ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  lea    D24(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x30(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x24(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  imul   $0x15180,0xc(%rsp),%r8d
  imul   $0xe10,0x14(%rsp),%eax
  add    %eax,%r8d
  imul   $0x3c,0x1c(%rsp),%eax
  add    %eax,%r8d
  add    0x24(%rsp),%r8d
  imul   $0x15180,0x8(%rsp),%eax
  imul   $0xe10,0x10(%rsp),%edx
  add    %edx,%eax
  imul   $0x3c,0x18(%rsp),%edx
  add    %edx,%eax
  add    0x20(%rsp),%eax
  sub    %eax,%r8d
  movslq %r8d,%rsi
  imul   $0xffffffffc22e4507,%rsi,%rsi
  shr    $0x20,%rsi
  add    %r8d,%esi
  sar    $0x10,%esi
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %esi,0x8(%rsp)
  imul   $0x15180,%esi,%eax
  sub    %eax,%r8d
  movslq %r8d,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r8d,%edx
  sar    $0xb,%edx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,0x10(%rsp)
  imul   $0xe10,%edx,%eax
  sub    %eax,%r8d
  movslq %r8d,%rcx
  imul   $0xffffffff88888889,%rcx,%rcx
  shr    $0x20,%rcx
  add    %r8d,%ecx
  sar    $0x5,%ecx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  mov    %ecx,0x18(%rsp)
  imul   $0x3c,%ecx,%eax
  sub    %eax,%r8d
  mov    %r8d,0x20(%rsp)
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string

tool: D24: %s %d

tool: D22: %d : %d : %d

tool: D13: %d dia(s)
%d hora(s)
%d minuto(s)
%d segundo(s)


assistant: ```c
int main() {
  int d1, d2, h1, h2, m1, m2, s1, s2, t1, t2, T;
  char *dia1, *dia2;
  scanf("%s %d", &dia1, &d1);
  scanf("%d : %d : %d", &h1, &m1, &s1);
  scanf("%s %d", &dia2, &d2);
  scanf("%d : %d : %d", &h2, &m2, &s2);
  t1 = (d1 * 86400) + (h1 * 3600) + (m1 * 60) + s1;
  t2 = (d2 * 86400) + (h2 * 3600) + (m2 * 60) + s2;
  T = t2 - t1;
  d1 = T / 86400;
  h1 = (T % 86400) / 3600;
  m1 = (((T % 86400) % 3600) / 60);
  s1 = (((T % 86400) % 3600) % 60);
  printf("%d dia(s)\n%d hora(s)\n%d minuto(s)\n%d segundo(s)\n", d1, h1, m1, s1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D28(%rip),%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    0x30(%rsp),%rsi
  call   <scanf@plt>
  lea    0x24(%rsp),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  imul   $0xe10,0x14(%rsp),%eax
  lea    D9(%rip),%rdi
  imul   $0x15180,0xc(%rsp),%r8d
  imul   $0xe10,0x10(%rsp),%edx
  add    %eax,%r8d
  imul   $0x3c,0x1c(%rsp),%eax
  add    %eax,%r8d
  imul   $0x15180,0x8(%rsp),%eax
  add    0x24(%rsp),%r8d
  add    %edx,%eax
  imul   $0x3c,0x18(%rsp),%edx
  add    %edx,%eax
  add    0x20(%rsp),%eax
  sub    %eax,%r8d
  movslq %r8d,%rsi
  mov    %r8d,%eax
  imul   $0xffffffffc22e4507,%rsi,%rsi
  sar    $0x1f,%eax
  shr    $0x20,%rsi
  add    %r8d,%esi
  sar    $0x10,%esi
  sub    %eax,%esi
  imul   $0x15180,%esi,%eax
  mov    %esi,0x8(%rsp)
  sub    %eax,%r8d
  movslq %r8d,%rdx
  mov    %r8d,%eax
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r8d,%edx
  sar    $0x1f,%eax
  sar    $0xb,%edx
  sub    %eax,%edx
  imul   $0xe10,%edx,%eax
  mov    %edx,0x10(%rsp)
  sub    %eax,%r8d
  movslq %r8d,%rcx
  mov    %r8d,%eax
  imul   $0xffffffff88888889,%rcx,%rcx
  sar    $0x1f,%eax
  shr    $0x20,%rcx
  add    %r8d,%ecx
  sar    $0x5,%ecx
  sub    %eax,%ecx
  imul   $0x3c,%ecx,%eax
  mov    %ecx,0x18(%rsp)
  sub    %eax,%r8d
  mov    %r8d,0x20(%rsp)
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D5: %s %d

tool: D28: %d : %d : %d

tool: D9: %d dia(s)
%d hora(s)
%d minuto(s)
%d segundo(s)


assistant: ```c
int main() {
  int d1, d2, h1, h2, m1, m2, s1, s2, t1, t2, T;
  char *dia1, *dia2;
  scanf("%s %d", &dia1, &d1);
  scanf("%d : %d : %d", &h1, &m1, &s1);
  scanf("%s %d", &dia2, &d2);
  scanf("%d : %d : %d", &h2, &m2, &s2);
  t1 = (d1 * 86400) + (h1 * 3600) + (m1 * 60) + s1;
  t2 = (d2 * 86400) + (h2 * 3600) + (m2 * 60) + s2;
  T = t2 - t1;
  d1 = T / 86400;
  h1 = (T % 86400) / 3600;
  m1 = (((T % 86400) % 3600) / 60);
  s1 = (((T % 86400) % 3600) % 60);
  printf("%d dia(s)\n%d hora(s)\n%d minuto(s)\n%d segundo(s)\n", d1, h1, m1, s1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D17(%rip),%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  lea    0xc(%rsp),%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    0x30(%rsp),%rsi
  call   <scanf@plt>
  lea    0x24(%rsp),%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  imul   $0xe10,0x14(%rsp),%eax
  lea    D21(%rip),%rdi
  imul   $0x15180,0xc(%rsp),%r8d
  imul   $0xe10,0x10(%rsp),%edx
  add    %eax,%r8d
  imul   $0x3c,0x1c(%rsp),%eax
  add    %eax,%r8d
  imul   $0x15180,0x8(%rsp),%eax
  add    0x24(%rsp),%r8d
  add    %edx,%eax
  imul   $0x3c,0x18(%rsp),%edx
  add    %edx,%eax
  add    0x20(%rsp),%eax
  sub    %eax,%r8d
  movslq %r8d,%rsi
  mov    %r8d,%eax
  imul   $0xffffffffc22e4507,%rsi,%rsi
  sar    $0x1f,%eax
  shr    $0x20,%rsi
  add    %r8d,%esi
  sar    $0x10,%esi
  sub    %eax,%esi
  imul   $0x15180,%esi,%eax
  mov    %esi,0x8(%rsp)
  sub    %eax,%r8d
  movslq %r8d,%rdx
  mov    %r8d,%eax
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r8d,%edx
  sar    $0x1f,%eax
  sar    $0xb,%edx
  sub    %eax,%edx
  imul   $0xe10,%edx,%eax
  mov    %edx,0x10(%rsp)
  sub    %eax,%r8d
  movslq %r8d,%rcx
  mov    %r8d,%eax
  imul   $0xffffffff88888889,%rcx,%rcx
  sar    $0x1f,%eax
  shr    $0x20,%rcx
  add    %r8d,%ecx
  sar    $0x5,%ecx
  sub    %eax,%ecx
  imul   $0x3c,%ecx,%eax
  mov    %ecx,0x18(%rsp)
  sub    %eax,%r8d
  mov    %r8d,0x20(%rsp)
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D21
type: string

tool: D24: %s %d

tool: D17: %d : %d : %d

tool: D21: %d dia(s)
%d hora(s)
%d minuto(s)
%d segundo(s)


assistant: ```c
int main() {
  int d1, d2, h1, h2, m1, m2, s1, s2, t1, t2, T;
  char *dia1, *dia2;
  scanf("%s %d", &dia1, &d1);
  scanf("%d : %d : %d", &h1, &m1, &s1);
  scanf("%s %d", &dia2, &d2);
  scanf("%d : %d : %d", &h2, &m2, &s2);
  t1 = (d1 * 86400) + (h1 * 3600) + (m1 * 60) + s1;
  t2 = (d2 * 86400) + (h2 * 3600) + (m2 * 60) + s2;
  T = t2 - t1;
  d1 = T / 86400;
  h1 = (T % 86400) / 3600;
  m1 = (((T % 86400) % 3600) / 60);
  s1 = (((T % 86400) % 3600) % 60);
  printf("%d dia(s)\n%d hora(s)\n%d minuto(s)\n%d segundo(s)\n", d1, h1, m1, s1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<throw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L3
L8:
  addl   $0x1,-0xc(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D13: Result of throw %d:  %d + %d


tool: D2: You got your total in %d throws!


assistant: ```c
void throw(int total) {
  int count = 0;
  int dice1, dice2;
  srand(time(NULL));
  while (dice1 + dice2 != total) {
    count = count + 1;
    dice1 = rand() % 6 + 1;
    dice2 = rand() % 6 + 1;
    printf("Result of throw %d:  %d + %d\n", count, dice1, dice2);
  }
  printf("You got your total in %d throws!\n", count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<throw>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %r13d,%r13d
  je     L14
  mov    $0x0,%r12d
  lea    D0(%rip),%r14
L9:
  add    $0x1,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x1,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebp
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %ebp,%ebx
  cmp    %r13d,%ebx
  jne    L9
L7:
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    $0x0,%r12d
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D7
type: string

tool: D0: Result of throw %d:  %d + %d


tool: D7: You got your total in %d throws!


assistant: ```c
void throw(int total) {
  int count = 0;
  int dice1, dice2;
  srand(time(NULL));
  while (dice1 + dice2 != total) {
    count = count + 1;
    dice1 = rand() % 6 + 1;
    dice2 = rand() % 6 + 1;
    printf("Result of throw %d:  %d + %d\n", count, dice1, dice2);
  }
  printf("You got your total in %d throws!\n", count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<throw>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %r12d,%r12d
  je     L16
  lea    D18(%rip),%r13
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%rbx
  imul   $0x2aaaaaab,%rdx,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x1,%ebx
  mov    %r14d,%esi
  mov    %r13,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %ebx,%edx
  lea    0x1(%rax),%ebp
  xor    %eax,%eax
  mov    %ebp,%ecx
  add    %ebp,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L9
L16:
  pop    %rbx
  mov    %r14d,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  lea    D11(%rip),%rdi
  pop    %r13
  pop    %r14
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D18: Result of throw %d:  %d + %d


tool: D11: You got your total in %d throws!


assistant: ```c
void throw(int total) {
  int count = 0;
  int dice1, dice2;
  srand(time(NULL));
  while (dice1 + dice2 != total) {
    count = count + 1;
    dice1 = rand() % 6 + 1;
    dice2 = rand() % 6 + 1;
    printf("Result of throw %d:  %d + %d\n", count, dice1, dice2);
  }
  printf("You got your total in %d throws!\n", count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<throw>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %r12d,%r12d
  je     L19
  lea    D13(%rip),%r13
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%rbx
  imul   $0x2aaaaaab,%rdx,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x1,%ebx
  mov    %r14d,%esi
  mov    %r13,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %ebx,%edx
  lea    0x1(%rax),%ebp
  xor    %eax,%eax
  mov    %ebp,%ecx
  add    %ebp,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L8
L19:
  pop    %rbx
  mov    %r14d,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  lea    D9(%rip),%rdi
  pop    %r13
  pop    %r14
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: D13: Result of throw %d:  %d + %d


tool: D9: You got your total in %d throws!


assistant: ```c
void throw(int total) {
  int count = 0;
  int dice1, dice2;
  srand(time(NULL));
  while (dice1 + dice2 != total) {
    count = count + 1;
    dice1 = rand() % 6 + 1;
    dice2 = rand() % 6 + 1;
    printf("Result of throw %d:  %d + %d\n", count, dice1, dice2);
  }
  printf("You got your total in %d throws!\n", count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<argument_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L44
L45:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L44
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
  cmpl   $0x0,-0x4(%rbp)
  jle    L47
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  jmp    L28
L47:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int argument_count(char *argv) {
  int argc = 0;
  while (*argv)
    if (*argv++ == ',')
      ++argc;
  return (argc > 0) ? ++argc : 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<argument_count>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x0,%edx
L0:
  add    $0x1,%rdi
  cmp    $0x2c,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
  lea    0x1(%rdx),%eax
  test   %edx,%edx
  mov    $0x0,%edx
  cmovle %edx,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int argument_count(char *argv) {
  int argc = 0;
  while (*argv)
    if (*argv++ == ',')
      ++argc;
  return (argc > 0) ? ++argc : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<argument_count>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L15
  xchg   %ax,%ax
L9:
  add    $0x1,%rdi
  cmp    $0x2c,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
  cmp    $0x1,%r8d
  sbb    $0xffffffff,%r8d
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argument_count(char *argv) {
  int argc = 0;
  while (*argv)
    if (*argv++ == ',')
      ++argc;
  return (argc > 0) ? ++argc : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<argument_count>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L2
  xchg   %ax,%ax
L11:
  add    $0x1,%rdi
  cmp    $0x2c,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
  cmp    $0x1,%r8d
  sbb    $0xffffffff,%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argument_count(char *argv) {
  int argc = 0;
  while (*argv)
    if (*argv++ == ',')
      ++argc;
  return (argc > 0) ? ++argc : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drag_cd_gi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd D12(%rip),%xmm0
  jbe    L34
  movsd  -0x8(%rbp),%xmm1
  movsd  D75(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D103(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  D108(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L36
L34:
  movsd  -0x8(%rbp),%xmm0
  comisd D15(%rip),%xmm0
  jbe    L31
  movsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D118(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L36
L31:
  movsd  -0x8(%rbp),%xmm0
  comisd D36(%rip),%xmm0
  jb     L3
  movsd  -0x8(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D52(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L36
L3:
  movsd  D49(%rip),%xmm0
L36:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: f64[2]
name: retrieve_data
arguments: data_tag: D75
datatype: f64
name: retrieve_data
arguments: data_tag: D103
datatype: f64
name: retrieve_data
arguments: data_tag: D108
datatype: f64
name: retrieve_data
arguments: data_tag: D15
datatype: f64[2]
name: retrieve_data
arguments: data_tag: D7
datatype: f64
name: retrieve_data
arguments: data_tag: D118
datatype: f64
name: retrieve_data
arguments: data_tag: D36
datatype: f64[2]
name: retrieve_data
arguments: data_tag: D3
datatype: f64
name: retrieve_data
arguments: data_tag: D52
datatype: f64
name: retrieve_data
arguments: data_tag: D16
datatype: f64
name: retrieve_data
arguments: data_tag: D49
datatype: f64

tool: {"D12": [1.65,0.0113272]}

tool: D75: 0.0113272

tool: D103: 0.143989

tool: D108: 0.845362

tool: {"D15": [1.2,0.00701308]}

tool: D7: 0.00701308

tool: D118: 0.630556

tool: {"D36": [0.7,1.17628]}

tool: D3: 1.17628

tool: D52: 1.28079

tool: D16: 0.531976

tool: D49: 0.2282

assistant: ```c
double drag_cd_gi(double mach) {
  if (mach > 1.65)
    return 0.845362 + mach * (-0.143989 + mach * 0.0113272);
  else if (mach > 1.2)
    return 0.630556 + mach * 0.00701308;
  else if (mach >= 0.7)
    return 0.531976 + mach * (-1.28079 + mach * 1.17628);
  else
    return 0.2282;
}
```
user: What is the c source code of the assembly code below?

```asm
<drag_cd_gi>:
  endbr64
  comisd D109(%rip),%xmm0
  ja     L28
  comisd D56(%rip),%xmm0
  ja     L23
  comisd D78(%rip),%xmm0
  jb     L20
  movapd %xmm0,%xmm1
  mulsd  D93(%rip),%xmm1
  subsd  D82(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D19(%rip),%xmm0
  ret
L28:
  movapd %xmm0,%xmm1
  mulsd  D27(%rip),%xmm1
  subsd  D43(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D108(%rip),%xmm0
  ret
L23:
  mulsd  D113(%rip),%xmm0
  addsd  D49(%rip),%xmm0
  ret
L20:
  movsd  D115(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D109
type_guessed: f64[2]
name: retrieve_data
arguments: data_label: D56
type_guessed: f64[2]
name: retrieve_data
arguments: data_label: D78
type_guessed: f64[2]
name: retrieve_data
arguments: data_label: D93
type_guessed: f64
name: retrieve_data
arguments: data_label: D82
type_guessed: f64
name: retrieve_data
arguments: data_label: D19
type_guessed: f64
name: retrieve_data
arguments: data_label: D27
type_guessed: f64
name: retrieve_data
arguments: data_label: D43
type_guessed: f64
name: retrieve_data
arguments: data_label: D108
type_guessed: f64
name: retrieve_data
arguments: data_label: D113
type_guessed: f64
name: retrieve_data
arguments: data_label: D49
type_guessed: f64
name: retrieve_data
arguments: data_label: D115
type_guessed: f64

tool: {"D109": [1.65,0.0113272]}

tool: {"D56": [1.2,0.00701308]}

tool: {"D78": [0.7,1.17628]}

tool: D93: 1.17628

tool: D82: 1.28079

tool: D19: 0.531976

tool: D27: 0.0113272

tool: D43: 0.143989

tool: D108: 0.845362

tool: D113: 0.00701308

tool: D49: 0.630556

tool: D115: 0.2282

assistant: ```c
double drag_cd_gi(double mach) {
  if (mach > 1.65)
    return 0.845362 + mach * (-0.143989 + mach * 0.0113272);
  else if (mach > 1.2)
    return 0.630556 + mach * 0.00701308;
  else if (mach >= 0.7)
    return 0.531976 + mach * (-1.28079 + mach * 1.17628);
  else
    return 0.2282;
}
```