ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_mark_cols>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L81
  mov    %rdi,%r14
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    %esi,%eax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%r15d
  shl    $0x3,%r15
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L26
L85:
  add    $0x1,%esi
L43:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L45
L65:
  mov    (%rax),%rdx
  movzbl (%rdx,%rbx,1),%edx
  cmp    $0x20,%dl
  je     L85
  cmp    %bpl,%dl
  jne    L43
  jmp    L85
L45:
  mov    %r14,%rcx
  mov    %esi,%edx
  mov    %r12d,%esi
  call   <blank_y@plt>
  add    %eax,%r13d
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  je     L13
L26:
  mov    %ebx,%edi
  mov    $0x0,%esi
  test   %r12d,%r12d
  jle    L45
  mov    (%r14),%rax
  lea    0x8(%rax,%r15,1),%rcx
  mov    $0x0,%esi
  jmp    L65
L81:
  mov    $0x0,%r13d
L13:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int trim_mark_cols(char ***piece, int x, int y, char c) {
  int i;
  int j;
  int blank_cols;
  int num_blanks;
  i = 0;
  j = 0;
  num_blanks = 0;
  blank_cols = 0;
  while (i < x) {
    while (j < y) {
      if ((*piece)[j][i] == c || (*piece)[j][i] == ' ')
        num_blanks++;
      j++;
    }
    blank_cols += blank_y(i, y, num_blanks, piece);
    num_blanks = 0;
    j = 0;
    i++;
  }
  return (blank_cols);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim_mark_cols>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L35
  movslq %esi,%rax
  lea    -0x1(%rdx),%ebp
  mov    %rdi,%r15
  mov    %edx,%ebx
  mov    %rax,0x8(%rsp)
  mov    %ecx,%r14d
  shl    $0x3,%rbp
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r13d,%edi
  xor    %r9d,%r9d
  test   %ebx,%ebx
  jle    L20
  mov    (%r15),%rdx
  xor    %r9d,%r9d
  lea    0x8(%rdx),%rax
  lea    (%rax,%rbp,1),%rcx
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L31:
  cmp    %r14b,%dl
  je     L21
  mov    %rax,%rdx
  cmp    %rax,%rcx
  je     L20
L26:
  add    $0x8,%rax
L82:
  mov    (%rdx),%rdx
  movzbl (%rdx,%r13,1),%edx
  cmp    $0x20,%dl
  jne    L31
L21:
  add    $0x1,%r9d
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L26
L20:
  mov    %r15,%rcx
  mov    %r9d,%edx
  mov    %ebx,%esi
  add    $0x1,%r13
  call   <blank_y@plt>
  add    %eax,%r12d
  cmp    0x8(%rsp),%r13
  jne    L30
L43:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  xor    %r12d,%r12d
  jmp    L43
```

assistant: ```c
int trim_mark_cols(char ***piece, int x, int y, char c) {
  int i;
  int j;
  int blank_cols;
  int num_blanks;
  i = 0;
  j = 0;
  num_blanks = 0;
  blank_cols = 0;
  while (i < x) {
    while (j < y) {
      if ((*piece)[j][i] == c || (*piece)[j][i] == ' ')
        num_blanks++;
      j++;
    }
    blank_cols += blank_y(i, y, num_blanks, piece);
    num_blanks = 0;
    j = 0;
    i++;
  }
  return (blank_cols);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim_mark_cols>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L8
  movslq %esi,%rax
  lea    -0x1(%rdx),%ebp
  mov    %rdi,%r15
  mov    %edx,%ebx
  mov    %rax,0x8(%rsp)
  mov    %ecx,%r14d
  shl    $0x3,%rbp
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r13d,%edi
  xor    %r9d,%r9d
  test   %ebx,%ebx
  jle    L58
  mov    (%r15),%rdx
  xor    %r9d,%r9d
  lea    0x8(%rdx),%rax
  lea    (%rax,%rbp,1),%rcx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L84:
  cmp    $0x20,%dl
  je     L52
  mov    %rax,%rdx
  cmp    %rax,%rcx
  je     L58
L72:
  add    $0x8,%rax
L27:
  mov    (%rdx),%rdx
  movzbl (%rdx,%r13,1),%edx
  cmp    %dl,%r14b
  jne    L84
L52:
  add    $0x1,%r9d
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L72
L58:
  mov    %r15,%rcx
  mov    %r9d,%edx
  mov    %ebx,%esi
  add    $0x1,%r13
  call   <blank_y@plt>
  add    %eax,%r12d
  cmp    %r13,0x8(%rsp)
  jne    L10
L55:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  xor    %r12d,%r12d
  jmp    L55
```

assistant: ```c
int trim_mark_cols(char ***piece, int x, int y, char c) {
  int i;
  int j;
  int blank_cols;
  int num_blanks;
  i = 0;
  j = 0;
  num_blanks = 0;
  blank_cols = 0;
  while (i < x) {
    while (j < y) {
      if ((*piece)[j][i] == c || (*piece)[j][i] == ' ')
        num_blanks++;
      j++;
    }
    blank_cols += blank_y(i, y, num_blanks, piece);
    num_blanks = 0;
    j = 0;
    i++;
  }
  return (blank_cols);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_signed_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  cltq
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  cltq
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  cltq
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int read_signed_int(unsigned char *data, long *value) {
  *value = (long)data[0] | (long)(data[1] << 8) | (long)(data[2] << 16) | (long)(data[3] << 24);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_signed_int>:
  endbr64
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  cltq
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  movslq %edx,%rdx
  movzbl (%rdi),%ecx
  or     %rcx,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int read_signed_int(unsigned char *data, long *value) {
  *value = (long)data[0] | (long)(data[1] << 8) | (long)(data[2] << 16) | (long)(data[3] << 24);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_signed_int>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  movzbl (%rdi),%ecx
  shl    $0x10,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  movzbl 0x3(%rdi),%edx
  cltq
  shl    $0x18,%edx
  movslq %edx,%rdx
  or     %rcx,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_signed_int(unsigned char *data, long *value) {
  *value = (long)data[0] | (long)(data[1] << 8) | (long)(data[2] << 16) | (long)(data[3] << 24);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_signed_int>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  movzbl (%rdi),%ecx
  shl    $0x10,%edx
  shl    $0x8,%eax
  or     %edx,%eax
  movzbl 0x3(%rdi),%edx
  cltq
  shl    $0x18,%edx
  movslq %edx,%rdx
  or     %rcx,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_signed_int(unsigned char *data, long *value) {
  *value = (long)data[0] | (long)(data[1] << 8) | (long)(data[2] << 16) | (long)(data[3] << 24);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inorderTraversal0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L27
L16:
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <traverse@plt>
  mov    -0x10(%rbp),%rax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int *inorderTraversal0(struct TreeNode *root, int *returnSize) {
  if (!root)
    return NULL;
  *returnSize = 0;
  int *arr = (int *)malloc(sizeof(int));
  traverse(root, &arr, returnSize);
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inorderTraversal0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L28
  mov    %rsi,%rbp
  movl   $0x0,(%rsi)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <traverse@plt>
  mov    (%rsp),%rax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %rdi,%rax
  jmp    L8
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *inorderTraversal0(struct TreeNode *root, int *returnSize) {
  if (!root)
    return NULL;
  *returnSize = 0;
  int *arr = (int *)malloc(sizeof(int));
  traverse(root, &arr, returnSize);
  return arr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inorderTraversal0>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L12
  movl   $0x0,(%rsi)
  mov    %rsi,%r12
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <traverse@plt>
  mov    (%rsp),%rax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  jmp    L9
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *inorderTraversal0(struct TreeNode *root, int *returnSize) {
  if (!root)
    return NULL;
  *returnSize = 0;
  int *arr = (int *)malloc(sizeof(int));
  traverse(root, &arr, returnSize);
  return arr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inorderTraversal0>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  movl   $0x0,(%rsi)
  mov    %rsi,%r12
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <traverse@plt>
  mov    (%rsp),%rax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  jmp    L19
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *inorderTraversal0(struct TreeNode *root, int *returnSize) {
  if (!root)
    return NULL;
  *returnSize = 0;
  int *arr = (int *)malloc(sizeof(int));
  traverse(root, &arr, returnSize);
  return arr;
}
```
user: What is the c source code of the assembly code below:

```asm
<pty_setup_slave_term>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  cmp    $0xffffffff,%eax
  jne    L58
  mov    $0xffffffff,%eax
  jmp    L50
L58:
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L37
  mov    -0x10(%rbp),%edx
  mov    D52(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
L37:
  mov    -0x20(%rbp),%edx
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    D62(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x4,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    D55(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    D42(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  nop
  mov    D71(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  cmp    $0xffffffff,%eax
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L50
L35:
  mov    $0x0,%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int pty_setup_slave_term(int slave, int raw) {
  struct termios slave_termios;
  while (-1 == tcgetattr(slave, &slave_termios)) {
    return -1;
  }
  slave_termios.c_lflag = 0;
  if (raw == 0)
    slave_termios.c_lflag |= ICANON;
  slave_termios.c_iflag &= ~(ECHO | INLCR | ICRNL);
  slave_termios.c_cc[VEOF] = 4;
  slave_termios.c_cc[VMIN] = 1;
  slave_termios.c_cc[VTIME] = 0;
  while (-1 == tcsetattr(slave, TCSADRAIN, &slave_termios)) {
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pty_setup_slave_term>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <tcgetattr@plt>
  cmp    $0xffffffff,%eax
  je     L0
  movl   $0x0,0x10(%rsp)
  test   %ebp,%ebp
  jne    L2
  mov    D54(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
L2:
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  mov    D22(%rip),%rdx
  or     (%rdx),%eax
  mov    D29(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,(%rsp)
  mov    D25(%rip),%rax
  mov    (%rax),%rdx
  mov    0x8(%rsp),%rax
  movl   $0x4,(%rax,%rdx,4)
  mov    D28(%rip),%rax
  mov    (%rax),%rdx
  mov    0x8(%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    D61(%rip),%rax
  mov    (%rax),%rdx
  mov    0x8(%rsp),%rax
  movl   $0x0,(%rax,%rdx,4)
  mov    %rsp,%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <tcsetattr@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pty_setup_slave_term(int slave, int raw) {
  struct termios slave_termios;
  while (-1 == tcgetattr(slave, &slave_termios)) {
    return -1;
  }
  slave_termios.c_lflag = 0;
  if (raw == 0)
    slave_termios.c_lflag |= ICANON;
  slave_termios.c_iflag &= ~(ECHO | INLCR | ICRNL);
  slave_termios.c_cc[VEOF] = 4;
  slave_termios.c_cc[VMIN] = 1;
  slave_termios.c_cc[VTIME] = 0;
  while (-1 == tcsetattr(slave, TCSADRAIN, &slave_termios)) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pty_setup_slave_term>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  cmp    $0xffffffff,%eax
  je     L35
  movl   $0x0,0x10(%rsp)
  test   %ebx,%ebx
  je     L36
L16:
  mov    D43(%rip),%rdx
  mov    D64(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D30(%rip),%rdx
  or     (%rdx),%eax
  mov    D4(%rip),%rdx
  not    %eax
  and    %eax,(%rsp)
  mov    0x8(%rsp),%rax
  mov    (%rdx),%rdx
  movl   $0x4,(%rax,%rdx,4)
  mov    D35(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x1,(%rax,%rdx,4)
  mov    D8(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x0,(%rax,%rdx,4)
  mov    D11(%rip),%rax
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D66(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  jmp    L16
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pty_setup_slave_term(int slave, int raw) {
  struct termios slave_termios;
  while (-1 == tcgetattr(slave, &slave_termios)) {
    return -1;
  }
  slave_termios.c_lflag = 0;
  if (raw == 0)
    slave_termios.c_lflag |= ICANON;
  slave_termios.c_iflag &= ~(ECHO | INLCR | ICRNL);
  slave_termios.c_cc[VEOF] = 4;
  slave_termios.c_cc[VMIN] = 1;
  slave_termios.c_cc[VTIME] = 0;
  while (-1 == tcsetattr(slave, TCSADRAIN, &slave_termios)) {
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pty_setup_slave_term>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  cmp    $0xffffffff,%eax
  je     L21
  movl   $0x0,0x10(%rsp)
  test   %ebx,%ebx
  je     L16
L3:
  mov    D52(%rip),%rdx
  mov    D28(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D76(%rip),%rdx
  or     (%rdx),%eax
  mov    D72(%rip),%rdx
  not    %eax
  and    %eax,(%rsp)
  mov    0x8(%rsp),%rax
  mov    (%rdx),%rdx
  movl   $0x4,(%rax,%rdx,4)
  mov    D12(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x1,(%rax,%rdx,4)
  mov    D43(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x0,(%rax,%rdx,4)
  mov    D8(%rip),%rax
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  jmp    L3
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pty_setup_slave_term(int slave, int raw) {
  struct termios slave_termios;
  while (-1 == tcgetattr(slave, &slave_termios)) {
    return -1;
  }
  slave_termios.c_lflag = 0;
  if (raw == 0)
    slave_termios.c_lflag |= ICANON;
  slave_termios.c_iflag &= ~(ECHO | INLCR | ICRNL);
  slave_termios.c_cc[VEOF] = 4;
  slave_termios.c_cc[VMIN] = 1;
  slave_termios.c_cc[VTIME] = 0;
  while (-1 == tcsetattr(slave, TCSADRAIN, &slave_termios)) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_strnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L23
  mov    -0x18(%rbp),%rax
  jmp    L37
L19:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <ft_strncmp@plt>
  test   %rax,%rax
  jne    L34
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L37
L34:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  ja     L19
L2:
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
char *ft_strnstr(const char *haystack, const char *needle, size_t len) {
  size_t i;
  size_t n_len;
  i = 0;
  if (!(n_len = ft_strlen(needle)))
    return ((char *)haystack);
  while (haystack[i] && i + n_len - 1 < len) {
    if (ft_strncmp((char *)&((haystack[i])), needle, n_len) == 0)
      return ((char *)&((haystack[i])));
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strnstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rsi,%rdi
  call   <ft_strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rax
  test   %rbp,%rbp
  je     L47
  cmpb   $0x0,(%rbx)
  je     L11
  lea    -0x1(%rbp),%rax
  cmp    %rax,%r13
  jbe    L10
  mov    %rbx,%rax
  sub    %rbp,%rax
  lea    0x1(%rax,%r13,1),%r13
L69:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ft_strncmp@plt>
  test   %rax,%rax
  je     L51
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L92
  cmp    %rbx,%r13
  jne    L69
  mov    $0x0,%eax
  jmp    L47
L11:
  mov    $0x0,%eax
  jmp    L47
L10:
  mov    $0x0,%eax
  jmp    L47
L51:
  mov    %rbx,%rax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L92:
  mov    $0x0,%eax
  jmp    L47
```

assistant: ```c
char *ft_strnstr(const char *haystack, const char *needle, size_t len) {
  size_t i;
  size_t n_len;
  i = 0;
  if (!(n_len = ft_strlen(needle)))
    return ((char *)haystack);
  while (haystack[i] && i + n_len - 1 < len) {
    if (ft_strncmp((char *)&((haystack[i])), needle, n_len) == 0)
      return ((char *)&((haystack[i])));
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strnstr>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rax
  test   %rbp,%rbp
  je     L22
  cmpb   $0x0,(%rbx)
  je     L29
  lea    -0x1(%rbp),%rax
  cmp    %rax,%r13
  jbe    L29
  mov    %rbx,%rax
  sub    %rbp,%rax
  lea    0x1(%rax,%r13,1),%r13
  jmp    L15
  nopl   (%rax)
L4:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L29
  cmp    %rbx,%r13
  je     L29
L15:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ft_strncmp@plt>
  test   %rax,%rax
  jne    L4
  mov    %rbx,%rax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strnstr(const char *haystack, const char *needle, size_t len) {
  size_t i;
  size_t n_len;
  i = 0;
  if (!(n_len = ft_strlen(needle)))
    return ((char *)haystack);
  while (haystack[i] && i + n_len - 1 < len) {
    if (ft_strncmp((char *)&((haystack[i])), needle, n_len) == 0)
      return ((char *)&((haystack[i])));
    i++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strnstr>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %rax,%rbp
  mov    %rbx,%rax
  test   %rbp,%rbp
  je     L15
  cmpb   $0x0,(%rbx)
  je     L32
  lea    -0x1(%rbp),%rax
  cmp    %rax,%r13
  jbe    L32
  mov    %rbx,%rax
  sub    %rbp,%rax
  lea    0x1(%rax,%r13,1),%r13
  jmp    L35
  nopl   (%rax)
L52:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L32
  cmp    %rbx,%r13
  je     L32
L35:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ft_strncmp@plt>
  test   %rax,%rax
  jne    L52
  mov    %rbx,%rax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strnstr(const char *haystack, const char *needle, size_t len) {
  size_t i;
  size_t n_len;
  i = 0;
  if (!(n_len = ft_strlen(needle)))
    return ((char *)haystack);
  while (haystack[i] && i + n_len - 1 < len) {
    if (ft_strncmp((char *)&((haystack[i])), needle, n_len) == 0)
      return ((char *)&((haystack[i])));
    i++;
  }
  return (NULL);
}
```