ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<lstEgrep>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L40
  movq   $0x0,0x10(%rsp)
  cmpq   $0x0,(%rdi)
  je     L116
  mov    $0x1,%ebx
  lea    0xc(%rsp),%rbp
  jmp    L112
L40:
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L61
L97:
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
L44:
  mov    $0x0,%eax
L61:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L85:
  mov    %rbp,%rdi
  call   <regfree@plt>
L13:
  add    $0x1,%rbx
  cmpq   $0x0,-0x8(%r12,%rbx,8)
  je     L116
L112:
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  jne    L97
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <regexec@plt>
  mov    D37(%rip),%rdx
  cmp    (%rdx),%rax
  je     L85
  mov    -0x8(%r12,%rbx,8),%rsi
  lea    0x10(%rsp),%rdi
  call   <lstPush@plt>
  cmp    $0xffffffff,%eax
  je     L107
  mov    %rbp,%rdi
  call   <regfree@plt>
  jmp    L13
L107:
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
  lea    0xc(%rsp),%rdi
  call   <regfree@plt>
  jmp    L44
L116:
  mov    0x10(%rsp),%rax
  jmp    L61
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **lstEgrep(char *const *lst, const char *regexp) {
  if (!lst || !regexp) {
    errno = EINVAL;
    return NULL;
  }
  char **new_lst = NULL;
  size_t i = 0;
  while (lst[i]) {
    regex_t reg;
    regex_t *preg = &reg;
    memset(preg, 0, sizeof(regex_t));
    if (0 != regcomp(preg, regexp, REG_EXTENDED)) {
      lstFree(new_lst);
      return NULL;
    }
    if (REG_NOMATCH == regexec(preg, lst[i], 0, NULL, 0)) {
      regfree(preg);
      i++;
      continue;
    }
    if (-1 == lstPush(&new_lst, lst[i])) {
      lstFree(new_lst);
      regfree(preg);
      return NULL;
    }
    regfree(preg);
    i++;
  }
  return new_lst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lstEgrep>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L64
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L64
  movq   $0x0,0x10(%rsp)
  mov    (%rdi),%rax
  mov    %rdi,%r12
  test   %rax,%rax
  je     L29
  mov    $0x1,%ebx
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r15
  mov    D34(%rip),%r14
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L2:
  mov    -0x8(%r12,%rbx,8),%rsi
  xor    %edx,%edx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %rbp,%rdi
  call   <regexec@plt>
  mov    D17(%rip),%rdx
  cmp    (%rdx),%rax
  je     L66
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %r15,%rdi
  call   <lstPush@plt>
  cmp    $0xffffffff,%eax
  je     L36
L66:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <regfree@plt>
  cmpq   $0x0,-0x8(%r12,%rbx,8)
  je     L9
L76:
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  je     L2
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
  xor    %eax,%eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L115
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    0x10(%rsp),%rax
  jmp    L29
  nop
L36:
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
  mov    %rbp,%rdi
  call   <regfree@plt>
  xor    %eax,%eax
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L64:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L29
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **lstEgrep(char *const *lst, const char *regexp) {
  if (!lst || !regexp) {
    errno = EINVAL;
    return NULL;
  }
  char **new_lst = NULL;
  size_t i = 0;
  while (lst[i]) {
    regex_t reg;
    regex_t *preg = &reg;
    memset(preg, 0, sizeof(regex_t));
    if (0 != regcomp(preg, regexp, REG_EXTENDED)) {
      lstFree(new_lst);
      return NULL;
    }
    if (REG_NOMATCH == regexec(preg, lst[i], 0, NULL, 0)) {
      regfree(preg);
      i++;
      continue;
    }
    if (-1 == lstPush(&new_lst, lst[i])) {
      lstFree(new_lst);
      regfree(preg);
      return NULL;
    }
    regfree(preg);
    i++;
  }
  return new_lst;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lstEgrep>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L75
  mov    %rsi,%r13
  test   %rsi,%rsi
  je     L75
  movq   $0x0,0x10(%rsp)
  mov    (%rdi),%rax
  mov    %rdi,%r12
  test   %rax,%rax
  je     L96
  mov    $0x1,%ebx
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r15
  mov    D10(%rip),%r14
  jmp    L112
  nopw   0x0(%rax,%rax,1)
L74:
  mov    -0x8(%r12,%rbx,8),%rsi
  xor    %edx,%edx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %rbp,%rdi
  call   <regexec@plt>
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rax
  je     L70
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %r15,%rdi
  call   <lstPush@plt>
  cmp    $0xffffffff,%eax
  je     L69
L70:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <regfree@plt>
  cmpq   $0x0,-0x8(%r12,%rbx,8)
  je     L32
L112:
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  je     L74
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
  xor    %eax,%eax
L96:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    0x10(%rsp),%rax
  jmp    L96
  nop
L69:
  mov    0x10(%rsp),%rdi
  call   <lstFree@plt>
  mov    %rbp,%rdi
  call   <regfree@plt>
  xor    %eax,%eax
  jmp    L96
  cs nopw 0x0(%rax,%rax,1)
L75:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  jmp    L96
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **lstEgrep(char *const *lst, const char *regexp) {
  if (!lst || !regexp) {
    errno = EINVAL;
    return NULL;
  }
  char **new_lst = NULL;
  size_t i = 0;
  while (lst[i]) {
    regex_t reg;
    regex_t *preg = &reg;
    memset(preg, 0, sizeof(regex_t));
    if (0 != regcomp(preg, regexp, REG_EXTENDED)) {
      lstFree(new_lst);
      return NULL;
    }
    if (REG_NOMATCH == regexec(preg, lst[i], 0, NULL, 0)) {
      regfree(preg);
      i++;
      continue;
    }
    if (-1 == lstPush(&new_lst, lst[i])) {
      lstFree(new_lst);
      regfree(preg);
      return NULL;
    }
    regfree(preg);
    i++;
  }
  return new_lst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nonlinear_color_interpolation_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L14
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
L14:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  movsd  D19(%rip),%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movsd  D19(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L0:
  cmpl   $0x2,-0x8(%rbp)
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_infered: f64

tool: D19: 1

assistant: ```c
void nonlinear_color_interpolation_2(float *x, float *c0, float *c1, float *c) {
  int i;
  float factor;
  for (i = 0; i < 3; i++) {
    if (x[i] < 0.0)
      x[i] = 0.0;
    factor = x[i] / (1.0 + x[i]);
    c[i] = c0[i] * (1.0 - factor) + c1[i] * factor;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<nonlinear_color_interpolation_2>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm5,%xmm5
  movsd  D1(%rip),%xmm2
  jmp    L29
L32:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi,%rax,1),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsi,%rax,1),%xmm1
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movapd %xmm2,%xmm3
  subsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm1
  mulss  (%rdx,%rax,1),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  je     L36
L29:
  comiss (%rdi,%rax,1),%xmm5
  jbe    L32
  movl   $0x0,(%rdi,%rax,1)
  jmp    L32
L36:
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
void nonlinear_color_interpolation_2(float *x, float *c0, float *c1, float *c) {
  int i;
  float factor;
  for (i = 0; i < 3; i++) {
    if (x[i] < 0.0)
      x[i] = 0.0;
    factor = x[i] / (1.0 + x[i]);
    c[i] = c0[i] * (1.0 - factor) + c1[i] * factor;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nonlinear_color_interpolation_2>:
  endbr64
  movsd  D1(%rip),%xmm3
  xor    %eax,%eax
  pxor   %xmm4,%xmm4
L9:
  movss  (%rdi,%rax,1),%xmm0
  comiss %xmm0,%xmm4
  ja     L19
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm2
  addsd  %xmm3,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm1
  subsd  %xmm1,%xmm2
L26:
  mulss  (%rdx,%rax,1),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsi,%rax,1),%xmm1
  mulsd  %xmm2,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L9
  ret
  xchg   %ax,%ax
L19:
  movl   $0x0,(%rdi,%rax,1)
  movapd %xmm3,%xmm2
  movaps %xmm4,%xmm0
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
void nonlinear_color_interpolation_2(float *x, float *c0, float *c1, float *c) {
  int i;
  float factor;
  for (i = 0; i < 3; i++) {
    if (x[i] < 0.0)
      x[i] = 0.0;
    factor = x[i] / (1.0 + x[i]);
    c[i] = c0[i] * (1.0 - factor) + c1[i] * factor;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<nonlinear_color_interpolation_2>:
  endbr64
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  movss  (%rax),%xmm0
  comiss %xmm0,%xmm1
  ja     L29
  movsd  D15(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm3
  addsd  %xmm2,%xmm3
  movapd %xmm2,%xmm4
  divsd  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm3
  subsd  %xmm3,%xmm4
L11:
  mulss  (%rdi),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd (%rsi),%xmm3
  mulsd  %xmm4,%xmm3
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm3,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rax),%xmm0
  comiss %xmm0,%xmm1
  ja     L7
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm3
  movapd %xmm2,%xmm4
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm3
  subsd  %xmm3,%xmm4
L40:
  mulss  0x4(%rdi),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd 0x4(%rsi),%xmm3
  mulsd  %xmm4,%xmm3
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm3
  cvtsd2ss %xmm3,%xmm3
  movss  %xmm3,0x4(%rdx)
  movss  0x8(%rax),%xmm0
  comiss %xmm0,%xmm1
  ja     L59
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  subsd  %xmm0,%xmm2
L28:
  mulss  0x8(%rdi),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsi),%xmm0
  mulsd  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
  nopl   0x0(%rax)
L29:
  movsd  D15(%rip),%xmm2
  movl   $0x0,(%rax)
  movaps %xmm1,%xmm0
  movapd %xmm2,%xmm4
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L59:
  movl   $0x0,0x8(%rax)
  jmp    L28
  nopl   0x0(%rax)
L7:
  movl   $0x0,0x4(%rax)
  movapd %xmm2,%xmm4
  movaps %xmm1,%xmm0
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: f64

tool: D15: 1

assistant: ```c
void nonlinear_color_interpolation_2(float *x, float *c0, float *c1, float *c) {
  int i;
  float factor;
  for (i = 0; i < 3; i++) {
    if (x[i] < 0.0)
      x[i] = 0.0;
    factor = x[i] / (1.0 + x[i]);
    c[i] = c0[i] * (1.0 - factor) + c1[i] * factor;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<hex2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  shr    %rsi
  mov    -0x28(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <chars_to_byte@plt>
  mov    %al,(%rbx)
  addq   $0x2,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  shr    %rax
  cmp    %rax,-0x38(%rbp)
  ja     L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void hex2bin(unsigned char *digest, const char *hex, size_t len) {
  for (size_t i = 0; i / 2 < len; i += 2) {
    digest[i / 2] = chars_to_byte(hex[i], hex[i + 1]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex2bin>:
  endbr64
  test   %rdx,%rdx
  je     L10
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    $0x0,%ebp
  mov    $0x0,%eax
L3:
  lea    (%r14,%rax,1),%rbx
  movsbl 0x1(%r12,%rbp,1),%esi
  movsbl (%r12,%rbp,1),%edi
  call   <chars_to_byte@plt>
  mov    %al,(%rbx)
  add    $0x2,%rbp
  mov    %rbp,%rax
  shr    %rax
  cmp    %r13,%rax
  jb     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  ret
```

assistant: ```c
void hex2bin(unsigned char *digest, const char *hex, size_t len) {
  for (size_t i = 0; i / 2 < len; i += 2) {
    digest[i / 2] = chars_to_byte(hex[i], hex[i + 1]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hex2bin>:
  endbr64
  test   %rdx,%rdx
  je     L4
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xchg   %ax,%ax
L6:
  movsbl 0x1(%r12,%rbp,1),%esi
  movsbl (%r12,%rbp,1),%edi
  lea    0x0(%r13,%rax,1),%rbx
  add    $0x2,%rbp
  call   <chars_to_byte@plt>
  mov    %al,(%rbx)
  mov    %rbp,%rax
  shr    %rax
  cmp    %r14,%rax
  jb     L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L4:
  ret
```

assistant: ```c
void hex2bin(unsigned char *digest, const char *hex, size_t len) {
  for (size_t i = 0; i / 2 < len; i += 2) {
    digest[i / 2] = chars_to_byte(hex[i], hex[i + 1]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex2bin>:
  endbr64
  test   %rdx,%rdx
  je     L13
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xchg   %ax,%ax
L19:
  movsbl 0x1(%r12,%rbp,1),%esi
  movsbl (%r12,%rbp,1),%edi
  lea    0x0(%r13,%rax,1),%rbx
  add    $0x2,%rbp
  call   <chars_to_byte@plt>
  mov    %al,(%rbx)
  mov    %rbp,%rax
  shr    %rax
  cmp    %r14,%rax
  jb     L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L13:
  ret
```

assistant: ```c
void hex2bin(unsigned char *digest, const char *hex, size_t len) {
  for (size_t i = 0; i / 2 < len; i += 2) {
    digest[i / 2] = chars_to_byte(hex[i], hex[i + 1]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<iclamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L23
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L14
L23:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L9
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  jmp    L14
L9:
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int iclamp(double x, double left, double right) {
  if (x < left) {
    return (int)left;
  } else if (x > right) {
    return (int)right;
  } else {
    return (int)x;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<iclamp>:
  endbr64
  comisd %xmm0,%xmm1
  ja     L19
  comisd %xmm2,%xmm0
  jbe    L11
  cvttsd2si %xmm2,%eax
  ret
L19:
  cvttsd2si %xmm1,%eax
  ret
L11:
  cvttsd2si %xmm0,%eax
  ret
```

assistant: ```c
int iclamp(double x, double left, double right) {
  if (x < left) {
    return (int)left;
  } else if (x > right) {
    return (int)right;
  } else {
    return (int)x;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iclamp>:
  endbr64
  comisd %xmm0,%xmm1
  ja     L6
  comisd %xmm2,%xmm0
  jbe    L9
  cvttsd2si %xmm2,%eax
  ret
  nopl   (%rax)
L9:
  cvttsd2si %xmm0,%eax
  ret
  nopl   (%rax)
L6:
  cvttsd2si %xmm1,%eax
  ret
```

assistant: ```c
int iclamp(double x, double left, double right) {
  if (x < left) {
    return (int)left;
  } else if (x > right) {
    return (int)right;
  } else {
    return (int)x;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<iclamp>:
  endbr64
  comisd %xmm0,%xmm1
  ja     L17
  comisd %xmm2,%xmm0
  jbe    L2
  cvttsd2si %xmm2,%eax
  ret
  nopl   (%rax)
L2:
  cvttsd2si %xmm0,%eax
  ret
  nopl   (%rax)
L17:
  cvttsd2si %xmm1,%eax
  ret
```

assistant: ```c
int iclamp(double x, double left, double right) {
  if (x < left) {
    return (int)left;
  } else if (x > right) {
    return (int)right;
  } else {
    return (int)x;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3131303245544147,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    -0x20(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rdx),%edx
  movsbq %dl,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: %s


assistant: ```c
void main(void) {
  char c[] = "GATE2011";
  char *p = c;
  printf("%s\n", p + p[3] - p[1]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3131303245544147,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0x13(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: %s


assistant: ```c
void main(void) {
  char c[] = "GATE2011";
  char *p = c;
  printf("%s\n", p + p[3] - p[1]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3131303245544147,%rax
  lea    0x13(%rsp),%rsi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %s


assistant: ```c
void main(void) {
  char c[] = "GATE2011";
  char *p = c;
  printf("%s\n", p + p[3] - p[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3131303245544147,%rax
  lea    0x13(%rsp),%rsi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %s


assistant: ```c
void main(void) {
  char c[] = "GATE2011";
  char *p = c;
  printf("%s\n", p + p[3] - p[1]);
}
```