ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<array_stretch2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L2:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x28(%rbp),%rax
  neg    %rax
  add    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L2
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  lea    (%rcx,%rax,1),%rdi
  mov    -0x20(%rbp),%esi
  mov    -0x30(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  call   <array_memset_stride@plt>
  nop
  leave
  ret
```

assistant: ```c
void array_stretch2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth, int wipe_value) {
  unsigned char *p, *q;
  assert(oldwidth < newwidth);
  p = base + (nelems - 1) * oldwidth;
  q = base + (nelems - 1) * newwidth;
  while (p > base) {
    memmove(q, p, oldwidth);
    p -= oldwidth;
    q -= newwidth;
  }
  array_memset_stride(base + oldwidth, nelems, newwidth - oldwidth, newwidth, wipe_value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<array_stretch2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    %rdx,%r12
  mov    %rcx,%r14
  mov    %r8d,0xc(%rsp)
  cmp    %rcx,%rdx
  setb   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    -0x1(%r15),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rbx
  imul   %r12,%rbx
  add    %r13,%rbx
  imul   %r14,%rbp
  add    %r13,%rbp
  cmp    %rbx,%r13
  jae    L15
L19:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  sub    %r12,%rbx
  sub    %r14,%rbp
  cmp    %rbx,%r13
  jb     L19
L15:
  mov    %r14,%rdx
  sub    %r12,%rdx
  lea    0x0(%r13,%r12,1),%rdi
  mov    0xc(%rsp),%r8d
  mov    %r14,%rcx
  mov    %r15d,%esi
  call   <array_memset_stride@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void array_stretch2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth, int wipe_value) {
  unsigned char *p, *q;
  assert(oldwidth < newwidth);
  p = base + (nelems - 1) * oldwidth;
  q = base + (nelems - 1) * newwidth;
  while (p > base) {
    memmove(q, p, oldwidth);
    p -= oldwidth;
    q -= newwidth;
  }
  array_memset_stride(base + oldwidth, nelems, newwidth - oldwidth, newwidth, wipe_value);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<array_stretch2>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %r15,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x18,%rsp
  cmp    %rcx,%rdx
  setb   %dil
  mov    %rcx,(%rsp)
  neg    %r12
  mov    %esi,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  call   <assert@plt>
  lea    -0x1(%r14),%edi
  movslq %edi,%rdi
  mov    %rdi,%rcx
  imul   %rbp,%rdi
  neg    %rbp
  imul   %r15,%rcx
  lea    (%rbx,%rdi,1),%r13
  lea    (%rbx,%rcx,1),%r14
  cmp    %r14,%rbx
  jae    L11
  nopl   0x0(%rax)
L3:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %r15,%rdx
  add    %r12,%r14
  call   <memmove@plt>
  add    %rbp,%r13
  cmp    %r14,%rbx
  jb     L3
L11:
  mov    (%rsp),%rcx
  mov    0xc(%rsp),%r8d
  lea    (%rbx,%r15,1),%rdi
  mov    0x8(%rsp),%esi
  add    $0x18,%rsp
  mov    %rcx,%rdx
  pop    %rbx
  pop    %rbp
  sub    %r15,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <array_memset_stride@plt>
```

assistant: ```c
void array_stretch2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth, int wipe_value) {
  unsigned char *p, *q;
  assert(oldwidth < newwidth);
  p = base + (nelems - 1) * oldwidth;
  q = base + (nelems - 1) * newwidth;
  while (p > base) {
    memmove(q, p, oldwidth);
    p -= oldwidth;
    q -= newwidth;
  }
  array_memset_stride(base + oldwidth, nelems, newwidth - oldwidth, newwidth, wipe_value);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<array_stretch2>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %r15,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x18,%rsp
  cmp    %rcx,%rdx
  setb   %dil
  mov    %rcx,(%rsp)
  neg    %r12
  mov    %esi,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  call   <assert@plt>
  lea    -0x1(%r14),%edi
  movslq %edi,%rdi
  mov    %rdi,%rcx
  imul   %rbp,%rdi
  neg    %rbp
  imul   %r15,%rcx
  lea    (%rbx,%rdi,1),%r13
  lea    (%rbx,%rcx,1),%r14
  cmp    %r14,%rbx
  jae    L3
  nopl   0x0(%rax)
L13:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %r15,%rdx
  add    %r12,%r14
  call   <memmove@plt>
  add    %rbp,%r13
  cmp    %r14,%rbx
  jb     L13
L3:
  mov    (%rsp),%rcx
  mov    0xc(%rsp),%r8d
  lea    (%rbx,%r15,1),%rdi
  mov    0x8(%rsp),%esi
  add    $0x18,%rsp
  mov    %rcx,%rdx
  pop    %rbx
  pop    %rbp
  sub    %r15,%rdx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <array_memset_stride@plt>
```

assistant: ```c
void array_stretch2(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth, int wipe_value) {
  unsigned char *p, *q;
  assert(oldwidth < newwidth);
  p = base + (nelems - 1) * oldwidth;
  q = base + (nelems - 1) * newwidth;
  while (p > base) {
    memmove(q, p, oldwidth);
    p -= oldwidth;
    q -= newwidth;
  }
  array_memset_stride(base + oldwidth, nelems, newwidth - oldwidth, newwidth, wipe_value);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arm_proc_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L1:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arm_proc_fill(void (**arr)(), void (*proc)(), int32_t size) {
  int32_t i;
  for (i = 0; i < size; i++) {
    arr[i] = proc;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arm_proc_fill>:
  endbr64
  test   %rdx,%rdx
  je     L0
  mov    %rdi,%rax
  lea    (%rdi,%rdx,8),%rdx
L4:
  mov    %rsi,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L4
L0:
  ret
```

assistant: ```c
void arm_proc_fill(void (**arr)(), void (*proc)(), int32_t size) {
  int32_t i;
  for (i = 0; i < size; i++) {
    arr[i] = proc;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arm_proc_fill>:
  endbr64
  test   %rdx,%rdx
  je     L0
  lea    (%rdi,%rdx,8),%rax
  nopl   (%rax)
L17:
  mov    %rsi,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L17
L0:
  ret
```

assistant: ```c
void arm_proc_fill(void (**arr)(), void (*proc)(), int32_t size) {
  int32_t i;
  for (i = 0; i < size; i++) {
    arr[i] = proc;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<arm_proc_fill>:
  endbr64
  test   %rdx,%rdx
  je     L5
  cmp    $0x1,%rdx
  je     L11
  mov    %rdx,%rcx
  movq   %rsi,%xmm0
  mov    %rdi,%rax
  shr    %rcx
  punpcklqdq %xmm0,%xmm0
  shl    $0x4,%rcx
  add    %rdi,%rcx
  nopl   0x0(%rax,%rax,1)
L23:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L23
  mov    %rdx,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%edx
  je     L46
L48:
  mov    %rsi,(%rdi,%rax,8)
L5:
  ret
  nopl   (%rax)
L46:
  ret
L11:
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void arm_proc_fill(void (**arr)(), void (*proc)(), int32_t size) {
  int32_t i;
  for (i = 0; i < size; i++) {
    arr[i] = proc;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x55(%rbp)
  movl   $0x0,-0x54(%rbp)
  movb   $0x0,-0x56(%rbp)
  jmp    L47
L12:
  movsbl -0x56(%rbp),%eax
  lea    -0x40(%rbp),%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x56(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x56(%rbp)
L47:
  cmpb   $0x3,-0x56(%rbp)
  jle    L12
  movb   $0x0,-0x56(%rbp)
  jmp    L3
L9:
  movsbl -0x56(%rbp),%eax
  lea    -0x40(%rbp),%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movsbl -0x56(%rbp),%ebx
  mov    %rax,%rdi
  call   <atoi@plt>
  movslq %ebx,%rdx
  mov    %eax,-0x50(%rbp,%rdx,4)
  movsbl -0x56(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  add    %eax,-0x54(%rbp)
  movzbl -0x56(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x56(%rbp)
L3:
  cmpb   $0x3,-0x56(%rbp)
  jle    L9
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D11: %s

tool: D0: %d


assistant: ```c
int main() {
  char s[4][10];
  char n = 0;
  char i;
  int num[4];
  int sum = 0;
  for (i = 0; i < 4; i++) {
    scanf("%s", s[i]);
  }
  for (i = 0; i < 4; i++) {
    num[i] = atoi(s[i]);
    sum += num[i];
  }
  printf("%d\n", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D7(%rip),%r13
L12:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0xa,%rbp
  cmp    %r12,%rbp
  jne    L12
  mov    $0x0,%ebp
L29:
  mov    %rbx,%rdi
  call   <atoi@plt>
  add    %eax,%ebp
  add    $0xa,%rbx
  cmp    %r12,%rbx
  jne    L29
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D7: %s

tool: D8: %d


assistant: ```c
int main() {
  char s[4][10];
  char n = 0;
  char i;
  int num[4];
  int sum = 0;
  for (i = 0; i < 4; i++) {
    scanf("%s", s[i]);
  }
  for (i = 0; i < 4; i++) {
    num[i] = atoi(s[i]);
    sum += num[i];
  }
  printf("%d\n", sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
L22:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0xa,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L22
  xor    %ebp,%ebp
L4:
  mov    %rbx,%rdi
  add    $0xa,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %r12,%rbx
  jne    L4
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string

tool: D3: %s

tool: D14: %d


assistant: ```c
int main() {
  char s[4][10];
  char n = 0;
  char i;
  int num[4];
  int sum = 0;
  for (i = 0; i < 4; i++) {
    scanf("%s", s[i]);
  }
  for (i = 0; i < 4; i++) {
    num[i] = atoi(s[i]);
    sum += num[i];
  }
  printf("%d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
L3:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0xa,%rbp
  call   <scanf@plt>
  cmp    %rbp,%r12
  jne    L3
  xor    %ebp,%ebp
L21:
  mov    %rbx,%rdi
  add    $0xa,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %rbx,%r12
  jne    L21
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D0: %s

tool: D2: %d


assistant: ```c
int main() {
  char s[4][10];
  char n = 0;
  char i;
  int num[4];
  int sum = 0;
  for (i = 0; i < 4; i++) {
    scanf("%s", s[i]);
  }
  for (i = 0; i < 4; i++) {
    num[i] = atoi(s[i]);
    sum += num[i];
  }
  printf("%d\n", sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L1:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %esi,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int skip_atoi(const char **s) {
  int i = 0;
  while (((**s) - '0' + 0U <= 9U))
    i = i * 10 + *((*s)++) - '0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_atoi>:
  endbr64
  mov    (%rdi),%rax
  movsbl (%rax),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L12
  add    $0x1,%rax
  mov    $0x0,%ecx
L20:
  mov    %rax,%rdx
  mov    %rax,(%rdi)
  lea    (%rcx,%rcx,4),%esi
  movsbl -0x1(%rax),%ecx
  lea    -0x30(%rcx,%rsi,2),%ecx
  add    $0x1,%rax
  movsbl (%rdx),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L20
L6:
  mov    %ecx,%eax
  ret
L12:
  mov    $0x0,%ecx
  jmp    L6
```

assistant: ```c
int skip_atoi(const char **s) {
  int i = 0;
  while (((**s) - '0' + 0U <= 9U))
    i = i * 10 + *((*s)++) - '0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip_atoi>:
  endbr64
  mov    (%rdi),%rax
  movsbl (%rax),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L7
  add    $0x1,%rax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L5:
  mov    %rax,%rdx
  mov    %rax,(%rdi)
  movsbl -0x1(%rax),%ecx
  lea    (%r8,%r8,4),%esi
  movsbl (%rdx),%edx
  add    $0x1,%rax
  lea    -0x30(%rcx,%rsi,2),%r8d
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L5
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int skip_atoi(const char **s) {
  int i = 0;
  while (((**s) - '0' + 0U <= 9U))
    i = i * 10 + *((*s)++) - '0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_atoi>:
  endbr64
  mov    (%rdi),%rax
  movsbl (%rax),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L18
  add    $0x1,%rax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L10:
  mov    %rax,%rdx
  mov    %rax,(%rdi)
  movsbl -0x1(%rax),%ecx
  lea    (%r8,%r8,4),%esi
  movsbl (%rdx),%edx
  add    $0x1,%rax
  lea    -0x30(%rcx,%rsi,2),%r8d
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L10
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int skip_atoi(const char **s) {
  int i = 0;
  while (((**s) - '0' + 0U <= 9U))
    i = i * 10 + *((*s)++) - '0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pow2>:
  endbr64
  sub    $0x8,%rsp
  call   <pow@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pow2>:
  endbr64
  jmp    1050 <pow@plt>
```

assistant: ```c
int pow2(int en, int dva) {
  int ret = pow(en, dva);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x26(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x30(%rbp)
  jmp    L48
L51:
  movl   $0x0,-0x2c(%rbp)
  jmp    L55
L14:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x26(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <Sort@plt>
  mov    %rax,%rbx
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x26(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <Sort@plt>
  cmp    %rax,%rbx
  jle    L21
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x26(%rbp,%rax,1),%eax
  mov    %al,-0x31(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x26(%rbp,%rax,1),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %dl,-0x26(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x31(%rbp),%edx
  mov    %dl,-0x26(%rbp,%rax,1)
L21:
  addl   $0x1,-0x2c(%rbp)
L55:
  mov    $0xd,%eax
  sub    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L14
  addl   $0x1,-0x30(%rbp)
L48:
  cmpl   $0xc,-0x30(%rbp)
  jle    L51
  lea    -0x26(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: %s

assistant: ```c
int main() {
  char teste[14], d;
  int n, y;
  scanf("%s", teste);
  for (n = 1; n < 13; n++) {
    for (y = 0; y < 13 - n; y++) {
      if (Sort(teste[y]) > Sort(teste[y + 1])) {
        d = teste[y];
        teste[y] = teste[y + 1];
        teste[y + 1] = d;
      }
    }
  }
  printf("%s", teste);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%r13
  mov    %r13,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  lea    0x16(%rsp),%r12
  jmp    L13
L9:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L25
L18:
  movsbl (%rbx),%edi
  call   <Sort@plt>
  mov    %rax,%rbp
  movsbl 0x1(%rbx),%edi
  call   <Sort@plt>
  cmp    %rax,%rbp
  jle    L9
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  mov    %dl,(%rbx)
  mov    %al,0x1(%rbx)
  jmp    L9
L25:
  sub    $0x1,%r12
  cmp    %r13,%r12
  je     L64
L13:
  mov    %r12d,%eax
  sub    %r13d,%eax
  mov    %r13,%rbx
  test   %eax,%eax
  jg     L18
  jmp    L25
L64:
  lea    0xa(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D10: %s

assistant: ```c
int main() {
  char teste[14], d;
  int n, y;
  scanf("%s", teste);
  for (n = 1; n < 13; n++) {
    for (y = 0; y < 13 - n; y++) {
      if (Sort(teste[y]) > Sort(teste[y + 1])) {
        d = teste[y];
        teste[y] = teste[y + 1];
        teste[y + 1] = d;
      }
    }
  }
  printf("%s", teste);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%r13
  lea    0x16(%rsp),%r12
  mov    %r13,%rsi
  call   <scanf@plt>
  nopl   0x0(%rax)
L32:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L34:
  movsbl (%rbx),%edi
  call   <Sort@plt>
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbp
  call   <Sort@plt>
  cmp    %rax,%rbp
  jle    L9
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  mov    %al,0x1(%rbx)
  mov    %dl,(%rbx)
L9:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L34
  lea    -0x1(%rbx),%r12
  cmp    %r13,%r12
  jne    L32
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: %s

assistant: ```c
int main() {
  char teste[14], d;
  int n, y;
  scanf("%s", teste);
  for (n = 1; n < 13; n++) {
    for (y = 0; y < 13 - n; y++) {
      if (Sort(teste[y]) > Sort(teste[y + 1])) {
        d = teste[y];
        teste[y] = teste[y + 1];
        teste[y + 1] = d;
      }
    }
  }
  printf("%s", teste);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%r13
  lea    0x16(%rsp),%r12
  mov    %r13,%rsi
  call   <scanf@plt>
  nopl   0x0(%rax)
L36:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl (%rbx),%edi
  call   <Sort@plt>
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbp
  call   <Sort@plt>
  cmp    %rax,%rbp
  jle    L3
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  mov    %al,0x1(%rbx)
  mov    %dl,(%rbx)
L3:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L22
  lea    -0x1(%rbx),%r12
  cmp    %r13,%r12
  jne    L36
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: %s

assistant: ```c
int main() {
  char teste[14], d;
  int n, y;
  scanf("%s", teste);
  for (n = 1; n < 13; n++) {
    for (y = 0; y < 13 - n; y++) {
      if (Sort(teste[y]) > Sort(teste[y + 1])) {
        d = teste[y];
        teste[y] = teste[y + 1];
        teste[y + 1] = d;
      }
    }
  }
  printf("%s", teste);
  return 0;
}
```