ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_field_string>:
  endbr64
  jmp    L153
  cs nopw 0x0(%rax,%rax,1)
L135:
  test   %al,%al
  je     L54
  add    $0x1,%rsi
L153:
  movzbl (%rsi),%eax
  cmp    $0x3d,%al
  je     L147
  cmp    $0xd,%al
  je     L11
  cmp    $0xa,%al
  jne    L135
L54:
  movzbl (%rsi),%edx
  cmp    $0x5b,%dl
  je     L15
  cmp    $0x20,%dl
  jne    L101
  nopl   0x0(%rax)
L15:
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  cmp    $0x20,%dl
  je     L15
  cmp    $0x5b,%dl
  je     L15
L101:
  cmp    $0xd,%dl
  ja     L55
  mov    $0xffffffffffffdbfe,%rax
  bt     %rdx,%rax
  jae    L24
L55:
  mov    $0x1,%eax
  mov    $0xffffffffffffdbfe,%r8
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L165:
  add    $0x1,%rax
  cmp    $0x100,%rax
  je     L70
L157:
  mov    %dl,-0x1(%rdi,%rax,1)
  movzbl (%rsi,%rax,1),%edx
  movslq %eax,%rcx
  cmp    $0xd,%dl
  ja     L165
  bt     %rdx,%r8
  jb     L165
  add    %rcx,%rdi
L24:
  movb   $0x0,(%rdi)
  ret
  nopl   0x0(%rax)
L11:
  cmp    $0x3d,%al
  jne    L54
L147:
  add    $0x1,%rsi
  jmp    L54
L70:
  add    $0xff,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void get_field_string(char *out, char *in) {
  int i = 0;
  while (in[0] != '=' && in[0] != 13 && in[0] != 10 && in[0] != 0)
    in++;
  if (in[0] == '=')
    in++;
  while (in[0] == ' ' || in[0] == '[')
    in++;
  while (in[0] != 13 && in[0] != 10 && in[0] != 0 && i < (0x100 - 1)) {
    out[i] = in[0];
    in++;
    i++;
  }
  out[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_field_string>:
  endbr64
  jmp    L96
  cs nopw 0x0(%rax,%rax,1)
L168:
  test   %al,%al
  je     L8
  add    $0x1,%rsi
L96:
  movzbl (%rsi),%eax
  cmp    $0x3d,%al
  je     L132
  cmp    $0xd,%al
  je     L149
  cmp    $0xa,%al
  jne    L168
L8:
  cmp    $0x5b,%al
  je     L78
  cmp    $0x20,%al
  jne    L103
  nop
L78:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  cmp    $0x20,%al
  je     L78
  cmp    $0x5b,%al
  je     L78
L103:
  cmp    $0xd,%al
  ja     L117
  mov    $0xffffffffffffdbfe,%rdx
  bt     %rax,%rdx
  jae    L124
L117:
  mov    $0x1,%edx
  mov    $0xffffffffffffdbfe,%r8
  jmp    L152
  nop
L101:
  add    $0x1,%rdx
  cmp    $0x100,%rdx
  je     L95
L152:
  mov    %al,-0x1(%rdi,%rdx,1)
  movzbl (%rsi,%rdx,1),%eax
  movslq %edx,%rcx
  cmp    $0xd,%al
  ja     L101
  bt     %rax,%r8
  jb     L101
  add    %rcx,%rdi
L124:
  movb   $0x0,(%rdi)
  ret
  nopl   0x0(%rax)
L149:
  cmp    $0x3d,%al
  jne    L8
L132:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  jmp    L8
L95:
  add    $0xff,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void get_field_string(char *out, char *in) {
  int i = 0;
  while (in[0] != '=' && in[0] != 13 && in[0] != 10 && in[0] != 0)
    in++;
  if (in[0] == '=')
    in++;
  while (in[0] == ' ' || in[0] == '[')
    in++;
  while (in[0] != 13 && in[0] != 10 && in[0] != 0 && i < (0x100 - 1)) {
    out[i] = in[0];
    in++;
    i++;
  }
  out[i] = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<comp_with_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L30
  mov    -0x24(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  je     L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  xor    %edx,%eax
  movzbl %al,%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  jne    L30
L13:
  mov    $0x1,%eax
  jmp    L39
L30:
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int comp_with_mask(void *addr, void *dest, unsigned int mask) {
  if (memcmp(addr, dest, mask / 8) == 0) {
    int n = mask / 8;
    int m = ~((1 << (8 - (mask % 8))) - 1);
    if (mask % 8 == 0 || (((unsigned char *)addr)[n] & m) == (((unsigned char *)dest)[n] & m))
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comp_with_mask>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %edx,%r13d
  shr    $0x3,%r13d
  mov    %r13d,%edx
  call   <memcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L0
  mov    $0x1,%eax
  and    $0x7,%ebx
  je     L0
  movslq %r13d,%r13
  movzbl (%r12,%r13,1),%eax
  xor    0x0(%rbp,%r13,1),%al
  movzbl %al,%eax
  mov    $0x8,%ecx
  sub    %ebx,%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  test   %edx,%eax
  sete   %al
  movzbl %al,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int comp_with_mask(void *addr, void *dest, unsigned int mask) {
  if (memcmp(addr, dest, mask / 8) == 0) {
    int n = mask / 8;
    int m = ~((1 << (8 - (mask % 8))) - 1);
    if (mask % 8 == 0 || (((unsigned char *)addr)[n] & m) == (((unsigned char *)dest)[n] & m))
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comp_with_mask>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  shr    $0x3,%r13d
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %r13d,%edx
  sub    $0x8,%rsp
  call   <memcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L4
  mov    $0x1,%eax
  and    $0x7,%ebx
  je     L4
  mov    $0x8,%ecx
  movzbl (%r12,%r13,1),%edx
  xor    0x0(%rbp,%r13,1),%dl
  sub    %ebx,%ecx
  movzbl %dl,%edx
  shl    %cl,%eax
  neg    %eax
  test   %eax,%edx
  sete   %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int comp_with_mask(void *addr, void *dest, unsigned int mask) {
  if (memcmp(addr, dest, mask / 8) == 0) {
    int n = mask / 8;
    int m = ~((1 << (8 - (mask % 8))) - 1);
    if (mask % 8 == 0 || (((unsigned char *)addr)[n] & m) == (((unsigned char *)dest)[n] & m))
      return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comp_with_mask>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  shr    $0x3,%r13d
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %r13d,%edx
  sub    $0x8,%rsp
  call   <memcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L16
  mov    $0x1,%eax
  and    $0x7,%ebx
  je     L16
  mov    $0x8,%ecx
  movzbl (%r12,%r13,1),%edx
  xor    0x0(%rbp,%r13,1),%dl
  sub    %ebx,%ecx
  movzbl %dl,%edx
  shl    %cl,%eax
  neg    %eax
  test   %eax,%edx
  sete   %al
  movzbl %al,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int comp_with_mask(void *addr, void *dest, unsigned int mask) {
  if (memcmp(addr, dest, mask / 8) == 0) {
    int n = mask / 8;
    int m = ~((1 << (8 - (mask % 8))) - 1);
    if (mask % 8 == 0 || (((unsigned char *)addr)[n] & m) == (((unsigned char *)dest)[n] & m))
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gtm_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L10
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L2
L10:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gtm_recv(int socket, void *buffer, size_t length, int flags) {
  int res;
  do {
    res = recv(socket, buffer, length, flags);
  } while (-1 == res && EINTR == errno);
  return (res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gtm_recv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%ebx
L5:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    D11(%rip),%rcx
  mov    D3(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L5
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int gtm_recv(int socket, void *buffer, size_t length, int flags) {
  int res;
  do {
    res = recv(socket, buffer, length, flags);
  } while (-1 == res && EINTR == errno);
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gtm_recv>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L8:
  mov    D12(%rip),%rdx
  mov    D8(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L27
L13:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0xffffffff,%eax
  je     L8
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int gtm_recv(int socket, void *buffer, size_t length, int flags) {
  int res;
  do {
    res = recv(socket, buffer, length, flags);
  } while (-1 == res && EINTR == errno);
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gtm_recv>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L15:
  mov    D0(%rip),%rdx
  mov    D5(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L10
L6:
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <recv@plt>
  cmp    $0xffffffff,%eax
  je     L15
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int gtm_recv(int socket, void *buffer, size_t length, int flags) {
  int res;
  do {
    res = recv(socket, buffer, length, flags);
  } while (-1 == res && EINTR == errno);
  return (res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_hw_config>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  jmp    L19
L2:
  lea    D19(%rip),%rax
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D2: HW_CONFIG

tool: D19: etc/hardware.ini

assistant: ```c
char *get_hw_config() {
  char *hw_config;
  hw_config = getenv("HW_CONFIG");
  return hw_config ? hw_config : "etc/hardware.ini";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_hw_config>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  lea    D0(%rip),%rdx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D12: HW_CONFIG

tool: D0: etc/hardware.ini

assistant: ```c
char *get_hw_config() {
  char *hw_config;
  hw_config = getenv("HW_CONFIG");
  return hw_config ? hw_config : "etc/hardware.ini";
}
```
user: What is the c source code of the assembly code below?

```asm
<get_hw_config>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <getenv@plt>
  lea    D7(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D7
type: string

tool: D15: HW_CONFIG

tool: D7: etc/hardware.ini

assistant: ```c
char *get_hw_config() {
  char *hw_config;
  hw_config = getenv("HW_CONFIG");
  return hw_config ? hw_config : "etc/hardware.ini";
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_hw_config>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  lea    D9(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D1: HW_CONFIG

tool: D9: etc/hardware.ini

assistant: ```c
char *get_hw_config() {
  char *hw_config;
  hw_config = getenv("HW_CONFIG");
  return hw_config ? hw_config : "etc/hardware.ini";
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: Testing...
..1
...2
....3


assistant: ```c
int main(void) {
  printf("Testing...\n..1\n...2\n....3\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: Testing...
..1
...2
....3


assistant: ```c
int main(void) {
  printf("Testing...\n..1\n...2\n....3\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: Testing...
..1
...2
....3


assistant: ```c
int main(void) {
  printf("Testing...\n..1\n...2\n....3\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Testing...
..1
...2
....3


assistant: ```c
int main(void) {
  printf("Testing...\n..1\n...2\n....3\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iglsadff1t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L25
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0xc(%rbp)
L25:
  cmpl   $0x0,-0xc(%rbp)
  jg     L12
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L38:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double iglsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  double y;
  y = x + g * d[0];
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = c[i + 1];
  return (y);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iglsadff1t>:
  endbr64
  movapd %xmm0,%xmm3
  mov    %rdi,%rcx
  mulsd  (%rdx),%xmm1
  addsd  %xmm0,%xmm1
  movslq %esi,%rax
  mulsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L5
  cltq
L34:
  movapd %xmm3,%xmm2
  mulsd  (%rcx,%rax,8),%xmm2
  addsd  (%rdx,%rax,8),%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L34
L5:
  test   %esi,%esi
  jle    L12
  lea    0x1(%rsi),%esi
  mov    $0x1,%eax
L6:
  movsd  (%rcx,%rax,8),%xmm2
  movsd  %xmm2,-0x8(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L6
L12:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double iglsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  double y;
  y = x + g * d[0];
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = c[i + 1];
  return (y);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<iglsadff1t>:
  endbr64
  mulsd  (%rdx),%xmm1
  movslq %esi,%rax
  movapd %xmm0,%xmm3
  mov    %rdi,%rcx
  addsd  %xmm0,%xmm1
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L25
  cltq
  nopl   (%rax)
L4:
  movsd  (%rcx,%rax,8),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  (%rdx,%rax,8),%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L4
L25:
  test   %esi,%esi
  jle    L31
  add    $0x1,%esi
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%rcx,%rax,8),%xmm2
  movsd  %xmm2,-0x8(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L18
L31:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double iglsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  double y;
  y = x + g * d[0];
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = c[i + 1];
  return (y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<iglsadff1t>:
  endbr64
  mulsd  (%rdx),%xmm1
  movslq %esi,%rax
  movapd %xmm0,%xmm3
  mov    %rdi,%rcx
  lea    -0x1(%rax),%r9d
  mov    %rax,%r8
  lea    0x0(,%rax,8),%rdi
  addsd  %xmm0,%xmm1
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  test   %r9d,%r9d
  jle    L50
  lea    -0x10(%rdi),%rsi
  lea    -0x8(%rdx,%rdi,1),%rax
  lea    (%rcx,%rsi,1),%r10
  cmp    %rax,%r10
  je     L108
  cmp    $0x2,%r8d
  je     L108
  mov    %r9d,%edi
  movapd %xmm3,%xmm0
  add    %rdx,%rsi
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm0,%xmm0
  neg    %rdi
  shl    $0x4,%rdi
  nopl   (%rax)
L27:
  movupd (%r10,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm4
  shufpd $0x1,%xmm2,%xmm2
  mulpd  %xmm0,%xmm2
  shufpd $0x1,%xmm4,%xmm4
  addpd  %xmm4,%xmm2
  shufpd $0x1,%xmm2,%xmm2
  movups %xmm2,(%rsi,%rax,1)
  sub    $0x10,%rax
  cmp    %rax,%rdi
  jne    L27
  mov    %r9d,%eax
  and    $0x1,%eax
  test   $0x1,%r9b
  je     L50
  cltq
  mulsd  (%rcx,%rax,8),%xmm3
  lea    (%rdx,%rax,8),%rsi
  addsd  (%rsi),%xmm3
  movsd  %xmm3,(%rsi)
L50:
  test   %r8d,%r8d
  jle    L60
  lea    0x10(%rcx),%rax
  cmp    %rax,%rdx
  je     L125
  cmp    $0x2,%r9d
  jbe    L125
  mov    %r8d,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopl   (%rax)
L41:
  movupd 0x8(%rcx,%rax,1),%xmm7
  movups %xmm7,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L41
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L60
  add    $0x1,%eax
  movsd  (%rcx,%rax,8),%xmm2
  movsd  %xmm2,-0x8(%rdx,%rax,8)
L60:
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L108:
  movslq %r9d,%rax
  nopl   0x0(%rax,%rax,1)
L109:
  movsd  (%rcx,%rax,8),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  (%rdx,%rax,8),%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L109
  jmp    L50
  nopl   (%rax)
L125:
  lea    0x1(%r8),%esi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L32:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,-0x8(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L32
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double iglsadff1t(double x, double *c, const int m, const double g, double *d) {
  int i;
  double y;
  y = x + g * d[0];
  d[m] = c[m] * x;
  for (i = m - 1; i >= 1; i--)
    d[i] += c[i] * x;
  for (i = 0; i < m; i++)
    d[i] = c[i + 1];
  return (y);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_to_le32_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L3
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__cpu_to_le32s@plt>
  addq   $0x4,-0x8(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void cpu_to_le32_array(unsigned int *buf, unsigned int words) {
  while (words--) {
    __cpu_to_le32s(buf);
    buf++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpu_to_le32_array>:
  endbr64
  test   %esi,%esi
  je     L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  mov    %eax,%eax
  lea    0x4(%rdi,%rax,4),%rbp
L8:
  mov    %rbx,%rdi
  call   <__cpu_to_le32s@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
void cpu_to_le32_array(unsigned int *buf, unsigned int words) {
  while (words--) {
    __cpu_to_le32s(buf);
    buf++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cpu_to_le32_array>:
  endbr64
  test   %esi,%esi
  je     L18
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <__cpu_to_le32s@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void cpu_to_le32_array(unsigned int *buf, unsigned int words) {
  while (words--) {
    __cpu_to_le32s(buf);
    buf++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_to_le32_array>:
  endbr64
  test   %esi,%esi
  je     L4
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <__cpu_to_le32s@plt>
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void cpu_to_le32_array(unsigned int *buf, unsigned int words) {
  while (words--) {
    __cpu_to_le32s(buf);
    buf++;
  }
}
```