ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_find_first_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L25
L36:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <__builtin_clz@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L2
L6:
  addq   $0x1,-0x10(%rbp)
  addq   $0x20,-0x8(%rbp)
L25:
  mov    -0x20(%rbp),%rax
  add    $0x1f,%rax
  shr    $0x5,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L36
  mov    -0x20(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
size_t bitmap_find_first_set(uint32_t *bitmap, size_t n_bits) {
  size_t i, pos;
  for (i = 0, pos = 0; i < (((n_bits) + 31) >> 5); i++, pos += 32) {
    if (bitmap[i])
      return pos + __builtin_clz(bitmap[i]);
  }
  return n_bits;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmap_find_first_set>:
  endbr64
  mov    %rsi,%rax
  lea    0x1f(%rsi),%rcx
  shr    $0x5,%rcx
  je     L35
  push   %rbx
  mov    %rdi,%r8
  mov    $0x0,%edx
L30:
  mov    %rdx,%rbx
  shl    $0x5,%rbx
  mov    (%r8,%rdx,8),%rdi
  test   %rdi,%rdi
  jne    L10
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L30
  jmp    L17
L10:
  call   <__builtin_clz@plt>
  add    %rbx,%rax
L17:
  pop    %rbx
  ret
L35:
  ret
```

assistant: ```c
size_t bitmap_find_first_set(uint32_t *bitmap, size_t n_bits) {
  size_t i, pos;
  for (i = 0, pos = 0; i < (((n_bits) + 31) >> 5); i++, pos += 32) {
    if (bitmap[i])
      return pos + __builtin_clz(bitmap[i]);
  }
  return n_bits;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_find_first_set>:
  endbr64
  lea    0x1f(%rsi),%rcx
  mov    %rsi,%rax
  shr    $0x5,%rcx
  je     L37
  push   %rbx
  mov    %rdi,%r8
  xor    %edx,%edx
  jmp    L36
  nopl   0x0(%rax)
L34:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L13
L36:
  mov    (%r8,%rdx,8),%rdi
  mov    %rdx,%rbx
  shl    $0x5,%rbx
  test   %rdi,%rdi
  je     L34
  call   <__builtin_clz@plt>
  add    %rbx,%rax
L13:
  pop    %rbx
  ret
L37:
  ret
```

assistant: ```c
size_t bitmap_find_first_set(uint32_t *bitmap, size_t n_bits) {
  size_t i, pos;
  for (i = 0, pos = 0; i < (((n_bits) + 31) >> 5); i++, pos += 32) {
    if (bitmap[i])
      return pos + __builtin_clz(bitmap[i]);
  }
  return n_bits;
}
```
user: What is the c source code of the assembly code below:

```asm
<bitmap_find_first_set>:
  endbr64
  lea    0x1f(%rsi),%rcx
  mov    %rsi,%rax
  shr    $0x5,%rcx
  je     L30
  push   %rbx
  mov    %rdi,%r8
  xor    %edx,%edx
  jmp    L34
  nopl   0x0(%rax)
L26:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L37
L34:
  mov    (%r8,%rdx,8),%rdi
  mov    %rdx,%rbx
  shl    $0x5,%rbx
  test   %rdi,%rdi
  je     L26
  call   <__builtin_clz@plt>
  add    %rbx,%rax
L37:
  pop    %rbx
  ret
L30:
  ret
```

assistant: ```c
size_t bitmap_find_first_set(uint32_t *bitmap, size_t n_bits) {
  size_t i, pos;
  for (i = 0, pos = 0; i < (((n_bits) + 31) >> 5); i++, pos += 32) {
    if (bitmap[i])
      return pos + __builtin_clz(bitmap[i]);
  }
  return n_bits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L17
L5:
  nop
L17:
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  if (a == b)
    return;
  *a ^= *b;
  *b ^= *a;
  *a ^= *b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L8
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
L8:
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  if (a == b)
    return;
  *a ^= *b;
  *b ^= *a;
  *a ^= *b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L5
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
L5:
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  if (a == b)
    return;
  *a ^= *b;
  *b ^= *a;
  *a ^= *b;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  cmp    %rsi,%rdi
  je     L0
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
L0:
  ret
```

assistant: ```c
void swap(int *a, int *b) {
  if (a == b)
    return;
  *a ^= *b;
  *b ^= *a;
  *a ^= *b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L81
L17:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x64(%rbp)
  movl   $0x1,-0x68(%rbp)
  jmp    L0
L79:
  mov    -0x64(%rbp),%eax
  cltd
  idivl  -0x68(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  mov    -0x64(%rbp),%eax
  cltd
  idivl  -0x68(%rbp)
  mov    %eax,%edx
  mov    -0x68(%rbp),%ecx
  lea    -0x60(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <test@plt>
  test   %rax,%rax
  jne    L6
L40:
  addl   $0x1,-0x68(%rbp)
L0:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L79
  jmp    L32
L6:
  nop
L32:
  mov    -0x68(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x6c(%rbp),%eax
  test   %eax,%eax
  je     L81
  mov    $0xa,%edi
  call   <putchar@plt>
L81:
  mov    -0x6c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x6c(%rbp)
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string
name: unpack_data
arguments: label: D0
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D15: %d

tool: D0: %s

tool: D9: %d


assistant: ```c
int main() {
  int T, n, i;
  char s[86];
  scanf("%d", &T);
  while (T--) {
    scanf("%s", s);
    n = strlen(s);
    for (i = 1; i <= n; ++i) {
      if (n % i == 0 && test(s, i, n / i)) {
        break;
      }
    }
    printf("%d\n", i);
    if (T)
      printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%r12
  lea    D19(%rip),%r14
  lea    D26(%rip),%r13
  jmp    L12
L40:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L101
L59:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L40
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <test@plt>
  test   %rax,%rax
  je     L40
L101:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jne    L104
L12:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L70
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L67
  mov    $0x1,%ebx
  jmp    L59
L67:
  mov    $0x1,%ebx
  jmp    L101
L104:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L12
L70:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string

tool: D22: %d

tool: D19: %s

tool: D26: %d


assistant: ```c
int main() {
  int T, n, i;
  char s[86];
  scanf("%d", &T);
  while (T--) {
    scanf("%s", s);
    n = strlen(s);
    for (i = 1; i <= n; ++i) {
      if (n % i == 0 && test(s, i, n / i)) {
        break;
      }
    }
    printf("%d\n", i);
    if (T)
      printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  lea    D6(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
L81:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L4
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L46
  jmp    L20
  nopl   (%rax)
L71:
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jl     L20
L46:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L71
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <test@plt>
  test   %rax,%rax
  je     L71
L20:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L60
L4:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L60:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L81
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string

tool: D10: %d

tool: D6: %s

tool: D9: %d


assistant: ```c
int main() {
  int T, n, i;
  char s[86];
  scanf("%d", &T);
  while (T--) {
    scanf("%s", s);
    n = strlen(s);
    for (i = 1; i <= n; ++i) {
      if (n % i == 0 && test(s, i, n / i)) {
        break;
      }
    }
    printf("%d\n", i);
    if (T)
      printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%rdi
  lea    D27(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
L38:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L22
  mov    %r12,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L21
  jmp    L43
  nopl   (%rax)
L17:
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jl     L43
L21:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L17
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <test@plt>
  test   %rax,%rax
  je     L17
L43:
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L32
L22:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L38
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
datatype: string
name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D20
datatype: string

tool: D23: %d

tool: D27: %s

tool: D20: %d


assistant: ```c
int main() {
  int T, n, i;
  char s[86];
  scanf("%d", &T);
  while (T--) {
    scanf("%s", s);
    n = strlen(s);
    for (i = 1; i <= n; ++i) {
      if (n % i == 0 && test(s, i, n / i)) {
        break;
      }
    }
    printf("%d\n", i);
    if (T)
      printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _write(int file, char *ptr, int len) {
  switch (file) {
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_write>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _write(int file, char *ptr, int len) {
  switch (file) {
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_write>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _write(int file, char *ptr, int len) {
  switch (file) {
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_write>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _write(int file, char *ptr, int len) {
  switch (file) {
  default:
    errno = EBADF;
    return -1;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sum_primes_under_with_seive2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L41
L55:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L77
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  imul   -0x20(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L17
L46:
  addl   $0x1,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  add    %eax,-0x1c(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L46
L77:
  addl   $0x1,-0x20(%rbp)
L41:
  mov    -0x20(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L55
  movq   $0x2,-0x10(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L34
L10:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L54
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  add    %rax,-0x10(%rbp)
L54:
  addl   $0x1,-0x20(%rbp)
L34:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L10
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9:  better seive method takes %d loops


assistant: ```c
long sum_primes_under_with_seive2(int l) {
  int loops = 0;
  int seive_bound = (l - 1) / 2;
  int *seive = (int *)calloc(seive_bound + 1, sizeof(int));
  const int cross_limit = (floor(sqrt(l)) - 1) / 2;
  int i = 1;
  for (i = 1; i <= cross_limit; i++) {
    if (!seive[i]) {
      int j;
      for (j = 2 * i * (i + 1); j <= seive_bound; j += 2 * i + 1) {
        loops++;
        seive[j] = 1;
      }
    }
  }
  long s = 2;
  for (i = 1; i <= seive_bound; i++) {
    if (!seive[i]) {
      s += 2 * i + 1;
    }
  }
  printf(" better seive method takes %d loops\n", loops);
  free(seive);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_primes_under_with_seive2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  lea    -0x1(%rdi),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  lea    0x1(%rbx),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  lea    -0x1(%rax),%edx
  mov    %edx,%r11d
  shr    $0x1f,%r11d
  add    %edx,%r11d
  sar    %r11d
  cmp    $0x2,%eax
  jle    L17
  lea    0x4(%rbp),%rdi
  mov    $0x3,%r9d
  mov    $0x1,%ecx
  mov    $0x0,%esi
  jmp    L115
L2:
  add    $0x1,%ecx
  add    $0x4,%rdi
  add    $0x2,%r9d
  cmp    %ecx,%r11d
  jl     L99
L115:
  cmpl   $0x0,(%rdi)
  jne    L2
  lea    0x1(%rcx),%eax
  imul   %ecx,%eax
  add    %eax,%eax
  cmp    %eax,%ebx
  jl     L2
  mov    %r9d,%r10d
  movslq %r9d,%r8
  shl    $0x2,%r8
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
L102:
  add    $0x1,%esi
  movl   $0x1,(%rdx)
  add    %r10d,%eax
  add    %r8,%rdx
  cmp    %eax,%ebx
  jge    L102
  jmp    L2
L17:
  mov    $0x0,%esi
L99:
  cmp    $0x2,%r12d
  jle    L30
  lea    0x4(%rbp),%rdx
  mov    $0x3,%ecx
  mov    $0x2,%r12d
  mov    $0x1,%eax
  jmp    L116
L97:
  add    $0x1,%eax
  add    $0x4,%rdx
  add    $0x2,%ecx
  cmp    %eax,%ebx
  jl     L79
L116:
  cmpl   $0x0,(%rdx)
  jne    L97
  movslq %ecx,%rdi
  add    %rdi,%r12
  jmp    L97
L30:
  mov    $0x2,%r12d
L79:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8:  better seive method takes %d loops


assistant: ```c
long sum_primes_under_with_seive2(int l) {
  int loops = 0;
  int seive_bound = (l - 1) / 2;
  int *seive = (int *)calloc(seive_bound + 1, sizeof(int));
  const int cross_limit = (floor(sqrt(l)) - 1) / 2;
  int i = 1;
  for (i = 1; i <= cross_limit; i++) {
    if (!seive[i]) {
      int j;
      for (j = 2 * i * (i + 1); j <= seive_bound; j += 2 * i + 1) {
        loops++;
        seive[j] = 1;
      }
    }
  }
  long s = 2;
  for (i = 1; i <= seive_bound; i++) {
    if (!seive[i]) {
      s += 2 * i + 1;
    }
  }
  printf(" better seive method takes %d loops\n", loops);
  free(seive);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum_primes_under_with_seive2>:
  endbr64
  lea    -0x1(%rdi),%eax
  push   %r12
  mov    $0x4,%esi
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  lea    0x1(%rbx),%edi
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    %rax,%rbp
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  lea    -0x1(%rax),%edx
  mov    %edx,%r10d
  shr    $0x1f,%r10d
  add    %edx,%r10d
  sar    %r10d
  cmp    $0x2,%eax
  jle    L69
  lea    0x4(%rbp),%r8
  mov    $0x3,%ecx
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L116
  nopl   0x0(%rax)
L38:
  add    $0x4,%r8
  add    $0x2,%ecx
  cmp    %edi,%r10d
  jl     L82
L116:
  mov    (%r8),%r9d
  mov    %edi,%eax
  add    $0x1,%edi
  test   %r9d,%r9d
  jne    L38
  imul   %edi,%eax
  add    %eax,%eax
  cmp    %eax,%ebx
  jl     L38
  mov    %ecx,%r9d
  movslq %eax,%rdx
  shl    $0x2,%r9
  lea    0x0(%rbp,%rdx,4),%rdx
  nopl   0x0(%rax)
L36:
  add    %ecx,%eax
  movl   $0x1,(%rdx)
  add    $0x1,%esi
  add    %r9,%rdx
  cmp    %eax,%ebx
  jge    L36
  add    $0x4,%r8
  add    $0x2,%ecx
  cmp    %edi,%r10d
  jge    L116
L82:
  cmp    $0x2,%r12d
  jle    L41
L88:
  lea    0x4(%rbp),%rdx
  mov    $0x3,%ecx
  mov    $0x2,%r12d
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L95:
  mov    (%rdx),%edi
  test   %edi,%edi
  jne    L34
  mov    %ecx,%edi
  add    %rdi,%r12
L34:
  add    $0x1,%eax
  add    $0x4,%rdx
  add    $0x2,%ecx
  cmp    %eax,%ebx
  jge    L95
L12:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L69:
  xor    %esi,%esi
  cmp    $0x2,%r12d
  jg     L88
L41:
  mov    $0x2,%r12d
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4:  better seive method takes %d loops


assistant: ```c
long sum_primes_under_with_seive2(int l) {
  int loops = 0;
  int seive_bound = (l - 1) / 2;
  int *seive = (int *)calloc(seive_bound + 1, sizeof(int));
  const int cross_limit = (floor(sqrt(l)) - 1) / 2;
  int i = 1;
  for (i = 1; i <= cross_limit; i++) {
    if (!seive[i]) {
      int j;
      for (j = 2 * i * (i + 1); j <= seive_bound; j += 2 * i + 1) {
        loops++;
        seive[j] = 1;
      }
    }
  }
  long s = 2;
  for (i = 1; i <= seive_bound; i++) {
    if (!seive[i]) {
      s += 2 * i + 1;
    }
  }
  printf(" better seive method takes %d loops\n", loops);
  free(seive);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%r8d
  mov    %eax,%ecx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D17(%rip),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: bin-%d-%d

assistant: ```c
const char *binname(int a, int b) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "bin-%d-%d", a, b);
  return rv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binname>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  mov    %esi,%r8d
  lea    D13(%rip),%rdx
  mov    $0x20,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: string

tool: D13: bin-%d-%d

assistant: ```c
const char *binname(int a, int b) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "bin-%d-%d", a, b);
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<binname>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  mov    %edi,%ecx
  mov    %esi,%r8d
  mov    %r12,%rdi
  lea    D5(%rip),%rdx
  mov    $0x20,%esi
  call   <snprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5: bin-%d-%d

assistant: ```c
const char *binname(int a, int b) {
  static char rv[32];
  snprintf(rv, sizeof(rv), "bin-%d-%d", a, b);
  return rv;
}
```