ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Socket_Send>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  setle  %al
  test   %edi,%edi
  setle  %dl
  or     %dl,%al
  jne    L36
  mov    %edi,%r13d
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  test   %rsi,%rsi
  jne    L0
  jmp    L36
  xchg   %ax,%ax
L33:
  add    %eax,%ebx
  cmp    %ebx,%r12d
  je     L29
L0:
  mov    %r12d,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %rax,%rax
  jne    L33
L36:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  movslq %r12d,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t Socket_Send(int c_fd, const void *buf, ssize_t len) {
  ssize_t stop = 0, offset = 0;
  size_t nsend;
  const void *sBuf = buf;
  if (c_fd < 1)
    return -1;
  if (len < 1)
    return -1;
  if (sBuf == NULL)
    return -1;
  do {
    nsend = write(c_fd, sBuf + offset, (len - offset));
    if (nsend < 0) {
      if (errno == EAGAIN || errno == EINTR) {
        continue;
      }
    } else if (nsend == 0)
      return -1;
    offset += nsend;
    if (offset == len)
      stop = 1;
  } while (!stop);
  return offset;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Socket_Send>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  setle  %al
  test   %edi,%edi
  setle  %dl
  or     %dl,%al
  jne    L26
  mov    %edi,%r13d
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  test   %rsi,%rsi
  jne    L16
  jmp    L26
  xchg   %ax,%ax
L44:
  add    %eax,%ebx
  cmp    %ebx,%r12d
  je     L24
L16:
  mov    %r12d,%edx
  movslq %ebx,%rsi
  mov    %r13d,%edi
  sub    %ebx,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %rax,%rax
  jne    L44
L26:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L24:
  add    $0x8,%rsp
  movslq %r12d,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t Socket_Send(int c_fd, const void *buf, ssize_t len) {
  ssize_t stop = 0, offset = 0;
  size_t nsend;
  const void *sBuf = buf;
  if (c_fd < 1)
    return -1;
  if (len < 1)
    return -1;
  if (sBuf == NULL)
    return -1;
  do {
    nsend = write(c_fd, sBuf + offset, (len - offset));
    if (nsend < 0) {
      if (errno == EAGAIN || errno == EINTR) {
        continue;
      }
    } else if (nsend == 0)
      return -1;
    offset += nsend;
    if (offset == len)
      stop = 1;
  } while (!stop);
  return offset;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L19
  mov    -0x14(%rbp),%eax
  jmp    L7
L19:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n <= 1) {
    return n;
  }
  return fib(n - 1) + fib(n - 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fib>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  jle    L2
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  ret
```

assistant: ```c
int fib(int n) {
  if (n <= 1) {
    return n;
  }
  return fib(n - 1) + fib(n - 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<s_memcpy2orgb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x8,%eax
  sub    -0x44(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  mov    $0x8,%eax
  sub    0x10(%rbp),%eax
  mov    %eax,0x10(%rbp)
  mov    $0x8,%eax
  sub    0x18(%rbp),%eax
  mov    %eax,0x18(%rbp)
  jmp    L3
L19:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L28
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %al,-0x13(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x10,%eax
  mov    %al,-0x12(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x8,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x13(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x20(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  movzbl -0x12(%rbp),%edx
  mov    0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x28(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  movzbl -0x11(%rbp),%edx
  mov    0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    0x30(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
L28:
  addq   $0x2,-0x10(%rbp)
  addq   $0x4,-0x8(%rbp)
  addq   $0x1,-0x28(%rbp)
L3:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  test   %eax,%eax
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s_memcpy2orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned short int *d = (unsigned short int *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<s_memcpy2orgb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  mov    $0x8,%edx
  mov    %edx,%r11d
  sub    %r9d,%r11d
  mov    %edx,%ebp
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L4
  mov    %rdi,%rax
  mov    %rcx,%rdi
  mov    %edx,%r9d
  mov    %r8d,%r8d
  add    %rax,%r8
  jmp    L35
L21:
  add    $0x2,%rsi
  add    $0x4,%rdi
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L4
L35:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L21
  mov    (%rdi),%ebx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  mov    %ebp,%ecx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  or     %r15d,%edx
  shr    $0x18,%ebx
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dx,(%rsi)
  jmp    L21
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy2orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned short int *d = (unsigned short int *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: What is the c source code of the assembly code below?

```asm
<s_memcpy2orgb>:
  endbr64
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    $0x8,%edx
  push   %r15
  mov    %edx,%r11d
  push   %r14
  sub    %r9d,%r11d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L26
  mov    %rdi,%rax
  mov    %r8d,%r8d
  mov    %rcx,%rdi
  mov    %edx,%r9d
  add    %rax,%r8
  nopl   0x0(%rax)
L6:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L22
  mov    (%rdi),%ebx
  mov    %ebp,%ecx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  shr    $0x18,%ebx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  or     %r15d,%edx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dx,(%rsi)
L22:
  add    $0x1,%rax
  add    $0x2,%rsi
  add    $0x4,%rdi
  cmp    %rax,%r8
  jne    L6
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy2orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned short int *d = (unsigned short int *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<s_memcpy2orgb>:
  endbr64
  mov    %esi,%r10d
  mov    %rdx,%rsi
  mov    $0x8,%edx
  push   %r15
  mov    %edx,%r11d
  push   %r14
  sub    %r9d,%r11d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    0x48(%rsp),%r12d
  mov    0x50(%rsp),%r13d
  mov    0x58(%rsp),%r14d
  sub    0x38(%rsp),%ebp
  sub    0x40(%rsp),%edx
  test   %r8d,%r8d
  je     L4
  mov    %rdi,%rax
  mov    %r8d,%r8d
  mov    %rcx,%rdi
  mov    %edx,%r9d
  add    %rax,%r8
  nopl   0x0(%rax)
L21:
  movzbl (%rax),%edx
  cmp    %r10d,%edx
  jne    L18
  mov    (%rdi),%ebx
  mov    %ebp,%ecx
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  sar    %cl,%edx
  mov    %r13d,%ecx
  shl    %cl,%edx
  movzbl %bh,%ecx
  shr    $0x18,%ebx
  mov    %ecx,%r15d
  mov    %r9d,%ecx
  sar    %cl,%r15d
  mov    %r14d,%ecx
  shl    %cl,%r15d
  mov    %r11d,%ecx
  sar    %cl,%ebx
  mov    %r12d,%ecx
  or     %r15d,%edx
  shl    %cl,%ebx
  or     %ebx,%edx
  mov    %dx,(%rsi)
L18:
  add    $0x1,%rax
  add    $0x2,%rsi
  add    $0x4,%rdi
  cmp    %r8,%rax
  jne    L21
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_memcpy2orgb(unsigned char *m, int id, void *dest, unsigned int *rgb, int n, int rl, int gl, int bl, int ro, int go, int bo) {
  unsigned char dr;
  unsigned char dg;
  unsigned char db;
  unsigned short int *d = (unsigned short int *)dest;
  unsigned int *s = (unsigned int *)rgb;
  rl = 8 - rl;
  gl = 8 - gl;
  bl = 8 - bl;
  while (n--) {
    if (*m == id) {
      dr = *s >> 0x18;
      dg = *s >> 0x10;
      db = *s >> 0x08;
      *d = ((dr >> rl) << ro) | ((dg >> gl) << go) | ((db >> bl) << bo);
    }
    d++;
    s++;
    m++;
  };
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tcm_decision>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x380(%rax),%edx
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sar    $0xa,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x2,%eax
  shl    $0x8,%eax
  sub    $0xffffff80,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tcm_decision(int level, int sample) {
  int x, xs;
  x = (sample + (7 * 128) - (level << 8)) >> 10;
  xs = (((x << 2) + level - 2) << 8) + 128;
  return xs;
}
```
user: What is the c source code of the assembly code below?

```asm
<tcm_decision>:
  endbr64
  add    $0x380,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  sub    %eax,%esi
  sar    $0xa,%esi
  lea    -0x2(%rdi,%rsi,4),%eax
  shl    $0x8,%eax
  sub    $0xffffff80,%eax
  ret
```

assistant: ```c
int tcm_decision(int level, int sample) {
  int x, xs;
  x = (sample + (7 * 128) - (level << 8)) >> 10;
  xs = (((x << 2) + level - 2) << 8) + 128;
  return xs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tcm_decision>:
  endbr64
  mov    %edi,%eax
  add    $0x380,%esi
  shl    $0x8,%eax
  sub    %eax,%esi
  sar    $0xa,%esi
  lea    -0x2(%rdi,%rsi,4),%eax
  shl    $0x8,%eax
  sub    $0xffffff80,%eax
  ret
```

assistant: ```c
int tcm_decision(int level, int sample) {
  int x, xs;
  x = (sample + (7 * 128) - (level << 8)) >> 10;
  xs = (((x << 2) + level - 2) << 8) + 128;
  return xs;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tcm_decision>:
  endbr64
  mov    %edi,%eax
  add    $0x380,%esi
  shl    $0x8,%eax
  sub    %eax,%esi
  sar    $0xa,%esi
  lea    -0x2(%rdi,%rsi,4),%eax
  shl    $0x8,%eax
  sub    $0xffffff80,%eax
  ret
```

assistant: ```c
int tcm_decision(int level, int sample) {
  int x, xs;
  x = (sample + (7 * 128) - (level << 8)) >> 10;
  xs = (((x << 2) + level - 2) << 8) + 128;
  return xs;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L14
L48:
  movl   $0x0,-0x38(%rbp)
  jmp    L59
L49:
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x38(%rbp)
L59:
  cmpl   $0x2,-0x38(%rbp)
  jle    L49
  addl   $0x1,-0x34(%rbp)
L14:
  cmpl   $0x2,-0x34(%rbp)
  jle    L48
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x9,-0x38(%rbp)
  jmp    L34
L51:
  lea    -0x3c(%rbp),%rsi
  lea    -0x40(%rbp),%rcx
  lea    -0x44(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <retorna_maior@plt>
  mov    -0x3c(%rbp),%ecx
  mov    -0x40(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0xffffffff,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x44(%rbp)
  subl   $0x1,-0x38(%rbp)
L34:
  cmpl   $0x0,-0x38(%rbp)
  jne    L51
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D24
type_guessed: string

tool: D14: %d

tool: D0: Elem	Linha	Coluna

tool: D24: %d	%d	%d


assistant: ```c
int main() {
  int x, y, A[3][3], maior = 0, linha, coluna;
  for (y = 0; y < 3; y++) {
    for (x = 0; x < 3; x++) {
      scanf("%d", &A[y][x]);
    }
  }
  printf("Elem\tLinha\tColuna\n");
  x = 3 * 3;
  while (x) {
    retorna_maior(A, 3, &maior, &linha, &coluna);
    printf("%d\t%d\t%d\n", maior, linha, coluna);
    A[linha][coluna] = -1;
    maior = 0;
    x--;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x1c(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D0(%rip),%r12
  jmp    L15
L59:
  add    $0x3,%r13
  add    $0xc,%rbp
  cmp    $0x9,%r13
  je     L35
L15:
  lea    -0xc(%rbp),%rbx
L5:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L5
  jmp    L59
L35:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x9,%ebx
  lea    D8(%rip),%rbp
L31:
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%r8
  mov    $0x3,%esi
  call   <retorna_maior@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq 0xc(%rsp),%rdx
  movslq 0x8(%rsp),%rax
  lea    (%rax,%rax,2),%rax
  add    %rdx,%rax
  movl   $0xffffffff,0x10(%rsp,%rax,4)
  movl   $0x0,0x4(%rsp)
  sub    $0x1,%ebx
  jne    L31
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D8
type: string

tool: D0: %d

tool: D4: Elem	Linha	Coluna

tool: D8: %d	%d	%d


assistant: ```c
int main() {
  int x, y, A[3][3], maior = 0, linha, coluna;
  for (y = 0; y < 3; y++) {
    for (x = 0; x < 3; x++) {
      scanf("%d", &A[y][x]);
    }
  }
  printf("Elem\tLinha\tColuna\n");
  x = 3 * 3;
  while (x) {
    retorna_maior(A, 3, &maior, &linha, &coluna);
    printf("%d\t%d\t%d\n", maior, linha, coluna);
    A[linha][coluna] = -1;
    maior = 0;
    x--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x34(%rsp),%r13
  mov    %rbp,%rbx
L15:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x4(%rbx),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x8(%rbx),%rsi
  mov    %r12,%rdi
  add    $0xc,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L15
  mov    $0x9,%ebx
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D20(%rip),%rdi
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  lea    D26(%rip),%r12
  nopl   0x0(%rax)
L7:
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <retorna_maior@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  mov    %r12,%rdi
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  lea    (%rax,%rax,2),%rax
  add    %rdx,%rax
  movl   $0xffffffff,0x10(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L7
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string
name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D26
type: string

tool: D1: %d

tool: D20: Elem	Linha	Coluna

tool: D26: %d	%d	%d


assistant: ```c
int main() {
  int x, y, A[3][3], maior = 0, linha, coluna;
  for (y = 0; y < 3; y++) {
    for (x = 0; x < 3; x++) {
      scanf("%d", &A[y][x]);
    }
  }
  printf("Elem\tLinha\tColuna\n");
  x = 3 * 3;
  while (x) {
    retorna_maior(A, 3, &maior, &linha, &coluna);
    printf("%d\t%d\t%d\n", maior, linha, coluna);
    A[linha][coluna] = -1;
    maior = 0;
    x--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x34(%rsp),%r13
  mov    %rbp,%rbx
L26:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x4(%rbx),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x8(%rbx),%rsi
  mov    %r12,%rdi
  add    $0xc,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L26
  mov    $0x9,%ebx
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%r13
  call   <puts@plt>
  lea    D10(%rip),%r12
  nopl   0x0(%rax)
L10:
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <retorna_maior@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  mov    %r12,%rdi
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  movl   $0x0,0x4(%rsp)
  lea    (%rax,%rax,2),%rax
  add    %rdx,%rax
  movl   $0xffffffff,0x10(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L10
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string

tool: D25: %d

tool: D2: Elem	Linha	Coluna

tool: D10: %d	%d	%d


assistant: ```c
int main() {
  int x, y, A[3][3], maior = 0, linha, coluna;
  for (y = 0; y < 3; y++) {
    for (x = 0; x < 3; x++) {
      scanf("%d", &A[y][x]);
    }
  }
  printf("Elem\tLinha\tColuna\n");
  x = 3 * 3;
  while (x) {
    retorna_maior(A, 3, &maior, &linha, &coluna);
    printf("%d\t%d\t%d\n", maior, linha, coluna);
    A[linha][coluna] = -1;
    maior = 0;
    x--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L32:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L19
  mov    -0x8(%rbp),%eax
  jmp    L3
L19:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L32
  mov    $0xffffffff,%eax
L3:
  leave
  ret
```

assistant: ```c
int find_idx(char *s, char c) {
  int i, len;
  len = str_length(s);
  for (i = 0; i < len; i++) {
    if (s[i] == c) {
      return i;
    }
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_idx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <str_length@plt>
  test   %eax,%eax
  jle    L32
  mov    %eax,%eax
  mov    $0x0,%edx
L22:
  mov    %edx,%ecx
  cmp    %bpl,(%rbx,%rdx,1)
  je     L24
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L22
  mov    $0xffffffff,%ecx
L24:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    $0xffffffff,%ecx
  jmp    L24
```

assistant: ```c
int find_idx(char *s, char c) {
  int i, len;
  len = str_length(s);
  for (i = 0; i < len; i++) {
    if (s[i] == c) {
      return i;
    }
  }
  return (-1);
}
```