ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BIO_new_ssl_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <BIO_s_connect@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L1
L22:
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <BIO_new_ssl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L29
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L71
  mov    -0x18(%rbp),%rax
  jmp    L1
L29:
  nop
  jmp    L41
L71:
  nop
L41:
  cmpq   $0x0,-0x10(%rbp)
  je     L46
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
L46:
  cmpq   $0x0,-0x18(%rbp)
  je     L69
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
L69:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
BIO *BIO_new_ssl_connect(SSL_CTX *ctx) {
  BIO *ret = NULL, *con = NULL, *ssl = NULL;
  if ((con = BIO_new(BIO_s_connect())) == NULL)
    return (NULL);
  if ((ssl = BIO_new_ssl(ctx, 1)) == NULL)
    goto err;
  if ((ret = BIO_push(ssl, con)) == NULL)
    goto err;
  return (ret);
err:
  if (con != NULL)
    BIO_free(con);
  if (ret != NULL)
    BIO_free(ret);
  return (NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BIO_new_ssl_connect>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <BIO_s_connect@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <BIO_new_ssl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L28
  mov    %rbx,%rsi
  call   <BIO_push@plt>
  test   %rax,%rax
  je     L28
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %rbx,%rdi
  call   <BIO_free@plt>
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
BIO *BIO_new_ssl_connect(SSL_CTX *ctx) {
  BIO *ret = NULL, *con = NULL, *ssl = NULL;
  if ((con = BIO_new(BIO_s_connect())) == NULL)
    return (NULL);
  if ((ssl = BIO_new_ssl(ctx, 1)) == NULL)
    goto err;
  if ((ret = BIO_push(ssl, con)) == NULL)
    goto err;
  return (ret);
err:
  if (con != NULL)
    BIO_free(con);
  if (ret != NULL)
    BIO_free(ret);
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<BIO_new_ssl_connect>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_s_connect@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L0
  mov    %r12,%rdi
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <BIO_new_ssl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  mov    %rbp,%rsi
  call   <BIO_push@plt>
  test   %rax,%rax
  je     L19
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L19:
  mov    %rbp,%rdi
  call   <BIO_free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
BIO *BIO_new_ssl_connect(SSL_CTX *ctx) {
  BIO *ret = NULL, *con = NULL, *ssl = NULL;
  if ((con = BIO_new(BIO_s_connect())) == NULL)
    return (NULL);
  if ((ssl = BIO_new_ssl(ctx, 1)) == NULL)
    goto err;
  if ((ret = BIO_push(ssl, con)) == NULL)
    goto err;
  return (ret);
err:
  if (con != NULL)
    BIO_free(con);
  if (ret != NULL)
    BIO_free(ret);
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BIO_new_ssl_connect>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_s_connect@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <BIO_new_ssl@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L21
  mov    %rbp,%rsi
  call   <BIO_push@plt>
  test   %rax,%rax
  je     L21
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L21:
  mov    %rbp,%rdi
  call   <BIO_free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
BIO *BIO_new_ssl_connect(SSL_CTX *ctx) {
  BIO *ret = NULL, *con = NULL, *ssl = NULL;
  if ((con = BIO_new(BIO_s_connect())) == NULL)
    return (NULL);
  if ((ssl = BIO_new_ssl(ctx, 1)) == NULL)
    goto err;
  if ((ret = BIO_push(ssl, con)) == NULL)
    goto err;
  return (ret);
err:
  if (con != NULL)
    BIO_free(con);
  if (ret != NULL)
    BIO_free(ret);
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nand_isbadblock_p2048>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x4e000004,%eax
  mov    (%rax),%rax
  mov    $0x4e000004,%edx
  and    $0xfffffffffffffffd,%rax
  mov    %rax,(%rdx)
  mov    $0x4e000020,%eax
  mov    (%rax),%rax
  mov    $0x4e000020,%edx
  or     $0x4,%rax
  mov    %rax,(%rdx)
  mov    $0x4e000008,%eax
  movb   $0x0,(%rax)
  mov    $0x4e00000c,%eax
  movb   $0x0,(%rax)
  mov    $0x4e00000c,%eax
  movb   $0x8,(%rax)
  mov    $0x4e00000c,%eax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    $0x4e00000c,%eax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    $0x4e00000c,%eax
  mov    %dl,(%rax)
  mov    $0x4e000008,%eax
  movb   $0x30,(%rax)
  nop
L1:
  mov    $0x4e000020,%eax
  mov    (%rax),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L1
  mov    $0x4e000010,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x4e000004,%eax
  mov    (%rax),%rax
  mov    $0x4e000004,%edx
  or     $0x2,%rax
  mov    %rax,(%rdx)
  cmpl   $0xff,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int nand_isbadblock_p2048(unsigned int block) {
  unsigned int page;
  int bad = 0;
  page = block << 6;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 2048 & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (2048 >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  bad = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
  return (bad != 0xFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nand_isbadblock_p2048>:
  endbr64
  shl    $0x6,%edi
  mov    0x4e000004,%rax
  and    $0xfffffffffffffffd,%rax
  mov    %rax,0x4e000004
  mov    0x4e000020,%rax
  or     $0x4,%rax
  mov    %rax,0x4e000020
  movb   $0x0,0x4e000008
  movb   $0x0,0x4e00000c
  movb   $0x8,0x4e00000c
  mov    %dil,0x4e00000c
  mov    %edi,%eax
  shr    $0x8,%eax
  mov    %al,0x4e00000c
  shr    $0x10,%edi
  mov    %dil,0x4e00000c
  movb   $0x30,0x4e000008
L1:
  mov    0x4e000020,%rax
  test   $0x4,%al
  je     L1
  movzbl 0x4e000010,%edx
  mov    0x4e000004,%rax
  or     $0x2,%rax
  mov    %rax,0x4e000004
  cmp    $0xff,%dl
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int nand_isbadblock_p2048(unsigned int block) {
  unsigned int page;
  int bad = 0;
  page = block << 6;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 2048 & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (2048 >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  bad = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
  return (bad != 0xFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nand_isbadblock_p2048>:
  endbr64
  mov    0x4e000004,%rax
  shl    $0x6,%edi
  and    $0xfffffffffffffffd,%rax
  mov    %rax,0x4e000004
  mov    0x4e000020,%rax
  or     $0x4,%rax
  mov    %rax,0x4e000020
  mov    %edi,%eax
  movb   $0x0,0x4e000008
  shr    $0x8,%eax
  movb   $0x0,0x4e00000c
  movb   $0x8,0x4e00000c
  mov    %dil,0x4e00000c
  shr    $0x10,%edi
  mov    %al,0x4e00000c
  mov    %dil,0x4e00000c
  movb   $0x30,0x4e000008
  xchg   %ax,%ax
L5:
  mov    0x4e000020,%rax
  test   $0x4,%al
  je     L5
  movzbl 0x4e000010,%edx
  mov    0x4e000004,%rax
  or     $0x2,%rax
  mov    %rax,0x4e000004
  xor    %eax,%eax
  cmp    $0xff,%dl
  setne  %al
  ret
```

assistant: ```c
int nand_isbadblock_p2048(unsigned int block) {
  unsigned int page;
  int bad = 0;
  page = block << 6;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 2048 & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (2048 >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  bad = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
  return (bad != 0xFF);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nand_isbadblock_p2048>:
  endbr64
  mov    0x4e000004,%rax
  shl    $0x6,%edi
  and    $0xfffffffffffffffd,%rax
  mov    %rax,0x4e000004
  mov    0x4e000020,%rax
  or     $0x4,%rax
  mov    %rax,0x4e000020
  mov    %edi,%eax
  movb   $0x0,0x4e000008
  shr    $0x8,%eax
  movb   $0x0,0x4e00000c
  movb   $0x8,0x4e00000c
  mov    %dil,0x4e00000c
  shr    $0x10,%edi
  mov    %al,0x4e00000c
  mov    %dil,0x4e00000c
  movb   $0x30,0x4e000008
  xchg   %ax,%ax
L4:
  mov    0x4e000020,%rax
  test   $0x4,%al
  je     L4
  movzbl 0x4e000010,%edx
  mov    0x4e000004,%rax
  or     $0x2,%rax
  mov    %rax,0x4e000004
  xor    %eax,%eax
  cmp    $0xff,%dl
  setne  %al
  ret
```

assistant: ```c
int nand_isbadblock_p2048(unsigned int block) {
  unsigned int page;
  int bad = 0;
  page = block << 6;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 2048 & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (2048 >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  bad = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
  return (bad != 0xFF);
}
```
user: What is the c source code of the assembly code below:

```asm
<safe_string_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L14
L50:
  mov    $0x0,%ebx
  jmp    L36
L42:
  mov    -0x10(%rbp),%rax
  add    %rbx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    %rbx,%rax
  jmp    L14
L40:
  add    $0x1,%rbx
L36:
  cmp    -0x18(%rbp),%rbx
  jb     L42
  mov    -0x18(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t safe_string_length(const char *s, size_t maxlen) {
  if (s == NULL) {
    return 0;
  } else {
    register size_t offset = 0;
    for (offset = 0; offset < maxlen; offset++) {
      if (s[offset] == '\0') {
        return offset;
      }
    }
    return maxlen;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<safe_string_length>:
  endbr64
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L26
  mov    $0x0,%eax
L38:
  cmpb   $0x0,(%rdi,%rax,1)
  je     L20
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L38
  mov    %rsi,%rax
  ret
L19:
  mov    $0x0,%eax
  ret
L26:
  mov    %rsi,%rax
L20:
  ret
```

assistant: ```c
size_t safe_string_length(const char *s, size_t maxlen) {
  if (s == NULL) {
    return 0;
  } else {
    register size_t offset = 0;
    for (offset = 0; offset < maxlen; offset++) {
      if (s[offset] == '\0') {
        return offset;
      }
    }
    return maxlen;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_string_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  test   %rsi,%rsi
  jne    L17
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L44
L17:
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L16
L29:
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  ret
  nopl   0x0(%rax)
L40:
  ret
```

assistant: ```c
size_t safe_string_length(const char *s, size_t maxlen) {
  if (s == NULL) {
    return 0;
  } else {
    register size_t offset = 0;
    for (offset = 0; offset < maxlen; offset++) {
      if (s[offset] == '\0') {
        return offset;
      }
    }
    return maxlen;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<safe_string_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L45
  test   %rsi,%rsi
  jne    L24
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L33
L24:
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L10
L35:
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  ret
  nopl   0x0(%rax)
L45:
  ret
```

assistant: ```c
size_t safe_string_length(const char *s, size_t maxlen) {
  if (s == NULL) {
    return 0;
  } else {
    register size_t offset = 0;
    for (offset = 0; offset < maxlen; offset++) {
      if (s[offset] == '\0') {
        return offset;
      }
    }
    return maxlen;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L16
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  je     L11
L16:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: %d:%g 

assistant: ```c
void output(int index, double value) {
  if (value != 0)
    printf("%d:%g ", index, value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<output>:
  endbr64
  ucomisd D0(%rip),%xmm0
  jp     L12
  jne    L12
  ret
L12:
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D5: %d:%g 

assistant: ```c
void output(int index, double value) {
  if (value != 0)
    printf("%d:%g ", index, value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output>:
  endbr64
  ucomisd D18(%rip),%xmm0
  jp     L15
  jne    L15
  ret
  nopl   0x0(%rax)
L15:
  mov    %edi,%esi
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: byte[8]
name: parse_data
arguments: data_label: D13
data_type: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D13: %d:%g 

assistant: ```c
void output(int index, double value) {
  if (value != 0)
    printf("%d:%g ", index, value);
}
```
user: What is the c source code of the assembly code below:

```asm
<output>:
  endbr64
  ucomisd D11(%rip),%xmm0
  jp     L0
  jne    L0
  ret
  nopl   0x0(%rax)
L0:
  mov    %edi,%esi
  lea    D15(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: byte[8]
name: retrieve_data
arguments: label: D15
type_guessed: string

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D15: %d:%g 

assistant: ```c
void output(int index, double value) {
  if (value != 0)
    printf("%d:%g ", index, value);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UARTDisableSIR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x30,%edx
  movslq %edx,%rdx
  and    $0xfffffff9,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTDisableSIR>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  add    $0x30,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTDisableSIR>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  add    $0x30,%ebx
  movslq %ebx,%rbx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    (%rbx),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTDisableSIR>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  add    $0x30,%ebx
  movslq %ebx,%rbx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    (%rbx),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: Translate the below assembly code into C programming language:

```asm
<diffrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divss  -0x20(%rbp),%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x0,-0x4(%rbp)
  jg     L1
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void diffrt(float *a, int n, float dt) {
  int i;
  for (i = n - 1; i > 0; i--) {
    a[i] = (a[i] - a[i - 1]) / dt;
  }
  a[0] = 0.;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<diffrt>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L3
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    -0x4(%rdi,%rdx,1),%rdx
  lea    -0x2(%rsi),%ecx
  shl    $0x2,%rcx
  sub    %rcx,%rdx
L16:
  movss  (%rax),%xmm1
  subss  -0x4(%rax),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rax)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L16
L3:
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void diffrt(float *a, int n, float dt) {
  int i;
  for (i = n - 1; i > 0; i--) {
    a[i] = (a[i] - a[i - 1]) / dt;
  }
  a[0] = 0.;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<diffrt>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L7
  cltq
  lea    -0x2(%rsi),%ecx
  lea    0x0(,%rax,4),%rdx
  shl    $0x2,%rcx
  lea    (%rdi,%rdx,1),%rax
  lea    -0x4(%rdi,%rdx,1),%rdx
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L12:
  movss  (%rax),%xmm1
  subss  -0x4(%rax),%xmm1
  sub    $0x4,%rax
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rax)
  cmp    %rdx,%rax
  jne    L12
L7:
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void diffrt(float *a, int n, float dt) {
  int i;
  for (i = n - 1; i > 0; i--) {
    a[i] = (a[i] - a[i - 1]) / dt;
  }
  a[0] = 0.;
}
```