user: 这段汇编代码用C语言表示是什么样的：

```asm
<hex_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L45:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %dl,-0x10(%rbp,%rax,1)
  addl   $0x1,-0x1c(%rbp)
L8:
  cmpl   $0x6,-0x1c(%rbp)
  jle    L45
  movl   $0x0,-0x18(%rbp)
  jmp    L89
L41:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cmp    $0x5,%eax
  ja     L81
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D56(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D56(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xa,-0x10(%rbp,%rax,1)
  jmp    L81
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xb,-0x10(%rbp,%rax,1)
  jmp    L81
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xc,-0x10(%rbp,%rax,1)
  jmp    L81
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xd,-0x10(%rbp,%rax,1)
  jmp    L81
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xe,-0x10(%rbp,%rax,1)
  jmp    L81
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0xf,-0x10(%rbp,%rax,1)
  nop
L81:
  addl   $0x1,-0x18(%rbp)
L89:
  cmpl   $0x6,-0x18(%rbp)
  jle    L41
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl -0x10(%rbp),%eax
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0xf(%rbp),%eax
  movsbl %al,%eax
  or     %edx,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x14(%rbp)
  jmp    L40
L98:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  movsbl %al,%eax
  or     %edx,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0x14(%rbp)
L40:
  cmpl   $0x5,-0x14(%rbp)
  jle    L98
  mov    $0x29,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D52
datatype: string
name: unpack_data
arguments: data_label: D48
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D32
datatype: string

tool: D52: %8s

tool: D48: rbg(

tool: D7: %d

tool: D32: , %d

assistant: ```c
int hex_dec() {
  char a[8];
  scanf("%8s", a);
  for (int i = 0; i < 7; ++i) {
    a[i] = a[i + 1];
  }
  for (int i = 0; i < 7; ++i) {
    switch (a[i]) {
    case 'a':
      a[i] = 10;
      break;
    case 'b':
      a[i] = 11;
      break;
    case 'c':
      a[i] = 12;
      break;
    case 'd':
      a[i] = 13;
      break;
    case 'e':
      a[i] = 14;
      break;
    case 'f':
      a[i] = 15;
      break;
    }
  }
  printf("rbg(");
  printf("%d", (a[0] << 4) | a[0 + 1]);
  for (int i = 2; i < 6; i = i + 2) {
    printf(", %d", (a[i] << 4) | a[i + 1]);
  }
  printf(")");
  return 0;
}
```