ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_letters>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L36
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  jmp    L19
  nopl   (%rax)
L13:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L42
L19:
  movsbl %sil,%ebp
  mov    %ebp,%edi
  call   <can_print_it@plt>
  test   %rax,%rax
  je     L13
  mov    %ebp,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L19
L42:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax)
L36:
  mov    $0xa,%edi
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: '%c' == %d 

assistant: ```c
void print_letters(char arg[]) {
  int i = 0;
  for (i = 0; arg[i] != '\0'; i++) {
    char ch = arg[i];
    if (can_print_it(ch)) {
      printf("'%c' == %d ", ch, ch);
    }
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_letters>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L23
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %sil,%ebp
  mov    %ebp,%edi
  call   <can_print_it@plt>
  test   %rax,%rax
  jne    L13
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L17
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebp,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  jne    L17
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0xa,%edi
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: '%c' == %d 

assistant: ```c
void print_letters(char arg[]) {
  int i = 0;
  for (i = 0; arg[i] != '\0'; i++) {
    char ch = arg[i];
    if (can_print_it(ch)) {
      printf("'%c' == %d ", ch, ch);
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bench>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x1c(%rsp)
  movb   $0x0,0x1b(%rsp)
  lea    0x50(%rsp),%rbp
  mov    %edi,%edx
  lea    D57(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm7,%xmm7
  cvtsi2sd %ebx,%xmm7
  movq   %xmm7,%r14
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  test   %ebx,%ebx
  jle    L5
  lea    0x40(%rsp),%r13
L20:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  lea    0x38(%rsp),%rbp
L8:
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    0x30(%rsp),%rdx
  push   %r12
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x2b(%rsp),%rax
  push   %rax
  lea    0x40(%rsp),%rax
  push   %rax
  lea    0x40(%rsp),%rax
  push   %rax
  lea    0x70(%rsp),%rax
  push   %rax
  mov    D49(%rip),%rax
  movq   %rax,%xmm2
  mov    %r13,%r9
  mov    $0x32,%r8d
  mov    %rbp,%rcx
  movsd  0x38(%rsp),%xmm1
  movsd  0x30(%rsp),%xmm0
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <hotLoop@plt>
  movsd  D43(%rip),%xmm3
  addsd  0x30(%rsp),%xmm3
  movsd  %xmm3,0x30(%rsp)
  add    $0x30,%rsp
  movq   %r14,%xmm5
  comisd %xmm3,%xmm5
  ja     L8
  movsd  D43(%rip),%xmm6
  addsd  0x8(%rsp),%xmm6
  movsd  %xmm6,0x8(%rsp)
  comisd %xmm6,%xmm5
  ja     L20
L5:
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D57
datatype: string
name: read_data
arguments: data_label: D32
datatype: string
name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D49
datatype: f64
name: read_data
arguments: data_label: D43
datatype: f32[2]

tool: D57: mandelbrot-%d.txt

tool: D32: w+

tool: D9: P4
%d %d


tool: D49: 2

tool: {"D43": [0.0,1.875]}

assistant: ```c
int bench(int inputN) {
  int w, h, bit_num = 0;
  char byte_acc = 0;
  int iter = 50;
  double x, y, limit = 2.0;
  double Zr, Zi, Cr, Ci, Tr, Ti;
  w = h = inputN;
  char filename[64];
  sprintf(filename, "mandelbrot-%d.txt", w);
  FILE *outStream = fopen(filename, "w+");
  printf("P4\n%d %d\n", w, h);
  for (y = 0; y < h; ++y) {
    for (x = 0; x < w; ++x) {
      Zr = Zi = Tr = Ti = 0.0;
      hotLoop(w, h, x, y, &Cr, &Ci, iter, &Tr, &Ti, limit, &Zr, &Zi, &byte_acc, &bit_num, outStream);
    }
  }
  fclose(outStream);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bench>:
  endbr64
  push   %r15
  mov    %edi,%edx
  lea    D42(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  movl   $0x0,0x4c(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x4b(%rsp)
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  lea    D57(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  pxor   %xmm5,%xmm5
  cvtsi2sd %r12d,%xmm5
  movsd  %xmm5,0x18(%rsp)
  test   %r12d,%r12d
  jle    L24
  lea    0x4c(%rsp),%rax
  lea    0x70(%rsp),%rbx
  pxor   %xmm1,%xmm1
  mov    %rax,0x30(%rsp)
  lea    0x4b(%rsp),%rax
  lea    0x68(%rsp),%r14
  mov    %rax,0x28(%rsp)
  lea    0x50(%rsp),%rax
  lea    0x60(%rsp),%r13
  mov    %rax,0x38(%rsp)
  lea    0x78(%rsp),%rax
  lea    0x58(%rsp),%r15
  mov    %rax,0x20(%rsp)
  mov    %rbx,%rax
  mov    %r12d,%ebx
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r12,%rax
  pxor   %xmm0,%xmm0
  mov    %r13,%r12
  mov    %r14,%r13
  mov    %rax,%r14
L23:
  movq   $0x0,0x78(%rsp)
  mov    %r14,%r9
  mov    %ebx,%esi
  mov    %ebx,%edi
  movq   $0x0,0x70(%rsp)
  mov    $0x32,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  movq   $0x0,0x58(%rsp)
  mov    D25(%rip),%rax
  movq   $0x0,0x50(%rsp)
  push   %rbp
  movq   %rax,%xmm2
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   %r15
  push   0x58(%rsp)
  push   0x48(%rsp)
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm1,0x40(%rsp)
  call   <hotLoop@plt>
  movsd  0x38(%rsp),%xmm0
  add    $0x30,%rsp
  addsd  D45(%rip),%xmm0
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm3
  ja     L23
  addsd  D45(%rip),%xmm1
  mov    %r14,%rax
  mov    %r13,%r14
  mov    %r12,%r13
  mov    %rax,%r12
  comisd %xmm1,%xmm3
  ja     L4
L24:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D42
datatype: string
name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D57
datatype: string
name: read_data
arguments: data_label: D25
datatype: f64
name: read_data
arguments: data_label: D45
datatype: f32[2]

tool: D42: mandelbrot-%d.txt

tool: D12: w+

tool: D57: P4
%d %d


tool: D25: 2

tool: {"D45": [0.0,1.875]}

assistant: ```c
int bench(int inputN) {
  int w, h, bit_num = 0;
  char byte_acc = 0;
  int iter = 50;
  double x, y, limit = 2.0;
  double Zr, Zi, Cr, Ci, Tr, Ti;
  w = h = inputN;
  char filename[64];
  sprintf(filename, "mandelbrot-%d.txt", w);
  FILE *outStream = fopen(filename, "w+");
  printf("P4\n%d %d\n", w, h);
  for (y = 0; y < h; ++y) {
    for (x = 0; x < w; ++x) {
      Zr = Zi = Tr = Ti = 0.0;
      hotLoop(w, h, x, y, &Cr, &Ci, iter, &Tr, &Ti, limit, &Zr, &Zi, &byte_acc, &bit_num, outStream);
    }
  }
  fclose(outStream);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bench>:
  endbr64
  push   %r15
  mov    %edi,%edx
  lea    D0(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  movl   $0x0,0x4c(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x4b(%rsp)
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    D52(%rip),%rsi
  call   <fopen@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  pxor   %xmm5,%xmm5
  cvtsi2sd %r12d,%xmm5
  movsd  %xmm5,0x18(%rsp)
  test   %r12d,%r12d
  jle    L11
  lea    0x4c(%rsp),%rax
  lea    0x70(%rsp),%rbx
  pxor   %xmm1,%xmm1
  mov    %rax,0x30(%rsp)
  lea    0x4b(%rsp),%rax
  lea    0x68(%rsp),%r14
  mov    %rax,0x28(%rsp)
  lea    0x50(%rsp),%rax
  lea    0x60(%rsp),%r13
  mov    %rax,0x38(%rsp)
  lea    0x78(%rsp),%rax
  lea    0x58(%rsp),%r15
  mov    %rax,0x20(%rsp)
  mov    %rbx,%rax
  mov    %r12d,%ebx
  mov    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r12,%rax
  pxor   %xmm0,%xmm0
  mov    %r13,%r12
  mov    %r14,%r13
  mov    %rax,%r14
L38:
  movq   $0x0,0x78(%rsp)
  mov    %r14,%r9
  mov    %ebx,%esi
  mov    %ebx,%edi
  movq   $0x0,0x70(%rsp)
  mov    $0x32,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  movq   $0x0,0x58(%rsp)
  mov    D36(%rip),%rax
  movq   $0x0,0x50(%rsp)
  push   %rbp
  movq   %rax,%xmm2
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   %r15
  push   0x58(%rsp)
  push   0x48(%rsp)
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm1,0x40(%rsp)
  call   <hotLoop@plt>
  movsd  0x38(%rsp),%xmm0
  add    $0x30,%rsp
  addsd  D28(%rip),%xmm0
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm3
  ja     L38
  addsd  D28(%rip),%xmm1
  mov    %r14,%rax
  mov    %r13,%r14
  mov    %r12,%r13
  mov    %rax,%r12
  comisd %xmm1,%xmm3
  ja     L37
L11:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D52
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D36
type: f64
name: unpack_data
arguments: label: D28
type: f32[2]

tool: D0: mandelbrot-%d.txt

tool: D52: w+

tool: D16: P4
%d %d


tool: D36: 2

tool: {"D28": [0.0,1.875]}

assistant: ```c
int bench(int inputN) {
  int w, h, bit_num = 0;
  char byte_acc = 0;
  int iter = 50;
  double x, y, limit = 2.0;
  double Zr, Zi, Cr, Ci, Tr, Ti;
  w = h = inputN;
  char filename[64];
  sprintf(filename, "mandelbrot-%d.txt", w);
  FILE *outStream = fopen(filename, "w+");
  printf("P4\n%d %d\n", w, h);
  for (y = 0; y < h; ++y) {
    for (x = 0; x < w; ++x) {
      Zr = Zi = Tr = Ti = 0.0;
      hotLoop(w, h, x, y, &Cr, &Ci, iter, &Tr, &Ti, limit, &Zr, &Zi, &byte_acc, &bit_num, outStream);
    }
  }
  fclose(outStream);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L56:
  addl   $0x1,-0x8(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L62
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L34
L62:
  cmpl   $0x20,-0x4(%rbp)
  jne    L33
  addl   $0x1,-0xc(%rbp)
  jmp    L34
L33:
  cmpl   $0xa,-0x8(%rbp)
  jle    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <print_blank@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
L34:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L56
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int cur_char;
  int cur_blanks_len;
  int cur_line_len;
  cur_blanks_len = 0;
  cur_line_len = 0;
  while ((cur_char = getchar()) != EOF) {
    cur_line_len++;
    if (cur_char == '\n') {
      cur_line_len = 0;
      cur_blanks_len = 0;
      putchar(cur_char);
    } else if (cur_char == ' ') {
      cur_blanks_len++;
    } else {
      if (cur_line_len > 10) {
        putchar('\n');
        cur_blanks_len = 0;
        cur_line_len = 1;
      }
      print_blank(cur_blanks_len);
      putchar(cur_char);
      cur_blanks_len = 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L15
L69:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L15
L70:
  add    $0x1,%r12d
  jmp    L15
L68:
  mov    %r12d,%edi
  call   <print_blank@plt>
  mov    %ebx,%edi
  call   <putchar@plt>
  mov    $0x0,%r12d
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D2(%rip),%rax
  cmp    %ebx,(%rax)
  je     L79
  add    $0x1,%ebp
  cmp    $0xa,%ebx
  je     L69
  cmp    $0x20,%ebx
  je     L70
  cmp    $0xa,%ebp
  jle    L68
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%ebp
  mov    $0x0,%r12d
  jmp    L68
L79:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int cur_char;
  int cur_blanks_len;
  int cur_line_len;
  cur_blanks_len = 0;
  cur_line_len = 0;
  while ((cur_char = getchar()) != EOF) {
    cur_line_len++;
    if (cur_char == '\n') {
      cur_line_len = 0;
      cur_blanks_len = 0;
      putchar(cur_char);
    } else if (cur_char == ' ') {
      cur_blanks_len++;
    } else {
      if (cur_line_len > 10) {
        putchar('\n');
        cur_blanks_len = 0;
        cur_line_len = 1;
      }
      print_blank(cur_blanks_len);
      putchar(cur_char);
      cur_blanks_len = 0;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D3(%rip),%r13
L28:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  je     L49
L30:
  add    $0x1,%ebx
  cmp    $0xa,%ebp
  je     L50
  cmp    $0x20,%ebp
  je     L53
  cmp    $0xa,%ebx
  jg     L19
L59:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <print_blank@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  jne    L30
L49:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L53:
  add    $0x1,%r12d
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L28
  nopl   0x0(%rax)
L19:
  mov    $0xa,%edi
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L59
```

assistant: ```c
int main(void) {
  int cur_char;
  int cur_blanks_len;
  int cur_line_len;
  cur_blanks_len = 0;
  cur_line_len = 0;
  while ((cur_char = getchar()) != EOF) {
    cur_line_len++;
    if (cur_char == '\n') {
      cur_line_len = 0;
      cur_blanks_len = 0;
      putchar(cur_char);
    } else if (cur_char == ' ') {
      cur_blanks_len++;
    } else {
      if (cur_line_len > 10) {
        putchar('\n');
        cur_blanks_len = 0;
        cur_line_len = 1;
      }
      print_blank(cur_blanks_len);
      putchar(cur_char);
      cur_blanks_len = 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D1(%rip),%r13
L52:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  je     L72
L18:
  add    $0x1,%ebx
  cmp    $0xa,%ebp
  je     L49
  cmp    $0x20,%ebp
  je     L33
  cmp    $0xa,%ebx
  jg     L30
L31:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <print_blank@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  jne    L18
L72:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  add    $0x1,%r12d
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L52
  nopl   0x0(%rax)
L30:
  mov    $0xa,%edi
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L31
```

assistant: ```c
int main(void) {
  int cur_char;
  int cur_blanks_len;
  int cur_line_len;
  cur_blanks_len = 0;
  cur_line_len = 0;
  while ((cur_char = getchar()) != EOF) {
    cur_line_len++;
    if (cur_char == '\n') {
      cur_line_len = 0;
      cur_blanks_len = 0;
      putchar(cur_char);
    } else if (cur_char == ' ') {
      cur_blanks_len++;
    } else {
      if (cur_line_len > 10) {
        putchar('\n');
        cur_blanks_len = 0;
        cur_line_len = 1;
      }
      print_blank(cur_blanks_len);
      putchar(cur_char);
      cur_blanks_len = 0;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  double x = ceil(2.4);
  if (fabs(x) - 3.0 < 0.01)
    return EXIT_SUCCESS;
  return EXIT_FAILURE;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  double x = ceil(2.4);
  if (fabs(x) - 3.0 < 0.01)
    return EXIT_SUCCESS;
  return EXIT_FAILURE;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  double x = ceil(2.4);
  if (fabs(x) - 3.0 < 0.01)
    return EXIT_SUCCESS;
  return EXIT_FAILURE;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<DCSMGrabRAMBlocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x20001c,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x4fffe0,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DCSMGrabRAMBlocks(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x0000001C)));
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFE0)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DCSMGrabRAMBlocks>:
  endbr64
  mov    0x20001c,%rax
  mov    %rax,-0x8(%rsp)
  mov    0x4fffe0,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMGrabRAMBlocks(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x0000001C)));
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFE0)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DCSMGrabRAMBlocks>:
  endbr64
  mov    0x20001c,%rax
  mov    %rax,-0x8(%rsp)
  mov    0x4fffe0,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMGrabRAMBlocks(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x0000001C)));
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFE0)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<DCSMGrabRAMBlocks>:
  endbr64
  mov    0x20001c,%rax
  mov    %rax,-0x8(%rsp)
  mov    0x4fffe0,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMGrabRAMBlocks(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x0000001C)));
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFE0)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<util_set_fd_cloexec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L14:
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  or     %eax,-0x4(%rbp)
L1:
  mov    D18(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  nop
  leave
  ret
```

assistant: ```c
void util_set_fd_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  if (flags < 0)
    flags = FD_CLOEXEC;
  else
    flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<util_set_fd_cloexec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L16
  mov    D24(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
L17:
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  pop    %rbx
  ret
L16:
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  jmp    L17
```

assistant: ```c
void util_set_fd_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  if (flags < 0)
    flags = FD_CLOEXEC;
  else
    flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<util_set_fd_cloexec>:
  endbr64
  mov    D17(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L0
  mov    D10(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
L9:
  mov    D31(%rip),%rax
  mov    %ebp,%edi
  pop    %rbp
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
  nopl   0x0(%rax)
L0:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  jmp    L9
```

assistant: ```c
void util_set_fd_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  if (flags < 0)
    flags = FD_CLOEXEC;
  else
    flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<util_set_fd_cloexec>:
  endbr64
  mov    D31(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L17
  mov    D9(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
L4:
  mov    D26(%rip),%rax
  mov    %ebp,%edi
  pop    %rbp
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1050 <fcntl@plt>
  nopl   0x0(%rax)
L17:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  jmp    L4
```

assistant: ```c
void util_set_fd_cloexec(int fd) {
  int flags;
  flags = fcntl(fd, F_GETFD);
  if (flags < 0)
    flags = FD_CLOEXEC;
  else
    flags |= FD_CLOEXEC;
  fcntl(fd, F_SETFD, flags);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EverySoOften>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L64
  cmpl   $0x0,-0x8(%rbp)
  jns    L51
L64:
  mov    $0xffffffff,%eax
  jmp    L35
L51:
  cmpl   $0x0,-0x8(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L35
L37:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L14
  mov    $0x1,%eax
  jmp    L35
L14:
  mov    $0x0,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int EverySoOften(int frameNum, int HowOften) {
  if (frameNum < 0 || HowOften < 0)
    return -1;
  if (HowOften == 0)
    return 0;
  if ((frameNum % HowOften) == 0) {
    return 1;
  }
  return 0;
}
```