ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <A@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: hello world


assistant: ```c
int main() {
  printf("hello world\n");
  A();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <A@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: hello world


assistant: ```c
int main() {
  printf("hello world\n");
  A();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <A@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: hello world


assistant: ```c
int main() {
  printf("hello world\n");
  A();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L1
  cmpl   $0x7a,-0x4(%rbp)
  jg     L1
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L29
L1:
  mov    -0x4(%rbp),%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 97 && c <= 122)
    return (c - 32);
  return (c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 97 && c <= 122)
    return (c - 32);
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 97 && c <= 122)
    return (c - 32);
  return (c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int ft_toupper(int c) {
  if (c >= 97 && c <= 122)
    return (c - 32);
  return (c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0xd,%edi
  call   <putc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void newline() {
  putc(10);
  putc(13);
}
```
user: What is the c source code of the assembly code below:

```asm
<newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0xd,%edi
  call   <putc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void newline() {
  putc(10);
  putc(13);
}
```
user: What is the c source code of the assembly code below?

```asm
<newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0xd,%edi
  add    $0x8,%rsp
  jmp    1050 <putc@plt>
```

assistant: ```c
void newline() {
  putc(10);
  putc(13);
}
```
user: Translate the below assembly code into C programming language:

```asm
<newline>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0xd,%edi
  add    $0x8,%rsp
  jmp    1050 <putc@plt>
```

assistant: ```c
void newline() {
  putc(10);
  putc(13);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fprint_boolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  je     L33
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprint_invalid@plt>
  jmp    L5
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L5
L22:
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D7: TRUE

tool: D3: FALSE

assistant: ```c
void fprint_boolean(FILE *f, unsigned char *p, unsigned char *e) {
  if (p != e - 1) {
    fprint_invalid(f, p, e);
    return;
  } else if (*p)
    fprintf(f, "TRUE");
  else
    fprintf(f, "FALSE");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fprint_boolean>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x1(%rdx),%rax
  cmp    %rax,%rsi
  jne    L13
  cmpb   $0x0,(%rsi)
  je     L32
  lea    D2(%rip),%rsi
  call   <fprintf@plt>
  jmp    L23
L13:
  call   <fprint_invalid@plt>
L23:
  add    $0x8,%rsp
  ret
L32:
  lea    D1(%rip),%rsi
  call   <fprintf@plt>
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D2: TRUE

tool: D1: FALSE

assistant: ```c
void fprint_boolean(FILE *f, unsigned char *p, unsigned char *e) {
  if (p != e - 1) {
    fprint_invalid(f, p, e);
    return;
  } else if (*p)
    fprintf(f, "TRUE");
  else
    fprintf(f, "FALSE");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fprint_boolean>:
  endbr64
  lea    -0x1(%rdx),%rax
  cmp    %rax,%rsi
  jne    L9
  cmpb   $0x0,(%rsi)
  je     L13
  lea    D7(%rip),%rsi
  jmp    1070 <fprintf@plt>
  xchg   %ax,%ax
L13:
  lea    D1(%rip),%rsi
  jmp    1070 <fprintf@plt>
  nopl   0x0(%rax)
L9:
  jmp    1060 <fprint_invalid@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D7: TRUE

tool: D1: FALSE

assistant: ```c
void fprint_boolean(FILE *f, unsigned char *p, unsigned char *e) {
  if (p != e - 1) {
    fprint_invalid(f, p, e);
    return;
  } else if (*p)
    fprintf(f, "TRUE");
  else
    fprintf(f, "FALSE");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fprint_boolean>:
  endbr64
  lea    -0x1(%rdx),%rax
  cmp    %rax,%rsi
  jne    L2
  cmpb   $0x0,(%rsi)
  je     L19
  lea    D8(%rip),%rsi
  jmp    1070 <fprintf@plt>
  xchg   %ax,%ax
L19:
  lea    D7(%rip),%rsi
  jmp    1070 <fprintf@plt>
  nopl   0x0(%rax)
L2:
  jmp    1060 <fprint_invalid@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D8: TRUE

tool: D7: FALSE

assistant: ```c
void fprint_boolean(FILE *f, unsigned char *p, unsigned char *e) {
  if (p != e - 1) {
    fprint_invalid(f, p, e);
    return;
  } else if (*p)
    fprintf(f, "TRUE");
  else
    fprintf(f, "FALSE");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_file_name_to_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D2: Escriba el nombre del archivo a eliminar: 

tool: D19: %s

assistant: ```c
char *get_file_name_to_delete(char *filename_list) {
  printf("%s\n", filename_list);
  printf("Escriba el nombre del archivo a eliminar: ");
  char *name = (char *)malloc(sizeof(char) * 30);
  scanf("%s", name);
  return name;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_file_name_to_delete>:
  endbr64
  push   %rbx
  call   <puts@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D12: Escriba el nombre del archivo a eliminar: 

tool: D15: %s

assistant: ```c
char *get_file_name_to_delete(char *filename_list) {
  printf("%s\n", filename_list);
  printf("Escriba el nombre del archivo a eliminar: ");
  char *name = (char *)malloc(sizeof(char) * 30);
  scanf("%s", name);
  return name;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_file_name_to_delete>:
  endbr64
  push   %r12
  call   <puts@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <malloc@plt>
  lea    D17(%rip),%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string
name: unpack_data
arguments: tag: D17
type_infered: string

tool: D7: Escriba el nombre del archivo a eliminar: 

tool: D17: %s

assistant: ```c
char *get_file_name_to_delete(char *filename_list) {
  printf("%s\n", filename_list);
  printf("Escriba el nombre del archivo a eliminar: ");
  char *name = (char *)malloc(sizeof(char) * 30);
  scanf("%s", name);
  return name;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_file_name_to_delete>:
  endbr64
  push   %r12
  call   <puts@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <malloc@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D6
type: string

tool: D2: Escriba el nombre del archivo a eliminar: 

tool: D6: %s

assistant: ```c
char *get_file_name_to_delete(char *filename_list) {
  printf("%s\n", filename_list);
  printf("Escriba el nombre del archivo a eliminar: ");
  char *name = (char *)malloc(sizeof(char) * 30);
  scanf("%s", name);
  return name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L52:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  sub    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L52
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L46:
  mov    -0xc(%rbp),%eax
  imul   -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L61:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L46
  mov    -0x8(%rbp),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  push   $0x0
  push   $0x0
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    0x10(%rbp),%rcx
  mov    %rax,%rdi
  call   <do_recurse@plt>
  add    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L69:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L71
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3,%al
  je     L71
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  imul   -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  movl   $0x1,-0x4(%rbp)
L71:
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L69
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int do_row(unsigned char *known, unsigned char *deduced, unsigned char *row, unsigned char *start, int len, int step, int *data) {
  int rowlen, i, freespace, done_any;
  freespace = len + 1;
  for (rowlen = 0; data[rowlen]; rowlen++)
    freespace -= data[rowlen] + 1;
  for (i = 0; i < len; i++) {
    known[i] = start[i * step];
    deduced[i] = 0;
  }
  do_recurse(known, deduced, row, data, len, freespace, 0, 0);
  done_any = 0;
  for (i = 0; i < len; i++)
    if (deduced[i] && deduced[i] != 3 && !known[i]) {
      start[i * step] = deduced[i];
      done_any = 1;
    }
  return done_any;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_row>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%r13
  mov    %r9d,%r12d
  mov    0x30(%rsp),%rcx
  lea    0x1(%r8),%r9d
  mov    (%rcx),%eax
  test   %eax,%eax
  je     L82
  lea    0x4(%rcx),%rdx
L42:
  add    $0x1,%eax
  sub    %eax,%r9d
  add    $0x4,%rdx
  mov    -0x4(%rdx),%eax
  test   %eax,%eax
  jne    L42
L82:
  test   %r8d,%r8d
  jle    L26
  movslq %r12d,%r10
  mov    %r13,%rdx
  mov    %r8d,%r14d
  mov    $0x0,%eax
L0:
  movzbl (%rdx),%edi
  mov    %dil,0x0(%rbp,%rax,1)
  movb   $0x0,(%rbx,%rax,1)
  add    $0x1,%rax
  add    %r10,%rdx
  cmp    %r14,%rax
  jne    L0
  push   $0x0
  push   $0x0
  mov    %rsi,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <do_recurse@plt>
  add    $0x10,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%eax
  mov    $0x0,%esi
  mov    $0x1,%edi
  jmp    L37
L88:
  add    $0x1,%rax
  add    %r12d,%ecx
  cmp    %r14,%rax
  je     L22
L37:
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L88
  cmp    $0x3,%dl
  je     L88
  cmpb   $0x0,0x0(%rbp,%rax,1)
  jne    L88
  movslq %ecx,%rsi
  mov    %dl,0x0(%r13,%rsi,1)
  mov    %edi,%esi
  jmp    L88
L26:
  push   $0x0
  push   $0x0
  mov    %rsi,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <do_recurse@plt>
  add    $0x10,%rsp
  mov    $0x0,%esi
L22:
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int do_row(unsigned char *known, unsigned char *deduced, unsigned char *row, unsigned char *start, int len, int step, int *data) {
  int rowlen, i, freespace, done_any;
  freespace = len + 1;
  for (rowlen = 0; data[rowlen]; rowlen++)
    freespace -= data[rowlen] + 1;
  for (i = 0; i < len; i++) {
    known[i] = start[i * step];
    deduced[i] = 0;
  }
  do_recurse(known, deduced, row, data, len, freespace, 0, 0);
  done_any = 0;
  for (i = 0; i < len; i++)
    if (deduced[i] && deduced[i] != 3 && !known[i]) {
      start[i * step] = deduced[i];
      done_any = 1;
    }
  return done_any;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_row>:
  endbr64
  push   %r14
  mov    %rdx,%r10
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    0x30(%rsp),%rcx
  mov    %r9d,%ebx
  lea    0x1(%r8),%r9d
  mov    (%rcx),%eax
  test   %eax,%eax
  je     L1
  lea    0x4(%rcx),%rdx
  xchg   %ax,%ax
L37:
  add    $0x1,%eax
  add    $0x4,%rdx
  sub    %eax,%r9d
  mov    -0x4(%rdx),%eax
  test   %eax,%eax
  jne    L37
L1:
  test   %r8d,%r8d
  jle    L73
  movslq %ebx,%rdi
  mov    %r12,%rdx
  movslq %r8d,%r14
  xor    %eax,%eax
  nopl   (%rax)
L77:
  movzbl (%rdx),%esi
  add    %rdi,%rdx
  mov    %sil,0x0(%r13,%rax,1)
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %r14,%rax
  jne    L77
  push   $0x0
  mov    %rbp,%rsi
  mov    %r10,%rdx
  mov    %r13,%rdi
  push   $0x0
  call   <do_recurse@plt>
  pop    %rcx
  xor    %eax,%eax
  pop    %rsi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L50:
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  je     L11
  cmp    $0x3,%dl
  je     L11
  cmpb   $0x0,0x0(%r13,%rax,1)
  jne    L11
  movslq %ecx,%rsi
  mov    $0x1,%r8d
  mov    %dl,(%r12,%rsi,1)
L11:
  add    $0x1,%rax
  add    %ebx,%ecx
  cmp    %r14,%rax
  jne    L50
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  push   $0x0
  mov    %r10,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  push   $0x0
  call   <do_recurse@plt>
  xor    %r8d,%r8d
  pop    %rax
  pop    %rdx
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int do_row(unsigned char *known, unsigned char *deduced, unsigned char *row, unsigned char *start, int len, int step, int *data) {
  int rowlen, i, freespace, done_any;
  freespace = len + 1;
  for (rowlen = 0; data[rowlen]; rowlen++)
    freespace -= data[rowlen] + 1;
  for (i = 0; i < len; i++) {
    known[i] = start[i * step];
    deduced[i] = 0;
  }
  do_recurse(known, deduced, row, data, len, freespace, 0, 0);
  done_any = 0;
  for (i = 0; i < len; i++)
    if (deduced[i] && deduced[i] != 3 && !known[i]) {
      start[i * step] = deduced[i];
      done_any = 1;
    }
  return done_any;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CompileICMPacket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edi
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <CompileIPhdr@plt>
  lea    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0xfff7,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x40(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int CompileICMPacket(char *soAddr, char *dAddr, u_char *rPckt) {
  struct iphdr ip;
  struct icmphdr icmp;
  u_char *packet;
  packet = (u_char *)malloc(sizeof(struct iphdr) + sizeof(struct icmp));
  memset(packet, 0, sizeof(packet));
  memset(&icmp, 0, sizeof(icmp));
  CompileIPhdr(&ip, soAddr, dAddr, IPPROTO_ICMP, getpid());
  memcpy(packet, &ip, sizeof(ip));
  memset(&icmp, 0, sizeof(icmp));
  icmp.type = ICMP_ECHO;
  icmp.checksum = 0xfff7;
  memcpy(packet + sizeof(struct iphdr), &icmp, sizeof(icmp));
  memcpy(rPckt, packet, sizeof(struct iphdr) + sizeof(struct icmp));
  free(packet);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CompileICMPacket>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%r12
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%r8d
  lea    0x8(%rsp),%r15
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <CompileIPhdr@plt>
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  movl   $0xfff7,0x10(%rsp)
  lea    0x40(%rbx),%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    $0xc,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x1,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CompileICMPacket(char *soAddr, char *dAddr, u_char *rPckt) {
  struct iphdr ip;
  struct icmphdr icmp;
  u_char *packet;
  packet = (u_char *)malloc(sizeof(struct iphdr) + sizeof(struct icmp));
  memset(packet, 0, sizeof(packet));
  memset(&icmp, 0, sizeof(icmp));
  CompileIPhdr(&ip, soAddr, dAddr, IPPROTO_ICMP, getpid());
  memcpy(packet, &ip, sizeof(ip));
  memset(&icmp, 0, sizeof(icmp));
  icmp.type = ICMP_ECHO;
  icmp.checksum = 0xfff7;
  memcpy(packet + sizeof(struct iphdr), &icmp, sizeof(icmp));
  memcpy(rPckt, packet, sizeof(struct iphdr) + sizeof(struct icmp));
  free(packet);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CompileICMPacket>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  mov    $0xc,%edi
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%rbx
  call   <malloc@plt>
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memset@plt>
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %eax,%r8d
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  call   <CompileIPhdr@plt>
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D1(%rip),%rax
  lea    0x40(%rbp),%rdi
  mov    %r13,%rsi
  mov    $0x8,%edx
  movl   $0xfff7,0x10(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <memcpy@plt>
  mov    %r12,%rdi
  mov    $0xc,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CompileICMPacket(char *soAddr, char *dAddr, u_char *rPckt) {
  struct iphdr ip;
  struct icmphdr icmp;
  u_char *packet;
  packet = (u_char *)malloc(sizeof(struct iphdr) + sizeof(struct icmp));
  memset(packet, 0, sizeof(packet));
  memset(&icmp, 0, sizeof(icmp));
  CompileIPhdr(&ip, soAddr, dAddr, IPPROTO_ICMP, getpid());
  memcpy(packet, &ip, sizeof(ip));
  memset(&icmp, 0, sizeof(icmp));
  icmp.type = ICMP_ECHO;
  icmp.checksum = 0xfff7;
  memcpy(packet + sizeof(struct iphdr), &icmp, sizeof(icmp));
  memcpy(rPckt, packet, sizeof(struct iphdr) + sizeof(struct icmp));
  free(packet);
  return 1;
}
```