ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x30(%rsp),%rbp
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  movl   $0x1,0xc(%rsp)
  jmp    L3
  nopl   0x0(%rax)
L101:
  mov    %r13,%r15
L3:
  mov    %rbx,%rdi
  mov    %r15d,%r12d
  call   <strlen@plt>
  cmp    %r15d,%eax
  jle    L39
  movzbl (%rbx,%r15,1),%eax
  lea    0x1(%r15),%r13
  cmp    %al,0x30(%rsp)
  jne    L101
  movslq 0xc(%rsp),%r15
  mov    %r13,%r14
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L67:
  movzbl (%rbx,%r14,1),%ecx
  movzbl 0x0(%rbp,%r15,1),%eax
  add    $0x1,%r14
  add    $0x1,%r15
  cmp    %al,%cl
  jne    L35
L7:
  mov    %rbp,%rdi
  mov    %r15d,0xc(%rsp)
  call   <strlen@plt>
  add    %r12d,%eax
  cmp    %r14d,%eax
  jg     L67
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    0xc(%rsp),%eax
  jne    L101
L13:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  call   <strlen@plt>
  cmp    0xc(%rsp),%eax
  jne    L101
  jmp    L13
  nopl   0x0(%rax)
L39:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
L75:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L82
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D18: Saisir string:

tool: D20: saisir substring:

tool: D22: OK DONE

tool: D5: Not Exist

assistant: ```c
int main() {
  int i, j, k = 1;
  char str[20], sub[20];
  printf("Saisir string:");
  gets(str);
  printf("saisir substring:");
  gets(sub);
  for (i = 0; i < strlen(str); i++) {
    if (sub[0] == str[i]) {
      for (j = i + 1; j < strlen(sub) + i; j++) {
        if (str[j] == sub[k]) {
          k++;
        } else {
          k = 0;
          break;
        }
      }
      if (k == strlen(sub)) {
        printf("OK DONE");
        return 0;
      }
    }
  }
  printf("Not Exist");
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L32
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L32:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L2
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BubbleSort(int *a, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int tmp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = tmp;
      }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BubbleSort>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  jmp    L4
L66:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L28
L29:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L66
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L66
L64:
  sub    $0x1,%r8d
  cmp    $0xffffffff,%r8d
  jne    L4
L16:
  ret
L28:
  sub    $0x1,%r8d
L4:
  test   %r8d,%r8d
  jle    L64
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L29
```

assistant: ```c
void BubbleSort(int *a, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int tmp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = tmp;
      }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BubbleSort>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi),%r9
  test   %edx,%edx
  je     L46
  nopl   0x0(%rax,%rax,1)
L33:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L9:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L34
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L34:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
  mov    %r8d,%edx
  test   %edx,%edx
  jne    L33
L46:
  ret
L21:
  ret
```

assistant: ```c
void BubbleSort(int *a, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int tmp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = tmp;
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BubbleSort>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi),%r9
  test   %eax,%eax
  je     L36
  nopl   0x0(%rax,%rax,1)
L47:
  sub    $0x1,%eax
  mov    %rdi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rsi
  nopl   (%rax)
L40:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L6
  movq   %xmm1,(%rdx)
L6:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L40
  mov    %r8d,%eax
  test   %eax,%eax
  jne    L47
L36:
  ret
L17:
  ret
```

assistant: ```c
void BubbleSort(int *a, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n - i - 1; j++)
      if (a[j] > a[j + 1]) {
        int tmp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = tmp;
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  je     L85
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  mov    $0x0,%eax
  jmp    L13
L85:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L8
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
L8:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L11
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L91
L11:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L47
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L91
L47:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L88
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L91
L88:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L123
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L91
L123:
  mov    $0x0,%eax
  jmp    L13
L91:
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4) {
    ft_putchar('\n');
    return (0);
  }
  int nb;
  int nb2;
  nb = atoi(argv[1]);
  nb2 = atoi(argv[3]);
  if ((argv[2][0]) == 43) {
    printf("%d\n", nb + nb2);
    return (0);
  } else if ((argv[2][0]) == 45) {
    printf("%d\n", (nb - nb2));
  } else if ((argv[2][0]) == 42) {
    printf("%d\n", (nb * nb2));
  } else if ((argv[2][0]) == 47) {
    printf("%d\n", (nb / nb2));
  } else if ((argv[2][0]) == 37) {
    printf("%d\n", (nb % nb2));
  } else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  je     L9
  mov    $0xa,%edi
  call   <ft_putchar@plt>
L53:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  mov    0x10(%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L27
  cmp    $0x2d,%dl
  je     L58
  cmp    $0x2a,%dl
  je     L102
  cmp    $0x2f,%dl
  je     L82
  cmp    $0x25,%dl
  jne    L53
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L27:
  lea    0x0(%rbp,%rcx,1),%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L58:
  mov    %ebp,%esi
  sub    %ecx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L102:
  mov    %ebp,%esi
  imul   %ecx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L53
L82:
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L53
```

tool_calls: name: unpack_data
arguments: data_tag: D33
datatype: string

tool: D33: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4) {
    ft_putchar('\n');
    return (0);
  }
  int nb;
  int nb2;
  nb = atoi(argv[1]);
  nb2 = atoi(argv[3]);
  if ((argv[2][0]) == 43) {
    printf("%d\n", nb + nb2);
    return (0);
  } else if ((argv[2][0]) == 45) {
    printf("%d\n", (nb - nb2));
  } else if ((argv[2][0]) == 42) {
    printf("%d\n", (nb * nb2));
  } else if ((argv[2][0]) == 47) {
    printf("%d\n", (nb / nb2));
  } else if ((argv[2][0]) == 37) {
    printf("%d\n", (nb % nb2));
  } else
    return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  je     L76
  mov    $0xa,%edi
  call   <ft_putchar@plt>
L103:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L76:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%ecx
  mov    0x10(%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L12
  cmp    $0x2d,%dl
  je     L38
  cmp    $0x2a,%dl
  je     L59
  cmp    $0x2f,%dl
  je     L16
  cmp    $0x25,%dl
  jne    L103
  mov    %ebp,%eax
  lea    D18(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  jmp    L103
L12:
  lea    0x0(%rbp,%rcx,1),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L103
L38:
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  sub    %ecx,%esi
  call   <printf@plt>
  jmp    L103
L59:
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  imul   %ecx,%esi
  call   <printf@plt>
  jmp    L103
L16:
  mov    %ebp,%eax
  lea    D18(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L103
```

tool_calls: name: read_data
arguments: data_tag: D18
type: string

tool: D18: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4) {
    ft_putchar('\n');
    return (0);
  }
  int nb;
  int nb2;
  nb = atoi(argv[1]);
  nb2 = atoi(argv[3]);
  if ((argv[2][0]) == 43) {
    printf("%d\n", nb + nb2);
    return (0);
  } else if ((argv[2][0]) == 45) {
    printf("%d\n", (nb - nb2));
  } else if ((argv[2][0]) == 42) {
    printf("%d\n", (nb * nb2));
  } else if ((argv[2][0]) == 47) {
    printf("%d\n", (nb / nb2));
  } else if ((argv[2][0]) == 37) {
    printf("%d\n", (nb % nb2));
  } else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  je     L30
  mov    $0xa,%edi
  call   <ft_putchar@plt>
L82:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%ecx
  mov    0x10(%rbx),%rax
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  je     L94
  cmp    $0x2d,%dl
  je     L46
  cmp    $0x2a,%dl
  je     L3
  cmp    $0x2f,%dl
  je     L108
  cmp    $0x25,%dl
  jne    L82
  mov    %ebp,%eax
  lea    D4(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %edx,%esi
  call   <printf@plt>
  jmp    L82
L94:
  lea    0x0(%rbp,%rcx,1),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L46:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  sub    %ecx,%esi
  call   <printf@plt>
  jmp    L82
L3:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  imul   %ecx,%esi
  call   <printf@plt>
  jmp    L82
L108:
  mov    %ebp,%eax
  lea    D4(%rip),%rdi
  cltd
  idiv   %ecx
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L82
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 4) {
    ft_putchar('\n');
    return (0);
  }
  int nb;
  int nb2;
  nb = atoi(argv[1]);
  nb2 = atoi(argv[3]);
  if ((argv[2][0]) == 43) {
    printf("%d\n", nb + nb2);
    return (0);
  } else if ((argv[2][0]) == 45) {
    printf("%d\n", (nb - nb2));
  } else if ((argv[2][0]) == 42) {
    printf("%d\n", (nb * nb2));
  } else if ((argv[2][0]) == 47) {
    printf("%d\n", (nb / nb2));
  } else if ((argv[2][0]) == 37) {
    printf("%d\n", (nb % nb2));
  } else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mutilsStrncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x20(%rbp),%rbx
  jmp    L28
L37:
  nop
  add    $0x1,%rbx
L28:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L37
  mov    -0x28(%rbp),%r12
  mov    -0x2c(%rbp),%r13d
  jmp    L40
L17:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L40:
  movzbl (%r12),%eax
  test   %al,%al
  je     L36
  sub    $0x1,%r13d
  test   %r13d,%r13d
  jns    L17
L36:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *mutilsStrncat(char *dst, char *src, int n) {
  register char *dscan, *sscan;
  register int count;
  for (dscan = dst; *dscan != '\0'; dscan++)
    continue;
  sscan = src;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return (dst);
}
```
user: What is the c source code of the assembly code below?

```asm
<mutilsStrncat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  cmpb   $0x0,(%rdi)
  jne    L40
L34:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L54
  test   %edx,%edx
  jle    L54
  lea    -0x1(%rdx),%edx
  lea    0x1(%rcx,%rdx,1),%rdx
L50:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L54
  cmp    %rdx,%rcx
  jne    L50
  mov    %rdx,%rcx
L54:
  movb   $0x0,(%rcx)
  ret
L40:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L34
  jmp    L40
```

assistant: ```c
char *mutilsStrncat(char *dst, char *src, int n) {
  register char *dscan, *sscan;
  register int count;
  for (dscan = dst; *dscan != '\0'; dscan++)
    continue;
  sscan = src;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return (dst);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mutilsStrncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  jne    L50
L61:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L58
  test   %edx,%edx
  jle    L58
  sub    $0x1,%edx
  lea    0x1(%rcx,%rdx,1),%rdx
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L39:
  cmp    %rdx,%rcx
  je     L58
L52:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L39
L58:
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L50:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L61
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L61
  jmp    L50
```

assistant: ```c
char *mutilsStrncat(char *dst, char *src, int n) {
  register char *dscan, *sscan;
  register int count;
  for (dscan = dst; *dscan != '\0'; dscan++)
    continue;
  sscan = src;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return (dst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mutilsStrncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  jne    L74
L71:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L61
  test   %edx,%edx
  jle    L61
  sub    $0x1,%edx
  lea    0x1(%rcx,%rdx,1),%rdx
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L24:
  cmp    %rdx,%rcx
  je     L61
L37:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L24
L61:
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L74:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L71
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L71
  jmp    L74
```

assistant: ```c
char *mutilsStrncat(char *dst, char *src, int n) {
  register char *dscan, *sscan;
  register int count;
  for (dscan = dst; *dscan != '\0'; dscan++)
    continue;
  sscan = src;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return (dst);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tegerPower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tegerPower(a, b) {
  int sum = 1;
  int i;
  for (i = 1; i <= b; i++) {
    sum = sum * a;
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tegerPower>:
  endbr64
  test   %esi,%esi
  jle    L29
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%edx
L6:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L6
L1:
  mov    %edx,%eax
  ret
L29:
  mov    $0x1,%edx
  jmp    L1
```

assistant: ```c
int tegerPower(a, b) {
  int sum = 1;
  int i;
  for (i = 1; i <= b; i++) {
    sum = sum * a;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tegerPower>:
  endbr64
  test   %esi,%esi
  jle    L13
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L3
  mov    %r8d,%eax
  ret
  nop
L13:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tegerPower(a, b) {
  int sum = 1;
  int i;
  for (i = 1; i <= b; i++) {
    sum = sum * a;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<tegerPower>:
  endbr64
  test   %esi,%esi
  jle    L2
  add    $0x1,%esi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L7
  mov    %r8d,%eax
  ret
  nop
L2:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int tegerPower(a, b) {
  int sum = 1;
  int i;
  for (i = 1; i <= b; i++) {
    sum = sum * a;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ext3level2pct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    $0x3f,%edx
  cmp    %dl,%al
  cmova  %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edx
  lea    D0(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ext3level2pct(unsigned char level) {
  static unsigned char table[64] = {0, 12, 13, 15, 15, 17, 18, 20, 21, 22, 23, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 40, 41, 43, 44, 46, 48, 50, 51, 53, 54, 56, 58, 60, 61, 63, 64, 66, 67, 69, 71, 73, 74, 76, 77, 79, 80, 82, 83, 85, 86, 88, 88, 90, 91, 92, 93, 95, 96, 97, 98, 99, 100, 100};
  return (int)table[((63u) < (level) ? (63u) : (level))];
}
```
user: What is the c source code of the assembly code below?

```asm
<ext3level2pct>:
  endbr64
  mov    $0x3f,%eax
  cmp    %al,%dil
  cmova  %eax,%edi
  movzbl %dil,%edi
  lea    D5(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: 

assistant: ```c
int ext3level2pct(unsigned char level) {
  static unsigned char table[64] = {0, 12, 13, 15, 15, 17, 18, 20, 21, 22, 23, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 40, 41, 43, 44, 46, 48, 50, 51, 53, 54, 56, 58, 60, 61, 63, 64, 66, 67, 69, 71, 73, 74, 76, 77, 79, 80, 82, 83, 85, 86, 88, 88, 90, 91, 92, 93, 95, 96, 97, 98, 99, 100, 100};
  return (int)table[((63u) < (level) ? (63u) : (level))];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ext3level2pct>:
  endbr64
  mov    $0x3f,%eax
  cmp    %al,%dil
  cmova  %eax,%edi
  lea    D9(%rip),%rax
  movzbl %dil,%edi
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: 

assistant: ```c
int ext3level2pct(unsigned char level) {
  static unsigned char table[64] = {0, 12, 13, 15, 15, 17, 18, 20, 21, 22, 23, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 40, 41, 43, 44, 46, 48, 50, 51, 53, 54, 56, 58, 60, 61, 63, 64, 66, 67, 69, 71, 73, 74, 76, 77, 79, 80, 82, 83, 85, 86, 88, 88, 90, 91, 92, 93, 95, 96, 97, 98, 99, 100, 100};
  return (int)table[((63u) < (level) ? (63u) : (level))];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ext3level2pct>:
  endbr64
  mov    $0x3f,%eax
  cmp    %al,%dil
  cmova  %eax,%edi
  lea    D2(%rip),%rax
  movzbl %dil,%edi
  movzbl (%rax,%rdi,1),%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: 

assistant: ```c
int ext3level2pct(unsigned char level) {
  static unsigned char table[64] = {0, 12, 13, 15, 15, 17, 18, 20, 21, 22, 23, 25, 26, 28, 29, 31, 32, 34, 35, 37, 38, 40, 41, 43, 44, 46, 48, 50, 51, 53, 54, 56, 58, 60, 61, 63, 64, 66, 67, 69, 71, 73, 74, 76, 77, 79, 80, 82, 83, 85, 86, 88, 88, 90, 91, 92, 93, 95, 96, 97, 98, 99, 100, 100};
  return (int)table[((63u) < (level) ? (63u) : (level))];
}
```