ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vasprintf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x64,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
L4:
  mov    $0x64,%r14d
  nopl   (%rax)
L23:
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  cmp    %eax,%r14d
  jg     L12
  add    %r14d,%r14d
  mov    %rbp,%rdi
  mov    %r14d,%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L23
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L12:
  pop    %rbx
  mov    %rbp,0x0(%r13)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

assistant: ```c
int vasprintf(char **strp, const char *fmt, va_list ap) {
  char *buf;
  int buf_s, buf_n;
  buf_s = 100;
  buf = malloc(buf_s);
  if (buf == NULL)
    exit(1);
  while (1) {
    buf_n = vsnprintf(buf, buf_s, fmt, ap);
    if (buf_n < buf_s) {
      *strp = buf;
      return buf_n;
    }
    buf_s = buf_s * 2;
    buf = realloc(buf, buf_s);
    if (buf == NULL)
      exit(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IoQueryDeviceDescription>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  nop
  mov    $0x0,%eax
  jmp    L0
L1:
  nop
  mov    $0xc0000001,%eax
L0:
  leave
  ret
```

assistant: ```c
int IoQueryDeviceDescription(int BusType, int BusNumber, int ControllerType, int ControllerNumber, int PeripheralType, int PeripheralNumber, int CalloutRoutine, int Context) {
  {
    int tmp_ndt_4;
    tmp_ndt_4 = __VERIFIER_nondet_int();
    if (tmp_ndt_4 == 0) {
      goto switch_5_0;
    } else {
      goto switch_5_default;
      if (0) {
      switch_5_0:
        return (0);
      switch_5_default:;
        return (-1073741823);
      } else {
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<IoQueryDeviceDescription>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L17
L19:
  add    $0x8,%rsp
  ret
L17:
  mov    $0xc0000001,%eax
  jmp    L19
```

assistant: ```c
int IoQueryDeviceDescription(int BusType, int BusNumber, int ControllerType, int ControllerNumber, int PeripheralType, int PeripheralNumber, int CalloutRoutine, int Context) {
  {
    int tmp_ndt_4;
    tmp_ndt_4 = __VERIFIER_nondet_int();
    if (tmp_ndt_4 == 0) {
      goto switch_5_0;
    } else {
      goto switch_5_default;
      if (0) {
      switch_5_0:
        return (0);
      switch_5_default:;
        return (-1073741823);
      } else {
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<IoQueryDeviceDescription>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L3
L8:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xc0000001,%eax
  jmp    L8
```

assistant: ```c
int IoQueryDeviceDescription(int BusType, int BusNumber, int ControllerType, int ControllerNumber, int PeripheralType, int PeripheralNumber, int CalloutRoutine, int Context) {
  {
    int tmp_ndt_4;
    tmp_ndt_4 = __VERIFIER_nondet_int();
    if (tmp_ndt_4 == 0) {
      goto switch_5_0;
    } else {
      goto switch_5_default;
      if (0) {
      switch_5_0:
        return (0);
      switch_5_default:;
        return (-1073741823);
      } else {
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<IoQueryDeviceDescription>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L13
L12:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xc0000001,%eax
  jmp    L12
```

assistant: ```c
int IoQueryDeviceDescription(int BusType, int BusNumber, int ControllerType, int ControllerNumber, int PeripheralType, int PeripheralNumber, int CalloutRoutine, int Context) {
  {
    int tmp_ndt_4;
    tmp_ndt_4 = __VERIFIER_nondet_int();
    if (tmp_ndt_4 == 0) {
      goto switch_5_0;
    } else {
      goto switch_5_default;
      if (0) {
      switch_5_0:
        return (0);
      switch_5_default:;
        return (-1073741823);
      } else {
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcstring_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wcscmp@plt>
  leave
  ret
```

assistant: ```c
int wcstring_cmp(const void *a, const void *b) {
  const wchar_t **ia = (const wchar_t **)a;
  const wchar_t **ib = (const wchar_t **)b;
  return wcscmp(*ia, *ib);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcstring_cmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <wcscmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wcstring_cmp(const void *a, const void *b) {
  const wchar_t **ia = (const wchar_t **)a;
  const wchar_t **ib = (const wchar_t **)b;
  return wcscmp(*ia, *ib);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcstring_cmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <wcscmp@plt>
```

assistant: ```c
int wcstring_cmp(const void *a, const void *b) {
  const wchar_t **ia = (const wchar_t **)a;
  const wchar_t **ib = (const wchar_t **)b;
  return wcscmp(*ia, *ib);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dummy_rng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <randombytes@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int dummy_rng(void *state, unsigned char *bytes, size_t len) {
  ((void)state);
  randombytes(bytes, len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dummy_rng>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <randombytes@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dummy_rng(void *state, unsigned char *bytes, size_t len) {
  ((void)state);
  randombytes(bytes, len);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dummy_rng>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <randombytes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dummy_rng(void *state, unsigned char *bytes, size_t len) {
  ((void)state);
  randombytes(bytes, len);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dummy_rng>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <randombytes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dummy_rng(void *state, unsigned char *bytes, size_t len) {
  ((void)state);
  randombytes(bytes, len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ppMem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L19:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdi
  mov    -0x18(%rbp),%rax
  add    %rdi,%rax
  mov    (%rax),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  cmpl   $0x2,-0x4(%rbp)
  jne    L25
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L25:
  addl   $0x4,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D7
datatype: string

tool: D16: MEM1:

tool: D7: 0x%x, 0x%x, 0x%x, 0x%x


assistant: ```c
void ppMem(unsigned int *mem, int len) {
  int i;
  printf("MEM1:\n");
  for (i = 0; i < len; i = i + 4) {
    printf("0x%x, 0x%x, 0x%x, 0x%x\n", mem[i], mem[i + 1], mem[i + 2], mem[i + 3]);
    mem[i] = 0;
    mem[i + 1] = 0;
    mem[i + 2] = 0;
    mem[i + 3] = 0;
    if (i == 2) {
      mem[i] = 0xffffffff;
      mem[i + 1] = 0;
      mem[i + 2] = 0;
      mem[i + 3] = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ppMem>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L9
  mov    %r12,%rbx
  sub    $0x1,%ebp
  shr    $0x2,%ebp
  mov    %ebp,%ebp
  shl    $0x4,%rbp
  lea    0x10(%r12,%rbp,1),%r12
  lea    D12(%rip),%rbp
L14:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,(%rbx)
  movl   $0x0,0x4(%rbx)
  movl   $0x0,0x8(%rbx)
  movl   $0x0,0xc(%rbx)
  add    $0x10,%rbx
  cmp    %r12,%rbx
  jne    L14
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D2: MEM1:

tool: D12: 0x%x, 0x%x, 0x%x, 0x%x


assistant: ```c
void ppMem(unsigned int *mem, int len) {
  int i;
  printf("MEM1:\n");
  for (i = 0; i < len; i = i + 4) {
    printf("0x%x, 0x%x, 0x%x, 0x%x\n", mem[i], mem[i + 1], mem[i + 2], mem[i + 3]);
    mem[i] = 0;
    mem[i + 1] = 0;
    mem[i + 2] = 0;
    mem[i + 3] = 0;
    if (i == 2) {
      mem[i] = 0xffffffff;
      mem[i + 1] = 0;
      mem[i + 2] = 0;
      mem[i + 3] = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ppMem>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L4
  sub    $0x1,%ebp
  shr    $0x2,%ebp
  shl    $0x4,%rbp
  lea    0x10(%rbx,%rbp,1),%r12
  lea    D19(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  add    $0x10,%rbx
  call   <printf@plt>
  movl   $0x0,-0x10(%rbx)
  movl   $0x0,-0xc(%rbx)
  movl   $0x0,-0x8(%rbx)
  movl   $0x0,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L14
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string
name: parse_data
arguments: label: D19
data_type: string

tool: D6: MEM1:

tool: D19: 0x%x, 0x%x, 0x%x, 0x%x


assistant: ```c
void ppMem(unsigned int *mem, int len) {
  int i;
  printf("MEM1:\n");
  for (i = 0; i < len; i = i + 4) {
    printf("0x%x, 0x%x, 0x%x, 0x%x\n", mem[i], mem[i + 1], mem[i + 2], mem[i + 3]);
    mem[i] = 0;
    mem[i + 1] = 0;
    mem[i + 2] = 0;
    mem[i + 3] = 0;
    if (i == 2) {
      mem[i] = 0xffffffff;
      mem[i + 1] = 0;
      mem[i + 2] = 0;
      mem[i + 3] = 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ppMem>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D19(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L17
  sub    $0x1,%ebp
  shr    $0x2,%ebp
  shl    $0x4,%rbp
  lea    0x10(%rbx,%rbp,1),%r12
  lea    D0(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  add    $0x10,%rbx
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movups %xmm0,-0x10(%rbx)
  cmp    %r12,%rbx
  jne    L15
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D19: MEM1:

tool: D0: 0x%x, 0x%x, 0x%x, 0x%x


assistant: ```c
void ppMem(unsigned int *mem, int len) {
  int i;
  printf("MEM1:\n");
  for (i = 0; i < len; i = i + 4) {
    printf("0x%x, 0x%x, 0x%x, 0x%x\n", mem[i], mem[i + 1], mem[i + 2], mem[i + 3]);
    mem[i] = 0;
    mem[i + 1] = 0;
    mem[i + 2] = 0;
    mem[i + 3] = 0;
    if (i == 2) {
      mem[i] = 0xffffffff;
      mem[i + 1] = 0;
      mem[i + 2] = 0;
      mem[i + 3] = 0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MatMul333>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  jmp    L35
L43:
  movl   $0x0,-0x54(%rbp)
  jmp    L7
L9:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x70(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rax,%rdx,8),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x70(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  0x10(%rax),%xmm2
  mov    -0x70(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x54(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movsd  %xmm0,-0x50(%rbp,%rax,8)
  addl   $0x1,-0x54(%rbp)
L7:
  cmpl   $0x2,-0x54(%rbp)
  jle    L9
  addl   $0x1,-0x58(%rbp)
L35:
  cmpl   $0x2,-0x58(%rbp)
  jle    L43
  lea    -0x50(%rbp),%rcx
  mov    -0x78(%rbp),%rax
  mov    $0x48,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
void MatMul333(const double Mat33a[3][3], const double Mat33b[3][3], double *Result) {
  double LocalResult[3][3];
  int iRowIndex, iColIndex;
  for (iRowIndex = 0; iRowIndex < 3; iRowIndex++) {
    for (iColIndex = 0; iColIndex < 3; iColIndex++) {
      LocalResult[iRowIndex][iColIndex] = Mat33a[iRowIndex][0] * Mat33b[0][iColIndex] + Mat33a[iRowIndex][1] * Mat33b[1][iColIndex] + Mat33a[iRowIndex][2] * Mat33b[2][iColIndex];
    }
  }
  memcpy(Result, LocalResult, sizeof(LocalResult));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MatMul333>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdx,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  lea    0x48(%rsp),%r8
  jmp    L45
L27:
  add    $0x18,%rdi
  add    $0x18,%rcx
  cmp    %r8,%rcx
  je     L6
L45:
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm2
  mov    $0x0,%eax
L18:
  movapd %xmm4,%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  movapd %xmm3,%xmm1
  mulsd  0x18(%rsi,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  0x30(%rsi,%rax,1),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L18
  jmp    L27
L6:
  mov    %rsp,%rsi
  mov    $0x48,%edx
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x58,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MatMul333(const double Mat33a[3][3], const double Mat33b[3][3], double *Result) {
  double LocalResult[3][3];
  int iRowIndex, iColIndex;
  for (iRowIndex = 0; iRowIndex < 3; iRowIndex++) {
    for (iColIndex = 0; iColIndex < 3; iColIndex++) {
      LocalResult[iRowIndex][iColIndex] = Mat33a[iRowIndex][0] * Mat33b[0][iColIndex] + Mat33a[iRowIndex][1] * Mat33b[1][iColIndex] + Mat33a[iRowIndex][2] * Mat33b[2][iColIndex];
    }
  }
  memcpy(Result, LocalResult, sizeof(LocalResult));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MatMul333>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdx,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  lea    0x48(%rsp),%r8
  mov    %r10,%rcx
L12:
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm3
  xor    %eax,%eax
  movsd  0x10(%rdi),%xmm2
L28:
  movsd  (%rsi,%rax,1),%xmm0
  movsd  0x18(%rsi,%rax,1),%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x30(%rsi,%rax,1),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L28
  add    $0x18,%rcx
  add    $0x18,%rdi
  cmp    %rcx,%r8
  jne    L12
  mov    $0x48,%edx
  mov    %r10,%rsi
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x58,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MatMul333(const double Mat33a[3][3], const double Mat33b[3][3], double *Result) {
  double LocalResult[3][3];
  int iRowIndex, iColIndex;
  for (iRowIndex = 0; iRowIndex < 3; iRowIndex++) {
    for (iColIndex = 0; iColIndex < 3; iColIndex++) {
      LocalResult[iRowIndex][iColIndex] = Mat33a[iRowIndex][0] * Mat33b[0][iColIndex] + Mat33a[iRowIndex][1] * Mat33b[1][iColIndex] + Mat33a[iRowIndex][2] * Mat33b[2][iColIndex];
    }
  }
  memcpy(Result, LocalResult, sizeof(LocalResult));
}
```
user: Translate the below assembly code into C programming language:

```asm
<MatMul333>:
  endbr64
  mov    %rdi,%rax
  sub    $0x58,%rsp
  movupd (%rsi),%xmm6
  movupd 0x10(%rsi),%xmm0
  movupd 0x10(%rax),%xmm1
  movupd 0x20(%rsi),%xmm4
  mov    %rdx,%rdi
  unpcklpd %xmm6,%xmm0
  movupd 0x10(%rsi),%xmm10
  movupd 0x20(%rax),%xmm9
  movlpd (%rax),%xmm1
  movapd %xmm4,%xmm8
  movupd 0x18(%rsi),%xmm7
  movupd 0x30(%rsi),%xmm5
  mov    %fs:0x28,%rdx
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  mulpd  %xmm0,%xmm1
  movupd (%rax),%xmm0
  unpckhpd %xmm10,%xmm8
  movupd 0x8(%rsi),%xmm3
  movupd 0x38(%rsi),%xmm2
  mov    $0x48,%edx
  shufpd $0x1,%xmm9,%xmm0
  mulpd  %xmm8,%xmm0
  movapd %xmm9,%xmm8
  movlpd 0x10(%rax),%xmm8
  addpd  %xmm0,%xmm1
  movsd  0x40(%rsi),%xmm0
  movhpd 0x30(%rsi),%xmm0
  mov    %rsp,%rsi
  mulpd  %xmm8,%xmm0
  addpd  %xmm0,%xmm1
  movupd (%rax),%xmm0
  unpcklpd %xmm0,%xmm0
  mulpd  %xmm6,%xmm0
  movaps %xmm1,0x10(%rsp)
  movapd %xmm9,%xmm1
  unpcklpd %xmm9,%xmm1
  mulpd  %xmm4,%xmm1
  unpckhpd %xmm4,%xmm4
  movapd %xmm0,%xmm8
  movupd (%rax),%xmm0
  unpckhpd %xmm0,%xmm0
  mulpd  %xmm7,%xmm0
  addpd  %xmm8,%xmm0
  movupd 0x10(%rax),%xmm8
  unpcklpd %xmm8,%xmm8
  mulpd  %xmm5,%xmm8
  addpd  %xmm8,%xmm0
  movsd  0x40(%rax),%xmm8
  movaps %xmm0,(%rsp)
  movupd 0x10(%rax),%xmm0
  unpckhpd %xmm0,%xmm0
  mulpd  %xmm3,%xmm0
  unpckhpd %xmm3,%xmm3
  addpd  %xmm1,%xmm0
  movapd %xmm9,%xmm1
  unpckhpd %xmm9,%xmm1
  mulpd  %xmm2,%xmm1
  unpckhpd %xmm2,%xmm2
  mulsd  %xmm8,%xmm2
  addpd  %xmm1,%xmm0
  movaps %xmm0,0x20(%rsp)
  movupd 0x30(%rax),%xmm0
  mulsd  %xmm0,%xmm3
  movapd %xmm0,%xmm1
  unpckhpd %xmm0,%xmm1
  mulpd  %xmm7,%xmm1
  movapd %xmm0,%xmm7
  unpcklpd %xmm0,%xmm7
  mulpd  %xmm7,%xmm6
  addpd  %xmm6,%xmm1
  movapd %xmm8,%xmm6
  unpcklpd %xmm6,%xmm6
  mulpd  %xmm6,%xmm5
  addpd  %xmm5,%xmm1
  movapd %xmm0,%xmm5
  unpckhpd %xmm5,%xmm5
  movaps %xmm1,0x30(%rsp)
  movapd %xmm5,%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x40(%rsp)
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void MatMul333(const double Mat33a[3][3], const double Mat33b[3][3], double *Result) {
  double LocalResult[3][3];
  int iRowIndex, iColIndex;
  for (iRowIndex = 0; iRowIndex < 3; iRowIndex++) {
    for (iColIndex = 0; iColIndex < 3; iColIndex++) {
      LocalResult[iRowIndex][iColIndex] = Mat33a[iRowIndex][0] * Mat33b[0][iColIndex] + Mat33a[iRowIndex][1] * Mat33b[1][iColIndex] + Mat33a[iRowIndex][2] * Mat33b[2][iColIndex];
    }
  }
  memcpy(Result, LocalResult, sizeof(LocalResult));
}
```