ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <open_netlink_socket@plt>
  test   %eax,%eax
  js     L14
  lea    D5(%rip),%rdi
  mov    %eax,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L10:
  mov    %ebx,%edi
  call   <read_event@plt>
  jmp    L10
L14:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D5: Netlink socket opened


tool: D1: Opening netlink socket failed


assistant: ```c
int main(int argc, char **argv) {
  int netlink_socket;
  netlink_socket = open_netlink_socket();
  if (netlink_socket < 0) {
    printf("Opening netlink socket failed\n");
    return -1;
  }
  printf("Netlink socket opened\n");
  while (1) {
    read_event(netlink_socket);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L22
L3:
  movl   $0x1,-0x10(%rbp)
  jmp    L19
L12:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L48
L62:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L95
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L66
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L66:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L38
L95:
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L62
L38:
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L90
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L90:
  mov    -0x14(%rbp),%eax
L22:
  leave
  ret
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int start = 0;
  int len = 0;
  int max = 0;
  int i = 0;
  int size = strlen(s);
  if (size == 0)
    return 0;
  for (i = 1; i < size; i++) {
    for (int j = start; j < i; j++) {
      if (s[j] == s[i]) {
        len = i - start;
        if (max < len)
          max = len;
        start = j + 1;
        break;
      }
    }
  }
  len = i - start;
  if (max < len)
    max = len;
  return max;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L40
  cmp    $0x1,%eax
  jle    L73
  mov    %eax,%ebp
  mov    $0x1,%r8d
  mov    $0x0,%r11d
  mov    $0x0,%r9d
  jmp    L16
L32:
  sub    %r9d,%r10d
  cmp    %r10d,%r11d
  cmovl  %r10d,%r11d
  lea    0x1(%rdx),%r9d
L47:
  add    $0x1,%r8
  cmp    %rbp,%r8
  je     L60
L16:
  mov    %r8d,%r10d
  mov    %r8d,%esi
  cmp    %r8d,%r9d
  jge    L47
  movzbl (%rbx,%r8,1),%ecx
  movslq %r9d,%rdx
L68:
  cmp    %cl,(%rbx,%rdx,1)
  je     L32
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L68
  jmp    L47
L73:
  mov    $0x1,%eax
  mov    $0x0,%r11d
  mov    $0x0,%r9d
L60:
  sub    %r9d,%eax
  cmp    %r11d,%eax
  cmovl  %r11d,%eax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int start = 0;
  int len = 0;
  int max = 0;
  int i = 0;
  int size = strlen(s);
  if (size == 0)
    return 0;
  for (i = 1; i < size; i++) {
    for (int j = start; j < i; j++) {
      if (s[j] == s[i]) {
        len = i - start;
        if (max < len)
          max = len;
        start = j + 1;
        break;
      }
    }
  }
  len = i - start;
  if (max < len)
    max = len;
  return max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r11d
  test   %eax,%eax
  je     L35
  cmp    $0x1,%eax
  jle    L46
  movslq %eax,%rbp
  mov    $0x1,%esi
  xor    %r10d,%r10d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %esi,%r9d
  cmp    %esi,%edi
  jge    L30
  mov    %esi,%edx
  lea    0x2(%rdi),%r8d
  lea    0x1(%rdi),%eax
  movzbl (%rbx,%rsi,1),%ecx
  sub    %edi,%edx
  movslq %r8d,%r8
  cltq
  sub    $0x1,%edx
  add    %r8,%rdx
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L30
L73:
  cmp    %cl,-0x1(%rbx,%rax,1)
  jne    L41
  sub    %edi,%r9d
  mov    %eax,%edi
  cmp    %r9d,%r10d
  cmovl  %r9d,%r10d
L30:
  add    $0x1,%rsi
  cmp    %rbp,%rsi
  jne    L32
  sub    %edi,%r11d
  cmp    %r10d,%r11d
  cmovl  %r10d,%r11d
L35:
  add    $0x8,%rsp
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  ret
L46:
  mov    $0x1,%r11d
  jmp    L35
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int start = 0;
  int len = 0;
  int max = 0;
  int i = 0;
  int size = strlen(s);
  if (size == 0)
    return 0;
  for (i = 1; i < size; i++) {
    for (int j = start; j < i; j++) {
      if (s[j] == s[i]) {
        len = i - start;
        if (max < len)
          max = len;
        start = j + 1;
        break;
      }
    }
  }
  len = i - start;
  if (max < len)
    max = len;
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r11d
  test   %eax,%eax
  je     L18
  cmp    $0x1,%eax
  jle    L67
  movslq %eax,%rbp
  mov    $0x1,%esi
  xor    %r10d,%r10d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %esi,%r9d
  cmp    %esi,%edi
  jge    L70
  mov    %esi,%edx
  lea    0x2(%rdi),%r8d
  lea    0x1(%rdi),%eax
  movzbl (%rbx,%rsi,1),%ecx
  sub    %edi,%edx
  movslq %r8d,%r8
  cltq
  sub    $0x1,%edx
  add    %r8,%rdx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L70
L74:
  cmp    %cl,-0x1(%rbx,%rax,1)
  jne    L17
  sub    %edi,%r9d
  mov    %eax,%edi
  cmp    %r9d,%r10d
  cmovl  %r9d,%r10d
L70:
  add    $0x1,%rsi
  cmp    %rsi,%rbp
  jne    L63
  sub    %edi,%r11d
  cmp    %r10d,%r11d
  cmovl  %r10d,%r11d
L18:
  add    $0x8,%rsp
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  ret
L67:
  mov    $0x1,%r11d
  jmp    L18
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int start = 0;
  int len = 0;
  int max = 0;
  int i = 0;
  int size = strlen(s);
  if (size == 0)
    return 0;
  for (i = 1; i < size; i++) {
    for (int j = start; j < i; j++) {
      if (s[j] == s[i]) {
        len = i - start;
        if (max < len)
          max = len;
        start = j + 1;
        break;
      }
    }
  }
  len = i - start;
  if (max < len)
    max = len;
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L3:
  shll   -0xc(%rbp)
  mov    $0x0,%eax
  call   <readInBit@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x1,-0x8(%rbp)
  jle    L3
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t readHeader(void) {
  uint8_t dataRead = 0;
  for (int i = 0; i < 2; i++) {
    dataRead <<= 1;
    uint8_t newBit = readInBit();
    dataRead |= newBit;
  }
  return dataRead;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readHeader>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <readInBit@plt>
  lea    (%rax,%rax,1),%ebx
  mov    $0x0,%eax
  call   <readInBit@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t readHeader(void) {
  uint8_t dataRead = 0;
  for (int i = 0; i < 2; i++) {
    dataRead <<= 1;
    uint8_t newBit = readInBit();
    dataRead |= newBit;
  }
  return dataRead;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readHeader>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <readInBit@plt>
  lea    (%rax,%rax,1),%ebx
  xor    %eax,%eax
  call   <readInBit@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t readHeader(void) {
  uint8_t dataRead = 0;
  for (int i = 0; i < 2; i++) {
    dataRead <<= 1;
    uint8_t newBit = readInBit();
    dataRead |= newBit;
  }
  return dataRead;
}
```
user: What is the c source code of the assembly code below?

```asm
<readHeader>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <readInBit@plt>
  lea    (%rax,%rax,1),%ebx
  xor    %eax,%eax
  call   <readInBit@plt>
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t readHeader(void) {
  uint8_t dataRead = 0;
  for (int i = 0; i < 2; i++) {
    dataRead <<= 1;
    uint8_t newBit = readInBit();
    dataRead |= newBit;
  }
  return dataRead;
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D48
type: string
name: unpack_data
arguments: data_tag: D91
type: string
name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D88
type: string
name: unpack_data
arguments: data_tag: D70
type: string
name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D93
type: string
name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D74
type: string

tool: D25: Usage: kickconv [options] in_file out_file


tool: D48: Options:


tool: D91:   -h, --help      Display this information


tool: D16:   -c, --csum      Fix bad ROM checksum


tool: D88:   -i, --cd32-swizz  CD32-ROM swizzle


tool: D70:   -I, --cd32-deswizz CD32-ROM de-swizzle


tool: D1:   -k, --key=FILE  Key file for encrypted ROM


tool: D93:   -s, --swap      Swap endianess (little vs big endian)


tool: D23:   -S, --split     Split into two 16-bit ROM files


tool: D74:   -m, --merge     Merge split ROM files into one


assistant: ```c
void usage(int rc) {
  printf("Usage: kickconv [options] in_file out_file\n");
  printf("Options:\n");
  printf("  -h, --help      Display this information\n");
  printf("  -c, --csum      Fix bad ROM checksum\n");
  printf("  -i, --cd32-swizz  CD32-ROM swizzle\n");
  printf("  -I, --cd32-deswizz CD32-ROM de-swizzle\n");
  printf("  -k, --key=FILE  Key file for encrypted ROM\n");
  printf("  -s, --swap      Swap endianess (little vs big endian)\n");
  printf("  -S, --split     Split into two 16-bit ROM files\n");
  printf("  -m, --merge     Merge split ROM files into one\n");
  exit(rc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D72(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D72
type_guessed: string
name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string
name: parse_data
arguments: data_tag: D78
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D48
type_guessed: string
name: parse_data
arguments: data_tag: D82
type_guessed: string
name: parse_data
arguments: data_tag: D51
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D72: Usage: kickconv [options] in_file out_file


tool: D26: Options:


tool: D5:   -h, --help      Display this information


tool: D78:   -c, --csum      Fix bad ROM checksum


tool: D18:   -i, --cd32-swizz  CD32-ROM swizzle


tool: D38:   -I, --cd32-deswizz CD32-ROM de-swizzle


tool: D48:   -k, --key=FILE  Key file for encrypted ROM


tool: D82:   -s, --swap      Swap endianess (little vs big endian)


tool: D51:   -S, --split     Split into two 16-bit ROM files


tool: D7:   -m, --merge     Merge split ROM files into one


assistant: ```c
void usage(int rc) {
  printf("Usage: kickconv [options] in_file out_file\n");
  printf("Options:\n");
  printf("  -h, --help      Display this information\n");
  printf("  -c, --csum      Fix bad ROM checksum\n");
  printf("  -i, --cd32-swizz  CD32-ROM swizzle\n");
  printf("  -I, --cd32-deswizz CD32-ROM de-swizzle\n");
  printf("  -k, --key=FILE  Key file for encrypted ROM\n");
  printf("  -s, --swap      Swap endianess (little vs big endian)\n");
  printf("  -S, --split     Split into two 16-bit ROM files\n");
  printf("  -m, --merge     Merge split ROM files into one\n");
  exit(rc);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  lea    D97(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D83(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D35
type_infered: string
name: read_data
arguments: tag: D87
type_infered: string
name: read_data
arguments: tag: D97
type_infered: string
name: read_data
arguments: tag: D45
type_infered: string
name: read_data
arguments: tag: D67
type_infered: string
name: read_data
arguments: tag: D41
type_infered: string
name: read_data
arguments: tag: D83
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D51
type_infered: string

tool: D35: Usage: kickconv [options] in_file out_file


tool: D87: Options:


tool: D97:   -h, --help      Display this information


tool: D45:   -c, --csum      Fix bad ROM checksum


tool: D67:   -i, --cd32-swizz  CD32-ROM swizzle


tool: D41:   -I, --cd32-deswizz CD32-ROM de-swizzle


tool: D83:   -k, --key=FILE  Key file for encrypted ROM


tool: D25:   -s, --swap      Swap endianess (little vs big endian)


tool: D34:   -S, --split     Split into two 16-bit ROM files


tool: D51:   -m, --merge     Merge split ROM files into one


assistant: ```c
void usage(int rc) {
  printf("Usage: kickconv [options] in_file out_file\n");
  printf("Options:\n");
  printf("  -h, --help      Display this information\n");
  printf("  -c, --csum      Fix bad ROM checksum\n");
  printf("  -i, --cd32-swizz  CD32-ROM swizzle\n");
  printf("  -I, --cd32-deswizz CD32-ROM de-swizzle\n");
  printf("  -k, --key=FILE  Key file for encrypted ROM\n");
  printf("  -s, --swap      Swap endianess (little vs big endian)\n");
  printf("  -S, --split     Split into two 16-bit ROM files\n");
  printf("  -m, --merge     Merge split ROM files into one\n");
  exit(rc);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D90(%rip),%rdi
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D90
type: string
name: read_data
arguments: label: D70
type: string
name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D53
type: string
name: read_data
arguments: label: D52
type: string
name: read_data
arguments: label: D64
type: string
name: read_data
arguments: label: D45
type: string
name: read_data
arguments: label: D12
type: string

tool: D13: Usage: kickconv [options] in_file out_file


tool: D19: Options:


tool: D90:   -h, --help      Display this information


tool: D70:   -c, --csum      Fix bad ROM checksum


tool: D23:   -i, --cd32-swizz  CD32-ROM swizzle


tool: D53:   -I, --cd32-deswizz CD32-ROM de-swizzle


tool: D52:   -k, --key=FILE  Key file for encrypted ROM


tool: D64:   -s, --swap      Swap endianess (little vs big endian)


tool: D45:   -S, --split     Split into two 16-bit ROM files


tool: D12:   -m, --merge     Merge split ROM files into one


assistant: ```c
void usage(int rc) {
  printf("Usage: kickconv [options] in_file out_file\n");
  printf("Options:\n");
  printf("  -h, --help      Display this information\n");
  printf("  -c, --csum      Fix bad ROM checksum\n");
  printf("  -i, --cd32-swizz  CD32-ROM swizzle\n");
  printf("  -I, --cd32-deswizz CD32-ROM de-swizzle\n");
  printf("  -k, --key=FILE  Key file for encrypted ROM\n");
  printf("  -s, --swap      Swap endianess (little vs big endian)\n");
  printf("  -S, --split     Split into two 16-bit ROM files\n");
  printf("  -m, --merge     Merge split ROM files into one\n");
  exit(rc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpystrarr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L12:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x8,-0x8(%rbp)
  addq   $0x8,-0x20(%rbp)
L10:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L12
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **cpystrarr(char **dest, char **source) {
  char **dest_ptr = dest;
  while (*source != 0x0) {
    *dest_ptr = malloc(strlen(*source) + 1);
    strcpy(*dest_ptr, *source);
    dest_ptr += 1;
    source += 1;
  }
  *dest_ptr = 0x0;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpystrarr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L22
  mov    %rsi,%rbx
  mov    %r12,%rbp
L28:
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rsi
  call   <strcpy@plt>
  add    $0x8,%rbp
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L28
L19:
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %r12,%rbp
  jmp    L19
```

assistant: ```c
char **cpystrarr(char **dest, char **source) {
  char **dest_ptr = dest;
  while (*source != 0x0) {
    *dest_ptr = malloc(strlen(*source) + 1);
    strcpy(*dest_ptr, *source);
    dest_ptr += 1;
    source += 1;
  }
  *dest_ptr = 0x0;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpystrarr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L4
  mov    %rsi,%rbx
  mov    %r12,%rbp
  nopl   0x0(%rax)
L8:
  call   <strlen@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L8
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L4:
  mov    %r12,%rbp
  mov    %r12,%rax
  movq   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **cpystrarr(char **dest, char **source) {
  char **dest_ptr = dest;
  while (*source != 0x0) {
    *dest_ptr = malloc(strlen(*source) + 1);
    strcpy(*dest_ptr, *source);
    dest_ptr += 1;
    source += 1;
  }
  *dest_ptr = 0x0;
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpystrarr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L13
  mov    %rsi,%rbx
  mov    %r12,%rbp
  nopl   0x0(%rax)
L14:
  call   <strlen@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbx),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L14
  movq   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  mov    %r12,%rbp
  mov    %r12,%rax
  movq   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **cpystrarr(char **dest, char **source) {
  char **dest_ptr = dest;
  while (*source != 0x0) {
    *dest_ptr = malloc(strlen(*source) + 1);
    strcpy(*dest_ptr, *source);
    dest_ptr += 1;
    source += 1;
  }
  *dest_ptr = 0x0;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<screentext_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L23
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L27
  mov    $0x0,%eax
  call   <screentext_newline@plt>
  jmp    L38
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <screentext_writecharnc@plt>
L38:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  call   <update_cursor@plt>
  nop
  leave
  ret
```

assistant: ```c
void screentext_print(char *c) {
  for (; *c; c++) {
    if (*c == '\n')
      screentext_newline();
    else
      screentext_writecharnc(*c);
  }
  update_cursor();
}
```