ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<logical_iterator>:
  endbr64
  mov    %edi,%eax
  test   %cx,%cx
  je     L48
  mov    %rdx,%r8
  sub    $0x1,%ecx
  movzwl %cx,%ecx
  lea    0x4(%rdx,%rcx,4),%rdx
  jmp    L18
L15:
  cmpl   $0x0,(%r8)
  je     L29
L36:
  add    $0x4,%r8
  cmp    %rdx,%r8
  je     L48
L18:
  test   %esi,%esi
  je     L15
  cmpl   $0x0,(%r8)
  je     L36
L29:
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
L48:
  ret
```

assistant: ```c
bool logical_iterator(bool initial_result, bool condition_matcher, bool *boolean_list, unsigned short array_size) {
  unsigned short i;
  bool result = initial_result;
  for (i = 0u; i < array_size; i++) {
    if (condition_matcher ? boolean_list[i] : !boolean_list[i]) {
      result = !initial_result;
      break;
    }
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<logical_iterator>:
  endbr64
  mov    %edi,%eax
  test   %cx,%cx
  je     L1
  sub    $0x1,%ecx
  movzwl %cx,%ecx
  lea    0x4(%rdx,%rcx,4),%r8
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L40:
  test   %ecx,%ecx
  jne    L37
L35:
  add    $0x4,%rdx
  cmp    %rdx,%r8
  je     L1
L16:
  mov    (%rdx),%ecx
  test   %esi,%esi
  jne    L40
  test   %ecx,%ecx
  jne    L35
L37:
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
L1:
  ret
```

assistant: ```c
bool logical_iterator(bool initial_result, bool condition_matcher, bool *boolean_list, unsigned short array_size) {
  unsigned short i;
  bool result = initial_result;
  for (i = 0u; i < array_size; i++) {
    if (condition_matcher ? boolean_list[i] : !boolean_list[i]) {
      result = !initial_result;
      break;
    }
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<logical_iterator>:
  endbr64
  mov    %edi,%eax
  test   %cx,%cx
  je     L71
  sub    $0x1,%ecx
  movzwl %cx,%ecx
  lea    0x4(%rdx,%rcx,4),%rcx
  test   %esi,%esi
  jne    L25
  mov    (%rdx),%edi
  test   %edi,%edi
  je     L45
L7:
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  je     L79
  mov    (%rdx),%edi
  test   %edi,%edi
  jne    L7
L45:
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  je     L71
L25:
  mov    (%rdx),%esi
  test   %esi,%esi
  je     L31
  jmp    L45
  nopl   0x0(%rax)
L71:
  ret
  nopl   0x0(%rax)
L79:
  ret
```

assistant: ```c
bool logical_iterator(bool initial_result, bool condition_matcher, bool *boolean_list, unsigned short array_size) {
  unsigned short i;
  bool result = initial_result;
  for (i = 0u; i < array_size; i++) {
    if (condition_matcher ? boolean_list[i] : !boolean_list[i]) {
      result = !initial_result;
      break;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<linear2ulaw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  sar    $0x8,%ax
  cwtl
  and    $0x80,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  movzwl -0x14(%rbp),%eax
  neg    %eax
  mov    %ax,-0x14(%rbp)
L16:
  cmpw   $0x7f7b,-0x14(%rbp)
  jle    L12
  movw   $0x7f7b,-0x14(%rbp)
L12:
  movzwl -0x14(%rbp),%eax
  add    $0x84,%ax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  sar    $0x7,%ax
  cwtl
  movzbl %al,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x8(%rbp)
  movswl -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  not    %eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L13
  movb   $0x2,-0xd(%rbp)
L13:
  movzbl -0xd(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char linear2ulaw(short sample) {
  static int exp_lut[256] = {0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7};
  int sign, exponent, mantissa;
  unsigned char ulawbyte;
  sign = (sample >> 8) & 0x80;
  if (sign != 0)
    sample = -sample;
  if (sample > 32635)
    sample = 32635;
  sample = sample + 0x84;
  exponent = exp_lut[(sample >> 7) & 0xFF];
  mantissa = (sample >> (exponent + 3)) & 0x0F;
  ulawbyte = ~(sign | (exponent << 4) | mantissa);
  if (ulawbyte == 0)
    ulawbyte = 0x02;
  return ulawbyte;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linear2ulaw>:
  endbr64
  mov    %edi,%eax
  sar    $0x8,%ax
  mov    %edi,%edx
  neg    %edx
  and    $0x80,%ax
  mov    %eax,%esi
  cmovne %edx,%edi
  mov    $0x7f7b,%eax
  cmp    %ax,%di
  cmovg  %eax,%edi
  add    $0x84,%di
  mov    %edi,%eax
  sar    $0x7,%ax
  movzbl %al,%eax
  lea    D5(%rip),%rdx
  mov    (%rdx,%rax,4),%edx
  movswl %di,%edi
  lea    0x3(%rdx),%ecx
  sar    %cl,%edi
  and    $0xf,%edi
  mov    %edx,%eax
  shl    $0x4,%eax
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xff,%al
  mov    $0x2,%edx
  cmove  %edx,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string

tool: 

assistant: ```c
unsigned char linear2ulaw(short sample) {
  static int exp_lut[256] = {0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7};
  int sign, exponent, mantissa;
  unsigned char ulawbyte;
  sign = (sample >> 8) & 0x80;
  if (sign != 0)
    sample = -sample;
  if (sample > 32635)
    sample = 32635;
  sample = sample + 0x84;
  exponent = exp_lut[(sample >> 7) & 0xFF];
  mantissa = (sample >> (exponent + 3)) & 0x0F;
  ulawbyte = ~(sign | (exponent << 4) | mantissa);
  if (ulawbyte == 0)
    ulawbyte = 0x02;
  return ulawbyte;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linear2ulaw>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x8,%ax
  neg    %edx
  and    $0x80,%ax
  cmovne %edx,%edi
  mov    %eax,%esi
  mov    $0x7f7b,%eax
  lea    D7(%rip),%rdx
  cmp    %ax,%di
  cmovg  %eax,%edi
  add    $0x84,%di
  mov    %edi,%eax
  movswl %di,%edi
  sar    $0x7,%ax
  movzbl %al,%eax
  mov    (%rdx,%rax,4),%edx
  lea    0x3(%rdx),%ecx
  mov    %edx,%eax
  mov    $0x2,%edx
  sar    %cl,%edi
  shl    $0x4,%eax
  and    $0xf,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xff,%al
  cmove  %edx,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: 

assistant: ```c
unsigned char linear2ulaw(short sample) {
  static int exp_lut[256] = {0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7};
  int sign, exponent, mantissa;
  unsigned char ulawbyte;
  sign = (sample >> 8) & 0x80;
  if (sign != 0)
    sample = -sample;
  if (sample > 32635)
    sample = 32635;
  sample = sample + 0x84;
  exponent = exp_lut[(sample >> 7) & 0xFF];
  mantissa = (sample >> (exponent + 3)) & 0x0F;
  ulawbyte = ~(sign | (exponent << 4) | mantissa);
  if (ulawbyte == 0)
    ulawbyte = 0x02;
  return ulawbyte;
}
```
user: What is the c source code of the assembly code below:

```asm
<linear2ulaw>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x8,%ax
  neg    %edx
  and    $0x80,%ax
  cmovne %edx,%edi
  mov    %eax,%esi
  mov    $0x7f7b,%eax
  lea    D3(%rip),%rdx
  cmp    %ax,%di
  cmovg  %eax,%edi
  add    $0x84,%di
  mov    %edi,%eax
  movswl %di,%edi
  sar    $0x7,%ax
  movzbl %al,%eax
  mov    (%rdx,%rax,4),%edx
  lea    0x3(%rdx),%ecx
  mov    %edx,%eax
  mov    $0x2,%edx
  sar    %cl,%edi
  shl    $0x4,%eax
  and    $0xf,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xff,%al
  cmove  %edx,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: 

assistant: ```c
unsigned char linear2ulaw(short sample) {
  static int exp_lut[256] = {0, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7};
  int sign, exponent, mantissa;
  unsigned char ulawbyte;
  sign = (sample >> 8) & 0x80;
  if (sign != 0)
    sample = -sample;
  if (sample > 32635)
    sample = 32635;
  sample = sample + 0x84;
  exponent = exp_lut[(sample >> 7) & 0xFF];
  mantissa = (sample >> (exponent + 3)) & 0x0F;
  ulawbyte = ~(sign | (exponent << 4) | mantissa);
  if (ulawbyte == 0)
    ulawbyte = 0x02;
  return ulawbyte;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<findtab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L30:
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L68:
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x18(%rbp),%rax
  jmp    L31
L11:
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
L50:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L30
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  jmp    L31
L7:
  mov    -0x18(%rbp),%rax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char *findtab(char *s, int field) {
  int i = 0;
  while (field) {
    i = 1;
    while (*s != '\t' && *s != '\0')
      s++;
    if (*s == '\0')
      return s;
    s++;
    field--;
  }
  return i ? --s : s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findtab>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jne    L8
L3:
  mov    %rdx,%rax
  ret
L2:
  mov    %rdi,%rdx
L63:
  test   %al,%al
  je     L3
  lea    0x1(%rdx),%rdi
  sub    $0x1,%esi
  je     L3
L8:
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L76
  test   %al,%al
  je     L76
L81:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L2
  test   %al,%al
  jne    L81
  jmp    L2
L76:
  mov    %rdi,%rdx
  jmp    L63
```

assistant: ```c
char *findtab(char *s, int field) {
  int i = 0;
  while (field) {
    i = 1;
    while (*s != '\t' && *s != '\0')
      s++;
    if (*s == '\0')
      return s;
    s++;
    field--;
  }
  return i ? --s : s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findtab>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  je     L55
  nopl   0x0(%rax,%rax,1)
L67:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  cmp    $0x9,%al
  je     L33
  nopl   0x0(%rax,%rax,1)
L62:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x9,%al
  je     L33
  test   %al,%al
  jne    L62
L33:
  mov    %rdi,%r8
  test   %al,%al
  je     L55
  add    $0x1,%rdi
  sub    $0x1,%esi
  jne    L67
L55:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *findtab(char *s, int field) {
  int i = 0;
  while (field) {
    i = 1;
    while (*s != '\t' && *s != '\0')
      s++;
    if (*s == '\0')
      return s;
    s++;
    field--;
  }
  return i ? --s : s;
}
```
user: What is the c source code of the assembly code below?

```asm
<findtab>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  je     L41
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  cmp    $0x9,%al
  je     L3
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x9,%al
  je     L3
  test   %al,%al
  jne    L24
L3:
  mov    %rdi,%r8
  test   %al,%al
  je     L41
  add    $0x1,%rdi
  sub    $0x1,%esi
  jne    L10
L41:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *findtab(char *s, int field) {
  int i = 0;
  while (field) {
    i = 1;
    while (*s != '\t' && *s != '\0')
      s++;
    if (*s == '\0')
      return s;
    s++;
    field--;
  }
  return i ? --s : s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nepim_unit_ll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_float@plt>
  test   %rax,%rax
  je     L29
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <multiplier_affix@plt>
  cvttss2si %xmm0,%rax
  imul   %rbx,%rax
  jmp    L14
L29:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <multiplier_affix@plt>
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rax
L14:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long long nepim_unit_ll(const char *str) {
  float f;
  if (parse_float(&f, str))
    return strtoll(str, 0, 10) * (long long)multiplier_affix(str);
  return f * multiplier_affix(str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nepim_unit_ll>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rsi
  call   <parse_float@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbx,%rdi
  call   <multiplier_affix@plt>
  mulss  0x4(%rsp),%xmm0
  cvttss2si %xmm0,%rax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtoll@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <multiplier_affix@plt>
  cvttss2si %xmm0,%rax
  imul   %rbp,%rax
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long nepim_unit_ll(const char *str) {
  float f;
  if (parse_float(&f, str))
    return strtoll(str, 0, 10) * (long long)multiplier_affix(str);
  return f * multiplier_affix(str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nepim_unit_ll>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <parse_float@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbp,%rdi
  call   <multiplier_affix@plt>
  mulss  0x4(%rsp),%xmm0
  cvttss2si %xmm0,%rax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <strtoll@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <multiplier_affix@plt>
  cvttss2si %xmm0,%rax
  imul   %rbx,%rax
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long nepim_unit_ll(const char *str) {
  float f;
  if (parse_float(&f, str))
    return strtoll(str, 0, 10) * (long long)multiplier_affix(str);
  return f * multiplier_affix(str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nepim_unit_ll>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <parse_float@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rdi
  call   <multiplier_affix@plt>
  mulss  0x4(%rsp),%xmm0
  cvttss2si %xmm0,%rax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <strtoll@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <multiplier_affix@plt>
  cvttss2si %xmm0,%rax
  imul   %rbx,%rax
  jmp    L25
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long nepim_unit_ll(const char *str) {
  float f;
  if (parse_float(&f, str))
    return strtoll(str, 0, 10) * (long long)multiplier_affix(str);
  return f * multiplier_affix(str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x814(%rbp)
  jmp    L0
L17:
  mov    -0x814(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x814(%rbp),%eax
  cltq
  mov    %edx,-0x810(%rbp,%rax,4)
  mov    -0x814(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x814(%rbp),%edx
  mov    %edx,-0x410(%rbp,%rax,4)
  addl   $0x1,-0x814(%rbp)
L0:
  cmpl   $0xff,-0x814(%rbp)
  jle    L17
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void main() {
  int i;
  int char_to_index[256];
  int index_to_char[257];
  for (i = 0; i < 256; i++) {
    char_to_index[i] = i + 1;
    index_to_char[i + 1] = i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x100,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  ret
```

assistant: ```c
void main() {
  int i;
  int char_to_index[256];
  int index_to_char[257];
  for (i = 0; i < 256; i++) {
    char_to_index[i] = i + 1;
    index_to_char[i + 1] = i;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int i;
  int char_to_index[256];
  int index_to_char[257];
  for (i = 0; i < 256; i++) {
    char_to_index[i] = i + 1;
    index_to_char[i + 1] = i;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int i;
  int char_to_index[256];
  int index_to_char[257];
  for (i = 0; i < 256; i++) {
    char_to_index[i] = i + 1;
    index_to_char[i + 1] = i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<summaryUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%esi
  lea    D3(%rip),%r9
  lea    D10(%rip),%r8
  lea    D34(%rip),%rdx
  mov    %rdx,%rcx
  lea    D87(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L3
L11:
  lea    D9(%rip),%rax
  mov    %rax,%rdx
  lea    D86(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <writeError@plt>
L3:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D34
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D87
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D86
type_infered: string

tool: D34: Brute force module for VNC sessions

tool: D10: 2.1

tool: D5: %s : version %s

tool: D3: No usable OPENSSL. Module disabled.

tool: D87: %s : version %s (%s)

tool: D9: vnc.mod

tool: D86: %s reports an error in summaryUsage() : ppszSummary must be NULL when called

assistant: ```c
void summaryUsage(char **ppszSummary) {
  int iLength = 0;
  if (*ppszSummary == NULL) {
    iLength = strlen("Brute force module for VNC sessions") + strlen("2.1") + strlen("%s : version %s") + strlen("No usable OPENSSL. Module disabled.") + 1;
    *ppszSummary = (char *)malloc(iLength);
    memset(*ppszSummary, 0, iLength);
    snprintf(*ppszSummary, iLength, "%s : version %s (%s)", "Brute force module for VNC sessions", "2.1", "No usable OPENSSL. Module disabled.");
  } else {
    writeError(3, "%s reports an error in summaryUsage() : ppszSummary must be NULL when called", "vnc.mod");
  }
}
```