user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r13
  movl   $0x1,0x1c(%rsp)
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ebp
  lea    -0x1(%rbp),%eax
  cmp    $0x3,%eax
  ja     L59
  mov    $0x1,%ebx
  mov    $0x1,%r14d
  jmp    L14
L109:
  sub    $0x1,%esi
  add    $0x1,%r14d
  cmp    $0x3,%esi
  ja     L4
L82:
  mov    %r15d,%ebx
L14:
  lea    D89(%rip),%rdi
  lea    0x1(%rbx),%r15d
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  movslq %r14d,%rdx
  mov    %esi,0x20(%rsp,%rdx,4)
  test   %esi,%esi
  je     L40
  cmp    $0x4,%esi
  jle    L109
L40:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  mov    %rdx,0x8(%rsp)
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%rdx
  test   %esi,%esi
  je     L58
  cmp    $0x4,%esi
  jle    L109
L58:
  lea    0x1(%r14),%eax
  mov    %esi,0x20(%rsp,%rdx,4)
  mov    %r14d,%esi
  lea    0x2(%rbx),%r15d
  mov    %eax,0x8(%rsp)
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  mov    0x8(%rsp),%r14d
  sub    $0x1,%esi
  add    $0x1,%r14d
  cmp    $0x3,%esi
  jbe    L82
  nopl   0x0(%rax)
L4:
  lea    D16(%rip),%rdi
  lea    0x24(%rsp),%rbx
  call   <puts@plt>
  lea    D18(%rip),%rdi
  lea    D14(%rip),%r12
  call   <puts@plt>
  lea    -0x2(%r15),%eax
  lea    (%rbx,%rax,4),%r13
  jmp    L65
  xchg   %ax,%ax
L12:
  mov    (%rbx),%ebp
  add    $0x4,%rbx
L65:
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L12
L68:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0xf8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L68
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D89
type_infered: string
name: disassemble_data
arguments: label: D41
type_infered: string
name: disassemble_data
arguments: label: D75
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string

tool: D0: 
Input a number, 1 - 4. Where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)

tool: D34: %d

tool: D89: 
Input a number, 1 - 4 where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)

tool: D41: 
Invalid input! you entered '%d'
Please input 1-4 or program will exit


tool: D75: i = %d


tool: D16: 

***END PROGRAM!***

tool: D18: You entered the following items:

tool: D14: %d 

assistant: ```c
int main() {
  int i = 0, itemCount = 0, input = 1, infant = 0, child = 0, teen = 0, adult = 0, PeopleTypes[50];
  printf("\nInput a number, 1 - 4. Where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)\n");
  scanf("%d", &input);
  itemCount++;
  PeopleTypes[i] = input;
  i++;
  for (i = 1; (input > 0) && (input <= 4); i++) {
    printf("\nInput a number, 1 - 4 where 1 represents an infant, 2 a child, 3 a teen, 4 an adult. (Use a negative number to exit.)\n");
    scanf("%d", &input);
    PeopleTypes[i] = input;
    itemCount++;
    if ((input == 0) || (input > 4)) {
      printf("\nInvalid input! you entered '%d'\nPlease input 1-4 or program will exit\n", PeopleTypes[i]);
      scanf("%d", &input);
      if ((input == 0) || (input > 4)) {
        PeopleTypes[i] = input;
        printf("i = %d\n", i);
        itemCount++;
        i++;
      } else
        ;
    }
  }
  i--;
  itemCount--;
  printf("\n\n***END PROGRAM!***\n");
  printf("You entered the following items:\n");
  for (i = 0; i < itemCount; i++) {
    printf("%d ", PeopleTypes[i]);
  }
  return 0;
}
```