ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fun@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d", fun(n));
  getchar();
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fun@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d", fun(n));
  getchar();
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pipe(int filedes[2]) {
  (void)filedes;
  errno = EMFILE;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pipe>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2]) {
  (void)filedes;
  errno = EMFILE;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pipe>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2]) {
  (void)filedes;
  errno = EMFILE;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pipe>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2]) {
  (void)filedes;
  errno = EMFILE;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L13
L27:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L19
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = (*s1 - *s2)) == 0 && *s1) {
    s1++;
    s2++;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl %dl,%eax
  movsbl (%rsi),%ecx
  sub    %ecx,%eax
  test   %dl,%dl
  je     L37
  test   %eax,%eax
  jne    L37
  mov    $0x1,%edx
L3:
  movzbl (%rdi,%rdx,1),%ecx
  movsbl %cl,%eax
  movsbl (%rsi,%rdx,1),%r8d
  sub    %r8d,%eax
  add    $0x1,%rdx
  test   %cl,%cl
  je     L37
  test   %eax,%eax
  je     L3
L37:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = (*s1 - *s2)) == 0 && *s1) {
    s1++;
    s2++;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%ecx
  mov    $0x1,%edx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L17
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L33:
  movsbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r9d
  add    $0x1,%rdx
  mov    %ecx,%r8d
  sub    %r9d,%ecx
  jne    L36
L17:
  test   %r8b,%r8b
  jne    L33
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %ecx,%eax
  ret
L26:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = (*s1 - *s2)) == 0 && *s1) {
    s1++;
    s2++;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%ecx
  mov    $0x1,%edx
  mov    %eax,%r8d
  sub    %ecx,%eax
  je     L24
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L14:
  movsbl (%rdi,%rdx,1),%ecx
  movsbl (%rsi,%rdx,1),%r9d
  add    $0x1,%rdx
  mov    %ecx,%r8d
  sub    %r9d,%ecx
  jne    L23
L24:
  test   %r8b,%r8b
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %ecx,%eax
  ret
L28:
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int r;
  while ((r = (*s1 - *s2)) == 0 && *s1) {
    s1++;
    s2++;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L28
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L28:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void preprocess(char *str) {
  char *src = str, *dest = str;
  while (*src != '\0') {
    if (isalpha(*src))
      *(dest++) = toupper(*src);
    src++;
  }
  *(++dest) = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<preprocess>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  mov    %rbx,%rbp
  jmp    L8
L1:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L33
L8:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L1
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L1
L23:
  mov    %rbx,%rbp
L33:
  movb   $0x0,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(char *str) {
  char *src = str, *dest = str;
  while (*src != '\0') {
    if (isalpha(*src))
      *(dest++) = toupper(*src);
    src++;
  }
  *(++dest) = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<preprocess>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L44
  mov    %rbp,%rbx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L21:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L44
L29:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L21
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <toupper@plt>
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L29
L44:
  movb   $0x0,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(char *str) {
  char *src = str, *dest = str;
  while (*src != '\0') {
    if (isalpha(*src))
      *(dest++) = toupper(*src);
    src++;
  }
  *(++dest) = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preprocess>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%rbp
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L26
  nopl   0x0(%rax,%rax,1)
L2:
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L13
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L2
L26:
  movb   $0x0,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %eax,%r8d
  lea    0x1(%rbp),%rax
  mov    %r8b,0x0(%rbp)
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L2
  movb   $0x0,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void preprocess(char *str) {
  char *src = str, *dest = str;
  while (*src != '\0') {
    if (isalpha(*src))
      *(dest++) = toupper(*src);
    src++;
  }
  *(++dest) = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x100,-0x4(%rbp)
L7:
  mov    $0xa,%edi
  call   <milli_delay@plt>
  jmp    L7
```

assistant: ```c
void test_b() {
  int i = 256;
  while (1) {
    milli_delay(10);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_b>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0xa,%edi
  call   <milli_delay@plt>
  jmp    L9
```

assistant: ```c
void test_b() {
  int i = 256;
  while (1) {
    milli_delay(10);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<test_b>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edi
  call   <milli_delay@plt>
  jmp    L8
```

assistant: ```c
void test_b() {
  int i = 256;
  while (1) {
    milli_delay(10);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_b>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  call   <milli_delay@plt>
  jmp    L5
```

assistant: ```c
void test_b() {
  int i = 256;
  while (1) {
    milli_delay(10);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clad_test_memeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L7
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rsi,%r8
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <clad_test_fail@plt>
  jmp    L19
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%esi
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    %rax,%rdi
  call   <clad_test_assert@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D7: Memory should be equal but pointer was null: %p %p; %s

tool: D9: Memory should be equal: %p %p; %s 

assistant: ```c
struct clad_test *clad_test_memeq(struct clad_test *test, void *m1, size_t n, void *m2, const char *explain) {
  if (!m2)
    return clad_test_fail(test, "Memory should be equal but pointer was null: %p %p; %s", m1, m2, explain);
  return clad_test_assert(test, memcmp(m1, m2, n) == 0, "Memory should be equal: %p %p; %s ", m1, m2, explain);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clad_test_memeq>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %r8,%r13
  test   %rcx,%rcx
  je     L2
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %sil
  movzbl %sil,%esi
  mov    %r13,%r9
  mov    %rbx,%r8
  mov    %rbp,%rcx
  lea    D16(%rip),%rdx
  mov    %r12,%rdi
  call   <clad_test_assert@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0x0,%ecx
  mov    %rsi,%rdx
  lea    D18(%rip),%rsi
  call   <clad_test_fail@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string

tool: D16: Memory should be equal: %p %p; %s 

tool: D18: Memory should be equal but pointer was null: %p %p; %s

assistant: ```c
struct clad_test *clad_test_memeq(struct clad_test *test, void *m1, size_t n, void *m2, const char *explain) {
  if (!m2)
    return clad_test_fail(test, "Memory should be equal but pointer was null: %p %p; %s", m1, m2, explain);
  return clad_test_assert(test, memcmp(m1, m2, n) == 0, "Memory should be equal: %p %p; %s ", m1, m2, explain);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clad_test_memeq>:
  endbr64
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L3
  mov    %rcx,%rsi
  mov    %r12,%rdi
  mov    %rcx,%rbx
  call   <memcmp@plt>
  xor    %esi,%esi
  mov    %r13,%r9
  mov    %rbx,%r8
  test   %rax,%rax
  mov    %r12,%rcx
  lea    D19(%rip),%rdx
  mov    %rbp,%rdi
  sete   %sil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <clad_test_assert@plt>
  nopl   (%rax)
L3:
  add    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  xor    %ecx,%ecx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <clad_test_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D19: Memory should be equal: %p %p; %s 

tool: D4: Memory should be equal but pointer was null: %p %p; %s

assistant: ```c
struct clad_test *clad_test_memeq(struct clad_test *test, void *m1, size_t n, void *m2, const char *explain) {
  if (!m2)
    return clad_test_fail(test, "Memory should be equal but pointer was null: %p %p; %s", m1, m2, explain);
  return clad_test_assert(test, memcmp(m1, m2, n) == 0, "Memory should be equal: %p %p; %s ", m1, m2, explain);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clad_test_memeq>:
  endbr64
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L7
  mov    %rcx,%rsi
  mov    %r12,%rdi
  mov    %rcx,%rbx
  call   <memcmp@plt>
  xor    %esi,%esi
  mov    %r13,%r9
  mov    %rbx,%r8
  test   %rax,%rax
  mov    %r12,%rcx
  lea    D18(%rip),%rdx
  mov    %rbp,%rdi
  sete   %sil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <clad_test_assert@plt>
  nopl   (%rax)
L7:
  add    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D15(%rip),%rsi
  xor    %ecx,%ecx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <clad_test_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D15
type: string

tool: D18: Memory should be equal: %p %p; %s 

tool: D15: Memory should be equal but pointer was null: %p %p; %s

assistant: ```c
struct clad_test *clad_test_memeq(struct clad_test *test, void *m1, size_t n, void *m2, const char *explain) {
  if (!m2)
    return clad_test_fail(test, "Memory should be equal but pointer was null: %p %p; %s", m1, m2, explain);
  return clad_test_assert(test, memcmp(m1, m2, n) == 0, "Memory should be equal: %p %p; %s ", m1, m2, explain);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_devname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%r8d
  mov    %eax,%ecx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmpl   $0x0,-0x1c(%rbp)
  jne    L10
  lea    D2(%rip),%rax
  jmp    L20
L10:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioc_name@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L19
L39:
  lea    D2(%rip),%rax
  jmp    L20
L19:
  mov    -0x8(%rbp),%rax
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D38
type: string

tool: D4: dev%d-%d

tool: D38: nodev

assistant: ```c
char *get_devname(unsigned int major, unsigned int minor, int pretty) {
  static char buf[32];
  char *name;
  snprintf(buf, 32, "dev%d-%d", major, minor);
  if (!pretty)
    return (buf);
  name = ioc_name(major, minor);
  if ((name == NULL) || !strcmp(name, "nodev"))
    return (buf);
  return (name);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_devname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %esi,%r8d
  mov    %edi,%ecx
  lea    D17(%rip),%rdx
  mov    $0x20,%esi
  lea    D20(%rip),%rdi
  call   <snprintf@plt>
  lea    D20(%rip),%rbx
  test   %r13d,%r13d
  jne    L10
L28:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <ioc_name@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  lea    D20(%rip),%rax
  cmove  %rax,%rbx
  jmp    L28
L33:
  lea    D20(%rip),%rbx
  jmp    L28
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string

tool: D17: dev%d-%d

tool: D29: nodev

assistant: ```c
char *get_devname(unsigned int major, unsigned int minor, int pretty) {
  static char buf[32];
  char *name;
  snprintf(buf, 32, "dev%d-%d", major, minor);
  if (!pretty)
    return (buf);
  name = ioc_name(major, minor);
  if ((name == NULL) || !strcmp(name, "nodev"))
    return (buf);
  return (name);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_devname>:
  endbr64
  push   %r12
  mov    %esi,%r8d
  mov    %esi,%r12d
  mov    %edi,%ecx
  push   %rbp
  mov    $0x20,%esi
  mov    %edi,%ebp
  lea    D32(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  lea    D23(%rip),%rdx
  call   <snprintf@plt>
  test   %ebx,%ebx
  jne    L6
L4:
  lea    D32(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L6:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <ioc_name@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  lea    D17(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L4
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: D23: dev%d-%d

tool: D17: nodev

assistant: ```c
char *get_devname(unsigned int major, unsigned int minor, int pretty) {
  static char buf[32];
  char *name;
  snprintf(buf, 32, "dev%d-%d", major, minor);
  if (!pretty)
    return (buf);
  name = ioc_name(major, minor);
  if ((name == NULL) || !strcmp(name, "nodev"))
    return (buf);
  return (name);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_devname>:
  endbr64
  push   %r12
  mov    %esi,%r8d
  mov    %esi,%r12d
  mov    %edi,%ecx
  push   %rbp
  mov    $0x20,%esi
  mov    %edi,%ebp
  lea    D34(%rip),%rdi
  push   %rbx
  mov    %edx,%ebx
  lea    D13(%rip),%rdx
  call   <snprintf@plt>
  test   %ebx,%ebx
  jne    L12
L10:
  lea    D34(%rip),%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nop
L12:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <ioc_name@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  lea    D33(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L10
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string

tool: D13: dev%d-%d

tool: D33: nodev

assistant: ```c
char *get_devname(unsigned int major, unsigned int minor, int pretty) {
  static char buf[32];
  char *name;
  snprintf(buf, 32, "dev%d-%d", major, minor);
  if (!pretty)
    return (buf);
  name = ioc_name(major, minor);
  if ((name == NULL) || !strcmp(name, "nodev"))
    return (buf);
  return (name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <Get_command@plt>
  mov    %al,-0xd(%rbp)
  jmp    L86
L18:
  movsbl -0xd(%rbp),%eax
  sub    $0x44,%eax
  cmp    $0x2c,%eax
  ja     L47
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D2(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <Get_value@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Insert@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L64
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Print@plt>
  jmp    L64
  mov    $0x0,%eax
  call   <Get_value@plt>
  mov    %eax,-0xc(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
  mov    $0x0,%eax
  call   <Get_value@plt>
  mov    %eax,-0xc(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L64
L47:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L64:
  mov    $0x0,%eax
  call   <Get_command@plt>
  mov    %al,-0xd(%rbp)
L86:
  cmpb   $0x71,-0xd(%rbp)
  je     L84
  cmpb   $0x51,-0xd(%rbp)
  jne    L18
L84:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D36
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D51
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D29
data_type: string

tool: D36: Member not implemented

tool: D12: Delete not implemented

tool: D51: Free list not implemented

tool: D21: There is no %c command


tool: D29: Please try again

assistant: ```c
int main(void) {
  char command;
  int value;
  struct list_node_s *head_p = NULL;
  command = Get_command();
  while (command != 'q' && command != 'Q') {
    switch (command) {
    case 'i':
    case 'I':
      value = Get_value();
      head_p = Insert(head_p, value);
      break;
    case 'p':
    case 'P':
      Print(head_p);
      break;
    case 'm':
    case 'M':
      value = Get_value();
      printf("Member not implemented\n");
      break;
    case 'd':
    case 'D':
      value = Get_value();
      printf("Delete not implemented\n");
      break;
    case 'f':
    case 'F':
      printf("Free list not implemented\n");
      break;
    default:
      printf("There is no %c command\n", command);
      printf("Please try again\n");
    }
    command = Get_command();
  }
  return 0;
}
```