ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x762,%ebx
  jmp    L67
  nopl   (%rax)
L17:
  imul   $0xc28f5c29,%ebx,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L61
  ror    $0x4,%eax
  mov    %ebx,%esi
  cmp    $0xa3d70a,%eax
  ja     L31
L45:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x777,%ebx
  je     L52
L67:
  test   $0x3,%bl
  je     L17
  mov    %ebx,%esi
L31:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x777,%ebx
  jne    L67
L52:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %ebx,%esi
  jmp    L45
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D3: %4d is a leap year


tool: D8: %4d is not a leap year.


assistant: ```c
int main() {
  int x;
  for (x = 1890; x <= 1910; ++x) {
    if (x % 4 == 0) {
      if (x % 100 == 0) {
        if (x % 400 == 0)
          printf("%4d is a leap year\n", x);
        else
          printf("%4d is not a leap year.\n", x);
      } else
        printf("%4d is a leap year\n", x);
    } else
      printf("%4d is not a leap year.\n", x);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_reg_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
bool is_reg_file(const char *filename) {
  struct stat buf;
  bzero(&buf, sizeof buf);
  stat(filename, &buf);
  return (S_ISREG(buf.st_mode) ? true : false);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_reg_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  movzbl %al,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_reg_file(const char *filename) {
  struct stat buf;
  bzero(&buf, sizeof buf);
  stat(filename, &buf);
  return (S_ISREG(buf.st_mode) ? true : false);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_reg_file>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <bzero@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_reg_file(const char *filename) {
  struct stat buf;
  bzero(&buf, sizeof buf);
  stat(filename, &buf);
  return (S_ISREG(buf.st_mode) ? true : false);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_reg_file>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <bzero@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_reg_file(const char *filename) {
  struct stat buf;
  bzero(&buf, sizeof buf);
  stat(filename, &buf);
  return (S_ISREG(buf.st_mode) ? true : false);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edi
  call   <print_bin>
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  and    $0x1,%edx
  test   %edx,%edx
  je     L2
  mov    $0x31,%edx
  jmp    L16
L2:
  mov    $0x30,%edx
L16:
  mov    %eax,%esi
  mov    %edx,%edi
  call   <putc@plt>
  jmp    L11
L3:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x30,%edi
  call   <putc@plt>
L11:
  nop
  leave
  ret
```

assistant: ```c
void print_bin(int number) {
  if (number) {
    print_bin(number >> 1);
    putc((number & 1) ? '1' : '0', stdout);
  } else {
    putc('0', stdout);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_bin>:
  endbr64
  push   %rbx
  test   %edi,%edi
  je     L15
  mov    %edi,%ebx
  sar    %edi
  call   <print_bin>
  and    $0x1,%ebx
  lea    0x30(%rbx),%edi
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <putc@plt>
L4:
  pop    %rbx
  ret
L15:
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    $0x30,%edi
  call   <putc@plt>
  jmp    L4
```

assistant: ```c
void print_bin(int number) {
  if (number) {
    print_bin(number >> 1);
    putc((number & 1) ? '1' : '0', stdout);
  } else {
    putc('0', stdout);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_bin>:
  endbr64
  test   %edi,%edi
  je     L50
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  sar    %r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  jne    L52
  mov    D34(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L9:
  and    $0x1,%ebx
  mov    0x0(%rbp),%esi
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <putc@plt>
  nopl   0x0(%rax)
L50:
  mov    D34(%rip),%rax
  mov    $0x30,%edi
  mov    (%rax),%esi
  jmp    1050 <putc@plt>
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %edi,%r13d
  sar    $0x2,%r13d
  je     L47
  mov    %edi,%r14d
  sar    $0x3,%r14d
  je     L54
  sar    $0x4,%edi
  and    $0x1,%r14d
  call   <print_bin>
  mov    D34(%rip),%rbp
  lea    0x30(%r14),%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L67:
  and    $0x1,%r13d
  mov    0x0(%rbp),%esi
  lea    0x30(%r13),%edi
  call   <putc@plt>
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L47:
  mov    D34(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L36:
  and    $0x1,%r12d
  mov    0x0(%rbp),%esi
  lea    0x30(%r12),%edi
  call   <putc@plt>
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L54:
  mov    D34(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
  jmp    L67
```

assistant: ```c
void print_bin(int number) {
  if (number) {
    print_bin(number >> 1);
    putc((number & 1) ? '1' : '0', stdout);
  } else {
    putc('0', stdout);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_bin>:
  endbr64
  test   %edi,%edi
  je     L62
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  sar    %r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  jne    L66
  mov    D31(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L33:
  and    $0x1,%ebx
  mov    0x0(%rbp),%esi
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <putc@plt>
  nopl   0x0(%rax)
L62:
  mov    D31(%rip),%rax
  mov    $0x30,%edi
  mov    (%rax),%esi
  jmp    1050 <putc@plt>
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %edi,%r13d
  sar    $0x2,%r13d
  je     L46
  mov    %edi,%r14d
  sar    $0x3,%r14d
  je     L41
  sar    $0x4,%edi
  and    $0x1,%r14d
  call   <print_bin>
  mov    D31(%rip),%rbp
  lea    0x30(%r14),%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L42:
  and    $0x1,%r13d
  mov    0x0(%rbp),%esi
  lea    0x30(%r13),%edi
  call   <putc@plt>
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L46:
  mov    D31(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
L31:
  and    $0x1,%r12d
  mov    0x0(%rbp),%esi
  lea    0x30(%r12),%edi
  call   <putc@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L41:
  mov    D31(%rip),%rbp
  mov    $0x30,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
  jmp    L42
```

assistant: ```c
void print_bin(int number) {
  if (number) {
    print_bin(number >> 1);
    putc((number & 1) ? '1' : '0', stdout);
  } else {
    putc('0', stdout);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x3,-0x424(%rbp)
  je     L44
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L44:
  mov    -0x430(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bmount@plt>
  mov    -0x430(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x418(%rbp)
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x41c(%rbp)
  jmp    L48
L5:
  lea    -0x410(%rbp),%rdx
  mov    -0x41c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <bwrite@plt>
  addl   $0x1,-0x41c(%rbp)
L48:
  mov    -0x41c(%rbp),%eax
  cmp    %eax,-0x418(%rbp)
  ja     L5
  mov    -0x418(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,-0x414(%rbp)
  mov    -0x414(%rbp),%edx
  mov    -0x418(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <initSB@plt>
  mov    -0x418(%rbp),%eax
  mov    %eax,%edi
  call   <initMB@plt>
  mov    -0x414(%rbp),%eax
  mov    %eax,%edi
  call   <initAI@plt>
  mov    $0x7,%esi
  mov    $0x64,%edi
  call   <reservar_inodo@plt>
  mov    $0x0,%eax
  call   <bumount@plt>
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 3) {
    puts("Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int nbloques = atoi(argv[2]);
  unsigned char buf[1024];
  memset(buf, 0, 1024);
  for (int i = 0; i < nbloques; ++i)
    bwrite(i, buf);
  unsigned int ninodos = nbloques / 4;
  initSB(nbloques, ninodos);
  initMB(nbloques);
  initAI(ninodos);
  reservar_inodo('d', 7);
  bumount();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L26
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %ebp,%ebp
  je     L45
  mov    $0x0,%ebx
  mov    %rsp,%r12
L8:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bwrite@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L8
L45:
  mov    %ebp,%ebx
  shr    $0x2,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <initSB@plt>
  mov    %ebp,%edi
  call   <initMB@plt>
  mov    %ebx,%edi
  call   <initAI@plt>
  mov    $0x7,%esi
  mov    $0x64,%edi
  call   <reservar_inodo@plt>
  mov    $0x0,%eax
  call   <bumount@plt>
  mov    $0x0,%eax
L44:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L44
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 3) {
    puts("Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int nbloques = atoi(argv[2]);
  unsigned char buf[1024];
  memset(buf, 0, 1024);
  for (int i = 0; i < nbloques; ++i)
    bwrite(i, buf);
  unsigned int ninodos = nbloques / 4;
  initSB(nbloques, ninodos);
  initMB(nbloques);
  initAI(ninodos);
  reservar_inodo('d', 7);
  bumount();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L46
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  mov    %rsp,%r12
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <memset@plt>
  test   %ebp,%ebp
  je     L39
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <bwrite@plt>
  cmp    %ebp,%ebx
  jne    L29
L39:
  mov    %ebp,%r12d
  mov    %ebp,%edi
  shr    $0x2,%r12d
  mov    %r12d,%esi
  call   <initSB@plt>
  mov    %ebp,%edi
  call   <initMB@plt>
  mov    %r12d,%edi
  call   <initAI@plt>
  mov    $0x7,%esi
  mov    $0x64,%edi
  call   <reservar_inodo@plt>
  xor    %eax,%eax
  call   <bumount@plt>
  xor    %eax,%eax
L25:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L25
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 3) {
    puts("Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int nbloques = atoi(argv[2]);
  unsigned char buf[1024];
  memset(buf, 0, 1024);
  for (int i = 0; i < nbloques; ++i)
    bwrite(i, buf);
  unsigned int ninodos = nbloques / 4;
  initSB(nbloques, ninodos);
  initMB(nbloques);
  initAI(ninodos);
  reservar_inodo('d', 7);
  bumount();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L40
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  mov    %rsp,%r12
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  xor    %esi,%esi
  mov    $0x400,%edx
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <memset@plt>
  test   %ebp,%ebp
  je     L10
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <bwrite@plt>
  cmp    %ebp,%ebx
  jne    L41
L10:
  mov    %ebp,%r12d
  mov    %ebp,%edi
  shr    $0x2,%r12d
  mov    %r12d,%esi
  call   <initSB@plt>
  mov    %ebp,%edi
  call   <initMB@plt>
  mov    %r12d,%edi
  call   <initAI@plt>
  mov    $0x7,%esi
  mov    $0x64,%edi
  call   <reservar_inodo@plt>
  xor    %eax,%eax
  call   <bumount@plt>
  xor    %eax,%eax
L1:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L1
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 3) {
    puts("Uso: mi_mkfs <nombre_fichero> <cantidad_bloques>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int nbloques = atoi(argv[2]);
  unsigned char buf[1024];
  memset(buf, 0, 1024);
  for (int i = 0; i < nbloques; ++i)
    bwrite(i, buf);
  unsigned int ninodos = nbloques / 4;
  initSB(nbloques, ninodos);
  initMB(nbloques);
  initAI(ninodos);
  reservar_inodo('d', 7);
  bumount();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quaternion_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x50(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x50(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x50(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  movsd  0x18(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x58(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x58(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x58(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x58(%rbp),%rax
  movsd  0x18(%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  -0x18(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  mulsd  -0x10(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x48(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x10(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  mov    -0x48(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x18(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  add    $0x18,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void quaternion_mult(double z[4], double x[4], double y[4]) {
  double a = x[0];
  double b = x[1];
  double c = x[2];
  double d = x[3];
  double y0 = y[0];
  double y1 = y[1];
  double y2 = y[2];
  double y3 = y[3];
  z[0] = a * y0 - b * y1 - c * y2 - d * y3;
  z[1] = b * y0 + a * y1 - d * y2 + c * y3;
  z[2] = c * y0 + d * y1 + a * y2 - b * y3;
  z[3] = d * y0 - c * y1 + b * y2 + a * y3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quaternion_mult>:
  endbr64
  movsd  (%rsi),%xmm2
  movsd  0x8(%rsi),%xmm3
  movsd  0x10(%rsi),%xmm4
  movsd  0x18(%rsi),%xmm0
  movsd  (%rdx),%xmm8
  movsd  0x8(%rdx),%xmm7
  movsd  0x10(%rdx),%xmm6
  movsd  0x18(%rdx),%xmm5
  movapd %xmm2,%xmm1
  mulsd  %xmm8,%xmm1
  movapd %xmm3,%xmm9
  mulsd  %xmm7,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm6,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm5,%xmm9
  subsd  %xmm9,%xmm1
  movsd  %xmm1,(%rdi)
  movapd %xmm3,%xmm1
  mulsd  %xmm8,%xmm1
  movapd %xmm2,%xmm9
  mulsd  %xmm7,%xmm9
  addsd  %xmm9,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm6,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm5,%xmm9
  addsd  %xmm9,%xmm1
  movsd  %xmm1,0x8(%rdi)
  movapd %xmm4,%xmm1
  mulsd  %xmm8,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm7,%xmm9
  addsd  %xmm9,%xmm1
  movapd %xmm2,%xmm9
  mulsd  %xmm6,%xmm9
  addsd  %xmm9,%xmm1
  movapd %xmm3,%xmm9
  mulsd  %xmm5,%xmm9
  subsd  %xmm9,%xmm1
  movsd  %xmm1,0x10(%rdi)
  mulsd  %xmm8,%xmm0
  mulsd  %xmm7,%xmm4
  subsd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm5,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void quaternion_mult(double z[4], double x[4], double y[4]) {
  double a = x[0];
  double b = x[1];
  double c = x[2];
  double d = x[3];
  double y0 = y[0];
  double y1 = y[1];
  double y2 = y[2];
  double y3 = y[3];
  z[0] = a * y0 - b * y1 - c * y2 - d * y3;
  z[1] = b * y0 + a * y1 - d * y2 + c * y3;
  z[2] = c * y0 + d * y1 + a * y2 - b * y3;
  z[3] = d * y0 - c * y1 + b * y2 + a * y3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quaternion_mult>:
  endbr64
  movsd  (%rsi),%xmm2
  movsd  0x8(%rsi),%xmm3
  movsd  (%rdx),%xmm8
  movsd  0x8(%rdx),%xmm7
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm9
  movsd  0x10(%rsi),%xmm4
  movsd  0x10(%rdx),%xmm6
  mulsd  %xmm7,%xmm9
  movsd  0x18(%rsi),%xmm0
  movsd  0x18(%rdx),%xmm5
  mulsd  %xmm8,%xmm1
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm6,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm5,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm2,%xmm9
  mulsd  %xmm7,%xmm9
  movsd  %xmm1,(%rdi)
  movapd %xmm3,%xmm1
  mulsd  %xmm8,%xmm1
  addsd  %xmm9,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm6,%xmm9
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm5,%xmm9
  addsd  %xmm9,%xmm1
  movapd %xmm0,%xmm9
  mulsd  %xmm7,%xmm9
  mulsd  %xmm8,%xmm0
  movsd  %xmm1,0x8(%rdi)
  movapd %xmm4,%xmm1
  mulsd  %xmm8,%xmm1
  mulsd  %xmm7,%xmm4
  addsd  %xmm9,%xmm1
  movapd %xmm2,%xmm9
  mulsd  %xmm6,%xmm9
  subsd  %xmm4,%xmm0
  mulsd  %xmm5,%xmm2
  addsd  %xmm9,%xmm1
  movapd %xmm3,%xmm9
  mulsd  %xmm6,%xmm3
  mulsd  %xmm5,%xmm9
  addsd  %xmm3,%xmm0
  subsd  %xmm9,%xmm1
  addsd  %xmm2,%xmm0
  movsd  %xmm1,0x10(%rdi)
  movsd  %xmm0,0x18(%rdi)
  ret
```

assistant: ```c
void quaternion_mult(double z[4], double x[4], double y[4]) {
  double a = x[0];
  double b = x[1];
  double c = x[2];
  double d = x[3];
  double y0 = y[0];
  double y1 = y[1];
  double y2 = y[2];
  double y3 = y[3];
  z[0] = a * y0 - b * y1 - c * y2 - d * y3;
  z[1] = b * y0 + a * y1 - d * y2 + c * y3;
  z[2] = c * y0 + d * y1 + a * y2 - b * y3;
  z[3] = d * y0 - c * y1 + b * y2 + a * y3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quaternion_mult>:
  endbr64
  movupd (%rdx),%xmm2
  movupd (%rsi),%xmm6
  movupd 0x10(%rsi),%xmm7
  movupd 0x10(%rdx),%xmm3
  movapd %xmm2,%xmm0
  movapd %xmm6,%xmm4
  movapd %xmm6,%xmm1
  unpcklpd %xmm2,%xmm0
  shufpd $0x1,%xmm6,%xmm4
  movapd %xmm7,%xmm5
  unpckhpd %xmm2,%xmm2
  mulpd  %xmm0,%xmm1
  movapd %xmm4,%xmm9
  shufpd $0x1,%xmm7,%xmm5
  movapd %xmm3,%xmm8
  mulpd  %xmm7,%xmm0
  unpcklpd %xmm3,%xmm8
  unpckhpd %xmm3,%xmm3
  mulpd  %xmm2,%xmm9
  mulpd  %xmm5,%xmm2
  mulpd  %xmm8,%xmm7
  mulpd  %xmm3,%xmm5
  mulpd  %xmm8,%xmm6
  movapd %xmm0,%xmm10
  mulpd  %xmm3,%xmm4
  addpd  %xmm2,%xmm10
  subpd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  subpd  %xmm9,%xmm2
  addpd  %xmm9,%xmm1
  movsd  %xmm10,%xmm0
  movsd  %xmm2,%xmm1
  addpd  %xmm6,%xmm0
  subpd  %xmm7,%xmm1
  movapd %xmm1,%xmm2
  addpd  %xmm5,%xmm1
  subpd  %xmm5,%xmm2
  movsd  %xmm2,%xmm1
  movups %xmm1,(%rdi)
  movapd %xmm0,%xmm1
  addpd  %xmm4,%xmm0
  subpd  %xmm4,%xmm1
  movsd  %xmm1,%xmm0
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void quaternion_mult(double z[4], double x[4], double y[4]) {
  double a = x[0];
  double b = x[1];
  double c = x[2];
  double d = x[3];
  double y0 = y[0];
  double y1 = y[1];
  double y2 = y[2];
  double y3 = y[3];
  z[0] = a * y0 - b * y1 - c * y2 - d * y3;
  z[1] = b * y0 + a * y1 - d * y2 + c * y3;
  z[2] = c * y0 + d * y1 + a * y2 - b * y3;
  z[3] = d * y0 - c * y1 + b * y2 + a * y3;
}
```