ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ps_report>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  lea    -0x410(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  cmp    $0xffffffff,%eax
  jne    L2
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L2:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D2: ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2

tool: D4: system call to ps failed

assistant: ```c
void ps_report(void) {
  char buf[1024];
  sprintf(buf, "ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2", getpid());
  if (system(buf) == -1) {
    perror("system call to ps failed");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ps_report>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    %rsp,%rbx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  cmp    $0xffffffff,%eax
  je     L22
L5:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x410,%rsp
  pop    %rbx
  ret
L22:
  lea    D12(%rip),%rdi
  call   <perror@plt>
  jmp    L5
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D4: ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2

tool: D12: system call to ps failed

assistant: ```c
void ps_report(void) {
  char buf[1024];
  sprintf(buf, "ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2", getpid());
  if (system(buf) == -1) {
    perror("system call to ps failed");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ps_report>:
  endbr64
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  cmp    $0xffffffff,%eax
  je     L26
L23:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x410,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  lea    D15(%rip),%rdi
  call   <perror@plt>
  jmp    L23
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string

tool: D2: ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2

tool: D15: system call to ps failed

assistant: ```c
void ps_report(void) {
  char buf[1024];
  sprintf(buf, "ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2", getpid());
  if (system(buf) == -1) {
    perror("system call to ps failed");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ps_report>:
  endbr64
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  cmp    $0xffffffff,%eax
  je     L20
L7:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L7
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D16: ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2

tool: D7: system call to ps failed

assistant: ```c
void ps_report(void) {
  char buf[1024];
  sprintf(buf, "ps -o comm,majflt,minflt,rss,drs,pagein,sz,trs,vsz %d 1>&2", getpid());
  if (system(buf) == -1) {
    perror("system call to ps failed");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<owAcquire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <OpenCOM@plt>
  test   %rax,%rax
  jns    L36
  mov    $0x8,%edi
  call   <owRaiseError@plt>
  mov    $0x0,%eax
  jmp    L30
L36:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <DS2480Detect@plt>
  test   %eax,%eax
  jne    L11
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <CloseCOM@plt>
  mov    $0x5,%edi
  call   <owRaiseError@plt>
  mov    $0x0,%eax
  jmp    L30
L11:
  mov    $0x1,%eax
L30:
  leave
  ret
```

assistant: ```c
int owAcquire(int portnum, char *port_zstr) {
  if (OpenCOM(portnum, port_zstr) < 0) {
    owRaiseError(8);
    return 0;
  }
  if (!DS2480Detect(portnum)) {
    CloseCOM(portnum);
    owRaiseError(5);
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<owAcquire>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  call   <OpenCOM@plt>
  test   %rax,%rax
  js     L34
  mov    %ebx,%edi
  call   <DS2480Detect@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L16
  mov    $0x1,%ebp
L11:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  mov    $0x8,%edi
  call   <owRaiseError@plt>
  mov    $0x0,%ebp
  jmp    L11
L16:
  mov    %ebx,%edi
  call   <CloseCOM@plt>
  mov    $0x5,%edi
  call   <owRaiseError@plt>
  jmp    L11
```

assistant: ```c
int owAcquire(int portnum, char *port_zstr) {
  if (OpenCOM(portnum, port_zstr) < 0) {
    owRaiseError(8);
    return 0;
  }
  if (!DS2480Detect(portnum)) {
    CloseCOM(portnum);
    owRaiseError(5);
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<owAcquire>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <OpenCOM@plt>
  test   %rax,%rax
  js     L9
  mov    %ebp,%edi
  call   <DS2480Detect@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L1
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0x8,%edi
  xor    %r12d,%r12d
  call   <owRaiseError@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%edi
  call   <CloseCOM@plt>
  mov    $0x5,%edi
  call   <owRaiseError@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int owAcquire(int portnum, char *port_zstr) {
  if (OpenCOM(portnum, port_zstr) < 0) {
    owRaiseError(8);
    return 0;
  }
  if (!DS2480Detect(portnum)) {
    CloseCOM(portnum);
    owRaiseError(5);
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<owAcquire>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <OpenCOM@plt>
  test   %rax,%rax
  js     L5
  mov    %ebp,%edi
  call   <DS2480Detect@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L18
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x8,%edi
  xor    %r12d,%r12d
  call   <owRaiseError@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebp,%edi
  call   <CloseCOM@plt>
  mov    $0x5,%edi
  call   <owRaiseError@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int owAcquire(int portnum, char *port_zstr) {
  if (OpenCOM(portnum, port_zstr) < 0) {
    owRaiseError(8);
    return 0;
  }
  if (!DS2480Detect(portnum)) {
    CloseCOM(portnum);
    owRaiseError(5);
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_spx_mm_getr_ps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movss  -0x20(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x1c(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x18(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x14(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void _spx_mm_getr_ps(__m128 U, float *__Z, float *__Y, float *__X, float *__W) {
  union {
    float __a[4];
    __m128 __v;
  } __u;
  __u.__v = U;
  *__Z = __u.__a[0];
  *__Y = __u.__a[1];
  *__X = __u.__a[2];
  *__W = __u.__a[3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_spx_mm_getr_ps>:
  endbr64
  mov    %edi,(%rsi)
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  movl   $0x0,(%r8)
  ret
```

assistant: ```c
void _spx_mm_getr_ps(__m128 U, float *__Z, float *__Y, float *__X, float *__W) {
  union {
    float __a[4];
    __m128 __v;
  } __u;
  __u.__v = U;
  *__Z = __u.__a[0];
  *__Y = __u.__a[1];
  *__X = __u.__a[2];
  *__W = __u.__a[3];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_spx_mm_getr_ps>:
  endbr64
  mov    %edi,(%rsi)
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  movl   $0x0,(%r8)
  ret
```

assistant: ```c
void _spx_mm_getr_ps(__m128 U, float *__Z, float *__Y, float *__X, float *__W) {
  union {
    float __a[4];
    __m128 __v;
  } __u;
  __u.__v = U;
  *__Z = __u.__a[0];
  *__Y = __u.__a[1];
  *__X = __u.__a[2];
  *__W = __u.__a[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_spx_mm_getr_ps>:
  endbr64
  mov    %edi,(%rsi)
  movl   $0x0,(%rdx)
  movl   $0x0,(%rcx)
  movl   $0x0,(%r8)
  ret
```

assistant: ```c
void _spx_mm_getr_ps(__m128 U, float *__Z, float *__Y, float *__X, float *__W) {
  union {
    float __a[4];
    __m128 __v;
  } __u;
  __u.__v = U;
  *__Z = __u.__a[0];
  *__Y = __u.__a[1];
  *__X = __u.__a[2];
  *__W = __u.__a[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <check_TeX_parentheses@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    check_TeX_parentheses(argv[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L18:
  mov    (%rbx),%rdi
  call   <check_TeX_parentheses@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    check_TeX_parentheses(argv[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <check_TeX_parentheses@plt>
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    check_TeX_parentheses(argv[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L11
  push   %rbp
  lea    -0x2(%rdi),%eax
  push   %rbx
  lea    0x10(%rsi,%rax,8),%rbp
  lea    0x8(%rsi),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <check_TeX_parentheses@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i < argc; i++)
    check_TeX_parentheses(argv[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Celebrity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L55
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L82
  addl   $0x1,-0xc(%rbp)
  jmp    L17
L82:
  subl   $0x1,-0x8(%rbp)
  jmp    L17
L55:
  nop
  movl   $0x0,-0x4(%rbp)
  jmp    L83
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L31
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x1,%eax
  je     L59
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L89
L59:
  mov    $0xffffffff,%eax
  jmp    L11
L31:
  nop
L89:
  addl   $0x1,-0x4(%rbp)
L83:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0xc(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int Celebrity(int Person[][100], int n) {
  int start = 0;
  int end = n - 1;
  while (1) {
    if (start == end) {
      break;
    }
    if (Person[start][end] == 1) {
      start++;
    } else {
      end--;
    }
  }
  for (int i = 0; i < n; i++) {
    if (i == start) {
      continue;
    }
    if (Person[start][i] == 1 || Person[i][start] == 0) {
      return -1;
    }
  }
  return start;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Celebrity>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%r8d
  sub    $0x1,%esi
  je     L79
  mov    $0x0,%ecx
  jmp    L28
L80:
  test   %r8d,%r8d
  jle    L116
L44:
  movslq %ecx,%rax
  lea    0x0(,%rax,4),%rdi
  add    %rdi,%rax
  lea    (%rax,%rax,4),%rsi
  shl    $0x4,%rsi
  add    %rdx,%rsi
  add    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L83
L96:
  add    $0x1,%ecx
L90:
  cmp    %ecx,%esi
  je     L80
L28:
  movslq %ecx,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  add    %rdx,%rax
  movslq %esi,%rdi
  cmpl   $0x1,(%rax,%rdi,4)
  je     L96
  sub    $0x1,%esi
  jmp    L90
L79:
  mov    %esi,%ecx
  jmp    L44
L71:
  add    $0x1,%rax
  add    $0x190,%rdx
  cmp    %eax,%r8d
  jle    L116
L83:
  cmp    %eax,%ecx
  je     L71
  cmpl   $0x1,(%rsi,%rax,4)
  je     L110
  cmpl   $0x0,(%rdx)
  jne    L71
  mov    $0xffffffff,%ecx
  jmp    L116
L110:
  mov    $0xffffffff,%ecx
L116:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int Celebrity(int Person[][100], int n) {
  int start = 0;
  int end = n - 1;
  while (1) {
    if (start == end) {
      break;
    }
    if (Person[start][end] == 1) {
      start++;
    } else {
      end--;
    }
  }
  for (int i = 0; i < n; i++) {
    if (i == start) {
      continue;
    }
    if (Person[start][i] == 1 || Person[i][start] == 0) {
      return -1;
    }
  }
  return start;
}
```
user: What is the c source code of the assembly code below:

```asm
<Celebrity>:
  endbr64
  mov    %esi,%r8d
  sub    $0x1,%r8d
  je     L6
  xor    %edx,%edx
  jmp    L22
  nopl   (%rax)
L74:
  sub    $0x1,%r8d
  cmp    %r8d,%edx
  je     L49
L22:
  movslq %edx,%rax
  movslq %r8d,%rcx
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  add    %rdi,%rax
  cmpl   $0x1,(%rax,%rcx,4)
  jne    L74
  add    $0x1,%edx
  cmp    %r8d,%edx
  jne    L22
L49:
  test   %esi,%esi
  jle    L72
  movslq %r8d,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rcx
  shl    $0x4,%rcx
  add    %rdi,%rcx
L53:
  lea    (%rdi,%rax,4),%rdx
  xor    %eax,%eax
L94:
  cmp    %eax,%r8d
  je     L43
  cmpl   $0x1,(%rcx,%rax,4)
  je     L70
  mov    (%rdx),%edi
  test   %edi,%edi
  je     L70
L43:
  add    $0x1,%rax
  add    $0x190,%rdx
  cmp    %eax,%esi
  jg     L94
L72:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L70:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L53
```

assistant: ```c
int Celebrity(int Person[][100], int n) {
  int start = 0;
  int end = n - 1;
  while (1) {
    if (start == end) {
      break;
    }
    if (Person[start][end] == 1) {
      start++;
    } else {
      end--;
    }
  }
  for (int i = 0; i < n; i++) {
    if (i == start) {
      continue;
    }
    if (Person[start][i] == 1 || Person[i][start] == 0) {
      return -1;
    }
  }
  return start;
}
```
user: What is the c source code of the assembly code below:

```asm
<Celebrity>:
  endbr64
  mov    %esi,%edx
  mov    %rdi,%r9
  sub    $0x1,%edx
  je     L113
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  jmp    L43
  nopl   0x0(%rax)
L71:
  sub    $0x1,%edx
  cmp    %r8d,%edx
  je     L60
L43:
  movslq %edx,%rdi
L67:
  lea    (%rcx,%rcx,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  add    %r9,%rax
  cmpl   $0x1,(%rax,%rdi,4)
  jne    L71
  add    $0x1,%r8d
  cmp    %edx,%r8d
  je     L60
  movslq %r8d,%rcx
  jmp    L67
  xchg   %ax,%ax
L60:
  test   %esi,%esi
  jle    L24
  movslq %r8d,%rcx
  lea    (%rcx,%rcx,4),%rax
  lea    (%rax,%rax,4),%rdi
  shl    $0x4,%rdi
  add    %r9,%rdi
L98:
  lea    (%r9,%rcx,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L31:
  cmp    %eax,%r8d
  je     L5
  cmpl   $0x1,(%rdi,%rax,4)
  je     L26
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  je     L26
L5:
  add    $0x1,%rax
  add    $0x190,%rdx
  cmp    %eax,%esi
  jg     L31
L24:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L113:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  jmp    L98
```

assistant: ```c
int Celebrity(int Person[][100], int n) {
  int start = 0;
  int end = n - 1;
  while (1) {
    if (start == end) {
      break;
    }
    if (Person[start][end] == 1) {
      start++;
    } else {
      end--;
    }
  }
  for (int i = 0; i < n; i++) {
    if (i == start) {
      continue;
    }
    if (Person[start][i] == 1 || Person[i][start] == 0) {
      return -1;
    }
  }
  return start;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compareStringAndStringProperty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%ecx
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
  movzwl -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x6(%rbp)
  movzwl -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movzwl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzwl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  movzwl -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x6(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0x2c(%rbp),%eax
  cmp    $0x6,%eax
  ja     L32
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x4(%rbp),%eax
  shr    $0x1f,%eax
  jmp    L51
  cmpl   $0x0,-0x4(%rbp)
  setle  %al
  jmp    L51
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  jmp    L51
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  jmp    L51
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  jmp    L51
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  jmp    L51
L32:
  mov    $0x0,%eax
L51:
  leave
  ret
```

assistant: ```c
unsigned char compareStringAndStringProperty(char *leftFirst, unsigned short leftLength, char *rightFirst, unsigned short rightLength, unsigned char op) {
  char rightTemp = rightFirst[rightLength];
  rightFirst[rightLength] = '\0';
  char leftTemp = leftFirst[leftLength];
  leftFirst[leftLength] = '\0';
  int result = strcmp(leftFirst, rightFirst);
  rightFirst[rightLength] = rightTemp;
  leftFirst[leftLength] = leftTemp;
  switch (op) {
  case 0x01:
    return (result < 0);
  case 0x02:
    return (result <= 0);
  case 0x03:
    return (result > 0);
  case 0x04:
    return (result >= 0);
  case 0x05:
    return (result == 0);
  case 0x06:
    return (result != 0);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compareStringAndStringProperty>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  mov    %r8d,%r12d
  movzwl %cx,%ecx
  lea    (%rdx,%rcx,1),%rbp
  movzbl 0x0(%rbp),%r14d
  movb   $0x0,0x0(%rbp)
  movzwl %bx,%ebx
  add    %rdi,%rbx
  movzbl (%rbx),%r13d
  movb   $0x0,(%rbx)
  call   <strcmp@plt>
  mov    %r14b,0x0(%rbp)
  mov    %r13b,(%rbx)
  cmp    $0x6,%r12b
  ja     L22
  movzbl %r12b,%r12d
  lea    D6(%rip),%rcx
  movslq (%rcx,%r12,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  shr    $0x1f,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  test   %eax,%eax
  setle  %al
  jmp    L20
  test   %eax,%eax
  setg   %al
  jmp    L20
  not    %eax
  shr    $0x1f,%eax
  jmp    L20
  test   %eax,%eax
  sete   %al
  jmp    L20
  test   %eax,%eax
  setne  %al
  jmp    L20
L22:
  mov    $0x0,%eax
  jmp    L20
```

assistant: ```c
unsigned char compareStringAndStringProperty(char *leftFirst, unsigned short leftLength, char *rightFirst, unsigned short rightLength, unsigned char op) {
  char rightTemp = rightFirst[rightLength];
  rightFirst[rightLength] = '\0';
  char leftTemp = leftFirst[leftLength];
  leftFirst[leftLength] = '\0';
  int result = strcmp(leftFirst, rightFirst);
  rightFirst[rightLength] = rightTemp;
  leftFirst[leftLength] = leftTemp;
  switch (op) {
  case 0x01:
    return (result < 0);
  case 0x02:
    return (result <= 0);
  case 0x03:
    return (result > 0);
  case 0x04:
    return (result >= 0);
  case 0x05:
    return (result == 0);
  case 0x06:
    return (result != 0);
  }
  return 0;
}
```