ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rcpPktType>:
  endbr64
  cmp    $0xe,%edi
  ja     L6
  lea    D16(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D54(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D8(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D140(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D141(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D104(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D139(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D105(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D31(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D152(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D75(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D137(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D114(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D142(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D147(%rip),%rax
  ret
L6:
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D54
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D140
type_guessed: string
name: unpack_data
arguments: label: D141
type_guessed: string
name: unpack_data
arguments: label: D104
type_guessed: string
name: unpack_data
arguments: label: D139
type_guessed: string
name: unpack_data
arguments: label: D105
type_guessed: string
name: unpack_data
arguments: label: D31
type_guessed: string
name: unpack_data
arguments: label: D152
type_guessed: string
name: unpack_data
arguments: label: D75
type_guessed: string
name: unpack_data
arguments: label: D137
type_guessed: string
name: unpack_data
arguments: label: D114
type_guessed: string
name: unpack_data
arguments: label: D142
type_guessed: string
name: unpack_data
arguments: label: D147
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D54: REGISTRATION

tool: D8: CLI

tool: D140: VLAN_DELETED

tool: D141: INTERFACE UP

tool: D104: INTERFACE DOWN

tool: D139: ADD ROUTE

tool: D105: DELETE ROUTE

tool: D31: LOG

tool: D152: ROUTE REQUEST

tool: D75: HTTP AUTHNETICATION

tool: D137: UPDATE SYSTEM FILES

tool: D114: UPDATE DNS

tool: D142: INTERFACE ADDRESS CHANGED

tool: D147: LOOPBACK

tool: D1: UNKNOWN

assistant: ```c
const char *rcpPktType(unsigned type) {
  switch (type) {
  case 1:
    return "CLI";
  case 2:
    return "REGISTRATION";
  case 3:
    return "LOG";
  case 4:
    return "INTERFACE UP";
  case 5:
    return "INTERFACE DOWN";
  case 6:
    return "ADD ROUTE";
  case 7:
    return "DELETE ROUTE";
  case 8:
    return "UPDATE SYSTEM FILES";
  case 9:
    return "UPDATE DNS";
  case 10:
    return "INTERFACE ADDRESS CHANGED";
  case 11:
    return "LOOPBACK";
  case 14:
    return "VLAN_DELETED";
  case 12:
    return "ROUTE REQUEST";
  case 13:
    return "HTTP AUTHNETICATION";
  }
  return "UNKNOWN";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sol_ptr_vector_take>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sol_ptr_vector_get@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sol_ptr_vector_del@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sol_ptr_vector_take(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sol_ptr_vector_take>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <sol_ptr_vector_get@plt>
  mov    %rax,%r12
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <sol_ptr_vector_del@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *sol_ptr_vector_take(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sol_ptr_vector_take>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <sol_ptr_vector_get@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sol_ptr_vector_del@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_ptr_vector_take(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sol_ptr_vector_take>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <sol_ptr_vector_get@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <sol_ptr_vector_del@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_ptr_vector_take(struct sol_ptr_vector *pv, uint16_t i) {
  void *result = sol_ptr_vector_get(pv, i);
  sol_ptr_vector_del(pv, i);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L28:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
L15:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_whitespace(const char *s) {
  for (; (*s != 0) && (isspace(*s)); s++)
    ;
  return (char *)s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L26
L20:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L11
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L20
  mov    %rbx,%rax
  jmp    L26
L11:
  mov    %rbx,%rax
L26:
  pop    %rbx
  ret
```

assistant: ```c
char *skip_whitespace(const char *s) {
  for (; (*s != 0) && (isspace(*s)); s++)
    ;
  return (char *)s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L28
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L34:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L35
L28:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L34
L35:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_whitespace(const char *s) {
  for (; (*s != 0) && (isspace(*s)); s++)
    ;
  return (char *)s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_whitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L13
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L34:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L23
L13:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L34
L23:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_whitespace(const char *s) {
  for (; (*s != 0) && (isspace(*s)); s++)
    ;
  return (char *)s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rate@plt>
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x20,%edi
  call   <post@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: bye.
Your rating was %s.


assistant: ```c
void die() {
  printf("bye.\nYour rating was %s.\n", rate());
  post(' ');
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rate@plt>
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x20,%edi
  call   <post@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: bye.
Your rating was %s.


assistant: ```c
void die() {
  printf("bye.\nYour rating was %s.\n", rate());
  post(' ');
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rate@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x20,%edi
  call   <post@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: bye.
Your rating was %s.


assistant: ```c
void die() {
  printf("bye.\nYour rating was %s.\n", rate());
  post(' ');
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rate@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x20,%edi
  call   <post@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: bye.
Your rating was %s.


assistant: ```c
void die() {
  printf("bye.\nYour rating was %s.\n", rate());
  post(' ');
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_is_library>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jg     L35
  mov    $0x0,%eax
  jmp    L51
L35:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6f,%al
  jne    L18
  mov    $0x1,%eax
  jmp    L51
L18:
  mov    $0x0,%eax
L51:
  leave
  ret
```

assistant: ```c
int file_is_library(char *filename) {
  if (strlen(filename) < 4)
    return 0;
  if ((filename[strlen(filename) - 3] == '.') && (filename[strlen(filename) - 2] == 's') && (filename[strlen(filename) - 1] == 'o')) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<file_is_library>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x3,%edx
  jg     L23
L1:
  pop    %rbx
  ret
L23:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    $0x0,%eax
  cmpb   $0x2e,-0x3(%rbx,%rdx,1)
  jne    L1
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    $0x0,%eax
  cmpb   $0x73,-0x2(%rbx,%rdx,1)
  jne    L1
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x6f,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
  jmp    L1
```

assistant: ```c
int file_is_library(char *filename) {
  if (strlen(filename) < 4)
    return 0;
  if ((filename[strlen(filename) - 3] == '.') && (filename[strlen(filename) - 2] == 's') && (filename[strlen(filename) - 1] == 'o')) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_is_library>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x3,%eax
  jg     L25
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x3(%rbx,%rax,1)
  jne    L16
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x73,-0x2(%rbx,%rax,1)
  jne    L16
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x6f,-0x1(%rbx,%rax,1)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int file_is_library(char *filename) {
  if (strlen(filename) < 4)
    return 0;
  if ((filename[strlen(filename) - 3] == '.') && (filename[strlen(filename) - 2] == 's') && (filename[strlen(filename) - 1] == 'o')) {
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file_is_library>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x3,%eax
  jg     L27
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2e,-0x3(%rbx,%rax,1)
  jne    L0
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x73,-0x2(%rbx,%rax,1)
  jne    L0
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x6f,-0x1(%rbx,%rax,1)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int file_is_library(char *filename) {
  if (strlen(filename) < 4)
    return 0;
  if ((filename[strlen(filename) - 3] == '.') && (filename[strlen(filename) - 2] == 's') && (filename[strlen(filename) - 1] == 'o')) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fce1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L6
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int fce1(int a, int b) {
  int swap;
  if (a < b) {
    swap = a;
    a = b;
    b = swap;
  }
  return a / b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fce1>:
  endbr64
  mov    %edi,%eax
  cmp    %esi,%edi
  jge    L4
  mov    %esi,%eax
  mov    %edi,%esi
L4:
  cltd
  idiv   %esi
  ret
```

assistant: ```c
__attribute__((no)) int fce1(int a, int b) {
  int swap;
  if (a < b) {
    swap = a;
    a = b;
    b = swap;
  }
  return a / b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fce1>:
  endbr64
  mov    %edi,%eax
  cmp    %esi,%edi
  jge    L5
  mov    %esi,%eax
  mov    %edi,%esi
L5:
  cltd
  idiv   %esi
  ret
```

assistant: ```c
__attribute__((no)) int fce1(int a, int b) {
  int swap;
  if (a < b) {
    swap = a;
    a = b;
    b = swap;
  }
  return a / b;
}
```
user: What is the c source code of the assembly code below?

```asm
<fce1>:
  endbr64
  mov    %edi,%eax
  cmp    %esi,%edi
  jge    L1
  mov    %esi,%eax
  mov    %edi,%esi
L1:
  cltd
  idiv   %esi
  ret
```

assistant: ```c
__attribute__((no)) int fce1(int a, int b) {
  int swap;
  if (a < b) {
    swap = a;
    a = b;
    b = swap;
  }
  return a / b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  movl   $0x2,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 1;
#pragma omp parallel
#pragma omp single
  {
#pragma omp task shared(x) depend(in : x)
    if (x != 1)
      abort();
#pragma omp task shared(x) depend(out : x)
    x = 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x = 1;
#pragma omp parallel
#pragma omp single
  {
#pragma omp task shared(x) depend(in : x)
    if (x != 1)
      abort();
#pragma omp task shared(x) depend(out : x)
    x = 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 1;
#pragma omp parallel
#pragma omp single
  {
#pragma omp task shared(x) depend(in : x)
    if (x != 1)
      abort();
#pragma omp task shared(x) depend(out : x)
    x = 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 1;
#pragma omp parallel
#pragma omp single
  {
#pragma omp task shared(x) depend(in : x)
    if (x != 1)
      abort();
#pragma omp task shared(x) depend(out : x)
    x = 2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L22
L12:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0xf4240,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L31:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L9:
  cmpl   $0x2,-0x14(%rbp)
  jle    L31
  addl   $0x1,-0x18(%rbp)
L22:
  cmpl   $0x6,-0x18(%rbp)
  jle    L12
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string

tool: D12: dmaxabssorted

tool: D25: # c::%s:len=%d


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmaxabssorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r15d
  lea    D2(%rip),%r14
  lea    D3(%rip),%r13
  jmp    L13
L3:
  add    $0x1,%r15d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L28
L13:
  lea    -0x3(%r12),%ebx
  mov    %r15d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
L2:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    $0xf4240,%edi
  call   <benchmark@plt>
  mov    $0xf4240,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L2
  jmp    L3
L28:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D2: dmaxabssorted

tool: D3: # c::%s:len=%d


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmaxabssorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  mov    0xc(%rsp),%esi
  mov    $0xa,%edi
  lea    -0x3(%rbp),%r15d
  call   <pow@plt>
  mov    %eax,%ebx
L19:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0xf4240,%edi
  add    $0x1,%r15d
  call   <benchmark@plt>
  mov    $0xf4240,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebp,%r15d
  jne    L19
  addl   $0x1,0xc(%rsp)
  lea    0x3(%r15),%ebp
  cmp    $0x12,%r15d
  jne    L16
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D11: dmaxabssorted

tool: D7: # c::%s:len=%d


tool: D2: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmaxabssorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```