user: What would the C source look like for the assembly code provided here?

```asm
<dump_hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x30(%rsp)
  test   %ebp,%ebp
  jle    L11
  lea    -0x1(%rbp),%eax
  lea    -0x10(%rbp),%ecx
  mov    %ebp,0x1c(%rsp)
  mov    0x1c(%rsp),%r12d
  and    $0xfffffff0,%eax
  mov    %ecx,0x14(%rsp)
  lea    D26(%rip),%r13
  lea    0x1e(%rsp),%rbx
  sub    %eax,%ecx
  lea    0x20(%rsp),%rax
  mov    %rdi,(%rsp)
  lea    0x1f(%rsp),%r14
  mov    %ecx,0x18(%rsp)
  sub    %ebp,%r12d
  mov    %rax,0x8(%rsp)
  cmp    $0xf,%ebp
  jle    L132
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  mov    $0x10,%edx
  mov    $0x10,%ebp
  call   <memcpy@plt>
L49:
  mov    %r12d,%esi
  lea    D28(%rip),%rdi
  lea    0x1(%rbp),%r12d
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x20(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    $0x2,%r15d
  call   <printf@plt>
  jmp    L135
  nopl   0x0(%rax)
L69:
  movzbl (%r14,%r15,1),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  test   $0x3,%r15b
  jne    L165
  mov    $0x20,%edi
  call   <putchar@plt>
L165:
  add    $0x1,%r15
L135:
  movzbl (%rbx,%r15,1),%eax
  lea    0x7f(%rax),%edx
  cmp    $0xfd,%dl
  ja     L31
  cmp    $0x1f,%al
  ja     L33
L31:
  movb   $0x2e,(%rbx,%r15,1)
L33:
  cmp    %r12,%r15
  jne    L69
  cmp    $0x10,%ebp
  jne    L138
L123:
  mov    0x8(%rsp),%rdi
  call   <puts@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%ecx
  addq   $0x10,(%rsp)
  mov    %eax,%ebp
  cmp    %ecx,%eax
  je     L11
  mov    0x1c(%rsp),%r12d
  sub    $0x10,%eax
  mov    %eax,0x14(%rsp)
  sub    %ebp,%r12d
  cmp    $0xf,%ebp
  jg     L16
L132:
  mov    (%rsp),%rsi
  mov    0x8(%rsp),%rdi
  mov    %ebp,%edx
  call   <memcpy@plt>
  jmp    L49
  nopl   (%rax)
L138:
  mov    %ebp,%r12d
  jmp    L134
  nopl   (%rax)
L79:
  cmp    $0x10,%r12d
  je     L62
L134:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  test   $0x3,%r12b
  jne    L79
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    $0x10,%r12d
  jne    L134
L62:
  movb   $0x0,0x20(%rsp,%rbp,1)
  jmp    L123
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L141
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L141:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D26: %02X

tool: D28: %08X	

tool: D9:    

assistant: ```c
void dump_hex(char *str, int len) {
  char d[17];
  d[16] = 0;
  unsigned int i, bytes, index = 0;
  int left_len = len;
  while (left_len > 0) {
    if (left_len / 16 >= 1) {
      memcpy(d, str + index, 16);
      bytes = 16;
    } else {
      memcpy(d, str + index, left_len);
      bytes = left_len;
    }
    printf("%08X\t", index);
    index += 16;
    for (i = 0; i < bytes; i++) {
      printf("%02X", (unsigned char)(d[i]));
      if ((i + 1) % 4 == 0)
        printf(" ");
      if (d[i] == 127 || d[i] < -127 || (d[i] >= 0 && d[i] <= 31))
        d[i] = '.';
    }
    if (bytes < 16) {
      for (i = bytes; i < 16; i++) {
        printf("   ");
        if ((i + 1) % 4 == 0)
          printf(" ");
      }
      d[bytes] = '\0';
    }
    printf("%s\n", d);
    left_len -= 16;
  }
}
```