ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2,%esi
  mov    $0x30d40,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  call   <p_list@plt>
  mov    $0x5,%esi
  mov    $0x30d40,%edi
  mov    %rax,%rbp
  call   <p_list@plt>
  mov    $0x30d40,%r9d
  xor    %esi,%esi
  mov    $0x30d40,%r10d
  mov    %rax,%r12
  xchg   %ax,%ax
L27:
  mov    0x0(%rbp,%rsi,8),%rdi
  mov    %r10,%r8
  mov    %r9,%rcx
  mov    %rsi,%rax
  sub    %rsi,%r8
  mov    %rdi,%r11
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    0x0(%rbp,%rax,8),%r11
L78:
  mov    0x0(%rbp,%rcx,8),%rdx
  add    %rdi,%rdx
  add    %r11,%rdx
  cmp    $0x30d2e,%rdx
  ja     L36
  mov    (%r12,%rcx,8),%rdx
  add    (%r12,%rax,8),%rdx
  add    (%r12,%rsi,8),%rdx
  cmp    $0xc342,%rdx
  ja     L36
  cmp    %rsi,%rax
  je     L11
  cmp    %rcx,%rax
  je     L11
  add    $0x6,%r13
  nopl   0x0(%rax)
L36:
  add    $0x1,%rax
  mov    %r8,%rdx
  sub    $0x1,%rcx
  sub    %rax,%rdx
  cmp    %rdx,%rax
  jbe    L34
  add    $0x1,%rsi
  sub    $0x2,%r9
  cmp    $0x1046a,%rsi
  jne    L27
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  add    $0x3,%r13
  jmp    L36
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: answer: %lld


assistant: ```c
int main(int argc, char **argv) {
  unsigned long k1, k2, k3;
  unsigned long long ans = 0;
  unsigned long *p2 = p_list(200000, 2);
  unsigned long *p5 = p_list(200000, 5);
#pragma omp parallel for private(k1, k2, k3) reduction(+ : ans)
  for (k1 = 0; k1 < 200000 / 3; k1++) {
    for (k2 = k1; k2 <= 200000 - k1 - k2; k2++) {
      k3 = 200000 - k1 - k2;
      if (p2[k1] + p2[k2] + p2[k3] < 199983 && p5[k1] + p5[k2] + p5[k3] < 49987) {
        if (k1 == k2 || k2 == k3) {
          ans += 3;
        } else {
          ans += 6;
        }
      }
    }
  }
  free(p2);
  free(p5);
  printf("answer: %lld\n", ans);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x2,%esi
  mov    $0x30d40,%edi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  call   <p_list@plt>
  mov    $0x5,%esi
  mov    $0x30d40,%edi
  mov    %rax,%rbp
  call   <p_list@plt>
  mov    $0x30d40,%r9d
  xor    %esi,%esi
  mov    $0x30d40,%r10d
  mov    %rax,%r12
  xchg   %ax,%ax
L21:
  mov    %r10,%rdi
  mov    0x0(%rbp,%rsi,8),%r8
  mov    %r9,%rcx
  mov    %rsi,%rax
  sub    %rsi,%rdi
  nopl   0x0(%rax)
L25:
  mov    0x0(%rbp,%rcx,8),%rdx
  add    0x0(%rbp,%rax,8),%rdx
  add    %r8,%rdx
  cmp    $0x30d2e,%rdx
  ja     L12
  mov    (%r12,%rcx,8),%rdx
  add    (%r12,%rax,8),%rdx
  add    (%r12,%rsi,8),%rdx
  cmp    $0xc342,%rdx
  ja     L12
  cmp    %rsi,%rax
  je     L8
  cmp    %rcx,%rax
  je     L8
  add    $0x6,%r13
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  mov    %rdi,%rdx
  sub    $0x1,%rcx
  sub    %rax,%rdx
  cmp    %rdx,%rax
  jbe    L25
  add    $0x1,%rsi
  sub    $0x2,%r9
  cmp    $0x1046a,%rsi
  jne    L21
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x3,%r13
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: answer: %lld


assistant: ```c
int main(int argc, char **argv) {
  unsigned long k1, k2, k3;
  unsigned long long ans = 0;
  unsigned long *p2 = p_list(200000, 2);
  unsigned long *p5 = p_list(200000, 5);
#pragma omp parallel for private(k1, k2, k3) reduction(+ : ans)
  for (k1 = 0; k1 < 200000 / 3; k1++) {
    for (k2 = k1; k2 <= 200000 - k1 - k2; k2++) {
      k3 = 200000 - k1 - k2;
      if (p2[k1] + p2[k2] + p2[k3] < 199983 && p5[k1] + p5[k2] + p5[k3] < 49987) {
        if (k1 == k2 || k2 == k3) {
          ans += 3;
        } else {
          ans += 6;
        }
      }
    }
  }
  free(p2);
  free(p5);
  printf("answer: %lld\n", ans);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a2f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  movsbl -0x24(%rbp),%eax
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%edx
  lea    -0x10(%rbp),%rsi
  mov    %eax,%edi
  call   <a2i@plt>
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x24(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  movsbl -0x24(%rbp),%eax
  lea    -0x1c(%rbp),%rcx
  mov    -0x28(%rbp),%edx
  lea    -0x10(%rbp),%rsi
  mov    %eax,%edi
  call   <a2i@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L20
L23:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x28(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
L20:
  cmpl   $0x0,-0x14(%rbp)
  jg     L23
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x18(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  movss  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
float a2f(char ch, char **src, int base) {
  float result = 0.0;
  int integer = 0;
  int fraction = 0;
  char *p = *src;
  a2i(ch, &p, base, &integer);
  ch = *p++;
  *src = p;
  a2i(ch, &p, base, &fraction);
  int digits = (p - (*src));
  result = (float)fraction;
  while (digits > 0) {
    result = result / (float)base;
    digits--;
  }
  result = result + (float)integer;
  *src = p;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<a2f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    (%rsi),%rax
  mov    %rax,0x10(%rsp)
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%r12
  movsbl %dil,%edi
  mov    %r12,%rsi
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,0x10(%rsp)
  movzbl (%rdx),%edi
  mov    %rax,(%rbx)
  lea    0xc(%rsp),%rcx
  movsbl %dil,%edi
  mov    %ebp,%edx
  mov    %r12,%rsi
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  mov    %rdx,%rcx
  sub    (%rbx),%rcx
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0xc(%rsp),%xmm1
  test   %ecx,%ecx
  jle    L17
  mov    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
L21:
  divss  %xmm0,%xmm1
  sub    $0x1,%eax
  jne    L21
L17:
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x8(%rsp),%xmm0
  addss  %xmm1,%xmm0
  mov    %rdx,(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float a2f(char ch, char **src, int base) {
  float result = 0.0;
  int integer = 0;
  int fraction = 0;
  char *p = *src;
  a2i(ch, &p, base, &integer);
  ch = *p++;
  *src = p;
  a2i(ch, &p, base, &fraction);
  int digits = (p - (*src));
  result = (float)fraction;
  while (digits > 0) {
    result = result / (float)base;
    digits--;
  }
  result = result + (float)integer;
  *src = p;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a2f>:
  endbr64
  push   %r12
  movsbl %dil,%edi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    (%rsi),%rax
  lea    0x8(%rsp),%rcx
  mov    %r12,%rsi
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  mov    %r12,%rsi
  lea    0x1(%rdx),%rax
  mov    %rax,0x10(%rsp)
  movsbl (%rdx),%edi
  mov    %ebp,%edx
  mov    %rax,(%rbx)
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0xc(%rsp),%xmm1
  mov    %rdx,%rcx
  sub    (%rbx),%rcx
  test   %ecx,%ecx
  jle    L13
  pxor   %xmm0,%xmm0
  mov    %ecx,%eax
  cvtsi2ss %ebp,%xmm0
  nopl   (%rax)
L14:
  divss  %xmm0,%xmm1
  sub    $0x1,%eax
  jne    L14
L13:
  pxor   %xmm0,%xmm0
  mov    %rdx,(%rbx)
  cvtsi2ssl 0x8(%rsp),%xmm0
  addss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float a2f(char ch, char **src, int base) {
  float result = 0.0;
  int integer = 0;
  int fraction = 0;
  char *p = *src;
  a2i(ch, &p, base, &integer);
  ch = *p++;
  *src = p;
  a2i(ch, &p, base, &fraction);
  int digits = (p - (*src));
  result = (float)fraction;
  while (digits > 0) {
    result = result / (float)base;
    digits--;
  }
  result = result + (float)integer;
  *src = p;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<a2f>:
  endbr64
  push   %r12
  movsbl %dil,%edi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    (%rsi),%rax
  lea    0x8(%rsp),%rcx
  mov    %r12,%rsi
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  mov    %r12,%rsi
  lea    0x1(%rdx),%rax
  mov    %rax,0x10(%rsp)
  movsbl (%rdx),%edi
  mov    %ebp,%edx
  mov    %rax,(%rbx)
  call   <a2i@plt>
  mov    0x10(%rsp),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0xc(%rsp),%xmm1
  mov    %rdx,%rcx
  sub    (%rbx),%rcx
  test   %ecx,%ecx
  jle    L28
  pxor   %xmm0,%xmm0
  mov    %ecx,%eax
  cvtsi2ss %ebp,%xmm0
  nopl   (%rax)
L18:
  divss  %xmm0,%xmm1
  sub    $0x1,%eax
  jne    L18
L28:
  pxor   %xmm0,%xmm0
  mov    %rdx,(%rbx)
  cvtsi2ssl 0x8(%rsp),%xmm0
  addss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float a2f(char ch, char **src, int base) {
  float result = 0.0;
  int integer = 0;
  int fraction = 0;
  char *p = *src;
  a2i(ch, &p, base, &integer);
  ch = *p++;
  *src = p;
  a2i(ch, &p, base, &fraction);
  int digits = (p - (*src));
  result = (float)fraction;
  while (digits > 0) {
    result = result / (float)base;
    digits--;
  }
  result = result + (float)integer;
  *src = p;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<startElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L4:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D3: start(%s)


tool: D4:  * %s = %s


assistant: ```c
void startElement(void *userData, const char *name, const char **atts) {
  int i;
  printf("start(%s)\n", name, userData);
  for (i = 0; atts[i]; i += 2) {
    char *key = atts[i + 0];
    char *val = atts[i + 1];
    printf(" * %s = %s\n", key, val);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<startElement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L18
  add    $0x8,%rbx
  lea    D9(%rip),%rbp
L2:
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x10,%rbx
  mov    -0x8(%rbx),%rsi
  test   %rsi,%rsi
  jne    L2
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D14: start(%s)


tool: D9:  * %s = %s


assistant: ```c
void startElement(void *userData, const char *name, const char **atts) {
  int i;
  printf("start(%s)\n", name, userData);
  for (i = 0; atts[i]; i += 2) {
    char *key = atts[i + 0];
    char *val = atts[i + 1];
    printf(" * %s = %s\n", key, val);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<startElement>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  lea    D15(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L14
  add    $0x8,%rbx
  lea    D8(%rip),%rbp
  nop
L10:
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  add    $0x10,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  test   %rsi,%rsi
  jne    L10
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D8
type_guessed: string

tool: D15: start(%s)


tool: D8:  * %s = %s


assistant: ```c
void startElement(void *userData, const char *name, const char **atts) {
  int i;
  printf("start(%s)\n", name, userData);
  for (i = 0; atts[i]; i += 2) {
    char *key = atts[i + 0];
    char *val = atts[i + 1];
    printf(" * %s = %s\n", key, val);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<startElement>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  lea    D10(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L19
  add    $0x8,%rbx
  lea    D9(%rip),%rbp
  nop
L18:
  mov    (%rbx),%rdx
  mov    %rbp,%rdi
  add    $0x10,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  test   %rsi,%rsi
  jne    L18
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D9
datatype: string

tool: D10: start(%s)


tool: D9:  * %s = %s


assistant: ```c
void startElement(void *userData, const char *name, const char **atts) {
  int i;
  printf("start(%s)\n", name, userData);
  for (i = 0; atts[i]; i += 2) {
    char *key = atts[i + 0];
    char *val = atts[i + 1];
    printf(" * %s = %s\n", key, val);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wgraphPartFmResize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: wgraphPartFmResize: not implemented

assistant: ```c
int wgraphPartFmResize() {
  SCOTCH_errorPrint("wgraphPartFmResize: not implemented");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wgraphPartFmResize>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: wgraphPartFmResize: not implemented

assistant: ```c
int wgraphPartFmResize() {
  SCOTCH_errorPrint("wgraphPartFmResize: not implemented");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<wgraphPartFmResize>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <SCOTCH_errorPrint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: wgraphPartFmResize: not implemented

assistant: ```c
int wgraphPartFmResize() {
  SCOTCH_errorPrint("wgraphPartFmResize: not implemented");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wgraphPartFmResize>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <SCOTCH_errorPrint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: wgraphPartFmResize: not implemented

assistant: ```c
int wgraphPartFmResize() {
  SCOTCH_errorPrint("wgraphPartFmResize: not implemented");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<walker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  add    $0x2,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x1,%eax
  jmp    L14
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int walker(size_t len, const char *name, void *ud) {
  const char **paths = ud;
  const char *argv0 = paths[0];
  size_t alen = strlen(argv0);
  char *buf = calloc(1, len + alen + 1 + 1);
  strncpy(buf, name, len);
  buf[len] = '/';
  strncpy(&buf[len + 1], argv0, alen);
  if (access(buf, F_OK) == 0) {
    paths[1] = buf;
    return 1;
  }
  free(buf);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<walker>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    (%rdx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x2(%rbp,%rax,1),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x2f,(%rbx,%rbp,1)
  lea    0x1(%rbx,%rbp,1),%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <strncpy@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbx,0x8(%r13)
  mov    $0x1,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
int walker(size_t len, const char *name, void *ud) {
  const char **paths = ud;
  const char *argv0 = paths[0];
  size_t alen = strlen(argv0);
  char *buf = calloc(1, len + alen + 1 + 1);
  strncpy(buf, name, len);
  buf[len] = '/';
  strncpy(&buf[len + 1], argv0, alen);
  if (access(buf, F_OK) == 0) {
    paths[1] = buf;
    return 1;
  }
  free(buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<walker>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x2(%rbx,%rax,1),%rsi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x2f,0x0(%rbp,%rbx,1)
  mov    %r15,%rsi
  mov    %r12,%rdx
  lea    0x1(%rbp,%rbx,1),%rdi
  call   <strncpy@plt>
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <access@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbp,0x8(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int walker(size_t len, const char *name, void *ud) {
  const char **paths = ud;
  const char *argv0 = paths[0];
  size_t alen = strlen(argv0);
  char *buf = calloc(1, len + alen + 1 + 1);
  strncpy(buf, name, len);
  buf[len] = '/';
  strncpy(&buf[len + 1], argv0, alen);
  if (access(buf, F_OK) == 0) {
    paths[1] = buf;
    return 1;
  }
  free(buf);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<walker>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x2(%rbx,%rax,1),%rsi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x2f,0x0(%rbp,%rbx,1)
  mov    %r15,%rsi
  mov    %r12,%rdx
  lea    0x1(%rbp,%rbx,1),%rdi
  call   <strncpy@plt>
  mov    D2(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <access@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbp,0x8(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int walker(size_t len, const char *name, void *ud) {
  const char **paths = ud;
  const char *argv0 = paths[0];
  size_t alen = strlen(argv0);
  char *buf = calloc(1, len + alen + 1 + 1);
  strncpy(buf, name, len);
  buf[len] = '/';
  strncpy(&buf[len + 1], argv0, alen);
  if (access(buf, F_OK) == 0) {
    paths[1] = buf;
    return 1;
  }
  free(buf);
  return 0;
}
```