user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  jg     L27
  lea    D123(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L70
L27:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L43
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x5,-0xc(%rbp)
  jmp    L56
L54:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D111(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x2,-0xc(%rbp)
L56:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L54
  jmp    L70
L43:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D145(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x6,-0xc(%rbp)
  jmp    L1
L77:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D111(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x2,-0xc(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L77
L70:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D60
type_infered: string
name: read_data
arguments: data_label: D123
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D84
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D54
type_infered: string
name: read_data
arguments: data_label: D111
type_infered: string
name: read_data
arguments: data_label: D92
type_infered: string
name: read_data
arguments: data_label: D145
type_infered: string
name: read_data
arguments: data_label: D90
type_infered: string
name: read_data
arguments: data_label: D42
type_infered: string

tool: D60: %d

tool: D123: NO

tool: D12: YES

tool: D84: 1 * 2 = 2

tool: D4: 2 * 3 = 6

tool: D54: 6 * 4 = 24

tool: D111: %d - %d = 1


tool: D92: 24 * 1 = 24

tool: D145: 3 + 4 = 7

tool: D90: 7 + 5 = 12

tool: D42: 12 * 2 = 24

assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  if (n < 4) {
    printf("NO\n");
  } else {
    if (n % 2 == 0) {
      printf("YES\n");
      printf("1 * 2 = 2\n");
      printf("2 * 3 = 6\n");
      printf("6 * 4 = 24\n");
      for (i = 5; i <= n; i += 2) {
        printf("%d - %d = 1\n", i + 1, i);
        printf("24 * 1 = 24\n");
      }
    } else {
      printf("YES\n");
      printf("1 * 2 = 2\n");
      printf("3 + 4 = 7\n");
      printf("7 + 5 = 12\n");
      printf("12 * 2 = 24\n");
      for (i = 6; i <= n; i += 2) {
        printf("%d - %d = 1\n", i + 1, i);
        printf("24 * 1 = 24\n");
      }
    }
  }
  return 0;
}
```