ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<safeMalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *safeMalloc(size_t size) {
  void *p = malloc(size);
  assert(p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<safeMalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *safeMalloc(size_t size) {
  void *p = malloc(size);
  assert(p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_cmd_fast>:
  endbr64
  mov    $0xc000a044,%eax
  orl    $0x2,(%rax)
  mov    %rdi,%r9
  lea    0x5(%rdi),%r10
  mov    $0x0,%eax
  mov    $0xc000a040,%edx
  jmp    L78
L48:
  mov    (%rdx),%esi
  or     $0x2,%esi
L46:
  mov    %esi,(%rdx)
  add    %eax,%eax
  nop
  orl    $0x1,(%rdx)
  mov    %eax,%esi
  xor    $0x9,%esi
  mov    %eax,%r8d
  xor    %cl,%r8b
  cmovs  %esi,%eax
  add    %ecx,%ecx
  sub    $0x1,%edi
  je     L42
L66:
  andl   $0xfffffffe,(%rdx)
  nop
  test   %cl,%cl
  js     L48
  mov    (%rdx),%esi
  and    $0xfffffffd,%esi
  jmp    L46
L42:
  and    $0x7f,%eax
  add    $0x1,%r9
  cmp    %r10,%r9
  je     L12
L78:
  movzbl (%r9),%ecx
  mov    $0x8,%edi
  jmp    L66
L12:
  lea    0x1(%rax,%rax,1),%eax
  mov    %eax,%edi
  mov    $0x8,%esi
  mov    $0xc000a040,%edx
  jmp    L36
L33:
  mov    (%rdx),%ecx
  or     $0x2,%ecx
L49:
  mov    %ecx,(%rdx)
  nop
  orl    $0x1,(%rdx)
  add    %edi,%edi
  sub    $0x1,%esi
  je     L90
L36:
  andl   $0xfffffffe,(%rdx)
  nop
  test   %dil,%dil
  js     L33
  mov    (%rdx),%ecx
  and    $0xfffffffd,%ecx
  jmp    L49
L90:
  ret
```

assistant: ```c
unsigned char send_cmd_fast(unsigned char *in) {
  int i, j;
  unsigned char b, crc = 0;
  *((unsigned int *)0xC000A044) |= (1 << 1);
  for (i = 0; i < 5; i++) {
    b = in[i];
    for (j = 0; j < 8; j++) {
      do {
        *((unsigned int *)0xC000A040) &= ~(1 << 0);
        asm volatile("nop");
      } while (0);
      if (b & 0x80)
        *((unsigned int *)0xC000A040) |= (1 << 1);
      else
        *((unsigned int *)0xC000A040) &= ~(1 << 1);
      crc <<= 1;
      do {
        asm volatile("nop");
        *((unsigned int *)0xC000A040) |= (1 << 0);
      } while (0);
      if ((crc ^ b) & 0x80)
        crc ^= 0x09;
      b <<= 1;
    }
    crc &= 0x7f;
  }
  crc = ((crc << 1) | 0x01);
  b = crc;
  for (j = 0; j < 8; j++) {
    do {
      *((unsigned int *)0xC000A040) &= ~(1 << 0);
      asm volatile("nop");
    } while (0);
    if (crc & 0x80)
      *((unsigned int *)0xC000A040) |= (1 << 1);
    else
      *((unsigned int *)0xC000A040) &= ~(1 << 1);
    do {
      asm volatile("nop");
      *((unsigned int *)0xC000A040) |= (1 << 0);
    } while (0);
    crc <<= 1;
  }
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<send_cmd_fast>:
  endbr64
  mov    $0xc000a044,%eax
  mov    $0xc000a040,%ecx
  lea    0x5(%rdi),%r11
  orl    $0x2,(%rax)
  mov    (%rcx),%edx
  xor    %eax,%eax
L46:
  movzbl (%rdi),%esi
  mov    $0x8,%r8d
  jmp    L16
  nopl   0x0(%rax)
L2:
  and    $0xfffffffd,%edx
L89:
  mov    %edx,(%rcx)
  add    %eax,%eax
  nop
  mov    (%rcx),%edx
  mov    %eax,%r9d
  mov    %eax,%r10d
  xor    $0x9,%r9d
  or     $0x1,%edx
  xor    %sil,%r10b
  cmovs  %r9d,%eax
  mov    %edx,(%rcx)
  add    %esi,%esi
  sub    $0x1,%r8d
  je     L74
L16:
  and    $0xfffffffe,%edx
  mov    %edx,(%rcx)
  nop
  mov    (%rcx),%edx
  test   %sil,%sil
  jns    L2
  or     $0x2,%edx
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L74:
  add    $0x1,%rdi
  and    $0x7f,%eax
  cmp    %rdi,%r11
  jne    L46
  lea    0x1(%rax,%rax,1),%eax
  mov    $0x8,%esi
  mov    $0xc000a040,%ecx
  mov    %eax,%edi
  jmp    L53
  cs nopw 0x0(%rax,%rax,1)
L83:
  and    $0xfffffffd,%edx
L82:
  mov    %edx,(%rcx)
  nop
  mov    (%rcx),%edx
  add    %edi,%edi
  or     $0x1,%edx
  mov    %edx,(%rcx)
  sub    $0x1,%esi
  je     L13
L53:
  and    $0xfffffffe,%edx
  mov    %edx,(%rcx)
  nop
  mov    (%rcx),%edx
  test   %dil,%dil
  jns    L83
  or     $0x2,%edx
  jmp    L82
  cs nopw 0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
unsigned char send_cmd_fast(unsigned char *in) {
  int i, j;
  unsigned char b, crc = 0;
  *((unsigned int *)0xC000A044) |= (1 << 1);
  for (i = 0; i < 5; i++) {
    b = in[i];
    for (j = 0; j < 8; j++) {
      do {
        *((unsigned int *)0xC000A040) &= ~(1 << 0);
        asm volatile("nop");
      } while (0);
      if (b & 0x80)
        *((unsigned int *)0xC000A040) |= (1 << 1);
      else
        *((unsigned int *)0xC000A040) &= ~(1 << 1);
      crc <<= 1;
      do {
        asm volatile("nop");
        *((unsigned int *)0xC000A040) |= (1 << 0);
      } while (0);
      if ((crc ^ b) & 0x80)
        crc ^= 0x09;
      b <<= 1;
    }
    crc &= 0x7f;
  }
  crc = ((crc << 1) | 0x01);
  b = crc;
  for (j = 0; j < 8; j++) {
    do {
      *((unsigned int *)0xC000A040) &= ~(1 << 0);
      asm volatile("nop");
    } while (0);
    if (crc & 0x80)
      *((unsigned int *)0xC000A040) |= (1 << 1);
    else
      *((unsigned int *)0xC000A040) &= ~(1 << 1);
    do {
      asm volatile("nop");
      *((unsigned int *)0xC000A040) |= (1 << 0);
    } while (0);
    crc <<= 1;
  }
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cmdargParse@plt>
  mov    $0x0,%eax
  call   <pre_init_modemu@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  jmp    L23
L4:
  mov    $0x0,%eax
  call   <init_modemu@plt>
L5:
  mov    $0x0,%eax
  call   <run_modemu@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x2710,%edi
  call   <usleep@plt>
  cmpl   $0x2,-0x4(%rbp)
  je     L5
  mov    -0x4(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ret;
  cmdargParse(argv);
  if (!pre_init_modemu())
    return 0;
  init_modemu();
  do {
    ret = run_modemu();
    usleep(10000);
  } while (ret == 2);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rdi
  call   <cmdargParse@plt>
  mov    $0x0,%eax
  call   <pre_init_modemu@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L21
L0:
  mov    %ebx,%eax
  pop    %rbx
  ret
L21:
  mov    $0x0,%eax
  call   <init_modemu@plt>
L19:
  mov    $0x0,%eax
  call   <run_modemu@plt>
  mov    %eax,%ebx
  mov    $0x2710,%edi
  call   <usleep@plt>
  cmp    $0x2,%ebx
  je     L19
  jmp    L0
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ret;
  cmdargParse(argv);
  if (!pre_init_modemu())
    return 0;
  init_modemu();
  do {
    ret = run_modemu();
    usleep(10000);
  } while (ret == 2);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%rdi
  call   <cmdargParse@plt>
  xor    %eax,%eax
  call   <pre_init_modemu@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L6
L1:
  mov    %r12d,%eax
  pop    %r12
  ret
L6:
  xor    %eax,%eax
  call   <init_modemu@plt>
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <run_modemu@plt>
  mov    $0x2710,%edi
  mov    %eax,%r12d
  call   <usleep@plt>
  cmp    $0x2,%r12d
  je     L14
  jmp    L1
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ret;
  cmdargParse(argv);
  if (!pre_init_modemu())
    return 0;
  init_modemu();
  do {
    ret = run_modemu();
    usleep(10000);
  } while (ret == 2);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%rdi
  call   <cmdargParse@plt>
  xor    %eax,%eax
  call   <pre_init_modemu@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L13
L12:
  mov    %r12d,%eax
  pop    %r12
  ret
L13:
  xor    %eax,%eax
  call   <init_modemu@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <run_modemu@plt>
  mov    $0x2710,%edi
  mov    %eax,%r12d
  call   <usleep@plt>
  cmp    $0x2,%r12d
  je     L0
  jmp    L12
```

assistant: ```c
int main(int argc, const char *argv[]) {
  int ret;
  cmdargParse(argv);
  if (!pre_init_modemu())
    return 0;
  init_modemu();
  do {
    ret = run_modemu();
    usleep(10000);
  } while (ret == 2);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_minimum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L12
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L12:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_minimum(int array[], int start_pos, int end_pos) {
  int min = start_pos, pos = start_pos;
  while (pos < end_pos) {
    if (array[pos] < array[min])
      min = pos;
    pos++;
  }
  return min;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_minimum>:
  endbr64
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L10
  movslq %esi,%rcx
L3:
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,(%rdi,%rcx,4)
  cmovl  %ecx,%eax
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jg     L3
L10:
  ret
```

assistant: ```c
int find_minimum(int array[], int start_pos, int end_pos) {
  int min = start_pos, pos = start_pos;
  while (pos < end_pos) {
    if (array[pos] < array[min])
      min = pos;
    pos++;
  }
  return min;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_minimum>:
  endbr64
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L19
  movslq %esi,%rcx
  nopl   (%rax)
L15:
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,(%rdi,%rcx,4)
  cmovl  %ecx,%eax
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jg     L15
L19:
  ret
```

assistant: ```c
int find_minimum(int array[], int start_pos, int end_pos) {
  int min = start_pos, pos = start_pos;
  while (pos < end_pos) {
    if (array[pos] < array[min])
      min = pos;
    pos++;
  }
  return min;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_minimum>:
  endbr64
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L3
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%r9d
  nopl   0x0(%rax)
L0:
  mov    (%rdi,%rcx,4),%r8d
  cmp    %r9d,%r8d
  jge    L9
  mov    %r8d,%r9d
  mov    %ecx,%eax
L9:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jg     L0
L3:
  ret
```

assistant: ```c
int find_minimum(int array[], int start_pos, int end_pos) {
  int min = start_pos, pos = start_pos;
  while (pos < end_pos) {
    if (array[pos] < array[min])
      min = pos;
    pos++;
  }
  return min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eoi_pic2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa0,%esi
  mov    $0x20,%edi
  call   <outb@plt>
  mov    $0x0,%eax
  call   <eoi_pic1@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void eoi_pic2(void) {
  outb(0x20, 0x00a0);
  eoi_pic1();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eoi_pic2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0,%esi
  mov    $0x20,%edi
  call   <outb@plt>
  mov    $0x0,%eax
  call   <eoi_pic1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void eoi_pic2(void) {
  outb(0x20, 0x00a0);
  eoi_pic1();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eoi_pic2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0,%esi
  mov    $0x20,%edi
  call   <outb@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <eoi_pic1@plt>
```

assistant: ```c
void eoi_pic2(void) {
  outb(0x20, 0x00a0);
  eoi_pic1();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eoi_pic2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0,%esi
  mov    $0x20,%edi
  call   <outb@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <eoi_pic1@plt>
```

assistant: ```c
void eoi_pic2(void) {
  outb(0x20, 0x00a0);
  eoi_pic1();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mul128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <hi_dword@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <lo_dword@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <hi_dword@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <lo_dword@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x30(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x20,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t mul128(uint64_t multiplier, uint64_t multiplicand, uint64_t *product_hi) {
  uint64_t a = hi_dword(multiplier);
  uint64_t b = lo_dword(multiplier);
  uint64_t c = hi_dword(multiplicand);
  uint64_t d = lo_dword(multiplicand);
  uint64_t ac = a * c;
  uint64_t ad = a * d;
  uint64_t bc = b * c;
  uint64_t bd = b * d;
  uint64_t adbc = ad + bc;
  uint64_t adbc_carry = adbc < ad ? 1 : 0;
  uint64_t product_lo = bd + (adbc << 32);
  uint64_t product_lo_carry = product_lo < bd ? 1 : 0;
  *product_hi = ac + (adbc >> 32) + (adbc_carry << 32) + product_lo_carry;
  return product_lo;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mul128>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %rdx,%r12
  call   <hi_dword@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <lo_dword@plt>
  mov    %eax,%ebx
  mov    %r14d,%edi
  call   <hi_dword@plt>
  mov    %eax,%r13d
  mov    %r14d,%edi
  call   <lo_dword@plt>
  mov    %ebp,%edx
  imul   %eax,%edx
  mov    %ebx,%ecx
  imul   %r13d,%ecx
  add    %ecx,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  imul   %r13d,%ebp
  add    %ebp,%edx
  mov    %edx,(%r12)
  imul   %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint64_t mul128(uint64_t multiplier, uint64_t multiplicand, uint64_t *product_hi) {
  uint64_t a = hi_dword(multiplier);
  uint64_t b = lo_dword(multiplier);
  uint64_t c = hi_dword(multiplicand);
  uint64_t d = lo_dword(multiplicand);
  uint64_t ac = a * c;
  uint64_t ad = a * d;
  uint64_t bc = b * c;
  uint64_t bd = b * d;
  uint64_t adbc = ad + bc;
  uint64_t adbc_carry = adbc < ad ? 1 : 0;
  uint64_t product_lo = bd + (adbc << 32);
  uint64_t product_lo_carry = product_lo < bd ? 1 : 0;
  *product_hi = ac + (adbc >> 32) + (adbc_carry << 32) + product_lo_carry;
  return product_lo;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mul128>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <hi_dword@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <lo_dword@plt>
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <hi_dword@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <lo_dword@plt>
  mov    %ebp,%edx
  imul   %r12d,%ebp
  mov    %ebx,%ecx
  imul   %r12d,%ecx
  imul   %eax,%edx
  imul   %ebx,%eax
  pop    %rbx
  add    %ecx,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  add    %ebp,%edx
  pop    %rbp
  pop    %r12
  mov    %edx,(%r14)
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint64_t mul128(uint64_t multiplier, uint64_t multiplicand, uint64_t *product_hi) {
  uint64_t a = hi_dword(multiplier);
  uint64_t b = lo_dword(multiplier);
  uint64_t c = hi_dword(multiplicand);
  uint64_t d = lo_dword(multiplicand);
  uint64_t ac = a * c;
  uint64_t ad = a * d;
  uint64_t bc = b * c;
  uint64_t bd = b * d;
  uint64_t adbc = ad + bc;
  uint64_t adbc_carry = adbc < ad ? 1 : 0;
  uint64_t product_lo = bd + (adbc << 32);
  uint64_t product_lo_carry = product_lo < bd ? 1 : 0;
  *product_hi = ac + (adbc >> 32) + (adbc_carry << 32) + product_lo_carry;
  return product_lo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mul128>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <hi_dword@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <lo_dword@plt>
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <hi_dword@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <lo_dword@plt>
  mov    %ebp,%edx
  imul   %r12d,%ebp
  mov    %ebx,%ecx
  imul   %r12d,%ecx
  imul   %eax,%edx
  imul   %ebx,%eax
  pop    %rbx
  add    %ecx,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  add    %ebp,%edx
  pop    %rbp
  pop    %r12
  mov    %edx,(%r14)
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint64_t mul128(uint64_t multiplier, uint64_t multiplicand, uint64_t *product_hi) {
  uint64_t a = hi_dword(multiplier);
  uint64_t b = lo_dword(multiplier);
  uint64_t c = hi_dword(multiplicand);
  uint64_t d = lo_dword(multiplicand);
  uint64_t ac = a * c;
  uint64_t ad = a * d;
  uint64_t bc = b * c;
  uint64_t bd = b * d;
  uint64_t adbc = ad + bc;
  uint64_t adbc_carry = adbc < ad ? 1 : 0;
  uint64_t product_lo = bd + (adbc << 32);
  uint64_t product_lo_carry = product_lo < bd ? 1 : 0;
  *product_hi = ac + (adbc >> 32) + (adbc_carry << 32) + product_lo_carry;
  return product_lo;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculateNext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
L14:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L14
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int calculateNext(int s2) {
  int cnex;
  do
    cnex = __VERIFIER_nondet_int();
  while (cnex == s2 || cnex == 0);
  return cnex;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculateNext>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L13:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    %ebx,%eax
  je     L13
  test   %eax,%eax
  je     L13
  pop    %rbx
  ret
```

assistant: ```c
int calculateNext(int s2) {
  int cnex;
  do
    cnex = __VERIFIER_nondet_int();
  while (cnex == s2 || cnex == 0);
  return cnex;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calculateNext>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    %ebx,%eax
  je     L5
  test   %eax,%eax
  je     L5
  pop    %rbx
  ret
```

assistant: ```c
int calculateNext(int s2) {
  int cnex;
  do
    cnex = __VERIFIER_nondet_int();
  while (cnex == s2 || cnex == 0);
  return cnex;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calculateNext>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    %ebx,%eax
  je     L8
  test   %eax,%eax
  je     L8
  pop    %rbx
  ret
```

assistant: ```c
int calculateNext(int s2) {
  int cnex;
  do
    cnex = __VERIFIER_nondet_int();
  while (cnex == s2 || cnex == 0);
  return cnex;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <build_heap@plt>
  jmp    L17
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  sub    $0x4,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <xor_swap@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <build_heap@plt>
  subq   $0x1,-0x8(%rbp)
L17:
  cmpq   $0x2,-0x8(%rbp)
  jg     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapsort(float **heap, long heapsize) {
  long index = heapsize;
  build_heap(heap, index);
  while (index > 2) {
    xor_swap(&(*heap)[1], &(*heap)[index - 1], sizeof(float));
    build_heap(heap, index - 1);
    index--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<heapsort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <build_heap@plt>
  cmp    $0x2,%rbx
  jle    L17
  sub    $0x1,%rbx
L8:
  mov    0x0(%rbp),%rdi
  lea    (%rdi,%rbx,4),%rsi
  add    $0x4,%rdi
  mov    $0x4,%edx
  call   <xor_swap@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <build_heap@plt>
  sub    $0x1,%rbx
  cmp    $0x1,%rbx
  jne    L8
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapsort(float **heap, long heapsize) {
  long index = heapsize;
  build_heap(heap, index);
  while (index > 2) {
    xor_swap(&(*heap)[1], &(*heap)[index - 1], sizeof(float));
    build_heap(heap, index - 1);
    index--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <build_heap@plt>
  cmp    $0x2,%rbx
  jle    L8
  sub    $0x1,%rbx
  nop
L16:
  mov    0x0(%rbp),%rdi
  mov    $0x4,%edx
  lea    (%rdi,%rbx,4),%rsi
  add    $0x4,%rdi
  call   <xor_swap@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <build_heap@plt>
  cmp    $0x1,%rbx
  jne    L16
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapsort(float **heap, long heapsize) {
  long index = heapsize;
  build_heap(heap, index);
  while (index > 2) {
    xor_swap(&(*heap)[1], &(*heap)[index - 1], sizeof(float));
    build_heap(heap, index - 1);
    index--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <build_heap@plt>
  cmp    $0x2,%rbx
  jle    L7
  sub    $0x1,%rbx
  nop
L13:
  mov    0x0(%rbp),%rdi
  mov    $0x4,%edx
  lea    (%rdi,%rbx,4),%rsi
  add    $0x4,%rdi
  call   <xor_swap@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <build_heap@plt>
  cmp    $0x1,%rbx
  jne    L13
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapsort(float **heap, long heapsize) {
  long index = heapsize;
  build_heap(heap, index);
  while (index > 2) {
    xor_swap(&(*heap)[1], &(*heap)[index - 1], sizeof(float));
    build_heap(heap, index - 1);
    index--;
  }
}
```