ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tanh>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  mulsd  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  divss  D56(%rip),%xmm0
  addss  D32(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movaps %xmm1,%xmm3
  divss  D0(%rip),%xmm3
  addss  %xmm0,%xmm3
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movaps %xmm1,%xmm0
  divss  D54(%rip),%xmm0
  addss  %xmm3,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movaps %xmm1,%xmm3
  divss  D30(%rip),%xmm3
  addss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  divss  D14(%rip),%xmm0
  addss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D56
type_guessed: byte[4]
name: read_data
arguments: tag: D32
type_guessed: f32
name: read_data
arguments: tag: D0
type_guessed: byte[4]
name: read_data
arguments: tag: D54
type_guessed: byte[4]
name: read_data
arguments: tag: D30
type_guessed: byte[4]
name: read_data
arguments: tag: D14
type_guessed: byte[4]

tool: {"D56": [0x00,0x00,0x40,0xc0]}

tool: D32: 0

tool: {"D0": [0x00,0x00,0x90,0xc1]}

tool: {"D54": [0x00,0x00,0xb4,0xc3]}

tool: {"D30": [0x00,0x40,0x6c,0xc6]}

tool: {"D14": [0x00,0xe4,0x84,0xc9]}

assistant: ```c
double tanh(double x) {
  float res = 0, pow = x, fact = -3;
  for (int i = 0; i < 5; i++) {
    res += pow / fact;
    pow *= x * x;
    fact *= (2 * (i + 1)) * (2 * (i + 1) + 1);
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tanh>:
  endbr64
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm2
  mulsd  %xmm0,%xmm0
  movaps %xmm2,%xmm3
  cvtss2sd %xmm2,%xmm2
  divss  D4(%rip),%xmm3
  addss  D45(%rip),%xmm3
  mulsd  %xmm0,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm1
  cvtss2sd %xmm2,%xmm2
  divss  D46(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  addss  %xmm3,%xmm1
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm3
  cvtss2sd %xmm2,%xmm2
  divss  D59(%rip),%xmm3
  mulsd  %xmm0,%xmm2
  addss  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm2,%xmm1
  movaps %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  divss  D44(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  addss  %xmm3,%xmm2
  cvtsd2ss %xmm0,%xmm0
  divss  D33(%rip),%xmm0
  addss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: byte[4]
name: unpack_data
arguments: data_label: D45
type: f32
name: unpack_data
arguments: data_label: D46
type: byte[4]
name: unpack_data
arguments: data_label: D59
type: byte[4]
name: unpack_data
arguments: data_label: D44
type: byte[4]
name: unpack_data
arguments: data_label: D33
type: byte[4]

tool: {"D4": [0x00,0x00,0x40,0xc0]}

tool: D45: 0

tool: {"D46": [0x00,0x00,0x90,0xc1]}

tool: {"D59": [0x00,0x00,0xb4,0xc3]}

tool: {"D44": [0x00,0x40,0x6c,0xc6]}

tool: {"D33": [0x00,0xe4,0x84,0xc9]}

assistant: ```c
double tanh(double x) {
  float res = 0, pow = x, fact = -3;
  for (int i = 0; i < 5; i++) {
    res += pow / fact;
    pow *= x * x;
    fact *= (2 * (i + 1)) * (2 * (i + 1) + 1);
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tanh>:
  endbr64
  pxor   %xmm2,%xmm2
  cvtsd2ss %xmm0,%xmm2
  mulsd  %xmm0,%xmm0
  movaps %xmm2,%xmm3
  cvtss2sd %xmm2,%xmm2
  divss  D5(%rip),%xmm3
  addss  D41(%rip),%xmm3
  mulsd  %xmm0,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm1
  cvtss2sd %xmm2,%xmm2
  divss  D36(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  addss  %xmm3,%xmm1
  cvtsd2ss %xmm2,%xmm2
  movaps %xmm2,%xmm3
  cvtss2sd %xmm2,%xmm2
  divss  D33(%rip),%xmm3
  mulsd  %xmm0,%xmm2
  addss  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm2,%xmm1
  movaps %xmm1,%xmm2
  cvtss2sd %xmm1,%xmm1
  divss  D4(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  addss  %xmm3,%xmm2
  cvtsd2ss %xmm0,%xmm0
  divss  D40(%rip),%xmm0
  addss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: byte[4]
name: parse_data
arguments: data_label: D41
type_guessed: f32
name: parse_data
arguments: data_label: D36
type_guessed: byte[4]
name: parse_data
arguments: data_label: D33
type_guessed: byte[4]
name: parse_data
arguments: data_label: D4
type_guessed: byte[4]
name: parse_data
arguments: data_label: D40
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x40,0xc0]}

tool: D41: 0

tool: {"D36": [0x00,0x00,0x90,0xc1]}

tool: {"D33": [0x00,0x00,0xb4,0xc3]}

tool: {"D4": [0x00,0x40,0x6c,0xc6]}

tool: {"D40": [0x00,0xe4,0x84,0xc9]}

assistant: ```c
double tanh(double x) {
  float res = 0, pow = x, fact = -3;
  for (int i = 0; i < 5; i++) {
    res += pow / fact;
    pow *= x * x;
    fact *= (2 * (i + 1)) * (2 * (i + 1) + 1);
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L11
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  jmp    L11
L16:
  mov    -0x8(%rbp),%rax
  mov    $0x100000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L16
L3:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: Allocated %d MB


assistant: ```c
int main(int argc, char **argv) {
  int max = -1;
  int mb = 0;
  char *buffer;
  if (argc > 1)
    max = atoi(argv[1]);
  while ((buffer = malloc(1024 * 1024)) != NULL && mb != max) {
    memset(buffer, 0, 1024 * 1024);
    mb++;
    printf("Allocated %d MB\n", mb);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffffff,%ebp
  cmp    $0x1,%edi
  jg     L15
L24:
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L17:
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %ebp,%ebx
  je     L38
  test   %rax,%rax
  je     L38
  mov    $0x100000,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L17
L15:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L24
L38:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: Allocated %d MB


assistant: ```c
int main(int argc, char **argv) {
  int max = -1;
  int mb = 0;
  char *buffer;
  if (argc > 1)
    max = atoi(argv[1]);
  while ((buffer = malloc(1024 * 1024)) != NULL && mb != max) {
    memset(buffer, 0, 1024 * 1024);
    mb++;
    printf("Allocated %d MB\n", mb);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  or     $0xffffffff,%ebp
  push   %rbx
  cmp    $0x1,%edi
  jle    L3
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L3:
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L38:
  cmp    %ebp,%ebx
  je     L24
  xor    %esi,%esi
  mov    $0x100000,%edx
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L12:
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L38
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: Allocated %d MB


assistant: ```c
int main(int argc, char **argv) {
  int max = -1;
  int mb = 0;
  char *buffer;
  if (argc > 1)
    max = atoi(argv[1]);
  while ((buffer = malloc(1024 * 1024)) != NULL && mb != max) {
    memset(buffer, 0, 1024 * 1024);
    mb++;
    printf("Allocated %d MB\n", mb);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  or     $0xffffffff,%ebp
  push   %rbx
  cmp    $0x1,%edi
  jle    L25
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L25:
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    %ebp,%ebx
  je     L19
  xor    %esi,%esi
  mov    $0x100000,%edx
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L7:
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L17
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: Allocated %d MB


assistant: ```c
int main(int argc, char **argv) {
  int max = -1;
  int mb = 0;
  char *buffer;
  if (argc > 1)
    max = atoi(argv[1]);
  while ((buffer = malloc(1024 * 1024)) != NULL && mb != max) {
    memset(buffer, 0, 1024 * 1024);
    mb++;
    printf("Allocated %d MB\n", mb);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<UNINSTALL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2f7e20662d206d72,%rax
  movabs $0x616c6c697a6f6d2e,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x736e6967756c702f,%rax
  movabs $0x7365726662696c2f,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x7265707061727768,%rax
  movabs $0x6c706873616c662d,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0x6f732e72657961,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void UNINSTALL(void) {
  char uninstall[] = "rm -f ~/.mozilla/plugins/libfreshwrapper-flashplayer.so";
  system(uninstall);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UNINSTALL>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x2f7e20662d206d72,%rax
  movabs $0x616c6c697a6f6d2e,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x736e6967756c702f,%rax
  movabs $0x7365726662696c2f,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x7265707061727768,%rax
  movabs $0x6c706873616c662d,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6f732e72657961,%rax
  mov    %rax,0x30(%rsp)
  mov    %rsp,%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void UNINSTALL(void) {
  char uninstall[] = "rm -f ~/.mozilla/plugins/libfreshwrapper-flashplayer.so";
  system(uninstall);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UNINSTALL>:
  endbr64
  sub    $0x48,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movabs $0x6f732e72657961,%rax
  movaps %xmm0,(%rsp)
  movdqa D15(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D12(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: byte[16]
name: read_data
arguments: tag: D15
datatype: byte[16]
name: read_data
arguments: tag: D12
datatype: byte[16]

tool: {"D8": [0x72,0x6d,0x20,0x2d,0x66,0x20,0x7e,0x2f,0x2e,0x6d,0x6f,0x7a,0x69,0x6c,0x6c,0x61]}

tool: {"D15": [0x2f,0x70,0x6c,0x75,0x67,0x69,0x6e,0x73,0x2f,0x6c,0x69,0x62,0x66,0x72,0x65,0x73]}

tool: {"D12": [0x68,0x77,0x72,0x61,0x70,0x70,0x65,0x72,0x2d,0x66,0x6c,0x61,0x73,0x68,0x70,0x6c]}

assistant: ```c
void UNINSTALL(void) {
  char uninstall[] = "rm -f ~/.mozilla/plugins/libfreshwrapper-flashplayer.so";
  system(uninstall);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UNINSTALL>:
  endbr64
  sub    $0x48,%rsp
  movdqa D29(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movabs $0x6f732e72657961,%rax
  movaps %xmm0,(%rsp)
  movdqa D20(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D6(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D20
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D6
type_guessed: byte[16]

tool: {"D29": [0x72,0x6d,0x20,0x2d,0x66,0x20,0x7e,0x2f,0x2e,0x6d,0x6f,0x7a,0x69,0x6c,0x6c,0x61]}

tool: {"D20": [0x2f,0x70,0x6c,0x75,0x67,0x69,0x6e,0x73,0x2f,0x6c,0x69,0x62,0x66,0x72,0x65,0x73]}

tool: {"D6": [0x68,0x77,0x72,0x61,0x70,0x70,0x65,0x72,0x2d,0x66,0x6c,0x61,0x73,0x68,0x70,0x6c]}

assistant: ```c
void UNINSTALL(void) {
  char uninstall[] = "rm -f ~/.mozilla/plugins/libfreshwrapper-flashplayer.so";
  system(uninstall);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xe50,%rsp
  mov    %rdi,-0x4e38(%rbp)
  mov    %rsi,-0x4e40(%rbp)
  mov    %rdx,-0x4e48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4e30(%rbp),%rcx
  mov    -0x4e48(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_arg_in_braces@plt>
  mov    %rax,-0x4e48(%rbp)
  mov    -0x4e40(%rbp),%rax
  mov    %rax,%rdi
  call   <get_list_length@plt>
  mov    %eax,%ecx
  lea    -0x4e30(%rbp),%rdx
  lea    -0x2720(%rbp),%rax
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x2720(%rbp),%rdx
  mov    -0x4e38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_internal_variable@plt>
  mov    -0x4e38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: {%s} {%d}

assistant: ```c
struct session *array_len(struct session *ses, struct listnode *list, char *arg) {
  char left[10000], buf[10000];
  arg = get_arg_in_braces(arg, left, 0);
  sprintf(buf, "{%s} {%d}", left, get_list_length(list));
  do_internal_variable(ses, buf);
  return ses;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<array_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0xe30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0x0,%edx
  mov    %r12,%rsi
  call   <get_arg_in_braces@plt>
  mov    %rbp,%rdi
  call   <get_list_length@plt>
  mov    %eax,%ecx
  lea    0x2710(%rsp),%rbp
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <do_internal_variable@plt>
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %rbx,%rax
  add    $0x4e30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: {%s} {%d}

assistant: ```c
struct session *array_len(struct session *ses, struct listnode *list, char *arg) {
  char left[10000], buf[10000];
  arg = get_arg_in_braces(arg, left, 0);
  sprintf(buf, "{%s} {%d}", left, get_list_length(list));
  do_internal_variable(ses, buf);
  return ses;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<array_len>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0xe30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rsi,%rbp
  mov    %rdi,%r12
  mov    %r13,%rsi
  mov    %rdx,%rdi
  xor    %edx,%edx
  call   <get_arg_in_braces@plt>
  mov    %rbp,%rdi
  lea    0x2710(%rsp),%rbp
  call   <get_list_length@plt>
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %eax,%ecx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <do_internal_variable@plt>
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x4e30,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: {%s} {%d}

assistant: ```c
struct session *array_len(struct session *ses, struct listnode *list, char *arg) {
  char left[10000], buf[10000];
  arg = get_arg_in_braces(arg, left, 0);
  sprintf(buf, "{%s} {%d}", left, get_list_length(list));
  do_internal_variable(ses, buf);
  return ses;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<array_len>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0xe30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rsi,%rbp
  mov    %rdi,%r12
  mov    %r13,%rsi
  mov    %rdx,%rdi
  xor    %edx,%edx
  call   <get_arg_in_braces@plt>
  mov    %rbp,%rdi
  lea    0x2710(%rsp),%rbp
  call   <get_list_length@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %eax,%ecx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <do_internal_variable@plt>
  mov    0x4e28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x4e30,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: {%s} {%d}

assistant: ```c
struct session *array_len(struct session *ses, struct listnode *list, char *arg) {
  char left[10000], buf[10000];
  arg = get_arg_in_braces(arg, left, 0);
  sprintf(buf, "{%s} {%d}", left, get_list_length(list));
  do_internal_variable(ses, buf);
  return ses;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_prime_factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rdx
  mov    -0x124(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_prime_factors@plt>
  mov    %eax,-0x114(%rbp)
  mov    -0x124(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x118(%rbp)
  jmp    L27
L8:
  mov    -0x118(%rbp),%eax
  cltq
  mov    -0x110(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x118(%rbp)
L27:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string

tool: D1: %lu: 

tool: D15: %lu 

assistant: ```c
void print_prime_factors(uint64_t n) {
  uint64_t factors[64];
  int j, k;
  k = get_prime_factors(n, factors);
  printf("%lu: ", n);
  for (j = 0; j < k; j++) {
    printf("%lu ", factors[j]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_prime_factors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <get_prime_factors@plt>
  mov    %eax,%ebp
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L16
  mov    %rsp,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rsp,%rax,4),%r12
  lea    D6(%rip),%rbp
L20:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L20
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D6
type: string

tool: D0: %lu: 

tool: D6: %lu 

assistant: ```c
void print_prime_factors(uint64_t n) {
  uint64_t factors[64];
  int j, k;
  k = get_prime_factors(n, factors);
  printf("%lu: ", n);
  for (j = 0; j < k; j++) {
    printf("%lu ", factors[j]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_prime_factors>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <get_prime_factors@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L20
  lea    -0x1(%r12),%eax
  lea    D11(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L21
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D4: %lu: 

tool: D11: %lu 

assistant: ```c
void print_prime_factors(uint64_t n) {
  uint64_t factors[64];
  int j, k;
  k = get_prime_factors(n, factors);
  printf("%lu: ", n);
  for (j = 0; j < k; j++) {
    printf("%lu ", factors[j]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_prime_factors>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <get_prime_factors@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L23
  lea    -0x1(%r12),%eax
  lea    D1(%rip),%rbp
  lea    0x4(%rsp,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D1
type: string

tool: D3: %lu: 

tool: D1: %lu 

assistant: ```c
void print_prime_factors(uint64_t n) {
  uint64_t factors[64];
  int j, k;
  k = get_prime_factors(n, factors);
  printf("%lu: ", n);
  for (j = 0; j < k; j++) {
    printf("%lu ", factors[j]);
  }
  printf("\n");
}
```