user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  movl   $0x0,-0x3c(%rbp)
  mov    -0x38(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x34(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x30(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x2c(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mpz_init_set_ui@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  movl   $0x1,-0x40(%rbp)
  jmp    L20
L27:
  mov    -0x30(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mul_ui@plt>
  mov    -0x2c(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mul_ui@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x38(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x34(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_add@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mpz_get_str@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jle    L12
  addl   $0x1,-0x3c(%rbp)
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x34(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  addl   $0x1,-0x40(%rbp)
L20:
  cmpl   $0x3e7,-0x40(%rbp)
  jle    L27
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, m = 0;
  char *ns, *ds;
  mpz_t na, nb, nc;
  mpz_t da, db, dc;
  mpz_init_set_ui(na, 1);
  mpz_init_set_ui(da, 1);
  mpz_init_set_ui(nb, 3);
  mpz_init_set_ui(db, 2);
  mpz_init(nc);
  mpz_init(dc);
  for (i = 1; i < 1000; i++) {
    mpz_mul_ui(nc, nb, 2);
    mpz_mul_ui(dc, db, 2);
    mpz_add(nc, na, nc);
    mpz_add(dc, da, dc);
    ns = mpz_get_str(NULL, 10, nc);
    ds = mpz_get_str(NULL, 10, dc);
    if (strlen(ns) > strlen(ds))
      m++;
    free(ns);
    free(ds);
    mpz_set(na, nb);
    mpz_set(da, db);
    mpz_set(nb, nc);
    mpz_set(db, dc);
  }
  printf("%d\n", m);
  return 0;
}
```