ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<cat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  mov    $0x1,%edi
  call   <exit@plt>
L18:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <cat_fd@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    $0x2,%edi
  call   <exit@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void cat(const char *path) {
  int r, fd;
  fd = open(path, 0);
  if (fd < 0)
    exit(1);
  cat_fd(fd);
  r = close(fd);
  if (r < 0)
    exit(2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cat>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L3
L2:
  mov    %ebx,%edi
  call   <cat_fd@plt>
  mov    %ebx,%edi
  call   <close@plt>
  test   %eax,%eax
  js     L38
L11:
  pop    %rbx
  ret
L3:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L38:
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L11
```

assistant: ```c
void cat(const char *path) {
  int r, fd;
  fd = open(path, 0);
  if (fd < 0)
    exit(1);
  cat_fd(fd);
  r = close(fd);
  if (r < 0)
    exit(2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cat>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L2
L7:
  mov    %ebp,%edi
  call   <cat_fd@plt>
  mov    %ebp,%edi
  call   <close@plt>
  test   %eax,%eax
  js     L19
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L7
  nopl   0x0(%rax)
L19:
  mov    $0x2,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

assistant: ```c
void cat(const char *path) {
  int r, fd;
  fd = open(path, 0);
  if (fd < 0)
    exit(1);
  cat_fd(fd);
  r = close(fd);
  if (r < 0)
    exit(2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cat>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L17
L22:
  mov    %ebp,%edi
  call   <cat_fd@plt>
  mov    %ebp,%edi
  call   <close@plt>
  test   %eax,%eax
  js     L29
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
  nopl   0x0(%rax)
L29:
  mov    $0x2,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

assistant: ```c
void cat(const char *path) {
  int r, fd;
  fd = open(path, 0);
  if (fd < 0)
    exit(1);
  cat_fd(fd);
  r = close(fd);
  if (r < 0)
    exit(2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<close_output_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L18
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  nop
L18:
  nop
  leave
  ret
```

assistant: ```c
void close_output_file(FILE *handle, char *filename, int errors) {
  if ((handle != stdout) && (handle != NULL)) {
    fclose(handle);
    if (errors)
      remove(filename);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<close_output_file>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %rdi,(%rax)
  je     L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  test   %rdi,%rdi
  je     L18
  call   <fclose@plt>
  test   %ebx,%ebx
  jne    L31
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    %rbp,%rdi
  call   <remove@plt>
  jmp    L18
L1:
  ret
```

assistant: ```c
void close_output_file(FILE *handle, char *filename, int errors) {
  if ((handle != stdout) && (handle != NULL)) {
    fclose(handle);
    if (errors)
      remove(filename);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<close_output_file>:
  endbr64
  mov    D4(%rip),%rax
  cmp    %rdi,(%rax)
  je     L24
  test   %rdi,%rdi
  je     L24
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fclose@plt>
  test   %ebx,%ebx
  jne    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  ret
  nopl   0x0(%rax)
L28:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <remove@plt>
```

assistant: ```c
void close_output_file(FILE *handle, char *filename, int errors) {
  if ((handle != stdout) && (handle != NULL)) {
    fclose(handle);
    if (errors)
      remove(filename);
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<close_output_file>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %rdi,(%rax)
  je     L15
  test   %rdi,%rdi
  je     L15
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fclose@plt>
  test   %ebx,%ebx
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <remove@plt>
```

assistant: ```c
void close_output_file(FILE *handle, char *filename, int errors) {
  if ((handle != stdout) && (handle != NULL)) {
    fclose(handle);
    if (errors)
      remove(filename);
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <floorf@plt>
  movq   %xmm0,%rbx
  movss  -0x1c(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movsd  %xmm3,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <ceilf@plt>
  movq   %xmm0,%rax
  movq   %rbx,%xmm2
  movsd  -0x28(%rbp),%xmm1
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D19
data_type: string

tool: D7: Enter a Number: 

tool: D18: %f

tool: D19: %.0f %.5f %.0f 


assistant: ```c
int main() {
  float n;
  printf("Enter a Number: ");
  scanf("%f", &n);
  printf("%.0f %.5f %.0f \n", ceilf(n), n, floorf(n));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  call   <floorf@plt>
  movq   %xmm0,%rbx
  movss  0x14(%rsp),%xmm3
  movss  %xmm3,0xc(%rsp)
  movaps %xmm3,%xmm0
  call   <ceilf@plt>
  movq   %rbx,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  lea    D7(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D1: Enter a Number: 

tool: D19: %f

tool: D7: %.0f %.5f %.0f 


assistant: ```c
int main() {
  float n;
  printf("Enter a Number: ");
  scanf("%f", &n);
  printf("%.0f %.5f %.0f \n", ceilf(n), n, floorf(n));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  call   <floorf@plt>
  movss  0x14(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0x4(%rsp)
  call   <ceilf@plt>
  movss  0x4(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  lea    D18(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string
name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string

tool: D8: Enter a Number: 

tool: D7: %f

tool: D18: %.0f %.5f %.0f 


assistant: ```c
int main() {
  float n;
  printf("Enter a Number: ");
  scanf("%f", &n);
  printf("%.0f %.5f %.0f \n", ceilf(n), n, floorf(n));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  call   <floorf@plt>
  movss  0x14(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0x4(%rsp)
  call   <ceilf@plt>
  movss  0x4(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  lea    D3(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string

tool: D9: Enter a Number: 

tool: D7: %f

tool: D3: %.0f %.5f %.0f 


assistant: ```c
int main() {
  float n;
  printf("Enter a Number: ");
  scanf("%f", &n);
  printf("%.0f %.5f %.0f \n", ceilf(n), n, floorf(n));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x5,-0x14(%rbp)
  je     L16
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L16:
  mov    -0x20(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rsi
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <process_biofile@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: Usage %s fasta_file qual_file extras_file output_file



assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 5) {
    printf("Usage %s fasta_file qual_file extras_file output_file\n\n", argv[0]);
    return -1;
  }
  int res = process_biofile(argv[1], argv[2], argv[3], argv[4]);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x5,%edi
  jne    L0
  mov    0x20(%rsi),%rcx
  mov    0x18(%rsi),%rdx
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <process_biofile@plt>
L19:
  add    $0x8,%rsp
  ret
L0:
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: Usage %s fasta_file qual_file extras_file output_file



assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 5) {
    printf("Usage %s fasta_file qual_file extras_file output_file\n\n", argv[0]);
    return -1;
  }
  int res = process_biofile(argv[1], argv[2], argv[3], argv[4]);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x5,%edi
  jne    L3
  mov    0x10(%rsi),%r8
  mov    0x20(%rsi),%rcx
  mov    0x18(%rsi),%rdx
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1060 <process_biofile@plt>
L3:
  push   %rax
  mov    (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rdx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: Usage %s fasta_file qual_file extras_file output_file



assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 5) {
    printf("Usage %s fasta_file qual_file extras_file output_file\n\n", argv[0]);
    return -1;
  }
  int res = process_biofile(argv[1], argv[2], argv[3], argv[4]);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x5,%edi
  jne    L9
  mov    0x10(%rsi),%r8
  mov    0x20(%rsi),%rcx
  mov    0x18(%rsi),%rdx
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1060 <process_biofile@plt>
L9:
  push   %rax
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rdx
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: Usage %s fasta_file qual_file extras_file output_file



assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 5) {
    printf("Usage %s fasta_file qual_file extras_file output_file\n\n", argv[0]);
    return -1;
  }
  int res = process_biofile(argv[1], argv[2], argv[3], argv[4]);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_error_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    $0x100,%edi
  call   <my_malloc@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *write_error_message(char *format, ...) {
  char *p = my_malloc(256);
  memset(p, 0, sizeof(p));
  va_list ap;
  va_start(ap, format);
  vsnprintf(p, 256, format, ap);
  va_end(ap);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_error_message>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x100,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbx
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *write_error_message(char *format, ...) {
  char *p = my_malloc(256);
  memset(p, 0, sizeof(p));
  va_list ap;
  va_start(ap, format);
  vsnprintf(p, 256, format, ap);
  va_end(ap);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_error_message>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x100,%edi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  call   <my_malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x100,%esi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *write_error_message(char *format, ...) {
  char *p = my_malloc(256);
  memset(p, 0, sizeof(p));
  va_list ap;
  va_start(ap, format);
  vsnprintf(p, 256, format, ap);
  va_end(ap);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_error_message>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x100,%edi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  call   <my_malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x100,%esi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *write_error_message(char *format, ...) {
  char *p = my_malloc(256);
  memset(p, 0, sizeof(p));
  va_list ap;
  va_start(ap, format);
  vsnprintf(p, 256, format, ap);
  va_end(ap);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<malloc_good_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L59
  mov    $0x1,%eax
  jmp    L4
L59:
  cmpq   $0x800,-0x18(%rbp)
  ja     L45
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L11:
  addl   $0x1,-0xc(%rbp)
L41:
  shrq   -0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  jmp    L4
L45:
  mov    -0x18(%rbp),%rax
  add    $0xfff,%rax
  and    $0xfffffffffffff000,%rax
L4:
  pop    %rbp
  ret
```

assistant: ```c
size_t malloc_good_size(size_t size) {
  if (size == 0) {
    return 1;
  } else if (size <= (((1UL << (12))) >> 1)) {
    int j;
    size_t ii;
    j = 1;
    ii = size - 1;
    while (ii >>= 1)
      j++;
    return ((size_t)1) << j;
  } else {
    return (((size) + ((((1UL << (12))) - 1))) & ~(((1UL << (12))) - 1));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<malloc_good_size>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L37
  cmp    $0x800,%rdi
  ja     L12
  sub    $0x1,%rdi
  shr    %rdi
  je     L21
  mov    $0x1,%ecx
L38:
  add    $0x1,%ecx
  shr    %rdi
  jne    L38
L23:
  mov    $0x1,%eax
  shl    %cl,%rax
  ret
L21:
  mov    $0x1,%ecx
  jmp    L23
L12:
  lea    0xfff(%rdi),%rax
  and    $0xfffffffffffff000,%rax
L37:
  ret
```

assistant: ```c
size_t malloc_good_size(size_t size) {
  if (size == 0) {
    return 1;
  } else if (size <= (((1UL << (12))) >> 1)) {
    int j;
    size_t ii;
    j = 1;
    ii = size - 1;
    while (ii >>= 1)
      j++;
    return ((size_t)1) << j;
  } else {
    return (((size) + ((((1UL << (12))) - 1))) & ~(((1UL << (12))) - 1));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_good_size>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L21
  cmp    $0x800,%rdi
  ja     L11
  sub    $0x1,%rdi
  shr    %rdi
  je     L0
  mov    $0x1,%ecx
  nopl   (%rax)
L33:
  add    $0x1,%ecx
  shr    %rdi
  jne    L33
  mov    $0x1,%eax
  shl    %cl,%rax
  ret
  nopl   0x0(%rax)
L11:
  lea    0xfff(%rdi),%rax
  and    $0xfffffffffffff000,%rax
L21:
  ret
  xchg   %ax,%ax
L0:
  mov    $0x2,%eax
  ret
```

assistant: ```c
size_t malloc_good_size(size_t size) {
  if (size == 0) {
    return 1;
  } else if (size <= (((1UL << (12))) >> 1)) {
    int j;
    size_t ii;
    j = 1;
    ii = size - 1;
    while (ii >>= 1)
      j++;
    return ((size_t)1) << j;
  } else {
    return (((size) + ((((1UL << (12))) - 1))) & ~(((1UL << (12))) - 1));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<malloc_good_size>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L21
  cmp    $0x800,%rdi
  ja     L18
  sub    $0x1,%rdi
  shr    %rdi
  je     L0
  mov    $0x1,%ecx
  nopl   (%rax)
L31:
  add    $0x1,%ecx
  shr    %rdi
  jne    L31
  mov    $0x1,%eax
  shl    %cl,%rax
  ret
  nopl   0x0(%rax)
L18:
  lea    0xfff(%rdi),%rax
  and    $0xfffffffffffff000,%rax
L21:
  ret
  xchg   %ax,%ax
L0:
  mov    $0x2,%eax
  ret
```

assistant: ```c
size_t malloc_good_size(size_t size) {
  if (size == 0) {
    return 1;
  } else if (size <= (((1UL << (12))) >> 1)) {
    int j;
    size_t ii;
    j = 1;
    ii = size - 1;
    while (ii >>= 1)
      j++;
    return ((size_t)1) << j;
  } else {
    return (((size) + ((((1UL << (12))) - 1))) & ~(((1UL << (12))) - 1));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<day_of_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x68db8bad,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   $0xffffd8f0,%eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   $0xffffd8f0,%eax,%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   $0xffffff9c,%eax,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <gregdate_to_julday@plt>
  mov    %rax,%rbx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <gregdate_to_julday@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  add    $0x1,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long day_of_year(int date) {
  const int year = date / 10000;
  const int month = (date - year * 10000) / 100;
  const int day = date - year * 10000 - month * 100;
  return gregdate_to_julday(year, month, day) - gregdate_to_julday(year, 1, 1) + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<day_of_year>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %edi,%rbx
  imul   $0x68db8bad,%rbx,%rbx
  sar    $0x2c,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  imul   $0xffffd8f0,%ebx,%eax
  add    %eax,%edi
  movslq %edi,%rsi
  imul   $0x51eb851f,%rsi,%rsi
  sar    $0x25,%rsi
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  imul   $0xffffff9c,%esi,%edx
  add    %edi,%edx
  mov    %ebx,%edi
  call   <gregdate_to_julday@plt>
  mov    %rax,%rbp
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <gregdate_to_julday@plt>
  mov    %rax,%rdx
  lea    0x1(%rbp),%rax
  sub    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long day_of_year(int date) {
  const int year = date / 10000;
  const int month = (date - year * 10000) / 100;
  const int day = date - year * 10000 - month * 100;
  return gregdate_to_julday(year, month, day) - gregdate_to_julday(year, 1, 1) + 1;
}
```