ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__strCopySub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x18(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x18(%rbp),%rax
  cmp    %rax,-0x20(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void __strCopySub(char **destPtr, char *src, size_t index, size_t len) {
  assert(destPtr != NULL);
  assert(*destPtr != NULL);
  assert(src != NULL);
  assert(index >= 0 && index <= strlen(src));
  assert(len >= 0 && len <= strlen(src) - index);
  *destPtr = (char *)realloc(*destPtr, len + 1);
  strncpy(*destPtr, &src[index], len);
  (*destPtr)[len] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__strCopySub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r13,%rax
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    %r13,%rax
  cmp    %r12,%rax
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x1(%r12),%rsi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  lea    (%rbx,%r13,1),%rsi
  mov    %r12,%rdx
  call   <strncpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void __strCopySub(char **destPtr, char *src, size_t index, size_t len) {
  assert(destPtr != NULL);
  assert(*destPtr != NULL);
  assert(src != NULL);
  assert(index >= 0 && index <= strlen(src));
  assert(len >= 0 && len <= strlen(src) - index);
  *destPtr = (char *)realloc(*destPtr, len + 1);
  strncpy(*destPtr, &src[index], len);
  (*destPtr)[len] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<__strCopySub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    %r13,%rax
  setae  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  sub    %r13,%rax
  cmp    %r12,%rax
  setae  %dil
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  lea    0x1(%r12),%rsi
  call   <realloc@plt>
  lea    (%rbx,%r13,1),%rsi
  mov    %r12,%rdx
  mov    %rax,0x0(%rbp)
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void __strCopySub(char **destPtr, char *src, size_t index, size_t len) {
  assert(destPtr != NULL);
  assert(*destPtr != NULL);
  assert(src != NULL);
  assert(index >= 0 && index <= strlen(src));
  assert(len >= 0 && len <= strlen(src) - index);
  *destPtr = (char *)realloc(*destPtr, len + 1);
  strncpy(*destPtr, &src[index], len);
  (*destPtr)[len] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__strCopySub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,0x0(%rbp)
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    %r13,%rax
  setae  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  sub    %r13,%rax
  cmp    %r12,%rax
  setae  %dil
  call   <assert@plt>
  mov    0x0(%rbp),%rdi
  lea    0x1(%r12),%rsi
  call   <realloc@plt>
  lea    (%rbx,%r13,1),%rsi
  mov    %r12,%rdx
  mov    %rax,0x0(%rbp)
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void __strCopySub(char **destPtr, char *src, size_t index, size_t len) {
  assert(destPtr != NULL);
  assert(*destPtr != NULL);
  assert(src != NULL);
  assert(index >= 0 && index <= strlen(src));
  assert(len >= 0 && len <= strlen(src) - index);
  *destPtr = (char *)realloc(*destPtr, len + 1);
  strncpy(*destPtr, &src[index], len);
  (*destPtr)[len] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmpfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmpfunc>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmpfunc>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmpfunc>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmpfunc(const void *a, const void *b) {
  const char **ia = (const char **)a;
  const char **ib = (const char **)b;
  return strcmp(*ia, *ib);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1b0(%rbp)
  jmp    L65
L77:
  mov    -0x1b0(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1b0(%rbp)
L65:
  cmpl   $0x63,-0x1b0(%rbp)
  jle    L77
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x32,-0x1ac(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  movl   $0x64,-0x1a4(%rbp)
L62:
  mov    -0x1a8(%rbp),%eax
  cmp    -0x1a4(%rbp),%eax
  jle    L66
  movl   $0xffffffff,-0x1ac(%rbp)
  jmp    L58
L66:
  mov    -0x1a8(%rbp),%edx
  mov    -0x1a4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1ac(%rbp)
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,%edx
  je     L35
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,%edx
  jle    L44
  mov    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1a4(%rbp)
  jmp    L45
L44:
  mov    -0x1ac(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1a8(%rbp)
  nop
L45:
  jmp    L62
L35:
  nop
L58:
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D9: Enter a number to search: 

tool: D25: %d

tool: D11: Given number is at position: %d


assistant: ```c
int main() {
  int a[100], x, i;
  for (i = 0; i < 100; i++)
    a[i] = i * 5;
  printf("Enter a number to search: ");
  scanf("%d", &x);
  int mid = 100 / 2, low = 0, high = 100;
  while (1) {
    if (low > high) {
      mid = -1;
      break;
    }
    mid = (low + high) / 2;
    if (x == a[mid])
      break;
    if (x < a[mid]) {
      high = mid - 1;
      continue;
    } else {
      low = mid + 1;
      continue;
    }
  }
  printf("Given number is at position: %d\n", mid);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
L51:
  mov    %eax,(%rdx)
  add    $0x5,%eax
  add    $0x4,%rdx
  cmp    $0x1f4,%eax
  jne    L51
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    $0x64,%esi
  mov    $0x0,%ecx
  jmp    L10
L28:
  lea    0x1(%rax),%ecx
L56:
  cmp    %esi,%ecx
  jg     L45
L10:
  lea    (%rcx,%rsi,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%r8d
  movslq %eax,%rdx
  mov    0x10(%rsp,%rdx,4),%edx
  cmp    %edi,%edx
  je     L64
  jle    L28
  lea    -0x1(%rax),%esi
  jmp    L56
L45:
  mov    $0xffffffff,%r8d
L64:
  mov    %r8d,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: string

tool: D22: Enter a number to search: 

tool: D11: %d

tool: D23: Given number is at position: %d


assistant: ```c
int main() {
  int a[100], x, i;
  for (i = 0; i < 100; i++)
    a[i] = i * 5;
  printf("Enter a number to search: ");
  scanf("%d", &x);
  int mid = 100 / 2, low = 0, high = 100;
  while (1) {
    if (low > high) {
      mid = -1;
      break;
    }
    mid = (low + high) / 2;
    if (x == a[mid])
      break;
    if (x < a[mid]) {
      high = mid - 1;
      continue;
    } else {
      low = mid + 1;
      continue;
    }
  }
  printf("Given number is at position: %d\n", mid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %eax,(%rdx)
  add    $0x5,%eax
  add    $0x4,%rdx
  cmp    $0x1f4,%eax
  jne    L33
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    $0x64,%edx
  xor    %eax,%eax
  jmp    L13
  nopl   0x0(%rax)
L54:
  lea    -0x1(%rsi),%edx
  cmp    %edx,%eax
  jg     L19
L13:
  lea    (%rax,%rdx,1),%esi
  sar    %esi
  movslq %esi,%rcx
  cmp    %edi,0x10(%rsp,%rcx,4)
  je     L41
  jg     L54
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  jle    L13
L19:
  or     $0xffffffff,%esi
L41:
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: D12: Enter a number to search: 

tool: D5: %d

tool: D13: Given number is at position: %d


assistant: ```c
int main() {
  int a[100], x, i;
  for (i = 0; i < 100; i++)
    a[i] = i * 5;
  printf("Enter a number to search: ");
  scanf("%d", &x);
  int mid = 100 / 2, low = 0, high = 100;
  while (1) {
    if (low > high) {
      mid = -1;
      break;
    }
    mid = (low + high) / 2;
    if (x == a[mid])
      break;
    if (x < a[mid]) {
      high = mid - 1;
      continue;
    } else {
      low = mid + 1;
      continue;
    }
  }
  printf("Given number is at position: %d\n", mid);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  movdqa D18(%rip),%xmm1
  movdqa D29(%rip),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x1a0(%rsp),%rdx
  lea    0x10(%rsp),%rax
  nopl   0x0(%rax,%rax,1)
L61:
  movdqa %xmm1,%xmm2
  add    $0x10,%rax
  paddd  %xmm3,%xmm1
  movdqa %xmm2,%xmm0
  pslld  $0x2,%xmm0
  paddd  %xmm2,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L61
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D46(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    $0x64,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L33:
  lea    (%rax,%rdx,1),%esi
  sar    %esi
  movslq %esi,%rcx
  cmp    %edi,0x10(%rsp,%rcx,4)
  je     L67
  jle    L56
  lea    -0x1(%rsi),%edx
  cmp    %eax,%edx
  jge    L33
L27:
  or     $0xffffffff,%esi
L67:
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
  nopl   (%rax)
L56:
  lea    0x1(%rsi),%eax
  cmp    %edx,%eax
  jle    L33
  jmp    L27
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D29
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D46
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D29": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D13: Enter a number to search: 

tool: D46: %d

tool: D1: Given number is at position: %d


assistant: ```c
int main() {
  int a[100], x, i;
  for (i = 0; i < 100; i++)
    a[i] = i * 5;
  printf("Enter a number to search: ");
  scanf("%d", &x);
  int mid = 100 / 2, low = 0, high = 100;
  while (1) {
    if (low > high) {
      mid = -1;
      break;
    }
    mid = (low + high) / 2;
    if (x == a[mid])
      break;
    if (x < a[mid]) {
      high = mid - 1;
      continue;
    } else {
      low = mid + 1;
      continue;
    }
  }
  printf("Given number is at position: %d\n", mid);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_file_objects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    D0(%rip),%rax
  mov    (%rax),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ebx,%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L27:
  cmp    %rdx,%rsp
  je     L87
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L87:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L24
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L24:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x28(%rbp)
L9:
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L32
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L9
L32:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L36
L20:
  mov    $0xffffffff,%eax
  jmp    L79
L36:
  mov    $0x0,%eax
L79:
  mov    %r12,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int copy_file_objects(FILE *source, FILE *target) {
  char buffer[BUFSIZ];
  size_t read;
  do {
    read = fread(buffer, 1, sizeof(buffer), source);
    fwrite(buffer, 1, read, target);
  } while (!feof(source) && !feof(target));
  return (ferror(source) || ferror(target)) ? -1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_file_objects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%r14d
  movslq %r14d,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L45:
  cmp    %rdx,%rsp
  je     L66
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L66:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L18
  orq    $0x0,-0x8(%rsp,%rax,1)
L18:
  mov    %rsp,%r13
L39:
  mov    %rbx,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %rax,%rdx
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L74
  mov    %r12,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L39
L74:
  mov    %rbx,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L0
  mov    %r12,%rdi
  call   <ferror@plt>
  neg    %rax
  sbb    %eax,%eax
L72:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L72
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy_file_objects(FILE *source, FILE *target) {
  char buffer[BUFSIZ];
  size_t read;
  do {
    read = fread(buffer, 1, sizeof(buffer), source);
    fwrite(buffer, 1, read, target);
  } while (!feof(source) && !feof(target));
  return (ferror(source) || ferror(target)) ? -1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_file_objects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D7(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%r14
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L89
L99:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L99
L89:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L76
L40:
  mov    %rsp,%rbx
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L2
L86:
  mov    %r12,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %rbx,%rdi
  mov    %r13,%rcx
  mov    $0x1,%esi
  mov    %rax,%rdx
  call   <fwrite@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L21
L2:
  mov    %r12,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L29
  mov    %r13,%rdi
  call   <ferror@plt>
  neg    %rax
  sbb    %eax,%eax
L12:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L96
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L76:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L40
L29:
  mov    $0xffffffff,%eax
  jmp    L12
L96:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy_file_objects(FILE *source, FILE *target) {
  char buffer[BUFSIZ];
  size_t read;
  do {
    read = fread(buffer, 1, sizeof(buffer), source);
    fwrite(buffer, 1, read, target);
  } while (!feof(source) && !feof(target));
  return (ferror(source) || ferror(target)) ? -1 : 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_file_objects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D5(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  mov    %rax,%r14
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L63
L86:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L86
L63:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L47
L1:
  mov    %rsp,%rbx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L12
L45:
  mov    %r12,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %rbx,%rdi
  mov    %r13,%rcx
  mov    $0x1,%esi
  mov    %rax,%rdx
  call   <fwrite@plt>
  mov    %r12,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L0
L12:
  mov    %r12,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L41
  mov    %r13,%rdi
  call   <ferror@plt>
  neg    %rax
  sbb    %eax,%eax
L99:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L47:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L1
L41:
  mov    $0xffffffff,%eax
  jmp    L99
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int copy_file_objects(FILE *source, FILE *target) {
  char buffer[BUFSIZ];
  size_t read;
  do {
    read = fread(buffer, 1, sizeof(buffer), source);
    fwrite(buffer, 1, read, target);
  } while (!feof(source) && !feof(target));
  return (ferror(source) || ferror(target)) ? -1 : 0;
}
```