ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<KeywordHash_Key>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L4
  add    $0x1,%rdi
  mov    $0x77,%r8d
  xor    %ecx,%ecx
  sub    %edi,%r8d
  jmp    L36
  nopl   0x0(%rax)
L19:
  add    $0x20,%edx
  add    $0x1,%rdi
  movsbl %dl,%edx
  imul   %eax,%edx
  add    %edx,%ecx
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L34
L36:
  lea    -0x41(%rdx),%esi
  lea    (%r8,%rdi,1),%eax
  cmp    $0x19,%sil
  jbe    L19
  imul   %eax,%edx
  add    $0x1,%rdi
  add    %edx,%ecx
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L36
L34:
  mov    %ecx,%eax
  mov    %ecx,%edx
  sar    $0xa,%eax
  sar    $0x14,%edx
  xor    %edx,%eax
  xor    %ecx,%eax
  and    $0x1ff,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int KeywordHash_Key(char *keyword) {
  int register hash, i;
  hash = 0;
  for (i = 0; keyword[i] != '\0'; i++) {
    if (keyword[i] >= 'A' && keyword[i] <= 'Z')
      hash += (keyword[i] + ('a' - 'A')) * (119 + i);
    else
      hash += keyword[i] * (119 + i);
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20)) & (512 - 1);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fclose@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fclose@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void quit() {
  fclose(stdin);
  fclose(stdout);
  fclose(stderr);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quit>:
  endbr64
  sub    $0x8,%rsp
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D20(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void quit() {
  fclose(stdin);
  fclose(stdout);
  fclose(stderr);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quit>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void quit() {
  fclose(stdin);
  fclose(stdout);
  fclose(stderr);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quit>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void quit() {
  fclose(stdin);
  fclose(stdout);
  fclose(stderr);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: %d

assistant: ```c
int main(void) {
  int i = 1;
  printf("%d", !i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
int main(void) {
  int i = 1;
  printf("%d", !i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main(void) {
  int i = 1;
  printf("%d", !i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main(void) {
  int i = 1;
  printf("%d", !i);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add_grey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <extract_grey@plt>
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  movzbl %al,%eax
  mov    $0xff,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <clamp@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <set_grey@plt>
  nop
  leave
  ret
```

assistant: ```c
void add_grey(unsigned char *grey, int i, int amount) {
  unsigned char val = extract_grey(grey, i);
  set_grey(grey, i, clamp(val + amount, 0, 255));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add_grey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <extract_grey@plt>
  lea    (%rax,%r12,1),%edi
  movzbl %dil,%edi
  mov    $0xff,%edx
  mov    $0x0,%esi
  call   <clamp@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <set_grey@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void add_grey(unsigned char *grey, int i, int amount) {
  unsigned char val = extract_grey(grey, i);
  set_grey(grey, i, clamp(val + amount, 0, 255));
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_grey>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <extract_grey@plt>
  mov    $0xff,%edx
  xor    %esi,%esi
  lea    (%rax,%rbx,1),%edi
  movzbl %dil,%edi
  call   <clamp@plt>
  pop    %rbx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <set_grey@plt>
```

assistant: ```c
void add_grey(unsigned char *grey, int i, int amount) {
  unsigned char val = extract_grey(grey, i);
  set_grey(grey, i, clamp(val + amount, 0, 255));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_grey>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <extract_grey@plt>
  mov    $0xff,%edx
  xor    %esi,%esi
  lea    (%rax,%rbx,1),%edi
  movzbl %dil,%edi
  call   <clamp@plt>
  pop    %rbx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1070 <set_grey@plt>
```

assistant: ```c
void add_grey(unsigned char *grey, int i, int amount) {
  unsigned char val = extract_grey(grey, i);
  set_grey(grey, i, clamp(val + amount, 0, 255));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_at_tests_callee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x1c(%rbp)
  movl   $0xb,-0x18(%rbp)
  movl   $0xc,-0x14(%rbp)
  movl   $0x7,-0x10(%rbp)
  movl   $0xd,-0xc(%rbp)
  movl   $0xe,-0x8(%rbp)
  movl   $0xf,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: What is the c source code of the assembly code below:

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ext2_look_up_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L23
  mov    $0x0,%eax
  jmp    L28
L23:
  addq   $0x1,-0x28(%rbp)
  movq   $0x2,-0x18(%rbp)
L62:
  movq   $0x0,-0x10(%rbp)
  jmp    L10
L101:
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L86
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L101
L86:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ext2_find_in_dir@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L28
L2:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  add    %rax,-0x28(%rbp)
  jmp    L62
L64:
  nop
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ext2_find_in_dir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L90
  mov    $0x0,%eax
  jmp    L28
L90:
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
uint32_t ext2_look_up_path(char *path) {
  if (path[0] != '/')
    return 0;
  path++;
  uint32_t curr_dir_inode = 2;
  for (;;) {
    size_t j;
    for (j = 0; path[j] != '/' && path[j] != '\0'; j++)
      ;
    if (path[j] == '\0')
      break;
    path[j] = '\0';
    curr_dir_inode = ext2_find_in_dir(curr_dir_inode, path);
    path[j] = '/';
    if (curr_dir_inode == 0)
      return 0;
    path += j + 1;
  }
  uint32_t inode = ext2_find_in_dir(curr_dir_inode, path);
  if (inode == 0)
    return 0;
  return inode;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ext2_look_up_path>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x2f,(%rdi)
  jne    L31
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbp
  mov    $0x2,%eax
  jmp    L23
L19:
  mov    %rbp,%r12
  mov    $0x0,%ebx
L54:
  test   %dl,%dl
  je     L76
  movb   $0x0,(%r12)
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ext2_find_in_dir@plt>
  movb   $0x2f,(%r12)
  test   %rax,%rax
  je     L77
  lea    0x1(%rbp,%rbx,1),%rbp
L23:
  movzbl 0x0(%rbp),%edx
  cmp    $0x2f,%dl
  je     L19
  test   %dl,%dl
  je     L19
  mov    $0x0,%ebx
L14:
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbx,1),%r12
  movzbl 0x0(%rbp,%rbx,1),%edx
  cmp    $0x2f,%dl
  je     L54
  test   %dl,%dl
  jne    L14
  jmp    L54
L76:
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ext2_find_in_dir@plt>
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  ret
```

assistant: ```c
uint32_t ext2_look_up_path(char *path) {
  if (path[0] != '/')
    return 0;
  path++;
  uint32_t curr_dir_inode = 2;
  for (;;) {
    size_t j;
    for (j = 0; path[j] != '/' && path[j] != '\0'; j++)
      ;
    if (path[j] == '\0')
      break;
    path[j] = '\0';
    curr_dir_inode = ext2_find_in_dir(curr_dir_inode, path);
    path[j] = '/';
    if (curr_dir_inode == 0)
      return 0;
    path += j + 1;
  }
  uint32_t inode = ext2_find_in_dir(curr_dir_inode, path);
  if (inode == 0)
    return 0;
  return inode;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ext2_look_up_path>:
  endbr64
  cmpb   $0x2f,(%rdi)
  je     L33
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L33:
  push   %r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  mov    $0x2,%edi
  push   %rbx
  nopl   (%rax)
L70:
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L75
  cmp    $0x2f,%dl
  je     L75
  xor    %ebx,%ebx
  nop
L6:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edx
  lea    0x0(%rbp,%rbx,1),%r12
  cmp    $0x2f,%dl
  je     L43
  test   %dl,%dl
  jne    L6
L51:
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <ext2_find_in_dir@plt>
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %rbp,%r12
  xor    %ebx,%ebx
  nopl   (%rax)
L43:
  test   %dl,%dl
  je     L51
  movb   $0x0,(%r12)
  mov    %rbp,%rsi
  call   <ext2_find_in_dir@plt>
  movb   $0x2f,(%r12)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L47
  lea    0x1(%rbp,%rbx,1),%rbp
  jmp    L70
L47:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t ext2_look_up_path(char *path) {
  if (path[0] != '/')
    return 0;
  path++;
  uint32_t curr_dir_inode = 2;
  for (;;) {
    size_t j;
    for (j = 0; path[j] != '/' && path[j] != '\0'; j++)
      ;
    if (path[j] == '\0')
      break;
    path[j] = '\0';
    curr_dir_inode = ext2_find_in_dir(curr_dir_inode, path);
    path[j] = '/';
    if (curr_dir_inode == 0)
      return 0;
    path += j + 1;
  }
  uint32_t inode = ext2_find_in_dir(curr_dir_inode, path);
  if (inode == 0)
    return 0;
  return inode;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ext2_look_up_path>:
  endbr64
  cmpb   $0x2f,(%rdi)
  je     L33
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L33:
  push   %r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  mov    $0x2,%edi
  push   %rbx
  nopl   (%rax)
L32:
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L49
  cmp    $0x2f,%dl
  je     L49
  xor    %ebx,%ebx
  nop
L66:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edx
  lea    0x0(%rbp,%rbx,1),%r12
  cmp    $0x2f,%dl
  je     L13
  test   %dl,%dl
  jne    L66
L69:
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <ext2_find_in_dir@plt>
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %rbp,%r12
  xor    %ebx,%ebx
  nopl   (%rax)
L13:
  test   %dl,%dl
  je     L69
  movb   $0x0,(%r12)
  mov    %rbp,%rsi
  call   <ext2_find_in_dir@plt>
  movb   $0x2f,(%r12)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L72
  lea    0x1(%rbp,%rbx,1),%rbp
  jmp    L32
L72:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t ext2_look_up_path(char *path) {
  if (path[0] != '/')
    return 0;
  path++;
  uint32_t curr_dir_inode = 2;
  for (;;) {
    size_t j;
    for (j = 0; path[j] != '/' && path[j] != '\0'; j++)
      ;
    if (path[j] == '\0')
      break;
    path[j] = '\0';
    curr_dir_inode = ext2_find_in_dir(curr_dir_inode, path);
    path[j] = '/';
    if (curr_dir_inode == 0)
      return 0;
    path += j + 1;
  }
  uint32_t inode = ext2_find_in_dir(curr_dir_inode, path);
  if (inode == 0)
    return 0;
  return inode;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isValidIpv4Address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <inet_pton@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L47
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidIpv6Address@plt>
  cmp    $0x1,%eax
  jne    L64
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  jmp    L38
L64:
  mov    $0x0,%eax
  jmp    L38
L47:
  cmpl   $0x1,-0xc(%rbp)
  jne    L29
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  jmp    L38
L29:
  mov    -0xc(%rbp),%eax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int isValidIpv4Address(char *ipAddress) {
  struct sockaddr_in sa;
  int result = inet_pton(AF_INET, ipAddress, &(sa.sin_addr));
  if (result == 0) {
    if (isValidIpv6Address(ipAddress) == 1)
      return AF_INET6;
    else
      return 0;
  }
  if (result == 1)
    return AF_INET;
  else
    return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<isValidIpv4Address>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rdi,%rsi
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <inet_pton@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L2
  cmp    $0x1,%eax
  je     L17
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rbp,%rdi
  call   <isValidIpv6Address@plt>
  cmp    $0x1,%eax
  jne    L22
  mov    D20(%rip),%rax
  mov    (%rax),%ebx
  jmp    L22
L17:
  mov    D28(%rip),%rax
  mov    (%rax),%ebx
  jmp    L22
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isValidIpv4Address(char *ipAddress) {
  struct sockaddr_in sa;
  int result = inet_pton(AF_INET, ipAddress, &(sa.sin_addr));
  if (result == 0) {
    if (isValidIpv6Address(ipAddress) == 1)
      return AF_INET6;
    else
      return 0;
  }
  if (result == 1)
    return AF_INET;
  else
    return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValidIpv4Address>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D19(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    (%rbx),%edi
  call   <inet_pton@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L30
  cmp    $0x1,%eax
  je     L10
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  mov    (%rbx),%r12d
  jmp    L4
  nopl   (%rax)
L30:
  mov    %rbp,%rdi
  call   <isValidIpv6Address@plt>
  cmp    $0x1,%eax
  jne    L4
  mov    D0(%rip),%rax
  mov    (%rax),%r12d
  jmp    L4
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isValidIpv4Address(char *ipAddress) {
  struct sockaddr_in sa;
  int result = inet_pton(AF_INET, ipAddress, &(sa.sin_addr));
  if (result == 0) {
    if (isValidIpv6Address(ipAddress) == 1)
      return AF_INET6;
    else
      return 0;
  }
  if (result == 1)
    return AF_INET;
  else
    return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<isValidIpv4Address>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D9(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    (%rbx),%edi
  call   <inet_pton@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L44
  cmp    $0x1,%eax
  je     L35
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L35:
  mov    (%rbx),%r12d
  jmp    L54
  nopl   (%rax)
L44:
  mov    %rbp,%rdi
  call   <isValidIpv6Address@plt>
  cmp    $0x1,%eax
  jne    L54
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
  jmp    L54
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isValidIpv4Address(char *ipAddress) {
  struct sockaddr_in sa;
  int result = inet_pton(AF_INET, ipAddress, &(sa.sin_addr));
  if (result == 0) {
    if (isValidIpv6Address(ipAddress) == 1)
      return AF_INET6;
    else
      return 0;
  }
  if (result == 1)
    return AF_INET;
  else
    return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GetEnvVarFmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  movl   $0x0,-0xc0(%rbp)
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <GetEnvVar@plt>
  mov    %rax,-0xb8(%rbp)
  cmpq   $0x0,-0xb8(%rbp)
  je     L8
  mov    -0xd0(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xb8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsscanf@plt>
  mov    %eax,-0xc0(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
L8:
  mov    -0xc0(%rbp),%eax
  leave
  ret
```

assistant: ```c
int GetEnvVarFmt(const char *name, const char *fmt, ...) {
  int cnt = 0;
  const char *s = GetEnvVar(name);
  if (s) {
    va_list args;
    va_start(args, fmt);
    cnt = vsscanf(s, fmt, args);
    va_end(args);
  }
  return cnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetEnvVarFmt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <GetEnvVar@plt>
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsscanf@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <va_end@plt>
L8:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int GetEnvVarFmt(const char *name, const char *fmt, ...) {
  int cnt = 0;
  const char *s = GetEnvVar(name);
  if (s) {
    va_list args;
    va_start(args, fmt);
    cnt = vsscanf(s, fmt, args);
    va_end(args);
  }
  return cnt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GetEnvVarFmt>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <GetEnvVar@plt>
  test   %rax,%rax
  je     L0
  xor    %r14d,%r14d
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <vsscanf@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
L0:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int GetEnvVarFmt(const char *name, const char *fmt, ...) {
  int cnt = 0;
  const char *s = GetEnvVar(name);
  if (s) {
    va_list args;
    va_start(args, fmt);
    cnt = vsscanf(s, fmt, args);
    va_end(args);
  }
  return cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GetEnvVarFmt>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <GetEnvVar@plt>
  test   %rax,%rax
  je     L8
  xor    %r14d,%r14d
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <vsscanf@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
L8:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int GetEnvVarFmt(const char *name, const char *fmt, ...) {
  int cnt = 0;
  const char *s = GetEnvVar(name);
  if (s) {
    va_list args;
    va_start(args, fmt);
    cnt = vsscanf(s, fmt, args);
    va_end(args);
  }
  return cnt;
}
```