user: 这段汇编代码用C语言表示是什么样的？

```asm
<lattice_path_mat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %fs:0x28,%rcx
  mov    %rcx,-0x38(%rbp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  mov    %rcx,%r15
  mov    -0x68(%rbp),%ecx
  add    $0x1,%ecx
  mov    -0x64(%rbp),%esi
  lea    0x1(%rsi),%edi
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x50(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movslq %ecx,%rsi
  shl    $0x3,%rsi
  movslq %edi,%rbx
  sub    $0x1,%rbx
  mov    %rbx,-0x48(%rbp)
  movslq %ecx,%rbx
  mov    %rbx,%r12
  mov    $0x0,%r13d
  movslq %edi,%rbx
  mov    %rbx,%rax
  mov    $0x0,%edx
  mov    %r13,%r14
  imul   %rax,%r14
  mov    %rdx,%rbx
  imul   %r12,%rbx
  add    %r14,%rbx
  mul    %r12
  add    %rdx,%rbx
  mov    %rbx,%rdx
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %edi,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    %r11,%rdx
  imul   %r8,%rdx
  mov    %r9,%rax
  imul   %r10,%rax
  lea    (%rdx,%rax,1),%rbx
  mov    %r10,%rax
  mul    %r8
  lea    (%rbx,%rdx,1),%r8
  mov    %r8,%rdx
  movslq %ecx,%rdx
  movslq %edi,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L59:
  cmp    %rdx,%rsp
  je     L84
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L59
L84:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L101
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L101:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L89
L61:
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x68(%rbp),%edx
  movslq %edx,%rdi
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rdi,%rdx
  movq   $0x1,(%rax,%rdx,8)
  addl   $0x1,-0x58(%rbp)
L89:
  mov    -0x64(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jge    L61
  movl   $0x0,-0x58(%rbp)
  jmp    L98
L64:
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdi
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rdi,%rdx
  movq   $0x1,(%rax,%rdx,8)
  addl   $0x1,-0x58(%rbp)
L98:
  mov    -0x68(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jge    L64
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x58(%rbp)
  jmp    L50
L85:
  mov    -0x68(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x54(%rbp)
  jmp    L104
L20:
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  mov    -0x58(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%r8
  movslq %edi,%rdx
  imul   %rcx,%rdx
  add    %r8,%rdx
  mov    (%rax,%rdx,8),%r8
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdi
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  imul   %rcx,%rdx
  add    %rdi,%rdx
  mov    (%rax,%rdx,8),%rax
  mov    %rsi,%rdi
  shr    $0x3,%rdi
  lea    (%r8,%rax,1),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%r8
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  imul   %rdi,%rdx
  add    %r8,%rdx
  mov    %rcx,(%rax,%rdx,8)
  subl   $0x1,-0x54(%rbp)
L104:
  cmpl   $0x0,-0x54(%rbp)
  jns    L20
  subl   $0x1,-0x58(%rbp)
L50:
  cmpl   $0x0,-0x58(%rbp)
  jns    L85
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
long long int lattice_path_mat(int a, int b) {
  long long int paths_num[a + 1][b + 1];
  int i, j;
  for (i = 0; i < a + 1; i++) {
    paths_num[i][b] = 1;
  }
  for (i = 0; i < b + 1; i++) {
    paths_num[a][i] = 1;
  }
  for (i = a - 1; i >= 0; i--) {
    for (j = b - 1; j >= 0; j--) {
      paths_num[i][j] = paths_num[i + 1][j] + paths_num[i][j + 1];
    }
  }
  return paths_num[0][0];
}
```