ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  jmp    L1
L95:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
L1:
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L95
  comisd D85(%rip),%xmm0
  jbe    L76
  pxor   %xmm3,%xmm3
  comisd %xmm0,%xmm3
  ja     L95
  comisd %xmm3,%xmm0
  ja     L95
  jmp    L1
L76:
  lea    0x10(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  jmp    L112
L90:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
L112:
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  ja     L90
  comisd D85(%rip),%xmm0
  jbe    L7
  pxor   %xmm4,%xmm4
  comisd %xmm0,%xmm4
  ja     L90
  comisd %xmm4,%xmm0
  ja     L90
  jmp    L112
L7:
  addsd  0x8(%rsp),%xmm0
  mulsd  D90(%rip),%xmm0
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D32
data_type: string
name: extract_symbolic_data
arguments: data_label: D85
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D90
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D28
data_type: string

tool: D34: %lf

tool: D32: nota invalida

tool: {"D85": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D90": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D28: media = %.2lf


assistant: ```c
main() {
  double a, b;
  scanf("%lf", &a);
  while (a < 0 || a > 10) {
    if (a < 0 || a > 0) {
      printf("nota invalida\n");
      scanf("%lf", &a);
    }
  }
  scanf("%lf", &b);
  while (b < 0 || b > 10) {
    if (b < 0 || b > 0) {
      printf("nota invalida\n");
      scanf("%lf", &b);
    }
  }
  printf("media = %.2lf\n", (a + b) / 2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D71(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L43:
  comisd %xmm0,%xmm1
  ja     L0
  comisd D54(%rip),%xmm0
  jbe    L95
L84:
  comisd %xmm1,%xmm0
  jbe    L43
L0:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L0
  comisd D54(%rip),%xmm0
  ja     L84
L95:
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rdi
  lea    D7(%rip),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L29:
  comisd %xmm0,%xmm1
  ja     L70
  comisd D54(%rip),%xmm0
  jbe    L59
L85:
  comisd %xmm1,%xmm0
  jbe    L29
L70:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L70
  comisd D54(%rip),%xmm0
  ja     L85
L59:
  addsd  0x8(%rsp),%xmm0
  mulsd  D65(%rip),%xmm0
  mov    $0x1,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D71
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D54
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D65
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string

tool: D7: nota invalida

tool: D71: %lf

tool: {"D54": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D11: media = %.2lf


assistant: ```c
main() {
  double a, b;
  scanf("%lf", &a);
  while (a < 0 || a > 10) {
    if (a < 0 || a > 0) {
      printf("nota invalida\n");
      scanf("%lf", &a);
    }
  }
  scanf("%lf", &b);
  while (b < 0 || b > 10) {
    if (b < 0 || b > 0) {
      printf("nota invalida\n");
      scanf("%lf", &b);
    }
  }
  printf("media = %.2lf\n", (a + b) / 2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D71(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L13:
  comisd %xmm0,%xmm1
  ja     L84
  comisd D70(%rip),%xmm0
  jbe    L3
L32:
  comisd %xmm1,%xmm0
  jbe    L13
L84:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L84
  comisd D70(%rip),%xmm0
  ja     L32
L3:
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rdi
  lea    D71(%rip),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L15:
  comisd %xmm0,%xmm1
  ja     L50
  comisd D70(%rip),%xmm0
  jbe    L7
L105:
  comisd %xmm1,%xmm0
  jbe    L15
L50:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L50
  comisd D70(%rip),%xmm0
  ja     L105
L7:
  addsd  0x8(%rsp),%xmm0
  mulsd  D42(%rip),%xmm0
  mov    $0x1,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D71
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D70
type_infered: byte[16]
name: parse_data
arguments: tag: D42
type_infered: byte[8]
name: parse_data
arguments: tag: D10
type_infered: string

tool: D71: nota invalida

tool: D2: %lf

tool: {"D70": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D10: media = %.2lf


assistant: ```c
main() {
  double a, b;
  scanf("%lf", &a);
  while (a < 0 || a > 10) {
    if (a < 0 || a > 0) {
      printf("nota invalida\n");
      scanf("%lf", &a);
    }
  }
  scanf("%lf", &b);
  while (b < 0 || b > 10) {
    if (b < 0 || b > 0) {
      printf("nota invalida\n");
      scanf("%lf", &b);
    }
  }
  printf("media = %.2lf\n", (a + b) / 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L0
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L23:
  mov    -0x18(%rbp),%rax
  xor    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  addq   $0x7ff,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L23
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  xor    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  jmp    L25
L0:
  nop
L25:
  leave
  ret
```

assistant: ```c
void mem_init(unsigned char *ptr, unsigned long size) {
  unsigned long i, j;
  if (size == 0)
    return;
  memset(ptr, '\0', size);
  for (i = 0; i < size; i += 2047) {
    j = (unsigned long)ptr ^ i;
    ptr[i] = ((j ^ (j >> 8)) & 0xFF);
  }
  j = (unsigned long)ptr ^ (size - 1);
  ptr[size - 1] = ((j ^ (j >> 8)) & 0xFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mem_init>:
  endbr64
  test   %rsi,%rsi
  jne    L9
  ret
L9:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%eax
L2:
  mov    %rbx,%rcx
  xor    %rax,%rcx
  mov    %rcx,%rdx
  shr    $0x8,%rdx
  xor    %ecx,%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x7ff,%rax
  cmp    %rax,%rbp
  ja     L2
  lea    -0x1(%rbp),%rax
  xor    %rbx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  xor    %edx,%eax
  mov    %al,-0x1(%rbx,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mem_init(unsigned char *ptr, unsigned long size) {
  unsigned long i, j;
  if (size == 0)
    return;
  memset(ptr, '\0', size);
  for (i = 0; i < size; i += 2047) {
    j = (unsigned long)ptr ^ i;
    ptr[i] = ((j ^ (j >> 8)) & 0xFF);
  }
  j = (unsigned long)ptr ^ (size - 1);
  ptr[size - 1] = ((j ^ (j >> 8)) & 0xFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mem_init>:
  endbr64
  test   %rsi,%rsi
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  push   %rbp
  mov    %rsi,%rdx
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rcx
  xor    %rax,%rcx
  mov    %rcx,%rdx
  shr    $0x8,%rdx
  xor    %ecx,%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x7ff,%rax
  cmp    %rax,%rbp
  ja     L5
  lea    -0x1(%rbp),%rax
  xor    %rbx,%rax
  mov    %rax,%rdx
  shr    $0x8,%rdx
  xor    %edx,%eax
  mov    %al,-0x1(%rbx,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mem_init(unsigned char *ptr, unsigned long size) {
  unsigned long i, j;
  if (size == 0)
    return;
  memset(ptr, '\0', size);
  for (i = 0; i < size; i += 2047) {
    j = (unsigned long)ptr ^ i;
    ptr[i] = ((j ^ (j >> 8)) & 0xFF);
  }
  j = (unsigned long)ptr ^ (size - 1);
  ptr[size - 1] = ((j ^ (j >> 8)) & 0xFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L82
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L10
  mov    D36(%rip),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L54
  jmp    L82
L54:
  mov    D36(%rip),%rax
  mov    (%rax),%rdx
  mov    D32(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L61
  mov    $0xffffffff,%eax
  jmp    L78
L10:
  cmpl   $0x0,-0x14(%rbp)
  je     L5
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
L82:
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  jmp    L85
L61:
  nop
  jmp    L85
L5:
  nop
L85:
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L78:
  leave
  ret
```

assistant: ```c
ssize_t readn(int fd, void *vptr, size_t n) {
  char *ptr;
  size_t nleft;
  ssize_t nread;
  nleft = n;
  ptr = vptr;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EAGAIN)
        break;
      else
        return (-1);
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (n - nleft);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L81
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L49
L46:
  mov    D23(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D18(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L34
  mov    D29(%rip),%rcx
  cmp    (%rcx),%rdx
  jne    L45
L35:
  mov    %r13d,%eax
  sub    %ebx,%eax
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  test   %rbx,%rbx
  je     L35
L49:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L46
  test   %eax,%eax
  je     L35
  cltq
  sub    %rax,%rbx
  add    %rax,%rbp
  jmp    L34
L81:
  mov    %rdx,%rbx
  jmp    L35
```

assistant: ```c
ssize_t readn(int fd, void *vptr, size_t n) {
  char *ptr;
  size_t nleft;
  ssize_t nread;
  nleft = n;
  ptr = vptr;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EAGAIN)
        break;
      else
        return (-1);
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (n - nleft);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readn>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L9
L45:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L23
  test   %eax,%eax
  je     L55
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  jne    L45
L9:
  xor    %ebx,%ebx
  jmp    L55
  nopl   0x0(%rax)
L23:
  mov    D12(%rip),%rdx
  mov    D24(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L45
  mov    D0(%rip),%rcx
  cmp    (%rcx),%rdx
  jne    L6
L55:
  mov    %ebp,%eax
  sub    %ebx,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(int fd, void *vptr, size_t n) {
  char *ptr;
  size_t nleft;
  ssize_t nread;
  nleft = n;
  ptr = vptr;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EAGAIN)
        break;
      else
        return (-1);
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (n - nleft);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readn>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L10
L0:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L57
  test   %eax,%eax
  je     L63
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  jne    L0
L10:
  xor    %ebx,%ebx
  jmp    L63
  nopl   0x0(%rax)
L57:
  mov    D20(%rip),%rdx
  mov    D1(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L0
  mov    D9(%rip),%rcx
  cmp    (%rcx),%rdx
  jne    L3
L63:
  mov    %ebp,%eax
  sub    %ebx,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(int fd, void *vptr, size_t n) {
  char *ptr;
  size_t nleft;
  ssize_t nread;
  nleft = n;
  ptr = vptr;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EAGAIN)
        break;
      else
        return (-1);
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return (n - nleft);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  cmpq   $0x0,-0x20(%rbp)
  je     L15
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L57:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L81
L62:
  addq   $0x1,-0x8(%rbp)
L81:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  jmp    L91
L23:
  nop
L91:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L4
L15:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
size_t strcspn(const char *cs, const char *ct) {
  const char *s1, *s2;
  if (cs && ct) {
    for (s1 = cs; *s1; s1++) {
      for (s2 = ct; (*s2 != *s1) && *s2; s2++) {
      };
      if (*s2) {
        break;
      }
    }
    return ((size_t)(s1 - cs));
  } else {
    return (0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L51
  movzbl (%rsi),%r9d
  test   %r9b,%r9b
  setne  %r10b
  mov    %rdi,%rax
  jmp    L6
L60:
  mov    %r9d,%ecx
L3:
  test   %cl,%cl
  jne    L80
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  je     L80
L6:
  cmp    %r8b,%r9b
  je     L60
  mov    %rsi,%rdx
  test   %r10b,%r10b
  je     L60
L12:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L3
  cmp    %r8b,%cl
  jne    L12
  jmp    L3
L51:
  mov    %rdi,%rax
L80:
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strcspn(const char *cs, const char *ct) {
  const char *s1, *s2;
  if (cs && ct) {
    for (s1 = cs; *s1; s1++) {
      for (s2 = ct; (*s2 != *s1) && *s2; s2++) {
      };
      if (*s2) {
        break;
      }
    }
    return ((size_t)(s1 - cs));
  } else {
    return (0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L16
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  nopl   0x0(%rax)
L7:
  cmp    %r8b,%r9b
  je     L22
  mov    %rsi,%rcx
  mov    %r9d,%edx
  jmp    L39
  nopl   (%rax)
L26:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  cmp    %r8b,%dl
  je     L22
L39:
  test   %dl,%dl
  jne    L26
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L7
L22:
  sub    %rdi,%rax
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strcspn(const char *cs, const char *ct) {
  const char *s1, *s2;
  if (cs && ct) {
    for (s1 = cs; *s1; s1++) {
      for (s2 = ct; (*s2 != *s1) && *s2; s2++) {
      };
      if (*s2) {
        break;
      }
    }
    return ((size_t)(s1 - cs));
  } else {
    return (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcspn>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L23
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  nopl   0x0(%rax)
L35:
  cmp    %r8b,%r9b
  je     L7
  mov    %rsi,%rcx
  mov    %r9d,%edx
  jmp    L55
  nopl   (%rax)
L58:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  cmp    %r8b,%dl
  je     L7
L55:
  test   %dl,%dl
  jne    L58
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L35
L7:
  sub    %rdi,%rax
  ret
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strcspn(const char *cs, const char *ct) {
  const char *s1, *s2;
  if (cs && ct) {
    for (s1 = cs; *s1; s1++) {
      for (s2 = ct; (*s2 != *s1) && *s2; s2++) {
      };
      if (*s2) {
        break;
      }
    }
    return ((size_t)(s1 - cs));
  } else {
    return (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n = (!m);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n = (!m);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n = (!m);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n = (!m);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf0,%esi
  mov    $0x10,%edi
  call   <main1@plt>
  mov    $0xd2,%esi
  mov    $0xf,%edi
  call   <main1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  main1(16, 240);
  main1(16 - 1, 210);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%esi
  mov    $0x10,%edi
  call   <main1@plt>
  mov    $0xd2,%esi
  mov    $0xf,%edi
  call   <main1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  main1(16, 240);
  main1(16 - 1, 210);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%esi
  mov    $0x10,%edi
  call   <main1@plt>
  mov    $0xd2,%esi
  mov    $0xf,%edi
  call   <main1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  main1(16, 240);
  main1(16 - 1, 210);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0,%esi
  mov    $0x10,%edi
  call   <main1@plt>
  mov    $0xd2,%esi
  mov    $0xf,%edi
  call   <main1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  main1(16, 240);
  main1(16 - 1, 210);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sc_cleanup_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void sc_cleanup_string(char **ptr) {
  if (ptr != NULL) {
    free(*ptr);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sc_cleanup_string>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void sc_cleanup_string(char **ptr) {
  if (ptr != NULL) {
    free(*ptr);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sc_cleanup_string>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    (%rdi),%rdi
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void sc_cleanup_string(char **ptr) {
  if (ptr != NULL) {
    free(*ptr);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sc_cleanup_string>:
  endbr64
  test   %rdi,%rdi
  je     L1
  mov    (%rdi),%rdi
  jmp    1050 <free@plt>
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void sc_cleanup_string(char **ptr) {
  if (ptr != NULL) {
    free(*ptr);
  }
}
```