user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dumpHex>:
  endbr64
  test   %rdi,%rdi
  je     L58
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x18,%rsp
  movq   $0x0,0x8(%rsp)
  cmp    $0x1,%edx
  jle    L93
  cmpb   $0xc0,(%rsi)
  je     L10
L7:
  lea    D3(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L37:
  mov    0x8(%rsp),%r14
  jmp    L192
  nopw   0x0(%rax,%rax,1)
L96:
  movzbl 0x0(%r13,%r14,1),%edx
  lea    D65(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <fprintf@plt>
  cmp    %r14d,%ebx
  jl     L21
L192:
  cmp    %r14d,%ebp
  jg     L96
  mov    %r12,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r15,%rdi
  call   <fwrite@plt>
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L192
L21:
  mov    %r12,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <fwrite@plt>
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%r14
  jmp    L177
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl -0x1(%r13,%r14,1),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  mov    %r14d,%eax
  add    $0x1,%r14
  cmp    %ebx,%eax
  jg     L146
L79:
  cmp    %eax,%ebp
  jle    L146
L177:
  movzbl -0x1(%r13,%r14,1),%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L13
  mov    %r12,%rsi
  mov    $0x2e,%edi
  call   <fputc@plt>
  mov    %r14d,%eax
  add    $0x1,%r14
  cmp    %ebx,%eax
  jle    L79
L146:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  addq   $0x10,0x8(%rsp)
  mov    0x8(%rsp),%rcx
  lea    0x1(%rbx),%eax
  add    $0x10,%ebx
  cmp    %ecx,%ebp
  jg     L37
  movslq %eax,%rcx
  lea    D3(%rip),%r15
  mov    %rcx,0x8(%rsp)
  cmp    %eax,%ebp
  jle    L39
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x8(%rsp),%r14
  jmp    L74
  nop
L182:
  movzbl 0x0(%r13,%r14,1),%edx
  lea    D65(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <fprintf@plt>
  cmp    %r14d,%ebx
  jl     L61
L74:
  cmp    %r14d,%ebp
  jg     L182
  mov    %r12,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r15,%rdi
  call   <fwrite@plt>
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L74
L61:
  mov    %r12,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  lea    0x10(%rbx),%eax
  add    $0x1,%ebx
  addq   $0x10,0x8(%rsp)
  cmp    %ebx,%ebp
  jle    L39
  mov    %eax,%ebx
  jmp    L36
L93:
  je     L7
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  ret
L10:
  cmpb   $0x23,0x1(%rsi)
  jne    L7
  add    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x32,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <fwrite@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D65
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D3:    

tool: D65: %02x 

tool: D38:   

tool: D10: (PAP Authentication Frame -- Contents not dumped)


assistant: ```c
void dumpHex(FILE *fp, unsigned char const *buf, int len) {
  int i;
  int base;
  if (!fp)
    return;
  if (len >= 2 && buf[0] == 0xC0 && buf[1] == 0x23) {
    fprintf(fp, "(PAP Authentication Frame -- Contents not dumped)\n");
    return;
  }
  for (base = 0; base < len; base += 16) {
    for (i = base; i < base + 16; i++) {
      if (i < len) {
        fprintf(fp, "%02x ", (unsigned)buf[i]);
      } else {
        fprintf(fp, "   ");
      }
    }
    fprintf(fp, "  ");
    for (i = base; i < base + 16; i++) {
      if (i < len) {
        if (isprint(buf[i])) {
          fprintf(fp, "%c", buf[i]);
        } else {
          fprintf(fp, ".");
        }
      } else {
        break;
      }
    }
    fprintf(fp, "\n");
  }
}
```