ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L59
L34:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L61
L60:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L60
L42:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L64
  addq   $0x1,-0x20(%rbp)
L59:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  jmp    L25
L64:
  nop
L25:
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *find(str1, str2)
char *str1;
char *str2;
{
  char *s1, *s2;
  for (; *str2 != '\0'; str2++) {
    for (s1 = str1, s2 = str2; *s1 != '\0' && *s1 == *s2; s1++, s2++)
      ;
    if (*s1 == '\0')
      break;
  }
  return (str2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L0
  movzbl (%rdi),%ecx
  jmp    L11
L53:
  test   %dl,%dl
  je     L0
  add    $0x1,%rsi
  cmpb   $0x0,(%rsi)
  je     L0
L11:
  test   %cl,%cl
  je     L0
  mov    %ecx,%edx
  mov    $0x0,%eax
L56:
  cmp    %dl,(%rsi,%rax,1)
  jne    L53
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L56
L0:
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *find(str1, str2)
char *str1;
char *str2;
{
  char *s1, *s2;
  for (; *str2 != '\0'; str2++) {
    for (s1 = str1, s2 = str2; *s1 != '\0' && *s1 == *s2; s1++, s2++)
      ;
    if (*s1 == '\0')
      break;
  }
  return (str2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find>:
  endbr64
  cmpb   $0x0,(%rsi)
  mov    %rsi,%r8
  je     L12
  movzbl (%rdi),%ecx
  nop
L11:
  test   %cl,%cl
  je     L12
  mov    %ecx,%edx
  xor    %eax,%eax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L12
L22:
  cmp    %dl,(%r8,%rax,1)
  je     L25
  add    $0x1,%r8
  cmpb   $0x0,(%r8)
  jne    L11
L12:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *find(str1, str2)
char *str1;
char *str2;
{
  char *s1, *s2;
  for (; *str2 != '\0'; str2++) {
    for (s1 = str1, s2 = str2; *s1 != '\0' && *s1 == *s2; s1++, s2++)
      ;
    if (*s1 == '\0')
      break;
  }
  return (str2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find>:
  endbr64
  cmpb   $0x0,(%rsi)
  mov    %rsi,%r8
  je     L45
  movzbl (%rdi),%ecx
  nop
L33:
  test   %cl,%cl
  je     L45
  mov    %ecx,%edx
  xor    %eax,%eax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L45
L8:
  cmp    %dl,(%r8,%rax,1)
  je     L14
  add    $0x1,%r8
  cmpb   $0x0,(%r8)
  jne    L33
L45:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *find(str1, str2)
char *str1;
char *str2;
{
  char *s1, *s2;
  for (; *str2 != '\0'; str2++) {
    for (s1 = str1, s2 = str2; *s1 != '\0' && *s1 == *s2; s1++, s2++)
      ;
    if (*s1 == '\0')
      break;
  }
  return (str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<h264sps_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <h264nal_init@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <h264nal_set_ref@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <h264nal_set_type@plt>
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movl   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void h264sps_init(uint8_t *p_h264sps) {
  h264nal_init(p_h264sps);
  h264nal_set_ref(p_h264sps, 1);
  h264nal_set_type(p_h264sps, 7);
  p_h264sps[5] = 0x0;
}
```
user: What is the c source code of the assembly code below:

```asm
<h264sps_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <h264nal_init@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <h264nal_set_ref@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <h264nal_set_type@plt>
  movl   $0x0,0x14(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void h264sps_init(uint8_t *p_h264sps) {
  h264nal_init(p_h264sps);
  h264nal_set_ref(p_h264sps, 1);
  h264nal_set_type(p_h264sps, 7);
  p_h264sps[5] = 0x0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h264sps_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <h264nal_init@plt>
  mov    %rbx,%rdi
  mov    $0x1,%esi
  call   <h264nal_set_ref@plt>
  mov    %rbx,%rdi
  mov    $0x7,%esi
  call   <h264nal_set_type@plt>
  movl   $0x0,0x14(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void h264sps_init(uint8_t *p_h264sps) {
  h264nal_init(p_h264sps);
  h264nal_set_ref(p_h264sps, 1);
  h264nal_set_type(p_h264sps, 7);
  p_h264sps[5] = 0x0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<h264sps_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <h264nal_init@plt>
  mov    %rbx,%rdi
  mov    $0x1,%esi
  call   <h264nal_set_ref@plt>
  mov    %rbx,%rdi
  mov    $0x7,%esi
  call   <h264nal_set_type@plt>
  movl   $0x0,0x14(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void h264sps_init(uint8_t *p_h264sps) {
  h264nal_init(p_h264sps);
  h264nal_set_ref(p_h264sps, 1);
  h264nal_set_type(p_h264sps, 7);
  p_h264sps[5] = 0x0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_conversion_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x30,-0x5(%rbp)
  jmp    L52
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L52:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L51
  cmpb   $0x39,-0x5(%rbp)
  jle    L1
L51:
  movb   $0x41,-0x5(%rbp)
  jmp    L7
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L74
  cmpb   $0x5a,-0x5(%rbp)
  jle    L21
L74:
  movb   $0x61,-0x5(%rbp)
  jmp    L69
L78:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L69:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L64
  cmpb   $0x7a,-0x5(%rbp)
  jle    L78
L64:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_conversion_array(char *array, int base) {
  char current;
  int i;
  i = 0;
  current = '0';
  while (i < base && current <= '9') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'A';
  while (i < base && current <= 'Z') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'a';
  while (i < base && current <= 'z') {
    array[i] = current;
    current++;
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_conversion_array>:
  endbr64
  test   %esi,%esi
  jle    L45
  mov    $0x1,%edx
  mov    $0x30,%ecx
L19:
  mov    %cl,-0x1(%rdi,%rdx,1)
  add    $0x1,%ecx
  mov    %edx,%eax
  cmp    %edx,%esi
  setg   %r9b
  cmp    $0x39,%cl
  setle  %r8b
  add    $0x1,%rdx
  test   %r8b,%r9b
  jne    L19
  cmp    %eax,%esi
  jle    L45
  add    $0x1,%eax
  cltq
  mov    $0x41,%ecx
L28:
  mov    %cl,-0x1(%rdi,%rax,1)
  add    $0x1,%ecx
  mov    %eax,%edx
  cmp    %eax,%esi
  setg   %r9b
  cmp    $0x5a,%cl
  setle  %r8b
  add    $0x1,%rax
  test   %r8b,%r9b
  jne    L28
  cmp    %edx,%esi
  jle    L45
  lea    0x1(%rdx),%eax
  cltq
  mov    $0x61,%edx
L10:
  mov    %dl,-0x1(%rdi,%rax,1)
  add    $0x1,%edx
  cmp    %eax,%esi
  setg   %r8b
  cmp    $0x7a,%dl
  setle  %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L10
L45:
  ret
```

assistant: ```c
void set_conversion_array(char *array, int base) {
  char current;
  int i;
  i = 0;
  current = '0';
  while (i < base && current <= '9') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'A';
  while (i < base && current <= 'Z') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'a';
  while (i < base && current <= 'z') {
    array[i] = current;
    current++;
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_conversion_array>:
  endbr64
  test   %esi,%esi
  jle    L22
  mov    $0x1,%edx
  mov    $0x30,%ecx
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %cl,-0x1(%rdi,%rdx,1)
  add    $0x1,%ecx
  cmp    %edx,%esi
  mov    %edx,%eax
  setg   %r9b
  cmp    $0x39,%cl
  setle  %r8b
  add    $0x1,%rdx
  test   %r8b,%r9b
  jne    L56
  cmp    %eax,%esi
  jle    L22
  add    $0x1,%eax
  mov    $0x41,%ecx
  cltq
  nopl   (%rax)
L4:
  mov    %cl,-0x1(%rdi,%rax,1)
  add    $0x1,%ecx
  cmp    %eax,%esi
  mov    %eax,%edx
  setg   %r9b
  cmp    $0x5a,%cl
  setle  %r8b
  add    $0x1,%rax
  test   %r8b,%r9b
  jne    L4
  cmp    %edx,%esi
  jle    L22
  lea    0x1(%rdx),%eax
  mov    $0x61,%edx
  cltq
  nopl   (%rax)
L43:
  mov    %dl,-0x1(%rdi,%rax,1)
  add    $0x1,%edx
  cmp    %eax,%esi
  setg   %r8b
  cmp    $0x7a,%dl
  setle  %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L43
L22:
  ret
```

assistant: ```c
void set_conversion_array(char *array, int base) {
  char current;
  int i;
  i = 0;
  current = '0';
  while (i < base && current <= '9') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'A';
  while (i < base && current <= 'Z') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'a';
  while (i < base && current <= 'z') {
    array[i] = current;
    current++;
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_conversion_array>:
  endbr64
  test   %esi,%esi
  jle    L54
  mov    $0x1,%edx
  mov    $0x30,%ecx
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %cl,-0x1(%rdi,%rdx,1)
  add    $0x1,%ecx
  cmp    %edx,%esi
  mov    %edx,%eax
  setg   %r9b
  cmp    $0x39,%cl
  setle  %r8b
  add    $0x1,%rdx
  test   %r8b,%r9b
  jne    L53
  cmp    %eax,%esi
  jle    L54
  add    $0x1,%eax
  mov    $0x41,%ecx
  cltq
  nopl   (%rax)
L18:
  mov    %cl,-0x1(%rdi,%rax,1)
  add    $0x1,%ecx
  cmp    %eax,%esi
  mov    %eax,%edx
  setg   %r9b
  cmp    $0x5a,%cl
  setle  %r8b
  add    $0x1,%rax
  test   %r8b,%r9b
  jne    L18
  cmp    %edx,%esi
  jle    L54
  lea    0x1(%rdx),%eax
  mov    $0x61,%edx
  cltq
  nopl   (%rax)
L48:
  mov    %dl,-0x1(%rdi,%rax,1)
  add    $0x1,%edx
  cmp    %eax,%esi
  setg   %r8b
  cmp    $0x7a,%dl
  setle  %cl
  add    $0x1,%rax
  test   %cl,%r8b
  jne    L48
L54:
  ret
```

assistant: ```c
void set_conversion_array(char *array, int base) {
  char current;
  int i;
  i = 0;
  current = '0';
  while (i < base && current <= '9') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'A';
  while (i < base && current <= 'Z') {
    array[i] = current;
    current++;
    i++;
  }
  current = 'a';
  while (i < base && current <= 'z') {
    array[i] = current;
    current++;
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L30
L5:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L42
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L42:
  cmpq   $0x0,-0x28(%rbp)
  je     L44
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L44
L12:
  addq   $0x1,-0x8(%rbp)
L44:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
extern size_t strlcpy(char *tgt, const char *src, size_t bufsize) {
  size_t length;
  for (length = 1; (length < bufsize) && *src; length++)
    *tgt++ = *src++;
  if (bufsize)
    *tgt = '\0';
  while (*src++)
    length++;
  return length - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlcpy>:
  endbr64
  cmp    $0x1,%rdx
  jbe    L11
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    $0x1,%edx
L48:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L62
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L48
  mov    %rcx,%rdi
L62:
  movb   $0x0,(%rdi)
L15:
  cmpb   $0x0,(%rsi)
  je     L80
  mov    %rdx,%rax
  sub    %rdx,%rsi
L56:
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L56
L76:
  sub    $0x1,%rax
  ret
L11:
  test   %rdx,%rdx
  jne    L71
  mov    $0x1,%edx
  jmp    L15
L71:
  mov    $0x1,%edx
  jmp    L62
L80:
  mov    %rdx,%rax
  jmp    L76
```

assistant: ```c
extern size_t strlcpy(char *tgt, const char *src, size_t bufsize) {
  size_t length;
  for (length = 1; (length < bufsize) && *src; length++)
    *tgt++ = *src++;
  if (bufsize)
    *tgt = '\0';
  while (*src++)
    length++;
  return length - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlcpy>:
  endbr64
  cmp    $0x1,%rdx
  jbe    L58
  lea    -0x1(%rdi,%rdx,1),%r8
  mov    $0x1,%eax
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  cmp    %r8,%rdi
  je     L46
L32:
  movzbl (%rsi),%edx
  mov    %rsi,%rcx
  lea    0x1(%rsi),%rsi
  test   %dl,%dl
  jne    L25
L43:
  mov    %rcx,%rsi
  movb   $0x0,(%rdi)
  cmpb   $0x0,(%rsi)
  je     L48
L4:
  sub    %rax,%rsi
  nopl   0x0(%rax)
L68:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L68
  mov    %r8,%rax
  ret
L58:
  test   %rdx,%rdx
  jne    L50
  cmpb   $0x0,(%rsi)
  mov    $0x1,%eax
  jne    L4
L48:
  lea    -0x1(%rax),%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rsi,%rcx
  jmp    L43
L50:
  mov    %rsi,%rcx
  mov    $0x1,%eax
  jmp    L43
```

assistant: ```c
extern size_t strlcpy(char *tgt, const char *src, size_t bufsize) {
  size_t length;
  for (length = 1; (length < bufsize) && *src; length++)
    *tgt++ = *src++;
  if (bufsize)
    *tgt = '\0';
  while (*src++)
    length++;
  return length - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlcpy>:
  endbr64
  cmp    $0x1,%rdx
  jbe    L81
  lea    -0x1(%rdi,%rdx,1),%r8
  mov    $0x1,%eax
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L48:
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %dl,-0x1(%rdi)
  cmp    %r8,%rdi
  je     L92
L13:
  movzbl (%rsi),%edx
  mov    %rsi,%rcx
  lea    0x1(%rsi),%rsi
  test   %dl,%dl
  jne    L48
L29:
  mov    %rcx,%rsi
  movb   $0x0,(%rdi)
  cmpb   $0x0,(%rsi)
  je     L54
L75:
  sub    %rax,%rsi
  nopl   0x0(%rax)
L7:
  mov    %rax,%r8
  add    $0x1,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L7
  mov    %r8,%rax
  ret
L81:
  test   %rdx,%rdx
  jne    L90
  cmpb   $0x0,(%rsi)
  mov    $0x1,%eax
  jne    L75
L54:
  lea    -0x1(%rax),%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  mov    %rsi,%rcx
  jmp    L29
L90:
  mov    %rsi,%rcx
  mov    $0x1,%eax
  jmp    L29
```

assistant: ```c
extern size_t strlcpy(char *tgt, const char *src, size_t bufsize) {
  size_t length;
  for (length = 1; (length < bufsize) && *src; length++)
    *tgt++ = *src++;
  if (bufsize)
    *tgt = '\0';
  while (*src++)
    length++;
  return length - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_9x9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L37
L19:
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L35:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L37:
  cmpl   $0x9,-0x8(%rbp)
  jle    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: %d	

assistant: ```c
int print_9x9(void) {
  int i, j;
  for (i = 1; i <= 9; i++) {
    for (j = 1; j <= i; j++)
      printf("%d\t", i * j);
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_9x9>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r12d
  lea    D4(%rip),%r14
  jmp    L39
L47:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    %r12d,%ebx
  jle    L47
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  je     L40
L39:
  mov    %r12d,%r13d
  mov    %r12d,%ebp
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jg     L47
  jmp    L22
L40:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: %d	

assistant: ```c
int print_9x9(void) {
  int i, j;
  for (i = 1; i <= 9; i++) {
    for (j = 1; j <= i; j++)
      printf("%d\t", i * j);
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_9x9>:
  endbr64
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  nop
L5:
  mov    %r12d,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  add    %r12d,%ebp
  cmp    %r13d,%ebx
  jne    L4
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%rbx),%r13d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: %d	

assistant: ```c
int print_9x9(void) {
  int i, j;
  for (i = 1; i <= 9; i++) {
    for (j = 1; j <= i; j++)
      printf("%d\t", i * j);
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_9x9>:
  endbr64
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  nop
L19:
  mov    %r12d,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  add    %r12d,%ebp
  cmp    %r13d,%ebx
  jne    L15
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%rbx),%r13d
  call   <putchar@plt>
  cmp    $0xa,%r12d
  jne    L19
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: %d	

assistant: ```c
int print_9x9(void) {
  int i, j;
  for (i = 1; i <= 9; i++) {
    for (j = 1; j <= i; j++)
      printf("%d\t", i * j);
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  jmp    L44
L55:
  lea    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x2c(%rbp)
L44:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L55
  movl   $0x0,-0x2c(%rbp)
  jmp    L58
L20:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L74
L70:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  subl   $0x1,-0x28(%rbp)
L74:
  cmpl   $0x0,-0x28(%rbp)
  jle    L43
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L70
L43:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x24(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x2c(%rbp)
L58:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L20
  movl   $0x0,-0x2c(%rbp)
  jmp    L73
L21:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L73:
  cmpl   $0x2,-0x2c(%rbp)
  jle    L21
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D24
type: string
name: read_data
arguments: tag: D17
type: string

tool: D24: %d

tool: D17: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, j, tmp, a[4];
  for (i = 0; i < 4; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 4; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--) {
      a[j] = a[j - 1];
    }
    a[j] = tmp;
  }
  for (i = 0; i < 4 - 1; i++) {
    printf("%d ", a[i]);
  }
  printf("%d", a[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r13
  mov    %rbx,%rbp
  lea    D2(%rip),%r12
L31:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L31
  mov    (%rsp),%edi
  mov    $0x0,%r8d
  mov    $0x0,%esi
  jmp    L56
L16:
  mov    %r8d,%esi
L4:
  add    $0x4,%rbx
L56:
  movslq %esi,%rsi
  mov    %edi,(%rsp,%rsi,4)
  add    $0x1,%r8d
  cmp    $0x4,%r8d
  je     L17
  mov    0x4(%rbx),%edi
  test   %r8d,%r8d
  jle    L16
  mov    %rbx,%rdx
  mov    %r8d,%eax
L39:
  mov    %eax,%esi
  sub    $0x1,%eax
  mov    (%rdx),%ecx
  cmp    %edi,%ecx
  jle    L4
  mov    %ecx,0x4(%rdx)
  sub    $0x4,%rdx
  test   %eax,%eax
  jne    L39
  mov    %eax,%esi
  jmp    L4
L17:
  mov    (%rsp),%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D2: %d

tool: D7: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int i, j, tmp, a[4];
  for (i = 0; i < 4; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < 4; i++) {
    tmp = a[i];
    for (j = i; j > 0 && a[j - 1] > tmp; j--) {
      a[j] = a[j - 1];
    }
    a[j] = tmp;
  }
  for (i = 0; i < 4 - 1; i++) {
    printf("%d ", a[i]);
  }
  printf("%d", a[i]);
  return 0;
}
```