ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_url>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    D14(%rip),%rsi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    $0x1,%r8d
  test   %rax,%rax
  je     L7
  lea    0x2(%rax),%rdi
  mov    $0x2f,%esi
  mov    %rdi,0x0(%rbp)
  call   <strchr@plt>
  test   %rax,%rax
  je     L10
  lea    0x1(%rax),%rdi
  movb   $0x0,(%rax)
  mov    %rdi,(%rbx)
  call   <strlen@plt>
  mov    (%rbx),%rsi
  lea    D18(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %r8d,%r8d
L7:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movq   $0x0,(%rbx)
  xor    %r8d,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D14: //

tool: D18: DEBUG: path = %s, len = %zd


assistant: ```c
int parse_url(const char *uri, char **host, char **path) {
  char *pos;
  pos = strstr(uri, "//");
  if (!pos) {
    return 1;
  }
  *host = pos + 2;
  pos = strchr(*host, '/');
  if (!pos) {
    *path = NULL;
  } else {
    *pos = '\0';
    *path = pos + 1;
    printf("DEBUG: path = %s, len = %zd\n", *path, strlen(*path));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x34(%rbp)
  movl   $0x39,-0x30(%rbp)
  movl   $0x22,-0x2c(%rbp)
  movl   $0x1a,-0x28(%rbp)
  movl   $0x4d,-0x24(%rbp)
  movl   $0x59,-0x20(%rbp)
  movl   $0x16,-0x1c(%rbp)
  movl   $0x2d,-0x18(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <selectionSort@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L26
L2:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L26:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: %d  

assistant: ```c
int main() {
  int n = 7, i;
  int a[] = {57, 34, 26, 77, 89, 22, 45};
  selectionSort(a, n);
  for (i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x39,(%rsp)
  movl   $0x22,0x4(%rsp)
  movl   $0x1a,0x8(%rsp)
  movl   $0x4d,0xc(%rsp)
  movl   $0x59,0x10(%rsp)
  movl   $0x16,0x14(%rsp)
  movl   $0x2d,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <selectionSort@plt>
  lea    0x1c(%rsp),%r12
  lea    D0(%rip),%rbp
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: %d  

assistant: ```c
int main() {
  int n = 7, i;
  int a[] = {57, 34, 26, 77, 89, 22, 45};
  selectionSort(a, n);
  for (i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2200000039,%rax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  movl   $0x2d,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x4d0000001a,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1600000059,%rax
  mov    %rax,0x10(%rsp)
  call   <selectionSort@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: %d  

assistant: ```c
int main() {
  int n = 7, i;
  int a[] = {57, 34, 26, 77, 89, 22, 45};
  selectionSort(a, n);
  for (i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    D28(%rip),%rax
  mov    %rbx,%rdi
  movl   $0x2d,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <selectionSort@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D11
type: byte[16]
name: disassemble_data
arguments: data_tag: D28
type: byte[8]

tool: D13: %d  

tool: {"D11": [0x39,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0x1a,0x00,0x00,0x00,0x4d,0x00,0x00,0x00]}

tool: {"D28": [0x59,0x00,0x00,0x00,0x16,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int n = 7, i;
  int a[] = {57, 34, 26, 77, 89, 22, 45};
  selectionSort(a, n);
  for (i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parseline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  mov    %rdi,%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx),%rdx
  movb   $0x20,(%rax,%rdx,1)
  movzbl D2(%rip),%eax
  cmp    $0x20,%al
  jne    L7
L141:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L141
L7:
  cmp    $0x27,%al
  je     L16
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
L132:
  test   %rax,%rax
  je     L115
  mov    %r14,%r12
  mov    $0x0,%ebp
  jmp    L147
L16:
  add    $0x1,%rbx
  mov    $0x27,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  jmp    L132
L104:
  add    $0x1,%rbx
  mov    $0x27,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
L70:
  add    $0x8,%r12
  test   %rax,%rax
  je     L28
L147:
  mov    %ebp,%r13d
  add    $0x1,%ebp
  mov    %rbx,(%r12)
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%eax
  cmp    $0x20,%al
  jne    L11
L18:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L18
L11:
  cmp    $0x27,%al
  je     L104
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  jmp    L70
L28:
  movslq %ebp,%rax
  lea    0x0(,%rax,8),%rdx
  movq   $0x0,(%r14,%rax,8)
  mov    $0x1,%eax
  test   %ebp,%ebp
  je     L80
  mov    -0x8(%r14,%rdx,1),%rdx
  mov    $0x0,%eax
  cmpb   $0x26,(%rdx)
  je     L95
L80:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L95:
  movslq %r13d,%r13
  movq   $0x0,(%r14,%r13,8)
  mov    $0x1,%eax
  jmp    L80
L115:
  movq   $0x0,(%r14)
  mov    $0x1,%eax
  jmp    L80
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  if (*buf == '\'') {
    buf++;
    delim = strchr(buf, '\'');
  } else {
    delim = strchr(buf, ' ');
  }
  while (delim) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
    if (*buf == '\'') {
      buf++;
      delim = strchr(buf, '\'');
    } else {
      delim = strchr(buf, ' ');
    }
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0) {
    argv[--argc] = NULL;
  }
  return bg;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parseline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,-0x1(%rax,%rbx,1)
  movzbl D19(%rip),%eax
  cmp    $0x20,%al
  jne    L97
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L44
L97:
  cmp    $0x27,%al
  je     L45
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
L25:
  mov    %r12,%r14
  xor    %ebp,%ebp
  nop
L40:
  mov    %rbx,(%r14)
  lea    0x1(%rax),%rbx
  add    $0x1,%ebp
  mov    %r14,%r13
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%eax
  cmp    $0x20,%al
  jne    L56
  nopl   0x0(%rax,%rax,1)
L87:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L87
L56:
  cmp    $0x27,%al
  je     L101
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
L32:
  add    $0x8,%r14
  test   %rax,%rax
  jne    L40
  movslq %ebp,%rbp
  mov    -0x8(%r12,%rbp,8),%rdx
  movq   $0x0,(%r12,%rbp,8)
  cmpb   $0x26,(%rdx)
  je     L70
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L101:
  add    $0x1,%rbx
  mov    $0x27,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  jmp    L32
L45:
  add    $0x1,%rbx
  mov    $0x27,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L25
L3:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  movq   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L70:
  movq   $0x0,0x0(%r13)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  if (*buf == '\'') {
    buf++;
    delim = strchr(buf, '\'');
  } else {
    delim = strchr(buf, ' ');
  }
  while (delim) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
    if (*buf == '\'') {
      buf++;
      delim = strchr(buf, '\'');
    } else {
      delim = strchr(buf, ' ');
    }
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0) {
    argv[--argc] = NULL;
  }
  return bg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,-0x1(%rax,%rbx,1)
  movzbl D7(%rip),%eax
  cmp    $0x20,%al
  jne    L88
  nopl   0x0(%rax,%rax,1)
L59:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L59
L88:
  cmp    $0x27,%al
  je     L85
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
L71:
  mov    %r12,%r14
  xor    %ebp,%ebp
  nop
L16:
  mov    %rbx,(%r14)
  lea    0x1(%rax),%rbx
  add    $0x1,%ebp
  mov    %r14,%r13
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%eax
  cmp    $0x20,%al
  jne    L3
  nopl   0x0(%rax,%rax,1)
L94:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L94
L3:
  mov    $0x20,%esi
  cmp    $0x27,%al
  jne    L51
  add    $0x1,%rbx
  mov    $0x27,%esi
L51:
  mov    %rbx,%rdi
  add    $0x8,%r14
  call   <strchr@plt>
  test   %rax,%rax
  jne    L16
  movslq %ebp,%rbp
  xor    %eax,%eax
  mov    -0x8(%r12,%rbp,8),%rdx
  movq   $0x0,(%r12,%rbp,8)
  cmpb   $0x26,(%rdx)
  je     L30
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L85:
  add    $0x1,%rbx
  mov    $0x27,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L71
L8:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  movq   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  movq   $0x0,0x0(%r13)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  if (*buf == '\'') {
    buf++;
    delim = strchr(buf, '\'');
  } else {
    delim = strchr(buf, ' ');
  }
  while (delim) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
    if (*buf == '\'') {
      buf++;
      delim = strchr(buf, '\'');
    } else {
      delim = strchr(buf, ' ');
    }
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0) {
    argv[--argc] = NULL;
  }
  return bg;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x3c(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%ecx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x38(%rbp)
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    $0x7a69,%edi
  call   <htons@plt>
  mov    %eax,-0x28(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    -0x38(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <listen@plt>
  movl   $0x10,-0x40(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    %eax,-0x34(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  int sockfd, new_sockfd;
  struct sockaddr_in host_addr, client_addr;
  socklen_t sin_size;
  int yes = 1;
  sockfd = socket(PF_INET, SOCK_STREAM, 0);
  host_addr.sin_family = AF_INET;
  host_addr.sin_port = htons(31337);
  host_addr.sin_addr.s_addr = INADDR_ANY;
  memset(&(host_addr.sin_zero), '\0', 8);
  bind(sockfd, (struct sockaddr *)&host_addr, sizeof(struct sockaddr));
  listen(sockfd, 4);
  sin_size = sizeof(struct sockaddr_in);
  new_sockfd = accept(sockfd, (struct sockaddr *)&client_addr, &sin_size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D37(%rip),%rax
  mov    (%rax),%esi
  mov    D30(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x1c(%rsp)
  mov    $0x7a69,%edi
  call   <htons@plt>
  mov    %eax,0x18(%rsp)
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  lea    0x10(%rsp),%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  movl   $0x10,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %ebx,%edi
  call   <accept@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int sockfd, new_sockfd;
  struct sockaddr_in host_addr, client_addr;
  socklen_t sin_size;
  int yes = 1;
  sockfd = socket(PF_INET, SOCK_STREAM, 0);
  host_addr.sin_family = AF_INET;
  host_addr.sin_port = htons(31337);
  host_addr.sin_addr.s_addr = INADDR_ANY;
  memset(&(host_addr.sin_zero), '\0', 8);
  bind(sockfd, (struct sockaddr *)&host_addr, sizeof(struct sockaddr));
  listen(sockfd, 4);
  sin_size = sizeof(struct sockaddr_in);
  new_sockfd = accept(sockfd, (struct sockaddr *)&client_addr, &sin_size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  lea    0x10(%rsp),%r12
  mov    (%rax),%esi
  mov    D31(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    $0x7a69,%edi
  mov    %eax,%ebp
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x1c(%rsp)
  call   <htons@plt>
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r12,%rdi
  mov    %eax,0x18(%rsp)
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <bind@plt>
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <listen@plt>
  lea    0xc(%rsp),%rdx
  mov    %ebp,%edi
  lea    0x20(%rsp),%rsi
  movl   $0x10,0xc(%rsp)
  call   <accept@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int sockfd, new_sockfd;
  struct sockaddr_in host_addr, client_addr;
  socklen_t sin_size;
  int yes = 1;
  sockfd = socket(PF_INET, SOCK_STREAM, 0);
  host_addr.sin_family = AF_INET;
  host_addr.sin_port = htons(31337);
  host_addr.sin_addr.s_addr = INADDR_ANY;
  memset(&(host_addr.sin_zero), '\0', 8);
  bind(sockfd, (struct sockaddr *)&host_addr, sizeof(struct sockaddr));
  listen(sockfd, 4);
  sin_size = sizeof(struct sockaddr_in);
  new_sockfd = accept(sockfd, (struct sockaddr *)&client_addr, &sin_size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  lea    0x10(%rsp),%r12
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    $0x7a69,%edi
  mov    %eax,%ebp
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x1c(%rsp)
  call   <htons@plt>
  mov    D32(%rip),%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  movd   %eax,%xmm1
  movd   (%rdx),%xmm0
  mov    $0x8,%edx
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x14(%rsp)
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <bind@plt>
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <listen@plt>
  lea    0xc(%rsp),%rdx
  mov    %ebp,%edi
  lea    0x20(%rsp),%rsi
  movl   $0x10,0xc(%rsp)
  call   <accept@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int sockfd, new_sockfd;
  struct sockaddr_in host_addr, client_addr;
  socklen_t sin_size;
  int yes = 1;
  sockfd = socket(PF_INET, SOCK_STREAM, 0);
  host_addr.sin_family = AF_INET;
  host_addr.sin_port = htons(31337);
  host_addr.sin_addr.s_addr = INADDR_ANY;
  memset(&(host_addr.sin_zero), '\0', 8);
  bind(sockfd, (struct sockaddr *)&host_addr, sizeof(struct sockaddr));
  listen(sockfd, 4);
  sin_size = sizeof(struct sockaddr_in);
  new_sockfd = accept(sockfd, (struct sockaddr *)&client_addr, &sin_size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softboundmpx_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_strrchr(const char *s, int c) {
  char *ret_ptr = strrchr(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<softboundmpx_strrchr>:
  endbr64
  push   %rbx
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_strrchr(const char *s, int c) {
  char *ret_ptr = strrchr(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<softboundmpx_strrchr>:
  endbr64
  push   %r12
  call   <strrchr@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  call   <__softboundmpx_propagate_metadata_shadow_stack_from@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_strrchr(const char *s, int c) {
  char *ret_ptr = strrchr(s, c);
  __softboundmpx_propagate_metadata_shadow_stack_from(1, 0);
  return ret_ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clear_vector_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L12
L13:
  mov    %rbx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x1,%rbx
L12:
  cmp    -0x18(%rbp),%rbx
  jle    L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void clear_vector_n(double *vec, long int n) {
  register long i;
  for (i = 0; i <= n; i++)
    vec[i] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clear_vector_n>:
  endbr64
  test   %rsi,%rsi
  js     L18
  mov    %rdi,%rax
  lea    0x8(%rdi,%rsi,8),%rdx
L14:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
L18:
  ret
```

assistant: ```c
void clear_vector_n(double *vec, long int n) {
  register long i;
  for (i = 0; i <= n; i++)
    vec[i] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clear_vector_n>:
  endbr64
  test   %rsi,%rsi
  js     L2
  lea    0x8(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void clear_vector_n(double *vec, long int n) {
  register long i;
  for (i = 0; i <= n; i++)
    vec[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_vector_n>:
  endbr64
  test   %rsi,%rsi
  js     L3
  lea    0x8(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void clear_vector_n(double *vec, long int n) {
  register long i;
  for (i = 0; i <= n; i++)
    vec[i] = 0;
}
```