ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  test   $0x1,%sil
  je     L23
  test   $0x1,%dl
  jne    L42
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  test   $0x1,%dl
  je     L57
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L42:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L57:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L66
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
type_guessed: string
name: unpack_data
arguments: label: D41
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D44
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D37: Introduzca dos numeros separados por un espacio:

tool: D41: %i %i

tool: D12: %i es impar y %i es par


tool: D16: %i es par y %i es impar


tool: D44: %i y %i son impares


tool: D24: %i y %i son pares


assistant: ```c
int main() {
  int a, b;
  printf("Introduzca dos numeros separados por un espacio:");
  scanf("%i %i", &a, &b);
  if (a % 2 == 0 && b % 2 == 0) {
    printf("%i y %i son pares\n", a, b);
  } else if (a % 2 != 0 && b % 2 != 0) {
    printf("%i y %i son impares\n", a, b);
  } else if (a % 2 == 0 || b % 2 != 0) {
    printf("%i es par y %i es impar\n", a, b);
  } else if (a % 2 != 0 || b % 2 == 0) {
    printf("%i es impar y %i es par\n", a, b);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L71
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,%r12
  mov    %rax,%rdx
  lea    D11(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <server_log@plt>
  test   %rbx,%rbx
  jne    L74
  jmp    L76
L113:
  lea    0x20(%rsp),%rbp
  mov    %r15,%rcx
  mov    %rbp,%rdx
  lea    D18(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <server_log@plt>
  movb   $0x0,0x20(%rsp)
  jmp    L110
L137:
  mov    %rbx,%rax
  and    $0xf,%eax
  mov    %dl,(%rsp,%rax,1)
L125:
  mov    %rbx,%rax
  and    $0xf,%eax
  movb   $0x0,0x1(%rsp,%rax,1)
  movsbl %dl,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  add    $0x3,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jae    L73
  test   %rbx,%rbx
  je     L110
  test   $0xf,%bl
  je     L113
L110:
  movzbl 0x0(%r13,%rbx,1),%edx
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  jbe    L137
  lea    -0x30(%rdx),%eax
  cmp    $0x2d,%al
  ja     L17
  movabs $0x2ffffffe03ff,%rcx
  bt     %rax,%rcx
  jb     L137
L17:
  mov    %rbx,%rax
  and    $0xf,%eax
  movb   $0x2e,(%rsp,%rax,1)
  jmp    L125
L73:
  test   %r12,%r12
  mov    $0x1,%eax
  cmovne %r12,%rax
  test   $0xf,%al
  jne    L116
L76:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L116:
  mov    %rsp,%rcx
  lea    0x20(%rsp),%rdx
  lea    D18(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <server_log@plt>
  jmp    L76
L71:
  mov    %rsi,%r12
  mov    %rsi,%rdx
  lea    D11(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <server_log@plt>
L74:
  mov    $0x0,%ebx
  lea    0x20(%rsp),%rbp
  lea    D19(%rip),%r14
  mov    %rsp,%r15
  jmp    L110
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D11: HEXDUMP size: %d

tool: D18: %s	%s

tool: D19: %02x 

assistant: ```c
void hexdump(char *str, size_t size) {
  size_t i;
  size_t len = (size) ? size : strlen(str);
  char buff1[3 * 16 + 1 + 5];
  char buff2[17];
  char *ptr = buff1;
  server_log(0, "HEXDUMP size: %d", len);
  for (i = 0; i < len; i++) {
    if (i != 0 && i % 16 == 0) {
      server_log(0, "%s\t%s", buff1, buff2);
      buff1[0] = 0x00;
      ptr = buff1;
    }
    if ((str[i] >= (int)*"a" && str[i] <= (int)*"z") || (str[i] >= (int)*"A" && str[i] <= (int)*"Z") || (str[i] == (int)*"[" || str[i] == (int)*"]") || (str[i] >= (int)*"0" && str[i] <= (int)*"9")) {
      buff2[i % 16] = str[i];
    } else {
      buff2[i % 16] = *".";
    }
    buff2[(i % 16) + 1] = 0x00;
    sprintf(ptr, "%02x ", str[i] & 0xff);
    ptr += 3;
  }
  if (i % 16 != 0)
    server_log(0, "%s\t%s", buff1, buff2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_inenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L18:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <len@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strn_cmp@plt>
  test   %rax,%rax
  je     L26
  mov    -0x4(%rbp),%eax
  jmp    L9
L26:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L18
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int find_inenv(char **env, const char *str) {
  int i;
  i = 0;
  while (env[i]) {
    if ((strn_cmp(env[i], str, len(str))))
      return (i);
    i++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<find_inenv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L32
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
L12:
  mov    %ebx,%r13d
  mov    %r12,%rdi
  call   <len@plt>
  mov    %eax,%edx
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  call   <strn_cmp@plt>
  test   %rax,%rax
  jne    L14
  add    $0x1,%rbx
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  jne    L12
  mov    $0x0,%r13d
L14:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    $0x0,%r13d
  jmp    L14
```

assistant: ```c
int find_inenv(char **env, const char *str) {
  int i;
  i = 0;
  while (env[i]) {
    if ((strn_cmp(env[i], str, len(str))))
      return (i);
    i++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_inenv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L9
  mov    %rdi,%rbp
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L5
  xchg   %ax,%ax
L28:
  add    $0x1,%rbx
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  je     L9
L5:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <len@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  call   <strn_cmp@plt>
  test   %rax,%rax
  je     L28
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int find_inenv(char **env, const char *str) {
  int i;
  i = 0;
  while (env[i]) {
    if ((strn_cmp(env[i], str, len(str))))
      return (i);
    i++;
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_inenv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L9
  mov    %rdi,%rbp
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L7
  xchg   %ax,%ax
L38:
  add    $0x1,%rbx
  cmpq   $0x0,0x0(%rbp,%rbx,8)
  je     L9
L7:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <len@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  call   <strn_cmp@plt>
  test   %rax,%rax
  je     L38
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int find_inenv(char **env, const char *str) {
  int i;
  i = 0;
  while (env[i]) {
    if ((strn_cmp(env[i], str, len(str))))
      return (i);
    i++;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x64,-0x18(%rbp)
  jmp    L7
L41:
  movl   $0x64,-0x14(%rbp)
  jmp    L24
L52:
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IsPalindrome@plt>
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  addl   $0x1,-0x14(%rbp)
L24:
  cmpl   $0x3e7,-0x14(%rbp)
  jle    L52
  addl   $0x1,-0x18(%rbp)
L7:
  cmpl   $0x3e7,-0x18(%rbp)
  jle    L41
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D12: The new max palindrome is the value:roduct of two three digit numbers is: %ld


tool: D5: The maximum palindrome that is the product of two three digit numbers is: %ld


assistant: ```c
int main() {
  long int value = 0;
  long int maxPalindrome = 0;
  for (int i = 100; i < 1000; i++) {
    for (int j = 100; j < 1000; j++) {
      value = i * j;
      if (IsPalindrome(value)) {
        if (value > maxPalindrome) {
          maxPalindrome = value;
          printf("The new max palindrome is the value:roduct of two three digit numbers is: %ld\n", maxPalindrome);
        }
      }
    }
  }
  printf("The maximum palindrome that is the product of two three digit numbers is: %ld\n", maxPalindrome);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%r14d
  mov    $0x0,%r13d
  lea    D3(%rip),%r15
  jmp    L6
L63:
  add    $0x1,%ebp
  sub    $0x1,%r12d
  je     L3
L56:
  mov    %r14d,%ebx
  imul   %ebp,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <IsPalindrome@plt>
  cmp    %r13,%rbx
  jle    L63
  test   %rax,%rax
  je     L63
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %rbx,%r13
  jmp    L63
L3:
  add    $0x1,%r14d
  cmp    $0x3e8,%r14d
  je     L18
L6:
  mov    $0x384,%r12d
  mov    $0x64,%ebp
  jmp    L56
L18:
  mov    %r13,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D4
type: string

tool: D3: The new max palindrome is the value:roduct of two three digit numbers is: %ld


tool: D4: The maximum palindrome that is the product of two three digit numbers is: %ld


assistant: ```c
int main() {
  long int value = 0;
  long int maxPalindrome = 0;
  for (int i = 100; i < 1000; i++) {
    for (int j = 100; j < 1000; j++) {
      value = i * j;
      if (IsPalindrome(value)) {
        if (value > maxPalindrome) {
          maxPalindrome = value;
          printf("The new max palindrome is the value:roduct of two three digit numbers is: %ld\n", maxPalindrome);
        }
      }
    }
  }
  printf("The maximum palindrome that is the product of two three digit numbers is: %ld\n", maxPalindrome);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  mov    $0x64,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L27:
  mov    $0x384,%ebp
  mov    $0x64,%r15d
  jmp    L15
  nop
L10:
  add    $0x1,%r15d
  sub    $0x1,%ebp
  je     L8
L15:
  mov    %r13d,%ebx
  imul   %r15d,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <IsPalindrome@plt>
  cmp    %r12,%rbx
  jle    L10
  test   %rax,%rax
  je     L10
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    %rbx,%r12
  add    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L15
L8:
  add    $0x1,%r13d
  cmp    $0x3e8,%r13d
  jne    L27
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string

tool: D19: The new max palindrome is the value:roduct of two three digit numbers is: %ld


tool: D12: The maximum palindrome that is the product of two three digit numbers is: %ld


assistant: ```c
int main() {
  long int value = 0;
  long int maxPalindrome = 0;
  for (int i = 100; i < 1000; i++) {
    for (int j = 100; j < 1000; j++) {
      value = i * j;
      if (IsPalindrome(value)) {
        if (value > maxPalindrome) {
          maxPalindrome = value;
          printf("The new max palindrome is the value:roduct of two three digit numbers is: %ld\n", maxPalindrome);
        }
      }
    }
  }
  printf("The maximum palindrome that is the product of two three digit numbers is: %ld\n", maxPalindrome);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    $0x64,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L17:
  mov    $0x384,%ebp
  mov    $0x64,%r15d
  jmp    L13
  nop
L36:
  add    $0x1,%r15d
  sub    $0x1,%ebp
  je     L40
L13:
  mov    %r13d,%ebx
  imul   %r15d,%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <IsPalindrome@plt>
  cmp    %r12,%rbx
  jle    L36
  test   %rax,%rax
  je     L36
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    %rbx,%r12
  add    $0x1,%r15d
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L13
L40:
  add    $0x1,%r13d
  cmp    $0x3e8,%r13d
  jne    L17
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string

tool: D0: The new max palindrome is the value:roduct of two three digit numbers is: %ld


tool: D12: The maximum palindrome that is the product of two three digit numbers is: %ld


assistant: ```c
int main() {
  long int value = 0;
  long int maxPalindrome = 0;
  for (int i = 100; i < 1000; i++) {
    for (int j = 100; j < 1000; j++) {
      value = i * j;
      if (IsPalindrome(value)) {
        if (value > maxPalindrome) {
          maxPalindrome = value;
          printf("The new max palindrome is the value:roduct of two three digit numbers is: %ld\n", maxPalindrome);
        }
      }
    }
  }
  printf("The maximum palindrome that is the product of two three digit numbers is: %ld\n", maxPalindrome);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_n2mbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L4
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    -0x8(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
unsigned int extract_n2mbits(unsigned int input, int n, int m) {
  int value;
  int mask;
  if (n < m) {
    n = n + m;
    m = n - m;
    n = n - m;
  }
  mask = ~(~0 << (m - n + 1));
  value = (input >> n) & mask;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_n2mbits>:
  endbr64
  ret
```

assistant: ```c
unsigned int extract_n2mbits(unsigned int input, int n, int m) {
  int value;
  int mask;
  if (n < m) {
    n = n + m;
    m = n - m;
    n = n - m;
  }
  mask = ~(~0 << (m - n + 1));
  value = (input >> n) & mask;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<extract_n2mbits>:
  endbr64
  ret
```

assistant: ```c
unsigned int extract_n2mbits(unsigned int input, int n, int m) {
  int value;
  int mask;
  if (n < m) {
    n = n + m;
    m = n - m;
    n = n - m;
  }
  mask = ~(~0 << (m - n + 1));
  value = (input >> n) & mask;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<extract_n2mbits>:
  endbr64
  ret
```

assistant: ```c
unsigned int extract_n2mbits(unsigned int input, int n, int m) {
  int value;
  int mask;
  if (n < m) {
    n = n + m;
    m = n - m;
    n = n - m;
  }
  mask = ~(~0 << (m - n + 1));
  value = (input >> n) & mask;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x74(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x74(%rbp),%eax
  lea    -0x70(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D0: input n:

tool: D1: %d

assistant: ```c
main() {
  int n;
  char s[100];
  printf("input n:\n");
  scanf("%d", &n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <itoa@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: D7: input n:

tool: D9: %d

assistant: ```c
main() {
  int n;
  char s[100];
  printf("input n:\n");
  scanf("%d", &n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string

tool: D5: input n:

tool: D10: %d

assistant: ```c
main() {
  int n;
  char s[100];
  printf("input n:\n");
  scanf("%d", &n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D7: input n:

tool: D16: %d

assistant: ```c
main() {
  int n;
  char s[100];
  printf("input n:\n");
  scanf("%d", &n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compat_err_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rcx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   *%rcx
L1:
  nop
  leave
  ret
```

assistant: ```c
void compat_err_func(const char *p, int i, void *voidp) {
  void (*err_func)(const char *, int) = (void (*)(const char *, int))voidp;
  if (err_func)
    (*err_func)(p, i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compat_err_func>:
  endbr64
  test   %rdx,%rdx
  je     L4
  sub    $0x8,%rsp
  call   *%rdx
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void compat_err_func(const char *p, int i, void *voidp) {
  void (*err_func)(const char *, int) = (void (*)(const char *, int))voidp;
  if (err_func)
    (*err_func)(p, i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compat_err_func>:
  endbr64
  test   %rdx,%rdx
  je     L3
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void compat_err_func(const char *p, int i, void *voidp) {
  void (*err_func)(const char *, int) = (void (*)(const char *, int))voidp;
  if (err_func)
    (*err_func)(p, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compat_err_func>:
  endbr64
  test   %rdx,%rdx
  je     L6
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void compat_err_func(const char *p, int i, void *voidp) {
  void (*err_func)(const char *, int) = (void (*)(const char *, int))voidp;
  if (err_func)
    (*err_func)(p, i);
}
```