ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L9
  mov    %edi,%eax
  cltd
  idiv   %esi
L9:
  ret
```

assistant: ```c
int f(int a, int b) {
  if (b == 0)
    return 0;
  return a / b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L4
  mov    %edi,%eax
  cltd
  idiv   %esi
L4:
  ret
```

assistant: ```c
int f(int a, int b) {
  if (b == 0)
    return 0;
  return a / b;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L3
  mov    %edi,%eax
  cltd
  idiv   %esi
L3:
  ret
```

assistant: ```c
int f(int a, int b) {
  if (b == 0)
    return 0;
  return a / b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ary_cb_freecharptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ary_xfree@plt>
  nop
  leave
  ret
```

assistant: ```c
void ary_cb_freecharptr(void *buf, void *userp) {
  (void)userp;
  ary_xfree(*(char **)buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<ary_cb_freecharptr>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <ary_xfree@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ary_cb_freecharptr(void *buf, void *userp) {
  (void)userp;
  ary_xfree(*(char **)buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ary_cb_freecharptr>:
  endbr64
  mov    (%rdi),%rdi
  jmp    1050 <ary_xfree@plt>
```

assistant: ```c
void ary_cb_freecharptr(void *buf, void *userp) {
  (void)userp;
  ary_xfree(*(char **)buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ary_cb_freecharptr>:
  endbr64
  mov    (%rdi),%rdi
  jmp    1050 <ary_xfree@plt>
```

assistant: ```c
void ary_cb_freecharptr(void *buf, void *userp) {
  (void)userp;
  ary_xfree(*(char **)buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<client>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  mov    $0x0,%eax
  call   <fail@plt>
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <parrot@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int client(int (*func)(const char *arg), const char *arg) {
  int fd = func(arg);
  if (fd < 0) {
    fail();
  }
  parrot(fd);
  close(fd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<client>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  call   *%rax
  mov    %eax,%ebx
  test   %eax,%eax
  js     L5
L14:
  mov    %ebx,%edi
  call   <parrot@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  call   <fail@plt>
  jmp    L14
```

assistant: ```c
int client(int (*func)(const char *arg), const char *arg) {
  int fd = func(arg);
  if (fd < 0) {
    fail();
  }
  parrot(fd);
  close(fd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<client>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  call   *%r8
  mov    %eax,%ebp
  test   %eax,%eax
  js     L4
L5:
  mov    %ebp,%edi
  call   <parrot@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <fail@plt>
  jmp    L5
```

assistant: ```c
int client(int (*func)(const char *arg), const char *arg) {
  int fd = func(arg);
  if (fd < 0) {
    fail();
  }
  parrot(fd);
  close(fd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<client>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  call   *%r8
  mov    %eax,%ebp
  test   %eax,%eax
  js     L6
L9:
  mov    %ebp,%edi
  call   <parrot@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <fail@plt>
  jmp    L9
```

assistant: ```c
int client(int (*func)(const char *arg), const char *arg) {
  int fd = func(arg);
  if (fd < 0) {
    fail();
  }
  parrot(fd);
  close(fd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<warnf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <warnvf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void warnf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  warnvf(fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<warnf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <warnvf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void warnf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  warnvf(fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<warnf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <warnvf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void warnf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  warnvf(fmt, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<warnf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <warnvf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void warnf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  warnvf(fmt, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int sum, i;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L3
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
L1:
  mov    (%rbx),%rdi
  call   <atoi@plt>
  add    %eax,%ebp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
L3:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int sum, i;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L18
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %r12,%rbx
  jne    L12
L18:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int sum, i;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L7
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %r12,%rbx
  jne    L15
L7:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int sum, i;
  for (i = 1; i < argc; i++) {
    sum += atoi(argv[i]);
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StringCopyExcept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0x20(%rbp)
  jmp    L42
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jl     L4
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L19
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x28(%rbp)
L3:
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
L19:
  pop    %rbp
  ret
```

assistant: ```c
void StringCopyExcept(char *in, int except, int maxlen, char *out) {
  char *orig_out;
  orig_out = out;
  maxlen--;
  while (*in) {
    if ((unsigned char)*in != except) {
      if ((out - orig_out) >= maxlen) {
        orig_out[maxlen] = '\0';
        return;
      }
      *out = *in;
      out++;
    }
    in++;
  }
  *out = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<StringCopyExcept>:
  endbr64
  sub    $0x1,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  mov    %rcx,%r8
  movslq %edx,%r10
  jmp    L5
L18:
  movslq %edx,%rdx
  movb   $0x0,(%rcx,%rdx,1)
  ret
L9:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
L5:
  movzbl %al,%r9d
  cmp    %esi,%r9d
  je     L9
  mov    %r8,%r9
  sub    %rcx,%r9
  cmp    %r10,%r9
  jge    L18
  mov    %al,(%r8)
  add    $0x1,%r8
  jmp    L9
L17:
  mov    %rcx,%r8
L36:
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
void StringCopyExcept(char *in, int except, int maxlen, char *out) {
  char *orig_out;
  orig_out = out;
  maxlen--;
  while (*in) {
    if ((unsigned char)*in != except) {
      if ((out - orig_out) >= maxlen) {
        orig_out[maxlen] = '\0';
        return;
      }
      *out = *in;
      out++;
    }
    in++;
  }
  *out = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StringCopyExcept>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x1,%edx
  mov    %rcx,%r8
  test   %al,%al
  je     L10
  movslq %edx,%rdx
  nopl   0x0(%rax)
L37:
  movzbl %al,%r9d
  cmp    %esi,%r9d
  je     L30
  mov    %r8,%r9
  sub    %rcx,%r9
  cmp    %rdx,%r9
  jge    L20
  mov    %al,(%r8)
  add    $0x1,%r8
L30:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L37
L10:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L20:
  movb   $0x0,(%rcx,%rdx,1)
  ret
```

assistant: ```c
void StringCopyExcept(char *in, int except, int maxlen, char *out) {
  char *orig_out;
  orig_out = out;
  maxlen--;
  while (*in) {
    if ((unsigned char)*in != except) {
      if ((out - orig_out) >= maxlen) {
        orig_out[maxlen] = '\0';
        return;
      }
      *out = *in;
      out++;
    }
    in++;
  }
  *out = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<StringCopyExcept>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x1,%edx
  mov    %rcx,%r8
  test   %al,%al
  je     L38
  movslq %edx,%rdx
  nopl   0x0(%rax)
L1:
  movzbl %al,%r9d
  cmp    %esi,%r9d
  je     L34
  mov    %r8,%r9
  sub    %rcx,%r9
  cmp    %rdx,%r9
  jge    L10
  mov    %al,(%r8)
  add    $0x1,%r8
L34:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L1
L38:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L10:
  movb   $0x0,(%rcx,%rdx,1)
  ret
```

assistant: ```c
void StringCopyExcept(char *in, int except, int maxlen, char *out) {
  char *orig_out;
  orig_out = out;
  maxlen--;
  while (*in) {
    if ((unsigned char)*in != except) {
      if ((out - orig_out) >= maxlen) {
        orig_out[maxlen] = '\0';
        return;
      }
      *out = *in;
      out++;
    }
    in++;
  }
  *out = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L32
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  add    %rax,-0x8(%rbp)
  jmp    L35
L20:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L35:
  cmpq   $0x0,-0x28(%rbp)
  jne    L20
  jmp    L27
L38:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L32:
  cmpq   $0x0,-0x28(%rbp)
  jne    L38
L27:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memmove(void *dst, void const *src, size_t len) {
  char *t1;
  char *t2;
  t1 = (char *)src;
  t2 = (char *)dst;
  if (t1 < t2) {
    t1 += len - 1;
    t2 += len - 1;
    while (len > 0) {
      *t2-- = *t1--;
      len--;
    }
  } else {
    while (len > 0) {
      *t2++ = *t1++;
      len--;
    }
  }
  return (dst);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jb     L12
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L5
L9:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L9
L1:
  ret
L5:
  ret
L12:
  test   %rdx,%rdx
  je     L1
L0:
  movzbl -0x1(%rsi,%rdx,1),%ecx
  mov    %cl,-0x1(%rax,%rdx,1)
  sub    $0x1,%rdx
  jne    L0
  ret
```

assistant: ```c
void *ft_memmove(void *dst, void const *src, size_t len) {
  char *t1;
  char *t2;
  t1 = (char *)src;
  t2 = (char *)dst;
  if (t1 < t2) {
    t1 += len - 1;
    t2 += len - 1;
    while (len > 0) {
      *t2-- = *t1--;
      len--;
    }
  } else {
    while (len > 0) {
      *t2++ = *t1++;
      len--;
    }
  }
  return (dst);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jb     L22
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L35
  nopl   0x0(%rax,%rax,1)
L39:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L39
L5:
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  test   %rdx,%rdx
  je     L5
  lea    -0x1(%rsi),%rdi
  lea    -0x1(%rax),%rsi
  nopl   (%rax)
L42:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  jne    L42
  ret
  xchg   %ax,%ax
L35:
  ret
```

assistant: ```c
void *ft_memmove(void *dst, void const *src, size_t len) {
  char *t1;
  char *t2;
  t1 = (char *)src;
  t2 = (char *)dst;
  if (t1 < t2) {
    t1 += len - 1;
    t2 += len - 1;
    while (len > 0) {
      *t2-- = *t1--;
      len--;
    }
  } else {
    while (len > 0) {
      *t2++ = *t1++;
      len--;
    }
  }
  return (dst);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rax
  cmp    %rdi,%rsi
  jb     L55
  test   %rdx,%rdx
  je     L178
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L98
  cmp    $0x6,%rdx
  jbe    L98
  cmp    $0xe,%rdx
  jbe    L68
  mov    %rax,%rsi
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rsi
  nopl   0x0(%rax)
L20:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rsi
  jne    L20
  mov    %rax,%r9
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%r9
  and    $0xf,%edx
  lea    (%rcx,%r9,1),%rdi
  lea    (%r8,%r9,1),%rsi
  cmp    %r9,%rax
  je     L178
  lea    -0x1(%rdx),%r10
  mov    %rdx,%rax
  cmp    $0x6,%r10
  jbe    L80
L95:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%r8,%r9,1)
  mov    %rax,%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %rcx,%rdi
  add    %rcx,%rsi
  cmp    %rcx,%rax
  je     L178
  lea    -0x1(%rdx),%r10
L80:
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %r10,%r10
  je     L178
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%rsi)
  cmp    $0x2,%rdx
  je     L178
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%rsi)
  cmp    $0x3,%rdx
  je     L178
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%rsi)
  cmp    $0x4,%rdx
  je     L178
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%rsi)
  cmp    $0x5,%rdx
  je     L178
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%rsi)
  cmp    $0x6,%rdx
  je     L178
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rsi)
L178:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L55:
  test   %rdx,%rdx
  je     L178
  lea    -0x1(%rsi),%rsi
  lea    -0x1(%rdi),%rcx
  nopl   (%rax)
L81:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  sub    $0x1,%rax
  jne    L81
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L98:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L142:
  movzbl (%rcx,%rdx,1),%esi
  mov    %sil,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L142
  jmp    L178
L68:
  mov    %r8,%rsi
  mov    %rcx,%rdi
  mov    %rax,%rdx
  xor    %r9d,%r9d
  jmp    L95
```

assistant: ```c
void *ft_memmove(void *dst, void const *src, size_t len) {
  char *t1;
  char *t2;
  t1 = (char *)src;
  t2 = (char *)dst;
  if (t1 < t2) {
    t1 += len - 1;
    t2 += len - 1;
    while (len > 0) {
      *t2-- = *t1--;
      len--;
    }
  } else {
    while (len > 0) {
      *t2++ = *t1++;
      len--;
    }
  }
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytes_to_hex_uc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  cltq
  lea    D5(%rip),%rdx
  movzbl (%rax,%rdx,1),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  cltq
  lea    D5(%rip),%rdx
  movzbl (%rax,%rdx,1),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L17
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: 0123456789ABCDEF

assistant: ```c
size_t bytes_to_hex_uc(const void *input, size_t size, unsigned char *output) {
  size_t i;
  const unsigned char *p;
  for (i = 0, p = (const unsigned char *)input; i < size; ++i, ++p) {
    *output++ = "0123456789ABCDEF"[(*p) >> 4];
    *output++ = "0123456789ABCDEF"[(*p) & 15];
  }
  *output = '\0';
  return 2 * size + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bytes_to_hex_uc>:
  endbr64
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L9
  lea    (%rdi,%rsi,1),%r9
  mov    %rdx,%rdi
  lea    D9(%rip),%r8
L12:
  movzbl (%rcx),%eax
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,(%rdi)
  add    $0x2,%rdi
  movzbl (%rcx),%eax
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,-0x1(%rdi)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L12
  lea    (%rdx,%rsi,2),%rdx
L9:
  movb   $0x0,(%rdx)
  lea    0x1(%rsi,%rsi,1),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: 0123456789ABCDEF

assistant: ```c
size_t bytes_to_hex_uc(const void *input, size_t size, unsigned char *output) {
  size_t i;
  const unsigned char *p;
  for (i = 0, p = (const unsigned char *)input; i < size; ++i, ++p) {
    *output++ = "0123456789ABCDEF"[(*p) >> 4];
    *output++ = "0123456789ABCDEF"[(*p) & 15];
  }
  *output = '\0';
  return 2 * size + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bytes_to_hex_uc>:
  endbr64
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L7
  lea    (%rdi,%rsi,1),%r9
  lea    D6(%rip),%r8
  mov    %rdx,%rdi
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rcx),%eax
  add    $0x2,%rdi
  add    $0x1,%rcx
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,-0x2(%rdi)
  movzbl -0x1(%rcx),%eax
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%r9
  jne    L15
  lea    (%rdx,%rsi,2),%rdx
L7:
  movb   $0x0,(%rdx)
  lea    0x1(%rsi,%rsi,1),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: 0123456789ABCDEF

assistant: ```c
size_t bytes_to_hex_uc(const void *input, size_t size, unsigned char *output) {
  size_t i;
  const unsigned char *p;
  for (i = 0, p = (const unsigned char *)input; i < size; ++i, ++p) {
    *output++ = "0123456789ABCDEF"[(*p) >> 4];
    *output++ = "0123456789ABCDEF"[(*p) & 15];
  }
  *output = '\0';
  return 2 * size + 1;
}
```