ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L34
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  nopl   (%rax)
L55:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   $0x1,%al
  je     L57
  movslq %ebp,%rdx
  add    $0x4,%rbx
  add    $0x1,%ebp
  mov    %eax,0x1a0(%rsp,%rdx,4)
  cmp    %ebp,0xc(%rsp)
  jg     L55
L16:
  mov    %ebp,%r13d
  shr    $0x1f,%r13d
  add    %ebp,%r13d
  sar    %r13d
  cmp    $0x1,%ebp
  jle    L34
  lea    0x1a0(%rsp),%r14
  movslq %ebp,%rbp
  xor    %ebx,%ebx
  lea    (%r14,%rbp,4),%rbp
  nopl   0x0(%rax,%rax,1)
L53:
  mov    (%r14,%rbx,4),%esi
  mov    %r12,%rdi
  sub    -0x4(%rbp),%esi
  add    $0x1,%rbx
  call   <printf@plt>
  sub    $0x4,%rbp
  cmp    %ebx,%r13d
  jg     L53
  test   %r13d,%r13d
  mov    $0x1,%eax
  cmovle %eax,%r13d
L37:
  testb  $0x1,0xc(%rsp)
  jne    L14
L43:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L57:
  add    $0x4,%rbx
  cmp    %ebp,0xc(%rsp)
  jg     L55
  jmp    L16
L14:
  sar    %r13d
  lea    D2(%rip),%rdi
  lea    0x1(%r13),%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  jmp    L43
L34:
  xor    %r13d,%r13d
  jmp    L37
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D2
data_type: string

tool: D5: %d

tool: D2: 
%d


assistant: ```c
int main() {
  int a[100], i, n, b, nech[100], cn, tuci;
  i = 0;
  cn = 0;
  b = 0;
  scanf("%d", &n);
  while (i < n) {
    scanf("%d", &a[b]);
    if (a[b] % 2 != 0) {
      nech[cn] = a[b];
      cn++;
      i++;
    }
    b++;
  }
  for (b = 0; b < cn / 2; b++) {
    tuci = nech[b] - nech[cn - (b + 1)];
    printf("%d", tuci);
  }
  if (n % 2 != 0) {
    printf("\n%d\n", a[(b / 2) + 1]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShiftRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x28(%rbp)
  jmp    L38
L12:
  movl   $0x0,-0x24(%rbp)
  jmp    L11
L45:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x24(%rbp)
L11:
  cmpl   $0x3,-0x24(%rbp)
  jle    L45
  movl   $0x0,-0x24(%rbp)
  jmp    L5
L56:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  add    %rax,%rcx
  movslq %edx,%rax
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0x24(%rbp)
L5:
  cmpl   $0x3,-0x24(%rbp)
  jle    L56
  addl   $0x1,-0x28(%rbp)
L38:
  cmpl   $0x3,-0x28(%rbp)
  jle    L12
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void ShiftRow(uint8_t state[4][4]) {
  uint8_t i, j;
  uint8_t tmp[4];
  for (i = 1; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      tmp[j] = state[i][j];
    }
    for (j = 0; j < 4; j++) {
      state[i][j] = tmp[(j + i) & 3];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ShiftRow>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  add    $0x10,%rdi
  mov    $0x1,%ecx
L12:
  mov    %rdi,%rsi
  mov    (%rdi),%eax
  mov    %eax,(%rsp)
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rsp)
  mov    0x8(%rdi),%eax
  mov    %eax,0x8(%rsp)
  mov    0xc(%rdi),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%eax
L4:
  lea    (%rcx,%rax,1),%edx
  and    $0x3,%edx
  mov    (%rsp,%rdx,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L4
  add    $0x1,%ecx
  add    $0x10,%rdi
  cmp    $0x4,%ecx
  jne    L12
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ShiftRow(uint8_t state[4][4]) {
  uint8_t i, j;
  uint8_t tmp[4];
  for (i = 1; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      tmp[j] = state[i][j];
    }
    for (j = 0; j < 4; j++) {
      state[i][j] = tmp[(j + i) & 3];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ShiftRow>:
  endbr64
  sub    $0x28,%rsp
  add    $0x10,%rdi
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L22:
  movdqu (%rdi),%xmm0
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
L26:
  lea    (%rcx,%rax,1),%edx
  and    $0x3,%edx
  mov    (%rsp,%rdx,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L26
  add    $0x1,%ecx
  add    $0x10,%rdi
  cmp    $0x4,%ecx
  jne    L22
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ShiftRow(uint8_t state[4][4]) {
  uint8_t i, j;
  uint8_t tmp[4];
  for (i = 1; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      tmp[j] = state[i][j];
    }
    for (j = 0; j < 4; j++) {
      state[i][j] = tmp[(j + i) & 3];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ShiftRow>:
  endbr64
  mov    0x10(%rdi),%eax
  mov    0x1c(%rdi),%edx
  mov    0x14(%rdi),%rcx
  mov    %eax,0x1c(%rdi)
  mov    0x20(%rdi),%rax
  mov    %edx,0x18(%rdi)
  mov    0x28(%rdi),%rdx
  mov    %rcx,0x10(%rdi)
  mov    0x3c(%rdi),%ecx
  mov    %rdx,0x20(%rdi)
  mov    0x30(%rdi),%rdx
  mov    %rax,0x28(%rdi)
  mov    0x38(%rdi),%eax
  mov    %ecx,0x30(%rdi)
  mov    %rdx,0x34(%rdi)
  mov    %eax,0x3c(%rdi)
  ret
```

assistant: ```c
void ShiftRow(uint8_t state[4][4]) {
  uint8_t i, j;
  uint8_t tmp[4];
  for (i = 1; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      tmp[j] = state[i][j];
    }
    for (j = 0; j < 4; j++) {
      state[i][j] = tmp[(j + i) & 3];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_188_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  notl   -0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_188_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_188_0_0>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_188_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_188_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%edx
  mov    %esi,%eax
  shl    $0x8,%edx
  shl    $0x8,%eax
  or     %edi,%edx
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_188_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_188_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%edx
  mov    %esi,%eax
  shl    $0x8,%edx
  shl    $0x8,%eax
  or     %edi,%edx
  or     %esi,%eax
  not    %edi
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_188_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cad_primeiro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cad_tamanho@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cad_tamanho@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cad_iguais@plt>
  test   %rax,%rax
  je     L48
  mov    $0x0,%eax
  jmp    L14
L48:
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L79:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L73
  movl   $0x0,-0xc(%rbp)
L73:
  addl   $0x1,-0x10(%rbp)
L29:
  cmpl   $0x0,-0xc(%rbp)
  je     L8
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L8
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L79
L8:
  cmpl   $0x0,-0xc(%rbp)
  je     L68
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
L68:
  mov    -0xc(%rbp),%eax
L14:
  leave
  ret
```

assistant: ```c
int cad_primeiro(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int len2 = cad_tamanho(s2);
  int i, flag;
  if (cad_iguais(s1, s2))
    return 0;
  for (i = 0, flag = 1; flag && i < len1 && i < len2; i++) {
    if (s1[i] > s2[i])
      flag = 0;
  }
  if (flag) {
    flag = len1 < len2 ? 1 : 0;
  }
  return flag;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cad_primeiro>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <cad_tamanho@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <cad_tamanho@plt>
  mov    %eax,%r13d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <cad_iguais@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L20
  test   %r12d,%r12d
  jle    L53
  test   %r13d,%r13d
  jle    L53
  mov    $0x0,%eax
  cmp    %r13d,%r12d
  mov    %r13d,%edx
  cmovle %r12d,%edx
  jmp    L42
L45:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L53
L42:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%rbx,%rax,1)
  jle    L45
  mov    $0x0,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  cmp    %r13d,%r12d
  setl   %al
  movzbl %al,%eax
  jmp    L20
```

assistant: ```c
int cad_primeiro(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int len2 = cad_tamanho(s2);
  int i, flag;
  if (cad_iguais(s1, s2))
    return 0;
  for (i = 0, flag = 1; flag && i < len1 && i < len2; i++) {
    if (s1[i] > s2[i])
      flag = 0;
  }
  if (flag) {
    flag = len1 < len2 ? 1 : 0;
  }
  return flag;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cad_primeiro>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <cad_tamanho@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <cad_tamanho@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <cad_iguais@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L14
  test   %r12d,%r12d
  jle    L9
  test   %r13d,%r13d
  jle    L9
  lea    0x1(%r13),%esi
  mov    $0x1,%edx
  nop
L2:
  movzbl -0x1(%rbx,%rdx,1),%edi
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    %cl,%dil
  jg     L21
  cmp    %edx,%r12d
  jle    L29
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L2
L9:
  xor    %eax,%eax
  cmp    %r13d,%r12d
  setl   %al
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  cmp    %cl,%dil
  jle    L9
L21:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int cad_primeiro(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int len2 = cad_tamanho(s2);
  int i, flag;
  if (cad_iguais(s1, s2))
    return 0;
  for (i = 0, flag = 1; flag && i < len1 && i < len2; i++) {
    if (s1[i] > s2[i])
      flag = 0;
  }
  if (flag) {
    flag = len1 < len2 ? 1 : 0;
  }
  return flag;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cad_primeiro>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <cad_tamanho@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <cad_tamanho@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <cad_iguais@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L62
  test   %r12d,%r12d
  jle    L23
  test   %r13d,%r13d
  jle    L23
  lea    0x1(%r13),%esi
  mov    $0x1,%edx
  nop
L48:
  movzbl -0x1(%rbx,%rdx,1),%edi
  movzbl -0x1(%rbp,%rdx,1),%ecx
  cmp    %cl,%dil
  jg     L13
  cmp    %edx,%r12d
  jle    L3
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L48
L23:
  xor    %eax,%eax
  cmp    %r13d,%r12d
  setl   %al
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  cmp    %cl,%dil
  jle    L23
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int cad_primeiro(char s1[], char s2[]) {
  int len1 = cad_tamanho(s1);
  int len2 = cad_tamanho(s2);
  int i, flag;
  if (cad_iguais(s1, s2))
    return 0;
  for (i = 0, flag = 1; flag && i < len1 && i < len2; i++) {
    if (s1[i] > s2[i])
      flag = 0;
  }
  if (flag) {
    flag = len1 < len2 ? 1 : 0;
  }
  return flag;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_itoa_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %esi,%r13d
  movabs $0xfffffffffffff,%rbx
  movq   %xmm0,0x8(%rsp)
  and    0x8(%rsp),%rbx
  mov    $0xe,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  movb   $0x0,0xd(%rax)
  lea    0xc(%rax),%rcx
  mov    %rcx,%rax
  lea    -0xa(%r13),%edi
  jmp    L89
L81:
  mov    %ebx,%edx
  and    $0xf,%edx
  add    $0x30,%edx
L118:
  mov    %dl,(%rax)
  shr    $0x4,%rbx
  lea    -0x1(%rax),%rdx
  cmp    %rsi,%rax
  je     L33
  mov    %rdx,%rax
L89:
  mov    %rbx,%rdx
  and    $0xf,%edx
  cmp    $0x9,%rdx
  jbe    L81
  mov    %ebx,%edx
  and    $0xf,%edx
  add    %edi,%edx
  jmp    L118
L33:
  cmp    $0xffffffff,%ebp
  je     L0
  cmp    $0xc,%ebp
  jg     L0
  movslq %ebp,%rdx
  cmpb   $0x37,(%rsi,%rdx,1)
  jle    L0
  lea    -0x1(%rsi,%rdx,1),%rax
  movzbl (%rax),%edi
  lea    0x1(%rdi),%r8d
  cmp    $0x39,%dil
  cmovne %r8d,%r12d
  mov    %r12b,(%rax)
  lea    -0x1(%rbp),%eax
  test   %eax,%eax
  jle    L0
  cltq
  add    %rsi,%rax
  sub    $0x2,%rdx
  lea    -0x2(%rbp),%edi
  sub    %rdi,%rdx
  lea    (%rsi,%rdx,1),%r8
L124:
  movzbl (%rax),%edx
  and    $0xffffffdf,%edx
  cmp    $0x47,%dl
  jne    L0
  movb   $0x30,(%rax)
  movzbl -0x1(%rax),%edi
  lea    0x1(%rdi),%edx
  cmp    $0x39,%dil
  cmove  %r13d,%edx
  mov    %dl,-0x1(%rax)
  sub    $0x1,%rax
  cmp    %r8,%rax
  jne    L124
L0:
  cmpb   $0x30,(%rcx)
  jne    L40
  movb   $0x0,(%rcx)
  lea    -0x1(%rcx),%rax
  cmp    %rsi,%rcx
  je     L40
  mov    %rax,%rcx
  jmp    L0
L40:
  mov    %rsi,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_itoa_hex(double flo, int p, char spec) {
  int len;
  char *hex;
  unsigned long long n;
  n = *((unsigned long long *)&flo) & 0x000FFFFFFFFFFFFFULL;
  len = 13;
  hex = (char *)malloc(sizeof(char) * (len + 1));
  hex[len] = '\0';
  while (len-- > 0) {
    hex[len] = ((n % 16) > 9) ? (spec + (n % 16) - 10) : ((n % 16) + '0');
    n /= 16;
  }
  if ((len = 13) && p != -1 && p < 13 && hex[p] > '7') {
    hex[p - 1] = (hex[p - 1] != '9') ? (hex[p - 1] + 1) : spec;
    while (--p > 0 && (hex[p] == 'g' || hex[p] == 'G')) {
      hex[p] = '0';
      hex[p - 1] = (hex[p - 1] != '9') ? (hex[p - 1] + 1) : spec;
    }
  }
  while (--len >= 0 && hex[len] == '0')
    hex[len] = '\0';
  return (hex);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_itoa_hex>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xe,%edi
  push   %rbx
  movabs $0xfffffffffffff,%rbx
  sub    $0x18,%rsp
  movq   %xmm0,0x8(%rsp)
  and    0x8(%rsp),%rbx
  call   <malloc@plt>
  lea    -0xa(%r12),%r9d
  lea    0xc(%rax),%rcx
  movb   $0x0,0xd(%rax)
  mov    %rax,%r8
  mov    %rcx,%rdx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %rax,%rdx
L20:
  mov    %ebx,%eax
  mov    %rbx,%rdi
  and    $0xf,%eax
  and    $0xf,%edi
  lea    (%r9,%rax,1),%esi
  add    $0x30,%eax
  cmp    $0xa,%rdi
  cmovae %esi,%eax
  shr    $0x4,%rbx
  mov    %al,(%rdx)
  lea    -0x1(%rdx),%rax
  cmp    %r8,%rdx
  jne    L65
  cmp    $0xffffffff,%ebp
  je     L101
  cmp    $0xc,%ebp
  jg     L101
  movslq %ebp,%rdx
  cmpb   $0x37,(%r8,%rdx,1)
  jle    L101
  lea    -0x1(%r8,%rdx,1),%rax
  movzbl (%rax),%esi
  lea    0x1(%rsi),%edi
  cmp    $0x39,%sil
  cmovne %edi,%r13d
  mov    %r13b,(%rax)
  cmp    $0x1,%ebp
  jle    L101
  sub    $0x2,%rdx
  lea    -0x2(%rbp),%esi
  sub    %rsi,%rdx
  lea    (%r8,%rdx,1),%rdi
  jmp    L1
  xchg   %ax,%ax
L87:
  movb   $0x30,(%rax)
  movzbl -0x1(%rax),%esi
  sub    $0x1,%rax
  lea    0x1(%rsi),%edx
  cmp    $0x39,%sil
  cmove  %r12d,%edx
  mov    %dl,(%rax)
  cmp    %rdi,%rax
  je     L101
L1:
  movzbl (%rax),%edx
  and    $0xffffffdf,%edx
  cmp    $0x47,%dl
  je     L87
  cmpb   $0x30,(%rcx)
  je     L95
L116:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rax,%rcx
L101:
  cmpb   $0x30,(%rcx)
  jne    L116
L95:
  movb   $0x0,(%rcx)
  lea    -0x1(%rcx),%rax
  cmp    %r8,%rcx
  jne    L43
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_itoa_hex(double flo, int p, char spec) {
  int len;
  char *hex;
  unsigned long long n;
  n = *((unsigned long long *)&flo) & 0x000FFFFFFFFFFFFFULL;
  len = 13;
  hex = (char *)malloc(sizeof(char) * (len + 1));
  hex[len] = '\0';
  while (len-- > 0) {
    hex[len] = ((n % 16) > 9) ? (spec + (n % 16) - 10) : ((n % 16) + '0');
    n /= 16;
  }
  if ((len = 13) && p != -1 && p < 13 && hex[p] > '7') {
    hex[p - 1] = (hex[p - 1] != '9') ? (hex[p - 1] + 1) : spec;
    while (--p > 0 && (hex[p] == 'g' || hex[p] == 'G')) {
      hex[p] = '0';
      hex[p - 1] = (hex[p - 1] != '9') ? (hex[p - 1] + 1) : spec;
    }
  }
  while (--len >= 0 && hex[len] == '0')
    hex[len] = '\0';
  return (hex);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<log_fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <log_message@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: FATAL

assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_message(1, "FATAL", fmt, ap);
  va_end(ap);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_fatal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <log_message@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: FATAL

assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_message(1, "FATAL", fmt, ap);
  va_end(ap);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<log_fatal>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1,%edi
  lea    D8(%rip),%rsi
  call   <log_message@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: FATAL

assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_message(1, "FATAL", fmt, ap);
  va_end(ap);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<log_fatal>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x1,%edi
  lea    D6(%rip),%rsi
  call   <log_message@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: FATAL

assistant: ```c
void log_fatal(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_message(1, "FATAL", fmt, ap);
  va_end(ap);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L20
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  int res;
  while (1) {
    if ((res = *s1 - *s2) != 0 || *s1 == '\0')
      break;
    s1++, s2++;
  }
  return res;
}
```