ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<qsort_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L24
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap_my@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L14:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L33
  addl   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap_my@plt>
L33:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L14
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap_my@plt>
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort_my>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort_my>
  jmp    L34
L24:
  nop
L34:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: in qsort .


assistant: ```c
void qsort_my(char *v[], int left, int right) {
  int i = 0;
  int j = 0;
  int last = 0;
  if (left > right)
    return;
  printf("in qsort .\n");
  swap_my(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap_my(v, ++last, i);
  swap_my(v, left, last);
  qsort_my(v, left, last - 1);
  qsort_my(v, last + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<qsort_my>:
  endbr64
  cmp    %edx,%esi
  jle    L44
  ret
L44:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x0(%r13,%r12,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap_my@plt>
  lea    0x1(%r13),%ebx
  cmp    %ebx,%r12d
  jl     L26
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,8),%r15
  movslq %ebx,%rbx
  mov    %r13d,%r14d
  jmp    L34
L37:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L33
L34:
  mov    %ebx,0xc(%rsp)
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    (%r15),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L37
  add    $0x1,%r14d
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap_my@plt>
  jmp    L37
L26:
  mov    %r13d,%r14d
L33:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap_my@plt>
  lea    -0x1(%r14),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <qsort_my>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <qsort_my>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: in qsort .


assistant: ```c
void qsort_my(char *v[], int left, int right) {
  int i = 0;
  int j = 0;
  int last = 0;
  if (left > right)
    return;
  printf("in qsort .\n");
  swap_my(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap_my(v, ++last, i);
  swap_my(v, left, last);
  qsort_my(v, left, last - 1);
  qsort_my(v, last + 1, right);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort_my>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L63:
  cmp    %ebp,%r14d
  jg     L61
L12:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap_my@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L56
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L70
L62:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L17
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <swap_my@plt>
  cmp    %r15d,%ebp
  jge    L62
L70:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap_my@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <qsort_my>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jle    L12
L61:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <swap_my@plt>
  jmp    L63
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: in qsort .


assistant: ```c
void qsort_my(char *v[], int left, int right) {
  int i = 0;
  int j = 0;
  int last = 0;
  if (left > right)
    return;
  printf("in qsort .\n");
  swap_my(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap_my(v, ++last, i);
  swap_my(v, left, last);
  qsort_my(v, left, last - 1);
  qsort_my(v, last + 1, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qsort_my>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L61:
  cmp    %ebp,%r14d
  jg     L16
L19:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap_my@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L53
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L73
L9:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L44
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <swap_my@plt>
  cmp    %r15d,%ebp
  jge    L9
L73:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap_my@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <qsort_my>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jle    L19
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <swap_my@plt>
  jmp    L61
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: in qsort .


assistant: ```c
void qsort_my(char *v[], int left, int right) {
  int i = 0;
  int j = 0;
  int last = 0;
  if (left > right)
    return;
  printf("in qsort .\n");
  swap_my(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap_my(v, ++last, i);
  swap_my(v, left, last);
  qsort_my(v, left, last - 1);
  qsort_my(v, last + 1, right);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <jc@plt>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <jc@plt>
  imul   %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <jc@plt>
  mov    %eax,%edi
  lea    -0x20(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    %ebx,%esi
  call   <LLdivLL@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int c(int p, int q) {
  long long x;
  LLdivLL(jc(p), (jc(q) * jc(p - q)), &x, NULL);
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<c>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%edi
  call   <jc@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  sub    %r12d,%edi
  call   <jc@plt>
  imul   %eax,%ebx
  mov    %ebp,%edi
  call   <jc@plt>
  mov    %eax,%edi
  mov    %rsp,%rdx
  mov    $0x0,%ecx
  mov    %ebx,%esi
  call   <LLdivLL@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int c(int p, int q) {
  long long x;
  LLdivLL(jc(p), (jc(q) * jc(p - q)), &x, NULL);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<c>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <jc@plt>
  mov    %ebp,%edi
  sub    %r12d,%edi
  mov    %eax,%ebx
  call   <jc@plt>
  mov    %ebp,%edi
  imul   %eax,%ebx
  call   <jc@plt>
  mov    %rsp,%rdx
  xor    %ecx,%ecx
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <LLdivLL@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int c(int p, int q) {
  long long x;
  LLdivLL(jc(p), (jc(q) * jc(p - q)), &x, NULL);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <jc@plt>
  mov    %ebp,%edi
  sub    %r12d,%edi
  mov    %eax,%ebx
  call   <jc@plt>
  mov    %ebp,%edi
  imul   %eax,%ebx
  call   <jc@plt>
  mov    %rsp,%rdx
  xor    %ecx,%ecx
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <LLdivLL@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int c(int p, int q) {
  long long x;
  LLdivLL(jc(p), (jc(q) * jc(p - q)), &x, NULL);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DoStrTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x120(%rbp),%rcx
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <_snprintf@plt>
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L4
  lea    -0x110(%rbp),%rsi
  mov    -0x128(%rbp),%rcx
  mov    -0x118(%rbp),%rdx
  mov    -0x120(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <Fail@plt>
L4:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: ERROR: failed to insert string "%s" into "%s"
Expected "%s" got "%s".


assistant: ```c
void DoStrTest(char *formatstr, char *param, char *checkstr) {
  char buf[256] = {0};
  _snprintf(buf, 256, formatstr, param);
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: failed to insert string \"%s\" into \"%s\"\n"
         "Expected \"%s\" got \"%s\".\n",
         param, formatstr, checkstr, buf);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DoStrTest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  mov    %rsp,%r13
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    $0x100,%esi
  mov    %r13,%rdi
  call   <_snprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L7
L9:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %rsp,%r8
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <Fail@plt>
  jmp    L9
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: ERROR: failed to insert string "%s" into "%s"
Expected "%s" got "%s".


assistant: ```c
void DoStrTest(char *formatstr, char *param, char *checkstr) {
  char buf[256] = {0};
  _snprintf(buf, 256, formatstr, param);
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: failed to insert string \"%s\" into \"%s\"\n"
         "Expected \"%s\" got \"%s\".\n",
         param, formatstr, checkstr, buf);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DoStrTest>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rsi,%rcx
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rdi,%rdx
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x100,%esi
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  call   <_snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L3
L6:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <Fail@plt>
  jmp    L6
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: ERROR: failed to insert string "%s" into "%s"
Expected "%s" got "%s".


assistant: ```c
void DoStrTest(char *formatstr, char *param, char *checkstr) {
  char buf[256] = {0};
  _snprintf(buf, 256, formatstr, param);
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: failed to insert string \"%s\" into \"%s\"\n"
         "Expected \"%s\" got \"%s\".\n",
         param, formatstr, checkstr, buf);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DoStrTest>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rsi,%rcx
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rdi,%rdx
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x100,%esi
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  call   <_snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L12
L20:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <Fail@plt>
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: ERROR: failed to insert string "%s" into "%s"
Expected "%s" got "%s".


assistant: ```c
void DoStrTest(char *formatstr, char *param, char *checkstr) {
  char buf[256] = {0};
  _snprintf(buf, 256, formatstr, param);
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: failed to insert string \"%s\" into \"%s\"\n"
         "Expected \"%s\" got \"%s\".\n",
         param, formatstr, checkstr, buf);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<emptydir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L43
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L43
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L43
  addq   $0x1,-0x10(%rbp)
L43:
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  cmpq   $0x0,-0x10(%rbp)
  je     L23
L38:
  cmpq   $0x0,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string

tool: D14: .

tool: D6: ..

assistant: ```c
int emptydir(DIR *dp) {
  struct dirent *entry;
  size_t files = 0;
  do {
    entry = readdir(dp);
    if (entry != NULL && strcmp(entry->d_name, ".") && strcmp(entry->d_name, ".."))
      files++;
  } while (entry != NULL && files == 0);
  return !files;
}
```
user: Translate the below assembly code into C programming language:

```asm
<emptydir>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D7(%rip),%r12
  lea    D17(%rip),%r13
  jmp    L44
L11:
  mov    %r13,%rsi
  mov    (%rbx),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
L44:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L44
  jmp    L11
L14:
  mov    $0x1,%eax
L36:
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  jmp    L36
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D7: .

tool: D17: ..

assistant: ```c
int emptydir(DIR *dp) {
  struct dirent *entry;
  size_t files = 0;
  do {
    entry = readdir(dp);
    if (entry != NULL && strcmp(entry->d_name, ".") && strcmp(entry->d_name, ".."))
      files++;
  } while (entry != NULL && files == 0);
  return !files;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emptydir>:
  endbr64
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L22:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
  mov    (%rax),%edi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string

tool: D12: ..

tool: D9: .

assistant: ```c
int emptydir(DIR *dp) {
  struct dirent *entry;
  size_t files = 0;
  do {
    entry = readdir(dp);
    if (entry != NULL && strcmp(entry->d_name, ".") && strcmp(entry->d_name, ".."))
      files++;
  } while (entry != NULL && files == 0);
  return !files;
}
```