ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zrpc_util_convertchartohexa>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L8
  sub    $0x41,%edx
  cmp    $0x25,%dl
  ja     L4
  lea    D8(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0xa,%eax
L8:
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  movl   $0xffffffff,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
  mov    $0xf,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xd,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xc,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xb,%eax
  ret
```

assistant: ```c
uint8_t zrpc_util_convertchartohexa(uint8_t *hexa, int *error) {
  if ((*hexa == '0') || (*hexa == '1') || (*hexa == '2') || (*hexa == '3') || (*hexa == '4') || (*hexa == '5') || (*hexa == '6') || (*hexa == '7') || (*hexa == '8') || (*hexa == '9'))
    return (uint8_t)(*hexa) - '0';
  if ((*hexa == 'a') || (*hexa == 'A'))
    return 0xa;
  if ((*hexa == 'b') || (*hexa == 'B'))
    return 0xb;
  if ((*hexa == 'c') || (*hexa == 'C'))
    return 0xc;
  if ((*hexa == 'd') || (*hexa == 'D'))
    return 0xd;
  if ((*hexa == 'e') || (*hexa == 'E'))
    return 0xe;
  if ((*hexa == 'f') || (*hexa == 'F'))
    return 0xf;
  *error = -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zrpc_util_convertchartohexa>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L10
  sub    $0x41,%edx
  cmp    $0x25,%dl
  ja     L1
  lea    D4(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0xa,%eax
L10:
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  movl   $0xffffffff,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
  mov    $0xf,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xd,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xc,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xb,%eax
  ret
```

assistant: ```c
uint8_t zrpc_util_convertchartohexa(uint8_t *hexa, int *error) {
  if ((*hexa == '0') || (*hexa == '1') || (*hexa == '2') || (*hexa == '3') || (*hexa == '4') || (*hexa == '5') || (*hexa == '6') || (*hexa == '7') || (*hexa == '8') || (*hexa == '9'))
    return (uint8_t)(*hexa) - '0';
  if ((*hexa == 'a') || (*hexa == 'A'))
    return 0xa;
  if ((*hexa == 'b') || (*hexa == 'B'))
    return 0xb;
  if ((*hexa == 'c') || (*hexa == 'C'))
    return 0xc;
  if ((*hexa == 'd') || (*hexa == 'D'))
    return 0xd;
  if ((*hexa == 'e') || (*hexa == 'E'))
    return 0xe;
  if ((*hexa == 'f') || (*hexa == 'F'))
    return 0xf;
  *error = -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L59
  cmp    $0x1d,%edi
  jg     L31
  cmp    $0xf,%edi
  jne    L47
L31:
  cmp    $0x1e,%edi
  je     L5
  cmp    $0xf,%edi
  je     L57
  cmp    $0x2d,%edi
  je     L117
  mov    $0x3c,%eax
  sub    %edi,%eax
  mov    %eax,%edi
  call   <printMinute@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L11
L59:
  mov    (%rsp),%edi
  call   <numbers@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L47:
  call   <printMinute@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L11
L5:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L11
L57:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L11
L117:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L11
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D56
type: string
name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D50
type: string

tool: D44: %d

tool: D27: minutes to 

tool: D6: o' clock

tool: D56: minutes past 

tool: D29: half past 

tool: D38: quarter past 

tool: D50: quarter to 

assistant: ```c
int main() {
  int h;
  scanf("%d", &h);
  int m;
  scanf("%d", &m);
  if (m == 0) {
    numbers(h);
    printf("o' clock");
  } else {
    if (m < 30 && m != 15) {
      printMinute(m);
      printf("minutes past ");
      numbers(h);
    } else if (m == 30) {
      printf("half past ");
      numbers(h);
    } else if (m == 15) {
      printf("quarter past ");
      numbers(h);
    } else if (m == 45) {
      printf("quarter to ");
      numbers(h + 1);
    } else {
      printMinute(60 - m);
      printf("minutes to ");
      numbers(h + 1);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D56(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L114
  cmp    $0x1d,%edi
  jg     L60
  cmp    $0xf,%edi
  je     L60
  call   <printMinute@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
L57:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L60:
  cmp    $0x1e,%edi
  je     L16
  cmp    $0xf,%edi
  je     L26
  cmp    $0x2d,%edi
  je     L47
  mov    $0x3c,%r8d
  sub    %edi,%r8d
  mov    %r8d,%edi
  call   <printMinute@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L57
L114:
  mov    (%rsp),%edi
  call   <numbers@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L47:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L57
L16:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L57
L26:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L57
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D59
type_infered: string
name: disassemble_data
arguments: tag: D64
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string

tool: D56: %d

tool: D58: minutes past 

tool: D59: minutes to 

tool: D64: o' clock

tool: D28: quarter to 

tool: D0: half past 

tool: D20: quarter past 

assistant: ```c
int main() {
  int h;
  scanf("%d", &h);
  int m;
  scanf("%d", &m);
  if (m == 0) {
    numbers(h);
    printf("o' clock");
  } else {
    if (m < 30 && m != 15) {
      printMinute(m);
      printf("minutes past ");
      numbers(h);
    } else if (m == 30) {
      printf("half past ");
      numbers(h);
    } else if (m == 15) {
      printf("quarter past ");
      numbers(h);
    } else if (m == 45) {
      printf("quarter to ");
      numbers(h + 1);
    } else {
      printMinute(60 - m);
      printf("minutes to ");
      numbers(h + 1);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L106
  cmp    $0x1d,%edi
  jg     L102
  cmp    $0xf,%edi
  je     L102
  call   <printMinute@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
L118:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L102:
  cmp    $0x1e,%edi
  je     L29
  cmp    $0xf,%edi
  je     L34
  cmp    $0x2d,%edi
  je     L53
  mov    $0x3c,%r8d
  sub    %edi,%r8d
  mov    %r8d,%edi
  call   <printMinute@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L118
L106:
  mov    (%rsp),%edi
  call   <numbers@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L118
L53:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    0x1(%rax),%edi
  call   <numbers@plt>
  jmp    L118
L29:
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L118
L34:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%edi
  call   <numbers@plt>
  jmp    L118
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D24
type_guessed: string
name: read_data
arguments: tag: D54
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D36
type_guessed: string
name: read_data
arguments: tag: D43
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string

tool: D24: %d

tool: D54: minutes past 

tool: D4: minutes to 

tool: D10: o' clock

tool: D36: quarter to 

tool: D43: half past 

tool: D30: quarter past 

assistant: ```c
int main() {
  int h;
  scanf("%d", &h);
  int m;
  scanf("%d", &m);
  if (m == 0) {
    numbers(h);
    printf("o' clock");
  } else {
    if (m < 30 && m != 15) {
      printMinute(m);
      printf("minutes past ");
      numbers(h);
    } else if (m == 30) {
      printf("half past ");
      numbers(h);
    } else if (m == 15) {
      printf("quarter past ");
      numbers(h);
    } else if (m == 45) {
      printf("quarter to ");
      numbers(h + 1);
    } else {
      printMinute(60 - m);
      printf("minutes to ");
      numbers(h + 1);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sock_read_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  cmpl   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  jmp    L33
L8:
  mov    -0x8(%rbp),%eax
  jmp    L33
L1:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L0:
  cmpl   $0x0,-0x18(%rbp)
  jg     L16
  mov    -0x8(%rbp),%eax
L33:
  leave
  ret
```

assistant: ```c
int sock_read_bytes(int sockfd, const unsigned char *buff, int len) {
  int t, n;
  for (t = 0; len > 0;) {
    n = recv(sockfd, (void *)buff + t, len, 0);
    if (n < 0)
      return ((t == 0) ? n : t);
    t += n;
    len -= n;
  }
  return (t);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sock_read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L29
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    $0x0,%ebp
L37:
  movslq %ebp,%rsi
  add    %r13,%rsi
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <recv@plt>
  test   %eax,%eax
  js     L13
  add    %eax,%ebp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L37
  jmp    L8
L13:
  test   %ebp,%ebp
  cmove  %eax,%ebp
L8:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    $0x0,%ebp
  jmp    L8
```

assistant: ```c
int sock_read_bytes(int sockfd, const unsigned char *buff, int len) {
  int t, n;
  for (t = 0; len > 0;) {
    n = recv(sockfd, (void *)buff + t, len, 0);
    if (n < 0)
      return ((t == 0) ? n : t);
    t += n;
    len -= n;
  }
  return (t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L37
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  xor    %r13d,%r13d
  jmp    L14
  xchg   %ax,%ax
L11:
  sub    %eax,%ebx
  add    %eax,%r13d
  test   %ebx,%ebx
  jle    L35
L14:
  movslq %r13d,%rsi
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %ebp,%edi
  add    %r12,%rsi
  call   <recv@plt>
  test   %eax,%eax
  jns    L11
  test   %r13d,%r13d
  cmove  %eax,%r13d
L35:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  xor    %r13d,%r13d
  jmp    L35
```

assistant: ```c
int sock_read_bytes(int sockfd, const unsigned char *buff, int len) {
  int t, n;
  for (t = 0; len > 0;) {
    n = recv(sockfd, (void *)buff + t, len, 0);
    if (n < 0)
      return ((t == 0) ? n : t);
    t += n;
    len -= n;
  }
  return (t);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sock_read_bytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L23
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  xor    %r13d,%r13d
  jmp    L4
  xchg   %ax,%ax
L19:
  sub    %eax,%ebx
  add    %eax,%r13d
  test   %ebx,%ebx
  jle    L1
L4:
  movslq %r13d,%rsi
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %ebp,%edi
  add    %r12,%rsi
  call   <recv@plt>
  test   %eax,%eax
  jns    L19
  test   %r13d,%r13d
  cmove  %eax,%r13d
L1:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  xor    %r13d,%r13d
  jmp    L1
```

assistant: ```c
int sock_read_bytes(int sockfd, const unsigned char *buff, int len) {
  int t, n;
  for (t = 0; len > 0;) {
    n = recv(sockfd, (void *)buff + t, len, 0);
    if (n < 0)
      return ((t == 0) ? n : t);
    t += n;
    len -= n;
  }
  return (t);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<key_update_128_inv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  add    $0x20,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  sar    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  add    $0x1c,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <present_sbox_inv@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  movl   $0x0,-0x18(%rbp)
  jmp    L27
L38:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x8,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x8,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L27:
  cmpl   $0x7,-0x18(%rbp)
  jle    L38
  movl   $0xf,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x5,%eax
  mov    %eax,-0x14(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void key_update_128_inv(uint8_t *buffer, uint8_t round) {
  uint8_t j;
  uint8_t t8;
  union __attribute__((packed)) {
    uint8_t v8[2];
    uint16_t v16;
  } tmp;
  buffer[8] ^= round << 6;
  buffer[7] ^= round >> 2;
  buffer[0] = present_sbox_inv(buffer[0]);
  for (j = 0; j < 8; ++j) {
    tmp.v8[0] = buffer[j];
    buffer[j] = buffer[j + 8];
    buffer[j + 8] = tmp.v8[0];
  }
  j = 15;
  t8 = (uint16_t)buffer[0] >> (5);
  do {
    tmp.v8[0] = buffer[j];
    tmp.v16 <<= 3;
    buffer[j] = tmp.v8[0] | t8;
    t8 = tmp.v8[1] & 0x07;
  } while (j--);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<key_update_128_inv>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%eax
  shl    $0x6,%eax
  xor    %eax,0x20(%rdi)
  sar    $0x2,%esi
  xor    %esi,0x1c(%rdi)
  mov    (%rdi),%edi
  call   <present_sbox_inv@plt>
  mov    %eax,(%rbx)
  lea    0x20(%rbx),%rsi
  mov    %rbx,%rax
L18:
  mov    (%rax),%edx
  mov    0x20(%rax),%ecx
  mov    %ecx,(%rax)
  mov    %edx,0x20(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L18
  mov    (%rbx),%ecx
  sar    $0x5,%ecx
  lea    0x3c(%rbx),%rdx
  mov    $0x0,%edi
L5:
  mov    %rdx,%rsi
  mov    (%rdx),%eax
  shl    $0x3,%eax
  or     %ecx,%eax
  mov    %eax,(%rdx)
  mov    %edi,%ecx
  sub    $0x4,%rdx
  cmp    %rbx,%rsi
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void key_update_128_inv(uint8_t *buffer, uint8_t round) {
  uint8_t j;
  uint8_t t8;
  union __attribute__((packed)) {
    uint8_t v8[2];
    uint16_t v16;
  } tmp;
  buffer[8] ^= round << 6;
  buffer[7] ^= round >> 2;
  buffer[0] = present_sbox_inv(buffer[0]);
  for (j = 0; j < 8; ++j) {
    tmp.v8[0] = buffer[j];
    buffer[j] = buffer[j + 8];
    buffer[j + 8] = tmp.v8[0];
  }
  j = 15;
  t8 = (uint16_t)buffer[0] >> (5);
  do {
    tmp.v8[0] = buffer[j];
    tmp.v16 <<= 3;
    buffer[j] = tmp.v8[0] | t8;
    t8 = tmp.v8[1] & 0x07;
  } while (j--);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<key_update_128_inv>:
  endbr64
  mov    %esi,%eax
  push   %rbx
  sar    $0x2,%esi
  mov    %rdi,%rbx
  xor    %esi,0x1c(%rdi)
  shl    $0x6,%eax
  xor    %eax,0x20(%rdi)
  mov    (%rdi),%edi
  call   <present_sbox_inv@plt>
  lea    0x20(%rbx),%rsi
  mov    %rbx,%rdx
  mov    %eax,(%rbx)
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rdx),%eax
L19:
  mov    0x20(%rdx),%ecx
  mov    %eax,0x20(%rdx)
  add    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rsi,%rdx
  jne    L5
  mov    (%rbx),%ecx
  lea    0x3c(%rbx),%rdx
  xor    %edi,%edi
  sar    $0x5,%ecx
  nop
L6:
  mov    (%rdx),%eax
  mov    %rdx,%rsi
  sub    $0x4,%rdx
  shl    $0x3,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  mov    %eax,0x4(%rdx)
  cmp    %rsi,%rbx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void key_update_128_inv(uint8_t *buffer, uint8_t round) {
  uint8_t j;
  uint8_t t8;
  union __attribute__((packed)) {
    uint8_t v8[2];
    uint16_t v16;
  } tmp;
  buffer[8] ^= round << 6;
  buffer[7] ^= round >> 2;
  buffer[0] = present_sbox_inv(buffer[0]);
  for (j = 0; j < 8; ++j) {
    tmp.v8[0] = buffer[j];
    buffer[j] = buffer[j + 8];
    buffer[j + 8] = tmp.v8[0];
  }
  j = 15;
  t8 = (uint16_t)buffer[0] >> (5);
  do {
    tmp.v8[0] = buffer[j];
    tmp.v16 <<= 3;
    buffer[j] = tmp.v8[0] | t8;
    t8 = tmp.v8[1] & 0x07;
  } while (j--);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<key_update_128_inv>:
  endbr64
  mov    %esi,%eax
  shl    $0x6,%esi
  push   %rbx
  movq   0x1c(%rdi),%xmm1
  sar    $0x2,%eax
  movd   %esi,%xmm3
  mov    %rdi,%rbx
  movd   %eax,%xmm0
  punpckldq %xmm3,%xmm0
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x1c(%rdi)
  mov    (%rdi),%edi
  call   <present_sbox_inv@plt>
  movdqu 0x20(%rbx),%xmm0
  movdqu 0x30(%rbx),%xmm1
  mov    %eax,(%rbx)
  mov    0x1c(%rbx),%eax
  movd   %xmm0,%ecx
  pshufd $0xff,%xmm1,%xmm2
  movd   %xmm0,%edx
  shl    $0x3,%eax
  sar    $0x5,%ecx
  or     %ecx,%eax
  shl    $0x3,%edx
  mov    %eax,0x3c(%rbx)
  mov    0x18(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x38(%rbx)
  mov    0x14(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x34(%rbx)
  mov    0x10(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x30(%rbx)
  mov    0xc(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x2c(%rbx)
  mov    0x8(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x28(%rbx)
  mov    0x4(%rbx),%eax
  shl    $0x3,%eax
  mov    %eax,0x24(%rbx)
  mov    (%rbx),%eax
  mov    %edx,(%rbx)
  shl    $0x3,%eax
  mov    %eax,0x20(%rbx)
  movd   %xmm2,%eax
  movdqa %xmm1,%xmm2
  punpckhdq %xmm1,%xmm2
  shl    $0x3,%eax
  mov    %eax,0x1c(%rbx)
  movd   %xmm2,%eax
  pshufd $0x55,%xmm1,%xmm2
  shl    $0x3,%eax
  mov    %eax,0x18(%rbx)
  movd   %xmm2,%eax
  shl    $0x3,%eax
  mov    %eax,0x14(%rbx)
  movd   %xmm1,%eax
  pshufd $0xff,%xmm0,%xmm1
  shl    $0x3,%eax
  mov    %eax,0x10(%rbx)
  movd   %xmm1,%eax
  movdqa %xmm0,%xmm1
  shl    $0x3,%eax
  punpckhdq %xmm0,%xmm1
  pshufd $0x55,%xmm0,%xmm0
  mov    %eax,0xc(%rbx)
  movd   %xmm1,%eax
  shl    $0x3,%eax
  mov    %eax,0x8(%rbx)
  movd   %xmm0,%eax
  shl    $0x3,%eax
  mov    %eax,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void key_update_128_inv(uint8_t *buffer, uint8_t round) {
  uint8_t j;
  uint8_t t8;
  union __attribute__((packed)) {
    uint8_t v8[2];
    uint16_t v16;
  } tmp;
  buffer[8] ^= round << 6;
  buffer[7] ^= round >> 2;
  buffer[0] = present_sbox_inv(buffer[0]);
  for (j = 0; j < 8; ++j) {
    tmp.v8[0] = buffer[j];
    buffer[j] = buffer[j + 8];
    buffer[j + 8] = tmp.v8[0];
  }
  j = 15;
  t8 = (uint16_t)buffer[0] >> (5);
  do {
    tmp.v8[0] = buffer[j];
    tmp.v16 <<= 3;
    buffer[j] = tmp.v8[0] | t8;
    t8 = tmp.v8[1] & 0x07;
  } while (j--);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_pic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <lprintf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <p_CopyFile@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: Copy %s to %s


assistant: ```c
int copy_pic(char *source, char *target) {
  lprintf(1, "Copy %s to %s\n", source, target);
  return p_CopyFile(source, target);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_pic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <lprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <p_CopyFile@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: Copy %s to %s


assistant: ```c
int copy_pic(char *source, char *target) {
  lprintf(1, "Copy %s to %s\n", source, target);
  return p_CopyFile(source, target);
}
```