ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D8(%rip),%xmm0
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rsi
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D16
type_infered: string

tool: {"D8": [0x54,0x75,0x74,0x6f,0x72,0x69,0x61,0x6c,0x73,0x59,0x69,0x69,0x62,0x61,0x69,0x00]}

tool: D16: The substring is: %s


assistant: ```c
int main() {
  const char haystack[20] = "TutorialsYiibai";
  const char needle[10] = "Yiibai";
  char *ret;
  ret = strstr(haystack, needle);
  printf("The substring is: %s\n", ret);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D4(%rip),%xmm0
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rsi
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: byte[16]
name: extract_symbolic_data
arguments: label: D13
type: string

tool: {"D4": [0x54,0x75,0x74,0x6f,0x72,0x69,0x61,0x6c,0x73,0x59,0x69,0x69,0x62,0x61,0x69,0x00]}

tool: D13: The substring is: %s


assistant: ```c
int main() {
  const char haystack[20] = "TutorialsYiibai";
  const char needle[10] = "Yiibai";
  char *ret;
  ret = strstr(haystack, needle);
  printf("The substring is: %s\n", ret);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ending>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L26
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L33
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L13
L33:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int ending(char *buffer) {
  while (*buffer) {
    if (*buffer == '\n') {
      *buffer = '\0';
      return 1;
    }
    buffer++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ending>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
L6:
  cmp    $0xa,%al
  je     L10
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
  ret
L10:
  movb   $0x0,(%rdi)
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ending(char *buffer) {
  while (*buffer) {
    if (*buffer == '\n') {
      *buffer = '\0';
      return 1;
    }
    buffer++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ending>:
  endbr64
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L22:
  cmp    $0xa,%al
  je     L6
  add    $0x1,%rdi
L15:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L22
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movb   $0x0,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ending(char *buffer) {
  while (*buffer) {
    if (*buffer == '\n') {
      *buffer = '\0';
      return 1;
    }
    buffer++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ending>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L15:
  cmp    $0xa,%al
  je     L25
  add    $0x1,%rdi
L23:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movb   $0x0,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ending(char *buffer) {
  while (*buffer) {
    if (*buffer == '\n') {
      *buffer = '\0';
      return 1;
    }
    buffer++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%r14
  lea    D37(%rip),%r13
  lea    D0(%rip),%r15
  lea    D6(%rip),%rbp
  jmp    L107
L37:
  mov    $0x1,%r12d
L123:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jl     L136
L146:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebx,%eax
  add    0xc(%rsp),%eax
  js     L37
  cmp    0x4(%rsp),%eax
  jg     L81
  cltq
  mov    0x8(%rsp),%edx
  mov    %edx,0x10(%rsp,%rax,4)
  jmp    L123
L81:
  mov    $0x1,%r12d
  jmp    L123
L136:
  test   %r12d,%r12d
  je     L60
L139:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  jmp    L107
L60:
  test   %eax,%eax
  jle    L7
  mov    $0x1,%edx
  lea    0x10(%rsp),%rcx
L90:
  cmpl   $0x0,(%rcx,%rdx,4)
  je     L139
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L90
L7:
  mov    0x4(%rsp),%eax
  mov    $0x1,%ebx
  cmp    $0x1,%eax
  jle    L46
L142:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L142
L46:
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L107:
  lea    0x10(%rsp),%rdi
  mov    $0xfa0,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L119
  jle    L7
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  jmp    L146
L119:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
datatype: string
name: parse_data
arguments: label: D37
datatype: string
name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D45
datatype: string

tool: D25: %d

tool: D37: %d 

tool: D0: %d


tool: D6: %d %d

tool: D45: -1

assistant: ```c
int main() {
  int n, i, c, p, posicao[1000], erro;
  while (1) {
    erro = 0;
    memset(posicao, 0, sizeof(posicao));
    scanf("%d", &n);
    if (n == 0)
      break;
    else {
      for (i = 1; i <= n; i++) {
        scanf("%d %d", &c, &p);
        if ((i + p) < 0 || (i + p) > n)
          erro = 1;
        else
          posicao[i + p] = c;
      }
      if (erro == 0) {
        for (i = 1; i <= n; i++) {
          if (posicao[i] == 0) {
            erro = 1;
            break;
          }
        }
      }
      if (erro == 1) {
        printf("-1\n");
      } else {
        for (i = 1; i <= n - 1; i++) {
          printf("%d ", posicao[i]);
        }
        printf("%d\n", posicao[n]);
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utfToISO>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L24:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  je     L16
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L23
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x3f,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x6,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  or     %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
L23:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void utfToISO(char *s) {
  int b, b2;
  char *s2;
  s2 = s;
  while (*s) {
    b = (int)*s++;
    if ((b & 0xe0) != 0xc0)
      *s2++ = (char)b;
    else {
      b2 = (int)*s++ & 0x3f;
      b = (b & 0x03) << 6;
      *s2++ = (char)(b | b2);
    }
  }
  *s2 = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utfToISO>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  lea    0x1(%rdi),%rdx
  jmp    L14
L15:
  mov    %rdx,%rsi
  movzbl 0x1(%rdi),%eax
  and    $0x3f,%eax
  shl    $0x6,%ecx
  or     %ecx,%eax
  lea    0x2(%rdi),%rdi
L32:
  mov    %al,-0x1(%rdx)
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L20
L14:
  movsbl %al,%ecx
  mov    %eax,%esi
  and    $0xe0,%esi
  cmp    $0xc0,%esi
  je     L15
  add    $0x1,%rdi
  mov    %rdx,%rsi
  jmp    L32
L10:
  mov    %rdi,%rsi
L20:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void utfToISO(char *s) {
  int b, b2;
  char *s2;
  s2 = s;
  while (*s) {
    b = (int)*s++;
    if ((b & 0xe0) != 0xc0)
      *s2++ = (char)b;
    else {
      b2 = (int)*s++ & 0x3f;
      b = (b & 0x03) << 6;
      *s2++ = (char)(b | b2);
    }
  }
  *s2 = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utfToISO>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  mov    %rdi,%rdx
  jmp    L0
L25:
  add    $0x1,%rdx
  mov    %al,-0x1(%rdi)
  movzbl (%rdx),%eax
  test   %al,%al
  je     L4
L0:
  mov    %eax,%esi
  movsbl %al,%ecx
  add    $0x1,%rdi
  and    $0xe0,%esi
  cmp    $0xc0,%esi
  jne    L25
  movzbl 0x1(%rdx),%eax
  shl    $0x6,%ecx
  add    $0x2,%rdx
  and    $0x3f,%eax
  or     %ecx,%eax
  mov    %al,-0x1(%rdi)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L0
L4:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void utfToISO(char *s) {
  int b, b2;
  char *s2;
  s2 = s;
  while (*s) {
    b = (int)*s++;
    if ((b & 0xe0) != 0xc0)
      *s2++ = (char)b;
    else {
      b2 = (int)*s++ & 0x3f;
      b = (b & 0x03) << 6;
      *s2++ = (char)(b | b2);
    }
  }
  *s2 = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<utfToISO>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  mov    %rdi,%rdx
  jmp    L44
L11:
  mov    %al,-0x1(%rdi)
  movzbl 0x1(%rdx),%eax
  lea    0x1(%rdx),%rsi
  test   %al,%al
  je     L33
L15:
  mov    %rsi,%rdx
L44:
  mov    %eax,%esi
  movsbl %al,%ecx
  add    $0x1,%rdi
  and    $0xe0,%esi
  cmp    $0xc0,%esi
  jne    L11
  movzbl 0x1(%rdx),%eax
  shl    $0x6,%ecx
  lea    0x2(%rdx),%rsi
  and    $0x3f,%eax
  or     %ecx,%eax
  mov    %al,-0x1(%rdi)
  movzbl 0x2(%rdx),%eax
  test   %al,%al
  jne    L15
L33:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void utfToISO(char *s) {
  int b, b2;
  char *s2;
  s2 = s;
  while (*s) {
    b = (int)*s++;
    if ((b & 0xe0) != 0xc0)
      *s2++ = (char)b;
    else {
      b2 = (int)*s++ & 0x3f;
      b = (b & 0x03) << 6;
      *s2++ = (char)(b | b2);
    }
  }
  *s2 = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_isatty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((weak)) int _isatty(int fd) {
  (void)fd;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_isatty>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((weak)) int _isatty(int fd) {
  (void)fd;
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_isatty>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
__attribute__((weak)) int _isatty(int fd) {
  (void)fd;
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L23
L21:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0x1,-0x14(%rbp)
  jg     L21
  mov    -0x8(%rbp),%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int fibonacci(int n) {
  int tmp, a = 0, b = 1;
  if (n == 0)
    return 0;
  while (n > 1) {
    tmp = b;
    b = a + b;
    a = tmp;
    n--;
  }
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fibonacci>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  je     L7
  cmp    $0x1,%edi
  jle    L15
  mov    $0x1,%eax
  mov    $0x0,%ecx
  jmp    L0
L38:
  mov    %edx,%eax
L0:
  lea    (%rcx,%rax,1),%edx
  sub    $0x1,%edi
  mov    %eax,%ecx
  cmp    $0x1,%edi
  jne    L38
L7:
  mov    %edx,%eax
  ret
L15:
  mov    $0x1,%edx
  jmp    L7
```

assistant: ```c
int fibonacci(int n) {
  int tmp, a = 0, b = 1;
  if (n == 0)
    return 0;
  while (n > 1) {
    tmp = b;
    b = a + b;
    a = tmp;
    n--;
  }
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fibonacci>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L41
  cmp    $0x1,%edi
  jle    L18
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L11
  nopl   0x0(%rax)
L40:
  mov    %r8d,%eax
L11:
  sub    $0x1,%edi
  lea    (%rdx,%rax,1),%r8d
  mov    %eax,%edx
  cmp    $0x1,%edi
  jne    L40
L41:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L18:
  mov    $0x1,%r8d
  jmp    L41
```

assistant: ```c
int fibonacci(int n) {
  int tmp, a = 0, b = 1;
  if (n == 0)
    return 0;
  while (n > 1) {
    tmp = b;
    b = a + b;
    a = tmp;
    n--;
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fibonacci>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L39
  cmp    $0x1,%edi
  jle    L28
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L3
  nopl   0x0(%rax)
L9:
  mov    %r8d,%eax
L3:
  sub    $0x1,%edi
  lea    (%rdx,%rax,1),%r8d
  mov    %eax,%edx
  cmp    $0x1,%edi
  jne    L9
L39:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%r8d
  jmp    L39
```

assistant: ```c
int fibonacci(int n) {
  int tmp, a = 0, b = 1;
  if (n == 0)
    return 0;
  while (n > 1) {
    tmp = b;
    b = a + b;
    a = tmp;
    n--;
  }
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L0
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sendchar@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  if (str) {
    **str = (char)c;
    ++(*str);
  } else {
    (void)sendchar(c);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    (%rdi),%rdx
  mov    %sil,(%rdx)
  addq   $0x1,(%rdi)
  ret
L6:
  sub    $0x8,%rsp
  mov    %esi,%edi
  call   <sendchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void printchar(char **str, int c) {
  if (str) {
    **str = (char)c;
    ++(*str);
  } else {
    (void)sendchar(c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L8
  mov    (%rdi),%rdx
  mov    %sil,(%rdx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
L8:
  mov    %esi,%edi
  jmp    1050 <sendchar@plt>
```

assistant: ```c
void printchar(char **str, int c) {
  if (str) {
    **str = (char)c;
    ++(*str);
  } else {
    (void)sendchar(c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printchar>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    (%rdi),%rdx
  mov    %sil,(%rdx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
L6:
  mov    %esi,%edi
  jmp    1050 <sendchar@plt>
```

assistant: ```c
void printchar(char **str, int c) {
  if (str) {
    **str = (char)c;
    ++(*str);
  } else {
    (void)sendchar(c);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strip_escapes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <resize_buffer@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  jmp    L12
L27:
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L49
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  jmp    L34
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
L34:
  mov    D25(%rip),%rsi
  mov    -0x8(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x8(%rbp)
  movslq %edx,%rdx
  add    %rsi,%rdx
  mov    %al,(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L27
  mov    D25(%rip),%rax
L12:
  leave
  ret
```

assistant: ```c
const char *strip_escapes(const char *p) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(p);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*p == '\\') ? *++p : *p)))
    ++p;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  lea    D16(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L26
  mov    $0x0,%edx
  jmp    L24
L8:
  mov    D12(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L9
  add    $0x1,%rbx
L24:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L8
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbx
  jmp    L8
L9:
  mov    D12(%rip),%rax
L7:
  pop    %rbx
  ret
L26:
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
const char *strip_escapes(const char *p) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(p);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*p == '\\') ? *++p : *p)))
    ++p;
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D15(%rip),%rsi
  lea    D33(%rip),%rdi
  lea    0x1(%rax),%edx
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L21
  xor    %edx,%edx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rbx
L14:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L0
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L0:
  mov    D33(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  jne    L39
  mov    D33(%rip),%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L21:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
const char *strip_escapes(const char *p) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(p);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*p == '\\') ? *++p : *p)))
    ++p;
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D34(%rip),%rsi
  lea    D10(%rip),%rdi
  lea    0x1(%rax),%edx
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L32
  xor    %edx,%edx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D10(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L22
L55:
  add    $0x1,%rbx
L26:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L36
  movzbl 0x1(%rbx),%eax
  mov    D10(%rip),%rcx
  lea    0x1(%rbx),%rsi
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L22
  mov    %rsi,%rbx
  jmp    L55
  nopl   0x0(%rax)
L22:
  mov    D10(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
const char *strip_escapes(const char *p) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(p);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*p == '\\') ? *++p : *p)))
    ++p;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<execat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L59
L14:
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L59:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L71
  movzbl (%rax),%edx
  cmp    $0x3a,%dl
  jne    L14
L71:
  cmp    %rbx,-0x10(%rbp)
  je     L78
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movb   $0x2f,(%rdx)
  jmp    L78
L74:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rsi),%esi
  mov    %sil,(%rdx)
L78:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L74
  movb   $0x0,(%rbx)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L64
  add    $0x1,%rax
  jmp    L73
L64:
  mov    $0x0,%eax
L73:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = 0;
  return (*s1 ? ++s1 : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<execat>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L61
  cmp    $0x3a,%cl
  je     L61
  mov    %rdx,%rax
L54:
  add    $0x1,%rdi
  mov    %rax,%r8
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L15
  cmp    $0x3a,%cl
  jne    L54
L15:
  cmp    %rax,%rdx
  je     L57
  lea    0x2(%r8),%rdx
  movb   $0x2f,(%rax)
L61:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L25
L43:
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L43
L25:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  cmpb   $0x0,(%rdi)
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
L57:
  mov    %rax,%rdx
  jmp    L61
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = 0;
  return (*s1 ? ++s1 : 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<execat>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x3a,%al
  je     L34
  test   %al,%al
  je     L34
  mov    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rcx,%r8
  add    $0x1,%rdi
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  cmp    $0x3a,%al
  jne    L11
L19:
  cmp    %rcx,%rdx
  je     L34
  movb   $0x2f,(%rcx)
  movzbl (%rsi),%eax
  lea    0x2(%r8),%rdx
  test   %al,%al
  je     L58
  nopl   0x0(%rax)
L13:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rsi
L34:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L13
L58:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  xor    %edx,%edx
  cmpb   $0x0,(%rdi)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
char *execat(s1, s2, si)
register char *s1, *s2;
char *si;
{
  register char *s;
  s = si;
  while (*s1 && *s1 != ':')
    *s++ = *s1++;
  if (si != s)
    *s++ = '/';
  while (*s2)
    *s++ = *s2++;
  *s = 0;
  return (*s1 ? ++s1 : 0);
}
```