user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Unique_Blk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0xa,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L67
L63:
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L75:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  test   %eax,%eax
  jne    L56
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L56:
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x2,-0xc(%rbp)
  jle    L75
  addl   $0x1,-0x10(%rbp)
L67:
  cmpl   $0x2,-0x10(%rbp)
  jle    L63
  cmpl   $0x1,-0x1c(%rbp)
  jne    L28
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x20(%rbp)
  jmp    L68
L16:
  mov    -0x20(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <Exist_Blk@plt>
  cmp    $0x1,%eax
  je     L15
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    -0x20(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  addl   $0x1,-0x20(%rbp)
L68:
  cmpl   $0x9,-0x20(%rbp)
  jle    L16
L28:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D25: block count = %d


tool: D8: Block unique is a[%d][%d]


tool: D18: a[%d][%d]=%d


assistant: ```c
void Unique_Blk(int a[9][9], int i, int j) {
  int x = i / 3, y = j / 3;
  int k;
  int count = 0, flag_m = 9 + 1, flag_n = 9 + 1;
  for (int m = 0; m < 3; m++) {
    for (int n = 0; n < 3; n++) {
      if (a[3 * x + m][3 * y + n] == 0) {
        count += 1;
        flag_m = m;
        flag_n = n;
      }
    }
  }
  if (count == 1) {
    printf("block count = %d\n", count);
    printf("Block unique is a[%d][%d]\n", flag_m, flag_n);
    for (k = 1; k < 9 + 1; k++) {
      if (Exist_Blk(a, i, j, k) != 1) {
        a[flag_m][flag_n] = k;
        printf("a[%d][%d]=%d\n", flag_m, flag_n, k);
      }
    }
  }
}
```