ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ConvertIntTo4ByteChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,-0xb(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %al,-0x9(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *ConvertIntTo4ByteChar(int value) {
  char buf[4];
  buf[0] = value & 0xff;
  buf[1] = (value >> 8) & 0xff;
  buf[2] = (value >> 16) & 0xff;
  buf[3] = (value >> 24) & 0xff;
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ConvertIntTo4ByteChar>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *ConvertIntTo4ByteChar(int value) {
  char buf[4];
  buf[0] = value & 0xff;
  buf[1] = (value >> 8) & 0xff;
  buf[2] = (value >> 16) & 0xff;
  buf[3] = (value >> 24) & 0xff;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ConvertIntTo4ByteChar>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *ConvertIntTo4ByteChar(int value) {
  char buf[4];
  buf[0] = value & 0xff;
  buf[1] = (value >> 8) & 0xff;
  buf[2] = (value >> 16) & 0xff;
  buf[3] = (value >> 24) & 0xff;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usr_warnx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%esi
  mov    -0xd8(%rbp),%rcx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <display_usr@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: WARNING

assistant: ```c
void usr_warnx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_usr("WARNING", lineno, filename, fmt, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usr_warnx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <display_usr@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D9: WARNING

assistant: ```c
void usr_warnx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_usr("WARNING", lineno, filename, fmt, args);
  va_end(args);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usr_warnx>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  call   <display_usr@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: WARNING

assistant: ```c
void usr_warnx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_usr("WARNING", lineno, filename, fmt, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usr_warnx>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  call   <display_usr@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: WARNING

assistant: ```c
void usr_warnx(int lineno, char *filename, char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  display_usr("WARNING", lineno, filename, fmt, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<greet_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x63,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <greet@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <recursive_b@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: %c

assistant: ```c
void greet_b(int i) {
  char c = 'c';
  scanf("%c", &c);
  greet(0);
  recursive_b(i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<greet_b>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x63,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%edi
  call   <greet@plt>
  mov    %ebx,%edi
  call   <recursive_b@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: %c

assistant: ```c
void greet_b(int i) {
  char c = 'c';
  scanf("%c", &c);
  greet(0);
  recursive_b(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<greet_b>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x63,0x7(%rsp)
  call   <scanf@plt>
  xor    %edi,%edi
  call   <greet@plt>
  mov    %ebp,%edi
  call   <recursive_b@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: %c

assistant: ```c
void greet_b(int i) {
  char c = 'c';
  scanf("%c", &c);
  greet(0);
  recursive_b(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<greet_b>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x63,0x7(%rsp)
  call   <scanf@plt>
  xor    %edi,%edi
  call   <greet@plt>
  mov    %ebp,%edi
  call   <recursive_b@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: %c

assistant: ```c
void greet_b(int i) {
  char c = 'c';
  scanf("%c", &c);
  greet(0);
  recursive_b(i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: %x


assistant: ```c
void printHex(uint32_t x) {
  printf("%x\n", x);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printHex>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: %x


assistant: ```c
void printHex(uint32_t x) {
  printf("%x\n", x);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printHex>:
  endbr64
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %x


assistant: ```c
void printHex(uint32_t x) {
  printf("%x\n", x);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printHex>:
  endbr64
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: %x


assistant: ```c
void printHex(uint32_t x) {
  printf("%x\n", x);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xe74,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <calculate_sec@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x28,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void test3(void) {
  int input_sec = 3700;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 40);
}
```
user: What is the c source code of the assembly code below:

```asm
<test3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0xe74,%edi
  call   <calculate_sec@plt>
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x28,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test3(void) {
  int input_sec = 3700;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 40);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test3>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe74,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x28,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test3(void) {
  int input_sec = 3700;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 40);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test3>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xe74,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <calculate_sec@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x28,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test3(void) {
  int input_sec = 3700;
  int sec, min, hr;
  calculate_sec(input_sec, &sec, &min, &hr);
  assert(hr == 1);
  assert(min == 1);
  assert(sec == 40);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<searchInsert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L66:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L93
  mov    -0x4(%rbp),%eax
  jmp    L97
L93:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L63
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L9
L63:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L66
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jg     L38
  mov    -0xc(%rbp),%eax
  jmp    L97
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L74
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  jmp    L97
L74:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
L97:
  pop    %rbp
  ret
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  int left;
  int right;
  int middle;
  left = 0;
  right = numsSize - 1;
  middle = (left + right) / 2;
  while (left < (right - 1)) {
    middle = (left + right) / 2;
    if (nums[middle] == target) {
      return middle;
    } else if (nums[middle] < target) {
      left = middle;
    } else {
      right = middle;
    }
  }
  if (target <= nums[left]) {
    return left;
  }
  if (target > nums[right]) {
    return right + 1;
  }
  return left + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<searchInsert>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edi
  mov    %edx,%esi
  sub    $0x1,%edi
  mov    $0x0,%edx
L27:
  lea    -0x1(%rdi),%r10d
L70:
  cmp    %edx,%r10d
  jle    L79
  lea    (%rdi,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%r8,%rcx,4),%ecx
  cmp    %esi,%ecx
  je     L32
  jge    L5
  mov    %eax,%edx
  jmp    L70
L5:
  mov    %eax,%edi
  jmp    L27
L79:
  movslq %edx,%rax
  mov    %edx,%r9d
  cmp    %esi,(%r8,%rax,4)
  jge    L32
  movslq %edi,%rax
  lea    0x1(%rdx),%r9d
  cmp    %esi,(%r8,%rax,4)
  jl     L4
L32:
  mov    %r9d,%eax
  ret
L4:
  lea    0x1(%rdi),%r9d
  jmp    L32
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  int left;
  int right;
  int middle;
  left = 0;
  right = numsSize - 1;
  middle = (left + right) / 2;
  while (left < (right - 1)) {
    middle = (left + right) / 2;
    if (nums[middle] == target) {
      return middle;
    } else if (nums[middle] < target) {
      left = middle;
    } else {
      right = middle;
    }
  }
  if (target <= nums[left]) {
    return left;
  }
  if (target > nums[right]) {
    return right + 1;
  }
  return left + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<searchInsert>:
  endbr64
  mov    %rdi,%r8
  sub    $0x1,%esi
  xor    %ecx,%ecx
L17:
  lea    -0x1(%rsi),%r10d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L65:
  lea    (%rsi,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %edx,(%r8,%rdi,4)
  je     L61
  jge    L27
  mov    %eax,%ecx
L10:
  cmp    %r10d,%ecx
  jl     L65
  movslq %ecx,%rax
  mov    %ecx,%r9d
  cmp    %edx,(%r8,%rax,4)
  jge    L61
  movslq %esi,%rax
  add    $0x1,%r9d
  cmp    %edx,(%r8,%rax,4)
  jl     L57
L61:
  mov    %r9d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %eax,%esi
  jmp    L17
L57:
  lea    0x1(%rsi),%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  int left;
  int right;
  int middle;
  left = 0;
  right = numsSize - 1;
  middle = (left + right) / 2;
  while (left < (right - 1)) {
    middle = (left + right) / 2;
    if (nums[middle] == target) {
      return middle;
    } else if (nums[middle] < target) {
      left = middle;
    } else {
      right = middle;
    }
  }
  if (target <= nums[left]) {
    return left;
  }
  if (target > nums[right]) {
    return right + 1;
  }
  return left + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<searchInsert>:
  endbr64
  mov    %rdi,%r8
  sub    $0x1,%esi
  xor    %ecx,%ecx
L48:
  lea    -0x1(%rsi),%r10d
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L41:
  lea    (%rsi,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %edx,(%r8,%rdi,4)
  je     L23
  jge    L24
  mov    %eax,%ecx
L64:
  cmp    %r10d,%ecx
  jl     L41
  movslq %ecx,%rax
  mov    %ecx,%r9d
  cmp    %edx,(%r8,%rax,4)
  jge    L23
  movslq %esi,%rax
  add    $0x1,%r9d
  cmp    %edx,(%r8,%rax,4)
  jl     L29
L23:
  mov    %r9d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %eax,%esi
  jmp    L48
L29:
  lea    0x1(%rsi),%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int searchInsert(int *nums, int numsSize, int target) {
  int left;
  int right;
  int middle;
  left = 0;
  right = numsSize - 1;
  middle = (left + right) / 2;
  while (left < (right - 1)) {
    middle = (left + right) / 2;
    if (nums[middle] == target) {
      return middle;
    } else if (nums[middle] < target) {
      left = middle;
    } else {
      right = middle;
    }
  }
  if (target <= nums[left]) {
    return left;
  }
  if (target > nums[right]) {
    return right + 1;
  }
  return left + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ssim_end4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L1
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%r12
  pxor   %xmm2,%xmm2
  movss  %xmm2,0xc(%rsp)
L5:
  mov    0x1c(%rbx),%ecx
  add    0xc(%rbx),%ecx
  add    0xc(%rbp),%ecx
  add    0x1c(%rbp),%ecx
  mov    0x18(%rbx),%edx
  add    0x8(%rbx),%edx
  add    0x8(%rbp),%edx
  add    0x18(%rbp),%edx
  mov    0x14(%rbx),%esi
  add    0x4(%rbx),%esi
  add    0x4(%rbp),%esi
  add    0x14(%rbp),%esi
  mov    0x10(%rbx),%edi
  add    (%rbx),%edi
  add    0x0(%rbp),%edi
  add    0x10(%rbp),%edi
  call   <ssim_end1@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    $0x10,%rbp
  cmp    %r12,%rbx
  jne    L5
L0:
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
  jmp    L0
```

assistant: ```c
float ssim_end4(int sum0[5][4], int sum1[5][4], int width) {
  int i;
  float ssim = 0.0;
  for (i = 0; i < width; i++)
    ssim += ssim_end1(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```
user: What is the c source code of the assembly code below:

```asm
<ssim_end4>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  shl    $0x4,%rax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x10(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0x1c(%rbx),%ecx
  mov    0x18(%rbx),%edx
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    -0x4(%rbx),%ecx
  add    -0x8(%rbx),%edx
  add    $0x10,%rbp
  add    -0x4(%rbp),%ecx
  add    -0x8(%rbp),%edx
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    -0xc(%rbx),%esi
  add    -0x10(%rbx),%edi
  add    -0xc(%rbp),%esi
  add    -0x10(%rbp),%edi
  add    0xc(%rbp),%ecx
  add    0x8(%rbp),%edx
  add    0x4(%rbp),%esi
  add    0x0(%rbp),%edi
  call   <ssim_end1@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbx,%r12
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float ssim_end4(int sum0[5][4], int sum1[5][4], int width) {
  int i;
  float ssim = 0.0;
  for (i = 0; i < width; i++)
    ssim += ssim_end1(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ssim_end4>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  shl    $0x4,%rax
  mov    %rsi,%rbp
  push   %rbx
  lea    0x10(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    0x1c(%rbx),%ecx
  mov    0x18(%rbx),%edx
  movss  %xmm0,0xc(%rsp)
  add    $0x10,%rbx
  add    -0x4(%rbx),%ecx
  add    -0x8(%rbx),%edx
  add    $0x10,%rbp
  add    -0x4(%rbp),%ecx
  add    -0x8(%rbp),%edx
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    -0xc(%rbx),%esi
  add    -0x10(%rbx),%edi
  add    -0xc(%rbp),%esi
  add    -0x10(%rbp),%edi
  add    0xc(%rbp),%ecx
  add    0x8(%rbp),%edx
  add    0x4(%rbp),%esi
  add    0x0(%rbp),%edi
  call   <ssim_end1@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbx,%r12
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float ssim_end4(int sum0[5][4], int sum1[5][4], int width) {
  int i;
  float ssim = 0.0;
  for (i = 0; i < width; i++)
    ssim += ssim_end1(sum0[i][0] + sum0[i + 1][0] + sum1[i][0] + sum1[i + 1][0], sum0[i][1] + sum0[i + 1][1] + sum1[i][1] + sum1[i + 1][1], sum0[i][2] + sum0[i + 1][2] + sum1[i][2] + sum1[i + 1][2], sum0[i][3] + sum0[i + 1][3] + sum1[i][3] + sum1[i + 1][3]);
  return ssim;
}
```