ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_isset>:
  endbr64
  movsbl (%rsi),%eax
  test   %al,%al
  je     L13
  movzbl %dil,%edi
  jmp    L29
  nopl   0x0(%rax)
L2:
  movsbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L13
L29:
  cmp    %edi,%eax
  jne    L2
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isset(int c, char *set) {
  while (*set) {
    if ((unsigned char)c == *set)
      return (1);
    set++;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<leaf_example>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int leaf_example(int g, int h, int i, int j) {
  int f;
  f = (g - h) + (i - j);
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<leaf_example>:
  endbr64
  sub    %esi,%edi
  sub    %ecx,%edx
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int leaf_example(int g, int h, int i, int j) {
  int f;
  f = (g - h) + (i - j);
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leaf_example>:
  endbr64
  sub    %esi,%edi
  sub    %ecx,%edx
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int leaf_example(int g, int h, int i, int j) {
  int f;
  f = (g - h) + (i - j);
  return f;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<leaf_example>:
  endbr64
  sub    %esi,%edi
  sub    %ecx,%edx
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int leaf_example(int g, int h, int i, int j) {
  int f;
  f = (g - h) + (i - j);
  return f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stw_be_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stw_be_p(void *ptr, int v) {
  uint8_t *d = (uint8_t *)ptr;
  d[0] = v >> 8;
  d[1] = v;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stw_be_p>:
  endbr64
  mov    %esi,%eax
  sar    $0x8,%eax
  mov    %eax,(%rdi)
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void stw_be_p(void *ptr, int v) {
  uint8_t *d = (uint8_t *)ptr;
  d[0] = v >> 8;
  d[1] = v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stw_be_p>:
  endbr64
  mov    %esi,%eax
  mov    %esi,0x4(%rdi)
  sar    $0x8,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void stw_be_p(void *ptr, int v) {
  uint8_t *d = (uint8_t *)ptr;
  d[0] = v >> 8;
  d[1] = v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stw_be_p>:
  endbr64
  mov    %esi,%eax
  movd   %esi,%xmm1
  sar    $0x8,%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

assistant: ```c
void stw_be_p(void *ptr, int v) {
  uint8_t *d = (uint8_t *)ptr;
  d[0] = v >> 8;
  d[1] = v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t read_size(void *ptr) {
  size_t *sizep = ptr;
  return *sizep;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_size>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
size_t read_size(void *ptr) {
  size_t *sizep = ptr;
  return *sizep;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_size>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
size_t read_size(void *ptr) {
  size_t *sizep = ptr;
  return *sizep;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_size>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
size_t read_size(void *ptr) {
  size_t *sizep = ptr;
  return *sizep;
}
```
user: What is the c source code of the assembly code below?

```asm
<gen_ILL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_ILL@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_ILL() {
  handle_ILL(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gen_ILL>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_ILL@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_ILL() {
  handle_ILL(0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<gen_ILL>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_ILL@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_ILL() {
  handle_ILL(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_ILL>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_ILL@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_ILL() {
  handle_ILL(0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strict_atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L31
  addq   $0x1,-0x18(%rbp)
  jmp    L22
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L22
  addq   $0x1,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L22
L64:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L48
  mov    $0x0,%eax
  jmp    L1
L48:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int strict_atol(const char *restrict str, long *restrict value) {
  int res = 0;
  int sign = 1;
  if (*str == '+')
    ++str;
  else if (*str == '-') {
    ++str;
    sign = -1;
  }
  for (; *str; ++str) {
    if (!isdigit(*str))
      return (0);
    res *= 10;
    res += *str - '0';
  }
  *value = sign * res;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strict_atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  movzbl (%rdi),%eax
  cmp    $0x2b,%al
  je     L24
  mov    $0x1,%r12d
  cmp    $0x2d,%al
  je     L18
L59:
  movzbl (%rbx),%edi
  mov    $0x0,%ebp
  test   %dil,%dil
  je     L12
L8:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L56
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
L12:
  imul   %ebp,%r12d
  movslq %r12d,%r12
  mov    %r12,0x0(%r13)
  mov    $0x1,%eax
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  add    $0x1,%rbx
  mov    $0x1,%r12d
  jmp    L59
L18:
  add    $0x1,%rbx
  mov    $0xffffffff,%r12d
  jmp    L59
```

assistant: ```c
int strict_atol(const char *restrict str, long *restrict value) {
  int res = 0;
  int sign = 1;
  if (*str == '+')
    ++str;
  else if (*str == '-') {
    ++str;
    sign = -1;
  }
  for (; *str; ++str) {
    if (!isdigit(*str))
      return (0);
    res *= 10;
    res += *str - '0';
  }
  *value = sign * res;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strict_atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  cmp    $0x2b,%dil
  je     L10
  mov    $0x1,%r12d
  cmp    $0x2d,%dil
  je     L42
L40:
  xor    %r13d,%r13d
  test   %dil,%dil
  jne    L84
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L65:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%r13,%r13,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r13d
  test   %dil,%dil
  je     L11
L84:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L65
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L42:
  movsbl 0x1(%rbx),%edi
  mov    $0xffffffff,%r12d
  add    $0x1,%rbx
  jmp    L40
L11:
  imul   %r12d,%r13d
  movslq %r13d,%r13
L34:
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl 0x1(%rbx),%edi
  mov    $0x1,%r12d
  add    $0x1,%rbx
  jmp    L40
L39:
  xor    %r13d,%r13d
  jmp    L34
```

assistant: ```c
int strict_atol(const char *restrict str, long *restrict value) {
  int res = 0;
  int sign = 1;
  if (*str == '+')
    ++str;
  else if (*str == '-') {
    ++str;
    sign = -1;
  }
  for (; *str; ++str) {
    if (!isdigit(*str))
      return (0);
    res *= 10;
    res += *str - '0';
  }
  *value = sign * res;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strict_atol>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  cmp    $0x2b,%dil
  je     L80
  mov    $0x1,%r12d
  cmp    $0x2d,%dil
  je     L7
L25:
  xor    %r13d,%r13d
  test   %dil,%dil
  jne    L18
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L62:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%r13,%r13,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r13d
  test   %dil,%dil
  je     L88
L18:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L62
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L7:
  movsbl 0x1(%rbx),%edi
  mov    $0xffffffff,%r12d
  add    $0x1,%rbx
  jmp    L25
L88:
  imul   %r12d,%r13d
  movslq %r13d,%r13
L27:
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  movsbl 0x1(%rbx),%edi
  mov    $0x1,%r12d
  add    $0x1,%rbx
  jmp    L25
L49:
  xor    %r13d,%r13d
  jmp    L27
```

assistant: ```c
int strict_atol(const char *restrict str, long *restrict value) {
  int res = 0;
  int sign = 1;
  if (*str == '+')
    ++str;
  else if (*str == '-') {
    ++str;
    sign = -1;
  }
  for (; *str; ++str) {
    if (!isdigit(*str))
      return (0);
    res *= 10;
    res += *str - '0';
  }
  *value = sign * res;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x4,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  cmp    $0x81234567,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x14,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  cmp    $0x45678123,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: Assertion successful :)


assistant: ```c
int main(int argc, char **argv) {
  assert(rotate_left(0x12345678, 4) == 0x81234567);
  assert(rotate_left(0x12345678, 20) == 0x45678123);
  printf("Assertion successful :)\x0A");
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  cmp    $0x81234567,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x14,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  cmp    $0x45678123,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: Assertion successful :)


assistant: ```c
int main(int argc, char **argv) {
  assert(rotate_left(0x12345678, 4) == 0x81234567);
  assert(rotate_left(0x12345678, 20) == 0x45678123);
  printf("Assertion successful :)\x0A");
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  xor    %edi,%edi
  cmp    $0x81234567,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  xor    %edi,%edi
  cmp    $0x45678123,%eax
  sete   %dil
  call   <assert@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: Assertion successful :)


assistant: ```c
int main(int argc, char **argv) {
  assert(rotate_left(0x12345678, 4) == 0x81234567);
  assert(rotate_left(0x12345678, 20) == 0x45678123);
  printf("Assertion successful :)\x0A");
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  xor    %edi,%edi
  cmp    $0x81234567,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x14,%esi
  mov    $0x12345678,%edi
  call   <rotate_left@plt>
  xor    %edi,%edi
  cmp    $0x45678123,%eax
  sete   %dil
  call   <assert@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: Assertion successful :)


assistant: ```c
int main(int argc, char **argv) {
  assert(rotate_left(0x12345678, 4) == 0x81234567);
  assert(rotate_left(0x12345678, 20) == 0x45678123);
  printf("Assertion successful :)\x0A");
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hs51>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %ecx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D12(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  movsd  D14(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm0
  movsd  D14(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L18
L5:
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x1,%ebx
L18:
  cmp    -0x40(%rbp),%ebx
  jl     L5
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_guessed: f64
name: unpack_data
arguments: data_label: D14
type_guessed: f64

tool: D12: 2

tool: D14: 1

assistant: ```c
void hs51(double *p, double *x, int m, int n, void *data) {
  register int i;
  double t1, t2, t3, t4;
  t1 = p[0] - p[1];
  t2 = p[1] + p[2] - 2.0;
  t3 = p[3] - 1.0;
  t4 = p[4] - 1.0;
  for (i = 0; i < n; ++i)
    x[i] = t1 * t1 + t2 * t2 + t3 * t3 + t4 * t4;
}
```
user: What is the c source code of the assembly code below?

```asm
<hs51>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  movsd  (%rdi),%xmm0
  subsd  %xmm1,%xmm0
  addsd  0x10(%rdi),%xmm1
  subsd  D2(%rip),%xmm1
  movsd  0x18(%rdi),%xmm3
  movsd  D18(%rip),%xmm4
  subsd  %xmm4,%xmm3
  movsd  0x20(%rdi),%xmm2
  subsd  %xmm4,%xmm2
  test   %ecx,%ecx
  jle    L5
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  mov    %rsi,%rax
  lea    -0x1(%rcx),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
L16:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: f64

tool: D2: 2

tool: D18: 1

assistant: ```c
void hs51(double *p, double *x, int m, int n, void *data) {
  register int i;
  double t1, t2, t3, t4;
  t1 = p[0] - p[1];
  t2 = p[1] + p[2] - 2.0;
  t3 = p[3] - 1.0;
  t4 = p[4] - 1.0;
  for (i = 0; i < n; ++i)
    x[i] = t1 * t1 + t2 * t2 + t3 * t3 + t4 * t4;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hs51>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  movsd  D1(%rip),%xmm4
  movsd  (%rdi),%xmm0
  movsd  0x18(%rdi),%xmm3
  movsd  0x20(%rdi),%xmm2
  subsd  %xmm1,%xmm0
  subsd  %xmm4,%xmm3
  addsd  0x10(%rdi),%xmm1
  subsd  %xmm4,%xmm2
  subsd  D13(%rip),%xmm1
  test   %ecx,%ecx
  jle    L14
  mulsd  %xmm0,%xmm0
  lea    -0x1(%rcx),%eax
  mulsd  %xmm1,%xmm1
  lea    0x8(%rsi,%rax,8),%rax
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  addsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
L4:
  movsd  %xmm0,(%rsi)
  add    $0x8,%rsi
  cmp    %rax,%rsi
  jne    L4
L14:
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: f64
name: read_data
arguments: label: D13
data_type: f64

tool: D1: 1

tool: D13: 2

assistant: ```c
void hs51(double *p, double *x, int m, int n, void *data) {
  register int i;
  double t1, t2, t3, t4;
  t1 = p[0] - p[1];
  t2 = p[1] + p[2] - 2.0;
  t3 = p[3] - 1.0;
  t4 = p[4] - 1.0;
  for (i = 0; i < n; ++i)
    x[i] = t1 * t1 + t2 * t2 + t3 * t3 + t4 * t4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hs51>:
  endbr64
  movsd  0x8(%rdi),%xmm1
  movsd  D18(%rip),%xmm4
  movsd  (%rdi),%xmm0
  movsd  0x18(%rdi),%xmm3
  movsd  0x20(%rdi),%xmm2
  subsd  %xmm1,%xmm0
  subsd  %xmm4,%xmm3
  addsd  0x10(%rdi),%xmm1
  subsd  %xmm4,%xmm2
  subsd  D4(%rip),%xmm1
  test   %ecx,%ecx
  jle    L9
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  addsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  cmp    $0x1,%ecx
  je     L7
  mov    %ecx,%edx
  movapd %xmm0,%xmm1
  mov    %rsi,%rax
  shr    %edx
  unpcklpd %xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L47:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L47
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L2
L42:
  cltq
  movsd  %xmm0,(%rsi,%rax,8)
L9:
  ret
  xchg   %ax,%ax
L2:
  ret
L7:
  xor    %eax,%eax
  jmp    L42
```

tool_calls: name: unpack_data
arguments: data_label: D18
datatype: f64
name: unpack_data
arguments: data_label: D4
datatype: f64

tool: D18: 1

tool: D4: 2

assistant: ```c
void hs51(double *p, double *x, int m, int n, void *data) {
  register int i;
  double t1, t2, t3, t4;
  t1 = p[0] - p[1];
  t2 = p[1] + p[2] - 2.0;
  t3 = p[3] - 1.0;
  t4 = p[4] - 1.0;
  for (i = 0; i < n; ++i)
    x[i] = t1 * t1 + t2 * t2 + t3 * t3 + t4 * t4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x3,-0x4(%rbp)
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 4; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printhash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(%rdi),%r12
  lea    D9(%rip),%rbp
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 4; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printhash>:
  endbr64
  push   %r12
  lea    0x4(%rdi),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L8:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 4; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printhash>:
  endbr64
  push   %r12
  lea    0x4(%rdi),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L8:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 4; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```