ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  movsd  D28(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbx
  movsd  %xmm0,0x20(%rsp)
  movsd  %xmm0,0x28(%rsp)
  call   <puts@plt>
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D67(%rip),%rdi
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  lea    0x20(%rsp),%rdi
  movsd  0x8(%rsp),%xmm0
  lea    0x28(%rsp),%rsi
  call   <oblRozwKwad@plt>
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  lea    0x48(%rsp),%rcx
  lea    0x40(%rsp),%rdx
  lea    0x38(%rsp),%rsi
  mov    %rbx,%rdi
  call   <obliczRozwDwukwad@plt>
  movq   %xmm0,%r15
  pxor   %xmm0,%xmm0
  movq   %r15,%xmm5
  comisd %xmm0,%xmm5
  jbe    L49
  xor    %ebp,%ebp
  lea    D34(%rip),%r14
  lea    D68(%rip),%r13
  lea    D65(%rip),%r12
L31:
  movsd  (%rbx),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <sprawdzRozw@plt>
  mov    %r12,%rdx
  movsd  (%rbx),%xmm0
  mov    %r14,%rdi
  test   %rax,%rax
  mov    $0x1,%eax
  cmovne %r13,%rdx
  add    $0x1,%ebp
  add    $0x8,%rbx
  mov    %ebp,%esi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movq   %r15,%xmm4
  cvtsi2sd %ebp,%xmm0
  comisd %xmm0,%xmm4
  ja     L31
L50:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  ucomisd %xmm0,%xmm5
  jp     L50
  jne    L50
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L50
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: byte[8]
name: retrieve_data
arguments: label: D67
type_guessed: string
name: retrieve_data
arguments: label: D34
type_guessed: string
name: retrieve_data
arguments: label: D68
type_guessed: string
name: retrieve_data
arguments: label: D65
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D4: Podaj wspolczynniki:

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D67: %lf %lf %lf

tool: D34: Rozwiazanie %i: %lf Czy poprawne: %s


tool: D68: tak

tool: D65: nie

tool: D16: Brak rozwiazan!

assistant: ```c
int main(void) {
  double a, b, c, t[2] = {-1, -1}, x[4], xrozw;
  printf("Podaj wspolczynniki:\n");
  scanf("%lf %lf %lf", &a, &b, &c);
  oblRozwKwad(a, b, c, t, t + 1);
  xrozw = obliczRozwDwukwad(t[0], t[1], x, x + 1, x + 2, x + 3);
  for (int i = 0; i < xrozw; ++i)
    printf("Rozwiazanie %i: %lf Czy poprawne: %s\n", i + 1, x[i], sprawdzRozw(a, b, c, x[i]) ? "tak" : "nie");
  if (xrozw == 0)
    printf("Brak rozwiazan!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L1
L51:
  shll   -0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L51
  cmpl   $0x0,-0x8(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  jmp    L61
L63:
  mov    $0x0,%eax
  call   <nondet_bool@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  je     L41
  nop
  mov    -0x24(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <nondet_bool@plt>
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
  jmp    L61
L41:
  mov    -0x24(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L61:
  cmpl   $0x0,-0x10(%rbp)
  jle    L62
  cmpl   $0x0,-0xc(%rbp)
  jg     L63
L62:
  nop
  leave
  ret
```

assistant: ```c
void f(int d) {
  int x, y, k, z = 1;
L1:
  while (z < k) {
    z = 2 * z;
  }
  assert(z >= 1);
L2:
  while (x > 0 && y > 0) {
    _Bool c = nondet_bool();
    if (c) {
    P1:
      x = x - d;
      y = nondet_bool();
      ;
      z = z - 1;
    } else {
      y = y - d;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f(int d) {
  int x, y, k, z = 1;
L1:
  while (z < k) {
    z = 2 * z;
  }
  assert(z >= 1);
L2:
  while (x > 0 && y > 0) {
    _Bool c = nondet_bool();
    if (c) {
    P1:
      x = x - d;
      y = nondet_bool();
      ;
      z = z - 1;
    } else {
      y = y - d;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f(int d) {
  int x, y, k, z = 1;
L1:
  while (z < k) {
    z = 2 * z;
  }
  assert(z >= 1);
L2:
  while (x > 0 && y > 0) {
    _Bool c = nondet_bool();
    if (c) {
    P1:
      x = x - d;
      y = nondet_bool();
      ;
      z = z - 1;
    } else {
      y = y - d;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f(int d) {
  int x, y, k, z = 1;
L1:
  while (z < k) {
    z = 2 * z;
  }
  assert(z >= 1);
L2:
  while (x > 0 && y > 0) {
    _Bool c = nondet_bool();
    if (c) {
    P1:
      x = x - d;
      y = nondet_bool();
      ;
      z = z - 1;
    } else {
      y = y - d;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ip_packet_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L27
  cmp    $0x82,%eax
  jg     L34
  cmp    $0x80,%eax
  je     L42
  cmp    $0x81,%eax
  je     L10
  jmp    L34
L27:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ip_icmp_packet_callback@plt>
  jmp    L34
L10:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ip_tcp_packet_callback@plt>
  jmp    L34
L42:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ip_udp_packet_callback@plt>
  nop
L34:
  nop
  leave
  ret
```

assistant: ```c
void ip_packet_callback(char *packet_content, int size) {
  struct iphdr *iph;
  iph = (struct iphdr *)(packet_content + sizeof(struct ethhdr));
  switch (iph->protocol) {
  case IPPROTO_ICMP:
    ip_icmp_packet_callback(packet_content, size);
    break;
  case IPPROTO_TCP:
    ip_tcp_packet_callback(packet_content, size);
    break;
  case IPPROTO_UDP:
    ip_udp_packet_callback(packet_content, size);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ip_packet_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    0x4(%rdi),%eax
  cmp    $0x81,%eax
  je     L44
  cmp    $0x82,%eax
  je     L54
  cmp    $0x80,%eax
  je     L46
L48:
  add    $0x8,%rsp
  ret
L54:
  call   <ip_icmp_packet_callback@plt>
  jmp    L48
L44:
  call   <ip_tcp_packet_callback@plt>
  jmp    L48
L46:
  call   <ip_udp_packet_callback@plt>
  jmp    L48
```

assistant: ```c
void ip_packet_callback(char *packet_content, int size) {
  struct iphdr *iph;
  iph = (struct iphdr *)(packet_content + sizeof(struct ethhdr));
  switch (iph->protocol) {
  case IPPROTO_ICMP:
    ip_icmp_packet_callback(packet_content, size);
    break;
  case IPPROTO_TCP:
    ip_tcp_packet_callback(packet_content, size);
    break;
  case IPPROTO_UDP:
    ip_udp_packet_callback(packet_content, size);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ip_packet_callback>:
  endbr64
  mov    0x4(%rdi),%eax
  cmp    $0x81,%eax
  je     L14
  cmp    $0x82,%eax
  je     L18
  cmp    $0x80,%eax
  je     L5
  ret
  nopl   (%rax)
L14:
  jmp    1070 <ip_tcp_packet_callback@plt>
  nopl   (%rax)
L5:
  jmp    1090 <ip_udp_packet_callback@plt>
  nopl   (%rax)
L18:
  jmp    1080 <ip_icmp_packet_callback@plt>
```

assistant: ```c
void ip_packet_callback(char *packet_content, int size) {
  struct iphdr *iph;
  iph = (struct iphdr *)(packet_content + sizeof(struct ethhdr));
  switch (iph->protocol) {
  case IPPROTO_ICMP:
    ip_icmp_packet_callback(packet_content, size);
    break;
  case IPPROTO_TCP:
    ip_tcp_packet_callback(packet_content, size);
    break;
  case IPPROTO_UDP:
    ip_udp_packet_callback(packet_content, size);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ip_packet_callback>:
  endbr64
  mov    0x4(%rdi),%eax
  cmp    $0x81,%eax
  je     L9
  cmp    $0x82,%eax
  je     L8
  cmp    $0x80,%eax
  je     L10
  ret
  nopl   (%rax)
L9:
  jmp    1070 <ip_tcp_packet_callback@plt>
  nopl   (%rax)
L10:
  jmp    1090 <ip_udp_packet_callback@plt>
  nopl   (%rax)
L8:
  jmp    1080 <ip_icmp_packet_callback@plt>
```

assistant: ```c
void ip_packet_callback(char *packet_content, int size) {
  struct iphdr *iph;
  iph = (struct iphdr *)(packet_content + sizeof(struct ethhdr));
  switch (iph->protocol) {
  case IPPROTO_ICMP:
    ip_icmp_packet_callback(packet_content, size);
    break;
  case IPPROTO_TCP:
    ip_tcp_packet_callback(packet_content, size);
    break;
  case IPPROTO_UDP:
    ip_udp_packet_callback(packet_content, size);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<inw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%ax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short inw(unsigned short _port) {
  unsigned short data;
  __asm__ __volatile__("in %%dx, %%ax" : "=a"(data) : "dN"(_port));
  return data;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(unsigned short _port) {
  unsigned short data;
  __asm__ __volatile__("in %%dx, %%ax" : "=a"(data) : "dN"(_port));
  return data;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(unsigned short _port) {
  unsigned short data;
  __asm__ __volatile__("in %%dx, %%ax" : "=a"(data) : "dN"(_port));
  return data;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(unsigned short _port) {
  unsigned short data;
  __asm__ __volatile__("in %%dx, %%ax" : "=a"(data) : "dN"(_port));
  return data;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Baud2Str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  sub    $0x6,%eax
  cmp    $0x4,%eax
  ja     L48
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D42(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D42(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
  lea    D32(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
  lea    D56(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
  lea    D14(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
  lea    D44(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
L48:
  lea    D25(%rip),%rax
  mov    %rax,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D56
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D44
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string

tool: D4: 9600 

tool: D32: 19.2k

tool: D56: 38.4k

tool: D14: 57.6k

tool: D44: 115.2k

tool: D25: nobaud

assistant: ```c
char *Baud2Str(unsigned char bin) {
  char *baudstr;
  unsigned char b;
  b = bin & 0x0f;
  switch (b) {
  case 6:
    baudstr = "9600 ";
    break;
  case 7:
    baudstr = "19.2k";
    break;
  case 8:
    baudstr = "38.4k";
    break;
  case 9:
    baudstr = "57.6k";
    break;
  case 10:
    baudstr = "115.2k";
    break;
  default:
    baudstr = "nobaud";
  }
  return (baudstr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Baud2Str>:
  endbr64
  and    $0xf,%edi
  sub    $0x6,%edi
  cmp    $0x4,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D28(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D67(%rip),%rax
  ret
  lea    D39(%rip),%rax
  ret
  lea    D1(%rip),%rax
  ret
  lea    D5(%rip),%rax
  ret
L6:
  lea    D26(%rip),%rax
  ret
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D67
data_type: string
name: unpack_data
arguments: label: D39
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D67: 19.2k

tool: D39: 38.4k

tool: D1: 57.6k

tool: D5: 115.2k

tool: D26: nobaud

tool: D4: 9600 

assistant: ```c
char *Baud2Str(unsigned char bin) {
  char *baudstr;
  unsigned char b;
  b = bin & 0x0f;
  switch (b) {
  case 6:
    baudstr = "9600 ";
    break;
  case 7:
    baudstr = "19.2k";
    break;
  case 8:
    baudstr = "38.4k";
    break;
  case 9:
    baudstr = "57.6k";
    break;
  case 10:
    baudstr = "115.2k";
    break;
  default:
    baudstr = "nobaud";
  }
  return (baudstr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_addchstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L11
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <addchstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L3
L11:
  nop
L3:
  leave
  ret
```

assistant: ```c
void cmd_addchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addchstr((chtype *)args[0]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmd_addchstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addchstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addchstr((chtype *)args[0]));
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_addchstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addchstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10a0 <report_return@plt>
  nopl   0x0(%rax)
L4:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addchstr((chtype *)args[0]));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_addchstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <addchstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    10a0 <report_return@plt>
  nopl   0x0(%rax)
L3:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_addchstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(addchstr((chtype *)args[0]));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L40
L53:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x8(,%r14,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L59
L30:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x3,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L48
  shl    $0x3,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L10:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L10
L48:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  jmp    L53
L59:
  lea    D1(%rip),%rdi
  call   <nrerror@plt>
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D3: Memory allocation failure 1 in matrix().

tool: D1: Memory allocation failure 2 in matrix().

assistant: ```c
double **dmatrix(long lowRow, long highRow, long lowCol, long highCol) {
  long nrow = highRow - lowRow + 1;
  long ncol = highCol - lowCol + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("Memory allocation failure 1 in matrix().");
  m += 1;
  m -= lowRow;
  m[lowRow] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[lowRow])
    nrerror("Memory allocation failure 2 in matrix().");
  m[lowRow] += 1;
  m[lowRow] -= lowCol;
  for (long i = lowRow + 1; i <= highRow; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%edi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
L42:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x8(,%r15,8),%edi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L39
L59:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,8),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L25
  lea    0x0(,%rbp,8),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopl   0x0(%rax)
L20:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L20
L25:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L31:
  lea    D17(%rip),%rdi
  call   <nrerror@plt>
  jmp    L42
  nopl   0x0(%rax)
L39:
  lea    D0(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L59
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D17: Memory allocation failure 1 in matrix().

tool: D0: Memory allocation failure 2 in matrix().

assistant: ```c
double **dmatrix(long lowRow, long highRow, long lowCol, long highCol) {
  long nrow = highRow - lowRow + 1;
  long ncol = highCol - lowCol + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("Memory allocation failure 1 in matrix().");
  m += 1;
  m -= lowRow;
  m[lowRow] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[lowRow])
    nrerror("Memory allocation failure 2 in matrix().");
  m[lowRow] += 1;
  m[lowRow] -= lowCol;
  for (long i = lowRow + 1; i <= highRow; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%edi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L6
L30:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x8(,%r15,8),%edi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L48
L57:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L23
  lea    0x0(,%rbx,8),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
  nop
L51:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L51
L23:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D11(%rip),%rdi
  call   <nrerror@plt>
  jmp    L30
  nopl   0x0(%rax)
L48:
  lea    D10(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L57
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string

tool: D11: Memory allocation failure 1 in matrix().

tool: D10: Memory allocation failure 2 in matrix().

assistant: ```c
double **dmatrix(long lowRow, long highRow, long lowCol, long highCol) {
  long nrow = highRow - lowRow + 1;
  long ncol = highCol - lowCol + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("Memory allocation failure 1 in matrix().");
  m += 1;
  m -= lowRow;
  m[lowRow] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[lowRow])
    nrerror("Memory allocation failure 2 in matrix().");
  m[lowRow] += 1;
  m[lowRow] -= lowCol;
  for (long i = lowRow + 1; i <= highRow; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```