ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_diagonal_dm_simple>:
  endbr64
  push   %rbp
  cvtss2sd %xmm0,%xmm0
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movsd  D15(%rip),%xmm5
  movss  %xmm1,0xc(%rsp)
  movaps %xmm3,%xmm1
  divsd  %xmm0,%xmm5
  movss  %xmm2,0x4(%rsp)
  movss  %xmm3,0x8(%rsp)
  movapd %xmm5,%xmm0
  call   <pow@plt>
  movss  0xc(%rsp),%xmm4
  movsd  D15(%rip),%xmm6
  movss  %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtss2sd %xmm4,%xmm0
  divsd  %xmm0,%xmm6
  movapd %xmm6,%xmm0
  call   <pow@plt>
  mov    %ebp,%edi
  movss  %xmm0,0x8(%rsp)
  call   <get_nchan_from_depth@plt>
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm2
  subss  (%rsp),%xmm2
  cvtsi2ss %eax,%xmm1
  mulss  0x4(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  divsd  D12(%rip),%xmm0
  add    $0x10,%rsp
  cvtss2sd %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  pop    %rbp
  cvtsd2ss %xmm0,%xmm0
  jmp    1070 <fabs@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
type: f64
name: disassemble_data
arguments: label: D12
type: f64

tool: D15: 1

tool: D12: 4148.808

assistant: ```c
float get_diagonal_dm_simple(float nu1, float nu2, float dt, int depth, float disp_ind) {
  float d1 = pow(1.0 / nu1, disp_ind);
  float d2 = pow(1.0 / nu2, disp_ind);
  int nchan = get_nchan_from_depth(depth);
  float dm_max = ((dt * nchan) / 4148.808) / (d2 - d1);
  return fabs(dm_max);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_diagonal_dm_simple>:
  endbr64
  push   %rbp
  cvtss2sd %xmm0,%xmm0
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movsd  D15(%rip),%xmm5
  movss  %xmm1,0xc(%rsp)
  movaps %xmm3,%xmm1
  divsd  %xmm0,%xmm5
  movss  %xmm2,0x4(%rsp)
  movss  %xmm3,0x8(%rsp)
  movapd %xmm5,%xmm0
  call   <pow@plt>
  movss  0xc(%rsp),%xmm4
  movsd  D15(%rip),%xmm6
  movss  %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtss2sd %xmm4,%xmm0
  divsd  %xmm0,%xmm6
  movapd %xmm6,%xmm0
  call   <pow@plt>
  mov    %ebp,%edi
  movss  %xmm0,0x8(%rsp)
  call   <get_nchan_from_depth@plt>
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm2
  subss  (%rsp),%xmm2
  cvtsi2ss %eax,%xmm1
  mulss  0x4(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  divsd  D22(%rip),%xmm0
  add    $0x10,%rsp
  cvtss2sd %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  pop    %rbp
  cvtsd2ss %xmm0,%xmm0
  jmp    1070 <fabs@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: f64
name: parse_data
arguments: data_label: D22
data_type: f64

tool: D15: 1

tool: D22: 4148.808

assistant: ```c
float get_diagonal_dm_simple(float nu1, float nu2, float dt, int depth, float disp_ind) {
  float d1 = pow(1.0 / nu1, disp_ind);
  float d2 = pow(1.0 / nu2, disp_ind);
  int nchan = get_nchan_from_depth(depth);
  float dm_max = ((dt * nchan) / 4148.808) / (d2 - d1);
  return fabs(dm_max);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<combineHelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L21
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  jmp    L2
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L34
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <combineHelp>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <combineHelp>
  jmp    L2
L34:
  nop
L2:
  leave
  ret
```

assistant: ```c
void combineHelp(int *arr, int ind, int num, int sel, int sum) {
  if (sum == sel) {
    printArray(arr, num);
    return;
  }
  if (ind == num) {
    return;
  }
  arr[ind] = 1;
  combineHelp(arr, ind + 1, num, sel, sum + 1);
  arr[ind] = 0;
  combineHelp(arr, ind + 1, num, sel, sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<combineHelp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  cmp    %ecx,%r8d
  je     L21
  mov    %ecx,%ebx
  mov    %r8d,%ebp
  cmp    %edx,%esi
  je     L9
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r14
  movl   $0x1,(%r14)
  lea    0x1(%rsi),%r15d
  lea    0x1(%r8),%r8d
  mov    %r15d,%esi
  call   <combineHelp>
  movl   $0x0,(%r14)
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <combineHelp>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    %edx,%esi
  call   <printArray@plt>
  jmp    L9
```

assistant: ```c
void combineHelp(int *arr, int ind, int num, int sel, int sum) {
  if (sum == sel) {
    printArray(arr, num);
    return;
  }
  if (ind == num) {
    return;
  }
  arr[ind] = 1;
  combineHelp(arr, ind + 1, num, sel, sum + 1);
  arr[ind] = 0;
  combineHelp(arr, ind + 1, num, sel, sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_level>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L38
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L10
  addl   $0x1,-0xc(%rbp)
L10:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L17
L22:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_level(const char *path) {
  int count = 0;
  for (size_t i = 0; path[i] != '\0' && path[i] != '>'; i++)
    if (path[i] == '/')
      count++;
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_level>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  cmp    $0x3e,%al
  je     L2
  add    $0x1,%rdi
  mov    $0x0,%edx
L35:
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L49
  cmp    $0x3e,%al
  jne    L35
L49:
  mov    %edx,%eax
  ret
L2:
  mov    $0x0,%edx
  jmp    L49
```

assistant: ```c
int get_level(const char *path) {
  int count = 0;
  for (size_t i = 0; path[i] != '\0' && path[i] != '>'; i++)
    if (path[i] == '/')
      count++;
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_level>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  cmp    $0x3e,%al
  je     L2
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L29:
  cmp    $0x2f,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L38
  cmp    $0x3e,%al
  jne    L29
L38:
  mov    %r8d,%eax
  ret
  nop
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_level(const char *path) {
  int count = 0;
  for (size_t i = 0; path[i] != '\0' && path[i] != '>'; i++)
    if (path[i] == '/')
      count++;
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_level>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  cmp    $0x3e,%al
  je     L31
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    $0x2f,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L36
  cmp    $0x3e,%al
  jne    L28
L36:
  mov    %r8d,%eax
  ret
  nop
L31:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_level(const char *path) {
  int count = 0;
  for (size_t i = 0; path[i] != '\0' && path[i] != '>'; i++)
    if (path[i] == '/')
      count++;
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AddHuffmanBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L56:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L31
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  and    %rdx,%rax
  test   %rax,%rax
  jne    L25
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L5
  mov    $0x1,%edi
  call   <malloc@plt>
  jmp    L2
L5:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L2:
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
L25:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L31:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  add    %rdx,%rax
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L56
  nop
  nop
  leave
  ret
```

assistant: ```c
void AddHuffmanBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> (length - i - 1)) & 1;
    if (((*bp) & 7) == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << ((*bp) & 7);
    (*bp)++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AddHuffmanBits>:
  endbr64
  test   %esi,%esi
  je     L19
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rdx,%r12
  mov    %rcx,%r14
  mov    %r8,%r13
  lea    -0x1(%rsi),%ebp
  jmp    L18
L0:
  add    %rsi,%rsi
  mov    (%r14),%rdi
  call   <realloc@plt>
L15:
  mov    %rax,(%r14)
L43:
  mov    (%r14),%rdx
  mov    0x0(%r13),%rax
  movb   $0x0,(%rdx,%rax,1)
  addq   $0x1,0x0(%r13)
L9:
  mov    0x0(%r13),%rax
  mov    (%r14),%rdx
  movzbl (%r12),%ecx
  and    $0x7,%ecx
  shl    %cl,%ebx
  or     %bl,-0x1(%rdx,%rax,1)
  addb   $0x1,(%r12)
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  je     L44
L18:
  mov    %r15d,%ebx
  mov    %ebp,%ecx
  shr    %cl,%ebx
  and    $0x1,%ebx
  testb  $0x7,(%r12)
  jne    L9
  mov    0x0(%r13),%rsi
  lea    -0x1(%rsi),%rax
  test   %rsi,%rax
  jne    L43
  test   %rsi,%rsi
  jne    L0
  mov    $0x1,%edi
  call   <malloc@plt>
  jmp    L15
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  ret
```

assistant: ```c
void AddHuffmanBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> (length - i - 1)) & 1;
    if (((*bp) & 7) == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << ((*bp) & 7);
    (*bp)++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AddHuffmanBits>:
  endbr64
  test   %esi,%esi
  je     L73
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdx),%eax
  jmp    L6
  xchg   %ax,%ax
L33:
  mov    (%r14),%rax
L70:
  movb   $0x0,(%rax,%rsi,1)
  mov    (%r15),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%r15)
  movzbl (%r12),%ecx
  and    $0x7,%ecx
L26:
  add    (%r14),%rdx
  shl    %cl,%ebx
  or     %bl,(%rdx)
  movzbl (%r12),%eax
  add    $0x1,%eax
  mov    %al,(%r12)
  sub    $0x1,%ebp
  jb     L40
L6:
  mov    %ebp,%ecx
  mov    %r13d,%ebx
  mov    (%r15),%rsi
  shr    %cl,%ebx
  and    $0x1,%ebx
  and    $0x7,%eax
  lea    -0x1(%rsi),%rdx
  mov    %eax,%ecx
  jne    L26
  test   %rdx,%rsi
  jne    L33
  test   %rsi,%rsi
  jne    L56
  mov    $0x1,%edi
  call   <malloc@plt>
L14:
  mov    %rax,(%r14)
  mov    (%r15),%rsi
  jmp    L70
  nopl   (%rax)
L56:
  mov    (%r14),%rdi
  add    %rsi,%rsi
  call   <realloc@plt>
  jmp    L14
  nopl   (%rax)
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  ret
```

assistant: ```c
void AddHuffmanBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> (length - i - 1)) & 1;
    if (((*bp) & 7) == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << ((*bp) & 7);
    (*bp)++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AddHuffmanBits>:
  endbr64
  test   %esi,%esi
  je     L70
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdx),%eax
  jmp    L27
  xchg   %ax,%ax
L75:
  mov    (%r14),%rax
L48:
  movb   $0x0,(%rax,%rsi,1)
  mov    (%r15),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%r15)
  movzbl (%r12),%ecx
  and    $0x7,%ecx
L54:
  add    (%r14),%rdx
  shl    %cl,%ebx
  or     %bl,(%rdx)
  movzbl (%r12),%eax
  add    $0x1,%eax
  mov    %al,(%r12)
  sub    $0x1,%ebp
  jb     L0
L27:
  mov    %ebp,%ecx
  mov    %r13d,%ebx
  mov    (%r15),%rsi
  shr    %cl,%ebx
  and    $0x1,%ebx
  and    $0x7,%eax
  lea    -0x1(%rsi),%rdx
  mov    %eax,%ecx
  jne    L54
  test   %rdx,%rsi
  jne    L75
  test   %rsi,%rsi
  jne    L52
  mov    $0x1,%edi
  call   <malloc@plt>
L42:
  mov    %rax,(%r14)
  mov    (%r15),%rsi
  jmp    L48
  nopl   (%rax)
L52:
  mov    (%r14),%rdi
  add    %rsi,%rsi
  call   <realloc@plt>
  jmp    L42
  nopl   (%rax)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L70:
  ret
```

assistant: ```c
void AddHuffmanBits(unsigned symbol, unsigned length, unsigned char *bp, unsigned char **out, size_t *outsize) {
  unsigned i;
  for (i = 0; i < length; i++) {
    unsigned bit = (symbol >> (length - i - 1)) & 1;
    if (((*bp) & 7) == 0) {
      if (!((*outsize) & ((*outsize) - 1))) {
        (*out) = (*outsize) == 0 ? malloc(sizeof(**out)) : realloc((*out), (*outsize) * 2 * sizeof(**out));
      }
      (*out)[(*outsize)] = (0);
      (*outsize)++;
    };
    (*out)[*outsize - 1] |= bit << ((*bp) & 7);
    (*bp)++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rm_unknown_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <alpha_to_int@plt>
  test   %rax,%rax
  jns    L12
  addl   $0x1,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L9:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void rm_unknown_char(char *tab, char *alphabet) {
  int i;
  int j = 0;
  for (i = 0; tab[i + 1] != '\0'; ++i) {
    if ((alpha_to_int(tab[i], alphabet)) < 0) {
      j++;
    } else {
      tab[i - j] = tab[i];
    }
  }
  tab[i - j] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<rm_unknown_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmpb   $0x0,0x1(%rdi)
  je     L46
  mov    %rsi,%r14
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L27
L40:
  movzbl 0x0(%rbp,%rbx,1),%edx
  mov    %ebx,%eax
  sub    %r13d,%eax
  cltq
  mov    %dl,0x0(%rbp,%rax,1)
L49:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmpb   $0x0,0x1(%rbp,%rbx,1)
  je     L48
L27:
  mov    %ebx,%r12d
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r14,%rsi
  call   <alpha_to_int@plt>
  test   %rax,%rax
  jns    L40
  add    $0x1,%r13d
  jmp    L49
L46:
  mov    $0x0,%r13d
  mov    $0x0,%r12d
L48:
  sub    %r13d,%r12d
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rm_unknown_char(char *tab, char *alphabet) {
  int i;
  int j = 0;
  for (i = 0; tab[i + 1] != '\0'; ++i) {
    if ((alpha_to_int(tab[i], alphabet)) < 0) {
      j++;
    } else {
      tab[i - j] = tab[i];
    }
  }
  tab[i - j] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<rm_unknown_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,0x1(%rdi)
  je     L1
  mov    %rsi,%r14
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  jmp    L47
  nop
L39:
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rbx,1),%edx
  add    $0x1,%rbx
  add    $0x1,%r12d
  sub    %r13d,%eax
  cltq
  mov    %dl,0x0(%rbp,%rax,1)
  cmpb   $0x0,0x1(%rbp,%rbx,1)
  je     L45
L47:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r14,%rsi
  mov    %ebx,%r12d
  call   <alpha_to_int@plt>
  test   %rax,%rax
  jns    L39
  add    $0x1,%rbx
  add    $0x1,%r13d
  add    $0x1,%r12d
  cmpb   $0x0,0x1(%rbp,%rbx,1)
  jne    L47
L45:
  sub    %r13d,%r12d
  movslq %r12d,%r12
  add    %r12,%rbp
L1:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rm_unknown_char(char *tab, char *alphabet) {
  int i;
  int j = 0;
  for (i = 0; tab[i + 1] != '\0'; ++i) {
    if ((alpha_to_int(tab[i], alphabet)) < 0) {
      j++;
    } else {
      tab[i - j] = tab[i];
    }
  }
  tab[i - j] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rm_unknown_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,0x1(%rdi)
  je     L34
  mov    %rsi,%r13
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nop
L31:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %r13,%rsi
  call   <alpha_to_int@plt>
  test   %rax,%rax
  js     L21
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rbx,1),%edx
  sub    %r12d,%eax
  cltq
  mov    %dl,0x0(%rbp,%rax,1)
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  cmpb   $0x0,0x1(%rbp,%rbx,1)
  jne    L31
L48:
  sub    %r12d,%eax
  cltq
  add    %rax,%rbp
L34:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%r12d
  cmpb   $0x0,0x1(%rbp,%rbx,1)
  jne    L31
  jmp    L48
```

assistant: ```c
void rm_unknown_char(char *tab, char *alphabet) {
  int i;
  int j = 0;
  for (i = 0; tab[i + 1] != '\0'; ++i) {
    if ((alpha_to_int(tab[i], alphabet)) < 0) {
      j++;
    } else {
      tab[i - j] = tab[i];
    }
  }
  tab[i - j] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memflip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L5
L7:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  xor    $0xffff,%edx
  mov    %edx,(%rax)
L5:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memflip(uint16_t *p, uint16_t len) {
  while (len--)
    *p++ ^= 0xFFFF;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memflip>:
  endbr64
  test   %esi,%esi
  je     L2
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
L4:
  add    $0x4,%rdi
  xorl   $0xffff,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L4
L2:
  ret
```

assistant: ```c
void memflip(uint16_t *p, uint16_t len) {
  while (len--)
    *p++ ^= 0xFFFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memflip>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  xchg   %ax,%ax
L4:
  add    $0x4,%rdi
  xorl   $0xffff,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L4
L7:
  ret
```

assistant: ```c
void memflip(uint16_t *p, uint16_t len) {
  while (len--)
    *p++ ^= 0xFFFF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memflip>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L20
  cmp    $0x2,%ecx
  jbe    L38
  mov    %esi,%edx
  movdqa D5(%rip),%xmm1
  mov    %rdi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L45:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pxor   %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L45
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  sub    %eax,%ecx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %eax,%esi
  je     L20
L38:
  xorl   $0xffff,(%rdi)
  test   %ecx,%ecx
  je     L20
  xorl   $0xffff,0x4(%rdi)
  cmp    $0x1,%ecx
  je     L20
  xorl   $0xffff,0x8(%rdi)
L20:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: byte[16]

tool: {"D5": [0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00]}

assistant: ```c
void memflip(uint16_t *p, uint16_t len) {
  while (len--)
    *p++ ^= 0xFFFF;
}
```