ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getAlphanumeric>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L15
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L20
  sub    $0x20,%edi
  mov    $0xffffffff,%eax
  cmp    $0x1a,%dil
  ja     L15
  movzbl %dil,%edi
  lea    D2(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L15:
  ret
L20:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int8_t getAlphanumeric(char c) {
  if (c >= '0' && c <= '9') {
    return (c - '0');
  }
  if (c >= 'A' && c <= 'Z') {
    return (c - 'A' + 10);
  }
  switch (c) {
  case ' ':
    return 36;
  case '$':
    return 37;
  case '%':
    return 38;
  case '*':
    return 39;
  case '+':
    return 40;
  case '-':
    return 41;
  case '.':
    return 42;
  case '/':
    return 43;
  case ':':
    return 44;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<thread_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Thread <%d> executing


assistant: ```c
void *thread_function(void *arg) {
  int x = (int)arg;
  printf("Thread <%d> executing\n", x);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<thread_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: Thread <%d> executing


assistant: ```c
void *thread_function(void *arg) {
  int x = (int)arg;
  printf("Thread <%d> executing\n", x);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<thread_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: Thread <%d> executing


assistant: ```c
void *thread_function(void *arg) {
  int x = (int)arg;
  printf("Thread <%d> executing\n", x);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<thread_function>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: Thread <%d> executing


assistant: ```c
void *thread_function(void *arg) {
  int x = (int)arg;
  printf("Thread <%d> executing\n", x);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CalculateCS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L34:
  mov    -0x4(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L29
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L29:
  shll   -0x4(%rbp)
L24:
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x7,-0x8(%rbp)
  jle    L34
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned CalculateCS(int c, unsigned previous) {
  int i;
  unsigned sum;
  sum = (previous ^ c) << 8;
  for (i = 0; i < 8; i++) {
    if (sum & 0x8000)
      sum = (sum << 1) ^ 0x1021;
    else
      sum = sum << 1;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CalculateCS>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  shl    $0x8,%eax
  mov    $0x8,%ecx
L6:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%edx
  lea    (%rax,%rax,1),%esi
  test   $0x80,%ah
  mov    %edx,%eax
  cmove  %esi,%eax
  sub    $0x1,%ecx
  jne    L6
  ret
```

assistant: ```c
unsigned CalculateCS(int c, unsigned previous) {
  int i;
  unsigned sum;
  sum = (previous ^ c) << 8;
  for (i = 0; i < 8; i++) {
    if (sum & 0x8000)
      sum = (sum << 1) ^ 0x1021;
    else
      sum = sum << 1;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CalculateCS>:
  endbr64
  mov    %edi,%eax
  mov    $0x8,%edx
  xor    %esi,%eax
  shl    $0x8,%eax
L3:
  mov    %eax,%esi
  add    %eax,%eax
  mov    %eax,%ecx
  and    $0x8000,%esi
  xor    $0x1021,%ecx
  test   %esi,%esi
  cmovne %ecx,%eax
  sub    $0x1,%edx
  jne    L3
  ret
```

assistant: ```c
unsigned CalculateCS(int c, unsigned previous) {
  int i;
  unsigned sum;
  sum = (previous ^ c) << 8;
  for (i = 0; i < 8; i++) {
    if (sum & 0x8000)
      sum = (sum << 1) ^ 0x1021;
    else
      sum = sum << 1;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CalculateCS>:
  endbr64
  xor    %esi,%edi
  mov    %edi,%eax
  shl    $0x9,%eax
  mov    %eax,%edx
  xor    $0x1021,%edx
  and    $0x80,%edi
  cmovne %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%r8d
  mov    %r8d,%edx
  xor    $0x1021,%edx
  test   $0x80,%ah
  cmovne %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned CalculateCS(int c, unsigned previous) {
  int i;
  unsigned sum;
  sum = (previous ^ c) << 8;
  for (i = 0; i < 8; i++) {
    if (sum & 0x8000)
      sum = (sum << 1) ^ 0x1021;
    else
      sum = sum << 1;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x4,-0xc(%rbp)
  jle    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int *p = (int *)malloc(5 * sizeof(int));
  int i = 0;
  for (i = 0; i < 5; i++) {
    p[i] = i + 1;
    printf("%d\n", p[i]);
  }
  free(p);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L5:
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    $0x5,%ebx
  jne    L5
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %d


assistant: ```c
int main() {
  int *p = (int *)malloc(5 * sizeof(int));
  int i = 0;
  for (i = 0; i < 5; i++) {
    p[i] = i + 1;
    printf("%d\n", p[i]);
  }
  free(p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x14,%edi
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
L8:
  add    $0x1,%ebx
  mov    %r12,%rdi
  add    $0x4,%rbp
  mov    %ebx,-0x4(%rbp)
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L8
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main() {
  int *p = (int *)malloc(5 * sizeof(int));
  int i = 0;
  for (i = 0; i < 5; i++) {
    p[i] = i + 1;
    printf("%d\n", p[i]);
  }
  free(p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x14,%edi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
L5:
  add    $0x1,%ebx
  mov    %r12,%rdi
  add    $0x4,%rbp
  mov    %ebx,-0x4(%rbp)
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L5
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int *p = (int *)malloc(5 * sizeof(int));
  int i = 0;
  for (i = 0; i < 5; i++) {
    p[i] = i + 1;
    printf("%d\n", p[i]);
  }
  free(p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_56_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_56_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D | T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_56_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  or     (%rdi),%sil
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_56_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D | T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_56_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %edx,%esi
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_56_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D | T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_56_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %edx,%esi
  and    %eax,%esi
  xor    %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_56_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D | T;
  stk2 = S & stk3;
  stk1 = T ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x62677572746163,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x62746168,-0x15(%rbp)
  movb   $0x0,-0x11(%rbp)
  lea    -0x15(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <squeeze@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: %s



assistant: ```c
int main() {
  char s1[] = "catrugb";
  char s2[] = "hatb";
  squeeze(s1, s2);
  printf("%s\n\n", s1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x62677572746163,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x62746168,0xb(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0xb(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <squeeze@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: %s



assistant: ```c
int main() {
  char s1[] = "catrugb";
  char s2[] = "hatb";
  squeeze(s1, s2);
  printf("%s\n\n", s1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x62677572746163,%rax
  lea    0x10(%rsp),%rbp
  lea    0xb(%rsp),%rsi
  movl   $0x62746168,0xb(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x10(%rsp)
  call   <squeeze@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %s



assistant: ```c
int main() {
  char s1[] = "catrugb";
  char s2[] = "hatb";
  squeeze(s1, s2);
  printf("%s\n\n", s1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x62677572746163,%rax
  lea    0x10(%rsp),%rbp
  lea    0xb(%rsp),%rsi
  movl   $0x62746168,0xb(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x10(%rsp)
  call   <squeeze@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: %s



assistant: ```c
int main() {
  char s1[] = "catrugb";
  char s2[] = "hatb";
  squeeze(s1, s2);
  printf("%s\n\n", s1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xxtea_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %rcx,-0x130(%rbp)
  mov    %r8,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    -0x110(%rbp),%rdx
  mov    -0x138(%rbp),%rax
  mov    $0x100,%ecx
  mov    %rax,%rdi
  call   <xxtea_to_key_array@plt>
  lea    -0x110(%rbp),%rdi
  mov    -0x130(%rbp),%rcx
  mov    -0x128(%rbp),%rdx
  mov    -0x120(%rbp),%rsi
  mov    -0x118(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <xxtea_ubyte_encrypt@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
size_t xxtea_encrypt(const void *data, size_t len, uint8_t *out, size_t out_size, const char *key) {
  uint32_t key_array[64];
  xxtea_to_key_array(key, strlen(key), key_array, sizeof(key_array));
  return xxtea_ubyte_encrypt((const uint8_t *)data, len, out, out_size, key_array);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xxtea_encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %r8,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rsp,%r15
  mov    $0x100,%ecx
  mov    %r15,%rdx
  mov    %rbx,%rdi
  call   <xxtea_to_key_array@plt>
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <xxtea_ubyte_encrypt@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t xxtea_encrypt(const void *data, size_t len, uint8_t *out, size_t out_size, const char *key) {
  uint32_t key_array[64];
  xxtea_to_key_array(key, strlen(key), key_array, sizeof(key_array));
  return xxtea_ubyte_encrypt((const uint8_t *)data, len, out, out_size, key_array);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xxtea_encrypt>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <strlen@plt>
  mov    $0x100,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <xxtea_to_key_array@plt>
  mov    %r14,%rdx
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <xxtea_ubyte_encrypt@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t xxtea_encrypt(const void *data, size_t len, uint8_t *out, size_t out_size, const char *key) {
  uint32_t key_array[64];
  xxtea_to_key_array(key, strlen(key), key_array, sizeof(key_array));
  return xxtea_ubyte_encrypt((const uint8_t *)data, len, out, out_size, key_array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xxtea_encrypt>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r8,%rdi
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <strlen@plt>
  mov    $0x100,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <xxtea_to_key_array@plt>
  mov    %r14,%rdx
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <xxtea_ubyte_encrypt@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t xxtea_encrypt(const void *data, size_t len, uint8_t *out, size_t out_size, const char *key) {
  uint32_t key_array[64];
  xxtea_to_key_array(key, strlen(key), key_array, sizeof(key_array));
  return xxtea_ubyte_encrypt((const uint8_t *)data, len, out, out_size, key_array);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseWords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <removeDupSpace@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L29
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L27
  movl   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  jmp    L36
L27:
  addq   $0x1,-0x10(%rbp)
L36:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  cmpl   $0x1,-0x18(%rbp)
  jne    L1
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void reverseWords(char *s) {
  int beg = 0, end = 0, hasSpace = 0;
  char *cur = s;
  removeDupSpace(s);
  size_t len = 0;
  for (; *cur; len++) {
    if (isspace(*cur)) {
      hasSpace = 1;
      end = cur - 1 - s;
      reverse(s, beg, end);
      beg = (++cur) - s;
    } else
      cur++;
  }
  if (hasSpace == 1) {
    end = cur - 1 - s;
    reverse(s, beg, end);
    reverse(s, 0, len - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseWords>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <removeDupSpace@plt>
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L55
  lea    0x1(%r12),%rbx
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x1,%r15d
  jmp    L63
L27:
  movzbl (%rax),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L36
L63:
  mov    %rbx,%rbp
  sub    %r12,%rbp
  sub    $0x1,%rbp
  movsbl %dil,%edi
  call   <isspace@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  test   %rdx,%rdx
  je     L27
  lea    -0x2(%rbx),%rdx
  sub    %r12,%rdx
  movslq %edx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %rbx,%rax
  mov    %ebx,%r13d
  sub    %r12d,%r13d
  mov    %r15d,%r14d
  jmp    L27
L36:
  cmp    $0x1,%r14d
  je     L8
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  lea    -0x1(%rax),%rdx
  mov    %rdx,%rax
  sub    %r12,%rax
  movslq %eax,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <reverse@plt>
  jmp    L55
```

assistant: ```c
void reverseWords(char *s) {
  int beg = 0, end = 0, hasSpace = 0;
  char *cur = s;
  removeDupSpace(s);
  size_t len = 0;
  for (; *cur; len++) {
    if (isspace(*cur)) {
      hasSpace = 1;
      end = cur - 1 - s;
      reverse(s, beg, end);
      beg = (++cur) - s;
    } else
      cur++;
  }
  if (hasSpace == 1) {
    end = cur - 1 - s;
    reverse(s, beg, end);
    reverse(s, 0, len - 1);
  }
}
```