ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  jmp    L68
L48:
  mov    -0x94(%rbp),%eax
  mov    %eax,%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    %dl,-0x90(%rbp,%rax,1)
  addl   $0x1,-0x94(%rbp)
L68:
  cmpl   $0x7f,-0x94(%rbp)
  jle    L48
  movl   $0x0,-0x94(%rbp)
  jmp    L26
L51:
  mov    -0x94(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  lea    0x1(%rax),%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    %dl,-0x90(%rbp,%rax,1)
  addl   $0x1,-0x94(%rbp)
L26:
  cmpl   $0x7f,-0x94(%rbp)
  jle    L51
  movl   $0x0,-0x94(%rbp)
  jmp    L34
L72:
  mov    -0x94(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    -0x94(%rbp),%edx
  add    $0x1,%edx
  cmp    %edx,%eax
  je     L38
  mov    $0x0,%eax
  call   <abort@plt>
L38:
  addl   $0x1,-0x94(%rbp)
L34:
  cmpl   $0x7f,-0x94(%rbp)
  jle    L72
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[128] __attribute__((__aligned__(16)));
    unsigned char b[128] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 128; i++) {
    s.b[i] = i;
  }
  for (i = 0; i < 128; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 128; i++) {
    if (s.a[i] != i + 1)
      abort();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
L63:
  mov    %al,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x80,%rax
  jne    L63
  mov    %rsp,%rax
  lea    0x80(%rsp),%rdx
L64:
  addb   $0x1,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L64
  mov    $0x1,%ebx
  lea    -0x1(%rsp),%rbp
  jmp    L14
L7:
  add    $0x1,%rbx
  cmp    $0x81,%rbx
  je     L23
L14:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%eax
  je     L7
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L7
L23:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[128] __attribute__((__aligned__(16)));
    unsigned char b[128] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 128; i++) {
    s.b[i] = i;
  }
  for (i = 0; i < 128; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 128; i++) {
    if (s.a[i] != i + 1)
      abort();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main1>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  nopl   (%rax)
L13:
  mov    %dl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x80,%rdx
  jne    L13
  lea    0x80(%rsp),%rdx
L21:
  addb   $0x1,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
  mov    $0x1,%ebx
  lea    -0x1(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L34:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%eax
  je     L31
  xor    %eax,%eax
  call   <abort@plt>
L31:
  add    $0x1,%rbx
  cmp    $0x81,%rbx
  jne    L34
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[128] __attribute__((__aligned__(16)));
    unsigned char b[128] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 128; i++) {
    s.b[i] = i;
  }
  for (i = 0; i < 128; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 128; i++) {
    if (s.a[i] != i + 1)
      abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main1>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x98,%rsp
  movdqa D31(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movdqa D43(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D54(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D76(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D50(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D46(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D41(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  nopl   0x0(%rax)
L22:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %ebx,%eax
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  add    $0x1,%rbx
  cmp    $0x81,%rbx
  jne    L22
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D31
data_type: byte[16]
name: parse_data
arguments: data_label: D43
data_type: byte[16]
name: parse_data
arguments: data_label: D54
data_type: byte[16]
name: parse_data
arguments: data_label: D76
data_type: byte[16]
name: parse_data
arguments: data_label: D50
data_type: byte[16]
name: parse_data
arguments: data_label: D46
data_type: byte[16]
name: parse_data
arguments: data_label: D41
data_type: byte[16]
name: parse_data
arguments: data_label: D2
data_type: byte[16]

tool: {"D31": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D43": [0x11,0x12,0x13,0x14,0x15,0x16,0x17,0x18,0x19,0x1a,0x1b,0x1c,0x1d,0x1e,0x1f,0x20]}

tool: {"D54": [0x21,0x22,0x23,0x24,0x25,0x26,0x27,0x28,0x29,0x2a,0x2b,0x2c,0x2d,0x2e,0x2f,0x30]}

tool: {"D76": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x3a,0x3b,0x3c,0x3d,0x3e,0x3f,0x40]}

tool: {"D50": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D46": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x5b,0x5c,0x5d,0x5e,0x5f,0x60]}

tool: {"D41": [0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70]}

tool: {"D2": [0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x7b,0x7c,0x7d,0x7e,0x7f,0x80]}

assistant: ```c
__attribute__((no)) int main1() {
  union {
    unsigned char a[128] __attribute__((__aligned__(16)));
    unsigned char b[128] __attribute__((__aligned__(16)));
  } s;
  int i;
  for (i = 0; i < 128; i++) {
    s.b[i] = i;
  }
  for (i = 0; i < 128; i++) {
    s.a[i] = s.b[i] + 1;
  }
  for (i = 0; i < 128; i++) {
    if (s.a[i] != i + 1)
      abort();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<floating_point_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L3
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L14
L3:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L14:
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x2a,%eax
  pop    %rbp
  ret
```

assistant: ```c
int floating_point_3(unsigned long long a) {
  double b = a;
  return 42;
}
```
user: What is the c source code of the assembly code below?

```asm
<floating_point_3>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int floating_point_3(unsigned long long a) {
  double b = a;
  return 42;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<floating_point_3>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int floating_point_3(unsigned long long a) {
  double b = a;
  return 42;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floating_point_3>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int floating_point_3(unsigned long long a) {
  double b = a;
  return 42;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<algo_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L52:
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L7:
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L20:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  imul   -0x38(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rsi
  mov    -0xc(%rbp),%eax
  imul   -0x38(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L20
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L7
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L52
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *algo_mul(int *row, int *col, int num_row, int num_col, int matrix_size) {
  int i, j, k;
  int *fract_matrix;
  fract_matrix = calloc(num_col * num_row, sizeof(int));
  for (k = 0; k < num_row; k++) {
    for (j = 0; j < num_col; j++) {
      for (i = 0; i < matrix_size; i++) {
        *(fract_matrix + j + k * num_col) += row[i + k * matrix_size] * col[i + j * matrix_size];
      }
    }
  }
  return fract_matrix;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<algo_mul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %edx,%r14d
  mov    %edx,0x4(%rsp)
  mov    %ecx,%r12d
  mov    %r8d,%ebx
  mov    %edx,%edi
  imul   %ecx,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r15
  test   %r14d,%r14d
  jle    L62
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r11d
  lea    -0x1(%r12),%eax
  mov    %rax,0x10(%rsp)
  lea    0x4(%r15),%rax
  mov    %rax,0x18(%rsp)
  mov    %ebx,%r8d
  jmp    L67
L5:
  movslq %r9d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    $0x0,%eax
L82:
  mov    (%rdi,%rax,4),%edx
  imul   (%rsi,%rax,4),%edx
  add    %edx,(%rcx)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L82
L56:
  add    $0x4,%rcx
  add    %ebx,%r9d
  cmp    %r10,%rcx
  je     L35
L50:
  test   %ebx,%ebx
  jg     L5
  jmp    L56
L35:
  add    $0x1,%r11d
  add    %r12d,%r13d
  add    %ebx,%r14d
  cmp    %r11d,0x4(%rsp)
  je     L62
L67:
  test   %r12d,%r12d
  jle    L35
  movslq %r13d,%rax
  lea    (%r15,%rax,4),%rcx
  add    0x10(%rsp),%rax
  mov    0x18(%rsp),%rsi
  lea    (%rsi,%rax,4),%r10
  movslq %r14d,%rax
  mov    0x8(%rsp),%rsi
  lea    (%rsi,%rax,4),%rdi
  mov    $0x0,%r9d
  jmp    L50
L62:
  mov    %r15,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *algo_mul(int *row, int *col, int num_row, int num_col, int matrix_size) {
  int i, j, k;
  int *fract_matrix;
  fract_matrix = calloc(num_col * num_row, sizeof(int));
  for (k = 0; k < num_row; k++) {
    for (j = 0; j < num_col; j++) {
      for (i = 0; i < matrix_size; i++) {
        *(fract_matrix + j + k * num_col) += row[i + k * matrix_size] * col[i + j * matrix_size];
      }
    }
  }
  return fract_matrix;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<algo_mul>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,%edi
  imul   %ecx,%edi
  mov    %edx,0x14(%rsp)
  call   <calloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r14d,%r14d
  jle    L4
  lea    -0x1(%r12),%edi
  add    $0x4,%rax
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  mov    %rdi,0x20(%rsp)
  xor    %r13d,%r13d
  lea    -0x1(%rbp),%r9d
  mov    %rax,0x28(%rsp)
  nopl   0x0(%rax)
L39:
  test   %r12d,%r12d
  jle    L58
  mov    0x8(%rsp),%rdi
  movslq %r14d,%rax
  xor    %r10d,%r10d
  lea    (%rdi,%rax,4),%rsi
  mov    0x28(%rsp),%rdi
  add    0x20(%rsp),%rax
  lea    (%rdi,%rax,4),%r11
  mov    0x18(%rsp),%rdi
  movslq %r15d,%rax
  lea    (%rdi,%rax,4),%r8
  cs nopw 0x0(%rax,%rax,1)
L51:
  test   %ebp,%ebp
  jle    L17
  movslq %r10d,%rax
  mov    (%rsi),%ecx
  lea    (%rbx,%rax,4),%rdi
  xor    %eax,%eax
  nop
L52:
  mov    (%r8,%rax,4),%edx
  imul   (%rdi,%rax,4),%edx
  add    %edx,%ecx
  mov    %rax,%rdx
  add    $0x1,%rax
  mov    %ecx,(%rsi)
  cmp    %r9,%rdx
  jne    L52
L17:
  add    $0x4,%rsi
  add    %ebp,%r10d
  cmp    %r11,%rsi
  jne    L51
L58:
  add    $0x1,%r13d
  add    %r12d,%r14d
  add    %ebp,%r15d
  cmp    %r13d,0x14(%rsp)
  jne    L39
L4:
  mov    0x8(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *algo_mul(int *row, int *col, int num_row, int num_col, int matrix_size) {
  int i, j, k;
  int *fract_matrix;
  fract_matrix = calloc(num_col * num_row, sizeof(int));
  for (k = 0; k < num_row; k++) {
    for (j = 0; j < num_col; j++) {
      for (i = 0; i < matrix_size; i++) {
        *(fract_matrix + j + k * num_col) += row[i + k * matrix_size] * col[i + j * matrix_size];
      }
    }
  }
  return fract_matrix;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<algo_mul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,%edi
  imul   %ecx,%edi
  mov    %rsi,0x10(%rsp)
  mov    $0x4,%esi
  mov    %edx,0x1c(%rsp)
  call   <calloc@plt>
  mov    %rax,%r15
  test   %ebx,%ebx
  jle    L9
  test   %ebp,%ebp
  jle    L9
  test   %r12d,%r12d
  jle    L9
  lea    0x4(%rax),%rax
  movslq %r12d,%r9
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  mov    %rax,0x28(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x0(,%r9,4),%r11
  xor    %ebx,%ebx
  mov    %rax,0x20(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    0x28(%rsp),%rcx
  movslq %r13d,%rax
  mov    0x10(%rsp),%rdi
  lea    (%r15,%rax,4),%rsi
  add    0x20(%rsp),%rax
  lea    (%rcx,%rax,4),%r10
  mov    0x8(%rsp),%rcx
  movslq %r14d,%rax
  lea    (%rcx,%rax,4),%r8
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rsi),%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  mov    (%r8,%rax,4),%edx
  imul   (%rdi,%rax,4),%edx
  add    $0x1,%rax
  add    %edx,%ecx
  mov    %ecx,(%rsi)
  cmp    %r9,%rax
  jne    L7
  add    $0x4,%rsi
  add    %r11,%rdi
  cmp    %rsi,%r10
  jne    L18
  add    $0x1,%ebx
  add    %ebp,%r13d
  add    %r12d,%r14d
  cmp    %ebx,0x1c(%rsp)
  jne    L8
L9:
  add    $0x38,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *algo_mul(int *row, int *col, int num_row, int num_col, int matrix_size) {
  int i, j, k;
  int *fract_matrix;
  fract_matrix = calloc(num_col * num_row, sizeof(int));
  for (k = 0; k < num_row; k++) {
    for (j = 0; j < num_col; j++) {
      for (i = 0; i < matrix_size; i++) {
        *(fract_matrix + j + k * num_col) += row[i + k * matrix_size] * col[i + j * matrix_size];
      }
    }
  }
  return fract_matrix;
}
```
user: What is the c source code of the assembly code below?

```asm
<buildTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movb   $0x41,-0x5(%rbp)
  jmp    L20
L24:
  movsbl -0x5(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L21:
  movzbl -0x5(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
L20:
  cmpb   $0x5a,-0x5(%rbp)
  jle    L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void buildTable(char str[], char table[]) {
  int p;
  char ch;
  strcpy(table, str);
  for (p = strlen(str), ch = 'A'; ch <= 'Z'; ch++)
    if (strchr(str, ch) == 0)
      table[p++] = ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildTable>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdi,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x41,%ebx
  jmp    L13
L34:
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  je     L39
L13:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L34
  movslq %ebp,%rax
  mov    %bl,0x0(%r13,%rax,1)
  lea    0x1(%rbp),%ebp
  jmp    L34
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void buildTable(char str[], char table[]) {
  int p;
  char ch;
  strcpy(table, str);
  for (p = strlen(str), ch = 'A'; ch <= 'Z'; ch++)
    if (strchr(str, ch) == 0)
      table[p++] = ch;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<buildTable>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  xchg   %ax,%ax
L17:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L12
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %bl,0x0(%r13,%rax,1)
L12:
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void buildTable(char str[], char table[]) {
  int p;
  char ch;
  strcpy(table, str);
  for (p = strlen(str), ch = 'A'; ch <= 'Z'; ch++)
    if (strchr(str, ch) == 0)
      table[p++] = ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buildTable>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  mov    $0x41,%ebx
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  xchg   %ax,%ax
L12:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %bl,0x0(%r13,%rax,1)
L10:
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void buildTable(char str[], char table[]) {
  int p;
  char ch;
  strcpy(table, str);
  for (p = strlen(str), ch = 'A'; ch <= 'Z'; ch++)
    if (strchr(str, ch) == 0)
      table[p++] = ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<file_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L1
L5:
  mov    $0x0,%eax
  jmp    L10
L1:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L10:
  leave
  ret
```

assistant: ```c
char *file_extension(const char *filename) {
  char *dot_tail = strrchr(filename, '.');
  if ((!dot_tail) || (dot_tail == filename))
    return NULL;
  return dot_tail + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L15
  cmp    %rax,%rbx
  je     L15
  add    $0x1,%rax
L27:
  pop    %rbx
  ret
L15:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
char *file_extension(const char *filename) {
  char *dot_tail = strrchr(filename, '.');
  if ((!dot_tail) || (dot_tail == filename))
    return NULL;
  return dot_tail + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  cmp    %rax,%rbx
  je     L4
  add    $0x1,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *file_extension(const char *filename) {
  char *dot_tail = strrchr(filename, '.');
  if ((!dot_tail) || (dot_tail == filename))
    return NULL;
  return dot_tail + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<file_extension>:
  endbr64
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L15
  cmp    %rax,%rbx
  je     L15
  add    $0x1,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *file_extension(const char *filename) {
  char *dot_tail = strrchr(filename, '.');
  if ((!dot_tail) || (dot_tail == filename))
    return NULL;
  return dot_tail + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<create_pidfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D19: w

tool: D9: %ld


assistant: ```c
void create_pidfile(const char *pidfile) {
  FILE *fp = fopen(pidfile, "w");
  if (fp) {
    fprintf(fp, "%ld\n", (long)getpid());
    fclose(fp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_pidfile>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rax,%rdx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L4:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D8: w

tool: D0: %ld


assistant: ```c
void create_pidfile(const char *pidfile) {
  FILE *fp = fopen(pidfile, "w");
  if (fp) {
    fprintf(fp, "%ld\n", (long)getpid());
    fclose(fp);
  }
}
```