ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTCharPutNonBlocking>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x7f,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%ecx
  mov    0x14(%ebx),%eax
  and    $0x60,%eax
  je     L1
  movzbl %bpl,%esi
  mov    $0x1,%eax
  mov    %esi,(%ebx)
L1:
  mov    %ecx,0xc(%ebx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int UARTCharPutNonBlocking(unsigned int baseAdd, unsigned char byteWrite) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  if ((*((volatile unsigned int *)(baseAdd + (0x14)))) & ((0x00000040u) | (0x00000020u))) {
    (*((volatile unsigned int *)(baseAdd + (0x0)))) = byteWrite;
    retVal = 1;
  }
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_comment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L68
L43:
  cmpl   $0x2a,-0x4(%rbp)
  jne    L10
  movl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x1,-0x8(%rbp)
  jne    L20
  cmpl   $0x2f,-0x4(%rbp)
  jne    L20
  mov    -0x4(%rbp),%eax
  jmp    L32
L20:
  cmpl   $0x2a,-0x4(%rbp)
  je     L68
  movl   $0x0,-0x8(%rbp)
L68:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L43
  mov    -0x4(%rbp),%eax
L32:
  leave
  ret
```

assistant: ```c
int is_comment(void) {
  int c, state = 0;
  while ((c = getch()) != EOF) {
    if (c == '*')
      state = 1;
    if (state == 1 && c == '/')
      return c;
    if (c != '*')
      state = 0;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_comment>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L53
L40:
  mov    $0x1,%ebx
  jmp    L53
L45:
  mov    %ebp,%ebx
L53:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L24
  cmp    $0x2a,%eax
  je     L40
  test   %ebx,%ebx
  je     L45
  cmp    $0x2f,%eax
  jne    L45
  mov    $0x2f,%eax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_comment(void) {
  int c, state = 0;
  while ((c = getch()) != EOF) {
    if (c == '*')
      state = 1;
    if (state == 1 && c == '/')
      return c;
    if (c != '*')
      state = 0;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_comment>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbp
L27:
  xor    %eax,%eax
  call   <getch@plt>
  cmp    %eax,0x0(%rbp)
  je     L4
L23:
  cmp    $0x2a,%eax
  je     L6
  cmp    $0x2f,%eax
  jne    L28
  test   %ebx,%ebx
  jne    L32
L28:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <getch@plt>
  cmp    %eax,0x0(%rbp)
  jne    L23
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%ebx
  jmp    L27
  nop
L32:
  add    $0x8,%rsp
  mov    $0x2f,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_comment(void) {
  int c, state = 0;
  while ((c = getch()) != EOF) {
    if (c == '*')
      state = 1;
    if (state == 1 && c == '/')
      return c;
    if (c != '*')
      state = 0;
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_comment>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbp
L27:
  xor    %eax,%eax
  call   <getch@plt>
  cmp    %eax,0x0(%rbp)
  je     L42
L10:
  cmp    $0x2a,%eax
  je     L8
  cmp    $0x2f,%eax
  jne    L4
  test   %ebx,%ebx
  jne    L26
L4:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <getch@plt>
  cmp    %eax,0x0(%rbp)
  jne    L10
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%ebx
  jmp    L27
  nop
L26:
  add    $0x8,%rsp
  mov    $0x2f,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_comment(void) {
  int c, state = 0;
  while ((c = getch()) != EOF) {
    if (c == '*')
      state = 1;
    if (state == 1 && c == '/')
      return c;
    if (c != '*')
      state = 0;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<house_1>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    $0x1,%r13d
  jg     L17
  movq   $0x0,(%rax)
  mov    D20(%rip),%rax
  mov    %rax,(%rbx)
L130:
  movsd  (%r12),%xmm2
  pxor   %xmm1,%xmm1
  movsd  0x0(%rbp),%xmm3
  ucomisd %xmm1,%xmm2
  jp     L112
  jne    L112
  comisd %xmm1,%xmm3
  movapd %xmm1,%xmm0
  jb     L127
L18:
  mov    %r12,%rdi
  movsd  %xmm0,(%rsp)
  call   <free@plt>
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  lea    0x8(%rbp),%rdi
  mov    %rax,%rdx
  lea    -0x1(%r13),%r8d
  mov    $0x1,%ecx
  mov    $0x1,%r9d
  mov    %rdi,%rsi
  call   <mmult@plt>
  mov    D20(%rip),%rax
  movslq %r13d,%rdx
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L34:
  movsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L34
  jmp    L130
  nopl   0x0(%rax)
L127:
  comisd %xmm3,%xmm1
  movsd  D12(%rip),%xmm0
  ja     L18
L112:
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm1
  ja     L75
  sqrtsd %xmm0,%xmm0
L111:
  comisd %xmm3,%xmm1
  jae    L41
  addsd  %xmm3,%xmm0
  xorpd  D33(%rip),%xmm2
  divsd  %xmm0,%xmm2
L143:
  movapd %xmm2,%xmm0
  movapd %xmm2,%xmm1
  movsd  %xmm2,(%rbx)
  addsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  (%r12),%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  test   %r13d,%r13d
  jle    L18
  lea    -0x1(%r13),%edx
  mov    %rbx,%rax
  movapd %xmm2,%xmm1
  lea    0x8(%rbx,%rdx,8),%rdx
  jmp    L21
  nop
L82:
  movsd  (%rax),%xmm1
L21:
  divsd  %xmm2,%xmm1
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L82
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L41:
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm2
  jmp    L143
L75:
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm2
  pxor   %xmm1,%xmm1
  jmp    L111
```

tool_calls: name: read_data
arguments: data_label: D20
datatype: f64
name: read_data
arguments: data_label: D12
datatype: f32[2]
name: read_data
arguments: data_label: D33
datatype: f32[4]

tool: D20: 1

tool: {"D12": [0.0,-2.0]}

tool: {"D33": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double house_1(double *x, int N, double *v) {
  double beta, mu, temp;
  double *sigma;
  int i;
  sigma = (double *)malloc(sizeof(double) * 1);
  if (N > 1) {
    mmult(x + 1, x + 1, sigma, 1, N - 1, 1);
  } else {
    sigma[0] = 0.0;
  }
  v[0] = 1.;
  for (i = 1; i < N; ++i) {
    v[i] = x[i];
  }
  if (sigma[0] == 0. && x[0] >= 0.) {
    beta = 0.;
  } else if (sigma[0] == 0. && x[0] < 0.) {
    beta = -2.;
  } else {
    mu = sqrt(sigma[0] + x[0] * x[0]);
    if (x[0] <= 0.) {
      v[0] = x[0] - mu;
    } else {
      v[0] = -sigma[0] / (x[0] + mu);
    }
    temp = v[0];
    beta = (2.0 * v[0] * v[0]) / (sigma[0] + v[0] * v[0]);
    for (i = 0; i < N; ++i) {
      v[i] /= temp;
    }
  }
  free(sigma);
  return beta;
}
```
user: Translate the below assembly code into C programming language:

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L6:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L2
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L34
L2:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
L34:
  leave
  ret
```

assistant: ```c
int *twoSum(int numbers[], int n, int target) {
  int i = 0;
  int j = 0;
  int *ptr = (int *)malloc(sizeof(int) * 2);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (numbers[i] + numbers[j] == target) {
        ptr[0] = i + 1;
        ptr[1] = j + 1;
        return ptr;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<twoSum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L32
  mov    %ebp,%r9d
  mov    $0x1,%r8d
L13:
  mov    %r8d,%r10d
  cmp    %r9,%r8
  je     L32
  mov    -0x4(%rbx,%r8,4),%edi
  mov    %r8,%rdx
L0:
  mov    %edx,%esi
  mov    %edi,%ecx
  add    (%rbx,%rdx,4),%ecx
  cmp    %r12d,%ecx
  je     L45
  add    $0x1,%rdx
  cmp    %edx,%ebp
  jg     L0
  add    $0x1,%r8
  jmp    L13
L45:
  mov    %r10d,(%rax)
  add    $0x1,%esi
  mov    %esi,0x4(%rax)
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int numbers[], int n, int target) {
  int i = 0;
  int j = 0;
  int *ptr = (int *)malloc(sizeof(int) * 2);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (numbers[i] + numbers[j] == target) {
        ptr[0] = i + 1;
        ptr[1] = j + 1;
        return ptr;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L59
  lea    0x1(%r12),%r9d
  mov    $0x2,%edx
L54:
  lea    -0x1(%rdx),%r10d
  cmp    %r9,%rdx
  je     L59
  mov    %r12d,%esi
  lea    0x1(%rdx),%r8
  mov    -0x8(%rbx,%rdx,4),%edi
  sub    %edx,%esi
  add    %r8,%rsi
  jmp    L16
  nopl   0x0(%rax)
L25:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L56
L16:
  mov    -0x4(%rbx,%rdx,4),%ecx
  add    %edi,%ecx
  cmp    %ebp,%ecx
  jne    L25
  mov    %r10d,(%rax)
  mov    %edx,0x4(%rax)
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %r8,%rdx
  jmp    L54
```

assistant: ```c
int *twoSum(int numbers[], int n, int target) {
  int i = 0;
  int j = 0;
  int *ptr = (int *)malloc(sizeof(int) * 2);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (numbers[i] + numbers[j] == target) {
        ptr[0] = i + 1;
        ptr[1] = j + 1;
        return ptr;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L15
  lea    0x1(%r12),%r9d
  mov    $0x2,%edx
L21:
  lea    -0x1(%rdx),%r10d
  cmp    %r9,%rdx
  je     L15
  mov    %r12d,%esi
  lea    0x1(%rdx),%r8
  mov    -0x8(%rbx,%rdx,4),%edi
  sub    %edx,%esi
  add    %r8,%rsi
  jmp    L36
  nopl   0x0(%rax)
L22:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L25
L36:
  mov    -0x4(%rbx,%rdx,4),%ecx
  add    %edi,%ecx
  cmp    %ebp,%ecx
  jne    L22
  mov    %r10d,(%rax)
  mov    %edx,0x4(%rax)
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %r8,%rdx
  jmp    L21
```

assistant: ```c
int *twoSum(int numbers[], int n, int target) {
  int i = 0;
  int j = 0;
  int *ptr = (int *)malloc(sizeof(int) * 2);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (numbers[i] + numbers[j] == target) {
        ptr[0] = i + 1;
        ptr[1] = j + 1;
        return ptr;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D6: Icaro Harry


tool: D4: pause

assistant: ```c
void main() {
  printf("Icaro Harry\n");
  system("pause");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D12: Icaro Harry


tool: D3: pause

assistant: ```c
void main() {
  printf("Icaro Harry\n");
  system("pause");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <system@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D11: Icaro Harry


tool: D3: pause

assistant: ```c
void main() {
  printf("Icaro Harry\n");
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <system@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D3: Icaro Harry


tool: D10: pause

assistant: ```c
void main() {
  printf("Icaro Harry\n");
  system("pause");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L28:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L37
  mov    $0x0,%eax
  jmp    L38
L37:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L28
  mov    $0x1,%eax
L38:
  leave
  ret
```

assistant: ```c
int isnum(char *str) {
  char c;
  int i = 0;
  while ((c = str[i++]) != '\0')
    if (!isdigit(c))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L10:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L4
  movsbl %dil,%edi
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L10
  jmp    L5
L4:
  mov    $0x1,%eax
L5:
  pop    %rbx
  ret
```

assistant: ```c
int isnum(char *str) {
  char c;
  int i = 0;
  while ((c = str[i++]) != '\0')
    if (!isdigit(c))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L3:
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  je     L29
L19:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L3
  mov    $0x1,%eax
L29:
  pop    %rbx
  ret
```

assistant: ```c
int isnum(char *str) {
  char c;
  int i = 0;
  while ((c = str[i++]) != '\0')
    if (!isdigit(c))
      return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L29:
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  je     L27
L5:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L29
  mov    $0x1,%eax
L27:
  pop    %rbx
  ret
```

assistant: ```c
int isnum(char *str) {
  char c;
  int i = 0;
  while ((c = str[i++]) != '\0')
    if (!isdigit(c))
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scalar_triple_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cross_product@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <multiply_vectors@plt>
  nop
  leave
  ret
```

assistant: ```c
void scalar_triple_product(const double *u, const double *v, const double *w, double *out) {
  cross_product(v, w, out);
  multiply_vectors(u, out, out);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scalar_triple_product>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rbx
  mov    %rcx,%rdx
  call   <cross_product@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <multiply_vectors@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void scalar_triple_product(const double *u, const double *v, const double *w, double *out) {
  cross_product(v, w, out);
  multiply_vectors(u, out, out);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scalar_triple_product>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbp
  mov    %rcx,%rdx
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <cross_product@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <multiply_vectors@plt>
```

assistant: ```c
void scalar_triple_product(const double *u, const double *v, const double *w, double *out) {
  cross_product(v, w, out);
  multiply_vectors(u, out, out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<scalar_triple_product>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbp
  mov    %rcx,%rdx
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <cross_product@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <multiply_vectors@plt>
```

assistant: ```c
void scalar_triple_product(const double *u, const double *v, const double *w, double *out) {
  cross_product(v, w, out);
  multiply_vectors(u, out, out);
}
```
user: What is the c source code of the assembly code below:

```asm
<sshbuf_get_bignum1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sshbuf_ptr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sshbuf_len@plt>
  cmp    $0x1,%eax
  jg     L75
  mov    $0xfffffffd,%eax
  jmp    L74
L75:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x7,%eax
  sar    $0x3,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x800,-0x8(%rbp)
  jbe    L43
  mov    $0xfffffff9,%eax
  jmp    L74
L43:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sshbuf_len@plt>
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x2,%rdx
  cmp    %rdx,%rax
  jae    L108
  mov    $0xfffffffd,%eax
  jmp    L74
L108:
  cmpq   $0x0,-0x30(%rbp)
  je     L94
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <BN_bin2bn@plt>
  test   %rax,%rax
  jne    L94
  mov    $0xfffffffe,%eax
  jmp    L74
L94:
  mov    -0x8(%rbp),%rax
  add    $0x2,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sshbuf_consume@plt>
  test   %rax,%rax
  je     L84
  mov    $0xffffffff,%eax
  jmp    L74
L84:
  mov    $0x0,%eax
L74:
  leave
  ret
```

assistant: ```c
int sshbuf_get_bignum1(struct sshbuf *buf, BIGNUM *v) {
  const u_char *d = sshbuf_ptr(buf);
  u_int16_t len_bits;
  size_t len_bytes;
  if (sshbuf_len(buf) < 2)
    return -3;
  len_bits = (((u_int16_t)(((const u_char *)(d))[0]) << 8) | (u_int16_t)(((const u_char *)(d))[1]));
  len_bytes = (len_bits + 7) >> 3;
  if (len_bytes > (16384 / 8))
    return -7;
  if (sshbuf_len(buf) < 2 + len_bytes)
    return -3;
  if (v != NULL && BN_bin2bn(d + 2, len_bytes, v) == NULL)
    return -2;
  if (sshbuf_consume(buf, 2 + len_bytes) != 0) {
    ;
    ;
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sshbuf_get_bignum1>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <sshbuf_ptr@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <sshbuf_len@plt>
  cmp    $0x1,%eax
  jle    L37
  mov    0x0(%rbp),%ebx
  shl    $0x8,%ebx
  or     0x8(%rbp),%ebx
  add    $0x7,%ebx
  sar    $0x3,%ebx
  movslq %ebx,%r14
  cmp    $0x800,%r14
  ja     L80
  mov    %r12,%rdi
  call   <sshbuf_len@plt>
  cltq
  lea    0x2(%r14),%rdx
  cmp    %rdx,%rax
  jb     L18
  test   %r13,%r13
  je     L36
  lea    0x10(%rbp),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <BN_bin2bn@plt>
  test   %rax,%rax
  je     L5
L36:
  lea    0x2(%rbx),%esi
  mov    %r12,%rdi
  call   <sshbuf_consume@plt>
  neg    %rax
  sbb    %eax,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  mov    $0xfffffffd,%eax
  jmp    L1
L80:
  mov    $0xfffffff9,%eax
  jmp    L1
L18:
  mov    $0xfffffffd,%eax
  jmp    L1
L5:
  mov    $0xfffffffe,%eax
  jmp    L1
```

assistant: ```c
int sshbuf_get_bignum1(struct sshbuf *buf, BIGNUM *v) {
  const u_char *d = sshbuf_ptr(buf);
  u_int16_t len_bits;
  size_t len_bytes;
  if (sshbuf_len(buf) < 2)
    return -3;
  len_bits = (((u_int16_t)(((const u_char *)(d))[0]) << 8) | (u_int16_t)(((const u_char *)(d))[1]));
  len_bytes = (len_bits + 7) >> 3;
  if (len_bytes > (16384 / 8))
    return -7;
  if (sshbuf_len(buf) < 2 + len_bytes)
    return -3;
  if (v != NULL && BN_bin2bn(d + 2, len_bytes, v) == NULL)
    return -2;
  if (sshbuf_consume(buf, 2 + len_bytes) != 0) {
    ;
    ;
    return -1;
  }
  return 0;
}
```