ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gint1_fn_S>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x30,%rsp
  movsd  (%rsi),%xmm2
  subsd  (%rdi),%xmm2
  movsd  0x8(%rsi),%xmm5
  movsd  0x10(%rsi),%xmm4
  movsd  %xmm0,0x10(%rsp)
  subsd  0x8(%rdi),%xmm5
  subsd  0x10(%rdi),%xmm4
  movsd  D12(%rip),%xmm1
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm4,0x18(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm5,%xmm5
  xorpd  D19(%rip),%xmm3
  mulsd  %xmm2,%xmm2
  mulsd  %xmm4,%xmm4
  addsd  %xmm5,%xmm2
  addsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D6(%rip),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: f64
name: disassemble_data
arguments: data_label: D19
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D6
type_guessed: f64

tool: D12: 0.75

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: 0.71270547035499

assistant: ```c
void gint1_fn_S(double *a, double a_a, double *p, double *out) {
  double v_0, v_1, v_2;
  v_0 = p[0] - a[0];
  v_1 = p[1] - a[1];
  v_2 = p[2] - a[2];
  out[0] = 0.71270547035499 * pow(a_a, 0.75) * exp(-a_a * (v_0 * v_0 + v_1 * v_1 + v_2 * v_2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftbitsright>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L37
  jmp    L25
L50:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x8,-0x20(%rbp)
L25:
  cmpq   $0x8,-0x20(%rbp)
  ja     L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L17
L37:
  mov    -0x28(%rbp),%rax
  shr    $0x3,%rax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x7,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L41:
  mov    -0x10(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  cltq
  not    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    $0x8,%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x8(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  ja     L41
  mov    -0x10(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L63
L70:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
L63:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L70
L17:
  pop    %rbp
  ret
```

assistant: ```c
void shiftbitsright(unsigned char *p, unsigned long num, unsigned long by) {
  int step, off;
  unsigned char *e;
  if (by >= num) {
    for (; num > 8; p++, num -= 8)
      *p = 0;
    *p &= (~0x00) >> num;
    return;
  }
  step = by / 8;
  off = by % 8;
  for (e = p + (num + 7) / 8 - 1; e > p + step; e--)
    *e = (*(e - step) >> off) | (*(e - step - 1) << (8 - off));
  *e = *(e - step) >> off;
  for (e = p; e < p + step; e++)
    *e = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shiftbitsright>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdx
  jae    L54
  push   %rbx
  mov    %rdx,%r8
  mov    %edx,%r9d
  and    $0x7,%r9d
  add    $0x7,%rsi
  shr    $0x3,%rsi
  lea    -0x1(%rdi,%rsi,1),%rdx
  shr    $0x3,%r8
  movslq %r8d,%r8
  lea    (%rdi,%r8,1),%r11
  cmp    %r11,%rdx
  jbe    L68
  sub    %r8,%rdx
  mov    %r11,%rbx
  sub    %r8,%rbx
  mov    $0x8,%r10d
  sub    %r9d,%r10d
L28:
  movzbl -0x1(%rdx),%esi
  mov    %r10d,%ecx
  shl    %cl,%esi
  movzbl (%rdx),%edi
  mov    %r9d,%ecx
  sar    %cl,%edi
  or     %edi,%esi
  mov    %sil,(%rdx,%r8,1)
  sub    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L28
  mov    %r11,%rdx
L68:
  mov    %rdx,%rcx
  sub    %r8,%rcx
  movzbl (%rcx),%esi
  mov    %r9d,%ecx
  sar    %cl,%esi
  mov    %sil,(%rdx)
  cmp    %r11,%rax
  jae    L26
L47:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %r11,%rax
  jne    L47
L26:
  pop    %rbx
  ret
L54:
  cmp    $0x8,%rsi
  jbe    L32
  sub    $0x9,%rsi
  shr    $0x3,%rsi
  lea    0x1(%rdi,%rsi,1),%rdx
L0:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
  ret
L32:
  ret
```

assistant: ```c
void shiftbitsright(unsigned char *p, unsigned long num, unsigned long by) {
  int step, off;
  unsigned char *e;
  if (by >= num) {
    for (; num > 8; p++, num -= 8)
      *p = 0;
    *p &= (~0x00) >> num;
    return;
  }
  step = by / 8;
  off = by % 8;
  for (e = p + (num + 7) / 8 - 1; e > p + step; e--)
    *e = (*(e - step) >> off) | (*(e - step - 1) << (8 - off));
  *e = *(e - step) >> off;
  for (e = p; e < p + step; e++)
    *e = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shiftbitsright>:
  endbr64
  cmp    %rsi,%rdx
  jae    L31
  mov    %edx,%r10d
  add    $0x7,%rsi
  shr    $0x3,%rdx
  movslq %edx,%r8
  shr    $0x3,%rsi
  and    $0x7,%r10d
  mov    %r8,%r11
  lea    -0x1(%rdi,%rsi,1),%rax
  lea    (%rdi,%r8,1),%r9
  neg    %r11
  cmp    %r9,%rax
  jbe    L36
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    $0x8,%ebx
  not    %rbp
  sub    %r10d,%ebx
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rax,%r11,1),%edx
  movzbl (%rax,%rbp,1),%esi
  mov    %r10d,%ecx
  sub    $0x1,%rax
  sar    %cl,%edx
  mov    %ebx,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  mov    %dl,0x1(%rax)
  cmp    %r9,%rax
  jne    L2
  mov    %r9,%r11
  mov    %r10d,%ecx
  sub    %r8,%r11
  movzbl (%r11),%edx
  sar    %cl,%edx
  mov    %dl,(%r9)
  cmp    %r9,%rdi
  jae    L5
  pop    %rbx
  mov    %r8,%rdx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  cmp    $0x8,%rsi
  jbe    L52
  lea    -0x9(%rsi),%rdx
  mov    %rdx,%rsi
  shr    $0x3,%rsi
  lea    0x1(%rsi),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
L52:
  ret
  nopl   (%rax)
L36:
  add    %rax,%r11
  mov    %r10d,%ecx
  movzbl (%r11),%edx
  sar    %cl,%edx
  mov    %dl,(%rax)
  cmp    %r9,%rdi
  jae    L52
  mov    %r8,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void shiftbitsright(unsigned char *p, unsigned long num, unsigned long by) {
  int step, off;
  unsigned char *e;
  if (by >= num) {
    for (; num > 8; p++, num -= 8)
      *p = 0;
    *p &= (~0x00) >> num;
    return;
  }
  step = by / 8;
  off = by % 8;
  for (e = p + (num + 7) / 8 - 1; e > p + step; e--)
    *e = (*(e - step) >> off) | (*(e - step - 1) << (8 - off));
  *e = *(e - step) >> off;
  for (e = p; e < p + step; e++)
    *e = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftbitsright>:
  endbr64
  cmp    %rsi,%rdx
  jae    L41
  mov    %edx,%r10d
  add    $0x7,%rsi
  shr    $0x3,%rdx
  movslq %edx,%r8
  shr    $0x3,%rsi
  and    $0x7,%r10d
  mov    %r8,%r11
  lea    -0x1(%rdi,%rsi,1),%rax
  lea    (%rdi,%r8,1),%r9
  neg    %r11
  cmp    %r9,%rax
  jbe    L6
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    $0x8,%ebx
  not    %rbp
  sub    %r10d,%ebx
  nopl   0x0(%rax,%rax,1)
L56:
  movzbl (%rax,%r11,1),%edx
  movzbl (%rax,%rbp,1),%esi
  mov    %r10d,%ecx
  sub    $0x1,%rax
  sar    %cl,%edx
  mov    %ebx,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  mov    %dl,0x1(%rax)
  cmp    %r9,%rax
  jne    L56
  mov    %r9,%r11
  mov    %r10d,%ecx
  sub    %r8,%r11
  movzbl (%r11),%edx
  sar    %cl,%edx
  mov    %dl,(%r9)
  cmp    %r9,%rdi
  jae    L37
  pop    %rbx
  mov    %r8,%rdx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    $0x8,%rsi
  jbe    L39
  lea    -0x9(%rsi),%rdx
  mov    %rdx,%rsi
  shr    $0x3,%rsi
  lea    0x1(%rsi),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
L39:
  ret
  nopl   (%rax)
L6:
  add    %rax,%r11
  mov    %r10d,%ecx
  movzbl (%r11),%edx
  sar    %cl,%edx
  mov    %dl,(%rax)
  cmp    %r9,%rdi
  jae    L39
  mov    %r8,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void shiftbitsright(unsigned char *p, unsigned long num, unsigned long by) {
  int step, off;
  unsigned char *e;
  if (by >= num) {
    for (; num > 8; p++, num -= 8)
      *p = 0;
    *p &= (~0x00) >> num;
    return;
  }
  step = by / 8;
  off = by % 8;
  for (e = p + (num + 7) / 8 - 1; e > p + step; e--)
    *e = (*(e - step) >> off) | (*(e - step - 1) << (8 - off));
  *e = *(e - step) >> off;
  for (e = p; e < p + step; e++)
    *e = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D49(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D34(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D62(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  (%rsp),%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D64(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type: string
name: read_data
arguments: data_label: D49
type: string
name: read_data
arguments: data_label: D68
type: string
name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D62
type: string
name: read_data
arguments: data_label: D64
type: string

tool: D15: Enter an floating point x:

tool: D49: %f

tool: D68: Enter a second floating point y:

tool: D34: the sum is %f


tool: D36: the difference is %f


tool: D62: the product is %f


tool: D64: the quotient is %f


assistant: ```c
int main() {
  float x;
  float y;
  float z;
  z = x + y;
  z = x - y;
  z = x * y;
  z = x / y;
  printf("Enter an floating point x:\n");
  scanf("%f", &x);
  printf("Enter a second floating point y:\n");
  scanf("%f", &y);
  z = x + y;
  printf("the sum is %f\n", z);
  z = x - y;
  printf("the difference is %f\n", z);
  z = x * y;
  printf("the product is %f\n", z);
  z = x / y;
  printf("the quotient is %f\n", z);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D2(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D64(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  movss  (%rsp),%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D64
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string

tool: D12: Enter an floating point x:

tool: D2: %f

tool: D3: Enter a second floating point y:

tool: D4: the sum is %f


tool: D64: the difference is %f


tool: D16: the product is %f


tool: D24: the quotient is %f


assistant: ```c
int main() {
  float x;
  float y;
  float z;
  z = x + y;
  z = x - y;
  z = x * y;
  z = x / y;
  printf("Enter an floating point x:\n");
  scanf("%f", &x);
  printf("Enter a second floating point y:\n");
  scanf("%f", &y);
  z = x + y;
  printf("the sum is %f\n", z);
  z = x - y;
  printf("the difference is %f\n", z);
  z = x * y;
  printf("the product is %f\n", z);
  z = x / y;
  printf("the quotient is %f\n", z);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D25(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D49(%rip),%rdi
  mov    $0x1,%eax
  movss  (%rsp),%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D45
type: string
name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D1
type: string
name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D49
type: string

tool: D34: Enter an floating point x:

tool: D25: %f

tool: D45: Enter a second floating point y:

tool: D7: the sum is %f


tool: D1: the difference is %f


tool: D24: the product is %f


tool: D49: the quotient is %f


assistant: ```c
int main() {
  float x;
  float y;
  float z;
  z = x + y;
  z = x - y;
  z = x * y;
  z = x / y;
  printf("Enter an floating point x:\n");
  scanf("%f", &x);
  printf("Enter a second floating point y:\n");
  scanf("%f", &y);
  z = x + y;
  printf("the sum is %f\n", z);
  z = x - y;
  printf("the difference is %f\n", z);
  z = x * y;
  printf("the product is %f\n", z);
  z = x / y;
  printf("the quotient is %f\n", z);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<give_my_mantissa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L17:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x17,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltd
  idiv   %esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  cmpl   $0x16,-0x8(%rbp)
  jle    L17
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0xc(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: float_part = %f


assistant: ```c
float give_my_mantissa(int mantissa) {
  float float_part = 0.0;
  int bit = 0;
  for (int i = 0; i < 23; i++) {
    bit = (mantissa >> i) & 1;
    float_part += bit / pow(2, 23 - i);
  }
  printf("float_part = %f\n", float_part);
  return float_part;
}
```
user: What is the c source code of the assembly code below?

```asm
<give_my_mantissa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movss  %xmm2,0xc(%rsp)
  mov    $0x17,%r12d
L9:
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  cltd
  idiv   %esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  cmp    $0x17,%ebx
  jne    L9
  lea    D9(%rip),%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: float_part = %f


assistant: ```c
float give_my_mantissa(int mantissa) {
  float float_part = 0.0;
  int bit = 0;
  for (int i = 0; i < 23; i++) {
    bit = (mantissa >> i) & 1;
    float_part += bit / pow(2, 23 - i);
  }
  printf("float_part = %f\n", float_part);
  return float_part;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<give_my_mantissa>:
  endbr64
  push   %r12
  pxor   %xmm2,%xmm2
  mov    $0x17,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
L2:
  mov    %r12d,%esi
  mov    $0x2,%edi
  sub    %ebx,%esi
  call   <pow@plt>
  mov    %ebx,%ecx
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  mov    %eax,%r8d
  mov    %ebp,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  cmp    $0x17,%ebx
  jne    L2
  lea    D0(%rip),%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: float_part = %f


assistant: ```c
float give_my_mantissa(int mantissa) {
  float float_part = 0.0;
  int bit = 0;
  for (int i = 0; i < 23; i++) {
    bit = (mantissa >> i) & 1;
    float_part += bit / pow(2, 23 - i);
  }
  printf("float_part = %f\n", float_part);
  return float_part;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<give_my_mantissa>:
  endbr64
  push   %r12
  pxor   %xmm2,%xmm2
  mov    $0x17,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
L4:
  mov    %r12d,%esi
  mov    $0x2,%edi
  sub    %ebx,%esi
  call   <pow@plt>
  mov    %ebx,%ecx
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  mov    %eax,%r8d
  mov    %ebp,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  cmp    $0x17,%ebx
  jne    L4
  lea    D9(%rip),%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: float_part = %f


assistant: ```c
float give_my_mantissa(int mantissa) {
  float float_part = 0.0;
  int bit = 0;
  for (int i = 0; i < 23; i++) {
    bit = (mantissa >> i) & 1;
    float_part += bit / pow(2, 23 - i);
  }
  printf("float_part = %f\n", float_part);
  return float_part;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writehex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x39,-0x4(%rbp)
  jle    L4
  movzbl -0x4(%rbp),%eax
  add    $0x7,%eax
  mov    %al,-0x4(%rbp)
L4:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <writechar@plt>
  nop
  leave
  ret
```

assistant: ```c
void writehex(char x) {
  x = (x & 0xf) + '0';
  if (x > '9') {
    x += 'A' - '9' - 1;
  }
  writechar(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<writehex>:
  endbr64
  sub    $0x8,%rsp
  and    $0xf,%edi
  lea    0x30(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x39,%al
  cmovg  %edi,%eax
  movsbl %al,%edi
  call   <writechar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void writehex(char x) {
  x = (x & 0xf) + '0';
  if (x > '9') {
    x += 'A' - '9' - 1;
  }
  writechar(x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<writehex>:
  endbr64
  and    $0xf,%edi
  lea    0x30(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <writechar@plt>
```

assistant: ```c
void writehex(char x) {
  x = (x & 0xf) + '0';
  if (x > '9') {
    x += 'A' - '9' - 1;
  }
  writechar(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writehex>:
  endbr64
  and    $0xf,%edi
  lea    0x30(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x39,%al
  cmova  %edi,%eax
  movzbl %al,%edi
  jmp    1050 <writechar@plt>
```

assistant: ```c
void writehex(char x) {
  x = (x & 0xf) + '0';
  if (x > '9') {
    x += 'A' - '9' - 1;
  }
  writechar(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<ziplistNew>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x11,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <zmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x10,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xff,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *ziplistNew(void) {
  unsigned int bytes = (sizeof(uint32_t) * 2 + sizeof(uint16_t)) + 1;
  unsigned char *zl = zmalloc(bytes);
  (*((uint32_t *)(zl))) = (bytes);
  (*((uint32_t *)((zl) + sizeof(uint32_t)))) = ((sizeof(uint32_t) * 2 + sizeof(uint16_t)));
  (*((uint16_t *)((zl) + sizeof(uint32_t) * 2))) = 0;
  zl[bytes - 1] = 255;
  return zl;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ziplistNew>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x11,%edi
  call   <zmalloc@plt>
  movl   $0x11,(%rax)
  movl   $0x10,0x4(%rax)
  movq   $0x0,0x8(%rax)
  movb   $0xff,0x10(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char *ziplistNew(void) {
  unsigned int bytes = (sizeof(uint32_t) * 2 + sizeof(uint16_t)) + 1;
  unsigned char *zl = zmalloc(bytes);
  (*((uint32_t *)(zl))) = (bytes);
  (*((uint32_t *)((zl) + sizeof(uint32_t)))) = ((sizeof(uint32_t) * 2 + sizeof(uint16_t)));
  (*((uint16_t *)((zl) + sizeof(uint32_t) * 2))) = 0;
  zl[bytes - 1] = 255;
  return zl;
}
```