ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<lcg_next>:
  endbr64
  test   %edi,%edi
  js     L8
  mov    %edi,D3(%rip)
L8:
  imul   $0x4fd,0x2f13(%rip),%eax        # 4024 <last.0>
  cltd
  shr    $0xf,%edx
  add    %edx,%eax
  and    $0x1ffff,%eax
  sub    %edx,%eax
  mov    %eax,D17(%rip)
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int lcg_next(int seed, int range) {
  static int last;
  if (seed >= 0)
    last = seed;
  last = ((1277 * last) + 0) % 131072;
  return (last % range);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lcg_next>:
  endbr64
  test   %edi,%edi
  cmovs  D11(%rip),%edi
  imul   $0x4fd,%edi,%edi
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0xf,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1ffff,%eax
  sub    %edx,%eax
  cltd
  mov    %eax,D14(%rip)
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int lcg_next(int seed, int range) {
  static int last;
  if (seed >= 0)
    last = seed;
  last = ((1277 * last) + 0) % 131072;
  return (last % range);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lcg_next>:
  endbr64
  test   %edi,%edi
  cmovs  D15(%rip),%edi
  imul   $0x4fd,%edi,%edi
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0xf,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1ffff,%eax
  sub    %edx,%eax
  cltd
  mov    %eax,D1(%rip)
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int lcg_next(int seed, int range) {
  static int last;
  if (seed >= 0)
    last = seed;
  last = ((1277 * last) + 0) % 131072;
  return (last % range);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_YVYU_ARGB>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  imul   %ecx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,0x1c(%rsp)
  cmp    $0x1,%edx
  jle    L14
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
L5:
  mov    0x8(%rbp),%r13
  mov    0x18(%rbp),%rax
  lea    0x28(%rsp),%r15
  lea    0x20(%rsp),%r14
  mov    0x8(%rsp),%r9
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rax,%rsi
  mov    0x0(%rbp),%rdi
  call   <yuv2rgb@plt>
  movq   $0x0,(%rbx)
  mov    0x20(%rsp),%rax
  mov    %rax,0x8(%rbx)
  mov    0x28(%rsp),%rax
  mov    %rax,0x10(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,0x18(%rbx)
  mov    0x10(%rbp),%rdi
  mov    0x8(%rsp),%r9
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    0x10(%rsp),%rsi
  call   <yuv2rgb@plt>
  movq   $0x0,0x20(%rbx)
  mov    0x20(%rsp),%rax
  mov    %rax,0x28(%rbx)
  mov    0x28(%rsp),%rax
  mov    %rax,0x30(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,0x38(%rbx)
  add    $0x40,%rbx
  add    $0x1,%r12d
  add    $0x20,%rbp
  cmp    0x1c(%rsp),%r12d
  jl     L5
L14:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert_YVYU_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t y = 0, u = 0, v = 0;
  uint8_t r = 0, g = 0, b = 0;
  uint8_t *p_src = src;
  uint8_t *rgb = dst;
  do {
  } while (0);
  for (i = 0; i < (w * h / 2); i++) {
    y = p_src[i * 4 + 0];
    v = p_src[i * 4 + 1];
    u = p_src[i * 4 + 3];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
    y = p_src[i * 4 + 2];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_YVYU_ARGB>:
  endbr64
  imul   %ecx,%edx
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r15d
  push   %r12
  push   %rbp
  shr    $0x1f,%r15d
  push   %rbx
  add    %edx,%r15d
  sar    %r15d
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %r15d,0x1c(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  cmp    $0x1,%edx
  jle    L21
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  lea    0x30(%rsp),%r15
  xor    %r12d,%r12d
  lea    0x28(%rsp),%r14
  lea    0x20(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x8(%rbp),%rdx
  mov    0x18(%rbp),%rsi
  mov    %r15,%r9
  mov    %r14,%r8
  mov    0x0(%rbp),%rdi
  mov    %r13,%rcx
  add    $0x40,%rbx
  add    $0x1,%r12d
  mov    %rdx,0x10(%rsp)
  add    $0x20,%rbp
  mov    %rsi,0x8(%rsp)
  call   <yuv2rgb@plt>
  mov    0x20(%rsp),%rax
  mov    %r15,%r9
  mov    %r14,%r8
  movq   $0x0,-0x40(%rbx)
  mov    0x10(%rsp),%rdx
  mov    %r13,%rcx
  mov    %rax,-0x38(%rbx)
  mov    0x28(%rsp),%rax
  mov    0x8(%rsp),%rsi
  mov    %rax,-0x30(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,-0x28(%rbx)
  mov    -0x10(%rbp),%rdi
  call   <yuv2rgb@plt>
  mov    0x20(%rsp),%rax
  movq   $0x0,-0x20(%rbx)
  mov    %rax,-0x18(%rbx)
  mov    0x28(%rsp),%rax
  mov    %rax,-0x10(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,-0x8(%rbx)
  cmp    0x1c(%rsp),%r12d
  jl     L25
L21:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert_YVYU_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t y = 0, u = 0, v = 0;
  uint8_t r = 0, g = 0, b = 0;
  uint8_t *p_src = src;
  uint8_t *rgb = dst;
  do {
  } while (0);
  for (i = 0; i < (w * h / 2); i++) {
    y = p_src[i * 4 + 0];
    v = p_src[i * 4 + 1];
    u = p_src[i * 4 + 3];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
    y = p_src[i * 4 + 2];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_YVYU_ARGB>:
  endbr64
  imul   %ecx,%edx
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r15d
  push   %r12
  push   %rbp
  shr    $0x1f,%r15d
  push   %rbx
  add    %edx,%r15d
  sar    %r15d
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %r15d,0x1c(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  cmp    $0x1,%edx
  jle    L13
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  lea    0x30(%rsp),%r15
  xor    %r12d,%r12d
  lea    0x28(%rsp),%r14
  lea    0x20(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x8(%rbp),%rdx
  mov    0x18(%rbp),%rsi
  mov    %r15,%r9
  mov    %r14,%r8
  mov    0x0(%rbp),%rdi
  mov    %r13,%rcx
  add    $0x40,%rbx
  add    $0x1,%r12d
  mov    %rdx,0x10(%rsp)
  add    $0x20,%rbp
  mov    %rsi,0x8(%rsp)
  call   <yuv2rgb@plt>
  mov    0x20(%rsp),%rax
  mov    %r15,%r9
  mov    %r14,%r8
  movq   $0x0,-0x40(%rbx)
  mov    0x10(%rsp),%rdx
  mov    %r13,%rcx
  mov    %rax,-0x38(%rbx)
  mov    0x28(%rsp),%rax
  mov    0x8(%rsp),%rsi
  mov    %rax,-0x30(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,-0x28(%rbx)
  mov    -0x10(%rbp),%rdi
  call   <yuv2rgb@plt>
  mov    0x20(%rsp),%rax
  movq   $0x0,-0x20(%rbx)
  mov    %rax,-0x18(%rbx)
  mov    0x28(%rsp),%rax
  mov    %rax,-0x10(%rbx)
  mov    0x30(%rsp),%rax
  mov    %rax,-0x8(%rbx)
  cmp    0x1c(%rsp),%r12d
  jl     L19
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert_YVYU_ARGB(uint8_t *src, uint8_t *dst, uint32_t w, uint32_t h) {
  uint32_t i = 0;
  uint8_t y = 0, u = 0, v = 0;
  uint8_t r = 0, g = 0, b = 0;
  uint8_t *p_src = src;
  uint8_t *rgb = dst;
  do {
  } while (0);
  for (i = 0; i < (w * h / 2); i++) {
    y = p_src[i * 4 + 0];
    v = p_src[i * 4 + 1];
    u = p_src[i * 4 + 3];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
    y = p_src[i * 4 + 2];
    yuv2rgb(y, u, v, &r, &g, &b);
    rgb[0] = 0;
    rgb[1] = r;
    rgb[2] = g;
    rgb[3] = b;
    rgb += 4;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_non_identifiers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0xf,-0x4(%rbp)
  jle    L3
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L29:
  addl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0xf,-0x4(%rbp)
  jle    L29
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L1:
  addl   $0x1,-0x4(%rbp)
L47:
  cmpl   $0xf,-0x4(%rbp)
  jle    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_non_identifiers() {
  int i, x;
#pragma omp target parallel for;
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for private(x);
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for, private(x);
  for (i = 0; i < 16; ++i)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_non_identifiers>:
  endbr64
  ret
```

assistant: ```c
void test_non_identifiers() {
  int i, x;
#pragma omp target parallel for;
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for private(x);
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for, private(x);
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_non_identifiers>:
  endbr64
  ret
```

assistant: ```c
void test_non_identifiers() {
  int i, x;
#pragma omp target parallel for;
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for private(x);
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for, private(x);
  for (i = 0; i < 16; ++i)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_non_identifiers>:
  endbr64
  ret
```

assistant: ```c
void test_non_identifiers() {
  int i, x;
#pragma omp target parallel for;
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for private(x);
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target parallel for, private(x);
  for (i = 0; i < 16; ++i)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<genCnt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  jmp    L53
L22:
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L64
L17:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L62
L28:
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L45
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L28
  jmp    L73
L45:
  nop
L73:
  addl   $0x1,-0x20(%rbp)
L64:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L17
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,(%rcx)
L53:
  mov    -0x24(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L22
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *genCnt(int NN) {
  int *T = (int *)calloc((NN + 1), sizeof(int));
  int D, I, J, TD;
  int SUM;
  int NLAST = 1;
  T[1] = 1;
  while (NN > NLAST) {
    SUM = 0;
    for (D = 1; D <= NLAST; D++) {
      I = NLAST + 1;
      TD = T[D] * D;
      for (J = 1; J <= NLAST; J++) {
        I = I - D;
        if (I <= 0)
          break;
        SUM += T[I] * TD;
      }
    }
    NLAST++;
    T[NLAST] = SUM / (NLAST - 1);
  }
  return T;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<genCnt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0x4(%rsp)
  lea    0x1(%rdi),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  movl   $0x1,0x4(%rax)
  cmp    $0x1,%ebx
  jle    L50
  lea    0x4(%rax,%rax,1),%r13
  mov    $0x1,%r10d
  mov    $0x4,%eax
  sub    %r12,%rax
  mov    %rax,0x8(%rsp)
  jmp    L31
L11:
  add    $0x4,%rbp
  sub    $0x1,%ebx
  je     L88
L22:
  mov    %r14d,%r8d
  sub    %ebx,%r8d
  mov    %r8d,%r9d
  imul   0x0(%rbp),%r9d
  mov    %ebx,%esi
  test   %ebx,%ebx
  jle    L11
  mov    %r12,%r11
  sub    %rbp,%r11
  mov    %r15,%rcx
  sub    %rbp,%rcx
  mov    $0x1,%edx
L66:
  mov    %r9d,%edi
  imul   (%rcx),%edi
  add    %edi,%eax
  add    $0x1,%edx
  cmp    %r10d,%edx
  jg     L11
  sub    %r8d,%esi
  add    %r11,%rcx
  test   %esi,%esi
  jg     L66
  jmp    L11
L88:
  lea    0x1(%r10),%ecx
  cltd
  idiv   %r10d
  mov    0x8(%rsp),%rbx
  mov    %eax,(%rbx,%r13,1)
  add    $0x4,%r13
  cmp    %ecx,0x4(%rsp)
  je     L50
  mov    %ecx,%r10d
L31:
  mov    $0x0,%eax
  test   %r10d,%r10d
  jle    L88
  lea    0x4(%r12),%rbp
  mov    %r10d,%ebx
  mov    $0x0,%eax
  lea    0x1(%r10),%r14d
  lea    0x4(%r13),%r15
  jmp    L22
L50:
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *genCnt(int NN) {
  int *T = (int *)calloc((NN + 1), sizeof(int));
  int D, I, J, TD;
  int SUM;
  int NLAST = 1;
  T[1] = 1;
  while (NN > NLAST) {
    SUM = 0;
    for (D = 1; D <= NLAST; D++) {
      I = NLAST + 1;
      TD = T[D] * D;
      for (J = 1; J <= NLAST; J++) {
        I = I - D;
        if (I <= 0)
          break;
        SUM += T[I] * TD;
      }
    }
    NLAST++;
    T[NLAST] = SUM / (NLAST - 1);
  }
  return T;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<genCnt>:
  endbr64
  push   %r15
  mov    $0x4,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    0x1(%rdi),%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x28,%rsp
  call   <calloc@plt>
  movl   $0x1,0x4(%rax)
  mov    %rax,%r12
  cmp    $0x1,%ebx
  jle    L33
  lea    0x4(%rax,%rax,1),%r13
  mov    %ebp,%eax
  mov    $0x2,%ebx
  mov    $0x1,%r11d
  mov    %rax,0x8(%rsp)
  lea    0x4(%r12),%rax
  mov    %rax,0x10(%rsp)
  mov    $0x4,%eax
  sub    %r12,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L44:
  mov    0x10(%rsp),%r14
  mov    %ebx,%r15d
  xor    %eax,%eax
  mov    $0x1,%r8d
  lea    0x4(%r13),%rbp
  nopl   0x0(%rax)
L4:
  mov    (%r14),%r10d
  mov    %r12,%r9
  mov    %rbp,%rsi
  mov    %r15d,%edx
  sub    %r14,%r9
  sub    %r14,%rsi
  mov    $0x1,%ecx
  imul   %r8d,%r10d
  nopl   0x0(%rax,%rax,1)
L58:
  sub    %r8d,%edx
  test   %edx,%edx
  jle    L40
  mov    (%rsi),%edi
  add    $0x1,%ecx
  add    %r9,%rsi
  imul   %r10d,%edi
  add    %edi,%eax
  cmp    %ecx,%r11d
  jge    L58
L40:
  add    $0x1,%r8d
  add    $0x4,%r14
  cmp    %ebx,%r8d
  jne    L4
  cltd
  mov    0x18(%rsp),%rcx
  add    $0x1,%rbx
  idiv   %r11d
  add    $0x1,%r11d
  mov    %eax,(%rcx,%r13,1)
  cmp    0x8(%rsp),%rbx
  je     L33
  mov    %rbp,%r13
  jmp    L44
L33:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *genCnt(int NN) {
  int *T = (int *)calloc((NN + 1), sizeof(int));
  int D, I, J, TD;
  int SUM;
  int NLAST = 1;
  T[1] = 1;
  while (NN > NLAST) {
    SUM = 0;
    for (D = 1; D <= NLAST; D++) {
      I = NLAST + 1;
      TD = T[D] * D;
      for (J = 1; J <= NLAST; J++) {
        I = I - D;
        if (I <= 0)
          break;
        SUM += T[I] * TD;
      }
    }
    NLAST++;
    T[NLAST] = SUM / (NLAST - 1);
  }
  return T;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<genCnt>:
  endbr64
  push   %r15
  mov    $0x4,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    0x1(%rdi),%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x28,%rsp
  call   <calloc@plt>
  movl   $0x1,0x4(%rax)
  mov    %rax,%r12
  cmp    $0x1,%ebx
  jle    L8
  lea    0x4(%rax,%rax,1),%r13
  mov    %ebp,%eax
  mov    $0x2,%ebx
  mov    $0x1,%r11d
  mov    %rax,0x8(%rsp)
  lea    0x4(%r12),%rax
  mov    %rax,0x10(%rsp)
  mov    $0x4,%eax
  sub    %r12,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L49:
  mov    0x10(%rsp),%r14
  mov    %ebx,%r15d
  xor    %eax,%eax
  mov    $0x1,%r8d
  lea    0x4(%r13),%rbp
  nopl   0x0(%rax)
L14:
  mov    (%r14),%r10d
  mov    %r12,%r9
  mov    %rbp,%rsi
  mov    %r15d,%edx
  sub    %r14,%r9
  sub    %r14,%rsi
  mov    $0x1,%ecx
  imul   %r8d,%r10d
  nopl   0x0(%rax,%rax,1)
L47:
  sub    %r8d,%edx
  test   %edx,%edx
  jle    L51
  mov    (%rsi),%edi
  add    $0x1,%ecx
  add    %r9,%rsi
  imul   %r10d,%edi
  add    %edi,%eax
  cmp    %ecx,%r11d
  jge    L47
L51:
  add    $0x1,%r8d
  add    $0x4,%r14
  cmp    %ebx,%r8d
  jne    L14
  cltd
  mov    0x18(%rsp),%rcx
  add    $0x1,%rbx
  idiv   %r11d
  add    $0x1,%r11d
  mov    %eax,(%rcx,%r13,1)
  cmp    0x8(%rsp),%rbx
  je     L8
  mov    %rbp,%r13
  jmp    L49
L8:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *genCnt(int NN) {
  int *T = (int *)calloc((NN + 1), sizeof(int));
  int D, I, J, TD;
  int SUM;
  int NLAST = 1;
  T[1] = 1;
  while (NN > NLAST) {
    SUM = 0;
    for (D = 1; D <= NLAST; D++) {
      I = NLAST + 1;
      TD = T[D] * D;
      for (J = 1; J <= NLAST; J++) {
        I = I - D;
        if (I <= 0)
          break;
        SUM += T[I] * TD;
      }
    }
    NLAST++;
    T[NLAST] = SUM / (NLAST - 1);
  }
  return T;
}
```
user: What is the c source code of the assembly code below?

```asm
<use_with_delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: asdasd


assistant: ```c
void use_with_delay(char **commands, int *delay, int number_of_command) {
  printf("asdasd\n");
  sleep(*delay);
  execvp(commands[0], commands + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<use_with_delay>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%rbp),%edi
  call   <sleep@plt>
  lea    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <execvp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: asdasd


assistant: ```c
void use_with_delay(char **commands, int *delay, int number_of_command) {
  printf("asdasd\n");
  sleep(*delay);
  execvp(commands[0], commands + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<use_with_delay>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    0x0(%rbp),%edi
  call   <sleep@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  lea    0x8(%rbx),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1080 <execvp@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: asdasd


assistant: ```c
void use_with_delay(char **commands, int *delay, int number_of_command) {
  printf("asdasd\n");
  sleep(*delay);
  execvp(commands[0], commands + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<use_with_delay>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    0x0(%rbp),%edi
  call   <sleep@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  lea    0x8(%rbx),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1080 <execvp@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: asdasd


assistant: ```c
void use_with_delay(char **commands, int *delay, int number_of_command) {
  printf("asdasd\n");
  sleep(*delay);
  execvp(commands[0], commands + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<totalizaResultado>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0xf,-0x4(%rbp)
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void totalizaResultado(float vetor1[], float vetor2[], float result[]) {
  int x;
  for (x = 0; x < 16; x++) {
    result[x] = vetor1[x] + vetor2[x];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<totalizaResultado>:
  endbr64
  mov    $0x0,%eax
L4:
  movss  (%rdi,%rax,1),%xmm0
  addss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L4
  ret
```

assistant: ```c
void totalizaResultado(float vetor1[], float vetor2[], float result[]) {
  int x;
  for (x = 0; x < 16; x++) {
    result[x] = vetor1[x] + vetor2[x];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<totalizaResultado>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movss  (%rdi,%rax,1),%xmm0
  addss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L2
  ret
```

assistant: ```c
void totalizaResultado(float vetor1[], float vetor2[], float result[]) {
  int x;
  for (x = 0; x < 16; x++) {
    result[x] = vetor1[x] + vetor2[x];
  }
}
```