ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Mod_FindInterval>:
  endbr64
  movslq %esi,%rax
  movaps %xmm0,%xmm1
  sub    $0x1,%esi
  movss  -0x4(%rdi,%rax,4),%xmm2
  divss  %xmm2,%xmm1
  cvttss2si %xmm1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  xor    %eax,%eax
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  test   %esi,%esi
  jg     L21
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%eax
  add    $0x4,%rdi
  cmp    %esi,%eax
  je     L3
L21:
  movss  (%rdi),%xmm1
  comiss %xmm0,%xmm1
  jbe    L23
L8:
  ret
  nopl   (%rax)
L3:
  ret
```

assistant: ```c
int Mod_FindInterval(const float *intervals, int numintervals, float time) {
  int i;
  float fullinterval, targettime;
  fullinterval = intervals[numintervals - 1];
  targettime = time - (int)(time / fullinterval) * fullinterval;
  for (i = 0; i < numintervals - 1; i++)
    if (intervals[i] > targettime)
      break;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bulk_erase_PIC24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  or     $0x24000a,%eax
  mov    %eax,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x883b0a,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x880190,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0xbb0800,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%eax
  call   <p16b_do_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void bulk_erase_PIC24(unsigned int nv) {
  dspic_send_24_bits(0x24000A | (nv << 4));
  dspic_send_24_bits(0x883B0A);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0x880190);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0xBB0800);
  dspic_send_24_bits(0x000000);
  dspic_send_24_bits(0x000000);
  p16b_do_write();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bulk_erase_PIC24>:
  endbr64
  sub    $0x8,%rsp
  shl    $0x4,%edi
  or     $0x24000a,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x883b0a,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x880190,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0xbb0800,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x0,%eax
  call   <p16b_do_write@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bulk_erase_PIC24(unsigned int nv) {
  dspic_send_24_bits(0x24000A | (nv << 4));
  dspic_send_24_bits(0x883B0A);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0x880190);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0xBB0800);
  dspic_send_24_bits(0x000000);
  dspic_send_24_bits(0x000000);
  p16b_do_write();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bulk_erase_PIC24>:
  endbr64
  shl    $0x4,%edi
  sub    $0x8,%rsp
  or     $0x24000a,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x883b0a,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x880190,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0x200000,%edi
  call   <dspic_send_24_bits@plt>
  mov    $0xbb0800,%edi
  call   <dspic_send_24_bits@plt>
  xor    %edi,%edi
  call   <dspic_send_24_bits@plt>
  xor    %edi,%edi
  call   <dspic_send_24_bits@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <p16b_do_write@plt>
```

assistant: ```c
void bulk_erase_PIC24(unsigned int nv) {
  dspic_send_24_bits(0x24000A | (nv << 4));
  dspic_send_24_bits(0x883B0A);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0x880190);
  dspic_send_24_bits(0x200000);
  dspic_send_24_bits(0xBB0800);
  dspic_send_24_bits(0x000000);
  dspic_send_24_bits(0x000000);
  p16b_do_write();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_native_64_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
uint64_t decode_native_64_unsigned(char *buf) {
  uint64_t rv;
  memcpy(&rv, buf, 8);
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_native_64_unsigned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t decode_native_64_unsigned(char *buf) {
  uint64_t rv;
  memcpy(&rv, buf, 8);
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_native_64_unsigned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t decode_native_64_unsigned(char *buf) {
  uint64_t rv;
  memcpy(&rv, buf, 8);
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_native_64_unsigned>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t decode_native_64_unsigned(char *buf) {
  uint64_t rv;
  memcpy(&rv, buf, 8);
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FreeDbl1D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
L9:
  nop
  leave
  ret
```

assistant: ```c
void FreeDbl1D(double *s) {
  if (s)
    free((void *)s);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FreeDbl1D>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void FreeDbl1D(double *s) {
  if (s)
    free((void *)s);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<FreeDbl1D>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void FreeDbl1D(double *s) {
  if (s)
    free((void *)s);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FreeDbl1D>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void FreeDbl1D(double *s) {
  if (s)
    free((void *)s);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: Ola internet


assistant: ```c
int main() {
  printf("Ola internet\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: Ola internet


assistant: ```c
int main() {
  printf("Ola internet\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string

tool: D8: Ola internet


assistant: ```c
int main() {
  printf("Ola internet\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: Ola internet


assistant: ```c
int main() {
  printf("Ola internet\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<getControlNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L36
L4:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x34(%rbp)
  addl   $0x1,-0x38(%rbp)
L36:
  cmpl   $0x8,-0x38(%rbp)
  jle    L4
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  cmpl   $0xa,-0x34(%rbp)
  jne    L11
  movl   $0x0,-0x34(%rbp)
L11:
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int getControlNumber(char *upn) {
  int i, controlNumber = 0, weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (i = 0; i < 9; i++) {
    controlNumber += ((upn[i] - '0') * weights[i]);
  }
  controlNumber = controlNumber % 11;
  if (controlNumber == 10) {
    controlNumber = 0;
  }
  return controlNumber;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getControlNumber>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    %rsp,%rsi
L13:
  movsbl (%rdi,%rdx,1),%eax
  sub    $0x30,%eax
  imul   (%rsi,%rdx,4),%eax
  add    %eax,%ecx
  add    $0x1,%rdx
  cmp    $0x9,%rdx
  jne    L13
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getControlNumber(char *upn) {
  int i, controlNumber = 0, weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (i = 0; i < 9; i++) {
    controlNumber += ((upn[i] - '0') * weights[i]);
  }
  controlNumber = controlNumber % 11;
  if (controlNumber == 10) {
    controlNumber = 0;
  }
  return controlNumber;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getControlNumber>:
  endbr64
  sub    $0x38,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x800000004,%rax
  mov    %rax,0x4(%rsp)
  movabs $0xa00000005,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x700000009,%rax
  mov    %rax,0x14(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x1c(%rsp)
  jmp    L16
  nopl   (%rax)
L21:
  mov    (%rsp,%rdx,4),%esi
L16:
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  imul   %esi,%eax
  add    %eax,%ecx
  cmp    $0x9,%rdx
  jne    L21
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  cmp    $0xa,%eax
  cmove  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getControlNumber(char *upn) {
  int i, controlNumber = 0, weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (i = 0; i < 9; i++) {
    controlNumber += ((upn[i] - '0') * weights[i]);
  }
  controlNumber = controlNumber % 11;
  if (controlNumber == 10) {
    controlNumber = 0;
  }
  return controlNumber;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getControlNumber>:
  endbr64
  movsbl 0x1(%rdi),%edx
  movsbl (%rdi),%ecx
  movsbl 0x8(%rdi),%eax
  lea    -0xc0(,%rdx,4),%edx
  lea    -0x60(%rdx,%rcx,2),%edx
  movsbl 0x2(%rdi),%ecx
  lea    -0x90(%rax,%rax,2),%eax
  lea    -0x180(%rdx,%rcx,8),%ecx
  movsbl 0x3(%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%edx
  add    %ecx,%edx
  movsbl 0x4(%rdi),%ecx
  lea    -0xf0(%rcx,%rcx,4),%ecx
  lea    (%rdx,%rcx,2),%esi
  movsbl 0x5(%rdi),%edx
  lea    -0x1b0(%rdx,%rdx,8),%ecx
  movsbl 0x6(%rdi),%edx
  add    %esi,%ecx
  sub    $0x30,%edx
  lea    (%rcx,%rdx,8),%ecx
  sub    %edx,%ecx
  movsbl 0x7(%rdi),%edx
  lea    -0x90(%rdx,%rdx,2),%edx
  add    %ecx,%edx
  lea    (%rdx,%rax,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int getControlNumber(char *upn) {
  int i, controlNumber = 0, weights[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
  for (i = 0; i < 9; i++) {
    controlNumber += ((upn[i] - '0') * weights[i]);
  }
  controlNumber = controlNumber % 11;
  if (controlNumber == 10) {
    controlNumber = 0;
  }
  return controlNumber;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mutstep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %edx,%r14d
  mov    %ecx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  lea    0x0(,%rax,8),%rbx
  movslq %edx,%rdx
  imul   %rdx,%rax
  lea    0xf(,%rax,8),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L79:
  cmp    %rcx,%rsp
  je     L99
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L99:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L83
  orq    $0x0,-0x8(%rsp,%rdx,1)
L83:
  mov    %rsp,%rax
  mov    %rax,-0x60(%rbp)
  test   %r14d,%r14d
  jle    L73
  lea    -0x1(%r15),%edi
  lea    0x8(%rax,%rdi,8),%r11
  mov    -0x58(%rbp),%r13
  mov    $0x0,%r12d
  mov    %rdi,%rax
  not    %rax
  shl    $0x3,%rax
  mov    %rax,-0x50(%rbp)
  jmp    L26
L60:
  mov    %r8,%r10
  mov    %r9,%rcx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L40:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L40
  movsd  %xmm1,(%r10)
  add    $0x8,%r8
  add    %rbx,%r9
  cmp    %r11,%r8
  jne    L60
L61:
  add    $0x1,%r12d
  add    %rbx,%r11
  add    %rbx,%r13
  cmp    %r12d,%r14d
  je     L73
L26:
  mov    %r13,%rsi
  mov    -0x50(%rbp),%rax
  lea    (%rax,%r11,1),%r8
  mov    -0x48(%rbp),%r9
  test   %r15d,%r15d
  jg     L60
  jmp    L61
L73:
  mov    %r14d,%edx
  imul   %r15d,%edx
  shl    $0x3,%edx
  mov    -0x60(%rbp),%rsi
  mov    -0x58(%rbp),%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mutstep(double *vec, const double *mut, const int nislands, const int nhap) {
  int i, j, k;
  double vec2[nislands][nhap];
  for (i = 0; i < nislands; i++)
    for (j = 0; j < nhap; j++) {
      vec2[i][j] = 0;
      for (k = 0; k < nhap; k++)
        vec2[i][j] += ((double(*)[nhap])mut)[j][k] * ((double(*)[nhap])vec)[i][k];
    }
  memcpy(vec, (double *)vec2, sizeof(double) * nislands * nhap);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<mutstep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edx,-0x44(%rbp)
  movslq %edx,%rdx
  mov    %ecx,-0x48(%rbp)
  mov    %rdi,-0x60(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%rcx
  lea    0x0(,%rax,8),%r14
  imul   %rdx,%rax
  lea    0xf(,%rax,8),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L63
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L63:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L25
L13:
  mov    -0x44(%rbp),%edx
  mov    %rsp,%rax
  mov    %rax,-0x68(%rbp)
  test   %edx,%edx
  jle    L62
  mov    -0x48(%rbp),%ecx
  mov    %rax,%rdi
  xor    %r13d,%r13d
  mov    -0x60(%rbp),%r15
  lea    -0x1(%rcx),%r12d
  lea    0x8(,%r12,8),%rcx
  add    %rcx,%rax
  mov    %rcx,-0x58(%rbp)
  mov    %rax,%rbx
  mov    %r12,%rax
  mov    %rbx,%r12
  mov    %r13d,%ebx
  mov    %r14,%r13
  mov    %rax,%r14
  nop
L68:
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  jle    L98
  mov    -0x58(%rbp),%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    -0x50(%rbp),%rsi
  pxor   %xmm2,%xmm2
  mov    %rax,%rdi
  mov    %rax,%r11
L35:
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L37:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%r15,%rax,8),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %r14,%rdx
  jne    L37
  movsd  %xmm1,(%r11)
  add    $0x8,%r11
  add    %r13,%rsi
  cmp    %r12,%r11
  jne    L35
L98:
  add    $0x1,%ebx
  add    %r13,%r12
  add    %r13,%r15
  add    %r13,%rdi
  cmp    %ebx,-0x44(%rbp)
  jne    L68
L62:
  mov    -0x44(%rbp),%edx
  imul   -0x48(%rbp),%edx
  mov    -0x68(%rbp),%rsi
  mov    -0x60(%rbp),%rdi
  shl    $0x3,%edx
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L25:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L13
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mutstep(double *vec, const double *mut, const int nislands, const int nhap) {
  int i, j, k;
  double vec2[nislands][nhap];
  for (i = 0; i < nislands; i++)
    for (j = 0; j < nhap; j++) {
      vec2[i][j] = 0;
      for (k = 0; k < nhap; k++)
        vec2[i][j] += ((double(*)[nhap])mut)[j][k] * ((double(*)[nhap])vec)[i][k];
    }
  memcpy(vec, (double *)vec2, sizeof(double) * nislands * nhap);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gwv_np_4>:
  endbr64
  push   %rbx
  lea    -0x20000(%rsp),%r11
L69:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L69
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x20018(%rsp)
  xor    %eax,%eax
L40:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x10(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x8000,%rax
  jne    L40
  lea    0x10(%rsp),%r8
  lea    0xc(%rsp),%rdx
  lea    0x1010(%rsp),%rcx
  lea    0x2000c(%rsp),%r9
  mov    %rcx,%rsi
  pxor   %xmm7,%xmm7
  movss  %xmm7,0x8(%rsp)
  movaps %xmm7,%xmm0
L65:
  lea    0x4(%rdx),%rax
L44:
  movss  (%rax),%xmm1
  addss  %xmm1,%xmm0
  maxss  0x8(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L44
  lea    0x1000(%rdx),%rdi
  mov    %rdi,%rax
L51:
  movss  (%rax),%xmm1
  addss  %xmm1,%xmm0
  maxss  0x8(%rsp),%xmm1
  movss  %xmm1,0x8(%rsp)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L51
  add    $0x1000,%rsi
  cmp    %rdi,%r9
  je     L71
  mov    %rdi,%rdx
  jmp    L65
L71:
  lea    0x21000(%r8),%rsi
  pxor   %xmm7,%xmm7
  movss  %xmm7,0xc(%rsp)
  movaps %xmm7,%xmm1
L0:
  lea    -0x1000(%rcx),%rax
  lea    -0x4(%rcx),%rdx
L24:
  movss  (%rax),%xmm3
  addss  %xmm3,%xmm1
  movss  (%rdx),%xmm2
  addss  %xmm2,%xmm1
  maxss  0xc(%rsp),%xmm3
  maxss  %xmm3,%xmm2
  movss  %xmm2,0xc(%rsp)
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %rcx,%rax
  jne    L24
  add    $0x1000,%rcx
  cmp    %rsi,%rcx
  jne    L0
  ucomiss %xmm0,%xmm1
  setnp  %dil
  movzbl %dil,%edi
  mov    $0x0,%ebx
  cmovne %ebx,%edi
  call   <assert@plt>
  movss  0x8(%rsp),%xmm7
  ucomiss 0xc(%rsp),%xmm7
  setnp  %dil
  movzbl %dil,%edi
  cmovne %ebx,%edi
  call   <assert@plt>
  mov    0x20018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x20020,%rsp
  pop    %rbx
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gwv_np_4() {
  int i, j;
  float arr[32768];
  float res = 0, mres = 0, hres = 0, hmres = 0;
  for (i = 0; i < 32768; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32)
  {
#pragma acc loop gang reduction(+ : res) reduction(max : mres)
    for (j = 0; j < 32; j++) {
#pragma acc loop worker vector reduction(+ : res) reduction(max : mres)
      for (i = 0; i < 1024; i++) {
        res += arr[j * 1024 + i];
        if (arr[j * 1024 + i] > mres)
          mres = arr[j * 1024 + i];
      }
#pragma acc loop worker vector reduction(+ : res) reduction(max : mres)
      for (i = 0; i < 1024; i++) {
        res += arr[j * 1024 + (1023 - i)];
        if (arr[j * 1024 + (1023 - i)] > mres)
          mres = arr[j * 1024 + (1023 - i)];
      }
    }
  }
  for (j = 0; j < 32; j++)
    for (i = 0; i < 1024; i++) {
      hres += arr[j * 1024 + i];
      hres += arr[j * 1024 + (1023 - i)];
      if (arr[j * 1024 + i] > hmres)
        hmres = arr[j * 1024 + i];
      if (arr[j * 1024 + (1023 - i)] > hmres)
        hmres = arr[j * 1024 + (1023 - i)];
    }
  assert(res == hres);
  assert(mres == hmres);
}
```