ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<iupStrFileMakeFileName>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L21
  mov    %rsi,%r15
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %rax,%rbp
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  lea    (%rax,%rbp,1),%r13d
  mov    %eax,0x8(%rsp)
  mov    %rax,%r12
  lea    0x2(%r13),%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  movslq %ebp,%rdi
  mov    0x8(%rsp),%r8d
  cmpb   $0x2f,-0x1(%rbx,%rdi,1)
  je     L37
  add    $0x1,%ebp
  movb   $0x2f,(%r14,%rdi,1)
  lea    0x0(%rbp,%r12,1),%r13d
  movslq %ebp,%rdi
L37:
  add    %r14,%rdi
  mov    %r8d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  movslq %r13d,%rax
  movb   $0x0,(%r14,%rax,1)
L17:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %r14d,%r14d
  jmp    L17
```

assistant: ```c
char *iupStrFileMakeFileName(const char *path, const char *title) {
  if (!path || !title)
    return NULL;
  else {
    int size_path = (int)strlen(path);
    int size_title = (int)strlen(title);
    char *file_name = malloc(size_path + size_title + 2);
    memcpy(file_name, path, size_path);
    if (path[size_path - 1] != '/') {
      file_name[size_path] = '/';
      size_path++;
    }
    memcpy(file_name + size_path, title, size_title);
    file_name[size_path + size_title] = 0;
    return file_name;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<iupStrFileMakeFileName>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%r15
  test   %rsi,%rsi
  je     L39
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %rax,%rbp
  mov    %eax,0xc(%rsp)
  call   <strlen@plt>
  lea    (%rax,%rbp,1),%r13d
  mov    %eax,0x8(%rsp)
  mov    %rax,%r12
  lea    0x2(%r13),%edi
  call   <malloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  movslq %ebp,%rdi
  mov    0x8(%rsp),%r8d
  cmpb   $0x2f,-0x1(%rbx,%rdi,1)
  je     L13
  add    $0x1,%ebp
  movb   $0x2f,(%r14,%rdi,1)
  lea    0x0(%rbp,%r12,1),%r13d
  movslq %ebp,%rdi
L13:
  add    %r14,%rdi
  mov    %r8d,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  movslq %r13d,%rax
  movb   $0x0,(%r14,%rax,1)
L18:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %r14d,%r14d
  jmp    L18
```

assistant: ```c
char *iupStrFileMakeFileName(const char *path, const char *title) {
  if (!path || !title)
    return NULL;
  else {
    int size_path = (int)strlen(path);
    int size_title = (int)strlen(title);
    char *file_name = malloc(size_path + size_title + 2);
    memcpy(file_name, path, size_path);
    if (path[size_path - 1] != '/') {
      file_name[size_path] = '/';
      size_path++;
    }
    memcpy(file_name + size_path, title, size_title);
    file_name[size_path + size_title] = 0;
    return file_name;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun_D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0xfd,-0xc(%rbp)
  jne    L54
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <nbits@plt>
  test   %eax,%eax
  jne    L23
  mov    $0xc,%eax
  jmp    L221
L23:
  mov    $0xfffffff3,%eax
  jmp    L221
L54:
  cmpl   $0xfc,-0xc(%rbp)
  jne    L308
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <nbits@plt>
  test   %eax,%eax
  jne    L103
  mov    $0xd,%eax
  jmp    L221
L103:
  mov    $0xfffffff2,%eax
  jmp    L221
L308:
  cmpl   $0xfe,-0xc(%rbp)
  jne    L272
  mov    -0x8(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <nbits@plt>
  cmp    $0x3,%eax
  je     L283
  cmp    $0x3,%eax
  jg     L272
  cmp    $0x2,%eax
  je     L60
  cmp    $0x2,%eax
  jg     L272
  test   %eax,%eax
  je     L130
  cmp    $0x1,%eax
  je     L113
  jmp    L272
L130:
  mov    $0xe,%eax
  jmp    L221
L113:
  mov    $0xfffffff1,%eax
  jmp    L221
L60:
  mov    $0xf,%eax
  jmp    L221
L283:
  mov    $0xfffffff0,%eax
  jmp    L221
L272:
  cmpl   $0xff,-0xc(%rbp)
  jne    L95
  mov    -0x8(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <nbits@plt>
  cmp    $0x7,%eax
  ja     L178
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x10,%eax
  jmp    L221
  mov    $0xffffffef,%eax
  jmp    L221
  mov    $0x11,%eax
  jmp    L221
  mov    $0xffffffee,%eax
  jmp    L221
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <_nbits@plt>
  test   %eax,%eax
  je     L105
  mov    $0xed,%eax
  jmp    L221
L105:
  mov    $0x12,%eax
  jmp    L221
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x12,%eax
  jmp    L221
L178:
  mov    $0xff,%eax
  jmp    L221
L95:
  mov    -0xc(%rbp),%eax
L221:
  leave
  ret
```

assistant: ```c
int fun_D(int *bitfill, int gkw) {
  if (gkw == 0xfd) {
    if (nbits(bitfill, 1) == 0)
      return 12;
    return -13;
  }
  if (gkw == 0xfc) {
    if (nbits(bitfill, 1) == 0)
      return 13;
    return -14;
  }
  if (gkw == 0xfe) {
    switch (nbits(bitfill, 2)) {
    case 0:
      return 14;
    case 1:
      return -15;
    case 2:
      return 15;
    case 3:
      return -16;
    }
  }
  if (gkw == 0xff) {
    switch (nbits(bitfill, 3)) {
    case 4:
      return 16;
    case 5:
      return -17;
    case 6:
      return 17;
    case 7:
      return -18;
    case 2:
      return _nbits(bitfill, 1) ? 0xed : 0x12;
    case 3:
      (*bitfill)--;
      return 18;
    }
    return 0xff;
  }
  return gkw;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fun_D>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  cmp    $0xfd,%esi
  je     L27
  mov    %esi,%ebx
  cmp    $0xfc,%esi
  je     L15
  cmp    $0xfe,%esi
  je     L115
  mov    %esi,%eax
  cmp    $0xff,%esi
  je     L4
L83:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    $0x1,%esi
  call   <nbits@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x19,%eax
  sub    $0xd,%eax
  jmp    L83
L15:
  mov    $0x1,%esi
  call   <nbits@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x1b,%eax
  sub    $0xe,%eax
  jmp    L83
L115:
  mov    $0x2,%esi
  call   <nbits@plt>
  mov    %eax,%edx
  cmp    $0x2,%eax
  je     L97
  jg     L46
  mov    $0xe,%eax
  test   %edx,%edx
  je     L83
  cmp    $0x1,%edx
  mov    $0xfffffff1,%eax
  cmovne %ebx,%eax
  jmp    L83
L46:
  cmp    $0x3,%eax
  mov    $0xfffffff0,%eax
  cmovne %ebx,%eax
  jmp    L83
L4:
  mov    $0x3,%esi
  call   <nbits@plt>
  cmp    $0x7,%eax
  ja     L132
  mov    %eax,%eax
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xffffffef,%eax
  jmp    L83
  mov    $0x11,%eax
  jmp    L83
  mov    $0xffffffee,%eax
  jmp    L83
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <_nbits@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x25,%al
  add    $0xed,%eax
  jmp    L83
  subl   $0x1,0x0(%rbp)
  mov    $0x12,%eax
  jmp    L83
L132:
  mov    %ebx,%eax
  jmp    L83
L97:
  mov    $0xf,%eax
  jmp    L83
  mov    $0x10,%eax
  jmp    L83
```

assistant: ```c
int fun_D(int *bitfill, int gkw) {
  if (gkw == 0xfd) {
    if (nbits(bitfill, 1) == 0)
      return 12;
    return -13;
  }
  if (gkw == 0xfc) {
    if (nbits(bitfill, 1) == 0)
      return 13;
    return -14;
  }
  if (gkw == 0xfe) {
    switch (nbits(bitfill, 2)) {
    case 0:
      return 14;
    case 1:
      return -15;
    case 2:
      return 15;
    case 3:
      return -16;
    }
  }
  if (gkw == 0xff) {
    switch (nbits(bitfill, 3)) {
    case 4:
      return 16;
    case 5:
      return -17;
    case 6:
      return 17;
    case 7:
      return -18;
    case 2:
      return _nbits(bitfill, 1) ? 0xed : 0x12;
    case 3:
      (*bitfill)--;
      return 18;
    }
    return 0xff;
  }
  return gkw;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read2LE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  shl    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int read2LE(FILE *fp) {
  unsigned int val;
  val = getc(fp);
  val |= getc(fp) << 8;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read2LE>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <getc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <getc@plt>
  shl    $0x8,%eax
  or     %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int read2LE(FILE *fp) {
  unsigned int val;
  val = getc(fp);
  val |= getc(fp) << 8;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read2LE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <getc@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int read2LE(FILE *fp) {
  unsigned int val;
  val = getc(fp);
  val |= getc(fp) << 8;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read2LE>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <getc@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int read2LE(FILE *fp) {
  unsigned int val;
  val = getc(fp);
  val |= getc(fp) << 8;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_device_xml>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  jmp    L20
L13:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D19: r

tool: D15: %s

assistant: ```c
void print_device_xml(const char *file_name) {
  FILE *xml_file;
  xml_file = fopen(file_name, "r");
  char line[1024];
  while (fgets(line, 1024, xml_file) != NULL) {
    printf("%s", line);
  }
  fclose(xml_file);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_device_xml>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D12(%rip),%rbp
  jmp    L22
L5:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L22:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D7: r

tool: D12: %s

assistant: ```c
void print_device_xml(const char *file_name) {
  FILE *xml_file;
  xml_file = fopen(file_name, "r");
  char line[1024];
  while (fgets(line, 1024, xml_file) != NULL) {
    printf("%s", line);
  }
  fclose(xml_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_device_xml>:
  endbr64
  push   %r12
  lea    D17(%rip),%rsi
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L17
  nopl   (%rax)
L0:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L17:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D10
type_guessed: string

tool: D17: r

tool: D10: %s

assistant: ```c
void print_device_xml(const char *file_name) {
  FILE *xml_file;
  xml_file = fopen(file_name, "r");
  char line[1024];
  while (fgets(line, 1024, xml_file) != NULL) {
    printf("%s", line);
  }
  fclose(xml_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_device_xml>:
  endbr64
  push   %r12
  lea    D15(%rip),%rsi
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L0
  nopl   (%rax)
L28:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L0:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L28
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D15: r

tool: D6: %s

assistant: ```c
void print_device_xml(const char *file_name) {
  FILE *xml_file;
  xml_file = fopen(file_name, "r");
  char line[1024];
  while (fgets(line, 1024, xml_file) != NULL) {
    printf("%s", line);
  }
  fclose(xml_file);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<normalize_3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void normalize_3d(double vector[3]) {
  double length;
  length = sqrt(vector[0] * vector[0] + vector[1] * vector[1] + vector[2] * vector[2]);
  vector[0] = vector[0] / length;
  vector[1] = vector[1] / length;
  vector[2] = vector[2] / length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<normalize_3d>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%r13
  mov    0x8(%rdi),%r12
  mov    0x10(%rdi),%rbp
  movq   %r13,%xmm0
  mulsd  %xmm0,%xmm0
  movq   %r12,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movq   %rbp,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L17
  sqrtsd %xmm0,%xmm0
L16:
  movq   %r13,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movq   %r12,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <sqrt@plt>
  jmp    L16
```

assistant: ```c
void normalize_3d(double vector[3]) {
  double length;
  length = sqrt(vector[0] * vector[0] + vector[1] * vector[1] + vector[2] * vector[2]);
  vector[0] = vector[0] / length;
  vector[1] = vector[1] / length;
  vector[2] = vector[2] / length;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normalize_3d>:
  endbr64
  sub    $0x28,%rsp
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm2
  movsd  0x10(%rdi),%xmm1
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm3,%xmm0
  addsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  pxor   %xmm4,%xmm4
  ucomisd %xmm0,%xmm4
  ja     L6
  sqrtsd %xmm0,%xmm0
L0:
  divsd  %xmm0,%xmm3
  divsd  %xmm0,%xmm2
  movsd  %xmm3,(%rdi)
  divsd  %xmm0,%xmm1
  movsd  %xmm2,0x8(%rdi)
  movsd  %xmm1,0x10(%rdi)
  add    $0x28,%rsp
  ret
L6:
  mov    %rdi,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  jmp    L0
```

assistant: ```c
void normalize_3d(double vector[3]) {
  double length;
  length = sqrt(vector[0] * vector[0] + vector[1] * vector[1] + vector[2] * vector[2]);
  vector[0] = vector[0] / length;
  vector[1] = vector[1] / length;
  vector[2] = vector[2] / length;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<normalize_3d>:
  endbr64
  sub    $0x28,%rsp
  movupd (%rdi),%xmm2
  movsd  (%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  %xmm0,%xmm0
  movapd %xmm2,%xmm4
  unpckhpd %xmm4,%xmm4
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  ucomisd %xmm0,%xmm3
  ja     L3
  sqrtsd %xmm0,%xmm0
L15:
  divsd  %xmm0,%xmm1
  movapd %xmm0,%xmm3
  unpcklpd %xmm3,%xmm3
  divpd  %xmm3,%xmm2
  movsd  %xmm1,0x10(%rdi)
  movups %xmm2,(%rdi)
  add    $0x28,%rsp
  ret
L3:
  mov    %rdi,0x18(%rsp)
  movaps %xmm2,(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rdi
  movapd (%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  jmp    L15
```

assistant: ```c
void normalize_3d(double vector[3]) {
  double length;
  length = sqrt(vector[0] * vector[0] + vector[1] * vector[1] + vector[2] * vector[2]);
  vector[0] = vector[0] / length;
  vector[1] = vector[1] / length;
  vector[2] = vector[2] / length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L28
  mov    -0x28(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x8(%rbp)
  jmp    L13
L12:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L13:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L12
  jmp    L20
L7:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L28:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L7
L20:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t len) {
  unsigned char *pd = dst;
  const unsigned char *ps = src;
  if (ps < pd) {
    for (pd += len, ps += len; len--;)
      *--pd = *--ps;
  } else {
    while (len--)
      *pd++ = *ps++;
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  ja     L10
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L41
L36:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L36
L35:
  ret
L41:
  ret
L10:
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L35
L39:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L39
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t len) {
  unsigned char *pd = dst;
  const unsigned char *ps = src;
  if (ps < pd) {
    for (pd += len, ps += len; len--;)
      *--pd = *--ps;
  } else {
    while (len--)
      *pd++ = *ps++;
  }
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%rcx
  cmp    %rsi,%rdi
  ja     L22
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L9
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L21
L37:
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  test   %rdx,%rdx
  je     L37
  nopl   (%rax)
L32:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L32
  ret
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, size_t len) {
  unsigned char *pd = dst;
  const unsigned char *ps = src;
  if (ps < pd) {
    for (pd += len, ps += len; len--;)
      *--pd = *--ps;
  } else {
    while (len--)
      *pd++ = *ps++;
  }
  return dst;
}
```