ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gsm0710_close_channel>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0x3e,%eax
  jbe    L9
  ret
  nopl   (%rax)
L9:
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <is_channel_used@plt>
  test   %eax,%eax
  je     L4
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <mark_channel_unused@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x53,%edx
  pop    %r12
  jmp    1070 <gsm0710_write_frame@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void gsm0710_close_channel(struct gsm0710_context *ctx, int channel) {
  if (channel <= 0 || channel > 63)
    return;
  if (!is_channel_used(ctx, channel))
    return;
  mark_channel_unused(ctx, channel);
  gsm0710_write_frame(ctx, channel, 0x53, 0, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<PB_Cgcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L30
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L30:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L110:
  sarl   -0xc(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L25
  sarl   -0x8(%rbp)
  shll   -0x10(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L110
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L72
  mov    -0xc(%rbp),%eax
  jmp    L40
L72:
  mov    $0x0,%eax
L40:
  sub    %eax,-0x8(%rbp)
  sarl   -0x8(%rbp)
  jmp    L63
L98:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L32
  mov    -0xc(%rbp),%eax
  jmp    L70
L32:
  mov    $0x0,%eax
L70:
  sub    %eax,-0x8(%rbp)
  sarl   -0x8(%rbp)
L63:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L98
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L56:
  cmpl   $0x0,-0xc(%rbp)
  jg     L25
  mov    -0x8(%rbp),%eax
  imul   -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int PB_Cgcd(int M, int N) {
  int gcd = 1, m_val, n_val, t;
  if (M > N) {
    m_val = N;
    n_val = M;
  } else {
    m_val = M;
    n_val = N;
  }
  while (m_val > 0) {
    while (!(m_val & 1)) {
      m_val >>= 1;
      if (!(n_val & 1)) {
        n_val >>= 1;
        gcd <<= 1;
      }
    }
    n_val -= (n_val & 1) ? m_val : 0;
    n_val >>= 1;
    while (n_val >= m_val) {
      n_val -= (n_val & 1) ? m_val : 0;
      n_val >>= 1;
    }
    t = n_val;
    n_val = m_val;
    m_val = t;
  }
  return (n_val * gcd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PB_Cgcd>:
  endbr64
  cmp    %esi,%edi
  jg     L108
  mov    %esi,%eax
  mov    %edi,%esi
  mov    %eax,%edi
L108:
  test   %esi,%esi
  jle    L71
  mov    $0x1,%eax
  jmp    L42
L54:
  test   $0x1,%sil
  jne    L8
L10:
  sar    %esi
  test   $0x1,%dil
  jne    L54
  sar    %edi
  add    %eax,%eax
  jmp    L54
L8:
  mov    %edi,%edx
  and    $0x1,%edx
  cmovne %esi,%edx
  sub    %edx,%edi
  sar    %edi
  mov    %edi,%edx
  cmp    %esi,%edi
  jl     L109
L65:
  mov    %edx,%ecx
  and    $0x1,%ecx
  cmovne %esi,%ecx
  sub    %ecx,%edx
  sar    %edx
  cmp    %esi,%edx
  jge    L65
L109:
  test   %edx,%edx
  jle    L62
  mov    %esi,%edi
  mov    %edx,%esi
L42:
  test   $0x1,%sil
  je     L10
  jmp    L8
L71:
  mov    %edi,%esi
  mov    $0x1,%eax
L62:
  imul   %esi,%eax
  ret
```

assistant: ```c
int PB_Cgcd(int M, int N) {
  int gcd = 1, m_val, n_val, t;
  if (M > N) {
    m_val = N;
    n_val = M;
  } else {
    m_val = M;
    n_val = N;
  }
  while (m_val > 0) {
    while (!(m_val & 1)) {
      m_val >>= 1;
      if (!(n_val & 1)) {
        n_val >>= 1;
        gcd <<= 1;
      }
    }
    n_val -= (n_val & 1) ? m_val : 0;
    n_val >>= 1;
    while (n_val >= m_val) {
      n_val -= (n_val & 1) ? m_val : 0;
      n_val >>= 1;
    }
    t = n_val;
    n_val = m_val;
    m_val = t;
  }
  return (n_val * gcd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PB_Cgcd>:
  endbr64
  cmp    %esi,%edi
  jg     L44
  mov    %esi,%eax
  mov    %edi,%esi
  mov    %eax,%edi
L44:
  test   %esi,%esi
  jle    L2
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edi,%ecx
  mov    %esi,%edx
  and    $0x1,%ecx
  test   $0x1,%sil
  jne    L37
  nopl   (%rax)
L76:
  mov    %edi,%ecx
  sar    %esi
  and    $0x1,%ecx
  jne    L41
  sar    %edi
  add    %eax,%eax
  mov    %edi,%ecx
  and    $0x1,%ecx
L41:
  test   $0x1,%sil
  je     L76
  mov    %esi,%edx
L37:
  mov    %edi,%r8d
  sub    %esi,%r8d
  test   %ecx,%ecx
  cmovne %r8d,%edi
  sar    %edi
  mov    %edi,%esi
  cmp    %edx,%edi
  jl     L15
  xchg   %ax,%ax
L20:
  mov    %esi,%ecx
  sub    %edx,%ecx
  test   $0x1,%sil
  cmovne %ecx,%esi
  sar    %esi
  cmp    %edx,%esi
  jge    L20
L15:
  test   %esi,%esi
  jle    L58
  mov    %edx,%edi
  jmp    L17
  nopl   0x0(%rax)
L58:
  imul   %edx,%eax
  ret
L2:
  mov    %edi,%eax
  ret
```

assistant: ```c
int PB_Cgcd(int M, int N) {
  int gcd = 1, m_val, n_val, t;
  if (M > N) {
    m_val = N;
    n_val = M;
  } else {
    m_val = M;
    n_val = N;
  }
  while (m_val > 0) {
    while (!(m_val & 1)) {
      m_val >>= 1;
      if (!(n_val & 1)) {
        n_val >>= 1;
        gcd <<= 1;
      }
    }
    n_val -= (n_val & 1) ? m_val : 0;
    n_val >>= 1;
    while (n_val >= m_val) {
      n_val -= (n_val & 1) ? m_val : 0;
      n_val >>= 1;
    }
    t = n_val;
    n_val = m_val;
    m_val = t;
  }
  return (n_val * gcd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PB_Cgcd>:
  endbr64
  cmp    %esi,%edi
  jg     L36
  mov    %esi,%eax
  mov    %edi,%esi
  mov    %eax,%edi
L36:
  test   %esi,%esi
  jle    L98
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %edi,%ecx
  and    $0x1,%ecx
  test   $0x1,%sil
  jne    L3
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %edi,%edx
  sar    %esi
  and    $0x1,%edx
  jne    L88
  sar    %edi
  add    %eax,%eax
  mov    %edi,%ecx
  and    $0x1,%ecx
  test   $0x1,%sil
  je     L93
L3:
  test   %ecx,%ecx
  jne    L120
  nopl   0x0(%rax)
L31:
  mov    %edi,%edx
  mov    %esi,%edi
L119:
  mov    %edx,%esi
  sar    %esi
  cmp    %edi,%esi
  jl     L2
  nopl   0x0(%rax)
L106:
  mov    %esi,%edx
  sub    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%esi
  sar    %esi
  cmp    %edi,%esi
  jge    L106
L2:
  test   %esi,%esi
  jg     L59
  imul   %edi,%eax
  ret
  nopl   0x0(%rax)
L88:
  test   $0x1,%sil
  jne    L120
L117:
  sar    %esi
  mov    %edx,%ecx
  test   $0x1,%sil
  je     L117
  test   %ecx,%ecx
  je     L31
  nopl   0x0(%rax)
L120:
  sub    %esi,%edi
  mov    %edi,%edx
  mov    %esi,%edi
  jmp    L119
L98:
  mov    %edi,%eax
  ret
```

assistant: ```c
int PB_Cgcd(int M, int N) {
  int gcd = 1, m_val, n_val, t;
  if (M > N) {
    m_val = N;
    n_val = M;
  } else {
    m_val = M;
    n_val = N;
  }
  while (m_val > 0) {
    while (!(m_val & 1)) {
      m_val >>= 1;
      if (!(n_val & 1)) {
        n_val >>= 1;
        gcd <<= 1;
      }
    }
    n_val -= (n_val & 1) ? m_val : 0;
    n_val >>= 1;
    while (n_val >= m_val) {
      n_val -= (n_val & 1) ? m_val : 0;
      n_val >>= 1;
    }
    t = n_val;
    n_val = m_val;
    m_val = t;
  }
  return (n_val * gcd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<split_and_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x424(%rbp)
  movl   $0x0,-0x420(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L24
L40:
  mov    -0x420(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x438(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L6
  mov    -0x41c(%rbp),%eax
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <char_to_num@plt>
  mov    %eax,-0x418(%rbp)
  cmpl   $0x0,-0x418(%rbp)
  js     L7
  mov    -0x418(%rbp),%edx
  mov    -0x424(%rbp),%ecx
  mov    -0x440(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <unique_insert@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  jns    L71
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L71:
  cmpl   $0x0,-0x414(%rbp)
  jle    L30
  addl   $0x1,-0x424(%rbp)
  jmp    L30
L7:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  movl   $0x0,-0x41c(%rbp)
  addl   $0x1,-0x420(%rbp)
  jmp    L24
L6:
  mov    -0x420(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x438(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x41c(%rbp),%eax
  cltq
  mov    %dl,-0x410(%rbp,%rax,1)
  addl   $0x1,-0x41c(%rbp)
  addl   $0x1,-0x420(%rbp)
L24:
  mov    -0x420(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x438(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    -0x424(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D6: insert data failed


tool: D19: number invalid


assistant: ```c
int split_and_insert(char buff[], int data[]) {
  char str[1024];
  int n, i, j, ret, tmp;
  memset(str, 0, sizeof(str));
  n = 0;
  i = 0;
  j = 0;
  while (buff[i] != '\0') {
    if ('\n' == buff[i]) {
      str[j] = '\0';
      tmp = char_to_num(str);
      if (tmp > -1) {
        ret = unique_insert(data, n, tmp);
        if (ret < 0)
          printf("insert data failed\n");
        else if (ret > 0)
          n++;
        else
          ;
      } else
        printf("number invalid\n");
      j = 0;
      i++;
      continue;
    }
    str[j] = buff[i];
    j++;
    i++;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split_and_insert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L53
  mov    $0x1,%ebx
  mov    $0x0,%edx
  mov    $0x0,%r12d
  lea    0x10(%rsp),%r13
  lea    D4(%rip),%r14
  lea    D1(%rip),%r15
  jmp    L46
L96:
  movslq %edx,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  mov    %r13,%rdi
  call   <char_to_num@plt>
  test   %eax,%eax
  js     L73
  mov    %eax,%edx
  mov    %r12d,%esi
  mov    0x8(%rsp),%rdi
  call   <unique_insert@plt>
  test   %eax,%eax
  js     L61
  setg   %al
  movzbl %al,%eax
  add    %eax,%r12d
L69:
  mov    %ebx,%eax
  mov    $0x0,%edx
L14:
  cltq
  movzbl 0x0(%rbp,%rax,1),%eax
  add    $0x1,%ebx
  test   %al,%al
  je     L41
L46:
  cmp    $0xa,%al
  je     L96
  movslq %edx,%rcx
  mov    %al,0x10(%rsp,%rcx,1)
  add    $0x1,%edx
  mov    %ebx,%eax
  jmp    L14
L61:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L69
L73:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L69
L53:
  mov    $0x0,%r12d
L41:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %r12d,%eax
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D4: number invalid


tool: D1: insert data failed


assistant: ```c
int split_and_insert(char buff[], int data[]) {
  char str[1024];
  int n, i, j, ret, tmp;
  memset(str, 0, sizeof(str));
  n = 0;
  i = 0;
  j = 0;
  while (buff[i] != '\0') {
    if ('\n' == buff[i]) {
      str[j] = '\0';
      tmp = char_to_num(str);
      if (tmp > -1) {
        ret = unique_insert(data, n, tmp);
        if (ret < 0)
          printf("insert data failed\n");
        else if (ret > 0)
          n++;
        else
          ;
      } else
        printf("number invalid\n");
      j = 0;
      i++;
      continue;
    }
    str[j] = buff[i];
    j++;
    i++;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split_and_insert>:
  endbr64
  push   %r15
  mov    $0x400,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L70
  add    $0x1,%rbx
  xor    %edx,%edx
  lea    D5(%rip),%r13
  xor    %r15d,%r15d
  lea    D11(%rip),%r14
  jmp    L52
  nopl   0x0(%rax)
L45:
  movslq %edx,%rcx
  add    $0x1,%rbx
  add    $0x1,%edx
  mov    %al,(%rsp,%rcx,1)
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L9
L52:
  cmp    $0xa,%al
  jne    L45
  movslq %edx,%rdx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <char_to_num@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L6
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <unique_insert@plt>
  test   %eax,%eax
  js     L92
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r15d
  xor    %edx,%edx
L55:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L52
  nopl   0x0(%rax)
L9:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x418,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %edx,%edx
  jmp    L55
  nopl   0x0(%rax)
L92:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %edx,%edx
  jmp    L55
  nopl   0x0(%rax)
L70:
  xor    %r15d,%r15d
  jmp    L9
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string

tool: D5: number invalid


tool: D11: insert data failed


assistant: ```c
int split_and_insert(char buff[], int data[]) {
  char str[1024];
  int n, i, j, ret, tmp;
  memset(str, 0, sizeof(str));
  n = 0;
  i = 0;
  j = 0;
  while (buff[i] != '\0') {
    if ('\n' == buff[i]) {
      str[j] = '\0';
      tmp = char_to_num(str);
      if (tmp > -1) {
        ret = unique_insert(data, n, tmp);
        if (ret < 0)
          printf("insert data failed\n");
        else if (ret > 0)
          n++;
        else
          ;
      } else
        printf("number invalid\n");
      j = 0;
      i++;
      continue;
    }
    str[j] = buff[i];
    j++;
    i++;
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split_and_insert>:
  endbr64
  push   %r15
  mov    $0x400,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L94
  add    $0x1,%rbx
  xor    %edx,%edx
  lea    D17(%rip),%r13
  xor    %r15d,%r15d
  lea    D1(%rip),%r14
  jmp    L73
  nopl   0x0(%rax)
L50:
  movslq %edx,%rcx
  add    $0x1,%rbx
  add    $0x1,%edx
  mov    %al,(%rsp,%rcx,1)
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L21
L73:
  cmp    $0xa,%al
  jne    L50
  movslq %edx,%rdx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rdx,1)
  call   <char_to_num@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L97
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <unique_insert@plt>
  test   %eax,%eax
  js     L11
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r15d
  xor    %edx,%edx
L66:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L73
  nopl   0x0(%rax)
L21:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x418,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %edx,%edx
  jmp    L66
  nopl   0x0(%rax)
L11:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %edx,%edx
  jmp    L66
  nopl   0x0(%rax)
L94:
  xor    %r15d,%r15d
  jmp    L21
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D17: number invalid


tool: D1: insert data failed


assistant: ```c
int split_and_insert(char buff[], int data[]) {
  char str[1024];
  int n, i, j, ret, tmp;
  memset(str, 0, sizeof(str));
  n = 0;
  i = 0;
  j = 0;
  while (buff[i] != '\0') {
    if ('\n' == buff[i]) {
      str[j] = '\0';
      tmp = char_to_num(str);
      if (tmp > -1) {
        ret = unique_insert(data, n, tmp);
        if (ret < 0)
          printf("insert data failed\n");
        else if (ret > 0)
          n++;
        else
          ;
      } else
        printf("number invalid\n");
      j = 0;
      i++;
      continue;
    }
    str[j] = buff[i];
    j++;
    i++;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sched_stat_runtime_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L3
  mov    -0x30(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_arg_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_arg_u64@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_or_add_task@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D3: comm

tool: D6: tid

assistant: ```c
void sched_stat_runtime_process(const char *modname, int pass, double clock, int cpu, void *args) {
  const char *comm;
  int tid;
  if (pass == 1) {
    comm = get_arg_str(args, "comm");
    tid = (int)get_arg_u64(args, "tid");
    (void)find_or_add_task(comm, tid);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sched_stat_runtime_process>:
  endbr64
  cmp    $0x1,%esi
  je     L0
  ret
L0:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%rbx
  lea    D6(%rip),%rsi
  mov    %rcx,%rdi
  call   <get_arg_str@plt>
  mov    %rax,%rbp
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <get_arg_u64@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <find_or_add_task@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string

tool: D6: comm

tool: D12: tid

assistant: ```c
void sched_stat_runtime_process(const char *modname, int pass, double clock, int cpu, void *args) {
  const char *comm;
  int tid;
  if (pass == 1) {
    comm = get_arg_str(args, "comm");
    tid = (int)get_arg_u64(args, "tid");
    (void)find_or_add_task(comm, tid);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sched_stat_runtime_process>:
  endbr64
  cmp    $0x1,%esi
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  push   %r12
  mov    %rcx,%rdi
  lea    D17(%rip),%rsi
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <get_arg_str@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  mov    %rax,%r12
  call   <get_arg_u64@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1080 <find_or_add_task@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string

tool: D17: comm

tool: D0: tid

assistant: ```c
void sched_stat_runtime_process(const char *modname, int pass, double clock, int cpu, void *args) {
  const char *comm;
  int tid;
  if (pass == 1) {
    comm = get_arg_str(args, "comm");
    tid = (int)get_arg_u64(args, "tid");
    (void)find_or_add_task(comm, tid);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sched_stat_runtime_process>:
  endbr64
  cmp    $0x1,%esi
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  push   %r12
  mov    %rcx,%rdi
  lea    D8(%rip),%rsi
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <get_arg_str@plt>
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  call   <get_arg_u64@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1080 <find_or_add_task@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D8: comm

tool: D2: tid

assistant: ```c
void sched_stat_runtime_process(const char *modname, int pass, double clock, int cpu, void *args) {
  const char *comm;
  int tid;
  if (pass == 1) {
    comm = get_arg_str(args, "comm");
    tid = (int)get_arg_u64(args, "tid");
    (void)find_or_add_task(comm, tid);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<byte_col_big5hkscs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3f,-0x4(%rbp)
  jle    L7
  cmpl   $0x7e,-0x4(%rbp)
  jg     L7
  mov    -0x4(%rbp),%eax
  sub    $0x40,%eax
  jmp    L33
L7:
  cmpl   $0xa0,-0x4(%rbp)
  jle    L50
  cmpl   $0xfe,-0x4(%rbp)
  jg     L50
  mov    -0x4(%rbp),%eax
  sub    $0x62,%eax
  jmp    L33
L50:
  mov    $0xffffffff,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int byte_col_big5hkscs(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0xa1 && byte < 0xff)
    return byte - 0x62;
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<byte_col_big5hkscs>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L0
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  ja     L11
  lea    -0x62(%rdi),%eax
  ret
L11:
  mov    $0xffffffff,%eax
L0:
  ret
```

assistant: ```c
int byte_col_big5hkscs(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0xa1 && byte < 0xff)
    return byte - 0x62;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<byte_col_big5hkscs>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L17
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  ja     L11
  lea    -0x62(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
L17:
  ret
```

assistant: ```c
int byte_col_big5hkscs(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0xa1 && byte < 0xff)
    return byte - 0x62;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<byte_col_big5hkscs>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L15
  lea    -0xa1(%rdi),%eax
  cmp    $0x5d,%eax
  ja     L0
  lea    -0x62(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
L15:
  ret
```

assistant: ```c
int byte_col_big5hkscs(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0xa1 && byte < 0xff)
    return byte - 0x62;
  else
    return -1;
}
```