ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<print_escaped_char>:
  endbr64
  mov    %esi,%edx
  cmp    $0xa,%esi
  je     L24
  cmp    $0x5c,%esi
  je     L32
  cmp    $0x27,%esi
  je     L32
  lea    -0x20(%rsi),%eax
  cmp    $0x5e,%eax
  jbe    L1
  movzbl %sil,%edx
  lea    D14(%rip),%rsi
  jmp    1080 <fprintf@plt>
  nopl   (%rax)
L1:
  mov    %rdi,%rsi
  mov    %edx,%edi
  jmp    1070 <fputc@plt>
  nopw   0x0(%rax,%rax,1)
L32:
  lea    D26(%rip),%rsi
  jmp    1080 <fprintf@plt>
  nopl   0x0(%rax)
L24:
  mov    %rdi,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  jmp    1090 <fwrite@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D14: \x%02x

tool: D26: \%c

tool: D3: \n

assistant: ```c
void print_escaped_char(FILE *f, int c) {
  if (c == '\n')
    fputs("\\n", f);
  else if (c == '\\' || c == '\'')
    fprintf(f, "\\%c", c);
  else if (c < 0x20 || c >= 0x7f)
    fprintf(f, "\\x%02x", 0xff & c);
  else
    fputc(c, f);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prepare_for_next_level_down>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <remove_last_slack_variable@plt>
  mov    %ebx,%edi
  call   <syscon_remove_symbol_from_table@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  lea    0xf(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <define_output_file@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <read_named_start_without_solutions@plt>
  mov    $0x0,%eax
  call   <solcon_scan_solution_banner@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <create_cascade_homotopy@plt>
  mov    $0x0,%eax
  call   <write_standard_target_system@plt>
  mov    $0x0,%eax
  call   <write_standard_start_system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D67
data_type: string
name: extract_symbolic_data
arguments: data_label: D46
data_type: string
name: extract_symbolic_data
arguments: data_label: D56
data_type: string
name: extract_symbolic_data
arguments: data_label: D68
data_type: string

tool: D19: 
removing last slack variable first ...


tool: D14: 
now ready for the next level down ...


tool: D34: 
Reading the name of the file for the start system...

tool: D67: 
Give a string of characters : 

tool: D46: %s

tool: D56: %c

tool: D68: 
creating the cascade homotopy ...



assistant: ```c
int prepare_for_next_level_down(int dimension) {
  char start[80], ch;
  int n, fail;
  printf("\nremoving last slack variable first ...\n");
  remove_last_slack_variable();
  fail = syscon_remove_symbol_from_table(dimension);
  printf("\nnow ready for the next level down ...\n");
  printf("\nReading the name of the file for the start system...");
  printf("\nGive a string of characters : ");
  scanf("%s", start);
  scanf("%c", &ch);
  fail = define_output_file();
  n = (int)strlen(start);
  fail = read_named_start_without_solutions(n, start);
  fail = solcon_scan_solution_banner();
  printf("\ncreating the cascade homotopy ...\n\n");
  fail = create_cascade_homotopy();
  fail = write_standard_target_system();
  fail = write_standard_start_system();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prepare_for_next_level_down>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D42(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <remove_last_slack_variable@plt>
  mov    %ebp,%edi
  lea    0x10(%rsp),%rbp
  call   <syscon_remove_symbol_from_table@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  lea    0xf(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <define_output_file@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <read_named_start_without_solutions@plt>
  xor    %eax,%eax
  call   <solcon_scan_solution_banner@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <create_cascade_homotopy@plt>
  xor    %eax,%eax
  call   <write_standard_target_system@plt>
  xor    %eax,%eax
  call   <write_standard_start_system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D42
type_guessed: string
name: parse_data
arguments: label: D22
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D50
type_guessed: string
name: parse_data
arguments: label: D41
type_guessed: string

tool: D42: 
removing last slack variable first ...


tool: D22: 
now ready for the next level down ...


tool: D19: 
Reading the name of the file for the start system...

tool: D10: 
Give a string of characters : 

tool: D8: %s

tool: D50: %c

tool: D41: 
creating the cascade homotopy ...



assistant: ```c
int prepare_for_next_level_down(int dimension) {
  char start[80], ch;
  int n, fail;
  printf("\nremoving last slack variable first ...\n");
  remove_last_slack_variable();
  fail = syscon_remove_symbol_from_table(dimension);
  printf("\nnow ready for the next level down ...\n");
  printf("\nReading the name of the file for the start system...");
  printf("\nGive a string of characters : ");
  scanf("%s", start);
  scanf("%c", &ch);
  fail = define_output_file();
  n = (int)strlen(start);
  fail = read_named_start_without_solutions(n, start);
  fail = solcon_scan_solution_banner();
  printf("\ncreating the cascade homotopy ...\n\n");
  fail = create_cascade_homotopy();
  fail = write_standard_target_system();
  fail = write_standard_start_system();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prepare_for_next_level_down>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D10(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <remove_last_slack_variable@plt>
  mov    %ebp,%edi
  lea    0x10(%rsp),%rbp
  call   <syscon_remove_symbol_from_table@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  lea    0xf(%rsp),%rsi
  lea    D68(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <define_output_file@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <read_named_start_without_solutions@plt>
  xor    %eax,%eax
  call   <solcon_scan_solution_banner@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <create_cascade_homotopy@plt>
  xor    %eax,%eax
  call   <write_standard_target_system@plt>
  xor    %eax,%eax
  call   <write_standard_start_system@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D29
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D58
type_infered: string
name: retrieve_data
arguments: tag: D68
type_infered: string
name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D10: 
removing last slack variable first ...


tool: D13: 
now ready for the next level down ...


tool: D29: 
Reading the name of the file for the start system...

tool: D4: 
Give a string of characters : 

tool: D58: %s

tool: D68: %c

tool: D8: 
creating the cascade homotopy ...



assistant: ```c
int prepare_for_next_level_down(int dimension) {
  char start[80], ch;
  int n, fail;
  printf("\nremoving last slack variable first ...\n");
  remove_last_slack_variable();
  fail = syscon_remove_symbol_from_table(dimension);
  printf("\nnow ready for the next level down ...\n");
  printf("\nReading the name of the file for the start system...");
  printf("\nGive a string of characters : ");
  scanf("%s", start);
  scanf("%c", &ch);
  fail = define_output_file();
  n = (int)strlen(start);
  fail = read_named_start_without_solutions(n, start);
  fail = solcon_scan_solution_banner();
  printf("\ncreating the cascade homotopy ...\n\n");
  fail = create_cascade_homotopy();
  fail = write_standard_target_system();
  fail = write_standard_start_system();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hea_cq_timestamp_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  movq   $0xa,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3b9aca00,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x40,-0x8(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L17
L3:
  mov    -0x20(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hea_get_u64_bits@plt>
  test   %rax,%rax
  je     L1
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  add    %rax,-0x28(%rbp)
L1:
  addq   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L3
  mov    -0x18(%rbp),%rax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  leave
  ret
```

assistant: ```c
__u32 hea_cq_timestamp_ns(__u32 frac) {
  const __u32 log_prec = 10;
  const __u64 ns = 1000000000ULL << log_prec;
  const __u32 bits = sizeof(frac) * 8;
  __u64 ret = 0;
  __u32 i;
  for (i = 0; i < bits; i++) {
    if (hea_get_u64_bits(frac, i, i))
      ret += ns >> (i + 1);
  }
  return (__u32)((ret + (1UL << (log_prec - 1))) >> log_prec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hea_cq_timestamp_ns>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  movabs $0xee6b280000,%r13
  jmp    L39
L24:
  add    $0x1,%rbx
  cmp    $0x40,%rbx
  je     L25
L39:
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <hea_get_u64_bits@plt>
  test   %rax,%rax
  je     L24
  lea    0x1(%rbx),%ecx
  mov    %r13,%rax
  shr    %cl,%rax
  add    %rax,%rbp
  jmp    L24
L25:
  lea    0x200(%rbp),%rax
  shr    $0xa,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__u32 hea_cq_timestamp_ns(__u32 frac) {
  const __u32 log_prec = 10;
  const __u64 ns = 1000000000ULL << log_prec;
  const __u32 bits = sizeof(frac) * 8;
  __u64 ret = 0;
  __u32 i;
  for (i = 0; i < bits; i++) {
    if (hea_get_u64_bits(frac, i, i))
      ret += ns >> (i + 1);
  }
  return (__u32)((ret + (1UL << (log_prec - 1))) >> log_prec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hea_cq_timestamp_ns>:
  endbr64
  push   %r13
  movabs $0xee6b280000,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L17:
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <hea_get_u64_bits@plt>
  test   %rax,%rax
  je     L18
  lea    0x1(%rbx),%ecx
  mov    %r13,%rax
  shr    %cl,%rax
  add    %rax,%rbp
L18:
  add    $0x1,%rbx
  cmp    $0x40,%rbx
  jne    L17
  add    $0x8,%rsp
  lea    0x200(%rbp),%rax
  pop    %rbx
  shr    $0xa,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__u32 hea_cq_timestamp_ns(__u32 frac) {
  const __u32 log_prec = 10;
  const __u64 ns = 1000000000ULL << log_prec;
  const __u32 bits = sizeof(frac) * 8;
  __u64 ret = 0;
  __u32 i;
  for (i = 0; i < bits; i++) {
    if (hea_get_u64_bits(frac, i, i))
      ret += ns >> (i + 1);
  }
  return (__u32)((ret + (1UL << (log_prec - 1))) >> log_prec);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hea_cq_timestamp_ns>:
  endbr64
  push   %r13
  movabs $0xee6b280000,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L17:
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <hea_get_u64_bits@plt>
  test   %rax,%rax
  je     L15
  lea    0x1(%rbx),%ecx
  mov    %r13,%rax
  shr    %cl,%rax
  add    %rax,%rbp
L15:
  add    $0x1,%rbx
  cmp    $0x40,%rbx
  jne    L17
  add    $0x8,%rsp
  lea    0x200(%rbp),%rax
  pop    %rbx
  shr    $0xa,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__u32 hea_cq_timestamp_ns(__u32 frac) {
  const __u32 log_prec = 10;
  const __u64 ns = 1000000000ULL << log_prec;
  const __u32 bits = sizeof(frac) * 8;
  __u64 ret = 0;
  __u32 i;
  for (i = 0; i < bits; i++) {
    if (hea_get_u64_bits(frac, i, i))
      ret += ns >> (i + 1);
  }
  return (__u32)((ret + (1UL << (log_prec - 1))) >> log_prec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isBorder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L33
  cmpl   $0x0,-0x8(%rbp)
  je     L33
  cmpl   $0x3e8,-0x4(%rbp)
  je     L33
  cmpl   $0x3e8,-0x8(%rbp)
  jne    L13
L33:
  mov    $0x1,%eax
  jmp    L37
L13:
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int isBorder(int i, int j) {
  if (i == 0 || j == 0 || i == 1000 || j == 1000)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isBorder>:
  endbr64
  test   %edi,%edi
  je     L14
  test   %esi,%esi
  je     L14
  cmp    $0x3e8,%edi
  sete   %al
  cmp    $0x3e8,%esi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isBorder(int i, int j) {
  if (i == 0 || j == 0 || i == 1000 || j == 1000)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isBorder>:
  endbr64
  test   %edi,%edi
  je     L12
  test   %esi,%esi
  je     L12
  cmp    $0x3e8,%edi
  sete   %al
  cmp    $0x3e8,%esi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isBorder(int i, int j) {
  if (i == 0 || j == 0 || i == 1000 || j == 1000)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isBorder>:
  endbr64
  test   %edi,%edi
  je     L14
  test   %esi,%esi
  je     L14
  cmp    $0x3e8,%edi
  sete   %al
  cmp    $0x3e8,%esi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isBorder(int i, int j) {
  if (i == 0 || j == 0 || i == 1000 || j == 1000)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hts_bin_bot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L6
L2:
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  mov    %edx,%ecx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
int hts_bin_bot(int bin, int n_lvls) {
  int l, b;
  for (l = 0, b = bin; b; ++l, b = (((b)-1) >> 3))
    ;
  return (bin - (((1 << (((l) << 1) + (l))) - 1) / 7)) << (n_lvls - l) * 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hts_bin_bot>:
  endbr64
  test   %edi,%edi
  je     L12
  mov    %edi,%eax
  mov    $0x0,%edx
L17:
  add    $0x1,%edx
  sub    $0x1,%eax
  sar    $0x3,%eax
  jne    L17
L6:
  lea    (%rdx,%rdx,2),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  add    %edi,%eax
  sub    %edx,%esi
  lea    (%rsi,%rsi,2),%ecx
  shl    %cl,%eax
  ret
L12:
  mov    %edi,%edx
  jmp    L6
```

assistant: ```c
int hts_bin_bot(int bin, int n_lvls) {
  int l, b;
  for (l = 0, b = bin; b; ++l, b = (((b)-1) >> 3))
    ;
  return (bin - (((1 << (((l) << 1) + (l))) - 1) / 7)) << (n_lvls - l) * 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hts_bin_bot>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  test   %eax,%eax
  je     L0
  mov    %eax,%edx
  xor    %esi,%esi
L9:
  sub    $0x1,%edx
  add    $0x1,%esi
  sar    $0x3,%edx
  jne    L9
  lea    (%rsi,%rsi,2),%ecx
  mov    $0x1,%edx
  sub    %esi,%edi
  shl    %cl,%edx
  sub    $0x1,%edx
  movslq %edx,%rcx
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %edx,%ecx
  sar    $0x1f,%edx
  sar    $0x2,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
L0:
  lea    (%rdi,%rdi,2),%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
int hts_bin_bot(int bin, int n_lvls) {
  int l, b;
  for (l = 0, b = bin; b; ++l, b = (((b)-1) >> 3))
    ;
  return (bin - (((1 << (((l) << 1) + (l))) - 1) / 7)) << (n_lvls - l) * 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hts_bin_bot>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  test   %eax,%eax
  je     L1
  mov    %eax,%edx
  xor    %esi,%esi
L19:
  sub    $0x1,%edx
  add    $0x1,%esi
  sar    $0x3,%edx
  jne    L19
  lea    (%rsi,%rsi,2),%ecx
  mov    $0x1,%edx
  sub    %esi,%edi
  shl    %cl,%edx
  sub    $0x1,%edx
  movslq %edx,%rcx
  imul   $0xffffffff92492493,%rcx,%rcx
  shr    $0x20,%rcx
  add    %edx,%ecx
  sar    $0x1f,%edx
  sar    $0x2,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
L1:
  lea    (%rdi,%rdi,2),%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
int hts_bin_bot(int bin, int n_lvls) {
  int l, b;
  for (l = 0, b = bin; b; ++l, b = (((b)-1) >> 3))
    ;
  return (bin - (((1 << (((l) << 1) + (l))) - 1) / 7)) << (n_lvls - l) * 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L14
L5:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L64
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L60
L64:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L60:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jb     L46
  movzbl -0x9(%rbp),%eax
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%ecx
  imul   %edx,%eax
  mov    %eax,%edx
  movslq %ecx,%rax
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L38
L46:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L38:
  addb   $0x2,-0xa(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L5
  movzbl -0x9(%rbp),%eax
  lea    0x3f(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x45,%eax
  movzbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L50
  mov    $0x0,%edx
  mov    $0x0,%r8d
  jmp    L6
L37:
  mov    %r8d,%ecx
L46:
  mov    %ecx,%eax
  imul   %ecx,%eax
L24:
  add    $0x2,%edx
  cmp    %dil,%dl
  jae    L50
L6:
  cmp    %al,%dl
  jb     L37
  lea    (%rax,%rax,1),%ecx
  cmp    %dl,%cl
  jbe    L46
  shl    $0x2,%eax
  jmp    L24
L50:
  add    $0x3f,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  add    $0x45,%eax
  test   %cl,%cl
  je     L11
  xor    %edx,%edx
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    (%rax,%rax,1),%edi
  cmp    %dl,%dil
  jbe    L51
  shl    $0x2,%eax
L22:
  add    $0x2,%edx
  cmp    %cl,%dl
  jae    L11
L8:
  cmp    %al,%dl
  jae    L19
  add    $0x2,%edx
  xor    %eax,%eax
  cmp    %cl,%dl
  jb     L8
L11:
  add    $0x3f,%eax
  mov    %al,(%rsi)
  ret
L51:
  mov    %edi,%eax
  imul   %edi,%eax
  jmp    L22
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)63;
  }
}
```