ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L99
L48:
  addq   $0x1,-0x18(%rbp)
L99:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L48
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L48
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L48
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L48
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L122:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L122
  subq   $0x1,-0x8(%rbp)
  jmp    L113
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
L80:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L113:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L21
L11:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strip(char *s) {
  char *s2;
  while (*s == '\t' || *s == ' ' || *s == '\r' || *s == '\n')
    s++;
  for (s2 = s; *s2; s2++)
    ;
  for (s2--; s2 >= s; s2--)
    if (*s2 == '\t' || *s2 == ' ' || *s2 == '\r' || *s2 == '\n')
      *s2 = 0;
    else
      break;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  ja     L3
  movabs $0x100002600,%rcx
  bt     %rdx,%rcx
  jb     L75
  jmp    L3
L100:
  bt     %rdx,%rcx
  jae    L3
L75:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L100
L3:
  cmpb   $0x0,(%rax)
  je     L17
  mov    %rax,%rdx
L20:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L20
L64:
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jb     L95
  lea    -0x1(%rax),%rdi
  movabs $0x100002600,%rsi
  jmp    L90
L17:
  mov    %rax,%rdx
  jmp    L64
L15:
  bt     %rcx,%rsi
  jae    L95
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L95
L90:
  movzbl (%rdx),%ecx
  cmp    $0x20,%cl
  jbe    L15
L95:
  ret
```

assistant: ```c
char *strip(char *s) {
  char *s2;
  while (*s == '\t' || *s == ' ' || *s == '\r' || *s == '\n')
    s++;
  for (s2 = s; *s2; s2++)
    ;
  for (s2--; s2 >= s; s2--)
    if (*s2 == '\t' || *s2 == ' ' || *s2 == '\r' || *s2 == '\n')
      *s2 = 0;
    else
      break;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strip>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  ja     L30
  movabs $0xfffffffeffffd9ff,%rdx
  nopl   (%rax)
L12:
  bt     %rax,%rdx
  jb     L42
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jbe    L12
L30:
  mov    %rdi,%r8
  nopl   (%rax)
L95:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L95
L76:
  movabs $0xfffffffeffffd9ff,%rcx
  cmp    %r8,%rax
  jb     L45
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L91
L45:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L91:
  bt     %rdx,%rcx
  jb     L45
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %r8,%rax
  jae    L44
  mov    %r8,%rax
  ret
L42:
  test   %al,%al
  jne    L30
  lea    -0x1(%rdi),%rax
  mov    %rdi,%r8
  jmp    L76
```

assistant: ```c
char *strip(char *s) {
  char *s2;
  while (*s == '\t' || *s == ' ' || *s == '\r' || *s == '\n')
    s++;
  for (s2 = s; *s2; s2++)
    ;
  for (s2--; s2 >= s; s2--)
    if (*s2 == '\t' || *s2 == ' ' || *s2 == '\r' || *s2 == '\n')
      *s2 = 0;
    else
      break;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  ja     L28
  movabs $0xfffffffeffffd9ff,%rdx
  nopl   (%rax)
L57:
  bt     %rax,%rdx
  jb     L29
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jbe    L57
L28:
  mov    %rdi,%r8
L76:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L76
L5:
  movabs $0xfffffffeffffd9ff,%rcx
  cmp    %r8,%rax
  jb     L83
  nopl   0x0(%rax,%rax,1)
L48:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L51
L83:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L51:
  bt     %rdx,%rcx
  jb     L83
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%r8
  jbe    L48
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  test   %al,%al
  jne    L28
  lea    -0x1(%rdi),%rax
  mov    %rdi,%r8
  jmp    L5
```

assistant: ```c
char *strip(char *s) {
  char *s2;
  while (*s == '\t' || *s == ' ' || *s == '\r' || *s == '\n')
    s++;
  for (s2 = s; *s2; s2++)
    ;
  for (s2--; s2 >= s; s2--)
    if (*s2 == '\t' || *s2 == ' ' || *s2 == '\r' || *s2 == '\n')
      *s2 = 0;
    else
      break;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L15:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L8
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *dest, int c, size_t n) {
  unsigned char c8 = n;
  unsigned char *target = dest;
  while (n--)
    *target++ = c8;
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%esi
  test   %rdx,%rdx
  je     L9
  add    %rdi,%rdx
  mov    %rdi,%rcx
L4:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L4
L9:
  ret
```

assistant: ```c
void *memset(void *dest, int c, size_t n) {
  unsigned char c8 = n;
  unsigned char *target = dest;
  while (n--)
    *target++ = c8;
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L9
  sub    $0x8,%rsp
  movzbl %dl,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int c, size_t n) {
  unsigned char c8 = n;
  unsigned char *target = dest;
  while (n--)
    *target++ = c8;
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L6
  sub    $0x8,%rsp
  movzbl %dl,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int c, size_t n) {
  unsigned char c8 = n;
  unsigned char *target = dest;
  while (n--)
    *target++ = c8;
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<slurp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L31
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %eax,%eax
  jne    L51
L34:
  mov    0x4(%rsp),%r13d
  movslq %r13d,%r14
  lea    0x1(%r14),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L81
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    %eax,%r13d
  jne    L4
  movb   $0x0,(%rbx,%r14,1)
  mov    %r12,%rdi
  call   <fclose@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rbx
  jmp    L25
L51:
  mov    $0x15e,%esi
  lea    D28(%rip),%rdi
  call   <valgrind_assert_failed@plt>
  jmp    L34
L81:
  mov    %rbp,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L4:
  movslq %r13d,%rsi
  mov    %rbp,%rdx
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L25
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D48
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string

tool: D48: r

tool: D4: slurp(): could not read from: %s


tool: D28: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c

tool: D26: slurp(): could not allocate memory for: %s


tool: D30: could not read all %li bytes from file: %s


assistant: ```c
char *slurp(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file == NULL) {
    printf("slurp(): could not read from: %s\n", filename);
    return NULL;
  }
  struct stat s;
  int rc = stat(filename, &s);
  if (!(rc == 0)) {
    valgrind_assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c", 350);
  };
  off_t length = s.st_size;
  char *result = malloc((size_t)length + 1);
  if (result == NULL) {
    printf("slurp(): could not allocate memory for: %s\n", filename);
    return NULL;
  }
  char *p = result;
  int actual = (int)fread(p, sizeof(char), (size_t)length, file);
  if (actual != length) {
    printf("could not read all %li bytes from file: %s\n", (long)length, filename);
    free(result);
    return NULL;
  }
  result[length] = '\0';
  fclose(file);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<slurp>:
  endbr64
  push   %r14
  lea    D18(%rip),%rsi
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L11
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <stat@plt>
  test   %eax,%eax
  jne    L66
L20:
  movslq 0x4(%rsp),%r13
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L65
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    %eax,%r13d
  jne    L36
  movb   $0x0,(%r12,%r13,1)
  mov    %rbp,%rdi
  call   <fclose@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  mov    $0x15e,%esi
  lea    D33(%rip),%rdi
  call   <valgrind_assert_failed@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r14,%rdx
  mov    %r13,%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L12
  nopl   0x0(%rax)
L11:
  mov    %r14,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L12
L5:
  call   <__stack_chk_fail@plt>
L65:
  mov    %r14,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D33
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D3
data_type: string
name: read_data
arguments: tag: D13
data_type: string

tool: D18: r

tool: D33: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c

tool: D39: could not read all %li bytes from file: %s


tool: D3: slurp(): could not read from: %s


tool: D13: slurp(): could not allocate memory for: %s


assistant: ```c
char *slurp(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file == NULL) {
    printf("slurp(): could not read from: %s\n", filename);
    return NULL;
  }
  struct stat s;
  int rc = stat(filename, &s);
  if (!(rc == 0)) {
    valgrind_assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c", 350);
  };
  off_t length = s.st_size;
  char *result = malloc((size_t)length + 1);
  if (result == NULL) {
    printf("slurp(): could not allocate memory for: %s\n", filename);
    return NULL;
  }
  char *p = result;
  int actual = (int)fread(p, sizeof(char), (size_t)length, file);
  if (actual != length) {
    printf("could not read all %li bytes from file: %s\n", (long)length, filename);
    free(result);
    return NULL;
  }
  result[length] = '\0';
  fclose(file);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<slurp>:
  endbr64
  push   %r14
  lea    D37(%rip),%rsi
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L73
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <stat@plt>
  test   %eax,%eax
  jne    L6
L29:
  movslq 0x4(%rsp),%r13
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    %eax,%r13d
  jne    L22
  movb   $0x0,(%r12,%r13,1)
  mov    %rbp,%rdi
  call   <fclose@plt>
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x15e,%esi
  lea    D25(%rip),%rdi
  call   <valgrind_assert_failed@plt>
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r14,%rdx
  mov    %r13,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L53
  nopl   0x0(%rax)
L73:
  mov    %r14,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L53
L78:
  call   <__stack_chk_fail@plt>
L2:
  mov    %r14,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L53
```

tool_calls: name: disassemble_data
arguments: label: D37
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D6
type: string
name: disassemble_data
arguments: label: D3
type: string

tool: D37: r

tool: D25: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c

tool: D23: could not read all %li bytes from file: %s


tool: D6: slurp(): could not read from: %s


tool: D3: slurp(): could not allocate memory for: %s


assistant: ```c
char *slurp(const char *filename) {
  FILE *file = fopen(filename, "r");
  if (file == NULL) {
    printf("slurp(): could not read from: %s\n", filename);
    return NULL;
  }
  struct stat s;
  int rc = stat(filename, &s);
  if (!(rc == 0)) {
    valgrind_assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/swift-lang/swift-t/refs/heads/master/c-utils/code/src/tools.c", 350);
  };
  off_t length = s.st_size;
  char *result = malloc((size_t)length + 1);
  if (result == NULL) {
    printf("slurp(): could not allocate memory for: %s\n", filename);
    return NULL;
  }
  char *p = result;
  int actual = (int)fread(p, sizeof(char), (size_t)length, file);
  if (actual != length) {
    printf("could not read all %li bytes from file: %s\n", (long)length, filename);
    free(result);
    return NULL;
  }
  result[length] = '\0';
  fclose(file);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gfarm_hash_key_equal_casefold_strptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L17
  mov    $0x0,%eax
  jmp    L18
L17:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  je     L13
  mov    $0x0,%eax
  jmp    L18
L13:
  mov    -0x34(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <gfarm_hash_key_equal_casefold@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int gfarm_hash_key_equal_casefold_strptr(const void *key1, int key1len, const void *key2, int key2len) {
  const char *const *strptr1 = key1, *const *strptr2 = key2;
  const char *str1 = *strptr1, *str2 = *strptr2;
  int len1, len2;
  if (tolower(*(unsigned char *)str1) != tolower(*(unsigned char *)str2))
    return (0);
  len1 = strlen(str1);
  len2 = strlen(str2);
  if (len1 != len2)
    return (0);
  return (gfarm_hash_key_equal_casefold(str1, len1, str2, len2));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gfarm_hash_key_equal_casefold_strptr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rbp
  mov    (%rdx),%r12
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rbx
  je     L2
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    $0x0,%eax
  cmp    %ecx,%ebx
  jne    L29
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <gfarm_hash_key_equal_casefold@plt>
  jmp    L29
```

assistant: ```c
int gfarm_hash_key_equal_casefold_strptr(const void *key1, int key1len, const void *key2, int key2len) {
  const char *const *strptr1 = key1, *const *strptr2 = key2;
  const char *str1 = *strptr1, *str2 = *strptr2;
  int len1, len2;
  if (tolower(*(unsigned char *)str1) != tolower(*(unsigned char *)str2))
    return (0);
  len1 = strlen(str1);
  len2 = strlen(str2);
  if (len1 != len2)
    return (0);
  return (gfarm_hash_key_equal_casefold(str1, len1, str2, len2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gfarm_hash_key_equal_casefold_strptr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    (%rdx),%r12
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L16
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jne    L13
  add    $0x8,%rsp
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <gfarm_hash_key_equal_casefold@plt>
```

assistant: ```c
int gfarm_hash_key_equal_casefold_strptr(const void *key1, int key1len, const void *key2, int key2len) {
  const char *const *strptr1 = key1, *const *strptr2 = key2;
  const char *str1 = *strptr1, *str2 = *strptr2;
  int len1, len2;
  if (tolower(*(unsigned char *)str1) != tolower(*(unsigned char *)str2))
    return (0);
  len1 = strlen(str1);
  len2 = strlen(str2);
  if (len1 != len2)
    return (0);
  return (gfarm_hash_key_equal_casefold(str1, len1, str2, len2));
}
```
user: What is the c source code of the assembly code below?

```asm
<gfarm_hash_key_equal_casefold_strptr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    (%rdx),%r12
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L5
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jne    L3
  add    $0x8,%rsp
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <gfarm_hash_key_equal_casefold@plt>
```

assistant: ```c
int gfarm_hash_key_equal_casefold_strptr(const void *key1, int key1len, const void *key2, int key2len) {
  const char *const *strptr1 = key1, *const *strptr2 = key2;
  const char *str1 = *strptr1, *str2 = *strptr2;
  int len1, len2;
  if (tolower(*(unsigned char *)str1) != tolower(*(unsigned char *)str2))
    return (0);
  len1 = strlen(str1);
  len2 = strlen(str2);
  if (len1 != len2)
    return (0);
  return (gfarm_hash_key_equal_casefold(str1, len1, str2, len2));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1ff,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: /tmp/moo

assistant: ```c
int main(int argc, char **argv) {
  mkdir("/tmp/moo", 0777);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ff,%esi
  lea    D3(%rip),%rdi
  call   <mkdir@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: /tmp/moo

assistant: ```c
int main(int argc, char **argv) {
  mkdir("/tmp/moo", 0777);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ff,%esi
  lea    D2(%rip),%rdi
  call   <mkdir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string

tool: D2: /tmp/moo

assistant: ```c
int main(int argc, char **argv) {
  mkdir("/tmp/moo", 0777);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ff,%esi
  lea    D0(%rip),%rdi
  call   <mkdir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: /tmp/moo

assistant: ```c
int main(int argc, char **argv) {
  mkdir("/tmp/moo", 0777);
  return 0;
}
```