ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dbg_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L14:
  mov    -0x10(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D17
type: string

tool: D8: encoded: 

tool: D17: %d 

assistant: ```c
void dbg_print(const uint8_t *buffer, uint32_t numbits) {
  printf("encoded: ");
  for (uint32_t i = 0; i < numbits; ++i) {
    uint8_t currentvalue = buffer[i / 8];
    uint32_t srcindex = i & 0x7;
    uint32_t srcbit = (currentvalue & (1 << srcindex)) ? 1 : 0;
    printf("%d ", srcbit);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dbg_print>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L3
  mov    $0x0,%ebx
  lea    D11(%rip),%r13
L19:
  lea    0x7(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x3,%eax
  cltq
  mov    %ebx,%ecx
  and    $0x7,%ecx
  mov    (%r12,%rax,4),%esi
  sar    %cl,%esi
  and    $0x1,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L19
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D16: encoded: 

tool: D11: %d 

assistant: ```c
void dbg_print(const uint8_t *buffer, uint32_t numbits) {
  printf("encoded: ");
  for (uint32_t i = 0; i < numbits; ++i) {
    uint8_t currentvalue = buffer[i / 8];
    uint32_t srcindex = i & 0x7;
    uint32_t srcbit = (currentvalue & (1 << srcindex)) ? 1 : 0;
    printf("%d ", srcbit);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dbg_print>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L14
  xor    %r13d,%r13d
  lea    D11(%rip),%r12
  nop
L15:
  mov    %r13d,%eax
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x1,%r13d
  sar    $0x3,%eax
  and    $0x7,%ecx
  cltq
  mov    0x0(%rbp,%rax,4),%esi
  xor    %eax,%eax
  sar    %cl,%esi
  and    $0x1,%esi
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L15
L14:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string

tool: D7: encoded: 

tool: D11: %d 

assistant: ```c
void dbg_print(const uint8_t *buffer, uint32_t numbits) {
  printf("encoded: ");
  for (uint32_t i = 0; i < numbits; ++i) {
    uint8_t currentvalue = buffer[i / 8];
    uint32_t srcindex = i & 0x7;
    uint32_t srcbit = (currentvalue & (1 << srcindex)) ? 1 : 0;
    printf("%d ", srcbit);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dbg_print>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L18
  xor    %r13d,%r13d
  lea    D1(%rip),%r12
  nop
L16:
  mov    %r13d,%eax
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x1,%r13d
  sar    $0x3,%eax
  and    $0x7,%ecx
  cltq
  mov    0x0(%rbp,%rax,4),%esi
  xor    %eax,%eax
  sar    %cl,%esi
  and    $0x1,%esi
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L16
L18:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D1
type: string

tool: D14: encoded: 

tool: D1: %d 

assistant: ```c
void dbg_print(const uint8_t *buffer, uint32_t numbits) {
  printf("encoded: ");
  for (uint32_t i = 0; i < numbits; ++i) {
    uint8_t currentvalue = buffer[i / 8];
    uint32_t srcindex = i & 0x7;
    uint32_t srcbit = (currentvalue & (1 << srcindex)) ? 1 : 0;
    printf("%d ", srcbit);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%r13d
  jmp    L57
L44:
  mov    $0x0,%ebx
  jmp    L54
L32:
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L3
  movslq %ebx,%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  movslq %ebx,%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  lea    (%r12,%rax,1),%rdx
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <swap@plt>
  jmp    L66
L3:
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    (%rax),%rdx
  movslq %ebx,%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L66
  movslq %ebx,%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L66
  movslq %ebx,%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  lea    (%r12,%rax,1),%rdx
  movslq %ebx,%rax
  shl    $0x3,%rax
  add    %r12,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <swap@plt>
L66:
  add    $0x1,%ebx
L54:
  cmp    $0x2,%ebx
  jle    L32
  add    $0x1,%r13d
L57:
  cmp    $0x3,%r13d
  jle    L44
  nop
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
sort(val) register long *val;
{
  register int i, j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 3; j++)
      if ((val[j] == 0) && (val[j + 1] != 0))
        swap(&val[j], &val[j + 1]);
      else if (val[j] > val[j + 1] && val[j + 1] != 0)
        swap(&val[j], &val[j + 1]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x4,%r12d
  lea    0x20(%rdi),%rbp
  jmp    L51
L24:
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L94
  cmp    %rdx,%rax
  jg     L25
L94:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L91
L15:
  lea    -0x8(%rbx),%rdi
  mov    %rbx,%rsi
  mov    -0x8(%rbx),%rax
  test   %rax,%rax
  jne    L24
  cmpq   $0x0,(%rbx)
  je     L94
  call   <swap@plt>
  jmp    L94
L25:
  mov    $0x0,%eax
  call   <swap@plt>
  jmp    L94
L91:
  sub    $0x1,%r12d
  je     L38
L51:
  lea    0x8(%r13),%rbx
  jmp    L15
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
sort(val) register long *val;
{
  register int i, j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 3; j++)
      if ((val[j] == 0) && (val[j + 1] != 0))
        swap(&val[j], &val[j + 1]);
      else if (val[j] > val[j + 1] && val[j + 1] != 0)
        swap(&val[j], &val[j + 1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort>:
  endbr64
  push   %r13
  mov    $0x4,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x18(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L67:
  mov    %r12,%rbx
L46:
  mov    (%rbx),%rax
  mov    %rbx,%rdi
  add    $0x8,%rbx
  mov    0x8(%rdi),%rdx
  test   %rax,%rax
  jne    L74
  test   %rdx,%rdx
  jne    L44
L33:
  cmp    %rbx,%rbp
  jne    L46
  sub    $0x1,%r13d
  jne    L67
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L74:
  cmp    %rdx,%rax
  jle    L33
  test   %rdx,%rdx
  je     L33
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <swap@plt>
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    %rbx,%rsi
  call   <swap@plt>
  jmp    L33
```

assistant: ```c
sort(val) register long *val;
{
  register int i, j;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 3; j++)
      if ((val[j] == 0) && (val[j + 1] != 0))
        swap(&val[j], &val[j + 1]);
      else if (val[j] > val[j + 1] && val[j + 1] != 0)
        swap(&val[j], &val[j + 1]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dm9000xtest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <sw_gpmi_init@plt>
  mov    $0x0,%eax
  call   <dm9000_initialize@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int dm9000xtest(int argc, char *argv[]) {
  sw_gpmi_init();
  dm9000_initialize();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dm9000xtest>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sw_gpmi_init@plt>
  mov    $0x0,%eax
  call   <dm9000_initialize@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dm9000xtest(int argc, char *argv[]) {
  sw_gpmi_init();
  dm9000_initialize();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dm9000xtest>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sw_gpmi_init@plt>
  xor    %eax,%eax
  call   <dm9000_initialize@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dm9000xtest(int argc, char *argv[]) {
  sw_gpmi_init();
  dm9000_initialize();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dm9000xtest>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sw_gpmi_init@plt>
  xor    %eax,%eax
  call   <dm9000_initialize@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dm9000xtest(int argc, char *argv[]) {
  sw_gpmi_init();
  dm9000_initialize();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_free(void) {
  void *ptr;
  ptr = NULL;
  free(ptr);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_free>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_free(void) {
  void *ptr;
  ptr = NULL;
  free(ptr);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_free>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <free@plt>
```

assistant: ```c
void test_free(void) {
  void *ptr;
  ptr = NULL;
  free(ptr);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_free>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <free@plt>
```

assistant: ```c
void test_free(void) {
  void *ptr;
  ptr = NULL;
  free(ptr);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<setbpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setbpt>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<setbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Zero24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L4:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
L3:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Zero24(void *destinationBuffer, signed int destinationStride, unsigned int count) {
  unsigned char *dest = (unsigned char *)destinationBuffer;
  while (count--) {
    dest[0] = 0;
    dest[1] = 0;
    dest[2] = 0;
    dest += destinationStride * 3;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Zero24>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L2
  lea    (%rsi,%rsi,2),%edx
  movslq %edx,%rdx
L13:
  movb   $0x0,(%rdi)
  movb   $0x0,0x1(%rdi)
  movb   $0x0,0x2(%rdi)
  add    %rdx,%rdi
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L13
L2:
  ret
```

assistant: ```c
void Zero24(void *destinationBuffer, signed int destinationStride, unsigned int count) {
  unsigned char *dest = (unsigned char *)destinationBuffer;
  while (count--) {
    dest[0] = 0;
    dest[1] = 0;
    dest[2] = 0;
    dest += destinationStride * 3;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Zero24>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L4
  lea    (%rsi,%rsi,2),%edx
  movslq %edx,%rdx
  nopl   0x0(%rax)
L1:
  movb   $0x0,(%rdi)
  movb   $0x0,0x1(%rdi)
  movb   $0x0,0x2(%rdi)
  add    %rdx,%rdi
  sub    $0x1,%eax
  jae    L1
L4:
  ret
```

assistant: ```c
void Zero24(void *destinationBuffer, signed int destinationStride, unsigned int count) {
  unsigned char *dest = (unsigned char *)destinationBuffer;
  while (count--) {
    dest[0] = 0;
    dest[1] = 0;
    dest[2] = 0;
    dest += destinationStride * 3;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Zero24>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L39
  lea    (%rsi,%rsi,2),%edx
  movslq %edx,%rdx
  cmp    $0x1,%esi
  jne    L29
  cs nopw 0x0(%rax,%rax,1)
L31:
  movb   $0x0,(%rdi)
  movb   $0x0,0x1(%rdi)
  movb   $0x0,0x2(%rdi)
  add    %rdx,%rdi
  sub    $0x1,%eax
  jae    L31
L39:
  ret
  nopl   0x0(%rax)
L29:
  movb   $0x0,(%rdi)
  movb   $0x0,0x1(%rdi)
  movb   $0x0,0x2(%rdi)
  add    %rdx,%rdi
  sub    $0x1,%eax
  jae    L29
  ret
```

assistant: ```c
void Zero24(void *destinationBuffer, signed int destinationStride, unsigned int count) {
  unsigned char *dest = (unsigned char *)destinationBuffer;
  while (count--) {
    dest[0] = 0;
    dest[1] = 0;
    dest[2] = 0;
    dest += destinationStride * 3;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2STxDataPut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L4:
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  cmp    $0xf,%rax
  ja     L4
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void I2STxDataPut(unsigned long ulBase, unsigned long ulData) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) >= 16) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulData;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<I2STxDataPut>:
  endbr64
L5:
  mov    0x18(%rdi),%rax
  cmp    $0xf,%rax
  ja     L5
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void I2STxDataPut(unsigned long ulBase, unsigned long ulData) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) >= 16) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulData;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<I2STxDataPut>:
  endbr64
  lea    0x18(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rdx),%rax
  cmp    $0xf,%rax
  ja     L0
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void I2STxDataPut(unsigned long ulBase, unsigned long ulData) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) >= 16) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulData;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<I2STxDataPut>:
  endbr64
  lea    0x18(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdx),%rax
  cmp    $0xf,%rax
  ja     L2
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void I2STxDataPut(unsigned long ulBase, unsigned long ulData) {
  ;
  while ((*((volatile unsigned long *)(ulBase + 0x00000018))) >= 16) {
  }
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulData;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zexy_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L15
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  jmp    L17
L16:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
char *zexy_strndup(const char *s, size_t n) {
  char *result = 0;
  size_t len = strlen(s) + 1;
  if (len > n) {
    len = n + 1;
  }
  result = malloc(len);
  if (!result) {
    return result;
  }
  memcpy(result, s, len);
  result[len - 1] = 0;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<zexy_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  lea    0x1(%rbp),%rax
  cmp    %rbp,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
L6:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *zexy_strndup(const char *s, size_t n) {
  char *result = 0;
  size_t len = strlen(s) + 1;
  if (len > n) {
    len = n + 1;
  }
  result = malloc(len);
  if (!result) {
    return result;
  }
  memcpy(result, s, len);
  result[len - 1] = 0;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<zexy_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  lea    0x1(%r12),%rax
  movslq %ebx,%rbx
  cmp    %r12,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *zexy_strndup(const char *s, size_t n) {
  char *result = 0;
  size_t len = strlen(s) + 1;
  if (len > n) {
    len = n + 1;
  }
  result = malloc(len);
  if (!result) {
    return result;
  }
  memcpy(result, s, len);
  result[len - 1] = 0;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zexy_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  lea    0x1(%r12),%rax
  movslq %ebx,%rbx
  cmp    %r12,%rbx
  cmova  %rax,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
L9:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *zexy_strndup(const char *s, size_t n) {
  char *result = 0;
  size_t len = strlen(s) + 1;
  if (len > n) {
    len = n + 1;
  }
  result = malloc(len);
  if (!result) {
    return result;
  }
  memcpy(result, s, len);
  result[len - 1] = 0;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Base64Decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %edx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x1b(%rsp)
  movb   $0x0,0x1f(%rsp)
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x333231307a797877,%rax
  movabs $0x2f2b393837363534,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  mov    %rbx,%rbp
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r13
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%ebx
  lea    0x20(%rsp),%r12
  jmp    L2
L37:
  lea    0x1b(%rsp),%rdi
  mov    %r15d,%edx
  mov    %r14,%rsi
  call   <decodeblock@plt>
  mov    %eax,0xc(%rsp)
L8:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    0xc(%rsp),%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  add    $0x1,%rbp
  cmp    %r13,%rbp
  je     L8
L2:
  movsbl 0x0(%rbp),%esi
  cmp    $0x3d,%esi
  je     L37
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L50
  movslq %ebx,%rdx
  sub    %r12,%rax
  mov    %al,0x1b(%rsp,%rdx,1)
  lea    0x1(%rbx),%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rdx,%rax,1),%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  test   $0x3,%dl
  jne    L50
  lea    0x1b(%rsp),%rdi
  mov    %r15d,%edx
  mov    %r14,%rsi
  call   <decodeblock@plt>
  mov    %eax,0xc(%rsp)
  movb   $0x0,0x1e(%rsp)
  movb   $0x0,0x1d(%rsp)
  movb   $0x0,0x1c(%rsp)
  movb   $0x0,0x1b(%rsp)
  jmp    L50
L12:
  movl   $0x0,0xc(%rsp)
  jmp    L8
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Base64Decode(char *input, char *output, int oplen) {
  char *charval = 0;
  char decoderinput[4 + 1] = "";
  char encodingtabe[63 + 1] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                              "abcdefghijklmnopqrstuvwxyz"
                              "0123456789"
                              "+/";
  ;
  int index = 0, asciival = 0, computeval = 0, iplen = 0, rc = 0;
  iplen = strlen(input);
  while (index < iplen) {
    asciival = (int)input[index];
    if (asciival == '=') {
      rc = decodeblock(decoderinput, output, oplen);
      break;
    } else {
      charval = strchr(encodingtabe, asciival);
      if (charval) {
        decoderinput[computeval] = charval - encodingtabe;
        computeval = (computeval + 1) % 4;
        if (computeval == 0) {
          rc = decodeblock(decoderinput, output, oplen);
          decoderinput[0] = decoderinput[1] = decoderinput[2] = decoderinput[3] = 0;
        }
      }
    }
    index++;
  }
  return rc;
}
```