ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D12(%rip),%r14
  lea    D6(%rip),%r13
  lea    D78(%rip),%r12
  lea    D96(%rip),%rbp
L31:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D68(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x64,%eax
  cmp    $0xf,%al
  ja     L23
  movzbl %al,%eax
  lea    D1(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    %rbx,%rdi
  call   <input@plt>
  mov    %rax,%rbx
  jmp    L31
  mov    %rbx,%rdi
  call   <print@plt>
  jmp    L31
  mov    %rbx,%rdi
  call   <sort@plt>
  jmp    L31
  mov    %rbx,%rdi
  call   <search@plt>
  jmp    L31
  mov    %rbx,%rdi
  call   <delete@plt>
  mov    %rax,%rbx
  jmp    L31
L23:
  lea    D63(%rip),%rdi
  call   <printf@plt>
  jmp    L31
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D78
type_infered: string
name: disassemble_data
arguments: data_tag: D96
type_infered: string
name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D91
type_infered: string
name: disassemble_data
arguments: data_tag: D57
type_infered: string
name: disassemble_data
arguments: data_tag: D68
type_infered: string
name: disassemble_data
arguments: data_tag: D63
type_infered: string

tool: D12: 
i:input


tool: D6: p:print


tool: D78: s:sort


tool: D96: f:search


tool: D5: d:delete


tool: D91: q:quit


tool: D57: Enter your choice: 

tool: D68: %c

tool: D63: invalid choice


assistant: ```c
main() {
  char ***db = 0;
  char choice;
  while (1) {
    printf("\ni:input\n");
    printf("p:print\n");
    printf("s:sort\n");
    printf("f:search\n");
    printf("d:delete\n");
    printf("q:quit\n");
    printf("Enter your choice: ");
    scanf("%c", &choice);
    switch (choice) {
    case 'i':
      db = input(db);
      break;
    case 'p':
      print(db);
      break;
    case 's':
      sort(db);
      break;
    case 'f':
      search(db);
      break;
    case 'd':
      db = delete (db);
      break;
    case 'q':
      return;
    default:
      printf("invalid choice\n");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D69(%rip),%r15
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  lea    D32(%rip),%r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D63(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x17(%rsp),%rax
  movq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  xchg   %ax,%ax
L55:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x17(%rsp),%eax
  sub    $0x64,%eax
  cmp    $0xf,%al
  ja     L74
  lea    D47(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L74:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L55
  xchg   %ax,%ax
  mov    0x8(%rsp),%rdi
  call   <sort@plt>
  jmp    L55
  nop
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
  mov    0x8(%rsp),%rdi
  call   <print@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
  mov    0x8(%rsp),%rdi
  call   <input@plt>
  mov    %rax,0x8(%rsp)
  jmp    L55
  nopl   0x0(%rax)
  mov    0x8(%rsp),%rdi
  call   <search@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
  mov    0x8(%rsp),%rdi
  call   <delete@plt>
  mov    %rax,0x8(%rsp)
  jmp    L55
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D69
datatype: string
name: parse_data
arguments: data_tag: D45
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D48
datatype: string
name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D63
datatype: string
name: parse_data
arguments: data_tag: D59
datatype: string
name: parse_data
arguments: data_tag: D51
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string

tool: D69: 
i:input


tool: D45: p:print


tool: D32: s:sort


tool: D48: f:search


tool: D14: d:delete


tool: D63: q:quit


tool: D59: Enter your choice: 

tool: D51: %c

tool: D24: invalid choice


assistant: ```c
main() {
  char ***db = 0;
  char choice;
  while (1) {
    printf("\ni:input\n");
    printf("p:print\n");
    printf("s:sort\n");
    printf("f:search\n");
    printf("d:delete\n");
    printf("q:quit\n");
    printf("Enter your choice: ");
    scanf("%c", &choice);
    switch (choice) {
    case 'i':
      db = input(db);
      break;
    case 'p':
      print(db);
      break;
    case 's':
      sort(db);
      break;
    case 'f':
      search(db);
      break;
    case 'd':
      db = delete (db);
      break;
    case 'q':
      return;
    default:
      printf("invalid choice\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: Unable to allocate %d bytes of memory

assistant: ```c
void *xrealloc(void *ptr, unsigned int howmuch) {
  void *p = realloc(ptr, howmuch);
  if (!p)
    die("Unable to allocate %d bytes of memory", howmuch);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrealloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L19:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <die@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Unable to allocate %d bytes of memory

assistant: ```c
void *xrealloc(void *ptr, unsigned int howmuch) {
  void *p = realloc(ptr, howmuch);
  if (!p)
    die("Unable to allocate %d bytes of memory", howmuch);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: Unable to allocate %d bytes of memory

assistant: ```c
void *xrealloc(void *ptr, unsigned int howmuch) {
  void *p = realloc(ptr, howmuch);
  if (!p)
    die("Unable to allocate %d bytes of memory", howmuch);
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrealloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: Unable to allocate %d bytes of memory

assistant: ```c
void *xrealloc(void *ptr, unsigned int howmuch) {
  void *p = realloc(ptr, howmuch);
  if (!p)
    die("Unable to allocate %d bytes of memory", howmuch);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cstrichr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L86
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L86:
  mov    $0x0,%eax
  jmp    L107
L5:
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <index@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  jmp    L107
L23:
  cmpb   $0x40,-0x1c(%rbp)
  jle    L69
  cmpb   $0x5a,-0x1c(%rbp)
  jg     L69
  movzbl -0x1c(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x1c(%rbp)
  jmp    L17
L69:
  cmpb   $0x60,-0x1c(%rbp)
  jle    L26
  cmpb   $0x7a,-0x1c(%rbp)
  jg     L26
  movzbl -0x1c(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x1c(%rbp)
  jmp    L17
L26:
  mov    $0x0,%eax
  jmp    L107
L17:
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <index@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L107:
  leave
  ret
```

assistant: ```c
char *cstrichr(char *str, char kar) {
  char *p;
  if (str == NULL || !*str)
    return NULL;
  if ((p = index((str), (kar))) != NULL)
    return p;
  if (kar >= 'A' && kar <= 'Z')
    kar += ' ';
  else if (kar >= 'a' && kar <= 'z')
    kar -= ' ';
  else {
    return NULL;
  }
  p = index((str), (kar));
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cstrichr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L26
  mov    %esi,%ebp
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L11
  movsbl %sil,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L68
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L68:
  lea    -0x41(%rbp),%edx
  lea    0x20(%rbp),%esi
  cmp    $0x19,%dl
  jbe    L66
  lea    -0x61(%rbp),%edx
  cmp    $0x19,%dl
  ja     L11
  lea    -0x20(%rbp),%esi
L66:
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  jmp    L11
L26:
  mov    %rdi,%rax
  jmp    L11
```

assistant: ```c
char *cstrichr(char *str, char kar) {
  char *p;
  if (str == NULL || !*str)
    return NULL;
  if ((p = index((str), (kar))) != NULL)
    return p;
  if (kar >= 'A' && kar <= 'Z')
    kar += ' ';
  else if (kar >= 'a' && kar <= 'z')
    kar -= ' ';
  else {
    return NULL;
  }
  p = index((str), (kar));
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cstrichr>:
  endbr64
  test   %rdi,%rdi
  je     L45
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %esi,%ebx
  movsbl %sil,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L37:
  lea    -0x41(%rbx),%eax
  lea    0x20(%rbx),%esi
  cmp    $0x19,%al
  jbe    L11
  lea    -0x61(%rbx),%eax
  cmp    $0x19,%al
  ja     L16
  lea    -0x20(%rbx),%esi
L11:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  movsbl %sil,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <index@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *cstrichr(char *str, char kar) {
  char *p;
  if (str == NULL || !*str)
    return NULL;
  if ((p = index((str), (kar))) != NULL)
    return p;
  if (kar >= 'A' && kar <= 'Z')
    kar += ' ';
  else if (kar >= 'a' && kar <= 'z')
    kar -= ' ';
  else {
    return NULL;
  }
  p = index((str), (kar));
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cstrichr>:
  endbr64
  test   %rdi,%rdi
  je     L47
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %esi,%ebx
  movsbl %sil,%esi
  call   <index@plt>
  test   %rax,%rax
  je     L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L27:
  lea    -0x41(%rbx),%eax
  lea    0x20(%rbx),%esi
  cmp    $0x19,%al
  jbe    L32
  lea    -0x61(%rbx),%eax
  cmp    $0x19,%al
  ja     L23
  lea    -0x20(%rbx),%esi
L32:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  movsbl %sil,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <index@plt>
  cs nopw 0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *cstrichr(char *str, char kar) {
  char *p;
  if (str == NULL || !*str)
    return NULL;
  if ((p = index((str), (kar))) != NULL)
    return p;
  if (kar >= 'A' && kar <= 'Z')
    kar += ' ';
  else if (kar >= 'a' && kar <= 'z')
    kar -= ' ';
  else {
    return NULL;
  }
  p = index((str), (kar));
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Bits_log2x64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L1:
  addl   $0x1,-0x4(%rbp)
L19:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Bits_log2x64(uint64_t number) {
  int out = 0;
  while (number >>= 1) {
    out++;
  }
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Bits_log2x64>:
  endbr64
  sar    %edi
  je     L18
  mov    $0x0,%eax
L1:
  add    $0x1,%eax
  sar    %edi
  jne    L1
  ret
L18:
  mov    %edi,%eax
  ret
```

assistant: ```c
int Bits_log2x64(uint64_t number) {
  int out = 0;
  while (number >>= 1) {
    out++;
  }
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Bits_log2x64>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L7
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%eax
  sar    %edi
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
int Bits_log2x64(uint64_t number) {
  int out = 0;
  while (number >>= 1) {
    out++;
  }
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Bits_log2x64>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L14
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%eax
  sar    %edi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
int Bits_log2x64(uint64_t number) {
  int out = 0;
  while (number >>= 1) {
    out++;
  }
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ptoc3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  movsd  D9(%rip),%xmm0
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ptoc3(double pr, double pe, double pp, double *cr, double *ct, double *cz) {
  double rcp;
  static double dtor = 1.74532925199432958e-2;
  rcp = dtor * pp;
  *cr = pr * sin(rcp);
  *ct = pe;
  *cz = pr * cos(rcp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ptoc3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r13
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%rbp
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  mulsd  D8(%rip),%xmm2
  movapd %xmm2,%xmm0
  call   <sincos@plt>
  movq   %rbx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%r14)
  mov    %r13,(%r12)
  movq   %rbx,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: byte[8]

tool: {"D8": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
int ptoc3(double pr, double pe, double pp, double *cr, double *ct, double *cz) {
  double rcp;
  static double dtor = 1.74532925199432958e-2;
  rcp = dtor * pp;
  *cr = pr * sin(rcp);
  *ct = pe;
  *cz = pr * cos(rcp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ptoc3>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  mulsd  D9(%rip),%xmm2
  movsd  %xmm1,(%rsp)
  movapd %xmm2,%xmm0
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm0
  xor    %eax,%eax
  movsd  (%rsp),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  0x10(%rsp),%xmm3
  movsd  %xmm0,(%r12)
  movsd  %xmm1,0x0(%rbp)
  movsd  %xmm3,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: byte[8]

tool: {"D9": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
int ptoc3(double pr, double pe, double pp, double *cr, double *ct, double *cz) {
  double rcp;
  static double dtor = 1.74532925199432958e-2;
  rcp = dtor * pp;
  *cr = pr * sin(rcp);
  *ct = pe;
  *cz = pr * cos(rcp);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ptoc3>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  mulsd  D8(%rip),%xmm2
  movsd  %xmm1,(%rsp)
  movapd %xmm2,%xmm0
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm0
  xor    %eax,%eax
  movsd  (%rsp),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  0x10(%rsp),%xmm3
  movsd  %xmm0,(%r12)
  movsd  %xmm1,0x0(%rbp)
  movsd  %xmm3,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: byte[8]

tool: {"D8": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

assistant: ```c
int ptoc3(double pr, double pe, double pp, double *cr, double *ct, double *cz) {
  double rcp;
  static double dtor = 1.74532925199432958e-2;
  rcp = dtor * pp;
  *cr = pr * sin(rcp);
  *ct = pe;
  *cz = pr * cos(rcp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qualityPoints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x59,-0x4(%rbp)
  jle    L51
  mov    $0x4,%eax
  jmp    L69
L51:
  cmpl   $0x4f,-0x4(%rbp)
  jle    L39
  mov    $0x3,%eax
  jmp    L69
L39:
  cmpl   $0x45,-0x4(%rbp)
  jle    L16
  mov    $0x2,%eax
  jmp    L69
L16:
  cmpl   $0x3b,-0x4(%rbp)
  jle    L38
  mov    $0x1,%eax
  jmp    L69
L38:
  mov    $0x0,%eax
L69:
  pop    %rbp
  ret
```

assistant: ```c
int qualityPoints(int n) {
  if (n >= 90)
    return 4;
  else if (n >= 80)
    return 3;
  else if (n >= 70)
    return 2;
  else if (n >= 60)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<qualityPoints>:
  endbr64
  mov    $0x4,%eax
  cmp    $0x59,%edi
  jg     L22
  mov    $0x3,%eax
  cmp    $0x4f,%edi
  jg     L22
  mov    $0x2,%eax
  cmp    $0x45,%edi
  jg     L22
  cmp    $0x3b,%edi
  setg   %al
  movzbl %al,%eax
L22:
  ret
```

assistant: ```c
int qualityPoints(int n) {
  if (n >= 90)
    return 4;
  else if (n >= 80)
    return 3;
  else if (n >= 70)
    return 2;
  else if (n >= 60)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qualityPoints>:
  endbr64
  mov    $0x4,%eax
  cmp    $0x59,%edi
  jg     L13
  mov    $0x3,%eax
  cmp    $0x4f,%edi
  jg     L13
  mov    $0x2,%eax
  cmp    $0x45,%edi
  jg     L13
  xor    %eax,%eax
  cmp    $0x3b,%edi
  setg   %al
L13:
  ret
```

assistant: ```c
int qualityPoints(int n) {
  if (n >= 90)
    return 4;
  else if (n >= 80)
    return 3;
  else if (n >= 70)
    return 2;
  else if (n >= 60)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qualityPoints>:
  endbr64
  mov    $0x4,%eax
  cmp    $0x59,%edi
  jg     L24
  mov    $0x3,%eax
  cmp    $0x4f,%edi
  jg     L24
  mov    $0x2,%eax
  cmp    $0x45,%edi
  jg     L24
  xor    %eax,%eax
  cmp    $0x3b,%edi
  setg   %al
L24:
  ret
```

assistant: ```c
int qualityPoints(int n) {
  if (n >= 90)
    return 4;
  else if (n >= 80)
    return 3;
  else if (n >= 70)
    return 2;
  else if (n >= 60)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PKCS12_get_friendlyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <PKCS12_get_attr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L10
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L14
  mov    $0x0,%eax
  jmp    L10
L14:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    0x4(%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <OPENSSL_uni2asc@plt>
L10:
  leave
  ret
```

assistant: ```c
char *PKCS12_get_friendlyname(PKCS12_SAFEBAG *bag) {
  ASN1_TYPE *atype;
  if (!(atype = PKCS12_get_attr(bag, NID_friendlyName)))
    return NULL;
  if (atype->type != V_ASN1_BMPSTRING)
    return NULL;
  return OPENSSL_uni2asc(atype->value.bmpstring->data, atype->value.bmpstring->length);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PKCS12_get_friendlyname>:
  endbr64
  sub    $0x8,%rsp
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <PKCS12_get_attr@plt>
  test   %rax,%rax
  je     L6
  mov    D8(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,(%rax)
  jne    L27
  mov    0x8(%rax),%rax
  mov    0x4(%rax),%edi
  mov    (%rax),%esi
  call   <OPENSSL_uni2asc@plt>
L6:
  add    $0x8,%rsp
  ret
L27:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
char *PKCS12_get_friendlyname(PKCS12_SAFEBAG *bag) {
  ASN1_TYPE *atype;
  if (!(atype = PKCS12_get_attr(bag, NID_friendlyName)))
    return NULL;
  if (atype->type != V_ASN1_BMPSTRING)
    return NULL;
  return OPENSSL_uni2asc(atype->value.bmpstring->data, atype->value.bmpstring->length);
}
```