ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test10>:
  endbr64
  sub    $0xa8,%rsp
  movdqa D3(%rip),%xmm0
  mov    $0x4bff,%edx
  mov    $0x23,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rcx
  movb   $0x22,0x62(%rsp)
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D47(%rip),%xmm0
  movabs $0x7766554433221100,%rax
  lea    0x20(%rsp),%rsi
  mov    %rax,0x30(%rsp)
  mov    $0x1100,%eax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D27(%rip),%xmm0
  mov    %ax,0x60(%rsp)
  lea    0x10(%rsp),%rax
  movaps %xmm0,0x70(%rsp)
  movdqa D2(%rip),%xmm0
  mov    %dx,0x90(%rsp)
  mov    $0x1c,%edx
  movaps %xmm0,0x80(%rsp)
  movdqa D22(%rip),%xmm0
  movl   $0xbbaa9988,0x38(%rsp)
  movb   $0x3c,0x92(%rsp)
  movaps %xmm0,0x10(%rsp)
  push   %rax
  push   $0x23
  lea    0x80(%rsp),%r9
  call   <run_test@plt>
  pop    %rcx
  pop    %rsi
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0xa8,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D47
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: byte[16]

tool: {"D3": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D47": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D27": [0xa8,0x0a,0x9b,0xd4,0x7a,0xee,0xdc,0x83,0x3e,0x1f,0xd8,0x92,0x67,0x32,0x51,0x04]}

tool: {"D2": [0xe8,0xf3,0x59,0xbc,0x62,0x98,0xae,0xe3,0x1f,0xce,0x5c,0x54,0x5d,0x3e,0x61,0x1a]}

tool: {"D22": [0x02,0x46,0x26,0x8a,0x38,0x39,0xbc,0x92,0x3c,0x44,0x8a,0x9a,0x62,0xab,0x7a,0x13]}

assistant: ```c
int test10() {
  unsigned long long mlen = 35;
  const unsigned long long clen = mlen;
  const unsigned long long hlen = 28;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char h[28] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb};
  const unsigned char m[35] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22};
  const unsigned char c[35] = {0xa8, 0x0a, 0x9b, 0xd4, 0x7a, 0xee, 0xdc, 0x83, 0x3e, 0x1f, 0xd8, 0x92, 0x67, 0x32, 0x51, 0x04, 0xe8, 0xf3, 0x59, 0xbc, 0x62, 0x98, 0xae, 0xe3, 0x1f, 0xce, 0x5c, 0x54, 0x5d, 0x3e, 0x61, 0x1a, 0xff, 0x4b, 0x3c};
  const unsigned char t[16] = {0x02, 0x46, 0x26, 0x8a, 0x38, 0x39, 0xbc, 0x92, 0x3c, 0x44, 0x8a, 0x9a, 0x62, 0xab, 0x7a, 0x13};
  return run_test(k, h, hlen, m, mlen, c, clen, t);
}
```
user: What is the c source code of the assembly code below?

```asm
<test10>:
  endbr64
  sub    $0xa8,%rsp
  movdqa D27(%rip),%xmm0
  mov    $0x4bff,%edx
  mov    $0x23,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rcx
  movb   $0x22,0x62(%rsp)
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  movabs $0x7766554433221100,%rax
  lea    0x20(%rsp),%rsi
  mov    %rax,0x30(%rsp)
  mov    $0x1100,%eax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D33(%rip),%xmm0
  mov    %ax,0x60(%rsp)
  lea    0x10(%rsp),%rax
  movaps %xmm0,0x70(%rsp)
  movdqa D32(%rip),%xmm0
  mov    %dx,0x90(%rsp)
  mov    $0x1c,%edx
  movaps %xmm0,0x80(%rsp)
  movdqa D14(%rip),%xmm0
  movl   $0xbbaa9988,0x38(%rsp)
  movb   $0x3c,0x92(%rsp)
  movaps %xmm0,0x10(%rsp)
  push   %rax
  push   $0x23
  lea    0x80(%rsp),%r9
  call   <run_test@plt>
  pop    %rcx
  pop    %rsi
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0xa8,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D1
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D33
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D32
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D14
type_infered: byte[16]

tool: {"D27": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D1": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D33": [0xa8,0x0a,0x9b,0xd4,0x7a,0xee,0xdc,0x83,0x3e,0x1f,0xd8,0x92,0x67,0x32,0x51,0x04]}

tool: {"D32": [0xe8,0xf3,0x59,0xbc,0x62,0x98,0xae,0xe3,0x1f,0xce,0x5c,0x54,0x5d,0x3e,0x61,0x1a]}

tool: {"D14": [0x02,0x46,0x26,0x8a,0x38,0x39,0xbc,0x92,0x3c,0x44,0x8a,0x9a,0x62,0xab,0x7a,0x13]}

assistant: ```c
int test10() {
  unsigned long long mlen = 35;
  const unsigned long long clen = mlen;
  const unsigned long long hlen = 28;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char h[28] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb};
  const unsigned char m[35] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22};
  const unsigned char c[35] = {0xa8, 0x0a, 0x9b, 0xd4, 0x7a, 0xee, 0xdc, 0x83, 0x3e, 0x1f, 0xd8, 0x92, 0x67, 0x32, 0x51, 0x04, 0xe8, 0xf3, 0x59, 0xbc, 0x62, 0x98, 0xae, 0xe3, 0x1f, 0xce, 0x5c, 0x54, 0x5d, 0x3e, 0x61, 0x1a, 0xff, 0x4b, 0x3c};
  const unsigned char t[16] = {0x02, 0x46, 0x26, 0x8a, 0x38, 0x39, 0xbc, 0x92, 0x3c, 0x44, 0x8a, 0x9a, 0x62, 0xab, 0x7a, 0x13};
  return run_test(k, h, hlen, m, mlen, c, clen, t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x650,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x520(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xa2,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  lea    -0x640(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x24,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,-0x648(%rbp)
  mov    $0xc,%edi
  call   <getRandomNumber@plt>
  mov    %eax,-0x644(%rbp)
  lea    -0x520(%rbp),%rax
  mov    %rax,%rdi
  call   <initialiseMazeArray@plt>
  mov    -0x644(%rbp),%ecx
  mov    -0x648(%rbp),%edx
  lea    -0x640(%rbp),%rsi
  lea    -0x520(%rbp),%rax
  mov    %rax,%rdi
  call   <removeWalls@plt>
  lea    -0x520(%rbp),%rax
  mov    %rax,%rdi
  call   <addRandomEntrances@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    -0x520(%rbp),%rax
  mov    %rax,%rdi
  call   <drawMaze@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string

tool: D12: cls

tool: D17: pause

assistant: ```c
int main() {
  int maze[13][25] = {{0}};
  int visited[13 / 2][25 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(25 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  addRandomEntrances(maze);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x640,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x638(%rsp)
  xor    %eax,%eax
  lea    0x120(%rsp),%rdi
  mov    $0xa2,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  mov    $0x24,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    %eax,%ebp
  mov    $0xc,%edi
  call   <getRandomNumber@plt>
  mov    %eax,%r12d
  lea    0x120(%rsp),%rbx
  mov    %rbx,%rdi
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <removeWalls@plt>
  mov    %rbx,%rdi
  call   <addRandomEntrances@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    %rbx,%rdi
  call   <drawMaze@plt>
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    0x638(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x640,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string

tool: D18: cls

tool: D1: pause

assistant: ```c
int main() {
  int maze[13][25] = {{0}};
  int visited[13 / 2][25 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(25 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  addRandomEntrances(maze);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa2,%ecx
  push   %r12
  push   %rbp
  sub    $0x640,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x638(%rsp)
  xor    %eax,%eax
  lea    0x120(%rsp),%rdi
  lea    0x120(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x24,%ecx
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    $0xc,%edi
  mov    %eax,%r12d
  call   <getRandomNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <removeWalls@plt>
  mov    %rbp,%rdi
  call   <addRandomEntrances@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <drawMaze@plt>
  lea    D9(%rip),%rdi
  call   <system@plt>
  mov    0x638(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x640,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D9
type_infered: string

tool: D18: cls

tool: D9: pause

assistant: ```c
int main() {
  int maze[13][25] = {{0}};
  int visited[13 / 2][25 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(25 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  addRandomEntrances(maze);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa2,%ecx
  push   %r12
  push   %rbp
  sub    $0x640,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x638(%rsp)
  xor    %eax,%eax
  lea    0x120(%rsp),%rdi
  lea    0x120(%rsp),%rbp
  rep stos %rax,%es:(%rdi)
  mov    $0x24,%ecx
  movl   $0x0,(%rdi)
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x6,%edi
  call   <getRandomNumber@plt>
  mov    $0xc,%edi
  mov    %eax,%r12d
  call   <getRandomNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <initialiseMazeArray@plt>
  mov    %rsp,%rsi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <removeWalls@plt>
  mov    %rbp,%rdi
  call   <addRandomEntrances@plt>
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <drawMaze@plt>
  lea    D0(%rip),%rdi
  call   <system@plt>
  mov    0x638(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x640,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string

tool: D1: cls

tool: D0: pause

assistant: ```c
int main() {
  int maze[13][25] = {{0}};
  int visited[13 / 2][25 / 2] = {{0}};
  srand(time(NULL));
  int startRow = getRandomNumber(13 / 2);
  int startCol = getRandomNumber(25 / 2);
  initialiseMazeArray(maze);
  removeWalls(maze, visited, startRow, startCol);
  addRandomEntrances(maze);
  system("cls");
  drawMaze(maze);
  system("pause");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<findstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L66
  addq   $0x1,-0x8(%rbp)
  jmp    L65
L66:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L65
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L65:
  addq   $0x1,-0x18(%rbp)
L42:
  cmpl   $0x0,-0xc(%rbp)
  je     L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L69
  movl   $0x0,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findstr(char *str, char *filterstr) {
  int end;
  char *ptr;
  end = 1;
  ptr = filterstr;
  while ((end) && (*str) && (*ptr)) {
    if (*str == *ptr)
      ptr++;
    else if (ptr != filterstr)
      ptr = filterstr;
    str++;
  }
  if (*ptr)
    end = 0;
  return end;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findstr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  test   %dl,%dl
  je     L5
L1:
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L5
  add    $0x1,%rax
  cmp    %dl,%cl
  cmovne %rsi,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L1
L5:
  cmpb   $0x0,(%rax)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int findstr(char *str, char *filterstr) {
  int end;
  char *ptr;
  end = 1;
  ptr = filterstr;
  while ((end) && (*str) && (*ptr)) {
    if (*str == *ptr)
      ptr++;
    else if (ptr != filterstr)
      ptr = filterstr;
    str++;
  }
  if (*ptr)
    end = 0;
  return end;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findstr>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%rax
  test   %cl,%cl
  jne    L46
  jmp    L1
L31:
  add    $0x1,%rax
  cmp    %cl,%dl
  cmovne %rsi,%rax
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  je     L30
L46:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L31
L41:
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   (%rax)
L30:
  movzbl (%rax),%edx
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
L1:
  movzbl (%rsi),%edx
  jmp    L41
```

assistant: ```c
int findstr(char *str, char *filterstr) {
  int end;
  char *ptr;
  end = 1;
  ptr = filterstr;
  while ((end) && (*str) && (*ptr)) {
    if (*str == *ptr)
      ptr++;
    else if (ptr != filterstr)
      ptr = filterstr;
    str++;
  }
  if (*ptr)
    end = 0;
  return end;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findstr>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%rax
  test   %cl,%cl
  jne    L35
  jmp    L10
L7:
  add    $0x1,%rax
  cmp    %cl,%dl
  cmovne %rsi,%rax
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  je     L18
L35:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L7
L14:
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   (%rax)
L18:
  movzbl (%rax),%edx
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
L10:
  movzbl (%rsi),%edx
  jmp    L14
```

assistant: ```c
int findstr(char *str, char *filterstr) {
  int end;
  char *ptr;
  end = 1;
  ptr = filterstr;
  while ((end) && (*str) && (*ptr)) {
    if (*str == *ptr)
      ptr++;
    else if (ptr != filterstr)
      ptr = filterstr;
    str++;
  }
  if (*ptr)
    end = 0;
  return end;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_find_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L35
  mov    -0x4(%rbp),%eax
  jmp    L2
L35:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    $0xffffffff,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int ft_find_base(char ch, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (ch == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L26
  mov    $0x0,%eax
L24:
  mov    %eax,%ecx
  cmp    %dl,%dil
  je     L31
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L24
  mov    $0xffffffff,%ecx
L31:
  mov    %ecx,%eax
  ret
L26:
  mov    $0xffffffff,%ecx
  jmp    L31
```

assistant: ```c
int ft_find_base(char ch, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (ch == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L34
  xor    %eax,%eax
  jmp    L15
  nop
L2:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L34
L15:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_find_base(char ch, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (ch == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_find_base>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L35
  xor    %eax,%eax
  jmp    L10
  nop
L3:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L35
L10:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_find_base(char ch, char *base) {
  int count;
  count = 0;
  while (base[count] != '\0') {
    if (ch == base[count])
      return (count);
    count++;
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<testmemmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6568,%rax
  mov    $0xa646c72,%edx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x2,%rax
  lea    -0x20(%rbp),%rcx
  mov    $0xd,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: %s

assistant: ```c
void testmemmove() {
  char buf[20] = "hello world\n";
  memmove(buf + 2, buf, 13);
  printf("%s", buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testmemmove>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6568,%rax
  mov    $0xa646c72,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x2(%rsp),%rdi
  mov    $0xd,%edx
  mov    %rbx,%rsi
  call   <memmove@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: %s

assistant: ```c
void testmemmove() {
  char buf[20] = "hello world\n";
  memmove(buf + 2, buf, 13);
  printf("%s", buf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testmemmove>:
  endbr64
  push   %rbp
  mov    $0xd,%edx
  sub    $0x20,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x2(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  call   <memmove@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
data_type: byte[16]
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: {"D12": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x0a,0x00,0x00,0x00,0x00]}

tool: D7: %s

assistant: ```c
void testmemmove() {
  char buf[20] = "hello world\n";
  memmove(buf + 2, buf, 13);
  printf("%s", buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testmemmove>:
  endbr64
  push   %rbp
  mov    $0xd,%edx
  sub    $0x20,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x2(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  call   <memmove@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: byte[16]
name: unpack_data
arguments: tag: D14
datatype: string

tool: {"D1": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x0a,0x00,0x00,0x00,0x00]}

tool: D14: %s

assistant: ```c
void testmemmove() {
  char buf[20] = "hello world\n";
  memmove(buf + 2, buf, 13);
  printf("%s", buf);
}
```