ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<flushall>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L28:
  mov    %rbp,%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <ioctl@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L34
  lea    0x3(%rsp),%rbx
L32:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L32
  jmp    L28
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void flushall(void) {
  char cc;
  int ic;
  for (;;) {
    ioctl(0, FIONREAD, &ic);
    if (ic <= 0)
      return;
    while (ic > 0) {
      read(0, &cc, 1);
      --ic;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<flushall>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D0(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x3(%rsp),%rbx
  nopl   (%rax)
L22:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  xor    %edi,%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L37
  nopl   (%rax)
L29:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L29
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void flushall(void) {
  char cc;
  int ic;
  for (;;) {
    ioctl(0, FIONREAD, &ic);
    if (ic <= 0)
      return;
    while (ic > 0) {
      read(0, &cc, 1);
      --ic;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flushall>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D9(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x3(%rsp),%rbx
  nopl   (%rax)
L12:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  xor    %edi,%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L8
  nopl   (%rax)
L3:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L3
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void flushall(void) {
  char cc;
  int ic;
  for (;;) {
    ioctl(0, FIONREAD, &ic);
    if (ic <= 0)
      return;
    while (ic > 0) {
      read(0, &cc, 1);
      --ic;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_multi_ssn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%r9d
  mov    $0x80000000,%r8d
  mov    $0x0,%ecx
  mov    $0xff,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <ssn_ddrt_init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L38
  mov    -0x4(%rbp),%eax
  jmp    L26
L38:
  mov    $0xb49c863c,%r9d
  mov    $0x80000000,%r8d
  mov    $0x0,%ecx
  mov    $0xff,%edx
  mov    $0x2000,%esi
  mov    $0x0,%edi
  call   <ssn_ddrt_init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L20
  mov    -0x4(%rbp),%eax
  jmp    L26
L20:
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
unsigned int check_multi_ssn(const struct training_data *training, unsigned int index) {
  unsigned int rel;
  rel = ssn_ddrt_init((0 << 8), (0 << 12), 0xff, 0, 0x80000000, 0);
  if (rel)
    return rel;
  rel = ssn_ddrt_init((0 << 8), (2 << 12), 0xff, 0, 0x80000000, 0xB49C863C);
  if (rel)
    return rel;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_multi_ssn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r9d
  mov    $0x80000000,%r8d
  mov    $0x0,%ecx
  mov    $0xff,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <ssn_ddrt_init@plt>
  test   %eax,%eax
  je     L13
L0:
  add    $0x8,%rsp
  ret
L13:
  mov    $0xb49c863c,%r9d
  mov    $0x80000000,%r8d
  mov    $0x0,%ecx
  mov    $0xff,%edx
  mov    $0x2000,%esi
  mov    $0x0,%edi
  call   <ssn_ddrt_init@plt>
  jmp    L0
```

assistant: ```c
unsigned int check_multi_ssn(const struct training_data *training, unsigned int index) {
  unsigned int rel;
  rel = ssn_ddrt_init((0 << 8), (0 << 12), 0xff, 0, 0x80000000, 0);
  if (rel)
    return rel;
  rel = ssn_ddrt_init((0 << 8), (2 << 12), 0xff, 0, 0x80000000, 0xB49C863C);
  if (rel)
    return rel;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_multi_ssn>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    $0x80000000,%r8d
  mov    $0xff,%edx
  call   <ssn_ddrt_init@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xb49c863c,%r9d
  mov    $0x80000000,%r8d
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0xff,%edx
  mov    $0x2000,%esi
  add    $0x8,%rsp
  jmp    1050 <ssn_ddrt_init@plt>
```

assistant: ```c
unsigned int check_multi_ssn(const struct training_data *training, unsigned int index) {
  unsigned int rel;
  rel = ssn_ddrt_init((0 << 8), (0 << 12), 0xff, 0, 0x80000000, 0);
  if (rel)
    return rel;
  rel = ssn_ddrt_init((0 << 8), (2 << 12), 0xff, 0, 0x80000000, 0xB49C863C);
  if (rel)
    return rel;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_multi_ssn>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    $0x80000000,%r8d
  mov    $0xff,%edx
  call   <ssn_ddrt_init@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xb49c863c,%r9d
  mov    $0x80000000,%r8d
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0xff,%edx
  mov    $0x2000,%esi
  add    $0x8,%rsp
  jmp    1050 <ssn_ddrt_init@plt>
```

assistant: ```c
unsigned int check_multi_ssn(const struct training_data *training, unsigned int index) {
  unsigned int rel;
  rel = ssn_ddrt_init((0 << 8), (0 << 12), 0xff, 0, 0x80000000, 0);
  if (rel)
    return rel;
  rel = ssn_ddrt_init((0 << 8), (2 << 12), 0xff, 0, 0x80000000, 0xB49C863C);
  if (rel)
    return rel;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pattern_edit_restore_pattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <seq_ctrl_get_scene@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <seq_ctrl_get_first_track@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <song_get_pattern_type@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <pattern_restore_pattern@plt>
  nop
  leave
  ret
```

assistant: ```c
void pattern_edit_restore_pattern(void) {
  int scene, track, pattern;
  scene = seq_ctrl_get_scene();
  track = seq_ctrl_get_first_track();
  pattern = song_get_pattern_type(scene, track);
  pattern_restore_pattern(pattern);
}
```
user: What is the c source code of the assembly code below?

```asm
<pattern_edit_restore_pattern>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <seq_ctrl_get_scene@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <seq_ctrl_get_first_track@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <song_get_pattern_type@plt>
  mov    %eax,%edi
  call   <pattern_restore_pattern@plt>
  pop    %rbx
  ret
```

assistant: ```c
void pattern_edit_restore_pattern(void) {
  int scene, track, pattern;
  scene = seq_ctrl_get_scene();
  track = seq_ctrl_get_first_track();
  pattern = song_get_pattern_type(scene, track);
  pattern_restore_pattern(pattern);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pattern_edit_restore_pattern>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <seq_ctrl_get_scene@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <seq_ctrl_get_first_track@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <song_get_pattern_type@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    10b0 <pattern_restore_pattern@plt>
```

assistant: ```c
void pattern_edit_restore_pattern(void) {
  int scene, track, pattern;
  scene = seq_ctrl_get_scene();
  track = seq_ctrl_get_first_track();
  pattern = song_get_pattern_type(scene, track);
  pattern_restore_pattern(pattern);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pattern_edit_restore_pattern>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <seq_ctrl_get_scene@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <seq_ctrl_get_first_track@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <song_get_pattern_type@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    10b0 <pattern_restore_pattern@plt>
```

assistant: ```c
void pattern_edit_restore_pattern(void) {
  int scene, track, pattern;
  scene = seq_ctrl_get_scene();
  track = seq_ctrl_get_first_track();
  pattern = song_get_pattern_type(scene, track);
  pattern_restore_pattern(pattern);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L7
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L51
L16:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L51
L7:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D19
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D9: %d

tool: D19: Leap Year

tool: D15: Not Leap Year

assistant: ```c
int main() {
  int y;
  scanf("%d", &y);
  if (y % 4 == 0) {
    if ((y % 100 == 0) && (y % 400 == 0))
      printf("Leap Year");
    else
      printf("Not Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   $0x3,%dl
  jne    L43
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rcx
  sar    $0x25,%rcx
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%ecx
  imul   $0x64,%ecx,%ecx
  mov    %edx,%esi
  sub    %ecx,%esi
  sar    $0x27,%rax
  sub    %edi,%eax
  imul   $0x190,%eax,%eax
  sub    %eax,%edx
  or     %edx,%esi
  je     L45
  lea    D9(%rip),%rdi
  call   <printf@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L45:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L43:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D34: %d

tool: D9: Not Leap Year

tool: D7: Leap Year

assistant: ```c
int main() {
  int y;
  scanf("%d", &y);
  if (y % 4 == 0) {
    if ((y % 100 == 0) && (y % 400 == 0))
      printf("Leap Year");
    else
      printf("Not Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %edi,%eax
  mov    %rsi,%rcx
  imul   $0x190,%eax,%eax
  mov    %edx,%esi
  sub    %edi,%ecx
  imul   $0x64,%ecx,%ecx
  sub    %ecx,%esi
  mov    %edx,%ecx
  and    $0x3,%edx
  sub    %eax,%ecx
  mov    %esi,%eax
  or     %ecx,%eax
  or     %edx,%eax
  je     L22
  lea    D8(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string

tool: D11: %d

tool: D8: Not Leap Year

tool: D10: Leap Year

assistant: ```c
int main() {
  int y;
  scanf("%d", &y);
  if (y % 4 == 0) {
    if ((y % 100 == 0) && (y % 400 == 0))
      printf("Leap Year");
    else
      printf("Not Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %edi,%eax
  mov    %rsi,%rcx
  imul   $0x190,%eax,%eax
  mov    %edx,%esi
  sub    %edi,%ecx
  imul   $0x64,%ecx,%ecx
  sub    %ecx,%esi
  mov    %edx,%ecx
  and    $0x3,%edx
  sub    %eax,%ecx
  mov    %esi,%eax
  or     %ecx,%eax
  or     %edx,%eax
  je     L5
  lea    D12(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D25: %d

tool: D12: Not Leap Year

tool: D0: Leap Year

assistant: ```c
int main() {
  int y;
  scanf("%d", &y);
  if (y % 4 == 0) {
    if ((y % 100 == 0) && (y % 400 == 0))
      printf("Leap Year");
    else
      printf("Not Leap Year");
  } else
    printf("Not Leap Year");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L2
L24:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L27
L28:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L27:
  cmpl   $0x2,-0x14(%rbp)
  jle    L28
  addl   $0x1,-0x18(%rbp)
L2:
  cmpl   $0x6,-0x18(%rbp)
  jle    L24
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string

tool: D19: dsemch

tool: D4: # c::%s:len=%d


tool: D28: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsemch", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D11(%rip),%r15
  jmp    L3
L39:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L0
L3:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L28:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L28
  jmp    L39
L0:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D21
type_guessed: string

tool: D11: dsemch

tool: D19: # c::%s:len=%d


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsemch", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D13(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L17:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L7:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L7
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L17
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D20
type: string

tool: D13: dsemch

tool: D22: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsemch", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```