ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D59(%rip),%rbx
  lea    D26(%rip),%rbp
  lea    D68(%rip),%r12
  lea    D64(%rip),%r13
  jmp    L20
L63:
  cmp    $0x1,%edi
  ja     L107
  mov    $0x0,%esi
  jmp    L53
L107:
  mov    $0x0,%esi
  jmp    L3
L0:
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
L20:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L34
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L34
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%r8d
  shr    %r8d
  cmp    $0x3,%edi
  jbe    L63
  mov    $0x2,%ecx
  mov    $0x0,%esi
L108:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jbe    L108
L3:
  add    $0x1,%esi
L53:
  cmp    %edi,%esi
  jb     L0
  je     L2
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L61
L2:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L61
L34:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D59
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string
name: disassemble_data
arguments: data_label: D68
datatype: string
name: disassemble_data
arguments: data_label: D64
datatype: string
name: disassemble_data
arguments: data_label: D58
datatype: string
name: disassemble_data
arguments: data_label: D39
datatype: string

tool: D5: PERFECTION OUTPUT

tool: D59: %u

tool: D26: %5u  

tool: D68: ABUNDANT

tool: D64: PERFECT

tool: D58: DEFICIENT

tool: D39: END OF OUTPUT

assistant: ```c
void main() {
  unsigned s, n, i;
  printf("PERFECTION OUTPUT\n");
  while (scanf("%u", &n) && n) {
    s = 0;
    printf("%5u  ", n);
    for (i = 2; i <= n / 2; i++)
      if (!(n % i))
        s += i;
    if (n > 1)
      s++;
    if (n > s)
      printf("DEFICIENT");
    else if (n == s)
      printf("PERFECT");
    else
      printf("ABUNDANT");
    printf("\n");
  }
  printf("END OF OUTPUT\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  lea    D66(%rip),%r15
  push   %r14
  lea    D63(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D64(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L99:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L5
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%r8d
  shr    %r8d
  cmp    $0x3,%edi
  jbe    L69
  mov    $0x2,%ecx
  xor    %esi,%esi
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L117:
  mov    %eax,%ecx
L62:
  xor    %edx,%edx
  mov    %edi,%eax
  div    %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  lea    0x1(%rcx),%eax
  cmp    %ecx,%r8d
  jne    L117
L123:
  add    $0x1,%esi
  cmp    %edi,%esi
  jb     L60
L82:
  je     L110
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L99
L5:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  xor    %esi,%esi
  cmp    $0x1,%edi
  ja     L123
  cmp    %edi,%esi
  jae    L82
L60:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L110:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D44
type: string
name: extract_symbolic_data
arguments: data_tag: D66
type: string
name: extract_symbolic_data
arguments: data_tag: D63
type: string
name: extract_symbolic_data
arguments: data_tag: D25
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D64
type: string
name: extract_symbolic_data
arguments: data_tag: D46
type: string

tool: D44: PERFECTION OUTPUT

tool: D66: PERFECT

tool: D63: DEFICIENT

tool: D25: ABUNDANT

tool: D24: %5u  

tool: D64: %u

tool: D46: END OF OUTPUT

assistant: ```c
void main() {
  unsigned s, n, i;
  printf("PERFECTION OUTPUT\n");
  while (scanf("%u", &n) && n) {
    s = 0;
    printf("%5u  ", n);
    for (i = 2; i <= n / 2; i++)
      if (!(n % i))
        s += i;
    if (n > 1)
      s++;
    if (n > s)
      printf("DEFICIENT");
    else if (n == s)
      printf("PERFECT");
    else
      printf("ABUNDANT");
    printf("\n");
  }
  printf("END OF OUTPUT\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D50(%rip),%rdi
  lea    D8(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  lea    D39(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D64(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L20
  cs nopw 0x0(%rax,%rax,1)
L127:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L20
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    %edi,%r8d
  shr    %r8d
  cmp    $0x3,%edi
  jbe    L17
  mov    $0x2,%ecx
  xor    %esi,%esi
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %eax,%ecx
L39:
  xor    %edx,%edx
  mov    %edi,%eax
  div    %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  lea    0x1(%rcx),%eax
  cmp    %r8d,%ecx
  jne    L36
L104:
  add    $0x1,%esi
  cmp    %edi,%esi
  jb     L108
L18:
  je     L122
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L118:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L127
L20:
  lea    D62(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  xor    %esi,%esi
  cmp    $0x1,%edi
  ja     L104
  cmp    %edi,%esi
  jae    L18
L108:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L118
  nopw   0x0(%rax,%rax,1)
L122:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L118
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D50
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D27
type_infered: string
name: read_data
arguments: data_tag: D39
type_infered: string
name: read_data
arguments: data_tag: D64
type_infered: string
name: read_data
arguments: data_tag: D62
type_infered: string

tool: D50: PERFECTION OUTPUT

tool: D8: PERFECT

tool: D21: DEFICIENT

tool: D27: ABUNDANT

tool: D39: %5u  

tool: D64: %u

tool: D62: END OF OUTPUT

assistant: ```c
void main() {
  unsigned s, n, i;
  printf("PERFECTION OUTPUT\n");
  while (scanf("%u", &n) && n) {
    s = 0;
    printf("%5u  ", n);
    for (i = 2; i <= n / 2; i++)
      if (!(n % i))
        s += i;
    if (n > 1)
      s++;
    if (n > s)
      printf("DEFICIENT");
    else if (n == s)
      printf("PERFECT");
    else
      printf("ABUNDANT");
    printf("\n");
  }
  printf("END OF OUTPUT\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x64,-0x18(%rbp)
  jmp    L26
L21:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L11
  addl   $0x1,-0x14(%rbp)
L11:
  addl   $0x1,-0x18(%rbp)
L26:
  cmpl   $0x3e7,-0x18(%rbp)
  jle    L21
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D1
datatype: string

tool: D2: %d %d %d


tool: D1: 
 Result: %d


assistant: ```c
main() {
  int a, b, c;
  int number, counter = 0;
  int d;
  for (number = 100; number <= 999; number++) {
    a = number / 100;
    b = (number / 10) % 10;
    c = (number % 100) % 10;
    d = b + c;
    printf("%d %d %d\n", a, b, c);
    if (a == d) {
      counter++;
    }
  }
  printf("\n Result: %d\n", counter);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%ebp
  mov    $0x0,%r12d
  lea    D23(%rip),%r14
L7:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  je     L2
  movslq %ebp,%rax
  imul   $0x51eb851f,%rax,%rbx
  sar    $0x25,%rbx
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%ebx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%ebx,%eax
  mov    %ebp,%esi
  sub    %eax,%esi
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %esi,%ecx
  lea    (%rdx,%rsi,1),%r13d
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r13d,%ebx
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  jmp    L7
L2:
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D23: %d %d %d


tool: D19: 
 Result: %d


assistant: ```c
main() {
  int a, b, c;
  int number, counter = 0;
  int d;
  for (number = 100; number <= 999; number++) {
    a = number / 100;
    b = (number / 10) % 10;
    c = (number % 100) % 10;
    d = b + c;
    printf("%d %d %d\n", a, b, c);
    if (a == d) {
      counter++;
    }
  }
  printf("\n Result: %d\n", counter);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  push   %r14
  xor    %eax,%eax
  mov    $0xcccccccd,%r14d
  push   %r13
  push   %r12
  mov    $0x64,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  jmp    L2
  nopl   0x0(%rax)
L19:
  mov    %r12d,%eax
  mov    %r12d,%esi
  mov    %rbx,%rdi
  imul   $0x51eb851f,%rax,%r15
  imul   %r14,%rax
  shr    $0x25,%r15
  shr    $0x23,%rax
  mov    %eax,%edx
  imul   %r14,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%r15d,%eax
  sub    %eax,%esi
  mov    %esi,%ecx
  imul   %r14,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  lea    (%rdx,%rsi,1),%r13d
  mov    %esi,%ecx
  mov    %r15d,%esi
  call   <printf@plt>
  xor    %eax,%eax
  cmp    %r13d,%r15d
  sete   %al
  add    %eax,%ebp
L2:
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L19
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string

tool: D1: %d %d %d


tool: D14: 
 Result: %d


assistant: ```c
main() {
  int a, b, c;
  int number, counter = 0;
  int d;
  for (number = 100; number <= 999; number++) {
    a = number / 100;
    b = (number / 10) % 10;
    c = (number % 100) % 10;
    d = b + c;
    printf("%d %d %d\n", a, b, c);
    if (a == d) {
      counter++;
    }
  }
  printf("\n Result: %d\n", counter);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  push   %r14
  xor    %eax,%eax
  mov    $0xcccccccd,%r14d
  push   %r13
  push   %r12
  mov    $0x65,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%eax
  mov    %r12d,%esi
  mov    %rbx,%rdi
  imul   $0x51eb851f,%rax,%r15
  imul   %r14,%rax
  shr    $0x25,%r15
  shr    $0x23,%rax
  mov    %eax,%edx
  imul   %r14,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%r15d,%eax
  sub    %eax,%esi
  mov    %esi,%ecx
  imul   %r14,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  lea    (%rdx,%rsi,1),%r13d
  mov    %esi,%ecx
  mov    %r15d,%esi
  call   <printf@plt>
  xor    %eax,%eax
  cmp    %r13d,%r15d
  sete   %al
  add    $0x1,%r12d
  add    %eax,%ebp
  cmp    $0x3e8,%r12d
  jne    L5
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D15: %d %d %d


tool: D0: 
 Result: %d


assistant: ```c
main() {
  int a, b, c;
  int number, counter = 0;
  int d;
  for (number = 100; number <= 999; number++) {
    a = number / 100;
    b = (number / 10) % 10;
    c = (number % 100) % 10;
    d = b + c;
    printf("%d %d %d\n", a, b, c);
    if (a == d) {
      counter++;
    }
  }
  printf("\n Result: %d\n", counter);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <enum1@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", enum1());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <enum1@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", enum1());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <enum1@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", enum1());
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <enum1@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", enum1());
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<basic_isort5p>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    %rcx,%rax
  mov    (%r8),%edx
  mov    (%rcx),%esi
  mov    $0x0,%ecx
  cmp    %esi,%edx
  jge    L64
  cmp    (%r10),%edx
  jl     L65
  cmp    (%r9),%edx
  jl     L39
  cmp    (%rdi),%edx
  jl     L23
  mov    %edx,(%rax)
  mov    %esi,(%r8)
  mov    $0x1,%ecx
  jmp    L64
L65:
  mov    %edx,(%rax)
  mov    %esi,(%r8)
  mov    (%rdi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rdi)
  mov    %edx,(%rax)
  mov    (%r9),%eax
  mov    (%rdi),%edx
  mov    %edx,(%r9)
  mov    %eax,(%rdi)
  mov    (%r10),%eax
  mov    (%r9),%edx
  mov    %edx,(%r10)
  mov    %eax,(%r9)
  mov    $0x4,%ecx
L64:
  mov    %ecx,%eax
  ret
L39:
  mov    %edx,(%rax)
  mov    %esi,(%r8)
  mov    (%rdi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rdi)
  mov    %edx,(%rax)
  mov    (%r9),%eax
  mov    (%rdi),%edx
  mov    %edx,(%r9)
  mov    %eax,(%rdi)
  mov    $0x3,%ecx
  jmp    L64
L23:
  mov    %edx,(%rax)
  mov    %esi,(%r8)
  mov    (%rdi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rdi)
  mov    %edx,(%rax)
  mov    $0x2,%ecx
  jmp    L64
```

assistant: ```c
int basic_isort5p(a, b, c, d, e)
int *a, *b, *c, *d, *e;
{
  int swaps = 0, aux;
  if (*e < *d) {
    if (*e < *a) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
      do {
        aux = *b;
        *b = *c;
        *c = aux;
        swaps++;
      } while (0);
      do {
        aux = *a;
        *a = *b;
        *b = aux;
        swaps++;
      } while (0);
    } else if (*e < *b) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
      do {
        aux = *b;
        *b = *c;
        *c = aux;
        swaps++;
      } while (0);
    } else if (*e < *c) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
    } else
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
  }
  return (swaps);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<basic_isort5p>:
  endbr64
  mov    %rdi,%r10
  mov    %rcx,%rax
  mov    %rsi,%rdi
  mov    (%rcx),%ecx
  mov    %rdx,%rsi
  mov    (%r8),%edx
  xor    %r9d,%r9d
  cmp    %ecx,%edx
  jge    L25
  cmp    (%r10),%edx
  jl     L30
  cmp    (%rdi),%edx
  jl     L16
  cmp    (%rsi),%edx
  mov    $0x1,%r9d
  mov    %edx,(%rax)
  mov    %ecx,(%r8)
  jl     L46
L25:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %edx,(%rax)
  mov    $0x4,%r9d
  mov    %ecx,(%r8)
  mov    (%rsi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    %edx,(%rax)
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  mov    (%r10),%eax
  mov    (%rdi),%edx
  mov    %edx,(%r10)
  mov    %eax,(%rdi)
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L46:
  mov    (%rsi),%edx
  mov    (%rax),%ecx
  mov    $0x2,%r9d
  mov    %ecx,(%rsi)
  mov    %edx,(%rax)
  jmp    L25
L16:
  mov    %edx,(%rax)
  mov    $0x3,%r9d
  mov    %ecx,(%r8)
  mov    (%rsi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    %edx,(%rax)
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  mov    %r9d,%eax
  ret
```

assistant: ```c
int basic_isort5p(a, b, c, d, e)
int *a, *b, *c, *d, *e;
{
  int swaps = 0, aux;
  if (*e < *d) {
    if (*e < *a) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
      do {
        aux = *b;
        *b = *c;
        *c = aux;
        swaps++;
      } while (0);
      do {
        aux = *a;
        *a = *b;
        *b = aux;
        swaps++;
      } while (0);
    } else if (*e < *b) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
      do {
        aux = *b;
        *b = *c;
        *c = aux;
        swaps++;
      } while (0);
    } else if (*e < *c) {
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
      do {
        aux = *c;
        *c = *d;
        *d = aux;
        swaps++;
      } while (0);
    } else
      do {
        aux = *d;
        *d = *e;
        *e = aux;
        swaps++;
      } while (0);
  }
  return (swaps);
}
```