ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L7
  lea    D28(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L7:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x2,%sil
  je     L13
L3:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L3
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D22
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D28: Call this program with %i arguments


tool: D22: %u


tool: D17: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calculate_face>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  jmp    L7
L27:
  mov    0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L32:
  mov    0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    0x18(%rbp),%rax
  imul   0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm2
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
L11:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L32
L7:
  mov    0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x18(%rbp)
  test   %rax,%rax
  jne    L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void calculate_face(float *mean_shape, float *principal_components, float *pc_deviations, float *coefficients, float *face, size_t coefficients_count, size_t dimensions, size_t vertices) {
  size_t j;
  while (vertices-- > 0) {
    face[vertices] = mean_shape[vertices];
    j = coefficients_count;
    while (j-- > 0) {
      face[vertices] += principal_components[vertices * dimensions + j] * coefficients[j] * pc_deviations[j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calculate_face>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    0x18(%rsp),%rax
  mov    0x20(%rsp),%rdx
  test   %rdx,%rdx
  je     L30
  mov    %rdi,%r11
  mov    %rcx,%rdi
  lea    -0x1(%rdx),%r10
  lea    (%r8,%r10,4),%r8
  mov    %rax,%rbx
  neg    %rbx
  shl    $0x2,%rbx
  imul   %r10,%rax
  lea    0x0(%rbp,%rax,4),%rcx
L14:
  movss  (%r11,%r10,4),%xmm0
  mov    %r8,%rdx
  movss  %xmm0,(%r8)
  lea    -0x1(%r9),%rax
  test   %r9,%r9
  je     L9
L12:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdx)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L12
L9:
  sub    $0x1,%r10
  sub    $0x4,%r8
  add    %rbx,%rcx
  cmp    $0xffffffffffffffff,%r10
  jne    L14
L30:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void calculate_face(float *mean_shape, float *principal_components, float *pc_deviations, float *coefficients, float *face, size_t coefficients_count, size_t dimensions, size_t vertices) {
  size_t j;
  while (vertices-- > 0) {
    face[vertices] = mean_shape[vertices];
    j = coefficients_count;
    while (j-- > 0) {
      face[vertices] += principal_components[vertices * dimensions + j] * coefficients[j] * pc_deviations[j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculate_face>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  push   %rbx
  mov    0x20(%rsp),%rdx
  test   %rdx,%rdx
  je     L0
  lea    -0x1(%rdx),%r10
  mov    %rdi,%r11
  lea    -0x1(%r9),%rbx
  mov    %rcx,%rdi
  lea    (%r8,%r10,4),%rdx
  mov    0x18(%rsp),%r8
  neg    %r8
  shl    $0x2,%r8
  mov    %r8,%rbp
  imul   %r10,%rbp
  sub    %rbp,%rax
  mov    %rax,%rcx
  nopl   0x0(%rax)
L8:
  movss  (%r11,%r10,4),%xmm1
  mov    %rbx,%rax
  movss  %xmm1,(%rdx)
  test   %r9,%r9
  je     L2
  nopw   0x0(%rax,%rax,1)
L12:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  sub    $0x1,%rax
  jae    L12
L2:
  sub    $0x1,%r10
  sub    $0x4,%rdx
  add    %r8,%rcx
  cmp    $0xffffffffffffffff,%r10
  jne    L8
L0:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void calculate_face(float *mean_shape, float *principal_components, float *pc_deviations, float *coefficients, float *face, size_t coefficients_count, size_t dimensions, size_t vertices) {
  size_t j;
  while (vertices-- > 0) {
    face[vertices] = mean_shape[vertices];
    j = coefficients_count;
    while (j-- > 0) {
      face[vertices] += principal_components[vertices * dimensions + j] * coefficients[j] * pc_deviations[j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calculate_face>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  push   %rbx
  mov    0x20(%rsp),%rdx
  test   %rdx,%rdx
  je     L18
  lea    -0x1(%rdx),%r10
  mov    %rdi,%r11
  lea    -0x1(%r9),%rbx
  mov    %rcx,%rdi
  lea    (%r8,%r10,4),%rdx
  mov    0x18(%rsp),%r8
  neg    %r8
  shl    $0x2,%r8
  mov    %r8,%rbp
  imul   %r10,%rbp
  sub    %rbp,%rax
  mov    %rax,%rcx
  nopl   0x0(%rax)
L21:
  movss  (%r11,%r10,4),%xmm1
  mov    %rbx,%rax
  movss  %xmm1,(%rdx)
  test   %r9,%r9
  je     L2
  nopw   0x0(%rax,%rax,1)
L1:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  sub    $0x1,%rax
  jae    L1
L2:
  sub    $0x1,%r10
  sub    $0x4,%rdx
  add    %r8,%rcx
  cmp    $0xffffffffffffffff,%r10
  jne    L21
L18:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void calculate_face(float *mean_shape, float *principal_components, float *pc_deviations, float *coefficients, float *face, size_t coefficients_count, size_t dimensions, size_t vertices) {
  size_t j;
  while (vertices-- > 0) {
    face[vertices] = mean_shape[vertices];
    j = coefficients_count;
    while (j-- > 0) {
      face[vertices] += principal_components[vertices * dimensions + j] * coefficients[j] * pc_deviations[j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_sl>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x68,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  mov    $0x6a,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  mov    %eax,%r13d
  mov    $0x6b,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  shl    $0xc,%r13d
  shl    $0x14,%eax
  or     %eax,%r13d
  mov    $0x6c,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  mov    %eax,%ebx
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  shl    $0x15,%eax
  mov    %eax,%r14d
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  shl    $0x1d,%eax
  mov    %eax,%ebp
  or     %r14d,%ebp
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  shl    $0x1c,%ebx
  mov    %ebx,%ecx
  and    $0x10000000,%ecx
  or     %r13d,%ecx
  movslq %ecx,%rcx
  mov    %ebp,%edx
  mov    %r12,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: %sSL in System memory: 0x%llx, RTSF in SL: 0x%lx


assistant: ```c
void dump_sl(const char *pfx) {
  u_int8_t val;
  unsigned int sl_size_mb;
  unsigned long rtsf_in_sl_addr;
  u_int64_t sl_in_mem_addr;
  val = readb_idx_reg(0x3c5, 0x68);
  switch (val) {
  case 0:
    sl_size_mb = 512;
    break;
  case 0x80:
    sl_size_mb = 256;
    break;
  case 0xc0:
    sl_size_mb = 128;
    break;
  case 0xe0:
    sl_size_mb = 64;
    break;
  case 0xf0:
    sl_size_mb = 32;
    break;
  case 0xf8:
    sl_size_mb = 16;
    break;
  case 0xfc:
    sl_size_mb = 8;
    break;
  case 0xfe:
    sl_size_mb = 4;
    break;
  case 0xff:
    sl_size_mb = 2;
    break;
  }
  rtsf_in_sl_addr = readb_idx_reg(0x3c5, 0x6a) << 12;
  rtsf_in_sl_addr |= readb_idx_reg(0x3c5, 0x6b) << 20;
  val = readb_idx_reg(0x3c5, 0x6c);
  rtsf_in_sl_addr |= (val & 0x1) << 28;
  sl_in_mem_addr = readb_idx_reg(0x3c5, 0x6d) << 21;
  sl_in_mem_addr |= readb_idx_reg(0x3c5, 0x6d) << 29;
  sl_in_mem_addr |= (readb_idx_reg(0x3c5, 0x6d) & 0x7f) << 37;
  printf("%sSL in System memory: 0x%llx, RTSF in SL: 0x%lx\n", pfx, sl_in_mem_addr, rtsf_in_sl_addr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dump_sl>:
  endbr64
  push   %r14
  mov    $0x68,%esi
  push   %r13
  mov    %rdi,%r13
  mov    $0x3c5,%edi
  push   %r12
  push   %rbp
  push   %rbx
  call   <readb_idx_reg@plt>
  mov    $0x6a,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  mov    $0x6b,%esi
  mov    $0x3c5,%edi
  mov    %eax,%ebp
  call   <readb_idx_reg@plt>
  shl    $0xc,%ebp
  mov    $0x6c,%esi
  mov    $0x3c5,%edi
  shl    $0x14,%eax
  or     %eax,%ebp
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  mov    %eax,%ebx
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  shl    $0x1c,%ebx
  shl    $0x15,%eax
  mov    %eax,%r14d
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  shl    $0x1d,%eax
  mov    %eax,%r12d
  call   <readb_idx_reg@plt>
  mov    %ebx,%ecx
  or     %r14d,%r12d
  pop    %rbx
  and    $0x10000000,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  or     %ebp,%ecx
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  movslq %ecx,%rcx
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: %sSL in System memory: 0x%llx, RTSF in SL: 0x%lx


assistant: ```c
void dump_sl(const char *pfx) {
  u_int8_t val;
  unsigned int sl_size_mb;
  unsigned long rtsf_in_sl_addr;
  u_int64_t sl_in_mem_addr;
  val = readb_idx_reg(0x3c5, 0x68);
  switch (val) {
  case 0:
    sl_size_mb = 512;
    break;
  case 0x80:
    sl_size_mb = 256;
    break;
  case 0xc0:
    sl_size_mb = 128;
    break;
  case 0xe0:
    sl_size_mb = 64;
    break;
  case 0xf0:
    sl_size_mb = 32;
    break;
  case 0xf8:
    sl_size_mb = 16;
    break;
  case 0xfc:
    sl_size_mb = 8;
    break;
  case 0xfe:
    sl_size_mb = 4;
    break;
  case 0xff:
    sl_size_mb = 2;
    break;
  }
  rtsf_in_sl_addr = readb_idx_reg(0x3c5, 0x6a) << 12;
  rtsf_in_sl_addr |= readb_idx_reg(0x3c5, 0x6b) << 20;
  val = readb_idx_reg(0x3c5, 0x6c);
  rtsf_in_sl_addr |= (val & 0x1) << 28;
  sl_in_mem_addr = readb_idx_reg(0x3c5, 0x6d) << 21;
  sl_in_mem_addr |= readb_idx_reg(0x3c5, 0x6d) << 29;
  sl_in_mem_addr |= (readb_idx_reg(0x3c5, 0x6d) & 0x7f) << 37;
  printf("%sSL in System memory: 0x%llx, RTSF in SL: 0x%lx\n", pfx, sl_in_mem_addr, rtsf_in_sl_addr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_sl>:
  endbr64
  push   %r14
  mov    $0x68,%esi
  push   %r13
  mov    %rdi,%r13
  mov    $0x3c5,%edi
  push   %r12
  push   %rbp
  push   %rbx
  call   <readb_idx_reg@plt>
  mov    $0x6a,%esi
  mov    $0x3c5,%edi
  call   <readb_idx_reg@plt>
  mov    $0x6b,%esi
  mov    $0x3c5,%edi
  mov    %eax,%ebp
  call   <readb_idx_reg@plt>
  shl    $0xc,%ebp
  mov    $0x6c,%esi
  mov    $0x3c5,%edi
  shl    $0x14,%eax
  or     %eax,%ebp
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  mov    %eax,%ebx
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  shl    $0x1c,%ebx
  shl    $0x15,%eax
  mov    %eax,%r14d
  call   <readb_idx_reg@plt>
  mov    $0x6d,%esi
  mov    $0x3c5,%edi
  shl    $0x1d,%eax
  mov    %eax,%r12d
  call   <readb_idx_reg@plt>
  mov    %ebx,%ecx
  or     %r14d,%r12d
  pop    %rbx
  and    $0x10000000,%ecx
  mov    %r12d,%edx
  mov    %r13,%rsi
  or     %ebp,%ecx
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  movslq %ecx,%rcx
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %sSL in System memory: 0x%llx, RTSF in SL: 0x%lx


assistant: ```c
void dump_sl(const char *pfx) {
  u_int8_t val;
  unsigned int sl_size_mb;
  unsigned long rtsf_in_sl_addr;
  u_int64_t sl_in_mem_addr;
  val = readb_idx_reg(0x3c5, 0x68);
  switch (val) {
  case 0:
    sl_size_mb = 512;
    break;
  case 0x80:
    sl_size_mb = 256;
    break;
  case 0xc0:
    sl_size_mb = 128;
    break;
  case 0xe0:
    sl_size_mb = 64;
    break;
  case 0xf0:
    sl_size_mb = 32;
    break;
  case 0xf8:
    sl_size_mb = 16;
    break;
  case 0xfc:
    sl_size_mb = 8;
    break;
  case 0xfe:
    sl_size_mb = 4;
    break;
  case 0xff:
    sl_size_mb = 2;
    break;
  }
  rtsf_in_sl_addr = readb_idx_reg(0x3c5, 0x6a) << 12;
  rtsf_in_sl_addr |= readb_idx_reg(0x3c5, 0x6b) << 20;
  val = readb_idx_reg(0x3c5, 0x6c);
  rtsf_in_sl_addr |= (val & 0x1) << 28;
  sl_in_mem_addr = readb_idx_reg(0x3c5, 0x6d) << 21;
  sl_in_mem_addr |= readb_idx_reg(0x3c5, 0x6d) << 29;
  sl_in_mem_addr |= (readb_idx_reg(0x3c5, 0x6d) & 0x7f) << 37;
  printf("%sSL in System memory: 0x%llx, RTSF in SL: 0x%lx\n", pfx, sl_in_mem_addr, rtsf_in_sl_addr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<td_ilog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L18:
  addl   $0x1,-0x4(%rbp)
L10:
  shrl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int td_ilog2(unsigned int v) {
  unsigned int l = 0;
  while (v >>= 1)
    l++;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<td_ilog2>:
  endbr64
  shr    %edi
  je     L12
  mov    $0x0,%eax
L14:
  add    $0x1,%eax
  shr    %edi
  jne    L14
  ret
L12:
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned int td_ilog2(unsigned int v) {
  unsigned int l = 0;
  while (v >>= 1)
    l++;
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<td_ilog2>:
  endbr64
  xor    %eax,%eax
  shr    %edi
  je     L8
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%eax
  shr    %edi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
unsigned int td_ilog2(unsigned int v) {
  unsigned int l = 0;
  while (v >>= 1)
    l++;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<td_ilog2>:
  endbr64
  xor    %eax,%eax
  shr    %edi
  je     L16
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x1,%eax
  shr    %edi
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
unsigned int td_ilog2(unsigned int v) {
  unsigned int l = 0;
  while (v >>= 1)
    l++;
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jle    L5
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D12: %d

tool: D4: %d %d

assistant: ```c
int main() {
  int cm, ft, inches;
  scanf("%d", &cm);
  inches = cm / 3;
  if (cm % 3 > 1)
    inches++;
  ft = inches / 12;
  inches = inches % 12;
  printf("%d %d", ft, inches);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
  add    %eax,%edx
  movslq %edx,%rsi
  imul   $0x2aaaaaab,%rsi,%rsi
  sar    $0x21,%rsi
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    (%rsi,%rsi,2),%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D6: %d

tool: D5: %d %d

assistant: ```c
int main() {
  int cm, ft, inches;
  scanf("%d", &cm);
  inches = cm / 3;
  if (cm % 3 > 1)
    inches++;
  ft = inches / 12;
  inches = inches % 12;
  printf("%d %d", ft, inches);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D5(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x55555556,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movslq %edx,%rsi
  mov    %edx,%eax
  imul   $0x2aaaaaab,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x21,%rsi
  sub    %eax,%esi
  lea    (%rsi,%rsi,2),%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string

tool: D19: %d

tool: D5: %d %d

assistant: ```c
int main() {
  int cm, ft, inches;
  scanf("%d", &cm);
  inches = cm / 3;
  if (cm % 3 > 1)
    inches++;
  ft = inches / 12;
  inches = inches % 12;
  printf("%d %d", ft, inches);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D9(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x55555556,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  sub    %ecx,%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movslq %edx,%rsi
  mov    %edx,%eax
  imul   $0x2aaaaaab,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x21,%rsi
  sub    %eax,%esi
  lea    (%rsi,%rsi,2),%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D6: %d

tool: D9: %d %d

assistant: ```c
int main() {
  int cm, ft, inches;
  scanf("%d", &cm);
  inches = cm / 3;
  if (cm % 3 > 1)
    inches++;
  ft = inches / 12;
  inches = inches % 12;
  printf("%d %d", ft, inches);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wrapper_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <wrapper_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *wrapper_strdup(const char *str, const char *file, const int line) {
  char *new_str = wrapper_malloc(strlen(str) + 1, file, line);
  strcpy(new_str, str);
  return new_str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wrapper_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    %r12d,%edx
  mov    %rbx,%rsi
  call   <wrapper_malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *wrapper_strdup(const char *str, const char *file, const int line) {
  char *new_str = wrapper_malloc(strlen(str) + 1, file, line);
  strcpy(new_str, str);
  return new_str;
}
```