ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<matrix_offset>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L64
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L33
  mov    %edi,%esi
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L45:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rdx,%rax,1),%xmm2
  movdqu (%rcx,%rax,1),%xmm1
  movdqu (%rdx,%rax,1),%xmm4
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm2
  pmuludq %xmm4,%xmm1
  pmuludq %xmm2,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %rsi,%rax
  jne    L45
  movdqa %xmm3,%xmm0
  mov    %edi,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%eax
  test   $0x3,%dil
  je     L37
L6:
  movslq %esi,%r10
  mov    (%rcx,%r10,4),%r9d
  imul   (%rdx,%r10,4),%r9d
  lea    0x0(,%r10,4),%r8
  add    %r9d,%eax
  lea    0x1(%rsi),%r9d
  cmp    %r9d,%edi
  jle    L43
  mov    0x4(%rcx,%r8,1),%r9d
  imul   0x4(%rdx,%r8,1),%r9d
  add    $0x2,%esi
  add    %r9d,%eax
  cmp    %esi,%edi
  jle    L43
  mov    0x8(%rdx,%r8,1),%edx
  imul   0x8(%rcx,%r8,1),%edx
  add    %edx,%eax
  ret
  nopl   (%rax)
L64:
  xor    %eax,%eax
L43:
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  ret
L33:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
int matrix_offset(int ndim, int *index, int *strides) {
  int offset = 0;
  for (int i = 0; i < ndim; i++) {
    offset += index[i] * strides[i];
  }
  return offset;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<noise_grad2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movss  %xmm0,-0x18(%rbp)
  movss  %xmm1,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jg     L65
  movss  -0x18(%rbp),%xmm0
  jmp    L68
L65:
  movss  -0x1c(%rbp),%xmm0
L68:
  movss  %xmm0,-0x8(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jg     L28
  movss  -0x1c(%rbp),%xmm0
  jmp    L79
L28:
  movss  -0x18(%rbp),%xmm0
L79:
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L69
  movss  -0x8(%rbp),%xmm0
  movss  D6(%rip),%xmm1
  xorps  %xmm1,%xmm0
  jmp    L64
L69:
  movss  -0x8(%rbp),%xmm0
L64:
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L13
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movsd  D17(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  jmp    L44
L13:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  addsd  %xmm0,%xmm0
L44:
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: byte[4]
name: parse_data
arguments: data_tag: D17
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x80]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
float noise_grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0 * v : 2.0 * v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<noise_grad2>:
  endbr64
  test   $0x4,%dil
  jne    L7
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
L7:
  test   $0x1,%dil
  je     L39
  xorps  D10(%rip),%xmm1
L39:
  cvtss2sd %xmm1,%xmm1
  test   $0x2,%dil
  je     L6
  cvtss2sd %xmm0,%xmm0
  mulsd  D7(%rip),%xmm0
L16:
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  ret
L6:
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L16
```

tool_calls: name: parse_data
arguments: label: D10
type: byte[16]
name: parse_data
arguments: label: D7
type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
float noise_grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0 * v : 2.0 * v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<noise_grad2>:
  endbr64
  test   $0x4,%dil
  je     L16
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
L16:
  test   $0x1,%dil
  je     L29
  xorps  D4(%rip),%xmm0
L29:
  and    $0x2,%edi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  je     L26
  mulsd  D16(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  xchg   %ax,%ax
L26:
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: byte[16]
name: unpack_data
arguments: tag: D16
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
float noise_grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0 * v : 2.0 * v);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<noise_grad2>:
  endbr64
  test   $0x4,%dil
  je     L2
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
L2:
  test   $0x1,%dil
  je     L23
  xorps  D3(%rip),%xmm0
L23:
  and    $0x2,%edi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  je     L25
  mulsd  D19(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  xchg   %ax,%ax
L25:
  addsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: byte[16]
name: unpack_data
arguments: label: D19
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
float noise_grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0 * v : 2.0 * v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spaciatic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  jne    L40
  mov    $0x1,%eax
  jmp    L56
L40:
  cmpb   $0xa,-0x4(%rbp)
  jne    L34
  mov    $0x1,%eax
  jmp    L56
L34:
  cmpb   $0xd,-0x4(%rbp)
  jne    L48
  mov    $0x1,%eax
  jmp    L56
L48:
  mov    $0x0,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
char spaciatic(char input) {
  if (input == ' ') {
    return 1;
  }
  if (input == 10) {
    return 1;
  }
  if (input == 13) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<spaciatic>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x20,%dil
  ja     L9
  movabs $0x100002400,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L9:
  xor    $0x1,%eax
  ret
```

assistant: ```c
char spaciatic(char input) {
  if (input == ' ') {
    return 1;
  }
  if (input == 10) {
    return 1;
  }
  if (input == 13) {
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spaciatic>:
  endbr64
  xor    %eax,%eax
  cmp    $0x20,%dil
  ja     L0
  movabs $0xfffffffeffffdbff,%rax
  mov    %edi,%ecx
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
L0:
  ret
```

assistant: ```c
char spaciatic(char input) {
  if (input == ' ') {
    return 1;
  }
  if (input == 10) {
    return 1;
  }
  if (input == 13) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<spaciatic>:
  endbr64
  xor    %eax,%eax
  cmp    $0x20,%dil
  ja     L7
  movabs $0xfffffffeffffdbff,%rax
  mov    %edi,%ecx
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
L7:
  ret
```

assistant: ```c
char spaciatic(char input) {
  if (input == ' ') {
    return 1;
  }
  if (input == 10) {
    return 1;
  }
  if (input == 13) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nsleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x3e7,-0x38(%rbp)
  jle    L14
  mov    -0x38(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  imul   $0xfffffffffffffc18,%rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  imul   $0xf4240,%rax,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L12
L14:
  movl   $0x0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  imul   $0xf4240,%rax,%rax
  mov    %rax,-0x28(%rbp)
L12:
  lea    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int nsleep(long miliseconds) {
  struct timespec req, rem;
  if (miliseconds > 999) {
    req.tv_sec = (int)(miliseconds / 1000);
    req.tv_nsec = (miliseconds - ((long)req.tv_sec * 1000)) * 1000000;
  } else {
    req.tv_sec = 0;
    req.tv_nsec = miliseconds * 1000000;
  }
  return nanosleep(&req, &rem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nsleep>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x3e7,%rdi
  jle    L11
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %edx,%eax
  movslq %edx,%rdx
  imul   $0xfffffffffffffc18,%rdx,%rdx
  add    %rdi,%rdx
  imul   $0xf4240,%rdx,%rdi
L19:
  mov    %eax,(%rsp)
  mov    %rdi,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x38,%rsp
  ret
L11:
  imul   $0xf4240,%rdi,%rdi
  mov    $0x0,%eax
  jmp    L19
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nsleep(long miliseconds) {
  struct timespec req, rem;
  if (miliseconds > 999) {
    req.tv_sec = (int)(miliseconds / 1000);
    req.tv_nsec = (miliseconds - ((long)req.tv_sec * 1000)) * 1000000;
  } else {
    req.tv_sec = 0;
    req.tv_nsec = miliseconds * 1000000;
  }
  return nanosleep(&req, &rem);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nsleep>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x3e7,%rdi
  jle    L22
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  mov    %edx,%eax
  movslq %edx,%rdx
  imul   $0xfffffffffffffc18,%rdx,%rdx
  add    %rdi,%rdx
  imul   $0xf4240,%rdx,%rdi
L13:
  mov    %rdi,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <nanosleep@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x38,%rsp
  ret
  nop
L22:
  imul   $0xf4240,%rdi,%rdi
  xor    %eax,%eax
  jmp    L13
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nsleep(long miliseconds) {
  struct timespec req, rem;
  if (miliseconds > 999) {
    req.tv_sec = (int)(miliseconds / 1000);
    req.tv_nsec = (miliseconds - ((long)req.tv_sec * 1000)) * 1000000;
  } else {
    req.tv_sec = 0;
    req.tv_nsec = miliseconds * 1000000;
  }
  return nanosleep(&req, &rem);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nsleep>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x3e7,%rdi
  jle    L28
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x7,%rdx
  sub    %rax,%rdx
  mov    %edx,%eax
  movslq %edx,%rdx
  imul   $0xfffffffffffffc18,%rdx,%rdx
  add    %rdi,%rdx
  imul   $0xf4240,%rdx,%rdi
L15:
  mov    %rdi,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <nanosleep@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x38,%rsp
  ret
  nop
L28:
  imul   $0xf4240,%rdi,%rdi
  xor    %eax,%eax
  jmp    L15
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nsleep(long miliseconds) {
  struct timespec req, rem;
  if (miliseconds > 999) {
    req.tv_sec = (int)(miliseconds / 1000);
    req.tv_nsec = (miliseconds - ((long)req.tv_sec * 1000)) * 1000000;
  } else {
    req.tv_sec = 0;
    req.tv_nsec = miliseconds * 1000000;
  }
  return nanosleep(&req, &rem);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lib_add_track>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hash_insert@plt>
  test   %eax,%eax
  je     L25
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_filtered@plt>
  test   %eax,%eax
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <views_add_track@plt>
  jmp    L7
L25:
  nop
L7:
  leave
  ret
```

assistant: ```c
void lib_add_track(struct track_info *ti) {
  if (!hash_insert(ti)) {
    return;
  }
  if (!is_filtered(ti))
    views_add_track(ti);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lib_add_track>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <hash_insert@plt>
  test   %eax,%eax
  jne    L26
L4:
  pop    %rbx
  ret
L26:
  mov    %rbx,%rdi
  call   <is_filtered@plt>
  test   %eax,%eax
  jne    L4
  mov    %rbx,%rdi
  call   <views_add_track@plt>
  jmp    L4
```

assistant: ```c
void lib_add_track(struct track_info *ti) {
  if (!hash_insert(ti)) {
    return;
  }
  if (!is_filtered(ti))
    views_add_track(ti);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lib_add_track>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hash_insert@plt>
  test   %eax,%eax
  jne    L8
L17:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <is_filtered@plt>
  test   %eax,%eax
  jne    L17
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <views_add_track@plt>
```

assistant: ```c
void lib_add_track(struct track_info *ti) {
  if (!hash_insert(ti)) {
    return;
  }
  if (!is_filtered(ti))
    views_add_track(ti);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lib_add_track>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <hash_insert@plt>
  test   %eax,%eax
  jne    L14
L2:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <is_filtered@plt>
  test   %eax,%eax
  jne    L2
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <views_add_track@plt>
```

assistant: ```c
void lib_add_track(struct track_info *ti) {
  if (!hash_insert(ti)) {
    return;
  }
  if (!is_filtered(ti))
    views_add_track(ti);
}
```
user: Translate the below assembly code into C programming language:

```asm
<precise_round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  fstpt  -0x10(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <roundld@plt>
  add    $0x10,%rsp
  fldt   -0x10(%rbp)
  fdivrp %st,%st(1)
  leave
  ret
```

assistant: ```c
long double precise_round(long double value, size_t decimal_paces) {
  long double fac = pow(10, decimal_paces);
  return roundld(value * fac) / fac;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<precise_round>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  fldt   0x20(%rsp)
  fxch   %st(1)
  fld    %st(0)
  fstpt  (%rsp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <roundld@plt>
  fldt   0x10(%rsp)
  fdivrp %st,%st(1)
  add    $0x28,%rsp
  ret
```

assistant: ```c
long double precise_round(long double value, size_t decimal_paces) {
  long double fac = pow(10, decimal_paces);
  return roundld(value * fac) / fac;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<precise_round>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  sub    $0x10,%rsp
  fldt   0x30(%rsp)
  fmul   %st(1),%st
  fxch   %st(1)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <roundld@plt>
  fldt   0x10(%rsp)
  add    $0x28,%rsp
  fdivrp %st,%st(1)
  ret
```

assistant: ```c
long double precise_round(long double value, size_t decimal_paces) {
  long double fac = pow(10, decimal_paces);
  return roundld(value * fac) / fac;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<precise_round>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0xa,%edi
  call   <pow@plt>
  sub    $0x10,%rsp
  fldt   0x30(%rsp)
  fmul   %st(1),%st
  fxch   %st(1)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <roundld@plt>
  fldt   0x10(%rsp)
  add    $0x28,%rsp
  fdivrp %st,%st(1)
  ret
```

assistant: ```c
long double precise_round(long double value, size_t decimal_paces) {
  long double fac = pow(10, decimal_paces);
  return roundld(value * fac) / fac;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c, b;
  b = -c;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int c, b;
  b = -c;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int c, b;
  b = -c;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int c, b;
  b = -c;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <kprint_at@plt>
  mov    $0xa,%edx
  mov    $0x4b,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <kprint_at@plt>
  mov    $0x14,%edx
  mov    $0x0,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <kprint_at@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <kprint@plt>
  mov    $0x18,%edx
  mov    $0x2d,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <kprint_at@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D43
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D10: X

tool: D9: This text spans multiple lines

tool: D43: There is a line
break

tool: D4: What happens when we run out of space?

assistant: ```c
void main() {
  clear_screen();
  kprint_at("X", 1, 6);
  kprint_at("This text spans multiple lines", 75, 10);
  kprint_at("There is a line\nbreak", 0, 20);
  kprint("There is a line\nbreak");
  kprint_at("What happens when we run out of space?", 45, 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0xa,%edx
  mov    $0x4b,%esi
  lea    D16(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0x14,%edx
  mov    $0x0,%esi
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  call   <kprint_at@plt>
  mov    %rbx,%rdi
  call   <kprint@plt>
  mov    $0x18,%edx
  mov    $0x2d,%esi
  lea    D2(%rip),%rdi
  call   <kprint_at@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D33
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D33: X

tool: D16: This text spans multiple lines

tool: D27: There is a line
break

tool: D2: What happens when we run out of space?

assistant: ```c
void main() {
  clear_screen();
  kprint_at("X", 1, 6);
  kprint_at("This text spans multiple lines", 75, 10);
  kprint_at("There is a line\nbreak", 0, 20);
  kprint("There is a line\nbreak");
  kprint_at("What happens when we run out of space?", 45, 24);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D1(%rip),%rbp
  call   <clear_screen@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D32(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0xa,%edx
  mov    $0x4b,%esi
  lea    D24(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0x14,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <kprint_at@plt>
  mov    %rbp,%rdi
  call   <kprint@plt>
  mov    $0x18,%edx
  mov    $0x2d,%esi
  pop    %rbp
  lea    D11(%rip),%rdi
  jmp    1070 <kprint_at@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string
name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D1: There is a line
break

tool: D32: X

tool: D24: This text spans multiple lines

tool: D11: What happens when we run out of space?

assistant: ```c
void main() {
  clear_screen();
  kprint_at("X", 1, 6);
  kprint_at("This text spans multiple lines", 75, 10);
  kprint_at("There is a line\nbreak", 0, 20);
  kprint("There is a line\nbreak");
  kprint_at("What happens when we run out of space?", 45, 24);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  lea    D10(%rip),%rbp
  call   <clear_screen@plt>
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0xa,%edx
  mov    $0x4b,%esi
  lea    D25(%rip),%rdi
  call   <kprint_at@plt>
  mov    $0x14,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <kprint_at@plt>
  mov    %rbp,%rdi
  call   <kprint@plt>
  mov    $0x18,%edx
  mov    $0x2d,%esi
  pop    %rbp
  lea    D23(%rip),%rdi
  jmp    1070 <kprint_at@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D25
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string

tool: D10: There is a line
break

tool: D6: X

tool: D25: This text spans multiple lines

tool: D23: What happens when we run out of space?

assistant: ```c
void main() {
  clear_screen();
  kprint_at("X", 1, 6);
  kprint_at("This text spans multiple lines", 75, 10);
  kprint_at("There is a line\nbreak", 0, 20);
  kprint("There is a line\nbreak");
  kprint_at("What happens when we run out of space?", 45, 24);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nsec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0x3b9aca00,%eax,%edx
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%eax,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int64_t nsec(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return ((int64_t)tv.tv_sec * 1000000000) + (int64_t)tv.tv_usec * 1000;
}
```