ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<rwx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  and    $0x100,%eax
  test   %eax,%eax
  je     L38
  mov    $0x72,%edx
  jmp    L17
L38:
  mov    $0x2d,%edx
L17:
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  movzwl -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L4
  mov    $0x77,%edx
  jmp    L36
L4:
  mov    $0x2d,%edx
L36:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  movzwl -0x4(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L15
  mov    $0x78,%edx
  jmp    L6
L15:
  mov    $0x2d,%edx
L6:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rwx(unsigned short bits, char *chars) {
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  mov    %al,0x1(%rsi)
  and    $0x40,%edi
  cmp    $0x1,%di
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(unsigned short bits, char *chars) {
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0x40,%edi
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  cmp    $0x1,%di
  mov    %al,0x1(%rsi)
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(unsigned short bits, char *chars) {
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: What is the c source code of the assembly code below?

```asm
<rwx>:
  endbr64
  mov    %edi,%eax
  and    $0x100,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0xffffffbb,%eax
  add    $0x72,%eax
  mov    %al,(%rsi)
  mov    %edi,%eax
  and    $0x80,%ax
  cmp    $0x1,%ax
  sbb    %eax,%eax
  and    $0x40,%edi
  and    $0xffffffb6,%eax
  add    $0x77,%eax
  cmp    $0x1,%di
  mov    %al,0x1(%rsi)
  sbb    %eax,%eax
  and    $0xffffffb5,%eax
  add    $0x78,%eax
  mov    %al,0x2(%rsi)
  ret
```

assistant: ```c
void rwx(unsigned short bits, char *chars) {
  chars[0] = (bits & 00400) ? 'r' : '-';
  chars[1] = (bits & 00200) ? 'w' : '-';
  chars[2] = (bits & 00100) ? 'x' : '-';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L36
  mov    $0x0,%eax
  jmp    L37
L36:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L53
  mov    $0x1,%eax
  jmp    L37
L53:
  cmpl   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x1,%eax
  jmp    L37
L26:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <find>
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x8(%rbp),%eax
L37:
  leave
  ret
```

assistant: ```c
int find(int k, int i) {
  int sum, j;
  if (i > k)
    return 0;
  else if (i == k)
    return 1;
  else if (i == 0)
    return 1;
  else {
    sum = 0;
    for (j = 0; j < k; j++) {
      sum += find(j, i - 1);
    }
    return sum;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  cmp    %edi,%esi
  jg     L7
  mov    %edi,%ebp
  test   %esi,%esi
  je     L17
  cmp    %edi,%esi
  je     L17
  test   %edi,%edi
  jle    L7
  mov    $0x0,%r13d
  lea    -0x1(%rsi),%ebx
L19:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <find>
  add    %eax,%r12d
  add    $0x1,%r13d
  cmp    %r13d,%ebp
  jne    L19
  jmp    L7
L17:
  mov    $0x1,%r12d
L7:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int find(int k, int i) {
  int sum, j;
  if (i > k)
    return 0;
  else if (i == k)
    return 1;
  else if (i == 0)
    return 1;
  else {
    sum = 0;
    for (j = 0; j < k; j++) {
      sum += find(j, i - 1);
    }
    return sum;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<same_sec3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L14
  mov    -0x28(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <uint4@plt>
  jmp    L1
L14:
  mov    $0x0,%eax
L1:
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L96
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <uint4@plt>
  jmp    L73
L96:
  mov    $0x0,%eax
L73:
  cmp    -0x14(%rbp),%eax
  je     L43
  mov    $0x0,%eax
  jmp    L81
L43:
  mov    -0x28(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L93
L71:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L93
  mov    $0x0,%eax
  jmp    L81
L93:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L71
  mov    $0x1,%eax
L81:
  leave
  ret
```

assistant: ```c
int same_sec3(unsigned char **sec_a, unsigned char **sec_b) {
  unsigned char *a, *b;
  unsigned int i;
  i = (sec_a[3] ? uint4(sec_a[3] + 0) : 0);
  if ((sec_b[3] ? uint4(sec_b[3] + 0) : 0) != i)
    return 0;
  a = sec_a[3];
  b = sec_b[3];
  while (i--) {
    if (*a++ != *b++)
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<same_sec3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    0x18(%rdi),%rdi
  test   %rdi,%rdi
  je     L29
  call   <uint4@plt>
  mov    %eax,%ebx
  mov    0x18(%r12),%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L43
L70:
  call   <uint4@plt>
L43:
  mov    $0x0,%edx
  cmp    %ebx,%eax
  je     L54
L22:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x1,%edx
  jmp    L22
L29:
  mov    0x18(%rsi),%rdi
  mov    $0x0,%ebx
  test   %rdi,%rdi
  jne    L70
L54:
  mov    0x18(%rbp),%rdi
  mov    0x18(%r12),%rsi
  mov    %ebx,%ecx
  mov    $0x0,%eax
L1:
  cmp    %rax,%rcx
  je     L4
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  je     L1
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
int same_sec3(unsigned char **sec_a, unsigned char **sec_b) {
  unsigned char *a, *b;
  unsigned int i;
  i = (sec_a[3] ? uint4(sec_a[3] + 0) : 0);
  if ((sec_b[3] ? uint4(sec_b[3] + 0) : 0) != i)
    return 0;
  a = sec_a[3];
  b = sec_b[3];
  while (i--) {
    if (*a++ != *b++)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<same_sec3>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x18(%rdi),%rdi
  test   %rdi,%rdi
  je     L69
  call   <uint4@plt>
  mov    0x18(%rbp),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L62
L64:
  call   <uint4@plt>
L62:
  cmp    %r12d,%eax
  je     L24
L63:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    0x18(%rbx),%rdi
  mov    0x18(%rbp),%rsi
L60:
  mov    %eax,%eax
  xor    %edx,%edx
  jmp    L44
  xchg   %ax,%ax
L53:
  movzbl (%rdi,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    -0x1(%rsi,%rdx,1),%cl
  jne    L63
L44:
  cmp    %rax,%rdx
  jne    L53
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L69:
  mov    0x18(%rsi),%rdi
  xor    %r12d,%r12d
  test   %rdi,%rdi
  jne    L64
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L60
```

assistant: ```c
int same_sec3(unsigned char **sec_a, unsigned char **sec_b) {
  unsigned char *a, *b;
  unsigned int i;
  i = (sec_a[3] ? uint4(sec_a[3] + 0) : 0);
  if ((sec_b[3] ? uint4(sec_b[3] + 0) : 0) != i)
    return 0;
  a = sec_a[3];
  b = sec_b[3];
  while (i--) {
    if (*a++ != *b++)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<same_sec3>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x18(%rdi),%rdi
  test   %rdi,%rdi
  je     L21
  call   <uint4@plt>
  mov    0x18(%rbp),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L27
L10:
  call   <uint4@plt>
L27:
  cmp    %r12d,%eax
  je     L58
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    0x18(%rbx),%rdi
  mov    0x18(%rbp),%rsi
L5:
  mov    %eax,%eax
  xor    %edx,%edx
  jmp    L73
  xchg   %ax,%ax
L46:
  movzbl (%rdi,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    -0x1(%rsi,%rdx,1),%cl
  jne    L16
L73:
  cmp    %rax,%rdx
  jne    L46
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L21:
  mov    0x18(%rsi),%rdi
  xor    %r12d,%r12d
  test   %rdi,%rdi
  jne    L10
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
int same_sec3(unsigned char **sec_a, unsigned char **sec_b) {
  unsigned char *a, *b;
  unsigned int i;
  i = (sec_a[3] ? uint4(sec_a[3] + 0) : 0);
  if ((sec_b[3] ? uint4(sec_b[3] + 0) : 0) != i)
    return 0;
  a = sec_a[3];
  b = sec_b[3];
  while (i--) {
    if (*a++ != *b++)
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zDecompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <inflateInit@plt>
  mov    %eax,-0x44(%rbp)
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x44(%rbp)
  je     L34
  mov    -0x44(%rbp),%eax
  jmp    L33
L34:
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x70(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inflate@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x70(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x70(%rbp),%rax
  mov    %rdx,(%rax)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <inflateEnd@plt>
  cmpl   $0x0,-0x44(%rbp)
  je     L22
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  jmp    L33
L22:
  mov    $0xffffffff,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int zDecompress(const unsigned char *data, size_t avail_in, unsigned char *odata, size_t *avail_out) {
  int ret;
  z_stream strm;
  strm.zalloc = Z_NULL;
  strm.zfree = Z_NULL;
  strm.opaque = Z_NULL;
  ret = inflateInit(&strm);
  if (ret != Z_OK)
    return ret;
  strm.avail_in = avail_in;
  strm.next_in = data;
  strm.next_out = odata;
  strm.avail_out = *avail_out;
  ret = inflate(&strm, Z_FINISH);
  *avail_out -= strm.avail_out;
  (void)inflateEnd(&strm);
  return ret ? Z_OK : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zDecompress>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x30(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rsp,%rdi
  call   <inflateInit@plt>
  mov    D13(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L7
L23:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %r13,(%rsp)
  mov    %r12,0x8(%rsp)
  mov    %rbp,0x10(%rsp)
  mov    (%rbx),%rax
  mov    %rax,0x18(%rsp)
  mov    %rsp,%r12
  mov    D38(%rip),%rax
  mov    (%rax),%esi
  mov    %r12,%rdi
  call   <inflate@plt>
  mov    %eax,%ebp
  mov    0x18(%rsp),%rax
  sub    %rax,(%rbx)
  mov    %r12,%rdi
  call   <inflateEnd@plt>
  test   %ebp,%ebp
  je     L13
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  jmp    L23
L13:
  mov    $0xffffffff,%eax
  jmp    L23
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zDecompress(const unsigned char *data, size_t avail_in, unsigned char *odata, size_t *avail_out) {
  int ret;
  z_stream strm;
  strm.zalloc = Z_NULL;
  strm.zfree = Z_NULL;
  strm.opaque = Z_NULL;
  ret = inflateInit(&strm);
  if (ret != Z_OK)
    return ret;
  strm.avail_in = avail_in;
  strm.next_in = data;
  strm.next_out = odata;
  strm.avail_out = *avail_out;
  ret = inflate(&strm, Z_FINISH);
  *avail_out -= strm.avail_out;
  (void)inflateEnd(&strm);
  return ret ? Z_OK : -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zDecompress>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  mov    D11(%rip),%rax
  mov    %rsp,%r15
  mov    %r15,%rdi
  mov    (%rax),%rax
  mov    %rax,0x30(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x20(%rsp)
  call   <inflateInit@plt>
  mov    D1(%rip),%r14
  cmp    %eax,(%r14)
  je     L34
L31:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%rbx),%rax
  mov    %r15,%rdi
  mov    %rbp,0x10(%rsp)
  mov    %r13,(%rsp)
  mov    %rax,0x18(%rsp)
  mov    D20(%rip),%rax
  mov    %r12,0x8(%rsp)
  mov    (%rax),%esi
  call   <inflate@plt>
  mov    %r15,%rdi
  mov    %eax,%ebp
  mov    0x18(%rsp),%rax
  sub    %rax,(%rbx)
  call   <inflateEnd@plt>
  test   %ebp,%ebp
  je     L45
  mov    (%r14),%eax
  jmp    L31
L45:
  mov    $0xffffffff,%eax
  jmp    L31
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zDecompress(const unsigned char *data, size_t avail_in, unsigned char *odata, size_t *avail_out) {
  int ret;
  z_stream strm;
  strm.zalloc = Z_NULL;
  strm.zfree = Z_NULL;
  strm.opaque = Z_NULL;
  ret = inflateInit(&strm);
  if (ret != Z_OK)
    return ret;
  strm.avail_in = avail_in;
  strm.next_in = data;
  strm.next_out = odata;
  strm.avail_out = *avail_out;
  ret = inflate(&strm, Z_FINISH);
  *avail_out -= strm.avail_out;
  (void)inflateEnd(&strm);
  return ret ? Z_OK : -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zDecompress>:
  endbr64
  push   %r13
  movq   %rdi,%xmm1
  movq   %rdx,%xmm2
  push   %r12
  punpcklqdq %xmm2,%xmm1
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D22(%rip),%rax
  lea    0x10(%rsp),%r12
  movaps %xmm1,(%rsp)
  mov    %r12,%rdi
  mov    (%rax),%rax
  movq   %rax,%xmm0
  mov    %rax,0x40(%rsp)
  punpcklqdq %xmm0,%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <inflateInit@plt>
  mov    D9(%rip),%r13
  cmp    %eax,0x0(%r13)
  je     L5
L44:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rax
  movdqa (%rsp),%xmm3
  mov    %r12,%rdi
  mov    %rbp,0x10(%rsp)
  mov    %rax,0x28(%rsp)
  mov    D27(%rip),%rax
  movups %xmm3,0x18(%rsp)
  mov    (%rax),%esi
  call   <inflate@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  mov    0x28(%rsp),%rax
  sub    %rax,(%rbx)
  call   <inflateEnd@plt>
  test   %ebp,%ebp
  je     L17
  mov    0x0(%r13),%eax
  jmp    L44
L17:
  mov    $0xffffffff,%eax
  jmp    L44
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zDecompress(const unsigned char *data, size_t avail_in, unsigned char *odata, size_t *avail_out) {
  int ret;
  z_stream strm;
  strm.zalloc = Z_NULL;
  strm.zfree = Z_NULL;
  strm.opaque = Z_NULL;
  ret = inflateInit(&strm);
  if (ret != Z_OK)
    return ret;
  strm.avail_in = avail_in;
  strm.next_in = data;
  strm.next_out = odata;
  strm.avail_out = *avail_out;
  ret = inflate(&strm, Z_FINISH);
  *avail_out -= strm.avail_out;
  (void)inflateEnd(&strm);
  return ret ? Z_OK : -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_int2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rcx
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void copy_int2(char **pointer, int16_t value) {
  value = htons(value);
  memcpy(*pointer, &value, 2);
  *pointer += 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_int2>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  call   <htons@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    (%rbx),%rdi
  call   <memcpy@plt>
  addq   $0x2,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void copy_int2(char **pointer, int16_t value) {
  value = htons(value);
  memcpy(*pointer, &value, 2);
  *pointer += 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_int2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htons@plt>
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x2,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void copy_int2(char **pointer, int16_t value) {
  value = htons(value);
  memcpy(*pointer, &value, 2);
  *pointer += 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_int2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <htons@plt>
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x2,%edx
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x2,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void copy_int2(char **pointer, int16_t value) {
  value = htons(value);
  memcpy(*pointer, &value, 2);
  *pointer += 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<oct2dec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r15
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  lea    D19(%rip),%r13
  jmp    L29
L163:
  cmp    $0x72,%eax
  mov    $0x1,%eax
  cmove  %eax,%ebx
L29:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <getopt@plt>
  cmp    $0xffffffff,%eax
  je     L148
  cmp    $0x68,%eax
  jne    L163
  mov    $0x1,%r14d
  jmp    L29
L148:
  test   %r14d,%r14d
  jne    L100
  test   %ebx,%ebx
  je     L161
  cmp    $0x2,%r12d
  jle    L117
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L117:
  mov    %r15,%rdi
  call   <noArgument@plt>
  cmp    $0x2,%r12d
  jne    L110
L72:
  mov    $0x1,%r13d
  lea    D43(%rip),%r14
  jmp    L160
L161:
  cmp    $0x1,%r12d
  jle    L52
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L72
L52:
  mov    %r15,%rdi
  call   <noArgument@plt>
L110:
  lea    D27(%rip),%rdi
  call   <printf@plt>
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  mov    0x0(%rbp,%r13,8),%rdi
  mov    $0xa,%edx
  mov    $0x8,%esi
  call   <convertBase@plt>
L152:
  add    $0x1,%r13
  cmp    %r13d,%r12d
  jle    L110
L160:
  test   %ebx,%ebx
  je     L98
  mov    0x0(%rbp,%r13,8),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L152
  mov    0x0(%rbp,%r13,8),%rdi
  mov    $0x8,%edx
  mov    $0xa,%esi
  call   <convertBase@plt>
  jmp    L152
L100:
  mov    %r15,%rdi
  call   <showUsage@plt>
  jmp    L47
```

tool_calls: name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D31
datatype: string
name: parse_data
arguments: label: D27
datatype: string

tool: D19: rh

tool: D0: OCT: 

tool: D43: -r

tool: D31: DEC: 

tool: D27: 


assistant: ```c
void oct2dec(int argc, char **argv, char *applet) {
  int opt = 0;
  bool reverse = false;
  bool pr_help = false;
  while ((opt = getopt(argc, argv, "rh")) != -1) {
    switch (opt) {
    case 'r':
      reverse = true;
      break;
    case 'h':
      pr_help = true;
      break;
    }
  }
  if (!pr_help) {
    if (reverse) {
      if (argc > 2) {
        printf("OCT: ");
      } else {
        noArgument(applet);
      }
    } else {
      if (argc > 1) {
        printf("DEC: ");
      } else {
        noArgument(applet);
      }
    }
    for (int i = 1; i < argc; i++) {
      if (reverse) {
        if (strcmp(argv[i], "-r") == 0) {
          continue;
        }
        convertBase(argv[i], 10, 8);
      } else {
        convertBase(argv[i], 8, 10);
      }
    }
    printf("\n");
  } else {
    showUsage(applet);
  }
}
```