ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x430(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x430(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x430(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x414(%rbp)
  mov    -0x414(%rbp),%edx
  lea    -0x210(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <print_error_lfmm@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char msg[512];
  char in[512];
  int n;
  strcpy(msg, argv[1]);
  strcpy(in, argv[2]);
  n = (int)atoi(argv[3]);
  print_error_lfmm(msg, in, n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbx),%rsi
  lea    0x200(%rsp),%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <print_error_lfmm@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char msg[512];
  char in[512];
  int n;
  strcpy(msg, argv[1]);
  strcpy(in, argv[2]);
  n = (int)atoi(argv[3]);
  print_error_lfmm(msg, in, n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x410,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x200(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <print_error_lfmm@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char msg[512];
  char in[512];
  int n;
  strcpy(msg, argv[1]);
  strcpy(in, argv[2]);
  n = (int)atoi(argv[3]);
  print_error_lfmm(msg, in, n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x410,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x200(%rsp),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <print_error_lfmm@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char msg[512];
  char in[512];
  int n;
  strcpy(msg, argv[1]);
  strcpy(in, argv[2]);
  n = (int)atoi(argv[3]);
  print_error_lfmm(msg, in, n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L10:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string
name: disassemble_data
arguments: label: D4
datatype: string

tool: D2: strcpy

tool: D4: # %s(dest=%p, src=%p)


assistant: ```c
char *strcpy(char *dest, const char *src) {
  printf("# %s(dest=%p, src=%p)\n", __FUNCTION__, dest, src);
  char *p = dest;
  while (*src)
    *p++ = *src++;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D17(%rip),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L12
  mov    $0x0,%eax
L2:
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L2
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D15
type_infered: string

tool: D17: strcpy

tool: D15: # %s(dest=%p, src=%p)


assistant: ```c
char *strcpy(char *dest, const char *src) {
  printf("# %s(dest=%p, src=%p)\n", __FUNCTION__, dest, src);
  char *p = dest;
  while (*src)
    *p++ = *src++;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %rdi,%r12
  push   %rbx
  lea    D1(%rip),%rdi
  mov    %rsi,%rbx
  xor    %eax,%eax
  lea    D4(%rip),%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L7
  xor    %eax,%eax
  nopl   (%rax)
L2:
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  jne    L2
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D1: # %s(dest=%p, src=%p)


tool: D4: strcpy

assistant: ```c
char *strcpy(char *dest, const char *src) {
  printf("# %s(dest=%p, src=%p)\n", __FUNCTION__, dest, src);
  char *p = dest;
  while (*src)
    *p++ = *src++;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %rdi,%r12
  push   %rbx
  lea    D0(%rip),%rdi
  mov    %rsi,%rbx
  xor    %eax,%eax
  lea    D1(%rip),%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L8
  xor    %eax,%eax
  nopl   (%rax)
L5:
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  jne    L5
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string

tool: D0: # %s(dest=%p, src=%p)


tool: D1: strcpy

assistant: ```c
char *strcpy(char *dest, const char *src) {
  printf("# %s(dest=%p, src=%p)\n", __FUNCTION__, dest, src);
  char *p = dest;
  while (*src)
    *p++ = *src++;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ld2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xffff,-0x14(%rbp)
  jbe    L44
  shrl   $0x10,-0x14(%rbp)
  addl   $0x10,-0x4(%rbp)
L44:
  cmpl   $0xff,-0x14(%rbp)
  jbe    L33
  shrl   $0x8,-0x14(%rbp)
  addl   $0x8,-0x4(%rbp)
L33:
  cmpl   $0xf,-0x14(%rbp)
  jbe    L43
  shrl   $0x4,-0x14(%rbp)
  addl   $0x4,-0x4(%rbp)
L43:
  cmpl   $0x3,-0x14(%rbp)
  jbe    L2
  shrl   $0x2,-0x14(%rbp)
  addl   $0x2,-0x4(%rbp)
L2:
  cmpl   $0x1,-0x14(%rbp)
  jbe    L3
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned ld2(unsigned int x) {
  unsigned r = 0;
  if (x >= 0x10000) {
    x >>= 16;
    r += 16;
  }
  if (x >= 0x100) {
    x >>= 8;
    r += 8;
  }
  if (x >= 0x10) {
    x >>= 4;
    r += 4;
  }
  if (x >= 4) {
    x >>= 2;
    r += 2;
  }
  if (x >= 2)
    r++;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ld2>:
  endbr64
  mov    $0x0,%eax
  cmp    $0xffff,%edi
  jbe    L34
  shr    $0x10,%edi
  mov    $0x10,%eax
L34:
  cmp    $0xff,%edi
  jbe    L24
  shr    $0x8,%edi
  add    $0x8,%eax
L24:
  cmp    $0xf,%edi
  jbe    L26
  shr    $0x4,%edi
  add    $0x4,%eax
L26:
  cmp    $0x3,%edi
  jbe    L30
  shr    $0x2,%edi
  add    $0x2,%eax
L30:
  cmp    $0x2,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned ld2(unsigned int x) {
  unsigned r = 0;
  if (x >= 0x10000) {
    x >>= 16;
    r += 16;
  }
  if (x >= 0x100) {
    x >>= 8;
    r += 8;
  }
  if (x >= 0x10) {
    x >>= 4;
    r += 4;
  }
  if (x >= 4) {
    x >>= 2;
    r += 2;
  }
  if (x >= 2)
    r++;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ld2>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffff,%edi
  jbe    L38
  shr    $0x10,%edi
  mov    $0x10,%eax
L38:
  cmp    $0xff,%edi
  jbe    L17
  shr    $0x8,%edi
  add    $0x8,%eax
L17:
  cmp    $0xf,%edi
  jbe    L15
  shr    $0x4,%edi
  add    $0x4,%eax
L15:
  cmp    $0x3,%edi
  jbe    L28
  shr    $0x2,%edi
  add    $0x2,%eax
L28:
  cmp    $0x2,%edi
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned ld2(unsigned int x) {
  unsigned r = 0;
  if (x >= 0x10000) {
    x >>= 16;
    r += 16;
  }
  if (x >= 0x100) {
    x >>= 8;
    r += 8;
  }
  if (x >= 0x10) {
    x >>= 4;
    r += 4;
  }
  if (x >= 4) {
    x >>= 2;
    r += 2;
  }
  if (x >= 2)
    r++;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ld2>:
  endbr64
  cmp    $0xffff,%edi
  jbe    L34
  shr    $0x10,%edi
  mov    $0x18,%edx
  mov    $0x10,%eax
L27:
  cmp    $0xff,%edi
  jbe    L9
  shr    $0x8,%edi
  mov    %edx,%eax
L9:
  cmp    $0xf,%edi
  jbe    L43
  shr    $0x4,%edi
  add    $0x4,%eax
L43:
  cmp    $0x3,%edi
  jbe    L6
  shr    $0x2,%edi
  add    $0x2,%eax
L6:
  cmp    $0x2,%edi
  sbb    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x8,%edx
  xor    %eax,%eax
  jmp    L27
```

assistant: ```c
unsigned ld2(unsigned int x) {
  unsigned r = 0;
  if (x >= 0x10000) {
    x >>= 16;
    r += 16;
  }
  if (x >= 0x100) {
    x >>= 8;
    r += 8;
  }
  if (x >= 0x10) {
    x >>= 4;
    r += 4;
  }
  if (x >= 4) {
    x >>= 2;
    r += 2;
  }
  if (x >= 2)
    r++;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<u8_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L45
L23:
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <u8_nextchar@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jne    L15
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L21
L15:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L45:
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
char *u8_strchr(const char *s, u_int32_t ch, size_t *charn) {
  size_t i = 0, lasti = 0;
  u_int32_t c;
  *charn = 0;
  while (s[i]) {
    c = u8_nextchar(s, &i);
    if (c == ch) {
      return (char *)&s[lasti];
    }
    lasti = i;
    (*charn)++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<u8_strchr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,(%rdx)
  cmpb   $0x0,(%rdi)
  je     L10
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%r12d
  mov    %rsp,%r14
L8:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <u8_nextchar@plt>
  cmp    %r13,%rax
  je     L20
  mov    (%rsp),%r12
  addq   $0x1,0x0(%rbp)
  cmpb   $0x0,(%rbx,%r12,1)
  jne    L8
  mov    $0x0,%eax
  jmp    L35
L20:
  lea    (%rbx,%r12,1),%rax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    $0x0,%eax
  jmp    L35
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *u8_strchr(const char *s, u_int32_t ch, size_t *charn) {
  size_t i = 0, lasti = 0;
  u_int32_t c;
  *charn = 0;
  while (s[i]) {
    c = u8_nextchar(s, &i);
    if (c == ch) {
      return (char *)&s[lasti];
    }
    lasti = i;
    (*charn)++;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<u8_strchr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  cmpb   $0x0,(%rdi)
  movq   $0x0,(%rsp)
  je     L40
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  xor    %r12d,%r12d
  mov    %rsp,%r14
  jmp    L52
  nopl   (%rax)
L59:
  mov    (%rsp),%r12
  addq   $0x1,0x0(%rbp)
  cmpb   $0x0,(%rbx,%r12,1)
  je     L40
L52:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <u8_nextchar@plt>
  cmp    %r13,%rax
  jne    L59
  lea    (%rbx,%r12,1),%rax
  jmp    L12
  xchg   %ax,%ax
L40:
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *u8_strchr(const char *s, u_int32_t ch, size_t *charn) {
  size_t i = 0, lasti = 0;
  u_int32_t c;
  *charn = 0;
  while (s[i]) {
    c = u8_nextchar(s, &i);
    if (c == ch) {
      return (char *)&s[lasti];
    }
    lasti = i;
    (*charn)++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<u8_strchr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rdx)
  cmpb   $0x0,(%rdi)
  movq   $0x0,(%rsp)
  je     L6
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  xor    %r12d,%r12d
  mov    %rsp,%r14
  jmp    L23
  nopl   (%rax)
L57:
  mov    (%rsp),%r12
  addq   $0x1,0x0(%rbp)
  cmpb   $0x0,(%rbx,%r12,1)
  je     L6
L23:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <u8_nextchar@plt>
  cmp    %r13,%rax
  jne    L57
  lea    (%rbx,%r12,1),%rax
  jmp    L56
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
L56:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *u8_strchr(const char *s, u_int32_t ch, size_t *charn) {
  size_t i = 0, lasti = 0;
  u_int32_t c;
  *charn = 0;
  while (s[i]) {
    c = u8_nextchar(s, &i);
    if (c == ch) {
      return (char *)&s[lasti];
    }
    lasti = i;
    (*charn)++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<hybrid1_ks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1c,-0x14(%rbp)
  jg     L3
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <add_to_array@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <make_general_hdl@plt>
  jmp    L16
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <ceil@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <add_to_array@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <make_hdl@plt>
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <hybrid1_ks>
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <hybrid1_ks>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: f64

tool: D5: 2

assistant: ```c
void hybrid1_ks(int n) {
  double l, h;
  if (n < 29) {
    add_to_array(n);
    make_general_hdl(n);
    return;
  }
  h = floor(n / 2.0);
  l = ceil(n / 2.0);
  add_to_array(n);
  make_hdl(n, l, h);
  hybrid1_ks(l);
  hybrid1_ks(h);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hybrid1_ks>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  cmp    $0x1c,%edi
  jle    L11
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
  mov    %ebp,%edi
  call   <floor@plt>
  movsd  %xmm0,(%rsp)
  mov    %ebp,%edi
  call   <ceil@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %ebx,%edi
  call   <add_to_array@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%edi
  call   <make_hdl@plt>
  cvttsd2si 0x8(%rsp),%edi
  call   <hybrid1_ks>
  cvttsd2si (%rsp),%edi
  call   <hybrid1_ks>
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <add_to_array@plt>
  mov    %ebx,%edi
  call   <make_general_hdl@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void hybrid1_ks(int n) {
  double l, h;
  if (n < 29) {
    add_to_array(n);
    make_general_hdl(n);
    return;
  }
  h = floor(n / 2.0);
  l = ceil(n / 2.0);
  add_to_array(n);
  make_hdl(n, l, h);
  hybrid1_ks(l);
  hybrid1_ks(h);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hybrid1_ks>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  cmp    $0x1c,%edi
  jle    L18
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  mov    %r12d,%edi
  call   <floor@plt>
  mov    %r12d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <ceil@plt>
  mov    %ebp,%edi
  movq   %xmm0,%r12
  call   <add_to_array@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %ebp,%edi
  movq   %r12,%xmm0
  call   <make_hdl@plt>
  movq   %r12,%xmm2
  cvttsd2si %xmm2,%edi
  call   <hybrid1_ks>
  movsd  0x8(%rsp),%xmm1
  cvttsd2si %xmm1,%ebp
  cmp    $0x1c,%ebp
  jg     L12
L18:
  mov    %ebp,%edi
  call   <add_to_array@plt>
  add    $0x18,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <make_general_hdl@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void hybrid1_ks(int n) {
  double l, h;
  if (n < 29) {
    add_to_array(n);
    make_general_hdl(n);
    return;
  }
  h = floor(n / 2.0);
  l = ceil(n / 2.0);
  add_to_array(n);
  make_hdl(n, l, h);
  hybrid1_ks(l);
  hybrid1_ks(h);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L23
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L17
L23:
  movl   $0x0,-0x14(%rbp)
  jmp    L66
L67:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L66:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L67
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <heapSort@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L56
L38:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L38
  mov    $0x0,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D5
type: string

tool: D36: %d

tool: D27: not memory

tool: D5: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *numberArray;
  numberArray = (int *)malloc(n * sizeof(*numberArray));
  if (numberArray == NULL) {
    printf("not memory");
    return 0;
  }
  int i;
  for (i = 0; i < n; i++) {
    scanf("%d", &numberArray[i]);
  }
  heapSort(numberArray, n);
  for (i = 0; i < n; i++) {
    printf("%d ", numberArray[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L67
  mov    %rax,%rbx
  mov    0x4(%rsp),%esi
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D25(%rip),%r13
  test   %esi,%esi
  jle    L56
L61:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%esi
  add    $0x4,%r12
  cmp    %ebp,%esi
  jg     L61
L56:
  mov    %rbx,%rdi
  call   <heapSort@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L69
  mov    $0x0,%ebp
  lea    D0(%rip),%r12
L35:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,0x4(%rsp)
  jg     L35
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L69
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
data_type: string
name: retrieve_data
arguments: data_tag: D0
data_type: string
name: retrieve_data
arguments: data_tag: D33
data_type: string

tool: D25: %d

tool: D0: %d 

tool: D33: not memory

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int *numberArray;
  numberArray = (int *)malloc(n * sizeof(*numberArray));
  if (numberArray == NULL) {
    printf("not memory");
    return 0;
  }
  int i;
  for (i = 0; i < n; i++) {
    scanf("%d", &numberArray[i]);
  }
  heapSort(numberArray, n);
  for (i = 0; i < n; i++) {
    printf("%d ", numberArray[i]);
  }
  return 0;
}
```