ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PartitionErAlgorithmIR>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  cmp    %rdi,%rcx
  jbe    L50
  mov    %rdi,%r15
L104:
  add    $0x1,%r15
  xor    %r14d,%r14d
  test   %r8,%r8
  je     L2
L27:
  mov    %r14d,-0x4(%r12,%r15,4)
  mov    %rbx,%r9
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %r8,0x8(%rsp)
  add    $0x1,%r14
  call   <PartitionErAlgorithmIR>
  mov    0x8(%rsp),%r8
  mov    %rax,%rbx
  cmp    %r8,%r14
  jne    L27
L2:
  mov    %r8d,-0x4(%r12,%r15,4)
  add    $0x1,%r8
  cmp    %r15,%r13
  ja     L104
  mov    %r13,%rax
  sub    0x18(%rsp),%rax
  add    %rax,0x10(%rsp)
L50:
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  xor    %r15d,%r15d
  call   <printf@plt>
  cmpq   $0x0,0x10(%rsp)
  je     L28
  nop
L84:
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  xor    %r14d,%r14d
  call   <printf@plt>
  test   %r13,%r13
  jne    L91
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L80:
  add    $0x1,%r14
  cmp    %r14,%r13
  je     L23
L91:
  movslq (%r12,%r14,4),%rax
  cmp    %r15,%rax
  jne    L80
  mov    0x0(%rbp,%r14,4),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%r13
  jne    L91
  xchg   %ax,%ax
L23:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    0x10(%rsp),%r15
  jne    L84
L28:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D30
data_type: string
name: unpack_data
arguments: data_label: D32
data_type: string
name: unpack_data
arguments: data_label: D39
data_type: string

tool: D37: partition: 

tool: D30: { 

tool: D32: %d 

tool: D39: }  

assistant: ```c
size_t PartitionErAlgorithmIR(size_t pos, int *val, int *sol, size_t n, size_t m, size_t count) {
  size_t i, j;
  if (pos >= n) {
    printf("partition: ");
    for (i = 0; i < m; i++) {
      printf("{ ");
      for (j = 0; j < n; j++) {
        if (sol[j] == i)
          printf("%d ", val[j]);
      }
      printf("}  ");
    }
    printf("\n");
    return (count + 1);
  }
  for (i = 0; i < m; i++) {
    sol[pos] = i;
    count = PartitionErAlgorithmIR(pos + 1, val, sol, n, m, count);
  }
  sol[pos] = m;
  count = PartitionErAlgorithmIR(pos + 1, val, sol, n, m + 1, count);
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PartitionErAlgorithmIR>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  cmp    %rdi,%rcx
  jbe    L63
  mov    %rdi,%r15
L11:
  add    $0x1,%r15
  xor    %r14d,%r14d
  test   %r8,%r8
  je     L23
L52:
  mov    %r14d,-0x4(%r12,%r15,4)
  mov    %rbx,%r9
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %r8,0x8(%rsp)
  add    $0x1,%r14
  call   <PartitionErAlgorithmIR>
  mov    0x8(%rsp),%r8
  mov    %rax,%rbx
  cmp    %r8,%r14
  jne    L52
L23:
  mov    %r8d,-0x4(%r12,%r15,4)
  add    $0x1,%r8
  cmp    %r15,%r13
  ja     L11
  mov    %r13,%rax
  sub    0x18(%rsp),%rax
  add    %rax,0x10(%rsp)
L63:
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  xor    %r15d,%r15d
  call   <printf@plt>
  cmpq   $0x0,0x10(%rsp)
  je     L66
  nop
L17:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  xor    %r14d,%r14d
  call   <printf@plt>
  test   %r13,%r13
  jne    L73
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L76:
  add    $0x1,%r14
  cmp    %r14,%r13
  je     L84
L73:
  movslq (%r12,%r14,4),%rax
  cmp    %r15,%rax
  jne    L76
  mov    0x0(%rbp,%r14,4),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%r13
  jne    L73
  xchg   %ax,%ax
L84:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    0x10(%rsp),%r15
  jne    L17
L66:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D22
data_type: string
name: disassemble_data
arguments: label: D17
data_type: string

tool: D1: partition: 

tool: D3: { 

tool: D22: %d 

tool: D17: }  

assistant: ```c
size_t PartitionErAlgorithmIR(size_t pos, int *val, int *sol, size_t n, size_t m, size_t count) {
  size_t i, j;
  if (pos >= n) {
    printf("partition: ");
    for (i = 0; i < m; i++) {
      printf("{ ");
      for (j = 0; j < n; j++) {
        if (sol[j] == i)
          printf("%d ", val[j]);
      }
      printf("}  ");
    }
    printf("\n");
    return (count + 1);
  }
  for (i = 0; i < m; i++) {
    sol[pos] = i;
    count = PartitionErAlgorithmIR(pos + 1, val, sol, n, m, count);
  }
  sol[pos] = m;
  count = PartitionErAlgorithmIR(pos + 1, val, sol, n, m + 1, count);
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<c_escape_char_for_string_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <add_c_string_escaped_char@plt>
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void c_escape_char_for_string_literal(char ch, char buffer[5]) {
  char *buffer_end = buffer + sizeof(char[5]) - sizeof(char);
  add_c_string_escaped_char(ch, &buffer, buffer_end);
  *buffer = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<c_escape_char_for_string_literal>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    %rsi,0x8(%rsp)
  add    $0x4,%rdx
  lea    0x8(%rsp),%rsi
  movsbl %dil,%edi
  call   <add_c_string_escaped_char@plt>
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
void c_escape_char_for_string_literal(char ch, char buffer[5]) {
  char *buffer_end = buffer + sizeof(char[5]) - sizeof(char);
  add_c_string_escaped_char(ch, &buffer, buffer_end);
  *buffer = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<c_escape_char_for_string_literal>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  movsbl %dil,%edi
  mov    %rsi,0x8(%rsp)
  add    $0x4,%rdx
  lea    0x8(%rsp),%rsi
  call   <add_c_string_escaped_char@plt>
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
void c_escape_char_for_string_literal(char ch, char buffer[5]) {
  char *buffer_end = buffer + sizeof(char[5]) - sizeof(char);
  add_c_string_escaped_char(ch, &buffer, buffer_end);
  *buffer = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D26(%rip),%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D26(%rip),%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: byte[8]
name: disassemble_data
arguments: data_tag: D40
type: string
name: disassemble_data
arguments: data_tag: D9
type: byte[8]
name: disassemble_data
arguments: data_tag: D26
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D40: La diagonal vale: %.2f


tool: {"D9": [0xc0,0x0a,0x1f,0x00,0xc6,0x48,0x1c,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  printf("La diagonal vale: %.2f\n", ((4 - 1) > 0) && ((6 - 2) > 0) ? pow((pow((4 - 1), 2) + pow((6 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 + 5 - 1) > 0) && ((2 + 5 - 2) > 0) ? pow((pow((1 + 5 - 1), 2) + pow((2 + 5 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((3 - 1) > 0) && ((0 - 2) > 0) ? pow((pow((3 - 1), 2) + pow((0 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 - 2) > 0) && ((4 - 2) > 0) ? pow((pow((1 - 2), 2) + pow((4 - 2), 2)), 0.5) : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  movsd  D1(%rip),%xmm0
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movsd  D5(%rip),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: byte[8]
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D5
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D23: La diagonal vale: %.2f


tool: {"D5": [0xc0,0x0a,0x1f,0x00,0xc6,0x48,0x1c,0x40]}

assistant: ```c
int main(void) {
  printf("La diagonal vale: %.2f\n", ((4 - 1) > 0) && ((6 - 2) > 0) ? pow((pow((4 - 1), 2) + pow((6 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 + 5 - 1) > 0) && ((2 + 5 - 2) > 0) ? pow((pow((1 + 5 - 1), 2) + pow((2 + 5 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((3 - 1) > 0) && ((0 - 2) > 0) ? pow((pow((3 - 1), 2) + pow((0 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 - 2) > 0) && ((4 - 2) > 0) ? pow((pow((1 - 2), 2) + pow((4 - 2), 2)), 0.5) : 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D27(%rip),%xmm0
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D3(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D27
datatype: byte[8]
name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D3
datatype: byte[8]

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D4: La diagonal vale: %.2f


tool: {"D3": [0xc0,0x0a,0x1f,0x00,0xc6,0x48,0x1c,0x40]}

assistant: ```c
int main(void) {
  printf("La diagonal vale: %.2f\n", ((4 - 1) > 0) && ((6 - 2) > 0) ? pow((pow((4 - 1), 2) + pow((6 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 + 5 - 1) > 0) && ((2 + 5 - 2) > 0) ? pow((pow((1 + 5 - 1), 2) + pow((2 + 5 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((3 - 1) > 0) && ((0 - 2) > 0) ? pow((pow((3 - 1), 2) + pow((0 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 - 2) > 0) && ((4 - 2) > 0) ? pow((pow((1 - 2), 2) + pow((4 - 2), 2)), 0.5) : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  movsd  D21(%rip),%xmm0
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movsd  D5(%rip),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
data_type: byte[8]
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D5
data_type: byte[8]

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D26: La diagonal vale: %.2f


tool: {"D5": [0xc0,0x0a,0x1f,0x00,0xc6,0x48,0x1c,0x40]}

assistant: ```c
int main(void) {
  printf("La diagonal vale: %.2f\n", ((4 - 1) > 0) && ((6 - 2) > 0) ? pow((pow((4 - 1), 2) + pow((6 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 + 5 - 1) > 0) && ((2 + 5 - 2) > 0) ? pow((pow((1 + 5 - 1), 2) + pow((2 + 5 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((3 - 1) > 0) && ((0 - 2) > 0) ? pow((pow((3 - 1), 2) + pow((0 - 2), 2)), 0.5) : 0);
  printf("La diagonal vale: %.2f\n", ((1 - 2) > 0) && ((4 - 2) > 0) ? pow((pow((1 - 2), 2) + pow((4 - 2), 2)), 0.5) : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: Usage: easter [general options] [-hjy] [year] ...
General options: [-31] [-A years] [-B years]


assistant: ```c
void usage(FILE *stream, int exit_code) {
  fprintf(stream, "Usage: easter [general options] [-hjy] [year] ...\n"
                  "General options: [-31] [-A years] [-B years]\n");
  exit(exit_code);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  lea    D1(%rip),%rsi
  call   <fprintf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: Usage: easter [general options] [-hjy] [year] ...
General options: [-31] [-A years] [-B years]


assistant: ```c
void usage(FILE *stream, int exit_code) {
  fprintf(stream, "Usage: easter [general options] [-hjy] [year] ...\n"
                  "General options: [-31] [-A years] [-B years]\n");
  exit(exit_code);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D9(%rip),%rsi
  call   <fprintf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: Usage: easter [general options] [-hjy] [year] ...
General options: [-31] [-A years] [-B years]


assistant: ```c
void usage(FILE *stream, int exit_code) {
  fprintf(stream, "Usage: easter [general options] [-hjy] [year] ...\n"
                  "General options: [-31] [-A years] [-B years]\n");
  exit(exit_code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D8(%rip),%rsi
  call   <fprintf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: Usage: easter [general options] [-hjy] [year] ...
General options: [-31] [-A years] [-B years]


assistant: ```c
void usage(FILE *stream, int exit_code) {
  fprintf(stream, "Usage: easter [general options] [-hjy] [year] ...\n"
                  "General options: [-31] [-A years] [-B years]\n");
  exit(exit_code);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bb_get_last_path_component>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L0
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L0
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L0:
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L19
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *bb_get_last_path_component(char *path) {
  char *first = path;
  char *last;
  last = path - 1;
  while (*path) {
    if ((*path != '/') && (path > ++last)) {
      last = first = path;
    }
    ++path;
  }
  if (*first == '/') {
    last = first;
  }
  last[1] = 0;
  return first;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bb_get_last_path_component>:
  endbr64
  lea    -0x1(%rdi),%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  mov    %rdi,%rcx
  jmp    L61
L58:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
L61:
  cmp    $0x2f,%al
  je     L58
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jae    L58
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  jmp    L58
L4:
  cmpb   $0x2f,(%rcx)
  cmove  %rcx,%rdx
L63:
  movb   $0x0,0x1(%rdx)
  mov    %rcx,%rax
  ret
L11:
  mov    %rdi,%rcx
  jmp    L63
```

assistant: ```c
char *bb_get_last_path_component(char *path) {
  char *first = path;
  char *last;
  last = path - 1;
  while (*path) {
    if ((*path != '/') && (path > ++last)) {
      last = first = path;
    }
    ++path;
  }
  if (*first == '/') {
    last = first;
  }
  last[1] = 0;
  return first;
}
```
user: What is the c source code of the assembly code below?

```asm
<bb_get_last_path_component>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  lea    -0x1(%rdi),%rsi
  test   %cl,%cl
  je     L3
  mov    %rdi,%rdx
  nopl   (%rax)
L38:
  cmp    $0x2f,%cl
  je     L20
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  jae    L20
  mov    %rdx,%rsi
  mov    %rdx,%rax
L20:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L38
  cmpb   $0x2f,(%rax)
  cmove  %rax,%rsi
L3:
  movb   $0x0,0x1(%rsi)
  ret
```

assistant: ```c
char *bb_get_last_path_component(char *path) {
  char *first = path;
  char *last;
  last = path - 1;
  while (*path) {
    if ((*path != '/') && (path > ++last)) {
      last = first = path;
    }
    ++path;
  }
  if (*first == '/') {
    last = first;
  }
  last[1] = 0;
  return first;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bb_get_last_path_component>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  lea    -0x1(%rdi),%rsi
  test   %cl,%cl
  je     L22
  mov    %rdi,%rdx
  nopl   (%rax)
L36:
  cmp    $0x2f,%cl
  je     L35
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jbe    L35
  mov    %rdx,%rsi
  mov    %rdx,%rax
L35:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L36
  cmpb   $0x2f,(%rax)
  cmove  %rax,%rsi
L22:
  movb   $0x0,0x1(%rsi)
  ret
```

assistant: ```c
char *bb_get_last_path_component(char *path) {
  char *first = path;
  char *last;
  last = path - 1;
  while (*path) {
    if ((*path != '/') && (path > ++last)) {
      last = first = path;
    }
    ++path;
  }
  if (*first == '/') {
    last = first;
  }
  last[1] = 0;
  return first;
}
```
user: What is the c source code of the assembly code below?

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L61
  cmpq   $0xffffffffffffffff,-0x10(%rbp)
  jne    L61
  mov    $0x0,%eax
  jmp    L44
L61:
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L15
  mov    -0x10(%rbp),%rax
  jmp    L44
L15:
  cmpq   $0xffffffffffffffff,-0x10(%rbp)
  jne    L66
  mov    -0x8(%rbp),%rax
  jmp    L44
L66:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  cmovle %rdx,%rax
L44:
  pop    %rbp
  ret
```

assistant: ```c
long long min(long long x, long long y) {
  if (x == -1 && y == -1)
    return 0;
  if (x == -1)
    return y;
  if (y == -1)
    return x;
  return x > y ? y : x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<min>:
  endbr64
  mov    %rdi,%rdx
  and    %rsi,%rdx
  mov    $0x0,%eax
  cmp    $0xffffffffffffffff,%rdx
  je     L9
  mov    %rsi,%rax
  cmp    $0xffffffffffffffff,%rdi
  je     L9
  cmp    %rsi,%rdi
  cmovle %rdi,%rax
  cmp    $0xffffffffffffffff,%rsi
  cmove  %rdi,%rax
L9:
  ret
```

assistant: ```c
long long min(long long x, long long y) {
  if (x == -1 && y == -1)
    return 0;
  if (x == -1)
    return y;
  if (y == -1)
    return x;
  return x > y ? y : x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<min>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  and    %rsi,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L15
  mov    %rsi,%rax
  cmp    $0xffffffffffffffff,%rdi
  je     L15
  cmp    %rsi,%rdi
  mov    %rsi,%rdx
  mov    %rdi,%rax
  cmovle %rdi,%rdx
  cmp    $0xffffffffffffffff,%rsi
  cmovne %rdx,%rax
L15:
  ret
```

assistant: ```c
long long min(long long x, long long y) {
  if (x == -1 && y == -1)
    return 0;
  if (x == -1)
    return y;
  if (y == -1)
    return x;
  return x > y ? y : x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  and    %rsi,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L15
  mov    %rsi,%rax
  cmp    $0xffffffffffffffff,%rdi
  je     L15
  cmp    %rsi,%rdi
  mov    %rsi,%rdx
  mov    %rdi,%rax
  cmovle %rdi,%rdx
  cmp    $0xffffffffffffffff,%rsi
  cmovne %rdx,%rax
L15:
  ret
```

assistant: ```c
long long min(long long x, long long y) {
  if (x == -1 && y == -1)
    return 0;
  if (x == -1)
    return y;
  if (y == -1)
    return x;
  return x > y ? y : x;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x1f,%rax
  and    $0x1,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L11
L3:
  mov    $0xffffffff,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int foo(unsigned long long x) {
  unsigned long long y = (x >> 31ULL) & 1ULL;
  if (y == 0ULL)
    return 0;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  sar    $0x1f,%eax
  ret
```

assistant: ```c
__attribute__((no)) int foo(unsigned long long x) {
  unsigned long long y = (x >> 31ULL) & 1ULL;
  if (y == 0ULL)
    return 0;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    %rdi,%rax
  shl    $0x20,%rax
  sar    $0x3f,%rax
  ret
```

assistant: ```c
__attribute__((no)) int foo(unsigned long long x) {
  unsigned long long y = (x >> 31ULL) & 1ULL;
  if (y == 0ULL)
    return 0;
  return -1;
}
```