ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<_tailRecursionHelper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  jmp    L14
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_tailRecursionHelper>
L14:
  leave
  ret
```

assistant: ```c
long _tailRecursionHelper(long EV_value, long EV_sum) {
  if ((EV_value == 0)) {
    return EV_sum;
  } else {
    return _tailRecursionHelper((EV_value - 1), (EV_sum + EV_value));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<_tailRecursionHelper>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  jne    L7
  ret
L7:
  sub    $0x8,%rsp
  lea    (%rdi,%rsi,1),%rsi
  sub    $0x1,%rdi
  call   <_tailRecursionHelper>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long _tailRecursionHelper(long EV_value, long EV_sum) {
  if ((EV_value == 0)) {
    return EV_sum;
  } else {
    return _tailRecursionHelper((EV_value - 1), (EV_sum + EV_value));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_tailRecursionHelper>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L12
  nopl   0x0(%rax)
L11:
  add    %rdi,%rax
  sub    $0x1,%rdi
  jne    L11
L12:
  ret
```

assistant: ```c
long _tailRecursionHelper(long EV_value, long EV_sum) {
  if ((EV_value == 0)) {
    return EV_sum;
  } else {
    return _tailRecursionHelper((EV_value - 1), (EV_sum + EV_value));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_tailRecursionHelper>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L3
  nopl   0x0(%rax)
L17:
  add    %rdi,%rax
  sub    $0x1,%rdi
  jne    L17
L3:
  ret
```

assistant: ```c
long _tailRecursionHelper(long EV_value, long EV_sum) {
  if ((EV_value == 0)) {
    return EV_sum;
  } else {
    return _tailRecursionHelper((EV_value - 1), (EV_sum + EV_value));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L37
  cmpl   $0x1ffffffe,-0xc(%rbp)
  jg     L37
  mov    $0x1,%eax
  jmp    L26
L37:
  mov    $0x0,%eax
L26:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  cmpl   $0x63,-0xc(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L52:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L85
  addl   $0x1,-0x14(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L52
  jmp    L87
L85:
  nop
L87:
  subl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L68:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L68
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *a;
  int i, j;
  int k = nondet_int();
  __ESBMC_assume(k >= 0 && (k < 0x1FFFFFFF));
  a = malloc(k * sizeof(int));
  __ESBMC_assume(a);
  __ESBMC_assume(k >= 100);
  for (i = 0; i != k; i++)
    if (a[i] <= 1)
      break;
  i--;
  for (j = 0; j < i; ++j)
    a[j] = a[i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,%ebx
  cmp    $0x1ffffffe,%eax
  setbe  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  cmp    $0x63,%ebx
  setg   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <__ESBMC_assume@plt>
  test   %ebx,%ebx
  je     L17
  mov    %rbp,%rax
  mov    %rbp,%rcx
  mov    $0x0,%edx
L40:
  cmpl   $0x1,(%rcx)
  jle    L35
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%ebx
  jne    L40
L35:
  lea    -0x1(%rdx),%ecx
  test   %ecx,%ecx
  jle    L17
  movslq %ecx,%rcx
  lea    0x0(%rbp,%rcx,4),%rsi
  lea    -0x2(%rdx),%edx
  lea    0x4(%rbp,%rdx,4),%rcx
L2:
  mov    (%rsi),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L2
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *a;
  int i, j;
  int k = nondet_int();
  __ESBMC_assume(k >= 0 && (k < 0x1FFFFFFF));
  a = malloc(k * sizeof(int));
  __ESBMC_assume(a);
  __ESBMC_assume(k >= 100);
  for (i = 0; i != k; i++)
    if (a[i] <= 1)
      break;
  i--;
  for (j = 0; j < i; ++j)
    a[j] = a[i];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <nondet_int@plt>
  xor    %edi,%edi
  cmp    $0x1ffffffe,%eax
  mov    %eax,%ebx
  setbe  %dil
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  xor    %edi,%edi
  cmp    $0x63,%ebx
  setg   %dil
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  test   %ebx,%ebx
  je     L36
  mov    %rbp,%rax
  mov    %rbp,%rcx
  xor    %edx,%edx
  jmp    L21
  nopl   0x0(%rax)
L40:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%ebx
  je     L47
L21:
  cmpl   $0x1,(%rcx)
  jg     L40
L47:
  lea    -0x1(%rdx),%ecx
  test   %ecx,%ecx
  jle    L36
  movslq %ecx,%rcx
  sub    $0x2,%edx
  lea    0x0(%rbp,%rcx,4),%rsi
  lea    0x4(%rbp,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L46:
  mov    (%rsi),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L46
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *a;
  int i, j;
  int k = nondet_int();
  __ESBMC_assume(k >= 0 && (k < 0x1FFFFFFF));
  a = malloc(k * sizeof(int));
  __ESBMC_assume(a);
  __ESBMC_assume(k >= 100);
  for (i = 0; i != k; i++)
    if (a[i] <= 1)
      break;
  i--;
  for (j = 0; j < i; ++j)
    a[j] = a[i];
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <nondet_int@plt>
  xor    %edi,%edi
  cmp    $0x1ffffffe,%eax
  mov    %eax,%ebx
  setbe  %dil
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  movslq %ebx,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  xor    %edi,%edi
  cmp    $0x63,%ebx
  setg   %dil
  xor    %eax,%eax
  call   <__ESBMC_assume@plt>
  test   %ebx,%ebx
  je     L105
  mov    %rbp,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  jmp    L77
L29:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%ebx
  je     L87
L77:
  cmpl   $0x1,(%rdx)
  jg     L29
L87:
  lea    -0x1(%rax),%edx
  test   %edx,%edx
  jle    L105
  movslq %edx,%rsi
  mov    %edx,%r8d
  sub    $0x2,%eax
  shl    $0x2,%rsi
  shl    $0x2,%r8
  lea    0x0(%rbp,%rsi,1),%rdi
  cmp    %rsi,%r8
  jg     L71
  cmp    $0x2,%eax
  jbe    L71
  mov    %edx,%eax
  movd   (%rdi),%xmm1
  shr    $0x2,%eax
  sub    $0x1,%eax
  pshufd $0x0,%xmm1,%xmm0
  shl    $0x4,%rax
  lea    0x10(%rbp,%rax,1),%rax
  nopl   (%rax)
L53:
  movups %xmm0,(%rcx)
  add    $0x10,%rcx
  cmp    %rax,%rcx
  jne    L53
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L105
  mov    (%rdi),%esi
  movslq %eax,%rcx
  lea    0x0(,%rcx,4),%r8
  mov    %esi,0x0(%rbp,%rcx,4)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L105
  add    $0x2,%eax
  mov    %esi,0x4(%rbp,%r8,1)
  cmp    %eax,%edx
  jle    L105
  mov    (%rdi),%eax
  mov    %eax,0x8(%rbp,%r8,1)
L105:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L71:
  lea    0x4(%rbp,%rax,4),%rdx
  nopw   0x0(%rax,%rax,1)
L48:
  mov    (%rdi),%eax
  add    $0x4,%rcx
  mov    %eax,-0x4(%rcx)
  cmp    %rdx,%rcx
  jne    L48
  jmp    L105
```

assistant: ```c
int main() {
  int *a;
  int i, j;
  int k = nondet_int();
  __ESBMC_assume(k >= 0 && (k < 0x1FFFFFFF));
  a = malloc(k * sizeof(int));
  __ESBMC_assume(a);
  __ESBMC_assume(k >= 100);
  for (i = 0; i != k; i++)
    if (a[i] <= 1)
      break;
  i--;
  for (j = 0; j < i; ++j)
    a[j] = a[i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<STEST906>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subq   $0x3,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D4: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)


tool: D12: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)


assistant: ```c
void STEST906(long long v) {
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)\n", v);
  v = v - 3;
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)\n", v);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<STEST906>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    -0x3(%rbx),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D13: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)


tool: D12: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)


assistant: ```c
void STEST906(long long v) {
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)\n", v);
  v = v - 3;
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)\n", v);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<STEST906>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    -0x3(%rbx),%rsi
  lea    D4(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D0: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)


tool: D4: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)


assistant: ```c
void STEST906(long long v) {
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)\n", v);
  v = v - 3;
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)\n", v);
}
```
user: What is the c source code of the assembly code below?

```asm
<STEST906>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    -0x3(%rbx),%rsi
  lea    D1(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D1
datatype: string

tool: D0: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)


tool: D1: sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)


assistant: ```c
void STEST906(long long v) {
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890123)\n", v);
  v = v - 3;
  printf("sub  (test15f - C906): Call by value long long literal :(%13lld=1234567890120)\n", v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcpf_disassoc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %r9d,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdi
  mov    -0x48(%rbp),%esi
  mov    -0x44(%rbp),%edx
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x18(%rbp),%ecx
  push   %rcx
  mov    0x10(%rbp),%ecx
  push   %rcx
  push   $0x0
  push   -0x40(%rbp)
  push   -0x30(%rbp)
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <lcpf_80211headers@plt>
  add    $0x30,%rsp
  mov    -0x18(%rbp),%rax
  mov    0x20(%rbp),%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x2,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <lcpa_append_copy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: REASONCODE

assistant: ```c
void lcpf_disassoc(struct lcpa_metapack *pack, uint8_t *src, uint8_t *dst, uint8_t *bssid, int framecontrol, int duration, int fragment, int sequence, int reasoncode) {
  uint8_t chunk[2];
  uint16_t *ch16 = (uint16_t *)chunk;
  lcpf_80211headers(pack, 0, 10, framecontrol, duration, dst, src, bssid, NULL, fragment, sequence);
  *ch16 = reasoncode;
  lcpa_append_copy(pack, "REASONCODE", 2, chunk);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lcpf_disassoc>:
  endbr64
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rcx,%rax
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  mov    %fs:0x28,%rdi
  mov    %rdi,0x10(%rsp)
  xor    %edi,%edi
  mov    0x30(%rsp),%edi
  push   %rdi
  mov    0x30(%rsp),%edi
  push   %rdi
  push   $0x0
  push   %rax
  push   %rsi
  mov    %rdx,%r9
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <lcpf_80211headers@plt>
  mov    0x60(%rsp),%eax
  mov    %eax,0x30(%rsp)
  add    $0x30,%rsp
  mov    %rsp,%rcx
  mov    $0x2,%edx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <lcpa_append_copy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: REASONCODE

assistant: ```c
void lcpf_disassoc(struct lcpa_metapack *pack, uint8_t *src, uint8_t *dst, uint8_t *bssid, int framecontrol, int duration, int fragment, int sequence, int reasoncode) {
  uint8_t chunk[2];
  uint16_t *ch16 = (uint16_t *)chunk;
  lcpf_80211headers(pack, 0, 10, framecontrol, duration, dst, src, bssid, NULL, fragment, sequence);
  *ch16 = reasoncode;
  lcpa_append_copy(pack, "REASONCODE", 2, chunk);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lcpf_disassoc>:
  endbr64
  push   %rbp
  mov    %rcx,%r10
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  mov    %rdx,%r9
  mov    $0xa,%edx
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  push   $0x0
  push   %r10
  push   %rsi
  xor    %esi,%esi
  call   <lcpf_80211headers@plt>
  mov    0x60(%rsp),%eax
  mov    $0x2,%edx
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  mov    %eax,0x30(%rsp)
  add    $0x30,%rsp
  mov    %rsp,%rcx
  call   <lcpa_append_copy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: REASONCODE

assistant: ```c
void lcpf_disassoc(struct lcpa_metapack *pack, uint8_t *src, uint8_t *dst, uint8_t *bssid, int framecontrol, int duration, int fragment, int sequence, int reasoncode) {
  uint8_t chunk[2];
  uint16_t *ch16 = (uint16_t *)chunk;
  lcpf_80211headers(pack, 0, 10, framecontrol, duration, dst, src, bssid, NULL, fragment, sequence);
  *ch16 = reasoncode;
  lcpa_append_copy(pack, "REASONCODE", 2, chunk);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lcpf_disassoc>:
  endbr64
  push   %rbp
  mov    %rcx,%r10
  mov    %r8d,%ecx
  mov    %r9d,%r8d
  mov    %rdx,%r9
  mov    $0xa,%edx
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  push   $0x0
  push   %r10
  push   %rsi
  xor    %esi,%esi
  call   <lcpf_80211headers@plt>
  mov    0x60(%rsp),%eax
  mov    $0x2,%edx
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  mov    %eax,0x30(%rsp)
  add    $0x30,%rsp
  mov    %rsp,%rcx
  call   <lcpa_append_copy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: REASONCODE

assistant: ```c
void lcpf_disassoc(struct lcpa_metapack *pack, uint8_t *src, uint8_t *dst, uint8_t *bssid, int framecontrol, int duration, int fragment, int sequence, int reasoncode) {
  uint8_t chunk[2];
  uint16_t *ch16 = (uint16_t *)chunk;
  lcpf_80211headers(pack, 0, 10, framecontrol, duration, dst, src, bssid, NULL, fragment, sequence);
  *ch16 = reasoncode;
  lcpa_append_copy(pack, "REASONCODE", 2, chunk);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L8
L17:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  imul   $0xfa,%rax,%rax
  add    $0xc1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D8
type: string

tool: D21: %lld

tool: D8: %lld


assistant: ```c
int main() {
  long long int k, t, res;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &k);
    res = 192 + (k - 1) * 250 + 1;
    printf("%lld\n", res);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L1
  lea    0x8(%rsp),%r12
  lea    D10(%rip),%rbp
  lea    D16(%rip),%rbx
L7:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rsi
  imul   $0xfa,%rsi,%rsi
  add    $0xc1,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L7
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D10: %lld

tool: D16: %lld


assistant: ```c
int main() {
  long long int k, t, res;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &k);
    res = 192 + (k - 1) * 250 + 1;
    printf("%lld\n", res);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L13
  lea    0x8(%rsp),%r12
  lea    D4(%rip),%rbp
  nop
L20:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  lea    -0x1(%rax),%rsi
  imul   $0xfa,%rsi,%rsi
  add    $0xc1,%rsi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L20
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D2: %lld

tool: D4: %lld


assistant: ```c
int main() {
  long long int k, t, res;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &k);
    res = 192 + (k - 1) * 250 + 1;
    printf("%lld\n", res);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  je     L16
  lea    0x8(%rsp),%r12
  lea    D15(%rip),%rbp
  nop
L17:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  lea    -0x1(%rax),%rsi
  imul   $0xfa,%rsi,%rsi
  add    $0xc1,%rsi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rax,%rax
  jne    L17
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D14: %lld

tool: D15: %lld


assistant: ```c
int main() {
  long long int k, t, res;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &k);
    res = 192 + (k - 1) * 250 + 1;
    printf("%lld\n", res);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<snd_pcm_conf_generic_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L35:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  lea    D3(%rip),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L16
  mov    $0x1,%eax
  jmp    L7
L16:
  addl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x2,-0x4(%rbp)
  jbe    L35
  mov    $0x0,%eax
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: comment

assistant: ```c
int snd_pcm_conf_generic_id(const char *id) {
  static const char ids[3][8] = {"comment", "type", "hint"};
  unsigned int k;
  for (k = 0; k < sizeof(ids) / sizeof(ids[0]); ++k) {
    if (strcmp(id, ids[k]) == 0)
      return 1;
  }
  return 0;
}
```