ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<uart_putdec>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0xa,%edi
  jbe    L22
  mov    %edi,%eax
  xor    %r12d,%r12d
  mov    $0xcccccccd,%ecx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %eax,%eax
  add    $0x1,%r12d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x6d,%edx
  ja     L18
  test   %r12b,%r12b
  js     L41
L33:
  mov    $0xcccccccd,%r13d
  mov    %r12d,%ebp
  mov    %r14d,%ebx
  xor    %eax,%eax
  test   %r12b,%r12b
  jle    L13
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %ebx,%ebx
  add    $0x1,%eax
  imul   %r13,%rbx
  shr    $0x23,%rbx
  cmp    %al,%r12b
  jne    L76
  lea    0x30(%rbx),%edi
  call   <uart_putc@plt>
  nopw   0x0(%rax,%rax,1)
L70:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  sub    $0x1,%bpl
  jne    L70
  sub    %ebx,%r14d
L6:
  sub    $0x1,%r12d
  mov    %r14d,%ebx
  xor    %eax,%eax
  mov    %r12d,%ebp
  test   %r12b,%r12b
  jg     L76
L13:
  lea    0x30(%r14),%edi
  call   <uart_putc@plt>
  mov    %r12d,%eax
  sub    $0x1,%al
  jns    L30
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  xor    %r12d,%r12d
  jmp    L33
L30:
  xor    %r14d,%r14d
  jmp    L6
```

assistant: ```c
void uart_putdec(unsigned int val) {
  unsigned int tmp, val2 = val;
  signed char ts = 0, i = 0;
  tmp = val2;
  while (tmp > 10) {
    tmp /= 10;
    ts++;
  }
  while (ts >= 0) {
    tmp = val2;
    while (i < ts) {
      tmp /= 10;
      i++;
    }
    uart_putc(tmp + 48);
    while (i > 0) {
      tmp *= 10;
      i--;
    }
    val2 = val2 - tmp;
    ts--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uart_putdec>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0xa,%edi
  jbe    L12
  mov    %edi,%eax
  xor    %r12d,%r12d
  mov    $0xcccccccd,%ecx
  nopl   0x0(%rax,%rax,1)
L96:
  mov    %eax,%eax
  add    $0x1,%r12d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x6d,%edx
  ja     L96
  test   %r12b,%r12b
  js     L14
L35:
  mov    D6(%rip),%rbp
  mov    $0xcccccccd,%r13d
  mov    %r14d,%ebx
  xor    %eax,%eax
  test   %r12b,%r12b
  jle    L93
  nopw   0x0(%rax,%rax,1)
L1:
  imul   %r13,%rbx
  add    $0x1,%eax
  shr    $0x23,%rbx
  mov    %rbx,%r15
  mov    %ebx,%ebx
  cmp    %r12b,%al
  jne    L1
  lea    0x30(%rbx),%edi
  call   <uart_putc@plt>
  cmp    $0x1,%r12b
  je     L110
  mov    %r12d,%edx
  xor    %eax,%eax
  movq   %rbp,%xmm0
  shr    %dl
  nop
L38:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %al,%dl
  ja     L38
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%ebx
  imul   %eax,%ebx
  imul   %r15d,%ebx
  test   $0x1,%r12b
  je     L88
L110:
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
L88:
  sub    %ebx,%r14d
L48:
  sub    $0x1,%r12d
  mov    %r14d,%ebx
  xor    %eax,%eax
  test   %r12b,%r12b
  jg     L1
L93:
  lea    0x30(%r14),%edi
  call   <uart_putc@plt>
  mov    %r12d,%eax
  sub    $0x1,%al
  jns    L3
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  xor    %r12d,%r12d
  jmp    L35
L3:
  xor    %r14d,%r14d
  jmp    L48
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: byte[8]

tool: {"D6": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void uart_putdec(unsigned int val) {
  unsigned int tmp, val2 = val;
  signed char ts = 0, i = 0;
  tmp = val2;
  while (tmp > 10) {
    tmp /= 10;
    ts++;
  }
  while (ts >= 0) {
    tmp = val2;
    while (i < ts) {
      tmp /= 10;
      i++;
    }
    uart_putc(tmp + 48);
    while (i > 0) {
      tmp *= 10;
      i--;
    }
    val2 = val2 - tmp;
    ts--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<numeric_str_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L11
  mov    $0x1,%eax
  jmp    L18
L11:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L32
  mov    $0xffffffff,%eax
  jmp    L18
L32:
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int numeric_str_cmp(const void *a, const void *b) {
  double aa = atof(*((const char **)a));
  double bb = atof(*((const char **)b));
  if (aa > bb)
    return 1;
  else if (aa < bb)
    return -1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<numeric_str_cmp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    (%rdi),%rdi
  call   <atof@plt>
  movq   %xmm0,%rbx
  mov    0x0(%rbp),%rdi
  call   <atof@plt>
  mov    $0x1,%eax
  movq   %rbx,%xmm1
  comisd %xmm0,%xmm1
  ja     L2
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  neg    %eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numeric_str_cmp(const void *a, const void *b) {
  double aa = atof(*((const char **)a));
  double bb = atof(*((const char **)b));
  if (aa > bb)
    return 1;
  else if (aa < bb)
    return -1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numeric_str_cmp>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  call   <atof@plt>
  mov    (%rbx),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L3
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  neg    %eax
L3:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int numeric_str_cmp(const void *a, const void *b) {
  double aa = atof(*((const char **)a));
  double bb = atof(*((const char **)b));
  if (aa > bb)
    return 1;
  else if (aa < bb)
    return -1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<numeric_str_cmp>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  call   <atof@plt>
  mov    (%rbx),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L0
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  neg    %eax
L0:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int numeric_str_cmp(const void *a, const void *b) {
  double aa = atof(*((const char **)a));
  double bb = atof(*((const char **)b));
  if (aa > bb)
    return 1;
  else if (aa < bb)
    return -1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_separator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L36
  mov    $0x0,%eax
  jmp    L25
L36:
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int is_separator(char *line) {
  unsigned int i;
  for (i = 0; line[i] != '\0'; i++) {
    if (line[i] != '-') {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_separator>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  mov    $0x0,%edx
L28:
  cmp    $0x2d,%al
  jne    L2
  add    $0x1,%edx
  mov    %edx,%eax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L28
  mov    $0x1,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_separator(char *line) {
  unsigned int i;
  for (i = 0; line[i] != '\0'; i++) {
    if (line[i] != '-') {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_separator>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  xor    %edx,%edx
  jmp    L23
  nop
L22:
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L26
L23:
  cmp    $0x2d,%al
  je     L22
  xor    %eax,%eax
  ret
  nopl   (%rax)
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_separator(char *line) {
  unsigned int i;
  for (i = 0; line[i] != '\0'; i++) {
    if (line[i] != '-') {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_separator>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  xor    %edx,%edx
  jmp    L4
  nop
L12:
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L2
L4:
  cmp    $0x2d,%al
  je     L12
  xor    %eax,%eax
  ret
  nopl   (%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_separator(char *line) {
  unsigned int i;
  for (i = 0; line[i] != '\0'; i++) {
    if (line[i] != '-') {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<suma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float suma(int a, int b) {
  float c;
  c = a + b;
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<suma>:
  endbr64
  add    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  ret
```

assistant: ```c
float suma(int a, int b) {
  float c;
  c = a + b;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<suma>:
  endbr64
  add    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  ret
```

assistant: ```c
float suma(int a, int b) {
  float c;
  c = a + b;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<suma>:
  endbr64
  add    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  ret
```

assistant: ```c
float suma(int a, int b) {
  float c;
  c = a + b;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L1:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0xa,-0x4(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: No debo fumar en clases


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 10; i++) {
    printf("No debo fumar en clases\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebx
  lea    D4(%rip),%rbp
L6:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: No debo fumar en clases


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 10; i++) {
    printf("No debo fumar en clases\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: No debo fumar en clases


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 10; i++) {
    printf("No debo fumar en clases\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: No debo fumar en clases


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 10; i++) {
    printf("No debo fumar en clases\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<speed_nothing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  jmp    L8
L7:
  mov    $0x0,%eax
  call   <cpucycles@plt>
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x60(%rbp,%rdx,8)
  addl   $0x1,-0x64(%rbp)
L8:
  cmpl   $0x9,-0x64(%rbp)
  jle    L7
  lea    -0x60(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print_bench@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: nothing

assistant: ```c
void speed_nothing() {
  unsigned long long t[10];
  int i;
  for (i = 0; i < 10; i++)
    t[i] = cpucycles();
  print_bench("nothing", t, 10);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<speed_nothing>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
L15:
  mov    $0x0,%eax
  call   <cpucycles@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L15
  mov    %rsp,%rsi
  mov    $0xa,%edx
  lea    D1(%rip),%rdi
  call   <print_bench@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: nothing

assistant: ```c
void speed_nothing() {
  unsigned long long t[10];
  int i;
  for (i = 0; i < 10; i++)
    t[i] = cpucycles();
  print_bench("nothing", t, 10);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<speed_nothing>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rbp
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <cpucycles@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L4
  mov    $0xa,%edx
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <print_bench@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: nothing

assistant: ```c
void speed_nothing() {
  unsigned long long t[10];
  int i;
  for (i = 0; i < 10; i++)
    t[i] = cpucycles();
  print_bench("nothing", t, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<speed_nothing>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rbp
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <cpucycles@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L17
  mov    $0xa,%edx
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <print_bench@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: nothing

assistant: ```c
void speed_nothing() {
  unsigned long long t[10];
  int i;
  for (i = 0; i < 10; i++)
    t[i] = cpucycles();
  print_bench("nothing", t, 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel_dgecp_3_0_lib4>:
  endbr64
  mov    %edi,%r9d
  mov    %rcx,%rdi
  cmp    $0x1,%r9d
  sete   %al
  movzbl %al,%eax
  lea    (%rsi,%rax,1),%ecx
  test   %ecx,%ecx
  jle    L16
  cmp    $0x3,%ecx
  jle    L62
  lea    -0x4(%rcx),%r10d
  shr    $0x2,%r10d
  lea    0x1(%r10),%r8d
  mov    %r8d,%r8d
  shl    $0x7,%r8
  lea    (%rdx,%r8,1),%rsi
  mov    %rdi,%rax
L52:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rax)
  movsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rax)
  movsd  0x20(%rdx),%xmm0
  movsd  %xmm0,0x20(%rax)
  movsd  0x28(%rdx),%xmm0
  movsd  %xmm0,0x28(%rax)
  movsd  0x30(%rdx),%xmm0
  movsd  %xmm0,0x30(%rax)
  movsd  0x40(%rdx),%xmm0
  movsd  %xmm0,0x40(%rax)
  movsd  0x48(%rdx),%xmm0
  movsd  %xmm0,0x48(%rax)
  movsd  0x50(%rdx),%xmm0
  movsd  %xmm0,0x50(%rax)
  movsd  0x60(%rdx),%xmm0
  movsd  %xmm0,0x60(%rax)
  movsd  0x68(%rdx),%xmm0
  movsd  %xmm0,0x68(%rax)
  movsd  0x70(%rdx),%xmm0
  movsd  %xmm0,0x70(%rax)
  sub    $0xffffffffffffff80,%rdx
  sub    $0xffffffffffffff80,%rax
  cmp    %rsi,%rdx
  jne    L52
  add    %r8,%rdi
  lea    0x4(,%r10,4),%r10d
  cmp    %r10d,%ecx
  jle    L23
L72:
  mov    %r10d,%r8d
  mov    %rdi,%rdx
  mov    %rsi,%rax
L79:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,0x10(%rdx)
  add    $0x20,%rax
  add    $0x20,%rdx
  add    $0x1,%r8d
  cmp    %r8d,%ecx
  jg     L79
  lea    -0x1(%rcx),%eax
  sub    %r10d,%eax
  add    $0x1,%rax
  shl    $0x5,%rax
  cmp    %r10d,%ecx
  mov    $0x20,%edx
  cmovle %rdx,%rax
  add    %rax,%rsi
  add    %rax,%rdi
L23:
  cmp    $0x1,%r9d
  je     L71
L16:
  ret
L62:
  mov    %rdx,%rsi
  mov    $0x0,%r10d
  jmp    L72
L71:
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x30(%rsi),%xmm0
  movsd  %xmm0,0x30(%rdi)
  jmp    L16
```

assistant: ```c
void kernel_dgecp_3_0_lib4(int tri, int kmax, double *A, double *B) {
  if (tri == 1) {
    kmax += 1;
  }
  if (kmax <= 0)
    return;
  const int bs = 4;
  int k;
  for (k = 0; k < kmax - 3; k += 4) {
    B[0 + bs * 0] = A[0 + bs * 0];
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    B[0 + bs * 1] = A[0 + bs * 1];
    B[1 + bs * 1] = A[1 + bs * 1];
    B[2 + bs * 1] = A[2 + bs * 1];
    B[0 + bs * 2] = A[0 + bs * 2];
    B[1 + bs * 2] = A[1 + bs * 2];
    B[2 + bs * 2] = A[2 + bs * 2];
    B[0 + bs * 3] = A[0 + bs * 3];
    B[1 + bs * 3] = A[1 + bs * 3];
    B[2 + bs * 3] = A[2 + bs * 3];
    A += 16;
    B += 16;
  }
  for (; k < kmax; k++) {
    B[0 + bs * 0] = A[0 + bs * 0];
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    A += 4;
    B += 4;
  }
  if (tri == 1) {
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    B[2 + bs * 1] = A[2 + bs * 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kernel_dgecp_3_0_lib4>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  mov    %edi,%r8d
  mov    %rdx,%r9
  sete   %al
  add    %eax,%esi
  test   %esi,%esi
  jle    L2
  cmp    $0x3,%esi
  jle    L58
  lea    -0x4(%rsi),%edx
  mov    %r9,%rax
  shr    $0x2,%edx
  lea    0x1(%rdx),%r10d
  mov    %r10,%rdx
  shl    $0x7,%r10
  lea    (%rcx,%r10,1),%rdi
  nopl   (%rax)
L44:
  movsd  (%rax),%xmm0
  sub    $0xffffffffffffff80,%rcx
  sub    $0xffffffffffffff80,%rax
  movsd  %xmm0,-0x80(%rcx)
  movsd  -0x78(%rax),%xmm0
  movsd  %xmm0,-0x78(%rcx)
  movsd  -0x70(%rax),%xmm0
  movsd  %xmm0,-0x70(%rcx)
  movsd  -0x60(%rax),%xmm0
  movsd  %xmm0,-0x60(%rcx)
  movsd  -0x58(%rax),%xmm0
  movsd  %xmm0,-0x58(%rcx)
  movsd  -0x50(%rax),%xmm0
  movsd  %xmm0,-0x50(%rcx)
  movsd  -0x40(%rax),%xmm0
  movsd  %xmm0,-0x40(%rcx)
  movsd  -0x38(%rax),%xmm0
  movsd  %xmm0,-0x38(%rcx)
  movsd  -0x30(%rax),%xmm0
  movsd  %xmm0,-0x30(%rcx)
  movsd  -0x20(%rax),%xmm0
  movsd  %xmm0,-0x20(%rcx)
  movsd  -0x18(%rax),%xmm0
  movsd  %xmm0,-0x18(%rcx)
  movsd  -0x10(%rax),%xmm0
  movsd  %xmm0,-0x10(%rcx)
  cmp    %rdi,%rcx
  jne    L44
  lea    0x0(,%rdx,4),%ecx
  add    %r10,%r9
  cmp    %esi,%ecx
  jge    L59
L65:
  mov    %ecx,%r10d
  mov    %rdi,%rdx
  mov    %r9,%rax
L9:
  movsd  (%rax),%xmm0
  add    $0x1,%r10d
  add    $0x20,%rax
  add    $0x20,%rdx
  movsd  %xmm0,-0x20(%rdx)
  movsd  -0x18(%rax),%xmm0
  movsd  %xmm0,-0x18(%rdx)
  movsd  -0x10(%rax),%xmm0
  movsd  %xmm0,-0x10(%rdx)
  cmp    %r10d,%esi
  jg     L9
  lea    -0x1(%rsi),%eax
  mov    $0x20,%edx
  sub    %ecx,%eax
  add    $0x1,%rax
  shl    $0x5,%rax
  cmp    %ecx,%esi
  cmovle %rdx,%rax
  add    %rax,%r9
  add    %rax,%rdi
L59:
  cmp    $0x1,%r8d
  je     L69
L2:
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  movsd  0x8(%r9),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%r9),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movsd  0x30(%r9),%xmm0
  movsd  %xmm0,0x30(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  jmp    L65
```

assistant: ```c
void kernel_dgecp_3_0_lib4(int tri, int kmax, double *A, double *B) {
  if (tri == 1) {
    kmax += 1;
  }
  if (kmax <= 0)
    return;
  const int bs = 4;
  int k;
  for (k = 0; k < kmax - 3; k += 4) {
    B[0 + bs * 0] = A[0 + bs * 0];
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    B[0 + bs * 1] = A[0 + bs * 1];
    B[1 + bs * 1] = A[1 + bs * 1];
    B[2 + bs * 1] = A[2 + bs * 1];
    B[0 + bs * 2] = A[0 + bs * 2];
    B[1 + bs * 2] = A[1 + bs * 2];
    B[2 + bs * 2] = A[2 + bs * 2];
    B[0 + bs * 3] = A[0 + bs * 3];
    B[1 + bs * 3] = A[1 + bs * 3];
    B[2 + bs * 3] = A[2 + bs * 3];
    A += 16;
    B += 16;
  }
  for (; k < kmax; k++) {
    B[0 + bs * 0] = A[0 + bs * 0];
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    A += 4;
    B += 4;
  }
  if (tri == 1) {
    B[1 + bs * 0] = A[1 + bs * 0];
    B[2 + bs * 0] = A[2 + bs * 0];
    B[2 + bs * 1] = A[2 + bs * 1];
  }
}
```