ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dobldobl_Newton_power_series>:
  endbr64
  sub    $0x38,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  xor    %r8d,%r8d
  mov    %ecx,0xc(%rsp)
  punpckldq %xmm1,%xmm0
  xor    %ecx,%ecx
  lea    0x18(%rsp),%rsi
  mov    $0x2b7,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edx,0x20(%rsp)
  lea    0xc(%rsp),%rdx
  movq   %xmm0,0x18(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobldobl_Newton_power_series(int idx, int maxdeg, int nbr, int verbose) {
  int fail = 0;
  int idxnbr[3];
  double *c;
  idxnbr[0] = idx;
  idxnbr[1] = maxdeg;
  idxnbr[2] = nbr;
  fail = _ada_use_c2phc4c(695, idxnbr, &verbose, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rdrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: RDRAND is not supported.

assistant: ```c
int rdrand() {
  printf("RDRAND is not supported.");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rdrand>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: RDRAND is not supported.

assistant: ```c
int rdrand() {
  printf("RDRAND is not supported.");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rdrand>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: RDRAND is not supported.

assistant: ```c
int rdrand() {
  printf("RDRAND is not supported.");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rdrand>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: RDRAND is not supported.

assistant: ```c
int rdrand() {
  printf("RDRAND is not supported.");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L14
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L27
L14:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L27
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L27:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double ceil(double d) {
  int c = (int)d;
  if (d > 0)
    d = (double)(c + 1);
  else if (d < 0)
    d = (double)c;
  return (d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ceil>:
  endbr64
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  comisd %xmm1,%xmm0
  jbe    L10
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L10:
  comisd %xmm0,%xmm1
  ja     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double ceil(double d) {
  int c = (int)d;
  if (d > 0)
    d = (double)(c + 1);
  else if (d < 0)
    d = (double)c;
  return (d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ceil>:
  endbr64
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%eax
  comisd %xmm1,%xmm0
  jbe    L19
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L19:
  comisd %xmm0,%xmm1
  ja     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double ceil(double d) {
  int c = (int)d;
  if (d > 0)
    d = (double)(c + 1);
  else if (d < 0)
    d = (double)c;
  return (d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<analize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc40,%rsp
  mov    %edi,-0xc24(%rbp)
  mov    %esi,-0xc28(%rbp)
  mov    %edx,-0xc2c(%rbp)
  mov    %rcx,-0xc38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc14(%rbp)
  jmp    L42
L36:
  mov    -0xc14(%rbp),%eax
  cltq
  movl   $0x0,-0xc10(%rbp,%rax,4)
  addl   $0x1,-0xc14(%rbp)
L42:
  cmpl   $0xff,-0xc14(%rbp)
  jle    L36
  mov    -0xc24(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x810(%rbp)
  mov    -0xc24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc14(%rbp)
  jmp    L63
L64:
  mov    -0xc14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc10(%rbp,%rax,4),%edx
  add    $0x1,%edx
  mov    %edx,-0xc10(%rbp,%rax,4)
  addl   $0x3,-0xc14(%rbp)
L63:
  mov    -0xc14(%rbp),%eax
  cmp    -0xc2c(%rbp),%eax
  jl     L64
  movl   $0x0,-0xc14(%rbp)
  jmp    L41
L55:
  mov    -0xc14(%rbp),%eax
  cltq
  mov    -0xc10(%rbp,%rax,4),%eax
  mov    -0xc14(%rbp),%edx
  lea    0x1(%rdx),%ecx
  movslq %eax,%rdx
  movslq %ecx,%rax
  mov    %rdx,-0x810(%rbp,%rax,8)
  addl   $0x1,-0xc14(%rbp)
L41:
  cmpl   $0xff,-0xc14(%rbp)
  jle    L55
  lea    -0x810(%rbp),%rcx
  mov    -0xc28(%rbp),%eax
  mov    $0x101,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int analize(int channel, int parentfd, int lenght, u_char buff[]) {
  int i;
  int count[256];
  u_char str[257];
  for (i = 0; i < 256; i++) {
    count[i] = 0;
  }
  str[0] = channel - 1;
  for (i = channel - 1; i < lenght; i += 3) {
    count[buff[i]]++;
  }
  for (i = 0; i < 256; i++) {
    str[i + 1] = (u_char)count[i];
  }
  write(parentfd, str, 257);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<analize>:
  endbr64
  sub    $0xc18,%rsp
  mov    %edi,%r8d
  mov    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x400(%rsp),%rsi
L28:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L28
  lea    -0x1(%r8),%esi
  movslq %esi,%rax
  mov    %rax,0x400(%rsp)
  cmp    %edx,%esi
  jge    L0
L32:
  mov    (%rcx,%rax,8),%rsi
  addl   $0x1,(%rsp,%rsi,4)
  add    $0x3,%rax
  cmp    %eax,%edx
  jg     L32
L0:
  mov    $0x0,%eax
L9:
  movslq (%rsp,%rax,4),%rdx
  mov    %rdx,0x408(%rsp,%rax,8)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L9
  lea    0x400(%rsp),%rsi
  mov    $0x101,%edx
  call   <write@plt>
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0xc18,%rsp
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int analize(int channel, int parentfd, int lenght, u_char buff[]) {
  int i;
  int count[256];
  u_char str[257];
  for (i = 0; i < 256; i++) {
    count[i] = 0;
  }
  str[0] = channel - 1;
  for (i = channel - 1; i < lenght; i += 3) {
    count[buff[i]]++;
  }
  for (i = 0; i < 256; i++) {
    str[i + 1] = (u_char)count[i];
  }
  write(parentfd, str, 257);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<analize>:
  endbr64
  sub    $0xc18,%rsp
  mov    %edi,%r11d
  mov    %esi,%r10d
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %rcx,%r9
  lea    -0x1(%r11),%edx
  mov    $0x80,%ecx
  mov    %rsi,%rdi
  rep stos %rax,%es:(%rdi)
  movslq %edx,%rax
  mov    %rax,0x400(%rsp)
  cmp    %r8d,%edx
  jge    L0
  nopl   0x0(%rax)
L20:
  mov    (%r9,%rax,8),%rdx
  add    $0x3,%rax
  addl   $0x1,(%rsp,%rdx,4)
  cmp    %eax,%r8d
  jg     L20
L0:
  xor    %eax,%eax
  lea    0x400(%rsp),%r8
  nopl   0x0(%rax,%rax,1)
L8:
  movslq (%rsi,%rax,4),%rdx
  mov    %rdx,0x8(%r8,%rax,8)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L8
  mov    $0x101,%edx
  mov    %r8,%rsi
  mov    %r10d,%edi
  call   <write@plt>
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0xc18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int analize(int channel, int parentfd, int lenght, u_char buff[]) {
  int i;
  int count[256];
  u_char str[257];
  for (i = 0; i < 256; i++) {
    count[i] = 0;
  }
  str[0] = channel - 1;
  for (i = channel - 1; i < lenght; i += 3) {
    count[buff[i]]++;
  }
  for (i = 0; i < 256; i++) {
    str[i + 1] = (u_char)count[i];
  }
  write(parentfd, str, 257);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<analize>:
  endbr64
  sub    $0xc18,%rsp
  mov    %esi,%r9d
  mov    %edx,%esi
  mov    %edi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %rcx,%r8
  mov    $0x80,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x1(%r10),%ecx
  movslq %ecx,%rax
  mov    %rax,0x400(%rsp)
  cmp    %esi,%ecx
  jge    L1
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%r8,%rax,8),%rcx
  add    $0x3,%rax
  addl   $0x1,(%rsp,%rcx,4)
  cmp    %eax,%esi
  jg     L20
L1:
  mov    %rdx,%rdi
  lea    0x408(%rsp),%rax
  pxor   %xmm3,%xmm3
  lea    0xc08(%rsp),%rdx
  nopw   0x0(%rax,%rax,1)
L3:
  movdqa (%rdi),%xmm0
  movdqa %xmm3,%xmm1
  add    $0x20,%rax
  add    $0x10,%rdi
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckldq %xmm1,%xmm2
  punpckhdq %xmm1,%xmm0
  movups %xmm2,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L3
  lea    0x400(%rsp),%rsi
  mov    $0x101,%edx
  mov    %r9d,%edi
  call   <write@plt>
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0xc18,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int analize(int channel, int parentfd, int lenght, u_char buff[]) {
  int i;
  int count[256];
  u_char str[257];
  for (i = 0; i < 256; i++) {
    count[i] = 0;
  }
  str[0] = channel - 1;
  for (i = channel - 1; i < lenght; i += 3) {
    count[buff[i]]++;
  }
  for (i = 0; i < 256; i++) {
    str[i + 1] = (u_char)count[i];
  }
  write(parentfd, str, 257);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setPlaymode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  push   $0x0
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
  jmp    L2
L17:
  cmpl   $0x1,-0x4(%rbp)
  jne    L12
  push   $0x4
  push   $0x10
  mov    $0x0,%r9d
  mov    $0x12,%r8d
  mov    $0x14,%ecx
  mov    $0x5,%edx
  mov    $0xe,%esi
  mov    $0x1,%edi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
  jmp    L2
L12:
  push   $0x0
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
L2:
  nop
  leave
  ret
```

assistant: ```c
void setPlaymode(int newmode) {
  if (newmode == 0) {
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
  } else if (newmode == 1) {
    setPlaymodeArgs(1, 14, 5, 20, 18, 0, 16, 4);
  } else
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setPlaymode>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L7
  cmp    $0x1,%edi
  je     L3
  push   $0x0
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
L19:
  add    $0x8,%rsp
  ret
L7:
  push   $0x0
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
  jmp    L19
L3:
  push   $0x4
  push   $0x10
  mov    $0x0,%r9d
  mov    $0x12,%r8d
  mov    $0x14,%ecx
  mov    $0x5,%edx
  mov    $0xe,%esi
  call   <setPlaymodeArgs@plt>
  add    $0x10,%rsp
  jmp    L19
```

assistant: ```c
void setPlaymode(int newmode) {
  if (newmode == 0) {
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
  } else if (newmode == 1) {
    setPlaymodeArgs(1, 14, 5, 20, 18, 0, 16, 4);
  } else
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<setPlaymode>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L6
  push   $0x4
  mov    $0x5,%edx
  xor    %r9d,%r9d
  mov    $0x12,%r8d
  push   $0x10
  mov    $0x14,%ecx
  mov    $0xe,%esi
  mov    $0x1,%edi
  call   <setPlaymodeArgs@plt>
  pop    %rax
  pop    %rdx
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  push   $0x0
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %r9d,%r9d
  push   $0x0
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %edi,%edi
  call   <setPlaymodeArgs@plt>
  pop    %rcx
  pop    %rsi
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setPlaymode(int newmode) {
  if (newmode == 0) {
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
  } else if (newmode == 1) {
    setPlaymodeArgs(1, 14, 5, 20, 18, 0, 16, 4);
  } else
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setPlaymode>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L4
  push   $0x4
  mov    $0x5,%edx
  xor    %r9d,%r9d
  mov    $0x12,%r8d
  push   $0x10
  mov    $0x14,%ecx
  mov    $0xe,%esi
  mov    $0x1,%edi
  call   <setPlaymodeArgs@plt>
  pop    %rax
  pop    %rdx
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  push   $0x0
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %r9d,%r9d
  push   $0x0
  xor    %r8d,%r8d
  xor    %edx,%edx
  xor    %edi,%edi
  call   <setPlaymodeArgs@plt>
  pop    %rcx
  pop    %rsi
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setPlaymode(int newmode) {
  if (newmode == 0) {
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
  } else if (newmode == 1) {
    setPlaymodeArgs(1, 14, 5, 20, 18, 0, 16, 4);
  } else
    setPlaymodeArgs(0, 0, 0, 0, 0, 0, 0, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L4:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  char *r = dst;
  while ((*dst++ = *src++))
    ;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  char *r = dst;
  while ((*dst++ = *src++))
    ;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L7:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  char *r = dst;
  while ((*dst++ = *src++))
    ;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L3
  ret
```

assistant: ```c
char *strcpy(char *dst, const char *src) {
  char *r = dst;
  while ((*dst++ = *src++))
    ;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<asn1_get_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jg     L45
  mov    $0xffffffec,%eax
  jmp    L19
L45:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L37
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L159
L37:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  cmp    $0x1,%eax
  je     L158
  cmp    $0x2,%eax
  je     L145
  jmp    L55
L158:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jg     L79
  mov    $0xffffffec,%eax
  jmp    L19
L79:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L159
L145:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  cmp    $0x2,%rax
  jg     L95
  mov    $0xffffffec,%eax
  jmp    L19
L95:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L159
L55:
  mov    $0xffffffe8,%eax
  jmp    L19
L159:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  sub    %rcx,%rax
  cmp    %eax,%edx
  jle    L60
  mov    $0xffffffec,%eax
  jmp    L19
L60:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int asn1_get_len(unsigned char **p, unsigned char *end, int *len) {
  if ((end - *p) < 1)
    return (-0x0014);
  if ((**p & 0x80) == 0)
    *len = *(*p)++;
  else {
    switch (**p & 0x7F) {
    case 1:
      if ((end - *p) < 2)
        return (-0x0014);
      *len = (*p)[1];
      (*p) += 2;
      break;
    case 2:
      if ((end - *p) < 3)
        return (-0x0014);
      *len = ((*p)[1] << 8) | (*p)[2];
      (*p) += 3;
      break;
    default:
      return (-0x0018);
      break;
    }
  }
  if (*len > (int)(end - *p))
    return (-0x0014);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<asn1_get_len>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  mov    (%rdi),%rcx
  mov    %rsi,%rdi
  sub    %rcx,%rdi
  test   %rdi,%rdi
  jle    L6
  movzbl (%rcx),%esi
  test   %sil,%sil
  js     L2
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%r8)
  movzbl (%rcx),%ecx
  mov    %ecx,(%rdx)
L51:
  sub    (%r8),%rax
  cmp    %eax,(%rdx)
  mov    $0x0,%eax
  mov    $0xffffffec,%edx
  cmovg  %edx,%eax
  ret
L2:
  and    $0x7f,%esi
  cmp    $0x1,%sil
  je     L45
  cmp    $0x2,%sil
  je     L18
  mov    $0xffffffe8,%eax
  ret
L45:
  cmp    $0x1,%rdi
  jle    L37
  movzbl 0x1(%rcx),%ecx
  mov    %ecx,(%rdx)
  addq   $0x2,(%r8)
  jmp    L51
L18:
  cmp    $0x2,%rdi
  jle    L12
  movzbl 0x1(%rcx),%esi
  shl    $0x8,%esi
  movzbl 0x2(%rcx),%ecx
  or     %esi,%ecx
  mov    %ecx,(%rdx)
  addq   $0x3,(%r8)
  jmp    L51
L6:
  mov    $0xffffffec,%eax
  ret
L37:
  mov    $0xffffffec,%eax
  ret
L12:
  mov    $0xffffffec,%eax
  ret
```

assistant: ```c
int asn1_get_len(unsigned char **p, unsigned char *end, int *len) {
  if ((end - *p) < 1)
    return (-0x0014);
  if ((**p & 0x80) == 0)
    *len = *(*p)++;
  else {
    switch (**p & 0x7F) {
    case 1:
      if ((end - *p) < 2)
        return (-0x0014);
      *len = (*p)[1];
      (*p) += 2;
      break;
    case 2:
      if ((end - *p) < 3)
        return (-0x0014);
      *len = ((*p)[1] << 8) | (*p)[2];
      (*p) += 3;
      break;
    default:
      return (-0x0018);
      break;
    }
  }
  if (*len > (int)(end - *p))
    return (-0x0014);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<asn1_get_len>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%r8
  sub    %rax,%r8
  test   %r8,%r8
  jle    L7
  movzbl (%rax),%ecx
  test   %cl,%cl
  js     L22
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl (%rax),%ecx
  mov    %ecx,(%rdx)
L66:
  sub    %r8,%rsi
  cmp    %esi,%ecx
  jg     L7
  xor    %eax,%eax
  ret
  nop
L22:
  and    $0x7f,%ecx
  cmp    $0x1,%cl
  je     L45
  cmp    $0x2,%cl
  jne    L73
  cmp    $0x2,%r8
  jle    L7
  movzwl 0x1(%rax),%ecx
  lea    0x3(%rax),%r8
  rol    $0x8,%cx
  movzwl %cx,%ecx
  mov    %ecx,(%rdx)
  mov    %r8,(%rdi)
  jmp    L66
  nopl   0x0(%rax)
L73:
  mov    $0xffffffe8,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  cmp    $0x1,%r8
  je     L7
  movzbl 0x1(%rax),%ecx
  lea    0x2(%rax),%r8
  mov    %ecx,(%rdx)
  mov    %r8,(%rdi)
  jmp    L66
  nopl   (%rax)
L7:
  mov    $0xffffffec,%eax
  ret
```

assistant: ```c
int asn1_get_len(unsigned char **p, unsigned char *end, int *len) {
  if ((end - *p) < 1)
    return (-0x0014);
  if ((**p & 0x80) == 0)
    *len = *(*p)++;
  else {
    switch (**p & 0x7F) {
    case 1:
      if ((end - *p) < 2)
        return (-0x0014);
      *len = (*p)[1];
      (*p) += 2;
      break;
    case 2:
      if ((end - *p) < 3)
        return (-0x0014);
      *len = ((*p)[1] << 8) | (*p)[2];
      (*p) += 3;
      break;
    default:
      return (-0x0018);
      break;
    }
  }
  if (*len > (int)(end - *p))
    return (-0x0014);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asn1_get_len>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%r8
  sub    %rax,%r8
  test   %r8,%r8
  jle    L56
  movzbl (%rax),%ecx
  test   %cl,%cl
  js     L31
  lea    0x1(%rax),%r8
  mov    %r8,(%rdi)
  movzbl (%rax),%ecx
  mov    %ecx,(%rdx)
L62:
  sub    %r8,%rsi
  cmp    %esi,%ecx
  jg     L56
  xor    %eax,%eax
  ret
  nop
L31:
  and    $0x7f,%ecx
  cmp    $0x1,%cl
  je     L74
  cmp    $0x2,%cl
  jne    L22
  cmp    $0x2,%r8
  jle    L56
  movzwl 0x1(%rax),%ecx
  lea    0x3(%rax),%r8
  rol    $0x8,%cx
  movzwl %cx,%ecx
  mov    %ecx,(%rdx)
  mov    %r8,(%rdi)
  jmp    L62
  nopl   0x0(%rax)
L22:
  mov    $0xffffffe8,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L74:
  cmp    $0x1,%r8
  je     L56
  movzbl 0x1(%rax),%ecx
  lea    0x2(%rax),%r8
  mov    %ecx,(%rdx)
  mov    %r8,(%rdi)
  jmp    L62
  nopl   (%rax)
L56:
  mov    $0xffffffec,%eax
  ret
```

assistant: ```c
int asn1_get_len(unsigned char **p, unsigned char *end, int *len) {
  if ((end - *p) < 1)
    return (-0x0014);
  if ((**p & 0x80) == 0)
    *len = *(*p)++;
  else {
    switch (**p & 0x7F) {
    case 1:
      if ((end - *p) < 2)
        return (-0x0014);
      *len = (*p)[1];
      (*p) += 2;
      break;
    case 2:
      if ((end - *p) < 3)
        return (-0x0014);
      *len = ((*p)[1] << 8) | (*p)[2];
      (*p) += 3;
      break;
    default:
      return (-0x0018);
      break;
    }
  }
  if (*len > (int)(end - *p))
    return (-0x0014);
  return (0);
}
```