ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nextword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    (%rdi),%rbx
  movsbl (%rbx),%edi
  test   %edi,%edi
  je     L66
L28:
  call   <Isspace@plt>
  test   %rax,%rax
  je     L57
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  test   %edi,%edi
  jne    L28
L66:
  mov    %rbx,%rbp
L36:
  mov    %rbp,(%r12)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  lea    0x1(%rbx),%rbp
  movsbl 0x1(%rbx),%edi
  test   %edi,%edi
  je     L36
L44:
  call   <Isspace@plt>
  test   %rax,%rax
  jne    L48
  add    $0x1,%rbp
  movsbl 0x0(%rbp),%edi
  test   %edi,%edi
  jne    L44
  jmp    L36
L48:
  movb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L36
```

assistant: ```c
char *nextword(char **str) {
  char *head, *tail;
  int ch;
  head = *str;
  for (;;) {
    ch = *head;
    if (!ch) {
      *str = head;
      return head;
    }
    if (!Isspace(ch))
      break;
    head++;
  }
  tail = head + 1;
  while ((ch = *tail)) {
    if (Isspace(ch)) {
      *tail++ = '\0';
      break;
    }
    tail++;
  }
  *str = tail;
  return head;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextword>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%r12
  jmp    L44
L35:
  call   <Isspace@plt>
  mov    %r12,%rbx
  add    $0x1,%r12
  test   %rax,%rax
  je     L16
L44:
  movsbl (%r12),%edi
  test   %edi,%edi
  jne    L35
  mov    %r12,%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  movsbl 0x1(%rbx),%edi
  test   %edi,%edi
  jne    L36
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L63:
  movsbl (%r12),%edi
  test   %edi,%edi
  je     L58
L36:
  call   <Isspace@plt>
  mov    %r12,%rdx
  add    $0x1,%r12
  test   %rax,%rax
  je     L63
  movb   $0x0,(%rdx)
L58:
  mov    %r12,%rax
  mov    %rbx,%r12
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *nextword(char **str) {
  char *head, *tail;
  int ch;
  head = *str;
  for (;;) {
    ch = *head;
    if (!ch) {
      *str = head;
      return head;
    }
    if (!Isspace(ch))
      break;
    head++;
  }
  tail = head + 1;
  while ((ch = *tail)) {
    if (Isspace(ch)) {
      *tail++ = '\0';
      break;
    }
    tail++;
  }
  *str = tail;
  return head;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nextword>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%r12
  jmp    L35
L62:
  call   <Isspace@plt>
  mov    %r12,%rbx
  add    $0x1,%r12
  test   %rax,%rax
  je     L10
L35:
  movsbl (%r12),%edi
  test   %edi,%edi
  jne    L62
  mov    %r12,%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  movsbl 0x1(%rbx),%edi
  test   %edi,%edi
  jne    L50
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L12:
  movsbl (%r12),%edi
  test   %edi,%edi
  je     L68
L50:
  call   <Isspace@plt>
  mov    %r12,%rdx
  add    $0x1,%r12
  test   %rax,%rax
  je     L12
  movb   $0x0,(%rdx)
L68:
  mov    %r12,%rax
  mov    %rbx,%r12
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *nextword(char **str) {
  char *head, *tail;
  int ch;
  head = *str;
  for (;;) {
    ch = *head;
    if (!ch) {
      *str = head;
      return head;
    }
    if (!Isspace(ch))
      break;
    head++;
  }
  tail = head + 1;
  while ((ch = *tail)) {
    if (Isspace(ch)) {
      *tail++ = '\0';
      break;
    }
    tail++;
  }
  *str = tail;
  return head;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mx_multmx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L39
L43:
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L29:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L33:
  mov    -0x14(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jb     L33
  mov    -0x14(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L29
  addl   $0x1,-0x14(%rbp)
L39:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L43
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mx_multmx(unsigned int m, unsigned int n, unsigned int q, double *p, double *a, double *b) {
  unsigned int i, j, k;
  double t;
  for (i = 0; i < m; i++) {
    for (j = 0; j < q; j++) {
      t = 0.0;
      for (k = 0; k < n; k++) {
        t += a[i * n + k] * b[k * q + j];
      }
      p[i * q + j] = t;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mx_multmx>:
  endbr64
  test   %edi,%edi
  je     L40
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %rcx,%r12
  mov    %ebx,%edi
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  jmp    L30
L40:
  ret
L41:
  mov    %r10d,%edx
  mov    %r13d,%eax
  pxor   %xmm1,%xmm1
L84:
  mov    %eax,%r15d
  mov    %edx,%ecx
  movsd  (%r8,%r15,8),%xmm0
  mulsd  (%r9,%rcx,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%eax
  add    %esi,%edx
  cmp    %edi,%eax
  jne    L84
L19:
  lea    0x0(%rbp,%r10,1),%eax
  movsd  %xmm1,(%r12,%rax,8)
  add    $0x1,%r10d
  cmp    %r10d,%esi
  je     L36
L89:
  pxor   %xmm1,%xmm1
  test   %ebx,%ebx
  jne    L41
  jmp    L19
L36:
  add    $0x1,%r14d
  add    %esi,%ebp
  add    %ebx,%r13d
  add    %ebx,%edi
  cmp    %r14d,%r11d
  je     L61
L30:
  mov    $0x0,%r10d
  test   %esi,%esi
  jne    L89
  jmp    L36
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mx_multmx(unsigned int m, unsigned int n, unsigned int q, double *p, double *a, double *b) {
  unsigned int i, j, k;
  double t;
  for (i = 0; i < m; i++) {
    for (j = 0; j < q; j++) {
      t = 0.0;
      for (k = 0; k < n; k++) {
        t += a[i * n + k] * b[k * q + j];
      }
      p[i * q + j] = t;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mx_multmx>:
  endbr64
  test   %edi,%edi
  je     L14
  push   %r15
  mov    %edi,%r11d
  pxor   %xmm2,%xmm2
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    %ebx,%edi
  xchg   %ax,%ax
L45:
  xor    %r10d,%r10d
  test   %esi,%esi
  je     L35
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r10d,%edx
  mov    %r13d,%eax
  movapd %xmm2,%xmm1
  test   %ebx,%ebx
  je     L50
  xchg   %ax,%ax
L42:
  mov    %eax,%r15d
  mov    %edx,%ecx
  add    $0x1,%eax
  add    %esi,%edx
  movsd  (%r8,%r15,8),%xmm0
  mulsd  (%r9,%rcx,8),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %edi,%eax
  jne    L42
L50:
  lea    (%r10,%rbp,1),%eax
  add    $0x1,%r10d
  movsd  %xmm1,(%r12,%rax,8)
  cmp    %r10d,%esi
  jne    L37
L35:
  add    $0x1,%r14d
  add    %esi,%ebp
  add    %ebx,%r13d
  add    %ebx,%edi
  cmp    %r14d,%r11d
  jne    L45
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  ret
```

assistant: ```c
void mx_multmx(unsigned int m, unsigned int n, unsigned int q, double *p, double *a, double *b) {
  unsigned int i, j, k;
  double t;
  for (i = 0; i < m; i++) {
    for (j = 0; j < q; j++) {
      t = 0.0;
      for (k = 0; k < n; k++) {
        t += a[i * n + k] * b[k * q + j];
      }
      p[i * q + j] = t;
    }
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mx_multmx>:
  endbr64
  test   %edi,%edi
  je     L11
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %edx,%esi
  test   %edx,%edx
  je     L56
  mov    %edi,%r11d
  mov    %rcx,%r12
  mov    %ebx,%edi
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  xor    %r14d,%r14d
  pxor   %xmm2,%xmm2
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %r10d,%edx
  mov    %r13d,%eax
  movapd %xmm2,%xmm1
  test   %ebx,%ebx
  je     L43
  xchg   %ax,%ax
L50:
  mov    %eax,%r15d
  mov    %edx,%ecx
  add    $0x1,%eax
  add    %esi,%edx
  movsd  (%r8,%r15,8),%xmm0
  mulsd  (%r9,%rcx,8),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %edi,%eax
  jne    L50
L43:
  lea    (%r10,%rbp,1),%eax
  add    $0x1,%r10d
  movsd  %xmm1,(%r12,%rax,8)
  cmp    %r10d,%esi
  jne    L41
  add    $0x1,%r14d
  add    %esi,%ebp
  add    %ebx,%r13d
  add    %ebx,%edi
  cmp    %r14d,%r11d
  jne    L21
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  ret
```

assistant: ```c
void mx_multmx(unsigned int m, unsigned int n, unsigned int q, double *p, double *a, double *b) {
  unsigned int i, j, k;
  double t;
  for (i = 0; i < m; i++) {
    for (j = 0; j < q; j++) {
      t = 0.0;
      for (k = 0; k < n; k++) {
        t += a[i * n + k] * b[k * q + j];
      }
      p[i * q + j] = t;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vdso_arch_syscall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    %rdx,%rdi
  lea    D1(%rip),%rcx
  jmp    *%gs:0x20
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long vdso_arch_syscall(long nr, long arg1, long arg2) {
  long ret;
  __asm__ volatile("lea .Lret%=(%%rip), %%rcx\n"
                   "jmp *%%gs:%c[syscalldb]\n"
                   ".Lret%=:\n"
                   : "=a"(ret)
                   : "0"(nr), "D"(arg1), "S"(arg2), [syscalldb] "i"(32)
                   : "memory", "rcx", "r11");
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vdso_arch_syscall>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  lea    D4(%rip),%rcx
  jmp    *%gs:0x20
  ret
```

assistant: ```c
long vdso_arch_syscall(long nr, long arg1, long arg2) {
  long ret;
  __asm__ volatile("lea .Lret%=(%%rip), %%rcx\n"
                   "jmp *%%gs:%c[syscalldb]\n"
                   ".Lret%=:\n"
                   : "=a"(ret)
                   : "0"(nr), "D"(arg1), "S"(arg2), [syscalldb] "i"(32)
                   : "memory", "rcx", "r11");
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vdso_arch_syscall>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  lea    D1(%rip),%rcx
  jmp    *%gs:0x20
  ret
```

assistant: ```c
long vdso_arch_syscall(long nr, long arg1, long arg2) {
  long ret;
  __asm__ volatile("lea .Lret%=(%%rip), %%rcx\n"
                   "jmp *%%gs:%c[syscalldb]\n"
                   ".Lret%=:\n"
                   : "=a"(ret)
                   : "0"(nr), "D"(arg1), "S"(arg2), [syscalldb] "i"(32)
                   : "memory", "rcx", "r11");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vdso_arch_syscall>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  lea    D1(%rip),%rcx
  jmp    *%gs:0x20
  ret
```

assistant: ```c
long vdso_arch_syscall(long nr, long arg1, long arg2) {
  long ret;
  __asm__ volatile("lea .Lret%=(%%rip), %%rcx\n"
                   "jmp *%%gs:%c[syscalldb]\n"
                   ".Lret%=:\n"
                   : "=a"(ret)
                   : "0"(nr), "D"(arg1), "S"(arg2), [syscalldb] "i"(32)
                   : "memory", "rcx", "r11");
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x10(%rbp)
  mov    %ax,-0xc(%rbp)
  cmpl   $0x2,-0x10(%rbp)
  jne    L2
  movzwl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <xor@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void encode(unsigned char *string, unsigned short string_len, int format) {
  if (format == 0x2) {
    xor(string, string_len);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encode>:
  endbr64
  cmp    $0x2,%edx
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  movzwl %si,%esi
  mov    $0x0,%eax
  call   <xor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void encode(unsigned char *string, unsigned short string_len, int format) {
  if (format == 0x2) {
    xor(string, string_len);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<encode>:
  endbr64
  cmp    $0x2,%edx
  je     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movzwl %si,%esi
  xor    %eax,%eax
  jmp    1050 <xor@plt>
```

assistant: ```c
void encode(unsigned char *string, unsigned short string_len, int format) {
  if (format == 0x2) {
    xor(string, string_len);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode>:
  endbr64
  cmp    $0x2,%edx
  je     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movzwl %si,%esi
  xor    %eax,%eax
  jmp    1050 <xor@plt>
```

assistant: ```c
void encode(unsigned char *string, unsigned short string_len, int format) {
  if (format == 0x2) {
    xor(string, string_len);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x28,%edx
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1d,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D62
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D38
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string

tool: D6: What's your name?

tool: D62: %s

tool: D16: What a super marvelous name!

tool: D14: Hello. %s. %s.


tool: D38: Your name of %d letters occupies %d memory cells.


tool: D12: The phrase of praise has %d letters


tool: D10: and occupies %d memory cells.


assistant: ```c
int main(int argc, char const *argv[]) {
  char name[40];
  printf("What's your name?\n");
  scanf("%s", name);
  printf("Hello. %s. %s.\n", name, "What a super marvelous name!");
  printf("Your name of %d letters occupies %d memory cells.\n", strlen(name), sizeof name);
  printf("The phrase of praise has %d letters\n", strlen("What a super marvelous name!"));
  printf("and occupies %d memory cells.\n", sizeof "What a super marvelous name!");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D63(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x28,%edx
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1d,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D48
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D63
datatype: string
name: retrieve_data
arguments: data_label: D55
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string

tool: D48: What's your name?

tool: D27: %s

tool: D26: What a super marvelous name!

tool: D63: Hello. %s. %s.


tool: D55: Your name of %d letters occupies %d memory cells.


tool: D12: The phrase of praise has %d letters


tool: D30: and occupies %d memory cells.


assistant: ```c
int main(int argc, char const *argv[]) {
  char name[40];
  printf("What's your name?\n");
  scanf("%s", name);
  printf("Hello. %s. %s.\n", name, "What a super marvelous name!");
  printf("Your name of %d letters occupies %d memory cells.\n", strlen(name), sizeof name);
  printf("The phrase of praise has %d letters\n", strlen("What a super marvelous name!"));
  printf("and occupies %d memory cells.\n", sizeof "What a super marvelous name!");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D49(%rip),%rdi
  lea    D24(%rip),%r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x28,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x1d,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D49
type: string
name: retrieve_data
arguments: data_label: D24
type: string
name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D41
type: string

tool: D49: What's your name?

tool: D24: What a super marvelous name!

tool: D7: %s

tool: D4: Hello. %s. %s.


tool: D3: Your name of %d letters occupies %d memory cells.


tool: D14: The phrase of praise has %d letters


tool: D41: and occupies %d memory cells.


assistant: ```c
int main(int argc, char const *argv[]) {
  char name[40];
  printf("What's your name?\n");
  scanf("%s", name);
  printf("Hello. %s. %s.\n", name, "What a super marvelous name!");
  printf("Your name of %d letters occupies %d memory cells.\n", strlen(name), sizeof name);
  printf("The phrase of praise has %d letters\n", strlen("What a super marvelous name!"));
  printf("and occupies %d memory cells.\n", sizeof "What a super marvelous name!");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  lea    D15(%rip),%r12
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x28,%edx
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    D54(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x1d,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D54
type_guessed: string
name: retrieve_data
arguments: label: D41
type_guessed: string

tool: D3: What's your name?

tool: D15: What a super marvelous name!

tool: D14: %s

tool: D27: Hello. %s. %s.


tool: D25: Your name of %d letters occupies %d memory cells.


tool: D54: The phrase of praise has %d letters


tool: D41: and occupies %d memory cells.


assistant: ```c
int main(int argc, char const *argv[]) {
  char name[40];
  printf("What's your name?\n");
  scanf("%s", name);
  printf("Hello. %s. %s.\n", name, "What a super marvelous name!");
  printf("Your name of %d letters occupies %d memory cells.\n", strlen(name), sizeof name);
  printf("The phrase of praise has %d letters\n", strlen("What a super marvelous name!"));
  printf("and occupies %d memory cells.\n", sizeof "What a super marvelous name!");
  return 0;
}
```