ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x27,-0x6d(%rbp)
  mov    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x64(%rbp)
  cmpl   $0x7,-0x64(%rbp)
  jne    L60
  mov    -0x80(%rbp),%rax
  mov    $0x7,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L62
  mov    -0x80(%rbp),%rax
  mov    $0x7,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L60
L62:
  mov    -0x88(%rbp),%rdx
  mov    -0x80(%rbp),%rcx
  mov    -0x78(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hputc@plt>
  jmp    L3
L60:
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x6c(%rbp)
  cmpl   $0x43,-0x6c(%rbp)
  jle    L23
  movl   $0x43,-0x6c(%rbp)
L23:
  movzbl -0x6d(%rbp),%eax
  mov    %al,-0x60(%rbp)
  mov    -0x6c(%rbp),%edx
  mov    -0x88(%rbp),%rax
  lea    -0x60(%rbp),%rcx
  add    $0x1,%rcx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  cmpl   $0x7,-0x6c(%rbp)
  jg     L33
  mov    -0x6c(%rbp),%eax
  mov    %eax,-0x68(%rbp)
  jmp    L25
L87:
  mov    -0x68(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x20,-0x60(%rbp,%rax,1)
  addl   $0x1,-0x68(%rbp)
L25:
  cmpl   $0x7,-0x68(%rbp)
  jle    L87
  movl   $0x8,-0x6c(%rbp)
L33:
  mov    -0x6c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x6d(%rbp),%edx
  mov    %dl,-0x60(%rbp,%rax,1)
  mov    -0x6c(%rbp),%eax
  add    $0x2,%eax
  cltq
  movb   $0x0,-0x60(%rbp,%rax,1)
  lea    -0x60(%rbp),%rdx
  mov    -0x80(%rbp),%rcx
  mov    -0x78(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hputc@plt>
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D0: COMMENT

tool: D1: HISTORY

assistant: ```c
int hputs(char *hstring, const char *keyword, const char *cval) {
  char squot = 39;
  char value[80];
  int lcval, i, lkeyword;
  lkeyword = (int)strlen(keyword);
  if (lkeyword == 7 && (strncmp(keyword, "COMMENT", 7) == 0 || strncmp(keyword, "HISTORY", 7) == 0)) {
    return (hputc(hstring, keyword, cval));
  }
  lcval = (int)strlen(cval);
  if (lcval > 67) {
    lcval = 67;
  }
  value[0] = squot;
  strncpy(&value[1], cval, lcval);
  if (lcval < 8) {
    for (i = lcval; i < 8; i++) {
      value[i + 1] = ' ';
    }
    lcval = 8;
  }
  value[lcval + 1] = squot;
  value[lcval + 2] = (char)0;
  return (hputc(hstring, keyword, value));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hputs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    $0x7,%eax
  je     L19
L35:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    $0x43,%eax
  cmp    %eax,%r13d
  cmovle %r13d,%eax
  mov    %eax,%ebx
  movb   $0x27,(%rsp)
  lea    0x1(%rsp),%rdi
  mov    %eax,%edx
  mov    %r14,%rsi
  call   <strncpy@plt>
  cmp    $0x7,%r13d
  jg     L37
  movslq %ebx,%rax
  lea    0x1(%rsp),%rdx
L56:
  movb   $0x20,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x7,%eax
  jle    L56
  mov    $0x8,%ebx
L37:
  lea    0x1(%rbx),%eax
  cltq
  movb   $0x27,(%rsp,%rax,1)
  lea    0x2(%rbx),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    %rsp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <hputc@plt>
L14:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  mov    $0x7,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L36
  mov    $0x7,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L35
L36:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <hputc@plt>
  jmp    L14
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D19: COMMENT

tool: D7: HISTORY

assistant: ```c
int hputs(char *hstring, const char *keyword, const char *cval) {
  char squot = 39;
  char value[80];
  int lcval, i, lkeyword;
  lkeyword = (int)strlen(keyword);
  if (lkeyword == 7 && (strncmp(keyword, "COMMENT", 7) == 0 || strncmp(keyword, "HISTORY", 7) == 0)) {
    return (hputc(hstring, keyword, cval));
  }
  lcval = (int)strlen(cval);
  if (lcval > 67) {
    lcval = 67;
  }
  value[0] = squot;
  strncpy(&value[1], cval, lcval);
  if (lcval < 8) {
    for (i = lcval; i < 8; i++) {
      value[i + 1] = ' ';
    }
    lcval = 8;
  }
  value[lcval + 1] = squot;
  value[lcval + 2] = (char)0;
  return (hputc(hstring, keyword, value));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hputs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x7,%eax
  je     L20
L43:
  mov    %r13,%rdi
  mov    $0x43,%ebx
  mov    %rsp,%r14
  call   <strlen@plt>
  lea    0x1(%rsp),%rdi
  mov    %r13,%rsi
  movb   $0x27,(%rsp)
  cmp    %ebx,%eax
  mov    %rax,%r15
  cmovle %eax,%ebx
  mov    %ebx,%edx
  call   <strncpy@plt>
  cmp    $0x7,%r15d
  jle    L26
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
L44:
  cltq
  movslq %ebx,%rbx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x27,(%rsp,%rax,1)
  movb   $0x0,(%rsp,%rbx,1)
  call   <hputc@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L26:
  lea    0x1(%rbx),%edi
  mov    $0x7,%edx
  mov    $0x20,%esi
  sub    %ebx,%edx
  movslq %edi,%rdi
  mov    $0xa,%ebx
  add    $0x1,%rdx
  add    %r14,%rdi
  call   <memset@plt>
  mov    $0x9,%eax
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x7,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L13
  mov    $0x7,%edx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L43
L13:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x68,%rsp
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <hputc@plt>
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D19: COMMENT

tool: D3: HISTORY

assistant: ```c
int hputs(char *hstring, const char *keyword, const char *cval) {
  char squot = 39;
  char value[80];
  int lcval, i, lkeyword;
  lkeyword = (int)strlen(keyword);
  if (lkeyword == 7 && (strncmp(keyword, "COMMENT", 7) == 0 || strncmp(keyword, "HISTORY", 7) == 0)) {
    return (hputc(hstring, keyword, cval));
  }
  lcval = (int)strlen(cval);
  if (lcval > 67) {
    lcval = 67;
  }
  value[0] = squot;
  strncpy(&value[1], cval, lcval);
  if (lcval < 8) {
    for (i = lcval; i < 8; i++) {
      value[i + 1] = ' ';
    }
    lcval = 8;
  }
  value[lcval + 1] = squot;
  value[lcval + 2] = (char)0;
  return (hputc(hstring, keyword, value));
}
```
user: Translate the below assembly code into C programming language:

```asm
<hputs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x7,%eax
  je     L24
L55:
  mov    %r13,%rdi
  mov    $0x43,%ebx
  mov    %rsp,%r14
  call   <strlen@plt>
  lea    0x1(%rsp),%rdi
  mov    %r13,%rsi
  movb   $0x27,(%rsp)
  cmp    %ebx,%eax
  mov    %rax,%r15
  cmovle %eax,%ebx
  mov    %ebx,%edx
  call   <strncpy@plt>
  cmp    $0x7,%r15d
  jle    L35
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
L11:
  cltq
  movslq %ebx,%rbx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x27,(%rsp,%rax,1)
  movb   $0x0,(%rsp,%rbx,1)
  call   <hputc@plt>
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L35:
  lea    0x1(%rbx),%edi
  mov    $0x7,%edx
  mov    $0x20,%esi
  sub    %ebx,%edx
  movslq %edi,%rdi
  mov    $0xa,%ebx
  add    $0x1,%rdx
  add    %r14,%rdi
  call   <memset@plt>
  mov    $0x9,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x7,%edx
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L31
  mov    $0x7,%edx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L55
L31:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x68,%rsp
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <hputc@plt>
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D15: COMMENT

tool: D7: HISTORY

assistant: ```c
int hputs(char *hstring, const char *keyword, const char *cval) {
  char squot = 39;
  char value[80];
  int lcval, i, lkeyword;
  lkeyword = (int)strlen(keyword);
  if (lkeyword == 7 && (strncmp(keyword, "COMMENT", 7) == 0 || strncmp(keyword, "HISTORY", 7) == 0)) {
    return (hputc(hstring, keyword, cval));
  }
  lcval = (int)strlen(cval);
  if (lcval > 67) {
    lcval = 67;
  }
  value[0] = squot;
  strncpy(&value[1], cval, lcval);
  if (lcval < 8) {
    for (i = lcval; i < 8; i++) {
      value[i + 1] = ' ';
    }
    lcval = 8;
  }
  value[lcval + 1] = squot;
  value[lcval + 2] = (char)0;
  return (hputc(hstring, keyword, value));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t slen = strlen(s);
  size_t minLen = (n > slen) ? slen : n;
  char *newstr = (char *)malloc(minLen + 1);
  memcpy(newstr, s, minLen);
  newstr[minLen] = '\0';
  return newstr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t slen = strlen(s);
  size_t minLen = (n > slen) ? slen : n;
  char *newstr = (char *)malloc(minLen + 1);
  memcpy(newstr, s, minLen);
  newstr[minLen] = '\0';
  return newstr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t slen = strlen(s);
  size_t minLen = (n > slen) ? slen : n;
  char *newstr = (char *)malloc(minLen + 1);
  memcpy(newstr, s, minLen);
  newstr[minLen] = '\0';
  return newstr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  size_t slen = strlen(s);
  size_t minLen = (n > slen) ? slen : n;
  char *newstr = (char *)malloc(minLen + 1);
  memcpy(newstr, s, minLen);
  newstr[minLen] = '\0';
  return newstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <unpack_v0@plt>
  mov    $0x0,%eax
  call   <unpack_v1@plt>
  mov    $0x0,%eax
  call   <unpack_v2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unpack_v0();
  unpack_v1();
  unpack_v2();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <unpack_v0@plt>
  mov    $0x0,%eax
  call   <unpack_v1@plt>
  mov    $0x0,%eax
  call   <unpack_v2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unpack_v0();
  unpack_v1();
  unpack_v2();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unpack_v0@plt>
  xor    %eax,%eax
  call   <unpack_v1@plt>
  xor    %eax,%eax
  call   <unpack_v2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unpack_v0();
  unpack_v1();
  unpack_v2();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <unpack_v0@plt>
  xor    %eax,%eax
  call   <unpack_v1@plt>
  xor    %eax,%eax
  call   <unpack_v2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  unpack_v0();
  unpack_v1();
  unpack_v2();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  movq   $0x30,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0x0,-0x10(%rbp)
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L41
L0:
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0x50(%rbp)
  jmp    L12
L26:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x44(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L34
L45:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  movsbl %al,%eax
  lea    -0x41(%rax),%edx
  mov    -0x48(%rbp),%eax
  add    %eax,%edx
  mov    -0x50(%rbp),%eax
  add    %eax,%edx
  mov    -0x4c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x48(%rbp)
  addl   $0x1,-0x4c(%rbp)
L34:
  mov    -0x4c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L45
  addl   $0x1,-0x50(%rbp)
L12:
  mov    -0x58(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L26
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x48(%rbp)
  addl   $0x1,-0x54(%rbp)
L41:
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D16: %d

tool: D26: %s

tool: D2: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i, j, k = 0;
  int nCasos, lStrings, valorHash = 0, tamString = 0;
  char frase[50] = {'0'};
  scanf("%d", &nCasos);
  getchar();
  for (i = 0; i < nCasos; i++) {
    scanf("%d", &lStrings);
    getchar();
    for (j = 0; j < lStrings; j++) {
      scanf("%s", frase);
      tamString = strlen(frase);
      for (k = 0; k < tamString; k++)
        valorHash = valorHash + ((int)frase[k] - 65) + j + k;
    }
    printf("%d\n", valorHash);
    valorHash = 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x30,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movw   $0x0,0x40(%rsp)
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L33
  mov    $0x0,%r14d
  lea    0xc(%rsp),%r15
  lea    D6(%rip),%r13
L1:
  mov    %r15,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L40
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L7:
  lea    0x10(%rsp),%r12
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L79
  mov    %eax,%eax
  mov    $0x0,%edx
  mov    %r12,%rsi
L27:
  movsbl (%rdx,%rsi,1),%ecx
  lea    -0x41(%rbx,%rcx,1),%ebx
  add    %ebp,%ebx
  add    %edx,%ebx
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L27
L79:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L7
L18:
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L1
L33:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  mov    $0x0,%ebx
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string

tool: D4: %d

tool: D6: %s

tool: D25: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i, j, k = 0;
  int nCasos, lStrings, valorHash = 0, tamString = 0;
  char frase[50] = {'0'};
  scanf("%d", &nCasos);
  getchar();
  for (i = 0; i < nCasos; i++) {
    scanf("%d", &lStrings);
    getchar();
    for (j = 0; j < lStrings; j++) {
      scanf("%s", frase);
      tamString = strlen(frase);
      for (k = 0; k < tamString; k++)
        valorHash = valorHash + ((int)frase[k] - 65) + j + k;
    }
    printf("%d\n", valorHash);
    valorHash = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  mov    %dx,0x50(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movq   $0x30,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%ecx
  test   %ecx,%ecx
  jle    L6
  lea    0x1c(%rsp),%rax
  xor    %r12d,%r12d
  lea    D0(%rip),%rbx
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L35:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r14
L56:
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %r14,%rsi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L46
  cltq
  xor    %edx,%edx
  nopl   (%rax)
L36:
  movsbl (%r14,%rdx,1),%ecx
  lea    -0x41(%rbp,%rcx,1),%ebp
  add    %r15d,%ebp
  add    %edx,%ebp
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L36
L46:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jg     L56
L7:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x18(%rsp)
  jg     L35
L6:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D2
data_type: string

tool: D1: %d

tool: D0: %s

tool: D2: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i, j, k = 0;
  int nCasos, lStrings, valorHash = 0, tamString = 0;
  char frase[50] = {'0'};
  scanf("%d", &nCasos);
  getchar();
  for (i = 0; i < nCasos; i++) {
    scanf("%d", &lStrings);
    getchar();
    for (j = 0; j < lStrings; j++) {
      scanf("%s", frase);
      tamString = strlen(frase);
      for (k = 0; k < tamString; k++)
        valorHash = valorHash + ((int)frase[k] - 65) + j + k;
    }
    printf("%d\n", valorHash);
    valorHash = 0;
  }
  return 0;
}
```