ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D6(%rip),%r15
  push   %r14
  lea    D27(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L4:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L0:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L0
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L4
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string
name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D6: dapxsumkbn

tool: D27: # c::%s:len=%d


tool: D19: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dapxsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D26(%rip),%r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L17:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L6:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L6
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L17
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D23
type: string

tool: D26: dapxsumkbn

tool: D17: # c::%s:len=%d


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dapxsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_E__sys_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x3b,%edi
  call   <putc@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x20,%edi
  call   <putc@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  nop
  leave
  ret
```

assistant: ```c
void _E__sys_error(char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  (void)vfprintf(stderr, fmt, pvar);
  va_end(pvar);
  putc(';', stderr);
  putc(' ', stderr);
  (void)fflush(stderr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_E__sys_error>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%esi
  mov    $0x3b,%edi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0x20,%edi
  call   <putc@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _E__sys_error(char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  (void)vfprintf(stderr, fmt, pvar);
  va_end(pvar);
  putc(';', stderr);
  putc(' ', stderr);
  (void)fflush(stderr);
}
```
user: What is the c source code of the assembly code below:

```asm
<_E__sys_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D2(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%esi
  mov    $0x3b,%edi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0x20,%edi
  call   <putc@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _E__sys_error(char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  (void)vfprintf(stderr, fmt, pvar);
  va_end(pvar);
  putc(';', stderr);
  putc(' ', stderr);
  (void)fflush(stderr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_E__sys_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D6(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rbx),%esi
  mov    $0x3b,%edi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0x20,%edi
  call   <putc@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void _E__sys_error(char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  (void)vfprintf(stderr, fmt, pvar);
  va_end(pvar);
  putc(';', stderr);
  putc(' ', stderr);
  (void)fflush(stderr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L23
L13:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fact_digsum@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L7:
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x109c80,-0x4(%rbp)
  jle    L13
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
  for (i = 3; i < 1088641; ++i)
    if (fact_digsum(i) == i)
      sum += i;
  printf("%d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%ebx
  mov    $0x0,%ebp
L9:
  mov    %ebx,%edi
  call   <fact_digsum@plt>
  mov    %eax,%edx
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%edx
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x109c81,%ebx
  jne    L9
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
  for (i = 3; i < 1088641; ++i)
    if (fact_digsum(i) == i)
      sum += i;
  printf("%d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    %ebx,%edi
  call   <fact_digsum@plt>
  mov    %eax,%r8d
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%r8d
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x109c81,%ebx
  jne    L2
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
  for (i = 3; i < 1088641; ++i)
    if (fact_digsum(i) == i)
      sum += i;
  printf("%d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    %ebx,%edi
  call   <fact_digsum@plt>
  mov    %eax,%r8d
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%r8d
  cmove  %eax,%ebp
  add    $0x1,%ebx
  cmp    $0x109c81,%ebx
  jne    L4
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
  for (i = 3; i < 1088641; ++i)
    if (fact_digsum(i) == i)
      sum += i;
  printf("%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<algoritmo4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L43
L44:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L40
L37:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edi
  cltd
  idiv   %edi
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L47:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L47
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L37
  addl   $0x1,-0x8(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L44
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <algoritmo3@plt>
  leave
  ret
```

assistant: ```c
int *algoritmo4(int **A, int *b, int n) {
  int m, i, j, k;
  for (k = 0; k < n - 1; k++) {
    for (i = k + 1; i < n; i++) {
      m = A[i][k] / A[k][k];
      A[i][k] = 0;
      for (j = k + 1; j < n; j++)
        A[i][j] = A[i][j] - m * A[k][j];
      b[i] = b[i] - m * b[k];
    }
  }
  return algoritmo3(A, b, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<algoritmo4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %rsi,%rbx
  mov    %edx,%r14d
  cmp    $0x1,%edx
  jle    L24
  lea    0x8(%rdi),%rbp
  lea    -0x2(%rdx),%eax
  mov    %eax,0x1c(%rsp)
  mov    %eax,%eax
  add    $0x2,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x4,%r13d
  movq   $0x1,0x10(%rsp)
  mov    $0x0,%r12d
L41:
  mov    0x10(%rsp),%r9
  cmp    %r9d,%r14d
  jle    L22
  lea    0x0(,%r12,4),%r11
  mov    0x1c(%rsp),%eax
  lea    0x2(%r12,%rax,1),%r8
  shl    $0x2,%r8
  mov    %rbp,%r10
L40:
  mov    %r10,%rdi
  mov    %r11,%rcx
  add    (%r10),%rcx
  mov    %rbp,%rsi
  mov    -0x8(%rbp),%r15
  mov    (%rcx),%eax
  cltd
  idivl  (%r15,%r11,1)
  movl   $0x0,(%rcx)
  mov    %r13,%rdx
  mov    %r9,0x8(%rsp)
L13:
  mov    %rdx,%rcx
  add    (%rdi),%rcx
  mov    -0x8(%rsi),%r15
  mov    %eax,%r9d
  imul   (%r15,%rdx,1),%r9d
  sub    %r9d,(%rcx)
  add    $0x4,%rdx
  cmp    %rdx,%r8
  jne    L13
  mov    0x8(%rsp),%r9
  imul   (%rbx,%r12,4),%eax
  sub    %eax,(%rbx,%r9,4)
  add    $0x1,%r9
  add    $0x8,%r10
  cmp    %r9d,%r14d
  jg     L40
L22:
  add    $0x1,%r12
  addq   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%rax
  add    $0x4,%r13
  add    $0x8,%rbp
  subl   $0x1,0x1c(%rsp)
  cmp    0x20(%rsp),%rax
  jne    L41
L24:
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    0x28(%rsp),%rdi
  call   <algoritmo3@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *algoritmo4(int **A, int *b, int n) {
  int m, i, j, k;
  for (k = 0; k < n - 1; k++) {
    for (i = k + 1; i < n; i++) {
      m = A[i][k] / A[k][k];
      A[i][k] = 0;
      for (j = k + 1; j < n; j++)
        A[i][j] = A[i][j] - m * A[k][j];
      b[i] = b[i] - m * b[k];
    }
  }
  return algoritmo3(A, b, n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<algoritmo4>:
  endbr64
  push   %r13
  mov    %rsi,%r10
  mov    %edx,%r8d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edx
  jle    L1
  lea    -0x2(%rdx),%r13d
  xor    %r11d,%r11d
  mov    $0x1,%ebp
  add    $0x2,%r13
  nopl   0x0(%rax,%rax,1)
L45:
  cmp    %ebp,%r8d
  jle    L11
  mov    (%r12,%r11,2),%rdi
  mov    %rbp,%r9
  lea    (%rdi,%r11,1),%rbx
L15:
  mov    (%r12,%r9,8),%rcx
  lea    (%rcx,%r11,1),%rsi
  mov    (%rsi),%eax
  cltd
  idivl  (%rbx)
  movl   $0x0,(%rsi)
  mov    %rbp,%rdx
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    (%rdi,%rdx,4),%esi
  imul   %eax,%esi
  sub    %esi,(%rcx,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r8d
  jg     L30
  imul   (%r10,%r11,1),%eax
  sub    %eax,(%r10,%r9,4)
  add    $0x1,%r9
  cmp    %r9d,%r8d
  jg     L15
L11:
  add    $0x1,%rbp
  add    $0x4,%r11
  cmp    %rbp,%r13
  jne    L45
L1:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  mov    %r8d,%edx
  pop    %r12
  mov    %r10,%rsi
  pop    %r13
  jmp    1050 <algoritmo3@plt>
```

assistant: ```c
int *algoritmo4(int **A, int *b, int n) {
  int m, i, j, k;
  for (k = 0; k < n - 1; k++) {
    for (i = k + 1; i < n; i++) {
      m = A[i][k] / A[k][k];
      A[i][k] = 0;
      for (j = k + 1; j < n; j++)
        A[i][j] = A[i][j] - m * A[k][j];
      b[i] = b[i] - m * b[k];
    }
  }
  return algoritmo3(A, b, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L24:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <split_me@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    $0x3e7,%eax
  jle    L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 1000; i++)
    split_me(&i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L11:
  mov    %rbx,%rdi
  call   <split_me@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3e7,%eax
  jle    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 1000; i++)
    split_me(&i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <split_me@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3e7,%eax
  jle    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 1000; i++)
    split_me(&i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %rbx,%rdi
  call   <split_me@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3e7,%eax
  jle    L16
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 1000; i++)
    split_me(&i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L54
  cmpb   $0x39,-0x4(%rbp)
  jg     L54
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L57
L54:
  cmpb   $0x60,-0x4(%rbp)
  jle    L59
  cmpb   $0x66,-0x4(%rbp)
  jg     L59
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L57
L59:
  cmpb   $0x40,-0x4(%rbp)
  jle    L38
  cmpb   $0x46,-0x4(%rbp)
  jg     L38
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L57
L38:
  mov    $0xffffffff,%eax
L57:
  pop    %rbp
  ret
```

assistant: ```c
int hex2int(char c) {
  if (c >= '0' && c <= '9')
    return (c - '0');
  if (c >= 'a' && c <= 'f')
    return (c - 'a' + 10);
  if (c >= 'A' && c <= 'F')
    return (c - 'A' + 10);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L9
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L9:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L16:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int hex2int(char c) {
  if (c >= '0' && c <= '9')
    return (c - '0');
  if (c >= 'a' && c <= 'f')
    return (c - 'a' + 10);
  if (c >= 'A' && c <= 'F')
    return (c - 'A' + 10);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L6
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L11
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex2int(char c) {
  if (c >= '0' && c <= '9')
    return (c - '0');
  if (c >= 'a' && c <= 'f')
    return (c - 'a' + 10);
  if (c >= 'A' && c <= 'F')
    return (c - 'A' + 10);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L10
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex2int(char c) {
  if (c >= '0' && c <= '9')
    return (c - '0');
  if (c >= 'a' && c <= 'f')
    return (c - 'a' + 10);
  if (c >= 'A' && c <= 'F')
    return (c - 'A' + 10);
  return -1;
}
```