ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gnd_extract_content>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    %rdi,%rsi
  mov    %rdi,(%rsp)
  call   <ft_strndup@plt>
  lea    (%rbx,%r12,1),%rdi
  mov    %rax,0x0(%r13)
  call   <ft_strdup@plt>
  mov    %rsp,%rdi
  mov    %rax,0x0(%rbp)
  call   <ft_strdel@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gnd_extract_content(char **stock, char **line, char *delim, size_t size_delim) {
  size_t size;
  char *ptr;
  ptr = *stock;
  size = (size_t)delim - (size_t)*stock;
  *line = ft_strndup(*stock, size);
  *stock = ft_strdup(delim + size_delim);
  ft_strdel(&ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x896000(%rsp),%r11
L51:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L51
  sub    $0xbd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x896bc8(%rbp)
  jmp    L20
L46:
  mov    -0x896bc8(%rbp),%eax
  cltq
  mov    -0x896bc8(%rbp),%edx
  mov    %edx,-0x896bc0(%rbp,%rax,4)
  movl   $0x0,-0x896bc4(%rbp)
  jmp    L12
L78:
  cmpl   $0x1f4,-0x896bc4(%rbp)
  jle    L42
  mov    -0x896bc8(%rbp),%edx
  mov    -0x896bc4(%rbp),%eax
  add    %edx,%eax
  lea    0x3(%rax),%edx
  mov    -0x896bc4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x896bc8(%rbp),%eax
  cltq
  imul   $0x5dc,%rax,%rax
  add    %rcx,%rax
  mov    %edx,-0x895450(%rbp,%rax,4)
  mov    -0x896bc8(%rbp),%eax
  imul   -0x896bc4(%rbp),%eax
  lea    0xa(%rax),%edx
  mov    -0x896bc4(%rbp),%eax
  cltq
  mov    %edx,-0x896bc0(%rbp,%rax,4)
  jmp    L25
L42:
  mov    -0x896bc4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x896bc8(%rbp),%eax
  cltq
  imul   $0x5dc,%rax,%rax
  add    %rdx,%rax
  mov    -0x895450(%rbp,%rax,4),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x896bc4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x896bc8(%rbp),%eax
  cltq
  imul   $0x5dc,%rax,%rax
  add    %rcx,%rax
  mov    %edx,-0x895450(%rbp,%rax,4)
L25:
  addl   $0x1,-0x896bc4(%rbp)
L12:
  cmpl   $0x5db,-0x896bc4(%rbp)
  jle    L78
  addl   $0x1,-0x896bc8(%rbp)
L20:
  cmpl   $0x5db,-0x896bc8(%rbp)
  jle    L46
  mov    -0x89255c(%rbp),%edx
  mov    -0x896ba0(%rbp),%eax
  imul   %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
int foo(void) {
  int i, j;
  int x[1500][1500], y[1500];
  for (i = 0; i < 1500; i++) {
    y[i] = i;
    for (j = 0; j < 1500; j++) {
      if (j > 500) {
        x[i][j] = i + j + 3;
        y[j] = i * j + 10;
      } else
        x[i][j] = x[i][j] * 3;
    }
  }
  return x[2][5] * y[8];
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  lea    -0x896000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0xbc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x896bb8(%rsp)
  xor    %eax,%eax
  lea    0x1770(%rsp),%r11
  mov    $0x0,%r10d
  jmp    L25
L54:
  mov    (%rdx),%edi
  lea    (%rdi,%rdi,2),%edi
  mov    %edi,(%rdx)
L20:
  add    $0x1,%rax
  add    $0x1,%ecx
  add    $0x4,%rdx
  add    %r8d,%esi
L24:
  cmp    $0x1f4,%eax
  jle    L54
  lea    (%r9,%rcx,1),%edi
  mov    %edi,(%rdx)
  mov    %esi,(%rsp,%rax,4)
  cmp    $0x5db,%ecx
  jle    L20
  add    $0x1,%r10
  add    $0x1770,%r11
  cmp    $0x5dc,%r10
  je     L0
L25:
  mov    %r10d,%r8d
  mov    %r10d,(%rsp,%r10,4)
  mov    %r11,%rdx
  mov    $0xa,%esi
  mov    $0x1,%ecx
  mov    $0x0,%eax
  lea    0x2(%r10),%r9d
  jmp    L24
L0:
  mov    0x4664(%rsp),%eax
  imul   0x20(%rsp),%eax
  mov    0x896bb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x896bc8,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int i, j;
  int x[1500][1500], y[1500];
  for (i = 0; i < 1500; i++) {
    y[i] = i;
    for (j = 0; j < 1500; j++) {
      if (j > 500) {
        x[i][j] = i + j + 3;
        y[j] = i * j + 10;
      } else
        x[i][j] = x[i][j] * 3;
    }
  }
  return x[2][5] * y[8];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  lea    -0x896000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0xbc8,%rsp
  xor    %r10d,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x896bb8(%rsp)
  xor    %eax,%eax
  lea    0x1770(%rsp),%r11
  mov    %rsp,%r8
L52:
  mov    %r10d,(%r8,%r10,4)
  mov    %r10d,%edi
  mov    %r11,%rdx
  mov    $0xa,%ecx
  xor    %eax,%eax
  lea    0x3(%r10),%r9d
  jmp    L13
  nopl   0x0(%rax)
L43:
  lea    (%r9,%rax,1),%esi
  mov    %ecx,(%r8,%rax,4)
  mov    %esi,(%rdx)
  cmp    $0x5db,%rax
  je     L29
L44:
  add    $0x1,%rax
  add    $0x4,%rdx
  add    %edi,%ecx
L13:
  cmp    $0x1f4,%rax
  ja     L43
  mov    (%rdx),%esi
  lea    (%rsi,%rsi,2),%esi
  mov    %esi,(%rdx)
  jmp    L44
L29:
  add    $0x1,%r10
  add    $0x1770,%r11
  cmp    $0x5dc,%r10
  jne    L52
  mov    0x4664(%rsp),%eax
  imul   0x20(%rsp),%eax
  mov    0x896bb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x896bc8,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int i, j;
  int x[1500][1500], y[1500];
  for (i = 0; i < 1500; i++) {
    y[i] = i;
    for (j = 0; j < 1500; j++) {
      if (j > 500) {
        x[i][j] = i + j + 3;
        y[j] = i * j + 10;
      } else
        x[i][j] = x[i][j] * 3;
    }
  }
  return x[2][5] * y[8];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  lea    -0x896000(%rsp),%r11
L30:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L30
  sub    $0xbc8,%rsp
  xor    %r10d,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x896bb8(%rsp)
  xor    %eax,%eax
  lea    0x1770(%rsp),%r11
  mov    %rsp,%r8
L57:
  mov    %r10d,(%r8,%r10,4)
  mov    %r10d,%edi
  mov    %r11,%rdx
  mov    $0xa,%ecx
  xor    %eax,%eax
  lea    0x3(%r10),%r9d
  jmp    L27
  nopl   0x0(%rax)
L41:
  lea    (%r9,%rax,1),%esi
  mov    %ecx,(%r8,%rax,4)
  mov    %esi,(%rdx)
  cmp    $0x5db,%rax
  je     L7
L45:
  add    $0x1,%rax
  add    $0x4,%rdx
  add    %edi,%ecx
L27:
  cmp    $0x1f4,%rax
  ja     L41
  mov    (%rdx),%esi
  lea    (%rsi,%rsi,2),%esi
  mov    %esi,(%rdx)
  jmp    L45
L7:
  add    $0x1,%r10
  add    $0x1770,%r11
  cmp    $0x5dc,%r10
  jne    L57
  mov    0x4664(%rsp),%eax
  imul   0x20(%rsp),%eax
  mov    0x896bb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x896bc8,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(void) {
  int i, j;
  int x[1500][1500], y[1500];
  for (i = 0; i < 1500; i++) {
    y[i] = i;
    for (j = 0; j < 1500; j++) {
      if (j > 500) {
        x[i][j] = i + j + 3;
        y[j] = i * j + 10;
      } else
        x[i][j] = x[i][j] * 3;
    }
  }
  return x[2][5] * y[8];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  andl   $0x3,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L23
  lea    D24(%rip),%rax
  jmp    L21
L23:
  cmpl   $0x2,-0x4(%rbp)
  jne    L48
  lea    D34(%rip),%rax
  jmp    L21
L48:
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  lea    D32(%rip),%rax
  jmp    L21
L6:
  lea    D8(%rip),%rax
L21:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D34
type_guessed: string
name: disassemble_data
arguments: label: D32
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D24: add

tool: D34: del

tool: D32: none

tool: D8: ???

assistant: ```c
const char *change_to_string(int change) {
  change &= (0x01 | 0x02);
  if (change == 0x01) {
    return "add";
  } else if (change == 0x02) {
    return "del";
  } else if (change == 0) {
    return "none";
  } else {
    return "???";
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_to_string>:
  endbr64
  and    $0x3,%edi
  lea    D20(%rip),%rax
  cmp    $0x1,%edi
  je     L8
  lea    D37(%rip),%rax
  cmp    $0x2,%edi
  je     L8
  test   %edi,%edi
  lea    D6(%rip),%rax
  lea    D24(%rip),%rdx
  cmovne %rdx,%rax
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D37
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D24
type_infered: string

tool: D20: add

tool: D37: del

tool: D6: none

tool: D24: ???

assistant: ```c
const char *change_to_string(int change) {
  change &= (0x01 | 0x02);
  if (change == 0x01) {
    return "add";
  } else if (change == 0x02) {
    return "del";
  } else if (change == 0) {
    return "none";
  } else {
    return "???";
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<change_to_string>:
  endbr64
  and    $0x3,%edi
  lea    D1(%rip),%rax
  cmp    $0x1,%edi
  je     L6
  lea    D38(%rip),%rax
  cmp    $0x2,%edi
  je     L6
  test   %edi,%edi
  lea    D34(%rip),%rax
  lea    D28(%rip),%rdx
  cmovne %rdx,%rax
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string

tool: D1: add

tool: D38: del

tool: D34: none

tool: D28: ???

assistant: ```c
const char *change_to_string(int change) {
  change &= (0x01 | 0x02);
  if (change == 0x01) {
    return "add";
  } else if (change == 0x02) {
    return "del";
  } else if (change == 0) {
    return "none";
  } else {
    return "???";
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<change_to_string>:
  endbr64
  and    $0x3,%edi
  lea    D22(%rip),%rax
  cmp    $0x1,%edi
  je     L4
  lea    D6(%rip),%rax
  cmp    $0x2,%edi
  je     L4
  test   %edi,%edi
  lea    D29(%rip),%rax
  lea    D39(%rip),%rdx
  cmovne %rdx,%rax
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type: string
name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D29
type: string
name: retrieve_data
arguments: data_label: D39
type: string

tool: D22: add

tool: D6: del

tool: D29: none

tool: D39: ???

assistant: ```c
const char *change_to_string(int change) {
  change &= (0x01 | 0x02);
  if (change == 0x01) {
    return "add";
  } else if (change == 0x02) {
    return "del";
  } else if (change == 0) {
    return "none";
  } else {
    return "???";
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  imul   $0xfb16,%ax,%ax
  sub    $0x2e4,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  imul   $0xba1,%ax,%dx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        if (state[0UL] < local2 + local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 413141921UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  imul   $0xdad6,(%rdi),%ax
  add    $0x629c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        if (state[0UL] < local2 + local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 413141921UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  imul   $0xdad6,(%rdi),%ax
  add    $0x629c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        if (state[0UL] < local2 + local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 413141921UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  imul   $0xdad6,(%rdi),%ax
  add    $0x629c,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        if (state[0UL] < local2 + local1) {
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 413141921UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %ld

assistant: ```c
int main() {
  size_t n;
  printf("%ld", sizeof(int));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: %ld

assistant: ```c
int main() {
  size_t n;
  printf("%ld", sizeof(int));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: %ld

assistant: ```c
int main() {
  size_t n;
  printf("%ld", sizeof(int));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: %ld

assistant: ```c
int main() {
  size_t n;
  printf("%ld", sizeof(int));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L26
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L36
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L36:
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void add(double P[], int degreeP, double Q[], int degreeQ, double R[]) {
  int degreeR = max(degreeP, degreeQ) + 1;
  int term;
  for (term = 0; term <= degreeR; term++) {
    R[term] = 0;
    if (term <= degreeP) {
      R[term] += P[term];
    }
    if (term <= degreeQ) {
      R[term] += Q[term];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %ecx,%r12d
  mov    %r8,%rbx
  mov    %ecx,%esi
  mov    %ebp,%edi
  call   <max@plt>
  cmp    $0xffffffff,%eax
  jl     L48
  lea    0x1(%rax),%ecx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  jmp    L36
L25:
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  je     L48
  mov    %rdx,%rax
L36:
  movq   $0x0,(%rbx,%rax,8)
  mov    %eax,%edx
  cmp    %eax,%ebp
  jl     L19
  movapd %xmm1,%xmm0
  addsd  0x0(%r13,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L19:
  cmp    %edx,%r12d
  jl     L25
  movsd  (%rbx,%rax,8),%xmm0
  addsd  (%r14,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  jmp    L25
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void add(double P[], int degreeP, double Q[], int degreeQ, double R[]) {
  int degreeR = max(degreeP, degreeQ) + 1;
  int term;
  for (term = 0; term <= degreeR; term++) {
    R[term] = 0;
    if (term <= degreeP) {
      R[term] += P[term];
    }
    if (term <= degreeQ) {
      R[term] += Q[term];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %ecx,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %r8,%rbx
  call   <max@plt>
  cmp    $0xffffffff,%eax
  jl     L41
  lea    0x1(%rax),%ecx
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rdx,%rax
L40:
  movq   $0x0,(%rbx,%rax,8)
  mov    %eax,%edx
  cmp    %ebp,%eax
  jg     L49
  movsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L49:
  cmp    %r12d,%edx
  jg     L22
  movsd  (%rbx,%rax,8),%xmm0
  addsd  (%r14,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L22:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rcx
  jne    L23
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void add(double P[], int degreeP, double Q[], int degreeQ, double R[]) {
  int degreeR = max(degreeP, degreeQ) + 1;
  int term;
  for (term = 0; term <= degreeR; term++) {
    R[term] = 0;
    if (term <= degreeP) {
      R[term] += P[term];
    }
    if (term <= degreeQ) {
      R[term] += Q[term];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %ecx,%esi
  push   %r13
  mov    %rdi,%r13
  mov    %r14d,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8,%rbx
  call   <max@plt>
  mov    %eax,%esi
  add    $0x1,%eax
  js     L61
  test   %r14d,%r14d
  js     L48
  cmp    %eax,%r14d
  pxor   %xmm1,%xmm1
  cmovle %r14d,%eax
  mov    %eax,%ecx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  movq   $0x0,(%rbx,%rax,8)
  mov    %eax,%edx
  mov    %eax,%edi
  movsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  cmp    %eax,%ebp
  jl     L79
  addsd  (%r12,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L79:
  add    $0x1,%rax
  add    $0x1,%edx
  cmp    %eax,%ecx
  jge    L29
  cmp    %edi,%esi
  jl     L61
L32:
  movslq %edx,%rax
  nopl   (%rax)
L76:
  movq   $0x0,(%rbx,%rax,8)
  cmp    %eax,%ebp
  jl     L20
  movsd  (%r12,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L20:
  add    $0x1,%rax
  lea    -0x1(%rax),%edx
  cmp    %edx,%esi
  jge    L76
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L48:
  xor    %edx,%edx
  pxor   %xmm1,%xmm1
  jmp    L32
```

assistant: ```c
void add(double P[], int degreeP, double Q[], int degreeQ, double R[]) {
  int degreeR = max(degreeP, degreeQ) + 1;
  int term;
  for (term = 0; term <= degreeR; term++) {
    R[term] = 0;
    if (term <= degreeP) {
      R[term] += P[term];
    }
    if (term <= degreeQ) {
      R[term] += Q[term];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<R_ancestrymap2geno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rdi
  call   <ancestrymap2geno@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_convert@plt>
  nop
  leave
  ret
```

assistant: ```c
void R_ancestrymap2geno(char **R_input_file, char **R_output_file, int *N, int *M) {
  ancestrymap2geno(*R_input_file, *R_output_file, N, M);
  print_convert(*N, *M);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<R_ancestrymap2geno>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <ancestrymap2geno@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  call   <print_convert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void R_ancestrymap2geno(char **R_input_file, char **R_output_file, int *N, int *M) {
  ancestrymap2geno(*R_input_file, *R_output_file, N, M);
  print_convert(*N, *M);
}
```