ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<B32_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  lea    (%rdx,%rdx,4),%edx
  push   %r12
  lea    0x7(%rdx),%eax
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  cmovns %edx,%eax
  mov    %rdi,0x8(%rsp)
  sar    $0x3,%eax
  add    $0x4,%eax
  cmp    %ecx,%eax
  jge    L61
  test   %r13d,%r13d
  lea    0x7(%r13),%r12d
  mov    0x8(%rsp),%rbp
  mov    %rsi,%r15
  cmovns %r13d,%r12d
  mov    %rsi,%rbx
  xor    %r14d,%r14d
  sar    $0x3,%r12d
  cmp    $0x7,%r13d
  jg     L40
  jmp    L28
  nopl   0x0(%rax)
L53:
  add    $0x1,%r14d
  add    $0x8,%rbp
  add    $0x5,%rbx
  cmp    %r14d,%r12d
  jle    L28
L40:
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <decode_chunk@plt>
  cmp    $0x5,%eax
  je     L53
L61:
  mov    $0xffffffff,%r13d
L32:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %r13d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    0x0(%r13,%rax,1),%edx
  lea    (%r12,%r12,4),%r13d
  and    $0x7,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L32
  shl    $0x3,%r12d
  mov    0x8(%rsp),%rdi
  movslq %r13d,%rax
  movslq %r12d,%r12
  lea    (%r15,%rax,1),%rsi
  add    %r12,%rdi
  call   <decode_chunk@plt>
  test   %eax,%eax
  js     L61
  add    %eax,%r13d
  jmp    L32
```

assistant: ```c
int B32_decode(char *source, char *destination, int size_source, int size_destination) {
  int chunks, reminder, size_reminder, i;
  if (size_destination < (((size_source * 5) / 8) + 5)) {
    return -1;
  }
  chunks = size_source / 8;
  reminder = size_source % 8;
  for (i = 0; i < chunks; i++) {
    if (decode_chunk(source + (i * 8), destination + (i * 5), 8) != 5) {
      return -1;
    }
  }
  if (reminder > 0) {
    size_reminder = decode_chunk(source + (chunks * 8), destination + (chunks * 5), reminder);
    if (size_reminder < 0)
      return -1;
  } else {
    size_reminder = 0;
  }
  return (int)((chunks * 5) + size_reminder);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<B32_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  lea    (%rdx,%rdx,4),%edx
  push   %r12
  lea    0x7(%rdx),%eax
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  cmovns %edx,%eax
  mov    %rdi,0x8(%rsp)
  sar    $0x3,%eax
  add    $0x4,%eax
  cmp    %ecx,%eax
  jge    L65
  test   %r13d,%r13d
  lea    0x7(%r13),%r12d
  mov    %rsi,%r15
  mov    %rdi,%rbp
  cmovns %r13d,%r12d
  mov    %rsi,%rbx
  xor    %r14d,%r14d
  sar    $0x3,%r12d
  cmp    $0x7,%r13d
  jg     L49
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L53:
  add    $0x1,%r14d
  add    $0x8,%rbp
  add    $0x5,%rbx
  cmp    %r14d,%r12d
  jle    L39
L49:
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <decode_chunk@plt>
  cmp    $0x5,%eax
  je     L53
L65:
  mov    $0xffffffff,%r13d
L15:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    %r13d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    0x0(%r13,%rax,1),%edx
  lea    (%r12,%r12,4),%r13d
  and    $0x7,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L15
  shl    $0x3,%r12d
  mov    0x8(%rsp),%rdi
  movslq %r13d,%rax
  movslq %r12d,%r12
  lea    (%r15,%rax,1),%rsi
  add    %r12,%rdi
  call   <decode_chunk@plt>
  test   %eax,%eax
  js     L65
  add    %eax,%r13d
  jmp    L15
```

assistant: ```c
int B32_decode(char *source, char *destination, int size_source, int size_destination) {
  int chunks, reminder, size_reminder, i;
  if (size_destination < (((size_source * 5) / 8) + 5)) {
    return -1;
  }
  chunks = size_source / 8;
  reminder = size_source % 8;
  for (i = 0; i < chunks; i++) {
    if (decode_chunk(source + (i * 8), destination + (i * 5), 8) != 5) {
      return -1;
    }
  }
  if (reminder > 0) {
    size_reminder = decode_chunk(source + (chunks * 8), destination + (chunks * 5), reminder);
    if (size_reminder < 0)
      return -1;
  } else {
    size_reminder = 0;
  }
  return (int)((chunks * 5) + size_reminder);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<release_expr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <expr_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void release_expr(struct expr_node *node, int own) {
  if (own) {
    expr_destroy(node);
    free(node);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<release_expr>:
  endbr64
  test   %esi,%esi
  jne    L2
  ret
L2:
  push   %rbx
  mov    %rdi,%rbx
  call   <expr_destroy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void release_expr(struct expr_node *node, int own) {
  if (own) {
    expr_destroy(node);
    free(node);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<release_expr>:
  endbr64
  test   %esi,%esi
  jne    L3
  ret
  nopl   0x0(%rax)
L3:
  push   %rbp
  mov    %rdi,%rbp
  call   <expr_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void release_expr(struct expr_node *node, int own) {
  if (own) {
    expr_destroy(node);
    free(node);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<release_expr>:
  endbr64
  test   %esi,%esi
  jne    L1
  ret
  nopl   0x0(%rax)
L1:
  push   %rbp
  mov    %rdi,%rbp
  call   <expr_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void release_expr(struct expr_node *node, int own) {
  if (own) {
    expr_destroy(node);
    free(node);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d86f_get_track_table_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x800,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <d86f_get_sides@plt>
  cmp    $0x1,%eax
  jne    L8
  sarl   -0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int d86f_get_track_table_size(int drive) {
  int temp = 2048;
  if (d86f_get_sides(drive) == 1)
    temp >>= 1;
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<d86f_get_track_table_size>:
  endbr64
  sub    $0x8,%rsp
  call   <d86f_get_sides@plt>
  cmp    $0x1,%eax
  mov    $0x800,%eax
  mov    $0x400,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int d86f_get_track_table_size(int drive) {
  int temp = 2048;
  if (d86f_get_sides(drive) == 1)
    temp >>= 1;
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<d86f_get_track_table_size>:
  endbr64
  sub    $0x8,%rsp
  call   <d86f_get_sides@plt>
  mov    $0x400,%edx
  cmp    $0x1,%eax
  mov    $0x800,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int d86f_get_track_table_size(int drive) {
  int temp = 2048;
  if (d86f_get_sides(drive) == 1)
    temp >>= 1;
  return temp;
}
```
user: What is the c source code of the assembly code below:

```asm
<d86f_get_track_table_size>:
  endbr64
  sub    $0x8,%rsp
  call   <d86f_get_sides@plt>
  mov    $0x400,%edx
  cmp    $0x1,%eax
  mov    $0x800,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int d86f_get_track_table_size(int drive) {
  int temp = 2048;
  if (d86f_get_sides(drive) == 1)
    temp >>= 1;
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L20
L54:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  jmp    L71
L45:
  addl   $0x1,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L24
L60:
  addl   $0x1,-0xc(%rbp)
  addl   $0x2,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L60
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L53
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L71
L53:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L71:
  cmpl   $0x1,-0x10(%rbp)
  jg     L45
L20:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L54
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: %d;

assistant: ```c
int main() {
  int limit = 10;
  int steps = 0;
  int nr = 2;
  int n;
  int d;
  int nn;
  while (nr <= limit) {
    n = nr;
    nr = nr + 1;
    while (!(n <= 1)) {
      steps = steps + 1;
      d = 0;
      nn = 2;
      while (nn <= n) {
        d = d + 1;
        nn = nn + 2;
      }
      if (nn <= (n + 1))
        n = n + n + n + 1;
      else
        n = d;
    }
  }
  printf("%d;", steps);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%r8d
  mov    $0x0,%esi
  jmp    L22
L98:
  lea    0x1(%rdx,%rdx,2),%edx
L26:
  cmp    $0x1,%edx
  jle    L81
L2:
  add    $0x1,%esi
  cmp    $0x1,%edx
  jle    L18
  mov    $0x2,%eax
L13:
  add    $0x2,%eax
  cmp    %edx,%eax
  jle    L13
  lea    -0x2(%rdx),%eax
  shr    %eax
  lea    0x1(%rax),%edi
  lea    0x1(%rdx),%ecx
  lea    0x4(%rax,%rax,1),%eax
  cmp    %eax,%ecx
  jge    L98
  mov    %edi,%edx
  jmp    L26
L18:
  je     L98
L81:
  add    $0x1,%r8d
  cmp    $0xb,%r8d
  je     L48
L22:
  mov    %r8d,%edx
  cmp    $0x1,%r8d
  jg     L2
  jmp    L81
L48:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: %d;

assistant: ```c
int main() {
  int limit = 10;
  int steps = 0;
  int nr = 2;
  int n;
  int d;
  int nn;
  while (nr <= limit) {
    n = nr;
    nr = nr + 1;
    while (!(n <= 1)) {
      steps = steps + 1;
      d = 0;
      nn = 2;
      while (nn <= n) {
        d = d + 1;
        nn = nn + 2;
      }
      if (nn <= (n + 1))
        n = n + n + n + 1;
      else
        n = d;
    }
  }
  printf("%d;", steps);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%r10d
  xor    %esi,%esi
  mov    $0x1,%r9d
  mov    $0x4,%r8d
  nopl   0x0(%rax)
L45:
  mov    %r10d,%eax
  add    $0x1,%r10d
  nopw   0x0(%rax,%rax,1)
L47:
  lea    -0x2(%rax),%edx
  add    $0x1,%esi
  lea    0x1(%rax),%edi
  shr    %edx
  cmp    $0x1,%eax
  lea    0x1(%rdx),%ecx
  lea    0x4(%rdx,%rdx,1),%edx
  cmovle %r8d,%edx
  cmovle %r9d,%ecx
  cmp    %edx,%edi
  jl     L37
  lea    0x1(%rax,%rax,2),%eax
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    $0x1,%ecx
  je     L32
  mov    %ecx,%eax
  jmp    L47
  nopl   0x0(%rax)
L32:
  cmp    $0xb,%r10d
  jne    L45
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: %d;

assistant: ```c
int main() {
  int limit = 10;
  int steps = 0;
  int nr = 2;
  int n;
  int d;
  int nn;
  while (nr <= limit) {
    n = nr;
    nr = nr + 1;
    while (!(n <= 1)) {
      steps = steps + 1;
      d = 0;
      nn = 2;
      while (nn <= n) {
        d = d + 1;
        nn = nn + 2;
      }
      if (nn <= (n + 1))
        n = n + n + n + 1;
      else
        n = d;
    }
  }
  printf("%d;", steps);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%r10d
  xor    %esi,%esi
  mov    $0x1,%r9d
  mov    $0x4,%r8d
  nopl   0x0(%rax)
L38:
  mov    %r10d,%eax
  add    $0x1,%r10d
  nopw   0x0(%rax,%rax,1)
L26:
  lea    -0x2(%rax),%edx
  add    $0x1,%esi
  lea    0x1(%rax),%edi
  shr    %edx
  cmp    $0x1,%eax
  lea    0x1(%rdx),%ecx
  lea    0x4(%rdx,%rdx,1),%edx
  cmovle %r8d,%edx
  cmovle %r9d,%ecx
  cmp    %edx,%edi
  jl     L1
  lea    0x1(%rax,%rax,2),%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    $0x1,%ecx
  je     L24
  mov    %ecx,%eax
  jmp    L26
  nopl   0x0(%rax)
L24:
  cmp    $0xb,%r10d
  jne    L38
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %d;

assistant: ```c
int main() {
  int limit = 10;
  int steps = 0;
  int nr = 2;
  int n;
  int d;
  int nn;
  while (nr <= limit) {
    n = nr;
    nr = nr + 1;
    while (!(n <= 1)) {
      steps = steps + 1;
      d = 0;
      nn = 2;
      while (nn <= n) {
        d = d + 1;
        nn = nn + 2;
      }
      if (nn <= (n + 1))
        n = n + n + n + 1;
      else
        n = d;
    }
  }
  printf("%d;", steps);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gettime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <copy_string@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
char *gettime() {
  time_t t, time();
  char *result, *ctime(), *copy_string();
  t = time((long *)0);
  result = copy_string(ctime(&t));
  result[24] = '\0';
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gettime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x0,%eax
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <copy_string@plt>
  movb   $0x0,0x18(%rax)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *gettime() {
  time_t t, time();
  char *result, *ctime(), *copy_string();
  t = time((long *)0);
  result = copy_string(ctime(&t));
  result[24] = '\0';
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gettime>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <copy_string@plt>
  movb   $0x0,0x18(%rax)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *gettime() {
  time_t t, time();
  char *result, *ctime(), *copy_string();
  t = time((long *)0);
  result = copy_string(ctime(&t));
  result[24] = '\0';
  return (result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gettime>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <copy_string@plt>
  movb   $0x0,0x18(%rax)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *gettime() {
  time_t t, time();
  char *result, *ctime(), *copy_string();
  t = time((long *)0);
  result = copy_string(ctime(&t));
  result[24] = '\0';
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x7,%eax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  cmp    $0x7,%ebx
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    D9(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D2(%rip),%rdx
  mov    %ecx,(%rdx)
  jmp    L15
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D6(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D12(%rip),%rdx
  mov    %ecx,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    D17(%rip),%rdx
  mov    (%rdx),%ecx
  mov    D4(%rip),%rdx
  mov    %ecx,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void *ptr;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!(ptr = malloc(size)))
    errno = ENOMEM;
  ;
  return (ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x64,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <populate_array@plt>
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main() {
  int *A = malloc(100 * sizeof(int *));
  int num_elements = 0;
  populate_array(A, &num_elements, 100);
  merge_sort(A, 0, num_elements - 1);
  print_array(A, num_elements);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x320,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x64,%edx
  mov    %rax,%rdi
  call   <populate_array@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <merge_sort@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *A = malloc(100 * sizeof(int *));
  int num_elements = 0;
  populate_array(A, &num_elements, 100);
  merge_sort(A, 0, num_elements - 1);
  print_array(A, num_elements);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x320,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x64,%edx
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <populate_array@plt>
  mov    0x4(%rsp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    -0x1(%rax),%edx
  call   <merge_sort@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *A = malloc(100 * sizeof(int *));
  int num_elements = 0;
  populate_array(A, &num_elements, 100);
  merge_sort(A, 0, num_elements - 1);
  print_array(A, num_elements);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x320,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x64,%edx
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <populate_array@plt>
  mov    0x4(%rsp),%eax
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    -0x1(%rax),%edx
  call   <merge_sort@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *A = malloc(100 * sizeof(int *));
  int num_elements = 0;
  populate_array(A, &num_elements, 100);
  merge_sort(A, 0, num_elements - 1);
  print_array(A, num_elements);
}
```