ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7fffffff,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xfffffffe,%eax
  mov    %eax,%ebp
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%esi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffffff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffffff00,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffff00ff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xff00ffff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffffff00,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffffff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xff00ffff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffff00ff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: u(%x)


assistant: ```c
int main() {
  unsigned u;
  u = reverse_bits(0x7fffffff);
  assert(u == 0xfffffffe);
  printf("u(%x)\n", u);
  u = reverse_bits(0x00ffffff);
  assert(u == 0xffffff00);
  printf("u(%x)\n", u);
  u = reverse_bits(0xffff00ff);
  assert(u == 0xff00ffff);
  printf("u(%x)\n", u);
  u = reverse_bits(0xffffff00);
  assert(u == 0x00ffffff);
  printf("u(%x)\n", u);
  u = reverse_bits(0xff00ffff);
  assert(u == 0xffff00ff);
  printf("u(%x)\n", u);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7fffffff,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xfffffffe,%eax
  mov    %eax,%ebp
  sete   %dil
  call   <assert@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffffff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffffff00,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffff00ff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xff00ffff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xffffff00,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffffff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xff00ffff,%edi
  call   <reverse_bits@plt>
  xor    %edi,%edi
  cmp    $0xffff00ff,%eax
  mov    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: u(%x)


assistant: ```c
int main() {
  unsigned u;
  u = reverse_bits(0x7fffffff);
  assert(u == 0xfffffffe);
  printf("u(%x)\n", u);
  u = reverse_bits(0x00ffffff);
  assert(u == 0xffffff00);
  printf("u(%x)\n", u);
  u = reverse_bits(0xffff00ff);
  assert(u == 0xff00ffff);
  printf("u(%x)\n", u);
  u = reverse_bits(0xffffff00);
  assert(u == 0x00ffffff);
  printf("u(%x)\n", u);
  u = reverse_bits(0xff00ffff);
  assert(u == 0xffff00ff);
  printf("u(%x)\n", u);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<spgat_standardize_cell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L36
  cmpl   $0x0,-0x24(%rbp)
  je     L31
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rdi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    $0x1,%r8d
  mov    %rax,%rdi
  call   <get_standardized_cell@plt>
  jmp    L12
L31:
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rdi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <standardize_primitive@plt>
  jmp    L12
L36:
  cmpl   $0x0,-0x24(%rbp)
  je     L8
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rdi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <get_standardized_cell@plt>
  jmp    L12
L8:
  movsd  -0x38(%rbp),%xmm0
  mov    -0x30(%rbp),%rdi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <standardize_cell@plt>
L12:
  leave
  ret
```

assistant: ```c
int spgat_standardize_cell(double lattice[3][3], double position[][3], int types[], const int num_atom, const int to_primitive, const int no_idealize, const double symprec, const double angle_tolerance) {
  if (to_primitive) {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 1, symprec, angle_tolerance);
    } else {
      return standardize_primitive(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  } else {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 0, symprec, angle_tolerance);
    } else {
      return standardize_cell(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spgat_standardize_cell>:
  endbr64
  sub    $0x8,%rsp
  test   %r8d,%r8d
  je     L42
  test   %r9d,%r9d
  je     L43
  mov    $0x1,%r8d
  call   <get_standardized_cell@plt>
L31:
  add    $0x8,%rsp
  ret
L43:
  call   <standardize_primitive@plt>
  jmp    L31
L42:
  test   %r9d,%r9d
  je     L0
  mov    $0x0,%r8d
  call   <get_standardized_cell@plt>
  jmp    L31
L0:
  call   <standardize_cell@plt>
  jmp    L31
```

assistant: ```c
int spgat_standardize_cell(double lattice[3][3], double position[][3], int types[], const int num_atom, const int to_primitive, const int no_idealize, const double symprec, const double angle_tolerance) {
  if (to_primitive) {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 1, symprec, angle_tolerance);
    } else {
      return standardize_primitive(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  } else {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 0, symprec, angle_tolerance);
    } else {
      return standardize_cell(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<spgat_standardize_cell>:
  endbr64
  test   %r8d,%r8d
  je     L18
  test   %r9d,%r9d
  je     L24
  mov    $0x1,%r8d
  jmp    1080 <get_standardized_cell@plt>
  nopl   0x0(%rax)
L18:
  test   %r9d,%r9d
  je     L12
  xor    %r8d,%r8d
  jmp    1080 <get_standardized_cell@plt>
  nopl   (%rax)
L12:
  jmp    1090 <standardize_cell@plt>
  nopl   (%rax)
L24:
  jmp    1070 <standardize_primitive@plt>
```

assistant: ```c
int spgat_standardize_cell(double lattice[3][3], double position[][3], int types[], const int num_atom, const int to_primitive, const int no_idealize, const double symprec, const double angle_tolerance) {
  if (to_primitive) {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 1, symprec, angle_tolerance);
    } else {
      return standardize_primitive(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  } else {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 0, symprec, angle_tolerance);
    } else {
      return standardize_cell(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<spgat_standardize_cell>:
  endbr64
  test   %r8d,%r8d
  je     L6
  test   %r9d,%r9d
  je     L3
  mov    $0x1,%r8d
  jmp    1080 <get_standardized_cell@plt>
  nopl   0x0(%rax)
L6:
  test   %r9d,%r9d
  je     L17
  xor    %r8d,%r8d
  jmp    1080 <get_standardized_cell@plt>
  nopl   (%rax)
L17:
  jmp    1090 <standardize_cell@plt>
  nopl   (%rax)
L3:
  jmp    1070 <standardize_primitive@plt>
```

assistant: ```c
int spgat_standardize_cell(double lattice[3][3], double position[][3], int types[], const int num_atom, const int to_primitive, const int no_idealize, const double symprec, const double angle_tolerance) {
  if (to_primitive) {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 1, symprec, angle_tolerance);
    } else {
      return standardize_primitive(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  } else {
    if (no_idealize) {
      return get_standardized_cell(lattice, position, types, num_atom, 0, symprec, angle_tolerance);
    } else {
      return standardize_cell(lattice, position, types, num_atom, symprec, angle_tolerance);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup(const char *str) {
  int n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup)
    strcpy(dup, str);
  return dup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdup(const char *str) {
  int n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup)
    strcpy(dup, str);
  return dup;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  int n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup)
    strcpy(dup, str);
  return dup;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *str) {
  int n = strlen(str) + 1;
  char *dup = malloc(n);
  if (dup)
    strcpy(dup, str);
  return dup;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L9
  movsd  -0x8(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L7
L9:
  movsd  -0x8(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L7:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: f64

tool: D2: 0.5

assistant: ```c
int round(double s) {
  if (s >= 0)
    s = s + 0.5;
  else
    s = s - 0.5;
  return ((int)s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<round>:
  endbr64
  comisd D4(%rip),%xmm0
  jb     L6
  addsd  D23(%rip),%xmm0
L10:
  cvttsd2si %xmm0,%eax
  ret
L6:
  subsd  D23(%rip),%xmm0
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: byte[16]
name: unpack_data
arguments: tag: D23
datatype: f64

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D23: 0.5

assistant: ```c
int round(double s) {
  if (s >= 0)
    s = s + 0.5;
  else
    s = s - 0.5;
  return ((int)s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<round>:
  endbr64
  comisd D7(%rip),%xmm0
  jb     L2
  addsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  subsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: byte[16]
name: parse_data
arguments: label: D26
data_type: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D26: 0.5

assistant: ```c
int round(double s) {
  if (s >= 0)
    s = s + 0.5;
  else
    s = s - 0.5;
  return ((int)s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<round>:
  endbr64
  comisd D19(%rip),%xmm0
  jb     L3
  addsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  subsd  D1(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: byte[16]
name: unpack_data
arguments: data_tag: D1
type_infered: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D1: 0.5

assistant: ```c
int round(double s) {
  if (s >= 0)
    s = s + 0.5;
  else
    s = s - 0.5;
  return ((int)s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <reverse@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  reverse();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <reverse@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  reverse();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reverse@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  reverse();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reverse@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  reverse();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x51e22cdb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L2:
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L1:
  mov    -0xc(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  shr    %eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  rol    %cl,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  xor    %ecx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x0,-0x14(%rbp)
  je     L1
  addl   $0x1,-0x10(%rbp)
L38:
  cmpl   $0x0,-0x10(%rbp)
  je     L2
  mov    -0xc(%rbp),%eax
  add    $0xf40537d,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << 1U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %edx,%eax
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  lea    0x1e80a6fa(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << 1U;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  lea    0x1e80a6fa(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << 1U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  lea    0x1e80a6fa(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << 1U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L67
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L67:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L11
  cmpl   $0xffff,-0x4(%rbp)
  jle    L92
L11:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L92:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x63,%al
  jne    L72
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L76
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L6
L76:
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <client@plt>
  jmp    L6
L72:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L105
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <server@plt>
  jmp    L6
L105:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D35
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D23: Command should be: myprog s <port> or myprog c <port> <address>

tool: D19: Port number should be equal to or larger than 1024 and smaller than 65535

tool: D35: NO IP address is given

tool: D26: unknown command type %s
Command should be: myprog s <port> or myprog c <port> <address>

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    printf("Command should be: myprog s <port> or myprog c <port> <address>\n");
    return 1;
  }
  int port = atoi(argv[2]);
  if (port < 1024 || port > 65535) {
    printf("Port number should be equal to or larger than 1024 and smaller than 65535\n");
    return 1;
  }
  if (argv[1][0] == 'c') {
    if (argv[3] == NULL) {
      printf("NO IP address is given\n");
      return 1;
    }
    return client(argv[3], port);
  } else if (argv[1][0] == 's') {
    return server(port);
  } else {
    printf("unknown command type %s\nCommand should be: myprog s <port> or myprog c <port> <address>", argv[1]);
    return 1;
  }
  return 0;
}
```