ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_profit_one_transaction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L44:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L26
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L3
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L3:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_profit_one_transaction(int *prices, int pricesSize) {
  int min_price_seen = prices[0];
  int max_profit = 0;
  for (int p = 1; p < pricesSize; p++) {
    if (prices[p] < min_price_seen)
      min_price_seen = prices[p];
    else if (prices[p] - min_price_seen > max_profit)
      max_profit = prices[p] - min_price_seen;
  }
  return max_profit;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<max_profit_one_transaction>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0x1,%esi
  jle    L21
  lea    0x4(%rdi),%rdx
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%rdi
  mov    $0x0,%esi
  jmp    L18
L42:
  mov    %eax,%ecx
L31:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L40
L18:
  mov    (%rdx),%eax
  cmp    %ecx,%eax
  jl     L42
  sub    %ecx,%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  jmp    L31
L21:
  mov    $0x0,%esi
L40:
  mov    %esi,%eax
  ret
```

assistant: ```c
int max_profit_one_transaction(int *prices, int pricesSize) {
  int min_price_seen = prices[0];
  int max_profit = 0;
  for (int p = 1; p < pricesSize; p++) {
    if (prices[p] < min_price_seen)
      min_price_seen = prices[p];
    else if (prices[p] - min_price_seen > max_profit)
      max_profit = prices[p] - min_price_seen;
  }
  return max_profit;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<max_profit_one_transaction>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0x1,%esi
  jle    L6
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rdx
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,4),%rsi
  jmp    L18
  nopl   0x0(%rax)
L17:
  sub    %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  je     L41
L18:
  mov    (%rdx),%eax
  cmp    %ecx,%eax
  jge    L17
  add    $0x4,%rdx
  mov    %eax,%ecx
  cmp    %rsi,%rdx
  jne    L18
L41:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int max_profit_one_transaction(int *prices, int pricesSize) {
  int min_price_seen = prices[0];
  int max_profit = 0;
  for (int p = 1; p < pricesSize; p++) {
    if (prices[p] < min_price_seen)
      min_price_seen = prices[p];
    else if (prices[p] - min_price_seen > max_profit)
      max_profit = prices[p] - min_price_seen;
  }
  return max_profit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<max_profit_one_transaction>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0x1,%esi
  jle    L36
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi),%rdx
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,4),%rsi
  jmp    L13
  nopl   0x0(%rax)
L20:
  sub    %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  je     L19
L13:
  mov    (%rdx),%eax
  cmp    %eax,%ecx
  jle    L20
  add    $0x4,%rdx
  mov    %eax,%ecx
  cmp    %rdx,%rsi
  jne    L13
L19:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int max_profit_one_transaction(int *prices, int pricesSize) {
  int min_price_seen = prices[0];
  int max_profit = 0;
  for (int p = 1; p < pricesSize; p++) {
    if (prices[p] < min_price_seen)
      min_price_seen = prices[p];
    else if (prices[p] - min_price_seen > max_profit)
      max_profit = prices[p] - min_price_seen;
  }
  return max_profit;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7e1,-0x10(%rbp)
  movl   $0x7e2,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: a[0] = %d
a[1] = %d


assistant: ```c
void main(void) {
  int a[2];
  a[0] = 2017;
  a[1] = 2018;
  printf("a[0] = %d\na[1] = %d\n", *a, a[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e2,%edx
  mov    $0x7e1,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: a[0] = %d
a[1] = %d


assistant: ```c
void main(void) {
  int a[2];
  a[0] = 2017;
  a[1] = 2018;
  printf("a[0] = %d\na[1] = %d\n", *a, a[1]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x7e2,%edx
  mov    $0x7e1,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: a[0] = %d
a[1] = %d


assistant: ```c
void main(void) {
  int a[2];
  a[0] = 2017;
  a[1] = 2018;
  printf("a[0] = %d\na[1] = %d\n", *a, a[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x7e2,%edx
  mov    $0x7e1,%esi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: a[0] = %d
a[1] = %d


assistant: ```c
void main(void) {
  int a[2];
  a[0] = 2017;
  a[1] = 2018;
  printf("a[0] = %d\na[1] = %d\n", *a, a[1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fb_PrintSingle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movss  %xmm0,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtss2sd -0x28(%rbp),%xmm1
  movq   %xmm1,%rax
  lea    -0x20(%rbp),%rcx
  mov    $0x1,%edx
  mov    $0x7,%esi
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <fb_hFloat2Str@plt>
  mov    %eax,%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fb_PrintFixString@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void fb_PrintSingle(int fnum, float val, int mask) {
  char buffer[8 + 1 + 9 + 1];
  fb_PrintFixString(fnum, fb_hFloat2Str((double)val, buffer, 7, 0x00000001), mask);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fb_PrintSingle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  cvtss2sd %xmm0,%xmm0
  mov    $0x1,%edx
  mov    $0x7,%esi
  call   <fb_hFloat2Str@plt>
  mov    %eax,%esi
  mov    %ebp,%edx
  mov    %ebx,%edi
  call   <fb_PrintFixString@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fb_PrintSingle(int fnum, float val, int mask) {
  char buffer[8 + 1 + 9 + 1];
  fb_PrintFixString(fnum, fb_hFloat2Str((double)val, buffer, 7, 0x00000001), mask);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fb_PrintSingle>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  mov    %esi,%r12d
  mov    $0x7,%esi
  push   %rbp
  mov    %edi,%ebp
  cvtss2sd %xmm0,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fb_hFloat2Str@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <fb_PrintFixString@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fb_PrintSingle(int fnum, float val, int mask) {
  char buffer[8 + 1 + 9 + 1];
  fb_PrintFixString(fnum, fb_hFloat2Str((double)val, buffer, 7, 0x00000001), mask);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fb_PrintSingle>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  mov    %esi,%r12d
  mov    $0x7,%esi
  push   %rbp
  mov    %edi,%ebp
  cvtss2sd %xmm0,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fb_hFloat2Str@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <fb_PrintFixString@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fb_PrintSingle(int fnum, float val, int mask) {
  char buffer[8 + 1 + 9 + 1];
  fb_PrintFixString(fnum, fb_hFloat2Str((double)val, buffer, 7, 0x00000001), mask);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_table@plt>
  mov    $0x0,%eax
  call   <yyparse@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  init_table();
  return yyparse();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_table@plt>
  mov    $0x0,%eax
  call   <yyparse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  init_table();
  return yyparse();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_table@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <yyparse@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  init_table();
  return yyparse();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_table@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <yyparse@plt>
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int i;
  init_table();
  return yyparse();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x61,-0x9(%rbp)
  jmp    L29
L22:
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x63,%al
  je     L24
  movzbl -0x9(%rbp),%eax
  cmp    $0x64,%al
  jne    L29
L24:
  mov    $0x0,%eax
  call   <rot13@plt>
L29:
  movzbl -0x9(%rbp),%eax
  cmp    $0x71,%al
  jne    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %c

assistant: ```c
int main() {
  char c;
  c = 'a';
  while (c != 'q') {
    scanf("%c", &c);
    if (c == 'c' || c == 'd')
      rot13();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x61,0x7(%rsp)
  lea    D6(%rip),%rbx
L29:
  cmpb   $0x71,0x7(%rsp)
  je     L19
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x63,%eax
  cmp    $0x1,%al
  ja     L29
  mov    $0x0,%eax
  call   <rot13@plt>
  jmp    L29
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string

tool: D6: %c

assistant: ```c
int main() {
  char c;
  c = 'a';
  while (c != 'q') {
    scanf("%c", &c);
    if (c == 'c' || c == 'd')
      rot13();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x61,0x7(%rsp)
  mov    $0x61,%eax
  jmp    L30
  nopl   0x0(%rax)
L49:
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  jbe    L44
L30:
  cmp    $0x71,%al
  jne    L49
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  call   <rot13@plt>
  movzbl 0x7(%rsp),%eax
  jmp    L30
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: %c

assistant: ```c
int main() {
  char c;
  c = 'a';
  while (c != 'q') {
    scanf("%c", &c);
    if (c == 'c' || c == 'd')
      rot13();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x61,0x7(%rsp)
  mov    $0x61,%eax
  jmp    L47
  nopl   0x0(%rax)
L15:
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x63(%rax),%edx
  cmp    $0x1,%dl
  jbe    L34
L47:
  cmp    $0x71,%al
  jne    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  call   <rot13@plt>
  movzbl 0x7(%rsp),%eax
  jmp    L47
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: %c

assistant: ```c
int main() {
  char c;
  c = 'a';
  while (c != 'q') {
    scanf("%c", &c);
    if (c == 'c' || c == 'd')
      rot13();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numberofRoutes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdi),%eax
  cltq
  lea    0x0(,%rax,8),%r9
  imul   %rax,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L55:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L0
  orq    $0x0,-0x8(%rsp,%rax,1)
L0:
  lea    0x7(%rsp),%rdi
  mov    %rdi,%r10
  shr    $0x3,%r10
  and    $0xfffffffffffffff8,%rdi
  test   %r11d,%r11d
  jle    L51
  mov    %r9,%rsi
  shr    $0x3,%rsi
  mov    %r11d,%ebx
  lea    -0x8(%r9),%rcx
  imul   %rsi,%rcx
  add    %rdi,%rcx
  mov    $0x0,%edx
  movslq %r11d,%r8
L27:
  movslq %edx,%rax
  imul   %rsi,%rax
  add    %r8,%rax
  movq   $0x1,(%rdi,%rax,8)
  movq   $0x1,(%rcx,%rdx,8)
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L27
  sub    $0x1,%r11d
  mov    %r9,%rsi
  shr    $0x3,%rsi
  neg    %r9
  lea    0x1(%rsi),%rax
  movslq %r11d,%rdx
  imul   %rdx,%rax
  lea    (%rdi,%rax,8),%r8
  mov    %r11d,%edi
L34:
  mov    %r8,%rax
  mov    %r11d,%ecx
L77:
  mov    0x8(%rax),%rdx
  add    (%rax,%rsi,8),%rdx
  mov    %rdx,(%rax)
  sub    $0x8,%rax
  sub    $0x1,%ecx
  jns    L77
  add    %r9,%r8
  sub    $0x1,%edi
  jns    L34
L51:
  mov    0x0(,%r10,8),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  mov    -0x8(%rbp),%rbx
  leave
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long numberofRoutes(int sizeofSquare) {
  long long square[sizeofSquare + 1][sizeofSquare + 1];
  int i, j;
  for (i = 0; i < sizeofSquare; i++) {
    square[i][sizeofSquare] = 1;
    square[sizeofSquare][i] = 1;
  }
  for (i = sizeofSquare - 1; i >= 0; i--) {
    for (j = sizeofSquare - 1; j >= 0; j--) {
      square[i][j] = square[i + 1][j] + square[i][j + 1];
    }
  }
  return square[0][0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numberofRoutes>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%edx
  movslq %edx,%rdx
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rdx,8),%rax
  mov    %rsp,%rsi
  imul   %rdx,%rdx
  lea    0xf(,%rdx,8),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L52
L46:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L46
L52:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L58
L57:
  lea    0x7(%rsp),%rsi
  mov    %rax,%r8
  lea    -0x1(%rdi),%r9d
  mov    %rsi,%r10
  shr    $0x3,%r8
  and    $0xfffffffffffffff8,%rsi
  shr    $0x3,%r10
  test   %edi,%edi
  jle    L31
  sub    $0x8,%rax
  movslq %edi,%rdi
  xor    %edx,%edx
  imul   %r8,%rax
  lea    (%rsi,%rax,1),%rcx
  xchg   %ax,%ax
L50:
  movslq %edx,%rax
  imul   %r8,%rax
  add    %rdi,%rax
  movq   $0x1,(%rsi,%rax,8)
  movq   $0x1,(%rcx,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L50
L105:
  movslq %r9d,%r11
  mov    %r8,%r13
  mov    %r9d,%ebx
  mov    %r11,%rax
  neg    %r13
  imul   %r8,%rax
  shl    $0x3,%r13
  add    %rdi,%rax
  lea    (%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L85:
  mov    %rdi,%rsi
  mov    %r12,%rax
  mov    %r9d,%ecx
  sub    %r11,%rsi
  imul   %r8,%rsi
  nopl   0x0(%rax,%rax,1)
L108:
  mov    (%rax),%rdx
  sub    $0x1,%ecx
  add    -0x8(%rax,%rsi,8),%rdx
  sub    $0x8,%rax
  mov    %rdx,(%rax)
  cmp    $0xffffffff,%ecx
  jne    L108
  sub    $0x1,%ebx
  add    %r13,%r12
  sub    $0x1,%rdi
  sub    $0x1,%r11
  cmp    $0xffffffff,%ebx
  jne    L85
L20:
  mov    0x0(,%r10,8),%rax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L58:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L57
L31:
  test   %r9d,%r9d
  js     L20
  movslq %edi,%rdi
  jmp    L105
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long numberofRoutes(int sizeofSquare) {
  long long square[sizeofSquare + 1][sizeofSquare + 1];
  int i, j;
  for (i = 0; i < sizeofSquare; i++) {
    square[i][sizeofSquare] = 1;
    square[sizeofSquare][i] = 1;
  }
  for (i = sizeofSquare - 1; i >= 0; i--) {
    for (j = sizeofSquare - 1; j >= 0; j--) {
      square[i][j] = square[i + 1][j] + square[i][j + 1];
    }
  }
  return square[0][0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<numberofRoutes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdi),%eax
  mov    %rsp,%rcx
  cltq
  lea    0x0(,%rax,8),%rbx
  imul   %rax,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L39
L24:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L24
L39:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L41
L69:
  lea    0x7(%rsp),%rcx
  mov    %rbx,%r11
  lea    -0x1(%rdi),%r8d
  mov    %rcx,%r9
  shr    $0x3,%r11
  and    $0xfffffffffffffff8,%rcx
  shr    $0x3,%r9
  test   %edi,%edi
  jle    L57
  lea    -0x8(%rbx),%rsi
  movslq %edi,%rdi
  xor    %edx,%edx
  mov    %rsi,%r10
  imul   %r11,%r10
  add    %rcx,%r10
  nopl   0x0(%rax)
L50:
  movslq %edx,%rax
  imul   %r11,%rax
  add    %rdi,%rax
  movq   $0x1,(%rcx,%rax,8)
  movq   $0x1,(%r10,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L50
L63:
  sub    $0x10,%rbx
  imul   %r11,%rsi
  mov    %r11,%r10
  movslq %r8d,%r12
  imul   %r11,%rbx
  neg    %r10
  shl    $0x3,%r10
  add    %rcx,%rsi
  add    %rbx,%rcx
  nopw   0x0(%rax,%rax,1)
L97:
  mov    (%rcx,%rdi,8),%rdx
  mov    %r12,%rax
  nop
L52:
  add    (%rsi,%rax,8),%rdx
  mov    %rdx,(%rcx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L52
  sub    $0x1,%r8d
  add    %r10,%rsi
  add    %r10,%rcx
  cmp    $0xffffffff,%r8d
  jne    L97
L61:
  mov    0x0(,%r9,8),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L95
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L41:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L57:
  test   %r8d,%r8d
  js     L61
  movslq %edi,%rdi
  lea    -0x8(%rbx),%rsi
  jmp    L63
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long numberofRoutes(int sizeofSquare) {
  long long square[sizeofSquare + 1][sizeofSquare + 1];
  int i, j;
  for (i = 0; i < sizeofSquare; i++) {
    square[i][sizeofSquare] = 1;
    square[sizeofSquare][i] = 1;
  }
  for (i = sizeofSquare - 1; i >= 0; i--) {
    for (j = sizeofSquare - 1; j >= 0; j--) {
      square[i][j] = square[i + 1][j] + square[i][j + 1];
    }
  }
  return square[0][0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<index_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
  mov    $0x0,%eax
  call   <index_dir@plt>
  mov    %rax,-0x28(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  lea    0x1(%rax),%ebx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x0,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <error_fatal@plt>
L17:
  mov    -0x48(%rbp),%rsi
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rsi,%r8
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string

tool: D9: memory

tool: D10: %s/%s.%s

assistant: ```c
char *index_file(const char *dir, const char *dbase, const char *suf) {
  const char *p;
  char *file;
  size_t len;
  if ((p = dir) == NULL) {
    p = index_dir();
  }
  len = strlen(p) + 1 + strlen(dbase) + 1 + strlen(suf);
  if ((file = (char *)malloc(len + 1)) == NULL) {
    error_fatal("memory", NULL);
  }
  (void)sprintf(file, "%s/%s.%s", p, dbase, suf);
  return file;
}
```