ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getline_tst>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbp
  mov    D8(%rip),%r13
  jmp    L5
L15:
  cmp    $0xa,%eax
  je     L25
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x3e7,%rbx
  je     L28
L5:
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <getchar@plt>
  cmp    %eax,0x0(%r13)
  jne    L15
  cmp    $0xa,%eax
  je     L25
L11:
  movslq %r12d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L25:
  movslq %r12d,%rax
  add    $0x1,%r12d
  movb   $0xa,0x0(%rbp,%rax,1)
  jmp    L11
L28:
  mov    $0x3e7,%r12d
  jmp    L11
```

assistant: ```c
int getline_tst(void) {
  int c, i;
  extern char line[];
  for (i = 0; i < 1000 - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {
    line[i] = c;
  }
  if (c == '\n') {
    line[i] = c;
    ++i;
  }
  line[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<graphsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L28
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3e,-0xc(%rbp)
  jle    L39
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3e,-0xc(%rbp)
  jle    L46
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L46:
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int graphsize(char *s) {
  char *p;
  int n;
  if (s[0] == ':')
    p = s + 1;
  else
    p = s;
  n = *p++ - 63;
  if (n > 62) {
    n = *p++ - 63;
    if (n > 62) {
      n = *p++ - 63;
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    } else {
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    }
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<graphsize>:
  endbr64
  mov    %rdi,%rdx
  cmpb   $0x3a,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdx
  movsbl (%rdx),%eax
  sub    $0x3f,%eax
  cmp    $0x3e,%eax
  jle    L9
  movsbl 0x1(%rdx),%eax
  sub    $0x3f,%eax
  cmp    $0x3e,%eax
  jle    L15
  movsbl 0x2(%rdx),%ecx
  sub    $0x3f,%ecx
  shl    $0x6,%ecx
  movsbl 0x3(%rdx),%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  shl    $0x6,%eax
  movsbl 0x4(%rdx),%ecx
  sub    $0x3f,%ecx
  or     %eax,%ecx
  shl    $0x6,%ecx
  movsbl 0x5(%rdx),%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  shl    $0x6,%eax
  movsbl 0x6(%rdx),%ecx
  sub    $0x3f,%ecx
  or     %eax,%ecx
  shl    $0x6,%ecx
  movsbl 0x7(%rdx),%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
  ret
L15:
  shl    $0x6,%eax
  movsbl 0x2(%rdx),%ecx
  sub    $0x3f,%ecx
  or     %eax,%ecx
  shl    $0x6,%ecx
  movsbl 0x3(%rdx),%eax
  sub    $0x3f,%eax
  or     %ecx,%eax
L9:
  ret
```

assistant: ```c
int graphsize(char *s) {
  char *p;
  int n;
  if (s[0] == ':')
    p = s + 1;
  else
    p = s;
  n = *p++ - 63;
  if (n > 62) {
    n = *p++ - 63;
    if (n > 62) {
      n = *p++ - 63;
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    } else {
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    }
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<graphsize>:
  endbr64
  movsbl (%rdi),%eax
  mov    %rdi,%rcx
  cmp    $0x3a,%al
  jne    L12
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rcx
L12:
  sub    $0x3f,%eax
  cmp    $0x3e,%eax
  jle    L28
  movsbl 0x1(%rcx),%edx
  movsbl 0x2(%rcx),%esi
  movsbl 0x3(%rcx),%edi
  sub    $0x3f,%edx
  sub    $0x3f,%esi
  sub    $0x3f,%edi
  cmp    $0x3e,%edx
  jle    L21
  movsbl 0x4(%rcx),%edx
  shl    $0x6,%esi
  movsbl 0x5(%rcx),%eax
  or     %edi,%esi
  shl    $0x6,%esi
  sub    $0x3f,%edx
  sub    $0x3f,%eax
  or     %esi,%edx
  shl    $0x6,%edx
  or     %edx,%eax
  movsbl 0x6(%rcx),%edx
  shl    $0x6,%eax
  sub    $0x3f,%edx
  or     %eax,%edx
  movsbl 0x7(%rcx),%eax
  shl    $0x6,%edx
  sub    $0x3f,%eax
  or     %edx,%eax
  ret
  xchg   %ax,%ax
L21:
  mov    %edx,%eax
  shl    $0x6,%eax
  or     %esi,%eax
  shl    $0x6,%eax
  or     %edi,%eax
L28:
  ret
```

assistant: ```c
int graphsize(char *s) {
  char *p;
  int n;
  if (s[0] == ':')
    p = s + 1;
  else
    p = s;
  n = *p++ - 63;
  if (n > 62) {
    n = *p++ - 63;
    if (n > 62) {
      n = *p++ - 63;
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    } else {
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    }
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<graphsize>:
  endbr64
  movsbl (%rdi),%eax
  mov    %rdi,%rcx
  cmp    $0x3a,%al
  jne    L1
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rcx
L1:
  sub    $0x3f,%eax
  cmp    $0x3e,%eax
  jle    L2
  movsbl 0x1(%rcx),%edx
  movsbl 0x2(%rcx),%esi
  movsbl 0x3(%rcx),%edi
  sub    $0x3f,%edx
  sub    $0x3f,%esi
  sub    $0x3f,%edi
  cmp    $0x3e,%edx
  jle    L9
  movsbl 0x4(%rcx),%edx
  shl    $0x6,%esi
  movsbl 0x5(%rcx),%eax
  or     %edi,%esi
  shl    $0x6,%esi
  sub    $0x3f,%edx
  sub    $0x3f,%eax
  or     %esi,%edx
  shl    $0x6,%edx
  or     %edx,%eax
  movsbl 0x6(%rcx),%edx
  shl    $0x6,%eax
  sub    $0x3f,%edx
  or     %eax,%edx
  movsbl 0x7(%rcx),%eax
  shl    $0x6,%edx
  sub    $0x3f,%eax
  or     %edx,%eax
  ret
  xchg   %ax,%ax
L9:
  mov    %edx,%eax
  shl    $0x6,%eax
  or     %esi,%eax
  shl    $0x6,%eax
  or     %edi,%eax
L2:
  ret
```

assistant: ```c
int graphsize(char *s) {
  char *p;
  int n;
  if (s[0] == ':')
    p = s + 1;
  else
    p = s;
  n = *p++ - 63;
  if (n > 62) {
    n = *p++ - 63;
    if (n > 62) {
      n = *p++ - 63;
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    } else {
      n = (n << 6) | (*p++ - 63);
      n = (n << 6) | (*p++ - 63);
    }
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L6:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jne    L6
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L47
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L4
L47:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D37
datatype: string
name: unpack_data
arguments: label: D29
datatype: string

tool: D17: Digite um inteiro positivo: 

tool: D2: %d

tool: D37: O numero %d e um numero palindromo 


tool: D29: O numero %d nao e um numero palindromo 


assistant: ```c
int main() {
  int num, aux, reverso;
  printf("Digite um inteiro positivo: ");
  scanf("%d", &num);
  aux = num;
  reverso = 0;
  while (aux != 0) {
    reverso = reverso * 10 + aux % 10;
    aux = aux / 10;
  }
  if (reverso == num)
    printf("O numero %d e um numero palindromo \n", num);
  else
    printf("O numero %d nao e um numero palindromo \n", reverso);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L10
  mov    %edi,%edx
  mov    $0x0,%esi
L33:
  lea    (%rsi,%rsi,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%esi
  mov    %eax,%edx
  test   %eax,%eax
  jne    L33
  cmp    %esi,%edi
  je     L21
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L10:
  mov    %edi,%esi
L21:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D7: Digite um inteiro positivo: 

tool: D27: %d

tool: D21: O numero %d nao e um numero palindromo 


tool: D5: O numero %d e um numero palindromo 


assistant: ```c
int main() {
  int num, aux, reverso;
  printf("Digite um inteiro positivo: ");
  scanf("%d", &num);
  aux = num;
  reverso = 0;
  while (aux != 0) {
    reverso = reverso * 10 + aux % 10;
    aux = aux / 10;
  }
  if (reverso == num)
    printf("O numero %d e um numero palindromo \n", num);
  else
    printf("O numero %d nao e um numero palindromo \n", reverso);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L34
  mov    %edi,%edx
  xor    %esi,%esi
  nopl   0x0(%rax)
L19:
  movslq %edx,%rax
  mov    %edx,%ecx
  lea    (%rsi,%rsi,4),%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%esi
  mov    %eax,%edx
  test   %eax,%eax
  jne    L19
  cmp    %esi,%edi
  je     L27
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L34:
  xor    %esi,%esi
L27:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string

tool: D37: Digite um inteiro positivo: 

tool: D20: %d

tool: D25: O numero %d nao e um numero palindromo 


tool: D24: O numero %d e um numero palindromo 


assistant: ```c
int main() {
  int num, aux, reverso;
  printf("Digite um inteiro positivo: ");
  scanf("%d", &num);
  aux = num;
  reverso = 0;
  while (aux != 0) {
    reverso = reverso * 10 + aux % 10;
    aux = aux / 10;
  }
  if (reverso == num)
    printf("O numero %d e um numero palindromo \n", num);
  else
    printf("O numero %d nao e um numero palindromo \n", reverso);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L9
  mov    %edi,%edx
  xor    %esi,%esi
  nopl   0x0(%rax)
L36:
  movslq %edx,%rax
  mov    %edx,%ecx
  lea    (%rsi,%rsi,4),%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%esi
  mov    %eax,%edx
  test   %eax,%eax
  jne    L36
  cmp    %esi,%edi
  je     L14
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  xor    %esi,%esi
L14:
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D33
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D34
type_infered: string

tool: D33: Digite um inteiro positivo: 

tool: D29: %d

tool: D20: O numero %d nao e um numero palindromo 


tool: D34: O numero %d e um numero palindromo 


assistant: ```c
int main() {
  int num, aux, reverso;
  printf("Digite um inteiro positivo: ");
  scanf("%d", &num);
  aux = num;
  reverso = 0;
  while (aux != 0) {
    reverso = reverso * 10 + aux % 10;
    aux = aux / 10;
  }
  if (reverso == num)
    printf("O numero %d e um numero palindromo \n", num);
  else
    printf("O numero %d nao e um numero palindromo \n", reverso);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fmt_o>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L2:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  add    $0x30,%eax
  subq   $0x1,-0x10(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  sarl   $0x3,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *fmt_o(uintmax_t x, char *s) {
  for (; x; x >>= 3)
    *--s = '0' + (x & 7);
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fmt_o>:
  endbr64
  mov    %rsi,%rax
  test   %edi,%edi
  je     L17
L6:
  sub    $0x1,%rax
  mov    %edi,%edx
  and    $0x7,%edx
  add    $0x30,%edx
  mov    %dl,(%rax)
  sar    $0x3,%edi
  jne    L6
L17:
  ret
```

assistant: ```c
char *fmt_o(uintmax_t x, char *s) {
  for (; x; x >>= 3)
    *--s = '0' + (x & 7);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmt_o>:
  endbr64
  mov    %rsi,%rax
  test   %edi,%edi
  je     L11
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %edi,%edx
  sub    $0x1,%rax
  and    $0x7,%edx
  add    $0x30,%edx
  sar    $0x3,%edi
  mov    %dl,(%rax)
  jne    L16
L11:
  ret
```

assistant: ```c
char *fmt_o(uintmax_t x, char *s) {
  for (; x; x >>= 3)
    *--s = '0' + (x & 7);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fmt_o>:
  endbr64
  mov    %rsi,%rax
  test   %edi,%edi
  je     L7
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edi,%edx
  sub    $0x1,%rax
  and    $0x7,%edx
  add    $0x30,%edx
  sar    $0x3,%edi
  mov    %dl,(%rax)
  jne    L3
L7:
  ret
```

assistant: ```c
char *fmt_o(uintmax_t x, char *s) {
  for (; x; x >>= 3)
    *--s = '0' + (x & 7);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_power2p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L33
  mov    $0x1,%eax
  jmp    L14
L33:
  cmpl   $0x2,-0x4(%rbp)
  jne    L55
  mov    $0x1,%eax
  jmp    L14
L55:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L52
  mov    $0x0,%eax
  jmp    L14
L52:
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edi
  call   <_power2p>
L14:
  leave
  ret
```

assistant: ```c
int _power2p(int value) {
  if (value == 0)
    return 1;
  if (value == 2)
    return 1;
  if (value & 0x1)
    return 0;
  return (_power2p(value >> 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_power2p>:
  endbr64
  mov    $0x1,%eax
  test   $0xfffffffd,%edi
  je     L0
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L19
L0:
  ret
L19:
  sub    $0x8,%rsp
  sar    %edi
  call   <_power2p>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _power2p(int value) {
  if (value == 0)
    return 1;
  if (value == 2)
    return 1;
  if (value & 0x1)
    return 0;
  return (_power2p(value >> 1));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_power2p>:
  endbr64
  test   $0xfffffffd,%edi
  je     L7
  mov    %edi,%eax
  and    $0x1,%eax
  je     L33
  jmp    L48
  nopl   (%rax)
L1:
  test   $0x1,%dil
  jne    L41
L33:
  sar    %edi
  test   $0xfffffffd,%edi
  jne    L1
L7:
  mov    $0x1,%eax
  ret
L48:
  xor    %eax,%eax
L41:
  ret
```

assistant: ```c
int _power2p(int value) {
  if (value == 0)
    return 1;
  if (value == 2)
    return 1;
  if (value & 0x1)
    return 0;
  return (_power2p(value >> 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<_power2p>:
  endbr64
  test   $0xfffffffd,%edi
  je     L15
  mov    %edi,%eax
  and    $0x1,%eax
  je     L28
  jmp    L36
  nopl   (%rax)
L8:
  test   $0x1,%dil
  jne    L14
L28:
  sar    %edi
  test   $0xfffffffd,%edi
  jne    L8
L15:
  mov    $0x1,%eax
  ret
L36:
  xor    %eax,%eax
L14:
  ret
```

assistant: ```c
int _power2p(int value) {
  if (value == 0)
    return 1;
  if (value == 2)
    return 1;
  if (value & 0x1)
    return 0;
  return (_power2p(value >> 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atomic_xchg64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  xchg   %rax,(%rdx)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t atomic_xchg64(void *ptr, uint64_t x) {
  __asm__ __volatile__("xchgq %0,%1" : "=r"(x) : "m"(*(volatile uint64_t *)ptr), "0"(x) : "memory");
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atomic_xchg64>:
  endbr64
  mov    %rsi,%rax
  xchg   %rax,(%rdi)
  ret
```

assistant: ```c
uint64_t atomic_xchg64(void *ptr, uint64_t x) {
  __asm__ __volatile__("xchgq %0,%1" : "=r"(x) : "m"(*(volatile uint64_t *)ptr), "0"(x) : "memory");
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atomic_xchg64>:
  endbr64
  mov    %rsi,%rax
  xchg   %rax,(%rdi)
  ret
```

assistant: ```c
uint64_t atomic_xchg64(void *ptr, uint64_t x) {
  __asm__ __volatile__("xchgq %0,%1" : "=r"(x) : "m"(*(volatile uint64_t *)ptr), "0"(x) : "memory");
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atomic_xchg64>:
  endbr64
  mov    %rsi,%rax
  xchg   %rax,(%rdi)
  ret
```

assistant: ```c
uint64_t atomic_xchg64(void *ptr, uint64_t x) {
  __asm__ __volatile__("xchgq %0,%1" : "=r"(x) : "m"(*(volatile uint64_t *)ptr), "0"(x) : "memory");
  return x;
}
```