ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L4
  jle    L40
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D7(%rip),%r14
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L69:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L40
L12:
  mov    (%rbx),%r12
  mov    %r12,%rdi
  call   <remove@plt>
  cmp    $0xffffffff,%eax
  jne    L69
  mov    0x0(%r13),%rdx
  mov    %rsp,%r15
  mov    %r12,%rcx
  mov    %r14,%rsi
  mov    %r15,%rdi
  add    $0x8,%rbx
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <perror@plt>
  cmp    %rbp,%rbx
  jne    L12
  nop
L40:
  xor    %eax,%eax
L30:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L30
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D7: %s: cannot remove '%s'

tool: D0: %s: missing operand


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *file;
  int ret;
  char sbuf[256];
  if (1 == argc) {
    printf("%s: missing operand\n", argv[0]);
    return 1;
  }
  for (i = 1; i < argc; i++) {
    file = argv[i];
    ret = remove(file);
    if (-1 == ret) {
      sprintf(sbuf, "%s: cannot remove '%s'", argv[0], file);
      perror(sbuf);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L28
  jle    L67
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D6(%rip),%r14
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L67
L25:
  mov    (%rbx),%r12
  mov    %r12,%rdi
  call   <remove@plt>
  cmp    $0xffffffff,%eax
  jne    L40
  mov    0x0(%r13),%rdx
  mov    %rsp,%r15
  mov    %r12,%rcx
  mov    %r14,%rsi
  mov    %r15,%rdi
  add    $0x8,%rbx
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <perror@plt>
  cmp    %rbp,%rbx
  jne    L25
  nop
L67:
  xor    %eax,%eax
L3:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L3
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D6: %s: cannot remove '%s'

tool: D1: %s: missing operand


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *file;
  int ret;
  char sbuf[256];
  if (1 == argc) {
    printf("%s: missing operand\n", argv[0]);
    return 1;
  }
  for (i = 1; i < argc; i++) {
    file = argv[i];
    ret = remove(file);
    if (-1 == ret) {
      sprintf(sbuf, "%s: cannot remove '%s'", argv[0], file);
      perror(sbuf);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<dissect_opt_hop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L7
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <tprintf@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: , Option(s) recognized 

assistant: ```c
void dissect_opt_hop(struct pkt_buff *pkt __attribute__((__unused__)), ssize_t *opt_len) {
  if (*opt_len)
    tprintf(", Option(s) recognized ");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dissect_opt_hop>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <tprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: , Option(s) recognized 

assistant: ```c
void dissect_opt_hop(struct pkt_buff *pkt __attribute__((__unused__)), ssize_t *opt_len) {
  if (*opt_len)
    tprintf(", Option(s) recognized ");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dissect_opt_hop>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D9(%rip),%rdi
  jmp    1050 <tprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: , Option(s) recognized 

assistant: ```c
void dissect_opt_hop(struct pkt_buff *pkt __attribute__((__unused__)), ssize_t *opt_len) {
  if (*opt_len)
    tprintf(", Option(s) recognized ");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dissect_opt_hop>:
  endbr64
  cmpq   $0x0,(%rsi)
  jne    L5
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  lea    D9(%rip),%rdi
  jmp    1050 <tprintf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: , Option(s) recognized 

assistant: ```c
void dissect_opt_hop(struct pkt_buff *pkt __attribute__((__unused__)), ssize_t *opt_len) {
  if (*opt_len)
    tprintf(", Option(s) recognized ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_processing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0xffffffff,-0x124(%rbp)
  je     L12
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
L17:
  lea    -0x110(%rbp),%rcx
  mov    -0x124(%rbp),%eax
  mov    $0xff,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recv_socket@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0x0,-0x114(%rbp)
  js     L7
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rcx
  mov    -0x124(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <send_socket@plt>
  jmp    L17
L7:
  nop
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void do_processing(int sockfd) {
  if (sockfd != -1) {
    int read;
    char buffer[256] = {0};
    while (1) {
      if ((read = recv_socket(sockfd, buffer, 255)) >= 0) {
        send_socket(sockfd, buffer, read);
      } else {
        break;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_processing>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  je     L21
  mov    %edi,%ebx
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  mov    %rsp,%rbp
  jmp    L11
L8:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_socket@plt>
L11:
  mov    $0xff,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recv_socket@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L8
L21:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_processing(int sockfd) {
  if (sockfd != -1) {
    int read;
    char buffer[256] = {0};
    while (1) {
      if ((read = recv_socket(sockfd, buffer, 255)) >= 0) {
        send_socket(sockfd, buffer, read);
      } else {
        break;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_processing>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  je     L0
  pxor   %xmm0,%xmm0
  mov    %edi,%ebx
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_socket@plt>
L1:
  mov    $0xff,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recv_socket@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L37
L0:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_processing(int sockfd) {
  if (sockfd != -1) {
    int read;
    char buffer[256] = {0};
    while (1) {
      if ((read = recv_socket(sockfd, buffer, 255)) >= 0) {
        send_socket(sockfd, buffer, read);
      } else {
        break;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_processing>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  je     L14
  pxor   %xmm0,%xmm0
  mov    %edi,%ebx
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_socket@plt>
L5:
  mov    $0xff,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recv_socket@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L29
L14:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_processing(int sockfd) {
  if (sockfd != -1) {
    int read;
    char buffer[256] = {0};
    while (1) {
      if ((read = recv_socket(sockfd, buffer, 255)) >= 0) {
        send_socket(sockfd, buffer, read);
      } else {
        break;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<softmax_x_ent_cpu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L7
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  je     L5
L7:
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <log@plt>
  movd   %xmm0,%eax
  movss  D3(%rip),%xmm0
  movd   %eax,%xmm1
  xorps  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  jmp    L36
L5:
  pxor   %xmm0,%xmm0
L36:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  -0x8(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x80]}

assistant: ```c
void softmax_x_ent_cpu(int n, float *pred, float *truth, float *delta, float *error) {
  int i;
  for (i = 0; i < n; ++i) {
    float t = truth[i];
    float p = pred[i];
    error[i] = (t) ? -log(p) : 0;
    delta[i] = t - p;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<softmax_x_ent_cpu>:
  endbr64
  test   %edi,%edi
  jle    L58
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %edi,%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%ebx
  jmp    L42
L0:
  movss  0x4(%rsp),%xmm0
  call   <log@plt>
  xorps  D3(%rip),%xmm0
L37:
  movss  %xmm0,(%r15,%rbx,4)
  movd   %ebp,%xmm0
  subss  0x4(%rsp),%xmm0
  movss  %xmm0,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  je     L20
L42:
  mov    0x0(%r13,%rbx,4),%ebp
  movss  (%r12,%rbx,4),%xmm1
  movss  %xmm1,0x4(%rsp)
  movd   %ebp,%xmm2
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L0
  movaps %xmm3,%xmm0
  je     L37
  jmp    L0
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void softmax_x_ent_cpu(int n, float *pred, float *truth, float *delta, float *error) {
  int i;
  for (i = 0; i < n; ++i) {
    float t = truth[i];
    float p = pred[i];
    error[i] = (t) ? -log(p) : 0;
    delta[i] = t - p;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<softmax_x_ent_cpu>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r15
  pxor   %xmm3,%xmm3
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  jmp    L28
  nopl   0x0(%rax)
L47:
  subss  %xmm2,%xmm1
  movss  %xmm0,(%r15,%rbx,4)
  movss  %xmm1,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L23
L28:
  movss  0x0(%r13,%rbx,4),%xmm1
  movss  (%r12,%rbx,4),%xmm2
  ucomiss %xmm3,%xmm1
  jp     L51
  movaps %xmm3,%xmm0
  je     L47
L51:
  movaps %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <log@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  xorps  D7(%rip),%xmm0
  movss  0x8(%rsp),%xmm2
  jmp    L47
  nopl   (%rax)
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void softmax_x_ent_cpu(int n, float *pred, float *truth, float *delta, float *error) {
  int i;
  for (i = 0; i < n; ++i) {
    float t = truth[i];
    float p = pred[i];
    error[i] = (t) ? -log(p) : 0;
    delta[i] = t - p;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<softmax_x_ent_cpu>:
  endbr64
  test   %edi,%edi
  jle    L41
  push   %r15
  pxor   %xmm3,%xmm3
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nop
L37:
  movss  0x0(%r13,%rbx,4),%xmm1
  movss  (%r12,%rbx,4),%xmm2
  ucomiss %xmm3,%xmm1
  jp     L12
  jne    L12
  subss  %xmm2,%xmm1
  movl   $0x0,(%r15,%rbx,4)
  movss  %xmm1,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L12:
  movaps %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <log@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  xorps  D3(%rip),%xmm0
  subss  %xmm2,%xmm1
  movss  %xmm0,(%r15,%rbx,4)
  movss  %xmm1,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void softmax_x_ent_cpu(int n, float *pred, float *truth, float *delta, float *error) {
  int i;
  for (i = 0; i < n; ++i) {
    float t = truth[i];
    float p = pred[i];
    error[i] = (t) ? -log(p) : 0;
    delta[i] = t - p;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: Hello world again

assistant: ```c
int main() {
  puts("Hello world again");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: Hello world again

assistant: ```c
int main() {
  puts("Hello world again");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: Hello world again

assistant: ```c
int main() {
  puts("Hello world again");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: Hello world again

assistant: ```c
int main() {
  puts("Hello world again");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x1c(%rbp),%edx
  mov    %edx,%ecx
  sub    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuffle(int *data, int len) {
  for (int i = 0; i < len - 1; ++i) {
    int k = (rand() % (len - i)) + i;
    int t = data[k];
    data[k] = data[i];
    data[i] = t;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    -0x2(%rsi),%r13d
  mov    $0x0,%ebx
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r12d,%ecx
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rax),%edx
  mov    0x0(%rbp,%rbx,4),%ecx
  mov    %ecx,(%rax)
  mov    %edx,0x0(%rbp,%rbx,4)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r13,%rax
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void shuffle(int *data, int len) {
  for (int i = 0; i < len - 1; ++i) {
    int k = (rand() % (len - i)) + i;
    int t = data[k];
    data[k] = data[i];
    data[i] = t;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x2(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%ecx
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  mov    0x0(%r13,%rbx,4),%ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %rbx,%rax
  mov    %edx,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %r12,%rax
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
void shuffle(int *data, int len) {
  for (int i = 0; i < len - 1; ++i) {
    int k = (rand() % (len - i)) + i;
    int t = data[k];
    data[k] = data[i];
    data[i] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shuffle>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x2(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %ebp,%ecx
  sub    %ebx,%ecx
  cltd
  idiv   %ecx
  mov    0x0(%r13,%rbx,4),%ecx
  add    %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %ecx,(%rax)
  mov    %rbx,%rax
  mov    %edx,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %r12,%rax
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void shuffle(int *data, int len) {
  for (int i = 0; i < len - 1; ++i) {
    int k = (rand() % (len - i)) + i;
    int t = data[k];
    data[k] = data[i];
    data[i] = t;
  }
}
```