ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_input>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D22(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  lea    D11(%rip),%rsi
  sub    $0x28,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x14(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  movl   $0x0,(%rbx)
  mov    %rax,%r15
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <fscanf@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    0x14(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L39
  movslq (%rbx),%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  addl   $0x1,(%rbx)
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L39:
  movl   $0x0,(%r14)
  mov    0x8(%rsp),%rbp
  mov    %r14,%rbx
  jmp    L46
  nopl   0x0(%rax)
L32:
  mov    %r15,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D20
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string

tool: D20: %d

tool: D22: /dev/stdin

tool: D11: r

assistant: ```c
void get_input(int *const str1, int *const str1_length, int *const str2, int *const str2_length) {
  FILE *instream;
  int *curr_str;
  int *curr_str_length;
  int node_num;
  instream = fopen("/dev/stdin", "r");
  curr_str = str1;
  curr_str_length = str1_length;
  *curr_str_length = 0;
  while (fscanf(instream, "%d", &node_num) != -1) {
    if (node_num == -1) {
      curr_str = str2;
      curr_str_length = str2_length;
      *curr_str_length = 0;
      continue;
    }
    curr_str[*curr_str_length] = node_num;
    (*curr_str_length)++;
  }
  fclose(instream);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movw   $0xffff,-0x14(%rbp)
  movq   $0xffffffffffffffff,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %ax,-0x12(%rbp)
  movzwl -0x12(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned f() {
  long long l2;
  unsigned short us;
  unsigned long long ul;
  short s2;
  ul = us = l2 = s2 = -1;
  return ul;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  mov    $0xffff,%eax
  ret
```

assistant: ```c
unsigned f() {
  long long l2;
  unsigned short us;
  unsigned long long ul;
  short s2;
  ul = us = l2 = s2 = -1;
  return ul;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    $0xffff,%eax
  ret
```

assistant: ```c
unsigned f() {
  long long l2;
  unsigned short us;
  unsigned long long ul;
  short s2;
  ul = us = l2 = s2 = -1;
  return ul;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0xffff,%eax
  ret
```

assistant: ```c
unsigned f() {
  long long l2;
  unsigned short us;
  unsigned long long ul;
  short s2;
  ul = us = l2 = s2 = -1;
  return ul;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xf,%esi
  mov    $0x5,%edi
  call   <addition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    $0x2d,%edi
  call   <subtraction@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x12c,%edi
  call   <division@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <multiplication@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D38
data_type: string
name: parse_data
arguments: data_label: D6
data_type: string

tool: D13: Addition: %d


tool: D39: Subtraction: %d


tool: D38: Division: %d


tool: D6: Multiplication: %d


assistant: ```c
int main() {
  int res;
  res = addition(5, 15);
  printf("Addition: %d\n", res);
  res = subtraction(45, 30);
  printf("Subtraction: %d\n", res);
  res = division(300, 10);
  printf("Division: %d\n", res);
  res = multiplication(8, 5);
  printf("Multiplication: %d\n", res);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  mov    $0x5,%edi
  call   <addition@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    $0x2d,%edi
  call   <subtraction@plt>
  mov    %eax,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x12c,%edi
  call   <division@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <multiplication@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string

tool: D9: Addition: %d


tool: D26: Subtraction: %d


tool: D5: Division: %d


tool: D23: Multiplication: %d


assistant: ```c
int main() {
  int res;
  res = addition(5, 15);
  printf("Addition: %d\n", res);
  res = subtraction(45, 30);
  printf("Subtraction: %d\n", res);
  res = division(300, 10);
  printf("Division: %d\n", res);
  res = multiplication(8, 5);
  printf("Multiplication: %d\n", res);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  mov    $0x5,%edi
  call   <addition@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    $0x2d,%edi
  call   <subtraction@plt>
  lea    D34(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x12c,%edi
  call   <division@plt>
  lea    D39(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <multiplication@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string
name: unpack_data
arguments: data_tag: D39
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D38: Addition: %d


tool: D34: Subtraction: %d


tool: D39: Division: %d


tool: D7: Multiplication: %d


assistant: ```c
int main() {
  int res;
  res = addition(5, 15);
  printf("Addition: %d\n", res);
  res = subtraction(45, 30);
  printf("Subtraction: %d\n", res);
  res = division(300, 10);
  printf("Division: %d\n", res);
  res = multiplication(8, 5);
  printf("Multiplication: %d\n", res);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  mov    $0x5,%edi
  call   <addition@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    $0x2d,%edi
  call   <subtraction@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x12c,%edi
  call   <division@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x8,%edi
  call   <multiplication@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D23
data_type: string

tool: D29: Addition: %d


tool: D13: Subtraction: %d


tool: D8: Division: %d


tool: D23: Multiplication: %d


assistant: ```c
int main() {
  int res;
  res = addition(5, 15);
  printf("Addition: %d\n", res);
  res = subtraction(45, 30);
  printf("Subtraction: %d\n", res);
  res = division(300, 10);
  printf("Division: %d\n", res);
  res = multiplication(8, 5);
  printf("Multiplication: %d\n", res);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L25
L33:
  cmpl   $0x50,-0x3f4(%rbp)
  jle    L25
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <getline2@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x0,-0x3f4(%rbp)
  jg     L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int main(void) {
  char str[1000];
  int len;
  while ((len = getline2(str)) > 0)
    if (len > 80)
      puts(str);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
L13:
  mov    %rbx,%rdi
  call   <getline2@plt>
  test   %eax,%eax
  jle    L4
  cmp    $0x50,%eax
  jle    L13
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L13
L4:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char str[1000];
  int len;
  while ((len = getline2(str)) > 0)
    if (len > 80)
      puts(str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L38
  nopl   0x0(%rax)
L29:
  cmp    $0x50,%eax
  jg     L33
L38:
  mov    %rbx,%rdi
  call   <getline2@plt>
  test   %eax,%eax
  jg     L29
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L38
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char str[1000];
  int len;
  while ((len = getline2(str)) > 0)
    if (len > 80)
      puts(str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L1
  nopl   0x0(%rax)
L21:
  cmp    $0x50,%eax
  jg     L34
L1:
  mov    %rbx,%rdi
  call   <getline2@plt>
  test   %eax,%eax
  jg     L21
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L1
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char str[1000];
  int len;
  while ((len = getline2(str)) > 0)
    if (len > 80)
      puts(str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L15:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L15
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memcpy(void *s1, const void *s2, size_t n) {
  size_t i;
  char *ptr1;
  char *ptr2;
  i = 0;
  ptr1 = ((char *)s1);
  ptr2 = ((char *)s2);
  while (i < n) {
    ptr1[i] = ptr2[i];
    i++;
  }
  return (((void *)ptr1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L19
  mov    $0x0,%ecx
L7:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L7
L19:
  ret
```

assistant: ```c
void *ft_memcpy(void *s1, const void *s2, size_t n) {
  size_t i;
  char *ptr1;
  char *ptr2;
  i = 0;
  ptr1 = ((char *)s1);
  ptr2 = ((char *)s2);
  while (i < n) {
    ptr1[i] = ptr2[i];
    i++;
  }
  return (((void *)ptr1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L11
  xor    %ecx,%ecx
  xchg   %ax,%ax
L5:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L5
L11:
  ret
```

assistant: ```c
void *ft_memcpy(void *s1, const void *s2, size_t n) {
  size_t i;
  char *ptr1;
  char *ptr2;
  i = 0;
  ptr1 = ((char *)s1);
  ptr2 = ((char *)s2);
  while (i < n) {
    ptr1[i] = ptr2[i];
    i++;
  }
  return (((void *)ptr1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L25
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rax
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L66
  cmp    $0x6,%rax
  jbe    L66
  mov    %rdx,%rsi
  cmp    $0xe,%rax
  jbe    L89
  and    $0xfffffffffffffff0,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L60:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L60
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%dl
  je     L25
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    -0x1(%rsi),%rdi
  cmp    $0x6,%rdi
  jbe    L125
L156:
  mov    (%rcx,%rax,1),%rdi
  mov    %rdi,(%r8,%rax,1)
  mov    %rsi,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rax
  cmp    %rdi,%rsi
  je     L25
L125:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  lea    0x1(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x1(%rcx,%rax,1),%esi
  mov    %sil,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x2(%rcx,%rax,1),%esi
  mov    %sil,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x3(%rcx,%rax,1),%esi
  mov    %sil,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x4(%rcx,%rax,1),%esi
  mov    %sil,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x5(%rcx,%rax,1),%esi
  mov    %sil,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L25
  movzbl 0x6(%rcx,%rax,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L25:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L58:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L58
  mov    %r8,%rax
  ret
L89:
  xor    %eax,%eax
  jmp    L156
```

assistant: ```c
void *ft_memcpy(void *s1, const void *s2, size_t n) {
  size_t i;
  char *ptr1;
  char *ptr2;
  i = 0;
  ptr1 = ((char *)s1);
  ptr2 = ((char *)s2);
  while (i < n) {
    ptr1[i] = ptr2[i];
    i++;
  }
  return (((void *)ptr1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_citrus_NONE_ctype_mbtowc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L31
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L72
L31:
  cmpq   $0x0,-0x20(%rbp)
  jne    L39
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L72
L39:
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L71
L44:
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
L71:
  mov    $0x0,%eax
  jmp    L72
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L72:
  pop    %rbp
  ret
```

assistant: ```c
int _citrus_NONE_ctype_mbtowc(void *__restrict cl, wchar_t *__restrict pwc, const char *__restrict s, size_t n, int *__restrict nresult) {
  if (s == NULL) {
    *nresult = 0;
    return (0);
  }
  if (n == 0) {
    return (EILSEQ);
  }
  if (pwc == NULL) {
    if (*s == '\0') {
      *nresult = 0;
    } else {
      *nresult = 1;
    }
    return (0);
  }
  *pwc = (wchar_t)(unsigned char)*s;
  *nresult = *s == '\0' ? 0 : 1;
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_citrus_NONE_ctype_mbtowc>:
  endbr64
  test   %rdx,%rdx
  je     L23
  test   %rcx,%rcx
  je     L12
  test   %rsi,%rsi
  je     L19
  movzbl (%rdx),%eax
  movzbl %al,%edx
  mov    %rdx,(%rsi)
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  mov    %eax,(%r8)
  mov    $0x0,%eax
  ret
L23:
  movl   $0x0,(%r8)
  mov    $0x0,%eax
  ret
L12:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
L19:
  cmpb   $0x0,(%rdx)
  jne    L4
  movl   $0x0,(%r8)
  mov    $0x0,%eax
  ret
L4:
  movl   $0x1,(%r8)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _citrus_NONE_ctype_mbtowc(void *__restrict cl, wchar_t *__restrict pwc, const char *__restrict s, size_t n, int *__restrict nresult) {
  if (s == NULL) {
    *nresult = 0;
    return (0);
  }
  if (n == 0) {
    return (EILSEQ);
  }
  if (pwc == NULL) {
    if (*s == '\0') {
      *nresult = 0;
    } else {
      *nresult = 1;
    }
    return (0);
  }
  *pwc = (wchar_t)(unsigned char)*s;
  *nresult = *s == '\0' ? 0 : 1;
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_citrus_NONE_ctype_mbtowc>:
  endbr64
  test   %rdx,%rdx
  je     L13
  test   %rcx,%rcx
  je     L5
  movzbl (%rdx),%eax
  test   %rsi,%rsi
  je     L26
  test   %al,%al
  movzbl %al,%edx
  setne  %al
  mov    %rdx,(%rsi)
  movzbl %al,%eax
  mov    %eax,(%r8)
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  test   %al,%al
  jne    L3
L13:
  movl   $0x0,(%r8)
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L3:
  movl   $0x1,(%r8)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _citrus_NONE_ctype_mbtowc(void *__restrict cl, wchar_t *__restrict pwc, const char *__restrict s, size_t n, int *__restrict nresult) {
  if (s == NULL) {
    *nresult = 0;
    return (0);
  }
  if (n == 0) {
    return (EILSEQ);
  }
  if (pwc == NULL) {
    if (*s == '\0') {
      *nresult = 0;
    } else {
      *nresult = 1;
    }
    return (0);
  }
  *pwc = (wchar_t)(unsigned char)*s;
  *nresult = *s == '\0' ? 0 : 1;
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_citrus_NONE_ctype_mbtowc>:
  endbr64
  test   %rdx,%rdx
  je     L35
  test   %rcx,%rcx
  je     L12
  movzbl (%rdx),%eax
  test   %rsi,%rsi
  je     L7
  test   %al,%al
  movzbl %al,%edx
  setne  %al
  mov    %rdx,(%rsi)
  movzbl %al,%eax
  mov    %eax,(%r8)
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  test   %al,%al
  jne    L5
L35:
  movl   $0x0,(%r8)
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L5:
  movl   $0x1,(%r8)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _citrus_NONE_ctype_mbtowc(void *__restrict cl, wchar_t *__restrict pwc, const char *__restrict s, size_t n, int *__restrict nresult) {
  if (s == NULL) {
    *nresult = 0;
    return (0);
  }
  if (n == 0) {
    return (EILSEQ);
  }
  if (pwc == NULL) {
    if (*s == '\0') {
      *nresult = 0;
    } else {
      *nresult = 1;
    }
    return (0);
  }
  *pwc = (wchar_t)(unsigned char)*s;
  *nresult = *s == '\0' ? 0 : 1;
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L8
  movl   $0xffffffff,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int m(char const key[], char const exp[], int val) {
  if (strcmp(key + 1, exp) != 0) {
    val = -1;
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<m>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  add    $0x1,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int m(char const key[], char const exp[], int val) {
  if (strcmp(key + 1, exp) != 0) {
    val = -1;
  }
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m>:
  endbr64
  push   %r12
  add    $0x1,%rdi
  mov    %edx,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int m(char const key[], char const exp[], int val) {
  if (strcmp(key + 1, exp) != 0) {
    val = -1;
  }
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m>:
  endbr64
  push   %r12
  add    $0x1,%rdi
  mov    %edx,%r12d
  call   <strcmp@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int m(char const key[], char const exp[], int val) {
  if (strcmp(key + 1, exp) != 0) {
    val = -1;
  }
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<handle_event_ver2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
int handle_event_ver2(int code, const unsigned char *ps, unsigned int ps_ptr, struct lv_event *event) {
  (void)code;
  (void)ps;
  (void)ps_ptr;
  (void)event;
  return 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<handle_event_ver2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int handle_event_ver2(int code, const unsigned char *ps, unsigned int ps_ptr, struct lv_event *event) {
  (void)code;
  (void)ps;
  (void)ps_ptr;
  (void)event;
  return 4;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<handle_event_ver2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int handle_event_ver2(int code, const unsigned char *ps, unsigned int ps_ptr, struct lv_event *event) {
  (void)code;
  (void)ps;
  (void)ps_ptr;
  (void)event;
  return 4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<handle_event_ver2>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int handle_event_ver2(int code, const unsigned char *ps, unsigned int ps_ptr, struct lv_event *event) {
  (void)code;
  (void)ps;
  (void)ps_ptr;
  (void)event;
  return 4;
}
```