ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<intToFloat12>:
  endbr64
  cmp    $0x1ff,%edi
  jbe    L109
  mov    %edi,%edx
  mov    $0x0,%eax
L97:
  mov    %edx,%ecx
  shr    %edx
  mov    %eax,%esi
  add    $0x1,%eax
  cmp    $0x1ff,%edx
  ja     L97
  test   %eax,%eax
  jle    L102
  test   $0x1,%cl
  je     L17
  add    $0x1,%edx
  cmp    $0x1ff,%edx
  jbe    L17
  lea    0x2(%rsi),%eax
  mov    $0x100,%edx
L17:
  test   $0x3,%al
  je     L55
L36:
  add    $0x1,%edx
  shr    %edx
  add    $0x1,%eax
  test   $0x3,%al
  jne    L36
  test   %eax,%eax
  jle    L103
L55:
  lea    -0x1(%rax),%ecx
  sar    %cl,%edi
  lea    0x1(%rdi),%edx
  sar    %edx
L103:
  lea    0x3(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0x2,%eax
  shl    $0x9,%eax
  or     %edx,%eax
  ret
L109:
  mov    %edi,%edx
  mov    $0x0,%eax
  jmp    L103
L102:
  test   $0x3,%al
  jne    L36
  jmp    L103
```

assistant: ```c
unsigned short intToFloat12(unsigned int val) {
  int oval = val;
  int shift = 0;
  unsigned int pval = val;
  while (val > 0x1ff) {
    pval = val;
    val >>= 1;
    shift++;
  }
  if (shift > 0 && (pval & 1)) {
    val++;
    if (val > 0x1ff) {
      val = (val + 1) >> 1;
      shift++;
    }
  }
  while (shift % 4 != 0) {
    val = (val + 1) >> 1;
    shift++;
  }
  if (shift > 0) {
    val = ((oval >> (shift - 1)) + 1) >> 1;
  }
  val |= (shift / 4) << 9;
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<intToFloat12>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1ff,%edi
  jbe    L33
  mov    %edi,%ecx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %ecx,%esi
  shr    %ecx
  mov    %edx,%edi
  add    $0x1,%edx
  cmp    $0x1ff,%ecx
  ja     L38
  and    $0x1,%esi
  je     L28
  add    $0x2,%edi
  cmp    $0x1ff,%ecx
  cmove  %edi,%edx
L28:
  test   $0x3,%dl
  je     L44
  nop
L42:
  mov    %edx,%ecx
  add    $0x1,%edx
  test   $0x3,%dl
  jne    L42
L7:
  sar    %cl,%eax
  sar    $0x2,%edx
  add    $0x1,%eax
  shl    $0x9,%edx
  sar    %eax
  or     %edx,%eax
L33:
  ret
L44:
  lea    -0x1(%rdx),%ecx
  jmp    L7
```

assistant: ```c
unsigned short intToFloat12(unsigned int val) {
  int oval = val;
  int shift = 0;
  unsigned int pval = val;
  while (val > 0x1ff) {
    pval = val;
    val >>= 1;
    shift++;
  }
  if (shift > 0 && (pval & 1)) {
    val++;
    if (val > 0x1ff) {
      val = (val + 1) >> 1;
      shift++;
    }
  }
  while (shift % 4 != 0) {
    val = (val + 1) >> 1;
    shift++;
  }
  if (shift > 0) {
    val = ((oval >> (shift - 1)) + 1) >> 1;
  }
  val |= (shift / 4) << 9;
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<intToFloat12>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1ff,%edi
  jbe    L32
  mov    %edi,%esi
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %esi,%edi
  shr    %esi
  mov    %edx,%ecx
  add    $0x1,%edx
  cmp    $0x1ff,%esi
  ja     L48
  and    $0x1,%edi
  je     L45
  cmp    $0x1ff,%esi
  jne    L45
  lea    0x2(%rcx),%esi
  mov    %edx,%ecx
  mov    %esi,%edx
  jmp    L45
  nop
L43:
  mov    %edx,%ecx
  add    $0x1,%edx
L45:
  test   $0x3,%dl
  jne    L43
  sar    %cl,%eax
  sar    $0x2,%edx
  add    $0x1,%eax
  shl    $0x9,%edx
  sar    %eax
  or     %edx,%eax
L32:
  ret
```

assistant: ```c
unsigned short intToFloat12(unsigned int val) {
  int oval = val;
  int shift = 0;
  unsigned int pval = val;
  while (val > 0x1ff) {
    pval = val;
    val >>= 1;
    shift++;
  }
  if (shift > 0 && (pval & 1)) {
    val++;
    if (val > 0x1ff) {
      val = (val + 1) >> 1;
      shift++;
    }
  }
  while (shift % 4 != 0) {
    val = (val + 1) >> 1;
    shift++;
  }
  if (shift > 0) {
    val = ((oval >> (shift - 1)) + 1) >> 1;
  }
  val |= (shift / 4) << 9;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
L1:
  mov    $0x0,%eax
  call   <task1@plt>
  mov    $0x0,%eax
  call   <quittask1@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L27
  cmpl   $0x1,-0x4(%rbp)
  jne    L27
  jmp    L1
L27:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
begintask1:;
  task1();
  int endtask1 = quittask1();
  if (endtask1 == 0) {
  } else if (endtask1 == 1) {
    goto begintask1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L2:
  mov    $0x0,%eax
  call   <task1@plt>
  mov    $0x0,%eax
  call   <quittask1@plt>
  cmp    $0x1,%eax
  je     L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
begintask1:;
  task1();
  int endtask1 = quittask1();
  if (endtask1 == 0) {
  } else if (endtask1 == 1) {
    goto begintask1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <task1@plt>
  xor    %eax,%eax
  call   <quittask1@plt>
  cmp    $0x1,%eax
  je     L8
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
begintask1:;
  task1();
  int endtask1 = quittask1();
  if (endtask1 == 0) {
  } else if (endtask1 == 1) {
    goto begintask1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <task1@plt>
  xor    %eax,%eax
  call   <quittask1@plt>
  cmp    $0x1,%eax
  je     L9
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
begintask1:;
  task1();
  int endtask1 = quittask1();
  if (endtask1 == 0) {
  } else if (endtask1 == 1) {
    goto begintask1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L7
L25:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0xa,-0xc(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D0: %d

tool: D19: %dx%d=%d


assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 1; i <= 10; i++) {
    printf("%dx%d=%d\n", num, i, num * i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebx
  lea    D0(%rip),%rbp
L7:
  mov    0x4(%rsp),%esi
  mov    %esi,%ecx
  imul   %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L7
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D6: %d

tool: D0: %dx%d=%d


assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 1; i <= 10; i++) {
    printf("%dx%d=%d\n", num, i, num * i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D6
type: string

tool: D0: %d

tool: D6: %dx%d=%d


assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 1; i <= 10; i++) {
    printf("%dx%d=%d\n", num, i, num * i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    %esi,%ecx
  imul   %ebx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D12: %d

tool: D9: %dx%d=%d


assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 1; i <= 10; i++) {
    printf("%dx%d=%d\n", num, i, num * i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<fgetcounts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movq   $0x1,(%rax)
  mov    -0x38(%rbp),%rax
  movq   $0x1,(%rax)
  jmp    L26
L29:
  movzbl -0x11(%rbp),%eax
  cmp    $0xa,%al
  jne    L32
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L59
L32:
  movzbl -0x11(%rbp),%eax
  cmp    $0x20,%al
  jne    L59
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L59:
  addq   $0x1,-0x10(%rbp)
L26:
  lea    -0x11(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
size_t fgetcounts(int fd, size_t *words, size_t *lines) {
  char ch;
  size_t chars = 0;
  *words = 1;
  *lines = 1;
  while (read(fd, &ch, 1)) {
    if (ch == '\n') {
      (*lines)++;
      (*words)++;
    } else if (ch == ' ')
      (*words)++;
    chars++;
  }
  return chars;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgetcounts>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x1,(%rsi)
  movq   $0x1,(%rdx)
  mov    $0x0,%ebx
  lea    0x7(%rsp),%r13
  jmp    L6
L35:
  addq   $0x1,(%r14)
  addq   $0x1,0x0(%rbp)
L3:
  add    $0x1,%rbx
L6:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L5
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L35
  cmp    $0x20,%al
  jne    L3
  addq   $0x1,0x0(%rbp)
  jmp    L3
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fgetcounts(int fd, size_t *words, size_t *lines) {
  char ch;
  size_t chars = 0;
  *words = 1;
  *lines = 1;
  while (read(fd, &ch, 1)) {
    if (ch == '\n') {
      (*lines)++;
      (*words)++;
    } else if (ch == ' ')
      (*words)++;
    chars++;
  }
  return chars;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgetcounts>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  movq   $0x1,(%rsi)
  movq   $0x1,(%rdx)
  jmp    L21
L39:
  cmp    $0x20,%al
  jne    L59
  addq   $0x1,(%rbx)
L59:
  add    $0x1,%r12
L21:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L16
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  jne    L39
  addq   $0x1,(%r14)
  addq   $0x1,(%rbx)
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fgetcounts(int fd, size_t *words, size_t *lines) {
  char ch;
  size_t chars = 0;
  *words = 1;
  *lines = 1;
  while (read(fd, &ch, 1)) {
    if (ch == '\n') {
      (*lines)++;
      (*words)++;
    } else if (ch == ' ')
      (*words)++;
    chars++;
  }
  return chars;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fgetcounts>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  movq   $0x1,(%rsi)
  movq   $0x1,(%rdx)
  jmp    L16
L42:
  cmp    $0x20,%al
  jne    L12
  addq   $0x1,(%rbx)
L12:
  add    $0x1,%r12
L16:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L33
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  jne    L42
  addq   $0x1,(%r14)
  addq   $0x1,(%rbx)
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t fgetcounts(int fd, size_t *words, size_t *lines) {
  char ch;
  size_t chars = 0;
  *words = 1;
  *lines = 1;
  while (read(fd, &ch, 1)) {
    if (ch == '\n') {
      (*lines)++;
      (*words)++;
    } else if (ch == ' ')
      (*words)++;
    chars++;
  }
  return chars;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BGBMID_SplinePolateF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  movsd  %xmm0,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,-0x4c(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4c(%rbp),%xmm1
  movsd  -0x68(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D3(%rip),%xmm0
  subsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x40(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x48(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: f64

tool: D3: 1

assistant: ```c
double BGBMID_SplinePolateF(float *samp, int len, double t) {
  double f, g, u, v;
  double a, b, c, d;
  double p;
  int i;
  i = floor(t);
  f = t - i;
  g = 1.0 - f;
  a = samp[i - 1];
  b = samp[i + 0];
  c = samp[i + 1];
  d = samp[i + 2];
  u = b + f * (b - a);
  v = c + g * (c - d);
  p = (u * g) + (v * f);
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BGBMID_SplinePolateF>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movq   %xmm0,%rbp
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %rbp,%xmm2
  subsd  %xmm0,%xmm2
  movsd  D6(%rip),%xmm3
  subsd  %xmm2,%xmm3
  cltq
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd 0x4(%rbx,%rax,4),%xmm4
  pxor   %xmm5,%xmm5
  cvtss2sd -0x4(%rbx,%rax,4),%xmm5
  movapd %xmm0,%xmm1
  subsd  %xmm5,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd 0x8(%rbx,%rax,4),%xmm5
  movapd %xmm4,%xmm1
  subsd  %xmm5,%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double BGBMID_SplinePolateF(float *samp, int len, double t) {
  double f, g, u, v;
  double a, b, c, d;
  double p;
  int i;
  i = floor(t);
  f = t - i;
  g = 1.0 - f;
  a = samp[i - 1];
  b = samp[i + 0];
  c = samp[i + 1];
  d = samp[i + 2];
  u = b + f * (b - a);
  v = c + g * (c - d);
  p = (u * g) + (v * f);
  return (p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BGBMID_SplinePolateF>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm0
  cltq
  movsd  D5(%rip),%xmm3
  pxor   %xmm4,%xmm4
  cvtss2sd -0x4(%rbx,%rax,4),%xmm5
  cvtss2sd 0x4(%rbx,%rax,4),%xmm4
  subsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm5,%xmm1
  pxor   %xmm5,%xmm5
  cvtss2sd 0x8(%rbx,%rax,4),%xmm5
  subsd  %xmm2,%xmm3
  add    $0x10,%rsp
  pop    %rbx
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm4,%xmm1
  subsd  %xmm5,%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
double BGBMID_SplinePolateF(float *samp, int len, double t) {
  double f, g, u, v;
  double a, b, c, d;
  double p;
  int i;
  i = floor(t);
  f = t - i;
  g = 1.0 - f;
  a = samp[i - 1];
  b = samp[i + 0];
  c = samp[i + 1];
  d = samp[i + 2];
  u = b + f * (b - a);
  v = c + g * (c - d);
  p = (u * g) + (v * f);
  return (p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BGBMID_SplinePolateF>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm0
  cltq
  movsd  D7(%rip),%xmm3
  pxor   %xmm4,%xmm4
  cvtss2sd -0x4(%rbx,%rax,4),%xmm5
  cvtss2sd 0x4(%rbx,%rax,4),%xmm4
  subsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm5,%xmm1
  pxor   %xmm5,%xmm5
  cvtss2sd 0x8(%rbx,%rax,4),%xmm5
  subsd  %xmm2,%xmm3
  add    $0x10,%rsp
  pop    %rbx
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm4,%xmm1
  subsd  %xmm5,%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: f64

tool: D7: 1

assistant: ```c
double BGBMID_SplinePolateF(float *samp, int len, double t) {
  double f, g, u, v;
  double a, b, c, d;
  double p;
  int i;
  i = floor(t);
  f = t - i;
  g = 1.0 - f;
  a = samp[i - 1];
  b = samp[i + 0];
  c = samp[i + 1];
  d = samp[i + 2];
  u = b + f * (b - a);
  v = c + g * (c - d);
  p = (u * g) + (v * f);
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<txt_soundex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x0,-0x12(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L49
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x41,%eax
  cltq
  lea    D9(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,-0x11(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L50
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
  jmp    L76
L50:
  cmpb   $0x30,-0x11(%rbp)
  je     L76
  movzbl -0x11(%rbp),%eax
  cmp    -0x12(%rbp),%al
  je     L76
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L76:
  movzbl -0x11(%rbp),%eax
  mov    %al,-0x12(%rbp)
L49:
  addq   $0x1,-0x28(%rbp)
L20:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  cmpl   $0x3,-0x10(%rbp)
  jle    L15
L10:
  lea    D24(%rip),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
data_type: string

tool: D27: Z000

assistant: ```c
const char *txt_soundex(const char *string) {
  static char result[5];
  char *pt = result;
  int upper_case;
  static char map[] = "01230120022455012623010202";
  char previous = 0;
  char transform;
  int i;
  strcpy(result, "Z000");
  for (i = 0; *string && i < 4; ++string) {
    if (isalpha(*string)) {
      upper_case = toupper(*string);
      transform = map[upper_case - 'A'];
      if (!i) {
        *pt++ = upper_case;
        ++i;
      } else {
        if (transform != '0' && transform != previous) {
          *pt++ = transform;
          ++i;
        }
      }
      previous = transform;
    }
  }
  return result;
}
```