ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<moremorecalldoupper>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %edx,%ebp
  mov    $0x63,%esi
  push   %rbx
  cvtsi2ss %edi,%xmm0
  mov    $0xfffabcde,%edx
  mov    %ecx,%ebx
  mov    $0x1,%eax
  mov    $0xea,%ecx
  sub    $0x30,%rsp
  addb   $0x2f,(%r8)
  mulss  D2(%rip),%xmm0
  addb   $0x2f,0x1(%r8)
  mov    %edi,0x14(%rsp)
  push   $0x65
  lea    0x1c(%rsp),%r9
  cvtss2sd %xmm0,%xmm0
  call   <calldoupper@plt>
  lea    0x0(%rbp,%rbx,1),%edi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <dolower@plt>
  mov    $0x3,%esi
  mov    %eax,%edi
  xor    %eax,%eax
  call   <dolower@plt>
  mov    %ebp,%esi
  mov    %eax,0x2c(%rsp)
  mov    0x2c(%rsp),%edi
  xor    %eax,%eax
  call   <dolower@plt>
  add    $0x38,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: byte[4]

tool: {"D2": [0x8f,0xc2,0xf5,0x3c]}

assistant: ```c
float moremorecalldoupper(const int x, char y, float f, int a, int b, char *c, int *d, char e) {
  c[0] += 47;
  c[1] += 47;
  d = 3;
  volatile int wdvc = dolower(dolower(a + b, calldoupper(x, 'c', x * 0.03f, 0xfffabcde, 234, c, &x, 'e')), 3);
  f = (float)(x / (int)y);
  return dolower(wdvc, a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getVectorLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double getVectorLength(int length, double *tf_idf) {
  double ret = 0.0;
  int i;
  for (i = 0; i < length; i++)
    ret += tf_idf[i] * tf_idf[i];
  ret = sqrt(ret);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<getVectorLength>:
  endbr64
  test   %edi,%edi
  jle    L17
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L35:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L35
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L31
L33:
  sqrtsd %xmm0,%xmm0
  ret
L17:
  pxor   %xmm0,%xmm0
  jmp    L33
L31:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double getVectorLength(int length, double *tf_idf) {
  double ret = 0.0;
  int i;
  for (i = 0; i < length; i++)
    ret += tf_idf[i] * tf_idf[i];
  ret = sqrt(ret);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getVectorLength>:
  endbr64
  test   %edi,%edi
  jle    L14
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rsi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L6:
  movsd  (%rsi),%xmm1
  add    $0x8,%rsi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L6
  ucomisd %xmm0,%xmm2
  ja     L3
  sqrtsd %xmm0,%xmm0
  ret
L14:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L3:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double getVectorLength(int length, double *tf_idf) {
  double ret = 0.0;
  int i;
  for (i = 0; i < length; i++)
    ret += tf_idf[i] * tf_idf[i];
  ret = sqrt(ret);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getVectorLength>:
  endbr64
  test   %edi,%edi
  jle    L27
  cmp    $0x1,%edi
  je     L33
  mov    %edi,%edx
  pxor   %xmm3,%xmm3
  mov    %rsi,%rax
  shr    %edx
  movapd %xmm3,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L48:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L48
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L1
L54:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L1:
  ucomisd %xmm0,%xmm3
  ja     L45
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L27:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L33:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L54
L45:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double getVectorLength(int length, double *tf_idf) {
  double ret = 0.0;
  int i;
  for (i = 0; i < length; i++)
    ret += tf_idf[i] * tf_idf[i];
  ret = sqrt(ret);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L49
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L114
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L49
L114:
  movl   $0x2,-0x8(%rbp)
  jmp    L49
L64:
  shll   $0x4,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L76
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L76
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L76:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L89
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L89
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x57,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L89:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L12
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L12
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x37,%eax
  mov    %eax,-0x4(%rbp)
L12:
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L64
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int htoi(const char *s) {
  int i = 0;
  int res = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X')) {
    i = 2;
  }
  for (; i < strlen(s); i++) {
    res = res * 16;
    if (s[i] >= '0' && s[i] <= '9') {
      res = res + s[i] - '0';
    } else if (s[i] >= 'a' && s[i] <= 'f') {
      res = res + s[i] - 'a' + 10;
    } else if (s[i] >= 'A' && s[i] <= 'F') {
      res = res + s[i] - 'A' + 10;
    }
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  cmpb   $0x30,(%rdi)
  je     L1
L41:
  movslq %ebx,%rbx
  mov    $0x0,%ebp
  jmp    L0
L1:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %bl
  movzbl %bl,%ebx
  add    %ebx,%ebx
  jmp    L41
L81:
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L36
  movsbl %al,%eax
  lea    -0x57(%rbp,%rax,1),%ebp
L47:
  add    $0x1,%rbx
L0:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L19
  shl    $0x4,%ebp
  movzbl (%r12,%rbx,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L81
  movsbl %al,%eax
  lea    -0x30(%rbp,%rax,1),%ebp
  jmp    L47
L36:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L47
  movsbl %al,%eax
  lea    -0x37(%rbp,%rax,1),%ebp
  jmp    L47
L19:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int htoi(const char *s) {
  int i = 0;
  int res = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X')) {
    i = 2;
  }
  for (; i < strlen(s); i++) {
    res = res * 16;
    if (s[i] >= '0' && s[i] <= '9') {
      res = res + s[i] - '0';
    } else if (s[i] >= 'a' && s[i] <= 'f') {
      res = res + s[i] - 'a' + 10;
    } else if (s[i] >= 'A' && s[i] <= 'F') {
      res = res + s[i] - 'A' + 10;
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cmpb   $0x30,(%rdi)
  jne    L39
  movzbl 0x1(%rdi),%eax
  xor    %ebx,%ebx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %bl
  add    %ebx,%ebx
L39:
  movslq %ebx,%rbx
  xor    %r12d,%r12d
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L50:
  lea    -0x30(%r12,%rax,1),%r12d
L38:
  add    $0x1,%rbx
L59:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L40
  movsbl 0x0(%rbp,%rbx,1),%eax
  shl    $0x4,%r12d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L50
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L63
  lea    -0x57(%r12,%rax,1),%r12d
  jmp    L38
  nopl   (%rax)
L63:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L38
  lea    -0x37(%r12,%rax,1),%r12d
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int htoi(const char *s) {
  int i = 0;
  int res = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X')) {
    i = 2;
  }
  for (; i < strlen(s); i++) {
    res = res * 16;
    if (s[i] >= '0' && s[i] <= '9') {
      res = res + s[i] - '0';
    } else if (s[i] >= 'a' && s[i] <= 'f') {
      res = res + s[i] - 'a' + 10;
    } else if (s[i] >= 'A' && s[i] <= 'F') {
      res = res + s[i] - 'A' + 10;
    }
  }
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  cmpb   $0x30,(%rdi)
  jne    L47
  movzbl 0x1(%rdi),%eax
  xor    %ebx,%ebx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %bl
  add    %ebx,%ebx
L47:
  movslq %ebx,%rbx
  xor    %r12d,%r12d
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L57:
  lea    -0x30(%r12,%rax,1),%r12d
L41:
  add    $0x1,%rbx
L58:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L54
  movsbl 0x0(%rbp,%rbx,1),%eax
  shl    $0x4,%r12d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L57
  lea    -0x61(%rax),%edx
  cmp    $0x5,%dl
  ja     L34
  lea    -0x57(%r12,%rax,1),%r12d
  jmp    L41
  nopl   (%rax)
L34:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L41
  lea    -0x37(%r12,%rax,1),%r12d
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int htoi(const char *s) {
  int i = 0;
  int res = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X')) {
    i = 2;
  }
  for (; i < strlen(s); i++) {
    res = res * 16;
    if (s[i] >= '0' && s[i] <= '9') {
      res = res + s[i] - '0';
    } else if (s[i] >= 'a' && s[i] <= 'f') {
      res = res + s[i] - 'a' + 10;
    } else if (s[i] >= 'A' && s[i] <= 'F') {
      res = res + s[i] - 'A' + 10;
    }
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L6
L29:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L37
L39:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L37:
  cmpl   $0x2,-0x14(%rbp)
  jle    L39
  addl   $0x1,-0x18(%rbp)
L6:
  cmpl   $0x6,-0x18(%rbp)
  jle    L29
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D4: snanstdevyc

tool: D7: # c::%s:len=%d


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "snanstdevyc", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D28(%rip),%r15
  jmp    L33
L11:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L32
L33:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L18:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L18
  jmp    L11
L32:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string

tool: D28: snanstdevyc

tool: D25: # c::%s:len=%d


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "snanstdevyc", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D23(%rip),%r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L17:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L17
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type: string
name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D9
type: string

tool: D23: snanstdevyc

tool: D0: # c::%s:len=%d


tool: D9: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "snanstdevyc", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D25(%rip),%r15
  push   %r14
  lea    D26(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L0:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L1:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L1
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L0
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D25: snanstdevyc

tool: D26: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "snanstdevyc", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<estimated_flops>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x40000,-0x18(%rbp)
  movq   $0x40000,-0x10(%rbp)
  movq   $0x40000,-0x8(%rbp)
  addq   $0x8000000,-0x18(%rbp)
  addq   $0x8000000,-0x8(%rbp)
  addq   $0x40000,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: adds: %lld muls: %lld divs: %lld


assistant: ```c
long long estimated_flops() {
  long long muls, divs, adds;
  muls = 512 * 512;
  divs = 512 * 512;
  adds = 512 * 512;
  muls += 512 * 512 * 512;
  adds += 512 * 512 * 512;
  adds += 512 * 512;
  printf("adds: %lld muls: %lld divs: %lld\n", adds, muls, divs);
  return adds + muls + divs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<estimated_flops>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%ecx
  mov    $0x8040000,%edx
  mov    $0x8080000,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x10100000,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: adds: %lld muls: %lld divs: %lld


assistant: ```c
long long estimated_flops() {
  long long muls, divs, adds;
  muls = 512 * 512;
  divs = 512 * 512;
  adds = 512 * 512;
  muls += 512 * 512 * 512;
  adds += 512 * 512 * 512;
  adds += 512 * 512;
  printf("adds: %lld muls: %lld divs: %lld\n", adds, muls, divs);
  return adds + muls + divs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<estimated_flops>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%ecx
  mov    $0x8040000,%edx
  mov    $0x8080000,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x10100000,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5: adds: %lld muls: %lld divs: %lld


assistant: ```c
long long estimated_flops() {
  long long muls, divs, adds;
  muls = 512 * 512;
  divs = 512 * 512;
  adds = 512 * 512;
  muls += 512 * 512 * 512;
  adds += 512 * 512 * 512;
  adds += 512 * 512;
  printf("adds: %lld muls: %lld divs: %lld\n", adds, muls, divs);
  return adds + muls + divs;
}
```
user: What is the c source code of the assembly code below?

```asm
<estimated_flops>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40000,%ecx
  mov    $0x8040000,%edx
  mov    $0x8080000,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x10100000,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4: adds: %lld muls: %lld divs: %lld


assistant: ```c
long long estimated_flops() {
  long long muls, divs, adds;
  muls = 512 * 512;
  divs = 512 * 512;
  adds = 512 * 512;
  muls += 512 * 512 * 512;
  adds += 512 * 512 * 512;
  adds += 512 * 512;
  printf("adds: %lld muls: %lld divs: %lld\n", adds, muls, divs);
  return adds + muls + divs;
}
```