user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L60
  mov    %rsi,%r12
  movslq %edi,%rbp
  lea    D87(%rip),%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L36:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L36
L60:
  movdqa D107(%rip),%xmm0
  mov    $0x4,%ebp
  mov    %rsp,%r12
  lea    D61(%rip),%rax
  lea    D78(%rip),%rcx
  movq   %rax,%xmm1
  lea    D7(%rip),%rax
  movl   $0x2,0x10(%rsp)
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm2
  lea    D83(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D20(%rip),%rax
  lea    0x20(%rsp),%rbx
  movaps %xmm0,0x20(%rsp)
  movq   %rcx,%xmm0
  lea    D28(%rip),%r13
  mov    %rax,0x40(%rsp)
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x30(%rsp)
L5:
  mov    (%r12,%rbp,4),%edx
  mov    (%rbx,%rbp,8),%rsi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%rbp
  jae    L5
  lea    D34(%rip),%r13
  mov    $0x4,%ebp
  lea    D111(%rip),%r14
  mov    %r13,%rdi
  call   <puts@plt>
L61:
  mov    (%r12,%rbp,4),%edx
  mov    (%rbx,%rbp,8),%rsi
  xor    %eax,%eax
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%rbp
  jae    L61
  mov    %r13,%rdi
  mov    $0x4,%ebp
  lea    D52(%rip),%r14
  call   <puts@plt>
L21:
  mov    (%r12,%rbp,4),%edx
  mov    (%rbx,%rbp,8),%rsi
  xor    %eax,%eax
  mov    %r14,%rdi
  call   <printf@plt>
  sub    $0x1,%rbp
  jae    L21
  mov    %r13,%rdi
  mov    %r12,%rbp
  lea    D112(%rip),%r13
  call   <puts@plt>
L40:
  mov    0x0(%rbp),%edx
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rax
  sub    %r12,%rax
  cmp    $0x10,%rax
  jle    L40
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D87
type_guessed: string
name: disassemble_data
arguments: data_label: D107
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D61
type_guessed: string
name: disassemble_data
arguments: data_label: D78
type_guessed: string
name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D83
type_guessed: string
name: disassemble_data
arguments: data_label: D20
type_guessed: string
name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D111
type_guessed: string
name: disassemble_data
arguments: data_label: D52
type_guessed: string
name: disassemble_data
arguments: data_label: D112
type_guessed: string

tool: D87: the argument %d is %s.


tool: {"D107": [0x17,0x00,0x00,0x00,0x2b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x59,0x00,0x00,0x00]}

tool: D61: Frank

tool: D78: Alan

tool: D7: John

tool: D83: Mary

tool: D20: Lisa

tool: D28: %s has %d years alive.


tool: D34: ---

tool: D111: %s is %d years old.


tool: D52: %s is %d years old again.


tool: D112: %s lived %d years so far.


assistant: ```c
int main(int argc, char *argv[]) {
  char **commandArgs = argv;
  for (int k = 0; k < argc; k++) {
    printf("the argument %d is %s.\n", k, *(commandArgs + k));
  }
  int ages[] = {23, 43, 12, 89, 2};
  char *names[] = {"Alan", "Frank", "Mary", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (i = count - 1; i >= 0; i--) {
    printf("%s has %d years alive.\n", names[i], ages[i]);
  }
  printf("---\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = count - 1; i >= 0; i--) {
    printf("%s is %d years old.\n", *(cur_name + i), *(cur_age + i));
  }
  printf("---\n");
  for (i = count - 1; i >= 0; i--) {
    printf("%s is %d years old again.\n", cur_name[i], cur_age[i]);
  }
  printf("---\n");
  for (cur_name = names, cur_age = ages; (cur_age - ages) < count; cur_name++, cur_age++) {
    printf("%s lived %d years so far.\n", *cur_name, *cur_age);
  }
  return 0;
}
```