ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SceltaMatrice@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  SceltaMatrice();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<randomWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <randomize@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L22:
  mov    $0x8,%esi
  mov    $0x2,%edi
  call   <randomInteger@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L36:
  mov    $0x5a,%esi
  mov    $0x41,%edi
  call   <randomInteger@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L36
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L22
  nop
  nop
  leave
  ret
```

assistant: ```c
void randomWord(int times) {
  int letterLenght;
  randomize();
  for (int i = 0; i < times; i++) {
    letterLenght = randomInteger(2, 8);
    for (int j = 0; j < letterLenght; j++) {
      printf("%c", randomInteger('A', 'Z'));
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<randomWord>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    $0x0,%eax
  call   <randomize@plt>
  test   %r13d,%r13d
  jle    L17
  mov    $0x0,%r12d
L15:
  mov    $0x8,%esi
  mov    $0x2,%edi
  call   <randomInteger@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L35
  mov    $0x0,%ebx
L39:
  mov    $0x5a,%esi
  mov    $0x41,%edi
  call   <randomInteger@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L39
L35:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jne    L15
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void randomWord(int times) {
  int letterLenght;
  randomize();
  for (int i = 0; i < times; i++) {
    letterLenght = randomInteger(2, 8);
    for (int j = 0; j < letterLenght; j++) {
      printf("%c", randomInteger('A', 'Z'));
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<randomWord>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <randomize@plt>
  test   %r13d,%r13d
  jle    L38
  xor    %r12d,%r12d
L2:
  mov    $0x8,%esi
  mov    $0x2,%edi
  call   <randomInteger@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L8
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x5a,%esi
  mov    $0x41,%edi
  add    $0x1,%ebx
  call   <randomInteger@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L25
L8:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,%r13d
  jne    L2
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void randomWord(int times) {
  int letterLenght;
  randomize();
  for (int i = 0; i < times; i++) {
    letterLenght = randomInteger(2, 8);
    for (int j = 0; j < letterLenght; j++) {
      printf("%c", randomInteger('A', 'Z'));
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<randomWord>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <randomize@plt>
  test   %r13d,%r13d
  jle    L20
  xor    %r12d,%r12d
L22:
  mov    $0x8,%esi
  mov    $0x2,%edi
  call   <randomInteger@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L24
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0x5a,%esi
  mov    $0x41,%edi
  add    $0x1,%ebx
  call   <randomInteger@plt>
  mov    %eax,%edi
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L30
L24:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r12d,%r13d
  jne    L22
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void randomWord(int times) {
  int letterLenght;
  randomize();
  for (int i = 0; i < times; i++) {
    letterLenght = randomInteger(2, 8);
    for (int j = 0; j < letterLenght; j++) {
      printf("%c", randomInteger('A', 'Z'));
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kb_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <enable_interrupt@plt>
  mov    $0x0,%eax
  call   <update_cursor@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kb_enable(void) {
  enable_interrupt(1);
  update_cursor();
}
```
user: Translate the below assembly code into C programming language:

```asm
<kb_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <enable_interrupt@plt>
  mov    $0x0,%eax
  call   <update_cursor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void kb_enable(void) {
  enable_interrupt(1);
  update_cursor();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kb_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <enable_interrupt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <update_cursor@plt>
```

assistant: ```c
void kb_enable(void) {
  enable_interrupt(1);
  update_cursor();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kb_enable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <enable_interrupt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <update_cursor@plt>
```

assistant: ```c
void kb_enable(void) {
  enable_interrupt(1);
  update_cursor();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x8(%rax,%rax,1),%ebp
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D94(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%ebx
  movd   %ebx,%xmm1
  mulss  D103(%rip),%xmm1
  movss  %xmm1,0xc(%rsp)
  mov    %ebp,%esi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  mulss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D40(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  mulss  D37(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D104(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D52
data_type: string
name: disassemble_data
arguments: label: D57
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D94
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D103
data_type: f32
name: disassemble_data
arguments: label: D56
data_type: string
name: disassemble_data
arguments: label: D40
data_type: string
name: disassemble_data
arguments: label: D37
data_type: byte[4]
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D104
data_type: string

tool: D52: what is the x coordinate of the line?

tool: D57: %d

tool: D7: 
y = %d 


tool: D94: 
What is the radius of the circle?

tool: D2: %f

tool: D103: 3.14

tool: D56: 

The y coordinate = %d 


tool: D40: The area = %.2f 


tool: {"D37": [0xc3,0xf5,0xc8,0x40]}

tool: D18: The circumference = %.2f 


tool: D104: 

	Sultan M.

assistant: ```c
int main() {
  int x;
  int y;
  float area;
  float circumference;
  float radius;
  printf("what is the x coordinate of the line?\n");
  scanf("%d", &x);
  y = 2 * x + 8;
  y = 2;
  y *= x;
  y += 8;
  printf("\ny = %d \n", y);
  printf("\nWhat is the radius of the circle?\n");
  scanf("%f", &radius);
  area = 3.14 * radius * radius;
  area = 3.14;
  area *= radius;
  area *= radius;
  circumference = 2 * 3.14 * radius;
  circumference = 2;
  circumference *= 3.14;
  circumference *= radius;
  printf("\n\nThe y coordinate = %d \n", y);
  printf("The area = %.2f \n", area);
  printf("The circumference = %.2f \n", circumference);
  printf("\n\n\tSultan M.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    D89(%rip),%rdi
  lea    0x8(%rax,%rax,1),%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  lea    D108(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  mov    %ebp,%esi
  xor    %eax,%eax
  movss  D63(%rip),%xmm0
  lea    D45(%rip),%rdi
  movss  %xmm1,0x8(%rsp)
  mulss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x8(%rsp),%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  mulss  D54(%rip),%xmm0
  lea    D81(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D93(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D89
type_guessed: string
name: disassemble_data
arguments: data_tag: D108
type_guessed: string
name: disassemble_data
arguments: data_tag: D74
type_guessed: string
name: disassemble_data
arguments: data_tag: D63
type_guessed: f32
name: disassemble_data
arguments: data_tag: D45
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D54
type_guessed: byte[4]
name: disassemble_data
arguments: data_tag: D81
type_guessed: string
name: disassemble_data
arguments: data_tag: D93
type_guessed: string

tool: D29: what is the x coordinate of the line?

tool: D6: %d

tool: D89: 
y = %d 


tool: D108: 
What is the radius of the circle?

tool: D74: %f

tool: D63: 3.14

tool: D45: 

The y coordinate = %d 


tool: D0: The area = %.2f 


tool: {"D54": [0xc3,0xf5,0xc8,0x40]}

tool: D81: The circumference = %.2f 


tool: D93: 

	Sultan M.

assistant: ```c
int main() {
  int x;
  int y;
  float area;
  float circumference;
  float radius;
  printf("what is the x coordinate of the line?\n");
  scanf("%d", &x);
  y = 2 * x + 8;
  y = 2;
  y *= x;
  y += 8;
  printf("\ny = %d \n", y);
  printf("\nWhat is the radius of the circle?\n");
  scanf("%f", &radius);
  area = 3.14 * radius * radius;
  area = 3.14;
  area *= radius;
  area *= radius;
  circumference = 2 * 3.14 * radius;
  circumference = 2;
  circumference *= 3.14;
  circumference *= radius;
  printf("\n\nThe y coordinate = %d \n", y);
  printf("The area = %.2f \n", area);
  printf("The circumference = %.2f \n", circumference);
  printf("\n\n\tSultan M.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D77(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    D68(%rip),%rdi
  lea    0x8(%rax,%rax,1),%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  mov    %ebp,%esi
  xor    %eax,%eax
  movss  D69(%rip),%xmm0
  lea    D4(%rip),%rdi
  movss  %xmm1,0x8(%rsp)
  mulss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x8(%rsp),%xmm0
  lea    D87(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  mulss  D31(%rip),%xmm0
  lea    D78(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D77
type_guessed: string
name: read_data
arguments: tag: D59
type_guessed: string
name: read_data
arguments: tag: D68
type_guessed: string
name: read_data
arguments: tag: D41
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D69
type_guessed: f32
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D87
type_guessed: string
name: read_data
arguments: tag: D31
type_guessed: byte[4]
name: read_data
arguments: tag: D78
type_guessed: string
name: read_data
arguments: tag: D64
type_guessed: string

tool: D77: what is the x coordinate of the line?

tool: D59: %d

tool: D68: 
y = %d 


tool: D41: 
What is the radius of the circle?

tool: D30: %f

tool: D69: 3.14

tool: D4: 

The y coordinate = %d 


tool: D87: The area = %.2f 


tool: {"D31": [0xc3,0xf5,0xc8,0x40]}

tool: D78: The circumference = %.2f 


tool: D64: 

	Sultan M.

assistant: ```c
int main() {
  int x;
  int y;
  float area;
  float circumference;
  float radius;
  printf("what is the x coordinate of the line?\n");
  scanf("%d", &x);
  y = 2 * x + 8;
  y = 2;
  y *= x;
  y += 8;
  printf("\ny = %d \n", y);
  printf("\nWhat is the radius of the circle?\n");
  scanf("%f", &radius);
  area = 3.14 * radius * radius;
  area = 3.14;
  area *= radius;
  area *= radius;
  circumference = 2 * 3.14 * radius;
  circumference = 2;
  circumference *= 3.14;
  circumference *= radius;
  printf("\n\nThe y coordinate = %d \n", y);
  printf("The area = %.2f \n", area);
  printf("The circumference = %.2f \n", circumference);
  printf("\n\n\tSultan M.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sustitucion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L24
L6:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L29
L34:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L34
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x10(%rbp)
L24:
  cmpl   $0x0,-0x10(%rbp)
  jns    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sustitucion(double **a, double *x, int filas, double *b) {
  int i, j, n;
  float sum;
  n = filas;
  x[n - 1] = b[n - 1] / a[n - 1][n - 1];
  for (i = n - 2; i >= 0; i--) {
    sum = b[i];
    for (j = i + 1; j <= n - 1; j++) {
      sum = sum - a[i][j] * x[j];
    }
    x[i] = sum / a[i][i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sustitucion>:
  endbr64
  mov    %rdi,%r9
  mov    %rcx,%r10
  movslq %edx,%rax
  shl    $0x3,%rax
  mov    -0x8(%rdi,%rax,1),%rcx
  movsd  -0x8(%r10,%rax,1),%xmm0
  divsd  -0x8(%rcx,%rax,1),%xmm0
  movsd  %xmm0,-0x8(%rsi,%rax,1)
  mov    %edx,%eax
  sub    $0x2,%eax
  js     L25
  lea    -0x1(%rdx),%r8d
  cltq
  lea    0x0(,%rax,8),%rdi
L19:
  pxor   %xmm0,%xmm0
  cvtsd2ss (%r10,%rdi,1),%xmm0
  cmp    %r8d,%edx
  jle    L36
  mov    (%r9,%rdi,1),%rcx
  movslq %r8d,%rax
L26:
  cvtss2sd %xmm0,%xmm0
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L26
L36:
  cvtss2sd %xmm0,%xmm0
  mov    (%r9,%rdi,1),%rax
  divsd  (%rax,%rdi,1),%xmm0
  movsd  %xmm0,(%rsi,%rdi,1)
  sub    $0x8,%rdi
  sub    $0x1,%r8d
  jne    L19
L25:
  ret
```

assistant: ```c
void sustitucion(double **a, double *x, int filas, double *b) {
  int i, j, n;
  float sum;
  n = filas;
  x[n - 1] = b[n - 1] / a[n - 1][n - 1];
  for (i = n - 2; i >= 0; i--) {
    sum = b[i];
    for (j = i + 1; j <= n - 1; j++) {
      sum = sum - a[i][j] * x[j];
    }
    x[i] = sum / a[i][i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sustitucion>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rcx,%r10
  mov    %rax,%rsi
  shl    $0x3,%rax
  mov    -0x8(%r8,%rax,1),%rdx
  movsd  -0x8(%rcx,%rax,1),%xmm0
  lea    -0x1(%rsi),%r9d
  divsd  -0x8(%rdx,%rax,1),%xmm0
  movsd  %xmm0,-0x8(%rdi,%rax,1)
  lea    -0x2(%rsi),%eax
  movslq %eax,%rcx
  shl    $0x3,%rcx
  test   %eax,%eax
  js     L6
L13:
  pxor   %xmm0,%xmm0
  mov    (%r8,%rcx,1),%rdx
  cvtsd2ss (%r10,%rcx,1),%xmm0
  cmp    %r9d,%esi
  jle    L38
  movslq %r9d,%rax
  cs nopw 0x0(%rax,%rax,1)
L34:
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  cvtss2sd %xmm0,%xmm0
  add    $0x1,%rax
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    %eax,%esi
  jg     L34
L38:
  cvtss2sd %xmm0,%xmm0
  divsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rdi,%rcx,1)
  sub    $0x8,%rcx
  sub    $0x1,%r9d
  jne    L13
L6:
  ret
```

assistant: ```c
void sustitucion(double **a, double *x, int filas, double *b) {
  int i, j, n;
  float sum;
  n = filas;
  x[n - 1] = b[n - 1] / a[n - 1][n - 1];
  for (i = n - 2; i >= 0; i--) {
    sum = b[i];
    for (j = i + 1; j <= n - 1; j++) {
      sum = sum - a[i][j] * x[j];
    }
    x[i] = sum / a[i][i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sustitucion>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rcx,%r10
  mov    %rax,%rsi
  shl    $0x3,%rax
  mov    -0x8(%r8,%rax,1),%rdx
  movsd  -0x8(%rcx,%rax,1),%xmm0
  lea    -0x1(%rsi),%r9d
  divsd  -0x8(%rdx,%rax,1),%xmm0
  movsd  %xmm0,-0x8(%rdi,%rax,1)
  lea    -0x2(%rsi),%eax
  movslq %eax,%rcx
  shl    $0x3,%rcx
  test   %eax,%eax
  js     L36
L0:
  pxor   %xmm0,%xmm0
  mov    (%r8,%rcx,1),%rdx
  cvtsd2ss (%r10,%rcx,1),%xmm0
  cmp    %r9d,%esi
  jle    L16
  movslq %r9d,%rax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  cvtss2sd %xmm0,%xmm0
  add    $0x1,%rax
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    %eax,%esi
  jg     L4
L16:
  cvtss2sd %xmm0,%xmm0
  divsd  (%rdx,%rcx,1),%xmm0
  movsd  %xmm0,(%rdi,%rcx,1)
  sub    $0x8,%rcx
  sub    $0x1,%r9d
  jne    L0
L36:
  ret
```

assistant: ```c
void sustitucion(double **a, double *x, int filas, double *b) {
  int i, j, n;
  float sum;
  n = filas;
  x[n - 1] = b[n - 1] / a[n - 1][n - 1];
  for (i = n - 2; i >= 0; i--) {
    sum = b[i];
    for (j = i + 1; j <= n - 1; j++) {
      sum = sum - a[i][j] * x[j];
    }
    x[i] = sum / a[i][i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cross(const double *x, const double *y, double *z) {
  z[0] = x[1] * y[2] - x[2] * y[1];
  z[1] = x[2] * y[0] - x[0] * y[2];
  z[2] = x[0] * y[1] - x[1] * y[0];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *x, const double *y, double *z) {
  z[0] = x[1] * y[2] - x[2] * y[1];
  z[1] = x[2] * y[0] - x[0] * y[2];
  z[2] = x[0] * y[1] - x[1] * y[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cross>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross(const double *x, const double *y, double *z) {
  z[0] = x[1] * y[2] - x[2] * y[1];
  z[1] = x[2] * y[0] - x[0] * y[2];
  z[2] = x[0] * y[1] - x[1] * y[0];
}
```