ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<totalVirtualMemory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <sysinfo@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L28
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L22
L28:
  mov    -0x20(%rbp),%rax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
long long totalVirtualMemory(bool withSwap) {
  struct sysinfo mem;
  sysinfo(&mem);
  if (withSwap)
    return mem.totalram + mem.totalswap;
  else
    return mem.totalram;
}
```
user: What is the c source code of the assembly code below:

```asm
<totalVirtualMemory>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sysinfo@plt>
  mov    (%rsp),%rax
  test   %ebx,%ebx
  je     L12
  mov    0x8(%rsp),%rax
  add    (%rsp),%rax
L12:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long totalVirtualMemory(bool withSwap) {
  struct sysinfo mem;
  sysinfo(&mem);
  if (withSwap)
    return mem.totalram + mem.totalswap;
  else
    return mem.totalram;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<totalVirtualMemory>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sysinfo@plt>
  mov    (%rsp),%rax
  test   %ebx,%ebx
  je     L11
  mov    0x8(%rsp),%rax
  add    (%rsp),%rax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long totalVirtualMemory(bool withSwap) {
  struct sysinfo mem;
  sysinfo(&mem);
  if (withSwap)
    return mem.totalram + mem.totalswap;
  else
    return mem.totalram;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<totalVirtualMemory>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <sysinfo@plt>
  mov    (%rsp),%rax
  test   %ebx,%ebx
  je     L6
  mov    0x8(%rsp),%rax
  add    (%rsp),%rax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long totalVirtualMemory(bool withSwap) {
  struct sysinfo mem;
  sysinfo(&mem);
  if (withSwap)
    return mem.totalram + mem.totalswap;
  else
    return mem.totalram;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__hsail_atomic_min_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L8:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  cmovle %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__sync_bool_compare_and_swap@plt>
  mov    %eax,-0x14(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  je     L8
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t __hsail_atomic_min_u32(uint32_t *ptr, uint32_t a) {
  int done = 0;
  uint32_t old_value;
  uint32_t new_value;
  while (!done) {
    old_value = *ptr;
    new_value = (old_value < a) ? old_value : a;
    done = __sync_bool_compare_and_swap(ptr, old_value, new_value);
  }
  return old_value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__hsail_atomic_min_u32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
L4:
  mov    (%r12),%rbx
  cmp    %rbp,%rbx
  mov    %rbp,%rdx
  cmovle %rbx,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <__sync_bool_compare_and_swap@plt>
  test   %eax,%eax
  je     L4
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t __hsail_atomic_min_u32(uint32_t *ptr, uint32_t a) {
  int done = 0;
  uint32_t old_value;
  uint32_t new_value;
  while (!done) {
    old_value = *ptr;
    new_value = (old_value < a) ? old_value : a;
    done = __sync_bool_compare_and_swap(ptr, old_value, new_value);
  }
  return old_value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__hsail_atomic_min_u32>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L7:
  mov    0x0(%rbp),%r12
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  cmp    %rbx,%r12
  mov    %r12,%rsi
  cmovle %r12,%rdx
  call   <__sync_bool_compare_and_swap@plt>
  test   %eax,%eax
  je     L7
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t __hsail_atomic_min_u32(uint32_t *ptr, uint32_t a) {
  int done = 0;
  uint32_t old_value;
  uint32_t new_value;
  while (!done) {
    old_value = *ptr;
    new_value = (old_value < a) ? old_value : a;
    done = __sync_bool_compare_and_swap(ptr, old_value, new_value);
  }
  return old_value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__hsail_atomic_min_u32>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L3:
  mov    0x0(%rbp),%r12
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  cmp    %rbx,%r12
  mov    %r12,%rsi
  cmovle %r12,%rdx
  call   <__sync_bool_compare_and_swap@plt>
  test   %eax,%eax
  je     L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t __hsail_atomic_min_u32(uint32_t *ptr, uint32_t a) {
  int done = 0;
  uint32_t old_value;
  uint32_t new_value;
  while (!done) {
    old_value = *ptr;
    new_value = (old_value < a) ? old_value : a;
    done = __sync_bool_compare_and_swap(ptr, old_value, new_value);
  }
  return old_value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rightOuterCrate1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <writeDebugStreamLine@plt>
  mov    $0x0,%edi
  call   <rightDropAtPos@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: Crate 1

assistant: ```c
void rightOuterCrate1() {
  writeDebugStreamLine("Crate 1");
  rightDropAtPos(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rightOuterCrate1>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <writeDebugStreamLine@plt>
  mov    $0x0,%edi
  call   <rightDropAtPos@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: Crate 1

assistant: ```c
void rightOuterCrate1() {
  writeDebugStreamLine("Crate 1");
  rightDropAtPos(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rightOuterCrate1>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <writeDebugStreamLine@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <rightDropAtPos@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: Crate 1

assistant: ```c
void rightOuterCrate1() {
  writeDebugStreamLine("Crate 1");
  rightDropAtPos(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<rightOuterCrate1>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <writeDebugStreamLine@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <rightDropAtPos@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Crate 1

assistant: ```c
void rightOuterCrate1() {
  writeDebugStreamLine("Crate 1");
  rightDropAtPos(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L5:
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x2,-0xc(%rbp)
  jle    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D8: floorf

tool: D14: # c::cephes::%s


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "floorf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D6(%rip),%r13
  lea    D29(%rip),%r12
  lea    D15(%rip),%rbp
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D6: floorf

tool: D29: # c::cephes::%s


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "floorf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D26(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string

tool: D26: floorf

tool: D28: # c::cephes::%s


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "floorf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D19(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L8
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D19: floorf

tool: D1: # c::cephes::%s


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "floorf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0xd0(%rbp)
  movl   $0x30,-0xcc(%rbp)
  lea    0x10(%rbp),%rax
  mov    %rax,-0xc8(%rbp)
  lea    -0xb0(%rbp),%rax
  mov    %rax,-0xc0(%rbp)
  mov    -0xd0(%rbp),%eax
  cmp    $0x2f,%eax
  ja     L15
  mov    -0xc0(%rbp),%rax
  mov    -0xd0(%rbp),%edx
  mov    %edx,%edx
  add    %rdx,%rax
  mov    -0xd0(%rbp),%edx
  add    $0x8,%edx
  mov    %edx,-0xd0(%rbp)
  jmp    L3
L15:
  mov    -0xc8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0xc8(%rbp)
L3:
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L68
  call   <abort@plt>
L68:
  mov    -0xd0(%rbp),%eax
  cmp    $0x2f,%eax
  ja     L28
  mov    -0xc0(%rbp),%rax
  mov    -0xd0(%rbp),%edx
  mov    %edx,%edx
  add    %rdx,%rax
  mov    -0xd0(%rbp),%edx
  add    $0x8,%edx
  mov    %edx,-0xd0(%rbp)
  jmp    L48
L28:
  mov    -0xc8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0xc8(%rbp)
L48:
  mov    (%rax),%eax
  cmp    $0x2,%eax
  je     L77
  call   <abort@plt>
L77:
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

assistant: ```c
void __attribute__((no)) chars(int i, ...) {
  __builtin_va_list args;
  __builtin_va_start(args, i);
  if (__builtin_va_arg(args, int) != 1)
    __builtin_abort();
  if (__builtin_va_arg(args, int) != 2)
    __builtin_abort();
  __builtin_va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chars>:
  endbr64
  sub    $0x58,%rsp
  mov    %rsi,0x28(%rsp)
  mov    %rdx,0x30(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x10,(%rsp)
  cmpl   $0x1,0x8(%rax)
  jne    L4
  add    $0x10,%rax
  movl   $0x18,(%rsp)
  cmpl   $0x2,(%rax)
  jne    L8
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x58,%rsp
  ret
L4:
  call   <abort@plt>
L8:
  call   <abort@plt>
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) chars(int i, ...) {
  __builtin_va_list args;
  __builtin_va_start(args, i);
  if (__builtin_va_arg(args, int) != 1)
    __builtin_abort();
  if (__builtin_va_arg(args, int) != 2)
    __builtin_abort();
  __builtin_va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chars>:
  endbr64
  sub    $0x58,%rsp
  mov    %rsi,0x28(%rsp)
  mov    %rdx,0x30(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rax
  movl   $0x10,(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  cmpl   $0x1,0x8(%rax)
  mov    %rax,0x10(%rsp)
  jne    1080 <chars.cold>
  cmpl   $0x2,0x10(%rax)
  jne    1080 <chars.cold>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) chars(int i, ...) {
  __builtin_va_list args;
  __builtin_va_start(args, i);
  if (__builtin_va_arg(args, int) != 1)
    __builtin_abort();
  if (__builtin_va_arg(args, int) != 2)
    __builtin_abort();
  __builtin_va_end(args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chars>:
  endbr64
  sub    $0x58,%rsp
  mov    %rsi,0x28(%rsp)
  mov    %rdx,0x30(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rax
  movl   $0x10,(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  cmpl   $0x1,0x8(%rax)
  mov    %rax,0x10(%rsp)
  jne    1080 <chars.cold>
  cmpl   $0x2,0x10(%rax)
  jne    1080 <chars.cold>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x58,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) chars(int i, ...) {
  __builtin_va_list args;
  __builtin_va_start(args, i);
  if (__builtin_va_arg(args, int) != 1)
    __builtin_abort();
  if (__builtin_va_arg(args, int) != 2)
    __builtin_abort();
  __builtin_va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <warning@plt>
  mov    $0x0,%eax
  jmp    L9
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <fatal_error@plt>
L5:
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D13: new: requested zero bytes of memory, continuing...


tool: D6: new: could not allocate %d byte block


assistant: ```c
void *new (size_t size) {
  void *data;
  if (size == 0) {
    warning("new: requested zero bytes of memory, continuing...\n");
    return NULL;
  }
  data = (void *)malloc(size);
  if (data == NULL)
    fatal_error("new: could not allocate %d byte block\n", size);
  return data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<new>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L30
  mov    %rdi,%rbx
  call   <malloc@plt>
  test   %rax,%rax
  je     L29
L6:
  pop    %rbx
  ret
L30:
  lea    D18(%rip),%rdi
  call   <warning@plt>
  mov    $0x0,%eax
  jmp    L6
L29:
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <fatal_error@plt>
  mov    $0x0,%eax
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_label: D18
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D18: new: requested zero bytes of memory, continuing...


tool: D1: new: could not allocate %d byte block


assistant: ```c
void *new (size_t size) {
  void *data;
  if (size == 0) {
    warning("new: requested zero bytes of memory, continuing...\n");
    return NULL;
  }
  data = (void *)malloc(size);
  if (data == NULL)
    fatal_error("new: could not allocate %d byte block\n", size);
  return data;
}
```
user: What is the c source code of the assembly code below:

```asm
<new>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  je     L5
  mov    %rdi,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L16
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <fatal_error@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  lea    D0(%rip),%rdi
  call   <warning@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string

tool: D1: new: could not allocate %d byte block


tool: D0: new: requested zero bytes of memory, continuing...


assistant: ```c
void *new (size_t size) {
  void *data;
  if (size == 0) {
    warning("new: requested zero bytes of memory, continuing...\n");
    return NULL;
  }
  data = (void *)malloc(size);
  if (data == NULL)
    fatal_error("new: could not allocate %d byte block\n", size);
  return data;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<new>:
  endbr64
  push   %rbp
  test   %rdi,%rdi
  je     L13
  mov    %rdi,%rbp
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <fatal_error@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  lea    D11(%rip),%rdi
  call   <warning@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D16: new: could not allocate %d byte block


tool: D11: new: requested zero bytes of memory, continuing...


assistant: ```c
void *new (size_t size) {
  void *data;
  if (size == 0) {
    warning("new: requested zero bytes of memory, continuing...\n");
    return NULL;
  }
  data = (void *)malloc(size);
  if (data == NULL)
    fatal_error("new: could not allocate %d byte block\n", size);
  return data;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L32:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x13,-0x4(%rbp)
  jle    L32
  movl   $0x13,-0x4(%rbp)
L8:
  addl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L39
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L39
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  cmpl   $0x7530,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %d


assistant: ```c
int main() {
  int i, k, n, j;
  k = 0;
  do {
    k = k + 1;
  } while (k <= 19);
  if (k = 19)
    ;
  {
    do {
      k = k + 2;
      if (k % 3 == 0 && k % 7 == 0) {
        printf("%d\n", k);
      }
    } while (k <= 30000);
  }
  return 0;
}
```