ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<max_profit_stock_2>:
  endbr64
  cmp    $0x1,%esi
  jle    L16
  lea    -0x2(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rsi
  nopl   0x0(%rax)
L17:
  mov    0x4(%rdi),%ecx
  mov    (%rdi),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  add    %r8d,%eax
  cmp    %edx,%ecx
  cmovg  %eax,%r8d
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L17
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int max_profit_stock_2(int *prices, int prices_size) {
  int max_profit = 0, i;
  for (i = 1; i < prices_size; ++i) {
    if (prices[i] > prices[i - 1]) {
      max_profit += prices[i] - prices[i - 1];
    }
  }
  return max_profit;
}
```
user: What is the c source code of the assembly code below:

```asm
<max_profit_stock_2>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L78
  lea    -0x2(%rsi),%eax
  lea    -0x1(%rsi),%edi
  cmp    $0x2,%eax
  jbe    L23
  mov    %edi,%esi
  mov    %rdx,%rax
  pxor   %xmm1,%xmm1
  shr    $0x2,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L89:
  movdqu 0x4(%rax),%xmm0
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  movdqa %xmm0,%xmm2
  pcmpgtd %xmm3,%xmm0
  psubd  %xmm3,%xmm2
  pand   %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L89
  movdqa %xmm1,%xmm0
  mov    %edi,%r8d
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%r8d
  paddd  %xmm0,%xmm1
  lea    0x1(%r8),%esi
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%edi
  je     L12
L61:
  movslq %esi,%r8
  lea    0x1(%rsi),%r10d
  shl    $0x2,%r8
  lea    (%rdx,%r8,1),%r9
  cmp    %edi,%r10d
  jge    L13
  cmp    %esi,%ecx
  jle    L13
  mov    -0x4(%r9),%r11d
  mov    (%r9),%r9d
  mov    %r9d,%r10d
  sub    %r11d,%r10d
  add    %eax,%r10d
  cmp    %r9d,%r11d
  cmovl  %r10d,%eax
  mov    0x4(%rdx,%r8,1),%r10d
  mov    %r10d,%r11d
  sub    %r9d,%r11d
  add    %eax,%r11d
  cmp    %r10d,%r9d
  lea    0x2(%rsi),%r9d
  cmovl  %r11d,%eax
  lea    0x3(%rsi),%r11d
  cmp    %r11d,%edi
  jg     L77
L9:
  movslq %r9d,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdx,%rsi,4),%esi
  mov    -0x4(%rdx,%r8,1),%r10d
  mov    %esi,%edi
  sub    %r10d,%edi
  add    %eax,%edi
  cmp    %r10d,%esi
  cmovg  %edi,%eax
  lea    0x1(%r9),%edi
  cmp    %edi,%ecx
  jle    L44
  mov    0x4(%rdx,%r8,1),%edi
  mov    %edi,%r10d
  sub    %esi,%r10d
  add    %eax,%r10d
  cmp    %edi,%esi
  cmovl  %r10d,%eax
  add    $0x2,%r9d
  cmp    %r9d,%ecx
  jle    L44
  mov    0x8(%rdx,%r8,1),%ecx
  mov    %ecx,%edx
  sub    %edi,%edx
  add    %eax,%edx
  cmp    %ecx,%edi
  cmovl  %edx,%eax
  ret
  nop
L77:
  mov    0x8(%rdx,%r8,1),%r9d
  mov    %r9d,%r11d
  sub    %r10d,%r11d
  add    %eax,%r11d
  cmp    %r9d,%r10d
  mov    0xc(%rdx,%r8,1),%r10d
  cmovl  %r11d,%eax
  mov    %r10d,%r11d
  sub    %r9d,%r11d
  add    %eax,%r11d
  cmp    %r10d,%r9d
  lea    0x4(%rsi),%r9d
  cmovl  %r11d,%eax
  lea    0x5(%rsi),%r11d
  cmp    %r11d,%edi
  jle    L9
  mov    0x10(%rdx,%r8,1),%edi
  mov    %edi,%r9d
  sub    %r10d,%r9d
  add    %eax,%r9d
  cmp    %r10d,%edi
  cmovg  %r9d,%eax
  mov    0x14(%rdx,%r8,1),%r9d
  mov    %r9d,%r8d
  sub    %edi,%r8d
  add    %eax,%r8d
  cmp    %r9d,%edi
  lea    0x6(%rsi),%r9d
  cmovl  %r8d,%eax
  jmp    L9
  xchg   %ax,%ax
L78:
  xor    %eax,%eax
L44:
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
L23:
  mov    $0x1,%esi
  xor    %eax,%eax
  jmp    L61
L13:
  mov    %esi,%r9d
  jmp    L9
```

assistant: ```c
int max_profit_stock_2(int *prices, int prices_size) {
  int max_profit = 0, i;
  for (i = 1; i < prices_size; ++i) {
    if (prices[i] > prices[i - 1]) {
      max_profit += prices[i] - prices[i - 1];
    }
  }
  return max_profit;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bswap_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) __attribute__((const)) uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bswap_32>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%edi
  and    $0xff00ff00,%edi
  sar    $0x8,%eax
  and    $0xff00ff,%eax
  or     %eax,%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  shl    $0x10,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
__attribute__((always_)) __attribute__((const)) uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bswap_32>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%edi
  sar    $0x8,%eax
  and    $0xff00ff00,%edi
  and    $0xff00ff,%eax
  or     %eax,%edi
  mov    %edi,%eax
  shl    $0x10,%edi
  sar    $0x10,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
__attribute__((always_)) __attribute__((const)) uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bswap_32>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%edi
  sar    $0x8,%eax
  and    $0xff00ff00,%edi
  and    $0xff00ff,%eax
  or     %eax,%edi
  mov    %edi,%eax
  shl    $0x10,%edi
  sar    $0x10,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
__attribute__((always_)) __attribute__((const)) uint32_t bswap_32(uint32_t x) {
  x = ((x << 8) & 0xFF00FF00) | ((x >> 8) & 0x00FF00FF);
  x = (x >> 16) | (x << 16);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ismedium>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x6a,-0x4(%rbp)
  jle    L29
  cmpb   $0x71,-0x4(%rbp)
  jg     L29
  mov    $0x1,%eax
  jmp    L21
L29:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int ismedium(char c) {
  if (c > 'j' && c <= 'q')
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ismedium>:
  endbr64
  sub    $0x6b,%edi
  cmp    $0x6,%dil
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ismedium(char c) {
  if (c > 'j' && c <= 'q')
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ismedium>:
  endbr64
  sub    $0x6b,%edi
  xor    %eax,%eax
  cmp    $0x6,%dil
  setbe  %al
  ret
```

assistant: ```c
int ismedium(char c) {
  if (c > 'j' && c <= 'q')
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ismedium>:
  endbr64
  sub    $0x6b,%edi
  xor    %eax,%eax
  cmp    $0x6,%dil
  setbe  %al
  ret
```

assistant: ```c
int ismedium(char c) {
  if (c > 'j' && c <= 'q')
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CG_NSEcho_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <trap_Args@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <CG_Printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: %s


assistant: ```c
void CG_NSEcho_f(void) {
  char message[256];
  trap_Args(message, sizeof(message));
  CG_Printf("%s\n", message);
}
```
user: What is the c source code of the assembly code below?

```asm
<CG_NSEcho_f>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <trap_Args@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <CG_Printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x110,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %s


assistant: ```c
void CG_NSEcho_f(void) {
  char message[256];
  trap_Args(message, sizeof(message));
  CG_Printf("%s\n", message);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CG_NSEcho_f>:
  endbr64
  push   %rbp
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <trap_Args@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <CG_Printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x110,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: %s


assistant: ```c
void CG_NSEcho_f(void) {
  char message[256];
  trap_Args(message, sizeof(message));
  CG_Printf("%s\n", message);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CG_NSEcho_f>:
  endbr64
  push   %rbp
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <trap_Args@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <CG_Printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: %s


assistant: ```c
void CG_NSEcho_f(void) {
  char message[256];
  trap_Args(message, sizeof(message));
  CG_Printf("%s\n", message);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ordiso>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  shl    $0x3,%rax
  lea    0x8(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L34:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L19
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L19:
  mov    %rsp,%rax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%ebx
  jmp    L51
L2:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  add    $0x1,%rbx
  addq   $0x8,-0x28(%rbp)
  addq   $0x8,-0x38(%rbp)
L51:
  cmp    -0x40(%rbp),%rbx
  jl     L2
  jmp    L50
L87:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L1
  mov    $0x0,%eax
  jmp    L67
L1:
  subq   $0x1,-0x40(%rbp)
  addq   $0x8,-0x20(%rbp)
L50:
  cmpq   $0x1,-0x40(%rbp)
  jg     L87
  mov    $0x1,%eax
L67:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int ordiso(const long *u, const long *v, const long *m, long len) {
  register long i;
  long *w = alloca(len * sizeof(*w));
  for (i = 0; i < len; i++, u++, m++)
    w[*u] = v[*m];
  for (; len > 1; len--, w++) {
    if (*w > *(w + 1))
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ordiso>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x17(,%rcx,8),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L58:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L58
L1:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L6
  orq    $0x0,-0x8(%rsp,%rax,1)
L6:
  lea    0xf(%rsp),%rdx
  and    $0xfffffffffffffff0,%rdx
  test   %rcx,%rcx
  jle    L9
  mov    $0x0,%eax
L47:
  mov    (%r8,%rax,8),%rsi
  mov    (%r10,%rax,8),%rdi
  mov    (%r9,%rdi,8),%rdi
  mov    %rdi,(%rdx,%rsi,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L47
L9:
  cmp    $0x1,%rcx
  jle    L35
  sub    $0x1,%rcx
  mov    $0x0,%eax
L28:
  mov    0x8(%rdx,%rax,8),%rsi
  cmp    %rsi,(%rdx,%rax,8)
  jg     L16
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L28
  mov    $0x1,%eax
  jmp    L67
L35:
  mov    $0x1,%eax
  jmp    L67
L16:
  mov    $0x0,%eax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  leave
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ordiso(const long *u, const long *v, const long *m, long len) {
  register long i;
  long *w = alloca(len * sizeof(*w));
  for (i = 0; i < len; i++, u++, m++)
    w[*u] = v[*m];
  for (; len > 1; len--, w++) {
    if (*w > *(w + 1))
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ordiso>:
  endbr64
  push   %rbp
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %rdi,%r8
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x17(,%rcx,8),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L64
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L72
L64:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L96
L61:
  lea    0xf(%rsp),%rsi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rsi
  test   %rcx,%rcx
  jle    L109
  nopl   0x0(%rax,%rax,1)
L104:
  mov    (%r10,%rax,8),%rdi
  mov    (%r8,%rax,8),%rdx
  add    $0x1,%rax
  mov    (%r9,%rdi,8),%rdi
  mov    %rdi,(%rsi,%rdx,8)
  cmp    %rax,%rcx
  jne    L104
  cmp    $0x1,%rcx
  jle    L109
  mov    (%rsi),%rdx
  sub    $0x1,%rcx
  xor    %eax,%eax
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L66:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L109
L20:
  mov    %rdx,%rdi
  mov    0x8(%rsi,%rax,8),%rdx
  cmp    %rdi,%rdx
  jge    L66
  xor    %eax,%eax
L88:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  leave
  ret
  nopl   0x0(%rax)
L109:
  mov    $0x1,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L96:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L61
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ordiso(const long *u, const long *v, const long *m, long len) {
  register long i;
  long *w = alloca(len * sizeof(*w));
  for (i = 0; i < len; i++, u++, m++)
    w[*u] = v[*m];
  for (; len > 1; len--, w++) {
    if (*w > *(w + 1))
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ordiso>:
  endbr64
  push   %rbp
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %rdi,%r8
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x17(,%rcx,8),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L70
L108:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L108
L70:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L62
L81:
  lea    0xf(%rsp),%rsi
  and    $0xfffffffffffffff0,%rsi
  test   %rcx,%rcx
  jle    L63
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L97:
  mov    (%r10,%rax,8),%rdi
  mov    (%r8,%rax,8),%rdx
  add    $0x1,%rax
  mov    (%r9,%rdi,8),%rdi
  mov    %rdi,(%rsi,%rdx,8)
  cmp    %rax,%rcx
  jne    L97
  cmp    $0x1,%rcx
  jle    L63
  mov    (%rsi),%rdx
  sub    $0x1,%rcx
  xor    %eax,%eax
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L67:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L63
L93:
  mov    %rdx,%rdi
  mov    0x8(%rsi,%rax,8),%rdx
  cmp    %rdi,%rdx
  jge    L67
  xor    %eax,%eax
L85:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  leave
  ret
  nopl   0x0(%rax)
L63:
  mov    $0x1,%eax
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L62:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L81
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ordiso(const long *u, const long *v, const long *m, long len) {
  register long i;
  long *w = alloca(len * sizeof(*w));
  for (i = 0; i < len; i++, u++, m++)
    w[*u] = v[*m];
  for (; len > 1; len--, w++) {
    if (*w > *(w + 1))
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xf,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  add    $0x8,%rax
  add    $0xa,%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void function(int a, int b, int c) {
  int x = 15;
  *(&x + 2) += 10;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<function>:
  endbr64
  ret
```

assistant: ```c
void function(int a, int b, int c) {
  int x = 15;
  *(&x + 2) += 10;
}
```
user: What is the c source code of the assembly code below:

```asm
<function>:
  endbr64
  ret
```

assistant: ```c
void function(int a, int b, int c) {
  int x = 15;
  *(&x + 2) += 10;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<function>:
  endbr64
  ret
```

assistant: ```c
void function(int a, int b, int c) {
  int x = 15;
  *(&x + 2) += 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum_elements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L16
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L9
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sum_elements>
  add    %ebx,%eax
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int sum_elements(int array[], int n) {
  if (n == 0) {
    return array[n];
  } else {
    return array[n] + sum_elements(array, n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum_elements>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %esi,%esi
  jne    L18
  mov    (%rdi),%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %esi,%ebx
  lea    -0x1(%rsi),%esi
  call   <sum_elements>
  movslq %ebx,%rbx
  add    0x0(%rbp,%rbx,4),%eax
  jmp    L10
```

assistant: ```c
int sum_elements(int array[], int n) {
  if (n == 0) {
    return array[n];
  } else {
    return array[n] + sum_elements(array, n - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_elements>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L13
  movslq %esi,%rdx
  xor    %eax,%eax
  nop
L17:
  add    (%rdi,%rdx,4),%eax
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L17
L13:
  add    (%rdi),%eax
  ret
```

assistant: ```c
int sum_elements(int array[], int n) {
  if (n == 0) {
    return array[n];
  } else {
    return array[n] + sum_elements(array, n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum_elements>:
  endbr64
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %esi,%esi
  je     L11
  lea    -0x1(%rsi),%edx
  mov    %esi,%r9d
  cmp    $0x2,%edx
  jbe    L23
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    -0xc(%rdi,%rax,4),%rdx
  mov    %esi,%edi
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  lea    -0x1(%rdi),%r8d
  mov    %rax,%rdi
  shl    $0x4,%r8
  sub    %r8,%rdi
  jmp    L53
  nopl   (%rax)
L26:
  sub    $0x10,%rax
L53:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L26
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%esi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%r9d
  je     L11
  lea    -0x1(%rsi),%edx
L3:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rcx,%rdi,4),%eax
  test   %edx,%edx
  je     L11
  add    -0x4(%rcx,%r8,1),%eax
  cmp    $0x2,%esi
  je     L11
  add    -0x8(%rcx,%r8,1),%eax
L11:
  add    (%rcx),%eax
  ret
L23:
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
int sum_elements(int array[], int n) {
  if (n == 0) {
    return array[n];
  } else {
    return array[n] + sum_elements(array, n - 1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: usage: %s infile [r(emove whitespace)]


assistant: ```c
void usage(char **argv) {
  printf("usage: %s infile [r(emove whitespace)]\n", argv[0]);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: usage: %s infile [r(emove whitespace)]


assistant: ```c
void usage(char **argv) {
  printf("usage: %s infile [r(emove whitespace)]\n", argv[0]);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: usage: %s infile [r(emove whitespace)]


assistant: ```c
void usage(char **argv) {
  printf("usage: %s infile [r(emove whitespace)]\n", argv[0]);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: usage: %s infile [r(emove whitespace)]


assistant: ```c
void usage(char **argv) {
  printf("usage: %s infile [r(emove whitespace)]\n", argv[0]);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: CIAO

assistant: ```c
main() {
  int x, y = 0;
  if (x > 0)
    printf("CIAO");
}
```