user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x358,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x348(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%r14
  lea    D31(%rip),%r15
  lea    D12(%rip),%r13
  jmp    L219
L113:
  lea    0x10(%rsp),%rdi
  mov    $0x0,%eax
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    0x1b0(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  jle    L229
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L32:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    %eax,%ebp
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L32
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L81
L69:
  mov    $0x0,%r12d
  mov    $0x0,%ebx
L240:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    %eax,%r12d
  cltq
  movl   $0x1,0x1b0(%rsp,%rax,4)
  add    $0x1,%ebx
  mov    0x8(%rsp),%eax
  cmp    %ebx,%eax
  jg     L240
L150:
  lea    0x0(%rbp,%r12,1),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L21
L86:
  cmp    %eax,0x4(%rsp)
  jge    L185
  sub    %ebp,%r12d
  mov    %r12d,%r8d
  shr    $0x1f,%r8d
  add    %r12d,%r8d
  sar    %r8d
  mov    $0x1,%eax
  lea    0x10(%rsp),%rcx
  jmp    L68
L81:
  mov    $0x0,%r12d
  jmp    L150
L21:
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L219
L138:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L209
L68:
  mov    %eax,%esi
  cmpl   $0x1,(%rcx,%rax,4)
  jne    L138
  lea    (%r8,%rax,1),%edx
  movslq %edx,%rdi
  cmpl   $0x1,0x1b0(%rsp,%rdi,4)
  jne    L138
L115:
  test   %esi,%esi
  je     L209
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L219
L185:
  sub    %r12d,%ebp
  mov    %ebp,%r8d
  shr    $0x1f,%r8d
  add    %ebp,%r8d
  sar    %r8d
  mov    $0x1,%eax
  lea    0x1b0(%rsp),%rcx
  jmp    L208
L139:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L209
L208:
  mov    %eax,%edx
  cmpl   $0x1,(%rcx,%rax,4)
  jne    L139
  lea    (%r8,%rax,1),%esi
  movslq %esi,%rdi
  cmpl   $0x1,0x10(%rsp,%rdi,4)
  jne    L139
  jmp    L115
L209:
  mov    %r15,%rdi
  call   <puts@plt>
L219:
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L113
  cmpl   $0x0,0x8(%rsp)
  je     L133
  lea    0x10(%rsp),%rdi
  mov    $0x0,%eax
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    0x1b0(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
L229:
  mov    0x8(%rsp),%eax
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  test   %eax,%eax
  jg     L69
  jmp    L86
L133:
  mov    0x348(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  mov    $0x0,%eax
  add    $0x358,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D28
datatype: string
name: retrieve_data
arguments: data_label: D31
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string

tool: D28: %d %d

tool: D31: -1

tool: D12: %d

tool: D23: %d %d


assistant: ```c
int main(void) {
  int nt, nh, i, temp;
  while (1) {
    scanf("%d %d", &nt, &nh);
    if (nt == 0 && nh == 0)
      break;
    int ct[101] = {0}, ch[101] = {0}, st = 0, sh = 0, flag[2] = {0};
    for (i = 0; i < nt; i++) {
      scanf("%d", &temp);
      st += temp;
      ct[temp] = 1;
    }
    for (i = 0; i < nh; i++) {
      scanf("%d", &temp);
      sh += temp;
      ch[temp] = 1;
    }
    if ((st + sh) % 2 == 1) {
      printf("-1\n");
      continue;
    }
    if (nt < nh) {
      for (i = 1; i <= 100; i++) {
        if (ct[i] == 1 && ch[(sh - st) / 2 + i] == 1) {
          flag[0] = i, flag[1] = (sh - st) / 2 + i;
          break;
        }
      }
    } else {
      for (i = 1; i <= 100; i++) {
        if (ch[i] == 1 && ct[(st - sh) / 2 + i] == 1) {
          flag[0] = (st - sh) / 2 + i, flag[1] = i;
          break;
        }
      }
    }
    if (flag[0] == 0) {
      printf("-1\n");
    } else {
      printf("%d %d\n", flag[0], flag[1]);
    }
  }
  return 0;
}
```