ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_cpu_fields>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x430,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x420(%rbp)
  movq   $0x0,-0x418(%rbp)
  lea    -0x410(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x428(%rbp)
  mov    -0x438(%rbp),%rdx
  lea    -0x420(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L17
L6:
  mov    -0x440(%rbp),%rax
  lea    0x48(%rax),%r11
  mov    -0x440(%rbp),%rax
  lea    0x40(%rax),%r10
  mov    -0x440(%rbp),%rax
  lea    0x38(%rax),%r9
  mov    -0x440(%rbp),%rax
  lea    0x30(%rax),%r8
  mov    -0x440(%rbp),%rax
  lea    0x28(%rax),%rdi
  mov    -0x440(%rbp),%rax
  lea    0x20(%rax),%rsi
  mov    -0x440(%rbp),%rax
  lea    0x18(%rax),%r12
  mov    -0x440(%rbp),%rax
  lea    0x10(%rax),%rbx
  mov    -0x440(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x440(%rbp),%rdx
  lea    -0x420(%rbp),%rax
  push   %r11
  push   %r10
  push   %r9
  push   %r8
  push   %rdi
  push   %rsi
  mov    %r12,%r9
  mov    %rbx,%r8
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  add    $0x30,%rsp
  mov    %eax,-0x42c(%rbp)
  cmpl   $0x3,-0x42c(%rbp)
  jg     L57
  mov    $0x0,%eax
  jmp    L17
L57:
  movl   $0x0,-0x430(%rbp)
  movl   $0x0,-0x430(%rbp)
  jmp    L11
L56:
  mov    -0x430(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x440(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x428(%rbp)
  addl   $0x1,-0x430(%rbp)
L11:
  cmpl   $0x9,-0x430(%rbp)
  jle    L56
  cmpq   $0x0,-0x428(%rbp)
  setne  %al
  movzbl %al,%eax
L17:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: %*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu

assistant: ```c
int read_cpu_fields(FILE *fp, unsigned long *fields) {
  int retval;
  char buffer[1024] = {0};
  unsigned long total_tick = 0;
  if (!fgets(buffer, 1024, fp)) {
    return 0;
  }
  retval = sscanf(buffer, "%*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu", &fields[0], &fields[1], &fields[2], &fields[3], &fields[4], &fields[5], &fields[6], &fields[7], &fields[8], &fields[9]);
  if (retval < 4) {
    return 0;
  }
  int i = 0;
  for (i = 0; i < 10; i++)
    total_tick += fields[i];
  return total_tick ? 1 : 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_cpu_fields>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %eax,%eax
  jne    L14
L29:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x410,%rsp
  pop    %rbx
  ret
L14:
  lea    0x8(%rbx),%rcx
  mov    %rsp,%rdi
  lea    0x48(%rbx),%rax
  push   %rax
  lea    0x40(%rbx),%rax
  push   %rax
  lea    0x38(%rbx),%rax
  push   %rax
  lea    0x30(%rbx),%rax
  push   %rax
  lea    0x28(%rbx),%rax
  push   %rax
  lea    0x20(%rbx),%rax
  push   %rax
  lea    0x18(%rbx),%r9
  lea    0x10(%rbx),%r8
  mov    %rbx,%rdx
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%edx
  add    $0x30,%rsp
  mov    $0x0,%eax
  cmp    $0x3,%edx
  jle    L29
  mov    %rbx,%rax
  add    $0x50,%rbx
  mov    $0x0,%edx
L0:
  add    (%rax),%rdx
  add    $0x8,%rax
  cmp    %rbx,%rax
  jne    L0
  test   %rdx,%rdx
  setne  %al
  movzbl %al,%eax
  jmp    L29
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu

assistant: ```c
int read_cpu_fields(FILE *fp, unsigned long *fields) {
  int retval;
  char buffer[1024] = {0};
  unsigned long total_tick = 0;
  if (!fgets(buffer, 1024, fp)) {
    return 0;
  }
  retval = sscanf(buffer, "%*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu", &fields[0], &fields[1], &fields[2], &fields[3], &fields[4], &fields[5], &fields[6], &fields[7], &fields[8], &fields[9]);
  if (retval < 4) {
    return 0;
  }
  int i = 0;
  for (i = 0; i < 10; i++)
    total_tick += fields[i];
  return total_tick ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_cpu_fields>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x400,%esi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  jne    L45
L3:
  xor    %eax,%eax
L35:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L45:
  lea    0x48(%rbx),%rax
  lea    0x8(%rbx),%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  push   %rax
  lea    0x40(%rbx),%rax
  lea    0x18(%rbx),%r9
  push   %rax
  lea    0x38(%rbx),%rax
  lea    0x10(%rbx),%r8
  push   %rax
  lea    0x30(%rbx),%rax
  lea    D3(%rip),%rsi
  push   %rax
  lea    0x28(%rbx),%rax
  push   %rax
  lea    0x20(%rbx),%rax
  push   %rax
  call   <sscanf@plt>
  add    $0x30,%rsp
  cmp    $0x3,%eax
  jle    L3
  mov    %rbx,%rax
  lea    0x50(%rbx),%rcx
  xor    %edx,%edx
  xchg   %ax,%ax
L34:
  add    (%rax),%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L34
  xor    %eax,%eax
  test   %rdx,%rdx
  setne  %al
  jmp    L35
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: %*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu

assistant: ```c
int read_cpu_fields(FILE *fp, unsigned long *fields) {
  int retval;
  char buffer[1024] = {0};
  unsigned long total_tick = 0;
  if (!fgets(buffer, 1024, fp)) {
    return 0;
  }
  retval = sscanf(buffer, "%*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu", &fields[0], &fields[1], &fields[2], &fields[3], &fields[4], &fields[5], &fields[6], &fields[7], &fields[8], &fields[9]);
  if (retval < 4) {
    return 0;
  }
  int i = 0;
  for (i = 0; i < 10; i++)
    total_tick += fields[i];
  return total_tick ? 1 : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_cpu_fields>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x400,%esi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  jne    L28
L39:
  xor    %eax,%eax
L33:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  lea    0x48(%rbx),%rax
  lea    0x8(%rbx),%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  push   %rax
  lea    0x40(%rbx),%rax
  lea    0x18(%rbx),%r9
  push   %rax
  lea    0x38(%rbx),%rax
  lea    0x10(%rbx),%r8
  push   %rax
  lea    0x30(%rbx),%rax
  lea    D5(%rip),%rsi
  push   %rax
  lea    0x28(%rbx),%rax
  push   %rax
  lea    0x20(%rbx),%rax
  push   %rax
  call   <sscanf@plt>
  add    $0x30,%rsp
  cmp    $0x3,%eax
  jle    L39
  movdqu 0x40(%rbx),%xmm0
  movdqu 0x30(%rbx),%xmm2
  movdqu 0x10(%rbx),%xmm1
  movdqu 0x20(%rbx),%xmm3
  paddq  %xmm2,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm1,%xmm0
  movdqu (%rbx),%xmm1
  paddq  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L33
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string

tool: D5: %*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu

assistant: ```c
int read_cpu_fields(FILE *fp, unsigned long *fields) {
  int retval;
  char buffer[1024] = {0};
  unsigned long total_tick = 0;
  if (!fgets(buffer, 1024, fp)) {
    return 0;
  }
  retval = sscanf(buffer, "%*s %lu %lu %lu %lu %lu %lu %lu %lu %lu %lu", &fields[0], &fields[1], &fields[2], &fields[3], &fields[4], &fields[5], &fields[6], &fields[7], &fields[8], &fields[9]);
  if (retval < 4) {
    return 0;
  }
  int i = 0;
  for (i = 0; i < 10; i++)
    total_tick += fields[i];
  return total_tick ? 1 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r15d
  lea    D26(%rip),%r14
  lea    D17(%rip),%r13
  lea    D60(%rip),%rbp
  lea    D50(%rip),%r12
  jmp    L33
L39:
  mov    %ebx,%edi
  call   <sqrt@plt>
  mov    0x20(%rsp),%r15d
  sub    %r15d,%eax
  mov    %eax,%edx
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  imul   0x1c(%rsp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  %xmm2,0xc(%rsp)
  mov    %ebx,%edi
  call   <sqrt@plt>
  neg    %r15d
  sub    %eax,%r15d
  mov    %r15d,%eax
  shr    $0x1f,%eax
  add    %r15d,%eax
  sar    %eax
  imul   0x1c(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D7(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%r15d
L33:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x20(%rsp),%ebx
  imul   %ebx,%ebx
  mov    0x1c(%rsp),%eax
  imul   0x24(%rsp),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  jns    L39
  lea    D58(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r15d
  cmp    $0x1,%r15d
  jbe    L33
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D26
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D60
type_guessed: string
name: read_data
arguments: tag: D50
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D18
type_guessed: string
name: read_data
arguments: tag: D58
type_guessed: string

tool: D26: 

Ingrese los coeficientes de la cuadratica ax^2+bx+c

tool: D17: a = 

tool: D60: %d

tool: D50: b = 

tool: D7: Raices: x1=%f x2=%f


tool: D18: c = 

tool: D58: sus dos raices son imaginarias!

assistant: ```c
int main() {
  int a, b, c;
  float r1, r2;
  unsigned int intentos = 0;
  while (intentos < 2) {
    printf("\n\nIngrese los coeficientes de la cuadratica ax^2+bx+c\n");
    printf("a = ");
    scanf("%d", &a);
    printf("b = ");
    scanf("%d", &b);
    printf("c = ");
    scanf("%d", &c);
    int deter = b * b - 4 * a * c;
    if (deter < 0) {
      printf("sus dos raices son imaginarias!\n");
      intentos++;
    } else {
      r1 = (-b + sqrt(deter)) / 2 * a;
      r2 = (-b - sqrt(deter)) / 2 * a;
      printf("Raices: x1=%f x2=%f\n", r1, r2);
      intentos = 0;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L21
L2:
  mov    -0x3f8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3f8(%rbp)
  mov    -0x3f4(%rbp),%edx
  cltq
  mov    %dl,-0x3f0(%rbp,%rax,1)
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0xa,-0x3f4(%rbp)
  jne    L2
  mov    -0x3f8(%rbp),%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <lower@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: %s


assistant: ```c
int main(void) {
  int c, i;
  char s[1000];
  while ((c = getchar()) != '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  lower(s);
  printf("%s\n", s);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L19
L14:
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
L19:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L14
  movslq %ebx,%rbp
  movb   $0x0,(%rsp,%rbp,1)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <lower@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: %s


assistant: ```c
int main(void) {
  int c, i;
  char s[1000];
  while ((c = getchar()) != '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  lower(s);
  printf("%s\n", s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L3
  nopl   0x0(%rax)
L14:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L3:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L14
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbp,1)
  call   <lower@plt>
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %s


assistant: ```c
int main(void) {
  int c, i;
  char s[1000];
  while ((c = getchar()) != '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  lower(s);
  printf("%s\n", s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L2
  nopl   0x0(%rax)
L12:
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L2:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L12
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rbp,1)
  call   <lower@plt>
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: %s


assistant: ```c
int main(void) {
  int c, i;
  char s[1000];
  while ((c = getchar()) != '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  lower(s);
  printf("%s\n", s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_reverced>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L17
  subl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <print_reverced>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L17:
  nop
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %d 

assistant: ```c
void print_reverced(const int str[], int size) {
  if (size <= 0) {
    return;
  }
  print_reverced(str + 1, --size);
  printf("%d ", str[0]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_reverced>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x1,%esi
  lea    0x4(%rdi),%rdi
  call   <print_reverced>
  mov    (%rbx),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
L1:
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: %d 

assistant: ```c
void print_reverced(const int str[], int size) {
  if (size <= 0) {
    return;
  }
  print_reverced(str + 1, --size);
  printf("%d ", str[0]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_reverced>:
  endbr64
  test   %esi,%esi
  jle    L37
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L15
  cmp    $0x2,%esi
  je     L25
  cmp    $0x3,%esi
  je     L5
  cmp    $0x4,%esi
  je     L27
  sub    $0x5,%esi
  lea    0x14(%rdi),%rdi
  call   <print_reverced>
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L27:
  mov    0xc(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L5:
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L25:
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L15:
  mov    (%rbx),%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L37:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: %d 

assistant: ```c
void print_reverced(const int str[], int size) {
  if (size <= 0) {
    return;
  }
  print_reverced(str + 1, --size);
  printf("%d ", str[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_reverced>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L39
  cmp    $0x2,%esi
  je     L48
  cmp    $0x3,%esi
  je     L3
  cmp    $0x4,%esi
  je     L19
  sub    $0x5,%esi
  lea    0x14(%rdi),%rdi
  call   <print_reverced>
  mov    0x10(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L19:
  mov    0xc(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L3:
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L48:
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L39:
  mov    (%rbx),%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L1:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
void print_reverced(const int str[], int size) {
  if (size <= 0) {
    return;
  }
  print_reverced(str + 1, --size);
  printf("%d ", str[0]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x10,%eax
  mov    %ax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x10,%eax
  mov    %ax,-0x2(%rbp)
  movswl -0x2(%rbp),%edx
  movswl -0x4(%rbp),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int x, int in1, int in2) {
  short a = (in1 & 0xffff0000) >> 16;
  short b = (in2 & 0xffff0000) >> 16;
  return x + b * a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  sar    $0x10,%edx
  sar    $0x10,%esi
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int foo(int x, int in1, int in2) {
  short a = (in1 & 0xffff0000) >> 16;
  short b = (in2 & 0xffff0000) >> 16;
  return x + b * a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  sar    $0x10,%edx
  sar    $0x10,%esi
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int foo(int x, int in1, int in2) {
  short a = (in1 & 0xffff0000) >> 16;
  short b = (in2 & 0xffff0000) >> 16;
  return x + b * a;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  sar    $0x10,%edx
  sar    $0x10,%esi
  imul   %esi,%edx
  lea    (%rdx,%rdi,1),%eax
  ret
```

assistant: ```c
int foo(int x, int in1, int in2) {
  short a = (in1 & 0xffff0000) >> 16;
  short b = (in2 & 0xffff0000) >> 16;
  return x + b * a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1a,-0x74(%rbp)
  lea    -0x70(%rbp),%rcx
  mov    -0x74(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: :%s:


assistant: ```c
int main(int argc, char **argv) {
  char s[100];
  int n = 26;
  itoa(n, s, 10);
  printf(":%s:\n", s);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xa,%edx
  mov    %rbx,%rsi
  mov    $0x1a,%edi
  call   <itoa@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: :%s:


assistant: ```c
int main(int argc, char **argv) {
  char s[100];
  int n = 26;
  itoa(n, s, 10);
  printf(":%s:\n", s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1a,%edi
  mov    $0xa,%edx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: :%s:


assistant: ```c
int main(int argc, char **argv) {
  char s[100];
  int n = 26;
  itoa(n, s, 10);
  printf(":%s:\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1a,%edi
  mov    $0xa,%edx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: :%s:


assistant: ```c
int main(int argc, char **argv) {
  char s[100];
  int n = 26;
  itoa(n, s, 10);
  printf(":%s:\n", s);
  return 0;
}
```