ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_usage>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: Usage: mf RULE_OPTIONS..
MiniFirewall implements an exact match algorithm, where unspecified options are ignored.
-i --in             input
-o --out            output
-s --s_ip IPADDR    source ip address
-m --s_mask MASK    source mask
-p --s_port PORT    source port
-d --d_ip IPADDR    destination ip address
-n --d_mask MASK    destination mask
-q --d_port PORT    destination port
-c --proto PROTO    protocol
-a --add            add a rule
-r --remove         remove a rule
-v --view           view rules
-h --help           this usage


assistant: ```c
void print_usage(void) {
  printf("Usage: mf RULE_OPTIONS..\n"
         "MiniFirewall implements an exact match algorithm, where "
         "unspecified options are ignored.\n"
         "-i --in             input\n"
         "-o --out            output\n"
         "-s --s_ip IPADDR    source ip address\n"
         "-m --s_mask MASK    source mask\n"
         "-p --s_port PORT    source port\n"
         "-d --d_ip IPADDR    destination ip address\n"
         "-n --d_mask MASK    destination mask\n"
         "-q --d_port PORT    destination port\n"
         "-c --proto PROTO    protocol\n"
         "-a --add            add a rule\n"
         "-r --remove         remove a rule\n"
         "-v --view           view rules\n"
         "-h --help           this usage\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tribonacci_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x1,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L14
L6:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L14:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L6
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long tribonacci_num(int n) {
  long t1 = 0;
  long t2 = 1;
  long t3 = 1;
  while (n-- > 0) {
    long t = t1 + t2 + t3;
    t1 = t2;
    t2 = t3;
    t3 = t;
  }
  return t3;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tribonacci_num>:
  endbr64
  lea    -0x1(%rdi),%ecx
  test   %edi,%edi
  jle    L22
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    $0x0,%eax
L6:
  mov    %rdx,%rdi
  add    %rsi,%rax
  add    %rax,%rdx
  sub    $0x1,%ecx
  mov    %rsi,%rax
  mov    %rdi,%rsi
  cmp    $0xffffffff,%ecx
  jne    L6
L3:
  mov    %rdx,%rax
  ret
L22:
  mov    $0x1,%edx
  jmp    L3
```

assistant: ```c
long tribonacci_num(int n) {
  long t1 = 0;
  long t2 = 1;
  long t3 = 1;
  while (n-- > 0) {
    long t = t1 + t2 + t3;
    t1 = t2;
    t2 = t3;
    t3 = t;
  }
  return t3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tribonacci_num>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%r8d
  test   %edi,%edi
  jle    L4
  mov    $0x1,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L14:
  add    %rcx,%rax
  mov    %r8,%rsi
  sub    $0x1,%edx
  add    %rax,%r8
  mov    %rcx,%rax
  mov    %rsi,%rcx
  cmp    $0xffffffff,%edx
  jne    L14
L4:
  mov    %r8,%rax
  ret
```

assistant: ```c
long tribonacci_num(int n) {
  long t1 = 0;
  long t2 = 1;
  long t3 = 1;
  while (n-- > 0) {
    long t = t1 + t2 + t3;
    t1 = t2;
    t2 = t3;
    t3 = t;
  }
  return t3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tribonacci_num>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%r8d
  test   %edi,%edi
  jle    L2
  mov    $0x1,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  add    %rcx,%rax
  mov    %r8,%rsi
  sub    $0x1,%edx
  add    %rax,%r8
  mov    %rcx,%rax
  mov    %rsi,%rcx
  cmp    $0xffffffff,%edx
  jne    L3
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
long tribonacci_num(int n) {
  long t1 = 0;
  long t2 = 1;
  long t3 = 1;
  while (n-- > 0) {
    long t = t1 + t2 + t3;
    t1 = t2;
    t2 = t3;
    t3 = t;
  }
  return t3;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x7,%eax
  lea    D20(%rip),%rdx
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D25
datatype: string

tool: D21: Usage: %s [-c,--calendar "<date>"]


tool: D20:  

tool: D25: %*s [-s,--stardate <stardate>]


assistant: ```c
void usage(char *exec) {
  printf("Usage: %s [-c,--calendar \"<date>\"]\n", exec);
  printf("%*s [-s,--stardate <stardate>]\n", (int)strlen(exec) + 7, " ");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x7(%rax),%esi
  lea    D29(%rip),%rdx
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D27
data_type: string

tool: D21: Usage: %s [-c,--calendar "<date>"]


tool: D29:  

tool: D27: %*s [-s,--stardate <stardate>]


assistant: ```c
void usage(char *exec) {
  printf("Usage: %s [-c,--calendar \"<date>\"]\n", exec);
  printf("%*s [-s,--stardate <stardate>]\n", (int)strlen(exec) + 7, " ");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D12(%rip),%rdx
  lea    D8(%rip),%rdi
  pop    %rbp
  lea    0x7(%rax),%esi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D28: Usage: %s [-c,--calendar "<date>"]


tool: D12:  

tool: D8: %*s [-s,--stardate <stardate>]


assistant: ```c
void usage(char *exec) {
  printf("Usage: %s [-c,--calendar \"<date>\"]\n", exec);
  printf("%*s [-s,--stardate <stardate>]\n", (int)strlen(exec) + 7, " ");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D0(%rip),%rdx
  lea    D10(%rip),%rdi
  pop    %rbp
  lea    0x7(%rax),%esi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D28: Usage: %s [-c,--calendar "<date>"]


tool: D0:  

tool: D10: %*s [-s,--stardate <stardate>]


assistant: ```c
void usage(char *exec) {
  printf("Usage: %s [-c,--calendar \"<date>\"]\n", exec);
  printf("%*s [-s,--stardate <stardate>]\n", (int)strlen(exec) + 7, " ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dasum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L4:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L6
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L6:
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dasum(unsigned int n, const double *dx) {
  double sum = 0.0;
  do {
    --n;
    if (dx[n] < 0)
      sum = sum - dx[n];
    else
      sum = sum + dx[n];
  } while (n);
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dasum>:
  endbr64
  lea    -0x1(%rdi),%eax
  lea    (%rsi,%rax,8),%rax
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
  jmp    L24
L22:
  subsd  %xmm0,%xmm1
L20:
  lea    -0x8(%rax),%rdx
  cmp    %rsi,%rax
  je     L17
  mov    %rdx,%rax
L24:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm2
  ja     L22
  addsd  %xmm0,%xmm1
  jmp    L20
L17:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dasum(unsigned int n, const double *dx) {
  double sum = 0.0;
  do {
    --n;
    if (dx[n] < 0)
      sum = sum - dx[n];
    else
      sum = sum + dx[n];
  } while (n);
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dasum>:
  endbr64
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  lea    (%rsi,%rax,8),%rax
  movapd %xmm2,%xmm1
  jmp    L23
  nopl   (%rax)
L33:
  addsd  %xmm0,%xmm1
  lea    -0x8(%rax),%rdx
  cmp    %rsi,%rax
  je     L27
L11:
  mov    %rdx,%rax
L23:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm2
  jbe    L33
  subsd  %xmm0,%xmm1
  lea    -0x8(%rax),%rdx
  cmp    %rsi,%rax
  jne    L11
L27:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dasum(unsigned int n, const double *dx) {
  double sum = 0.0;
  do {
    --n;
    if (dx[n] < 0)
      sum = sum - dx[n];
    else
      sum = sum + dx[n];
  } while (n);
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dasum>:
  endbr64
  lea    -0x1(%rdi),%eax
  pxor   %xmm2,%xmm2
  lea    (%rsi,%rax,8),%rax
  movapd %xmm2,%xmm1
  jmp    L3
  nopl   (%rax)
L1:
  addsd  %xmm0,%xmm1
  lea    -0x8(%rax),%rdx
  cmp    %rsi,%rax
  je     L26
L27:
  mov    %rdx,%rax
L3:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm2
  jbe    L1
  subsd  %xmm0,%xmm1
  lea    -0x8(%rax),%rdx
  cmp    %rsi,%rax
  jne    L27
L26:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dasum(unsigned int n, const double *dx) {
  double sum = 0.0;
  do {
    --n;
    if (dx[n] < 0)
      sum = sum - dx[n];
    else
      sum = sum + dx[n];
  } while (n);
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<run_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  %xmm5,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x60(%rbp),%xmm4
  movsd  -0x58(%rbp),%xmm3
  movsd  -0x50(%rbp),%xmm2
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x6,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rdi
  movsd  -0x60(%rbp),%xmm4
  movsd  -0x58(%rbp),%xmm3
  movsd  -0x50(%rbp),%xmm2
  movsd  -0x48(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <circle_circle_intersection@plt>
  movsd  -0x10(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D18: x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :


tool: D5:   x3=%F, y3=%F, x3_prime=%F, y3_prime=%F


assistant: ```c
void run_test(double x0, double y0, double r0, double x1, double y1, double r1) {
  double x3, y3, x3_prime, y3_prime;
  printf("x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :\n", x0, y0, r0, x1, y1, r1);
  circle_circle_intersection(x0, y0, r0, x1, y1, r1, &x3, &y3, &x3_prime, &y3_prime);
  printf("  x3=%F, y3=%F, x3_prime=%F, y3_prime=%F\n", x3, y3, x3_prime, y3_prime);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<run_test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movq   %xmm2,%r12
  movq   %xmm3,%r13
  movq   %xmm4,%r14
  movq   %xmm5,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  mov    $0x6,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movq   %r15,%xmm5
  movq   %r14,%xmm4
  movq   %r13,%xmm3
  movq   %r12,%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <circle_circle_intersection@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  lea    D3(%rip),%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D6: x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :


tool: D3:   x3=%F, y3=%F, x3_prime=%F, y3_prime=%F


assistant: ```c
void run_test(double x0, double y0, double r0, double x1, double y1, double r1) {
  double x3, y3, x3_prime, y3_prime;
  printf("x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :\n", x0, y0, r0, x1, y1, r1);
  circle_circle_intersection(x0, y0, r0, x1, y1, r1, &x3, &y3, &x3_prime, &y3_prime);
  printf("  x3=%F, y3=%F, x3_prime=%F, y3_prime=%F\n", x3, y3, x3_prime, y3_prime);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<run_test>:
  endbr64
  sub    $0x68,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x6,%eax
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  lea    0x38(%rsp),%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  lea    0x50(%rsp),%rcx
  lea    0x48(%rsp),%rdx
  movsd  0x28(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm4
  lea    0x40(%rsp),%rsi
  call   <circle_circle_intersection@plt>
  movsd  0x50(%rsp),%xmm3
  mov    $0x4,%eax
  movsd  0x48(%rsp),%xmm2
  movsd  0x40(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm0
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x68,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D16: x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :


tool: D17:   x3=%F, y3=%F, x3_prime=%F, y3_prime=%F


assistant: ```c
void run_test(double x0, double y0, double r0, double x1, double y1, double r1) {
  double x3, y3, x3_prime, y3_prime;
  printf("x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :\n", x0, y0, r0, x1, y1, r1);
  circle_circle_intersection(x0, y0, r0, x1, y1, r1, &x3, &y3, &x3_prime, &y3_prime);
  printf("  x3=%F, y3=%F, x3_prime=%F, y3_prime=%F\n", x3, y3, x3_prime, y3_prime);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_test>:
  endbr64
  sub    $0x68,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x6,%eax
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  lea    0x38(%rsp),%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  lea    0x50(%rsp),%rcx
  lea    0x48(%rsp),%rdx
  movsd  0x28(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm4
  lea    0x40(%rsp),%rsi
  call   <circle_circle_intersection@plt>
  movsd  0x50(%rsp),%xmm3
  mov    $0x4,%eax
  movsd  0x48(%rsp),%xmm2
  movsd  0x40(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x68,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string

tool: D3: x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :


tool: D18:   x3=%F, y3=%F, x3_prime=%F, y3_prime=%F


assistant: ```c
void run_test(double x0, double y0, double r0, double x1, double y1, double r1) {
  double x3, y3, x3_prime, y3_prime;
  printf("x0=%F, y0=%F, r0=%F, x1=%F, y1=%F, r1=%F :\n", x0, y0, r0, x1, y1, r1);
  circle_circle_intersection(x0, y0, r0, x1, y1, r1, &x3, &y3, &x3_prime, &y3_prime);
  printf("  x3=%F, y3=%F, x3_prime=%F, y3_prime=%F\n", x3, y3, x3_prime, y3_prime);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gui_getk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gui_kbhit@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gui_getk() {
  int result;
  result = 0;
  if (gui_kbhit()) {
    result = getchar();
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gui_getk>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gui_kbhit@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L13
L19:
  add    $0x8,%rsp
  ret
L13:
  call   <getchar@plt>
  jmp    L19
```

assistant: ```c
int gui_getk() {
  int result;
  result = 0;
  if (gui_kbhit()) {
    result = getchar();
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gui_getk>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gui_kbhit@plt>
  test   %rax,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <getchar@plt>
```

assistant: ```c
int gui_getk() {
  int result;
  result = 0;
  if (gui_kbhit()) {
    result = getchar();
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gui_getk>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gui_kbhit@plt>
  test   %rax,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <getchar@plt>
```

assistant: ```c
int gui_getk() {
  int result;
  result = 0;
  if (gui_kbhit()) {
    result = getchar();
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<random_level>:
  endbr64
  push   %rbx
  call   <rand_r@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D0(%rip),%rax
  divsd  (%rax),%xmm0
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    $0x1f,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int random_level(unsigned int *seedp) {
  const double P = 0.5;
  int lvl = (int)(log(((double)rand_r(seedp) / RAND_MAX)) / log(1. - P));
  return lvl < (32 - 1) ? lvl : (32 - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_level>:
  endbr64
  push   %rbx
  call   <rand_r@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D9(%rip),%rax
  divsd  (%rax),%xmm0
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <log@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %r8d
  mov    $0x1f,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int random_level(unsigned int *seedp) {
  const double P = 0.5;
  int lvl = (int)(log(((double)rand_r(seedp) / RAND_MAX)) / log(1. - P));
  return lvl < (32 - 1) ? lvl : (32 - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<random_level>:
  endbr64
  push   %rbx
  call   <rand_r@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D9(%rip),%rax
  divsd  (%rax),%xmm0
  cvttsd2si %xmm0,%edi
  call   <log@plt>
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <log@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %r8d
  mov    $0x1f,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int random_level(unsigned int *seedp) {
  const double P = 0.5;
  int lvl = (int)(log(((double)rand_r(seedp) / RAND_MAX)) / log(1. - P));
  return lvl < (32 - 1) ? lvl : (32 - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<connected_mark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L28
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L18:
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <connected_mark>
L49:
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  jmp    L20
L28:
  nop
L20:
  leave
  ret
```

assistant: ```c
void connected_mark(char *mgph, int size, int *mark, int v) {
  if (mark[v])
    return;
  mark[v] = 1;
  for (int i = 0; i < size; i++) {
    if (mgph[v + size * i])
      connected_mark(mgph, size, mark, i);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<connected_mark>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %ecx,%rbx
  lea    (%rdx,%rbx,4),%rax
  mov    (%rax),%ebp
  test   %ebp,%ebp
  jne    L3
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %rdx,%r13
  movl   $0x1,(%rax)
  test   %esi,%esi
  jle    L3
  movslq %esi,%r15
  add    %rdi,%rbx
  jmp    L31
L42:
  add    $0x1,%ebp
  add    %r15,%rbx
  cmp    %ebp,%r12d
  je     L3
L31:
  cmpb   $0x0,(%rbx)
  je     L42
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <connected_mark>
  jmp    L42
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void connected_mark(char *mgph, int size, int *mark, int v) {
  if (mark[v])
    return;
  mark[v] = 1;
  for (int i = 0; i < size; i++) {
    if (mgph[v + size * i])
      connected_mark(mgph, size, mark, i);
  }
}
```