ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<atoi_my>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L20
  cmp    $0xa,%sil
  je     L20
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    D7(%rip),%r13
  lea    D10(%rip),%rbp
L22:
  cmp    $0x2d,%sil
  je     L3
  mov    %esi,%edx
  mov    %r12d,%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  mov    %rbp,%rdi
  lea    -0x30(%rax,%rdx,2),%r12d
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
L3:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L0
  cmp    $0xa,%sil
  jne    L22
L0:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L20:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D7: * line = '%c' and %d;i = %d;


tool: D10: i = %d;


assistant: ```c
int atoi_my(char *line) {
  int i = 0;
  while (*line != '\0' && *line != '\n') {
    if (*line == '-') {
      ;
    } else {
      printf("* line = '%c' and %d;i = %d;\n", *line, *line, i);
      i = *line - '0' + i * 10;
      printf("i = %d;\n", i);
    }
    *line++;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoi_my>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L43
  cmp    $0xa,%sil
  je     L43
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    D17(%rip),%r13
  lea    D16(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L46:
  cmp    $0x2d,%sil
  je     L33
  mov    %r12d,%ecx
  mov    %esi,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  movsbl (%rbx),%esi
  cmp    $0xa,%sil
  je     L59
  test   %sil,%sil
  jne    L46
L59:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L33:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L59
  cmp    $0xa,%sil
  jne    L46
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L43:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D17: * line = '%c' and %d;i = %d;


tool: D16: i = %d;


assistant: ```c
int atoi_my(char *line) {
  int i = 0;
  while (*line != '\0' && *line != '\n') {
    if (*line == '-') {
      ;
    } else {
      printf("* line = '%c' and %d;i = %d;\n", *line, *line, i);
      i = *line - '0' + i * 10;
      printf("i = %d;\n", i);
    }
    *line++;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L26:
  addl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L10
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <tar@plt>
  mov    %eax,-0x8(%rbp)
L5:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L26
  nop
  nop
  leave
  ret
```

assistant: ```c
void bug(int q, int bcount) {
  int j = 0;
  int outgo = 0;
  while (j != -1) {
    outgo++;
    if (outgo > q - 1)
      outgo = q - 1;
    j = tar(outgo * bcount);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bug>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  lea    -0x1(%rdi),%r13d
L3:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  cmovge %r13d,%ebx
  mov    %ebx,%edi
  imul   %r12d,%edi
  call   <tar@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bug(int q, int bcount) {
  int j = 0;
  int outgo = 0;
  while (j != -1) {
    outgo++;
    if (outgo > q - 1)
      outgo = q - 1;
    j = tar(outgo * bcount);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bug>:
  endbr64
  push   %r13
  lea    -0x1(%rdi),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  cmovge %r13d,%ebx
  mov    %ebx,%edi
  imul   %r12d,%edi
  call   <tar@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bug(int q, int bcount) {
  int j = 0;
  int outgo = 0;
  while (j != -1) {
    outgo++;
    if (outgo > q - 1)
      outgo = q - 1;
    j = tar(outgo * bcount);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bug>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nop
L19:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jl     L12
  lea    -0x1(%rbp),%ebx
L12:
  mov    %ebx,%edi
  imul   %r12d,%edi
  call   <tar@plt>
  cmp    $0xffffffff,%eax
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bug(int q, int bcount) {
  int j = 0;
  int outgo = 0;
  while (j != -1) {
    outgo++;
    if (outgo > q - 1)
      outgo = q - 1;
    j = tar(outgo * bcount);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<atflags_bsd_to_linux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L9
  orl    $0x100,-0x4(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L18
  orl    $0x200,-0x4(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L27
  orl    $0x400,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atflags_bsd_to_linux(int flags) {
  int linux_flags = 0;
  if (flags & 0x20)
    linux_flags |= 0x100;
  if (flags & 0x80)
    linux_flags |= 0x200;
  if (flags & 0x40)
    linux_flags |= 0x400;
  return linux_flags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atflags_bsd_to_linux>:
  endbr64
  lea    0x0(,%rdi,8),%eax
  and    $0x100,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x80,%dil
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x4,%dh
  test   $0x40,%dil
  cmovne %edx,%eax
  ret
```

assistant: ```c
int atflags_bsd_to_linux(int flags) {
  int linux_flags = 0;
  if (flags & 0x20)
    linux_flags |= 0x100;
  if (flags & 0x80)
    linux_flags |= 0x200;
  if (flags & 0x40)
    linux_flags |= 0x400;
  return linux_flags;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atflags_bsd_to_linux>:
  endbr64
  lea    0x0(,%rdi,8),%eax
  and    $0x100,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x80,%dil
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x4,%dh
  and    $0x40,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int atflags_bsd_to_linux(int flags) {
  int linux_flags = 0;
  if (flags & 0x20)
    linux_flags |= 0x100;
  if (flags & 0x80)
    linux_flags |= 0x200;
  if (flags & 0x40)
    linux_flags |= 0x400;
  return linux_flags;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atflags_bsd_to_linux>:
  endbr64
  lea    0x0(,%rdi,8),%eax
  and    $0x100,%eax
  mov    %eax,%edx
  or     $0x2,%dh
  test   $0x80,%dil
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x4,%dh
  and    $0x40,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int atflags_bsd_to_linux(int flags) {
  int linux_flags = 0;
  if (flags & 0x20)
    linux_flags |= 0x100;
  if (flags & 0x80)
    linux_flags |= 0x200;
  if (flags & 0x40)
    linux_flags |= 0x400;
  return linux_flags;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<byteswap_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <byteswap4@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
float byteswap_float(float num) {
  uint32_t answer = 0;
  memcpy(&answer, &num, 4);
  answer = byteswap4(answer);
  memcpy(&num, &answer, 4);
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<byteswap_float>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rbx
  lea    0x14(%rsp),%rbp
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  call   <byteswap4@plt>
  movss  %xmm0,0x14(%rsp)
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float byteswap_float(float num) {
  uint32_t answer = 0;
  memcpy(&answer, &num, 4);
  answer = byteswap4(answer);
  memcpy(&num, &answer, 4);
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<byteswap_float>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x28,%rsp
  lea    0xc(%rsp),%rbp
  lea    0x14(%rsp),%r12
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x14(%rsp)
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  call   <byteswap4@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0x14(%rsp)
  call   <memcpy@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float byteswap_float(float num) {
  uint32_t answer = 0;
  memcpy(&answer, &num, 4);
  answer = byteswap4(answer);
  memcpy(&num, &answer, 4);
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<byteswap_float>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x28,%rsp
  lea    0xc(%rsp),%rbp
  lea    0x14(%rsp),%r12
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x14(%rsp)
  call   <memcpy@plt>
  movss  0x14(%rsp),%xmm0
  call   <byteswap4@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0x14(%rsp)
  call   <memcpy@plt>
  movss  0xc(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float byteswap_float(float num) {
  uint32_t answer = 0;
  memcpy(&answer, &num, 4);
  answer = byteswap4(answer);
  memcpy(&num, &answer, 4);
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<req_linha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  nop
L3:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *req_linha() {
  char *l = malloc(sizeof(char) * 256);
  while (!fgets(l, 256, stdin))
    ;
  l[strlen(l) - 1] = '\0';
  return (unsigned char *)l;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<req_linha>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    D5(%rip),%rbp
L7:
  mov    0x0(%rbp),%edx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L7
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *req_linha() {
  char *l = malloc(sizeof(char) * 256);
  while (!fgets(l, 256, stdin))
    ;
  l[strlen(l) - 1] = '\0';
  return (unsigned char *)l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<req_linha>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    D8(%rip),%rbx
  mov    %rax,%r12
  nop
L1:
  mov    (%rbx),%edx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L1
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned char *req_linha() {
  char *l = malloc(sizeof(char) * 256);
  while (!fgets(l, 256, stdin))
    ;
  l[strlen(l) - 1] = '\0';
  return (unsigned char *)l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<req_linha>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    D6(%rip),%rbx
  mov    %rax,%r12
  nop
L5:
  mov    (%rbx),%edx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %eax,%eax
  je     L5
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned char *req_linha() {
  char *l = malloc(sizeof(char) * 256);
  while (!fgets(l, 256, stdin))
    ;
  l[strlen(l) - 1] = '\0';
  return (unsigned char *)l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L12
L16:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <func>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltd
  idiv   %ecx
L12:
  leave
  ret
```

assistant: ```c
int func(int i) {
  if (i == 0)
    return 1;
  else
    return (i / func(i - 1));
}
```
user: What is the c source code of the assembly code below?

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L9
  ret
L9:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <func>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pop    %rbx
  ret
```

assistant: ```c
int func(int i) {
  if (i == 0)
    return 1;
  else
    return (i / func(i - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L18
  ret
  xchg   %ax,%ax
L18:
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x1,%ebp
  jne    L38
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %edi,%r12d
  sub    $0x2,%r12d
  jne    L20
L14:
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %ebp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  lea    -0x3(%rdi),%edi
  call   <func>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  mov    %ebp,%eax
  cltd
  idiv   %r12d
  mov    %eax,%ebp
  jmp    L14
```

assistant: ```c
int func(int i) {
  if (i == 0)
    return 1;
  else
    return (i / func(i - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L1
  ret
  xchg   %ax,%ax
L1:
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x1,%ebp
  jne    L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %edi,%r12d
  sub    $0x2,%r12d
  jne    L7
L6:
  mov    %ebx,%eax
  pop    %rbx
  cltd
  idiv   %ebp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    -0x3(%rdi),%edi
  call   <func>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  mov    %ebp,%eax
  cltd
  idiv   %r12d
  mov    %eax,%ebp
  jmp    L6
```

assistant: ```c
int func(int i) {
  if (i == 0)
    return 1;
  else
    return (i / func(i - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aio_suspend64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int aio_suspend64(const struct aiocb64 *const list[], int nent, const struct timespec *timeout) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aio_suspend64>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int aio_suspend64(const struct aiocb64 *const list[], int nent, const struct timespec *timeout) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aio_suspend64>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int aio_suspend64(const struct aiocb64 *const list[], int nent, const struct timespec *timeout) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aio_suspend64>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int aio_suspend64(const struct aiocb64 *const list[], int nent, const struct timespec *timeout) {
  errno = ENOSYS;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CTRL_REGSC_BITSET_BW1000>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <switch_on_bits@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x60,%esi
  mov    %rax,%rdi
  call   <switch_off_bits@plt>
  nop
  leave
  ret
```

assistant: ```c
void CTRL_REGSC_BITSET_BW1000(unsigned char *data) {
  switch_on_bits(data, (0x80));
  switch_off_bits(data, (0x40 | 0x20));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CTRL_REGSC_BITSET_BW1000>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x80,%esi
  call   <switch_on_bits@plt>
  mov    $0x60,%esi
  mov    %rbx,%rdi
  call   <switch_off_bits@plt>
  pop    %rbx
  ret
```

assistant: ```c
void CTRL_REGSC_BITSET_BW1000(unsigned char *data) {
  switch_on_bits(data, (0x80));
  switch_off_bits(data, (0x40 | 0x20));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CTRL_REGSC_BITSET_BW1000>:
  endbr64
  push   %rbp
  mov    $0x80,%esi
  mov    %rdi,%rbp
  call   <switch_on_bits@plt>
  mov    %rbp,%rdi
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <switch_off_bits@plt>
```

assistant: ```c
void CTRL_REGSC_BITSET_BW1000(unsigned char *data) {
  switch_on_bits(data, (0x80));
  switch_off_bits(data, (0x40 | 0x20));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CTRL_REGSC_BITSET_BW1000>:
  endbr64
  push   %rbp
  mov    $0x80,%esi
  mov    %rdi,%rbp
  call   <switch_on_bits@plt>
  mov    %rbp,%rdi
  mov    $0x60,%esi
  pop    %rbp
  jmp    1060 <switch_off_bits@plt>
```

assistant: ```c
void CTRL_REGSC_BITSET_BW1000(unsigned char *data) {
  switch_on_bits(data, (0x80));
  switch_off_bits(data, (0x40 | 0x20));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lock add %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lock add %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int *p, int a) {
  __atomic_fetch_add(&p, a, 0);
  __atomic_add_fetch(&p, a, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  movslq %esi,%rsi
  lock add %rsi,-0x8(%rsp)
  lock add %rsi,-0x8(%rsp)
  ret
```

assistant: ```c
void foo(int *p, int a) {
  __atomic_fetch_add(&p, a, 0);
  __atomic_add_fetch(&p, a, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,-0x8(%rsp)
  lock add %rsi,-0x8(%rsp)
  lock add %rsi,-0x8(%rsp)
  ret
```

assistant: ```c
void foo(int *p, int a) {
  __atomic_fetch_add(&p, a, 0);
  __atomic_add_fetch(&p, a, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<evalChunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %esi,-0xec(%rbp)
  mov    %edx,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xec(%rbp),%eax
  mov    %eax,-0xd8(%rbp)
  movl   $0x0,-0xd4(%rbp)
  jmp    L27
L17:
  mov    -0xd8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xe8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  addl   $0x1,-0xd4(%rbp)
  addl   $0x1,-0xd8(%rbp)
L27:
  mov    -0xd8(%rbp),%eax
  cmp    -0xf0(%rbp),%eax
  jle    L17
  mov    -0xd4(%rbp),%eax
  cltq
  movb   $0x0,-0xd0(%rbp,%rax,1)
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <eval@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double evalChunk(char str[200], int start, int end) {
  char exprstr[200];
  int i = start, j = 0;
  for (i = i; i <= end; i++) {
    exprstr[j] = str[i];
    j++;
  }
  exprstr[j] = '\0';
  return eval(exprstr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<evalChunk>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  cmp    %edx,%esi
  jg     L9
  movslq %esi,%rcx
  mov    %rcx,%rax
  mov    %rsp,%r8
  sub    %rcx,%r8
L18:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jge    L18
  sub    %esi,%edx
  add    $0x1,%edx
L26:
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  mov    %rsp,%rdi
  call   <eval@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0xd8,%rsp
  ret
L9:
  mov    $0x0,%edx
  jmp    L26
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double evalChunk(char str[200], int start, int end) {
  char exprstr[200];
  int i = start, j = 0;
  for (i = i; i <= end; i++) {
    exprstr[j] = str[i];
    j++;
  }
  exprstr[j] = '\0';
  return eval(exprstr);
}
```