ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<C_genTySkelSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <C_mkIndexName@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x46,%rax
  mov    %rax,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string
name: extract_symbolic_data
arguments: data_tag: D16
datatype: string
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string

tool: D3:     DF_mkSortType(tySkelBase, 

tool: D16: );


tool: D14:     tySkelBase += DF_TY_ATOMIC_SIZE;


assistant: ```c
char *C_genTySkelSort(char *name) {
  char *kindName = C_mkIndexName(name);
  char *mytext = NULL;
  mytext = UTIL_mallocStr(strlen("    DF_mkSortType(tySkelBase, ") + strlen(");\n") + strlen(kindName) + strlen("    tySkelBase += DF_TY_ATOMIC_SIZE;\n"));
  strcpy(mytext, "    DF_mkSortType(tySkelBase, ");
  strcat(mytext, kindName);
  free(kindName);
  strcat(mytext, ");\n");
  strcat(mytext, "    tySkelBase += DF_TY_ATOMIC_SIZE;\n");
  return mytext;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<C_genTySkelSort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <C_mkIndexName@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x46(%rax),%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,%rbx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D13:     DF_mkSortType(tySkelBase, 

tool: D11: );


tool: D2:     tySkelBase += DF_TY_ATOMIC_SIZE;


assistant: ```c
char *C_genTySkelSort(char *name) {
  char *kindName = C_mkIndexName(name);
  char *mytext = NULL;
  mytext = UTIL_mallocStr(strlen("    DF_mkSortType(tySkelBase, ") + strlen(");\n") + strlen(kindName) + strlen("    tySkelBase += DF_TY_ATOMIC_SIZE;\n"));
  strcpy(mytext, "    DF_mkSortType(tySkelBase, ");
  strcat(mytext, kindName);
  free(kindName);
  strcat(mytext, ");\n");
  strcat(mytext, "    tySkelBase += DF_TY_ATOMIC_SIZE;\n");
  return mytext;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<C_genTySkelSort>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <C_mkIndexName@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x46(%rax),%rdi
  call   <UTIL_mallocStr@plt>
  lea    D16(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  lea    D11(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D16:     DF_mkSortType(tySkelBase, 

tool: D11: );


tool: D14:     tySkelBase += DF_TY_ATOMIC_SIZE;


assistant: ```c
char *C_genTySkelSort(char *name) {
  char *kindName = C_mkIndexName(name);
  char *mytext = NULL;
  mytext = UTIL_mallocStr(strlen("    DF_mkSortType(tySkelBase, ") + strlen(");\n") + strlen(kindName) + strlen("    tySkelBase += DF_TY_ATOMIC_SIZE;\n"));
  strcpy(mytext, "    DF_mkSortType(tySkelBase, ");
  strcat(mytext, kindName);
  free(kindName);
  strcat(mytext, ");\n");
  strcat(mytext, "    tySkelBase += DF_TY_ATOMIC_SIZE;\n");
  return mytext;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<C_genTySkelSort>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <C_mkIndexName@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x46(%rax),%rdi
  call   <UTIL_mallocStr@plt>
  lea    D27(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  lea    D21(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D5(%rip),%rsi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D27:     DF_mkSortType(tySkelBase, 

tool: D21: );


tool: D5:     tySkelBase += DF_TY_ATOMIC_SIZE;


assistant: ```c
char *C_genTySkelSort(char *name) {
  char *kindName = C_mkIndexName(name);
  char *mytext = NULL;
  mytext = UTIL_mallocStr(strlen("    DF_mkSortType(tySkelBase, ") + strlen(");\n") + strlen(kindName) + strlen("    tySkelBase += DF_TY_ATOMIC_SIZE;\n"));
  strcpy(mytext, "    DF_mkSortType(tySkelBase, ");
  strcat(mytext, kindName);
  free(kindName);
  strcat(mytext, ");\n");
  strcat(mytext, "    tySkelBase += DF_TY_ATOMIC_SIZE;\n");
  return mytext;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_hash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1505,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L19:
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t c_hash_string(const void *key) {
  const unsigned char *str;
  uint32_t hash;
  hash = 5381;
  for (str = key; *str; str++)
    hash = ((hash << 5) + hash) ^ *str;
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<c_hash_string>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  mov    $0x1505,%eax
L12:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  movzbl %dl,%edx
  xor    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  ret
L18:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
uint32_t c_hash_string(const void *key) {
  const unsigned char *str;
  uint32_t hash;
  hash = 5381;
  for (str = key; *str; str++)
    hash = ((hash << 5) + hash) ^ *str;
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<c_hash_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L8
L2:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%eax
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
  ret
  nopl   (%rax)
L8:
  ret
```

assistant: ```c
uint32_t c_hash_string(const void *key) {
  const unsigned char *str;
  uint32_t hash;
  hash = 5381;
  for (str = key; *str; str++)
    hash = ((hash << 5) + hash) ^ *str;
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_hash_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L12
L0:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  add    %ecx,%eax
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  ret
  nopl   (%rax)
L12:
  ret
```

assistant: ```c
uint32_t c_hash_string(const void *key) {
  const unsigned char *str;
  uint32_t hash;
  hash = 5381;
  for (str = key; *str; str++)
    hash = ((hash << 5) + hash) ^ *str;
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vlog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vlog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<info>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <vlog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vlog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vlog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vlog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vlog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void info(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vlog(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  movss  -0x10(%rbp),%xmm4
  movss  -0x14(%rbp),%xmm3
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  movss  -0x20(%rbp),%xmm2
  movss  -0x24(%rbp),%xmm1
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%edi
  movss  -0x30(%rbp),%xmm0
  movaps %xmm4,%xmm5
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <add10@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D5: %d

tool: D9: Sum = %ld


assistant: ```c
int main() {
  float n, m, o, p, q, k;
  int a, b, c, d;
  float result;
  scanf("%d", &n);
  result = add10(n, m, a, b, o, p, c, d, q, k);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm5,%xmm5
  movaps %xmm5,%xmm4
  mov    $0x0,%ecx
  mov    $0x0,%edx
  movaps %xmm5,%xmm3
  movaps %xmm5,%xmm2
  mov    $0x0,%esi
  mov    $0x0,%edi
  movaps %xmm5,%xmm1
  movss  0x4(%rsp),%xmm0
  call   <add10@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D0: %d

tool: D2: Sum = %ld


assistant: ```c
int main() {
  float n, m, o, p, q, k;
  int a, b, c, d;
  float result;
  scanf("%d", &n);
  result = add10(n, m, a, b, o, p, c, d, q, k);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm5,%xmm5
  xor    %edi,%edi
  xor    %ecx,%ecx
  movss  0x4(%rsp),%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  movaps %xmm5,%xmm4
  movaps %xmm5,%xmm3
  movaps %xmm5,%xmm2
  movaps %xmm5,%xmm1
  call   <add10@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D4: %d

tool: D15: Sum = %ld


assistant: ```c
int main() {
  float n, m, o, p, q, k;
  int a, b, c, d;
  float result;
  scanf("%d", &n);
  result = add10(n, m, a, b, o, p, c, d, q, k);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm5,%xmm5
  xor    %edi,%edi
  xor    %ecx,%ecx
  movss  0x4(%rsp),%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  movaps %xmm5,%xmm4
  movaps %xmm5,%xmm3
  movaps %xmm5,%xmm2
  movaps %xmm5,%xmm1
  call   <add10@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D2: %d

tool: D3: Sum = %ld


assistant: ```c
int main() {
  float n, m, o, p, q, k;
  int a, b, c, d;
  float result;
  scanf("%d", &n);
  result = add10(n, m, a, b, o, p, c, d, q, k);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L27
L13:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp,%rdx,4),%ecx
  mov    -0x38(%rbp),%edx
  add    %ecx,%edx
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L27:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L13
  movl   $0x0,-0x34(%rbp)
  jmp    L11
L25:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L11:
  cmpl   $0x6,-0x34(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string

tool: D6: %d

tool: D21: %d


assistant: ```c
int main(void) {
  int n, i, v;
  int sum[7] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v);
    sum[i % 7] += v;
  }
  for (i = 0; i < 7; i++) {
    printf("%d\n", sum[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L22
  mov    $0x0,%ebx
  lea    D24(%rip),%rbp
L39:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq %ebx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x2,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  mov    0xc(%rsp),%edx
  add    %edx,0x10(%rsp,%rax,4)
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L39
L22:
  lea    0x10(%rsp),%rbx
  lea    0x2c(%rsp),%r12
  lea    D3(%rip),%rbp
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string

tool: D24: %d

tool: D3: %d


assistant: ```c
int main(void) {
  int n, i, v;
  int sum[7] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v);
    sum[i % 7] += v;
  }
  for (i = 0; i < 7; i++) {
    printf("%d\n", sum[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movl   $0x0,0x28(%rsp)
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L37
  xor    %r12d,%r12d
  lea    0xc(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r12d,%edx
  mov    %r12d,%eax
  imul   $0x24924925,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %r12d,%eax
  add    $0x1,%r12d
  sub    %edx,%eax
  mov    0xc(%rsp),%edx
  cltq
  add    %edx,0x10(%rsp,%rax,4)
  cmp    %r12d,0x8(%rsp)
  jg     L15
L37:
  lea    0x10(%rsp),%rbx
  lea    0x2c(%rsp),%r12
  lea    D4(%rip),%rbp
  nopl   0x0(%rax)
L25:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L25
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string
name: retrieve_data
arguments: data_tag: D4
type: string

tool: D1: %d

tool: D4: %d


assistant: ```c
int main(void) {
  int n, i, v;
  int sum[7] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v);
    sum[i % 7] += v;
  }
  for (i = 0; i < 7; i++) {
    printf("%d\n", sum[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movl   $0x0,0x28(%rsp)
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L35
  xor    %r12d,%r12d
  lea    0xc(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r12d,%edx
  mov    %r12d,%eax
  imul   $0x24924925,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x2,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %r12d,%eax
  add    $0x1,%r12d
  sub    %edx,%eax
  mov    0xc(%rsp),%edx
  cltq
  add    %edx,0x10(%rsp,%rax,4)
  cmp    %r12d,0x8(%rsp)
  jg     L0
L35:
  lea    0x10(%rsp),%rbx
  lea    0x2c(%rsp),%r12
  lea    D3(%rip),%rbp
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
data_type: string
name: read_data
arguments: label: D3
data_type: string

tool: D17: %d

tool: D3: %d


assistant: ```c
int main(void) {
  int n, i, v;
  int sum[7] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v);
    sum[i % 7] += v;
  }
  for (i = 0; i < 7; i++) {
    printf("%d\n", sum[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```