ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filecopy>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x100,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L7:
  mov    $0x100,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L6
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filecopy(int fd_in, int fd_out) {
  char buffer[256] = {0};
  while ((read(fd_in, buffer, 256)) > 0) {
    write(fd_out, buffer, strlen(buffer));
    memset(buffer, 0, 256);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_addstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L13
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <addstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L3
L13:
  nop
L3:
  leave
  ret
```

assistant: ```c
void cmd_addstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addstr(args[0]));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_addstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L8
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L8:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addstr(args[0]));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmd_addstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L1
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10a0 <report_return@plt>
  nopl   0x0(%rax)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addstr(args[0]));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmd_addstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L8
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10a0 <report_return@plt>
  nopl   0x0(%rax)
L8:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addstr(args[0]));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%r12
  mov    $0x0,%ebx
  test   %r12,%r12
  je     L22
  movzbl (%r12),%eax
  test   %al,%al
  je     L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  je     L22
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
L22:
  mov    -0x18(%rbp),%rax
  mov    %rbx,(%rax)
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *strsep(char **s1, const char *s2) {
  register char *s = *s1;
  register char *p;
  p = NULL;
  if (s && *s && (p = strpbrk(s, s2))) {
    *p++ = 0;
  }
  *s1 = p;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strsep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  mov    %rbx,%rdx
  test   %rbx,%rbx
  je     L11
  mov    $0x0,%edx
  cmpb   $0x0,(%rbx)
  je     L11
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L11
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
L11:
  mov    %rdx,0x0(%rbp)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strsep(char **s1, const char *s2) {
  register char *s = *s1;
  register char *p;
  p = NULL;
  if (s && *s && (p = strpbrk(s, s2))) {
    *p++ = 0;
  }
  *s1 = p;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strsep>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  je     L4
  cmpb   $0x0,(%r12)
  je     L4
  mov    %r12,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbp
L4:
  mov    %rbp,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strsep(char **s1, const char *s2) {
  register char *s = *s1;
  register char *p;
  p = NULL;
  if (s && *s && (p = strpbrk(s, s2))) {
    *p++ = 0;
  }
  *s1 = p;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsep>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  je     L7
  cmpb   $0x0,(%r12)
  je     L7
  mov    %r12,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbp
L7:
  mov    %rbp,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strsep(char **s1, const char *s2) {
  register char *s = *s1;
  register char *p;
  p = NULL;
  if (s && *s && (p = strpbrk(s, s2))) {
    *p++ = 0;
  }
  *s1 = p;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <exercicio8@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  exercicio8();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <exercicio8@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exercicio8();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <exercicio8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exercicio8();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <exercicio8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  exercicio8();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L6:
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L32:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L32
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D38
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D2: enter the size of pattern: 

tool: D38: %d

tool: D27: * 

tool: D3: 


assistant: ```c
int main() {
  int i, j, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j <= i; j++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  lea    D8(%rip),%r12
  lea    D21(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L19
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L44
L51:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L4
L19:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L44
  jmp    L51
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D21
type_guessed: string

tool: D14: enter the size of pattern: 

tool: D33: %d

tool: D8: * 

tool: D21: 


assistant: ```c
int main() {
  int i, j, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j <= i; j++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D32(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  xor    %ebp,%ebp
  lea    D33(%rip),%r12
  lea    D29(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L20
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L18
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D33
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string

tool: D32: enter the size of pattern: 

tool: D19: %d

tool: D33: * 

tool: D29: 


assistant: ```c
int main() {
  int i, j, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j <= i; j++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D39(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L17
  xor    %ebp,%ebp
  lea    D7(%rip),%r12
  lea    D14(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L18
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L1
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D39
type_infered: string
name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string

tool: D39: enter the size of pattern: 

tool: D23: %d

tool: D7: * 

tool: D14: 


assistant: ```c
int main() {
  int i, j, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j <= i; j++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strict_sigmoid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jbe    L3
  pxor   %xmm0,%xmm0
  cvtss2sd -0x18(%rbp),%xmm0
  movsd  D30(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  divss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  jmp    L7
L3:
  movss  D40(%rip),%xmm0
  subss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  movsd  D30(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movss  D40(%rip),%xmm0
  movaps %xmm0,%xmm3
  subss  -0x14(%rbp),%xmm3
  movaps %xmm3,%xmm1
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  cvttss2si %xmm1,%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  cvtss2sd %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D30
type_infered: f64
name: unpack_data
arguments: data_tag: D40
type_infered: f32
name: unpack_data
arguments: data_tag: D0
type_infered: byte[8]

tool: D30: 0.25

tool: D40: 1

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
float strict_sigmoid(float x, float inflect) {
  if (x < inflect) {
    return (inflect / 0.25) * pow(x / (2 * inflect), 2);
  } else {
    float omi = (1 - inflect);
    return 1 - (omi / 0.25) * pow((1 - x) / (2 * omi), 2);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strict_sigmoid>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  comiss %xmm0,%xmm1
  jbe    L18
  addss  %xmm1,%xmm1
  divss  %xmm1,%xmm0
  cvttss2si %xmm0,%edi
  mov    $0x2,%esi
  call   <pow@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  mulsd  D23(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
L3:
  add    $0x18,%rsp
  ret
L18:
  movss  D9(%rip),%xmm1
  movaps %xmm1,%xmm3
  subss  0xc(%rsp),%xmm3
  subss  %xmm0,%xmm1
  movaps %xmm3,%xmm0
  movss  %xmm3,0xc(%rsp)
  addss  %xmm3,%xmm0
  divss  %xmm0,%xmm1
  cvttss2si %xmm1,%edi
  mov    $0x2,%esi
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mulsd  D23(%rip),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  jmp    L3
```

tool_calls: name: unpack_data
arguments: tag: D23
type: byte[8]
name: unpack_data
arguments: tag: D9
type: f32
name: unpack_data
arguments: tag: D13
type: byte[8]

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D9: 1

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
float strict_sigmoid(float x, float inflect) {
  if (x < inflect) {
    return (inflect / 0.25) * pow(x / (2 * inflect), 2);
  } else {
    float omi = (1 - inflect);
    return 1 - (omi / 0.25) * pow((1 - x) / (2 * omi), 2);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strict_sigmoid>:
  endbr64
  sub    $0x18,%rsp
  comiss %xmm0,%xmm1
  jbe    L9
  movaps %xmm1,%xmm2
  mov    $0x2,%esi
  movss  %xmm1,0xc(%rsp)
  addss  %xmm1,%xmm2
  divss  %xmm2,%xmm0
  cvttss2si %xmm0,%edi
  call   <pow@plt>
  movss  0xc(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D8(%rip),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nop
L9:
  movss  D35(%rip),%xmm3
  mov    $0x2,%esi
  movaps %xmm3,%xmm2
  subss  %xmm0,%xmm3
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  addss  %xmm2,%xmm0
  divss  %xmm0,%xmm3
  cvttss2si %xmm3,%edi
  call   <pow@plt>
  movss  0xc(%rsp),%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  mulsd  D8(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D25(%rip),%xmm0
  add    $0x18,%rsp
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: byte[8]
name: disassemble_data
arguments: tag: D35
datatype: f32
name: disassemble_data
arguments: tag: D25
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D35: 1

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
float strict_sigmoid(float x, float inflect) {
  if (x < inflect) {
    return (inflect / 0.25) * pow(x / (2 * inflect), 2);
  } else {
    float omi = (1 - inflect);
    return 1 - (omi / 0.25) * pow((1 - x) / (2 * omi), 2);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strict_sigmoid>:
  endbr64
  sub    $0x18,%rsp
  comiss %xmm0,%xmm1
  jbe    L4
  movaps %xmm1,%xmm2
  mov    $0x2,%esi
  movss  %xmm1,0xc(%rsp)
  addss  %xmm1,%xmm2
  divss  %xmm2,%xmm0
  cvttss2si %xmm0,%edi
  call   <pow@plt>
  movss  0xc(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D28(%rip),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nop
L4:
  movss  D0(%rip),%xmm3
  mov    $0x2,%esi
  movaps %xmm3,%xmm2
  subss  %xmm0,%xmm3
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  addss  %xmm2,%xmm0
  divss  %xmm0,%xmm3
  cvttss2si %xmm3,%edi
  call   <pow@plt>
  movss  0xc(%rsp),%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  mulsd  D28(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D4(%rip),%xmm0
  add    $0x18,%rsp
  subsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
type_infered: byte[8]
name: read_data
arguments: data_tag: D0
type_infered: f32
name: read_data
arguments: data_tag: D4
type_infered: byte[8]

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D0: 1

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
float strict_sigmoid(float x, float inflect) {
  if (x < inflect) {
    return (inflect / 0.25) * pow(x / (2 * inflect), 2);
  } else {
    float omi = (1 - inflect);
    return 1 - (omi / 0.25) * pow((1 - x) / (2 * omi), 2);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Interp3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  andl   $0xf8f8f8,-0xc(%rbp)
  andl   $0xf8f8f8,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Interp3(unsigned char *pc, int c1, int c2) {
  c1 &= 0xf8f8f8;
  c2 &= 0xf8f8f8;
  *((int *)pc) = (c1 * 7 + c2) >> 3;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Interp3>:
  endbr64
  and    $0xf8f8f8,%esi
  lea    0x0(,%rsi,8),%eax
  sub    %esi,%eax
  and    $0xf8f8f8,%edx
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp3(unsigned char *pc, int c1, int c2) {
  c1 &= 0xf8f8f8;
  c2 &= 0xf8f8f8;
  *((int *)pc) = (c1 * 7 + c2) >> 3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Interp3>:
  endbr64
  and    $0xf8f8f8,%esi
  and    $0xf8f8f8,%edx
  lea    0x0(,%rsi,8),%eax
  sub    %esi,%eax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp3(unsigned char *pc, int c1, int c2) {
  c1 &= 0xf8f8f8;
  c2 &= 0xf8f8f8;
  *((int *)pc) = (c1 * 7 + c2) >> 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Interp3>:
  endbr64
  and    $0xf8f8f8,%esi
  and    $0xf8f8f8,%edx
  lea    0x0(,%rsi,8),%eax
  sub    %esi,%eax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Interp3(unsigned char *pc, int c1, int c2) {
  c1 &= 0xf8f8f8;
  c2 &= 0xf8f8f8;
  *((int *)pc) = (c1 * 7 + c2) >> 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sig_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L15:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L6:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0xf9f,-0x4(%rbp)
  jle    L6
  addl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0x493df,-0x8(%rbp)
  jle    L15
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D12: 
sig_int starting


tool: D14: sig_int finished


assistant: ```c
void sig_int(int signo) {
  int i = 0;
  int j = 0;
  volatile int k = 0;
  printf("\nsig_int starting\n");
  for (i = 0; i < 300000; ++i) {
    for (j = 0; j < 4000; ++j) {
      k += i * j;
    }
  }
  printf("sig_int finished\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sig_int>:
  endbr64
  sub    $0x18,%rsp
  movl   $0x0,0xc(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
L2:
  mov    %edi,%esi
  mov    $0x0,%ecx
  mov    $0xfa0,%edx
L9:
  mov    0xc(%rsp),%eax
  add    %ecx,%eax
  mov    %eax,0xc(%rsp)
  add    %esi,%ecx
  sub    $0x1,%edx
  jne    L9
  add    $0x1,%edi
  cmp    $0x493e0,%edi
  jne    L2
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string

tool: D10: 
sig_int starting


tool: D15: sig_int finished


assistant: ```c
void sig_int(int signo) {
  int i = 0;
  int j = 0;
  volatile int k = 0;
  printf("\nsig_int starting\n");
  for (i = 0; i < 300000; ++i) {
    for (j = 0; j < 4000; ++j) {
      k += i * j;
    }
  }
  printf("sig_int finished\n");
}
```