ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yar_remap>:
  endbr64
  push   %rbx
  mov    %rdx,%r8
  mov    0x10(%rsp),%r11
  mov    %rcx,%r10
  mov    0x18(%rsp),%rbx
  test   %rsi,%rsi
  jle    L24
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
  nopl   0x0(%rax)
L1:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L1
L24:
  test   %r8,%r8
  jle    L14
  mov    %r9,%rax
  lea    (%r9,%r8,4),%rcx
  nopl   0x0(%rax)
L35:
  movslq (%rax),%rdx
  add    $0x4,%rax
  movq   $0x0,(%rdi,%rdx,8)
  cmp    %rax,%rcx
  jne    L35
  xor    %eax,%eax
  xchg   %ax,%ax
L39:
  movslq (%r9,%rax,4),%rdx
  movslq (%r11,%rax,4),%rcx
  lea    (%rdi,%rdx,8),%rdx
  movsd  (%rbx,%rcx,8),%xmm0
  mulsd  (%r10,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%r8
  jne    L39
L14:
  pop    %rbx
  ret
```

assistant: ```c
void yar_remap(double *restrict dst_array, double missval, long dst_size, long num_links, double *restrict map_wts, long num_wts, const int *restrict dst_add, const int *restrict src_add, const double *restrict src_array) {
  long n;
  for (n = 0; n < dst_size; ++n)
    dst_array[n] = missval;
  for (n = 0; n < num_links; ++n)
    dst_array[dst_add[n]] = 0;
  for (n = 0; n < num_links; ++n) {
    dst_array[dst_add[n]] += src_array[src_add[n]] * map_wts[n];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<yar_remap>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    0x10(%rsp),%r10
  mov    %rdx,%rsi
  mov    0x18(%rsp),%r11
  mov    %rcx,%r8
  test   %rbx,%rbx
  jle    L33
  cmp    $0x1,%rbx
  je     L55
  mov    %rbx,%rdx
  movapd %xmm0,%xmm1
  mov    %rdi,%rax
  shr    %rdx
  unpcklpd %xmm1,%xmm1
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nop
L61:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L61
  mov    %rbx,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%ebx
  je     L33
L45:
  movsd  %xmm0,(%rdi,%rax,8)
L33:
  test   %rsi,%rsi
  jle    L46
  mov    %r9,%rax
  lea    (%r9,%rsi,4),%rcx
  nopl   0x0(%rax)
L62:
  movslq (%rax),%rdx
  add    $0x4,%rax
  movq   $0x0,(%rdi,%rdx,8)
  cmp    %rcx,%rax
  jne    L62
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L41:
  movslq (%r9,%rax,4),%rdx
  movslq (%r10,%rax,4),%rcx
  lea    (%rdi,%rdx,8),%rdx
  movsd  (%r11,%rcx,8),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L41
L46:
  pop    %rbx
  ret
L55:
  xor    %eax,%eax
  jmp    L45
```

assistant: ```c
void yar_remap(double *restrict dst_array, double missval, long dst_size, long num_links, double *restrict map_wts, long num_wts, const int *restrict dst_add, const int *restrict src_add, const double *restrict src_array) {
  long n;
  for (n = 0; n < dst_size; ++n)
    dst_array[n] = missval;
  for (n = 0; n < num_links; ++n)
    dst_array[dst_add[n]] = 0;
  for (n = 0; n < num_links; ++n) {
    dst_array[dst_add[n]] += src_array[src_add[n]] * map_wts[n];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_setcchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L7
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L13
L7:
  nop
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_setcchar(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_setcchar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D6(%rip),%rdi
  call   <report_error@plt>
L3:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: UNSUPPORTED

assistant: ```c
void cmd_setcchar(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_setcchar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L6
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <report_error@plt>
  nopl   0x0(%rax)
L6:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_setcchar(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmd_setcchar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L5
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <report_error@plt>
  nopl   0x0(%rax)
L5:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: UNSUPPORTED

assistant: ```c
void cmd_setcchar(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_error("UNSUPPORTED");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <init_test@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x1,%eax
  jmp    L5
L13:
  mov    $0x0,%eax
L5:
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x2,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x15,-0x8(%rbp)
  jmp    L15
L3:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    $0x1,%esi
  mov    %edx,%ecx
  shl    %cl,%esi
  mov    %esi,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %ecx,%edi
  call   <print_for@plt>
  addq   $0x1,-0x8(%rbp)
L15:
  cmpq   $0x1e,-0x8(%rbp)
  jbe    L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: 
Sequential on file %s:


assistant: ```c
int main(int argc, char **argv) {
  assert(init_test() == 0 && "Could not initialize.");
  assert(argc == 2 && "usage: file_read.out target_file");
  printf("\nSequential on file %s:\n", argv[1]);
  for (size_t fs_bits = 31 - 10; fs_bits < 31; ++fs_bits) {
    print_for(1 << fs_bits, false, argv[1]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <init_test@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x2,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rbp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x15,%ebx
  mov    $0x1,%r12d
L3:
  mov    0x8(%rbp),%rdx
  mov    %r12d,%edi
  mov    %ebx,%ecx
  shl    %cl,%edi
  mov    $0x0,%esi
  call   <print_for@plt>
  add    $0x1,%rbx
  cmp    $0x1f,%rbx
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: 
Sequential on file %s:


assistant: ```c
int main(int argc, char **argv) {
  assert(init_test() == 0 && "Could not initialize.");
  assert(argc == 2 && "usage: file_read.out target_file");
  printf("\nSequential on file %s:\n", argv[1]);
  for (size_t fs_bits = 31 - 10; fs_bits < 31; ++fs_bits) {
    print_for(1 << fs_bits, false, argv[1]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    $0x1,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <init_test@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x2,%ebx
  mov    $0x15,%ebx
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rbp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%ecx
  mov    0x8(%rbp),%rdx
  mov    %r12d,%edi
  xor    %esi,%esi
  shl    %cl,%edi
  add    $0x1,%rbx
  call   <print_for@plt>
  cmp    $0x1f,%rbx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: 
Sequential on file %s:


assistant: ```c
int main(int argc, char **argv) {
  assert(init_test() == 0 && "Could not initialize.");
  assert(argc == 2 && "usage: file_read.out target_file");
  printf("\nSequential on file %s:\n", argv[1]);
  for (size_t fs_bits = 31 - 10; fs_bits < 31; ++fs_bits) {
    print_for(1 << fs_bits, false, argv[1]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    $0x1,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <init_test@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x2,%ebx
  mov    $0x15,%ebx
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rbp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%ecx
  mov    0x8(%rbp),%rdx
  mov    %r12d,%edi
  xor    %esi,%esi
  shl    %cl,%edi
  add    $0x1,%rbx
  call   <print_for@plt>
  cmp    $0x1f,%rbx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: 
Sequential on file %s:


assistant: ```c
int main(int argc, char **argv) {
  assert(init_test() == 0 && "Could not initialize.");
  assert(argc == 2 && "usage: file_read.out target_file");
  printf("\nSequential on file %s:\n", argv[1]);
  for (size_t fs_bits = 31 - 10; fs_bits < 31; ++fs_bits) {
    print_for(1 << fs_bits, false, argv[1]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jle    L30
  cmpl   $0x24,-0x2c(%rbp)
  jle    L82
L30:
  mov    $0x0,%eax
  jmp    L96
L82:
  mov    -0x34(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L17
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jns    L17
  addl   $0x1,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  neg    %rax
  mov    %rax,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <log@plt>
  mov    %eax,%ebx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <get_log_base@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L34
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L34:
  mov    -0x34(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L32
  cmpl   $0x8,-0x2c(%rbp)
  jne    L16
  addl   $0x1,-0x20(%rbp)
  jmp    L32
L16:
  cmpl   $0x10,-0x2c(%rbp)
  jne    L32
  addl   $0x2,-0x20(%rbp)
L32:
  mov    -0x20(%rbp),%eax
L96:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int count_digits(unsigned long long num, int base, int precision, int type) {
  int count = 0;
  unsigned long long tmp_num = num;
  if (base < 2 || base > 36) {
    return 0;
  }
  if ((type & 2) && (((signed long long)num) < 0ll)) {
    ++count;
    tmp_num = -num;
  }
  int long_num = ceil(log(tmp_num) / get_log_base(base));
  count += long_num;
  if (long_num < precision) {
    count = precision;
  }
  if (type & 32) {
    if (base == 8) {
      ++count;
    } else if (base == 16) {
      count += 2;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_digits>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r13d
  lea    -0x2(%rsi),%edx
  mov    $0x0,%eax
  cmp    $0x22,%edx
  ja     L11
  mov    %esi,%ebp
  mov    %ecx,%r12d
  mov    %ecx,%ebx
  and    $0x2,%ebx
  je     L24
  mov    $0x0,%ebx
  test   %rdi,%rdi
  js     L18
L24:
  call   <log@plt>
  mov    %eax,%r14d
  mov    %ebp,%edi
  call   <get_log_base@plt>
  mov    %eax,%ecx
  mov    %r14d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  call   <ceil@plt>
  add    %eax,%ebx
  cmp    %r13d,%eax
  mov    %r13d,%eax
  cmovge %ebx,%eax
  test   $0x20,%r12b
  je     L11
  cmp    $0x8,%ebp
  je     L9
  lea    0x2(%rax),%edx
  cmp    $0x10,%ebp
  cmove  %edx,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  neg    %rdi
  mov    $0x1,%ebx
  jmp    L24
L9:
  add    $0x1,%eax
  jmp    L11
```

assistant: ```c
int count_digits(unsigned long long num, int base, int precision, int type) {
  int count = 0;
  unsigned long long tmp_num = num;
  if (base < 2 || base > 36) {
    return 0;
  }
  if ((type & 2) && (((signed long long)num) < 0ll)) {
    ++count;
    tmp_num = -num;
  }
  int long_num = ceil(log(tmp_num) / get_log_base(base));
  count += long_num;
  if (long_num < precision) {
    count = precision;
  }
  if (type & 32) {
    if (base == 8) {
      ++count;
    } else if (base == 16) {
      count += 2;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_digits>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  lea    -0x2(%rsi),%edx
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x22,%edx
  ja     L46
  mov    %ecx,%ebx
  mov    %esi,%ebp
  mov    %ecx,%r12d
  and    $0x2,%ebx
  je     L18
  xor    %ebx,%ebx
  test   %rdi,%rdi
  js     L30
L18:
  call   <log@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <get_log_base@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%edi
  call   <ceil@plt>
  add    %eax,%ebx
  cmp    %r14d,%eax
  mov    %r14d,%eax
  cmovge %ebx,%eax
  and    $0x20,%r12d
  je     L46
  cmp    $0x8,%ebp
  je     L7
  lea    0x2(%rax),%edx
  cmp    $0x10,%ebp
  cmove  %edx,%eax
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  neg    %rdi
  mov    $0x1,%ebx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L7:
  pop    %rbx
  add    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int count_digits(unsigned long long num, int base, int precision, int type) {
  int count = 0;
  unsigned long long tmp_num = num;
  if (base < 2 || base > 36) {
    return 0;
  }
  if ((type & 2) && (((signed long long)num) < 0ll)) {
    ++count;
    tmp_num = -num;
  }
  int long_num = ceil(log(tmp_num) / get_log_base(base));
  count += long_num;
  if (long_num < precision) {
    count = precision;
  }
  if (type & 32) {
    if (base == 8) {
      ++count;
    } else if (base == 16) {
      count += 2;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_digits>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  lea    -0x2(%rsi),%edx
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x22,%edx
  ja     L42
  mov    %ecx,%ebx
  mov    %esi,%ebp
  mov    %ecx,%r12d
  and    $0x2,%ebx
  je     L22
  xor    %ebx,%ebx
  test   %rdi,%rdi
  js     L23
L22:
  call   <log@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <get_log_base@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%edi
  call   <ceil@plt>
  add    %eax,%ebx
  cmp    %r14d,%eax
  mov    %r14d,%eax
  cmovge %ebx,%eax
  and    $0x20,%r12d
  je     L42
  cmp    $0x8,%ebp
  je     L38
  lea    0x2(%rax),%edx
  cmp    $0x10,%ebp
  cmove  %edx,%eax
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L23:
  neg    %rdi
  mov    $0x1,%ebx
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L38:
  pop    %rbx
  add    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int count_digits(unsigned long long num, int base, int precision, int type) {
  int count = 0;
  unsigned long long tmp_num = num;
  if (base < 2 || base > 36) {
    return 0;
  }
  if ((type & 2) && (((signed long long)num) < 0ll)) {
    ++count;
    tmp_num = -num;
  }
  int long_num = ceil(log(tmp_num) / get_log_base(base));
  count += long_num;
  if (long_num < precision) {
    count = precision;
  }
  if (type & 32) {
    if (base == 8) {
      ++count;
    } else if (base == 16) {
      count += 2;
    }
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    $0xf4240,%edi
  call   <usleep@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void sleep(int sec) {
  int i;
  for (i = 0; i < sec; i++)
    usleep(1 * 1000 * 1000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sleep>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L5:
  mov    $0xf4240,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  ret
```

assistant: ```c
void sleep(int sec) {
  int i;
  for (i = 0; i < sec; i++)
    usleep(1 * 1000 * 1000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sleep>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xf4240,%edi
  add    $0x1,%ebx
  call   <usleep@plt>
  cmp    %ebx,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  ret
```

assistant: ```c
void sleep(int sec) {
  int i;
  for (i = 0; i < sec; i++)
    usleep(1 * 1000 * 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0xf4240,%edi
  add    $0x1,%ebx
  call   <usleep@plt>
  cmp    %ebx,%ebp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
void sleep(int sec) {
  int i;
  for (i = 0; i < sec; i++)
    usleep(1 * 1000 * 1000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_multiple_arg_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L102
  mov    $0x0,%eax
  jmp    L84
L102:
  mov    -0x38(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L80
L78:
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L106
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x30(%rbp)
  addq   $0x1,-0x20(%rbp)
L80:
  cmpq   $0x0,-0x30(%rbp)
  jne    L78
  jmp    L124
L106:
  nop
L124:
  cmpq   $0x0,-0x30(%rbp)
  je     L131
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L74
L131:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x28(%rbp)
L74:
  mov    -0x20(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L82
L115:
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L121
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L121
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L121
  addq   $0x1,-0x18(%rbp)
L121:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    (%rax,%rdx,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L82:
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L115
L34:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L84:
  leave
  ret
```

assistant: ```c
char *get_multiple_arg_token(const char *arg) {
  char *tok, *ret;
  size_t len, num_of_escape, i, j;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  num_of_escape = 0;
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
      ++num_of_escape;
    } else
      break;
  }
  if (tok)
    len = (size_t)(tok - arg + 1);
  else
    len = strlen(arg) + 1;
  len -= num_of_escape;
  ret = (char *)malloc(len);
  i = 0;
  j = 0;
  while (arg[i] && (j < len - 1)) {
    if (arg[i] == '\\' && arg[i + 1] && arg[i + 1] == ',')
      ++i;
    ret[j++] = arg[i++];
  }
  ret[len - 1] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_multiple_arg_token>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L4
  mov    $0x2c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L85
  mov    $0x0,%r12d
L32:
  cmpb   $0x5c,-0x1(%rax)
  jne    L8
  lea    0x1(%rax),%rdi
  mov    $0x2c,%esi
  call   <strchr@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L32
L54:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  jmp    L128
L132:
  lea    0x1(%rdx),%rdi
  movzbl 0x0(%rbp,%rdx,1),%esi
  mov    %sil,(%rcx)
  movzbl 0x1(%rbp,%rdx,1),%esi
  test   %sil,%sil
  je     L131
  add    $0x1,%rcx
  cmp    %r8,%rcx
  je     L131
  mov    %rdi,%rdx
L99:
  cmp    $0x5c,%sil
  jne    L132
  lea    0x1(%rdx),%rsi
  cmpb   $0x2c,0x1(%rbp,%rdx,1)
  cmove  %rsi,%rdx
  jmp    L132
L131:
  movb   $0x0,-0x1(%rax,%rbx,1)
L27:
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %rdi,%r9
  jmp    L27
L8:
  sub    %rbp,%rax
  lea    0x1(%rax),%rbx
L128:
  sub    %r12,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r9
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L131
  cmp    $0x1,%rbx
  je     L131
  mov    %rax,%rcx
  lea    -0x1(%rax,%rbx,1),%r8
  mov    $0x0,%edx
  jmp    L99
L85:
  mov    $0x0,%r12d
  jmp    L54
```

assistant: ```c
char *get_multiple_arg_token(const char *arg) {
  char *tok, *ret;
  size_t len, num_of_escape, i, j;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  num_of_escape = 0;
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
      ++num_of_escape;
    } else
      break;
  }
  if (tok)
    len = (size_t)(tok - arg + 1);
  else
    len = strlen(arg) + 1;
  len -= num_of_escape;
  ret = (char *)malloc(len);
  i = 0;
  j = 0;
  while (arg[i] && (j < len - 1)) {
    if (arg[i] == '\\' && arg[i + 1] && arg[i + 1] == ',')
      ++i;
    ret[j++] = arg[i++];
  }
  ret[len - 1] = '\0';
  return ret;
}
```