ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_aligned>:
  endbr64
  ret
```

assistant: ```c
void test_aligned() {
  int i;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute parallel for simd aligned(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int *x, y, z[25];
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 2 * 2)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y, z : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x) aligned(z, x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z) aligned(y, z)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_aligned>:
  endbr64
  ret
```

assistant: ```c
void test_aligned() {
  int i;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute parallel for simd aligned(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int *x, y, z[25];
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 2 * 2)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y, z : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x) aligned(z, x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z) aligned(y, z)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_aligned>:
  endbr64
  ret
```

assistant: ```c
void test_aligned() {
  int i;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute parallel for simd aligned(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int *x, y, z[25];
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 2 * 2)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x : 1, y, z : 1)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x) aligned(z, x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target
#pragma omp teams
#pragma omp distribute parallel for simd aligned(x, y, z) aligned(y, z)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x3,%eax
  and    $0x10,%eax
  mov    %al,-0x9(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L11:
  cmpq   $0x3,-0x8(%rbp)
  jne    L56
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %ecx,%eax
  and    $0xffffffef,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L30
L56:
  cmpq   $0x6,-0x8(%rbp)
  jne    L52
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L30
L52:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  or     %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L30:
  addq   $0x1,-0x8(%rbp)
L2:
  cmpq   $0x6,-0x8(%rbp)
  jbe    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotation(unsigned char *target) {
  unsigned char carry_left;
  unsigned char carry_right;
  carry_left = (target[0] & 0x80) >> 3;
  for (size_t index = 0; index < 7; index++) {
    if (index == 3) {
      carry_right = (target[index] & 0x08) >> 3;
      target[index] = (((target[index] << 1) | ((target[index + 1] & 0x80) >> 7)) & ~0x10) | carry_left;
    } else if (index == 6) {
      target[index] = (target[index] << 1) | carry_right;
    } else {
      target[index] = (target[index] << 1) | ((target[index + 1] & 0x80) >> 7);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotation>:
  endbr64
  mov    %rdi,%rcx
  movzbl (%rdi),%r9d
  sar    $0x3,%r9d
  and    $0x10,%r9d
  mov    $0x1,%esi
  mov    $0x0,%eax
  jmp    L37
L25:
  movzbl 0x3(%rcx),%edi
  mov    %edi,%r8d
  sar    $0x3,%r8d
  and    $0x1,%r8d
  movzbl 0x4(%rcx),%edx
  shr    $0x7,%dl
  add    %edi,%edi
  or     %edi,%edx
  and    $0xffffffef,%edx
  or     %r9d,%edx
  mov    %dl,0x3(%rcx)
  jmp    L12
L33:
  movzbl (%rcx,%rsi,1),%edx
  shr    $0x7,%dl
  movzbl (%rcx,%rax,1),%edi
  add    %edi,%edi
  or     %edi,%edx
  mov    %dl,(%rcx,%rax,1)
  cmp    $0x6,%rsi
  ja     L42
L12:
  add    $0x1,%rax
  add    $0x1,%rsi
L37:
  cmp    $0x3,%rax
  je     L25
  cmp    $0x6,%rax
  jne    L33
  movzbl 0x6(%rcx),%eax
  add    %eax,%eax
  or     %eax,%r8d
  mov    %r8b,0x6(%rcx)
  ret
L42:
  ret
```

assistant: ```c
void rotation(unsigned char *target) {
  unsigned char carry_left;
  unsigned char carry_right;
  carry_left = (target[0] & 0x80) >> 3;
  for (size_t index = 0; index < 7; index++) {
    if (index == 3) {
      carry_right = (target[index] & 0x08) >> 3;
      target[index] = (((target[index] << 1) | ((target[index + 1] & 0x80) >> 7)) & ~0x10) | carry_left;
    } else if (index == 6) {
      target[index] = (target[index] << 1) | carry_right;
    } else {
      target[index] = (target[index] << 1) | ((target[index + 1] & 0x80) >> 7);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotation>:
  endbr64
  movzbl (%rdi),%r9d
  mov    %rdi,%rcx
  xor    %eax,%eax
  mov    $0x1,%edi
  sar    $0x3,%r9d
  and    $0x10,%r9d
  jmp    L12
  nopl   0x0(%rax)
L13:
  cmp    $0x6,%rax
  je     L4
  movzbl (%rcx,%rdi,1),%edx
  movzbl (%rcx,%rax,1),%esi
  shr    $0x7,%dl
  add    %esi,%esi
  or     %esi,%edx
  mov    %dl,(%rcx,%rax,1)
L9:
  add    $0x1,%rax
  add    $0x1,%rdi
L12:
  cmp    $0x3,%rax
  jne    L13
  movzbl 0x3(%rcx),%esi
  movzbl 0x4(%rcx),%edx
  mov    %esi,%r8d
  shr    $0x7,%dl
  add    %esi,%esi
  or     %esi,%edx
  sar    $0x3,%r8d
  and    $0xffffffef,%edx
  and    $0x1,%r8d
  or     %r9d,%edx
  mov    %dl,0x3(%rcx)
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl 0x6(%rcx),%eax
  add    %eax,%eax
  or     %eax,%r8d
  mov    %r8b,0x6(%rcx)
  ret
```

assistant: ```c
void rotation(unsigned char *target) {
  unsigned char carry_left;
  unsigned char carry_right;
  carry_left = (target[0] & 0x80) >> 3;
  for (size_t index = 0; index < 7; index++) {
    if (index == 3) {
      carry_right = (target[index] & 0x08) >> 3;
      target[index] = (((target[index] << 1) | ((target[index + 1] & 0x80) >> 7)) & ~0x10) | carry_left;
    } else if (index == 6) {
      target[index] = (target[index] << 1) | carry_right;
    } else {
      target[index] = (target[index] << 1) | ((target[index + 1] & 0x80) >> 7);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotation>:
  endbr64
  movzbl 0x1(%rdi),%edx
  movzbl (%rdi),%esi
  mov    %rdi,%rax
  mov    %edx,%ecx
  lea    (%rsi,%rsi,1),%edi
  add    %edx,%edx
  sar    $0x3,%esi
  shr    $0x7,%cl
  and    $0x10,%esi
  or     %edi,%ecx
  mov    %cl,(%rax)
  movzbl 0x2(%rax),%ecx
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edi,%edx
  mov    %dl,0x1(%rax)
  movzbl 0x3(%rax),%edx
  mov    %edx,%edi
  lea    (%rdx,%rdx,1),%r8d
  sar    $0x3,%edx
  shr    $0x7,%dil
  and    $0x1,%edx
  or     %edi,%ecx
  movzbl 0x4(%rax),%edi
  mov    %cl,0x2(%rax)
  mov    %edi,%ecx
  add    %edi,%edi
  shr    $0x7,%cl
  or     %r8d,%ecx
  and    $0xffffffef,%ecx
  or     %esi,%ecx
  movzbl 0x5(%rax),%esi
  mov    %cl,0x3(%rax)
  mov    %esi,%ecx
  add    %esi,%esi
  shr    $0x7,%cl
  or     %ecx,%edi
  movzbl 0x6(%rax),%ecx
  mov    %dil,0x4(%rax)
  mov    %ecx,%edi
  add    %ecx,%ecx
  shr    $0x7,%dil
  or     %edx,%ecx
  or     %edi,%esi
  mov    %cl,0x6(%rax)
  mov    %sil,0x5(%rax)
  ret
```

assistant: ```c
void rotation(unsigned char *target) {
  unsigned char carry_left;
  unsigned char carry_right;
  carry_left = (target[0] & 0x80) >> 3;
  for (size_t index = 0; index < 7; index++) {
    if (index == 3) {
      carry_right = (target[index] & 0x08) >> 3;
      target[index] = (((target[index] << 1) | ((target[index + 1] & 0x80) >> 7)) & ~0x10) | carry_left;
    } else if (index == 6) {
      target[index] = (target[index] << 1) | carry_right;
    } else {
      target[index] = (target[index] << 1) | ((target[index + 1] & 0x80) >> 7);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: %s


assistant: ```c
int foo(int n, const char *str) {
  char *data = alloca(n);
  memcpy(data, str, n);
  return printf("%s\n", data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: %s


assistant: ```c
int foo(int n, const char *str) {
  char *data = alloca(n);
  memcpy(data, str, n);
  return printf("%s\n", data);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: %s


assistant: ```c
int foo(int n, const char *str) {
  char *data = alloca(n);
  memcpy(data, str, n);
  return printf("%s\n", data);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %s


assistant: ```c
int foo(int n, const char *str) {
  char *data = alloca(n);
  memcpy(data, str, n);
  return printf("%s\n", data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_cmd_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L58
L45:
  movzbl -0xd(%rbp),%eax
  cmp    $0xa,%al
  je     L52
  movzbl -0xd(%rbp),%eax
  cmp    $0xd,%al
  je     L52
  movzbl -0xd(%rbp),%eax
  test   %al,%al
  je     L52
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L36
L58:
  lea    -0xd(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L45
  jmp    L52
L36:
  nop
L52:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int read_cmd_line(int fd, char *buf, unsigned int buf_len) {
  unsigned int count = 0;
  char ch;
  while (read(fd, &ch, 1) > 0) {
    if ((ch != '\n') && (ch != '\r') && (ch != '\0')) {
      buf[count] = ch;
      count++;
    } else {
      break;
    }
    if (count == (buf_len - 1)) {
      break;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_cmd_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    0x7(%rsp),%r14
  jmp    L21
L33:
  mov    %ebx,%edx
  mov    %al,0x0(%r13,%rdx,1)
  add    $0x1,%ebx
  lea    -0x1(%r12),%eax
  cmp    %ebx,%eax
  je     L1
L21:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jle    L1
  movzbl 0x7(%rsp),%eax
  cmp    $0xd,%al
  ja     L33
  mov    $0x2401,%edx
  bt     %rax,%rdx
  jae    L33
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_cmd_line(int fd, char *buf, unsigned int buf_len) {
  unsigned int count = 0;
  char ch;
  while (read(fd, &ch, 1) > 0) {
    if ((ch != '\n') && (ch != '\r') && (ch != '\0')) {
      buf[count] = ch;
      count++;
    } else {
      break;
    }
    if (count == (buf_len - 1)) {
      break;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_cmd_line>:
  endbr64
  push   %r15
  mov    $0xffffffffffffdbfe,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r14
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12d,%edx
  add    $0x1,%r12d
  mov    %al,0x0(%r13,%rdx,1)
  lea    -0x1(%rbp),%eax
  cmp    %r12d,%eax
  je     L36
L27:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %rax,%rax
  jle    L36
  movzbl 0x7(%rsp),%eax
  cmp    $0xd,%al
  ja     L2
  bt     %rax,%r15
  jb     L2
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_cmd_line(int fd, char *buf, unsigned int buf_len) {
  unsigned int count = 0;
  char ch;
  while (read(fd, &ch, 1) > 0) {
    if ((ch != '\n') && (ch != '\r') && (ch != '\0')) {
      buf[count] = ch;
      count++;
    } else {
      break;
    }
    if (count == (buf_len - 1)) {
      break;
    }
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_cmd_line>:
  endbr64
  push   %r15
  mov    $0xffffffffffffdbfe,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r14
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r12d,%edx
  add    $0x1,%r12d
  mov    %al,0x0(%r13,%rdx,1)
  lea    -0x1(%rbp),%eax
  cmp    %r12d,%eax
  je     L20
L29:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %rax,%rax
  jle    L20
  movzbl 0x7(%rsp),%eax
  cmp    $0xd,%al
  ja     L10
  bt     %rax,%r15
  jb     L10
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_cmd_line(int fd, char *buf, unsigned int buf_len) {
  unsigned int count = 0;
  char ch;
  while (read(fd, &ch, 1) > 0) {
    if ((ch != '\n') && (ch != '\r') && (ch != '\0')) {
      buf[count] = ch;
      count++;
    } else {
      break;
    }
    if (count == (buf_len - 1)) {
      break;
    }
  }
  return count;
}
```