user: Please show me the C implementation that matches the assembly code listed below:

```asm
<twoSum>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  lea    -0x1(%r14),%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,4),%edi
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r14d,%r14d
  jle    L18
  cmp    $0x2,%r12d
  jbe    L86
  mov    %r14d,%edx
  movdqa D6(%rip),%xmm0
  movdqa D17(%rip),%xmm2
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L25:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L25
  mov    %r14d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r14b
  je     L18
L22:
  movslq %eax,%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r14d
  jle    L18
  add    $0x2,%eax
  mov    %edx,0x4(%r13,%rcx,1)
  cmp    %r14d,%eax
  jge    L18
  mov    %eax,0x8(%r13,%rcx,1)
L18:
  mov    %r12d,%ecx
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sort@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  nop
L39:
  cmp    %r12d,%edi
  jge    L48
  movslq %edi,%rdx
  mov    0x0(%rbp,%rdx,4),%esi
  lea    0x0(,%rdx,4),%r10
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%r8d
  lea    0x0(,%rdx,4),%r9
  lea    0x1(%rdi),%edx
  movslq %edx,%rdx
  lea    (%r8,%rsi,1),%ecx
  cmp    %ecx,%ebx
  jle    L79
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    0x0(%rbp,%rdx,4),%esi
  mov    %edx,%edi
  lea    0x0(,%rdx,4),%r10
  add    $0x1,%rdx
  lea    (%rsi,%r8,1),%ecx
  cmp    %ebx,%ecx
  jl     L3
L79:
  cmp    %ecx,%ebx
  jge    L77
  lea    -0x1(%r12),%edx
  movslq %edx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L106:
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %edx,%r12d
  lea    0x0(,%rdx,4),%r9
  sub    $0x1,%rdx
  add    %esi,%ecx
  cmp    %ebx,%ecx
  jg     L106
L77:
  cmp    %ecx,%ebx
  jne    L39
  add    %r13,%r9
  add    %r10,%r13
  mov    0x0(%r13),%ecx
  mov    (%r9),%edx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  mov    %edx,(%rax)
  mov    (%r9),%edx
  mov    0x0(%r13),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,0x4(%rax)
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L86:
  xor    %eax,%eax
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: byte[16]
name: disassemble_data
arguments: data_label: D17
datatype: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int *twoSum(int *nums, int size, int target) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  for (int i = 0; i < size; i++)
    indexes[i] = i;
  sort(nums, indexes, 0, size - 1);
  int *result = (int *)malloc(sizeof(int) * 2);
  int l = 0, r = size - 1;
  while (l < r) {
    while (nums[l] + nums[r] < target)
      l++;
    while (nums[l] + nums[r] > target)
      r--;
    if (nums[l] + nums[r] == target) {
      result[0] = ((indexes[l]) < (indexes[r]) ? (indexes[l]) : (indexes[r]));
      result[1] = ((indexes[l]) > (indexes[r]) ? (indexes[l]) : (indexes[r]));
      return result;
    }
  }
}
```