ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<piece_replace_quote_comma>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %ecx,%edx
  mov    %r13,%rdi
  call   <piece_delete_quote_comma@plt>
  movb   $0x0,(%rbx)
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <piece_insert_quote_comma@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *piece_replace_quote_comma(char *destination, char *source, char *new_data, int piece_offset) {
  char tmp[1024];
  char *results;
  piece_delete_quote_comma(tmp, source, piece_offset);
  *destination = '\0';
  results = piece_insert_quote_comma(destination, tmp, new_data, piece_offset);
  return results;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<piece_replace_quote_comma>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    %ecx,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <piece_delete_quote_comma@plt>
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rdx
  mov    %r12d,%ecx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <piece_insert_quote_comma@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x418,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *piece_replace_quote_comma(char *destination, char *source, char *new_data, int piece_offset) {
  char tmp[1024];
  char *results;
  piece_delete_quote_comma(tmp, source, piece_offset);
  *destination = '\0';
  results = piece_insert_quote_comma(destination, tmp, new_data, piece_offset);
  return results;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<piece_replace_quote_comma>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    %ecx,%edx
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <piece_delete_quote_comma@plt>
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rdx
  mov    %r12d,%ecx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <piece_insert_quote_comma@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x418,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *piece_replace_quote_comma(char *destination, char *source, char *new_data, int piece_offset) {
  char tmp[1024];
  char *results;
  piece_delete_quote_comma(tmp, source, piece_offset);
  *destination = '\0';
  results = piece_insert_quote_comma(destination, tmp, new_data, piece_offset);
  return results;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D41(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D46(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L4
L28:
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L4:
  cmpl   $0x3,-0x38(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D41
data_type: string
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string

tool: D41: Norte

tool: D46: Sul

tool: D25: Leste

tool: D13: Oeste

tool: D24: %s = %d


assistant: ```c
int main() {
  typedef enum direcao { Norte, Sul, Leste, Oeste, DirecaoLast } Direcao;
  const char *DirecaoNames[] = {"Norte", "Sul", "Leste", "Oeste"};
  for (int i = 0; i < DirecaoLast; i++) {
    Direcao direcao = i;
    printf("%s = %d\n", DirecaoNames[i], direcao);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rax
  mov    %rax,(%rsp)
  lea    D21(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D20(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D2(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D25(%rip),%rbp
L10:
  mov    (%rsp,%rbx,8),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D42
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D20
type: string
name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D25
type: string

tool: D42: Norte

tool: D21: Sul

tool: D20: Leste

tool: D2: Oeste

tool: D25: %s = %d


assistant: ```c
int main() {
  typedef enum direcao { Norte, Sul, Leste, Oeste, DirecaoLast } Direcao;
  const char *DirecaoNames[] = {"Norte", "Sul", "Leste", "Oeste"};
  for (int i = 0; i < DirecaoLast; i++) {
    Direcao direcao = i;
    printf("%s = %d\n", DirecaoNames[i], direcao);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rsi
  lea    D28(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D41(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D15(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D9(%rip),%rax
  mov    %rax,0x18(%rsp)
L20:
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L5
  mov    (%rsp,%rbx,8),%rsi
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
type: string
name: retrieve_data
arguments: data_label: D28
type: string
name: retrieve_data
arguments: data_label: D41
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D9
type: string

tool: D40: Norte

tool: D28: %s = %d


tool: D41: Sul

tool: D15: Leste

tool: D9: Oeste

assistant: ```c
int main() {
  typedef enum direcao { Norte, Sul, Leste, Oeste, DirecaoLast } Direcao;
  const char *DirecaoNames[] = {"Norte", "Sul", "Leste", "Oeste"};
  for (int i = 0; i < DirecaoLast; i++) {
    Direcao direcao = i;
    printf("%s = %d\n", DirecaoNames[i], direcao);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D31(%rip),%rcx
  push   %rbp
  movq   %rcx,%xmm0
  lea    D48(%rip),%rcx
  lea    D23(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D49(%rip),%rax
  mov    %rsp,%r12
  movq   %rax,%xmm1
  lea    D19(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L5:
  mov    (%r12,%rbx,8),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L5
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D31
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D49
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D31: Norte

tool: D48: Leste

tool: D23: %s = %d


tool: D49: Sul

tool: D19: Oeste

assistant: ```c
int main() {
  typedef enum direcao { Norte, Sul, Leste, Oeste, DirecaoLast } Direcao;
  const char *DirecaoNames[] = {"Norte", "Sul", "Leste", "Oeste"};
  for (int i = 0; i < DirecaoLast; i++) {
    Direcao direcao = i;
    printf("%s = %d\n", DirecaoNames[i], direcao);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_40>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_40@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_40(void) {
  handle_40(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gen_40>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_40@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_40(void) {
  handle_40(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gen_40>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_40@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_40(void) {
  handle_40(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen_40>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_40@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_40(void) {
  handle_40(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L10
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_max(int *arr, int size) {
  int res = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] > res)
      res = arr[i];
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_max>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%edx
L25:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L25
L12:
  mov    %edx,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int find_max(int *arr, int size) {
  int res = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] > res)
      res = arr[i];
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_max>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L12
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int find_max(int *arr, int size) {
  int res = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] > res)
      res = arr[i];
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_max>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L42
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L44
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm2,%xmm2
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L14:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L14
  movdqa %xmm2,%xmm0
  mov    %edx,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%ecx
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L10
L63:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L22
  mov    0x4(%rdi,%r8,1),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L22
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
L22:
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
L44:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L63
```

assistant: ```c
int find_max(int *arr, int size) {
  int res = 0, i;
  for (i = 0; i < size; i++)
    if (arr[i] > res)
      res = arr[i];
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_argv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  movl   $0x0,(%r12)
  mov    %rbp,(%rax)
  mov    %rax,%r13
  nopw   0x0(%rax,%rax,1)
L104:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  lea    0x1(%rbx),%rbx
  test   %r8,%r8
  jne    L104
  movl   $0x0,0xc(%rsp)
  xor    %r15d,%r15d
L124:
  movzbl (%rax),%r14d
  lea    0x1(%rax),%rbx
  test   %r14b,%r14b
  jne    L132
L164:
  test   %r15d,%r15d
  je     L47
  movslq %r15d,%r15
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  add    %rbp,%r15
  call   <memset@plt>
L37:
  movb   $0x0,(%r15)
  mov    (%r12),%eax
  lea    0x1(%r15),%rbp
  add    $0x1,%eax
  mov    %eax,(%r12)
  cltq
  mov    %rbp,0x0(%r13,%rax,8)
  test   %r14b,%r14b
  jne    L129
  jmp    L60
  nop
L66:
  add    $0x1,%rbx
L129:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L66
  cmpb   $0x0,(%rbx)
  jne    L181
L60:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L132:
  movsbl %r14b,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L11
  testb  $0x1,0xc(%rsp)
  je     L164
L11:
  cmp    $0x5c,%r14b
  je     L20
  cmp    $0x22,%r14b
  je     L36
L84:
  test   %r15d,%r15d
  je     L146
  movslq %r15d,%r15
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  call   <memset@plt>
  lea    0x0(%rbp,%r15,1),%rax
L112:
  mov    %r14b,(%rax)
  lea    0x1(%rax),%rbp
  nopl   (%rax)
L181:
  xor    %r15d,%r15d
L185:
  mov    %rbx,%rax
  jmp    L124
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r15d
  jmp    L185
  cs nopw 0x0(%rax,%rax,1)
L47:
  mov    %rbp,%r15
  jmp    L37
L36:
  mov    %r15d,%eax
  sar    %r15d
  and    $0x1,%eax
  test   %eax,%eax
  jne    L84
  xorl   $0x1,0xc(%rsp)
  test   %r15d,%r15d
  je     L185
  movslq %r15d,%r15
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  mov    %r15,%rdx
  add    %r15,%rbp
  xor    %r15d,%r15d
  call   <memset@plt>
  jmp    L185
L146:
  mov    %rbp,%rax
  jmp    L112
```

assistant: ```c
char **parse_argv(char *cmdline, int *argc) {
  char **result = calloc(strlen(cmdline), sizeof(char *));
  char *output = cmdline;
  char c;
  int nb = 0;
  int iq = 0;
  *argc = 0;
  result[0] = output;
  while (isspace(*cmdline))
    cmdline++;
  do {
    c = *cmdline++;
    if (!c || (isspace(c) && !iq)) {
      while (nb) {
        *output++ = '\\';
        nb--;
      }
      *output++ = 0;
      result[++*argc] = output;
      if (!c)
        return result;
      while (isspace(*cmdline))
        cmdline++;
      if (!*cmdline)
        return result;
      continue;
    }
    if (c == '\\')
      ++nb;
    else {
      if (c == '"') {
        if (!(nb & 1)) {
          iq = !iq;
          c = 0;
        }
        nb = nb >> 1;
      }
      while (nb) {
        *output++ = '\\';
        nb--;
      }
      if (c)
        *output++ = c;
    }
  } while (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_argv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  movl   $0x0,(%r12)
  mov    %rbp,(%rax)
  mov    %rax,%r13
  nopw   0x0(%rax,%rax,1)
L162:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  lea    0x1(%rbx),%rbx
  test   %r8,%r8
  jne    L162
  movl   $0x0,0xc(%rsp)
  xor    %r15d,%r15d
L81:
  movzbl (%rax),%r14d
  lea    0x1(%rax),%rbx
  test   %r14b,%r14b
  jne    L136
L86:
  test   %r15d,%r15d
  je     L6
  movslq %r15d,%r15
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  add    %rbp,%r15
  call   <memset@plt>
L109:
  movb   $0x0,(%r15)
  mov    (%r12),%eax
  lea    0x1(%r15),%rbp
  add    $0x1,%eax
  mov    %eax,(%r12)
  cltq
  mov    %rbp,0x0(%r13,%rax,8)
  test   %r14b,%r14b
  jne    L23
  jmp    L91
  nop
L64:
  add    $0x1,%rbx
L23:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L64
  cmpb   $0x0,(%rbx)
  jne    L21
L91:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L136:
  movsbl %r14b,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L169
  testb  $0x1,0xc(%rsp)
  je     L86
L169:
  cmp    $0x5c,%r14b
  je     L184
  cmp    $0x22,%r14b
  je     L153
L132:
  test   %r15d,%r15d
  je     L105
  movslq %r15d,%r15
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  call   <memset@plt>
  lea    0x0(%rbp,%r15,1),%rax
L40:
  mov    %r14b,(%rax)
  lea    0x1(%rax),%rbp
  nopl   (%rax)
L21:
  xor    %r15d,%r15d
L27:
  mov    %rbx,%rax
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L184:
  add    $0x1,%r15d
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rbp,%r15
  jmp    L109
L153:
  mov    %r15d,%eax
  sar    %r15d
  and    $0x1,%eax
  test   %eax,%eax
  jne    L132
  xorl   $0x1,0xc(%rsp)
  test   %r15d,%r15d
  je     L27
  movslq %r15d,%r15
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  mov    %r15,%rdx
  add    %r15,%rbp
  xor    %r15d,%r15d
  call   <memset@plt>
  jmp    L27
L105:
  mov    %rbp,%rax
  jmp    L40
```

assistant: ```c
char **parse_argv(char *cmdline, int *argc) {
  char **result = calloc(strlen(cmdline), sizeof(char *));
  char *output = cmdline;
  char c;
  int nb = 0;
  int iq = 0;
  *argc = 0;
  result[0] = output;
  while (isspace(*cmdline))
    cmdline++;
  do {
    c = *cmdline++;
    if (!c || (isspace(c) && !iq)) {
      while (nb) {
        *output++ = '\\';
        nb--;
      }
      *output++ = 0;
      result[++*argc] = output;
      if (!c)
        return result;
      while (isspace(*cmdline))
        cmdline++;
      if (!*cmdline)
        return result;
      continue;
    }
    if (c == '\\')
      ++nb;
    else {
      if (c == '"') {
        if (!(nb & 1)) {
          iq = !iq;
          c = 0;
        }
        nb = nb >> 1;
      }
      while (nb) {
        *output++ = '\\';
        nb--;
      }
      if (c)
        *output++ = c;
    }
  } while (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <baz@plt>
  leave
  ret
```

assistant: ```c
int foo(int n) {
  int baz(int);
  return baz(n);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  call   <baz@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int foo(int n) {
  int baz(int);
  return baz(n);
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  jmp    1050 <baz@plt>
```

assistant: ```c
int foo(int n) {
  int baz(int);
  return baz(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  jmp    1050 <baz@plt>
```

assistant: ```c
int foo(int n) {
  int baz(int);
  return baz(n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<debug_usage>:
  endbr64
  push   %rbx
  lea    D90(%rip),%rbx
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D101(%rip),%rdi
  call   <puts@plt>
  lea    D100(%rip),%rdi
  call   <puts@plt>
  lea    D69(%rip),%rdi
  call   <puts@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    D87(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D74(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D99(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <list_debugs@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D90
type: string
name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D101
type: string
name: parse_data
arguments: tag: D100
type: string
name: parse_data
arguments: tag: D69
type: string
name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D87
type: string
name: parse_data
arguments: tag: D28
type: string
name: parse_data
arguments: tag: D74
type: string
name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D99
type: string
name: parse_data
arguments: tag: D29
type: string

tool: D90: subnet-tools

tool: D24: Usage: %s -D Debugs [OPTIONS] [COMMAND] [FILES]


tool: D101: Debugs looks like : symbol1:level,symbol2:level;...

tool: D100: symbol is the  symbol to  debug, increasing level gives more info, ie :

tool: D69: level 1 : get more infos on errors (badly formatted file, bad IP etc...)

tool: D30: level 4+ : print  internal program debug info ; wont tell you anything without source code

tool: D87: level 9 : if implemented, print info for each loop of the program

tool: D28: Example 1 :

tool: D74: '%s -D memory:1,parseopts:2,trucmuche:3 simplify1 MYFILE'


tool: D27: Example 2 :

tool: D99: '%s -D loadcsv:3 sort MYFILE' will tell you every invalid line in your file.



tool: D29: Available symbols :

assistant: ```c
void debug_usage(void) {
  printf("Usage: %s -D Debugs [OPTIONS] [COMMAND] [FILES]\n", "subnet-tools");
  printf("Debugs looks like : symbol1:level,symbol2:level;...\n");
  printf("symbol is the  symbol to  debug, increasing level gives more info, ie :\n");
  printf("level 1 : get more infos on errors (badly formatted file, bad IP etc...)\n");
  printf("level 4+ : print  internal program debug info ; wont tell you anything without source code\n");
  printf("level 9 : if implemented, print info for each loop of the program\n");
  printf("Example 1 :\n");
  printf("'%s -D memory:1,parseopts:2,trucmuche:3 simplify1 MYFILE'\n", "subnet-tools");
  printf("Example 2 :\n");
  printf("'%s -D loadcsv:3 sort MYFILE' will tell you every invalid line in your file.\n\n", "subnet-tools");
  printf("Available symbols :\n");
  list_debugs();
}
```