user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L112
  lea    0x20(%rsp),%rax
  lea    0x28(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    0x30(%rsp),%r12
  lea    D12(%rip),%rbp
  nopl   0x0(%rax)
L95:
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  mov    %r15,%rdx
  xor    %ebx,%ebx
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x20(%rsp)
  je     L71
  xor    %r13d,%r13d
  jmp    L70
  nopl   (%rax)
L140:
  mov    0x30(%rsp),%rbx
  add    $0x1,%r13
  cmp    %r13,0x20(%rsp)
  jbe    L71
L70:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rbx,%rbx
  je     L140
  mov    0x30(%rsp),%rax
  cmp    %rax,%rbx
  cmovb  %rax,%rbx
  add    $0x1,%r13
  cmp    %r13,0x20(%rsp)
  ja     L70
L71:
  xor    %r13d,%r13d
  cmpq   $0x0,0x28(%rsp)
  je     L135
  xor    %r14d,%r14d
  jmp    L129
  nopl   0x0(%rax)
L105:
  mov    0x30(%rsp),%r13
  add    $0x1,%r14
  cmp    %r14,0x28(%rsp)
  jbe    L135
L129:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %r13,%r13
  je     L105
  mov    0x30(%rsp),%rax
  cmp    %rax,%r13
  cmovb  %rax,%r13
  add    $0x1,%r14
  cmp    %r14,0x28(%rsp)
  ja     L129
L135:
  cmp    %r13,%rbx
  jl     L144
  lea    D5(%rip),%rdi
  call   <printf@plt>
L130:
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jne    L95
L112:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L144:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L130
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D40
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D36
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D44
type_guessed: string

tool: D40: %d

tool: D12: %llu

tool: D36: %llu%llu

tool: D5: Godzilla


tool: D44: MechaGodzilla


assistant: ```c
int main() {
  int t;
  unsigned long long int i, mechg, god, godarmy, mecharmy, strength;
  scanf("%d", &t);
  while (t--) {
    god = 0;
    mechg = 0;
    scanf("%llu%llu", &godarmy, &mecharmy);
    long long int max1 = 0, max2 = 0;
    for (i = 0; i < godarmy; i++) {
      scanf("%llu", &strength);
      if (max1 == 0)
        max1 = strength;
      else if (strength > max1)
        max1 = strength;
    }
    long long int j = 0, k = 0;
    for (i = 0; i < mecharmy; i++) {
      scanf("%llu", &strength);
      if (max2 == 0)
        max2 = strength;
      else if (strength > max2)
        max2 = strength;
    }
    if (max1 >= max2)
      printf("Godzilla\n");
    else
      printf("MechaGodzilla\n");
  }
  return 0;
}
```