user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbx
  lea    0x8(%rsp),%rbp
L314:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <__VERIFIER_nondet_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L314
  xor    %edi,%edi
  cmpb   $0x0,0x7(%rsp)
  sete   %dil
  call   <__VERIFIER_assume@plt>
  movzbl 0x3(%rsp),%eax
  test   %al,%al
  je     L211
  movzbl 0x4(%rsp),%ecx
  test   %cl,%cl
  je     L231
  cmpb   $0x0,0x5(%rsp)
  je     L272
  cmpb   $0x0,0x6(%rsp)
  je     L117
  cmp    $0x61,%al
  je     L42
  xor    %edx,%edx
  cmp    $0x41,%al
  mov    $0x4,%edi
  sete   %dl
L9:
  cmp    $0x61,%cl
  je     L19
  cmp    $0x41,%cl
  jne    L213
L19:
  add    $0x1,%edx
L213:
  movzbl 0x5(%rsp),%esi
  cmp    $0x2,%edi
  je     L233
  cmp    $0x61,%sil
  je     L120
  cmp    $0x41,%sil
  jne    L63
L120:
  add    $0x1,%edx
L63:
  cmp    $0x4,%edi
  jne    L233
  movzbl 0x6(%rsp),%edi
  cmp    $0x61,%dil
  je     L318
  cmp    $0x41,%dil
  jne    L233
L318:
  add    $0x1,%edx
L233:
  cmp    $0x61,%al
  je     L35
  cmp    $0x41,%al
  sete   %al
  movzbl %al,%eax
L17:
  cmp    $0x61,%cl
  je     L335
  cmp    $0x41,%cl
  jne    L147
L335:
  add    $0x1,%eax
L147:
  test   %sil,%sil
  je     L62
  cmp    $0x61,%sil
  je     L15
  cmp    $0x41,%sil
  jne    L313
L15:
  add    $0x1,%eax
L313:
  movzbl 0x6(%rsp),%ecx
  test   %cl,%cl
  je     L62
  cmp    $0x61,%cl
  je     L294
  cmp    $0x41,%cl
  jne    L62
L294:
  add    $0x1,%eax
L62:
  xor    %edi,%edi
  cmp    %edx,%eax
  sete   %dil
  call   <__VERIFIER_assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x1,%eax
  jmp    L17
L211:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L62
L117:
  cmp    $0x61,%al
  je     L319
  xor    %edx,%edx
  cmp    $0x41,%al
  mov    $0x3,%edi
  sete   %dl
  jmp    L9
L231:
  cmp    $0x61,%al
  je     L1
  xor    %edx,%edx
  cmp    $0x41,%al
  sete   %dl
  mov    %edx,%eax
  jmp    L62
L42:
  mov    $0x4,%edi
  mov    $0x1,%edx
  jmp    L9
L272:
  cmp    $0x61,%al
  je     L12
  xor    %edx,%edx
  cmp    $0x41,%al
  mov    $0x2,%edi
  sete   %dl
  jmp    L9
L1:
  mov    $0x1,%edx
  mov    $0x1,%eax
  jmp    L62
L12:
  mov    $0x2,%edi
  mov    $0x1,%edx
  jmp    L9
L319:
  mov    $0x3,%edi
  mov    $0x1,%edx
  jmp    L9
L131:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main(void) {
  char input_string[5], vogal_array[] = {'a', 'A', 'e', 'E', 'i', 'I', 'o', 'O', 'u', 'U', '\0'};
  ;
  unsigned int i, j, cont, tam_string, n_caracter;
  for (i = 0; i < 5; i++)
    input_string[i] = __VERIFIER_nondet_char();
  __VERIFIER_assume(input_string[5 - 1] == '\0');
  n_caracter = 0;
  while (input_string[n_caracter] != '\0')
    n_caracter++;
  cont = 0;
  for (i = 0; i < n_caracter; i++)
    for (j = 0; j < 5 / 2; j++)
      if (input_string[i] == vogal_array[j])
        cont++;
  i = 0;
  int cont_aux = 0;
  while (input_string[i] != '\0') {
    for (j = 0; j < 5 / 2; j++) {
      if (input_string[i] == vogal_array[j])
        cont_aux++;
    }
    i++;
  }
  __VERIFIER_assert(cont_aux == cont);
}
```