ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D60(%rip),%r12
  lea    D23(%rip),%rbp
  lea    D4(%rip),%r13
L35:
  lea    0x4(%rsp),%rbx
L17:
  cmpl   $0x0,0x4(%rsp)
  jg     L25
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jg     L17
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L35
L25:
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <recursedigit@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D60
type: string
name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D41
type: string
name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D64
type: string
name: disassemble_data
arguments: data_label: D55
type: string

tool: D60: Give me a number: 

tool: D23: %d

tool: D4: I need a positive integer.

tool: D41: The binary representation of: 

tool: D18: %d


tool: D64: is: 

tool: D55: 


assistant: ```c
int main() {
  int a;
  a = 0;
  while (0 >= a) {
    printf("Give me a number: ");
    scanf("%d", &a);
    if (0 >= a) {
      printf("I need a positive integer.\n");
    }
  }
  printf("The binary representation of: ");
  printf("%d\n", a);
  printf("is: ");
  recursedigit(a);
  printf("\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D68(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
L21:
  test   %eax,%eax
  jg     L14
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L3
L14:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <recursedigit@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  jmp    L21
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D34
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D68
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D65
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string

tool: D34: I need a positive integer.

tool: D37: Give me a number: 

tool: D68: %d

tool: D6: The binary representation of: 

tool: D15: %d


tool: D65: is: 

tool: D27: 


assistant: ```c
int main() {
  int a;
  a = 0;
  while (0 >= a) {
    printf("Give me a number: ");
    scanf("%d", &a);
    if (0 >= a) {
      printf("I need a positive integer.\n");
    }
  }
  printf("The binary representation of: ");
  printf("%d\n", a);
  printf("is: ");
  recursedigit(a);
  printf("\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
L7:
  test   %eax,%eax
  jg     L8
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L3
L8:
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <recursedigit@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  jmp    L7
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D50
data_type: string
name: retrieve_data
arguments: label: D47
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D34
data_type: string

tool: D19: I need a positive integer.

tool: D21: Give me a number: 

tool: D7: %d

tool: D50: The binary representation of: 

tool: D47: %d


tool: D26: is: 

tool: D34: 


assistant: ```c
int main() {
  int a;
  a = 0;
  while (0 >= a) {
    printf("Give me a number: ");
    scanf("%d", &a);
    if (0 >= a) {
      printf("I need a positive integer.\n");
    }
  }
  printf("The binary representation of: ");
  printf("%d\n", a);
  printf("is: ");
  recursedigit(a);
  printf("\n\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x1a8(%rbp)
  jmp    L24
L54:
  mov    -0x1a8(%rbp),%rax
  movl   $0xffffffff,-0x1a0(%rbp,%rax,4)
  addq   $0x1,-0x1a8(%rbp)
L24:
  cmpq   $0x63,-0x1a8(%rbp)
  jle    L54
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  movq   $0x0,-0x1a8(%rbp)
  jmp    L25
L6:
  mov    -0x1a8(%rbp),%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L19
  mov    $0x0,%eax
  call   <abort@plt>
L19:
  addq   $0x1,-0x1a8(%rbp)
L25:
  cmpq   $0x63,-0x1a8(%rbp)
  jle    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int main() {
  int array[100];
  long i;
  for (i = 0; i < 100; ++i)
    array[i] = -1;
  foo(array);
  for (i = 0; i < 100; ++i)
    if (array[i])
      abort();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x190(%rsp),%rbp
  mov    %rbx,%rax
L16:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L16
  mov    %rsp,%rdi
  call   <foo@plt>
  jmp    L3
L42:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L59
L3:
  cmpl   $0x0,(%rbx)
  je     L42
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L42
L59:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[100];
  long i;
  for (i = 0; i < 100; ++i)
    array[i] = -1;
  foo(array);
  for (i = 0; i < 100; ++i)
    if (array[i])
      abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%ecx
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xffffffffffffffff,%rax
  lea    0x190(%rsp),%rbp
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rdi
  call   <foo@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L46
L33:
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L18
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <abort@plt>
  cmp    %rbx,%rbp
  jne    L33
L46:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x1a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[100];
  long i;
  for (i = 0; i < 100; ++i)
    array[i] = -1;
  foo(array);
  for (i = 0; i < 100; ++i)
    if (array[i])
      abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%ecx
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xffffffffffffffff,%rax
  lea    0x190(%rsp),%rbp
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rdi
  call   <foo@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L27
L41:
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L20
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <abort@plt>
  cmp    %rbx,%rbp
  jne    L41
L27:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x1a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array[100];
  long i;
  for (i = 0; i < 100; ++i)
    array[i] = -1;
  foo(array);
  for (i = 0; i < 100; ++i)
    if (array[i])
      abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  rol    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int rol(unsigned int x, int n) {
  unsigned long result = (x << n) | (x >> (32 - n));
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rol>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned int rol(unsigned int x, int n) {
  unsigned long result = (x << n) | (x >> (32 - n));
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rol>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned int rol(unsigned int x, int n) {
  unsigned long result = (x << n) | (x >> (32 - n));
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rol>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  rol    %cl,%eax
  ret
```

assistant: ```c
unsigned int rol(unsigned int x, int n) {
  unsigned long result = (x << n) | (x >> (32 - n));
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hexnumstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <hexnumlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L17:
  mov    -0x20(%rbp),%rax
  and    $0xf,%eax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  lea    D3(%rip),%rax
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rdx)
  shrq   $0x4,-0x20(%rbp)
  subl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x0,-0x8(%rbp)
  jns    L17
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: 0123456789abcdef

assistant: ```c
int hexnumstr(char *buf, unsigned long num) {
  int i;
  int len = hexnumlen(num);
  buf[len] = '\0';
  for (i = len - 1; i >= 0; i--) {
    buf[i] = "0123456789abcdef"[(num & 0xf)];
    num >>= 4;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hexnumstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <hexnumlen@plt>
  movslq %eax,%rcx
  movb   $0x0,0x0(%rbp,%rcx,1)
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L1
  movslq %edx,%rdx
  add    %rbp,%rdx
  lea    -0x2(%rbp,%rcx,1),%rsi
  lea    -0x1(%rax),%ecx
  sub    %rcx,%rsi
  lea    D4(%rip),%rdi
L6:
  mov    %rbx,%rcx
  and    $0xf,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,(%rdx)
  shr    $0x4,%rbx
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L6
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: 0123456789abcdef

assistant: ```c
int hexnumstr(char *buf, unsigned long num) {
  int i;
  int len = hexnumlen(num);
  buf[len] = '\0';
  for (i = len - 1; i >= 0; i--) {
    buf[i] = "0123456789abcdef"[(num & 0xf)];
    num >>= 4;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hexnumstr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <hexnumlen@plt>
  movslq %eax,%rsi
  mov    %eax,%ecx
  movb   $0x0,0x0(%rbp,%rsi,1)
  sub    $0x1,%ecx
  js     L15
  movslq %ecx,%rdx
  lea    -0x2(%rbp,%rsi,1),%rsi
  mov    %ecx,%ecx
  add    %rbp,%rdx
  sub    %rcx,%rsi
  lea    D9(%rip),%rdi
  xchg   %ax,%ax
L17:
  mov    %rbx,%rcx
  sub    $0x1,%rdx
  shr    $0x4,%rbx
  and    $0xf,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L17
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: 0123456789abcdef

assistant: ```c
int hexnumstr(char *buf, unsigned long num) {
  int i;
  int len = hexnumlen(num);
  buf[len] = '\0';
  for (i = len - 1; i >= 0; i--) {
    buf[i] = "0123456789abcdef"[(num & 0xf)];
    num >>= 4;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hexnumstr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <hexnumlen@plt>
  movslq %eax,%rsi
  mov    %eax,%ecx
  movb   $0x0,0x0(%rbp,%rsi,1)
  sub    $0x1,%ecx
  js     L1
  movslq %ecx,%rdx
  lea    -0x2(%rbp,%rsi,1),%rsi
  mov    %ecx,%ecx
  add    %rbp,%rdx
  sub    %rcx,%rsi
  lea    D1(%rip),%rdi
  xchg   %ax,%ax
L19:
  mov    %rbx,%rcx
  sub    $0x1,%rdx
  shr    $0x4,%rbx
  and    $0xf,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  mov    %cl,0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L19
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: 0123456789abcdef

assistant: ```c
int hexnumstr(char *buf, unsigned long num) {
  int i;
  int len = hexnumlen(num);
  buf[len] = '\0';
  for (i = len - 1; i >= 0; i--) {
    buf[i] = "0123456789abcdef"[(num & 0xf)];
    num >>= 4;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dump_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L23
  mov    -0x24(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L23:
  cmpq   $0x0,-0x20(%rbp)
  je     L5
  cmpl   $0x0,-0x24(%rbp)
  je     L5
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0xf,%eax
  jne    L42
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
L42:
  addl   $0x1,-0x4(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L6
L5:
  nop
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D10
data_type: string

tool: D14: %s (%d): 

tool: D10: %02x 

assistant: ```c
void dump_data(FILE *fp, const uint8_t *data, int len, const char *msg) {
  if (msg)
    fprintf(fp, "%s (%d): ", msg, len);
  if (!data || !len)
    return;
  int i;
  for (i = 0; i < len; i++) {
    fprintf(fp, "%02x ", data[i]);
    if (i % 16 == 15)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  test   %rcx,%rcx
  je     L44
  mov    %rcx,%rdx
  mov    %ebp,%ecx
  lea    D23(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
L44:
  test   %r13,%r13
  je     L8
  test   %ebp,%ebp
  je     L8
  jle    L13
  mov    0x0(%r13),%edx
  lea    D15(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %ebp,%ebp
  mov    $0x1,%ebx
  lea    D15(%rip),%r14
  jmp    L58
L77:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
L16:
  add    $0x1,%rbx
L58:
  cmp    %rbp,%rbx
  je     L13
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0xf,%eax
  jne    L16
  jmp    L77
L13:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D23: %s (%d): 

tool: D15: %02x 

assistant: ```c
void dump_data(FILE *fp, const uint8_t *data, int len, const char *msg) {
  if (msg)
    fprintf(fp, "%s (%d): ", msg, len);
  if (!data || !len)
    return;
  int i;
  for (i = 0; i < len; i++) {
    fprintf(fp, "%02x ", data[i]);
    if (i % 16 == 15)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump_data>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  test   %rcx,%rcx
  je     L1
  mov    %rcx,%rdx
  lea    D6(%rip),%rsi
  mov    %ebp,%ecx
  xor    %eax,%eax
  call   <fprintf@plt>
L1:
  test   %r13,%r13
  je     L42
  test   %ebp,%ebp
  je     L42
  jle    L0
  mov    0x0(%r13),%edx
  lea    D10(%rip),%r14
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %r14,%rsi
  mov    $0x1,%ebx
  call   <fprintf@plt>
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rbx
L36:
  cmp    %rbx,%rbp
  je     L0
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %ebx,%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L34
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L34
  nopl   0x0(%rax)
L0:
  pop    %rbx
  mov    %r12,%rsi
  pop    %rbp
  mov    $0xa,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <fputc@plt>
  nopl   (%rax)
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string

tool: D6: %s (%d): 

tool: D10: %02x 

assistant: ```c
void dump_data(FILE *fp, const uint8_t *data, int len, const char *msg) {
  if (msg)
    fprintf(fp, "%s (%d): ", msg, len);
  if (!data || !len)
    return;
  int i;
  for (i = 0; i < len; i++) {
    fprintf(fp, "%02x ", data[i]);
    if (i % 16 == 15)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_data>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L23
  mov    %rcx,%rdx
  lea    D1(%rip),%rsi
  mov    %r15d,%ecx
  xor    %eax,%eax
  call   <fprintf@plt>
L23:
  test   %r12,%r12
  je     L34
  test   %r15d,%r15d
  je     L34
  jle    L8
  mov    (%r12),%edx
  lea    D4(%rip),%r13
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r13,%rsi
  movslq %r15d,%r14
  mov    $0x1,%ebx
  call   <fprintf@plt>
  cmp    $0x1,%r15d
  jne    L27
  jmp    L8
L17:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  je     L8
L27:
  mov    (%r12,%rbx,4),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %ebx,%eax
  and    $0xf,%eax
  cmp    $0xf,%eax
  jne    L17
  mov    %rbp,%rsi
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %rbx,%r14
  jne    L27
L8:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <fputc@plt>
  nopl   (%rax)
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D1: %s (%d): 

tool: D4: %02x 

assistant: ```c
void dump_data(FILE *fp, const uint8_t *data, int len, const char *msg) {
  if (msg)
    fprintf(fp, "%s (%d): ", msg, len);
  if (!data || !len)
    return;
  int i;
  for (i = 0; i < len; i++) {
    fprintf(fp, "%02x ", data[i]);
    if (i % 16 == 15)
      fprintf(fp, "\n");
  }
  fprintf(fp, "\n");
}
```