ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<skipcond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    $0x1,%ebx
L74:
  add    $0x1,%rax
  movzbl (%rax),%edx
  movsbl %dl,%edx
  cmp    $0x5c,%edx
  je     L55
  cmp    $0x5c,%edx
  jg     L74
  cmp    $0x3f,%edx
  je     L155
  cmp    $0x3f,%edx
  jg     L74
  cmp    $0x3a,%edx
  je     L135
  cmp    $0x3a,%edx
  jg     L74
  test   %edx,%edx
  je     L110
  cmp    $0x2e,%edx
  je     L27
  jmp    L74
L155:
  add    $0x1,%ebx
  jmp    L144
L135:
  cmp    $0x1,%ebx
  jne    L168
  jmp    L19
L27:
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jne    L16
  jmp    L19
L55:
  add    $0x1,%rax
  jmp    L144
L110:
  sub    $0x1,%rax
  jmp    L19
L168:
  nop
  jmp    L74
L16:
  nop
L144:
  jmp    L74
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
const char *skipcond(p)
register const char *p;
{
  register int iflevel;
  iflevel = 1;
  for (;;)
    switch (*++p) {
    case '?':
      iflevel++;
      break;
    case ':':
      if (iflevel == 1)
        return (p);
      break;
    case '.':
      if (--iflevel == 0)
        return (p);
      break;
    case '\\':
      ++p;
      break;
    case '\0':
      return (p - 1);
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skipcond>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%esi
L41:
  lea    0x1(%rax),%rcx
  movzbl 0x1(%rax),%edx
  cmp    $0x3a,%dl
  je     L29
  jle    L53
  cmp    $0x3f,%dl
  je     L1
  cmp    $0x5c,%dl
  jne    L8
  add    $0x2,%rax
  jmp    L41
L53:
  test   %dl,%dl
  je     L126
  cmp    $0x2e,%dl
  jne    L79
  sub    $0x1,%esi
  je     L94
  mov    %rcx,%rax
  jmp    L41
L79:
  mov    %rcx,%rax
  jmp    L41
L8:
  mov    %rcx,%rax
  jmp    L41
L1:
  add    $0x1,%esi
  mov    %rcx,%rax
  jmp    L41
L29:
  cmp    $0x1,%esi
  je     L107
  mov    %rcx,%rax
  jmp    L41
L107:
  mov    %rcx,%rax
  ret
L94:
  mov    %rcx,%rax
L126:
  ret
```

assistant: ```c
const char *skipcond(p)
register const char *p;
{
  register int iflevel;
  iflevel = 1;
  for (;;)
    switch (*++p) {
    case '?':
      iflevel++;
      break;
    case ':':
      if (iflevel == 1)
        return (p);
      break;
    case '.':
      if (--iflevel == 0)
        return (p);
      break;
    case '\\':
      ++p;
      break;
    case '\0':
      return (p - 1);
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<skipcond>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%esi
L8:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    $0x3a,%dl
  je     L88
L27:
  jg     L70
  test   %dl,%dl
  je     L84
  cmp    $0x2e,%dl
  jne    L5
  sub    $0x1,%esi
  je     L31
L5:
  mov    %rcx,%rax
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    $0x3a,%dl
  jne    L27
L88:
  cmp    $0x1,%esi
  jne    L5
L31:
  mov    %rcx,%rax
L84:
  ret
  nopw   0x0(%rax,%rax,1)
L70:
  cmp    $0x3f,%dl
  je     L73
  cmp    $0x5c,%dl
  jne    L5
  add    $0x2,%rax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%esi
  mov    %rcx,%rax
  jmp    L8
```

assistant: ```c
const char *skipcond(p)
register const char *p;
{
  register int iflevel;
  iflevel = 1;
  for (;;)
    switch (*++p) {
    case '?':
      iflevel++;
      break;
    case ':':
      if (iflevel == 1)
        return (p);
      break;
    case '.':
      if (--iflevel == 0)
        return (p);
      break;
    case '\\':
      ++p;
      break;
    case '\0':
      return (p - 1);
    }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skipcond>:
  endbr64
  mov    %rdi,%rax
  mov    $0x1,%esi
L90:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    $0x3a,%dl
  je     L100
L52:
  jg     L28
  test   %dl,%dl
  je     L29
  cmp    $0x2e,%dl
  jne    L82
  sub    $0x1,%esi
  je     L35
L82:
  mov    %rcx,%rax
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    $0x3a,%dl
  jne    L52
L100:
  cmp    $0x1,%esi
  jne    L82
L35:
  mov    %rcx,%rax
L29:
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    $0x3f,%dl
  je     L18
  cmp    $0x5c,%dl
  jne    L82
  add    $0x2,%rax
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%esi
  mov    %rcx,%rax
  jmp    L90
```

assistant: ```c
const char *skipcond(p)
register const char *p;
{
  register int iflevel;
  iflevel = 1;
  for (;;)
    switch (*++p) {
    case '?':
      iflevel++;
      break;
    case ':':
      if (iflevel == 1)
        return (p);
      break;
    case '.':
      if (--iflevel == 0)
        return (p);
      break;
    case '\\':
      ++p;
      break;
    case '\0':
      return (p - 1);
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<page46>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rcx
  mov    $0x36,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x35,%edi
  call   <choose@plt>
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D8: "Why do you ask about the communists, Troubleshooter?  It is not in the


tool: D0: interest of your continued survival to be asking about such topics," says


tool: D27: The Computer.


tool: D7: You change the subject

tool: D4: You insist on talking about the communists

assistant: ```c
page46() {
  printf("\"Why do you ask about the communists, Troubleshooter?  It is not in the\n");
  printf("interest of your continued survival to be asking about such topics,\" says\n");
  printf("The Computer.\n");
  return choose(53, "You insist on talking about the communists", 54, "You change the subject");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<page46>:
  endbr64
  sub    $0x8,%rsp
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rcx
  mov    $0x36,%edx
  lea    D21(%rip),%rsi
  mov    $0x35,%edi
  call   <choose@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D35
data_type: string
name: retrieve_data
arguments: data_label: D29
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string

tool: D35: "Why do you ask about the communists, Troubleshooter?  It is not in the


tool: D29: interest of your continued survival to be asking about such topics," says


tool: D20: The Computer.


tool: D19: You change the subject

tool: D21: You insist on talking about the communists

assistant: ```c
page46() {
  printf("\"Why do you ask about the communists, Troubleshooter?  It is not in the\n");
  printf("interest of your continued survival to be asking about such topics,\" says\n");
  printf("The Computer.\n");
  return choose(53, "You insist on talking about the communists", 54, "You change the subject");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<page46>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rcx
  mov    $0x36,%edx
  lea    D10(%rip),%rsi
  mov    $0x35,%edi
  add    $0x8,%rsp
  jmp    1060 <choose@plt>
```

tool_calls: name: unpack_data
arguments: tag: D38
datatype: string
name: unpack_data
arguments: tag: D37
datatype: string
name: unpack_data
arguments: tag: D47
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string

tool: D38: "Why do you ask about the communists, Troubleshooter?  It is not in the


tool: D37: interest of your continued survival to be asking about such topics," says


tool: D47: The Computer.


tool: D9: You change the subject

tool: D10: You insist on talking about the communists

assistant: ```c
page46() {
  printf("\"Why do you ask about the communists, Troubleshooter?  It is not in the\n");
  printf("interest of your continued survival to be asking about such topics,\" says\n");
  printf("The Computer.\n");
  return choose(53, "You insist on talking about the communists", 54, "You change the subject");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<page46>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rcx
  mov    $0x36,%edx
  lea    D8(%rip),%rsi
  mov    $0x35,%edi
  add    $0x8,%rsp
  jmp    1060 <choose@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type: string
name: disassemble_data
arguments: data_label: D43
type: string
name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D41
type: string
name: disassemble_data
arguments: data_label: D8
type: string

tool: D21: "Why do you ask about the communists, Troubleshooter?  It is not in the


tool: D43: interest of your continued survival to be asking about such topics," says


tool: D0: The Computer.


tool: D41: You change the subject

tool: D8: You insist on talking about the communists

assistant: ```c
page46() {
  printf("\"Why do you ask about the communists, Troubleshooter?  It is not in the\n");
  printf("interest of your continued survival to be asking about such topics,\" says\n");
  printf("The Computer.\n");
  return choose(53, "You insist on talking about the communists", 54, "You change the subject");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_sq_eng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L8:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  mov    %eax,%edi
  call   <square@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L8
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x20(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float find_sq_eng(short *speech, int x_start, int len) {
  int i;
  float total = 0.0;
  for (i = 0; i < len; i++)
    total += square(speech[x_start + i]);
  total = total / len;
  total = sqrt(total);
  return (total);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_sq_eng>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edx,%r12d
  test   %edx,%edx
  jle    L7
  movslq %esi,%rsi
  lea    (%rdi,%rsi,2),%rbx
  lea    -0x1(%rdx),%eax
  add    %rsi,%rax
  lea    0x2(%rdi,%rax,2),%rbp
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
L22:
  movswl (%rbx),%edi
  call   <square@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x2,%rbx
  cmp    %rbp,%rbx
  jne    L22
L8:
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  jmp    L8
```

assistant: ```c
float find_sq_eng(short *speech, int x_start, int len) {
  int i;
  float total = 0.0;
  for (i = 0; i < len; i++)
    total += square(speech[x_start + i]);
  total = total / len;
  total = sqrt(total);
  return (total);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_sq_eng>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L17
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  add    %rsi,%rax
  lea    (%rdi,%rsi,2),%rbx
  lea    0x2(%rdi,%rax,2),%rbp
  nopl   0x0(%rax)
L11:
  movswl (%rbx),%edi
  movss  %xmm0,0xc(%rsp)
  add    $0x2,%rbx
  call   <square@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbp,%rbx
  jne    L11
L14:
  pxor   %xmm1,%xmm1
  add    $0x10,%rsp
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm1,%xmm0
  jmp    1060 <sqrt@plt>
  nopl   0x0(%rax)
L17:
  pxor   %xmm0,%xmm0
  jmp    L14
```

assistant: ```c
float find_sq_eng(short *speech, int x_start, int len) {
  int i;
  float total = 0.0;
  for (i = 0; i < len; i++)
    total += square(speech[x_start + i]);
  total = total / len;
  total = sqrt(total);
  return (total);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<find_sq_eng>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L0
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  add    %rsi,%rax
  lea    (%rdi,%rsi,2),%rbx
  lea    0x2(%rdi,%rax,2),%rbp
  nopl   0x0(%rax)
L1:
  movswl (%rbx),%edi
  movss  %xmm0,0xc(%rsp)
  add    $0x2,%rbx
  call   <square@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbp,%rbx
  jne    L1
L20:
  pxor   %xmm1,%xmm1
  add    $0x10,%rsp
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm1,%xmm0
  jmp    1060 <sqrt@plt>
  nopl   0x0(%rax)
L0:
  pxor   %xmm0,%xmm0
  jmp    L20
```

assistant: ```c
float find_sq_eng(short *speech, int x_start, int len) {
  int i;
  float total = 0.0;
  for (i = 0; i < len; i++)
    total += square(speech[x_start + i]);
  total = total / len;
  total = sqrt(total);
  return (total);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sock_writev@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int sock_write(int s, void *buf, size_t size) {
  struct iovec iov;
  int ret;
  iov.iov_base = buf;
  iov.iov_len = size;
  ret = sock_writev(s, &iov, 1);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_write>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edx
  call   <sock_writev@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_write(int s, void *buf, size_t size) {
  struct iovec iov;
  int ret;
  iov.iov_base = buf;
  iov.iov_len = size;
  ret = sock_writev(s, &iov, 1);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_write>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    %rdx,(%rsp)
  mov    $0x1,%edx
  call   <sock_writev@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_write(int s, void *buf, size_t size) {
  struct iovec iov;
  int ret;
  iov.iov_base = buf;
  iov.iov_len = size;
  ret = sock_writev(s, &iov, 1);
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sock_write>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    %rdx,(%rsp)
  mov    $0x1,%edx
  call   <sock_writev@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_write(int s, void *buf, size_t size) {
  struct iovec iov;
  int ret;
  iov.iov_base = buf;
  iov.iov_len = size;
  ret = sock_writev(s, &iov, 1);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<preprocLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <preprocVars@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <preprocBackticks@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <preprocAutospace@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *preprocLine(char *line) {
  line = preprocVars(line);
  line = preprocBackticks(line);
  line = preprocAutospace(line);
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<preprocLine>:
  endbr64
  sub    $0x8,%rsp
  call   <preprocVars@plt>
  mov    %rax,%rdi
  call   <preprocBackticks@plt>
  mov    %rax,%rdi
  call   <preprocAutospace@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *preprocLine(char *line) {
  line = preprocVars(line);
  line = preprocBackticks(line);
  line = preprocAutospace(line);
  return line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<preprocLine>:
  endbr64
  sub    $0x8,%rsp
  call   <preprocVars@plt>
  mov    %rax,%rdi
  call   <preprocBackticks@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1090 <preprocAutospace@plt>
```

assistant: ```c
char *preprocLine(char *line) {
  line = preprocVars(line);
  line = preprocBackticks(line);
  line = preprocAutospace(line);
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<preprocLine>:
  endbr64
  sub    $0x8,%rsp
  call   <preprocVars@plt>
  mov    %rax,%rdi
  call   <preprocBackticks@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1090 <preprocAutospace@plt>
```

assistant: ```c
char *preprocLine(char *line) {
  line = preprocVars(line);
  line = preprocBackticks(line);
  line = preprocAutospace(line);
  return line;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transfer_YUVA16161616_to_VYU888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0xffff,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff80008001,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x17,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  shl    $0xf,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff80008001,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x17,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  shl    $0xf,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff80008001,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x17,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUVA16161616_to_VYU888(unsigned char *(*output), uint16_t *input) {
  int y, u, v, a, anti_a;
  a = input[3];
  anti_a = 0xffff - a;
  y = ((uint32_t)input[0] * a) / 0xffff00;
  u = ((uint32_t)input[1] * a + 0x8000 * anti_a) / 0xffff00;
  v = ((uint32_t)input[2] * a + 0x8000 * anti_a) / 0xffff00;
  *(*output)++ = v;
  *(*output)++ = y;
  *(*output)++ = u;
}
```
user: What is the c source code of the assembly code below?

```asm
<transfer_YUVA16161616_to_VYU888>:
  endbr64
  mov    %rsi,%rcx
  mov    0xc(%rsi),%eax
  mov    %eax,%edx
  imul   (%rsi),%edx
  movslq %edx,%rsi
  imul   $0xffffffff80008001,%rsi,%rsi
  shr    $0x20,%rsi
  add    %edx,%esi
  sar    $0x17,%esi
  sar    $0x1f,%edx
  sub    %edx,%esi
  mov    $0xffff,%r9d
  sub    %eax,%r9d
  shl    $0xf,%r9d
  mov    %eax,%r8d
  imul   0x4(%rcx),%r8d
  add    %r9d,%r8d
  movslq %r8d,%rdx
  imul   $0xffffffff80008001,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r8d,%edx
  sar    $0x17,%edx
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  imul   0x8(%rcx),%eax
  add    %r9d,%eax
  movslq %eax,%rcx
  imul   $0xffffffff80008001,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x17,%ecx
  sar    $0x1f,%eax
  sub    %eax,%ecx
  mov    (%rdi),%rax
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  mov    %cl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %sil,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void transfer_YUVA16161616_to_VYU888(unsigned char *(*output), uint16_t *input) {
  int y, u, v, a, anti_a;
  a = input[3];
  anti_a = 0xffff - a;
  y = ((uint32_t)input[0] * a) / 0xffff00;
  u = ((uint32_t)input[1] * a + 0x8000 * anti_a) / 0xffff00;
  v = ((uint32_t)input[2] * a + 0x8000 * anti_a) / 0xffff00;
  *(*output)++ = v;
  *(*output)++ = y;
  *(*output)++ = u;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transfer_YUVA16161616_to_VYU888>:
  endbr64
  mov    0xc(%rsi),%eax
  mov    (%rsi),%edx
  mov    %rsi,%rcx
  mov    $0xffff,%r9d
  mov    0x4(%rcx),%r8d
  imul   %eax,%edx
  sub    %eax,%r9d
  imul   %eax,%r8d
  shl    $0xf,%r9d
  imul   0x8(%rcx),%eax
  movslq %edx,%rsi
  imul   $0xffffffff80008001,%rsi,%rsi
  add    %r9d,%r8d
  add    %r9d,%eax
  movslq %eax,%rcx
  shr    $0x20,%rsi
  imul   $0xffffffff80008001,%rcx,%rcx
  add    %edx,%esi
  sar    $0x1f,%edx
  sar    $0x17,%esi
  sub    %edx,%esi
  movslq %r8d,%rdx
  shr    $0x20,%rcx
  imul   $0xffffffff80008001,%rdx,%rdx
  add    %eax,%ecx
  sar    $0x1f,%eax
  sar    $0x17,%ecx
  sub    %eax,%ecx
  mov    (%rdi),%rax
  shr    $0x20,%rdx
  add    %r8d,%edx
  sar    $0x1f,%r8d
  sar    $0x17,%edx
  sub    %r8d,%edx
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  mov    %cl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %sil,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void transfer_YUVA16161616_to_VYU888(unsigned char *(*output), uint16_t *input) {
  int y, u, v, a, anti_a;
  a = input[3];
  anti_a = 0xffff - a;
  y = ((uint32_t)input[0] * a) / 0xffff00;
  u = ((uint32_t)input[1] * a + 0x8000 * anti_a) / 0xffff00;
  v = ((uint32_t)input[2] * a + 0x8000 * anti_a) / 0xffff00;
  *(*output)++ = v;
  *(*output)++ = y;
  *(*output)++ = u;
}
```