ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<constantP>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  movslq %ecx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  add    $0x1,%r15d
  call   <memcpy@plt>
  add    %r14,%rbx
  cmp    %r15d,%ebp
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int constantP(void *pval, int rn, void *rp, int rs) {

  int k;
  for (k = 0; k < rn; k++) {
    memcpy(rp + k * rs, pval, rs);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvSqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    $0xbe6f0000,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    -0x14(%rbp),%rax
  shr    %edx
  mov    %edx,(%rax)
  movss  -0x24(%rbp),%xmm1
  movss  D2(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  D29(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  D29(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  -0x24(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D29
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

tool: {"D29": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float cvSqrt(float arg) {
  float x, y;
  unsigned iarg = *((unsigned *)&arg);
  *((unsigned *)&x) = (0xbe6f0000 - iarg) >> 1;
  y = arg * 0.5f;
  x *= 1.5f - y * x * x;
  x *= 1.5f - y * x * x;
  return x * arg;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cvSqrt>:
  endbr64
  movaps %xmm0,%xmm3
  mulss  D8(%rip),%xmm3
  mov    $0xbe6f0000,%eax
  movd   %xmm0,-0x4(%rsp)
  sub    -0x4(%rsp),%eax
  shr    %eax
  movd   %eax,%xmm2
  movd   %eax,%xmm5
  mulss  %xmm3,%xmm5
  mulss  %xmm2,%xmm5
  movss  D1(%rip),%xmm1
  movaps %xmm1,%xmm4
  subss  %xmm5,%xmm4
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm3
  subss  %xmm3,%xmm1
  mulss  %xmm2,%xmm1
  mulss  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: byte[4]
name: parse_data
arguments: data_label: D1
data_type: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x3f]}

tool: {"D1": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float cvSqrt(float arg) {
  float x, y;
  unsigned iarg = *((unsigned *)&arg);
  *((unsigned *)&x) = (0xbe6f0000 - iarg) >> 1;
  y = arg * 0.5f;
  x *= 1.5f - y * x * x;
  x *= 1.5f - y * x * x;
  return x * arg;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cvSqrt>:
  endbr64
  movss  D6(%rip),%xmm3
  movd   %xmm0,-0x4(%rsp)
  mov    $0xbe6f0000,%eax
  sub    -0x4(%rsp),%eax
  shr    %eax
  movss  D11(%rip),%xmm1
  mulss  %xmm0,%xmm3
  movd   %eax,%xmm5
  movd   %eax,%xmm2
  movaps %xmm1,%xmm4
  mulss  %xmm3,%xmm5
  mulss  %xmm2,%xmm5
  subss  %xmm5,%xmm4
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm3
  subss  %xmm3,%xmm1
  mulss  %xmm2,%xmm1
  mulss  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: byte[4]
name: retrieve_data
arguments: tag: D11
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3f]}

tool: {"D11": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float cvSqrt(float arg) {
  float x, y;
  unsigned iarg = *((unsigned *)&arg);
  *((unsigned *)&x) = (0xbe6f0000 - iarg) >> 1;
  y = arg * 0.5f;
  x *= 1.5f - y * x * x;
  x *= 1.5f - y * x * x;
  return x * arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cvSqrt>:
  endbr64
  movss  D1(%rip),%xmm3
  movd   %xmm0,-0x4(%rsp)
  mov    $0xbe6f0000,%eax
  sub    -0x4(%rsp),%eax
  shr    %eax
  movss  D2(%rip),%xmm1
  mulss  %xmm0,%xmm3
  movd   %eax,%xmm5
  movd   %eax,%xmm2
  movaps %xmm1,%xmm4
  mulss  %xmm3,%xmm5
  mulss  %xmm2,%xmm5
  subss  %xmm5,%xmm4
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm3
  mulss  %xmm2,%xmm3
  subss  %xmm3,%xmm1
  mulss  %xmm2,%xmm1
  mulss  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: byte[4]
name: parse_data
arguments: tag: D2
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

tool: {"D2": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float cvSqrt(float arg) {
  float x, y;
  unsigned iarg = *((unsigned *)&arg);
  *((unsigned *)&x) = (0xbe6f0000 - iarg) >> 1;
  y = arg * 0.5f;
  x *= 1.5f - y * x * x;
  x *= 1.5f - y * x * x;
  return x * arg;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L107
  lea    0xc(%rsp),%r12
  lea    D15(%rip),%rbx
  lea    0x14(%rsp),%rbp
  jmp    L42
L52:
  lea    0x10(%rsp),%r9
  lea    -0x1(%rcx),%eax
  lea    0x0(%rbp,%rax,4),%r10
  mov    %r8d,%eax
L27:
  mov    %esi,%edx
  imul   (%r9),%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%eax
  lea    (%rax,%rax,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%edx
  mov    %edx,(%r9)
  add    $0x4,%r9
  cmp    %r10,%r9
  jne    L27
  test   %eax,%eax
  je     L33
  lea    0x1(%rcx),%r9d
  movslq %r9d,%r9
L62:
  mov    %r9d,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%r10d
  add    %r10d,%r10d
  sub    %r10d,%eax
  mov    %eax,0xc(%rsp,%r9,4)
  mov    %edx,%eax
  add    $0x1,%r9
  test   %edx,%edx
  jne    L62
L33:
  add    $0x1,%esi
  cmp    %edi,%esi
  je     L69
L56:
  test   %ecx,%ecx
  jg     L52
  jmp    L33
L69:
  sub    $0x1,%ecx
  js     L108
L29:
  movslq %ecx,%r13
L147:
  mov    0x10(%rsp,%r13,4),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%r13
  test   %r13d,%r13d
  jns    L147
L108:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L107
L42:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  movl   $0x1,0x10(%rsp)
  test   %edi,%edi
  jle    L3
  add    $0x1,%edi
  mov    $0x1,%esi
  mov    $0x1,%ecx
  mov    $0x0,%r8d
  jmp    L56
L3:
  mov    $0x0,%ecx
  jmp    L29
L107:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  mov    $0x0,%eax
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string

tool: D15: %d

assistant: ```c
int main() {
  int test;
  scanf("%d", &test);
  while (test--) {
    int array[200];
    int m;
    int n;
    int i;
    int hold, index;
    scanf("%d", &n);
    hold = n;
    array[0] = 1;
    m = 1;
    i = 1;
    while (i <= n) {
      int temp = 0;
      for (index = 0; index < m; index++) {
        int x = i * array[index] + temp;
        array[index] = x % 10;
        temp = x / 10;
      }
      while (temp != 0) {
        array[m++] = temp % 10;
        temp /= 10;
      }
      i++;
    }
    for (i = m - 1; i >= 0; i--) {
      printf("%d", array[i]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    0x10(%rsp),%r12
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L76
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  movl   $0x1,0x10(%rsp)
  test   %edi,%edi
  jle    L65
  add    $0x1,%edi
  mov    $0x1,%ecx
  mov    $0x1,%esi
  xor    %r11d,%r11d
  lea    0x14(%rsp),%r8
  nopl   0x0(%rax)
L55:
  mov    %r11d,%eax
  mov    %r12,%r9
  lea    (%r8,%rax,4),%r10
  xor    %eax,%eax
  nopl   0x0(%rax)
L2:
  mov    (%r9),%edx
  add    $0x4,%r9
  imul   %ecx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%r13d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r13d
  sar    $0x22,%rax
  sub    %r13d,%eax
  lea    (%rax,%rax,4),%r13d
  add    %r13d,%r13d
  sub    %r13d,%edx
  mov    %edx,-0x4(%r9)
  cmp    %r10,%r9
  jne    L2
  test   %eax,%eax
  je     L5
  lea    0x1(%rsi),%r9d
  movslq %r9d,%r9
  nopw   0x0(%rax,%rax,1)
L43:
  movslq %eax,%rdx
  mov    %eax,%r10d
  mov    %r9d,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%r10d
  add    %r10d,%r10d
  sub    %r10d,%eax
  mov    %eax,-0x4(%r12,%r9,4)
  mov    %edx,%eax
  add    $0x1,%r9
  test   %edx,%edx
  jne    L43
  lea    -0x1(%rsi),%r11d
L5:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jne    L55
L79:
  movslq %r11d,%rax
  mov    %rbp,%r14
  lea    (%r12,%rax,4),%r13
  nopl   (%rax)
L81:
  mov    0x0(%r13),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  sub    $0x4,%r13
  call   <printf@plt>
  cmp    %r14,%r13
  jne    L81
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L11
L76:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  xor    %r11d,%r11d
  jmp    L79
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main() {
  int test;
  scanf("%d", &test);
  while (test--) {
    int array[200];
    int m;
    int n;
    int i;
    int hold, index;
    scanf("%d", &n);
    hold = n;
    array[0] = 1;
    m = 1;
    i = 1;
    while (i <= n) {
      int temp = 0;
      for (index = 0; index < m; index++) {
        int x = i * array[index] + temp;
        array[index] = x % 10;
        temp = x / 10;
      }
      while (temp != 0) {
        array[m++] = temp % 10;
        temp /= 10;
      }
      i++;
    }
    for (i = m - 1; i >= 0; i--) {
      printf("%d", array[i]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L12
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L36
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L35
L36:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
L35:
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
char *strdup(const char *string) {
  char *palaute;
  unsigned int length;
  if (!string)
    return NULL;
  length = strlen(string);
  palaute = malloc(length + 1);
  if (palaute) {
    memcpy(palaute, string, length);
    palaute[length] = '\0';
  } else
    errno = ENOMEM;
  return palaute;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L10
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %ebx,%ebx
  movb   $0x0,0x0(%rbp,%rbx,1)
L19:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  jmp    L19
```

assistant: ```c
char *strdup(const char *string) {
  char *palaute;
  unsigned int length;
  if (!string)
    return NULL;
  length = strlen(string);
  palaute = malloc(length + 1);
  if (palaute) {
    memcpy(palaute, string, length);
    palaute[length] = '\0';
  } else
    errno = ENOMEM;
  return palaute;
}
```
user: What is the c source code of the assembly code below?

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *string) {
  char *palaute;
  unsigned int length;
  if (!string)
    return NULL;
  length = strlen(string);
  palaute = malloc(length + 1);
  if (palaute) {
    memcpy(palaute, string, length);
    palaute[length] = '\0';
  } else
    errno = ENOMEM;
  return palaute;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *string) {
  char *palaute;
  unsigned int length;
  if (!string)
    return NULL;
  length = strlen(string);
  palaute = malloc(length + 1);
  if (palaute) {
    memcpy(palaute, string, length);
    palaute[length] = '\0';
  } else
    errno = ENOMEM;
  return palaute;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<searchRange>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %rcx,%r13
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r9
  mov    %r12d,%edx
  mov    $0x0,%esi
L70:
  cmp    %edx,%esi
  jge    L79
  lea    (%rsi,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rdi
  lea    (%rbx,%rdi,4),%r8
  mov    (%r8),%edi
  cmp    %ebp,%edi
  jle    L28
  mov    %eax,%edx
  jmp    L70
L28:
  jge    L26
  lea    0x1(%rax),%esi
  jmp    L70
L26:
  movl   $0x2,0x0(%r13)
  cmp    $0xffffffff,%eax
  je     L113
  sub    $0x1,%eax
  cmp    $0x1,%ecx
  jle    L99
  mov    (%r8),%ecx
  movslq %eax,%rdx
L67:
  mov    %edx,%eax
  sub    $0x1,%rdx
  cmp    0x4(%rbx,%rdx,4),%ecx
  je     L67
L99:
  lea    0x1(%rax),%esi
  cmp    $0xfffffffe,%eax
  mov    $0x0,%eax
  cmove  %eax,%esi
  lea    0x1(%rsi),%edx
  cmp    %edx,%r12d
  jle    L3
  movslq %esi,%rax
  mov    (%rbx,%rax,4),%ecx
  movslq %edx,%rax
L29:
  mov    %eax,%edx
  cmp    (%rbx,%rax,4),%ecx
  jne    L3
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L29
L3:
  sub    $0x1,%edx
L73:
  mov    %esi,(%r9)
  mov    %edx,0x4(%r9)
  mov    %r9,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  movl   $0x2,0x0(%r13)
L113:
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edx
  jmp    L73
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int *buf = (int *)malloc(sizeof(int) * 2);
  int a = 0;
  int b = numsSize;
  int ret = -1;
  while (a < b) {
    int mid = (a + b) / 2;
    int val = nums[mid];
    if (target < val) {
      b = mid;
    } else if (target > val) {
      a = mid + 1;
    } else {
      ret = mid;
      break;
    }
  }
  *returnSize = 2;
  if (ret == -1) {
    buf[0] = -1;
    buf[1] = -1;
    return buf;
  }
  int i;
  for (i = ret - 1; ret > 0; --i) {
    if (nums[ret] != nums[i])
      break;
  }
  ret = i + 1;
  if (ret == -1)
    ret = 0;
  i = ret;
  for (i = ret + 1; i < numsSize; ++i) {
    if (nums[ret] != nums[i])
      break;
  }
  buf[0] = ret;
  buf[1] = i - 1;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<searchRange>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    %rax,%r8
  jmp    L5
  nopl   0x0(%rax)
L65:
  lea    (%rsi,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  lea    (%rbx,%rdi,4),%rdi
  cmp    %r12d,(%rdi)
  jle    L9
  mov    %eax,%edx
L5:
  cmp    %edx,%esi
  jl     L65
  movl   $0x2,0x0(%r13)
L135:
  mov    $0xffffffff,%r9d
  mov    $0xffffffff,%edx
L3:
  mov    %r9d,(%r8)
  mov    %r8,%rax
  mov    %edx,0x4(%r8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  jge    L115
  lea    0x1(%rax),%esi
  jmp    L5
L115:
  movl   $0x2,0x0(%r13)
  cmp    $0xffffffff,%eax
  je     L135
  sub    $0x1,%eax
  cmp    $0x1,%ecx
  jle    L95
  mov    (%rdi),%ecx
  cltq
L31:
  mov    %eax,%edx
  sub    $0x1,%rax
  cmp    0x4(%rbx,%rax,4),%ecx
  je     L31
  lea    0x1(%rdx),%r9d
  cmp    $0xfffffffe,%edx
  je     L18
L95:
  lea    0x1(%r9),%eax
L150:
  cmp    %eax,%ebp
  jle    L64
  movslq %r9d,%rdx
  cltq
  mov    (%rbx,%rdx,4),%ecx
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L117:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jle    L3
L56:
  mov    %eax,%edx
  cmp    (%rbx,%rax,4),%ecx
  je     L117
  sub    $0x1,%edx
  jmp    L3
  nopl   0x0(%rax)
L18:
  mov    $0x1,%eax
  xor    %r9d,%r9d
  jmp    L150
L64:
  mov    %r9d,%edx
  jmp    L3
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int *buf = (int *)malloc(sizeof(int) * 2);
  int a = 0;
  int b = numsSize;
  int ret = -1;
  while (a < b) {
    int mid = (a + b) / 2;
    int val = nums[mid];
    if (target < val) {
      b = mid;
    } else if (target > val) {
      a = mid + 1;
    } else {
      ret = mid;
      break;
    }
  }
  *returnSize = 2;
  if (ret == -1) {
    buf[0] = -1;
    buf[1] = -1;
    return buf;
  }
  int i;
  for (i = ret - 1; ret > 0; --i) {
    if (nums[ret] != nums[i])
      break;
  }
  ret = i + 1;
  if (ret == -1)
    ret = 0;
  i = ret;
  for (i = ret + 1; i < numsSize; ++i) {
    if (nums[ret] != nums[i])
      break;
  }
  buf[0] = ret;
  buf[1] = i - 1;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<searchRange>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebp,%ecx
  xor    %esi,%esi
  mov    %rax,%r8
  jmp    L149
  nopl   0x0(%rax)
L56:
  lea    (%rsi,%rcx,1),%r9d
  mov    %r9d,%eax
  shr    $0x1f,%eax
  add    %r9d,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  shl    $0x2,%rdx
  lea    (%rbx,%rdx,1),%rdi
  cmp    %r12d,(%rdi)
  jle    L46
  mov    %eax,%ecx
L149:
  cmp    %ecx,%esi
  jl     L56
  movl   $0x2,0x0(%r13)
L84:
  mov    $0xffffffff,%r10d
  mov    $0xffffffff,%edx
L97:
  mov    %r10d,(%r8)
  mov    %r8,%rax
  mov    %edx,0x4(%r8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  jge    L20
  lea    0x1(%rax),%esi
  jmp    L149
L20:
  movl   $0x2,0x0(%r13)
  cmp    $0xffffffff,%eax
  je     L84
  lea    -0x1(%rax),%ecx
  cmp    $0x1,%r9d
  jle    L142
  sub    $0x2,%eax
  mov    (%rdi),%esi
  cltq
  cmp    -0x4(%rbx,%rdx,1),%esi
  jne    L165
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %eax,%ecx
  sub    $0x1,%rax
  cmp    0x4(%rbx,%rax,4),%esi
  je     L26
L165:
  lea    0x1(%rcx),%r10d
  cmp    $0xfffffffe,%ecx
  je     L27
L142:
  lea    0x1(%r10),%eax
L119:
  cmp    %eax,%ebp
  jle    L86
  movslq %r10d,%rdx
  cltq
  mov    (%rbx,%rdx,4),%ecx
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L100:
  add    $0x1,%rax
  cmp    %eax,%ebp
  jle    L97
L73:
  mov    %eax,%edx
  cmp    (%rbx,%rax,4),%ecx
  je     L100
  sub    $0x1,%edx
  jmp    L97
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  xor    %r10d,%r10d
  jmp    L119
L86:
  mov    %r10d,%edx
  jmp    L97
```

assistant: ```c
int *searchRange(int *nums, int numsSize, int target, int *returnSize) {
  int *buf = (int *)malloc(sizeof(int) * 2);
  int a = 0;
  int b = numsSize;
  int ret = -1;
  while (a < b) {
    int mid = (a + b) / 2;
    int val = nums[mid];
    if (target < val) {
      b = mid;
    } else if (target > val) {
      a = mid + 1;
    } else {
      ret = mid;
      break;
    }
  }
  *returnSize = 2;
  if (ret == -1) {
    buf[0] = -1;
    buf[1] = -1;
    return buf;
  }
  int i;
  for (i = ret - 1; ret > 0; --i) {
    if (nums[ret] != nums[i])
      break;
  }
  ret = i + 1;
  if (ret == -1)
    ret = 0;
  i = ret;
  for (i = ret + 1; i < numsSize; ++i) {
    if (nums[ret] != nums[i])
      break;
  }
  buf[0] = ret;
  buf[1] = i - 1;
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2cWriteWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x8(%rbp)
  mov    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%edx
  movzbl -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <i2c_smbus_write_word_data@plt>
  test   %rax,%rax
  je     L16
  mov    $0xffffffff,%eax
  jmp    L14
L16:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int i2cWriteWord(int i2cAdapter, unsigned char address, unsigned short word) {
  if (i2c_smbus_write_word_data(i2cAdapter, address, word)) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2cWriteWord>:
  endbr64
  sub    $0x8,%rsp
  movzwl %dx,%edx
  movzbl %sil,%esi
  call   <i2c_smbus_write_word_data@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int i2cWriteWord(int i2cAdapter, unsigned char address, unsigned short word) {
  if (i2c_smbus_write_word_data(i2cAdapter, address, word)) {
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i2cWriteWord>:
  endbr64
  sub    $0x8,%rsp
  movzwl %dx,%edx
  movzbl %sil,%esi
  call   <i2c_smbus_write_word_data@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int i2cWriteWord(int i2cAdapter, unsigned char address, unsigned short word) {
  if (i2c_smbus_write_word_data(i2cAdapter, address, word)) {
    return -1;
  }
  return 0;
}
```