user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  lea    0x0(,%rax,4),%rdx
  mov    %rax,%rcx
  imul   %rax,%rax
  mov    %rdx,-0x78(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L228
L141:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L141
L228:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L225
L172:
  mov    %rsp,-0x68(%rbp)
  test   %ecx,%ecx
  jle    L40
  mov    -0x78(%rbp),%rax
  movl   $0x0,-0x48(%rbp)
  xor    %r14d,%r14d
  lea    D13(%rip),%r12
  shr    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  xchg   %ax,%ax
L175:
  mov    -0x68(%rbp),%rax
  xor    %r15d,%r15d
  lea    (%rax,%r14,4),%r13
  nopl   0x0(%rax,%rax,1)
L89:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %r15d,%eax
  jg     L89
  addl   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%ecx
  add    -0x50(%rbp),%r14
  cmp    %ecx,%eax
  jg     L175
  test   %eax,%eax
  jle    L40
  mov    -0x50(%rbp),%rdx
  mov    -0x68(%rbp),%rcx
  movq   $0x0,-0x48(%rbp)
  neg    %rdx
  mov    %rcx,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  nopl   (%rax)
L219:
  mov    -0x48(%rbp),%rdx
  mov    -0x60(%rbp),%r14
  test   %edx,%edx
  movslq %edx,%rsi
  setne  %r12b
  mov    %rsi,%r13
  xor    %r15d,%r15d
  imul   -0x50(%rbp),%rsi
  mov    %rsi,-0x70(%rbp)
  jmp    L176
  nopw   0x0(%rax,%rax,1)
L81:
  cmp    %r15d,%eax
  je     L2
  mov    -0x58(%rbp),%rax
  cmp    %esi,(%r14,%rax,4)
  jge    L9
  mov    -0x50(%rbp),%rax
  cmp    %esi,(%r14,%rax,4)
  jge    L9
  cmp    %esi,-0x4(%r14)
  jge    L9
  add    $0x1,%r15d
  mov    -0x68(%rbp),%rcx
  movslq %r15d,%rax
  add    -0x70(%rbp),%rax
  cmp    %esi,(%rcx,%rax,4)
  jl     L36
  nopl   0x0(%rax,%rax,1)
L60:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L6:
  mov    -0x3c(%rbp),%eax
  add    $0x4,%r14
  cmp    %r15d,%eax
  jle    L77
L176:
  mov    (%r14),%esi
  test   %r15d,%r15d
  je     L2
  test   %r12b,%r12b
  je     L2
  sub    $0x1,%eax
  cmp    %r13d,%eax
  jne    L81
L2:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  add    $0x4,%r14
  call   <printf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %r15d,%eax
  jg     L176
L77:
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0x1,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    -0x48(%rbp),%rdx
  mov    -0x78(%rbp),%rdi
  add    %rdi,-0x60(%rbp)
  cmp    %edx,%eax
  jg     L219
L40:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%r15d
  jmp    L60
  nopl   0x0(%rax)
L36:
  mov    $0x58,%edi
  call   <putchar@plt>
  jmp    L6
L225:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L172
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string

tool: D3: %d

tool: D13: %1d

assistant: ```c
int main() {
  int i = 0, j, k, n;
  long int x;
  scanf("%d", &n);
  int a[n][n];
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      scanf("%1d", &a[i][j]);
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (i != 0 && j != 0 && i != n - 1 && j != n - 1) {
        if (a[i][j] > a[i - 1][j] && a[i][j] > a[i + 1][j] && a[i][j] > a[i][j - 1] && a[i][j] > a[i][j + 1]) {
          printf("X");
        } else {
          printf("%d", a[i][j]);
        }
      } else {
        printf("%d", a[i][j]);
      }
    }
    printf("\n");
  }
  return 0;
}
```