ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<solve>:
  endbr64
  mov    (%rdi),%rax
  movslq %edx,%r11
  push   %rbp
  mov    %rsi,%rcx
  lea    0x0(,%r11,8),%rdx
  push   %rbx
  movsd  (%rsi),%xmm0
  mov    %r11,%r9
  divsd  (%rax),%xmm0
  lea    -0x8(%rdx),%rax
  movsd  %xmm0,(%rsi)
  lea    -0x1(%r11),%r10d
  lea    (%rsi,%rax,1),%rbx
  add    -0x8(%rdi,%rdx,1),%rax
  mov    %rax,%rbp
  cmp    $0x1,%r11d
  jle    L12
  mov    $0x1,%esi
  pxor   %xmm2,%xmm2
  nopl   (%rax)
L48:
  lea    0x0(,%rsi,8),%r8
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  xchg   %ax,%ax
L9:
  mov    (%rdi,%rax,8),%rdx
  movsd  (%rdx,%r8,1),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L9
  movsd  (%rcx,%rsi,8),%xmm0
  mov    (%rdi,%rsi,8),%rax
  subsd  %xmm1,%xmm0
  divsd  (%rax,%r8,1),%xmm0
  movsd  %xmm0,(%rcx,%rsi,8)
  add    $0x1,%rsi
  cmp    %rsi,%r11
  jne    L48
  movsd  (%rbx),%xmm0
  divsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%rbx)
L27:
  movslq %r10d,%r10
  lea    0x0(,%r10,8),%r8
  lea    (%rcx,%r8,1),%rdx
  sub    $0x8,%r8
  nopl   (%rax)
L57:
  mov    (%rdi,%r8,1),%rsi
  movsd  -0x8(%rdx),%xmm1
  mov    %r10,%rax
  nopl   0x0(%rax)
L16:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdx)
  cmp    %eax,%r9d
  jg     L16
  sub    $0x1,%r10
  divsd  (%rsi,%r8,1),%xmm1
  sub    $0x8,%rdx
  movsd  %xmm1,(%rdx)
  sub    $0x8,%r8
  test   %r10d,%r10d
  jg     L57
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  movsd  (%rbx),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,(%rbx)
  test   %r10d,%r10d
  jg     L27
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int solve(double **A, double *z, int n) {
  int i, k;
  double sum;
  z[0] /= A[0][0];
  for (i = 1; i < n; i++) {
    sum = 0.0;
    for (k = 0; k < i; k++)
      sum += A[k][i] * z[k];
    z[i] = (z[i] - sum) / A[i][i];
  }
  z[n - 1] /= A[n - 1][n - 1];
  for (i = n - 1; i >= 1; i--) {
    for (k = i; k < n; k++)
      z[i - 1] -= A[i - 1][k] * z[k];
    z[i - 1] /= A[i - 1][i - 1];
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qd_floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  -0x28(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L36
  ucomisd %xmm1,%xmm0
  jne    L36
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movsd  -0x20(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L54
  ucomisd %xmm1,%xmm0
  jne    L54
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L54
  ucomisd %xmm1,%xmm0
  jne    L54
  mov    -0x38(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
L54:
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <qd_renorm4@plt>
  movsd  -0x28(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L3
L36:
  movsd  -0x28(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
L3:
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void qd_floor(const double *a, double *b) {
  double x0, x1, x2, x3;
  x1 = 0.0;
  x2 = 0.0;
  x3 = 0.0;
  x0 = floor(a[0]);
  if (x0 == a[0]) {
    x1 = floor(a[1]);
    if (x1 == a[1]) {
      x2 = floor(a[2]);
      if (x2 == a[2])
        x3 = floor(a[3]);
    }
    qd_renorm4(&x0, &x1, &x2, &x3);
    b[0] = x0;
    b[1] = x1;
    b[2] = x2;
    b[3] = x3;
  } else
    b[0] = x0;
  b[1] = x1;
  b[2] = x2;
  b[3] = x3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L15
  cmpl   $0x14,-0x4(%rbp)
  jle    L30
L15:
  mov    $0xffffffff,%eax
  jmp    L38
L30:
  cmpl   $0x0,-0x4(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L38
L26:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   -0x4(%rbp),%eax
L38:
  leave
  ret
```

assistant: ```c
uint64_t factorial(int n) {
  if (n < 0 || n > 20)
    return -1;
  if (n == 0)
    return 1;
  return n * factorial(n - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  cmp    $0x14,%edi
  ja     L29
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L1
L5:
  pop    %rbx
  ret
L1:
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
  jmp    L5
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint64_t factorial(int n) {
  if (n < 0 || n > 20)
    return -1;
  if (n == 0)
    return 1;
  return n * factorial(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<factorial>:
  endbr64
  cmp    $0x14,%edi
  ja     L27
  mov    $0x1,%eax
  test   %edi,%edi
  je     L13
  nopw   0x0(%rax,%rax,1)
L12:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L12
  ret
L27:
  mov    $0xffffffff,%eax
  ret
L13:
  ret
```

assistant: ```c
uint64_t factorial(int n) {
  if (n < 0 || n > 20)
    return -1;
  if (n == 0)
    return 1;
  return n * factorial(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factorial>:
  endbr64
  cmp    $0x14,%edi
  ja     L5
  mov    $0x1,%eax
  test   %edi,%edi
  je     L18
  nopw   0x0(%rax,%rax,1)
L27:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L27
  ret
L5:
  mov    $0xffffffff,%eax
  ret
L18:
  ret
```

assistant: ```c
uint64_t factorial(int n) {
  if (n < 0 || n > 20)
    return -1;
  if (n == 0)
    return 1;
  return n * factorial(n - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gu_decompress_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_inflate@plt>
  mov    D7(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int gu_decompress_mem(const void *src, long src_size, void **dst, long *dst_size) {
  *dst_size = *(long *)&((unsigned char *)src)[src_size - 4];
  *dst = malloc(*dst_size);
  if (Z_DATA_ERROR == _inflate(src, src_size, *dst, *dst_size)) {
    free(*dst);
    *dst = (void *)src;
    *dst_size = src_size;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gu_decompress_mem>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%rbx
  mov    -0x4(%rdi,%rsi,1),%rdi
  mov    %rdi,(%rcx)
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,0x0(%r13)
  mov    (%rbx),%rcx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_inflate@plt>
  mov    D9(%rip),%rdx
  cmp    (%rdx),%rax
  je     L12
L1:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    0x0(%r13),%rdi
  call   <free@plt>
  mov    %r12,0x0(%r13)
  mov    %rbp,(%rbx)
  jmp    L1
```

assistant: ```c
int gu_decompress_mem(const void *src, long src_size, void **dst, long *dst_size) {
  *dst_size = *(long *)&((unsigned char *)src)[src_size - 4];
  *dst = malloc(*dst_size);
  if (Z_DATA_ERROR == _inflate(src, src_size, *dst, *dst_size)) {
    free(*dst);
    *dst = (void *)src;
    *dst_size = src_size;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gu_decompress_mem>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    -0x4(%rdi,%rsi,1),%r14
  mov    %rsi,%rbx
  mov    %r14,(%rcx)
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  mov    %rax,%rdx
  call   <_inflate@plt>
  mov    D4(%rip),%rdx
  cmp    (%rdx),%rax
  je     L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbp,(%r12)
  xor    %eax,%eax
  mov    %rbx,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int gu_decompress_mem(const void *src, long src_size, void **dst, long *dst_size) {
  *dst_size = *(long *)&((unsigned char *)src)[src_size - 4];
  *dst = malloc(*dst_size);
  if (Z_DATA_ERROR == _inflate(src, src_size, *dst, *dst_size)) {
    free(*dst);
    *dst = (void *)src;
    *dst_size = src_size;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gu_decompress_mem>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    -0x4(%rdi,%rsi,1),%r14
  mov    %rsi,%rbx
  mov    %r14,(%rcx)
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  mov    %rax,%rdx
  call   <_inflate@plt>
  mov    D2(%rip),%rdx
  cmp    (%rdx),%rax
  je     L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbp,(%r12)
  xor    %eax,%eax
  mov    %rbx,0x0(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int gu_decompress_mem(const void *src, long src_size, void **dst, long *dst_size) {
  *dst_size = *(long *)&((unsigned char *)src)[src_size - 4];
  *dst = malloc(*dst_size);
  if (Z_DATA_ERROR == _inflate(src, src_size, *dst, *dst_size)) {
    free(*dst);
    *dst = (void *)src;
    *dst_size = src_size;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L50:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L44
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L11
  movl   $0x0,-0x14(%rbp)
  jmp    L59
L11:
  mov    $0xffffffff,%eax
  jmp    L2
L44:
  cmpl   $0x0,-0x14(%rbp)
  je     L21
L59:
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L33:
  cmpq   $0x0,-0x10(%rbp)
  jne    L50
  jmp    L36
L21:
  nop
L36:
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L2:
  leave
  ret
```

assistant: ```c
ssize_t Readn(int fd, void *vptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (errno == EINTR)
        nread = 0;
      else
        return -1;
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Readn>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L34
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r14d
  jmp    L66
L2:
  mov    D7(%rip),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L75
  mov    %r14d,%eax
L29:
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L9
L66:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L2
  jne    L29
L9:
  mov    %r13d,%eax
  sub    %ebx,%eax
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  mov    $0xffffffff,%eax
  jmp    L53
L34:
  mov    %rdx,%rbx
  jmp    L9
```

assistant: ```c
ssize_t Readn(int fd, void *vptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (errno == EINTR)
        nread = 0;
      else
        return -1;
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Readn>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L37
  nop
L8:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L45
  je     L39
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L8
L37:
  xor    %ebx,%ebx
L39:
  add    $0x8,%rsp
  mov    %ebp,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L45:
  mov    D16(%rip),%rax
  mov    D8(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L8
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t Readn(int fd, void *vptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (errno == EINTR)
        nread = 0;
      else
        return -1;
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Readn>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L9
  nop
L4:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L20
  je     L47
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L4
L9:
  xor    %ebx,%ebx
L47:
  add    $0x8,%rsp
  mov    %ebp,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L20:
  mov    D18(%rip),%rax
  mov    D9(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L4
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t Readn(int fd, void *vptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (errno == EINTR)
        nread = 0;
      else
        return -1;
    } else if (nread == 0)
      break;
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ubs_copylongs_byteswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L0
L13:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  shr    $0x18,%rax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  shr    $0x10,%rax
  shl    $0x8,%rax
  movzwl %ax,%eax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  shr    $0x8,%rax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rax
  shl    $0x8,%rax
  movzwl %ax,%eax
  add    %rdx,%rax
  shl    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
L0:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ubs_copylongs_byteswap(unsigned long *dest, unsigned long *src, int num) {
  for (; --num >= 0;)
    dest[num] = ((((((((src[num]) >> 16) & 0xff00) >> 8) + ((((src[num]) >> 16) & 0xff) << 8)))) + (((((((src[num]) & 0xffff) & 0xff00) >> 8) + ((((src[num]) & 0xffff) & 0xff) << 8)) << 16)));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ubs_copylongs_byteswap>:
  endbr64
  mov    %rsi,%r8
  sub    $0x1,%edx
  js     L11
  movslq %edx,%rdx
L6:
  mov    (%r8,%rdx,8),%rax
  mov    %rax,%rcx
  shr    $0x8,%rcx
  and    $0xff00,%ecx
  mov    %rax,%rsi
  shr    $0x18,%rsi
  movzbl %sil,%esi
  add    %rsi,%rcx
  movzbl %ah,%esi
  shl    $0x8,%rax
  movzwl %ax,%eax
  add    %rsi,%rax
  shl    $0x10,%rax
  add    %rcx,%rax
  mov    %rax,(%rdi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L6
L11:
  ret
```

assistant: ```c
void ubs_copylongs_byteswap(unsigned long *dest, unsigned long *src, int num) {
  for (; --num >= 0;)
    dest[num] = ((((((((src[num]) >> 16) & 0xff00) >> 8) + ((((src[num]) >> 16) & 0xff) << 8)))) + (((((((src[num]) & 0xffff) & 0xff00) >> 8) + ((((src[num]) & 0xffff) & 0xff) << 8)) << 16)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ubs_copylongs_byteswap>:
  endbr64
  mov    %rsi,%r8
  sub    $0x1,%edx
  js     L18
  movslq %edx,%rdx
  nop
L7:
  mov    (%r8,%rdx,8),%rax
  mov    %rax,%rcx
  mov    %rax,%rsi
  shr    $0x8,%rcx
  shr    $0x18,%rsi
  movzbl %sil,%esi
  and    $0xff00,%ecx
  add    %rsi,%rcx
  movzbl %ah,%esi
  shl    $0x8,%rax
  movzwl %ax,%eax
  add    %rsi,%rax
  shl    $0x10,%rax
  add    %rcx,%rax
  mov    %rax,(%rdi,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L7
L18:
  ret
```

assistant: ```c
void ubs_copylongs_byteswap(unsigned long *dest, unsigned long *src, int num) {
  for (; --num >= 0;)
    dest[num] = ((((((((src[num]) >> 16) & 0xff00) >> 8) + ((((src[num]) >> 16) & 0xff) << 8)))) + (((((((src[num]) & 0xffff) & 0xff00) >> 8) + ((((src[num]) & 0xffff) & 0xff) << 8)) << 16)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ubs_copylongs_byteswap>:
  endbr64
  mov    %rsi,%rcx
  mov    %edx,%esi
  sub    $0x1,%esi
  js     L10
  movslq %edx,%rax
  mov    %edx,%r8d
  shl    $0x3,%rax
  lea    -0x10(%rax),%r9
  lea    -0x8(%rdi,%rax,1),%rax
  lea    (%rcx,%r9,1),%r10
  cmp    %rax,%r10
  je     L35
  cmp    $0x1,%esi
  jbe    L35
  shr    %edx
  movdqa D15(%rip),%xmm4
  add    %rdi,%r9
  xor    %eax,%eax
  neg    %rdx
  movdqa D17(%rip),%xmm3
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L1:
  movdqu (%r10,%rax,1),%xmm1
  shufpd $0x1,%xmm1,%xmm1
  movdqa %xmm1,%xmm0
  movdqa %xmm1,%xmm2
  psrlq  $0x10,%xmm0
  psrlq  $0x18,%xmm2
  psllq  $0x8,%xmm0
  pand   %xmm3,%xmm2
  pand   %xmm4,%xmm0
  paddq  %xmm2,%xmm0
  movdqa %xmm1,%xmm2
  psrlq  $0x8,%xmm2
  psllq  $0x8,%xmm1
  pand   %xmm3,%xmm2
  pand   %xmm4,%xmm1
  paddq  %xmm2,%xmm1
  psllq  $0x10,%xmm1
  paddq  %xmm1,%xmm0
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%r9,%rax,1)
  sub    $0x10,%rax
  cmp    %rdx,%rax
  jne    L1
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  sub    %eax,%esi
  cmp    %eax,%r8d
  je     L10
  movslq %esi,%rsi
  mov    (%rcx,%rsi,8),%rax
  mov    %rax,%rdx
  mov    %rax,%rcx
  shr    $0x8,%rdx
  shr    $0x18,%rcx
  movzbl %cl,%ecx
  and    $0xff00,%edx
  add    %rcx,%rdx
  movzbl %ah,%ecx
  shl    $0x8,%rax
  movzwl %ax,%eax
  add    %rcx,%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  mov    %rax,(%rdi,%rsi,8)
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
  nopl   0x0(%rax)
L35:
  push   %rbx
  movslq %esi,%rsi
  nopl   0x0(%rax)
L38:
  mov    (%rcx,%rsi,8),%rdx
  mov    %rdx,%rax
  mov    %rdx,%r8
  movzbl %dh,%ebx
  shr    $0x18,%rdx
  shl    $0x8,%rax
  shr    $0x8,%r8
  movzbl %dl,%edx
  movzwl %ax,%eax
  and    $0xff00,%r8d
  add    %rbx,%rax
  add    %r8,%rdx
  shl    $0x10,%rax
  add    %rdx,%rax
  mov    %rax,(%rdi,%rsi,8)
  sub    $0x1,%rsi
  test   %esi,%esi
  jns    L38
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: byte[16]
name: unpack_data
arguments: data_label: D17
datatype: byte[16]

tool: {"D15": [0xff,0xff,0x00,0x00,0x00,0x00,0x00,0x00,0xff,0xff,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D17": [0xff,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void ubs_copylongs_byteswap(unsigned long *dest, unsigned long *src, int num) {
  for (; --num >= 0;)
    dest[num] = ((((((((src[num]) >> 16) & 0xff00) >> 8) + ((((src[num]) >> 16) & 0xff) << 8)))) + (((((((src[num]) & 0xffff) & 0xff00) >> 8) + ((((src[num]) & 0xffff) & 0xff) << 8)) << 16)));
}
```
user: What is the c source code of the assembly code below:

```asm
<ltol3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rcx
  jmp    L16
L5:
  mov    (%rcx),%rsi
  mov    %rsi,%rdi
  sar    $0x10,%rdi
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  mov    %dil,(%rsi)
  mov    (%rcx),%rsi
  cmp    $0x8,%rsi
  setg   %dil
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  mov    %dil,(%rsi)
  mov    (%rcx),%rdi
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  mov    %dil,(%rsi)
L16:
  mov    %edx,%esi
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  jg     L5
  nop
  pop    %rbp
  ret
```

assistant: ```c
ltol3(cp, lp, n) register char *cp;
register long *lp;
register int n;
{
  while (n-- > 0) {
    *cp++ = (*lp >> 16);
    *cp++ = (*lp > 8);
    *cp++ = *lp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ltol3>:
  endbr64
  test   %edx,%edx
  jle    L4
  mov    %edx,%edx
  lea    (%rdx,%rdx,2),%rdx
  add    %rdi,%rdx
L2:
  mov    (%rsi),%rax
  sar    $0x10,%rax
  mov    %al,(%rdi)
  cmpq   $0x8,(%rsi)
  setg   0x1(%rdi)
  add    $0x3,%rdi
  mov    (%rsi),%rax
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rdx
  jne    L2
L4:
  ret
```

assistant: ```c
ltol3(cp, lp, n) register char *cp;
register long *lp;
register int n;
{
  while (n-- > 0) {
    *cp++ = (*lp >> 16);
    *cp++ = (*lp > 8);
    *cp++ = *lp;
  }
}
```