ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Gamma_Density>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x28,%rsp
  comisd %xmm2,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  jae    L5
  xor    %eax,%eax
  call   <Gamma_Function_Max_Arg@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  comisd %xmm3,%xmm0
  jb     L17
  movapd %xmm3,%xmm1
  movapd %xmm2,%xmm0
  subsd  D20(%rip),%xmm1
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm2
  xorpd  D8(%rip),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm0,%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <Gamma_Function@plt>
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
L5:
  add    $0x28,%rsp
  ret
  nop
L17:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <log@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm0
  subsd  D20(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Ln_Gamma_Function@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x28,%rsp
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    10d0 <exp@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
type_infered: f64
name: read_data
arguments: data_tag: D8
type_infered: f32[4]

tool: D20: 1

tool: {"D8": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double Gamma_Density(double x, double nu) {
  if (x <= 0.0)
    return 0.0;
  if (nu <= Gamma_Function_Max_Arg())
    return pow(x, nu - 1.0) * exp(-x) / Gamma_Function(nu);
  else
    return exp((nu - 1.0) * log(x) - x - Ln_Gamma_Function(nu));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  je     L130
  cmpl   $0x9,-0x14(%rbp)
  jg     L66
  cmpl   $0x2,-0x14(%rbp)
  je     L24
  cmpl   $0x5,-0x14(%rbp)
  je     L56
  jmp    L66
L24:
  movl   $0x2,-0x4(%rbp)
L27:
  movl   $0x3,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L27
  nop
L121:
  movl   $0x4,-0x4(%rbp)
  jmp    L66
L96:
  nop
L56:
  movl   $0x5,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cmp    $0x1,%eax
  jle    L123
  movl   $0x6,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cmp    $0x2,%eax
  jle    L111
  jmp    L121
L123:
  movl   $0x7,-0x4(%rbp)
  cmpl   $0xc,-0x14(%rbp)
  je     L61
L111:
  movl   $0x8,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L96
  jmp    L66
L130:
  movl   $0x9,-0x4(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jne    L103
  movl   $0xa,-0x4(%rbp)
  jmp    L135
L103:
  movl   $0xb,-0x4(%rbp)
  jmp    L135
L61:
  nop
L135:
  movl   $0xc,-0x4(%rbp)
  nop
L66:
  movl   $0xd,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  switch (argc) {
  case 2:
    x = 2;
    do {
      x = 3;
    } while (argc > 0);
  four:
    x = 4;
    break;
  case 5:
    do {
      x = 5;
      if (argc-- > 1) {
        x = 6;
        if (argc-- > 2)
          goto four;
      } else {
        x = 7;
        if (argc == 12)
          goto twelve;
      }
      x = 8;
    } while (argc > 0);
    break;
  case 9:
    x = 9;
    if (argc == 10)
      x = 10;
    else
      x = 11;
  twelve:
    x = 12;
    break;
  }
  x = 13;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L12
  mov    $0xd,%eax
  ret
L12:
  jmp    L12
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  switch (argc) {
  case 2:
    x = 2;
    do {
      x = 3;
    } while (argc > 0);
  four:
    x = 4;
    break;
  case 5:
    do {
      x = 5;
      if (argc-- > 1) {
        x = 6;
        if (argc-- > 2)
          goto four;
      } else {
        x = 7;
        if (argc == 12)
          goto twelve;
      }
      x = 8;
    } while (argc > 0);
    break;
  case 9:
    x = 9;
    if (argc == 10)
      x = 10;
    else
      x = 11;
  twelve:
    x = 12;
    break;
  }
  x = 13;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L6
  mov    $0xd,%eax
  ret
L6:
  jmp    L6
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  switch (argc) {
  case 2:
    x = 2;
    do {
      x = 3;
    } while (argc > 0);
  four:
    x = 4;
    break;
  case 5:
    do {
      x = 5;
      if (argc-- > 1) {
        x = 6;
        if (argc-- > 2)
          goto four;
      } else {
        x = 7;
        if (argc == 12)
          goto twelve;
      }
      x = 8;
    } while (argc > 0);
    break;
  case 9:
    x = 9;
    if (argc == 10)
      x = 10;
    else
      x = 11;
  twelve:
    x = 12;
    break;
  }
  x = 13;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L18
  mov    $0xd,%eax
  ret
L18:
  jmp    L18
```

assistant: ```c
int main(int argc, char *argv[]) {
  int x = 1;
  switch (argc) {
  case 2:
    x = 2;
    do {
      x = 3;
    } while (argc > 0);
  four:
    x = 4;
    break;
  case 5:
    do {
      x = 5;
      if (argc-- > 1) {
        x = 6;
        if (argc-- > 2)
          goto four;
      } else {
        x = 7;
        if (argc == 12)
          goto twelve;
      }
      x = 8;
    } while (argc > 0);
    break;
  case 9:
    x = 9;
    if (argc == 10)
      x = 10;
    else
      x = 11;
  twelve:
    x = 12;
    break;
  }
  x = 13;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shortreverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void shortreverse(char s[]) {
  int c, i, j;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shortreverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L1
  cltq
  mov    $0x0,%edx
L0:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L0
L1:
  pop    %rbx
  ret
```

assistant: ```c
void shortreverse(char s[]) {
  int c, i, j;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shortreverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L3
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L5
L3:
  pop    %rbx
  ret
```

assistant: ```c
void shortreverse(char s[]) {
  int c, i, j;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shortreverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L1
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L19
L1:
  pop    %rbx
  ret
```

assistant: ```c
void shortreverse(char s[]) {
  int c, i, j;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qEncode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L60
L76:
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <qEscaped@plt>
  test   %rax,%rax
  je     L68
  addl   $0x3,-0x1c(%rbp)
  jmp    L60
L68:
  addl   $0x1,-0x1c(%rbp)
L60:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  cmpb   $0x0,-0x1d(%rbp)
  jne    L76
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <needMem@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L58
L79:
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <qEscaped@plt>
  test   %rax,%rax
  je     L43
  movsbl -0x1d(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  addq   $0x3,-0x10(%rbp)
  jmp    L58
L43:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x1d(%rbp),%edx
  mov    %dl,(%rax)
L58:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1d(%rbp)
  cmpb   $0x0,-0x1d(%rbp)
  jne    L79
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: Q%02X

assistant: ```c
char *qEncode(char *input) {
  int size = 0;
  char *s, *d, c;
  s = input;
  while ((c = *s++) != 0) {
    if (qEscaped(c))
      size += 3;
    else
      size += 1;
  }
  char *output = needMem(size + 1);
  s = input;
  d = output;
  while ((c = *s++) != 0) {
    if (qEscaped(c)) {
      sprintf(d, "Q%02X", (unsigned)c);
      d += 3;
    } else
      *d++ = c;
  }
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qEncode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x1(%rdi),%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L51
  mov    %rbp,%r13
  mov    $0x0,%ebx
L15:
  movsbl %dil,%edi
  call   <qEscaped@plt>
  mov    %rax,%rdx
  lea    0x3(%rbx),%eax
  add    $0x1,%ebx
  test   %rdx,%rdx
  cmovne %eax,%ebx
  add    $0x1,%r13
  movzbl -0x1(%r13),%edi
  test   %dil,%dil
  jne    L15
L67:
  lea    0x1(%rbx),%edi
  call   <needMem@plt>
  mov    %rax,%r13
  movzbl (%r12),%ebx
  test   %bl,%bl
  je     L63
  mov    %rax,%r12
  lea    D1(%rip),%r14
  jmp    L30
L51:
  mov    $0x0,%ebx
  jmp    L67
L48:
  mov    %bl,(%r12)
  lea    0x1(%r12),%r12
L49:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L63
L30:
  movsbl %bl,%edi
  call   <qEscaped@plt>
  test   %rax,%rax
  je     L48
  movsbl %bl,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  add    $0x3,%r12
  jmp    L49
L63:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: Q%02X

assistant: ```c
char *qEncode(char *input) {
  int size = 0;
  char *s, *d, c;
  s = input;
  while ((c = *s++) != 0) {
    if (qEscaped(c))
      size += 3;
    else
      size += 1;
  }
  char *output = needMem(size + 1);
  s = input;
  d = output;
  while ((c = *s++) != 0) {
    if (qEscaped(c)) {
      sprintf(d, "Q%02X", (unsigned)c);
      d += 3;
    } else
      *d++ = c;
  }
  return output;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<qEncode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L71
  mov    %rbp,%r13
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  call   <qEscaped@plt>
  mov    %rax,%r8
  lea    0x3(%rbx),%eax
  add    $0x1,%ebx
  test   %r8,%r8
  cmovne %eax,%ebx
  movsbl 0x0(%r13),%edi
  add    $0x1,%r13
  test   %dil,%dil
  jne    L14
  lea    0x1(%rbx),%edi
L75:
  call   <needMem@plt>
  movzbl (%r12),%ebx
  lea    D4(%rip),%r15
  mov    %rax,%r14
  mov    %rax,%r12
  test   %bl,%bl
  jne    L23
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rbp
  mov    %bl,(%r12)
  add    $0x1,%r12
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L59
L23:
  movsbl %bl,%r13d
  mov    %r13d,%edi
  call   <qEscaped@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  mov    %r13d,%edx
  mov    %r15,%rsi
  add    $0x1,%rbp
  call   <sprintf@plt>
  movzbl -0x1(%rbp),%ebx
  add    $0x3,%r12
  test   %bl,%bl
  jne    L23
L59:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L71:
  mov    $0x1,%edi
  jmp    L75
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: Q%02X

assistant: ```c
char *qEncode(char *input) {
  int size = 0;
  char *s, *d, c;
  s = input;
  while ((c = *s++) != 0) {
    if (qEscaped(c))
      size += 3;
    else
      size += 1;
  }
  char *output = needMem(size + 1);
  s = input;
  d = output;
  while ((c = *s++) != 0) {
    if (qEscaped(c)) {
      sprintf(d, "Q%02X", (unsigned)c);
      d += 3;
    } else
      *d++ = c;
  }
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qEncode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L30
  mov    %rbp,%r13
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  call   <qEscaped@plt>
  mov    %rax,%r8
  lea    0x3(%rbx),%eax
  add    $0x1,%ebx
  test   %r8,%r8
  cmovne %eax,%ebx
  movsbl 0x0(%r13),%edi
  add    $0x1,%r13
  test   %dil,%dil
  jne    L26
  lea    0x1(%rbx),%edi
L31:
  call   <needMem@plt>
  movzbl (%r12),%ebx
  lea    D5(%rip),%r15
  mov    %rax,%r14
  mov    %rax,%r12
  test   %bl,%bl
  jne    L9
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L75:
  add    $0x1,%rbp
  mov    %bl,(%r12)
  lea    0x1(%r12),%rax
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L24
L8:
  mov    %rax,%r12
L9:
  movsbl %bl,%r13d
  mov    %r13d,%edi
  call   <qEscaped@plt>
  test   %rax,%rax
  je     L75
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <sprintf@plt>
  movzbl -0x1(%rbp),%ebx
  lea    0x3(%r12),%rax
  test   %bl,%bl
  jne    L8
L24:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0x1,%edi
  jmp    L31
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: Q%02X

assistant: ```c
char *qEncode(char *input) {
  int size = 0;
  char *s, *d, c;
  s = input;
  while ((c = *s++) != 0) {
    if (qEscaped(c))
      size += 3;
    else
      size += 1;
  }
  char *output = needMem(size + 1);
  s = input;
  d = output;
  while ((c = *s++) != 0) {
    if (qEscaped(c)) {
      sprintf(d, "Q%02X", (unsigned)c);
      d += 3;
    } else
      *d++ = c;
  }
  return output;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1f4,%edx
  mov    $0x3e8,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D49
data_type: string
name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D0
data_type: string

tool: D26: usage:	graph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]

tool: D22: 	style - (a)sterisk (d)dash (p)eriod]

tool: D20: 	0 < xsize < %d, 0 < ysize < %d


tool: D49: 	-cC compression scheme, a for average, s for selection

tool: D11: 	-l prints license

tool: D0: 	file should contain float values in plain text

assistant: ```c
void usage() {
  printf("usage:\tgraph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]\n");
  printf("\tstyle - (a)sterisk (d)dash (p)eriod]\n");
  printf("\t0 < xsize < %d, 0 < ysize < %d\n", 1000, 500);
  printf("\t-cC compression scheme, a for average, s for selection\n");
  printf("\t-l prints license\n");
  printf("\tfile should contain float values in plain text\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x1f4,%edx
  mov    $0x3e8,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D50
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string
name: extract_symbolic_data
arguments: data_label: D46
type: string
name: extract_symbolic_data
arguments: data_label: D52
type: string
name: extract_symbolic_data
arguments: data_label: D47
type: string
name: extract_symbolic_data
arguments: data_label: D43
type: string

tool: D50: usage:	graph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]

tool: D26: 	style - (a)sterisk (d)dash (p)eriod]

tool: D46: 	0 < xsize < %d, 0 < ysize < %d


tool: D52: 	-cC compression scheme, a for average, s for selection

tool: D47: 	-l prints license

tool: D43: 	file should contain float values in plain text

assistant: ```c
void usage() {
  printf("usage:\tgraph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]\n");
  printf("\tstyle - (a)sterisk (d)dash (p)eriod]\n");
  printf("\t0 < xsize < %d, 0 < ysize < %d\n", 1000, 500);
  printf("\t-cC compression scheme, a for average, s for selection\n");
  printf("\t-l prints license\n");
  printf("\tfile should contain float values in plain text\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x1f4,%edx
  mov    $0x3e8,%esi
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string
name: disassemble_data
arguments: data_label: D35
type_guessed: string
name: disassemble_data
arguments: data_label: D57
type_guessed: string
name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D48
type_guessed: string

tool: D30: usage:	graph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]

tool: D15: 	style - (a)sterisk (d)dash (p)eriod]

tool: D35: 	0 < xsize < %d, 0 < ysize < %d


tool: D57: 	-cC compression scheme, a for average, s for selection

tool: D23: 	-l prints license

tool: D48: 	file should contain float values in plain text

assistant: ```c
void usage() {
  printf("usage:\tgraph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]\n");
  printf("\tstyle - (a)sterisk (d)dash (p)eriod]\n");
  printf("\t0 < xsize < %d, 0 < ysize < %d\n", 1000, 500);
  printf("\t-cC compression scheme, a for average, s for selection\n");
  printf("\t-l prints license\n");
  printf("\tfile should contain float values in plain text\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1f4,%edx
  mov    $0x3e8,%esi
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D7
data_type: string
name: extract_symbolic_data
arguments: tag: D40
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D8: usage:	graph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]

tool: D7: 	style - (a)sterisk (d)dash (p)eriod]

tool: D40: 	0 < xsize < %d, 0 < ysize < %d


tool: D19: 	-cC compression scheme, a for average, s for selection

tool: D9: 	-l prints license

tool: D5: 	file should contain float values in plain text

assistant: ```c
void usage() {
  printf("usage:\tgraph [-sstyle] [-xsize] [-ysize] [-cC] [-l] [file]\n");
  printf("\tstyle - (a)sterisk (d)dash (p)eriod]\n");
  printf("\t0 < xsize < %d, 0 < ysize < %d\n", 1000, 500);
  printf("\t-cC compression scheme, a for average, s for selection\n");
  printf("\t-l prints license\n");
  printf("\tfile should contain float values in plain text\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  lea    D1(%rip),%rax
  mov    %rax,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  jmp    L7
L5:
  mov    $0x0,%eax
  call   <abort@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: 

assistant: ```c
char *sstrdup(const char *str) {
  char *s = NULL;
  if (!str)
    str = "";
  s = strdup(str);
  if (s)
    return s;
  abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sstrdup>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  lea    D8(%rip),%rax
  cmove  %rax,%rdi
  call   <strdup@plt>
  test   %rax,%rax
  je     L16
L1:
  add    $0x8,%rsp
  ret
L16:
  call   <abort@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: 

assistant: ```c
char *sstrdup(const char *str) {
  char *s = NULL;
  if (!str)
    str = "";
  s = strdup(str);
  if (s)
    return s;
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sstrdup>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rax
  test   %rdi,%rdi
  cmove  %rax,%rdi
  call   <strdup@plt>
  test   %rax,%rax
  je     L7
L8:
  add    $0x8,%rsp
  ret
L7:
  call   <abort@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: 

assistant: ```c
char *sstrdup(const char *str) {
  char *s = NULL;
  if (!str)
    str = "";
  s = strdup(str);
  if (s)
    return s;
  abort();
}
```