ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<random_generate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  sub    %ebp,%esi
  cltd
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int random_generate(int min, int max) {
  int number, input;
  number = rand() % (max + 1 - min) + min;
  ;
  return number;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_generate>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  sub    %ebp,%esi
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int random_generate(int min, int max) {
  int number, input;
  number = rand() % (max + 1 - min) + min;
  ;
  return number;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<random_generate>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  lea    0x1(%rbx),%esi
  add    $0x8,%rsp
  sub    %ebp,%esi
  cltd
  pop    %rbx
  idiv   %esi
  lea    (%rdx,%rbp,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int random_generate(int min, int max) {
  int number, input;
  number = rand() % (max + 1 - min) + min;
  ;
  return number;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<name_of_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x52,%eax
  cmp    $0x21,%eax
  ja     L8
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D37(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D37(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L8:
  mov    $0x1,%edi
  call   <fault@plt>
  lea    D57(%rip),%rax
  jmp    L24
  lea    D49(%rip),%rax
  jmp    L24
  lea    D31(%rip),%rax
  jmp    L24
  lea    D34(%rip),%rax
  jmp    L24
  lea    D12(%rip),%rax
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D57
type: string
name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D31
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D12
type: string

tool: D57: string

tool: D49: integer

tool: D31: routine

tool: D34: routine or grouping

tool: D12: grouping

assistant: ```c
char *name_of_type(int n) {
  switch (n) {
  default:
    fault(1);
  case 's':
    return "string";
  case 'i':
    return "integer";
  case 'r':
    return "routine";
  case 'R':
    return "routine or grouping";
  case 'g':
    return "grouping";
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<name_of_type>:
  endbr64
  sub    $0x52,%edi
  cmp    $0x21,%edi
  ja     L4
  mov    %edi,%edi
  lea    D58(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D33(%rip),%rax
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fault@plt>
  lea    D33(%rip),%rax
  add    $0x8,%rsp
  ret
  lea    D66(%rip),%rax
  ret
  lea    D46(%rip),%rax
  ret
  lea    D18(%rip),%rax
  ret
  lea    D35(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D33
data_type: string
name: parse_data
arguments: label: D66
data_type: string
name: parse_data
arguments: label: D46
data_type: string
name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D35
data_type: string

tool: D33: string

tool: D66: routine

tool: D46: routine or grouping

tool: D18: grouping

tool: D35: integer

assistant: ```c
char *name_of_type(int n) {
  switch (n) {
  default:
    fault(1);
  case 's':
    return "string";
  case 'i':
    return "integer";
  case 'r':
    return "routine";
  case 'R':
    return "routine or grouping";
  case 'g':
    return "grouping";
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<name_of_type>:
  endbr64
  sub    $0x52,%edi
  cmp    $0x21,%edi
  ja     L2
  lea    D42(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L2:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fault@plt>
  lea    D58(%rip),%rax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  lea    D27(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D18(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D40(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D58(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D58
datatype: string
name: parse_data
arguments: label: D27
datatype: string
name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D40
datatype: string

tool: D58: string

tool: D27: routine or grouping

tool: D18: grouping

tool: D28: routine

tool: D40: integer

assistant: ```c
char *name_of_type(int n) {
  switch (n) {
  default:
    fault(1);
  case 's':
    return "string";
  case 'i':
    return "integer";
  case 'r':
    return "routine";
  case 'R':
    return "routine or grouping";
  case 'g':
    return "grouping";
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<name_of_type>:
  endbr64
  sub    $0x52,%edi
  cmp    $0x21,%edi
  ja     L6
  lea    D44(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L6:
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fault@plt>
  lea    D6(%rip),%rax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
  lea    D28(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D13(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D54(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D50(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D54
type_guessed: string
name: parse_data
arguments: label: D50
type_guessed: string

tool: D6: string

tool: D28: routine or grouping

tool: D13: grouping

tool: D54: routine

tool: D50: integer

assistant: ```c
char *name_of_type(int n) {
  switch (n) {
  default:
    fault(1);
  case 's':
    return "string";
  case 'i':
    return "integer";
  case 'r':
    return "routine";
  case 'R':
    return "routine or grouping";
  case 'g':
    return "grouping";
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<decompose_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L15:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x6,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <decompose_row@plt>
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L15
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L23:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <decompose_column@plt>
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void decompose_image(float *image) {
  int row;
  for (row = 0; row < 64; ++row)
    decompose_row(image + 3 * 64 * row);
  for (row = 0; row < 64; ++row)
    decompose_column(image + 3 * row);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decompose_image>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0xc000(%rdi),%r12
  mov    %rdi,%rbp
L9:
  mov    %rbp,%rdi
  call   <decompose_row@plt>
  add    $0x300,%rbp
  cmp    %r12,%rbp
  jne    L9
  lea    0x300(%rbx),%rbp
L3:
  mov    %rbx,%rdi
  call   <decompose_column@plt>
  add    $0xc,%rbx
  cmp    %rbp,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decompose_image(float *image) {
  int row;
  for (row = 0; row < 64; ++row)
    decompose_row(image + 3 * 64 * row);
  for (row = 0; row < 64; ++row)
    decompose_column(image + 3 * row);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<decompose_image>:
  endbr64
  push   %r12
  lea    0xc000(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L15:
  mov    %rbp,%rdi
  add    $0x300,%rbp
  call   <decompose_row@plt>
  cmp    %r12,%rbp
  jne    L15
  lea    0x300(%rbx),%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  add    $0xc,%rbx
  call   <decompose_column@plt>
  cmp    %rbp,%rbx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decompose_image(float *image) {
  int row;
  for (row = 0; row < 64; ++row)
    decompose_row(image + 3 * 64 * row);
  for (row = 0; row < 64; ++row)
    decompose_column(image + 3 * row);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<decompose_image>:
  endbr64
  push   %r12
  lea    0xc000(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L19:
  mov    %rbp,%rdi
  add    $0x300,%rbp
  call   <decompose_row@plt>
  cmp    %rbp,%r12
  jne    L19
  lea    0x300(%rbx),%rbp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  add    $0xc,%rbx
  call   <decompose_column@plt>
  cmp    %rbx,%rbp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decompose_image(float *image) {
  int row;
  for (row = 0; row < 64; ++row)
    decompose_row(image + 3 * 64 * row);
  for (row = 0; row < 64; ++row)
    decompose_column(image + 3 * row);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <lib1_func1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  lib1_func1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lib1_func1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lib1_func1();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lib1_func1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lib1_func1();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lib1_func1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lib1_func1();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x6b,%eax
  je     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x4b,%eax
  jne    L31
L8:
  shll   $0xa,-0x4(%rbp)
L31:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  je     L20
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x4d,%eax
  jne    L23
L20:
  shll   $0x14,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int parse_bytes(s)
char *s;
{
  int n = atoi(s);
  if ((lastchar(s) == 'k') || (lastchar(s) == 'K'))
    n *= 1024;
  if ((lastchar(s) == 'm') || (lastchar(s) == 'M'))
    n *= (1024 * 1024);
  return (n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_bytes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x6b,%eax
  jne    L26
L20:
  shl    $0xa,%ebp
L50:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  jne    L34
L37:
  shl    $0x14,%ebp
L14:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x4b,%eax
  jne    L50
  jmp    L20
L34:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <lastchar@plt>
  cmp    $0x4d,%eax
  jne    L14
  jmp    L37
```

assistant: ```c
int parse_bytes(s)
char *s;
{
  int n = atoi(s);
  if ((lastchar(s) == 'k') || (lastchar(s) == 'K'))
    n *= 1024;
  if ((lastchar(s) == 'm') || (lastchar(s) == 'M'))
    n *= (1024 * 1024);
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_bytes>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <lastchar@plt>
  cmp    $0x6b,%eax
  jne    L46
L14:
  xor    %eax,%eax
  mov    %rbp,%rdi
  shl    $0xa,%r12d
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  jne    L45
L10:
  shl    $0x14,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x4b,%eax
  je     L14
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  je     L10
L45:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x4d,%eax
  je     L10
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int parse_bytes(s)
char *s;
{
  int n = atoi(s);
  if ((lastchar(s) == 'k') || (lastchar(s) == 'K'))
    n *= 1024;
  if ((lastchar(s) == 'm') || (lastchar(s) == 'M'))
    n *= (1024 * 1024);
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_bytes>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <lastchar@plt>
  cmp    $0x6b,%eax
  jne    L41
L39:
  xor    %eax,%eax
  mov    %rbp,%rdi
  shl    $0xa,%r12d
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  jne    L10
L48:
  shl    $0x14,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x4b,%eax
  je     L39
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x6d,%eax
  je     L48
L10:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <lastchar@plt>
  cmp    $0x4d,%eax
  je     L48
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int parse_bytes(s)
char *s;
{
  int n = atoi(s);
  if ((lastchar(s) == 'k') || (lastchar(s) == 'K'))
    n *= 1024;
  if ((lastchar(s) == 'm') || (lastchar(s) == 'M'))
    n *= (1024 * 1024);
  return (n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1505,-0x8(%rbp)
  jmp    L7
L2:
  mov    -0x8(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  imul   $0x51d07eaf,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x61,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_key(const char *key) {
  int c;
  unsigned int h = 5381;
  while ((c = *key++))
    h = ((h << 5) + h) + c;
  return h % 97;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash_key>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  mov    $0x1505,%edx
L22:
  mov    %edx,%esi
  shl    $0x5,%esi
  add    %esi,%edx
  movsbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  jne    L22
L10:
  mov    %edx,%ecx
  imul   $0x51d07eaf,%rcx,%rcx
  shr    $0x20,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x61,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L12:
  mov    $0x1505,%edx
  jmp    L10
```

assistant: ```c
unsigned int hash_key(const char *key) {
  int c;
  unsigned int h = 5381;
  while ((c = *key++))
    h = ((h << 5) + h) + c;
  return h % 97;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash_key>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L3
  mov    $0x1505,%edx
  nopl   0x0(%rax)
L16:
  mov    %edx,%esi
  add    $0x1,%rcx
  shl    $0x5,%esi
  add    %esi,%edx
  add    %eax,%edx
  movsbl -0x1(%rcx),%eax
  test   %al,%al
  jne    L16
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x51d07eaf,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x61,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L3:
  mov    $0x2e,%eax
  ret
```

assistant: ```c
unsigned int hash_key(const char *key) {
  int c;
  unsigned int h = 5381;
  while ((c = *key++))
    h = ((h << 5) + h) + c;
  return h % 97;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_key>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L7
  mov    $0x1505,%edx
  nopl   0x0(%rax)
L19:
  mov    %edx,%esi
  add    $0x1,%rcx
  shl    $0x5,%esi
  add    %esi,%edx
  add    %eax,%edx
  movsbl -0x1(%rcx),%eax
  test   %al,%al
  jne    L19
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x51d07eaf,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x61,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   (%rax)
L7:
  mov    $0x2e,%eax
  ret
```

assistant: ```c
unsigned int hash_key(const char *key) {
  int c;
  unsigned int h = 5381;
  while ((c = *key++))
    h = ((h << 5) + h) + c;
  return h % 97;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ccount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L10
  addl   $0x1,-0x8(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L5
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ccount(char *str, char c) {
  int count = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ccount>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L8
L2:
  cmp    %r13b,0x0(%rbp,%rbx,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  add    $0x1,%rbx
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ccount(char *str, char c) {
  int count = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ccount>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  cmp    %r13b,0x0(%rbp,%rbx,1)
  sete   %al
  add    $0x1,%rbx
  add    %eax,%r12d
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L17
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ccount(char *str, char c) {
  int count = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ccount>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  cmp    %r13b,0x0(%rbp,%rbx,1)
  sete   %al
  add    $0x1,%rbx
  add    %eax,%r12d
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ccount(char *str, char c) {
  int count = 0;
  for (int i = 0; i < strlen(str); i++) {
    if (str[i] == c) {
      count++;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<diagMul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <sqrt@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <sqrt@plt>
  test   %r12d,%r12d
  jle    L82
  mov    %eax,%r13d
  mov    %eax,%r8d
  neg    %r8d
  mov    $0x0,%r9d
  mov    $0x0,%esi
  mov    $0x0,%r14d
  lea    -0x1(%rax),%edi
  jmp    L46
L19:
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  je     L92
  test   %edx,%edx
  jle    L77
  lea    (%rdx,%rcx,1),%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  lea    (%r10,%rdx,1),%r15d
  movslq %r15d,%r15
  movss  (%rax),%xmm0
  subss  (%rbx,%r15,4),%xmm0
  movss  %xmm0,(%rax)
L77:
  mov    %edx,%eax
L43:
  cmp    %eax,%edi
  jle    L8
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  lea    (%r11,%rax,1),%r15d
  movslq %r15d,%r15
  movss  (%rdx),%xmm0
  subss  (%rbx,%r15,4),%xmm0
  movss  %xmm0,(%rdx)
L8:
  test   %esi,%esi
  jle    L54
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  lea    (%rax,%r8,1),%r15d
  movslq %r15d,%r15
  movss  (%rdx),%xmm0
  subss  (%rbx,%r15,4),%xmm0
  movss  %xmm0,(%rdx)
L54:
  cmp    %esi,%edi
  jle    L19
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
  lea    (%r9,%rax,1),%r15d
  movslq %r15d,%r15
  movss  (%rdx),%xmm0
  subss  (%rbx,%r15,4),%xmm0
  movss  %xmm0,(%rdx)
  jmp    L19
L92:
  lea    0x1(%rsi),%edx
  add    %r13d,%r8d
  cmp    %esi,%eax
  je     L82
  mov    %edx,%esi
L46:
  mov    %r9d,%ecx
  add    %r13d,%r9d
  mov    %r14d,%eax
  lea    0x1(%rcx),%r11d
  lea    -0x1(%rcx),%r10d
  jmp    L43
L82:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void diagMul(int size, float *xx, float *res) {
  int dim = sqrt(size);
  int _xRes = sqrt(size);
  int y;
  int x;
  for (y = 0; y < dim; y++) {
    for (x = 0; x < dim; x++) {
      if (x > 0) {
        res[x + y * _xRes] += -xx[(x - 1) + y * _xRes];
      }
      if (x < _xRes - 1) {
        res[x + y * _xRes] += -xx[(x + 1) + y * _xRes];
      }
      if (y > 0) {
        res[x + y * _xRes] += -xx[x + (y - 1) * _xRes];
      }
      if (y < _xRes - 1) {
        res[x + y * _xRes] += -xx[x + (y + 1) * _xRes];
      }
    }
  }
}
```