ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<cvt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %esi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%ecx
  mov    -0x124(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <read_cvt@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    -0x118(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string

tool: D18: cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt

tool: D19: rm -f /tmp/gxrandr_cvt

assistant: ```c
char *cvt(int width, int height) {
  char cmd[256];
  sprintf(cmd, "cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt", width, height);
  system(cmd);
  char *result = (char *)malloc(sizeof(char) * 128);
  read_cvt(result);
  system("rm -f /tmp/gxrandr_cvt");
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cvt>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%edx
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <read_cvt@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbx,%rax
  add    $0x110,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string

tool: D4: cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt

tool: D18: rm -f /tmp/gxrandr_cvt

assistant: ```c
char *cvt(int width, int height) {
  char cmd[256];
  sprintf(cmd, "cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt", width, height);
  system(cmd);
  char *result = (char *)malloc(sizeof(char) * 128);
  read_cvt(result);
  system("rm -f /tmp/gxrandr_cvt");
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cvt>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %esi,%ecx
  lea    D1(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <system@plt>
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <read_cvt@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D1: cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt

tool: D3: rm -f /tmp/gxrandr_cvt

assistant: ```c
char *cvt(int width, int height) {
  char cmd[256];
  sprintf(cmd, "cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt", width, height);
  system(cmd);
  char *result = (char *)malloc(sizeof(char) * 128);
  read_cvt(result);
  system("rm -f /tmp/gxrandr_cvt");
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cvt>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %esi,%ecx
  lea    D17(%rip),%rsi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <system@plt>
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <read_cvt@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D18
type: string

tool: D17: cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt

tool: D18: rm -f /tmp/gxrandr_cvt

assistant: ```c
char *cvt(int width, int height) {
  char cmd[256];
  sprintf(cmd, "cvt %d %d | grep Modeline | awk -F' ' '{print $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13}' > /tmp/gxrandr_cvt", width, height);
  system(cmd);
  char *result = (char *)malloc(sizeof(char) * 128);
  read_cvt(result);
  system("rm -f /tmp/gxrandr_cvt");
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D32
data_type: string

tool: D4: Grade report for: Sultan Alqahtan!


tool: D31: Assignment 06	Test 01	Quiz 01	Worksheet 01!


tool: D27:  5/5            10/10   4/5     10/10!


tool: D7: Total points:	29/30


tool: D21: Average:	96.67


tool: D32: Letter Grade:	 A


assistant: ```c
int main() {
  printf("Grade report for: Sultan Alqahtan!\n");
  printf("Assignment 06\tTest 01\tQuiz 01\tWorksheet 01!\n");
  printf(" 5/5            10/10   4/5     10/10!\n");
  printf("Total points:\t29/30\n");
  printf("Average:\t96.67\n");
  printf("Letter Grade:\t A\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D54
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string

tool: D32: Grade report for: Sultan Alqahtan!


tool: D0: Assignment 06	Test 01	Quiz 01	Worksheet 01!


tool: D38:  5/5            10/10   4/5     10/10!


tool: D54: Total points:	29/30


tool: D19: Average:	96.67


tool: D35: Letter Grade:	 A


assistant: ```c
int main() {
  printf("Grade report for: Sultan Alqahtan!\n");
  printf("Assignment 06\tTest 01\tQuiz 01\tWorksheet 01!\n");
  printf(" 5/5            10/10   4/5     10/10!\n");
  printf("Total points:\t29/30\n");
  printf("Average:\t96.67\n");
  printf("Letter Grade:\t A\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D30
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D58
data_type: string
name: unpack_data
arguments: data_label: D59
data_type: string

tool: D1: Grade report for: Sultan Alqahtan!


tool: D30: Assignment 06	Test 01	Quiz 01	Worksheet 01!


tool: D16:  5/5            10/10   4/5     10/10!


tool: D29: Total points:	29/30


tool: D58: Average:	96.67


tool: D59: Letter Grade:	 A


assistant: ```c
int main() {
  printf("Grade report for: Sultan Alqahtan!\n");
  printf("Assignment 06\tTest 01\tQuiz 01\tWorksheet 01!\n");
  printf(" 5/5            10/10   4/5     10/10!\n");
  printf("Total points:\t29/30\n");
  printf("Average:\t96.67\n");
  printf("Letter Grade:\t A\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D39
type: string
name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D59
type: string
name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D9
type: string

tool: D39: Grade report for: Sultan Alqahtan!


tool: D11: Assignment 06	Test 01	Quiz 01	Worksheet 01!


tool: D59:  5/5            10/10   4/5     10/10!


tool: D16: Total points:	29/30


tool: D42: Average:	96.67


tool: D9: Letter Grade:	 A


assistant: ```c
int main() {
  printf("Grade report for: Sultan Alqahtan!\n");
  printf("Assignment 06\tTest 01\tQuiz 01\tWorksheet 01!\n");
  printf(" 5/5            10/10   4/5     10/10!\n");
  printf("Total points:\t29/30\n");
  printf("Average:\t96.67\n");
  printf("Letter Grade:\t A\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L10:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *string) {
  size_t result = 0;
  while (string[result])
    ++result;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x0,%eax
L18:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L18
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *string) {
  size_t result = 0;
  while (string[result])
    ++result;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L3
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
size_t strlen(const char *string) {
  size_t result = 0;
  while (string[result])
    ++result;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L12
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
size_t strlen(const char *string) {
  size_t result = 0;
  while (string[result])
    ++result;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<intToRoman>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3e8,-0x40(%rbp)
  movl   $0x384,-0x3c(%rbp)
  movl   $0x1f4,-0x38(%rbp)
  movl   $0x190,-0x34(%rbp)
  movl   $0x64,-0x30(%rbp)
  movl   $0x5a,-0x2c(%rbp)
  movl   $0x32,-0x28(%rbp)
  movl   $0x28,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movw   $0x4d,-0x70(%rbp)
  movb   $0x0,-0x6e(%rbp)
  movw   $0x4d43,-0x6d(%rbp)
  movb   $0x0,-0x6b(%rbp)
  movw   $0x44,-0x6a(%rbp)
  movb   $0x0,-0x68(%rbp)
  movw   $0x4443,-0x67(%rbp)
  movb   $0x0,-0x65(%rbp)
  movw   $0x43,-0x64(%rbp)
  movb   $0x0,-0x62(%rbp)
  movw   $0x4358,-0x61(%rbp)
  movb   $0x0,-0x5f(%rbp)
  movw   $0x4c,-0x5e(%rbp)
  movb   $0x0,-0x5c(%rbp)
  movw   $0x4c58,-0x5b(%rbp)
  movb   $0x0,-0x59(%rbp)
  movw   $0x58,-0x58(%rbp)
  movb   $0x0,-0x56(%rbp)
  movw   $0x5849,-0x55(%rbp)
  movb   $0x0,-0x53(%rbp)
  movw   $0x56,-0x52(%rbp)
  movb   $0x0,-0x50(%rbp)
  movw   $0x5649,-0x4f(%rbp)
  movb   $0x0,-0x4d(%rbp)
  movw   $0x49,-0x4c(%rbp)
  movb   $0x0,-0x4a(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x7c(%rbp)
  jmp    L38
L15:
  mov    -0x7c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  sub    %eax,-0x84(%rbp)
  lea    -0x70(%rbp),%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L31:
  mov    -0x7c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    %eax,-0x84(%rbp)
  jge    L15
  addl   $0x1,-0x7c(%rbp)
L38:
  cmpl   $0xc,-0x7c(%rbp)
  jle    L31
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
char *intToRoman(int num) {
  int nums[13] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
  char str[13][3] = {{"M"}, {"CM"}, {"D"}, {"CD"}, {"C"}, {"XC"}, {"L"}, {"XL"}, {"X"}, {"IX"}, {"V"}, {"IV"}, {"I"}};
  char *ret = (char *)malloc(sizeof(char) * 16);
  memset(ret, 0, 16);
  for (int i = 0; i < 13; i++) {
    while (num >= nums[i]) {
      num -= nums[i];
      strcat(ret, str[i]);
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intToRoman>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x3e8,0x40(%rsp)
  movl   $0x384,0x44(%rsp)
  movl   $0x1f4,0x48(%rsp)
  movl   $0x190,0x4c(%rsp)
  movl   $0x64,0x50(%rsp)
  movl   $0x5a,0x54(%rsp)
  movl   $0x32,0x58(%rsp)
  movl   $0x28,0x5c(%rsp)
  movl   $0xa,0x60(%rsp)
  movl   $0x9,0x64(%rsp)
  movl   $0x5,0x68(%rsp)
  movl   $0x4,0x6c(%rsp)
  movl   $0x1,0x70(%rsp)
  movw   $0x4d,0x10(%rsp)
  movb   $0x0,0x12(%rsp)
  movw   $0x4d43,0x13(%rsp)
  movb   $0x0,0x15(%rsp)
  movw   $0x44,0x16(%rsp)
  movb   $0x0,0x18(%rsp)
  movw   $0x4443,0x19(%rsp)
  movb   $0x0,0x1b(%rsp)
  movw   $0x43,0x1c(%rsp)
  movb   $0x0,0x1e(%rsp)
  movw   $0x4358,0x1f(%rsp)
  movb   $0x0,0x21(%rsp)
  movw   $0x4c,0x22(%rsp)
  movb   $0x0,0x24(%rsp)
  movw   $0x4c58,0x25(%rsp)
  movb   $0x0,0x27(%rsp)
  movw   $0x58,0x28(%rsp)
  movb   $0x0,0x2a(%rsp)
  movw   $0x5849,0x2b(%rsp)
  movb   $0x0,0x2d(%rsp)
  movw   $0x56,0x2e(%rsp)
  movb   $0x0,0x30(%rsp)
  movw   $0x5649,0x31(%rsp)
  movb   $0x0,0x33(%rsp)
  movw   $0x49,0x34(%rsp)
  movb   $0x0,0x36(%rsp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    0x40(%rsp),%r15
  lea    0x10(%rsp),%r14
  lea    0x37(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L4
L45:
  sub    %ebp,%ebx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  cmp    %ebp,%ebx
  jge    L45
L46:
  add    $0x4,%r15
  add    $0x3,%r14
  cmp    0x8(%rsp),%r14
  je     L40
L4:
  mov    (%r15),%ebp
  mov    %r14,%r12
  cmp    %ebx,%ebp
  jle    L45
  jmp    L46
L40:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %r13,%rax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *intToRoman(int num) {
  int nums[13] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
  char str[13][3] = {{"M"}, {"CM"}, {"D"}, {"CD"}, {"C"}, {"XC"}, {"L"}, {"XL"}, {"X"}, {"IX"}, {"V"}, {"IV"}, {"I"}};
  char *ret = (char *)malloc(sizeof(char) * 16);
  memset(ret, 0, 16);
  for (int i = 0; i < 13; i++) {
    while (num >= nums[i]) {
      num -= nums[i];
      strcat(ret, str[i]);
    }
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<intToRoman>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x3e8,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  sub    $0x78,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x1f400000384,%rax
  movb   $0x0,0x26(%rsp)
  lea    0x34(%rsp),%r14
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D3(%rip),%xmm0
  lea    0x27(%rsp),%r15
  movl   $0x564900,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x34(%rsp)
  movabs $0x6400000190,%rax
  mov    %rax,0x3c(%rsp)
  movabs $0x320000005a,%rax
  mov    %rax,0x44(%rsp)
  movabs $0xa00000028,%rax
  mov    %rax,0x4c(%rsp)
  movabs $0x500000009,%rax
  mov    %rax,0x54(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x5c(%rsp)
  mov    $0x49,%eax
  mov    %ax,0x24(%rsp)
  call   <malloc@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  jmp    L43
  nopl   0x0(%rax)
L45:
  mov    %r12,%rsi
  mov    %r13,%rdi
  sub    %ebp,%ebx
  call   <strcat@plt>
L43:
  cmp    %ebx,%ebp
  jle    L45
  add    $0x3,%r12
  cmp    %r15,%r12
  je     L30
  mov    (%r14),%ebp
  add    $0x4,%r14
  jmp    L43
L30:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x78,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: byte[16]
name: extract_symbolic_data
arguments: label: D3
type: byte[16]

tool: {"D10": [0x4d,0x00,0x00,0x43,0x4d,0x00,0x44,0x00,0x00,0x43,0x44,0x00,0x43,0x00,0x00,0x58]}

tool: {"D3": [0x43,0x00,0x4c,0x00,0x00,0x58,0x4c,0x00,0x58,0x00,0x00,0x49,0x58,0x00,0x56,0x00]}

assistant: ```c
char *intToRoman(int num) {
  int nums[13] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
  char str[13][3] = {{"M"}, {"CM"}, {"D"}, {"CD"}, {"C"}, {"XC"}, {"L"}, {"XL"}, {"X"}, {"IX"}, {"V"}, {"IV"}, {"I"}};
  char *ret = (char *)malloc(sizeof(char) * 16);
  memset(ret, 0, 16);
  for (int i = 0; i < 13; i++) {
    while (num >= nums[i]) {
      num -= nums[i];
      strcat(ret, str[i]);
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intToRoman>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  sub    $0x78,%rsp
  movdqa D33(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x49,%eax
  movb   $0x0,0x26(%rsp)
  mov    %rsp,%r12
  movaps %xmm0,0x30(%rsp)
  lea    0x30(%rsp),%r14
  lea    0x27(%rsp),%r15
  movdqa D32(%rip),%xmm0
  movl   $0x1,0x60(%rsp)
  movaps %xmm0,0x40(%rsp)
  movdqa D35(%rip),%xmm0
  movl   $0x564900,0x20(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D48(%rip),%xmm0
  mov    %ax,0x24(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D27(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <malloc@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  nopl   0x0(%rax)
L8:
  mov    (%r14),%ebp
  cmp    %ebx,%ebp
  jg     L9
  nopw   0x0(%rax,%rax,1)
L25:
  sub    %ebp,%ebx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  cmp    %ebx,%ebp
  jle    L25
L9:
  add    $0x3,%r12
  add    $0x4,%r14
  cmp    %r12,%r15
  jne    L8
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x78,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
type: byte[16]
name: extract_symbolic_data
arguments: tag: D32
type: byte[16]
name: extract_symbolic_data
arguments: tag: D35
type: byte[16]
name: extract_symbolic_data
arguments: tag: D48
type: byte[16]
name: extract_symbolic_data
arguments: tag: D27
type: byte[16]

tool: {"D33": [0xe8,0x03,0x00,0x00,0x84,0x03,0x00,0x00,0xf4,0x01,0x00,0x00,0x90,0x01,0x00,0x00]}

tool: {"D32": [0x64,0x00,0x00,0x00,0x5a,0x00,0x00,0x00,0x32,0x00,0x00,0x00,0x28,0x00,0x00,0x00]}

tool: {"D35": [0x0a,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D48": [0x4d,0x00,0x00,0x43,0x4d,0x00,0x44,0x00,0x00,0x43,0x44,0x00,0x43,0x00,0x00,0x58]}

tool: {"D27": [0x43,0x00,0x4c,0x00,0x00,0x58,0x4c,0x00,0x58,0x00,0x00,0x49,0x58,0x00,0x56,0x00]}

assistant: ```c
char *intToRoman(int num) {
  int nums[13] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
  char str[13][3] = {{"M"}, {"CM"}, {"D"}, {"CD"}, {"C"}, {"XC"}, {"L"}, {"XL"}, {"X"}, {"IX"}, {"V"}, {"IV"}, {"I"}};
  char *ret = (char *)malloc(sizeof(char) * 16);
  memset(ret, 0, 16);
  for (int i = 0; i < 13; i++) {
    while (num >= nums[i]) {
      num -= nums[i];
      strcat(ret, str[i]);
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void g_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vfprintf(stdout, format, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<g_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void g_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vfprintf(stdout, format, ap);
  va_end(ap);
}
```