ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_TransInv>:
  endbr64
  push   %r12
  push   %rbp
  lea    D49(%rip),%rbp
  push   %rbx
  sub    $0x110,%rsp
  movsd  D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    D27(%rip),%rax
  lea    0x80(%rsp),%rbx
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  movsd  %xmm0,(%rsp)
  lea    0x100(%rsp),%r12
  mov    %rax,0x30(%rsp)
  mov    D0(%rip),%rax
  movsd  %xmm0,0x48(%rsp)
  movsd  %xmm0,0x78(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  mov    %rax,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  call   <TransInv@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
L7:
  movsd  0x18(%rbx),%xmm3
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x20,%rbx
  movsd  -0x10(%rbx),%xmm2
  movsd  -0x18(%rbx),%xmm1
  mov    $0x4,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D49
type_guessed: string
name: unpack_data
arguments: tag: D36
type_guessed: byte[8]
name: unpack_data
arguments: tag: D27
type_guessed: byte[8]
name: unpack_data
arguments: tag: D0
type_guessed: byte[8]
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D49: %lf %lf %lf %lf


tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D10: InvT:

assistant: ```c
void test_TransInv() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double InvT[4][4];
  TransInv(T, InvT);
  printf("InvT:\n");
  int i;
  for (i = 0; i < 4; i++) {
    printf("%lf %lf %lf %lf\n", InvT[i][0], InvT[i][1], InvT[i][2], InvT[i][3]);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_TransInv>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x110,%rsp
  movq   D34(%rip),%xmm1
  movq   D57(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movapd D42(%rip),%xmm2
  mov    %rsp,%rdi
  lea    0x80(%rsp),%rbx
  movaps %xmm1,0x30(%rsp)
  movapd D38(%rip),%xmm1
  mov    %rbx,%rsi
  lea    0x100(%rsp),%r12
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm1,0x40(%rsp)
  movaps %xmm2,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm1,0x70(%rsp)
  call   <TransInv@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
L13:
  movsd  0x18(%rbx),%xmm3
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x20,%rbx
  movsd  -0x10(%rbx),%xmm2
  movsd  -0x18(%rbx),%xmm1
  mov    $0x4,%eax
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L13
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D34
datatype: byte[8]
name: read_data
arguments: tag: D57
datatype: byte[8]
name: read_data
arguments: tag: D42
datatype: byte[16]
name: read_data
arguments: tag: D38
datatype: byte[16]
name: read_data
arguments: tag: D7
datatype: string

tool: D16: %lf %lf %lf %lf


tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D7: InvT:

assistant: ```c
void test_TransInv() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double InvT[4][4];
  TransInv(T, InvT);
  printf("InvT:\n");
  int i;
  for (i = 0; i < 4; i++) {
    printf("%lf %lf %lf %lf\n", InvT[i][0], InvT[i][1], InvT[i][2], InvT[i][3]);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shr    $0x3,%rax
  or     $0xffffffb5,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  or     $0xffffffdd,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 28054104UL) | (unsigned char)197;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  or     $0xfffffffd,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 28054104UL) | (unsigned char)197;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  or     $0xfffffffd,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 28054104UL) | (unsigned char)197;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  shr    $0x3,%rax
  or     $0xfffffffd,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[local1] >>= (state[local1] & (unsigned char)7) | 1UL;
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 28054104UL) | (unsigned char)197;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PinTypeTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <PinModeSet@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x60,%esi
  mov    %rax,%rdi
  call   <PinConfigSet@plt>
  nop
  leave
  ret
```

assistant: ```c
void PinTypeTimer(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PinTypeTimer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <PinModeSet@plt>
  mov    $0x0,%edx
  mov    $0x60,%esi
  mov    %rbx,%rdi
  call   <PinConfigSet@plt>
  pop    %rbx
  ret
```

assistant: ```c
void PinTypeTimer(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PinTypeTimer>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <PinModeSet@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <PinConfigSet@plt>
```

assistant: ```c
void PinTypeTimer(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PinTypeTimer>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <PinModeSet@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <PinConfigSet@plt>
```

assistant: ```c
void PinTypeTimer(unsigned long ulPin, unsigned long ulPinMode) {
  PinModeSet(ulPin, ulPinMode);
  PinConfigSet(ulPin, 0x00000020 | 0x00000040, 0x00000000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vtimes_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  je     L22
  mov    -0x4c(%rbp),%eax
  lea    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <__getrusage@plt>
  test   %rax,%rax
  jns    L39
  mov    $0xffffffff,%eax
  jmp    L15
L39:
  mov    -0x10(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  mov    -0x14(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,0x20(%rax)
  mov    -0x30(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0x18(%rax)
  mov    -0x34(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0x14(%rax)
  mov    -0x38(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0x10(%rax)
  mov    -0x3c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0xc(%rax)
  mov    -0x40(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,0x8(%rax)
L22:
  mov    $0x0,%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int vtimes_one(struct vtimes *vt, enum __rusage_who who) {
  if (vt != NULL) {
    struct rusage usage;
    if (__getrusage(who, &usage) < 0)
      return -1;
    vt->vm_utime = ((usage.ru_utime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_utime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_stime = ((usage.ru_stime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_stime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_idsrss = usage.ru_idrss + usage.ru_isrss;
    vt->vm_majflt = usage.ru_majflt;
    vt->vm_minflt = usage.ru_minflt;
    vt->vm_nswap = usage.ru_nswap;
    vt->vm_inblk = usage.ru_inblock;
    vt->vm_oublk = usage.ru_oublock;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vtimes_one>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L27
  mov    %esi,%edi
  mov    %rsp,%rsi
  call   <__getrusage@plt>
  test   %rax,%rax
  js     L17
  mov    D5(%rip),%rsi
  mov    (%rsi),%edx
  mov    %edx,%ecx
  imul   0x34(%rsp),%ecx
  movslq %ecx,%rax
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   0x30(%rsp),%edx
  add    %edx,%eax
  mov    %eax,(%rbx)
  mov    (%rsi),%edx
  mov    %edx,%ecx
  imul   0x2c(%rsp),%ecx
  movslq %ecx,%rax
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   0x28(%rsp),%edx
  add    %edx,%eax
  mov    %eax,0x4(%rbx)
  mov    0x18(%rsp),%rax
  add    0x20(%rsp),%rax
  mov    %rax,0x20(%rbx)
  mov    0x10(%rsp),%eax
  mov    %eax,0x18(%rbx)
  mov    0xc(%rsp),%eax
  mov    %eax,0x14(%rbx)
  mov    0x8(%rsp),%eax
  mov    %eax,0x10(%rbx)
  mov    0x4(%rsp),%eax
  mov    %eax,0xc(%rbx)
  mov    (%rsp),%eax
  mov    %eax,0x8(%rbx)
  mov    $0x0,%eax
L27:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x40,%rsp
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L27
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtimes_one(struct vtimes *vt, enum __rusage_who who) {
  if (vt != NULL) {
    struct rusage usage;
    if (__getrusage(who, &usage) < 0)
      return -1;
    vt->vm_utime = ((usage.ru_utime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_utime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_stime = ((usage.ru_stime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_stime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_idsrss = usage.ru_idrss + usage.ru_isrss;
    vt->vm_majflt = usage.ru_majflt;
    vt->vm_minflt = usage.ru_minflt;
    vt->vm_nswap = usage.ru_nswap;
    vt->vm_inblk = usage.ru_inblock;
    vt->vm_oublk = usage.ru_oublock;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vtimes_one>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L38
  mov    %esi,%edi
  mov    %rsp,%rsi
  call   <__getrusage@plt>
  test   %rax,%rax
  js     L17
  mov    D2(%rip),%rax
  mov    0x34(%rsp),%ecx
  mov    (%rax),%edx
  imul   %edx,%ecx
  movslq %ecx,%rax
  sar    $0x1f,%ecx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %ecx,%eax
  mov    0x30(%rsp),%ecx
  imul   %edx,%ecx
  add    %ecx,%eax
  mov    0x2c(%rsp),%ecx
  mov    %eax,(%rbx)
  imul   %edx,%ecx
  imul   0x28(%rsp),%edx
  movslq %ecx,%rax
  sar    $0x1f,%ecx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %ecx,%eax
  add    %edx,%eax
  mov    %eax,0x4(%rbx)
  mov    0x18(%rsp),%rax
  add    0x20(%rsp),%rax
  mov    %rax,0x20(%rbx)
  mov    (%rsp),%rax
  mov    %rax,0x8(%rbx)
  mov    0x8(%rsp),%rax
  mov    %rax,0x10(%rbx)
  mov    0x10(%rsp),%eax
  mov    %eax,0x18(%rbx)
L38:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x48,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L17:
  mov    $0xffffffff,%r12d
  jmp    L38
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtimes_one(struct vtimes *vt, enum __rusage_who who) {
  if (vt != NULL) {
    struct rusage usage;
    if (__getrusage(who, &usage) < 0)
      return -1;
    vt->vm_utime = ((usage.ru_utime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_utime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_stime = ((usage.ru_stime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_stime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_idsrss = usage.ru_idrss + usage.ru_isrss;
    vt->vm_majflt = usage.ru_majflt;
    vt->vm_minflt = usage.ru_minflt;
    vt->vm_nswap = usage.ru_nswap;
    vt->vm_inblk = usage.ru_inblock;
    vt->vm_oublk = usage.ru_oublock;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vtimes_one>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L22
  mov    %esi,%edi
  mov    %rsp,%rsi
  call   <__getrusage@plt>
  test   %rax,%rax
  js     L7
  mov    D6(%rip),%rax
  mov    0x34(%rsp),%ecx
  movd   (%rsp),%xmm1
  movd   0x4(%rsp),%xmm2
  mov    (%rax),%edx
  punpckldq %xmm2,%xmm1
  imul   %edx,%ecx
  movslq %ecx,%rax
  sar    $0x1f,%ecx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %ecx,%eax
  mov    0x30(%rsp),%ecx
  imul   %edx,%ecx
  add    %ecx,%eax
  mov    0x2c(%rsp),%ecx
  movd   %eax,%xmm0
  imul   %edx,%ecx
  imul   0x28(%rsp),%edx
  movslq %ecx,%rax
  sar    $0x1f,%ecx
  imul   $0x431bde83,%rax,%rax
  sar    $0x32,%rax
  sub    %ecx,%eax
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  add    0x20(%rsp),%rdx
  mov    %rdx,0x20(%rbx)
  mov    0x10(%rsp),%edx
  movd   %eax,%xmm3
  punpckldq %xmm3,%xmm0
  mov    %edx,0x18(%rbx)
  mov    0x8(%rsp),%rdx
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rbx)
  mov    %rdx,0x10(%rbx)
L22:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x48,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L7:
  mov    $0xffffffff,%r12d
  jmp    L22
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtimes_one(struct vtimes *vt, enum __rusage_who who) {
  if (vt != NULL) {
    struct rusage usage;
    if (__getrusage(who, &usage) < 0)
      return -1;
    vt->vm_utime = ((usage.ru_utime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_utime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_stime = ((usage.ru_stime.tv_sec * VTIMES_UNITS_PER_SECOND) + (usage.ru_stime.tv_usec * VTIMES_UNITS_PER_SECOND / 1000000));
    vt->vm_idsrss = usage.ru_idrss + usage.ru_isrss;
    vt->vm_majflt = usage.ru_majflt;
    vt->vm_minflt = usage.ru_minflt;
    vt->vm_nswap = usage.ru_nswap;
    vt->vm_inblk = usage.ru_inblock;
    vt->vm_oublk = usage.ru_oublock;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L23:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fibonacci@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L1
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
L1:
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x3d0900,-0xc(%rbp)
  jle    L23
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main() {
  int n;
  int i, total = 0;
  while (n <= 4000000) {
    n = fibonacci(i);
    if (n % 2 == 0) {
      total += n;
    }
    i++;
  }
  printf("%d\n", total);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
L9:
  mov    %ebp,%edi
  call   <fibonacci@plt>
  lea    (%rbx,%rax,1),%edx
  test   $0x1,%al
  cmove  %edx,%ebx
  add    $0x1,%ebp
  cmp    $0x3d0900,%eax
  jle    L9
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main() {
  int n;
  int i, total = 0;
  while (n <= 4000000) {
    n = fibonacci(i);
    if (n % 2 == 0) {
      total += n;
    }
    i++;
  }
  printf("%d\n", total);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  mov    %ebx,%edi
  call   <fibonacci@plt>
  test   $0x1,%al
  lea    0x0(%rbp,%rax,1),%edx
  cmove  %edx,%ebp
  add    $0x1,%ebx
  cmp    $0x3d0900,%eax
  jle    L8
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main() {
  int n;
  int i, total = 0;
  while (n <= 4000000) {
    n = fibonacci(i);
    if (n % 2 == 0) {
      total += n;
    }
    i++;
  }
  printf("%d\n", total);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  mov    %ebx,%edi
  call   <fibonacci@plt>
  test   $0x1,%al
  lea    0x0(%rbp,%rax,1),%edx
  cmove  %edx,%ebp
  add    $0x1,%ebx
  cmp    $0x3d0900,%eax
  jle    L4
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int n;
  int i, total = 0;
  while (n <= 4000000) {
    n = fibonacci(i);
    if (n % 2 == 0) {
      total += n;
    }
    i++;
  }
  printf("%d\n", total);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L19
L11:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L19:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
int str_to_str(char *buf, const char *str, unsigned long count) {
  unsigned long size;
  size = strlen(str);
  if (count < size)
    count = size;
  else
    memset(buf, ' ', count - size);
  strcpy(buf + (count - size), str);
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  cmp    %rbx,%rax
  jbe    L4
  mov    %rax,%rbx
L9:
  mov    %rbx,%rax
  sub    %r12,%rax
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  mov    $0x20,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L9
```

assistant: ```c
int str_to_str(char *buf, const char *str, unsigned long count) {
  unsigned long size;
  size = strlen(str);
  if (count < size)
    count = size;
  else
    memset(buf, ' ', count - size);
  strcpy(buf + (count - size), str);
  return count;
}
```