ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<uninitvar_strncpy_s>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  xor    %edx,%edx
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  xor    %ebx,%ebx
  mov    %rbx,%rcx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    %r15,%rdi
  call   <strncpy_s@plt>
  xor    %esi,%esi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  xor    %edx,%edx
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strncpy_s@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_strncpy_s(char *Ct, size_t N1, char *S, size_t N2) {
  char dest[42];
  char *s;
  size_t n1;
  size_t n2;
  (void)strncpy_s(dest, n1, s, n2);
  (void)strncpy_s(Ct, n1, S, N2);
  (void)strncpy_s(Ct, N1, s, N2);
  (void)strncpy_s(Ct, N1, S, n2);
  (void)strncpy_s(Ct, N1, S, N2);
  (void)strncpy_s(dest, N1, S, N2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uninitvar_strncpy_s>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  xor    %edx,%edx
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  xor    %ebx,%ebx
  mov    %rbx,%rcx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    %r15,%rdi
  call   <strncpy_s@plt>
  xor    %esi,%esi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  xor    %edx,%edx
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy_s@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strncpy_s@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uninitvar_strncpy_s(char *Ct, size_t N1, char *S, size_t N2) {
  char dest[42];
  char *s;
  size_t n1;
  size_t n2;
  (void)strncpy_s(dest, n1, s, n2);
  (void)strncpy_s(Ct, n1, S, N2);
  (void)strncpy_s(Ct, N1, s, N2);
  (void)strncpy_s(Ct, N1, S, n2);
  (void)strncpy_s(Ct, N1, S, N2);
  (void)strncpy_s(dest, N1, S, N2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rtlsdr_get_device_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <do_init@plt>
  cmpl   $0x0,-0x4(%rbp)
  js     L5
  cmpl   $0x2,-0x4(%rbp)
  jle    L29
L5:
  lea    D4(%rip),%rax
  jmp    L27
L29:
  lea    D1(%rip),%rax
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: 

tool: D1: Generic RTL2832U OEM

assistant: ```c
const char *rtlsdr_get_device_name(uint32_t index) {
  do_init();
  if (index < 0 || index > 2)
    return "";
  return "Generic RTL2832U OEM";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtlsdr_get_device_name>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <do_init@plt>
  cmp    $0x3,%ebx
  lea    D11(%rip),%rax
  lea    D9(%rip),%rdx
  cmovae %rdx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D11: Generic RTL2832U OEM

tool: 

assistant: ```c
const char *rtlsdr_get_device_name(uint32_t index) {
  do_init();
  if (index < 0 || index > 2)
    return "";
  return "Generic RTL2832U OEM";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rtlsdr_get_device_name>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <do_init@plt>
  cmp    $0x3,%ebx
  pop    %rbx
  lea    D6(%rip),%rax
  lea    D17(%rip),%rdx
  cmovae %rdx,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D6: Generic RTL2832U OEM

tool: 

assistant: ```c
const char *rtlsdr_get_device_name(uint32_t index) {
  do_init();
  if (index < 0 || index > 2)
    return "";
  return "Generic RTL2832U OEM";
}
```
user: What is the c source code of the assembly code below?

```asm
<rtlsdr_get_device_name>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <do_init@plt>
  cmp    $0x3,%ebx
  pop    %rbx
  lea    D5(%rip),%rax
  lea    D2(%rip),%rdx
  cmovae %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D5: Generic RTL2832U OEM

tool: 

assistant: ```c
const char *rtlsdr_get_device_name(uint32_t index) {
  do_init();
  if (index < 0 || index > 2)
    return "";
  return "Generic RTL2832U OEM";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L2
  jmp    L42
L89:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  addl   $0x1,-0xc(%rbp)
L42:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L73
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L89
L73:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L0
L25:
  nop
  jmp    L0
L27:
  nop
  jmp    L0
L2:
  nop
L0:
  leave
  ret
```

assistant: ```c
void write_image(int src, int des, int bs, int count, int sp, int sk) {
  int i;
  char *buf;
  i = 0;
  buf = (char *)malloc(bs * sizeof(char));
  if (!buf)
    return;
  if (lseek(src, sp * bs, SEEK_SET) == -1)
    return;
  if (lseek(des, sk * bs, SEEK_SET) == -1)
    return;
  while (read(src, buf, bs) && i < count) {
    write(des, buf, bs);
    ++i;
  }
  free(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_image>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r14d
  mov    %r8d,%r15d
  mov    %r9d,0xc(%rsp)
  mov    %edx,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L10
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    %rax,%rbp
  imul   %ebx,%r15d
  mov    %r15d,%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%edi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    0xc(%rsp),%esi
  imul   %ebx,%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    %r13d,%edi
  call   <lseek@plt>
  mov    $0x0,%r15d
  cmp    $0xffffffff,%eax
  je     L12
L69:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    %r14d,%r15d
  jge    L23
  test   %rax,%rax
  je     L23
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  add    $0x1,%r15d
  jmp    L69
L23:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L12
```

assistant: ```c
void write_image(int src, int des, int bs, int count, int sp, int sk) {
  int i;
  char *buf;
  i = 0;
  buf = (char *)malloc(bs * sizeof(char));
  if (!buf)
    return;
  if (lseek(src, sp * bs, SEEK_SET) == -1)
    return;
  if (lseek(des, sk * bs, SEEK_SET) == -1)
    return;
  while (read(src, buf, bs) && i < count) {
    write(des, buf, bs);
    ++i;
  }
  free(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_image>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %r9d,0xc(%rsp)
  call   <malloc@plt>
  test   %rax,%rax
  jne    L32
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L32:
  imul   %ebx,%r14d
  mov    %rax,%r15
  mov    D18(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%edx
  mov    %r14d,%esi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L38
  mov    0xc(%rsp),%esi
  mov    D18(%rip),%rax
  mov    %r12d,%edi
  xor    %r14d,%r14d
  imul   %ebx,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  jne    L40
  jmp    L38
  nopl   0x0(%rax)
L11:
  test   %rax,%rax
  je     L4
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  add    $0x1,%r14d
  call   <write@plt>
L40:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %r13d,%r14d
  jl     L11
L4:
  add    $0x18,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void write_image(int src, int des, int bs, int count, int sp, int sk) {
  int i;
  char *buf;
  i = 0;
  buf = (char *)malloc(bs * sizeof(char));
  if (!buf)
    return;
  if (lseek(src, sp * bs, SEEK_SET) == -1)
    return;
  if (lseek(des, sk * bs, SEEK_SET) == -1)
    return;
  while (read(src, buf, bs) && i < count) {
    write(des, buf, bs);
    ++i;
  }
  free(buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_image>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %r9d,0xc(%rsp)
  call   <malloc@plt>
  test   %rax,%rax
  jne    L11
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L11:
  imul   %ebx,%r14d
  mov    %rax,%r15
  mov    D14(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%edx
  mov    %r14d,%esi
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    0xc(%rsp),%esi
  mov    D14(%rip),%rax
  mov    %r12d,%edi
  xor    %r14d,%r14d
  imul   %ebx,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  cmp    $0xffffffff,%eax
  jne    L40
  jmp    L33
  nopl   0x0(%rax)
L36:
  test   %rax,%rax
  je     L50
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  add    $0x1,%r14d
  call   <write@plt>
L40:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    %r13d,%r14d
  jl     L36
L50:
  add    $0x18,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void write_image(int src, int des, int bs, int count, int sp, int sk) {
  int i;
  char *buf;
  i = 0;
  buf = (char *)malloc(bs * sizeof(char));
  if (!buf)
    return;
  if (lseek(src, sp * bs, SEEK_SET) == -1)
    return;
  if (lseek(des, sk * bs, SEEK_SET) == -1)
    return;
  while (read(src, buf, bs) && i < count) {
    write(des, buf, bs);
    ++i;
  }
  free(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L48
L14:
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L11
L47:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L11
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x24(%rbp),%eax
  add    %esi,%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x2e,(%rax)
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
L48:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_move(char **array[], int level, int up, int right) {
  int i;
  int j;
  i = -1;
  while (array[level][++i]) {
    j = -1;
    while (array[level][i][++j]) {
      if (array[level][i][j] != '.') {
        array[level][i - up][j + right] = array[level][i][j];
        array[level][i][j] = '.';
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_move>:
  endbr64
  mov    %ecx,%r10d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%r8
  mov    (%r8),%rax
  cmpq   $0x0,(%rax)
  je     L64
  neg    %edx
  mov    %edx,%r11d
  mov    $0x0,%edi
  jmp    L16
L46:
  lea    (%r10,%rax,1),%esi
  movslq %esi,%rsi
  mov    (%rcx,%r9,1),%rcx
  mov    %dl,(%rcx,%rsi,1)
  mov    (%r8),%rdx
  mov    (%rdx,%rdi,1),%rdx
  movb   $0x2e,(%rdx,%rax,1)
L70:
  mov    (%r8),%rcx
  add    $0x1,%rax
  mov    (%rcx,%rdi,1),%rdx
  movzbl (%rdx,%rax,1),%edx
  test   %dl,%dl
  je     L4
L53:
  cmp    $0x2e,%dl
  jne    L46
  jmp    L70
L4:
  add    $0x8,%rdi
  add    $0x1,%r11d
  mov    (%r8),%rax
  cmpq   $0x0,(%rax,%rdi,1)
  je     L64
L16:
  mov    (%r8),%rcx
  mov    (%rcx,%rdi,1),%rax
  movzbl (%rax),%edx
  movslq %r11d,%r9
  shl    $0x3,%r9
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L53
  jmp    L4
L64:
  ret
```

assistant: ```c
void ft_move(char **array[], int level, int up, int right) {
  int i;
  int j;
  i = -1;
  while (array[level][++i]) {
    j = -1;
    while (array[level][i][++j]) {
      if (array[level][i][j] != '.') {
        array[level][i - up][j + right] = array[level][i][j];
        array[level][i][j] = '.';
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_move>:
  endbr64
  movslq %esi,%rsi
  mov    %ecx,%r10d
  lea    (%rdi,%rsi,8),%r8
  mov    (%r8),%rsi
  mov    (%rsi),%rax
  test   %rax,%rax
  je     L48
  neg    %edx
  xor    %edi,%edi
  mov    %edx,%r11d
L17:
  movzbl (%rax),%edx
  movslq %r11d,%r9
  xor    %eax,%eax
  shl    $0x3,%r9
  test   %dl,%dl
  je     L0
L20:
  cmp    $0x2e,%dl
  je     L34
  mov    (%rsi,%r9,1),%rsi
  lea    (%r10,%rax,1),%ecx
  movslq %ecx,%rcx
  mov    %dl,(%rsi,%rcx,1)
  mov    (%r8),%rdx
  mov    (%rdx,%rdi,1),%rdx
  movb   $0x2e,(%rdx,%rax,1)
  mov    (%r8),%rsi
L34:
  mov    (%rsi,%rdi,1),%rdx
  add    $0x1,%rax
  movzbl (%rdx,%rax,1),%edx
  test   %dl,%dl
  jne    L20
L0:
  add    $0x8,%rdi
  add    $0x1,%r11d
  mov    (%rsi,%rdi,1),%rax
  test   %rax,%rax
  jne    L17
L48:
  ret
```

assistant: ```c
void ft_move(char **array[], int level, int up, int right) {
  int i;
  int j;
  i = -1;
  while (array[level][++i]) {
    j = -1;
    while (array[level][i][++j]) {
      if (array[level][i][j] != '.') {
        array[level][i - up][j + right] = array[level][i][j];
        array[level][i][j] = '.';
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_move>:
  endbr64
  movslq %esi,%rsi
  mov    %ecx,%r11d
  lea    (%rdi,%rsi,8),%r9
  mov    (%r9),%rdi
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L30
  neg    %edx
  xor    %r8d,%r8d
  xchg   %ax,%ax
L29:
  movzbl (%rsi),%ecx
  movslq %edx,%r10
  xor    %eax,%eax
  shl    $0x3,%r10
  test   %cl,%cl
  je     L58
L68:
  cmp    $0x2e,%cl
  je     L52
  mov    (%rdi,%r10,1),%rdi
  lea    (%r11,%rax,1),%esi
  movslq %esi,%rsi
  mov    %cl,(%rdi,%rsi,1)
  mov    (%r9),%rcx
  mov    (%rcx,%r8,1),%rcx
  movb   $0x2e,(%rcx,%rax,1)
  mov    (%r9),%rdi
  add    $0x1,%rax
  mov    (%rdi,%r8,1),%rsi
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L68
L58:
  add    $0x8,%r8
  add    $0x1,%edx
  mov    (%rdi,%r8,1),%rsi
  test   %rsi,%rsi
  jne    L29
L30:
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L68
  add    $0x8,%r8
  add    $0x1,%edx
  mov    (%rdi,%r8,1),%rsi
  test   %rsi,%rsi
  jne    L29
  jmp    L30
```

assistant: ```c
void ft_move(char **array[], int level, int up, int right) {
  int i;
  int j;
  i = -1;
  while (array[level][++i]) {
    j = -1;
    while (array[level][i][++j]) {
      if (array[level][i][j] != '.') {
        array[level][i - up][j + right] = array[level][i][j];
        array[level][i][j] = '.';
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findMaxElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L26
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L26:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findMaxElement(int array[], int length) {
  int max = array[0];
  for (int i = 1; i < length; i++) {
    if (max < array[i]) {
      max = array[i];
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findMaxElement>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L18
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L17:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L17
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int findMaxElement(int array[], int length) {
  int max = array[0];
  for (int i = 1; i < length; i++) {
    if (max < array[i]) {
      max = array[i];
    }
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findMaxElement>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L10
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L3
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findMaxElement(int array[], int length) {
  int max = array[0];
  for (int i = 1; i < length; i++) {
    if (max < array[i]) {
      max = array[i];
    }
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findMaxElement>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L44
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L23
  mov    %edi,%esi
  movd   %eax,%xmm3
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm3,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L31:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm0,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L31
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %r8d,%edi
  je     L54
L61:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L44
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L44
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L44:
  ret
  nopl   0x0(%rax)
L54:
  ret
L23:
  mov    $0x1,%esi
  jmp    L61
```

assistant: ```c
int findMaxElement(int array[], int length) {
  int max = array[0];
  for (int i = 1; i < length; i++) {
    if (max < array[i]) {
      max = array[i];
    }
  }
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<date_get_month>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int date_get_month(void) {
  time_t t = time(NULL);
  struct tm *lt = localtime(&t);
  return lt->tm_mon + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<date_get_month>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int date_get_month(void) {
  time_t t = time(NULL);
  struct tm *lt = localtime(&t);
  return lt->tm_mon + 1;
}
```