ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x3f4(%rbp)
  jmp    L5
L11:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0x3f4(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mgetline@plt>
  test   %rax,%rax
  jg     L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: %s


assistant: ```c
int main(void) {
  int lim = 10;
  char c[1000];
  while (mgetline(c, lim) > 0)
    printf("%s\n", c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rbx
  jmp    L10
L25:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L10:
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <mgetline@plt>
  test   %rax,%rax
  jg     L25
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: %s


assistant: ```c
int main(void) {
  int lim = 10;
  char c[1000];
  while (mgetline(c, lim) > 0)
    printf("%s\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L18
  nopl   0x0(%rax)
L23:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L18:
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <mgetline@plt>
  test   %rax,%rax
  jg     L23
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: %s


assistant: ```c
int main(void) {
  int lim = 10;
  char c[1000];
  while (mgetline(c, lim) > 0)
    printf("%s\n", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L7
  nopl   0x0(%rax)
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L7:
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <mgetline@plt>
  test   %rax,%rax
  jg     L26
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x3f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: %s


assistant: ```c
int main(void) {
  int lim = 10;
  char c[1000];
  while (mgetline(c, lim) > 0)
    printf("%s\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getsockopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  cltq
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    %rax,-0x28(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xf,%edi
  call   <__socketcall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int getsockopt(int fd, int level, int optname, __ptr_t optval, socklen_t *optlen) {
  unsigned long args[5];
  args[0] = fd;
  args[1] = level;
  args[2] = optname;
  args[3] = (unsigned long)optval;
  args[4] = (unsigned long)optlen;
  return (__socketcall(15, args));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getsockopt>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    %rdi,(%rsp)
  movslq %esi,%rsi
  mov    %rsi,0x8(%rsp)
  movslq %edx,%rdx
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x20(%rsp)
  mov    %rsp,%rsi
  mov    $0xf,%edi
  call   <__socketcall@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockopt(int fd, int level, int optname, __ptr_t optval, socklen_t *optlen) {
  unsigned long args[5];
  args[0] = fd;
  args[1] = level;
  args[2] = optname;
  args[3] = (unsigned long)optval;
  args[4] = (unsigned long)optlen;
  return (__socketcall(15, args));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getsockopt>:
  endbr64
  sub    $0x38,%rsp
  movslq %edi,%rdi
  movslq %esi,%rsi
  movslq %edx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    $0xf,%edi
  mov    %rsi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x20(%rsp)
  call   <__socketcall@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockopt(int fd, int level, int optname, __ptr_t optval, socklen_t *optlen) {
  unsigned long args[5];
  args[0] = fd;
  args[1] = level;
  args[2] = optname;
  args[3] = (unsigned long)optval;
  args[4] = (unsigned long)optlen;
  return (__socketcall(15, args));
}
```
user: What is the c source code of the assembly code below:

```asm
<getsockopt>:
  endbr64
  sub    $0x38,%rsp
  movslq %esi,%rsi
  movslq %edx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  movq   %rsi,%xmm1
  mov    $0xf,%edi
  movq   %rax,%xmm0
  mov    %rsp,%rsi
  mov    %rdx,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x20(%rsp)
  movaps %xmm0,(%rsp)
  call   <__socketcall@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockopt(int fd, int level, int optname, __ptr_t optval, socklen_t *optlen) {
  unsigned long args[5];
  args[0] = fd;
  args[1] = level;
  args[2] = optname;
  args[3] = (unsigned long)optval;
  args[4] = (unsigned long)optlen;
  return (__socketcall(15, args));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GenerateImageHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %rdx,-0x418(%rbp)
  mov    %ecx,-0x41c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x408(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x408(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x408(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x408(%rbp),%rax
  lea    D58(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x41c(%rbp),%ecx
  mov    -0x418(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  lea    D51(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x3f0(%rbp),%rdx
  mov    -0x408(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x408(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x408(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x3f4(%rbp)
  mov    -0x3f4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x408(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x41c(%rbp),%edx
  mov    -0x410(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x3f4(%rbp),%edx
  mov    -0x41c(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D58
type_infered: string
name: unpack_data
arguments: data_label: D51
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string

tool: D38: HTTP/1.1 200 OK


tool: D10: Date: Sun, 21 Dec 2003 23:10:01 GMT


tool: D29: Server: IRTrans 2.0


tool: D58: Mime-Version: 1.0


tool: D51: Content-Type: image/%s
Content-Length: %6d


tool: D23: 


assistant: ```c
int GenerateImageHeader(char *mem, char *data, char *type, int len) {
  char ln[1000];
  int hlen;
  sprintf(mem, "HTTP/1.1 200 OK\r\n");
  strcat(mem, "Date: Sun, 21 Dec 2003 23:10:01 GMT\r\n");
  strcat(mem, "Server: IRTrans 2.0\r\n");
  strcat(mem, "Mime-Version: 1.0\r\n");
  sprintf(ln, "Content-Type: image/%s\r\nContent-Length: %6d\r\n", type, len);
  strcat(mem, ln);
  strcat(mem, "\r\n");
  hlen = (int)strlen(mem);
  memcpy(mem + hlen, data, len);
  return (hlen + len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GenerateImageHeader>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  movabs $0x312e312f50545448,%rax
  movabs $0xd4b4f2030303220,%rdx
  mov    %rax,(%rdi)
  mov    %rdx,0x8(%rdi)
  movw   $0xa,0x10(%rdi)
  lea    D42(%rip),%rsi
  call   <strcat@plt>
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rsp,%r14
  mov    %ebp,%ecx
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  cltq
  lea    (%rbx,%rax,1),%rdi
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  lea    0x0(%rbp,%r12,1),%eax
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D42
datatype: string
name: read_data
arguments: data_tag: D28
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D42: Date: Sun, 21 Dec 2003 23:10:01 GMT


tool: D28: Server: IRTrans 2.0


tool: D12: Mime-Version: 1.0


tool: D7: Content-Type: image/%s
Content-Length: %6d


tool: D3: 


assistant: ```c
int GenerateImageHeader(char *mem, char *data, char *type, int len) {
  char ln[1000];
  int hlen;
  sprintf(mem, "HTTP/1.1 200 OK\r\n");
  strcat(mem, "Date: Sun, 21 Dec 2003 23:10:01 GMT\r\n");
  strcat(mem, "Server: IRTrans 2.0\r\n");
  strcat(mem, "Mime-Version: 1.0\r\n");
  sprintf(ln, "Content-Type: image/%s\r\nContent-Length: %6d\r\n", type, len);
  strcat(mem, ln);
  strcat(mem, "\r\n");
  hlen = (int)strlen(mem);
  memcpy(mem + hlen, data, len);
  return (hlen + len);
}
```
user: What is the c source code of the assembly code below:

```asm
<GenerateImageHeader>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D51(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x3f0,%rsp
  movdqa D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%eax
  mov    %rsp,%r14
  mov    %ax,0x10(%rdi)
  movups %xmm0,(%rdi)
  call   <strcat@plt>
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    %r14,%rdi
  lea    D32(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%r12
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%r12,1),%eax
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D51
type: string
name: retrieve_data
arguments: tag: D36
type: byte[16]
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D32
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D51: Date: Sun, 21 Dec 2003 23:10:01 GMT


tool: {"D36": [0x48,0x54,0x54,0x50,0x2f,0x31,0x2e,0x31,0x20,0x32,0x30,0x30,0x20,0x4f,0x4b,0x0d]}

tool: D18: Server: IRTrans 2.0


tool: D4: Mime-Version: 1.0


tool: D32: Content-Type: image/%s
Content-Length: %6d


tool: D14: 


assistant: ```c
int GenerateImageHeader(char *mem, char *data, char *type, int len) {
  char ln[1000];
  int hlen;
  sprintf(mem, "HTTP/1.1 200 OK\r\n");
  strcat(mem, "Date: Sun, 21 Dec 2003 23:10:01 GMT\r\n");
  strcat(mem, "Server: IRTrans 2.0\r\n");
  strcat(mem, "Mime-Version: 1.0\r\n");
  sprintf(ln, "Content-Type: image/%s\r\nContent-Length: %6d\r\n", type, len);
  strcat(mem, ln);
  strcat(mem, "\r\n");
  hlen = (int)strlen(mem);
  memcpy(mem + hlen, data, len);
  return (hlen + len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GenerateImageHeader>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D53(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x3f0,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%eax
  mov    %rsp,%r14
  mov    %ax,0x10(%rdi)
  movups %xmm0,(%rdi)
  call   <strcat@plt>
  lea    D46(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D50(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    %r14,%rdi
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%r12
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%r12,1),%eax
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x3f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D53
data_type: string
name: unpack_data
arguments: tag: D3
data_type: byte[16]
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D50
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D53: Date: Sun, 21 Dec 2003 23:10:01 GMT


tool: {"D3": [0x48,0x54,0x54,0x50,0x2f,0x31,0x2e,0x31,0x20,0x32,0x30,0x30,0x20,0x4f,0x4b,0x0d]}

tool: D46: Server: IRTrans 2.0


tool: D50: Mime-Version: 1.0


tool: D20: Content-Type: image/%s
Content-Length: %6d


tool: D4: 


assistant: ```c
int GenerateImageHeader(char *mem, char *data, char *type, int len) {
  char ln[1000];
  int hlen;
  sprintf(mem, "HTTP/1.1 200 OK\r\n");
  strcat(mem, "Date: Sun, 21 Dec 2003 23:10:01 GMT\r\n");
  strcat(mem, "Server: IRTrans 2.0\r\n");
  strcat(mem, "Mime-Version: 1.0\r\n");
  sprintf(ln, "Content-Type: image/%s\r\nContent-Length: %6d\r\n", type, len);
  strcat(mem, ln);
  strcat(mem, "\r\n");
  hlen = (int)strlen(mem);
  memcpy(mem + hlen, data, len);
  return (hlen + len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <type1@plt>
  add    $0x10,%rsp
  leave
  ret
```

assistant: ```c
int Type(void *v) {
  int *msgvec = v;
  return (type1(msgvec, 0, 0, 0, 0, NULL, NULL));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Type>:
  endbr64
  sub    $0x10,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <type1@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int Type(void *v) {
  int *msgvec = v;
  return (type1(msgvec, 0, 0, 0, 0, NULL, NULL));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Type>:
  endbr64
  sub    $0x10,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   $0x0
  xor    %edx,%edx
  xor    %esi,%esi
  call   <type1@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int Type(void *v) {
  int *msgvec = v;
  return (type1(msgvec, 0, 0, 0, 0, NULL, NULL));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Type>:
  endbr64
  sub    $0x10,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   $0x0
  xor    %edx,%edx
  xor    %esi,%esi
  call   <type1@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int Type(void *v) {
  int *msgvec = v;
  return (type1(msgvec, 0, 0, 0, 0, NULL, NULL));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hex2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  subb   $0x30,-0x4(%rbp)
  cmpb   $0x9,-0x4(%rbp)
  jbe    L12
  movzbl -0x4(%rbp),%eax
  add    $0x2f,%eax
  or     $0x20,%eax
  mov    %al,-0x4(%rbp)
  subb   $0x56,-0x4(%rbp)
L12:
  cmpb   $0xf,-0x4(%rbp)
  jbe    L14
  movb   $0xff,-0x4(%rbp)
L14:
  movzbl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char hex2int(unsigned char hex) {
  hex = hex - '0';
  if (hex > 9) {
    hex = (hex + '0' - 1) | 0x20;
    hex = hex - 'a' + 11;
  }
  if (hex > 15) {
    hex = 0xFF;
  }
  return hex;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L0
  sub    $0x1,%edi
  or     $0x20,%edi
  lea    -0x56(%rdi),%eax
L0:
  cmp    $0x10,%al
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
char hex2int(unsigned char hex) {
  hex = hex - '0';
  if (hex > 9) {
    hex = (hex + '0' - 1) | 0x20;
    hex = hex - 'a' + 11;
  }
  if (hex > 15) {
    hex = 0xFF;
  }
  return hex;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L9
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  or     $0x20,%edi
  sub    $0x56,%edi
  cmp    $0xf,%dil
  cmovbe %edi,%eax
L9:
  ret
```

assistant: ```c
char hex2int(unsigned char hex) {
  hex = hex - '0';
  if (hex > 9) {
    hex = (hex + '0' - 1) | 0x20;
    hex = hex - 'a' + 11;
  }
  if (hex > 15) {
    hex = 0xFF;
  }
  return hex;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hex2int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L7
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  or     $0x20,%edi
  sub    $0x56,%edi
  cmp    $0xf,%dil
  cmovbe %edi,%eax
L7:
  ret
```

assistant: ```c
char hex2int(unsigned char hex) {
  hex = hex - '0';
  if (hex > 9) {
    hex = (hex + '0' - 1) | 0x20;
    hex = hex - 'a' + 11;
  }
  if (hex > 15) {
    hex = 0xFF;
  }
  return hex;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<findSumOfPrimes_limited>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x2,-0x28(%rbp)
  jmp    L100
L57:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L40
  mov    -0x28(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L42
L16:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L50
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L29
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  jmp    L29
L50:
  nop
L29:
  mov    -0x28(%rbp),%rax
  add    %rax,-0x20(%rbp)
L42:
  cmpq   $0x1e847f,-0x20(%rbp)
  jle    L16
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x30(%rbp)
  jmp    L39
L40:
  nop
L39:
  addq   $0x1,-0x28(%rbp)
L100:
  cmpq   $0x1e847f,-0x28(%rbp)
  jle    L57
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L105
L7:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L105:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L7
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
long findSumOfPrimes_limited(long *sieve, long maxValue) {
  long *primesArray = malloc(sizeof(long) * (maxValue / 2));
  long primesFound = 0;
  for (long a = 2; a < 2000000; ++a) {
    if (sieve[a] == 0)
      continue;
    else {
      for (long b = a + a; b < 2000000; b += a) {
        if (sieve[b] == 0)
          continue;
        else if (sieve[b] % b == 0)
          sieve[b] = 0;
      }
      primesArray[primesFound] = a;
      primesFound++;
    }
  }
  unsigned long result = 0;
  for (long a = 0; a < primesFound; ++a)
    result += primesArray[a];
  return result;
}
```