ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<print_gcd>:
  endbr64
  mov    %edx,%eax
  mov    %rdi,%r8
  mov    %rsi,%r10
  mov    %edx,%edi
  imul   %ecx,%eax
  test   %eax,%eax
  je     L202
  push   %rbx
  cmp    %ecx,%edi
  je     L164
  nopw   0x0(%rax,%rax,1)
L22:
  jge    L80
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L143
L117:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L143:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  jle    L173
  lea    -0x1(%rdi),%r9d
  xor    %ebx,%ebx
  xor    %r11d,%r11d
  add    $0x2,%r9
  cs nopw 0x0(%rax,%rax,1)
L73:
  test   %edi,%edi
  jle    L41
  movslq %r11d,%rcx
  mov    $0x1,%edx
  add    %r10,%rcx
  jmp    L144
  nopl   0x0(%rax)
L17:
  mov    %edx,%esi
  add    $0x1,%rdx
  cmp    %rdx,%r9
  je     L116
L144:
  movzbl -0x1(%rdx,%rcx,1),%esi
  cmp    %sil,-0x1(%r8,%rdx,1)
  je     L17
  jmp    L117
L41:
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L116:
  cmp    %esi,%edi
  jne    L117
  add    $0x1,%ebx
  add    %edi,%r11d
  cmp    %eax,%ebx
  jne    L73
L173:
  mov    %r8,%rsi
  lea    D7(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    %r10,%rax
  mov    %r8,%r10
  jle    L117
  mov    %edi,%edx
  mov    %ecx,%edi
  mov    %rax,%r8
  mov    %edi,%eax
  mov    %edx,%ecx
  imul   %edx,%eax
  test   %eax,%eax
  je     L117
  cmp    %ecx,%edi
  jne    L22
L164:
  movzbl (%r10),%eax
  cmp    %al,(%r8)
  jne    L141
  test   %edi,%edi
  jle    L141
  mov    $0x1,%eax
  nopl   0x0(%rax)
L190:
  movzbl (%r10,%rax,1),%ebx
  cmp    %bl,(%r8,%rax,1)
  mov    %eax,%esi
  sete   %cl
  cmp    %eax,%edi
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L190
  cmp    %esi,%edi
  jne    L117
L72:
  mov    %r8,%rsi
  lea    D7(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
L141:
  xor    %esi,%esi
  cmp    %esi,%edi
  je     L72
  jmp    L117
L202:
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: %s

assistant: ```c
void print_gcd(char s1[], char s2[], int n1, int n2) {
  if (n1 * n2 == 0) {
    return;
  }
  if (n1 == n2) {
    int j;
    for (j = 0; (s1[j] == s2[j]) && (j < n1); j++) {
      ;
    }
    if (j == n1) {
      printf("%s", s1);
    } else
      return;
  }
  if (n1 < n2) {
    if (n2 % n1 == 0) {
      int i, j;
      for (i = 0; i < n1 / n2; i++) {
        for (j = 0; (j < n1) && (s1[j] == s2[n1 * i + j]); j++) {
          ;
        }
        if (j != n1)
          return;
      }
      printf("%s", s1);
    }
  }
  if (n2 < n1) {
    return print_gcd(s2, s1, n2, n1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L12
  cmpl   $0x1,-0x14(%rbp)
  jne    L30
L12:
  mov    -0x14(%rbp),%eax
  jmp    L32
L30:
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L45:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jg     L45
  mov    -0xc(%rbp),%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0 || n == 1)
    return n;
  int x = 0, y = 1, z = 1;
  while (n > 0) {
    x = y;
    y = z;
    z = x + y;
    n--;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fib>:
  endbr64
  mov    %edi,%edx
  cmp    $0x1,%edi
  jbe    L45
  test   %edi,%edi
  jle    L12
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L11
L27:
  mov    %eax,%edx
  mov    %ecx,%eax
L11:
  lea    (%rdx,%rax,1),%ecx
  sub    $0x1,%edi
  jne    L27
L45:
  mov    %edx,%eax
  ret
L12:
  mov    $0x0,%edx
  jmp    L45
```

assistant: ```c
int fib(int n) {
  if (n == 0 || n == 1)
    return n;
  int x = 0, y = 1, z = 1;
  while (n > 0) {
    x = y;
    y = z;
    z = x + y;
    n--;
  }
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fib>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  cmp    $0x1,%edi
  jbe    L17
  test   %edi,%edi
  jle    L13
  mov    $0x1,%ecx
  mov    $0x1,%eax
  jmp    L11
  nopl   (%rax)
L2:
  mov    %ecx,%eax
  mov    %esi,%ecx
L11:
  lea    (%rax,%rcx,1),%esi
  sub    $0x1,%edx
  jne    L2
  ret
  nopl   (%rax)
L13:
  xor    %eax,%eax
L17:
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0 || n == 1)
    return n;
  int x = 0, y = 1, z = 1;
  while (n > 0) {
    x = y;
    y = z;
    z = x + y;
    n--;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fib>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  cmp    $0x1,%edi
  jbe    L33
  test   %edi,%edi
  jle    L22
  mov    $0x1,%ecx
  mov    $0x1,%eax
  jmp    L1
  nopl   (%rax)
L37:
  mov    %ecx,%eax
  mov    %esi,%ecx
L1:
  lea    (%rax,%rcx,1),%esi
  sub    $0x1,%edx
  jne    L37
  ret
  nopl   (%rax)
L22:
  xor    %eax,%eax
L33:
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 0 || n == 1)
    return n;
  int x = 0, y = 1, z = 1;
  while (n > 0) {
    x = y;
    y = z;
    z = x + y;
    n--;
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x1,-0x18(%rbp)
  jg     L16
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <to_binary@plt>
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <rellena@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_reg(char *reg) {
  int i = strlen(reg);
  char *num = malloc(i);
  int j = 0;
  while (i > 1) {
    num[j] = reg[j + 1];
    i--;
    j++;
  }
  num[j] = '\0';
  i = atoi(num);
  char *resultado = rellena(to_binary(i), 5);
  return resultado;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_reg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x1,%ebp
  jle    L16
  mov    %ebp,%eax
  mov    $0x1,%edx
L17:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,-0x1(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L17
  sub    $0x1,%ebp
L11:
  movslq %ebp,%rbp
  movb   $0x0,(%rdi,%rbp,1)
  call   <atoi@plt>
  mov    %eax,%edi
  call   <to_binary@plt>
  mov    %eax,%edi
  mov    $0x5,%esi
  call   <rellena@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x0,%ebp
  jmp    L11
```

assistant: ```c
char *get_reg(char *reg) {
  int i = strlen(reg);
  char *num = malloc(i);
  int j = 0;
  while (i > 1) {
    num[j] = reg[j + 1];
    i--;
    j++;
  }
  num[j] = '\0';
  i = atoi(num);
  char *resultado = rellena(to_binary(i), 5);
  return resultado;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_reg>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x1,%ebp
  jle    L10
  movslq %ebp,%rax
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,-0x1(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L8
  lea    -0x1(%rbp),%eax
  add    %rdi,%rax
L10:
  movb   $0x0,(%rax)
  call   <atoi@plt>
  mov    %eax,%edi
  call   <to_binary@plt>
  add    $0x8,%rsp
  mov    $0x5,%esi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    10b0 <rellena@plt>
```

assistant: ```c
char *get_reg(char *reg) {
  int i = strlen(reg);
  char *num = malloc(i);
  int j = 0;
  while (i > 1) {
    num[j] = reg[j + 1];
    i--;
    j++;
  }
  num[j] = '\0';
  i = atoi(num);
  char *resultado = rellena(to_binary(i), 5);
  return resultado;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_reg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x1,%ebx
  jle    L155
  lea    0x2(%rbp),%rcx
  mov    %rdi,%rdx
  lea    -0x2(%rbx),%eax
  mov    %ebx,%esi
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L128
  cmp    $0x6,%eax
  jbe    L128
  lea    -0x1(%rbx),%ecx
  cmp    $0xe,%eax
  jbe    L18
  mov    %ecx,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
L58:
  movdqu 0x1(%rbp,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L58
  mov    %ecx,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  sub    %edx,%ebx
  cmp    %edx,%ecx
  je     L53
  mov    %esi,%r8d
  sub    %edx,%r8d
  lea    -0x1(%r8),%ecx
  sub    $0x2,%r8d
  cmp    $0x6,%r8d
  jbe    L40
L113:
  mov    0x1(%rbp,%rdx,1),%r8
  mov    %r8,(%rdi,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  sub    %edx,%ebx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L53
L40:
  cltq
  movzbl 0x1(%rbp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  cmp    $0x2,%ebx
  je     L53
  movzbl 0x2(%rbp,%rax,1),%edx
  mov    %dl,0x1(%rdi,%rax,1)
  cmp    $0x3,%ebx
  je     L53
  movzbl 0x3(%rbp,%rax,1),%edx
  mov    %dl,0x2(%rdi,%rax,1)
  cmp    $0x4,%ebx
  je     L53
  movzbl 0x4(%rbp,%rax,1),%edx
  mov    %dl,0x3(%rdi,%rax,1)
  cmp    $0x5,%ebx
  je     L53
  movzbl 0x5(%rbp,%rax,1),%edx
  mov    %dl,0x4(%rdi,%rax,1)
  cmp    $0x6,%ebx
  je     L53
  movzbl 0x6(%rbp,%rax,1),%edx
  mov    %dl,0x5(%rdi,%rax,1)
  cmp    $0x7,%ebx
  je     L53
  movzbl 0x7(%rbp,%rax,1),%edx
  mov    %dl,0x6(%rdi,%rax,1)
L53:
  lea    -0x1(%rsi),%eax
  add    %rdi,%rax
L155:
  movb   $0x0,(%rax)
  call   <atoi@plt>
  mov    %eax,%edi
  call   <to_binary@plt>
  add    $0x8,%rsp
  mov    $0x5,%esi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    10b0 <rellena@plt>
  nopl   0x0(%rax,%rax,1)
L128:
  mov    $0x1,%eax
  nopl   (%rax)
L57:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,-0x1(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L57
  jmp    L53
L18:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L113
```

assistant: ```c
char *get_reg(char *reg) {
  int i = strlen(reg);
  char *num = malloc(i);
  int j = 0;
  while (i > 1) {
    num[j] = reg[j + 1];
    i--;
    j++;
  }
  num[j] = '\0';
  i = atoi(num);
  char *resultado = rellena(to_binary(i), 5);
  return resultado;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L25
L33:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L21
  movl   $0x0,-0x14(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L25
L21:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L2
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L25
L2:
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L25:
  cmpl   $0x0,-0x14(%rbp)
  jne    L33
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D69
type: string
name: disassemble_data
arguments: label: D56
type: string
name: disassemble_data
arguments: label: D39
type: string
name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D68
type: string
name: disassemble_data
arguments: label: D16
type: f64
name: disassemble_data
arguments: label: D49
type: string

tool: D69: Raten Sie eine Zahl zwischen 0 und 99

tool: D56: %i

tool: D39: Gefunden :-) 

tool: D17: zu klein

tool: D68: zu gross

tool: D16: 1

tool: D49: Der Kehrwert der Zahl ist %f


assistant: ```c
int main() {
  srand(time(0));
  int zufall = rand() % 100;
  int raten = 1;
  printf("Raten Sie eine Zahl zwischen 0 und 99\n");
  while (raten) {
    int R;
    scanf("%i", &R);
    if (R == zufall) {
      raten = 0;
      printf("Gefunden :-) \n");
    } else {
      if (R < zufall)
        printf("zu klein\n");
      else
        printf("zu gross\n");
    }
  }
  float kehrwert = 1.0 / zufall;
  printf("Der Kehrwert der Zahl ist %f\n", kehrwert);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  cltd
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  lea    D65(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%r12
  lea    D44(%rip),%rbp
  lea    D42(%rip),%r14
  lea    D25(%rip),%r13
  jmp    L5
L1:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  D12(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    %r14,%rdi
  call   <puts@plt>
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  je     L1
  jge    L3
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L5
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D65
type_guessed: string
name: disassemble_data
arguments: tag: D44
type_guessed: string
name: disassemble_data
arguments: tag: D42
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string
name: disassemble_data
arguments: tag: D31
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: f64
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D65: Raten Sie eine Zahl zwischen 0 und 99

tool: D44: %i

tool: D42: zu gross

tool: D25: zu klein

tool: D31: Gefunden :-) 

tool: D12: 1

tool: D19: Der Kehrwert der Zahl ist %f


assistant: ```c
int main() {
  srand(time(0));
  int zufall = rand() % 100;
  int raten = 1;
  printf("Raten Sie eine Zahl zwischen 0 und 99\n");
  while (raten) {
    int R;
    scanf("%i", &R);
    if (R == zufall) {
      raten = 0;
      printf("Gefunden :-) \n");
    } else {
      if (R < zufall)
        printf("zu klein\n");
      else
        printf("zu gross\n");
    }
  }
  float kehrwert = 1.0 / zufall;
  printf("Der Kehrwert der Zahl ist %f\n", kehrwert);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D40(%rip),%r14
  push   %r13
  lea    D48(%rip),%r13
  push   %r12
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D39(%rip),%rdi
  movslq %eax,%rbx
  cltd
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  je     L17
  jge    L4
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L8
  nopl   (%rax)
L4:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L17:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movsd  D13(%rip),%xmm0
  cvtsi2sd %ebx,%xmm1
  lea    D11(%rip),%rdi
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
type: string
name: unpack_data
arguments: data_label: D48
type: string
name: unpack_data
arguments: data_label: D45
type: string
name: unpack_data
arguments: data_label: D39
type: string
name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D13
type: f64
name: unpack_data
arguments: data_label: D11
type: string

tool: D40: zu gross

tool: D48: zu klein

tool: D45: %i

tool: D39: Raten Sie eine Zahl zwischen 0 und 99

tool: D1: Gefunden :-) 

tool: D13: 1

tool: D11: Der Kehrwert der Zahl ist %f


assistant: ```c
int main() {
  srand(time(0));
  int zufall = rand() % 100;
  int raten = 1;
  printf("Raten Sie eine Zahl zwischen 0 und 99\n");
  while (raten) {
    int R;
    scanf("%i", &R);
    if (R == zufall) {
      raten = 0;
      printf("Gefunden :-) \n");
    } else {
      if (R < zufall)
        printf("zu klein\n");
      else
        printf("zu gross\n");
    }
  }
  float kehrwert = 1.0 / zufall;
  printf("Der Kehrwert der Zahl ist %f\n", kehrwert);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D68(%rip),%r14
  push   %r13
  lea    D49(%rip),%r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D51(%rip),%rdi
  movslq %eax,%rbx
  cltd
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  je     L19
  jge    L45
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L38
  nopl   (%rax)
L45:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L19:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  movsd  D67(%rip),%xmm0
  cvtsi2sd %ebx,%xmm1
  lea    D53(%rip),%rdi
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D68
data_type: string
name: disassemble_data
arguments: data_label: D49
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string
name: disassemble_data
arguments: data_label: D51
data_type: string
name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D67
data_type: f64
name: disassemble_data
arguments: data_label: D53
data_type: string

tool: D68: zu gross

tool: D49: zu klein

tool: D11: %i

tool: D51: Raten Sie eine Zahl zwischen 0 und 99

tool: D19: Gefunden :-) 

tool: D67: 1

tool: D53: Der Kehrwert der Zahl ist %f


assistant: ```c
int main() {
  srand(time(0));
  int zufall = rand() % 100;
  int raten = 1;
  printf("Raten Sie eine Zahl zwischen 0 und 99\n");
  while (raten) {
    int R;
    scanf("%i", &R);
    if (R == zufall) {
      raten = 0;
      printf("Gefunden :-) \n");
    } else {
      if (R < zufall)
        printf("zu klein\n");
      else
        printf("zu gross\n");
    }
  }
  float kehrwert = 1.0 / zufall;
  printf("Der Kehrwert der Zahl ist %f\n", kehrwert);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  va_list arg;
  va_start(arg, format);
  int ret = vfprintf(stdout, format, arg);
  va_end(arg);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  va_list arg;
  va_start(arg, format);
  int ret = vfprintf(stdout, format, arg);
  va_end(arg);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *restrict format, ...) {
  va_list arg;
  va_start(arg, format);
  int ret = vfprintf(stdout, format, arg);
  va_end(arg);
  return ret;
}
```