ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  movdqa D32(%rip),%xmm0
  movdqa D24(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0xfb0(%rsp),%r15
  mov    %r13,%rax
  nopl   0x0(%rax,%rax,1)
L61:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %r15,%rax
  jne    L61
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D22(%rip),%rbx
  lea    D13(%rip),%r14
  nopl   (%rax)
L62:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L13
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rsi
  mov    0x10(%rsp,%rax,4),%edx
  mov    %rax,%r8
  mov    %rsi,%r9
  cmp    0x10(%rsp,%rsi,4),%edx
  je     L62
  mov    %r13,%rax
L58:
  cmp    (%rax),%edx
  jne    L24
  mov    0x10(%rsp,%rsi,4),%ecx
  mov    %ecx,(%rax)
L24:
  add    $0x4,%rax
  cmp    %r15,%rax
  jne    L58
  mov    %r9d,%edx
  mov    %r8d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L62
L13:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D32
data_type: byte[16]
name: disassemble_data
arguments: data_label: D24
data_type: byte[16]
name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: {"D32": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D24": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D22: %d %d

tool: D13: %d-%d


assistant: ```c
int main(int argc, char **argv) {
  int id[1000];
  int i, t, p, q;
  for (i = 0; i < 1000; i++) {
    id[i] = i;
  }
  while (scanf("%d %d", &p, &q) == 2) {
    if (id[p] == id[q])
      continue;
    for (t = id[p], i = 0; i < 1000; i++) {
      if (id[i] == t)
        id[i] = id[q];
    }
    printf("%d-%d\n", p, q);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x18(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L11
  mov    -0x24(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L11:
  mov    -0x24(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string

tool: D25: %d%d%d%d%d

tool: D28: %d


assistant: ```c
int main(void) {
  int wd, jap, arith, pj, pa, dj, da;
  scanf("%d%d%d%d%d", &wd, &jap, &arith, &pj, &pa);
  dj = ceil(1.0 * jap / pj);
  da = ceil(1.0 * arith / pa);
  if (dj > da) {
    printf("%d\n", wd - dj);
  } else {
    printf("%d\n", wd - da);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x10(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0xc(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x14(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  cmp    %eax,%ebx
  jle    L9
  mov    0x4(%rsp),%esi
  sub    %ebx,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  mov    0x4(%rsp),%esi
  sub    %eax,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D27
datatype: string

tool: D17: %d%d%d%d%d

tool: D27: %d


assistant: ```c
int main(void) {
  int wd, jap, arith, pj, pa, dj, da;
  scanf("%d%d%d%d%d", &wd, &jap, &arith, &pj, &pa);
  dj = ceil(1.0 * jap / pj);
  da = ceil(1.0 * arith / pa);
  if (dj > da) {
    printf("%d\n", wd - dj);
  } else {
    printf("%d\n", wd - da);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rdi
  sub    $0x20,%rsp
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x10(%rsp),%xmm1
  cvtsi2sdl 0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0xc(%rsp),%xmm0
  mov    %eax,%ebx
  cvtsi2sdl 0x14(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  mov    0x4(%rsp),%esi
  cmp    %eax,%ebx
  jle    L16
  sub    %ebx,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L16:
  sub    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string

tool: D9: %d%d%d%d%d

tool: D10: %d


assistant: ```c
int main(void) {
  int wd, jap, arith, pj, pa, dj, da;
  scanf("%d%d%d%d%d", &wd, &jap, &arith, &pj, &pa);
  dj = ceil(1.0 * jap / pj);
  da = ceil(1.0 * arith / pa);
  if (dj > da) {
    printf("%d\n", wd - dj);
  } else {
    printf("%d\n", wd - da);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  sub    $0x20,%rsp
  lea    0x4(%rsp),%rsi
  lea    0xc(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x10(%rsp),%xmm1
  cvtsi2sdl 0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0xc(%rsp),%xmm0
  mov    %eax,%ebx
  cvtsi2sdl 0x14(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  mov    0x4(%rsp),%esi
  cmp    %eax,%ebx
  jle    L13
  sub    %ebx,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L13:
  sub    %eax,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string

tool: D6: %d%d%d%d%d

tool: D27: %d


assistant: ```c
int main(void) {
  int wd, jap, arith, pj, pa, dj, da;
  scanf("%d%d%d%d%d", &wd, &jap, &arith, &pj, &pa);
  dj = ceil(1.0 * jap / pj);
  da = ceil(1.0 * arith / pa);
  if (dj > da) {
    printf("%d\n", wd - dj);
  } else {
    printf("%d\n", wd - da);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1,-0x24(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  jmp    L63
L26:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L65
  movl   $0x0,-0x24(%rbp)
  jmp    L63
L65:
  addl   $0x1,-0x2c(%rbp)
  subl   $0x1,-0x28(%rbp)
L63:
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L20
  cmpl   $0x0,-0x24(%rbp)
  jne    L26
L20:
  cmpl   $0x0,-0x24(%rbp)
  je     L64
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L66
L64:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L66:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: string

tool: D13: Entre com uma palavra: 

tool: D27: A palavra e palindrome


tool: D21: A palavra nao e palindrome


assistant: ```c
main() {
  char palavra[20];
  int i = 0, j, pali = 1;
  printf("Entre com uma palavra: ");
  gets(palavra);
  j = strlen(palavra) - 1;
  while ((i < j) && (pali)) {
    if (palavra[i] != palavra[j])
      pali = 0;
    else {
      i++;
      j--;
    }
  }
  if (pali)
    printf("A palavra e palindrome\n");
  else
    printf("A palavra nao e palindrome\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%esi
  mov    %rbx,%rdi
  cltq
  lea    (%rbx,%rax,1),%rdx
  mov    $0x1,%eax
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L71:
  cmp    %esi,%ecx
  jge    L18
  test   %eax,%eax
  je     L18
  movzbl -0x1(%rdx),%ebx
  cmp    %bl,(%rdi)
  je     L3
  mov    %r8d,%eax
  jmp    L71
L3:
  add    $0x1,%ecx
  sub    $0x1,%esi
  add    $0x1,%rdi
  sub    $0x1,%rdx
  jmp    L71
L18:
  test   %eax,%eax
  je     L24
  lea    D9(%rip),%rdi
  call   <printf@plt>
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D29
type: string

tool: D3: Entre com uma palavra: 

tool: D9: A palavra e palindrome


tool: D29: A palavra nao e palindrome


assistant: ```c
main() {
  char palavra[20];
  int i = 0, j, pali = 1;
  printf("Entre com uma palavra: ");
  gets(palavra);
  j = strlen(palavra) - 1;
  while ((i < j) && (pali)) {
    if (palavra[i] != palavra[j])
      pali = 0;
    else {
      i++;
      j--;
    }
  }
  if (pali)
    printf("A palavra e palindrome\n");
  else
    printf("A palavra nao e palindrome\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D23(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  xor    %edi,%edi
  movslq %eax,%rcx
  lea    -0x1(%rax),%r8d
  add    %rbx,%rcx
L48:
  mov    %r8d,%eax
  sub    %edi,%eax
  cmp    %eax,%edi
  mov    $0x1,%eax
  setl   %sil
  nopw   0x0(%rax,%rax,1)
L50:
  test   %eax,%eax
  je     L66
  test   %sil,%sil
  je     L23
  movzbl -0x1(%rcx),%ebx
  xor    %eax,%eax
  cmp    %bl,(%rdx)
  jne    L50
  add    $0x1,%edi
  add    $0x1,%rdx
  sub    $0x1,%rcx
  jmp    L48
L66:
  lea    D26(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L23:
  test   %eax,%eax
  je     L66
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string
name: extract_symbolic_data
arguments: data_label: D25
datatype: string

tool: D23: Entre com uma palavra: 

tool: D26: A palavra nao e palindrome


tool: D25: A palavra e palindrome


assistant: ```c
main() {
  char palavra[20];
  int i = 0, j, pali = 1;
  printf("Entre com uma palavra: ");
  gets(palavra);
  j = strlen(palavra) - 1;
  while ((i < j) && (pali)) {
    if (palavra[i] != palavra[j])
      pali = 0;
    else {
      i++;
      j--;
    }
  }
  if (pali)
    printf("A palavra e palindrome\n");
  else
    printf("A palavra nao e palindrome\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  xor    %edi,%edi
  movslq %eax,%rcx
  lea    -0x1(%rax),%r8d
  add    %rbx,%rcx
L38:
  mov    %r8d,%eax
  sub    %edi,%eax
  cmp    %eax,%edi
  mov    $0x1,%eax
  setl   %sil
  nopw   0x0(%rax,%rax,1)
L42:
  test   %eax,%eax
  je     L10
  test   %sil,%sil
  je     L27
  movzbl -0x1(%rcx),%ebx
  xor    %eax,%eax
  cmp    %bl,(%rdx)
  jne    L42
  add    $0x1,%edi
  add    $0x1,%rdx
  sub    $0x1,%rcx
  jmp    L38
L10:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L27:
  test   %eax,%eax
  je     L10
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D2: Entre com uma palavra: 

tool: D11: A palavra nao e palindrome


tool: D5: A palavra e palindrome


assistant: ```c
main() {
  char palavra[20];
  int i = 0, j, pali = 1;
  printf("Entre com uma palavra: ");
  gets(palavra);
  j = strlen(palavra) - 1;
  while ((i < j) && (pali)) {
    if (palavra[i] != palavra[j])
      pali = 0;
    else {
      i++;
      j--;
    }
  }
  if (pali)
    printf("A palavra e palindrome\n");
  else
    printf("A palavra nao e palindrome\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<warshall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L83
L42:
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L46:
  movl   $0x0,-0x8(%rbp)
  jmp    L53
L44:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L38
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L38
L15:
  mov    $0x1,%ecx
  jmp    L5
L38:
  mov    $0x0,%ecx
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  addl   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L46
  addl   $0x1,-0x4(%rbp)
L83:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L42
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void warshall(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = arr[i][j] || (arr[i][k] && arr[k][j]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warshall>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x190(%rdi,%rax,1),%r11
  mov    %esi,%esi
  mov    %rsi,%r12
  neg    %r12
  shl    $0x2,%r12
  mov    %rdi,%rbx
  mov    $0x0,%r10d
  mov    $0x1,%r8d
  jmp    L51
L16:
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L26
L82:
  mov    %r8d,%edx
  cmpl   $0x0,(%rcx,%rax,4)
  jne    L16
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L16
  cmpl   $0x0,(%r9,%rax,4)
  setne  %dl
  movzbl %dl,%edx
  jmp    L16
L26:
  add    $0x190,%rdi
  cmp    %r11,%rdi
  je     L52
L24:
  lea    (%rdi,%r10,1),%rcx
  mov    $0x0,%eax
  jmp    L82
L52:
  add    $0x4,%r11
  sub    $0x4,%r10
  add    $0x190,%rbx
  cmp    %r12,%r10
  je     L48
L51:
  mov    %rbx,%r9
  mov    %rbp,%rdi
  sub    %r10,%rdi
  jmp    L24
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

assistant: ```c
void warshall(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = arr[i][j] || (arr[i][k] && arr[k][j]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<warshall>:
  endbr64
  test   %esi,%esi
  jle    L47
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  push   %rbx
  mov    %rdi,%r11
  lea    (%rax,%rax,4),%rax
  mov    %rsi,%rbx
  mov    %rdi,%r8
  xor    %r9d,%r9d
  lea    (%rax,%rax,4),%rax
  neg    %rbx
  shl    $0x4,%rax
  shl    $0x2,%rbx
  lea    0x190(%rdi,%rax,1),%r10
  nopl   0x0(%rax)
L14:
  mov    %r11,%rdi
  sub    %r9,%rdi
  cs nopw 0x0(%rax,%rax,1)
L30:
  lea    (%rdi,%r9,1),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L48:
  cmpl   $0x0,(%rcx,%rax,4)
  mov    $0x1,%edx
  jne    L57
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L57
  xor    %edx,%edx
  cmpl   $0x0,(%r8,%rax,4)
  setne  %dl
L57:
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L48
  add    $0x190,%rdi
  cmp    %r10,%rdi
  jne    L30
  sub    $0x4,%r9
  add    $0x4,%r10
  add    $0x190,%r8
  cmp    %rbx,%r9
  jne    L14
  pop    %rbx
  ret
L47:
  ret
```

assistant: ```c
void warshall(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = arr[i][j] || (arr[i][k] && arr[k][j]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<warshall>:
  endbr64
  test   %esi,%esi
  jle    L29
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  push   %rbx
  mov    %rdi,%r11
  lea    (%rax,%rax,4),%rax
  mov    %rsi,%rbx
  mov    %rdi,%r8
  xor    %r9d,%r9d
  lea    (%rax,%rax,4),%rax
  neg    %rbx
  shl    $0x4,%rax
  shl    $0x2,%rbx
  lea    0x190(%rdi,%rax,1),%r10
  nopl   0x0(%rax)
L13:
  mov    %r11,%rdi
  sub    %r9,%rdi
  cs nopw 0x0(%rax,%rax,1)
L54:
  lea    (%rdi,%r9,1),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L53:
  cmpl   $0x0,(%rcx,%rax,4)
  mov    $0x1,%edx
  jne    L36
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L36
  xor    %edx,%edx
  cmpl   $0x0,(%r8,%rax,4)
  setne  %dl
L36:
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L53
  add    $0x190,%rdi
  cmp    %r10,%rdi
  jne    L54
  sub    $0x4,%r9
  add    $0x4,%r10
  add    $0x190,%r8
  cmp    %rbx,%r9
  jne    L13
  pop    %rbx
  ret
L29:
  ret
```

assistant: ```c
void warshall(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = arr[i][j] || (arr[i][k] && arr[k][j]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_skippable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  jmp    L32
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x4(%rbp)
  jne    L37
  mov    $0x1,%eax
  jmp    L16
L37:
  addq   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int is_skippable(char c, char *skips) {
  for (; *skips; ++skips)
    if (c == *skips)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_skippable>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L13
L4:
  cmp    %al,%dil
  je     L11
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L4
  mov    $0x0,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_skippable(char c, char *skips) {
  for (; *skips; ++skips)
    if (c == *skips)
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_skippable>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    %al,%dil
  je     L2
  add    $0x1,%rsi
L16:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L28
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_skippable(char c, char *skips) {
  for (; *skips; ++skips)
    if (c == *skips)
      return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_skippable>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L18:
  cmp    %al,%dil
  je     L29
  add    $0x1,%rsi
L0:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_skippable(char c, char *skips) {
  for (; *skips; ++skips)
    if (c == *skips)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTFIFOLevelSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x34,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTFIFOLevelSet(uint32_t ui32Base, uint32_t ui32TxLevel, uint32_t ui32RxLevel) {
  ;

  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000034))) = ui32TxLevel | ui32RxLevel;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UARTFIFOLevelSet>:
  endbr64
  add    $0x34,%edi
  movslq %edi,%rdi
  or     %edx,%esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void UARTFIFOLevelSet(uint32_t ui32Base, uint32_t ui32TxLevel, uint32_t ui32RxLevel) {
  ;

  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000034))) = ui32TxLevel | ui32RxLevel;
}
```