ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkforrunning>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L37
  cmpb   $0x0,(%rdi)
  je     L26
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  test   %ebx,%ebx
  js     L93
  mov    %rsp,%rbp
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x3f,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L29
  mov    %rsp,%rdi
  call   <atol@plt>
  test   %eax,%eax
  jg     L82
L29:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%eax
L93:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L82:
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <kill@plt>
  test   %eax,%eax
  jne    L29
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xfffffffe,%eax
  jmp    L93
L37:
  mov    $0xffffffff,%eax
  jmp    L93
L26:
  mov    $0xffffffff,%eax
  jmp    L93
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkforrunning(const char *fname) {
  char buffer[64];
  int pidfile;
  pid_t pid;
  if (!fname || (strlen(fname) == 0))
    return -1;
  if ((pidfile = open(fname, O_RDONLY)) < 0)
    return 0;
  memset(buffer, 0, 64);
  if (read(pidfile, buffer, 63)) {
    if ((pid = atol(buffer)) > 0) {
      if (!kill(pid, 0)) {
        close(pidfile);
        return -2;
      }
    }
  }
  close(pidfile);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<checkforrunning>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  cmpb   $0x0,(%rdi)
  je     L1
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  test   %ebp,%ebp
  js     L43
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x3f,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L40
L44:
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
L43:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %r12,%rdi
  call   <atol@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jle    L44
  xor    %esi,%esi
  call   <kill@plt>
  test   %eax,%eax
  jne    L44
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffe,%eax
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%eax
  jmp    L43
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkforrunning(const char *fname) {
  char buffer[64];
  int pidfile;
  pid_t pid;
  if (!fname || (strlen(fname) == 0))
    return -1;
  if ((pidfile = open(fname, O_RDONLY)) < 0)
    return 0;
  memset(buffer, 0, 64);
  if (read(pidfile, buffer, 63)) {
    if ((pid = atol(buffer)) > 0) {
      if (!kill(pid, 0)) {
        close(pidfile);
        return -2;
      }
    }
  }
  close(pidfile);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkforrunning>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  cmpb   $0x0,(%rdi)
  je     L1
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  test   %ebp,%ebp
  js     L88
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x3f,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L20
L40:
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
L88:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rdi
  call   <atol@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jle    L40
  xor    %esi,%esi
  call   <kill@plt>
  test   %eax,%eax
  jne    L40
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffe,%eax
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%eax
  jmp    L88
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkforrunning(const char *fname) {
  char buffer[64];
  int pidfile;
  pid_t pid;
  if (!fname || (strlen(fname) == 0))
    return -1;
  if ((pidfile = open(fname, O_RDONLY)) < 0)
    return 0;
  memset(buffer, 0, 64);
  if (read(pidfile, buffer, 63)) {
    if ((pid = atol(buffer)) > 0) {
      if (!kill(pid, 0)) {
        close(pidfile);
        return -2;
      }
    }
  }
  close(pidfile);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<af5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_hold@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *af5() {
  int *p = my_malloc(12);
  my_hold(p);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<af5>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <my_hold@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *af5() {
  int *p = my_malloc(12);
  my_hold(p);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<af5>:
  endbr64
  push   %r12
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <my_hold@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *af5() {
  int *p = my_malloc(12);
  my_hold(p);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<af5>:
  endbr64
  push   %r12
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <my_hold@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *af5() {
  int *p = my_malloc(12);
  my_hold(p);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<moveBack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <HiveX_motor_setDirection@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <HiveX_motor_setDirection@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void moveBack() {
  HiveX_motor_setDirection(0, 1);
  HiveX_motor_setDirection(1, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<moveBack>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <HiveX_motor_setDirection@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <HiveX_motor_setDirection@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void moveBack() {
  HiveX_motor_setDirection(0, 1);
  HiveX_motor_setDirection(1, 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<moveBack>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <HiveX_motor_setDirection@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <HiveX_motor_setDirection@plt>
```

assistant: ```c
void moveBack() {
  HiveX_motor_setDirection(0, 1);
  HiveX_motor_setDirection(1, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<moveBack>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <HiveX_motor_setDirection@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <HiveX_motor_setDirection@plt>
```

assistant: ```c
void moveBack() {
  HiveX_motor_setDirection(0, 1);
  HiveX_motor_setDirection(1, 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sliBubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L11
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L18:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L43
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L43:
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L18
  subl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0x0,-0x10(%rbp)
  jns    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sliBubbleSort(signed long long int sliarray[], int size) {
  int i, j;
  signed long long int temp;
  for (i = (size - 1); i >= 0; i--) {
    for (j = 0; j < i; j++) {
      if (sliarray[j + 1] < sliarray[j]) {
        temp = sliarray[j + 1];
        sliarray[j + 1] = sliarray[j];
        sliarray[j] = temp;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sliBubbleSort>:
  endbr64
  test   %esi,%esi
  jle    L50
  lea    -0x2(%rsi),%r8d
  lea    0x8(%rdi),%r9
  jmp    L32
L53:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L45
L56:
  mov    0x8(%rax),%rdx
  mov    (%rax),%rcx
  cmp    %rcx,%rdx
  jge    L53
  mov    %rcx,0x8(%rax)
  mov    %rdx,(%rax)
  jmp    L53
L52:
  test   %r8d,%r8d
  jns    L45
L50:
  ret
L45:
  sub    $0x1,%r8d
L32:
  lea    0x1(%r8),%eax
  test   %eax,%eax
  jle    L52
  mov    %rdi,%rax
  mov    %r8d,%edx
  lea    (%r9,%rdx,8),%rsi
  jmp    L56
```

assistant: ```c
void sliBubbleSort(signed long long int sliarray[], int size) {
  int i, j;
  signed long long int temp;
  for (i = (size - 1); i >= 0; i--) {
    for (j = 0; j < i; j++) {
      if (sliarray[j + 1] < sliarray[j]) {
        temp = sliarray[j + 1];
        sliarray[j + 1] = sliarray[j];
        sliarray[j] = temp;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sliBubbleSort>:
  endbr64
  lea    0x8(%rdi),%r9
  sub    $0x1,%esi
  js     L24
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L51
  nopl   (%rax)
L53:
  mov    %r8d,%edx
  mov    %rdi,%rax
  lea    (%r9,%rdx,8),%rsi
  nopw   0x0(%rax,%rax,1)
L57:
  mov    0x8(%rax),%rdx
  mov    (%rax),%rcx
  cmp    %rcx,%rdx
  jge    L14
  mov    %rcx,0x8(%rax)
  mov    %rdx,(%rax)
L14:
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L57
L21:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jg     L53
L51:
  test   %r8d,%r8d
  jns    L21
  ret
L24:
  ret
```

assistant: ```c
void sliBubbleSort(signed long long int sliarray[], int size) {
  int i, j;
  signed long long int temp;
  for (i = (size - 1); i >= 0; i--) {
    for (j = 0; j < i; j++) {
      if (sliarray[j + 1] < sliarray[j]) {
        temp = sliarray[j + 1];
        sliarray[j + 1] = sliarray[j];
        sliarray[j] = temp;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sliBubbleSort>:
  endbr64
  lea    0x8(%rdi),%r9
  sub    $0x1,%esi
  js     L41
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L19
  nopl   (%rax)
L58:
  mov    %r8d,%eax
  mov    %rdi,%rdx
  lea    (%r9,%rax,8),%rsi
  nopw   0x0(%rax,%rax,1)
L49:
  movdqu (%rdx),%xmm0
  movhlps %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  movq   %xmm0,%rcx
  movq   %xmm2,%rax
  shufpd $0x1,%xmm0,%xmm1
  cmp    %rax,%rcx
  jle    L35
  movups %xmm1,(%rdx)
L35:
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L49
L7:
  mov    %r8d,%esi
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jg     L58
L19:
  test   %r8d,%r8d
  jns    L7
  ret
L41:
  ret
```

assistant: ```c
void sliBubbleSort(signed long long int sliarray[], int size) {
  int i, j;
  signed long long int temp;
  for (i = (size - 1); i >= 0; i--) {
    for (j = 0; j < i; j++) {
      if (sliarray[j + 1] < sliarray[j]) {
        temp = sliarray[j + 1];
        sliarray[j + 1] = sliarray[j];
        sliarray[j] = temp;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<talloc_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L12
  mov    $0x0,%eax
  jmp    L0
L12:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__talloc_strlendup@plt>
L0:
  leave
  ret
```

assistant: ```c
char *talloc_strndup(const void *t, const char *p, size_t n) {
  if (__builtin_expect(!!(!p), 0))
    return NULL;
  return __talloc_strlendup(t, p, strnlen(p, n));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<talloc_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rsi,%rsi
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L8
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strnlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <__talloc_strlendup@plt>
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *talloc_strndup(const void *t, const char *p, size_t n) {
  if (__builtin_expect(!!(!p), 0))
    return NULL;
  return __talloc_strlendup(t, p, strnlen(p, n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<talloc_strndup>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  sete   %dil
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L0
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <__talloc_strlendup@plt>
  nopl   0x0(%rax)
L0:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *talloc_strndup(const void *t, const char *p, size_t n) {
  if (__builtin_expect(!!(!p), 0))
    return NULL;
  return __talloc_strlendup(t, p, strnlen(p, n));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<talloc_strndup>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  sete   %dil
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L3
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <__talloc_strlendup@plt>
  nopl   0x0(%rax)
L3:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *talloc_strndup(const void *t, const char *p, size_t n) {
  if (__builtin_expect(!!(!p), 0))
    return NULL;
  return __talloc_strlendup(t, p, strnlen(p, n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<source_handler_http_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D11(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <spx_php_global_array_get@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D11: HTTP_%s

tool: D7: _SERVER

assistant: ```c
const char *source_handler_http_header(const char *parameter) {
  char key[128];
  snprintf(key, sizeof(key), "HTTP_%s", parameter);
  return spx_php_global_array_get("_SERVER", key);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<source_handler_http_header>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D16(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <spx_php_global_array_get@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x90,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D16: HTTP_%s

tool: D13: _SERVER

assistant: ```c
const char *source_handler_http_header(const char *parameter) {
  char key[128];
  snprintf(key, sizeof(key), "HTTP_%s", parameter);
  return spx_php_global_array_get("_SERVER", key);
}
```
user: What is the c source code of the assembly code below?

```asm
<source_handler_http_header>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D12(%rip),%rdx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <spx_php_global_array_get@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x90,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D12: HTTP_%s

tool: D3: _SERVER

assistant: ```c
const char *source_handler_http_header(const char *parameter) {
  char key[128];
  snprintf(key, sizeof(key), "HTTP_%s", parameter);
  return spx_php_global_array_get("_SERVER", key);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<source_handler_http_header>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  lea    D12(%rip),%rdx
  mov    $0x80,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <spx_php_global_array_get@plt>
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x90,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D12: HTTP_%s

tool: D4: _SERVER

assistant: ```c
const char *source_handler_http_header(const char *parameter) {
  char key[128];
  snprintf(key, sizeof(key), "HTTP_%s", parameter);
  return spx_php_global_array_get("_SERVER", key);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<interpolate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  imul   %edx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int interpolate(int x, int xa, int xb, int ya, int yb) {
  int bf, factor, plus;
  bf = 2 * (yb - ya) * (x - xa) / (xb - xa);
  factor = bf / 2;
  plus = bf % 2;
  return ya + factor + plus;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<interpolate>:
  endbr64
  mov    %r8d,%eax
  sub    %ecx,%eax
  sub    %esi,%edi
  imul   %edi,%eax
  add    %eax,%eax
  mov    %edx,%edi
  sub    %esi,%edi
  cltd
  idiv   %edi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  add    %ecx,%edx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int interpolate(int x, int xa, int xb, int ya, int yb) {
  int bf, factor, plus;
  bf = 2 * (yb - ya) * (x - xa) / (xb - xa);
  factor = bf / 2;
  plus = bf % 2;
  return ya + factor + plus;
}
```
user: What is the c source code of the assembly code below:

```asm
<interpolate>:
  endbr64
  mov    %r8d,%eax
  sub    %esi,%edi
  sub    %ecx,%eax
  imul   %edi,%eax
  mov    %edx,%edi
  sub    %esi,%edi
  add    %eax,%eax
  cltd
  idiv   %edi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  add    %ecx,%edx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int interpolate(int x, int xa, int xb, int ya, int yb) {
  int bf, factor, plus;
  bf = 2 * (yb - ya) * (x - xa) / (xb - xa);
  factor = bf / 2;
  plus = bf % 2;
  return ya + factor + plus;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<interpolate>:
  endbr64
  mov    %r8d,%eax
  sub    %esi,%edi
  sub    %ecx,%eax
  imul   %edi,%eax
  mov    %edx,%edi
  sub    %esi,%edi
  add    %eax,%eax
  cltd
  idiv   %edi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  add    %ecx,%edx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int interpolate(int x, int xa, int xb, int ya, int yb) {
  int bf, factor, plus;
  bf = 2 * (yb - ya) * (x - xa) / (xb - xa);
  factor = bf / 2;
  plus = bf % 2;
  return ya + factor + plus;
}
```
user: Translate the below assembly code into C programming language:

```asm
<removeLeadingZeros_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L14
L24:
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L24
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L24
L41:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L64
L26:
  addq   $0x1,-0x10(%rbp)
L64:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L38
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
L38:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *removeLeadingZeros_str(char *s) {
  char *front = s;
  while ((front[1] != '\0') && ((front[0] == '0') || (front[0] == '-')))
    front++;
  char *end = front;
  while (end[0] != '\0')
    end++;
  char *new = malloc(((end - front) + 2) * sizeof(char));
  strcpy(new, front);
  if (s[0] == '-') {
    memmove(new + 1, new, (end - front) + 1);
    new[0] = '-';
  }
  return new;
}
```