ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wep_keygen104>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x50(%rsp),%rsi
  mov    %rbp,%rax
  xchg   %ax,%ax
L10:
  movslq %ecx,%rdx
  add    $0x1,%ecx
  movzbl (%rdi,%rdx,1),%edx
  test   %dl,%dl
  jne    L25
  movzbl (%rdi),%edx
  mov    $0x1,%ecx
L25:
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L10
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <MD5_Init@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <MD5_Update@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MD5_Final@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,(%rbx)
  mov    0x18(%rsp),%eax
  mov    %eax,0x8(%rbx)
  movzbl 0x1c(%rsp),%eax
  mov    %al,0xc(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wep_keygen104(const char *str, u_char *keys) {
  MD5_CTX ctx;
  u_char buf[64];
  int i, j;
  j = 0;
  for (i = 0; i < 64; i++) {
    if (str[j] == 0)
      j = 0;
    buf[i] = str[j++];
  }
  MD5_Init(&ctx);
  MD5_Update(&ctx, buf, sizeof buf);
  MD5_Final(buf, &ctx);
  for (i = 0; i < 13; i++) {
    keys[i] = buf[i];
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wep_keygen104>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x50(%rsp),%rsi
  mov    %rbp,%rax
  xchg   %ax,%ax
L48:
  movslq %edx,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  test   %cl,%cl
  je     L5
  mov    %cl,(%rax)
  add    $0x1,%rax
  add    $0x1,%edx
  cmp    %rax,%rsi
  jne    L48
L16:
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <MD5_Init@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <MD5_Update@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MD5_Final@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,(%rbx)
  mov    0x18(%rsp),%eax
  mov    %eax,0x8(%rbx)
  movzbl 0x1c(%rsp),%eax
  mov    %al,0xc(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  movzbl (%rdi),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rsi
  je     L16
  mov    $0x1,%edx
  jmp    L48
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wep_keygen104(const char *str, u_char *keys) {
  MD5_CTX ctx;
  u_char buf[64];
  int i, j;
  j = 0;
  for (i = 0; i < 64; i++) {
    if (str[j] == 0)
      j = 0;
    buf[i] = str[j++];
  }
  MD5_Init(&ctx);
  MD5_Update(&ctx, buf, sizeof buf);
  MD5_Final(buf, &ctx);
  for (i = 0; i < 13; i++) {
    keys[i] = buf[i];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L26
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <solve_file@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  jmp    L23
L26:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D5: cdoku - DLX Sudoku Solver in C

tool: D6: usage: %s [file]...


assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc > 1) {
    for (i = 1; i < argc; i++)
      solve_file(argv[i]);
  } else {
    printf("cdoku - DLX Sudoku Solver in C\n");
    printf("usage: %s [file]...\n", argv[0]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  cmp    $0x1,%edi
  jle    L2
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L6:
  mov    (%rbx),%rdi
  call   <solve_file@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
L1:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    0x0(%rbp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D6: cdoku - DLX Sudoku Solver in C

tool: D17: usage: %s [file]...


assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc > 1) {
    for (i = 1; i < argc; i++)
      solve_file(argv[i]);
  } else {
    printf("cdoku - DLX Sudoku Solver in C\n");
    printf("usage: %s [file]...\n", argv[0]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L10
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  xchg   %ax,%ax
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <solve_file@plt>
  cmp    %rbp,%rbx
  jne    L18
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x0(%rbp),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string

tool: D4: cdoku - DLX Sudoku Solver in C

tool: D18: usage: %s [file]...


assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc > 1) {
    for (i = 1; i < argc; i++)
      solve_file(argv[i]);
  } else {
    printf("cdoku - DLX Sudoku Solver in C\n");
    printf("usage: %s [file]...\n", argv[0]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L25
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  xchg   %ax,%ax
L23:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <solve_file@plt>
  cmp    %rbp,%rbx
  jne    L23
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    0x0(%rbp),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D1: cdoku - DLX Sudoku Solver in C

tool: D6: usage: %s [file]...


assistant: ```c
int main(int argc, char **argv) {
  int i;
  if (argc > 1) {
    for (i = 1; i < argc; i++)
      solve_file(argv[i]);
  } else {
    printf("cdoku - DLX Sudoku Solver in C\n");
    printf("usage: %s [file]...\n", argv[0]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fossil_panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fossil_panic(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fossil_panic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fossil_panic(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fossil_panic>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fossil_panic(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fossil_panic>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fossil_panic(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<glmExpandMatrix24d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x50,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x58,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x68,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x70,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x78,%rax
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void glmExpandMatrix24d(double result[16], const double m[4]) {
  result[0] = m[0];
  result[1] = m[1];
  result[2] = 0;
  result[3] = 0;
  result[4] = m[2];
  result[5] = m[3];
  result[6] = 0;
  result[7] = 0;
  result[8] = 0;
  result[9] = 0;
  result[10] = 0;
  result[11] = 0;
  result[12] = 0;
  result[13] = 0;
  result[14] = 0;
  result[15] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<glmExpandMatrix24d>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x40(%rdi)
  movq   $0x0,0x48(%rdi)
  movq   $0x0,0x50(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    D0(%rip),%rax
  mov    %rax,0x78(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void glmExpandMatrix24d(double result[16], const double m[4]) {
  result[0] = m[0];
  result[1] = m[1];
  result[2] = 0;
  result[3] = 0;
  result[4] = m[2];
  result[5] = m[3];
  result[6] = 0;
  result[7] = 0;
  result[8] = 0;
  result[9] = 0;
  result[10] = 0;
  result[11] = 0;
  result[12] = 0;
  result[13] = 0;
  result[14] = 0;
  result[15] = 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glmExpandMatrix24d>:
  endbr64
  movsd  (%rsi),%xmm0
  mov    D6(%rip),%rax
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x18(%rsi),%xmm0
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x40(%rdi)
  movq   $0x0,0x48(%rdi)
  movq   $0x0,0x50(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    %rax,0x78(%rdi)
  movsd  %xmm0,0x28(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void glmExpandMatrix24d(double result[16], const double m[4]) {
  result[0] = m[0];
  result[1] = m[1];
  result[2] = 0;
  result[3] = 0;
  result[4] = m[2];
  result[5] = m[3];
  result[6] = 0;
  result[7] = 0;
  result[8] = 0;
  result[9] = 0;
  result[10] = 0;
  result[11] = 0;
  result[12] = 0;
  result[13] = 0;
  result[14] = 0;
  result[15] = 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<glmExpandMatrix24d>:
  endbr64
  movsd  (%rsi),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdi)
  pxor   %xmm0,%xmm0
  movups %xmm0,0x10(%rdi)
  movsd  0x10(%rsi),%xmm1
  movsd  %xmm1,0x20(%rdi)
  movsd  0x18(%rsi),%xmm1
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm0,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  movapd D7(%rip),%xmm0
  movsd  %xmm1,0x28(%rdi)
  movups %xmm0,0x70(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void glmExpandMatrix24d(double result[16], const double m[4]) {
  result[0] = m[0];
  result[1] = m[1];
  result[2] = 0;
  result[3] = 0;
  result[4] = m[2];
  result[5] = m[3];
  result[6] = 0;
  result[7] = 0;
  result[8] = 0;
  result[9] = 0;
  result[10] = 0;
  result[11] = 0;
  result[12] = 0;
  result[13] = 0;
  result[14] = 0;
  result[15] = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_beep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L15
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <beep@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L12
L15:
  nop
L12:
  leave
  ret
```

assistant: ```c
void cmd_beep(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(beep());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_beep>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <beep@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_beep(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(beep());
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmd_beep>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L7
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <beep@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_beep(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(beep());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmd_beep>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L0
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <beep@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_beep(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(beep());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply33d33d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x3,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x6,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x20,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x28,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  add    $0x3,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x38,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x40,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  add    $0x6,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L14:
  cmpl   $0x2,-0x1c(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiply33d33d(double *m1, double *m2, double *m3) {
  int a;
  double m2r0, m2r1, m2r2;
  for (a = 0; a < 3; a++) {
    m2r0 = m2[a];
    m2r1 = m2[3 + a];
    m2r2 = m2[6 + a];
    m3[a] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2;
    m3[3 + a] = m1[3] * m2r0 + m1[4] * m2r1 + m1[5] * m2r2;
    m3[6 + a] = m1[6] * m2r0 + m1[7] * m2r1 + m1[8] * m2r2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply33d33d>:
  endbr64
  mov    $0x0,%eax
L1:
  movsd  (%rsi,%rax,1),%xmm0
  movsd  0x18(%rsi,%rax,1),%xmm2
  movsd  0x30(%rsi,%rax,1),%xmm1
  movapd %xmm0,%xmm3
  mulsd  (%rdi),%xmm3
  movapd %xmm2,%xmm4
  mulsd  0x8(%rdi),%xmm4
  addsd  %xmm4,%xmm3
  movapd %xmm1,%xmm4
  mulsd  0x10(%rdi),%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,(%rdx,%rax,1)
  movapd %xmm0,%xmm3
  mulsd  0x18(%rdi),%xmm3
  movapd %xmm2,%xmm4
  mulsd  0x20(%rdi),%xmm4
  addsd  %xmm4,%xmm3
  movapd %xmm1,%xmm4
  mulsd  0x28(%rdi),%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x18(%rdx,%rax,1)
  mulsd  0x30(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm2
  addsd  %xmm2,%xmm0
  mulsd  0x40(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L1
  ret
```

assistant: ```c
void multiply33d33d(double *m1, double *m2, double *m3) {
  int a;
  double m2r0, m2r1, m2r2;
  for (a = 0; a < 3; a++) {
    m2r0 = m2[a];
    m2r1 = m2[3 + a];
    m2r2 = m2[6 + a];
    m3[a] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2;
    m3[3 + a] = m1[3] * m2r0 + m1[4] * m2r1 + m1[5] * m2r2;
    m3[6 + a] = m1[6] * m2r0 + m1[7] * m2r1 + m1[8] * m2r2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply33d33d>:
  endbr64
  xor    %eax,%eax
L9:
  movsd  (%rsi,%rax,1),%xmm0
  movsd  0x18(%rsi,%rax,1),%xmm2
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm4
  movsd  0x30(%rsi,%rax,1),%xmm1
  mulsd  %xmm2,%xmm4
  mulsd  %xmm0,%xmm3
  addsd  %xmm4,%xmm3
  movsd  0x10(%rdi),%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,(%rdx,%rax,1)
  movsd  0x18(%rdi),%xmm3
  movsd  0x20(%rdi),%xmm4
  mulsd  %xmm0,%xmm3
  mulsd  %xmm2,%xmm4
  addsd  %xmm4,%xmm3
  movsd  0x28(%rdi),%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm3
  movsd  %xmm3,0x18(%rdx,%rax,1)
  mulsd  0x30(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm2
  mulsd  0x40(%rdi),%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L9
  ret
```

assistant: ```c
void multiply33d33d(double *m1, double *m2, double *m3) {
  int a;
  double m2r0, m2r1, m2r2;
  for (a = 0; a < 3; a++) {
    m2r0 = m2[a];
    m2r1 = m2[3 + a];
    m2r2 = m2[6 + a];
    m3[a] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2;
    m3[3 + a] = m1[3] * m2r0 + m1[4] * m2r1 + m1[5] * m2r2;
    m3[6 + a] = m1[6] * m2r0 + m1[7] * m2r1 + m1[8] * m2r2;
  }
}
```