ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<asn1_find_end>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %dl,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  mov    %rax,0x20(%rsp)
  test   %dl,%dl
  je     L117
  mov    $0x1,%r12d
  lea    0x20(%rsp),%r14
  test   %rsi,%rsi
  jg     L118
  jmp    L21
L117:
  add    %rsi,%rax
  mov    %rax,(%rdi)
  mov    $0x1,%r13d
  jmp    L1
L0:
  sub    $0x2,%rbx
  jmp    L140
L79:
  mov    0x20(%rsp),%r15
  lea    0xc(%rsp),%rcx
  lea    0x18(%rsp),%rdi
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0xffffffffffffffff
  push   %rbx
  mov    %r14,%r9
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <asn1_check_tlen@plt>
  mov    %eax,%r13d
  add    $0x30,%rsp
  test   %eax,%eax
  je     L62
  cmpb   $0x0,0xc(%rsp)
  je     L121
  add    $0x1,%r12d
L35:
  sub    0x20(%rsp),%r15
  lea    (%r15,%rbx,1),%rbx
L140:
  test   %rbx,%rbx
  jle    L145
L118:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <asn1_check_eoc@plt>
  test   %rax,%rax
  je     L79
  sub    $0x1,%r12d
  jne    L0
L110:
  mov    0x20(%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    $0x1,%r13d
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    %r13d,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L1
L121:
  mov    0x18(%rsp),%rax
  add    %rax,0x20(%rsp)
  jmp    L35
L145:
  test   %r12d,%r12d
  je     L110
L21:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  mov    $0x0,%r13d
  jmp    L1
L92:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1_find_end(const unsigned char **in, long len, char inf) {
  int expected_eoc;
  long plen;
  const unsigned char *p = *in, *q;
  if (inf == 0) {
    *in += len;
    return 1;
  }
  expected_eoc = 1;
  while (len > 0) {
    if (asn1_check_eoc(&p, len)) {
      expected_eoc--;
      if (expected_eoc == 0)
        break;
      len -= 2;
      continue;
    }
    q = p;
    if (!asn1_check_tlen(&plen, NULL, NULL, &inf, NULL, &p, len, -1, 0, 0, NULL)) {
      ASN1error(ERR_R_NESTED_ASN1_ERROR);
      return 0;
    }
    if (inf)
      expected_eoc++;
    else
      p += plen;
    len -= p - q;
  }
  if (expected_eoc) {
    ASN1error(ASN1_R_MISSING_EOC);
    return 0;
  }
  *in = p;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<asn1_find_end>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %dl,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    (%rdi),%rax
  mov    %rax,0x20(%rsp)
  test   %dl,%dl
  je     L125
  mov    $0x1,%r12d
  lea    0x20(%rsp),%r15
  lea    0xc(%rsp),%r14
  test   %rsi,%rsi
  jle    L72
L84:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <asn1_check_eoc@plt>
  test   %rax,%rax
  je     L118
  sub    $0x1,%r12d
  jne    L119
  mov    0x20(%rsp),%rax
  mov    $0x1,%r13d
  mov    %rax,0x0(%rbp)
L59:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L118:
  mov    0x20(%rsp),%rax
  lea    0x18(%rsp),%rdi
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    %r15,%r9
  xor    %r8d,%r8d
  mov    %r14,%rcx
  xor    %esi,%esi
  mov    %rax,0x8(%rsp)
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0xffffffffffffffff
  push   %rbx
  call   <asn1_check_tlen@plt>
  add    $0x30,%rsp
  mov    %eax,%r13d
  test   %eax,%eax
  je     L33
  cmpb   $0x0,0xc(%rsp)
  mov    0x20(%rsp),%rax
  je     L65
  add    $0x1,%r12d
L49:
  sub    (%rsp),%rax
  sub    %rax,%rbx
L117:
  test   %rbx,%rbx
  jg     L84
L72:
  mov    D5(%rip),%rax
  xor    %r13d,%r13d
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L125:
  add    %rsi,%rax
  mov    $0x1,%r13d
  mov    %rax,(%rdi)
  jmp    L59
  nopl   0x0(%rax)
L119:
  sub    $0x2,%rbx
  jmp    L117
  xchg   %ax,%ax
L65:
  add    0x18(%rsp),%rax
  mov    %rax,0x20(%rsp)
  jmp    L49
  nopl   0x0(%rax)
L33:
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L59
L108:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1_find_end(const unsigned char **in, long len, char inf) {
  int expected_eoc;
  long plen;
  const unsigned char *p = *in, *q;
  if (inf == 0) {
    *in += len;
    return 1;
  }
  expected_eoc = 1;
  while (len > 0) {
    if (asn1_check_eoc(&p, len)) {
      expected_eoc--;
      if (expected_eoc == 0)
        break;
      len -= 2;
      continue;
    }
    q = p;
    if (!asn1_check_tlen(&plen, NULL, NULL, &inf, NULL, &p, len, -1, 0, 0, NULL)) {
      ASN1error(ERR_R_NESTED_ASN1_ERROR);
      return 0;
    }
    if (inf)
      expected_eoc++;
    else
      p += plen;
    len -= p - q;
  }
  if (expected_eoc) {
    ASN1error(ASN1_R_MISSING_EOC);
    return 0;
  }
  *in = p;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<asn1_find_end>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %dl,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    (%rdi),%rax
  mov    %rax,0x20(%rsp)
  test   %dl,%dl
  je     L25
  mov    $0x1,%r12d
  lea    0x20(%rsp),%r15
  lea    0xc(%rsp),%r14
  test   %rsi,%rsi
  jle    L7
L111:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <asn1_check_eoc@plt>
  test   %rax,%rax
  je     L95
  sub    $0x1,%r12d
  jne    L44
  mov    0x20(%rsp),%rax
  mov    $0x1,%r13d
  mov    %rax,0x0(%rbp)
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L95:
  mov    0x20(%rsp),%rax
  lea    0x18(%rsp),%rdi
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    %r15,%r9
  xor    %r8d,%r8d
  mov    %r14,%rcx
  xor    %esi,%esi
  mov    %rax,0x8(%rsp)
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0xffffffffffffffff
  push   %rbx
  call   <asn1_check_tlen@plt>
  add    $0x30,%rsp
  mov    %eax,%r13d
  test   %eax,%eax
  je     L93
  cmpb   $0x0,0xc(%rsp)
  mov    0x20(%rsp),%rax
  je     L2
  add    $0x1,%r12d
L70:
  sub    (%rsp),%rax
  sub    %rax,%rbx
L129:
  test   %rbx,%rbx
  jg     L111
L7:
  mov    D19(%rip),%rax
  xor    %r13d,%r13d
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L25:
  add    %rsi,%rax
  mov    $0x1,%r13d
  mov    %rax,(%rdi)
  jmp    L3
  nopl   0x0(%rax)
L44:
  sub    $0x2,%rbx
  jmp    L129
  xchg   %ax,%ax
L2:
  add    0x18(%rsp),%rax
  mov    %rax,0x20(%rsp)
  jmp    L70
  nopl   0x0(%rax)
L93:
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L3
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1_find_end(const unsigned char **in, long len, char inf) {
  int expected_eoc;
  long plen;
  const unsigned char *p = *in, *q;
  if (inf == 0) {
    *in += len;
    return 1;
  }
  expected_eoc = 1;
  while (len > 0) {
    if (asn1_check_eoc(&p, len)) {
      expected_eoc--;
      if (expected_eoc == 0)
        break;
      len -= 2;
      continue;
    }
    q = p;
    if (!asn1_check_tlen(&plen, NULL, NULL, &inf, NULL, &p, len, -1, 0, 0, NULL)) {
      ASN1error(ERR_R_NESTED_ASN1_ERROR);
      return 0;
    }
    if (inf)
      expected_eoc++;
    else
      p += plen;
    len -= p - q;
  }
  if (expected_eoc) {
    ASN1error(ASN1_R_MISSING_EOC);
    return 0;
  }
  *in = p;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cs_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L52
L41:
  addq   $0x1,-0x20(%rbp)
L52:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L12
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
L12:
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L42
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L59
L29:
  cmpq   $0x1,-0x10(%rbp)
  je     L5
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L5:
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L59:
  leave
  ret
```

assistant: ```c
size_t cs_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cs_strlcat>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L52
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
L33:
  cmpb   $0x0,(%rax)
  je     L84
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L33
  mov    %rcx,%rax
L84:
  mov    %rax,%rbx
  sub    %r8,%rbx
  sub    %rbx,%rdx
  je     L9
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  test   %r8b,%r8b
  jne    L7
L18:
  movb   $0x0,(%rax)
  sub    %rsi,%rcx
  lea    (%rcx,%rbx,1),%rax
L49:
  pop    %rbx
  ret
L52:
  mov    %rdx,%rbx
L9:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  jmp    L49
L11:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L18
L7:
  cmp    $0x1,%rdx
  je     L11
  mov    %r8b,(%rax)
  sub    $0x1,%rdx
  lea    0x1(%rax),%rax
  jmp    L11
```

assistant: ```c
size_t cs_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cs_strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L75
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L71
  nopl   0x0(%rax,%rax,1)
L86:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L49
L71:
  cmpb   $0x0,(%rax)
  jne    L86
L49:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L62
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L76
  jmp    L79
  nopl   (%rax)
L9:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L98:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L12
L76:
  cmp    $0x1,%rdx
  jne    L9
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L98
  sub    %rsi,%rcx
  add    %rcx,%r12
L79:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L79
L75:
  xor    %r12d,%r12d
L62:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t cs_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cs_strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L92
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L36
L13:
  cmpb   $0x0,(%rax)
  jne    L56
L36:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L96
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L54
  jmp    L2
  nopl   (%rax)
L15:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L19:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L81
L54:
  cmp    $0x1,%rdx
  jne    L15
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L19
  sub    %rsi,%rcx
  add    %rcx,%r12
L2:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L81:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L2
L92:
  xor    %r12d,%r12d
L96:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t cs_strlcat(char *dest, const char *source, size_t nMaxLength) {
  char *d = dest;
  const char *s = source;
  size_t n = nMaxLength;
  size_t dlen;
  while (n-- != 0 && *d != '\0') {
    d++;
  }
  dlen = d - dest;
  n = nMaxLength - dlen;
  if (n == 0) {
    return (dlen + strlen(s));
  }
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - source));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D6: hello, my cat

tool: D2: Byebye, my cat!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, my cat");
  sleep(3);
  printf("Byebye, my cat!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string
name: read_data
arguments: data_label: D19
type: string

tool: D4: hello, my cat

tool: D19: Byebye, my cat!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, my cat");
  sleep(3);
  printf("Byebye, my cat!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D7: hello, my cat

tool: D11: Byebye, my cat!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, my cat");
  sleep(3);
  printf("Byebye, my cat!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <sleep@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string

tool: D7: hello, my cat

tool: D2: Byebye, my cat!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("hello, my cat");
  sleep(3);
  printf("Byebye, my cat!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x13,-0x4(%rbp)
  jle    L4
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D23: 
Final prime data: 

tool: D20: %d 

tool: D2: 


assistant: ```c
void printSet(int set[]) {
  int i = 0;
  printf("\nFinal prime data: ");
  for (i = 0; i < 20; i++)
    printf("%d ", set[i]);
  printf("\n\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printSet>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  add    $0x50,%rbp
  lea    D10(%rip),%r12
L2:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L2
  lea    D16(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D16
datatype: string

tool: D6: 
Final prime data: 

tool: D10: %d 

tool: D16: 


assistant: ```c
void printSet(int set[]) {
  int i = 0;
  printf("\nFinal prime data: ");
  for (i = 0; i < 20; i++)
    printf("%d ", set[i]);
  printf("\n\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printSet>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D12(%rip),%rdi
  lea    0x50(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string

tool: D27: %d 

tool: D12: 
Final prime data: 

tool: D10: 


assistant: ```c
void printSet(int set[]) {
  int i = 0;
  printf("\nFinal prime data: ");
  for (i = 0; i < 20; i++)
    printf("%d ", set[i]);
  printf("\n\n");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printSet>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdi
  lea    0x50(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  lea    D24(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string

tool: D22: %d 

tool: D8: 
Final prime data: 

tool: D24: 


assistant: ```c
void printSet(int set[]) {
  int i = 0;
  printf("\nFinal prime data: ");
  for (i = 0; i < 20; i++)
    printf("%d ", set[i]);
  printf("\n\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<env_lookup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L26:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strneq@plt>
  test   %rax,%rax
  je     L31
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <env_key_length@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L3
L31:
  addq   $0x8,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
char *env_lookup(char **env, const char *key, size_t len) {
  char **e;
  for (e = env; *e; ++e) {
    if (strneq(*e, key, len)) {
      size_t key_len = env_key_length(*e);
      return strdup(&(*e)[key_len]);
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<env_lookup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L14
L11:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <strneq@plt>
  test   %rax,%rax
  jne    L24
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L11
  jmp    L14
L24:
  mov    (%rbx),%rdi
  call   <env_key_length@plt>
  add    (%rbx),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdi
L14:
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *env_lookup(char **env, const char *key, size_t len) {
  char **e;
  for (e = env; *e; ++e) {
    if (strneq(*e, key, len)) {
      size_t key_len = env_key_length(*e);
      return strdup(&(*e)[key_len]);
    }
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<env_lookup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%r12
  mov    %rdx,%rbp
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L39
L35:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <strneq@plt>
  test   %rax,%rax
  je     L19
  mov    (%rbx),%rdi
  call   <env_key_length@plt>
  add    (%rbx),%rax
  pop    %rbx
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <strdup@plt>
  nopl   0x0(%rax)
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *env_lookup(char **env, const char *key, size_t len) {
  char **e;
  for (e = env; *e; ++e) {
    if (strneq(*e, key, len)) {
      size_t key_len = env_key_length(*e);
      return strdup(&(*e)[key_len]);
    }
  }
  return NULL;
}
```