user: 这段汇编代码用C语言表示是什么样的:

```asm
<encodeutf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    D92(%rip),%eax
  sub    $0x1,%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D95(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L28
  mov    $0xffffffff,%eax
  jmp    L109
L28:
  movl   $0x0,-0x8(%rbp)
  jmp    L100
L17:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D95(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L111
  addl   $0x1,-0x8(%rbp)
L100:
  mov    D92(%rip),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L17
  jmp    L67
L111:
  nop
L67:
  mov    D92(%rip),%eax
  cmp    %eax,-0x8(%rbp)
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jae    L93
  mov    $0xffffffff,%eax
  jmp    L109
L93:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    $0x1,%eax
  jne    L68
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L65
L68:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L74
L48:
  mov    -0x18(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  shrq   $0x6,-0x18(%rbp)
  subl   $0x1,-0x4(%rbp)
L74:
  cmpl   $0x0,-0x4(%rbp)
  jg     L48
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  or     -0x9(%rbp),%al
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
L65:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D26(%rip),%rax
  mov    (%rdx,%rax,1),%eax
L109:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D92
data_type: byte[4]
name: retrieve_data
arguments: data_tag: D95
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string

tool: {"D92": [0x06,0x00,0x00,0x00]}

tool: D95: 

tool: D26: 

assistant: ```c
int encodeutf8(unsigned long u, unsigned char *buf, size_t maxbytes) {
  static const struct {
    int nbytes;
    unsigned long max;
  } tab[] = {
      {1, 0x0000007F}, {2, 0x000007FF}, {3, 0x0000FFFF}, {4, 0x001FFFFF}, {5, 0x03FFFFFF}, {6, 0x7FFFFFFF},
  };
  static const int ntab = sizeof(tab) / sizeof(tab[0]);
  int i, j;
  if (u > tab[ntab - 1].max)
    return -1;
  for (i = 0; i < ntab; ++i) {
    if (u <= tab[i].max)
      break;
  }
  assert(i < ntab);
  if (tab[i].nbytes > maxbytes)
    return -1;
  if (tab[i].nbytes == 1) {
    buf[0] = u;
  } else {
    for (j = tab[i].nbytes - 1; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> tab[i].nbytes);
    buf[0] = mask | u;
  }
  return tab[i].nbytes;
}
```