ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<pega_input>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getch@plt>
  sub    $0x71,%eax
  cmp    $0x12,%eax
  ja     L22
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  mov    $0x4,%eax
L22:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%eax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%eax
  jmp    L22
```

assistant: ```c
int pega_input() {
  switch (getch()) {
  case KEY_LEFT:
    return 0;
    break;
  case KEY_RIGHT:
    return 1;
    break;
  case KEY_DOWN:
    return 2;
    break;
  case KEY_UP:
    return 3;
    break;
  case 'q':
    return 4;
    break;
  default:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pega_input>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getch@plt>
  sub    $0x71,%eax
  cmp    $0x12,%eax
  ja     L0
  lea    D3(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  mov    $0x4,%eax
L0:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%eax
  jmp    L0
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%eax
  jmp    L0
```

assistant: ```c
int pega_input() {
  switch (getch()) {
  case KEY_LEFT:
    return 0;
    break;
  case KEY_RIGHT:
    return 1;
    break;
  case KEY_DOWN:
    return 2;
    break;
  case KEY_UP:
    return 3;
    break;
  case 'q':
    return 4;
    break;
  default:
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nvme_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x10,%eax
  or     -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <nvme_get_log@plt>
  leave
  ret
```

assistant: ```c
int nvme_log(int fd, __u32 nsid, __u8 log_id, __u32 data_len, void *data) {
  __u32 cdw10 = log_id | ((data_len >> 2) - 1) << 16;
  return nvme_get_log(fd, nsid, cdw10, data_len, data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nvme_log>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%eax
  mov    %ecx,%edx
  sar    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x10,%edx
  or     %eax,%edx
  call   <nvme_get_log@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int nvme_log(int fd, __u32 nsid, __u8 log_id, __u32 data_len, void *data) {
  __u32 cdw10 = log_id | ((data_len >> 2) - 1) << 16;
  return nvme_get_log(fd, nsid, cdw10, data_len, data);
}
```
user: What is the c source code of the assembly code below:

```asm
<nvme_log>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%edx
  sar    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x10,%edx
  or     %r9d,%edx
  jmp    1050 <nvme_get_log@plt>
```

assistant: ```c
int nvme_log(int fd, __u32 nsid, __u8 log_id, __u32 data_len, void *data) {
  __u32 cdw10 = log_id | ((data_len >> 2) - 1) << 16;
  return nvme_get_log(fd, nsid, cdw10, data_len, data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nvme_log>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%edx
  sar    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x10,%edx
  or     %r9d,%edx
  jmp    1050 <nvme_get_log@plt>
```

assistant: ```c
int nvme_log(int fd, __u32 nsid, __u8 log_id, __u32 data_len, void *data) {
  __u32 cdw10 = log_id | ((data_len >> 2) - 1) << 16;
  return nvme_get_log(fd, nsid, cdw10, data_len, data);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L4
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_input(char *buffer, int maxCount) {
  fgets(buffer, maxCount, stdin);
  fflush(stdin);
  int size = strlen(buffer);
  if (buffer[size - 1] == '\n')
    buffer[--size] = '\0';
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_input>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    D9(%rip),%rbp
  mov    0x0(%rbp),%edx
  call   <fgets@plt>
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0xa,(%rdx)
  je     L16
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  sub    $0x1,%eax
  movb   $0x0,(%rdx)
  jmp    L12
```

assistant: ```c
int get_input(char *buffer, int maxCount) {
  fgets(buffer, maxCount, stdin);
  fflush(stdin);
  int size = strlen(buffer);
  if (buffer[size - 1] == '\n')
    buffer[--size] = '\0';
  return size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_input>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbp
  mov    0x0(%rbp),%edx
  call   <fgets@plt>
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0xa,(%rdx)
  jne    L3
  movb   $0x0,(%rdx)
  sub    $0x1,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_input(char *buffer, int maxCount) {
  fgets(buffer, maxCount, stdin);
  fflush(stdin);
  int size = strlen(buffer);
  if (buffer[size - 1] == '\n')
    buffer[--size] = '\0';
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_input>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rbp
  mov    0x0(%rbp),%edx
  call   <fgets@plt>
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0xa,(%rdx)
  jne    L4
  movb   $0x0,(%rdx)
  sub    $0x1,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_input(char *buffer, int maxCount) {
  fgets(buffer, maxCount, stdin);
  fflush(stdin);
  int size = strlen(buffer);
  if (buffer[size - 1] == '\n')
    buffer[--size] = '\0';
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_mm_div_ss>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    (%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__m128 __attribute__((__always___, __nodebug__)) _mm_div_ss(__m128 a, __m128 b) {
  a[0] /= b[0];
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mm_div_ss>:
  endbr64
  mov    (%rdi),%eax
  cltd
  idivl  (%rsi)
  mov    %eax,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
__m128 __attribute__((__always___, __nodebug__)) _mm_div_ss(__m128 a, __m128 b) {
  a[0] /= b[0];
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_mm_div_ss>:
  endbr64
  mov    (%rdi),%eax
  cltd
  idivl  (%rsi)
  mov    %eax,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
__m128 __attribute__((__always___, __nodebug__)) _mm_div_ss(__m128 a, __m128 b) {
  a[0] /= b[0];
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mm_div_ss>:
  endbr64
  mov    (%rdi),%eax
  cltd
  idivl  (%rsi)
  mov    %eax,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
__m128 __attribute__((__always___, __nodebug__)) _mm_div_ss(__m128 a, __m128 b) {
  a[0] /= b[0];
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L46
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L5
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L40
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L40:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L13
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort>
  jmp    L18
L46:
  nop
L18:
  leave
  ret
```

assistant: ```c
void qsort(int *x, int l, int u) {
  if (l >= u)
    return;
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + i, x + (++m));
  }
  swap(x + l, x + m);
  qsort(x, l, m - 1);
  qsort(x, m + 1, u);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qsort>:
  endbr64
  cmp    %edx,%esi
  jge    L54
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r12d
  lea    0x1(%rsi),%ebx
  cmp    %ebx,%edx
  jl     L11
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r15
  movslq %ebx,%rbx
  mov    %esi,%r13d
  jmp    L29
L57:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L41
L29:
  lea    0x0(%rbp,%rbx,4),%rdi
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L57
  add    $0x1,%r13d
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swap@plt>
  jmp    L57
L11:
  mov    %esi,%r13d
L41:
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  lea    -0x1(%r13),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <qsort>
  lea    0x1(%r13),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <qsort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  ret
```

assistant: ```c
void qsort(int *x, int l, int u) {
  if (l >= u)
    return;
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + i, x + (++m));
  }
  swap(x + l, x + m);
  qsort(x, l, m - 1);
  qsort(x, m + 1, u);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qsort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L36:
  cmp    %r13d,%r14d
  jge    L40
L34:
  movslq %r14d,%rax
  lea    0x1(%r14),%ebx
  lea    0x0(%rbp,%rax,4),%r15
  cmp    %ebx,%r13d
  jl     L68
  movslq %ebx,%rbx
  mov    %r14d,%r12d
  jmp    L17
  nopl   0x0(%rax)
L66:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jl     L51
L17:
  mov    (%r15),%eax
  lea    0x0(%rbp,%rbx,4),%rdi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L66
  add    $0x1,%r12d
  add    $0x1,%rbx
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swap@plt>
  cmp    %ebx,%r13d
  jge    L17
L51:
  movslq %r12d,%rax
  mov    %r15,%rdi
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r12),%edx
  mov    %rbp,%rdi
  call   <qsort>
  lea    0x1(%r12),%r14d
  cmp    %r13d,%r14d
  jl     L34
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %r15,%rsi
  mov    %r15,%rdi
  lea    -0x1(%r14),%r13d
  call   <swap@plt>
  jmp    L36
```

assistant: ```c
void qsort(int *x, int l, int u) {
  if (l >= u)
    return;
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + i, x + (++m));
  }
  swap(x + l, x + m);
  qsort(x, l, m - 1);
  qsort(x, m + 1, u);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getushort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %ax,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1a(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  movzwl -0x1a(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
unsigned short getushort(unsigned short x) {
  char *p1, *p2;
  unsigned short y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[1] = p1[0];
  p2[0] = p1[1];
  return (y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getushort>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%edx
  mov    %al,%dh
  movsbl %ah,%eax
  mov    %al,%dl
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned short getushort(unsigned short x) {
  char *p1, *p2;
  unsigned short y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[1] = p1[0];
  p2[0] = p1[1];
  return (y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getushort>:
  endbr64
  mov    %edi,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short getushort(unsigned short x) {
  char *p1, *p2;
  unsigned short y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[1] = p1[0];
  p2[0] = p1[1];
  return (y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getushort>:
  endbr64
  mov    %edi,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short getushort(unsigned short x) {
  char *p1, *p2;
  unsigned short y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[1] = p1[0];
  p2[0] = p1[1];
  return (y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L4
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0xa(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void push(double *stack, int *pos, double num, int *stacksize) {
  if ((*pos) + 1 >= *stacksize) {
    *stacksize += 10;
    stack = (double *)realloc(stack, sizeof(double) * *stacksize);
  }
  (*pos)++;
  stack[*pos] = num;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<push>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  movq   %xmm0,%rbp
  mov    (%rdx),%esi
  mov    (%rbx),%eax
  add    $0x1,%eax
  cmp    %esi,%eax
  jge    L15
L6:
  mov    (%rbx),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  movslq %edx,%rdx
  mov    %rbp,(%rdi,%rdx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  add    $0xa,%esi
  mov    %esi,(%rdx)
  shl    $0x3,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  jmp    L6
```

assistant: ```c
void push(double *stack, int *pos, double num, int *stacksize) {
  if ((*pos) + 1 >= *stacksize) {
    *stacksize += 10;
    stack = (double *)realloc(stack, sizeof(double) * *stacksize);
  }
  (*pos)++;
  stack[*pos] = num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<push>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    (%rsi),%eax
  mov    (%rdx),%esi
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jge    L0
  mov    %ecx,(%rbx)
  movslq %ecx,%rcx
  movsd  %xmm0,(%rdi,%rcx,8)
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0xa,%esi
  movsd  %xmm0,0x8(%rsp)
  mov    %esi,(%rdx)
  shl    $0x3,%esi
  call   <realloc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rax,%rdi
  mov    (%rbx),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,(%rbx)
  movslq %ecx,%rcx
  movsd  %xmm0,(%rdi,%rcx,8)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void push(double *stack, int *pos, double num, int *stacksize) {
  if ((*pos) + 1 >= *stacksize) {
    *stacksize += 10;
    stack = (double *)realloc(stack, sizeof(double) * *stacksize);
  }
  (*pos)++;
  stack[*pos] = num;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<push>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    (%rsi),%eax
  mov    (%rdx),%esi
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jge    L4
  mov    %ecx,(%rbx)
  movslq %ecx,%rcx
  movsd  %xmm0,(%rdi,%rcx,8)
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0xa,%esi
  movsd  %xmm0,0x8(%rsp)
  mov    %esi,(%rdx)
  shl    $0x3,%esi
  call   <realloc@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rax,%rdi
  mov    (%rbx),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,(%rbx)
  movslq %ecx,%rcx
  movsd  %xmm0,(%rdi,%rcx,8)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void push(double *stack, int *pos, double num, int *stacksize) {
  if ((*pos) + 1 >= *stacksize) {
    *stacksize += 10;
    stack = (double *)realloc(stack, sizeof(double) * *stacksize);
  }
  (*pos)++;
  stack[*pos] = num;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_f3tensor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_f3tensor(double ***t, long nrl, long nrh, long ncl, long nch, long ndl, long ndh) {
  free((char *)(t[nrl][ncl] + ndl - 1));
  free((char *)(t[nrl] + ncl - 1));
  free((char *)(t + nrl - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_f3tensor>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,8),%rbx
  lea    (%rdi,%rbx,1),%r12
  lea    0x0(,%rcx,8),%r13
  mov    (%r12),%rax
  mov    (%rax,%rcx,8),%rax
  lea    -0x8(%rax,%r9,8),%rdi
  call   <free@plt>
  mov    (%r12),%rax
  lea    -0x8(%rax,%r13,1),%rdi
  call   <free@plt>
  lea    -0x8(%rbp,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void free_f3tensor(double ***t, long nrl, long nrh, long ncl, long nch, long ndl, long ndh) {
  free((char *)(t[nrl][ncl] + ndl - 1));
  free((char *)(t[nrl] + ncl - 1));
  free((char *)(t + nrl - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_f3tensor>:
  endbr64
  push   %r13
  lea    0x0(,%rcx,8),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x0(,%rsi,8),%rbx
  lea    (%rdi,%rbx,1),%r12
  sub    $0x8,%rsp
  mov    (%r12),%rax
  mov    (%rax,%rcx,8),%rax
  lea    -0x8(%rax,%r9,8),%rdi
  call   <free@plt>
  mov    (%r12),%rax
  lea    -0x8(%rax,%r13,1),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  lea    -0x8(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void free_f3tensor(double ***t, long nrl, long nrh, long ncl, long nch, long ndl, long ndh) {
  free((char *)(t[nrl][ncl] + ndl - 1));
  free((char *)(t[nrl] + ncl - 1));
  free((char *)(t + nrl - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_f3tensor>:
  endbr64
  push   %r13
  lea    0x0(,%rcx,8),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x0(,%rsi,8),%rbx
  lea    (%rdi,%rbx,1),%r12
  sub    $0x8,%rsp
  mov    (%r12),%rax
  mov    (%rax,%rcx,8),%rax
  lea    -0x8(%rax,%r9,8),%rdi
  call   <free@plt>
  mov    (%r12),%rax
  lea    -0x8(%rax,%r13,1),%rdi
  call   <free@plt>
  add    $0x8,%rsp
  lea    -0x8(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <free@plt>
```

assistant: ```c
void free_f3tensor(double ***t, long nrl, long nrh, long ncl, long nch, long ndl, long ndh) {
  free((char *)(t[nrl][ncl] + ndl - 1));
  free((char *)(t[nrl] + ncl - 1));
  free((char *)(t + nrl - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rte_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movzbl D48(%rip),%eax
  test   %al,%al
  je     L6
  lea    D48(%rip),%rax
  jmp    L10
L6:
  sub    $0x8,%rsp
  push   $0x0
  mov    $0xb,%r9d
  mov    $0x11,%r8d
  lea    D12(%rip),%rax
  mov    %rax,%rcx
  lea    D8(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    $0x10,%rsp
  lea    D48(%rip),%rax
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D12: DPDK

tool: D8: %s %d.%02d.%d

assistant: ```c
const char *rte_version(void) {
  static char version[32];
  if (version[0] != 0)
    return version;
  if (strlen("") == 0)
    snprintf(version, sizeof(version), "%s %d.%02d.%d", "DPDK", 17, 11, 0);
  else
    snprintf(version, sizeof(version), "%s %d.%02d.%d%s%d", "DPDK", 17, 11, 0, "", 16 < 16 ? 16 : 16 - 16);
  return version;
}
```