ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readln>:
  endbr64
  test   %edx,%edx
  jle    L67
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  je     L52
  lea    -0x1(%rdx),%r12d
  mov    %edi,%ebp
  mov    %rsi,%r13
  add    %rsi,%r12
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L66:
  sub    %ebx,%eax
  add    %r13d,%eax
  cmpb   $0xa,0x0(%r13)
  je     L17
  add    $0x1,%r13
  cmp    %r12,%r13
  je     L44
L58:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L66
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L44:
  add    $0x1,%eax
L17:
  movb   $0x0,0x1(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    $0x1,%eax
  mov    %rsi,%r13
  jmp    L17
L67:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readln(int fd, char *buf, int cnt) {
  int i, rcnt = 0;
  if (cnt < 1)
    return -1;
  while (cnt >= 2) {
    i = read(fd, buf, 1);
    if (i != 1)
      return i;
    if (*buf == '\n')
      break;
    rcnt++;
    buf++;
    cnt--;
  }
  *++buf = '\0';
  rcnt++;
  return rcnt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ctz64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  xor    %eax,%eax
  tzcnt  -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t ctz64(uint64_t x) {
  assert(x != 0);
  return __builtin_ctzl(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ctz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  tzcnt  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t ctz64(uint64_t x) {
  assert(x != 0);
  return __builtin_ctzl(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ctz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  tzcnt  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t ctz64(uint64_t x) {
  assert(x != 0);
  return __builtin_ctzl(x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ctz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %eax,%eax
  tzcnt  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t ctz64(uint64_t x) {
  assert(x != 0);
  return __builtin_ctzl(x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<restaure_term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int restaure_term(struct termios *initial_term) {
  tcsetattr(0, TCSANOW, initial_term);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<restaure_term>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int restaure_term(struct termios *initial_term) {
  tcsetattr(0, TCSANOW, initial_term);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<restaure_term>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    %rdi,%rdx
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int restaure_term(struct termios *initial_term) {
  tcsetattr(0, TCSANOW, initial_term);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<restaure_term>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    %rdi,%rdx
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int restaure_term(struct termios *initial_term) {
  tcsetattr(0, TCSANOW, initial_term);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D23(%rip),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string

tool: D13: Unknown system error %d

assistant: ```c
char *strerror(int e) {
  static char emsg[40];
  {
    sprintf(emsg, "Unknown system error %d", e);
    return (&emsg[0]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strerror>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  lea    D14(%rip),%rsi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string

tool: D14: Unknown system error %d

assistant: ```c
char *strerror(int e) {
  static char emsg[40];
  {
    sprintf(emsg, "Unknown system error %d", e);
    return (&emsg[0]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strerror>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  mov    %edi,%edx
  lea    D15(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: string

tool: D15: Unknown system error %d

assistant: ```c
char *strerror(int e) {
  static char emsg[40];
  {
    sprintf(emsg, "Unknown system error %d", e);
    return (&emsg[0]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strerror>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  mov    %edi,%edx
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: Unknown system error %d

assistant: ```c
char *strerror(int e) {
  static char emsg[40];
  {
    sprintf(emsg, "Unknown system error %d", e);
    return (&emsg[0]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D60(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D38(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D51(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x4,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  mov    -0x5c(%rbp),%edx
  lea    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stdlib_strided_dsumpw@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f64
name: parse_data
arguments: data_label: D60
type_guessed: f64
name: parse_data
arguments: data_label: D2
type_guessed: f64
name: parse_data
arguments: data_label: D38
type_guessed: f64
name: parse_data
arguments: data_label: D9
type_guessed: f64
name: parse_data
arguments: data_label: D0
type_guessed: f64
name: parse_data
arguments: data_label: D1
type_guessed: f64
name: parse_data
arguments: data_label: D51
type_guessed: f64
name: parse_data
arguments: data_label: D42
type_guessed: string

tool: D4: 1

tool: D60: 2

tool: D2: 3

tool: D38: 4

tool: D9: 5

tool: D0: 6

tool: D1: 7

tool: D51: 8

tool: D42: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dsumpw(N, x, stride);
  printf("sum: %lf\n", v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D83(%rip),%rax
  mov    %rax,(%rsp)
  mov    D30(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D39(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D37(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D28(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D6(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D74(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D69(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  mov    $0x4,%edi
  call   <stdlib_strided_dsumpw@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D83
type_infered: f64
name: disassemble_data
arguments: data_tag: D30
type_infered: f64
name: disassemble_data
arguments: data_tag: D39
type_infered: f64
name: disassemble_data
arguments: data_tag: D37
type_infered: f64
name: disassemble_data
arguments: data_tag: D28
type_infered: f64
name: disassemble_data
arguments: data_tag: D6
type_infered: f64
name: disassemble_data
arguments: data_tag: D74
type_infered: f64
name: disassemble_data
arguments: data_tag: D69
type_infered: f64
name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D83: 1

tool: D30: 2

tool: D39: 3

tool: D37: 4

tool: D28: 5

tool: D6: 6

tool: D74: 7

tool: D69: 8

tool: D5: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dsumpw(N, x, stride);
  printf("sum: %lf\n", v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x4,%edi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D35(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D63(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D33(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D11(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D1(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D68(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D8(%rip),%rax
  mov    %rax,0x38(%rsp)
  call   <stdlib_strided_dsumpw@plt>
  lea    D80(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D35
datatype: f64
name: parse_data
arguments: data_tag: D25
datatype: f64
name: parse_data
arguments: data_tag: D63
datatype: f64
name: parse_data
arguments: data_tag: D33
datatype: f64
name: parse_data
arguments: data_tag: D11
datatype: f64
name: parse_data
arguments: data_tag: D1
datatype: f64
name: parse_data
arguments: data_tag: D68
datatype: f64
name: parse_data
arguments: data_tag: D8
datatype: f64
name: parse_data
arguments: data_tag: D80
datatype: string

tool: D35: 1

tool: D25: 2

tool: D63: 3

tool: D33: 4

tool: D11: 5

tool: D1: 6

tool: D68: 7

tool: D8: 8

tool: D80: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dsumpw(N, x, stride);
  printf("sum: %lf\n", v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x4,%edi
  mov    $0x2,%edx
  movapd D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movapd D42(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D48(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D23(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <stdlib_strided_dsumpw@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D15
type_infered: f64[2]
name: read_data
arguments: tag: D42
type_infered: f64[2]
name: read_data
arguments: tag: D48
type_infered: f64[2]
name: read_data
arguments: tag: D23
type_infered: f64[2]
name: read_data
arguments: tag: D27
type_infered: string

tool: {"D15": [1.0,2.0]}

tool: {"D42": [3.0,4.0]}

tool: {"D48": [5.0,6.0]}

tool: {"D23": [7.0,8.0]}

tool: D27: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dsumpw(N, x, stride);
  printf("sum: %lf\n", v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<codecpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsbq -0x28(%rbp),%rdx
  mov    %rdx,%rcx
  shl    $0x7,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %dl,(%rcx,%rax,1)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  movsbq -0x28(%rbp),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void codecpy(char code_arr[128][128], char code[], int num, char sign) {
  for (int i = 0; i < num; i++)
    code_arr[(int)sign][i] = code[i];
  code_arr[(int)sign][num] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<codecpy>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L14
  movsbq %cl,%r8
  shl    $0x7,%r8
  add    %rdi,%r8
  mov    %edx,%r9d
  mov    $0x0,%eax
L19:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L19
L14:
  movsbq %cl,%rcx
  shl    $0x7,%rcx
  add    %rcx,%r10
  movslq %edx,%rdx
  movb   $0x0,(%r10,%rdx,1)
  ret
```

assistant: ```c
void codecpy(char code_arr[128][128], char code[], int num, char sign) {
  for (int i = 0; i < num; i++)
    code_arr[(int)sign][i] = code[i];
  code_arr[(int)sign][num] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<codecpy>:
  endbr64
  movsbq %cl,%rcx
  xor    %eax,%eax
  shl    $0x7,%rcx
  add    %rcx,%rdi
  movslq %edx,%rcx
  test   %edx,%edx
  jle    L14
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L19
L14:
  movb   $0x0,(%rdi,%rcx,1)
  ret
```

assistant: ```c
void codecpy(char code_arr[128][128], char code[], int num, char sign) {
  for (int i = 0; i < num; i++)
    code_arr[(int)sign][i] = code[i];
  code_arr[(int)sign][num] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<codecpy>:
  endbr64
  movsbq %cl,%rcx
  movslq %edx,%rax
  shl    $0x7,%rcx
  lea    (%rdi,%rcx,1),%rdx
  test   %eax,%eax
  jle    L149
  lea    0x1(%rsi),%r9
  mov    %rdx,%rdi
  lea    -0x1(%rax),%ecx
  mov    %eax,%r8d
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L65
  cmp    $0x6,%ecx
  jbe    L65
  cmp    $0xe,%ecx
  jbe    L236
  movdqu (%rsi),%xmm0
  mov    %eax,%ecx
  shr    $0x4,%ecx
  movups %xmm0,(%rdx)
  cmp    $0x1,%ecx
  je     L63
  movdqu 0x10(%rsi),%xmm1
  movups %xmm1,0x10(%rdx)
  cmp    $0x2,%ecx
  je     L63
  movdqu 0x20(%rsi),%xmm2
  movups %xmm2,0x20(%rdx)
  cmp    $0x3,%ecx
  je     L63
  movdqu 0x30(%rsi),%xmm3
  movups %xmm3,0x30(%rdx)
  cmp    $0x4,%ecx
  je     L63
  movdqu 0x40(%rsi),%xmm4
  movups %xmm4,0x40(%rdx)
  cmp    $0x5,%ecx
  je     L63
  movdqu 0x50(%rsi),%xmm5
  movups %xmm5,0x50(%rdx)
  cmp    $0x6,%ecx
  je     L63
  movdqu 0x60(%rsi),%xmm6
  movups %xmm6,0x60(%rdx)
  cmp    $0x7,%ecx
  je     L63
  movdqu 0x70(%rsi),%xmm7
  movups %xmm7,0x70(%rdx)
  cmp    $0x8,%ecx
  je     L63
  mov    $0x80,%edi
  mov    $0x8,%r8d
L161:
  movdqu (%rsi,%rdi,1),%xmm7
  add    $0x1,%r8d
  movups %xmm7,(%rdx,%rdi,1)
  add    $0x10,%rdi
  cmp    %r8d,%ecx
  jne    L161
  nop
L63:
  mov    %eax,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%ecx
  cmp    %edi,%eax
  je     L149
  mov    %eax,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L111
L101:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rdx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%ecx
  cmp    %edi,%r8d
  je     L149
L111:
  movslq %ecx,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  lea    0x1(%rcx),%edi
  cmp    %edi,%eax
  jle    L149
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  lea    0x2(%rcx),%edi
  cmp    %edi,%eax
  jle    L149
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  lea    0x3(%rcx),%edi
  cmp    %edi,%eax
  jle    L149
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  lea    0x4(%rcx),%edi
  cmp    %edi,%eax
  jle    L149
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  lea    0x5(%rcx),%edi
  cmp    %edi,%eax
  jle    L149
  movslq %edi,%rdi
  add    $0x6,%ecx
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rdx,%rdi,1)
  cmp    %ecx,%eax
  jle    L149
  movslq %ecx,%rcx
  movzbl (%rsi,%rcx,1),%esi
  mov    %sil,(%rdx,%rcx,1)
L149:
  movb   $0x0,(%rdx,%rax,1)
  ret
  cs nopw 0x0(%rax,%rax,1)
L65:
  mov    %eax,%r8d
  xor    %ecx,%ecx
  nopl   (%rax)
L177:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rdx,%rcx,1)
  add    $0x1,%rcx
  cmp    %r8,%rcx
  jne    L177
  movb   $0x0,(%rdx,%rax,1)
  ret
L236:
  xor    %edi,%edi
  xor    %ecx,%ecx
  jmp    L101
```

assistant: ```c
void codecpy(char code_arr[128][128], char code[], int num, char sign) {
  for (int i = 0; i < num; i++)
    code_arr[(int)sign][i] = code[i];
  code_arr[(int)sign][num] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_str(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < (len + 1); i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_str>:
  endbr64
  test   %edx,%edx
  js     L4
  lea    0x1(%rdx),%ecx
  mov    $0x0,%eax
L9:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L9
L4:
  ret
```

assistant: ```c
void copy_str(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < (len + 1); i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_str>:
  endbr64
  test   %edx,%edx
  js     L5
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L19
L5:
  ret
```

assistant: ```c
void copy_str(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < (len + 1); i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_str>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  js     L62
  lea    0x1(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L109
  cmp    $0x6,%edx
  jbe    L109
  lea    0x1(%rdx),%r8d
  cmp    $0xe,%edx
  jbe    L75
  mov    %r8d,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   (%rax)
L157:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L157
  mov    %r8d,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%r8d
  je     L62
  mov    %edx,%r9d
  sub    %edi,%r9d
  lea    0x1(%r9),%r8d
  cmp    $0x6,%r9d
  jbe    L115
L119:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L62
L115:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jl     L62
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jl     L62
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jl     L62
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jl     L62
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jl     L62
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jl     L62
  cltq
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
L62:
  ret
  nopl   0x0(%rax)
L109:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L37:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  mov    %rax,%rdi
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L37
  ret
L75:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L119
```

assistant: ```c
void copy_str(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < (len + 1); i++) {
    *(dest + i) = *(src + i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__syscall_getcwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x2f,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L12
L3:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int __syscall_getcwd(char *buf, size_t size) {
  if (buf && size) {
    buf[0] = '/';
    buf[1] = 0;
    return 1;
  }
  return -EINVAL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__syscall_getcwd>:
  endbr64
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L19
  movb   $0x2f,(%rdi)
  movb   $0x0,0x1(%rdi)
  mov    $0x1,%eax
  ret
L19:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int __syscall_getcwd(char *buf, size_t size) {
  if (buf && size) {
    buf[0] = '/';
    buf[1] = 0;
    return 1;
  }
  return -EINVAL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__syscall_getcwd>:
  endbr64
  test   %rdi,%rdi
  je     L12
  test   %rsi,%rsi
  je     L12
  mov    $0x2f,%eax
  mov    %ax,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L12:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int __syscall_getcwd(char *buf, size_t size) {
  if (buf && size) {
    buf[0] = '/';
    buf[1] = 0;
    return 1;
  }
  return -EINVAL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__syscall_getcwd>:
  endbr64
  test   %rdi,%rdi
  je     L14
  test   %rsi,%rsi
  je     L14
  mov    $0x2f,%eax
  mov    %ax,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L14:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int __syscall_getcwd(char *buf, size_t size) {
  if (buf && size) {
    buf[0] = '/';
    buf[1] = 0;
    return 1;
  }
  return -EINVAL;
}
```