ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<MakeHillFormulaString>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  test   %rdi,%rdi
  je     L38
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %rcx,%rbp
  cmpl   $0x0,(%rcx)
  je     L42
L38:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    %r13d,%eax
  jl     L5
  orl    $0x1,0x0(%rbp)
  lea    0x1(%r13),%r12d
  jmp    L38
L5:
  lea    0x1(%rax),%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L38
```

assistant: ```c
int MakeHillFormulaString(char *szHillFormula, char *szLinearCT, int nLen_szLinearCT, int *bOverflow) {
  int nLen;
  if (szHillFormula && !*bOverflow) {
    if (nLen_szLinearCT > (nLen = strlen(szHillFormula))) {
      memcpy(szLinearCT, szHillFormula, nLen + 1);
      return nLen;
    }
    *bOverflow |= 1;
    return nLen_szLinearCT + 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MakeHillFormulaString>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L7
  mov    (%rcx),%eax
  mov    %rcx,%rbx
  test   %eax,%eax
  je     L35
L7:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L35:
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %edx,%r12d
  call   <strlen@plt>
  mov    %eax,%r13d
  cmp    %r12d,%eax
  jl     L23
  lea    0x1(%r12),%r13d
  orl    $0x1,(%rbx)
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L7
```

assistant: ```c
int MakeHillFormulaString(char *szHillFormula, char *szLinearCT, int nLen_szLinearCT, int *bOverflow) {
  int nLen;
  if (szHillFormula && !*bOverflow) {
    if (nLen_szLinearCT > (nLen = strlen(szHillFormula))) {
      memcpy(szLinearCT, szHillFormula, nLen + 1);
      return nLen;
    }
    *bOverflow |= 1;
    return nLen_szLinearCT + 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MakeHillFormulaString>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L32
  mov    (%rcx),%eax
  mov    %rcx,%rbx
  test   %eax,%eax
  je     L1
L32:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %edx,%r12d
  call   <strlen@plt>
  mov    %eax,%r13d
  cmp    %r12d,%eax
  jl     L39
  lea    0x1(%r12),%r13d
  orl    $0x1,(%rbx)
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L32
```

assistant: ```c
int MakeHillFormulaString(char *szHillFormula, char *szLinearCT, int nLen_szLinearCT, int *bOverflow) {
  int nLen;
  if (szHillFormula && !*bOverflow) {
    if (nLen_szLinearCT > (nLen = strlen(szHillFormula))) {
      memcpy(szLinearCT, szHillFormula, nLen + 1);
      return nLen;
    }
    *bOverflow |= 1;
    return nLen_szLinearCT + 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<___chdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  cmpb   $0x2f,(%rsi)
  je     L73
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L172
  jmp    L36
L73:
  call   <strcpy@plt>
  jmp    L94
L87:
  movzbl 0x1(%rbx),%edx
  test   %dl,%dl
  je     L36
  cmp    $0x2f,%dl
  je     L160
  cmp    $0x2e,%dl
  jne    L96
  movzbl 0x2(%rbx),%edx
  test   %dl,%dl
  je     L125
  cmp    $0x2f,%dl
  jne    L96
L125:
  cmp    %rax,%rbp
  jae    L195
L186:
  cmpb   $0x2f,-0x1(%rax)
  je     L195
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L186
  mov    %rbp,%rax
L195:
  test   %dl,%dl
  jne    L133
L36:
  movb   $0x0,(%rax)
L94:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L160:
  add    $0x2,%rbx
  jmp    L151
L133:
  add    $0x3,%rbx
  jmp    L151
L8:
  mov    %rdx,%rax
L151:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L36
L172:
  cmp    $0x2e,%dl
  je     L87
L96:
  lea    0x1(%rax),%rdx
  movb   $0x2f,(%rax)
  cmpb   $0x2f,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L95
  cmp    $0x2f,%al
  je     L95
L24:
  add    $0x1,%rbx
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L8
  cmp    $0x2f,%al
  jne    L24
  jmp    L8
L95:
  mov    %rdx,%rax
  jmp    L151
```

assistant: ```c
void ___chdir(char *dest, const char *src) {
  if (src[0] == '/') {
    strcpy(dest, src);
    return;
  }
  char *ptr = dest + strlen(dest);
  while (*src) {
    if (src[0] == '.' && src[1] == 0)
      break;
    if (src[0] == '.' && src[1] == '/') {
      ++src;
      ++src;
      continue;
    }
    if (src[0] == '.' && src[1] == '.' && (src[2] == 0 || src[2] == '/')) {
      while (ptr > dest && ptr[-1] != '/')
        --ptr;
      ++src;
      ++src;
      if (*src == 0)
        break;
      ++src;
      continue;
    }
    *ptr++ = '/';
    if (*src == '/')
      ++src;
    while (*src && *src != '/')
      *ptr++ = *src++;
  }
  *ptr = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<___chdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rsi)
  je     L7
  call   <strlen@plt>
  movslq %eax,%rdx
  movzbl 0x0(%rbp),%eax
  add    %r12,%rdx
L31:
  test   %al,%al
  je     L169
  cmp    $0x2e,%al
  je     L77
L53:
  movb   $0x2f,(%rdx)
  movzbl 0x0(%rbp),%eax
  lea    0x1(%rdx),%rcx
  cmp    $0x2f,%al
  je     L203
L33:
  test   %al,%al
  je     L111
  mov    %rcx,%rdx
  jmp    L209
  nopl   0x0(%rax)
L88:
  cmp    $0x2f,%al
  je     L31
L209:
  add    $0x1,%rbp
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L88
L169:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L77:
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L169
  cmp    $0x2f,%al
  je     L63
  cmp    $0x2e,%al
  jne    L53
  movzbl 0x2(%rbp),%eax
  test   %al,%al
  je     L181
  cmp    $0x2f,%al
  jne    L53
L181:
  cmp    %rdx,%r12
  jb     L187
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L94:
  sub    $0x1,%rdx
  cmp    %rdx,%r12
  je     L78
L187:
  cmpb   $0x2f,-0x1(%rdx)
  jne    L94
L78:
  test   %al,%al
  je     L169
  movzbl 0x3(%rbp),%eax
  add    $0x3,%rbp
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L203:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  cmp    $0x2f,%al
  jne    L33
L111:
  mov    %rcx,%rdx
  jmp    L31
L63:
  movzbl 0x2(%rbp),%eax
  add    $0x2,%rbp
  jmp    L31
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1060 <strcpy@plt>
```

assistant: ```c
void ___chdir(char *dest, const char *src) {
  if (src[0] == '/') {
    strcpy(dest, src);
    return;
  }
  char *ptr = dest + strlen(dest);
  while (*src) {
    if (src[0] == '.' && src[1] == 0)
      break;
    if (src[0] == '.' && src[1] == '/') {
      ++src;
      ++src;
      continue;
    }
    if (src[0] == '.' && src[1] == '.' && (src[2] == 0 || src[2] == '/')) {
      while (ptr > dest && ptr[-1] != '/')
        --ptr;
      ++src;
      ++src;
      if (*src == 0)
        break;
      ++src;
      continue;
    }
    *ptr++ = '/';
    if (*src == '/')
      ++src;
    while (*src && *src != '/')
      *ptr++ = *src++;
  }
  *ptr = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<___chdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2f,(%rsi)
  je     L42
  call   <strlen@plt>
  movslq %eax,%rdx
  movzbl 0x0(%rbp),%eax
  add    %r12,%rdx
L112:
  test   %al,%al
  je     L87
  cmp    $0x2e,%al
  je     L147
L53:
  movb   $0x2f,(%rdx)
  movzbl 0x0(%rbp),%eax
  lea    0x1(%rdx),%rcx
  cmp    $0x2f,%al
  je     L140
L49:
  test   %al,%al
  je     L123
  mov    %rcx,%rdx
  jmp    L56
  nopl   0x0(%rax)
L111:
  cmp    $0x2f,%al
  je     L112
L56:
  add    $0x1,%rbp
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L111
L87:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L147:
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L87
  cmp    $0x2f,%al
  je     L124
  cmp    $0x2e,%al
  jne    L53
  movzbl 0x2(%rbp),%eax
  test   %al,%al
  je     L136
  cmp    $0x2f,%al
  jne    L53
L136:
  cmp    %rdx,%r12
  jb     L131
  jmp    L160
  nopl   0x0(%rax,%rax,1)
L34:
  sub    $0x1,%rdx
  cmp    %rdx,%r12
  je     L160
L131:
  cmpb   $0x2f,-0x1(%rdx)
  jne    L34
L160:
  test   %al,%al
  je     L87
  movzbl 0x3(%rbp),%eax
  add    $0x3,%rbp
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L140:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  cmp    $0x2f,%al
  jne    L49
L123:
  mov    %rcx,%rdx
  jmp    L112
L124:
  movzbl 0x2(%rbp),%eax
  add    $0x2,%rbp
  jmp    L112
L42:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1060 <strcpy@plt>
```

assistant: ```c
void ___chdir(char *dest, const char *src) {
  if (src[0] == '/') {
    strcpy(dest, src);
    return;
  }
  char *ptr = dest + strlen(dest);
  while (*src) {
    if (src[0] == '.' && src[1] == 0)
      break;
    if (src[0] == '.' && src[1] == '/') {
      ++src;
      ++src;
      continue;
    }
    if (src[0] == '.' && src[1] == '.' && (src[2] == 0 || src[2] == '/')) {
      while (ptr > dest && ptr[-1] != '/')
        --ptr;
      ++src;
      ++src;
      if (*src == 0)
        break;
      ++src;
      continue;
    }
    *ptr++ = '/';
    if (*src == '/')
      ++src;
    while (*src && *src != '/')
      *ptr++ = *src++;
  }
  *ptr = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mapUnmappedPages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L12:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isPageMapped@plt>
  test   %rax,%rax
  jne    L12
  jmp    L18
L22:
  mov    $0x0,%eax
  call   <palloc@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mapPage@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    $0x0,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  jne    L22
  nop
  nop
  leave
  ret
```

assistant: ```c
void mapUnmappedPages(int *table) {
  int page;
  page = 0;
  while (isPageMapped(table, page))
    page = page + 1;
  while (pavailable()) {
    mapPage(table, page, (int)palloc());
    page = page + 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mapUnmappedPages>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L24
L33:
  add    $0x1,%ebx
L24:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isPageMapped@plt>
  test   %rax,%rax
  jne    L33
  jmp    L11
L27:
  mov    $0x0,%eax
  call   <palloc@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <mapPage@plt>
  add    $0x1,%ebx
L11:
  mov    $0x0,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mapUnmappedPages(int *table) {
  int page;
  page = 0;
  while (isPageMapped(table, page))
    page = page + 1;
  while (pavailable()) {
    mapPage(table, page, (int)palloc());
    page = page + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mapUnmappedPages>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nopl   0x0(%rax)
L9:
  add    $0x1,%ebx
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isPageMapped@plt>
  test   %rax,%rax
  jne    L9
  xor    %eax,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  je     L15
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <palloc@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <mapPage@plt>
  xor    %eax,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  jne    L0
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mapUnmappedPages(int *table) {
  int page;
  page = 0;
  while (isPageMapped(table, page))
    page = page + 1;
  while (pavailable()) {
    mapPage(table, page, (int)palloc());
    page = page + 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mapUnmappedPages>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax)
L10:
  add    $0x1,%ebx
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isPageMapped@plt>
  test   %rax,%rax
  jne    L10
  xor    %eax,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  je     L4
  cs nopw 0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  call   <palloc@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <mapPage@plt>
  xor    %eax,%eax
  call   <pavailable@plt>
  test   %rax,%rax
  jne    L34
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mapUnmappedPages(int *table) {
  int page;
  page = 0;
  while (isPageMapped(table, page))
    page = page + 1;
  while (pavailable()) {
    mapPage(table, page, (int)palloc());
    page = page + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,%edx
  test   $0x10,%al
  je     L18
  movzbl %al,%esi
  shl    $0x10,%esi
  and    $0xff00ffff,%edx
  or     %esi,%edx
  mov    %eax,%esi
  sar    $0x18,%esi
  mov    %sil,%dl
  shl    $0x8,%eax
  and    $0xff000000,%eax
  and    $0xffffff,%edx
  or     %eax,%edx
L0:
  sub    $0x50cd53c7,%edx
  mov    %edx,(%rcx)
  ret
L18:
  mov    %eax,%esi
  shl    $0x8,%esi
  sar    $0x18,%esi
  mov    %sil,%dl
  movzbl %al,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %eax,%edx
  jmp    L0
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  unsigned short copy14;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        copy11 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy12 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        copy13 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy14 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    } else {
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy17;
    }
    output[0UL] = state[0UL] - 1355633607U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  imul   $0x9f65fb16,(%rdi),%edx
  mov    %rsi,%rcx
  sub    $0x1a4602e4,%edx
  mov    %edx,%esi
  mov    %edx,%eax
  shl    $0x8,%esi
  sar    $0x18,%esi
  test   $0x10,%al
  je     L2
  movzbl %dl,%edi
  and    $0xff00ffff,%eax
  sar    $0x18,%edx
  shl    $0x10,%edi
  shl    $0x18,%esi
  or     %edi,%eax
  mov    %dl,%al
  and    $0xffffff,%eax
  or     %esi,%eax
  sub    $0x50cd53c7,%eax
  mov    %eax,(%rcx)
  ret
  nopl   (%rax)
L2:
  mov    %sil,%al
  movzbl %dl,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  sub    $0x50cd53c7,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  unsigned short copy14;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        copy11 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy12 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        copy13 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy14 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    } else {
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy17;
    }
    output[0UL] = state[0UL] - 1355633607U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,%ecx
  mov    %eax,%edx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %ecx,%edi
  test   $0x10,%al
  je     L3
  shl    $0x18,%ecx
  and    $0xffffff,%edx
  mov    %eax,%edi
  or     %ecx,%edx
  shr    $0x18,%edi
L3:
  mov    %dil,%dl
  movzbl %al,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %eax,%edx
  sub    $0x50cd53c7,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  unsigned short copy14;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    if (state[0UL] & 1U) {
      if (state[0UL] & 1U) {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        copy11 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy12 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      } else {
        copy13 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy14 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 4U) & 1U) {
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy16 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    } else {
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy17;
    }
    output[0UL] = state[0UL] - 1355633607U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<buf_set_uint32_le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  shr    $0x18,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void buf_set_uint32_le(void *buf, unsigned long addr, unsigned long val) {
  unsigned char *tmp = (unsigned char *)buf + addr;
  tmp[0] = val & 0xff;
  tmp[1] = (val >> 8) & 0xff;
  tmp[2] = (val >> 16) & 0xff;
  tmp[3] = (val >> 24) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<buf_set_uint32_le>:
  endbr64
  add    %rsi,%rdi
  mov    %dl,(%rdi)
  movzbl %dh,%eax
  mov    %al,0x1(%rdi)
  mov    %rdx,%rax
  shr    $0x10,%rax
  mov    %al,0x2(%rdi)
  shr    $0x18,%rdx
  mov    %dl,0x3(%rdi)
  ret
```

assistant: ```c
void buf_set_uint32_le(void *buf, unsigned long addr, unsigned long val) {
  unsigned char *tmp = (unsigned char *)buf + addr;
  tmp[0] = val & 0xff;
  tmp[1] = (val >> 8) & 0xff;
  tmp[2] = (val >> 16) & 0xff;
  tmp[3] = (val >> 24) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<buf_set_uint32_le>:
  endbr64
  mov    %edx,(%rdi,%rsi,1)
  ret
```

assistant: ```c
void buf_set_uint32_le(void *buf, unsigned long addr, unsigned long val) {
  unsigned char *tmp = (unsigned char *)buf + addr;
  tmp[0] = val & 0xff;
  tmp[1] = (val >> 8) & 0xff;
  tmp[2] = (val >> 16) & 0xff;
  tmp[3] = (val >> 24) & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buf_set_uint32_le>:
  endbr64
  mov    %edx,(%rdi,%rsi,1)
  ret
```

assistant: ```c
void buf_set_uint32_le(void *buf, unsigned long addr, unsigned long val) {
  unsigned char *tmp = (unsigned char *)buf + addr;
  tmp[0] = val & 0xff;
  tmp[1] = (val >> 8) & 0xff;
  tmp[2] = (val >> 16) & 0xff;
  tmp[3] = (val >> 24) & 0xff;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getromanv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movsbl -0x14(%rbp),%eax
  test   %eax,%eax
  je     L6
  test   %eax,%eax
  js     L48
  cmp    $0x58,%eax
  jg     L48
  cmp    $0x43,%eax
  jl     L48
  sub    $0x43,%eax
  cmp    $0x15,%eax
  ja     L48
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D6(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x1,-0x4(%rbp)
  jmp    L48
  movl   $0x5,-0x4(%rbp)
  jmp    L48
  movl   $0xa,-0x4(%rbp)
  jmp    L48
  movl   $0x32,-0x4(%rbp)
  jmp    L48
  movl   $0x64,-0x4(%rbp)
  jmp    L48
L6:
  movl   $0x0,-0x4(%rbp)
  nop
L48:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getromanv(char c) {
  int s = 0;
  switch (c) {
  case 'I':
    s = 1;
    break;
  case 'V':
    s = 5;
    break;
  case 'X':
    s = 10;
    break;
  case 'L':
    s = 50;
    break;
  case 'C':
    s = 100;
    break;
  case '\0':
    s = 0;
    break;
  }
  return s;
}
```