ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<find_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jb     L174
  movsd  -0x28(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jb     L174
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jb     L174
  movsd  -0x38(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jb     L174
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L138
L174:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L16
  movsd  -0x20(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L16
  movsd  -0x30(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L16
  movsd  -0x38(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L16
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L138
L16:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jb     L123
  movsd  -0x20(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jb     L123
  movsd  -0x28(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jb     L123
  movsd  -0x38(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jb     L123
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L138
L123:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x38(%rbp),%xmm0
  jb     L138
  movsd  -0x20(%rbp),%xmm0
  comisd -0x38(%rbp),%xmm0
  jb     L138
  movsd  -0x28(%rbp),%xmm0
  comisd -0x38(%rbp),%xmm0
  jb     L138
  movsd  -0x30(%rbp),%xmm0
  comisd -0x38(%rbp),%xmm0
  jb     L138
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L138:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double find_min(double number1, double number2, double number3, double number4, double number5) {
  double min_number = number1;
  if ((number2 <= number1) && (number2 <= number3) && (number2 <= number4) && (number2 <= number5)) {
    min_number = number2;
  } else if ((number3 <= number1) && (number3 <= number2) && (number3 <= number4) && (number3 <= number5)) {
    min_number = number3;
  } else if ((number4 <= number1) && (number4 <= number2) && (number4 <= number3) && (number4 <= number5)) {
    min_number = number4;
  } else if ((number5 <= number1) && (number5 <= number2) && (number5 <= number3) && (number5 <= number4)) {
    min_number = number5;
  }
  return min_number;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_min>:
  endbr64
  comisd %xmm1,%xmm0
  jb     L91
  comisd %xmm1,%xmm2
  jb     L91
  comisd %xmm1,%xmm3
  jb     L91
  comisd %xmm1,%xmm4
  jae    L26
L91:
  comisd %xmm2,%xmm0
  jb     L74
  comisd %xmm2,%xmm1
  jb     L74
  comisd %xmm2,%xmm3
  jb     L74
  comisd %xmm2,%xmm4
  jae    L44
L74:
  comisd %xmm3,%xmm0
  jb     L69
  comisd %xmm3,%xmm1
  jb     L69
  comisd %xmm3,%xmm2
  jb     L69
  comisd %xmm3,%xmm4
  jae    L87
L69:
  comisd %xmm4,%xmm0
  jb     L131
  comisd %xmm4,%xmm1
  jb     L131
  comisd %xmm4,%xmm2
  jb     L131
  movapd %xmm4,%xmm1
  cmpnlesd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm4,%xmm1
  orpd   %xmm1,%xmm0
  ret
L26:
  movapd %xmm1,%xmm0
  ret
L44:
  movapd %xmm2,%xmm0
  ret
L87:
  movapd %xmm3,%xmm0
L131:
  ret
```

assistant: ```c
double find_min(double number1, double number2, double number3, double number4, double number5) {
  double min_number = number1;
  if ((number2 <= number1) && (number2 <= number3) && (number2 <= number4) && (number2 <= number5)) {
    min_number = number2;
  } else if ((number3 <= number1) && (number3 <= number2) && (number3 <= number4) && (number3 <= number5)) {
    min_number = number3;
  } else if ((number4 <= number1) && (number4 <= number2) && (number4 <= number3) && (number4 <= number5)) {
    min_number = number4;
  } else if ((number5 <= number1) && (number5 <= number2) && (number5 <= number3) && (number5 <= number4)) {
    min_number = number5;
  }
  return min_number;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_min>:
  endbr64
  comisd %xmm1,%xmm0
  jb     L42
  comisd %xmm1,%xmm2
  jb     L42
  comisd %xmm1,%xmm3
  jb     L42
  comisd %xmm1,%xmm4
  jb     L42
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L42:
  comisd %xmm2,%xmm0
  jb     L45
  comisd %xmm2,%xmm1
  jb     L45
  comisd %xmm2,%xmm3
  jb     L45
  comisd %xmm2,%xmm4
  jb     L45
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L45:
  comisd %xmm3,%xmm0
  jb     L47
  comisd %xmm3,%xmm1
  jb     L47
  comisd %xmm3,%xmm2
  jb     L47
  comisd %xmm3,%xmm4
  jb     L47
  movapd %xmm3,%xmm0
L142:
  ret
  nopl   (%rax)
L47:
  comisd %xmm4,%xmm0
  jb     L142
  comisd %xmm4,%xmm1
  jb     L142
  comisd %xmm4,%xmm2
  jb     L142
  movapd %xmm4,%xmm1
  cmpnlesd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm4,%xmm1
  orpd   %xmm1,%xmm0
  ret
```

assistant: ```c
double find_min(double number1, double number2, double number3, double number4, double number5) {
  double min_number = number1;
  if ((number2 <= number1) && (number2 <= number3) && (number2 <= number4) && (number2 <= number5)) {
    min_number = number2;
  } else if ((number3 <= number1) && (number3 <= number2) && (number3 <= number4) && (number3 <= number5)) {
    min_number = number3;
  } else if ((number4 <= number1) && (number4 <= number2) && (number4 <= number3) && (number4 <= number5)) {
    min_number = number4;
  } else if ((number5 <= number1) && (number5 <= number2) && (number5 <= number3) && (number5 <= number4)) {
    min_number = number5;
  }
  return min_number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_min>:
  endbr64
  comisd %xmm1,%xmm0
  jb     L59
  comisd %xmm1,%xmm2
  jb     L59
  comisd %xmm1,%xmm3
  jb     L59
  comisd %xmm1,%xmm4
  jb     L59
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L59:
  comisd %xmm2,%xmm0
  jb     L61
  comisd %xmm2,%xmm1
  jb     L61
  comisd %xmm2,%xmm3
  jb     L61
  comisd %xmm2,%xmm4
  jb     L61
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L61:
  comisd %xmm3,%xmm0
  jb     L20
  comisd %xmm3,%xmm1
  jb     L20
  comisd %xmm3,%xmm2
  jb     L20
  comisd %xmm3,%xmm4
  jb     L20
  movapd %xmm3,%xmm0
L1:
  ret
  nopl   (%rax)
L20:
  comisd %xmm4,%xmm0
  jb     L1
  comisd %xmm4,%xmm1
  jb     L1
  comisd %xmm4,%xmm2
  jb     L1
  movapd %xmm4,%xmm1
  cmpnlesd %xmm3,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm4,%xmm1
  orpd   %xmm1,%xmm0
  ret
```

assistant: ```c
double find_min(double number1, double number2, double number3, double number4, double number5) {
  double min_number = number1;
  if ((number2 <= number1) && (number2 <= number3) && (number2 <= number4) && (number2 <= number5)) {
    min_number = number2;
  } else if ((number3 <= number1) && (number3 <= number2) && (number3 <= number4) && (number3 <= number5)) {
    min_number = number3;
  } else if ((number4 <= number1) && (number4 <= number2) && (number4 <= number3) && (number4 <= number5)) {
    min_number = number4;
  } else if ((number5 <= number1) && (number5 <= number2) && (number5 <= number3) && (number5 <= number4)) {
    min_number = number5;
  }
  return min_number;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main_function_name_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L56:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x20,%eax
  jg     L27
  cmp    $0x9,%eax
  jge    L104
  jmp    L115
L10:
  sub    $0x2e,%eax
  movabs $0x200000000800d,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L93
  jmp    L115
L104:
  mov    %eax,%edx
  movabs $0x100002600,%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L93
  jmp    L115
L27:
  cmp    $0x5f,%eax
  jg     L115
  cmp    $0x2e,%eax
  jge    L10
  jmp    L115
L93:
  mov    -0x4(%rbp),%eax
  jmp    L86
L115:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x4(%rbp),%eax
L86:
  pop    %rbp
  ret
```

assistant: ```c
int main_function_name_length(char *arg) {
  int len;
  for (len = 0; arg[len]; len++) {
    switch (arg[len]) {
    case ' ':
    case '\t':
    case '\r':
    case '\n':
    case '0':
    case '1':
    case '.':
    case '_':
    case '=':
      return len;
    }
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main_function_name_length>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L95
  add    $0x1,%rdi
  mov    $0x0,%edx
  movabs $0x200000000800d,%rsi
  movabs $0x100002600,%rcx
  jmp    L88
L13:
  cmp    $0x8,%al
  jg     L54
L39:
  add    $0x1,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L59
L88:
  cmp    $0x20,%al
  jle    L13
  sub    $0x2e,%eax
  cmp    $0x31,%al
  ja     L39
  bt     %rax,%rsi
  jae    L39
  jmp    L59
L54:
  bt     %rax,%rcx
  jae    L39
L59:
  mov    %edx,%eax
  ret
L95:
  mov    $0x0,%edx
  jmp    L59
```

assistant: ```c
int main_function_name_length(char *arg) {
  int len;
  for (len = 0; arg[len]; len++) {
    switch (arg[len]) {
    case ' ':
    case '\t':
    case '\r':
    case '\n':
    case '0':
    case '1':
    case '.':
    case '_':
    case '=':
      return len;
    }
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main_function_name_length>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L69
  add    $0x1,%rdi
  xor    %r8d,%r8d
  movabs $0x200000000800d,%rcx
  movabs $0x100002600,%rdx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    $0x8,%al
  jg     L78
L62:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%r8d
  test   %al,%al
  je     L12
L43:
  cmp    $0x20,%al
  jle    L13
  sub    $0x2e,%eax
  cmp    $0x31,%al
  ja     L62
  bt     %rax,%rcx
  jae    L62
L12:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  bt     %rax,%rdx
  jae    L62
  mov    %r8d,%eax
  ret
L69:
  xor    %r8d,%r8d
  jmp    L12
```

assistant: ```c
int main_function_name_length(char *arg) {
  int len;
  for (len = 0; arg[len]; len++) {
    switch (arg[len]) {
    case ' ':
    case '\t':
    case '\r':
    case '\n':
    case '0':
    case '1':
    case '.':
    case '_':
    case '=':
      return len;
    }
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main_function_name_length>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
  add    $0x1,%rdi
  xor    %r8d,%r8d
  movabs $0x200000000800d,%rcx
  movabs $0x100002600,%rdx
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L39:
  cmp    $0x8,%al
  jg     L69
L55:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%r8d
  test   %al,%al
  je     L15
L60:
  cmp    $0x20,%al
  jle    L39
  sub    $0x2e,%eax
  cmp    $0x31,%al
  ja     L55
  bt     %rax,%rcx
  jae    L55
L15:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  bt     %rax,%rdx
  jae    L55
  mov    %r8d,%eax
  ret
L29:
  xor    %r8d,%r8d
  jmp    L15
```

assistant: ```c
int main_function_name_length(char *arg) {
  int len;
  for (len = 0; arg[len]; len++) {
    switch (arg[len]) {
    case ' ':
    case '\t':
    case '\r':
    case '\n':
    case '0':
    case '1':
    case '.':
    case '_':
    case '=':
      return len;
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L49:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L5
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jg     L49
  jmp    L1
L5:
  nop
L1:
  cmpl   $0x0,-0x10(%rbp)
  je     L40
  mov    -0x10(%rbp),%eax
  jmp    L29
L40:
  mov    -0xc(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int xread(int fd, void *buf, int bsz) {
  char *b = buf;
  int nread = 0;
  int r;
  do {
    if ((r = read(fd, b, bsz)) <= 0)
      break;
    b += r;
    bsz -= r;
    nread += r;
  } while (bsz > 0);
  return nread ? nread : r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xread>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0x0,%r12d
L13:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L12
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  add    %eax,%r12d
  test   %ebx,%ebx
  jg     L13
L12:
  test   %r12d,%r12d
  cmove  %eax,%r12d
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int xread(int fd, void *buf, int bsz) {
  char *b = buf;
  int nread = 0;
  int r;
  do {
    if ((r = read(fd, b, bsz)) <= 0)
      break;
    b += r;
    bsz -= r;
    nread += r;
  } while (bsz > 0);
  return nread ? nread : r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xread>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L21:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %eax,%r13d
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L29
L27:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L21
  test   %r13d,%r13d
  cmove  %eax,%r13d
L29:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int xread(int fd, void *buf, int bsz) {
  char *b = buf;
  int nread = 0;
  int r;
  do {
    if ((r = read(fd, b, bsz)) <= 0)
      break;
    b += r;
    bsz -= r;
    nread += r;
  } while (bsz > 0);
  return nread ? nread : r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xread>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L6:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %eax,%r13d
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L3
L8:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L6
  test   %r13d,%r13d
  cmove  %eax,%r13d
L3:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int xread(int fd, void *buf, int bsz) {
  char *b = buf;
  int nread = 0;
  int r;
  do {
    if ((r = read(fd, b, bsz)) <= 0)
      break;
    b += r;
    bsz -= r;
    nread += r;
  } while (bsz > 0);
  return nread ? nread : r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<early_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void early_init(unsigned int r0, unsigned int mach_type, unsigned int atags) {
  if (r0 != 0) {
  }
  if (mach_type == 0) {
  }
  if (atags == 0) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<early_init>:
  endbr64
  ret
```

assistant: ```c
void early_init(unsigned int r0, unsigned int mach_type, unsigned int atags) {
  if (r0 != 0) {
  }
  if (mach_type == 0) {
  }
  if (atags == 0) {
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<early_init>:
  endbr64
  ret
```

assistant: ```c
void early_init(unsigned int r0, unsigned int mach_type, unsigned int atags) {
  if (r0 != 0) {
  }
  if (mach_type == 0) {
  }
  if (atags == 0) {
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<early_init>:
  endbr64
  ret
```

assistant: ```c
void early_init(unsigned int r0, unsigned int mach_type, unsigned int atags) {
  if (r0 != 0) {
  }
  if (mach_type == 0) {
  }
  if (atags == 0) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_print_tab_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L5:
  mov    $0x9,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void hash_print_tab_(int cnt) {
  for (int n = 0; n < cnt; n++) {
    putchar('\t');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_print_tab_>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L14:
  mov    $0x9,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
void hash_print_tab_(int cnt) {
  for (int n = 0; n < cnt; n++) {
    putchar('\t');
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_print_tab_>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  ret
```

assistant: ```c
void hash_print_tab_(int cnt) {
  for (int n = 0; n < cnt; n++) {
    putchar('\t');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_print_tab_>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  ret
```

assistant: ```c
void hash_print_tab_(int cnt) {
  for (int n = 0; n < cnt; n++) {
    putchar('\t');
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<matrixMulOnHost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L17
L49:
  movl   $0x0,-0x20(%rbp)
  jmp    L3
L41:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L57:
  mov    -0x24(%rbp),%eax
  imul   -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L57
  mov    -0x24(%rbp),%eax
  imul   -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x20(%rbp)
L3:
  mov    -0x20(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L41
  addl   $0x1,-0x24(%rbp)
L17:
  mov    -0x24(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L49
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixMulOnHost(float *M, float *N, float *P, int width) {
  for (int i = 0; i < width; ++i) {
    for (int j = 0; j < width; ++j) {
      double sum = 0;
      for (int k = 0; k < width; ++k) {
        double a = M[i * width + k];
        double b = N[k * width + j];
        sum += a * b;
      }
      P[i * width + j] = sum;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrixMulOnHost>:
  endbr64
  test   %ecx,%ecx
  jle    L37
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r9
  mov    %ecx,%r12d
  movslq %ecx,%rcx
  shl    $0x2,%rcx
  mov    %rdi,%r10
  lea    -0x1(%r12),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%ebp
  mov    %r12d,%r11d
L33:
  mov    %rbx,%r8
  mov    $0x0,%edi
L3:
  mov    %r8,%rdx
  mov    %r10,%rax
  pxor   %xmm1,%xmm1
L20:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd (%rdx),%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x4,%rax
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L20
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%r9,%rdi,4)
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    %r11,%rdi
  jne    L3
  add    $0x1,%ebp
  add    %rcx,%r9
  add    %rcx,%r10
  add    %rcx,%rsi
  cmp    %ebp,%r12d
  jne    L33
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  ret
```

assistant: ```c
void matrixMulOnHost(float *M, float *N, float *P, int width) {
  for (int i = 0; i < width; ++i) {
    for (int j = 0; j < width; ++j) {
      double sum = 0;
      for (int k = 0; k < width; ++k) {
        double a = M[i * width + k];
        double b = N[k * width + j];
        sum += a * b;
      }
      P[i * width + j] = sum;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixMulOnHost>:
  endbr64
  test   %ecx,%ecx
  jle    L20
  push   %r12
  mov    %ecx,%r12d
  movslq %ecx,%rcx
  mov    %rsi,%r11
  lea    -0x1(%r12),%eax
  push   %rbp
  mov    %rdi,%r9
  mov    %rdx,%r10
  push   %rbx
  shl    $0x2,%rcx
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %ebp,%ebp
  pxor   %xmm3,%xmm3
  mov    %r12d,%ebx
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %r11,%r8
  xor    %edi,%edi
  nopl   (%rax)
L12:
  mov    %r8,%rdx
  mov    %r9,%rax
  movapd %xmm3,%xmm1
  nopw   0x0(%rax,%rax,1)
L37:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  add    $0x4,%rax
  cvtss2sd (%rdx),%xmm2
  cvtss2sd -0x4(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  add    %rcx,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L37
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%r10,%rdi,4)
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    %rdi,%rbx
  jne    L12
  add    $0x1,%ebp
  add    %rcx,%r10
  add    %rcx,%r9
  add    %rcx,%rsi
  cmp    %ebp,%r12d
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  ret
```

assistant: ```c
void matrixMulOnHost(float *M, float *N, float *P, int width) {
  for (int i = 0; i < width; ++i) {
    for (int j = 0; j < width; ++j) {
      double sum = 0;
      for (int k = 0; k < width; ++k) {
        double a = M[i * width + k];
        double b = N[k * width + j];
        sum += a * b;
      }
      P[i * width + j] = sum;
    }
  }
}
```