ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L22
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  jmp    L24
L22:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat st;
  if (stat(filename, &st) == 0)
    return S_ISDIR(st.st_mode);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L25
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L25:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L0
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat st;
  if (stat(filename, &st) == 0)
    return S_ISDIR(st.st_mode);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L2
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L2:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat st;
  if (stat(filename, &st) == 0)
    return S_ISDIR(st.st_mode);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_directory>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L21
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L21:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  jmp    L6
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_directory(const char *filename) {
  struct stat st;
  if (stat(filename, &st) == 0)
    return S_ISDIR(st.st_mode);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %rsi,-0x2030(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2028(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movl   $0x0,-0x2018(%rbp)
  jmp    L3
L0:
  movl   $0x0,-0x2014(%rbp)
  jmp    L16
L49:
  mov    -0x2014(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x2018(%rbp),%eax
  add    %eax,%edx
  mov    -0x2018(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x2014(%rbp),%eax
  add    %eax,%ecx
  movslq %edx,%rax
  movzbl -0x2010(%rbp,%rax,1),%edx
  movslq %ecx,%rax
  mov    %dl,-0x1010(%rbp,%rax,1)
  addl   $0x1,-0x2014(%rbp)
L16:
  cmpl   $0xf,-0x2014(%rbp)
  jle    L49
  addl   $0x1,-0x2018(%rbp)
L3:
  cmpl   $0xff,-0x2018(%rbp)
  jle    L0
  mov    -0x2030(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
void convert(FILE *fi, FILE *fo) {
  char inbuf[0x1000];
  char outbuf[0x1000];
  fread(inbuf, 0x1000, 1, fi);
  for (int c = 0; c < 256; ++c) {
    for (int l = 0; l < 16; ++l) {
      outbuf[c * 16 + l] = inbuf[c + 256 * l];
    }
  }
  fwrite(outbuf, 0x1000, 1, fo);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0x1000,%esi
  call   <fread@plt>
  lea    0x1000(%rsp),%r8
  mov    %r8,%rsi
  mov    $0x0,%edi
  jmp    L49
L11:
  add    $0x1,%edi
  add    $0x10,%r8
  add    $0x1,%rsi
  cmp    $0x100,%edi
  je     L36
L49:
  lea    -0x1000(%rsi),%rax
  mov    %r8,%rdx
L27:
  movzbl (%rax),%ecx
  mov    %cl,(%rdx)
  add    $0x100,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L27
  jmp    L11
L36:
  lea    0x1000(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x1000,%esi
  call   <fwrite@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x2010,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert(FILE *fi, FILE *fo) {
  char inbuf[0x1000];
  char outbuf[0x1000];
  fread(inbuf, 0x1000, 1, fi);
  for (int c = 0; c < 256; ++c) {
    for (int l = 0; l < 16; ++l) {
      outbuf[c * 16 + l] = inbuf[c + 256 * l];
    }
  }
  fwrite(outbuf, 0x1000, 1, fo);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert>:
  endbr64
  push   %r12
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rcx
  mov    %rsi,%r12
  mov    %rsp,%rdi
  mov    $0x1000,%esi
  call   <fread@plt>
  lea    0x1000(%rsp),%rdi
  xor    %r8d,%r8d
  mov    %rdi,%r9
  mov    %rdi,%rsi
  xchg   %ax,%ax
L24:
  lea    -0x1000(%rsi),%rax
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rax),%ecx
  add    $0x100,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L7
  add    $0x1,%r8d
  add    $0x10,%rdi
  lea    0x1(%rax),%rsi
  cmp    $0x100,%r8d
  jne    L24
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1000,%esi
  mov    %r9,%rdi
  call   <fwrite@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x2010,%rsp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert(FILE *fi, FILE *fo) {
  char inbuf[0x1000];
  char outbuf[0x1000];
  fread(inbuf, 0x1000, 1, fi);
  for (int c = 0; c < 256; ++c) {
    for (int l = 0; l < 16; ++l) {
      outbuf[c * 16 + l] = inbuf[c + 256 * l];
    }
  }
  fwrite(outbuf, 0x1000, 1, fo);
}
```
user: What is the c source code of the assembly code below:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L12
L25:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x8(%rbp),%rax
  jmp    L36
L29:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    $0x0,%eax
L36:
  leave
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  const char *p = s1;
  const int32_t len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0)
      return (char *)p;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L25
L23:
  add    $0x1,%rbx
L25:
  movsbl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L23
L26:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  const char *p = s1;
  const int32_t len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0)
      return (char *)p;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L25
  add    $0x1,%r12
L8:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L11
L25:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  const char *p = s1;
  const int32_t len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0)
      return (char *)p;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L10
  add    $0x1,%r12
L18:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L11
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  const char *p = s1;
  const int32_t len = strlen(s2);
  for (; (p = strchr(p, *s2)) != 0; p++) {
    if (strncmp(p, s2, len) == 0)
      return (char *)p;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L13:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memset(void *s, int c, size_t n) {
  char *s_cursor;
  s_cursor = (char *)s;
  while (n-- != 0) {
    *s_cursor = (char)c;
    s_cursor++;
  }
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L19
  add    %rdi,%rdx
  mov    %rdi,%rcx
L15:
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L15
L19:
  ret
```

assistant: ```c
void *ft_memset(void *s, int c, size_t n) {
  char *s_cursor;
  s_cursor = (char *)s;
  while (n-- != 0) {
    *s_cursor = (char)c;
    s_cursor++;
  }
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_memset>:
  endbr64
  test   %rdx,%rdx
  je     L1
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *ft_memset(void *s, int c, size_t n) {
  char *s_cursor;
  s_cursor = (char *)s;
  while (n-- != 0) {
    *s_cursor = (char)c;
    s_cursor++;
  }
  return (s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_memset>:
  endbr64
  test   %rdx,%rdx
  je     L7
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *ft_memset(void *s, int c, size_t n) {
  char *s_cursor;
  s_cursor = (char *)s;
  while (n-- != 0) {
    *s_cursor = (char)c;
    s_cursor++;
  }
  return (s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L7:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void str_cpy(char des[], char src[]) {
  int i = 0, j = 0;
  while ((des[i++] = src[j++]))
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_cpy>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L8
  ret
```

assistant: ```c
void str_cpy(char des[], char src[]) {
  int i = 0, j = 0;
  while ((des[i++] = src[j++]))
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_cpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L5
  ret
```

assistant: ```c
void str_cpy(char des[], char src[]) {
  int i = 0, j = 0;
  while ((des[i++] = src[j++]))
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_cpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L3
  ret
```

assistant: ```c
void str_cpy(char des[], char src[]) {
  int i = 0, j = 0;
  while ((des[i++] = src[j++]))
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: %02x

assistant: ```c
void print_hash(const unsigned char *hash, const int hash_len) {
  for (int i = 0; i < hash_len; i++) {
    printf("%02x", hash[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_hash>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D6(%rip),%rbp
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: %02x

assistant: ```c
void print_hash(const unsigned char *hash, const int hash_len) {
  for (int i = 0; i < hash_len; i++) {
    printf("%02x", hash[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_hash>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: %02x

assistant: ```c
void print_hash(const unsigned char *hash, const int hash_len) {
  for (int i = 0; i < hash_len; i++) {
    printf("%02x", hash[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_hash>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L10:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %02x

assistant: ```c
void print_hash(const unsigned char *hash, const int hash_len) {
  for (int i = 0; i < hash_len; i++) {
    printf("%02x", hash[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L11
L13:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x2,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L39
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L16
L39:
  cmpl   $0x0,-0x4(%rbp)
  je     L16
  mov    $0x9,%edi
  call   <putchar@plt>
L16:
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x14,-0x8(%rbp)
  jle    L13
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main(void) {
  int i, counter;
  counter = 0;
  i = 0;
  for (counter = 1; counter <= 20; counter++) {
    printf("%d", counter);
    i = counter % 5;
    if (i == 0) {
      printf("\n");
    } else if (i != 0) {
      printf("\t");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D7(%rip),%rbp
  jmp    L13
L17:
  mov    $0x9,%edi
  call   <putchar@plt>
L29:
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  je     L11
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L29
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int main(void) {
  int i, counter;
  counter = 0;
  i = 0;
  for (counter = 1; counter <= 20; counter++) {
    printf("%d", counter);
    i = counter % 5;
    if (i == 0) {
      printf("\n");
    } else if (i != 0) {
      printf("\t");
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x15,%ebx
  je     L6
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  jbe    L25
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x15,%ebx
  jne    L8
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: %d

assistant: ```c
int main(void) {
  int i, counter;
  counter = 0;
  i = 0;
  for (counter = 1; counter <= 20; counter++) {
    printf("%d", counter);
    i = counter % 5;
    if (i == 0) {
      printf("\n");
    } else if (i != 0) {
      printf("\t");
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L31:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x15,%ebx
  je     L7
L27:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  jbe    L31
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x15,%ebx
  jne    L27
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %d

assistant: ```c
int main(void) {
  int i, counter;
  counter = 0;
  i = 0;
  for (counter = 1; counter <= 20; counter++) {
    printf("%d", counter);
    i = counter % 5;
    if (i == 0) {
      printf("\n");
    } else if (i != 0) {
      printf("\t");
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x4,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x18,%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int ff_get_fourcc(const char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x4,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movsbl 0x1(%rbx),%eax
  shl    $0x8,%eax
  movsbl (%rbx),%edx
  add    %edx,%eax
  movsbl 0x2(%rbx),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movsbl 0x3(%rbx),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ff_get_fourcc(const char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ff_get_fourcc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x4,%rax
  sete   %dil
  xor    %eax,%eax
  call   <assert@plt>
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movsbl 0x2(%rbx),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movsbl 0x3(%rbx),%edx
  pop    %rbx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int ff_get_fourcc(const char *s) {
  assert(strlen(s) == 4);
  return (s[0]) + (s[1] << 8) + (s[2] << 16) + (s[3] << 24);
}
```