ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D7: %s v0.6final (2013-08-07)


tool: D16: info at http://www.nex-hack.info

BE WARNED! This is unfinished and/or incomplete and/or untested code!
USE AT YOUR OWN RISK!


assistant: ```c
void do_version(const char *tool_name) {
  printf("%s "
         "v0.6final (2013-08-07)"
         "\n",
         tool_name);
  printf("info at http://www.nex-hack.info\n\n"
         "BE WARNED! This is unfinished and/or incomplete and/or untested code!\n"
         "USE AT YOUR OWN RISK!\n\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_version>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D3: %s v0.6final (2013-08-07)


tool: D19: info at http://www.nex-hack.info

BE WARNED! This is unfinished and/or incomplete and/or untested code!
USE AT YOUR OWN RISK!


assistant: ```c
void do_version(const char *tool_name) {
  printf("%s "
         "v0.6final (2013-08-07)"
         "\n",
         tool_name);
  printf("info at http://www.nex-hack.info\n\n"
         "BE WARNED! This is unfinished and/or incomplete and/or untested code!\n"
         "USE AT YOUR OWN RISK!\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_version>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D10: %s v0.6final (2013-08-07)


tool: D19: info at http://www.nex-hack.info

BE WARNED! This is unfinished and/or incomplete and/or untested code!
USE AT YOUR OWN RISK!


assistant: ```c
void do_version(const char *tool_name) {
  printf("%s "
         "v0.6final (2013-08-07)"
         "\n",
         tool_name);
  printf("info at http://www.nex-hack.info\n\n"
         "BE WARNED! This is unfinished and/or incomplete and/or untested code!\n"
         "USE AT YOUR OWN RISK!\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_version>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string

tool: D2: %s v0.6final (2013-08-07)


tool: D18: info at http://www.nex-hack.info

BE WARNED! This is unfinished and/or incomplete and/or untested code!
USE AT YOUR OWN RISK!


assistant: ```c
void do_version(const char *tool_name) {
  printf("%s "
         "v0.6final (2013-08-07)"
         "\n",
         tool_name);
  printf("info at http://www.nex-hack.info\n\n"
         "BE WARNED! This is unfinished and/or incomplete and/or untested code!\n"
         "USE AT YOUR OWN RISK!\n\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D18
type_infered: string

tool: D5: Number: 

tool: D1: %d

tool: D18: Fibonacci is: %d


assistant: ```c
int main() {
  int num;
  printf("Number: ");
  scanf("%d", &num);
  printf("Fibonacci is: %d\n", fib(num));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D28
data_type: string

tool: D25: Number: 

tool: D22: %d

tool: D28: Fibonacci is: %d


assistant: ```c
int main() {
  int num;
  printf("Number: ");
  scanf("%d", &num);
  printf("Fibonacci is: %d\n", fib(num));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D22: Number: 

tool: D12: %d

tool: D6: Fibonacci is: %d


assistant: ```c
int main() {
  int num;
  printf("Number: ");
  scanf("%d", &num);
  printf("Fibonacci is: %d\n", fib(num));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fib@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D22
type: string
name: retrieve_data
arguments: data_tag: D4
type: string

tool: D2: Number: 

tool: D22: %d

tool: D4: Fibonacci is: %d


assistant: ```c
int main() {
  int num;
  printf("Number: ");
  scanf("%d", &num);
  printf("Fibonacci is: %d\n", fib(num));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc0000000,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  je     L1
  mov    $0x0,%eax
  call   <bar@plt>
L1:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
__attribute__((no, noclone)) void foo(unsigned int x) {
  signed int y = ((-0x7fffffff - 1) / 2);
  signed int r;
  if (__builtin_mul_overflow(x, y, &r))
    bar();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0xc0000000,%esi
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L14
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L14:
  mov    $0x0,%eax
  call   <bar@plt>
  jmp    L5
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(unsigned int x) {
  signed int y = ((-0x7fffffff - 1) / 2);
  signed int r;
  if (__builtin_mul_overflow(x, y, &r))
    bar();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xc0000000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L22
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  call   <bar@plt>
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(unsigned int x) {
  signed int y = ((-0x7fffffff - 1) / 2);
  signed int r;
  if (__builtin_mul_overflow(x, y, &r))
    bar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xc0000000,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L1
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <bar@plt>
  jmp    L7
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no, noclone)) void foo(unsigned int x) {
  signed int y = ((-0x7fffffff - 1) / 2);
  signed int r;
  if (__builtin_mul_overflow(x, y, &r))
    bar();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_pb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  fld1
  fstpt  -0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L37
  fldt   -0x10(%rbp)
  jmp    L21
L37:
  cmpl   $0x0,-0x14(%rbp)
  jle    L42
  jmp    L78
L75:
  fildl  -0x18(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
L78:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L75
  jmp    L15
L42:
  cmpl   $0x0,-0x14(%rbp)
  jns    L15
  jmp    L0
L62:
  fildl  -0x18(%rbp)
  fldt   -0x10(%rbp)
  fdivp  %st,%st(1)
  fstpt  -0x10(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  js     L62
L15:
  fldt   -0x10(%rbp)
L21:
  pop    %rbp
  ret
```

assistant: ```c
long double ft_pb(int power, int base) {
  long double result;
  result = 1.0;
  if (power == 0)
    return (result);
  else if (power > 0)
    while (power-- > 0)
      result *= base;
  else if (power < 0)
    while (power++ < 0)
      result /= base;
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_pb>:
  endbr64
  mov    %esi,-0xc(%rsp)
  test   %edi,%edi
  je     L10
  jle    L15
  sub    $0x1,%edi
  fld1
  fildl  -0xc(%rsp)
L23:
  fmul   %st,%st(1)
  sub    $0x1,%edi
  cmp    $0xffffffff,%edi
  jne    L23
  fstp   %st(0)
  ret
L15:
  add    $0x1,%edi
  fld1
  fildl  -0xc(%rsp)
L18:
  fdivr  %st,%st(1)
  add    $0x1,%edi
  cmp    $0x1,%edi
  jne    L18
  fstp   %st(0)
  ret
L10:
  fld1
  ret
```

assistant: ```c
long double ft_pb(int power, int base) {
  long double result;
  result = 1.0;
  if (power == 0)
    return (result);
  else if (power > 0)
    while (power-- > 0)
      result *= base;
  else if (power < 0)
    while (power++ < 0)
      result /= base;
  return (result);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_pb>:
  endbr64
  mov    %esi,-0xc(%rsp)
  test   %edi,%edi
  je     L6
  fildl  -0xc(%rsp)
  jle    L14
  fld1
  sub    $0x1,%edi
  nopw   0x0(%rax,%rax,1)
L20:
  fmul   %st(1),%st
  sub    $0x1,%edi
  jae    L20
  fstp   %st(1)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%edi
  fld1
  nopl   (%rax)
L13:
  fdiv   %st(1),%st
  add    $0x1,%edi
  cmp    $0x1,%edi
  jne    L13
  fstp   %st(1)
  ret
  nopl   (%rax)
L6:
  fld1
  ret
```

assistant: ```c
long double ft_pb(int power, int base) {
  long double result;
  result = 1.0;
  if (power == 0)
    return (result);
  else if (power > 0)
    while (power-- > 0)
      result *= base;
  else if (power < 0)
    while (power++ < 0)
      result /= base;
  return (result);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_pb>:
  endbr64
  mov    %esi,-0xc(%rsp)
  test   %edi,%edi
  je     L23
  fildl  -0xc(%rsp)
  jle    L3
  fld1
  sub    $0x1,%edi
  nopw   0x0(%rax,%rax,1)
L25:
  fmul   %st(1),%st
  sub    $0x1,%edi
  jae    L25
  fstp   %st(1)
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%edi
  fld1
  nopl   (%rax)
L0:
  fdiv   %st(1),%st
  add    $0x1,%edi
  cmp    $0x1,%edi
  jne    L0
  fstp   %st(1)
  ret
  nopl   (%rax)
L23:
  fld1
  ret
```

assistant: ```c
long double ft_pb(int power, int base) {
  long double result;
  result = 1.0;
  if (power == 0)
    return (result);
  else if (power > 0)
    while (power-- > 0)
      result *= base;
  else if (power < 0)
    while (power++ < 0)
      result /= base;
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<in_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x1,%eax
  jmp    L28
L37:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int in_array(const char *element, char **array) {
  int i;
  for (i = 0; array[i]; i++) {
    if (strcmp(element, array[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<in_array>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L6
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x8(%rax),%rbx
L10:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L20
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rsi
  test   %rsi,%rsi
  jne    L10
  mov    $0x0,%eax
  jmp    L39
L6:
  mov    $0x0,%eax
  ret
L20:
  mov    $0x1,%eax
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int in_array(const char *element, char **array) {
  int i;
  for (i = 0; array[i]; i++) {
    if (strcmp(element, array[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<in_array>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L7
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
  jmp    L9
  xchg   %ax,%ax
L8:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L20
L9:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int in_array(const char *element, char **array) {
  int i;
  for (i = 0; array[i]; i++) {
    if (strcmp(element, array[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<in_array>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L34
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
  jmp    L23
  xchg   %ax,%ax
L16:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  test   %rsi,%rsi
  je     L30
L23:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L16
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int in_array(const char *element, char **array) {
  int i;
  for (i = 0; array[i]; i++) {
    if (strcmp(element, array[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L8
  movq   $0x1,-0x10(%rbp)
  movl   $0x2,-0x18(%rbp)
  jmp    L53
L22:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x2,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L22
  mov    -0x10(%rbp),%rax
  jmp    L59
L8:
  movq   $0x1,-0x8(%rbp)
  movl   $0x3,-0x14(%rbp)
  jmp    L35
L43:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x2,-0x14(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L43
  mov    -0x8(%rbp),%rax
L59:
  pop    %rbp
  ret
```

assistant: ```c
long ffact(int a) {
  if (a % 2 == 0) {
    long prod = 1;
    int i;
    for (i = 2; i <= a; i += 2) {
      prod *= i;
    }
    return prod;
  }
  long prod = 1;
  int i;
  for (i = 3; i <= a; i += 2) {
    prod *= i;
  }
  return prod;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ffact>:
  endbr64
  test   $0x1,%dil
  je     L52
  mov    $0x3,%eax
  mov    $0x1,%edx
  cmp    $0x2,%edi
  jle    L66
L13:
  imul   %rax,%rdx
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L13
L66:
  mov    %rdx,%rax
  ret
L52:
  cmp    $0x1,%edi
  jle    L7
  mov    $0x2,%eax
  mov    $0x1,%edx
L25:
  imul   %rax,%rdx
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L25
  jmp    L66
L7:
  mov    $0x1,%edx
  jmp    L66
```

assistant: ```c
long ffact(int a) {
  if (a % 2 == 0) {
    long prod = 1;
    int i;
    for (i = 2; i <= a; i += 2) {
      prod *= i;
    }
    return prod;
  }
  long prod = 1;
  int i;
  for (i = 3; i <= a; i += 2) {
    prod *= i;
  }
  return prod;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ffact>:
  endbr64
  test   $0x1,%dil
  je     L15
  mov    $0x3,%eax
  mov    $0x1,%r8d
  cmp    $0x2,%edi
  jle    L4
  nopw   0x0(%rax,%rax,1)
L59:
  imul   %rax,%r8
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L59
L4:
  mov    %r8,%rax
  ret
L15:
  cmp    $0x1,%edi
  jle    L54
  mov    $0x2,%eax
  mov    $0x1,%r8d
L38:
  imul   %rax,%r8
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L38
  mov    %r8,%rax
  ret
L54:
  mov    $0x1,%r8d
  jmp    L4
```

assistant: ```c
long ffact(int a) {
  if (a % 2 == 0) {
    long prod = 1;
    int i;
    for (i = 2; i <= a; i += 2) {
      prod *= i;
    }
    return prod;
  }
  long prod = 1;
  int i;
  for (i = 3; i <= a; i += 2) {
    prod *= i;
  }
  return prod;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ffact>:
  endbr64
  test   $0x1,%dil
  je     L23
  mov    $0x3,%eax
  mov    $0x1,%r8d
  cmp    $0x2,%edi
  jle    L42
  nopw   0x0(%rax,%rax,1)
L28:
  imul   %rax,%r8
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L28
L42:
  mov    %r8,%rax
  ret
L23:
  cmp    $0x1,%edi
  jle    L43
  mov    $0x2,%eax
  mov    $0x1,%r8d
L11:
  imul   %rax,%r8
  add    $0x2,%rax
  cmp    %eax,%edi
  jge    L11
  mov    %r8,%rax
  ret
L43:
  mov    $0x1,%r8d
  jmp    L42
```

assistant: ```c
long ffact(int a) {
  if (a % 2 == 0) {
    long prod = 1;
    int i;
    for (i = 2; i <= a; i += 2) {
      prod *= i;
    }
    return prod;
  }
  long prod = 1;
  int i;
  for (i = 3; i <= a; i += 2) {
    prod *= i;
  }
  return prod;
}
```
user: What is the c source code of the assembly code below:

```asm
<fail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <headers_cleanup@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fail() {
  headers_cleanup();
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fail>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <headers_cleanup@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fail() {
  headers_cleanup();
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fail>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <headers_cleanup@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fail() {
  headers_cleanup();
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fail>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <headers_cleanup@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fail() {
  headers_cleanup();
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  movl   $0x2c,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %edx,%ebx
  sub    %ebx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  int arg1 = 44;
  int arg2 = 2;
  int sub = 0;
  __asm__("subl %%ebx, %%eax;" : "=a"(sub) : "a"(arg1), "b"(arg2));
  return sub;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2c,%eax
  mov    $0x2,%ebx
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int arg1 = 44;
  int arg2 = 2;
  int sub = 0;
  __asm__("subl %%ebx, %%eax;" : "=a"(sub) : "a"(arg1), "b"(arg2));
  return sub;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2c,%eax
  mov    $0x2,%ebx
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int arg1 = 44;
  int arg2 = 2;
  int sub = 0;
  __asm__("subl %%ebx, %%eax;" : "=a"(sub) : "a"(arg1), "b"(arg2));
  return sub;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2c,%eax
  mov    $0x2,%ebx
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int arg1 = 44;
  int arg2 = 2;
  int sub = 0;
  __asm__("subl %%ebx, %%eax;" : "=a"(sub) : "a"(arg1), "b"(arg2));
  return sub;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x3,%edi
  call   <g@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f(3);
  g(0x03);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x3,%edi
  call   <g@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(3);
  g(0x03);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x3,%edi
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(3);
  g(0x03);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <f@plt>
  mov    $0x3,%edi
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(3);
  g(0x03);
}
```