ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  add    0x4(%rsp),%eax
  add    0xc(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x21,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
data_type: string
name: parse_data
arguments: data_label: D56
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D58
data_type: string
name: parse_data
arguments: data_label: D17
data_type: string

tool: D22: What is your first value?

tool: D56: %d

tool: D28: What is your second value?

tool: D18: What is your third value?

tool: D39: What is your fourth value?

tool: D58: What is your fifth value?

tool: D17: The average of your five values is: %d

assistant: ```c
int main() {
  int a, b, c, d, e;
  printf("What is your first value?\n");
  scanf("%d", &a);
  printf("What is your second value?\n");
  scanf("%d", &b);
  printf("What is your third value?\n");
  scanf("%d", &c);
  printf("What is your fourth value?\n");
  scanf("%d", &d);
  printf("What is your fifth value?\n");
  scanf("%d", &e);
  int average = (a + b + c + d + e) / 5;
  printf("The average of your five values is: %d", average);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  lea    D27(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D61(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  add    0x4(%rsp),%eax
  lea    D59(%rip),%rdi
  add    0xc(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x21,%rsi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string
name: retrieve_data
arguments: data_label: D34
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D61
datatype: string
name: retrieve_data
arguments: data_label: D59
datatype: string

tool: D30: What is your first value?

tool: D27: %d

tool: D28: What is your second value?

tool: D34: What is your third value?

tool: D3: What is your fourth value?

tool: D61: What is your fifth value?

tool: D59: The average of your five values is: %d

assistant: ```c
int main() {
  int a, b, c, d, e;
  printf("What is your first value?\n");
  scanf("%d", &a);
  printf("What is your second value?\n");
  scanf("%d", &b);
  printf("What is your third value?\n");
  scanf("%d", &c);
  printf("What is your fourth value?\n");
  scanf("%d", &d);
  printf("What is your fifth value?\n");
  scanf("%d", &e);
  int average = (a + b + c + d + e) / 5;
  printf("The average of your five values is: %d", average);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D44(%rip),%rdi
  lea    D69(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  add    0x4(%rsp),%eax
  lea    D14(%rip),%rdi
  add    0xc(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x21,%rsi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D44
datatype: string
name: extract_symbolic_data
arguments: tag: D69
datatype: string
name: extract_symbolic_data
arguments: tag: D51
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D44: What is your first value?

tool: D69: %d

tool: D51: What is your second value?

tool: D10: What is your third value?

tool: D3: What is your fourth value?

tool: D7: What is your fifth value?

tool: D14: The average of your five values is: %d

assistant: ```c
int main() {
  int a, b, c, d, e;
  printf("What is your first value?\n");
  scanf("%d", &a);
  printf("What is your second value?\n");
  scanf("%d", &b);
  printf("What is your third value?\n");
  scanf("%d", &c);
  printf("What is your fourth value?\n");
  scanf("%d", &d);
  printf("What is your fifth value?\n");
  scanf("%d", &e);
  int average = (a + b + c + d + e) / 5;
  printf("The average of your five values is: %d", average);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seperator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L5
  mov    $0x0,%eax
  jmp    L6
L5:
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <waddch@plt>
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int seperator(WINDOW *pad, int compact) {
  if (compact)
    return 0;
  waddch(pad, '\n');
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<seperator>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  je     L4
  ret
L4:
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <waddch@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int seperator(WINDOW *pad, int compact) {
  if (compact)
    return 0;
  waddch(pad, '\n');
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<seperator>:
  endbr64
  test   %esi,%esi
  je     L0
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <waddch@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int seperator(WINDOW *pad, int compact) {
  if (compact)
    return 0;
  waddch(pad, '\n');
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<seperator>:
  endbr64
  test   %esi,%esi
  je     L7
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  sub    $0x8,%rsp
  mov    $0xa,%esi
  call   <waddch@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int seperator(WINDOW *pad, int compact) {
  if (compact)
    return 0;
  waddch(pad, '\n');
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<large_opchain>:
  endbr64
  movapd %xmm0,%xmm7
  mulsd  %xmm1,%xmm7
  movapd %xmm0,%xmm5
  mulsd  %xmm2,%xmm5
  movapd %xmm0,%xmm4
  mulsd  %xmm3,%xmm4
  movapd %xmm1,%xmm6
  mulsd  %xmm2,%xmm6
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm2
  movapd %xmm7,%xmm0
  addsd  %xmm7,%xmm0
  movapd %xmm7,%xmm3
  addsd  %xmm5,%xmm3
  mulsd  %xmm3,%xmm0
  movapd %xmm5,%xmm3
  addsd  %xmm5,%xmm3
  addsd  %xmm4,%xmm5
  mulsd  %xmm5,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm4,%xmm3
  addsd  %xmm7,%xmm4
  mulsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm6,%xmm4
  addsd  %xmm6,%xmm4
  movapd %xmm6,%xmm3
  addsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm4
  movapd %xmm1,%xmm3
  addsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm3
  addsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double large_opchain(double a, double b, double c, double d) {
  double ab = a * b;
  double ac = a * c;
  double ad = a * d;
  double bc = b * c;
  double bd = b * d;
  double cd = c * d;
  double p01 = ab + ab;
  double p02 = ab + ac;
  double p03 = ac + ac;
  double p04 = ad + ac;
  double p05 = ad + ad;
  double p06 = ab + ad;
  double p07 = bc + bc;
  double p08 = bc + bd;
  double p09 = bd + bd;
  double p10 = bd + cd;
  double p11 = cd + cd;
  double p12 = bc + cd;
  double q01 = p01 * p02;
  double q02 = p03 * p04;
  double q03 = p05 * p06;
  double q04 = p07 * p08;
  double q05 = p09 * p10;
  double q06 = p11 * p12;
  double r01 = q01 + q02;
  double r02 = r01 + q03;
  double r03 = q04 + q05;
  double r04 = r03 + q06;
  return r02 + r04;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<large_opchain>:
  endbr64
  movapd %xmm0,%xmm7
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm4
  mulsd  %xmm1,%xmm7
  movapd %xmm1,%xmm6
  mulsd  %xmm2,%xmm5
  mulsd  %xmm2,%xmm6
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm2
  movapd %xmm7,%xmm0
  movapd %xmm7,%xmm3
  addsd  %xmm5,%xmm3
  addsd  %xmm7,%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm5,%xmm3
  addsd  %xmm5,%xmm3
  addsd  %xmm4,%xmm5
  mulsd  %xmm5,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm4,%xmm3
  addsd  %xmm7,%xmm4
  mulsd  %xmm4,%xmm3
  movapd %xmm6,%xmm4
  addsd  %xmm6,%xmm4
  addsd  %xmm3,%xmm0
  movapd %xmm6,%xmm3
  addsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm4
  movapd %xmm1,%xmm3
  addsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm3
  addsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double large_opchain(double a, double b, double c, double d) {
  double ab = a * b;
  double ac = a * c;
  double ad = a * d;
  double bc = b * c;
  double bd = b * d;
  double cd = c * d;
  double p01 = ab + ab;
  double p02 = ab + ac;
  double p03 = ac + ac;
  double p04 = ad + ac;
  double p05 = ad + ad;
  double p06 = ab + ad;
  double p07 = bc + bc;
  double p08 = bc + bd;
  double p09 = bd + bd;
  double p10 = bd + cd;
  double p11 = cd + cd;
  double p12 = bc + cd;
  double q01 = p01 * p02;
  double q02 = p03 * p04;
  double q03 = p05 * p06;
  double q04 = p07 * p08;
  double q05 = p09 * p10;
  double q06 = p11 * p12;
  double r01 = q01 + q02;
  double r02 = r01 + q03;
  double r03 = q04 + q05;
  double r04 = r03 + q06;
  return r02 + r04;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<large_opchain>:
  endbr64
  movapd %xmm0,%xmm7
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm4
  mulsd  %xmm1,%xmm7
  movapd %xmm1,%xmm6
  mulsd  %xmm2,%xmm5
  mulsd  %xmm2,%xmm6
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm2
  movapd %xmm7,%xmm0
  movapd %xmm7,%xmm3
  addsd  %xmm5,%xmm3
  addsd  %xmm7,%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm5,%xmm3
  addsd  %xmm5,%xmm3
  addsd  %xmm4,%xmm5
  mulsd  %xmm5,%xmm3
  addsd  %xmm3,%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm4,%xmm3
  addsd  %xmm7,%xmm4
  mulsd  %xmm4,%xmm3
  movapd %xmm6,%xmm4
  addsd  %xmm6,%xmm4
  addsd  %xmm3,%xmm0
  movapd %xmm6,%xmm3
  addsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm4
  movapd %xmm1,%xmm3
  addsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm3
  addsd  %xmm2,%xmm3
  addsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double large_opchain(double a, double b, double c, double d) {
  double ab = a * b;
  double ac = a * c;
  double ad = a * d;
  double bc = b * c;
  double bd = b * d;
  double cd = c * d;
  double p01 = ab + ab;
  double p02 = ab + ac;
  double p03 = ac + ac;
  double p04 = ad + ac;
  double p05 = ad + ad;
  double p06 = ab + ad;
  double p07 = bc + bc;
  double p08 = bc + bd;
  double p09 = bd + bd;
  double p10 = bd + cd;
  double p11 = cd + cd;
  double p12 = bc + cd;
  double q01 = p01 * p02;
  double q02 = p03 * p04;
  double q03 = p05 * p06;
  double q04 = p07 * p08;
  double q05 = p09 * p10;
  double q06 = p11 * p12;
  double r01 = q01 + q02;
  double r02 = r01 + q03;
  double r03 = q04 + q05;
  double r04 = r03 + q06;
  return r02 + r04;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compute_discrepancy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L2:
  mov    -0x28(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gmult@plt>
  xor    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L2
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int compute_discrepancy(int lambda[], int S[], int L, int n) {
  int i, sum = 0;
  for (i = 0; i <= L; i++)
    sum ^= gmult(lambda[i], S[n - i]);
  return (sum);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<compute_discrepancy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  js     L28
  mov    %rdi,%r14
  mov    %edx,%r13d
  movslq %ecx,%rcx
  lea    (%rsi,%rcx,4),%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
L23:
  mov    (%r14,%rbx,4),%edi
  mov    0x0(%rbp),%esi
  call   <gmult@plt>
  xor    %eax,%r12d
  add    $0x1,%rbx
  sub    $0x4,%rbp
  cmp    %ebx,%r13d
  jge    L23
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    $0x0,%r12d
  jmp    L15
```

assistant: ```c
int compute_discrepancy(int lambda[], int S[], int L, int n) {
  int i, sum = 0;
  for (i = 0; i <= L; i++)
    sum ^= gmult(lambda[i], S[n - i]);
  return (sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_discrepancy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  js     L11
  movslq %ecx,%rcx
  mov    %rdi,%r14
  mov    %edx,%r13d
  xor    %ebx,%ebx
  lea    (%rsi,%rcx,4),%rbp
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%r14,%rbx,4),%edi
  mov    0x0(%rbp),%esi
  add    $0x1,%rbx
  sub    $0x4,%rbp
  call   <gmult@plt>
  xor    %eax,%r12d
  cmp    %ebx,%r13d
  jge    L9
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int compute_discrepancy(int lambda[], int S[], int L, int n) {
  int i, sum = 0;
  for (i = 0; i <= L; i++)
    sum ^= gmult(lambda[i], S[n - i]);
  return (sum);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<compute_discrepancy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  js     L19
  movslq %ecx,%rcx
  mov    %rdi,%r14
  mov    %edx,%r13d
  xor    %ebx,%ebx
  lea    (%rsi,%rcx,4),%rbp
  xor    %r12d,%r12d
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%r14,%rbx,4),%edi
  mov    0x0(%rbp),%esi
  add    $0x1,%rbx
  sub    $0x4,%rbp
  call   <gmult@plt>
  xor    %eax,%r12d
  cmp    %ebx,%r13d
  jge    L6
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int compute_discrepancy(int lambda[], int S[], int L, int n) {
  int i, sum = 0;
  for (i = 0; i <= L; i++)
    sum ^= gmult(lambda[i], S[n - i]);
  return (sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<on>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x8(%rax),%ebx
  mov    $0x2,%edi
  call   <Game_scale@plt>
  imul   %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x64,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int on(unsigned int lev) {
  int perlevel = (int)((8 + 3 * lev) * Game_scale(2));
  return ((perlevel) < (100) ? (perlevel) : (100));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<on>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <Game_scale@plt>
  mov    %eax,%edx
  lea    0x8(%rbx,%rbx,2),%eax
  imul   %edx,%eax
  mov    $0x64,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int on(unsigned int lev) {
  int perlevel = (int)((8 + 3 * lev) * Game_scale(2));
  return ((perlevel) < (100) ? (perlevel) : (100));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<on>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <Game_scale@plt>
  mov    $0x64,%edx
  mov    %eax,%r8d
  lea    0x8(%rbx,%rbx,2),%eax
  pop    %rbx
  imul   %r8d,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int on(unsigned int lev) {
  int perlevel = (int)((8 + 3 * lev) * Game_scale(2));
  return ((perlevel) < (100) ? (perlevel) : (100));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<on>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <Game_scale@plt>
  mov    $0x64,%edx
  mov    %eax,%r8d
  lea    0x8(%rbx,%rbx,2),%eax
  pop    %rbx
  imul   %r8d,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int on(unsigned int lev) {
  int perlevel = (int)((8 + 3 * lev) * Game_scale(2));
  return ((perlevel) < (100) ? (perlevel) : (100));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %edi,-0x834(%rbp)
  mov    %rsi,-0x840(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,-0x828(%rbp)
  mov    -0x828(%rbp),%edx
  mov    -0x828(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <setreuid@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x820(%rbp)
  mov    -0x820(%rbp),%rax
  mov    $0x3b,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x818(%rbp)
  cmpq   $0x0,-0x818(%rbp)
  je     L10
  mov    $0x63,%edi
  call   <exit@plt>
L10:
  mov    -0x820(%rbp),%rax
  mov    $0x7c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x818(%rbp)
  cmpq   $0x0,-0x818(%rbp)
  je     L13
  mov    $0x63,%edi
  call   <exit@plt>
L13:
  mov    -0x820(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x818(%rbp)
  cmpq   $0x0,-0x818(%rbp)
  je     L27
  mov    $0x63,%edi
  call   <exit@plt>
L27:
  mov    -0x820(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x840(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <dirname@plt>
  mov    %rax,%rsi
  mov    -0x820(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execl@plt>
  mov    %eax,-0x824(%rbp)
  mov    -0x824(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D0: PHP_CGI_FILE

tool: D20: ./%s.karma_cgi.php

tool: D8: %s/%s.karma_cgi.php

assistant: ```c
int main(int argc, char **argv) {
  char *puntero;
  char comando[1024];
  char comando_real[1024];
  int retorno;
  uid_t miuid;
  miuid = geteuid();
  setreuid(miuid, miuid);
  char *fichero = getenv("PHP_CGI_FILE");
  puntero = strstr(fichero, ";");
  if (puntero != NULL) {
    exit(99);
  }
  puntero = strstr(fichero, "|");
  if (puntero != NULL) {
    exit(99);
  }
  puntero = strstr(fichero, ".");
  if (puntero != NULL) {
    exit(99);
  }
  sprintf(comando, "./%s.karma_cgi.php", fichero);
  sprintf(comando_real, "%s/%s.karma_cgi.php", dirname(argv[0]), fichero);
  retorno = execl(comando_real, comando_real, NULL);
  exit(retorno);
}
```