ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L78:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x70,%al
  jg     L30
  cmp    $0x60,%al
  jg     L31
  cmp    $0x20,%al
  je     L75
L7:
  cmp    $0xa,%al
  jne    L78
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  lea    -0x61(%rax),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x9249,%edx
  jne    L75
  test   $0x4924,%edx
  je     L112
  add    $0x3,%ebp
  jmp    L7
L30:
  lea    -0x71(%rax),%edx
  cmp    $0x9,%dl
  ja     L78
  lea    -0x72(%rax),%edx
  cmp    $0x8,%dl
  ja     L87
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  add    $0x4,%ebp
  jmp    L78
  nopl   (%rax)
L75:
  add    $0x1,%ebp
  jmp    L7
  nopl   (%rax)
L112:
  test   $0x2492,%edx
  je     L78
L87:
  add    $0x2,%ebp
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: %d

assistant: ```c
int main() {
  int i;
  char a;
  while (a != '\n') {
    a = getchar();
    switch (a) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      i++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      i += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      i += 3;
      break;
    case 's':
    case 'z':
      i += 4;
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L62:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x70,%al
  jg     L49
  cmp    $0x60,%al
  jg     L115
  cmp    $0x20,%al
  je     L64
L91:
  cmp    $0xa,%al
  jne    L62
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L115:
  lea    -0x61(%rax),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x9249,%edx
  jne    L64
  test   $0x4924,%edx
  je     L32
  add    $0x3,%ebp
  jmp    L91
L49:
  lea    -0x71(%rax),%edx
  cmp    $0x9,%dl
  ja     L62
  lea    -0x72(%rax),%edx
  cmp    $0x8,%dl
  ja     L24
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  add    $0x4,%ebp
  jmp    L62
  nopl   (%rax)
L64:
  add    $0x1,%ebp
  jmp    L91
  nopl   (%rax)
L32:
  test   $0x2492,%edx
  je     L62
L24:
  add    $0x2,%ebp
  jmp    L91
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int main() {
  int i;
  char a;
  while (a != '\n') {
    a = getchar();
    switch (a) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      i++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      i += 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      i += 3;
      break;
    case 's':
    case 'z':
      i += 4;
      break;
    }
  }
  printf("%d", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<plugin_script_config_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <plugin_script_config_read@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int plugin_script_config_cb(void *data, const char *option, const char *value) {
  (void)option;
  (void)value;
  plugin_script_config_read(data);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plugin_script_config_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <plugin_script_config_read@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int plugin_script_config_cb(void *data, const char *option, const char *value) {
  (void)option;
  (void)value;
  plugin_script_config_read(data);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<plugin_script_config_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <plugin_script_config_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int plugin_script_config_cb(void *data, const char *option, const char *value) {
  (void)option;
  (void)value;
  plugin_script_config_read(data);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plugin_script_config_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <plugin_script_config_read@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int plugin_script_config_cb(void *data, const char *option, const char *value) {
  (void)option;
  (void)value;
  plugin_script_config_read(data);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<from_1750flt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cwtl
  sar    $0x8,%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  movsbl -0xd(%rbp),%eax
  sub    $0x17,%eax
  mov    %eax,%edi
  call   <pow2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double from_1750flt(short *input) {
  int int_mant;
  double flt_exp;
  signed char int_exp;
  int_exp = (signed char)(input[1] & 0xFF);
  int_mant = ((int)input[0] << 8) | (((int)input[1] & 0xFF00) >> 8);
  flt_exp = pow2((int)int_exp - 23);
  return (double)int_mant * flt_exp;
}
```
user: What is the c source code of the assembly code below?

```asm
<from_1750flt>:
  endbr64
  push   %rbx
  movzwl 0x2(%rdi),%eax
  movswl (%rdi),%ebx
  shl    $0x8,%ebx
  movswl %ax,%edx
  movzbl %dh,%edx
  or     %edx,%ebx
  movsbl %al,%edi
  sub    $0x17,%edi
  call   <pow2@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double from_1750flt(short *input) {
  int int_mant;
  double flt_exp;
  signed char int_exp;
  int_exp = (signed char)(input[1] & 0xFF);
  int_mant = ((int)input[0] << 8) | (((int)input[1] & 0xFF00) >> 8);
  flt_exp = pow2((int)int_exp - 23);
  return (double)int_mant * flt_exp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<from_1750flt>:
  endbr64
  push   %rbx
  movswl 0x2(%rdi),%edx
  movswl (%rdi),%ebx
  mov    %edx,%eax
  movzbl %dh,%edx
  movsbl %al,%edi
  shl    $0x8,%ebx
  sub    $0x17,%edi
  or     %edx,%ebx
  call   <pow2@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  pop    %rbx
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double from_1750flt(short *input) {
  int int_mant;
  double flt_exp;
  signed char int_exp;
  int_exp = (signed char)(input[1] & 0xFF);
  int_mant = ((int)input[0] << 8) | (((int)input[1] & 0xFF00) >> 8);
  flt_exp = pow2((int)int_exp - 23);
  return (double)int_mant * flt_exp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<from_1750flt>:
  endbr64
  push   %rbx
  movswl 0x2(%rdi),%edx
  movswl (%rdi),%ebx
  mov    %edx,%eax
  movzbl %dh,%edx
  movsbl %al,%edi
  shl    $0x8,%ebx
  sub    $0x17,%edi
  or     %edx,%ebx
  call   <pow2@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  pop    %rbx
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double from_1750flt(short *input) {
  int int_mant;
  double flt_exp;
  signed char int_exp;
  int_exp = (signed char)(input[1] & 0xFF);
  int_mant = ((int)input[0] << 8) | (((int)input[1] & 0xFF00) >> 8);
  flt_exp = pow2((int)int_exp - 23);
  return (double)int_mant * flt_exp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<drop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <find@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0xff,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *drop(void *_set, const void *_element) {
  unsigned char *element = find(_set, _element);
  if (element)
    *element = 255;
  return element;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <find@plt>
  movslq %eax,%rdx
  test   %eax,%eax
  je     L3
  movb   $0xff,(%rdx)
L3:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *drop(void *_set, const void *_element) {
  unsigned char *element = find(_set, _element);
  if (element)
    *element = 255;
  return element;
}
```
user: What is the c source code of the assembly code below?

```asm
<drop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <find@plt>
  movslq %eax,%r8
  test   %eax,%eax
  je     L9
  movb   $0xff,(%r8)
L9:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *drop(void *_set, const void *_element) {
  unsigned char *element = find(_set, _element);
  if (element)
    *element = 255;
  return element;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <find@plt>
  movslq %eax,%r8
  test   %eax,%eax
  je     L1
  movb   $0xff,(%r8)
L1:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *drop(void *_set, const void *_element) {
  unsigned char *element = find(_set, _element);
  if (element)
    *element = 255;
  return element;
}
```
user: Translate the below assembly code into C programming language:

```asm
<thr_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printids@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thr_fn(void *arg) {
  printids(arg);
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<thr_fn>:
  endbr64
  sub    $0x8,%rsp
  call   <printids@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thr_fn(void *arg) {
  printids(arg);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thr_fn>:
  endbr64
  sub    $0x8,%rsp
  call   <printids@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thr_fn(void *arg) {
  printids(arg);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<thr_fn>:
  endbr64
  sub    $0x8,%rsp
  call   <printids@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thr_fn(void *arg) {
  printids(arg);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L38
  cmpl   $0x20,-0xc(%rbp)
  jg     L38
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  and    $0x1f,%eax
  test   %eax,%eax
  je     L34
  mov    -0xc(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rax
  sub    $0x1,%rax
  jmp    L28
L34:
  mov    $0xffffffffffffffff,%rax
L28:
  and    %rdx,%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L18
L38:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__bitmap_empty@plt>
L18:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int bitmap_empty(const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !(*src & (((nbits) % 32) ? (1UL << ((nbits) % 32)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_empty>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  jg     L27
  test   %rax,%rax
  je     L27
  mov    0x0(%rbp),%rdx
  mov    $0xffffffffffffffff,%rax
  test   $0x1f,%bl
  je     L12
  mov    %ebx,%ecx
  and    $0x1f,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  sub    $0x1,%rax
L12:
  test   %rax,%rdx
  sete   %al
  movzbl %al,%eax
  jmp    L9
L27:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <__bitmap_empty@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int bitmap_empty(const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !(*src & (((nbits) % 32) ? (1UL << ((nbits) % 32)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_empty>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L14
  cmp    $0x20,%ebp
  jg     L14
  mov    (%r12),%rax
  and    $0x1f,%ebp
  je     L4
  mov    $0xffffffffffffffff,%rdx
  mov    %ebp,%ecx
  shl    %cl,%rdx
  not    %rdx
  and    %rdx,%rax
L4:
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L14:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <__bitmap_empty@plt>
```

assistant: ```c
__attribute__((always_)) int bitmap_empty(const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !(*src & (((nbits) % 32) ? (1UL << ((nbits) % 32)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_empty>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L20
  cmp    $0x20,%ebp
  jg     L20
  mov    (%r12),%rax
  and    $0x1f,%ebp
  je     L6
  mov    $0xffffffffffffffff,%rdx
  mov    %ebp,%ecx
  shl    %cl,%rdx
  not    %rdx
  and    %rdx,%rax
L6:
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L20:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <__bitmap_empty@plt>
```

assistant: ```c
__attribute__((always_)) int bitmap_empty(const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 32))
    return !(*src & (((nbits) % 32) ? (1UL << ((nbits) % 32)) - 1 : ~0UL));
  else
    return __bitmap_empty(src, nbits);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L27:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L41
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L28:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0x18(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L28
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L41:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(void) {
  int num, temp, sum, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sum = 0;
    for (i = 0; i < num / 4; i++) {
      scanf("%d\n", &temp);
      sum += temp;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%r12
  jmp    L21
L25:
  mov    $0x0,%ebp
L8:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L21:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L1
  cmp    $0x3,%eax
  jle    L25
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L51:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  mov    (%rsp),%edx
  lea    0x3(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    %ebx,%eax
  jg     L51
  jmp    L8
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %d


assistant: ```c
int main(void) {
  int num, temp, sum, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sum = 0;
    for (i = 0; i < num / 4; i++) {
      scanf("%d\n", &temp);
      sum += temp;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L29
  cmp    $0x3,%eax
  jle    L48
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  call   <scanf@plt>
  mov    (%rsp),%edx
  add    0x4(%rsp),%r14d
  lea    0x3(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    %r13d,%eax
  jg     L2
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L15
  nopl   0x0(%rax)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L48:
  xor    %r14d,%r14d
  mov    %rbx,%rdi
  mov    %r14d,%esi
  call   <printf@plt>
  jmp    L15
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(void) {
  int num, temp, sum, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sum = 0;
    for (i = 0; i < num / 4; i++) {
      scanf("%d\n", &temp);
      sum += temp;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L5
  cmp    $0x3,%eax
  jle    L9
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  call   <scanf@plt>
  mov    (%rsp),%edx
  add    0x4(%rsp),%r14d
  lea    0x3(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    %r13d,%eax
  jg     L57
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L32
  nopl   0x0(%rax)
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L9:
  xor    %r14d,%r14d
  mov    %rbx,%rdi
  mov    %r14d,%esi
  call   <printf@plt>
  jmp    L32
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int main(void) {
  int num, temp, sum, i;
  while (1) {
    scanf("%d\n", &num);
    if (num == 0)
      break;
    sum = 0;
    for (i = 0; i < num / 4; i++) {
      scanf("%d\n", &temp);
      sum += temp;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L11
L38:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L22
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L11
L22:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L38
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int factors(int n) {
  int factors = 0;
  int factor = 2;
  while (factor * factor <= n) {
    if (n % factor == 0) {
      n /= factor;
      factors++;
    } else {
      factor++;
    }
  }
  return factors + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<factors>:
  endbr64
  cmp    $0x3,%edi
  jle    L32
  mov    $0x2,%ecx
  mov    $0x0,%esi
  jmp    L36
L39:
  add    $0x1,%ecx
L27:
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L0
L36:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L39
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  add    $0x1,%esi
  jmp    L27
L32:
  mov    $0x0,%esi
L0:
  lea    0x1(%rsi),%eax
  ret
```

assistant: ```c
int factors(int n) {
  int factors = 0;
  int factor = 2;
  while (factor * factor <= n) {
    if (n % factor == 0) {
      n /= factor;
      factors++;
    } else {
      factor++;
    }
  }
  return factors + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factors>:
  endbr64
  cmp    $0x3,%edi
  jle    L7
  mov    $0x2,%ecx
  xor    %esi,%esi
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %eax,%edi
  mov    %ecx,%eax
  add    $0x1,%esi
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L45
L46:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L12
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L46
L45:
  lea    0x1(%rsi),%eax
  ret
  nop
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int factors(int n) {
  int factors = 0;
  int factor = 2;
  while (factor * factor <= n) {
    if (n % factor == 0) {
      n /= factor;
      factors++;
    } else {
      factor++;
    }
  }
  return factors + 1;
}
```