ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  lea    0x19(%rsp),%rbp
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  add    $0x41,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L8
  movb   $0x4d,0xb(%rsp)
  movb   $0x41,0xc(%rsp)
  movb   $0x47,0xd(%rsp)
  movb   $0x49,0xe(%rsp)
  movb   $0x43,0xf(%rsp)
  movb   $0x41,0x10(%rsp)
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char vetor[26];
  int i;
  srand((unsigned)time(NULL));
  for (i = 0; i < 25; i++) {
    vetor[i] = (rand() % 25) + 65;
  }
  vetor[11] = 'M';
  vetor[12] = 'A';
  vetor[13] = 'G';
  vetor[14] = 'I';
  vetor[15] = 'C';
  vetor[16] = 'A';
  printf("%s", vetor);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x19(%rsp),%rbx
  call   <time@plt>
  mov    %rbp,%r12
  mov    %eax,%edi
  call   <srand@plt>
  nopl   (%rax)
L18:
  xor    %eax,%eax
  add    $0x1,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  add    $0x41,%eax
  mov    %al,-0x1(%r12)
  cmp    %rbx,%r12
  jne    L18
  mov    $0x4143,%eax
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  movl   $0x4947414d,0xb(%rsp)
  mov    %ax,0xf(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char vetor[26];
  int i;
  srand((unsigned)time(NULL));
  for (i = 0; i < 25; i++) {
    vetor[i] = (rand() % 25) + 65;
  }
  vetor[11] = 'M';
  vetor[12] = 'A';
  vetor[13] = 'G';
  vetor[14] = 'I';
  vetor[15] = 'C';
  vetor[16] = 'A';
  printf("%s", vetor);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x19(%rsp),%rbx
  call   <time@plt>
  mov    %rbp,%r12
  mov    %eax,%edi
  call   <srand@plt>
  nopl   (%rax)
L16:
  xor    %eax,%eax
  add    $0x1,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  add    $0x41,%eax
  mov    %al,-0x1(%r12)
  cmp    %r12,%rbx
  jne    L16
  mov    $0x4143,%eax
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  movl   $0x4947414d,0xb(%rsp)
  mov    %ax,0xf(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char vetor[26];
  int i;
  srand((unsigned)time(NULL));
  for (i = 0; i < 25; i++) {
    vetor[i] = (rand() % 25) + 65;
  }
  vetor[11] = 'M';
  vetor[12] = 'A';
  vetor[13] = 'G';
  vetor[14] = 'I';
  vetor[15] = 'C';
  vetor[16] = 'A';
  printf("%s", vetor);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factorizacionPrimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getFactorPrimo@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: %ld


assistant: ```c
void factorizacionPrimo(long n) {
  n = getFactorPrimo(n);
  if (n > 1)
    printf("%ld\n", n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorizacionPrimo>:
  endbr64
  sub    $0x8,%rsp
  call   <getFactorPrimo@plt>
  cmp    $0x1,%rax
  jg     L8
L11:
  add    $0x8,%rsp
  ret
L8:
  mov    %rax,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %ld


assistant: ```c
void factorizacionPrimo(long n) {
  n = getFactorPrimo(n);
  if (n > 1)
    printf("%ld\n", n);
}
```
user: What is the c source code of the assembly code below:

```asm
<factorizacionPrimo>:
  endbr64
  sub    $0x8,%rsp
  call   <getFactorPrimo@plt>
  cmp    $0x1,%rax
  jg     L1
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rax,%rsi
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %ld


assistant: ```c
void factorizacionPrimo(long n) {
  n = getFactorPrimo(n);
  if (n > 1)
    printf("%ld\n", n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorizacionPrimo>:
  endbr64
  sub    $0x8,%rsp
  call   <getFactorPrimo@plt>
  cmp    $0x1,%rax
  jg     L0
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: %ld


assistant: ```c
void factorizacionPrimo(long n) {
  n = getFactorPrimo(n);
  if (n > 1)
    printf("%ld\n", n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <generate_array@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    $0x0,%edx
  mov    %ebx,%esi
  call   <check_array_and_print@plt>
  cmp    $0x6,%ebp
  ja     L0
  mov    %ebp,%eax
  lea    D0(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_selection@plt>
L0:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <check_array_and_print@plt>
  mov    %rsp,%rdi
  mov    %ebx,%esi
  call   <destroy_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_bubble@plt>
  jmp    L0
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_insertion@plt>
  jmp    L0
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_merge@plt>
  jmp    L0
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_quick@plt>
  jmp    L0
  mov    %ebx,%esi
  mov    (%rsp),%rdi
  call   <sort_counting@plt>
  jmp    L0
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(int size, int max, int code) {
  int *array;
  array = generate_array(size, max);
  check_array_and_print(array, size, 0);
  switch (code) {
  case 1:
    sort_selection(array, size);
    break;
  case 2:
    sort_bubble(array, size);
    break;
  case 3:
    sort_insertion(array, size);
    break;
  case 4:
    sort_merge(array, size);
    break;
  case 5:
    sort_quick(array, size);
    break;
  case 6:
    sort_counting(array, size);
    break;
  default:
    break;
  }
  check_array_and_print(array, size, code);
  destroy_array(&array, size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trailingZeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  jg     L7
  mov    $0x0,%eax
  jmp    L35
L7:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  if (n < 5)
    return 0;
  int c;
  c = 0;
  while (n > 0) {
    n /= 5;
    c += n;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trailingZeroes>:
  endbr64
  mov    $0x0,%edx
  cmp    $0x4,%edi
  jle    L18
L19:
  mov    %edi,%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  add    %eax,%edx
  cmp    $0x4,%ecx
  jg     L19
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  if (n < 5)
    return 0;
  int c;
  c = 0;
  while (n > 0) {
    n /= 5;
    c += n;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trailingZeroes>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L0
  mov    $0xcccccccd,%edx
L12:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x22,%rdi
  add    %edi,%eax
  test   %edi,%edi
  jne    L12
L0:
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  if (n < 5)
    return 0;
  int c;
  c = 0;
  while (n > 0) {
    n /= 5;
    c += n;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trailingZeroes>:
  endbr64
  xor    %eax,%eax
  cmp    $0x4,%edi
  jle    L1
  mov    $0xcccccccd,%edx
L2:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x22,%rdi
  add    %edi,%eax
  test   %edi,%edi
  jne    L2
L1:
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  if (n < 5)
    return 0;
  int c;
  c = 0;
  while (n > 0) {
    n /= 5;
    c += n;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ir_get_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ir_get_code@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ir_hash_match@plt>
  jmp    L19
L18:
  mov    $0xffffffff,%eax
L19:
  leave
  ret
```

assistant: ```c
int ir_get_command(void) {
  unsigned char *code;
  code = ir_get_code();
  if (code) {
    return ir_hash_match(code);
  } else {
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ir_get_command>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ir_get_code@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  call   <ir_hash_match@plt>
L7:
  add    $0x8,%rsp
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int ir_get_command(void) {
  unsigned char *code;
  code = ir_get_code();
  if (code) {
    return ir_hash_match(code);
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ir_get_command>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ir_get_code@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1060 <ir_hash_match@plt>
L9:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ir_get_command(void) {
  unsigned char *code;
  code = ir_get_code();
  if (code) {
    return ir_hash_match(code);
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ir_get_command>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ir_get_code@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1060 <ir_hash_match@plt>
L3:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ir_get_command(void) {
  unsigned char *code;
  code = ir_get_code();
  if (code) {
    return ir_hash_match(code);
  } else {
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L20:
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L5:
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D8
type: string

tool: D5: Input two numbers to add: 

tool: D3: %f


tool: D8: %lf %lf

assistant: ```c
int main() {
  double x, y;
  printf("Input two numbers to add: ");
  while (scanf("%lf %lf", &x, &y))
    printf("%f\n", x + y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D23(%rip),%rbx
  lea    D22(%rip),%r13
  jmp    L27
L2:
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L27:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string

tool: D0: Input two numbers to add: 

tool: D23: %lf %lf

tool: D22: %f


assistant: ```c
int main() {
  double x, y;
  printf("Input two numbers to add: ");
  while (scanf("%lf %lf", &x, &y))
    printf("%f\n", x + y);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  call   <printf@plt>
  jmp    L4
  nopl   0x0(%rax)
L23:
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L4:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D8: Input two numbers to add: 

tool: D3: %f


tool: D13: %lf %lf

assistant: ```c
int main() {
  double x, y;
  printf("Input two numbers to add: ");
  while (scanf("%lf %lf", &x, &y))
    printf("%f\n", x + y);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  lea    D27(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  call   <printf@plt>
  jmp    L17
  nopl   0x0(%rax)
L23:
  movsd  0x8(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L23
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string

tool: D15: Input two numbers to add: 

tool: D27: %f


tool: D22: %lf %lf

assistant: ```c
int main() {
  double x, y;
  printf("Input two numbers to add: ");
  while (scanf("%lf %lf", &x, &y))
    printf("%f\n", x + y);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<criar_novo_consumidor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L5
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L5:
  mov    $0x0,%eax
  call   <cliente@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: Erro na criacao do processo consumidor


assistant: ```c
void criar_novo_consumidor() {
  int numero_novo_processo;
  numero_novo_processo = fork();
  if (numero_novo_processo == -1) {
    printf("Erro na criacao do processo consumidor\n");
  } else {
    cliente();
    exit(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<criar_novo_consumidor>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    $0x0,%eax
  call   <cliente@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L5:
  add    $0x8,%rsp
  ret
L3:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Erro na criacao do processo consumidor


assistant: ```c
void criar_novo_consumidor() {
  int numero_novo_processo;
  numero_novo_processo = fork();
  if (numero_novo_processo == -1) {
    printf("Erro na criacao do processo consumidor\n");
  } else {
    cliente();
    exit(0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<criar_novo_consumidor>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L3
  xor    %eax,%eax
  call   <cliente@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10a0 <exit@plt>
  nopl   0x0(%rax)
L3:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string

tool: D1: Erro na criacao do processo consumidor


assistant: ```c
void criar_novo_consumidor() {
  int numero_novo_processo;
  numero_novo_processo = fork();
  if (numero_novo_processo == -1) {
    printf("Erro na criacao do processo consumidor\n");
  } else {
    cliente();
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<criar_novo_consumidor>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L9
  xor    %eax,%eax
  call   <cliente@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10a0 <exit@plt>
  nopl   0x0(%rax)
L9:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: Erro na criacao do processo consumidor


assistant: ```c
void criar_novo_consumidor() {
  int numero_novo_processo;
  numero_novo_processo = fork();
  if (numero_novo_processo == -1) {
    printf("Erro na criacao do processo consumidor\n");
  } else {
    cliente();
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crypto_auth_hmacsha256_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <crypto_auth_hmacsha256@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_verify_32@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int crypto_auth_hmacsha256_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[32];
  crypto_auth_hmacsha256(correct, in, inlen, k);
  return crypto_verify_32(h, correct);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crypto_auth_hmacsha256_verify>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <crypto_auth_hmacsha256@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <crypto_verify_32@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_auth_hmacsha256_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[32];
  crypto_auth_hmacsha256(correct, in, inlen, k);
  return crypto_verify_32(h, correct);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypto_auth_hmacsha256_verify>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <crypto_auth_hmacsha256@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_verify_32@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_auth_hmacsha256_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[32];
  crypto_auth_hmacsha256(correct, in, inlen, k);
  return crypto_verify_32(h, correct);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<crypto_auth_hmacsha256_verify>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <crypto_auth_hmacsha256@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_verify_32@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_auth_hmacsha256_verify(const unsigned char *h, const unsigned char *in, unsigned long long inlen, const unsigned char *k) {
  unsigned char correct[32];
  crypto_auth_hmacsha256(correct, in, inlen, k);
  return crypto_verify_32(h, correct);
}
```