ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<internal_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L27
  negl   -0x14(%rbp)
L27:
  movl   $0x0,-0xc(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D8(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L12
  cmpl   $0x0,-0x4(%rbp)
  jns    L32
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L32:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L25:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L25
  nop
  nop
  leave
  ret
```

assistant: ```c
void internal_itoa(int n, char s[], int radix) {
  static char const HEXDIGITS[0x10] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int i, j, sign;
  char c;
  if ((sign = n) < 0) {
    n = -n;
  }
  i = 0;
  do {
    s[i++] = HEXDIGITS[n % radix];
  } while ((n /= radix) > 0);
  if (sign < 0) {
    s[i++] = '-';
  }
  s[i] = '\0';
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<internal_itoa>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  mov    %rsi,%rbx
  mov    %edx,%edi
  mov    %r8d,%edx
  neg    %edx
  cmovs  %r8d,%edx
  mov    $0x0,%ecx
  lea    D5(%rip),%r9
L18:
  mov    %ecx,%r10d
  add    $0x1,%ecx
  mov    %edx,%eax
  cltd
  idiv   %edi
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,(%rsi)
  mov    %eax,%edx
  add    $0x1,%rsi
  test   %eax,%eax
  jg     L18
  test   %r8d,%r8d
  js     L47
L20:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L33
  cltq
  mov    $0x0,%edx
L23:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L23
L33:
  pop    %rbx
  ret
L47:
  movslq %ecx,%rcx
  movb   $0x2d,(%rbx,%rcx,1)
  lea    0x2(%r10),%ecx
  jmp    L20
```

assistant: ```c
void internal_itoa(int n, char s[], int radix) {
  static char const HEXDIGITS[0x10] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int i, j, sign;
  char c;
  if ((sign = n) < 0) {
    n = -n;
  }
  i = 0;
  do {
    s[i++] = HEXDIGITS[n % radix];
  } while ((n /= radix) > 0);
  if (sign < 0) {
    s[i++] = '-';
  }
  s[i] = '\0';
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<internal_itoa>:
  endbr64
  mov    %edi,%r8d
  push   %rbx
  mov    %edx,%edi
  mov    %rsi,%rbx
  mov    %r8d,%eax
  lea    D1(%rip),%r9
  neg    %eax
  cmovs  %r8d,%eax
  xor    %ecx,%ecx
  nop
L13:
  cltd
  mov    %ecx,%r10d
  add    $0x1,%rsi
  idiv   %edi
  add    $0x1,%ecx
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jg     L13
  test   %r8d,%r8d
  jns    L24
  movslq %ecx,%rcx
  movb   $0x2d,(%rbx,%rcx,1)
  lea    0x2(%r10),%ecx
L24:
  movslq %ecx,%rcx
  mov    %rbx,%rdi
  movb   $0x0,(%rbx,%rcx,1)
  call   <strlen@plt>
  xor    %edx,%edx
  sub    $0x1,%eax
  movslq %eax,%rcx
  test   %eax,%eax
  jle    L15
  nopw   0x0(%rax,%rax,1)
L31:
  movzbl (%rbx,%rdx,1),%eax
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %al,(%rbx,%rcx,1)
  sub    $0x1,%rcx
  cmp    %edx,%ecx
  jg     L31
L15:
  pop    %rbx
  ret
```

assistant: ```c
void internal_itoa(int n, char s[], int radix) {
  static char const HEXDIGITS[0x10] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int i, j, sign;
  char c;
  if ((sign = n) < 0) {
    n = -n;
  }
  i = 0;
  do {
    s[i++] = HEXDIGITS[n % radix];
  } while ((n /= radix) > 0);
  if (sign < 0) {
    s[i++] = '-';
  }
  s[i] = '\0';
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<internal_itoa>:
  endbr64
  mov    %edi,%r8d
  push   %rbx
  mov    %edx,%edi
  mov    %rsi,%rbx
  mov    %r8d,%eax
  lea    D9(%rip),%r9
  neg    %eax
  cmovs  %r8d,%eax
  xor    %ecx,%ecx
  nop
L19:
  cltd
  mov    %ecx,%r10d
  add    $0x1,%rsi
  idiv   %edi
  add    $0x1,%ecx
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jg     L19
  test   %r8d,%r8d
  jns    L18
  movslq %ecx,%rcx
  movb   $0x2d,(%rbx,%rcx,1)
  lea    0x2(%r10),%ecx
L18:
  movslq %ecx,%rcx
  mov    %rbx,%rdi
  movb   $0x0,(%rbx,%rcx,1)
  call   <strlen@plt>
  xor    %edx,%edx
  sub    $0x1,%eax
  movslq %eax,%rcx
  test   %eax,%eax
  jle    L39
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl (%rbx,%rdx,1),%eax
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %al,(%rbx,%rcx,1)
  sub    $0x1,%rcx
  cmp    %edx,%ecx
  jg     L24
L39:
  pop    %rbx
  ret
```

assistant: ```c
void internal_itoa(int n, char s[], int radix) {
  static char const HEXDIGITS[0x10] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
  int i, j, sign;
  char c;
  if ((sign = n) < 0) {
    n = -n;
  }
  i = 0;
  do {
    s[i++] = HEXDIGITS[n % radix];
  } while ((n /= radix) > 0);
  if (sign < 0) {
    s[i++] = '-';
  }
  s[i] = '\0';
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendfd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%r8d
  mov    %rax,%rdi
  call   <sendfd_payload@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void sendfd(const char *test, int sockfd, int sendfd) {
  char ch;
  return (sendfd_payload(test, sockfd, sendfd, &ch, sizeof(ch)));
}
```
user: What is the c source code of the assembly code below?

```asm
<sendfd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rcx
  mov    $0x1,%r8d
  call   <sendfd_payload@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendfd(const char *test, int sockfd, int sendfd) {
  char ch;
  return (sendfd_payload(test, sockfd, sendfd, &ch, sizeof(ch)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sendfd>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rcx
  call   <sendfd_payload@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendfd(const char *test, int sockfd, int sendfd) {
  char ch;
  return (sendfd_payload(test, sockfd, sendfd, &ch, sizeof(ch)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sendfd>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rcx
  call   <sendfd_payload@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sendfd(const char *test, int sockfd, int sendfd) {
  char ch;
  return (sendfd_payload(test, sockfd, sendfd, &ch, sizeof(ch)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CopyBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  sub    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L9
L30:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L11
L31:
  mov    -0x10(%rbp),%rax
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  sub    -0x40(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  sub    -0x48(%rbp),%rax
  imul   -0x8(%rbp),%rax
  add    %rcx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jl     L31
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  cmp    0x10(%rbp),%rax
  jl     L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CopyBlock(double *B, double *dest, long n3, long is, long ks, long il, long kl) {
  long i, k, bs;
  bs = il - is;
  for (k = ks; k < kl; k++)
    for (i = is; i < il; i++) {
      dest[(i - is) + (k - ks) * bs] = B[i + k * n3];
    }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CopyBlock>:
  endbr64
  push   %rbp
  push   %rbx
  mov    0x18(%rsp),%r11
  mov    %r9,%r10
  sub    %rcx,%r10
  cmp    %r11,%r8
  jge    L48
  mov    %rdi,%rbp
  mov    %rcx,%rdi
  lea    0x0(,%rdx,8),%rbx
  imul   %r8,%rdx
  add    %rcx,%rdx
  lea    0x0(%rbp,%rdx,8),%rcx
  shl    $0x3,%r10
  mov    %rsi,%rdx
  mov    %r10,%rsi
  jmp    L38
L6:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L6
L25:
  add    $0x1,%r8
  add    %rbx,%rcx
  add    %r10,%rdx
  cmp    %r8,%r11
  je     L48
L38:
  mov    $0x0,%eax
  cmp    %rdi,%r9
  jg     L6
  jmp    L25
L48:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void CopyBlock(double *B, double *dest, long n3, long is, long ks, long il, long kl) {
  long i, k, bs;
  bs = il - is;
  for (k = ks; k < kl; k++)
    for (i = is; i < il; i++) {
      dest[(i - is) + (k - ks) * bs] = B[i + k * n3];
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CopyBlock>:
  endbr64
  push   %rbx
  mov    0x10(%rsp),%r10
  mov    %rsi,%rax
  mov    %r9,%rsi
  sub    %rcx,%rsi
  cmp    %r10,%r8
  jge    L32
  lea    0x0(,%rdx,8),%r11
  mov    %rdi,%rbx
  shl    $0x3,%rsi
  mov    %rcx,%rdi
  imul   %r8,%rdx
  add    %rcx,%rdx
  lea    (%rbx,%rdx,8),%rcx
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  cmp    %rdi,%r9
  jle    L10
  nopw   0x0(%rax,%rax,1)
L22:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L22
L10:
  add    $0x1,%r8
  add    %r11,%rcx
  add    %rsi,%rdx
  cmp    %r8,%r10
  jne    L39
L32:
  pop    %rbx
  ret
```

assistant: ```c
void CopyBlock(double *B, double *dest, long n3, long is, long ks, long il, long kl) {
  long i, k, bs;
  bs = il - is;
  for (k = ks; k < kl; k++)
    for (i = is; i < il; i++) {
      dest[(i - is) + (k - ks) * bs] = B[i + k * n3];
    }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CopyBlock>:
  endbr64
  push   %r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  sub    %rcx,%r14
  push   %r12
  push   %rbp
  push   %rbx
  cmp    0x38(%rsp),%r8
  jge    L61
  mov    %rcx,%r10
  cmp    %rcx,%r9
  jle    L61
  mov    %rsi,%r11
  mov    %r8,%rsi
  mov    %r8,%rbp
  mov    %r14,%r9
  imul   %rdx,%rsi
  mov    %r14,%r8
  and    $0xfffffffffffffffe,%r9
  mov    %rdi,%rbx
  shr    %r8
  mov    %rdx,%r12
  add    %r9,%r10
  lea    0x0(,%rdx,8),%r15
  lea    0x0(,%r14,8),%r13
  mov    %r11,%rdx
  shl    $0x4,%r8
  lea    (%rsi,%rcx,1),%rax
  lea    (%rdi,%rax,8),%rcx
  lea    -0x1(%r14),%rax
  xor    %edi,%edi
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x8(%rcx),%rax
  cmp    %rax,%rdx
  je     L77
  xor    %eax,%eax
  cmpq   $0x2,-0x10(%rsp)
  jbe    L77
  nopl   0x0(%rax,%rax,1)
L84:
  movupd (%rcx,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L84
  cmp    %r14,%r9
  je     L28
  lea    (%rsi,%r10,1),%rax
  movsd  (%rbx,%rax,8),%xmm0
  lea    (%rdi,%r9,1),%rax
  movsd  %xmm0,(%r11,%rax,8)
L28:
  add    $0x1,%rbp
  add    %r15,%rcx
  add    %r13,%rdx
  add    %r12,%rsi
  add    %r14,%rdi
  cmp    %rbp,0x38(%rsp)
  jne    L11
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L77:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r13,%rax
  jne    L18
  jmp    L28
```

assistant: ```c
void CopyBlock(double *B, double *dest, long n3, long is, long ks, long il, long kl) {
  long i, k, bs;
  bs = il - is;
  for (k = ks; k < kl; k++)
    for (i = is; i < il; i++) {
      dest[(i - is) + (k - ks) * bs] = B[i + k * n3];
    }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<majorityElement1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %rdx,%r13
  test   %esi,%esi
  jle    L51
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%r8d
  mov    $0x0,%esi
  jmp    L91
L97:
  add    $0x1,%esi
L45:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  je     L76
L91:
  mov    (%rdi),%edx
  cmp    %ebx,%edx
  je     L97
  cmp    %ebp,%edx
  je     L148
  test   %esi,%esi
  je     L29
  test   %r8d,%r8d
  je     L69
  sub    $0x1,%esi
  sub    $0x1,%r8d
  jmp    L45
L148:
  add    $0x1,%r8d
  jmp    L45
L29:
  mov    %edx,%ebx
  mov    $0x1,%esi
  jmp    L45
L69:
  mov    %edx,%ebp
  mov    $0x1,%r8d
  jmp    L45
L76:
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  jmp    L122
L87:
  add    $0x1,%r15d
L56:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L139
L122:
  mov    (%rax),%edx
  cmp    %ebx,%edx
  je     L87
  cmp    %ebp,%edx
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%r14d
  jmp    L56
L51:
  mov    $0x0,%r14d
  mov    $0x0,%r15d
L139:
  mov    $0x8,%edi
  call   <malloc@plt>
  movslq %r12d,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%r12d
  sub    %r12d,%edx
  mov    $0x0,%ecx
  cmp    %r15d,%edx
  jge    L115
  mov    %ebx,(%rax)
  mov    $0x1,%ecx
L115:
  cmp    %r14d,%edx
  jge    L121
  movslq %ecx,%rdx
  mov    %ebp,(%rax,%rdx,4)
  lea    0x1(%rcx),%ecx
L121:
  mov    %ecx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *majorityElement1(int *nums, int size, int *returnSize) {
  int count1 = 0, count2 = 0;
  int a, b;
  for (int i = 0; i < size; i++) {
    if (nums[i] == a)
      count1++;
    else if (nums[i] == b)
      count2++;
    else {
      if (count1 == 0)
        a = nums[i], count1 = 1;
      else if (count2 == 0)
        b = nums[i], count2 = 1;
      else
        count1--, count2--;
    }
  }
  count1 = count2 = 0;
  for (int i = 0; i < size; i++)
    if (nums[i] == a)
      count1++;
    else if (nums[i] == b)
      count2++;
  int *res = (int *)malloc(sizeof(int) * 2);
  int index = 0;
  if (count1 > size / 3)
    res[index++] = a;
  if (count2 > size / 3)
    res[index++] = b;
  *returnSize = index;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<majorityElement1>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L151
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  xor    %esi,%esi
  lea    0x4(%rdi,%rax,4),%rcx
  mov    %rdi,%rax
  jmp    L136
  nopw   0x0(%rax,%rax,1)
L49:
  cmp    %r12d,%edx
  je     L138
  test   %esi,%esi
  je     L98
  test   %r8d,%r8d
  je     L28
  sub    $0x1,%esi
  sub    $0x1,%r8d
  nopl   0x0(%rax)
L60:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L34
L136:
  mov    (%rax),%edx
  cmp    %ebx,%edx
  jne    L49
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %rcx,%rax
  jne    L136
L34:
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L77:
  cmp    %r12d,%eax
  sete   %al
  add    $0x4,%rdi
  movzbl %al,%eax
  add    %eax,%ebp
  cmp    %rcx,%rdi
  je     L2
L134:
  mov    (%rdi),%eax
  cmp    %ebx,%eax
  jne    L77
  add    $0x4,%rdi
  add    $0x1,%r15d
  cmp    %rcx,%rdi
  jne    L134
L2:
  mov    $0x8,%edi
  call   <malloc@plt>
  movslq %r13d,%rdx
  sar    $0x1f,%r13d
  xor    %ecx,%ecx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %r13d,%edx
  cmp    %r15d,%edx
  jge    L115
  mov    %ebx,(%rax)
  mov    $0x1,%ecx
L115:
  cmp    %ebp,%edx
  jge    L167
  movslq %ecx,%rdx
  add    $0x1,%ecx
  mov    %r12d,(%rax,%rdx,4)
L167:
  mov    %ecx,(%r14)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L138:
  add    $0x1,%r8d
  jmp    L60
  nopl   0x0(%rax)
L98:
  mov    %edx,%ebx
  mov    $0x1,%esi
  jmp    L60
  nopl   0x0(%rax)
L28:
  mov    %edx,%r12d
  mov    $0x1,%r8d
  jmp    L60
  xchg   %ax,%ax
L151:
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  jmp    L2
```

assistant: ```c
int *majorityElement1(int *nums, int size, int *returnSize) {
  int count1 = 0, count2 = 0;
  int a, b;
  for (int i = 0; i < size; i++) {
    if (nums[i] == a)
      count1++;
    else if (nums[i] == b)
      count2++;
    else {
      if (count1 == 0)
        a = nums[i], count1 = 1;
      else if (count2 == 0)
        b = nums[i], count2 = 1;
      else
        count1--, count2--;
    }
  }
  count1 = count2 = 0;
  for (int i = 0; i < size; i++)
    if (nums[i] == a)
      count1++;
    else if (nums[i] == b)
      count2++;
  int *res = (int *)malloc(sizeof(int) * 2);
  int index = 0;
  if (count1 > size / 3)
    res[index++] = a;
  if (count2 > size / 3)
    res[index++] = b;
  *returnSize = index;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZVaxpy31>:
  endbr64
  movsd  (%r8),%xmm3
  movsd  0x8(%r8),%xmm4
  movsd  0x10(%r8),%xmm5
  movsd  0x18(%r8),%xmm6
  movsd  0x20(%r8),%xmm7
  movsd  0x28(%r8),%xmm8
  test   %edi,%edi
  jle    L18
  mov    %edi,%edi
  shl    $0x4,%rdi
  mov    $0x0,%eax
L11:
  movsd  (%r9,%rax,1),%xmm1
  movsd  0x8(%r9,%rax,1),%xmm0
  movapd %xmm3,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm4,%xmm9
  mulsd  %xmm0,%xmm9
  subsd  %xmm9,%xmm2
  addsd  (%rsi,%rax,1),%xmm2
  movsd  %xmm2,(%rsi,%rax,1)
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm4,%xmm9
  mulsd  %xmm1,%xmm9
  addsd  %xmm9,%xmm2
  addsd  0x8(%rsi,%rax,1),%xmm2
  movsd  %xmm2,0x8(%rsi,%rax,1)
  movapd %xmm5,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm6,%xmm9
  mulsd  %xmm0,%xmm9
  subsd  %xmm9,%xmm2
  addsd  (%rdx,%rax,1),%xmm2
  movsd  %xmm2,(%rdx,%rax,1)
  movapd %xmm5,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm6,%xmm9
  mulsd  %xmm1,%xmm9
  addsd  %xmm9,%xmm2
  addsd  0x8(%rdx,%rax,1),%xmm2
  movsd  %xmm2,0x8(%rdx,%rax,1)
  movapd %xmm7,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm8,%xmm9
  mulsd  %xmm0,%xmm9
  subsd  %xmm9,%xmm2
  addsd  (%rcx,%rax,1),%xmm2
  movsd  %xmm2,(%rcx,%rax,1)
  mulsd  %xmm7,%xmm0
  mulsd  %xmm8,%xmm1
  addsd  %xmm1,%xmm0
  addsd  0x8(%rcx,%rax,1),%xmm0
  movsd  %xmm0,0x8(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L11
L18:
  ret
```

assistant: ```c
void ZVaxpy31(int n, double y0[], double y1[], double y2[], double alpha[], double x0[]) {
  register double ar00, ar10, ar20;
  register double ai00, ai10, ai20;
  register double xr0i;
  register double xi0i;
  int ii;
  ar00 = alpha[0];
  ai00 = alpha[1];
  ar10 = alpha[2];
  ai10 = alpha[3];
  ar20 = alpha[4];
  ai20 = alpha[5];
  for (ii = 0; ii < n; ii++) {
    xr0i = x0[2 * ii];
    xi0i = x0[2 * ii + 1];
    y0[2 * ii] += (ar00 * xr0i - ai00 * xi0i);
    y0[2 * ii + 1] += (ar00 * xi0i + ai00 * xr0i);
    y1[2 * ii] += (ar10 * xr0i - ai10 * xi0i);
    y1[2 * ii + 1] += (ar10 * xi0i + ai10 * xr0i);
    y2[2 * ii] += (ar20 * xr0i - ai20 * xi0i);
    y2[2 * ii + 1] += (ar20 * xi0i + ai20 * xr0i);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ZVaxpy31>:
  endbr64
  movsd  (%r8),%xmm3
  movsd  0x8(%r8),%xmm4
  movsd  0x10(%r8),%xmm5
  movsd  0x18(%r8),%xmm6
  movsd  0x20(%r8),%xmm7
  movsd  0x28(%r8),%xmm8
  test   %edi,%edi
  jle    L2
  movslq %edi,%rdi
  xor    %eax,%eax
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L5:
  movsd  (%r9,%rax,1),%xmm1
  movsd  0x8(%r9,%rax,1),%xmm0
  movapd %xmm3,%xmm2
  movapd %xmm4,%xmm9
  mulsd  %xmm0,%xmm9
  mulsd  %xmm1,%xmm2
  subsd  %xmm9,%xmm2
  addsd  (%rsi,%rax,1),%xmm2
  movapd %xmm4,%xmm9
  mulsd  %xmm1,%xmm9
  movsd  %xmm2,(%rsi,%rax,1)
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm9,%xmm2
  addsd  0x8(%rsi,%rax,1),%xmm2
  movapd %xmm6,%xmm9
  mulsd  %xmm0,%xmm9
  movsd  %xmm2,0x8(%rsi,%rax,1)
  movapd %xmm5,%xmm2
  mulsd  %xmm1,%xmm2
  subsd  %xmm9,%xmm2
  addsd  (%rdx,%rax,1),%xmm2
  movapd %xmm6,%xmm9
  mulsd  %xmm1,%xmm9
  movsd  %xmm2,(%rdx,%rax,1)
  movapd %xmm5,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm9,%xmm2
  addsd  0x8(%rdx,%rax,1),%xmm2
  movapd %xmm8,%xmm9
  mulsd  %xmm0,%xmm9
  mulsd  %xmm7,%xmm0
  movsd  %xmm2,0x8(%rdx,%rax,1)
  movapd %xmm7,%xmm2
  mulsd  %xmm1,%xmm2
  mulsd  %xmm8,%xmm1
  subsd  %xmm9,%xmm2
  addsd  (%rcx,%rax,1),%xmm2
  addsd  %xmm1,%xmm0
  addsd  0x8(%rcx,%rax,1),%xmm0
  movsd  %xmm2,(%rcx,%rax,1)
  movsd  %xmm0,0x8(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L5
L2:
  ret
```

assistant: ```c
void ZVaxpy31(int n, double y0[], double y1[], double y2[], double alpha[], double x0[]) {
  register double ar00, ar10, ar20;
  register double ai00, ai10, ai20;
  register double xr0i;
  register double xi0i;
  int ii;
  ar00 = alpha[0];
  ai00 = alpha[1];
  ar10 = alpha[2];
  ai10 = alpha[3];
  ar20 = alpha[4];
  ai20 = alpha[5];
  for (ii = 0; ii < n; ii++) {
    xr0i = x0[2 * ii];
    xi0i = x0[2 * ii + 1];
    y0[2 * ii] += (ar00 * xr0i - ai00 * xi0i);
    y0[2 * ii + 1] += (ar00 * xi0i + ai00 * xr0i);
    y1[2 * ii] += (ar10 * xr0i - ai10 * xi0i);
    y1[2 * ii + 1] += (ar10 * xi0i + ai10 * xr0i);
    y2[2 * ii] += (ar20 * xr0i - ai20 * xi0i);
    y2[2 * ii + 1] += (ar20 * xi0i + ai20 * xr0i);
  }
  return;
}
```