ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cli_send_cmd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  cmp    %rbp,%rax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cli_send_cmd(int fd, char *cmd) {
  if (write(fd, cmd, strlen(cmd) + 1) != strlen(cmd) + 1)
    return (-1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cli_send_cmd>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  lea    0x1(%rax),%rdx
  call   <write@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  add    $0x1,%rax
  cmp    %rbx,%rax
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int cli_send_cmd(int fd, char *cmd) {
  if (write(fd, cmd, strlen(cmd) + 1) != strlen(cmd) + 1)
    return (-1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cli_send_cmd>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  lea    0x1(%rax),%rdx
  call   <write@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  add    $0x1,%rax
  cmp    %rbx,%rax
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int cli_send_cmd(int fd, char *cmd) {
  if (write(fd, cmd, strlen(cmd) + 1) != strlen(cmd) + 1)
    return (-1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<use_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <use_buf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void use_memset() {
  char tgt[100];
  memset(tgt, 0, sizeof(tgt));
  use_buf(tgt);
}
```
user: What is the c source code of the assembly code below:

```asm
<use_memset>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <use_buf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x70,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void use_memset() {
  char tgt[100];
  memset(tgt, 0, sizeof(tgt));
  use_buf(tgt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<use_memset>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x64,%edx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <use_buf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void use_memset() {
  char tgt[100];
  memset(tgt, 0, sizeof(tgt));
  use_buf(tgt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<use_memset>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x64,%edx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <use_buf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void use_memset() {
  char tgt[100];
  memset(tgt, 0, sizeof(tgt));
  use_buf(tgt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ho_recognize_font_1_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double ho_recognize_font_1_zero(const double *array_in) {
  double return_value = 0.0;
  return return_value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ho_recognize_font_1_zero>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double ho_recognize_font_1_zero(const double *array_in) {
  double return_value = 0.0;
  return return_value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ho_recognize_font_1_zero>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double ho_recognize_font_1_zero(const double *array_in) {
  double return_value = 0.0;
  return return_value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ho_recognize_font_1_zero>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double ho_recognize_font_1_zero(const double *array_in) {
  double return_value = 0.0;
  return return_value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<closure_mapping_order4_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x6,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x7,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0x8,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movl   $0xb,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movl   $0xc,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movl   $0xd,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movl   $0x10,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  movl   $0x11,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movl   $0x12,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movl   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  movl   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movl   $0x9,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  movl   $0xe,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  movl   $0x13,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3c,%rax
  movl   $0x17,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  movl   $0x16,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x44,%rax
  movl   $0x15,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  movl   $0xf,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4c,%rax
  movl   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x50,%rax
  movl   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x54,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x58,%rax
  movl   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x5c,%rax
  movl   $0x18,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  movl   $0x14,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void closure_mapping_order4_square(int *out_2138521137306367256) {
  out_2138521137306367256[0] = 6;
  out_2138521137306367256[1] = 7;
  out_2138521137306367256[2] = 8;
  out_2138521137306367256[3] = 11;
  out_2138521137306367256[4] = 12;
  out_2138521137306367256[5] = 13;
  out_2138521137306367256[6] = 16;
  out_2138521137306367256[7] = 17;
  out_2138521137306367256[8] = 18;
  out_2138521137306367256[9] = 1;
  out_2138521137306367256[10] = 2;
  out_2138521137306367256[11] = 3;
  out_2138521137306367256[12] = 9;
  out_2138521137306367256[13] = 14;
  out_2138521137306367256[14] = 19;
  out_2138521137306367256[15] = 23;
  out_2138521137306367256[16] = 22;
  out_2138521137306367256[17] = 21;
  out_2138521137306367256[18] = 15;
  out_2138521137306367256[19] = 10;
  out_2138521137306367256[20] = 5;
  out_2138521137306367256[21] = 0;
  out_2138521137306367256[22] = 4;
  out_2138521137306367256[23] = 24;
  out_2138521137306367256[24] = 20;
}
```
user: Translate the below assembly code into C programming language:

```asm
<closure_mapping_order4_square>:
  endbr64
  movl   $0x6,(%rdi)
  movl   $0x7,0x4(%rdi)
  movl   $0x8,0x8(%rdi)
  movl   $0xb,0xc(%rdi)
  movl   $0xc,0x10(%rdi)
  movl   $0xd,0x14(%rdi)
  movl   $0x10,0x18(%rdi)
  movl   $0x11,0x1c(%rdi)
  movl   $0x12,0x20(%rdi)
  movl   $0x1,0x24(%rdi)
  movl   $0x2,0x28(%rdi)
  movl   $0x3,0x2c(%rdi)
  movl   $0x9,0x30(%rdi)
  movl   $0xe,0x34(%rdi)
  movl   $0x13,0x38(%rdi)
  movl   $0x17,0x3c(%rdi)
  movl   $0x16,0x40(%rdi)
  movl   $0x15,0x44(%rdi)
  movl   $0xf,0x48(%rdi)
  movl   $0xa,0x4c(%rdi)
  movl   $0x5,0x50(%rdi)
  movl   $0x0,0x54(%rdi)
  movl   $0x4,0x58(%rdi)
  movl   $0x18,0x5c(%rdi)
  movl   $0x14,0x60(%rdi)
  ret
```

assistant: ```c
void closure_mapping_order4_square(int *out_2138521137306367256) {
  out_2138521137306367256[0] = 6;
  out_2138521137306367256[1] = 7;
  out_2138521137306367256[2] = 8;
  out_2138521137306367256[3] = 11;
  out_2138521137306367256[4] = 12;
  out_2138521137306367256[5] = 13;
  out_2138521137306367256[6] = 16;
  out_2138521137306367256[7] = 17;
  out_2138521137306367256[8] = 18;
  out_2138521137306367256[9] = 1;
  out_2138521137306367256[10] = 2;
  out_2138521137306367256[11] = 3;
  out_2138521137306367256[12] = 9;
  out_2138521137306367256[13] = 14;
  out_2138521137306367256[14] = 19;
  out_2138521137306367256[15] = 23;
  out_2138521137306367256[16] = 22;
  out_2138521137306367256[17] = 21;
  out_2138521137306367256[18] = 15;
  out_2138521137306367256[19] = 10;
  out_2138521137306367256[20] = 5;
  out_2138521137306367256[21] = 0;
  out_2138521137306367256[22] = 4;
  out_2138521137306367256[23] = 24;
  out_2138521137306367256[24] = 20;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<closure_mapping_order4_square>:
  endbr64
  movabs $0x700000006,%rax
  movq   $0x5,0x50(%rdi)
  mov    %rax,(%rdi)
  movabs $0xb00000008,%rax
  mov    %rax,0x8(%rdi)
  movabs $0xd0000000c,%rax
  mov    %rax,0x10(%rdi)
  movabs $0x1100000010,%rax
  mov    %rax,0x18(%rdi)
  movabs $0x100000012,%rax
  mov    %rax,0x20(%rdi)
  movabs $0x300000002,%rax
  mov    %rax,0x28(%rdi)
  movabs $0xe00000009,%rax
  mov    %rax,0x30(%rdi)
  movabs $0x1700000013,%rax
  mov    %rax,0x38(%rdi)
  movabs $0x1500000016,%rax
  mov    %rax,0x40(%rdi)
  movabs $0xa0000000f,%rax
  mov    %rax,0x48(%rdi)
  movabs $0x1800000004,%rax
  mov    %rax,0x58(%rdi)
  movl   $0x14,0x60(%rdi)
  ret
```

assistant: ```c
void closure_mapping_order4_square(int *out_2138521137306367256) {
  out_2138521137306367256[0] = 6;
  out_2138521137306367256[1] = 7;
  out_2138521137306367256[2] = 8;
  out_2138521137306367256[3] = 11;
  out_2138521137306367256[4] = 12;
  out_2138521137306367256[5] = 13;
  out_2138521137306367256[6] = 16;
  out_2138521137306367256[7] = 17;
  out_2138521137306367256[8] = 18;
  out_2138521137306367256[9] = 1;
  out_2138521137306367256[10] = 2;
  out_2138521137306367256[11] = 3;
  out_2138521137306367256[12] = 9;
  out_2138521137306367256[13] = 14;
  out_2138521137306367256[14] = 19;
  out_2138521137306367256[15] = 23;
  out_2138521137306367256[16] = 22;
  out_2138521137306367256[17] = 21;
  out_2138521137306367256[18] = 15;
  out_2138521137306367256[19] = 10;
  out_2138521137306367256[20] = 5;
  out_2138521137306367256[21] = 0;
  out_2138521137306367256[22] = 4;
  out_2138521137306367256[23] = 24;
  out_2138521137306367256[24] = 20;
}
```
user: What is the c source code of the assembly code below?

```asm
<closure_mapping_order4_square>:
  endbr64
  movdqa D47(%rip),%xmm0
  movl   $0x14,0x60(%rdi)
  movups %xmm0,(%rdi)
  movdqa D9(%rip),%xmm0
  movups %xmm0,0x10(%rdi)
  movdqa D20(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movdqa D52(%rip),%xmm0
  movups %xmm0,0x30(%rdi)
  movdqa D12(%rip),%xmm0
  movups %xmm0,0x40(%rdi)
  movdqa D7(%rip),%xmm0
  movups %xmm0,0x50(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D47
type: byte[16]
name: unpack_data
arguments: tag: D9
type: byte[16]
name: unpack_data
arguments: tag: D20
type: byte[16]
name: unpack_data
arguments: tag: D52
type: byte[16]
name: unpack_data
arguments: tag: D12
type: byte[16]
name: unpack_data
arguments: tag: D7
type: byte[16]

tool: {"D47": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D9": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

tool: {"D20": [0x12,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D52": [0x09,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x13,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: {"D12": [0x16,0x00,0x00,0x00,0x15,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D7": [0x05,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x18,0x00,0x00,0x00]}

assistant: ```c
void closure_mapping_order4_square(int *out_2138521137306367256) {
  out_2138521137306367256[0] = 6;
  out_2138521137306367256[1] = 7;
  out_2138521137306367256[2] = 8;
  out_2138521137306367256[3] = 11;
  out_2138521137306367256[4] = 12;
  out_2138521137306367256[5] = 13;
  out_2138521137306367256[6] = 16;
  out_2138521137306367256[7] = 17;
  out_2138521137306367256[8] = 18;
  out_2138521137306367256[9] = 1;
  out_2138521137306367256[10] = 2;
  out_2138521137306367256[11] = 3;
  out_2138521137306367256[12] = 9;
  out_2138521137306367256[13] = 14;
  out_2138521137306367256[14] = 19;
  out_2138521137306367256[15] = 23;
  out_2138521137306367256[16] = 22;
  out_2138521137306367256[17] = 21;
  out_2138521137306367256[18] = 15;
  out_2138521137306367256[19] = 10;
  out_2138521137306367256[20] = 5;
  out_2138521137306367256[21] = 0;
  out_2138521137306367256[22] = 4;
  out_2138521137306367256[23] = 24;
  out_2138521137306367256[24] = 20;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scmAccess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int scmAccess(sqlite3_vfs *pVfs, const char *zPath, int flags, int *pResOut) {
  *pResOut = 0;
  return SQLITE_OK;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scmAccess>:
  endbr64
  movl   $0x0,(%rcx)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int scmAccess(sqlite3_vfs *pVfs, const char *zPath, int flags, int *pResOut) {
  *pResOut = 0;
  return SQLITE_OK;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scmAccess>:
  endbr64
  mov    D8(%rip),%rax
  movl   $0x0,(%rcx)
  mov    (%rax),%eax
  ret
```

assistant: ```c
int scmAccess(sqlite3_vfs *pVfs, const char *zPath, int flags, int *pResOut) {
  *pResOut = 0;
  return SQLITE_OK;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<scmAccess>:
  endbr64
  mov    D8(%rip),%rax
  movl   $0x0,(%rcx)
  mov    (%rax),%eax
  ret
```

assistant: ```c
int scmAccess(sqlite3_vfs *pVfs, const char *zPath, int flags, int *pResOut) {
  *pResOut = 0;
  return SQLITE_OK;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_repeating_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L15
L27:
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L12
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L12:
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L27
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *remove_repeating_chars(const char *str) {
  int len = strlen(str);
  char *copy = malloc(len * sizeof(char));
  copy[0] = str[0];
  int i, index = 1;
  for (i = 1; i < len - 1; i++) {
    if (copy[index - 1] != str[i]) {
      copy[index] = str[i];
      index++;
    }
  }
  copy[index] = '\0';
  return copy;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_repeating_chars>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %dl,(%rax)
  cmp    $0x2,%ebp
  jle    L32
  lea    0x1(%rbx),%rdx
  lea    -0x3(%rbp),%ecx
  lea    0x2(%rbx,%rcx,1),%r8
  mov    $0x1,%ecx
  jmp    L8
L37:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L22
L8:
  movslq %ecx,%rsi
  movzbl (%rdx),%edi
  cmp    %dil,-0x1(%rax,%rsi,1)
  je     L37
  mov    %dil,(%rax,%rsi,1)
  add    $0x1,%ecx
  jmp    L37
L32:
  mov    $0x1,%ecx
L22:
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *remove_repeating_chars(const char *str) {
  int len = strlen(str);
  char *copy = malloc(len * sizeof(char));
  copy[0] = str[0];
  int i, index = 1;
  for (i = 1; i < len - 1; i++) {
    if (copy[index - 1] != str[i]) {
      copy[index] = str[i];
      index++;
    }
  }
  copy[index] = '\0';
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remove_repeating_chars>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  movzbl (%rbx),%esi
  mov    %sil,(%rax)
  cmp    $0x2,%ebp
  jle    L25
  lea    -0x3(%rbp),%r10d
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  mov    $0x1,%edx
  add    %rbx,%r10
  jmp    L1
  nopl   (%rax)
L12:
  movzbl -0x1(%rax,%rdx,1),%esi
  add    $0x1,%rdi
L1:
  movzbl 0x1(%rdi),%ecx
  mov    %rdx,%r9
  cmp    %sil,%cl
  je     L17
  add    $0x1,%r8d
  mov    %cl,(%rax,%rdx,1)
  movslq %r8d,%rdx
  mov    %rdx,%r9
L17:
  cmp    %rdi,%r10
  jne    L12
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%r9d
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *remove_repeating_chars(const char *str) {
  int len = strlen(str);
  char *copy = malloc(len * sizeof(char));
  copy[0] = str[0];
  int i, index = 1;
  for (i = 1; i < len - 1; i++) {
    if (copy[index - 1] != str[i]) {
      copy[index] = str[i];
      index++;
    }
  }
  copy[index] = '\0';
  return copy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_repeating_chars>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  movzbl (%rbx),%esi
  mov    %sil,(%rax)
  cmp    $0x2,%ebp
  jle    L17
  lea    -0x3(%rbp),%r10d
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  mov    $0x1,%edx
  add    %rbx,%r10
  jmp    L0
  nopl   (%rax)
L2:
  movzbl -0x1(%rax,%rdx,1),%esi
  add    $0x1,%rdi
L0:
  movzbl 0x1(%rdi),%ecx
  mov    %rdx,%r9
  cmp    %sil,%cl
  je     L34
  add    $0x1,%r8d
  mov    %cl,(%rax,%rdx,1)
  movslq %r8d,%rdx
  mov    %rdx,%r9
L34:
  cmp    %rdi,%r10
  jne    L2
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%r9d
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *remove_repeating_chars(const char *str) {
  int len = strlen(str);
  char *copy = malloc(len * sizeof(char));
  copy[0] = str[0];
  int i, index = 1;
  for (i = 1; i < len - 1; i++) {
    if (copy[index - 1] != str[i]) {
      copy[index] = str[i];
      index++;
    }
  }
  copy[index] = '\0';
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  movsd  D116(%rip),%xmm1
  movss  D49(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L66
L70:
  add    $0x8,%rsp
  ret
L66:
  movsd  D80(%rip),%xmm1
  movss  D12(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L70
  movsd  D18(%rip),%xmm1
  movss  D5(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x3,%eax
  test   %edx,%edx
  je     L70
  movsd  D74(%rip),%xmm1
  movss  D89(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x4,%eax
  test   %edx,%edx
  je     L70
  movsd  D20(%rip),%xmm1
  movss  D134(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x5,%eax
  test   %edx,%edx
  je     L70
  movsd  D131(%rip),%xmm1
  movss  D58(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x6,%eax
  test   %edx,%edx
  je     L70
  movsd  D18(%rip),%xmm1
  movss  D5(%rip),%xmm0
  call   <eq@plt>
  mov    %eax,%edx
  mov    $0x7,%eax
  test   %edx,%edx
  je     L70
  movsd  D140(%rip),%xmm1
  movss  D92(%rip),%xmm0
  call   <eq@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  shl    $0x3,%eax
  jmp    L70
```

tool_calls: name: read_data
arguments: tag: D116
data_type: f64
name: read_data
arguments: tag: D49
data_type: byte[4]
name: read_data
arguments: tag: D80
data_type: byte[8]
name: read_data
arguments: tag: D12
data_type: byte[4]
name: read_data
arguments: tag: D18
data_type: f64
name: read_data
arguments: tag: D5
data_type: byte[4]
name: read_data
arguments: tag: D74
data_type: f64
name: read_data
arguments: tag: D89
data_type: byte[4]
name: read_data
arguments: tag: D20
data_type: f64
name: read_data
arguments: tag: D134
data_type: byte[4]
name: read_data
arguments: tag: D131
data_type: f64
name: read_data
arguments: tag: D58
data_type: byte[4]
name: read_data
arguments: tag: D140
data_type: f64
name: read_data
arguments: tag: D92
data_type: byte[4]

tool: D116: 5

tool: {"D49": [0x00,0x00,0xa0,0x40]}

tool: {"D80": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D12": [0x00,0x00,0x80,0xbf]}

tool: D18: 6

tool: {"D5": [0x00,0x00,0xc0,0x40]}

tool: D74: 0.666

tool: {"D89": [0xab,0xaa,0x2a,0x3f]}

tool: D20: 4

tool: {"D134": [0x00,0x00,0x80,0x40]}

tool: D131: 3

tool: {"D58": [0x00,0x00,0x40,0x40]}

tool: D140: 2

tool: {"D92": [0x00,0x00,0x00,0x40]}

assistant: ```c
int test() {
  float x = 2.0f;
  double y = 3.0, z;
  z = x + y;
  if (!eq(z, 5.0))
    return 1;
  z = x - y;
  if (!eq(z, -1.0))
    return 2;
  z = x * y;
  if (!eq(z, 6.0))
    return 3;
  z = x / y;
  if (!eq(z, 0.666))
    return 4;
  x += 2.0f;
  if (!eq(x, 4.0))
    return 5;
  x -= 1.0f;
  if (!eq(x, 3.0))
    return 6;
  x *= 2.0f;
  if (!eq(x, 6.0))
    return 7;
  x /= 3.0f;
  if (!eq(x, 2.0))
    return 8;
  return 0;
}
```