ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<assert_failed>:
  endbr64
  sub    $0x38,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f69747265737341,%r8
  movabs $0x64656c696166206e,%r9
  mov    %r8,(%rsp)
  mov    %r9,0x8(%rsp)
  movabs $0x61207325206e6920,%r10
  movabs $0x2520656e696c2074,%r11
  mov    %r10,0x10(%rsp)
  mov    %r11,0x18(%rsp)
  movw   $0xa64,0x20(%rsp)
  movb   $0x0,0x22(%rsp)
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void assert_failed(char *file, int line) {
  const char ASSERT_FAILED_STR[] = "Assertion failed in %s at line %d\n";
  printf(ASSERT_FAILED_STR, file, line);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assert_failed>:
  endbr64
  sub    $0x38,%rsp
  movdqa D2(%rip),%xmm0
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xa64,%eax
  mov    %r8,%rsi
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movb   $0x0,0x22(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: byte[16]
name: retrieve_data
arguments: data_tag: D8
type: byte[16]

tool: {"D2": [0x41,0x73,0x73,0x65,0x72,0x74,0x69,0x6f,0x6e,0x20,0x66,0x61,0x69,0x6c,0x65,0x64]}

tool: {"D8": [0x20,0x69,0x6e,0x20,0x25,0x73,0x20,0x61,0x74,0x20,0x6c,0x69,0x6e,0x65,0x20,0x25]}

assistant: ```c
void assert_failed(char *file, int line) {
  const char ASSERT_FAILED_STR[] = "Assertion failed in %s at line %d\n";
  printf(ASSERT_FAILED_STR, file, line);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assert_failed>:
  endbr64
  sub    $0x38,%rsp
  movdqa D5(%rip),%xmm0
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xa64,%eax
  mov    %r8,%rsi
  movaps %xmm0,(%rsp)
  movdqa D4(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movb   $0x0,0x22(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: byte[16]
name: parse_data
arguments: tag: D4
type_infered: byte[16]

tool: {"D5": [0x41,0x73,0x73,0x65,0x72,0x74,0x69,0x6f,0x6e,0x20,0x66,0x61,0x69,0x6c,0x65,0x64]}

tool: {"D4": [0x20,0x69,0x6e,0x20,0x25,0x73,0x20,0x61,0x74,0x20,0x6c,0x69,0x6e,0x65,0x20,0x25]}

assistant: ```c
void assert_failed(char *file, int line) {
  const char ASSERT_FAILED_STR[] = "Assertion failed in %s at line %d\n";
  printf(ASSERT_FAILED_STR, file, line);
}
```
user: What is the c source code of the assembly code below?

```asm
<log_fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string

tool: D9: FATAL: 

tool: D10: 


assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  printf("FATAL: ");
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  printf("\r\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<log_fatal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D12: FATAL: 

tool: D1: 


assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  printf("FATAL: ");
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  printf("\r\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_fatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D10(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string

tool: D10: FATAL: 

tool: D14: 


assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  printf("FATAL: ");
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  printf("\r\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<log_fatal>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D19: FATAL: 

tool: D12: 


assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  printf("FATAL: ");
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  printf("\r\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Restart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <U3_TxPutsf@plt>
L7:
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: restart


assistant: ```c
int Restart(char *buf) {
  U3_TxPutsf("restart\r\n");
  while (1)
    ;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Restart>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <U3_TxPutsf@plt>
L1:
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: restart


assistant: ```c
int Restart(char *buf) {
  U3_TxPutsf("restart\r\n");
  while (1)
    ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Restart>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <U3_TxPutsf@plt>
L8:
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: restart


assistant: ```c
int Restart(char *buf) {
  U3_TxPutsf("restart\r\n");
  while (1)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Restart>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <U3_TxPutsf@plt>
L8:
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: restart


assistant: ```c
int Restart(char *buf) {
  U3_TxPutsf("restart\r\n");
  while (1)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<imprime_matriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L3:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L8:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0x9,-0x4(%rbp)
  jle    L8
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x9,-0x8(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: mat[%d,%d] = %lf


assistant: ```c
void imprime_matriz(double **matriz) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("mat[%d,%d] = %lf\n", i, j, matriz[i][j]);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<imprime_matriz>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebp
  lea    D2(%rip),%r13
L11:
  mov    $0x0,%ebx
L2:
  mov    (%r12),%rax
  movsd  (%rax,%rbx,8),%xmm0
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L2
  add    $0x1,%ebp
  add    $0x8,%r12
  cmp    $0xa,%ebp
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: mat[%d,%d] = %lf


assistant: ```c
void imprime_matriz(double **matriz) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("mat[%d,%d] = %lf\n", i, j, matriz[i][j]);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<imprime_matriz>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%r13),%rax
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  movsd  (%rax,%rbx,8),%xmm0
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L2
  add    $0x1,%ebp
  add    $0x8,%r13
  cmp    $0xa,%ebp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: mat[%d,%d] = %lf


assistant: ```c
void imprime_matriz(double **matriz) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("mat[%d,%d] = %lf\n", i, j, matriz[i][j]);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imprime_matriz>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x0(%r13),%rax
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  movsd  (%rax,%rbx,8),%xmm0
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L7
  add    $0x1,%ebp
  add    $0x8,%r13
  cmp    $0xa,%ebp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: mat[%d,%d] = %lf


assistant: ```c
void imprime_matriz(double **matriz) {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("mat[%d,%d] = %lf\n", i, j, matriz[i][j]);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x9,-0x10(%rbp)
  jmp    L39
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x18(%rbp),%rdx
  lea    -0x4(%rdx),%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L63
L48:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L33
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,%rax
  mov    %eax,-0xc(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cltq
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,%rax
  mov    %eax,-0x4(%rbp)
  sarl   -0x8(%rbp)
L63:
  cmpl   $0x0,-0x8(%rbp)
  jne    L48
  cmpl   $0x1,-0xc(%rbp)
  je     L39
  mov    $0x0,%eax
  jmp    L35
L39:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jne    L9
  mov    $0x1,%eax
L35:
  leave
  ret
```

assistant: ```c
unsigned long is_prime(unsigned long val) {
  int i = 0, p = 0, exp = 0, a = 0;
  for (i = 9; i--;) {
    a = (rand() % (val - 4)) + 2;
    p = 1;
    exp = val - 1;
    while (exp) {
      if (exp & 1) {
        p = (p * a) % val;
      }
      a = (a * a) % val;
      exp >>= 1;
    }
    if (p != 1) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_prime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x9,%ebp
  lea    -0x4(%rdi),%r12
  jmp    L27
L8:
  imul   %ecx,%ecx
  movslq %ecx,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %edx,%ecx
  sar    %esi
  je     L43
L78:
  test   $0x1,%sil
  je     L8
  imul   %ecx,%edi
  movslq %edi,%rax
  mov    $0x0,%edx
  div    %rbx
  mov    %edx,%edi
  jmp    L8
L43:
  cmp    $0x1,%edi
  jne    L80
L40:
  sub    $0x1,%ebp
  je     L14
L27:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    $0x0,%edx
  div    %r12
  lea    0x2(%rdx),%ecx
  mov    %ebx,%esi
  sub    $0x1,%esi
  je     L40
  mov    $0x1,%edi
  jmp    L78
L14:
  mov    $0x1,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  mov    $0x0,%eax
  jmp    L33
```

assistant: ```c
unsigned long is_prime(unsigned long val) {
  int i = 0, p = 0, exp = 0, a = 0;
  for (i = 9; i--;) {
    a = (rand() % (val - 4)) + 2;
    p = 1;
    exp = val - 1;
    while (exp) {
      if (exp & 1) {
        p = (p * a) % val;
      }
      a = (a * a) % val;
      exp >>= 1;
    }
    if (p != 1) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_prime>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbp
  lea    -0x4(%rdi),%rbp
  push   %rbx
  mov    $0x9,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L24:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edx,%edx
  div    %rbp
  lea    0x2(%rdx),%ecx
  test   %r12d,%r12d
  je     L3
  mov    %r12d,%esi
  mov    $0x1,%edi
  nopl   0x0(%rax)
L22:
  test   $0x1,%sil
  je     L39
  imul   %ecx,%edi
  xor    %edx,%edx
  movslq %edi,%rax
  div    %r13
  mov    %edx,%edi
L39:
  imul   %ecx,%ecx
  xor    %edx,%edx
  movslq %ecx,%rax
  div    %r13
  sar    %esi
  mov    %edx,%ecx
  jne    L22
  cmp    $0x1,%edi
  jne    L28
L3:
  sub    $0x1,%ebx
  jne    L24
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long is_prime(unsigned long val) {
  int i = 0, p = 0, exp = 0, a = 0;
  for (i = 9; i--;) {
    a = (rand() % (val - 4)) + 2;
    p = 1;
    exp = val - 1;
    while (exp) {
      if (exp & 1) {
        p = (p * a) % val;
      }
      a = (a * a) % val;
      exp >>= 1;
    }
    if (p != 1) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbp
  lea    -0x4(%rdi),%rbp
  push   %rbx
  mov    $0x9,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edx,%edx
  div    %rbp
  lea    0x2(%rdx),%ecx
  test   %r12d,%r12d
  je     L48
  mov    %r12d,%esi
  mov    $0x1,%edi
  nopl   0x0(%rax)
L34:
  test   $0x1,%sil
  je     L25
  imul   %ecx,%edi
  xor    %edx,%edx
  movslq %edi,%rax
  div    %r13
  mov    %edx,%edi
L25:
  imul   %ecx,%ecx
  xor    %edx,%edx
  movslq %ecx,%rax
  div    %r13
  sar    %esi
  mov    %edx,%ecx
  jne    L34
  cmp    $0x1,%edi
  jne    L12
L48:
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long is_prime(unsigned long val) {
  int i = 0, p = 0, exp = 0, a = 0;
  for (i = 9; i--;) {
    a = (rand() % (val - 4)) + 2;
    p = 1;
    exp = val - 1;
    while (exp) {
      if (exp & 1) {
        p = (p * a) % val;
      }
      a = (a * a) % val;
      exp >>= 1;
    }
    if (p != 1) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  jmp    L19
L0:
  movss  -0x14(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x8(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
L19:
  movss  -0x18(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  ja     L0
  movss  -0x14(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: f32

tool: D4: 1

assistant: ```c
float power(float a, float b) {
  float x = a;
  for (float i = 1; i < b; i++) {
    a = a * x;
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  movaps %xmm0,%xmm3
  movss  D2(%rip),%xmm2
  movaps %xmm2,%xmm4
  comiss %xmm2,%xmm1
  jbe    L10
L8:
  mulss  %xmm3,%xmm0
  addss  %xmm4,%xmm2
  comiss %xmm2,%xmm1
  ja     L8
  ret
L10:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: f32

tool: D2: 1

assistant: ```c
float power(float a, float b) {
  float x = a;
  for (float i = 1; i < b; i++) {
    a = a * x;
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  movss  D2(%rip),%xmm4
  movaps %xmm0,%xmm3
  comiss %xmm4,%xmm1
  movaps %xmm4,%xmm2
  jbe    L5
  nopw   0x0(%rax,%rax,1)
L19:
  addss  %xmm4,%xmm2
  mulss  %xmm3,%xmm0
  comiss %xmm2,%xmm1
  ja     L19
L5:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: f32

tool: D2: 1

assistant: ```c
float power(float a, float b) {
  float x = a;
  for (float i = 1; i < b; i++) {
    a = a * x;
  }
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power>:
  endbr64
  movss  D3(%rip),%xmm4
  movaps %xmm0,%xmm3
  comiss %xmm4,%xmm1
  movaps %xmm4,%xmm2
  jbe    L14
  nopw   0x0(%rax,%rax,1)
L12:
  addss  %xmm4,%xmm2
  mulss  %xmm3,%xmm0
  comiss %xmm2,%xmm1
  ja     L12
L14:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: f32

tool: D3: 1

assistant: ```c
float power(float a, float b) {
  float x = a;
  for (float i = 1; i < b; i++) {
    a = a * x;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pop_quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <command@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <pop_done@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: QUIT

assistant: ```c
int pop_quit(void) {
  int i;
  i = command("QUIT");
  pop_done();
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pop_quit>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rdi
  call   <command@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <pop_done@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: QUIT

assistant: ```c
int pop_quit(void) {
  int i;
  i = command("QUIT");
  pop_done();
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pop_quit>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  call   <command@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <pop_done@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: QUIT

assistant: ```c
int pop_quit(void) {
  int i;
  i = command("QUIT");
  pop_done();
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pop_quit>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  call   <command@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <pop_done@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: QUIT

assistant: ```c
int pop_quit(void) {
  int i;
  i = command("QUIT");
  pop_done();
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zDumpLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    $0xa,%ebx
  jne    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int zDumpLine(FILE *fp) {
  register int c;
  while ((c = fgetc(fp)) != '\n')
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zDumpLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L5:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%eax
  jne    L5
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int zDumpLine(FILE *fp) {
  register int c;
  while ((c = fgetc(fp)) != '\n')
    ;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zDumpLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%eax
  jne    L4
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int zDumpLine(FILE *fp) {
  register int c;
  while ((c = fgetc(fp)) != '\n')
    ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zDumpLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%eax
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int zDumpLine(FILE *fp) {
  register int c;
  while ((c = fgetc(fp)) != '\n')
    ;
  return 0;
}
```