ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D28
type_infered: string

tool: D21: 1! = %i


tool: D10: 3! = %i


tool: D28: 5! = %i


assistant: ```c
int main() {
  printf("1! = %i\n", factorial(1));
  printf("3! = %i\n", factorial(3));
  printf("5! = %i\n", factorial(5));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D19
type: string

tool: D5: 1! = %i


tool: D2: 3! = %i


tool: D19: 5! = %i


assistant: ```c
int main() {
  printf("1! = %i\n", factorial(1));
  printf("3! = %i\n", factorial(3));
  printf("5! = %i\n", factorial(5));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <factorial@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <factorial@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <factorial@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D12: 1! = %i


tool: D23: 3! = %i


tool: D7: 5! = %i


assistant: ```c
int main() {
  printf("1! = %i\n", factorial(1));
  printf("3! = %i\n", factorial(3));
  printf("5! = %i\n", factorial(5));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <factorial@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <factorial@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <factorial@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string

tool: D11: 1! = %i


tool: D0: 3! = %i


tool: D20: 5! = %i


assistant: ```c
int main() {
  printf("1! = %i\n", factorial(1));
  printf("3! = %i\n", factorial(3));
  printf("5! = %i\n", factorial(5));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strmapi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L35
L26:
  movl   $0x0,-0x1c(%rbp)
  jmp    L23
L12:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x1c(%rbp),%eax
  mov    -0x1c(%rbp),%ecx
  movslq %ecx,%rsi
  mov    -0x18(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    -0x30(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x18(%rbp),%rax
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  int i;
  char *dest;
  if (!(dest = ft_strnew(ft_strlen(s))))
    return (NULL);
  i = 0;
  while (s[i]) {
    dest[i] = (*f)(i, s[i]);
    i++;
  }
  return (dest);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strmapi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  movzbl (%r12),%esi
  test   %sil,%sil
  je     L24
  mov    $0x0,%ebx
L5:
  movsbl %sil,%esi
  mov    %ebx,%edi
  call   *%r13
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%esi
  test   %sil,%sil
  jne    L5
L24:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  int i;
  char *dest;
  if (!(dest = ft_strnew(ft_strlen(s))))
    return (NULL);
  i = 0;
  while (s[i]) {
    dest[i] = (*f)(i, s[i]);
    i++;
  }
  return (dest);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strmapi>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  movsbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L0
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%edi
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  jne    L20
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  int i;
  char *dest;
  if (!(dest = ft_strnew(ft_strlen(s))))
    return (NULL);
  i = 0;
  while (s[i]) {
    dest[i] = (*f)(i, s[i]);
    i++;
  }
  return (dest);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strmapi>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L28
  movsbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L28
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  jne    L18
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  int i;
  char *dest;
  if (!(dest = ft_strnew(ft_strlen(s))))
    return (NULL);
  i = 0;
  while (s[i]) {
    dest[i] = (*f)(i, s[i]);
    i++;
  }
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<v_wait_uart_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L5:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  and    $0x400000,%eax
  test   %eax,%eax
  jne    L26
  mov    $0x4,%edi
  call   <delay_tick@plt>
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x4e1f,-0x4(%rbp)
  jbe    L5
  jmp    L27
L26:
  nop
L27:
  nop
  leave
  ret
```

assistant: ```c
void v_wait_uart_empty() {
  unsigned int count = 0;
  do {
    if ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 22)) == 0) {
      delay_tick(4);
    } else {
      break;
    }
    count++;
  } while (count < 20000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<v_wait_uart_empty>:
  endbr64
  push   %rbx
  mov    $0x4e20,%ebx
L11:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x400000,%eax
  jne    L0
  mov    $0x4,%edi
  call   <delay_tick@plt>
  sub    $0x1,%ebx
  jne    L11
L0:
  pop    %rbx
  ret
```

assistant: ```c
void v_wait_uart_empty() {
  unsigned int count = 0;
  do {
    if ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 22)) == 0) {
      delay_tick(4);
    } else {
      break;
    }
    count++;
  } while (count < 20000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<v_wait_uart_empty>:
  endbr64
  push   %rbx
  mov    $0x4e20,%ebx
  jmp    L4
  nopl   0x0(%rax)
L20:
  mov    $0x4,%edi
  call   <delay_tick@plt>
  sub    $0x1,%ebx
  je     L2
L4:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x400000,%eax
  je     L20
L2:
  pop    %rbx
  ret
```

assistant: ```c
void v_wait_uart_empty() {
  unsigned int count = 0;
  do {
    if ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 22)) == 0) {
      delay_tick(4);
    } else {
      break;
    }
    count++;
  } while (count < 20000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<v_wait_uart_empty>:
  endbr64
  push   %rbx
  mov    $0x4e20,%ebx
  jmp    L26
  nopl   0x0(%rax)
L28:
  mov    $0x4,%edi
  call   <delay_tick@plt>
  sub    $0x1,%ebx
  je     L8
L26:
  mov    $0xf31004cc,%edi
  call   <readl@plt>
  test   $0x400000,%eax
  je     L28
L8:
  pop    %rbx
  ret
```

assistant: ```c
void v_wait_uart_empty() {
  unsigned int count = 0;
  do {
    if ((readl((0xf3100000 + (((0x01 << 10) | (0x33 << 2))))) & (1 << 22)) == 0) {
      delay_tick(4);
    } else {
      break;
    }
    count++;
  } while (count < 20000);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fcpeek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char fcpeek(FILE *f) {
  char c = getc(f);
  ungetc(c, f);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fcpeek>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <getc@plt>
  mov    %eax,%ebx
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char fcpeek(FILE *f) {
  char c = getc(f);
  ungetc(c, f);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<fcpeek>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rsi
  movsbl %al,%edi
  mov    %edi,%r12d
  call   <ungetc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char fcpeek(FILE *f) {
  char c = getc(f);
  ungetc(c, f);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fcpeek>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rsi
  movsbl %al,%edi
  mov    %edi,%r12d
  call   <ungetc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char fcpeek(FILE *f) {
  char c = getc(f);
  ungetc(c, f);
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L24
  pxor   %xmm0,%xmm0
  jmp    L2
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int ilast, float *w, float *w2) {
  int i;
  for (i = 0; i < ilast; ++i) {
    w[i] = (0.0f > w2[i] ? 0.0f : w2[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  test   %edi,%edi
  jle    L18
  mov    %edi,%edi
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm3
L16:
  movss  (%rdx,%rax,4),%xmm0
  movaps %xmm0,%xmm1
  cmpnltss %xmm2,%xmm1
  andps  %xmm1,%xmm0
  andnps %xmm3,%xmm1
  orps   %xmm1,%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L16
L18:
  ret
```

assistant: ```c
void foo(int ilast, float *w, float *w2) {
  int i;
  for (i = 0; i < ilast; ++i) {
    w[i] = (0.0f > w2[i] ? 0.0f : w2[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L14:
  movaps %xmm1,%xmm0
  maxss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L14
L5:
  ret
```

assistant: ```c
void foo(int ilast, float *w, float *w2) {
  int i;
  for (i = 0; i < ilast; ++i) {
    w[i] = (0.0f > w2[i] ? 0.0f : w2[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L26
  lea    0x4(%rdx),%rsi
  mov    %rcx,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L34
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L34
  mov    %edi,%esi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L5:
  movups (%rdx,%rax,1),%xmm0
  movups (%rdx,%rax,1),%xmm2
  cmpltps %xmm1,%xmm0
  andnps %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L5
  mov    %r9d,%esi
  and    $0xfffffffc,%esi
  test   $0x3,%r9b
  je     L26
  mov    %esi,%r8d
  pxor   %xmm0,%xmm0
  lea    0x1(%rsi),%eax
  movaps %xmm0,%xmm1
  maxss  (%rdx,%r8,4),%xmm1
  lea    0x0(,%r8,4),%rdi
  movss  %xmm1,(%rcx,%r8,4)
  cmp    %eax,%r9d
  jle    L26
  movaps %xmm0,%xmm1
  maxss  0x4(%rdx,%rdi,1),%xmm1
  add    $0x2,%esi
  movss  %xmm1,0x4(%rcx,%rdi,1)
  cmp    %esi,%r9d
  jle    L26
  maxss  0x8(%rdx,%rdi,1),%xmm0
  movss  %xmm0,0x8(%rcx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r9d,%eax
  xor    %esi,%esi
  pxor   %xmm0,%xmm0
L39:
  movaps %xmm0,%xmm1
  maxss  (%rdx,%rsi,4),%xmm1
  movss  %xmm1,(%rcx,%rsi,4)
  add    $0x1,%rsi
  cmp    %rsi,%rax
  jne    L39
L26:
  ret
```

assistant: ```c
void foo(int ilast, float *w, float *w2) {
  int i;
  for (i = 0; i < ilast; ++i) {
    w[i] = (0.0f > w2[i] ? 0.0f : w2[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xffffffec,%edi
  call   <itoa@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: %s


assistant: ```c
int main(void) {
  char str[10] = "";
  itoa(-20, str);
  printf("%s\n", str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0xffffffec,%edi
  call   <itoa@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: %s


assistant: ```c
int main(void) {
  char str[10] = "";
  itoa(-20, str);
  printf("%s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xffffffec,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %rbp,%rsi
  mov    %ax,0x16(%rsp)
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %s


assistant: ```c
int main(void) {
  char str[10] = "";
  itoa(-20, str);
  printf("%s\n", str);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xffffffec,%edi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  mov    %rbp,%rsi
  mov    %ax,0x16(%rsp)
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: %s


assistant: ```c
int main(void) {
  char str[10] = "";
  itoa(-20, str);
  printf("%s\n", str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D34(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: D34: 123

tool: D24: p = %s


tool: D20: 56

assistant: ```c
int main(void) {
  char *p = "123";
  printf("p = %s\n", p);
  p = "456" + 1;
  printf("p = %s\n", p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D19(%rip),%rsi
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string

tool: D19: 123

tool: D22: p = %s


tool: D29: 56

assistant: ```c
int main(void) {
  char *p = "123";
  printf("p = %s\n", p);
  p = "456" + 1;
  printf("p = %s\n", p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string
name: extract_symbolic_data
arguments: data_tag: D26
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D7: p = %s


tool: D26: 123

tool: D4: 56

assistant: ```c
int main(void) {
  char *p = "123";
  printf("p = %s\n", p);
  p = "456" + 1;
  printf("p = %s\n", p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rbp
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D22(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: string

tool: D26: p = %s


tool: D13: 123

tool: D22: 56

assistant: ```c
int main(void) {
  char *p = "123";
  printf("p = %s\n", p);
  p = "456" + 1;
  printf("p = %s\n", p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_put_big_nbr_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <my_select_dict@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jae    L9
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <str_to_char@plt>
  mov    %eax,%edi
  call   <char_to_str@plt>
  jmp    L0
L9:
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <str_to_char@plt>
  mov    %eax,%edi
  call   <char_to_str@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <my_putnbr_base@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <my_strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *my_put_big_nbr_base(unsigned int nbr, int base, int dict) {
  char *nbr_convert;
  char *tab_base = my_select_dict(dict);
  if (nbr < base) {
    return (char *)char_to_str(str_to_char(tab_base + nbr));
  } else {
    nbr_convert = my_strcat(my_putnbr_base(nbr / base, base, dict), char_to_str(str_to_char(tab_base + (nbr % base))));
    return (char *)nbr_convert;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_put_big_nbr_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %edx,%edi
  call   <my_select_dict@plt>
  mov    %rax,%rdi
  cmp    %ebx,%ebp
  jbe    L1
  mov    %ebx,%ebx
  add    %rbx,%rdi
  call   <str_to_char@plt>
  mov    %eax,%edi
  call   <char_to_str@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ebp
  mov    %eax,%ebx
  add    %rdx,%rdi
  call   <str_to_char@plt>
  mov    %eax,%edi
  call   <char_to_str@plt>
  mov    %rax,%r13
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <my_putnbr_base@plt>
  mov    %eax,%edi
  mov    %r13,%rsi
  call   <my_strcat@plt>
  jmp    L5
```

assistant: ```c
char *my_put_big_nbr_base(unsigned int nbr, int base, int dict) {
  char *nbr_convert;
  char *tab_base = my_select_dict(dict);
  if (nbr < base) {
    return (char *)char_to_str(str_to_char(tab_base + nbr));
  } else {
    nbr_convert = my_strcat(my_putnbr_base(nbr / base, base, dict), char_to_str(str_to_char(tab_base + (nbr % base))));
    return (char *)nbr_convert;
  }
}
```