ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<countCheck>:
  endbr64
  mov    %esi,%edx
  test   %si,%si
  je     L104
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%ax
  jbe    L4
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x4,%cx
  sub    $0x1,%ecx
  movzwl %cx,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddb  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L18
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfff0,%esi
  and    $0xfffffff0,%ecx
  paddb  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  add    %rdi,%rsi
  psadbw %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0xf,%dl
  je     L118
L15:
  mov    %edx,%r8d
  sub    %ecx,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9w
  jbe    L55
  movzwl %cx,%r9d
  pxor   %xmm0,%xmm0
  movq   (%rdi,%r9,1),%xmm1
  mov    %r8,%r9
  and    $0xfff8,%r9d
  movdqa %xmm1,%xmm3
  add    %r9,%rsi
  psadbw %xmm0,%xmm3
  movq   %xmm3,%rdi
  add    %edi,%eax
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%ecx
  cmp    %di,%r8w
  je     L118
L55:
  lea    0x1(%rcx),%edi
  add    (%rsi),%al
  cmp    %di,%dx
  jbe    L118
  lea    0x2(%rcx),%edi
  add    0x1(%rsi),%al
  cmp    %di,%dx
  jbe    L118
  lea    0x3(%rcx),%edi
  add    0x2(%rsi),%al
  cmp    %di,%dx
  jbe    L118
  lea    0x4(%rcx),%edi
  add    0x3(%rsi),%al
  cmp    %di,%dx
  jbe    L118
  lea    0x5(%rcx),%edi
  add    0x4(%rsi),%al
  cmp    %di,%dx
  jbe    L118
  add    $0x6,%ecx
  add    0x5(%rsi),%al
  cmp    %cx,%dx
  jbe    L118
  add    0x6(%rsi),%al
L118:
  neg    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L104:
  xor    %eax,%eax
  ret
L4:
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
unsigned char countCheck(unsigned char *data, unsigned short len) {
  unsigned char cs = 0;
  unsigned short i;
  for (i = 0; i < len; i++, data++)
    cs += *data;
  return ((~cs) + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L51
  cmpq   $0x0,-0x28(%rbp)
  je     L51
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L11
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L11:
  addl   $0x1,-0x8(%rbp)
L73:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L65
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  jmp    L65
L36:
  nop
L65:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L51:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getNum(char *dest, int dsize, const char *src, int ssize) {
  int ret = 0;
  if (dest && src) {
    int i, j;
    memset(dest, 0, dsize);
    for (i = 0, j = 0; i < ssize && i < dsize; i++) {
      if (isspace(src[i])) {
        break;
      } else if (isdigit(src[i])) {
        dest[j++] = src[i];
      }
    }
    ret = j;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getNum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L71
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  test   %rdx,%rdx
  jne    L48
L71:
  mov    $0x0,%ebp
L53:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  mov    %esi,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  cmp    %r13d,%ebx
  mov    %r13d,%esi
  cmovle %ebx,%esi
  test   %esi,%esi
  jle    L8
  mov    %rbp,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rbp,%rax,1),%r14
  mov    $0x0,%ebp
  jmp    L68
L22:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L53
L68:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L53
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L22
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  mov    %dl,(%r12,%rax,1)
  lea    0x1(%rbp),%ebp
  jmp    L22
L8:
  mov    $0x0,%ebp
  jmp    L53
```

assistant: ```c
int getNum(char *dest, int dsize, const char *src, int ssize) {
  int ret = 0;
  if (dest && src) {
    int i, j;
    memset(dest, 0, dsize);
    for (i = 0, j = 0; i < ssize && i < dsize; i++) {
      if (isspace(src[i])) {
        break;
      } else if (isdigit(src[i])) {
        dest[j++] = src[i];
      }
    }
    ret = j;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<getNum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L26
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L41
L26:
  xor    %r12d,%r12d
L25:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L41:
  mov    %esi,%r12d
  mov    %ecx,%r13d
  mov    %esi,%edx
  xor    %esi,%esi
  mov    %rdi,%rbp
  call   <memset@plt>
  cmp    %r13d,%r12d
  mov    %r13d,%esi
  cmovle %r12d,%esi
  test   %esi,%esi
  jle    L26
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L43
  nopl   (%rax)
L29:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L5
  movzbl (%rbx),%edx
  movslq %r12d,%rax
  add    $0x1,%r12d
  mov    %dl,0x0(%rbp,%rax,1)
L5:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L25
L43:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L29
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getNum(char *dest, int dsize, const char *src, int ssize) {
  int ret = 0;
  if (dest && src) {
    int i, j;
    memset(dest, 0, dsize);
    for (i = 0, j = 0; i < ssize && i < dsize; i++) {
      if (isspace(src[i])) {
        break;
      } else if (isdigit(src[i])) {
        dest[j++] = src[i];
      }
    }
    ret = j;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getNum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L7
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L68
L7:
  xor    %r12d,%r12d
L32:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L68:
  mov    %esi,%r12d
  mov    %ecx,%r13d
  mov    %esi,%edx
  xor    %esi,%esi
  mov    %rdi,%rbp
  call   <memset@plt>
  cmp    %r13d,%r12d
  mov    %r13d,%esi
  cmovle %r12d,%esi
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L50
  nopl   (%rax)
L2:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L25
  movzbl (%rbx),%edx
  movslq %r12d,%rax
  add    $0x1,%r12d
  mov    %dl,0x0(%rbp,%rax,1)
L25:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L32
L50:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getNum(char *dest, int dsize, const char *src, int ssize) {
  int ret = 0;
  if (dest && src) {
    int i, j;
    memset(dest, 0, dsize);
    for (i = 0, j = 0; i < ssize && i < dsize; i++) {
      if (isspace(src[i])) {
        break;
      } else if (isdigit(src[i])) {
        dest[j++] = src[i];
      }
    }
    ret = j;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<function_causing_seg_fault>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x186a0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L3:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void function_causing_seg_fault(void) {
  const int numberOfIntegers = 100000;
  int *p = (int *)malloc(numberOfIntegers);
  int i;
  for (i = 0; i < numberOfIntegers; ++i)
    p[i] = i;
  free(p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<function_causing_seg_fault>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x186a0,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rcx
  mov    $0x0,%edx
L2:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    $0x186a0,%edx
  jne    L2
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void function_causing_seg_fault(void) {
  const int numberOfIntegers = 100000;
  int *p = (int *)malloc(numberOfIntegers);
  int i;
  for (i = 0; i < numberOfIntegers; ++i)
    p[i] = i;
  free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<function_causing_seg_fault>:
  endbr64
  mov    $0x186a0,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %edx,(%rcx)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    $0x186a0,%edx
  jne    L8
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

assistant: ```c
void function_causing_seg_fault(void) {
  const int numberOfIntegers = 100000;
  int *p = (int *)malloc(numberOfIntegers);
  int i;
  for (i = 0; i < numberOfIntegers; ++i)
    p[i] = i;
  free(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<function_causing_seg_fault>:
  endbr64
  mov    $0x186a0,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  movdqa D12(%rip),%xmm0
  movdqa D4(%rip),%xmm2
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x61a80(%rax),%rcx
  nop
L2:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L2
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type: byte[16]
name: extract_symbolic_data
arguments: tag: D4
type: byte[16]

tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void function_causing_seg_fault(void) {
  const int numberOfIntegers = 100000;
  int *p = (int *)malloc(numberOfIntegers);
  int i;
  for (i = 0; i < numberOfIntegers; ++i)
    p[i] = i;
  free(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<charge_fraction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L33
  movsd  -0x8(%rbp),%xmm1
  movsd  D47(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D47(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L27
L33:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L11
  movsd  -0x8(%rbp),%xmm1
  movsd  D47(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L27
L11:
  movsd  D47(%rip),%xmm0
L27:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
type_guessed: f64
name: disassemble_data
arguments: data_tag: D47
type_guessed: f64

tool: D26: 1.2766

tool: D47: 1

assistant: ```c
double charge_fraction(double charge) {
  const double charge_ratio = 1.2766;
  if (charge < 0.)
    return 1. / (1. + charge_ratio);
  else if (charge > 0.)
    return charge_ratio / (1. + charge_ratio);
  else
    return 1.;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<charge_fraction>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L29
  movsd  D17(%rip),%xmm1
  comisd D1(%rip),%xmm0
  jbe    L20
L17:
  movapd %xmm1,%xmm0
  ret
L20:
  movsd  D8(%rip),%xmm1
  jmp    L17
L29:
  movsd  D13(%rip),%xmm1
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D1
type_infered: f64
name: unpack_data
arguments: data_tag: D8
type_infered: f64
name: unpack_data
arguments: data_tag: D13
type_infered: byte[8]

tool: {"D17": [0x53,0xff,0x51,0xce,0xa6,0xf1,0xe1,0x3f]}

tool: D1: 0

tool: D8: 1

tool: {"D13": [0x59,0x01,0x5c,0x63,0xb2,0x1c,0xdc,0x3f]}

assistant: ```c
double charge_fraction(double charge) {
  const double charge_ratio = 1.2766;
  if (charge < 0.)
    return 1. / (1. + charge_ratio);
  else if (charge > 0.)
    return charge_ratio / (1. + charge_ratio);
  else
    return 1.;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<charge_fraction>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L4
  comisd %xmm1,%xmm0
  movsd  D7(%rip),%xmm2
  jbe    L11
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  movsd  D27(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L4:
  movsd  D8(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: byte[8]
name: unpack_data
arguments: data_label: D27
data_type: f64
name: unpack_data
arguments: data_label: D8
data_type: byte[8]

tool: {"D7": [0x53,0xff,0x51,0xce,0xa6,0xf1,0xe1,0x3f]}

tool: D27: 1

tool: {"D8": [0x59,0x01,0x5c,0x63,0xb2,0x1c,0xdc,0x3f]}

assistant: ```c
double charge_fraction(double charge) {
  const double charge_ratio = 1.2766;
  if (charge < 0.)
    return 1. / (1. + charge_ratio);
  else if (charge > 0.)
    return charge_ratio / (1. + charge_ratio);
  else
    return 1.;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<charge_fraction>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L4
  comisd %xmm1,%xmm0
  movsd  D2(%rip),%xmm2
  jbe    L11
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  movsd  D0(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   (%rax)
L4:
  movsd  D14(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: byte[8]
name: parse_data
arguments: data_tag: D0
type: f64
name: parse_data
arguments: data_tag: D14
type: byte[8]

tool: {"D2": [0x53,0xff,0x51,0xce,0xa6,0xf1,0xe1,0x3f]}

tool: D0: 1

tool: {"D14": [0x59,0x01,0x5c,0x63,0xb2,0x1c,0xdc,0x3f]}

assistant: ```c
double charge_fraction(double charge) {
  const double charge_ratio = 1.2766;
  if (charge < 0.)
    return 1. / (1. + charge_ratio);
  else if (charge > 0.)
    return charge_ratio / (1. + charge_ratio);
  else
    return 1.;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_pthread@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_pthread();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_pthread@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_pthread();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_pthread@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_pthread();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_pthread@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_pthread();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%r10
  call   <should_appear1.0>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int fn3(int x) {
  int i = x;
  inline int should_appear1(void) {
    char *p = __builtin_alloca(i);
    check(p);
    return i;
  }
  return should_appear1();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fn3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %edi,(%rsp)
  mov    %rsp,%r10
  call   <should_appear1.0>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn3(int x) {
  int i = x;
  inline int should_appear1(void) {
    char *p = __builtin_alloca(i);
    check(p);
    return i;
  }
  return should_appear1();
}
```
user: What is the c source code of the assembly code below?

```asm
<fn3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  lea    0x30(%rsp),%rax
  mov    %edi,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <should_appear1.0>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn3(int x) {
  int i = x;
  inline int should_appear1(void) {
    char *p = __builtin_alloca(i);
    check(p);
    return i;
  }
  return should_appear1();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  lea    0x30(%rsp),%rax
  mov    %edi,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <should_appear1.0>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fn3(int x) {
  int i = x;
  inline int should_appear1(void) {
    char *p = __builtin_alloca(i);
    check(p);
    return i;
  }
  return should_appear1();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<slice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L10
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  je     L23
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addl   $0x1,-0x20(%rbp)
L23:
  addl   $0x1,-0x1c(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **slice(char **args, int argc, int index) {
  int next = 0;
  char **items = malloc((argc - 1) * sizeof(char *));
  for (int i = 0; i < argc; i++) {
    if (i != index) {
      items[next] = malloc(strlen(args[i]));
      strcpy(items[next], args[i]);
      next++;
    }
  }
  return items;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<slice>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%r14d
  lea    -0x8(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L38
  mov    %r12d,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L1
L8:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L38
L1:
  cmp    %ebx,%r14d
  je     L8
  mov    0x0(%r13,%rbx,8),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  movslq %ebp,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,8),%r15
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%r15)
  mov    0x0(%r13,%rbx,8),%rsi
  call   <strcpy@plt>
  add    $0x1,%ebp
  jmp    L8
L38:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **slice(char **args, int argc, int index) {
  int next = 0;
  char **items = malloc((argc - 1) * sizeof(char *));
  for (int i = 0; i < argc; i++) {
    if (i != index) {
      items[next] = malloc(strlen(args[i]));
      strcpy(items[next], args[i]);
      next++;
    }
  }
  return items;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<slice>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  lea    -0x8(,%rsi,8),%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %r12d,%r12d
  jle    L3
  movslq %r12d,%rax
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L24:
  cmp    %ebx,%r14d
  je     L7
  mov    0x0(%r13,%rbx,8),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  movslq %ebp,%rax
  add    $0x1,%ebp
  lea    (%r15,%rax,8),%r12
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L7:
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L24
L3:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **slice(char **args, int argc, int index) {
  int next = 0;
  char **items = malloc((argc - 1) * sizeof(char *));
  for (int i = 0; i < argc; i++) {
    if (i != index) {
      items[next] = malloc(strlen(args[i]));
      strcpy(items[next], args[i]);
      next++;
    }
  }
  return items;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<slice>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  lea    -0x8(,%rsi,8),%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %r12d,%r12d
  jle    L8
  movslq %r12d,%rax
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L29:
  cmp    %ebx,%r14d
  je     L20
  mov    0x0(%r13,%rbx,8),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  movslq %ebp,%rax
  add    $0x1,%ebp
  lea    (%r15,%rax,8),%r12
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L20:
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L29
L8:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **slice(char **args, int argc, int index) {
  int next = 0;
  char **items = malloc((argc - 1) * sizeof(char *));
  for (int i = 0; i < argc; i++) {
    if (i != index) {
      items[next] = malloc(strlen(args[i]));
      strcpy(items[next], args[i]);
      next++;
    }
  }
  return items;
}
```