ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movabs $0x1b4334b500,%rdx
  push   %r14
  mov    %rsi,%r8
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  shl    $0x7,%rax
  and    %rdx,%rax
  mov    0x8(%rdi),%rdx
  mov    %rax,(%rsp)
  test   %rdx,%rdx
  je     L111
  mov    %rsp,%r11
  xor    %esi,%esi
  mov    $0x2,%ebx
  mov    %r11,%rdi
L68:
  mov    %rsi,%rcx
  shr    %rcx
  and    $0x6,%ecx
  mov    %ecx,%eax
  or     $0x1,%eax
  cmpq   $0x0,(%rsp)
  jne    L98
  mov    (%rsp),%r9
  rolq   $0x20,(%rdi)
  cmp    $0x2,%rdx
  jbe    L14
L95:
  mov    %r9,%rcx
  mov    %r9,%r14
  shr    $0x3,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%r14
  mov    %r14,0x10(%rsp)
  rolq   $0x20,(%rdi)
  cmp    $0x4,%rdx
  ja     L6
  nopl   0x0(%rax)
L14:
  add    $0x1,%rsi
  add    $0x8,%rdi
  cmp    %rdx,%rsi
  jne    L68
  mov    (%rsp),%rax
L111:
  shr    $0x8,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  nopl   (%rax)
L98:
  movzbl 0x1(%rsp),%ecx
  movzbl 0x7(%rsp),%r9d
  mov    %cl,0x7(%rsp)
  mov    %r9b,0x1(%rsp)
  cmp    $0x2,%rdx
  jbe    L14
  mov    %rbx,%r14
  mov    %eax,%ecx
  mov    (%rsp),%r9
  shl    %cl,%r14
  cmp    %r14,%r9
  jbe    L95
  movzbl 0x11(%rsp),%ecx
  movzbl 0x17(%rsp),%r10d
  mov    %cl,0x17(%rsp)
  mov    %r10b,0x11(%rsp)
  cmp    $0x4,%rdx
  jbe    L14
L6:
  mov    $0x4,%ebp
  mov    %eax,%ecx
  mov    %r11,%r10
  mov    %rbp,%r14
  shl    %cl,%r14
  cmp    %r14,%r9
  ja     L106
L51:
  mov    %r9,%rcx
  shr    $0x3,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%r9
  mov    %r9,0x20(%r10)
  rolq   $0x20,(%rdi)
L27:
  add    $0x2,%rbp
  add    $0x10,%r10
  cmp    %rdx,%rbp
  jae    L14
  mov    %rbp,%r14
  mov    %eax,%ecx
  mov    (%rsp),%r9
  shl    %cl,%r14
  cmp    %r14,%r9
  jbe    L51
L106:
  movzbl 0x21(%r10),%ecx
  movzbl 0x27(%r10),%r9d
  mov    %cl,0x27(%r10)
  mov    %r9b,0x21(%r10)
  jmp    L27
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  unsigned int copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > local2 << (((local1 >> 1UL) & 7UL) | 1UL)) {
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 7);
          *((char *)(&state[local2]) + 7) = copy11;
        } else {
          state[local2] = state[local1] >> (((state[local1] >> 3UL) & 7UL) | 1UL);
          copy13 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy13;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 1UL) >> 7UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<acceptConnection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L25
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L9
L25:
  mov    -0xc(%rbp),%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: accept client sock error:

assistant: ```c
int acceptConnection(int sockfd, struct sockaddr *clientAddress) {
  int addrlen = sizeof(*clientAddress);
  int clientfd = accept(sockfd, clientAddress, &addrlen);
  if (clientfd == -1) {
    perror("accept client sock error:");
    return -1;
  }
  return clientfd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<acceptConnection>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  call   <accept@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L16
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L0
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string

tool: D6: accept client sock error:

assistant: ```c
int acceptConnection(int sockfd, struct sockaddr *clientAddress) {
  int addrlen = sizeof(*clientAddress);
  int clientfd = accept(sockfd, clientAddress, &addrlen);
  if (clientfd == -1) {
    perror("accept client sock error:");
    return -1;
  }
  return clientfd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<acceptConnection>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L22
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L22:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L18
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: accept client sock error:

assistant: ```c
int acceptConnection(int sockfd, struct sockaddr *clientAddress) {
  int addrlen = sizeof(*clientAddress);
  int clientfd = accept(sockfd, clientAddress, &addrlen);
  if (clientfd == -1) {
    perror("accept client sock error:");
    return -1;
  }
  return clientfd;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<acceptConnection>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0x4,0x4(%rsp)
  call   <accept@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L7
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L7:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L8
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string

tool: D2: accept client sock error:

assistant: ```c
int acceptConnection(int sockfd, struct sockaddr *clientAddress) {
  int addrlen = sizeof(*clientAddress);
  int clientfd = accept(sockfd, clientAddress, &addrlen);
  if (clientfd == -1) {
    perror("accept client sock error:");
    return -1;
  }
  return clientfd;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RBR_vector_set_dist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L18:
  movss  -0x1c(%rbp),%xmm0
  movaps %xmm0,%xmm1
  divss  -0xc(%rbp),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L1:
  cmpl   $0x2,-0x10(%rbp)
  jle    L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *RBR_vector_set_dist(float *V1, float R) {
  int i;
  float *V2;
  float r;
  V2 = (float *)malloc(3 * sizeof(float));
  r = sqrt(V1[0] * V1[0] + V1[1] * V1[1] + V1[2] * V1[2]);
  for (i = 0; i < 3; ++i)
    V2[i] = (R / r) * V1[i];
  return V2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RBR_vector_set_dist>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  movss  %xmm0,0xc(%rsp)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movss  (%rbx),%xmm0
  movss  0x4(%rbx),%xmm2
  movss  0x8(%rbx),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  mulss  (%rbx),%xmm1
  movss  %xmm1,0x0(%rbp)
  movaps %xmm0,%xmm1
  mulss  0x4(%rbx),%xmm1
  movss  %xmm1,0x4(%rbp)
  mulss  0x8(%rbx),%xmm0
  movss  %xmm0,0x8(%rbp)
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float *RBR_vector_set_dist(float *V1, float R) {
  int i;
  float *V2;
  float r;
  V2 = (float *)malloc(3 * sizeof(float));
  r = sqrt(V1[0] * V1[0] + V1[1] * V1[1] + V1[2] * V1[2]);
  for (i = 0; i < 3; ++i)
    V2[i] = (R / r) * V1[i];
  return V2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RBR_vector_set_dist>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  movss  (%rbx),%xmm0
  movss  0x4(%rbx),%xmm3
  movss  0x8(%rbx),%xmm2
  mov    %rax,%r12
  mulss  %xmm3,%xmm3
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  mov    %r12,%rax
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  mulss  (%rbx),%xmm1
  movss  %xmm1,(%r12)
  movss  0x4(%rbx),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%r12)
  mulss  0x8(%rbx),%xmm0
  movss  %xmm0,0x8(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
float *RBR_vector_set_dist(float *V1, float R) {
  int i;
  float *V2;
  float r;
  V2 = (float *)malloc(3 * sizeof(float));
  r = sqrt(V1[0] * V1[0] + V1[1] * V1[1] + V1[2] * V1[2]);
  for (i = 0; i < 3; ++i)
    V2[i] = (R / r) * V1[i];
  return V2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RBR_vector_set_dist>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  movss  (%rbx),%xmm0
  movss  0x4(%rbx),%xmm3
  movss  0x8(%rbx),%xmm2
  mov    %rax,%r12
  mulss  %xmm3,%xmm3
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  lea    0x4(%rbx),%rax
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    %rax,%r12
  je     L8
  movq   (%rbx),%xmm1
  movaps %xmm0,%xmm2
  mov    %r12,%rax
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm1
  movlps %xmm1,(%r12)
  mulss  0x8(%rbx),%xmm0
  movss  %xmm0,0x8(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movss  (%rbx),%xmm1
  mov    %r12,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  mulss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
float *RBR_vector_set_dist(float *V1, float R) {
  int i;
  float *V2;
  float r;
  V2 = (float *)malloc(3 * sizeof(float));
  r = sqrt(V1[0] * V1[0] + V1[1] * V1[1] + V1[2] * V1[2]);
  for (i = 0; i < 3; ++i)
    V2[i] = (R / r) * V1[i];
  return V2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<make_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: %s/%s

assistant: ```c
char *make_path(const char *path, const char *file) {
  char *filename;
  asprintf(&filename, "%s/%s", path, file);
  return filename;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<make_path>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D6(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: %s/%s

assistant: ```c
char *make_path(const char *path, const char *file) {
  char *filename;
  asprintf(&filename, "%s/%s", path, file);
  return filename;
}
```
user: What is the c source code of the assembly code below?

```asm
<make_path>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D3(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %s/%s

assistant: ```c
char *make_path(const char *path, const char *file) {
  char *filename;
  asprintf(&filename, "%s/%s", path, file);
  return filename;
}
```
user: What is the c source code of the assembly code below?

```asm
<make_path>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D2(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: %s/%s

assistant: ```c
char *make_path(const char *path, const char *file) {
  char *filename;
  asprintf(&filename, "%s/%s", path, file);
  return filename;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L9
  cmpl   $0x0,-0x18(%rbp)
  js     L9
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L20
L9:
  mov    $0xffffffff,%eax
  jmp    L47
L20:
  cmpl   $0x0,-0x14(%rbp)
  je     L76
  cmpl   $0x0,-0x18(%rbp)
  jne    L15
L76:
  mov    $0x1,%eax
  jmp    L47
L15:
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L53
L6:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L53:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L6
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L32
L23:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L23
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
L47:
  pop    %rbp
  ret
```

assistant: ```c
int binomial(int n, int k) {
  int num, denom, i;
  if (n < 0 || k < 0 || n < k)
    return -1;
  if (n == 0 || k == 0)
    return 1;
  num = 1;
  for (i = k + 1; i <= n; ++i) {
    num = num * i;
  }
  denom = 1;
  for (i = 2; i <= n - k; ++i) {
    denom *= i;
  }
  return num / denom;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binomial>:
  endbr64
  test   %esi,%esi
  mov    $0x0,%eax
  cmovns %esi,%eax
  cmp    %edi,%eax
  jg     L86
  test   %esi,%esi
  js     L86
  test   %edi,%edi
  je     L36
  test   %esi,%esi
  je     L36
  lea    0x1(%rsi),%edx
  cmp    %edx,%edi
  jl     L32
  lea    0x1(%rdi),%ecx
  mov    $0x1,%eax
L80:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L80
L6:
  sub    %esi,%edi
  cmp    $0x1,%edi
  jle    L18
  lea    0x1(%rdi),%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
L81:
  imul   %edx,%esi
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L81
L83:
  cltd
  idiv   %esi
  ret
L32:
  mov    $0x1,%eax
  jmp    L6
L18:
  mov    $0x1,%esi
  jmp    L83
L86:
  mov    $0xffffffff,%eax
  ret
L36:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int binomial(int n, int k) {
  int num, denom, i;
  if (n < 0 || k < 0 || n < k)
    return -1;
  if (n == 0 || k == 0)
    return 1;
  num = 1;
  for (i = k + 1; i <= n; ++i) {
    num = num * i;
  }
  denom = 1;
  for (i = 2; i <= n - k; ++i) {
    denom *= i;
  }
  return num / denom;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binomial>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  cmovns %esi,%eax
  cmp    %edi,%eax
  jg     L3
  test   %esi,%esi
  js     L3
  test   %edi,%edi
  je     L20
  test   %esi,%esi
  je     L20
  lea    0x1(%rsi),%edx
  cmp    %edx,%edi
  jl     L76
  lea    0x1(%rdi),%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L32:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L32
L13:
  sub    %esi,%edi
  cmp    $0x1,%edi
  jle    L8
  lea    0x1(%rdi),%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  xchg   %ax,%ax
L2:
  imul   %edx,%esi
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L2
  cltd
  idiv   %esi
  ret
  xchg   %ax,%ax
L20:
  mov    $0x1,%eax
L8:
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    $0x1,%eax
  jmp    L13
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binomial(int n, int k) {
  int num, denom, i;
  if (n < 0 || k < 0 || n < k)
    return -1;
  if (n == 0 || k == 0)
    return 1;
  num = 1;
  for (i = k + 1; i <= n; ++i) {
    num = num * i;
  }
  denom = 1;
  for (i = 2; i <= n - k; ++i) {
    denom *= i;
  }
  return num / denom;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binomial>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  cmovns %esi,%eax
  cmp    %edi,%eax
  jg     L12
  test   %esi,%esi
  js     L12
  test   %edi,%edi
  je     L85
  test   %esi,%esi
  je     L85
  lea    0x1(%rsi),%edx
  cmp    %edx,%edi
  jl     L74
  lea    0x1(%rdi),%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L31:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L31
L40:
  sub    %esi,%edi
  cmp    $0x1,%edi
  jle    L10
  lea    0x1(%rdi),%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  xchg   %ax,%ax
L39:
  imul   %edx,%esi
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L39
  cltd
  idiv   %esi
  ret
  xchg   %ax,%ax
L85:
  mov    $0x1,%eax
L10:
  ret
  cs nopw 0x0(%rax,%rax,1)
L74:
  mov    $0x1,%eax
  jmp    L40
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binomial(int n, int k) {
  int num, denom, i;
  if (n < 0 || k < 0 || n < k)
    return -1;
  if (n == 0 || k == 0)
    return 1;
  num = 1;
  for (i = k + 1; i <= n; ++i) {
    num = num * i;
  }
  denom = 1;
  for (i = 2; i <= n - k; ++i) {
    denom *= i;
  }
  return num / denom;
}
```
user: What is the c source code of the assembly code below:

```asm
<array2D_contiguous>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L73
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L73:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L12
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L12:
  movl   $0x1,-0x10(%rbp)
  jmp    L38
L20:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  movl   $0x0,-0x10(%rbp)
  jmp    L35
L24:
  movl   $0x0,-0xc(%rbp)
  jmp    L70
L36:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L36
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D14: Out of memory (array2D_contiguous, pointer array)! Exiting...


tool: D2: Out of memory (array2D_contiguous, chunk array)! Exiting...


assistant: ```c
double **array2D_contiguous(int nRows, int nCols) {
  int i, j;
  double **array2D;
  array2D = (double **)malloc(nRows * sizeof(double *));
  if (array2D == NULL) {
    printf("Out of memory (array2D_contiguous, pointer array)! Exiting...\n");
    exit(-1);
  }
  array2D[0] = (double *)malloc(nRows * nCols * sizeof(double));
  if (array2D[0] == NULL) {
    printf("Out of memory (array2D_contiguous, chunk array)! Exiting...\n");
    exit(-1);
  }
  for (i = 1; i < nRows; i++) {
    array2D[i] = array2D[i - 1] + nCols;
  }
#pragma omp parallel for schedule(static) shared(array2D) private(i, j) firstprivate(nRows, nCols) default(none)
  for (i = 0; i < nRows; i++) {
    for (j = 0; j < nCols; j++) {
      array2D[i][j] = 0;
    }
  }
  return array2D;
}
```