ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<transf_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  movsd  %xmm1,-0x58(%rbp)
  movsd  %xmm2,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x50(%rbp),%xmm0
  subsd  -0x58(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x60(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x34(%rbp)
  mov    D10(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D40(%rip)
  lea    -0x20(%rbp),%rcx
  mov    %eax,%edx
  lea    D40(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  lea    -0x20(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L17
L2:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x38(%rbp),%xmm0
  mulsd  -0x60(%rbp),%xmm0
  movsd  -0x58(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x38(%rbp)
L17:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type: byte[8]
name: unpack_data
arguments: tag: D40
type: string
name: unpack_data
arguments: tag: D29
type: string
name: unpack_data
arguments: tag: D3
type: string

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D40: t%d.txt

tool: D29: w

tool: D3: %f %f


assistant: ```c
void transf_print(double *power, double freq_max, double freq_min, double freq_delta) {
  FILE *file;
  static int id;
  char fname[16];
  int i;
  int size = (freq_max - freq_min) / freq_delta + 1;
  sprintf(fname, "t%d.txt", id++);
  file = fopen(fname, "w");
  for (i = 0; i < size; i++) {
    double f = freq_min + i * freq_delta;
    fprintf(file, "%f %f\n", f, power[i]);
  }
  fclose(file);
}
```
user: Translate the below assembly code into C programming language:

```asm
<transf_print>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r13
  movsd  %xmm1,(%rsp)
  movsd  %xmm2,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  addsd  D11(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  mov    D27(%rip),%edx
  lea    0x1(%rdx),%eax
  mov    %eax,D38(%rip)
  lea    0x10(%rsp),%rbx
  lea    D38(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L11
  mov    %r12d,%r12d
  mov    $0x0,%ebx
  lea    D31(%rip),%r14
L25:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movsd  0x0(%r13,%rbx,8),%xmm1
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L25
L11:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
type: byte[8]
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D31
type: string

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D38: t%d.txt

tool: D17: w

tool: D31: %f %f


assistant: ```c
void transf_print(double *power, double freq_max, double freq_min, double freq_delta) {
  FILE *file;
  static int id;
  char fname[16];
  int i;
  int size = (freq_max - freq_min) / freq_delta + 1;
  sprintf(fname, "t%d.txt", id++);
  file = fopen(fname, "w");
  for (i = 0; i < size; i++) {
    double f = freq_min + i * freq_delta;
    fprintf(file, "%f %f\n", f, power[i]);
  }
  fclose(file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transf_print>:
  endbr64
  subsd  %xmm1,%xmm0
  push   %r14
  lea    D45(%rip),%rsi
  push   %r13
  push   %r12
  divsd  %xmm2,%xmm0
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    D54(%rip),%edx
  movsd  %xmm1,(%rsp)
  lea    0x10(%rsp),%r12
  movsd  %xmm2,0x8(%rsp)
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdx),%eax
  mov    %eax,D55(%rip)
  addsd  D55(%rip),%xmm0
  cvttsd2si %xmm0,%ebx
  call   <sprintf@plt>
  lea    D40(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L8
  movslq %ebx,%rbx
  xor    %r13d,%r13d
  lea    D56(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  pxor   %xmm0,%xmm0
  movsd  0x0(%rbp,%r13,8),%xmm1
  mov    %r12,%rsi
  mov    %r14,%rdi
  cvtsi2sd %r13d,%xmm0
  mulsd  0x8(%rsp),%xmm0
  add    $0x1,%r13
  addsd  (%rsp),%xmm0
  call   <fprintf@plt>
  cmp    %r13,%rbx
  jne    L3
L8:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D55
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D40
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D56
type_guessed: string

tool: D45: t%d.txt

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D40: w

tool: D56: %f %f


assistant: ```c
void transf_print(double *power, double freq_max, double freq_min, double freq_delta) {
  FILE *file;
  static int id;
  char fname[16];
  int i;
  int size = (freq_max - freq_min) / freq_delta + 1;
  sprintf(fname, "t%d.txt", id++);
  file = fopen(fname, "w");
  for (i = 0; i < size; i++) {
    double f = freq_min + i * freq_delta;
    fprintf(file, "%f %f\n", f, power[i]);
  }
  fclose(file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<transf_print>:
  endbr64
  subsd  %xmm1,%xmm0
  push   %r14
  lea    D47(%rip),%rsi
  push   %r13
  push   %r12
  divsd  %xmm2,%xmm0
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    D54(%rip),%edx
  movsd  %xmm1,(%rsp)
  lea    0x10(%rsp),%r12
  movsd  %xmm2,0x8(%rsp)
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdx),%eax
  mov    %eax,D27(%rip)
  addsd  D27(%rip),%xmm0
  cvttsd2si %xmm0,%ebx
  call   <sprintf@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L26
  movslq %ebx,%rbx
  xor    %r13d,%r13d
  lea    D22(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  movsd  0x0(%rbp,%r13,8),%xmm1
  mov    %r12,%rsi
  mov    %r14,%rdi
  cvtsi2sd %r13d,%xmm0
  mulsd  0x8(%rsp),%xmm0
  add    $0x1,%r13
  addsd  (%rsp),%xmm0
  call   <fprintf@plt>
  cmp    %r13,%rbx
  jne    L6
L26:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D47
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string

tool: D47: t%d.txt

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D5: w

tool: D22: %f %f


assistant: ```c
void transf_print(double *power, double freq_max, double freq_min, double freq_delta) {
  FILE *file;
  static int id;
  char fname[16];
  int i;
  int size = (freq_max - freq_min) / freq_delta + 1;
  sprintf(fname, "t%d.txt", id++);
  file = fopen(fname, "w");
  for (i = 0; i < size; i++) {
    double f = freq_min + i * freq_delta;
    fprintf(file, "%f %f\n", f, power[i]);
  }
  fclose(file);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unmapfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <munmap@plt>
  leave
  ret
```

assistant: ```c
int unmapfile(void *ptr, size_t sz) {
  assert(ptr != NULL);
  return munmap(ptr, sz);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unmapfile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <munmap@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int unmapfile(void *ptr, size_t sz) {
  assert(ptr != NULL);
  return munmap(ptr, sz);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unmapfile>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <munmap@plt>
```

assistant: ```c
int unmapfile(void *ptr, size_t sz) {
  assert(ptr != NULL);
  return munmap(ptr, sz);
}
```
user: What is the c source code of the assembly code below:

```asm
<unmapfile>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <munmap@plt>
```

assistant: ```c
int unmapfile(void *ptr, size_t sz) {
  assert(ptr != NULL);
  return munmap(ptr, sz);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *uart_out(void *arg) {
  char *s = arg;
  puts(s);
  return arg;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uart_out>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <puts@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *uart_out(void *arg) {
  char *s = arg;
  puts(s);
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uart_out>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <puts@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *uart_out(void *arg) {
  char *s = arg;
  puts(s);
  return arg;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_out>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <puts@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *uart_out(void *arg) {
  char *s = arg;
  puts(s);
  return arg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_ugly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L29
  mov    $0x0,%eax
  jmp    L20
L29:
  cmpl   $0x1,-0x4(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L20
L57:
  sarl   -0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L57
  jmp    L2
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L24
  jmp    L12
L54:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L54
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
L20:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char is_ugly(int num) {
  if (num <= 0)
    return 0;
  if (num == 1)
    return 1;
  while (num % 2 == 0) {
    num = num >> 1;
  }
  while (num % 3 == 0) {
    num = num / 3;
  }
  while (num % 5 == 0) {
    num = num / 5;
  }
  return num == 1 ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_ugly>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%edx
  test   %edi,%edi
  jle    L12
  mov    $0x1,%edx
  cmp    $0x1,%edi
  je     L12
  test   $0x1,%al
  jne    L31
L53:
  sar    %eax
  test   $0x1,%al
  je     L53
L31:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %edx,%eax
  jne    L17
L23:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  movslq %edx,%rcx
  imul   $0x55555556,%rcx,%rcx
  shr    $0x20,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  lea    (%rcx,%rcx,2),%ecx
  cmp    %ecx,%edx
  je     L23
L17:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %edx,%eax
  jne    L30
L43:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x21,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  cmp    %ecx,%edx
  je     L43
L30:
  cmp    $0x1,%eax
  sete   %dl
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned char is_ugly(int num) {
  if (num <= 0)
    return 0;
  if (num == 1)
    return 1;
  while (num % 2 == 0) {
    num = num >> 1;
  }
  while (num % 3 == 0) {
    num = num / 3;
  }
  while (num % 5 == 0) {
    num = num / 5;
  }
  return num == 1 ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_ugly>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L59
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jne    L1
  jmp    L59
  xchg   %ax,%ax
L14:
  sar    %eax
L1:
  test   $0x1,%al
  je     L14
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L57:
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x55555556,%rdx,%rdx
  mov    %eax,%ecx
  shr    $0x20,%rdx
  mov    %edx,%eax
  sub    %ecx,%eax
L60:
  imul   $0xaaaaaaab,%eax,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  jbe    L57
  jmp    L70
  nopl   (%rax)
L13:
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x21,%rdx
  mov    %edx,%eax
  sub    %ecx,%eax
L70:
  imul   $0xcccccccd,%eax,%edx
  add    $0x19999999,%edx
  cmp    $0x33333332,%edx
  jbe    L13
  cmp    $0x1,%eax
  sete   %r8b
L59:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char is_ugly(int num) {
  if (num <= 0)
    return 0;
  if (num == 1)
    return 1;
  while (num % 2 == 0) {
    num = num >> 1;
  }
  while (num % 3 == 0) {
    num = num / 3;
  }
  while (num % 5 == 0) {
    num = num / 5;
  }
  return num == 1 ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_ugly>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L55
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jne    L4
  jmp    L55
  xchg   %ax,%ax
L67:
  sar    %eax
L4:
  test   $0x1,%al
  je     L67
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L48:
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x55555556,%rdx,%rdx
  mov    %eax,%ecx
  shr    $0x20,%rdx
  mov    %edx,%eax
  sub    %ecx,%eax
L59:
  imul   $0xaaaaaaab,%eax,%edx
  add    $0x2aaaaaaa,%edx
  cmp    $0x55555554,%edx
  jbe    L48
  jmp    L68
  nopl   (%rax)
L3:
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x21,%rdx
  mov    %edx,%eax
  sub    %ecx,%eax
L68:
  imul   $0xcccccccd,%eax,%edx
  add    $0x19999999,%edx
  cmp    $0x33333332,%edx
  jbe    L3
  cmp    $0x1,%eax
  sete   %r8b
L55:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char is_ugly(int num) {
  if (num <= 0)
    return 0;
  if (num == 1)
    return 1;
  while (num % 2 == 0) {
    num = num >> 1;
  }
  while (num % 3 == 0) {
    num = num / 3;
  }
  while (num % 5 == 0) {
    num = num / 5;
  }
  return num == 1 ? 1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hcf@plt>
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D8: Enter the first number  : 

tool: D13: %i

tool: D21: Enter the second number : 

tool: D3: HCF of %i and %i is %i

assistant: ```c
int main() {
  int a, b;
  printf("Enter the first number  : ");
  scanf("%i", &a);
  printf("Enter the second number : ");
  scanf("%i", &b);
  printf("HCF of %i and %i is %i", a, b, hcf(a, b));
  getch();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <hcf@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D34
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D12: Enter the first number  : 

tool: D7: %i

tool: D34: Enter the second number : 

tool: D11: HCF of %i and %i is %i

assistant: ```c
int main() {
  int a, b;
  printf("Enter the first number  : ");
  scanf("%i", &a);
  printf("Enter the second number : ");
  scanf("%i", &b);
  printf("HCF of %i and %i is %i", a, b, hcf(a, b));
  getch();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D29(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <hcf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D39(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: string
name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D39
data_type: string

tool: D11: Enter the first number  : 

tool: D29: %i

tool: D16: Enter the second number : 

tool: D39: HCF of %i and %i is %i

assistant: ```c
int main() {
  int a, b;
  printf("Enter the first number  : ");
  scanf("%i", &a);
  printf("Enter the second number : ");
  scanf("%i", &b);
  printf("HCF of %i and %i is %i", a, b, hcf(a, b));
  getch();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D21(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <hcf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D33(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D33
datatype: string

tool: D27: Enter the first number  : 

tool: D21: %i

tool: D16: Enter the second number : 

tool: D33: HCF of %i and %i is %i

assistant: ```c
int main() {
  int a, b;
  printf("Enter the first number  : ");
  scanf("%i", &a);
  printf("Enter the second number : ");
  scanf("%i", &b);
  printf("HCF of %i and %i is %i", a, b, hcf(a, b));
  getch();
  return 0;
}
```