ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<logd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0xe0(%rbp)
  je     L22
  mov    -0xe0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc4(%rbp),%edx
  mov    -0xe0(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc0(%rbp),%rdx
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <vlogd@plt>
  mov    -0xc0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L0
L22:
  mov    -0xd8(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <vlogd@plt>
L0:
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void logd(const char *cmd, const char *format, ...) {
  va_list ap;
  char *arg;
  if (format) {
    va_start(ap, format);
    vasprintf(&arg, format, ap);
    va_end(ap);
    vlogd(0, cmd, arg);
    free(arg);
  } else
    vlogd(0, cmd, NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<logd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L14
  mov    %rsi,%rbx
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbx,%rsi
  call   <vasprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <vlogd@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    $0x0,%edx
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <vlogd@plt>
  jmp    L25
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void logd(const char *cmd, const char *format, ...) {
  va_list ap;
  char *arg;
  if (format) {
    va_start(ap, format);
    vasprintf(&arg, format, ap);
    va_end(ap);
    vlogd(0, cmd, arg);
    free(arg);
  } else
    vlogd(0, cmd, NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<logd>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L4
  xor    %r13d,%r13d
  mov    %rsi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  call   <vasprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rdx
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <vlogd@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rdi,%rsi
  xor    %edx,%edx
  xor    %edi,%edi
  call   <vlogd@plt>
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void logd(const char *cmd, const char *format, ...) {
  va_list ap;
  char *arg;
  if (format) {
    va_start(ap, format);
    vasprintf(&arg, format, ap);
    va_end(ap);
    vlogd(0, cmd, arg);
    free(arg);
  } else
    vlogd(0, cmd, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<logd>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L25
  xor    %r13d,%r13d
  mov    %rsi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rsp,%rdi
  call   <vasprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    (%rsp),%rdx
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <vlogd@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rdi,%rsi
  xor    %edx,%edx
  xor    %edi,%edi
  call   <vlogd@plt>
  jmp    L21
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void logd(const char *cmd, const char *format, ...) {
  va_list ap;
  char *arg;
  if (format) {
    va_start(ap, format);
    vasprintf(&arg, format, ap);
    va_end(ap);
    vlogd(0, cmd, arg);
    free(arg);
  } else
    vlogd(0, cmd, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmpstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <zstrlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <zstrlen@plt>
  cmp    %rax,%rbx
  je     L78
  mov    $0x0,%eax
  jmp    L43
L78:
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L85:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L25
  addq   $0x1,-0x18(%rbp)
  jmp    L81
L25:
  mov    $0x0,%eax
  jmp    L43
L81:
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <zstrlen@plt>
  cmp    %rax,%rbx
  jb     L85
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <zstrlen@plt>
  cmp    %rax,-0x18(%rbp)
  jne    L43
  mov    $0x1,%eax
  jmp    L43
L43:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int cmpstr(const char *a, const char *b) {
  unsigned long testcmp = 0;
  if (zstrlen(a) != zstrlen(b)) {
    return 0;
  } else {
    for (int i = 0; i < zstrlen(a); i++) {
      if (a[i] == b[i]) {
        testcmp = (testcmp + 1);
      } else {
        return 0;
      }
    }
  }
  if (testcmp == zstrlen(a)) {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<cmpstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <zstrlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <zstrlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rbx
  jne    L24
  mov    $0x0,%ebx
  jmp    L47
L27:
  add    $0x1,%rbx
L47:
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  cmp    %rbx,%rax
  jbe    L16
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L27
  mov    $0x0,%eax
  jmp    L24
L16:
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %rbx,%rdx
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpstr(const char *a, const char *b) {
  unsigned long testcmp = 0;
  if (zstrlen(a) != zstrlen(b)) {
    return 0;
  } else {
    for (int i = 0; i < zstrlen(a); i++) {
      if (a[i] == b[i]) {
        testcmp = (testcmp + 1);
      } else {
        return 0;
      }
    }
  }
  if (testcmp == zstrlen(a)) {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<cmpstr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <zstrlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <zstrlen@plt>
  cmp    %rax,%rbx
  jne    L7
  xor    %ebx,%ebx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L7
  add    $0x1,%rbx
L35:
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  cmp    %rbx,%rax
  ja     L20
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpstr(const char *a, const char *b) {
  unsigned long testcmp = 0;
  if (zstrlen(a) != zstrlen(b)) {
    return 0;
  } else {
    for (int i = 0; i < zstrlen(a); i++) {
      if (a[i] == b[i]) {
        testcmp = (testcmp + 1);
      } else {
        return 0;
      }
    }
  }
  if (testcmp == zstrlen(a)) {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpstr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <zstrlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <zstrlen@plt>
  cmp    %rax,%rbx
  jne    L12
  xor    %ebx,%ebx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  jne    L12
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  cmp    %rbx,%rax
  ja     L4
  mov    %rbp,%rdi
  call   <zstrlen@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpstr(const char *a, const char *b) {
  unsigned long testcmp = 0;
  if (zstrlen(a) != zstrlen(b)) {
    return 0;
  } else {
    for (int i = 0; i < zstrlen(a); i++) {
      if (a[i] == b[i]) {
        testcmp = (testcmp + 1);
      } else {
        return 0;
      }
    }
  }
  if (testcmp == zstrlen(a)) {
    return 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void g1() {
#define X 1
  int resync_parser_3;
}
```
user: What is the c source code of the assembly code below?

```asm
<g1>:
  endbr64
  ret
```

assistant: ```c
void g1() {
#define X 1
  int resync_parser_3;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g1>:
  endbr64
  ret
```

assistant: ```c
void g1() {
#define X 1
  int resync_parser_3;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<g1>:
  endbr64
  ret
```

assistant: ```c
void g1() {
#define X 1
  int resync_parser_3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<use_buf_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void use_buf_malloc(int *buf, int len) {
  for (int i = 0; i < len; i++)
    buf[i] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<use_buf_malloc>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L15:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L15
L18:
  ret
```

assistant: ```c
void use_buf_malloc(int *buf, int len) {
  for (int i = 0; i < len; i++)
    buf[i] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<use_buf_malloc>:
  endbr64
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void use_buf_malloc(int *buf, int len) {
  for (int i = 0; i < len; i++)
    buf[i] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<use_buf_malloc>:
  endbr64
  test   %esi,%esi
  jle    L4
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void use_buf_malloc(int *buf, int len) {
  for (int i = 0; i < len; i++)
    buf[i] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x54(%rbp)
  je     L21
  cmpl   $0x2,-0x54(%rbp)
  je     L24
  jmp    L50
L21:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L46
L24:
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x50(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L50
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L50:
  mov    $0x0,%eax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D38
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string

tool: D2: Minecraft Package Manager C Remake

tool: D38: Not enough args.

tool: D12: install

tool: D28: Install!

assistant: ```c
int main(int argc, char *argv[]) {
  char arg2[64];
  puts("Minecraft Package Manager C Remake");
  switch (argc) {
  case 1:
    puts("Not enough args.");
    return 1;
  case 2:
    strcpy(arg2, argv[1]);
    if (strcmp(arg2, "install") == 0) {
      puts("Install!");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  je     L67
  cmp    $0x2,%ebx
  je     L47
  mov    $0x0,%ebx
L12:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  mov    %ebx,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L12
L47:
  mov    0x8(%rbp),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L52
  mov    $0x0,%ebx
  jmp    L12
L52:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L12
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D38
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D38: Minecraft Package Manager C Remake

tool: D11: Not enough args.

tool: D21: install

tool: D12: Install!

assistant: ```c
int main(int argc, char *argv[]) {
  char arg2[64];
  puts("Minecraft Package Manager C Remake");
  switch (argc) {
  case 1:
    puts("Not enough args.");
    return 1;
  case 2:
    strcpy(arg2, argv[1]);
    if (strcmp(arg2, "install") == 0) {
      puts("Install!");
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %edi,%ebx
  lea    D28(%rip),%rdi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  cmp    $0x1,%ebx
  je     L22
  cmp    $0x2,%ebx
  jne    L47
  mov    0x8(%r12),%rsi
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D34(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L46
L47:
  xor    %r12d,%r12d
L23:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L22:
  lea    D36(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L23
L46:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D28: Minecraft Package Manager C Remake

tool: D34: install

tool: D36: Not enough args.

tool: D20: Install!

assistant: ```c
int main(int argc, char *argv[]) {
  char arg2[64];
  puts("Minecraft Package Manager C Remake");
  switch (argc) {
  case 1:
    puts("Not enough args.");
    return 1;
  case 2:
    strcpy(arg2, argv[1]);
    if (strcmp(arg2, "install") == 0) {
      puts("Install!");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %edi,%ebx
  lea    D26(%rip),%rdi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  cmp    $0x1,%ebx
  je     L56
  cmp    $0x2,%ebx
  jne    L52
  mov    0x8(%r12),%rsi
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D38(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L31
L52:
  xor    %r12d,%r12d
L57:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L56:
  lea    D9(%rip),%rdi
  mov    $0x1,%r12d
  call   <puts@plt>
  jmp    L57
L31:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L57
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D38
type: string
name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D33
type: string

tool: D26: Minecraft Package Manager C Remake

tool: D38: install

tool: D9: Not enough args.

tool: D33: Install!

assistant: ```c
int main(int argc, char *argv[]) {
  char arg2[64];
  puts("Minecraft Package Manager C Remake");
  switch (argc) {
  case 1:
    puts("Not enough args.");
    return 1;
  case 2:
    strcpy(arg2, argv[1]);
    if (strcmp(arg2, "install") == 0) {
      puts("Install!");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gen_53>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_53@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_53(void) {
  handle_53(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_53>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_53@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_53(void) {
  handle_53(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_53>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_53@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_53(void) {
  handle_53(0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_53>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_53@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_53(void) {
  handle_53(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ZN5small3PrvEPPiS0_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned int *_ZN5small3PrvEPPiS0_(struct l_class_OC_small *llvm_cbe_this, unsigned int **llvm_cbe_i, unsigned int *llvm_cbe_q) {
  unsigned int *llvm_cbe_retval;
  struct l_class_OC_small *llvm_cbe_this_2e_addr;
  unsigned int **llvm_cbe_i_2e_addr;
  unsigned int *llvm_cbe_q_2e_addr;
  struct l_class_OC_small *llvm_cbe_this1;
  unsigned int *llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp2;
  unsigned int *llvm_cbe_tmp3;
  unsigned int *llvm_cbe_tmp__64;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_i_2e_addr) = llvm_cbe_i;
  *(&llvm_cbe_q_2e_addr) = llvm_cbe_q;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_q_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe_i_2e_addr);
  *llvm_cbe_tmp2 = llvm_cbe_tmp;
  llvm_cbe_tmp3 = *(&llvm_cbe_q_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp3;
  llvm_cbe_tmp__64 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__64;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ZN5small3PrvEPPiS0_>:
  endbr64
  mov    %rdx,%rax
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
unsigned int *_ZN5small3PrvEPPiS0_(struct l_class_OC_small *llvm_cbe_this, unsigned int **llvm_cbe_i, unsigned int *llvm_cbe_q) {
  unsigned int *llvm_cbe_retval;
  struct l_class_OC_small *llvm_cbe_this_2e_addr;
  unsigned int **llvm_cbe_i_2e_addr;
  unsigned int *llvm_cbe_q_2e_addr;
  struct l_class_OC_small *llvm_cbe_this1;
  unsigned int *llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp2;
  unsigned int *llvm_cbe_tmp3;
  unsigned int *llvm_cbe_tmp__64;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_i_2e_addr) = llvm_cbe_i;
  *(&llvm_cbe_q_2e_addr) = llvm_cbe_q;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_q_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe_i_2e_addr);
  *llvm_cbe_tmp2 = llvm_cbe_tmp;
  llvm_cbe_tmp3 = *(&llvm_cbe_q_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp3;
  llvm_cbe_tmp__64 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__64;
}
```
user: What is the c source code of the assembly code below:

```asm
<_ZN5small3PrvEPPiS0_>:
  endbr64
  mov    %rdx,(%rsi)
  mov    %rdx,%rax
  ret
```

assistant: ```c
unsigned int *_ZN5small3PrvEPPiS0_(struct l_class_OC_small *llvm_cbe_this, unsigned int **llvm_cbe_i, unsigned int *llvm_cbe_q) {
  unsigned int *llvm_cbe_retval;
  struct l_class_OC_small *llvm_cbe_this_2e_addr;
  unsigned int **llvm_cbe_i_2e_addr;
  unsigned int *llvm_cbe_q_2e_addr;
  struct l_class_OC_small *llvm_cbe_this1;
  unsigned int *llvm_cbe_tmp;
  unsigned int **llvm_cbe_tmp2;
  unsigned int *llvm_cbe_tmp3;
  unsigned int *llvm_cbe_tmp__64;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_i_2e_addr) = llvm_cbe_i;
  *(&llvm_cbe_q_2e_addr) = llvm_cbe_q;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp = *(&llvm_cbe_q_2e_addr);
  llvm_cbe_tmp2 = *(&llvm_cbe_i_2e_addr);
  *llvm_cbe_tmp2 = llvm_cbe_tmp;
  llvm_cbe_tmp3 = *(&llvm_cbe_q_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp3;
  llvm_cbe_tmp__64 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__64;
}
```