ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  sub    0x8(%rsp),%edi
  mov    $0x2,%esi
  call   <pow@plt>
  movq   %xmm0,%rbx
  mov    0x14(%rsp),%edi
  sub    0x10(%rsp),%edi
  mov    $0x2,%esi
  call   <pow@plt>
  movq   %rbx,%xmm2
  addsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L0
  sqrtsd %xmm0,%xmm0
L9:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <sqrt@plt>
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D2: %i

tool: D13: A DISTANCIA ENTRE A e B = %0.2f


assistant: ```c
int main() {
  int x1, x2, y1, y2;
  scanf("%i", &x1);
  scanf("%i", &y1);
  scanf("%i", &x2);
  scanf("%i", &y2);
  double e1 = pow(x2 - x1, 2);
  double e2 = pow(y2 - y1, 2);
  double d = sqrt(e1 + e2);
  printf("A DISTANCIA ENTRE A e B = %0.2f\n", d);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edi
  mov    $0x2,%esi
  sub    0x18(%rsp),%edi
  call   <pow@plt>
  mov    0x24(%rsp),%edi
  mov    $0x2,%esi
  sub    0x20(%rsp),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L20
  sqrtsd %xmm0,%xmm0
L16:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L20:
  call   <sqrt@plt>
  jmp    L16
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D1: %i

tool: D0: A DISTANCIA ENTRE A e B = %0.2f


assistant: ```c
int main() {
  int x1, x2, y1, y2;
  scanf("%i", &x1);
  scanf("%i", &y1);
  scanf("%i", &x2);
  scanf("%i", &y2);
  double e1 = pow(x2 - x1, 2);
  double e2 = pow(y2 - y1, 2);
  double d = sqrt(e1 + e2);
  printf("A DISTANCIA ENTRE A e B = %0.2f\n", d);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edi
  mov    $0x2,%esi
  sub    0x18(%rsp),%edi
  call   <pow@plt>
  mov    0x24(%rsp),%edi
  mov    $0x2,%esi
  sub    0x20(%rsp),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L23
  sqrtsd %xmm0,%xmm0
L19:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  call   <sqrt@plt>
  jmp    L19
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D12: %i

tool: D9: A DISTANCIA ENTRE A e B = %0.2f


assistant: ```c
int main() {
  int x1, x2, y1, y2;
  scanf("%i", &x1);
  scanf("%i", &y1);
  scanf("%i", &x2);
  scanf("%i", &y2);
  double e1 = pow(x2 - x1, 2);
  double e2 = pow(y2 - y1, 2);
  double d = sqrt(e1 + e2);
  printf("A DISTANCIA ENTRE A e B = %0.2f\n", d);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <assert@plt>
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  xor    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
uint32_t hash(double value) {
  assert(sizeof(double) == 2 * sizeof(uint32_t));
  union u {
    double uValue;
    uint32_t word[2];
  };
  union u valueUnion;
  valueUnion.uValue = value;
  return valueUnion.word[0] ^ valueUnion.word[1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  mov    %rbx,%rdx
  sar    $0x20,%rdx
  xor    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t hash(double value) {
  assert(sizeof(double) == 2 * sizeof(uint32_t));
  union u {
    double uValue;
    uint32_t word[2];
  };
  union u valueUnion;
  valueUnion.uValue = value;
  return valueUnion.word[0] ^ valueUnion.word[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  movq   %xmm0,%rbx
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rax
  pop    %rbx
  sar    $0x20,%rdx
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash(double value) {
  assert(sizeof(double) == 2 * sizeof(uint32_t));
  union u {
    double uValue;
    uint32_t word[2];
  };
  union u valueUnion;
  valueUnion.uValue = value;
  return valueUnion.word[0] ^ valueUnion.word[1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  movq   %xmm0,%rbx
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rax
  pop    %rbx
  sar    $0x20,%rdx
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash(double value) {
  assert(sizeof(double) == 2 * sizeof(uint32_t));
  union u {
    double uValue;
    uint32_t word[2];
  };
  union u valueUnion;
  valueUnion.uValue = value;
  return valueUnion.word[0] ^ valueUnion.word[1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiple_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x80,-0x4(%rbp)
  je     L41
  cmpl   $0x81,-0x4(%rbp)
  je     L48
  jmp    L24
L41:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L48:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L24:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L45:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string

tool: D23: 


tool: D35: SIGKILL


tool: D33: SIGINT : the user interrupted the program with ctrl-c


tool: D26: Unknown signal.


assistant: ```c
void multiple_handler(int signal) {
  printf("\n");
  switch (signal) {
  case SIGKILL:
    printf("SIGKILL\n");
    break;
  case SIGINT:
    printf("SIGINT : the user interrupted the program with ctrl-c\n");
    break;
  default:
    printf("Unknown signal.\n");
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiple_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D33(%rip),%rdi
  call   <printf@plt>
  cmp    $0x80,%ebx
  je     L5
  cmp    $0x81,%ebx
  je     L35
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L5:
  lea    D34(%rip),%rdi
  call   <printf@plt>
L19:
  pop    %rbx
  ret
L35:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: tag: D33
type: string
name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D34
type: string
name: parse_data
arguments: tag: D31
type: string

tool: D33: 


tool: D9: Unknown signal.


tool: D34: SIGKILL


tool: D31: SIGINT : the user interrupted the program with ctrl-c


assistant: ```c
void multiple_handler(int signal) {
  printf("\n");
  switch (signal) {
  case SIGKILL:
    printf("SIGKILL\n");
    break;
  case SIGINT:
    printf("SIGINT : the user interrupted the program with ctrl-c\n");
    break;
  default:
    printf("Unknown signal.\n");
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiple_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  cmp    $0x80,%ebx
  je     L18
  cmp    $0x81,%ebx
  je     L16
  lea    D16(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
L18:
  lea    D24(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
  nopl   (%rax)
L16:
  lea    D28(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D2: 


tool: D16: Unknown signal.


tool: D24: SIGKILL


tool: D28: SIGINT : the user interrupted the program with ctrl-c


assistant: ```c
void multiple_handler(int signal) {
  printf("\n");
  switch (signal) {
  case SIGKILL:
    printf("SIGKILL\n");
    break;
  case SIGINT:
    printf("SIGINT : the user interrupted the program with ctrl-c\n");
    break;
  default:
    printf("Unknown signal.\n");
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiple_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D25(%rip),%rdi
  call   <printf@plt>
  cmp    $0x80,%ebx
  je     L12
  cmp    $0x81,%ebx
  je     L3
  lea    D35(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
L12:
  lea    D12(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
  nopl   (%rax)
L3:
  lea    D34(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D35
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D34
type: string

tool: D25: 


tool: D35: Unknown signal.


tool: D12: SIGKILL


tool: D34: SIGINT : the user interrupted the program with ctrl-c


assistant: ```c
void multiple_handler(int signal) {
  printf("\n");
  switch (signal) {
  case SIGKILL:
    printf("SIGKILL\n");
    break;
  case SIGINT:
    printf("SIGINT : the user interrupted the program with ctrl-c\n");
    break;
  default:
    printf("Unknown signal.\n");
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calculate>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L29
  mov    %rbx,%rdx
  lea    -0x2(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r10
  mov    $0x0,%edi
  mov    $0x1,%r11d
  jmp    L203
L80:
  add    $0x1,%edi
L169:
  add    $0x1,%rdx
  cmp    %r10,%rdx
  je     L28
L203:
  movzbl (%rdx),%esi
  cmp    $0x20,%sil
  je     L80
  movsbl %sil,%r8d
  cmp    $0x72,%sil
  setle  %r9b
  lea    -0x60(%r8),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ecx
  jne    L136
  test   %r9b,%r9b
  jne    L124
L136:
  lea    -0x72(%rsi),%ecx
  cmp    $0x8,%cl
  ja     L133
  mov    %r11,%rax
  shl    %cl,%rax
  test   $0x91,%al
  jne    L124
  test   $0x102,%eax
  jne    L15
L133:
  lea    -0x5e(%r8),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ecx
  jne    L53
  test   %r9b,%r9b
  jne    L163
L53:
  cmp    $0x77,%sil
  je     L163
  cmp    $0x74,%sil
  je     L163
  sub    $0x5f,%r8d
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r8d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%r8d
  jne    L49
  test   %r9b,%r9b
  jne    L141
L49:
  cmp    $0x78,%sil
  je     L141
  cmp    $0x75,%sil
  jne    L169
L141:
  add    $0x2,%edi
  jmp    L169
L124:
  add    $0x3,%edi
  jmp    L169
L15:
  add    $0x4,%edi
  jmp    L169
L163:
  add    $0x1,%edi
  jmp    L169
L29:
  mov    $0x0,%edi
L28:
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int calculate(char *input) {
  int i, l, count = 0;
  int temp;
  l = strlen(input) - 1;
  for (i = 0; i < l; i++) {
    temp = input[i] - ('a' - 1);
    if (input[i] == ' ') {
      count++;
    } else if (((temp % 3 == 0) && (input[i] < 's')) || (input[i] == 'r') || (input[i] == 'v') || (input[i] == 'y')) {
      count += 3;
    } else if (input[i] == 's' || input[i] == 'z') {
      count += 4;
    } else if ((((temp + 2) % 3 == 0) && input[i] < 's') || (input[i] == 't') || (input[i] == 'w')) {
      count += 1;
    } else if ((((temp + 1) % 3 == 0) && input[i] < 's') || (input[i] == 'u') || (input[i] == 'x')) {
      count += 2;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculate>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L172
  sub    $0x2,%eax
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  mov    $0x1,%r11d
  lea    0x1(%rbx,%rax,1),%r10
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L35
  movsbl %al,%esi
  cmp    $0x72,%al
  lea    -0x60(%rsi),%edx
  setle  %r9b
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L109
  test   %r9b,%r9b
  jne    L55
L109:
  lea    -0x72(%rax),%ecx
  cmp    $0x8,%cl
  ja     L4
  mov    %r11,%rdx
  shl    %cl,%rdx
  test   $0x91,%dl
  jne    L55
  test   $0x102,%edx
  jne    L67
L4:
  lea    -0x5e(%rsi),%edx
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L188
  test   %r9b,%r9b
  jne    L35
L188:
  cmp    $0x74,%al
  je     L35
  cmp    $0x77,%al
  je     L35
  lea    -0x5f(%rsi),%edx
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L135
  test   %r9b,%r9b
  jne    L9
L135:
  cmp    $0x78,%al
  je     L9
  cmp    $0x75,%al
  jne    L59
L9:
  add    $0x1,%rdi
  add    $0x2,%r8d
  cmp    %r10,%rdi
  jne    L0
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L35:
  add    $0x1,%r8d
L59:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L0
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L55:
  add    $0x3,%r8d
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L67:
  add    $0x4,%r8d
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L172:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculate(char *input) {
  int i, l, count = 0;
  int temp;
  l = strlen(input) - 1;
  for (i = 0; i < l; i++) {
    temp = input[i] - ('a' - 1);
    if (input[i] == ' ') {
      count++;
    } else if (((temp % 3 == 0) && (input[i] < 's')) || (input[i] == 'r') || (input[i] == 'v') || (input[i] == 'y')) {
      count += 3;
    } else if (input[i] == 's' || input[i] == 'z') {
      count += 4;
    } else if ((((temp + 2) % 3 == 0) && input[i] < 's') || (input[i] == 't') || (input[i] == 'w')) {
      count += 1;
    } else if ((((temp + 1) % 3 == 0) && input[i] < 's') || (input[i] == 'u') || (input[i] == 'x')) {
      count += 2;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calculate>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L42
  sub    $0x2,%eax
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  mov    $0x1,%r11d
  lea    0x1(%rbx,%rax,1),%r10
  nopw   0x0(%rax,%rax,1)
L63:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L4
  movsbl %al,%esi
  cmp    $0x72,%al
  lea    -0x60(%rsi),%edx
  setle  %r9b
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L84
  test   %r9b,%r9b
  jne    L88
L84:
  lea    -0x72(%rax),%ecx
  cmp    $0x8,%cl
  ja     L171
  mov    %r11,%rdx
  shl    %cl,%rdx
  test   $0x91,%dl
  jne    L88
  test   $0x102,%edx
  jne    L77
L171:
  lea    -0x5e(%rsi),%edx
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L23
  test   %r9b,%r9b
  jne    L4
L23:
  cmp    $0x74,%al
  je     L4
  cmp    $0x77,%al
  je     L4
  lea    -0x5f(%rsi),%edx
  imul   $0xaaaaaaab,%edx,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  ja     L114
  test   %r9b,%r9b
  jne    L18
L114:
  cmp    $0x78,%al
  je     L18
  cmp    $0x75,%al
  jne    L10
L18:
  add    $0x1,%rdi
  add    $0x2,%r8d
  cmp    %rdi,%r10
  jne    L63
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L4:
  add    $0x1,%r8d
L10:
  add    $0x1,%rdi
  cmp    %rdi,%r10
  jne    L63
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L88:
  add    $0x3,%r8d
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L77:
  add    $0x4,%r8d
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L42:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int calculate(char *input) {
  int i, l, count = 0;
  int temp;
  l = strlen(input) - 1;
  for (i = 0; i < l; i++) {
    temp = input[i] - ('a' - 1);
    if (input[i] == ' ') {
      count++;
    } else if (((temp % 3 == 0) && (input[i] < 's')) || (input[i] == 'r') || (input[i] == 'v') || (input[i] == 'y')) {
      count += 3;
    } else if (input[i] == 's' || input[i] == 'z') {
      count += 4;
    } else if ((((temp + 2) % 3 == 0) && input[i] < 's') || (input[i] == 't') || (input[i] == 'w')) {
      count += 1;
    } else if ((((temp + 1) % 3 == 0) && input[i] < 's') || (input[i] == 'u') || (input[i] == 'x')) {
      count += 2;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main() {
  void *p;
  void *q = &p;
  void *r = &p;
  p = &q;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  void *p;
  void *q = &p;
  void *r = &p;
  p = &q;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  void *p;
  void *q = &p;
  void *r = &p;
  p = &q;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  void *p;
  void *q = &p;
  void *r = &p;
  p = &q;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pb__get_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L81
  mov    $0x1,%eax
  jmp    L115
L81:
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    $0x2,%eax
  jmp    L115
L28:
  mov    -0x8(%rbp),%rax
  lea    D34(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  mov    $0x3,%eax
  jmp    L115
L1:
  mov    -0x8(%rbp),%rax
  lea    D40(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x4,%eax
  jmp    L115
L32:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    $0x5,%eax
  jmp    L115
L64:
  mov    -0x8(%rbp),%rax
  lea    D45(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L103
  mov    $0x6,%eax
  jmp    L115
L103:
  mov    $0x0,%eax
L115:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D40
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D45
type_infered: string

tool: D6: uInt32

tool: D1: int32

tool: D34: sInt32

tool: D40: float

tool: D14: double

tool: D45: string

assistant: ```c
int pb__get_type(const char *type) {
  if (strcmp(type, "uInt32") == 0)
    return 1;
  if (strcmp(type, "int32") == 0)
    return 2;
  if (strcmp(type, "sInt32") == 0)
    return 3;
  if (strcmp(type, "float") == 0)
    return 4;
  if (strcmp(type, "double") == 0)
    return 5;
  if (strcmp(type, "string") == 0)
    return 6;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pb__get_type>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D25(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L14
L58:
  pop    %rbx
  ret
L14:
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L58
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x3,%eax
  test   %rdx,%rdx
  je     L58
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x4,%eax
  test   %rdx,%rdx
  je     L58
  lea    D45(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x5,%eax
  test   %rdx,%rdx
  je     L58
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  jmp    L58
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
datatype: string
name: extract_symbolic_data
arguments: label: D47
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D45
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D25: uInt32

tool: D47: int32

tool: D13: sInt32

tool: D16: float

tool: D45: double

tool: D3: string

assistant: ```c
int pb__get_type(const char *type) {
  if (strcmp(type, "uInt32") == 0)
    return 1;
  if (strcmp(type, "int32") == 0)
    return 2;
  if (strcmp(type, "sInt32") == 0)
    return 3;
  if (strcmp(type, "float") == 0)
    return 4;
  if (strcmp(type, "double") == 0)
    return 5;
  if (strcmp(type, "string") == 0)
    return 6;
  return 0;
}
```