ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L25
  mov    %rax,%rbp
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r13
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r13,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  test   %r14d,%r14d
  je     L75
  movslq %r14d,%rsi
  xor    %eax,%eax
  lea    0x0(,%rsi,4),%rcx
  jmp    L59
  nopl   (%rax)
L41:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L75
L59:
  cmp    %edx,(%rbx,%rax,1)
  jne    L41
  movl   $0x1,0x0(%rbp,%rax,1)
L84:
  add    $0x1,%r15d
  cmp    %r15d,(%rsp)
  jg     L49
  lea    -0x1(%r14),%eax
  xor    %esi,%esi
  lea    0x4(%rbp,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L79:
  add    0x0(%rbp),%esi
  add    $0x4,%rbp
  cmp    %rbp,%rax
  jne    L79
  test   %esi,%esi
  jg     L3
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L75:
  mov    %edx,(%rbx,%rsi,4)
  add    $0x1,%r14d
  movl   $0x0,0x0(%rbp,%rsi,4)
  jmp    L84
L3:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D18
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D4: Entre com N: 

tool: D18: %d

tool: D19: 
%d repetidos

assistant: ```c
int main() {
  int N, repetidos = 0;
  printf("Entre com N: ");
  scanf("%d", &N);
  int *v1 = malloc(N * sizeof(int));
  int *flag = malloc(N * sizeof(int));
  int cont = 0;
  for (int i = 0; i < N; i++) {
    int valor = 0;
    scanf("%d", &valor);
    int achou = 0;
    for (int j = 0; j < cont; j++) {
      if (valor == v1[j]) {
        flag[j] = 1;
        achou = 1;
        break;
      }
    }
    if (!achou) {
      v1[cont] = valor;
      flag[cont++] = 0;
    }
  }
  for (int i = 0; i < cont; i++)
    repetidos += flag[i];
  if (repetidos > 0)
    printf("\n%d repetidos", repetidos);
}
```
user: Translate the below assembly code into C programming language:

```asm
<VecAdd3iv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void VecAdd3iv(int v[3], const int a[3], const int b[3], const int c[3]) {
  v[0] = a[0] + b[0] + c[0];
  v[1] = a[1] + b[1] + c[1];
  v[2] = a[2] + b[2] + c[2];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<VecAdd3iv>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdx),%edi
  add    (%rsi),%edi
  add    (%rcx),%edi
  mov    %edi,(%rax)
  mov    0x4(%rdx),%edi
  add    0x4(%rsi),%edi
  add    0x4(%rcx),%edi
  mov    %edi,0x4(%rax)
  mov    0x8(%rdx),%edx
  add    0x8(%rsi),%edx
  add    0x8(%rcx),%edx
  mov    %edx,0x8(%rax)
  ret
```

assistant: ```c
void VecAdd3iv(int v[3], const int a[3], const int b[3], const int c[3]) {
  v[0] = a[0] + b[0] + c[0];
  v[1] = a[1] + b[1] + c[1];
  v[2] = a[2] + b[2] + c[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VecAdd3iv>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdx),%edi
  add    (%rsi),%edi
  add    (%rcx),%edi
  mov    %edi,(%rax)
  mov    0x4(%rdx),%edi
  add    0x4(%rsi),%edi
  add    0x4(%rcx),%edi
  mov    %edi,0x4(%rax)
  mov    0x8(%rdx),%edx
  add    0x8(%rsi),%edx
  add    0x8(%rcx),%edx
  mov    %edx,0x8(%rax)
  ret
```

assistant: ```c
void VecAdd3iv(int v[3], const int a[3], const int b[3], const int c[3]) {
  v[0] = a[0] + b[0] + c[0];
  v[1] = a[1] + b[1] + c[1];
  v[2] = a[2] + b[2] + c[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<VecAdd3iv>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdx),%edi
  add    (%rsi),%edi
  add    (%rcx),%edi
  mov    %edi,(%rax)
  mov    0x4(%rdx),%edi
  add    0x4(%rsi),%edi
  add    0x4(%rcx),%edi
  mov    %edi,0x4(%rax)
  mov    0x8(%rdx),%edx
  add    0x8(%rsi),%edx
  add    0x8(%rcx),%edx
  mov    %edx,0x8(%rax)
  ret
```

assistant: ```c
void VecAdd3iv(int v[3], const int a[3], const int b[3], const int c[3]) {
  v[0] = a[0] + b[0] + c[0];
  v[1] = a[1] + b[1] + c[1];
  v[2] = a[2] + b[2] + c[2];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i2uc_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L11
L8:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    -0x80(%rcx),%edx
  mov    %dl,(%rax)
L11:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void i2uc_array(const int *src, unsigned char *dest, int count) {
  while (--count >= 0)
    dest[count] = ((src[count] >> 24) + 128);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<i2uc_array>:
  endbr64
  sub    $0x1,%edx
  js     L5
  movslq %edx,%rdx
L1:
  movsbl 0x3(%rdi,%rdx,4),%eax
  add    $0xffffff80,%eax
  mov    %al,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L1
L5:
  ret
```

assistant: ```c
void i2uc_array(const int *src, unsigned char *dest, int count) {
  while (--count >= 0)
    dest[count] = ((src[count] >> 24) + 128);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i2uc_array>:
  endbr64
  sub    $0x1,%edx
  js     L3
  movslq %edx,%rdx
  nopl   0x0(%rax)
L14:
  movsbl 0x3(%rdi,%rdx,4),%eax
  add    $0xffffff80,%eax
  mov    %al,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L14
L3:
  ret
```

assistant: ```c
void i2uc_array(const int *src, unsigned char *dest, int count) {
  while (--count >= 0)
    dest[count] = ((src[count] >> 24) + 128);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i2uc_array>:
  endbr64
  sub    $0x1,%edx
  js     L10
  movslq %edx,%rdx
  nopl   0x0(%rax)
L16:
  movsbl 0x3(%rdi,%rdx,4),%eax
  add    $0xffffff80,%eax
  mov    %al,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L16
L10:
  ret
```

assistant: ```c
void i2uc_array(const int *src, unsigned char *dest, int count) {
  while (--count >= 0)
    dest[count] = ((src[count] >> 24) + 128);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prot_read_udp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  pop    %rbp
  ret
```

assistant: ```c
void *prot_read_udp(void *data, uint16_t *src_port, uint16_t *dst_port) {
  const struct udphdr *udp = data;
  *src_port = udp->source;
  *dst_port = udp->dest;
  return data + sizeof(*udp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prot_read_udp>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
  lea    0x8(%rdi),%rax
  ret
```

assistant: ```c
void *prot_read_udp(void *data, uint16_t *src_port, uint16_t *dst_port) {
  const struct udphdr *udp = data;
  *src_port = udp->source;
  *dst_port = udp->dest;
  return data + sizeof(*udp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prot_read_udp>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
  lea    0x8(%rdi),%rax
  ret
```

assistant: ```c
void *prot_read_udp(void *data, uint16_t *src_port, uint16_t *dst_port) {
  const struct udphdr *udp = data;
  *src_port = udp->source;
  *dst_port = udp->dest;
  return data + sizeof(*udp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prot_read_udp>:
  endbr64
  mov    0x4(%rdi),%eax
  mov    %eax,(%rsi)
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
  lea    0x8(%rdi),%rax
  ret
```

assistant: ```c
void *prot_read_udp(void *data, uint16_t *src_port, uint16_t *dst_port) {
  const struct udphdr *udp = data;
  *src_port = udp->source;
  *dst_port = udp->dest;
  return data + sizeof(*udp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<r2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  movss  (%rax),%xmm1
  lea    0x4(%rax),%rdx
  movss  (%rdx),%xmm0
  movaps %xmm1,%xmm2
  addss  %xmm0,%xmm2
  movss  (%rax),%xmm0
  lea    0x4(%rax),%rdx
  movss  (%rdx),%xmm1
  movaps %xmm0,%xmm3
  subss  %xmm1,%xmm3
  movaps %xmm2,%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  movaps %xmm3,%xmm0
  addss  %xmm3,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void r2(register float *a) {
  register float t1, t2;
  t1 = a[0] + a[1];
  t2 = a[0] - a[1];
  a[0] = t1 * 2;
  a[1] = t2 * 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<r2>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  movaps %xmm0,%xmm1
  addss  %xmm2,%xmm1
  addss  %xmm1,%xmm1
  movss  %xmm1,(%rdi)
  subss  %xmm2,%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,0x4(%rdi)
  ret
```

assistant: ```c
void r2(register float *a) {
  register float t1, t2;
  t1 = a[0] + a[1];
  t2 = a[0] - a[1];
  a[0] = t1 * 2;
  a[1] = t2 * 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<r2>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm0,%xmm0
  addss  %xmm1,%xmm1
  movss  %xmm0,0x4(%rdi)
  movss  %xmm1,(%rdi)
  ret
```

assistant: ```c
void r2(register float *a) {
  register float t1, t2;
  t1 = a[0] + a[1];
  t2 = a[0] - a[1];
  a[0] = t1 * 2;
  a[1] = t2 * 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<r2>:
  endbr64
  movq   (%rdi),%xmm1
  movaps %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  shufps $0xe0,%xmm0,%xmm0
  movaps %xmm0,%xmm2
  subps  %xmm1,%xmm0
  addps  %xmm1,%xmm2
  movss  %xmm2,%xmm0
  addps  %xmm0,%xmm0
  movlps %xmm0,(%rdi)
  ret
```

assistant: ```c
void r2(register float *a) {
  register float t1, t2;
  t1 = a[0] + a[1];
  t2 = a[0] - a[1];
  a[0] = t1 * 2;
  a[1] = t2 * 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GO_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  negl   -0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int GO_abs(int n) {
  if (n < 0)
    n = -n;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GO_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int GO_abs(int n) {
  if (n < 0)
    n = -n;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GO_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int GO_abs(int n) {
  if (n < 0)
    n = -n;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GO_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int GO_abs(int n) {
  if (n < 0)
    n = -n;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L19
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L0
L19:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <read_mem@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: Usage: ./readmem mb_count value


assistant: ```c
int main(int argc, char *const argv[]) {
  if (argc != 3) {
    printf("Usage: ./readmem mb_count value\n");
    return -1;
  }
  int mb_count = atoi(argv[1]);
  int value = atoi(argv[2]);
  return read_mem(mb_count, value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jne    L8
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <read_mem@plt>
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: Usage: ./readmem mb_count value


assistant: ```c
int main(int argc, char *const argv[]) {
  if (argc != 3) {
    printf("Usage: ./readmem mb_count value\n");
    return -1;
  }
  int mb_count = atoi(argv[1]);
  int value = atoi(argv[2]);
  return read_mem(mb_count, value);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jne    L5
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  mov    %eax,%esi
  pop    %rbp
  jmp    1080 <read_mem@plt>
L5:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rdx
  or     $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: Usage: ./readmem mb_count value


assistant: ```c
int main(int argc, char *const argv[]) {
  if (argc != 3) {
    printf("Usage: ./readmem mb_count value\n");
    return -1;
  }
  int mb_count = atoi(argv[1]);
  int value = atoi(argv[2]);
  return read_mem(mb_count, value);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jne    L2
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  mov    %eax,%esi
  pop    %rbp
  jmp    1080 <read_mem@plt>
L2:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rdx
  or     $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: Usage: ./readmem mb_count value


assistant: ```c
int main(int argc, char *const argv[]) {
  if (argc != 3) {
    printf("Usage: ./readmem mb_count value\n");
    return -1;
  }
  int mb_count = atoi(argv[1]);
  int value = atoi(argv[2]);
  return read_mem(mb_count, value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x123,-0x30(%rbp)
  movq   $0x234,-0x28(%rbp)
  movq   $0x345,-0x20(%rbp)
  movq   $0x456,-0x18(%rbp)
  movq   $0x4,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <init_by_array@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L12
L2:
  mov    $0x0,%eax
  call   <genrand_int32@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x4,%eax
  jne    L38
  mov    $0xa,%edi
  call   <putchar@plt>
L38:
  addl   $0x1,-0x3c(%rbp)
L12:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: %10lu 

assistant: ```c
int main(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  init_by_array(init, length);
  for (i = 0; i < 10; i++) {
    printf("%10lu ", genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x123,(%rsp)
  movq   $0x234,0x8(%rsp)
  movq   $0x345,0x10(%rsp)
  movq   $0x456,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <init_by_array@plt>
  mov    $0x0,%eax
  call   <genrand_int32@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D13(%rip),%rbp
  jmp    L25
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
L25:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L28
  mov    $0x0,%eax
  call   <genrand_int32@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  jne    L25
  jmp    L39
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string

tool: D13: %10lu 

assistant: ```c
int main(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  init_by_array(init, length);
  for (i = 0; i < 10; i++) {
    printf("%10lu ", genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x123,(%rsp)
  movq   $0x234,0x8(%rsp)
  movq   $0x345,0x10(%rsp)
  movq   $0x456,0x18(%rsp)
  call   <init_by_array@plt>
  xor    %eax,%eax
  call   <genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L38:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L26
L18:
  xor    %eax,%eax
  call   <genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L38
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0xa,%ebx
  jne    L18
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D7: %10lu 

assistant: ```c
int main(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  init_by_array(init, length);
  for (i = 0; i < 10; i++) {
    printf("%10lu ", genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D18(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <init_by_array@plt>
  xor    %eax,%eax
  call   <genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
  nopl   0x0(%rax)
L24:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L4
L18:
  xor    %eax,%eax
  call   <genrand_int32@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  sub    $0x33333334,%eax
  cmp    $0x33333332,%eax
  ja     L24
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0xa,%ebx
  jne    L18
L4:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D22
datatype: byte[16]
name: parse_data
arguments: tag: D8
datatype: byte[16]

tool: D18: %10lu 

tool: {"D22": [0x23,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x02,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D8": [0x45,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x56,0x04,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int i;
  unsigned long init[4] = {0x123, 0x234, 0x345, 0x456}, length = 4;
  init_by_array(init, length);
  for (i = 0; i < 10; i++) {
    printf("%10lu ", genrand_int32());
    if (i % 5 == 4)
      printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__infer_nondet_unsigned_long_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int __infer_nondet_unsigned_long_int() {
  unsigned long int ret;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__infer_nondet_unsigned_long_int>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long int __infer_nondet_unsigned_long_int() {
  unsigned long int ret;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<__infer_nondet_unsigned_long_int>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long int __infer_nondet_unsigned_long_int() {
  unsigned long int ret;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__infer_nondet_unsigned_long_int>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long int __infer_nondet_unsigned_long_int() {
  unsigned long int ret;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<syscon_degree_of_dobldobl_polynomial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x153,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_degree_of_dobldobl_polynomial(int k, int *d) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(339, &k, d, c);
  return fail;
}
```