ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  xor    $0x29be1cdb,%rax
  mov    %rax,%rdx
  mov    %rax,%rcx
  test   $0x10,%al
  je     L6
  test   $0x4,%al
  je     L10
  movabs $0xffffffffffffff,%rdi
  sar    $0x38,%rcx
  mov    %cl,%dh
  movzbl %ah,%ecx
  shl    $0x38,%rcx
  and    %rdi,%rdx
  movabs $0xffff00ffffffffff,%rdi
  or     %rcx,%rdx
  mov    %rax,%rcx
  shr    $0x18,%rax
  shr    $0x10,%rcx
  and    %rdi,%rdx
  and    $0xff0000,%eax
  and    $0xff,%ecx
  shl    $0x28,%rcx
  or     %rcx,%rdx
  mov    %rax,%rcx
  mov    %rdx,%rax
  and    $0xffffffffff00ffff,%rax
  or     %rcx,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
  nopl   (%rax)
L6:
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  mov    %rax,%rdx
  movzbl %al,%eax
  shl    $0x10,%rcx
  shl    $0x28,%rax
  sar    $0x38,%rcx
  mov    %cl,%dl
  movabs $0xffff00ffffffffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  char copy12;
  unsigned int copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 2UL) & 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy11;
        copy11 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy11;
        state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = copy12;
      }
    } else {
      state[0UL] >>= ((state[0UL] >> 2UL) & 7UL) | 1UL;
      copy13 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy13;
      copy13 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy13;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mkpath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L43
L44:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L22
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <do_mkdir@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2f,(%rax)
L22:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L43:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
L14:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L5
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <do_mkdir@plt>
  mov    %eax,-0x1c(%rbp)
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mkpath(const char *path, mode_t mode) {
  char *pp;
  char *sp;
  int status = 0;
  char *copypath = strdup(path);
  pp = copypath;
  while (status == 0 && (sp = strchr(pp, '/')) != 0) {
    if (sp != pp) {
      *sp = '\0';
      status = do_mkdir(copypath, mode);
      *sp = '/';
    }
    pp = sp + 1;
  }
  if (status == 0)
    status = do_mkdir(path, mode);
  free(copypath);
  return status;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mkpath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  call   <strdup@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  jmp    L18
L3:
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <do_mkdir@plt>
  mov    %eax,%r12d
L4:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  lea    0x1(%rbx),%rbp
L18:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  cmp    %rbp,%rbx
  je     L46
  movb   $0x0,(%rbx)
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <do_mkdir@plt>
  mov    %eax,%r12d
  movb   $0x2f,(%rbx)
  lea    0x1(%rbx),%rbp
  test   %eax,%eax
  je     L18
  jmp    L4
```

assistant: ```c
int mkpath(const char *path, mode_t mode) {
  char *pp;
  char *sp;
  int status = 0;
  char *copypath = strdup(path);
  pp = copypath;
  while (status == 0 && (sp = strchr(pp, '/')) != 0) {
    if (sp != pp) {
      *sp = '\0';
      status = do_mkdir(copypath, mode);
      *sp = '/';
    }
    pp = sp + 1;
  }
  if (status == 0)
    status = do_mkdir(path, mode);
  free(copypath);
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mkpath>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
  cmp    %rbp,%rbx
  je     L5
  movb   $0x0,(%rbx)
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    0x1(%rbx),%rbp
  call   <do_mkdir@plt>
  movb   $0x2f,(%rbx)
  mov    %eax,%r15d
  test   %eax,%eax
  je     L18
L22:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rbp
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <do_mkdir@plt>
  mov    %eax,%r15d
  jmp    L22
```

assistant: ```c
int mkpath(const char *path, mode_t mode) {
  char *pp;
  char *sp;
  int status = 0;
  char *copypath = strdup(path);
  pp = copypath;
  while (status == 0 && (sp = strchr(pp, '/')) != 0) {
    if (sp != pp) {
      *sp = '\0';
      status = do_mkdir(copypath, mode);
      *sp = '/';
    }
    pp = sp + 1;
  }
  if (status == 0)
    status = do_mkdir(path, mode);
  free(copypath);
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkpath>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L30:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L44
  cmp    %rbp,%rbx
  je     L10
  movb   $0x0,(%rbx)
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    0x1(%rbx),%rbp
  call   <do_mkdir@plt>
  movb   $0x2f,(%rbx)
  mov    %eax,%r15d
  test   %eax,%eax
  je     L30
L48:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rbp
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <do_mkdir@plt>
  mov    %eax,%r15d
  jmp    L48
```

assistant: ```c
int mkpath(const char *path, mode_t mode) {
  char *pp;
  char *sp;
  int status = 0;
  char *copypath = strdup(path);
  pp = copypath;
  while (status == 0 && (sp = strchr(pp, '/')) != 0) {
    if (sp != pp) {
      *sp = '\0';
      status = do_mkdir(copypath, mode);
      *sp = '/';
    }
    pp = sp + 1;
  }
  if (status == 0)
    status = do_mkdir(path, mode);
  free(copypath);
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8_iterate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x30(%rbp)
  jne    L67
  mov    -0x28(%rbp),%rax
  jmp    L30
L67:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <utf8_check_first@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L30
L45:
  cmpq   $0x1,-0x10(%rbp)
  jne    L91
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  jmp    L100
L91:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  ja     L88
  lea    -0x11(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <utf8_check_full@plt>
  test   %eax,%eax
  jne    L100
L88:
  mov    $0x0,%eax
  jmp    L30
L100:
  cmpq   $0x0,-0x38(%rbp)
  je     L109
  movzbl -0x11(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
L109:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

assistant: ```c
const char *utf8_iterate(const char *buffer, size_t bufsize, int32_t *codepoint) {
  size_t count;
  int32_t value;
  if (!bufsize)
    return buffer;
  count = utf8_check_first(buffer[0]);
  if (count <= 0)
    return NULL;
  if (count == 1)
    value = (unsigned char)buffer[0];
  else {
    if (count > bufsize || !utf8_check_full(buffer, count, &value))
      return NULL;
  }
  if (codepoint)
    *codepoint = value;
  return buffer + count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utf8_iterate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L25
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    %rsi,%rbp
  mov    %rdx,%r13
  movsbl (%rdi),%edi
  call   <utf8_check_first@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L75
  cmp    $0x1,%rax
  je     L22
  cmp    %rax,%rbp
  jb     L49
  lea    0x7(%rsp),%rdx
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <utf8_check_full@plt>
  test   %eax,%eax
  je     L39
L112:
  test   %r13,%r13
  je     L104
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%r13)
L104:
  add    %r12,%rbx
  jmp    L38
L22:
  movzbl (%rbx),%eax
  mov    %al,0x7(%rsp)
  jmp    L112
L75:
  mov    $0x0,%ebx
  jmp    L38
L49:
  mov    $0x0,%ebx
  jmp    L38
L39:
  mov    $0x0,%ebx
  jmp    L38
L106:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *utf8_iterate(const char *buffer, size_t bufsize, int32_t *codepoint) {
  size_t count;
  int32_t value;
  if (!bufsize)
    return buffer;
  count = utf8_check_first(buffer[0]);
  if (count <= 0)
    return NULL;
  if (count == 1)
    value = (unsigned char)buffer[0];
  else {
    if (count > bufsize || !utf8_check_full(buffer, count, &value))
      return NULL;
  }
  if (codepoint)
    *codepoint = value;
  return buffer + count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf8_iterate>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L29
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <utf8_check_first@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L14
  cmp    $0x1,%rax
  je     L6
  cmp    %rax,%rbx
  jb     L14
  lea    0x7(%rsp),%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <utf8_check_full@plt>
  test   %eax,%eax
  je     L14
L87:
  test   %rbp,%rbp
  je     L69
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%rbp)
L69:
  add    %r13,%r12
  jmp    L42
  nop
L14:
  xor    %r12d,%r12d
  jmp    L42
  nopl   (%rax)
L6:
  movzbl (%r12),%eax
  mov    %al,0x7(%rsp)
  jmp    L87
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *utf8_iterate(const char *buffer, size_t bufsize, int32_t *codepoint) {
  size_t count;
  int32_t value;
  if (!bufsize)
    return buffer;
  count = utf8_check_first(buffer[0]);
  if (count <= 0)
    return NULL;
  if (count == 1)
    value = (unsigned char)buffer[0];
  else {
    if (count > bufsize || !utf8_check_full(buffer, count, &value))
      return NULL;
  }
  if (codepoint)
    *codepoint = value;
  return buffer + count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utf8_iterate>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L43
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L43:
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <utf8_check_first@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L18
  cmp    $0x1,%rax
  je     L9
  cmp    %rax,%rbx
  jb     L18
  lea    0x7(%rsp),%rdx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <utf8_check_full@plt>
  test   %eax,%eax
  je     L18
L96:
  test   %rbp,%rbp
  je     L14
  movzbl 0x7(%rsp),%eax
  mov    %al,0x0(%rbp)
L14:
  add    %r13,%r12
  jmp    L23
  nop
L18:
  xor    %r12d,%r12d
  jmp    L23
  nopl   (%rax)
L9:
  movzbl (%r12),%eax
  mov    %al,0x7(%rsp)
  jmp    L96
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *utf8_iterate(const char *buffer, size_t bufsize, int32_t *codepoint) {
  size_t count;
  int32_t value;
  if (!bufsize)
    return buffer;
  count = utf8_check_first(buffer[0]);
  if (count <= 0)
    return NULL;
  if (count == 1)
    value = (unsigned char)buffer[0];
  else {
    if (count > bufsize || !utf8_check_full(buffer, count, &value))
      return NULL;
  }
  if (codepoint)
    *codepoint = value;
  return buffer + count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <time@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ctime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *date() {
  char *str, *ctime();
  long time(), nseconds;
  nseconds = time((long *)0);
  str = ctime(&nseconds);
  return (str);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<date>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *date() {
  char *str, *ctime();
  long time(), nseconds;
  nseconds = time((long *)0);
  str = ctime(&nseconds);
  return (str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<date>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *date() {
  char *str, *ctime();
  long time(), nseconds;
  nseconds = time((long *)0);
  str = ctime(&nseconds);
  return (str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<date>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <ctime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *date() {
  char *str, *ctime();
  long time(), nseconds;
  nseconds = time((long *)0);
  str = ctime(&nseconds);
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SysCtlClockGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400fb800,%eax
  mov    (%rax),%rax
  and    $0x3,%eax
  cmp    $0x3,%rax
  jne    L134
  mov    $0x400fb804,%eax
  mov    (%rax),%rax
  and    $0x7f,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    $0x400fb804,%eax
  mov    (%rax),%rax
  shr    $0x8,%rax
  and    $0x3,%eax
  cmp    $0x3,%rax
  je     L56
  cmp    $0x3,%rax
  ja     L173
  cmp    $0x1,%rax
  je     L76
  cmp    $0x2,%rax
  je     L3
  jmp    L173
L76:
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  add    %rax,-0x8(%rbp)
  jmp    L134
L3:
  mov    -0x8(%rbp),%rax
  shr    %rax
  add    %rax,-0x8(%rbp)
  jmp    L134
L56:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shr    $0x2,%rax
  add    %rax,-0x8(%rbp)
  jmp    L134
L173:
  nop
L134:
  mov    $0x400fb80c,%eax
  mov    (%rax),%rax
  and    $0x3,%eax
  cmp    $0x3,%rax
  je     L147
  cmp    $0x3,%rax
  ja     L197
  cmp    $0x1,%rax
  je     L145
  cmp    $0x2,%rax
  je     L67
  jmp    L197
L145:
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  jmp    L161
L67:
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L161
L147:
  mov    -0x8(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L161
L197:
  nop
L161:
  mov    $0x400fb810,%eax
  mov    (%rax),%rax
  and    $0x3,%eax
  cmp    $0x1,%rax
  je     L144
  cmp    $0x2,%rax
  je     L71
  jmp    L28
L144:
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L71:
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  nop
L28:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long SysCtlClockGet(unsigned long ulClockIn) {
  if (((*((volatile unsigned long *)(0x400FB800))) & (0x00000001 | 0x00000002)) == 3) {
    ulClockIn = ulClockIn * ((*((volatile unsigned long *)(0x400FB804))) & 0x0000007F);
    ulClockIn = ulClockIn / 2;
    switch (((*((volatile unsigned long *)(0x400FB804))) & 0x00000300) >> 8) {
    default:
    case 0:
      break;
    case 1:
      ulClockIn += ulClockIn / 4;
      break;
    case 2:
      ulClockIn += ulClockIn / 2;
      break;
    case 3:
      ulClockIn += (ulClockIn * 3) / 4;
      break;
    }
  }
  switch ((*((volatile unsigned long *)(0x400FB80C))) & 0x00000003) {
  default:
  case 0:
    break;
  case 1:
    ulClockIn /= 2;
    break;
  case 2:
    ulClockIn /= 4;
    break;
  case 3:
    ulClockIn /= 8;
    break;
  }
  switch ((*((volatile unsigned long *)(0x400FB810))) & 0x00000003) {
  default:
  case 0:
    break;
  case 1:
    ulClockIn /= 2;
    break;
  case 2:
    ulClockIn /= 4;
    break;
  }
  return ulClockIn;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SysCtlClockGet>:
  endbr64
  mov    %rdi,%rax
  mov    0x400fb800,%rdx
  and    $0x3,%edx
  cmp    $0x3,%rdx
  je     L64
L6:
  mov    0x400fb80c,%rdx
  and    $0x3,%edx
  cmp    $0x2,%rdx
  je     L43
  cmp    $0x3,%rdx
  je     L13
  mov    %rax,%rcx
  shr    %rcx
  cmp    $0x1,%rdx
  cmove  %rcx,%rax
L58:
  mov    0x400fb810,%rdx
  and    $0x3,%edx
  cmp    $0x1,%rdx
  je     L91
  mov    %rax,%rcx
  shr    $0x2,%rcx
  cmp    $0x2,%rdx
  cmove  %rcx,%rax
  ret
L64:
  mov    0x400fb804,%rdx
  and    $0x7f,%edx
  imul   %rdi,%rdx
  mov    %rdx,%rax
  shr    %rax
  mov    0x400fb804,%rcx
  shr    $0x8,%rcx
  and    $0x3,%ecx
  cmp    $0x2,%rcx
  je     L73
  cmp    $0x3,%rcx
  je     L5
  shr    $0x3,%rdx
  add    %rax,%rdx
  cmp    $0x1,%rcx
  cmove  %rdx,%rax
  jmp    L6
L73:
  shr    $0x2,%rdx
  add    %rdx,%rax
  jmp    L6
L5:
  lea    (%rax,%rax,2),%rdx
  shr    $0x2,%rdx
  add    %rdx,%rax
  jmp    L6
L43:
  shr    $0x2,%rax
  jmp    L58
L13:
  shr    $0x3,%rax
  jmp    L58
L91:
  shr    %rax
  ret
```

assistant: ```c
unsigned long SysCtlClockGet(unsigned long ulClockIn) {
  if (((*((volatile unsigned long *)(0x400FB800))) & (0x00000001 | 0x00000002)) == 3) {
    ulClockIn = ulClockIn * ((*((volatile unsigned long *)(0x400FB804))) & 0x0000007F);
    ulClockIn = ulClockIn / 2;
    switch (((*((volatile unsigned long *)(0x400FB804))) & 0x00000300) >> 8) {
    default:
    case 0:
      break;
    case 1:
      ulClockIn += ulClockIn / 4;
      break;
    case 2:
      ulClockIn += ulClockIn / 2;
      break;
    case 3:
      ulClockIn += (ulClockIn * 3) / 4;
      break;
    }
  }
  switch ((*((volatile unsigned long *)(0x400FB80C))) & 0x00000003) {
  default:
  case 0:
    break;
  case 1:
    ulClockIn /= 2;
    break;
  case 2:
    ulClockIn /= 4;
    break;
  case 3:
    ulClockIn /= 8;
    break;
  }
  switch ((*((volatile unsigned long *)(0x400FB810))) & 0x00000003) {
  default:
  case 0:
    break;
  case 1:
    ulClockIn /= 2;
    break;
  case 2:
    ulClockIn /= 4;
    break;
  }
  return ulClockIn;
}
```