ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_help_message>:
  endbr64
  sub    $0x8,%rsp
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D0
type_guessed: string
name: unpack_data
arguments: data_label: D37
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D56
type_guessed: string

tool: D25: (Optional) command line input is of the form: 



tool: D0: -3 - output all blocks in 3D


tool: D37: -x - cutting plane (>= 0.0 && <= 1.0)


tool: D43: -y - cutting plane (>= 0.0 && <= 1.0)


tool: D32: -z - cutting plane (>= 0.0 && <= 1.0)


tool: D11: -i - input filename


tool: D56: -o - output filename (genesis file)


assistant: ```c
void print_help_message(void) {
  printf("(Optional) command line input is of the form: \n\n");
  printf("-3 - output all blocks in 3D\n");
  printf("-x - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-y - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-z - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-i - input filename\n");
  printf("-o - output filename (genesis file)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_help_message>:
  endbr64
  sub    $0x8,%rsp
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D55
data_type: string
name: unpack_data
arguments: tag: D56
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D45
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string

tool: D55: (Optional) command line input is of the form: 



tool: D56: -3 - output all blocks in 3D


tool: D5: -x - cutting plane (>= 0.0 && <= 1.0)


tool: D29: -y - cutting plane (>= 0.0 && <= 1.0)


tool: D4: -z - cutting plane (>= 0.0 && <= 1.0)


tool: D45: -i - input filename


tool: D24: -o - output filename (genesis file)


assistant: ```c
void print_help_message(void) {
  printf("(Optional) command line input is of the form: \n\n");
  printf("-3 - output all blocks in 3D\n");
  printf("-x - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-y - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-z - cutting plane (>= 0.0 && <= 1.0)\n");
  printf("-i - input filename\n");
  printf("-o - output filename (genesis file)\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: Hello, World!

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Hello, World!");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: Hello, World!

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Hello, World!");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: Hello, World!

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Hello, World!");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: Hello, World!

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Hello, World!");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L15
  cltq
  mov    $0x0,%edx
L4:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L4
L15:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L1
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L15:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L15
L1:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L4
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L14
L4:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--)
    c = s[i], s[i] = s[j], s[j] = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<neuralops_image_flip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L21
L1:
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L49:
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L40:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  imul   -0x28(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L40
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L49
  addq   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void neuralops_image_flip(size_t width, size_t height, size_t chan, const float *in_pixels, float *out_pixels) {
  size_t p = 0;
  for (size_t a = 0; a < chan; a++) {
    for (size_t y = 0; y < height; y++) {
      for (size_t x = 0; x < width; x++) {
        out_pixels[p] = in_pixels[(width - x - 1) + width * (y + height * a)];
        p += 1;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<neuralops_image_flip>:
  endbr64
  test   %rdx,%rdx
  je     L87
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%r11
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %r8,%r10
  mov    %rsi,%r14
  imul   %rdi,%r14
  lea    -0x1(%rdi),%r13
  mov    $0x0,%ebp
  mov    $0x0,%esi
  jmp    L74
L5:
  lea    (%rbx,%r8,4),%rdx
  lea    (%r10,%rsi,4),%rax
  add    %r9,%rsi
  lea    (%r10,%rsi,4),%rcx
L49:
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L49
L45:
  add    $0x1,%rdi
  add    %r9,%r8
  cmp    %rdi,%r11
  je     L78
L6:
  test   %r9,%r9
  jne    L5
  jmp    L45
L78:
  add    $0x1,%rbp
  add    %r14,%r13
  cmp    %rbp,%r12
  je     L55
L74:
  mov    %r13,%r8
  mov    $0x0,%edi
  test   %r11,%r11
  jne    L6
  jmp    L78
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L87:
  ret
```

assistant: ```c
void neuralops_image_flip(size_t width, size_t height, size_t chan, const float *in_pixels, float *out_pixels) {
  size_t p = 0;
  for (size_t a = 0; a < chan; a++) {
    for (size_t y = 0; y < height; y++) {
      for (size_t x = 0; x < width; x++) {
        out_pixels[p] = in_pixels[(width - x - 1) + width * (y + height * a)];
        p += 1;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<neuralops_image_flip>:
  endbr64
  test   %rdx,%rdx
  je     L24
  push   %r14
  mov    %rsi,%r14
  mov    %rsi,%r11
  mov    %rdi,%r9
  imul   %rdi,%r14
  push   %r13
  mov    %r8,%r10
  lea    -0x1(%rdi),%r13
  push   %r12
  xor    %esi,%esi
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rcx,%rbx
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r13,%r8
  xor    %edi,%edi
  test   %r11,%r11
  je     L36
  nopw   0x0(%rax,%rax,1)
L51:
  test   %r9,%r9
  je     L49
  lea    (%r10,%rsi,4),%rax
  add    %r9,%rsi
  lea    (%rbx,%r8,4),%rdx
  lea    (%r10,%rsi,4),%rcx
  nopl   0x0(%rax)
L9:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  sub    $0x4,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L9
L49:
  add    $0x1,%rdi
  add    %r9,%r8
  cmp    %rdi,%r11
  jne    L51
L36:
  add    $0x1,%rbp
  add    %r14,%r13
  cmp    %rbp,%r12
  jne    L30
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  ret
```

assistant: ```c
void neuralops_image_flip(size_t width, size_t height, size_t chan, const float *in_pixels, float *out_pixels) {
  size_t p = 0;
  for (size_t a = 0; a < chan; a++) {
    for (size_t y = 0; y < height; y++) {
      for (size_t x = 0; x < width; x++) {
        out_pixels[p] = in_pixels[(width - x - 1) + width * (y + height * a)];
        p += 1;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<neuralops_image_flip>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x50(%rsp)
  mov    %rdx,-0x10(%rsp)
  test   %rdx,%rdx
  je     L78
  test   %rsi,%rsi
  je     L78
  mov    %rdi,%rax
  mov    %rdi,%rbp
  mov    %rcx,%r14
  mov    %r8,%r9
  shr    $0x2,%rax
  imul   %rdi,%rsi
  lea    -0x1(%rdi),%rcx
  and    $0xfffffffffffffffc,%rbp
  shl    $0x4,%rax
  mov    %rcx,-0x48(%rsp)
  lea    0x1(%rbp),%r15
  lea    0x4(%r14),%r12
  mov    %rax,-0x40(%rsp)
  lea    0x2(%rbp),%rax
  mov    %rax,-0x30(%rsp)
  lea    -0xc(%r14),%rax
  mov    %rcx,-0x20(%rsp)
  movq   $0x0,-0x28(%rsp)
  mov    %rax,-0x38(%rsp)
  mov    %rsi,-0x18(%rsp)
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L16:
  mov    -0x20(%rsp),%rcx
  xor    %r10d,%r10d
L20:
  test   %rdi,%rdi
  je     L96
  mov    %rcx,%rbx
  lea    (%rdi,%rsi,1),%r11
  lea    0x0(,%rcx,4),%rax
  sub    %rdi,%rbx
  lea    (%r9,%r11,4),%r8
  lea    (%r9,%rsi,4),%rdx
  lea    (%r12,%rbx,4),%rbx
  cmp    %rbx,%r8
  lea    (%r12,%rax,1),%rbx
  setbe  %r13b
  cmp    %rbx,%rdx
  setae  %bl
  or     %r13b,%bl
  je     L77
  cmpq   $0x2,-0x48(%rsp)
  jbe    L77
  add    -0x38(%rsp),%rax
  mov    %rax,%r8
  sub    -0x40(%rsp),%r8
  nopw   0x0(%rax,%rax,1)
L1:
  movups (%rax),%xmm0
  sub    $0x10,%rax
  add    $0x10,%rdx
  shufps $0x1b,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %r8,%rax
  jne    L1
  add    %rbp,%rsi
  cmp    %rbp,%rdi
  je     L99
  mov    %rcx,%rdx
  lea    0x0(,%rsi,4),%rax
  sub    %rbp,%rdx
  movss  (%r14,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rsi,4)
  cmp    %r15,%rdi
  jbe    L99
  mov    %rcx,%rdx
  mov    -0x30(%rsp),%rsi
  sub    %r15,%rdx
  movss  (%r14,%rdx,4),%xmm0
  movss  %xmm0,0x4(%r9,%rax,1)
  cmp    %rsi,%rdi
  jbe    L99
  mov    %rcx,%rdx
  sub    %rsi,%rdx
  movss  (%r14,%rdx,4),%xmm0
  movss  %xmm0,0x8(%r9,%rax,1)
L99:
  mov    %r11,%rsi
L96:
  add    $0x1,%r10
  add    %rdi,%rcx
  cmp    %r10,-0x50(%rsp)
  jne    L20
  addq   $0x1,-0x28(%rsp)
  mov    -0x18(%rsp),%rbx
  mov    -0x28(%rsp),%rax
  add    %rbx,-0x20(%rsp)
  cmp    %rax,-0x10(%rsp)
  jne    L16
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L77:
  add    %r14,%rax
  nopl   0x0(%rax,%rax,1)
L91:
  movss  (%rax),%xmm0
  add    $0x4,%rdx
  sub    $0x4,%rax
  movss  %xmm0,-0x4(%rdx)
  cmp    %r8,%rdx
  jne    L91
  jmp    L99
```

assistant: ```c
void neuralops_image_flip(size_t width, size_t height, size_t chan, const float *in_pixels, float *out_pixels) {
  size_t p = 0;
  for (size_t a = 0; a < chan; a++) {
    for (size_t y = 0; y < height; y++) {
      for (size_t x = 0; x < width; x++) {
        out_pixels[p] = in_pixels[(width - x - 1) + width * (y + height * a)];
        p += 1;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<regPrintPos>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L17
  movapd %xmm0,%xmm2
  mulsd  D29(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  ja     L60
L24:
  cvttsd2si %xmm0,%rbp
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbp,%xmm1
  subsd  %xmm1,%xmm0
  comisd D6(%rip),%xmm0
  jbe    L83
  add    $0x1,%rbp
  pxor   %xmm0,%xmm0
L83:
  movabs $0x8888888888888889,%rbx
  mov    %rbp,%rax
  imul   %rbx
  lea    (%rdx,%rbp,1),%rcx
  sar    $0x5,%rcx
  mov    %rbp,%rax
  sar    $0x3f,%rax
  sub    %rax,%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  sub    %rcx,%rax
  shl    $0x2,%rax
  sub    %rax,%rbp
  mov    %rcx,%rax
  imul   %rbx
  lea    (%rdx,%rcx,1),%rbx
  sar    $0x5,%rbx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rbx
  mov    %rbx,%rax
  shl    $0x4,%rax
  sub    %rbx,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rcx,%r13
  lea    0x10(%rsp),%rdi
  call   <regPrintVal@plt>
  lea    0x10(%rsp),%r9
  cmpb   $0x30,0x10(%rsp)
  je     L46
L2:
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  ja     L11
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    %rbx,%rdx
  lea    D44(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
L95:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  xorpd  D20(%rip),%xmm0
  jmp    L24
L46:
  lea    0x11(%rsp),%r9
  jmp    L2
L11:
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    %rbx,%rdx
  lea    D36(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  jmp    L95
L17:
  mov    %rsi,%rdi
  movsd  0x8(%rsp),%xmm0
  call   <regPrintVal@plt>
  jmp    L95
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
data_type: f64
name: parse_data
arguments: tag: D6
data_type: f64[2]
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D20
data_type: byte[16]
name: parse_data
arguments: tag: D36
data_type: string

tool: D29: 3600

tool: {"D6": [0.9999,0.0]}

tool: D44: %02ld:%02ld:%02ld%s

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D36: -%02ld:%02ld:%02ld%s

assistant: ```c
void regPrintPos(double x, int world, char *buf) {
  char tmp[80];
  char *ptr;
  long h, m;
  double s;
  double fs;
  long is;
  int south;
  if (world) {
    south = x < 0;
    s = x * 3600.0;
    if (south)
      s = -s;
    is = (long)s;
    if (s - is > 0.9999) {
      is++;
      fs = 0;
    } else {
      fs = s - is;
    }
    m = is / 60;
    is = is % 60;
    h = m / 60;
    m = m % 60;
    regPrintVal(fs, tmp);
    ptr = tmp;
    if (*ptr == '0')
      ptr++;
    if (south)
      sprintf(buf, "-%02ld:%02ld:%02ld%s", h, m, is, ptr);
    else
      sprintf(buf, "%02ld:%02ld:%02ld%s", h, m, is, ptr);
  } else {
    regPrintVal(x, buf);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<close_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close_file@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void close_all() {
  int channel;
  for (channel = 0; channel < (64 - 32); channel++)
    close_file(channel);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<close_all>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L5:
  mov    %ebx,%edi
  call   <close_file@plt>
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void close_all() {
  int channel;
  for (channel = 0; channel < (64 - 32); channel++)
    close_file(channel);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<close_all>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close_file@plt>
  cmp    $0x20,%ebx
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void close_all() {
  int channel;
  for (channel = 0; channel < (64 - 32); channel++)
    close_file(channel);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<close_all>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close_file@plt>
  cmp    $0x20,%ebx
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
void close_all() {
  int channel;
  for (channel = 0; channel < (64 - 32); channel++)
    close_file(channel);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ebml_int_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  addl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x80,-0x4(%rbp)
  jmp    L29
L19:
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x8,-0x8(%rbp)
  je     L23
  shll   $0x7,-0x4(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L19
  jmp    L30
L23:
  nop
L30:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ebml_int_size(uint64_t value) {
  value++;
  int size = 1;
  uint64_t max_value;
  for (max_value = 1 << 7; value >= max_value; max_value <<= 7) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ebml_int_size>:
  endbr64
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x80,%edx
  cmp    $0x7f,%edi
  jle    L20
L6:
  shl    $0x7,%edx
  cmp    %edx,%edi
  jl     L18
  add    $0x1,%eax
  cmp    $0x8,%eax
  jne    L6
L18:
  ret
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ebml_int_size(uint64_t value) {
  value++;
  int size = 1;
  uint64_t max_value;
  for (max_value = 1 << 7; value >= max_value; max_value <<= 7) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ebml_int_size>:
  endbr64
  add    $0x1,%edi
  mov    $0x2,%eax
  mov    $0x80,%edx
  cmp    $0x7f,%edi
  jle    L6
L10:
  shl    $0x7,%edx
  cmp    %edx,%edi
  jl     L11
  add    $0x1,%eax
  cmp    $0x8,%eax
  jne    L10
L11:
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ebml_int_size(uint64_t value) {
  value++;
  int size = 1;
  uint64_t max_value;
  for (max_value = 1 << 7; value >= max_value; max_value <<= 7) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ebml_int_size>:
  endbr64
  add    $0x1,%edi
  cmp    $0x7f,%edi
  jle    L11
  cmp    $0x3fff,%edi
  jle    L1
  cmp    $0x1fffff,%edi
  jle    L10
  xor    %eax,%eax
  cmp    $0xfffffff,%edi
  setg   %al
  lea    0x4(,%rax,4),%eax
  ret
  nop
L11:
  mov    $0x1,%eax
  ret
L1:
  mov    $0x2,%eax
  ret
L10:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int ebml_int_size(uint64_t value) {
  value++;
  int size = 1;
  uint64_t max_value;
  for (max_value = 1 << 7; value >= max_value; max_value <<= 7) {
    size++;
    if (size == 8)
      break;
  }
  return size;
}
```