ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<safe_iconv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  shl    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L62
L23:
  lea    -0x18(%rbp),%rdi
  lea    -0x10(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <iconv@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L89
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L89
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  or     $0x1,%eax
  mov    %eax,%edx
  mov    -0x58(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L70
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x5f,(%rax)
L70:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L62:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L23
L89:
  mov    -0x10(%rbp),%rax
  sub    -0x48(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L15
L13:
  mov    -0x28(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L43
  mov    -0x28(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  or     $0x1,%eax
  mov    %eax,%edx
  mov    -0x58(%rbp),%rax
  mov    %edx,(%rax)
L43:
  addl   $0x1,-0x28(%rbp)
L15:
  mov    -0x28(%rbp),%eax
  cmp    %rax,-0x50(%rbp)
  ja     L13
  mov    -0x50(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

assistant: ```c
int safe_iconv(iconv_t conv, const wchar_t *wchar, char *dest, size_t len, int *mangled) {
  size_t in_len = len * sizeof(wchar_t);
  size_t out_len = len * 4;
  char *dptr = dest;
  while (in_len > 0) {
    int r = iconv(conv, (char **)&wchar, &in_len, &dptr, &out_len);
    if (r >= 0 || errno != EILSEQ)
      break;
    *mangled |= 1;
    if (dptr)
      *dptr++ = '_';
    in_len--;
    wchar++;
    out_len--;
  }
  len = dptr - dest;
  unsigned int i;
  for (i = 0; i < len; i++) {
    if (dest[i] == '?') {
      dest[i] = '_';
      *mangled |= 1;
    }
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<safe_iconv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  shl    $0x2,%rcx
  mov    %rcx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %rdx,0x20(%rsp)
  je     L41
  mov    %edi,%r12d
  mov    %rdx,%rbp
  mov    %r8,%rbx
  lea    0x18(%rsp),%r13
  jmp    L133
L102:
  mov    0x10(%rsp),%rax
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  addq   $0x4,0x8(%rsp)
  subq   $0x1,0x18(%rsp)
  test   %rax,%rax
  je     L15
L133:
  lea    0x20(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r13,%r8
  mov    %r12d,%edi
  call   <iconv@plt>
  test   %eax,%eax
  jns    L15
  mov    D9(%rip),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L15
  orl    $0x1,(%rbx)
  mov    0x20(%rsp),%rax
  test   %rax,%rax
  je     L102
  lea    0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  movb   $0x5f,(%rax)
  jmp    L102
L15:
  mov    0x20(%rsp),%rax
  sub    %rbp,%rax
  mov    %rax,%rsi
  je     L22
  mov    $0x0,%ecx
  mov    $0x0,%edx
  jmp    L136
L5:
  add    $0x1,%ecx
  mov    %ecx,%edx
  cmp    %rsi,%rdx
  jae    L33
L136:
  add    %rbp,%rdx
  cmpb   $0x3f,(%rdx)
  jne    L5
  movb   $0x5f,(%rdx)
  orl    $0x1,(%rbx)
  jmp    L5
L41:
  mov    $0x0,%eax
  jmp    L33
L22:
  mov    $0x0,%eax
L33:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int safe_iconv(iconv_t conv, const wchar_t *wchar, char *dest, size_t len, int *mangled) {
  size_t in_len = len * sizeof(wchar_t);
  size_t out_len = len * 4;
  char *dptr = dest;
  while (in_len > 0) {
    int r = iconv(conv, (char **)&wchar, &in_len, &dptr, &out_len);
    if (r >= 0 || errno != EILSEQ)
      break;
    *mangled |= 1;
    if (dptr)
      *dptr++ = '_';
    in_len--;
    wchar++;
    out_len--;
  }
  len = dptr - dest;
  unsigned int i;
  for (i = 0; i < len; i++) {
    if (dest[i] == '?') {
      dest[i] = '_';
      *mangled |= 1;
    }
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<safe_iconv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  shl    $0x2,%rcx
  mov    %rdx,0x20(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  je     L38
  mov    %edi,%r12d
  lea    0x18(%rsp),%rbp
  lea    0x20(%rsp),%r15
  mov    %r8,%rbx
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  jmp    L83
L89:
  mov    D16(%rip),%rdx
  mov    D2(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L53
  orl    $0x1,(%rbx)
  test   %rax,%rax
  je     L111
  lea    0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  movb   $0x5f,(%rax)
L111:
  mov    0x10(%rsp),%rax
  addq   $0x4,0x8(%rsp)
  subq   $0x1,0x18(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L43
L83:
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <iconv@plt>
  test   %eax,%eax
  mov    0x20(%rsp),%rax
  js     L89
L53:
  sub    (%rsp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    %eax,%r8d
  mov    $0x0,%eax
  je     L26
  nopl   0x0(%rax)
L22:
  add    (%rsp),%rax
  cmpb   $0x3f,(%rax)
  jne    L19
  movb   $0x5f,(%rax)
  orl    $0x1,(%rbx)
L19:
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  cmp    %rdx,%rax
  jb     L22
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x38,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L43:
  mov    0x20(%rsp),%rax
  jmp    L53
L38:
  xor    %r8d,%r8d
  jmp    L26
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int safe_iconv(iconv_t conv, const wchar_t *wchar, char *dest, size_t len, int *mangled) {
  size_t in_len = len * sizeof(wchar_t);
  size_t out_len = len * 4;
  char *dptr = dest;
  while (in_len > 0) {
    int r = iconv(conv, (char **)&wchar, &in_len, &dptr, &out_len);
    if (r >= 0 || errno != EILSEQ)
      break;
    *mangled |= 1;
    if (dptr)
      *dptr++ = '_';
    in_len--;
    wchar++;
    out_len--;
  }
  len = dptr - dest;
  unsigned int i;
  for (i = 0; i < len; i++) {
    if (dest[i] == '?') {
      dest[i] = '_';
      *mangled |= 1;
    }
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<safe_iconv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  shl    $0x2,%rcx
  mov    %rdx,0x20(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  je     L49
  mov    %edi,%r12d
  lea    0x18(%rsp),%rbp
  lea    0x20(%rsp),%r15
  mov    %r8,%rbx
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  xchg   %ax,%ax
L35:
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <iconv@plt>
  test   %eax,%eax
  mov    0x20(%rsp),%rax
  jns    L14
  mov    D14(%rip),%rdx
  mov    D3(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L14
  orl    $0x1,(%rbx)
  test   %rax,%rax
  je     L43
  lea    0x1(%rax),%rdx
  mov    %rdx,0x20(%rsp)
  movb   $0x5f,(%rax)
  mov    0x10(%rsp),%rax
  addq   $0x4,0x8(%rsp)
  sub    $0x1,%rax
  subq   $0x1,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  jne    L35
  mov    0x20(%rsp),%rax
L14:
  sub    (%rsp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    %eax,%r8d
  mov    $0x0,%eax
  je     L96
  nopl   (%rax)
L117:
  add    (%rsp),%rax
  cmpb   $0x3f,(%rax)
  jne    L64
  movb   $0x5f,(%rax)
  orl    $0x1,(%rbx)
L64:
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  cmp    %rdx,%rax
  jb     L117
L96:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x38,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L43:
  mov    0x10(%rsp),%rdi
  addq   $0x4,0x8(%rsp)
  subq   $0x1,0x18(%rsp)
  lea    -0x1(%rdi),%rdx
  mov    %rdx,0x10(%rsp)
  test   %rdx,%rdx
  jne    L35
  jmp    L14
L49:
  xor    %r8d,%r8d
  jmp    L96
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int safe_iconv(iconv_t conv, const wchar_t *wchar, char *dest, size_t len, int *mangled) {
  size_t in_len = len * sizeof(wchar_t);
  size_t out_len = len * 4;
  char *dptr = dest;
  while (in_len > 0) {
    int r = iconv(conv, (char **)&wchar, &in_len, &dptr, &out_len);
    if (r >= 0 || errno != EILSEQ)
      break;
    *mangled |= 1;
    if (dptr)
      *dptr++ = '_';
    in_len--;
    wchar++;
    out_len--;
  }
  len = dptr - dest;
  unsigned int i;
  for (i = 0; i < len; i++) {
    if (dest[i] == '?') {
      dest[i] = '_';
      *mangled |= 1;
    }
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<handle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <isused@plt>
  test   %eax,%eax
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0xff,(%rax)
L4:
  nop
  leave
  ret
```

assistant: ```c
void handle(c) char *c;
{
  if (isused(*c))
    *c = 0377;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<handle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  mov    $0x0,%eax
  call   <isused@plt>
  test   %eax,%eax
  je     L2
  movb   $0xff,(%rbx)
L2:
  pop    %rbx
  ret
```

assistant: ```c
void handle(c) char *c;
{
  if (isused(*c))
    *c = 0377;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<handle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  call   <isused@plt>
  test   %eax,%eax
  je     L5
  movb   $0xff,(%rbx)
L5:
  pop    %rbx
  ret
```

assistant: ```c
void handle(c) char *c;
{
  if (isused(*c))
    *c = 0377;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<handle>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  call   <isused@plt>
  test   %eax,%eax
  je     L0
  movb   $0xff,(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void handle(c) char *c;
{
  if (isused(*c))
    *c = 0377;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xfffffffe,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = ~1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = ~1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = ~1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = ~1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<roundToTenths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  D11(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movss  D8(%rip),%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <floor@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: f32
name: extract_symbolic_data
arguments: label: D8
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D19
type_infered: string

tool: D11: 10

tool: {"D8": [0x00,0x00,0x00,0x3f]}

tool: D19: original = %f  Rounded to Tenth = %.1f


assistant: ```c
void roundToTenths(float number) {
  float rounded = floor(number * 10 + .5) / 10;
  printf("original = %f  Rounded to Tenth = %.1f\n", number, rounded);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<roundToTenths>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  movaps %xmm0,%xmm2
  mulss  D5(%rip),%xmm2
  movaps %xmm2,%xmm0
  addss  D0(%rip),%xmm0
  call   <floor@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: f32
name: unpack_data
arguments: tag: D0
type_infered: byte[4]
name: unpack_data
arguments: tag: D14
type_infered: string

tool: D5: 10

tool: {"D0": [0x00,0x00,0x00,0x3f]}

tool: D14: original = %f  Rounded to Tenth = %.1f


assistant: ```c
void roundToTenths(float number) {
  float rounded = floor(number * 10 + .5) / 10;
  printf("original = %f  Rounded to Tenth = %.1f\n", number, rounded);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<roundToTenths>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mulss  D4(%rip),%xmm0
  addss  D23(%rip),%xmm0
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  lea    D9(%rip),%rdi
  imul   $0x66666667,%rdx,%rdx
  movaps %xmm2,%xmm0
  sar    $0x22,%rdx
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm1
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: f32
name: extract_symbolic_data
arguments: data_label: D23
data_type: byte[4]
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D4: 10

tool: {"D23": [0x00,0x00,0x00,0x3f]}

tool: D9: original = %f  Rounded to Tenth = %.1f


assistant: ```c
void roundToTenths(float number) {
  float rounded = floor(number * 10 + .5) / 10;
  printf("original = %f  Rounded to Tenth = %.1f\n", number, rounded);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<roundToTenths>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  mulss  D24(%rip),%xmm0
  addss  D19(%rip),%xmm0
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  lea    D9(%rip),%rdi
  imul   $0x66666667,%rdx,%rdx
  movaps %xmm2,%xmm0
  sar    $0x22,%rdx
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm1
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
type_guessed: f32
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D24: 10

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: D9: original = %f  Rounded to Tenth = %.1f


assistant: ```c
void roundToTenths(float number) {
  float rounded = floor(number * 10 + .5) / 10;
  printf("original = %f  Rounded to Tenth = %.1f\n", number, rounded);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_time_t@plt>
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
time_t time(time_t *tloc) {
  time_t t;
  t = __infer_nondet_time_t();
  if (tloc)
    *tloc = t;
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <__infer_nondet_time_t@plt>
  test   %rbx,%rbx
  je     L8
  mov    %eax,(%rbx)
L8:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *tloc) {
  time_t t;
  t = __infer_nondet_time_t();
  if (tloc)
    *tloc = t;
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<time>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__infer_nondet_time_t@plt>
  test   %rbx,%rbx
  je     L6
  mov    %eax,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *tloc) {
  time_t t;
  t = __infer_nondet_time_t();
  if (tloc)
    *tloc = t;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<time>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__infer_nondet_time_t@plt>
  test   %rbx,%rbx
  je     L0
  mov    %eax,(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *tloc) {
  time_t t;
  t = __infer_nondet_time_t();
  if (tloc)
    *tloc = t;
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  jmp    L4
L7:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  neg    %rax
  and    %rdx,%rax
L4:
  pop    %rbp
  ret
```

assistant: ```c
size_t align(size_t sz, size_t a) {
  if (a == 0)
    return sz;
  return (sz + a - 1) & ~(a - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<align>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L4
  lea    -0x1(%rdi,%rsi,1),%rax
  neg    %rsi
  and    %rsi,%rax
L4:
  ret
```

assistant: ```c
size_t align(size_t sz, size_t a) {
  if (a == 0)
    return sz;
  return (sz + a - 1) & ~(a - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<align>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L3
  lea    -0x1(%rdi,%rsi,1),%rax
  neg    %rsi
  and    %rsi,%rax
L3:
  ret
```

assistant: ```c
size_t align(size_t sz, size_t a) {
  if (a == 0)
    return sz;
  return (sz + a - 1) & ~(a - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<align>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L0
  lea    -0x1(%rdi,%rsi,1),%rax
  neg    %rsi
  and    %rsi,%rax
L0:
  ret
```

assistant: ```c
size_t align(size_t sz, size_t a) {
  if (a == 0)
    return sz;
  return (sz + a - 1) & ~(a - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ConvertSMVer2Cores>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x10,-0x40(%rbp)
  movl   $0x8,-0x3c(%rbp)
  movl   $0x11,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  movl   $0x12,-0x30(%rbp)
  movl   $0x8,-0x2c(%rbp)
  movl   $0x13,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0x20,-0x20(%rbp)
  movl   $0x20,-0x1c(%rbp)
  movl   $0x21,-0x18(%rbp)
  movl   $0x30,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L42
L16:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%eax
  mov    -0x54(%rbp),%edx
  mov    %edx,%ecx
  shl    $0x4,%ecx
  mov    -0x58(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jne    L9
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x3c(%rbp,%rax,8),%eax
  jmp    L43
L9:
  addl   $0x1,-0x44(%rbp)
L42:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%eax
  cmp    $0xffffffff,%eax
  jne    L16
  mov    -0x58(%rbp),%edx
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: MapSMtoCores undefined SMversion %d.%d!


assistant: ```c
int _ConvertSMVer2Cores(int major, int minor) {
  typedef struct {
    int SM;
    int Cores;
  } sSMtoCores;
  sSMtoCores nGpuArchCoresPerSM[] = {{0x10, 8}, {0x11, 8}, {0x12, 8}, {0x13, 8}, {0x20, 32}, {0x21, 48}, {-1, -1}};
  int index = 0;
  while (nGpuArchCoresPerSM[index].SM != -1) {
    if (nGpuArchCoresPerSM[index].SM == ((major << 4) + minor)) {
      return nGpuArchCoresPerSM[index].Cores;
    }
    index++;
  }
  printf("MapSMtoCores undefined SMversion %d.%d!\n", major, minor);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ConvertSMVer2Cores>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x10,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x11,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x12,0x10(%rsp)
  movl   $0x8,0x14(%rsp)
  movl   $0x13,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x20,0x20(%rsp)
  movl   $0x20,0x24(%rsp)
  movl   $0x21,0x28(%rsp)
  movl   $0x30,0x2c(%rsp)
  movl   $0xffffffff,0x30(%rsp)
  movl   $0xffffffff,0x34(%rsp)
  mov    %edi,%ecx
  shl    $0x4,%ecx
  add    %esi,%ecx
  mov    $0x10,%ebx
L6:
  cmp    %ebx,%ecx
  je     L24
  add    $0x1,%rax
  mov    (%rsp,%rax,8),%ebx
  cmp    $0xffffffff,%ebx
  jne    L6
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L24:
  movslq %eax,%r8
  mov    0x4(%rsp,%r8,8),%ebx
  jmp    L27
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: MapSMtoCores undefined SMversion %d.%d!


assistant: ```c
int _ConvertSMVer2Cores(int major, int minor) {
  typedef struct {
    int SM;
    int Cores;
  } sSMtoCores;
  sSMtoCores nGpuArchCoresPerSM[] = {{0x10, 8}, {0x11, 8}, {0x12, 8}, {0x13, 8}, {0x20, 32}, {0x21, 48}, {-1, -1}};
  int index = 0;
  while (nGpuArchCoresPerSM[index].SM != -1) {
    if (nGpuArchCoresPerSM[index].SM == ((major << 4) + minor)) {
      return nGpuArchCoresPerSM[index].Cores;
    }
    index++;
  }
  printf("MapSMtoCores undefined SMversion %d.%d!\n", major, minor);
  return -1;
}
```