user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D58(%rip),%r13
  push   %r12
  lea    D38(%rip),%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  lea    D46(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x4(%rsp),%edx
  lea    -0x2711(%rdx),%eax
  cmp    $0x15f8d,%eax
  ja     L51
  movslq %edx,%rsi
  mov    %edx,%edi
  imul   $0x68db8bad,%rsi,%rsi
  sar    $0x1f,%edi
  sar    $0x2c,%rsi
  mov    %esi,%eax
  sub    %edi,%esi
  sub    %edi,%eax
  mov    $0xcccccccd,%edi
  imul   $0x2710,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %eax,%r8d
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x26,%rdx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%r8d
  mov    %r8d,%ecx
  imul   $0x51eb851f,%rcx,%rcx
  shr    $0x25,%rcx
  imul   $0x64,%ecx,%edx
  mov    %r8d,%ecx
  sub    %edx,%ecx
  mov    %ecx,%edx
  mov    %ecx,0x4(%rsp)
  imul   %rdi,%rdx
  mov    %ecx,%edi
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  cmp    %edi,%esi
  jne    L22
  mov    $0x3e8,%esi
  cltd
  mov    $0xa,%edi
  idiv   %esi
  mov    %eax,%esi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  cmp    %eax,%esi
  je     L4
L22:
  lea    D45(%rip),%rdi
  call   <puts@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L9
L4:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L35
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D58
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D46
type_infered: string
name: unpack_data
arguments: tag: D45
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D18: You did not provide a 5 digit number!!!

tool: D58: Enter a 5 digit number: 

tool: D38: %s

tool: D46: %d

tool: D45: Not a palindrome!!!

tool: D10: The given number is a palindrome!!!

assistant: ```c
int main(void) {
  int number;
  int flag = 1;
  int numA;
  int numB;
  int numC;
  int numD;
  printf("%s", "Enter a 5 digit number: ");
  scanf("%d", &number);
  while (flag != -1) {
    if (number > 10000) {
      if (number < 99999) {
        numA = number / 10000;
        number = number % 10000;
        numB = number / 1000;
        number = number % 1000;
        number = number % 100;
        numC = number / 10;
        numD = number % 10;
        if (numA == numD) {
          if (numB == numC) {
            puts("The given number is a palindrome!!!");
          } else
            puts("Not a palindrome!!!");
        } else
          puts("Not a palindrome!!!");
        flag = -1;
      } else {
        puts("You did not provide a 5 digit number!!!");
        printf("%s", "Enter a 5 digit number: ");
        scanf("%d", &number);
      }
    } else {
      puts("You did not provide a 5 digit number!!!");
      printf("%s", "Enter a 5 digit number: ");
      scanf("%d", &number);
    }
  }
  return 0;
}
```