user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D205(%rip),%rdi
  call   <puts@plt>
  lea    D109(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rbx
  jmp    L27
L19:
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  lea    D157(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  movapd %xmm0,%xmm1
  divsd  D98(%rip),%xmm1
  lea    D68(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D103(%rip),%rdi
  call   <puts@plt>
L27:
  lea    0x20(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  D130(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm0,%xmm0
  addsd  D130(%rip),%xmm0
  movapd %xmm1,%xmm5
  divsd  %xmm0,%xmm5
  movsd  D214(%rip),%xmm6
  mulsd  %xmm5,%xmm6
  movsd  %xmm6,0x10(%rsp)
  movsd  D170(%rip),%xmm1
  movsd  %xmm5,0x18(%rsp)
  movapd %xmm5,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm6
  mulsd  %xmm6,%xmm1
  mulsd  0x18(%rsp),%xmm6
  movapd %xmm6,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  D116(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  D84(%rip),%xmm0
  movsd  D190(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L19
  comisd D190(%rip),%xmm0
  jbe    L39
  movsd  D190(%rip),%xmm1
  subsd  %xmm0,%xmm1
  xorpd  D77(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  lea    D157(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  movapd %xmm0,%xmm1
  divsd  D98(%rip),%xmm1
  lea    D68(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D103(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L39:
  movsd  0x8(%rsp),%xmm0
  lea    D125(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D205
type: string
name: parse_data
arguments: data_label: D109
type: string
name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D157
type: string
name: parse_data
arguments: data_label: D98
type: byte[8]
name: parse_data
arguments: data_label: D68
type: string
name: parse_data
arguments: data_label: D103
type: string
name: parse_data
arguments: data_label: D130
type: f64
name: parse_data
arguments: data_label: D214
type: byte[8]
name: parse_data
arguments: data_label: D170
type: byte[8]
name: parse_data
arguments: data_label: D116
type: byte[8]
name: parse_data
arguments: data_label: D84
type: byte[8]
name: parse_data
arguments: data_label: D190
type: f64[2]
name: parse_data
arguments: data_label: D77
type: byte[16]
name: parse_data
arguments: data_label: D125
type: string

tool: D205: At a depth of 5000 feet, the flow rate is 641.3225 cubic feet per second

tool: D109: Please enter your initial guess with flow rate 1000.000 cubic feet per second

tool: D3: %lf

tool: D157: Acording to your guess the flow rate is %f cubic feet per second


tool: {"D98": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D68: Deffernce is %f
with percentage error %f


tool: D103: Please enter the your next guess

tool: D130: 10

tool: {"D214": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x19,0x40]}

tool: {"D170": [0x55,0x55,0x55,0x55,0x55,0x55,0xe5,0x3f]}

tool: {"D116": [0x92,0x24,0x49,0x92,0x24,0x89,0x5a,0x40]}

tool: {"D84": [0xd3,0xc1,0x32,0x90,0x65,0xd4,0xa3,0x3f]}

tool: {"D190": [1000.0,100.0]}

tool: {"D77": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D125: Your guess is rigth %f


assistant: ```c
main() {
  double q, n = .014, r, a, s = .0015, depth, width = 10;
  printf("At a depth of 5000 feet, the flow rate is 641.3225 cubic feet per second\n");
  printf("Please enter your initial guess with flow rate 1000.000 cubic feet per second\n");
  while (1) {
    scanf("%lf", &depth);
    r = depth * width / (2 * depth + width);
    a = (2.0 * 3.14 * r * depth) + (2.0 * 3.14 * r * r);
    q = ((1.486 / n) * a * (pow(r, (double)2 / 3)) * (pow(s, (double)1 / 2)));
    if (q < 1000) {
      double fin = 1000 - q;
      printf("Acording to your guess the flow rate is %f cubic feet per second\n", q);
      printf("Deffernce is %f\nwith percentage error %f\n", fin, fin / 100);
      printf("Please enter the your next guess\n");
    } else if (q > 1000) {
      double fin = (1000 - q) * (-1.0);
      printf("Acording to your guess the flow rate is %f cubic feet per second\n", q);
      printf("Deffernce is %f\nwith percentage error %f\n", fin, fin / 100);
      printf("Please enter the your next guess\n");
    } else {
      printf("Your guess is rigth %f\n", depth);
      break;
    }
  }
}
```