ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D18(%rip),%r15
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L11:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L11
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L16
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D11
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D18: dsemch

tool: D11: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dsemch", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pty_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
L5:
  lea    -0x18(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L30
  mov    D46(%rip),%rax
  mov    (%rax),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L5
  mov    D46(%rip),%rax
  mov    (%rax),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L5
L30:
  cmpl   $0x1,-0x4(%rbp)
  je     L43
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L25
L43:
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int pty_send(int fd, char d) {
  int r;
  do {
    r = write(fd, &d, 1);
  } while (r < 0 && (errno == EINTR || errno == EAGAIN));
  return (r == 1) ? 0 : -EINVAL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pty_send>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rbp
L10:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L17
  mov    D31(%rip),%rax
  mov    (%rax),%rax
  mov    D19(%rip),%rdx
  cmp    (%rdx),%rax
  je     L10
  mov    D21(%rip),%rdx
  cmp    (%rdx),%rax
  je     L10
L12:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  neg    %edx
L5:
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x0,%edx
  cmp    $0x1,%eax
  je     L5
  jmp    L12
```

assistant: ```c
int pty_send(int fd, char d) {
  int r;
  do {
    r = write(fd, &d, 1);
  } while (r < 0 && (errno == EINTR || errno == EAGAIN));
  return (r == 1) ? 0 : -EINVAL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pty_send>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L24
  mov    D14(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L26
  mov    D27(%rip),%rdx
  cmp    (%rdx),%rax
  je     L26
L38:
  mov    D37(%rip),%rax
  mov    (%rax),%r8d
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  neg    %r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  xor    %r8d,%r8d
  cmp    $0x1,%eax
  jne    L38
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pty_send(int fd, char d) {
  int r;
  do {
    r = write(fd, &d, 1);
  } while (r < 0 && (errno == EINTR || errno == EAGAIN));
  return (r == 1) ? 0 : -EINVAL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pty_send>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L5
  mov    D1(%rip),%rax
  mov    D2(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L15
  mov    D38(%rip),%rdx
  cmp    (%rdx),%rax
  je     L15
L6:
  mov    D10(%rip),%rax
  mov    (%rax),%r8d
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  neg    %r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %r8d,%r8d
  cmp    $0x1,%eax
  jne    L6
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pty_send(int fd, char d) {
  int r;
  do {
    r = write(fd, &d, 1);
  } while (r < 0 && (errno == EINTR || errno == EAGAIN));
  return (r == 1) ? 0 : -EINVAL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<output_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movabs $0x100000208,%rdx
  movzbl -0x4(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void output_char(char c) {
  *(char *)(0x100000208) = c;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_char>:
  endbr64
  mov    %edi,%eax
  movabs %al,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(char *)(0x100000208) = c;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<output_char>:
  endbr64
  mov    %edi,%eax
  movabs %al,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(char *)(0x100000208) = c;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output_char>:
  endbr64
  mov    %edi,%eax
  movabs %al,0x100000208
  ret
```

assistant: ```c
void output_char(char c) {
  *(char *)(0x100000208) = c;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_region>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L2:
  mov    -0x14(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  imul   0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x40(%rbp),%eax
  add    %edx,%eax
  imul   0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    0x10(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    0x18(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy_region(unsigned char *out, unsigned char *in, int xout, int yout, int xin, int yin, int dx, int dy, int outw, int inw) {
  int j;
  unsigned char *outrow, *inrow;
  for (j = 0; j < dy; j++) {
    outrow = out + (j + yout) * outw;
    inrow = in + (j + yin) * inw;
    memcpy(outrow + xout, inrow + xin, dx);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy_region>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %edx,%eax
  mov    0x50(%rsp),%r14d
  mov    0x58(%rsp),%r13d
  mov    0x60(%rsp),%esi
  mov    0x68(%rsp),%edx
  test   %r13d,%r13d
  jle    L7
  mov    %rdi,%rbp
  movslq %esi,%r15
  imul   %esi,%ecx
  movslq %ecx,%rcx
  cltq
  add    %rax,%rcx
  add    %rcx,%rbp
  movslq %edx,%rax
  mov    %rax,0x8(%rsp)
  imul   %edx,%r9d
  movslq %r9d,%r9
  movslq %r8d,%r8
  add    %r9,%r8
  add    %r8,%rbx
  mov    $0x0,%r12d
L5:
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x1,%r12d
  add    %r15,%rbp
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L5
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy_region(unsigned char *out, unsigned char *in, int xout, int yout, int xin, int yin, int dx, int dy, int outw, int inw) {
  int j;
  unsigned char *outrow, *inrow;
  for (j = 0; j < dy; j++) {
    outrow = out + (j + yout) * outw;
    inrow = in + (j + yin) * inw;
    memcpy(outrow + xout, inrow + xin, dx);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy_region>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%r10d
  mov    0x40(%rsp),%r13d
  mov    0x50(%rsp),%edi
  mov    0x58(%rsp),%esi
  test   %r10d,%r10d
  jle    L3
  imul   %edi,%ecx
  movslq %edx,%rdx
  movslq %r8d,%r8
  movslq %edi,%r15
  imul   %esi,%r9d
  movslq %esi,%r14
  xor    %r12d,%r12d
  movslq %ecx,%rbx
  movslq %r9d,%r9
  add    %rdx,%rbx
  add    %r9,%r8
  add    %rax,%rbx
  add    %r8,%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r13d,%edx
  add    $0x1,%r12d
  call   <memcpy@plt>
  add    %r15,%rbx
  add    %r14,%rbp
  cmp    %r12d,0x48(%rsp)
  jne    L2
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy_region(unsigned char *out, unsigned char *in, int xout, int yout, int xin, int yin, int dx, int dy, int outw, int inw) {
  int j;
  unsigned char *outrow, *inrow;
  for (j = 0; j < dy; j++) {
    outrow = out + (j + yout) * outw;
    inrow = in + (j + yin) * inw;
    memcpy(outrow + xout, inrow + xin, dx);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy_region>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%r10d
  mov    0x40(%rsp),%r13d
  mov    0x50(%rsp),%edi
  mov    0x58(%rsp),%esi
  test   %r10d,%r10d
  jle    L2
  imul   %edi,%ecx
  movslq %edx,%rdx
  movslq %r8d,%r8
  movslq %edi,%r15
  imul   %esi,%r9d
  movslq %esi,%r14
  xor    %r12d,%r12d
  movslq %ecx,%rbx
  movslq %r9d,%r9
  add    %rdx,%rbx
  add    %r9,%r8
  add    %rax,%rbx
  add    %r8,%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r13d,%edx
  add    $0x1,%r12d
  call   <memcpy@plt>
  add    %r15,%rbx
  add    %r14,%rbp
  cmp    %r12d,0x48(%rsp)
  jne    L9
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy_region(unsigned char *out, unsigned char *in, int xout, int yout, int xin, int yin, int dx, int dy, int outw, int inw) {
  int j;
  unsigned char *outrow, *inrow;
  for (j = 0; j < dy; j++) {
    outrow = out + (j + yout) * outw;
    inrow = in + (j + yin) * inw;
    memcpy(outrow + xout, inrow + xin, dx);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<be200_uart_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <uart1_read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L55
  cmpl   $0x3,-0x4(%rbp)
  jg     L67
  cmpl   $0x1,-0x4(%rbp)
  je     L18
  cmpl   $0x2,-0x4(%rbp)
  je     L78
  jmp    L67
L18:
  mov    $0x0,%eax
  call   <be200_uart_set_freq@plt>
  jmp    L5
L78:
  mov    $0x0,%eax
  call   <be200_uart_nonce_test@plt>
  jmp    L5
L55:
  mov    $0x0,%eax
  call   <be200_uart_check_idle@plt>
  jmp    L5
L67:
  nop
L5:
  nop
  leave
  ret
```

assistant: ```c
void be200_uart_handler() {
  uint8_t cmd;
  cmd = uart1_read();
  switch (cmd) {
  case 0x01:
    be200_uart_set_freq();
    break;
  case 0x02:
    be200_uart_nonce_test();
    break;
  case 0x03:
    be200_uart_check_idle();
    break;
  default:
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<be200_uart_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <uart1_read@plt>
  cmp    $0x2,%eax
  je     L8
  cmp    $0x3,%eax
  je     L13
  cmp    $0x1,%eax
  je     L24
L25:
  add    $0x8,%rsp
  ret
L24:
  mov    $0x0,%eax
  call   <be200_uart_set_freq@plt>
  jmp    L25
L8:
  mov    $0x0,%eax
  call   <be200_uart_nonce_test@plt>
  jmp    L25
L13:
  mov    $0x0,%eax
  call   <be200_uart_check_idle@plt>
  jmp    L25
```

assistant: ```c
void be200_uart_handler() {
  uint8_t cmd;
  cmd = uart1_read();
  switch (cmd) {
  case 0x01:
    be200_uart_set_freq();
    break;
  case 0x02:
    be200_uart_nonce_test();
    break;
  case 0x03:
    be200_uart_check_idle();
    break;
  default:
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<be200_uart_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart1_read@plt>
  cmp    $0x2,%eax
  je     L24
  cmp    $0x3,%eax
  je     L3
  cmp    $0x1,%eax
  je     L13
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <be200_uart_nonce_test@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <be200_uart_set_freq@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <be200_uart_check_idle@plt>
```

assistant: ```c
void be200_uart_handler() {
  uint8_t cmd;
  cmd = uart1_read();
  switch (cmd) {
  case 0x01:
    be200_uart_set_freq();
    break;
  case 0x02:
    be200_uart_nonce_test();
    break;
  case 0x03:
    be200_uart_check_idle();
    break;
  default:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<be200_uart_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <uart1_read@plt>
  cmp    $0x2,%eax
  je     L26
  cmp    $0x3,%eax
  je     L16
  cmp    $0x1,%eax
  je     L29
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10a0 <be200_uart_nonce_test@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <be200_uart_set_freq@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <be200_uart_check_idle@plt>
```

assistant: ```c
void be200_uart_handler() {
  uint8_t cmd;
  cmd = uart1_read();
  switch (cmd) {
  case 0x01:
    be200_uart_set_freq();
    break;
  case 0x02:
    be200_uart_nonce_test();
    break;
  case 0x03:
    be200_uart_check_idle();
    break;
  default:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<brokenCalc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L12:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L30
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  jmp    L10
L30:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L10:
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L12
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int brokenCalc(int X, int Y) {
  int step = 0;
  while (X < Y) {
    Y = Y & 1 ? Y + 1 : Y / 2;
    step++;
  }
  step += X - Y;
  return step;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<brokenCalc>:
  endbr64
  cmp    %edi,%esi
  jle    L28
  mov    $0x0,%edx
  jmp    L49
L36:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
L11:
  add    $0x1,%edx
  cmp    %edi,%esi
  jle    L30
L49:
  test   $0x1,%sil
  je     L36
  add    $0x1,%esi
  jmp    L11
L28:
  mov    $0x0,%edx
L30:
  sub    %esi,%edi
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int brokenCalc(int X, int Y) {
  int step = 0;
  while (X < Y) {
    Y = Y & 1 ? Y + 1 : Y / 2;
    step++;
  }
  step += X - Y;
  return step;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<brokenCalc>:
  endbr64
  xor    %edx,%edx
  cmp    %edi,%esi
  jg     L27
  jmp    L20
  nopl   0x0(%rax)
L14:
  add    $0x1,%esi
  add    $0x1,%edx
  cmp    %edi,%esi
  jle    L20
L27:
  test   $0x1,%sil
  jne    L14
  mov    %esi,%eax
  add    $0x1,%edx
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
  cmp    %edi,%esi
  jg     L27
L20:
  sub    %esi,%edi
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int brokenCalc(int X, int Y) {
  int step = 0;
  while (X < Y) {
    Y = Y & 1 ? Y + 1 : Y / 2;
    step++;
  }
  step += X - Y;
  return step;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<brokenCalc>:
  endbr64
  xor    %edx,%edx
  cmp    %edi,%esi
  jg     L40
  jmp    L6
  nopl   0x0(%rax)
L37:
  add    $0x1,%esi
  add    $0x1,%edx
  cmp    %edi,%esi
  jle    L6
L40:
  test   $0x1,%sil
  jne    L37
  mov    %esi,%eax
  add    $0x1,%edx
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
  cmp    %edi,%esi
  jg     L40
L6:
  sub    %esi,%edi
  lea    (%rdi,%rdx,1),%eax
  ret
```

assistant: ```c
int brokenCalc(int X, int Y) {
  int step = 0;
  while (X < Y) {
    Y = Y & 1 ? Y + 1 : Y / 2;
    step++;
  }
  step += X - Y;
  return step;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kindColprintCompareLines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L37
  mov    -0x24(%rbp),%eax
  jmp    L2
L37:
  mov    -0x38(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L34
  mov    -0x24(%rbp),%eax
  jmp    L2
L34:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int kindColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_parser = colprintLineGetColumn(a, 0);
  const char *b_parser = colprintLineGetColumn(b, 0);
  const char *a_letter;
  const char *b_letter;
  int r;
  r = strcmp(a_parser, b_parser);
  if (r != 0)
    return r;
  a_letter = colprintLineGetColumn(a, 1);
  b_letter = colprintLineGetColumn(b, 1);
  r = strcmp(a_letter, b_letter);
  if (r != 0)
    return r;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kindColprintCompareLines>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%r12
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L3
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rbp
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  jmp    L17
```

assistant: ```c
int kindColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_parser = colprintLineGetColumn(a, 0);
  const char *b_parser = colprintLineGetColumn(b, 0);
  const char *a_letter;
  const char *b_letter;
  int r;
  r = strcmp(a_parser, b_parser);
  if (r != 0)
    return r;
  a_letter = colprintLineGetColumn(a, 1);
  b_letter = colprintLineGetColumn(b, 1);
  r = strcmp(a_letter, b_letter);
  if (r != 0)
    return r;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<kindColprintCompareLines>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <colprintLineGetColumn@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <colprintLineGetColumn@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L2
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <colprintLineGetColumn@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %rax,%rsi
  pop    %r13
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int kindColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_parser = colprintLineGetColumn(a, 0);
  const char *b_parser = colprintLineGetColumn(b, 0);
  const char *a_letter;
  const char *b_letter;
  int r;
  r = strcmp(a_parser, b_parser);
  if (r != 0)
    return r;
  a_letter = colprintLineGetColumn(a, 1);
  b_letter = colprintLineGetColumn(b, 1);
  r = strcmp(a_letter, b_letter);
  if (r != 0)
    return r;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kindColprintCompareLines>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <colprintLineGetColumn@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <colprintLineGetColumn@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L7
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <colprintLineGetColumn@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %rax,%rsi
  pop    %r13
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int kindColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_parser = colprintLineGetColumn(a, 0);
  const char *b_parser = colprintLineGetColumn(b, 0);
  const char *a_letter;
  const char *b_letter;
  int r;
  r = strcmp(a_parser, b_parser);
  if (r != 0)
    return r;
  a_letter = colprintLineGetColumn(a, 1);
  b_letter = colprintLineGetColumn(b, 1);
  r = strcmp(a_letter, b_letter);
  if (r != 0)
    return r;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  xor    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
L7:
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t parity(uint32_t dat) {
  uint32_t ret = 0;
  for (; dat; dat >>= 1)
    ret ^= dat & 1;
  return ret & 1;
}
```