ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D23(%rip),%rbp
L12:
  mov    %ebx,%r13d
L31:
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jle    L33
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L31
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  jmp    L12
L33:
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  cmp    $0xffffffff,%eax
  jl     L83
  movslq %r13d,%rdx
  lea    0x10(%rsp,%rdx,4),%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
  jmp    L4
L83:
  mov    0x8(%rsp),%edx
  cmp    $0x1,%edx
  jle    L8
  movslq %r13d,%r13
  lea    0x10(%rsp,%r13,4),%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L109:
  test   $0x1,%dl
  jne    L8
  mov    0x10(%rsp,%rbx,4),%esi
  sub    -0x4(%rbp),%esi
  mov    %esi,0xc(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%edx
  add    $0x1,%rbx
  sub    $0x4,%rbp
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jg     L109
L8:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L128
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L101:
  movslq %ecx,%rcx
  mov    0x10(%rsp,%rcx,4),%esi
L7:
  mov    %esi,0xc(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%ecx
  add    $0x1,%rbx
  sub    $0x4,%rbp
  cmp    %ebx,%edx
  jl     L83
L4:
  test   $0x1,%al
  je     L83
  cmp    %ebx,%ecx
  je     L101
  mov    0x10(%rsp,%rbx,4),%esi
  sub    -0x4(%rbp),%esi
  jmp    L7
L128:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D23: %d

tool: D5: %d


assistant: ```c
int main() {
  int n, i, last, previ, a, odds[100];
  scanf("%d", &n);
  for (i = 0; i < n;) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      odds[i] = a;
      i += 1;
    }
  }
  i--;
  previ = i;
  for (last = previ, i = 0; i <= n / 2; i++) {
    if (n % 2 != 0) {
      if (i == n / 2)
        a = odds[n / 2];
      else
        a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
  for (last = previ, i = 0; i < n / 2; i++) {
    if (n % 2 == 0) {
      a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
L124:
  movslq %ebx,%rbp
  jmp    L79
  cs nopw 0x0(%rax,%rax,1)
L141:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  jne    L17
L79:
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L141
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    $0xffffffff,%eax
  jl     L1
  lea    0x10(%rsp),%rbx
  movslq %ebp,%rcx
  xor    %r13d,%r13d
  lea    (%rbx,%rcx,4),%r14
  lea    D5(%rip),%r12
  jmp    L20
  nopl   (%rax)
L107:
  mov    (%rbx,%r13,4),%esi
  sub    -0x4(%r14),%esi
L138:
  mov    %r12,%rdi
  mov    %esi,0xc(%rsp)
  add    $0x1,%r13
  sub    $0x4,%r14
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r13d,%edx
  jl     L1
L20:
  test   $0x1,%al
  je     L1
  cmp    %r13d,%edx
  jne    L107
  movslq %edx,%rdx
  mov    0x10(%rsp,%rdx,4),%esi
  jmp    L138
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x1,%eax
  jle    L60
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  lea    (%rbx,%rbp,4),%r13
  lea    D5(%rip),%rbp
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L109:
  mov    (%rbx,%r12,4),%esi
  mov    %rbp,%rdi
  sub    -0x4(%r13),%esi
  add    $0x1,%r12
  mov    %esi,0xc(%rsp)
  sub    $0x4,%r13
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r12d,%edx
  jle    L60
L134:
  test   $0x1,%al
  je     L109
L60:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  jmp    L124
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D10: %d

tool: D5: %d


assistant: ```c
int main() {
  int n, i, last, previ, a, odds[100];
  scanf("%d", &n);
  for (i = 0; i < n;) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      odds[i] = a;
      i += 1;
    }
  }
  i--;
  previ = i;
  for (last = previ, i = 0; i <= n / 2; i++) {
    if (n % 2 != 0) {
      if (i == n / 2)
        a = odds[n / 2];
      else
        a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
  for (last = previ, i = 0; i < n / 2; i++) {
    if (n % 2 == 0) {
      a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
L133:
  movslq %ebx,%rbp
  jmp    L73
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  jne    L100
L73:
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L117
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    $0xffffffff,%eax
  jl     L25
  lea    0x10(%rsp),%rbx
  movslq %ebp,%rcx
  xor    %r13d,%r13d
  lea    (%rbx,%rcx,4),%r14
  lea    D24(%rip),%r12
  jmp    L51
  nopl   (%rax)
L64:
  mov    (%rbx,%r13,4),%esi
  sub    -0x4(%r14),%esi
L8:
  mov    %r12,%rdi
  mov    %esi,0xc(%rsp)
  add    $0x1,%r13
  sub    $0x4,%r14
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r13d,%edx
  jl     L25
L51:
  test   $0x1,%al
  je     L25
  cmp    %r13d,%edx
  jne    L64
  movslq %edx,%rdx
  mov    0x10(%rsp,%rdx,4),%esi
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    $0x1,%eax
  jle    L33
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  lea    (%rbx,%rbp,4),%r13
  lea    D24(%rip),%rbp
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L66:
  mov    (%rbx,%r12,4),%esi
  mov    %rbp,%rdi
  sub    -0x4(%r13),%esi
  add    $0x1,%r12
  mov    %esi,0xc(%rsp)
  sub    $0x4,%r13
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r12d,%edx
  jle    L33
L110:
  test   $0x1,%al
  je     L66
L33:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L100:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  jmp    L133
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: D14: %d

tool: D24: %d


assistant: ```c
int main() {
  int n, i, last, previ, a, odds[100];
  scanf("%d", &n);
  for (i = 0; i < n;) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      odds[i] = a;
      i += 1;
    }
  }
  i--;
  previ = i;
  for (last = previ, i = 0; i <= n / 2; i++) {
    if (n % 2 != 0) {
      if (i == n / 2)
        a = odds[n / 2];
      else
        a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
  for (last = previ, i = 0; i < n / 2; i++) {
    if (n % 2 == 0) {
      a = odds[i] - odds[last];
      last--;
    } else
      break;
    printf("%d\n", a);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_els>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  nop
L12:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L12
L16:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_els(void **tab) {
  char **tmp;
  int i;
  i = -1;
  if ((tmp = (char **)tab) != NULL)
    while (tmp[++i] != NULL)
      ;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_els>:
  endbr64
  test   %rdi,%rdi
  je     L3
  mov    $0x0,%eax
L28:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L28
L10:
  mov    %edx,%eax
  ret
L3:
  mov    $0xffffffff,%edx
  jmp    L10
```

assistant: ```c
int count_els(void **tab) {
  char **tmp;
  int i;
  i = -1;
  if ((tmp = (char **)tab) != NULL)
    while (tmp[++i] != NULL)
      ;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_els>:
  endbr64
  test   %rdi,%rdi
  je     L10
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L7
L18:
  mov    %r8d,%eax
  ret
L10:
  mov    $0xffffffff,%r8d
  jmp    L18
```

assistant: ```c
int count_els(void **tab) {
  char **tmp;
  int i;
  i = -1;
  if ((tmp = (char **)tab) != NULL)
    while (tmp[++i] != NULL)
      ;
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<count_els>:
  endbr64
  test   %rdi,%rdi
  je     L3
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L13
L27:
  mov    %r8d,%eax
  ret
L3:
  mov    $0xffffffff,%r8d
  jmp    L27
```

assistant: ```c
int count_els(void **tab) {
  char **tmp;
  int i;
  i = -1;
  if ((tmp = (char **)tab) != NULL)
    while (tmp[++i] != NULL)
      ;
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x4,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 3;
  int c = 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 3;
  int c = 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 3;
  int c = 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 3;
  int c = 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L20
L23:
  movsbl -0x11(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L32:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0xa,-0x11(%rbp)
  jne    L23
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L32
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D20
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string

tool: D21:  is not an integer.


tool: D20: Please enter an interger value:

tool: D23: %ld

assistant: ```c
long get_long(void) {
  long input;
  char ch;
  while (scanf("%ld", &input) != 1) {
    while ((ch = getchar()) != '\n')
      putchar(ch);
    printf(" is not an integer.\n");
    printf("Please enter an interger value:");
  }
  return input;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_long>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D27(%rip),%rbx
  lea    D11(%rip),%r13
  lea    D29(%rip),%r12
  jmp    L33
L25:
  movsbl %al,%edi
  call   <putchar@plt>
L29:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L25
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
L33:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L29
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string

tool: D27: %ld

tool: D11:  is not an integer.


tool: D29: Please enter an interger value:

assistant: ```c
long get_long(void) {
  long input;
  char ch;
  while (scanf("%ld", &input) != 1) {
    while ((ch = getchar()) != '\n')
      putchar(ch);
    printf(" is not an integer.\n");
    printf("Please enter an interger value:");
  }
  return input;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_long>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L33
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L45:
  movsbl %al,%edi
  call   <putchar@plt>
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L45
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L33
L49:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D22
datatype: string

tool: D2:  is not an integer.


tool: D26: Please enter an interger value:

tool: D22: %ld

assistant: ```c
long get_long(void) {
  long input;
  char ch;
  while (scanf("%ld", &input) != 1) {
    while ((ch = getchar()) != '\n')
      putchar(ch);
    printf(" is not an integer.\n");
    printf("Please enter an interger value:");
  }
  return input;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_long>:
  endbr64
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L24
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl %al,%edi
  call   <putchar@plt>
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L35
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L24
L12:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string

tool: D28:  is not an integer.


tool: D1: Please enter an interger value:

tool: D3: %ld

assistant: ```c
long get_long(void) {
  long input;
  char ch;
  while (scanf("%ld", &input) != 1) {
    while ((ch = getchar()) != '\n')
      putchar(ch);
    printf(" is not an integer.\n");
    printf("Please enter an interger value:");
  }
  return input;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L30
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dp@plt>
  test   %rax,%rax
  je     L19
  lea    D25(%rip),%rax
  jmp    L7
L19:
  lea    D19(%rip),%rax
L7:
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    $0x0,%eax
  call   <input@plt>
  test   %rax,%rax
  jne    L21
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D19
type: string

tool: D22: Collection #%d:


tool: D25: Can be divided.


tool: D19: Can't be divided.


assistant: ```c
int main(void) {
  int i;
  for (i = 1; input(); ++i) {
    printf("Collection #%d:\n", i);
    puts(dp() ? "Can be divided.\n" : "Can't be divided.\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D28(%rip),%r13
  lea    D27(%rip),%r12
  lea    D12(%rip),%rbp
  jmp    L14
L4:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dp@plt>
  test   %rax,%rax
  mov    %rbp,%rdi
  cmovne %r12,%rdi
  call   <puts@plt>
  add    $0x1,%ebx
L14:
  mov    $0x0,%eax
  call   <input@plt>
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string

tool: D28: Collection #%d:


tool: D27: Can be divided.


tool: D12: Can't be divided.


assistant: ```c
int main(void) {
  int i;
  for (i = 1; input(); ++i) {
    printf("Collection #%d:\n", i);
    puts(dp() ? "Can be divided.\n" : "Can't be divided.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <dp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  cmovne %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
L19:
  xor    %eax,%eax
  call   <input@plt>
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string

tool: D5: Collection #%d:


tool: D4: Can be divided.


tool: D16: Can't be divided.


assistant: ```c
int main(void) {
  int i;
  for (i = 1; input(); ++i) {
    printf("Collection #%d:\n", i);
    puts(dp() ? "Can be divided.\n" : "Can't be divided.\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <dp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  cmovne %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
L18:
  xor    %eax,%eax
  call   <input@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D27
data_type: string

tool: D25: Collection #%d:


tool: D16: Can be divided.


tool: D27: Can't be divided.


assistant: ```c
int main(void) {
  int i;
  for (i = 1; input(); ++i) {
    printf("Collection #%d:\n", i);
    puts(dp() ? "Can be divided.\n" : "Can't be divided.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<uwsgi_opt_legion_node>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <uwsgi_concat2@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L11
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <uwsgi_log@plt>
  mov    $0x1,%edi
  call   <uwsgi_exit@plt>
L11:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <uwsgi_legion_get_by_name@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <uwsgi_log@plt>
  mov    $0x1,%edi
  call   <uwsgi_exit@plt>
L13:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <uwsgi_legion_register_node@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string
name: retrieve_data
arguments: tag: D22
data_type: string

tool: 

tool: D29: invalid legion-node syntax, must be <legion> <addr>


tool: D22: unknown legion: %s


assistant: ```c
void uwsgi_opt_legion_node(char *opt, char *value, void *foobar) {
  char *legion = uwsgi_concat2(value, (char *)"");
  char *space = strchr(legion, ' ');
  if (!space) {
    uwsgi_log("invalid legion-node syntax, must be <legion> <addr>\n");
    uwsgi_exit(1);
  }
  *space = 0;
  struct uwsgi_legion *ul = uwsgi_legion_get_by_name(legion);
  if (!ul) {
    uwsgi_log("unknown legion: %s\n", legion);
    uwsgi_exit(1);
  }
  uwsgi_legion_register_node(ul, space + 1);
}
```