ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<gcCollect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L45
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L45
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L25
  cmpq   $0x0,(%rdi)
  je     L25
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L32:
  add    $0x1,%rbx
  cmpq   $0x0,(%rdi,%rbx,8)
  lea    0x0(,%rbx,8),%r12
  jne    L32
  lea    0x10(%r12),%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L61
L5:
  mov    %rax,0x0(%rbp)
  mov    %r13,(%rax,%r12,1)
  mov    0x0(%rbp),%rax
  movq   $0x0,0x8(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x10,%esi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  call   <realloc@plt>
  test   %rax,%rax
  jne    L5
L61:
  mov    0x0(%rbp),%rax
  mov    (%rax,%r12,1),%rdi
  call   <free@plt>
  mov    0x0(%rbp),%rax
  movq   $0x0,(%rax,%r12,1)
  mov    D30(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gcCollect(void ***gc, void *ptr) {
  if (gc == NULL || ptr == NULL) {
    errno = EINVAL;
    return;
  }
  size_t len_ptr = sizeof(void *);
  size_t i = 0;
  if (*gc) {
    while ((*gc)[i]) {
      i++;
    }
  }
  void **t = (void **)realloc(*gc, len_ptr * (i + 2));
  if (!t) {
    free((*gc)[i]);
    (*gc)[i] = NULL;
    errno = ENOMEM;
    return;
  }
  *gc = t;
  (*gc)[i] = ptr;
  (*gc)[i + 1] = NULL;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gcCollect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L21
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L46
  cmpq   $0x0,(%rdi)
  je     L46
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
  cmpq   $0x0,(%rdi,%rbx,8)
  lea    0x0(,%rbx,8),%r12
  jne    L4
  lea    0x10(%r12),%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L12
L0:
  mov    %rax,0x0(%rbp)
  mov    %r13,(%rax,%r12,1)
  mov    0x0(%rbp),%rax
  movq   $0x0,0x8(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0x10,%esi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  call   <realloc@plt>
  test   %rax,%rax
  jne    L0
L12:
  mov    0x0(%rbp),%rax
  mov    (%rax,%r12,1),%rdi
  call   <free@plt>
  mov    0x0(%rbp),%rax
  movq   $0x0,(%rax,%r12,1)
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D38(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D38(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void gcCollect(void ***gc, void *ptr) {
  if (gc == NULL || ptr == NULL) {
    errno = EINVAL;
    return;
  }
  size_t len_ptr = sizeof(void *);
  size_t i = 0;
  if (*gc) {
    while ((*gc)[i]) {
      i++;
    }
  }
  void **t = (void **)realloc(*gc, len_ptr * (i + 2));
  if (!t) {
    free((*gc)[i]);
    (*gc)[i] = NULL;
    errno = ENOMEM;
    return;
  }
  *gc = t;
  (*gc)[i] = ptr;
  (*gc)[i + 1] = NULL;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<process_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <process_token@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: string

tool: D16:  

assistant: ```c
void process_line(char *thisline) {
  char *next_token;
  next_token = strtok(thisline, " ");
  do {
    process_token(next_token);
  } while ((next_token = strtok(NULL, " ")) != NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_line>:
  endbr64
  push   %rbx
  lea    D16(%rip),%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  lea    D16(%rip),%rbx
L3:
  call   <process_token@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L3
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string

tool: D16:  

assistant: ```c
void process_line(char *thisline) {
  char *next_token;
  next_token = strtok(thisline, " ");
  do {
    process_token(next_token);
  } while ((next_token = strtok(NULL, " ")) != NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<process_line>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  nopw   0x0(%rax,%rax,1)
L6:
  call   <process_token@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L6
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5:  

assistant: ```c
void process_line(char *thisline) {
  char *next_token;
  next_token = strtok(thisline, " ");
  do {
    process_token(next_token);
  } while ((next_token = strtok(NULL, " ")) != NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<process_line>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  call   <process_token@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L5
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4:  

assistant: ```c
void process_line(char *thisline) {
  char *next_token;
  next_token = strtok(thisline, " ");
  do {
    process_token(next_token);
  } while ((next_token = strtok(NULL, " ")) != NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binary>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%edx
  lea    D28(%rip),%rsi
  lea    D77(%rip),%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movzbl D77(%rip),%esi
  test   %sil,%sil
  je     L4
  lea    D77(%rip),%rbx
  lea    D35(%rip),%rbp
  lea    D75(%rip),%r14
  mov    %rbx,%r13
  lea    D55(%rip),%r12
L19:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  sub    %rbp,%rax
  cltq
  lea    (%rax,%rax,4),%rsi
  add    %r14,%rsi
  mov    %rbx,%rax
  sub    %r13,%rax
  lea    (%r12,%rax,4),%rdi
  call   <strcpy@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L19
L4:
  mov    $0x31,%esi
  lea    D55(%rip),%rdi
  call   <strchr@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D75
type_guessed: string

tool: D28: %x

tool: D35: 0123456789abcdef

tool: D75: 0000

assistant: ```c
const char *binary(int value) {
  static const char binnums[16][5] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
  static const char *hexnums = "0123456789abcdef";
  static char inbuffer[16], outbuffer[4 * 16];
  const char *i;
  sprintf(inbuffer, "%x", value);
  for (i = inbuffer; *i != 0; ++i) {
    int d = strchr(hexnums, *i) - hexnums;
    char *o = outbuffer + (i - inbuffer) * 4;
    sprintf(o, "%s", binnums[d]);
  }
  return strchr(outbuffer, '1');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary>:
  endbr64
  push   %r14
  mov    %edi,%edx
  lea    D15(%rip),%rsi
  xor    %eax,%eax
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  call   <sprintf@plt>
  movsbl D31(%rip),%esi
  test   %sil,%sil
  je     L2
  mov    %r12,%rbx
  lea    D53(%rip),%rbp
  lea    D39(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <strchr@plt>
  sub    %rbp,%rax
  cltq
  lea    (%rax,%rax,4),%rsi
  mov    %rbx,%rax
  add    $0x1,%rbx
  sub    %r12,%rax
  add    %r14,%rsi
  lea    0x0(%r13,%rax,4),%rdi
  call   <strcpy@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L3
L2:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x31,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <strchr@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D53
type_guessed: string
name: unpack_data
arguments: data_label: D39
type_guessed: string

tool: D15: %x

tool: D53: 0123456789abcdef

tool: D39: 0000

assistant: ```c
const char *binary(int value) {
  static const char binnums[16][5] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
  static const char *hexnums = "0123456789abcdef";
  static char inbuffer[16], outbuffer[4 * 16];
  const char *i;
  sprintf(inbuffer, "%x", value);
  for (i = inbuffer; *i != 0; ++i) {
    int d = strchr(hexnums, *i) - hexnums;
    char *o = outbuffer + (i - inbuffer) * 4;
    sprintf(o, "%s", binnums[d]);
  }
  return strchr(outbuffer, '1');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary>:
  endbr64
  push   %r14
  mov    %edi,%edx
  lea    D45(%rip),%rsi
  xor    %eax,%eax
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  call   <sprintf@plt>
  movsbl D44(%rip),%esi
  test   %sil,%sil
  je     L10
  mov    %r12,%rbx
  lea    D56(%rip),%rbp
  lea    D27(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <strchr@plt>
  sub    %rbp,%rax
  cltq
  lea    (%rax,%rax,4),%rsi
  mov    %rbx,%rax
  add    $0x1,%rbx
  sub    %r12,%rax
  add    %r14,%rsi
  lea    0x0(%r13,%rax,4),%rdi
  call   <strcpy@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L5
L10:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  mov    $0x31,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <strchr@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D45
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string

tool: D45: %x

tool: D56: 0123456789abcdef

tool: D27: 0000

assistant: ```c
const char *binary(int value) {
  static const char binnums[16][5] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
  static const char *hexnums = "0123456789abcdef";
  static char inbuffer[16], outbuffer[4 * 16];
  const char *i;
  sprintf(inbuffer, "%x", value);
  for (i = inbuffer; *i != 0; ++i) {
    int d = strchr(hexnums, *i) - hexnums;
    char *o = outbuffer + (i - inbuffer) * 4;
    sprintf(o, "%s", binnums[d]);
  }
  return strchr(outbuffer, '1');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L19
L3:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
L19:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *bp++ = *ap;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insw>:
  endbr64
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
L19:
  add    $0x2,%rsi
  movzwl (%rdi),%eax
  mov    %ax,-0x2(%rsi)
  cmp    %rdx,%rsi
  jne    L19
L15:
  ret
```

assistant: ```c
void insw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *bp++ = *ap;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insw>:
  endbr64
  test   %edx,%edx
  je     L6
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
  xchg   %ax,%ax
L13:
  movzwl (%rdi),%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  cmp    %rdx,%rsi
  jne    L13
L6:
  ret
```

assistant: ```c
void insw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *bp++ = *ap;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insw>:
  endbr64
  test   %edx,%edx
  je     L0
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
  xchg   %ax,%ax
L4:
  movzwl (%rdi),%eax
  add    $0x2,%rsi
  mov    %ax,-0x2(%rsi)
  cmp    %rdx,%rsi
  jne    L4
L0:
  ret
```

assistant: ```c
void insw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *bp++ = *ap;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BLK>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L1:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void BLK(n) int n;
{
  int i = 1;
  while (i <= n) {
    printf(" ");
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BLK>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1,%ebx
L2:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  ret
```

assistant: ```c
void BLK(n) int n;
{
  int i = 1;
  while (i <= n) {
    printf(" ");
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BLK>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void BLK(n) int n;
{
  int i = 1;
  while (i <= n) {
    printf(" ");
    i++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<BLK>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L8:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
void BLK(n) int n;
{
  int i = 1;
  while (i <= n) {
    printf(" ");
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rotateR_fun_int16_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x4(%rbp),%eax
  jmp    L6
L11:
  mov    $0x10,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x7fff,%edx
  mov    %edx,%edi
  mov    %eax,%ecx
  sar    %cl,%edi
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    %edi,%eax
  or     %esi,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int16_t rotateR_fun_int16_t(int16_t x, int32_t i) {
  if ((i %= 16) == 0)
    return x;
  return (x << (16 - i)) | ((0x7fff >> (i - 1)) & (x >> i));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rotateR_fun_int16_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  test   $0xf,%sil
  je     L1
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rsi,%rax,1),%edi
  and    $0xf,%edi
  sub    %eax,%edi
  lea    -0x1(%rdi),%ecx
  mov    $0x7fff,%eax
  sar    %cl,%eax
  and    $0xf,%esi
  mov    %edx,%r8d
  mov    %esi,%ecx
  sar    %cl,%r8d
  and    %r8d,%eax
  mov    $0x10,%ecx
  sub    %edi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
L1:
  ret
```

assistant: ```c
int16_t rotateR_fun_int16_t(int16_t x, int32_t i) {
  if ((i %= 16) == 0)
    return x;
  return (x << (16 - i)) | ((0x7fff >> (i - 1)) & (x >> i));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotateR_fun_int16_t>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  and    $0xf,%edi
  je     L2
  mov    %esi,%edx
  mov    %eax,%r8d
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  add    %edx,%esi
  and    $0xf,%esi
  sub    %edx,%esi
  mov    $0x7fff,%edx
  lea    -0x1(%rsi),%ecx
  sar    %cl,%edx
  mov    %edi,%ecx
  sar    %cl,%r8d
  mov    $0x10,%ecx
  sub    %esi,%ecx
  and    %r8d,%edx
  shl    %cl,%eax
  or     %edx,%eax
L2:
  ret
```

assistant: ```c
int16_t rotateR_fun_int16_t(int16_t x, int32_t i) {
  if ((i %= 16) == 0)
    return x;
  return (x << (16 - i)) | ((0x7fff >> (i - 1)) & (x >> i));
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotateR_fun_int16_t>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  and    $0xf,%edi
  je     L7
  mov    %esi,%edx
  mov    %eax,%r8d
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  add    %edx,%esi
  and    $0xf,%esi
  sub    %edx,%esi
  mov    $0x7fff,%edx
  lea    -0x1(%rsi),%ecx
  sar    %cl,%edx
  mov    %edi,%ecx
  sar    %cl,%r8d
  mov    $0x10,%ecx
  sub    %esi,%ecx
  and    %r8d,%edx
  shl    %cl,%eax
  or     %edx,%eax
L7:
  ret
```

assistant: ```c
int16_t rotateR_fun_int16_t(int16_t x, int32_t i) {
  if ((i %= 16) == 0)
    return x;
  return (x << (16 - i)) | ((0x7fff >> (i - 1)) & (x >> i));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x12c,-0x8(%rbp)
  movl   $0x14,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L17
L5:
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <ftoc@plt>
  movq   %xmm0,%rdx
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
L17:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x8(%rbp),%xmm0
  comiss -0x10(%rbp),%xmm0
  jae    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D5: Fahr Celsius

tool: D18: %3.0f %6.1f


assistant: ```c
main() {
  float fahr;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("Fahr Celsius\n");
  while (fahr <= upper) {
    printf("%3.0f %6.1f\n", fahr, ftoc(fahr));
    fahr = fahr + step;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%ebx
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  lea    D18(%rip),%rbp
L1:
  movss  0xc(%rsp),%xmm0
  call   <ftoc@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  D22(%rip),%xmm3
  addss  0xc(%rsp),%xmm3
  movss  %xmm3,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D22
type: byte[4]

tool: D16: Fahr Celsius

tool: D18: %3.0f %6.1f


tool: {"D22": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("Fahr Celsius\n");
  while (fahr <= upper) {
    printf("%3.0f %6.1f\n", fahr, ftoc(fahr));
    fahr = fahr + step;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D29(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L0:
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <ftoc@plt>
  movss  0xc(%rsp),%xmm2
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D11(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: byte[4]

tool: D13: Fahr Celsius

tool: D29: %3.0f %6.1f


tool: {"D11": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("Fahr Celsius\n");
  while (fahr <= upper) {
    printf("%3.0f %6.1f\n", fahr, ftoc(fahr));
    fahr = fahr + step;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L9:
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <ftoc@plt>
  movss  0xc(%rsp),%xmm2
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D2(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: byte[4]

tool: D3: Fahr Celsius

tool: D16: %3.0f %6.1f


tool: {"D2": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  printf("Fahr Celsius\n");
  while (fahr <= upper) {
    printf("%3.0f %6.1f\n", fahr, ftoc(fahr));
    fahr = fahr + step;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mov_reg32_imm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xb8,%eax
  mov    %eax,%edi
  call   <put8@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void mov_reg32_imm32(int reg32, unsigned long imm32) {
  put8(0xB8 + reg32);
  put32(imm32);
}
```