ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generate_test_frame_dynamic_method>:
  endbr64
  lea    D9(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: return -1;

assistant: ```c
void generate_test_frame_dynamic_method(FILE *stream, struct dynamic_packet_test_function_impl_gen_struct *record, unsigned int indent) {
  (void)(record);
  (void)(indent);
  fprintf(stream, "return -1;");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generate_test_frame_dynamic_method>:
  endbr64
  lea    D5(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: return -1;

assistant: ```c
void generate_test_frame_dynamic_method(FILE *stream, struct dynamic_packet_test_function_impl_gen_struct *record, unsigned int indent) {
  (void)(record);
  (void)(indent);
  fprintf(stream, "return -1;");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ScaleImage24RGB>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  imul   %edi,%edx
  mov    %r9d,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  imul   %edi,%ecx
  mov    0x38(%rsp),%esi
  sub    %ecx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  lea    (%rdx,%rbx,1),%r15d
  lea    (%rcx,%rax,1),%r11d
  cmp    %r11d,%eax
  jge    L99
  mov    %eax,%r10d
  lea    (%r9,%r9,2),%r14d
  movslq %r14d,%r14
  lea    -0x1(%rdx),%edx
  imul   %eax,%r9d
  lea    (%r9,%rbx,1),%eax
  lea    (%rax,%rax,2),%eax
  cltq
  lea    0x3(%rdx,%rdx,2),%rcx
  add    %rcx,%rax
  add    %rax,%r8
  mov    $0x0,%esi
  mov    $0x0,%ecx
  mov    $0x0,%r13d
  lea    0x1(%rdx),%r9
  lea    0x0(,%r9,4),%rax
  sub    %rax,%r9
  jmp    L90
L11:
  cmp    %r8,%rax
  je     L21
L20:
  movzbl (%rdx),%esi
  mov    %sil,(%rax)
  movzbl 0x1(%rdx),%esi
  mov    %sil,0x1(%rax)
  add    $0x3,%rax
  movzbl 0x2(%rdx),%esi
  mov    %sil,-0x1(%rax)
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L11
  add    $0x3,%rdx
  mov    $0x0,%ecx
  jmp    L11
L21:
  mov    -0x4(%rsp),%esi
L79:
  add    $0x1,%esi
  cmp    %esi,%edi
  je     L44
L9:
  add    $0x1,%r10d
  add    %r14,%r8
  cmp    %r10d,%r11d
  je     L99
L90:
  lea    (%r9,%r8,1),%rax
  mov    %r12d,%edx
  imul   %r13d,%edx
  lea    (%rdx,%rdx,2),%edx
  movslq %edx,%rdx
  add    %rbp,%rdx
  cmp    %r15d,%ebx
  jge    L79
  mov    %esi,-0x4(%rsp)
  jmp    L20
L44:
  add    $0x1,%r13d
  mov    $0x0,%esi
  jmp    L9
L99:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ScaleImage24RGB(int zoom, unsigned char *srcbuf, int srcw, int srch, unsigned char *dstbuf, int dstw, int dsth) {
  int dest_x_offset = (dstw - (srcw * zoom)) / 2;
  int dest_y_offset = (dsth - (srch * zoom)) / 2;
  int dest_x_end = dest_x_offset + srcw * zoom;
  int dest_y_end = dest_y_offset + srch * zoom;
  int srcx = 0;
  int srcy = 0;
  int srcx_inc_count = 0;
  int srcy_inc_count = 0;
  int desty = dest_y_offset;
  for (; desty < dest_y_end; desty++) {
    srcx = 0;
    int destx = dest_x_offset;
    unsigned char *dstline = &(dstbuf[(desty * dstw + destx) * 3]);
    unsigned char *srcline = &(srcbuf[(srcy * srcw + srcx) * 3]);
    for (; destx < dest_x_end; destx++) {
      *dstline++ = *(srcline + 0);
      *dstline++ = *(srcline + 1);
      *dstline++ = *(srcline + 2);
      srcx_inc_count++;
      if (srcx_inc_count == zoom) {
        srcline += 3;
        srcx_inc_count = 0;
        srcx++;
      }
    }
    srcy_inc_count++;
    if (srcy_inc_count == zoom) {
      srcy_inc_count = 0;
      srcy++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ScaleImage24RGB>:
  endbr64
  push   %r15
  mov    %r9d,%eax
  imul   %edi,%ecx
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  imul   %edi,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    %edx,%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  mov    0x38(%rsp),%eax
  sar    %ebx
  sub    %ecx,%eax
  lea    (%rdx,%rbx,1),%r15d
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  lea    (%rcx,%rsi,1),%r11d
  cmp    %r11d,%esi
  jge    L20
  lea    (%r9,%r9,2),%r14d
  lea    -0x1(%rdx),%r10d
  xor    %ecx,%ecx
  xor    %r13d,%r13d
  imul   %esi,%r9d
  add    $0x1,%r10
  movslq %r14d,%r14
  lea    (%r10,%r10,2),%rdx
  lea    (%r9,%rbx,1),%eax
  xor    %r9d,%r9d
  lea    (%rax,%rax,2),%eax
  cltq
  add    %rdx,%rax
  add    %rax,%r8
  lea    0x0(,%r10,4),%rax
  sub    %rax,%r10
  nopl   0x0(%rax)
L54:
  mov    %r12d,%edx
  lea    (%r10,%r8,1),%rax
  imul   %r13d,%edx
  lea    (%rdx,%rdx,2),%edx
  movslq %edx,%rdx
  add    %rbp,%rdx
  cmp    %r15d,%ebx
  jge    L15
  mov    %esi,-0x4(%rsp)
  nopl   (%rax)
L25:
  movzbl (%rdx),%esi
  add    $0x3,%rax
  add    $0x1,%ecx
  mov    %sil,-0x3(%rax)
  movzbl 0x1(%rdx),%esi
  mov    %sil,-0x2(%rax)
  movzbl 0x2(%rdx),%esi
  mov    %sil,-0x1(%rax)
  cmp    %ecx,%edi
  jne    L37
  add    $0x3,%rdx
  xor    %ecx,%ecx
L37:
  cmp    %r8,%rax
  jne    L25
  mov    -0x4(%rsp),%esi
L15:
  add    $0x1,%r9d
  cmp    %r9d,%edi
  jne    L2
  add    $0x1,%r13d
  xor    %r9d,%r9d
L2:
  add    $0x1,%esi
  add    %r14,%r8
  cmp    %esi,%r11d
  jne    L54
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ScaleImage24RGB(int zoom, unsigned char *srcbuf, int srcw, int srch, unsigned char *dstbuf, int dstw, int dsth) {
  int dest_x_offset = (dstw - (srcw * zoom)) / 2;
  int dest_y_offset = (dsth - (srch * zoom)) / 2;
  int dest_x_end = dest_x_offset + srcw * zoom;
  int dest_y_end = dest_y_offset + srch * zoom;
  int srcx = 0;
  int srcy = 0;
  int srcx_inc_count = 0;
  int srcy_inc_count = 0;
  int desty = dest_y_offset;
  for (; desty < dest_y_end; desty++) {
    srcx = 0;
    int destx = dest_x_offset;
    unsigned char *dstline = &(dstbuf[(desty * dstw + destx) * 3]);
    unsigned char *srcline = &(srcbuf[(srcy * srcw + srcx) * 3]);
    for (; destx < dest_x_end; destx++) {
      *dstline++ = *(srcline + 0);
      *dstline++ = *(srcline + 1);
      *dstline++ = *(srcline + 2);
      srcx_inc_count++;
      if (srcx_inc_count == zoom) {
        srcline += 3;
        srcx_inc_count = 0;
        srcx++;
      }
    }
    srcy_inc_count++;
    if (srcy_inc_count == zoom) {
      srcy_inc_count = 0;
      srcy++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ScaleImage24RGB>:
  endbr64
  push   %r14
  imul   %edi,%ecx
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %r9d,%edx
  imul   %edi,%esi
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    0x30(%rsp),%edx
  sar    %eax
  sub    %ecx,%edx
  mov    %edx,%r10d
  shr    $0x1f,%r10d
  add    %edx,%r10d
  lea    (%rsi,%rax,1),%edx
  sar    %r10d
  lea    (%rcx,%r10,1),%r11d
  cmp    %r11d,%r10d
  jge    L38
  cmp    %edx,%eax
  jge    L38
  lea    (%r9,%r9,2),%r14d
  lea    -0x1(%rsi),%r12d
  xor    %ecx,%ecx
  xor    %r13d,%r13d
  imul   %r10d,%r9d
  add    $0x1,%r12
  movslq %r14d,%r14
  lea    (%r12,%r12,2),%rdx
  add    %r9d,%eax
  xor    %r9d,%r9d
  lea    (%rax,%rax,2),%eax
  cltq
  add    %rdx,%rax
  add    %rax,%r8
  lea    0x0(,%r12,4),%rax
  sub    %rax,%r12
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %ebp,%edx
  lea    (%r12,%r8,1),%rax
  imul   %r13d,%edx
  lea    (%rdx,%rdx,2),%edx
  movslq %edx,%rdx
  add    %rbx,%rdx
  nopl   0x0(%rax,%rax,1)
L33:
  movzbl (%rdx),%esi
  add    $0x3,%rax
  add    $0x1,%ecx
  mov    %sil,-0x3(%rax)
  movzbl 0x1(%rdx),%esi
  mov    %sil,-0x2(%rax)
  movzbl 0x2(%rdx),%esi
  mov    %sil,-0x1(%rax)
  cmp    %edi,%ecx
  jne    L46
  add    $0x3,%rdx
  xor    %ecx,%ecx
L46:
  cmp    %r8,%rax
  jne    L33
  add    $0x1,%r9d
  cmp    %r9d,%edi
  jne    L36
  add    $0x1,%r13d
  xor    %r9d,%r9d
L36:
  add    $0x1,%r10d
  add    %r14,%r8
  cmp    %r10d,%r11d
  jne    L55
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void ScaleImage24RGB(int zoom, unsigned char *srcbuf, int srcw, int srch, unsigned char *dstbuf, int dstw, int dsth) {
  int dest_x_offset = (dstw - (srcw * zoom)) / 2;
  int dest_y_offset = (dsth - (srch * zoom)) / 2;
  int dest_x_end = dest_x_offset + srcw * zoom;
  int dest_y_end = dest_y_offset + srch * zoom;
  int srcx = 0;
  int srcy = 0;
  int srcx_inc_count = 0;
  int srcy_inc_count = 0;
  int desty = dest_y_offset;
  for (; desty < dest_y_end; desty++) {
    srcx = 0;
    int destx = dest_x_offset;
    unsigned char *dstline = &(dstbuf[(desty * dstw + destx) * 3]);
    unsigned char *srcline = &(srcbuf[(srcy * srcw + srcx) * 3]);
    for (; destx < dest_x_end; destx++) {
      *dstline++ = *(srcline + 0);
      *dstline++ = *(srcline + 1);
      *dstline++ = *(srcline + 2);
      srcx_inc_count++;
      if (srcx_inc_count == zoom) {
        srcline += 3;
        srcx_inc_count = 0;
        srcx++;
      }
    }
    srcy_inc_count++;
    if (srcy_inc_count == zoom) {
      srcy_inc_count = 0;
      srcy++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bombs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <rexit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: Error in TOS program, %d bombs!


assistant: ```c
void bombs(int num) {
  printf("Error in TOS program, %d bombs!\n", num);
  rexit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bombs>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <rexit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: Error in TOS program, %d bombs!


assistant: ```c
void bombs(int num) {
  printf("Error in TOS program, %d bombs!\n", num);
  rexit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bombs>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <rexit@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: Error in TOS program, %d bombs!


assistant: ```c
void bombs(int num) {
  printf("Error in TOS program, %d bombs!\n", num);
  rexit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bombs>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <rexit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: Error in TOS program, %d bombs!


assistant: ```c
void bombs(int num) {
  printf("Error in TOS program, %d bombs!\n", num);
  rexit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<list_split_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x0,%eax
  call   <list_create@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L85
L33:
  addq   $0x1,-0x20(%rbp)
L42:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L33
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L33
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L4
L56:
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L48
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L48
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
L48:
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_add@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L85:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  jmp    L93
L7:
  nop
L93:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct list *list_split_words(char *s) {
  struct list *result = list_create();
  char *p = s;
  char *q;
  while (*p) {
    while (*p == ' ' || *p == '\t')
      p++;
    if (!*p)
      break;
    q = p + 1;
    while (!(*q == ' ' || *q == '\t' || *q == '\0'))
      q++;
    char *data = malloc((size_t)(q - p + 2));
    strncpy(data, p, (size_t)(q - p));
    data[q - p] = '\0';
    list_add(result, data);
    p = q;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_split_words>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <list_create@plt>
  mov    %rax,%r13
  cmpb   $0x0,(%rbx)
  jne    L38
L54:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    %rbx,%r14
  sub    %r12,%r14
  lea    0x2(%r14),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r14,1)
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <list_add@plt>
  cmpb   $0x0,(%rbx)
  je     L54
L38:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L15
  mov    %rbx,%r12
  cmp    $0x9,%al
  jne    L67
L15:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L15
  cmp    $0x9,%al
  je     L15
  mov    %rbx,%r12
L67:
  test   %al,%al
  je     L54
  lea    0x1(%r12),%rbx
  movzbl 0x1(%r12),%eax
  test   $0xdf,%al
  je     L28
  cmp    $0x9,%al
  je     L28
L79:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   $0xdf,%al
  je     L28
  cmp    $0x9,%al
  jne    L79
  jmp    L28
```

assistant: ```c
struct list *list_split_words(char *s) {
  struct list *result = list_create();
  char *p = s;
  char *q;
  while (*p) {
    while (*p == ' ' || *p == '\t')
      p++;
    if (!*p)
      break;
    q = p + 1;
    while (!(*q == ' ' || *q == '\t' || *q == '\0'))
      q++;
    char *data = malloc((size_t)(q - p + 2));
    strncpy(data, p, (size_t)(q - p));
    data[q - p] = '\0';
    list_add(result, data);
    p = q;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_split_words>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <list_create@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L106
  nopl   0x0(%rax)
L18:
  cmp    $0x20,%al
  je     L125
  cmp    $0x9,%al
  jne    L78
L125:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L125
  cmp    $0x9,%al
  je     L125
  test   %al,%al
  je     L106
L78:
  mov    %rbx,%r14
  add    $0x1,%rbx
  movzbl 0x1(%r14),%eax
  test   $0xdf,%al
  je     L4
  cmp    $0x9,%al
  jne    L47
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    $0x9,%al
  je     L115
L47:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   $0xdf,%al
  jne    L37
L115:
  mov    %rbx,%r13
  sub    %r14,%r13
  lea    0x2(%r13),%rdi
L7:
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x0(%rbp,%r13,1)
  call   <list_add@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L18
L106:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%r13d
  mov    $0x3,%edi
  jmp    L7
```

assistant: ```c
struct list *list_split_words(char *s) {
  struct list *result = list_create();
  char *p = s;
  char *q;
  while (*p) {
    while (*p == ' ' || *p == '\t')
      p++;
    if (!*p)
      break;
    q = p + 1;
    while (!(*q == ' ' || *q == '\t' || *q == '\0'))
      q++;
    char *data = malloc((size_t)(q - p + 2));
    strncpy(data, p, (size_t)(q - p));
    data[q - p] = '\0';
    list_add(result, data);
    p = q;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<list_split_words>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <list_create@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L104
  nopl   0x0(%rax)
L122:
  cmp    $0x20,%al
  je     L10
  cmp    $0x9,%al
  jne    L84
L10:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L10
  cmp    $0x9,%al
  je     L10
  test   %al,%al
  je     L104
L84:
  mov    %rbx,%r14
  add    $0x1,%rbx
  movzbl 0x1(%r14),%eax
  test   $0xdf,%al
  je     L71
  cmp    $0x9,%al
  jne    L52
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L44:
  cmp    $0x9,%al
  je     L82
L52:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   $0xdf,%al
  jne    L44
L82:
  mov    %rbx,%r13
  sub    %r14,%r13
  lea    0x2(%r13),%rdi
L97:
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x0(%rbp,%r13,1)
  call   <list_add@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L122
L104:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L71:
  mov    $0x1,%r13d
  mov    $0x3,%edi
  jmp    L97
```

assistant: ```c
struct list *list_split_words(char *s) {
  struct list *result = list_create();
  char *p = s;
  char *q;
  while (*p) {
    while (*p == ' ' || *p == '\t')
      p++;
    if (!*p)
      break;
    q = p + 1;
    while (!(*q == ' ' || *q == '\t' || *q == '\0'))
      q++;
    char *data = malloc((size_t)(q - p + 2));
    strncpy(data, p, (size_t)(q - p));
    data[q - p] = '\0';
    list_add(result, data);
    p = q;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2a2,-0x40(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x40(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void main() {
  int x;
  int y;
  int *p1;
  int **p2;
  int ***p3;
  int *q1;
  int **q2;
  int ***q3;
  x = 674;
  p1 = &x;
  p2 = &p1;
  p3 = &p2;
  q3 = p3;
  q2 = *q3;
  q1 = *q2;
  y = *q1;
  test(x == y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int x;
  int y;
  int *p1;
  int **p2;
  int ***p3;
  int *q1;
  int **q2;
  int ***q3;
  x = 674;
  p1 = &x;
  p2 = &p1;
  p3 = &p2;
  q3 = p3;
  q2 = *q3;
  q1 = *q2;
  y = *q1;
  test(x == y);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <test@plt>
```

assistant: ```c
void main() {
  int x;
  int y;
  int *p1;
  int **p2;
  int ***p3;
  int *q1;
  int **q2;
  int ***q3;
  x = 674;
  p1 = &x;
  p2 = &p1;
  p3 = &p2;
  q3 = p3;
  q2 = *q3;
  q1 = *q2;
  y = *q1;
  test(x == y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <test@plt>
```

assistant: ```c
void main() {
  int x;
  int y;
  int *p1;
  int **p2;
  int ***p3;
  int *q1;
  int **q2;
  int ***q3;
  x = 674;
  p1 = &x;
  p2 = &p1;
  p3 = &p2;
  q3 = p3;
  q2 = *q3;
  q1 = *q2;
  y = *q1;
  test(x == y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numOfCharInString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L10
L27:
  movsbq -0x1(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L26
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L26:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %al,-0x1(%rbp)
  jl     L27
  movzbl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
char numOfCharInString(const char *str, const char searchChar) {
  char num = 0;
  char i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (*(str + i) == searchChar) {
      num++;
    }
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numOfCharInString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L4
L9:
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  sete   %al
  add    %eax,%r13d
  add    $0x1,%ebx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L9
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char numOfCharInString(const char *str, const char searchChar) {
  char num = 0;
  char i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (*(str + i) == searchChar) {
      num++;
    }
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<numOfCharInString>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L19:
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  sete   %al
  add    $0x1,%ebx
  add    %eax,%r13d
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L19
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char numOfCharInString(const char *str, const char searchChar) {
  char num = 0;
  char i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (*(str + i) == searchChar) {
      num++;
    }
  }
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<numOfCharInString>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L11:
  movsbq %bl,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  sete   %al
  add    $0x1,%ebx
  add    %eax,%r13d
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L11
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char numOfCharInString(const char *str, const char searchChar) {
  char num = 0;
  char i = 0;
  for (i = 0; i < strlen(str); i++) {
    if (*(str + i) == searchChar) {
      num++;
    }
  }
  return num;
}
```