ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_expr_end>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  lea    D2(%rip),%rdi
  call   <dbgprintf@plt>
  xor    %eax,%eax
  cmpb   $0x27,(%r12)
  sete   %al
  add    %rax,%r12
  mov    %r12,%rdi
  call   <skip_space@plt>
  movsbl (%rax),%edi
  mov    %rax,%r12
  cmp    $0x28,%dil
  jne    L43
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L27:
  test   %al,%al
  je     L23
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
L43:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L23
  movzbl (%r12),%eax
  lea    -0x28(%rax),%edx
  cmp    $0x1,%dl
  ja     L27
L23:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %rax,%rdi
  call   <find_matching_parenthesis@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  cmpb   $0x29,(%r12)
  sete   %al
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: find_expr_end: %s


assistant: ```c
char *find_expr_end(const char *e) {
  dbgprintf("find_expr_end: %s\n", e);
  if (*e == '\'')
    ++e;
  e = skip_space(e);
  if (*e == '(') {
    e = find_matching_parenthesis(e);
    return (char *)(*e == ')' ? e + 1 : e);
  } else {
    while (!isspace(*e) && *e != '(' && *e != ')' && *e != '\0')
      ++e;
    return (char *)e;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_expr_end>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  lea    D4(%rip),%rdi
  call   <dbgprintf@plt>
  xor    %eax,%eax
  cmpb   $0x27,(%r12)
  sete   %al
  add    %rax,%r12
  mov    %r12,%rdi
  call   <skip_space@plt>
  cmpb   $0x28,(%rax)
  mov    %rax,%r12
  jne    L28
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L13:
  test   %al,%al
  je     L5
  add    $0x1,%r12
L28:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L5
  movzbl (%r12),%eax
  lea    -0x28(%rax),%edx
  cmp    $0x1,%dl
  ja     L13
L5:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    %rax,%rdi
  call   <find_matching_parenthesis@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  cmpb   $0x29,(%r12)
  sete   %al
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D4: find_expr_end: %s


assistant: ```c
char *find_expr_end(const char *e) {
  dbgprintf("find_expr_end: %s\n", e);
  if (*e == '\'')
    ++e;
  e = skip_space(e);
  if (*e == '(') {
    e = find_matching_parenthesis(e);
    return (char *)(*e == ')' ? e + 1 : e);
  } else {
    while (!isspace(*e) && *e != '(' && *e != ')' && *e != '\0')
      ++e;
    return (char *)e;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_ansi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L7:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L26
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0xd(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L26:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ansi_apply@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
L16:
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L45
L48:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  jmp    L2
L45:
  nop
L2:
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int parse_ansi(const char *text, int *ansi_state) {
  int next_state = *ansi_state;
  int code = 0;
  int len = 0;
  while (text[len]) {
    char c = text[len++];
    if (isdigit(c)) {
      code = code * 10 + c - '0';
    } else {
      next_state = ansi_apply(next_state, code);
      code = 0;
    }
    if (isalpha(c))
      break;
  }
  *ansi_state = next_state;
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_ansi>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    (%rsi),%r14d
  mov    %rdi,%rbp
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%r15d
  jmp    L28
L17:
  lea    (%r12,%r12,4),%eax
  lea    -0x30(%rbx,%rax,2),%r12d
L48:
  mov    %ebx,%edi
  call   <isalpha@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L47
L28:
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L47
  add    $0x1,%r13d
  movsbl %bl,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <ansi_apply@plt>
  mov    %eax,%r14d
  mov    %r15d,%r12d
  jmp    L48
L47:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int parse_ansi(const char *text, int *ansi_state) {
  int next_state = *ansi_state;
  int code = 0;
  int len = 0;
  while (text[len]) {
    char c = text[len++];
    if (isdigit(c)) {
      code = code * 10 + c - '0';
    } else {
      next_state = ansi_apply(next_state, code);
      code = 0;
    }
    if (isalpha(c))
      break;
  }
  *ansi_state = next_state;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_ansi>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%r14d
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L44:
  lea    (%r12,%r12,4),%eax
  mov    %ebp,%edi
  add    $0x1,%rbx
  lea    -0x30(%rbp,%rax,2),%r12d
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L5
L10:
  movsbl (%rbx),%ebp
  test   %bpl,%bpl
  je     L5
  mov    %ebp,%edi
  add    $0x1,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L44
  mov    %r12d,%esi
  mov    %r14d,%edi
  xor    %r12d,%r12d
  add    $0x1,%rbx
  call   <ansi_apply@plt>
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <isalpha@plt>
  test   %rax,%rax
  je     L10
L5:
  mov    %r14d,(%r15)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int parse_ansi(const char *text, int *ansi_state) {
  int next_state = *ansi_state;
  int code = 0;
  int len = 0;
  while (text[len]) {
    char c = text[len++];
    if (isdigit(c)) {
      code = code * 10 + c - '0';
    } else {
      next_state = ansi_apply(next_state, code);
      code = 0;
    }
    if (isalpha(c))
      break;
  }
  *ansi_state = next_state;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_ansi>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%r14d
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%ebp
  test   %bpl,%bpl
  je     L14
  mov    %ebp,%edi
  add    $0x1,%r13d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L36
  lea    (%r12,%r12,4),%eax
  mov    %ebp,%edi
  add    $0x1,%rbx
  lea    -0x30(%rbp,%rax,2),%r12d
  call   <isalpha@plt>
  test   %rax,%rax
  je     L16
L14:
  mov    %r14d,(%r15)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L36:
  mov    %r14d,%edi
  mov    %r12d,%esi
  add    $0x1,%rbx
  call   <ansi_apply@plt>
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L14
  xor    %r12d,%r12d
  jmp    L16
```

assistant: ```c
int parse_ansi(const char *text, int *ansi_state) {
  int next_state = *ansi_state;
  int code = 0;
  int len = 0;
  while (text[len]) {
    char c = text[len++];
    if (isdigit(c)) {
      code = code * 10 + c - '0';
    } else {
      next_state = ansi_apply(next_state, code);
      code = 0;
    }
    if (isalpha(c))
      break;
  }
  *ansi_state = next_state;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<computeLempelZivFact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <emalloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  movq   $0x0,-0x20(%rbp)
  jmp    L0
L6:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <maximum@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    %rbx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x30(%rbp)
  jg     L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long computeLempelZivFact(long *lpf, long n) {
  long *lz, i;
  lz = (long *)emalloc(n * sizeof(long));
  lz[0] = 0;
  i = 0;
  while (lz[i] < n) {
    lz[i + 1] = lz[i] + maximum(1, lpf[lz[i]] + 1);
    i++;
  }
  free(lz);
  free(lpf);
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<computeLempelZivFact>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  lea    0x0(,%rsi,8),%rdi
  call   <emalloc@plt>
  mov    %rax,%r15
  movq   $0x0,(%rax)
  test   %r13,%r13
  jle    L17
  lea    0x8(%rax),%rbp
  mov    $0x0,%r12d
  mov    $0x0,%ebx
L14:
  mov    (%r14,%rbx,8),%rax
  lea    0x1(%rax),%rsi
  mov    $0x1,%edi
  call   <maximum@plt>
  add    %rax,%rbx
  mov    %rbx,0x0(%rbp)
  add    $0x1,%r12
  add    $0x8,%rbp
  cmp    %r13,%rbx
  jl     L14
L16:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%r12d
  jmp    L16
```

assistant: ```c
long computeLempelZivFact(long *lpf, long n) {
  long *lz, i;
  lz = (long *)emalloc(n * sizeof(long));
  lz[0] = 0;
  i = 0;
  while (lz[i] < n) {
    lz[i + 1] = lz[i] + maximum(1, lpf[lz[i]] + 1);
    i++;
  }
  free(lz);
  free(lpf);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computeLempelZivFact>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%rsi,8),%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <emalloc@plt>
  movq   $0x0,(%rax)
  mov    %rax,%r14
  test   %rbp,%rbp
  jle    L12
  lea    0x8(%rax),%r15
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  nopl   (%rax)
L27:
  mov    0x0(%r13,%rbx,8),%rax
  mov    $0x1,%edi
  add    $0x1,%r12
  add    $0x8,%r15
  lea    0x1(%rax),%rsi
  call   <maximum@plt>
  add    %rax,%rbx
  mov    %rbx,-0x8(%r15)
  cmp    %rbp,%rbx
  jl     L27
L6:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  jmp    L6
```

assistant: ```c
long computeLempelZivFact(long *lpf, long n) {
  long *lz, i;
  lz = (long *)emalloc(n * sizeof(long));
  lz[0] = 0;
  i = 0;
  while (lz[i] < n) {
    lz[i + 1] = lz[i] + maximum(1, lpf[lz[i]] + 1);
    i++;
  }
  free(lz);
  free(lpf);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeLempelZivFact>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%rsi,8),%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <emalloc@plt>
  movq   $0x0,(%rax)
  mov    %rax,%r14
  test   %rbp,%rbp
  jle    L12
  lea    0x8(%rax),%r15
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  nopl   (%rax)
L18:
  mov    0x0(%r13,%rbx,8),%rax
  mov    $0x1,%edi
  add    $0x1,%r12
  add    $0x8,%r15
  lea    0x1(%rax),%rsi
  call   <maximum@plt>
  add    %rax,%rbx
  mov    %rbx,-0x8(%r15)
  cmp    %rbp,%rbx
  jl     L18
L20:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  jmp    L20
```

assistant: ```c
long computeLempelZivFact(long *lpf, long n) {
  long *lz, i;
  lz = (long *)emalloc(n * sizeof(long));
  lz[0] = 0;
  i = 0;
  while (lz[i] < n) {
    lz[i + 1] = lz[i] + maximum(1, lpf[lz[i]] + 1);
    i++;
  }
  free(lz);
  free(lpf);
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D6
datatype: string

tool: D16: Testing copy()


tool: D6: Done!



assistant: ```c
int test_copy(const char *from, const char *to) {
  printf("Testing copy()\n");
  copy(from, to);
  printf("Done!\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <copy@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D13: Testing copy()


tool: D18: Done!



assistant: ```c
int test_copy(const char *from, const char *to) {
  printf("Testing copy()\n");
  copy(from, to);
  printf("Done!\n\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string

tool: D3: Testing copy()


tool: D13: Done!



assistant: ```c
int test_copy(const char *from, const char *to) {
  printf("Testing copy()\n");
  copy(from, to);
  printf("Done!\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <copy@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D18: Testing copy()


tool: D8: Done!



assistant: ```c
int test_copy(const char *from, const char *to) {
  printf("Testing copy()\n");
  copy(from, to);
  printf("Done!\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<totalNQueens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x1c(%rbp)
L29:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <dfs@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int totalNQueens(int n) {
  int *sol = (int *)malloc(sizeof(int) * n);
  int *nums = (int *)malloc(sizeof(int) * n);
  int ret = 0;
  for (int i = 0; i < n; i++) {
    nums[i] = 1;
  }
  dfs(n, sol, nums, &ret, 0);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<totalNQueens>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x0(,%rdi,4),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  movl   $0x0,0x4(%rsp)
  test   %ebx,%ebx
  jle    L8
  mov    %rax,%rcx
  mov    %ebx,%eax
  lea    (%rdx,%rax,4),%rsi
L2:
  movl   $0x1,(%rcx)
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L2
L8:
  lea    0x4(%rsp),%rcx
  mov    $0x0,%r8d
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int totalNQueens(int n) {
  int *sol = (int *)malloc(sizeof(int) * n);
  int *nums = (int *)malloc(sizeof(int) * n);
  int ret = 0;
  for (int i = 0; i < n; i++) {
    nums[i] = 1;
  }
  dfs(n, sol, nums, &ret, 0);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<totalNQueens>:
  endbr64
  push   %r13
  lea    0x0(,%rdi,4),%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rdx
  test   %ebp,%ebp
  jle    L28
  mov    %rax,%rcx
  mov    %ebp,%eax
  lea    (%rdx,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L4:
  movl   $0x1,(%rcx)
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L4
L28:
  lea    0x4(%rsp),%rcx
  xor    %r8d,%r8d
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int totalNQueens(int n) {
  int *sol = (int *)malloc(sizeof(int) * n);
  int *nums = (int *)malloc(sizeof(int) * n);
  int ret = 0;
  for (int i = 0; i < n; i++) {
    nums[i] = 1;
  }
  dfs(n, sol, nums, &ret, 0);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<totalNQueens>:
  endbr64
  push   %r13
  lea    0x0(,%rdi,4),%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movl   $0x0,0x4(%rsp)
  mov    %rax,%r9
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L25
  mov    %ebp,%edx
  movdqa D1(%rip),%xmm0
  mov    %r9,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r9,%rdx
  nopl   0x0(%rax)
L79:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L79
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bpl
  je     L10
L55:
  movslq %eax,%rdx
  movl   $0x1,(%r9,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L10
  movl   $0x1,0x4(%r9,%rcx,1)
  add    $0x2,%eax
  cmp    %eax,%ebp
  jle    L10
  movl   $0x1,0x8(%r9,%rcx,1)
L10:
  lea    0x4(%rsp),%rcx
  xor    %r8d,%r8d
  mov    %r9,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <dfs@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  xor    %eax,%eax
  jmp    L55
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: byte[16]

tool: {"D1": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int totalNQueens(int n) {
  int *sol = (int *)malloc(sizeof(int) * n);
  int *nums = (int *)malloc(sizeof(int) * n);
  int ret = 0;
  for (int i = 0; i < n; i++) {
    nums[i] = 1;
  }
  dfs(n, sol, nums, &ret, 0);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L27
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L27:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_max(int *pancakes, int left, int right) {
  int index = left;
  int max = pancakes[index];
  for (int i = left + 1; i <= right; i++) {
    if (pancakes[i] > max) {
      max = pancakes[i];
      index = i;
    }
  }
  return index;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_max>:
  endbr64
  mov    %esi,%eax
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%r9d
  lea    0x1(%rsi),%ecx
  cmp    %edx,%ecx
  jg     L39
  movslq %ecx,%rcx
  jmp    L7
L6:
  add    $0x1,%rcx
  cmp    %ecx,%edx
  jl     L39
L7:
  mov    (%rdi,%rcx,4),%r8d
  cmp    %r9d,%r8d
  jle    L6
  mov    %r8d,%r9d
  mov    %ecx,%eax
  jmp    L6
L39:
  ret
```

assistant: ```c
int find_max(int *pancakes, int left, int right) {
  int index = left;
  int max = pancakes[index];
  for (int i = left + 1; i <= right; i++) {
    if (pancakes[i] > max) {
      max = pancakes[i];
      index = i;
    }
  }
  return index;
}
```