user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3a000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x9b0,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x3a9a8(%rsp)
  xor    %eax,%eax
  lea    D108(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  movss  D36(%rip),%xmm0
L23:
  movss  %xmm0,0x27120(%rsp,%rax,1)
  movss  %xmm0,0x138a0(%rsp,%rax,1)
  movss  %xmm0,0x20(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x13880,%rax
  jne    L23
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x9,%ebx
  pxor   %xmm6,%xmm6
  movsd  %xmm6,(%rsp)
  movq   %xmm6,%rbp
L34:
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  lea    0x20(%rsp),%rdx
  lea    0x27120(%rsp),%rcx
L4:
  movss  0x138a0(%rsp,%rax,1),%xmm0
  mulss  (%rax,%rcx,1),%xmm0
  addss  (%rax,%rdx,1),%xmm0
  movss  %xmm0,(%rax,%rdx,1)
  add    $0x4,%rax
  cmp    $0x9c40,%rax
  jne    L4
  lea    0x18(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x18(%rsp),%eax
  add    0x1c(%rsp),%eax
  imul   $0xfff0bdc0,0x10(%rsp),%edx
  add    %edx,%eax
  sub    0x14(%rsp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  divss  D78(%rip),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movsd  D65(%rip),%xmm0
  divsd  %xmm3,%xmm0
  divsd  D117(%rip),%xmm0
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm2
  mov    D20(%rip),%rax
  movq   %rax,%xmm1
  lea    D29(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movq   %rbp,%xmm4
  addsd  D65(%rip),%xmm4
  movq   %xmm4,%rbp
  movsd  (%rsp),%xmm5
  addsd  0x8(%rsp),%xmm5
  movsd  %xmm5,(%rsp)
  sub    $0x1,%ebx
  jne    L34
  cmp    $0xa,%r12d
  jle    L38
  movss  0x9c60(%rsp),%xmm1
  mov    $0x4e20,%eax
  pxor   %xmm0,%xmm0
L33:
  addss  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L33
  cvtss2sd %xmm0,%xmm0
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L38:
  movq   %rbp,%xmm0
  mulsd  D66(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  (%rsp),%xmm7
  divsd  %xmm7,%xmm2
  movapd %xmm7,%xmm1
  lea    D52(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x3a9a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x3a9b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D108
data_type: string
name: parse_data
arguments: label: D36
data_type: f32
name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D78
data_type: f32
name: parse_data
arguments: label: D65
data_type: f32[2]
name: parse_data
arguments: label: D117
data_type: f32[2]
name: parse_data
arguments: label: D20
data_type: f32[2]
name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D35
data_type: string
name: parse_data
arguments: label: D66
data_type: byte[8]
name: parse_data
arguments: label: D52
data_type: string

tool: D108: init data

tool: D36: 0.2

tool: D10: start FP op

tool: D78: 1000000

tool: {"D65": [0.0,22.98023223876953]}

tool: {"D117": [0.0,10.9073486328125]}

tool: {"D20": [0.0,3.890625]}

tool: D29: MFlops:%lf Mops= %f %lf


tool: D35: d= %f


tool: {"D66": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D52: tot_Mops= %f, tot_time= %f, overall Mops/sec= %f


assistant: ```c
int main(int argc, char **argv) {
  float a[20000], b[20000], c[20000];
  int i, j, k, m;
  double result, ops, tot_ops, tot_time;
  struct timeval tv1, tv2;
  printf("init data\n");
  for (i = 0; i < 20000; i++) {
    a[i] = b[i] = c[i] = 0.2;
  }
  printf("start FP op\n");
  long iMax = 10000;
  m = 0;
  tot_ops = 0.0;
  tot_time = 0.0;
  while (++m < 10) {
    gettimeofday(&tv1, NULL);
    for (i = 0; i < iMax; i++) {
      a[i] += b[i] * c[i];
    }
    gettimeofday(&tv2, NULL);
    float dt = (float)(tv2.tv_sec * 1000000 + tv2.tv_usec - tv1.tv_sec * 1000000 - tv1.tv_usec) / 1000000;
    ops = (double)2 * iMax * 20000;
    result = ops / dt / 1000000.0;
    printf("MFlops:%lf Mops= %f %lf\n", result, 1.0e-6 * ops, dt);
    tot_ops += ops;
    tot_time += dt;
  }
  if (argc > 10) {
    float d = 0;
    for (j = 0; j < 20000; j++) {
      d += a[i];
    }
    printf("d= %f\n", d);
  }
  printf("tot_Mops= %f, tot_time= %f, overall Mops/sec= %f\n", 1.0e-6 * tot_ops, tot_time, 1.0e-6 * tot_ops / tot_time);
  return 0;
}
```