ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<matmpy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x20(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %esi,%esi
  jle    L41
  lea    -0x1(%rdx),%eax
  mov    %esi,%ebp
  movslq %edx,%rsi
  mov    %rdi,%rbx
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rdi),%rax
  mov    %edx,%r11d
  mov    %r8d,%r14d
  mov    %rax,-0x8(%rsp)
  shl    $0x3,%rsi
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  movslq %r8d,%r12
  pxor   %xmm2,%xmm2
L1:
  test   %r14d,%r14d
  jle    L47
  mov    -0x8(%rsp),%rdi
  movslq %r15d,%rax
  mov    -0x20(%rsp),%r8
  lea    0x0(,%rax,8),%r9
  add    -0x10(%rsp),%rax
  lea    (%rbx,%r9,1),%r10
  lea    (%rdi,%rax,8),%rcx
  add    -0x18(%rsp),%r9
  xor    %edi,%edi
  xchg   %ax,%ax
L13:
  mov    %r8,%rdx
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L7
  nop
L55:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L55
L7:
  movsd  %xmm1,(%r9,%rdi,8)
  add    $0x1,%rdi
  add    $0x8,%r8
  cmp    %r12,%rdi
  jne    L13
L47:
  add    $0x1,%r13d
  add    %ebp,%r15d
  cmp    %r13d,%ebp
  jne    L1
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matmpy(a, n, m, b, l, c) double a[], b[], c[];
int n, m, l;
{
  int i, j, k;
  double s;
  for (i = 0; i < n; i++) {
    for (j = 0; j < l; j++) {
      s = 0.;
      for (k = 0; k < m; k++) {
        s += a[k + i * n] * b[j + k * m];
      }
      c[j + i * n] = s;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matmpy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x18(%rsp)
  test   %esi,%esi
  jle    L5
  movslq %r8d,%r11
  test   %r11d,%r11d
  jle    L5
  lea    0x8(%rdi),%rax
  mov    %esi,%ebp
  movslq %edx,%rsi
  mov    %rdi,%rbx
  mov    %rax,-0x8(%rsp)
  lea    -0x1(%rdx),%eax
  mov    %edx,%r12d
  mov    %r9,%r15
  mov    %rax,-0x10(%rsp)
  shl    $0x3,%rsi
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax)
L45:
  mov    -0x8(%rsp),%rdi
  movslq %r14d,%rax
  mov    -0x18(%rsp),%r8
  lea    0x0(,%rax,8),%r9
  add    -0x10(%rsp),%rax
  lea    (%rbx,%r9,1),%r10
  lea    (%rdi,%rax,8),%rcx
  add    %r15,%r9
  xor    %edi,%edi
  nop
L9:
  mov    %r8,%rdx
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  test   %r12d,%r12d
  jle    L18
  nop
L31:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L31
L18:
  movsd  %xmm1,(%r9,%rdi,8)
  add    $0x1,%rdi
  add    $0x8,%r8
  cmp    %rdi,%r11
  jne    L9
  add    $0x1,%r13d
  add    %ebp,%r14d
  cmp    %r13d,%ebp
  jne    L45
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matmpy(a, n, m, b, l, c) double a[], b[], c[];
int n, m, l;
{
  int i, j, k;
  double s;
  for (i = 0; i < n; i++) {
    for (j = 0; j < l; j++) {
      s = 0.;
      for (k = 0; k < m; k++) {
        s += a[k + i * n] * b[j + k * m];
      }
      c[j + i * n] = s;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L1
L36:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L44:
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L28
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x0,-0xc(%rbp)
  jns    L8
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: %s


assistant: ```c
char *reverse(char *str) {
  if (str == NULL)
    return NULL;
  int strLen = 0, i = 0;
  while (str[strLen] != '\0')
    strLen++;
  char *newStr = (char *)malloc(sizeof(char) * strLen);
  for (int j = strLen - 1; j >= 0; j--)
    newStr[i++] = str[j];
  newStr[i] = '\0';
  printf("%s\n", newStr);
  return newStr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reverse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L37
  cmpb   $0x0,(%rdi)
  je     L26
  lea    0x1(%rdi),%rax
  mov    $0x0,%edi
L68:
  mov    %edi,%ebx
  add    $0x1,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L68
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  js     L34
  movslq %ebx,%rcx
  lea    (%r12,%rcx,1),%rdx
  lea    -0x1(%r12,%rcx,1),%rdi
  mov    %ebx,%esi
  sub    %rsi,%rdi
  add    %rcx,%rax
  lea    (%r12,%rax,1),%rsi
L55:
  movzbl (%rdx),%ecx
  mov    %rsi,%rax
  sub    %rdx,%rax
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L55
  add    $0x1,%ebx
L22:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L78:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0x0,%ebx
  jmp    L22
L37:
  mov    %rdi,%rbp
  jmp    L78
L26:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L22
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: %s


assistant: ```c
char *reverse(char *str) {
  if (str == NULL)
    return NULL;
  int strLen = 0, i = 0;
  while (str[strLen] != '\0')
    strLen++;
  char *newStr = (char *)malloc(sizeof(char) * strLen);
  for (int j = strLen - 1; j >= 0; j--)
    newStr[i++] = str[j];
  newStr[i] = '\0';
  printf("%s\n", newStr);
  return newStr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L56
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L8
  lea    0x1(%rdi),%rax
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L47:
  add    $0x1,%rax
  movslq %ebx,%r12
  add    $0x1,%ebx
  cmpb   $0x0,-0x1(%rax)
  jne    L47
  mov    %ebx,%edi
  call   <malloc@plt>
  lea    -0x1(%rbp,%r12,1),%r8
  lea    0x0(%rbp,%r12,1),%rdx
  lea    (%r12,%rax,1),%rcx
  mov    %rax,%r13
  sub    %r12,%r8
  lea    0x0(%rbp,%rcx,1),%rdi
L49:
  movzbl (%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L49
  movslq %ebx,%rbx
  add    %rbx,%rax
L26:
  movb   $0x0,(%rax)
  mov    %r13,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L26
L56:
  xor    %r13d,%r13d
  jmp    L3
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: %s


assistant: ```c
char *reverse(char *str) {
  if (str == NULL)
    return NULL;
  int strLen = 0, i = 0;
  while (str[strLen] != '\0')
    strLen++;
  char *newStr = (char *)malloc(sizeof(char) * strLen);
  for (int j = strLen - 1; j >= 0; j--)
    newStr[i++] = str[j];
  newStr[i] = '\0';
  printf("%s\n", newStr);
  return newStr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L39
  lea    0x1(%rdi),%rax
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  movslq %ebx,%r12
  add    $0x1,%ebx
  cmpb   $0x0,-0x1(%rax)
  jne    L12
  mov    %ebx,%edi
  call   <malloc@plt>
  lea    -0x1(%rbp,%r12,1),%r8
  lea    0x0(%rbp,%r12,1),%rdx
  lea    (%rax,%r12,1),%rcx
  mov    %rax,%r13
  sub    %r12,%r8
  lea    0x0(%rbp,%rcx,1),%rdi
L28:
  movzbl (%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L28
  movslq %ebx,%rbx
  add    %rbx,%rax
L4:
  movb   $0x0,(%rax)
  mov    %r13,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L14:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  jmp    L4
L17:
  xor    %r13d,%r13d
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: %s


assistant: ```c
char *reverse(char *str) {
  if (str == NULL)
    return NULL;
  int strLen = 0, i = 0;
  while (str[strLen] != '\0')
    strLen++;
  char *newStr = (char *)malloc(sizeof(char) * strLen);
  for (int j = strLen - 1; j >= 0; j--)
    newStr[i++] = str[j];
  newStr[i] = '\0';
  printf("%s\n", newStr);
  return newStr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<array_squeeze1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L13:
  mov    -0x4(%rbp),%eax
  cltq
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  cltq
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memmove@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void array_squeeze1(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  int i;
  assert(oldwidth > newwidth);
  for (i = 1; i < nelems; i++)
    memmove(base + i * newwidth, base + i * oldwidth, newwidth);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<array_squeeze1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %rcx,%r12
  cmp    %rcx,%rdx
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x1,%r14d
  jle    L2
  lea    (%rbx,%r12,1),%rbp
  add    %r13,%rbx
  mov    $0x1,%r15d
L14:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  add    $0x1,%r15d
  add    %r12,%rbp
  add    %r13,%rbx
  cmp    %r15d,%r14d
  jne    L14
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void array_squeeze1(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  int i;
  assert(oldwidth > newwidth);
  for (i = 1; i < nelems; i++)
    memmove(base + i * newwidth, base + i * oldwidth, newwidth);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<array_squeeze1>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    %rcx,%rdx
  seta   %dil
  call   <assert@plt>
  cmp    $0x1,%r14d
  jle    L13
  lea    (%rbx,%r15,1),%r12
  mov    $0x1,%ebp
  add    %r13,%rbx
  xchg   %ax,%ax
L15:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %r15,%rdx
  add    $0x1,%ebp
  call   <memmove@plt>
  add    %r15,%r12
  add    %r13,%rbx
  cmp    %ebp,%r14d
  jne    L15
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void array_squeeze1(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  int i;
  assert(oldwidth > newwidth);
  for (i = 1; i < nelems; i++)
    memmove(base + i * newwidth, base + i * oldwidth, newwidth);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<array_squeeze1>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    %rcx,%rdx
  seta   %dil
  call   <assert@plt>
  cmp    $0x1,%r14d
  jle    L13
  lea    (%rbx,%r15,1),%r12
  mov    $0x1,%ebp
  add    %r13,%rbx
  xchg   %ax,%ax
L12:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    %r15,%rdx
  add    $0x1,%ebp
  call   <memmove@plt>
  add    %r15,%r12
  add    %r13,%rbx
  cmp    %ebp,%r14d
  jne    L12
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void array_squeeze1(unsigned char *base, int nelems, size_t oldwidth, size_t newwidth) {
  int i;
  assert(oldwidth > newwidth);
  for (i = 1; i < nelems; i++)
    memmove(base + i * newwidth, base + i * oldwidth, newwidth);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thread_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: hello world

assistant: ```c
void *thread_function(void) {
  char *hello = malloc(sizeof(char) * 10);
  strcpy(hello, "hello world");
  pthread_exit((void *)hello);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<thread_function>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <pthread_exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: hello world

assistant: ```c
void *thread_function(void) {
  char *hello = malloc(sizeof(char) * 10);
  strcpy(hello, "hello world");
  pthread_exit((void *)hello);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<thread_function>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <pthread_exit@plt>
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: hello world

assistant: ```c
void *thread_function(void) {
  char *hello = malloc(sizeof(char) * 10);
  strcpy(hello, "hello world");
  pthread_exit((void *)hello);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<thread_function>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <pthread_exit@plt>
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: hello world

assistant: ```c
void *thread_function(void) {
  char *hello = malloc(sizeof(char) * 10);
  strcpy(hello, "hello world");
  pthread_exit((void *)hello);
}
```
user: What is the c source code of the assembly code below?

```asm
<futex_wake>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0xca,%eax
  mov    -0x18(%rbp),%rdi
  mov    $0x1,%esi
  mov    -0x1c(%rbp),%edx
  syscall
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void futex_wake(int *addr, int count) {
  long res;
  __asm volatile("syscall" : "=a"(res) : "0"(202), "D"(addr), "S"(1), "d"(count) : "r11", "rcx", "memory");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<futex_wake>:
  endbr64
  mov    %esi,%edx
  mov    $0xca,%eax
  mov    $0x1,%esi
  syscall
  ret
```

assistant: ```c
void futex_wake(int *addr, int count) {
  long res;
  __asm volatile("syscall" : "=a"(res) : "0"(202), "D"(addr), "S"(1), "d"(count) : "r11", "rcx", "memory");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<futex_wake>:
  endbr64
  mov    %esi,%edx
  mov    $0xca,%eax
  mov    $0x1,%esi
  syscall
  ret
```

assistant: ```c
void futex_wake(int *addr, int count) {
  long res;
  __asm volatile("syscall" : "=a"(res) : "0"(202), "D"(addr), "S"(1), "d"(count) : "r11", "rcx", "memory");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<futex_wake>:
  endbr64
  mov    %esi,%edx
  mov    $0xca,%eax
  mov    $0x1,%esi
  syscall
  ret
```

assistant: ```c
void futex_wake(int *addr, int count) {
  long res;
  __asm volatile("syscall" : "=a"(res) : "0"(202), "D"(addr), "S"(1), "d"(count) : "r11", "rcx", "memory");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rs232_send_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    $0xffffffff,%eax
  jmp    L1
L14:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int rs232_send_byte(int fd, unsigned char byte) {
  int n;
  n = write(fd, &byte, 1);
  if (n < 0)
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rs232_send_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  sar    $0x1f,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int rs232_send_byte(int fd, unsigned char byte) {
  int n;
  n = write(fd, &byte, 1);
  if (n < 0)
    return (-1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rs232_send_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  add    $0x18,%rsp
  sar    $0x1f,%eax
  ret
```

assistant: ```c
int rs232_send_byte(int fd, unsigned char byte) {
  int n;
  n = write(fd, &byte, 1);
  if (n < 0)
    return (-1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rs232_send_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  add    $0x18,%rsp
  sar    $0x1f,%eax
  ret
```

assistant: ```c
int rs232_send_byte(int fd, unsigned char byte) {
  int n;
  n = write(fd, &byte, 1);
  if (n < 0)
    return (-1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ws_unmask_payload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %esi,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ws_unmask_payload(char *buf, int len, int offset, unsigned char mask[]) {
  int i, j = 0;
  for (i = offset; i < len; ++i, ++j) {
    buf[i] ^= mask[j % 4];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ws_unmask_payload>:
  endbr64
  cmp    %esi,%edx
  jge    L2
  movslq %edx,%rax
  add    %rax,%rdi
  sub    %edx,%esi
  mov    $0x0,%edx
L3:
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  shr    $0x1e,%r8d
  lea    (%rdx,%r8,1),%eax
  and    $0x3,%eax
  sub    %r8d,%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  xor    %al,(%rdi)
  add    $0x1,%edx
  add    $0x1,%rdi
  cmp    %esi,%edx
  jne    L3
L2:
  ret
```

assistant: ```c
void ws_unmask_payload(char *buf, int len, int offset, unsigned char mask[]) {
  int i, j = 0;
  for (i = offset; i < len; ++i, ++j) {
    buf[i] ^= mask[j % 4];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ws_unmask_payload>:
  endbr64
  cmp    %esi,%edx
  jge    L5
  movslq %edx,%rax
  sub    %edx,%esi
  add    %rax,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %eax,%edx
  add    $0x1,%eax
  and    $0x3,%edx
  movzbl (%rcx,%rdx,1),%edx
  xor    %dl,(%rdi)
  add    $0x1,%rdi
  cmp    %esi,%eax
  jne    L17
L5:
  ret
```

assistant: ```c
void ws_unmask_payload(char *buf, int len, int offset, unsigned char mask[]) {
  int i, j = 0;
  for (i = offset; i < len; ++i, ++j) {
    buf[i] ^= mask[j % 4];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ws_unmask_payload>:
  endbr64
  cmp    %esi,%edx
  jge    L0
  movslq %edx,%rax
  sub    %edx,%esi
  add    %rax,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %eax,%edx
  add    $0x1,%eax
  and    $0x3,%edx
  movzbl (%rcx,%rdx,1),%edx
  xor    %dl,(%rdi)
  add    $0x1,%rdi
  cmp    %esi,%eax
  jne    L2
L0:
  ret
```

assistant: ```c
void ws_unmask_payload(char *buf, int len, int offset, unsigned char mask[]) {
  int i, j = 0;
  for (i = offset; i < len; ++i, ++j) {
    buf[i] ^= mask[j % 4];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<left_shift_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L16
L9:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L16:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void left_shift_string(char *str, int N) {
  int i;
  while (N--) {
    for (i = 0; str[i] != '\0'; i++)
      str[i] = str[i + 1];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_shift_string>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  jne    L0
  ret
L1:
  movzbl 0x1(%rax),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L1
L6:
  sub    $0x1,%ecx
  cmp    $0xffffffff,%ecx
  je     L27
L0:
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  jne    L1
  jmp    L6
L27:
  ret
```

assistant: ```c
void left_shift_string(char *str, int N) {
  int i;
  while (N--) {
    for (i = 0; str[i] != '\0'; i++)
      str[i] = str[i + 1];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<left_shift_string>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L21
  nopl   0x0(%rax,%rax,1)
L1:
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L25
  nopl   0x0(%rax,%rax,1)
L23:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L23
L25:
  sub    $0x1,%ecx
  jae    L1
  ret
L21:
  ret
```

assistant: ```c
void left_shift_string(char *str, int N) {
  int i;
  while (N--) {
    for (i = 0; str[i] != '\0'; i++)
      str[i] = str[i + 1];
  }
}
```