ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<display>:
  endbr64
  push   %r13
  lea    0x50(%rdi),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    0x10(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L13:
  lea    -0x10(%rbp),%rbx
L1:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
  mov    $0xa,%edi
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: %d 

assistant: ```c
void display(int matrix[4][4]) {
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      printf("%d ", matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0xc(%rbp),%eax
  jmp    L2
L14:
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int findString(char *to_find, char *where_to_look) {
  int result = -1;
  char *ptstr;
  ptstr = strstr(where_to_look, to_find);
  if (ptstr == NULL) {
    return result;
  }
  result = ptstr - where_to_look;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findString>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  sub    %ebx,%eax
L19:
  pop    %rbx
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int findString(char *to_find, char *where_to_look) {
  int result = -1;
  char *ptstr;
  ptstr = strstr(where_to_look, to_find);
  if (ptstr == NULL) {
    return result;
  }
  result = ptstr - where_to_look;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findString>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L8
  sub    %ebx,%eax
  pop    %rbx
  ret
L8:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int findString(char *to_find, char *where_to_look) {
  int result = -1;
  char *ptstr;
  ptstr = strstr(where_to_look, to_find);
  if (ptstr == NULL) {
    return result;
  }
  result = ptstr - where_to_look;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findString>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L6
  sub    %ebx,%eax
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int findString(char *to_find, char *where_to_look) {
  int result = -1;
  char *ptstr;
  ptstr = strstr(where_to_look, to_find);
  if (ptstr == NULL) {
    return result;
  }
  result = ptstr - where_to_look;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  nop
L58:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fgetc@plt>
  cmp    $0x20,%al
  setne  %al
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  je     L94
  cmpb   $0xa,-0x5(%rbp)
  je     L94
  cmpb   $0x0,-0x5(%rbp)
  je     L94
  cmpb   $0x9,-0x5(%rbp)
  je     L58
L94:
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L61:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fgetc@plt>
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  cmpb   $0x20,-0x5(%rbp)
  je     L37
  cmpb   $0xa,-0x5(%rbp)
  je     L37
  cmpb   $0x0,-0x5(%rbp)
  je     L37
  cmpb   $0x9,-0x5(%rbp)
  je     L37
  addl   $0x1,-0x4(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L61
L37:
  movb   $0x0,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_word(int max_len, char *target) {
  char new_char;
  int i;
  while ((new_char = fgetc(stdin) != ' ') && (new_char != '\n') && (new_char != '\0') && (new_char == '\t'))
    ;
  for (i = 0; i < max_len - 1; i++) {
    new_char = (char)fgetc(stdin);
    ;
    target[i] = new_char;
    if ((new_char == ' ') || (new_char == '\n') || (new_char == '\0') || (new_char == '\t')) {
      break;
    }
  }
  new_char = '\0';
  target[i] = new_char;
  ;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <fgetc@plt>
  cmp    $0x1,%r12d
  jle    L0
  mov    %r14,%rbp
  sub    $0x1,%r12d
  mov    $0x0,%ebx
  mov    D18(%rip),%r13
L29:
  mov    0x0(%r13),%edi
  call   <fgetc@plt>
  mov    %al,0x0(%rbp)
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L47
  test   $0xdf,%al
  je     L47
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L29
  mov    %r12d,%ebx
L47:
  movslq %ebx,%rax
  movb   $0x0,(%r14,%rax,1)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  mov    $0x0,%ebx
  jmp    L47
```

assistant: ```c
int read_word(int max_len, char *target) {
  char new_char;
  int i;
  while ((new_char = fgetc(stdin) != ' ') && (new_char != '\n') && (new_char != '\0') && (new_char == '\t'))
    ;
  for (i = 0; i < max_len - 1; i++) {
    new_char = (char)fgetc(stdin);
    ;
    target[i] = new_char;
    if ((new_char == ' ') || (new_char == '\n') || (new_char == '\0') || (new_char == '\t')) {
      break;
    }
  }
  new_char = '\0';
  target[i] = new_char;
  ;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    D0(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    0x0(%rbp),%edi
  sub    $0x1,%ebx
  call   <fgetc@plt>
  test   %ebx,%ebx
  jle    L18
  mov    %r12,%r13
  xor    %r14d,%r14d
  nopl   (%rax)
L48:
  mov    0x0(%rbp),%edi
  call   <fgetc@plt>
  mov    %r13,%rdx
  lea    -0x9(%rax),%ecx
  mov    %al,0x0(%r13)
  cmp    $0x1,%cl
  jbe    L41
  test   $0xdf,%al
  je     L41
  add    $0x1,%r14d
  lea    0x1(%r13),%r13
  cmp    %ebx,%r14d
  jne    L48
  movslq %r14d,%rdx
  add    %r12,%rdx
L41:
  movb   $0x0,(%rdx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    %r12,%rdx
  xor    %r14d,%r14d
  jmp    L41
```

assistant: ```c
int read_word(int max_len, char *target) {
  char new_char;
  int i;
  while ((new_char = fgetc(stdin) != ' ') && (new_char != '\n') && (new_char != '\0') && (new_char == '\t'))
    ;
  for (i = 0; i < max_len - 1; i++) {
    new_char = (char)fgetc(stdin);
    ;
    target[i] = new_char;
    if ((new_char == ' ') || (new_char == '\n') || (new_char == '\0') || (new_char == '\t')) {
      break;
    }
  }
  new_char = '\0';
  target[i] = new_char;
  ;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_word>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    D9(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    0x0(%rbp),%edi
  sub    $0x1,%ebx
  call   <fgetc@plt>
  test   %ebx,%ebx
  jle    L5
  mov    %r12,%r13
  xor    %r14d,%r14d
  nopl   (%rax)
L14:
  mov    0x0(%rbp),%edi
  call   <fgetc@plt>
  mov    %r13,%rdx
  lea    -0x9(%rax),%ecx
  mov    %al,0x0(%r13)
  cmp    $0x1,%cl
  jbe    L38
  test   $0xdf,%al
  je     L38
  add    $0x1,%r14d
  lea    0x1(%r13),%r13
  cmp    %ebx,%r14d
  jne    L14
  movslq %r14d,%rdx
  add    %r12,%rdx
L38:
  movb   $0x0,(%rdx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %r12,%rdx
  xor    %r14d,%r14d
  jmp    L38
```

assistant: ```c
int read_word(int max_len, char *target) {
  char new_char;
  int i;
  while ((new_char = fgetc(stdin) != ' ') && (new_char != '\n') && (new_char != '\0') && (new_char == '\t'))
    ;
  for (i = 0; i < max_len - 1; i++) {
    new_char = (char)fgetc(stdin);
    ;
    target[i] = new_char;
    if ((new_char == ' ') || (new_char == '\n') || (new_char == '\0') || (new_char == '\t')) {
      break;
    }
  }
  new_char = '\0';
  target[i] = new_char;
  ;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<checkthat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%ebx
  movslq %ebx,%rax
  movzbl (%rdi,%rax,1),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L45
  cmp    $0x20,%al
  jne    L5
L45:
  lea    0x1(%rbx),%eax
  cltq
L33:
  mov    %eax,%ebx
  mov    %eax,0x0(%rbp)
  movzbl (%r12,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L33
  cmp    $0x20,%dl
  je     L33
L5:
  mov    0x0(%rbp),%eax
  add    $0x1,%eax
  cltq
L60:
  mov    %eax,%edi
  mov    %eax,0x0(%rbp)
  movzbl (%r12,%rax,1),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L53
  cmp    $0x9,%dl
  jne    L60
L53:
  sub    %ebx,%edi
  add    $0x1,%edi
  call   <ft_memalloc@plt>
  mov    %rax,(%rsp)
  mov    %ebx,0x0(%rbp)
  movslq %ebx,%rax
  add    %r12,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L39
  cmp    $0x9,%dl
  je     L39
  mov    $0x0,%edx
L1:
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  lea    0x1(%rdx),%esi
  movzbl (%rax),%ecx
  mov    (%rsp),%rax
  mov    %cl,(%rax,%rdx,1)
  mov    0x0(%rbp),%ebx
  movslq %ebx,%rax
  add    %r12,%rax
  movzbl (%rax),%ecx
  add    $0x1,%rdx
  test   $0xdf,%cl
  je     L11
  cmp    $0x9,%cl
  jne    L1
L11:
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  movslq %esi,%rsi
  mov    (%rsp),%rax
  movb   $0x0,(%rax,%rsi,1)
  mov    %r13,%rsi
  mov    (%rsp),%rdi
  call   <ft_strcmp@plt>
  test   %rax,%rax
  je     L99
  mov    %rsp,%rdi
  call   <ft_memdel@plt>
  cmpb   $0x6e,0x1(%r13)
  sete   %al
  movzbl %al,%eax
  add    $0x1,%eax
L50:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%esi
  jmp    L11
L99:
  mov    %rsp,%rdi
  call   <ft_memdel@plt>
  mov    $0x0,%eax
  jmp    L50
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkthat(char *buff, int *i, int save, char *find) {
  char *name;
  while (buff[i[0]] == ' ' || buff[i[0]] == '\t' || buff[i[0]] == '\n')
    (*i)++;
  save = i[0];
  while (buff[i[0]] != ' ' && buff[i[0]] != '\t')
    (*i)++;
  name = (char *)ft_memalloc(sizeof(char) * ((i[0] - save) + 1));
  i[0] = save;
  save = 0;
  while (buff[*i] && buff[i[0]] != ' ' && buff[i[0]] != '\t')
    name[save++] = buff[i[0]++];
  i[0]++;
  name[save] = '\0';
  if ((ft_strcmp(name, find)) != 0) {
    ft_memdel((void **)&name);
    if (find[1] == 'n')
      return (2);
    return (1);
  }
  ft_memdel((void **)&name);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checkthat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq (%rsi),%rax
  lea    (%rdi,%rax,1),%rbp
  mov    %rax,%rbx
  movzbl 0x0(%rbp),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L134
  cmp    $0x20,%dl
  jne    L24
L134:
  lea    0x1(%r14,%rax,1),%rax
  lea    0x1(%rbx),%esi
  sub    %eax,%esi
L54:
  lea    (%rsi,%rax,1),%ebx
  mov    %rax,%rbp
  add    $0x1,%rax
  mov    %ebx,(%r12)
  movzbl -0x1(%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L54
  cmp    $0x20,%dl
  je     L54
L24:
  lea    0x1(%rbx),%r15d
  movslq %r15d,%rax
  cs nopw 0x0(%rax,%rax,1)
L86:
  mov    %eax,(%r12)
  movzbl (%r14,%rax,1),%edx
  mov    %eax,%edi
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L132
  cmp    $0x9,%dl
  jne    L86
L132:
  sub    %ebx,%edi
  add    $0x1,%edi
  call   <ft_memalloc@plt>
  mov    %ebx,(%r12)
  movzbl 0x0(%rbp),%edx
  mov    %rax,(%rsp)
  test   $0xdf,%dl
  je     L20
  cmp    $0x9,%dl
  je     L20
  xor    %edx,%edx
  jmp    L11
  nopl   (%rax)
L39:
  cmp    $0x9,%al
  je     L61
  mov    (%rsp),%rax
  lea    0x1(%rbx),%r15d
L11:
  mov    %r15d,(%r12)
  movzbl 0x0(%rbp),%ecx
  lea    0x1(%rdx),%esi
  mov    %cl,(%rax,%rdx,1)
  movslq (%r12),%rbp
  add    $0x1,%rdx
  mov    %rbp,%rbx
  add    %r14,%rbp
  movzbl 0x0(%rbp),%eax
  test   $0xdf,%al
  jne    L39
L61:
  movslq %esi,%rax
  lea    0x1(%rbx),%r15d
  add    (%rsp),%rax
L20:
  mov    %r15d,(%r12)
  mov    %r13,%rsi
  movb   $0x0,(%rax)
  mov    (%rsp),%rdi
  call   <ft_strcmp@plt>
  mov    %rsp,%rdi
  test   %rax,%rax
  je     L21
  call   <ft_memdel@plt>
  xor    %eax,%eax
  cmpb   $0x6e,0x1(%r13)
  sete   %al
  add    $0x1,%eax
L78:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  call   <ft_memdel@plt>
  xor    %eax,%eax
  jmp    L78
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkthat(char *buff, int *i, int save, char *find) {
  char *name;
  while (buff[i[0]] == ' ' || buff[i[0]] == '\t' || buff[i[0]] == '\n')
    (*i)++;
  save = i[0];
  while (buff[i[0]] != ' ' && buff[i[0]] != '\t')
    (*i)++;
  name = (char *)ft_memalloc(sizeof(char) * ((i[0] - save) + 1));
  i[0] = save;
  save = 0;
  while (buff[*i] && buff[i[0]] != ' ' && buff[i[0]] != '\t')
    name[save++] = buff[i[0]++];
  i[0]++;
  name[save] = '\0';
  if ((ft_strcmp(name, find)) != 0) {
    ft_memdel((void **)&name);
    if (find[1] == 'n')
      return (2);
    return (1);
  }
  ft_memdel((void **)&name);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checkthat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq (%rsi),%rax
  lea    (%rdi,%rax,1),%r14
  mov    %rax,%rbx
  movzbl (%r14),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L123
  cmp    $0x20,%dl
  jne    L67
L123:
  lea    0x1(%r13,%rax,1),%rax
  lea    0x1(%rbx),%esi
  sub    %eax,%esi
L87:
  lea    (%rsi,%rax,1),%ebx
  mov    %rax,%r14
  add    $0x1,%rax
  mov    %ebx,0x0(%rbp)
  movzbl -0x1(%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L87
  cmp    $0x20,%dl
  je     L87
L67:
  lea    0x1(%rbx),%r15d
  movslq %r15d,%rax
  nopl   (%rax)
L135:
  mov    %eax,0x0(%rbp)
  movzbl 0x0(%r13,%rax,1),%edx
  mov    %eax,%edi
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L23
  cmp    $0x9,%dl
  jne    L135
L23:
  sub    %ebx,%edi
  add    $0x1,%edi
  call   <ft_memalloc@plt>
  mov    %ebx,0x0(%rbp)
  movzbl (%r14),%edx
  mov    %rax,(%rsp)
  mov    %rax,%rsi
  test   $0xdf,%dl
  je     L96
  cmp    $0x9,%dl
  je     L96
  mov    %r15d,0x0(%rbp)
  movzbl (%r14),%edx
  mov    %dl,(%rax)
  movslq 0x0(%rbp),%rax
  mov    %rax,%rbx
  add    %r13,%rax
  movzbl (%rax),%ecx
  test   $0xdf,%cl
  je     L91
  mov    $0x1,%edx
  cmp    $0x9,%cl
  jne    L25
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L126:
  cmp    $0x9,%cl
  je     L58
L25:
  add    $0x1,%ebx
  lea    0x1(%rdx),%esi
  mov    %ebx,0x0(%rbp)
  movzbl (%rax),%ecx
  mov    (%rsp),%rax
  mov    %cl,(%rax,%rdx,1)
  movslq 0x0(%rbp),%rax
  add    $0x1,%rdx
  mov    %rax,%rbx
  add    %r13,%rax
  movzbl (%rax),%ecx
  test   $0xdf,%cl
  jne    L126
L58:
  movslq %esi,%rsi
  lea    0x1(%rbx),%r15d
  add    (%rsp),%rsi
L96:
  mov    %r15d,0x0(%rbp)
  movb   $0x0,(%rsi)
  mov    (%rsp),%rdi
  mov    %r12,%rsi
  call   <ft_strcmp@plt>
  mov    %rsp,%rdi
  test   %rax,%rax
  je     L145
  call   <ft_memdel@plt>
  xor    %eax,%eax
  cmpb   $0x6e,0x1(%r12)
  sete   %al
  add    $0x1,%eax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L145:
  call   <ft_memdel@plt>
  xor    %eax,%eax
  jmp    L38
L91:
  mov    $0x1,%esi
  jmp    L58
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int checkthat(char *buff, int *i, int save, char *find) {
  char *name;
  while (buff[i[0]] == ' ' || buff[i[0]] == '\t' || buff[i[0]] == '\n')
    (*i)++;
  save = i[0];
  while (buff[i[0]] != ' ' && buff[i[0]] != '\t')
    (*i)++;
  name = (char *)ft_memalloc(sizeof(char) * ((i[0] - save) + 1));
  i[0] = save;
  save = 0;
  while (buff[*i] && buff[i[0]] != ' ' && buff[i[0]] != '\t')
    name[save++] = buff[i[0]++];
  i[0]++;
  name[save] = '\0';
  if ((ft_strcmp(name, find)) != 0) {
    ft_memdel((void **)&name);
    if (find[1] == 'n')
      return (2);
    return (1);
  }
  ft_memdel((void **)&name);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_PROCEDURE_LINKAGE_TABLE_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wait() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wait>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_PROCEDURE_LINKAGE_TABLE_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wait>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <_PROCEDURE_LINKAGE_TABLE_@plt>
```

assistant: ```c
void wait() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wait>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <_PROCEDURE_LINKAGE_TABLE_@plt>
```

assistant: ```c
void wait() {
  _PROCEDURE_LINKAGE_TABLE_();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<InterlockedExchange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long InterlockedExchange(long *p, long v) {
  long old = *p;
  *p = v;
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<InterlockedExchange>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
long InterlockedExchange(long *p, long v) {
  long old = *p;
  *p = v;
  return old;
}
```
user: What is the c source code of the assembly code below:

```asm
<InterlockedExchange>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
long InterlockedExchange(long *p, long v) {
  long old = *p;
  *p = v;
  return old;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<InterlockedExchange>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
long InterlockedExchange(long *p, long v) {
  long old = *p;
  *p = v;
  return old;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<destroy_all_readers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L28
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <waitpid@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <delete_temp_file@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L28:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  nop
  nop
  leave
  ret
```

assistant: ```c
void destroy_all_readers(int cpus, int *pid_array, const char *node, const char *port) {
  int cpu;
  for (cpu = 0; cpu < cpus; cpu++) {
    if (pid_array[cpu] > 0) {
      kill(pid_array[cpu], SIGKILL);
      waitpid(pid_array[cpu], NULL, 0);
      delete_temp_file(node, port, cpu);
      pid_array[cpu] = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_all_readers>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %edi,%r12d
  mov    $0x0,%ebx
  jmp    L12
L2:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L37
L12:
  mov    0x0(%rbp,%rbx,4),%edi
  test   %edi,%edi
  jle    L2
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <kill@plt>
  mov    0x0(%rbp,%rbx,4),%edi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <waitpid@plt>
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <delete_temp_file@plt>
  movl   $0x0,0x0(%rbp,%rbx,4)
  jmp    L2
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  ret
```

assistant: ```c
void destroy_all_readers(int cpus, int *pid_array, const char *node, const char *port) {
  int cpu;
  for (cpu = 0; cpu < cpus; cpu++) {
    if (pid_array[cpu] > 0) {
      kill(pid_array[cpu], SIGKILL);
      waitpid(pid_array[cpu], NULL, 0);
      delete_temp_file(node, port, cpu);
      pid_array[cpu] = 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<destroy_all_readers>:
  endbr64
  test   %edi,%edi
  jle    L29
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L23:
  mov    0x0(%rbp,%rbx,4),%edi
  test   %edi,%edi
  jle    L19
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <kill@plt>
  mov    0x0(%rbp,%rbx,4),%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <waitpid@plt>
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <delete_temp_file@plt>
  movl   $0x0,0x0(%rbp,%rbx,4)
L19:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L23
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  ret
```

assistant: ```c
void destroy_all_readers(int cpus, int *pid_array, const char *node, const char *port) {
  int cpu;
  for (cpu = 0; cpu < cpus; cpu++) {
    if (pid_array[cpu] > 0) {
      kill(pid_array[cpu], SIGKILL);
      waitpid(pid_array[cpu], NULL, 0);
      delete_temp_file(node, port, cpu);
      pid_array[cpu] = 0;
    }
  }
}
```