ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%esi
  mov    $0x1,%eax
  movsd  D2(%rip),%xmm0
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x40000000,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x24,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: f64
name: read_data
arguments: data_label: D41
type: string
name: read_data
arguments: data_label: D57
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D55
type: string
name: read_data
arguments: data_label: D5
type: string

tool: D2: 1.2

tool: D41: You have %d bugs at the imaginary rate of %f.


tool: D57: The entire universe has %ld bugs.


tool: D23: You are expected to have %f bugs.


tool: D55: That is only a %e portion of the universe.


tool: D5: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 30;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_to_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_to_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vector_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *vector_copy(double *v, int n) {
  double *copy;
  int i;
  copy = (double *)malloc(n * sizeof(double));
  for (i = 0; i < n; i++) {
    copy[i] = v[i];
  }
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L11
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%rsi
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rcx
L14:
  movsd  (%rcx,%rdx,1),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L14
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *vector_copy(double *v, int n) {
  double *copy;
  int i;
  copy = (double *)malloc(n * sizeof(double));
  for (i = 0; i < n; i++) {
    copy[i] = v[i];
  }
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_copy>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L4
  sub    %rax,%rbx
  lea    (%rax,%rbp,8),%rsi
  mov    %rax,%rdx
  mov    %rbx,%rcx
  nopl   0x0(%rax)
L10:
  movsd  (%rcx,%rdx,1),%xmm0
  add    $0x8,%rdx
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rsi,%rdx
  jne    L10
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *vector_copy(double *v, int n) {
  double *copy;
  int i;
  copy = (double *)malloc(n * sizeof(double));
  for (i = 0; i < n; i++) {
    copy[i] = v[i];
  }
  return copy;
}
```
user: What is the c source code of the assembly code below:

```asm
<vector_copy>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L27
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L26
  lea    0x8(%rbx),%rax
  cmp    %rax,%r8
  je     L26
  mov    %ebp,%edx
  mov    %rbx,%rcx
  mov    %r8,%rax
  shr    %edx
  sub    %r8,%rcx
  shl    $0x4,%rdx
  add    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L3:
  movupd (%rax,%rcx,1),%xmm1
  add    $0x10,%rax
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L3
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebp
  je     L27
  movsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L27:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  lea    (%r8,%rbp,8),%rdx
  mov    %r8,%rax
  sub    %r8,%rbx
  nopw   0x0(%rax,%rax,1)
L8:
  movsd  (%rbx,%rax,1),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L8
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *vector_copy(double *v, int n) {
  double *copy;
  int i;
  copy = (double *)malloc(n * sizeof(double));
  for (i = 0; i < n; i++) {
    copy[i] = v[i];
  }
  return copy;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<outMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <outArrInt@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: 


assistant: ```c
void outMat(int **xs, int r, int c) {
  for (int i = 0; i < r; i++)
    outArrInt(xs[i], c);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<outMat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  mov    %edx,%ebp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
L2:
  mov    %ebp,%esi
  mov    (%rbx),%rdi
  call   <outArrInt@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
L16:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: 


assistant: ```c
void outMat(int **xs, int r, int c) {
  for (int i = 0; i < r; i++)
    outArrInt(xs[i], c);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<outMat>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%rdi
  mov    %ebp,%esi
  add    $0x8,%rbx
  call   <outArrInt@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  lea    D13(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: string

tool: D13: 


assistant: ```c
void outMat(int **xs, int r, int c) {
  for (int i = 0; i < r; i++)
    outArrInt(xs[i], c);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<outMat>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%rdi
  mov    %ebp,%esi
  add    $0x8,%rbx
  call   <outArrInt@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  lea    D17(%rip),%rdi
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string

tool: D17: 


assistant: ```c
void outMat(int **xs, int r, int c) {
  for (int i = 0; i < r; i++)
    outArrInt(xs[i], c);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swapchar_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0xff,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L16
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  sar    $0x8,%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapchar_(INJ, OUJ, NUM) int INJ[1], OUJ[1];
int *NUM;
{
  int t1, t2, t3, t4;
  int c1, c2, c3, c4;
  int k, i;
  c1 = 0xff;
  c2 = c1 << 8;
  c3 = c2 << 8;
  c4 = c3 << 8;
  for (i = 0; i < *NUM; i++) {
    t1 = ((INJ[i] & c1) & c1) << 8;
    t2 = (((INJ[i] & c2) >> 8) & c1);
    OUJ[i] = t1 | t2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swapchar_>:
  endbr64
  cmpl   $0x0,(%rdx)
  jle    L14
  push   %rbx
  mov    $0x0,%ecx
L1:
  mov    (%rdi,%rcx,4),%eax
  movzbl %ah,%ebx
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %ebx,%eax
  mov    %eax,(%rsi,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,(%rdx)
  jg     L1
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
void swapchar_(INJ, OUJ, NUM) int INJ[1], OUJ[1];
int *NUM;
{
  int t1, t2, t3, t4;
  int c1, c2, c3, c4;
  int k, i;
  c1 = 0xff;
  c2 = c1 << 8;
  c3 = c2 << 8;
  c4 = c3 << 8;
  for (i = 0; i < *NUM; i++) {
    t1 = ((INJ[i] & c1) & c1) << 8;
    t2 = (((INJ[i] & c2) >> 8) & c1);
    OUJ[i] = t1 | t2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapchar_>:
  endbr64
  mov    (%rdx),%eax
  test   %eax,%eax
  jle    L11
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L6:
  movzwl (%rdi,%rcx,4),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,(%rsi,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,(%rdx)
  jg     L6
L11:
  ret
```

assistant: ```c
void swapchar_(INJ, OUJ, NUM) int INJ[1], OUJ[1];
int *NUM;
{
  int t1, t2, t3, t4;
  int c1, c2, c3, c4;
  int k, i;
  c1 = 0xff;
  c2 = c1 << 8;
  c3 = c2 << 8;
  c4 = c3 << 8;
  for (i = 0; i < *NUM; i++) {
    t1 = ((INJ[i] & c1) & c1) << 8;
    t2 = (((INJ[i] & c2) >> 8) & c1);
    OUJ[i] = t1 | t2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapchar_>:
  endbr64
  mov    (%rdx),%eax
  test   %eax,%eax
  jle    L18
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L17:
  movzwl (%rdi,%rcx,4),%eax
  rol    $0x8,%ax
  movzwl %ax,%eax
  mov    %eax,(%rsi,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,(%rdx)
  jg     L17
L18:
  ret
```

assistant: ```c
void swapchar_(INJ, OUJ, NUM) int INJ[1], OUJ[1];
int *NUM;
{
  int t1, t2, t3, t4;
  int c1, c2, c3, c4;
  int k, i;
  c1 = 0xff;
  c2 = c1 << 8;
  c3 = c2 << 8;
  c4 = c3 << 8;
  for (i = 0; i < *NUM; i++) {
    t1 = ((INJ[i] & c1) & c1) << 8;
    t2 = (((INJ[i] & c2) >> 8) & c1);
    OUJ[i] = t1 | t2;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PrintHello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Hello World!, It's me , thread %ld


assistant: ```c
void *PrintHello(void *threadid) {
  long tid;
  tid = (long)threadid;
  printf("Hello World!, It's me , thread %ld\n", tid);
  pthread_exit(NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PrintHello>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9: Hello World!, It's me , thread %ld


assistant: ```c
void *PrintHello(void *threadid) {
  long tid;
  tid = (long)threadid;
  printf("Hello World!, It's me , thread %ld\n", tid);
  pthread_exit(NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PrintHello>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: Hello World!, It's me , thread %ld


assistant: ```c
void *PrintHello(void *threadid) {
  long tid;
  tid = (long)threadid;
  printf("Hello World!, It's me , thread %ld\n", tid);
  pthread_exit(NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PrintHello>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: Hello World!, It's me , thread %ld


assistant: ```c
void *PrintHello(void *threadid) {
  long tid;
  tid = (long)threadid;
  printf("Hello World!, It's me , thread %ld\n", tid);
  pthread_exit(NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
datatype: string
name: retrieve_data
arguments: data_label: D41
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D35
datatype: string
name: retrieve_data
arguments: data_label: D31
datatype: string
name: retrieve_data
arguments: data_label: D68
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D24: Enter your variable: 

tool: D41: %d

tool: D12: %d + 2 = %d


tool: D35: %d - 2 = %d


tool: D31: %d * 2 = %d


tool: D68: %d / 2 = %d


tool: D0: %d %% 2 = %d


assistant: ```c
int main() {
  int x;
  printf("Enter your variable: ");
  scanf("%d", &x);
  printf("%d + 2 = %d\n", x, x + 2);
  printf("%d - 2 = %d\n", x, x - 2);
  printf("%d * 2 = %d\n", x, x * 2);
  printf("%d / 2 = %d\n", x, x / 2);
  printf("%d %% 2 = %d\n", x, x % 2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    0x2(%rsi),%edx
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    -0x2(%rsi),%edx
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    (%rsi,%rsi,1),%edx
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rsi,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D58
data_type: string
name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D36
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D24: Enter your variable: 

tool: D17: %d

tool: D58: %d + 2 = %d


tool: D26: %d - 2 = %d


tool: D36: %d * 2 = %d


tool: D19: %d / 2 = %d


tool: D1: %d %% 2 = %d


assistant: ```c
int main() {
  int x;
  printf("Enter your variable: ");
  scanf("%d", &x);
  printf("%d + 2 = %d\n", x, x + 2);
  printf("%d - 2 = %d\n", x, x - 2);
  printf("%d * 2 = %d\n", x, x * 2);
  printf("%d / 2 = %d\n", x, x / 2);
  printf("%d %% 2 = %d\n", x, x % 2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  lea    0x2(%rsi),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  lea    -0x2(%rsi),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  lea    (%rsi,%rsi,1),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D44(%rip),%rdi
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rsi,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type_guessed: string
name: disassemble_data
arguments: label: D34
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string
name: disassemble_data
arguments: label: D42
type_guessed: string
name: disassemble_data
arguments: label: D51
type_guessed: string
name: disassemble_data
arguments: label: D44
type_guessed: string

tool: D18: Enter your variable: 

tool: D34: %d

tool: D24: %d + 2 = %d


tool: D22: %d - 2 = %d


tool: D42: %d * 2 = %d


tool: D51: %d / 2 = %d


tool: D44: %d %% 2 = %d


assistant: ```c
int main() {
  int x;
  printf("Enter your variable: ");
  scanf("%d", &x);
  printf("%d + 2 = %d\n", x, x + 2);
  printf("%d - 2 = %d\n", x, x - 2);
  printf("%d * 2 = %d\n", x, x * 2);
  printf("%d / 2 = %d\n", x, x / 2);
  printf("%d %% 2 = %d\n", x, x % 2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D35(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  lea    0x2(%rsi),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  lea    -0x2(%rsi),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  lea    (%rsi,%rsi,1),%edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D37(%rip),%rdi
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rsi,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D58
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D11
type: string
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D37
type: string

tool: D35: Enter your variable: 

tool: D58: %d

tool: D24: %d + 2 = %d


tool: D9: %d - 2 = %d


tool: D11: %d * 2 = %d


tool: D31: %d / 2 = %d


tool: D37: %d %% 2 = %d


assistant: ```c
int main() {
  int x;
  printf("Enter your variable: ");
  scanf("%d", &x);
  printf("%d + 2 = %d\n", x, x + 2);
  printf("%d - 2 = %d\n", x, x - 2);
  printf("%d * 2 = %d\n", x, x * 2);
  printf("%d / 2 = %d\n", x, x / 2);
  printf("%d %% 2 = %d\n", x, x % 2);
  return 0;
}
```