ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minimum>:
  endbr64
  mov    (%rdi),%eax
  mov    %rdi,%rdx
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L18
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%esi
  cmp    $0x2,%esi
  jbe    L6
  mov    %edi,%esi
  movd   %eax,%xmm4
  lea    0x4(%rdx),%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm4,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L48:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L48
  movdqa %xmm0,%xmm2
  mov    %edi,%r8d
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%r8d
  movdqa %xmm2,%xmm1
  lea    0x1(%r8),%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %r8d,%edi
  je     L49
L8:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r8
  mov    (%rdx,%rdi,4),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  lea    0x1(%rsi),%edi
  cmp    %edi,%ecx
  jle    L18
  mov    0x4(%rdx,%r8,1),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L18
  mov    0x8(%rdx,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L18:
  ret
  nopl   (%rax)
L49:
  ret
L6:
  mov    $0x1,%esi
  jmp    L8
```

assistant: ```c
int minimum(int values[], int nelms) {
  int minValue, i;
  minValue = values[0];
  for (i = 1; i < nelms; ++i) {
    if (values[i] < minValue) {
      minValue = values[i];
    }
  }
  return minValue;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PTHREAD_MUTEXATTR_INIT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutexattr_init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: %s


assistant: ```c
int PTHREAD_MUTEXATTR_INIT(pthread_mutexattr_t *a) {
  int err;
  if (err = pthread_mutexattr_init(a)) {
    printf("%s\n", strerror(err));
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PTHREAD_MUTEXATTR_INIT>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutexattr_init@plt>
  test   %eax,%eax
  jne    L8
L10:
  add    $0x8,%rsp
  ret
L8:
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: %s


assistant: ```c
int PTHREAD_MUTEXATTR_INIT(pthread_mutexattr_t *a) {
  int err;
  if (err = pthread_mutexattr_init(a)) {
    printf("%s\n", strerror(err));
    abort();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<PTHREAD_MUTEXATTR_INIT>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutexattr_init@plt>
  test   %eax,%eax
  jne    L6
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %eax,%edi
  call   <strerror@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <abort@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s


assistant: ```c
int PTHREAD_MUTEXATTR_INIT(pthread_mutexattr_t *a) {
  int err;
  if (err = pthread_mutexattr_init(a)) {
    printf("%s\n", strerror(err));
    abort();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PTHREAD_MUTEXATTR_INIT>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutexattr_init@plt>
  test   %eax,%eax
  jne    L4
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %eax,%edi
  call   <strerror@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <abort@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: %s


assistant: ```c
int PTHREAD_MUTEXATTR_INIT(pthread_mutexattr_t *a) {
  int err;
  if (err = pthread_mutexattr_init(a)) {
    printf("%s\n", strerror(err));
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<char_l2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rsi
  lea    -0x20(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <l2a@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    $0x1,%rax
  jne    L39
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x30(%rbp)
  jge    L40
L39:
  mov    -0x38(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x4,%eax
  jmp    L27
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
long char_l2a(number, nplace, string, nchar)
long number;
long nplace;
char string[];
long *nchar;
{
  long status;
  char *pbuff, *pstr, *l2a();
  pstr = string;
  pbuff = l2a(number, (nplace - 1), nchar, &status);
  if ((status != 1L) || (*nchar > nplace)) {
    *string = (char)'\0';
    *nchar = 0;
    return (4L);
  }
  for (; *pbuff != (char)'\0'; pstr++, pbuff++) {
    *pstr = *pbuff;
  }
  *pstr = (char)'\0';
  return (1L);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<char_l2a>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  lea    -0x1(%rsi),%rsi
  mov    %rbp,%rdx
  call   <l2a@plt>
  mov    (%rsp),%rcx
  cmp    $0x1,%rcx
  jne    L59
  cmp    %r12,0x0(%rbp)
  jg     L59
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L5
L56:
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L56
L5:
  movb   $0x0,(%rbx)
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rcx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  movb   $0x0,(%rbx)
  movq   $0x0,0x0(%rbp)
  mov    $0x4,%ecx
  jmp    L28
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long char_l2a(number, nplace, string, nchar)
long number;
long nplace;
char string[];
long *nchar;
{
  long status;
  char *pbuff, *pstr, *l2a();
  pstr = string;
  pbuff = l2a(number, (nplace - 1), nchar, &status);
  if ((status != 1L) || (*nchar > nplace)) {
    *string = (char)'\0';
    *nchar = 0;
    return (4L);
  }
  for (; *pbuff != (char)'\0'; pstr++, pbuff++) {
    *pstr = *pbuff;
  }
  *pstr = (char)'\0';
  return (1L);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<char_l2a>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  sub    $0x1,%rsi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rbp,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <l2a@plt>
  mov    (%rsp),%r8
  cmp    $0x1,%r8
  jne    L42
  cmp    %r12,0x0(%rbp)
  jle    L56
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %dl,(%rbx)
  add    $0x1,%rax
  add    $0x1,%rbx
L56:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L23
  movb   $0x0,(%rbx)
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  movb   $0x0,(%rbx)
  mov    $0x4,%r8d
  movq   $0x0,0x0(%rbp)
  jmp    L15
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long char_l2a(number, nplace, string, nchar)
long number;
long nplace;
char string[];
long *nchar;
{
  long status;
  char *pbuff, *pstr, *l2a();
  pstr = string;
  pbuff = l2a(number, (nplace - 1), nchar, &status);
  if ((status != 1L) || (*nchar > nplace)) {
    *string = (char)'\0';
    *nchar = 0;
    return (4L);
  }
  for (; *pbuff != (char)'\0'; pstr++, pbuff++) {
    *pstr = *pbuff;
  }
  *pstr = (char)'\0';
  return (1L);
}
```
user: Translate the below assembly code into C programming language:

```asm
<char_l2a>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  sub    $0x1,%rsi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rbp,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <l2a@plt>
  mov    (%rsp),%r8
  cmp    $0x1,%r8
  jne    L15
  cmp    %r12,0x0(%rbp)
  jle    L16
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %dl,(%rbx)
  add    $0x1,%rax
  add    $0x1,%rbx
L16:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L1
  movb   $0x0,(%rbx)
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  movb   $0x0,(%rbx)
  mov    $0x4,%r8d
  movq   $0x0,0x0(%rbp)
  jmp    L31
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long char_l2a(number, nplace, string, nchar)
long number;
long nplace;
char string[];
long *nchar;
{
  long status;
  char *pbuff, *pstr, *l2a();
  pstr = string;
  pbuff = l2a(number, (nplace - 1), nchar, &status);
  if ((status != 1L) || (*nchar > nplace)) {
    *string = (char)'\0';
    *nchar = 0;
    return (4L);
  }
  for (; *pbuff != (char)'\0'; pstr++, pbuff++) {
    *pstr = *pbuff;
  }
  *pstr = (char)'\0';
  return (1L);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_cos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc30(%rbp),%rax
  mov    $0xc1c,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  movl   $0x0,-0xc4c(%rbp)
  movl   $0x0,-0xc4c(%rbp)
  jmp    L64
L65:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc4c(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0xc40(%rbp)
  mov    -0xc40(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  D17(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0xc38(%rbp)
  movsd  -0xc38(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc44(%rbp)
  mov    $0xf,%eax
  sub    -0xc44(%rbp),%eax
  mov    -0xc4c(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0xc30,%rax
  movb   $0x2e,(%rax)
  addl   $0x1,-0xc4c(%rbp)
L64:
  cmpl   $0x63,-0xc4c(%rbp)
  jle    L65
  movl   $0x0,-0xc4c(%rbp)
  jmp    L67
L46:
  movl   $0x0,-0xc48(%rbp)
  movl   $0x0,-0xc48(%rbp)
  jmp    L99
L61:
  cmpl   $0xf,-0xc4c(%rbp)
  jne    L11
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L55
L11:
  mov    -0xc48(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xc4c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0xc30,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L55
L29:
  mov    -0xc48(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xc4c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0xc30,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L55:
  addl   $0x1,-0xc48(%rbp)
L99:
  cmpl   $0x63,-0xc48(%rbp)
  jle    L61
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc4c(%rbp)
L67:
  cmpl   $0x1e,-0xc4c(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type: f64
name: retrieve_data
arguments: label: D17
type: f64
name: retrieve_data
arguments: label: D3
type: f64

tool: D18: 0.08

tool: D17: 15

tool: D3: 0.5

assistant: ```c
int print_cos() {
  char map[31][100];
  bzero(map, sizeof(map));
  int i = 0;
  for (i = 0; i < 100; i++) {
    double x = i * 0.08;
    double y = cos(x) * 15.0;
    int ypos = (int)(y + 0.5);
    map[15 - ypos][i] = '.';
  }
  for (i = 0; i < 31; i++) {
    int j = 0;
    for (j = 0; j < 100; j++) {
      if (15 == i) {
        printf("*");
      } else if (0 == map[i][j]) {
        printf(" ");
      } else {
        printf("%c", map[i][j]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_cos>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xc1c,%esi
  call   <bzero@plt>
  mov    $0x0,%ebx
  mov    $0xf,%ebp
L88:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D5(%rip),%xmm0
  call   <cos@plt>
  movslq %ebx,%rdx
  mulsd  D24(%rip),%xmm0
  addsd  D0(%rip),%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %ebp,%eax
  sub    %ecx,%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xc30(%rsp,%rax,4),%rax
  movb   $0x2e,-0xc30(%rdx,%rax,1)
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L88
  lea    0x64(%rsp),%r12
  mov    $0x0,%ebp
  jmp    L35
L70:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L73
L93:
  movsbl %dil,%edi
  call   <putchar@plt>
L73:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L20
L28:
  cmp    $0xf,%ebp
  je     L70
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L93
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L73
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  add    $0x64,%r12
  cmp    $0x1f,%ebp
  je     L66
L35:
  lea    -0x64(%r12),%rbx
  jmp    L28
L66:
  mov    0xc28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  mov    $0x0,%eax
  add    $0xc30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: f64
name: unpack_data
arguments: label: D24
data_type: f64
name: unpack_data
arguments: label: D0
data_type: f64

tool: D5: 0.08

tool: D24: 15

tool: D0: 0.5

assistant: ```c
int print_cos() {
  char map[31][100];
  bzero(map, sizeof(map));
  int i = 0;
  for (i = 0; i < 100; i++) {
    double x = i * 0.08;
    double y = cos(x) * 15.0;
    int ypos = (int)(y + 0.5);
    map[15 - ypos][i] = '.';
  }
  for (i = 0; i < 31; i++) {
    int j = 0;
    for (j = 0; j < 100; j++) {
      if (15 == i) {
        printf("*");
      } else if (0 == map[i][j]) {
        printf(" ");
      } else {
        printf("%c", map[i][j]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_cos>:
  endbr64
  push   %r12
  mov    $0xc1c,%esi
  push   %rbp
  mov    $0xf,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <bzero@plt>
  movsd  D38(%rip),%xmm0
  jmp    L51
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D39(%rip),%xmm0
  call   <cos@plt>
L51:
  mulsd  D11(%rip),%xmm0
  mov    %ebp,%eax
  movslq %ebx,%rdx
  add    $0x1,%ebx
  addsd  D37(%rip),%xmm0
  cvttsd2si %xmm0,%ecx
  sub    %ecx,%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xc30(%rsp,%rax,4),%rax
  movb   $0x2e,-0xc30(%rdx,%rax,1)
  cmp    $0x64,%ebx
  jne    L14
  lea    0x64(%rsp),%r12
  xor    %ebp,%ebp
L97:
  lea    -0x64(%r12),%rbx
  jmp    L99
L64:
  mov    $0x20,%edi
  call   <putchar@plt>
L9:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L91
L99:
  cmp    $0xf,%ebp
  je     L8
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L64
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L99
L91:
  mov    $0xa,%edi
  add    $0x1,%ebp
  lea    0x64(%rbx),%r12
  call   <putchar@plt>
  cmp    $0x1f,%ebp
  jne    L97
  mov    0xc28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0xc30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L9
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D39
type_infered: f64
name: unpack_data
arguments: data_tag: D11
type_infered: f64
name: unpack_data
arguments: data_tag: D37
type_infered: f64

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D39: 0.08

tool: D11: 15

tool: D37: 0.5

assistant: ```c
int print_cos() {
  char map[31][100];
  bzero(map, sizeof(map));
  int i = 0;
  for (i = 0; i < 100; i++) {
    double x = i * 0.08;
    double y = cos(x) * 15.0;
    int ypos = (int)(y + 0.5);
    map[15 - ypos][i] = '.';
  }
  for (i = 0; i < 31; i++) {
    int j = 0;
    for (j = 0; j < 100; j++) {
      if (15 == i) {
        printf("*");
      } else if (0 == map[i][j]) {
        printf(" ");
      } else {
        printf("%c", map[i][j]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_cos>:
  endbr64
  push   %r12
  mov    $0xc1c,%esi
  push   %rbp
  mov    $0xf,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <bzero@plt>
  movb   $0x2e,(%rsp)
  nopl   (%rax)
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D23(%rip),%xmm0
  call   <cos@plt>
  mulsd  D10(%rip),%xmm0
  mov    %ebp,%eax
  movslq %ebx,%rdx
  addsd  D15(%rip),%xmm0
  add    $0x1,%ebx
  cvttsd2si %xmm0,%ecx
  sub    %ecx,%eax
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0xc30(%rsp,%rax,4),%rax
  movb   $0x2e,-0xc30(%rdx,%rax,1)
  cmp    $0x64,%ebx
  jne    L11
  lea    0x64(%rsp),%rbp
  xor    %r12d,%r12d
L28:
  cmp    $0xf,%r12d
  je     L77
L49:
  lea    -0x64(%rbp),%rbx
  nopl   0x0(%rax)
L38:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L55
  mov    $0x20,%edi
L55:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L38
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x64(%rbx),%rbp
  call   <putchar@plt>
  cmp    $0x1f,%r12d
  jne    L28
  mov    0xc28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0xc30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L77:
  mov    $0x64,%ebx
  nopl   0x0(%rax)
L76:
  mov    $0x2a,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L76
  mov    $0xa,%edi
  add    $0x64,%rbp
  mov    $0x10,%r12d
  call   <putchar@plt>
  jmp    L49
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
datatype: f64
name: disassemble_data
arguments: data_tag: D10
datatype: f64
name: disassemble_data
arguments: data_tag: D15
datatype: f64

tool: D23: 0.08

tool: D10: 15

tool: D15: 0.5

assistant: ```c
int print_cos() {
  char map[31][100];
  bzero(map, sizeof(map));
  int i = 0;
  for (i = 0; i < 100; i++) {
    double x = i * 0.08;
    double y = cos(x) * 15.0;
    int ypos = (int)(y + 0.5);
    map[15 - ypos][i] = '.';
  }
  for (i = 0; i < 31; i++) {
    int j = 0;
    for (j = 0; j < 100; j++) {
      if (15 == i) {
        printf("*");
      } else if (0 == map[i][j]) {
        printf(" ");
      } else {
        printf("%c", map[i][j]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cipher_aes_b64_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L40
  cmpl   $0x0,-0x2c(%rbp)
  jne    L10
L40:
  mov    $0x0,%eax
  jmp    L24
L10:
  lea    -0x1c(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <unbase64@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L24
L44:
  mov    -0x1c(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L77
  mov    -0x1c(%rbp),%eax
  cmp    $0xf,%eax
  jg     L16
L77:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L24
L16:
  mov    -0x1c(%rbp),%esi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cipher_aes_decrypt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

assistant: ```c
char *cipher_aes_b64_decrypt(const unsigned char *in, int inlen, int *outlen, const uint8_t *key) {
  *outlen = 0;
  if (!in || inlen == 0) {
    return NULL;
  }
  int ub64len;
  unsigned char *ub64 = unbase64((const char *)in, inlen, &ub64len);
  if (!ub64) {
    return NULL;
  }
  if ((ub64len % (4 * 4)) || ub64len < (4 * 4)) {
    memset(ub64, 0, ub64len);
    free(ub64);
    return NULL;
  }
  char *ret = cipher_aes_decrypt(ub64, ub64len, outlen, key);
  memset(ub64, 0, ub64len);
  free(ub64);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cipher_aes_b64_decrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdx)
  test   %rdi,%rdi
  je     L48
  mov    %rdx,%rbp
  mov    %rcx,%r12
  test   %esi,%esi
  je     L48
  lea    0x4(%rsp),%rdx
  call   <unbase64@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L21
  mov    0x4(%rsp),%esi
  test   $0xf,%sil
  jne    L70
  cmp    $0xf,%esi
  jle    L70
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <cipher_aes_decrypt@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <free@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L70:
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L39
L48:
  mov    $0x0,%ebp
  jmp    L39
L21:
  mov    %rax,%rbp
  jmp    L39
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *cipher_aes_b64_decrypt(const unsigned char *in, int inlen, int *outlen, const uint8_t *key) {
  *outlen = 0;
  if (!in || inlen == 0) {
    return NULL;
  }
  int ub64len;
  unsigned char *ub64 = unbase64((const char *)in, inlen, &ub64len);
  if (!ub64) {
    return NULL;
  }
  if ((ub64len % (4 * 4)) || ub64len < (4 * 4)) {
    memset(ub64, 0, ub64len);
    free(ub64);
    return NULL;
  }
  char *ret = cipher_aes_decrypt(ub64, ub64len, outlen, key);
  memset(ub64, 0, ub64len);
  free(ub64);
  return ret;
}
```