ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<optionValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  movslq (%rsi),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x1(%rdx),%r13d
  movslq %r13d,%rax
  mov    (%rdi,%rax,8),%rdi
  test   %rdi,%rdi
  je     L31
  lea    0x8(%rsp),%rsi
  xor    %edx,%edx
  call   <strtol@plt>
  mov    %eax,%r12d
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L25
  cmpb   $0x0,(%rax)
  je     L34
L25:
  movslq (%rbx),%rdx
L5:
  mov    0x0(%rbp,%rdx,8),%rdx
  lea    0x10(%rsp),%rbp
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <Usage@plt>
L34:
  mov    %r13d,(%rbx)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x78,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %r12d,%r12d
  jmp    L5
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: Expected a numeric-parameter for %.20s

assistant: ```c
int optionValue(char **argv, int *num) {
  int next = *num + 1;
  char *src = argv[next];
  char *tmp = 0;
  int result = 0;
  if (src != 0) {
    result = (int)strtol(src, &tmp, 0);
    if (tmp == 0 || *tmp != 0)
      src = 0;
  }
  if (src == 0) {
    char temp[80];
    sprintf(temp, "Expected a numeric-parameter for %.20s", argv[*num]);
    Usage(temp);
  }
  *num = next;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<optionValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  movslq (%rsi),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x1(%rdx),%r13d
  movslq %r13d,%rax
  mov    (%rdi,%rax,8),%rdi
  test   %rdi,%rdi
  je     L37
  lea    0x8(%rsp),%rsi
  xor    %edx,%edx
  call   <strtol@plt>
  mov    %eax,%r12d
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L32
  cmpb   $0x0,(%rax)
  je     L18
L32:
  movslq (%rbx),%rdx
L26:
  mov    0x0(%rbp,%rdx,8),%rdx
  lea    0x10(%rsp),%rbp
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <Usage@plt>
L18:
  mov    %r13d,(%rbx)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x78,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %r12d,%r12d
  jmp    L26
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: Expected a numeric-parameter for %.20s

assistant: ```c
int optionValue(char **argv, int *num) {
  int next = *num + 1;
  char *src = argv[next];
  char *tmp = 0;
  int result = 0;
  if (src != 0) {
    result = (int)strtol(src, &tmp, 0);
    if (tmp == 0 || *tmp != 0)
      src = 0;
  }
  if (src == 0) {
    char temp[80];
    sprintf(temp, "Expected a numeric-parameter for %.20s", argv[*num]);
    Usage(temp);
  }
  *num = next;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hashmapShortEquals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool hashmapShortEquals(void *keyA, void *keyB) {
  short a = *((short *)keyA);
  short b = *((short *)keyB);
  return a == b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashmapShortEquals>:
  endbr64
  movzwl (%rsi),%eax
  cmp    %ax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool hashmapShortEquals(void *keyA, void *keyB) {
  short a = *((short *)keyA);
  short b = *((short *)keyB);
  return a == b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hashmapShortEquals>:
  endbr64
  movzwl (%rsi),%eax
  cmp    %ax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool hashmapShortEquals(void *keyA, void *keyB) {
  short a = *((short *)keyA);
  short b = *((short *)keyB);
  return a == b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hashmapShortEquals>:
  endbr64
  movzwl (%rsi),%eax
  cmp    %ax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool hashmapShortEquals(void *keyA, void *keyB) {
  short a = *((short *)keyA);
  short b = *((short *)keyB);
  return a == b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L0
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L0:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(double *v, int low, int high) {
  if (low < high) {
    int k = partition(v, low, high);
    quicksort(v, low, k - 1);
    quicksort(v, k + 1, high);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L6
  ret
L6:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(double *v, int low, int high) {
  if (low < high) {
    int k = partition(v, low, high);
    quicksort(v, low, k - 1);
    quicksort(v, k + 1, high);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  blksize_t d = 0;
  (void)argc;
  (void)argv;
  (void)d;
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  blksize_t d = 0;
  (void)argc;
  (void)argv;
  (void)d;
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  blksize_t d = 0;
  (void)argc;
  (void)argv;
  (void)d;
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  blksize_t d = 0;
  (void)argc;
  (void)argv;
  (void)d;
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ScanRowForPieces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L33:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L33
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
  jmp    L13
L6:
  mov    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int ScanRowForPieces(char *row) {
  while (*row == '.') {
    row++;
  }
  if (*row == '\0') {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ScanRowForPieces>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  jne    L14
L17:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L17
L14:
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ScanRowForPieces(char *row) {
  while (*row == '.') {
    row++;
  }
  if (*row == '\0') {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ScanRowForPieces>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
L11:
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L8
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ScanRowForPieces(char *row) {
  while (*row == '.') {
    row++;
  }
  if (*row == '\0') {
    return 0;
  } else {
    return 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ScanRowForPieces>:
  endbr64
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdi
L6:
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L4
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ScanRowForPieces(char *row) {
  while (*row == '.') {
    row++;
  }
  if (*row == '\0') {
    return 0;
  } else {
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_permissions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    D94(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L91
  addl   $0x1,-0x14(%rbp)
L91:
  mov    -0x1c(%rbp),%edx
  mov    D82(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L27
  addl   $0x2,-0x14(%rbp)
L27:
  mov    -0x1c(%rbp),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L43
  addl   $0x4,-0x14(%rbp)
L43:
  mov    -0x1c(%rbp),%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L86
  addl   $0x1,-0x10(%rbp)
L86:
  mov    -0x1c(%rbp),%edx
  mov    D93(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L10
  addl   $0x2,-0x10(%rbp)
L10:
  mov    -0x1c(%rbp),%edx
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L0
  addl   $0x4,-0x10(%rbp)
L0:
  mov    -0x1c(%rbp),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L94
  addl   $0x1,-0xc(%rbp)
L94:
  mov    -0x1c(%rbp),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L2
  addl   $0x2,-0xc(%rbp)
L2:
  mov    -0x1c(%rbp),%edx
  mov    D77(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L57
  addl   $0x4,-0xc(%rbp)
L57:
  mov    -0x1c(%rbp),%edx
  mov    D76(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L83
  movl   $0xffffffff,-0x18(%rbp)
L83:
  mov    -0x14(%rbp),%eax
  imul   $0x64,%eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int get_permissions(char *path) {
  struct stat buffer;
  stat(path, &buffer);
  int d = 1, u = 0, g = 0, o = 0;
  if (buffer.st_mode & S_IRUSR)
    u++;
  if (buffer.st_mode & S_IWUSR)
    u += 2;
  if (buffer.st_mode & S_IXUSR)
    u += 4;
  if (buffer.st_mode & S_IRGRP)
    g++;
  if (buffer.st_mode & S_IWGRP)
    g += 2;
  if (buffer.st_mode & S_IXGRP)
    g += 4;
  if (buffer.st_mode & S_IROTH)
    o++;
  if (buffer.st_mode & S_IWOTH)
    o += 2;
  if (buffer.st_mode & S_IXOTH)
    o += 4;
  if (buffer.st_mode & S_IFDIR)
    d = -1;
  return d * (u * 100 + g * 10 + o);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_permissions>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    D58(%rip),%rax
  mov    %edx,%ecx
  and    (%rax),%ecx
  setne  %cl
  movzbl %cl,%ecx
  mov    D24(%rip),%rax
  mov    %edx,%esi
  and    (%rax),%esi
  lea    0x2(%rcx),%eax
  cmovne %eax,%ecx
  mov    D85(%rip),%rax
  mov    %edx,%esi
  and    (%rax),%esi
  lea    0x4(%rcx),%eax
  cmovne %eax,%ecx
  mov    D53(%rip),%rax
  mov    %edx,%edi
  and    (%rax),%edi
  setne  %sil
  movzbl %sil,%esi
  mov    D52(%rip),%rax
  mov    %edx,%edi
  and    (%rax),%edi
  lea    0x2(%rsi),%eax
  cmovne %eax,%esi
  mov    D64(%rip),%rax
  mov    %edx,%edi
  and    (%rax),%edi
  lea    0x4(%rsi),%eax
  cmovne %eax,%esi
  mov    D60(%rip),%rax
  mov    %edx,%edi
  and    (%rax),%edi
  setne  %dil
  movzbl %dil,%edi
  mov    D36(%rip),%rax
  mov    %edx,%r8d
  and    (%rax),%r8d
  lea    0x2(%rdi),%eax
  cmovne %eax,%edi
  mov    D42(%rip),%rax
  mov    %edx,%r8d
  and    (%rax),%r8d
  lea    0x4(%rdi),%eax
  cmovne %eax,%edi
  mov    D92(%rip),%rax
  and    (%rax),%edx
  cmp    $0x1,%edx
  sbb    %edx,%edx
  and    $0x2,%edx
  sub    $0x1,%edx
  imul   $0x64,%ecx,%ecx
  lea    (%rsi,%rsi,4),%eax
  lea    (%rcx,%rax,2),%eax
  add    %edi,%eax
  imul   %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_permissions(char *path) {
  struct stat buffer;
  stat(path, &buffer);
  int d = 1, u = 0, g = 0, o = 0;
  if (buffer.st_mode & S_IRUSR)
    u++;
  if (buffer.st_mode & S_IWUSR)
    u += 2;
  if (buffer.st_mode & S_IXUSR)
    u += 4;
  if (buffer.st_mode & S_IRGRP)
    g++;
  if (buffer.st_mode & S_IWGRP)
    g += 2;
  if (buffer.st_mode & S_IXGRP)
    g += 4;
  if (buffer.st_mode & S_IROTH)
    o++;
  if (buffer.st_mode & S_IWOTH)
    o += 2;
  if (buffer.st_mode & S_IXOTH)
    o += 4;
  if (buffer.st_mode & S_IFDIR)
    d = -1;
  return d * (u * 100 + g * 10 + o);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_permissions>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    D44(%rip),%rax
  mov    %edx,%ecx
  and    (%rax),%ecx
  mov    D77(%rip),%rax
  mov    %edx,%esi
  setne  %cl
  mov    %edx,%edi
  mov    %edx,%r8d
  movzbl %cl,%ecx
  and    (%rax),%esi
  mov    %edx,%esi
  lea    0x2(%rcx),%eax
  cmovne %eax,%ecx
  mov    D2(%rip),%rax
  and    (%rax),%esi
  lea    0x4(%rcx),%eax
  cmovne %eax,%ecx
  mov    D98(%rip),%rax
  xor    %esi,%esi
  and    (%rax),%edi
  mov    D22(%rip),%rax
  mov    %edx,%edi
  setne  %sil
  and    (%rax),%edi
  lea    0x2(%rsi),%eax
  mov    %edx,%edi
  cmovne %eax,%esi
  mov    D66(%rip),%rax
  and    (%rax),%edi
  lea    0x4(%rsi),%eax
  mov    %edx,%edi
  cmovne %eax,%esi
  mov    D13(%rip),%rax
  and    (%rax),%edi
  mov    D62(%rip),%rax
  setne  %dil
  movzbl %dil,%edi
  and    (%rax),%r8d
  mov    %edx,%r8d
  lea    0x2(%rdi),%eax
  cmovne %eax,%edi
  mov    D27(%rip),%rax
  and    (%rax),%r8d
  lea    0x4(%rdi),%eax
  cmovne %eax,%edi
  mov    D5(%rip),%rax
  and    (%rax),%edx
  lea    (%rsi,%rsi,4),%eax
  cmp    $0x1,%edx
  sbb    %edx,%edx
  imul   $0x64,%ecx,%ecx
  and    $0x2,%edx
  sub    $0x1,%edx
  lea    (%rcx,%rax,2),%eax
  add    %edi,%eax
  imul   %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_permissions(char *path) {
  struct stat buffer;
  stat(path, &buffer);
  int d = 1, u = 0, g = 0, o = 0;
  if (buffer.st_mode & S_IRUSR)
    u++;
  if (buffer.st_mode & S_IWUSR)
    u += 2;
  if (buffer.st_mode & S_IXUSR)
    u += 4;
  if (buffer.st_mode & S_IRGRP)
    g++;
  if (buffer.st_mode & S_IWGRP)
    g += 2;
  if (buffer.st_mode & S_IXGRP)
    g += 4;
  if (buffer.st_mode & S_IROTH)
    o++;
  if (buffer.st_mode & S_IWOTH)
    o += 2;
  if (buffer.st_mode & S_IXOTH)
    o += 4;
  if (buffer.st_mode & S_IFDIR)
    d = -1;
  return d * (u * 100 + g * 10 + o);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_permissions>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    D16(%rip),%rax
  mov    %edx,%ecx
  and    (%rax),%ecx
  mov    D41(%rip),%rax
  mov    %edx,%esi
  setne  %cl
  mov    %edx,%edi
  mov    %edx,%r8d
  movzbl %cl,%ecx
  and    (%rax),%esi
  mov    %edx,%esi
  lea    0x2(%rcx),%eax
  cmovne %eax,%ecx
  mov    D84(%rip),%rax
  and    (%rax),%esi
  lea    0x4(%rcx),%eax
  cmovne %eax,%ecx
  mov    D48(%rip),%rax
  xor    %esi,%esi
  and    (%rax),%edi
  mov    D20(%rip),%rax
  mov    %edx,%edi
  setne  %sil
  and    (%rax),%edi
  lea    0x2(%rsi),%eax
  mov    %edx,%edi
  cmovne %eax,%esi
  mov    D80(%rip),%rax
  and    (%rax),%edi
  lea    0x4(%rsi),%eax
  mov    %edx,%edi
  cmovne %eax,%esi
  mov    D94(%rip),%rax
  and    (%rax),%edi
  mov    D8(%rip),%rax
  setne  %dil
  movzbl %dil,%edi
  and    (%rax),%r8d
  mov    %edx,%r8d
  lea    0x2(%rdi),%eax
  cmovne %eax,%edi
  mov    D99(%rip),%rax
  and    (%rax),%r8d
  lea    0x4(%rdi),%eax
  cmovne %eax,%edi
  mov    D97(%rip),%rax
  and    (%rax),%edx
  lea    (%rsi,%rsi,4),%eax
  cmp    $0x1,%edx
  sbb    %edx,%edx
  imul   $0x64,%ecx,%ecx
  and    $0x2,%edx
  sub    $0x1,%edx
  lea    (%rcx,%rax,2),%eax
  add    %edi,%eax
  imul   %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_permissions(char *path) {
  struct stat buffer;
  stat(path, &buffer);
  int d = 1, u = 0, g = 0, o = 0;
  if (buffer.st_mode & S_IRUSR)
    u++;
  if (buffer.st_mode & S_IWUSR)
    u += 2;
  if (buffer.st_mode & S_IXUSR)
    u += 4;
  if (buffer.st_mode & S_IRGRP)
    g++;
  if (buffer.st_mode & S_IWGRP)
    g += 2;
  if (buffer.st_mode & S_IXGRP)
    g += 4;
  if (buffer.st_mode & S_IROTH)
    o++;
  if (buffer.st_mode & S_IWOTH)
    o += 2;
  if (buffer.st_mode & S_IXOTH)
    o += 4;
  if (buffer.st_mode & S_IFDIR)
    d = -1;
  return d * (u * 100 + g * 10 + o);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L12
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L1
L12:
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
L1:
  nop
  leave
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
  if (fmt->type == V4L2_BUF_TYPE_VIDEO_CAPTURE || fmt->type == V4L2_BUF_TYPE_VIDEO_OUTPUT)
    fmt->fmt.pix.priv = V4L2_PIX_FMT_PRIV_MAGIC;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %ebx,0x0(%rbp)
  mov    %ebx,%ebx
  mov    D4(%rip),%rax
  cmp    (%rax),%rbx
  je     L17
  mov    D26(%rip),%rax
  cmp    (%rax),%rbx
  jne    L3
L17:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rbp)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
  if (fmt->type == V4L2_BUF_TYPE_VIDEO_CAPTURE || fmt->type == V4L2_BUF_TYPE_VIDEO_OUTPUT)
    fmt->fmt.pix.priv = V4L2_PIX_FMT_PRIV_MAGIC;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    D8(%rip),%rax
  mov    %ebx,0x0(%rbp)
  cmp    (%rax),%rbx
  je     L9
  mov    D5(%rip),%rax
  cmp    (%rax),%rbx
  je     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L9:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
  if (fmt->type == V4L2_BUF_TYPE_VIDEO_CAPTURE || fmt->type == V4L2_BUF_TYPE_VIDEO_OUTPUT)
    fmt->fmt.pix.priv = V4L2_PIX_FMT_PRIV_MAGIC;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<v4l_format_init>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    D11(%rip),%rax
  mov    %ebx,0x0(%rbp)
  cmp    (%rax),%rbx
  je     L7
  mov    D16(%rip),%rax
  cmp    (%rax),%rbx
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void v4l_format_init(struct v4l2_format *fmt, unsigned type) {
  memset(fmt, 0, sizeof(*fmt));
  fmt->type = type;
  if (fmt->type == V4L2_BUF_TYPE_VIDEO_CAPTURE || fmt->type == V4L2_BUF_TYPE_VIDEO_OUTPUT)
    fmt->fmt.pix.priv = V4L2_PIX_FMT_PRIV_MAGIC;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L2
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L27
L2:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x28(%rbp)
L12:
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(void const *s1, void const *s2, size_t n) {
  unsigned char const *c1;
  unsigned char const *c2;
  c1 = s1;
  c2 = s2;
  while (n) {
    if (*c1 != *c2) {
      return (*c1 - *c2);
    }
    ++c1;
    ++c2;
    --n;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L1
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L17
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
  mov    $0x0,%eax
  ret
L17:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(void const *s1, void const *s2, size_t n) {
  unsigned char const *c1;
  unsigned char const *c2;
  c1 = s1;
  c2 = s2;
  while (n) {
    if (*c1 != *c2) {
      return (*c1 - *c2);
    }
    ++c1;
    ++c2;
    --n;
  }
  return (0);
}
```