ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_closest_word>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    (%rsi),%rsi
  call   <get_closeless@plt>
  cmp    $0x1,%r13d
  jle    L10
  movaps %xmm0,%xmm1
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%r14,%rbx,8),%rsi
  mov    %rbp,%rdi
  movss  %xmm1,0xc(%rsp)
  call   <get_closeless@plt>
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  maxss  %xmm1,%xmm0
  cmova  %ebx,%r12d
  add    $0x1,%rbx
  movaps %xmm0,%xmm1
  cmp    %r13,%rbx
  jne    L19
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x10,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_closest_word(char *word, char **dictionary, int N) {
  float close, mclose;
  int i, index;
  mclose = get_closeless(word, dictionary[0]);
  index = 0;
  for (i = 1; i < N; i++) {
    close = get_closeless(word, dictionary[i]);
    if (close > mclose) {
      mclose = close;
      index = i;
    }
  }
  return index;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ERI_Interpolate_Linear_Real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L58
L27:
  addl   $0x1,-0x24(%rbp)
L58:
  mov    -0x24(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jge    L65
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x38(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L27
L65:
  cmpl   $0x0,-0x24(%rbp)
  jne    L37
  mov    -0x48(%rbp),%rax
  movsd  (%rax),%xmm0
  jmp    L44
L37:
  mov    -0x24(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jne    L55
  mov    -0x4c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L44
L55:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x10(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  subsd  -0x20(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x10(%rbp),%xmm0
L44:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double ERI_Interpolate_Linear_Real(double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    return sy[0];
  }
  if (i == ns) {
    return sy[ns - 1];
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[i - 1];
  y1 = sy[i];
  return y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ERI_Interpolate_Linear_Real>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  test   %edx,%edx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r13d,%r13d
  jle    L57
  mov    %rbp,%rdx
  mov    $0x0,%eax
L44:
  movq   %rbx,%xmm4
  comisd (%rdx),%xmm4
  jbe    L27
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%r13d
  jne    L44
  test   %r13d,%r13d
  jne    L78
L57:
  movsd  (%r12),%xmm0
  jmp    L6
L27:
  test   %eax,%eax
  je     L57
  cmp    %eax,%r13d
  je     L78
  cltq
  lea    0x0(,%rax,8),%rdx
  movsd  -0x8(%rbp,%rdx,1),%xmm3
  movsd  -0x8(%r12,%rdx,1),%xmm2
  movsd  (%r12,%rax,8),%xmm0
  subsd  %xmm2,%xmm0
  movq   %rbx,%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  movsd  0x0(%rbp,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L78:
  movslq %r13d,%r13
  movsd  -0x8(%r12,%r13,8),%xmm0
  jmp    L6
```

assistant: ```c
double ERI_Interpolate_Linear_Real(double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    return sy[0];
  }
  if (i == ns) {
    return sy[ns - 1];
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[i - 1];
  y1 = sy[i];
  return y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ERI_Interpolate_Linear_Real>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  movslq %edx,%rbx
  sub    $0x10,%rsp
  test   %ebx,%ebx
  setg   %dil
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  xor    %eax,%eax
  xor    %ecx,%ecx
  test   %ebx,%ebx
  movsd  0x8(%rsp),%xmm0
  jg     L47
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%ecx
  add    $0x8,%rax
  cmp    %ecx,%ebx
  je     L37
L47:
  movsd  0x0(%rbp,%rax,1),%xmm1
  comisd %xmm1,%xmm0
  ja     L27
  test   %ecx,%ecx
  je     L28
  movsd  -0x8(%rbp,%rax,1),%xmm4
  movsd  -0x8(%r12,%rax,1),%xmm3
  movsd  (%r12,%rax,1),%xmm2
  add    $0x10,%rsp
  subsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm1
  pop    %rbx
  pop    %rbp
  subsd  %xmm3,%xmm2
  pop    %r12
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nop
L37:
  movsd  -0x8(%r12,%rbx,8),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  movsd  (%r12),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double ERI_Interpolate_Linear_Real(double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    return sy[0];
  }
  if (i == ns) {
    return sy[ns - 1];
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[i - 1];
  y1 = sy[i];
  return y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ERI_Interpolate_Linear_Real>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  movslq %edx,%rbx
  sub    $0x10,%rsp
  test   %ebx,%ebx
  setg   %dil
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  xor    %eax,%eax
  xor    %ecx,%ecx
  test   %ebx,%ebx
  movsd  0x8(%rsp),%xmm0
  jg     L1
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ecx
  add    $0x8,%rax
  cmp    %ecx,%ebx
  je     L42
L1:
  movsd  0x0(%rbp,%rax,1),%xmm1
  comisd %xmm1,%xmm0
  ja     L5
  test   %ecx,%ecx
  je     L21
  movsd  -0x8(%rbp,%rax,1),%xmm4
  movsd  -0x8(%r12,%rax,1),%xmm3
  movsd  (%r12,%rax,1),%xmm2
  add    $0x10,%rsp
  subsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm1
  pop    %rbx
  pop    %rbp
  subsd  %xmm3,%xmm2
  pop    %r12
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
  nop
L42:
  movsd  -0x8(%r12,%rbx,8),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  movsd  (%r12),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double ERI_Interpolate_Linear_Real(double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    return sy[0];
  }
  if (i == ns) {
    return sy[ns - 1];
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[i - 1];
  y1 = sy[i];
  return y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7e0,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string

tool: D0: 
Qual ano voce nasceu?

tool: D13: %d

tool: D27: 
Voce possui %d anos


assistant: ```c
int main() {
  int atual;
  int nascimento;
  int anos;
  atual = 2016;
  printf("\nQual ano voce nasceu?");
  scanf("%d", &nascimento);
  anos = atual - nascimento;
  printf("\nVoce possui %d anos\n", anos);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    $0x7e0,%esi
  sub    0x4(%rsp),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D6: 
Qual ano voce nasceu?

tool: D14: %d

tool: D13: 
Voce possui %d anos


assistant: ```c
int main() {
  int atual;
  int nascimento;
  int anos;
  atual = 2016;
  printf("\nQual ano voce nasceu?");
  scanf("%d", &nascimento);
  anos = atual - nascimento;
  printf("\nVoce possui %d anos\n", anos);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x7e0,%esi
  xor    %eax,%eax
  sub    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D25: 
Qual ano voce nasceu?

tool: D4: %d

tool: D7: 
Voce possui %d anos


assistant: ```c
int main() {
  int atual;
  int nascimento;
  int anos;
  atual = 2016;
  printf("\nQual ano voce nasceu?");
  scanf("%d", &nascimento);
  anos = atual - nascimento;
  printf("\nVoce possui %d anos\n", anos);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    $0x7e0,%esi
  xor    %eax,%eax
  sub    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D14
type: string

tool: D0: 
Qual ano voce nasceu?

tool: D2: %d

tool: D14: 
Voce possui %d anos


assistant: ```c
int main() {
  int atual;
  int nascimento;
  int anos;
  atual = 2016;
  printf("\nQual ano voce nasceu?");
  scanf("%d", &nascimento);
  anos = atual - nascimento;
  printf("\nVoce possui %d anos\n", anos);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<system_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void system_(char *line, int linelen) {
  char *com;
  com = malloc(linelen);
  if (com) {
    strncpy(com, line, linelen);
    line[linelen] = '\0';
    system(line);
    free(com);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<system_>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void system_(char *line, int linelen) {
  char *com;
  com = malloc(linelen);
  if (com) {
    strncpy(com, line, linelen);
    line[linelen] = '\0';
    system(line);
    free(com);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<system_>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L9
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rdi
  call   <system@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void system_(char *line, int linelen) {
  char *com;
  com = malloc(linelen);
  if (com) {
    strncpy(com, line, linelen);
    line[linelen] = '\0';
    system(line);
    free(com);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<system_>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rdi
  call   <system@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void system_(char *line, int linelen) {
  char *com;
  com = malloc(linelen);
  if (com) {
    strncpy(com, line, linelen);
    line[linelen] = '\0';
    system(line);
    free(com);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<latlon2km>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm1
  movss  D32(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  D32(%rip),%xmm0
  divss  %xmm1,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm0,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x10(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  %xmm2,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm1
  movss  D7(%rip),%xmm0
  addss  %xmm1,%xmm0
  mulss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  movss  D32(%rip),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm6,%xmm6
  cvtss2sd %xmm0,%xmm6
  movq   %xmm6,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x40(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D32
type_infered: f32
name: disassemble_data
arguments: label: D7
type_infered: f32

tool: D32: 1

tool: D7: 2

assistant: ```c
latlon2km(arg, latkm, lonkm, rc, g2) float *arg, *latkm, *lonkm, *rc, *g2;
{
  float cosA, sinA, g2s2, den;
  cosA = cos((*arg));
  sinA = sin((*arg));
  g2s2 = (*g2) * sinA * sinA;
  den = sqrt(((float)(1.0)) / (((float)(1.0)) + g2s2));
  *lonkm = (*rc) * cosA * den;
  *latkm = (*rc) * (sqrt(((float)(1.0)) + g2s2 * (((float)(2.0)) + (*g2)))) * den * den * den;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<latlon2km>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%rbp
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  call   <sincos@plt>
  pxor   %xmm2,%xmm2
  cvtsd2ss 0x10(%rsp),%xmm2
  movd   %xmm2,%r14d
  pxor   %xmm0,%xmm0
  cvtsd2ss 0x18(%rsp),%xmm0
  movaps %xmm0,%xmm1
  mulss  0x0(%rbp),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  D25(%rip),%xmm0
  addss  %xmm0,%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L25
  sqrtss %xmm0,%xmm0
  movss  %xmm0,0x8(%rsp)
L6:
  movd   %r14d,%xmm0
  mulss  (%r12),%xmm0
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x0(%r13)
  pxor   %xmm4,%xmm4
  cvtss2sd (%r12),%xmm4
  movsd  %xmm4,(%rsp)
  movss  D20(%rip),%xmm0
  addss  0x0(%rbp),%xmm0
  mulss  0xc(%rsp),%xmm0
  addss  D25(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L31
  sqrtsd %xmm0,%xmm0
L10:
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm1
  mulsd  (%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <sqrtf@plt>
  movss  %xmm0,0x8(%rsp)
  jmp    L6
L31:
  call   <sqrt@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type: f32
name: unpack_data
arguments: data_tag: D20
type: f32

tool: D25: 1

tool: D20: 2

assistant: ```c
latlon2km(arg, latkm, lonkm, rc, g2) float *arg, *latkm, *lonkm, *rc, *g2;
{
  float cosA, sinA, g2s2, den;
  cosA = cos((*arg));
  sinA = sin((*arg));
  g2s2 = (*g2) * sinA * sinA;
  den = sqrt(((float)(1.0)) / (((float)(1.0)) + g2s2));
  *lonkm = (*rc) * cosA * den;
  *latkm = (*rc) * (sqrt(((float)(1.0)) + g2s2 * (((float)(2.0)) + (*g2)))) * den * den * den;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<latlon2km>:
  endbr64
  push   %r13
  mov    %rdi,%r9
  pxor   %xmm0,%xmm0
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  cvtss2sd (%r9),%xmm0
  call   <sincos@plt>
  movss  (%r12),%xmm3
  pxor   %xmm0,%xmm0
  movss  D9(%rip),%xmm4
  cvtsd2ss 0x18(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mulss  %xmm0,%xmm3
  movaps %xmm4,%xmm2
  cvtsd2ss 0x10(%rsp),%xmm1
  mulss  %xmm0,%xmm3
  movaps %xmm3,%xmm0
  addss  %xmm4,%xmm0
  divss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomiss %xmm2,%xmm0
  ja     L7
  sqrtss %xmm2,%xmm2
L38:
  mulss  0x0(%r13),%xmm1
  movss  D18(%rip),%xmm0
  mulss  %xmm2,%xmm1
  movss  %xmm1,0x0(%rbp)
  addss  (%r12),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x0(%r13),%xmm1
  mulss  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  addss  %xmm4,%xmm0
  cvtss2sd %xmm0,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L24
  sqrtsd %xmm0,%xmm0
L26:
  mulsd  %xmm0,%xmm1
  cvtss2sd %xmm2,%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  movaps %xmm2,%xmm0
  movss  %xmm3,0xc(%rsp)
  movss  %xmm1,(%rsp)
  call   <sqrtf@plt>
  movss  0xc(%rsp),%xmm3
  movss  (%rsp),%xmm1
  movss  D9(%rip),%xmm4
  movaps %xmm0,%xmm2
  jmp    L38
L24:
  movss  %xmm2,0xc(%rsp)
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: f32
name: retrieve_data
arguments: data_tag: D18
data_type: f32

tool: D9: 1

tool: D18: 2

assistant: ```c
latlon2km(arg, latkm, lonkm, rc, g2) float *arg, *latkm, *lonkm, *rc, *g2;
{
  float cosA, sinA, g2s2, den;
  cosA = cos((*arg));
  sinA = sin((*arg));
  g2s2 = (*g2) * sinA * sinA;
  den = sqrt(((float)(1.0)) / (((float)(1.0)) + g2s2));
  *lonkm = (*rc) * cosA * den;
  *latkm = (*rc) * (sqrt(((float)(1.0)) + g2s2 * (((float)(2.0)) + (*g2)))) * den * den * den;
}
```