ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<copyblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L91:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L91
L44:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L113
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L113:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x38(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L100
L20:
  mov    -0x50(%rbp),%rax
  mov    -0x38(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x30(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jge    L98
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  jmp    L26
L98:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
L26:
  mov    -0x34(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <r_read@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jns    L92
  mov    $0xffffffff,%eax
  jmp    L24
L92:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L0
  mov    -0x38(%rbp),%eax
  jmp    L24
L0:
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x48(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <r_write@plt>
  test   %rax,%rax
  jns    L8
  mov    $0xffffffff,%eax
  jmp    L24
L8:
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x38(%rbp)
L100:
  mov    -0x38(%rbp),%eax
  cltq
  cmp    %rax,-0x50(%rbp)
  ja     L20
  mov    -0x38(%rbp),%eax
L24:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L102
  call   <__stack_chk_fail@plt>
L102:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int copyblock(int fromfd, int tofd, size_t size) {
  char buf[PIPE_BUF];
  int bytesread;
  int totalbytes = 0;
  int blocksize = PIPE_BUF;
  int bytesleft;
  while (totalbytes < size) {
    bytesleft = size - totalbytes;
    if (bytesleft < PIPE_BUF) {
      blocksize = bytesleft;
    } else {
      blocksize = PIPE_BUF;
    }
    if ((bytesread = r_read(fromfd, buf, blocksize)) < 0)
      return -1;
    if (bytesread == 0)
      return totalbytes;
    if (r_write(tofd, buf, bytesread) < 0)
      return -1;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copyblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L113:
  cmp    %rdx,%rsp
  je     L111
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L113
L111:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L81
  orq    $0x0,-0x8(%rsp,%rax,1)
L81:
  mov    %rsp,%r14
  test   %r13,%r13
  je     L95
  mov    $0x0,%r12d
  mov    D4(%rip),%r15
L105:
  mov    %r13d,%edx
  sub    %r12d,%edx
  mov    (%r15),%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %r14,%rsi
  mov    -0x44(%rbp),%edi
  call   <r_read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L51
  je     L89
  mov    %eax,%edx
  mov    %r14,%rsi
  mov    -0x48(%rbp),%edi
  call   <r_write@plt>
  test   %rax,%rax
  js     L99
  add    %ebx,%r12d
  movslq %r12d,%rax
  cmp    %r13,%rax
  jb     L105
  jmp    L89
L95:
  mov    $0x0,%r12d
  jmp    L89
L51:
  mov    $0xffffffff,%r12d
L89:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    %r12d,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L99:
  mov    $0xffffffff,%r12d
  jmp    L89
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copyblock(int fromfd, int tofd, size_t size) {
  char buf[PIPE_BUF];
  int bytesread;
  int totalbytes = 0;
  int blocksize = PIPE_BUF;
  int bytesleft;
  while (totalbytes < size) {
    bytesleft = size - totalbytes;
    if (bytesleft < PIPE_BUF) {
      blocksize = bytesleft;
    } else {
      blocksize = PIPE_BUF;
    }
    if ((bytesread = r_read(fromfd, buf, blocksize)) < 0)
      return -1;
    if (bytesread == 0)
      return totalbytes;
    if (r_write(tofd, buf, bytesread) < 0)
      return -1;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copyblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,-0x50(%rbp)
  mov    %rsp,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D16(%rip),%rax
  movslq (%rax),%rdx
  mov    %rdx,%rax
  add    $0xf,%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L102
L92:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L92
L102:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L87
L81:
  mov    -0x50(%rbp),%rcx
  mov    %rsp,%rbx
  test   %rcx,%rcx
  je     L17
  mov    %ecx,-0x44(%rbp)
  xor    %r15d,%r15d
  jmp    L59
  nopl   (%rax)
L53:
  je     L98
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <r_write@plt>
  test   %rax,%rax
  js     L0
  add    %r12d,%r15d
  movslq %r15d,%rax
  cmp    -0x50(%rbp),%rax
  jae    L98
  mov    D16(%rip),%rax
  mov    (%rax),%eax
L59:
  mov    -0x44(%rbp),%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  sub    %r15d,%edx
  cmp    %eax,%edx
  cmovg  %eax,%edx
  call   <r_read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L53
L0:
  mov    $0xffffffff,%r15d
L98:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  lea    -0x28(%rbp),%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L87:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L81
L17:
  xor    %r15d,%r15d
  jmp    L98
L112:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copyblock(int fromfd, int tofd, size_t size) {
  char buf[PIPE_BUF];
  int bytesread;
  int totalbytes = 0;
  int blocksize = PIPE_BUF;
  int bytesleft;
  while (totalbytes < size) {
    bytesleft = size - totalbytes;
    if (bytesleft < PIPE_BUF) {
      blocksize = bytesleft;
    } else {
      blocksize = PIPE_BUF;
    }
    if ((bytesread = r_read(fromfd, buf, blocksize)) < 0)
      return -1;
    if (bytesread == 0)
      return totalbytes;
    if (r_write(tofd, buf, bytesread) < 0)
      return -1;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,-0x50(%rbp)
  mov    %rsp,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    D17(%rip),%rax
  movslq (%rax),%rdx
  mov    %rdx,%rax
  add    $0xf,%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L43
L55:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L55
L43:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L94
L110:
  mov    -0x50(%rbp),%rcx
  mov    %rsp,%rbx
  test   %rcx,%rcx
  je     L63
  mov    %ecx,-0x44(%rbp)
  xor    %r15d,%r15d
  jmp    L67
  nopl   (%rax)
L81:
  je     L99
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <r_write@plt>
  test   %rax,%rax
  js     L100
  add    %r12d,%r15d
  movslq %r15d,%rax
  cmp    -0x50(%rbp),%rax
  jae    L99
  mov    D17(%rip),%rax
  mov    (%rax),%eax
L67:
  mov    -0x44(%rbp),%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  sub    %r15d,%edx
  cmp    %eax,%edx
  cmovg  %eax,%edx
  call   <r_read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L81
L100:
  mov    $0xffffffff,%r15d
L99:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  lea    -0x28(%rbp),%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L94:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L110
L63:
  xor    %r15d,%r15d
  jmp    L99
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copyblock(int fromfd, int tofd, size_t size) {
  char buf[PIPE_BUF];
  int bytesread;
  int totalbytes = 0;
  int blocksize = PIPE_BUF;
  int bytesleft;
  while (totalbytes < size) {
    bytesleft = size - totalbytes;
    if (bytesleft < PIPE_BUF) {
      blocksize = bytesleft;
    } else {
      blocksize = PIPE_BUF;
    }
    if ((bytesread = r_read(fromfd, buf, blocksize)) < 0)
      return -1;
    if (bytesread == 0)
      return totalbytes;
    if (r_write(tofd, buf, bytesread) < 0)
      return -1;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkAndWriteEffect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L18
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L48
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
L48:
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L10
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
L10:
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jne    L25
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  jmp    L25
L18:
  nop
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void checkAndWriteEffect(int row, int col, int queenX, int queenY, int **chessboard) {
  if (chessboard[row][col]) {
    return;
  }
  if (row == queenX) {
    chessboard[row][col] = 2;
  }
  if (col == queenY) {
    chessboard[row][col] = 2;
  }
  if (abs(row - queenX) == abs(col - queenY)) {
    chessboard[row][col] = 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkAndWriteEffect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebp
  movslq %edi,%rcx
  lea    (%r8,%rcx,8),%r13
  movslq %esi,%r12
  mov    0x0(%r13),%rcx
  lea    (%rcx,%r12,4),%rcx
  cmpl   $0x0,(%rcx)
  jne    L21
  mov    %edi,%eax
  mov    %esi,%ebx
  cmp    %edx,%edi
  je     L56
L15:
  cmp    %ebp,%ebx
  je     L31
L30:
  sub    %edx,%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%r14
  sub    %ebp,%ebx
  mov    %ebx,%edi
  call   <abs@plt>
  cmp    %rax,%r14
  je     L6
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  movl   $0x2,(%rcx)
  jmp    L15
L31:
  mov    0x0(%r13),%rcx
  movl   $0x2,(%rcx,%r12,4)
  jmp    L30
L6:
  mov    0x0(%r13),%rax
  movl   $0x2,(%rax,%r12,4)
  jmp    L21
```

assistant: ```c
void checkAndWriteEffect(int row, int col, int queenX, int queenY, int **chessboard) {
  if (chessboard[row][col]) {
    return;
  }
  if (row == queenX) {
    chessboard[row][col] = 2;
  }
  if (col == queenY) {
    chessboard[row][col] = 2;
  }
  if (abs(row - queenX) == abs(col - queenY)) {
    chessboard[row][col] = 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkAndWriteEffect>:
  endbr64
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  movslq %edi,%rcx
  lea    (%r8,%rcx,8),%r14
  push   %rbx
  mov    (%r14),%rcx
  lea    (%rcx,%r13,4),%rcx
  mov    (%rcx),%eax
  test   %eax,%eax
  jne    L10
  mov    %edi,%eax
  mov    %r13,%rbx
  cmp    %edx,%edi
  je     L60
  cmp    %ebp,%ebx
  je     L30
L14:
  sub    %edx,%eax
  sub    %ebp,%ebx
  mov    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  mov    %rax,%r12
  call   <abs@plt>
  cmp    %rax,%r12
  je     L13
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L13:
  mov    (%r14),%rax
  movl   $0x2,(%rax,%r13,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  movl   $0x2,(%rcx)
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L60:
  movl   $0x2,(%rcx)
  cmp    %ebp,%ebx
  jne    L14
  jmp    L30
```

assistant: ```c
void checkAndWriteEffect(int row, int col, int queenX, int queenY, int **chessboard) {
  if (chessboard[row][col]) {
    return;
  }
  if (row == queenX) {
    chessboard[row][col] = 2;
  }
  if (col == queenY) {
    chessboard[row][col] = 2;
  }
  if (abs(row - queenX) == abs(col - queenY)) {
    chessboard[row][col] = 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkAndWriteEffect>:
  endbr64
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  movslq %edi,%rcx
  lea    (%r8,%rcx,8),%r14
  push   %rbx
  mov    (%r14),%rcx
  lea    (%rcx,%r13,4),%rcx
  mov    (%rcx),%eax
  test   %eax,%eax
  jne    L50
  mov    %edi,%eax
  mov    %r13,%rbx
  cmp    %edx,%edi
  je     L59
  cmp    %ebp,%ebx
  je     L62
L25:
  sub    %edx,%eax
  sub    %ebp,%ebx
  mov    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  mov    %rax,%r12
  call   <abs@plt>
  cmp    %rax,%r12
  je     L38
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L38:
  mov    (%r14),%rax
  movl   $0x2,(%rax,%r13,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L62:
  movl   $0x2,(%rcx)
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L59:
  movl   $0x2,(%rcx)
  cmp    %ebp,%ebx
  jne    L25
  jmp    L62
```

assistant: ```c
void checkAndWriteEffect(int row, int col, int queenX, int queenY, int **chessboard) {
  if (chessboard[row][col]) {
    return;
  }
  if (row == queenX) {
    chessboard[row][col] = 2;
  }
  if (col == queenY) {
    chessboard[row][col] = 2;
  }
  if (abs(row - queenX) == abs(col - queenY)) {
    chessboard[row][col] = 2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sumLogProbs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L32:
  cmpl   $0x0,-0x14(%rbp)
  je     L40
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L15
L40:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L15:
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L32
  mov    D1(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  ucomisd -0x10(%rbp),%xmm2
  jp     L22
  movq   %rax,%xmm3
  ucomisd -0x10(%rbp),%xmm3
  jne    L22
  movsd  -0x10(%rbp),%xmm0
  jmp    L68
L22:
  movl   $0x0,-0x14(%rbp)
  jmp    L67
L62:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L62
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x10(%rbp),%xmm0
L68:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: f64

tool: D1: 0

assistant: ```c
double sumLogProbs(double *logprobs, int sz) {
  double max = 0.0;
  double p = 0.0;
  int i;
  for (i = 0; i < sz; ++i)
    if (i == 0 || logprobs[i] > max)
      max = logprobs[i];
  if (max == log(0))
    return max;
  for (i = 0; i < sz; ++i)
    p += exp(logprobs[i] - max);
  return max + log(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sumLogProbs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L23
  mov    %rdi,%r12
  lea    -0x1(%rsi),%r13d
  mov    %esi,%esi
  mov    $0x0,%eax
  mov    D2(%rip),%rbp
  jmp    L32
L47:
  mov    (%r12,%rax,8),%rbp
L66:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L51
L32:
  test   %eax,%eax
  je     L47
  movsd  (%r12,%rax,8),%xmm0
  movq   %rbp,%xmm3
  comisd %xmm3,%xmm0
  jbe    L66
  jmp    L47
L51:
  pxor   %xmm0,%xmm0
  call   <log@plt>
  movq   %rbp,%xmm5
  ucomisd %xmm0,%xmm5
  jp     L38
  je     L77
L38:
  mov    %r12,%rbx
  lea    0x8(%r12,%r13,8),%r12
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
L21:
  movsd  (%rbx),%xmm0
  movq   %rbp,%xmm1
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
L93:
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movq   %rbp,%xmm4
  addsd  %xmm0,%xmm4
  movq   %xmm4,%rbp
L77:
  movq   %rbp,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  pxor   %xmm0,%xmm0
  call   <log@plt>
  pxor   %xmm7,%xmm7
  ucomisd %xmm7,%xmm0
  jp     L4
  movq   %xmm7,%rbp
  je     L77
L4:
  mov    D2(%rip),%rbp
  mov    %rbp,0x8(%rsp)
  jmp    L93
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: f64

tool: D2: 0

assistant: ```c
double sumLogProbs(double *logprobs, int sz) {
  double max = 0.0;
  double p = 0.0;
  int i;
  for (i = 0; i < sz; ++i)
    if (i == 0 || logprobs[i] > max)
      max = logprobs[i];
  if (max == log(0))
    return max;
  for (i = 0; i < sz; ++i)
    p += exp(logprobs[i] - max);
  return max + log(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<sumLogProbs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L49
  pxor   %xmm2,%xmm2
  lea    -0x1(%rsi),%ebp
  mov    %rdi,%rbx
  mov    %esi,%esi
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  jmp    L84
  cs nopw 0x0(%rax,%rax,1)
L68:
  maxsd  %xmm1,%xmm0
  add    $0x1,%rax
  movapd %xmm0,%xmm1
  cmp    %rsi,%rax
  je     L17
L84:
  movsd  (%rbx,%rax,8),%xmm0
  test   %rax,%rax
  jne    L68
  add    $0x1,%rax
  movapd %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L84
L17:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  ucomisd %xmm0,%xmm1
  jp     L45
  je     L44
L45:
  lea    0x8(%rbx,%rbp,8),%rbp
  nopl   0x0(%rax)
L37:
  movsd  (%rbx),%xmm0
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  movsd  %xmm1,(%rsp)
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  cmp    %rbp,%rbx
  cvtsi2sd %rax,%xmm0
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm2
  jne    L37
L99:
  movapd %xmm2,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm1
L44:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm2
  ucomisd %xmm2,%xmm0
  jp     L41
  movapd %xmm2,%xmm1
  je     L44
L41:
  movapd %xmm2,%xmm1
  jmp    L99
```

assistant: ```c
double sumLogProbs(double *logprobs, int sz) {
  double max = 0.0;
  double p = 0.0;
  int i;
  for (i = 0; i < sz; ++i)
    if (i == 0 || logprobs[i] > max)
      max = logprobs[i];
  if (max == log(0))
    return max;
  for (i = 0; i < sz; ++i)
    p += exp(logprobs[i] - max);
  return max + log(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<sumLogProbs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L55
  pxor   %xmm2,%xmm2
  lea    -0x1(%rsi),%ebp
  mov    %rdi,%rbx
  mov    %esi,%esi
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L77:
  maxsd  %xmm1,%xmm0
  add    $0x1,%rax
  movapd %xmm0,%xmm1
  cmp    %rsi,%rax
  je     L30
L89:
  movsd  (%rbx,%rax,8),%xmm0
  test   %rax,%rax
  jne    L77
  add    $0x1,%rax
  movapd %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L89
L30:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  ucomisd %xmm1,%xmm0
  jp     L47
  je     L56
L47:
  lea    0x8(%rbx,%rbp,8),%rbp
  nopl   0x0(%rax)
L91:
  movsd  (%rbx),%xmm0
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  movsd  %xmm1,(%rsp)
  subsd  %xmm1,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  cmp    %rbx,%rbp
  cvtsi2sd %rax,%xmm0
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm2
  jne    L91
L96:
  movapd %xmm2,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm1
  addsd  %xmm0,%xmm1
L56:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm2
  ucomisd %xmm2,%xmm0
  jp     L2
  movapd %xmm2,%xmm1
  je     L56
L2:
  movapd %xmm2,%xmm1
  jmp    L96
```

assistant: ```c
double sumLogProbs(double *logprobs, int sz) {
  double max = 0.0;
  double p = 0.0;
  int i;
  for (i = 0; i < sz; ++i)
    if (i == 0 || logprobs[i] > max)
      max = logprobs[i];
  if (max == log(0))
    return max;
  for (i = 0; i < sz; ++i)
    p += exp(logprobs[i] - max);
  return max + log(p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<residential_calculation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: f64
name: retrieve_data
arguments: data_tag: D2
type_guessed: f64

tool: D1: 0.052

tool: D2: 6

assistant: ```c
double residential_calculation(int consumption) {
  double amount_due = 0.0;
  amount_due = 6.0 + (consumption * 0.052);
  return amount_due;
}
```