ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  test   %rax,%rax
  js     L18
L19:
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L48
  jne    L52
  mov    0xc(%rsp),%edi
  call   <close@plt>
  lea    0x10(%rsp),%rbx
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%edi
  call   <read@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L40:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x420,%rsp
  pop    %rbx
  ret
L18:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
L48:
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L52:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    $0x6,%edx
  lea    D8(%rip),%rsi
  mov    0xc(%rsp),%edi
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%edi
  call   <wait@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L40
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D0: pipe()

tool: D10: fork()

tool: D8: Hello!

assistant: ```c
int main() {
  int pfd[2];
  char buf[1024];
  pid_t pid;
  if (pipe(pfd) < 0) {
    perror("pipe()");
    exit(1);
  }
  pid = fork();
  if (pid < 0) {
    perror("fork()");
    exit(1);
  }
  if (pid == 0) {
    close(pfd[1]);
    read(pfd[0], buf, 1024);
    puts(buf);
    close(pfd[0]);
    exit(0);
  } else {
    close(pfd[0]);
    write(pfd[1], "Hello!", 6);
    close(pfd[1]);
    wait(NULL);
    exit(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  test   %rax,%rax
  js     L18
L34:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L25
  jne    L5
  mov    0xc(%rsp),%edi
  lea    0x10(%rsp),%rbp
  call   <close@plt>
  mov    0x8(%rsp),%edi
  mov    $0x400,%edx
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
L3:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x420,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L25:
  lea    D20(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0xc(%rsp),%edi
  mov    $0x6,%edx
  lea    D2(%rip),%rsi
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <wait@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L3
L18:
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D20: fork()

tool: D2: Hello!

tool: D10: pipe()

assistant: ```c
int main() {
  int pfd[2];
  char buf[1024];
  pid_t pid;
  if (pipe(pfd) < 0) {
    perror("pipe()");
    exit(1);
  }
  pid = fork();
  if (pid < 0) {
    perror("fork()");
    exit(1);
  }
  if (pid == 0) {
    close(pfd[1]);
    read(pfd[0], buf, 1024);
    puts(buf);
    close(pfd[0]);
    exit(0);
  } else {
    close(pfd[0]);
    write(pfd[1], "Hello!", 6);
    close(pfd[1]);
    wait(NULL);
    exit(0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  test   %rax,%rax
  js     L26
L17:
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L46
  jne    L21
  mov    0xc(%rsp),%edi
  lea    0x10(%rsp),%rbp
  call   <close@plt>
  mov    0x8(%rsp),%edi
  mov    $0x400,%edx
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <exit@plt>
L2:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x420,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L46:
  lea    D22(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L21:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0xc(%rsp),%edi
  mov    $0x6,%edx
  lea    D27(%rip),%rsi
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  xor    %edi,%edi
  call   <wait@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L2
L26:
  lea    D19(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
data_type: string
name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D22: fork()

tool: D27: Hello!

tool: D19: pipe()

assistant: ```c
int main() {
  int pfd[2];
  char buf[1024];
  pid_t pid;
  if (pipe(pfd) < 0) {
    perror("pipe()");
    exit(1);
  }
  pid = fork();
  if (pid < 0) {
    perror("fork()");
    exit(1);
  }
  if (pid == 0) {
    close(pfd[1]);
    read(pfd[0], buf, 1024);
    puts(buf);
    close(pfd[0]);
    exit(0);
  } else {
    close(pfd[0]);
    write(pfd[1], "Hello!", 6);
    close(pfd[1]);
    wait(NULL);
    exit(0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bubble_down@plt>
  subl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x4(%rbp)
  jns    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapify(int *A, int size) {
  int pos = size - 1;
  while (pos >= 0) {
    bubble_down(A, size, pos);
    pos--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  sub    $0x1,%ebx
  js     L19
L7:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <bubble_down@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L7
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapify(int *A, int size) {
  int pos = size - 1;
  while (pos >= 0) {
    bubble_down(A, size, pos);
    pos--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  js     L7
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax)
L12:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <bubble_down@plt>
  sub    $0x1,%ebx
  jae    L12
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapify(int *A, int size) {
  int pos = size - 1;
  while (pos >= 0) {
    bubble_down(A, size, pos);
    pos--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebx
  js     L11
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax)
L15:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <bubble_down@plt>
  sub    $0x1,%ebx
  jae    L15
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapify(int *A, int size) {
  int pos = size - 1;
  while (pos >= 0) {
    bubble_down(A, size, pos);
    pos--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  lea    0x5f158c66(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      local2 = 0UL;
      while (local2 < 0U) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      local2 = 0UL;
      while (local2 < 0U) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      local2 = 0UL;
      while (local2 < 0U) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x5e7b97ab,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      local2 = 0UL;
      while (local2 < 0U) {
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 2699719578U;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xdr_u_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L18
  cmp    $0x82,%eax
  jg     L6
  cmp    $0x80,%eax
  je     L92
  cmp    $0x81,%eax
  jne    L6
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_PUTLONG@plt>
  jmp    L53
L18:
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  jne    L64
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L64:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L92:
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  jmp    L53
L6:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
bool_t xdr_u_int(XDR *xdrs, u_int *up) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*up;
    return (XDR_PUTLONG(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!XDR_GETLONG(xdrs, (long *)&l)) {
      return (FALSE);
    }
    *up = (u_int)l;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_u_int>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L71
  cmp    $0x82,%eax
  je     L8
  cmp    $0x80,%eax
  je     L73
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
L71:
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <XDR_PUTLONG@plt>
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  je     L57
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
L57:
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
L73:
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  jmp    L47
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int(XDR *xdrs, u_int *up) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*up;
    return (XDR_PUTLONG(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!XDR_GETLONG(xdrs, (long *)&l)) {
      return (FALSE);
    }
    *up = (u_int)l;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xdr_u_int>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L12
  cmp    $0x82,%eax
  je     L0
  cmp    $0x80,%eax
  je     L66
L50:
  mov    D20(%rip),%rax
  mov    (%rax),%eax
L61:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <XDR_PUTLONG@plt>
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L66:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  je     L50
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L61
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int(XDR *xdrs, u_int *up) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*up;
    return (XDR_PUTLONG(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!XDR_GETLONG(xdrs, (long *)&l)) {
      return (FALSE);
    }
    *up = (u_int)l;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xdr_u_int>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L36
  cmp    $0x82,%eax
  je     L71
  cmp    $0x80,%eax
  je     L43
L78:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L40:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
L36:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  call   <XDR_PUTLONG@plt>
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L43:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L71:
  lea    0x4(%rsp),%rsi
  call   <XDR_GETLONG@plt>
  test   %eax,%eax
  je     L78
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L40
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int(XDR *xdrs, u_int *up) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*up;
    return (XDR_PUTLONG(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!XDR_GETLONG(xdrs, (long *)&l)) {
      return (FALSE);
    }
    *up = (u_int)l;
    return (TRUE);
  case XDR_FREE:
    return (TRUE);
  }
  return (FALSE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<no_multiples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L34:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L48
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  je     L48
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L53
L19:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L53:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L19
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  subl   $0x1,-0x18(%rbp)
L48:
  addl   $0x1,-0x18(%rbp)
L14:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jl     L34
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void no_multiples(char *string) {
  int i, j;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == ' ' && i != (strlen(string) - 1)) {
      for (j = i + 1; j < strlen(string); j++) {
        string[j - 1] = string[j];
      }
      string[strlen(string) - 1] = '\0';
      *(string + i) = toupper(*(string + i));
      i--;
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<no_multiples>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L53
L19:
  movzbl (%rbx,%r13,1),%eax
  mov    %al,-0x1(%rbx,%r13,1)
  add    $0x1,%r13
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L19
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  movsbl (%r12),%edi
  call   <toupper@plt>
  mov    %al,(%r12)
  sub    $0x1,%ebp
L18:
  add    $0x1,%ebp
L53:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L34
  movslq %ebp,%r12
  add    %rbx,%r12
  cmpb   $0x20,(%r12)
  jne    L18
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  lea    0x1(%rbp),%r13d
  movslq %r13d,%r13
  cmp    %ebp,%eax
  je     L18
  jmp    L17
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void no_multiples(char *string) {
  int i, j;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == ' ' && i != (strlen(string) - 1)) {
      for (j = i + 1; j < strlen(string); j++) {
        string[j - 1] = string[j];
      }
      string[strlen(string) - 1] = '\0';
      *(string + i) = toupper(*(string + i));
      i--;
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<no_multiples>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    %ebx,%r12d
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L44
  movslq %r12d,%r13
  lea    0x1(%r12),%ebx
  add    %rbp,%r13
  cmpb   $0x20,0x0(%r13)
  jne    L39
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L39
  movslq %ebx,%rbx
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L52:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,-0x1(%rbp,%rbx,1)
  add    $0x1,%rbx
L66:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L52
  mov    %rbp,%rdi
  mov    %r12d,%ebx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  movsbl 0x0(%r13),%edi
  call   <toupper@plt>
  mov    %al,0x0(%r13)
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void no_multiples(char *string) {
  int i, j;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == ' ' && i != (strlen(string) - 1)) {
      for (j = i + 1; j < strlen(string); j++) {
        string[j - 1] = string[j];
      }
      string[strlen(string) - 1] = '\0';
      *(string + i) = toupper(*(string + i));
      i--;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<no_multiples>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %ebx,%r12d
L35:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jle    L22
  movslq %r12d,%r13
  lea    0x1(%r12),%ebx
  add    %rbp,%r13
  cmpb   $0x20,0x0(%r13)
  jne    L54
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L54
  movslq %ebx,%rbx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,-0x1(%rbp,%rbx,1)
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L34
  mov    %rbp,%rdi
  mov    %r12d,%ebx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbp,%rax,1)
  movsbl 0x0(%r13),%edi
  call   <toupper@plt>
  mov    %al,0x0(%r13)
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void no_multiples(char *string) {
  int i, j;
  for (i = 0; i < strlen(string); i++) {
    if (string[i] == ' ' && i != (strlen(string) - 1)) {
      for (j = i + 1; j < strlen(string); j++) {
        string[j - 1] = string[j];
      }
      string[strlen(string) - 1] = '\0';
      *(string + i) = toupper(*(string + i));
      i--;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L17:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  int i = 0;
  while (*s++)
    i++;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlen>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,(%rdi)
  je     L13
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L25:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L25
L27:
  mov    %ecx,%eax
  ret
L13:
  mov    $0x0,%ecx
  jmp    L27
```

assistant: ```c
unsigned strlen(const char *s) {
  int i = 0;
  while (*s++)
    i++;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  lea    0x1(%rdi),%rax
  je     L2
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L3:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  int i = 0;
  while (*s++)
    i++;
  return i;
}
```