ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBHostEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L6
  add    $0x102,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
L6:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBHostEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) &= ~0x00000001;
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<USBHostEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L7
  add    $0x102,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L7:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBHostEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) &= ~0x00000001;
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBHostEndpointDataAck>:
  endbr64
  test   %esi,%esi
  jne    L2
  add    $0x102,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L2:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  and    $0xfffffffe,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void USBHostEndpointDataAck(uint32_t ui32Base, uint32_t ui32Endpoint) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    (*((volatile uint8_t *)(ui32Base + 0x00000102))) &= ~0x00000001;
  } else {
    (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) &= ~(0x00000001);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FINA_Init@plt>
  test   %rax,%rax
  jne    L9
  nop
L14:
  mov    $0x0,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  je     L14
L9:
  mov    $0x0,%eax
  call   <FINA_End@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (0 == FINA_Init(argc, argv))
    while (0 == FINA_Tick())
      ;
  FINA_End();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <FINA_Init@plt>
  test   %rax,%rax
  jne    L19
L4:
  mov    $0x0,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  je     L4
L19:
  mov    $0x0,%eax
  call   <FINA_End@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (0 == FINA_Init(argc, argv))
    while (0 == FINA_Tick())
      ;
  FINA_End();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <FINA_Init@plt>
  test   %rax,%rax
  je     L2
L18:
  xor    %eax,%eax
  call   <FINA_End@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L2:
  xor    %eax,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  jne    L18
  xor    %eax,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  je     L2
  jmp    L18
```

assistant: ```c
int main(int argc, char **argv) {
  if (0 == FINA_Init(argc, argv))
    while (0 == FINA_Tick())
      ;
  FINA_End();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <FINA_Init@plt>
  test   %rax,%rax
  je     L35
L39:
  xor    %eax,%eax
  call   <FINA_End@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L35:
  xor    %eax,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  jne    L39
  xor    %eax,%eax
  call   <FINA_Tick@plt>
  test   %rax,%rax
  je     L35
  jmp    L39
```

assistant: ```c
int main(int argc, char **argv) {
  if (0 == FINA_Init(argc, argv))
    while (0 == FINA_Tick())
      ;
  FINA_End();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<help_rlogin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <esc_prn@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: 
{Hrlogin} [{Uip}] {Uport}
  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. 
  To attach to the console of a virtual router running on port 2000 of this
  host PC, use {Hrlogin 2000}
  To telnet to the port 2004 of a remote host 10.1.1.1, use
  {Hrlogin 10.1.1.1 2004}


assistant: ```c
int help_rlogin(int argc, char **argv) {
  esc_prn("\n{Hrlogin} [{Uip}] {Uport}\n"
          "  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. \n"
          "  To attach to the console of a virtual router running on port 2000 of this\n"
          "  host PC, use {Hrlogin 2000}\n"
          "  To telnet to the port 2004 of a remote host 10.1.1.1, use\n"
          "  {Hrlogin 10.1.1.1 2004}\n");
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help_rlogin>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <esc_prn@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: 
{Hrlogin} [{Uip}] {Uport}
  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. 
  To attach to the console of a virtual router running on port 2000 of this
  host PC, use {Hrlogin 2000}
  To telnet to the port 2004 of a remote host 10.1.1.1, use
  {Hrlogin 10.1.1.1 2004}


assistant: ```c
int help_rlogin(int argc, char **argv) {
  esc_prn("\n{Hrlogin} [{Uip}] {Uport}\n"
          "  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. \n"
          "  To attach to the console of a virtual router running on port 2000 of this\n"
          "  host PC, use {Hrlogin 2000}\n"
          "  To telnet to the port 2004 of a remote host 10.1.1.1, use\n"
          "  {Hrlogin 10.1.1.1 2004}\n");
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<help_rlogin>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <esc_prn@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: 
{Hrlogin} [{Uip}] {Uport}
  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. 
  To attach to the console of a virtual router running on port 2000 of this
  host PC, use {Hrlogin 2000}
  To telnet to the port 2004 of a remote host 10.1.1.1, use
  {Hrlogin 10.1.1.1 2004}


assistant: ```c
int help_rlogin(int argc, char **argv) {
  esc_prn("\n{Hrlogin} [{Uip}] {Uport}\n"
          "  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. \n"
          "  To attach to the console of a virtual router running on port 2000 of this\n"
          "  host PC, use {Hrlogin 2000}\n"
          "  To telnet to the port 2004 of a remote host 10.1.1.1, use\n"
          "  {Hrlogin 10.1.1.1 2004}\n");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<help_rlogin>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <esc_prn@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: 
{Hrlogin} [{Uip}] {Uport}
  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. 
  To attach to the console of a virtual router running on port 2000 of this
  host PC, use {Hrlogin 2000}
  To telnet to the port 2004 of a remote host 10.1.1.1, use
  {Hrlogin 10.1.1.1 2004}


assistant: ```c
int help_rlogin(int argc, char **argv) {
  esc_prn("\n{Hrlogin} [{Uip}] {Uport}\n"
          "  Telnet to {Uport} at {Uip} (default 127.0.0.1) relative to host PC. \n"
          "  To attach to the console of a virtual router running on port 2000 of this\n"
          "  host PC, use {Hrlogin 2000}\n"
          "  To telnet to the port 2004 of a remote host 10.1.1.1, use\n"
          "  {Hrlogin 10.1.1.1 2004}\n");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x2800,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L7
L18:
  mov    -0x18(%rbp),%eax
  cltq
  lea    D7(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x19(%rbp)
  je     L9
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string

tool: D15: %s

tool: D7: SOS

tool: D8: %d


assistant: ```c
int main() {
  char *S = (char *)malloc(10240 * sizeof(char));
  char *iter = S;
  int i = 0;
  int count = 0;
  scanf("%s", S);
  while (*iter != '\0') {
    char c = "SOS"[i];
    if (c != *iter)
      count++;
    i = (i + 1) % 3;
    iter++;
  }
  printf("%d\n", count);
  free(S);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2800,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L12
  mov    %rbx,%rcx
  mov    $0x0,%esi
  mov    $0x0,%eax
  lea    D15(%rip),%r8
L1:
  movslq %eax,%rdi
  cmp    %dl,(%r8,%rdi,1)
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%esi
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,2),%edi
  mov    %edx,%eax
  sub    %edi,%eax
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L1
L21:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  mov    $0x0,%esi
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D27: %s

tool: D15: SOS

tool: D12: %d


assistant: ```c
int main() {
  char *S = (char *)malloc(10240 * sizeof(char));
  char *iter = S;
  int i = 0;
  int count = 0;
  scanf("%s", S);
  while (*iter != '\0') {
    char c = "SOS"[i];
    if (c != *iter)
      count++;
    i = (i + 1) % 3;
    iter++;
  }
  printf("%d\n", count);
  free(S);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2800,%edi
  call   <malloc@plt>
  lea    D13(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L20
  mov    %rbp,%rcx
  xor    %esi,%esi
  xor    %eax,%eax
  mov    $0xaaaaaaab,%r8d
  lea    D21(%rip),%r9
  nopl   (%rax)
L13:
  movslq %eax,%rdi
  cmp    %dl,(%r9,%rdi,1)
  setne  %dl
  add    $0x1,%eax
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %edx,%esi
  mov    %rax,%rdx
  imul   %r8,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edi
  mov    %edx,%eax
  movzbl (%rcx),%edx
  sub    %edi,%eax
  test   %dl,%dl
  jne    L13
L21:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L20:
  xor    %esi,%esi
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D13: %s

tool: D21: SOS

tool: D7: %d


assistant: ```c
int main() {
  char *S = (char *)malloc(10240 * sizeof(char));
  char *iter = S;
  int i = 0;
  int count = 0;
  scanf("%s", S);
  while (*iter != '\0') {
    char c = "SOS"[i];
    if (c != *iter)
      count++;
    i = (i + 1) % 3;
    iter++;
  }
  printf("%d\n", count);
  free(S);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2800,%edi
  call   <malloc@plt>
  lea    D23(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L6
  mov    %rbp,%rcx
  xor    %esi,%esi
  xor    %eax,%eax
  mov    $0xaaaaaaab,%r8d
  lea    D17(%rip),%r9
  nopl   (%rax)
L11:
  movslq %eax,%rdi
  cmp    (%r9,%rdi,1),%dl
  setne  %dl
  add    $0x1,%eax
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %edx,%esi
  mov    %rax,%rdx
  imul   %r8,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%edi
  mov    %edx,%eax
  movzbl (%rcx),%edx
  sub    %edi,%eax
  test   %dl,%dl
  jne    L11
L16:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  xor    %esi,%esi
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D23
data_type: string
name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D27
data_type: string

tool: D23: %s

tool: D17: SOS

tool: D27: %d


assistant: ```c
int main() {
  char *S = (char *)malloc(10240 * sizeof(char));
  char *iter = S;
  int i = 0;
  int count = 0;
  scanf("%s", S);
  while (*iter != '\0') {
    char c = "SOS"[i];
    if (c != *iter)
      count++;
    i = (i + 1) % 3;
    iter++;
  }
  printf("%d\n", count);
  free(S);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<version_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L30
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L30
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L30
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L47:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L47
L48:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L16
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L30
L16:
  movl   $0x0,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int version_number(const char *base, const char *backup, size_t base_length) {
  int version;
  const char *p;
  version = 0;
  if (!strncmp(base, backup, base_length) && (isascii((unsigned char)backup[base_length]) && isdigit((unsigned char)backup[base_length]))) {
    for (p = &backup[base_length]; (isascii((unsigned char)*p) && isdigit((unsigned char)*p)); ++p)
      version = version * 10 + *p - '0';
    if (p[0] != '~' || p[1])
      version = 0;
  }
  return version;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<version_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <strncmp@plt>
  mov    $0x0,%r12d
  test   %eax,%eax
  je     L28
L50:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    %eax,%r12d
  add    %rbp,%rbx
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L50
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L50
  mov    %r12d,%ebp
  jmp    L34
L47:
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
L34:
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L75
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L47
L75:
  cmpb   $0x7e,(%rbx)
  jne    L50
  cmpb   $0x0,0x1(%rbx)
  cmove  %ebp,%r12d
  jmp    L50
```

assistant: ```c
int version_number(const char *base, const char *backup, size_t base_length) {
  int version;
  const char *p;
  version = 0;
  if (!strncmp(base, backup, base_length) && (isascii((unsigned char)backup[base_length]) && isdigit((unsigned char)backup[base_length]))) {
    for (p = &backup[base_length]; (isascii((unsigned char)*p) && isdigit((unsigned char)*p)); ++p)
      version = version * 10 + *p - '0';
    if (p[0] != '~' || p[1])
      version = 0;
  }
  return version;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<version_number>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  je     L83
L84:
  xor    %r12d,%r12d
L50:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L83:
  add    %rbp,%rbx
  mov    %eax,%r12d
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L84
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L24
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L59:
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L55
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L24:
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L59
L55:
  cmpb   $0x7e,(%rbx)
  jne    L84
  cmpb   $0x0,0x1(%rbx)
  je     L50
  jmp    L84
```

assistant: ```c
int version_number(const char *base, const char *backup, size_t base_length) {
  int version;
  const char *p;
  version = 0;
  if (!strncmp(base, backup, base_length) && (isascii((unsigned char)backup[base_length]) && isdigit((unsigned char)backup[base_length]))) {
    for (p = &backup[base_length]; (isascii((unsigned char)*p) && isdigit((unsigned char)*p)); ++p)
      version = version * 10 + *p - '0';
    if (p[0] != '~' || p[1])
      version = 0;
  }
  return version;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<version_number>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  je     L1
L52:
  xor    %r12d,%r12d
L17:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    %rbp,%rbx
  mov    %eax,%r12d
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L52
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L35
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L10
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L35:
  movzbl (%rbx),%edi
  call   <isascii@plt>
  test   %rax,%rax
  jne    L30
L10:
  cmpb   $0x7e,(%rbx)
  jne    L52
  cmpb   $0x0,0x1(%rbx)
  je     L17
  jmp    L52
```

assistant: ```c
int version_number(const char *base, const char *backup, size_t base_length) {
  int version;
  const char *p;
  version = 0;
  if (!strncmp(base, backup, base_length) && (isascii((unsigned char)backup[base_length]) && isdigit((unsigned char)backup[base_length]))) {
    for (p = &backup[base_length]; (isascii((unsigned char)*p) && isdigit((unsigned char)*p)); ++p)
      version = version * 10 + *p - '0';
    if (p[0] != '~' || p[1])
      version = 0;
  }
  return version;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int vul(char *content, int len) {
  char buffer[16];
  memcpy(buffer, content, len);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vul>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vul(char *content, int len) {
  char buffer[16];
  memcpy(buffer, content, len);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vul>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vul(char *content, int len) {
  char buffer[16];
  memcpy(buffer, content, len);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vul>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vul(char *content, int len) {
  char buffer[16];
  memcpy(buffer, content, len);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<L_negate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x80000000,-0x14(%rbp)
  je     L14
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L15
L14:
  mov    $0x7fffffff,%eax
L15:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t L_negate(int32_t L_var1) {
  int32_t L_var_out;
  L_var_out = (L_var1 == (int32_t)0x80000000L) ? (int32_t)0x7fffffffL : -L_var1;
  return (L_var_out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<L_negate>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmp    $0x80000000,%edi
  mov    $0x7fffffff,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int32_t L_negate(int32_t L_var1) {
  int32_t L_var_out;
  L_var_out = (L_var1 == (int32_t)0x80000000L) ? (int32_t)0x7fffffffL : -L_var1;
  return (L_var_out);
}
```