ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<class_win_stats1>:
  endbr64
  cmp    $0x9,%edi
  ja     L88
  sub    $0x8,%rsp
  mov    %edi,%edi
  lea    D72(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D16(%rip),%rdi
  call   <printf@plt>
L17:
  add    $0x8,%rsp
  ret
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D98(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L88:
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D46
datatype: string
name: read_data
arguments: data_label: D86
datatype: string
name: read_data
arguments: data_label: D80
datatype: string
name: read_data
arguments: data_label: D47
datatype: string
name: read_data
arguments: data_label: D98
datatype: string
name: read_data
arguments: data_label: D39
datatype: string
name: read_data
arguments: data_label: D28
datatype: string
name: read_data
arguments: data_label: D54
datatype: string

tool: D16: : Druid               %3.d Runs     :


tool: D46: : Hunter              %3.d Runs     :


tool: D86: : Mage                %3.d Runs     :


tool: D80: : Paladin             %3.d Runs     :


tool: D47: : Priest              %3.d Runs     :


tool: D98: : Rogue               %3.d Runs     :


tool: D39: : Shaman              %3.d Runs     :


tool: D28: : Warlock             %3.d Runs     :


tool: D54: : Warrior             %3.d Runs     :


assistant: ```c
void class_win_stats1(int class, int runs) {
  switch (class) {
  case 1:
    printf(": Druid               %3.d Runs     :\n", runs);
    break;
  case 2:
    printf(": Hunter              %3.d Runs     :\n", runs);
    break;
  case 3:
    printf(": Mage                %3.d Runs     :\n", runs);
    break;
  case 4:
    printf(": Paladin             %3.d Runs     :\n", runs);
    break;
  case 5:
    printf(": Priest              %3.d Runs     :\n", runs);
    break;
  case 6:
    printf(": Rogue               %3.d Runs     :\n", runs);
    break;
  case 7:
    printf(": Shaman              %3.d Runs     :\n", runs);
    break;
  case 8:
    printf(": Warlock             %3.d Runs     :\n", runs);
    break;
  case 9:
    printf(": Warrior             %3.d Runs     :\n", runs);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<class_win_stats1>:
  endbr64
  cmp    $0x9,%edi
  ja     L0
  lea    D0(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D96(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D57(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D77(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D70(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D58(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D16(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D24(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D48(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
L0:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D96
data_type: string
name: extract_symbolic_data
arguments: data_label: D57
data_type: string
name: extract_symbolic_data
arguments: data_label: D77
data_type: string
name: extract_symbolic_data
arguments: data_label: D70
data_type: string
name: extract_symbolic_data
arguments: data_label: D58
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string
name: extract_symbolic_data
arguments: data_label: D48
data_type: string
name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D96: : Warrior             %3.d Runs     :


tool: D57: : Druid               %3.d Runs     :


tool: D77: : Hunter              %3.d Runs     :


tool: D70: : Mage                %3.d Runs     :


tool: D58: : Paladin             %3.d Runs     :


tool: D16: : Priest              %3.d Runs     :


tool: D24: : Rogue               %3.d Runs     :


tool: D48: : Shaman              %3.d Runs     :


tool: D7: : Warlock             %3.d Runs     :


assistant: ```c
void class_win_stats1(int class, int runs) {
  switch (class) {
  case 1:
    printf(": Druid               %3.d Runs     :\n", runs);
    break;
  case 2:
    printf(": Hunter              %3.d Runs     :\n", runs);
    break;
  case 3:
    printf(": Mage                %3.d Runs     :\n", runs);
    break;
  case 4:
    printf(": Paladin             %3.d Runs     :\n", runs);
    break;
  case 5:
    printf(": Priest              %3.d Runs     :\n", runs);
    break;
  case 6:
    printf(": Rogue               %3.d Runs     :\n", runs);
    break;
  case 7:
    printf(": Shaman              %3.d Runs     :\n", runs);
    break;
  case 8:
    printf(": Warlock             %3.d Runs     :\n", runs);
    break;
  case 9:
    printf(": Warrior             %3.d Runs     :\n", runs);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<class_win_stats1>:
  endbr64
  cmp    $0x9,%edi
  ja     L0
  lea    D1(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D76(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D71(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D43(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D38(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D59(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D26(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D85(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D62(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
L0:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D76
type_infered: string
name: parse_data
arguments: data_tag: D71
type_infered: string
name: parse_data
arguments: data_tag: D43
type_infered: string
name: parse_data
arguments: data_tag: D38
type_infered: string
name: parse_data
arguments: data_tag: D59
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D85
type_infered: string
name: parse_data
arguments: data_tag: D62
type_infered: string
name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D76: : Warrior             %3.d Runs     :


tool: D71: : Druid               %3.d Runs     :


tool: D43: : Hunter              %3.d Runs     :


tool: D38: : Mage                %3.d Runs     :


tool: D59: : Paladin             %3.d Runs     :


tool: D26: : Priest              %3.d Runs     :


tool: D85: : Rogue               %3.d Runs     :


tool: D62: : Shaman              %3.d Runs     :


tool: D3: : Warlock             %3.d Runs     :


assistant: ```c
void class_win_stats1(int class, int runs) {
  switch (class) {
  case 1:
    printf(": Druid               %3.d Runs     :\n", runs);
    break;
  case 2:
    printf(": Hunter              %3.d Runs     :\n", runs);
    break;
  case 3:
    printf(": Mage                %3.d Runs     :\n", runs);
    break;
  case 4:
    printf(": Paladin             %3.d Runs     :\n", runs);
    break;
  case 5:
    printf(": Priest              %3.d Runs     :\n", runs);
    break;
  case 6:
    printf(": Rogue               %3.d Runs     :\n", runs);
    break;
  case 7:
    printf(": Shaman              %3.d Runs     :\n", runs);
    break;
  case 8:
    printf(": Warlock             %3.d Runs     :\n", runs);
    break;
  case 9:
    printf(": Warrior             %3.d Runs     :\n", runs);
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<myqsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L11
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L44:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jns    L26
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L26:
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L44
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <myqsort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <myqsort>
  jmp    L24
L11:
  nop
L24:
  leave
  ret
```

assistant: ```c
void myqsort(char *v[], int left, int right, int (*comp)(char *a, char *b)) {
  int i, last;
  if (left >= right) {
    return;
  }
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if ((*comp)(v[i], v[left]) < 0) {
      swap(v, ++last, i);
    }
  }
  swap(v, left, last);
  myqsort(v, left, last - 1, comp);
  myqsort(v, last + 1, right, comp);
}
```
user: What is the c source code of the assembly code below:

```asm
<myqsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    %edx,%esi
  jl     L63
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  mov    %rdi,%rbp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %esi,%ebx
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %esi,%r14d
  call   <swap@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jl     L36
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,8),%r15
  movslq %ebx,%rbx
  jmp    L31
L41:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L7
L31:
  mov    %ebx,0x8(%rsp)
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    (%r15),%rsi
  call   *%r13
  test   %eax,%eax
  jns    L41
  add    $0x1,%r14d
  mov    0x8(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L41
L36:
  mov    0xc(%rsp),%r14d
L7:
  mov    %r14d,%edx
  mov    0xc(%rsp),%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13,%rcx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <myqsort>
  lea    0x1(%r14),%esi
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <myqsort>
  jmp    L68
```

assistant: ```c
void myqsort(char *v[], int left, int right, int (*comp)(char *a, char *b)) {
  int i, last;
  if (left >= right) {
    return;
  }
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if ((*comp)(v[i], v[left]) < 0) {
      swap(v, ++last, i);
    }
  }
  swap(v, left, last);
  myqsort(v, left, last - 1, comp);
  myqsort(v, last + 1, right, comp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<myqsort>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rcx,(%rsp)
L34:
  cmp    %r15d,%ebp
  jle    L44
L32:
  lea    0x0(%rbp,%r15,1),%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r15),%ecx
  cmp    %ecx,%ebp
  jl     L59
  movslq %r15d,%rax
  movslq %ecx,%r14
  mov    %r15d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L46
L27:
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L75
L46:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r14,8),%rdi
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L27
  add    $0x1,%r13d
  mov    %r14d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r14
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r14d,%ebp
  jge    L46
L75:
  mov    %r15d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    (%rsp),%rcx
  mov    %r15d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  lea    0x1(%r13),%r15d
  call   <myqsort>
  cmp    %ebp,%r15d
  jl     L32
L44:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  mov    %r15d,%edx
  mov    %r15d,%esi
  lea    -0x1(%r15),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L34
```

assistant: ```c
void myqsort(char *v[], int left, int right, int (*comp)(char *a, char *b)) {
  int i, last;
  if (left >= right) {
    return;
  }
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if ((*comp)(v[i], v[left]) < 0) {
      swap(v, ++last, i);
    }
  }
  swap(v, left, last);
  myqsort(v, left, last - 1, comp);
  myqsort(v, last + 1, right, comp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<myqsort>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rcx,(%rsp)
L26:
  cmp    %r15d,%ebp
  jle    L52
L46:
  lea    0x0(%rbp,%r15,1),%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r15),%ecx
  cmp    %ecx,%ebp
  jl     L32
  movslq %r15d,%rax
  movslq %ecx,%r14
  mov    %r15d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L49
L65:
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L77
L49:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r14,8),%rdi
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L65
  add    $0x1,%r13d
  mov    %r14d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r14
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r14d,%ebp
  jge    L49
L77:
  mov    %r15d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    (%rsp),%rcx
  mov    %r15d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  lea    0x1(%r13),%r15d
  call   <myqsort>
  cmp    %ebp,%r15d
  jl     L46
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r15d,%edx
  mov    %r15d,%esi
  lea    -0x1(%r15),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L26
```

assistant: ```c
void myqsort(char *v[], int left, int right, int (*comp)(char *a, char *b)) {
  int i, last;
  if (left >= right) {
    return;
  }
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++) {
    if ((*comp)(v[i], v[left]) < 0) {
      swap(v, ++last, i);
    }
  }
  swap(v, left, last);
  myqsort(v, left, last - 1, comp);
  myqsort(v, last + 1, right, comp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  lea    D75(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D66(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x38(%rbp),%edi
  mov    -0x3c(%rbp),%esi
  mov    -0x40(%rbp),%ecx
  mov    -0x44(%rbp),%edx
  mov    -0x48(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D75
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D66
type_guessed: string
name: extract_symbolic_data
arguments: tag: D76
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D75: abcabcbb

tool: D33: bbbbbb

tool: D27: pwwkew

tool: D25: dvdf

tool: D66: abba

tool: D76: %d, %d, %d, %d, %d.


tool: D1: abc'"#$5acefgh

tool: D14: %d.


assistant: ```c
int main(void) {
  char *a = "abcabcbb";
  char *b = "bbbbbb";
  char *c = "pwwkew";
  char *d = "dvdf";
  char *e = "abba";
  int ret1 = lengthOfLongestSubstring(a);
  int ret2 = lengthOfLongestSubstring(b);
  int ret3 = lengthOfLongestSubstring(c);
  int ret4 = lengthOfLongestSubstring(d);
  int ret5 = lengthOfLongestSubstring(e);
  printf("%d, %d, %d, %d, %d.\n", ret1, ret2, ret3, ret4, ret5);
  char *f = "abc'\"#$5acefgh";
  int ret6 = lengthOfLongestSubstring(f);
  printf("%d.\n", ret6);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%ebx
  lea    D21(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%ebp
  lea    D78(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%r12d
  lea    D59(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%r13d
  lea    D10(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D78
type_infered: string
name: unpack_data
arguments: label: D59
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D51
type_infered: string
name: unpack_data
arguments: label: D68
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D2: abcabcbb

tool: D21: bbbbbb

tool: D78: pwwkew

tool: D59: dvdf

tool: D10: abba

tool: D51: %d, %d, %d, %d, %d.


tool: D68: abc'"#$5acefgh

tool: D0: %d.


assistant: ```c
int main(void) {
  char *a = "abcabcbb";
  char *b = "bbbbbb";
  char *c = "pwwkew";
  char *d = "dvdf";
  char *e = "abba";
  int ret1 = lengthOfLongestSubstring(a);
  int ret2 = lengthOfLongestSubstring(b);
  int ret3 = lengthOfLongestSubstring(c);
  int ret4 = lengthOfLongestSubstring(d);
  int ret5 = lengthOfLongestSubstring(e);
  printf("%d, %d, %d, %d, %d.\n", ret1, ret2, ret3, ret4, ret5);
  char *f = "abc'\"#$5acefgh";
  int ret6 = lengthOfLongestSubstring(f);
  printf("%d.\n", ret6);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D73(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <lengthOfLongestSubstring@plt>
  lea    D65(%rip),%rdi
  mov    %eax,%ebp
  call   <lengthOfLongestSubstring@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%r12d
  call   <lengthOfLongestSubstring@plt>
  lea    D57(%rip),%rdi
  mov    %eax,%r13d
  call   <lengthOfLongestSubstring@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%ebx
  call   <lengthOfLongestSubstring@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%r9d
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  lea    D67(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D73
type: string
name: unpack_data
arguments: data_label: D65
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D57
type: string
name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D70
type: string
name: unpack_data
arguments: data_label: D67
type: string

tool: D73: abcabcbb

tool: D65: bbbbbb

tool: D6: pwwkew

tool: D57: dvdf

tool: D9: abba

tool: D20: %d, %d, %d, %d, %d.


tool: D70: abc'"#$5acefgh

tool: D67: %d.


assistant: ```c
int main(void) {
  char *a = "abcabcbb";
  char *b = "bbbbbb";
  char *c = "pwwkew";
  char *d = "dvdf";
  char *e = "abba";
  int ret1 = lengthOfLongestSubstring(a);
  int ret2 = lengthOfLongestSubstring(b);
  int ret3 = lengthOfLongestSubstring(c);
  int ret4 = lengthOfLongestSubstring(d);
  int ret5 = lengthOfLongestSubstring(e);
  printf("%d, %d, %d, %d, %d.\n", ret1, ret2, ret3, ret4, ret5);
  char *f = "abc'\"#$5acefgh";
  int ret6 = lengthOfLongestSubstring(f);
  printf("%d.\n", ret6);
  return 0;
}
```