ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<mystrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mystrdup(char *str) {
  char *dest = malloc(strlen(str) + 1);
  if (dest)
    strcpy(dest, str);
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrdup(char *str) {
  char *dest = malloc(strlen(str) + 1);
  if (dest)
    strcpy(dest, str);
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mystrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(char *str) {
  char *dest = malloc(strlen(str) + 1);
  if (dest)
    strcpy(dest, str);
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mystrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(char *str) {
  char *dest = malloc(strlen(str) + 1);
  if (dest)
    strcpy(dest, str);
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  movsd  (%r12),%xmm0
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm6
  movsd  %xmm6,(%rsp)
  movsd  0x18(%rsp),%xmm5
  movsd  %xmm5,0x8(%rsp)
  movsd  0x8(%r12),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  mov    0x10(%rsp),%rbp
  mov    0x18(%rsp),%r15
  movsd  0x10(%r12),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movq   %rbp,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx)
  movq   %r15,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsp),%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  (%rsp),%xmm6
  movapd %xmm6,%xmm4
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm3
  movsd  %xmm3,0x8(%rbx)
  mulsd  %xmm6,%xmm0
  movapd %xmm5,%xmm3
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rbx)
  movq   %rbp,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rbx)
  movq   %r15,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm6,%xmm4
  mulsd  %xmm2,%xmm4
  movapd %xmm5,%xmm3
  mulsd  %xmm0,%xmm3
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x20(%rbx)
  mulsd  %xmm6,%xmm0
  mulsd  %xmm5,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,0x28(%rbx)
  xorpd  D9(%rip),%xmm1
  movsd  %xmm1,0x30(%rbx)
  movq   %rbp,%xmm0
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,0x38(%rbx)
  movsd  %xmm4,0x40(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void rotmatrix(double M[3][3], double rot[3]) {
  double c[3] = {cos(rot[0]), cos(rot[1]), cos(rot[2])};
  double s[3] = {sin(rot[0]), sin(rot[1]), sin(rot[2])};
  M[0][0] = c[2] * c[1];
  M[0][1] = c[2] * s[1] * s[0] - s[2] * c[0];
  M[0][2] = c[2] * s[1] * c[0] + s[2] * s[0];
  M[1][0] = s[2] * c[1];
  M[1][1] = s[2] * s[1] * s[0] + c[2] * c[0];
  M[1][2] = s[2] * s[1] * c[0] - c[2] * s[0];
  M[2][0] = -s[2];
  M[2][1] = c[1] * s[0];
  M[2][2] = c[2] * c[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotmatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  movsd  0x0(%rbp),%xmm0
  lea    0x28(%rsp),%r12
  lea    0x20(%rsp),%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x8(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm5
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm5,0x10(%rsp)
  call   <sincos@plt>
  movsd  0x10(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm6
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm6,(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm4
  movsd  (%rsp),%xmm6
  movsd  0x20(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm5
  movapd %xmm4,%xmm3
  movsd  0x18(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm0
  mulsd  %xmm2,%xmm3
  movapd %xmm5,%xmm7
  movapd %xmm1,%xmm8
  mulsd  %xmm0,%xmm8
  movsd  %xmm3,(%rbx)
  movapd %xmm2,%xmm3
  mulsd  %xmm6,%xmm3
  mulsd  %xmm0,%xmm6
  mulsd  %xmm3,%xmm7
  mulsd  %xmm1,%xmm3
  subsd  %xmm8,%xmm7
  movsd  %xmm7,0x8(%rbx)
  movapd %xmm5,%xmm7
  mulsd  %xmm0,%xmm7
  addsd  %xmm7,%xmm3
  movapd %xmm1,%xmm7
  mulsd  %xmm2,%xmm7
  mulsd  %xmm6,%xmm1
  movsd  %xmm3,0x10(%rbx)
  mulsd  %xmm5,%xmm2
  movapd %xmm4,%xmm3
  mulsd  %xmm0,%xmm3
  xorpd  D2(%rip),%xmm0
  mulsd  %xmm5,%xmm4
  movsd  %xmm0,0x30(%rbx)
  movsd  %xmm7,0x40(%rbx)
  subsd  %xmm2,%xmm1
  movsd  %xmm3,0x18(%rbx)
  movapd %xmm5,%xmm3
  mulsd  %xmm6,%xmm3
  movsd  %xmm4,0x38(%rbx)
  movsd  %xmm1,0x28(%rbx)
  addsd  %xmm7,%xmm3
  movsd  %xmm3,0x20(%rbx)
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void rotmatrix(double M[3][3], double rot[3]) {
  double c[3] = {cos(rot[0]), cos(rot[1]), cos(rot[2])};
  double s[3] = {sin(rot[0]), sin(rot[1]), sin(rot[2])};
  M[0][0] = c[2] * c[1];
  M[0][1] = c[2] * s[1] * s[0] - s[2] * c[0];
  M[0][2] = c[2] * s[1] * c[0] + s[2] * s[0];
  M[1][0] = s[2] * c[1];
  M[1][1] = s[2] * s[1] * s[0] + c[2] * c[0];
  M[1][2] = s[2] * s[1] * c[0] - c[2] * s[0];
  M[2][0] = -s[2];
  M[2][1] = c[1] * s[0];
  M[2][2] = c[2] * c[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rotmatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  movsd  0x0(%rbp),%xmm0
  lea    0x28(%rsp),%r12
  lea    0x20(%rsp),%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sincos@plt>
  movsd  0x8(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm5
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm5,0x10(%rsp)
  call   <sincos@plt>
  movsd  0x10(%rbp),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm7
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm7,(%rsp)
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  (%rsp),%xmm7
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm1
  movapd %xmm3,%xmm2
  movsd  0x28(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm7,%xmm2
  movapd %xmm1,%xmm10
  movapd %xmm5,%xmm9
  mulsd  %xmm0,%xmm10
  movapd %xmm4,%xmm8
  movapd %xmm1,%xmm6
  mulsd  %xmm3,%xmm8
  mulsd  %xmm0,%xmm7
  mulsd  %xmm3,%xmm6
  mulsd  %xmm2,%xmm9
  mulsd  %xmm1,%xmm2
  mulsd  %xmm5,%xmm3
  mulsd  %xmm7,%xmm1
  movsd  %xmm6,0x40(%rbx)
  subsd  %xmm10,%xmm9
  unpcklpd %xmm9,%xmm8
  subsd  %xmm3,%xmm1
  movups %xmm8,(%rbx)
  movapd %xmm5,%xmm8
  mulsd  %xmm0,%xmm8
  addsd  %xmm8,%xmm2
  movapd %xmm4,%xmm8
  mulsd  %xmm0,%xmm8
  xorpd  D6(%rip),%xmm0
  mulsd  %xmm5,%xmm4
  unpcklpd %xmm8,%xmm2
  movups %xmm2,0x10(%rbx)
  movapd %xmm5,%xmm2
  unpcklpd %xmm4,%xmm0
  mulsd  %xmm7,%xmm2
  movups %xmm0,0x30(%rbx)
  addsd  %xmm6,%xmm2
  unpcklpd %xmm1,%xmm2
  movups %xmm2,0x20(%rbx)
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void rotmatrix(double M[3][3], double rot[3]) {
  double c[3] = {cos(rot[0]), cos(rot[1]), cos(rot[2])};
  double s[3] = {sin(rot[0]), sin(rot[1]), sin(rot[2])};
  M[0][0] = c[2] * c[1];
  M[0][1] = c[2] * s[1] * s[0] - s[2] * c[0];
  M[0][2] = c[2] * s[1] * c[0] + s[2] * s[0];
  M[1][0] = s[2] * c[1];
  M[1][1] = s[2] * s[1] * s[0] + c[2] * c[0];
  M[1][2] = s[2] * s[1] * c[0] - c[2] * s[0];
  M[2][0] = -s[2];
  M[2][1] = c[1] * s[0];
  M[2][2] = c[2] * c[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sort_Double_Increase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jb     L14
  mov    $0xffffffff,%eax
  jmp    L0
L14:
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int Sort_Double_Increase(const void *a, const void *b) {
  if ((*(double *)(a)) <= (*(double *)(b)))
    return -1;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Sort_Double_Increase>:
  endbr64
  movsd  (%rsi),%xmm0
  comisd (%rdi),%xmm0
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int Sort_Double_Increase(const void *a, const void *b) {
  if ((*(double *)(a)) <= (*(double *)(b)))
    return -1;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Sort_Double_Increase>:
  endbr64
  movsd  (%rsi),%xmm0
  comisd (%rdi),%xmm0
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int Sort_Double_Increase(const void *a, const void *b) {
  if ((*(double *)(a)) <= (*(double *)(b)))
    return -1;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Sort_Double_Increase>:
  endbr64
  movsd  (%rsi),%xmm0
  comisd (%rdi),%xmm0
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int Sort_Double_Increase(const void *a, const void *b) {
  if ((*(double *)(a)) <= (*(double *)(b)))
    return -1;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %ecx,-0xdc(%rbp)
  mov    %r8,-0xe8(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rsi
  mov    -0xdc(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_xprintf@plt>
  mov    -0xe8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xe8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xvprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_xprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D18
datatype: string

tool: D0: %-10s %-10s %-3d %-8s 

tool: D18: 


assistant: ```c
void _msg(const char *type, const char *file, const char *func, int line, const char *fmt, ...) {
  _xprintf("%-10s %-10s %-3d %-8s ", file, func, line, type);
  {
    va_list arp;
    va_start(arp, fmt);
    xvprintf(fmt, arp);
    va_end(arp);
  }
  _xprintf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<_msg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %r8,%rbx
  mov    %rdi,%r8
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <_xprintf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <xvprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <_xprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string

tool: D1: %-10s %-10s %-3d %-8s 

tool: D11: 


assistant: ```c
void _msg(const char *type, const char *file, const char *func, int line, const char *fmt, ...) {
  _xprintf("%-10s %-10s %-3d %-8s ", file, func, line, type);
  {
    va_list arp;
    va_start(arp, fmt);
    xvprintf(fmt, arp);
    va_end(arp);
  }
  _xprintf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_msg>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbp
  mov    %r8,%rbp
  mov    %rdi,%r8
  lea    D8(%rip),%rdi
  sub    $0x8,%rsp
  call   <_xprintf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <xvprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <_xprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D18
type: string

tool: D8: %-10s %-10s %-3d %-8s 

tool: D18: 


assistant: ```c
void _msg(const char *type, const char *file, const char *func, int line, const char *fmt, ...) {
  _xprintf("%-10s %-10s %-3d %-8s ", file, func, line, type);
  {
    va_list arp;
    va_start(arp, fmt);
    xvprintf(fmt, arp);
    va_end(arp);
  }
  _xprintf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<_msg>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  push   %rbp
  mov    %r8,%rbp
  mov    %rdi,%r8
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <_xprintf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <xvprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <_xprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D13: %-10s %-10s %-3d %-8s 

tool: D6: 


assistant: ```c
void _msg(const char *type, const char *file, const char *func, int line, const char *fmt, ...) {
  _xprintf("%-10s %-10s %-3d %-8s ", file, func, line, type);
  {
    va_list arp;
    va_start(arp, fmt);
    xvprintf(fmt, arp);
    va_end(arp);
  }
  _xprintf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lqunit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L15
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L15
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rdx
  add    $0x10,%rdx
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L19
L15:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L19:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *lqunit(double *a, double *aunit) {
  double norm = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2] + a[3] * a[3]);
  if (!norm)
    aunit[0] = aunit[1] = aunit[2] = aunit[3] = 0;
  else {
    aunit[0] = a[0] / norm;
    aunit[1] = a[1] / norm;
    aunit[2] = a[2] / norm;
    aunit[3] = a[3] / norm;
  }
  return (aunit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lqunit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%r12
  movsd  0x8(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm2
  movsd  0x18(%rdi),%xmm1
  movq   %r12,%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L30
  sqrtsd %xmm0,%xmm0
L10:
  ucomisd D2(%rip),%xmm0
  jp     L39
  jne    L39
  movq   $0x0,0x18(%rbp)
  movq   $0x0,0x10(%rbp)
  movq   $0x0,0x8(%rbp)
  movq   $0x0,0x0(%rbp)
L47:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  call   <sqrt@plt>
  jmp    L10
L39:
  movq   %r12,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
  movsd  0x18(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbp)
  jmp    L47
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: f64

tool: D2: 0

assistant: ```c
double *lqunit(double *a, double *aunit) {
  double norm = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2] + a[3] * a[3]);
  if (!norm)
    aunit[0] = aunit[1] = aunit[2] = aunit[3] = 0;
  else {
    aunit[0] = a[0] / norm;
    aunit[1] = a[1] / norm;
    aunit[2] = a[2] / norm;
    aunit[3] = a[3] / norm;
  }
  return (aunit);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lqunit>:
  endbr64
  sub    $0x28,%rsp
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm3
  mov    %rsi,%rax
  movsd  0x10(%rdi),%xmm2
  movsd  0x18(%rdi),%xmm1
  mulsd  %xmm3,%xmm3
  movapd %xmm4,%xmm0
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L38
  sqrtsd %xmm0,%xmm0
L29:
  ucomisd %xmm1,%xmm0
  jp     L16
  jne    L16
  movq   $0x0,0x18(%rax)
  movq   $0x0,0x10(%rax)
  movq   $0x0,0x8(%rax)
  movq   $0x0,(%rax)
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  divsd  %xmm0,%xmm4
  movsd  %xmm4,(%rax)
  movsd  0x8(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rax)
  movsd  0x10(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rax)
  movsd  0x18(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rax)
  add    $0x28,%rsp
  ret
L38:
  mov    %rdi,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  mov    %rsi,0x18(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rdi
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm4
  jmp    L29
```

assistant: ```c
double *lqunit(double *a, double *aunit) {
  double norm = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2] + a[3] * a[3]);
  if (!norm)
    aunit[0] = aunit[1] = aunit[2] = aunit[3] = 0;
  else {
    aunit[0] = a[0] / norm;
    aunit[1] = a[1] / norm;
    aunit[2] = a[2] / norm;
    aunit[3] = a[3] / norm;
  }
  return (aunit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lqunit>:
  endbr64
  sub    $0x28,%rsp
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm3
  mov    %rsi,%rax
  movsd  0x10(%rdi),%xmm2
  movsd  0x18(%rdi),%xmm1
  mulsd  %xmm3,%xmm3
  movapd %xmm4,%xmm0
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L10
  sqrtsd %xmm0,%xmm0
L0:
  ucomisd %xmm1,%xmm0
  jp     L32
  jne    L32
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rax)
  movups %xmm0,0x10(%rax)
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L32:
  divsd  %xmm0,%xmm4
  movsd  %xmm4,(%rax)
  movsd  0x8(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rax)
  movsd  0x10(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rax)
  movsd  0x18(%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rax)
  add    $0x28,%rsp
  ret
L10:
  mov    %rdi,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  mov    %rsi,0x18(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rdi
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm4
  jmp    L0
```

assistant: ```c
double *lqunit(double *a, double *aunit) {
  double norm = sqrt(a[0] * a[0] + a[1] * a[1] + a[2] * a[2] + a[3] * a[3]);
  if (!norm)
    aunit[0] = aunit[1] = aunit[2] = aunit[3] = 0;
  else {
    aunit[0] = a[0] / norm;
    aunit[1] = a[1] / norm;
    aunit[2] = a[2] / norm;
    aunit[3] = a[3] / norm;
  }
  return (aunit);
}
```