ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4e3000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0x920,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4e3910(%rbp),%rdx
  lea    -0x4e2010(%rbp),%rcx
  lea    -0x4e3918(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <le_entrada@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4e3918(%rbp),%eax
  lea    -0x4e3910(%rbp),%rdx
  lea    -0x4e2010(%rbp),%rsi
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <testa_cholesky@plt>
  mov    %eax,-0x4e3914(%rbp)
  cmpl   $0xffffffff,-0x4e3914(%rbp)
  jne    L3
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string

tool: D15: CHOL row:


tool: D18: A equacao nao pode ser resolvida.


assistant: ```c
int main() {
  int n;
  double A[800][800];
  double b[800];
  int p[800];
  int ret;
  le_entrada(&n, A, b);
  printf("CHOL row:\n");
  ret = testa_cholesky(n, A, b, 0, 0, 1);
  if (ret == -1) {
    printf("A equacao nao pode ser resolvida.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4e3000(%rsp),%r11
L25:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L25
  sub    $0x928,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e3918(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x1910(%rsp),%rbx
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <le_entrada@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <testa_cholesky@plt>
  cmp    $0xffffffff,%eax
  je     L7
L3:
  mov    0x4e3918(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x4e3928,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D0: CHOL row:


tool: D12: A equacao nao pode ser resolvida.


assistant: ```c
int main() {
  int n;
  double A[800][800];
  double b[800];
  int p[800];
  int ret;
  le_entrada(&n, A, b);
  printf("CHOL row:\n");
  ret = testa_cholesky(n, A, b, 0, 0, 1);
  if (ret == -1) {
    printf("A equacao nao pode ser resolvida.\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4e3000(%rsp),%r11
L20:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L20
  sub    $0x928,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e3918(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x1910(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    0xc(%rsp),%rdi
  call   <le_entrada@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%r9d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <testa_cholesky@plt>
  cmp    $0xffffffff,%eax
  je     L37
L8:
  mov    0x4e3918(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x4e3928,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L37:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D12
type_infered: string

tool: D13: CHOL row:


tool: D12: A equacao nao pode ser resolvida.


assistant: ```c
int main() {
  int n;
  double A[800][800];
  double b[800];
  int p[800];
  int ret;
  le_entrada(&n, A, b);
  printf("CHOL row:\n");
  ret = testa_cholesky(n, A, b, 0, 0, 1);
  if (ret == -1) {
    printf("A equacao nao pode ser resolvida.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4e3000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x928,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e3918(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x1910(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    0xc(%rsp),%rdi
  call   <le_entrada@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%r9d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <testa_cholesky@plt>
  cmp    $0xffffffff,%eax
  je     L5
L12:
  mov    0x4e3918(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x4e3928,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
data_type: string
name: parse_data
arguments: label: D5
data_type: string

tool: D14: CHOL row:


tool: D5: A equacao nao pode ser resolvida.


assistant: ```c
int main() {
  int n;
  double A[800][800];
  double b[800];
  int p[800];
  int ret;
  le_entrada(&n, A, b);
  printf("CHOL row:\n");
  ret = testa_cholesky(n, A, b, 0, 0, 1);
  if (ret == -1) {
    printf("A equacao nao pode ser resolvida.\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Construct@plt>
  mov    $0x0,%eax
  call   <BFS1@plt>
  mov    $0x0,%eax
  call   <BFS2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  Construct();
  BFS1();
  BFS2();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Construct@plt>
  mov    $0x0,%eax
  call   <BFS1@plt>
  mov    $0x0,%eax
  call   <BFS2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Construct();
  BFS1();
  BFS2();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Construct@plt>
  xor    %eax,%eax
  call   <BFS1@plt>
  xor    %eax,%eax
  call   <BFS2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Construct();
  BFS1();
  BFS2();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Construct@plt>
  xor    %eax,%eax
  call   <BFS1@plt>
  xor    %eax,%eax
  call   <BFS2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Construct();
  BFS1();
  BFS2();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imu_waitByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L4:
  lea    -0x9(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L4
  movzbl -0x9(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
unsigned char imu_waitByte(int fd) {
  unsigned char rxb[1];
  while (read(fd, rxb, 1) != 1)
    ;
  return rxb[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imu_waitByte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
L13:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L13
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char imu_waitByte(int fd) {
  unsigned char rxb[1];
  while (read(fd, rxb, 1) != 1)
    ;
  return rxb[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imu_waitByte>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax)
L8:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L8
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char imu_waitByte(int fd) {
  unsigned char rxb[1];
  while (read(fd, rxb, 1) != 1)
    ;
  return rxb[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imu_waitByte>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  nopl   0x0(%rax)
L0:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L0
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char imu_waitByte(int fd) {
  unsigned char rxb[1];
  while (read(fd, rxb, 1) != 1)
    ;
  return rxb[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<monitor_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <monitor_put@plt>
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void monitor_write(char *c) {
  int counter = 0;
  while (c[counter]) {
    monitor_put(c[counter++]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<monitor_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  push   %rbx
  lea    0x1(%rdi),%rbx
L18:
  movsbl %al,%edi
  call   <monitor_put@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L18
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void monitor_write(char *c) {
  int counter = 0;
  while (c[counter]) {
    monitor_put(c[counter++]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<monitor_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  push   %rbx
  lea    0x1(%rdi),%rbx
L2:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <monitor_put@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L2
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void monitor_write(char *c) {
  int counter = 0;
  while (c[counter]) {
    monitor_put(c[counter++]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<monitor_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  push   %rbx
  lea    0x1(%rdi),%rbx
L1:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <monitor_put@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L1
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void monitor_write(char *c) {
  int counter = 0;
  while (c[counter]) {
    monitor_put(c[counter++]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fmt_convert_s24_to_s32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L17:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  shl    $0x8,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fmt_convert_s24_to_s32(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] << 8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmt_convert_s24_to_s32>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  mov    (%rsi,%rax,4),%ecx
  shl    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L0:
  ret
```

assistant: ```c
void fmt_convert_s24_to_s32(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] << 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fmt_convert_s24_to_s32>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  mov    (%rsi,%rax,4),%ecx
  shl    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L8
L10:
  ret
```

assistant: ```c
void fmt_convert_s24_to_s32(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] << 8);
}
```
user: What is the c source code of the assembly code below?

```asm
<fmt_convert_s24_to_s32>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L34
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L41
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L41
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L21:
  movdqu (%rsi,%rax,1),%xmm0
  pslld  $0x8,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L21
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L34
  mov    %eax,%r8d
  mov    (%rsi,%r8,4),%r9d
  lea    0x0(,%r8,4),%rdi
  shl    $0x8,%r9d
  mov    %r9d,(%rcx,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edx
  jle    L34
  mov    0x4(%rsi,%rdi,1),%r8d
  add    $0x2,%eax
  shl    $0x8,%r8d
  mov    %r8d,0x4(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L34
  mov    0x8(%rsi,%rdi,1),%eax
  shl    $0x8,%eax
  mov    %eax,0x8(%rcx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L77:
  mov    (%rsi,%rax,4),%edi
  shl    $0x8,%edi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L77
L34:
  ret
```

assistant: ```c
void fmt_convert_s24_to_s32(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] << 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<listen_unix_stream_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <listen@plt>
  test   %rax,%rax
  jns    L18
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L19
L18:
  mov    $0x1,%eax
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: Error - listen_unix_stream_socket() - listen::

assistant: ```c
bool listen_unix_stream_socket(int sock, int cnt) {
  if (listen(sock, cnt) < 0) {
    perror("Error - listen_unix_stream_socket() - listen::");
    return false;
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<listen_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <listen@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  js     L6
L11:
  add    $0x8,%rsp
  ret
L6:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: Error - listen_unix_stream_socket() - listen::

assistant: ```c
bool listen_unix_stream_socket(int sock, int cnt) {
  if (listen(sock, cnt) < 0) {
    perror("Error - listen_unix_stream_socket() - listen::");
    return false;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<listen_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <listen@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L5
  add    $0x8,%rsp
  ret
  nop
L5:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: Error - listen_unix_stream_socket() - listen::

assistant: ```c
bool listen_unix_stream_socket(int sock, int cnt) {
  if (listen(sock, cnt) < 0) {
    perror("Error - listen_unix_stream_socket() - listen::");
    return false;
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<listen_unix_stream_socket>:
  endbr64
  sub    $0x8,%rsp
  call   <listen@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L3
  add    $0x8,%rsp
  ret
  nop
L3:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: Error - listen_unix_stream_socket() - listen::

assistant: ```c
bool listen_unix_stream_socket(int sock, int cnt) {
  if (listen(sock, cnt) < 0) {
    perror("Error - listen_unix_stream_socket() - listen::");
    return false;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<canny>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %r9,0x8(%rsp)
  mov    (%rsi),%edi
  imul   (%rdx),%edi
  imul   (%rcx),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%r8
  movsd  (%r15),%xmm0
  mov    0x0(%r13),%ecx
  mov    0x0(%rbp),%edx
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <canny_aux@plt>
  sub    $0x8,%rsp
  mov    0x0(%r13),%eax
  push   %rax
  mov    0x0(%rbp),%r9d
  mov    (%rbx),%r8d
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    0x18(%rsp),%rax
  mov    (%rax),%esi
  mov    0x60(%rsp),%rax
  mov    (%rax),%edi
  call   <hysteresis@plt>
  add    $0x10,%rsp
  mov    $0x0,%edx
  cmpl   $0x0,0x0(%r13)
  jg     L8
L63:
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  imul   (%rbx),%eax
  imul   %edx,%eax
  add    %ecx,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edi
  lea    -0x1(%rdi),%esi
  imul   %eax,%esi
  add    %esi,%eax
  imul   %edx,%eax
  add    %ecx,%esi
  add    %esi,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  add    $0x1,%ecx
  mov    0x0(%rbp),%eax
  cmp    %ecx,%eax
  jg     L25
L58:
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L48
  mov    $0x0,%ecx
L18:
  mov    0x0(%rbp),%esi
  imul   %esi,%eax
  imul   %edx,%eax
  imul   %ecx,%esi
  add    %esi,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  mov    0x0(%rbp),%eax
  mov    %eax,%esi
  imul   %ecx,%esi
  lea    -0x1(%rax,%rsi,1),%esi
  imul   (%rbx),%eax
  imul   %edx,%eax
  add    %esi,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  add    $0x1,%ecx
  mov    (%rbx),%eax
  cmp    %ecx,%eax
  jg     L18
L48:
  add    $0x1,%edx
  cmp    %edx,0x0(%r13)
  jle    L63
L8:
  mov    0x0(%rbp),%eax
  mov    $0x0,%ecx
  test   %eax,%eax
  jg     L25
  jmp    L58
```

assistant: ```c
void canny(int *image, int *width, int *height, int *depth, double *s, int *low, int *high) {
  int plane_size = *width * *height * *depth;
  int *magim, i, d;
  magim = (int *)malloc(plane_size * sizeof(int));
  canny_aux(image, *width, *height, *depth, *s, magim);
  hysteresis(*high, *low, image, magim, *width, *height, *depth);
  for (d = 0; d < *depth; d++) {
    for (i = 0; i < *height; i++) {
      image[((*height) * (0) + (i) + (*width) * (*height) * (d))] = 255;
      image[((*height) * (*width - 1) + (i) + (*width) * (*height) * (d))] = 255;
    }
    for (i = 0; i < *width; i++) {
      image[((*height) * (i) + (0) + (*width) * (*height) * (d))] = 255;
      image[((*height) * (i) + (*height - 1) + (*width) * (*height) * (d))] = 255;
    }
  }
  free(magim);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<canny>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    (%rsi),%edi
  imul   (%rdx),%edi
  imul   (%rcx),%edi
  mov    0x50(%rsp),%r10
  mov    %r8,0x8(%rsp)
  mov    %r10,(%rsp)
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdx
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    0x0(%r13),%ecx
  mov    %rax,%r8
  mov    %rax,%r14
  movsd  (%rdx),%xmm0
  mov    0x0(%rbp),%edx
  call   <canny_aux@plt>
  mov    0x0(%r13),%eax
  sub    $0x8,%rsp
  mov    (%rbx),%r8d
  mov    0x0(%rbp),%r9d
  mov    (%r15),%esi
  mov    %r14,%rcx
  mov    %r12,%rdx
  push   %rax
  mov    0x10(%rsp),%r10
  mov    (%r10),%edi
  call   <hysteresis@plt>
  mov    0x0(%r13),%ecx
  pop    %rax
  pop    %rdx
  test   %ecx,%ecx
  jle    L67
  xor    %ecx,%ecx
  nopl   (%rax)
L19:
  mov    0x0(%rbp),%eax
  xor    %edx,%edx
  test   %eax,%eax
  jle    L50
  nopl   0x0(%rax)
L28:
  imul   (%rbx),%eax
  imul   %ecx,%eax
  add    %edx,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  mov    (%rbx),%edi
  mov    0x0(%rbp),%eax
  lea    -0x1(%rdi),%esi
  imul   %eax,%esi
  add    %esi,%eax
  add    %edx,%esi
  add    $0x1,%edx
  imul   %ecx,%eax
  add    %esi,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  mov    0x0(%rbp),%eax
  cmp    %edx,%eax
  jg     L28
L50:
  mov    (%rbx),%edx
  test   %edx,%edx
  jle    L3
  xor    %esi,%esi
  jmp    L42
  nopl   0x0(%rax)
L58:
  mov    0x0(%rbp),%eax
L42:
  imul   %eax,%edx
  imul   %esi,%eax
  imul   %ecx,%edx
  add    %eax,%edx
  movslq %edx,%rdx
  movl   $0xff,(%r12,%rdx,4)
  mov    0x0(%rbp),%eax
  mov    %eax,%edx
  imul   %esi,%edx
  add    $0x1,%esi
  lea    -0x1(%rax,%rdx,1),%edx
  imul   (%rbx),%eax
  imul   %ecx,%eax
  add    %edx,%eax
  cltq
  movl   $0xff,(%r12,%rax,4)
  mov    (%rbx),%edx
  cmp    %esi,%edx
  jg     L58
L3:
  add    $0x1,%ecx
  cmp    %ecx,0x0(%r13)
  jg     L19
L67:
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

assistant: ```c
void canny(int *image, int *width, int *height, int *depth, double *s, int *low, int *high) {
  int plane_size = *width * *height * *depth;
  int *magim, i, d;
  magim = (int *)malloc(plane_size * sizeof(int));
  canny_aux(image, *width, *height, *depth, *s, magim);
  hysteresis(*high, *low, image, magim, *width, *height, *depth);
  for (d = 0; d < *depth; d++) {
    for (i = 0; i < *height; i++) {
      image[((*height) * (0) + (i) + (*width) * (*height) * (d))] = 255;
      image[((*height) * (*width - 1) + (i) + (*width) * (*height) * (d))] = 255;
    }
    for (i = 0; i < *width; i++) {
      image[((*height) * (i) + (0) + (*width) * (*height) * (d))] = 255;
      image[((*height) * (i) + (*height - 1) + (*width) * (*height) * (d))] = 255;
    }
  }
  free(magim);
}
```