ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cholcol>:
  endbr64
  test   %edi,%edi
  jle    L35
  push   %r15
  pxor   %xmm2,%xmm2
  xor    %r15d,%r15d
  push   %r14
  mov    $0xffffffffffffe6f8,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x1908(%rsi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsd  (%rsi),%xmm0
  comisd %xmm0,%xmm2
  jae    L84
  cs nopw 0x0(%rax,%rax,1)
L96:
  ucomisd %xmm0,%xmm2
  ja     L69
  sqrtsd %xmm0,%xmm0
L15:
  lea    0x1(%r15),%r8d
  movsd  %xmm0,-0x1908(%rbp)
  cmp    %r8d,%r13d
  je     L22
  lea    -0x1(%r13),%eax
  lea    0x3200(%rbp,%r14,1),%r9
  sub    %r8d,%eax
  lea    -0x8(%rbp),%rcx
  lea    -0x1(%r15),%edi
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x8,%rax
  add    %rax,%r9
  nopl   0x0(%rax)
L20:
  test   %r15d,%r15d
  je     L19
  movsd  (%rcx),%xmm1
  lea    (%rcx,%r12,1),%rsi
  xor    %eax,%eax
  nop
L83:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rdx,%rdi
  jne    L83
L19:
  movsd  (%rcx),%xmm0
  add    $0x1900,%rcx
  divsd  -0x1908(%rbp),%xmm0
  movsd  %xmm0,-0x1900(%rcx)
  cmp    %r9,%rcx
  jne    L20
  add    $0x1900,%rbx
  movsd  0x0(%rbp),%xmm0
  mov    %rbx,%rax
  nopl   (%rax)
L59:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp)
  cmp    %rbp,%rax
  jne    L59
  sub    $0x8,%r12
  add    $0x1908,%rbp
  mov    %r8d,%r15d
  comisd %xmm0,%xmm2
  jb     L96
L84:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  xor    %eax,%eax
  ret
L69:
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  jmp    L15
```

assistant: ```c
int cholcol(int n, double A[][800]) {
  int i, j, k;
  for (k = 0; k < n; k++) {
    for (j = 0; j < k; j++) {
      A[k][k] -= A[k][j] * A[k][j];
    }
    if (A[k][k] <= 0)
      return -1;
    else
      A[k][k] = sqrt(A[k][k]);
    for (i = k + 1; i < n; i++) {
      for (j = 0; j < k; j++) {
        A[i][k] -= A[i][j] * A[k][j];
      }
      A[i][k] /= A[k][k];
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cholcol>:
  endbr64
  test   %edi,%edi
  jle    L74
  push   %r15
  pxor   %xmm2,%xmm2
  lea    -0x1(%rdi),%r15d
  mov    $0xffffffffffffe6f8,%r9
  push   %r14
  mov    %edi,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    0x1908(%rsi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsd  -0x1908(%rbp),%xmm0
  comisd %xmm0,%xmm2
  jae    L53
  xchg   %ax,%ax
L45:
  ucomisd %xmm0,%xmm2
  ja     L47
  sqrtsd %xmm0,%xmm0
L3:
  movsd  %xmm0,-0x1908(%rbp)
  cmp    %r15,%r13
  je     L31
  lea    -0x2(%r14),%eax
  lea    0x3200(%rbp,%r9,1),%r8
  mov    %r13d,%r10d
  sub    %r13d,%eax
  lea    -0x8(%rbp),%rcx
  lea    -0x1(%r13),%edi
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x8,%rax
  add    %rax,%r8
  nopl   0x0(%rax,%rax,1)
L29:
  test   %r10d,%r10d
  jle    L96
  movsd  (%rcx),%xmm1
  lea    (%rcx,%r12,1),%rsi
  xor    %eax,%eax
  nop
L44:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rbx,%rax,8),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rdx,%rdi
  jne    L44
L96:
  movsd  (%rcx),%xmm0
  add    $0x1900,%rcx
  divsd  -0x1908(%rbp),%xmm0
  movsd  %xmm0,-0x1900(%rcx)
  cmp    %r8,%rcx
  jne    L29
  add    $0x1900,%rbx
  movsd  0x0(%rbp),%xmm1
  mov    %rbx,%rax
  nopl   (%rax)
L82:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  cmp    %rbp,%rax
  jne    L82
  movsd  0x0(%rbp),%xmm0
  add    $0x1908,%rbp
  add    $0x1,%r13
  sub    $0x8,%r12
  comisd %xmm0,%xmm2
  jb     L45
L53:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  xor    %eax,%eax
  ret
L47:
  call   <sqrt@plt>
  mov    $0xffffffffffffe6f8,%r9
  pxor   %xmm2,%xmm2
  jmp    L3
```

assistant: ```c
int cholcol(int n, double A[][800]) {
  int i, j, k;
  for (k = 0; k < n; k++) {
    for (j = 0; j < k; j++) {
      A[k][k] -= A[k][j] * A[k][j];
    }
    if (A[k][k] <= 0)
      return -1;
    else
      A[k][k] = sqrt(A[k][k]);
    for (i = k + 1; i < n; i++) {
      for (j = 0; j < k; j++) {
        A[i][k] -= A[i][j] * A[k][j];
      }
      A[i][k] /= A[k][k];
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L13
L6:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
L13:
  leave
  ret
```

assistant: ```c
int puts(const char *string) {
  size_t len = strlen(string);
  if (len == fwrite(string, len, 1, stdout)) {
    return putchar('\n');
  } else
    return EOF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  cmp    %rbx,%rax
  je     L18
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L17
```

assistant: ```c
int puts(const char *string) {
  size_t len = strlen(string);
  if (len == fwrite(string, len, 1, stdout)) {
    return putchar('\n');
  } else
    return EOF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %rax,%rbx
  mov    D15(%rip),%rax
  mov    %rbx,%rsi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  cmp    %rbx,%rax
  je     L7
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

assistant: ```c
int puts(const char *string) {
  size_t len = strlen(string);
  if (len == fwrite(string, len, 1, stdout)) {
    return putchar('\n');
  } else
    return EOF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %rax,%rbx
  mov    D5(%rip),%rax
  mov    %rbx,%rsi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  cmp    %rbx,%rax
  je     L0
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <putchar@plt>
```

assistant: ```c
int puts(const char *string) {
  size_t len = strlen(string);
  if (len == fwrite(string, len, 1, stdout)) {
    return putchar('\n');
  } else
    return EOF;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<FindFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x2f5c,-0xb(%rbp)
  movb   $0x3a,-0x9(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L20
L37:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0xb(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L14:
  addl   $0x1,-0x24(%rbp)
L20:
  cmpl   $0x2,-0x24(%rbp)
  jle    L37
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *FindFileName(const char *const fullPath) {
  int i;
  const char *start;
  const char *tmp;
  const char delim[3] = {'\\', '/', ':'};
  start = fullPath;
  for (i = 0; i < 3; i++) {
    tmp = strrchr(start, delim[i]);
    if (tmp != NULL) {
      start = tmp + 1;
    }
  }
  return (char *)start;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindFileName>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x2f5c,0x5(%rsp)
  movb   $0x3a,0x7(%rsp)
  lea    0x5(%rsp),%rbx
  lea    0x8(%rsp),%r12
L15:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *FindFileName(const char *const fullPath) {
  int i;
  const char *start;
  const char *tmp;
  const char delim[3] = {'\\', '/', ':'};
  start = fullPath;
  for (i = 0; i < 3; i++) {
    tmp = strrchr(start, delim[i]);
    if (tmp != NULL) {
      start = tmp + 1;
    }
  }
  return (char *)start;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FindFileName>:
  endbr64
  push   %r12
  mov    $0x5c,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2f5c,%eax
  movb   $0x3a,0x7(%rsp)
  lea    0x5(%rsp),%rbp
  mov    %ax,0x5(%rsp)
  lea    0x8(%rsp),%rbx
L4:
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%r12
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L2
  movsbl 0x0(%rbp),%esi
  jmp    L4
  nop
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *FindFileName(const char *const fullPath) {
  int i;
  const char *start;
  const char *tmp;
  const char delim[3] = {'\\', '/', ':'};
  start = fullPath;
  for (i = 0; i < 3; i++) {
    tmp = strrchr(start, delim[i]);
    if (tmp != NULL) {
      start = tmp + 1;
    }
  }
  return (char *)start;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FindFileName>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2f5c,%eax
  movb   $0x3a,0x7(%rsp)
  lea    0x5(%rsp),%rbx
  mov    %ax,0x5(%rsp)
  lea    0x8(%rsp),%rbp
L13:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%r12
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *FindFileName(const char *const fullPath) {
  int i;
  const char *start;
  const char *tmp;
  const char delim[3] = {'\\', '/', ':'};
  start = fullPath;
  for (i = 0; i < 3; i++) {
    tmp = strrchr(start, delim[i]);
    if (tmp != NULL) {
      start = tmp + 1;
    }
  }
  return (char *)start;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<syscon_multprec_Laurent_size_limit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x25f,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_multprec_Laurent_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(607, &k, szl, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<syscon_multprec_Laurent_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x25f,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_Laurent_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(607, &k, szl, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<syscon_multprec_Laurent_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x25f,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_Laurent_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(607, &k, szl, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<syscon_multprec_Laurent_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x25f,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_Laurent_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(607, &k, szl, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x302020102010100,%rax
  movabs $0x403030203020201,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xf,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x4,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
uint8_t count_bit(uint8_t x) {
  const unsigned char ones[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4};
  return ones[x & 0xf] + ones[x >> 4];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_bit>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x302020102010100,%rax
  movabs $0x403030203020201,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %edi,%eax
  and    $0xf,%eax
  movzbl (%rsp,%rax,1),%eax
  sar    $0x4,%edi
  movslq %edi,%rdi
  movzbl (%rsp,%rdi,1),%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t count_bit(uint8_t x) {
  const unsigned char ones[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4};
  return ones[x & 0xf] + ones[x >> 4];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_bit>:
  endbr64
  sub    $0x28,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  sar    $0x4,%edi
  and    $0xf,%eax
  movslq %edi,%rdi
  movaps %xmm0,(%rsp)
  movzbl (%rsp,%rax,1),%eax
  movzbl (%rsp,%rdi,1),%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: byte[16]

tool: {"D0": [0x00,0x01,0x01,0x02,0x01,0x02,0x02,0x03,0x01,0x02,0x02,0x03,0x02,0x03,0x03,0x04]}

assistant: ```c
uint8_t count_bit(uint8_t x) {
  const unsigned char ones[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4};
  return ones[x & 0xf] + ones[x >> 4];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<count_bit>:
  endbr64
  sub    $0x28,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  sar    $0x4,%edi
  and    $0xf,%eax
  movslq %edi,%rdi
  movaps %xmm0,(%rsp)
  movzbl (%rsp,%rax,1),%eax
  movzbl (%rsp,%rdi,1),%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: byte[16]

tool: {"D0": [0x00,0x01,0x01,0x02,0x01,0x02,0x02,0x03,0x01,0x02,0x02,0x03,0x02,0x03,0x03,0x04]}

assistant: ```c
uint8_t count_bit(uint8_t x) {
  const unsigned char ones[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4};
  return ones[x & 0xf] + ones[x >> 4];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<LCDIDDConfigSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LCDIDDConfigSet(uint32_t ui32Base, uint32_t ui32Config) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32Config;
}
```
user: Translate the below assembly code into C programming language:

```asm
<LCDIDDConfigSet>:
  endbr64
  mov    %rsi,0xc(%rdi)
  ret
```

assistant: ```c
void LCDIDDConfigSet(uint32_t ui32Base, uint32_t ui32Config) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32Config;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LCDIDDConfigSet>:
  endbr64
  mov    %rsi,0xc(%rdi)
  ret
```

assistant: ```c
void LCDIDDConfigSet(uint32_t ui32Base, uint32_t ui32Config) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32Config;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LCDIDDConfigSet>:
  endbr64
  mov    %rsi,0xc(%rdi)
  ret
```

assistant: ```c
void LCDIDDConfigSet(uint32_t ui32Base, uint32_t ui32Config) {
  ;

  ;
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32Config;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L7
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L28
  addq   $0x1,-0x8(%rbp)
  jmp    L7
L28:
  mov    -0x8(%rbp),%rax
  jmp    L35
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
char *strpbrk(str, set) const char *str;
const char *set;
{
  while (*str != '\0')
    if (strchr(set, *str) == 0)
      ++str;
    else
      return (char *)str;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strpbrk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L40
L11:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L22
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L11
  jmp    L37
L40:
  mov    $0x0,%eax
  jmp    L37
L22:
  mov    %rbx,%rax
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(str, set) const char *str;
const char *set;
{
  while (*str != '\0')
    if (strchr(set, *str) == 0)
      ++str;
    else
      return (char *)str;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L32
  mov    %rdi,%rbx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L14:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L7
L29:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  mov    %rbx,%rax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  xor    %eax,%eax
  jmp    L7
```

assistant: ```c
char *strpbrk(str, set) const char *str;
const char *set;
{
  while (*str != '\0')
    if (strchr(set, *str) == 0)
      ++str;
    else
      return (char *)str;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L24
  mov    %rdi,%rbx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L41:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L31
L42:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
  mov    %rbx,%rax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
char *strpbrk(str, set) const char *str;
const char *set;
{
  while (*str != '\0')
    if (strchr(set, *str) == 0)
      ++str;
    else
      return (char *)str;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x13(%rbp),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <check_duplicates@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L24
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L24:
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  lea    -0x13(%rbp),%rax
  lea    D58(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <check_duplicates@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jne    L34
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L14
L34:
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D46
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D55
type_guessed: string
name: read_data
arguments: tag: D58
type_guessed: string

tool: D46: 0691874532

tool: D14: %s contains duplicates


tool: D55: %s contains no duplicates


tool: D58: 0681874132

assistant: ```c
int main(int argc, char **argv) {
  int rc;
  char full_str[11];
  strcpy(full_str, "0691874532");
  if ((rc = check_duplicates(full_str)) == 1) {
    printf("%s contains duplicates\n", full_str);
  } else {
    printf("%s contains no duplicates\n", full_str);
  }
  strcpy(full_str, "0681874132");
  if ((rc = check_duplicates(full_str)) == 1) {
    printf("%s contains duplicates\n", full_str);
  } else {
    printf("%s contains no duplicates\n", full_str);
  }
}
```