ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i0f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L8
L18:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x24(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x1c(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  addl   $0x1,-0x10(%rbp)
L8:
  cmpl   $0x13,-0x10(%rbp)
  jle    L18
  movss  -0x1c(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
data_type: f32

tool: D11: 1

assistant: ```c
float i0f(float x) {
  float sum = 1.0, val = 1.0, c = 0.0;
  for (int n = 1; n < 20; n++) {
    float tmp = x / (2 * n);
    val *= tmp * tmp;
    float y = val - c;
    float t = sum + y;
    c = (t - sum) - y;
    sum = t;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i0f>:
  endbr64
  movaps %xmm0,%xmm5
  mov    $0x2,%eax
  pxor   %xmm2,%xmm2
  movss  D8(%rip),%xmm3
  movaps %xmm3,%xmm0
L9:
  pxor   %xmm4,%xmm4
  cvtsi2ss %eax,%xmm4
  movaps %xmm5,%xmm1
  divss  %xmm4,%xmm1
  mulss  %xmm1,%xmm1
  mulss  %xmm1,%xmm3
  movaps %xmm3,%xmm1
  subss  %xmm2,%xmm1
  movaps %xmm0,%xmm4
  addss  %xmm1,%xmm0
  movaps %xmm0,%xmm2
  subss  %xmm4,%xmm2
  subss  %xmm1,%xmm2
  add    $0x2,%eax
  cmp    $0x28,%eax
  jne    L9
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: f32

tool: D8: 1

assistant: ```c
float i0f(float x) {
  float sum = 1.0, val = 1.0, c = 0.0;
  for (int n = 1; n < 20; n++) {
    float tmp = x / (2 * n);
    val *= tmp * tmp;
    float y = val - c;
    float t = sum + y;
    c = (t - sum) - y;
    sum = t;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i0f>:
  endbr64
  movss  D6(%rip),%xmm4
  mov    $0x2,%eax
  pxor   %xmm3,%xmm3
  movaps %xmm4,%xmm2
  nopl   0x0(%rax,%rax,1)
L8:
  pxor   %xmm5,%xmm5
  movaps %xmm0,%xmm1
  cvtsi2ss %eax,%xmm5
  add    $0x2,%eax
  divss  %xmm5,%xmm1
  movaps %xmm2,%xmm5
  mulss  %xmm1,%xmm1
  mulss  %xmm1,%xmm4
  movaps %xmm4,%xmm1
  subss  %xmm3,%xmm1
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm3
  subss  %xmm5,%xmm3
  subss  %xmm1,%xmm3
  cmp    $0x28,%eax
  jne    L8
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: f32

tool: D6: 1

assistant: ```c
float i0f(float x) {
  float sum = 1.0, val = 1.0, c = 0.0;
  for (int n = 1; n < 20; n++) {
    float tmp = x / (2 * n);
    val *= tmp * tmp;
    float y = val - c;
    float t = sum + y;
    c = (t - sum) - y;
    sum = t;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i0f>:
  endbr64
  movss  D8(%rip),%xmm4
  mov    $0x2,%eax
  pxor   %xmm3,%xmm3
  movaps %xmm4,%xmm2
  nopl   0x0(%rax,%rax,1)
L5:
  pxor   %xmm5,%xmm5
  movaps %xmm0,%xmm1
  cvtsi2ss %eax,%xmm5
  add    $0x2,%eax
  divss  %xmm5,%xmm1
  movaps %xmm2,%xmm5
  mulss  %xmm1,%xmm1
  mulss  %xmm1,%xmm4
  movaps %xmm4,%xmm1
  subss  %xmm3,%xmm1
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm3
  subss  %xmm5,%xmm3
  subss  %xmm1,%xmm3
  cmp    $0x28,%eax
  jne    L5
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: f32

tool: D8: 1

assistant: ```c
float i0f(float x) {
  float sum = 1.0, val = 1.0, c = 0.0;
  for (int n = 1; n < 20; n++) {
    float tmp = x / (2 * n);
    val *= tmp * tmp;
    float y = val - c;
    float t = sum + y;
    c = (t - sum) - y;
    sum = t;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<errata_36>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf0000fe0,%eax
  mov    (%rax),%eax
  movzbl %al,%eax
  cmp    $0x6,%eax
  jne    L31
  mov    $0xf0000fe4,%eax
  mov    (%rax),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L31
  mov    $0xf0000fe8,%eax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0x30,%eax
  jne    L37
  mov    $0x1,%eax
  jmp    L73
L37:
  mov    $0xf0000fe8,%eax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0x40,%eax
  jne    L43
  mov    $0x1,%eax
  jmp    L73
L43:
  mov    $0xf0000fe8,%eax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0x50,%eax
  jne    L31
  mov    $0x1,%eax
  jmp    L73
L31:
  mov    $0x0,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x40) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x50) {
      return true;
    }
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<errata_36>:
  endbr64
  mov    $0x0,%edx
  movabs 0xf0000fe0,%eax
  cmp    $0x6,%al
  je     L10
L27:
  mov    %edx,%eax
  ret
L10:
  movabs 0xf0000fe4,%eax
  test   $0xf,%al
  jne    L27
  movabs 0xf0000fe8,%eax
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0x30,%edx
  sete   %dl
  and    $0xe0,%eax
  cmp    $0x40,%eax
  sete   %al
  or     %eax,%edx
  movzbl %dl,%edx
  jmp    L27
```

assistant: ```c
bool errata_36(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x40) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x50) {
      return true;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<errata_36>:
  endbr64
  movabs 0xf0000fe0,%eax
  xor    %r8d,%r8d
  cmp    $0x6,%al
  je     L17
L4:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movabs 0xf0000fe4,%eax
  test   $0xf,%al
  jne    L4
  movabs 0xf0000fe8,%eax
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0x30,%edx
  sete   %r8b
  and    $0xe0,%eax
  cmp    $0x40,%eax
  sete   %al
  or     %eax,%r8d
  movzbl %r8b,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x40) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x50) {
      return true;
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<errata_36>:
  endbr64
  movabs 0xf0000fe0,%eax
  xor    %r8d,%r8d
  cmp    $0x6,%al
  je     L17
L9:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movabs 0xf0000fe4,%eax
  test   $0xf,%al
  jne    L9
  movabs 0xf0000fe8,%eax
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0x30,%edx
  sete   %r8b
  and    $0xe0,%eax
  cmp    $0x40,%eax
  sete   %al
  or     %eax,%r8d
  movzbl %r8b,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool errata_36(void) {
  if ((((*(uint32_t *)0xF0000FE0) & 0x000000FF) == 0x6) && (((*(uint32_t *)0xF0000FE4) & 0x0000000F) == 0x0)) {
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x30) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x40) {
      return true;
    }
    if (((*(uint32_t *)0xF0000FE8) & 0x000000F0) == 0x50) {
      return true;
    }
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  xor    $0x1cdb,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x2(%rdi),%esi
  test   %si,%si
  je     L34
  mov    $0x0,%eax
  lea    0x6(%rsp),%r9
  jmp    L6
L1:
  movzwl %ax,%edx
  lea    (%r9,%rdx,2),%rdx
  movzbl 0x1(%rdx),%ecx
  movzbl (%rdx),%edi
  mov    %dil,0x1(%rdx)
  mov    %cl,(%rdx)
L22:
  add    $0x2,%eax
  cmp    %si,%ax
  jae    L34
L6:
  movzwl 0x6(%rsp),%ecx
  cmp    %ax,%cx
  je     L1
  movzwl %cx,%edx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  mov    %dx,0x6(%rsp)
  jmp    L22
L34:
  movzwl 0x6(%rsp),%eax
  add    %eax,%eax
  mov    %ax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy16;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy13;
          state[0UL] = state[local1] << (((state[local1] >> (unsigned short)4) & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] != local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      } else {
        copy16 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy16;
        state[local1] = state[0UL] | state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << (unsigned short)1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl (%rdi),%ecx
  movzwl 0x2(%rdi),%edi
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    $0x1cdb,%cx
  mov    %cx,0x6(%rsp)
  test   %di,%di
  je     L8
  lea    0x6(%rsp),%r9
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L11:
  movzwl 0x6(%rsp,%rdx,2),%edx
  add    $0x2,%eax
  mov    %edx,%ecx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  mov    %dx,0x6(%rsp)
  mov    %edx,%ecx
  cmp    %di,%ax
  jae    L8
L20:
  movzwl %ax,%esi
  movzwl %ax,%edx
  lea    (%r9,%rsi,2),%rsi
  cmp    %cx,%ax
  jne    L11
  add    $0x2,%eax
  rolw   $0x8,(%rsi)
  movzwl 0x6(%rsp),%ecx
  cmp    %di,%ax
  jb     L20
L8:
  add    %ecx,%ecx
  mov    %cx,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy16;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy13;
          state[0UL] = state[local1] << (((state[local1] >> (unsigned short)4) & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] != local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      } else {
        copy16 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy16;
        state[local1] = state[0UL] | state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << (unsigned short)1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl (%rdi),%ecx
  movzwl 0x2(%rdi),%edi
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    $0x1cdb,%cx
  mov    %cx,0x6(%rsp)
  test   %di,%di
  je     L51
  lea    0x6(%rsp),%r9
  cs nopw 0x0(%rax,%rax,1)
L30:
  movzwl %ax,%esi
  movzwl %ax,%edx
  lea    (%r9,%rsi,2),%rsi
  cmp    %cx,%ax
  je     L19
  movzwl 0x6(%rsp,%rdx,2),%edx
  add    $0x2,%eax
  mov    %edx,%ecx
  shr    $0x4,%cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%edx
  mov    %dx,0x6(%rsp)
  mov    %edx,%ecx
  cmp    %ax,%di
  ja     L30
L51:
  add    %ecx,%ecx
  mov    %cx,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L19:
  add    $0x2,%eax
  rolw   $0x8,(%rsi)
  movzwl 0x6(%rsp),%ecx
  cmp    %di,%ax
  jb     L30
  jmp    L51
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  char copy16;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        if (state[0UL] == local1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy13 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy13;
          state[0UL] = state[local1] << (((state[local1] >> (unsigned short)4) & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] != local1) {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      } else {
        copy16 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy16;
        state[local1] = state[0UL] | state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << (unsigned short)1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <runtimeError@plt>
L6:
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: allocation failure in cvector()

assistant: ```c
unsigned char *cvector(long nl, long nh) {
  unsigned char *v;
  v = (unsigned char *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned char)));
  if (!v)
    runtimeError("allocation failure in cvector()");
  return v - nl + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cvector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    %rdi,%rsi
  lea    0x2(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
L4:
  sub    %rbp,%rbx
  lea    0x1(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  lea    D0(%rip),%rdi
  call   <runtimeError@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: allocation failure in cvector()

assistant: ```c
unsigned char *cvector(long nl, long nh) {
  unsigned char *v;
  v = (unsigned char *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned char)));
  if (!v)
    runtimeError("allocation failure in cvector()");
  return v - nl + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x2(%rsi),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  sub    %rbp,%rbx
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
  nop
L6:
  lea    D5(%rip),%rdi
  sub    %rbp,%rbx
  call   <runtimeError@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: allocation failure in cvector()

assistant: ```c
unsigned char *cvector(long nl, long nh) {
  unsigned char *v;
  v = (unsigned char *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned char)));
  if (!v)
    runtimeError("allocation failure in cvector()");
  return v - nl + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<cvector>:
  endbr64
  push   %rbp
  sub    %rdi,%rsi
  mov    %rdi,%rbp
  push   %rbx
  lea    0x2(%rsi),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  sub    %rbp,%rbx
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
  nop
L0:
  lea    D9(%rip),%rdi
  sub    %rbp,%rbx
  call   <runtimeError@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: allocation failure in cvector()

assistant: ```c
unsigned char *cvector(long nl, long nh) {
  unsigned char *v;
  v = (unsigned char *)malloc((size_t)((nh - nl + 1 + 1) * sizeof(unsigned char)));
  if (!v)
    runtimeError("allocation failure in cvector()");
  return v - nl + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pq_gen_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  shr    $0x3,%rax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L23
L21:
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x18(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x4,%eax
  mov    %eax,-0x28(%rbp)
  jmp    L19
L16:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  xor    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  movabs $0xfefefefefefefefe,%rax
  mov    %rdx,%rcx
  and    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  movabs $0x101010101010100,%rax
  and    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x7,%rax
  mov    %rax,%rsi
  movabs $0x101010101010101,%rax
  and    %rsi,%rax
  sub    %rax,%rdx
  movabs $0x1d1d1d1d1d1d1d1d,%rax
  and    %rdx,%rax
  xor    %rcx,%rax
  xor    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  subl   $0x1,-0x28(%rbp)
L19:
  cmpl   $0x0,-0x28(%rbp)
  jns    L16
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L23:
  mov    -0x2c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pq_gen_base(int vects, int len, void **array) {
  int i, j;
  unsigned long p, q, s;
  unsigned long **src = (unsigned long **)array;
  int blocks = len / sizeof(long);
  for (i = 0; i < blocks; i++) {
    q = p = src[vects - 3][i];
    for (j = vects - 4; j >= 0; j--) {
      p ^= s = src[j][i];
      q = s ^ (((q << 1) & 0xfefefefefefefefeULL) ^ ((((q & 0x8080808080808080ULL) << 1) - ((q & 0x8080808080808080ULL) >> 7)) & 0x1d1d1d1d1d1d1d1dULL));
    }
    src[vects - 2][i] = p;
    src[vects - 1][i] = q;
  }
  return 0;
}
```