ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_sentence>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movb   $0x0,-0x1(%rdi,%rbp,1)
  test   %rdx,%rdx
  je     L31
  mov    %rdx,%rsi
  call   <strstr@plt>
  mov    %rax,%r12
L28:
  test   %r12,%r12
  je     L37
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  lea    0x2(%rax),%rdx
  sub    %rbx,%rdx
  cmp    %rbp,%rdx
  jge    L2
  movb   $0x0,0x2(%rax)
L37:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%r12
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: 


assistant: ```c
char *find_sentence(char *buf, int bsz, const char *prfx) {
  char *bp = NULL, *ep = NULL;
  buf[bsz - 1] = '\0';
  if (prfx == NULL)
    bp = strstr(buf, "$");
  else
    bp = strstr(buf, prfx);
  if (bp == NULL)
    return NULL;
  ep = strstr(bp, "\r\n");
  if (ep == NULL)
    return NULL;
  if (ep + 2 - buf < bsz)
    ep[2] = '\0';
  else
    return NULL;
  return bp;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_sentence>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movb   $0x0,-0x1(%rdi,%rbp,1)
  test   %rdx,%rdx
  je     L12
  mov    %rdx,%rsi
  call   <strstr@plt>
  mov    %rax,%r12
L25:
  test   %r12,%r12
  je     L37
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  lea    0x2(%rax),%rdx
  sub    %rbx,%rdx
  cmp    %rbp,%rdx
  jge    L3
  movb   $0x0,0x2(%rax)
L37:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%r12
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: 


assistant: ```c
char *find_sentence(char *buf, int bsz, const char *prfx) {
  char *bp = NULL, *ep = NULL;
  buf[bsz - 1] = '\0';
  if (prfx == NULL)
    bp = strstr(buf, "$");
  else
    bp = strstr(buf, prfx);
  if (bp == NULL)
    return NULL;
  ep = strstr(bp, "\r\n");
  if (ep == NULL)
    return NULL;
  if (ep + 2 - buf < bsz)
    ep[2] = '\0';
  else
    return NULL;
  return bp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jik>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x58(%rbp),%rdx
  mov    %rdx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x20(%rbp)
  mov    %rdx,%r10
  mov    $0x0,%r11d
  mov    -0x58(%rbp),%rcx
  mov    %rcx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x18(%rbp)
  mov    %rcx,%r8
  mov    $0x0,%r9d
  movq   $0x0,-0x40(%rbp)
  jmp    L36
L58:
  movq   $0x0,-0x48(%rbp)
  jmp    L55
L42:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
  jmp    L27
L44:
  mov    %rax,%rsi
  imul   -0x48(%rbp),%rsi
  lea    0x0(,%rsi,8),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x38(%rbp),%rsi
  movsd  (%rdi,%rsi,8),%xmm1
  mov    %rdx,%rsi
  imul   -0x38(%rbp),%rsi
  lea    0x0(,%rsi,8),%rdi
  mov    -0x68(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%rsi
  movsd  (%rdi,%rsi,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  addq   $0x1,-0x38(%rbp)
L27:
  mov    -0x38(%rbp),%rsi
  cmp    -0x58(%rbp),%rsi
  jb     L44
  mov    %rcx,%rsi
  imul   -0x48(%rbp),%rsi
  lea    0x0(,%rsi,8),%rdi
  mov    -0x70(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x40(%rbp),%rsi
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rdi,%rsi,8)
  addq   $0x1,-0x48(%rbp)
L55:
  mov    -0x48(%rbp),%rsi
  cmp    -0x58(%rbp),%rsi
  jb     L42
  addq   $0x1,-0x40(%rbp)
L36:
  mov    -0x40(%rbp),%rsi
  cmp    -0x58(%rbp),%rsi
  jb     L58
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void jik(size_t n, double A[(n)][(n)], double B[(n)][(n)], double C[(n)][(n)]) {
  size_t i, j, k;
  double sum;
  for (j = 0; j < n; j++)
    for (i = 0; i < n; i++) {
      sum = 0.0;
      for (k = 0; k < n; k++)
        sum += A[i][k] * B[k][j];
      C[i][j] = sum;
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jik>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  lea    0x0(,%rdi,8),%rcx
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L24
L34:
  lea    0x1(%r13),%rax
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %rsi,%r13
  je     L3
  mov    %rax,%r13
L24:
  mov    %r12,%r10
  mov    %rbp,%r9
  mov    %r14,%r11
L2:
  mov    %r10,%rdi
  mov    %rbx,%rdx
  pxor   %xmm1,%xmm1
  mov    $0x0,%eax
L29:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  mov    %rax,%rsi
  add    $0x1,%rax
  add    %rcx,%rdx
  cmp    %rax,%r8
  jne    L29
  movsd  %xmm1,(%r9)
  lea    0x1(%r11),%rax
  add    %rcx,%r9
  add    %rcx,%r10
  cmp    %rsi,%r11
  je     L34
  mov    %rax,%r11
  jmp    L2
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

assistant: ```c
void jik(size_t n, double A[(n)][(n)], double B[(n)][(n)], double C[(n)][(n)]) {
  size_t i, j, k;
  double sum;
  for (j = 0; j < n; j++)
    for (i = 0; i < n; i++) {
      sum = 0.0;
      for (k = 0; k < n; k++)
        sum += A[i][k] * B[k][j];
      C[i][j] = sum;
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jik>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r12
  mov    %rdi,%r8
  mov    %rdx,%r11
  xor    %r12d,%r12d
  push   %rbp
  pxor   %xmm2,%xmm2
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x0(,%rdi,8),%rsi
  nopl   0x0(%rax)
L25:
  mov    %rbx,%rcx
  mov    %rbp,%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L9:
  mov    %r11,%rdx
  movapd %xmm2,%xmm1
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx),%xmm0
  mov    %rax,%rdi
  add    $0x1,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L8
  movsd  %xmm1,(%r10)
  lea    0x1(%r9),%rax
  add    %rsi,%r10
  add    %rsi,%rcx
  cmp    %rdi,%r9
  je     L58
  mov    %rax,%r9
  jmp    L9
  nopl   (%rax)
L58:
  lea    0x1(%r12),%rax
  add    $0x8,%r11
  add    $0x8,%rbp
  cmp    %r9,%r12
  je     L54
  mov    %rax,%r12
  jmp    L25
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  ret
```

assistant: ```c
void jik(size_t n, double A[(n)][(n)], double B[(n)][(n)], double C[(n)][(n)]) {
  size_t i, j, k;
  double sum;
  for (j = 0; j < n; j++)
    for (i = 0; i < n; i++) {
      sum = 0.0;
      for (k = 0; k < n; k++)
        sum += A[i][k] * B[k][j];
      C[i][j] = sum;
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jik>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %r12
  mov    %rdi,%r8
  mov    %rdx,%r11
  xor    %r12d,%r12d
  push   %rbp
  pxor   %xmm2,%xmm2
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x0(,%rdi,8),%rsi
  nopl   0x0(%rax)
L25:
  mov    %rbx,%rcx
  mov    %rbp,%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L18:
  mov    %r11,%rdx
  movapd %xmm2,%xmm1
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx),%xmm0
  mov    %rax,%rdi
  add    $0x1,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L7
  movsd  %xmm1,(%r10)
  lea    0x1(%r9),%rax
  add    %rsi,%r10
  add    %rsi,%rcx
  cmp    %rdi,%r9
  je     L33
  mov    %rax,%r9
  jmp    L18
  nopl   (%rax)
L33:
  lea    0x1(%r12),%rax
  add    $0x8,%r11
  add    $0x8,%rbp
  cmp    %r9,%r12
  je     L39
  mov    %rax,%r12
  jmp    L25
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void jik(size_t n, double A[(n)][(n)], double B[(n)][(n)], double C[(n)][(n)]) {
  size_t i, j, k;
  double sum;
  for (j = 0; j < n; j++)
    for (i = 0; i < n; i++) {
      sum = 0.0;
      for (k = 0; k < n; k++)
        sum += A[i][k] * B[k][j];
      C[i][j] = sum;
    }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invalid_acces_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: %c

assistant: ```c
void invalid_acces_function() {
  char *p = malloc(4);
  printf("%c", p[4]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<invalid_acces_function>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movsbl 0x4(%rax),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: %c

assistant: ```c
void invalid_acces_function() {
  char *p = malloc(4);
  printf("%c", p[4]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<invalid_acces_function>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D7(%rip),%rdi
  movsbl 0x4(%rax),%esi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: %c

assistant: ```c
void invalid_acces_function() {
  char *p = malloc(4);
  printf("%c", p[4]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<invalid_acces_function>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    D2(%rip),%rdi
  movsbl 0x4(%rax),%esi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %c

assistant: ```c
void invalid_acces_function() {
  char *p = malloc(4);
  printf("%c", p[4]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn_cl_1_33_35_4294967295>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <next_utf8@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L38
  cmpl   $0x21,-0xc(%rbp)
  ja     L38
  mov    -0x10(%rbp),%eax
  jmp    L39
L38:
  cmpl   $0x22,-0xc(%rbp)
  jbe    L44
  mov    -0x10(%rbp),%eax
  jmp    L39
L44:
  mov    $0xffffffff,%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int fn_cl_1_33_35_4294967295(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 1 && c <= 33)
    return pos;
  if (c >= 35 && c <= 4294967295)
    return pos;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fn_cl_1_33_35_4294967295>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <next_utf8@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x20,%edx
  jbe    L12
  cmp    $0x22,%eax
  mov    $0xffffffff,%eax
  cmova  0x4(%rsp),%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
L12:
  mov    0x4(%rsp),%eax
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_1_33_35_4294967295(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 1 && c <= 33)
    return pos;
  if (c >= 35 && c <= 4294967295)
    return pos;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fn_cl_1_33_35_4294967295>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x20,%edx
  jbe    L24
  cmp    $0x22,%eax
  jbe    L22
L24:
  mov    0x4(%rsp),%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
L22:
  mov    $0xffffffff,%eax
  jmp    L31
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_1_33_35_4294967295(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 1 && c <= 33)
    return pos;
  if (c >= 35 && c <= 4294967295)
    return pos;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fn_cl_1_33_35_4294967295>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <next_utf8@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x20,%edx
  jbe    L20
  cmp    $0x22,%eax
  jbe    L7
L20:
  mov    0x4(%rsp),%eax
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L33
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn_cl_1_33_35_4294967295(const char *text) {
  int pos = 0;
  unsigned int c = next_utf8(text, &pos);
  if (c >= 1 && c <= 33)
    return pos;
  if (c >= 35 && c <= 4294967295)
    return pos;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcf_enc_inttype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x7f,-0x8(%rbp)
  jg     L35
  cmpq   $0xffffffffffffff88,-0x8(%rbp)
  jl     L35
  mov    $0x1,%eax
  jmp    L3
L35:
  cmpq   $0x7fff,-0x8(%rbp)
  jg     L11
  cmpq   $0xffffffffffff8008,-0x8(%rbp)
  jl     L11
  mov    $0x2,%eax
  jmp    L3
L11:
  mov    $0x3,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int bcf_enc_inttype(long x) {
  if (x <= (0x7f) && x >= (-120))
    return 1;
  if (x <= (0x7fff) && x >= (-32760))
    return 2;
  return 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcf_enc_inttype>:
  endbr64
  lea    0x78(%rdi),%rdx
  mov    $0x1,%eax
  cmp    $0xf7,%rdx
  jbe    L8
  add    $0x7ff8,%rdi
  cmp    $0xfff7,%rdi
  seta   %al
  movzbl %al,%eax
  add    $0x2,%eax
L8:
  ret
```

assistant: ```c
int bcf_enc_inttype(long x) {
  if (x <= (0x7f) && x >= (-120))
    return 1;
  if (x <= (0x7fff) && x >= (-32760))
    return 2;
  return 3;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bcf_enc_inttype>:
  endbr64
  lea    0x78(%rdi),%rdx
  mov    $0x1,%eax
  cmp    $0xf7,%rdx
  jbe    L2
  add    $0x7ff8,%rdi
  xor    %eax,%eax
  cmp    $0xfff7,%rdi
  seta   %al
  add    $0x2,%eax
L2:
  ret
```

assistant: ```c
int bcf_enc_inttype(long x) {
  if (x <= (0x7f) && x >= (-120))
    return 1;
  if (x <= (0x7fff) && x >= (-32760))
    return 2;
  return 3;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bcf_enc_inttype>:
  endbr64
  lea    0x78(%rdi),%rdx
  mov    $0x1,%eax
  cmp    $0xf7,%rdx
  jbe    L9
  add    $0x7ff8,%rdi
  xor    %eax,%eax
  cmp    $0xfff7,%rdi
  seta   %al
  add    $0x2,%eax
L9:
  ret
```

assistant: ```c
int bcf_enc_inttype(long x) {
  if (x <= (0x7f) && x >= (-120))
    return 1;
  if (x <= (0x7fff) && x >= (-32760))
    return 2;
  return 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<split_host_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L12
L7:
  mov    -0x30(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L12:
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int split_host_port(char *input, int default_port, char **host, int *port) {
  char *p;
  *host = strdup(input);
  if ((p = strchr(*host, ':'))) {
    *port = strtol(p + 1, NULL, 0);
    *p = 0;
  } else {
    *port = default_port;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<split_host_port>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,0x0(%rbp)
  movb   $0x0,(%rbx)
L0:
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    %r12d,0x0(%rbp)
  jmp    L0
```

assistant: ```c
int split_host_port(char *input, int default_port, char **host, int *port) {
  char *p;
  *host = strdup(input);
  if ((p = strchr(*host, ':'))) {
    *port = strtol(p + 1, NULL, 0);
    *p = 0;
  } else {
    *port = default_port;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<split_host_port>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strdup@plt>
  mov    $0x3a,%esi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  lea    0x1(%rax),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rbx
  call   <strtol@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x1,%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,0x0(%rbp)
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int split_host_port(char *input, int default_port, char **host, int *port) {
  char *p;
  *host = strdup(input);
  if ((p = strchr(*host, ':'))) {
    *port = strtol(p + 1, NULL, 0);
    *p = 0;
  } else {
    *port = default_port;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split_host_port>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strdup@plt>
  mov    $0x3a,%esi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rax,%rbx
  call   <strtol@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x1,%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12d,0x0(%rbp)
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int split_host_port(char *input, int default_port, char **host, int *port) {
  char *p;
  *host = strdup(input);
  if ((p = strchr(*host, ':'))) {
    *port = strtol(p + 1, NULL, 0);
    *p = 0;
  } else {
    *port = default_port;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<duration_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <round@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xc8,0x3f]}

assistant: ```c
long long duration_get(long long on, long long off) {
  long long duration;
  double d;
  d = (float)(on - off);
  d *= (1.5 / 8.0);
  d = round(d);
  return ((long long)d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<duration_get>:
  endbr64
  sub    $0x8,%rsp
  sub    %rsi,%rdi
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D1(%rip),%xmm0
  call   <round@plt>
  cvttsd2si %xmm0,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xc8,0x3f]}

assistant: ```c
long long duration_get(long long on, long long off) {
  long long duration;
  double d;
  d = (float)(on - off);
  d *= (1.5 / 8.0);
  d = round(d);
  return ((long long)d);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<duration_get>:
  endbr64
  sub    %rsi,%rdi
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D5(%rip),%xmm0
  call   <round@plt>
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xc8,0x3f]}

assistant: ```c
long long duration_get(long long on, long long off) {
  long long duration;
  double d;
  d = (float)(on - off);
  d *= (1.5 / 8.0);
  d = round(d);
  return ((long long)d);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<duration_get>:
  endbr64
  sub    %rsi,%rdi
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D6(%rip),%xmm0
  call   <round@plt>
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xc8,0x3f]}

assistant: ```c
long long duration_get(long long on, long long off) {
  long long duration;
  double d;
  d = (float)(on - off);
  d *= (1.5 / 8.0);
  d = round(d);
  return ((long long)d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_sleep1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L2:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0xa,%edi
  call   <zcoroutine_sleep_millisecond@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: test_sleep1, 1s + 10ms 


assistant: ```c
void *test_sleep1(void *context) {
  while (1) {
    sleep(1);
    zcoroutine_sleep_millisecond(10);
    printf("test_sleep1, 1s + 10ms \n");
  }
  return context;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_sleep1>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
L8:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0xa,%edi
  call   <zcoroutine_sleep_millisecond@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: test_sleep1, 1s + 10ms 


assistant: ```c
void *test_sleep1(void *context) {
  while (1) {
    sleep(1);
    zcoroutine_sleep_millisecond(10);
    printf("test_sleep1, 1s + 10ms \n");
  }
  return context;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_sleep1>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0xa,%edi
  call   <zcoroutine_sleep_millisecond@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: test_sleep1, 1s + 10ms 


assistant: ```c
void *test_sleep1(void *context) {
  while (1) {
    sleep(1);
    zcoroutine_sleep_millisecond(10);
    printf("test_sleep1, 1s + 10ms \n");
  }
  return context;
}
```