ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<cum_normal>:
  endbr64
  pxor   %xmm5,%xmm5
  comisd %xmm2,%xmm5
  jae    L11
  subsd  %xmm1,%xmm0
  sub    $0x18,%rsp
  movsd  D118(%rip),%xmm6
  movapd %xmm6,%xmm1
  movapd %xmm0,%xmm3
  divsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm2
  xorpd  D48(%rip),%xmm2
  movsd  %xmm3,0x8(%rsp)
  cmpltsd %xmm5,%xmm0
  andpd  %xmm0,%xmm2
  andnpd %xmm3,%xmm0
  orpd   %xmm0,%xmm2
  movsd  D27(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm6,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D90(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm1,(%rsp)
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  movsd  D9(%rip),%xmm2
  pxor   %xmm5,%xmm5
  movsd  D3(%rip),%xmm4
  mulsd  D88(%rip),%xmm0
  mulsd  %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm3
  mov    D118(%rip),%rax
  mulsd  %xmm1,%xmm4
  comisd %xmm3,%xmm5
  movq   %rax,%xmm6
  mulsd  %xmm1,%xmm2
  addsd  %xmm4,%xmm2
  movsd  D8(%rip),%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm2
  movsd  D93(%rip),%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  addsd  %xmm4,%xmm2
  movsd  D108(%rip),%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movq   %rax,%xmm0
  subsd  %xmm1,%xmm0
  ja     L18
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  subsd  %xmm0,%xmm6
  add    $0x18,%rsp
  movapd %xmm6,%xmm0
  ret
  nopl   (%rax)
L11:
  movsd  D103(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D118
type_infered: f64
name: read_data
arguments: tag: D48
type_infered: f32[4]
name: read_data
arguments: tag: D27
type_infered: byte[8]
name: read_data
arguments: tag: D90
type_infered: f32[2]
name: read_data
arguments: tag: D9
type_infered: byte[8]
name: read_data
arguments: tag: D3
type_infered: f64
name: read_data
arguments: tag: D88
type_infered: f64
name: read_data
arguments: tag: D8
type_infered: f64
name: read_data
arguments: tag: D93
type_infered: byte[8]
name: read_data
arguments: tag: D108
type_infered: f64
name: read_data
arguments: tag: D103
type_infered: f32[2]

tool: D118: 1

tool: {"D48": [0.0,-0.0,0.0,0.0]}

tool: {"D27": [0x0e,0x10,0x71,0x18,0x71,0xa6,0xcd,0x3f]}

tool: {"D90": [0.0,-1.75]}

tool: {"D9": [0x5b,0x32,0xa8,0xe5,0xf0,0xd1,0xd6,0xbf]}

tool: D3: 0.31938153

tool: D88: 0.39894228040143

tool: D8: 1.781477937

tool: {"D93": [0xd0,0x78,0xf2,0x4e,0xdd,0x23,0xfd,0xbf]}

tool: D108: 1.330274429

tool: {"D103": [0.0,-1.875]}

assistant: ```c
double cum_normal(double sample, double mean, double stddev) {
  double a, b, c, d, e, f, g, h, temp;
  a = 0.319381530;
  b = -0.356563782;
  c = 1.781477937;
  d = -1.821255978;
  e = 1.330274429;
  f = .2316419;
  if (stddev <= 0.0)
    return -1.0;
  sample = (sample - mean) / stddev;
  if (sample < 0.0)
    temp = -sample;
  else
    temp = sample;
  g = 1.0 / (1.0 + f * temp);
  h = 1.0 - (0.39894228040143 * exp(-0.5 * temp * temp)) * (a * g + b * g * g + c * g * g * g + d * g * g * g * g + e * g * g * g * g * g);
  if (sample < 0.0)
    h = 1.0 - h;
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x32,%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: coucou


assistant: ```c
int main() {
  char *f;
  f = malloc(400);
  free(f + 50);
  printf("coucou\n");
  free(f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x32(%rax),%rdi
  call   <free@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: coucou


assistant: ```c
int main() {
  char *f;
  f = malloc(400);
  free(f + 50);
  printf("coucou\n");
  free(f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x190,%edi
  call   <malloc@plt>
  lea    0x32(%rax),%rdi
  mov    %rax,%rbp
  call   <free@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: coucou


assistant: ```c
int main() {
  char *f;
  f = malloc(400);
  free(f + 50);
  printf("coucou\n");
  free(f);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x190,%edi
  call   <malloc@plt>
  lea    0x32(%rax),%rdi
  mov    %rax,%rbp
  call   <free@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: coucou


assistant: ```c
int main() {
  char *f;
  f = malloc(400);
  free(f + 50);
  printf("coucou\n");
  free(f);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<us_resp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <c_malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L2
L33:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L2
  mov    -0x30(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <c_realloc@plt>
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x11(%rbp)
  mov    D8(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x11(%rbp)
  je     L7
  cmpb   $0xa,-0x11(%rbp)
  jne    L33
L7:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L17
L8:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <c_realloc@plt>
L17:
  leave
  ret
```

assistant: ```c
char *us_resp(FILE *stream, int min, int chunk) {
  char ch;
  int lenght = 0, size = min;
  char *result = c_malloc(size * sizeof(char));
  while ((ch = fgetc(stream)) != EOF && ch != '\n') {
    result[lenght++] = ch;
    if (lenght == size)
      result = c_realloc(result, (size += chunk) * sizeof(char));
  }
  result[lenght++] = '\0';
  if (strlen(result) == 0) {
    free(result);
    return NULL;
  }
  return c_realloc(result, lenght * sizeof(char));
}
```
user: Translate the below assembly code into C programming language:

```asm
<us_resp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%r13d
  mov    %edx,0xc(%rsp)
  mov    %esi,%edi
  call   <c_malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  jmp    L0
L23:
  add    $0x1,%rbx
L0:
  mov    %ebx,%ebp
  mov    %ebx,%r14d
  mov    %r15,%rdi
  call   <fgetc@plt>
  mov    D0(%rip),%rdx
  cmp    %al,(%rdx)
  je     L40
  cmp    $0xa,%al
  je     L40
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L23
  add    0xc(%rsp),%r13d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <c_realloc@plt>
  mov    %rax,%r12
  jmp    L23
L40:
  lea    0x1(%r14),%esi
  movslq %r14d,%r14
  movb   $0x0,(%r12,%r14,1)
  cmpb   $0x0,(%r12)
  je     L37
  mov    %r12,%rdi
  call   <c_realloc@plt>
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L18
```

assistant: ```c
char *us_resp(FILE *stream, int min, int chunk) {
  char ch;
  int lenght = 0, size = min;
  char *result = c_malloc(size * sizeof(char));
  while ((ch = fgetc(stream)) != EOF && ch != '\n') {
    result[lenght++] = ch;
    if (lenght == size)
      result = c_realloc(result, (size += chunk) * sizeof(char));
  }
  result[lenght++] = '\0';
  if (strlen(result) == 0) {
    free(result);
    return NULL;
  }
  return c_realloc(result, lenght * sizeof(char));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<us_resp>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <c_malloc@plt>
  mov    D9(%rip),%r13
  mov    %rax,%rbp
  jmp    L2
L49:
  add    $0x1,%r15
L2:
  mov    %r12,%rdi
  call   <fgetc@plt>
  lea    0x0(%rbp,%r15,1),%rdx
  lea    0x1(%r15),%esi
  cmp    %al,0x0(%r13)
  je     L46
  cmp    $0xa,%al
  je     L46
  mov    %al,(%rdx)
  cmp    %esi,%ebx
  jne    L49
  add    %r14d,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%esi
  call   <c_realloc@plt>
  mov    %rax,%rbp
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L46:
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  mov    %rbp,%rdi
  je     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <c_realloc@plt>
  nop
L9:
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *us_resp(FILE *stream, int min, int chunk) {
  char ch;
  int lenght = 0, size = min;
  char *result = c_malloc(size * sizeof(char));
  while ((ch = fgetc(stream)) != EOF && ch != '\n') {
    result[lenght++] = ch;
    if (lenght == size)
      result = c_realloc(result, (size += chunk) * sizeof(char));
  }
  result[lenght++] = '\0';
  if (strlen(result) == 0) {
    free(result);
    return NULL;
  }
  return c_realloc(result, lenght * sizeof(char));
}
```
user: What is the c source code of the assembly code below?

```asm
<us_resp>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <c_malloc@plt>
  mov    D5(%rip),%r13
  mov    %rax,%rbp
  jmp    L21
L54:
  add    $0x1,%r15
L21:
  mov    %r12,%rdi
  call   <fgetc@plt>
  lea    0x0(%rbp,%r15,1),%rdx
  lea    0x1(%r15),%esi
  cmp    %al,0x0(%r13)
  je     L7
  cmp    $0xa,%al
  je     L7
  mov    %al,(%rdx)
  cmp    %ebx,%esi
  jne    L54
  add    %r14d,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%esi
  call   <c_realloc@plt>
  mov    %rax,%rbp
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L7:
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  mov    %rbp,%rdi
  je     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <c_realloc@plt>
  nop
L9:
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *us_resp(FILE *stream, int min, int chunk) {
  char ch;
  int lenght = 0, size = min;
  char *result = c_malloc(size * sizeof(char));
  while ((ch = fgetc(stream)) != EOF && ch != '\n') {
    result[lenght++] = ch;
    if (lenght == size)
      result = c_realloc(result, (size += chunk) * sizeof(char));
  }
  result[lenght++] = '\0';
  if (strlen(result) == 0) {
    free(result);
    return NULL;
  }
  return c_realloc(result, lenght * sizeof(char));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<EE_WaitIdle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L46
L10:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1004,%esi
  mov    %rax,%rdi
  call   <PEX_8111Read@plt>
  mov    -0x10(%rbp),%eax
  and    $0x80000,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x10(%rbp),%eax
  jmp    L16
L17:
  addl   $0x1,-0xc(%rbp)
L46:
  cmpl   $0x3e7,-0xc(%rbp)
  jle    L10
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x80000,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: ERROR: EEPROM Busy timeout!


assistant: ```c
int EE_WaitIdle(void *info) {
  int eeCtl, ii;
  for (ii = 0; ii < 1000; ii++) {
    PEX_8111Read(info, 0x1004, &eeCtl);
    if ((eeCtl & (1 << 19)) == 0)
      return (eeCtl);
  }
  printf("ERROR: EEPROM Busy timeout!\n");
  return (1 << 19);
}
```
user: Translate the below assembly code into C programming language:

```asm
<EE_WaitIdle>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3e8,%ebx
  lea    0x4(%rsp),%r12
L21:
  mov    %r12,%rdx
  mov    $0x1004,%esi
  mov    %rbp,%rdi
  call   <PEX_8111Read@plt>
  mov    0x4(%rsp),%eax
  test   $0x80000,%eax
  je     L13
  sub    $0x1,%ebx
  jne    L21
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x80000,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: ERROR: EEPROM Busy timeout!


assistant: ```c
int EE_WaitIdle(void *info) {
  int eeCtl, ii;
  for (ii = 0; ii < 1000; ii++) {
    PEX_8111Read(info, 0x1004, &eeCtl);
    if ((eeCtl & (1 << 19)) == 0)
      return (eeCtl);
  }
  printf("ERROR: EEPROM Busy timeout!\n");
  return (1 << 19);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EE_WaitIdle>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L46:
  sub    $0x1,%ebx
  je     L28
L19:
  mov    %r12,%rdx
  mov    $0x1004,%esi
  mov    %rbp,%rdi
  call   <PEX_8111Read@plt>
  mov    0x4(%rsp),%eax
  test   $0x80000,%eax
  jne    L46
L42:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x80000,%eax
  jmp    L42
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: ERROR: EEPROM Busy timeout!


assistant: ```c
int EE_WaitIdle(void *info) {
  int eeCtl, ii;
  for (ii = 0; ii < 1000; ii++) {
    PEX_8111Read(info, 0x1004, &eeCtl);
    if ((eeCtl & (1 << 19)) == 0)
      return (eeCtl);
  }
  printf("ERROR: EEPROM Busy timeout!\n");
  return (1 << 19);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EE_WaitIdle>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L12:
  sub    $0x1,%ebx
  je     L22
L6:
  mov    %r12,%rdx
  mov    $0x1004,%esi
  mov    %rbp,%rdi
  call   <PEX_8111Read@plt>
  mov    0x4(%rsp),%eax
  test   $0x80000,%eax
  jne    L12
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x80000,%eax
  jmp    L44
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: ERROR: EEPROM Busy timeout!


assistant: ```c
int EE_WaitIdle(void *info) {
  int eeCtl, ii;
  for (ii = 0; ii < 1000; ii++) {
    PEX_8111Read(info, 0x1004, &eeCtl);
    if ((eeCtl & (1 << 19)) == 0)
      return (eeCtl);
  }
  printf("ERROR: EEPROM Busy timeout!\n");
  return (1 << 19);
}
```
user: What is the c source code of the assembly code below:

```asm
<xh_str_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L12:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int xh_str_hash(const void *key, void *data) {
  const char *str = *(const char **)key;
  int hash = 0;
  (void)data;
  while (*str) {
    hash = hash * 31 + *str++;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xh_str_hash>:
  endbr64
  mov    (%rdi),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L15
  mov    $0x0,%esi
L10:
  mov    %esi,%edx
  shl    $0x5,%edx
  sub    %esi,%edx
  add    $0x1,%rcx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%esi
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L10
L25:
  mov    %esi,%eax
  ret
L15:
  mov    $0x0,%esi
  jmp    L25
```

assistant: ```c
int xh_str_hash(const void *key, void *data) {
  const char *str = *(const char **)key;
  int hash = 0;
  (void)data;
  while (*str) {
    hash = hash * 31 + *str++;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xh_str_hash>:
  endbr64
  mov    (%rdi),%rcx
  xor    %r8d,%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  je     L13
  nopl   0x0(%rax)
L6:
  mov    %r8d,%edx
  add    $0x1,%rcx
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  jne    L6
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int xh_str_hash(const void *key, void *data) {
  const char *str = *(const char **)key;
  int hash = 0;
  (void)data;
  while (*str) {
    hash = hash * 31 + *str++;
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xh_str_hash>:
  endbr64
  mov    (%rdi),%rcx
  xor    %r8d,%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  je     L1
  nopl   0x0(%rax)
L7:
  mov    %r8d,%edx
  add    $0x1,%rcx
  shl    $0x5,%edx
  sub    %r8d,%edx
  lea    (%rax,%rdx,1),%r8d
  movsbl (%rcx),%eax
  test   %al,%al
  jne    L7
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int xh_str_hash(const void *key, void *data) {
  const char *str = *(const char **)key;
  int hash = 0;
  (void)data;
  while (*str) {
    hash = hash * 31 + *str++;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D13(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  endbr64
  cmpl   $0xa,-0x14(%rbp)
  je     L75
  jmp    L58
L64:
  jmp    *%rax
L75:
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
L58:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L64
  endbr64
  cmpl   $0x37,-0x10(%rbp)
  je     L61
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L63
L61:
  cmpl   $0x0,-0xc(%rbp)
  jg     L50
  mov    $0x0,%eax
  jmp    L63
L50:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x75(%rip),%rax        # 1145 <main+0x2c>
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L64
L63:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: 

tool: 

tool: D3: Bad result: %d


assistant: ```c
int main() {
  void *nextstate = &&Loop;
  int x = 0;
  int acc = 0;
  int count = 5;
Loop:
  if (x == 10)
    nextstate = &&Done;
  acc += x;
  x++;
  goto *nextstate;
Done:
  if (acc != 11 * 10 / 2) {
    printf("Bad result: %d\n", acc);
    return 1;
  }
  if (count <= 0)
    return 0;
  acc = 0;
  x = 0;
  nextstate = &&Loop;
  count--;
  goto *nextstate;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  mov    $0x0,%esi
  mov    $0x0,%edi
  lea    D11(%rip),%r8
  mov    %r8,%rcx
  lea    D20(%rip),%r9
L19:
  add    %edi,%esi
  add    $0x1,%edi
  mov    %r8,%rdx
  jmp    L26
  endbr64
  cmp    $0xa,%edi
  cmove  %r9,%r8
  jmp    L19
  endbr64
  cmp    $0x37,%esi
  jne    L21
  test   %eax,%eax
  jle    L20
  sub    $0x1,%eax
  mov    %rcx,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    %rcx,%r8
L26:
  jmp    *%rdx
L21:
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L20:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string

tool: 

tool: 

tool: D14: Bad result: %d


assistant: ```c
int main() {
  void *nextstate = &&Loop;
  int x = 0;
  int acc = 0;
  int count = 5;
Loop:
  if (x == 10)
    nextstate = &&Done;
  acc += x;
  x++;
  goto *nextstate;
Done:
  if (acc != 11 * 10 / 2) {
    printf("Bad result: %d\n", acc);
    return 1;
  }
  if (count <= 0)
    return 0;
  acc = 0;
  x = 0;
  nextstate = &&Loop;
  count--;
  goto *nextstate;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  lea    D5(%rip),%rcx
  mov    $0x5,%eax
  add    %edx,%esi
  lea    D30(%rip),%rdi
  add    $0x1,%edx
  jmp    *%rcx
  nopw   0x0(%rax,%rax,1)
  endbr64
  cmp    $0x37,%esi
  jne    L1
  test   %eax,%eax
  jle    L17
  sub    $0x1,%eax
  xor    %esi,%esi
  lea    D5(%rip),%rcx
  xor    %edx,%edx
  endbr64
  cmp    $0xa,%edx
  cmove  %rdi,%rcx
  add    %edx,%esi
  add    $0x1,%edx
  jmp    *%rcx
L1:
  push   %rax
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rdx
  ret
L17:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D30
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string

tool: 

tool: 

tool: D15: Bad result: %d


assistant: ```c
int main() {
  void *nextstate = &&Loop;
  int x = 0;
  int acc = 0;
  int count = 5;
Loop:
  if (x == 10)
    nextstate = &&Done;
  acc += x;
  x++;
  goto *nextstate;
Done:
  if (acc != 11 * 10 / 2) {
    printf("Bad result: %d\n", acc);
    return 1;
  }
  if (count <= 0)
    return 0;
  acc = 0;
  x = 0;
  nextstate = &&Loop;
  count--;
  goto *nextstate;
}
```