user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1d0(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1cc(%rbp)
  jmp    L3
L39:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1cc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1cc(%rbp)
L3:
  mov    -0x1d0(%rbp),%eax
  cmp    %eax,-0x1cc(%rbp)
  jl     L39
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x1c8(%rbp)
  jmp    L95
L135:
  mov    -0x1c8(%rbp),%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x1c8(%rbp)
L95:
  mov    -0x1d0(%rbp),%eax
  cltq
  cmp    %rax,-0x1c8(%rbp)
  jb     L135
  movq   $0x0,-0x1c0(%rbp)
  jmp    L60
L30:
  mov    -0x1c0(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x1b8(%rbp)
  jmp    L17
L31:
  mov    -0x1c0(%rbp),%rax
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b8(%rbp),%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L74
  mov    -0x1c0(%rbp),%rax
  mov    %rax,-0x1b0(%rbp)
  jmp    L57
L29:
  mov    -0x1b0(%rbp),%rax
  add    $0x1,%rax
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b0(%rbp),%rax
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addq   $0x1,-0x1b0(%rbp)
L57:
  mov    -0x1d0(%rbp),%eax
  cltq
  cmp    %rax,-0x1b0(%rbp)
  jb     L29
  mov    -0x1d0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1d0(%rbp)
  subq   $0x1,-0x1b8(%rbp)
L74:
  addq   $0x1,-0x1b8(%rbp)
L17:
  mov    -0x1d0(%rbp),%eax
  cltq
  cmp    %rax,-0x1b8(%rbp)
  jb     L31
  addq   $0x1,-0x1c0(%rbp)
L60:
  mov    -0x1d0(%rbp),%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,-0x1c0(%rbp)
  jb     L30
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x1a8(%rbp)
  jmp    L10
L118:
  mov    -0x1a8(%rbp),%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x1a8(%rbp)
L10:
  mov    -0x1d0(%rbp),%eax
  cltq
  cmp    %rax,-0x1a8(%rbp)
  jb     L118
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D40
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D48
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D44
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string

tool: D40: Enter a number of array: 

tool: D48: %d

tool: D17: Before: 

tool: D44: %d 

tool: D27: After: 

assistant: ```c
int main(void) {
  int arr[100], number, i;
  printf("Enter a number of array: ");
  scanf("%d", &number);
  for (i = 0; i < number; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Before: ");
  for (size_t i = 0; i < number; i++) {
    printf("%d ", arr[i]);
  }
  for (size_t i = 0; i < number - 1; i++) {
    for (size_t j = i + 1; j < number; j++) {
      if (arr[i] == arr[j]) {
        for (size_t k = i; k < number; k++) {
          arr[k] = arr[k + 1];
        }
        number--;
        j--;
      }
    }
  }
  printf("After: ");
  for (size_t i = 0; i < number; i++) {
    printf("%d ", arr[i]);
  }
  return 0;
}
```