user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  cmp    $0x4,%edi
  je     L14
  xor    %eax,%eax
  jmp    1150 <help2@plt>
L14:
  push   %r15
  lea    D48(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r15
  mov    0x18(%rsi),%r13
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %rax,%r14
  call   <fopen@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rax,0x8(%rsp)
  call   <fopen@plt>
  mov    %rax,%r12
  test   %r14,%r14
  je     L49
  mov    $0x3e8,%edi
  xor    %r15d,%r15d
  lea    D10(%rip),%rbx
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L63:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x1,%r15d
  call   <strtok@plt>
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  lea    D30(%rip),%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    0x8(%rsp),%rdi
  lea    D24(%rip),%rsi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <fprintf@plt>
L80:
  mov    %rbp,%rdi
  call   <free@plt>
L57:
  mov    %r14,%rdx
  mov    $0x3e8,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L0
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcpy@plt>
  test   %r15d,%r15d
  je     L63
  mov    %rbp,%rdi
  call   <string_replace@plt>
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L22
  lea    0x1(%rbp),%r15
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <fprintf@plt>
  movsbl -0x1(%r15),%edx
  test   %dl,%dl
  jne    L33
L22:
  mov    %r12,%rsi
  mov    $0xa,%edi
  xor    %r15d,%r15d
  call   <fputc@plt>
  jmp    L80
L0:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <free@plt>
L28:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    %rbp,%rdi
  call   <perror@plt>
  jmp    L28
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D30
datatype: string
name: extract_symbolic_data
arguments: tag: D24
datatype: string

tool: D48: Reading %s


tool: D38: w+

tool: D12: r

tool: D10: %c 

tool: D17: 


tool: D30: |

tool: D24: %s


assistant: ```c
int main(int argc, char **argv) {
  char *filename, *labelfile, *seqfile;
  int **S;
  char *str, *linetemp, *line, *label;
  int i, j, count;
  FILE *inpfile, *labfile, *opfile;
  if (argc != 3 + 1) {
    return help2();
  }
  filename = argv[1];
  labelfile = argv[2];
  seqfile = argv[3];
  printf("Reading %s\n", filename);
  inpfile = fopen(filename, "r");
  labfile = fopen(labelfile, "w+");
  opfile = fopen(seqfile, "w+");
  if (inpfile) {
    line = (char *)malloc(1000 * sizeof(char));
    i = 0;
    count = 0;
    while (fgets(line, 1000, inpfile)) {
      linetemp = (char *)malloc(1000 * sizeof(char));
      strcpy(linetemp, line);
      if (count == 0) {
        label = strtok(linetemp, "\n");
        label = strtok(linetemp, "|");
        label = strtok(NULL, "|");
        fprintf(labfile, "%s\n", label);
        count = 1;
      } else {
        string_replace(linetemp);
        j = 0;
        while (linetemp[j] != '\0') {
          fprintf(opfile, "%c ", linetemp[j]);
          j++;
        }
        fprintf(opfile, "\n");
        count = 0;
      }
      free(linetemp);
      i++;
    }
    fclose(inpfile);
    fclose(labfile);
    fclose(opfile);
    free(line);
  } else {
    perror(filename);
  }
}
```