ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fftw_find_generator>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x1,%r12d
  cmp    $0x2,%edi
  je     L15
  mov    %edi,%r13d
  lea    -0x1(%rdi),%ebp
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <get_prime_factors@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L13
  mov    $0x0,%ebx
  mov    $0x2,%r12d
  jmp    L31
L27:
  add    $0x1,%r12d
  mov    $0x0,%ebx
L31:
  movslq %ebx,%rcx
  mov    %ebp,%eax
  cltd
  idivl  (%rsp,%rcx,4)
  mov    %eax,%esi
  mov    %r13d,%edx
  mov    %r12d,%edi
  call   <fftw_power_mod@plt>
  cmp    $0x1,%eax
  je     L27
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jg     L31
L15:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %r12d,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0x2,%r12d
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fftw_find_generator(int p) {
  int n, i, size;
  int primef[16];
  int pm1 = p - 1;
  if (p == 2)
    return 1;
  size = get_prime_factors(pm1, primef);
  n = 2;
  for (i = 0; i < size; i++)
    if (fftw_power_mod(n, pm1 / primef[i], p) == 1) {
      i = -1;
      n++;
    }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fftw_find_generator>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L40
  lea    -0x1(%rdi),%r12d
  mov    %edi,%ebp
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <get_prime_factors@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L20
  xor    %ebx,%ebx
  mov    $0x2,%r13d
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r12d,%eax
  movslq %ebx,%rcx
  mov    %r13d,%edi
  cltd
  idivl  (%rsp,%rcx,4)
  mov    %ebp,%edx
  mov    %eax,%esi
  call   <fftw_power_mod@plt>
  cmp    $0x1,%eax
  je     L66
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jg     L43
L40:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x50,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  add    $0x1,%r13d
  xor    %ebx,%ebx
  jmp    L43
L20:
  mov    $0x2,%r13d
  jmp    L40
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fftw_find_generator(int p) {
  int n, i, size;
  int primef[16];
  int pm1 = p - 1;
  if (p == 2)
    return 1;
  size = get_prime_factors(pm1, primef);
  n = 2;
  for (i = 0; i < size; i++)
    if (fftw_power_mod(n, pm1 / primef[i], p) == 1) {
      i = -1;
      n++;
    }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fftw_find_generator>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L55
  lea    -0x1(%rdi),%r12d
  mov    %edi,%ebp
  mov    %rsp,%rsi
  mov    %r12d,%edi
  call   <get_prime_factors@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L66
  xor    %ebx,%ebx
  mov    $0x2,%r13d
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r12d,%eax
  movslq %ebx,%rcx
  mov    %r13d,%edi
  cltd
  idivl  (%rsp,%rcx,4)
  mov    %ebp,%edx
  mov    %eax,%esi
  call   <fftw_power_mod@plt>
  cmp    $0x1,%eax
  je     L48
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jg     L43
L55:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x50,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x1,%r13d
  xor    %ebx,%ebx
  jmp    L43
L66:
  mov    $0x2,%r13d
  jmp    L55
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fftw_find_generator(int p) {
  int n, i, size;
  int primef[16];
  int pm1 = p - 1;
  if (p == 2)
    return 1;
  size = get_prime_factors(pm1, primef);
  n = 2;
  for (i = 0; i < size; i++)
    if (fftw_power_mod(n, pm1 / primef[i], p) == 1) {
      i = -1;
      n++;
    }
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<ResetISR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MD4_Final>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0x30(%rsi),%r12
  mov    (%rsi),%rdi
  movb   $0x80,(%r12,%rdi,1)
  add    $0x1,%rdi
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  lea    -0x8(%rdx),%eax
  cltq
  cmp    %rdi,%rax
  jb     L6
L11:
  mov    D1(%rip),%r13
  mov    0x0(%r13),%eax
  lea    -0x8(%rax),%edx
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  movslq 0x0(%r13),%rax
  lea    -0x8(%r12,%rax,1),%rax
  mov    0x8(%rbx),%edx
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  mov    %edx,0x4(%rax)
  lea    0x8(%rax),%r12
  movslq 0x0(%r13),%rax
  sub    %rax,%r12
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <md4_block_data_order@plt>
  movq   $0x0,(%rbx)
  mov    0x0(%r13),%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%rbp)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%rbp)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%rbp)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%rbp)
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  sub    %edi,%edx
  add    %r12,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <md4_block_data_order@plt>
  mov    $0x0,%edi
  jmp    L11
```

assistant: ```c
int MD4_Final(unsigned char *md, MD4_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD4_CBLOCK - 8)) {
    memset(p + n, 0, MD4_CBLOCK - n);
    n = 0;
    md4_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD4_CBLOCK - 8 - n);
  p += MD4_CBLOCK - 8;
  (*((unsigned int *)(p)) = (c->Nl), (p) += 4);
  (*((unsigned int *)(p)) = (c->Nh), (p) += 4);
  p -= MD4_CBLOCK;
  md4_block_data_order(c, p, 1);
  c->num = 0;
  memset(p, 0, MD4_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
  } while (0);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MD4_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x30(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D8(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L0
L14:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <md4_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  movq   $0x0,(%rbx)
  call   <memset@plt>
  mov    0x10(%rbx),%rax
  mov    %eax,0x0(%r13)
  mov    0x18(%rbx),%rax
  mov    %eax,0x4(%r13)
  mov    0x20(%rbx),%rax
  mov    %eax,0x8(%r13)
  mov    0x28(%rbx),%rax
  mov    %eax,0xc(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <md4_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L14
```

assistant: ```c
int MD4_Final(unsigned char *md, MD4_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD4_CBLOCK - 8)) {
    memset(p + n, 0, MD4_CBLOCK - n);
    n = 0;
    md4_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD4_CBLOCK - 8 - n);
  p += MD4_CBLOCK - 8;
  (*((unsigned int *)(p)) = (c->Nl), (p) += 4);
  (*((unsigned int *)(p)) = (c->Nh), (p) += 4);
  p -= MD4_CBLOCK;
  md4_block_data_order(c, p, 1);
  c->num = 0;
  memset(p, 0, MD4_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
  } while (0);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<MD4_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x30(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D3(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L11
L9:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <md4_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  movq   $0x0,(%rbx)
  call   <memset@plt>
  movdqu 0x10(%rbx),%xmm0
  movdqu 0x20(%rbx),%xmm1
  mov    $0x1,%eax
  shufps $0x88,%xmm1,%xmm0
  movups %xmm0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <md4_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L9
```

assistant: ```c
int MD4_Final(unsigned char *md, MD4_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD4_CBLOCK - 8)) {
    memset(p + n, 0, MD4_CBLOCK - n);
    n = 0;
    md4_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD4_CBLOCK - 8 - n);
  p += MD4_CBLOCK - 8;
  (*((unsigned int *)(p)) = (c->Nl), (p) += 4);
  (*((unsigned int *)(p)) = (c->Nh), (p) += 4);
  p -= MD4_CBLOCK;
  md4_block_data_order(c, p, 1);
  c->num = 0;
  memset(p, 0, MD4_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
  } while (0);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strzcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L7
L24:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L65
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L65:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    $0x0,%eax
  jmp    L63
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L9
  mov    $0xffffffff,%eax
  jmp    L63
L9:
  mov    $0x1,%eax
L63:
  pop    %rbp
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  test   %dl,%dl
  je     L4
  cmp    %cl,%dl
  jne    L4
  mov    $0x1,%eax
L37:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  je     L4
  cmp    %cl,%dl
  je     L37
L4:
  mov    $0x0,%eax
  test   %cl,%cl
  je     L44
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L44:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L10
  jmp    L34
  nopl   (%rax)
L46:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L34
L10:
  test   %dl,%dl
  jne    L46
L34:
  xor    %eax,%eax
  test   %cl,%cl
  je     L45
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L45:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strzcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L9
  jmp    L10
  nopl   (%rax)
L44:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L10
L9:
  test   %dl,%dl
  jne    L44
L10:
  xor    %eax,%eax
  test   %cl,%cl
  je     L22
  cmp    %cl,%dl
  sbb    %eax,%eax
  or     $0x1,%eax
L22:
  ret
```

assistant: ```c
int strzcmp(const char *s1, const char *s2) {
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Print_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D15: %s:


tool: D25: %d 

tool: D5: 


assistant: ```c
void Print_list(int a[], int n, char *title) {
  int i;
  printf("%s:\n", title);
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Print_list>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L9
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D6(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
L9:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type: string
name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D28: %s:


tool: D6: %d 

tool: D16: 


assistant: ```c
void Print_list(int a[], int n, char *title) {
  int i;
  printf("%s:\n", title);
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Print_list>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L17
  lea    -0x1(%rbp),%eax
  lea    D13(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
L17:
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string

tool: D2: %s:


tool: D13: %d 

tool: D23: 


assistant: ```c
void Print_list(int a[], int n, char *title) {
  int i;
  printf("%s:\n", title);
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print_list>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L4
  lea    -0x1(%rbp),%eax
  lea    D14(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
L4:
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D8: %s:


tool: D14: %d 

tool: D3: 


assistant: ```c
void Print_list(int a[], int n, char *title) {
  int i;
  printf("%s:\n", title);
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<NMI320_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <npm_isdbt_init@plt>
  test   %rax,%rax
  jle    L16
  mov    $0x1,%eax
  jmp    L1
L16:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
char NMI320_init() {
  if (npm_isdbt_init() > 0)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NMI320_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <npm_isdbt_init@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char NMI320_init() {
  if (npm_isdbt_init() > 0)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NMI320_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <npm_isdbt_init@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char NMI320_init() {
  if (npm_isdbt_init() > 0)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<NMI320_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <npm_isdbt_init@plt>
  test   %rax,%rax
  setg   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char NMI320_init() {
  if (npm_isdbt_init() > 0)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<osmType_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jne    L47
  lea    D1(%rip),%rax
  jmp    L25
L47:
  lea    D37(%rip),%rax
L25:
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ParseXML_Encode_Safe_XML@plt>
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L10:
  cmpq   $0x0,-0x20(%rbp)
  je     L57
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ParseXML_Encode_Safe_XML@plt>
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  cmpl   $0x3,-0xc(%rbp)
  jne    L39
  lea    D7(%rip),%rax
  jmp    L1
L39:
  lea    D37(%rip),%rax
L1:
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string
name: extract_symbolic_data
arguments: label: D37
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D22
type_infered: string
name: extract_symbolic_data
arguments: label: D16
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D66
type_infered: string

tool: D1: /

tool: 

tool: D12: <%s%s

tool: D22:  version="%s"

tool: D16:  generator="%s"

tool: D7:  /

tool: D66: %s>


assistant: ```c
int osmType_function(const char *_tag_, int _type_, const char *version, const char *generator) {
  printf("<%s%s", (_type_ == 2) ? "/" : "", _tag_);
  if (version)
    printf(" version=\"%s\"", ParseXML_Encode_Safe_XML(version));
  if (generator)
    printf(" generator=\"%s\"", ParseXML_Encode_Safe_XML(generator));
  printf("%s>\n", (_type_ == (1 | 2)) ? " /" : "");
  return (0);
}
```