ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<accuracy>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L28
  lea    -0x1(%rdx),%eax
  mov    %rsi,%rcx
  cmp    $0x2,%eax
  jbe    L21
  mov    %edx,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%esi
  shl    $0x4,%rsi
  xchg   %ax,%ax
L44:
  movups (%rdi,%rax,1),%xmm1
  movups (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  subps  %xmm3,%xmm1
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L44
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  cmp    %edx,%esi
  je     L23
L77:
  mov    %edx,%r8d
  sub    %esi,%r8d
  cmp    $0x1,%r8d
  je     L72
  movq   (%rdi,%rsi,4),%xmm1
  movq   (%rcx,%rsi,4),%xmm2
  mov    %r8d,%esi
  and    $0xfffffffe,%esi
  subps  %xmm2,%xmm1
  add    %esi,%eax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%r8d
  je     L23
L72:
  cltq
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rcx,%rax,4),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
L23:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %rax,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pxor   %xmm0,%xmm0
  jmp    L23
L21:
  xor    %esi,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L77
```

assistant: ```c
float accuracy(float *arr1, float *arr2, int len) {
  float err = 0.0;
  int i;
  for (i = 0; i < len; i++) {
    err += (arr1[i] - arr2[i]) * (arr1[i] - arr2[i]);
  }
  return (float)sqrt(err / len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Openspace@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  Openspace();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Openspace@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  Openspace();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Openspace@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  Openspace();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Openspace@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  Openspace();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imprime_vetor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D7: %.5e


assistant: ```c
void imprime_vetor(int n, double b[]) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%.5e\n", b[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imprime_vetor>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  lea    D3(%rip),%rbp
L13:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: %.5e


assistant: ```c
void imprime_vetor(int n, double b[]) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%.5e\n", b[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imprime_vetor>:
  endbr64
  test   %edi,%edi
  jle    L17
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L13:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: %.5e


assistant: ```c
void imprime_vetor(int n, double b[]) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%.5e\n", b[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<imprime_vetor>:
  endbr64
  test   %edi,%edi
  jle    L12
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L7:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: %.5e


assistant: ```c
void imprime_vetor(int n, double b[]) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%.5e\n", b[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ILibDecompressString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x1,%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x3f,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x6,%al
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x2,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L4
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ILibDecompressString(unsigned char *CurrentCompressed, const int bufferLength, const int DecompressedLength) {
  unsigned char *RetVal = (char *)malloc(DecompressedLength + 1);
  unsigned char *CurrentUnCompressed = RetVal;
  unsigned char *EndPtr = RetVal + DecompressedLength;
  int offset, length;
  do {
    memcpy(CurrentUnCompressed, CurrentCompressed + 1, (int)*CurrentCompressed);

    CurrentUnCompressed += (int)*CurrentCompressed;
    CurrentCompressed += 1 + ((int)*CurrentCompressed);
    length = (unsigned short)((*(CurrentCompressed)) & 63);
    offset = ((unsigned short)(*(CurrentCompressed + 1)) << 2) + (((unsigned short)(*(CurrentCompressed))) >> 6);
    memcpy(CurrentUnCompressed, CurrentUnCompressed - offset, length);

    CurrentCompressed += 2;
    CurrentUnCompressed += length;
  } while (CurrentUnCompressed < EndPtr);
  RetVal[DecompressedLength] = 0;
  return (RetVal);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ILibDecompressString>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%r12d
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %r12d,%r12
  add    %rax,%r12
  mov    %rax,%rbp
L1:
  movzbl (%rbx),%edx
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movzbl (%rbx),%eax
  movzbl %al,%r14d
  add    %rbp,%r14
  movzbl %al,%eax
  lea    0x1(%rbx,%rax,1),%rbx
  movzbl (%rbx),%eax
  mov    %eax,%ebp
  and    $0x3f,%ebp
  mov    %eax,%edx
  and    $0x3f,%edx
  movzbl 0x1(%rbx),%ecx
  shr    $0x6,%al
  movzbl %al,%eax
  lea    (%rax,%rcx,4),%eax
  cltq
  mov    %r14,%rsi
  sub    %rax,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  add    $0x2,%rbx
  movzbl %bpl,%ebp
  add    %r14,%rbp
  cmp    %rbp,%r12
  ja     L1
  movb   $0x0,(%r12)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ILibDecompressString(unsigned char *CurrentCompressed, const int bufferLength, const int DecompressedLength) {
  unsigned char *RetVal = (char *)malloc(DecompressedLength + 1);
  unsigned char *CurrentUnCompressed = RetVal;
  unsigned char *EndPtr = RetVal + DecompressedLength;
  int offset, length;
  do {
    memcpy(CurrentUnCompressed, CurrentCompressed + 1, (int)*CurrentCompressed);

    CurrentUnCompressed += (int)*CurrentCompressed;
    CurrentCompressed += 1 + ((int)*CurrentCompressed);
    length = (unsigned short)((*(CurrentCompressed)) & 63);
    offset = ((unsigned short)(*(CurrentCompressed + 1)) << 2) + (((unsigned short)(*(CurrentCompressed))) >> 6);
    memcpy(CurrentUnCompressed, CurrentUnCompressed - offset, length);

    CurrentCompressed += 2;
    CurrentUnCompressed += length;
  } while (CurrentUnCompressed < EndPtr);
  RetVal[DecompressedLength] = 0;
  return (RetVal);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ILibDecompressString>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  add    %rax,%rbp
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%r14),%edx
  lea    0x1(%r14),%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movzbl (%r14),%edx
  lea    0x1(%r14,%rdx,1),%r14
  add    %rdx,%rbx
  movzbl (%r14),%eax
  movzbl 0x1(%r14),%ecx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  add    $0x2,%r14
  mov    %eax,%r13d
  mov    %eax,%edx
  shr    $0x6,%al
  movzbl %al,%eax
  and    $0x3f,%r13d
  and    $0x3f,%edx
  lea    (%rax,%rcx,4),%eax
  movzbl %r13b,%r13d
  cltq
  add    %r13,%rbx
  sub    %rax,%rsi
  call   <memcpy@plt>
  cmp    %rbx,%rbp
  ja     L9
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ILibDecompressString(unsigned char *CurrentCompressed, const int bufferLength, const int DecompressedLength) {
  unsigned char *RetVal = (char *)malloc(DecompressedLength + 1);
  unsigned char *CurrentUnCompressed = RetVal;
  unsigned char *EndPtr = RetVal + DecompressedLength;
  int offset, length;
  do {
    memcpy(CurrentUnCompressed, CurrentCompressed + 1, (int)*CurrentCompressed);

    CurrentUnCompressed += (int)*CurrentCompressed;
    CurrentCompressed += 1 + ((int)*CurrentCompressed);
    length = (unsigned short)((*(CurrentCompressed)) & 63);
    offset = ((unsigned short)(*(CurrentCompressed + 1)) << 2) + (((unsigned short)(*(CurrentCompressed))) >> 6);
    memcpy(CurrentUnCompressed, CurrentUnCompressed - offset, length);

    CurrentCompressed += 2;
    CurrentUnCompressed += length;
  } while (CurrentUnCompressed < EndPtr);
  RetVal[DecompressedLength] = 0;
  return (RetVal);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ILibDecompressString>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  add    %rax,%rbp
  mov    %rax,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%r14),%edx
  lea    0x1(%r14),%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movzbl (%r14),%edx
  lea    0x1(%r14,%rdx,1),%r14
  add    %rdx,%rbx
  movzbl (%r14),%eax
  movzbl 0x1(%r14),%ecx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  add    $0x2,%r14
  mov    %eax,%r13d
  mov    %eax,%edx
  shr    $0x6,%al
  movzbl %al,%eax
  and    $0x3f,%r13d
  and    $0x3f,%edx
  lea    (%rax,%rcx,4),%eax
  movzbl %r13b,%r13d
  cltq
  add    %r13,%rbx
  sub    %rax,%rsi
  call   <memcpy@plt>
  cmp    %rbx,%rbp
  ja     L3
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ILibDecompressString(unsigned char *CurrentCompressed, const int bufferLength, const int DecompressedLength) {
  unsigned char *RetVal = (char *)malloc(DecompressedLength + 1);
  unsigned char *CurrentUnCompressed = RetVal;
  unsigned char *EndPtr = RetVal + DecompressedLength;
  int offset, length;
  do {
    memcpy(CurrentUnCompressed, CurrentCompressed + 1, (int)*CurrentCompressed);

    CurrentUnCompressed += (int)*CurrentCompressed;
    CurrentCompressed += 1 + ((int)*CurrentCompressed);
    length = (unsigned short)((*(CurrentCompressed)) & 63);
    offset = ((unsigned short)(*(CurrentCompressed + 1)) << 2) + (((unsigned short)(*(CurrentCompressed))) >> 6);
    memcpy(CurrentUnCompressed, CurrentUnCompressed - offset, length);

    CurrentCompressed += 2;
    CurrentUnCompressed += length;
  } while (CurrentUnCompressed < EndPtr);
  RetVal[DecompressedLength] = 0;
  return (RetVal);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x150(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x28,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x0,-0x15c(%rbp)
  lea    -0x15c(%rbp),%rax
  mov    %rax,-0x158(%rbp)
  mov    -0x158(%rbp),%rdx
  lea    -0x150(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_message@plt>
  mov    -0x158(%rbp),%rdx
  lea    -0x150(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse_message@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  int message[81] = {0};
  int len = 0;
  int *chars = &len;
  read_message(message, chars);
  reverse_message(message, chars);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x168,%rsp
  mov    $0x28,%ecx
  mov    %fs:(%rcx),%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <read_message@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <reverse_message@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int message[81] = {0};
  int len = 0;
  int *chars = &len;
  read_message(message, chars);
  reverse_message(message, chars);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x28,%ecx
  push   %rbp
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %r12,%rsi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    %rbp,%rdi
  call   <read_message@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <reverse_message@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x168,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int message[81] = {0};
  int len = 0;
  int *chars = &len;
  read_message(message, chars);
  reverse_message(message, chars);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x28,%ecx
  push   %rbp
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %r12,%rsi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    %rbp,%rdi
  call   <read_message@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <reverse_message@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x168,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int message[81] = {0};
  int len = 0;
  int *chars = &len;
  read_message(message, chars);
  reverse_message(message, chars);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <_strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: Length of s is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int len;
  static char s[] = "It is";
  len = _strlen(s);
  printf("Length of s is %d\n", len);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <_strlen@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string

tool: D16: Length of s is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int len;
  static char s[] = "It is";
  len = _strlen(s);
  printf("Length of s is %d\n", len);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <_strlen@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: Length of s is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int len;
  static char s[] = "It is";
  len = _strlen(s);
  printf("Length of s is %d\n", len);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <_strlen@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
data_type: string

tool: D14: Length of s is %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int len;
  static char s[] = "It is";
  len = _strlen(s);
  printf("Length of s is %d\n", len);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <fonction_recursive@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  fonction_recursive(1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fonction_recursive@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fonction_recursive(1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fonction_recursive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fonction_recursive(1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fonction_recursive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fonction_recursive(1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decode_crysis_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_replace@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D26(%rip),%rdx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_replace@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D28
type: string
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D16
type: string

tool: D7: "

tool: D28: &quot;

tool: D26: &

tool: D16: &amp;

assistant: ```c
char *decode_crysis_val(char *val) {
  val = str_replace(val, "&quot;", "\"");
  return str_replace(val, "&amp;", "&");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decode_crysis_val>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdx
  lea    D27(%rip),%rsi
  call   <str_replace@plt>
  mov    %rax,%rdi
  lea    D26(%rip),%rdx
  lea    D37(%rip),%rsi
  call   <str_replace@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D37
type: string

tool: D17: "

tool: D27: &quot;

tool: D26: &

tool: D37: &amp;

assistant: ```c
char *decode_crysis_val(char *val) {
  val = str_replace(val, "&quot;", "\"");
  return str_replace(val, "&amp;", "&");
}
```
user: Translate the below assembly code into C programming language:

```asm
<decode_crysis_val>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdx
  lea    D16(%rip),%rsi
  call   <str_replace@plt>
  lea    D20(%rip),%rdx
  lea    D39(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1050 <str_replace@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D39
data_type: string

tool: D22: "

tool: D16: &quot;

tool: D20: &

tool: D39: &amp;

assistant: ```c
char *decode_crysis_val(char *val) {
  val = str_replace(val, "&quot;", "\"");
  return str_replace(val, "&amp;", "&");
}
```
user: What is the c source code of the assembly code below?

```asm
<decode_crysis_val>:
  endbr64
  sub    $0x8,%rsp
  lea    D35(%rip),%rdx
  lea    D24(%rip),%rsi
  call   <str_replace@plt>
  lea    D21(%rip),%rdx
  lea    D19(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1050 <str_replace@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string

tool: D35: "

tool: D24: &quot;

tool: D21: &

tool: D19: &amp;

assistant: ```c
char *decode_crysis_val(char *val) {
  val = str_replace(val, "&quot;", "\"");
  return str_replace(val, "&amp;", "&");
}
```