ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L16:
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <svcfd_create@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <svc_destroy@plt>
  addl   $0x1,-0x20(%rbp)
  jmp    L19
L1:
  nop
L19:
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L16
  cmpl   $0x1,-0x18(%rbp)
  jne    L28
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x20(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type: string
name: extract_symbolic_data
arguments: data_tag: D25
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string

tool: D12: Aimed : %d


tool: D25: Got : %d


tool: D15: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int fd = 0;
  SVCXPRT *svcr = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    svcr = svcfd_create(fd, 0, 0);
    if (svcr == NULL)
      continue;
    svc_destroy(svcr);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L14
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L1
L11:
  call   <svc_destroy@plt>
  add    $0x1,%ebp
L43:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L26
L1:
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <svcfd_create@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
  jmp    L43
L14:
  mov    $0x0,%ebp
L26:
  cmp    %ebp,%r12d
  setne  %bl
  movzbl %bl,%ebx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int fd = 0;
  SVCXPRT *svcr = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    svcr = svcfd_create(fd, 0, 0);
    if (svcr == NULL)
      continue;
    svc_destroy(svcr);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L17
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L16:
  xor    %edi,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <svcfd_create@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L34
  call   <svc_destroy@plt>
  add    $0x1,%ebp
L34:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L16
L25:
  cmp    %ebp,%r12d
  lea    D6(%rip),%rdi
  setne  %r12b
  movzbl %r12b,%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  xor    %ebp,%ebp
  jmp    L25
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int fd = 0;
  SVCXPRT *svcr = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    svcr = svcfd_create(fd, 0, 0);
    if (svcr == NULL)
      continue;
    svc_destroy(svcr);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x18(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L25
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L19:
  xor    %edi,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <svcfd_create@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L21
  call   <svc_destroy@plt>
  add    $0x1,%ebp
L21:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L19
L6:
  cmp    %ebp,%r12d
  lea    D6(%rip),%rdi
  setne  %r12b
  movzbl %r12b,%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  xor    %ebp,%ebp
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: %d


assistant: ```c
int main(int argn, char *argc[]) {
  int run_mode = 0;
  int test_status = 1;
  int fd = 0;
  SVCXPRT *svcr = NULL;
  int nbCall = atoi(argc[3]);
  int nbOk = 0;
  int i;
  for (i = 0; i < nbCall; i++) {
    svcr = svcfd_create(fd, 0, 0);
    if (svcr == NULL)
      continue;
    svc_destroy(svcr);
    nbOk++;
  }
  if (run_mode == 1) {
    printf("Aimed : %d\n", nbCall);
    printf("Got : %d\n", nbOk);
  }
  test_status = (nbOk == nbCall) ? 0 : 1;
  printf("%d\n", test_status);
  return test_status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_read_retry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rcx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L73
  mov    %edi,%ebp
  mov    %edx,%r15d
  mov    %edx,%r14d
  mov    $0x0,%r12d
  lea    0x10(%rsp),%r13
  jmp    L57
L8:
  mov    D27(%rip),%rax
  mov    (%rax),%rdx
  mov    D54(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%ebx
L162:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    D82(%rip),%rax
  mov    (%rax),%rdx
  mov    D54(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%ebx
  jmp    L162
L32:
  cmp    $0xffffffff,%eax
  je     L158
  add    %eax,%r12d
  sub    %eax,%r14d
L51:
  cmp    %r15d,%r12d
  jge    L137
L57:
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  lea    0x14(%rsp),%rbx
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  lea    0x1(%rbp),%edi
  mov    (%rsp),%r8
  mov    %rbx,%rcx
  mov    $0x0,%edx
  mov    %r13,%rsi
  call   <_select_retry@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L162
  test   %eax,%eax
  je     L8
  lea    0x14(%rsp),%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L35
  movslq %r12d,%rsi
  add    0x8(%rsp),%rsi
  mov    %r14d,%edx
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jne    L32
  cmp    $0x1,%ebx
  jne    L32
  mov    D82(%rip),%rax
  mov    (%rax),%rdx
  mov    D54(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%ebx
  jmp    L162
L158:
  mov    D54(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D71(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L51
  mov    D86(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L51
  mov    %eax,%ebx
  jmp    L162
L137:
  mov    %r12d,%ebx
  jmp    L162
L73:
  mov    $0x0,%ebx
  jmp    L162
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t _read_retry(int sockfd, void *buf, int count, struct timeval *timeout) {
  int n, total = 0, remain = count, rv = 0;
  fd_set rfds, xfds;
  while (total < count) {
    FD_ZERO(&rfds);
    FD_SET(sockfd, &rfds);
    FD_ZERO(&xfds);
    FD_SET(sockfd, &xfds);
    rv = _select_retry(sockfd + 1, &rfds, NULL, &xfds, timeout);
    if (rv == -1)
      return -1;
    else if (rv == 0) {
      errno = ETIMEDOUT;
      return -1;
    }
    if (FD_ISSET(sockfd, &xfds)) {
      errno = EPIPE;
      return -1;
    }
    n = read(sockfd, buf + (off_t)total, remain);
    if ((n == 0) && (rv == 1)) {
      errno = EPIPE;
      return -1;
    }
    if (n == -1) {
      if ((errno == EAGAIN) || (errno == EINTR)) {
        continue;
      }
      return -1;
    }
    total += n;
    remain -= n;
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_read_retry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L128
  lea    0x1(%rdi),%eax
  mov    %edi,%ebp
  mov    %edx,%r15d
  xor    %r13d,%r13d
  mov    %eax,0x18(%rsp)
  lea    0x20(%rsp),%r14
  lea    0x24(%rsp),%r12
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L120:
  add    %eax,%r13d
  sub    %eax,%r15d
L81:
  cmp    0x1c(%rsp),%r13d
  jge    L98
L72:
  mov    %r14,%rdi
  call   <FD_ZERO@plt>
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    0x8(%rsp),%r8
  mov    0x18(%rsp),%edi
  xor    %edx,%edx
  mov    %r12,%rcx
  mov    %r14,%rsi
  call   <_select_retry@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L116
  test   %eax,%eax
  je     L62
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L43
  movslq %r13d,%rsi
  mov    %r15d,%edx
  add    0x10(%rsp),%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jne    L23
  cmp    $0x1,%ebx
  je     L43
L23:
  cmp    $0xffffffff,%eax
  jne    L120
  mov    D63(%rip),%rax
  mov    D30(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L81
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rax
  je     L81
  nop
L116:
  mov    $0xffffffff,%r13d
L98:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    D50(%rip),%rax
  mov    (%rax),%rdx
  mov    D63(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L116
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    D64(%rip),%rax
  mov    $0xffffffff,%r13d
  mov    (%rax),%rdx
  mov    D63(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L98
L128:
  xor    %r13d,%r13d
  jmp    L98
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t _read_retry(int sockfd, void *buf, int count, struct timeval *timeout) {
  int n, total = 0, remain = count, rv = 0;
  fd_set rfds, xfds;
  while (total < count) {
    FD_ZERO(&rfds);
    FD_SET(sockfd, &rfds);
    FD_ZERO(&xfds);
    FD_SET(sockfd, &xfds);
    rv = _select_retry(sockfd + 1, &rfds, NULL, &xfds, timeout);
    if (rv == -1)
      return -1;
    else if (rv == 0) {
      errno = ETIMEDOUT;
      return -1;
    }
    if (FD_ISSET(sockfd, &xfds)) {
      errno = EPIPE;
      return -1;
    }
    n = read(sockfd, buf + (off_t)total, remain);
    if ((n == 0) && (rv == 1)) {
      errno = EPIPE;
      return -1;
    }
    if (n == -1) {
      if ((errno == EAGAIN) || (errno == EINTR)) {
        continue;
      }
      return -1;
    }
    total += n;
    remain -= n;
  }
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_read_retry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L79
  lea    0x1(%rdi),%eax
  mov    %edi,%ebp
  mov    %edx,%r15d
  xor    %r13d,%r13d
  mov    %eax,0x18(%rsp)
  lea    0x20(%rsp),%r14
  lea    0x24(%rsp),%r12
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L123:
  add    %eax,%r13d
  sub    %eax,%r15d
L96:
  cmp    0x1c(%rsp),%r13d
  jge    L20
L100:
  mov    %r14,%rdi
  call   <FD_ZERO@plt>
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    0x8(%rsp),%r8
  mov    0x18(%rsp),%edi
  xor    %edx,%edx
  mov    %r12,%rcx
  mov    %r14,%rsi
  call   <_select_retry@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L43
  test   %eax,%eax
  je     L94
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L115
  movslq %r13d,%rsi
  mov    %r15d,%edx
  add    0x10(%rsp),%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jne    L149
  cmp    $0x1,%ebx
  je     L115
L149:
  cmp    $0xffffffff,%eax
  jne    L123
  mov    D42(%rip),%rax
  mov    D67(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L96
  mov    D66(%rip),%rdx
  cmp    (%rdx),%rax
  je     L96
  nop
L43:
  mov    $0xffffffff,%r13d
L20:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L115:
  mov    D68(%rip),%rax
  mov    (%rax),%rdx
  mov    D42(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    D31(%rip),%rax
  mov    $0xffffffff,%r13d
  mov    (%rax),%rdx
  mov    D42(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L20
L79:
  xor    %r13d,%r13d
  jmp    L20
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t _read_retry(int sockfd, void *buf, int count, struct timeval *timeout) {
  int n, total = 0, remain = count, rv = 0;
  fd_set rfds, xfds;
  while (total < count) {
    FD_ZERO(&rfds);
    FD_SET(sockfd, &rfds);
    FD_ZERO(&xfds);
    FD_SET(sockfd, &xfds);
    rv = _select_retry(sockfd + 1, &rfds, NULL, &xfds, timeout);
    if (rv == -1)
      return -1;
    else if (rv == 0) {
      errno = ETIMEDOUT;
      return -1;
    }
    if (FD_ISSET(sockfd, &xfds)) {
      errno = EPIPE;
      return -1;
    }
    n = read(sockfd, buf + (off_t)total, remain);
    if ((n == 0) && (rv == 1)) {
      errno = EPIPE;
      return -1;
    }
    if (n == -1) {
      if ((errno == EAGAIN) || (errno == EINTR)) {
        continue;
      }
      return -1;
    }
    total += n;
    remain -= n;
  }
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LCDprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <LCDputc@plt>
  addl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x7,-0x4(%rbp)
  jle    L24
  jmp    L32
L5:
  nop
L32:
  nop
  leave
  ret
```

assistant: ```c
void LCDprint(char *buf) {
  int i;
  for (i = 0; i < 8; i++) {
    if (buf[i] == 0)
      break;
    LCDputc(buf[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LCDprint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x8(%rdi),%rbp
L12:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L7
  movsbl %dil,%edi
  call   <LCDputc@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void LCDprint(char *buf) {
  int i;
  for (i = 0; i < 8; i++) {
    if (buf[i] == 0)
      break;
    LCDputc(buf[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LCDprint>:
  endbr64
  push   %rbp
  lea    0x8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L12
  call   <LCDputc@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void LCDprint(char *buf) {
  int i;
  for (i = 0; i < 8; i++) {
    if (buf[i] == 0)
      break;
    LCDputc(buf[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<LCDprint>:
  endbr64
  push   %rbp
  lea    0x8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L7
  call   <LCDputc@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void LCDprint(char *buf) {
  int i;
  for (i = 0; i < 8; i++) {
    if (buf[i] == 0)
      break;
    LCDputc(buf[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <times@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x28(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  add    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  sar    $0x1f,%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  sar    $0x1f,%eax
  shr    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%eax
  add    %ecx,%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0xffffff80,%eax
  mov    %eax,-0x28(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    -0x28(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: seed=%#x
ticks=%#x


assistant: ```c
int main() {
  int i, j;
  unsigned int seed;
  struct tms tms;
  clock_t num_ticks = 0;
  num_ticks = times(&tms);
  num_ticks = tms.tms_cutime + tms.tms_stime + tms.tms_utime + tms.tms_cstime + num_ticks;
  num_ticks += clock();
  num_ticks += time(NULL);
  num_ticks = 128 - ((unsigned char)(((unsigned int)(num_ticks >> 31) >> 24) + num_ticks) - ((unsigned int)(num_ticks >> 31) >> 24));
  seed = num_ticks + time(0);
  printf("seed=%#x\nticks=%#x\n", seed, num_ticks & 0x7fffffff);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <times@plt>
  mov    0x4(%rsp),%ebx
  add    (%rsp),%ebx
  add    0x8(%rsp),%ebx
  add    0xc(%rsp),%ebx
  add    %eax,%ebx
  mov    $0x0,%eax
  call   <clock@plt>
  add    %eax,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  add    %ebx,%eax
  cltd
  shr    $0x18,%edx
  lea    0x80(%rdx),%ebx
  add    %eax,%edx
  movzbl %dl,%edx
  sub    %edx,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %ebx,%edx
  and    $0x7fffffff,%edx
  lea    (%rax,%rbx,1),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: seed=%#x
ticks=%#x


assistant: ```c
int main() {
  int i, j;
  unsigned int seed;
  struct tms tms;
  clock_t num_ticks = 0;
  num_ticks = times(&tms);
  num_ticks = tms.tms_cutime + tms.tms_stime + tms.tms_utime + tms.tms_cstime + num_ticks;
  num_ticks += clock();
  num_ticks += time(NULL);
  num_ticks = 128 - ((unsigned char)(((unsigned int)(num_ticks >> 31) >> 24) + num_ticks) - ((unsigned int)(num_ticks >> 31) >> 24));
  seed = num_ticks + time(0);
  printf("seed=%#x\nticks=%#x\n", seed, num_ticks & 0x7fffffff);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <times@plt>
  mov    0x4(%rsp),%ebx
  add    (%rsp),%ebx
  add    0x8(%rsp),%ebx
  add    0xc(%rsp),%ebx
  add    %eax,%ebx
  xor    %eax,%eax
  call   <clock@plt>
  xor    %edi,%edi
  add    %eax,%ebx
  call   <time@plt>
  xor    %edi,%edi
  add    %ebx,%eax
  cltd
  shr    $0x18,%edx
  lea    0x80(%rdx),%ebx
  add    %eax,%edx
  movzbl %dl,%edx
  sub    %edx,%ebx
  call   <time@plt>
  mov    %ebx,%edx
  lea    D3(%rip),%rdi
  and    $0x7fffffff,%edx
  lea    (%rax,%rbx,1),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: seed=%#x
ticks=%#x


assistant: ```c
int main() {
  int i, j;
  unsigned int seed;
  struct tms tms;
  clock_t num_ticks = 0;
  num_ticks = times(&tms);
  num_ticks = tms.tms_cutime + tms.tms_stime + tms.tms_utime + tms.tms_cstime + num_ticks;
  num_ticks += clock();
  num_ticks += time(NULL);
  num_ticks = 128 - ((unsigned char)(((unsigned int)(num_ticks >> 31) >> 24) + num_ticks) - ((unsigned int)(num_ticks >> 31) >> 24));
  seed = num_ticks + time(0);
  printf("seed=%#x\nticks=%#x\n", seed, num_ticks & 0x7fffffff);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <times@plt>
  mov    0x4(%rsp),%ebx
  add    (%rsp),%ebx
  add    0x8(%rsp),%ebx
  add    0xc(%rsp),%ebx
  add    %eax,%ebx
  xor    %eax,%eax
  call   <clock@plt>
  xor    %edi,%edi
  add    %eax,%ebx
  call   <time@plt>
  xor    %edi,%edi
  add    %ebx,%eax
  cltd
  shr    $0x18,%edx
  lea    0x80(%rdx),%ebx
  add    %eax,%edx
  movzbl %dl,%edx
  sub    %edx,%ebx
  call   <time@plt>
  mov    %ebx,%edx
  lea    D6(%rip),%rdi
  and    $0x7fffffff,%edx
  lea    (%rax,%rbx,1),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: seed=%#x
ticks=%#x


assistant: ```c
int main() {
  int i, j;
  unsigned int seed;
  struct tms tms;
  clock_t num_ticks = 0;
  num_ticks = times(&tms);
  num_ticks = tms.tms_cutime + tms.tms_stime + tms.tms_utime + tms.tms_cstime + num_ticks;
  num_ticks += clock();
  num_ticks += time(NULL);
  num_ticks = 128 - ((unsigned char)(((unsigned int)(num_ticks >> 31) >> 24) + num_ticks) - ((unsigned int)(num_ticks >> 31) >> 24));
  seed = num_ticks + time(0);
  printf("seed=%#x\nticks=%#x\n", seed, num_ticks & 0x7fffffff);
  return 0;
}
```