ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<switch_sym_link>:
  endbr64
  push   %r12
  mov    $0x14,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <readlink@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  add    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <remove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  add    %r12,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdx
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ecx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <symlink@plt>
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D2: Currently pointing to %s


tool: D3: %s.%d

tool: D15: Now pointing to %s


assistant: ```c
void switch_sym_link(const char *file_name_ptr) {
  char buf[(20)];
  int bufsize = 0;
  int file_index = 0;
  bufsize = readlink(file_name_ptr, buf, (20));
  buf[bufsize + 1] = '\0';
  printf("Currently pointing to %s\n", buf);
  remove(file_name_ptr);
  int index_of_int = strlen(file_name_ptr) + 1;
  file_index = atoi(buf + index_of_int);
  file_index++;
  sprintf(buf, "%s.%d", file_name_ptr, file_index);
  symlink(buf, file_name_ptr);
  printf("Now pointing to %s\n", buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<switch_sym_link>:
  endbr64
  push   %r12
  mov    $0x14,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <readlink@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  add    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <remove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  movslq %edi,%rdi
  add    %r12,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdx
  lea    D26(%rip),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%ecx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <symlink@plt>
  mov    %r12,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string
name: retrieve_data
arguments: data_tag: D22
data_type: string

tool: D2: Currently pointing to %s


tool: D26: %s.%d

tool: D22: Now pointing to %s


assistant: ```c
void switch_sym_link(const char *file_name_ptr) {
  char buf[(20)];
  int bufsize = 0;
  int file_index = 0;
  bufsize = readlink(file_name_ptr, buf, (20));
  buf[bufsize + 1] = '\0';
  printf("Currently pointing to %s\n", buf);
  remove(file_name_ptr);
  int index_of_int = strlen(file_name_ptr) + 1;
  file_index = atoi(buf + index_of_int);
  file_index++;
  sprintf(buf, "%s.%d", file_name_ptr, file_index);
  symlink(buf, file_name_ptr);
  printf("Now pointing to %s\n", buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_sub_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_sub_ok(int x, int y) {
  long long llx = (long long)x;
  long long lly = (long long)y;
  long long lldiff = llx - lly;
  int diff = (int)lldiff;
  return (lldiff == diff);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_sub_ok>:
  endbr64
  movslq %edi,%rdi
  movslq %esi,%rsi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_sub_ok(int x, int y) {
  long long llx = (long long)x;
  long long lly = (long long)y;
  long long lldiff = llx - lly;
  int diff = (int)lldiff;
  return (lldiff == diff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_sub_ok>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_sub_ok(int x, int y) {
  long long llx = (long long)x;
  long long lly = (long long)y;
  long long lldiff = llx - lly;
  int diff = (int)lldiff;
  return (lldiff == diff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_sub_ok>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_sub_ok(int x, int y) {
  long long llx = (long long)x;
  long long lly = (long long)y;
  long long lldiff = llx - lly;
  int diff = (int)lldiff;
  return (lldiff == diff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<selSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L19:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <min@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <display@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void selSort(int *ptr, int size) {
  int i, temp, minUnsort;
  for (i = 0; i < size; i++) {
    minUnsort = min(ptr, i, size);
    temp = ptr[i];
    ptr[i] = ptr[minUnsort];
    ptr[minUnsort] = temp;
    display(ptr);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<selSort>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %esi,%r13d
  mov    $0x0,%ebx
L9:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <min@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  mov    %edx,(%rax)
  mov    %rbp,%rdi
  call   <display@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

assistant: ```c
void selSort(int *ptr, int size) {
  int i, temp, minUnsort;
  for (i = 0; i < size; i++) {
    minUnsort = min(ptr, i, size);
    temp = ptr[i];
    ptr[i] = ptr[minUnsort];
    ptr[minUnsort] = temp;
    display(ptr);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<selSort>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L11:
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <min@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %rbp,%rdi
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  mov    %edx,(%rax)
  call   <display@plt>
  cmp    %r12,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void selSort(int *ptr, int size) {
  int i, temp, minUnsort;
  for (i = 0; i < size; i++) {
    minUnsort = min(ptr, i, size);
    temp = ptr[i];
    ptr[i] = ptr[minUnsort];
    ptr[minUnsort] = temp;
    display(ptr);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<selSort>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L15:
  mov    %ebx,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <min@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %rbp,%rdi
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  mov    %edx,(%rax)
  call   <display@plt>
  cmp    %r12,%rbx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void selSort(int *ptr, int size) {
  int i, temp, minUnsort;
  for (i = 0; i < size; i++) {
    minUnsort = min(ptr, i, size);
    temp = ptr[i];
    ptr[i] = ptr[minUnsort];
    ptr[minUnsort] = temp;
    display(ptr);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_first>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L13:
  nop
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L13
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
char get_first(void) {
  int ch;
  ch = getchar();
  while (getchar() != '\n')
    continue;
  return ch;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_first>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
L1:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L1
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char get_first(void) {
  int ch;
  ch = getchar();
  while (getchar() != '\n')
    continue;
  return ch;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_first>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L9
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char get_first(void) {
  int ch;
  ch = getchar();
  while (getchar() != '\n')
    continue;
  return ch;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_first>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L8
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char get_first(void) {
  int ch;
  ch = getchar();
  while (getchar() != '\n')
    continue;
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<desvio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <varianza@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double desvio(double arreglo[], int size) {
  double var = varianza(arreglo, size);
  double des = sqrt(var);
  return des;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<desvio>:
  endbr64
  sub    $0x8,%rsp
  call   <varianza@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
  sqrtsd %xmm0,%xmm0
L15:
  add    $0x8,%rsp
  ret
L7:
  call   <sqrt@plt>
  jmp    L15
```

assistant: ```c
double desvio(double arreglo[], int size) {
  double var = varianza(arreglo, size);
  double des = sqrt(var);
  return des;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<desvio>:
  endbr64
  sub    $0x8,%rsp
  call   <varianza@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L5
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L5:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double desvio(double arreglo[], int size) {
  double var = varianza(arreglo, size);
  double des = sqrt(var);
  return des;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<desvio>:
  endbr64
  sub    $0x8,%rsp
  call   <varianza@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L1
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L1:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double desvio(double arreglo[], int size) {
  double var = varianza(arreglo, size);
  double des = sqrt(var);
  return des;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_keyboard_keypress_key_not_found>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x10(%rbp)
  mov    $0x0,%eax
  call   <keyboard_init@plt>
  mov    $0xff,%edi
  call   <keyboard_keypress@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <check_keyports@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void test_keyboard_keypress_key_not_found() {
  unsigned char expected_keyports[8] = {0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff};
  keyboard_init();
  keyboard_keypress(0xff);
  check_keyports(expected_keyports);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_keyboard_keypress_key_not_found>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  call   <keyboard_init@plt>
  mov    $0xff,%edi
  call   <keyboard_keypress@plt>
  mov    %rsp,%rdi
  call   <check_keyports@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_keyboard_keypress_key_not_found() {
  unsigned char expected_keyports[8] = {0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff};
  keyboard_init();
  keyboard_keypress(0xff);
  check_keyports(expected_keyports);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_keyboard_keypress_key_not_found>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  call   <keyboard_init@plt>
  mov    $0xff,%edi
  call   <keyboard_keypress@plt>
  mov    %rsp,%rdi
  call   <check_keyports@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_keyboard_keypress_key_not_found() {
  unsigned char expected_keyports[8] = {0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff};
  keyboard_init();
  keyboard_keypress(0xff);
  check_keyports(expected_keyports);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_keyboard_keypress_key_not_found>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  call   <keyboard_init@plt>
  mov    $0xff,%edi
  call   <keyboard_keypress@plt>
  mov    %rsp,%rdi
  call   <check_keyports@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_keyboard_keypress_key_not_found() {
  unsigned char expected_keyports[8] = {0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff};
  keyboard_init();
  keyboard_keypress(0xff);
  check_keyports(expected_keyports);
}
```
user: What is the c source code of the assembly code below?

```asm
<escape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    $0xa,%esi
  call   <strchr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  setne  %r12b
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x0,%r8d
  test   %eax,%eax
  jle    L35
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  sete   %r8b
  movzbl %r8b,%r8d
L35:
  movb   $0x22,0x0(%rbp)
  test   %r14,%r14
  je     L30
  movb   $0x22,0x1(%rbp)
  movb   $0xa,0x2(%rbp)
  lea    0x4(%rbp),%rax
  movb   $0x22,0x3(%rbp)
  lea    -0x4(%r13),%esi
  movzbl (%rbx),%ecx
  cmp    $0x1,%esi
  jle    L42
  test   %cl,%cl
  je     L42
L10:
  lea    0x1(%rbx),%rdx
  jmp    L72
L29:
  movb   $0x5c,(%rax)
  lea    0x1(%rax),%rax
L43:
  mov    %rdx,%rcx
  movzbl -0x1(%rdx),%edi
  mov    %dil,(%rax)
  lea    0x1(%rax),%rax
L19:
  sub    $0x1,%esi
  movzbl (%rcx),%ecx
  add    $0x1,%rdx
  cmp    $0x1,%esi
  jle    L42
  test   %cl,%cl
  je     L42
L72:
  cmp    $0x22,%cl
  je     L29
  cmp    $0xa,%cl
  jne    L43
  movb   $0x5c,(%rax)
  movb   $0x6e,0x1(%rax)
  movb   $0x22,0x2(%rax)
  movb   $0xa,0x3(%rax)
  movb   $0x22,0x4(%rax)
  sub    $0x5,%esi
  mov    %rdx,%rcx
  lea    0x5(%rax),%rax
  jmp    L19
L42:
  test   %r8d,%r8d
  je     L95
  lea    -0x3(%rax),%rdx
  test   %r12b,%r12b
  cmovne %rdx,%rax
L95:
  movb   $0x22,(%rax)
  movb   $0x0,0x1(%rax)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  lea    0x1(%rbp),%rax
  lea    -0x1(%r13),%esi
  movzbl (%rbx),%ecx
  cmp    $0x1,%esi
  jle    L95
  test   %cl,%cl
  jne    L10
  jmp    L95
```

assistant: ```c
char *escape(const char *text, char *bf, int len) {
  char *bfp = bf;
  int multiline = strchr(text, '\n') != NULL;
  int eol = 0;
  int textlen = strlen(text);
  if ((textlen > 0) && (text[textlen - 1] == '\n'))
    eol = 1;
  *bfp++ = '"';
  --len;
  if (multiline) {
    *bfp++ = '"';
    *bfp++ = '\n';
    *bfp++ = '"';
    len -= 3;
  }
  while (*text != '\0' && len > 1) {
    if (*text == '"')
      *bfp++ = '\\';
    else if (*text == '\n') {
      *bfp++ = '\\';
      *bfp++ = 'n';
      *bfp++ = '"';
      *bfp++ = '\n';
      *bfp++ = '"';
      len -= 5;
      ++text;
      goto next;
    }
    *bfp++ = *text++;
  next:
    --len;
  }
  if (multiline && eol)
    bfp -= 3;
  *bfp++ = '"';
  *bfp = '\0';
  return bf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<escape>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0xa,%esi
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  mov    %rbx,%rdi
  test   %rax,%rax
  mov    %rax,%r14
  setne  %r12b
  call   <strlen@plt>
  xor    %esi,%esi
  test   %eax,%eax
  jle    L79
  cltq
  xor    %esi,%esi
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  sete   %sil
L79:
  movb   $0x22,0x0(%r13)
  test   %r14,%r14
  je     L38
  mov    $0xa22,%ecx
  movb   $0x22,0x3(%r13)
  lea    0x4(%r13),%rax
  mov    %cx,0x1(%r13)
  lea    -0x4(%rbp),%ecx
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jg     L116
  jmp    L78
  nopl   0x0(%rax)
L94:
  cmp    $0xa,%dl
  je     L75
L77:
  movzbl -0x1(%rbx),%edx
  sub    $0x1,%ecx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jle    L78
L116:
  test   %dl,%dl
  je     L78
L16:
  add    $0x1,%rbx
  cmp    $0x22,%dl
  jne    L94
  movb   $0x5c,(%rax)
  add    $0x1,%rax
  jmp    L77
  nopl   0x0(%rax)
L75:
  sub    $0x5,%ecx
  movl   $0xa226e5c,(%rax)
  add    $0x5,%rax
  sub    $0x1,%ecx
  movb   $0x22,-0x1(%rax)
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jg     L116
  nopl   0x0(%rax)
L78:
  test   %esi,%esi
  je     L34
  lea    -0x3(%rax),%rdx
  test   %r12b,%r12b
  cmovne %rdx,%rax
L34:
  mov    $0x22,%edx
  mov    %dx,(%rax)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  lea    -0x1(%rbp),%ecx
  movzbl (%rbx),%edx
  lea    0x1(%r13),%rax
  cmp    $0x1,%ecx
  jle    L34
  test   %dl,%dl
  jne    L16
  jmp    L34
```

assistant: ```c
char *escape(const char *text, char *bf, int len) {
  char *bfp = bf;
  int multiline = strchr(text, '\n') != NULL;
  int eol = 0;
  int textlen = strlen(text);
  if ((textlen > 0) && (text[textlen - 1] == '\n'))
    eol = 1;
  *bfp++ = '"';
  --len;
  if (multiline) {
    *bfp++ = '"';
    *bfp++ = '\n';
    *bfp++ = '"';
    len -= 3;
  }
  while (*text != '\0' && len > 1) {
    if (*text == '"')
      *bfp++ = '\\';
    else if (*text == '\n') {
      *bfp++ = '\\';
      *bfp++ = 'n';
      *bfp++ = '"';
      *bfp++ = '\n';
      *bfp++ = '"';
      len -= 5;
      ++text;
      goto next;
    }
    *bfp++ = *text++;
  next:
    --len;
  }
  if (multiline && eol)
    bfp -= 3;
  *bfp++ = '"';
  *bfp = '\0';
  return bf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<escape>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0xa,%esi
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  mov    %rbx,%rdi
  test   %rax,%rax
  mov    %rax,%r14
  setne  %r12b
  call   <strlen@plt>
  xor    %esi,%esi
  test   %eax,%eax
  jle    L127
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  sete   %sil
L127:
  movb   $0x22,0x0(%r13)
  test   %r14,%r14
  je     L128
  mov    $0xa22,%ecx
  movb   $0x22,0x3(%r13)
  lea    0x4(%r13),%rax
  mov    %cx,0x1(%r13)
  lea    -0x4(%rbp),%ecx
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jg     L68
  jmp    L21
  nop
L85:
  cmp    $0xa,%dl
  je     L61
L22:
  movzbl -0x1(%rbx),%edx
  sub    $0x1,%ecx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jle    L21
L68:
  test   %dl,%dl
  je     L21
L7:
  add    $0x1,%rbx
  cmp    $0x22,%dl
  jne    L85
  movb   $0x5c,(%rax)
  add    $0x1,%rax
  jmp    L22
  nopl   0x0(%rax)
L61:
  sub    $0x5,%ecx
  movl   $0xa226e5c,(%rax)
  add    $0x5,%rax
  sub    $0x1,%ecx
  movb   $0x22,-0x1(%rax)
  movzbl (%rbx),%edx
  cmp    $0x1,%ecx
  jg     L68
  nopl   0x0(%rax)
L21:
  test   %r12b,%r12b
  je     L12
  lea    -0x3(%rax),%rdx
  test   %sil,%sil
  cmovne %rdx,%rax
L12:
  mov    $0x22,%edx
  mov    %dx,(%rax)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L128:
  lea    -0x1(%rbp),%ecx
  movzbl (%rbx),%edx
  lea    0x1(%r13),%rax
  cmp    $0x1,%ecx
  jle    L12
  test   %dl,%dl
  jne    L7
  jmp    L12
```

assistant: ```c
char *escape(const char *text, char *bf, int len) {
  char *bfp = bf;
  int multiline = strchr(text, '\n') != NULL;
  int eol = 0;
  int textlen = strlen(text);
  if ((textlen > 0) && (text[textlen - 1] == '\n'))
    eol = 1;
  *bfp++ = '"';
  --len;
  if (multiline) {
    *bfp++ = '"';
    *bfp++ = '\n';
    *bfp++ = '"';
    len -= 3;
  }
  while (*text != '\0' && len > 1) {
    if (*text == '"')
      *bfp++ = '\\';
    else if (*text == '\n') {
      *bfp++ = '\\';
      *bfp++ = 'n';
      *bfp++ = '"';
      *bfp++ = '\n';
      *bfp++ = '"';
      len -= 5;
      ++text;
      goto next;
    }
    *bfp++ = *text++;
  next:
    --len;
  }
  if (multiline && eol)
    bfp -= 3;
  *bfp++ = '"';
  *bfp = '\0';
  return bf;
}
```