ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<constroiHeap>:
  endbr64
  cmp    $0x1,%edi
  jle    L17
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r12
  mov    $0x1,%r13d
  jmp    L48
L25:
  cmp    %r13d,%r14d
  je     L27
L48:
  add    $0x1,%r13d
  mov    %r13d,%ebx
  cmp    $0x1,%r13d
  jle    L25
L0:
  mov    %ebx,%ebp
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    %eax,%ebx
  cltq
  mov    (%r12,%rax,4),%edi
  movslq %ebp,%rax
  mov    (%r12,%rax,4),%esi
  cmp    %esi,%edi
  jge    L25
  call   <troca@plt>
  cmp    $0x3,%ebp
  jg     L0
  jmp    L25
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  ret
```

assistant: ```c
void constroiHeap(int m, int v[]) {
  int k, f;
  for (k = 1; k < m; ++k) {
    f = k + 1;
    while (f > 1 && v[f / 2] < v[f]) {
      troca(v[f / 2], v[f]);
      f /= 2;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<constroiHeap>:
  endbr64
  cmp    $0x1,%edi
  jle    L13
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L29:
  add    $0x1,%ebp
  mov    %ebp,%ebx
  nopl   (%rax)
L14:
  movslq %ebx,%rax
  sar    %ebx
  movslq %ebx,%rdx
  mov    0x0(%r13,%rax,4),%esi
  mov    0x0(%r13,%rdx,4),%edi
  cmp    %esi,%edi
  jge    L35
  call   <troca@plt>
  cmp    $0x1,%ebx
  jne    L14
L35:
  cmp    %ebp,%r12d
  jne    L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

assistant: ```c
void constroiHeap(int m, int v[]) {
  int k, f;
  for (k = 1; k < m; ++k) {
    f = k + 1;
    while (f > 1 && v[f / 2] < v[f]) {
      troca(v[f / 2], v[f]);
      f /= 2;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<constroiHeap>:
  endbr64
  cmp    $0x1,%edi
  jle    L23
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L28:
  add    $0x1,%ebp
  mov    %ebp,%ebx
  nopl   (%rax)
L5:
  movslq %ebx,%rax
  sar    %ebx
  movslq %ebx,%rdx
  mov    0x0(%r13,%rax,4),%esi
  mov    0x0(%r13,%rdx,4),%edi
  cmp    %esi,%edi
  jge    L8
  call   <troca@plt>
  cmp    $0x1,%ebx
  jne    L5
L8:
  cmp    %ebp,%r12d
  jne    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  ret
```

assistant: ```c
void constroiHeap(int m, int v[]) {
  int k, f;
  for (k = 1; k < m; ++k) {
    f = k + 1;
    while (f > 1 && v[f / 2] < v[f]) {
      troca(v[f / 2], v[f]);
      f /= 2;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main1>:
  endbr64
  push   %rbp
  xor    %ecx,%ecx
  mov    $0x34,%esi
  xor    %edi,%edi
  push   %rbx
  pxor   %xmm2,%xmm2
  sub    $0xe8,%rsp
  movss  D16(%rip),%xmm0
  movss  D19(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    $0x31,%eax
  movl   $0x30323031,(%rsp)
  lea    0x71(%rsp),%r9
  mov    %ax,0x4(%rsp)
  movb   $0x34,0x70(%rsp)
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %edi,%edi
L22:
  add    $0x1,%rcx
  mov    %eax,%esi
L67:
  divss  %xmm1,%xmm0
  movslq %ecx,%r8
  comiss %xmm2,%xmm0
  jbe    L55
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,(%r9,%rcx,1)
  cmp    %sil,%al
  jne    L13
  add    $0x1,%edi
  cmp    $0x6,%edi
  jne    L22
  lea    -0x1(%r8),%eax
  cltq
  movb   $0x29,0x70(%rsp,%rax,1)
  lea    -0x3(%r8),%eax
  cltq
  movb   $0x28,0x70(%rsp,%rax,1)
  movb   $0x0,0x70(%rsp,%r8,1)
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L49
  movslq %eax,%rbx
  nopl   0x0(%rax,%rax,1)
L36:
  movsbl 0x0(%rbp,%rbx,1),%edi
  sub    $0x1,%rbx
  call   <putchar@plt>
  test   %ebx,%ebx
  jns    L36
L49:
  mov    $0x2e,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  lea    0x70(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D19
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: {"D16": [0xef,0xaf,0x83,0x40]}

tool: {"D19": [0x00,0x00,0x20,0x41]}

tool: D3: %s

assistant: ```c
void main1() {
  float a = 100;
  int b = 3;
  int c = a;
  char str1[100];
  char str2[100];
  int i = 0;
  while (c > 0) {
    str1[i++] = '0' + (c % b);
    c = c / b;
    a = a / b;
  }
  str1[i] = '\0';
  i = 0;
  int count = 0;
  while (a > 0) {
    a = a * 10;
    c = a;
    str2[i] = '0' + (c % 10);
    if (i > 0 && str2[i - 1] == str2[i]) {
      count++;
    } else {
      count = 0;
    }
    if (count > 5) {
      str2[i - 2] = ')';
      str2[i - 4] = '(';
      str2[i - 1] = '\0';
      break;
    }
    a = a / 10;
    i++;
  }
  int len = strlen(str1);
  for (i = len - 1; i >= 0; i--) {
    printf("%c", str1[i]);
  }
  printf(".");
  printf("%s", str2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmpcasenosensitive_internal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x60,-0x2(%rbp)
  jle    L105
  cmpb   $0x7a,-0x2(%rbp)
  jg     L105
  movzbl -0x2(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x2(%rbp)
L105:
  cmpb   $0x60,-0x1(%rbp)
  jle    L81
  cmpb   $0x7a,-0x1(%rbp)
  jg     L81
  movzbl -0x1(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x1(%rbp)
L81:
  cmpb   $0x0,-0x2(%rbp)
  jne    L22
  cmpb   $0x0,-0x1(%rbp)
  jne    L109
  mov    $0x0,%eax
  jmp    L129
L109:
  mov    $0xffffffff,%eax
  jmp    L129
L22:
  cmpb   $0x0,-0x1(%rbp)
  jne    L58
  mov    $0x1,%eax
  jmp    L129
L58:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L126
  mov    $0xffffffff,%eax
  jmp    L129
L126:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L30
  mov    $0x1,%eax
L129:
  pop    %rbp
  ret
```

assistant: ```c
int strcmpcasenosensitive_internal(const char *fileName1, const char *fileName2) {
  while (1) {
    char c1 = *(fileName1++), c2 = *(fileName2++);
    if ((c1 >= 'a') && (c1 <= 'z'))
      c1 -= 0x20;
    if ((c2 >= 'a') && (c2 <= 'z'))
      c2 -= 0x20;
    if (c1 == '\0')
      return (c2 == '\0' ? 0 : -1);
    if (c2 == '\0')
      return 1;
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmpcasenosensitive_internal>:
  endbr64
  mov    $0x0,%ecx
  jmp    L94
L82:
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r8b
  ja     L63
  sub    $0x20,%eax
  test   %dl,%dl
  jne    L95
L55:
  neg    %al
  sbb    %eax,%eax
  ret
L63:
  test   %dl,%dl
  je     L55
L16:
  test   %al,%al
  je     L59
L95:
  cmp    %al,%dl
  jl     L54
  add    $0x1,%rcx
  cmp    %al,%dl
  jg     L44
L94:
  movzbl (%rdi,%rcx,1),%edx
  movzbl (%rsi,%rcx,1),%eax
  lea    -0x61(%rdx),%r8d
  cmp    $0x19,%r8b
  ja     L82
  sub    $0x20,%edx
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r8b
  ja     L16
  sub    $0x20,%eax
  jmp    L95
L44:
  mov    $0x1,%eax
  ret
L59:
  mov    $0x1,%eax
  ret
L54:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmpcasenosensitive_internal(const char *fileName1, const char *fileName2) {
  while (1) {
    char c1 = *(fileName1++), c2 = *(fileName2++);
    if ((c1 >= 'a') && (c1 <= 'z'))
      c1 -= 0x20;
    if ((c2 >= 'a') && (c2 <= 'z'))
      c2 -= 0x20;
    if (c1 == '\0')
      return (c2 == '\0' ? 0 : -1);
    if (c2 == '\0')
      return 1;
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmpcasenosensitive_internal>:
  endbr64
  xor    %ecx,%ecx
  jmp    L82
  nopl   0x0(%rax,%rax,1)
L74:
  sub    $0x20,%edx
  cmp    $0x19,%r8b
  ja     L31
  sub    $0x20,%eax
L51:
  cmp    %al,%dl
  jl     L6
  add    $0x1,%rcx
  cmp    %al,%dl
  jg     L56
L82:
  movzbl (%rdi,%rcx,1),%edx
  movzbl (%rsi,%rcx,1),%eax
  lea    -0x61(%rdx),%r9d
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r9b
  jbe    L74
  cmp    $0x19,%r8b
  ja     L14
  sub    $0x20,%eax
  test   %dl,%dl
  jne    L51
L78:
  neg    %al
  sbb    %eax,%eax
  ret
L14:
  test   %dl,%dl
  je     L78
L31:
  test   %al,%al
  jne    L51
L56:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmpcasenosensitive_internal(const char *fileName1, const char *fileName2) {
  while (1) {
    char c1 = *(fileName1++), c2 = *(fileName2++);
    if ((c1 >= 'a') && (c1 <= 'z'))
      c1 -= 0x20;
    if ((c2 >= 'a') && (c2 <= 'z'))
      c2 -= 0x20;
    if (c1 == '\0')
      return (c2 == '\0' ? 0 : -1);
    if (c2 == '\0')
      return 1;
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmpcasenosensitive_internal>:
  endbr64
  xor    %ecx,%ecx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L65:
  sub    $0x20,%edx
  cmp    $0x19,%r8b
  ja     L88
  sub    $0x20,%eax
L14:
  cmp    %al,%dl
  jl     L68
  add    $0x1,%rcx
  cmp    %al,%dl
  jg     L24
L45:
  movzbl (%rdi,%rcx,1),%edx
  movzbl (%rsi,%rcx,1),%eax
  lea    -0x61(%rdx),%r9d
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r9b
  jbe    L65
  cmp    $0x19,%r8b
  ja     L59
  sub    $0x20,%eax
  test   %dl,%dl
  jne    L14
L84:
  neg    %al
  sbb    %eax,%eax
  ret
L59:
  test   %dl,%dl
  je     L84
L88:
  test   %al,%al
  jne    L14
L24:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L68:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmpcasenosensitive_internal(const char *fileName1, const char *fileName2) {
  while (1) {
    char c1 = *(fileName1++), c2 = *(fileName2++);
    if ((c1 >= 'a') && (c1 <= 'z'))
      c1 -= 0x20;
    if ((c2 >= 'a') && (c2 <= 'z'))
      c2 -= 0x20;
    if (c1 == '\0')
      return (c2 == '\0' ? 0 : -1);
    if (c2 == '\0')
      return 1;
    if (c1 < c2)
      return -1;
    if (c1 > c2)
      return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rbp
  lea    D9(%rip),%rbx
L47:
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0xf(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%esi
  cmp    $0x2b,%sil
  je     L3
  cmp    $0x2f,%sil
  je     L14
  cmp    $0x2a,%sil
  je     L74
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L47
L3:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
L30:
  movsbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  lea    D16(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L74:
  movss  0x10(%rsp),%xmm2
  mulss  0x14(%rsp),%xmm2
  jmp    L30
L14:
  movss  0x14(%rsp),%xmm0
  ucomiss D10(%rip),%xmm0
  jp     L42
  jne    L42
  lea    D46(%rip),%rdi
  call   <puts@plt>
  jmp    L47
L42:
  movss  0x10(%rsp),%xmm2
  divss  %xmm0,%xmm2
  jmp    L30
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D49
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D46
data_type: string

tool: D49: Dwste thn praksh me th morfh:
 (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter

tool: D9: %f %c %f

tool: D18: Dwsate lathos praksh! Parakalw ksanaprospathiste ->

tool: D16: To apotelesma einai %f %c %f = %f 


tool: {"D10": [0x00,0x00,0x00,0x00]}

tool: D46: Diairesh me to 0! Parakalw ksanaprospathiste ->

assistant: ```c
int main() {
  float a, c;
  char b;
  float result;
  int ok = 0;
  do {
    ok = 1;
    a = c = result = 0.0f;
    printf("Dwste thn praksh me th morfh:\n (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter\n");
    scanf("%f %c %f", &a, &b, &c);
    switch (b) {
    case '+': {
      result = a + c;
      break;
    }
    case '*': {
      result = a * c;
      break;
    }
    case '/': {
      if (c == 0) {
        printf("Diairesh me to 0! Parakalw ksanaprospathiste ->\n");
        ok = 0;
        break;
      }
      result = a / c;
      break;
    }
    default: {
      printf("Dwsate lathos praksh! Parakalw ksanaprospathiste ->\n");
      ok = 0;
      break;
    }
    }
  } while (!ok);
  printf("To apotelesma einai %f %c %f = %f \n", a, b, c, result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%r15
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D31(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0xf(%rsp),%r12
  lea    0x10(%rsp),%rbp
L97:
  mov    %r14,%rdi
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <puts@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2b,%al
  je     L85
  cmp    $0x2f,%al
  je     L92
  cmp    $0x2a,%al
  je     L24
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L97
L85:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
  mov    $0x2b,%esi
L91:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D43(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  movss  0x10(%rsp),%xmm2
  mov    $0x2a,%esi
  mulss  0x14(%rsp),%xmm2
  jmp    L91
L92:
  movss  0x14(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm0
  jp     L76
  jne    L76
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L97
L76:
  movss  0x10(%rsp),%xmm2
  mov    $0x2f,%esi
  divss  %xmm0,%xmm2
  jmp    L91
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type_infered: string
name: retrieve_data
arguments: label: D36
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D43
type_infered: string
name: retrieve_data
arguments: label: D32
type_infered: string

tool: D37: Dwsate lathos praksh! Parakalw ksanaprospathiste ->

tool: D36: Dwste thn praksh me th morfh:
 (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter

tool: D31: %f %c %f

tool: D43: To apotelesma einai %f %c %f = %f 


tool: D32: Diairesh me to 0! Parakalw ksanaprospathiste ->

assistant: ```c
int main() {
  float a, c;
  char b;
  float result;
  int ok = 0;
  do {
    ok = 1;
    a = c = result = 0.0f;
    printf("Dwste thn praksh me th morfh:\n (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter\n");
    scanf("%f %c %f", &a, &b, &c);
    switch (b) {
    case '+': {
      result = a + c;
      break;
    }
    case '*': {
      result = a * c;
      break;
    }
    case '/': {
      if (c == 0) {
        printf("Diairesh me to 0! Parakalw ksanaprospathiste ->\n");
        ok = 0;
        break;
      }
      result = a / c;
      break;
    }
    default: {
      printf("Dwsate lathos praksh! Parakalw ksanaprospathiste ->\n");
      ok = 0;
      break;
    }
    }
  } while (!ok);
  printf("To apotelesma einai %f %c %f = %f \n", a, b, c, result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%r15
  push   %r14
  lea    D32(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r13
  lea    0xf(%rsp),%r12
  lea    0x10(%rsp),%rbp
L55:
  mov    %r14,%rdi
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <puts@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x2b,%al
  je     L9
  cmp    $0x2f,%al
  je     L82
  cmp    $0x2a,%al
  je     L21
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L55
L9:
  movss  0x10(%rsp),%xmm2
  addss  0x14(%rsp),%xmm2
  mov    $0x2b,%esi
L62:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D18(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  movss  0x10(%rsp),%xmm2
  mov    $0x2a,%esi
  mulss  0x14(%rsp),%xmm2
  jmp    L62
L82:
  movss  0x14(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm0
  jp     L80
  jne    L80
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L55
L80:
  movss  0x10(%rsp),%xmm2
  mov    $0x2f,%esi
  divss  %xmm0,%xmm2
  jmp    L62
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D32
data_type: string
name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D0
data_type: string

tool: D10: Dwsate lathos praksh! Parakalw ksanaprospathiste ->

tool: D32: Dwste thn praksh me th morfh:
 (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter

tool: D17: %f %c %f

tool: D18: To apotelesma einai %f %c %f = %f 


tool: D0: Diairesh me to 0! Parakalw ksanaprospathiste ->

assistant: ```c
int main() {
  float a, c;
  char b;
  float result;
  int ok = 0;
  do {
    ok = 1;
    a = c = result = 0.0f;
    printf("Dwste thn praksh me th morfh:\n (arithmos) (praksh) (arithmos), xwris tis parentheseis kai pieste enter\n");
    scanf("%f %c %f", &a, &b, &c);
    switch (b) {
    case '+': {
      result = a + c;
      break;
    }
    case '*': {
      result = a * c;
      break;
    }
    case '/': {
      if (c == 0) {
        printf("Diairesh me to 0! Parakalw ksanaprospathiste ->\n");
        ok = 0;
        break;
      }
      result = a / c;
      break;
    }
    default: {
      printf("Dwsate lathos praksh! Parakalw ksanaprospathiste ->\n");
      ok = 0;
      break;
    }
    }
  } while (!ok);
  printf("To apotelesma einai %f %c %f = %f \n", a, b, c, result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<config_parse_host>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  jne    L2
  mov    $0x0,%eax
  jmp    L7
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
L7:
  leave
  ret
```

assistant: ```c
char *config_parse_host(const char *buf) {
  char *new_host;
  size_t len;
  if (gethostbyname(buf) == NULL) {
    return NULL;
  }
  len = strlen(buf) + 1;
  new_host = malloc(sizeof(char) * len);
  memcpy(new_host, buf, len);
  return new_host;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<config_parse_host>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <gethostbyname@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movslq %ebp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *config_parse_host(const char *buf) {
  char *new_host;
  size_t len;
  if (gethostbyname(buf) == NULL) {
    return NULL;
  }
  len = strlen(buf) + 1;
  new_host = malloc(sizeof(char) * len);
  memcpy(new_host, buf, len);
  return new_host;
}
```
user: Translate the below assembly code into C programming language:

```asm
<config_parse_host>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    %rax,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *config_parse_host(const char *buf) {
  char *new_host;
  size_t len;
  if (gethostbyname(buf) == NULL) {
    return NULL;
  }
  len = strlen(buf) + 1;
  new_host = malloc(sizeof(char) * len);
  memcpy(new_host, buf, len);
  return new_host;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<config_parse_host>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %rax,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *config_parse_host(const char *buf) {
  char *new_host;
  size_t len;
  if (gethostbyname(buf) == NULL) {
    return NULL;
  }
  len = strlen(buf) + 1;
  new_host = malloc(sizeof(char) * len);
  memcpy(new_host, buf, len);
  return new_host;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SysCtlPWMClockGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fe010,%eax
  mov    (%rax),%rax
  and    $0x100000,%eax
  mov    %rax,%rdi
  call   <DEBUG_ASSERT@plt>
  mov    $0x400fe060,%eax
  mov    (%rax),%rax
  and    $0x100000,%eax
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
  jmp    L15
L10:
  mov    $0x400fe060,%eax
  mov    (%rax),%rax
  and    $0x1e0000,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long SysCtlPWMClockGet(void) {
  DEBUG_ASSERT((*((volatile unsigned long *)(0x400FE010))) & 0x00100000);
  if (!((*((volatile unsigned long *)(0x400FE060))) & 0x00100000)) {
    return (0x00000000);
  } else {
    return ((*((volatile unsigned long *)(0x400FE060))) & (0x00100000 | 0x000E0000));
  }
}
```