ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<palette_feu>:
  endbr64
  push   %rbx
  sub    $0x310,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x308(%rsp)
  xor    %eax,%eax
  call   <cng_clear_screen@plt>
  mov    %rsp,%rsi
  lea    0x300(%rsp),%rcx
  mov    %rsi,%rax
L13:
  movb   $0x0,(%rax)
  movb   $0x0,0x1(%rax)
  movb   $0x0,0x2(%rax)
  add    $0x3,%rax
  cmp    %rcx,%rax
  jne    L13
  lea    0xc0(%rsi),%rdi
  mov    %rsi,%rax
  mov    $0xffffffff,%edx
L51:
  movb   $0xff,(%rax)
  movb   $0xff,0x1(%rax)
  mov    %dl,0x2(%rax)
  add    $0x3,%rax
  sub    $0x4,%edx
  cmp    %rdi,%rax
  jne    L51
  lea    0xc0(%rsp),%rax
  lea    0x180(%rsi),%rdi
  mov    $0xffffffff,%edx
L67:
  movb   $0xff,(%rax)
  mov    %dl,0x1(%rax)
  movb   $0x0,0x2(%rax)
  add    $0x3,%rax
  sub    $0x2,%edx
  cmp    %rdi,%rax
  jne    L67
  lea    0x180(%rsp),%rax
  add    $0x240,%rsi
  mov    $0xffffff80,%edx
L14:
  movb   $0xff,(%rax)
  mov    %dl,0x1(%rax)
  movb   $0x0,0x2(%rax)
  add    $0x3,%rax
  sub    $0x2,%edx
  cmp    %rsi,%rax
  jne    L14
  lea    0x240(%rsp),%rax
  mov    $0xffffffff,%edx
L21:
  mov    %dl,(%rax)
  movb   $0x0,0x1(%rax)
  movb   $0x0,0x2(%rax)
  sub    $0x4,%edx
  add    $0x3,%rax
  cmp    %rcx,%rax
  jne    L21
  mov    %rsp,%rdi
  call   <cng_palette@plt>
  mov    $0x0,%edi
  call   <cng_current_color_index@plt>
  mov    $0x0,%eax
  call   <cng_clear_screen@plt>
  mov    $0x0,%ebx
L61:
  mov    %ebx,%edi
  call   <cng_current_color_index@plt>
  mov    %ebx,%ecx
  mov    $0x280,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <cng_line@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L61
  mov    $0x7d0,%edi
  call   <cng_delay@plt>
  mov    $0x0,%eax
  call   <menu@plt>
  mov    0x308(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x310,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int palette_feu() {
  unsigned char feu[256][3];
  int i, r, v, b;
  cng_clear_screen();
  for (i = 0; i < 256; i++) {
    feu[i][0] = 0;
    feu[i][1] = 0;
    feu[i][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i][0] = 255;
    feu[i][1] = 255;
    feu[i][2] = 255 - (i * 4);
  }
  for (i = 0; i < 64; i++) {
    feu[i + 64][0] = 255;
    feu[i + 64][1] = 255 - (i * 2);
    feu[i + 64][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i + 128][0] = 255;
    feu[i + 128][1] = 128 - (i * 2);
    feu[i + 128][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i + 192][0] = 255 - (i * 4);
    feu[i + 192][1] = 0;
    feu[i + 192][2] = 0;
  }
  cng_palette(feu);
  cng_current_color_index(0);
  cng_clear_screen();
  for (i = 0; i < 256; i++) {
    cng_current_color_index(i);
    cng_line(0, i, 640, i);
  }
  cng_delay(2000);
  menu();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<palette_feu>:
  endbr64
  push   %rbx
  sub    $0x310,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x308(%rsp)
  xor    %eax,%eax
  call   <cng_clear_screen@plt>
  mov    %rsp,%rdi
  lea    0x300(%rsp),%rcx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L49:
  movb   $0x0,(%rax)
  add    $0x3,%rax
  movb   $0x0,-0x2(%rax)
  movb   $0x0,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L49
  lea    0xc0(%rdi),%rsi
  mov    %rdi,%rax
  mov    $0xffffffff,%edx
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %dl,0x2(%rax)
  add    $0x3,%rax
  sub    $0x4,%edx
  movb   $0xff,-0x3(%rax)
  movb   $0xff,-0x2(%rax)
  cmp    %rsi,%rax
  jne    L55
  lea    0xc0(%rsp),%rax
  lea    0x180(%rdi),%rsi
  mov    $0xffffffff,%edx
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %dl,0x1(%rax)
  add    $0x3,%rax
  sub    $0x2,%edx
  movb   $0xff,-0x3(%rax)
  movb   $0x0,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L26
  lea    0x180(%rsp),%rax
  lea    0x240(%rdi),%rsi
  mov    $0xffffff80,%edx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %dl,0x1(%rax)
  add    $0x3,%rax
  sub    $0x2,%edx
  movb   $0xff,-0x3(%rax)
  movb   $0x0,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L29
  lea    0x240(%rsp),%rax
  mov    $0xffffffff,%edx
  nopl   0x0(%rax)
L16:
  mov    %dl,(%rax)
  add    $0x3,%rax
  sub    $0x4,%edx
  movb   $0x0,-0x2(%rax)
  movb   $0x0,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L16
  call   <cng_palette@plt>
  xor    %edi,%edi
  xor    %ebx,%ebx
  call   <cng_current_color_index@plt>
  xor    %eax,%eax
  call   <cng_clear_screen@plt>
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %ebx,%edi
  call   <cng_current_color_index@plt>
  mov    %ebx,%ecx
  mov    %ebx,%esi
  mov    $0x280,%edx
  xor    %edi,%edi
  add    $0x1,%ebx
  call   <cng_line@plt>
  cmp    $0x100,%ebx
  jne    L31
  mov    $0x7d0,%edi
  call   <cng_delay@plt>
  xor    %eax,%eax
  call   <menu@plt>
  mov    0x308(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x310,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int palette_feu() {
  unsigned char feu[256][3];
  int i, r, v, b;
  cng_clear_screen();
  for (i = 0; i < 256; i++) {
    feu[i][0] = 0;
    feu[i][1] = 0;
    feu[i][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i][0] = 255;
    feu[i][1] = 255;
    feu[i][2] = 255 - (i * 4);
  }
  for (i = 0; i < 64; i++) {
    feu[i + 64][0] = 255;
    feu[i + 64][1] = 255 - (i * 2);
    feu[i + 64][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i + 128][0] = 255;
    feu[i + 128][1] = 128 - (i * 2);
    feu[i + 128][2] = 0;
  }
  for (i = 0; i < 64; i++) {
    feu[i + 192][0] = 255 - (i * 4);
    feu[i + 192][1] = 0;
    feu[i + 192][2] = 0;
  }
  cng_palette(feu);
  cng_current_color_index(0);
  cng_clear_screen();
  for (i = 0; i < 256; i++) {
    cng_current_color_index(i);
    cng_line(0, i, 640, i);
  }
  cng_delay(2000);
  menu();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quicktime_current_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x10(%rbp),%rax
  add    $0x7c25b080,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
unsigned long quicktime_current_time(void) {
  time_t t;
  time(&t);
  return (t + (66 * 31536000) + 1468800);
}
```
user: What is the c source code of the assembly code below?

```asm
<quicktime_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  mov    (%rsp),%rax
  add    $0x7c25b080,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long quicktime_current_time(void) {
  time_t t;
  time(&t);
  return (t + (66 * 31536000) + 1468800);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quicktime_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  mov    (%rsp),%rax
  add    $0x7c25b080,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long quicktime_current_time(void) {
  time_t t;
  time(&t);
  return (t + (66 * 31536000) + 1468800);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quicktime_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  mov    (%rsp),%rax
  add    $0x7c25b080,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long quicktime_current_time(void) {
  time_t t;
  time(&t);
  return (t + (66 * 31536000) + 1468800);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncatSafe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  cmp    %eax,-0x24(%rbp)
  jg     L0
  mov    $0x0,%eax
  jmp    L14
L0:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    $0x1,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char strncatSafe(char *dest, char *src, int destSize) {
  if (strlen(dest) + strlen(src) + 1 > destSize) {
    return 0;
  }
  strcat(dest, src);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncatSafe>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    $0x0,%eax
  cmp    %r13d,%ebx
  jl     L1
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    $0x1,%eax
  jmp    L5
```

assistant: ```c
char strncatSafe(char *dest, char *src, int destSize) {
  if (strlen(dest) + strlen(src) + 1 > destSize) {
    return 0;
  }
  strcat(dest, src);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncatSafe>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  xor    %eax,%eax
  cmp    %r13d,%ebx
  jge    L2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    $0x1,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char strncatSafe(char *dest, char *src, int destSize) {
  if (strlen(dest) + strlen(src) + 1 > destSize) {
    return 0;
  }
  strcat(dest, src);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncatSafe>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  xor    %eax,%eax
  cmp    %r13d,%ebx
  jge    L0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    $0x1,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char strncatSafe(char *dest, char *src, int destSize) {
  if (strlen(dest) + strlen(src) + 1 > destSize) {
    return 0;
  }
  strcat(dest, src);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fileTypeTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L40
  mov    $0x1,%eax
  jmp    L3
L40:
  mov    -0xc(%rbp),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L3
L44:
  mov    $0x1,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int fileTypeTest(const char *path, int type) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 1;
  };
  if ((st.st_mode & S_IFMT) == type) {
    return 0;
  };
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fileTypeTest>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L12
  mov    D0(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileTypeTest(const char *path, int type) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 1;
  };
  if ((st.st_mode & S_IFMT) == type) {
    return 0;
  };
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fileTypeTest>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L17
  mov    D0(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileTypeTest(const char *path, int type) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 1;
  };
  if ((st.st_mode & S_IFMT) == type) {
    return 0;
  };
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fileTypeTest>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L8
  mov    D7(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fileTypeTest(const char *path, int type) {
  struct stat st;
  if (stat(path, &st) != 0) {
    return 1;
  };
  if ((st.st_mode & S_IFMT) == type) {
    return 0;
  };
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ejecutartarea_1_svc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  add    %eax,%eax
  add    $0x3,%eax
  mov    %eax,D22(%rip)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
datatype: string

tool: D17: Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida


assistant: ```c
u_long *ejecutartarea_1_svc(u_long *argp, struct svc_req *rqstp) {
  static u_long result;
  result = *argp / 8 * 2 + 9 - 6;
  printf("Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida\n");
  return &result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ejecutartarea_1_svc>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edx
  lea    0x7(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x3,%eax
  lea    0x3(%rax,%rax,1),%eax
  mov    %eax,D8(%rip)
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string

tool: D16: Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida


assistant: ```c
u_long *ejecutartarea_1_svc(u_long *argp, struct svc_req *rqstp) {
  static u_long result;
  result = *argp / 8 * 2 + 9 - 6;
  printf("Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida\n");
  return &result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ejecutartarea_1_svc>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edx
  lea    D3(%rip),%rdi
  test   %edx,%edx
  lea    0x7(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x3,%eax
  lea    0x3(%rax,%rax,1),%eax
  mov    %eax,D17(%rip)
  call   <printf@plt>
  lea    D17(%rip),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida


assistant: ```c
u_long *ejecutartarea_1_svc(u_long *argp, struct svc_req *rqstp) {
  static u_long result;
  result = *argp / 8 * 2 + 9 - 6;
  printf("Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida\n");
  return &result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ejecutartarea_1_svc>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edx
  lea    D0(%rip),%rdi
  test   %edx,%edx
  lea    0x7(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x3,%eax
  lea    0x3(%rax,%rax,1),%eax
  mov    %eax,D9(%rip)
  call   <printf@plt>
  lea    D9(%rip),%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida


assistant: ```c
u_long *ejecutartarea_1_svc(u_long *argp, struct svc_req *rqstp) {
  static u_long result;
  result = *argp / 8 * 2 + 9 - 6;
  printf("Soy el servidor y realice la siguiente operacion aritmetica, entrada/8*2+6-9), que fue asignada a la salida\n");
  return &result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_malloc0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L10
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
void *s_malloc0(size_t size) {
  if (size == 0)
    return NULL;
  void *ptr = malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<s_malloc0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *s_malloc0(size_t size) {
  if (size == 0)
    return NULL;
  void *ptr = malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<s_malloc0>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *s_malloc0(size_t size) {
  if (size == 0)
    return NULL;
  void *ptr = malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s_malloc0>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L5
  mov    %rdi,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *s_malloc0(size_t size) {
  if (size == 0)
    return NULL;
  void *ptr = malloc(size);
  if (ptr)
    memset(ptr, 0, size);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_F90_FCD_BLANK>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L9
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
L9:
  nop
  leave
  ret
```

assistant: ```c
void _F90_FCD_BLANK(char *trg_addr, int trg_len) {
  if (trg_len > 0)
    (void)memset(trg_addr, ((int)' '), trg_len);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_F90_FCD_BLANK>:
  endbr64
  test   %esi,%esi
  jg     L2
  ret
L2:
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    $0x20,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _F90_FCD_BLANK(char *trg_addr, int trg_len) {
  if (trg_len > 0)
    (void)memset(trg_addr, ((int)' '), trg_len);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_F90_FCD_BLANK>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jg     L9
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x20,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void _F90_FCD_BLANK(char *trg_addr, int trg_len) {
  if (trg_len > 0)
    (void)memset(trg_addr, ((int)' '), trg_len);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_F90_FCD_BLANK>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jg     L8
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x20,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void _F90_FCD_BLANK(char *trg_addr, int trg_len) {
  if (trg_len > 0)
    (void)memset(trg_addr, ((int)' '), trg_len);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rebuild_vec_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *rebuild_vec_list(int *vec_list, int length) {
  vec_list = (int *)realloc(vec_list, (length + 1) * sizeof(int));
  return vec_list;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rebuild_vec_list>:
  endbr64
  sub    $0x8,%rsp
  lea    0x4(,%rsi,4),%esi
  call   <realloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *rebuild_vec_list(int *vec_list, int length) {
  vec_list = (int *)realloc(vec_list, (length + 1) * sizeof(int));
  return vec_list;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rebuild_vec_list>:
  endbr64
  lea    0x4(,%rsi,4),%esi
  jmp    1050 <realloc@plt>
```

assistant: ```c
int *rebuild_vec_list(int *vec_list, int length) {
  vec_list = (int *)realloc(vec_list, (length + 1) * sizeof(int));
  return vec_list;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rebuild_vec_list>:
  endbr64
  lea    0x4(,%rsi,4),%esi
  jmp    1050 <realloc@plt>
```

assistant: ```c
int *rebuild_vec_list(int *vec_list, int length) {
  vec_list = (int *)realloc(vec_list, (length + 1) * sizeof(int));
  return vec_list;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x86,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L4:
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x18(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0xb,-0x14(%rbp)
  jbe    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: %08x
%08x
%08x


assistant: ```c
void main() {
  unsigned x = 134;
  unsigned y = 1;
  unsigned q, r, p, i;
  for (i = 0; i < 12; i++) {
    q = x / y;
    r = x % y;
    p = q * y + r;
    y++;
    printf("%08x\n%08x\n%08x\n", y, q, p);
  }
}
```