ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<myread>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %eax,%ebx
  jne    L18
L15:
  pop    %rbx
  ret
L18:
  lea    D2(%rip),%rdi
  call   <err@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: Error reading input file.


assistant: ```c
void myread(void *p, int length, FILE *f) {
  int l = fread(p, 1, length, f);
  if (l != length)
    err("Error reading input file.\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<myread>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %esi,%ebx
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %eax,%ebx
  jne    L1
  pop    %rbx
  ret
  nopl   0x0(%rax)
L1:
  lea    D1(%rip),%rdi
  pop    %rbx
  jmp    1070 <err@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: Error reading input file.


assistant: ```c
void myread(void *p, int length, FILE *f) {
  int l = fread(p, 1, length, f);
  if (l != length)
    err("Error reading input file.\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<myread>:
  endbr64
  push   %rbx
  mov    %rdx,%rcx
  mov    %esi,%ebx
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  cmp    %eax,%ebx
  jne    L2
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1070 <err@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: Error reading input file.


assistant: ```c
void myread(void *p, int length, FILE *f) {
  int l = fread(p, 1, length, f);
  if (l != length)
    err("Error reading input file.\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L12
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  movq   $0x0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x8(%rbp)
  je     L0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: string

tool: D28: wb

tool: D39: /tmp/duk-test-compile-file-temp.js

tool: D9: failed to open %s


tool: D36: failed to write test data fully

assistant: ```c
void write_file(const char *filename, const char *data) {
  FILE *f;
  size_t ret;
  f = fopen(filename, "wb");
  if (!f) {
    printf("failed to open %s\n", "/tmp/duk-test-compile-file-temp.js");
    return;
  }
  ret = fwrite((const void *)data, 1, strlen(data), f);
  fflush(f);
  fclose(f);
  f = NULL;
  if (ret != strlen(data)) {
    printf("failed to write test data fully\n");
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    D39(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L30
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12,%rax
  jne    L34
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  lea    D34(%rip),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L34:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L27
```

tool_calls: name: parse_data
arguments: data_label: D39
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string
name: parse_data
arguments: data_label: D27
type_guessed: string
name: parse_data
arguments: data_label: D29
type_guessed: string

tool: D39: wb

tool: D34: /tmp/duk-test-compile-file-temp.js

tool: D27: failed to open %s


tool: D29: failed to write test data fully

assistant: ```c
void write_file(const char *filename, const char *data) {
  FILE *f;
  size_t ret;
  f = fopen(filename, "wb");
  if (!f) {
    printf("failed to open %s\n", "/tmp/duk-test-compile-file-temp.js");
    return;
  }
  ret = fwrite((const void *)data, 1, strlen(data), f);
  fflush(f);
  fclose(f);
  f = NULL;
  if (ret != strlen(data)) {
    printf("failed to write test data fully\n");
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D21(%rip),%rsi
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L11:
  pop    %rbx
  lea    D27(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <puts@plt>
L6:
  pop    %rbx
  lea    D17(%rip),%rsi
  pop    %rbp
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  pop    %r12
  jmp    10e0 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D10
type_guessed: string

tool: D21: wb

tool: D27: failed to write test data fully

tool: D17: /tmp/duk-test-compile-file-temp.js

tool: D10: failed to open %s


assistant: ```c
void write_file(const char *filename, const char *data) {
  FILE *f;
  size_t ret;
  f = fopen(filename, "wb");
  if (!f) {
    printf("failed to open %s\n", "/tmp/duk-test-compile-file-temp.js");
    return;
  }
  ret = fwrite((const void *)data, 1, strlen(data), f);
  fflush(f);
  fclose(f);
  f = NULL;
  if (ret != strlen(data)) {
    printf("failed to write test data fully\n");
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_file>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  push   %rbx
  call   <fopen@plt>
  test   %rax,%rax
  je     L11
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <puts@plt>
L11:
  pop    %rbx
  lea    D24(%rip),%rsi
  pop    %rbp
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  pop    %r12
  jmp    10e0 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D3: wb

tool: D11: failed to write test data fully

tool: D24: /tmp/duk-test-compile-file-temp.js

tool: D5: failed to open %s


assistant: ```c
void write_file(const char *filename, const char *data) {
  FILE *f;
  size_t ret;
  f = fopen(filename, "wb");
  if (!f) {
    printf("failed to open %s\n", "/tmp/duk-test-compile-file-temp.js");
    return;
  }
  ret = fwrite((const void *)data, 1, strlen(data), f);
  fflush(f);
  fclose(f);
  f = NULL;
  if (ret != strlen(data)) {
    printf("failed to write test data fully\n");
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<heap_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L8
  jmp    L18
L17:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L8
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
L8:
  nop
  leave
  ret
```

assistant: ```c
void heap_insert(int *heap, int num, int cur_index) {
  heap[cur_index] = num;
  int parent = cur_index / 2;
  if ((parent > 0)) {
    while ((heap[parent] < heap[cur_index]) && (parent > 0)) {
      swap(&heap[parent], &heap[cur_index]);
      cur_index = parent;
      parent = cur_index / 2;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heap_insert>:
  endbr64
  mov    %esi,%ecx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rsi
  mov    %ecx,(%rsi)
  cmp    $0x1,%edx
  jle    L30
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ebx
  cltq
  lea    (%rdi,%rax,4),%rdi
  cmp    (%rdi),%ecx
  jle    L17
L12:
  call   <swap@plt>
  mov    %ebx,%edx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    %eax,%ebx
  cltq
  lea    0x0(%rbp,%rax,4),%rdi
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jge    L17
  cmp    $0x1,%edx
  jg     L12
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  ret
```

assistant: ```c
void heap_insert(int *heap, int num, int cur_index) {
  heap[cur_index] = num;
  int parent = cur_index / 2;
  if ((parent > 0)) {
    while ((heap[parent] < heap[cur_index]) && (parent > 0)) {
      swap(&heap[parent], &heap[cur_index]);
      cur_index = parent;
      parent = cur_index / 2;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heap_insert>:
  endbr64
  movslq %edx,%rdx
  mov    %esi,%eax
  lea    (%rdi,%rdx,4),%rsi
  mov    %eax,(%rsi)
  cmp    $0x1,%edx
  jle    L34
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sar    %ebx
  movslq %ebx,%rdx
  lea    (%rdi,%rdx,4),%rdi
  sub    $0x8,%rsp
  cmp    (%rdi),%eax
  jg     L19
  jmp    L22
  nop
L41:
  test   %ebx,%ebx
  jle    L22
L19:
  call   <swap@plt>
  movslq %ebx,%rax
  sar    %ebx
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rax,4),%rsi
  lea    0x0(%rbp,%rdx,4),%rdi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jl     L41
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  ret
```

assistant: ```c
void heap_insert(int *heap, int num, int cur_index) {
  heap[cur_index] = num;
  int parent = cur_index / 2;
  if ((parent > 0)) {
    while ((heap[parent] < heap[cur_index]) && (parent > 0)) {
      swap(&heap[parent], &heap[cur_index]);
      cur_index = parent;
      parent = cur_index / 2;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heap_insert>:
  endbr64
  movslq %edx,%rdx
  mov    %esi,%eax
  lea    (%rdi,%rdx,4),%rsi
  mov    %eax,(%rsi)
  cmp    $0x1,%edx
  jle    L43
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sar    %ebx
  movslq %ebx,%rdx
  lea    (%rdi,%rdx,4),%rdi
  sub    $0x8,%rsp
  cmp    (%rdi),%eax
  jg     L35
  jmp    L48
  nop
L49:
  test   %ebx,%ebx
  jle    L48
L35:
  call   <swap@plt>
  movslq %ebx,%rax
  sar    %ebx
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rax,4),%rsi
  lea    0x0(%rbp,%rdx,4),%rdi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jl     L49
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  ret
```

assistant: ```c
void heap_insert(int *heap, int num, int cur_index) {
  heap[cur_index] = num;
  int parent = cur_index / 2;
  if ((parent > 0)) {
    while ((heap[parent] < heap[cur_index]) && (parent > 0)) {
      swap(&heap[parent], &heap[cur_index]);
      cur_index = parent;
      parent = cur_index / 2;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L17:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L4
  cmpl   $0x0,-0xc(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L35
L14:
  mov    -0xc(%rbp),%eax
  jmp    L35
L4:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
L56:
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  mov    $0x1,%eax
L35:
  leave
  ret
```

assistant: ```c
int send_all(int socket, void *buf, size_t len) {
  char *ptr = (char *)buf;
  while (len > 0) {
    int n = write(socket, ptr, len);
    if (n < 1) {
      if (n == 0)
        return 0;
      return n;
    }
    ptr += n;
    len -= n;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_all>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L31
L2:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L15
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L2
  mov    $0x1,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    $0x1,%eax
  jmp    L15
```

assistant: ```c
int send_all(int socket, void *buf, size_t len) {
  char *ptr = (char *)buf;
  while (len > 0) {
    int n = write(socket, ptr, len);
    if (n < 1) {
      if (n == 0)
        return 0;
      return n;
    }
    ptr += n;
    len -= n;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_all>:
  endbr64
  test   %rdx,%rdx
  je     L29
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L18:
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  je     L37
L30:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int send_all(int socket, void *buf, size_t len) {
  char *ptr = (char *)buf;
  while (len > 0) {
    int n = write(socket, ptr, len);
    if (n < 1) {
      if (n == 0)
        return 0;
      return n;
    }
    ptr += n;
    len -= n;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<send_all>:
  endbr64
  test   %rdx,%rdx
  je     L2
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L26:
  cltq
  add    %rax,%r12
  sub    %rax,%rbx
  je     L39
L4:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int send_all(int socket, void *buf, size_t len) {
  char *ptr = (char *)buf;
  while (len > 0) {
    int n = write(socket, ptr, len);
    if (n < 1) {
      if (n == 0)
        return 0;
      return n;
    }
    ptr += n;
    len -= n;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lookup_hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getaddrinfo@plt>
  test   %rax,%rax
  je     L26
  movl   $0x1,-0x14(%rbp)
  jmp    L9
L26:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <getnameinfo@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L2
  movl   $0x1,-0x14(%rbp)
  jmp    L49
L2:
  movl   $0x0,-0x14(%rbp)
L49:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
L9:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int lookup_hostname(const char *addr, char *hostname, size_t buflen) {
  struct addrinfo *addrinfo;
  int rc;
  if (getaddrinfo(addr, NULL, NULL, &addrinfo)) {
    rc = 1;
  } else {
    if (getnameinfo(addrinfo->ai_addr, addrinfo->ai_addrlen, hostname, buflen, NULL, 0, 0)) {
      rc = 1;
    } else {
      rc = 0;
    }
    freeaddrinfo(addrinfo);
  }
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lookup_hostname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <getaddrinfo@plt>
  mov    $0x1,%ebp
  test   %rax,%rax
  je     L4
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    (%rsp),%rax
  mov    0x4(%rax),%edi
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    (%rax),%esi
  call   <getnameinfo@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  setne  %bpl
  movzbl %bpl,%ebp
  mov    (%rsp),%rdi
  call   <freeaddrinfo@plt>
  jmp    L0
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lookup_hostname(const char *addr, char *hostname, size_t buflen) {
  struct addrinfo *addrinfo;
  int rc;
  if (getaddrinfo(addr, NULL, NULL, &addrinfo)) {
    rc = 1;
  } else {
    if (getnameinfo(addrinfo->ai_addr, addrinfo->ai_addrlen, hostname, buflen, NULL, 0, 0)) {
      rc = 1;
    } else {
      rc = 0;
    }
    freeaddrinfo(addrinfo);
  }
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lookup_hostname>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  xor    %edx,%edx
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <getaddrinfo@plt>
  test   %rax,%rax
  je     L27
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L27:
  mov    (%rsp),%rax
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  xor    %r13d,%r13d
  mov    0x4(%rax),%edi
  push   $0x0
  mov    (%rax),%esi
  call   <getnameinfo@plt>
  pop    %rdx
  pop    %rcx
  mov    (%rsp),%rdi
  test   %rax,%rax
  setne  %r13b
  call   <freeaddrinfo@plt>
  jmp    L14
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lookup_hostname(const char *addr, char *hostname, size_t buflen) {
  struct addrinfo *addrinfo;
  int rc;
  if (getaddrinfo(addr, NULL, NULL, &addrinfo)) {
    rc = 1;
  } else {
    if (getnameinfo(addrinfo->ai_addr, addrinfo->ai_addrlen, hostname, buflen, NULL, 0, 0)) {
      rc = 1;
    } else {
      rc = 0;
    }
    freeaddrinfo(addrinfo);
  }
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lookup_hostname>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  xor    %edx,%edx
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <getaddrinfo@plt>
  test   %rax,%rax
  je     L25
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L25:
  mov    (%rsp),%rax
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  xor    %r13d,%r13d
  mov    0x4(%rax),%edi
  push   $0x0
  mov    (%rax),%esi
  call   <getnameinfo@plt>
  pop    %rdx
  pop    %rcx
  mov    (%rsp),%rdi
  test   %rax,%rax
  setne  %r13b
  call   <freeaddrinfo@plt>
  jmp    L13
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lookup_hostname(const char *addr, char *hostname, size_t buflen) {
  struct addrinfo *addrinfo;
  int rc;
  if (getaddrinfo(addr, NULL, NULL, &addrinfo)) {
    rc = 1;
  } else {
    if (getnameinfo(addrinfo->ai_addr, addrinfo->ai_addrlen, hostname, buflen, NULL, 0, 0)) {
      rc = 1;
    } else {
      rc = 0;
    }
    freeaddrinfo(addrinfo);
  }
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_digittoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L44
  mov    $0x0,%eax
  jmp    L39
L44:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L37
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L39
L37:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L22
  mov    -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L39
L22:
  mov    -0x4(%rbp),%eax
  sub    $0x57,%eax
L39:
  leave
  ret
```

assistant: ```c
int _digittoint(int c) {
  if (!isxdigit(c))
    return 0;
  if (isdigit(c))
    return c - '0';
  else
    return isupper(c) ? c - 'A' + 10 : c - 'a' + 10;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_digittoint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L26
L24:
  pop    %rbx
  ret
L26:
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L33
  lea    -0x30(%rbx),%eax
  jmp    L24
L33:
  mov    %ebx,%edi
  call   <isupper@plt>
  mov    %rax,%rdx
  lea    -0x37(%rbx),%eax
  sub    $0x57,%ebx
  test   %rdx,%rdx
  cmove  %ebx,%eax
  jmp    L24
```

assistant: ```c
int _digittoint(int c) {
  if (!isxdigit(c))
    return 0;
  if (isdigit(c))
    return c - '0';
  else
    return isupper(c) ? c - 'A' + 10 : c - 'a' + 10;
}
```