ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_mount>:
  endbr64
  push   %r13
  lea    D8(%rip),%rsi
  mov    %rdi,%r13
  lea    D14(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L38
  jmp    L51
  nopl   (%rax)
L54:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L51
  lea    0x1(%rax),%r12
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L51
  movb   $0x0,(%rax)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L32
L38:
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L54
  mov    %rbp,%rdi
  call   <fclose@plt>
L51:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D8: r

tool: D14: /proc/mounts

assistant: ```c
char *find_mount(char *mp) {
  FILE *fp = fopen("/proc/mounts", "r");
  static char line[256];
  char *point = NULL;
  if (!fp)
    return NULL;
  while (fgets(line, sizeof(line), fp)) {
    char *s, *t = strstr(line, " ");
    if (!t)
      return NULL;
    t++;
    s = strstr(t, " ");
    if (!s)
      return NULL;
    *s = '\0';
    if (!strcmp(t, mp)) {
      fclose(fp);
      return t;
    }
  }
  fclose(fp);
  return point;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TEST_cpp_line_directive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D26
data_type: string
name: parse_data
arguments: label: D24
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D20
data_type: string

tool: D26: #line 50
__LINE__

tool: D24: 50

tool: D30: #line 50 "foo"
__LINE__ __FILE__

tool: D20: 50 "foo"

assistant: ```c
void TEST_cpp_line_directive(void) {
  test("50", "#line 50\n"
             "__LINE__");
  test("50 \"foo\"", "#line 50 \"foo\"\n"
                     "__LINE__ __FILE__");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TEST_cpp_line_directive>:
  endbr64
  sub    $0x8,%rsp
  lea    D30(%rip),%rsi
  lea    D37(%rip),%rdi
  call   <test@plt>
  lea    D29(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <test@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D30
datatype: string
name: read_data
arguments: data_label: D37
datatype: string
name: read_data
arguments: data_label: D29
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D30: #line 50
__LINE__

tool: D37: 50

tool: D29: #line 50 "foo"
__LINE__ __FILE__

tool: D4: 50 "foo"

assistant: ```c
void TEST_cpp_line_directive(void) {
  test("50", "#line 50\n"
             "__LINE__");
  test("50 \"foo\"", "#line 50 \"foo\"\n"
                     "__LINE__ __FILE__");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TEST_cpp_line_directive>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <test@plt>
  lea    D22(%rip),%rsi
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <test@plt>
```

tool_calls: name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D28
data_type: string

tool: D10: #line 50
__LINE__

tool: D16: 50

tool: D22: #line 50 "foo"
__LINE__ __FILE__

tool: D28: 50 "foo"

assistant: ```c
void TEST_cpp_line_directive(void) {
  test("50", "#line 50\n"
             "__LINE__");
  test("50 \"foo\"", "#line 50 \"foo\"\n"
                     "__LINE__ __FILE__");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TEST_cpp_line_directive>:
  endbr64
  sub    $0x8,%rsp
  lea    D29(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <test@plt>
  lea    D1(%rip),%rsi
  lea    D23(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <test@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string

tool: D29: #line 50
__LINE__

tool: D27: 50

tool: D1: #line 50 "foo"
__LINE__ __FILE__

tool: D23: 50 "foo"

assistant: ```c
void TEST_cpp_line_directive(void) {
  test("50", "#line 50\n"
             "__LINE__");
  test("50 \"foo\"", "#line 50 \"foo\"\n"
                     "__LINE__ __FILE__");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<conv_i32_to_d32_and_d16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    %edx,%eax
  test   %rax,%rax
  js     L50
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L17
L50:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L17:
  movsd  %xmm0,(%rcx)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    %edx,%eax
  test   %rax,%rax
  js     L3
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L13
L3:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L13:
  movsd  %xmm0,(%rcx)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    %edx,%eax
  test   %rax,%rax
  js     L77
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L72
L77:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L72:
  movsd  %xmm0,(%rcx)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L25
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void conv_i32_to_d32_and_d16(double *d32, double *d16, unsigned int *i32, int len) {
  int i = 0;
  unsigned int a;
#pragma pipeloop(0)
  for (; i < len; i++) {
    a = i32[i];
    d32[i] = (double)(i32[i]);
    d16[2 * i] = (double)(a & 0xffff);
    d16[2 * i + 1] = (double)(a >> 16);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<conv_i32_to_d32_and_d16>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%r9
  test   %ecx,%ecx
  jle    L19
  mov    %ecx,%ecx
  mov    $0x0,%edx
L0:
  mov    (%r9,%rdx,4),%eax
  mov    %eax,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  movsd  %xmm0,(%r8,%rdx,8)
  movzwl %ax,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  movsd  %xmm0,(%rsi)
  shr    $0x10,%eax
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,0x8(%rsi)
  add    $0x1,%rdx
  add    $0x10,%rsi
  cmp    %rcx,%rdx
  jne    L0
L19:
  ret
```

assistant: ```c
void conv_i32_to_d32_and_d16(double *d32, double *d16, unsigned int *i32, int len) {
  int i = 0;
  unsigned int a;
#pragma pipeloop(0)
  for (; i < len; i++) {
    a = i32[i];
    d32[i] = (double)(i32[i]);
    d16[2 * i] = (double)(a & 0xffff);
    d16[2 * i + 1] = (double)(a >> 16);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<conv_i32_to_d32_and_d16>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%r9
  test   %ecx,%ecx
  jle    L17
  movslq %ecx,%rcx
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%r9,%rdx,4),%edi
  pxor   %xmm0,%xmm0
  add    $0x10,%rsi
  cvtsi2sd %rdi,%xmm0
  mov    %rdi,%rax
  movzwl %di,%edi
  shr    $0x10,%eax
  movsd  %xmm0,(%r8,%rdx,8)
  pxor   %xmm0,%xmm0
  add    $0x1,%rdx
  cvtsi2sd %edi,%xmm0
  movsd  %xmm0,-0x10(%rsi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rdx,%rcx
  jne    L6
L17:
  ret
```

assistant: ```c
void conv_i32_to_d32_and_d16(double *d32, double *d16, unsigned int *i32, int len) {
  int i = 0;
  unsigned int a;
#pragma pipeloop(0)
  for (; i < len; i++) {
    a = i32[i];
    d32[i] = (double)(i32[i]);
    d16[2 * i] = (double)(a & 0xffff);
    d16[2 * i + 1] = (double)(a >> 16);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *rep(double d, int n, double *res) {
  if (res == 0) {
    res = malloc(sizeof(double) * n);
  }
  for (int i = 0; i < n; ++i) {
    res[i] = d;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    %edi,%ebp
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L14
L17:
  test   %ebp,%ebp
  jle    L7
  mov    %rax,%rdx
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%rcx
L35:
  mov    %rbx,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L35
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  jmp    L17
```

assistant: ```c
double *rep(double d, int n, double *res) {
  if (res == 0) {
    res = malloc(sizeof(double) * n);
  }
  for (int i = 0; i < n; ++i) {
    res[i] = d;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rep>:
  endbr64
  push   %rbx
  mov    %rsi,%rax
  mov    %edi,%ebx
  sub    $0x10,%rsp
  test   %rsi,%rsi
  je     L25
L26:
  test   %ebx,%ebx
  jle    L37
  mov    %rax,%rdx
  lea    (%rax,%rbx,8),%rcx
  xchg   %ax,%ax
L0:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L0
L37:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  lea    0x0(,%rbx,8),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <malloc@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L26
```

assistant: ```c
double *rep(double d, int n, double *res) {
  if (res == 0) {
    res = malloc(sizeof(double) * n);
  }
  for (int i = 0; i < n; ++i) {
    res[i] = d;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rep>:
  endbr64
  push   %rbx
  mov    %rsi,%rax
  mov    %edi,%ebx
  sub    $0x10,%rsp
  test   %rsi,%rsi
  je     L36
L31:
  test   %ebx,%ebx
  jle    L41
  cmp    $0x1,%ebx
  je     L25
  mov    %ebx,%ecx
  movapd %xmm0,%xmm1
  mov    %rax,%rdx
  shr    %ecx
  unpcklpd %xmm1,%xmm1
  shl    $0x4,%rcx
  add    %rax,%rcx
  nopw   0x0(%rax,%rax,1)
L51:
  movups %xmm1,(%rdx)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L51
  mov    %ebx,%edx
  and    $0xfffffffe,%edx
  and    $0x1,%ebx
  je     L41
L47:
  movslq %edx,%rdx
  movsd  %xmm0,(%rax,%rdx,8)
L41:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L36:
  lea    0x0(,%rdi,8),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <malloc@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L31
L25:
  xor    %edx,%edx
  jmp    L47
```

assistant: ```c
double *rep(double d, int n, double *res) {
  if (res == 0) {
    res = malloc(sizeof(double) * n);
  }
  for (int i = 0; i < n; ++i) {
    res[i] = d;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L19
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L13:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  nop
  leave
  ret
```

assistant: ```c
str_tolower(cp) char *cp;
{
  for (; *cp; cp++) {
    if (isupper(*cp))
      *cp = tolower(*cp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_tolower>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L2
L6:
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L30
  mov    %ebx,%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  jmp    L30
```

assistant: ```c
str_tolower(cp) char *cp;
{
  for (; *cp; cp++) {
    if (isupper(*cp))
      *cp = tolower(*cp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_tolower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L9
  nopl   (%rax)
L12:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L4
  mov    %ebp,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
L4:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L12
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
str_tolower(cp) char *cp;
{
  for (; *cp; cp++) {
    if (isupper(*cp))
      *cp = tolower(*cp);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_tolower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  nopl   (%rax)
L26:
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  test   %eax,%eax
  je     L17
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L26
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L17:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L26
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
str_tolower(cp) char *cp;
{
  for (; *cp; cp++) {
    if (isupper(*cp))
      *cp = tolower(*cp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char inb(unsigned short addr) {
  unsigned char val;
  __asm__ __volatile__("inb %w1,%0" : "=a"(val) : "Nd"(addr));
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short addr) {
  unsigned char val;
  __asm__ __volatile__("inb %w1,%0" : "=a"(val) : "Nd"(addr));
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short addr) {
  unsigned char val;
  __asm__ __volatile__("inb %w1,%0" : "=a"(val) : "Nd"(addr));
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inb(unsigned short addr) {
  unsigned char val;
  __asm__ __volatile__("inb %w1,%0" : "=a"(val) : "Nd"(addr));
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L73
L35:
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L73:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L35
  movl   $0x0,-0x14(%rbp)
  jmp    L99
L7:
  movl   $0x0,-0x10(%rbp)
  jmp    L57
L89:
  movl   $0x1,-0xc(%rbp)
  movb   $0x58,-0x1d(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L51:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  imul   -0xc(%rbp),%eax
  add    %ecx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  movb   $0x20,-0x1d(%rbp)
  jmp    L20
L17:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0x0,-0x8(%rbp)
  jns    L51
L20:
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L57:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L89
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L99:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int layer = getchar() - '0';
  int size = 1;
  for (int i = 0; i < layer; i++)
    size *= 3;
  for (int y = 0; y < size; y++) {
    for (int x = 0; x < size; x++) {
      int p3i = 1;
      char ch = 'X';
      for (int i = layer - 1; i >= 0; i--) {
        if ((x / p3i + (y / p3i) * p3i) & 1) {
          ch = ' ';
          break;
        }
        p3i *= 3;
      }
      putchar(ch);
    }
    putchar('\n');
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0x30,%eax
  jle    L147
  lea    -0x30(%rax),%edx
  mov    $0x0,%eax
  mov    $0x1,%r13d
L3:
  lea    0x0(%r13,%r13,2),%r13d
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L3
  test   %r13d,%r13d
  jle    L67
L60:
  mov    $0x0,%ebp
  mov    $0x58,%r14d
  jmp    L63
L144:
  mov    %r14d,%edi
L104:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jle    L26
L146:
  mov    %r12d,%edi
  sub    $0x31,%edi
  js     L108
  lea    0x0(%rbp,%rbx,1),%eax
  test   $0x1,%al
  jne    L65
  mov    $0x1,%ecx
L2:
  lea    (%rcx,%rcx,2),%esi
  mov    %esi,%ecx
  sub    $0x1,%edi
  cmp    $0xffffffff,%edi
  je     L144
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  imul   %eax,%esi
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    %eax,%esi
  test   $0x1,%sil
  je     L2
  mov    $0x20,%edi
  jmp    L104
L108:
  mov    %r14d,%edi
  jmp    L104
L65:
  mov    $0x20,%edi
  jmp    L104
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jle    L67
L63:
  mov    $0x0,%ebx
  jmp    L146
L147:
  mov    $0x1,%r13d
  jmp    L60
L67:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int layer = getchar() - '0';
  int size = 1;
  for (int i = 0; i < layer; i++)
    size *= 3;
  for (int y = 0; y < size; y++) {
    for (int x = 0; x < size; x++) {
      int p3i = 1;
      char ch = 'X';
      for (int i = layer - 1; i >= 0; i--) {
        if ((x / p3i + (y / p3i) * p3i) & 1) {
          ch = ' ';
          break;
        }
        p3i *= 3;
      }
      putchar(ch);
    }
    putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  mov    %eax,%ebx
  test   %edx,%edx
  jle    L82
  xor    %eax,%eax
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L73:
  add    $0x1,%eax
  lea    0x0(%rbp,%rbp,2),%ebp
  cmp    %eax,%edx
  jne    L73
L31:
  sub    $0x31,%ebx
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L108:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L51:
  test   %ebx,%ebx
  js     L84
  lea    (%r12,%r13,1),%eax
  test   $0x1,%al
  jne    L70
  mov    %ebx,%edi
  mov    $0x1,%ecx
  jmp    L12
  nopl   (%rax)
L103:
  mov    %r13d,%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  mov    %eax,%esi
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  add    %eax,%esi
  and    $0x1,%esi
  jne    L70
L12:
  lea    (%rcx,%rcx,2),%ecx
  sub    $0x1,%edi
  jae    L103
L84:
  mov    $0x58,%edi
L13:
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  jne    L51
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r12d,%r13d
  jne    L108
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  mov    $0x20,%edi
  jmp    L13
L82:
  mov    $0x1,%ebp
  jmp    L31
```

assistant: ```c
int main(int argc, char **argv) {
  int layer = getchar() - '0';
  int size = 1;
  for (int i = 0; i < layer; i++)
    size *= 3;
  for (int y = 0; y < size; y++) {
    for (int x = 0; x < size; x++) {
      int p3i = 1;
      char ch = 'X';
      for (int i = layer - 1; i >= 0; i--) {
        if ((x / p3i + (y / p3i) * p3i) & 1) {
          ch = ' ';
          break;
        }
        p3i *= 3;
      }
      putchar(ch);
    }
    putchar('\n');
  }
  return 0;
}
```