ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L23
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L27
L23:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
type_guessed: string
name: parse_data
arguments: data_tag: D24
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string
name: parse_data
arguments: data_tag: D43
type_guessed: string

tool: D20: Wpisz liczbe rzeczywista: 

tool: D24: %lf

tool: D28: Wpisano liczbe rzeczywista %lf


tool: D35: Pierwiastek Kwadratowy z %lf to %lf


tool: D43: Pierwiastek kwadratowy z liczby ujemnej nie istnieje

assistant: ```c
int main() {
  double x, z;
  printf("Wpisz liczbe rzeczywista: ");
  scanf("%lf", &x);
  printf("Wpisano liczbe rzeczywista %lf\n", x);
  if (x >= 0) {
    z = sqrt(x);
    printf("Pierwiastek Kwadratowy z %lf to %lf\n", x, z);
  } else {
    printf("Pierwiastek kwadratowy z liczby ujemnej nie istnieje\n");
    exit(1);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <luaL_check_string@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x2,%edi
  call   <luaL_check_number@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <luaI_emptybuff@plt>
  jmp    L6
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <addstr@plt>
L6:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L8
  mov    $0x0,%edi
  call   <luaI_addchar@plt>
  mov    %eax,%edi
  call   <lua_pushstring@plt>
  nop
  leave
  ret
```

assistant: ```c
void str_rep(void) {
  char *s = luaL_check_string(1);
  int n = (int)luaL_check_number(2);
  luaI_emptybuff();
  while (n-- > 0)
    addstr(s);
  lua_pushstring(luaI_addchar(0));
}
```
user: What is the c source code of the assembly code below?

```asm
<str_rep>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%edi
  call   <luaL_check_string@plt>
  mov    %rax,%rbp
  mov    $0x2,%edi
  call   <luaL_check_number@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  call   <luaI_emptybuff@plt>
  lea    -0x1(%r12),%ebx
  test   %r12d,%r12d
  jle    L19
L13:
  mov    %rbp,%rdi
  call   <addstr@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L13
L19:
  mov    $0x0,%edi
  call   <luaI_addchar@plt>
  mov    %eax,%edi
  call   <lua_pushstring@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void str_rep(void) {
  char *s = luaL_check_string(1);
  int n = (int)luaL_check_number(2);
  luaI_emptybuff();
  while (n-- > 0)
    addstr(s);
  lua_pushstring(luaI_addchar(0));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rep>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  push   %rbx
  call   <luaL_check_string@plt>
  mov    $0x2,%edi
  mov    %rax,%rbp
  call   <luaL_check_number@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <luaI_emptybuff@plt>
  test   %r12d,%r12d
  jle    L10
  lea    -0x1(%r12),%ebx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <addstr@plt>
  sub    $0x1,%ebx
  jae    L1
L10:
  xor    %edi,%edi
  call   <luaI_addchar@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10e0 <lua_pushstring@plt>
```

assistant: ```c
void str_rep(void) {
  char *s = luaL_check_string(1);
  int n = (int)luaL_check_number(2);
  luaI_emptybuff();
  while (n-- > 0)
    addstr(s);
  lua_pushstring(luaI_addchar(0));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_rep>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  push   %rbx
  call   <luaL_check_string@plt>
  mov    $0x2,%edi
  mov    %rax,%rbp
  call   <luaL_check_number@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <luaI_emptybuff@plt>
  test   %r12d,%r12d
  jle    L1
  lea    -0x1(%r12),%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <addstr@plt>
  sub    $0x1,%ebx
  jae    L14
L1:
  xor    %edi,%edi
  call   <luaI_addchar@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    10e0 <lua_pushstring@plt>
```

assistant: ```c
void str_rep(void) {
  char *s = luaL_check_string(1);
  int n = (int)luaL_check_number(2);
  luaI_emptybuff();
  while (n-- > 0)
    addstr(s);
  lua_pushstring(luaI_addchar(0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L0:
  mov    -0x18(%rbp),%eax
  imul   -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %edx,%ecx
  sar    $0x4,%ecx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L17:
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jg     L0
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D38
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D38: 
%d

tool: D13: %d


assistant: ```c
int main() {
  int n, m, k, i = 1, sum = 0;
  scanf("\n%d", &n);
  scanf("\n%d", &m);
  scanf("\n%d", &k);
  sum = m * k;
  for (; n > k; n = n - k) {
    sum = sum + (k * (m - (i * m * 2 / 100)));
    i++;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    %r8d,%r9d
  imul   %esi,%r9d
  mov    0xc(%rsp),%edi
  cmp    %edi,%esi
  jge    L20
  mov    %r8d,%ecx
L6:
  movslq %ecx,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %r8d,%eax
  imul   %esi,%eax
  add    %eax,%r9d
  sub    %esi,%edi
  add    %r8d,%ecx
  cmp    %edi,%esi
  jl     L6
  mov    %edi,0xc(%rsp)
L20:
  mov    %r9d,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D13: 
%d

tool: D3: %d


assistant: ```c
int main() {
  int n, m, k, i = 1, sum = 0;
  scanf("\n%d", &n);
  scanf("\n%d", &m);
  scanf("\n%d", &k);
  sum = m * k;
  for (; n > k; n = n - k) {
    sum = sum + (k * (m - (i * m * 2 / 100)));
    i++;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r8d,%r9d
  imul   %esi,%r9d
  cmp    %edi,%esi
  jge    L0
  mov    %r8d,%ecx
  nopw   0x0(%rax,%rax,1)
L13:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  sub    %esi,%edi
  add    %r8d,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x24,%rdx
  sub    %edx,%eax
  add    %r8d,%eax
  imul   %esi,%eax
  add    %eax,%r9d
  cmp    %edi,%esi
  jl     L13
  mov    %edi,0xc(%rsp)
L0:
  mov    %r9d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string

tool: D7: 
%d

tool: D10: %d


assistant: ```c
int main() {
  int n, m, k, i = 1, sum = 0;
  scanf("\n%d", &n);
  scanf("\n%d", &m);
  scanf("\n%d", &k);
  sum = m * k;
  for (; n > k; n = n - k) {
    sum = sum + (k * (m - (i * m * 2 / 100)));
    i++;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r8d,%r9d
  imul   %esi,%r9d
  cmp    %edi,%esi
  jge    L24
  mov    %r8d,%ecx
  nopw   0x0(%rax,%rax,1)
L11:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  sub    %esi,%edi
  add    %r8d,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x24,%rdx
  sub    %edx,%eax
  add    %r8d,%eax
  imul   %esi,%eax
  add    %eax,%r9d
  cmp    %edi,%esi
  jl     L11
  mov    %edi,0xc(%rsp)
L24:
  mov    %r9d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D10
data_type: string

tool: D13: 
%d

tool: D10: %d


assistant: ```c
int main() {
  int n, m, k, i = 1, sum = 0;
  scanf("\n%d", &n);
  scanf("\n%d", &m);
  scanf("\n%d", &k);
  sum = m * k;
  for (; n > k; n = n - k) {
    sum = sum + (k * (m - (i * m * 2 / 100)));
    i++;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <init_uart@plt>
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L2
```

assistant: ```c
int main(void) {
  char c;
  init_uart(0, 1);
  for (;;) {
    c = getchar();
    putchar(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <init_uart@plt>
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L3
```

assistant: ```c
int main(void) {
  char c;
  init_uart(0, 1);
  for (;;) {
    c = getchar();
    putchar(c);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <init_uart@plt>
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  char c;
  init_uart(0, 1);
  for (;;) {
    c = getchar();
    putchar(c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <init_uart@plt>
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L9
```

assistant: ```c
int main(void) {
  char c;
  init_uart(0, 1);
  for (;;) {
    c = getchar();
    putchar(c);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strxstart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L42
L68:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <qe_toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <qe_toupper@plt>
  cmp    %rax,%rbx
  je     L120
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L80
L25:
  addq   $0x1,-0x18(%rbp)
  jmp    L42
L80:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L79
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L79
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L47
L79:
  addq   $0x1,-0x20(%rbp)
  jmp    L42
L47:
  mov    $0x0,%eax
  jmp    L113
L120:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  cmpq   $0x0,-0x38(%rbp)
  je     L128
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
L128:
  mov    $0x1,%eax
L113:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strxstart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (qe_toupper((unsigned char)*p) != qe_toupper((unsigned char)*q)) {
      if (*q == '-' || *q == '_' || *q == ' ') {
        q++;
        continue;
      }
      if (*p == '-' || *p == '_' || *p == ' ') {
        p++;
        continue;
      }
      return 0;
    }
    p++;
    q++;
  }
  if (ptr)
    *ptr = p;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strxstart>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%r13
  cmpb   $0x0,(%rsi)
  je     L27
  mov    %rsi,%rbx
  movabs $0x8000000000002001,%r14
  jmp    L0
L104:
  movzbl (%r12),%eax
  sub    $0x20,%eax
  cmp    $0x3f,%al
  ja     L87
  bt     %rax,%r14
  jae    L68
  add    $0x1,%r12
  jmp    L118
L81:
  add    $0x1,%r12
  add    $0x1,%rbx
L118:
  cmpb   $0x0,(%rbx)
  je     L27
L0:
  movzbl (%r12),%edi
  call   <qe_toupper@plt>
  mov    %rax,%rbp
  movzbl (%rbx),%edi
  call   <qe_toupper@plt>
  cmp    %rax,%rbp
  je     L81
  movzbl (%rbx),%eax
  sub    $0x20,%eax
  cmp    $0x3f,%al
  ja     L104
  bt     %rax,%r14
  jae    L104
  add    $0x1,%rbx
  jmp    L118
L27:
  mov    $0x1,%eax
  test   %r13,%r13
  je     L121
  mov    %r12,0x0(%r13)
  jmp    L121
L87:
  mov    $0x0,%eax
L121:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  mov    $0x0,%eax
  jmp    L121
```

assistant: ```c
int strxstart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (qe_toupper((unsigned char)*p) != qe_toupper((unsigned char)*q)) {
      if (*q == '-' || *q == '_' || *q == ' ') {
        q++;
        continue;
      }
      if (*p == '-' || *p == '_' || *p == ' ') {
        p++;
        continue;
      }
      return 0;
    }
    p++;
    q++;
  }
  if (ptr)
    *ptr = p;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strxstart>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  je     L34
  movabs $0x8000000000002001,%r14
  mov    %rsi,%rbx
L46:
  movzbl (%r12),%edi
  call   <qe_toupper@plt>
  movzbl (%rbx),%edi
  mov    %rax,%rbp
  call   <qe_toupper@plt>
  cmp    %rax,%rbp
  je     L18
  movzbl (%rbx),%eax
  lea    -0x20(%rax),%edx
  cmp    $0x3f,%dl
  ja     L81
  bt     %rdx,%r14
  jae    L81
L4:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L80:
  test   %al,%al
  jne    L46
L34:
  mov    $0x1,%eax
  test   %r13,%r13
  je     L40
  pop    %rbx
  pop    %rbp
  mov    %r12,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  movzbl (%r12),%ecx
  lea    -0x20(%rcx),%edx
  cmp    $0x3f,%dl
  ja     L88
  bt     %rdx,%r14
  jae    L88
  add    $0x1,%r12
  jmp    L80
  nopl   0x0(%rax)
L18:
  add    $0x1,%r12
  jmp    L4
  xchg   %ax,%ax
L88:
  xor    %eax,%eax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strxstart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (qe_toupper((unsigned char)*p) != qe_toupper((unsigned char)*q)) {
      if (*q == '-' || *q == '_' || *q == ' ') {
        q++;
        continue;
      }
      if (*p == '-' || *p == '_' || *p == ' ') {
        p++;
        continue;
      }
      return 0;
    }
    p++;
    q++;
  }
  if (ptr)
    *ptr = p;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strxstart>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  je     L77
  movabs $0x8000000000002001,%r14
  mov    %rsi,%rbx
L83:
  movzbl (%r12),%edi
  call   <qe_toupper@plt>
  movzbl (%rbx),%edi
  mov    %rax,%rbp
  call   <qe_toupper@plt>
  cmp    %rax,%rbp
  je     L19
  movzbl (%rbx),%eax
  lea    -0x20(%rax),%edx
  cmp    $0x3f,%dl
  ja     L80
  bt     %rdx,%r14
  jae    L80
L60:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L22:
  test   %al,%al
  jne    L83
L77:
  mov    $0x1,%eax
  test   %r13,%r13
  je     L56
  pop    %rbx
  pop    %rbp
  mov    %r12,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  movzbl (%r12),%ecx
  lea    -0x20(%rcx),%edx
  cmp    $0x3f,%dl
  ja     L42
  bt     %rdx,%r14
  jae    L42
  add    $0x1,%r12
  jmp    L22
  nopl   0x0(%rax)
L19:
  add    $0x1,%r12
  jmp    L60
  xchg   %ax,%ax
L42:
  xor    %eax,%eax
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strxstart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (qe_toupper((unsigned char)*p) != qe_toupper((unsigned char)*q)) {
      if (*q == '-' || *q == '_' || *q == ' ') {
        q++;
        continue;
      }
      if (*p == '-' || *p == '_' || *p == ' ') {
        p++;
        continue;
      }
      return 0;
    }
    p++;
    q++;
  }
  if (ptr)
    *ptr = p;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D7(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
type: string

tool: D21: Error %d

assistant: ```c
char *strerror(int errnum) {
  static char buf[16];
  sprintf(buf, "Error %d", errnum);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strerror>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  lea    D4(%rip),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: Error %d

assistant: ```c
char *strerror(int errnum) {
  static char buf[16];
  sprintf(buf, "Error %d", errnum);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strerror>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    %edi,%edx
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_guessed: string

tool: D16: Error %d

assistant: ```c
char *strerror(int errnum) {
  static char buf[16];
  sprintf(buf, "Error %d", errnum);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strerror>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  mov    %edi,%edx
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: string

tool: D18: Error %d

assistant: ```c
char *strerror(int errnum) {
  static char buf[16];
  sprintf(buf, "Error %d", errnum);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xb,%rax
  movzbl (%rax),%eax
  cmp    $0x3,%al
  setne  %dl
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  sete   %al
  and    %edx,%eax
  test   %al,%al
  je     L2
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  jmp    L15
L2:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
L15:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string

tool: D23: MOV  [

tool: D1: ],AL

tool: D12: ],AX

assistant: ```c
putmem(sym) char *sym;
{
  if ((sym[11] != 3) & (sym[12] == 1)) {
    ot("MOV  [");
    outstr(sym + 0);
    ot("],AL");
    nl();
  } else {
    ot("MOV  [");
    outstr(sym + 0);
    ot("],AX");
    nl();
  }
}
```