ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arr_uint8_clear_conditional>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L27
L15:
  movzwl -0x2(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L26
  movzwl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L26:
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L27:
  movzwl -0x2(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arr_uint8_clear_conditional(unsigned char *pDest, unsigned short int *pTest, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    if (pTest[i] == 0) {
      pDest[i] = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr_uint8_clear_conditional>:
  endbr64
  test   %rdx,%rdx
  je     L24
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L20
L30:
  add    $0x1,%ecx
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jae    L24
L20:
  cmpw   $0x0,(%rsi,%rax,2)
  jne    L30
  movb   $0x0,(%rdi,%rax,1)
  jmp    L30
L24:
  ret
```

assistant: ```c
void arr_uint8_clear_conditional(unsigned char *pDest, unsigned short int *pTest, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    if (pTest[i] == 0) {
      pDest[i] = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arr_uint8_clear_conditional>:
  endbr64
  test   %rdx,%rdx
  je     L4
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  cmpw   $0x0,(%rsi,%rax,2)
  jne    L6
  movb   $0x0,(%rdi,%rax,1)
L6:
  add    $0x1,%ecx
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jb     L19
L4:
  ret
```

assistant: ```c
void arr_uint8_clear_conditional(unsigned char *pDest, unsigned short int *pTest, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    if (pTest[i] == 0) {
      pDest[i] = 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arr_uint8_clear_conditional>:
  endbr64
  test   %rdx,%rdx
  je     L22
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L23:
  cmpw   $0x0,(%rsi,%rax,2)
  jne    L1
  movb   $0x0,(%rdi,%rax,1)
L1:
  add    $0x1,%ecx
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jb     L23
L22:
  ret
```

assistant: ```c
void arr_uint8_clear_conditional(unsigned char *pDest, unsigned short int *pTest, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    if (pTest[i] == 0) {
      pDest[i] = 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L29:
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L30
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy2d(double **u_previous, double **u_current, int dimX, int dimY) {
  int i, j;
  for (i = 0; i < dimX; i++)
    for (j = 0; j < dimY; j++)
      u_previous[i][j] = u_current[i][j];
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy2d>:
  endbr64
  test   %edx,%edx
  jle    L1
  mov    %rsi,%r8
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r9
  lea    -0x1(%rcx),%eax
  lea    0x8(,%rax,8),%rsi
  jmp    L51
L34:
  mov    (%r8),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    (%rdi),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L34
L21:
  add    $0x8,%r8
  add    $0x8,%rdi
  cmp    %r9,%r8
  je     L1
L51:
  mov    $0x0,%eax
  test   %ecx,%ecx
  jg     L34
  jmp    L21
L1:
  ret
```

assistant: ```c
void copy2d(double **u_previous, double **u_current, int dimX, int dimY) {
  int i, j;
  for (i = 0; i < dimX; i++)
    for (j = 0; j < dimY; j++)
      u_previous[i][j] = u_current[i][j];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy2d>:
  endbr64
  mov    %rdi,%r11
  test   %edx,%edx
  jle    L12
  movslq %edx,%r10
  xor    %r9d,%r9d
  movslq %ecx,%r8
  nopl   0x0(%rax)
L19:
  test   %ecx,%ecx
  jle    L31
  mov    (%rsi,%r9,8),%rdi
  mov    (%r11,%r9,8),%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L27:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L27
L31:
  add    $0x1,%r9
  cmp    %r10,%r9
  jne    L19
L12:
  ret
```

assistant: ```c
void copy2d(double **u_previous, double **u_current, int dimX, int dimY) {
  int i, j;
  for (i = 0; i < dimX; i++)
    for (j = 0; j < dimY; j++)
      u_previous[i][j] = u_current[i][j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy2d>:
  endbr64
  test   %edx,%edx
  jle    L11
  mov    %ecx,%r10d
  test   %ecx,%ecx
  jle    L11
  mov    %ecx,%eax
  push   %r13
  mov    %rdi,%r11
  xor    %r8d,%r8d
  push   %r12
  shr    %eax
  mov    %ecx,%r12d
  lea    -0x1(%rcx),%r13d
  lea    -0x1(%rax),%edi
  and    $0xfffffffe,%r12d
  push   %rbp
  mov    %ecx,%r9d
  push   %rbx
  add    $0x1,%rdi
  mov    %rsi,%rbx
  mov    %r12d,%esi
  shl    $0x4,%rdi
  movslq %edx,%rbp
  shl    $0x3,%rsi
  nopl   (%rax)
L19:
  mov    (%rbx,%r8,8),%rdx
  mov    (%r11,%r8,8),%rcx
  lea    0x8(%rdx),%rax
  cmp    %rax,%rcx
  je     L45
  xor    %eax,%eax
  cmp    $0x2,%r13d
  jbe    L45
  nopl   0x0(%rax)
L20:
  movupd (%rdx,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L20
  cmp    %r12d,%r10d
  je     L51
  movsd  (%rdx,%rsi,1),%xmm0
  movsd  %xmm0,(%rcx,%rsi,1)
L51:
  add    $0x1,%r8
  cmp    %rbp,%r8
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L16
  jmp    L51
L11:
  ret
```

assistant: ```c
void copy2d(double **u_previous, double **u_current, int dimX, int dimY) {
  int i, j;
  for (i = 0; i < dimX; i++)
    for (j = 0; j < dimY; j++)
      u_previous[i][j] = u_current[i][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lang_readcompatibility>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    $0x20,%ecx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <lang_readstring@plt>
  mov    -0x50(%rbp),%rsi
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jg     L16
  mov    -0x50(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L16:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D8: LANG_COMPATIBILITY

tool: D14: %d.%d.%d

assistant: ```c
void lang_readcompatibility(const char *filename, int *ver, int *subver, int *wipver) {
  char compat[32];
  lang_readstring(filename, "LANG_COMPATIBILITY", compat, sizeof(compat));
  if (sscanf(compat, "%d.%d.%d", ver, subver, wipver) < 3)
    *ver = *subver = *wipver = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lang_readcompatibility>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0x20,%ecx
  mov    %r13,%rdx
  lea    D14(%rip),%rsi
  call   <lang_readstring@plt>
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D6(%rip),%rsi
  mov    %r13,%rdi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jg     L7
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  movl   $0x0,(%rbx)
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D14: LANG_COMPATIBILITY

tool: D6: %d.%d.%d

assistant: ```c
void lang_readcompatibility(const char *filename, int *ver, int *subver, int *wipver) {
  char compat[32];
  lang_readstring(filename, "LANG_COMPATIBILITY", compat, sizeof(compat));
  if (sscanf(compat, "%d.%d.%d", ver, subver, wipver) < 3)
    *ver = *subver = *wipver = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lang_readcompatibility>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    $0x20,%ecx
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D1(%rip),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdx
  call   <lang_readstring@plt>
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D9(%rip),%rsi
  mov    %r13,%rdi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jg     L7
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  movl   $0x0,(%rbx)
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D1: LANG_COMPATIBILITY

tool: D9: %d.%d.%d

assistant: ```c
void lang_readcompatibility(const char *filename, int *ver, int *subver, int *wipver) {
  char compat[32];
  lang_readstring(filename, "LANG_COMPATIBILITY", compat, sizeof(compat));
  if (sscanf(compat, "%d.%d.%d", ver, subver, wipver) < 3)
    *ver = *subver = *wipver = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lang_readcompatibility>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  mov    $0x20,%ecx
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D5(%rip),%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdx
  call   <lang_readstring@plt>
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D12(%rip),%rsi
  mov    %r13,%rdi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jg     L10
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  movl   $0x0,(%rbx)
L10:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D12
datatype: string

tool: D5: LANG_COMPATIBILITY

tool: D12: %d.%d.%d

assistant: ```c
void lang_readcompatibility(const char *filename, int *ver, int *subver, int *wipver) {
  char compat[32];
  lang_readstring(filename, "LANG_COMPATIBILITY", compat, sizeof(compat));
  if (sscanf(compat, "%d.%d.%d", ver, subver, wipver) < 3)
    *ver = *subver = *wipver = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: main


assistant: ```c
int main() {
  printf("main\n");
  foo();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: main


assistant: ```c
int main() {
  printf("main\n");
  foo();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: main


assistant: ```c
int main() {
  printf("main\n");
  foo();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: main


assistant: ```c
int main() {
  printf("main\n");
  foo();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<itos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <count_digits@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L16
L3:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x0,-0x14(%rbp)
  jns    L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *itos(int x) {
  int ndigits = count_digits(x, 0);
  char *s = malloc(ndigits + 1);
  int i;
  int n = x;
  s[ndigits] = 0;
  for (i = ndigits - 1; i >= 0; i--) {
    s[i] = n % 10 + 48;
    n /= 10;
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%esi
  call   <count_digits@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movslq %ebp,%rax
  movb   $0x0,(%rdi,%rax,1)
  mov    %ebp,%edx
  sub    $0x1,%edx
  js     L1
  movslq %edx,%rdx
  add    %rdi,%rdx
  lea    -0x2(%rdi,%rax,1),%rsi
  lea    -0x1(%rbp),%eax
  sub    %rax,%rsi
L14:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rdx)
  mov    %eax,%ebx
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L14
L1:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *itos(int x) {
  int ndigits = count_digits(x, 0);
  char *s = malloc(ndigits + 1);
  int i;
  int n = x;
  s[ndigits] = 0;
  for (i = ndigits - 1; i >= 0; i--) {
    s[i] = n % 10 + 48;
    n /= 10;
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itos>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <count_digits@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  mov    %rax,%r8
  movslq %ebp,%rax
  movb   $0x0,(%r8,%rax,1)
  sub    $0x1,%ebp
  js     L14
  movslq %ebp,%rdx
  lea    -0x2(%r8,%rax,1),%rsi
  mov    %ebp,%ebp
  add    %r8,%rdx
  sub    %rbp,%rsi
  nopl   (%rax)
L7:
  movslq %ebx,%rax
  mov    %ebx,%ecx
  sub    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rdx)
  mov    %eax,%ebx
  cmp    %rsi,%rdx
  jne    L7
L14:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *itos(int x) {
  int ndigits = count_digits(x, 0);
  char *s = malloc(ndigits + 1);
  int i;
  int n = x;
  s[ndigits] = 0;
  for (i = ndigits - 1; i >= 0; i--) {
    s[i] = n % 10 + 48;
    n /= 10;
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itos>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <count_digits@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  mov    %rax,%r8
  movslq %ebp,%rax
  movb   $0x0,(%r8,%rax,1)
  sub    $0x1,%ebp
  js     L8
  movslq %ebp,%rdx
  lea    -0x2(%r8,%rax,1),%rsi
  mov    %ebp,%ebp
  add    %r8,%rdx
  sub    %rbp,%rsi
  nopl   (%rax)
L5:
  movslq %ebx,%rax
  mov    %ebx,%ecx
  sub    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rdx)
  mov    %eax,%ebx
  cmp    %rdx,%rsi
  jne    L5
L8:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *itos(int x) {
  int ndigits = count_digits(x, 0);
  char *s = malloc(ndigits + 1);
  int i;
  int n = x;
  s[ndigits] = 0;
  for (i = ndigits - 1; i >= 0; i--) {
    s[i] = n % 10 + 48;
    n /= 10;
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wc_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L144
L113:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L75
  jmp    L54
L50:
  addq   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L167
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L50
L167:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x1,%eax
  jmp    L13
L112:
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L144
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L112
  jmp    L144
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  je     L156
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L104
L156:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L144:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L104
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L113
L104:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    $0x1,%eax
  jmp    L13
L17:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int wc_match(char *wc, char *str) {
  while (*wc && *str) {
    if (*wc == '*') {
      while (*wc && *wc == '*')
        wc++;
      if (!*wc)
        return 1;
      while (*str && *str != *wc)
        str++;
    } else if (*wc == '?' || *wc == *str) {
      wc++;
      str++;
    } else {
      break;
    }
  }
  if (!*wc && !*str)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wc_match>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L101
  jmp    L28
L63:
  movzbl (%rdi),%eax
  cmp    $0x2a,%al
  jne    L112
L154:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x2a,%al
  je     L154
L112:
  test   %al,%al
  je     L72
  cmp    %al,%dl
  je     L92
L82:
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  cmp    %al,%dl
  je     L92
  test   %dl,%dl
  jne    L82
  jmp    L92
L61:
  add    $0x1,%rdi
  add    $0x1,%rsi
L92:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
L101:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L156
  cmp    $0x2a,%al
  je     L63
  cmp    %al,%dl
  je     L61
  cmp    $0x3f,%al
  je     L61
L156:
  mov    $0x0,%edx
  test   %al,%al
  jne    L158
L28:
  cmpb   $0x0,(%rsi)
  sete   %dl
  movzbl %dl,%edx
L158:
  mov    %edx,%eax
  ret
L72:
  mov    $0x1,%edx
  jmp    L158
```

assistant: ```c
int wc_match(char *wc, char *str) {
  while (*wc && *str) {
    if (*wc == '*') {
      while (*wc && *wc == '*')
        wc++;
      if (!*wc)
        return 1;
      while (*str && *str != *wc)
        str++;
    } else if (*wc == '?' || *wc == *str) {
      wc++;
      str++;
    } else {
      break;
    }
  }
  if (!*wc && !*str)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wc_match>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  test   %dl,%dl
  jne    L141
  jmp    L69
L103:
  cmp    %al,%dl
  je     L99
  cmp    $0x3f,%dl
  jne    L34
L99:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
L118:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L69
L141:
  test   %al,%al
  je     L34
  cmp    $0x2a,%dl
  jne    L103
  movzbl (%rdi),%edx
  cmp    $0x2a,%dl
  jne    L50
  nopl   (%rax)
L40:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  cmp    $0x2a,%dl
  je     L40
L50:
  test   %dl,%dl
  je     L131
  cmp    %al,%dl
  jne    L125
  jmp    L118
  nopw   0x0(%rax,%rax,1)
L98:
  cmp    %dl,%al
  je     L118
L125:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  jne    L98
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L141
L69:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L34:
  xor    %eax,%eax
  ret
L131:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wc_match(char *wc, char *str) {
  while (*wc && *str) {
    if (*wc == '*') {
      while (*wc && *wc == '*')
        wc++;
      if (!*wc)
        return 1;
      while (*str && *str != *wc)
        str++;
    } else if (*wc == '?' || *wc == *str) {
      wc++;
      str++;
    } else {
      break;
    }
  }
  if (!*wc && !*str)
    return 1;
  return 0;
}
```