user: 下面的汇编指令对应的C源代码是什么:

```asm
<quadratic_formula>:
  endbr64
  push   %rbp
  lea    D72(%rip),%rdi
  lea    D155(%rip),%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm0
  movsd  D103(%rip),%xmm1
  call   <pow@plt>
  movss  D118(%rip),%xmm2
  mulss  0x1c(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  mulss  0x24(%rsp),%xmm2
  cvtsi2ss %eax,%xmm0
  mov    D103(%rip),%rax
  subss  %xmm2,%xmm0
  cvttss2si %xmm0,%ebp
  test   %ebp,%ebp
  js     L30
  movss  0x20(%rsp),%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  movss  D118(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  mulss  0x24(%rsp),%xmm1
  cvtsi2ss %eax,%xmm0
  subss  %xmm1,%xmm0
  movsd  D105(%rip),%xmm1
  call   <pow@plt>
  pxor   %xmm3,%xmm3
  movss  0x1c(%rsp),%xmm0
  movss  0x20(%rsp),%xmm1
  cvtsi2ss %eax,%xmm3
  movaps %xmm0,%xmm2
  addss  %xmm0,%xmm2
  movaps %xmm3,%xmm0
  subss  %xmm1,%xmm0
  divss  %xmm2,%xmm0
  test   %ebp,%ebp
  je     L10
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  lea    D63(%rip),%rbp
  movss  %xmm3,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  movss  %xmm1,0x4(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  movss  0x4(%rsp),%xmm1
  xorps  D159(%rip),%xmm1
  lea    D39(%rip),%rdi
  movss  0xc(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  mov    $0x1,%eax
  movaps %xmm1,%xmm0
  subss  %xmm3,%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x30,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L30:
  lea    D114(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D72
datatype: string
name: extract_symbolic_data
arguments: data_label: D155
datatype: string
name: extract_symbolic_data
arguments: data_label: D65
datatype: string
name: extract_symbolic_data
arguments: data_label: D20
datatype: string
name: extract_symbolic_data
arguments: data_label: D103
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D118
datatype: byte[4]
name: extract_symbolic_data
arguments: data_label: D105
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D58
datatype: string
name: extract_symbolic_data
arguments: data_label: D63
datatype: string
name: extract_symbolic_data
arguments: data_label: D159
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D114
datatype: string

tool: D72: A value: 

tool: D155: %f

tool: D65: B value: 

tool: D20: C value: 

tool: {"D103": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D118": [0x00,0x00,0x80,0x40]}

tool: {"D105": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D58: Solution 1: (%f

tool: D63: ,0)

tool: {"D159": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D39: Solution 2: (%f

tool: D27: Solution: (%f

tool: D114: No real solutions

assistant: ```c
void quadratic_formula() {
  float a, b, c, d, qf1, qf2;
  int dis;
  printf("A value: ");
  scanf("%f", &a);
  printf("B value: ");
  scanf("%f", &b);
  printf("C value: ");
  scanf("%f", &c);
  dis = pow(b, 2) - (4 * a * c);
  if (dis < 0) {
    printf("No real solutions\n");
  } else {
    d = (pow(b, 2)) - (4 * a * c);
    d = pow(d, .5);
    qf1 = (-b + d) / (2 * a);
    qf2 = (-b - d) / (2 * a);
    if (dis == 0) {
      printf("Solution: (%f", qf1);
      printf(",0)\n");
    } else {
      printf("Solution 1: (%f", qf1);
      printf(",0)\n");
      printf("Solution 2: (%f", qf2);
      printf(",0)\n");
      ;
    }
  }
}
```