ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gca_median5>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r14
  mov    %r8,0x8(%rsp)
  mov    %r14,%rdx
  call   *%r9
  test   %eax,%eax
  jle    L65
  mov    %rbp,%rax
  mov    %r15,%rbp
  mov    %rax,%r15
L65:
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   *%r12
  test   %eax,%eax
  jle    L62
  mov    %r13,%rax
  mov    %rbx,%r13
  mov    %rax,%rbx
L62:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   *%r12
  mov    %r14,%rdx
  test   %eax,%eax
  js     L54
  mov    0x8(%rsp),%r13
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   *%r12
  mov    %r13,%rcx
  test   %eax,%eax
  jle    L5
  mov    %rbx,%r13
  mov    %rcx,%rbx
L5:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   *%r12
  mov    %r14,%rdx
  test   %eax,%eax
  js     L64
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   *%r12
  test   %eax,%eax
  mov    %rbp,%rax
  cmovs  %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L54:
  mov    0x8(%rsp),%rbp
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   *%r12
  mov    %rbp,%rcx
  test   %eax,%eax
  jle    L5
  mov    %r15,%rbp
  mov    %rcx,%r15
  jmp    L5
  nopl   (%rax)
L64:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   *%r12
  test   %eax,%eax
  mov    %r13,%rax
  cmovs  %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *gca_median5(void *p0, void *p1, void *p2, void *p3, void *p4, int (*compar)(const void *_a, const void *_b, void *_arg), void *arg) {
  if (compar(p0, p1, arg) > 0)
    do {
      __typeof(p0) _tmp = (p0);
      (p0) = (p1);
      (p1) = _tmp;
    } while (0);
  if (compar(p2, p3, arg) > 0)
    do {
      __typeof(p2) _tmp = (p2);
      (p2) = (p3);
      (p3) = _tmp;
    } while (0);
  if (compar(p0, p2, arg) < 0) {
    p0 = p4;
    if (compar(p0, p1, arg) > 0)
      do {
        __typeof(p0) _tmp = (p0);
        (p0) = (p1);
        (p1) = _tmp;
      } while (0);
  } else {
    p2 = p4;
    if (compar(p2, p3, arg) > 0)
      do {
        __typeof(p2) _tmp = (p2);
        (p2) = (p3);
        (p3) = _tmp;
      } while (0);
  }
  if (compar(p0, p2, arg) < 0) {
    return (compar(p1, p2, arg) < 0 ? p1 : p2);
  } else {
    return (compar(p3, p0, arg) < 0 ? p3 : p0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addBinary>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <reverse@plt>
  mov    %eax,%r15d
  mov    %r12,%rdi
  call   <reverse@plt>
  mov    %eax,%ebx
  mov    %eax,0x8(%rsp)
  movb   $0x30,0x17(%rsp)
  lea    0x2(%r15),%eax
  lea    0x2(%rbx),%edi
  cmp    %ebx,%r15d
  cmovg  %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    %ebx,%r15d
  cmovle %r15d,%ebx
  mov    %ebx,0xc(%rsp)
  test   %ebx,%ebx
  jle    L27
  mov    %ebx,%eax
  add    %rbp,%rax
  mov    %rax,(%rsp)
  mov    %rbp,%rbx
  mov    %rbp,%r14
  neg    %r14
L98:
  lea    0x17(%rsp),%rdx
  lea    (%r12,%r14,1),%rax
  movsbl (%rax,%rbx,1),%esi
  lea    0x0(%r13,%r14,1),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <addChar@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    (%rsp),%rbx
  jne    L98
L44:
  mov    0xc(%rsp),%ecx
  cmp    %ecx,%r15d
  jle    L109
  movslq %ecx,%rax
  lea    (%rax,%rbp,1),%rbx
  lea    0x1(%rbp,%rax,1),%r14
  lea    -0x1(%r15),%eax
  sub    %ecx,%eax
  add    %rax,%r14
  lea    0x17(%rsp),%rax
  mov    %rax,(%rsp)
L107:
  mov    %r13,%rax
  sub    %rbp,%rax
  movsbl (%rax,%rbx,1),%edi
  mov    (%rsp),%rdx
  mov    $0x30,%esi
  call   <addChar@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L107
L49:
  mov    0x8(%rsp),%ecx
  cmp    %r15d,%ecx
  jle    L110
  movslq %r15d,%rax
  lea    (%rax,%rbp,1),%rbx
  lea    0x1(%rbp,%rax,1),%r13
  lea    -0x1(%rcx),%eax
  sub    %r15d,%eax
  add    %rax,%r13
  lea    0x17(%rsp),%r14
L36:
  mov    %r12,%rax
  sub    %rbp,%rax
  movsbl (%rax,%rbx,1),%esi
  mov    %r14,%rdx
  mov    $0x30,%edi
  call   <addChar@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L36
L56:
  cmpb   $0x31,0x17(%rsp)
  je     L65
  movslq 0x8(%rsp),%rax
  movb   $0x0,0x0(%rbp,%rax,1)
L58:
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  movl   $0x0,0xc(%rsp)
  jmp    L44
L109:
  mov    0xc(%rsp),%r15d
  jmp    L49
L110:
  mov    %r15d,0x8(%rsp)
  jmp    L56
L65:
  mov    0x8(%rsp),%ecx
  movslq %ecx,%rax
  movb   $0x31,0x0(%rbp,%rax,1)
  lea    0x1(%rcx),%eax
  cltq
  movb   $0x0,0x0(%rbp,%rax,1)
  jmp    L58
L96:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *addBinary(char *a, char *b) {
  char *c;
  int aSize = reverse(a);
  int bSize = reverse(b);
  int cSize;
  int i = 0, j = 0;
  char tag = '0';
  cSize = aSize > bSize ? aSize + 2 : bSize + 2;
  c = (char *)malloc(sizeof(char) * cSize);
  while ((i < aSize) && (i < bSize)) {
    c[i] = addChar(a[i], b[i], &tag);
    i++;
  }
  while (i < aSize) {
    c[i] = addChar(a[i], '0', &tag);
    i++;
  }
  while (i < bSize) {
    c[i] = addChar('0', b[i], &tag);
    i++;
  }
  if (tag == '1') {
    c[i++] = tag;
    c[i] = '\0';
  } else {
    c[i] = '\0';
  }
  reverse(c);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  jmp    L30
L32:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    %eax,%edi
  call   <sort_shift_down@plt>
  subl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0x0,-0x8(%rbp)
  jg     L32
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L16:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <sort_shift_down@plt>
  subl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x1,-0x8(%rbp)
  jg     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void sort_heap(int num[], int n) {
  int k, item;
  for (k = n / 2; k >= 1; k--)
    sort_shift_down(num[k], num, k, n);
  for (k = n; k > 1; k--) {
    item = num[k];
    num[k] = num[1];
    sort_shift_down(item, num, 1, k - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  add    %esi,%r12d
  sar    %r12d
  cmp    $0x1,%esi
  jle    L8
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movslq %r12d,%r12
L24:
  mov    0x0(%rbp,%r12,4),%edi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <sort_shift_down@plt>
  sub    $0x1,%r12
  test   %r12d,%r12d
  jg     L24
  movslq %ebx,%rbx
L10:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    0x4(%rbp),%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  lea    -0x1(%rbx),%ecx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  call   <sort_shift_down@plt>
  sub    $0x1,%rbx
  cmp    $0x1,%ebx
  jg     L10
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort_heap(int num[], int n) {
  int k, item;
  for (k = n / 2; k >= 1; k--)
    sort_shift_down(num[k], num, k, n);
  for (k = n; k > 1; k--) {
    item = num[k];
    num[k] = num[1];
    sort_shift_down(item, num, 1, k - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%r12d
  shr    $0x1f,%r12d
  add    %ebx,%r12d
  sar    %r12d
  cmp    $0x1,%ebx
  jle    L24
  mov    %rdi,%rbp
  movslq %r12d,%r12
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x0(%rbp,%r12,4),%edi
  mov    %r12d,%edx
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  sub    $0x1,%r12
  call   <sort_shift_down@plt>
  test   %r12d,%r12d
  jg     L25
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x4(%rbp),%eax
  mov    0x0(%rbp,%rbx,4),%edi
  lea    -0x1(%rbx),%ecx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <sort_shift_down@plt>
  cmp    $0x1,%ebx
  jg     L17
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort_heap(int num[], int n) {
  int k, item;
  for (k = n / 2; k >= 1; k--)
    sort_shift_down(num[k], num, k, n);
  for (k = n; k > 1; k--) {
    item = num[k];
    num[k] = num[1];
    sort_shift_down(item, num, 1, k - 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%r12d
  shr    $0x1f,%r12d
  add    %ebx,%r12d
  sar    %r12d
  cmp    $0x1,%ebx
  jle    L20
  mov    %rdi,%rbp
  movslq %r12d,%r12
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%r12,4),%edi
  mov    %r12d,%edx
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  sub    $0x1,%r12
  call   <sort_shift_down@plt>
  test   %r12d,%r12d
  jg     L1
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x4(%rbp),%eax
  mov    0x0(%rbp,%rbx,4),%edi
  lea    -0x1(%rbx),%ecx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %eax,0x0(%rbp,%rbx,4)
  sub    $0x1,%rbx
  call   <sort_shift_down@plt>
  cmp    $0x1,%ebx
  jg     L2
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort_heap(int num[], int n) {
  int k, item;
  for (k = n / 2; k >= 1; k--)
    sort_shift_down(num[k], num, k, n);
  for (k = n; k > 1; k--) {
    item = num[k];
    num[k] = num[1];
    sort_shift_down(item, num, 1, k - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<board_msi_kt4v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <via_vt823x_gpio_set@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x2e,%edi
  call   <w836xx_memw_enable@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int board_msi_kt4v(void) {
  int ret;
  ret = via_vt823x_gpio_set(12, 1);
  w836xx_memw_enable(0x2E);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<board_msi_kt4v>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <via_vt823x_gpio_set@plt>
  mov    %eax,%ebx
  mov    $0x2e,%edi
  call   <w836xx_memw_enable@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int board_msi_kt4v(void) {
  int ret;
  ret = via_vt823x_gpio_set(12, 1);
  w836xx_memw_enable(0x2E);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<board_msi_kt4v>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <via_vt823x_gpio_set@plt>
  mov    $0x2e,%edi
  mov    %eax,%r12d
  call   <w836xx_memw_enable@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int board_msi_kt4v(void) {
  int ret;
  ret = via_vt823x_gpio_set(12, 1);
  w836xx_memw_enable(0x2E);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<board_msi_kt4v>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    $0xc,%edi
  call   <via_vt823x_gpio_set@plt>
  mov    $0x2e,%edi
  mov    %eax,%r12d
  call   <w836xx_memw_enable@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int board_msi_kt4v(void) {
  int ret;
  ret = via_vt823x_gpio_set(12, 1);
  w836xx_memw_enable(0x2E);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trapezoid_numerical_integration>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  mov    %edi,%r12d
  mov    %rsi,%rbp
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rsp)
  cvttsd2si %xmm1,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  js     L21
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  mov    $0x0,%ebx
  lea    D22(%rip),%r14
  lea    D4(%rip),%r13
  jmp    L12
L38:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  call   *%rbp
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L4:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  movq   %xmm2,%r15
  movapd %xmm2,%xmm0
  call   *%rbp
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   %r15,%xmm0
  mulsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  call   *%rbp
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jl     L6
L12:
  test   %ebx,%ebx
  je     L38
  cmp    %ebx,%r12d
  je     L38
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  call   *%rbp
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L4
L21:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
L6:
  movsd  0x8(%rsp),%xmm0
  mulsd  D20(%rip),%xmm0
  mulsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: f64

tool: D17: Value of h is %lf:


tool: D22: %lf 

tool: D4: Iterations: %d and f(x) = %lf and sum = %lf 


tool: D20: 0.5

assistant: ```c
double trapezoid_numerical_integration(double x0, double xn, int ndivisions, double (*fp)(double)) {
  int i;
  double result = 0, h;
  h = (xn - x0) / ndivisions;
  printf("Value of h is %lf:\n", h);
  for (i = 0; i <= ndivisions; i++) {
    if (i == 0 || i == ndivisions)
      result += fp(x0 + i * h);
    else
      result += 2.0 * fp(i);
    printf("%lf ", 2.0 * fp(i));
    printf("Iterations: %d and f(x) = %lf and sum = %lf \n", i, fp(x0 + i * h), result);
  }
  result = result * 0.5 * h;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trapezoid_numerical_integration>:
  endbr64
  push   %r14
  subsd  %xmm0,%xmm1
  xor    %eax,%eax
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  lea    D21(%rip),%rdi
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  movsd  %xmm1,0x20(%rsp)
  call   <printf@plt>
  test   %r12d,%r12d
  js     L54
  pxor   %xmm6,%xmm6
  xor    %ebx,%ebx
  lea    D37(%rip),%r14
  movsd  %xmm6,0x8(%rsp)
  lea    D4(%rip),%r13
  jmp    L24
  nopl   0x0(%rax)
L50:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   *%rbp
  movsd  0x10(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm4
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm4
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm4,0x10(%rsp)
L39:
  movapd %xmm1,%xmm0
  call   *%rbp
  mov    %r14,%rdi
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  call   *%rbp
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x2,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L55
L24:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  test   %ebx,%ebx
  je     L7
  cmp    %ebx,%r12d
  jne    L50
L7:
  movsd  0x20(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm1,0x28(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   *%rbp
  addsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L55:
  movsd  0x8(%rsp),%xmm0
  mulsd  D20(%rip),%xmm0
L27:
  mulsd  0x20(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L54:
  pxor   %xmm0,%xmm0
  jmp    L27
```

tool_calls: name: unpack_data
arguments: label: D21
datatype: string
name: unpack_data
arguments: label: D37
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D20
datatype: f64

tool: D21: Value of h is %lf:


tool: D37: %lf 

tool: D4: Iterations: %d and f(x) = %lf and sum = %lf 


tool: D20: 0.5

assistant: ```c
double trapezoid_numerical_integration(double x0, double xn, int ndivisions, double (*fp)(double)) {
  int i;
  double result = 0, h;
  h = (xn - x0) / ndivisions;
  printf("Value of h is %lf:\n", h);
  for (i = 0; i <= ndivisions; i++) {
    if (i == 0 || i == ndivisions)
      result += fp(x0 + i * h);
    else
      result += 2.0 * fp(i);
    printf("%lf ", 2.0 * fp(i));
    printf("Iterations: %d and f(x) = %lf and sum = %lf \n", i, fp(x0 + i * h), result);
  }
  result = result * 0.5 * h;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<trapezoid_numerical_integration>:
  endbr64
  push   %r14
  subsd  %xmm0,%xmm1
  xor    %eax,%eax
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  lea    D31(%rip),%rdi
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  movsd  %xmm1,0x10(%rsp)
  call   <printf@plt>
  test   %r12d,%r12d
  js     L37
  pxor   %xmm6,%xmm6
  xor    %ebx,%ebx
  lea    D13(%rip),%r14
  movsd  %xmm6,0x8(%rsp)
  lea    D16(%rip),%r13
  jmp    L62
  nopl   0x0(%rax)
L9:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x20(%rsp)
  call   *%rbp
  movsd  0x20(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   *%rbp
  mov    %r14,%rdi
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  movsd  0x20(%rsp),%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  addsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
L10:
  call   *%rbp
  movsd  0x8(%rsp),%xmm1
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x2,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L52
L62:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  test   %ebx,%ebx
  je     L50
  cmp    %ebx,%r12d
  jne    L9
L50:
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm1,0x28(%rsp)
  mulsd  %xmm1,%xmm2
  addsd  0x18(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x20(%rsp)
  call   *%rbp
  addsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   *%rbp
  mov    %r14,%rdi
  xor    %eax,%eax
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  movsd  0x20(%rsp),%xmm2
  movapd %xmm2,%xmm0
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L52:
  movsd  0x8(%rsp),%xmm0
  mulsd  D26(%rip),%xmm0
L26:
  mulsd  0x10(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L37:
  pxor   %xmm0,%xmm0
  jmp    L26
```

tool_calls: name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string
name: read_data
arguments: data_tag: D26
datatype: f64

tool: D31: Value of h is %lf:


tool: D13: %lf 

tool: D16: Iterations: %d and f(x) = %lf and sum = %lf 


tool: D26: 0.5

assistant: ```c
double trapezoid_numerical_integration(double x0, double xn, int ndivisions, double (*fp)(double)) {
  int i;
  double result = 0, h;
  h = (xn - x0) / ndivisions;
  printf("Value of h is %lf:\n", h);
  for (i = 0; i <= ndivisions; i++) {
    if (i == 0 || i == ndivisions)
      result += fp(x0 + i * h);
    else
      result += 2.0 * fp(i);
    printf("%lf ", 2.0 * fp(i));
    printf("Iterations: %d and f(x) = %lf and sum = %lf \n", i, fp(x0 + i * h), result);
  }
  result = result * 0.5 * h;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bcompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L40
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  jmp    L70
L40:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L43
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L44
  mov    -0x4(%rbp),%eax
  jmp    L70
L44:
  mov    $0xffffffff,%eax
  jmp    L70
L43:
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L52
  mov    -0x4(%rbp),%eax
  jmp    L70
L52:
  mov    $0x1,%eax
L70:
  leave
  ret
```

assistant: ```c
int bcompare(unsigned char *a, int alen, unsigned char *b, int blen) {
  int stat;
  if (alen == blen) {
    return memcmp(a, b, alen);
  } else if (alen < blen) {
    if ((stat = memcmp(a, b, alen)) != 0)
      return stat;
    return -1;
  } else {
    if ((stat = memcmp(a, b, blen)) != 0)
      return stat;
    return +1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bcompare>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  mov    %rdx,%rsi
  cmp    %ecx,%eax
  je     L25
  jge    L47
  mov    %eax,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L40
L25:
  mov    %eax,%edx
  call   <memcmp@plt>
  jmp    L40
L47:
  mov    %ecx,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
L40:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bcompare(unsigned char *a, int alen, unsigned char *b, int blen) {
  int stat;
  if (alen == blen) {
    return memcmp(a, b, alen);
  } else if (alen < blen) {
    if ((stat = memcmp(a, b, alen)) != 0)
      return stat;
    return -1;
  } else {
    if ((stat = memcmp(a, b, blen)) != 0)
      return stat;
    return +1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bcompare>:
  endbr64
  mov    %esi,%r8d
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  cmp    %ecx,%r8d
  je     L7
  jl     L20
  mov    %ecx,%edx
  call   <memcmp@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  cmove  %edx,%eax
L22:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r8d,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r8d,%edx
  add    $0x8,%rsp
  jmp    1050 <memcmp@plt>
```

assistant: ```c
int bcompare(unsigned char *a, int alen, unsigned char *b, int blen) {
  int stat;
  if (alen == blen) {
    return memcmp(a, b, alen);
  } else if (alen < blen) {
    if ((stat = memcmp(a, b, alen)) != 0)
      return stat;
    return -1;
  } else {
    if ((stat = memcmp(a, b, blen)) != 0)
      return stat;
    return +1;
  }
}
```