ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<macan_check_cmac>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  js     L2
  mov    %r9d,%eax
  movslq %r8d,%rbx
  sub    $0x8,%rax
  cmp    %rax,%rbx
  jbe    L21
L2:
  lea    0x10(%rsp),%r15
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %r12,%rcx
  mov    %r15,%rdx
  call   <macan_aes_cmac@plt>
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <memchk@plt>
L34:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  call   <macan_get_time@plt>
  lea    (%r12,%rbx,4),%rbx
  lea    -0x1(%rax),%r15
  add    $0x2,%rax
  mov    %rbx,(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rax,0x8(%rsp)
L41:
  mov    %r15,%rdi
  call   <htole32@plt>
  mov    (%rsp),%rcx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %rax,(%rcx)
  mov    %r12,%rcx
  call   <macan_aes_cmac@plt>
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L38
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  jne    L41
  xor    %eax,%eax
  jmp    L34
  nopl   (%rax)
L38:
  mov    $0x1,%eax
  jmp    L34
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int macan_check_cmac(struct macan_ctx *ctx, struct macan_key *skey, const uint8_t *cmac4, uint8_t *plain, int time_index, unsigned len) {
  uint8_t cmac[16];
  uint32_t *time_ptr;
  if (time_index < 0 || (unsigned)time_index > len - sizeof(*time_ptr)) {
    macan_aes_cmac(skey, len, cmac, plain);
    return memchk(cmac4, cmac, 4);
  }
  uint32_t time = (uint32_t)macan_get_time(ctx);
  int delta_t;
  time_ptr = (uint32_t *)&plain[time_index];
  for (delta_t = -1; delta_t <= 1; delta_t++) {
    *time_ptr = htole32(time + (uint32_t)delta_t);
    macan_aes_cmac(skey, len, cmac, plain);
    if (memcmp(cmac4, cmac, 4) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ReadAndEditStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L8
L31:
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xd(%rbp),%eax
  cmp    $0x20,%al
  setne  %dl
  movzbl -0xd(%rbp),%eax
  cmp    $0x9,%al
  setne  %al
  and    %edx,%eax
  movzbl %al,%edx
  movzbl -0xd(%rbp),%eax
  cmp    $0xd,%al
  setne  %al
  movzbl %al,%eax
  and    %eax,%edx
  movzbl -0xd(%rbp),%eax
  cmp    $0xa,%al
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L8
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L8:
  movzbl -0xd(%rbp),%eax
  cmp    $0xa,%al
  jne    L31
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: %c

assistant: ```c
void ReadAndEditStr(char *Str, int StringSize) {
  char Aux;
  int i = 0;
  memset(Str, 0, StringSize);
  while (Aux != '\n') {
    scanf("%c", &Aux);
    if ((Aux != ' ') & (Aux != '\t') & (Aux != '\r') & (Aux != '\n')) {
      Str[i] = Aux;
      i++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReadAndEditStr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x7(%rsp),%rbp
  lea    D0(%rip),%rbx
  movabs $0x100002600,%r12
L28:
  cmpb   $0xa,0x7(%rsp)
  je     L29
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x20,%al
  ja     L14
  bt     %rax,%r12
  jb     L28
L14:
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  jmp    L28
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: %c

assistant: ```c
void ReadAndEditStr(char *Str, int StringSize) {
  char Aux;
  int i = 0;
  memset(Str, 0, StringSize);
  while (Aux != '\n') {
    scanf("%c", &Aux);
    if ((Aux != ' ') & (Aux != '\t') & (Aux != '\r') & (Aux != '\n')) {
      Str[i] = Aux;
      i++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ReadAndEditStr>:
  endbr64
  push   %r13
  mov    %esi,%edx
  xor    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  movabs $0xfffffffeffffd9ff,%r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <memset@plt>
  movzbl 0x7(%rsp),%eax
  nopl   (%rax)
L34:
  cmp    $0xa,%al
  je     L36
L42:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x20,%al
  jbe    L33
L53:
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    $0xa,%al
  jne    L42
  nopl   0x0(%rax)
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  bt     %rax,%r12
  jae    L34
  jmp    L53
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: %c

assistant: ```c
void ReadAndEditStr(char *Str, int StringSize) {
  char Aux;
  int i = 0;
  memset(Str, 0, StringSize);
  while (Aux != '\n') {
    scanf("%c", &Aux);
    if ((Aux != ' ') & (Aux != '\t') & (Aux != '\r') & (Aux != '\n')) {
      Str[i] = Aux;
      i++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ReadAndEditStr>:
  endbr64
  push   %r13
  mov    %esi,%edx
  xor    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  movabs $0xfffffffeffffd9ff,%r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <memset@plt>
  movzbl 0x7(%rsp),%eax
  nopl   (%rax)
L30:
  cmp    $0xa,%al
  je     L45
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x20,%al
  jbe    L50
L23:
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    $0xa,%al
  jne    L1
  nopl   0x0(%rax)
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  bt     %rax,%r12
  jae    L30
  jmp    L23
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %c

assistant: ```c
void ReadAndEditStr(char *Str, int StringSize) {
  char Aux;
  int i = 0;
  memset(Str, 0, StringSize);
  while (Aux != '\n') {
    scanf("%c", &Aux);
    if ((Aux != ' ') & (Aux != '\t') & (Aux != '\r') & (Aux != '\n')) {
      Str[i] = Aux;
      i++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x0,-0x4(%rbp)
  je     L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(char *s1, char *s2) {
  int i = 0, c = 0;
  while (c == 0) {
    c = s1[i] - s2[i];
    i++;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  mov    $0x0,%edx
L4:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  sub    %ecx,%eax
  je     L4
  ret
```

assistant: ```c
int strcmp(char *s1, char *s2) {
  int i = 0, c = 0;
  while (c == 0) {
    c = s1[i] - s2[i];
    i++;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L1:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  sub    %ecx,%eax
  je     L1
  ret
```

assistant: ```c
int strcmp(char *s1, char *s2) {
  int i = 0, c = 0;
  while (c == 0) {
    c = s1[i] - s2[i];
    i++;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsbl (%rdi,%rdx,1),%eax
  movsbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  sub    %ecx,%eax
  je     L4
  ret
```

assistant: ```c
int strcmp(char *s1, char *s2) {
  int i = 0, c = 0;
  while (c == 0) {
    c = s1[i] - s2[i];
    i++;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<draw>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D15(%rip),%rcx
  mov    %rcx,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  movw   $0xeb,0x50(%rsp)
  movw   $0xe1,0x52(%rsp)
  movw   $0xe2,0x54(%rsp)
  movw   $0xd7,0x56(%rsp)
  movw   $0xd8,0x58(%rsp)
  movw   $0xd2,0x5a(%rsp)
  movw   $0xd1,0x5c(%rsp)
  movw   $0xde,0x5e(%rsp)
  movw   $0xdf,0x60(%rsp)
  movw   $0xe0,0x62(%rsp)
  movw   $0xdc,0x64(%rsp)
  movw   $0xdd,0x66(%rsp)
  movw   $0x3b,0x68(%rsp)
  movw   $0x3b,0x6a(%rsp)
  mov    %rdi,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L31
L24:
  mov    0x30(%rsp,%rbx,8),%r13
L77:
  lea    D7(%rip),%rdi
  call   <strlen@plt>
  imul   %r15d,%eax
  mov    %eax,%esi
  mov    0x4(%rsp),%eax
  lea    (%rax,%rbx,1),%edi
  mov    %ebp,%ecx
  mov    %r13,%rdx
  call   <mvprintw@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  je     L70
L18:
  mov    (%r14,%r12,4),%ebp
  test   %ebp,%ebp
  je     L24
  mov    0x10(%rsp,%rbx,8),%r13
  jmp    L77
L70:
  mov    $0x0,%eax
  call   <standend@plt>
  add    $0x1,%r12
  cmp    $0x4,%r12
  je     L47
L83:
  mov    %r12d,%r15d
  movslq (%r14,%r12,4),%rdi
  call   <NTZ@plt>
  cmp    $0x20,%ax
  mov    $0x0,%edx
  cmove  %edx,%eax
  movswq %ax,%rax
  movswl 0x50(%rsp,%rax,2),%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attrset@plt>
  mov    $0x0,%ebx
  jmp    L18
L47:
  addl   $0x3,0x4(%rsp)
  mov    0x4(%rsp),%eax
  addq   $0x10,0x8(%rsp)
  cmp    $0xc,%eax
  je     L25
L31:
  mov    0x8(%rsp),%r14
  mov    $0x0,%r12d
  jmp    L83
L25:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D7:        

tool: D15:   % 4d 

assistant: ```c
int draw(int field[][4]) {
  char *tile[] = {
      "       ",
      "  % 4d ",
      "       ",
  };
  char *waku[] = {
      "       ",
      "       ",
      "       ",
  };
  short colors = 0, color[] = {
                        235, 225, 226, 215, 216, 210, 209, 222, 223, 224, 220, 221, 59, 59,
                    };
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      colors = NTZ((unsigned long)field[i][j]);
      attrset(COLOR_PAIR(color[colors == 32 ? 0 : colors]));
      for (int k = 0; k < (int)(sizeof(waku) / sizeof(waku[0])); k++) {
        mvprintw(i * (int)(sizeof(waku) / sizeof(waku[0])) + k, j * strlen(waku[0]), field[i][j] ? tile[k] : waku[k], field[i][j]);
      }
      standend();
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<draw>:
  endbr64
  push   %r15
  lea    D14(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %r15,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  movabs $0xd700e200e100eb,%rax
  mov    %rax,0x50(%rsp)
  movabs $0xde00d100d200d8,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xdd00dc00e000df,%rax
  mov    %r15,0x20(%rsp)
  mov    %r15,0x30(%rsp)
  mov    %r15,0x38(%rsp)
  mov    %r15,0x40(%rsp)
  mov    %rax,0x60(%rsp)
  movl   $0x3b003b,0x68(%rsp)
  movl   $0x0,0xc(%rsp)
L47:
  xor    %ebp,%ebp
L31:
  movslq (%r12,%rbp,4),%rdi
  mov    %ebp,0x8(%rsp)
  call   <NTZ@plt>
  mov    $0xeb,%edi
  cmp    $0x20,%ax
  je     L51
  movswq %ax,%rax
  movswl 0x50(%rsp,%rax,2),%edi
L51:
  call   <COLOR_PAIR@plt>
  xor    %ebx,%ebx
  mov    %eax,%edi
  call   <attrset@plt>
L42:
  mov    (%r12,%rbp,4),%r14d
  test   %r14d,%r14d
  je     L37
  mov    0x10(%rsp,%rbx,8),%r13
L43:
  mov    %r15,%rdi
  call   <strlen@plt>
  imul   0x8(%rsp),%eax
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %eax,%esi
  mov    0xc(%rsp),%eax
  lea    (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  call   <mvprintw@plt>
  cmp    $0x3,%rbx
  jne    L42
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <standend@plt>
  cmp    $0x4,%rbp
  jne    L31
  addl   $0x3,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x10,%r12
  cmp    $0xc,%eax
  jne    L47
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    0x30(%rsp,%rbx,8),%r13
  jmp    L43
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D14:        

tool: D0:   % 4d 

assistant: ```c
int draw(int field[][4]) {
  char *tile[] = {
      "       ",
      "  % 4d ",
      "       ",
  };
  char *waku[] = {
      "       ",
      "       ",
      "       ",
  };
  short colors = 0, color[] = {
                        235, 225, 226, 215, 216, 210, 209, 222, 223, 224, 220, 221, 59, 59,
                    };
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      colors = NTZ((unsigned long)field[i][j]);
      attrset(COLOR_PAIR(color[colors == 32 ? 0 : colors]));
      for (int k = 0; k < (int)(sizeof(waku) / sizeof(waku[0])); k++) {
        mvprintw(i * (int)(sizeof(waku) / sizeof(waku[0])) + k, j * strlen(waku[0]), field[i][j] ? tile[k] : waku[k], field[i][j]);
      }
      standend();
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<draw>:
  endbr64
  push   %r15
  lea    D3(%rip),%r15
  push   %r14
  movq   %r15,%xmm0
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %r15,0x20(%rsp)
  movq   %rax,%xmm1
  mov    D28(%rip),%rax
  mov    %r15,0x40(%rsp)
  punpcklqdq %xmm1,%xmm0
  movl   $0x3b003b,0x68(%rsp)
  movaps %xmm0,0x10(%rsp)
  movq   %r15,%xmm0
  punpcklqdq %xmm0,%xmm0
  mov    %rax,0x60(%rsp)
  movaps %xmm0,0x30(%rsp)
  movdqa D25(%rip),%xmm0
  movl   $0x0,0xc(%rsp)
  movaps %xmm0,0x50(%rsp)
L54:
  xor    %ebp,%ebp
L21:
  movslq (%r12,%rbp,4),%rdi
  mov    %ebp,0x8(%rsp)
  call   <NTZ@plt>
  mov    $0xeb,%edi
  cmp    $0x20,%ax
  je     L2
  movswq %ax,%rax
  movswl 0x50(%rsp,%rax,2),%edi
L2:
  call   <COLOR_PAIR@plt>
  xor    %ebx,%ebx
  mov    %eax,%edi
  call   <attrset@plt>
L5:
  mov    (%r12,%rbp,4),%r14d
  test   %r14d,%r14d
  je     L55
  mov    0x10(%rsp,%rbx,8),%r13
L13:
  mov    %r15,%rdi
  call   <strlen@plt>
  imul   0x8(%rsp),%eax
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %eax,%esi
  mov    0xc(%rsp),%eax
  lea    (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  call   <mvprintw@plt>
  cmp    $0x3,%rbx
  jne    L5
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <standend@plt>
  cmp    $0x4,%rbp
  jne    L21
  addl   $0x3,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x10,%r12
  cmp    $0xc,%eax
  jne    L54
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L55:
  mov    0x30(%rsp,%rbx,8),%r13
  jmp    L13
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D28
type_guessed: byte[8]
name: read_data
arguments: tag: D25
type_guessed: byte[16]

tool: D3:        

tool: D10:   % 4d 

tool: {"D28": [0xdf,0x00,0xe0,0x00,0xdc,0x00,0xdd,0x00]}

tool: {"D25": [0xeb,0x00,0xe1,0x00,0xe2,0x00,0xd7,0x00,0xd8,0x00,0xd2,0x00,0xd1,0x00,0xde,0x00]}

assistant: ```c
int draw(int field[][4]) {
  char *tile[] = {
      "       ",
      "  % 4d ",
      "       ",
  };
  char *waku[] = {
      "       ",
      "       ",
      "       ",
  };
  short colors = 0, color[] = {
                        235, 225, 226, 215, 216, 210, 209, 222, 223, 224, 220, 221, 59, 59,
                    };
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      colors = NTZ((unsigned long)field[i][j]);
      attrset(COLOR_PAIR(color[colors == 32 ? 0 : colors]));
      for (int k = 0; k < (int)(sizeof(waku) / sizeof(waku[0])); k++) {
        mvprintw(i * (int)(sizeof(waku) / sizeof(waku[0])) + k, j * strlen(waku[0]), field[i][j] ? tile[k] : waku[k], field[i][j]);
      }
      standend();
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  movq   $0x0,0x8(%rax)
  movl   $0x0,0x10(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%rax
  movl   $0x2,0x4(%rax)
  mov    -0x28(%rbp),%rax
  movss  D2(%rip),%xmm0
  movss  %xmm0,0x8(%rax)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x40,0x40]}

assistant: ```c
struct D {
  int i, j;
  float f, g, h;
} i() {
  return (struct D){1, 2, 3};
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i>:
  endbr64
  mov    %rdi,%rax
  movq   $0x0,0xc(%rdi)
  movl   $0x1,(%rdi)
  movl   $0x2,0x4(%rdi)
  movl   $0x40400000,0x8(%rdi)
  ret
```

assistant: ```c
struct D {
  int i, j;
  float f, g, h;
} i() {
  return (struct D){1, 2, 3};
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i>:
  endbr64
  movabs $0x200000001,%rdx
  movq   $0x40400000,0x8(%rdi)
  mov    %rdi,%rax
  mov    %rdx,(%rdi)
  movl   $0x0,0x10(%rdi)
  ret
```

assistant: ```c
struct D {
  int i, j;
  float f, g, h;
} i() {
  return (struct D){1, 2, 3};
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i>:
  endbr64
  mov    D3(%rip),%rdx
  movq   $0x0,0xc(%rdi)
  mov    %rdi,%rax
  movl   $0x40400000,0x8(%rdi)
  mov    %rdx,(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: byte[8]

tool: {"D3": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
struct D {
  int i, j;
  float f, g, h;
} i() {
  return (struct D){1, 2, 3};
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wcsdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wcscpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
wchar_t *wcsdup(const wchar_t *string) {
  wchar_t *result;
  assert(string);
  result = (wchar_t *)malloc((wcslen(string) + 1) * sizeof(wchar_t));
  wcscpy(result, string);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wcsdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <wcslen@plt>
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <wcscpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
wchar_t *wcsdup(const wchar_t *string) {
  wchar_t *result;
  assert(string);
  result = (wchar_t *)malloc((wcslen(string) + 1) * sizeof(wchar_t));
  wcscpy(result, string);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wcsdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <wcslen@plt>
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <wcscpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *wcsdup(const wchar_t *string) {
  wchar_t *result;
  assert(string);
  result = (wchar_t *)malloc((wcslen(string) + 1) * sizeof(wchar_t));
  wcscpy(result, string);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wcsdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <wcslen@plt>
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <wcscpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *wcsdup(const wchar_t *string) {
  wchar_t *result;
  assert(string);
  result = (wchar_t *)malloc((wcslen(string) + 1) * sizeof(wchar_t));
  wcscpy(result, string);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<determineMatchResult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L45
  mov    $0xffffffff,%eax
  jmp    L40
L45:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x70,%al
  jne    L21
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x72,%al
  jne    L21
  mov    -0x4(%rbp),%eax
  jmp    L40
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x72,%al
  jne    L71
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L71
  mov    -0x4(%rbp),%eax
  jmp    L40
L71:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x73,%al
  jne    L62
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x70,%al
  jne    L62
  mov    -0x4(%rbp),%eax
  jmp    L40
L62:
  mov    -0x8(%rbp),%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int determineMatchResult(int idOne, char choiceOne[], int idTwo, char choiceTwo[]) {
  if (choiceOne[0] == choiceTwo[0])
    return -1;
  if (choiceOne[0] == 'p' && choiceTwo[0] == 'r')
    return idOne;
  if (choiceOne[0] == 'r' && choiceTwo[0] == 's')
    return idOne;
  if (choiceOne[0] == 's' && choiceTwo[0] == 'p')
    return idOne;
  return idTwo;
}
```