ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L9
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D22(%rip),%r12
  lea    D8(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %r14,%rdx
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  mov    0x10(%rsp),%esi
  cmp    %esi,%edi
  mov    %esi,%ecx
  mov    %esi,%eax
  cmovbe %edi,%ecx
  cmovae %edi,%eax
  jmp    L16
  xchg   %ax,%ax
L48:
  mov    %edx,%ecx
L16:
  xor    %edx,%edx
  div    %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L48
  mov    %esi,%eax
  xor    %edx,%edx
  add    $0x1,%ebx
  div    %ecx
  xor    %edx,%edx
  mov    %eax,%esi
  mov    %edi,%eax
  mov    %rbp,%rdi
  div    %ecx
  imul   %eax,%esi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  ja     L46
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D22
type: string
name: retrieve_data
arguments: data_tag: D8
type: string

tool: D11: %u

tool: D22: %u %u

tool: D8: %u


assistant: ```c
int main() {
  unsigned int T, i, l, b;
  unsigned int divisor, dividend, remainder;
  scanf("%u", &T);
  for (i = 0; i < T; i++) {
    scanf("%u %u", &l, &b);
    divisor = (l < b) ? l : b;
    dividend = (l > b) ? l : b;
    do {
      remainder = dividend % divisor;
      dividend = divisor;
      divisor = remainder;
    } while (remainder > 0);
    printf("%u\n", ((l / dividend) * (b / dividend)));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %esi,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %esi,%r9d
  shr    $0x1f,%r9d
  add    %esi,%r9d
  sar    %r9d
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L103:
  cmp    %rdx,%rsp
  je     L179
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L103
L179:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L118
  orq    $0x0,-0x8(%rsp,%rax,1)
L118:
  mov    %rsp,%r11
  test   %r9d,%r9d
  mov    $0x1,%eax
  cmovg  %r9d,%eax
  cmp    %eax,%r8d
  jle    L7
  mov    %r9d,%edx
  mov    $0x1,%esi
  mov    $0x0,%eax
  jmp    L34
L170:
  add    $0x1,%edx
  mov    %r10d,%edi
L60:
  mov    %edi,-0x4(%r11,%rsi,4)
  mov    %esi,%edi
  add    $0x1,%rsi
  cmp    %r9d,%eax
  jge    L0
  cmp    %r8d,%edx
  jge    L0
L34:
  movslq %eax,%rdi
  mov    (%rcx,%rdi,4),%edi
  movslq %edx,%r10
  mov    (%rcx,%r10,4),%r10d
  cmp    %r10d,%edi
  jg     L170
  add    $0x1,%eax
  jmp    L60
L7:
  mov    %r9d,%edx
  mov    $0x0,%edi
  mov    $0x0,%eax
L0:
  cmp    %eax,%r9d
  je     L111
  jle    L52
  cltq
  movslq %edi,%rdi
  sub    %rax,%rdi
  lea    (%r11,%rdi,4),%rsi
L20:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jg     L20
L52:
  test   %r8d,%r8d
  jle    L11
  mov    %r8d,%r8d
  mov    $0x0,%eax
L27:
  mov    (%r11,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
L11:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  leave
  ret
L111:
  cmp    %edx,%r8d
  jle    L52
  movslq %edx,%rdx
  movslq %edi,%rdi
  sub    %rdx,%rdi
  lea    (%r11,%rdi,4),%rsi
L106:
  mov    (%rcx,%rdx,4),%eax
  mov    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r8d
  jg     L106
  jmp    L52
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int vetor[], int tamanho) {
  int meio = tamanho / 2;
  int i = 0, j = meio, k = 0;
  int aux[tamanho];
  while (i < meio && j < tamanho) {
    if (vetor[i] <= vetor[j])
      aux[k] = vetor[i++];
    else
      aux[k] = vetor[j++];
    k++;
  }
  if (i == meio)
    while (j < tamanho)
      aux[k++] = vetor[j++];
  else
    while (i < meio)
      aux[k++] = vetor[i++];
  for (i = 0; i < tamanho; i++)
    vetor[i] = aux[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %r14d,%r8d
  push   %r12
  shr    $0x1f,%r8d
  mov    %rdi,%r12
  push   %rbx
  add    %r14d,%r8d
  mov    %r14,%rbx
  sar    %r8d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r14,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L125
L156:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L156
L125:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L34
L77:
  test   %r8d,%r8d
  mov    $0x1,%eax
  mov    %rsp,%r13
  mov    %r8d,%esi
  cmovg  %r8d,%eax
  cmp    %eax,%ebx
  jle    L78
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L64
  xchg   %ax,%ax
L98:
  add    $0x1,%edx
L153:
  mov    %ecx,-0x4(%r13,%rax,4)
  movslq %eax,%rcx
  add    $0x1,%rax
  cmp    %r8d,%edx
  jge    L130
  cmp    %ebx,%esi
  jge    L130
L64:
  movslq %edx,%rcx
  movslq %esi,%rdi
  mov    (%r12,%rcx,4),%ecx
  mov    (%r12,%rdi,4),%edi
  cmp    %edi,%ecx
  jle    L98
  add    $0x1,%esi
  mov    %edi,%ecx
  jmp    L153
L78:
  xor    %ecx,%ecx
  xor    %edx,%edx
  nopl   (%rax)
L130:
  cmp    %edx,%r8d
  je     L120
  jle    L158
  sub    $0x1,%r8d
  lea    0x0(%r13,%rcx,4),%rdi
  sub    %edx,%r8d
  movslq %edx,%rdx
  lea    0x4(,%r8,4),%r8
  lea    (%r12,%rdx,4),%rsi
  mov    %r8,%rdx
  call   <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L158:
  test   %ebx,%ebx
  jle    L104
  lea    0x0(,%r14,4),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L104:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L120:
  cmp    %esi,%ebx
  jle    L158
  lea    -0x1(%rbx),%eax
  lea    0x0(%r13,%rcx,4),%rdi
  sub    %esi,%eax
  movslq %esi,%rsi
  lea    0x4(,%rax,4),%rdx
  lea    (%r12,%rsi,4),%rsi
  call   <memcpy@plt>
  jmp    L158
  nopl   0x0(%rax)
L34:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L77
L136:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int vetor[], int tamanho) {
  int meio = tamanho / 2;
  int i = 0, j = meio, k = 0;
  int aux[tamanho];
  while (i < meio && j < tamanho) {
    if (vetor[i] <= vetor[j])
      aux[k] = vetor[i++];
    else
      aux[k] = vetor[j++];
    k++;
  }
  if (i == meio)
    while (j < tamanho)
      aux[k++] = vetor[j++];
  else
    while (i < meio)
      aux[k++] = vetor[i++];
  for (i = 0; i < tamanho; i++)
    vetor[i] = aux[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %r14d,%r8d
  push   %r12
  shr    $0x1f,%r8d
  mov    %rdi,%r12
  push   %rbx
  add    %r14d,%r8d
  mov    %r14,%rbx
  sar    %r8d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r14,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L58
L66:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L66
L58:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L179
L160:
  test   %r8d,%r8d
  mov    $0x1,%eax
  mov    %rsp,%r13
  mov    %r8d,%ecx
  cmovg  %r8d,%eax
  cmp    %eax,%ebx
  jle    L74
  mov    $0x1,%eax
  xor    %edx,%edx
  xor    %r10d,%r10d
  movslq %r8d,%r9
  nopw   0x0(%rax,%rax,1)
L92:
  mov    (%r12,%r10,4),%edi
  mov    (%r12,%r9,4),%esi
  cmp    %edi,%esi
  jl     L4
L33:
  mov    %edi,-0x4(%r13,%rax,4)
  movslq %eax,%rsi
  add    $0x1,%edx
  add    $0x1,%rax
  cmp    %ebx,%ecx
  jge    L114
  cmp    %r8d,%edx
  jge    L114
  movslq %edx,%r10
  mov    (%r12,%r9,4),%esi
  mov    (%r12,%r10,4),%edi
  cmp    %edi,%esi
  jge    L33
L4:
  mov    %esi,-0x4(%r13,%rax,4)
  add    $0x1,%ecx
  movslq %eax,%rsi
  add    $0x1,%rax
  cmp    %edx,%r8d
  jle    L114
  cmp    %ebx,%ecx
  jge    L114
  movslq %ecx,%r9
  jmp    L92
L74:
  xor    %esi,%esi
  xor    %edx,%edx
  nopl   0x0(%rax)
L114:
  cmp    %edx,%r8d
  je     L109
  jle    L15
  sub    $0x1,%r8d
  lea    0x0(%r13,%rsi,4),%rdi
  sub    %edx,%r8d
  movslq %edx,%rdx
  lea    0x4(,%r8,4),%r8
  lea    (%r12,%rdx,4),%rsi
  mov    %r8,%rdx
  call   <memcpy@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  test   %ebx,%ebx
  jle    L28
  lea    0x0(,%r14,4),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L28:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L109:
  cmp    %ecx,%ebx
  jle    L15
  lea    -0x1(%rbx),%eax
  lea    0x0(%r13,%rsi,4),%rdi
  sub    %ecx,%eax
  movslq %ecx,%rcx
  lea    0x4(,%rax,4),%rdx
  lea    (%r12,%rcx,4),%rsi
  call   <memcpy@plt>
  jmp    L15
  nopl   0x0(%rax)
L179:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L160
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int vetor[], int tamanho) {
  int meio = tamanho / 2;
  int i = 0, j = meio, k = 0;
  int aux[tamanho];
  while (i < meio && j < tamanho) {
    if (vetor[i] <= vetor[j])
      aux[k] = vetor[i++];
    else
      aux[k] = vetor[j++];
    k++;
  }
  if (i == meio)
    while (j < tamanho)
      aux[k++] = vetor[j++];
  else
    while (i < meio)
      aux[k++] = vetor[i++];
  for (i = 0; i < tamanho; i++)
    vetor[i] = aux[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xor128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0xb,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  sar    $0x13,%eax
  mov    %edx,%ecx
  xor    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t xor128(uint32_t *s) {
  uint32_t x = s[0] ^ (s[0] << 11);
  s[0] = s[1];
  s[1] = s[2];
  s[2] = s[3];
  return s[3] = (s[3] ^ (s[3] >> 19)) ^ (x ^ (x >> 8));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xor128>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  mov    0x4(%rdi),%eax
  mov    %eax,(%rdi)
  mov    0x8(%rdi),%eax
  mov    %eax,0x4(%rdi)
  mov    0xc(%rdi),%ecx
  mov    %ecx,0x8(%rdi)
  mov    %ecx,%eax
  sar    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    $0x8,%edx
  xor    %edx,%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
uint32_t xor128(uint32_t *s) {
  uint32_t x = s[0] ^ (s[0] << 11);
  s[0] = s[1];
  s[1] = s[2];
  s[2] = s[3];
  return s[3] = (s[3] ^ (s[3] >> 19)) ^ (x ^ (x >> 8));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xor128>:
  endbr64
  mov    (%rdi),%eax
  mov    0xc(%rdi),%ecx
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  mov    0x4(%rdi),%eax
  mov    %eax,(%rdi)
  mov    0x8(%rdi),%eax
  mov    %ecx,0x8(%rdi)
  mov    %eax,0x4(%rdi)
  mov    %ecx,%eax
  sar    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    $0x8,%edx
  xor    %edx,%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
uint32_t xor128(uint32_t *s) {
  uint32_t x = s[0] ^ (s[0] << 11);
  s[0] = s[1];
  s[1] = s[2];
  s[2] = s[3];
  return s[3] = (s[3] ^ (s[3] >> 19)) ^ (x ^ (x >> 8));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xor128>:
  endbr64
  mov    (%rdi),%eax
  mov    0xc(%rdi),%ecx
  movd   0x4(%rdi),%xmm0
  movd   0x8(%rdi),%xmm3
  mov    %eax,%edx
  movd   %ecx,%xmm1
  shl    $0xb,%edx
  punpckldq %xmm3,%xmm0
  xor    %eax,%edx
  mov    %ecx,%eax
  sar    $0x13,%eax
  xor    %ecx,%eax
  xor    %edx,%eax
  sar    $0x8,%edx
  xor    %edx,%eax
  movd   %eax,%xmm2
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
uint32_t xor128(uint32_t *s) {
  uint32_t x = s[0] ^ (s[0] << 11);
  s[0] = s[1];
  s[1] = s[2];
  s[2] = s[3];
  return s[3] = (s[3] ^ (s[3] >> 19)) ^ (x ^ (x >> 8));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<thrd_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <thd_join@plt>
  test   %rax,%rax
  je     L12
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L11
L12:
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int thrd_join(thrd_t thr, int *res) {
  void *rv;
  if (thd_join(thr, &rv))
    return thrd_error;
  *res = (int)rv;
  return thrd_success;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<thrd_join>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <thd_join@plt>
  test   %rax,%rax
  jne    L16
  mov    (%rsp),%rax
  mov    %eax,(%rbx)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L27
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int thrd_join(thrd_t thr, int *res) {
  void *rv;
  if (thd_join(thr, &rv))
    return thrd_error;
  *res = (int)rv;
  return thrd_success;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thrd_join>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <thd_join@plt>
  test   %rax,%rax
  jne    L26
  mov    (%rsp),%rax
  mov    %eax,(%rbx)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L26:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L24
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int thrd_join(thrd_t thr, int *res) {
  void *rv;
  if (thd_join(thr, &rv))
    return thrd_error;
  *res = (int)rv;
  return thrd_success;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<thrd_join>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <thd_join@plt>
  test   %rax,%rax
  jne    L1
  mov    (%rsp),%rax
  mov    %eax,(%rbx)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L1:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L26
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int thrd_join(thrd_t thr, int *res) {
  void *rv;
  if (thd_join(thr, &rv))
    return thrd_error;
  *res = (int)rv;
  return thrd_success;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_null_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <mean@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void test_null_array(void) {
  int res;
  assert((mean(NULL, 1, &res) == 1));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_null_array>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <mean@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_null_array(void) {
  int res;
  assert((mean(NULL, 1, &res) == 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_null_array>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <mean@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_null_array(void) {
  int res;
  assert((mean(NULL, 1, &res) == 1));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_null_array>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <mean@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_null_array(void) {
  int res;
  assert((mean(NULL, 1, &res) == 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetDataBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <GetDataBlock_@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int GetDataBlock(FILE *fd, unsigned char *buf) {
  int rv;
  int i;
  rv = GetDataBlock_(fd, buf);
  if (0) {
    printf("[GetDataBlock returning %d", rv);
    if (rv > 0) {
      printf(":");
      for (i = 0; i < rv; i++)
        printf(" %02x", buf[i]);
    }
    printf("]\n");
  }
  return (rv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetDataBlock>:
  endbr64
  sub    $0x8,%rsp
  call   <GetDataBlock_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int GetDataBlock(FILE *fd, unsigned char *buf) {
  int rv;
  int i;
  rv = GetDataBlock_(fd, buf);
  if (0) {
    printf("[GetDataBlock returning %d", rv);
    if (rv > 0) {
      printf(":");
      for (i = 0; i < rv; i++)
        printf(" %02x", buf[i]);
    }
    printf("]\n");
  }
  return (rv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetDataBlock>:
  endbr64
  jmp    1050 <GetDataBlock_@plt>
```

assistant: ```c
int GetDataBlock(FILE *fd, unsigned char *buf) {
  int rv;
  int i;
  rv = GetDataBlock_(fd, buf);
  if (0) {
    printf("[GetDataBlock returning %d", rv);
    if (rv > 0) {
      printf(":");
      for (i = 0; i < rv; i++)
        printf(" %02x", buf[i]);
    }
    printf("]\n");
  }
  return (rv);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GetDataBlock>:
  endbr64
  jmp    1050 <GetDataBlock_@plt>
```

assistant: ```c
int GetDataBlock(FILE *fd, unsigned char *buf) {
  int rv;
  int i;
  rv = GetDataBlock_(fd, buf);
  if (0) {
    printf("[GetDataBlock returning %d", rv);
    if (rv > 0) {
      printf(":");
      for (i = 0; i < rv; i++)
        printf(" %02x", buf[i]);
    }
    printf("]\n");
  }
  return (rv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swapTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L12:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  imul   -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    0x10(%rbp),%esi
  mov    -0x8(%rbp),%edx
  add    %esi,%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L12
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapTable(int *pdata, int dataSize, int partSize, int posX1, int posY1, int posX2, int posY2) {
  int i, j;
  for (i = 0; i < partSize; i++) {
    for (j = 0; j < partSize; j++) {
      *(pdata + (posX2 + j) * dataSize + (posY2 + i)) = *(pdata + (posX1 + i) * dataSize + (posY1 + j));
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<swapTable>:
  endbr64
  mov    %rdi,%r11
  mov    %edx,%eax
  mov    %ecx,%edx
  test   %eax,%eax
  jle    L3
  movslq 0x8(%rsp),%r10
  imul   %esi,%r9d
  movslq %r9d,%rcx
  add    %r10,%rcx
  lea    (%rdi,%rcx,4),%r9
  movslq %esi,%rdi
  shl    $0x2,%rdi
  lea    -0x1(%rax),%ecx
  imul   %esi,%edx
  movslq %edx,%rdx
  movslq %r8d,%r8
  add    %r8,%rdx
  add    %rcx,%rdx
  lea    0x4(%r11,%rdx,4),%rsi
  lea    0x1(%r10,%rcx,1),%r11
  mov    %eax,%eax
  neg    %rax
  lea    0x0(,%rax,4),%r8
L15:
  lea    (%r8,%rsi,1),%rax
  mov    %r9,%rdx
L26:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rax
  add    %rdi,%rdx
  cmp    %rsi,%rax
  jne    L26
  add    $0x4,%r9
  add    $0x1,%r10
  add    %rdi,%rsi
  cmp    %r11,%r10
  jne    L15
L3:
  ret
```

assistant: ```c
void swapTable(int *pdata, int dataSize, int partSize, int posX1, int posY1, int posX2, int posY2) {
  int i, j;
  for (i = 0; i < partSize; i++) {
    for (j = 0; j < partSize; j++) {
      *(pdata + (posX2 + j) * dataSize + (posY2 + i)) = *(pdata + (posX1 + i) * dataSize + (posY1 + j));
    }
  }
}
```