ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D26
type_infered: string
name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D11
type_infered: string

tool: D26: 
ERROR in matrixlib:
	 %s

tool: D23: 
(in function %s)

tool: D11: 
Exiting program

assistant: ```c
int err_exit(char *err_message, char *func_name) {
  printf("\nERROR in matrixlib:\n\t %s", err_message);
  printf("\n(in function %s)", func_name);
  printf("\nExiting program\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memory_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x7ff,-0x8(%rbp)
  jle    L30
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  sub    $0x1,%edx
  sub    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memory_test(unsigned char *in_buffer, unsigned int *in_length, unsigned char *out_buffer) {
  int i, length = *in_length;
  for (i = 0; i < 2048; i++) {
    out_buffer[i] = 0;
  }
  for (i = 0; i < length; i++) {
    out_buffer[length - 1 - i] = in_buffer[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memory_test>:
  endbr64
  mov    (%rsi),%esi
  lea    0x800(%rdx),%rcx
  mov    %rdx,%rax
L24:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L24
  test   %esi,%esi
  jle    L19
  movslq %esi,%rcx
  lea    -0x1(%rdx,%rcx,1),%rax
  lea    -0x2(%rdx,%rcx,1),%rcx
  lea    -0x1(%rsi),%edx
  sub    %rdx,%rcx
L12:
  movzbl (%rdi),%edx
  mov    %dl,(%rax)
  add    $0x1,%rdi
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L19:
  ret
```

assistant: ```c
void memory_test(unsigned char *in_buffer, unsigned int *in_length, unsigned char *out_buffer) {
  int i, length = *in_length;
  for (i = 0; i < 2048; i++) {
    out_buffer[i] = 0;
  }
  for (i = 0; i < length; i++) {
    out_buffer[length - 1 - i] = in_buffer[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memory_test>:
  endbr64
  mov    %rdi,%r8
  lea    0x8(%rdx),%rdi
  mov    %rdx,%rcx
  mov    %rsi,%r9
  and    $0xfffffffffffffff8,%rdi
  movslq (%r9),%r9
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  sub    %rdi,%rcx
  mov    %rdx,%rsi
  movq   $0x0,0x7f8(%rdx)
  add    $0x800,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r9d,%r9d
  jle    L8
  lea    -0x1(%r9),%ecx
  mov    %r8,%rdx
  movslq %ecx,%rax
  mov    %ecx,%ecx
  add    %rsi,%rax
  lea    -0x2(%rsi,%r9,1),%rsi
  sub    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl (%rdx),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %rsi,%rax
  jne    L10
L8:
  ret
```

assistant: ```c
void memory_test(unsigned char *in_buffer, unsigned int *in_length, unsigned char *out_buffer) {
  int i, length = *in_length;
  for (i = 0; i < 2048; i++) {
    out_buffer[i] = 0;
  }
  for (i = 0; i < length; i++) {
    out_buffer[length - 1 - i] = in_buffer[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memory_test>:
  endbr64
  mov    %rdi,%r8
  lea    0x8(%rdx),%rdi
  mov    %rdx,%rcx
  mov    %rsi,%r9
  and    $0xfffffffffffffff8,%rdi
  movslq (%r9),%r9
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  sub    %rdi,%rcx
  mov    %rdx,%rsi
  movq   $0x0,0x7f8(%rdx)
  add    $0x800,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  test   %r9d,%r9d
  jle    L10
  lea    -0x1(%r9),%ecx
  mov    %r8,%rdx
  movslq %ecx,%rax
  mov    %ecx,%ecx
  add    %rsi,%rax
  lea    -0x2(%rsi,%r9,1),%rsi
  sub    %rcx,%rsi
  nopw   0x0(%rax,%rax,1)
L18:
  movzbl (%rdx),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,0x1(%rax)
  cmp    %rsi,%rax
  jne    L18
L10:
  ret
```

assistant: ```c
void memory_test(unsigned char *in_buffer, unsigned int *in_length, unsigned char *out_buffer) {
  int i, length = *in_length;
  for (i = 0; i < 2048; i++) {
    out_buffer[i] = 0;
  }
  for (i = 0; i < length; i++) {
    out_buffer[length - 1 - i] = in_buffer[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<map_netdb_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x7,%eax
  pop    %rbp
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<map_netdb_error>:
  endbr64
  mov    $0x7,%eax
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<map_netdb_error>:
  endbr64
  mov    $0x7,%eax
  ret
```

assistant: ```c
int map_netdb_error(int netdb_code) {
  switch (netdb_code) {
  default:
    return 7;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x18(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x20(%rbp),%xmm3
  movss  -0x14(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x1c(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x18(%rbp),%xmm3
  movss  -0x1c(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm2
  divss  %xmm2,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L16
  ucomiss %xmm1,%xmm0
  jne    L16
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L16:
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D6: %f %f %f %f

tool: D2: INF

tool: D16: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x;
  x = (a1 * a2) * (b1 - b2) / (a2 * b1 - a1 * b2);
  float y;
  y = (b1 * b2) * (a1 - a2) / (a1 * b2 - a2 * b1);
  if ((a1 / a2) == (b1 / b2)) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", x, y);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm0
  movss  0x10(%rsp),%xmm4
  movss  0xc(%rsp),%xmm2
  movss  0x14(%rsp),%xmm3
  movaps %xmm0,%xmm5
  divss  %xmm4,%xmm5
  movaps %xmm2,%xmm1
  divss  %xmm3,%xmm1
  ucomiss %xmm1,%xmm5
  jp     L22
  jne    L22
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L22:
  movaps %xmm4,%xmm5
  mulss  %xmm2,%xmm5
  movaps %xmm0,%xmm6
  mulss  %xmm3,%xmm6
  movaps %xmm2,%xmm1
  mulss  %xmm3,%xmm1
  movaps %xmm0,%xmm7
  subss  %xmm4,%xmm7
  mulss  %xmm7,%xmm1
  movaps %xmm6,%xmm7
  subss  %xmm5,%xmm7
  divss  %xmm7,%xmm1
  mulss  %xmm4,%xmm0
  subss  %xmm3,%xmm2
  mulss  %xmm2,%xmm0
  subss  %xmm6,%xmm5
  divss  %xmm5,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D26(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L13
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string

tool: D9: %f %f %f %f

tool: D19: INF

tool: D26: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x;
  x = (a1 * a2) * (b1 - b2) / (a2 * b1 - a1 * b2);
  float y;
  y = (b1 * b2) * (a1 - a2) / (a1 * b2 - a2 * b1);
  if ((a1 / a2) == (b1 / b2)) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", x, y);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D0(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm4
  movss  0x14(%rsp),%xmm3
  movaps %xmm2,%xmm5
  movaps %xmm0,%xmm1
  divss  %xmm4,%xmm5
  divss  %xmm3,%xmm1
  ucomiss %xmm1,%xmm5
  jp     L26
  jne    L26
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L26:
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm6
  movaps %xmm2,%xmm7
  mov    $0x2,%eax
  mulss  %xmm3,%xmm1
  movaps %xmm4,%xmm5
  subss  %xmm4,%xmm7
  mulss  %xmm4,%xmm2
  lea    D10(%rip),%rdi
  mulss  %xmm3,%xmm6
  mulss  %xmm0,%xmm5
  subss  %xmm3,%xmm0
  mulss  %xmm7,%xmm1
  mulss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  movaps %xmm6,%xmm7
  subss  %xmm5,%xmm7
  subss  %xmm6,%xmm5
  divss  %xmm7,%xmm1
  divss  %xmm5,%xmm2
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L8
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string

tool: D0: %f %f %f %f

tool: D13: INF

tool: D10: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x;
  x = (a1 * a2) * (b1 - b2) / (a2 * b1 - a1 * b2);
  float y;
  y = (b1 * b2) * (a1 - a2) / (a1 * b2 - a2 * b1);
  if ((a1 / a2) == (b1 / b2)) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", x, y);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D26(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm4
  movss  0x14(%rsp),%xmm3
  movaps %xmm2,%xmm5
  movaps %xmm0,%xmm1
  divss  %xmm4,%xmm5
  divss  %xmm3,%xmm1
  ucomiss %xmm1,%xmm5
  jp     L14
  jne    L14
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L14:
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm6
  movaps %xmm2,%xmm7
  mov    $0x2,%eax
  mulss  %xmm3,%xmm1
  movaps %xmm4,%xmm5
  subss  %xmm4,%xmm7
  mulss  %xmm4,%xmm2
  lea    D20(%rip),%rdi
  mulss  %xmm3,%xmm6
  mulss  %xmm0,%xmm5
  subss  %xmm3,%xmm0
  mulss  %xmm7,%xmm1
  mulss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  movaps %xmm6,%xmm7
  subss  %xmm5,%xmm7
  subss  %xmm6,%xmm5
  divss  %xmm7,%xmm1
  divss  %xmm5,%xmm2
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L32
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D22
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D26: %f %f %f %f

tool: D22: INF

tool: D20: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x;
  x = (a1 * a2) * (b1 - b2) / (a2 * b1 - a1 * b2);
  float y;
  y = (b1 * b2) * (a1 - a2) / (a1 * b2 - a2 * b1);
  if ((a1 / a2) == (b1 / b2)) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", x, y);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <prnt@plt>
  mov    $0x0,%eax
  call   <printEqualSign@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <prnt@plt>
  mov    $0x0,%eax
  call   <spaces@plt>
  nop
  leave
  ret
```

assistant: ```c
void printS(const char *s, char *t) {
  prnt(s);
  printEqualSign();
  prnt(t);
  spaces();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printS>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <prnt@plt>
  mov    $0x0,%eax
  call   <printEqualSign@plt>
  mov    %rbx,%rdi
  call   <prnt@plt>
  mov    $0x0,%eax
  call   <spaces@plt>
  pop    %rbx
  ret
```

assistant: ```c
void printS(const char *s, char *t) {
  prnt(s);
  printEqualSign();
  prnt(t);
  spaces();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printS>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <prnt@plt>
  xor    %eax,%eax
  call   <printEqualSign@plt>
  mov    %rbp,%rdi
  call   <prnt@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <spaces@plt>
```

assistant: ```c
void printS(const char *s, char *t) {
  prnt(s);
  printEqualSign();
  prnt(t);
  spaces();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printS>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <prnt@plt>
  xor    %eax,%eax
  call   <printEqualSign@plt>
  mov    %rbp,%rdi
  call   <prnt@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <spaces@plt>
```

assistant: ```c
void printS(const char *s, char *t) {
  prnt(s);
  printEqualSign();
  prnt(t);
  spaces();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_keygen_assist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0xff,%esi
  mov    %eax,%edi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  leave
  ret
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  return _mm_xor_si128(temp1, temp2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_keygen_assist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    $0xff,%esi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,%r12d
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%ebp
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%ebp
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  return _mm_xor_si128(temp1, temp2);
}
```
user: What is the c source code of the assembly code below:

```asm
<aes_keygen_assist>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  mov    $0xff,%esi
  push   %rbp
  call   <_mm_shuffle_epi32@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %eax,%r13d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbp
  mov    %r13d,%esi
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  return _mm_xor_si128(temp1, temp2);
}
```
user: What is the c source code of the assembly code below?

```asm
<aes_keygen_assist>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  mov    $0xff,%esi
  push   %rbp
  call   <_mm_shuffle_epi32@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %eax,%r13d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbp
  mov    %r13d,%esi
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  return _mm_xor_si128(temp1, temp2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arch_execute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    %rdx,(%rcx)
  mov    %rcx,%rsp
  call   *(%rsp)
  mov    %rcx,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rax,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arch_execute(void *sp, void *func, void *arg) {
  asm volatile("movq %2, %%rdi;"
               "movq %1, 0(%0);"
               "movq %0, %%rsp;"
               "call *0(%%rsp);"
               : "+r"(sp), "+r"(func), "+r"(arg)
               :
               : "memory");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arch_execute>:
  endbr64
  mov    %rdx,%rdi
  mov    %rsi,(%rdi)
  mov    %rdi,%rsp
  call   *(%rsp)
  ret
```

assistant: ```c
void arch_execute(void *sp, void *func, void *arg) {
  asm volatile("movq %2, %%rdi;"
               "movq %1, 0(%0);"
               "movq %0, %%rsp;"
               "call *0(%%rsp);"
               : "+r"(sp), "+r"(func), "+r"(arg)
               :
               : "memory");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arch_execute>:
  endbr64
  mov    %rdx,%rdi
  mov    %rsi,(%rdi)
  mov    %rdi,%rsp
  call   *(%rsp)
  ret
```

assistant: ```c
void arch_execute(void *sp, void *func, void *arg) {
  asm volatile("movq %2, %%rdi;"
               "movq %1, 0(%0);"
               "movq %0, %%rsp;"
               "call *0(%%rsp);"
               : "+r"(sp), "+r"(func), "+r"(arg)
               :
               : "memory");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arch_execute>:
  endbr64
  mov    %rdx,%rdi
  mov    %rsi,(%rdi)
  mov    %rdi,%rsp
  call   *(%rsp)
  ret
```

assistant: ```c
void arch_execute(void *sp, void *func, void *arg) {
  asm volatile("movq %2, %%rdi;"
               "movq %1, 0(%0);"
               "movq %0, %%rsp;"
               "call *0(%%rsp);"
               : "+r"(sp), "+r"(func), "+r"(arg)
               :
               : "memory");
}
```