ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fc8300_ppi_longwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x24(%rbp)
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movw   $0x4,-0x2(%rbp)
  movb   $0x80,-0x3(%rbp)
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl -0x20(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    $0x0,%eax
  mov    %dl,(%rax)
  mov    $0x0,%eax
  movzwl -0x20(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%edx
  movzbl -0x3(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x0,%eax
  movzwl -0x2(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
  mov    -0x24(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    $0x0,%eax
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    $0x0,%eax
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    $0x0,%eax
  mov    %dl,(%rax)
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fc8300_ppi_longwrite(void *handle, unsigned short devid, unsigned short addr, unsigned int data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x00;
  OAL_OBTAIN_SEMAPHORE();
  (*(volatile unsigned char *)0x00) = (addr & 0xff00) >> 8;
  (*(volatile unsigned char *)0x00) = addr & 0xff;
  (*(volatile unsigned char *)0x00) = command;
  (*(volatile unsigned char *)0x00) = length & 0xff;
  (*(volatile unsigned char *)0x00) = data & 0x000000ff;
  (*(volatile unsigned char *)0x00) = (data & 0x0000ff00) >> 8;
  (*(volatile unsigned char *)0x00) = (data & 0x00ff0000) >> 16;
  (*(volatile unsigned char *)0x00) = (data & 0xff000000) >> 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fc8300_ppi_longwrite>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  mov    %ebp,%eax
  shr    $0x8,%ax
  mov    %al,0x0
  mov    %bpl,0x0
  movb   $0x80,0x0
  movb   $0x4,0x0
  mov    %bl,0x0
  mov    %ebx,%eax
  shr    $0x8,%eax
  mov    %al,0x0
  mov    %ebx,%eax
  shr    $0x10,%eax
  mov    %al,0x0
  shr    $0x18,%ebx
  mov    %bl,0x0
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_longwrite(void *handle, unsigned short devid, unsigned short addr, unsigned int data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x00;
  OAL_OBTAIN_SEMAPHORE();
  (*(volatile unsigned char *)0x00) = (addr & 0xff00) >> 8;
  (*(volatile unsigned char *)0x00) = addr & 0xff;
  (*(volatile unsigned char *)0x00) = command;
  (*(volatile unsigned char *)0x00) = length & 0xff;
  (*(volatile unsigned char *)0x00) = data & 0x000000ff;
  (*(volatile unsigned char *)0x00) = (data & 0x0000ff00) >> 8;
  (*(volatile unsigned char *)0x00) = (data & 0x00ff0000) >> 16;
  (*(volatile unsigned char *)0x00) = (data & 0xff000000) >> 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fc8300_ppi_longwrite>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movb   $0x0,0x0
  ud2
```

assistant: ```c
int fc8300_ppi_longwrite(void *handle, unsigned short devid, unsigned short addr, unsigned int data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x00;
  OAL_OBTAIN_SEMAPHORE();
  (*(volatile unsigned char *)0x00) = (addr & 0xff00) >> 8;
  (*(volatile unsigned char *)0x00) = addr & 0xff;
  (*(volatile unsigned char *)0x00) = command;
  (*(volatile unsigned char *)0x00) = length & 0xff;
  (*(volatile unsigned char *)0x00) = data & 0x000000ff;
  (*(volatile unsigned char *)0x00) = (data & 0x0000ff00) >> 8;
  (*(volatile unsigned char *)0x00) = (data & 0x00ff0000) >> 16;
  (*(volatile unsigned char *)0x00) = (data & 0xff000000) >> 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fc8300_ppi_longwrite>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movb   $0x0,0x0
  ud2
```

assistant: ```c
int fc8300_ppi_longwrite(void *handle, unsigned short devid, unsigned short addr, unsigned int data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x00;
  OAL_OBTAIN_SEMAPHORE();
  (*(volatile unsigned char *)0x00) = (addr & 0xff00) >> 8;
  (*(volatile unsigned char *)0x00) = addr & 0xff;
  (*(volatile unsigned char *)0x00) = command;
  (*(volatile unsigned char *)0x00) = length & 0xff;
  (*(volatile unsigned char *)0x00) = data & 0x000000ff;
  (*(volatile unsigned char *)0x00) = (data & 0x0000ff00) >> 8;
  (*(volatile unsigned char *)0x00) = (data & 0x00ff0000) >> 16;
  (*(volatile unsigned char *)0x00) = (data & 0xff000000) >> 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flip_G2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  movabs $0x810204080,%rax
  and    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x40810204000,%rax
  and    -0x30(%rbp),%rax
  movabs $0x1fbf7efdf8000,%rdx
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movabs $0x2000000000000,%rax
  and    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rcx
  movabs $0x2000000000000,%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  movabs $0x40810204000,%rax
  and    %rdx,%rax
  or     %rax,-0x20(%rbp)
L18:
  movabs $0xf8000000000000,%rax
  and    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x4000000000000,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  movabs $0xfc000000000000,%rax
  and    %rdx,%rax
  or     %rax,-0x20(%rbp)
L13:
  movabs $0x202020202,%rax
  and    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x20202020200,%rax
  and    -0x30(%rbp),%rax
  movabs $0x1fdfdfdfdfc00,%rdx
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movabs $0x2000000000000,%rax
  and    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rcx
  movabs $0x2000000000000,%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  movabs $0x20202020200,%rax
  and    %rdx,%rax
  or     %rax,-0x20(%rbp)
L23:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long flip_G2(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r, flipped = 0ULL;
  my_discs = discs_player & 0X0000000810204080ULL;
  opp_discs = (discs_opponent & 0X0000040810204000ULL) | 0X0001FBF7EFDF8000ULL;
  r = ((my_discs << 7) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000040810204000ULL;
  }
  my_discs = discs_player & 0X00F8000000000000ULL;
  r = (discs_opponent + 0X0004000000000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X00FC000000000000ULL;
  }
  my_discs = discs_player & 0X0000000202020202ULL;
  opp_discs = (discs_opponent & 0X0000020202020200ULL) | 0X0001FDFDFDFDFC00ULL;
  r = ((my_discs << 8) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000020202020200ULL;
  }
  return flipped;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flip_G2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movabs $0x810204080,%rdi
  and    %r12,%rdi
  movabs $0x40810204000,%rbx
  and    %rsi,%rbx
  movabs $0x1fbf7efdf8000,%rax
  or     %rax,%rbx
  mov    %rdi,%rax
  shl    $0x7,%rax
  add    %rax,%rbx
  movabs $0x2000000000000,%rax
  and    %rax,%rbx
  jne    L17
L48:
  movabs $0x4000000000000,%rax
  add    %rbp,%rax
  and    %r12,%rax
  movabs $0xf8000000000000,%rdx
  and    %rdx,%rax
  je     L33
  sub    $0x1,%rax
  movabs $0xfc000000000000,%rdx
  and    %rdx,%rax
  or     %rax,%rbx
L33:
  movabs $0x202020202,%rax
  and    %rax,%r12
  movabs $0x20202020200,%rax
  and    %rax,%rbp
  movabs $0x1fdfdfdfdfc00,%rax
  or     %rax,%rbp
  mov    %r12,%rax
  shl    $0x8,%rax
  lea    0x0(%rbp,%rax,1),%rax
  shr    $0x31,%rax
  jne    L15
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  movabs $0x2000000000000,%rbx
  sub    %rdx,%rbx
  movabs $0x40810204000,%rax
  and    %rax,%rbx
  jmp    L48
L15:
  mov    %r12,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  movabs $0x2000000000000,%rax
  sub    %rdx,%rax
  movabs $0x20202020200,%rdx
  and    %rdx,%rax
  or     %rax,%rbx
  jmp    L2
```

assistant: ```c
unsigned long long flip_G2(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r, flipped = 0ULL;
  my_discs = discs_player & 0X0000000810204080ULL;
  opp_discs = (discs_opponent & 0X0000040810204000ULL) | 0X0001FBF7EFDF8000ULL;
  r = ((my_discs << 7) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000040810204000ULL;
  }
  my_discs = discs_player & 0X00F8000000000000ULL;
  r = (discs_opponent + 0X0004000000000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X00FC000000000000ULL;
  }
  my_discs = discs_player & 0X0000000202020202ULL;
  opp_discs = (discs_opponent & 0X0000020202020200ULL) | 0X0001FDFDFDFDFC00ULL;
  r = ((my_discs << 8) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000020202020200ULL;
  }
  return flipped;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<flip_G2>:
  endbr64
  movabs $0x1fbf7efdf8000,%rax
  push   %r14
  movabs $0x40810204000,%r14
  push   %r13
  movabs $0x2000000000000,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  and    %r14,%r12
  movabs $0x810204080,%rdi
  and    %rbp,%rdi
  or     %rax,%r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rax
  shl    $0x7,%rax
  add    %rax,%r12
  and    %r13,%r12
  jne    L17
L7:
  movabs $0x4000000000000,%rax
  movabs $0xf8000000000000,%rdx
  add    %rbx,%rax
  and    %rbp,%rax
  and    %rdx,%rax
  je     L26
  movabs $0xfc000000000000,%rdx
  sub    $0x1,%rax
  and    %rdx,%rax
  or     %rax,%r12
L26:
  movabs $0x202020202,%rax
  movabs $0x20202020200,%r14
  movabs $0x2000000000000,%r13
  and    %rax,%rbp
  and    %r14,%rbx
  movabs $0x1fdfdfdfdfc00,%rax
  or     %rax,%rbx
  mov    %rbp,%rax
  shl    $0x8,%rax
  add    %rax,%rbx
  test   %r13,%rbx
  jne    L38
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  sub    %rdx,%r13
  and    %r14,%r13
  mov    %r13,%r12
  jmp    L7
  nopl   (%rax)
L38:
  mov    %rbp,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  pop    %rbx
  pop    %rbp
  mov    %eax,%ecx
  shl    %cl,%rdx
  sub    %rdx,%r13
  and    %r14,%r13
  or     %r13,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long flip_G2(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r, flipped = 0ULL;
  my_discs = discs_player & 0X0000000810204080ULL;
  opp_discs = (discs_opponent & 0X0000040810204000ULL) | 0X0001FBF7EFDF8000ULL;
  r = ((my_discs << 7) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000040810204000ULL;
  }
  my_discs = discs_player & 0X00F8000000000000ULL;
  r = (discs_opponent + 0X0004000000000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X00FC000000000000ULL;
  }
  my_discs = discs_player & 0X0000000202020202ULL;
  opp_discs = (discs_opponent & 0X0000020202020200ULL) | 0X0001FDFDFDFDFC00ULL;
  r = ((my_discs << 8) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000020202020200ULL;
  }
  return flipped;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<flip_G2>:
  endbr64
  movabs $0x1fbf7efdf8000,%rax
  push   %r14
  movabs $0x40810204000,%r14
  push   %r13
  movabs $0x2000000000000,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  and    %r14,%r12
  movabs $0x810204080,%rdi
  and    %rbp,%rdi
  or     %rax,%r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rax
  shl    $0x7,%rax
  add    %rax,%r12
  and    %r13,%r12
  jne    L5
L33:
  movabs $0x4000000000000,%rax
  movabs $0xf8000000000000,%rdx
  add    %rbx,%rax
  and    %rbp,%rax
  and    %rdx,%rax
  je     L24
  movabs $0xfc000000000000,%rdx
  sub    $0x1,%rax
  and    %rdx,%rax
  or     %rax,%r12
L24:
  movabs $0x202020202,%rax
  movabs $0x20202020200,%r14
  movabs $0x2000000000000,%r13
  and    %rax,%rbp
  and    %r14,%rbx
  movabs $0x1fdfdfdfdfc00,%rax
  or     %rax,%rbx
  mov    %rbp,%rax
  shl    $0x8,%rax
  add    %rax,%rbx
  test   %r13,%rbx
  jne    L11
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  call   <last_bit@plt>
  mov    $0x2,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  sub    %rdx,%r13
  and    %r14,%r13
  mov    %r13,%r12
  jmp    L33
  nopl   (%rax)
L11:
  mov    %rbp,%rdi
  call   <last_bit@plt>
  mov    $0x2,%edx
  pop    %rbx
  pop    %rbp
  mov    %eax,%ecx
  shl    %cl,%rdx
  sub    %rdx,%r13
  and    %r14,%r13
  or     %r13,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned long long flip_G2(const unsigned long long discs_player, const unsigned long long discs_opponent) {
  unsigned long long my_discs, opp_discs, r, flipped = 0ULL;
  my_discs = discs_player & 0X0000000810204080ULL;
  opp_discs = (discs_opponent & 0X0000040810204000ULL) | 0X0001FBF7EFDF8000ULL;
  r = ((my_discs << 7) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000040810204000ULL;
  }
  my_discs = discs_player & 0X00F8000000000000ULL;
  r = (discs_opponent + 0X0004000000000000ULL) & my_discs;
  if (r != 0) {
    flipped |= (r - 1) & 0X00FC000000000000ULL;
  }
  my_discs = discs_player & 0X0000000202020202ULL;
  opp_discs = (discs_opponent & 0X0000020202020200ULL) | 0X0001FDFDFDFDFC00ULL;
  r = ((my_discs << 8) + opp_discs) & 0X0002000000000000ULL;
  if (r != 0) {
    flipped |= (0X0002000000000000ULL - (0X2ULL << last_bit(my_discs))) & 0X0000020202020200ULL;
  }
  return flipped;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x64,%edi
  call   <primes@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: 


assistant: ```c
int main() {
  primes(100, 0, 0);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x64,%edi
  call   <primes@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: 


assistant: ```c
int main() {
  primes(100, 0, 0);
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x64,%edi
  call   <primes@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
int main() {
  primes(100, 0, 0);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x64,%edi
  call   <primes@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D3: 


assistant: ```c
int main() {
  primes(100, 0, 0);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L25
L43:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L25:
  cmpl   $0x8,-0x34(%rbp)
  jle    L43
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <qsort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L32
L40:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L32:
  cmpl   $0x8,-0x34(%rbp)
  jle    L40
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_guessed: string

tool: D11: %d, 

assistant: ```c
main() {
  int test[] = {3, 5, 1, 7, 3, 9, 7, 0, 2};
  int i;
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
  qsort(test, 0, 8);
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  mov    %rbx,%rbp
  lea    D4(%rip),%r13
L19:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <qsort@plt>
  lea    D4(%rip),%rbp
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: %d, 

assistant: ```c
main() {
  int test[] = {3, 5, 1, 7, 3, 9, 7, 0, 2};
  int i;
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
  qsort(test, 0, 8);
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x3,%esi
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000003,%rax
  mov    %rsp,%r14
  lea    0x4(%rsp),%rbp
  lea    0x24(%rsp),%r12
  movq   $0x7,0x18(%rsp)
  mov    %r14,%rbx
  movl   $0x2,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x700000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x900000003,%rax
  mov    %rax,0x10(%rsp)
  jmp    L13
  nopl   0x0(%rax)
L23:
  mov    0x0(%rbp),%esi
  add    $0x4,%rbp
L13:
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <qsort@plt>
  nopl   (%rax)
L18:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: %d, 

assistant: ```c
main() {
  int test[] = {3, 5, 1, 7, 3, 9, 7, 0, 2};
  int i;
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
  qsort(test, 0, 8);
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x20(%rsp)
  mov    %rsp,%r14
  lea    0x24(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D17(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  movaps %xmm0,0x10(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <qsort@plt>
  nopl   (%rax)
L3:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D17
data_type: byte[16]

tool: D9: %d, 

tool: {"D4": [0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D17": [0x03,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
main() {
  int test[] = {3, 5, 1, 7, 3, 9, 7, 0, 2};
  int i;
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
  qsort(test, 0, 8);
  for (i = 0; i < 9; i++)
    printf("%d, ", test[i]);
  putchar('\n');
}
```