ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<xread>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%ebx
  jmp    L39
L59:
  mov    D2(%rip),%rdx
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L12
L49:
  cmp    %rbp,%rbx
  je     L48
L39:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %rax,%rax
  js     L59
  je     L55
  add    %rax,%rbx
  jmp    L49
L12:
  mov    $0xffffffffffffffff,%rax
  jmp    L14
L55:
  mov    %rbx,%rbp
L48:
  mov    %rbp,%rax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xread(int fd, void *buf, size_t count) {
  char *b = buf;
  size_t pos = 0;
  do {
    ssize_t rc = read(fd, b + pos, count - pos);
    if (rc < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    }
    if (rc == 0) {
      break;
    }
    pos += (size_t)rc;
  } while (count - pos > 0);
  return pos;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xread>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L49:
  je     L34
  add    %rax,%rbx
L9:
  cmp    %rbp,%rbx
  je     L2
L24:
  mov    %rbp,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  sub    %rbx,%rdx
  call   <read@plt>
  test   %rax,%rax
  jns    L49
  mov    D8(%rip),%rax
  mov    D4(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L9
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L34:
  mov    %rbx,%rbp
L2:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xread(int fd, void *buf, size_t count) {
  char *b = buf;
  size_t pos = 0;
  do {
    ssize_t rc = read(fd, b + pos, count - pos);
    if (rc < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    }
    if (rc == 0) {
      break;
    }
    pos += (size_t)rc;
  } while (count - pos > 0);
  return pos;
}
```
user: What is the c source code of the assembly code below:

```asm
<xread>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L20:
  je     L28
  add    %rax,%rbx
L44:
  cmp    %rbp,%rbx
  je     L14
L29:
  mov    %rbp,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  sub    %rbx,%rdx
  call   <read@plt>
  test   %rax,%rax
  jns    L20
  mov    D10(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L44
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  mov    %rbx,%rbp
L14:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xread(int fd, void *buf, size_t count) {
  char *b = buf;
  size_t pos = 0;
  do {
    ssize_t rc = read(fd, b + pos, count - pos);
    if (rc < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    }
    if (rc == 0) {
      break;
    }
    pos += (size_t)rc;
  } while (count - pos > 0);
  return pos;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <interpret@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <stop_the_world_mark_and_sweep@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  interpret();
  putchar('\n');
  stop_the_world_mark_and_sweep();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <interpret@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <stop_the_world_mark_and_sweep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  interpret();
  putchar('\n');
  stop_the_world_mark_and_sweep();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <interpret@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <stop_the_world_mark_and_sweep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  interpret();
  putchar('\n');
  stop_the_world_mark_and_sweep();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <interpret@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <stop_the_world_mark_and_sweep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  interpret();
  putchar('\n');
  stop_the_world_mark_and_sweep();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  f();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  f();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<myrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L7:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *myrealloc(char *buff, size_t *buffsize) {
  char *newbuff;
  size_t newbuffsize = *buffsize * 2;
  newbuff = (char *)malloc(sizeof(char) * newbuffsize);
  if (newbuff) {
    memcpy(newbuff, buff, *buffsize);
    free(buff);
    buff = newbuff;
    *buffsize = newbuffsize;
  }
  return buff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<myrealloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    (%rsi),%rax
  lea    (%rax,%rax,1),%r13
  mov    %r13d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L1
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %rax,%rbp
  mov    (%r12),%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,(%r12)
  mov    %rbp,%rbx
  jmp    L8
```

assistant: ```c
char *myrealloc(char *buff, size_t *buffsize) {
  char *newbuff;
  size_t newbuffsize = *buffsize * 2;
  newbuff = (char *)malloc(sizeof(char) * newbuffsize);
  if (newbuff) {
    memcpy(newbuff, buff, *buffsize);
    free(buff);
    buff = newbuff;
    *buffsize = newbuffsize;
  }
  return buff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<myrealloc>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rax
  lea    (%rax,%rax,1),%r13
  mov    %r13d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp),%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcpy@plt>
  mov    %r12,%rdi
  mov    %rbx,%r12
  call   <free@plt>
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *myrealloc(char *buff, size_t *buffsize) {
  char *newbuff;
  size_t newbuffsize = *buffsize * 2;
  newbuff = (char *)malloc(sizeof(char) * newbuffsize);
  if (newbuff) {
    memcpy(newbuff, buff, *buffsize);
    free(buff);
    buff = newbuff;
    *buffsize = newbuffsize;
  }
  return buff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<myrealloc>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rax
  lea    (%rax,%rax,1),%r13
  mov    %r13d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    0x0(%rbp),%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcpy@plt>
  mov    %r12,%rdi
  mov    %rbx,%r12
  call   <free@plt>
  mov    %r13,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *myrealloc(char *buff, size_t *buffsize) {
  char *newbuff;
  size_t newbuffsize = *buffsize * 2;
  newbuff = (char *)malloc(sizeof(char) * newbuffsize);
  if (newbuff) {
    memcpy(newbuff, buff, *buffsize);
    free(buff);
    buff = newbuff;
    *buffsize = newbuffsize;
  }
  return buff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0xa,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
signed int f5(signed int v_a, signed int v_b) {
  signed int v_anda = v_a & 1023;
  signed int v_shlb = v_b << 10;
  signed int v_or = v_anda | v_shlb;
  return v_or;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f5>:
  endbr64
  and    $0x3ff,%edi
  shl    $0xa,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
signed int f5(signed int v_a, signed int v_b) {
  signed int v_anda = v_a & 1023;
  signed int v_shlb = v_b << 10;
  signed int v_or = v_anda | v_shlb;
  return v_or;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f5>:
  endbr64
  and    $0x3ff,%edi
  shl    $0xa,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
signed int f5(signed int v_a, signed int v_b) {
  signed int v_anda = v_a & 1023;
  signed int v_shlb = v_b << 10;
  signed int v_or = v_anda | v_shlb;
  return v_or;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UARTAutobaudSpeedGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x80,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x38,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int UARTAutobaudSpeedGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x0080));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x38)))) & (0x0000001Fu));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTAutobaudSpeedGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x80,%esi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x38(%ebx),%eax
  mov    %edx,0xc(%ebx)
  and    $0x1f,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int UARTAutobaudSpeedGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x0080));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x38)))) & (0x0000001Fu));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UARTAutobaudSpeedGet>:
  endbr64
  push   %rbx
  mov    $0x80,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x38(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x1f,%eax
  ret
```

assistant: ```c
unsigned int UARTAutobaudSpeedGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x0080));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x38)))) & (0x0000001Fu));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTAutobaudSpeedGet>:
  endbr64
  push   %rbx
  mov    $0x80,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x38(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x1f,%eax
  ret
```

assistant: ```c
unsigned int UARTAutobaudSpeedGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x0080));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x38)))) & (0x0000001Fu));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x48(%rbp)
  jmp    L26
L21:
  lea    -0x4c(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    D41(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L26
  lea    -0x4c(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    D41(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
L26:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L21
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D41
type_infered: string

tool: D29: %s

tool: D4: r

tool: D9: t

tool: D41: %i

assistant: ```c
int main() {
  int i;
  FILE *arquivo;
  char t[50];
  scanf("%s", t);
  arquivo = fopen("t", "r");
  while (!feof(arquivo)) {
    if (fscanf(arquivo, "%i", &i) == 1) {
      fscanf(arquivo, "%i", &i);
    }
  }
  fclose(arquivo);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D38(%rip),%rbp
L38:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L22
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L38
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  jmp    L38
L22:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string

tool: D1: %s

tool: D22: r

tool: D5: t

tool: D38: %i

assistant: ```c
int main() {
  int i;
  FILE *arquivo;
  char t[50];
  scanf("%s", t);
  arquivo = fopen("t", "r");
  while (!feof(arquivo)) {
    if (fscanf(arquivo, "%i", &i) == 1) {
      fscanf(arquivo, "%i", &i);
    }
  }
  fclose(arquivo);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  lea    D12(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L39
  nopl   0x0(%rax)
L25:
  lea    0xc(%rsp),%r12
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L15
L39:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L25
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  jmp    L39
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D7: %s

tool: D11: %i

tool: D12: r

tool: D14: t

assistant: ```c
int main() {
  int i;
  FILE *arquivo;
  char t[50];
  scanf("%s", t);
  arquivo = fopen("t", "r");
  while (!feof(arquivo)) {
    if (fscanf(arquivo, "%i", &i) == 1) {
      fscanf(arquivo, "%i", &i);
    }
  }
  fclose(arquivo);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  lea    D23(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  jmp    L48
  nopl   0x0(%rax)
L25:
  lea    0xc(%rsp),%r12
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L32
L48:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L25
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  jmp    L48
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string

tool: D21: %s

tool: D14: %i

tool: D23: r

tool: D29: t

assistant: ```c
int main() {
  int i;
  FILE *arquivo;
  char t[50];
  scanf("%s", t);
  arquivo = fopen("t", "r");
  while (!feof(arquivo)) {
    if (fscanf(arquivo, "%i", &i) == 1) {
      fscanf(arquivo, "%i", &i);
    }
  }
  fclose(arquivo);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D137(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D127(%rip),%rdi
  call   <printf@plt>
  lea    D90(%rip),%rdi
  call   <printf@plt>
  lea    D121(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D129(%rip),%rdi
  call   <printf@plt>
  lea    D80(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D56
data_type: string
name: extract_symbolic_data
arguments: tag: D137
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D66
data_type: string
name: extract_symbolic_data
arguments: tag: D127
data_type: string
name: extract_symbolic_data
arguments: tag: D90
data_type: string
name: extract_symbolic_data
arguments: tag: D121
data_type: string
name: extract_symbolic_data
arguments: tag: D59
data_type: string
name: extract_symbolic_data
arguments: tag: D44
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D129
data_type: string
name: extract_symbolic_data
arguments: tag: D80
data_type: string
name: extract_symbolic_data
arguments: tag: D53
data_type: string

tool: D22: Usage: water [image]


tool: D56: 'h'            - help


tool: D137: 'l'            - toggle lighting


tool: D26: 'f'            - increase frequency


tool: D66: 'F'            - decrease frequency


tool: D127: 'm'            - toggle mesh


tool: D90: 't'            - toggle wireframe


tool: D121: 'x'            - toggle water motion


tool: D59: 'UP'           - increase amplitude


tool: D44: 'DOWN'         - decrease amplitude


tool: D0: 'RIGHT'        - increase phase change


tool: D129: 'LEFT'         - decreae phase change


tool: D80: left mouse     - pan


tool: D53: middle mouse   - rotate


assistant: ```c
void help(void) {
  printf("Usage: water [image]\n");
  printf("'h'            - help\n");
  printf("'l'            - toggle lighting\n");
  printf("'f'            - increase frequency\n");
  printf("'F'            - decrease frequency\n");
  printf("'m'            - toggle mesh\n");
  printf("'t'            - toggle wireframe\n");
  printf("'x'            - toggle water motion\n");
  printf("'UP'           - increase amplitude\n");
  printf("'DOWN'         - decrease amplitude\n");
  printf("'RIGHT'        - increase phase change\n");
  printf("'LEFT'         - decreae phase change\n");
  printf("left mouse     - pan\n");
  printf("middle mouse   - rotate\n");
}
```