ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str2xterm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x23,(%rdi)
  je     L169
  mov    %rsp,%r13
  mov    $0xa,%edx
  mov    %r13,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rbx
  mov    %rax,%r12
  cmp    %rbp,%rbx
  je     L138
  cmpb   $0x0,(%rbx)
  jne    L8
  cmp    $0xff,%eax
  jg     L147
L159:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L92
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L23:
  cmpb   $0x0,(%rbx)
  je     L135
  add    $0x1,%rbx
L8:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L23
L135:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    (%rsp),%rbp
  mov    %rax,%r14
  cmp    %rbx,%rbp
  je     L138
  cmpb   $0x0,(%rbx)
  jne    L20
  jmp    L138
  nopl   0x0(%rax,%rax,1)
L58:
  cmpb   $0x0,0x0(%rbp)
  je     L109
  add    $0x1,%rbp
L20:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L58
L109:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strtol@plt>
  cmp    %rbp,(%rsp)
  je     L138
  cmpb   $0x0,0x0(%rbp)
  je     L138
  shl    $0x10,%r12d
  shl    $0x8,%r14d
  lea    (%r12,%r14,1),%edi
  add    %eax,%edi
  movslq %edi,%rdi
L0:
  call   <rgb2xterm@plt>
  jmp    L159
  xchg   %ax,%ax
L169:
  add    $0x1,%rbp
  mov    %rsp,%rsi
  mov    $0x10,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    %rax,%rdi
  cmp    %rbp,(%rsp)
  jne    L0
L138:
  mov    $0xffffffff,%eax
  jmp    L159
  nopw   0x0(%rax,%rax,1)
L147:
  movslq %eax,%rdi
  call   <rgb2xterm@plt>
  jmp    L159
L92:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str2xterm(char *str) {
  long rgb;
  int xterm, r, g, b;
  char *p, *t;
  p = str;
  if (*p == '#') {
    p++;
    rgb = strtol(p, &t, 16);
    if (p == t) {
      return (-1);
    } else {
      return (rgb2xterm(rgb));
    }
  } else {
    r = strtol(p, &t, 10);
    if (p == t) {
      return (-1);
    } else if (*t == 0) {
      if (r < 256)
        return (r);
      return (rgb2xterm(r));
    } else {
      p = t;
      while (!isdigit(*p) && (*p != 0)) {
        p++;
      }
      g = strtol(p, &t, 10);
      if ((p == t) || (*p == 0)) {
        return (-1);
      }
      p = t;
      while (!isdigit(*p) && (*p != 0)) {
        p++;
      }
      b = strtol(p, &t, 10);
      if ((p == t) || (*p == 0)) {
        return (-1);
      }
      rgb = (r << 16) + (g << 8) + b;
      return (rgb2xterm(rgb));
    }
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FDLIBM_isnan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x8(%rbp)
  lea    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  neg    %eax
  or     -0x4(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x7ff00000,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x1f,%eax
  pop    %rbp
  ret
```

assistant: ```c
int FDLIBM_isnan(double x) {
  int hx, lx;
  hx = (*(1 + (int *)&x) & 0x7fffffff);
  lx = *(int *)&x;
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FDLIBM_isnan>:
  endbr64
  movq   %xmm0,%rax
  movq   %xmm0,%rcx
  sar    $0x20,%rcx
  and    $0x7fffffff,%ecx
  movd   %xmm0,%edx
  neg    %edx
  or     %eax,%edx
  shr    $0x1f,%edx
  or     %ecx,%edx
  mov    $0x7ff00000,%eax
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int FDLIBM_isnan(double x) {
  int hx, lx;
  hx = (*(1 + (int *)&x) & 0x7fffffff);
  lx = *(int *)&x;
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: What is the c source code of the assembly code below:

```asm
<FDLIBM_isnan>:
  endbr64
  movd   %xmm0,%edx
  movq   %xmm0,%rax
  movq   %xmm0,%rcx
  neg    %edx
  sar    $0x20,%rcx
  or     %eax,%edx
  and    $0x7fffffff,%ecx
  mov    $0x7ff00000,%eax
  shr    $0x1f,%edx
  or     %ecx,%edx
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int FDLIBM_isnan(double x) {
  int hx, lx;
  hx = (*(1 + (int *)&x) & 0x7fffffff);
  lx = *(int *)&x;
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FDLIBM_isnan>:
  endbr64
  movd   %xmm0,%edx
  movq   %xmm0,%rax
  movq   %xmm0,%rcx
  neg    %edx
  sar    $0x20,%rcx
  or     %eax,%edx
  and    $0x7fffffff,%ecx
  mov    $0x7ff00000,%eax
  shr    $0x1f,%edx
  or     %ecx,%edx
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int FDLIBM_isnan(double x) {
  int hx, lx;
  hx = (*(1 + (int *)&x) & 0x7fffffff);
  lx = *(int *)&x;
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cbstrfwimatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L97
  cmpq   $0x0,-0x20(%rbp)
  je     L97
  mov    $0x1,%eax
  jmp    L57
L97:
  mov    $0x0,%eax
L57:
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L0
L91:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  mov    $0x0,%eax
  jmp    L128
L72:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x40,-0x8(%rbp)
  jle    L13
  cmpl   $0x5a,-0x8(%rbp)
  jg     L13
  addl   $0x20,-0x8(%rbp)
L13:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L35
  cmpl   $0x5a,-0x4(%rbp)
  jg     L35
  addl   $0x20,-0x4(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L104
  mov    $0x0,%eax
  jmp    L128
L104:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L91
  mov    $0x1,%eax
L128:
  leave
  ret
```

assistant: ```c
int cbstrfwimatch(const char *str, const char *key) {
  int sc, kc;
  assert(str && key);
  while (*key != '\0') {
    if (*str == '\0')
      return 0;
    sc = *str;
    if (sc >= 'A' && sc <= 'Z')
      sc += 'a' - 'A';
    kc = *key;
    if (kc >= 'A' && kc <= 'Z')
      kc += 'a' - 'A';
    if (sc != kc)
      return 0;
    key++;
    str++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cbstrfwimatch>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L41
  mov    $0x0,%ecx
L54:
  movzbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  je     L61
  movsbl %dl,%edx
  lea    -0x41(%rdx),%edi
  lea    0x20(%rdx),%esi
  cmp    $0x1a,%edi
  cmovb  %esi,%edx
  movsbl %al,%eax
  lea    -0x41(%rax),%edi
  lea    0x20(%rax),%esi
  cmp    $0x1a,%edi
  cmovb  %esi,%eax
  cmp    %eax,%edx
  jne    L51
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%eax
  test   %al,%al
  jne    L54
  mov    $0x1,%eax
  jmp    L40
L41:
  mov    $0x1,%eax
  jmp    L40
L61:
  mov    $0x0,%eax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  mov    $0x0,%eax
  jmp    L40
```

assistant: ```c
int cbstrfwimatch(const char *str, const char *key) {
  int sc, kc;
  assert(str && key);
  while (*key != '\0') {
    if (*str == '\0')
      return 0;
    sc = *str;
    if (sc >= 'A' && sc <= 'Z')
      sc += 'a' - 'A';
    kc = *key;
    if (kc >= 'A' && kc <= 'Z')
      kc += 'a' - 'A';
    if (sc != kc)
      return 0;
    key++;
    str++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cbstrfwimatch>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  movsbl (%rbx),%eax
  test   %al,%al
  je     L8
  xor    %ecx,%ecx
  jmp    L21
  nopl   0x0(%rax)
L40:
  lea    -0x41(%rdx),%edi
  lea    0x20(%rdx),%esi
  cmp    $0x1a,%edi
  lea    -0x41(%rax),%edi
  cmovb  %esi,%edx
  lea    0x20(%rax),%esi
  cmp    $0x1a,%edi
  cmovb  %esi,%eax
  cmp    %eax,%edx
  jne    L43
  add    $0x1,%rcx
  movsbl (%rbx,%rcx,1),%eax
  test   %al,%al
  je     L8
L21:
  movsbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  jne    L40
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cbstrfwimatch(const char *str, const char *key) {
  int sc, kc;
  assert(str && key);
  while (*key != '\0') {
    if (*str == '\0')
      return 0;
    sc = *str;
    if (sc >= 'A' && sc <= 'Z')
      sc += 'a' - 'A';
    kc = *key;
    if (kc >= 'A' && kc <= 'Z')
      kc += 'a' - 'A';
    if (sc != kc)
      return 0;
    key++;
    str++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cbstrfwimatch>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  movsbl (%rbx),%eax
  test   %al,%al
  je     L19
  xor    %ecx,%ecx
  jmp    L36
  nopl   0x0(%rax)
L1:
  lea    -0x41(%rdx),%edi
  lea    0x20(%rdx),%esi
  cmp    $0x1a,%edi
  lea    -0x41(%rax),%edi
  cmovb  %esi,%edx
  lea    0x20(%rax),%esi
  cmp    $0x1a,%edi
  cmovb  %esi,%eax
  cmp    %eax,%edx
  jne    L18
  add    $0x1,%rcx
  movsbl (%rbx,%rcx,1),%eax
  test   %al,%al
  je     L19
L36:
  movsbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  jne    L1
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cbstrfwimatch(const char *str, const char *key) {
  int sc, kc;
  assert(str && key);
  while (*key != '\0') {
    if (*str == '\0')
      return 0;
    sc = *str;
    if (sc >= 'A' && sc <= 'Z')
      sc += 'a' - 'A';
    kc = *key;
    if (kc >= 'A' && kc <= 'Z')
      kc += 'a' - 'A';
    if (sc != kc)
      return 0;
    key++;
    str++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void print_array(int *a, int size) {
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D5(%rip),%rbp
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: %d 

assistant: ```c
void print_array(int *a, int size) {
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: %d 

assistant: ```c
void print_array(int *a, int size) {
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: %d 

assistant: ```c
void print_array(int *a, int size) {
  for (int i = 0; i < size; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<CheckCoordL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cx,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %cx,-0x8(%rbp)
  mov    %dx,-0xc(%rbp)
  mov    %ax,-0x10(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  jns    L56
  movswl -0xc(%rbp),%eax
  movswl -0x4(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x400,%eax
  jle    L56
  mov    $0x1,%eax
  jmp    L13
L56:
  cmpw   $0x0,-0xc(%rbp)
  jns    L11
  movswl -0x4(%rbp),%eax
  movswl -0xc(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x400,%eax
  jle    L11
  mov    $0x1,%eax
  jmp    L13
L11:
  cmpw   $0x0,-0x8(%rbp)
  jns    L64
  movswl -0x10(%rbp),%eax
  movswl -0x8(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x200,%eax
  jle    L64
  mov    $0x1,%eax
  jmp    L13
L64:
  cmpw   $0x0,-0x10(%rbp)
  jns    L108
  movswl -0x8(%rbp),%eax
  movswl -0x10(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x200,%eax
  jle    L108
  mov    $0x1,%eax
  jmp    L13
L108:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short CheckCoordL(short slx0, short sly0, short slx1, short sly1) {
  if (slx0 < 0) {
    if ((slx1 - slx0) > 1024)
      return 1;
  }
  if (slx1 < 0) {
    if ((slx0 - slx1) > 1024)
      return 1;
  }
  if (sly0 < 0) {
    if ((sly1 - sly0) > 512)
      return 1;
  }
  if (sly1 < 0) {
    if ((sly0 - sly1) > 512)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CheckCoordL>:
  endbr64
  mov    %esi,%eax
  test   %di,%di
  js     L30
L109:
  test   %dx,%dx
  js     L66
L104:
  test   %ax,%ax
  js     L105
L49:
  mov    $0x0,%esi
  test   %cx,%cx
  js     L103
L86:
  mov    %esi,%eax
  ret
L30:
  movswl %dx,%r8d
  movswl %di,%esi
  sub    %esi,%r8d
  mov    $0x1,%esi
  cmp    $0x400,%r8d
  jle    L109
  jmp    L86
L66:
  movswl %di,%edi
  movswl %dx,%edx
  sub    %edx,%edi
  mov    $0x1,%esi
  cmp    $0x400,%edi
  jle    L104
  jmp    L86
L105:
  movswl %cx,%edx
  movswl %ax,%esi
  sub    %esi,%edx
  mov    $0x1,%esi
  cmp    $0x200,%edx
  jle    L49
  jmp    L86
L103:
  cwtl
  movswl %cx,%ecx
  sub    %ecx,%eax
  cmp    $0x200,%eax
  setg   %sil
  movzbl %sil,%esi
  jmp    L86
```

assistant: ```c
unsigned short CheckCoordL(short slx0, short sly0, short slx1, short sly1) {
  if (slx0 < 0) {
    if ((slx1 - slx0) > 1024)
      return 1;
  }
  if (slx1 < 0) {
    if ((slx0 - slx1) > 1024)
      return 1;
  }
  if (sly0 < 0) {
    if ((sly1 - sly0) > 512)
      return 1;
  }
  if (sly1 < 0) {
    if ((sly0 - sly1) > 512)
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<CheckCoordL>:
  endbr64
  mov    %esi,%eax
  test   %di,%di
  js     L42
  test   %dx,%dx
  js     L53
L50:
  test   %ax,%ax
  js     L9
  xor    %r8d,%r8d
  test   %cx,%cx
  js     L81
L15:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L9:
  movswl %cx,%edx
  movswl %ax,%esi
  mov    $0x1,%r8d
  sub    %esi,%edx
  cmp    $0x200,%edx
  jg     L15
  xor    %r8d,%r8d
  test   %cx,%cx
  jns    L15
L81:
  movswl %cx,%ecx
  cwtl
  xor    %r8d,%r8d
  sub    %ecx,%eax
  cmp    $0x200,%eax
  setg   %r8b
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L42:
  movswl %di,%r8d
  movswl %dx,%esi
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    $0x400,%esi
  jg     L15
  test   %dx,%dx
  jns    L50
L53:
  movswl %di,%edi
  movswl %dx,%edx
  mov    $0x1,%r8d
  sub    %edx,%edi
  cmp    $0x400,%edi
  jle    L50
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short CheckCoordL(short slx0, short sly0, short slx1, short sly1) {
  if (slx0 < 0) {
    if ((slx1 - slx0) > 1024)
      return 1;
  }
  if (slx1 < 0) {
    if ((slx0 - slx1) > 1024)
      return 1;
  }
  if (sly0 < 0) {
    if ((sly1 - sly0) > 512)
      return 1;
  }
  if (sly1 < 0) {
    if ((sly0 - sly1) > 512)
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CheckCoordL>:
  endbr64
  mov    %esi,%eax
  test   %di,%di
  js     L83
  test   %dx,%dx
  js     L84
L8:
  test   %ax,%ax
  js     L51
  xor    %r8d,%r8d
  test   %cx,%cx
  js     L42
L29:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L51:
  movswl %cx,%edx
  movswl %ax,%esi
  mov    $0x1,%r8d
  sub    %esi,%edx
  cmp    $0x200,%edx
  jg     L29
  xor    %r8d,%r8d
  test   %cx,%cx
  jns    L29
L42:
  movswl %cx,%ecx
  cwtl
  xor    %r8d,%r8d
  sub    %ecx,%eax
  cmp    $0x200,%eax
  setg   %r8b
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L83:
  movswl %di,%r8d
  movswl %dx,%esi
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    $0x400,%esi
  jg     L29
  test   %dx,%dx
  jns    L8
L84:
  movswl %di,%edi
  movswl %dx,%edx
  mov    $0x1,%r8d
  sub    %edx,%edi
  cmp    $0x400,%edi
  jle    L8
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short CheckCoordL(short slx0, short sly0, short slx1, short sly1) {
  if (slx0 < 0) {
    if ((slx1 - slx0) > 1024)
      return 1;
  }
  if (slx1 < 0) {
    if ((slx0 - slx1) > 1024)
      return 1;
  }
  if (sly0 < 0) {
    if ((sly1 - sly0) > 512)
      return 1;
  }
  if (sly1 < 0) {
    if ((sly0 - sly1) > 512)
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x124(%rbp)
  jne    L20
  mov    -0x130(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L32
L20:
  movl   $0x1,-0x120(%rbp)
  jmp    L33
L10:
  mov    -0x120(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  mov    %eax,-0x11c(%rbp)
  cmpl   $0xffffffff,-0x11c(%rbp)
  jne    L42
  mov    -0x130(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x118(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L42:
  addl   $0x1,-0x120(%rbp)
L33:
  mov    -0x120(%rbp),%eax
  cmp    -0x124(%rbp),%eax
  jl     L10
  mov    $0x0,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D7: %s: missing operand


tool: D19: %s: cannot remove '%s'

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *file;
  int ret;
  char sbuf[256];
  if (1 == argc) {
    printf("%s: missing operand\n", argv[0]);
    return 1;
  }
  for (i = 1; i < argc; i++) {
    file = argv[i];
    ret = remove(file);
    if (-1 == ret) {
      sprintf(sbuf, "%s: cannot remove '%s'", argv[0], file);
      perror(sbuf);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L7
  jle    L67
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D6(%rip),%r14
  jmp    L5
L7:
  mov    (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%eax
  jmp    L67
L53:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L23
L5:
  mov    (%rbx),%rbp
  mov    %rbp,%rdi
  call   <remove@plt>
  cmp    $0xffffffff,%eax
  jne    L53
  mov    %rsp,%r15
  mov    %rbp,%rcx
  mov    0x0(%r13),%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <perror@plt>
  jmp    L53
L23:
  mov    $0x0,%eax
L67:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D6: %s: cannot remove '%s'

tool: D5: %s: missing operand


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  char *file;
  int ret;
  char sbuf[256];
  if (1 == argc) {
    printf("%s: missing operand\n", argv[0]);
    return 1;
  }
  for (i = 1; i < argc; i++) {
    file = argv[i];
    ret = remove(file);
    if (-1 == ret) {
      sprintf(sbuf, "%s: cannot remove '%s'", argv[0], file);
      perror(sbuf);
    }
  }
  return 0;
}
```