ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum_multiples_below>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L0:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L6
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L31
L6:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L31:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_multiples_below(int number, int first_div, int second_div) {
  int i;
  int sum = 0;
  for (i = 0; i < number; i++) {
    if (!(i % first_div) || !(i % second_div))
      sum += i;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum_multiples_below>:
  endbr64
  mov    %edx,%r9d
  test   %edi,%edi
  jle    L51
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  jmp    L42
L20:
  add    %ecx,%r8d
L53:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L59
L42:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L20
  mov    %ecx,%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L53
  jmp    L20
L51:
  mov    $0x0,%r8d
L59:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_multiples_below(int number, int first_div, int second_div) {
  int i;
  int sum = 0;
  for (i = 0; i < number; i++) {
    if (!(i % first_div) || !(i % second_div))
      sum += i;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_multiples_below>:
  endbr64
  mov    %edx,%r9d
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L28
  xor    %ecx,%ecx
L39:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L17
  mov    %ecx,%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L29
L17:
  add    %ecx,%r8d
L29:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L39
L28:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_multiples_below(int number, int first_div, int second_div) {
  int i;
  int sum = 0;
  for (i = 0; i < number; i++) {
    if (!(i % first_div) || !(i % second_div))
      sum += i;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_multiples_below>:
  endbr64
  mov    %edx,%r9d
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L39
  xor    %ecx,%ecx
L30:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L22
  mov    %ecx,%eax
  cltd
  idiv   %r9d
  test   %edx,%edx
  jne    L12
L22:
  add    %ecx,%r8d
L12:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L30
L39:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_multiples_below(int number, int first_div, int second_div) {
  int i;
  int sum = 0;
  for (i = 0; i < number; i++) {
    if (!(i % first_div) || !(i % second_div))
      sum += i;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mystrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mystrdup(const char *src) {
  size_t len = strlen(src);
  char *dst = malloc(len + 1);
  if (dst)
    strcpy(dst, src);
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrdup(const char *src) {
  size_t len = strlen(src);
  char *dst = malloc(len + 1);
  if (dst)
    strcpy(dst, src);
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mystrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(const char *src) {
  size_t len = strlen(src);
  char *dst = malloc(len + 1);
  if (dst)
    strcpy(dst, src);
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mystrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(const char *src) {
  size_t len = strlen(src);
  char *dst = malloc(len + 1);
  if (dst)
    strcpy(dst, src);
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1b,-0x4(%rbp)
  jne    L2
  mov    $0x0,%edi
  call   <exit@plt>
L2:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 27)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x1b,%edi
  je     L13
L11:
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 27)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: Translate the below assembly code into C programming language:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  cmp    $0x1b,%edi
  je     L9
L14:
  add    $0x10,%rsp
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   (%rax)
L9:
  xor    %edi,%edi
  mov    %esi,0xc(%rsp)
  call   <exit@plt>
  mov    0xc(%rsp),%edx
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 27)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HandleKey>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %edi,%ebp
  sub    $0x10,%rsp
  cmp    $0x1b,%edi
  je     L10
L14:
  add    $0x10,%rsp
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
  nopl   (%rax)
L10:
  xor    %edi,%edi
  mov    %esi,0xc(%rsp)
  call   <exit@plt>
  mov    0xc(%rsp),%edx
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: Key: %d -> %d


assistant: ```c
void HandleKey(int keycode, int bDown) {
  if (keycode == 27)
    exit(0);
  printf("Key: %d -> %d\n", keycode, bDown);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<epr_free_and_null_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <epr_free_string@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L11
L5:
  nop
L11:
  leave
  ret
```

assistant: ```c
void epr_free_and_null_string(char **str) {
  if (*str == NULL)
    return;
  epr_free_string(*str);
  *str = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<epr_free_and_null_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  call   <epr_free_string@plt>
  movq   $0x0,(%rbx)
L2:
  pop    %rbx
  ret
```

assistant: ```c
void epr_free_and_null_string(char **str) {
  if (*str == NULL)
    return;
  epr_free_string(*str);
  *str = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<epr_free_and_null_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L5
  call   <epr_free_string@plt>
  movq   $0x0,(%rbx)
L5:
  pop    %rbx
  ret
```

assistant: ```c
void epr_free_and_null_string(char **str) {
  if (*str == NULL)
    return;
  epr_free_string(*str);
  *str = NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<epr_free_and_null_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  call   <epr_free_string@plt>
  movq   $0x0,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void epr_free_and_null_string(char **str) {
  if (*str == NULL)
    return;
  epr_free_string(*str);
  *str = NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <factorielle@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 
%d


assistant: ```c
int main(void) {
  printf("\n%d\n", factorielle(5));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorielle@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: 
%d


assistant: ```c
int main(void) {
  printf("\n%d\n", factorielle(5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorielle@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: 
%d


assistant: ```c
int main(void) {
  printf("\n%d\n", factorielle(5));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorielle@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: 
%d


assistant: ```c
int main(void) {
  printf("\n%d\n", factorielle(5));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
L9:
  jmp    L9
```

assistant: ```c
void _exit(int code) {
  (void)code;
  while (true)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_exit>:
  endbr64
L9:
  jmp    L9
```

assistant: ```c
void _exit(int code) {
  (void)code;
  while (true)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void _exit(int code) {
  (void)code;
  while (true)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void _exit(int code) {
  (void)code;
  while (true)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add_polys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xd9,-0x4(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_polys(int dst[], int src[]) {
  int i;
  for (i = 0; i < (109 * 2); i++)
    dst[i] ^= src[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_polys>:
  endbr64
  mov    $0x0,%eax
L2:
  mov    (%rsi,%rax,1),%edx
  xor    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x368,%rax
  jne    L2
  ret
```

assistant: ```c
void add_polys(int dst[], int src[]) {
  int i;
  for (i = 0; i < (109 * 2); i++)
    dst[i] ^= src[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_polys>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,1),%edx
  xor    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x368,%rax
  jne    L6
  ret
```

assistant: ```c
void add_polys(int dst[], int src[]) {
  int i;
  for (i = 0; i < (109 * 2); i++)
    dst[i] ^= src[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_polys>:
  endbr64
  lea    0x4(%rsi),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  mov    $0x0,%eax
  jbe    L16
  nopl   0x0(%rax)
L6:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    $0x360,%rax
  jne    L6
  movq   0x360(%rdi),%xmm0
  movq   0x360(%rsi),%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x360(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rsi,%rax,1),%edx
  xor    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x368,%rax
  jne    L16
  ret
```

assistant: ```c
void add_polys(int dst[], int src[]) {
  int i;
  for (i = 0; i < (109 * 2); i++)
    dst[i] ^= src[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L8
L4:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*(str + len) != '\0') {
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x0,%eax
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L13
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*(str + len) != '\0') {
    len++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L15
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*(str + len) != '\0') {
    len++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L14
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t len = 0;
  while (*(str + len) != '\0') {
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x2(%rdi),%edi
  test   %di,%di
  je     L38
  lea    0x6(%rsp),%rax
  mov    $0x0,%edx
  jmp    L55
L6:
  add    %ecx,%ecx
  mov    %cx,(%rax)
L51:
  add    $0x1,%edx
  add    $0x2,%rax
  cmp    %di,%dx
  je     L38
L55:
  movzwl 0x6(%rsp),%ecx
  cmp    %dx,%cx
  jbe    L6
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%r8d
  mov    %r8b,(%rax)
  mov    %cl,0x1(%rax)
  jmp    L51
L38:
  movzwl 0x6(%rsp),%eax
  ror    $0x5,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        }
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)5) | (state[0UL] << (unsigned short)11);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  lea    0x7296(%rax),%ecx
  mov    %cx,0x6(%rsp)
  test   %di,%di
  je     L16
  lea    0x6(%rsp),%rax
  xor    %edx,%edx
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%r8d
  add    $0x1,%edx
  add    $0x2,%rax
  mov    %r8b,-0x2(%rax)
  mov    %cl,-0x1(%rax)
  movzwl 0x6(%rsp),%ecx
  cmp    %di,%dx
  je     L16
L59:
  cmp    %cx,%dx
  jb     L12
  add    %ecx,%ecx
  add    $0x1,%edx
  add    $0x2,%rax
  mov    %cx,-0x2(%rax)
  cmp    %di,%dx
  jne    L59
L16:
  ror    $0x5,%cx
  mov    %cx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        }
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)5) | (state[0UL] << (unsigned short)11);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movzwl 0x2(%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  mov    %ax,0x6(%rsp)
  test   %dx,%dx
  je     L100
  test   %ax,%ax
  jne    L74
  cmp    $0x1,%dx
  je     L100
L42:
  add    %eax,%eax
  mov    %ax,0x8(%rsp)
L112:
  cmp    $0x2,%dx
  jbe    L100
  lea    0x6(%rsp),%rdi
  mov    $0x2,%ecx
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  mov    0x5(%rdi),%al
  mov    0x4(%rdi),%ah
  mov    %ax,0x4(%rdi)
  movzwl 0x6(%rsp),%eax
L31:
  add    $0x1,%ecx
  add    $0x2,%rdi
  cmp    %dx,%cx
  je     L100
L88:
  cmp    %ax,%cx
  jb     L54
  add    %eax,%eax
  mov    %ax,0x4(%rdi)
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L100:
  ror    $0x5,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L74:
  rol    $0x8,%ax
  mov    %ax,0x6(%rsp)
  cmp    $0x1,%dx
  je     L100
  cmp    $0x1,%ax
  jbe    L42
  rolw   $0x8,0x8(%rsp)
  jmp    L112
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        }
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)5) | (state[0UL] << (unsigned short)11);
  }
}
```