ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<transmit_listing>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L28
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <dprintf@plt>
  add    %eax,%r12d
L28:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12d,%edx
  mov    %r14d,%edi
  mov    $0xc8,%esi
  call   <send_control_response@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <closedir@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  pop    %rbx
  mov    %r14d,%edi
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  mov    $0x193,%esi
  pop    %r13
  pop    %r14
  jmp    10c0 <send_control_response@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %s


assistant: ```c
int transmit_listing(char *filename, int data_sock, int control_sock) {
  int err;
  DIR *dir;
  struct dirent *ent;
  int data_length = 0;
  dir = opendir(filename);
  if (dir == NULL) {
    err = send_control_response(control_sock, 403, 0);
    return err;
  }
  while (true) {
    ent = readdir(dir);
    if (ent == NULL) {
      err = send_control_response(control_sock, 200, data_length);
      break;
    }
    data_length += dprintf(data_sock, "%s\n", ent->d_name);
  }
  closedir(dir);
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<transmit_listing>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L0
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <dprintf@plt>
  add    %eax,%r12d
L0:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L29
  mov    %r12d,%edx
  mov    %r14d,%edi
  mov    $0xc8,%esi
  call   <send_control_response@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <closedir@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  mov    %r14d,%edi
  pop    %rbp
  xor    %edx,%edx
  pop    %r12
  mov    $0x193,%esi
  pop    %r13
  pop    %r14
  jmp    10c0 <send_control_response@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: %s


assistant: ```c
int transmit_listing(char *filename, int data_sock, int control_sock) {
  int err;
  DIR *dir;
  struct dirent *ent;
  int data_length = 0;
  dir = opendir(filename);
  if (dir == NULL) {
    err = send_control_response(control_sock, 403, 0);
    return err;
  }
  while (true) {
    ent = readdir(dir);
    if (ent == NULL) {
      err = send_control_response(control_sock, 200, data_length);
      break;
    }
    data_length += dprintf(data_sock, "%s\n", ent->d_name);
  }
  closedir(dir);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<module_notfound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: Error!
Module %s not found!

assistant: ```c
void module_notfound(const char *module) {
  printf("Error!\nModule %s not found!", module);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<module_notfound>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: Error!
Module %s not found!

assistant: ```c
void module_notfound(const char *module) {
  printf("Error!\nModule %s not found!", module);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<module_notfound>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: Error!
Module %s not found!

assistant: ```c
void module_notfound(const char *module) {
  printf("Error!\nModule %s not found!", module);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<module_notfound>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: Error!
Module %s not found!

assistant: ```c
void module_notfound(const char *module) {
  printf("Error!\nModule %s not found!", module);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L19:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int *a, int argc) {
  int b;
  int i;
  int d, e;
  for (i = 0; i < argc; i++) {
    e = *a;
  }
  return d + e;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    (%rdi),%eax
  mov    $0x0,%edx
L4:
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L4
L17:
  ret
```

assistant: ```c
int main(int *a, int argc) {
  int b;
  int i;
  int d, e;
  for (i = 0; i < argc; i++) {
    e = *a;
  }
  return d + e;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    (%rdi),%eax
L4:
  ret
```

assistant: ```c
int main(int *a, int argc) {
  int b;
  int i;
  int d, e;
  for (i = 0; i < argc; i++) {
    e = *a;
  }
  return d + e;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    (%rdi),%eax
L7:
  ret
```

assistant: ```c
int main(int *a, int argc) {
  int b;
  int i;
  int d, e;
  for (i = 0; i < argc; i++) {
    e = *a;
  }
  return d + e;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L65:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  lea    D43(%rip),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <display_menu@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L29
  movl   $0x1,-0x8(%rbp)
  jmp    L40
L29:
  cmpl   $0x2,-0x4(%rbp)
  jne    L17
  movl   $0x2,-0x8(%rbp)
  jmp    L40
L17:
  cmpl   $0x3,-0x4(%rbp)
  jne    L108
  movl   $0x3,-0x8(%rbp)
  jmp    L40
L108:
  movl   $0xffffffff,-0x8(%rbp)
L40:
  cmpl   $0x0,-0x8(%rbp)
  je     L65
  jmp    L123
L42:
  mov    $0x0,%eax
  call   <task1_main@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x8(%rbp)
L123:
  cmpl   $0x1,-0x8(%rbp)
  je     L42
  jmp    L30
L68:
  mov    $0x0,%eax
  call   <task2_main@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x8(%rbp)
L30:
  cmpl   $0x2,-0x8(%rbp)
  je     L68
  jmp    L45
L12:
  mov    $0x0,%eax
  call   <task3_main@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x8(%rbp)
L45:
  cmpl   $0x3,-0x8(%rbp)
  je     L12
L4:
  cmpl   $0x0,-0x8(%rbp)
  jns    L40
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
datatype: string
name: extract_symbolic_data
arguments: label: D53
datatype: string
name: extract_symbolic_data
arguments: label: D54
datatype: string
name: extract_symbolic_data
arguments: label: D72
datatype: string

tool: D43: 1. Task 1 - Prime Numbers
2. Task 2 - Employee Pay
3. Task 3 - Number Guess Ultra
4. Quit

tool: D53: Lab 5 Main Menu

tool: D54: pause

tool: D72: cls

assistant: ```c
int main(void) {
  int option = 0, lab_task = 0;
  while (lab_task >= 0) {
    while (lab_task == 0) {
      option = display_menu("Lab 5 Main Menu", "1. Task 1 - Prime Numbers\n2. Task 2 - Employee Pay\n3. Task 3 - Number Guess Ultra\n4. Quit", 4, 1);
      if (option == 1) {
        lab_task = 1;
      } else if (option == 2) {
        lab_task = 2;
      } else if (option == 3) {
        lab_task = 3;
      } else {
        lab_task = -1;
      }
    }
    while (lab_task == 1) {
      task1_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 2) {
      task2_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 3) {
      task3_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D19(%rip),%r13
  lea    D2(%rip),%r12
  lea    D46(%rip),%rbx
L66:
  lea    D47(%rip),%rbp
L63:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <display_menu@plt>
  cmp    $0x1,%eax
  je     L14
  cmp    $0x2,%eax
  je     L20
  cmp    $0x3,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  jmp    L54
L14:
  mov    $0x0,%eax
  call   <task1_main@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    $0x0,%eax
L4:
  test   %eax,%eax
  js     L15
  test   %eax,%eax
  je     L63
  cmp    $0x1,%eax
  je     L14
L54:
  cmp    $0x2,%eax
  je     L20
  cmp    $0x3,%eax
  jne    L4
  mov    $0x0,%eax
  call   <task3_main@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D47(%rip),%rdi
  call   <system@plt>
  jmp    L66
L20:
  mov    $0x0,%eax
  call   <task2_main@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  jmp    L4
L15:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D46
type: string
name: disassemble_data
arguments: data_label: D47
type: string

tool: D19: 1. Task 1 - Prime Numbers
2. Task 2 - Employee Pay
3. Task 3 - Number Guess Ultra
4. Quit

tool: D2: Lab 5 Main Menu

tool: D46: pause

tool: D47: cls

assistant: ```c
int main(void) {
  int option = 0, lab_task = 0;
  while (lab_task >= 0) {
    while (lab_task == 0) {
      option = display_menu("Lab 5 Main Menu", "1. Task 1 - Prime Numbers\n2. Task 2 - Employee Pay\n3. Task 3 - Number Guess Ultra\n4. Quit", 4, 1);
      if (option == 1) {
        lab_task = 1;
      } else if (option == 2) {
        lab_task = 2;
      } else if (option == 3) {
        lab_task = 3;
      } else {
        lab_task = -1;
      }
    }
    while (lab_task == 1) {
      task1_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 2) {
      task2_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 3) {
      task3_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L46:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <display_menu@plt>
  cmp    $0x1,%eax
  je     L31
  cmp    $0x2,%eax
  je     L59
  cmp    $0x3,%eax
  je     L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  call   <task1_main@plt>
L32:
  mov    %r13,%rdi
  call   <system@plt>
  mov    %r12,%rdi
  call   <system@plt>
  jmp    L46
  nopl   0x0(%rax)
L59:
  xor    %eax,%eax
  call   <task2_main@plt>
  jmp    L32
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <task3_main@plt>
  mov    %r13,%rdi
  call   <system@plt>
  mov    %r12,%rdi
  call   <system@plt>
  jmp    L46
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D29
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string

tool: D1: pause

tool: D29: cls

tool: D27: 1. Task 1 - Prime Numbers
2. Task 2 - Employee Pay
3. Task 3 - Number Guess Ultra
4. Quit

tool: D28: Lab 5 Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_task = 0;
  while (lab_task >= 0) {
    while (lab_task == 0) {
      option = display_menu("Lab 5 Main Menu", "1. Task 1 - Prime Numbers\n2. Task 2 - Employee Pay\n3. Task 3 - Number Guess Ultra\n4. Quit", 4, 1);
      if (option == 1) {
        lab_task = 1;
      } else if (option == 2) {
        lab_task = 2;
      } else if (option == 3) {
        lab_task = 3;
      } else {
        lab_task = -1;
      }
    }
    while (lab_task == 1) {
      task1_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 2) {
      task2_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 3) {
      task3_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  lea    D32(%rip),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <display_menu@plt>
  cmp    $0x1,%eax
  je     L22
  cmp    $0x2,%eax
  je     L46
  cmp    $0x3,%eax
  je     L51
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  call   <task1_main@plt>
L35:
  mov    %r13,%rdi
  call   <system@plt>
  mov    %r12,%rdi
  call   <system@plt>
  jmp    L47
  nopl   0x0(%rax)
L46:
  xor    %eax,%eax
  call   <task2_main@plt>
  jmp    L35
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  call   <task3_main@plt>
  mov    %r13,%rdi
  call   <system@plt>
  mov    %r12,%rdi
  call   <system@plt>
  jmp    L47
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D38
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string
name: parse_data
arguments: data_label: D32
data_type: string

tool: D13: pause

tool: D38: cls

tool: D25: 1. Task 1 - Prime Numbers
2. Task 2 - Employee Pay
3. Task 3 - Number Guess Ultra
4. Quit

tool: D32: Lab 5 Main Menu

assistant: ```c
int main(void) {
  int option = 0, lab_task = 0;
  while (lab_task >= 0) {
    while (lab_task == 0) {
      option = display_menu("Lab 5 Main Menu", "1. Task 1 - Prime Numbers\n2. Task 2 - Employee Pay\n3. Task 3 - Number Guess Ultra\n4. Quit", 4, 1);
      if (option == 1) {
        lab_task = 1;
      } else if (option == 2) {
        lab_task = 2;
      } else if (option == 3) {
        lab_task = 3;
      } else {
        lab_task = -1;
      }
    }
    while (lab_task == 1) {
      task1_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 2) {
      task2_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
    while (lab_task == 3) {
      task3_main();
      system("pause");
      system("cls");
      lab_task = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    -0x2677b1b0(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        state[0UL] = state[local1] | state[local2];
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 745879451UL) + 100500971UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x3dbc2f18,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        state[0UL] = state[local1] | state[local2];
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 745879451UL) + 100500971UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x3dbc2f18,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        state[0UL] = state[local1] | state[local2];
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 745879451UL) + 100500971UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x3dbc2f18,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        state[local1] |= ((state[local1] | state[local2]) & 31UL) << 4UL;
        state[0UL] = state[local1] | state[local2];
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 745879451UL) + 100500971UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L30
  addl   $0x1,-0x4(%rbp)
  jmp    L13
L30:
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L36
  addl   $0x1,-0x4(%rbp)
  jmp    L21
L36:
  addl   $0x1,-0x8(%rbp)
L21:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int a, int b) {
  if (a == b) {
    a++;
  } else {
    b++;
  }
  if (a == b) {
    a++;
  } else {
    b++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int a, int b) {
  if (a == b) {
    a++;
  } else {
    b++;
  }
  if (a == b) {
    a++;
  } else {
    b++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int a, int b) {
  if (a == b) {
    a++;
  } else {
    b++;
  }
  if (a == b) {
    a++;
  } else {
    b++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int a, int b) {
  if (a == b) {
    a++;
  } else {
    b++;
  }
  if (a == b) {
    a++;
  } else {
    b++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mid_point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: f64

tool: D6: 2

assistant: ```c
void mid_point(double x0, double y0, double x1, double y1, double *mx, double *my) {
  *mx = (x0 + x1) / 2.0;
  *my = (y0 + y1) / 2.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mid_point>:
  endbr64
  addsd  %xmm2,%xmm0
  movsd  D0(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdi)
  addsd  %xmm3,%xmm1
  mulsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void mid_point(double x0, double y0, double x1, double y1, double *mx, double *my) {
  *mx = (x0 + x1) / 2.0;
  *my = (y0 + y1) / 2.0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mid_point>:
  endbr64
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm1
  movsd  D4(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  movsd  %xmm0,(%rdi)
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void mid_point(double x0, double y0, double x1, double y1, double *mx, double *my) {
  *mx = (x0 + x1) / 2.0;
  *my = (y0 + y1) / 2.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<mid_point>:
  endbr64
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm1
  movsd  D9(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  movsd  %xmm0,(%rdi)
  movsd  %xmm1,(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void mid_point(double x0, double y0, double x1, double y1, double *mx, double *my) {
  *mx = (x0 + x1) / 2.0;
  *my = (y0 + y1) / 2.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<keyboard_set_map_any>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L17
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <keyboard_parse_set_pos_row@plt>
  jmp    L2
L17:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <keyboard_parse_set_neg_row@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void keyboard_set_map_any(signed long sym, int row, int col, int shift) {
  if (row >= 0) {
    keyboard_parse_set_pos_row(sym, row, col, shift);
  } else {
    keyboard_parse_set_neg_row(sym, row, col);
  }
}
```