ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<bpf_load_program>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  mov    $0x8,%esi
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r14,%rdi
  mov    %r15,(%rsp)
  call   <ptr_to_u64@plt>
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  call   <ptr_to_u64@plt>
  xor    %edi,%edi
  mov    %rax,(%rsp)
  call   <ptr_to_u64@plt>
  mov    %rbp,(%rsp)
  mov    $0x8,%edx
  mov    %r13,%rsi
  mov    D3(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <sys_bpf@plt>
  test   %rbx,%rbx
  sete   %dl
  cmpq   $0x0,0x50(%rsp)
  sete   %cl
  or     %cl,%dl
  jne    L39
  test   %eax,%eax
  js     L11
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L11:
  mov    %rbx,%rdi
  call   <ptr_to_u64@plt>
  movb   $0x0,(%rbx)
  mov    0x50(%rsp),%rax
  mov    %r13,%rsi
  mov    0x0(%rbp),%edi
  mov    $0x8,%edx
  mov    %rax,(%rsp)
  movl   $0x1,(%rsp)
  call   <sys_bpf@plt>
  jmp    L39
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_load_program(enum bpf_prog_type type, const struct bpf_insn *insns, size_t insns_cnt, const char *license, __u32 kern_version, char *log_buf, size_t log_buf_sz) {
  int fd;
  union bpf_attr attr;
  bzero(&attr, sizeof(attr));
  attr.prog_type = type;
  attr.insn_cnt = (__u32)insns_cnt;
  attr.insns = ptr_to_u64(insns);
  attr.license = ptr_to_u64(license);
  attr.log_buf = ptr_to_u64(NULL);
  attr.log_size = 0;
  attr.log_level = 0;
  attr.kern_version = kern_version;
  fd = sys_bpf(BPF_PROG_LOAD, &attr, sizeof(attr));
  if (fd >= 0 || !log_buf || !log_buf_sz)
    return fd;
  attr.log_buf = ptr_to_u64(log_buf);
  attr.log_size = log_buf_sz;
  attr.log_level = 1;
  log_buf[0] = 0;
  return sys_bpf(BPF_PROG_LOAD, &attr, sizeof(attr));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<polindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xe0(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strrev@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L28:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D25
type: string
name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D27
type: string

tool: D25: %s

tool: D7: 1

tool: D27: 0

assistant: ```c
int polindrome() {
  char a[100];
  char b[100];
  scanf("%s", a);
  strcpy(b, a);
  strrev(b);
  if (strcmp(a, b) == 0) {
    printf("1");
  } else {
    printf("0");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<polindrome>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  lea    0x70(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strrev@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  lea    D28(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string

tool: D17: %s

tool: D28: 1

tool: D14: 0

assistant: ```c
int polindrome() {
  char a[100];
  char b[100];
  scanf("%s", a);
  strcpy(b, a);
  strrev(b);
  if (strcmp(a, b) == 0) {
    printf("1");
  } else {
    printf("0");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<polindrome>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strrev@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  lea    D6(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D2
type: string

tool: D0: %s

tool: D6: 1

tool: D2: 0

assistant: ```c
int polindrome() {
  char a[100];
  char b[100];
  scanf("%s", a);
  strcpy(b, a);
  strrev(b);
  if (strcmp(a, b) == 0) {
    printf("1");
  } else {
    printf("0");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<polindrome>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strrev@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  lea    D15(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string
name: unpack_data
arguments: data_label: D24
datatype: string

tool: D16: %s

tool: D15: 1

tool: D24: 0

assistant: ```c
int polindrome() {
  char a[100];
  char b[100];
  scanf("%s", a);
  strcpy(b, a);
  strrev(b);
  if (strcmp(a, b) == 0) {
    printf("1");
  } else {
    printf("0");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<indx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L5
L4:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
ptrdiff_t indx(const char *s1, const char *s2) {
  char *t;
  t = strstr(s1, s2);
  if (t == NULL)
    return (-1);
  else
    return (t - s1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<indx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L6
  sub    %ebx,%eax
L3:
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
ptrdiff_t indx(const char *s1, const char *s2) {
  char *t;
  t = strstr(s1, s2);
  if (t == NULL)
    return (-1);
  else
    return (t - s1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<indx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L3
  sub    %ebx,%eax
  pop    %rbx
  ret
L3:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
ptrdiff_t indx(const char *s1, const char *s2) {
  char *t;
  t = strstr(s1, s2);
  if (t == NULL)
    return (-1);
  else
    return (t - s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<indx>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  sub    %ebx,%eax
  pop    %rbx
  ret
L9:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
ptrdiff_t indx(const char *s1, const char *s2) {
  char *t;
  t = strstr(s1, s2);
  if (t == NULL)
    return (-1);
  else
    return (t - s1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<normiraj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void normiraj(double *v) {
  double d = sqrt(v[0] * v[0] + v[1] * v[1] + v[2] * v[2]);
  v[0] /= d;
  v[1] /= d;
  v[2] /= d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<normiraj>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%r13
  mov    0x8(%rdi),%r12
  mov    0x10(%rdi),%rbp
  movq   %r13,%xmm0
  mulsd  %xmm0,%xmm0
  movq   %r12,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movq   %rbp,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
L4:
  movq   %r13,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movq   %r12,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <sqrt@plt>
  jmp    L4
```

assistant: ```c
void normiraj(double *v) {
  double d = sqrt(v[0] * v[0] + v[1] * v[1] + v[2] * v[2]);
  v[0] /= d;
  v[1] /= d;
  v[2] /= d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<normiraj>:
  endbr64
  sub    $0x28,%rsp
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm2
  movsd  0x10(%rdi),%xmm1
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm3,%xmm0
  addsd  %xmm4,%xmm0
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm0
  pxor   %xmm4,%xmm4
  ucomisd %xmm0,%xmm4
  ja     L7
  sqrtsd %xmm0,%xmm0
L16:
  divsd  %xmm0,%xmm3
  divsd  %xmm0,%xmm2
  movsd  %xmm3,(%rdi)
  divsd  %xmm0,%xmm1
  movsd  %xmm2,0x8(%rdi)
  movsd  %xmm1,0x10(%rdi)
  add    $0x28,%rsp
  ret
L7:
  mov    %rdi,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rdi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  jmp    L16
```

assistant: ```c
void normiraj(double *v) {
  double d = sqrt(v[0] * v[0] + v[1] * v[1] + v[2] * v[2]);
  v[0] /= d;
  v[1] /= d;
  v[2] /= d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<normiraj>:
  endbr64
  sub    $0x28,%rsp
  movupd (%rdi),%xmm2
  movsd  (%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  %xmm0,%xmm0
  movapd %xmm2,%xmm4
  unpckhpd %xmm4,%xmm4
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm0
  pxor   %xmm3,%xmm3
  ucomisd %xmm0,%xmm3
  ja     L11
  sqrtsd %xmm0,%xmm0
L17:
  divsd  %xmm0,%xmm1
  movapd %xmm0,%xmm3
  unpcklpd %xmm3,%xmm3
  divpd  %xmm3,%xmm2
  movsd  %xmm1,0x10(%rdi)
  movups %xmm2,(%rdi)
  add    $0x28,%rsp
  ret
L11:
  mov    %rdi,0x18(%rsp)
  movaps %xmm2,(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  mov    0x18(%rsp),%rdi
  movapd (%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  jmp    L17
```

assistant: ```c
void normiraj(double *v) {
  double d = sqrt(v[0] * v[0] + v[1] * v[1] + v[2] * v[2]);
  v[0] /= d;
  v[1] /= d;
  v[2] /= d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<baselineGT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L11
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L11:
  cmpl   $0x0,-0x14(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L16
L17:
  nop
L16:
  leave
  ret
```

assistant: ```c
void baselineGT(unsigned a) {
  char *b = ((void *)0);
  if (a > 0)
    b = malloc(1);
  if (a == 0)
    return;
  free(b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<baselineGT>:
  endbr64
  test   %edi,%edi
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void baselineGT(unsigned a) {
  char *b = ((void *)0);
  if (a > 0)
    b = malloc(1);
  if (a == 0)
    return;
  free(b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<baselineGT>:
  endbr64
  test   %edi,%edi
  jne    L8
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void baselineGT(unsigned a) {
  char *b = ((void *)0);
  if (a > 0)
    b = malloc(1);
  if (a == 0)
    return;
  free(b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baselineGT>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void baselineGT(unsigned a) {
  char *b = ((void *)0);
  if (a > 0)
    b = malloc(1);
  if (a == 0)
    return;
  free(b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setup_ram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x48000000,%eax
  movq   $0x22011110,(%rax)
  mov    $0x48000008,%eax
  movq   $0x700,(%rax)
  mov    $0x48000010,%eax
  movq   $0x700,(%rax)
  mov    $0x48000018,%eax
  movq   $0x700,(%rax)
  mov    $0x48000020,%eax
  movq   $0x700,(%rax)
  mov    $0x48000028,%eax
  movq   $0x700,(%rax)
  mov    $0x48000030,%eax
  movq   $0x700,(%rax)
  mov    $0x48000038,%eax
  movq   $0x18005,(%rax)
  mov    $0x48000040,%eax
  movq   $0x18005,(%rax)
  mov    $0x48000048,%eax
  movq   $0x8c07a3,(%rax)
  mov    $0x48000050,%eax
  movq   $0xb1,(%rax)
  mov    $0x48000058,%eax
  movq   $0x30,(%rax)
  mov    $0x48000060,%eax
  movq   $0x30,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setup_ram() {
  ((volatile unsigned long *)0x48000000)[0] = 0x22011110;
  ((volatile unsigned long *)0x48000000)[1] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[2] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[3] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[4] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[5] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[6] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[7] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[8] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[9] = 0x008C07A3;
  ((volatile unsigned long *)0x48000000)[10] = 0x000000B1;
  ((volatile unsigned long *)0x48000000)[11] = 0x00000030;
  ((volatile unsigned long *)0x48000000)[12] = 0x00000030;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup_ram>:
  endbr64
  movq   $0x22011110,0x48000000
  movq   $0x700,0x48000008
  movq   $0x700,0x48000010
  movq   $0x700,0x48000018
  movq   $0x700,0x48000020
  movq   $0x700,0x48000028
  movq   $0x700,0x48000030
  movq   $0x18005,0x48000038
  movq   $0x18005,0x48000040
  movq   $0x8c07a3,0x48000048
  movq   $0xb1,0x48000050
  movq   $0x30,0x48000058
  movq   $0x30,0x48000060
  ret
```

assistant: ```c
void setup_ram() {
  ((volatile unsigned long *)0x48000000)[0] = 0x22011110;
  ((volatile unsigned long *)0x48000000)[1] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[2] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[3] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[4] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[5] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[6] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[7] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[8] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[9] = 0x008C07A3;
  ((volatile unsigned long *)0x48000000)[10] = 0x000000B1;
  ((volatile unsigned long *)0x48000000)[11] = 0x00000030;
  ((volatile unsigned long *)0x48000000)[12] = 0x00000030;
}
```
user: What is the c source code of the assembly code below?

```asm
<setup_ram>:
  endbr64
  movq   $0x22011110,0x48000000
  movq   $0x700,0x48000008
  movq   $0x700,0x48000010
  movq   $0x700,0x48000018
  movq   $0x700,0x48000020
  movq   $0x700,0x48000028
  movq   $0x700,0x48000030
  movq   $0x18005,0x48000038
  movq   $0x18005,0x48000040
  movq   $0x8c07a3,0x48000048
  movq   $0xb1,0x48000050
  movq   $0x30,0x48000058
  movq   $0x30,0x48000060
  ret
```

assistant: ```c
void setup_ram() {
  ((volatile unsigned long *)0x48000000)[0] = 0x22011110;
  ((volatile unsigned long *)0x48000000)[1] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[2] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[3] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[4] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[5] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[6] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[7] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[8] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[9] = 0x008C07A3;
  ((volatile unsigned long *)0x48000000)[10] = 0x000000B1;
  ((volatile unsigned long *)0x48000000)[11] = 0x00000030;
  ((volatile unsigned long *)0x48000000)[12] = 0x00000030;
}
```
user: What is the c source code of the assembly code below:

```asm
<setup_ram>:
  endbr64
  movq   $0x22011110,0x48000000
  movq   $0x700,0x48000008
  movq   $0x700,0x48000010
  movq   $0x700,0x48000018
  movq   $0x700,0x48000020
  movq   $0x700,0x48000028
  movq   $0x700,0x48000030
  movq   $0x18005,0x48000038
  movq   $0x18005,0x48000040
  movq   $0x8c07a3,0x48000048
  movq   $0xb1,0x48000050
  movq   $0x30,0x48000058
  movq   $0x30,0x48000060
  ret
```

assistant: ```c
void setup_ram() {
  ((volatile unsigned long *)0x48000000)[0] = 0x22011110;
  ((volatile unsigned long *)0x48000000)[1] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[2] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[3] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[4] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[5] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[6] = 0x00000700;
  ((volatile unsigned long *)0x48000000)[7] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[8] = 0x00018005;
  ((volatile unsigned long *)0x48000000)[9] = 0x008C07A3;
  ((volatile unsigned long *)0x48000000)[10] = 0x000000B1;
  ((volatile unsigned long *)0x48000000)[11] = 0x00000030;
  ((volatile unsigned long *)0x48000000)[12] = 0x00000030;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_new_radius>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L28
L27:
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x58(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x50(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x58(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x38(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm2
  movsd  D3(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x50(%rbp),%xmm2
  movsd  D14(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x58(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  D38(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x58(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm2
  movsd  D38(%rip),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  jbe    L4
  movsd  -0x58(%rbp),%xmm0
  jmp    L23
L4:
  movsd  -0x58(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L25
  movsd  -0x58(%rbp),%xmm0
  jmp    L23
L25:
  addl   $0x1,-0x2c(%rbp)
L28:
  cmpl   $0x3e7,-0x2c(%rbp)
  jle    L27
  movsd  -0x58(%rbp),%xmm0
L23:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: f64
name: extract_symbolic_data
arguments: data_tag: D14
type: f32[2]
name: extract_symbolic_data
arguments: data_tag: D38
type: f32[2]

tool: D3: 3

tool: {"D14": [0.0,2.25]}

tool: {"D38": [0.0,12.430511474609375]}

assistant: ```c
double find_new_radius(double a, double b, double c, double d, double r) {
  double f, df, dx, sigma, rold, rzero;
  int i;
  rzero = r;
  for (i = 0; i < 1000; i++) {
    f = a * r + b * r * r + c * r * r * r + d * r * r * r * r - rzero;
    df = a + 2.0 * b * r + 3.0 * c * r * r + 4 * d * r * r * r;
    dx = f / df;
    rold = r;
    r -= dx;
    if ((3000000 - r) * (r - -3000000) < 0.0) {
      return (r);
    }
    if (fabs((r - rold) / rold) < 1e-12) {
      return (r);
    }
  }
  return (r);
}
```