ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmdwait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  jne    L64
  mov    $0xffffffff,%eax
  jmp    L31
L64:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L25
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <WEXITSTATUS@plt>
  jmp    L31
L25:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <WIFSIGNALED@plt>
  test   %rax,%rax
  je     L60
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <WTERMSIG@plt>
  sub    $0xffffff80,%eax
  jmp    L31
L60:
  mov    $0x0,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int cmdwait(int pid) {
  int s;
  if (-1 == waitpid(pid, &s, 0))
    return -1;
  if (WIFEXITED(s))
    return WEXITSTATUS(s);
  else if (WIFSIGNALED(s))
    return (128 + WTERMSIG(s));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmdwait>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  je     L14
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  jne    L3
  mov    0x4(%rsp),%edi
  call   <WIFSIGNALED@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L5
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x18,%rsp
  ret
L3:
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
  jmp    L14
L5:
  mov    0x4(%rsp),%edi
  call   <WTERMSIG@plt>
  sub    $0xffffff80,%eax
  jmp    L14
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmdwait(int pid) {
  int s;
  if (-1 == waitpid(pid, &s, 0))
    return -1;
  if (WIFEXITED(s))
    return WEXITSTATUS(s);
  else if (WIFSIGNALED(s))
    return (128 + WTERMSIG(s));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmdwait>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  je     L41
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  mov    0x4(%rsp),%edi
  test   %rax,%rax
  jne    L55
  call   <WIFSIGNALED@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L21
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
  nop
L55:
  call   <WEXITSTATUS@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x4(%rsp),%edi
  call   <WTERMSIG@plt>
  sub    $0xffffff80,%eax
  jmp    L41
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmdwait(int pid) {
  int s;
  if (-1 == waitpid(pid, &s, 0))
    return -1;
  if (WIFEXITED(s))
    return WEXITSTATUS(s);
  else if (WIFSIGNALED(s))
    return (128 + WTERMSIG(s));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmdwait>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  je     L49
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  mov    0x4(%rsp),%edi
  test   %rax,%rax
  jne    L19
  call   <WIFSIGNALED@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L50
L49:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x18,%rsp
  ret
  nop
L19:
  call   <WEXITSTATUS@plt>
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L50:
  mov    0x4(%rsp),%edi
  call   <WTERMSIG@plt>
  sub    $0xffffff80,%eax
  jmp    L49
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cmdwait(int pid) {
  int s;
  if (-1 == waitpid(pid, &s, 0))
    return -1;
  if (WIFEXITED(s))
    return WEXITSTATUS(s);
  else if (WIFSIGNALED(s))
    return (128 + WTERMSIG(s));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DistInitVertexList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <AccessMarkVertexListFirst@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L12
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <AccessMarkVertexListFirst@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L12:
  leave
  ret
```

assistant: ```c
int DistInitVertexList(Schema, A, D)
struct frvStruct *Schema;
struct Vertex **A;
struct Mark *D;
{
  if (AccessMarkVertexListFirst(D) == 0)
    return (0);
  else
    (*A) = AccessMarkVertexListFirst(D);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DistInitVertexList>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <AccessMarkVertexListFirst@plt>
  test   %eax,%eax
  jne    L4
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <AccessMarkVertexListFirst@plt>
  cltq
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L1
```

assistant: ```c
int DistInitVertexList(Schema, A, D)
struct frvStruct *Schema;
struct Vertex **A;
struct Mark *D;
{
  if (AccessMarkVertexListFirst(D) == 0)
    return (0);
  else
    (*A) = AccessMarkVertexListFirst(D);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<DistInitVertexList>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rdi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <AccessMarkVertexListFirst@plt>
  test   %eax,%eax
  je     L6
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <AccessMarkVertexListFirst@plt>
  cltq
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DistInitVertexList(Schema, A, D)
struct frvStruct *Schema;
struct Vertex **A;
struct Mark *D;
{
  if (AccessMarkVertexListFirst(D) == 0)
    return (0);
  else
    (*A) = AccessMarkVertexListFirst(D);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DistInitVertexList>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rdi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <AccessMarkVertexListFirst@plt>
  test   %eax,%eax
  je     L4
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <AccessMarkVertexListFirst@plt>
  cltq
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DistInitVertexList(Schema, A, D)
struct frvStruct *Schema;
struct Vertex **A;
struct Mark *D;
{
  if (AccessMarkVertexListFirst(D) == 0)
    return (0);
  else
    (*A) = AccessMarkVertexListFirst(D);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uninitvar_iswdigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uninitvar_iswdigit(void) {
  wint_t i;
  (void)iswdigit(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninitvar_iswdigit>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_iswdigit(void) {
  wint_t i;
  (void)iswdigit(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uninitvar_iswdigit>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_iswdigit(void) {
  wint_t i;
  (void)iswdigit(i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uninitvar_iswdigit>:
  endbr64
  ret
```

assistant: ```c
void uninitvar_iswdigit(void) {
  wint_t i;
  (void)iswdigit(i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stream_read_frame_body>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fullread@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  je     L28
  cmpq   $0x0,-0x8(%rbp)
  jg     L15
  mov    $0x0,%eax
  jmp    L19
L15:
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L28:
  mov    $0x1,%eax
L19:
  leave
  ret
```

assistant: ```c
int stream_read_frame_body(struct reader *rds, unsigned char *buf, int size) {
  long l;
  if ((l = fullread(rds, buf, size)) != size) {
    if (l <= 0)
      return 0;
    memset(buf + l, 0, size - l);
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stream_read_frame_body>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <fullread@plt>
  movslq %ebx,%rcx
  mov    $0x1,%edx
  cmp    %rax,%rcx
  je     L15
  mov    $0x0,%edx
  test   %rax,%rax
  jle    L15
  sub    %eax,%ebx
  mov    %ebx,%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x1,%edx
L15:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int stream_read_frame_body(struct reader *rds, unsigned char *buf, int size) {
  long l;
  if ((l = fullread(rds, buf, size)) != size) {
    if (l <= 0)
      return 0;
    memset(buf + l, 0, size - l);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stream_read_frame_body>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fullread@plt>
  movslq %ebx,%rdx
  mov    $0x1,%r8d
  cmp    %rax,%rdx
  je     L4
  xor    %r8d,%r8d
  test   %rax,%rax
  jle    L4
  sub    %eax,%ebx
  lea    0x0(%rbp,%rax,1),%rdi
  xor    %esi,%esi
  mov    %ebx,%edx
  call   <memset@plt>
  mov    $0x1,%r8d
L4:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int stream_read_frame_body(struct reader *rds, unsigned char *buf, int size) {
  long l;
  if ((l = fullread(rds, buf, size)) != size) {
    if (l <= 0)
      return 0;
    memset(buf + l, 0, size - l);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stream_read_frame_body>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fullread@plt>
  movslq %ebx,%rdx
  mov    $0x1,%r8d
  cmp    %rax,%rdx
  je     L2
  xor    %r8d,%r8d
  test   %rax,%rax
  jle    L2
  sub    %eax,%ebx
  lea    0x0(%rbp,%rax,1),%rdi
  xor    %esi,%esi
  mov    %ebx,%edx
  call   <memset@plt>
  mov    $0x1,%r8d
L2:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int stream_read_frame_body(struct reader *rds, unsigned char *buf, int size) {
  long l;
  if ((l = fullread(rds, buf, size)) != size) {
    if (l <= 0)
      return 0;
    memset(buf + l, 0, size - l);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_mmap_ro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L67
  mov    $0x0,%eax
  jmp    L66
L67:
  lea    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L54
  mov    D20(%rip),%rax
  mov    (%rax),%ecx
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    -0x1c(%rbp),%esi
  mov    $0x0,%r9d
  mov    %esi,%r8d
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,-0x10(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  je     L35
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L66
L54:
  nop
  jmp    L36
L35:
  nop
L36:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
L66:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void *_mmap_ro(const char *filename, size_t *size) {
  int fd = open(filename, O_RDONLY);
  if (fd == -1)
    return NULL;
  struct stat st;
  if (fstat(fd, &st) == -1)
    goto err;
  void *ptr = mmap(NULL, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (ptr == MAP_FAILED)
    goto err;
  close(fd);
  *size = st.st_size;
  return ptr;
err:
  close(fd);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_mmap_ro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D31(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L43
  mov    %eax,%ebx
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    $0x0,%r9d
  mov    %ebx,%r8d
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    (%rsp),%rsi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,%rbp
  mov    D7(%rip),%rax
  cmp    %rbp,(%rax)
  je     L3
  mov    %ebx,%edi
  call   <close@plt>
  mov    (%rsp),%rax
  mov    %rax,(%r12)
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%ebp
  jmp    L11
L43:
  mov    $0x0,%ebp
  jmp    L11
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_mmap_ro(const char *filename, size_t *size) {
  int fd = open(filename, O_RDONLY);
  if (fd == -1)
    return NULL;
  struct stat st;
  if (fstat(fd, &st) == -1)
    goto err;
  void *ptr = mmap(NULL, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (ptr == MAP_FAILED)
    goto err;
  close(fd);
  *size = st.st_size;
  return ptr;
err:
  close(fd);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_mmap_ro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L28
  mov    %rsp,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L55
  mov    D22(%rip),%rax
  mov    (%rsp),%rsi
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %ebp,%r8d
  mov    (%rax),%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D6(%rip),%rax
  cmp    %r12,(%rax)
  je     L55
  mov    %ebp,%edi
  call   <close@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  mov    %ebp,%edi
  xor    %r12d,%r12d
  call   <close@plt>
  jmp    L21
  nopl   0x0(%rax)
L28:
  xor    %r12d,%r12d
  jmp    L21
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_mmap_ro(const char *filename, size_t *size) {
  int fd = open(filename, O_RDONLY);
  if (fd == -1)
    return NULL;
  struct stat st;
  if (fstat(fd, &st) == -1)
    goto err;
  void *ptr = mmap(NULL, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (ptr == MAP_FAILED)
    goto err;
  close(fd);
  *size = st.st_size;
  return ptr;
err:
  close(fd);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_mmap_ro>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  cmp    $0xffffffff,%eax
  je     L10
  mov    %rsp,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L50
  mov    D8(%rip),%rax
  mov    (%rsp),%rsi
  xor    %r9d,%r9d
  xor    %edi,%edi
  mov    %ebp,%r8d
  mov    (%rax),%ecx
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%r12
  mov    D34(%rip),%rax
  cmp    %r12,(%rax)
  je     L50
  mov    %ebp,%edi
  call   <close@plt>
  mov    (%rsp),%rax
  mov    %rax,(%rbx)
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L50:
  mov    %ebp,%edi
  xor    %r12d,%r12d
  call   <close@plt>
  jmp    L33
  nopl   0x0(%rax)
L10:
  xor    %r12d,%r12d
  jmp    L33
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_mmap_ro(const char *filename, size_t *size) {
  int fd = open(filename, O_RDONLY);
  if (fd == -1)
    return NULL;
  struct stat st;
  if (fstat(fd, &st) == -1)
    goto err;
  void *ptr = mmap(NULL, st.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (ptr == MAP_FAILED)
    goto err;
  close(fd);
  *size = st.st_size;
  return ptr;
err:
  close(fd);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__unordsf2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <toRep@plt>
  and    $0x7fffffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <toRep@plt>
  and    $0x7fffffff,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7f800000,-0x8(%rbp)
  ja     L10
  cmpl   $0x7f800000,-0x4(%rbp)
  jbe    L27
L10:
  mov    $0x1,%eax
  jmp    L11
L27:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int __unordsf2(float a, float b) {
  const unsigned aAbs = toRep(a) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  const unsigned bAbs = toRep(b) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  return aAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U)) || bAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__unordsf2>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <toRep@plt>
  mov    %eax,%ebx
  movss  0xc(%rsp),%xmm0
  call   <toRep@plt>
  and    $0x7fffffff,%ebx
  cmp    $0x7f800000,%ebx
  seta   %dl
  and    $0x7fffffff,%eax
  cmp    $0x7f800000,%eax
  seta   %al
  or     %eax,%edx
  movzbl %dl,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int __unordsf2(float a, float b) {
  const unsigned aAbs = toRep(a) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  const unsigned bAbs = toRep(b) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  return aAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U)) || bAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U));
}
```
user: Translate the below assembly code into C programming language:

```asm
<__unordsf2>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <toRep@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  and    $0x7fffffff,%ebx
  movaps %xmm1,%xmm0
  call   <toRep@plt>
  cmp    $0x7f800000,%ebx
  seta   %dl
  and    $0x7fffffff,%eax
  cmp    $0x7f800000,%eax
  seta   %al
  add    $0x10,%rsp
  or     %eax,%edx
  pop    %rbx
  movzbl %dl,%eax
  ret
```

assistant: ```c
int __unordsf2(float a, float b) {
  const unsigned aAbs = toRep(a) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  const unsigned bAbs = toRep(b) & (((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U);
  return aAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U)) || bAbs > ((((1) << (23 + ((sizeof(unsigned) * 8) - 23 - 1))) - 1U) ^ (((1) << 23) - 1U));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L25:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L30
  lea    D10(%rip),%rax
  jmp    L8
L30:
  lea    D5(%rip),%rax
L8:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D10:  

tool: 

tool: D3: %s%s

assistant: ```c
main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%s%s", argv[i], (i < argc - 1) ? " " : "");
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L6
  mov    %rsi,%r12
  mov    %edi,%r15d
  mov    $0x1,%ebx
  lea    -0x1(%rdi),%ebp
  lea    D5(%rip),%r14
  lea    D4(%rip),%r13
L19:
  cmp    %ebx,%ebp
  mov    %r13,%rdx
  cmovg  %r14,%rdx
  mov    (%r12,%rbx,8),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L19
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string

tool: D5:  

tool: 

tool: D10: %s%s

assistant: ```c
main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%s%s", argv[i], (i < argc - 1) ? " " : "");
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L10
  movslq %edi,%rax
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%r15d
  mov    $0x1,%ebx
  mov    %rax,0x8(%rsp)
  lea    D4(%rip),%r14
  lea    D27(%rip),%r13
  lea    D15(%rip),%r12
L3:
  cmp    %ebx,%r15d
  mov    %r12,%rdx
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r14,%rdi
  cmovle %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    0x8(%rsp),%rbx
  jne    L3
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D15
type: string

tool: D4: %s%s

tool: 

tool: D15:  

assistant: ```c
main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%s%s", argv[i], (i < argc - 1) ? " " : "");
  printf("\n");
  return 0;
}
```