ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<exposed_dragons>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xc,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0xc(%rsp),%rdi
  mov    $0xc,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%ebx
  jmp    L51
L40:
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L36
L51:
  mov    %ebx,%edi
  call   <lastcard@plt>
  lea    -0x1b(%rax),%edx
  cmp    $0xb,%edx
  ja     L40
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    $0x7,%ebx
  jle    L40
  movl   $0x1,0xc(%rsp,%rax,4)
  jmp    L40
L36:
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    %rsp,%r13
  jmp    L84
L18:
  cmpl   $0x0,0xc(%rsp,%rbx,4)
  jne    L112
L107:
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  je     L14
L84:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <find_freecell@plt>
  cmp    $0xffffffff,%eax
  je     L18
L112:
  cmpl   $0x4,0x0(%r13,%rbx,4)
  jne    L107
  mov    $0x1,%eax
  mov    %ebp,%ecx
  shl    %cl,%eax
  or     %eax,%r12d
  jmp    L107
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    %r12d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exposed_dragons() {
  int dragoncount[3];
  bool dragoncell[3];
  memset(dragoncount, 0, sizeof(int) * 3);
  memset(dragoncell, 0, sizeof(bool) * 3);
  for (int i = 0; i < 11; i++) {
    int lc = lastcard(i);
    if ((lc >= 27) && (lc < 39)) {
      dragoncount[lc % 3]++;
      if (i >= 8)
        dragoncell[lc % 3] = true;
    }
  }
  int result = 0;
  for (int i = 0; i < 3; i++)
    if (((find_freecell() != -1) || dragoncell[i]) && (dragoncount[i] == 4))
      result |= (1 << i);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<exposed_dragons>:
  endbr64
  push   %r15
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xc(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%edi
  call   <lastcard@plt>
  lea    -0x1b(%rax),%edx
  cmp    $0xb,%edx
  ja     L0
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  cmp    $0x7,%r12d
  jle    L0
  movl   $0x1,0xc(%rsp,%rdx,4)
  nop
L0:
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  jne    L19
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  mov    $0x1,%r15d
L33:
  xor    %eax,%eax
  mov    %r12d,%r13d
  call   <find_freecell@plt>
  cmp    $0xffffffff,%eax
  je     L76
L66:
  cmpl   $0x4,(%rbx,%r12,4)
  jne    L78
  mov    %r15d,%eax
  mov    %r13d,%ecx
  shl    %cl,%eax
  or     %eax,%r14d
L78:
  add    $0x1,%r12
  cmp    $0x3,%r12
  jne    L33
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  mov    0x0(%rbp,%r12,4),%eax
  test   %eax,%eax
  je     L78
  jmp    L66
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exposed_dragons() {
  int dragoncount[3];
  bool dragoncell[3];
  memset(dragoncount, 0, sizeof(int) * 3);
  memset(dragoncell, 0, sizeof(bool) * 3);
  for (int i = 0; i < 11; i++) {
    int lc = lastcard(i);
    if ((lc >= 27) && (lc < 39)) {
      dragoncount[lc % 3]++;
      if (i >= 8)
        dragoncell[lc % 3] = true;
    }
  }
  int result = 0;
  for (int i = 0; i < 3; i++)
    if (((find_freecell() != -1) || dragoncell[i]) && (dragoncount[i] == 4))
      result |= (1 << i);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exposed_dragons>:
  endbr64
  push   %r15
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0xc(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0xc,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r12d,%edi
  call   <lastcard@plt>
  lea    -0x1b(%rax),%edx
  cmp    $0xb,%edx
  ja     L50
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  addl   $0x1,(%rsp,%rdx,4)
  cmp    $0x7,%r12d
  jle    L50
  movl   $0x1,0xc(%rsp,%rdx,4)
  nop
L50:
  add    $0x1,%r12d
  cmp    $0xb,%r12d
  jne    L33
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  mov    $0x1,%r15d
L11:
  xor    %eax,%eax
  mov    %r12d,%r13d
  call   <find_freecell@plt>
  cmp    $0xffffffff,%eax
  je     L80
L4:
  cmpl   $0x4,(%rbx,%r12,4)
  jne    L31
  mov    %r15d,%eax
  mov    %r13d,%ecx
  shl    %cl,%eax
  or     %eax,%r14d
L31:
  add    $0x1,%r12
  cmp    $0x3,%r12
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x28,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  mov    0x0(%rbp,%r12,4),%eax
  test   %eax,%eax
  je     L31
  jmp    L4
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exposed_dragons() {
  int dragoncount[3];
  bool dragoncell[3];
  memset(dragoncount, 0, sizeof(int) * 3);
  memset(dragoncell, 0, sizeof(bool) * 3);
  for (int i = 0; i < 11; i++) {
    int lc = lastcard(i);
    if ((lc >= 27) && (lc < 39)) {
      dragoncount[lc % 3]++;
      if (i >= 8)
        dragoncell[lc % 3] = true;
    }
  }
  int result = 0;
  for (int i = 0; i < 3; i++)
    if (((find_freecell() != -1) || dragoncell[i]) && (dragoncount[i] == 4))
      result |= (1 << i);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L7:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
time_t time(time_t *foo) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  if (foo)
    *foo = tv.tv_sec;
  return tv.tv_sec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %rbx,%rbx
  je     L13
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
L13:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t time(time_t *foo) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  if (foo)
    *foo = tv.tv_sec;
  return tv.tv_sec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%eax
  test   %rbx,%rbx
  je     L1
  mov    %eax,(%rbx)
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t time(time_t *foo) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  if (foo)
    *foo = tv.tv_sec;
  return tv.tv_sec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<time>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%eax
  test   %rbx,%rbx
  je     L13
  mov    %eax,(%rbx)
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t time(time_t *foo) {
  struct timeval tv;
  gettimeofday(&tv, 0);
  if (foo)
    *foo = tv.tv_sec;
  return tv.tv_sec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transpose_matrix08>:
  endbr64
  test   %rsi,%rsi
  jle    L6
  push   %rbx
  mov    %rdi,%r9
  mov    %rdx,%r11
  mov    %rcx,%rbx
  lea    0x0(,%rsi,4),%r8
  lea    -0x1(%rdx),%r10
  shr    $0x3,%r10
  add    $0x1,%r10
  shl    $0x5,%r10
  mov    $0x0,%ecx
L14:
  mov    (%r9,%rcx,2),%rax
  test   %r11,%r11
  jle    L24
  mov    %rbx,%rdx
  lea    (%rax,%r10,1),%rdi
L32:
  movss  (%rax),%xmm7
  movss  0x4(%rax),%xmm6
  movss  0x8(%rax),%xmm5
  movss  0xc(%rax),%xmm4
  movss  0x10(%rax),%xmm3
  movss  0x14(%rax),%xmm2
  movss  0x18(%rax),%xmm1
  add    $0x20,%rax
  movss  -0x4(%rax),%xmm0
  mov    (%rdx),%rsi
  movss  %xmm7,(%rsi,%rcx,1)
  mov    0x8(%rdx),%rsi
  movss  %xmm6,(%rsi,%rcx,1)
  mov    0x10(%rdx),%rsi
  movss  %xmm5,(%rsi,%rcx,1)
  mov    0x18(%rdx),%rsi
  movss  %xmm4,(%rsi,%rcx,1)
  mov    0x20(%rdx),%rsi
  movss  %xmm3,(%rsi,%rcx,1)
  mov    0x28(%rdx),%rsi
  movss  %xmm2,(%rsi,%rcx,1)
  mov    0x30(%rdx),%rsi
  movss  %xmm1,(%rsi,%rcx,1)
  mov    0x38(%rdx),%rsi
  movss  %xmm0,(%rsi,%rcx,1)
  add    $0x40,%rdx
  cmp    %rax,%rdi
  jne    L32
L24:
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L14
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
void transpose_matrix08(float **m, long nrow, long ncol, float **transposed) {
  long i, j;
  float m0, m1, m2, m3, m4, m5, m6, m7;
  float *pm;
  for (i = 0; i < nrow; i++) {
    pm = m[i];
    for (j = 0; j < ncol; j++) {
      m0 = *pm++;
      m1 = *pm++;
      m2 = *pm++;
      m3 = *pm++;
      m4 = *pm++;
      m5 = *pm++;
      m6 = *pm++;
      m7 = *pm++;
      transposed[j++][i] = m0;
      transposed[j++][i] = m1;
      transposed[j++][i] = m2;
      transposed[j++][i] = m3;
      transposed[j++][i] = m4;
      transposed[j++][i] = m5;
      transposed[j++][i] = m6;
      transposed[j][i] = m7;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transpose_matrix08>:
  endbr64
  test   %rsi,%rsi
  jle    L31
  lea    -0x1(%rdx),%r10
  push   %rbx
  mov    %rdi,%r9
  mov    %rcx,%rbx
  shr    $0x3,%r10
  mov    %rdx,%r11
  lea    0x0(,%rsi,4),%r8
  xor    %ecx,%ecx
  add    $0x1,%r10
  shl    $0x5,%r10
  nopl   0x0(%rax)
L19:
  mov    (%r9,%rcx,2),%rax
  test   %r11,%r11
  jle    L8
  mov    %rbx,%rdx
  lea    (%rax,%r10,1),%rdi
  nopl   0x0(%rax)
L4:
  movss  (%rax),%xmm7
  mov    (%rdx),%rsi
  add    $0x20,%rax
  add    $0x40,%rdx
  movss  -0x1c(%rax),%xmm6
  movss  -0x18(%rax),%xmm5
  movss  -0x14(%rax),%xmm4
  movss  -0x10(%rax),%xmm3
  movss  -0xc(%rax),%xmm2
  movss  -0x8(%rax),%xmm1
  movss  -0x4(%rax),%xmm0
  movss  %xmm7,(%rsi,%rcx,1)
  mov    -0x38(%rdx),%rsi
  movss  %xmm6,(%rsi,%rcx,1)
  mov    -0x30(%rdx),%rsi
  movss  %xmm5,(%rsi,%rcx,1)
  mov    -0x28(%rdx),%rsi
  movss  %xmm4,(%rsi,%rcx,1)
  mov    -0x20(%rdx),%rsi
  movss  %xmm3,(%rsi,%rcx,1)
  mov    -0x18(%rdx),%rsi
  movss  %xmm2,(%rsi,%rcx,1)
  mov    -0x10(%rdx),%rsi
  movss  %xmm1,(%rsi,%rcx,1)
  mov    -0x8(%rdx),%rsi
  movss  %xmm0,(%rsi,%rcx,1)
  cmp    %rdi,%rax
  jne    L4
L8:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L19
  pop    %rbx
  ret
L31:
  ret
```

assistant: ```c
void transpose_matrix08(float **m, long nrow, long ncol, float **transposed) {
  long i, j;
  float m0, m1, m2, m3, m4, m5, m6, m7;
  float *pm;
  for (i = 0; i < nrow; i++) {
    pm = m[i];
    for (j = 0; j < ncol; j++) {
      m0 = *pm++;
      m1 = *pm++;
      m2 = *pm++;
      m3 = *pm++;
      m4 = *pm++;
      m5 = *pm++;
      m6 = *pm++;
      m7 = *pm++;
      transposed[j++][i] = m0;
      transposed[j++][i] = m1;
      transposed[j++][i] = m2;
      transposed[j++][i] = m3;
      transposed[j++][i] = m4;
      transposed[j++][i] = m5;
      transposed[j++][i] = m6;
      transposed[j][i] = m7;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<transpose_matrix08>:
  endbr64
  mov    %rdi,%r8
  mov    %rcx,%r11
  test   %rsi,%rsi
  jle    L21
  test   %rdx,%rdx
  jle    L21
  lea    -0x1(%rdx),%r9
  lea    0x0(,%rsi,4),%r10
  xor    %ecx,%ecx
  mov    %r9,%rdx
  shr    $0x3,%rdx
  lea    0x1(%rdx),%r9
  shl    $0x5,%r9
  nopl   0x0(%rax)
L24:
  mov    (%r8,%rcx,2),%rax
  mov    %r11,%rdx
  lea    (%rax,%r9,1),%rdi
  nopl   0x0(%rax,%rax,1)
L31:
  movss  (%rax),%xmm7
  mov    (%rdx),%rsi
  add    $0x20,%rax
  add    $0x40,%rdx
  movss  -0x1c(%rax),%xmm6
  movss  -0x18(%rax),%xmm5
  movss  -0x14(%rax),%xmm4
  movss  -0x10(%rax),%xmm3
  movss  -0xc(%rax),%xmm2
  movss  -0x8(%rax),%xmm1
  movss  -0x4(%rax),%xmm0
  movss  %xmm7,(%rsi,%rcx,1)
  mov    -0x38(%rdx),%rsi
  movss  %xmm6,(%rsi,%rcx,1)
  mov    -0x30(%rdx),%rsi
  movss  %xmm5,(%rsi,%rcx,1)
  mov    -0x28(%rdx),%rsi
  movss  %xmm4,(%rsi,%rcx,1)
  mov    -0x20(%rdx),%rsi
  movss  %xmm3,(%rsi,%rcx,1)
  mov    -0x18(%rdx),%rsi
  movss  %xmm2,(%rsi,%rcx,1)
  mov    -0x10(%rdx),%rsi
  movss  %xmm1,(%rsi,%rcx,1)
  mov    -0x8(%rdx),%rsi
  movss  %xmm0,(%rsi,%rcx,1)
  cmp    %rdi,%rax
  jne    L31
  add    $0x4,%rcx
  cmp    %rcx,%r10
  jne    L24
L21:
  ret
```

assistant: ```c
void transpose_matrix08(float **m, long nrow, long ncol, float **transposed) {
  long i, j;
  float m0, m1, m2, m3, m4, m5, m6, m7;
  float *pm;
  for (i = 0; i < nrow; i++) {
    pm = m[i];
    for (j = 0; j < ncol; j++) {
      m0 = *pm++;
      m1 = *pm++;
      m2 = *pm++;
      m3 = *pm++;
      m4 = *pm++;
      m5 = *pm++;
      m6 = *pm++;
      m7 = *pm++;
      transposed[j++][i] = m0;
      transposed[j++][i] = m1;
      transposed[j++][i] = m2;
      transposed[j++][i] = m3;
      transposed[j++][i] = m4;
      transposed[j++][i] = m5;
      transposed[j++][i] = m6;
      transposed[j][i] = m7;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L3:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L9:
  cmpl   $0x63,-0x4(%rbp)
  jle    L3
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0, s = 0;
  while (s < 100) {
    s += ++i;
  };
  printf("%d\n", i);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  mov    $0x0,%esi
L7:
  add    $0x1,%esi
  add    %esi,%eax
  cmp    $0x63,%eax
  jle    L7
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0, s = 0;
  while (s < 100) {
    s += ++i;
  };
  printf("%d\n", i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L3:
  add    $0x1,%esi
  add    %esi,%eax
  cmp    $0x63,%eax
  jle    L3
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0, s = 0;
  while (s < 100) {
    s += ++i;
  };
  printf("%d\n", i);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L5:
  add    $0x1,%esi
  add    %esi,%eax
  cmp    $0x63,%eax
  jle    L5
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0, s = 0;
  while (s < 100) {
    s += ++i;
  };
  printf("%d\n", i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <main_best_match@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int istat = main_best_match(argc, argv);
  return istat;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <main_best_match@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int istat = main_best_match(argc, argv);
  return istat;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  jmp    1050 <main_best_match@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int istat = main_best_match(argc, argv);
  return istat;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  jmp    1050 <main_best_match@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int istat = main_best_match(argc, argv);
  return istat;
}
```
user: What is the c source code of the assembly code below:

```asm
<encode_thumb_cc_jump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0xfff80000,-0x14(%rbp)
  jl     L0
  cmpl   $0x7ffff,-0x14(%rbp)
  jg     L0
  mov    -0x14(%rbp),%eax
  and    $0x80000,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x20000,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x40000,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x1a,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x5,%eax
  and    $0x3f0000,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0xd,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0xb,%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  and    $0x7ff,%eax
  or     %edx,%eax
  jmp    L26
L0:
  mov    $0xffffffff,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int encode_thumb_cc_jump(int v) {
  int s, j1, j2;
  if (v >= (int)-0x80000 && v <= 0x7ffff) {
    s = !!(v & 0x80000);
    j1 = !!(v & 0x20000);
    j2 = !!(v & 0x40000);
    return ((s << 26) | ((v & 0x1f800) << 5) | (j1 << 13) | (j2 << 11) | (v & 0x7ff));
  }
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode_thumb_cc_jump>:
  endbr64
  lea    0x80000(%rdi),%eax
  cmp    $0xfffff,%eax
  ja     L2
  mov    %edi,%eax
  shl    $0x5,%eax
  and    $0x3f0000,%eax
  mov    %edi,%edx
  and    $0x7ff,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shl    $0x7,%edx
  and    $0x4000000,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x4,%edx
  and    $0x2000,%edx
  or     %edx,%eax
  shr    $0x7,%edi
  and    $0x800,%edi
  or     %edi,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int encode_thumb_cc_jump(int v) {
  int s, j1, j2;
  if (v >= (int)-0x80000 && v <= 0x7ffff) {
    s = !!(v & 0x80000);
    j1 = !!(v & 0x20000);
    j2 = !!(v & 0x40000);
    return ((s << 26) | ((v & 0x1f800) << 5) | (j1 << 13) | (j2 << 11) | (v & 0x7ff));
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<encode_thumb_cc_jump>:
  endbr64
  lea    0x80000(%rdi),%eax
  cmp    $0xfffff,%eax
  ja     L2
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x5,%eax
  and    $0x7ff,%edx
  and    $0x3f0000,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shl    $0x7,%edx
  and    $0x4000000,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x7,%edi
  shr    $0x4,%edx
  and    $0x800,%edi
  and    $0x2000,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int encode_thumb_cc_jump(int v) {
  int s, j1, j2;
  if (v >= (int)-0x80000 && v <= 0x7ffff) {
    s = !!(v & 0x80000);
    j1 = !!(v & 0x20000);
    j2 = !!(v & 0x40000);
    return ((s << 26) | ((v & 0x1f800) << 5) | (j1 << 13) | (j2 << 11) | (v & 0x7ff));
  }
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode_thumb_cc_jump>:
  endbr64
  lea    0x80000(%rdi),%eax
  cmp    $0xfffff,%eax
  ja     L3
  mov    %edi,%eax
  mov    %edi,%edx
  shl    $0x5,%eax
  and    $0x7ff,%edx
  and    $0x3f0000,%eax
  or     %edx,%eax
  mov    %edi,%edx
  shl    $0x7,%edx
  and    $0x4000000,%edx
  or     %edx,%eax
  mov    %edi,%edx
  shr    $0x7,%edi
  shr    $0x4,%edx
  and    $0x800,%edi
  and    $0x2000,%edx
  or     %edx,%eax
  or     %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int encode_thumb_cc_jump(int v) {
  int s, j1, j2;
  if (v >= (int)-0x80000 && v <= 0x7ffff) {
    s = !!(v & 0x80000);
    j1 = !!(v & 0x20000);
    j2 = !!(v & 0x40000);
    return ((s << 26) | ((v & 0x1f800) << 5) | (j1 << 13) | (j2 << 11) | (v & 0x7ff));
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x384,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  int a = 900;
  int b = 3;
  int c;
  c = a / b;
  printf("%d", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12c,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int a = 900;
  int b = 3;
  int c;
  c = a / b;
  printf("%d", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12c,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: %d

assistant: ```c
int main() {
  int a = 900;
  int b = 3;
  int c;
  c = a / b;
  printf("%d", c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12c,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main() {
  int a = 900;
  int b = 3;
  int c;
  c = a / b;
  printf("%d", c);
  return 0;
}
```