ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<_divides>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <__CrestCall@plt>
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <__CrestStore@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <__CrestStore@plt>
  movslq 0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x8,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbx,%rsi
  mov    $0x7,%edi
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  cltd
  idivl  0xc(%rsp)
  movslq %edx,%rdx
  mov    $0x4,%esi
  mov    $0x6,%edi
  call   <__CrestApply2@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x5,%edi
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  cltd
  idivl  0xc(%rsp)
  test   %edx,%edx
  sete   %dl
  movzbl %dl,%edx
  mov    $0xc,%esi
  mov    $0x4,%edi
  call   <__CrestApply2@plt>
  lea    0x14(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x9,%edi
  call   <__CrestStore@plt>
  mov    0x8(%rsp),%eax
  cltd
  idivl  0xc(%rsp)
  test   %edx,%edx
  sete   %al
  movzbl %al,%eax
  mov    %eax,0x14(%rsp)
  sete   %dl
  movzbl %dl,%edx
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <__CrestLoad@plt>
  mov    $0xb,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _divides(int n, int m) {
  int __retres3;
  {
    __CrestCall(3, 1);
    __CrestStore(2, (unsigned long)(&m));
    __CrestStore(1, (unsigned long)(&n));
    __CrestLoad(8, (unsigned long)(&m), (long long)m);
    __CrestLoad(7, (unsigned long)(&n), (long long)n);
    __CrestApply2(6, 4, (long long)(m % n));
    __CrestLoad(5, (unsigned long)0, (long long)0);
    __CrestApply2(4, 12, (long long)(m % n == 0));
    __CrestStore(9, (unsigned long)(&__retres3));
    __retres3 = m % n == 0;
    {
      __CrestLoad(10, (unsigned long)(&__retres3), (long long)__retres3);
      __CrestReturn(11);
      return (__retres3);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_divides>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%r12
  mov    $0x3,%edi
  lea    0xc(%rsp),%rbp
  mov    %esi,0x8(%rsp)
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <__CrestCall@plt>
  mov    %r12,%rsi
  mov    $0x2,%edi
  call   <__CrestStore@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <__CrestStore@plt>
  movslq 0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    $0x8,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x7,%edi
  lea    0x14(%rsp),%rbp
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  mov    $0x4,%esi
  mov    $0x6,%edi
  cltd
  idivl  0xc(%rsp)
  movslq %edx,%rdx
  call   <__CrestApply2@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x5,%edi
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  mov    $0xc,%esi
  mov    $0x4,%edi
  cltd
  idivl  0xc(%rsp)
  test   %edx,%edx
  sete   %dl
  movzbl %dl,%edx
  call   <__CrestApply2@plt>
  mov    %rbp,%rsi
  mov    $0x9,%edi
  call   <__CrestStore@plt>
  mov    0x8(%rsp),%eax
  mov    %rbp,%rsi
  mov    $0xa,%edi
  cltd
  idivl  0xc(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  sete   %dl
  sete   %al
  movzbl %dl,%edx
  mov    %eax,0x14(%rsp)
  call   <__CrestLoad@plt>
  mov    $0xb,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _divides(int n, int m) {
  int __retres3;
  {
    __CrestCall(3, 1);
    __CrestStore(2, (unsigned long)(&m));
    __CrestStore(1, (unsigned long)(&n));
    __CrestLoad(8, (unsigned long)(&m), (long long)m);
    __CrestLoad(7, (unsigned long)(&n), (long long)n);
    __CrestApply2(6, 4, (long long)(m % n));
    __CrestLoad(5, (unsigned long)0, (long long)0);
    __CrestApply2(4, 12, (long long)(m % n == 0));
    __CrestStore(9, (unsigned long)(&__retres3));
    __retres3 = m % n == 0;
    {
      __CrestLoad(10, (unsigned long)(&__retres3), (long long)__retres3);
      __CrestReturn(11);
      return (__retres3);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_divides>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%r12
  mov    $0x3,%edi
  lea    0xc(%rsp),%rbp
  mov    %esi,0x8(%rsp)
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <__CrestCall@plt>
  mov    %r12,%rsi
  mov    $0x2,%edi
  call   <__CrestStore@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <__CrestStore@plt>
  movslq 0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    $0x8,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x7,%edi
  lea    0x14(%rsp),%rbp
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  mov    $0x4,%esi
  mov    $0x6,%edi
  cltd
  idivl  0xc(%rsp)
  movslq %edx,%rdx
  call   <__CrestApply2@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x5,%edi
  call   <__CrestLoad@plt>
  mov    0x8(%rsp),%eax
  mov    $0xc,%esi
  mov    $0x4,%edi
  cltd
  idivl  0xc(%rsp)
  test   %edx,%edx
  sete   %dl
  movzbl %dl,%edx
  call   <__CrestApply2@plt>
  mov    %rbp,%rsi
  mov    $0x9,%edi
  call   <__CrestStore@plt>
  mov    0x8(%rsp),%eax
  mov    %rbp,%rsi
  mov    $0xa,%edi
  cltd
  idivl  0xc(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  sete   %dl
  sete   %al
  movzbl %dl,%edx
  mov    %eax,0x14(%rsp)
  call   <__CrestLoad@plt>
  mov    $0xb,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _divides(int n, int m) {
  int __retres3;
  {
    __CrestCall(3, 1);
    __CrestStore(2, (unsigned long)(&m));
    __CrestStore(1, (unsigned long)(&n));
    __CrestLoad(8, (unsigned long)(&m), (long long)m);
    __CrestLoad(7, (unsigned long)(&n), (long long)n);
    __CrestApply2(6, 4, (long long)(m % n));
    __CrestLoad(5, (unsigned long)0, (long long)0);
    __CrestApply2(4, 12, (long long)(m % n == 0));
    __CrestStore(9, (unsigned long)(&__retres3));
    __retres3 = m % n == 0;
    {
      __CrestLoad(10, (unsigned long)(&__retres3), (long long)__retres3);
      __CrestReturn(11);
      return (__retres3);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  nop
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test(unsigned long b) {
  int a;
  asm volatile("nop " : "=a"(a) : "0"(b));
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  mov    %rdi,%rax
  nop
  ret
```

assistant: ```c
int test(unsigned long b) {
  int a;
  asm volatile("nop " : "=a"(a) : "0"(b));
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  mov    %rdi,%rax
  nop
  ret
```

assistant: ```c
int test(unsigned long b) {
  int a;
  asm volatile("nop " : "=a"(a) : "0"(b));
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  mov    %rdi,%rax
  nop
  ret
```

assistant: ```c
int test(unsigned long b) {
  int a;
  asm volatile("nop " : "=a"(a) : "0"(b));
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x3(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  mov    $0x0,%eax
  call   <prompt_bread@plt>
  mov    %al,-0x3(%rbp)
  mov    $0x0,%eax
  call   <prompt_double@plt>
  mov    %al,-0x2(%rbp)
  mov    $0x0,%eax
  call   <prompt_manual@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x77,-0x3(%rbp)
  jne    L11
  movsbl -0x1(%rbp),%edx
  movsbl -0x2(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <white_bread_main@plt>
  jmp    L13
L11:
  movsbl -0x1(%rbp),%edx
  movsbl -0x2(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sweet_bread_main@plt>
L13:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char bread_type = '\0', double_size = '\0', manual_bake = '\0';
  bread_type = prompt_bread();
  double_size = prompt_double();
  manual_bake = prompt_manual();
  if (bread_type == 'w') {
    white_bread_main(double_size, manual_bake);
  } else {
    sweet_bread_main(double_size, manual_bake);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prompt_bread@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <prompt_double@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <prompt_manual@plt>
  cmp    $0x77,%bpl
  je     L16
  movsbl %al,%esi
  movsbl %bl,%edi
  call   <sweet_bread_main@plt>
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  movsbl %al,%esi
  movsbl %bl,%edi
  call   <white_bread_main@plt>
  jmp    L13
```

assistant: ```c
int main(void) {
  char bread_type = '\0', double_size = '\0', manual_bake = '\0';
  bread_type = prompt_bread();
  double_size = prompt_double();
  manual_bake = prompt_manual();
  if (bread_type == 'w') {
    white_bread_main(double_size, manual_bake);
  } else {
    sweet_bread_main(double_size, manual_bake);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <prompt_bread@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <prompt_double@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <prompt_manual@plt>
  movsbl %bl,%edi
  movsbl %al,%esi
  cmp    $0x77,%bpl
  je     L1
  call   <sweet_bread_main@plt>
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <white_bread_main@plt>
  jmp    L13
```

assistant: ```c
int main(void) {
  char bread_type = '\0', double_size = '\0', manual_bake = '\0';
  bread_type = prompt_bread();
  double_size = prompt_double();
  manual_bake = prompt_manual();
  if (bread_type == 'w') {
    white_bread_main(double_size, manual_bake);
  } else {
    sweet_bread_main(double_size, manual_bake);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <prompt_bread@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <prompt_double@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <prompt_manual@plt>
  movsbl %bl,%edi
  movsbl %al,%esi
  cmp    $0x77,%bpl
  je     L18
  call   <sweet_bread_main@plt>
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <white_bread_main@plt>
  jmp    L10
```

assistant: ```c
int main(void) {
  char bread_type = '\0', double_size = '\0', manual_bake = '\0';
  bread_type = prompt_bread();
  double_size = prompt_double();
  manual_bake = prompt_manual();
  if (bread_type == 'w') {
    white_bread_main(double_size, manual_bake);
  } else {
    sweet_bread_main(double_size, manual_bake);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zigzag32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    -0x4(%rbp),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  sub    $0x1,%eax
  jmp    L10
L4:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t zigzag32(int32_t v) {
  if (v < 0)
    return ((uint32_t)(-v)) * 2 - 1;
  else
    return v * 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zigzag32>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  test   %edi,%edi
  js     L1
L9:
  ret
L1:
  neg    %edi
  lea    -0x1(%rdi,%rdi,1),%eax
  jmp    L9
```

assistant: ```c
uint32_t zigzag32(int32_t v) {
  if (v < 0)
    return ((uint32_t)(-v)) * 2 - 1;
  else
    return v * 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zigzag32>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  test   %edi,%edi
  js     L6
  ret
  nopl   0x0(%rax)
L6:
  neg    %edi
  lea    -0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
uint32_t zigzag32(int32_t v) {
  if (v < 0)
    return ((uint32_t)(-v)) * 2 - 1;
  else
    return v * 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zigzag32>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  test   %edi,%edi
  js     L0
  ret
  nopl   0x0(%rax)
L0:
  neg    %edi
  lea    -0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
uint32_t zigzag32(int32_t v) {
  if (v < 0)
    return ((uint32_t)(-v)) * 2 - 1;
  else
    return v * 2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<timespec_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L30
  mov    $0x1,%eax
  jmp    L34
L30:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L40
  mov    $0xffffffff,%eax
  jmp    L34
L40:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jle    L29
  mov    $0x1,%eax
  jmp    L34
L29:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jge    L9
  mov    $0xffffffff,%eax
  jmp    L34
L9:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int timespec_compare(const struct timespec *ts1, const struct timespec *ts2) {
  if (ts1->tv_sec > ts2->tv_sec)
    return 1;
  if (ts1->tv_sec < ts2->tv_sec)
    return -1;
  if (ts1->tv_nsec > ts2->tv_nsec)
    return 1;
  if (ts1->tv_nsec < ts2->tv_nsec)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_compare>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L18
  mov    $0xffffffff,%eax
  jl     L18
  mov    0x8(%rdi),%rcx
  mov    0x8(%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jg     L18
  setl   %al
  movzbl %al,%eax
  neg    %eax
L18:
  ret
```

assistant: ```c
int timespec_compare(const struct timespec *ts1, const struct timespec *ts2) {
  if (ts1->tv_sec > ts2->tv_sec)
    return 1;
  if (ts1->tv_sec < ts2->tv_sec)
    return -1;
  if (ts1->tv_nsec > ts2->tv_nsec)
    return 1;
  if (ts1->tv_nsec < ts2->tv_nsec)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timespec_compare>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jg     L23
  mov    $0xffffffff,%eax
  jl     L23
  mov    0x8(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x8(%rdi)
  jg     L23
  setl   %al
  movzbl %al,%eax
  neg    %eax
L23:
  ret
```

assistant: ```c
int timespec_compare(const struct timespec *ts1, const struct timespec *ts2) {
  if (ts1->tv_sec > ts2->tv_sec)
    return 1;
  if (ts1->tv_sec < ts2->tv_sec)
    return -1;
  if (ts1->tv_nsec > ts2->tv_nsec)
    return 1;
  if (ts1->tv_nsec < ts2->tv_nsec)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timespec_compare>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jg     L26
  mov    $0xffffffff,%eax
  jl     L26
  mov    0x8(%rsi),%rcx
  mov    $0x1,%eax
  cmp    %rcx,0x8(%rdi)
  jg     L26
  setl   %al
  movzbl %al,%eax
  neg    %eax
L26:
  ret
```

assistant: ```c
int timespec_compare(const struct timespec *ts1, const struct timespec *ts2) {
  if (ts1->tv_sec > ts2->tv_sec)
    return 1;
  if (ts1->tv_sec < ts2->tv_sec)
    return -1;
  if (ts1->tv_nsec > ts2->tv_nsec)
    return 1;
  if (ts1->tv_nsec < ts2->tv_nsec)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3e7,%ebx
  lea    0x11(%rsp),%r12
  jmp    L22
L28:
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%edx
  mov    %r13d,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L41
L19:
  cmp    $0x1,%ebx
  je     L69
L22:
  mov    %ebx,%r15d
  imul   %ebx,%r15d
  mov    %ebx,%r13d
  sub    $0x1,%ebx
  mov    %ebx,%r14d
  imul   %r13d,%r14d
  lea    0xa(%rsp),%rbp
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x7,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r15d,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r14d,%edx
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <is_palindrome@plt>
  cmp    $0x1,%eax
  je     L28
L41:
  mov    %r12,%rdi
  call   <is_palindrome@plt>
  cmp    $0x1,%eax
  jne    L19
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edx
  mov    %r13d,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L19
L69:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D34: Largest 3-digit palindrome: 

tool: D3: Found by multiplying %d and %d


tool: D19: %d

assistant: ```c
int main() {
  int i, j, cur1, cur2;
  i = 999;
  while (i > 1) {
    cur1 = i * i;
    cur2 = i * (i - 1);
    char cur_str1[7];
    char cur_str2[7];
    memset(cur_str1, 0, 7);
    memset(cur_str2, 0, 7);
    sprintf(cur_str1, "%d", cur1);
    sprintf(cur_str2, "%d", cur2);
    if (is_palindrome(cur_str1) == 1) {
      printf("Largest 3-digit palindrome: ");
      printf(cur_str1);
      printf("\n");
      printf("Found by multiplying %d and %d\n", i, i);
      exit(0);
    }
    if (is_palindrome(cur_str2) == 1) {
      printf("Largest 3-digit palindrome: ");
      printf(cur_str2);
      printf("\n");
      printf("Found by multiplying %d and %d\n", i, (i - 1));
      exit(0);
    }
    i--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x3e7,%r14d
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1a(%rsp),%rbp
  lea    0x21(%rsp),%rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  call   <is_palindrome@plt>
  cmp    $0x1,%eax
  je     L20
L34:
  cmp    $0x1,%r14d
  je     L49
L26:
  mov    %r14d,%r9d
  mov    %r14d,%r12d
  xor    %esi,%esi
  mov    $0x7,%edx
  imul   %r14d,%r9d
  sub    $0x1,%r14d
  mov    %rbp,%rdi
  mov    %r14d,%r15d
  imul   %r12d,%r15d
  mov    %r9d,0xc(%rsp)
  call   <memset@plt>
  xor    %esi,%esi
  mov    $0x7,%edx
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  mov    %r15d,%edx
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <is_palindrome@plt>
  cmp    $0x1,%eax
  jne    L8
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    %rbx,%rdi
  call   <is_palindrome@plt>
  cmp    $0x1,%eax
  jne    L34
L20:
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  mov    %r14d,%edx
  mov    %r12d,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    $0x1,%r14d
  jne    L26
L49:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D46
type_guessed: string

tool: D18: %d

tool: D36: Largest 3-digit palindrome: 

tool: D46: Found by multiplying %d and %d


assistant: ```c
int main() {
  int i, j, cur1, cur2;
  i = 999;
  while (i > 1) {
    cur1 = i * i;
    cur2 = i * (i - 1);
    char cur_str1[7];
    char cur_str2[7];
    memset(cur_str1, 0, 7);
    memset(cur_str2, 0, 7);
    sprintf(cur_str1, "%d", cur1);
    sprintf(cur_str2, "%d", cur2);
    if (is_palindrome(cur_str1) == 1) {
      printf("Largest 3-digit palindrome: ");
      printf(cur_str1);
      printf("\n");
      printf("Found by multiplying %d and %d\n", i, i);
      exit(0);
    }
    if (is_palindrome(cur_str2) == 1) {
      printf("Largest 3-digit palindrome: ");
      printf(cur_str2);
      printf("\n");
      printf("Found by multiplying %d and %d\n", i, (i - 1));
      exit(0);
    }
    i--;
  }
}
```