ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shiftRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x4(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x5(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x6(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x7(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x7(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x8(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x9(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xa(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x9(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xb(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xa(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xb(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0xc(%rax),%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0xd(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xf(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xd(%rax),%rdx
  movzbl -0x2(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xf(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xe(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xe(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shiftRows(unsigned char buf[]) {
  unsigned char aux1, aux2;
  aux1 = buf[4];
  buf[4] = buf[5];
  buf[5] = buf[6];
  buf[6] = buf[7];
  buf[7] = aux1;
  aux1 = buf[8];
  aux2 = buf[9];
  buf[8] = buf[10];
  buf[9] = buf[11];
  buf[10] = aux1;
  buf[11] = aux2;
  aux1 = buf[12];
  aux2 = buf[13];
  buf[12] = buf[15];
  buf[13] = aux1;
  buf[15] = buf[14];
  buf[14] = aux2;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shiftRows>:
  endbr64
  movzbl 0x4(%rdi),%eax
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x4(%rdi)
  movzbl 0x6(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %dl,0x6(%rdi)
  mov    %al,0x7(%rdi)
  movzbl 0x8(%rdi),%edx
  movzbl 0x9(%rdi),%eax
  movzbl 0xa(%rdi),%ecx
  mov    %cl,0x8(%rdi)
  movzbl 0xb(%rdi),%ecx
  mov    %cl,0x9(%rdi)
  mov    %dl,0xa(%rdi)
  mov    %al,0xb(%rdi)
  movzbl 0xc(%rdi),%edx
  movzbl 0xd(%rdi),%eax
  movzbl 0xf(%rdi),%ecx
  mov    %cl,0xc(%rdi)
  mov    %dl,0xd(%rdi)
  movzbl 0xe(%rdi),%edx
  mov    %dl,0xf(%rdi)
  mov    %al,0xe(%rdi)
  ret
```

assistant: ```c
void shiftRows(unsigned char buf[]) {
  unsigned char aux1, aux2;
  aux1 = buf[4];
  buf[4] = buf[5];
  buf[5] = buf[6];
  buf[6] = buf[7];
  buf[7] = aux1;
  aux1 = buf[8];
  aux2 = buf[9];
  buf[8] = buf[10];
  buf[9] = buf[11];
  buf[10] = aux1;
  buf[11] = aux2;
  aux1 = buf[12];
  aux2 = buf[13];
  buf[12] = buf[15];
  buf[13] = aux1;
  buf[15] = buf[14];
  buf[14] = aux2;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shiftRows>:
  endbr64
  movzbl 0x5(%rdi),%edx
  movzbl 0x4(%rdi),%eax
  mov    %dl,0x4(%rdi)
  movzbl 0x6(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %al,0x7(%rdi)
  movzwl 0x8(%rdi),%eax
  mov    %dl,0x6(%rdi)
  movzwl 0xa(%rdi),%edx
  mov    %ax,0xa(%rdi)
  movzwl 0xc(%rdi),%eax
  mov    %dx,0x8(%rdi)
  movzbl 0xf(%rdi),%edx
  mov    %dl,0xc(%rdi)
  movzbl 0xe(%rdi),%edx
  mov    %ax,0xd(%rdi)
  mov    %dl,0xf(%rdi)
  ret
```

assistant: ```c
void shiftRows(unsigned char buf[]) {
  unsigned char aux1, aux2;
  aux1 = buf[4];
  buf[4] = buf[5];
  buf[5] = buf[6];
  buf[6] = buf[7];
  buf[7] = aux1;
  aux1 = buf[8];
  aux2 = buf[9];
  buf[8] = buf[10];
  buf[9] = buf[11];
  buf[10] = aux1;
  buf[11] = aux2;
  aux1 = buf[12];
  aux2 = buf[13];
  buf[12] = buf[15];
  buf[13] = aux1;
  buf[15] = buf[14];
  buf[14] = aux2;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shiftRows>:
  endbr64
  movzbl 0x9(%rdi),%eax
  movzbl 0x8(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0xb(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0xa(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x4(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x7(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x6(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0x5(%rdi),%ecx
  shl    $0x8,%rax
  or     %rcx,%rax
  movzbl 0xf(%rdi),%ecx
  mov    %rax,0x4(%rdi)
  movzwl 0xc(%rdi),%eax
  mov    %cl,0xc(%rdi)
  movzbl 0xe(%rdi),%ecx
  mov    %ax,0xd(%rdi)
  mov    %cl,0xf(%rdi)
  ret
```

assistant: ```c
void shiftRows(unsigned char buf[]) {
  unsigned char aux1, aux2;
  aux1 = buf[4];
  buf[4] = buf[5];
  buf[5] = buf[6];
  buf[6] = buf[7];
  buf[7] = aux1;
  aux1 = buf[8];
  aux2 = buf[9];
  buf[8] = buf[10];
  buf[9] = buf[11];
  buf[10] = aux1;
  buf[11] = aux2;
  aux1 = buf[12];
  aux2 = buf[13];
  buf[12] = buf[15];
  buf[13] = aux1;
  buf[15] = buf[14];
  buf[14] = aux2;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L34:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L3:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L41
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L41
  cmpl   $0xa,-0x8(%rbp)
  jne    L34
L41:
  cmpl   $0xa,-0x8(%rbp)
  jne    L38
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  cmp    $0x1,%esi
  jle    L31
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L38:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L41
  cmp    $0xa,%eax
  je     L41
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L38
  mov    %r12d,%ebx
  jmp    L24
L31:
  mov    $0x0,%ebx
L41:
  cmp    $0xa,%eax
  je     L48
L24:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  movslq %ebx,%rax
  movb   $0xa,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L24
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getLine>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L35
  mov    D5(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L14:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L25
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %ebp,%edx
  je     L13
  mov    %edx,%r14d
L42:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L14
  cmp    $0xa,%eax
  je     L29
L35:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  lea    0x1(%r14),%edx
L25:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L13:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getLine>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  xor    %r14d,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L19
  mov    D5(%rip),%r12
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L53:
  lea    0x1(%r14),%edx
  cmp    $0xa,%eax
  je     L30
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %ebp,%edx
  je     L4
  mov    %edx,%r14d
L58:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbx,%rcx
  cmp    %eax,(%r12)
  jne    L53
  cmp    $0xa,%eax
  je     L21
L19:
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    0x1(%r14),%edx
L30:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r14
  add    %r13,%rcx
  movb   $0x0,(%rcx)
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  movslq %ebp,%rcx
  mov    %ebp,%r14d
  add    %r13,%rcx
  mov    %r14d,%eax
  movb   $0x0,(%rcx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int getLine(char s[], int lim) {
  int c, i;
  i = 0;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n') {
    s[i++] = c;
  }
  if (c == '\n') {
    s[i++] = c;
  }
  s[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L45
L12:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D22(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <y1@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L47
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L47:
  addl   $0x1,-0x24(%rbp)
L45:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L12
L8:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L20
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type: f64
name: parse_data
arguments: label: D26
type: string

tool: D22: 100000

tool: D26: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = y1(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L18:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D15(%rip),%xmm0
  call   <y1@plt>
  ucomisd %xmm0,%xmm0
  jp     L19
  sub    $0x1,%ebx
  jne    L18
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L23
L19:
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L23:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: f64
name: extract_symbolic_data
arguments: label: D13
data_type: string

tool: D15: 100000

tool: D13: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = y1(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L15
  xchg   %ax,%ax
L22:
  sub    $0x1,%ebx
  je     L10
L15:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D9(%rip),%xmm0
  call   <y1@plt>
  ucomisd %xmm0,%xmm0
  jnp    L22
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: f64
name: unpack_data
arguments: label: D10
datatype: string

tool: D9: 100000

tool: D10: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = y1(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L25
  xchg   %ax,%ax
L27:
  sub    $0x1,%ebx
  je     L8
L25:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D15(%rip),%xmm0
  call   <y1@plt>
  ucomisd %xmm0,%xmm0
  jnp    L27
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: f64
name: unpack_data
arguments: data_label: D10
datatype: string

tool: D15: 100000

tool: D10: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = rand_double() * 100000.0;
    y = y1(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fig04_11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L26:
  cmpl   $0x5,-0x4(%rbp)
  je     L28
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0xa,-0x4(%rbp)
  jbe    L26
  jmp    L7
L28:
  nop
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D6: %u 

tool: D3: 
Broke out of loop at x == %u


assistant: ```c
void fig04_11() {
  unsigned int x;
  for (x = 1; x <= 10; ++x) {
    if (x == 5) {
      break;
    }
    printf("%u ", x);
  }
  printf("\nBroke out of loop at x == %u\n", x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fig04_11>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D14(%rip),%rbp
L11:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  je     L3
  cmp    $0xa,%ebx
  jbe    L11
L3:
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string

tool: D14: %u 

tool: D7: 
Broke out of loop at x == %u


assistant: ```c
void fig04_11() {
  unsigned int x;
  for (x = 1; x <= 10; ++x) {
    if (x == 5) {
      break;
    }
    printf("%u ", x);
  }
  printf("\nBroke out of loop at x == %u\n", x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fig04_11>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L6
  add    $0x8,%rsp
  mov    $0x5,%esi
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D8
type: string

tool: D3: %u 

tool: D8: 
Broke out of loop at x == %u


assistant: ```c
void fig04_11() {
  unsigned int x;
  for (x = 1; x <= 10; ++x) {
    if (x == 5) {
      break;
    }
    printf("%u ", x);
  }
  printf("\nBroke out of loop at x == %u\n", x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fig04_11>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L7
  add    $0x8,%rsp
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D19: %u 

tool: D1: 
Broke out of loop at x == %u


assistant: ```c
void fig04_11() {
  unsigned int x;
  for (x = 1; x <= 10; ++x) {
    if (x == 5) {
      break;
    }
    printf("%u ", x);
  }
  printf("\nBroke out of loop at x == %u\n", x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void foo(void *p, int x) {
  if (x > 0) {
    free(p);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(void *p, int x) {
  if (x > 0) {
    free(p);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jg     L1
  ret
  nopl   0x0(%rax)
L1:
  jmp    1050 <free@plt>
```

assistant: ```c
void foo(void *p, int x) {
  if (x > 0) {
    free(p);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  test   %esi,%esi
  jg     L4
  ret
  nopl   0x0(%rax)
L4:
  jmp    1050 <free@plt>
```

assistant: ```c
void foo(void *p, int x) {
  if (x > 0) {
    free(p);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x432065766f6c2049,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x21,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D4(%rip),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L12
L23:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x24(%rbp)
L12:
  cmpl   $0xc,-0x24(%rbp)
  jle    L23
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: I love C too!

assistant: ```c
int main() {
  char str[] = "I love C!";
  printf("%s\n", str);
  char *ps = "I love C too!";
  for (int i = 0; i < 13; i++) {
    printf("%c", *(ps + i));
  }
  printf("%s\n", ps);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x432065766f6c2049,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x21,0x16(%rsp)
  lea    0xe(%rsp),%rdi
  call   <puts@plt>
  lea    D5(%rip),%rbx
  lea    0xd(%rbx),%rbp
L9:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: I love C too!

assistant: ```c
int main() {
  char str[] = "I love C!";
  printf("%s\n", str);
  char *ps = "I love C too!";
  for (int i = 0; i < 13; i++) {
    printf("%c", *(ps + i));
  }
  printf("%s\n", ps);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  lea    0xc(%rbx),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x432065766f6c2049,%rax
  lea    0xe(%rsp),%rdi
  mov    %rax,0xe(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x16(%rsp)
  call   <puts@plt>
  mov    $0x49,%edi
  jmp    L14
  nopl   (%rax)
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
L14:
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L4
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D12:  love C too!

tool: D2: I love C too!

assistant: ```c
int main() {
  char str[] = "I love C!";
  printf("%s\n", str);
  char *ps = "I love C too!";
  for (int i = 0; i < 13; i++) {
    printf("%c", *(ps + i));
  }
  printf("%s\n", ps);
  return 0;
}
```