ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L13:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <lame_read_stat@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D12
type: f32[2]

tool: D1: [P %f]


tool: {"D12": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0.0;
  while (1) {
    if (lame_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  lea    D15(%rip),%rbp
  jmp    L14
L6:
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
L11:
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
L14:
  mov    %rbx,%rdi
  call   <lame_read_stat@plt>
  test   %rax,%rax
  je     L6
  jmp    L11
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D16
data_type: f32[2]

tool: D15: [P %f]


tool: {"D16": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0.0;
  while (1) {
    if (lame_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  call   <lame_read_stat@plt>
  test   %rax,%rax
  jne    L16
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
L16:
  mov    D3(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D3
type: f32[2]

tool: D19: [P %f]


tool: {"D3": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0.0;
  while (1) {
    if (lame_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L9:
  mov    %rbx,%rdi
  call   <lame_read_stat@plt>
  test   %rax,%rax
  jne    L1
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
L1:
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: f32[2]

tool: D12: [P %f]


tool: {"D6": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0.0;
  while (1) {
    if (lame_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = stat("/tmp/foo", &buf);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <stat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = stat("/tmp/foo", &buf);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = stat("/tmp/foo", &buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = stat("/tmp/foo", &buf);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Congru_Mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L16:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Congru_Mod(int a, int b, int m) {
  int result = 1;
  for (int i = 0; i < b; i++) {
    result = (result * a) % m;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Congru_Mod>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L27
  mov    $0x0,%ecx
  mov    $0x1,%edx
L0:
  mov    %edx,%eax
  imul   %edi,%eax
  cltd
  idiv   %r8d
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L0
L23:
  mov    %edx,%eax
  ret
L27:
  mov    $0x1,%edx
  jmp    L23
```

assistant: ```c
int Congru_Mod(int a, int b, int m) {
  int result = 1;
  for (int i = 0; i < b; i++) {
    result = (result * a) % m;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Congru_Mod>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L1
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edx,%eax
  add    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %r8d
  cmp    %ecx,%esi
  jne    L10
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int Congru_Mod(int a, int b, int m) {
  int result = 1;
  for (int i = 0; i < b; i++) {
    result = (result * a) % m;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Congru_Mod>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L3
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edx,%eax
  add    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %r8d
  cmp    %ecx,%esi
  jne    L11
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int Congru_Mod(int a, int b, int m) {
  int result = 1;
  for (int i = 0; i < b; i++) {
    result = (result * a) % m;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_correct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x84(%rbp)
  jmp    L24
L8:
  movl   $0x0,-0x80(%rbp)
  jmp    L41
L69:
  mov    -0x84(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rax,%rdx
  mov    -0x80(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x7c(%rbp)
  mov    -0x84(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rax,%rdx
  mov    -0x80(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x80(%rbp),%r8d
  mov    -0x84(%rbp),%edi
  lea    -0x70(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  lea    -0x78(%rbp),%rsi
  mov    -0x98(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <alloc_values@plt>
  mov    -0x78(%rbp),%rsi
  lea    -0x70(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  mov    -0x7c(%rbp),%eax
  mov    %eax,%edi
  call   <findx@plt>
  cmp    $0x1,%eax
  jne    L27
  mov    -0x84(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x98(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x80(%rbp),%eax
  cltq
  mov    -0x7c(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    $0x1,%eax
  jmp    L25
L27:
  mov    -0x84(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x98(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x80(%rbp),%eax
  cltq
  mov    -0x7c(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0x80(%rbp)
L41:
  cmpl   $0x8,-0x80(%rbp)
  jle    L69
  addl   $0x1,-0x84(%rbp)
L24:
  cmpl   $0x8,-0x84(%rbp)
  jle    L8
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int is_correct(int S[9][9]) {
  int i, j, key, *H_arr, *V_arr[9], *B_arr[3];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      key = S[i][j];
      S[i][j] = 0;
      alloc_values(S, &H_arr, V_arr, B_arr, i, j);
      if (findx(key, H_arr, V_arr, B_arr) == 1) {
        S[i][j] = key;
        return 1;
      }
      S[i][j] = key;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_correct>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x20(%rsp),%r14
  jmp    L31
L47:
  movslq 0x4(%rsp),%rdx
  mov    %r13d,0x0(%rbp,%rdx,4)
L40:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    $0x9,%rax
  je     L54
L31:
  mov    0x8(%rsp),%rax
  mov    %eax,(%rsp)
  lea    (%rax,%rax,8),%rax
  lea    (%r15,%rax,4),%rbp
  mov    $0x0,%ebx
L48:
  mov    %ebx,0x4(%rsp)
  mov    0x0(%rbp,%rbx,4),%r13d
  movl   $0x0,0x0(%rbp,%rbx,4)
  lea    0x40(%rsp),%r12
  lea    0x18(%rsp),%rsi
  mov    %ebx,%r9d
  mov    (%rsp),%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r15,%rdi
  call   <alloc_values@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    0x18(%rsp),%rsi
  mov    %r13d,%edi
  call   <findx@plt>
  cmp    $0x1,%eax
  je     L47
  mov    %r13d,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  jne    L48
  jmp    L37
L54:
  mov    $0x0,%eax
  jmp    L40
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_correct(int S[9][9]) {
  int i, j, key, *H_arr, *V_arr[9], *B_arr[3];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      key = S[i][j];
      S[i][j] = 0;
      alloc_values(S, &H_arr, V_arr, B_arr, i, j);
      if (findx(key, H_arr, V_arr, B_arr) == 1) {
        S[i][j] = key;
        return 1;
      }
      S[i][j] = key;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_correct>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rax
  lea    0x30(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x50(%rsp),%rbp
L40:
  mov    0x18(%rsp),%rax
  xor    %r15d,%r15d
  mov    %eax,%r8d
  lea    (%rax,%rax,8),%rax
  lea    0x0(%r13,%rax,4),%r14
  mov    %r14,%rax
  mov    %r15,%r14
  mov    %rax,%r15
  nopl   (%rax)
L39:
  mov    (%r15,%r14,4),%ebx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%r9d
  mov    %r12,%rcx
  movl   $0x0,(%r15,%r14,4)
  mov    %rbp,%rdx
  mov    %r13,%rdi
  mov    %r8d,0x10(%rsp)
  mov    %r14d,0x14(%rsp)
  call   <alloc_values@plt>
  mov    0x28(%rsp),%rsi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <findx@plt>
  mov    0x10(%rsp),%r8d
  cmp    $0x1,%eax
  je     L35
  mov    %ebx,(%r15,%r14,4)
  add    $0x1,%r14
  cmp    $0x9,%r14
  jne    L39
  addq   $0x1,0x18(%rsp)
  mov    0x18(%rsp),%rax
  cmp    $0x9,%rax
  jne    L40
  xor    %eax,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L35:
  movslq 0x14(%rsp),%rdx
  mov    %ebx,(%r15,%rdx,4)
L48:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_correct(int S[9][9]) {
  int i, j, key, *H_arr, *V_arr[9], *B_arr[3];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      key = S[i][j];
      S[i][j] = 0;
      alloc_values(S, &H_arr, V_arr, B_arr, i, j);
      if (findx(key, H_arr, V_arr, B_arr) == 1) {
        S[i][j] = key;
        return 1;
      }
      S[i][j] = key;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_correct>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rax
  lea    0x30(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  lea    0x50(%rsp),%rbp
L16:
  mov    0x18(%rsp),%rax
  xor    %r15d,%r15d
  mov    %eax,%r8d
  lea    (%rax,%rax,8),%rax
  lea    0x0(%r13,%rax,4),%r14
  mov    %r14,%rax
  mov    %r15,%r14
  mov    %rax,%r15
  nopl   (%rax)
L28:
  mov    (%r15,%r14,4),%ebx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%r9d
  mov    %r12,%rcx
  movl   $0x0,(%r15,%r14,4)
  mov    %rbp,%rdx
  mov    %r13,%rdi
  mov    %r8d,0x10(%rsp)
  mov    %r14d,0x14(%rsp)
  call   <alloc_values@plt>
  mov    0x28(%rsp),%rsi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <findx@plt>
  mov    0x10(%rsp),%r8d
  cmp    $0x1,%eax
  je     L19
  mov    %ebx,(%r15,%r14,4)
  add    $0x1,%r14
  cmp    $0x9,%r14
  jne    L28
  addq   $0x1,0x18(%rsp)
  mov    0x18(%rsp),%rax
  cmp    $0x9,%rax
  jne    L16
  xor    %eax,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L19:
  movslq 0x14(%rsp),%rdx
  mov    %ebx,(%r15,%rdx,4)
L48:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_correct(int S[9][9]) {
  int i, j, key, *H_arr, *V_arr[9], *B_arr[3];
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      key = S[i][j];
      S[i][j] = 0;
      alloc_values(S, &H_arr, V_arr, B_arr, i, j);
      if (findx(key, H_arr, V_arr, B_arr) == 1) {
        S[i][j] = key;
        return 1;
      }
      S[i][j] = key;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L25
L85:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L85
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L85
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L85
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L4
L36:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L36
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  subq   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void parse(char *command, char **args) {
  while (*command != '\0') {
    while (*command == ' ' || *command == '\t' || *command == '\n') {
      *command++ = '\0';
    }
    *args++ = command;
    while (*command != '\0' && *command != ' ' && *command != '\t' && *command != '\n') {
      command++;
    }
  }
  *--args = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse>:
  endbr64
  cmpb   $0x0,(%rdi)
  jne    L79
L15:
  movq   $0x0,-0x8(%rsi)
  ret
L65:
  cmpb   $0x0,(%rdi)
  je     L15
L79:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L103
  cmp    $0x20,%al
  jne    L14
L103:
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L103
  cmp    $0x20,%al
  je     L103
L14:
  add    $0x8,%rsi
  mov    %rdi,-0x8(%rsi)
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L65
  test   $0xdf,%al
  je     L65
L19:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L65
  test   $0xdf,%al
  jne    L19
  jmp    L65
```

assistant: ```c
void parse(char *command, char **args) {
  while (*command != '\0') {
    while (*command == ' ' || *command == '\t' || *command == '\n') {
      *command++ = '\0';
    }
    *args++ = command;
    while (*command != '\0' && *command != ' ' && *command != '\t' && *command != '\n') {
      command++;
    }
  }
  *--args = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<parse>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  nopl   0x0(%rax,%rax,1)
L77:
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L21
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L11
L21:
  cmp    $0x20,%al
  je     L11
  mov    %rdi,(%rsi)
  movzbl (%rdi),%eax
  add    $0x8,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L48
  jmp    L46
  nopl   0x0(%rax)
L52:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L46
L48:
  test   $0xdf,%al
  jne    L52
L46:
  test   %al,%al
  jne    L77
L30:
  movq   $0x0,-0x8(%rsi)
  ret
```

assistant: ```c
void parse(char *command, char **args) {
  while (*command != '\0') {
    while (*command == ' ' || *command == '\t' || *command == '\n') {
      *command++ = '\0';
    }
    *args++ = command;
    while (*command != '\0' && *command != ' ' && *command != '\t' && *command != '\n') {
      command++;
    }
  }
  *--args = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L40
  nopl   0x0(%rax,%rax,1)
L25:
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L42
  nopl   0x0(%rax,%rax,1)
L89:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L89
L42:
  cmp    $0x20,%al
  je     L89
  mov    %rdi,(%rsi)
  movzbl (%rdi),%eax
  add    $0x8,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L5
  jmp    L36
  nopl   0x0(%rax)
L73:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L36
L5:
  test   $0xdf,%al
  jne    L73
L36:
  test   %al,%al
  jne    L25
L40:
  movq   $0x0,-0x8(%rsi)
  ret
```

assistant: ```c
void parse(char *command, char **args) {
  while (*command != '\0') {
    while (*command == ' ' || *command == '\t' || *command == '\n') {
      *command++ = '\0';
    }
    *args++ = command;
    while (*command != '\0' && *command != ' ' && *command != '\t' && *command != '\n') {
      command++;
    }
  }
  *--args = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rank_first_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x3(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%al
  jge    L27
  mov    $0xffffffff,%eax
  jmp    L32
L27:
  movzbl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%al
  jle    L62
  mov    $0x1,%eax
  jmp    L32
L62:
  movzbl -0x3(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L14
  mov    $0xffffffff,%eax
  jmp    L32
L14:
  movzbl -0x3(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jle    L64
  mov    $0x1,%eax
  jmp    L32
L64:
  mov    $0x0,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
int rank_first_compare(void *a, void *b) {
  char rank1 = *((char *)a);
  char suit1 = *(((char *)a + 1));
  char rank2 = *((char *)b);
  char suit2 = *(((char *)b + 1));
  if (rank1 < rank2)
    return -1;
  else if (rank1 > rank2)
    return 1;
  else if (suit1 < suit2)
    return -1;
  else if (suit1 > suit2)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rank_first_compare>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jl     L0
  mov    $0x1,%eax
  jg     L0
  movzbl 0x1(%rdi),%ecx
  movzbl 0x1(%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %dl,%cl
  jl     L0
  setg   %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int rank_first_compare(void *a, void *b) {
  char rank1 = *((char *)a);
  char suit1 = *(((char *)a + 1));
  char rank2 = *((char *)b);
  char suit2 = *(((char *)b + 1));
  if (rank1 < rank2)
    return -1;
  else if (rank1 > rank2)
    return 1;
  else if (suit1 < suit2)
    return -1;
  else if (suit1 > suit2)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rank_first_compare>:
  endbr64
  movzbl (%rsi),%ecx
  mov    $0xffffffff,%eax
  cmp    %cl,(%rdi)
  jl     L19
  mov    $0x1,%eax
  jg     L19
  movzbl 0x1(%rsi),%eax
  cmp    %al,0x1(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
L19:
  ret
```

assistant: ```c
int rank_first_compare(void *a, void *b) {
  char rank1 = *((char *)a);
  char suit1 = *(((char *)a + 1));
  char rank2 = *((char *)b);
  char suit2 = *(((char *)b + 1));
  if (rank1 < rank2)
    return -1;
  else if (rank1 > rank2)
    return 1;
  else if (suit1 < suit2)
    return -1;
  else if (suit1 > suit2)
    return 1;
  else
    return 0;
}
```