ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  jle    L38
  mov    $0x0,%esi
  movabs $0x6666666666666667,%r8
  mov    $0x12000,%r9d
  jmp    L37
L25:
  mov    %rdx,%rdi
L37:
  mov    %rdi,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rdi,%rcx
  sub    %rax,%rcx
  add    $0x9,%rcx
  mov    %r9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rsi
  mov    %rdi,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  cmp    $0x9,%rdi
  jg     L25
  test   %rsi,%rsi
  jle    L69
  movabs $0x6666666666666667,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rsi,%rdx
  sub    %rax,%rdx
  mov    $0x90,%eax
  bt     %rdx,%rax
  jae    L38
  movabs $0x6666666666666667,%rdi
  mov    $0x90,%r9d
L33:
  mov    %rsi,%r8
  mov    %rsi,%rax
  imul   %rdi
  sar    $0x2,%rdx
  sar    $0x3f,%rsi
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  mov    %rcx,%rsi
  cmp    $0x9,%r8
  jle    L97
  mov    %rcx,%rax
  imul   %rdi
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  bt     %rcx,%r9
  jb     L33
L38:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L69:
  je     L38
L97:
  lea    D7(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D3: %lld

tool: D20: NO


tool: D7: YES


assistant: ```c
int main() {
  long long int a;
  scanf("%lld", &a);
  long long int b = a;
  long long int c = 0;
  long long int temp;
  while (b > 0) {
    temp = b % 10;
    if ((temp == 4) || (temp == 7))
      c++;
    b = b / 10;
  }
  long long int d = c;
  long long t;
  long long int x = 0;
  while (d > 0) {
    t = d % 10;
    if ((t != 4) && (t != 7)) {
      x = 1;
      break;
    }
    d = d / 10;
  }
  if (x == 0 && c != 0)
    printf("YES\n");
  else
    printf("NO\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  jle    L85
  xor    %esi,%esi
  mov    $0x90,%r9d
  movabs $0xcccccccccccccccd,%r8
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %rdx,%rdi
L88:
  mov    %rdi,%rax
  mov    %rdi,%rcx
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rsi
  cmp    $0x9,%rdi
  jg     L84
  test   %rsi,%rsi
  je     L85
  mov    %rsi,%rax
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rsi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  mov    $0x90,%eax
  bt     %rdx,%rax
  jae    L85
  movabs $0xcccccccccccccccd,%rcx
  mov    $0x90,%edi
  jmp    L10
  nopl   (%rax)
L76:
  mov    %rsi,%rax
  mul    %rcx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rsi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  bt     %rdx,%rdi
  jae    L85
L10:
  mov    %rsi,%rax
  mul    %rcx
  mov    %rdx,%rsi
  shr    $0x3,%rsi
  jne    L76
  lea    D15(%rip),%rdi
  call   <printf@plt>
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L85:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D8
data_type: string

tool: D7: %lld

tool: D15: YES


tool: D8: NO


assistant: ```c
int main() {
  long long int a;
  scanf("%lld", &a);
  long long int b = a;
  long long int c = 0;
  long long int temp;
  while (b > 0) {
    temp = b % 10;
    if ((temp == 4) || (temp == 7))
      c++;
    b = b / 10;
  }
  long long int d = c;
  long long t;
  long long int x = 0;
  while (d > 0) {
    t = d % 10;
    if ((t != 4) && (t != 7)) {
      x = 1;
      break;
    }
    d = d / 10;
  }
  if (x == 0 && c != 0)
    printf("YES\n");
  else
    printf("NO\n");
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  test   %rdi,%rdi
  jle    L11
  xor    %esi,%esi
  mov    $0x90,%r9d
  movabs $0xcccccccccccccccd,%r8
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rdx,%rdi
L44:
  mov    %rdi,%rax
  mov    %rdi,%rcx
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %r9,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rsi
  cmp    $0x9,%rdi
  jg     L40
  test   %rsi,%rsi
  je     L11
  mov    %rsi,%rax
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rsi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  mov    $0x90,%eax
  bt     %rdx,%rax
  jae    L11
  movabs $0xcccccccccccccccd,%rcx
  mov    $0x90,%edi
  jmp    L39
  nopl   (%rax)
L53:
  mov    %rsi,%rax
  mul    %rcx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rsi,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  bt     %rdx,%rdi
  jae    L11
L39:
  mov    %rsi,%rax
  mul    %rcx
  mov    %rdx,%rsi
  shr    $0x3,%rsi
  jne    L53
  lea    D22(%rip),%rdi
  call   <printf@plt>
L87:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L11:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L87
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D29: %lld

tool: D22: YES


tool: D12: NO


assistant: ```c
int main() {
  long long int a;
  scanf("%lld", &a);
  long long int b = a;
  long long int c = 0;
  long long int temp;
  while (b > 0) {
    temp = b % 10;
    if ((temp == 4) || (temp == 7))
      c++;
    b = b / 10;
  }
  long long int d = c;
  long long t;
  long long int x = 0;
  while (d > 0) {
    t = d % 10;
    if ((t != 4) && (t != 7)) {
      x = 1;
      break;
    }
    d = d / 10;
  }
  if (x == 0 && c != 0)
    printf("YES\n");
  else
    printf("NO\n");
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ui32_to_f64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L24:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    %edx,%eax
  test   %rax,%rax
  js     L34
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L11
L34:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L11:
  movsd  %xmm0,(%rcx)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ui32_to_f64(double *out, unsigned int *x, unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    out[i] = (double)x[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ui32_to_f64>:
  endbr64
  test   %edx,%edx
  je     L10
  mov    %edx,%edx
  mov    $0x0,%eax
L13:
  mov    (%rsi,%rax,4),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L10:
  ret
```

assistant: ```c
void ui32_to_f64(double *out, unsigned int *x, unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    out[i] = (double)x[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ui32_to_f64>:
  endbr64
  test   %edx,%edx
  je     L7
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  mov    (%rsi,%rax,4),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L3
L7:
  ret
```

assistant: ```c
void ui32_to_f64(double *out, unsigned int *x, unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    out[i] = (double)x[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ui32_to_f64>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  test   %edx,%edx
  je     L56
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L31
  shr    $0x2,%edx
  movapd D5(%rip),%xmm4
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  shl    $0x4,%rdx
  nopw   0x0(%rax,%rax,1)
L27:
  movdqu (%rsi,%rax,1),%xmm0
  cvtdq2pd %xmm0,%xmm1
  movapd %xmm1,%xmm2
  pshufd $0xee,%xmm0,%xmm0
  cmpltpd %xmm3,%xmm2
  cvtdq2pd %xmm0,%xmm0
  andpd  %xmm4,%xmm2
  addpd  %xmm2,%xmm1
  movups %xmm1,(%rcx,%rax,2)
  movapd %xmm0,%xmm1
  cmpltpd %xmm3,%xmm1
  andpd  %xmm4,%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,0x10(%rcx,%rax,2)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L27
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L7
L15:
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  mov    (%rsi,%rdx,4),%r8d
  cvtsi2sd %r8,%xmm0
  movsd  %xmm0,(%rcx,%rdx,8)
  lea    0x1(%rax),%edx
  cmp    %edx,%edi
  jbe    L56
  mov    (%rsi,%rdx,4),%r8d
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2sd %r8,%xmm0
  movsd  %xmm0,(%rcx,%rdx,8)
  cmp    %eax,%edi
  jbe    L56
  mov    (%rsi,%rax,4),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
L56:
  ret
  nop
L7:
  ret
L31:
  xor    %eax,%eax
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41]}

assistant: ```c
void ui32_to_f64(double *out, unsigned int *x, unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    out[i] = (double)x[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<b6_utf8_enc_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  ja     L53
  mov    $0x1,%eax
  jmp    L6
L53:
  cmpl   $0x7ff,-0x4(%rbp)
  ja     L54
  mov    $0x2,%eax
  jmp    L6
L54:
  cmpl   $0xffff,-0x4(%rbp)
  ja     L1
  mov    $0x3,%eax
  jmp    L6
L1:
  cmpl   $0x1fffff,-0x4(%rbp)
  ja     L79
  mov    $0x4,%eax
  jmp    L6
L79:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int b6_utf8_enc_len(unsigned int unicode) {
  if (unicode < 0x80)
    return 1;
  if (unicode < 0x800)
    return 2;
  if (unicode < 0x10000)
    return 3;
  if (unicode < 0x200000)
    return 4;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<b6_utf8_enc_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jbe    L1
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jbe    L1
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jbe    L1
  cmp    $0x1fffff,%edi
  setbe  %al
  movzbl %al,%eax
  shl    $0x2,%eax
L1:
  ret
```

assistant: ```c
unsigned int b6_utf8_enc_len(unsigned int unicode) {
  if (unicode < 0x80)
    return 1;
  if (unicode < 0x800)
    return 2;
  if (unicode < 0x10000)
    return 3;
  if (unicode < 0x200000)
    return 4;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<b6_utf8_enc_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jbe    L15
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jbe    L15
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jbe    L15
  xor    %eax,%eax
  cmp    $0x1fffff,%edi
  setbe  %al
  shl    $0x2,%eax
L15:
  ret
```

assistant: ```c
unsigned int b6_utf8_enc_len(unsigned int unicode) {
  if (unicode < 0x80)
    return 1;
  if (unicode < 0x800)
    return 2;
  if (unicode < 0x10000)
    return 3;
  if (unicode < 0x200000)
    return 4;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<b6_utf8_enc_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jbe    L22
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jbe    L22
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jbe    L22
  xor    %eax,%eax
  cmp    $0x1fffff,%edi
  setbe  %al
  shl    $0x2,%eax
L22:
  ret
```

assistant: ```c
unsigned int b6_utf8_enc_len(unsigned int unicode) {
  if (unicode < 0x80)
    return 1;
  if (unicode < 0x800)
    return 2;
  if (unicode < 0x10000)
    return 3;
  if (unicode < 0x200000)
    return 4;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inet_netof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L18
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  mov    %ebx,%edx
  and    %eax,%edx
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L15
L18:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L23
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%ebx
  mov    %ebx,%edx
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L15
L23:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%ebx
  mov    %ebx,%edx
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return ((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT;
  else if (IN_CLASSB(i))
    return ((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT;
  else
    return ((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L14
  mov    D57(%rip),%rax
  and    (%rax),%ebx
  mov    %ebx,%eax
  mov    D12(%rip),%rdx
  mov    (%rdx),%ecx
  sar    %cl,%eax
L10:
  pop    %rbx
  ret
L14:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L13
  mov    D47(%rip),%rax
  and    (%rax),%ebx
  mov    D39(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L10
L13:
  mov    D23(%rip),%rax
  and    (%rax),%ebx
  mov    D19(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L10
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return ((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT;
  else if (IN_CLASSB(i))
    return ((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT;
  else
    return ((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L17
  mov    D51(%rip),%rax
  mov    D11(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L17:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L0
  mov    D17(%rip),%rax
  and    (%rax),%ebx
  mov    D58(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    D7(%rip),%rax
  and    (%rax),%ebx
  mov    D18(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return ((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT;
  else if (IN_CLASSB(i))
    return ((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT;
  else
    return ((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L5
  mov    D55(%rip),%rax
  mov    D34(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L5:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L0
  mov    D25(%rip),%rax
  and    (%rax),%ebx
  mov    D54(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    D15(%rip),%rax
  and    (%rax),%ebx
  mov    D44(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_int32_t i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return ((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT;
  else if (IN_CLASSB(i))
    return ((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT;
  else
    return ((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doc_pending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L35
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doc_following@plt>
  jmp    L17
L35:
  cmpl   $0x0,-0x14(%rbp)
  jns    L10
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doc_prior@plt>
  jmp    L17
L10:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
L17:
  leave
  ret
```

assistant: ```c
wint_t doc_pending(struct pane *p, struct mark *m, int n) {
  if (n > 0)
    return doc_following(p, m);
  if (n < 0)
    return doc_prior(p, m);
  return WEOF;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<doc_pending>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jg     L31
  js     L27
  mov    D5(%rip),%rax
  mov    (%rax),%eax
L2:
  add    $0x8,%rsp
  ret
L31:
  call   <doc_following@plt>
  jmp    L2
L27:
  call   <doc_prior@plt>
  jmp    L2
```

assistant: ```c
wint_t doc_pending(struct pane *p, struct mark *m, int n) {
  if (n > 0)
    return doc_following(p, m);
  if (n < 0)
    return doc_prior(p, m);
  return WEOF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<doc_pending>:
  endbr64
  test   %edx,%edx
  jg     L12
  jne    L15
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L12:
  jmp    1060 <doc_following@plt>
  nopl   (%rax)
L15:
  jmp    1070 <doc_prior@plt>
```

assistant: ```c
wint_t doc_pending(struct pane *p, struct mark *m, int n) {
  if (n > 0)
    return doc_following(p, m);
  if (n < 0)
    return doc_prior(p, m);
  return WEOF;
}
```
user: What is the c source code of the assembly code below:

```asm
<doc_pending>:
  endbr64
  test   %edx,%edx
  jg     L4
  jne    L11
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L4:
  jmp    1060 <doc_following@plt>
  nopl   (%rax)
L11:
  jmp    1070 <doc_prior@plt>
```

assistant: ```c
wint_t doc_pending(struct pane *p, struct mark *m, int n) {
  if (n > 0)
    return doc_following(p, m);
  if (n < 0)
    return doc_prior(p, m);
  return WEOF;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lib3ds_quat_ln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <atan2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L31
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L11
L31:
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L11:
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L30:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L9:
  cmpl   $0x2,-0x1c(%rbp)
  jle    L30
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void lib3ds_quat_ln(float c[4]) {
  double om, s, t;
  s = sqrt(c[0] * c[0] + c[1] * c[1] + c[2] * c[2]);
  om = atan2(s, (double)c[3]);
  if (fabs(s) < (1e-5)) {
    t = 0.0f;
  } else {
    t = om / s;
  }
  {
    int i;
    for (i = 0; i < 3; ++i) {
      c[i] = (float)(c[i] * t);
    }
    c[3] = 0.0f;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<lib3ds_quat_ln>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  movss  0x8(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rbp
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rbx),%xmm1
  call   <atan2@plt>
  movq   %xmm0,%r12
  movq   %rbp,%xmm0
  call   <fabs@plt>
  pxor   %xmm1,%xmm1
  test   %eax,%eax
  jle    L8
  movq   %r12,%xmm1
  movq   %rbp,%xmm3
  divsd  %xmm3,%xmm1
L8:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rbx)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rbx),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x4(%rbx)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rbx),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%rbx)
  movl   $0x0,0xc(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lib3ds_quat_ln(float c[4]) {
  double om, s, t;
  s = sqrt(c[0] * c[0] + c[1] * c[1] + c[2] * c[2]);
  om = atan2(s, (double)c[3]);
  if (fabs(s) < (1e-5)) {
    t = 0.0f;
  } else {
    t = om / s;
  }
  {
    int i;
    for (i = 0; i < 3; ++i) {
      c[i] = (float)(c[i] * t);
    }
    c[3] = 0.0f;
  }
}
```