ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<reg2>:
  endbr64
  sub    $0x18,%rsp
  lea    D56(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L28
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    0x4(%rsp),%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  shr    $0x1f,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  shr    $0x19,%esi
  and    $0x1,%esi
  call   <printf@plt>
  movzbl 0x7(%rsp),%esi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  and    $0x1,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  sar    $0xe,%esi
  and    $0x3ff,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  shr    $0x8,%esi
  and    $0x1,%esi
  call   <printf@plt>
  jmp    L23
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D56
type_guessed: string
name: disassemble_data
arguments: label: D60
type_guessed: string
name: disassemble_data
arguments: label: D43
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D44
type_guessed: string
name: disassemble_data
arguments: label: D21
type_guessed: string
name: disassemble_data
arguments: label: D53
type_guessed: string

tool: D56: 
input reg2: 

tool: D60: %x

tool: D43: LDS: %u 


tool: D24: DBR: %u 


tool: D44: RDIV2: %u 


tool: D21: R: %u 


tool: D53: LDF: %u 


assistant: ```c
void reg2(void) {
  uint32_t reg2 = 0;
  printf("\ninput reg2: ");
  if (scanf("%x", &reg2)) {
    printf("LDS: %u \n", (reg2 & 1 << 31) != 0);
    printf("DBR: %u \n", (reg2 & 1 << 25) != 0);
    printf("RDIV2: %u \n", (reg2 & 1 << 24) != 0);
    printf("R: %u \n", (reg2 & (0x3FF << 14)) >> 14);
    printf("LDF: %u \n", (reg2 & 1 << 8) != 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reg2>:
  endbr64
  sub    $0x18,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L1
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x4(%rsp),%esi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  shr    $0x1f,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  shr    $0x19,%esi
  and    $0x1,%esi
  call   <printf@plt>
  movzbl 0x7(%rsp),%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  and    $0x1,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  sar    $0xe,%esi
  and    $0x3ff,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  shr    $0x8,%esi
  and    $0x1,%esi
  call   <printf@plt>
  jmp    L28
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D45
datatype: string
name: disassemble_data
arguments: data_label: D46
datatype: string
name: disassemble_data
arguments: data_label: D68
datatype: string
name: disassemble_data
arguments: data_label: D31
datatype: string
name: disassemble_data
arguments: data_label: D49
datatype: string
name: disassemble_data
arguments: data_label: D40
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D45: 
input reg2: 

tool: D46: %x

tool: D68: LDS: %u 


tool: D31: DBR: %u 


tool: D49: RDIV2: %u 


tool: D40: R: %u 


tool: D6: LDF: %u 


assistant: ```c
void reg2(void) {
  uint32_t reg2 = 0;
  printf("\ninput reg2: ");
  if (scanf("%x", &reg2)) {
    printf("LDS: %u \n", (reg2 & 1 << 31) != 0);
    printf("DBR: %u \n", (reg2 & 1 << 25) != 0);
    printf("RDIV2: %u \n", (reg2 & 1 << 24) != 0);
    printf("R: %u \n", (reg2 & (0x3FF << 14)) >> 14);
    printf("LDF: %u \n", (reg2 & 1 << 8) != 0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<preencheMatriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L39:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x6,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  imul   $0x3e8,%eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,(%rcx,%rdx,4)
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0xa,-0x4(%rbp)
  jle    L39
  addl   $0x1,-0x8(%rbp)
L0:
  cmpl   $0x5,-0x8(%rbp)
  jle    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void preencheMatriz(int iMapaGeografico[][11]) {
  int iContador1 = 0;
  int iContador2 = 0;
  for (iContador1 = 0; iContador1 < 6; iContador1++) {
    for (iContador2 = 0; iContador2 < 11; iContador2++) {
      iMapaGeografico[iContador1][iContador2] = rand() % 1000;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<preencheMatriz>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x2c(%rdi),%rbp
  lea    0x134(%rdi),%r12
L13:
  lea    -0x2c(%rbp),%rbx
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L8
  add    $0x2c,%rbp
  cmp    %r12,%rbp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void preencheMatriz(int iMapaGeografico[][11]) {
  int iContador1 = 0;
  int iContador2 = 0;
  for (iContador1 = 0; iContador1 < 6; iContador1++) {
    for (iContador2 = 0; iContador2 < 11; iContador2++) {
      iMapaGeografico[iContador1][iContador2] = rand() % 1000;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<preencheMatriz>:
  endbr64
  push   %r12
  push   %rbp
  lea    0x134(%rdi),%rbp
  push   %rbx
  lea    0x2c(%rdi),%rbx
  nopl   0x0(%rax,%rax,1)
L10:
  lea    -0x2c(%rbx),%r12
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L19
  lea    0x2c(%r12),%rbx
  cmp    %rbp,%rbx
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void preencheMatriz(int iMapaGeografico[][11]) {
  int iContador1 = 0;
  int iContador2 = 0;
  for (iContador1 = 0; iContador1 < 6; iContador1++) {
    for (iContador2 = 0; iContador2 < 11; iContador2++) {
      iMapaGeografico[iContador1][iContador2] = rand() % 1000;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<preencheMatriz>:
  endbr64
  push   %r12
  push   %rbp
  lea    0x134(%rdi),%rbp
  push   %rbx
  lea    0x2c(%rdi),%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  lea    -0x2c(%rbx),%r12
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L10
  lea    0x2c(%r12),%rbx
  cmp    %rbp,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void preencheMatriz(int iMapaGeografico[][11]) {
  int iContador1 = 0;
  int iContador2 = 0;
  for (iContador1 = 0; iContador1 < 6; iContador1++) {
    for (iContador2 = 0; iContador2 < 11; iContador2++) {
      iMapaGeografico[iContador1][iContador2] = rand() % 1000;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<os_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L37
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <os_memcpy@plt>
  jmp    L27
L37:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L13:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L21:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
L27:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *os_memmove(void *dest, const void *src, size_t n) {
  if (dest < src) {
    os_memcpy(dest, src, n);
  } else {
    char *d = (char *)dest + n;
    const char *s = (const char *)src + n;
    while (n--) {
      *--d = *--s;
    }
  }
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<os_memmove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    %rsi,%rdi
  jb     L37
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L31
L28:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L28
L31:
  mov    %rbx,%rax
  pop    %rbx
  ret
L37:
  call   <os_memcpy@plt>
  jmp    L31
```

assistant: ```c
void *os_memmove(void *dest, const void *src, size_t n) {
  if (dest < src) {
    os_memcpy(dest, src, n);
  } else {
    char *d = (char *)dest + n;
    const char *s = (const char *)src + n;
    while (n--) {
      *--d = *--s;
    }
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<os_memmove>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  cmp    %rsi,%rdi
  jb     L4
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L23
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  sub    $0x1,%rax
  jae    L17
L23:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  call   <os_memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *os_memmove(void *dest, const void *src, size_t n) {
  if (dest < src) {
    os_memcpy(dest, src, n);
  } else {
    char *d = (char *)dest + n;
    const char *s = (const char *)src + n;
    while (n--) {
      *--d = *--s;
    }
  }
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<os_memmove>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  cmp    %rsi,%rdi
  jb     L5
  lea    -0x1(%rdx),%rax
  test   %rdx,%rdx
  je     L1
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  sub    $0x1,%rax
  jae    L12
L1:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  call   <os_memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *os_memmove(void *dest, const void *src, size_t n) {
  if (dest < src) {
    os_memcpy(dest, src, n);
  } else {
    char *d = (char *)dest + n;
    const char *s = (const char *)src + n;
    while (n--) {
      *--d = *--s;
    }
  }
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf0f4,%esi
  mov    $0x80,%edi
  call   <passShort@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  printf("%d\n", passShort(0x80, 0xf0f4));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0f4,%esi
  mov    $0x80,%edi
  call   <passShort@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: %d


assistant: ```c
int main() {
  printf("%d\n", passShort(0x80, 0xf0f4));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0f4,%esi
  mov    $0x80,%edi
  call   <passShort@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int main() {
  printf("%d\n", passShort(0x80, 0xf0f4));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf0f4,%esi
  mov    $0x80,%edi
  call   <passShort@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: %d


assistant: ```c
int main() {
  printf("%d\n", passShort(0x80, 0xf0f4));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decode_base64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x0(,%rax,4),%eax
  movslq %eax,%rdi
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %r12d,%r12d
  jle    L1
  mov    %r14,%rbx
  sub    $0x1,%r12d
  mov    %r12d,%eax
  lea    0x1(%r14,%rax,1),%r13
  mov    %r14,%rbp
L19:
  movsbl 0x0(%rbp),%edi
  call   <ctoi@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L19
  mov    %r15,%rdx
  shr    $0x2,%r12d
  mov    %r12d,%r12d
  lea    0x4(%r14,%r12,4),%rsi
L24:
  movsbl (%rbx),%eax
  shl    $0x12,%eax
  movsbl 0x3(%rbx),%ecx
  or     %ecx,%eax
  movsbl 0x1(%rbx),%ecx
  shl    $0xc,%ecx
  or     %ecx,%eax
  movsbl 0x2(%rbx),%ecx
  shl    $0x6,%ecx
  or     %ecx,%eax
  mov    %eax,%ecx
  sar    $0x10,%ecx
  mov    %cl,(%rdx)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdx)
  mov    %al,0x2(%rdx)
  add    $0x4,%rbx
  add    $0x3,%rdx
  cmp    %rsi,%rbx
  jne    L24
L1:
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  mov    %r15,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void decode_base64(char *str_in, char **str_out) {
  int i, j, b;
  int len_i = (strlen(str_in));
  char *str_t = (char *)malloc((len_i * 4) / 3);
  char *str_in_cp = (char *)malloc(len_i);
  strcpy(str_in_cp, str_in);
  for (i = 0; i < len_i; i++)
    str_in_cp[i] = ctoi(str_in_cp[i]);
  for (i = 0, j = 0; i < len_i; i += 4, j += 3) {
    b = (str_in_cp[i] << 18) | (str_in_cp[i + 1] << 12) | (str_in_cp[i + 2] << 6) | str_in_cp[i + 3];
    str_t[j] = b >> 16 & 0xff;
    str_t[j + 1] = b >> 8 & 0xff;
    str_t[j + 2] = b & 0xff;
  }
  free(str_in_cp);
  *str_out = str_t;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decode_base64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r14d
  shl    $0x2,%eax
  movslq %eax,%rdi
  sar    $0x1f,%eax
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sub    %eax,%edi
  call   <malloc@plt>
  mov    %r14d,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  test   %r14d,%r14d
  jle    L14
  lea    -0x1(%r14),%eax
  mov    %rbp,%r13
  mov    %rbp,%r12
  mov    %rax,%r14
  lea    0x1(%rbp,%rax,1),%r15
  nopl   (%rax)
L29:
  movsbl (%r12),%edi
  add    $0x1,%r12
  call   <ctoi@plt>
  mov    %al,-0x1(%r12)
  cmp    %r12,%r15
  jne    L29
  shr    $0x2,%r14d
  mov    %rbx,%rdx
  lea    0x4(%rbp,%r14,4),%rsi
  nopl   0x0(%rax)
L4:
  movsbl 0x0(%r13),%eax
  movsbl 0x3(%r13),%ecx
  add    $0x4,%r13
  add    $0x3,%rdx
  shl    $0x12,%eax
  or     %ecx,%eax
  movsbl -0x3(%r13),%ecx
  shl    $0xc,%ecx
  or     %ecx,%eax
  movsbl -0x2(%r13),%ecx
  shl    $0x6,%ecx
  or     %ecx,%eax
  mov    %eax,%ecx
  mov    %ah,-0x2(%rdx)
  sar    $0x10,%ecx
  mov    %al,-0x1(%rdx)
  mov    %cl,-0x3(%rdx)
  cmp    %r13,%rsi
  jne    L4
L14:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void decode_base64(char *str_in, char **str_out) {
  int i, j, b;
  int len_i = (strlen(str_in));
  char *str_t = (char *)malloc((len_i * 4) / 3);
  char *str_in_cp = (char *)malloc(len_i);
  strcpy(str_in_cp, str_in);
  for (i = 0; i < len_i; i++)
    str_in_cp[i] = ctoi(str_in_cp[i]);
  for (i = 0, j = 0; i < len_i; i += 4, j += 3) {
    b = (str_in_cp[i] << 18) | (str_in_cp[i + 1] << 12) | (str_in_cp[i + 2] << 6) | str_in_cp[i + 3];
    str_t[j] = b >> 16 & 0xff;
    str_t[j + 1] = b >> 8 & 0xff;
    str_t[j + 2] = b & 0xff;
  }
  free(str_in_cp);
  *str_out = str_t;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_base64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r14d
  shl    $0x2,%eax
  movslq %eax,%rdi
  sar    $0x1f,%eax
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sub    %eax,%edi
  call   <malloc@plt>
  mov    %r14d,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  test   %r14d,%r14d
  jle    L10
  lea    -0x1(%r14),%eax
  mov    %rbp,%r13
  mov    %rbp,%r12
  mov    %rax,%r14
  lea    0x1(%rbp,%rax,1),%r15
  nopl   (%rax)
L18:
  movsbl (%r12),%edi
  add    $0x1,%r12
  call   <ctoi@plt>
  mov    %al,-0x1(%r12)
  cmp    %r12,%r15
  jne    L18
  shr    $0x2,%r14d
  mov    %rbx,%rdx
  lea    0x4(%rbp,%r14,4),%rsi
  nopl   0x0(%rax)
L6:
  movsbl 0x0(%r13),%eax
  movsbl 0x3(%r13),%ecx
  add    $0x4,%r13
  add    $0x3,%rdx
  shl    $0x12,%eax
  or     %ecx,%eax
  movsbl -0x3(%r13),%ecx
  shl    $0xc,%ecx
  or     %ecx,%eax
  movsbl -0x2(%r13),%ecx
  shl    $0x6,%ecx
  or     %ecx,%eax
  mov    %eax,%ecx
  mov    %ah,-0x2(%rdx)
  sar    $0x10,%ecx
  mov    %al,-0x1(%rdx)
  mov    %cl,-0x3(%rdx)
  cmp    %r13,%rsi
  jne    L6
L10:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void decode_base64(char *str_in, char **str_out) {
  int i, j, b;
  int len_i = (strlen(str_in));
  char *str_t = (char *)malloc((len_i * 4) / 3);
  char *str_in_cp = (char *)malloc(len_i);
  strcpy(str_in_cp, str_in);
  for (i = 0; i < len_i; i++)
    str_in_cp[i] = ctoi(str_in_cp[i]);
  for (i = 0, j = 0; i < len_i; i += 4, j += 3) {
    b = (str_in_cp[i] << 18) | (str_in_cp[i + 1] << 12) | (str_in_cp[i + 2] << 6) | str_in_cp[i + 3];
    str_t[j] = b >> 16 & 0xff;
    str_t[j + 1] = b >> 8 & 0xff;
    str_t[j + 2] = b & 0xff;
  }
  free(str_in_cp);
  *str_out = str_t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strmcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  jmp    L40
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L33
L17:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L33:
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L43
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L43:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L40:
  pop    %rbp
  ret
```

assistant: ```c
char *strmcpy(char *dest, const char *src, size_t maxlen) {
  char *d;
  if (maxlen == 0)
    return dest;
  d = dest;
  while (--maxlen > 0 && *src != 0)
    *d++ = *src++;
  *d = 0;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strmcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L23
  mov    %rdi,%r8
  mov    %rsi,%rcx
  lea    -0x1(%rsi,%rdx,1),%rsi
  cmp    $0x1,%rdx
  je     L24
L37:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L24
  add    $0x1,%rcx
  add    $0x1,%r8
  mov    %dl,-0x1(%r8)
  cmp    %rsi,%rcx
  jne    L37
L24:
  movb   $0x0,(%r8)
L23:
  ret
```

assistant: ```c
char *strmcpy(char *dest, const char *src, size_t maxlen) {
  char *d;
  if (maxlen == 0)
    return dest;
  d = dest;
  while (--maxlen > 0 && *src != 0)
    *d++ = *src++;
  *d = 0;
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<strmcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L45
  mov    %rdi,%rcx
  lea    -0x1(%rsi,%rdx,1),%r8
  cmp    $0x1,%rdx
  jne    L34
  jmp    L23
  nopl   0x0(%rax)
L24:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  cmp    %r8,%rsi
  je     L23
L34:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L24
L23:
  movb   $0x0,(%rcx)
L45:
  ret
```

assistant: ```c
char *strmcpy(char *dest, const char *src, size_t maxlen) {
  char *d;
  if (maxlen == 0)
    return dest;
  d = dest;
  while (--maxlen > 0 && *src != 0)
    *d++ = *src++;
  *d = 0;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strmcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L37
  mov    %rdi,%rcx
  lea    -0x1(%rsi,%rdx,1),%r8
  cmp    $0x1,%rdx
  jne    L17
  jmp    L7
  nopl   0x0(%rax)
L31:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  cmp    %r8,%rsi
  je     L7
L17:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L31
L7:
  movb   $0x0,(%rcx)
L37:
  ret
```

assistant: ```c
char *strmcpy(char *dest, const char *src, size_t maxlen) {
  char *d;
  if (maxlen == 0)
    return dest;
  d = dest;
  while (--maxlen > 0 && *src != 0)
    *d++ = *src++;
  *d = 0;
  return dest;
}
```