ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<_eaud_hex_string_to_octet_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex_char_to_nibble@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L9
  mov    -0xc(%rbp),%eax
  jmp    L4
L9:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex_char_to_nibble@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L51
  mov    -0xc(%rbp),%eax
  jmp    L4
L51:
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x2,-0x20(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  mov    -0xc(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int _eaud_hex_string_to_octet_string(char *raw, char *hex, int len) {
  uint8_t x;
  int tmp;
  int hex_len;
  hex_len = 0;
  while (hex_len < len) {
    tmp = hex_char_to_nibble(hex[0]);
    if (tmp == -1) {
      return hex_len;
    }
    x = (tmp << 4);
    hex_len++;
    tmp = hex_char_to_nibble(hex[1]);
    if (tmp == -1) {
      return hex_len;
    }
    x |= (tmp & 0xff);
    hex_len++;
    *raw++ = x;
    hex += 2;
  }
  return hex_len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_eaud_hex_string_to_octet_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L30
  mov    %rdi,%r12
  mov    %rsi,%rbp
  sub    $0x1,%edx
  shr    %edx
  lea    0x1(%rdx),%r14d
  add    %rdi,%r14
  mov    $0x0,%r13d
L5:
  movsbl 0x0(%rbp),%edi
  call   <hex_char_to_nibble@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L42
  shl    $0x4,%ebx
  movsbl 0x1(%rbp),%edi
  call   <hex_char_to_nibble@plt>
  cmp    $0xffffffff,%eax
  je     L59
  add    $0x2,%r13d
  add    $0x1,%r12
  movzbl %al,%eax
  or     %ebx,%eax
  mov    %al,-0x1(%r12)
  add    $0x2,%rbp
  cmp    %r14,%r12
  jne    L5
  jmp    L42
L59:
  add    $0x1,%r13d
L42:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  mov    $0x0,%r13d
  jmp    L42
```

assistant: ```c
int _eaud_hex_string_to_octet_string(char *raw, char *hex, int len) {
  uint8_t x;
  int tmp;
  int hex_len;
  hex_len = 0;
  while (hex_len < len) {
    tmp = hex_char_to_nibble(hex[0]);
    if (tmp == -1) {
      return hex_len;
    }
    x = (tmp << 4);
    hex_len++;
    tmp = hex_char_to_nibble(hex[1]);
    if (tmp == -1) {
      return hex_len;
    }
    x |= (tmp & 0xff);
    hex_len++;
    *raw++ = x;
    hex += 2;
  }
  return hex_len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_eaud_hex_string_to_octet_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L14
  sub    $0x1,%edx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  xor    %r13d,%r13d
  shr    %edx
  lea    0x1(%rdx),%r14d
  add    %rdi,%r14
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L52:
  movsbl 0x1(%rbp),%edi
  shl    $0x4,%ebx
  call   <hex_char_to_nibble@plt>
  cmp    $0xffffffff,%eax
  je     L16
  movzbl %al,%eax
  add    $0x1,%r12
  add    $0x2,%r13d
  add    $0x2,%rbp
  or     %ebx,%eax
  mov    %al,-0x1(%r12)
  cmp    %r14,%r12
  je     L50
L22:
  movsbl 0x0(%rbp),%edi
  call   <hex_char_to_nibble@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L52
L50:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  xor    %r13d,%r13d
  jmp    L50
```

assistant: ```c
int _eaud_hex_string_to_octet_string(char *raw, char *hex, int len) {
  uint8_t x;
  int tmp;
  int hex_len;
  hex_len = 0;
  while (hex_len < len) {
    tmp = hex_char_to_nibble(hex[0]);
    if (tmp == -1) {
      return hex_len;
    }
    x = (tmp << 4);
    hex_len++;
    tmp = hex_char_to_nibble(hex[1]);
    if (tmp == -1) {
      return hex_len;
    }
    x |= (tmp & 0xff);
    hex_len++;
    *raw++ = x;
    hex += 2;
  }
  return hex_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_eaud_hex_string_to_octet_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L3
  sub    $0x1,%edx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  xor    %r13d,%r13d
  shr    %edx
  lea    0x1(%rdx),%r14d
  add    %rdi,%r14
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L26:
  movsbl 0x1(%rbp),%edi
  shl    $0x4,%ebx
  call   <hex_char_to_nibble@plt>
  cmp    $0xffffffff,%eax
  je     L53
  movzbl %al,%eax
  add    $0x1,%r12
  add    $0x2,%r13d
  add    $0x2,%rbp
  or     %ebx,%eax
  mov    %al,-0x1(%r12)
  cmp    %r14,%r12
  je     L11
L15:
  movsbl 0x0(%rbp),%edi
  call   <hex_char_to_nibble@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L26
L11:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  add    $0x1,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  xor    %r13d,%r13d
  jmp    L11
```

assistant: ```c
int _eaud_hex_string_to_octet_string(char *raw, char *hex, int len) {
  uint8_t x;
  int tmp;
  int hex_len;
  hex_len = 0;
  while (hex_len < len) {
    tmp = hex_char_to_nibble(hex[0]);
    if (tmp == -1) {
      return hex_len;
    }
    x = (tmp << 4);
    hex_len++;
    tmp = hex_char_to_nibble(hex[1]);
    if (tmp == -1) {
      return hex_len;
    }
    x |= (tmp & 0xff);
    hex_len++;
    *raw++ = x;
    hex += 2;
  }
  return hex_len;
}
```
user: What is the c source code of the assembly code below?

```asm
<log2_ceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L3:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int log2_ceil(int x) {
  int r = 1;
  while (1 << r < x)
    r++;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<log2_ceil>:
  endbr64
  cmp    $0x2,%edi
  jle    L4
  mov    $0x1,%ecx
  mov    $0x1,%edx
L25:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L25
L6:
  mov    %ecx,%eax
  ret
L4:
  mov    $0x1,%ecx
  jmp    L6
```

assistant: ```c
int log2_ceil(int x) {
  int r = 1;
  while (1 << r < x)
    r++;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log2_ceil>:
  endbr64
  mov    $0x1,%ecx
  cmp    $0x2,%edi
  jle    L17
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L18
L17:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int log2_ceil(int x) {
  int r = 1;
  while (1 << r < x)
    r++;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<log2_ceil>:
  endbr64
  mov    $0x1,%ecx
  cmp    $0x2,%edi
  jle    L16
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %edi,%eax
  jl     L4
L16:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int log2_ceil(int x) {
  int r = 1;
  while (1 << r < x)
    r++;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x3,%rax
  or     $0x61bab5,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  jne    L7
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shr    %rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  or     $0x1b1b1ac7,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if (!((state[0UL] >> 3UL) & 1UL)) {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
    }
    output[0UL] = state[0UL] | 454761159UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  test   $0x8,%dl
  jne    L1
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L1:
  or     $0x1b1b1ac7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if (!((state[0UL] >> 3UL) & 1UL)) {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
    }
    output[0UL] = state[0UL] | 454761159UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  and    $0x8,%edx
  jne    L1
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L1:
  or     $0x1b1b1ac7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if (!((state[0UL] >> 3UL) & 1UL)) {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
    }
    output[0UL] = state[0UL] | 454761159UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  and    $0x8,%edx
  jne    L3
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L3:
  or     $0x1b1b1ac7,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if (!((state[0UL] >> 3UL) & 1UL)) {
      state[0UL] <<= ((state[0UL] >> 1UL) & 7UL) | 1UL;
    }
    output[0UL] = state[0UL] | 454761159UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<proc_step_and_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <proc_step@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L14
  mov    $0xffffffff,%eax
  jmp    L2
L14:
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    %eax,%edi
  call   <waitid@plt>
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int proc_step_and_wait(pid_t pid) {
  int ret;
  siginfo_t info;
  ret = proc_step(pid);
  if (ret)
    return -1;
  waitid(P_PID, pid, &info, WSTOPPED);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<proc_step_and_wait>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <proc_step@plt>
  test   %eax,%eax
  jne    L17
  mov    %eax,%ebx
  lea    0x4(%rsp),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebp,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <waitid@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0xffffffff,%ebx
  jmp    L26
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int proc_step_and_wait(pid_t pid) {
  int ret;
  siginfo_t info;
  ret = proc_step(pid);
  if (ret)
    return -1;
  waitid(P_PID, pid, &info, WSTOPPED);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<proc_step_and_wait>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <proc_step@plt>
  test   %eax,%eax
  jne    L24
  mov    %eax,%r12d
  mov    D14(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    %ebp,%esi
  mov    (%rax),%ecx
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <waitid@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0xffffffff,%r12d
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int proc_step_and_wait(pid_t pid) {
  int ret;
  siginfo_t info;
  ret = proc_step(pid);
  if (ret)
    return -1;
  waitid(P_PID, pid, &info, WSTOPPED);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proc_step_and_wait>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <proc_step@plt>
  test   %eax,%eax
  jne    L6
  mov    %eax,%r12d
  mov    D17(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    %ebp,%esi
  mov    (%rax),%ecx
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <waitid@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%r12d
  jmp    L1
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int proc_step_and_wait(pid_t pid) {
  int ret;
  siginfo_t info;
  ret = proc_step(pid);
  if (ret)
    return -1;
  waitid(P_PID, pid, &info, WSTOPPED);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tty_FlushIn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L2:
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void tty_FlushIn() {
  char key;
  while (read(0, &key, 1) != -1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tty_FlushIn>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
L9:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tty_FlushIn() {
  char key;
  while (read(0, &key, 1) != -1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tty_FlushIn>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  xchg   %ax,%ax
L2:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tty_FlushIn() {
  char key;
  while (read(0, &key, 1) != -1)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<tty_FlushIn>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  xchg   %ax,%ax
L11:
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tty_FlushIn() {
  char key;
  while (read(0, &key, 1) != -1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm

:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L20
  mov    $0x58,%eax
  jmp    L16
L20:
  cmpl   $0x0,-0x4(%rbp)
  jne    L53
  mov    $0x4f,%eax
  jmp    L16
L53:
  cmpl   $0x2,-0x4(%rbp)
  jne    L40
  mov    $0x20,%eax
  jmp    L16
L40:
  mov    $0x20,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
char s(int r) {
  if (r == 1) {
    return 88;
  }
  if (r == 0) {
    return 79;
  }
  if (r == 2) {
    return 32;
  }
  return 32;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm

:
  endbr64
  mov    $0x58,%eax
  cmp    $0x1,%edi
  je     L2
  sbb    %eax,%eax
  and    $0x2f,%eax
  add    $0x20,%eax
L2:
  ret
```

assistant: ```c
char s(int r) {
  if (r == 1) {
    return 88;
  }
  if (r == 0) {
    return 79;
  }
  if (r == 2) {
    return 32;
  }
  return 32;
}
```
user: What would the C source look like for the assembly code provided here?

```asm

:
  endbr64
  mov    $0x58,%eax
  cmp    $0x1,%edi
  je     L4
  sbb    %eax,%eax
  and    $0x2f,%eax
  add    $0x20,%eax
L4:
  ret
```

assistant: ```c
char s(int r) {
  if (r == 1) {
    return 88;
  }
  if (r == 0) {
    return 79;
  }
  if (r == 2) {
    return 32;
  }
  return 32;
}
```
user: What would the C source look like for the assembly code provided here?

```asm

:
  endbr64
  mov    $0x58,%eax
  cmp    $0x1,%edi
  je     L5
  sbb    %eax,%eax
  and    $0x2f,%eax
  add    $0x20,%eax
L5:
  ret
```

assistant: ```c
char s(int r) {
  if (r == 1) {
    return 88;
  }
  if (r == 0) {
    return 79;
  }
  if (r == 2) {
    return 32;
  }
  return 32;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printCounterResults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D0
datatype: string

tool: D26: lines = %i 


tool: D3: characters = %i 


tool: D0: words = %i 


assistant: ```c
void printCounterResults(int *lines, int *characters, int *words) {
  printf("\n");
  printf("lines = %i \n", *lines);
  printf("characters = %i \n", *characters);
  printf("words = %i \n", *words);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printCounterResults>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%r12),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D15: lines = %i 


tool: D24: characters = %i 


tool: D7: words = %i 


assistant: ```c
void printCounterResults(int *lines, int *characters, int *words) {
  printf("\n");
  printf("lines = %i \n", *lines);
  printf("characters = %i \n", *characters);
  printf("words = %i \n", *words);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printCounterResults>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <putchar@plt>
  mov    (%r12),%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D18(%rip),%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string

tool: D6: lines = %i 


tool: D10: characters = %i 


tool: D18: words = %i 


assistant: ```c
void printCounterResults(int *lines, int *characters, int *words) {
  printf("\n");
  printf("lines = %i \n", *lines);
  printf("characters = %i \n", *characters);
  printf("words = %i \n", *words);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printCounterResults>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <putchar@plt>
  mov    (%r12),%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D1(%rip),%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string

tool: D25: lines = %i 


tool: D16: characters = %i 


tool: D1: words = %i 


assistant: ```c
void printCounterResults(int *lines, int *characters, int *words) {
  printf("\n");
  printf("lines = %i \n", *lines);
  printf("characters = %i \n", *characters);
  printf("words = %i \n", *words);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <vga_cls@plt>
L9:
  jmp    L9
```

assistant: ```c
void main() {
  vga_cls();
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <vga_cls@plt>
L5:
  jmp    L5
```

assistant: ```c
void main() {
  vga_cls();
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <vga_cls@plt>
L8:
  jmp    L8
```

assistant: ```c
void main() {
  vga_cls();
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <vga_cls@plt>
L9:
  jmp    L9
```

assistant: ```c
void main() {
  vga_cls();
  while (1)
    ;
}
```