ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<print_color_primaries>:
  endbr64
  mov    $0x4,%edx
  lea    D14(%rip),%rsi
  lea    D2(%rip),%rdi
  jmp    1050 <print_enum@plt>
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: color_primaries

assistant: ```c
void print_color_primaries() {
  static const char *COLOR_PRIMARIES_STRINGS[] = {
      "HDTV",
      "SDTV 525",
      "SDTV 625",
      "D-Cinema",
  };
  print_enum("color_primaries", COLOR_PRIMARIES_STRINGS, (sizeof(COLOR_PRIMARIES_STRINGS) / sizeof((COLOR_PRIMARIES_STRINGS)[0])));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBEndpointDataSend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L24
  mov    -0x14(%rbp),%eax
  add    $0x102,%eax
  cltq
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L37
  mov    $0xffffffff,%eax
  jmp    L19
L37:
  mov    -0x1c(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L24:
  mov    -0x14(%rbp),%eax
  lea    0x102(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L46
  mov    $0xffffffff,%eax
  jmp    L19
L46:
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  lea    0x102(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int32_t USBEndpointDataSend(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32TransType) {
  uint32_t ui32TxPktRdy;
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102))) & 0x00000002) {
      return (-1);
    }
    ui32TxPktRdy = ui32TransType & 0xff;
  } else {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) & 0x00000001) {
      return (-1);
    }
    ui32TxPktRdy = (ui32TransType >> 8) & 0xff;
  }
  (*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) = ui32TxPktRdy;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<USBEndpointDataSend>:
  endbr64
  test   %esi,%esi
  jne    L0
  lea    0x102(%rdi),%eax
  cltq
  movzbl (%rax),%eax
  test   $0x2,%al
  jne    L20
  movzbl %dl,%edx
L15:
  lea    0x102(%rdi,%rsi,1),%eax
  cltq
  mov    %dl,(%rax)
  mov    $0x0,%eax
  ret
L0:
  lea    0x102(%rdi,%rsi,1),%eax
  cltq
  movzbl (%rax),%eax
  test   $0x1,%al
  jne    L23
  movzbl %dh,%edx
  jmp    L15
L20:
  mov    $0xffffffff,%eax
  ret
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int32_t USBEndpointDataSend(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32TransType) {
  uint32_t ui32TxPktRdy;
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102))) & 0x00000002) {
      return (-1);
    }
    ui32TxPktRdy = ui32TransType & 0xff;
  } else {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) & 0x00000001) {
      return (-1);
    }
    ui32TxPktRdy = (ui32TransType >> 8) & 0xff;
  }
  (*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) = ui32TxPktRdy;
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<USBEndpointDataSend>:
  endbr64
  add    $0x102,%edi
  test   %esi,%esi
  jne    L29
  movslq %edi,%rsi
  movzbl (%rsi),%eax
  test   $0x2,%al
  jne    L11
  movzbl %dl,%edx
  xor    %eax,%eax
  mov    %dl,(%rsi)
  ret
L29:
  add    %edi,%esi
  movslq %esi,%rsi
  movzbl (%rsi),%eax
  test   $0x1,%al
  jne    L11
  movzbl %dh,%edx
  xor    %eax,%eax
  mov    %dl,(%rsi)
  ret
  nopl   0x0(%rax)
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int32_t USBEndpointDataSend(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32TransType) {
  uint32_t ui32TxPktRdy;
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102))) & 0x00000002) {
      return (-1);
    }
    ui32TxPktRdy = ui32TransType & 0xff;
  } else {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) & 0x00000001) {
      return (-1);
    }
    ui32TxPktRdy = (ui32TransType >> 8) & 0xff;
  }
  (*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) = ui32TxPktRdy;
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<USBEndpointDataSend>:
  endbr64
  add    $0x102,%edi
  test   %esi,%esi
  jne    L21
  movslq %edi,%rsi
  movzbl (%rsi),%eax
  test   $0x2,%al
  jne    L16
  movzbl %dl,%edx
  xor    %eax,%eax
  mov    %dl,(%rsi)
  ret
L21:
  add    %edi,%esi
  movslq %esi,%rsi
  movzbl (%rsi),%eax
  test   $0x1,%al
  jne    L16
  movzbl %dh,%edx
  xor    %eax,%eax
  mov    %dl,(%rsi)
  ret
  nopl   0x0(%rax)
L16:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int32_t USBEndpointDataSend(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32TransType) {
  uint32_t ui32TxPktRdy;
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102))) & 0x00000002) {
      return (-1);
    }
    ui32TxPktRdy = ui32TransType & 0xff;
  } else {
    if ((*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) & 0x00000001) {
      return (-1);
    }
    ui32TxPktRdy = (ui32TransType >> 8) & 0xff;
  }
  (*((volatile unsigned char *)(ui32Base + 0x00000102 + ui32Endpoint))) = ui32TxPktRdy;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumR_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumR_i(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumR_i>:
  endbr64
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L9:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
L21:
  mov    %edx,%eax
  ret
L1:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
int sumR_i(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumR_i>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L5
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumR_i(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<sumR_i>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L33
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L54
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L34:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L34
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L23
L3:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L16
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L16
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
L16:
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  ret
L54:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
int sumR_i(int arr[], int n) {
  int sum = 0;
  for (int i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<atp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x64(%rbp),%edx
  lea    -0x60(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <display_aux_message@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: Aux Testpoint %d

assistant: ```c
int atp(int testpoint) {
  char message[80];
  sprintf(message, "Aux Testpoint %d", testpoint);
  display_aux_message(message);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atp>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <display_aux_message@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: Aux Testpoint %d

assistant: ```c
int atp(int testpoint) {
  char message[80];
  sprintf(message, "Aux Testpoint %d", testpoint);
  display_aux_message(message);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atp>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D4(%rip),%rsi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <display_aux_message@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: Aux Testpoint %d

assistant: ```c
int atp(int testpoint) {
  char message[80];
  sprintf(message, "Aux Testpoint %d", testpoint);
  display_aux_message(message);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atp>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  lea    D2(%rip),%rsi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <display_aux_message@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: Aux Testpoint %d

assistant: ```c
int atp(int testpoint) {
  char message[80];
  sprintf(message, "Aux Testpoint %d", testpoint);
  display_aux_message(message);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<errnoCallback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D18(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int errnoCallback(int value, void (*callback)()) {
  errno = value;
  callback();
  return errno;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<errnoCallback>:
  endbr64
  push   %rbx
  mov    D1(%rip),%rbx
  mov    %edi,(%rbx)
  mov    $0x0,%eax
  call   *%rsi
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int errnoCallback(int value, void (*callback)()) {
  errno = value;
  callback();
  return errno;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<errnoCallback>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  xor    %eax,%eax
  mov    %edi,(%rbx)
  call   *%rsi
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int errnoCallback(int value, void (*callback)()) {
  errno = value;
  callback();
  return errno;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<errnoCallback>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  xor    %eax,%eax
  mov    %edi,(%rbx)
  call   *%rsi
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int errnoCallback(int value, void (*callback)()) {
  errno = value;
  callback();
  return errno;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L7:
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  cmp    $0xa,%eax
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int main() {
  int err;
  struct timeval tv;
  err = gettimeofday(&tv, NULL);
  assert(err == 0);
  while (1) {
    struct timeval tv2;
    err = gettimeofday(&tv2, NULL);
    assert(err == 0);
    if (tv2.tv_sec - tv.tv_sec > 10)
      break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x4(%rsp),%rbx
L12:
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  sub    (%rsp),%eax
  cmp    $0xa,%eax
  jle    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int err;
  struct timeval tv;
  err = gettimeofday(&tv, NULL);
  assert(err == 0);
  while (1) {
    struct timeval tv2;
    err = gettimeofday(&tv2, NULL);
    assert(err == 0);
    if (tv2.tv_sec - tv.tv_sec > 10)
      break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x4(%rsp),%rbx
  call   <gettimeofday@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  nopl   (%rax)
L10:
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  sub    (%rsp),%eax
  cmp    $0xa,%eax
  jle    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int err;
  struct timeval tv;
  err = gettimeofday(&tv, NULL);
  assert(err == 0);
  while (1) {
    struct timeval tv2;
    err = gettimeofday(&tv2, NULL);
    assert(err == 0);
    if (tv2.tv_sec - tv.tv_sec > 10)
      break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x4(%rsp),%rbx
  call   <gettimeofday@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  nopl   (%rax)
L10:
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  sub    (%rsp),%eax
  cmp    $0xa,%eax
  jle    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int err;
  struct timeval tv;
  err = gettimeofday(&tv, NULL);
  assert(err == 0);
  while (1) {
    struct timeval tv2;
    err = gettimeofday(&tv2, NULL);
    assert(err == 0);
    if (tv2.tv_sec - tv.tv_sec > 10)
      break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<buildgraph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  lea    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <addEdge@plt>
  nop
  leave
  ret
```

assistant: ```c
void buildgraph(struct graph *grp) {
  addEdge(&grp, 0, 5);
  addEdge(&grp, 0, 2);
  addEdge(&grp, 1, 0);
  addEdge(&grp, 2, 5);
  addEdge(&grp, 3, 1);
  addEdge(&grp, 3, 4);
  addEdge(&grp, 4, 2);
  addEdge(&grp, 5, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildgraph>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rbx
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x1,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  mov    $0x4,%edx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <addEdge@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void buildgraph(struct graph *grp) {
  addEdge(&grp, 0, 5);
  addEdge(&grp, 0, 2);
  addEdge(&grp, 1, 0);
  addEdge(&grp, 2, 5);
  addEdge(&grp, 3, 1);
  addEdge(&grp, 3, 4);
  addEdge(&grp, 4, 2);
  addEdge(&grp, 5, 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<buildgraph>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  xor    %esi,%esi
  sub    $0x10,%rsp
  lea    0x8(%rsp),%rbp
  mov    %rdi,0x8(%rsp)
  mov    %rbp,%rdi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  xor    %esi,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x1,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0x2,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x3,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x3,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  mov    $0x4,%esi
  call   <addEdge@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    $0x5,%esi
  call   <addEdge@plt>
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
void buildgraph(struct graph *grp) {
  addEdge(&grp, 0, 5);
  addEdge(&grp, 0, 2);
  addEdge(&grp, 1, 0);
  addEdge(&grp, 2, 5);
  addEdge(&grp, 3, 1);
  addEdge(&grp, 3, 4);
  addEdge(&grp, 4, 2);
  addEdge(&grp, 5, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L41
L19:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  addb   $0x2,-0xa(%rbp)
L41:
  cmpb   $0x0,-0xa(%rbp)
  je     L19
  movb   $0x0,-0xa(%rbp)
  jmp    L39
L27:
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xa(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L39:
  cmpb   $0x0,-0xa(%rbp)
  je     L27
  movzbl -0x9(%rbp),%eax
  lea    0x68(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] - state[local1];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 595841640UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movb   $0x68,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] - state[local1];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 595841640UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movb   $0x68,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] = state[0UL] - state[local1];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] + 595841640UL;
  }
}
```