ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  lea    D12(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L11
  nopl   0x0(%rax,%rax,1)
L81:
  mov    0x10(%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jg     L100
  jmp    L108
  nop
L71:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x10(%rsp),%eax
  cmp    %ebx,%eax
  jl     L108
  nopl   (%rax)
L100:
  cmp    %ebx,%eax
  je     L32
  cmp    $0x1,%ebx
  je     L32
  cmp    $0x1,%ebp
  je     L32
  cmp    %ebp,0x14(%rsp)
  jne    L71
L32:
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  cmp    %ebx,%eax
  jge    L100
L108:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x14(%rsp)
  jge    L81
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D18: %d %d %d

tool: D12: %d

assistant: ```c
int main() {
  int N, width, height;
  scanf("%d %d %d", &N, &width, &height);
  int i, j;
  for (i = 1; i <= height; i++) {
    for (j = 1; j <= width; j++) {
      if (j == width || j == 1 || i == 1 || i == height)
        printf("%d", N);
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strreqerr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D58(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x5,-0x44(%rbp)
  jbe    L18
  movl   $0x0,-0x44(%rbp)
L18:
  mov    -0x44(%rbp),%eax
  mov    -0x40(%rbp,%rax,8),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D58
type: string
name: extract_symbolic_data
arguments: data_label: D34
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string
name: extract_symbolic_data
arguments: data_label: D30
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D58: Unknown error

tool: D34: System error

tool: D40: Connection has failed

tool: D30: Connection timeout

tool: D29: Receive timeout

tool: D1: Send timeout

assistant: ```c
const char *strreqerr(unsigned int req_err) {
  const char *req_err_str[] = {
      "Unknown error", "System error", "Connection has failed", "Connection timeout", "Receive timeout", "Send timeout",
  };
  if (req_err >= (sizeof(req_err_str) / sizeof((req_err_str)[0]))) {
    req_err = 0;
  }
  return req_err_str[req_err];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strreqerr>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,(%rsp)
  lea    D38(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D32(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D50(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D21(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D46(%rip),%rax
  mov    %rax,0x28(%rsp)
  cmp    $0x6,%edi
  mov    $0x0,%eax
  cmovae %eax,%edi
  mov    %edi,%edi
  mov    (%rsp,%rdi,8),%rax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x48,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D38
datatype: string
name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D50
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string

tool: D4: Unknown error

tool: D38: System error

tool: D32: Connection has failed

tool: D50: Connection timeout

tool: D21: Receive timeout

tool: D46: Send timeout

assistant: ```c
const char *strreqerr(unsigned int req_err) {
  const char *req_err_str[] = {
      "Unknown error", "System error", "Connection has failed", "Connection timeout", "Receive timeout", "Send timeout",
  };
  if (req_err >= (sizeof(req_err_str) / sizeof((req_err_str)[0]))) {
    req_err = 0;
  }
  return req_err_str[req_err];
}
```
user: What is the c source code of the assembly code below:

```asm
<strreqerr>:
  endbr64
  sub    $0x48,%rsp
  lea    D36(%rip),%rcx
  lea    D45(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D26(%rip),%rax
  lea    D40(%rip),%rdx
  mov    %rcx,0x8(%rsp)
  lea    D38(%rip),%rcx
  mov    %rsi,0x10(%rsp)
  lea    D30(%rip),%rsi
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %rsi,0x28(%rsp)
  mov    %rax,(%rsp)
  cmp    $0x5,%edi
  ja     L4
  mov    %edi,%edi
  mov    (%rsp,%rdi,8),%rax
L4:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D45
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D40
type: string
name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D30
type: string

tool: D36: System error

tool: D45: Connection has failed

tool: D26: Unknown error

tool: D40: Connection timeout

tool: D38: Receive timeout

tool: D30: Send timeout

assistant: ```c
const char *strreqerr(unsigned int req_err) {
  const char *req_err_str[] = {
      "Unknown error", "System error", "Connection has failed", "Connection timeout", "Receive timeout", "Send timeout",
  };
  if (req_err >= (sizeof(req_err_str) / sizeof((req_err_str)[0]))) {
    req_err = 0;
  }
  return req_err_str[req_err];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strreqerr>:
  endbr64
  sub    $0x48,%rsp
  lea    D28(%rip),%rdx
  lea    D1(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D37(%rip),%rax
  movq   %rdx,%xmm1
  lea    D0(%rip),%rdx
  lea    D14(%rip),%rsi
  movq   %rdx,%xmm2
  lea    D33(%rip),%rdx
  movq   %rdx,%xmm3
  movq   %rax,%xmm0
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
  movq   %rsi,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
  cmp    $0x5,%edi
  ja     L10
  mov    %edi,%edi
  mov    (%rsp,%rdi,8),%rax
L10:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x48,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D37
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D33
data_type: string

tool: D28: System error

tool: D1: Connection has failed

tool: D37: Unknown error

tool: D0: Connection timeout

tool: D14: Receive timeout

tool: D33: Send timeout

assistant: ```c
const char *strreqerr(unsigned int req_err) {
  const char *req_err_str[] = {
      "Unknown error", "System error", "Connection has failed", "Connection timeout", "Receive timeout", "Send timeout",
  };
  if (req_err >= (sizeof(req_err_str) / sizeof((req_err_str)[0]))) {
    req_err = 0;
  }
  return req_err_str[req_err];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<homeDrive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L8:
  mov    $0x0,%eax
  call   <defaultDrive@plt>
  jmp    L25
L6:
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7: HOMEDRIVE

assistant: ```c
char *homeDrive(void) {
  char *s;
  return ((s = getenv("HOMEDRIVE")) && *s) ? s : defaultDrive();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<homeDrive>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L19
  cmpb   $0x0,(%rax)
  jne    L17
L19:
  mov    $0x0,%eax
  call   <defaultDrive@plt>
L17:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string

tool: D3: HOMEDRIVE

assistant: ```c
char *homeDrive(void) {
  char *s;
  return ((s = getenv("HOMEDRIVE")) && *s) ? s : defaultDrive();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<homeDrive>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  cmpb   $0x0,(%rax)
  jne    L3
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <defaultDrive@plt>
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: HOMEDRIVE

assistant: ```c
char *homeDrive(void) {
  char *s;
  return ((s = getenv("HOMEDRIVE")) && *s) ? s : defaultDrive();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<homeDrive>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L2
  cmpb   $0x0,(%rax)
  jne    L13
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <defaultDrive@plt>
  nopl   0x0(%rax)
L13:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: HOMEDRIVE

assistant: ```c
char *homeDrive(void) {
  char *s;
  return ((s = getenv("HOMEDRIVE")) && *s) ? s : defaultDrive();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dobulk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x3e8,-0x2c(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0x60(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <doioctl@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  js     L17
  mov    -0x34(%rbp),%eax
  jmp    L21
L17:
  mov    $0xffffffff,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  mov    %rcx,%rdx
  mov    %fs:0x28,%rcx
  mov    %rcx,0x28(%rsp)
  xor    %ecx,%ecx
  movq   $0x0,0x18(%rsp)
  mov    %edi,(%rsp)
  movl   $0x3e8,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <doioctl@plt>
  test   %eax,%eax
  mov    $0xffffffff,%edx
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movl   $0x4e729,-0xb0(%rbp)
  movl   $0x20,-0xac(%rbp)
  movl   $0x2b,-0xa8(%rbp)
  movl   $0x2b,-0xa4(%rbp)
  movl   $0x36,-0xa0(%rbp)
  movl   $0x41,-0x9c(%rbp)
  movl   $0x4c,-0x98(%rbp)
  movl   $0xc33,-0x94(%rbp)
  movl   $0x2b,-0x90(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x529,-0x80(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0xb0(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  lea    -0x60(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    $0x14,%ecx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <rank@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  lea    -0x60(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    $0x14,%ecx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <rearrange@plt>
  lea    -0xb0(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a[20] = {321321, 32, 43, 43, 54, 65, 76, 3123, 43, 1, 0, 0, 1321};
  int r[20] = {0};
  print_array(a, 20);
  rank(a, 20, r, 20);
  print_array(r, 20);
  rearrange(a, 20, r, 20);
  print_array(a, 20);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movl   $0x4e729,(%rsp)
  movl   $0x20,0x4(%rsp)
  movl   $0x2b,0x8(%rsp)
  movl   $0x2b,0xc(%rsp)
  movl   $0x36,0x10(%rsp)
  movl   $0x41,0x14(%rsp)
  movl   $0x4c,0x18(%rsp)
  movl   $0xc33,0x1c(%rsp)
  movl   $0x2b,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x529,0x30(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  mov    %rsp,%rbx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  lea    0x50(%rsp),%rbp
  mov    $0x14,%ecx
  mov    %rbp,%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <rank@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    $0x14,%ecx
  mov    %rbp,%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <rearrange@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[20] = {321321, 32, 43, 43, 54, 65, 76, 3123, 43, 1, 0, 0, 1321};
  int r[20] = {0};
  print_array(a, 20);
  rank(a, 20, r, 20);
  print_array(r, 20);
  rearrange(a, 20, r, 20);
  print_array(a, 20);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x14,%esi
  push   %rbp
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  movabs $0x200004e729,%rax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%r12
  movaps %xmm0,0x50(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    %rax,(%rsp)
  movabs $0x2b0000002b,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x4100000036,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xc330000004c,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x10000002b,%rax
  mov    %rax,0x20(%rsp)
  movq   $0x529,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  call   <print_array@plt>
  mov    $0x14,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <rank@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <print_array@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    $0x14,%ecx
  call   <rearrange@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a[20] = {321321, 32, 43, 43, 54, 65, 76, 3123, 43, 1, 0, 0, 1321};
  int r[20] = {0};
  print_array(a, 20);
  rank(a, 20, r, 20);
  print_array(r, 20);
  rearrange(a, 20, r, 20);
  print_array(a, 20);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x14,%esi
  push   %rbp
  sub    $0xb8,%rsp
  movdqa D22(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x50(%rsp),%r12
  movups %xmm0,0x28(%rsp)
  mov    D26(%rip),%rax
  movaps %xmm1,(%rsp)
  mov    %rbp,%rdi
  movdqa D28(%rip),%xmm1
  movups %xmm0,0x38(%rsp)
  movaps %xmm1,0x10(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movq   $0x0,0x48(%rsp)
  mov    %rax,0x20(%rsp)
  movl   $0x529,0x30(%rsp)
  call   <print_array@plt>
  mov    $0x14,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <rank@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <print_array@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    $0x14,%ecx
  call   <rearrange@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_infered: byte[16]
name: retrieve_data
arguments: tag: D26
type_infered: byte[8]
name: retrieve_data
arguments: tag: D28
type_infered: byte[16]

tool: {"D22": [0x29,0xe7,0x04,0x00,0x20,0x00,0x00,0x00,0x2b,0x00,0x00,0x00,0x2b,0x00,0x00,0x00]}

tool: {"D26": [0x2b,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D28": [0x36,0x00,0x00,0x00,0x41,0x00,0x00,0x00,0x4c,0x00,0x00,0x00,0x33,0x0c,0x00,0x00]}

assistant: ```c
int main(void) {
  int a[20] = {321321, 32, 43, 43, 54, 65, 76, 3123, 43, 1, 0, 0, 1321};
  int r[20] = {0};
  print_array(a, 20);
  rank(a, 20, r, 20);
  print_array(r, 20);
  rearrange(a, 20, r, 20);
  print_array(a, 20);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transform44f3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movss  0x4(%rax),%xmm3
  mov    -0x10(%rbp),%rax
  movss  0x8(%rax),%xmm4
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm4,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movss  (%rax),%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm0
  mulss  %xmm4,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm2
  movaps %xmm2,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  movss  (%rax),%xmm0
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movss  (%rax),%xmm0
  mulss  %xmm4,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transform44f3f(float *m1, float *m2, float *m3) {
  register float m2r0 = m2[0];
  register float m2r1 = m2[1];
  register float m2r2 = m2[2];
  m3[0] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2 + m1[3];
  m3[1] = m1[4] * m2r0 + m1[5] * m2r1 + m1[6] * m2r2 + m1[7];
  m3[2] = m1[8] * m2r0 + m1[9] * m2r1 + m1[10] * m2r2 + m1[11];
}
```