ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  or     %edx,%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L71
  movl   $0x1010101,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L21:
  addq   $0x4,-0x18(%rbp)
  addq   $0x4,-0x20(%rbp)
  subq   $0x4,-0x28(%rbp)
L0:
  cmpq   $0x3,-0x28(%rbp)
  jbe    L71
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L71
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %edx,%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L21
  jmp    L71
L11:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xe(%rbp),%eax
  cmp    -0xd(%rbp),%al
  je     L99
  movsbl -0xe(%rbp),%eax
  movsbl -0xd(%rbp),%edx
  sub    %edx,%eax
  jmp    L8
L99:
  cmpb   $0x0,-0xe(%rbp)
  jne    L71
  mov    $0x0,%eax
  jmp    L8
L71:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L11
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *a, const char *b, size_t n) {
  if ((((int)a | (int)b) & 3) == 0) {
    int w;
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (n >= 4 && (w = *(int *)a) == *(int *)b && !(((w)-ones_word) & ~(w)&eights_word))
      a += 4, b += 4, n -= 4;
  }
  while (n-- > 0) {
    char c1, c2;
    if ((c1 = *a++) != (c2 = *b++))
      return c1 - c2;
    if (c1 == 0)
      return 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x3,%al
  jne    L68
  cmp    $0x3,%rdx
  jbe    L68
L60:
  mov    (%rdi),%eax
  cmp    %eax,(%rsi)
  jne    L68
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  jne    L68
  add    $0x4,%rdi
  add    $0x4,%rsi
  sub    $0x4,%rdx
  cmp    $0x3,%rdx
  ja     L60
L68:
  mov    $0x0,%eax
L31:
  cmp    %rax,%rdx
  je     L63
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L59
  add    $0x1,%rax
  test   %cl,%cl
  jne    L31
  mov    $0x0,%eax
  ret
L59:
  movsbl %cl,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L63:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strncmp(const char *a, const char *b, size_t n) {
  if ((((int)a | (int)b) & 3) == 0) {
    int w;
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (n >= 4 && (w = *(int *)a) == *(int *)b && !(((w)-ones_word) & ~(w)&eights_word))
      a += 4, b += 4, n -= 4;
  }
  while (n-- > 0) {
    char c1, c2;
    if ((c1 = *a++) != (c2 = *b++))
      return c1 - c2;
    if (c1 == 0)
      return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x3,%al
  je     L45
L18:
  xor    %eax,%eax
  jmp    L29
L44:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L22
  add    $0x1,%rax
  test   %cl,%cl
  je     L33
L29:
  cmp    %rax,%rdx
  jne    L44
L33:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L69:
  mov    (%rdi),%eax
  cmp    %eax,(%rsi)
  jne    L18
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  jne    L18
  add    $0x4,%rdi
  add    $0x4,%rsi
  sub    $0x4,%rdx
L45:
  cmp    $0x3,%rdx
  ja     L69
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *a, const char *b, size_t n) {
  if ((((int)a | (int)b) & 3) == 0) {
    int w;
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (n >= 4 && (w = *(int *)a) == *(int *)b && !(((w)-ones_word) & ~(w)&eights_word))
      a += 4, b += 4, n -= 4;
  }
  while (n-- > 0) {
    char c1, c2;
    if ((c1 = *a++) != (c2 = *b++))
      return c1 - c2;
    if (c1 == 0)
      return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x3,%al
  je     L49
L88:
  xor    %eax,%eax
  jmp    L13
L76:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L17
  add    $0x1,%rax
  test   %cl,%cl
  je     L83
L13:
  cmp    %rax,%rdx
  jne    L76
L83:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L60:
  mov    (%rdi),%eax
  cmp    %eax,(%rsi)
  jne    L88
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  jne    L88
  add    $0x4,%rdi
  add    $0x4,%rsi
  sub    $0x4,%rdx
L49:
  cmp    $0x3,%rdx
  ja     L60
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *a, const char *b, size_t n) {
  if ((((int)a | (int)b) & 3) == 0) {
    int w;
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (n >= 4 && (w = *(int *)a) == *(int *)b && !(((w)-ones_word) & ~(w)&eights_word))
      a += 4, b += 4, n -= 4;
  }
  while (n-- > 0) {
    char c1, c2;
    if ((c1 = *a++) != (c2 = *b++))
      return c1 - c2;
    if (c1 == 0)
      return 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D16: Student ID : 20113343 


tool: D5: Name : Hyun Jae Young 


assistant: ```c
void display() {
  printf("Student ID : 20113343 \n");
  printf("Name : Hyun Jae Young \n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string

tool: D16: Student ID : 20113343 


tool: D14: Name : Hyun Jae Young 


assistant: ```c
void display() {
  printf("Student ID : 20113343 \n");
  printf("Name : Hyun Jae Young \n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D7: Student ID : 20113343 


tool: D1: Name : Hyun Jae Young 


assistant: ```c
void display() {
  printf("Student ID : 20113343 \n");
  printf("Name : Hyun Jae Young \n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string

tool: D6: Student ID : 20113343 


tool: D9: Name : Hyun Jae Young 


assistant: ```c
void display() {
  printf("Student ID : 20113343 \n");
  printf("Name : Hyun Jae Young \n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xfffffffa,-0x4(%rbp)
  jl     L26
  cmpl   $0x4,-0x4(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  cmp    $0xfffffff9,%eax
  je     L0
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  cmp    $0x7,%eax
  jne    L26
L0:
  mov    $0x0,%eax
  call   <link_error@plt>
L26:
  nop
  leave
  ret
```

assistant: ```c
void f12(int a, int b) {
  if (a >= -6 && a <= 4)
    if ((a / b) == -7 || (a / b) == 7)
      link_error();
}
```
user: Translate the below assembly code into C programming language:

```asm
<f12>:
  endbr64
  ret
```

assistant: ```c
void f12(int a, int b) {
  if (a >= -6 && a <= 4)
    if ((a / b) == -7 || (a / b) == 7)
      link_error();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f12>:
  endbr64
  ret
```

assistant: ```c
void f12(int a, int b) {
  if (a >= -6 && a <= 4)
    if ((a / b) == -7 || (a / b) == 7)
      link_error();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f12>:
  endbr64
  ret
```

assistant: ```c
void f12(int a, int b) {
  if (a >= -6 && a <= 4)
    if ((a / b) == -7 || (a / b) == 7)
      link_error();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void vector_delete(char **data, unsigned int *size, unsigned int *capacity) {
  free(*data);
  *data = NULL;
  *size = 0;
  *capacity = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vector_delete>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vector_delete(char **data, unsigned int *size, unsigned int *capacity) {
  free(*data);
  *data = NULL;
  *size = 0;
  *capacity = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_delete>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vector_delete(char **data, unsigned int *size, unsigned int *capacity) {
  free(*data);
  *data = NULL;
  *size = 0;
  *capacity = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_delete>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  movl   $0x0,(%r12)
  movl   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vector_delete(char **data, unsigned int *size, unsigned int *capacity) {
  free(*data);
  *data = NULL;
  *size = 0;
  *capacity = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compare_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x50,%rsp
  mov    %rdi,-0x1048(%rbp)
  mov    %rsi,-0x1050(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1048(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x1030(%rbp)
  cmpq   $0x0,-0x1030(%rbp)
  jne    L87
  mov    $0x0,%eax
  jmp    L109
L87:
  mov    -0x1050(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x1028(%rbp)
  cmpq   $0x0,-0x1028(%rbp)
  jne    L55
  mov    $0x0,%eax
  jmp    L109
L55:
  mov    -0x1030(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    $0x800,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x1020(%rbp)
  mov    -0x1028(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    $0x800,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x1018(%rbp)
  cmpq   $0x0,-0x1020(%rbp)
  jne    L103
  cmpq   $0x0,-0x1018(%rbp)
  jne    L103
  movl   $0x1,-0x1034(%rbp)
  jmp    L46
L103:
  cmpq   $0x0,-0x1020(%rbp)
  je     L14
  cmpq   $0x0,-0x1018(%rbp)
  je     L14
  lea    -0x810(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L55
L14:
  movl   $0x0,-0x1034(%rbp)
L46:
  mov    -0x1030(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x1028(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x1034(%rbp),%eax
L109:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D15: r

assistant: ```c
int compare_file(const char *outfn, const char *newfn) {
  FILE *old_f, *new_f;
  char oldbuf[2048], newbuf[2048], *oldcp, *newcp;
  int retval;
  old_f = fopen(outfn, "r");
  if (!old_f)
    return 0;
  new_f = fopen(newfn, "r");
  if (!new_f)
    return 0;
  while (1) {
    oldcp = fgets(oldbuf, sizeof(oldbuf), old_f);
    newcp = fgets(newbuf, sizeof(newbuf), new_f);
    if (!oldcp && !newcp) {
      retval = 1;
      break;
    }
    if (!oldcp || !newcp || strcmp(oldbuf, newbuf)) {
      retval = 0;
      break;
    }
  }
  fclose(old_f);
  fclose(new_f);
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compare_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L92
  mov    %rax,%rbp
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L70
  mov    %rsp,%rbx
L59:
  mov    %rbp,%rdx
  mov    $0x800,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %rax,%r13
  lea    0x800(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x800,%esi
  call   <fgets@plt>
  test   %r13,%r13
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %r13,%rax
  je     L64
  test   %dl,%dl
  jne    L99
  test   %cl,%cl
  jne    L99
  lea    0x800(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L59
  mov    $0x0,%ebx
  jmp    L17
L64:
  mov    $0x1,%ebx
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
L92:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    %ebx,%eax
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L99:
  mov    $0x0,%ebx
  jmp    L17
L70:
  mov    $0x0,%ebx
  jmp    L92
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: r

assistant: ```c
int compare_file(const char *outfn, const char *newfn) {
  FILE *old_f, *new_f;
  char oldbuf[2048], newbuf[2048], *oldcp, *newcp;
  int retval;
  old_f = fopen(outfn, "r");
  if (!old_f)
    return 0;
  new_f = fopen(newfn, "r");
  if (!new_f)
    return 0;
  while (1) {
    oldcp = fgets(oldbuf, sizeof(oldbuf), old_f);
    newcp = fgets(newbuf, sizeof(newbuf), new_f);
    if (!oldcp && !newcp) {
      retval = 1;
      break;
    }
    if (!oldcp || !newcp || strcmp(oldbuf, newbuf)) {
      retval = 0;
      break;
    }
  }
  fclose(old_f);
  fclose(new_f);
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare_file>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D1(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %r12,%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L24
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L24
  mov    %rsp,%r12
  lea    0x800(%rsp),%rbp
  jmp    L88
  nopl   (%rax)
L23:
  test   %dl,%dl
  jne    L34
  test   %cl,%cl
  jne    L34
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
L88:
  mov    %r13,%rdx
  mov    $0x800,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r14,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <fgets@plt>
  test   %rbx,%rbx
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %rax,%rbx
  jne    L23
  mov    $0x1,%r12d
  jmp    L13
  nopl   0x0(%rax)
L24:
  xor    %r12d,%r12d
L16:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x1010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  xor    %r12d,%r12d
L13:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  jmp    L16
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: r

assistant: ```c
int compare_file(const char *outfn, const char *newfn) {
  FILE *old_f, *new_f;
  char oldbuf[2048], newbuf[2048], *oldcp, *newcp;
  int retval;
  old_f = fopen(outfn, "r");
  if (!old_f)
    return 0;
  new_f = fopen(newfn, "r");
  if (!new_f)
    return 0;
  while (1) {
    oldcp = fgets(oldbuf, sizeof(oldbuf), old_f);
    newcp = fgets(newbuf, sizeof(newbuf), new_f);
    if (!oldcp && !newcp) {
      retval = 1;
      break;
    }
    if (!oldcp || !newcp || strcmp(oldbuf, newbuf)) {
      retval = 0;
      break;
    }
  }
  fclose(old_f);
  fclose(new_f);
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare_file>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  lea    D7(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %r12,%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L92
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L92
  mov    %rsp,%r12
  lea    0x800(%rsp),%rbp
  jmp    L73
  nopl   (%rax)
L72:
  test   %dl,%dl
  jne    L66
  test   %cl,%cl
  jne    L66
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L66
L73:
  mov    %r13,%rdx
  mov    $0x800,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r14,%rdx
  mov    $0x800,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <fgets@plt>
  test   %rbx,%rbx
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %rax,%rbx
  jne    L72
  mov    $0x1,%r12d
  jmp    L7
  nopl   0x0(%rax)
L92:
  xor    %r12d,%r12d
L60:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x1010,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L66:
  xor    %r12d,%r12d
L7:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdi
  call   <fclose@plt>
  jmp    L60
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: r

assistant: ```c
int compare_file(const char *outfn, const char *newfn) {
  FILE *old_f, *new_f;
  char oldbuf[2048], newbuf[2048], *oldcp, *newcp;
  int retval;
  old_f = fopen(outfn, "r");
  if (!old_f)
    return 0;
  new_f = fopen(newfn, "r");
  if (!new_f)
    return 0;
  while (1) {
    oldcp = fgets(oldbuf, sizeof(oldbuf), old_f);
    newcp = fgets(newbuf, sizeof(newbuf), new_f);
    if (!oldcp && !newcp) {
      retval = 1;
      break;
    }
    if (!oldcp || !newcp || strcmp(oldbuf, newbuf)) {
      retval = 0;
      break;
    }
  }
  fclose(old_f);
  fclose(new_f);
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<conversion>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,0x4(%rsp)
  je     L2
  lea    D67(%rip),%rdi
  call   <puts@plt>
  lea    0x30(%rsp),%rcx
  lea    0x28(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movsd  0x30(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  call   <yuv2rgb@plt>
  movsd  0x18(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  0x20(%rsp),%xmm0
  lea    D66(%rip),%rdi
  mov    $0x6,%eax
  call   <printf@plt>
L8:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x48,%rsp
  ret
L2:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <rgb2yuv@plt>
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  lea    D10(%rip),%rdi
  mov    $0x6,%eax
  call   <printf@plt>
  jmp    L8
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D30
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D67
datatype: string
name: unpack_data
arguments: tag: D47
datatype: string
name: unpack_data
arguments: tag: D66
datatype: string
name: unpack_data
arguments: tag: D31
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string

tool: D30: Conversion rgb->Yuv 1;Yuv->rgb 2
Choix ?=(1 ou 2)

tool: D6: %d

tool: D67: Entrez les valeurs Y,u,v

tool: D47: %lf %lf %lf

tool: D66: Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf


tool: D31: Entrez les valeurs r,g,b

tool: D10: r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf


assistant: ```c
void conversion() {
  int choix;
  double r, g, b, y, u, v;
  printf("Conversion rgb->Yuv 1;Yuv->rgb 2\nChoix ?=(1 ou 2)");
  scanf("%d", &choix);
  printf("\n");
  if (choix == 1) {
    printf("Entrez les valeurs r,g,b\n");
    scanf("%lf %lf %lf", &r, &g, &b);
    printf("\n");
    rgb2yuv(&y, &u, &v, r, g, b);
    printf("r=%lf g=%lf b=%lf -> Y=%lf u=%lf v=%lf\n", r, g, b, y, u, v);
  } else {
    printf("Entrez les valeurs Y,u,v\n");
    scanf("%lf %lf %lf", &y, &u, &v);
    printf("\n");
    yuv2rgb(&r, &g, &b, y, u, v);
    printf("Y=%lf u=%lf v=%lf -> r=%lf g=%lf b=%lf\n", y, u, v, r, g, b);
  }
}
```