user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    D71(%rip),%r14
  lea    D80(%rip),%r13
  lea    D74(%rip),%r12
  jmp    L5
L88:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %rax,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edi
L9:
  add    $0x1,%rbx
  mov    %rbx,%rcx
  imul   %rbx,%rcx
  mov    (%rsp),%rsi
  cmp    %rcx,%rsi
  jb     L25
L99:
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rbx
  test   %rdx,%rdx
  jne    L9
  cmp    %rsi,%rcx
  jne    L88
  mov    %edi,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  jmp    L9
L25:
  test   %edi,%edi
  jne    L44
L29:
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
L5:
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %eax,%edi
  cmp    $0x1,%eax
  jne    L42
  mov    (%rsp),%rsi
  mov    $0x2,%ebx
  mov    $0x4,%ecx
  mov    $0x0,%ebp
  cmp    $0x3,%rsi
  ja     L99
L44:
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L29
L42:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D71
data_type: string
name: extract_symbolic_data
arguments: tag: D80
data_type: string
name: extract_symbolic_data
arguments: tag: D74
data_type: string
name: extract_symbolic_data
arguments: tag: D52
data_type: string
name: extract_symbolic_data
arguments: tag: D43
data_type: string
name: extract_symbolic_data
arguments: tag: D39
data_type: string

tool: D31: Please enter an integer for analysis: 

tool: D26: Enter q to quit.

tool: D71: %lu

tool: D80: %lu is divisible by %lu.


tool: D74: %lu is divisible by %lu and %lu.


tool: D52: Please enter another integer for analysis: 

tool: D43: %lu is prime.


tool: D39: Bye.

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long num;
  unsigned long div;
  bool isPrime;
  printf("Please enter an integer for analysis: ");
  printf("Enter q to quit.\n");
  while (scanf("%lu", &num) == 1) {
    for (div = 2, isPrime = true; (div * div) <= num; div++) {
      if (num % div == 0) {
        if ((div * div) != num) {
          printf("%lu is divisible by %lu and %lu.\n", num, div, num / div);
        } else {
          printf("%lu is divisible by %lu.\n", num, div, isPrime);
        }
        isPrime = false;
      }
    }
    if (isPrime) {
      printf("%lu is prime.\n", num);
    }
    printf("Please enter another integer for analysis: ");
    printf("Enter q to quit.\n");
  }
  printf("Bye.\n");
  return 0;
}
```