ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<params__ten_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int params__ten_power(int power) {
  int value = 1;
  for (int i = 0; i < power; ++i) {
    value *= 10;
  }
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<params__ten_power>:
  endbr64
  test   %edi,%edi
  jle    L13
  mov    $0x0,%edx
  mov    $0x1,%eax
L14:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L14
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int params__ten_power(int power) {
  int value = 1;
  for (int i = 0; i < power; ++i) {
    value *= 10;
  }
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<params__ten_power>:
  endbr64
  test   %edi,%edi
  jle    L15
  xor    %edx,%edx
  mov    $0x1,%eax
  nop
L17:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %edx,%edi
  jne    L17
  ret
  nopl   (%rax)
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int params__ten_power(int power) {
  int value = 1;
  for (int i = 0; i < power; ++i) {
    value *= 10;
  }
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<params__ten_power>:
  endbr64
  test   %edi,%edi
  jle    L18
  cmp    $0x1,%edi
  je     L9
  movq   D3(%rip),%xmm0
  mov    %edi,%edx
  xor    %eax,%eax
  shr    %edx
  nopl   0x0(%rax,%rax,1)
L47:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L47
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%edx
  imul   %edx,%eax
  and    $0x1,%edi
  je     L36
L3:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L36:
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x1,%eax
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: byte[8]

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int params__ten_power(int power) {
  int value = 1;
  for (int i = 0; i < power; ++i) {
    value *= 10;
  }
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L18:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long sum1(char *array, int start_i, int end_i) {
  int i;
  long res = 0;
  for (i = start_i; i < end_i; i++) {
    res += *((long *)(array + i * 32));
  }
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum1>:
  endbr64
  cmp    %edx,%esi
  jge    L15
  mov    %esi,%eax
  shl    $0x5,%eax
  cltq
  add    %rdi,%rax
  sub    $0x1,%edx
  sub    %esi,%edx
  movslq %esi,%rsi
  add    %rsi,%rdx
  shl    $0x5,%rdx
  lea    0x20(%rdi,%rdx,1),%rcx
  mov    $0x0,%edx
L6:
  add    (%rax),%rdx
  add    $0x20,%rax
  cmp    %rcx,%rax
  jne    L6
L10:
  mov    %rdx,%rax
  ret
L15:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
long sum1(char *array, int start_i, int end_i) {
  int i;
  long res = 0;
  for (i = start_i; i < end_i; i++) {
    res += *((long *)(array + i * 32));
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum1>:
  endbr64
  cmp    %edx,%esi
  jge    L1
  sub    $0x1,%edx
  mov    %esi,%eax
  xor    %r8d,%r8d
  sub    %esi,%edx
  movslq %esi,%rsi
  shl    $0x5,%eax
  add    %rsi,%rdx
  cltq
  shl    $0x5,%rdx
  add    %rdi,%rax
  lea    0x20(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L7:
  add    (%rax),%r8
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L7
  mov    %r8,%rax
  ret
L1:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long sum1(char *array, int start_i, int end_i) {
  int i;
  long res = 0;
  for (i = start_i; i < end_i; i++) {
    res += *((long *)(array + i * 32));
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum1>:
  endbr64
  cmp    %edx,%esi
  jge    L1
  sub    $0x1,%edx
  mov    %esi,%eax
  xor    %r8d,%r8d
  sub    %esi,%edx
  movslq %esi,%rsi
  shl    $0x5,%eax
  add    %rsi,%rdx
  cltq
  shl    $0x5,%rdx
  add    %rdi,%rax
  lea    0x20(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L4:
  add    (%rax),%r8
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    %r8,%rax
  ret
L1:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long sum1(char *array, int start_i, int end_i) {
  int i;
  long res = 0;
  for (i = start_i; i < end_i; i++) {
    res += *((long *)(array + i * 32));
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1000,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 4096;
  if (argc > 1)
    n = atoi(argv[1]);
  foo(n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    $0x1000,%edi
  cmp    $0x1,%eax
  jg     L15
L19:
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L15:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L19
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 4096;
  if (argc > 1)
    n = atoi(argv[1]);
  foo(n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    $0x1000,%edi
  cmp    $0x1,%r8d
  jle    L8
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
L8:
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 4096;
  if (argc > 1)
    n = atoi(argv[1]);
  foo(n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    $0x1000,%edi
  cmp    $0x1,%r8d
  jle    L8
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
L8:
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 4096;
  if (argc > 1)
    n = atoi(argv[1]);
  foo(n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L102
L8:
  cmpb   $0x5c,-0xd(%rbp)
  jne    L113
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  cmp    $0x74,%eax
  je     L91
  cmp    $0x74,%eax
  jg     L7
  cmp    $0x30,%eax
  je     L78
  cmp    $0x6e,%eax
  jne    L7
  mov    -0x18(%rbp),%rax
  movb   $0xa,(%rax)
  jmp    L85
L91:
  mov    -0x18(%rbp),%rax
  movb   $0x9,(%rax)
  jmp    L85
L78:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L85
L7:
  mov    -0x18(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L85
L113:
  mov    -0x18(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
L85:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L102:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L8
  cmpl   $0x0,-0xc(%rbp)
  jne    L94
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <errx@plt>
L94:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: no delimiters specified

assistant: ```c
int tr(wchar_t *arg) {
  int cnt;
  wchar_t ch, *p;
  for (p = arg, cnt = 0; (ch = *p++); ++arg, ++cnt)
    if (ch == '\\')
      switch (ch = *p++) {
      case 'n':
        *arg = '\n';
        break;
      case 't':
        *arg = '\t';
        break;
      case '0':
        *arg = '\0';
        break;
      default:
        *arg = ch;
        break;
      }
    else
      *arg = ch;
  if (!cnt)
    errx(1, "no delimiters specified");
  return (cnt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  lea    0x1(%rdi),%rsi
  mov    %rdi,%rdx
  mov    $0x0,%ecx
  mov    $0xa,%r10d
  mov    $0x9,%r9d
  mov    $0x0,%r8d
  jmp    L36
L46:
  lea    0x2(%rdx),%rsi
  movzbl 0x1(%rdx),%eax
  cmp    $0x6e,%al
  je     L9
  cmp    $0x74,%al
  je     L90
  mov    %rsi,%rdx
  cmp    $0x30,%al
  je     L100
L20:
  mov    %al,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%ecx
  lea    0x1(%rdx),%rsi
  movzbl (%rdx),%eax
  test   %al,%al
  je     L37
L36:
  cmp    $0x5c,%al
  je     L46
  mov    %rsi,%rdx
  jmp    L20
L100:
  mov    %r8d,%eax
  jmp    L20
L9:
  mov    %rsi,%rdx
  mov    %r10d,%eax
  jmp    L20
L90:
  mov    %rsi,%rdx
  mov    %r9d,%eax
  jmp    L20
L37:
  test   %ecx,%ecx
  je     L11
  mov    %ecx,%eax
  ret
L11:
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  mov    $0x0,%ecx
  mov    %ecx,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: no delimiters specified

assistant: ```c
int tr(wchar_t *arg) {
  int cnt;
  wchar_t ch, *p;
  for (p = arg, cnt = 0; (ch = *p++); ++arg, ++cnt)
    if (ch == '\\')
      switch (ch = *p++) {
      case 'n':
        *arg = '\n';
        break;
      case 't':
        *arg = '\t';
        break;
      case '0':
        *arg = '\0';
        break;
      default:
        *arg = ch;
        break;
      }
    else
      *arg = ch;
  if (!cnt)
    errx(1, "no delimiters specified");
  return (cnt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
  lea    0x1(%rdi),%rcx
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rcx,%rdi
L85:
  mov    %al,(%rdx)
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  add    $0x1,%r8d
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L16
L4:
  cmp    $0x5c,%al
  jne    L15
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rcx
  mov    %rcx,%rdi
  cmp    $0x6e,%al
  je     L69
  cmp    $0x74,%al
  je     L78
  cmp    $0x30,%al
  jne    L85
  xor    %eax,%eax
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L78:
  mov    $0x9,%eax
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L69:
  mov    $0xa,%eax
  jmp    L85
  nop
L29:
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: no delimiters specified

assistant: ```c
int tr(wchar_t *arg) {
  int cnt;
  wchar_t ch, *p;
  for (p = arg, cnt = 0; (ch = *p++); ++arg, ++cnt)
    if (ch == '\\')
      switch (ch = *p++) {
      case 'n':
        *arg = '\n';
        break;
      case 't':
        *arg = '\t';
        break;
      case '0':
        *arg = '\0';
        break;
      default:
        *arg = ch;
        break;
      }
    else
      *arg = ch;
  if (!cnt)
    errx(1, "no delimiters specified");
  return (cnt);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  lea    0x1(%rdi),%rcx
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %rcx,%rdi
L98:
  mov    %al,(%rdx)
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  add    $0x1,%r8d
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L44
L15:
  cmp    $0x5c,%al
  jne    L55
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rcx
  mov    %rcx,%rdi
  cmp    $0x6e,%al
  je     L7
  cmp    $0x74,%al
  je     L27
  cmp    $0x30,%al
  jne    L98
  xor    %eax,%eax
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x9,%eax
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xa,%eax
  jmp    L98
  nop
L11:
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: no delimiters specified

assistant: ```c
int tr(wchar_t *arg) {
  int cnt;
  wchar_t ch, *p;
  for (p = arg, cnt = 0; (ch = *p++); ++arg, ++cnt)
    if (ch == '\\')
      switch (ch = *p++) {
      case 'n':
        *arg = '\n';
        break;
      case 't':
        *arg = '\t';
        break;
      case '0':
        *arg = '\0';
        break;
      default:
        *arg = ch;
        break;
      }
    else
      *arg = ch;
  if (!cnt)
    errx(1, "no delimiters specified");
  return (cnt);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fgetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L31
  mov    $0xffffffff,%eax
  jmp    L10
L31:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,D62(%rip)
  mov    D62(%rip),%rax
  test   %rax,%rax
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L10
L22:
  mov    D62(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,D73(%rip)
  mov    D73(%rip),%rdx
  mov    D62(%rip),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <chop@plt>
  mov    %rax,D9(%rip)
  mov    D9(%rip),%rax
L10:
  leave
  ret
```

assistant: ```c
int fgetline(FILE *inputstream, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(inputstream))
    return -1;
  buffptr = fgets(buffer, size, inputstream);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fgetline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L17
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <chop@plt>
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L6
L14:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int fgetline(FILE *inputstream, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(inputstream))
    return -1;
  buffptr = fgets(buffer, size, inputstream);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fgetline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <chop@plt>
L2:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int fgetline(FILE *inputstream, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(inputstream))
    return -1;
  buffptr = fgets(buffer, size, inputstream);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fgetline>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  call   <feof@plt>
  test   %rax,%rax
  jne    L15
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <fgets@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <chop@plt>
L27:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int fgetline(FILE *inputstream, size_t size, char *buffer) {
  static size_t len;
  static char *buffptr;
  if (feof(inputstream))
    return -1;
  buffptr = fgets(buffer, size, inputstream);
  if (buffptr == NULL)
    return -1;
  len = strlen(buffptr);
  len = chop(buffptr, len);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_mul_overflow_int_int_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  call   <overflowed@plt>
L11:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int test_mul_overflow_int_int_int(int x, int y) {
  int r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_mul_overflow_int_int_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L3
L27:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <overflowed@plt>
  jmp    L27
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_mul_overflow_int_int_int(int x, int y) {
  int r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_mul_overflow_int_int_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L1
L18:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L1:
  xor    %eax,%eax
  call   <overflowed@plt>
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_mul_overflow_int_int_int(int x, int y) {
  int r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_mul_overflow_int_int_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L1
L18:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
L1:
  xor    %eax,%eax
  call   <overflowed@plt>
  jmp    L18
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_mul_overflow_int_int_int(int x, int y) {
  int r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<nl_nid_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L17
  mov    $0x0,%eax
  call   <nl_oom@plt>
L17:
  mov    -0x10(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *nl_nid_addr(char *nid) {
  char *addr, *p;
  if (!(addr = strdup(nid)))
    nl_oom();
  if ((p = strchr(addr, '@')))
    *p = '\0';
  return addr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nl_nid_addr>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L5:
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
L7:
  mov    %rbx,%rax
  pop    %rbx
  ret
L28:
  mov    $0x0,%eax
  call   <nl_oom@plt>
  jmp    L5
```

assistant: ```c
char *nl_nid_addr(char *nid) {
  char *addr, *p;
  if (!(addr = strdup(nid)))
    nl_oom();
  if ((p = strchr(addr, '@')))
    *p = '\0';
  return addr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nl_nid_addr>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L2:
  mov    $0x40,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
L25:
  mov    %r12,%rax
  pop    %r12
  ret
L15:
  xor    %eax,%eax
  call   <nl_oom@plt>
  jmp    L2
```

assistant: ```c
char *nl_nid_addr(char *nid) {
  char *addr, *p;
  if (!(addr = strdup(nid)))
    nl_oom();
  if ((p = strchr(addr, '@')))
    *p = '\0';
  return addr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nl_nid_addr>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L14:
  mov    $0x40,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  movb   $0x0,(%rax)
L1:
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  xor    %eax,%eax
  call   <nl_oom@plt>
  jmp    L14
```

assistant: ```c
char *nl_nid_addr(char *nid) {
  char *addr, *p;
  if (!(addr = strdup(nid)))
    nl_oom();
  if ((p = strchr(addr, '@')))
    *p = '\0';
  return addr;
}
```