ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L44:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L44
  sub    $0xdf8,%rsp
  lea    D26(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x5de8(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rax
  lea    0x18(%rsp),%r14
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r13
L118:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L79
L8:
  mov    0x18(%rsp),%eax
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r12
  lea    0x2f00(%rsp),%rbp
  test   %eax,%eax
  jle    L98
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x0(%rbp,%r15,4)
  mov    %eax,(%r12,%r15,4)
  mov    0x18(%rsp),%eax
  add    $0x1,%r15
  cmp    %r15d,%eax
  jg     L72
L98:
  lea    -0x1(%rax),%r9d
  test   %r9d,%r9d
  jle    L116
  mov    0x8(%rsp),%rdi
  sub    $0x2,%eax
  mov    0x20(%rsp),%esi
  lea    0x24(%rsp),%rcx
  lea    (%rdi,%rax,4),%r8
  xor    %edi,%edi
  nopl   (%rax)
L106:
  mov    %esi,%edx
  mov    (%rcx),%esi
  sub    %esi,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cltq
  mov    0x2f00(%rsp,%rax,4),%edx
  test   %edx,%edx
  jne    L92
  movl   $0x1,0x2f00(%rsp,%rax,4)
  add    $0x1,%edi
L92:
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L106
L63:
  cmp    %edi,%r9d
  je     L58
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L8
L79:
  mov    0x5de8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x5df8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L58:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L118
  nopl   0x0(%rax)
L116:
  xor    %edi,%edi
  jmp    L63
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D26: %d

tool: D10: Not jolly


tool: D4: Jolly


assistant: ```c
int main() {
  int integers[3000];
  int check[3000];
  int n_int, n;
  int i, diff, count;
  while (scanf("%d", &n_int) == 1) {
    for (i = 0; i < n_int; i++) {
      scanf("%d", &n);
      integers[i] = n;
      check[i] = 0;
    }
    for (count = 0, i = 0; i < n_int - 1; i++) {
      diff = ((integers[i] - integers[i + 1]) > 0) ? (integers[i] - integers[i + 1]) : (-1 * (integers[i] - integers[i + 1]));
      if (!check[diff]) {
        check[diff] = 1;
        count++;
      }
    }
    if (count == n_int - 1)
      printf("Jolly\n");
    else
      printf("Not jolly\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x5000(%rsp),%r11
L119:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L119
  sub    $0xdf8,%rsp
  lea    D10(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x5de8(%rsp)
  xor    %eax,%eax
  lea    0x28(%rsp),%rax
  lea    0x18(%rsp),%r14
  mov    %rax,0x8(%rsp)
  lea    0x1c(%rsp),%r13
L86:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L83
L115:
  mov    0x18(%rsp),%eax
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r12
  lea    0x2f00(%rsp),%rbp
  test   %eax,%eax
  jle    L5
  nopl   0x0(%rax,%rax,1)
L88:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x0(%rbp,%r15,4)
  mov    %eax,(%r12,%r15,4)
  mov    0x18(%rsp),%eax
  add    $0x1,%r15
  cmp    %r15d,%eax
  jg     L88
L5:
  lea    -0x1(%rax),%r9d
  test   %r9d,%r9d
  jle    L62
  mov    0x8(%rsp),%rdi
  sub    $0x2,%eax
  mov    0x20(%rsp),%esi
  lea    0x24(%rsp),%rcx
  lea    (%rdi,%rax,4),%r8
  xor    %edi,%edi
  nopl   (%rax)
L68:
  mov    %esi,%edx
  mov    (%rcx),%esi
  sub    %esi,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cltq
  mov    0x2f00(%rsp,%rax,4),%edx
  test   %edx,%edx
  jne    L42
  movl   $0x1,0x2f00(%rsp,%rax,4)
  add    $0x1,%edi
L42:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L68
L101:
  cmp    %edi,%r9d
  je     L33
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L115
L83:
  mov    0x5de8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x5df8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L33:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L86
  nopl   0x0(%rax)
L62:
  xor    %edi,%edi
  jmp    L101
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D10: %d

tool: D22: Not jolly


tool: D12: Jolly


assistant: ```c
int main() {
  int integers[3000];
  int check[3000];
  int n_int, n;
  int i, diff, count;
  while (scanf("%d", &n_int) == 1) {
    for (i = 0; i < n_int; i++) {
      scanf("%d", &n);
      integers[i] = n;
      check[i] = 0;
    }
    for (count = 0, i = 0; i < n_int - 1; i++) {
      diff = ((integers[i] - integers[i + 1]) > 0) ? (integers[i] - integers[i + 1]) : (-1 * (integers[i] - integers[i + 1]));
      if (!check[diff]) {
        check[diff] = 1;
        count++;
      }
    }
    if (count == n_int - 1)
      printf("Jolly\n");
    else
      printf("Not jolly\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_LL@plt>
  mov    $0x0,%eax
  call   <test_ULL@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: TEST OK

assistant: ```c
int main() {
  test_LL();
  test_ULL();
  puts("TEST OK");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_LL@plt>
  mov    $0x0,%eax
  call   <test_ULL@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: TEST OK

assistant: ```c
int main() {
  test_LL();
  test_ULL();
  puts("TEST OK");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_LL@plt>
  xor    %eax,%eax
  call   <test_ULL@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: TEST OK

assistant: ```c
int main() {
  test_LL();
  test_ULL();
  puts("TEST OK");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_LL@plt>
  xor    %eax,%eax
  call   <test_ULL@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: TEST OK

assistant: ```c
int main() {
  test_LL();
  test_ULL();
  puts("TEST OK");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <dprintf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: usage: %s interface channel


assistant: ```c
int usage(char *argv0) {
  dprintf(2, "usage: %s interface channel\n", argv0);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D9(%rip),%rsi
  mov    $0x2,%edi
  call   <dprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: usage: %s interface channel


assistant: ```c
int usage(char *argv0) {
  dprintf(2, "usage: %s interface channel\n", argv0);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D5(%rip),%rsi
  mov    $0x2,%edi
  call   <dprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: usage: %s interface channel


assistant: ```c
int usage(char *argv0) {
  dprintf(2, "usage: %s interface channel\n", argv0);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D4(%rip),%rsi
  mov    $0x2,%edi
  call   <dprintf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: usage: %s interface channel


assistant: ```c
int usage(char *argv0) {
  dprintf(2, "usage: %s interface channel\n", argv0);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindExpression>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <HashText@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <HashText@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L24
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L20
  mov    -0x14(%rbp),%eax
  jmp    L10
L20:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <MoveHash@plt>
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L38
  mov    $0xffffffff,%eax
L10:
  leave
  ret
```

assistant: ```c
int FindExpression(char *Text, char *Expression) {
  int CurrentIndex = 0;
  int TextLength = strlen(Text);
  int HashLength = strlen(Expression);
  int CurrentHash = HashText(Text, HashLength);
  int ExpressionHash = HashText(Expression, HashLength);
  while (CurrentIndex < TextLength) {
    if (CurrentHash == ExpressionHash) {
      return CurrentIndex;
    }
    CurrentHash = MoveHash(CurrentHash, HashLength, Text[CurrentIndex], Text[CurrentIndex + HashLength]);
    CurrentIndex = CurrentIndex + 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FindExpression>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %eax,%esi
  mov    %r15,0x8(%rsp)
  mov    %r15,%rdi
  call   <HashText@plt>
  mov    %eax,%ebp
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <HashText@plt>
  test   %r14d,%r14d
  jle    L12
  mov    %eax,%r13d
  cmp    %eax,%ebp
  je     L9
  lea    -0x1(%r14),%r15d
  mov    0x8(%rsp),%rax
  add    %rax,%r15
  mov    %rax,%rbx
  mov    $0x1,%r14d
  sub    %eax,%r14d
L19:
  movslq %r12d,%rax
  movsbl (%rbx,%rax,1),%ecx
  movsbl (%rbx),%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <MoveHash@plt>
  mov    %eax,%ebp
  lea    (%r14,%rbx,1),%eax
  cmp    %r15,%rbx
  je     L57
  add    $0x1,%rbx
  cmp    %ebp,%r13d
  jne    L19
  jmp    L38
L57:
  mov    $0xffffffff,%eax
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L38
L9:
  mov    $0x0,%eax
  jmp    L38
```

assistant: ```c
int FindExpression(char *Text, char *Expression) {
  int CurrentIndex = 0;
  int TextLength = strlen(Text);
  int HashLength = strlen(Expression);
  int CurrentHash = HashText(Text, HashLength);
  int ExpressionHash = HashText(Expression, HashLength);
  while (CurrentIndex < TextLength) {
    if (CurrentHash == ExpressionHash) {
      return CurrentIndex;
    }
    CurrentHash = MoveHash(CurrentHash, HashLength, Text[CurrentIndex], Text[CurrentIndex + HashLength]);
    CurrentIndex = CurrentIndex + 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FindExpression>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <HashText@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,0xc(%rsp)
  call   <HashText@plt>
  test   %r13d,%r13d
  mov    0xc(%rsp),%r8d
  jle    L59
  mov    %eax,%r12d
  cmp    %eax,%r8d
  je     L47
  lea    -0x1(%r13),%r14d
  mov    $0x1,%r13d
  movslq %ebp,%r15
  add    %rbx,%r14
  sub    %ebx,%r13d
  jmp    L55
  nopl   0x0(%rax)
L17:
  add    $0x1,%rbx
  cmp    %r8d,%r12d
  je     L46
L55:
  movsbl (%rbx,%r15,1),%ecx
  movsbl (%rbx),%edx
  mov    %r8d,%edi
  mov    %ebp,%esi
  call   <MoveHash@plt>
  mov    %eax,%r8d
  lea    0x0(%r13,%rbx,1),%eax
  cmp    %r14,%rbx
  jne    L17
L59:
  mov    $0xffffffff,%eax
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  xor    %eax,%eax
  jmp    L46
```

assistant: ```c
int FindExpression(char *Text, char *Expression) {
  int CurrentIndex = 0;
  int TextLength = strlen(Text);
  int HashLength = strlen(Expression);
  int CurrentHash = HashText(Text, HashLength);
  int ExpressionHash = HashText(Expression, HashLength);
  while (CurrentIndex < TextLength) {
    if (CurrentHash == ExpressionHash) {
      return CurrentIndex;
    }
    CurrentHash = MoveHash(CurrentHash, HashLength, Text[CurrentIndex], Text[CurrentIndex + HashLength]);
    CurrentIndex = CurrentIndex + 1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FindExpression>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <HashText@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %eax,0xc(%rsp)
  call   <HashText@plt>
  test   %r13d,%r13d
  mov    0xc(%rsp),%r8d
  jle    L44
  mov    %eax,%r12d
  cmp    %eax,%r8d
  je     L40
  lea    -0x1(%r13),%r14d
  mov    $0x1,%r13d
  movslq %ebp,%r15
  add    %rbx,%r14
  sub    %ebx,%r13d
  jmp    L11
  nopl   0x0(%rax)
L46:
  add    $0x1,%rbx
  cmp    %r8d,%r12d
  je     L17
L11:
  movsbl (%rbx,%r15,1),%ecx
  movsbl (%rbx),%edx
  mov    %r8d,%edi
  mov    %ebp,%esi
  call   <MoveHash@plt>
  mov    %eax,%r8d
  lea    0x0(%r13,%rbx,1),%eax
  cmp    %rbx,%r14
  jne    L46
L44:
  mov    $0xffffffff,%eax
L17:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
int FindExpression(char *Text, char *Expression) {
  int CurrentIndex = 0;
  int TextLength = strlen(Text);
  int HashLength = strlen(Expression);
  int CurrentHash = HashText(Text, HashLength);
  int ExpressionHash = HashText(Expression, HashLength);
  while (CurrentIndex < TextLength) {
    if (CurrentHash == ExpressionHash) {
      return CurrentIndex;
    }
    CurrentHash = MoveHash(CurrentHash, HashLength, Text[CurrentIndex], Text[CurrentIndex + HashLength]);
    CurrentIndex = CurrentIndex + 1;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vec_clone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vec_len@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <umax@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vec_alloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L19
  mov    $0x0,%eax
  jmp    L38
L19:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vec_join@plt>
  test   %rax,%rax
  je     L41
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <vec_free@plt>
  mov    $0x0,%eax
  jmp    L38
L41:
  mov    -0x10(%rbp),%rax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void *vec_clone(void const *vec, size_t size) {
  void *ret = 0x0;
  ret = vec_alloc(size, umax(vec_len(vec), 8));
  if (!ret)
    return 0;
  if (vec_join(&ret, vec, size)) {
    vec_free(ret);
    return 0;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vec_clone>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <vec_len@plt>
  mov    %eax,%edi
  mov    $0x8,%esi
  call   <umax@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <vec_alloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L23
  mov    %rsp,%rdi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <vec_join@plt>
  mov    %rax,%rdx
  mov    (%rsp),%rax
  test   %rdx,%rdx
  jne    L18
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rax,%rdi
  call   <vec_free@plt>
  mov    $0x0,%eax
  jmp    L23
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *vec_clone(void const *vec, size_t size) {
  void *ret = 0x0;
  ret = vec_alloc(size, umax(vec_len(vec), 8));
  if (!ret)
    return 0;
  if (vec_join(&ret, vec, size)) {
    vec_free(ret);
    return 0;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vec_clone>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <vec_len@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <umax@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <vec_alloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L9
  mov    %rsp,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <vec_join@plt>
  mov    %rax,%r8
  mov    (%rsp),%rax
  test   %r8,%r8
  jne    L4
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  mov    %rax,%rdi
  call   <vec_free@plt>
  xor    %eax,%eax
  jmp    L9
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *vec_clone(void const *vec, size_t size) {
  void *ret = 0x0;
  ret = vec_alloc(size, umax(vec_len(vec), 8));
  if (!ret)
    return 0;
  if (vec_join(&ret, vec, size)) {
    vec_free(ret);
    return 0;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vec_clone>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <vec_len@plt>
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <umax@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <vec_alloc@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  je     L14
  mov    %rsp,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <vec_join@plt>
  mov    %rax,%r8
  mov    (%rsp),%rax
  test   %r8,%r8
  jne    L32
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L32:
  mov    %rax,%rdi
  call   <vec_free@plt>
  xor    %eax,%eax
  jmp    L14
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *vec_clone(void const *vec, size_t size) {
  void *ret = 0x0;
  ret = vec_alloc(size, umax(vec_len(vec), 8));
  if (!ret)
    return 0;
  if (vec_join(&ret, vec, size)) {
    vec_free(ret);
    return 0;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcnt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L23
  addl   $0x1,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcnt(char *string, char c) {
  int i, cnt = 0;
  for (i = 0; string[i] != '\0'; i++) {
    if (string[i] == c)
      cnt++;
  }
  return cnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcnt>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdi
  mov    $0x0,%edx
L9:
  cmp    %al,%sil
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L9
L3:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L3
```

assistant: ```c
int strcnt(char *string, char c) {
  int i, cnt = 0;
  for (i = 0; string[i] != '\0'; i++) {
    if (string[i] == c)
      cnt++;
  }
  return cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcnt>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L2:
  cmp    %al,%sil
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strcnt(char *string, char c) {
  int i, cnt = 0;
  for (i = 0; string[i] != '\0'; i++) {
    if (string[i] == c)
      cnt++;
  }
  return cnt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcnt>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L17:
  cmp    %sil,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L17
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strcnt(char *string, char c) {
  int i, cnt = 0;
  for (i = 0; string[i] != '\0'; i++) {
    if (string[i] == c)
      cnt++;
  }
  return cnt;
}
```