ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x468,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x46c(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  je     L65
  movl   $0x0,-0x468(%rbp)
  jmp    L0
L28:
  movl   $0x0,-0x464(%rbp)
  jmp    L56
L50:
  nop
L16:
  lea    -0x46d(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  je     L70
  movzbl -0x46d(%rbp),%eax
  cmp    $0xa,%al
  je     L16
L70:
  movzbl -0x46d(%rbp),%eax
  cmp    $0x23,%al
  sete   %al
  mov    %eax,%ecx
  mov    -0x464(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x468(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  add    %rsi,%rax
  sub    $0x450,%rax
  mov    %cl,(%rax)
  addl   $0x1,-0x464(%rbp)
L56:
  mov    -0x46c(%rbp),%eax
  cmp    %eax,-0x464(%rbp)
  jl     L50
  addl   $0x1,-0x468(%rbp)
L0:
  mov    -0x46c(%rbp),%eax
  cmp    %eax,-0x468(%rbp)
  jl     L28
  mov    -0x46c(%rbp),%edx
  lea    -0x460(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <walk@plt>
  mov    %eax,%ebx
  mov    -0x46c(%rbp),%edx
  mov    -0x46c(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x46c(%rbp),%eax
  lea    -0x1(%rax),%esi
  lea    -0x460(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <walk@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L65:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D18
data_type: string

tool: D10: %d

tool: D16: %c

tool: D18: %d


assistant: ```c
int main() {
  char buffer, maze[33][33];
  int n, lin, col;
  if (scanf("%d", &n)) {
    for (lin = 0; lin < n; lin++) {
      for (col = 0; col < n; col++) {
        while (scanf("%c", &buffer) && buffer == '\n')
          ;
        maze[lin][col] = buffer == '#';
      }
    }
    printf("%d\n", 9 * (walk(maze, 0, 0, n) + walk(maze, n - 1, n - 1, n)));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x468,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x458(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L90
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L21
  lea    0x10(%rsp),%r12
  mov    $0x0,%r13d
  lea    D9(%rip),%rbx
  jmp    L41
L92:
  cmpb   $0x23,0xb(%rsp)
  sete   (%r12,%rbp,1)
  add    $0x1,%rbp
  cmp    %ebp,0xc(%rsp)
  jle    L3
L34:
  lea    0xb(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  je     L92
  cmpb   $0xa,0xb(%rsp)
  je     L34
  jmp    L92
L3:
  add    $0x1,%r13d
  mov    0xc(%rsp),%ecx
  add    $0x21,%r12
  cmp    %r13d,%ecx
  jle    L21
L41:
  mov    $0x0,%ebp
  cmpl   $0x0,0xc(%rsp)
  jg     L34
  jmp    L3
L21:
  lea    0x10(%rsp),%rbp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <walk@plt>
  mov    %eax,%ebx
  mov    0xc(%rsp),%ecx
  lea    -0x1(%rcx),%esi
  mov    %esi,%edx
  mov    %rbp,%rdi
  call   <walk@plt>
  lea    (%rbx,%rax,1),%esi
  imul   $0x9,%esi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L90:
  mov    0x458(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x468,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D15: %d

tool: D9: %c

tool: D5: %d


assistant: ```c
int main() {
  char buffer, maze[33][33];
  int n, lin, col;
  if (scanf("%d", &n)) {
    for (lin = 0; lin < n; lin++) {
      for (col = 0; col < n; col++) {
        while (scanf("%c", &buffer) && buffer == '\n')
          ;
        maze[lin][col] = buffer == '#';
      }
    }
    printf("%d\n", 9 * (walk(maze, 0, 0, n) + walk(maze, n - 1, n - 1, n)));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x468,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x458(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  test   %rax,%rax
  je     L61
  mov    0xc(%rsp),%ecx
  lea    0x10(%rsp),%r15
  test   %ecx,%ecx
  jle    L6
  mov    %r15,%r13
  xor    %r14d,%r14d
  lea    0xb(%rsp),%rbp
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L17:
  xor    %r12d,%r12d
  jmp    L15
  nopl   (%rax)
L71:
  cmp    $0xa,%al
  jne    L5
L15:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  movzbl 0xb(%rsp),%eax
  jne    L71
L5:
  cmp    $0x23,%al
  mov    0xc(%rsp),%ecx
  sete   0x0(%r13,%r12,1)
  add    $0x1,%r12
  cmp    %r12d,%ecx
  jg     L15
  add    $0x1,%r14d
  add    $0x21,%r13
  cmp    %r14d,%ecx
  jg     L17
L6:
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <walk@plt>
  mov    0xc(%rsp),%ecx
  mov    %r15,%rdi
  mov    %eax,%ebx
  lea    -0x1(%rcx),%esi
  mov    %esi,%edx
  call   <walk@plt>
  lea    D11(%rip),%rdi
  lea    (%rbx,%rax,1),%esi
  lea    (%rsi,%rsi,8),%esi
  call   <printf@plt>
L61:
  mov    0x458(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x468,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D28
datatype: string
name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D11
datatype: string

tool: D28: %d

tool: D9: %c

tool: D11: %d


assistant: ```c
int main() {
  char buffer, maze[33][33];
  int n, lin, col;
  if (scanf("%d", &n)) {
    for (lin = 0; lin < n; lin++) {
      for (col = 0; col < n; col++) {
        while (scanf("%c", &buffer) && buffer == '\n')
          ;
        maze[lin][col] = buffer == '#';
      }
    }
    printf("%d\n", 9 * (walk(maze, 0, 0, n) + walk(maze, n - 1, n - 1, n)));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x468,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x458(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  test   %rax,%rax
  je     L35
  mov    0xc(%rsp),%ecx
  lea    0x10(%rsp),%r15
  test   %ecx,%ecx
  jle    L11
  mov    %r15,%r13
  xor    %r14d,%r14d
  lea    0xb(%rsp),%rbp
  lea    D29(%rip),%rbx
  nopl   0x0(%rax)
L70:
  xor    %r12d,%r12d
  jmp    L51
  nopl   (%rax)
L23:
  cmp    $0xa,%al
  jne    L33
L51:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  movzbl 0xb(%rsp),%eax
  jne    L23
L33:
  cmp    $0x23,%al
  mov    0xc(%rsp),%ecx
  sete   0x0(%r13,%r12,1)
  add    $0x1,%r12
  cmp    %r12d,%ecx
  jg     L51
  add    $0x1,%r14d
  cmp    %r14d,%ecx
  jle    L11
  add    $0x21,%r13
  jmp    L70
L11:
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <walk@plt>
  mov    0xc(%rsp),%ecx
  mov    %r15,%rdi
  mov    %eax,%ebx
  lea    -0x1(%rcx),%esi
  mov    %esi,%edx
  call   <walk@plt>
  lea    D17(%rip),%rdi
  lea    (%rbx,%rax,1),%esi
  lea    (%rsi,%rsi,8),%esi
  call   <printf@plt>
L35:
  mov    0x458(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x468,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D26: %d

tool: D29: %c

tool: D17: %d


assistant: ```c
int main() {
  char buffer, maze[33][33];
  int n, lin, col;
  if (scanf("%d", &n)) {
    for (lin = 0; lin < n; lin++) {
      for (col = 0; col < n; col++) {
        while (scanf("%c", &buffer) && buffer == '\n')
          ;
        maze[lin][col] = buffer == '#';
      }
    }
    printf("%d\n", 9 * (walk(maze, 0, 0, n) + walk(maze, n - 1, n - 1, n)));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SensorSetMirrorFlip_SIV100A>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpb   $0x1,-0x14(%rbp)
  jne    L37
  movb   $0x2,-0x14(%rbp)
  jmp    L36
L37:
  cmpb   $0x2,-0x14(%rbp)
  jne    L36
  movb   $0x1,-0x14(%rbp)
L36:
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cReadByte@plt>
  movzbl -0x9(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cWriteByte@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void SensorSetMirrorFlip_SIV100A(unsigned char val) {
  unsigned char x;
  if (val == 0x01)
    val = 0x2;
  else if (val == 0x02)
    val = 0x01;
  VIM_SIF_I2cReadByte(0x04, &x);
  x &= 0xfc;
  x |= (val & 0x03);
  VIM_SIF_I2cWriteByte(0x04, x);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SensorSetMirrorFlip_SIV100A>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%ebx
  cmp    $0x1,%dil
  je     L17
  mov    %edi,%ebx
  cmp    $0x2,%dil
  mov    $0x1,%eax
  cmove  %eax,%ebx
L17:
  lea    0x7(%rsp),%rsi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cReadByte@plt>
  movzbl 0x7(%rsp),%esi
  and    $0xfffffffc,%esi
  and    $0x3,%ebx
  or     %ebx,%esi
  mov    %sil,0x7(%rsp)
  movzbl %sil,%esi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cWriteByte@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SensorSetMirrorFlip_SIV100A(unsigned char val) {
  unsigned char x;
  if (val == 0x01)
    val = 0x2;
  else if (val == 0x02)
    val = 0x01;
  VIM_SIF_I2cReadByte(0x04, &x);
  x &= 0xfc;
  x |= (val & 0x03);
  VIM_SIF_I2cWriteByte(0x04, x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SensorSetMirrorFlip_SIV100A>:
  endbr64
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%dil
  je     L19
  mov    %edi,%ebx
  mov    $0x1,%eax
  and    $0x3,%ebx
  cmp    $0x2,%dil
  cmove  %eax,%ebx
L19:
  lea    0x7(%rsp),%rsi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cReadByte@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x4,%edi
  and    $0xfffffffc,%esi
  or     %ebx,%esi
  mov    %sil,0x7(%rsp)
  movzbl %sil,%esi
  call   <VIM_SIF_I2cWriteByte@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SensorSetMirrorFlip_SIV100A(unsigned char val) {
  unsigned char x;
  if (val == 0x01)
    val = 0x2;
  else if (val == 0x02)
    val = 0x01;
  VIM_SIF_I2cReadByte(0x04, &x);
  x &= 0xfc;
  x |= (val & 0x03);
  VIM_SIF_I2cWriteByte(0x04, x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SensorSetMirrorFlip_SIV100A>:
  endbr64
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%dil
  je     L9
  mov    %edi,%ebx
  mov    $0x1,%eax
  and    $0x3,%ebx
  cmp    $0x2,%dil
  cmove  %eax,%ebx
L9:
  lea    0x7(%rsp),%rsi
  mov    $0x4,%edi
  call   <VIM_SIF_I2cReadByte@plt>
  movzbl 0x7(%rsp),%esi
  mov    $0x4,%edi
  and    $0xfffffffc,%esi
  or     %ebx,%esi
  mov    %sil,0x7(%rsp)
  movzbl %sil,%esi
  call   <VIM_SIF_I2cWriteByte@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SensorSetMirrorFlip_SIV100A(unsigned char val) {
  unsigned char x;
  if (val == 0x01)
    val = 0x2;
  else if (val == 0x02)
    val = 0x01;
  VIM_SIF_I2cReadByte(0x04, &x);
  x &= 0xfc;
  x |= (val & 0x03);
  VIM_SIF_I2cWriteByte(0x04, x);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  void *m = malloc(2 * sizeof(void));
  free(m);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *m = malloc(2 * sizeof(void));
  free(m);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *m = malloc(2 * sizeof(void));
  free(m);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *m = malloc(2 * sizeof(void));
  free(m);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ILLutil_nextprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  ja     L9
  mov    $0x3,%eax
  jmp    L25
L9:
  orl    $0x1,-0x4(%rbp)
  jmp    L28
L34:
  addl   $0x2,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L34
  mov    -0x4(%rbp),%eax
L25:
  leave
  ret
```

assistant: ```c
unsigned int ILLutil_nextprime(unsigned int x) {
  if (x < 3)
    return 3;
  x |= 1;
  while (!isprime(x))
    x += 2;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ILLutil_nextprime>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
  cmp    $0x2,%edi
  jbe    L21
  or     $0x1,%edi
  mov    %edi,%ebx
  jmp    L6
L24:
  add    $0x2,%ebx
L6:
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L24
L21:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ILLutil_nextprime(unsigned int x) {
  if (x < 3)
    return 3;
  x |= 1;
  while (!isprime(x))
    x += 2;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ILLutil_nextprime>:
  endbr64
  push   %r12
  mov    $0x3,%r12d
  cmp    $0x2,%edi
  jbe    L16
  or     $0x1,%edi
  mov    %edi,%r12d
  jmp    L28
  nopl   0x0(%rax)
L9:
  add    $0x2,%r12d
L28:
  mov    %r12d,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L9
L16:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int ILLutil_nextprime(unsigned int x) {
  if (x < 3)
    return 3;
  x |= 1;
  while (!isprime(x))
    x += 2;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ILLutil_nextprime>:
  endbr64
  push   %r12
  mov    $0x3,%r12d
  cmp    $0x2,%edi
  jbe    L6
  or     $0x1,%edi
  mov    %edi,%r12d
  jmp    L27
  nopl   0x0(%rax)
L26:
  add    $0x2,%r12d
L27:
  mov    %r12d,%edi
  call   <isprime@plt>
  test   %eax,%eax
  je     L26
L6:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int ILLutil_nextprime(unsigned int x) {
  if (x < 3)
    return 3;
  x |= 1;
  while (!isprime(x))
    x += 2;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dict_free_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pdf_obj_delete@plt>
  cmpq   $0x0,-0x10(%rbp)
  je     L8
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void dict_free_val(char *key, void *val, void *x) {
  extern void pdf_obj_delete(void *);
  pdf_obj_delete(val);
  if (val)
    free(val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dict_free_val>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <pdf_obj_delete@plt>
  test   %rbx,%rbx
  je     L4
  mov    %rbx,%rdi
  call   <free@plt>
L4:
  pop    %rbx
  ret
```

assistant: ```c
void dict_free_val(char *key, void *val, void *x) {
  extern void pdf_obj_delete(void *);
  pdf_obj_delete(val);
  if (val)
    free(val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dict_free_val>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <pdf_obj_delete@plt>
  test   %rbp,%rbp
  je     L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  xchg   %ax,%ax
L0:
  pop    %rbp
  ret
```

assistant: ```c
void dict_free_val(char *key, void *val, void *x) {
  extern void pdf_obj_delete(void *);
  pdf_obj_delete(val);
  if (val)
    free(val);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dict_free_val>:
  endbr64
  push   %rbp
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <pdf_obj_delete@plt>
  test   %rbp,%rbp
  je     L0
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  xchg   %ax,%ax
L0:
  pop    %rbp
  ret
```

assistant: ```c
void dict_free_val(char *key, void *val, void *x) {
  extern void pdf_obj_delete(void *);
  pdf_obj_delete(val);
  if (val)
    free(val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    %eax,%edi
  call   <bar@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int t = 0;
  bar(foo(&t));
  if (t != 1)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <foo@plt>
  mov    %eax,%edi
  call   <bar@plt>
  cmpl   $0x1,0x4(%rsp)
  jne    L1
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L15
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int t = 0;
  bar(foo(&t));
  if (t != 1)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    %eax,%edi
  call   <bar@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L10
  xor    %eax,%eax
  call   <abort@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int t = 0;
  bar(foo(&t));
  if (t != 1)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    %eax,%edi
  call   <bar@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L0
  xor    %eax,%eax
  call   <abort@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int t = 0;
  bar(foo(&t));
  if (t != 1)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vector_length2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float vector_length2(const float vec[], int n) {
  float len = 0;
  int i;
  for (i = 0; i < n; i++)
    len += vec[i] * vec[i];
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vector_length2>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm1,%xmm1
L9:
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
L27:
  movaps %xmm1,%xmm0
  ret
L17:
  pxor   %xmm1,%xmm1
  jmp    L27
```

assistant: ```c
float vector_length2(const float vec[], int n) {
  float len = 0;
  int i;
  for (i = 0; i < n; i++)
    len += vec[i] * vec[i];
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_length2>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L11:
  movss  (%rdi),%xmm0
  add    $0x4,%rdi
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L11
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L18:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float vector_length2(const float vec[], int n) {
  float len = 0;
  int i;
  for (i = 0; i < n; i++)
    len += vec[i] * vec[i];
  return len;
}
```