ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_char>:
  endbr64
  push   %rbp
  mov    $0xf,%eax
  mov    %edi,%ebp
  mov    %esi,%edi
  push   %rbx
  sub    $0x8,%rsp
  test   %cl,%cl
  cmovne %ecx,%eax
  mov    %eax,%ebx
  mov    %esi,%eax
  or     %edx,%eax
  js     L13
  mov    %edx,%esi
  call   <get_screen_offset@plt>
  cmp    $0xa,%bpl
  je     L26
L34:
  movslq %eax,%rdx
  mov    %bpl,0xb8000(%rdx)
  mov    %bl,0xb8001(%rdx)
L9:
  lea    0x2(%rax),%edi
  call   <handle_scrolling@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    1080 <set_cursor@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <get_cursor@plt>
  cmp    $0xa,%bpl
  jne    L34
L26:
  movslq %eax,%rsi
  sar    $0x1f,%eax
  mov    $0x4f,%edi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x26,%rsi
  sub    %eax,%esi
  call   <get_screen_offset@plt>
  jmp    L9
```

assistant: ```c
void print_char(char character, int col, int row, char attribute_byte) {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  if (!attribute_byte) {
    attribute_byte = 0x0f;
  }
  int offset;
  if (col >= 0 && row >= 0) {
    offset = get_screen_offset(col, row);
  } else {
    offset = get_cursor();
  }
  if (character == '\n') {
    int rows = offset / (2 * 80);
    offset = get_screen_offset(80 - 1, rows);
  } else {
    vidmem[offset] = character;
    vidmem[offset + 1] = attribute_byte;
  }
  offset += 2;
  offset = handle_scrolling(offset);
  set_cursor(offset);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_char>:
  endbr64
  push   %rbp
  mov    $0xf,%eax
  mov    %edi,%ebp
  mov    %esi,%edi
  push   %rbx
  sub    $0x8,%rsp
  test   %cl,%cl
  cmovne %ecx,%eax
  mov    %eax,%ebx
  mov    %esi,%eax
  or     %edx,%eax
  js     L7
  mov    %edx,%esi
  call   <get_screen_offset@plt>
  cmp    $0xa,%bpl
  je     L25
L24:
  movslq %eax,%rdx
  mov    %bpl,0xb8000(%rdx)
  mov    %bl,0xb8001(%rdx)
L27:
  lea    0x2(%rax),%edi
  call   <handle_scrolling@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    1080 <set_cursor@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <get_cursor@plt>
  cmp    $0xa,%bpl
  jne    L24
L25:
  movslq %eax,%rsi
  sar    $0x1f,%eax
  mov    $0x4f,%edi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x26,%rsi
  sub    %eax,%esi
  call   <get_screen_offset@plt>
  jmp    L27
```

assistant: ```c
void print_char(char character, int col, int row, char attribute_byte) {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  if (!attribute_byte) {
    attribute_byte = 0x0f;
  }
  int offset;
  if (col >= 0 && row >= 0) {
    offset = get_screen_offset(col, row);
  } else {
    offset = get_cursor();
  }
  if (character == '\n') {
    int rows = offset / (2 * 80);
    offset = get_screen_offset(80 - 1, rows);
  } else {
    vidmem[offset] = character;
    vidmem[offset + 1] = attribute_byte;
  }
  offset += 2;
  offset = handle_scrolling(offset);
  set_cursor(offset);
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L11
L50:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L11
  mov    $0x1,%eax
  jmp    L64
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L61
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
L61:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
L48:
  mov    $0x1,%eax
  jmp    L64
L24:
  mov    $0x0,%eax
L64:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b) {
    if (*a++ != *b++)
      return 1;
  }
  if (*a || *b)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L28
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    %dl,%al
  je     L4
  mov    $0x1,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
L8:
  cmpb   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b) {
    if (*a++ != *b++)
      return 1;
  }
  if (*a || *b)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L16:
  test   %dl,%dl
  je     L6
  add    $0x1,%rax
  cmp    %dl,%cl
  jne    L6
L8:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   %cl,%cl
  jne    L16
  xor    %eax,%eax
  test   %dl,%dl
  setne  %al
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b) {
    if (*a++ != *b++)
      return 1;
  }
  if (*a || *b)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L27:
  test   %dl,%dl
  je     L24
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L24
L20:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   %cl,%cl
  jne    L27
  xor    %eax,%eax
  test   %dl,%dl
  setne  %al
  ret
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while (*a && *b) {
    if (*a++ != *b++)
      return 1;
  }
  if (*a || *b)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<issue_request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <append_string_katcl@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <append_string_katcl@plt>
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <append_string_katcl@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D14
datatype: string

tool: D5: ?sensor-sampling

tool: D14: event

assistant: ```c
int issue_request(struct katcl_line *l, char *sensor, int verbose) {
  append_string_katcl(l, 0x01 | 0x10, "?sensor-sampling");
  append_string_katcl(l, 0x10, sensor);
  append_string_katcl(l, 0x10 | 0x02, "event");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<issue_request>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D11(%rip),%rdx
  mov    $0x11,%esi
  call   <append_string_katcl@plt>
  mov    %rbp,%rdx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <append_string_katcl@plt>
  lea    D17(%rip),%rdx
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <append_string_katcl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D11: ?sensor-sampling

tool: D17: event

assistant: ```c
int issue_request(struct katcl_line *l, char *sensor, int verbose) {
  append_string_katcl(l, 0x01 | 0x10, "?sensor-sampling");
  append_string_katcl(l, 0x10, sensor);
  append_string_katcl(l, 0x10 | 0x02, "event");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<issue_request>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdx
  mov    %rsi,%r12
  mov    $0x11,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <append_string_katcl@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <append_string_katcl@plt>
  mov    %rbp,%rdi
  mov    $0x12,%esi
  lea    D0(%rip),%rdx
  call   <append_string_katcl@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D5: ?sensor-sampling

tool: D0: event

assistant: ```c
int issue_request(struct katcl_line *l, char *sensor, int verbose) {
  append_string_katcl(l, 0x01 | 0x10, "?sensor-sampling");
  append_string_katcl(l, 0x10, sensor);
  append_string_katcl(l, 0x10 | 0x02, "event");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<issue_request>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdx
  mov    %rsi,%r12
  mov    $0x11,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <append_string_katcl@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <append_string_katcl@plt>
  mov    %rbp,%rdi
  mov    $0x12,%esi
  lea    D10(%rip),%rdx
  call   <append_string_katcl@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D10
type: string

tool: D15: ?sensor-sampling

tool: D10: event

assistant: ```c
int issue_request(struct katcl_line *l, char *sensor, int verbose) {
  append_string_katcl(l, 0x01 | 0x10, "?sensor-sampling");
  append_string_katcl(l, 0x10, sensor);
  append_string_katcl(l, 0x10 | 0x02, "event");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cgau1>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %esi,%r12d
  mov    $0x0,%ebx
  lea    0x38(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x28(%rsp)
L19:
  mov    0x0(%rbp,%rbx,8),%r15
  mov    0x28(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  movq   %r15,%xmm0
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm3
  movq   %r15,%xmm0
  mulsd  D0(%rip),%xmm0
  movsd  %xmm2,0x10(%rsp)
  mulsd  %xmm2,%xmm0
  movsd  %xmm3,0x18(%rsp)
  subsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   %r15,%xmm5
  mulsd  %xmm5,%xmm5
  movapd %xmm5,%xmm6
  xorpd  D9(%rip),%xmm6
  movq   %xmm6,%r15
  movapd %xmm6,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x1,%edi
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%r13,%rbx,8)
  movsd  0x0(%rbp,%rbx,8),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  0x18(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   %r15,%xmm0
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm4
  mulsd  0x8(%rsp),%xmm4
  movq   %xmm4,%r15
  mov    $0x1,%edi
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %r15,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%r14,%rbx,8)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D9
type_infered: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void cgau1(double *x, int sigInLength, double *psir, double *psii, int sigOutLength, double ys) {
  int count;
  double x2, cosx, sinx;
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    cosx = cos(x[count]);
    sinx = sin(x[count]);
    psir[count] = (-2 * x[count] * cosx - sinx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
    psii[count] = (2 * x[count] * sinx - cosx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cgau1>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %rax,0x28(%rsp)
  lea    0x38(%rsp),%r15
  lea    0x30(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%rbx,%rbp,8),%xmm0
  mov    %r14,%rsi
  mov    %r15,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D14(%rip),%xmm1
  movsd  0x30(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm3
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  movsd  %xmm2,0x20(%rsp)
  xorpd  D1(%rip),%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  mulsd  %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm4,%xmm4
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  cvtsi2sd %eax,%xmm4
  movsd  0x20(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm0
  divsd  %xmm4,%xmm1
  movsd  %xmm1,(%r12,%rbp,8)
  movsd  (%rbx,%rbp,8),%xmm1
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%edi
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%r13,%rbp,8)
  add    $0x1,%rbp
  cmp    %rbp,0x28(%rsp)
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L4:
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type_infered: byte[8]
name: unpack_data
arguments: label: D1
type_infered: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void cgau1(double *x, int sigInLength, double *psir, double *psii, int sigOutLength, double ys) {
  int count;
  double x2, cosx, sinx;
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    cosx = cos(x[count]);
    sinx = sin(x[count]);
    psir[count] = (-2 * x[count] * cosx - sinx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
    psii[count] = (2 * x[count] * sinx - cosx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cgau1>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %rax,0x28(%rsp)
  lea    0x38(%rsp),%r15
  lea    0x30(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L10:
  movsd  (%rbx,%rbp,8),%xmm0
  mov    %r14,%rsi
  mov    %r15,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D6(%rip),%xmm1
  movsd  0x30(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm3
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  movsd  %xmm2,0x20(%rsp)
  xorpd  D8(%rip),%xmm0
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  mulsd  %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm4,%xmm4
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  cvtsi2sd %eax,%xmm4
  movsd  0x20(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm0
  divsd  %xmm4,%xmm1
  movsd  %xmm1,(%r12,%rbp,8)
  movsd  (%rbx,%rbp,8),%xmm1
  addsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%edi
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sqrt@plt>
  lea    (%rax,%rax,1),%edi
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%r13,%rbp,8)
  add    $0x1,%rbp
  cmp    %rbp,0x28(%rsp)
  jne    L10
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L4:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D8
type_guessed: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void cgau1(double *x, int sigInLength, double *psir, double *psii, int sigOutLength, double ys) {
  int count;
  double x2, cosx, sinx;
  for (count = 0; count < sigInLength; count++) {
    x2 = x[count] * x[count];
    cosx = cos(x[count]);
    sinx = sin(x[count]);
    psir[count] = (-2 * x[count] * cosx - sinx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
    psii[count] = (2 * x[count] * sinx - cosx) * exp(-x2) / sqrt(2 * sqrt(3.1415926535897931159980 / 2));
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ChkMurMur3>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %edx,%esi
  lea    0x3(%r9),%edi
  test   %r9d,%r9d
  cmovns %r9d,%edi
  sar    $0x2,%edi
  cmp    $0x3,%r9d
  jle    L29
  mov    $0x0,%ecx
L52:
  imul   $0xcc9e2d51,(%r8,%rcx,4),%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  sar    $0x11,%edx
  or     %edx,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %esi,%eax
  mov    %eax,%edx
  shl    $0xd,%edx
  sar    $0x13,%eax
  or     %edx,%eax
  lea    -0x19ab949c(%rax,%rax,4),%esi
  add    $0x1,%rcx
  cmp    %ecx,%edi
  jg     L52
L29:
  shl    $0x2,%edi
  movslq %edi,%rdi
  lea    (%r8,%rdi,4),%rdx
  mov    %r9d,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L61
  cmp    $0x3,%eax
  je     L47
  cmp    $0x1,%eax
  jne    L57
  mov    $0x0,%eax
  jmp    L43
L47:
  mov    0x8(%rdx),%ecx
  shl    $0x10,%ecx
L60:
  mov    0x4(%rdx),%eax
  shl    $0x8,%eax
  xor    %ecx,%eax
L43:
  xor    (%rdx),%eax
  imul   $0xcc9e2d51,%eax,%eax
  mov    %eax,%edx
  shl    $0xf,%edx
  sar    $0x11,%eax
  or     %edx,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %eax,%esi
L57:
  xor    %r9d,%esi
  mov    %esi,%eax
  sar    $0x10,%eax
  xor    %esi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
L61:
  mov    $0x0,%ecx
  jmp    L60
```

assistant: ```c
uint32_t ChkMurMur3(const void *buf, uint32_t len, uint32_t seed) {
  static const uint32_t c1 = 0xcc9e2d51;
  static const uint32_t c2 = 0x1b873593;
  static const uint32_t r1 = 15;
  static const uint32_t r2 = 13;
  static const uint32_t m = 5;
  static const uint32_t n = 0xe6546b64;
  const uint8_t *tail;
  uint32_t hash = seed, k, k1;
  const int nblocks = len / 4;
  const uint32_t *blocks = (const uint32_t *)buf;
  int i;
  for (i = 0; i < nblocks; i++) {
    k = blocks[i];
    k *= c1;
    k = (k << r1) | (k >> (32 - r1));
    k *= c2;
    hash ^= k;
    hash = ((hash << r2) | (hash >> (32 - r2))) * m + n;
  }
  tail = (const uint8_t *)(((const uint8_t *)buf) + nblocks * 4);
  k1 = 0;
  switch (len & 3) {
  case 3:
    k1 ^= tail[2] << 16;
  case 2:
    k1 ^= tail[1] << 8;
  case 1:
    k1 ^= tail[0];
    k1 *= c1;
    k1 = (k1 << r1) | (k1 >> (32 - r1));
    k1 *= c2;
    hash ^= k1;
  }
  hash ^= len;
  hash ^= (hash >> 16);
  hash *= 0x85ebca6b;
  hash ^= (hash >> 13);
  hash *= 0xc2b2ae35;
  hash ^= (hash >> 16);
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<ChkMurMur3>:
  endbr64
  mov    %esi,%r9d
  mov    %rdi,%r8
  mov    %edx,%esi
  test   %r9d,%r9d
  lea    0x3(%r9),%edi
  cmovns %r9d,%edi
  sar    $0x2,%edi
  cmp    $0x3,%r9d
  jle    L67
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L72:
  imul   $0xcc9e2d51,(%r8,%rcx,4),%edx
  add    $0x1,%rcx
  mov    %edx,%eax
  sar    $0x11,%edx
  shl    $0xf,%eax
  or     %edx,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %esi,%eax
  mov    %eax,%edx
  sar    $0x13,%eax
  shl    $0xd,%edx
  or     %edx,%eax
  lea    -0x19ab949c(%rax,%rax,4),%esi
  cmp    %ecx,%edi
  jg     L72
L67:
  shl    $0x2,%edi
  mov    %r9d,%eax
  movslq %edi,%rdi
  and    $0x3,%eax
  lea    (%r8,%rdi,4),%rdx
  cmp    $0x2,%eax
  je     L55
  cmp    $0x3,%eax
  je     L73
  cmp    $0x1,%eax
  je     L6
L63:
  xor    %r9d,%esi
  mov    %esi,%eax
  sar    $0x10,%eax
  xor    %esi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
  nop
L6:
  xor    %eax,%eax
L37:
  xor    (%rdx),%eax
  imul   $0xcc9e2d51,%eax,%eax
  mov    %eax,%edx
  sar    $0x11,%eax
  shl    $0xf,%edx
  or     %edx,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %eax,%esi
  jmp    L63
  xchg   %ax,%ax
L73:
  mov    0x8(%rdx),%ecx
  shl    $0x10,%ecx
L48:
  mov    0x4(%rdx),%eax
  shl    $0x8,%eax
  xor    %ecx,%eax
  jmp    L37
L55:
  xor    %ecx,%ecx
  jmp    L48
```

assistant: ```c
uint32_t ChkMurMur3(const void *buf, uint32_t len, uint32_t seed) {
  static const uint32_t c1 = 0xcc9e2d51;
  static const uint32_t c2 = 0x1b873593;
  static const uint32_t r1 = 15;
  static const uint32_t r2 = 13;
  static const uint32_t m = 5;
  static const uint32_t n = 0xe6546b64;
  const uint8_t *tail;
  uint32_t hash = seed, k, k1;
  const int nblocks = len / 4;
  const uint32_t *blocks = (const uint32_t *)buf;
  int i;
  for (i = 0; i < nblocks; i++) {
    k = blocks[i];
    k *= c1;
    k = (k << r1) | (k >> (32 - r1));
    k *= c2;
    hash ^= k;
    hash = ((hash << r2) | (hash >> (32 - r2))) * m + n;
  }
  tail = (const uint8_t *)(((const uint8_t *)buf) + nblocks * 4);
  k1 = 0;
  switch (len & 3) {
  case 3:
    k1 ^= tail[2] << 16;
  case 2:
    k1 ^= tail[1] << 8;
  case 1:
    k1 ^= tail[0];
    k1 *= c1;
    k1 = (k1 << r1) | (k1 >> (32 - r1));
    k1 *= c2;
    hash ^= k1;
  }
  hash ^= len;
  hash ^= (hash >> 16);
  hash *= 0x85ebca6b;
  hash ^= (hash >> 13);
  hash *= 0xc2b2ae35;
  hash ^= (hash >> 16);
  return hash;
}
```