ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fec_decode_old>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    0x10(%rbp),%eax
  mov    %ax,-0x2c(%rbp)
  movzwl -0x2c(%rbp),%edi
  mov    -0x28(%rbp),%r9
  mov    -0x20(%rbp),%r8
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  sub    $0x8,%rsp
  push   %rdi
  mov    %eax,%edi
  call   <reduce@plt>
  add    $0x10,%rsp
  movzwl -0x2c(%rbp),%r8d
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <resolve@plt>
  nop
  leave
  ret
```

assistant: ```c
void fec_decode_old(unsigned int blockSize, unsigned char **data_blocks, unsigned int nr_data_blocks, unsigned char **fec_blocks, unsigned int *fec_block_nos, unsigned int *erased_blocks, unsigned short nr_fec_blocks) {
  reduce(blockSize, data_blocks, nr_data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
  resolve(blockSize, data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fec_decode_old>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  movzwl 0x48(%rsp),%r15d
  push   %r15
  call   <reduce@plt>
  mov    %r15d,%r9d
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <resolve@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fec_decode_old(unsigned int blockSize, unsigned char **data_blocks, unsigned int nr_data_blocks, unsigned char **fec_blocks, unsigned int *fec_block_nos, unsigned int *erased_blocks, unsigned short nr_fec_blocks) {
  reduce(blockSize, data_blocks, nr_data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
  resolve(blockSize, data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fec_decode_old>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x10,%rsp
  movzwl 0x48(%rsp),%r15d
  push   %r15
  call   <reduce@plt>
  add    $0x18,%rsp
  mov    %r15d,%r9d
  mov    %rbx,%r8
  mov    %r14,%rcx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <resolve@plt>
```

assistant: ```c
void fec_decode_old(unsigned int blockSize, unsigned char **data_blocks, unsigned int nr_data_blocks, unsigned char **fec_blocks, unsigned int *fec_block_nos, unsigned int *erased_blocks, unsigned short nr_fec_blocks) {
  reduce(blockSize, data_blocks, nr_data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
  resolve(blockSize, data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fec_decode_old>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x10,%rsp
  movzwl 0x48(%rsp),%r15d
  push   %r15
  call   <reduce@plt>
  add    $0x18,%rsp
  mov    %r15d,%r9d
  mov    %rbx,%r8
  mov    %r14,%rcx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <resolve@plt>
```

assistant: ```c
void fec_decode_old(unsigned int blockSize, unsigned char **data_blocks, unsigned int nr_data_blocks, unsigned char **fec_blocks, unsigned int *fec_block_nos, unsigned int *erased_blocks, unsigned short nr_fec_blocks) {
  reduce(blockSize, data_blocks, nr_data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
  resolve(blockSize, data_blocks, fec_blocks, fec_block_nos, erased_blocks, nr_fec_blocks);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COM_DefaultExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L22
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L30
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L30
L22:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Q_strcat@plt>
  jmp    L23
L30:
  nop
L23:
  leave
  ret
```

assistant: ```c
void COM_DefaultExtension(char *path, int maxSize, const char *extension) {
  const char *dot = strrchr(path, '.'), *slash;
  if (dot && ((slash = strrchr(path, '/')) == ((void *)0) || slash < dot))
    return;
  else
    Q_strcat(path, maxSize, extension);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COM_DefaultExtension>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rbp
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  cmp    %rax,%rbp
  ja     L1
  test   %rax,%rax
  je     L1
L27:
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <Q_strcat@plt>
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void COM_DefaultExtension(char *path, int maxSize, const char *extension) {
  const char *dot = strrchr(path, '.'), *slash;
  if (dot && ((slash = strrchr(path, '/')) == ((void *)0) || slash < dot))
    return;
  else
    Q_strcat(path, maxSize, extension);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<COM_DefaultExtension>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x2e,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L20
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L21
  cmp    %rax,%rbx
  ja     L21
L20:
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <Q_strcat@plt>
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void COM_DefaultExtension(char *path, int maxSize, const char *extension) {
  const char *dot = strrchr(path, '.'), *slash;
  if (dot && ((slash = strrchr(path, '/')) == ((void *)0) || slash < dot))
    return;
  else
    Q_strcat(path, maxSize, extension);
}
```
user: Translate the below assembly code into C programming language:

```asm
<COM_DefaultExtension>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x2e,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L20
  cmp    %rax,%rbx
  ja     L20
L6:
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <Q_strcat@plt>
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void COM_DefaultExtension(char *path, int maxSize, const char *extension) {
  const char *dot = strrchr(path, '.'), *slash;
  if (dot && ((slash = strrchr(path, '/')) == ((void *)0) || slash < dot))
    return;
  else
    Q_strcat(path, maxSize, extension);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compLT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L8
  movl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int compLT(char *key1, char *key2) {
  int rc = 0;
  if (strcmp(key1, key2) < 0)
    rc = 1;
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compLT>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  shr    $0x3f,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compLT(char *key1, char *key2) {
  int rc = 0;
  if (strcmp(key1, key2) < 0)
    rc = 1;
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compLT>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  shr    $0x3f,%rax
  ret
```

assistant: ```c
int compLT(char *key1, char *key2) {
  int rc = 0;
  if (strcmp(key1, key2) < 0)
    rc = 1;
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compLT>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  shr    $0x3f,%rax
  ret
```

assistant: ```c
int compLT(char *key1, char *key2) {
  int rc = 0;
  if (strcmp(key1, key2) < 0)
    rc = 1;
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <square@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x9,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: The value of i is %d and it's square is %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 10; i++) {
    printf("The value of i is %d and it's square is %d\n", i, square(i));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L5:
  mov    %ebx,%edi
  call   <square@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: The value of i is %d and it's square is %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 10; i++) {
    printf("The value of i is %d and it's square is %d\n", i, square(i));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <square@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: The value of i is %d and it's square is %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 10; i++) {
    printf("The value of i is %d and it's square is %d\n", i, square(i));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <square@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: The value of i is %d and it's square is %d


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 10; i++) {
    printf("The value of i is %d and it's square is %d\n", i, square(i));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_zero_arr_inplace_plus_float_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    %esi,%r8d
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <_zero_arr_plus_float_fn@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
float *_zero_arr_inplace_plus_float_fn(float **x, int orig_i, const char *filename, unsigned lineno) {
  *x = _zero_arr_plus_float_fn(*x, 1, orig_i, filename, lineno);
  return *x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_zero_arr_inplace_plus_float_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  mov    (%rdi),%rdi
  call   <_zero_arr_plus_float_fn@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
float *_zero_arr_inplace_plus_float_fn(float **x, int orig_i, const char *filename, unsigned lineno) {
  *x = _zero_arr_plus_float_fn(*x, 1, orig_i, filename, lineno);
  return *x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_zero_arr_inplace_plus_float_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <_zero_arr_plus_float_fn@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
float *_zero_arr_inplace_plus_float_fn(float **x, int orig_i, const char *filename, unsigned lineno) {
  *x = _zero_arr_plus_float_fn(*x, 1, orig_i, filename, lineno);
  return *x;
}
```
user: What is the c source code of the assembly code below?

```asm
<_zero_arr_inplace_plus_float_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <_zero_arr_plus_float_fn@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
float *_zero_arr_inplace_plus_float_fn(float **x, int orig_i, const char *filename, unsigned lineno) {
  *x = _zero_arr_plus_float_fn(*x, 1, orig_i, filename, lineno);
  return *x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<now_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x10(%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D28(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  D6(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  D8(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D28
type_infered: byte[8]
name: read_data
arguments: data_label: D6
type_infered: byte[8]
name: read_data
arguments: data_label: D8
type_infered: byte[8]

tool: {"D28": [0x00,0x00,0x00,0x80,0x74,0xd2,0xea,0x41]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x38,0x9c,0x8c,0x41]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double now_time(void) {
  struct tm *now;
  struct timeval t;
  gettimeofday(&t, NULL);
  now = localtime(&t.tv_sec);
  return (double)(now->tm_hour) * 3600.0e+6 + (double)(now->tm_min) * 60.0e+6 + (double)(now->tm_sec) * 1.0e+6 + (double)(t.tv_usec);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<now_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rax),%xmm0
  mulsd  D28(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x8(%rax),%xmm1
  mulsd  D4(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rax),%xmm1
  mulsd  D7(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D4
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D7
type_guessed: byte[8]

tool: {"D28": [0x00,0x00,0x00,0x80,0x74,0xd2,0xea,0x41]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x38,0x9c,0x8c,0x41]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double now_time(void) {
  struct tm *now;
  struct timeval t;
  gettimeofday(&t, NULL);
  now = localtime(&t.tv_sec);
  return (double)(now->tm_hour) * 3600.0e+6 + (double)(now->tm_min) * 60.0e+6 + (double)(now->tm_sec) * 1.0e+6 + (double)(t.tv_usec);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<now_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x10(%rax),%xmm0
  mulsd  D26(%rip),%xmm0
  cvtsi2sdq 0x8(%rax),%xmm1
  mulsd  D2(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rax),%xmm1
  mulsd  D17(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type: byte[8]
name: retrieve_data
arguments: data_tag: D2
type: byte[8]
name: retrieve_data
arguments: data_tag: D17
type: byte[8]

tool: {"D26": [0x00,0x00,0x00,0x80,0x74,0xd2,0xea,0x41]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x38,0x9c,0x8c,0x41]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double now_time(void) {
  struct tm *now;
  struct timeval t;
  gettimeofday(&t, NULL);
  now = localtime(&t.tv_sec);
  return (double)(now->tm_hour) * 3600.0e+6 + (double)(now->tm_min) * 60.0e+6 + (double)(now->tm_sec) * 1.0e+6 + (double)(t.tv_usec);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<now_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x10(%rax),%xmm0
  mulsd  D21(%rip),%xmm0
  cvtsi2sdq 0x8(%rax),%xmm1
  mulsd  D23(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rax),%xmm1
  mulsd  D13(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D23
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D13
type: byte[8]

tool: {"D21": [0x00,0x00,0x00,0x80,0x74,0xd2,0xea,0x41]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x38,0x9c,0x8c,0x41]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double now_time(void) {
  struct tm *now;
  struct timeval t;
  gettimeofday(&t, NULL);
  now = localtime(&t.tv_sec);
  return (double)(now->tm_hour) * 3600.0e+6 + (double)(now->tm_min) * 60.0e+6 + (double)(now->tm_sec) * 1.0e+6 + (double)(t.tv_usec);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jg     L9
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L56
L9:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L48
L1:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L56:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D47
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D23
type: string

tool: D47: Input a number: 

tool: D36: %d

tool: D22: Input a number greater than two.

tool: D5: Factors: 

tool: D23:  %d %d

assistant: ```c
int main() {
  int number;
  int sqrt_n;
  int i;
  printf("Input a number: ");
  scanf("%d", &number);
  if (number < 2) {
    printf("Input a number greater than two.\n");
    return -1;
  }
  printf("Factors: ");
  sqrt_n = (int)sqrt(number);
  for (i = 2; i <= sqrt_n; i++) {
    if ((number % i) == 0) {
      printf(" %d %d", i, number / i);
    }
  }
  printf("\n");
  return 0;
}
```