ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<decode_digit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %dil,%dil
  js     L129
  mov    %ebx,%edi
  and    $0x7f,%edi
  cmp    $0x5f,%dil
  je     L98
L88:
  cmp    $0x6,%dil
  je     L29
  cmp    $0x6b,%dil
  je     L0
  cmp    $0x2f,%dil
  je     L67
  cmp    $0x36,%dil
  je     L99
  cmp    $0x3d,%dil
  je     L4
  cmp    $0x7d,%dil
  je     L14
  cmp    $0x7,%dil
  je     L2
  cmp    $0x7f,%dil
  je     L103
  cmp    $0x3f,%dil
  je     L75
  cmp    $0x58,%dil
  je     L94
  pop    %rbx
  ret
  nopl   (%rax)
L94:
  mov    $0x4c,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L75:
  mov    $0x39,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L103:
  mov    $0x38,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x37,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x36,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x35,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L99:
  mov    $0x34,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x32,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L129:
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  and    $0x7f,%edi
  cmp    $0x5f,%dil
  jne    L88
L98:
  mov    $0x30,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   (%rax)
L67:
  mov    $0x33,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax)
L29:
  mov    $0x31,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void decode_digit(unsigned char raw_digit) {
  unsigned char digit_pattern[] = {0x00, 0x5f, 0x06, 0x6b, 0x2f, 0x36, 0x3d, 0x7d, 0x07, 0x7f, 0x3f, 0x58};
  char *digit_string[] = {"", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "L"};
  if (raw_digit & 0x80)
    printf(".");
  for (int i = 0; i <= 11; i++)
    if (digit_pattern[i] == (raw_digit & 0x7f))
      printf("%s", digit_string[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    0xc(%rax),%eax
  add    %edx,%eax
  add    $0x2,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    $0x1,%eax
  jmp    L4
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0xc(%rax),%ecx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%eax
  add    %ecx,%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0xc(%rax),%ecx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%eax
  add    %ecx,%eax
  cltq
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int add_entry(const char *name, glob_t *pglob, int *nfound) {
  pglob->gl_pathv = (char **)realloc(pglob->gl_pathv, (pglob->gl_pathc + pglob->gl_offs + 2) * sizeof(char *));
  if (pglob->gl_pathv == NULL)
    return 1;
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc] = strdup(name);
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc + 1] = NULL;
  pglob->gl_pathc++;
  (*nfound)++;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<add_entry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    0xc(%rsi),%eax
  add    0x8(%rsi),%eax
  lea    0x10(,%rax,8),%esi
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%edx
  test   %rax,%rax
  je     L0
  mov    0x8(%rbx),%edx
  add    0xc(%rbx),%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,8),%r13
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%r13)
  mov    0x8(%rbx),%eax
  add    0xc(%rbx),%eax
  cltq
  mov    (%rbx),%rdx
  movq   $0x0,0x8(%rdx,%rax,8)
  addl   $0x1,0x8(%rbx)
  addl   $0x1,0x0(%rbp)
  mov    $0x0,%edx
L0:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int add_entry(const char *name, glob_t *pglob, int *nfound) {
  pglob->gl_pathv = (char **)realloc(pglob->gl_pathv, (pglob->gl_pathc + pglob->gl_offs + 2) * sizeof(char *));
  if (pglob->gl_pathv == NULL)
    return 1;
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc] = strdup(name);
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc + 1] = NULL;
  pglob->gl_pathc++;
  (*nfound)++;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_entry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    0xc(%rsi),%eax
  mov    (%rbx),%rdi
  add    0x8(%rsi),%eax
  lea    0x10(,%rax,8),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  test   %rbp,%rbp
  je     L7
  mov    0x8(%rbx),%r14d
  mov    0xc(%rbx),%r15d
  mov    %r13,%rdi
  add    %r14d,%r15d
  add    $0x1,%r14d
  movslq %r15d,%r15
  lea    0x0(,%r15,8),%rdx
  mov    %rdx,0x8(%rsp)
  call   <strdup@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,0x0(%rbp,%r15,8)
  xor    %eax,%eax
  movq   $0x0,0x8(%rbp,%rdx,1)
  mov    %r14d,0x8(%rbx)
  addl   $0x1,(%r12)
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int add_entry(const char *name, glob_t *pglob, int *nfound) {
  pglob->gl_pathv = (char **)realloc(pglob->gl_pathv, (pglob->gl_pathc + pglob->gl_offs + 2) * sizeof(char *));
  if (pglob->gl_pathv == NULL)
    return 1;
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc] = strdup(name);
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc + 1] = NULL;
  pglob->gl_pathc++;
  (*nfound)++;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_entry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    0xc(%rsi),%eax
  mov    (%rbx),%rdi
  add    0x8(%rsi),%eax
  lea    0x10(,%rax,8),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  test   %rbp,%rbp
  je     L8
  mov    0x8(%rbx),%r14d
  mov    0xc(%rbx),%r15d
  mov    %r13,%rdi
  add    %r14d,%r15d
  add    $0x1,%r14d
  movslq %r15d,%r15
  lea    0x0(,%r15,8),%rdx
  mov    %rdx,0x8(%rsp)
  call   <strdup@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,0x0(%rbp,%r15,8)
  xor    %eax,%eax
  movq   $0x0,0x8(%rbp,%rdx,1)
  mov    %r14d,0x8(%rbx)
  addl   $0x1,(%r12)
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int add_entry(const char *name, glob_t *pglob, int *nfound) {
  pglob->gl_pathv = (char **)realloc(pglob->gl_pathv, (pglob->gl_pathc + pglob->gl_offs + 2) * sizeof(char *));
  if (pglob->gl_pathv == NULL)
    return 1;
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc] = strdup(name);
  pglob->gl_pathv[pglob->gl_offs + pglob->gl_pathc + 1] = NULL;
  pglob->gl_pathc++;
  (*nfound)++;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<binary_search_with_less_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L50:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L0
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L54
L0:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L54:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jg     L50
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L22
  mov    -0x1c(%rbp),%eax
  jmp    L20
L22:
  mov    $0xffffffff,%eax
L20:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: Searching for %d


assistant: ```c
int binary_search_with_less_comp(int a[], int l, int r, int key) {
  printf("Searching for %d\n", key);
  int m = 0;
  while (r - l > 1) {
    m = l + (r - l) / 2;
    if (key < a[m])
      r = m;
    else
      l = m;
  }
  if (key == a[l])
    return l;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_search_with_less_comp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %ecx,%ebp
  mov    %ecx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L19:
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ebx,%eax
  movslq %eax,%rdx
  cmp    %ebp,(%r12,%rdx,4)
  cmovle %eax,%ebx
  cmovg  %eax,%r13d
L15:
  mov    %r13d,%edx
  sub    %ebx,%edx
  cmp    $0x1,%edx
  jg     L19
  movslq %ebx,%rax
  cmp    %ebp,(%r12,%rax,4)
  mov    $0xffffffff,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: Searching for %d


assistant: ```c
int binary_search_with_less_comp(int a[], int l, int r, int key) {
  printf("Searching for %d\n", key);
  int m = 0;
  while (r - l > 1) {
    m = l + (r - l) / 2;
    if (key < a[m])
      r = m;
    else
      l = m;
  }
  if (key == a[l])
    return l;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_search_with_less_comp>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    D0(%rip),%rdi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L10:
  sar    %eax
  add    %ebx,%eax
  movslq %eax,%rsi
  cmp    %ebp,(%r12,%rsi,4)
  cmovle %eax,%ebx
  cmovg  %eax,%r13d
L3:
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jg     L10
  movslq %ebx,%rax
  cmp    %ebp,(%r12,%rax,4)
  mov    $0xffffffff,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: Searching for %d


assistant: ```c
int binary_search_with_less_comp(int a[], int l, int r, int key) {
  printf("Searching for %d\n", key);
  int m = 0;
  while (r - l > 1) {
    m = l + (r - l) / 2;
    if (key < a[m])
      r = m;
    else
      l = m;
  }
  if (key == a[l])
    return l;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binary_search_with_less_comp>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    D2(%rip),%rdi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %ecx,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L9:
  sar    %eax
  add    %ebx,%eax
  movslq %eax,%rsi
  cmp    %ebp,(%r12,%rsi,4)
  cmovle %eax,%ebx
  cmovg  %eax,%r13d
L0:
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jg     L9
  movslq %ebx,%rax
  cmp    %ebp,(%r12,%rax,4)
  mov    $0xffffffff,%eax
  cmove  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: Searching for %d


assistant: ```c
int binary_search_with_less_comp(int a[], int l, int r, int key) {
  printf("Searching for %d\n", key);
  int m = 0;
  while (r - l > 1) {
    m = l + (r - l) / 2;
    if (key < a[m])
      r = m;
    else
      l = m;
  }
  if (key == a[l])
    return l;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_PBS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: f64

tool: D0: 2

assistant: ```c
float get_PBS(double in_t_1, double in_t_2, double out_t) {
  float PBS;
  PBS = ((in_t_1 + in_t_2 - out_t) / 2.);
  return PBS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_PBS>:
  endbr64
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  D2(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
float get_PBS(double in_t_1, double in_t_2, double out_t) {
  float PBS;
  PBS = ((in_t_1 + in_t_2 - out_t) / 2.);
  return PBS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_PBS>:
  endbr64
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  D4(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
float get_PBS(double in_t_1, double in_t_2, double out_t) {
  float PBS;
  PBS = ((in_t_1 + in_t_2 - out_t) / 2.);
  return PBS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_PBS>:
  endbr64
  addsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  D7(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
float get_PBS(double in_t_1, double in_t_2, double out_t) {
  float PBS;
  PBS = ((in_t_1 + in_t_2 - out_t) / 2.);
  return PBS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void xfree(void *ptr) {
  if ((__builtin_expect((ptr == NULL), 0))) {
    ;
  };
  free(ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xfree>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void xfree(void *ptr) {
  if ((__builtin_expect((ptr == NULL), 0))) {
    ;
  };
  free(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void xfree(void *ptr) {
  if ((__builtin_expect((ptr == NULL), 0))) {
    ;
  };
  free(ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void xfree(void *ptr) {
  if ((__builtin_expect((ptr == NULL), 0))) {
    ;
  };
  free(ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x80(%rbp)
  movl   $0x1,-0x7c(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x84(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x78(%rbp)
  jmp    L19
L30:
  mov    -0x80(%rbp),%eax
  imul   -0x78(%rbp),%eax
  mov    %eax,-0x80(%rbp)
  subl   $0x1,-0x78(%rbp)
L19:
  cmpl   $0x0,-0x78(%rbp)
  jg     L30
  mov    -0x84(%rbp),%eax
  mov    %eax,-0x78(%rbp)
  jmp    L28
L38:
  mov    -0x7c(%rbp),%eax
  imul   -0x78(%rbp),%eax
  mov    %eax,-0x7c(%rbp)
  subl   $0x1,-0x78(%rbp)
L28:
  cmpl   $0x0,-0x78(%rbp)
  jg     L38
  mov    -0x80(%rbp),%eax
  cltd
  idivl  -0x7c(%rbp)
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D45
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D40
type_guessed: string

tool: D1: Enter the string 

tool: D8: %s

tool: D45: Enter the value of r

tool: D3: %d

tool: D40: The r permutations of a string of n letters is %d

assistant: ```c
int main() {
  int n, p = 1, r, q = 1, i;
  char a[100];
  printf("Enter the string \n");
  scanf("%s", a);
  n = strlen(a);
  printf("Enter the value of r\n");
  scanf("%d", &r);
  for (i = n; i >= 1; i--) {
    p = p * i;
  }
  for (i = r; i >= 1; i--) {
    q = q * i;
  }
  printf("The r permutations of a string of n letters is %d", p / q);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %ebx,%ebx
  jle    L52
  mov    $0x1,%eax
L15:
  imul   %ebx,%eax
  sub    $0x1,%ebx
  jne    L15
L38:
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L64
  mov    $0x1,%ecx
L24:
  imul   %edx,%ecx
  sub    $0x1,%edx
  jne    L24
L47:
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L52:
  mov    $0x1,%eax
  jmp    L38
L64:
  mov    $0x1,%ecx
  jmp    L47
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D49
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D40
type_infered: string

tool: D3: Enter the string 

tool: D11: %s

tool: D49: Enter the value of r

tool: D13: %d

tool: D40: The r permutations of a string of n letters is %d

assistant: ```c
int main() {
  int n, p = 1, r, q = 1, i;
  char a[100];
  printf("Enter the string \n");
  scanf("%s", a);
  n = strlen(a);
  printf("Enter the value of r\n");
  scanf("%d", &r);
  for (i = n; i >= 1; i--) {
    p = p * i;
  }
  for (i = r; i >= 1; i--) {
    q = q * i;
  }
  printf("The r permutations of a string of n letters is %d", p / q);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rdi
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0x1,%eax
  test   %ebx,%ebx
  jle    L22
  nopl   0x0(%rax)
L37:
  imul   %ebx,%eax
  sub    $0x1,%ebx
  jne    L37
L22:
  mov    0xc(%rsp),%edx
  mov    $0x1,%ecx
  test   %edx,%edx
  jle    L12
  nopl   (%rax)
L47:
  imul   %edx,%ecx
  sub    $0x1,%edx
  jne    L47
L12:
  cltd
  lea    D13(%rip),%rdi
  idiv   %ecx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D45
data_type: string
name: retrieve_data
arguments: label: D35
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D45: Enter the string 

tool: D35: %s

tool: D20: Enter the value of r

tool: D11: %d

tool: D13: The r permutations of a string of n letters is %d

assistant: ```c
int main() {
  int n, p = 1, r, q = 1, i;
  char a[100];
  printf("Enter the string \n");
  scanf("%s", a);
  n = strlen(a);
  printf("Enter the value of r\n");
  scanf("%d", &r);
  for (i = n; i >= 1; i--) {
    p = p * i;
  }
  for (i = r; i >= 1; i--) {
    q = q * i;
  }
  printf("The r permutations of a string of n letters is %d", p / q);
  return 0;
}
```