ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mischia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L23
L7:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <irand@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x0,-0xc(%rbp)
  jg     L7
  nop
  leave
  ret
```

assistant: ```c
void mischia(int *carte, int N) {
  int i, comodo, x;
  for (i = 0; i < N; i++)
    carte[i] = i;
  for (i = (N - 1); i > 0; i--) {
    x = irand(i + 1);
    comodo = carte[i];
    carte[i] = carte[x];
    carte[x] = comodo;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mischia>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %esi,%esi
  jle    L1
  mov    %esi,%edx
  mov    $0x0,%eax
L18:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L1:
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L39
  movslq %esi,%rbx
L2:
  lea    0x1(%rbx),%edi
  call   <irand@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  mov    %edx,(%rax)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L2
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mischia(int *carte, int N) {
  int i, comodo, x;
  for (i = 0; i < N; i++)
    carte[i] = i;
  for (i = (N - 1); i > 0; i--) {
    x = irand(i + 1);
    comodo = carte[i];
    carte[i] = carte[x];
    carte[x] = comodo;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mischia>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L29
  movslq %esi,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
L29:
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L25
  movslq %esi,%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  lea    0x1(%rbx),%edi
  call   <irand@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  mov    %edx,(%rax)
  test   %ebx,%ebx
  jg     L14
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mischia(int *carte, int N) {
  int i, comodo, x;
  for (i = 0; i < N; i++)
    carte[i] = i;
  for (i = (N - 1); i > 0; i--) {
    x = irand(i + 1);
    comodo = carte[i];
    carte[i] = carte[x];
    carte[x] = comodo;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mischia>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L7
  cmp    $0x2,%ebx
  jbe    L29
  mov    %esi,%edx
  movdqa D3(%rip),%xmm0
  movdqa D12(%rip),%xmm2
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   (%rax)
L80:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L80
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L73
L8:
  movslq %eax,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L7
  add    $0x2,%eax
  mov    %edx,0x4(%rbp,%rcx,1)
  cmp    %eax,%esi
  jle    L73
  mov    %eax,0x8(%rbp,%rcx,1)
L73:
  movslq %ebx,%rbx
L16:
  lea    0x1(%rbx),%edi
  call   <irand@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  mov    %edx,(%rax)
  test   %ebx,%ebx
  jg     L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  test   %ebx,%ebx
  jg     L73
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  xor    %eax,%eax
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: byte[16]
name: unpack_data
arguments: data_tag: D12
type_infered: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void mischia(int *carte, int N) {
  int i, comodo, x;
  for (i = 0; i < N; i++)
    carte[i] = i;
  for (i = (N - 1); i > 0; i--) {
    x = irand(i + 1);
    comodo = carte[i];
    carte[i] = carte[x];
    carte[x] = comodo;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extractfilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L29
L2:
  addq   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L32
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L28
L32:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L28:
  nop
  leave
  ret
```

assistant: ```c
void extractfilename(char *name, char *path) {
  char *pFile = strrchr(path, '/');
  if (pFile == NULL)
    pFile = path;
  else
    pFile = pFile + 1;
  char *pExt = strrchr(pFile, '.');
  if (pExt != NULL)
    strncpy(name, pFile, pExt - pFile);
  else
    strcpy(name, pFile);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extractfilename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  mov    %eax,%edx
  sub    %ebx,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L2
```

assistant: ```c
void extractfilename(char *name, char *path) {
  char *pFile = strrchr(path, '/');
  if (pFile == NULL)
    pFile = path;
  else
    pFile = pFile + 1;
  char *pExt = strrchr(pFile, '.');
  if (pExt != NULL)
    strncpy(name, pFile, pExt - pFile);
  else
    strcpy(name, pFile);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extractfilename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%rbp
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <strncpy@plt>
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
```

assistant: ```c
void extractfilename(char *name, char *path) {
  char *pFile = strrchr(path, '/');
  if (pFile == NULL)
    pFile = path;
  else
    pFile = pFile + 1;
  char *pExt = strrchr(pFile, '.');
  if (pExt != NULL)
    strncpy(name, pFile, pExt - pFile);
  else
    strcpy(name, pFile);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<extractfilename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    $0x2e,%esi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%rbp
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <strncpy@plt>
  nopl   0x0(%rax)
L1:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
```

assistant: ```c
void extractfilename(char *name, char *path) {
  char *pFile = strrchr(path, '/');
  if (pFile == NULL)
    pFile = path;
  else
    pFile = pFile + 1;
  char *pExt = strrchr(pFile, '.');
  if (pExt != NULL)
    strncpy(name, pFile, pExt - pFile);
  else
    strcpy(name, pFile);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matrix_transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L12:
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L36:
  mov    -0x4(%rbp),%eax
  cltq
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  imul   -0x28(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L36
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_transpose(double *res, double *a, size_t n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      res[i * n + j] = a[j * n + i];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matrix_transpose>:
  endbr64
  test   %rdx,%rdx
  je     L24
  lea    0x0(,%rdx,8),%r8
  add    %r8,%rdi
  mov    %rdx,%r10
  neg    %r10
  shl    $0x3,%r10
  mov    $0x0,%r9d
L19:
  lea    (%rdi,%r10,1),%rax
  mov    %rsi,%rcx
L11:
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rax)
  add    %r8,%rcx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L11
  add    $0x1,%r9
  add    $0x8,%rsi
  add    %r8,%rdi
  cmp    %r9,%rdx
  jne    L19
L24:
  ret
```

assistant: ```c
void matrix_transpose(double *res, double *a, size_t n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      res[i * n + j] = a[j * n + i];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix_transpose>:
  endbr64
  test   %rdx,%rdx
  je     L0
  lea    0x0(,%rdx,8),%r8
  xor    %r9d,%r9d
  add    %r8,%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  mov    %rsi,%rcx
  sub    %r8,%rax
  nopl   0x0(%rax)
L10:
  movsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    %r8,%rcx
  movsd  %xmm0,-0x8(%rax)
  cmp    %rdi,%rax
  jne    L10
  add    $0x1,%r9
  add    $0x8,%rsi
  add    %r8,%rdi
  cmp    %r9,%rdx
  jne    L2
L0:
  ret
```

assistant: ```c
void matrix_transpose(double *res, double *a, size_t n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      res[i * n + j] = a[j * n + i];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_transpose>:
  endbr64
  test   %rdx,%rdx
  je     L18
  lea    0x0(,%rdx,8),%r8
  xor    %r9d,%r9d
  add    %r8,%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  mov    %rsi,%rcx
  sub    %r8,%rax
  nopl   0x0(%rax)
L13:
  movsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    %r8,%rcx
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdi
  jne    L13
  add    $0x1,%r9
  add    $0x8,%rsi
  add    %r8,%rdi
  cmp    %r9,%rdx
  jne    L2
L18:
  ret
```

assistant: ```c
void matrix_transpose(double *res, double *a, size_t n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      res[i * n + j] = a[j * n + i];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filter_error_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9:  Upgrade your browser extension so you can enter it.

assistant: ```c
void filter_error_message(char *message) {
  char *nullit;
  nullit = strstr(message, " Upgrade your browser extension so you can enter it.");
  if (nullit)
    *nullit = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filter_error_message>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0:  Upgrade your browser extension so you can enter it.

assistant: ```c
void filter_error_message(char *message) {
  char *nullit;
  nullit = strstr(message, " Upgrade your browser extension so you can enter it.");
  if (nullit)
    *nullit = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<filter_error_message>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1:  Upgrade your browser extension so you can enter it.

assistant: ```c
void filter_error_message(char *message) {
  char *nullit;
  nullit = strstr(message, " Upgrade your browser extension so you can enter it.");
  if (nullit)
    *nullit = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filter_error_message>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6:  Upgrade your browser extension so you can enter it.

assistant: ```c
void filter_error_message(char *message) {
  char *nullit;
  nullit = strstr(message, " Upgrade your browser extension so you can enter it.");
  if (nullit)
    *nullit = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_pattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L12
  mov    $0xffffffff,%eax
  jmp    L4
L12:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L37
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int check_pattern(unsigned char *buf, unsigned char pattern, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (buf[i] != pattern)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_pattern>:
  endbr64
  test   %edx,%edx
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L0:
  cmp    %sil,(%rax)
  jne    L26
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
  mov    $0x0,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
L26:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int check_pattern(unsigned char *buf, unsigned char pattern, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (buf[i] != pattern)
      return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_pattern>:
  endbr64
  test   %edx,%edx
  jle    L2
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L2
L1:
  cmp    %sil,(%rdi)
  je     L26
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_pattern(unsigned char *buf, unsigned char pattern, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (buf[i] != pattern)
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_pattern>:
  endbr64
  test   %edx,%edx
  jle    L19
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L19
L11:
  cmp    %sil,(%rdi)
  je     L2
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_pattern(unsigned char *buf, unsigned char pattern, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (buf[i] != pattern)
      return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movabs $0x8888888888888889,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x5,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x63,-0x8(%rbp)
  jbe    L15
  lea    D12(%rip),%rax
  jmp    L4
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D37(%rip),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D30(%rip),%rax
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D37
type: string

tool: D12: 99:59+

tool: D37: %2lu:%02lu 

assistant: ```c
char *time_string(unsigned long seconds) {
  static char buffer[10];
  unsigned long minutes;
  minutes = seconds / 60;
  seconds %= 60;
  if (minutes > 99)
    return "99:59+";
  sprintf(buffer, "%2lu:%02lu ", minutes, seconds);
  return buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<time_string>:
  endbr64
  lea    D17(%rip),%rax
  cmp    $0x176f,%rdi
  jbe    L6
  ret
L6:
  push   %rbx
  movabs $0x8888888888888889,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rdi,%rcx
  sub    %rax,%rcx
  lea    D2(%rip),%rsi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D17: 99:59+

tool: D2: %2lu:%02lu 

assistant: ```c
char *time_string(unsigned long seconds) {
  static char buffer[10];
  unsigned long minutes;
  minutes = seconds / 60;
  seconds %= 60;
  if (minutes > 99)
    return "99:59+";
  sprintf(buffer, "%2lu:%02lu ", minutes, seconds);
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<time_string>:
  endbr64
  cmp    $0x176f,%rdi
  jbe    L6
  lea    D1(%rip),%rax
  ret
  nopl   (%rax)
L6:
  mov    %rdi,%rax
  push   %rbx
  mov    %rdi,%rcx
  lea    D6(%rip),%rbx
  movabs $0x8888888888888889,%rdx
  mov    %rbx,%rdi
  lea    D19(%rip),%rsi
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D1: 99:59+

tool: D19: %2lu:%02lu 

assistant: ```c
char *time_string(unsigned long seconds) {
  static char buffer[10];
  unsigned long minutes;
  minutes = seconds / 60;
  seconds %= 60;
  if (minutes > 99)
    return "99:59+";
  sprintf(buffer, "%2lu:%02lu ", minutes, seconds);
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<time_string>:
  endbr64
  cmp    $0x176f,%rdi
  jbe    L4
  lea    D18(%rip),%rax
  ret
  nopl   (%rax)
L4:
  mov    %rdi,%rax
  push   %rbx
  mov    %rdi,%rcx
  lea    D13(%rip),%rbx
  movabs $0x8888888888888889,%rdx
  mov    %rbx,%rdi
  lea    D19(%rip),%rsi
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D18: 99:59+

tool: D19: %2lu:%02lu 

assistant: ```c
char *time_string(unsigned long seconds) {
  static char buffer[10];
  unsigned long minutes;
  minutes = seconds / 60;
  seconds %= 60;
  if (minutes > 99)
    return "99:59+";
  sprintf(buffer, "%2lu:%02lu ", minutes, seconds);
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MonthFromTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <DayWithinYear@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <InLeapYear@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1e,-0x8(%rbp)
  jg     L61
  mov    $0x0,%eax
  jmp    L44
L61:
  mov    -0x4(%rbp),%eax
  add    $0x3a,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L194
  mov    $0x1,%eax
  jmp    L44
L194:
  mov    -0x4(%rbp),%eax
  add    $0x59,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L52
  mov    $0x2,%eax
  jmp    L44
L52:
  mov    -0x4(%rbp),%eax
  add    $0x77,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L127
  mov    $0x3,%eax
  jmp    L44
L127:
  mov    -0x4(%rbp),%eax
  add    $0x96,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L12
  mov    $0x4,%eax
  jmp    L44
L12:
  mov    -0x4(%rbp),%eax
  add    $0xb4,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L40
  mov    $0x5,%eax
  jmp    L44
L40:
  mov    -0x4(%rbp),%eax
  add    $0xd3,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L106
  mov    $0x6,%eax
  jmp    L44
L106:
  mov    -0x4(%rbp),%eax
  add    $0xf2,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L156
  mov    $0x7,%eax
  jmp    L44
L156:
  mov    -0x4(%rbp),%eax
  add    $0x110,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L3
  mov    $0x8,%eax
  jmp    L44
L3:
  mov    -0x4(%rbp),%eax
  add    $0x12f,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L4
  mov    $0x9,%eax
  jmp    L44
L4:
  mov    -0x4(%rbp),%eax
  add    $0x14d,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L67
  mov    $0xa,%eax
  jmp    L44
L67:
  mov    $0xb,%eax
L44:
  leave
  ret
```

assistant: ```c
int MonthFromTime(double t) {
  int day = DayWithinYear(t);
  int leap = InLeapYear(t);
  if (day < 31)
    return 0;
  if (day < 59 + leap)
    return 1;
  if (day < 90 + leap)
    return 2;
  if (day < 120 + leap)
    return 3;
  if (day < 151 + leap)
    return 4;
  if (day < 181 + leap)
    return 5;
  if (day < 212 + leap)
    return 6;
  if (day < 243 + leap)
    return 7;
  if (day < 273 + leap)
    return 8;
  if (day < 304 + leap)
    return 9;
  if (day < 334 + leap)
    return 10;
  return 11;
}
```