user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  push   %rbp
  lea    D39(%rip),%rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L38
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  nopl   (%rax)
L51:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %ebx,0xc(%rsp)
  jg     L51
L38:
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L44
  lea    0x60(%rsp),%r12
  xor    %ebx,%ebx
  nop
L1:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %ebx,0xc(%rsp)
  jg     L1
L44:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq 0xc(%rsp),%rcx
  test   %ecx,%ecx
  jle    L90
  lea    0x10(%rsp),%rdi
  pxor   %xmm5,%xmm5
  lea    0x60(%rsp),%r8
  xor    %edx,%edx
  movss  0x8(%rsp),%xmm4
  movss  D48(%rip),%xmm6
  mov    %rdi,%rsi
  nopl   (%rax)
L18:
  xor    %eax,%eax
  movaps %xmm6,%xmm3
  movaps %xmm6,%xmm2
L42:
  cmp    %edx,%eax
  je     L8
  movss  (%rdi,%rax,4),%xmm1
  movaps %xmm4,%xmm0
  subss  %xmm1,%xmm0
  mulss  %xmm0,%xmm2
  movss  (%rsi),%xmm0
  subss  %xmm1,%xmm0
  mulss  %xmm0,%xmm3
L8:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L42
  divss  %xmm3,%xmm2
  add    $0x4,%rsi
  mulss  (%r8,%rdx,4),%xmm2
  add    $0x1,%rdx
  addss  %xmm2,%xmm5
  cmp    %rcx,%rdx
  jne    L18
L41:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm5,%xmm0
  call   <printf@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L90:
  pxor   %xmm5,%xmm5
  jmp    L41
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D39
type_infered: string
name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D49
type_infered: string
name: extract_symbolic_data
arguments: data_label: D56
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D48
type_infered: byte[4]

tool: D13: Enter the value of n

tool: D39: %f

tool: D33: %d

tool: D49: Enter the values of x

tool: D56: Enter the values of y

tool: D20: Enter the interpolating point

tool: {"D48": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void main() {
  float x[20], y[20], m, o, inter, s = 0;
  int i, j, n;
  printf("Enter the value of n");
  scanf("%d", &n);
  printf("Enter the values of x");
  for (i = 0; i < n; i++)
    scanf("%f", &x[i]);
  printf("Enter the values of y");
  for (i = 0; i < n; i++)
    scanf("%f", &y[i]);
  printf("Enter the interpolating point");
  scanf("%f", &inter);
  for (i = 0; i < n; i++) {
    m = 1;
    o = 1;
    for (j = 0; j < n; j++)
      if (i != j) {
        m *= inter - x[j];
        o *= x[i] - x[j];
      }
    s += (m / o) * y[i];
  }
  printf("%f", s);
}
```