ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L58
  mov    $0x1,%ebx
  lea    0x10(%rsp),%rbp
  lea    D19(%rip),%r12
  lea    D12(%rip),%r13
  nopl   (%rax)
L1:
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jle    L20
  lea    -0x1(%rax),%edx
  movsbl 0x10(%rsp),%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  movslq %edx,%rdx
  movsbl 0x10(%rsp,%rdx,1),%ecx
  lea    -0x2(%rax),%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0xc(%rsp),%ebx
  jle    L1
L58:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L1
  jmp    L58
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D19
data_type: string
name: parse_data
arguments: label: D12
data_type: string

tool: D5: %d

tool: D19: %s

tool: D12: %c%d%c


assistant: ```c
int main(void) {
  int i, n, nn;
  char a[126];
  scanf("%d", &n);
  for (nn = 1; nn <= n; nn++) {
    scanf("%s", a);
    i = strlen(a);
    if (i > 10)
      printf("%c%d%c\n", a[0], (i - 2), a[i - 1]);
    else
      printf("%s\n", a);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_buserror_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <VDP_init@plt>
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <VDP_drawText@plt>
  mov    $0x5,%edi
  call   <showBusAddressErrorDump@plt>
L2:
  jmp    L2
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: BUS ERROR !

assistant: ```c
void _buserror_callback() {
  VDP_init();
  VDP_drawText("BUS ERROR !", 10, 3);
  showBusAddressErrorDump(5);
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_buserror_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <VDP_init@plt>
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <VDP_drawText@plt>
  mov    $0x5,%edi
  call   <showBusAddressErrorDump@plt>
L1:
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: BUS ERROR !

assistant: ```c
void _buserror_callback() {
  VDP_init();
  VDP_drawText("BUS ERROR !", 10, 3);
  showBusAddressErrorDump(5);
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_buserror_callback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <VDP_init@plt>
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D1(%rip),%rdi
  call   <VDP_drawText@plt>
  mov    $0x5,%edi
  call   <showBusAddressErrorDump@plt>
L8:
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: BUS ERROR !

assistant: ```c
void _buserror_callback() {
  VDP_init();
  VDP_drawText("BUS ERROR !", 10, 3);
  showBusAddressErrorDump(5);
  while (1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_buserror_callback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <VDP_init@plt>
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <VDP_drawText@plt>
  mov    $0x5,%edi
  call   <showBusAddressErrorDump@plt>
L9:
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: BUS ERROR !

assistant: ```c
void _buserror_callback() {
  VDP_init();
  VDP_drawText("BUS ERROR !", 10, 3);
  showBusAddressErrorDump(5);
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <read_ptr@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <read_size@plt>
  mov    %eax,-0xc(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  leave
  ret
```

assistant: ```c
void do_read() {
  char *addr = read_ptr();
  uint32_t size = read_size();
  write(STDOUT_FILENO, addr, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_read>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <read_ptr@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <read_size@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void do_read() {
  char *addr = read_ptr();
  uint32_t size = read_size();
  write(STDOUT_FILENO, addr, size);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_read>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <read_ptr@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <read_size@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %eax,%edx
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  jmp    1080 <write@plt>
```

assistant: ```c
void do_read() {
  char *addr = read_ptr();
  uint32_t size = read_size();
  write(STDOUT_FILENO, addr, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_read>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <read_ptr@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <read_size@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %eax,%edx
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  jmp    1080 <write@plt>
```

assistant: ```c
void do_read() {
  char *addr = read_ptr();
  uint32_t size = read_size();
  write(STDOUT_FILENO, addr, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addRoundKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L3:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  xor    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0xf,-0x14(%rbp)
  jle    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void addRoundKey(unsigned char *const block, const unsigned char *const key) {
  unsigned char *a = block;
  const unsigned char *b = key;
  int i;
  for (i = 0; i < 16; i++) {
    *a = (*a) ^ (*(b++));
    a++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addRoundKey>:
  endbr64
  mov    $0x0,%eax
L5:
  movzbl (%rsi,%rax,1),%edx
  xor    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L5
  ret
```

assistant: ```c
void addRoundKey(unsigned char *const block, const unsigned char *const key) {
  unsigned char *a = block;
  const unsigned char *b = key;
  int i;
  for (i = 0; i < 16; i++) {
    *a = (*a) ^ (*(b++));
    a++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<addRoundKey>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl (%rsi,%rax,1),%edx
  xor    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L7
  ret
```

assistant: ```c
void addRoundKey(unsigned char *const block, const unsigned char *const key) {
  unsigned char *a = block;
  const unsigned char *b = key;
  int i;
  for (i = 0; i < 16; i++) {
    *a = (*a) ^ (*(b++));
    a++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addRoundKey>:
  endbr64
  mov    %rsi,%rdx
  mov    %rdi,%rcx
  lea    0x1(%rsi),%rsi
  sub    %rsi,%rcx
  cmp    $0xe,%rcx
  jbe    L9
  movdqu (%rdx),%xmm0
  movdqu (%rdi),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rdx),%ecx
  xor    %cl,(%rdi)
  movzbl 0x1(%rdx),%ecx
  xor    %cl,0x1(%rdi)
  movzbl 0x2(%rdx),%ecx
  xor    %cl,0x2(%rdi)
  movzbl 0x3(%rdx),%ecx
  xor    %cl,0x3(%rdi)
  movzbl 0x4(%rdx),%ecx
  xor    %cl,0x4(%rdi)
  movzbl 0x5(%rdx),%ecx
  xor    %cl,0x5(%rdi)
  movzbl 0x6(%rdx),%ecx
  xor    %cl,0x6(%rdi)
  movzbl 0x7(%rdx),%ecx
  xor    %cl,0x7(%rdi)
  movzbl 0x8(%rdx),%ecx
  xor    %cl,0x8(%rdi)
  movzbl 0x9(%rdx),%ecx
  xor    %cl,0x9(%rdi)
  movzbl 0xa(%rdx),%ecx
  xor    %cl,0xa(%rdi)
  movzbl 0xb(%rdx),%ecx
  xor    %cl,0xb(%rdi)
  movzbl 0xc(%rdx),%ecx
  xor    %cl,0xc(%rdi)
  movzbl 0xd(%rdx),%ecx
  xor    %cl,0xd(%rdi)
  movzbl 0xe(%rdx),%ecx
  xor    %cl,0xe(%rdi)
  movzbl 0xf(%rdx),%edx
  xor    %dl,0xf(%rdi)
  ret
```

assistant: ```c
void addRoundKey(unsigned char *const block, const unsigned char *const key) {
  unsigned char *a = block;
  const unsigned char *b = key;
  int i;
  for (i = 0; i < 16; i++) {
    *a = (*a) ^ (*(b++));
    a++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x6f245ff2,-0x8(%rbp)
  movl   $0x7f67ff89,-0x4(%rbp)
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <printBits@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printBits@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D44
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string
name: extract_symbolic_data
arguments: data_label: D24
type: string
name: extract_symbolic_data
arguments: data_label: D55
type: string

tool: D44: a:

tool: D19: countBits(a,1)=%d


tool: D14: countBits(a,0)=%d


tool: D40: b:

tool: D24: countBits(b,1)=%d


tool: D55: countBits(b,0)=%d


assistant: ```c
void test4() {
  unsigned int a = 0x6F245FF2;
  unsigned int b = 0x7F67FF89;
  printf("a:\n");
  printBits(a);
  printf("countBits(a,1)=%d\n", countBits(a, 1));
  printf("countBits(a,0)=%d\n", countBits(a, 0));
  printf("b:\n");
  printBits(b);
  printf("countBits(b,1)=%d\n", countBits(b, 1));
  printf("countBits(b,0)=%d\n", countBits(b, 0));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test4>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x6f245ff2,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x7f67ff89,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  mov    %eax,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D59
datatype: string
name: unpack_data
arguments: tag: D49
datatype: string

tool: D10: a:

tool: D9: countBits(a,1)=%d


tool: D16: countBits(a,0)=%d


tool: D12: b:

tool: D59: countBits(b,1)=%d


tool: D49: countBits(b,0)=%d


assistant: ```c
void test4() {
  unsigned int a = 0x6F245FF2;
  unsigned int b = 0x7F67FF89;
  printf("a:\n");
  printBits(a);
  printf("countBits(a,1)=%d\n", countBits(a, 1));
  printf("countBits(a,0)=%d\n", countBits(a, 0));
  printf("b:\n");
  printBits(b);
  printf("countBits(b,1)=%d\n", countBits(b, 1));
  printf("countBits(b,0)=%d\n", countBits(b, 0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test4>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x6f245ff2,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x7f67ff89,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  lea    D34(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D34
datatype: string

tool: D23: a:

tool: D16: countBits(a,1)=%d


tool: D18: countBits(a,0)=%d


tool: D0: b:

tool: D9: countBits(b,1)=%d


tool: D34: countBits(b,0)=%d


assistant: ```c
void test4() {
  unsigned int a = 0x6F245FF2;
  unsigned int b = 0x7F67FF89;
  printf("a:\n");
  printBits(a);
  printf("countBits(a,1)=%d\n", countBits(a, 1));
  printf("countBits(a,0)=%d\n", countBits(a, 0));
  printf("b:\n");
  printBits(b);
  printf("countBits(b,1)=%d\n", countBits(b, 1));
  printf("countBits(b,0)=%d\n", countBits(b, 0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test4>:
  endbr64
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    $0x6f245ff2,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x6f245ff2,%edi
  call   <countBits@plt>
  lea    D57(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x7f67ff89,%edi
  call   <printBits@plt>
  mov    $0x1,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0x7f67ff89,%edi
  call   <countBits@plt>
  lea    D45(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string
name: retrieve_data
arguments: data_tag: D57
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D45
datatype: string

tool: D37: a:

tool: D33: countBits(a,1)=%d


tool: D57: countBits(a,0)=%d


tool: D7: b:

tool: D9: countBits(b,1)=%d


tool: D45: countBits(b,0)=%d


assistant: ```c
void test4() {
  unsigned int a = 0x6F245FF2;
  unsigned int b = 0x7F67FF89;
  printf("a:\n");
  printBits(a);
  printf("countBits(a,1)=%d\n", countBits(a, 1));
  printf("countBits(a,0)=%d\n", countBits(a, 0));
  printf("b:\n");
  printBits(b);
  printf("countBits(b,1)=%d\n", countBits(b, 1));
  printf("countBits(b,0)=%d\n", countBits(b, 0));
}
```
user: Translate the below assembly code into C programming language:

```asm
<getunicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L59:
  addq   $0x1,-0x8(%rbp)
L83:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x55,%al
  jne    L95
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L95
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L95
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L95
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L95
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L95
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L87
L95:
  mov    $0xffffffff,%eax
  jmp    L16
L87:
  mov    -0x8(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
L16:
  leave
  ret
```

assistant: ```c
int getunicode(char **p0) {
  char *p = *p0;
  while (*p == ' ' || *p == '\t')
    p++;
  if (*p != 'U' || p[1] != '+' || !isxdigit(p[2]) || !isxdigit(p[3]) || !isxdigit(p[4]) || !isxdigit(p[5]) || isxdigit(p[6]))
    return -1;
  *p0 = p + 6;
  return strtol(p + 2, 0, 16);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getunicode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L17
  cmp    $0x9,%al
  jne    L177
L17:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L17
  cmp    $0x9,%al
  je     L17
L177:
  cmp    $0x55,%al
  jne    L144
  cmpb   $0x2b,0x1(%rbx)
  jne    L113
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L32
  movsbl 0x3(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L62
  movsbl 0x4(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L85
  movsbl 0x5(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L45
  movsbl 0x6(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L15
  lea    0x6(%rbx),%rax
  mov    %rax,0x0(%rbp)
  lea    0x2(%rbx),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
L71:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L144:
  mov    $0xffffffff,%eax
  jmp    L71
L113:
  mov    $0xffffffff,%eax
  jmp    L71
L32:
  mov    $0xffffffff,%eax
  jmp    L71
L62:
  mov    $0xffffffff,%eax
  jmp    L71
L85:
  mov    $0xffffffff,%eax
  jmp    L71
L45:
  mov    $0xffffffff,%eax
  jmp    L71
L15:
  mov    $0xffffffff,%eax
  jmp    L71
```

assistant: ```c
int getunicode(char **p0) {
  char *p = *p0;
  while (*p == ' ' || *p == '\t')
    p++;
  if (*p != 'U' || p[1] != '+' || !isxdigit(p[2]) || !isxdigit(p[3]) || !isxdigit(p[4]) || !isxdigit(p[5]) || isxdigit(p[6]))
    return -1;
  *p0 = p + 6;
  return strtol(p + 2, 0, 16);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getunicode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L16
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L0
L16:
  cmp    $0x9,%al
  je     L0
  cmp    $0x55,%al
  jne    L61
  cmpb   $0x2b,0x1(%rbx)
  jne    L61
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl 0x3(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl 0x4(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl 0x5(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl 0x6(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L61
  lea    0x6(%rbx),%rax
  lea    0x2(%rbx),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <strtol@plt>
  xchg   %ax,%ax
L61:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int getunicode(char **p0) {
  char *p = *p0;
  while (*p == ' ' || *p == '\t')
    p++;
  if (*p != 'U' || p[1] != '+' || !isxdigit(p[2]) || !isxdigit(p[3]) || !isxdigit(p[4]) || !isxdigit(p[5]) || isxdigit(p[6]))
    return -1;
  *p0 = p + 6;
  return strtol(p + 2, 0, 16);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getunicode>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L3
  nopw   0x0(%rax,%rax,1)
L28:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L28
L3:
  cmp    $0x9,%al
  je     L28
  cmp    $0x55,%al
  jne    L21
  cmpb   $0x2b,0x1(%rbx)
  jne    L21
  movsbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  movsbl 0x3(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  movsbl 0x4(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  movsbl 0x5(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L21
  movsbl 0x6(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L21
  lea    0x6(%rbx),%rax
  lea    0x2(%rbx),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rax,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1060 <strtol@plt>
  xchg   %ax,%ax
L21:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int getunicode(char **p0) {
  char *p = *p0;
  while (*p == ' ' || *p == '\t')
    p++;
  if (*p != 'U' || p[1] != '+' || !isxdigit(p[2]) || !isxdigit(p[3]) || !isxdigit(p[4]) || !isxdigit(p[5]) || isxdigit(p[6]))
    return -1;
  *p0 = p + 6;
  return strtol(p + 2, 0, 16);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jle    L2
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  add    $0x1,%eax
  jmp    L8
L2:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
L8:
  pop    %rbp
  ret
```

assistant: ```c
int nceil(int a, int b) {
  if (a % b > 0) {
    return (a / b + 1);
  } else {
    return (a / b);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<nceil>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jle    L7
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    $0x1,%eax
  ret
L7:
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int nceil(int a, int b) {
  if (a % b > 0) {
    return (a / b + 1);
  } else {
    return (a / b);
  }
}
```