ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<match_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L80
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L80
  cmpq   $0x0,-0x20(%rbp)
  je     L80
  mov    $0x1,%eax
  jmp    L3
L80:
  mov    $0x0,%eax
L3:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L61
L33:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L61:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L66
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L66
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L33
L66:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
  mov    $0x1,%eax
  jmp    L2
L1:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
bool match_literal(char **p, void *zs) {
  assert(p && *p && zs);
  char *q = *p;
  char *s = zs;
  while (*s && *q && (*s == *q)) {
    ++q;
    ++s;
  }
  return !*s && (*p = q);
}
```
user: Translate the below assembly code into C programming language:

```asm
<match_literal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%edi
  test   %rbp,%rbp
  je     L60
  cmpq   $0x0,0x0(%rbp)
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
L60:
  call   <assert@plt>
  mov    0x0(%rbp),%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L51
L30:
  movzbl (%rdx),%ecx
  cmp    %al,%cl
  jne    L14
  test   %cl,%cl
  je     L14
  add    $0x1,%rdx
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L30
L51:
  mov    %rdx,0x0(%rbp)
  test   %rdx,%rdx
  setne  %cl
  movzbl %cl,%ecx
  jmp    L22
L14:
  mov    $0x0,%ecx
  test   %al,%al
  je     L51
L22:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool match_literal(char **p, void *zs) {
  assert(p && *p && zs);
  char *q = *p;
  char *s = zs;
  while (*s && *q && (*s == *q)) {
    ++q;
    ++s;
  }
  return !*s && (*p = q);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match_literal>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  je     L40
  cmpq   $0x0,0x0(%rbp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
L40:
  call   <assert@plt>
  movzbl (%rbx),%edx
  mov    0x0(%rbp),%rax
  test   %dl,%dl
  jne    L2
  jmp    L14
  nopl   0x0(%rax)
L33:
  cmp    %dl,%cl
  jne    L24
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
L2:
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L33
L24:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  test   %rax,%rax
  mov    %rax,0x0(%rbp)
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool match_literal(char **p, void *zs) {
  assert(p && *p && zs);
  char *q = *p;
  char *s = zs;
  while (*s && *q && (*s == *q)) {
    ++q;
    ++s;
  }
  return !*s && (*p = q);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match_literal>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rbp,%rbp
  je     L0
  cmpq   $0x0,0x0(%rbp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
L0:
  call   <assert@plt>
  movzbl (%rbx),%edx
  mov    0x0(%rbp),%rax
  test   %dl,%dl
  jne    L52
  jmp    L31
  nopl   0x0(%rax)
L13:
  cmp    %dl,%cl
  jne    L15
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  add    $0x1,%rax
  test   %dl,%dl
  je     L31
L52:
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L13
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L31:
  test   %rax,%rax
  mov    %rax,0x0(%rbp)
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool match_literal(char **p, void *zs) {
  assert(p && *p && zs);
  char *q = *p;
  char *s = zs;
  while (*s && *q && (*s == *q)) {
    ++q;
    ++s;
  }
  return !*s && (*p = q);
}
```
user: What is the c source code of the assembly code below?

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  sub    $0x8,%rsp
  push   $0x7
  mov    $0x6,%r9d
  mov    $0x5,%r8d
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <w@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    $0x144,%r9d
  mov    $0x7b,%r8d
  mov    %eax,%edi
  call   <sum@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int g(int i, int j, int k, int y) {
  int a = w(1, 2, 3, 4, 5, 6, 7);
  return a + sum(i, j, k, y, 123, 324);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<g>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %ecx,%r14d
  sub    $0x8,%rsp
  push   $0x7
  mov    $0x6,%r9d
  mov    $0x5,%r8d
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <w@plt>
  mov    %eax,%ebx
  mov    $0x144,%r9d
  mov    $0x7b,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <sum@plt>
  add    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int g(int i, int j, int k, int y) {
  int a = w(1, 2, 3, 4, 5, 6, 7);
  return a + sum(i, j, k, y, 123, 324);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<g>:
  endbr64
  push   %r14
  mov    $0x6,%r9d
  mov    %ecx,%r14d
  mov    $0x5,%r8d
  push   %r13
  mov    $0x4,%ecx
  mov    %edx,%r13d
  mov    $0x3,%edx
  push   %r12
  mov    %esi,%r12d
  mov    $0x2,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  sub    $0x8,%rsp
  push   $0x7
  call   <w@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    $0x144,%r9d
  mov    $0x7b,%r8d
  mov    %eax,%ebx
  call   <sum@plt>
  pop    %rdx
  pop    %rcx
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int g(int i, int j, int k, int y) {
  int a = w(1, 2, 3, 4, 5, 6, 7);
  return a + sum(i, j, k, y, 123, 324);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L6:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L6
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x10(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string

tool: D38: %d

tool: D8: %f

tool: D35: Sum: %.0f

tool: D27: 
Avg: %.2f

assistant: ```c
int main() {
  int n, i = 0;
  float a, sum = 0, avg;
  scanf("%d", &n);
  do {
    scanf("%f", &a);
    sum = sum + a;
    i++;
  } while (i < n);
  printf("Sum: %.0f", sum);
  avg = sum / n;
  printf("\nAvg: %.2f", avg);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    D19(%rip),%ebp
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
L5:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movd   %ebp,%xmm2
  addss  0x4(%rsp),%xmm2
  movd   %xmm2,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L5
  movaps %xmm2,%xmm0
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rsp),%xmm1
  movd   %ebp,%xmm0
  divss  %xmm1,%xmm0
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: f32
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D35
type: string

tool: D22: %d

tool: D19: 0

tool: D20: %f

tool: D4: Sum: %.0f

tool: D35: 
Avg: %.2f

assistant: ```c
int main() {
  int n, i = 0;
  float a, sum = 0, avg;
  scanf("%d", &n);
  do {
    scanf("%f", &a);
    sum = sum + a;
    i++;
  } while (i < n);
  printf("Sum: %.0f", sum);
  avg = sum / n;
  printf("\nAvg: %.2f", avg);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  nop
L16:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  call   <scanf@plt>
  add    $0x1,%ebx
  movss  0xc(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  cmp    %ebx,0x10(%rsp)
  jg     L16
  lea    D36(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D30(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D36
data_type: string
name: unpack_data
arguments: label: D30
data_type: string

tool: D23: %d

tool: D3: %f

tool: D36: Sum: %.0f

tool: D30: 
Avg: %.2f

assistant: ```c
int main() {
  int n, i = 0;
  float a, sum = 0, avg;
  scanf("%d", &n);
  do {
    scanf("%f", &a);
    sum = sum + a;
    i++;
  } while (i < n);
  printf("Sum: %.0f", sum);
  avg = sum / n;
  printf("\nAvg: %.2f", avg);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  push   %rbp
  lea    D39(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  nop
L13:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  call   <scanf@plt>
  add    $0x1,%ebx
  movss  0xc(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  cmp    %ebx,0x10(%rsp)
  jg     L13
  lea    D33(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D9(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D39
type_infered: string
name: unpack_data
arguments: data_tag: D33
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D12: %d

tool: D39: %f

tool: D33: Sum: %.0f

tool: D9: 
Avg: %.2f

assistant: ```c
int main() {
  int n, i = 0;
  float a, sum = 0, avg;
  scanf("%d", &n);
  do {
    scanf("%f", &a);
    sum = sum + a;
    i++;
  } while (i < n);
  printf("Sum: %.0f", sum);
  avg = sum / n;
  printf("\nAvg: %.2f", avg);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: malloc

assistant: ```c
void *xmalloc(size_t size) {
  void *ret;
  ret = malloc(size);
  if (!ret)
    perror("malloc");
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L0:
  mov    %rbx,%rax
  pop    %rbx
  ret
L2:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: malloc

assistant: ```c
void *xmalloc(size_t size) {
  void *ret;
  ret = malloc(size);
  if (!ret)
    perror("malloc");
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L4:
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: malloc

assistant: ```c
void *xmalloc(size_t size) {
  void *ret;
  ret = malloc(size);
  if (!ret)
    perror("malloc");
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L17:
  mov    %r12,%rax
  pop    %r12
  ret
L14:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  jmp    L17
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: malloc

assistant: ```c
void *xmalloc(size_t size) {
  void *ret;
  ret = malloc(size);
  if (!ret)
    perror("malloc");
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int p1, int p2) {
  int c = p1;
  p1 = p2;
  p2 = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  ret
```

assistant: ```c
void swap(int p1, int p2) {
  int c = p1;
  p1 = p2;
  p2 = c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<swap>:
  endbr64
  ret
```

assistant: ```c
void swap(int p1, int p2) {
  int c = p1;
  p1 = p2;
  p2 = c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap>:
  endbr64
  ret
```

assistant: ```c
void swap(int p1, int p2) {
  int c = p1;
  p1 = p2;
  p2 = c;
}
```
user: What is the c source code of the assembly code below:

```asm
<starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L42
  cmpq   $0x0,-0x20(%rbp)
  jne    L45
L42:
  mov    $0x0,%eax
  jmp    L22
L45:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L36
  mov    $0x0,%eax
  jmp    L22
L36:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L22:
  leave
  ret
```

assistant: ```c
int starts_with(const char *str, const char *prefix) {
  if (!str || !prefix)
    return 0;
  size_t lenstr = strlen(str);
  size_t lenprefix = strlen(prefix);
  if (lenprefix > lenstr)
    return 0;
  return strncmp(str, prefix, lenprefix) == 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<starts_with>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L1
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jae    L9
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L25
L1:
  mov    $0x0,%eax
  jmp    L25
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int starts_with(const char *str, const char *prefix) {
  if (!str || !prefix)
    return 0;
  size_t lenstr = strlen(str);
  size_t lenprefix = strlen(prefix);
  if (lenprefix > lenstr)
    return 0;
  return strncmp(str, prefix, lenprefix) == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<starts_with>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%rbx
  jae    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int starts_with(const char *str, const char *prefix) {
  if (!str || !prefix)
    return 0;
  size_t lenstr = strlen(str);
  size_t lenprefix = strlen(prefix);
  if (lenprefix > lenstr)
    return 0;
  return strncmp(str, prefix, lenprefix) == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<starts_with>:
  endbr64
  test   %rdi,%rdi
  je     L20
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%rbx
  jae    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L18:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int starts_with(const char *str, const char *prefix) {
  if (!str || !prefix)
    return 0;
  size_t lenstr = strlen(str);
  size_t lenprefix = strlen(prefix);
  if (lenprefix > lenstr)
    return 0;
  return strncmp(str, prefix, lenprefix) == 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<li_rand_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <li_rand_device_bytes@plt>
  cmp    $0x1,%eax
  jne    L11
  mov    $0x1,%eax
  jmp    L30
L11:
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L21:
  mov    $0x0,%eax
  call   <li_rand_pseudo_bytes@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
int li_rand_bytes(unsigned char *buf, int num) {
  if (1 == li_rand_device_bytes(buf, num)) {
    return 1;
  } else {
    for (int i = 0; i < num; ++i)
      buf[i] = li_rand_pseudo_bytes() & 0xFF;
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<li_rand_bytes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  call   <li_rand_device_bytes@plt>
  cmp    $0x1,%eax
  je     L32
  test   %ebp,%ebp
  jle    L35
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L24:
  mov    $0x0,%eax
  call   <li_rand_pseudo_bytes@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L24
  mov    $0x0,%eax
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%eax
  jmp    L32
```

assistant: ```c
int li_rand_bytes(unsigned char *buf, int num) {
  if (1 == li_rand_device_bytes(buf, num)) {
    return 1;
  } else {
    for (int i = 0; i < num; ++i)
      buf[i] = li_rand_pseudo_bytes() & 0xFF;
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<li_rand_bytes>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <li_rand_device_bytes@plt>
  cmp    $0x1,%eax
  je     L25
  test   %ebp,%ebp
  jle    L24
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   (%rax)
L9:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <li_rand_pseudo_bytes@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L9
L24:
  xor    %eax,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int li_rand_bytes(unsigned char *buf, int num) {
  if (1 == li_rand_device_bytes(buf, num)) {
    return 1;
  } else {
    for (int i = 0; i < num; ++i)
      buf[i] = li_rand_pseudo_bytes() & 0xFF;
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<li_rand_bytes>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <li_rand_device_bytes@plt>
  cmp    $0x1,%eax
  je     L2
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   (%rax)
L6:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <li_rand_pseudo_bytes@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L6
L15:
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int li_rand_bytes(unsigned char *buf, int num) {
  if (1 == li_rand_device_bytes(buf, num)) {
    return 1;
  } else {
    for (int i = 0; i < num; ++i)
      buf[i] = li_rand_pseudo_bytes() & 0xFF;
    return 0;
  }
}
```