ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<M7_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D0: M7_f(const char *s) is not yet implemented!


tool: D7: %s


assistant: ```c
int M7_f(char *s) {
  debug("M7_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<M7_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D17
type: string

tool: D18: M7_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M7_f(char *s) {
  debug("M7_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sm4_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x10,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x90(%rbp),%rdx
  mov    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sm4_key_schedule@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <print@plt>
  movl   $0x0,-0x94(%rbp)
  jmp    L25
L29:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0xa8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sm4_round_func@plt>
  addl   $0x1,-0x94(%rbp)
L25:
  cmpl   $0x1f,-0x94(%rbp)
  jle    L29
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <sm4_reverse@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sm4_encrypt(void *plaintext, void const *key) {
  uint32_t round_key[32] = {0};
  sm4_key_schedule(key, round_key);
  print(round_key, 32);
  int i;
  for (i = 0; i < 32; ++i)
    sm4_round_func((uint32_t *)plaintext, round_key[i]);
  sm4_reverse((uint32_t *)plaintext);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sm4_encrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x10,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %rdx,%rdi
  call   <sm4_key_schedule@plt>
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  lea    0x80(%rsp),%r12
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <sm4_round_func@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    %rbp,%rdi
  call   <sm4_reverse@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sm4_encrypt(void *plaintext, void const *key) {
  uint32_t round_key[32] = {0};
  sm4_key_schedule(key, round_key);
  print(round_key, 32);
  int i;
  for (i = 0; i < 32; ++i)
    sm4_round_func((uint32_t *)plaintext, round_key[i]);
  sm4_reverse((uint32_t *)plaintext);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sm4_encrypt>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  mov    $0x10,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rsp,%rdi
  lea    0x80(%rsp),%r12
  mov    %rbx,%rsi
  rep stos %rax,%es:(%rdi)
  mov    %r8,%rdi
  call   <sm4_key_schedule@plt>
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <sm4_round_func@plt>
  cmp    %r12,%rbx
  jne    L9
  mov    %rbp,%rdi
  call   <sm4_reverse@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sm4_encrypt(void *plaintext, void const *key) {
  uint32_t round_key[32] = {0};
  sm4_key_schedule(key, round_key);
  print(round_key, 32);
  int i;
  for (i = 0; i < 32; ++i)
    sm4_round_func((uint32_t *)plaintext, round_key[i]);
  sm4_reverse((uint32_t *)plaintext);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sm4_encrypt>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  mov    $0x10,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rsp,%rdi
  lea    0x80(%rsp),%r12
  mov    %rbx,%rsi
  rep stos %rax,%es:(%rdi)
  mov    %r8,%rdi
  call   <sm4_key_schedule@plt>
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <sm4_round_func@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    %rbp,%rdi
  call   <sm4_reverse@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sm4_encrypt(void *plaintext, void const *key) {
  uint32_t round_key[32] = {0};
  sm4_key_schedule(key, round_key);
  print(round_key, 32);
  int i;
  for (i = 0; i < 32; ++i)
    sm4_round_func((uint32_t *)plaintext, round_key[i]);
  sm4_reverse((uint32_t *)plaintext);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<disasm_rr_a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: RR    A

assistant: ```c
int disasm_rr_a(struct em8051 *aCPU, int aPosition, char *aBuffer) {
  sprintf(aBuffer, "RR    A");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<disasm_rr_a>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: RR    A

assistant: ```c
int disasm_rr_a(struct em8051 *aCPU, int aPosition, char *aBuffer) {
  sprintf(aBuffer, "RR    A");
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<disasm_rr_a>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: RR    A

assistant: ```c
int disasm_rr_a(struct em8051 *aCPU, int aPosition, char *aBuffer) {
  sprintf(aBuffer, "RR    A");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<disasm_rr_a>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: RR    A

assistant: ```c
int disasm_rr_a(struct em8051 *aCPU, int aPosition, char *aBuffer) {
  sprintf(aBuffer, "RR    A");
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L17
L19:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L5
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L5:
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void *memdup(const void *src, size_t len) {
  void *dst = NULL;
  if (len == 0) {
    return NULL;
  }
  dst = calloc(1, len);
  if ((__builtin_expect(!!(dst != NULL), 1))) {
    memcpy(dst, src, len);
  }
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  test   %rsi,%rsi
  je     L26
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L10
L26:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L26
```

assistant: ```c
__attribute__((visibility("default"))) void *memdup(const void *src, size_t len) {
  void *dst = NULL;
  if (len == 0) {
    return NULL;
  }
  dst = calloc(1, len);
  if ((__builtin_expect(!!(dst != NULL), 1))) {
    memcpy(dst, src, len);
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memdup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rsi,%rsi
  je     L11
  mov    %rdi,%rbp
  mov    $0x1,%edi
  mov    %rsi,%r13
  call   <calloc@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L3
L11:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L3:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void *memdup(const void *src, size_t len) {
  void *dst = NULL;
  if (len == 0) {
    return NULL;
  }
  dst = calloc(1, len);
  if ((__builtin_expect(!!(dst != NULL), 1))) {
    memcpy(dst, src, len);
  }
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memdup>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%rbp
  mov    $0x1,%edi
  mov    %rsi,%r13
  call   <calloc@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L17
L1:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((visibility("default"))) void *memdup(const void *src, size_t len) {
  void *dst = NULL;
  if (len == 0) {
    return NULL;
  }
  dst = calloc(1, len);
  if ((__builtin_expect(!!(dst != NULL), 1))) {
    memcpy(dst, src, len);
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L15:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L15
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D15
type: string

tool: D8: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int i;
  for (i = (a > b ? a : b); (i % a != 0 || i % b != 0); i++) {
  }
  printf("%d\n", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovge %edi,%esi
  jmp    L12
L17:
  add    $0x1,%esi
L12:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L17
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L17
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D18
datatype: string

tool: D19: %d %d

tool: D18: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int i;
  for (i = (a > b ? a : b); (i % a != 0 || i % b != 0); i++) {
  }
  printf("%d\n", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovge %edi,%esi
  jmp    L6
  nopl   0x0(%rax)
L11:
  add    $0x1,%esi
L6:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L11
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L11
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D2: %d %d

tool: D1: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int i;
  for (i = (a > b ? a : b); (i % a != 0 || i % b != 0); i++) {
  }
  printf("%d\n", i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%ecx
  cmp    %ecx,%edi
  mov    %ecx,%esi
  cmovge %edi,%esi
  jmp    L23
  nopl   0x0(%rax)
L21:
  add    $0x1,%esi
L23:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L21
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L21
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D2
type: string

tool: D18: %d %d

tool: D2: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%d %d", &a, &b);
  int i;
  for (i = (a > b ? a : b); (i % a != 0 || i % b != 0); i++) {
  }
  printf("%d\n", i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isUgly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L37
  mov    $0x0,%eax
  jmp    L17
L33:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L33
  jmp    L54
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L54:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L0
  jmp    L6
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L34
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
bool isUgly(int num) {
  if (num <= 0) {
    return false;
  }
  while (num % 2 == 0)
    num /= 2;
  while (num % 3 == 0)
    num /= 3;
  while (num % 5 == 0)
    num /= 5;
  return num == 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isUgly>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%edx
  test   %edi,%edi
  jle    L32
  test   $0x1,%al
  jne    L25
L26:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %edx,%eax
  test   $0x1,%dl
  je     L26
L25:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %edx,%eax
  jne    L66
L31:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  movslq %edx,%rcx
  imul   $0x55555556,%rcx,%rcx
  shr    $0x20,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  lea    (%rcx,%rcx,2),%ecx
  cmp    %ecx,%edx
  je     L31
L66:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %edx,%eax
  jne    L15
L37:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x21,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  cmp    %ecx,%edx
  je     L37
L15:
  cmp    $0x1,%eax
  sete   %dl
  movzbl %dl,%edx
L32:
  mov    %edx,%eax
  ret
```

assistant: ```c
bool isUgly(int num) {
  if (num <= 0) {
    return false;
  }
  while (num % 2 == 0)
    num /= 2;
  while (num % 3 == 0)
    num /= 3;
  while (num % 5 == 0)
    num /= 5;
  return num == 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<isUgly>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jg     L2
  jmp    L23
  nopl   0x0(%rax)
L39:
  sar    %edi
L2:
  test   $0x1,%dil
  je     L39
  imul   $0xaaaaaaab,%edi,%eax
  cmp    $0x55555555,%eax
  ja     L24
  mov    $0xaaaaaaab,%edx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x21,%rdi
  imul   $0xaaaaaaab,%edi,%eax
  cmp    $0x55555555,%eax
  jbe    L15
L24:
  imul   $0xcccccccd,%edi,%eax
  cmp    $0x33333333,%eax
  ja     L50
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L26:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x22,%rdi
  imul   $0xcccccccd,%edi,%eax
  cmp    $0x33333333,%eax
  jbe    L26
L50:
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
L23:
  ret
```

assistant: ```c
bool isUgly(int num) {
  if (num <= 0) {
    return false;
  }
  while (num % 2 == 0)
    num /= 2;
  while (num % 3 == 0)
    num /= 3;
  while (num % 5 == 0)
    num /= 5;
  return num == 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isUgly>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jg     L2
  jmp    L64
  nopl   0x0(%rax)
L46:
  sar    %edi
L2:
  test   $0x1,%dil
  je     L46
  imul   $0xaaaaaaab,%edi,%eax
  cmp    $0x55555555,%eax
  ja     L21
  mov    $0xaaaaaaab,%edx
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x21,%rdi
  imul   $0xaaaaaaab,%edi,%eax
  cmp    $0x55555555,%eax
  jbe    L40
L21:
  imul   $0xcccccccd,%edi,%eax
  cmp    $0x33333333,%eax
  ja     L14
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L38:
  mov    %edi,%edi
  imul   %rdx,%rdi
  shr    $0x22,%rdi
  imul   $0xcccccccd,%edi,%eax
  cmp    $0x33333333,%eax
  jbe    L38
L14:
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
L64:
  ret
```

assistant: ```c
bool isUgly(int num) {
  if (num <= 0) {
    return false;
  }
  while (num % 2 == 0)
    num /= 2;
  while (num % 3 == 0)
    num /= 3;
  while (num % 5 == 0)
    num /= 5;
  return num == 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<msg_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_vmsg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void msg_exit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _vmsg(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msg_exit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_vmsg@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void msg_exit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _vmsg(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<msg_exit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <_vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void msg_exit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _vmsg(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msg_exit>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <_vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void msg_exit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  _vmsg(fmt, ap);
  va_end(ap);
  exit(1);
}
```