ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GPMCECCSizeValSet>:
  endbr64
  test   %esi,%esi
  jne    L4
  mov    0x1fc(%edi),%ecx
  shl    $0xc,%edx
  and    $0xff000,%edx
  and    $0xfff00fff,%ecx
  mov    %ecx,0x1fc(%edi)
  mov    0x1fc(%edi),%ecx
  or     %ecx,%edx
  mov    %edx,0x1fc(%edi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  cmp    $0x1,%esi
  je     L5
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x1fc(%edi),%ecx
  shl    $0x16,%edx
  and    $0x3fc00000,%edx
  and    $0xc03fffff,%ecx
  mov    %ecx,0x1fc(%edi)
  mov    0x1fc(%edi),%ecx
  or     %ecx,%edx
  mov    %edx,0x1fc(%edi)
  ret
```

assistant: ```c
void GPMCECCSizeValSet(unsigned int baseAddr, unsigned int eccSize, unsigned int eccSizeVal) {
  if (eccSize == (0)) {
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) &= ~(0x000FF000u);
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) |= ((eccSizeVal << (0x0000000Cu)) & (0x000FF000u));
  } else if (eccSize == (1)) {
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) &= ~(0x3FC00000u);
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) |= ((eccSizeVal << (0x00000016u)) & (0x3FC00000u));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GPMCECCSizeValSet>:
  endbr64
  test   %esi,%esi
  jne    L6
  mov    0x1fc(%edi),%ecx
  shl    $0xc,%edx
  and    $0xff000,%edx
  and    $0xfff00fff,%ecx
  mov    %ecx,0x1fc(%edi)
  mov    0x1fc(%edi),%ecx
  or     %ecx,%edx
  mov    %edx,0x1fc(%edi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  cmp    $0x1,%esi
  je     L5
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x1fc(%edi),%ecx
  shl    $0x16,%edx
  and    $0x3fc00000,%edx
  and    $0xc03fffff,%ecx
  mov    %ecx,0x1fc(%edi)
  mov    0x1fc(%edi),%ecx
  or     %ecx,%edx
  mov    %edx,0x1fc(%edi)
  ret
```

assistant: ```c
void GPMCECCSizeValSet(unsigned int baseAddr, unsigned int eccSize, unsigned int eccSizeVal) {
  if (eccSize == (0)) {
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) &= ~(0x000FF000u);
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) |= ((eccSizeVal << (0x0000000Cu)) & (0x000FF000u));
  } else if (eccSize == (1)) {
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) &= ~(0x3FC00000u);
    (*((volatile unsigned int *)(baseAddr + (0x1FC)))) |= ((eccSizeVal << (0x00000016u)) & (0x3FC00000u));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_task1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: thread 1 returning


assistant: ```c
void *thread_task1(void *arg) {
  printf("thread 1 returning\n");
  return (void *)5;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<thread_task1>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: thread 1 returning


assistant: ```c
void *thread_task1(void *arg) {
  printf("thread 1 returning\n");
  return (void *)5;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<thread_task1>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: thread 1 returning


assistant: ```c
void *thread_task1(void *arg) {
  printf("thread 1 returning\n");
  return (void *)5;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_task1>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: thread 1 returning


assistant: ```c
void *thread_task1(void *arg) {
  printf("thread 1 returning\n");
  return (void *)5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encode_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x7fff,-0x14(%rbp)
  jbe    L8
  mov    $0x1,%esi
  mov    $0x6,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x4,(%rax)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L28
L8:
  cmpl   $0x7f,-0x14(%rbp)
  jbe    L10
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x2,(%rax)
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L28
L10:
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
L28:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *encode_integer(unsigned int value) {
  unsigned char *integer_string = NULL;
  if (value > 32767) {
    integer_string = (unsigned char *)calloc(6, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x04;
    integer_string[2] = (unsigned char)(value >> 24);
    integer_string[3] = (unsigned char)(value >> 16);
    integer_string[4] = (unsigned char)(value >> 8);
    integer_string[5] = (unsigned char)(value);
  } else if (value > 127) {
    integer_string = (unsigned char *)calloc(4, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x02;
    integer_string[2] = (unsigned char)(value >> 8);
    integer_string[3] = (unsigned char)(value);
  } else {
    integer_string = (unsigned char *)calloc(3, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x01;
    integer_string[2] = (unsigned char)(value);
  }
  return integer_string;
}
```
user: What is the c source code of the assembly code below?

```asm
<encode_integer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x7fff,%edi
  ja     L31
  cmp    $0x7f,%edi
  jbe    L6
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  movb   $0x2,(%rax)
  movb   $0x2,0x1(%rax)
  movzbl %bh,%ecx
  mov    %cl,0x2(%rax)
  mov    %bl,0x3(%rax)
L19:
  pop    %rbx
  ret
L31:
  mov    $0x1,%esi
  mov    $0x6,%edi
  call   <calloc@plt>
  movb   $0x2,(%rax)
  movb   $0x4,0x1(%rax)
  mov    %ebx,%edx
  shr    $0x18,%edx
  mov    %dl,0x2(%rax)
  mov    %ebx,%edx
  shr    $0x10,%edx
  mov    %dl,0x3(%rax)
  movzbl %bh,%ecx
  mov    %cl,0x4(%rax)
  mov    %bl,0x5(%rax)
  jmp    L19
L6:
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <calloc@plt>
  movb   $0x2,(%rax)
  movb   $0x1,0x1(%rax)
  mov    %bl,0x2(%rax)
  jmp    L19
```

assistant: ```c
unsigned char *encode_integer(unsigned int value) {
  unsigned char *integer_string = NULL;
  if (value > 32767) {
    integer_string = (unsigned char *)calloc(6, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x04;
    integer_string[2] = (unsigned char)(value >> 24);
    integer_string[3] = (unsigned char)(value >> 16);
    integer_string[4] = (unsigned char)(value >> 8);
    integer_string[5] = (unsigned char)(value);
  } else if (value > 127) {
    integer_string = (unsigned char *)calloc(4, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x02;
    integer_string[2] = (unsigned char)(value >> 8);
    integer_string[3] = (unsigned char)(value);
  } else {
    integer_string = (unsigned char *)calloc(3, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x01;
    integer_string[2] = (unsigned char)(value);
  }
  return integer_string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encode_integer>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    %edi,%ebx
  cmp    $0x7fff,%edi
  ja     L12
  cmp    $0x7f,%edi
  jbe    L7
  mov    $0x4,%edi
  rol    $0x8,%bx
  call   <calloc@plt>
  mov    $0x202,%ecx
  mov    %cx,(%rax)
  mov    %bx,0x2(%rax)
  pop    %rbx
  ret
  nopl   (%rax)
L7:
  mov    $0x3,%edi
  call   <calloc@plt>
  mov    $0x102,%edx
  mov    %dx,(%rax)
  mov    %bl,0x2(%rax)
  pop    %rbx
  ret
  nop
L12:
  mov    $0x6,%edi
  bswap  %ebx
  call   <calloc@plt>
  mov    $0x402,%esi
  mov    %si,(%rax)
  mov    %ebx,0x2(%rax)
  pop    %rbx
  ret
```

assistant: ```c
unsigned char *encode_integer(unsigned int value) {
  unsigned char *integer_string = NULL;
  if (value > 32767) {
    integer_string = (unsigned char *)calloc(6, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x04;
    integer_string[2] = (unsigned char)(value >> 24);
    integer_string[3] = (unsigned char)(value >> 16);
    integer_string[4] = (unsigned char)(value >> 8);
    integer_string[5] = (unsigned char)(value);
  } else if (value > 127) {
    integer_string = (unsigned char *)calloc(4, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x02;
    integer_string[2] = (unsigned char)(value >> 8);
    integer_string[3] = (unsigned char)(value);
  } else {
    integer_string = (unsigned char *)calloc(3, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x01;
    integer_string[2] = (unsigned char)(value);
  }
  return integer_string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<encode_integer>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  mov    %edi,%ebx
  cmp    $0x7fff,%edi
  ja     L11
  cmp    $0x7f,%edi
  jbe    L14
  mov    $0x4,%edi
  rol    $0x8,%bx
  call   <calloc@plt>
  mov    $0x202,%ecx
  mov    %cx,(%rax)
  mov    %bx,0x2(%rax)
  pop    %rbx
  ret
  nopl   (%rax)
L14:
  mov    $0x3,%edi
  call   <calloc@plt>
  mov    $0x102,%edx
  mov    %dx,(%rax)
  mov    %bl,0x2(%rax)
  pop    %rbx
  ret
  nop
L11:
  mov    $0x6,%edi
  bswap  %ebx
  call   <calloc@plt>
  mov    $0x402,%esi
  mov    %si,(%rax)
  mov    %ebx,0x2(%rax)
  pop    %rbx
  ret
```

assistant: ```c
unsigned char *encode_integer(unsigned int value) {
  unsigned char *integer_string = NULL;
  if (value > 32767) {
    integer_string = (unsigned char *)calloc(6, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x04;
    integer_string[2] = (unsigned char)(value >> 24);
    integer_string[3] = (unsigned char)(value >> 16);
    integer_string[4] = (unsigned char)(value >> 8);
    integer_string[5] = (unsigned char)(value);
  } else if (value > 127) {
    integer_string = (unsigned char *)calloc(4, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x02;
    integer_string[2] = (unsigned char)(value >> 8);
    integer_string[3] = (unsigned char)(value);
  } else {
    integer_string = (unsigned char *)calloc(3, sizeof(unsigned char));
    integer_string[0] = 0x02;
    integer_string[1] = 0x01;
    integer_string[2] = (unsigned char)(value);
  }
  return integer_string;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void test(void) {
  clock_t clock_ticks;
  clock_ticks = clock();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test(void) {
  clock_t clock_ticks;
  clock_ticks = clock();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <clock@plt>
```

assistant: ```c
void test(void) {
  clock_t clock_ticks;
  clock_ticks = clock();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <clock@plt>
```

assistant: ```c
void test(void) {
  clock_t clock_ticks;
  clock_ticks = clock();
}
```
user: Translate the below assembly code into C programming language:

```asm
<d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int d(int v) {
  int z = v;
  return z;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int d(int v) {
  int z = v;
  return z;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int d(int v) {
  int z = v;
  return z;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<d>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int d(int v) {
  int z = v;
  return z;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LZ4_compress_limitedOutput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpl   $0x1000a,-0x14(%rbp)
  jg     L7
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <LZ4_compress64kCtx@plt>
  jmp    L16
L7:
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <LZ4_compressCtx@plt>
L16:
  leave
  ret
```

assistant: ```c
int LZ4_compress_limitedOutput(const char *source, char *dest, int isize, int maxOutputSize) {
  if (isize < (int)((1 << 16) + ((8 + 4) - 1)))
    return LZ4_compress64kCtx(NULL, source, dest, isize, maxOutputSize);
  return LZ4_compressCtx(NULL, source, dest, isize, maxOutputSize);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LZ4_compress_limitedOutput>:
  endbr64
  sub    $0x8,%rsp
  mov    %ecx,%r8d
  cmp    $0x1000a,%edx
  jle    L10
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <LZ4_compressCtx@plt>
L2:
  add    $0x8,%rsp
  ret
L10:
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    $0x0,%edi
  call   <LZ4_compress64kCtx@plt>
  jmp    L2
```

assistant: ```c
int LZ4_compress_limitedOutput(const char *source, char *dest, int isize, int maxOutputSize) {
  if (isize < (int)((1 << 16) + ((8 + 4) - 1)))
    return LZ4_compress64kCtx(NULL, source, dest, isize, maxOutputSize);
  return LZ4_compressCtx(NULL, source, dest, isize, maxOutputSize);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LZ4_compress_limitedOutput>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  xor    %edi,%edi
  cmp    $0x1000a,%r9d
  jle    L6
  jmp    1060 <LZ4_compressCtx@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  jmp    1070 <LZ4_compress64kCtx@plt>
```

assistant: ```c
int LZ4_compress_limitedOutput(const char *source, char *dest, int isize, int maxOutputSize) {
  if (isize < (int)((1 << 16) + ((8 + 4) - 1)))
    return LZ4_compress64kCtx(NULL, source, dest, isize, maxOutputSize);
  return LZ4_compressCtx(NULL, source, dest, isize, maxOutputSize);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LZ4_compress_limitedOutput>:
  endbr64
  mov    %edx,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  xor    %edi,%edi
  cmp    $0x1000a,%r9d
  jle    L0
  jmp    1060 <LZ4_compressCtx@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  jmp    1070 <LZ4_compress64kCtx@plt>
```

assistant: ```c
int LZ4_compress_limitedOutput(const char *source, char *dest, int isize, int maxOutputSize) {
  if (isize < (int)((1 << 16) + ((8 + 4) - 1)))
    return LZ4_compress64kCtx(NULL, source, dest, isize, maxOutputSize);
  return LZ4_compressCtx(NULL, source, dest, isize, maxOutputSize);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mtime_e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  0x8(%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: f64
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: D6: 1000

tool: D20: %s%lfms


assistant: ```c
void mtime_e(struct timeval *tvs, char *printme) {
  struct timeval tve;
  double elapsedTime;
  gettimeofday(&tve, NULL);
  elapsedTime = (tve.tv_sec - (*tvs).tv_sec) * 1000.0;
  elapsedTime += (tve.tv_usec - (*tvs).tv_usec) / 1000.0;
  printf("%s%lfms\n", printme, elapsedTime);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mtime_e>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  (%rsp),%xmm1
  subsd  (%rbx),%xmm1
  movsd  D14(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  0x8(%rbx),%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
type_guessed: f64
name: unpack_data
arguments: label: D11
type_guessed: string

tool: D14: 1000

tool: D11: %s%lfms


assistant: ```c
void mtime_e(struct timeval *tvs, char *printme) {
  struct timeval tve;
  double elapsedTime;
  gettimeofday(&tve, NULL);
  elapsedTime = (tve.tv_sec - (*tvs).tv_sec) * 1000.0;
  elapsedTime += (tve.tv_usec - (*tvs).tv_usec) / 1000.0;
  printf("%s%lfms\n", printme, elapsedTime);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mtime_e>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  0x8(%rbx),%xmm0
  mov    %rbp,%rsi
  movsd  D0(%rip),%xmm2
  movsd  (%rsp),%xmm1
  lea    D15(%rip),%rdi
  subsd  (%rbx),%xmm1
  divsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: f64
name: parse_data
arguments: tag: D15
type_infered: string

tool: D0: 1000

tool: D15: %s%lfms


assistant: ```c
void mtime_e(struct timeval *tvs, char *printme) {
  struct timeval tve;
  double elapsedTime;
  gettimeofday(&tve, NULL);
  elapsedTime = (tve.tv_sec - (*tvs).tv_sec) * 1000.0;
  elapsedTime += (tve.tv_usec - (*tvs).tv_usec) / 1000.0;
  printf("%s%lfms\n", printme, elapsedTime);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mtime_e>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  0x8(%rbx),%xmm0
  mov    %rbp,%rsi
  movsd  D16(%rip),%xmm2
  movsd  (%rsp),%xmm1
  lea    D8(%rip),%rdi
  subsd  (%rbx),%xmm1
  divsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: f64
name: retrieve_data
arguments: tag: D8
type: string

tool: D16: 1000

tool: D8: %s%lfms


assistant: ```c
void mtime_e(struct timeval *tvs, char *printme) {
  struct timeval tve;
  double elapsedTime;
  gettimeofday(&tve, NULL);
  elapsedTime = (tve.tv_sec - (*tvs).tv_sec) * 1000.0;
  elapsedTime += (tve.tv_usec - (*tvs).tv_usec) / 1000.0;
  printf("%s%lfms\n", printme, elapsedTime);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L42:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L42
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L26
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D59(%rip),%r13
  lea    D51(%rip),%r12
L102:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L102
L26:
  lea    -0x1(%rax),%edi
  test   %edi,%edi
  jle    L45
  lea    0x14(%rsp),%r8
  jmp    L131
L92:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L37
L113:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L92
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L92
L37:
  sub    $0x1,%edi
  je     L45
L131:
  test   %edi,%edi
  jle    L37
  lea    0x10(%rsp),%rax
  lea    -0x1(%rdi),%edx
  lea    (%r8,%rdx,4),%rsi
  jmp    L113
L45:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L44
  mov    $0x0,%ebx
  lea    D46(%rip),%rbp
L39:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L39
L44:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D51
type_guessed: string
name: retrieve_data
arguments: label: D59
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D46
type_guessed: string

tool: D12: Enter the no. of numbers to be sorted :

tool: D51: %d

tool: D59: Enter Elements:

tool: D27: 
The sorted numbers are :

tool: D46: %d 

assistant: ```c
int main() {
  int a[10000], i, j, n, t;
  printf("Enter the no. of numbers to be sorted :");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    printf("Enter Elements:");
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - i - 1; j++) {
      if (a[j] > a[j + 1]) {
        t = a[j];
        a[j] = a[j + 1];
        a[j + 1] = t;
      }
    }
  }
  printf("\nThe sorted numbers are :");
  for (i = 0; i < n; i++) {
    printf("%d ", a[i]);
  }
  return 0;
}
```