ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binToDecimal>:
  endbr64
  test   %edi,%edi
  jle    L8
  mov    $0x1,%esi
  xor    %r8d,%r8d
  mov    $0xcccccccd,%r9d
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %edi,%eax
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,%edx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %edi,%ecx
  mov    %edx,%edi
  imul   %esi,%eax
  add    %esi,%esi
  add    %eax,%r8d
  cmp    $0x9,%ecx
  jg     L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int binToDecimal(int num) {
  int total = 0;
  int multiplier = 1;
  int remainder;
  while (num > 0) {
    remainder = num % 10;
    num /= 10;
    total += remainder * multiplier;
    multiplier *= 2;
  }
  return total;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x2,-0x60(%rbp)
L34:
  mov    -0x60(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x64(%rbp),%edx
  mov    -0x58(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <toBaseN@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x64(%rbp)
  jg     L22
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <countUnique@plt>
  cmp    %eax,-0x64(%rbp)
  jne    L22
  mov    -0x64(%rbp),%edx
  mov    -0x60(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <toBaseN@plt>
  mov    -0x64(%rbp),%edx
  mov    -0x58(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <toBaseN@plt>
  lea    -0x30(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  jmp    L5
L22:
  addq   $0x1,-0x60(%rbp)
  jmp    L34
L5:
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: Base %d : Num %8s Square %16s


assistant: ```c
void find(int base) {
  char nBuf[32];
  char sqBuf[32];
  long long n, s;
  for (n = 2;; n++) {
    s = n * n;
    toBaseN(sqBuf, s, base);
    if (strlen(sqBuf) >= base && countUnique(sqBuf) == base) {
      toBaseN(nBuf, n, base);
      toBaseN(sqBuf, s, base);
      printf("Base %d : Num %8s Square %16s\n", base, nBuf, sqBuf);
      break;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<find>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x2,%ebx
  lea    0x20(%rsp),%r12
  jmp    L18
L34:
  add    $0x1,%rbx
L18:
  mov    %rbx,%r13
  imul   %rbx,%r13
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <toBaseN@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L34
  mov    %r12,%rdi
  call   <countUnique@plt>
  cmp    %ebp,%eax
  jne    L34
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <toBaseN@plt>
  lea    0x20(%rsp),%rbx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <toBaseN@plt>
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: Base %d : Num %8s Square %16s


assistant: ```c
void find(int base) {
  char nBuf[32];
  char sqBuf[32];
  long long n, s;
  for (n = 2;; n++) {
    s = n * n;
    toBaseN(sqBuf, s, base);
    if (strlen(sqBuf) >= base && countUnique(sqBuf) == base) {
      toBaseN(nBuf, n, base);
      toBaseN(sqBuf, s, base);
      printf("Base %d : Num %8s Square %16s\n", base, nBuf, sqBuf);
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x2,%ebp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
  jmp    L11
L30:
  add    $0x1,%rbp
L11:
  mov    %rbp,%r14
  mov    %r13,%rdi
  mov    %r12d,%edx
  imul   %rbp,%r14
  mov    %r14,%rsi
  call   <toBaseN@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L30
  mov    %r13,%rdi
  call   <countUnique@plt>
  cmp    %r12d,%eax
  jne    L30
  mov    %rsp,%r15
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <toBaseN@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <toBaseN@plt>
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D7: Base %d : Num %8s Square %16s


assistant: ```c
void find(int base) {
  char nBuf[32];
  char sqBuf[32];
  long long n, s;
  for (n = 2;; n++) {
    s = n * n;
    toBaseN(sqBuf, s, base);
    if (strlen(sqBuf) >= base && countUnique(sqBuf) == base) {
      toBaseN(nBuf, n, base);
      toBaseN(sqBuf, s, base);
      printf("Base %d : Num %8s Square %16s\n", base, nBuf, sqBuf);
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x2,%ebp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
  jmp    L20
L7:
  add    $0x1,%rbp
L20:
  mov    %rbp,%r14
  mov    %r13,%rdi
  mov    %r12d,%edx
  imul   %rbp,%r14
  mov    %r14,%rsi
  call   <toBaseN@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L7
  mov    %r13,%rdi
  call   <countUnique@plt>
  cmp    %r12d,%eax
  jne    L7
  mov    %rsp,%r15
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <toBaseN@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <toBaseN@plt>
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: Base %d : Num %8s Square %16s


assistant: ```c
void find(int base) {
  char nBuf[32];
  char sqBuf[32];
  long long n, s;
  for (n = 2;; n++) {
    s = n * n;
    toBaseN(sqBuf, s, base);
    if (strlen(sqBuf) >= base && countUnique(sqBuf) == base) {
      toBaseN(nBuf, n, base);
      toBaseN(sqBuf, s, base);
      printf("Base %d : Num %8s Square %16s\n", base, nBuf, sqBuf);
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L14:
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L14
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %ecx,%edx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D16: Enter a fraction: 

tool: D15: %1d / %d

tool: D7: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int n, n2, m, d, remainder;
  printf("Enter a fraction: ");
  scanf("%1d / %d", &n, &d);
  m = n;
  n2 = n;
  while (n != 0) {
    remainder = m % n;
    m = n;
    n = remainder;
  }
  printf("In lowest terms: %d/%d\n", n2 / m, (d / m));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  je     L16
  movl   $0x0,(%rsp)
L16:
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string

tool: D1: Enter a fraction: 

tool: D20: %1d / %d

tool: D18: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int n, n2, m, d, remainder;
  printf("Enter a fraction: ");
  scanf("%1d / %d", &n, &d);
  m = n;
  n2 = n;
  while (n != 0) {
    remainder = m % n;
    m = n;
    n = remainder;
  }
  printf("In lowest terms: %d/%d\n", n2 / m, (d / m));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  mov    0x4(%rsp),%eax
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  movl   $0x0,(%rsp)
  cltd
  idiv   %ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_guessed: string
name: retrieve_data
arguments: data_label: D6
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D10: Enter a fraction: 

tool: D6: %1d / %d

tool: D12: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int n, n2, m, d, remainder;
  printf("Enter a fraction: ");
  scanf("%1d / %d", &n, &d);
  m = n;
  n2 = n;
  while (n != 0) {
    remainder = m % n;
    m = n;
    n = remainder;
  }
  printf("In lowest terms: %d/%d\n", n2 / m, (d / m));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  mov    0x4(%rsp),%eax
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  movl   $0x0,(%rsp)
  cltd
  idiv   %ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D27: Enter a fraction: 

tool: D0: %1d / %d

tool: D7: In lowest terms: %d/%d


assistant: ```c
int main(void) {
  int n, n2, m, d, remainder;
  printf("Enter a fraction: ");
  scanf("%1d / %d", &n, &d);
  m = n;
  n2 = n;
  while (n != 0) {
    remainder = m % n;
    m = n;
    n = remainder;
  }
  printf("In lowest terms: %d/%d\n", n2 / m, (d / m));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concat_fopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r12
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %rax,%rdx
  mov    %rdx,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  mov    %rax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    %rax,%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L2:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L2
L1:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L29
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L29:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x50(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x58(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %r12,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
concat_fopen(char *s1, char *s2, char *mode) {
  char str[strlen(s1) + strlen(s2) + 1];
  strcpy(str, s1);
  strcat(str, s2);
  return fopen(str, mode);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<concat_fopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x10(%r14,%rax,1),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L24:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L2:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L7
  orq    $0x0,-0x8(%rsp,%rax,1)
L7:
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <fopen@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
concat_fopen(char *s1, char *s2, char *mode) {
  char str[strlen(s1) + strlen(s2) + 1];
  strcpy(str, s1);
  strcat(str, s2);
  return fopen(str, mode);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<concat_fopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x10(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L45
L43:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L43
L45:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L41
L18:
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <fopen@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L18
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
concat_fopen(char *s1, char *s2, char *mode) {
  char str[strlen(s1) + strlen(s2) + 1];
  strcpy(str, s1);
  strcat(str, s2);
  return fopen(str, mode);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<concat_fopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x10(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L35
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L35:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L47
L12:
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <fopen@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L12
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
concat_fopen(char *s1, char *s2, char *mode) {
  char str[strlen(s1) + strlen(s2) + 1];
  strcpy(str, s1);
  strcat(str, s2);
  return fopen(str, mode);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flat_put_addr_at_rp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0xc0000000,%eax
  test   %rax,%rax
  je     L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_unaligned@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x80000000,%eax
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  and    $0xffc00000,%eax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  shr    $0xa,%rax
  or     %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L11
L6:
  mov    -0x8(%rbp),%rax
  and    $0xfffffc00,%eax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  and    $0x3ff,%eax
  or     %rdx,%rax
  mov    %rax,-0x20(%rbp)
L11:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <put_unaligned@plt>
  nop
  leave
  ret
```

assistant: ```c
unsigned long flat_put_addr_at_rp(unsigned long *rp, unsigned long addr, unsigned long relval) {
  if (relval & 0xC0000000) {
    unsigned long old_val = get_unaligned(rp);
    if (relval & 0x80000000)
      addr = (old_val & 0xffc00000) | (addr >> 10);
    else
      addr = (old_val & 0xfffffc00) | (addr & 0x3ff);
  }
  put_unaligned(addr, rp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<flat_put_addr_at_rp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   $0xc0000000,%edx
  jne    L21
L11:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    %rdx,%r12
  call   <get_unaligned@plt>
  test   $0x80000000,%r12d
  je     L13
  shr    $0xa,%rbx
  and    $0xffc00000,%eax
  or     %rax,%rbx
  jmp    L11
L13:
  and    $0x3ff,%ebx
  and    $0xfffffc00,%eax
  or     %rax,%rbx
  jmp    L11
```

assistant: ```c
unsigned long flat_put_addr_at_rp(unsigned long *rp, unsigned long addr, unsigned long relval) {
  if (relval & 0xC0000000) {
    unsigned long old_val = get_unaligned(rp);
    if (relval & 0x80000000)
      addr = (old_val & 0xffc00000) | (addr >> 10);
    else
      addr = (old_val & 0xfffffc00) | (addr & 0x3ff);
  }
  put_unaligned(addr, rp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flat_put_addr_at_rp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   $0xc0000000,%edx
  jne    L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rdx,%rbx
  call   <get_unaligned@plt>
  test   $0x80000000,%ebx
  je     L12
  and    $0xffc00000,%eax
  shr    $0xa,%rbp
  mov    %r12,%rsi
  or     %rax,%rbp
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  and    $0xfffffc00,%eax
  and    $0x3ff,%ebp
  mov    %r12,%rsi
  or     %rax,%rbp
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long flat_put_addr_at_rp(unsigned long *rp, unsigned long addr, unsigned long relval) {
  if (relval & 0xC0000000) {
    unsigned long old_val = get_unaligned(rp);
    if (relval & 0x80000000)
      addr = (old_val & 0xffc00000) | (addr >> 10);
    else
      addr = (old_val & 0xfffffc00) | (addr & 0x3ff);
  }
  put_unaligned(addr, rp);
}
```
user: What is the c source code of the assembly code below?

```asm
<flat_put_addr_at_rp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   $0xc0000000,%edx
  jne    L4
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rdx,%rbx
  call   <get_unaligned@plt>
  test   $0x80000000,%ebx
  je     L1
  and    $0xffc00000,%eax
  shr    $0xa,%rbp
  mov    %r12,%rsi
  or     %rax,%rbp
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  and    $0xfffffc00,%eax
  and    $0x3ff,%ebp
  mov    %r12,%rsi
  or     %rax,%rbp
  mov    %rbp,%rdi
  call   <put_unaligned@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long flat_put_addr_at_rp(unsigned long *rp, unsigned long addr, unsigned long relval) {
  if (relval & 0xC0000000) {
    unsigned long old_val = get_unaligned(rp);
    if (relval & 0x80000000)
      addr = (old_val & 0xffc00000) | (addr >> 10);
    else
      addr = (old_val & 0xfffffc00) | (addr & 0x3ff);
  }
  put_unaligned(addr, rp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uart_puts_ln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xd,%edi
  call   <uart_putc@plt>
  mov    $0xa,%edi
  call   <uart_putc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_puts_ln(void) {
  uart_putc(0x0D);
  uart_putc(0x0A);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_puts_ln>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <uart_putc@plt>
  mov    $0xa,%edi
  call   <uart_putc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uart_puts_ln(void) {
  uart_putc(0x0D);
  uart_putc(0x0A);
}
```