ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    $0xf,%ecx
  mov    $0x1,%edx
  mov    $0xa,%edi
  mov    $0x0,%ebx
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xf,%ecx
  mov    $0x1,%edx
  mov    $0x10,%edi
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xf,%ecx
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    $0xa,%edi
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    $0xa,%edi
  call   <posAfterNoMax@plt>
  xor    %edi,%edi
  cmp    $0xfffffff6,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0xfffffffa,%esi
  mov    $0x4,%edi
  call   <elCollV1@plt>
  xor    %edi,%edi
  ucomisd D8(%rip),%xmm0
  setnp  %dil
  cmovne %ebx,%edi
  call   <assert@plt>
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0xfffffffa,%esi
  mov    $0x4,%edi
  call   <elCollV2@plt>
  xor    %edi,%edi
  ucomisd D1(%rip),%xmm0
  setnp  %dil
  cmovne %ebx,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: byte[8]
name: retrieve_data
arguments: data_tag: D1
type: f64

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x21,0xc0]}

tool: D1: 1.5

assistant: ```c
int main() {
  assert(posAfter(10, 0, 1, 15) == 10);
  assert(posAfter(16, 0, 1, 15) == 1);
  assert(posAfter(10, 0, -1, 15) == 5);
  assert(posAfterNoMax(10, 0, -1) == -10);
  assert(elCollV1(4, -6, 3, 5) == -8.5);
  assert(elCollV2(4, -6, 3, 5) == 1.5);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    $0xf,%ecx
  mov    $0x1,%edx
  mov    $0xa,%edi
  mov    $0x0,%ebx
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xf,%ecx
  mov    $0x1,%edx
  mov    $0x10,%edi
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xf,%ecx
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    $0xa,%edi
  call   <posAfter@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    $0xa,%edi
  call   <posAfterNoMax@plt>
  xor    %edi,%edi
  cmp    $0xfffffff6,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0xfffffffa,%esi
  mov    $0x4,%edi
  call   <elCollV1@plt>
  xor    %edi,%edi
  ucomisd D8(%rip),%xmm0
  setnp  %dil
  cmovne %ebx,%edi
  call   <assert@plt>
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0xfffffffa,%esi
  mov    $0x4,%edi
  call   <elCollV2@plt>
  xor    %edi,%edi
  ucomisd D14(%rip),%xmm0
  setnp  %dil
  cmovne %ebx,%edi
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D14
type_guessed: f64

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x21,0xc0]}

tool: D14: 1.5

assistant: ```c
int main() {
  assert(posAfter(10, 0, 1, 15) == 10);
  assert(posAfter(16, 0, 1, 15) == 1);
  assert(posAfter(10, 0, -1, 15) == 5);
  assert(posAfterNoMax(10, 0, -1) == -10);
  assert(elCollV1(4, -6, 3, 5) == -8.5);
  assert(elCollV2(4, -6, 3, 5) == 1.5);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<driveDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %edi,%edx
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movswl -0x18(%rbp),%edx
  movswl -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <waitDistance@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L15
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  jne    L18
L15:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L20
L18:
  mov    -0x4(%rbp),%eax
L20:
  leave
  ret
```

assistant: ```c
int driveDistance(short vel, short rad, int dist, int interrupt) {
  int ret = 0;
  if (drive(vel, rad) == -1 || (ret = waitDistance(dist, interrupt)) == INT_MIN || drive(0, 0) == -1)
    return INT_MIN;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<driveDistance>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    %ecx,%ebp
  movswl %si,%esi
  movswl %di,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <waitDistance@plt>
  mov    %eax,%ebx
  mov    D2(%rip),%rax
  cmp    %ebx,(%rax)
  je     L9
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  jne    L12
L9:
  mov    D2(%rip),%rax
  mov    (%rax),%ebx
L12:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int driveDistance(short vel, short rad, int dist, int interrupt) {
  int ret = 0;
  if (drive(vel, rad) == -1 || (ret = waitDistance(dist, interrupt)) == INT_MIN || drive(0, 0) == -1)
    return INT_MIN;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<driveDistance>:
  endbr64
  push   %r12
  movswl %si,%esi
  movswl %di,%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  sub    $0x8,%rsp
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L21
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <waitDistance@plt>
  mov    D14(%rip),%rbp
  mov    %eax,%r12d
  cmp    %eax,0x0(%rbp)
  je     L17
  xor    %esi,%esi
  xor    %edi,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L3
L17:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    D14(%rip),%rax
  mov    (%rax),%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L3:
  mov    0x0(%rbp),%r12d
  jmp    L17
```

assistant: ```c
int driveDistance(short vel, short rad, int dist, int interrupt) {
  int ret = 0;
  if (drive(vel, rad) == -1 || (ret = waitDistance(dist, interrupt)) == INT_MIN || drive(0, 0) == -1)
    return INT_MIN;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<driveDistance>:
  endbr64
  push   %r12
  movswl %si,%esi
  movswl %di,%edi
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  sub    $0x8,%rsp
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <waitDistance@plt>
  mov    D6(%rip),%rbp
  mov    %eax,%r12d
  cmp    %eax,0x0(%rbp)
  je     L38
  xor    %esi,%esi
  xor    %edi,%edi
  call   <drive@plt>
  cmp    $0xffffffff,%eax
  je     L15
L38:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    D6(%rip),%rax
  mov    (%rax),%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L15:
  mov    0x0(%rbp),%r12d
  jmp    L38
```

assistant: ```c
int driveDistance(short vel, short rad, int dist, int interrupt) {
  int ret = 0;
  if (drive(vel, rad) == -1 || (ret = waitDistance(dist, interrupt)) == INT_MIN || drive(0, 0) == -1)
    return INT_MIN;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *a, *b, *c, *d;
  a = (int *)malloc(sizeof(int));
  b = a;
  c = b;
  d = c;
  a = NULL;
  b = NULL;
  c = NULL;
  d = NULL;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *a, *b, *c, *d;
  a = (int *)malloc(sizeof(int));
  b = a;
  c = b;
  d = c;
  a = NULL;
  b = NULL;
  c = NULL;
  d = NULL;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *a, *b, *c, *d;
  a = (int *)malloc(sizeof(int));
  b = a;
  c = b;
  d = c;
  a = NULL;
  b = NULL;
  c = NULL;
  d = NULL;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int *a, *b, *c, *d;
  a = (int *)malloc(sizeof(int));
  b = a;
  c = b;
  d = c;
  a = NULL;
  b = NULL;
  c = NULL;
  d = NULL;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<syscon_create_evaluator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x93,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_create_evaluator(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(147, a, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<syscon_create_evaluator>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x93,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int syscon_create_evaluator(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(147, a, b, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<syscon_create_evaluator>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x93,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int syscon_create_evaluator(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(147, a, b, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<syscon_create_evaluator>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x93,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int syscon_create_evaluator(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(147, a, b, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<SHAMD5IntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0xe,%eax
  and    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  and    $0x2,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    $0x3fe4,%eax
  mov    %eax,%eax
  mov    %rax,%rcx
  movslq %edx,%rax
  mov    %rax,(%rcx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5IntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0xFFFFC01C))) = (((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SHAMD5IntClear>:
  endbr64
  mov    %esi,%eax
  sar    $0xe,%eax
  and    $0x4,%eax
  sar    $0x10,%esi
  and    $0x2,%esi
  or     %esi,%eax
  cltq
  mov    %rax,-0x3fe4(%edi)
  ret
```

assistant: ```c
void SHAMD5IntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0xFFFFC01C))) = (((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SHAMD5IntClear>:
  endbr64
  mov    %esi,%eax
  sar    $0x10,%esi
  sar    $0xe,%eax
  and    $0x2,%esi
  and    $0x4,%eax
  or     %esi,%eax
  cltq
  mov    %rax,-0x3fe4(%edi)
  ret
```

assistant: ```c
void SHAMD5IntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0xFFFFC01C))) = (((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SHAMD5IntClear>:
  endbr64
  mov    %esi,%eax
  sar    $0x10,%esi
  sar    $0xe,%eax
  and    $0x2,%esi
  and    $0x4,%eax
  or     %esi,%eax
  cltq
  mov    %rax,-0x3fe4(%edi)
  ret
```

assistant: ```c
void SHAMD5IntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ui32Base + 0xFFFFC01C))) = (((ui32IntFlags & 0x00010000) >> 14) | ((ui32IntFlags & 0x00020000) >> 16) | ((ui32IntFlags & 0x00040000) >> 19));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chop_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L24
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L39
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L39:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L19:
  nop
  leave
  ret
```

assistant: ```c
void chop_extension(char *string) {
  assert(string != NULL);
  char *last_point = NULL;
  while (*string != 0) {
    if (*string == '.') {
      last_point = string;
    }
    string += 1;
  }
  if (last_point != NULL) {
    *last_point = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chop_extension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L21
  mov    $0x0,%edx
L19:
  cmp    $0x2e,%al
  cmove  %rbx,%rdx
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L19
  test   %rdx,%rdx
  je     L21
  movb   $0x0,(%rdx)
L21:
  pop    %rbx
  ret
```

assistant: ```c
void chop_extension(char *string) {
  assert(string != NULL);
  char *last_point = NULL;
  while (*string != 0) {
    if (*string == '.') {
      last_point = string;
    }
    string += 1;
  }
  if (last_point != NULL) {
    *last_point = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<chop_extension>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L16
  xor    %edx,%edx
  nopl   0x0(%rax)
L18:
  cmp    $0x2e,%al
  cmove  %rbx,%rdx
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L18
  test   %rdx,%rdx
  je     L16
  movb   $0x0,(%rdx)
L16:
  pop    %rbx
  ret
```

assistant: ```c
void chop_extension(char *string) {
  assert(string != NULL);
  char *last_point = NULL;
  while (*string != 0) {
    if (*string == '.') {
      last_point = string;
    }
    string += 1;
  }
  if (last_point != NULL) {
    *last_point = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chop_extension>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L6
  xor    %edx,%edx
  nopl   0x0(%rax)
L23:
  cmp    $0x2e,%al
  cmove  %rbx,%rdx
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L23
  test   %rdx,%rdx
  je     L6
  movb   $0x0,(%rdx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void chop_extension(char *string) {
  assert(string != NULL);
  char *last_point = NULL;
  while (*string != 0) {
    if (*string == '.') {
      last_point = string;
    }
    string += 1;
  }
  if (last_point != NULL) {
    *last_point = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<oddSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L24:
  subl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L55
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L24
  jmp    L55
L0:
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L40
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L0
L40:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void oddSort(int *arr, int size) {
  int even = size - 1, odd = 0;
  while (odd < even) {
    while (arr[even] % 2 && even > odd)
      even--;
    while (!(arr[odd] % 2) && odd < even)
      odd++;
    int temp = arr[even];
    arr[even] = arr[odd];
    arr[odd] = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<oddSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  jg     L53
  ret
L92:
  mov    %r8d,(%r9)
  mov    %esi,(%r10)
  cmp    %edx,%eax
  jle    L5
L53:
  movslq %eax,%rcx
  lea    (%rdi,%rcx,4),%r9
  mov    (%r9),%esi
  test   $0x1,%sil
  je     L88
  lea    -0x4(%rdi,%rcx,4),%rcx
  cmp    %edx,%eax
  jle    L88
L40:
  sub    $0x1,%eax
  mov    %rcx,%r9
  mov    (%rcx),%esi
  sub    $0x4,%rcx
  test   $0x1,%sil
  je     L88
  cmp    %edx,%eax
  jg     L40
L88:
  movslq %edx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%r10
  mov    (%r10),%r8d
  test   $0x1,%r8b
  jne    L92
  cmp    %edx,%eax
  jle    L92
  lea    0x4(%rdi,%rcx,1),%rcx
L100:
  add    $0x1,%edx
  mov    %rcx,%r10
  mov    (%rcx),%r8d
  add    $0x4,%rcx
  test   $0x1,%r8b
  jne    L92
  cmp    %eax,%edx
  jl     L100
  jmp    L92
L5:
  ret
```

assistant: ```c
void oddSort(int *arr, int size) {
  int even = size - 1, odd = 0;
  while (odd < even) {
    while (arr[even] % 2 && even > odd)
      even--;
    while (!(arr[odd] % 2) && odd < even)
      odd++;
    int temp = arr[even];
    arr[even] = arr[odd];
    arr[odd] = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<oddSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  test   %eax,%eax
  jle    L2
  nopl   0x0(%rax)
L37:
  movslq %eax,%rcx
  cmp    %edx,%eax
  lea    (%rdi,%rcx,4),%r10
  setg   %r9b
  mov    (%r10),%esi
  test   $0x1,%sil
  je     L64
  lea    -0x4(%rdi,%rcx,4),%rcx
  jmp    L69
  nopl   (%rax)
L68:
  mov    (%rcx),%esi
  sub    $0x1,%eax
  mov    %rcx,%r10
  cmp    %edx,%eax
  setg   %r9b
  sub    $0x4,%rcx
  test   $0x1,%sil
  je     L64
L69:
  test   %r9b,%r9b
  jne    L68
L64:
  movslq %edx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%r11
  mov    (%r11),%r8d
  test   $0x1,%r8b
  jne    L48
  test   %r9b,%r9b
  je     L48
  lea    0x4(%rdi,%rcx,1),%rcx
  jmp    L80
  nopl   (%rax)
L9:
  test   $0x1,%r8b
  jne    L48
L80:
  add    $0x1,%edx
  mov    (%rcx),%r8d
  mov    %rcx,%r11
  add    $0x4,%rcx
  cmp    %eax,%edx
  jl     L9
L48:
  mov    %r8d,(%r10)
  mov    %esi,(%r11)
  cmp    %edx,%eax
  jg     L37
  ret
L2:
  ret
```

assistant: ```c
void oddSort(int *arr, int size) {
  int even = size - 1, odd = 0;
  while (odd < even) {
    while (arr[even] % 2 && even > odd)
      even--;
    while (!(arr[odd] % 2) && odd < even)
      odd++;
    int temp = arr[even];
    arr[even] = arr[odd];
    arr[odd] = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<oddSort>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %edx,%edx
  test   %eax,%eax
  jle    L91
  nopl   0x0(%rax)
L98:
  movslq %eax,%rcx
  cmp    %edx,%eax
  lea    (%rdi,%rcx,4),%r10
  setg   %r9b
  mov    (%r10),%esi
  test   $0x1,%sil
  je     L44
  lea    -0x4(%rdi,%rcx,4),%rcx
  jmp    L56
  nopl   (%rax)
L57:
  mov    (%rcx),%esi
  sub    $0x1,%eax
  mov    %rcx,%r10
  cmp    %edx,%eax
  setg   %r9b
  sub    $0x4,%rcx
  test   $0x1,%sil
  je     L44
L56:
  test   %r9b,%r9b
  jne    L57
L44:
  movslq %edx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%r11
  mov    (%r11),%r8d
  test   $0x1,%r8b
  jne    L69
  test   %r9b,%r9b
  je     L69
  lea    0x4(%rdi,%rcx,1),%rcx
  jmp    L47
  nopl   (%rax)
L54:
  test   $0x1,%r8b
  jne    L69
L47:
  add    $0x1,%edx
  mov    (%rcx),%r8d
  mov    %rcx,%r11
  add    $0x4,%rcx
  cmp    %eax,%edx
  jl     L54
L69:
  mov    %r8d,(%r10)
  mov    %esi,(%r11)
  cmp    %edx,%eax
  jg     L98
  ret
L91:
  ret
```

assistant: ```c
void oddSort(int *arr, int size) {
  int even = size - 1, odd = 0;
  while (odd < even) {
    while (arr[even] % 2 && even > odd)
      even--;
    while (!(arr[odd] % 2) && odd < even)
      odd++;
    int temp = arr[even];
    arr[even] = arr[odd];
    arr[odd] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x78(%rbp)
  movl   $0x0,-0x80(%rbp)
  jmp    L101
L108:
  mov    -0x80(%rbp),%eax
  cltq
  movl   $0x0,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x80(%rbp)
L101:
  cmpl   $0x18,-0x80(%rbp)
  jle    L108
  jmp    L13
L74:
  cmpl   $0x60,-0x74(%rbp)
  jle    L13
  cmpl   $0x7a,-0x74(%rbp)
  jg     L13
  mov    -0x74(%rbp),%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x74(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jne    L74
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L65
L96:
  mov    -0x80(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L83
  mov    $0xa,%edi
  call   <putchar@plt>
L83:
  movl   $0x0,-0x7c(%rbp)
  jmp    L69
L48:
  mov    -0x80(%rbp),%eax
  add    $0x61,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x7c(%rbp)
L69:
  mov    -0x80(%rbp),%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  cmp    %eax,-0x7c(%rbp)
  jl     L48
  addl   $0x1,-0x80(%rbp)
L65:
  cmpl   $0x18,-0x80(%rbp)
  jle    L96
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: Symbols gistogram

assistant: ```c
main() {
  int symbols['z' - 'a'];
  int c, i, j;
  int end = getchar();
  for (i = 0; i < 'z' - 'a'; ++i) {
    symbols[i] = 0;
  }
  while ((c = getchar()) != end)
    if (c >= 'a' && c <= 'z')
      ++symbols[c - 'a'];
  printf("Symbols gistogram\n");
  for (i = 0; i < 'z' - 'a'; ++i) {
    if (symbols[i] != 0) {
      printf("\n");
    }
    for (j = 0; j < symbols[i]; ++j) {
      printf("%c", i + 'a');
    }
  }
}
```