user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  lea    0x8(%rsp),%rbp
  lea    D62(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    0x10(%rsp),%rbx
  lea    D53(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    0x4(%rsp),%r13
  mov    %edx,%ecx
  mov    %r13,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%r12),%rdi
  call   <strlen@plt>
  movslq %eax,%rsi
  lea    D89(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%r12),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  lea    D80(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,%ecx
  mov    %r13,%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D62
type: string
name: unpack_data
arguments: data_label: D53
type: string
name: unpack_data
arguments: data_label: D59
type: string
name: unpack_data
arguments: data_label: D64
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D89
type: string
name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D80
type: string
name: unpack_data
arguments: data_label: D32
type: string

tool: D62: one

tool: D53: two

tool: D59: [BEFORE] buffer_two is at %p and contains '%s'


tool: D64: [BEFORE] buffer_one is at %p and contains '%s'


tool: D24: [BEFORE] value is at %p and is %d (0x%08x)


tool: D89: 
[STRCPY] copying %u bytes into buffer_two



tool: D12: [AFTER] buffer_two is at %p and contains '%s'


tool: D80: [AFTER] buffer_one is at %p and contains '%s'


tool: D32: [AFTER] value is at %p and is %d (0x%08x)


assistant: ```c
int main(int argc, char *argv[]) {
  argc = (int)argc;
  int value = 5;
  char buffer_one[8], buffer_two[8];
  strcpy(buffer_one, "one");
  strcpy(buffer_two, "two");
  printf("[BEFORE] buffer_two is at %p and contains \'%s\'\n", (void *)buffer_two, buffer_two);
  printf("[BEFORE] buffer_one is at %p and contains \'%s\'\n", (void *)buffer_one, buffer_one);
  printf("[BEFORE] value is at %p and is %d (0x%08x)\n", (void *)&value, value, value);
  printf("\n[STRCPY] copying %u bytes into buffer_two\n\n", strlen(argv[1]));
  strcpy(buffer_two, argv[1]);
  printf("[AFTER] buffer_two is at %p and contains \'%s\'\n", (void *)buffer_two, buffer_two);
  printf("[AFTER] buffer_one is at %p and contains \'%s\'\n", (void *)buffer_one, buffer_one);
  printf("[AFTER] value is at %p and is %d (0x%08x)\n", (void *)&value, value, value);
}
```