ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_analyze@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_analyze(argc, argv);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_analyze@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_analyze(argc, argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_analyze@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_analyze(argc, argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_analyze@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_analyze(argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CTAI_Util_IQSort2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  cmp    %ecx,%edx
  jl     L29
L84:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %rdi,%r15
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %ecx,%esi
  mov    %edx,%edi
  call   <choose_pivot@plt>
  cltq
  lea    0x0(,%rax,4),%rbp
  movslq %r14d,%rbx
  shl    $0x2,%rbx
  lea    (%r15,%rbx,1),%r12
  mov    %r12,0x20(%rsp)
  lea    (%r15,%rbp,1),%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %rbx,%rdi
  mov    0x8(%rsp),%rax
  add    %rax,%rdi
  mov    %rdi,0x28(%rsp)
  lea    (%rax,%rbp,1),%rsi
  call   <swap@plt>
  mov    (%r12),%r12d
  lea    0x1(%r14),%ebp
  mov    %r13d,%ebx
  cmp    %ebp,%r13d
  jge    L79
L121:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rbp
  lea    (%r15,%rbp,1),%rsi
  mov    0x20(%rsp),%rdi
  call   <swap@plt>
  mov    0x8(%rsp),%r12
  lea    (%r12,%rbp,1),%rsi
  mov    0x28(%rsp),%rdi
  call   <swap@plt>
  lea    -0x1(%rbx),%ecx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <CTAI_Util_IQSort2>
  lea    0x1(%rbx),%edx
  mov    %r13d,%ecx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <CTAI_Util_IQSort2>
  jmp    L84
L21:
  cmp    %ebx,%r14d
  jg     L33
  movslq %ebx,%rax
  lea    (%r15,%rax,4),%rax
L63:
  cmp    %r12d,(%rax)
  jle    L33
  sub    $0x1,%ebx
  sub    $0x4,%rax
  cmp    %ebx,%r14d
  jle    L63
L33:
  cmp    %ebx,%ebp
  jl     L100
  jne    L121
L79:
  movslq %ebp,%rax
  lea    (%r15,%rax,4),%rax
  cmp    %ebp,%r13d
  jl     L21
L69:
  cmp    %r12d,(%rax)
  jg     L21
  add    $0x1,%ebp
  add    $0x4,%rax
  cmp    %ebp,%r13d
  jge    L69
  jmp    L21
L100:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  movslq %ebp,%rax
  shl    $0x2,%rax
  mov    %rdx,0x10(%rsp)
  lea    (%r15,%rdx,1),%rsi
  mov    %rax,0x18(%rsp)
  lea    (%r15,%rax,1),%rdi
  call   <swap@plt>
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rcx
  add    %rcx,%rsi
  mov    0x18(%rsp),%rdi
  add    %rcx,%rdi
  call   <swap@plt>
  jmp    L79
```

assistant: ```c
void CTAI_Util_IQSort2(int *list, int *indx, int m, int n) {
  int key, i, j, k;
  if (m < n) {
    k = choose_pivot(m, n);
    swap(&list[m], &list[k]);
    swap(&indx[m], &indx[k]);
    key = list[m];
    i = m + 1;
    j = n;
    while (i <= j) {
      while ((i <= n) && (list[i] <= key))
        i++;
      while ((j >= m) && (list[j] > key))
        j--;
      if (i < j) {
        swap(&list[i], &list[j]);
        swap(&indx[i], &indx[j]);
      }
    }
    swap(&list[m], &list[j]);
    swap(&indx[m], &indx[j]);
    CTAI_Util_IQSort2(list, indx, m, j - 1);
    CTAI_Util_IQSort2(list, indx, j + 1, n);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<core__math___Float___is_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <math___Float_is_nan___impl@plt>
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  nop
  movzwl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
short int core__math___Float___is_nan(double self) {
  short int var;
  short int var1;
  var1 = math___Float_is_nan___impl(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<core__math___Float___is_nan>:
  endbr64
  sub    $0x8,%rsp
  call   <math___Float_is_nan___impl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
short int core__math___Float___is_nan(double self) {
  short int var;
  short int var1;
  var1 = math___Float_is_nan___impl(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<core__math___Float___is_nan>:
  endbr64
  jmp    1050 <math___Float_is_nan___impl@plt>
```

assistant: ```c
short int core__math___Float___is_nan(double self) {
  short int var;
  short int var1;
  var1 = math___Float_is_nan___impl(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What is the c source code of the assembly code below:

```asm
<constant_pointers_to_variables>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x20,-0x20(%rbp)
  movl   $0x10,-0x1c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D48
type_guessed: string
name: retrieve_data
arguments: data_tag: D51
type_guessed: string
name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D42
type_guessed: string

tool: D18: 
[3] ----------------------------


tool: D48: Constant pointer to variables:

tool: D51: Memory Address of 'a': %p


tool: D25: Value of 'a': %i



tool: D13: Memory Address of 'b': %p


tool: D42: Value of 'b': %i



assistant: ```c
void constant_pointers_to_variables(void) {
  printf("\n[3] ----------------------------\n\n");
  printf("Constant pointer to variables:\n");
  int a = 32, b = 16;
  int *const c = &(a);
  int *const d = &(b);
  *d = *c;
  printf("Memory Address of 'a': %p\n", c);
  printf("Value of 'a': %i\n\n", *c);
  printf("Memory Address of 'b': %p\n", d);
  printf("Value of 'b': %i\n\n", *d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<constant_pointers_to_variables>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  movl   $0x20,(%rsp)
  movl   $0x20,0x4(%rsp)
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D38
data_type: string
name: read_data
arguments: data_label: D49
data_type: string
name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D52
data_type: string
name: read_data
arguments: data_label: D25
data_type: string

tool: D38: 
[3] ----------------------------


tool: D49: Constant pointer to variables:

tool: D19: Memory Address of 'a': %p


tool: D11: Value of 'a': %i



tool: D52: Memory Address of 'b': %p


tool: D25: Value of 'b': %i



assistant: ```c
void constant_pointers_to_variables(void) {
  printf("\n[3] ----------------------------\n\n");
  printf("Constant pointer to variables:\n");
  int a = 32, b = 16;
  int *const c = &(a);
  int *const d = &(b);
  *d = *c;
  printf("Memory Address of 'a': %p\n", c);
  printf("Value of 'a': %i\n\n", *c);
  printf("Memory Address of 'b': %p\n", d);
  printf("Value of 'b': %i\n\n", *d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<constant_pointers_to_variables>:
  endbr64
  sub    $0x18,%rsp
  lea    D55(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  movl   $0x20,(%rsp)
  movl   $0x20,0x4(%rsp)
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D55
data_type: string
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D49
data_type: string
name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D47
data_type: string

tool: D55: 
[3] ----------------------------


tool: D0: Constant pointer to variables:

tool: D49: Memory Address of 'a': %p


tool: D31: Value of 'a': %i



tool: D2: Memory Address of 'b': %p


tool: D47: Value of 'b': %i



assistant: ```c
void constant_pointers_to_variables(void) {
  printf("\n[3] ----------------------------\n\n");
  printf("Constant pointer to variables:\n");
  int a = 32, b = 16;
  int *const c = &(a);
  int *const d = &(b);
  *d = *c;
  printf("Memory Address of 'a': %p\n", c);
  printf("Value of 'a': %i\n\n", *c);
  printf("Memory Address of 'b': %p\n", d);
  printf("Value of 'b': %i\n\n", *d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<constant_pointers_to_variables>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  movl   $0x20,(%rsp)
  movl   $0x20,0x4(%rsp)
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D50
data_type: string
name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string
name: retrieve_data
arguments: data_tag: D57
data_type: string
name: retrieve_data
arguments: data_tag: D54
data_type: string

tool: D16: 
[3] ----------------------------


tool: D50: Constant pointer to variables:

tool: D20: Memory Address of 'a': %p


tool: D18: Value of 'a': %i



tool: D57: Memory Address of 'b': %p


tool: D54: Value of 'b': %i



assistant: ```c
void constant_pointers_to_variables(void) {
  printf("\n[3] ----------------------------\n\n");
  printf("Constant pointer to variables:\n");
  int a = 32, b = 16;
  int *const c = &(a);
  int *const d = &(b);
  *d = *c;
  printf("Memory Address of 'a': %p\n", c);
  printf("Value of 'a': %i\n\n", *c);
  printf("Memory Address of 'b': %p\n", d);
  printf("Value of 'b': %i\n\n", *d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_mmc_device>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L14
L3:
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
bool is_mmc_device(off_t device_size) {
  if (device_size == 0)
    return false;
  if (device_size > (32 * (1024 * (1024 * (1024LL)))))
    return false;
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_mmc_device>:
  endbr64
  test   %edi,%edi
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_mmc_device(off_t device_size) {
  if (device_size == 0)
    return false;
  if (device_size > (32 * (1024 * (1024 * (1024LL)))))
    return false;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_mmc_device>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  setne  %al
  ret
```

assistant: ```c
bool is_mmc_device(off_t device_size) {
  if (device_size == 0)
    return false;
  if (device_size > (32 * (1024 * (1024 * (1024LL)))))
    return false;
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_mmc_device>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  setne  %al
  ret
```

assistant: ```c
bool is_mmc_device(off_t device_size) {
  if (device_size == 0)
    return false;
  if (device_size > (32 * (1024 * (1024 * (1024LL)))))
    return false;
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L13:
  nop
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L14:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x3,%eax
  shl    $0x9,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x3,-0x4(%rbp)
  jle    L14
  addl   $0x1,-0x8(%rbp)
L0:
  cmpl   $0x1ff,-0x8(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hist(int bucket[512 * 4], int a[2048], int exp) {
  int blockID = 0;
loop2:
  for (blockID = 0; blockID < 512; blockID++) {
  loop1:
    for (int maskID = 0; maskID < 4; maskID++)
      bucket[((a[blockID * 4 + maskID] >> exp) & 0x3) * 512 + blockID + 1]++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hist>:
  endbr64
  mov    %edx,%ecx
  lea    0x10(%rsi),%r8
  mov    $0x0,%r9d
  jmp    L34
L17:
  add    $0x1,%r9d
  add    $0x10,%r8
  cmp    $0x200,%r9d
  je     L8
L34:
  lea    -0x10(%r8),%rsi
L15:
  mov    (%rsi),%eax
  sar    %cl,%eax
  and    $0x3,%eax
  shl    $0x9,%eax
  add    %r9d,%eax
  cltq
  addl   $0x1,0x4(%rdi,%rax,4)
  add    $0x4,%rsi
  cmp    %r8,%rsi
  jne    L15
  jmp    L17
L8:
  ret
```

assistant: ```c
void hist(int bucket[512 * 4], int a[2048], int exp) {
  int blockID = 0;
loop2:
  for (blockID = 0; blockID < 512; blockID++) {
  loop1:
    for (int maskID = 0; maskID < 4; maskID++)
      bucket[((a[blockID * 4 + maskID] >> exp) & 0x3) * 512 + blockID + 1]++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hist>:
  endbr64
  mov    %edx,%ecx
  lea    0x10(%rsi),%r8
  xor    %r9d,%r9d
  nopl   (%rax)
L5:
  lea    -0x10(%r8),%rsi
L3:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  sar    %cl,%eax
  and    $0x3,%eax
  shl    $0x9,%eax
  lea    0x1(%r9,%rax,1),%eax
  cltq
  addl   $0x1,(%rdi,%rax,4)
  cmp    %rsi,%r8
  jne    L3
  add    $0x1,%r9d
  add    $0x10,%r8
  cmp    $0x200,%r9d
  jne    L5
  ret
```

assistant: ```c
void hist(int bucket[512 * 4], int a[2048], int exp) {
  int blockID = 0;
loop2:
  for (blockID = 0; blockID < 512; blockID++) {
  loop1:
    for (int maskID = 0; maskID < 4; maskID++)
      bucket[((a[blockID * 4 + maskID] >> exp) & 0x3) * 512 + blockID + 1]++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hist>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  mov    %rsi,%rdi
  xor    %esi,%esi
  xchg   %ax,%ax
L5:
  mov    (%rdi),%edx
  add    $0x10,%rdi
  sar    %cl,%edx
  and    $0x3,%edx
  shl    $0x9,%edx
  lea    0x1(%rsi,%rdx,1),%edx
  movslq %edx,%rdx
  addl   $0x1,(%rax,%rdx,4)
  mov    -0xc(%rdi),%edx
  sar    %cl,%edx
  and    $0x3,%edx
  shl    $0x9,%edx
  lea    0x1(%rsi,%rdx,1),%edx
  movslq %edx,%rdx
  addl   $0x1,(%rax,%rdx,4)
  mov    -0x8(%rdi),%edx
  sar    %cl,%edx
  and    $0x3,%edx
  shl    $0x9,%edx
  lea    0x1(%rsi,%rdx,1),%edx
  movslq %edx,%rdx
  addl   $0x1,(%rax,%rdx,4)
  mov    -0x4(%rdi),%edx
  sar    %cl,%edx
  and    $0x3,%edx
  shl    $0x9,%edx
  lea    0x1(%rsi,%rdx,1),%edx
  add    $0x1,%esi
  movslq %edx,%rdx
  addl   $0x1,(%rax,%rdx,4)
  cmp    $0x200,%esi
  jne    L5
  ret
```

assistant: ```c
void hist(int bucket[512 * 4], int a[2048], int exp) {
  int blockID = 0;
loop2:
  for (blockID = 0; blockID < 512; blockID++) {
  loop1:
    for (int maskID = 0; maskID < 4; maskID++)
      bucket[((a[blockID * 4 + maskID] >> exp) & 0x3) * 512 + blockID + 1]++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cigar_int_to_op>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x8,%eax
  jbe    L16
  mov    $0x4d,%eax
  jmp    L4
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D2(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
char cigar_int_to_op(uint32_t cigar_int) {
  uint8_t letter_code = cigar_int & 0xfU;
  static const char map[] = {
      'M', 'I', 'D', 'N', 'S', 'H', 'P', '=', 'X',
  };
  if (letter_code >= (sizeof(map) / sizeof(map[0]))) {
    return 'M';
  }
  return map[letter_code];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cigar_int_to_op>:
  endbr64
  and    $0xf,%edi
  mov    $0x4d,%eax
  cmp    $0x8,%edi
  ja     L1
  movslq %edi,%rdi
  lea    D6(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L1:
  ret
```

assistant: ```c
char cigar_int_to_op(uint32_t cigar_int) {
  uint8_t letter_code = cigar_int & 0xfU;
  static const char map[] = {
      'M', 'I', 'D', 'N', 'S', 'H', 'P', '=', 'X',
  };
  if (letter_code >= (sizeof(map) / sizeof(map[0]))) {
    return 'M';
  }
  return map[letter_code];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cigar_int_to_op>:
  endbr64
  and    $0xf,%edi
  mov    $0x4d,%eax
  cmp    $0x8,%edi
  jg     L1
  movslq %edi,%rdi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L1:
  ret
```

assistant: ```c
char cigar_int_to_op(uint32_t cigar_int) {
  uint8_t letter_code = cigar_int & 0xfU;
  static const char map[] = {
      'M', 'I', 'D', 'N', 'S', 'H', 'P', '=', 'X',
  };
  if (letter_code >= (sizeof(map) / sizeof(map[0]))) {
    return 'M';
  }
  return map[letter_code];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cigar_int_to_op>:
  endbr64
  and    $0xf,%edi
  mov    $0x4d,%eax
  cmp    $0x8,%edi
  jg     L4
  movslq %edi,%rdi
  lea    D4(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L4:
  ret
```

assistant: ```c
char cigar_int_to_op(uint32_t cigar_int) {
  uint8_t letter_code = cigar_int & 0xfU;
  static const char map[] = {
      'M', 'I', 'D', 'N', 'S', 'H', 'P', '=', 'X',
  };
  if (letter_code >= (sizeof(map) / sizeof(map[0]))) {
    return 'M';
  }
  return map[letter_code];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<respond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %edx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x94(%rbp),%edx
  lea    -0x90(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x90(%rbp),%rcx
  mov    -0x98(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0xa0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x90(%rbp),%rcx
  mov    -0x98(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string

tool: D13: HTTP/1.1 200 OK
Server: nanorestfile
Content-Length: %d


tool: D17: Connection: close
Content-Type: text/%s



assistant: ```c
void respond(int len, char *mime, int socketfd) {
  char buffer[128];
  sprintf(buffer, "HTTP/1.1 200 OK\r\nServer: nanorestfile\r\nContent-Length: %d\r\n", len);
  write(socketfd, buffer, strlen(buffer));
  sprintf(buffer, "Connection: close\r\nContent-Type: text/%s\r\n\r\n", mime);
  write(socketfd, buffer, strlen(buffer));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<respond>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %edi,%edx
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    %r12,%rdx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D17: HTTP/1.1 200 OK
Server: nanorestfile
Content-Length: %d


tool: D19: Connection: close
Content-Type: text/%s



assistant: ```c
void respond(int len, char *mime, int socketfd) {
  char buffer[128];
  sprintf(buffer, "HTTP/1.1 200 OK\r\nServer: nanorestfile\r\nContent-Length: %d\r\n", len);
  write(socketfd, buffer, strlen(buffer));
  sprintf(buffer, "Connection: close\r\nContent-Type: text/%s\r\n\r\n", mime);
  write(socketfd, buffer, strlen(buffer));
}
```