ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hamiltonian_matching>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L18:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L18
  mov    -0x28(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <permutation@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <matching_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const struct matching *hamiltonian_matching(int t, int n) {
  int i;
  int *v;
  v = malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    v[i] = i;
  permutation(t, v, n);
  const struct matching *res = matching_new(n, v);
  free(v);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hamiltonian_matching>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jle    L17
  mov    %ebp,%edx
  mov    $0x0,%eax
L11:
  mov    %eax,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
L17:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <permutation@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <matching_new@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const struct matching *hamiltonian_matching(int t, int n) {
  int i;
  int *v;
  v = malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    v[i] = i;
  permutation(t, v, n);
  const struct matching *res = matching_new(n, v);
  free(v);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hamiltonian_matching>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  lea    0x0(,%rbx,4),%edi
  mov    %rbx,%r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L5
  xor    %eax,%eax
  nopl   0x0(%rax)
L18:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L18
L5:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <permutation@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <matching_new@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const struct matching *hamiltonian_matching(int t, int n) {
  int i;
  int *v;
  v = malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    v[i] = i;
  permutation(t, v, n);
  const struct matching *res = matching_new(n, v);
  free(v);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hamiltonian_matching>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  lea    0x0(,%rsi,4),%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L69
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L62
  mov    %ebp,%edx
  movdqa D9(%rip),%xmm0
  movdqa D7(%rip),%xmm2
  mov    %r12,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r12,%rdx
  nopl   0x0(%rax)
L60:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L60
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bpl
  je     L69
L14:
  movslq %eax,%rdx
  mov    %eax,(%r12,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L69
  add    $0x2,%eax
  mov    %edx,0x4(%r12,%rcx,1)
  cmp    %eax,%ebp
  jle    L69
  mov    %eax,0x8(%r12,%rcx,1)
L69:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <permutation@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <matching_new@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  xor    %eax,%eax
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D7
type_guessed: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
const struct matching *hamiltonian_matching(int t, int n) {
  int i;
  int *v;
  v = malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    v[i] = i;
  permutation(t, v, n);
  const struct matching *res = matching_new(n, v);
  free(v);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<isBeforeSignedInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L40
L5:
  cmpl   $0x0,-0x4(%rbp)
  jns    L66
  cmpl   $0x0,-0x8(%rbp)
  js     L64
L66:
  cmpl   $0x0,-0x4(%rbp)
  js     L17
  cmpl   $0x0,-0x8(%rbp)
  js     L17
L64:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  jmp    L40
L17:
  mov    -0xc(%rbp),%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int isBeforeSignedInt(int numA, int numB, int ambiguousCase) {
  if (numA == numB) {
    return 0;
  }
  if ((numA < 0 && numB < 0) || (numA >= 0 && numB >= 0)) {
    return numA < numB;
  } else {
    return ambiguousCase;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isBeforeSignedInt>:
  endbr64
  mov    $0x0,%eax
  cmp    %esi,%edi
  je     L15
  mov    %edx,%eax
  mov    %edi,%ecx
  xor    %esi,%ecx
  js     L15
  cmp    %esi,%edi
  setl   %al
  movzbl %al,%eax
L15:
  ret
```

assistant: ```c
int isBeforeSignedInt(int numA, int numB, int ambiguousCase) {
  if (numA == numB) {
    return 0;
  }
  if ((numA < 0 && numB < 0) || (numA >= 0 && numB >= 0)) {
    return numA < numB;
  } else {
    return ambiguousCase;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isBeforeSignedInt>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  je     L9
  mov    %edi,%ecx
  mov    %edx,%eax
  xor    %esi,%ecx
  js     L9
  xor    %eax,%eax
  cmp    %esi,%edi
  setl   %al
L9:
  ret
```

assistant: ```c
int isBeforeSignedInt(int numA, int numB, int ambiguousCase) {
  if (numA == numB) {
    return 0;
  }
  if ((numA < 0 && numB < 0) || (numA >= 0 && numB >= 0)) {
    return numA < numB;
  } else {
    return ambiguousCase;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isBeforeSignedInt>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  je     L3
  mov    %edi,%ecx
  mov    %edx,%eax
  xor    %esi,%ecx
  js     L3
  xor    %eax,%eax
  cmp    %esi,%edi
  setl   %al
L3:
  ret
```

assistant: ```c
int isBeforeSignedInt(int numA, int numB, int ambiguousCase) {
  if (numA == numB) {
    return 0;
  }
  if ((numA < 0 && numB < 0) || (numA >= 0 && numB >= 0)) {
    return numA < numB;
  } else {
    return ambiguousCase;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L34
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  jmp    L38
L34:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  lea    D20(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x3,-0x10(%rbp)
  jmp    L6
L38:
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x5,-0x10(%rbp)
  nop
L6:
  jmp    L44
L49:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  subl   $0x1,-0x10(%rbp)
L44:
  cmpl   $0x0,-0x10(%rbp)
  jg     L49
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D0: fork program stating


tool: D10: fork failed

tool: D20: This is the child

tool: D2: This is the parent

assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program stating\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    n = 3;
    break;
  default:
    message = "This is the parent";
    n = 5;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L17
  cmp    $0x1,%eax
  sbb    %ebx,%ebx
  and    $0xfffffffe,%ebx
  add    $0x5,%ebx
  test   %eax,%eax
  lea    D0(%rip),%rbp
  lea    D43(%rip),%rax
  cmovne %rax,%rbp
L6:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D20(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    $0x3,%ebx
  lea    D0(%rip),%rbp
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D43
type: string
name: disassemble_data
arguments: data_label: D20
type: string

tool: D10: fork program stating


tool: D0: This is the child

tool: D43: This is the parent

tool: D20: fork failed

assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program stating\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    n = 3;
    break;
  default:
    message = "This is the parent";
    n = 5;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L0
  cmp    $0x1,%eax
  lea    D33(%rip),%rbp
  sbb    %ebx,%ebx
  and    $0xfffffffe,%ebx
  add    $0x5,%ebx
  test   %eax,%eax
  lea    D2(%rip),%rax
  cmovne %rax,%rbp
  nop
L10:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L10
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D43(%rip),%rdi
  mov    $0x3,%ebx
  lea    D33(%rip),%rbp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D43
type: string

tool: D35: fork program stating


tool: D33: This is the child

tool: D2: This is the parent

tool: D43: fork failed

assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program stating\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    n = 3;
    break;
  default:
    message = "This is the parent";
    n = 5;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L25
  cmp    $0x1,%eax
  lea    D18(%rip),%rbp
  sbb    %ebx,%ebx
  and    $0xfffffffe,%ebx
  add    $0x5,%ebx
  test   %eax,%eax
  lea    D14(%rip),%rax
  cmovne %rax,%rbp
  nop
L10:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L10
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  lea    D41(%rip),%rdi
  mov    $0x3,%ebx
  lea    D18(%rip),%rbp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D41
data_type: string

tool: D38: fork program stating


tool: D18: This is the child

tool: D14: This is the parent

tool: D41: fork failed

assistant: ```c
int main() {
  pid_t pid;
  char *message;
  int n;
  printf("fork program stating\n");
  pid = fork();
  switch (pid) {
  case -1:
    perror("fork failed");
    exit(1);
  case 0:
    message = "This is the child";
    n = 3;
    break;
  default:
    message = "This is the parent";
    n = 5;
    break;
  }
  for (; n > 0; n--) {
    puts(message);
    sleep(1);
  }
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L12:
  mov    -0x20(%rbp),%rdx
  lea    -0x16(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0xe,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L3
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,%ecx
  lea    -0x16(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L3:
  nop
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D25:  r

tool: D0: froot.txt

tool: D5: 
	Error reading file!

tool: D9: %3d: %s


assistant: ```c
int main() {
  char fruit[14];
  FILE *myfile;
  int x;
  if (!(myfile = fopen("froot.txt", " r"))) {
    puts("\n\tError reading file!");
    return 1;
  }
  while (!0) {
    x = fread(&fruit, 14, 1, myfile);
    if (x == 0)
      break;
    printf("%3d: %s\n", ftell(myfile), fruit);
  }
  fclose(myfile);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D20(%rip),%r12
  test   %rax,%rax
  jne    L36
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  jmp    L29
L1:
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %eax,%esi
  lea    0xa(%rsp),%rdx
  mov    %r12,%rdi
  call   <printf@plt>
L36:
  lea    0xa(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0xe,%esi
  call   <fread@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L1
  mov    %rbp,%rdi
  call   <fclose@plt>
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D31
type_infered: string

tool: D13:  r

tool: D10: froot.txt

tool: D20: %3d: %s


tool: D31: 
	Error reading file!

assistant: ```c
int main() {
  char fruit[14];
  FILE *myfile;
  int x;
  if (!(myfile = fopen("froot.txt", " r"))) {
    puts("\n\tError reading file!");
    return 1;
  }
  while (!0) {
    x = fread(&fruit, 14, 1, myfile);
    if (x == 0)
      break;
    printf("%3d: %s\n", ftell(myfile), fruit);
  }
  fclose(myfile);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D37(%rip),%rsi
  lea    D34(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%rbx
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L4
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L13:
  call   <ftell@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L4:
  mov    %rbx,%rdi
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0xe,%esi
  call   <fread@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L13
  call   <fclose@plt>
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  lea    D2(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L28
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D37
type_guessed: string
name: read_data
arguments: data_tag: D34
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D37:  r

tool: D34: froot.txt

tool: D25: %3d: %s


tool: D2: 
	Error reading file!

assistant: ```c
int main() {
  char fruit[14];
  FILE *myfile;
  int x;
  if (!(myfile = fopen("froot.txt", " r"))) {
    puts("\n\tError reading file!");
    return 1;
  }
  while (!0) {
    x = fread(&fruit, 14, 1, myfile);
    if (x == 0)
      break;
    printf("%3d: %s\n", ftell(myfile), fruit);
  }
  fclose(myfile);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%rsi
  lea    D28(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%rbx
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L44
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L16:
  call   <ftell@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L44:
  mov    %rbx,%rdi
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0xe,%esi
  call   <fread@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L16
  call   <fclose@plt>
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  lea    D16(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L35
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type: string
name: retrieve_data
arguments: tag: D28
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D16
type: string

tool: D21:  r

tool: D28: froot.txt

tool: D17: %3d: %s


tool: D16: 
	Error reading file!

assistant: ```c
int main() {
  char fruit[14];
  FILE *myfile;
  int x;
  if (!(myfile = fopen("froot.txt", " r"))) {
    puts("\n\tError reading file!");
    return 1;
  }
  while (!0) {
    x = fread(&fruit, 14, 1, myfile);
    if (x == 0)
      break;
    printf("%3d: %s\n", ftell(myfile), fruit);
  }
  fclose(myfile);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mem_rcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  jmp    L4
L6:
  subq   $0x4,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
L4:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mem_rcopy(uint8_t *dst, uint8_t const *src, uint16_t len) {
  src += len;
  while (len--) {
    *dst++ = *--src;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_rcopy>:
  endbr64
  movslq %edx,%rax
  lea    (%rsi,%rax,4),%rax
  test   %edx,%edx
  je     L4
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rcx
L16:
  sub    $0x4,%rax
  add    $0x4,%rdi
  mov    (%rax),%edx
  mov    %edx,-0x4(%rdi)
  cmp    %rcx,%rdi
  jne    L16
L4:
  ret
```

assistant: ```c
void mem_rcopy(uint8_t *dst, uint8_t const *src, uint16_t len) {
  src += len;
  while (len--) {
    *dst++ = *--src;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_rcopy>:
  endbr64
  movslq %edx,%rax
  lea    (%rsi,%rax,4),%rax
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rcx
  nopl   (%rax)
L16:
  mov    -0x4(%rax),%edx
  add    $0x4,%rdi
  sub    $0x4,%rax
  mov    %edx,-0x4(%rdi)
  cmp    %rcx,%rdi
  jne    L16
L8:
  ret
```

assistant: ```c
void mem_rcopy(uint8_t *dst, uint8_t const *src, uint16_t len) {
  src += len;
  while (len--) {
    *dst++ = *--src;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_rcopy>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%rcx
  mov    %rax,%rdi
  shl    $0x2,%rax
  lea    (%rsi,%rax,1),%r8
  test   %edi,%edi
  je     L69
  mov    %edi,%r11d
  mov    %rax,%rdx
  push   %rbx
  lea    0x0(,%r11,4),%r9
  sub    %r9,%rdx
  lea    (%rcx,%r9,1),%rbx
  add    %rsi,%rdx
  cmp    %rdx,%rbx
  setbe  %dl
  cmp    %rcx,%r8
  setbe  %r9b
  or     %r9b,%dl
  je     L80
  lea    -0x1(%rdi),%r10d
  cmp    $0x2,%r10d
  jbe    L80
  mov    %edi,%r9d
  lea    -0x10(%rsi,%rax,1),%rsi
  mov    %rcx,%rdx
  shr    $0x2,%r9d
  lea    -0x10(%rsi),%rax
  lea    -0x1(%r9),%r11d
  mov    %rax,%r9
  shl    $0x4,%r11
  sub    %r11,%r9
  jmp    L22
  nopl   (%rax)
L33:
  sub    $0x10,%rax
L22:
  movdqu (%rsi),%xmm0
  add    $0x10,%rdx
  mov    %rax,%rsi
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rax,%r9
  jne    L33
  mov    %edi,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%eax
  sub    %edx,%r10d
  shl    $0x2,%rax
  add    %rax,%rcx
  cmp    %edx,%edi
  je     L38
  sub    %rax,%r8
  mov    -0x4(%r8),%edx
  mov    %edx,(%rcx)
  test   %r10d,%r10d
  je     L38
  mov    -0x8(%r8),%edx
  mov    %edx,0x4(%rcx)
  cmp    $0x1,%r10d
  je     L38
  mov    -0xc(%r8),%eax
  mov    %eax,0x8(%rcx)
L38:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L80:
  lea    (%rcx,%r11,4),%rdx
  nopl   0x0(%rax)
L36:
  mov    -0x4(%r8),%eax
  add    $0x4,%rcx
  sub    $0x4,%r8
  mov    %eax,-0x4(%rcx)
  cmp    %rcx,%rdx
  jne    L36
  pop    %rbx
  ret
  xchg   %ax,%ax
L69:
  ret
```

assistant: ```c
void mem_rcopy(uint8_t *dst, uint8_t const *src, uint16_t len) {
  src += len;
  while (len--) {
    *dst++ = *--src;
  }
}
```