ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L18
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s++)
    n++;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L0
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s++)
    n++;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_push>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x123456789abcdef,%rbp
  mov    %rbp,(%rsp)
  movabs $0x5555555555555555,%rax
  mov    %rax,(%rdi)
  lea    0x1000(%rdi),%rdx
  mov    %rax,0xff8(%rdi)
  lea    0x8(%rdi),%rdi
  and    $0xfffffffffffffff8,%rdi
  mov    %rbx,%rcx
  sub    %rdi,%rcx
  add    $0x1000,%ecx
  shr    $0x3,%ecx
  mov    %ecx,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rcx
  mov    $0xffffffffffffffef,%rax
  mov    %rsp,%rsi
  mov    %rdx,%rsp
  push   $0xfffffffffffffff9
  push   %rax
  push   (%rcx)
  push   $0xffffffffff941c0d
  mov    %rsp,%rdx
  mov    %rsi,%rsp
  cmpq   $0xfffffffffffffff9,0xff8(%rbx)
  sete   %sil
  movzbl %sil,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <report@plt>
  cmpq   $0xffffffffffffffef,0xff0(%rbx)
  sete   %sil
  movzbl %sil,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <report@plt>
  cmp    %rbp,0xfe8(%rbx)
  sete   %sil
  movzbl %sil,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <report@plt>
  cmpq   $0xffffffffff941c0d,0xfe0(%rbx)
  sete   %sil
  movzbl %sil,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <report@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D22: push $imm8

tool: D36: push %reg

tool: D38: push mem

tool: D19: push $imm

assistant: ```c
void test_push(void *mem) {
  unsigned long tmp;
  unsigned long *stack_top = mem + 4096;
  unsigned long *new_stack_top;
  unsigned long memw = 0x123456789abcdeful;
  __builtin_memset(mem, 0x55, (void *)stack_top - mem);
  asm volatile("mov %%rsp, %[tmp] \n\t"
               "mov %[stack_top], %%rsp \n\t"
               "pushq $-7 \n\t"
               "pushq %[reg] \n\t"
               "pushq (%[mem]) \n\t"
               "pushq $-7070707 \n\t"
               "mov %%rsp, %[new_stack_top] \n\t"
               "mov %[tmp], %%rsp"
               : [tmp] "=&r"(tmp), [new_stack_top] "=r"(new_stack_top)
               : [stack_top] "r"(stack_top), [reg] "r"(-17l), [mem] "r"(&memw)
               : "memory");
  report("push $imm8", stack_top[-1] == -7ul);
  report("push %reg", stack_top[-2] == -17ul);
  report("push mem", stack_top[-3] == 0x123456789abcdeful);
  report("push $imm", stack_top[-4] == -7070707);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_push>:
  endbr64
  push   %rbp
  lea    0x1000(%rdi),%rdx
  movabs $0x123456789abcdef,%rbp
  push   %rbx
  mov    %rdi,%rbx
  add    $0x8,%rdi
  mov    %rbx,%rcx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rbp,(%rsp)
  movabs $0x5555555555555555,%rax
  mov    %rax,-0x8(%rdi)
  mov    %rax,0xff0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1000,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rcx
  mov    $0xffffffffffffffef,%rax
  mov    %rsp,%rsi
  mov    %rdx,%rsp
  push   $0xfffffffffffffff9
  push   %rax
  push   (%rcx)
  push   $0xffffffffff941c0d
  mov    %rsp,%rdx
  mov    %rsi,%rsp
  xor    %esi,%esi
  cmpq   $0xfffffffffffffff9,0xff8(%rbx)
  lea    D36(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  cmpq   $0xffffffffffffffef,0xff0(%rbx)
  lea    D16(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  cmp    %rbp,0xfe8(%rbx)
  lea    D6(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  lea    D37(%rip),%rdi
  cmpq   $0xffffffffff941c0d,0xfe0(%rbx)
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D36
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D37
datatype: string

tool: D36: push $imm8

tool: D16: push %reg

tool: D6: push mem

tool: D37: push $imm

assistant: ```c
void test_push(void *mem) {
  unsigned long tmp;
  unsigned long *stack_top = mem + 4096;
  unsigned long *new_stack_top;
  unsigned long memw = 0x123456789abcdeful;
  __builtin_memset(mem, 0x55, (void *)stack_top - mem);
  asm volatile("mov %%rsp, %[tmp] \n\t"
               "mov %[stack_top], %%rsp \n\t"
               "pushq $-7 \n\t"
               "pushq %[reg] \n\t"
               "pushq (%[mem]) \n\t"
               "pushq $-7070707 \n\t"
               "mov %%rsp, %[new_stack_top] \n\t"
               "mov %[tmp], %%rsp"
               : [tmp] "=&r"(tmp), [new_stack_top] "=r"(new_stack_top)
               : [stack_top] "r"(stack_top), [reg] "r"(-17l), [mem] "r"(&memw)
               : "memory");
  report("push $imm8", stack_top[-1] == -7ul);
  report("push %reg", stack_top[-2] == -17ul);
  report("push mem", stack_top[-3] == 0x123456789abcdeful);
  report("push $imm", stack_top[-4] == -7070707);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_push>:
  endbr64
  push   %rbp
  lea    0x1000(%rdi),%rdx
  movabs $0x123456789abcdef,%rbp
  push   %rbx
  mov    %rdi,%rbx
  add    $0x8,%rdi
  mov    %rbx,%rcx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rbp,(%rsp)
  movabs $0x5555555555555555,%rax
  mov    %rax,-0x8(%rdi)
  mov    %rax,0xff0(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    $0x1000,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rcx
  mov    $0xffffffffffffffef,%rax
  mov    %rsp,%rsi
  mov    %rdx,%rsp
  push   $0xfffffffffffffff9
  push   %rax
  push   (%rcx)
  push   $0xffffffffff941c0d
  mov    %rsp,%rdx
  mov    %rsi,%rsp
  xor    %esi,%esi
  cmpq   $0xfffffffffffffff9,0xff8(%rbx)
  lea    D10(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  cmpq   $0xffffffffffffffef,0xff0(%rbx)
  lea    D22(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  cmp    %rbp,0xfe8(%rbx)
  lea    D2(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  cmpq   $0xffffffffff941c0d,0xfe0(%rbx)
  sete   %sil
  xor    %eax,%eax
  call   <report@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D10: push $imm8

tool: D22: push %reg

tool: D2: push mem

tool: D4: push $imm

assistant: ```c
void test_push(void *mem) {
  unsigned long tmp;
  unsigned long *stack_top = mem + 4096;
  unsigned long *new_stack_top;
  unsigned long memw = 0x123456789abcdeful;
  __builtin_memset(mem, 0x55, (void *)stack_top - mem);
  asm volatile("mov %%rsp, %[tmp] \n\t"
               "mov %[stack_top], %%rsp \n\t"
               "pushq $-7 \n\t"
               "pushq %[reg] \n\t"
               "pushq (%[mem]) \n\t"
               "pushq $-7070707 \n\t"
               "mov %%rsp, %[new_stack_top] \n\t"
               "mov %[tmp], %%rsp"
               : [tmp] "=&r"(tmp), [new_stack_top] "=r"(new_stack_top)
               : [stack_top] "r"(stack_top), [reg] "r"(-17l), [mem] "r"(&memw)
               : "memory");
  report("push $imm8", stack_top[-1] == -7ul);
  report("push %reg", stack_top[-2] == -17ul);
  report("push mem", stack_top[-3] == 0x123456789abcdeful);
  report("push $imm", stack_top[-4] == -7070707);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_find_next_zero_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  and    $0x3f,%eax
  test   %rax,%rax
  je     L28
  mov    -0x20(%rbp),%eax
  cltq
  shr    $0x6,%rax
  add    $0x1,%rax
  shl    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L43
L37:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <bitmap_test_bit@plt>
  test   %eax,%eax
  jne    L38
  mov    -0x20(%rbp),%eax
  jmp    L24
L38:
  addl   $0x1,-0x20(%rbp)
L43:
  mov    -0x20(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L37
L28:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L62
  mov    -0x1c(%rbp),%eax
  jmp    L24
L62:
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x6,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <bitmap_find_first_zero_bit@plt>
  mov    -0x20(%rbp),%edx
  add    %edx,%eax
L24:
  leave
  ret
```

assistant: ```c
int bitmap_find_next_zero_bit(const unsigned long *maskp, int nmaskbits, int offset) {
  int n;
  if (offset % (8 * sizeof(long)) != 0) {
    n = (((offset) / (8 * sizeof(long))) + 1) * (8 * sizeof(long));
    n = ((n) < (nmaskbits) ? (n) : (nmaskbits));
    while (offset < n) {
      if (!bitmap_test_bit(offset, maskp))
        return offset;
      offset++;
    }
  }
  if (offset >= nmaskbits)
    return nmaskbits;
  return offset + bitmap_find_first_zero_bit(maskp + ((offset) / (8 * sizeof(long))), nmaskbits - offset);
}
```
user: What is the c source code of the assembly code below:

```asm
<bitmap_find_next_zero_bit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  test   $0x3f,%dl
  je     L23
  movslq %edx,%rbp
  shr    $0x6,%rbp
  add    $0x1,%rbp
  shl    $0x6,%ebp
  cmp    %esi,%ebp
  cmovg  %esi,%ebp
  cmp    %ebp,%edx
  jge    L23
L1:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bitmap_test_bit@plt>
  test   %eax,%eax
  je     L69
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L1
  mov    %ebp,%ebx
L23:
  mov    %r13d,%eax
  cmp    %r13d,%ebx
  jl     L38
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %r13d,%esi
  sub    %ebx,%esi
  movslq %ebx,%rax
  shr    $0x6,%rax
  lea    (%r12,%rax,8),%rdi
  call   <bitmap_find_first_zero_bit@plt>
  add    %ebx,%eax
  jmp    L67
L69:
  mov    %ebx,%eax
  jmp    L67
```

assistant: ```c
int bitmap_find_next_zero_bit(const unsigned long *maskp, int nmaskbits, int offset) {
  int n;
  if (offset % (8 * sizeof(long)) != 0) {
    n = (((offset) / (8 * sizeof(long))) + 1) * (8 * sizeof(long));
    n = ((n) < (nmaskbits) ? (n) : (nmaskbits));
    while (offset < n) {
      if (!bitmap_test_bit(offset, maskp))
        return offset;
      offset++;
    }
  }
  if (offset >= nmaskbits)
    return nmaskbits;
  return offset + bitmap_find_first_zero_bit(maskp + ((offset) / (8 * sizeof(long))), nmaskbits - offset);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitmap_find_next_zero_bit>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  and    $0x3f,%edx
  je     L34
  mov    %ebx,%eax
  and    $0xffffffc0,%eax
  lea    0x40(%rax),%r13d
  cmp    %esi,%r13d
  cmovg  %esi,%r13d
  cmp    %r13d,%ebx
  jl     L38
  nop
L34:
  mov    %ebp,%eax
  cmp    %ebp,%ebx
  jl     L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L34
L38:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bitmap_test_bit@plt>
  test   %eax,%eax
  jne    L4
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  sub    %ebx,%eax
  mov    %eax,%esi
  movslq %ebx,%rax
  shr    $0x6,%rax
  lea    (%r12,%rax,8),%rdi
  call   <bitmap_find_first_zero_bit@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bitmap_find_next_zero_bit(const unsigned long *maskp, int nmaskbits, int offset) {
  int n;
  if (offset % (8 * sizeof(long)) != 0) {
    n = (((offset) / (8 * sizeof(long))) + 1) * (8 * sizeof(long));
    n = ((n) < (nmaskbits) ? (n) : (nmaskbits));
    while (offset < n) {
      if (!bitmap_test_bit(offset, maskp))
        return offset;
      offset++;
    }
  }
  if (offset >= nmaskbits)
    return nmaskbits;
  return offset + bitmap_find_first_zero_bit(maskp + ((offset) / (8 * sizeof(long))), nmaskbits - offset);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_find_next_zero_bit>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  and    $0x3f,%edx
  je     L22
  mov    %ebx,%eax
  and    $0xffffffc0,%eax
  lea    0x40(%rax),%r13d
  cmp    %esi,%r13d
  cmovg  %esi,%r13d
  cmp    %r13d,%ebx
  jl     L39
  nop
L22:
  mov    %ebp,%eax
  cmp    %ebp,%ebx
  jl     L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L22
L39:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bitmap_test_bit@plt>
  test   %eax,%eax
  jne    L1
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  sub    %ebx,%eax
  mov    %eax,%esi
  movslq %ebx,%rax
  shr    $0x6,%rax
  lea    (%r12,%rax,8),%rdi
  call   <bitmap_find_first_zero_bit@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bitmap_find_next_zero_bit(const unsigned long *maskp, int nmaskbits, int offset) {
  int n;
  if (offset % (8 * sizeof(long)) != 0) {
    n = (((offset) / (8 * sizeof(long))) + 1) * (8 * sizeof(long));
    n = ((n) < (nmaskbits) ? (n) : (nmaskbits));
    while (offset < n) {
      if (!bitmap_test_bit(offset, maskp))
        return offset;
      offset++;
    }
  }
  if (offset >= nmaskbits)
    return nmaskbits;
  return offset + bitmap_find_first_zero_bit(maskp + ((offset) / (8 * sizeof(long))), nmaskbits - offset);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mul_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L50
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L59
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%esi
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  imul   %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  add    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L3
  addl   $0x1,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L24
  addl   $0x1,-0xc(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int mul_matrix(int pr[][100], int m1[][100], int m2[][100], int m, int n, int q) {
  int i, j, k;
  for (i = 0; i < m; i++)
    for (j = 0; j < q; j++) {
      pr[i][j] = 0;
      for (k = 0; k < n; k++)
        pr[i][j] += m1[i][k] * m2[k][j];
    }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mul_matrix>:
  endbr64
  test   %ecx,%ecx
  jle    L20
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  mov    %ecx,%edx
  mov    %r8d,%ebx
  mov    %r9d,%r13d
  lea    -0x1(%r9),%eax
  lea    0x4(%rdi,%rax,4),%r10
  mov    %rsi,%r11
  lea    -0x1(%r8),%ecx
  lea    0x4(%rsi,%rcx,4),%rdi
  lea    -0x1(%rdx),%edx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  lea    0x190(%rsi,%rdx,1),%r14
  not    %rax
  lea    0x0(,%rax,4),%r12
  jmp    L47
L65:
  mov    %r8,%rsi
  movl   $0x0,(%r8)
  test   %ebx,%ebx
  jle    L78
  mov    %r9,%rcx
  mov    %r11,%rax
L58:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    %edx,(%rsi)
  add    $0x4,%rax
  add    $0x190,%rcx
  cmp    %rdi,%rax
  jne    L58
L78:
  add    $0x4,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  jne    L65
L12:
  add    $0x190,%r10
  add    $0x190,%r11
  add    $0x190,%rdi
  cmp    %r14,%r11
  je     L0
L47:
  lea    (%r12,%r10,1),%r8
  mov    %rbp,%r9
  test   %r13d,%r13d
  jg     L65
  jmp    L12
L0:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int mul_matrix(int pr[][100], int m1[][100], int m2[][100], int m, int n, int q) {
  int i, j, k;
  for (i = 0; i < m; i++)
    for (j = 0; j < q; j++) {
      pr[i][j] = 0;
      for (k = 0; k < n; k++)
        pr[i][j] += m1[i][k] * m2[k][j];
    }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mul_matrix>:
  endbr64
  test   %ecx,%ecx
  jle    L21
  push   %r14
  lea    -0x1(%r9),%eax
  mov    %rsi,%r10
  push   %r13
  shl    $0x2,%rax
  mov    $0xfffffffffffffffc,%r13
  push   %r12
  lea    0x4(%rdi,%rax,1),%r11
  mov    %r9d,%r12d
  sub    %rax,%r13
  push   %rbp
  mov    %rdx,%rbp
  mov    %ecx,%edx
  lea    -0x1(%r8),%ecx
  sub    $0x1,%edx
  push   %rbx
  mov    %r8d,%ebx
  lea    0x4(%rsi,%rcx,4),%r8
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  lea    0x190(%rsi,%rdx,1),%r14
  nopl   0x0(%rax)
L46:
  lea    0x0(%r13,%r11,1),%rdi
  mov    %rbp,%r9
  test   %r12d,%r12d
  jle    L53
  nopl   (%rax)
L5:
  movl   $0x0,(%rdi)
  mov    %r9,%rsi
  mov    %r10,%rax
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jle    L54
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rax),%edx
  imul   (%rsi),%edx
  add    $0x4,%rax
  add    $0x190,%rsi
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r8,%rax
  jne    L30
L54:
  add    $0x4,%rdi
  add    $0x4,%r9
  cmp    %r11,%rdi
  jne    L5
L53:
  add    $0x190,%r10
  add    $0x190,%r11
  add    $0x190,%r8
  cmp    %r14,%r10
  jne    L46
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mul_matrix(int pr[][100], int m1[][100], int m2[][100], int m, int n, int q) {
  int i, j, k;
  for (i = 0; i < m; i++)
    for (j = 0; j < q; j++) {
      pr[i][j] = 0;
      for (k = 0; k < n; k++)
        pr[i][j] += m1[i][k] * m2[k][j];
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mul_matrix>:
  endbr64
  test   %ecx,%ecx
  jle    L49
  mov    %r9d,%eax
  test   %r9d,%r9d
  jle    L49
  push   %r13
  sub    $0x1,%eax
  mov    %rsi,%r10
  push   %r12
  shl    $0x2,%rax
  mov    $0xfffffffffffffffc,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    %ecx,%edx
  lea    -0x1(%r8),%ecx
  sub    $0x1,%edx
  push   %rbx
  lea    0x4(%rdi,%rax,1),%r11
  mov    %r8d,%ebx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x4(%rsi,%rcx,4),%r8
  sub    %rax,%r12
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  lea    0x190(%rsi,%rdx,1),%r13
  nop
L34:
  lea    (%r12,%r11,1),%rdi
  mov    %rbp,%r9
  nopw   0x0(%rax,%rax,1)
L36:
  movl   $0x0,(%rdi)
  mov    %r9,%rsi
  mov    %r10,%rax
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jle    L17
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rax),%edx
  imul   (%rsi),%edx
  add    $0x4,%rax
  add    $0x190,%rsi
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r8,%rax
  jne    L26
L17:
  add    $0x4,%rdi
  add    $0x4,%r9
  cmp    %r11,%rdi
  jne    L36
  add    $0x190,%r10
  add    $0x190,%r11
  add    $0x190,%r8
  cmp    %r13,%r10
  jne    L34
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mul_matrix(int pr[][100], int m1[][100], int m2[][100], int m, int n, int q) {
  int i, j, k;
  for (i = 0; i < m; i++)
    for (j = 0; j < q; j++) {
      pr[i][j] = 0;
      for (k = 0; k < n; k++)
        pr[i][j] += m1[i][k] * m2[k][j];
    }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bmp_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L10:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L10
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: %02X

assistant: ```c
void bmp_print(uint8_t *buf, size_t buflen) {
  size_t i;
  for (i = 0; i < buflen; i++) {
    printf("%02X", buf[i]);
  }
  printf("\n");
}
```