ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<track_paths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <sample_to_new_slices@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <swap_slices@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <witness_set_to_system_container@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <validate_solutions@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int track_paths(void) {
  int fail;
  fail = sample_to_new_slices();
  if (0 > 0)
    printf("Done tracking.\n");
  if (0 > 1)
    printf("Solutions computed :\n");
  if (0 > 1)
    fail = solcon_write_standard_solutions();
  fail = swap_slices();
  fail = witness_set_to_system_container();
  fail = validate_solutions();
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<track_paths>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sample_to_new_slices@plt>
  mov    $0x0,%eax
  call   <swap_slices@plt>
  mov    $0x0,%eax
  call   <witness_set_to_system_container@plt>
  mov    $0x0,%eax
  call   <validate_solutions@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int track_paths(void) {
  int fail;
  fail = sample_to_new_slices();
  if (0 > 0)
    printf("Done tracking.\n");
  if (0 > 1)
    printf("Solutions computed :\n");
  if (0 > 1)
    fail = solcon_write_standard_solutions();
  fail = swap_slices();
  fail = witness_set_to_system_container();
  fail = validate_solutions();
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<track_paths>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sample_to_new_slices@plt>
  xor    %eax,%eax
  call   <swap_slices@plt>
  xor    %eax,%eax
  call   <witness_set_to_system_container@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <validate_solutions@plt>
```

assistant: ```c
int track_paths(void) {
  int fail;
  fail = sample_to_new_slices();
  if (0 > 0)
    printf("Done tracking.\n");
  if (0 > 1)
    printf("Solutions computed :\n");
  if (0 > 1)
    fail = solcon_write_standard_solutions();
  fail = swap_slices();
  fail = witness_set_to_system_container();
  fail = validate_solutions();
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__syscall_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %eax,%edx
  neg    %edx
  mov    %edx,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __syscall_error(void) {
  register int edx __asm__("%edx");
  __asm__("mov %eax, %edx\n\t"
          "negl %edx");
  __set_errno(edx);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__syscall_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %eax,%edx
  neg    %edx
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __syscall_error(void) {
  register int edx __asm__("%edx");
  __asm__("mov %eax, %edx\n\t"
          "negl %edx");
  __set_errno(edx);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__syscall_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %eax,%edx
  neg    %edx
  xor    %eax,%eax
  mov    %edx,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __syscall_error(void) {
  register int edx __asm__("%edx");
  __asm__("mov %eax, %edx\n\t"
          "negl %edx");
  __set_errno(edx);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__syscall_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %eax,%edx
  neg    %edx
  xor    %eax,%eax
  mov    %edx,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __syscall_error(void) {
  register int edx __asm__("%edx");
  __asm__("mov %eax, %edx\n\t"
          "negl %edx");
  __set_errno(edx);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *int_ptr(int val) {
  int *res = malloc(sizeof res);
  *res = val;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<int_ptr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *int_ptr(int val) {
  int *res = malloc(sizeof res);
  *res = val;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<int_ptr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *int_ptr(int val) {
  int *res = malloc(sizeof res);
  *res = val;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_ptr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %ebx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
int *int_ptr(int val) {
  int *res = malloc(sizeof res);
  *res = val;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<brw_wm_projective>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <brw_wm_projective_st@plt>
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <brw_wm_sample@plt>
  leave
  ret
```

assistant: ```c
int brw_wm_projective(struct brw_compile *p, int dw, int channel, int msg, int result) {
  brw_wm_projective_st(p, dw, channel, msg);
  return brw_wm_sample(p, dw, channel, msg, result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<brw_wm_projective>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  call   <brw_wm_projective_st@plt>
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <brw_wm_sample@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int brw_wm_projective(struct brw_compile *p, int dw, int channel, int msg, int result) {
  brw_wm_projective_st(p, dw, channel, msg);
  return brw_wm_sample(p, dw, channel, msg, result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<brw_wm_projective>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <brw_wm_projective_st@plt>
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  pop    %rbx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <brw_wm_sample@plt>
```

assistant: ```c
int brw_wm_projective(struct brw_compile *p, int dw, int channel, int msg, int result) {
  brw_wm_projective_st(p, dw, channel, msg);
  return brw_wm_sample(p, dw, channel, msg, result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<brw_wm_projective>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <brw_wm_projective_st@plt>
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  pop    %rbx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <brw_wm_sample@plt>
```

assistant: ```c
int brw_wm_projective(struct brw_compile *p, int dw, int channel, int msg, int result) {
  brw_wm_projective_st(p, dw, channel, msg);
  return brw_wm_sample(p, dw, channel, msg, result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_pattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jle    L65
  mov    $0x0,%eax
  jmp    L87
L65:
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L7:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L128
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L88
  movl   $0x1,-0x1c(%rbp)
  jmp    L88
L128:
  cmpl   $0x0,-0x34(%rbp)
  jne    L73
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L73
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L88
  movl   $0x1,-0x1c(%rbp)
  jmp    L88
L73:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L88
  movl   $0x1,-0x1c(%rbp)
L88:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L68
  mov    $0x0,%eax
  jmp    L87
L68:
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    $0x1,%eax
L87:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int string_pattern(char *s, char *pattern, int matchcase) {
  int patlen, match, i;
  patlen = strlen(pattern);
  if (strlen(s) < patlen)
    return 0;
  for (i = 0; i < patlen; ++i) {
    match = 0;
    if (pattern[i] == '#') {
      if (isdigit((unsigned char)s[i]))
        match = 1;
    } else if (!matchcase && isalpha((unsigned char)pattern[i])) {
      if (tolower((unsigned char)pattern[i]) == tolower((unsigned char)s[i]))
        match = 1;
    } else {
      if (pattern[i] == s[i])
        match = 1;
    }
    if (!match)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_pattern>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %r12d,%edx
  jl     L0
  test   %r12d,%r12d
  jle    L95
  mov    %r14,%rbx
  lea    -0x1(%r12),%eax
  lea    0x1(%r14,%rax,1),%r14
  jmp    L30
L73:
  movzbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L65
  jmp    L0
L96:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%r12)
  jne    L125
L65:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r14,%rbx
  je     L89
L30:
  mov    %rbx,%r12
  movzbl (%rbx),%edi
  cmp    $0x23,%dil
  je     L73
  test   %r13d,%r13d
  jne    L96
  movzbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L96
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %rax,%r12
  je     L65
  mov    %r13d,%eax
  jmp    L0
L89:
  mov    $0x1,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L95:
  mov    $0x1,%eax
  jmp    L0
L125:
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
int string_pattern(char *s, char *pattern, int matchcase) {
  int patlen, match, i;
  patlen = strlen(pattern);
  if (strlen(s) < patlen)
    return 0;
  for (i = 0; i < patlen; ++i) {
    match = 0;
    if (pattern[i] == '#') {
      if (isdigit((unsigned char)s[i]))
        match = 1;
    } else if (!matchcase && isalpha((unsigned char)pattern[i])) {
      if (tolower((unsigned char)pattern[i]) == tolower((unsigned char)s[i]))
        match = 1;
    } else {
      if (pattern[i] == s[i])
        match = 1;
    }
    if (!match)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_pattern>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %r13d,%eax
  jl     L51
  test   %r13d,%r13d
  jle    L85
  lea    -0x1(%r13),%eax
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L129
  nopl   (%rax)
L118:
  cmp    %dil,0x0(%rbp)
  jne    L51
L93:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  je     L85
L129:
  movzbl (%rbx),%edi
  cmp    $0x23,%dil
  je     L109
  test   %r12d,%r12d
  jne    L118
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L72
  movzbl (%rbx),%edi
  cmp    %dil,0x0(%rbp)
  je     L93
L51:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L109:
  movzbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L51
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L129
L85:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L72:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  mov    %rax,%r14
  call   <tolower@plt>
  cmp    %rax,%r14
  je     L93
  jmp    L51
```

assistant: ```c
int string_pattern(char *s, char *pattern, int matchcase) {
  int patlen, match, i;
  patlen = strlen(pattern);
  if (strlen(s) < patlen)
    return 0;
  for (i = 0; i < patlen; ++i) {
    match = 0;
    if (pattern[i] == '#') {
      if (isdigit((unsigned char)s[i]))
        match = 1;
    } else if (!matchcase && isalpha((unsigned char)pattern[i])) {
      if (tolower((unsigned char)pattern[i]) == tolower((unsigned char)s[i]))
        match = 1;
    } else {
      if (pattern[i] == s[i])
        match = 1;
    }
    if (!match)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_pattern>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L22
  test   %r12d,%r12d
  jle    L150
  lea    -0x1(%r12),%eax
  lea    0x1(%rbx,%rax,1),%r12
  test   %r13d,%r13d
  je     L65
  movzbl (%rbx),%eax
  cmp    $0x23,%al
  je     L103
  xchg   %ax,%ax
L154:
  cmp    %al,0x0(%rbp)
  jne    L22
L77:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L150
  movzbl (%rbx),%eax
  cmp    $0x23,%al
  jne    L154
L103:
  movzbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L77
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L40
  movzbl (%rbx),%eax
  cmp    %al,0x0(%rbp)
  jne    L22
L11:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L150
L65:
  movzbl (%rbx),%edi
  cmp    $0x23,%dil
  jne    L14
  movzbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L22
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  jne    L65
L150:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  mov    %rax,%r13
  call   <tolower@plt>
  cmp    %rax,%r13
  je     L11
  jmp    L22
```

assistant: ```c
int string_pattern(char *s, char *pattern, int matchcase) {
  int patlen, match, i;
  patlen = strlen(pattern);
  if (strlen(s) < patlen)
    return 0;
  for (i = 0; i < patlen; ++i) {
    match = 0;
    if (pattern[i] == '#') {
      if (isdigit((unsigned char)s[i]))
        match = 1;
    } else if (!matchcase && isalpha((unsigned char)pattern[i])) {
      if (tolower((unsigned char)pattern[i]) == tolower((unsigned char)s[i]))
        match = 1;
    } else {
      if (pattern[i] == s[i])
        match = 1;
    }
    if (!match)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<gost_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L3:
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <F@plt>
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x1f,-0x8(%rbp)
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void gost_encrypt(uint32_t *out, const uint32_t *in) {
  uint32_t A = in[0];
  uint32_t B = in[1];
  for (int i = 0; i < 32; i++) {
    uint32_t A1 = B ^ F(A, i);
    B = A;
    A = A1;
  }
  out[0] = B;
  out[1] = A;
}
```
user: What is the c source code of the assembly code below?

```asm
<gost_encrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    (%rsi),%ebp
  mov    0x4(%rsi),%r12d
  mov    $0x0,%ebx
  jmp    L14
L16:
  mov    %eax,%ebp
L14:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <F@plt>
  xor    %r12d,%eax
  add    $0x1,%ebx
  mov    %ebp,%r12d
  cmp    $0x20,%ebx
  jne    L16
  mov    %ebp,0x0(%r13)
  mov    %eax,0x4(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gost_encrypt(uint32_t *out, const uint32_t *in) {
  uint32_t A = in[0];
  uint32_t B = in[1];
  for (int i = 0; i < 32; i++) {
    uint32_t A1 = B ^ F(A, i);
    B = A;
    A = A1;
  }
  out[0] = B;
  out[1] = A;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gost_encrypt>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    (%rsi),%ebp
  mov    0x4(%rsi),%r12d
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%ebp
L1:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <F@plt>
  xor    %r12d,%eax
  mov    %ebp,%r12d
  cmp    $0x20,%ebx
  jne    L5
  mov    %ebp,0x0(%r13)
  mov    %eax,0x4(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gost_encrypt(uint32_t *out, const uint32_t *in) {
  uint32_t A = in[0];
  uint32_t B = in[1];
  for (int i = 0; i < 32; i++) {
    uint32_t A1 = B ^ F(A, i);
    B = A;
    A = A1;
  }
  out[0] = B;
  out[1] = A;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gost_encrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    (%rsi),%ebp
  mov    0x4(%rsi),%r13d
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %eax,%ebp
L2:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <F@plt>
  xor    %r13d,%eax
  mov    %ebp,%r13d
  cmp    $0x20,%ebx
  jne    L1
  movd   %ebp,%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gost_encrypt(uint32_t *out, const uint32_t *in) {
  uint32_t A = in[0];
  uint32_t B = in[1];
  for (int i = 0; i < 32; i++) {
    uint32_t A1 = B ^ F(A, i);
    B = A;
    A = A1;
  }
  out[0] = B;
  out[1] = A;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L48:
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L8
L42:
  subl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x0,-0x4(%rbp)
  jle    L30
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *s) {
  int len = 0;
  while (isspace((unsigned int)(*s)))
    s++;
  len = strlen(s);
  while (len > 0 && isspace((unsigned int)(s[len - 1])))
    len--;
  s[len] = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  jmp    L38
L14:
  add    $0x1,%rbp
L38:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L25
  cltq
  lea    -0x1(%rbp,%rax,1),%r12
L30:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L25
  sub    $0x1,%r12
  sub    $0x1,%ebx
  jne    L30
L25:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *s) {
  int len = 0;
  while (isspace((unsigned int)(*s)))
    s++;
  len = strlen(s);
  while (len > 0 && isspace((unsigned int)(s[len - 1])))
    len--;
  s[len] = '\0';
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L18
L17:
  add    $0x1,%r12
L18:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  test   %eax,%eax
  jg     L53
  jmp    L56
  nopl   0x0(%rax)
L23:
  lea    -0x1(%rbx),%eax
  sub    $0x1,%rbx
  je     L20
L53:
  movsbl -0x1(%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L23
L56:
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  movslq %eax,%rbx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *s) {
  int len = 0;
  while (isspace((unsigned int)(*s)))
    s++;
  len = strlen(s);
  while (len > 0 && isspace((unsigned int)(s[len - 1])))
    len--;
  s[len] = '\0';
  return s;
}
```