user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<debcmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%r12
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L87
  jmp    L190
  nopl   0x0(%rax)
L163:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L190
L87:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L163
L190:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r13
  test   %dil,%dil
  jne    L293
  jmp    L196
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  test   %dil,%dil
  je     L254
L293:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  cmpb   $0x3a,(%r12)
  movzbl 0x0(%r13),%eax
  je     L179
L237:
  cmpb   $0x3a,0x0(%r13)
  jne    L140
  jmp    L119
L176:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L235
  movsbl 0x0(%rbp),%esi
  movsbl (%rbx),%edi
  call   <debccmp@plt>
  test   %eax,%eax
  jne    L109
  add    $0x1,%rbx
  add    $0x1,%rbp
L140:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L176
L235:
  mov    %rbx,%r13
  jmp    L200
  nopl   0x0(%rax,%rax,1)
L94:
  add    $0x1,%r13
L200:
  movsbl 0x0(%r13),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L94
  mov    %rbp,%r12
  jmp    L210
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x1,%r12
L210:
  movsbl (%r12),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
  sub    %rbx,%r13
  sub    %rbp,%r12
  cmp    %r12,%r13
  jg     L21
  setl   %al
  movzbl %al,%eax
  neg    %eax
L109:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L254:
  cmpb   $0x3a,(%r12)
  jne    L237
L21:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L179:
  cmp    $0x3a,%al
  jne    L21
  mov    %r12,%rdx
  mov    %r13,%rax
  sub    %rbx,%rdx
  sub    %rbp,%rax
  cmp    %rax,%rdx
  jg     L21
  jge    L184
  jmp    L119
  nopl   0x0(%rax)
L207:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  jl     L119
  jg     L21
  add    $0x1,%rbx
  add    $0x1,%rbp
L184:
  cmp    %r12,%rbx
  jne    L207
  lea    0x1(%r12),%rbx
  lea    0x1(%r13),%rbp
  jmp    L140
L196:
  cmpb   $0x3a,(%r12)
  jne    L140
  jmp    L21
L119:
  mov    $0xffffffff,%eax
  jmp    L109
```

assistant: ```c
int debcmp(const char *d1, const char *d2) {
  const char *sd1 = d1, *sd2 = d2;
  while (*d1) {
    if (!isdigit(*d1)) {
      break;
    }
    ++d1;
  }
  while (*d2) {
    if (!isdigit(*d2)) {
      break;
    }
    ++d2;
  }
  if (*d1 == ':') {
    if (*d2 != ':') {
      return 1;
    }
    if (d1 - sd1 > d2 - sd2) {
      return 1;
    } else if (d1 - sd1 < d2 - sd2) {
      return -1;
    }
    while (sd1 != d1) {
      if (*sd1 < *sd2) {
        return -1;
      } else if (*sd2 < *sd1) {
        return 1;
      }
      ++sd1;
      ++sd2;
    }
    ++sd1;
    ++sd2;
    ++d1;
    ++d2;
  } else if (*d2 == ':') {
    return -1;
  } else {
    d1 = sd1;
    d2 = sd2;
  }
  while (!isdigit(*d1) && !isdigit(*d2)) {
    int r = debccmp(*d1, *d2);
    if (r) {
      return r;
    }
    ++d1;
    ++d2;
  }
  sd1 = d1;
  sd2 = d2;
  while (isdigit(*d1)) {
    ++d1;
  }
  while (isdigit(*d2)) {
    ++d2;
  }
  if (d1 - sd1 > d2 - sd2) {
    return 1;
  } else if (d1 - sd1 < d2 - sd2) {
    return -1;
  }
  return 0;
}
```