ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<floats_mat44_rotate_z_self>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <floats_mat44_rotate_z@plt>
  sub    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %r13,%rcx
  push   $0x4
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    $0x4,%r9d
  push   $0x4
  mov    $0x4,%r8d
  lea    0x58(%rsp),%r12
  push   %r12
  call   <floats_mat_AB@plt>
  mov    %r13,%rsp
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_mat44_rotate_z_self(float rad, float out[16]) {
  float tmp[16], prod[16];
  floats_mat44_rotate_z(rad, tmp);
  floats_mat_AB(out, 4, 4, tmp, 4, 4, prod, 4, 4);
  memcpy(out, prod, sizeof(float) * 16);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%r12
  jmp    L12
L13:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L12
  lea    -0x1(%rbx),%rax
  movzbl (%rax),%edx
  lea    -0x1(%r12),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L36
  mov    $0xffffffff,%eax
  jmp    L37
L36:
  mov    $0x1,%eax
  jmp    L37
L12:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
  mov    $0x0,%eax
L37:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *str1, const void *str2, size_t count) {
  register unsigned char *s1 = (unsigned char *)str1;
  register unsigned char *s2 = (unsigned char *)str2;
  while (count-- > 0) {
    if (*s1++ != *s2++)
      return s1[-1] < s2[-1] ? -1 : 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp>:
  endbr64
  mov    $0x0,%eax
L9:
  cmp    %rax,%rdx
  je     L13
  movzbl (%rdi,%rax,1),%r8d
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%r8b
  je     L9
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(const void *str1, const void *str2, size_t count) {
  register unsigned char *s1 = (unsigned char *)str1;
  register unsigned char *s2 = (unsigned char *)str2;
  while (count-- > 0) {
    if (*s1++ != *s2++)
      return s1[-1] < s2[-1] ? -1 : 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L17
L14:
  cmp    %rax,%rdx
  jne    L9
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *str1, const void *str2, size_t count) {
  register unsigned char *s1 = (unsigned char *)str1;
  register unsigned char *s2 = (unsigned char *)str2;
  while (count-- > 0) {
    if (*s1++ != *s2++)
      return s1[-1] < s2[-1] ? -1 : 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L0
L22:
  cmp    %rax,%rdx
  jne    L14
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *str1, const void *str2, size_t count) {
  register unsigned char *s1 = (unsigned char *)str1;
  register unsigned char *s2 = (unsigned char *)str2;
  while (count-- > 0) {
    if (*s1++ != *s2++)
      return s1[-1] < s2[-1] ? -1 : 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%esi
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  add    %esi,%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D49
data_type: string
name: read_data
arguments: data_tag: D35
data_type: string

tool: D49: %d %d %d

tool: D35: %d


assistant: ```c
int main() {
  int A, B, C;
  scanf("%d %d %d", &A, &B, &C);
  printf("%d\n", (A + B) % C);
  printf("%d\n", (A % C + B % C) % C);
  printf("%d\n", (A * B) % C);
  printf("%d\n", (A % C * B % C) % C);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0xc(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  mov    0x10(%rsp),%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rdx,1),%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  imul   0x10(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D0: %d %d %d

tool: D15: %d


assistant: ```c
int main() {
  int A, B, C;
  scanf("%d %d %d", &A, &B, &C);
  printf("%d\n", (A + B) % C);
  printf("%d\n", (A % C + B % C) % C);
  printf("%d\n", (A * B) % C);
  printf("%d\n", (A % C * B % C) % C);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  lea    D12(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0xc(%rsp),%eax
  mov    %rbp,%rdi
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %rbp,%rdi
  cltd
  idiv   %ecx
  mov    0x10(%rsp),%eax
  mov    %edx,%esi
  cltd
  idiv   %ecx
  lea    (%rsi,%rdx,1),%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  mov    %rbp,%rdi
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %rbp,%rdi
  cltd
  idiv   %ecx
  mov    0x10(%rsp),%eax
  imul   %edx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D12
data_type: string

tool: D4: %d %d %d

tool: D12: %d


assistant: ```c
int main() {
  int A, B, C;
  scanf("%d %d %d", &A, &B, &C);
  printf("%d\n", (A + B) % C);
  printf("%d\n", (A % C + B % C) % C);
  printf("%d\n", (A * B) % C);
  printf("%d\n", (A % C * B % C) % C);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  lea    D3(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  add    0xc(%rsp),%eax
  mov    %rbp,%rdi
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %rbp,%rdi
  cltd
  idiv   %ecx
  mov    0x10(%rsp),%eax
  mov    %edx,%esi
  cltd
  idiv   %ecx
  lea    (%rsi,%rdx,1),%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  mov    %rbp,%rdi
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x14(%rsp),%ecx
  mov    %rbp,%rdi
  cltd
  idiv   %ecx
  mov    0x10(%rsp),%eax
  imul   %edx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D8: %d %d %d

tool: D3: %d


assistant: ```c
int main() {
  int A, B, C;
  scanf("%d %d %d", &A, &B, &C);
  printf("%d\n", (A + B) % C);
  printf("%d\n", (A % C + B % C) % C);
  printf("%d\n", (A * B) % C);
  printf("%d\n", (A % C * B % C) % C);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gpei>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rax),%xmm1
  mulsd  -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double gpei(x, y, p)
double x, y;
double *p;
{ return ((p[6] * x * y) - (p[5] * y)); }
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpei>:
  endbr64
  mulsd  0x30(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  0x28(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double gpei(x, y, p)
double x, y;
double *p;
{ return ((p[6] * x * y) - (p[5] * y)); }
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gpei>:
  endbr64
  mulsd  0x30(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  0x28(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double gpei(x, y, p)
double x, y;
double *p;
{ return ((p[6] * x * y) - (p[5] * y)); }
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gpei>:
  endbr64
  mulsd  0x30(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  0x28(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double gpei(x, y, p)
double x, y;
double *p;
{ return ((p[6] * x * y) - (p[5] * y)); }
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <message@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %s


assistant: ```c
int main(void) {
  printf("%s\n", message());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <message@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: %s


assistant: ```c
int main(void) {
  printf("%s\n", message());
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <message@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: %s


assistant: ```c
int main(void) {
  printf("%s\n", message());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <message@plt>
  lea    D8(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8: %s


assistant: ```c
int main(void) {
  printf("%s\n", message());
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D70(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L30
L73:
  movss  0x14(%rsp),%xmm0
  comiss 0x8(%rsp),%xmm0
  jb     L66
  movss  0x4(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L3
L66:
  movss  0x14(%rsp),%xmm0
  comiss 0xc(%rsp),%xmm0
  jb     L24
  movss  0x8(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L38
L24:
  movss  0x14(%rsp),%xmm0
  comiss 0x10(%rsp),%xmm0
  jb     L127
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L28
L127:
  movss  0x10(%rsp),%xmm0
  comiss 0x14(%rsp),%xmm0
  ja     L2
L90:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L30:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L3:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L38:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L28:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L127
L2:
  lea    D68(%rip),%rdi
  call   <printf@plt>
  jmp    L90
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D46
data_type: string
name: disassemble_data
arguments: data_tag: D70
data_type: string
name: disassemble_data
arguments: data_tag: D37
data_type: string
name: disassemble_data
arguments: data_tag: D53
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D41
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D68
data_type: string

tool: D46: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D70: %f

tool: D37: Thank you. Now enter student score (perrcent) >

tool: D53: Student has an A grade


tool: D13: Student has an B grade


tool: D41: Student has an C grade


tool: D28: Student has an D grade


tool: D68: Student has an F grade


assistant: ```c
int main(void) {
  float A, B, C, D, avg;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f", &A);
  scanf("%f", &B);
  scanf("%f", &C);
  scanf("%f", &D);
  printf("Thank you. Now enter student score (perrcent) >");
  scanf("%f", &avg);
  if (avg >= A)
    printf("Student has an A grade\n");
  if (avg >= B && avg < A)
    printf("Student has an B grade\n");
  if (avg >= C && avg < B)
    printf("Student has an C grade\n");
  if (avg >= D && avg < C) {
    printf("Student has an D grade\n");
  }
  if (avg < D) {
    printf("Student has an F grade\n");
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D50(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L87
L103:
  comiss 0x8(%rsp),%xmm0
  jb     L44
  movss  0x4(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L104
L44:
  comiss 0xc(%rsp),%xmm0
  jb     L101
  movss  0x8(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L11
L101:
  comiss 0x10(%rsp),%xmm0
  jb     L134
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L123
L134:
  movss  0x10(%rsp),%xmm0
  comiss 0x14(%rsp),%xmm0
  ja     L138
L137:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L87:
  lea    D78(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L103
L138:
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L137
L123:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L134
L104:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L44
L11:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L101
L120:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D49
data_type: string
name: read_data
arguments: data_tag: D50
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D78
data_type: string
name: read_data
arguments: data_tag: D54
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D47
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D49: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D50: %f

tool: D1: Thank you. Now enter student score (perrcent) >

tool: D78: Student has an A grade


tool: D54: Student has an F grade


tool: D36: Student has an D grade


tool: D47: Student has an B grade


tool: D17: Student has an C grade


assistant: ```c
int main(void) {
  float A, B, C, D, avg;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f", &A);
  scanf("%f", &B);
  scanf("%f", &C);
  scanf("%f", &D);
  printf("Thank you. Now enter student score (perrcent) >");
  scanf("%f", &avg);
  if (avg >= A)
    printf("Student has an A grade\n");
  if (avg >= B && avg < A)
    printf("Student has an B grade\n");
  if (avg >= C && avg < B)
    printf("Student has an C grade\n");
  if (avg >= D && avg < C) {
    printf("Student has an D grade\n");
  }
  if (avg < D) {
    printf("Student has an F grade\n");
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D70(%rip),%rdi
  lea    D51(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D63(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L62
L52:
  comiss 0x8(%rsp),%xmm0
  jb     L87
  movss  0x4(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L80
L87:
  comiss 0xc(%rsp),%xmm0
  jb     L70
  movss  0x8(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L128
L70:
  comiss 0x10(%rsp),%xmm0
  jb     L18
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  ja     L76
L18:
  movss  0x10(%rsp),%xmm0
  comiss 0x14(%rsp),%xmm0
  ja     L116
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L62:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L52
L116:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L76:
  lea    D77(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L80:
  lea    D61(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L87
L128:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  movss  0x14(%rsp),%xmm0
  jmp    L70
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D70
type: string
name: disassemble_data
arguments: data_tag: D51
type: string
name: disassemble_data
arguments: data_tag: D63
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D77
type: string
name: disassemble_data
arguments: data_tag: D61
type: string
name: disassemble_data
arguments: data_tag: D24
type: string

tool: D70: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D51: %f

tool: D63: Thank you. Now enter student score (perrcent) >

tool: D28: Student has an A grade


tool: D33: Student has an F grade


tool: D77: Student has an D grade


tool: D61: Student has an B grade


tool: D24: Student has an C grade


assistant: ```c
int main(void) {
  float A, B, C, D, avg;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f", &A);
  scanf("%f", &B);
  scanf("%f", &C);
  scanf("%f", &D);
  printf("Thank you. Now enter student score (perrcent) >");
  scanf("%f", &avg);
  if (avg >= A)
    printf("Student has an A grade\n");
  if (avg >= B && avg < A)
    printf("Student has an B grade\n");
  if (avg >= C && avg < B)
    printf("Student has an C grade\n");
  if (avg >= D && avg < C) {
    printf("Student has an D grade\n");
  }
  if (avg < D) {
    printf("Student has an F grade\n");
  }
  return (0);
}
```