ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_dstdep_mask>:
  endbr64
  mov    $0x0,%r8d
  test   $0x4,%dil
  je     L7
  mov    %esi,%ecx
  sar    $0x3,%ecx
  mov    %ecx,%eax
  and    $0x7,%eax
  and    $0x3,%ecx
  test   %edx,%edx
  cmove  %eax,%ecx
  mov    $0x1,%r8d
  shl    %cl,%r8d
L7:
  test   $0x8,%dil
  je     L3
  mov    %esi,%eax
  and    $0x7,%eax
  and    $0x3,%esi
  test   %edx,%edx
  cmovne %esi,%eax
  mov    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%r8d
L3:
  mov    %rdi,%rax
  shr    $0xc,%rax
  movzbl %al,%eax
  or     %r8d,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x400000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x800000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x110,%edx
  test   $0x200000,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint32_t get_dstdep_mask(uint64_t data, uint32_t fetchdat, int bit8) {
  uint32_t mask = 0;
  if (data & (1ull << 2)) {
    int reg = (fetchdat >> 3) & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  if (data & (1ull << 3)) {
    int reg = fetchdat & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  mask |= ((data >> 12) & 0xff);
  if (data & (1ull << 22))
    mask |= (1 << 9);
  if (data & (1ull << 23))
    mask |= (1 << 9);
  if (data & (1ull << 21))
    mask |= (1 << 8) | (1 << 4);
  return mask;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_dstdep_mask>:
  endbr64
  xor    %r8d,%r8d
  test   $0x4,%dil
  je     L18
  mov    %esi,%ecx
  mov    $0x1,%r8d
  sar    $0x3,%ecx
  mov    %ecx,%eax
  and    $0x3,%ecx
  and    $0x7,%eax
  test   %edx,%edx
  cmove  %eax,%ecx
  shl    %cl,%r8d
L18:
  test   $0x8,%dil
  je     L5
  mov    %esi,%eax
  and    $0x3,%esi
  and    $0x7,%eax
  test   %edx,%edx
  cmovne %esi,%eax
  mov    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%r8d
L5:
  mov    %rdi,%rax
  shr    $0xc,%rax
  movzbl %al,%eax
  or     %r8d,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x400000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x800000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x110,%edx
  test   $0x200000,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint32_t get_dstdep_mask(uint64_t data, uint32_t fetchdat, int bit8) {
  uint32_t mask = 0;
  if (data & (1ull << 2)) {
    int reg = (fetchdat >> 3) & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  if (data & (1ull << 3)) {
    int reg = fetchdat & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  mask |= ((data >> 12) & 0xff);
  if (data & (1ull << 22))
    mask |= (1 << 9);
  if (data & (1ull << 23))
    mask |= (1 << 9);
  if (data & (1ull << 21))
    mask |= (1 << 8) | (1 << 4);
  return mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_dstdep_mask>:
  endbr64
  xor    %r8d,%r8d
  test   $0x4,%dil
  je     L18
  mov    %esi,%ecx
  mov    $0x1,%r8d
  sar    $0x3,%ecx
  mov    %ecx,%eax
  and    $0x3,%ecx
  and    $0x7,%eax
  test   %edx,%edx
  cmove  %eax,%ecx
  shl    %cl,%r8d
L18:
  test   $0x8,%dil
  je     L12
  mov    %esi,%eax
  and    $0x3,%esi
  and    $0x7,%eax
  test   %edx,%edx
  cmovne %esi,%eax
  mov    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%r8d
L12:
  mov    %rdi,%rax
  shr    $0xc,%rax
  movzbl %al,%eax
  or     %r8d,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x400000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x800000,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x110,%edx
  test   $0x200000,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint32_t get_dstdep_mask(uint64_t data, uint32_t fetchdat, int bit8) {
  uint32_t mask = 0;
  if (data & (1ull << 2)) {
    int reg = (fetchdat >> 3) & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  if (data & (1ull << 3)) {
    int reg = fetchdat & 7;
    if (bit8)
      reg &= 3;
    mask |= (1 << reg);
  }
  mask |= ((data >> 12) & 0xff);
  if (data & (1ull << 22))
    mask |= (1 << 9);
  if (data & (1ull << 23))
    mask |= (1 << 9);
  if (data & (1ull << 21))
    mask |= (1 << 8) | (1 << 4);
  return mask;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  setg   %al
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%cl
  setl   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_chars(const void *l1, const void *l2) {
  const char *la = (const char *)l1;
  const char *lb = (const char *)l2;
  return ((*la > *lb) - (*la < *lb));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_chars>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  setg   %al
  movzbl %al,%eax
  setl   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_chars(const void *l1, const void *l2) {
  const char *la = (const char *)l1;
  const char *lb = (const char *)l2;
  return ((*la > *lb) - (*la < *lb));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compare_chars>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  setg   %al
  setl   %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_chars(const void *l1, const void *l2) {
  const char *la = (const char *)l1;
  const char *lb = (const char *)l2;
  return ((*la > *lb) - (*la < *lb));
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_chars>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  setg   %al
  setl   %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_chars(const void *l1, const void *l2) {
  const char *la = (const char *)l1;
  const char *lb = (const char *)l2;
  return ((*la > *lb) - (*la < *lb));
}
```
user: What is the c source code of the assembly code below?

```asm
<vectorScale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movslq %eax,%rcx
  imul   $0xffffffff84210843,%rcx,%rcx
  shr    $0x20,%rcx
  add    %eax,%ecx
  sar    $0x5,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x2,-0x4(%rbp)
  jle    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vectorScale(int *input, int *scale, int *output) {
  int i;
  for (i = 0; i < 3; i++) {
    output[i] = input[i] * (*scale) / 62;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vectorScale>:
  endbr64
  mov    %rdi,%r8
  mov    $0x0,%edi
L6:
  mov    (%r8,%rdi,1),%ecx
  imul   (%rsi),%ecx
  movslq %ecx,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x5,%eax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rdx,%rdi,1)
  add    $0x4,%rdi
  cmp    $0xc,%rdi
  jne    L6
  ret
```

assistant: ```c
void vectorScale(int *input, int *scale, int *output) {
  int i;
  for (i = 0; i < 3; i++) {
    output[i] = input[i] * (*scale) / 62;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vectorScale>:
  endbr64
  mov    %rdi,%r8
  xor    %edi,%edi
L3:
  mov    (%r8,%rdi,1),%ecx
  imul   (%rsi),%ecx
  movslq %ecx,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x1f,%ecx
  sar    $0x5,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx,%rdi,1)
  add    $0x4,%rdi
  cmp    $0xc,%rdi
  jne    L3
  ret
```

assistant: ```c
void vectorScale(int *input, int *scale, int *output) {
  int i;
  for (i = 0; i < 3; i++) {
    output[i] = input[i] * (*scale) / 62;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vectorScale>:
  endbr64
  mov    %rdi,%rcx
  mov    (%rsi),%edi
  imul   (%rcx),%edi
  movslq %edi,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x5,%eax
  sub    %edi,%eax
  mov    %eax,(%rdx)
  mov    0x4(%rcx),%edi
  imul   (%rsi),%edi
  movslq %edi,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x1f,%edi
  sar    $0x5,%eax
  sub    %edi,%eax
  mov    %eax,0x4(%rdx)
  mov    0x8(%rcx),%ecx
  imul   (%rsi),%ecx
  movslq %ecx,%rax
  imul   $0xffffffff84210843,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x1f,%ecx
  sar    $0x5,%eax
  sub    %ecx,%eax
  mov    %eax,0x8(%rdx)
  ret
```

assistant: ```c
void vectorScale(int *input, int *scale, int *output) {
  int i;
  for (i = 0; i < 3; i++) {
    output[i] = input[i] * (*scale) / 62;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sort>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <sort>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <merge@plt>
  jmp    L6
L9:
  nop
L6:
  leave
  ret
```

assistant: ```c
void sort(long long int l, long long int r) {
  long long int mid = (l + r) / 2;
  if (l == r)
    return;
  else {
    sort(l, mid);
    sort(mid + 1, r);
    merge(l, mid, mid + 1, r);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sort>:
  endbr64
  cmp    %rsi,%rdi
  je     L3
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    (%rdi,%rsi,1),%rax
  mov    %rax,%r12
  shr    $0x3f,%r12
  add    %rax,%r12
  sar    %r12
  mov    %r12,%rsi
  call   <sort>
  lea    0x1(%r12),%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <sort>
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  ret
```

assistant: ```c
void sort(long long int l, long long int r) {
  long long int mid = (l + r) / 2;
  if (l == r)
    return;
  else {
    sort(l, mid);
    sort(mid + 1, r);
    merge(l, mid, mid + 1, r);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cvt_l_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  je     L43
  cmp    $0x3,%eax
  jg     L68
  cmp    $0x2,%eax
  je     L97
  cmp    $0x2,%eax
  jg     L68
  test   %eax,%eax
  je     L78
  cmp    $0x1,%eax
  je     L47
  jmp    L68
L78:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <round_l_s@plt>
  jmp    L68
L47:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <trunc_l_s@plt>
  jmp    L68
L97:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ceil_l_s@plt>
  jmp    L68
L43:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <floor_l_s@plt>
  nop
L68:
  leave
  ret
```

assistant: ```c
void cvt_l_s(const uint32_t *fcr31, const float *source, int64_t *dest) {
  switch (*fcr31 & 3) {
  case 0:
    round_l_s(source, dest);
    return;
  case 1:
    trunc_l_s(source, dest);
    return;
  case 2:
    ceil_l_s(source, dest);
    return;
  case 3:
    floor_l_s(source, dest);
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cvt_l_s>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    (%rax),%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L22
  jg     L66
  test   %eax,%eax
  je     L58
  cmp    $0x1,%eax
  jne    L14
  call   <trunc_l_s@plt>
  jmp    L14
L58:
  call   <round_l_s@plt>
L14:
  add    $0x8,%rsp
  ret
L22:
  call   <ceil_l_s@plt>
  jmp    L14
L66:
  call   <floor_l_s@plt>
  jmp    L14
```

assistant: ```c
void cvt_l_s(const uint32_t *fcr31, const float *source, int64_t *dest) {
  switch (*fcr31 & 3) {
  case 0:
    round_l_s(source, dest);
    return;
  case 1:
    trunc_l_s(source, dest);
    return;
  case 2:
    ceil_l_s(source, dest);
    return;
  case 3:
    floor_l_s(source, dest);
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cvt_l_s>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    (%r8),%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L17
  cmp    $0x3,%eax
  je     L8
  cmp    $0x1,%eax
  je     L24
  jmp    1090 <round_l_s@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  jmp    10a0 <ceil_l_s@plt>
  nopl   (%rax)
L24:
  jmp    10b0 <trunc_l_s@plt>
  nopl   (%rax)
L8:
  jmp    1080 <floor_l_s@plt>
```

assistant: ```c
void cvt_l_s(const uint32_t *fcr31, const float *source, int64_t *dest) {
  switch (*fcr31 & 3) {
  case 0:
    round_l_s(source, dest);
    return;
  case 1:
    trunc_l_s(source, dest);
    return;
  case 2:
    ceil_l_s(source, dest);
    return;
  case 3:
    floor_l_s(source, dest);
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvt_l_s>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    (%r8),%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L9
  cmp    $0x3,%eax
  je     L11
  cmp    $0x1,%eax
  je     L28
  jmp    1090 <round_l_s@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  jmp    10a0 <ceil_l_s@plt>
  nopl   (%rax)
L28:
  jmp    10b0 <trunc_l_s@plt>
  nopl   (%rax)
L11:
  jmp    1080 <floor_l_s@plt>
```

assistant: ```c
void cvt_l_s(const uint32_t *fcr31, const float *source, int64_t *dest) {
  switch (*fcr31 & 3) {
  case 0:
    round_l_s(source, dest);
    return;
  case 1:
    trunc_l_s(source, dest);
    return;
  case 2:
    ceil_l_s(source, dest);
    return;
  case 3:
    floor_l_s(source, dest);
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uart_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L3
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_putc@plt>
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_puts(const char *s) {
  while (*s)
    uart_putc(*s++);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L15
L9:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <uart_putc@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L15:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(const char *s) {
  while (*s)
    uart_putc(*s++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
L18:
  call   <uart_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L18
L3:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(const char *s) {
  while (*s)
    uart_putc(*s++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L2:
  call   <uart_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L2
L9:
  pop    %rbx
  ret
```

assistant: ```c
void uart_puts(const char *s) {
  while (*s)
    uart_putc(*s++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x2,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L82
  mov    -0x14(%rbp),%eax
  jmp    L60
L82:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L49
  mov    -0x14(%rbp),%eax
  jmp    L60
L49:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L44
  mov    -0x14(%rbp),%eax
  jmp    L60
L44:
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x3,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L36
  mov    -0x14(%rbp),%eax
  jmp    L60
L36:
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L55
  mov    -0x14(%rbp),%eax
  jmp    L60
L55:
  mov    $0x0,%eax
L60:
  pop    %rbp
  ret
```

assistant: ```c
int cmp4(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmp4>:
  endbr64
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L8
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L8
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L8
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L8
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L8:
  ret
```

assistant: ```c
int cmp4(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmp4>:
  endbr64
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L12
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L12
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L12
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L12
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L12:
  ret
```

assistant: ```c
int cmp4(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmp4>:
  endbr64
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L30
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L30
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L30
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
  jne    L30
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
L30:
  ret
```

assistant: ```c
int cmp4(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<load_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
float load_float(unsigned char **bufferp) {
  unsigned char *buffer = *bufferp;
  float f;
  memcpy(&f, buffer, 4);
  *bufferp += 4;
  return f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<load_float>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    (%rbx),%rsi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float load_float(unsigned char **bufferp) {
  unsigned char *buffer = *bufferp;
  float f;
  memcpy(&f, buffer, 4);
  *bufferp += 4;
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<load_float>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float load_float(unsigned char **bufferp) {
  unsigned char *buffer = *bufferp;
  float f;
  memcpy(&f, buffer, 4);
  *bufferp += 4;
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<load_float>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float load_float(unsigned char **bufferp) {
  unsigned char *buffer = *bufferp;
  float f;
  memcpy(&f, buffer, 4);
  *bufferp += 4;
  return f;
}
```