user: 这段汇编代码用C语言表示是什么样的?

```asm
<recipe>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rax
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x58(%rbp)
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x38(%rbp)
  xor    %edx,%edx
  lea    (%rcx,%rcx,4),%rdx
  mov    %rsp,%rdi
  lea    0xf(%rcx,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rdi
  and    $0xfffffffffffffff0,%rsi
  cmp    %rdi,%rsp
  je     L38
L17:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L17
L38:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L22
L2:
  lea    0xf(,%rcx,8),%rdx
  mov    %rsp,%rsi
  mov    %rsp,%r12
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L150
L12:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L12
L150:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L153
L18:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L115
  mov    %eax,%eax
  movsd  D8(%rip),%xmm2
  mov    %rbx,%r14
  mov    %r12,%r13
  lea    (%rbx,%rax,8),%rax
  lea    -0x40(%rbp),%r15
  mov    %rax,-0x48(%rbp)
  movsd  %xmm2,-0x50(%rbp)
  nop
L41:
  mov    %r14,%rcx
  mov    %r15,%rdx
  lea    D55(%rip),%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  movsd  (%r14),%xmm0
  ucomisd D28(%rip),%xmm0
  jp     L81
  jne    L81
  movsd  -0x58(%rbp),%xmm1
  mulsd  -0x40(%rbp),%xmm1
  add    $0x15,%r13
  add    $0x8,%r14
  mov    D38(%rip),%rax
  mov    %rax,-0x8(%r14)
  movsd  %xmm1,-0x50(%rbp)
  cmp    -0x48(%rbp),%r14
  jne    L41
L147:
  lea    D11(%rip),%r14
  nopl   (%rax)
L16:
  movsd  -0x50(%rbp),%xmm0
  mulsd  (%rbx),%xmm0
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x8,%rbx
  add    $0x15,%r12
  call   <printf@plt>
  cmp    -0x48(%rbp),%rbx
  jne    L16
L115:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L114
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L22:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L81:
  divsd  D28(%rip),%xmm0
  add    $0x15,%r13
  movsd  %xmm0,(%r14)
  add    $0x8,%r14
  cmp    -0x48(%rbp),%r14
  jne    L41
  jmp    L147
L153:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L18
L114:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D55
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: f64
name: disassemble_data
arguments: tag: D38
type_guessed: f64
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D55: %s %lf %lf

tool: D28: 100

tool: D38: 1

tool: D11: %s %.1lf


assistant: ```c
void recipe(int ingredients, double scale) {
  char names[ingredients][21];
  double percentage[ingredients];
  double migs = -1;
  for (int i = 0; i < ingredients; i++) {
    double g;
    scanf("%s %lf %lf", names[i], &g, percentage + i);
    if (percentage[i] == 100.0)
      migs = g * scale;
    percentage[i] /= 100.0;
  }
  for (int i = 0; i < ingredients; i++)
    printf("%s %.1lf\n", names[i], migs * percentage[i]);
}
```