ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_add>:
  endbr64
  mov    %rdx,%r11
  push   %rbx
  mov    %rcx,%rdx
  cmp    %r8,%rcx
  jae    L32
  mov    %rsi,%rax
  mov    %r8,%rdx
  mov    %r11,%rsi
  mov    %rcx,%r8
  mov    %rax,%r11
L32:
  movzwl (%rsi),%ecx
  movzwl (%r11),%eax
  lea    (%rcx,%rax,1),%r9d
  add    %rcx,%rax
  mov    %r9w,(%rdi)
  shr    $0x10,%rax
  cmp    $0x1,%r8
  jbe    L94
  mov    %r8,%r9
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L87:
  movzwl (%rsi,%rcx,2),%r10d
  movzwl (%r11,%rcx,2),%ebx
  movzwl %ax,%eax
  add    %rbx,%r10
  add    %r10,%rax
  mov    %ax,(%rdi,%rcx,2)
  add    $0x1,%rcx
  shr    $0x10,%rax
  cmp    %r8,%rcx
  jne    L87
L39:
  cmp    %rdi,%rsi
  je     L38
  cmp    %r8,%rdx
  jbe    L61
  xchg   %ax,%ax
L57:
  movzwl (%rsi,%r8,2),%ecx
  add    $0x1,%r9
  lea    (%rcx,%rax,1),%r10d
  movzwl %ax,%eax
  add    %rcx,%rax
  mov    %r10w,(%rdi,%r8,2)
  mov    %r9,%r8
  shr    $0x10,%rax
  cmp    %r9,%rdx
  ja     L57
L61:
  test   %ax,%ax
  je     L30
  mov    $0x1,%eax
  mov    %ax,(%rdi,%r9,2)
  add    $0x1,%r9
L30:
  mov    %r9,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L38:
  cmp    %r8,%rdx
  jbe    L119
  test   $0x1,%al
  je     L119
  nopl   0x0(%rax)
L124:
  movzwl (%rsi,%r8,2),%eax
  add    $0x1,%r9
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  mov    %cx,(%rdi,%r8,2)
  shr    $0x10,%rax
  mov    %r9,%r8
  cmp    %r9,%rdx
  jbe    L119
  test   %rax,%rax
  jne    L124
L119:
  mov    %rdx,%r9
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L94:
  mov    $0x1,%r8d
  mov    $0x1,%r9d
  jmp    L39
```

assistant: ```c
long mp_add(unsigned short *rop, unsigned short *op1, unsigned short *op2, unsigned long len1, unsigned long len2) {
  unsigned long value;
  unsigned short carry;
  long size;
  if (len1 < len2) {
    unsigned short *top = op1;
    unsigned long tlen = len1;
    op1 = op2;
    len1 = len2;
    op2 = top;
    len2 = tlen;
  };
  value = (unsigned long)op1[0] + op2[0];
  rop[0] = value;
  carry = value >> 16;
  for (size = 1; size < len2; size++) {
    value = (unsigned long)op1[size] + op2[size] + carry;
    rop[size] = value;
    carry = value >> 16;
  }
  if (rop != op1) {
    for (; size < len1; size++) {
      value = (unsigned long)op1[size] + carry;
      rop[size] = value;
      carry = value >> 16;
    }
  } else {
    for (; carry && size < len1; size++) {
      value = (unsigned long)op1[size] + carry;
      rop[size] = value;
      carry = value >> 16;
    }
    size = len1;
  }
  if (carry)
    rop[size++] = carry;
  return (size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mp_add>:
  endbr64
  push   %rbx
  mov    %rdx,%r9
  mov    %rcx,%r10
  cmp    %r8,%rcx
  jae    L34
  mov    %rsi,%rax
  mov    %r8,%r10
  mov    %rdx,%rsi
  mov    %rcx,%r8
  mov    %rax,%r9
L34:
  movzwl (%rsi),%edx
  movzwl (%r9),%eax
  lea    (%rdx,%rax,1),%ecx
  add    %rdx,%rax
  mov    %cx,(%rdi)
  shr    $0x10,%rax
  cmp    $0x1,%r8
  jbe    L114
  mov    %r8,%r11
  mov    $0x1,%ecx
  nopl   (%rax)
L62:
  movzwl (%rsi,%rcx,2),%edx
  movzwl (%r9,%rcx,2),%ebx
  movzwl %ax,%eax
  add    %rbx,%rdx
  add    %rdx,%rax
  mov    %ax,(%rdi,%rcx,2)
  add    $0x1,%rcx
  shr    $0x10,%rax
  cmp    %r8,%rcx
  jne    L62
L45:
  cmp    %rdi,%rsi
  je     L122
  cmp    %r8,%r10
  jbe    L55
  mov    %r11,%r9
  nopl   0x0(%rax)
L8:
  movzwl (%rsi,%r8,2),%edx
  add    $0x1,%r9
  lea    (%rdx,%rax,1),%ecx
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %cx,(%rdi,%r8,2)
  mov    %r9,%r8
  shr    $0x10,%rax
  cmp    %r9,%r10
  ja     L8
  lea    -0x1(%r10),%rdx
  xor    %ecx,%ecx
  sub    %r11,%rdx
  add    $0x1,%r11
  cmp    %r11,%r10
  cmovb  %rcx,%rdx
  lea    (%rdx,%r11,1),%r10
L100:
  test   %ax,%ax
  je     L44
  mov    $0x1,%eax
  add    $0x1,%r9
  mov    %ax,(%rdi,%r10,2)
L44:
  mov    %r9,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L122:
  cmp    %r8,%r10
  jbe    L63
  test   $0x1,%al
  je     L63
  nopl   0x0(%rax)
L10:
  movzwl (%rsi,%r8,2),%eax
  add    $0x1,%r11
  lea    0x1(%rax),%edx
  add    $0x1,%rax
  mov    %dx,(%rdi,%r8,2)
  shr    $0x10,%rax
  mov    %r11,%r8
  cmp    %r11,%r10
  jbe    L63
  test   %rax,%rax
  jne    L10
L63:
  mov    %r10,%r9
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L114:
  mov    $0x1,%r8d
  mov    $0x1,%r11d
  jmp    L45
L55:
  mov    %r8,%r10
  mov    %r11,%r9
  jmp    L100
```

assistant: ```c
long mp_add(unsigned short *rop, unsigned short *op1, unsigned short *op2, unsigned long len1, unsigned long len2) {
  unsigned long value;
  unsigned short carry;
  long size;
  if (len1 < len2) {
    unsigned short *top = op1;
    unsigned long tlen = len1;
    op1 = op2;
    len1 = len2;
    op2 = top;
    len2 = tlen;
  };
  value = (unsigned long)op1[0] + op2[0];
  rop[0] = value;
  carry = value >> 16;
  for (size = 1; size < len2; size++) {
    value = (unsigned long)op1[size] + op2[size] + carry;
    rop[size] = value;
    carry = value >> 16;
  }
  if (rop != op1) {
    for (; size < len1; size++) {
      value = (unsigned long)op1[size] + carry;
      rop[size] = value;
      carry = value >> 16;
    }
  } else {
    for (; carry && size < len1; size++) {
      value = (unsigned long)op1[size] + carry;
      rop[size] = value;
      carry = value >> 16;
    }
    size = len1;
  }
  if (carry)
    rop[size++] = carry;
  return (size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<crStrjoin3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <crStrlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <crStrlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <crStrlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <crAlloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crMemcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <crMemcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <crMemcpy@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *crStrjoin3(const char *str1, const char *str2, const char *str3) {
  const int len1 = crStrlen(str1), len2 = crStrlen(str2), len3 = crStrlen(str3);
  char *s = crAlloc(len1 + len2 + len3 + 1);
  if (s) {
    crMemcpy(s, str1, len1);
    crMemcpy(s + len1, str2, len2);
    crMemcpy(s + len1 + len2, str3, len3);
    s[len1 + len2 + len3] = '\0';
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crStrjoin3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%rbp
  call   <crStrlen@plt>
  mov    %eax,%r12d
  mov    %r14,%rdi
  call   <crStrlen@plt>
  mov    %eax,%ebx
  mov    %rbp,0x8(%rsp)
  mov    %rbp,%rdi
  call   <crStrlen@plt>
  lea    (%r12,%rbx,1),%r13d
  mov    %eax,0x4(%rsp)
  add    %eax,%r13d
  lea    0x1(%r13),%edi
  call   <crAlloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <crMemcpy@plt>
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,1),%rdi
  mov    %ebx,%edx
  mov    %r14,%rsi
  call   <crMemcpy@plt>
  movslq %ebx,%rdi
  add    %r12,%rdi
  add    %rbp,%rdi
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%rsi
  call   <crMemcpy@plt>
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
L1:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crStrjoin3(const char *str1, const char *str2, const char *str3) {
  const int len1 = crStrlen(str1), len2 = crStrlen(str2), len3 = crStrlen(str3);
  char *s = crAlloc(len1 + len2 + len3 + 1);
  if (s) {
    crMemcpy(s, str1, len1);
    crMemcpy(s + len1, str2, len2);
    crMemcpy(s + len1 + len2, str3, len3);
    s[len1 + len2 + len3] = '\0';
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crStrjoin3>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <crStrlen@plt>
  mov    %r15,%rdi
  movslq %eax,%rbp
  call   <crStrlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <crStrlen@plt>
  lea    0x0(%rbp,%rbx,1),%r12d
  add    %eax,%r12d
  mov    %eax,0x4(%rsp)
  lea    0x1(%r12),%edi
  call   <crAlloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L7
  mov    0x8(%rsp),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  movslq %r12d,%r12
  call   <crMemcpy@plt>
  lea    (%r14,%rbp,1),%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <crMemcpy@plt>
  movslq %ebx,%rdi
  mov    0x4(%rsp),%edx
  mov    %r13,%rsi
  add    %rbp,%rdi
  add    %r14,%rdi
  call   <crMemcpy@plt>
  movb   $0x0,(%r14,%r12,1)
L7:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crStrjoin3(const char *str1, const char *str2, const char *str3) {
  const int len1 = crStrlen(str1), len2 = crStrlen(str2), len3 = crStrlen(str3);
  char *s = crAlloc(len1 + len2 + len3 + 1);
  if (s) {
    crMemcpy(s, str1, len1);
    crMemcpy(s + len1, str2, len2);
    crMemcpy(s + len1 + len2, str3, len3);
    s[len1 + len2 + len3] = '\0';
  }
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<crStrjoin3>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <crStrlen@plt>
  mov    %r15,%rdi
  movslq %eax,%rbp
  call   <crStrlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <crStrlen@plt>
  lea    0x0(%rbp,%rbx,1),%r12d
  add    %eax,%r12d
  mov    %eax,0x4(%rsp)
  lea    0x1(%r12),%edi
  call   <crAlloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L5
  mov    0x8(%rsp),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  movslq %r12d,%r12
  call   <crMemcpy@plt>
  lea    (%r14,%rbp,1),%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <crMemcpy@plt>
  movslq %ebx,%rdi
  mov    0x4(%rsp),%edx
  mov    %r13,%rsi
  add    %rbp,%rdi
  add    %r14,%rdi
  call   <crMemcpy@plt>
  movb   $0x0,(%r14,%r12,1)
L5:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *crStrjoin3(const char *str1, const char *str2, const char *str3) {
  const int len1 = crStrlen(str1), len2 = crStrlen(str2), len3 = crStrlen(str3);
  char *s = crAlloc(len1 + len2 + len3 + 1);
  if (s) {
    crMemcpy(s, str1, len1);
    crMemcpy(s + len1, str2, len2);
    crMemcpy(s + len1 + len2, str3, len3);
    s[len1 + len2 + len3] = '\0';
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__wasm_float_max_f64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jnp    L28
  movsd  -0x8(%rbp),%xmm0
  jmp    L37
L28:
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jnp    L25
  movsd  -0x10(%rbp),%xmm0
  jmp    L37
L25:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L4
  movsd  -0x8(%rbp),%xmm0
  jmp    L37
L4:
  movsd  -0x10(%rbp),%xmm0
L37:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double __wasm_float_max_f64(double lhs, double rhs) {
  if (lhs != lhs)
    return lhs;
  if (rhs != rhs)
    return rhs;
  return lhs > rhs ? lhs : rhs;
}
```
user: What is the c source code of the assembly code below:

```asm
<__wasm_float_max_f64>:
  endbr64
  ucomisd %xmm0,%xmm0
  jp     L11
  ucomisd %xmm1,%xmm1
  jp     L17
  maxsd  %xmm1,%xmm0
  ret
L17:
  movapd %xmm1,%xmm0
L11:
  ret
```

assistant: ```c
double __wasm_float_max_f64(double lhs, double rhs) {
  if (lhs != lhs)
    return lhs;
  if (rhs != rhs)
    return rhs;
  return lhs > rhs ? lhs : rhs;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__wasm_float_max_f64>:
  endbr64
  ucomisd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  jp     L13
  ucomisd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  jp     L13
  maxsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
double __wasm_float_max_f64(double lhs, double rhs) {
  if (lhs != lhs)
    return lhs;
  if (rhs != rhs)
    return rhs;
  return lhs > rhs ? lhs : rhs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__wasm_float_max_f64>:
  endbr64
  ucomisd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  jp     L7
  ucomisd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  jp     L7
  maxsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
double __wasm_float_max_f64(double lhs, double rhs) {
  if (lhs != lhs)
    return lhs;
  if (rhs != rhs)
    return rhs;
  return lhs > rhs ? lhs : rhs;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_boolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L2
L18:
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L2
L1:
  mov    -0x8(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string

tool: D3: yes

tool: D15: no

assistant: ```c
int parse_boolean(char *str, int *boolean) {
  if (str == NULL)
    return 0;
  if (strcasecmp(str, "yes") == 0) {
    *boolean = 1;
    return 1;
  }
  if (strcasecmp(str, "no") == 0) {
    *boolean = 0;
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_boolean>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L13
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D1(%rip),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L31
  movl   $0x1,0x0(%rbp)
  mov    $0x1,%eax
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L26
  movl   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L26
L13:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string

tool: D1: yes

tool: D11: no

assistant: ```c
int parse_boolean(char *str, int *boolean) {
  if (str == NULL)
    return 0;
  if (strcasecmp(str, "yes") == 0) {
    *boolean = 1;
    return 1;
  }
  if (strcasecmp(str, "no") == 0) {
    *boolean = 0;
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_boolean>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  sub    $0x8,%rsp
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L24
  movl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L29:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  movl   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string

tool: D9: yes

tool: D12: no

assistant: ```c
int parse_boolean(char *str, int *boolean) {
  if (str == NULL)
    return 0;
  if (strcasecmp(str, "yes") == 0) {
    *boolean = 1;
    return 1;
  }
  if (strcasecmp(str, "no") == 0) {
    *boolean = 0;
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_boolean>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  sub    $0x8,%rsp
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L3
  movl   $0x1,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L13
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movl   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string

tool: D0: yes

tool: D14: no

assistant: ```c
int parse_boolean(char *str, int *boolean) {
  if (str == NULL)
    return 0;
  if (strcasecmp(str, "yes") == 0) {
    *boolean = 1;
    return 1;
  }
  if (strcasecmp(str, "no") == 0) {
    *boolean = 0;
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bot_fileutils_fwrite32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    $0x1,%eax
  jne    L5
  mov    $0x0,%eax
  jmp    L18
L5:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

assistant: ```c
int bot_fileutils_fwrite32(FILE *f, int32_t v) {
  v = htonl(v);
  if (fwrite(&v, 4, 1, f) == 1)
    return 0;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bot_fileutils_fwrite32>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fwrite@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int bot_fileutils_fwrite32(FILE *f, int32_t v) {
  v = htonl(v);
  if (fwrite(&v, 4, 1, f) == 1)
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bot_fileutils_fwrite32>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  lea    0xc(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %eax,0xc(%rsp)
  call   <fwrite@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int bot_fileutils_fwrite32(FILE *f, int32_t v) {
  v = htonl(v);
  if (fwrite(&v, 4, 1, f) == 1)
    return 0;
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bot_fileutils_fwrite32>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htonl@plt>
  lea    0xc(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %eax,0xc(%rsp)
  call   <fwrite@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int bot_fileutils_fwrite32(FILE *f, int32_t v) {
  v = htonl(v);
  if (fwrite(&v, 4, 1, f) == 1)
    return 0;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <push@plt>
  nop
  leave
  ret
```

assistant: ```c
void subtract() {
  int b = pop();
  int a = pop();
  push(a - b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<subtract>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <pop@plt>
  sub    %ebx,%eax
  mov    %eax,%edi
  call   <push@plt>
  pop    %rbx
  ret
```

assistant: ```c
void subtract() {
  int b = pop();
  int a = pop();
  push(a - b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<subtract>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <pop@plt>
  sub    %ebx,%eax
  pop    %rbx
  mov    %eax,%edi
  jmp    1070 <push@plt>
```

assistant: ```c
void subtract() {
  int b = pop();
  int a = pop();
  push(a - b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<subtract>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <pop@plt>
  sub    %ebx,%eax
  pop    %rbx
  mov    %eax,%edi
  jmp    1070 <push@plt>
```

assistant: ```c
void subtract() {
  int b = pop();
  int a = pop();
  push(a - b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<funcAngDist_alpha0_0plus_0plus_12049_L0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <EvalAngDist_alpha0_0plus_0plus_12049_L0@plt>
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double funcAngDist_alpha0_0plus_0plus_12049_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngDist_alpha0_0plus_0plus_12049_L0(x[0]);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<funcAngDist_alpha0_0plus_0plus_12049_L0>:
  endbr64
  push   %rbx
  mov    (%rsi),%rbx
  movsd  (%rdi),%xmm0
  call   <EvalAngDist_alpha0_0plus_0plus_12049_L0@plt>
  movq   %rbx,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double funcAngDist_alpha0_0plus_0plus_12049_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngDist_alpha0_0plus_0plus_12049_L0(x[0]);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<funcAngDist_alpha0_0plus_0plus_12049_L0>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <EvalAngDist_alpha0_0plus_0plus_12049_L0@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double funcAngDist_alpha0_0plus_0plus_12049_L0(double *x, double *par) {
  double result;
  result = par[0] * EvalAngDist_alpha0_0plus_0plus_12049_L0(x[0]);
  return result;
}
```