user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x17,-0x50(%rbp)
  movl   $0x2b,-0x4c(%rbp)
  movl   $0xc,-0x48(%rbp)
  movl   $0x59,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  lea    D90(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D55(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x5,-0x64(%rbp)
  movl   $0x0,-0x68(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L40
L60:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L40:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L60
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L43
L3:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L43:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L3
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L33
L76:
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x68(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L33:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L76
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  jmp    L55
L42:
  mov    -0x60(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x58(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x8,-0x58(%rbp)
  addq   $0x4,-0x60(%rbp)
L55:
  lea    -0x50(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x64(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jl     L42
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D90
type_infered: string
name: retrieve_data
arguments: label: D63
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D55
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D61
type_infered: string

tool: D90: Alan

tool: D63: Frank

tool: D27: Many

tool: D55: John

tool: D12: Lisa

tool: D10: %s is %d years old.


tool: D31: ----------------------

tool: D61: %s is %d years old,


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {23, 43, 12, 89, 2};
  char *names[] = {"Alan", "Frank", "Many", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%s is %d years old.\n", names[i], ages[i]);
  }
  printf("----------------------\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count; i++) {
    printf("%s is %d years old,\n", *(cur_name + i), *(cur_age + i));
  }
  printf("----------------------\n");
  for (i = 0; i < count; i++) {
    printf("%s is %d years old,\n", cur_name[i], cur_age[i]);
  }
  printf("----------------------\n");
  for (cur_name = names, cur_age = ages; (cur_age - ages) < count; cur_name++, cur_age++) {
    printf("%s is %d years old,\n", *cur_name, *cur_age);
  }
  printf("----------------------\n");
  return 0;
}
```