ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<shiftleft>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  movzwl %dx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%r12
  movzwl (%r12),%ecx
  cmp    %dx,%cx
  jbe    L4
L36:
  test   %r13d,%r13d
  je     L11
  movzbl (%rbx),%esi
  lea    -0x1(%r13),%edi
  mov    %ebp,%ecx
  add    %rbx,%rdi
  shl    %cl,%esi
  mov    %esi,%edx
  cmp    %rdi,%rbx
  je     L22
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl 0x1(%rbx),%esi
  movzwl (%r12),%ecx
  add    $0x1,%rbx
  sub    %ebp,%ecx
  mov    %esi,%eax
  sar    %cl,%eax
  mov    %ebp,%ecx
  or     %eax,%edx
  shl    %cl,%esi
  mov    %dl,-0x1(%rbx)
  mov    %esi,%edx
  cmp    %rdi,%rbx
  jne    L38
L22:
  mov    %sil,(%rbx)
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    %ebp,%eax
  xor    %edx,%edx
  div    %cx
  movzwl %ax,%eax
  sub    %eax,%r13d
  mov    %rax,%rsi
  lea    -0x1(%rcx,%r13,1),%eax
  add    %rdi,%rsi
  cltd
  idiv   %ecx
  mov    %eax,%edx
  call   <memmove@plt>
  mov    %ebp,%eax
  xor    %edx,%edx
  divw   (%r12)
  movzwl %dx,%ebp
  jmp    L36
```

assistant: ```c
void shiftleft(unsigned char *data, int size, unsigned short left) {
  unsigned char *byte;
  if (left >= CHAR_BIT) {
    size -= left / CHAR_BIT;
    memmove(data, data + left / CHAR_BIT, (size + CHAR_BIT - 1) / CHAR_BIT);
    left %= CHAR_BIT;
  }
  for (byte = data; size--; ++byte) {
    unsigned char bits;
    if (size)
      bits = byte[1] >> (CHAR_BIT - left);
    else
      bits = 0;
    *byte <<= left;
    *byte |= bits;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shiftleft>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbx
  movzwl (%rbx),%ecx
  cmp    %dx,%cx
  jbe    L42
L5:
  lea    -0x1(%r12),%eax
  test   %r12d,%r12d
  je     L27
  movzbl 0x0(%rbp),%edx
  mov    %r13d,%ecx
  movzwl %r13w,%edi
  mov    %eax,%r9d
  shl    %cl,%edx
  test   %eax,%eax
  je     L24
  lea    0x0(%rbp,%r9,1),%r8
  mov    %rbp,%rax
  nopl   0x0(%rax)
L9:
  movzbl 0x1(%rax),%esi
  movzwl (%rbx),%ecx
  add    $0x1,%rax
  sub    %edi,%ecx
  mov    %esi,%r10d
  sar    %cl,%r10d
  mov    %edi,%ecx
  or     %r10d,%edx
  shl    %cl,%esi
  mov    %dl,-0x1(%rax)
  mov    %esi,%edx
  cmp    %r8,%rax
  jne    L9
L24:
  mov    %dl,0x0(%rbp,%r9,1)
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L42:
  mov    %edx,%eax
  xor    %edx,%edx
  div    %cx
  movzwl %ax,%eax
  sub    %eax,%r12d
  mov    %rax,%rsi
  lea    -0x1(%rcx,%r12,1),%eax
  add    %rdi,%rsi
  cltd
  idiv   %ecx
  mov    %eax,%edx
  call   <memmove@plt>
  mov    %r13d,%eax
  xor    %edx,%edx
  divw   (%rbx)
  mov    %edx,%r13d
  jmp    L5
```

assistant: ```c
void shiftleft(unsigned char *data, int size, unsigned short left) {
  unsigned char *byte;
  if (left >= CHAR_BIT) {
    size -= left / CHAR_BIT;
    memmove(data, data + left / CHAR_BIT, (size + CHAR_BIT - 1) / CHAR_BIT);
    left %= CHAR_BIT;
  }
  for (byte = data; size--; ++byte) {
    unsigned char bits;
    if (size)
      bits = byte[1] >> (CHAR_BIT - left);
    else
      bits = 0;
    *byte <<= left;
    *byte |= bits;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fix_tri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fix_tri(int *pnV, double *vertex, int *pnF, int *face) {
  (void)pnV, (void)vertex, (void)pnF, (void)face;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fix_tri>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int fix_tri(int *pnV, double *vertex, int *pnF, int *face) {
  (void)pnV, (void)vertex, (void)pnF, (void)face;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fix_tri>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int fix_tri(int *pnV, double *vertex, int *pnF, int *face) {
  (void)pnV, (void)vertex, (void)pnF, (void)face;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fix_tri>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int fix_tri(int *pnV, double *vertex, int *pnF, int *face) {
  (void)pnV, (void)vertex, (void)pnF, (void)face;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <do_swapd@plt>
  mov    $0x0,%eax
  call   <do_step@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_fold(void) {
  do_swapd();
  do_step();
}
```
user: What is the c source code of the assembly code below:

```asm
<do_fold>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <do_swapd@plt>
  mov    $0x0,%eax
  call   <do_step@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void do_fold(void) {
  do_swapd();
  do_step();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_fold>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_swapd@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <do_step@plt>
```

assistant: ```c
void do_fold(void) {
  do_swapd();
  do_step();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_fold>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_swapd@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <do_step@plt>
```

assistant: ```c
void do_fold(void) {
  do_swapd();
  do_step();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0xa,-0x4(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: %i green bottles, hanging on a wall


assistant: ```c
int main() {
  int counter;
  for (counter = 1; counter < 11; counter++) {
    printf("%i green bottles, hanging on a wall\n", counter);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: %i green bottles, hanging on a wall


assistant: ```c
int main() {
  int counter;
  for (counter = 1; counter < 11; counter++) {
    printf("%i green bottles, hanging on a wall\n", counter);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %i green bottles, hanging on a wall


assistant: ```c
int main() {
  int counter;
  for (counter = 1; counter < 11; counter++) {
    printf("%i green bottles, hanging on a wall\n", counter);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %i green bottles, hanging on a wall


assistant: ```c
int main() {
  int counter;
  for (counter = 1; counter < 11; counter++) {
    printf("%i green bottles, hanging on a wall\n", counter);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%eax
  mov    $0xffffffff,%ecx
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  cld
  mov    -0x18(%rbp),%edi
  repnz scas %es:(%rdi),%al
  not    %ecx
  dec    %ecx
  mov    %ecx,%edx
L14:
  mov    -0x18(%rbp),%edi
  mov    %esi,%eax
  mov    %edx,%ecx
  repz cmpsb %es:(%rdi),%ds:(%rsi)
  je     L2
  xchg   %eax,%esi
  inc    %esi
  cmpb   $0x0,-0x1(%eax)
  jne    L14
  xor    %eax,%eax
L2:
  mov    %rax,%rbx
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  register char *__res;
  __asm__("cld\n\t"
          "movl %4,%%edi\n\t"
          "repne\n\t"
          "scasb\n\t"
          "notl %%ecx\n\t"
          "decl %%ecx\n\t"
          "movl %%ecx,%%edx\n"
          "1:\tmovl %4,%%edi\n\t"
          "movl %%esi,%%eax\n\t"
          "movl %%edx,%%ecx\n\t"
          "repe\n\t"
          "cmpsb\n\t"
          "je 2f\n\t"
          "xchgl %%eax,%%esi\n\t"
          "incl %%esi\n\t"
          "cmpb $0,-1(%%eax)\n\t"
          "jne 1b\n\t"
          "xorl %%eax,%%eax\n\t"
          "2:"
          : "=a"(__res)
          : "0"(0), "c"(0xffffffff), "S"(cs), "g"(ct));
  return __res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_height_inches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D15: Please enter Height (y Inches): 

tool: D9: %d

assistant: ```c
int get_height_inches(void) {
  int value = 0.0;
  printf("Please enter Height (y Inches): ");
  scanf("%d", &value);
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_height_inches>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D18
type: string

tool: D1: Please enter Height (y Inches): 

tool: D18: %d

assistant: ```c
int get_height_inches(void) {
  int value = 0.0;
  printf("Please enter Height (y Inches): ");
  scanf("%d", &value);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_height_inches>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
type_infered: string
name: unpack_data
arguments: label: D12
type_infered: string

tool: D14: Please enter Height (y Inches): 

tool: D12: %d

assistant: ```c
int get_height_inches(void) {
  int value = 0.0;
  printf("Please enter Height (y Inches): ");
  scanf("%d", &value);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_height_inches>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string

tool: D9: Please enter Height (y Inches): 

tool: D11: %d

assistant: ```c
int get_height_inches(void) {
  int value = 0.0;
  printf("Please enter Height (y Inches): ");
  scanf("%d", &value);
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x18(%rbp)
  jne    L18
  movsd  -0x20(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L5
L18:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D48(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L5:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D58
datatype: string
name: read_data
arguments: tag: D37
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D48
datatype: string
name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D19
datatype: string

tool: D58: 
	---------------%s----------------



tool: D37: 			SIZE	 TIME_SEC	 gflops
 

tool: D22: 			%d	%f	 %lf	


tool: D48: ---

tool: D46: 			%d	%lf 	%s	


tool: D19: 
	------------------------------------------------------------------------------------------------

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t------------------------------------------------------------------------------------------------");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L5
  lea    D34(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L14:
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D31(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D54
type: string
name: disassemble_data
arguments: tag: D35
type: string
name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D43
type: string
name: disassemble_data
arguments: tag: D40
type: string
name: disassemble_data
arguments: tag: D31
type: string

tool: D54: 
	---------------%s----------------



tool: D35: 			SIZE	 TIME_SEC	 gflops
 

tool: D34: ---

tool: D43: 			%d	%lf 	%s	


tool: D40: 
	------------------------------------------------------------------------------------------------

tool: D31: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t------------------------------------------------------------------------------------------------");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D4(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L14
  lea    D3(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
L5:
  add    $0x18,%rsp
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L14:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D4: 
	---------------%s----------------



tool: D19: 			SIZE	 TIME_SEC	 gflops
 

tool: D3: ---

tool: D25: 			%d	%lf 	%s	


tool: D29: 
	------------------------------------------------------------------------------------------------

tool: D2: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t------------------------------------------------------------------------------------------------");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D50(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L17
  lea    D40(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
L15:
  add    $0x18,%rsp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L17:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D50
type_infered: string
name: disassemble_data
arguments: tag: D31
type_infered: string
name: disassemble_data
arguments: tag: D40
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D50: 
	---------------%s----------------



tool: D31: 			SIZE	 TIME_SEC	 gflops
 

tool: D40: ---

tool: D13: 			%d	%lf 	%s	


tool: D0: 
	------------------------------------------------------------------------------------------------

tool: D15: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t------------------------------------------------------------------------------------------------");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CalcNN>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %edi,%r8d
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L149
  mov    %rsp,%rdi
  mov    $0x1f4,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movl   $0x6,(%rsp)
  mov    $0x1,%ecx
  mov    $0x4,%esi
  lea    0x4(%rsp),%r10
  mov    $0x0,%r9d
  mov    $0xcccccccd,%edi
  cmp    $0x3,%r8d
  jg     L87
  movb   $0x0,0x1(%rbx)
  mov    $0x0,%edx
  jmp    L35
L149:
  call   <CalcMM@plt>
  mov    %eax,%edx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  jmp    L74
L50:
  mov    %rsp,%r11
  lea    -0x1(%rcx),%eax
  lea    (%r10,%rax,4),%r12
  mov    %r9d,%eax
L114:
  mov    %esi,%edx
  imul   (%r11),%edx
  add    %eax,%edx
  mov    %edx,%eax
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ebp
  add    %ebp,%ebp
  sub    %ebp,%edx
  mov    %edx,(%r11)
  add    $0x4,%r11
  cmp    %r12,%r11
  jne    L114
  test   %eax,%eax
  je     L62
  lea    0x1(%rcx),%r11d
  movslq %r11d,%r11
L12:
  mov    %r11d,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ebp
  sar    $0x1f,%ebp
  sub    %ebp,%edx
  lea    (%rdx,%rdx,4),%ebp
  add    %ebp,%ebp
  sub    %ebp,%eax
  mov    %eax,-0x4(%rsp,%r11,4)
  mov    %edx,%eax
  add    $0x1,%r11
  test   %edx,%edx
  jne    L12
L62:
  cmp    $0x3e7,%ecx
  jg     L83
  add    $0x1,%esi
  cmp    %esi,%r8d
  jl     L33
L87:
  test   %ecx,%ecx
  jg     L50
  jmp    L62
L83:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L74:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  movslq %ecx,%rax
  movb   $0x0,(%rbx,%rax,1)
  lea    -0x1(%rcx),%edx
  test   %ecx,%ecx
  jle    L74
L35:
  movslq %edx,%rax
  lea    (%rsp,%rax,4),%rcx
  mov    %rbx,%rax
  lea    0x1(%rdx,%rbx,1),%esi
L19:
  movzbl (%rcx),%ebx
  lea    0x30(%rbx),%edx
  mov    %dl,(%rax)
  sub    $0x4,%rcx
  add    $0x1,%rax
  mov    %esi,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jg     L19
  jmp    L74
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D1: %u

tool: D3: overflow!


assistant: ```c
void CalcNN(int n, char *pOut) {
  if (n < 2) {
    sprintf(pOut, "%u", CalcMM(n));
    return;
  }
  unsigned int res[1000] = {6};
  int i, j, len, carry;
  for (i = 4, len = 1; i <= n; ++i) {
    for (j = 0, carry = 0; j < len; ++j) {
      res[j] = res[j] * i + carry;
      carry = res[j] / 10;
      res[j] %= 10;
    }
    for (; carry; carry /= 10)
      res[len++] = carry % 10;
    if (len >= 1000) {
      printf("overflow!\n");
      return;
    }
  }
  i = 0;
  pOut[len] = '\0';
  while (len-- > 0)
    pOut[i++] = res[len] + '0';
}
```