ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%r13d
  lea    0x24(%rsp),%r12
  lea    D36(%rip),%rbp
  lea    D14(%rip),%r14
  lea    D23(%rip),%r15
  cmpl   $0x0,0xc(%rsp)
  jg     L88
L65:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  cmpl   $0x2,0x14(%rsp)
  je     L28
L44:
  mov    %r14,%rdi
  call   <printf@plt>
L147:
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jle    L65
L88:
  lea    0x10(%rsp),%rbx
L48:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L48
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L97
  cmp    $0x2,%eax
  jne    L44
  cmpl   $0x3,0x14(%rsp)
  jne    L44
  cmpl   $0x4,0x18(%rsp)
  jne    L44
  cmpl   $0x5,0x1c(%rsp)
  jne    L44
  cmpl   $0x6,0x20(%rsp)
  jne    L44
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L147
L28:
  cmpl   $0x3,0x18(%rsp)
  jne    L44
  cmpl   $0x4,0x1c(%rsp)
  jne    L44
  cmpl   $0x5,0x20(%rsp)
  jne    L44
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L147
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D36
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string

tool: D36: %d

tool: D14: N


tool: D23: Y


assistant: ```c
int main() {
  int t, ara[10], i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    for (j = 0; j < 5; j++) {
      scanf("%d", &ara[j]);
    }
    if (ara[0] == 1 && ara[1] == 2 && ara[2] == 3 && ara[3] == 4 && ara[4] == 5)
      printf("Y\n");
    else if (ara[0] == 2 && ara[1] == 3 && ara[2] == 4 && ara[3] == 5 && ara[4] == 6)
      printf("Y\n");
    else
      printf("N\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  lea    0x24(%rsp),%rbp
  lea    D13(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r13,%r15
L91:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %rbp,%r15
  jne    L91
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L58
  cmp    $0x2,%eax
  jne    L100
  cmpl   $0x3,0x14(%rsp)
  je     L53
L100:
  mov    %r14,%rdi
  call   <printf@plt>
L83:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jg     L42
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  cmpl   $0x2,0x14(%rsp)
  jne    L100
  cmpl   $0x3,0x18(%rsp)
  jne    L100
  cmpl   $0x4,0x1c(%rsp)
  jne    L100
  cmpl   $0x5,0x20(%rsp)
  jne    L100
L59:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L53:
  cmpl   $0x4,0x18(%rsp)
  jne    L100
  cmpl   $0x5,0x1c(%rsp)
  jne    L100
  cmpl   $0x6,0x20(%rsp)
  jne    L100
  jmp    L59
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string

tool: D2: %d

tool: D13: N


tool: D29: Y


assistant: ```c
int main() {
  int t, ara[10], i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    for (j = 0; j < 5; j++) {
      scanf("%d", &ara[j]);
    }
    if (ara[0] == 1 && ara[1] == 2 && ara[2] == 3 && ara[3] == 4 && ara[4] == 5)
      printf("Y\n");
    else if (ara[0] == 2 && ara[1] == 3 && ara[2] == 4 && ara[3] == 5 && ara[4] == 6)
      printf("Y\n");
    else
      printf("N\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D28(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L92
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  lea    0x24(%rsp),%rbp
  lea    D9(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L103:
  mov    %r13,%r15
L1:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %r15,%rbp
  jne    L1
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L8
  cmp    $0x2,%eax
  jne    L27
  cmpl   $0x3,0x14(%rsp)
  je     L145
L27:
  mov    %r14,%rdi
  call   <printf@plt>
L21:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jg     L103
L92:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  cmpl   $0x2,0x14(%rsp)
  jne    L27
  cmpl   $0x3,0x18(%rsp)
  jne    L27
  cmpl   $0x4,0x1c(%rsp)
  jne    L27
  cmpl   $0x5,0x20(%rsp)
  jne    L27
L156:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L145:
  cmpl   $0x4,0x18(%rsp)
  jne    L27
  cmpl   $0x5,0x1c(%rsp)
  jne    L27
  cmpl   $0x6,0x20(%rsp)
  jne    L27
  jmp    L156
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D28
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D28: %d

tool: D9: N


tool: D12: Y


assistant: ```c
int main() {
  int t, ara[10], i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    for (j = 0; j < 5; j++) {
      scanf("%d", &ara[j]);
    }
    if (ara[0] == 1 && ara[1] == 2 && ara[2] == 3 && ara[3] == 4 && ara[4] == 5)
      printf("Y\n");
    else if (ara[0] == 2 && ara[1] == 3 && ara[2] == 4 && ara[3] == 5 && ara[4] == 6)
      printf("Y\n");
    else
      printf("N\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isPrimeNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L19
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L32
  mov    $0x0,%eax
  jmp    L6
L32:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x18(%rbp),%rdx
  shr    %rdx
  cmp    %rdx,%rax
  jbe    L13
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int isPrimeNumber(unsigned long int n) {
  int i;
  for (i = 2; i <= (n >> 1); i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isPrimeNumber>:
  endbr64
  mov    %rdi,%rsi
  shr    %rsi
  cmp    $0x3,%rdi
  jbe    L18
  test   $0x1,%dil
  je     L9
  add    $0x1,%rsi
  mov    $0x3,%ecx
L3:
  cmp    %rsi,%rcx
  je     L30
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  jne    L3
  mov    $0x0,%eax
  ret
L30:
  mov    $0x1,%eax
  ret
L18:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isPrimeNumber(unsigned long int n) {
  int i;
  for (i = 2; i <= (n >> 1); i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPrimeNumber>:
  endbr64
  mov    %rdi,%rsi
  shr    %rsi
  cmp    $0x3,%rdi
  jbe    L39
  test   $0x1,%dil
  je     L40
  add    $0x1,%rsi
  mov    $0x3,%ecx
  jmp    L21
  nopl   0x0(%rax)
L37:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  je     L40
L21:
  cmp    %rsi,%rcx
  jne    L37
L39:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isPrimeNumber(unsigned long int n) {
  int i;
  for (i = 2; i <= (n >> 1); i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isPrimeNumber>:
  endbr64
  mov    %rdi,%rsi
  shr    %rsi
  cmp    $0x3,%rdi
  jbe    L12
  test   $0x1,%dil
  je     L15
  add    $0x1,%rsi
  mov    $0x3,%ecx
  jmp    L29
  nopl   0x0(%rax)
L31:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  test   %rdx,%rdx
  je     L15
L29:
  cmp    %rcx,%rsi
  jne    L31
L12:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isPrimeNumber(unsigned long int n) {
  int i;
  for (i = 2; i <= (n >> 1); i++)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SysTick_Wait10ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L18:
  mov    $0xc3500,%edi
  call   <SysTick_Wait@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void SysTick_Wait10ms(unsigned long delay) {
  unsigned long i;
  for (i = 0; i < delay; i++) {
    SysTick_Wait(800000);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<SysTick_Wait10ms>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L19:
  mov    $0xc3500,%edi
  call   <SysTick_Wait@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
void SysTick_Wait10ms(unsigned long delay) {
  unsigned long i;
  for (i = 0; i < delay; i++) {
    SysTick_Wait(800000);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SysTick_Wait10ms>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    $0xc3500,%edi
  add    $0x1,%rbx
  call   <SysTick_Wait@plt>
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void SysTick_Wait10ms(unsigned long delay) {
  unsigned long i;
  for (i = 0; i < delay; i++) {
    SysTick_Wait(800000);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SysTick_Wait10ms>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L5:
  mov    $0xc3500,%edi
  add    $0x1,%rbx
  call   <SysTick_Wait@plt>
  cmp    %rbx,%rbp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void SysTick_Wait10ms(unsigned long delay) {
  unsigned long i;
  for (i = 0; i < delay; i++) {
    SysTick_Wait(800000);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_anim_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_icmp@plt>
  test   %rax,%rax
  jne    L48
  mov    $0x0,%eax
  jmp    L44
L48:
  mov    -0x8(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_icmp@plt>
  test   %rax,%rax
  jne    L22
  mov    $0x1,%eax
  jmp    L44
L22:
  mov    -0x8(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_icmp@plt>
  test   %rax,%rax
  jne    L49
  mov    $0x2,%eax
  jmp    L44
L49:
  mov    $0x0,%eax
L44:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string

tool: D17: Surge

tool: D22: Neon

tool: D23: Charge

assistant: ```c
int get_anim_id(const char *player_name) {
  if (str_icmp(player_name, "Surge") == 0)
    return 0;
  else if (str_icmp(player_name, "Neon") == 0)
    return 1;
  else if (str_icmp(player_name, "Charge") == 0)
    return 2;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_anim_id>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rsi
  call   <str_icmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L6
L16:
  pop    %rbx
  ret
L6:
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_icmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L16
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_icmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D21
data_type: string

tool: D8: Surge

tool: D1: Neon

tool: D21: Charge

assistant: ```c
int get_anim_id(const char *player_name) {
  if (str_icmp(player_name, "Surge") == 0)
    return 0;
  else if (str_icmp(player_name, "Neon") == 0)
    return 1;
  else if (str_icmp(player_name, "Charge") == 0)
    return 2;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_anim_id>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rsi
  mov    %rdi,%rbp
  call   <str_icmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
L15:
  pop    %rbp
  ret
L9:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_icmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L15
  mov    %rbp,%rdi
  lea    D20(%rip),%rsi
  call   <str_icmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string

tool: D11: Surge

tool: D14: Neon

tool: D20: Charge

assistant: ```c
int get_anim_id(const char *player_name) {
  if (str_icmp(player_name, "Surge") == 0)
    return 0;
  else if (str_icmp(player_name, "Neon") == 0)
    return 1;
  else if (str_icmp(player_name, "Charge") == 0)
    return 2;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_anim_id>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rsi
  mov    %rdi,%rbp
  call   <str_icmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L13
L14:
  pop    %rbp
  ret
L13:
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <str_icmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L14
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <str_icmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D20
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string

tool: D29: Surge

tool: D20: Neon

tool: D11: Charge

assistant: ```c
int get_anim_id(const char *player_name) {
  if (str_icmp(player_name, "Surge") == 0)
    return 0;
  else if (str_icmp(player_name, "Neon") == 0)
    return 1;
  else if (str_icmp(player_name, "Charge") == 0)
    return 2;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L47
L0:
  addq   $0x1,-0x10(%rbp)
L47:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  jmp    L45
L37:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L45:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L37
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strncat(char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (s1[i])
    i++;
  while (s2[j] && j < n) {
    s1[i] = s2[j];
    i++;
    j++;
  }
  s1[i] = '\0';
  return (s1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strncat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L4
  mov    $0x0,%r8d
L36:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  jne    L36
L42:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L63
  test   %r9b,%r9b
  je     L63
  mov    $0x0,%ecx
  lea    (%rax,%r8,1),%r10
  lea    0x1(%r8),%rdi
L62:
  mov    %r9b,(%r10,%rcx,1)
  lea    (%rdi,%rcx,1),%r8
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  jbe    L63
  test   %r9b,%r9b
  jne    L62
L63:
  movb   $0x0,(%rax,%r8,1)
  ret
L4:
  mov    $0x0,%r8d
  jmp    L42
```

assistant: ```c
char *ft_strncat(char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (s1[i])
    i++;
  while (s2[j] && j < n) {
    s1[i] = s2[j];
    i++;
    j++;
  }
  s1[i] = '\0';
  return (s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L50
  xor    %r8d,%r8d
  nop
L75:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  lea    (%rax,%r8,1),%rcx
  jne    L75
L26:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L33
  test   %r9b,%r9b
  je     L33
  lea    0x1(%r8),%r10
  xor    %ecx,%ecx
  add    %rax,%r8
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L48:
  test   %r9b,%r9b
  je     L19
L0:
  mov    %r9b,(%r8,%rcx,1)
  lea    (%r10,%rcx,1),%rdi
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  ja     L48
L19:
  lea    (%rax,%rdi,1),%rcx
L33:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L26
```

assistant: ```c
char *ft_strncat(char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (s1[i])
    i++;
  while (s2[j] && j < n) {
    s1[i] = s2[j];
    i++;
    j++;
  }
  s1[i] = '\0';
  return (s1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L70
  xor    %r8d,%r8d
  nop
L32:
  add    $0x1,%r8
  cmpb   $0x0,(%rax,%r8,1)
  lea    (%rax,%r8,1),%rcx
  jne    L32
L58:
  movzbl (%rsi),%r9d
  test   %rdx,%rdx
  je     L43
  test   %r9b,%r9b
  je     L43
  lea    0x1(%r8),%r10
  xor    %ecx,%ecx
  add    %rax,%r8
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L69:
  test   %r9b,%r9b
  je     L14
L53:
  mov    %r9b,(%r8,%rcx,1)
  lea    (%r10,%rcx,1),%rdi
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r9d
  cmp    %rcx,%rdx
  ja     L69
L14:
  lea    (%rax,%rdi,1),%rcx
L43:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L58
```

assistant: ```c
char *ft_strncat(char *s1, const char *s2, size_t n) {
  size_t i;
  size_t j;
  i = 0;
  j = 0;
  while (s1[i])
    i++;
  while (s2[j] && j < n) {
    s1[i] = s2[j];
    i++;
    j++;
  }
  s1[i] = '\0';
  return (s1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dotMultiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dotMultiplication(double *a, double *b, int len) {
  double result = 0;
  for (int i = 0; i < len; i++) {
    result += a[i] * b[i];
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dotMultiplication>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L24:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L24
L17:
  movapd %xmm1,%xmm0
  ret
L0:
  pxor   %xmm1,%xmm1
  jmp    L17
```

assistant: ```c
double dotMultiplication(double *a, double *b, int len) {
  double result = 0;
  for (int i = 0; i < len; i++) {
    result += a[i] * b[i];
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dotMultiplication>:
  endbr64
  test   %edx,%edx
  jle    L19
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L16:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L16
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dotMultiplication(double *a, double *b, int len) {
  double result = 0;
  for (int i = 0; i < len; i++) {
    result += a[i] * b[i];
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dotMultiplication>:
  endbr64
  test   %edx,%edx
  jle    L25
  cmp    $0x1,%edx
  je     L17
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L39:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L39
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L5
L33:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L5:
  ret
  nopl   0x0(%rax)
L25:
  pxor   %xmm0,%xmm0
  ret
L17:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L33
```

assistant: ```c
double dotMultiplication(double *a, double *b, int len) {
  double result = 0;
  for (int i = 0; i < len; i++) {
    result += a[i] * b[i];
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_stop_monitor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <profil@plt>
  mov    $0x0,%eax
  call   <write_gmon@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _stop_monitor(void) {
  profil(NULL, 0, 0, 0);
  write_gmon();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_stop_monitor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <profil@plt>
  mov    $0x0,%eax
  call   <write_gmon@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _stop_monitor(void) {
  profil(NULL, 0, 0, 0);
  write_gmon();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_stop_monitor>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <profil@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <write_gmon@plt>
```

assistant: ```c
void _stop_monitor(void) {
  profil(NULL, 0, 0, 0);
  write_gmon();
}
```