user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<FormatCCF>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  mov    %rdi,%rbp
  test   %al,%al
  je     L108
  movabs $0xf8000001fc00fffe,%rsi
  mov    %rdi,%rdx
  jmp    L286
  nopl   0x0(%rax)
L135:
  lea    -0x20(%rax),%ecx
  sub    $0x40,%eax
  mov    %cl,(%rdx)
L256:
  bt     %rax,%rsi
  jb     L63
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L239
L286:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  jbe    L135
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  and    $0xfffffffd,%ecx
  cmp    $0x8,%cl
  je     L214
  cmp    $0xd,%al
  jne    L243
L214:
  movb   $0x20,(%rdx)
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L286
L239:
  movzbl 0x0(%rbp),%ecx
  xor    %eax,%eax
  test   %cl,%cl
  je     L108
  nopl   0x0(%rax,%rax,1)
L157:
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x20,%cl
  jne    L271
  nop
L226:
  mov    %edx,%eax
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    $0x20,%cl
  je     L226
  test   %cl,%cl
  jne    L271
L68:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x20,%cl
  jne    L150
  nop
L164:
  mov    %edx,%eax
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    $0x20,%cl
  je     L164
  test   %cl,%cl
  je     L51
L184:
  movslq %ebx,%rdx
  add    $0x1,%eax
  add    $0x1,%ebx
  mov    %cl,(%rsp,%rdx,1)
L51:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    $0x20,%cl
  jne    L10
  nopl   0x0(%rax,%rax,1)
L78:
  mov    %edx,%eax
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    $0x20,%cl
  je     L78
L10:
  lea    0x1(%rbx),%esi
  test   %cl,%cl
  je     L201
  lea    0x1(%rax),%edx
  movslq %ebx,%rbx
  mov    %cl,(%rsp,%rbx,1)
  movslq %edx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%ecx
  cmp    $0x20,%cl
  jne    L277
  lea    0x2(%rax),%edx
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L309:
  mov    %edx,%eax
  add    $0x1,%rdx
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    $0x20,%cl
  je     L309
L253:
  test   %cl,%cl
  je     L130
  movslq %esi,%rdx
  add    $0x1,%eax
  add    $0x1,%esi
  mov    %cl,(%rsp,%rdx,1)
L130:
  movslq %eax,%rdx
  lea    0x1(%rsi),%ebx
  movslq %esi,%rsi
  movzbl 0x0(%rbp,%rdx,1),%ecx
  movb   $0x20,(%rsp,%rsi,1)
  test   %cl,%cl
  jne    L157
L108:
  mov    %rsp,%r13
  movslq %ebx,%rax
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%rax,1)
  call   <strlen@plt>
  cmp    $0x17,%eax
  jle    L283
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%r12
  cltd
  imul   $0x66666667,%r12,%r12
  sar    $0x21,%r12
  sub    %edx,%r12d
  lea    (%r12,%r12,4),%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  jne    L283
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    $0x1414,%eax
  jg     L283
  lea    -0x1(%rbx),%eax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <strcpy@plt>
  jmp    L220
  nopw   0x0(%rax,%rax,1)
L243:
  sub    $0x20,%eax
  cmp    $0x3a,%al
  jbe    L256
L63:
  mov    $0x2d,%r12d
L220:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x2728,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L283:
  mov    $0x2b,%r12d
  jmp    L220
L271:
  movslq %ebx,%rdx
  add    $0x1,%eax
  add    $0x1,%ebx
  mov    %cl,(%rsp,%rdx,1)
  jmp    L68
  nopl   0x0(%rax)
L201:
  movslq %eax,%rdx
  mov    %ebx,%esi
  movzbl 0x0(%rbp,%rdx,1),%ecx
  jmp    L253
  nopw   0x0(%rax,%rax,1)
L150:
  test   %cl,%cl
  jne    L184
  xor    %ecx,%ecx
  jmp    L10
L277:
  mov    %edx,%eax
  jmp    L253
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int FormatCCF(char *ccf) {
  char st[10000];
  int j, i;
  i = 0;
  while (ccf[i]) {
    if (ccf[i] >= 'a' && ccf[i] <= 'z')
      ccf[i] -= 'a' - 'A';
    if (ccf[i] == 13 || ccf[i] == 10 || ccf[i] == 8)
      ccf[i] = ' ';
    if ((ccf[i] < '0' || ccf[i] > '9') && (ccf[i] < 'A' || ccf[i] > 'Z') && ccf[i] != ' ') {
      return (45);
    }
    i++;
  }
  i = 0;
  while (ccf[i]) {
    while (ccf[i] == ' ')
      i++;
    if (ccf[i])
      st[j++] = ccf[i++];
    while (ccf[i] == ' ')
      i++;
    if (ccf[i])
      st[j++] = ccf[i++];
    while (ccf[i] == ' ')
      i++;
    if (ccf[i])
      st[j++] = ccf[i++];
    while (ccf[i] == ' ')
      i++;
    if (ccf[i])
      st[j++] = ccf[i++];
    st[j++] = ' ';
  }
  st[j] = 0;
  if (strlen(st) < 24 || (strlen(st) % 5) || strlen(st) > 5140)
    return (43);
  st[j - 1] = 0;
  strcpy(ccf, st);
  return (0);
}
```