ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strncat_symbolic_dst_length>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  mov    %rdi,%rbp
  lea    D9(%rip),%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x3,%eax
  setg   %dil
  jmp    1090 <clang_analyzer_eval@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: 1234

assistant: ```c
void strncat_symbolic_dst_length(char *dst) {
  strncat(dst, "1234", 5);
  clang_analyzer_eval(strlen(dst) >= 4);
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L34
L31:
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L15
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *reverse(char *string) {
  char temp;
  int length, head, tail;
  while (string[length] != '\0') {
    length++;
  }
  tail = length - 1;
  for (head = 0; head < length / 2; head++, tail--) {
    temp = string[head];
    string[head] = string[tail];
    string[tail] = temp;
  }
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%esi
  cmpb   $0x0,(%rdi)
  je     L38
  mov    $0x1,%edx
L15:
  mov    %edx,%esi
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L15
L38:
  lea    -0x1(%rsi),%ecx
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L5
  movslq %ecx,%rcx
  add    %rax,%rcx
  mov    $0x0,%edx
L28:
  movzbl (%rax,%rdx,1),%esi
  movzbl (%rcx),%edi
  mov    %dil,(%rax,%rdx,1)
  mov    %sil,(%rcx)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %edx,%r8d
  jg     L28
L5:
  ret
```

assistant: ```c
char *reverse(char *string) {
  char temp;
  int length, head, tail;
  while (string[length] != '\0') {
    length++;
  }
  tail = length - 1;
  for (head = 0; head < length / 2; head++, tail--) {
    temp = string[head];
    string[head] = string[tail];
    string[tail] = temp;
  }
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  xor    %esi,%esi
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L27
  lea    0x1(%rdi),%rcx
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rcx
  mov    %esi,%edx
  add    $0x1,%esi
  cmpb   $0x0,-0x1(%rcx)
  jne    L39
L1:
  mov    %esi,%r8d
  movslq %edx,%rdx
  xor    %ecx,%ecx
  shr    $0x1f,%r8d
  add    %rax,%rdx
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L16
  nopl   0x0(%rax)
L8:
  movzbl (%rdx),%edi
  movzbl (%rax,%rcx,1),%esi
  sub    $0x1,%rdx
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  mov    %sil,0x1(%rdx)
  cmp    %ecx,%r8d
  jg     L8
L16:
  ret
  nopl   (%rax)
L27:
  xor    %esi,%esi
  lea    -0x1(%rsi),%edx
  jmp    L1
```

assistant: ```c
char *reverse(char *string) {
  char temp;
  int length, head, tail;
  while (string[length] != '\0') {
    length++;
  }
  tail = length - 1;
  for (head = 0; head < length / 2; head++, tail--) {
    temp = string[head];
    string[head] = string[tail];
    string[tail] = temp;
  }
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  xor    %esi,%esi
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L15
  lea    0x1(%rdi),%rcx
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rcx
  mov    %esi,%edx
  add    $0x1,%esi
  cmpb   $0x0,-0x1(%rcx)
  jne    L25
L36:
  mov    %esi,%r8d
  movslq %edx,%rdx
  xor    %ecx,%ecx
  shr    $0x1f,%r8d
  add    %rax,%rdx
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L20
  nopl   0x0(%rax)
L23:
  movzbl (%rdx),%edi
  movzbl (%rax,%rcx,1),%esi
  sub    $0x1,%rdx
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  mov    %sil,0x1(%rdx)
  cmp    %ecx,%r8d
  jg     L23
L20:
  ret
  nopl   (%rax)
L15:
  xor    %esi,%esi
  lea    -0x1(%rsi),%edx
  jmp    L36
```

assistant: ```c
char *reverse(char *string) {
  char temp;
  int length, head, tail;
  while (string[length] != '\0') {
    length++;
  }
  tail = length - 1;
  for (head = 0; head < length / 2; head++, tail--) {
    temp = string[head];
    string[head] = string[tail];
    string[tail] = temp;
  }
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_crc16_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <lha_crc16_buf@plt>
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void test_crc16_empty(void) {
  uint16_t crc;
  crc = 0;
  lha_crc16_buf(&crc, NULL, 0);
  assert(crc == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_crc16_empty>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <lha_crc16_buf@plt>
  cmpq   $0x0,(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_crc16_empty(void) {
  uint16_t crc;
  crc = 0;
  lha_crc16_buf(&crc, NULL, 0);
  assert(crc == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_crc16_empty>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <lha_crc16_buf@plt>
  xor    %edi,%edi
  cmpq   $0x0,(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_crc16_empty(void) {
  uint16_t crc;
  crc = 0;
  lha_crc16_buf(&crc, NULL, 0);
  assert(crc == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_crc16_empty>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <lha_crc16_buf@plt>
  xor    %edi,%edi
  cmpq   $0x0,(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_crc16_empty(void) {
  uint16_t crc;
  crc = 0;
  lha_crc16_buf(&crc, NULL, 0);
  assert(crc == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vde_chain_nm4_work>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  movl   $0x4,(%rax)
L18:
  cmpq   $0x0,-0x10(%rbp)
  je     L39
  mov    -0x10(%rbp),%rax
  movl   $0x3,(%rax)
L39:
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L12:
  cmpq   $0x0,-0x20(%rbp)
  je     L13
  mov    -0x20(%rbp),%rax
  movl   $0x2f,(%rax)
L13:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int vde_chain_nm4_work(int *sz_arg, int *sz_res, int *sz_iw, int *sz_w) {
  if (sz_arg)
    *sz_arg = 4;
  if (sz_res)
    *sz_res = 3;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 47;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vde_chain_nm4_work>:
  endbr64
  test   %rdi,%rdi
  je     L27
  movl   $0x4,(%rdi)
L27:
  test   %rsi,%rsi
  je     L21
  movl   $0x3,(%rsi)
L21:
  test   %rdx,%rdx
  je     L2
  movl   $0x0,(%rdx)
L2:
  test   %rcx,%rcx
  je     L23
  movl   $0x2f,(%rcx)
L23:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int vde_chain_nm4_work(int *sz_arg, int *sz_res, int *sz_iw, int *sz_w) {
  if (sz_arg)
    *sz_arg = 4;
  if (sz_res)
    *sz_res = 3;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 47;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vde_chain_nm4_work>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movl   $0x4,(%rdi)
L0:
  test   %rsi,%rsi
  je     L2
  movl   $0x3,(%rsi)
L2:
  test   %rdx,%rdx
  je     L3
  movl   $0x0,(%rdx)
L3:
  test   %rcx,%rcx
  je     L21
  movl   $0x2f,(%rcx)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vde_chain_nm4_work(int *sz_arg, int *sz_res, int *sz_iw, int *sz_w) {
  if (sz_arg)
    *sz_arg = 4;
  if (sz_res)
    *sz_res = 3;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 47;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vde_chain_nm4_work>:
  endbr64
  test   %rdi,%rdi
  je     L9
  movl   $0x4,(%rdi)
L9:
  test   %rsi,%rsi
  je     L19
  movl   $0x3,(%rsi)
L19:
  test   %rdx,%rdx
  je     L0
  movl   $0x0,(%rdx)
L0:
  test   %rcx,%rcx
  je     L2
  movl   $0x2f,(%rcx)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int vde_chain_nm4_work(int *sz_arg, int *sz_res, int *sz_iw, int *sz_w) {
  if (sz_arg)
    *sz_arg = 4;
  if (sz_res)
    *sz_res = 3;
  if (sz_iw)
    *sz_iw = 0;
  if (sz_w)
    *sz_w = 47;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x646c72,-0xc(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L4
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L4:
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D22
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string

tool: D24: w

tool: D22: ./test.txt

tool: D0: Error opening file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  char str[] = "Hello World";
  f = fopen("./test.txt", "w");
  if (!f) {
    perror("Error opening file");
    exit(1);
  }
  fwrite(str, sizeof(str) - 1, 1, f);
  fclose(f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,0xc(%rsp)
  movl   $0x646c72,0x14(%rsp)
  lea    D23(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L18:
  lea    0xc(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0xb,%esi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  lea    D18(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string

tool: D23: w

tool: D16: ./test.txt

tool: D18: Error opening file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  char str[] = "Hello World";
  f = fopen("./test.txt", "w");
  if (!f) {
    perror("Error opening file");
    exit(1);
  }
  fwrite(str, sizeof(str) - 1, 1, f);
  fclose(f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rsi
  lea    D27(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  movl   $0x646c72,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
L1:
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0xb,%esi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  lea    D13(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D17: w

tool: D27: ./test.txt

tool: D13: Error opening file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  char str[] = "Hello World";
  f = fopen("./test.txt", "w");
  if (!f) {
    perror("Error opening file");
    exit(1);
  }
  fwrite(str, sizeof(str) - 1, 1, f);
  fclose(f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rsi
  lea    D24(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  movl   $0x646c72,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
L18:
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0xb,%esi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D23: w

tool: D24: ./test.txt

tool: D3: Error opening file

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *f;
  char str[] = "Hello World";
  f = fopen("./test.txt", "w");
  if (!f) {
    perror("Error opening file");
    exit(1);
  }
  fwrite(str, sizeof(str) - 1, 1, f);
  fclose(f);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  mov    $0x2d,%edi
  call   <putchar@plt>
  negl   -0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <printd>
L8:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x30(%rdx),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10)
    printd(n / 10);
  putchar(n % 10 + '0');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printd>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L16
L17:
  lea    0x9(%rbx),%eax
  cmp    $0x12,%eax
  ja     L26
L9:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  call   <putchar@plt>
  pop    %rbx
  ret
L16:
  mov    $0x2d,%edi
  call   <putchar@plt>
  neg    %ebx
  jmp    L17
L26:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <printd>
  jmp    L9
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10)
    printd(n / 10);
  putchar(n % 10 + '0');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L58
L48:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L33
L61:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L33:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L9
L25:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  jmp    L61
  nopl   0x0(%rax)
L58:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putchar@plt>
  jmp    L48
  nopl   0x0(%rax)
L9:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L26
L30:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putchar@plt>
  jmp    L25
  nop
L26:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <printd>
  jmp    L30
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10)
    printd(n / 10);
  putchar(n % 10 + '0');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L12
L69:
  lea    0x9(%rbx),%eax
  mov    %ebx,%r12d
  cmp    $0x12,%eax
  ja     L11
L2:
  mov    $0xcccccccd,%eax
  add    $0x8,%rsp
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <putchar@plt>
  nopl   (%rax)
L11:
  mov    $0xcccccccd,%edi
  mov    %r12,%rbp
  imul   %rdi,%rbp
  shr    $0x23,%rbp
  lea    0x9(%rbp),%eax
  mov    %ebp,%r15d
  cmp    $0x12,%eax
  ja     L3
L29:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edi
  call   <putchar@plt>
  jmp    L2
  nopl   0x0(%rax)
L12:
  mov    $0x2d,%edi
  neg    %ebx
  call   <putchar@plt>
  jmp    L69
  nopl   0x0(%rax)
L3:
  mov    %r15,%r13
  imul   %rdi,%r13
  shr    $0x23,%r13
  lea    0x9(%r13),%eax
  mov    %r13d,%r14d
  cmp    $0x12,%eax
  ja     L10
L8:
  mov    $0xcccccccd,%eax
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  lea    0x30(%r13),%edi
  call   <putchar@plt>
  jmp    L29
  nop
L10:
  imul   %r14,%rdi
  shr    $0x23,%rdi
  call   <printd>
  jmp    L8
```

assistant: ```c
void printd(int n) {
  if (n < 0) {
    putchar('-');
    n = -n;
  }
  if (n / 10)
    printd(n / 10);
  putchar(n % 10 + '0');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_inner_ddot_trans>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rax
  mov    %rdx,%r10
  movapd %xmm0,%xmm3
  mov    %ecx,%r11d
  cmp    $0x3,%ecx
  jle    L54
  movslq %r8d,%rbp
  shl    $0x3,%rbp
  lea    (%r8,%r8,1),%esi
  movslq %esi,%rbx
  shl    $0x3,%rbx
  add    %r8d,%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  lea    0x0(,%r8,4),%ecx
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  lea    -0x4(%r11),%r12d
  shr    $0x2,%r12d
  lea    0x1(%r12),%r13d
  mov    %r13d,%r13d
  mov    %r13,%r9
  shl    $0x5,%r9
  add    %rax,%r9
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
L23:
  movsd  (%rax),%xmm2
  mulsd  (%rdx),%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x8(%rax),%xmm2
  mulsd  (%rdx,%rbp,1),%xmm2
  addsd  %xmm2,%xmm1
  movsd  0x10(%rax),%xmm2
  mulsd  (%rdx,%rbx,1),%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x18(%rax),%xmm2
  mulsd  (%rdx,%rsi,1),%xmm2
  addsd  %xmm2,%xmm1
  add    %rcx,%rdx
  add    $0x20,%rax
  cmp    %r9,%rax
  jne    L23
  imul   %r13,%rcx
  add    %rcx,%r10
  lea    0x4(,%r12,4),%eax
L27:
  cmp    %eax,%r11d
  je     L55
  lea    -0x1(%r11),%edx
  cmp    %eax,%edx
  jle    L21
  movsd  (%r9),%xmm2
  mulsd  (%r10),%xmm2
  addsd  %xmm2,%xmm0
  movslq %r8d,%r8
  shl    $0x3,%r8
  add    %r8,%r10
  movsd  0x8(%r9),%xmm2
  mulsd  (%r10),%xmm2
  addsd  %xmm2,%xmm1
  add    %r8,%r10
  add    $0x10,%r9
  add    $0x2,%eax
L21:
  cmp    %r11d,%eax
  jge    L55
  movsd  (%r9),%xmm2
  mulsd  (%r10),%xmm2
  addsd  %xmm2,%xmm0
L55:
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  mov    %rsi,%r9
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
void _inner_ddot_trans(double *Cr, const double *Ar, const double *Br, double alpha, int nVP, int ldB) {
  register int k, iB;
  register double f0, f1, f2, f3, cval0, cval1;
  cval0 = 0.0;
  cval1 = 0.0;
  for (k = 0; k < nVP - 3; k += 4) {
    f0 = Ar[0] * Br[0];
    cval0 += f0;
    f1 = Ar[1] * Br[ldB];
    cval1 += f1;
    f2 = Ar[2] * Br[2 * ldB];
    cval0 += f2;
    f3 = Ar[3] * Br[3 * ldB];
    cval1 += f3;
    Br += 4 * ldB;
    Ar += 4;
  }
  if (k == nVP)
    goto update;
  if (k < nVP - 1) {
    f0 = Ar[0] * Br[0];
    cval0 += f0;
    f1 = Ar[1] * Br[ldB];
    cval1 += f1;
    Br += 2 * ldB;
    Ar += 2;
    k += 2;
  }
  if (k < nVP) {
    f0 = Ar[0] * Br[0];
    cval0 += f0;
    Br += ldB;
    Ar++;
    k++;
  }
update:
  f0 = (cval0 + cval1) * alpha;
  Cr[0] += f0;
}
```