ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Check_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <Panic@plt>
L17:
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <Panic@plt>
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L2
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <Panic@plt>
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string

tool: D15: 1234567890

tool: D8: strdup

tool: D4: strdup NULL byte

tool: D25: strdup string length

assistant: ```c
void Check_strdup(void) {
  char *ptr;
  ptr = strdup("1234567890");
  if (!ptr)
    Panic("strdup");
  if (ptr[10] != '\0')
    Panic("strdup NULL byte");
  if (strlen(ptr) != 10)
    Panic("strdup string length");
  free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Check_strdup>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
L55:
  cmpb   $0x0,0xa(%rbx)
  jne    L47
L33:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jne    L34
L13:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L26:
  lea    D2(%rip),%rdi
  call   <Panic@plt>
  jmp    L55
L47:
  lea    D33(%rip),%rdi
  call   <Panic@plt>
  jmp    L33
L34:
  lea    D7(%rip),%rdi
  call   <Panic@plt>
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D7
type: string

tool: D6: 1234567890

tool: D2: strdup

tool: D33: strdup NULL byte

tool: D7: strdup string length

assistant: ```c
void Check_strdup(void) {
  char *ptr;
  ptr = strdup("1234567890");
  if (!ptr)
    Panic("strdup");
  if (ptr[10] != '\0')
    Panic("strdup NULL byte");
  if (strlen(ptr) != 10)
    Panic("strdup string length");
  free(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Check_strdup>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
L7:
  cmpb   $0x0,0xa(%rbp)
  jne    L39
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L1
  lea    D1(%rip),%rdi
  call   <Panic@plt>
L1:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
  nopl   0x0(%rax)
L39:
  lea    D18(%rip),%rdi
  call   <Panic@plt>
  jmp    L15
L37:
  lea    D34(%rip),%rdi
  call   <Panic@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D34
type: string

tool: D7: 1234567890

tool: D1: strdup string length

tool: D18: strdup NULL byte

tool: D34: strdup

assistant: ```c
void Check_strdup(void) {
  char *ptr;
  ptr = strdup("1234567890");
  if (!ptr)
    Panic("strdup");
  if (ptr[10] != '\0')
    Panic("strdup NULL byte");
  if (strlen(ptr) != 10)
    Panic("strdup string length");
  free(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Check_strdup>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L29
L37:
  cmpb   $0x0,0xa(%rbp)
  jne    L47
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  je     L27
  lea    D2(%rip),%rdi
  call   <Panic@plt>
L27:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
  nopl   0x0(%rax)
L47:
  lea    D38(%rip),%rdi
  call   <Panic@plt>
  jmp    L48
L29:
  lea    D37(%rip),%rdi
  call   <Panic@plt>
  jmp    L37
```

tool_calls: name: retrieve_data
arguments: label: D36
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D38
type_infered: string
name: retrieve_data
arguments: label: D37
type_infered: string

tool: D36: 1234567890

tool: D2: strdup string length

tool: D38: strdup NULL byte

tool: D37: strdup

assistant: ```c
void Check_strdup(void) {
  char *ptr;
  ptr = strdup("1234567890");
  if (!ptr)
    Panic("strdup");
  if (ptr[10] != '\0')
    Panic("strdup NULL byte");
  if (strlen(ptr) != 10)
    Panic("strdup string length");
  free(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<return_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L18
L26:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L52
  addl   $0x1,-0x18(%rbp)
  jmp    L29
L52:
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L26
L29:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L27:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L27
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *return_string(char *word) {
  int i, j;
  size_t size = strlen(word);
  char *tmp;
  for (i = 1; i < size; i++) {
    if (word[i] == '"') {
      i++;
      break;
    }
  }
  tmp = (char *)malloc(sizeof(char) * i + 1);
  for (j = 0; j < i; j++) {
    tmp[j] = word[j];
  }
  tmp[i] = '\0';
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<return_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x1,%rax
  jbe    L0
  lea    0x1(%rbp),%rdx
  add    %rbp,%rax
  mov    $0x1,%ebx
L22:
  cmpb   $0x22,(%rdx)
  je     L5
  add    $0x1,%ebx
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L22
  jmp    L36
L5:
  add    $0x1,%ebx
L36:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L55
  mov    $0x0,%edx
L67:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L67
L55:
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x2,%edi
  call   <malloc@plt>
  movzbl 0x0(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x1,%ebx
  jmp    L55
```

assistant: ```c
char *return_string(char *word) {
  int i, j;
  size_t size = strlen(word);
  char *tmp;
  for (i = 1; i < size; i++) {
    if (word[i] == '"') {
      i++;
      break;
    }
  }
  tmp = (char *)malloc(sizeof(char) * i + 1);
  for (j = 0; j < i; j++) {
    tmp[j] = word[j];
  }
  tmp[i] = '\0';
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<return_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x1,%rax
  jbe    L26
  mov    $0x2,%ebx
  jmp    L41
  nopl   (%rax)
L27:
  lea    0x1(%rbx),%rdx
  cmp    %rax,%rbx
  je     L20
  mov    %rdx,%rbx
L41:
  cmpb   $0x22,-0x1(%rbp,%rbx,1)
  mov    %ebx,%r12d
  jne    L27
L20:
  lea    0x1(%r12),%edi
L33:
  call   <malloc@plt>
  lea    -0x1(%r12),%edx
  lea    0x1(%rax,%rdx,1),%rsi
  sub    %rax,%rbp
  mov    %rax,%rdx
L47:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rsi
  jne    L47
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    $0x1,%ebx
  mov    $0x2,%edi
  mov    $0x1,%r12d
  jmp    L33
```

assistant: ```c
char *return_string(char *word) {
  int i, j;
  size_t size = strlen(word);
  char *tmp;
  for (i = 1; i < size; i++) {
    if (word[i] == '"') {
      i++;
      break;
    }
  }
  tmp = (char *)malloc(sizeof(char) * i + 1);
  for (j = 0; j < i; j++) {
    tmp[j] = word[j];
  }
  tmp[i] = '\0';
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<return_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x1,%rax
  jbe    L66
  mov    $0x2,%ebx
  jmp    L17
  nopl   0x0(%rax)
L34:
  lea    0x1(%rbx),%rdx
  cmp    %rbx,%rax
  je     L47
  mov    %rdx,%rbx
L17:
  cmpb   $0x22,-0x1(%rbp,%rbx,1)
  mov    %ebx,%r12d
  jne    L34
L47:
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  lea    0x1(%rbp),%rsi
  mov    %ebx,%ecx
  mov    %rax,%r8
  lea    -0x1(%rbx),%eax
  mov    %r8,%rdx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L184
  cmp    $0x6,%eax
  jbe    L184
  cmp    $0xe,%eax
  jbe    L126
  mov    %ebx,%eax
  mov    %rbp,%rdx
  shr    $0x4,%eax
  sub    %r8,%rdx
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%r8,%rax,1),%rsi
  mov    %r8,%rax
L169:
  movdqu (%rax,%rdx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L169
  mov    %ecx,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ecx
  je     L148
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L26
L143:
  mov    0x0(%rbp,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %ecx,%edx
  je     L148
L26:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L148
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%r12d
  jle    L148
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%r12d
  jle    L148
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%r12d
  jle    L148
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%r12d
  jle    L148
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%r12d
  jle    L148
  cltq
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L148:
  movb   $0x0,(%r8,%rbx,1)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  mov    $0x2,%edi
  mov    $0x1,%ebx
  call   <malloc@plt>
  mov    %rax,%r8
  xor    %eax,%eax
L184:
  lea    0x1(%r8,%rax,1),%rcx
  sub    %r8,%rbp
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L128:
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L128
  movb   $0x0,(%r8,%rbx,1)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L126:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L143
```

assistant: ```c
char *return_string(char *word) {
  int i, j;
  size_t size = strlen(word);
  char *tmp;
  for (i = 1; i < size; i++) {
    if (word[i] == '"') {
      i++;
      break;
    }
  }
  tmp = (char *)malloc(sizeof(char) * i + 1);
  for (j = 0; j < i; j++) {
    tmp[j] = word[j];
  }
  tmp[i] = '\0';
  return tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L6
  nop
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(int v) {
  switch (v) {
  case 1:
    break;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int v) {
  switch (v) {
  case 1:
    break;
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int v) {
  switch (v) {
  case 1:
    break;
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(int v) {
  switch (v) {
  case 1:
    break;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L86
L50:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L9
  addl   $0x1,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L86
L9:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L86:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jg     L87
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L50
  jmp    L87
L1:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L87:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L1
  jmp    L45
L77:
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L45:
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L77
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int merge(int a[], int temp[], int p, int q, int r, int s) {
  int inv = 0;
  int i = p;
  while (p <= q && r <= s) {
    if (a[r] < a[p]) {
      inv++;
      temp[i++] = a[r++];
    } else {
      temp[i++] = a[p++];
    }
  }
  while (p <= q) {
    temp[i++] = a[p++];
  }
  while (r <= s) {
    temp[i++] = a[r++];
  }
  return inv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<merge>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r11
  mov    %ecx,%esi
  cmp    %ecx,%edx
  jg     L9
  cmp    %r9d,%r8d
  jg     L9
  lea    0x1(%rdx),%ecx
  movslq %edx,%rax
  lea    (%r11,%rax,4),%rax
  mov    $0x0,%r12d
  jmp    L41
L39:
  add    $0x1,%edx
  mov    %ecx,%ebp
  mov    %r10d,(%rax)
L53:
  add    $0x1,%ecx
  add    $0x4,%rax
  cmp    %esi,%edx
  jg     L18
  cmp    %r9d,%r8d
  jg     L18
L41:
  movslq %r8d,%r10
  mov    (%rdi,%r10,4),%ebx
  movslq %edx,%r10
  mov    (%rdi,%r10,4),%r10d
  cmp    %r10d,%ebx
  jge    L39
  add    $0x1,%r12d
  add    $0x1,%r8d
  mov    %ecx,%ebp
  mov    %ebx,(%rax)
  jmp    L53
L9:
  mov    %edx,%ebp
  mov    $0x0,%r12d
L18:
  cmp    %edx,%esi
  jl     L16
  movslq %edx,%rax
  movslq %ebp,%rcx
  sub    %rax,%rcx
  lea    (%r11,%rcx,4),%r10
L78:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L78
  lea    0x1(%rbp,%rsi,1),%ebp
  sub    %edx,%ebp
L16:
  cmp    %r8d,%r9d
  jl     L20
  movslq %r8d,%r8
  movslq %ebp,%rbp
  sub    %r8,%rbp
  lea    (%r11,%rbp,4),%rdx
L98:
  mov    (%rdi,%r8,4),%eax
  mov    %eax,(%rdx,%r8,4)
  add    $0x1,%r8
  cmp    %r8d,%r9d
  jge    L98
L20:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int merge(int a[], int temp[], int p, int q, int r, int s) {
  int inv = 0;
  int i = p;
  while (p <= q && r <= s) {
    if (a[r] < a[p]) {
      inv++;
      temp[i++] = a[r++];
    } else {
      temp[i++] = a[p++];
    }
  }
  while (p <= q) {
    temp[i++] = a[p++];
  }
  while (r <= s) {
    temp[i++] = a[r++];
  }
  return inv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<merge>:
  endbr64
  push   %r12
  mov    %rsi,%r10
  mov    %ecx,%esi
  push   %rbx
  cmp    %ecx,%edx
  jg     L98
  cmp    %r9d,%r8d
  jg     L98
  lea    0x1(%rdx),%eax
  xor    %r12d,%r12d
  cltq
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ecx,-0x4(%r10,%rax,4)
  add    $0x1,%r12d
  add    $0x1,%r8d
  add    $0x1,%rax
  cmp    %esi,%edx
  jg     L68
L25:
  cmp    %r9d,%r8d
  jg     L68
L38:
  movslq %r8d,%rcx
  movslq %edx,%r11
  mov    %eax,%ebx
  mov    (%rdi,%rcx,4),%ecx
  mov    (%rdi,%r11,4),%r11d
  cmp    %r11d,%ecx
  jl     L15
  mov    %r11d,%ecx
  add    $0x1,%edx
  mov    %ecx,-0x4(%r10,%rax,4)
  add    $0x1,%rax
  cmp    %esi,%edx
  jle    L25
L68:
  cmp    %edx,%esi
  jl     L67
  movslq %edx,%rax
  movslq %ebx,%rcx
  sub    %rax,%rcx
  lea    (%r10,%rcx,4),%r11
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L21
  lea    0x1(%rbx,%rsi,1),%ebx
  sub    %edx,%ebx
L67:
  cmp    %r8d,%r9d
  jl     L60
  movslq %r8d,%r8
  movslq %ebx,%rbx
  sub    %r8,%rbx
  lea    (%r10,%rbx,4),%rdx
  nop
L99:
  mov    (%rdi,%r8,4),%eax
  mov    %eax,(%rdx,%r8,4)
  add    $0x1,%r8
  cmp    %r8d,%r9d
  jge    L99
L60:
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L98:
  mov    %edx,%ebx
  xor    %r12d,%r12d
  jmp    L68
```

assistant: ```c
int merge(int a[], int temp[], int p, int q, int r, int s) {
  int inv = 0;
  int i = p;
  while (p <= q && r <= s) {
    if (a[r] < a[p]) {
      inv++;
      temp[i++] = a[r++];
    } else {
      temp[i++] = a[p++];
    }
  }
  while (p <= q) {
    temp[i++] = a[p++];
  }
  while (r <= s) {
    temp[i++] = a[r++];
  }
  return inv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L132
  mov    $0x0,%eax
  jmp    L8
L39:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L132:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L39
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L39
  jmp    L116
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L18
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L14
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L141
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L14
L141:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L85
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L85
L14:
  addq   $0x1,-0x10(%rbp)
L116:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
L85:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L135
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L8
L135:
  mov    -0x14(%rbp),%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int my_atoi(char *str) {
  int retval = 0;
  char *ptr = str;
  char *pstr = str;
  if (NULL == str)
    return 0;
  while (*ptr == ' ' || *ptr == '\t') {
    ptr++;
    pstr = ptr;
  }
  while (*ptr) {
    if (*ptr >= '0' && (*ptr) <= '9') {
      retval = retval * 10 + (*ptr) - '0';
    } else if ((*ptr == '-' && ptr == pstr) || (*ptr == '+' && ptr == pstr)) {
      ;
    } else {
      break;
    }
    ptr++;
  }
  return pstr[0] == '-' ? -retval : retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_atoi>:
  endbr64
  test   %rdi,%rdi
  je     L85
  movzbl (%rdi),%r8d
  cmp    $0x20,%r8b
  je     L98
  cmp    $0x9,%r8b
  jne    L5
L98:
  add    $0x1,%rdi
  movzbl (%rdi),%r8d
  cmp    $0x20,%r8b
  je     L98
  cmp    $0x9,%r8b
  je     L98
L5:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L115
  mov    %rdi,%rdx
  mov    $0x0,%esi
  jmp    L47
L125:
  sub    $0x2b,%eax
  test   $0xfd,%al
  jne    L95
  cmp    %rdx,%rdi
  jne    L95
L0:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L95
L47:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L125
  lea    (%rsi,%rsi,4),%ecx
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%esi
  jmp    L0
L115:
  mov    $0x0,%esi
L95:
  mov    %esi,%eax
  neg    %eax
  cmp    $0x2d,%r8b
  cmove  %eax,%esi
L91:
  mov    %esi,%eax
  ret
L85:
  mov    $0x0,%esi
  jmp    L91
```

assistant: ```c
int my_atoi(char *str) {
  int retval = 0;
  char *ptr = str;
  char *pstr = str;
  if (NULL == str)
    return 0;
  while (*ptr == ' ' || *ptr == '\t') {
    ptr++;
    pstr = ptr;
  }
  while (*ptr) {
    if (*ptr >= '0' && (*ptr) <= '9') {
      retval = retval * 10 + (*ptr) - '0';
    } else if ((*ptr == '-' && ptr == pstr) || (*ptr == '+' && ptr == pstr)) {
      ;
    } else {
      break;
    }
    ptr++;
  }
  return pstr[0] == '-' ? -retval : retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_atoi>:
  endbr64
  test   %rdi,%rdi
  jne    L63
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L86:
  add    $0x1,%rdi
L63:
  movzbl (%rdi),%esi
  cmp    $0x20,%sil
  je     L86
  cmp    $0x9,%sil
  je     L86
  test   %sil,%sil
  je     L25
  mov    %rdi,%rdx
  movsbl %sil,%eax
  xor    %r8d,%r8d
  jmp    L40
  nopl   0x0(%rax)
L56:
  lea    (%r8,%r8,4),%ecx
  lea    -0x30(%rax,%rcx,2),%r8d
L37:
  movsbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L72
L40:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L56
  sub    $0x2b,%eax
  test   $0xfd,%al
  jne    L72
  cmp    %rdx,%rdi
  je     L37
L72:
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x2d,%sil
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int my_atoi(char *str) {
  int retval = 0;
  char *ptr = str;
  char *pstr = str;
  if (NULL == str)
    return 0;
  while (*ptr == ' ' || *ptr == '\t') {
    ptr++;
    pstr = ptr;
  }
  while (*ptr) {
    if (*ptr >= '0' && (*ptr) <= '9') {
      retval = retval * 10 + (*ptr) - '0';
    } else if ((*ptr == '-' && ptr == pstr) || (*ptr == '+' && ptr == pstr)) {
      ;
    } else {
      break;
    }
    ptr++;
  }
  return pstr[0] == '-' ? -retval : retval;
}
```