ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<depth>:
  endbr64
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D28(%rip),%rbx
  jmp    L49
  nopl   0x0(%rax)
L18:
  add    $0x2,%rbp
L56:
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <strspn@plt>
  cltq
  add    %rax,%rbp
L49:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L18
  mov    $0x3,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L28
  add    $0x3,%rbp
  sub    $0x1,%r12d
  jae    L56
L50:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  mov    %rbp,%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L50
  add    $0x1,%r12d
  jmp    L56
```

tool_calls: name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string

tool: D14: ../

tool: D17: /

tool: D28: ./

assistant: ```c
int depth(const char *path) {
  int n = 0;
  for (;;) {
    if (strncmp(path, "./", 2) == 0)
      path += 2;
    else if (strncmp(path, "../", 3) == 0) {
      path += 3;
      if (--n < 0)
        return n;
    } else if ((path = strchr(path, '/')))
      ++n;
    else
      return n;
    path = path + strspn(path, "/");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  cmpl   $0x0,-0x8(%rbp)
  je     L11
  mov    $0x1,%eax
  jmp    L0
L11:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int and (int a, int b) {
  if (a && b) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<and>:
  endbr64
  test   %edi,%edi
  setne  %dl
  test   %esi,%esi
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int and (int a, int b) {
  if (a && b) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<and>:
  endbr64
  test   %edi,%edi
  setne  %dl
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int and (int a, int b) {
  if (a && b) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<and>:
  endbr64
  test   %edi,%edi
  setne  %dl
  xor    %eax,%eax
  test   %esi,%esi
  setne  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int and (int a, int b) {
  if (a && b) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stdimpl_lltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jne    L6
  cmpq   $0x0,-0x8(%rbp)
  jns    L6
  mov    -0x8(%rbp),%rax
  neg    %rax
  mov    %rax,%rdi
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rsi
  call   <_xtoa@plt>
  jmp    L13
L6:
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <_xtoa@plt>
L13:
  leave
  ret
```

assistant: ```c
char *stdimpl_lltoa(long long v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdimpl_lltoa>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xa,%edx
  jne    L4
  test   %rdi,%rdi
  jns    L4
  neg    %rdi
  mov    $0x1,%ecx
  call   <_xtoa@plt>
  jmp    L28
L4:
  mov    $0x0,%ecx
  call   <_xtoa@plt>
L28:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *stdimpl_lltoa(long long v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stdimpl_lltoa>:
  endbr64
  cmp    $0xa,%edx
  jne    L19
  test   %rdi,%rdi
  jns    L19
  neg    %rdi
  mov    $0x1,%ecx
  jmp    1050 <_xtoa@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %ecx,%ecx
  jmp    1050 <_xtoa@plt>
```

assistant: ```c
char *stdimpl_lltoa(long long v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdimpl_lltoa>:
  endbr64
  cmp    $0xa,%edx
  jne    L9
  test   %rdi,%rdi
  jns    L9
  neg    %rdi
  mov    $0x1,%ecx
  jmp    1050 <_xtoa@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %ecx,%ecx
  jmp    1050 <_xtoa@plt>
```

assistant: ```c
char *stdimpl_lltoa(long long v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xilinxcorelib_a_2032562814_3212880686_p_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x898,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x6078,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast@plt>
  mov    -0x48(%rbp),%rax
  add    $0x5f28,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void xilinxcorelib_a_2032562814_3212880686_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 2200U);
  t2 = *((char **)t1);
  t1 = (t0 + 24696);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 1U);
  xsi_driver_first_trans_fast(t1);
LAB2:
  t7 = (t0 + 24360);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xilinxcorelib_a_2032562814_3212880686_p_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x898(%rdi),%rsi
  mov    0x60b0(%rdi),%rax
  mov    0x38(%rax),%rdi
  mov    $0x1,%edx
  call   <memcpy@plt>
  lea    0x6078(%rbx),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5f28(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2032562814_3212880686_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 2200U);
  t2 = *((char **)t1);
  t1 = (t0 + 24696);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 1U);
  xsi_driver_first_trans_fast(t1);
LAB2:
  t7 = (t0 + 24360);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xilinxcorelib_a_2032562814_3212880686_p_3>:
  endbr64
  push   %rbx
  mov    0x60b0(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x1,%edx
  mov    0x898(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x6078(%rbx),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5f28(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2032562814_3212880686_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 2200U);
  t2 = *((char **)t1);
  t1 = (t0 + 24696);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 1U);
  xsi_driver_first_trans_fast(t1);
LAB2:
  t7 = (t0 + 24360);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xilinxcorelib_a_2032562814_3212880686_p_3>:
  endbr64
  push   %rbx
  mov    0x60b0(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x1,%edx
  mov    0x898(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x6078(%rbx),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x5f28(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2032562814_3212880686_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 2200U);
  t2 = *((char **)t1);
  t1 = (t0 + 24696);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 1U);
  xsi_driver_first_trans_fast(t1);
LAB2:
  t7 = (t0 + 24360);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jle    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: %d 	

assistant: ```c
int main(void) {
  int counter = 1;
  do {
    printf("%d \t", counter);
  } while (++counter <= 10);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D7(%rip),%rbp
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: %d 	

assistant: ```c
int main(void) {
  int counter = 1;
  do {
    printf("%d \t", counter);
  } while (++counter <= 10);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: %d 	

assistant: ```c
int main(void) {
  int counter = 1;
  do {
    printf("%d \t", counter);
  } while (++counter <= 10);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d 	

assistant: ```c
int main(void) {
  int counter = 1;
  do {
    printf("%d \t", counter);
  } while (++counter <= 10);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calcplot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rdx
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <calcplot1@plt>
  mov    -0x30(%rbp),%rdx
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <calcplot1@plt>
  mov    -0x38(%rbp),%rdx
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <calcplot1@plt>
  mov    -0x38(%rbp),%rdx
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rdi
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <calcplotp@plt>
  nop
  leave
  ret
```

assistant: ```c
void calcplot(double x, double y, double dx, double dy, double *r, double *g, double *b) {
  calcplot1(x, y, r, 1 / 64.0);
  calcplot1(x, y, g, 1 / 512.0);
  calcplot1(x, y, b, 1 / 4096.0);
  calcplotp(x, y, dx, dy, b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calcplot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movq   %xmm2,%r13
  movq   %xmm3,%r14
  mov    %rsi,%r15
  mov    %rdx,%r12
  mov    $0x0,%esi
  call   <calcplot1@plt>
  mov    $0x0,%esi
  mov    %r15,%rdi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <calcplot1@plt>
  mov    $0x0,%esi
  mov    %r12,%rdi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <calcplot1@plt>
  mov    %r12,%rdi
  movq   %r14,%xmm3
  movq   %r13,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <calcplotp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void calcplot(double x, double y, double dx, double dy, double *r, double *g, double *b) {
  calcplot1(x, y, r, 1 / 64.0);
  calcplot1(x, y, g, 1 / 512.0);
  calcplot1(x, y, b, 1 / 4096.0);
  calcplotp(x, y, dx, dy, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calcplot>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x28,%rsp
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <calcplot1@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rdi
  xor    %esi,%esi
  movsd  (%rsp),%xmm0
  call   <calcplot1@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbp,%rdi
  xor    %esi,%esi
  movsd  (%rsp),%xmm0
  call   <calcplot1@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  mov    %rbp,%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  jmp    1060 <calcplotp@plt>
```

assistant: ```c
void calcplot(double x, double y, double dx, double dy, double *r, double *g, double *b) {
  calcplot1(x, y, r, 1 / 64.0);
  calcplot1(x, y, g, 1 / 512.0);
  calcplot1(x, y, b, 1 / 4096.0);
  calcplotp(x, y, dx, dy, b);
}
```
user: What is the c source code of the assembly code below:

```asm
<calcplot>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x28,%rsp
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <calcplot1@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rdi
  xor    %esi,%esi
  movsd  (%rsp),%xmm0
  call   <calcplot1@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbp,%rdi
  xor    %esi,%esi
  movsd  (%rsp),%xmm0
  call   <calcplot1@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  mov    %rbp,%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  jmp    1060 <calcplotp@plt>
```

assistant: ```c
void calcplot(double x, double y, double dx, double dy, double *r, double *g, double *b) {
  calcplot1(x, y, r, 1 / 64.0);
  calcplot1(x, y, g, 1 / 512.0);
  calcplot1(x, y, b, 1 / 4096.0);
  calcplotp(x, y, dx, dy, b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remove_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x2c(%rbp)
  mov    %al,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L59
  mov    $0x0,%eax
  jmp    L97
L59:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L75
  mov    $0x0,%eax
  jmp    L97
L75:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbl -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpb   $0x0,-0x30(%rbp)
  je     L96
  movsbl -0x30(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  jmp    L9
L96:
  mov    $0x0,%eax
L9:
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L43
  cmpq   $0x0,-0x8(%rbp)
  je     L63
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L43
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L43
L63:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L43:
  mov    -0x18(%rbp),%rax
L97:
  leave
  ret
```

assistant: ```c
char(*remove_ext(char *mystr, char dot, char sep)) {
  char *retstr, *lastdot, *lastsep;
  if (mystr == NULL)
    return NULL;
  if ((retstr = malloc(strlen(mystr) + 1)) == NULL)
    return NULL;
  strcpy(retstr, mystr);
  lastdot = strrchr(retstr, dot);
  lastsep = (sep == 0) ? NULL : strchr(retstr, sep);
  if (lastdot != NULL) {
    if (lastsep != NULL) {
      if (lastsep < lastdot) {
        *lastdot = '\0';
      }
    } else {
      *lastdot = '\0';
    }
  }
  return retstr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_ext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L24
  mov    %esi,%r12d
  mov    %edx,%r13d
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbl %r12b,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbp
  test   %r13b,%r13b
  jne    L64
  test   %rax,%rax
  jne    L35
L36:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  movsbl %r13b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rbp,%rbp
  je     L36
  test   %rax,%rax
  je     L35
  cmp    %rax,%rbp
  jbe    L36
  movb   $0x0,0x0(%rbp)
  jmp    L36
L35:
  movb   $0x0,0x0(%rbp)
  jmp    L36
L24:
  mov    %rdi,%rbx
  jmp    L36
```

assistant: ```c
char(*remove_ext(char *mystr, char dot, char sep)) {
  char *retstr, *lastdot, *lastsep;
  if (mystr == NULL)
    return NULL;
  if ((retstr = malloc(strlen(mystr) + 1)) == NULL)
    return NULL;
  strcpy(retstr, mystr);
  lastdot = strrchr(retstr, dot);
  lastsep = (sep == 0) ? NULL : strchr(retstr, sep);
  if (lastdot != NULL) {
    if (lastsep != NULL) {
      if (lastsep < lastdot) {
        *lastdot = '\0';
      }
    } else {
      *lastdot = '\0';
    }
  }
  return retstr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_ext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r13d
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbl %bl,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %r13b,%r13b
  jne    L26
  test   %rax,%rax
  je     L24
L41:
  movb   $0x0,(%rbx)
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  movsbl %r13b,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rbx,%rbx
  je     L24
  test   %rax,%rax
  je     L41
  cmp    %rax,%rbx
  ja     L41
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char(*remove_ext(char *mystr, char dot, char sep)) {
  char *retstr, *lastdot, *lastsep;
  if (mystr == NULL)
    return NULL;
  if ((retstr = malloc(strlen(mystr) + 1)) == NULL)
    return NULL;
  strcpy(retstr, mystr);
  lastdot = strrchr(retstr, dot);
  lastsep = (sep == 0) ? NULL : strchr(retstr, sep);
  if (lastdot != NULL) {
    if (lastsep != NULL) {
      if (lastsep < lastdot) {
        *lastdot = '\0';
      }
    } else {
      *lastdot = '\0';
    }
  }
  return retstr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_ext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r13d
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbl %bl,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %r13b,%r13b
  jne    L20
  test   %rax,%rax
  je     L61
L14:
  movb   $0x0,(%rbx)
L61:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  movsbl %r13b,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rbx,%rbx
  je     L61
  test   %rax,%rax
  je     L14
  cmp    %rax,%rbx
  ja     L14
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char(*remove_ext(char *mystr, char dot, char sep)) {
  char *retstr, *lastdot, *lastsep;
  if (mystr == NULL)
    return NULL;
  if ((retstr = malloc(strlen(mystr) + 1)) == NULL)
    return NULL;
  strcpy(retstr, mystr);
  lastdot = strrchr(retstr, dot);
  lastsep = (sep == 0) ? NULL : strchr(retstr, sep);
  if (lastdot != NULL) {
    if (lastsep != NULL) {
      if (lastsep < lastdot) {
        *lastdot = '\0';
      }
    } else {
      *lastdot = '\0';
    }
  }
  return retstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ((__attribute__((unit(foo))) float)1.0f) + 1.0f;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ((__attribute__((unit(foo))) float)1.0f) + 1.0f;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ((__attribute__((unit(foo))) float)1.0f) + 1.0f;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ((__attribute__((unit(foo))) float)1.0f) + 1.0f;
  return 0;
}
```