add    $0x1,%r12d
  sub    %edx,%eax
  test   %eax,%eax
  je     L17
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x21,%r12d
  jne    L19
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D5: %2d	

tool: D6: %2d


assistant: ```c
int main(void) {
  int t, y;
  int i = 1;
  int offset = 3;
  int nu_dag = 29;
  t = offset;
  while (i <= t) {
    printf("\t");
    t--;
  }
  y = i + offset;
  while (i <= nu_dag) {
    if (y % 7 == 0) {
      printf("%2d\n", i);
      i++;
      y++;
    } else {
      printf("%2d\t", i);
      i++;
      y++;
    }
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sk_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x401,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x400,%edx
  mov    %eax,%edi
  call   <cw_read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L16
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L16:
  leave
  ret
```

assistant: ```c
char *sk_recv(int sock, int ssl) {
  char *buffer = (char *)malloc(1024 + 1);
  int ret = cw_read(sock, buffer, 1024, ssl);
  if (ret <= 0) {
    free(buffer);
    return NULL;
  }
  buffer[ret] = 0;
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sk_recv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x401,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    $0x400,%edx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <cw_read@plt>
  test   %eax,%eax
  jle    L8
  cltq
  movb   $0x0,(%rbx,%rax,1)
L4:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L4
```

assistant: ```c
char *sk_recv(int sock, int ssl) {
  char *buffer = (char *)malloc(1024 + 1);
  int ret = cw_read(sock, buffer, 1024, ssl);
  if (ret <= 0) {
    free(buffer);
    return NULL;
  }
  buffer[ret] = 0;
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sk_recv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x401,%edi
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    $0x400,%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <cw_read@plt>
  test   %eax,%eax
  jle    L1
  cltq
  movb   $0x0,(%r12,%rax,1)
L3:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L3
```

assistant: ```c
char *sk_recv(int sock, int ssl) {
  char *buffer = (char *)malloc(1024 + 1);
  int ret = cw_read(sock, buffer, 1024, ssl);
  if (ret <= 0) {
    free(buffer);
    return NULL;
  }
  buffer[ret] = 0;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sk_recv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x401,%edi
  call   <malloc@plt>
  mov    %r13d,%ecx
  mov    $0x400,%edx
  mov    %ebp,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <cw_read@plt>
  test   %eax,%eax
  jle    L4
  cltq
  movb   $0x0,(%r12,%rax,1)
L10:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L10
```

assistant: ```c
char *sk_recv(int sock, int ssl) {
  char *buffer = (char *)malloc(1024 + 1);
  int ret = cw_read(sock, buffer, 1024, ssl);
  if (ret <= 0) {
    free(buffer);
    return NULL;
  }
  buffer[ret] = 0;
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<change_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x820(%rbp)
  cmpq   $0x0,-0x820(%rbp)
  jne    L13
  mov    $0x12c,%eax
  jmp    L36
L13:
  mov    -0x820(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    %rdx,%rcx
  lea    D35(%rip),%rdx
  mov    $0x800,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x810(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x818(%rbp)
  cmpq   $0x0,-0x818(%rbp)
  jne    L25
  mov    $0x12d,%eax
  jmp    L36
L25:
  mov    -0x828(%rbp),%rdx
  mov    -0x818(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D35
datatype: string
name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D21
datatype: string

tool: D3: BOITHOHOME

tool: D35: %s/var/phonehome.state

tool: D18: w

tool: D21: %s


assistant: ```c
int change_state(char *cmd) {
  FILE *fp;
  char path[2048];
  char *bh;
  bh = getenv("BOITHOHOME");
  if (bh == NULL)
    return 300;
  snprintf(path, sizeof(path), "%s/var/phonehome.state", bh);
  fp = fopen(path, "w");
  if (fp == NULL) {
    return 301;
  }
  fprintf(fp, "%s\n", cmd);
  fclose(fp);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<change_state>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rcx
  mov    %rsp,%rbx
  lea    D14(%rip),%rdx
  mov    $0x800,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L32
  mov    %rbp,%rdx
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L40:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x12c,%eax
  jmp    L40
L32:
  mov    $0x12d,%eax
  jmp    L40
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D26
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string

tool: D26: BOITHOHOME

tool: D14: %s/var/phonehome.state

tool: D25: w

tool: D29: %s


assistant: ```c
int change_state(char *cmd) {
  FILE *fp;
  char path[2048];
  char *bh;
  bh = getenv("BOITHOHOME");
  if (bh == NULL)
    return 300;
  snprintf(path, sizeof(path), "%s/var/phonehome.state", bh);
  fp = fopen(path, "w");
  if (fp == NULL) {
    return 301;
  }
  fprintf(fp, "%s\n", cmd);
  fclose(fp);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<change_state>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <getenv@plt>
  test   %rax,%rax
  je     L28
  mov    %rsp,%rbp
  mov    %rax,%rcx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  lea    D10(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L43
  mov    %r12,%rdx
  lea    D26(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L42:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x818,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x12c,%eax
  jmp    L42
  nop
L43:
  mov    $0x12d,%eax
  jmp    L42
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string

tool: D5: BOITHOHOME

tool: D10: %s/var/phonehome.state

tool: D9: w

tool: D26: %s


assistant: ```c
int change_state(char *cmd) {
  FILE *fp;
  char path[2048];
  char *bh;
  bh = getenv("BOITHOHOME");
  if (bh == NULL)
    return 300;
  snprintf(path, sizeof(path), "%s/var/phonehome.state", bh);
  fp = fopen(path, "w");
  if (fp == NULL) {
    return 301;
  }
  fprintf(fp, "%s\n", cmd);
  fclose(fp);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<change_state>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D8(%rip),%rdi
  push   %rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <getenv@plt>
  test   %rax,%rax
  je     L49
  mov    %rsp,%rbp
  mov    %rax,%rcx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  lea    D9(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L33
  mov    %r12,%rdx
  lea    D37(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L29:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x818,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    $0x12c,%eax
  jmp    L29
  nop
L33:
  mov    $0x12d,%eax
  jmp    L29
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D9
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D37
data_type: string

tool: D8: BOITHOHOME

tool: D9: %s/var/phonehome.state

tool: D5: w

tool: D37: %s


assistant: ```c
int change_state(char *cmd) {
  FILE *fp;
  char path[2048];
  char *bh;
  bh = getenv("BOITHOHOME");
  if (bh == NULL)
    return 300;
  snprintf(path, sizeof(path), "%s/var/phonehome.state", bh);
  fp = fopen(path, "w");
  if (fp == NULL) {
    return 301;
  }
  fprintf(fp, "%s\n", cmd);
  fclose(fp);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sum_a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L3:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sum_a(const double *restrict input, double *restrict output, int len) {
  for (int i = 0; i < len; i++)
    output[i] = input[2 * i] + input[2 * i + 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_a>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L15:
  movsd  (%rax),%xmm0
  addsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rsi)
  add    $0x10,%rax
  add    $0x8,%rsi
  cmp    %rdx,%rax
  jne    L15
L17:
  ret
```

assistant: ```c
void sum_a(const double *restrict input, double *restrict output, int len) {
  for (int i = 0; i < len; i++)
    output[i] = input[2 * i] + input[2 * i + 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sum_a>:
  endbr64
  test   %edx,%edx
  jle    L15
  lea    -0x1(%rdx),%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rax
  nopl   0x0(%rax)
L2:
  movsd  (%rdi),%xmm0
  addsd  0x8(%rdi),%xmm0
  add    $0x10,%rdi
  add    $0x8,%rsi
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rdi,%rax
  jne    L2
L15:
  ret
```

assistant: ```c
void sum_a(const double *restrict input, double *restrict output, int len) {
  for (int i = 0; i < len; i++)
    output[i] = input[2 * i] + input[2 * i + 1];
}
```
user: What is the c source code of the assembly code below?

```asm
<sum_a>:
  endbr64
  test   %edx,%edx
  jle    L10
  cmp    $0x1,%edx
  je     L23
  mov    %edx,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L17:
  movupd (%rdi,%rax,2),%xmm1
  movupd 0x10(%rdi,%rax,2),%xmm0
  movlpd 0x8(%rdi,%rax,2),%xmm0
  movhpd 0x10(%rdi,%rax,2),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L17
  mov    %edx,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%edx
  je     L2
L36:
  lea    (%rcx,%rcx,1),%eax
  movslq %ecx,%rcx
  cltq
  movsd  0x8(%rdi,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rcx,8)
L10:
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
L23:
  xor    %ecx,%ecx
  jmp    L36
```

assistant: ```c
void sum_a(const double *restrict input, double *restrict output, int len) {
  for (int i = 0; i < len; i++)
    output[i] = input[2 * i] + input[2 * i + 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <f@plt>
  cmp    $0x24,%eax
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  if (f(3) != sizeof(short) * 2 * 3 * 3)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  cmp    $0x24,%eax
  jne    L3
L12:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L12
```

assistant: ```c
main() {
  if (f(3) != sizeof(short) * 2 * 3 * 3)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  cmp    $0x24,%eax
  je     L7
  xor    %eax,%eax
  call   <abort@plt>
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  if (f(3) != sizeof(short) * 2 * 3 * 3)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  cmp    $0x24,%eax
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  if (f(3) != sizeof(short) * 2 * 3 * 3)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test22() {
  if ("help")
    (void)0;
  if (test22)
    (void)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test22>:
  endbr64
  ret
```

assistant: ```c
void test22() {
  if ("help")
    (void)0;
  if (test22)
    (void)0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test22>:
  endbr64
  ret
```

assistant: ```c
void test22() {
  if ("help")
    (void)0;
  if (test22)
    (void)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test22>:
  endbr64
  ret
```

assistant: ```c
void test22() {
  if ("help")
    (void)0;
  if (test22)
    (void)0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<approx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L3
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  jmp    L7
L3:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
L7:
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: f64

tool: D1: 0.04

assistant: ```c
int approx(int a, int b) {
  int diff = (a > b) ? (a - b) : (b - a);
  return ((float)diff / (float)b) < 0.04;
}
```
user: What is the c source code of the assembly code below:

```asm
<approx>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  mov    %esi,%eax
  sub    %edi,%eax
  cmp    %esi,%edi
  cmovg  %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D6(%rip),%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: f64

tool: D6: 0.04

assistant: ```c
int approx(int a, int b) {
  int diff = (a > b) ? (a - b) : (b - a);
  return ((float)diff / (float)b) < 0.04;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<approx>:
  endbr64
  mov    %edi,%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %esi,%eax
  sub    %esi,%edx
  cvtsi2ss %esi,%xmm1
  sub    %edi,%eax
  cmp    %esi,%edi
  cmovg  %edx,%eax
  cvtsi2ss %eax,%xmm0
  xor    %eax,%eax
  divss  %xmm1,%xmm0
  movsd  D2(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  comisd %xmm0,%xmm1
  seta   %al
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: f64

tool: D2: 0.04

assistant: ```c
int approx(int a, int b) {
  int diff = (a > b) ? (a - b) : (b - a);
  return ((float)diff / (float)b) < 0.04;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<approx>:
  endbr64
  mov    %edi,%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %esi,%eax
  sub    %esi,%edx
  cvtsi2ss %esi,%xmm1
  sub    %edi,%eax
  cmp    %esi,%edi
  cmovg  %edx,%eax
  cvtsi2ss %eax,%xmm0
  xor    %eax,%eax
  divss  %xmm1,%xmm0
  movsd  D0(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  comisd %xmm0,%xmm1
  seta   %al
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: f64

tool: D0: 0.04

assistant: ```c
int approx(int a, int b) {
  int diff = (a > b) ? (a - b) : (b - a);
  return ((float)diff / (float)b) < 0.04;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calday_to_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <calendar_dpy@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x168,-0x10(%rbp)
  je     L38
  cmpl   $0x16d,-0x10(%rbp)
  je     L38
  cmpl   $0x16e,-0x10(%rbp)
  jne    L19
L38:
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <decode_day@plt>
  jmp    L30
L19:
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <decode_julday@plt>
L30:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cdiEncodeDate@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int calday_to_date(int calendar, int calday) {
  int date;
  int dpy;
  int year, month, day;
  dpy = calendar_dpy(calendar);
  if (dpy == 360 || dpy == 365 || dpy == 366)
    decode_day(dpy, calday, &year, &month, &day);
  else
    decode_julday(calendar, calday, &year, &month, &day);
  date = cdiEncodeDate(year, month, day);
  return (date);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calday_to_date>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <calendar_dpy@plt>
  mov    %eax,%edi
  lea    -0x16d(%rax),%eax
  cmp    $0x1,%eax
  jbe    L15
  cmp    $0x168,%edi
  jne    L32
L15:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  mov    %ebp,%esi
  call   <decode_day@plt>
L18:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <cdiEncodeDate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <decode_julday@plt>
  jmp    L18
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calday_to_date(int calendar, int calday) {
  int date;
  int dpy;
  int year, month, day;
  dpy = calendar_dpy(calendar);
  if (dpy == 360 || dpy == 365 || dpy == 366)
    decode_day(dpy, calday, &year, &month, &day);
  else
    decode_julday(calendar, calday, &year, &month, &day);
  date = cdiEncodeDate(year, month, day);
  return (date);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calday_to_date>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <calendar_dpy@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %r12d,%esi
  mov    %eax,%edi
  sub    $0x16d,%eax
  lea    0x14(%rsp),%r8
  cmp    $0x1,%eax
  jbe    L29
  cmp    $0x168,%edi
  jne    L28
L29:
  call   <decode_day@plt>
L33:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <cdiEncodeDate@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  mov    %ebp,%edi
  call   <decode_julday@plt>
  jmp    L33
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int calday_to_date(int calendar, int calday) {
  int date;
  int dpy;
  int year, month, day;
  dpy = calendar_dpy(calendar);
  if (dpy == 360 || dpy == 365 || dpy == 366)
    decode_day(dpy, calday, &year, &month, &day);
  else
    decode_julday(calendar, calday, &year, &month, &day);
  date = cdiEncodeDate(year, month, day);
  return (date);
}
```