ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_stat_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L44
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    $0x0,%r13d
  lea    D7(%rip),%r14
  lea    0x10(%rsp),%rbp
  lea    D42(%rip),%r15
  jmp    L67
L9:
  movslq %r13d,%rdi
  add    0x8(%rsp),%rdi
  mov    %rbx,%rdx
  mov    %r15,%rsi
  call   <sprintf@plt>
  add    %eax,%r13d
L67:
  mov    %r12,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L95
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L67
  mov    %r14,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L67
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L9
L95:
  mov    %r12,%rdi
  call   <fclose@plt>
  lea    D30(%rip),%rdi
  call   <system@plt>
  test   %r13d,%r13d
  jle    L38
  movslq %r13d,%r13
  mov    0x8(%rsp),%rax
  movb   $0x0,-0x1(%rax,%r13,1)
L44:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  movslq %r13d,%r13
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax,%r13,1)
  jmp    L44
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D24
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D42
type_guessed: string
name: read_data
arguments: data_tag: D30
type_guessed: string

tool: D24: r

tool: D13: /tmp/rndc_tsar.txt

tool: D7: ,

tool: D42: %s,

tool: D30: rm /tmp/rndc_tsar.txt

assistant: ```c
void parse_stat_file(char buf[]) {
  FILE *fp = fopen("/tmp/rndc_tsar.txt", "r");
  if (!fp)
    return;
  rewind(fp);
  int pos = 0;
  char line[128];
  while (fgets(line, 128, fp)) {
    char *s = strtok(line, ",");
    if (!s)
      continue;
    s = strtok(NULL, ",");
    if (!s)
      continue;
    if (strlen(s) > 0)
      s[strlen(s) - 1] = '\0';
    pos += sprintf(buf + pos, "%s,", s);
  }
  fclose(fp);
  system("rm /tmp/rndc_tsar.txt");
  if (pos > 0)
    buf[pos - 1] = '\0';
  else
    buf[pos] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_stat_file>:
  endbr64
  push   %r15
  lea    D0(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,0x8(%rsp)
  lea    D47(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L40
  mov    %rax,%rdi
  mov    %rax,%rbp
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  call   <rewind@plt>
  lea    D8(%rip),%r13
  lea    D23(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L87
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L79
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L79
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L74
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r14,%rax,1)
L74:
  movslq %r12d,%rdi
  mov    %r14,%rdx
  add    0x8(%rsp),%rdi
  mov    %r15,%rsi
  call   <sprintf@plt>
  add    %eax,%r12d
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L87:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D33(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rcx
  movslq %r12d,%rax
  test   %r12d,%r12d
  jle    L26
  movb   $0x0,-0x1(%rcx,%rax,1)
L40:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movb   $0x0,(%rcx,%rax,1)
  jmp    L40
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D47
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string
name: retrieve_data
arguments: tag: D33
datatype: string

tool: D0: r

tool: D47: /tmp/rndc_tsar.txt

tool: D8: ,

tool: D23: %s,

tool: D33: rm /tmp/rndc_tsar.txt

assistant: ```c
void parse_stat_file(char buf[]) {
  FILE *fp = fopen("/tmp/rndc_tsar.txt", "r");
  if (!fp)
    return;
  rewind(fp);
  int pos = 0;
  char line[128];
  while (fgets(line, 128, fp)) {
    char *s = strtok(line, ",");
    if (!s)
      continue;
    s = strtok(NULL, ",");
    if (!s)
      continue;
    if (strlen(s) > 0)
      s[strlen(s) - 1] = '\0';
    pos += sprintf(buf + pos, "%s,", s);
  }
  fclose(fp);
  system("rm /tmp/rndc_tsar.txt");
  if (pos > 0)
    buf[pos - 1] = '\0';
  else
    buf[pos] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_stat_file>:
  endbr64
  push   %r15
  lea    D5(%rip),%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,0x8(%rsp)
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rdi
  mov    %rax,%rbp
  lea    0x10(%rsp),%rbx
  xor    %r12d,%r12d
  call   <rewind@plt>
  lea    D16(%rip),%r13
  lea    D6(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L81:
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L81
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L81
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L86
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r14,%rax,1)
L86:
  movslq %r12d,%rdi
  mov    %r14,%rdx
  add    0x8(%rsp),%rdi
  mov    %r15,%rsi
  call   <sprintf@plt>
  add    %eax,%r12d
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D21(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rcx
  movslq %r12d,%rax
  test   %r12d,%r12d
  jle    L79
  movb   $0x0,-0x1(%rcx,%rax,1)
L19:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  movb   $0x0,(%rcx,%rax,1)
  jmp    L19
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D45
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D21
type: string

tool: D5: r

tool: D45: /tmp/rndc_tsar.txt

tool: D16: ,

tool: D6: %s,

tool: D21: rm /tmp/rndc_tsar.txt

assistant: ```c
void parse_stat_file(char buf[]) {
  FILE *fp = fopen("/tmp/rndc_tsar.txt", "r");
  if (!fp)
    return;
  rewind(fp);
  int pos = 0;
  char line[128];
  while (fgets(line, 128, fp)) {
    char *s = strtok(line, ",");
    if (!s)
      continue;
    s = strtok(NULL, ",");
    if (!s)
      continue;
    if (strlen(s) > 0)
      s[strlen(s) - 1] = '\0';
    pos += sprintf(buf + pos, "%s,", s);
  }
  fclose(fp);
  system("rm /tmp/rndc_tsar.txt");
  if (pos > 0)
    buf[pos - 1] = '\0';
  else
    buf[pos] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <dlopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dlsym@plt>
  jmp    L5
L2:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
void *init(const char *lib, const char *func) {
  void *handle = dlopen(lib, RTLD_LAZY | RTLD_LOCAL);
  return (handle == NULL) ? NULL : dlsym(handle, func);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  or     (%rax),%esi
  call   <dlopen@plt>
  test   %rax,%rax
  je     L0
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <dlsym@plt>
L0:
  pop    %rbx
  ret
```

assistant: ```c
void *init(const char *lib, const char *func) {
  void *handle = dlopen(lib, RTLD_LAZY | RTLD_LOCAL);
  return (handle == NULL) ? NULL : dlsym(handle, func);
}
```
user: What is the c source code of the assembly code below:

```asm
<init>:
  endbr64
  mov    D10(%rip),%rax
  push   %rbp
  mov    %rsi,%rbp
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  or     (%rax),%esi
  call   <dlopen@plt>
  test   %rax,%rax
  je     L2
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <dlsym@plt>
L2:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *init(const char *lib, const char *func) {
  void *handle = dlopen(lib, RTLD_LAZY | RTLD_LOCAL);
  return (handle == NULL) ? NULL : dlsym(handle, func);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init>:
  endbr64
  mov    D18(%rip),%rax
  push   %rbp
  mov    %rsi,%rbp
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  or     (%rax),%esi
  call   <dlopen@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <dlsym@plt>
L9:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *init(const char *lib, const char *func) {
  void *handle = dlopen(lib, RTLD_LAZY | RTLD_LOCAL);
  return (handle == NULL) ? NULL : dlsym(handle, func);
}
```
user: Translate the below assembly code into C programming language:

```asm
<startTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  shl    $0x9,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1fffff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x15,%eax
  add    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int startTimer(int timeout) {
  struct timespec tp;
  clock_gettime(CLOCK_MONOTONIC, &tp);
  return ((int)tp.tv_sec + timeout) * 512 + (int)tp.tv_nsec / 2097152;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<startTimer>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  add    0x8(%rsp),%ebx
  shl    $0x9,%ebx
  mov    (%rsp),%rdx
  lea    0x1fffff(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x15,%eax
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int startTimer(int timeout) {
  struct timespec tp;
  clock_gettime(CLOCK_MONOTONIC, &tp);
  return ((int)tp.tv_sec + timeout) * 512 + (int)tp.tv_nsec / 2097152;
}
```
user: Translate the below assembly code into C programming language:

```asm
<startTimer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rsp),%rdx
  add    0x8(%rsp),%ebx
  shl    $0x9,%ebx
  lea    0x1fffff(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x15,%eax
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int startTimer(int timeout) {
  struct timespec tp;
  clock_gettime(CLOCK_MONOTONIC, &tp);
  return ((int)tp.tv_sec + timeout) * 512 + (int)tp.tv_nsec / 2097152;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<startTimer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rsp),%rdx
  add    0x8(%rsp),%ebx
  shl    $0x9,%ebx
  lea    0x1fffff(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x15,%eax
  add    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int startTimer(int timeout) {
  struct timespec tp;
  clock_gettime(CLOCK_MONOTONIC, &tp);
  return ((int)tp.tv_sec + timeout) * 512 + (int)tp.tv_nsec / 2097152;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x30(%rbp)
  je     L39
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
L39:
  mov    $0xffffffff,%eax
  jmp    L62
L46:
  mov    -0x34(%rbp),%edx
  lea    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L34
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x30(%rbp)
  je     L34
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  cmpq   $0xffff,-0x10(%rbp)
  jbe    L69
L34:
  mov    $0xffffffff,%eax
  jmp    L62
L69:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L62:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
int get_u16(__u16 *val, const char *arg, int base) {
  unsigned long res;
  char *ptr;
  if (!arg || !*arg)
    return -1;
  res = strtoul(arg, &ptr, base);
  if (!ptr || ptr == arg || *ptr || res > 0xFFFF)
    return -1;
  *val = res;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_u16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L74
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmpb   $0x0,(%rsi)
  je     L107
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L34
  test   %rdx,%rdx
  je     L34
  cmpb   $0x0,(%rdx)
  jne    L39
  cmp    $0xffff,%rax
  ja     L39
  mov    %rax,0x0(%rbp)
  mov    $0x0,%eax
L99:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L74:
  mov    $0xffffffff,%eax
  jmp    L99
L107:
  mov    $0xffffffff,%eax
  jmp    L99
L34:
  mov    $0xffffffff,%eax
  jmp    L99
L39:
  mov    $0xffffffff,%eax
  jmp    L99
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_u16(__u16 *val, const char *arg, int base) {
  unsigned long res;
  char *ptr;
  if (!arg || !*arg)
    return -1;
  res = strtoul(arg, &ptr, base);
  if (!ptr || ptr == arg || *ptr || res > 0xFFFF)
    return -1;
  *val = res;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_u16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L6
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbx
  je     L6
  mov    %rdi,%rbp
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L6
  cmp    %rbx,%rdx
  je     L6
  cmpb   $0x0,(%rdx)
  jne    L6
  cmp    $0xffff,%rax
  ja     L6
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  mov    $0xffffffff,%eax
  jmp    L27
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_u16(__u16 *val, const char *arg, int base) {
  unsigned long res;
  char *ptr;
  if (!arg || !*arg)
    return -1;
  res = strtoul(arg, &ptr, base);
  if (!ptr || ptr == arg || *ptr || res > 0xFFFF)
    return -1;
  *val = res;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_u16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L4
  cmpb   $0x0,(%rsi)
  mov    %rsi,%rbx
  je     L4
  mov    %rdi,%rbp
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L4
  cmp    %rbx,%rdx
  je     L4
  cmpb   $0x0,(%rdx)
  jne    L4
  cmp    $0xffff,%rax
  ja     L4
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  mov    $0xffffffff,%eax
  jmp    L38
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_u16(__u16 *val, const char *arg, int base) {
  unsigned long res;
  char *ptr;
  if (!arg || !*arg)
    return -1;
  res = strtoul(arg, &ptr, base);
  if (!ptr || ptr == arg || *ptr || res > 0xFFFF)
    return -1;
  *val = res;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ptys_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xfffffffb,%eax
  jmp    L4
L11:
  mov    -0x4(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int ptys_open(int fdm, const char *pts_name, bool acquire) {
  int fds;
  fds = open(pts_name, O_RDWR);
  if (fds < 0) {
    close(fdm);
    return -5;
  }
  return fds;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptys_open>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L11
L6:
  pop    %rbx
  ret
L11:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xfffffffb,%eax
  jmp    L6
```

assistant: ```c
int ptys_open(int fdm, const char *pts_name, bool acquire) {
  int fds;
  fds = open(pts_name, O_RDWR);
  if (fds < 0) {
    close(fdm);
    return -5;
  }
  return fds;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ptys_open>:
  endbr64
  mov    D1(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L8
  pop    %rbp
  ret
L8:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffb,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ptys_open(int fdm, const char *pts_name, bool acquire) {
  int fds;
  fds = open(pts_name, O_RDWR);
  if (fds < 0) {
    close(fdm);
    return -5;
  }
  return fds;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ptys_open>:
  endbr64
  mov    D0(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L4
  pop    %rbp
  ret
L4:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xfffffffb,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ptys_open(int fdm, const char *pts_name, bool acquire) {
  int fds;
  fds = open(pts_name, O_RDWR);
  if (fds < 0) {
    close(fdm);
    return -5;
  }
  return fds;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: This is a test program with 8 commands and help command
		com1[parameter]	--give a instruction and print the parameter
		com2			--give a instruction
		com3			--give a instruction
		- h OR - help		--give the help


assistant: ```c
int help(char **para) {
  printf("This is a test program with 8 commands and help command\n		com1[parameter]\t--give a instruction and print the parameter\n		com2\t\t\t--give a instruction\n		com3\t\t\t--give a instruction\n		- h OR - help\t\t--give "
         "the help\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: This is a test program with 8 commands and help command
		com1[parameter]	--give a instruction and print the parameter
		com2			--give a instruction
		com3			--give a instruction
		- h OR - help		--give the help


assistant: ```c
int help(char **para) {
  printf("This is a test program with 8 commands and help command\n		com1[parameter]\t--give a instruction and print the parameter\n		com2\t\t\t--give a instruction\n		com3\t\t\t--give a instruction\n		- h OR - help\t\t--give "
         "the help\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: This is a test program with 8 commands and help command
		com1[parameter]	--give a instruction and print the parameter
		com2			--give a instruction
		com3			--give a instruction
		- h OR - help		--give the help


assistant: ```c
int help(char **para) {
  printf("This is a test program with 8 commands and help command\n		com1[parameter]\t--give a instruction and print the parameter\n		com2\t\t\t--give a instruction\n		com3\t\t\t--give a instruction\n		- h OR - help\t\t--give "
         "the help\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: This is a test program with 8 commands and help command
		com1[parameter]	--give a instruction and print the parameter
		com2			--give a instruction
		com3			--give a instruction
		- h OR - help		--give the help


assistant: ```c
int help(char **para) {
  printf("This is a test program with 8 commands and help command\n		com1[parameter]\t--give a instruction and print the parameter\n		com2\t\t\t--give a instruction\n		com3\t\t\t--give a instruction\n		- h OR - help\t\t--give "
         "the help\n");
  return 0;
}
```