user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%rbp
  mov    $0x31,%eax
  movl   $0x3033,0xa(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x36(%rsp)
  movb   $0x0,0xe(%rsp)
  movl   $0x2e3033,0xf(%rsp)
  movb   $0x0,0x13(%rsp)
  movl   $0x30332e30,0x14(%rsp)
  movb   $0x0,0x18(%rsp)
  movl   $0x30332e,0x19(%rsp)
  movb   $0x0,0x1d(%rsp)
  movl   $0x316533,0x1e(%rsp)
  movb   $0x0,0x22(%rsp)
  movl   $0x65302e33,0x32(%rsp)
  movl   $0x3165,0x23(%rsp)
  movb   $0x0,0x27(%rsp)
  movl   $0x312d6533,0x28(%rsp)
  movb   $0x0,0x2c(%rsp)
  movl   $0x3365332d,0x2d(%rsp)
  movb   $0x0,0x31(%rsp)
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  lea    0xf(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D86(%rip),%rdi
  lea    0x14(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D48(%rip),%rdi
  lea    0x19(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  lea    0x1e(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D83(%rip),%rdi
  lea    0x32(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D59(%rip),%rdi
  lea    0x23(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D60(%rip),%rdi
  lea    0x28(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D73(%rip),%rdi
  lea    0x2d(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D86
type_infered: string
name: retrieve_data
arguments: data_tag: D48
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D83
type_infered: string
name: retrieve_data
arguments: data_tag: D59
type_infered: string
name: retrieve_data
arguments: data_tag: D60
type_infered: string
name: retrieve_data
arguments: data_tag: D73
type_infered: string
name: retrieve_data
arguments: data_tag: D19
type_infered: string

tool: D12: 1In: %s	Out:%f


tool: D86: 2In: %s	Out:%f


tool: D48: 3In: %s	Out:%f


tool: D6: 4In: %s	Out:%f


tool: D83: 5In: %s	Out:%f


tool: D59: 6In: %s	Out:%f


tool: D60: 7In: %s	Out:%f


tool: D73: 8In: %s	Out:%f


tool: D19: 9In: %s	Out:%f


assistant: ```c
int main(void) {
  char t1[5] = "30";
  char t2[5] = "30.";
  char t3[5] = "0.30";
  char t4[5] = ".30";
  char t5[5] = "3e1";
  char t6[6] = "3.0e1";
  char t7[5] = "e1";
  char t8[5] = "3e-1";
  char t9[5] = "-3e3";
  printf("1In: %s\tOut:%f\n", t1, atof(t1));
  printf("2In: %s\tOut:%f\n", t2, atof(t2));
  printf("3In: %s\tOut:%f\n", t3, atof(t3));
  printf("4In: %s\tOut:%f\n", t4, atof(t4));
  printf("5In: %s\tOut:%f\n", t5, atof(t5));
  printf("6In: %s\tOut:%f\n", t6, atof(t6));
  printf("7In: %s\tOut:%f\n", t7, atof(t7));
  printf("8In: %s\tOut:%f\n", t8, atof(t8));
  printf("9In: %s\tOut:%f\n", t9, atof(t9));
}
```