ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compute_hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L19
  mov    $0x1505,%eax
L9:
  mov    %rax,%rdi
  shl    $0x5,%rdi
  add    %rdi,%rax
  movzbl %dl,%edx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L9
L13:
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
L19:
  mov    $0x1505,%eax
  jmp    L13
```

assistant: ```c
unsigned long compute_hash(unsigned char *str, size_t bound) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash % bound;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compute_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L10
  nopl   0x0(%rax)
L11:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L11
L10:
  xor    %edx,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long compute_hash(unsigned char *str, size_t bound) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash % bound;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compute_hash>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L13
  nopl   0x0(%rax)
L4:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L4
L13:
  xor    %edx,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned long compute_hash(unsigned char *str, size_t bound) {
  unsigned long hash = 5381;
  int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash % bound;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L99
  mov    $0x0,%eax
  jmp    L89
L99:
  cmpl   $0x3,-0x14(%rbp)
  jg     L26
  mov    $0x1,%eax
  jmp    L89
L26:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L77
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L8
L77:
  mov    $0x0,%eax
  jmp    L89
L8:
  movl   $0x5,-0x4(%rbp)
  jmp    L43
L117:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L82
  mov    -0x4(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L78
L82:
  mov    $0x0,%eax
  jmp    L89
L78:
  addl   $0x6,-0x4(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L117
  mov    $0x1,%eax
L89:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n <= 1) {
    return 0;
  } else if (n <= 3) {
    return 1;
  } else if (n % 2 == 0 || n % 3 == 0) {
    return 0;
  }
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L81
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jle    L81
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L81
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L81
  cmp    $0x18,%edi
  jle    L7
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L81
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L81
  mov    $0x5,%esi
L82:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jg     L74
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L81
  add    $0x8,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L82
L81:
  ret
L74:
  mov    $0x1,%eax
  ret
L7:
  mov    $0x1,%eax
  jmp    L81
```

assistant: ```c
int is_prime(int n) {
  if (n <= 1) {
    return 0;
  } else if (n <= 3) {
    return 1;
  } else if (n % 2 == 0 || n % 3 == 0) {
    return 0;
  }
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L75
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L75
  xor    %edx,%edx
  test   $0x1,%dil
  je     L75
  movslq %edi,%rax
  mov    %edi,%esi
  imul   $0x55555556,%rax,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L75
  cmp    $0x18,%ecx
  jle    L91
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L75
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %esi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L75
  mov    $0x5,%esi
  jmp    L47
  nopl   (%rax)
L73:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L75
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L75
L47:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L73
L91:
  mov    $0x1,%edx
L75:
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n <= 1) {
    return 0;
  } else if (n <= 3) {
    return 1;
  } else if (n % 2 == 0 || n % 3 == 0) {
    return 0;
  }
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L96
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L96
  xor    %edx,%edx
  test   $0x1,%dil
  je     L96
  movslq %edi,%rax
  mov    %edi,%esi
  imul   $0x55555556,%rax,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L96
  cmp    $0x18,%ecx
  jle    L21
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L96
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %esi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L96
  mov    $0x5,%esi
  jmp    L68
  nopl   (%rax)
L67:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L96
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L96
L68:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L67
L21:
  mov    $0x1,%edx
L96:
  mov    %edx,%eax
  ret
```

assistant: ```c
int is_prime(int n) {
  if (n <= 1) {
    return 0;
  } else if (n <= 3) {
    return 1;
  } else if (n % 2 == 0 || n % 3 == 0) {
    return 0;
  }
  for (int i = 5; i * i <= n; i += 6) {
    if (n % i == 0 || n % (i + 2) == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x44(%rbp)
  setne  %al
  movzbl %al,%eax
  cltq
  movl   $0xc,-0x40(%rbp,%rax,4)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int a[12];
  int b;
  a[b != 1] = 12;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a[12];
  int b;
  a[b != 1] = 12;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a[12];
  int b;
  a[b != 1] = 12;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a[12];
  int b;
  a[b != 1] = 12;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xilinxcorelib_a_3146741991_0543512595_p_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x5,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%rbp
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x5,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    0x7728(%rbx),%rax
  mov    0x38(%rax),%rdi
  mov    $0x5,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  lea    0x76f0(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x6ea0(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_2(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t6;
  unsigned char t8;
  unsigned int t9;
  char *t10;
  char *t11;
  unsigned char t12;
  unsigned char t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
  char *t23;
  char *t24;
  char *t25;
  char *t26;
  char *t27;
  char *t28;
LAB0:
  t4 = (t0 + 55646);
  t6 = (t0 + 55654);
  t8 = 1;
  if (8U == 7U)
    goto LAB14;
LAB15:
  t8 = 0;
LAB16:
  if (t8 == 1)
    goto LAB11;
LAB12:
  t3 = (unsigned char)0;
LAB13:
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t14 = (0 == 1);
  t1 = t14;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB20:
  t21 = xsi_get_transient_memory(5U);
  memset(t21, 0, 5U);
  t22 = t21;
  memset(t22, (unsigned char)2, 5U);
  t23 = (t0 + 30448);
  t24 = (t23 + 56U);
  t25 = *((char **)t24);
  t26 = (t25 + 56U);
  t27 = *((char **)t26);
  memcpy(t27, t21, 5U);
  xsi_driver_first_trans_fast_port(t23);
LAB2:
  t28 = (t0 + 28320);
  *((int *)t28) = 1;
LAB1:
  return;
LAB3:
  t15 = (t0 + 6256U);
  t16 = *((char **)t15);
  t15 = (t0 + 30448);
  t17 = (t15 + 56U);
  t18 = *((char **)t17);
  t19 = (t18 + 56U);
  t20 = *((char **)t19);
  memcpy(t20, t16, 5U);
  xsi_driver_first_trans_fast_port(t15);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t13 = (0 == 1);
  t2 = t13;
  goto LAB10;
LAB11:
  t12 = (0 == 1);
  t3 = t12;
  goto LAB13;
LAB14:
  t9 = 0;
LAB17:
  if (t9 < 8U)
    goto LAB18;
  else
    goto LAB16;
LAB18:
  t10 = (t4 + t9);
  t11 = (t6 + t9);
  if (*((unsigned char *)t10) != *((unsigned char *)t11))
    goto LAB15;
LAB19:
  t9 = (t9 + 1);
  goto LAB17;
LAB21:
  goto LAB2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xilinxcorelib_a_3146741991_0543512595_p_2>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edi
  sub    $0x8,%rsp
  call   <xsi_get_transient_memory@plt>
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0x2,%esi
  call   <memset@plt>
  mov    0x7728(%rbx),%rax
  mov    %rbp,%rsi
  mov    $0x5,%edx
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x76f0(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x6ea0(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_2(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t6;
  unsigned char t8;
  unsigned int t9;
  char *t10;
  char *t11;
  unsigned char t12;
  unsigned char t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
  char *t23;
  char *t24;
  char *t25;
  char *t26;
  char *t27;
  char *t28;
LAB0:
  t4 = (t0 + 55646);
  t6 = (t0 + 55654);
  t8 = 1;
  if (8U == 7U)
    goto LAB14;
LAB15:
  t8 = 0;
LAB16:
  if (t8 == 1)
    goto LAB11;
LAB12:
  t3 = (unsigned char)0;
LAB13:
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t14 = (0 == 1);
  t1 = t14;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB20:
  t21 = xsi_get_transient_memory(5U);
  memset(t21, 0, 5U);
  t22 = t21;
  memset(t22, (unsigned char)2, 5U);
  t23 = (t0 + 30448);
  t24 = (t23 + 56U);
  t25 = *((char **)t24);
  t26 = (t25 + 56U);
  t27 = *((char **)t26);
  memcpy(t27, t21, 5U);
  xsi_driver_first_trans_fast_port(t23);
LAB2:
  t28 = (t0 + 28320);
  *((int *)t28) = 1;
LAB1:
  return;
LAB3:
  t15 = (t0 + 6256U);
  t16 = *((char **)t15);
  t15 = (t0 + 30448);
  t17 = (t15 + 56U);
  t18 = *((char **)t17);
  t19 = (t18 + 56U);
  t20 = *((char **)t19);
  memcpy(t20, t16, 5U);
  xsi_driver_first_trans_fast_port(t15);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t13 = (0 == 1);
  t2 = t13;
  goto LAB10;
LAB11:
  t12 = (0 == 1);
  t3 = t12;
  goto LAB13;
LAB14:
  t9 = 0;
LAB17:
  if (t9 < 8U)
    goto LAB18;
  else
    goto LAB16;
LAB18:
  t10 = (t4 + t9);
  t11 = (t6 + t9);
  if (*((unsigned char *)t10) != *((unsigned char *)t11))
    goto LAB15;
LAB19:
  t9 = (t9 + 1);
  goto LAB17;
LAB21:
  goto LAB2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xilinxcorelib_a_3146741991_0543512595_p_2>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edi
  sub    $0x8,%rsp
  call   <xsi_get_transient_memory@plt>
  mov    $0x5,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  mov    $0x2,%esi
  call   <memset@plt>
  mov    0x7728(%rbx),%rax
  mov    %rbp,%rsi
  mov    $0x5,%edx
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x76f0(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x6ea0(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_2(char *t0) {
  unsigned char t1;
  unsigned char t2;
  unsigned char t3;
  char *t4;
  char *t6;
  unsigned char t8;
  unsigned int t9;
  char *t10;
  char *t11;
  unsigned char t12;
  unsigned char t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
  char *t19;
  char *t20;
  char *t21;
  char *t22;
  char *t23;
  char *t24;
  char *t25;
  char *t26;
  char *t27;
  char *t28;
LAB0:
  t4 = (t0 + 55646);
  t6 = (t0 + 55654);
  t8 = 1;
  if (8U == 7U)
    goto LAB14;
LAB15:
  t8 = 0;
LAB16:
  if (t8 == 1)
    goto LAB11;
LAB12:
  t3 = (unsigned char)0;
LAB13:
  if (t3 == 1)
    goto LAB8;
LAB9:
  t2 = (unsigned char)0;
LAB10:
  if (t2 == 1)
    goto LAB5;
LAB6:
  t14 = (0 == 1);
  t1 = t14;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB20:
  t21 = xsi_get_transient_memory(5U);
  memset(t21, 0, 5U);
  t22 = t21;
  memset(t22, (unsigned char)2, 5U);
  t23 = (t0 + 30448);
  t24 = (t23 + 56U);
  t25 = *((char **)t24);
  t26 = (t25 + 56U);
  t27 = *((char **)t26);
  memcpy(t27, t21, 5U);
  xsi_driver_first_trans_fast_port(t23);
LAB2:
  t28 = (t0 + 28320);
  *((int *)t28) = 1;
LAB1:
  return;
LAB3:
  t15 = (t0 + 6256U);
  t16 = *((char **)t15);
  t15 = (t0 + 30448);
  t17 = (t15 + 56U);
  t18 = *((char **)t17);
  t19 = (t18 + 56U);
  t20 = *((char **)t19);
  memcpy(t20, t16, 5U);
  xsi_driver_first_trans_fast_port(t15);
  goto LAB2;
LAB5:
  t1 = (unsigned char)1;
  goto LAB7;
LAB8:
  t13 = (0 == 1);
  t2 = t13;
  goto LAB10;
LAB11:
  t12 = (0 == 1);
  t3 = t12;
  goto LAB13;
LAB14:
  t9 = 0;
LAB17:
  if (t9 < 8U)
    goto LAB18;
  else
    goto LAB16;
LAB18:
  t10 = (t4 + t9);
  t11 = (t6 + t9);
  if (*((unsigned char *)t10) != *((unsigned char *)t11))
    goto LAB15;
LAB19:
  t9 = (t9 + 1);
  goto LAB17;
LAB21:
  goto LAB2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<i4x0_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  je     L89
  cmp    $0x3,%eax
  jg     L93
  cmp    $0x2,%eax
  je     L14
  cmp    $0x2,%eax
  jg     L93
  test   %eax,%eax
  je     L96
  cmp    $0x1,%eax
  je     L40
  jmp    L93
L96:
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x77,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mem_set_mem_state@plt>
  jmp    L93
L40:
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x17,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mem_set_mem_state@plt>
  jmp    L93
L14:
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x71,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mem_set_mem_state@plt>
  jmp    L93
L89:
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x11,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mem_set_mem_state@plt>
  nop
L93:
  mov    $0x0,%eax
  call   <flushmmucache_nopc@plt>
  nop
  leave
  ret
```

assistant: ```c
void i4x0_map(uint32_t addr, uint32_t size, int state) {
  switch (state & 3) {
  case 0:
    mem_set_mem_state(addr, size, 0x70 | 0x07);
    break;
  case 1:
    mem_set_mem_state(addr, size, 0x10 | 0x07);
    break;
  case 2:
    mem_set_mem_state(addr, size, 0x70 | 0x01);
    break;
  case 3:
    mem_set_mem_state(addr, size, 0x10 | 0x01);
    break;
  }
  flushmmucache_nopc();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<i4x0_map>:
  endbr64
  sub    $0x8,%rsp
  and    $0x3,%edx
  cmp    $0x2,%edx
  je     L0
  jg     L23
  test   %edx,%edx
  je     L33
  cmp    $0x1,%edx
  jne    L6
  mov    $0x17,%edx
  call   <mem_set_mem_state@plt>
  jmp    L6
L33:
  mov    $0x77,%edx
  call   <mem_set_mem_state@plt>
L6:
  mov    $0x0,%eax
  call   <flushmmucache_nopc@plt>
  add    $0x8,%rsp
  ret
L0:
  mov    $0x71,%edx
  call   <mem_set_mem_state@plt>
  jmp    L6
L23:
  mov    $0x11,%edx
  call   <mem_set_mem_state@plt>
  jmp    L6
```

assistant: ```c
void i4x0_map(uint32_t addr, uint32_t size, int state) {
  switch (state & 3) {
  case 0:
    mem_set_mem_state(addr, size, 0x70 | 0x07);
    break;
  case 1:
    mem_set_mem_state(addr, size, 0x10 | 0x07);
    break;
  case 2:
    mem_set_mem_state(addr, size, 0x70 | 0x01);
    break;
  case 3:
    mem_set_mem_state(addr, size, 0x10 | 0x01);
    break;
  }
  flushmmucache_nopc();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<i4x0_map>:
  endbr64
  and    $0x3,%edx
  sub    $0x8,%rsp
  cmp    $0x2,%edx
  je     L14
  cmp    $0x3,%edx
  je     L16
  cmp    $0x1,%edx
  je     L20
  mov    $0x77,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nop
L14:
  mov    $0x71,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nopl   (%rax)
L20:
  mov    $0x17,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nopl   (%rax)
L16:
  mov    $0x11,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
```

assistant: ```c
void i4x0_map(uint32_t addr, uint32_t size, int state) {
  switch (state & 3) {
  case 0:
    mem_set_mem_state(addr, size, 0x70 | 0x07);
    break;
  case 1:
    mem_set_mem_state(addr, size, 0x10 | 0x07);
    break;
  case 2:
    mem_set_mem_state(addr, size, 0x70 | 0x01);
    break;
  case 3:
    mem_set_mem_state(addr, size, 0x10 | 0x01);
    break;
  }
  flushmmucache_nopc();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i4x0_map>:
  endbr64
  and    $0x3,%edx
  sub    $0x8,%rsp
  cmp    $0x2,%edx
  je     L20
  cmp    $0x3,%edx
  je     L26
  cmp    $0x1,%edx
  je     L4
  mov    $0x77,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nop
L20:
  mov    $0x71,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nopl   (%rax)
L4:
  mov    $0x17,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
  nopl   (%rax)
L26:
  mov    $0x11,%edx
  call   <mem_set_mem_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <flushmmucache_nopc@plt>
```

assistant: ```c
void i4x0_map(uint32_t addr, uint32_t size, int state) {
  switch (state & 3) {
  case 0:
    mem_set_mem_state(addr, size, 0x70 | 0x07);
    break;
  case 1:
    mem_set_mem_state(addr, size, 0x10 | 0x07);
    break;
  case 2:
    mem_set_mem_state(addr, size, 0x70 | 0x01);
    break;
  case 3:
    mem_set_mem_state(addr, size, 0x10 | 0x01);
    break;
  }
  flushmmucache_nopc();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<C>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovle %esi,%eax
  cmovge %esi,%edx
  add    $0x1,%edx
  cmp    %edx,%edi
  jl     L60
  movsd  D10(%rip),%xmm0
  movsd  D23(%rip),%xmm3
  movapd %xmm3,%xmm2
  jmp    L31
L32:
  add    $0x1,%edx
  cmp    %edx,%edi
  jl     L67
L31:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  comisd %xmm3,%xmm0
  jbe    L32
  test   %eax,%eax
  je     L67
L41:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  sub    $0x1,%eax
  comisd %xmm2,%xmm0
  jbe    L32
  test   %eax,%eax
  jne    L41
L67:
  cvttsd2si %xmm0,%eax
  ret
L60:
  movsd  D10(%rip),%xmm0
  jmp    L67
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: byte[8]
name: parse_data
arguments: tag: D23
data_type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
int C(int n, int r) {
  int diff = n - r;
  int M = ((r) > (diff) ? (r) : (diff));
  int m = ((r) < (diff) ? (r) : (diff));
  double top;
  int i, j;
  int done = 0;
  for (top = 1, i = M + 1, j = m; !done && i <= n; ++i) {
    top *= i;
    while (top > 1000000) {
      if (!j) {
        done = 1;
        break;
      }
      top /= j;
      j--;
    }
  }
  return top;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<C>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovge %esi,%edx
  cmovle %esi,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jl     L1
  movsd  D6(%rip),%xmm0
  movsd  D8(%rip),%xmm2
  nopl   0x0(%rax)
L4:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  ja     L36
  jmp    L29
  nopl   0x0(%rax)
L54:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  sub    $0x1,%eax
  divsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jbe    L29
L36:
  test   %eax,%eax
  jne    L54
L7:
  cvttsd2si %xmm0,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%edx
  cmp    %edx,%edi
  jge    L4
  jmp    L7
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: byte[8]
name: parse_data
arguments: label: D8
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
int C(int n, int r) {
  int diff = n - r;
  int M = ((r) > (diff) ? (r) : (diff));
  int m = ((r) < (diff) ? (r) : (diff));
  double top;
  int i, j;
  int done = 0;
  for (top = 1, i = M + 1, j = m; !done && i <= n; ++i) {
    top *= i;
    while (top > 1000000) {
      if (!j) {
        done = 1;
        break;
      }
      top /= j;
      j--;
    }
  }
  return top;
}
```