ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_and_clear_bit>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  cltq
  mov    (%rsi),%rcx
  mov    %rax,%rdx
  not    %rdx
  and    %rcx,%rdx
  mov    %rdx,(%rsi)
  test   %rcx,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, unsigned long *addr) {
  unsigned long mask = (1 << (nr));
  unsigned long old = *addr;
  *addr = old & ~mask;
  return (old & mask) != 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_and_clear_bit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    (%rsi),%rcx
  cltq
  mov    %rax,%rdx
  not    %rdx
  and    %rcx,%rdx
  test   %rcx,%rax
  setne  %al
  mov    %rdx,(%rsi)
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, unsigned long *addr) {
  unsigned long mask = (1 << (nr));
  unsigned long old = *addr;
  *addr = old & ~mask;
  return (old & mask) != 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_and_clear_bit>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    (%rsi),%rcx
  cltq
  mov    %rax,%rdx
  not    %rdx
  and    %rcx,%rdx
  test   %rcx,%rax
  setne  %al
  mov    %rdx,(%rsi)
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, unsigned long *addr) {
  unsigned long mask = (1 << (nr));
  unsigned long old = *addr;
  *addr = old & ~mask;
  return (old & mask) != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x5,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: hello

assistant: ```c
int main() {
  char *p;
  p = "hello";
  return strlen(p) - 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <strlen@plt>
  sub    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: hello

assistant: ```c
int main() {
  char *p;
  p = "hello";
  return strlen(p) - 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  sub    $0x5,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: hello

assistant: ```c
int main() {
  char *p;
  p = "hello";
  return strlen(p) - 5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  sub    $0x5,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: hello

assistant: ```c
int main() {
  char *p;
  p = "hello";
  return strlen(p) - 5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kill_group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <kill@plt>
  nop
  leave
  ret
```

assistant: ```c
void kill_group(pid_t pid, int signum) {
  kill(pid, signum);
  signal(signum, SIG_IGN);
  kill(0, signum);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kill_group>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <kill@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <signal@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <kill@plt>
  pop    %rbx
  ret
```

assistant: ```c
void kill_group(pid_t pid, int signum) {
  kill(pid, signum);
  signal(signum, SIG_IGN);
  kill(0, signum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<kill_group>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <kill@plt>
  mov    D7(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <signal@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  jmp    1070 <kill@plt>
```

assistant: ```c
void kill_group(pid_t pid, int signum) {
  kill(pid, signum);
  signal(signum, SIG_IGN);
  kill(0, signum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kill_group>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <kill@plt>
  mov    D7(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <signal@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  jmp    1070 <kill@plt>
```

assistant: ```c
void kill_group(pid_t pid, int signum) {
  kill(pid, signum);
  signal(signum, SIG_IGN);
  kill(0, signum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DINT_TO_INT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x7fff,-0x14(%rbp)
  jle    L3
  movw   $0x7fff,-0x2(%rbp)
  jmp    L26
L3:
  cmpl   $0xffff8001,-0x14(%rbp)
  jge    L30
  movw   $0x8001,-0x2(%rbp)
  jmp    L26
L30:
  mov    -0x14(%rbp),%eax
  mov    %ax,-0x2(%rbp)
L26:
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short DINT_TO_INT(int var) {
  short newvar;
  if (var > 32767)
    newvar = 32767;
  else if (var < -32767)
    newvar = -32767;
  else
    newvar = (short)var;
  return newvar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DINT_TO_INT>:
  endbr64
  mov    $0x7fff,%eax
  cmp    $0x7fff,%edi
  jg     L9
  cmp    $0xffff8001,%edi
  mov    $0xffff8001,%eax
  cmovge %edi,%eax
L9:
  ret
```

assistant: ```c
short DINT_TO_INT(int var) {
  short newvar;
  if (var > 32767)
    newvar = 32767;
  else if (var < -32767)
    newvar = -32767;
  else
    newvar = (short)var;
  return newvar;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DINT_TO_INT>:
  endbr64
  mov    $0x7fff,%eax
  cmp    $0x7fff,%edi
  jg     L3
  cmp    $0xffff8001,%edi
  mov    $0xffff8001,%eax
  cmovge %edi,%eax
L3:
  ret
```

assistant: ```c
short DINT_TO_INT(int var) {
  short newvar;
  if (var > 32767)
    newvar = 32767;
  else if (var < -32767)
    newvar = -32767;
  else
    newvar = (short)var;
  return newvar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DINT_TO_INT>:
  endbr64
  mov    $0x7fff,%eax
  cmp    $0x7fff,%edi
  jg     L0
  cmp    $0xffff8001,%edi
  mov    $0xffff8001,%eax
  cmovge %edi,%eax
L0:
  ret
```

assistant: ```c
short DINT_TO_INT(int var) {
  short newvar;
  if (var > 32767)
    newvar = 32767;
  else if (var < -32767)
    newvar = -32767;
  else
    newvar = (short)var;
  return newvar;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rsync_patch_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
struct rsync_patch *rsync_patch_new(char *basefile, int outfd) {
  basefile = basefile;
  outfd = outfd;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rsync_patch_new>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct rsync_patch *rsync_patch_new(char *basefile, int outfd) {
  basefile = basefile;
  outfd = outfd;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rsync_patch_new>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct rsync_patch *rsync_patch_new(char *basefile, int outfd) {
  basefile = basefile;
  outfd = outfd;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rsync_patch_new>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct rsync_patch *rsync_patch_new(char *basefile, int outfd) {
  basefile = basefile;
  outfd = outfd;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L46
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L46
  cmpq   $0x0,-0x28(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L37
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  jmp    L20
L37:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
L20:
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L43
L46:
  mov    -0x28(%rbp),%rax
  jmp    L5
L43:
  cmpl   $0x0,-0x14(%rbp)
  je     L16
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L16:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *Strcat(char *left, const char *right) {
  int zero = 0;
  unsigned size;
  if ((right == (char *)NULL) || (*right == '\0') || ((left = (char *)((zero = (left == (char *)NULL)) ? malloc(size = strlen(right) + 1) : realloc(left, size = strlen(left) + strlen(right) + 1))) == (char *)NULL)) {
    return (left);
  }
  if (zero) {
    memset(left, 0, size);
  }
  return (strcat(left, right));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Strcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rsi,%rsi
  je     L3
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  cmpb   $0x0,(%rsi)
  je     L66
  test   %rdi,%rdi
  je     L7
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L66
L46:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L66:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L66
  mov    %r12d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L46
L3:
  mov    %rdi,%rbp
  jmp    L66
```

assistant: ```c
char *Strcat(char *left, const char *right) {
  int zero = 0;
  unsigned size;
  if ((right == (char *)NULL) || (*right == '\0') || ((left = (char *)((zero = (left == (char *)NULL)) ? malloc(size = strlen(right) + 1) : realloc(left, size = strlen(left) + strlen(right) + 1))) == (char *)NULL)) {
    return (left);
  }
  if (zero) {
    memset(left, 0, size);
  }
  return (strcat(left, right));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Strcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L46
  cmpb   $0x0,(%rsi)
  mov    %rsi,%r12
  je     L46
  test   %rdi,%rdi
  je     L54
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L29
L51:
  add    $0x18,%rsp
  mov    %r12,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <strcat@plt>
  nopl   0x0(%rax,%rax,1)
L46:
  add    $0x18,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L54:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L4
L29:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,0x8(%rsp)
  call   <memset@plt>
  mov    0x8(%rsp),%rdi
  jmp    L51
```

assistant: ```c
char *Strcat(char *left, const char *right) {
  int zero = 0;
  unsigned size;
  if ((right == (char *)NULL) || (*right == '\0') || ((left = (char *)((zero = (left == (char *)NULL)) ? malloc(size = strlen(right) + 1) : realloc(left, size = strlen(left) + strlen(right) + 1))) == (char *)NULL)) {
    return (left);
  }
  if (zero) {
    memset(left, 0, size);
  }
  return (strcat(left, right));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Strcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L12
  cmpb   $0x0,(%rsi)
  mov    %rsi,%r12
  je     L12
  test   %rdi,%rdi
  je     L56
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L44
L28:
  add    $0x18,%rsp
  mov    %r12,%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <strcat@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x18,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L56:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L7
L44:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,0x8(%rsp)
  call   <memset@plt>
  mov    0x8(%rsp),%rdi
  jmp    L28
```

assistant: ```c
char *Strcat(char *left, const char *right) {
  int zero = 0;
  unsigned size;
  if ((right == (char *)NULL) || (*right == '\0') || ((left = (char *)((zero = (left == (char *)NULL)) ? malloc(size = strlen(right) + 1) : realloc(left, size = strlen(left) + strlen(right) + 1))) == (char *)NULL)) {
    return (left);
  }
  if (zero) {
    memset(left, 0, size);
  }
  return (strcat(left, right));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L14
  cmpq   $0x0,-0x20(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L37
L14:
  cmpq   $0x0,-0x18(%rbp)
  jne    L48
  mov    $0xffffffff,%eax
  jmp    L37
L48:
  cmpq   $0x0,-0x20(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L37
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L76
  movzbl -0x2(%rbp),%eax
  movzbl -0x1(%rbp),%edx
  sub    %edx,%eax
  jmp    L37
L76:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L1
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  unsigned char u1, u2;
  if (!s1 && !s2)
    return 0;
  if (!s1)
    return -1;
  if (!s2)
    return 1;
  for (; n--; s1++, s2++) {
    u1 = *(unsigned char *)s1;
    u2 = *(unsigned char *)s2;
    if (u1 != u2)
      return (u1 - u2);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L25
  mov    $0x0,%eax
L15:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L11
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L15
  mov    $0x0,%eax
  ret
L11:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  unsigned char u1, u2;
  if (!s1 && !s2)
    return 0;
  if (!s1)
    return -1;
  if (!s2)
    return 1;
  for (; n--; s1++, s2++) {
    u1 = *(unsigned char *)s1;
    u2 = *(unsigned char *)s2;
    if (u1 != u2)
      return (u1 - u2);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L3
  xor    %eax,%eax
  jmp    L17
  nopl   (%rax)
L20:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L3
L17:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L20
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  unsigned char u1, u2;
  if (!s1 && !s2)
    return 0;
  if (!s1)
    return -1;
  if (!s2)
    return 1;
  for (; n--; s1++, s2++) {
    u1 = *(unsigned char *)s1;
    u2 = *(unsigned char *)s2;
    if (u1 != u2)
      return (u1 - u2);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L1
  xor    %eax,%eax
  jmp    L38
  nopl   (%rax)
L12:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L1
L38:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L12
  movzbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  unsigned char u1, u2;
  if (!s1 && !s2)
    return 0;
  if (!s1)
    return -1;
  if (!s2)
    return 1;
  for (; n--; s1++, s2++) {
    u1 = *(unsigned char *)s1;
    u2 = *(unsigned char *)s2;
    if (u1 != u2)
      return (u1 - u2);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7c(%rbp)
  movl   $0x64,-0x78(%rbp)
  jmp    L8
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x74(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x74(%rbp)
  je     L30
  cmpl   $0xa,-0x74(%rbp)
  je     L49
  mov    -0x7c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x7c(%rbp)
  mov    -0x74(%rbp),%edx
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
L8:
  mov    -0x78(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x7c(%rbp)
  jl     L11
  jmp    L26
L30:
  nop
  jmp    L26
L49:
  nop
L26:
  mov    -0x7c(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i = 0, lim = 100, c;
  char s[100];
  while (i < (lim - 1)) {
    c = getchar();
    if (c == EOF)
      break;
    else if (c == '\n')
      break;
    s[i++] = c;
  }
  s[i] = '\0';
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x63,%ebx
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D8(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L29
  cmp    $0xa,%eax
  je     L29
  sub    $0x1,%ebx
  jne    L21
L29:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i = 0, lim = 100, c;
  char s[100];
  while (i < (lim - 1)) {
    c = getchar();
    if (c == EOF)
      break;
    else if (c == '\n')
      break;
    s[i++] = c;
  }
  s[i] = '\0';
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbp
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L15:
  cmp    $0xa,%eax
  je     L8
  sub    $0x1,%ebx
  je     L8
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L15
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 0, lim = 100, c;
  char s[100];
  while (i < (lim - 1)) {
    c = getchar();
    if (c == EOF)
      break;
    else if (c == '\n')
      break;
    s[i++] = c;
  }
  s[i] = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x63,%ebx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbp
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0xa,%eax
  je     L3
  sub    $0x1,%ebx
  je     L3
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L23
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = 0, lim = 100, c;
  char s[100];
  while (i < (lim - 1)) {
    c = getchar();
    if (c == EOF)
      break;
    else if (c == '\n')
      break;
    s[i++] = c;
  }
  s[i] = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_ldiv5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  addl   $0x2,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L1:
  mov    -0x14(%rbp),%eax
  cltq
  lea    D0(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %edx,%esi
  sub    %eax,%esi
  mov    -0x14(%rbp),%eax
  cltq
  lea    D0(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L6:
  cmpl   $0x2,-0x14(%rbp)
  jle    L1
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0:  

assistant: ```c
void _ldiv5(uint64_t *v) {
  uint32_t i, hi;
  uint64_t rem = *v, quot = 0U, q;
  static const char shifts[] = {32, 3, 0};
  rem += 2;
  for (i = 0U; i < 3; i++) {
    hi = rem >> shifts[i];
    q = (uint64_t)(hi / 5) << shifts[i];
    rem -= q * 5;
    quot += q;
  }
  *v = quot;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ldiv5>:
  endbr64
  mov    %rdi,%rsi
  mov    (%rdi),%eax
  lea    0x2(%rax),%edi
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  shl    %cl,%edx
  lea    (%rdx,%rdx,4),%eax
  sub    %eax,%edi
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0x3,%eax
  cltq
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    0x0(,%rax,8),%edi
  add    %edi,%edx
  shl    $0x5,%eax
  add    %edi,%eax
  sub    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  add    %edx,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void _ldiv5(uint64_t *v) {
  uint32_t i, hi;
  uint64_t rem = *v, quot = 0U, q;
  static const char shifts[] = {32, 3, 0};
  rem += 2;
  for (i = 0U; i < 3; i++) {
    hi = rem >> shifts[i];
    q = (uint64_t)(hi / 5) << shifts[i];
    rem -= q * 5;
    quot += q;
  }
  *v = quot;
}
```