ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dprint>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r12d
  jle    L18
  lea    -0x2(%r12),%eax
  lea    0x4(%rbp),%rbx
  lea    0x8(%rbp,%rax,4),%r12
  lea    D2(%rip),%rbp
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
L18:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D2
type_infered: string

tool: D7: %s: %d

tool: D2: , %d

assistant: ```c
void dprint(char *m, int *d, int n) {
  int i;
  printf("%s: %d", m, d[0]);
  for (i = 1; i < n; i++) {
    printf(", %d", d[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dprint>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%edx
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r12d
  jle    L1
  lea    -0x2(%r12),%eax
  lea    0x4(%rbp),%rbx
  lea    0x8(%rbp,%rax,4),%r12
  lea    D13(%rip),%rbp
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
L1:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D13
type: string

tool: D1: %s: %d

tool: D13: , %d

assistant: ```c
void dprint(char *m, int *d, int n) {
  int i;
  printf("%s: %d", m, d[0]);
  for (i = 1; i < n; i++) {
    printf(", %d", d[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<variance_kernel_sse2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_sub_epi16@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_add_epi32@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_add_epi16@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void variance_kernel_sse2(const __m128i src_ptr, const __m128i ref_ptr, __m128i *const sse, __m128i *const sum) {
  const __m128i diff = _mm_sub_epi16(src_ptr, ref_ptr);
  *sse = _mm_add_epi32(*sse, _mm_madd_epi16(diff, diff));
  *sum = _mm_add_epi16(*sum, diff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<variance_kernel_sse2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <_mm_sub_epi16@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %eax,%edi
  call   <_mm_madd_epi16@plt>
  mov    %eax,%esi
  mov    (%r12),%edi
  call   <_mm_add_epi32@plt>
  mov    %eax,(%r12)
  mov    %ebx,%esi
  mov    0x0(%rbp),%edi
  call   <_mm_add_epi16@plt>
  mov    %eax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void variance_kernel_sse2(const __m128i src_ptr, const __m128i ref_ptr, __m128i *const sse, __m128i *const sum) {
  const __m128i diff = _mm_sub_epi16(src_ptr, ref_ptr);
  *sse = _mm_add_epi32(*sse, _mm_madd_epi16(diff, diff));
  *sum = _mm_add_epi16(*sum, diff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<variance_kernel_sse2>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <_mm_sub_epi16@plt>
  mov    %eax,%esi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <_mm_madd_epi16@plt>
  mov    (%r12),%edi
  mov    %eax,%esi
  call   <_mm_add_epi32@plt>
  mov    %ebp,%esi
  mov    %eax,(%r12)
  mov    (%rbx),%edi
  call   <_mm_add_epi16@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void variance_kernel_sse2(const __m128i src_ptr, const __m128i ref_ptr, __m128i *const sse, __m128i *const sum) {
  const __m128i diff = _mm_sub_epi16(src_ptr, ref_ptr);
  *sse = _mm_add_epi32(*sse, _mm_madd_epi16(diff, diff));
  *sum = _mm_add_epi16(*sum, diff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<variance_kernel_sse2>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <_mm_sub_epi16@plt>
  mov    %eax,%esi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <_mm_madd_epi16@plt>
  mov    (%r12),%edi
  mov    %eax,%esi
  call   <_mm_add_epi32@plt>
  mov    %ebp,%esi
  mov    %eax,(%r12)
  mov    (%rbx),%edi
  call   <_mm_add_epi16@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void variance_kernel_sse2(const __m128i src_ptr, const __m128i ref_ptr, __m128i *const sse, __m128i *const sum) {
  const __m128i diff = _mm_sub_epi16(src_ptr, ref_ptr);
  *sse = _mm_add_epi32(*sse, _mm_madd_epi16(diff, diff));
  *sum = _mm_add_epi16(*sum, diff);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L17:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L19
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L19:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t length = 0;
  while (length < maxlen && s[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  mov    $0x0,%edx
  test   %rsi,%rsi
  je     L10
L23:
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L4
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L23
  jmp    L18
L10:
  ret
L4:
  mov    %rdx,%rax
L18:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t length = 0;
  while (length < maxlen && s[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L32
  jmp    L31
L27:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L16
L32:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L27
  mov    %rdx,%rax
L16:
  ret
L31:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t length = 0;
  while (length < maxlen && s[length] != '\0') {
    length++;
  }
  return length;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L2
  jmp    L4
L13:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L14
L2:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L13
  mov    %rdx,%rax
L14:
  ret
L4:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  size_t length = 0;
  while (length < maxlen && s[length] != '\0') {
    length++;
  }
  return length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_cc3_camera_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe002800c,%eax
  movq   $0x8000,(%rax)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  mov    $0xe0028004,%eax
  movq   $0x8000,(%rax)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  mov    $0xe002800c,%eax
  movq   $0x8000,(%rax)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _cc3_camera_reset() {
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE0028004))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_cc3_camera_reset>:
  endbr64
  push   %rbx
  mov    $0xe002800c,%ebx
  movq   $0x8000,(%rbx)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  mov    $0xe0028004,%eax
  movq   $0x8000,(%rax)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  movq   $0x8000,(%rbx)
  mov    $0x1,%edi
  call   <_cc3_delay_us_4@plt>
  pop    %rbx
  ret
```

assistant: ```c
void _cc3_camera_reset() {
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE0028004))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_cc3_camera_reset>:
  endbr64
  push   %rbx
  mov    $0xe002800c,%ebx
  mov    $0x1,%edi
  movq   $0x8000,(%rbx)
  call   <_cc3_delay_us_4@plt>
  mov    $0xe0028004,%eax
  mov    $0x1,%edi
  movq   $0x8000,(%rax)
  call   <_cc3_delay_us_4@plt>
  movq   $0x8000,(%rbx)
  mov    $0x1,%edi
  pop    %rbx
  jmp    1050 <_cc3_delay_us_4@plt>
```

assistant: ```c
void _cc3_camera_reset() {
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE0028004))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_cc3_camera_reset>:
  endbr64
  push   %rbx
  mov    $0xe002800c,%ebx
  mov    $0x1,%edi
  movq   $0x8000,(%rbx)
  call   <_cc3_delay_us_4@plt>
  mov    $0xe0028004,%eax
  mov    $0x1,%edi
  movq   $0x8000,(%rax)
  call   <_cc3_delay_us_4@plt>
  movq   $0x8000,(%rbx)
  mov    $0x1,%edi
  pop    %rbx
  jmp    1050 <_cc3_delay_us_4@plt>
```

assistant: ```c
void _cc3_camera_reset() {
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE0028004))) = 0x008000;
  _cc3_delay_us_4(1);
  (*(volatile unsigned long *)((0xE002800C))) = 0x008000;
  _cc3_delay_us_4(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fill_table_a000>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    $0x30,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L38
L13:
  movl   $0x0,-0x44(%rbp)
  jmp    L43
L47:
  mov    -0x58(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x58(%rbp)
  mov    -0x44(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x40(%rbp,%rdx,4),%edx
  mov    %edx,(%rax)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%ecx
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L43:
  cmpl   $0xb,-0x44(%rbp)
  jle    L47
  addl   $0x1,-0x48(%rbp)
L38:
  cmpl   $0xff,-0x48(%rbp)
  jle    L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void fill_table_a000(unsigned int *p) {
  static unsigned int initial_values[12] = {0xFFAD9B00, 0xFFDDEE00, 0x00221200, 0x00526500, 0xFFC21E00, 0x003DE200, 0xFF924B80, 0xFFD2A300, 0x002D5D00, 0x006DB480, 0xFFED3E00, 0x0012C200};
  static unsigned int values_derivated[12] = {0x0000A4CA, 0x00004424, 0xFFFFBBDC, 0xFFFF5B36, 0x00007BC4, 0xFFFF843C, 0x0000DB69, 0x00005ABA, 0xFFFFA546, 0xFFFF2497, 0x00002584, 0xFFFFDA7C};
  unsigned int temp_values[12];
  int i, j;
  memcpy(temp_values, initial_values, sizeof(initial_values));
  for (i = 0; i < 256; i++) {
    for (j = 0; j < 12; j++) {
      *p++ = temp_values[j];
      temp_values[j] += values_derivated[j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fill_table_a000>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x30,%edx
  lea    D0(%rip),%rsi
  call   <memcpy@plt>
  lea    0x3000(%rbx),%rsi
  lea    D12(%rip),%rcx
  jmp    L15
L33:
  add    $0x30,%rbx
  cmp    %rbx,%rsi
  je     L29
L15:
  mov    $0x0,%eax
L43:
  mov    (%rsp,%rax,1),%edx
  mov    %edx,(%rbx,%rax,1)
  add    (%rcx,%rax,1),%edx
  mov    %edx,(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x30,%rax
  jne    L43
  jmp    L33
L29:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x40,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D12: ʤ

assistant: ```c
void fill_table_a000(unsigned int *p) {
  static unsigned int initial_values[12] = {0xFFAD9B00, 0xFFDDEE00, 0x00221200, 0x00526500, 0xFFC21E00, 0x003DE200, 0xFF924B80, 0xFFD2A300, 0x002D5D00, 0x006DB480, 0xFFED3E00, 0x0012C200};
  static unsigned int values_derivated[12] = {0x0000A4CA, 0x00004424, 0xFFFFBBDC, 0xFFFF5B36, 0x00007BC4, 0xFFFF843C, 0x0000DB69, 0x00005ABA, 0xFFFFA546, 0xFFFF2497, 0x00002584, 0xFFFFDA7C};
  unsigned int temp_values[12];
  int i, j;
  memcpy(temp_values, initial_values, sizeof(initial_values));
  for (i = 0; i < 256; i++) {
    for (j = 0; j < 12; j++) {
      *p++ = temp_values[j];
      temp_values[j] += values_derivated[j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fill_table_a000>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rsi
  mov    $0x30,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x3000(%rbx),%rdi
  lea    0x30(%rsp),%rsi
L20:
  movdqa 0x0(%rbp),%xmm0
  movdqa 0x10(%rbp),%xmm1
  mov    %rbp,%rax
  mov    $0xa4ca,%ecx
  movdqa 0x20(%rbp),%xmm2
  lea    D1(%rip),%rdx
  movups %xmm0,(%rbx)
  movups %xmm1,0x10(%rbx)
  movups %xmm2,0x20(%rbx)
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%rdx),%ecx
  add    $0x4,%rdx
L27:
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L4
  add    $0x30,%rbx
  cmp    %rdi,%rbx
  jne    L20
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: $D

assistant: ```c
void fill_table_a000(unsigned int *p) {
  static unsigned int initial_values[12] = {0xFFAD9B00, 0xFFDDEE00, 0x00221200, 0x00526500, 0xFFC21E00, 0x003DE200, 0xFF924B80, 0xFFD2A300, 0x002D5D00, 0x006DB480, 0xFFED3E00, 0x0012C200};
  static unsigned int values_derivated[12] = {0x0000A4CA, 0x00004424, 0xFFFFBBDC, 0xFFFF5B36, 0x00007BC4, 0xFFFF843C, 0x0000DB69, 0x00005ABA, 0xFFFFA546, 0xFFFF2497, 0x00002584, 0xFFFFDA7C};
  unsigned int temp_values[12];
  int i, j;
  memcpy(temp_values, initial_values, sizeof(initial_values));
  for (i = 0; i < 256; i++) {
    for (j = 0; j < 12; j++) {
      *p++ = temp_values[j];
      temp_values[j] += values_derivated[j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_table_a000>:
  endbr64
  push   %rbx
  mov    $0x30,%edx
  mov    %rdi,%rbx
  lea    D33(%rip),%rsi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movdqa (%rsp),%xmm2
  mov    %rbx,%rax
  movdqa 0x10(%rsp),%xmm1
  movdqa 0x20(%rsp),%xmm0
  movdqa D24(%rip),%xmm7
  lea    0x3000(%rbx),%rdx
  movdqa D22(%rip),%xmm8
  movdqa D13(%rip),%xmm6
  nopl   0x0(%rax)
L4:
  movdqa %xmm2,%xmm5
  movdqa %xmm1,%xmm4
  movdqa %xmm0,%xmm3
  add    $0x30,%rax
  movups %xmm5,-0x30(%rax)
  paddd  %xmm8,%xmm2
  paddd  %xmm7,%xmm1
  movups %xmm4,-0x20(%rax)
  paddd  %xmm6,%xmm0
  movups %xmm3,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L4
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x40,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type_guessed: byte[16]
name: parse_data
arguments: label: D22
type_guessed: byte[16]
name: parse_data
arguments: label: D13
type_guessed: byte[16]

tool: {"D24": [0xc4,0x7b,0x00,0x00,0x3c,0x84,0xff,0xff,0x69,0xdb,0x00,0x00,0xba,0x5a,0x00,0x00]}

tool: {"D22": [0xca,0xa4,0x00,0x00,0x24,0x44,0x00,0x00,0xdc,0xbb,0xff,0xff,0x36,0x5b,0xff,0xff]}

tool: {"D13": [0x46,0xa5,0xff,0xff,0x97,0x24,0xff,0xff,0x84,0x25,0x00,0x00,0x7c,0xda,0xff,0xff]}

assistant: ```c
void fill_table_a000(unsigned int *p) {
  static unsigned int initial_values[12] = {0xFFAD9B00, 0xFFDDEE00, 0x00221200, 0x00526500, 0xFFC21E00, 0x003DE200, 0xFF924B80, 0xFFD2A300, 0x002D5D00, 0x006DB480, 0xFFED3E00, 0x0012C200};
  static unsigned int values_derivated[12] = {0x0000A4CA, 0x00004424, 0xFFFFBBDC, 0xFFFF5B36, 0x00007BC4, 0xFFFF843C, 0x0000DB69, 0x00005ABA, 0xFFFFA546, 0xFFFF2497, 0x00002584, 0xFFFFDA7C};
  unsigned int temp_values[12];
  int i, j;
  memcpy(temp_values, initial_values, sizeof(initial_values));
  for (i = 0; i < 256; i++) {
    for (j = 0; j < 12; j++) {
      *p++ = temp_values[j];
      temp_values[j] += values_derivated[j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SeleccionPadres>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L43
L2:
  mov    $0x0,%eax
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x28(%rbp),%eax
  cltq
  movss  %xmm0,-0x20(%rbp,%rax,4)
  mov    -0x28(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L43:
  cmpl   $0x4,-0x28(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L45
L8:
  movl   $0x5,-0x28(%rbp)
L46:
  subl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x24(%rbp),%eax
  cltq
  movss  -0x20(%rbp,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jae    L46
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    $0x5,%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x24(%rbp)
L45:
  cmpl   $0x4,-0x24(%rbp)
  jle    L8
  mov    -0x38(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D12: aleatorios

tool: D4: %f 

assistant: ```c
int SeleccionPadres(int padres[5], float acumulado[5]) {
  int i, x;
  float Aleatorio[5];
  printf("aleatorios");
  for (i = 0; i < 5; i++) {
    Aleatorio[i] = drand48() * 1;
    printf("%f ", Aleatorio[i]);
  }
  printf("\n");
  for (x = 0; x < 5; x++) {
    i = 5;
    do {
      i--;
    } while (acumulado[i] <= Aleatorio[x]);
    padres[x] = (5 - i);
  }
  return padres[5];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SeleccionPadres>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%r12
  lea    0x14(%rsp),%r14
  lea    D9(%rip),%r13
L34:
  mov    $0x0,%eax
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12)
  cvtss2sd %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%r12
  cmp    %r14,%r12
  jne    L34
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ecx
  mov    $0x5,%esi
L26:
  movss  (%rsp,%rcx,1),%xmm0
  mov    $0x4,%eax
L24:
  mov    %eax,%edx
  sub    $0x1,%rax
  comiss 0x4(%rbx,%rax,4),%xmm0
  jae    L24
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x14,%rcx
  jne    L26
  mov    0x14(%rbp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D2: aleatorios

tool: D9: %f 

assistant: ```c
int SeleccionPadres(int padres[5], float acumulado[5]) {
  int i, x;
  float Aleatorio[5];
  printf("aleatorios");
  for (i = 0; i < 5; i++) {
    Aleatorio[i] = drand48() * 1;
    printf("%f ", Aleatorio[i]);
  }
  printf("\n");
  for (x = 0; x < 5; x++) {
    i = 5;
    do {
      i--;
    } while (acumulado[i] <= Aleatorio[x]);
    padres[x] = (5 - i);
  }
  return padres[5];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SeleccionPadres>:
  endbr64
  push   %r15
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x14(%rsp),%r15
  mov    %r12,%r13
  call   <printf@plt>
L25:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  mov    %r14,%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  movss  %xmm0,-0x4(%r13)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %r15,%r13
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %ecx,%ecx
  mov    $0x5,%esi
L31:
  movss  (%r12,%rcx,1),%xmm0
  mov    $0x4,%eax
  nopl   0x0(%rax)
L24:
  mov    %eax,%edx
  sub    $0x1,%rax
  comiss 0x4(%rbx,%rax,4),%xmm0
  jae    L24
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x14,%rcx
  jne    L31
  mov    0x14(%rbp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D11: %f 

tool: D6: aleatorios

assistant: ```c
int SeleccionPadres(int padres[5], float acumulado[5]) {
  int i, x;
  float Aleatorio[5];
  printf("aleatorios");
  for (i = 0; i < 5; i++) {
    Aleatorio[i] = drand48() * 1;
    printf("%f ", Aleatorio[i]);
  }
  printf("\n");
  for (x = 0; x < 5; x++) {
    i = 5;
    do {
      i--;
    } while (acumulado[i] <= Aleatorio[x]);
    padres[x] = (5 - i);
  }
  return padres[5];
}
```