user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L4
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %r13d,%ebx
  jle    L94
  nopl   (%rax)
L62:
  mov    $0x20,%edi
  sub    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r13d,%ebx
  jne    L62
L94:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L106:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %r13d,%ebx
  jle    L106
  sub    $0x1,%ebp
  sub    %r13d,%ebx
  cmp    $0x1,%r13d
  je     L65
  nopw   0x0(%rax,%rax,1)
L101:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%eax
  sub    $0x1,%ebp
  cmp    %ebx,%eax
  jne    L101
L65:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r13d,%ebx
  jge    L36
  test   %ebx,%ebx
  jle    L4
  mov    $0x1,%r14d
  nopw   0x0(%rax,%rax,1)
L76:
  lea    -0x1(%r14),%r13d
  mov    $0x1,%ebp
  cmp    %r13d,%ebx
  jle    L103
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  mov    %ebx,%eax
  sub    %r13d,%eax
  cmp    %ebp,%eax
  jge    L117
L103:
  mov    $0x1,%r13d
  sub    $0x1,%ebp
  cmp    %r14d,%ebx
  jle    L38
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    %r13d,%esi
  add    $0x1,%r13d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    %r14d,%eax
  cmp    %r13d,%eax
  jge    L58
L38:
  mov    $0xa,%edi
  lea    0x1(%r14),%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jl     L4
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r14d
  jne    L17
  mov    0x4(%rsp),%ebx
  mov    %ebp,%r14d
  jmp    L76
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D15
type: string

tool: D0:  Enter the number of lines 

tool: D15: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int n, i, j, k;
  printf(" Enter the number of lines \n");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = n; j > i; j--)
      printf(" ");
    for (j = 1; j <= i; j++)
      printf("%d", j);
    for (k = 1; k <= i - 1; k++)
      printf("%d", --j - 1);
    printf("\n");
  }
  for (i = 1; i <= n; i++) {
    for (j = 1; j < i; j++)
      printf(" ");
    for (j = 1; j <= n - (i - 1); j++)
      printf("%d", j);
    for (k = 1; k <= n - (i); k++)
      printf("%d", --j - 1);
    printf("\n");
  }
  return 0;
}
```