ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movw   $0x150,-0x4(%rbp)
  movw   $0xfeb0,-0x2(%rbp)
  movswl -0x4(%rbp),%edx
  movswl -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movswl -0x2(%rbp),%edx
  movswl -0x2(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movswl -0x4(%rbp),%edx
  movswl -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10052,%ecx
  mov    $0x10052,%edx
  mov    $0x10052,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D31
data_type: string

tool: D14: num as short and unsigned short:%hd %hu


tool: D25: -num as short and unsigned short: %hd %hu


tool: D23: num as int and char:%d %c


tool: D31: WORDS as int,short and char:%d %hd %c


assistant: ```c
int main(int argc, char const *argv[]) {
  short num = 336;
  short mnum = -336;
  printf("num as short and unsigned short:%hd %hu\n", num, num);
  printf("-num as short and unsigned short: %hd %hu\n", mnum, mnum);
  printf("num as int and char:%d %c\n", num, num);
  printf("WORDS as int,short and char:%d %hd %c\n", 65618, 65618, 65618);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x150,%edx
  mov    $0x150,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffeb0,%edx
  mov    $0xfffffeb0,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x150,%edx
  mov    $0x150,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x10052,%ecx
  mov    $0x10052,%edx
  mov    $0x10052,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D36
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D11: num as short and unsigned short:%hd %hu


tool: D4: -num as short and unsigned short: %hd %hu


tool: D36: num as int and char:%d %c


tool: D17: WORDS as int,short and char:%d %hd %c


assistant: ```c
int main(int argc, char const *argv[]) {
  short num = 336;
  short mnum = -336;
  printf("num as short and unsigned short:%hd %hu\n", num, num);
  printf("-num as short and unsigned short: %hd %hu\n", mnum, mnum);
  printf("num as int and char:%d %c\n", num, num);
  printf("WORDS as int,short and char:%d %hd %c\n", 65618, 65618, 65618);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffeb0,%edx
  mov    $0xfffffeb0,%esi
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x10052,%ecx
  xor    %eax,%eax
  mov    $0x10052,%edx
  mov    $0x10052,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: D39: num as short and unsigned short:%hd %hu


tool: D6: -num as short and unsigned short: %hd %hu


tool: D22: num as int and char:%d %c


tool: D28: WORDS as int,short and char:%d %hd %c


assistant: ```c
int main(int argc, char const *argv[]) {
  short num = 336;
  short mnum = -336;
  printf("num as short and unsigned short:%hd %hu\n", num, num);
  printf("-num as short and unsigned short: %hd %hu\n", mnum, mnum);
  printf("num as int and char:%d %c\n", num, num);
  printf("WORDS as int,short and char:%d %hd %c\n", 65618, 65618, 65618);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffeb0,%edx
  mov    $0xfffffeb0,%esi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x150,%edx
  mov    $0x150,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x10052,%ecx
  xor    %eax,%eax
  mov    $0x10052,%edx
  mov    $0x10052,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D20
type_infered: string

tool: D2: num as short and unsigned short:%hd %hu


tool: D4: -num as short and unsigned short: %hd %hu


tool: D19: num as int and char:%d %c


tool: D20: WORDS as int,short and char:%d %hd %c


assistant: ```c
int main(int argc, char const *argv[]) {
  short num = 336;
  short mnum = -336;
  printf("num as short and unsigned short:%hd %hu\n", num, num);
  printf("-num as short and unsigned short: %hd %hu\n", mnum, mnum);
  printf("num as int and char:%d %c\n", num, num);
  printf("WORDS as int,short and char:%d %hd %c\n", 65618, 65618, 65618);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_plugin_detailed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: msoffice - Microsoft Office 2007/2010/2013 plugin
------------------------------------------------
Use this module to crack password-protected MSOffice files
Input should be a MS Office file specified with -f
Known software that uses this password hashing method:
Microsoft Office: 2007, 2010, 2013.

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("msoffice - Microsoft Office 2007/2010/2013 plugin\n"
          "------------------------------------------------\n"
          "Use this module to crack password-protected MSOffice files\n"
          "Input should be a MS Office file specified with -f\n"
          "Known software that uses this password hashing method:\n"
          "Microsoft Office: 2007, 2010, 2013.\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: msoffice - Microsoft Office 2007/2010/2013 plugin
------------------------------------------------
Use this module to crack password-protected MSOffice files
Input should be a MS Office file specified with -f
Known software that uses this password hashing method:
Microsoft Office: 2007, 2010, 2013.

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("msoffice - Microsoft Office 2007/2010/2013 plugin\n"
          "------------------------------------------------\n"
          "Use this module to crack password-protected MSOffice files\n"
          "Input should be a MS Office file specified with -f\n"
          "Known software that uses this password hashing method:\n"
          "Microsoft Office: 2007, 2010, 2013.\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: msoffice - Microsoft Office 2007/2010/2013 plugin
------------------------------------------------
Use this module to crack password-protected MSOffice files
Input should be a MS Office file specified with -f
Known software that uses this password hashing method:
Microsoft Office: 2007, 2010, 2013.

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("msoffice - Microsoft Office 2007/2010/2013 plugin\n"
          "------------------------------------------------\n"
          "Use this module to crack password-protected MSOffice files\n"
          "Input should be a MS Office file specified with -f\n"
          "Known software that uses this password hashing method:\n"
          "Microsoft Office: 2007, 2010, 2013.\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D6(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: msoffice - Microsoft Office 2007/2010/2013 plugin
------------------------------------------------
Use this module to crack password-protected MSOffice files
Input should be a MS Office file specified with -f
Known software that uses this password hashing method:
Microsoft Office: 2007, 2010, 2013.

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("msoffice - Microsoft Office 2007/2010/2013 plugin\n"
          "------------------------------------------------\n"
          "Use this module to crack password-protected MSOffice files\n"
          "Input should be a MS Office file specified with -f\n"
          "Known software that uses this password hashing method:\n"
          "Microsoft Office: 2007, 2010, 2013.\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L3
L24:
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L23
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L22
  movsbl -0x9(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    $0x61,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L3
L22:
  movsbl -0x9(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    $0x41,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L3
L23:
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x9(%rbp)
  mov    D0(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L32
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cmp    $0x1ff,%eax
  jle    L24
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  char c;
  int i = 0, delta = 'F' - 'A';
  while ((c = getchar()) != EOF && i++ < 512) {
    if (isalpha(c))
      islower(c) ? putchar((c + delta - 'a') % 26 + 'a') : putchar((c + delta - 'A') % 26 + 'A');
    else
      putchar(c);
  }
  putchar('\n');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x201,%ebp
  jmp    L7
L5:
  sub    $0x3c,%ebx
  movslq %ebx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebx
  lea    0x41(%rbx),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L7
L51:
  mov    %ebx,%edi
  call   <putchar@plt>
L7:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %al,(%rdx)
  je     L34
  sub    $0x1,%ebp
  je     L34
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L51
  mov    %ebx,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L5
  sub    $0x5c,%ebx
  movslq %ebx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebx
  lea    0x61(%rbx),%edi
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L7
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char c;
  int i = 0, delta = 'F' - 'A';
  while ((c = getchar()) != EOF && i++ < 512) {
    if (isalpha(c))
      islower(c) ? putchar((c + delta - 'a') % 26 + 'a') : putchar((c + delta - 'A') % 26 + 'A');
    else
      putchar(c);
  }
  putchar('\n');
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    D8(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x201,%ebx
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%r12)
  je     L27
L56:
  sub    $0x1,%ebx
  je     L27
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L16
  call   <islower@plt>
  test   %rax,%rax
  je     L13
  sub    $0x5c,%ebp
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebp
  lea    0x61(%rbp),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%r12)
  jne    L56
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  call   <putchar@plt>
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x3c,%ebp
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebp
  lea    0x41(%rbp),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  jmp    L55
```

assistant: ```c
int main() {
  char c;
  int i = 0, delta = 'F' - 'A';
  while ((c = getchar()) != EOF && i++ < 512) {
    if (isalpha(c))
      islower(c) ? putchar((c + delta - 'a') % 26 + 'a') : putchar((c + delta - 'A') % 26 + 'A');
    else
      putchar(c);
  }
  putchar('\n');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    D4(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x201,%ebx
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%r12)
  je     L43
L12:
  sub    $0x1,%ebx
  je     L43
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L52
  call   <islower@plt>
  test   %rax,%rax
  je     L55
  sub    $0x5c,%ebp
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebp
  lea    0x61(%rbp),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%r12)
  jne    L12
L43:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L52:
  call   <putchar@plt>
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L55:
  sub    $0x3c,%ebp
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ebp
  lea    0x41(%rbp),%edi
  movzbl %dil,%edi
  call   <putchar@plt>
  jmp    L9
```

assistant: ```c
int main() {
  char c;
  int i = 0, delta = 'F' - 'A';
  while ((c = getchar()) != EOF && i++ < 512) {
    if (isalpha(c))
      islower(c) ? putchar((c + delta - 'a') % 26 + 'a') : putchar((c + delta - 'A') % 26 + 'A');
    else
      putchar(c);
  }
  putchar('\n');
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Redraw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <lc4_reset_vmem@plt>
  mov    $0x0,%eax
  call   <DrawCursor@plt>
  mov    $0x0,%eax
  call   <DrawMissileCommand@plt>
  mov    $0x0,%eax
  call   <DrawCities@plt>
  mov    $0x0,%eax
  call   <DrawMissiles@plt>
  mov    $0x0,%eax
  call   <DrawMeteors@plt>
  mov    $0x0,%eax
  call   <lc4_blt_vmem@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Redraw() {
  lc4_reset_vmem();
  DrawCursor();
  DrawMissileCommand();
  DrawCities();
  DrawMissiles();
  DrawMeteors();
  lc4_blt_vmem();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Redraw>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lc4_reset_vmem@plt>
  mov    $0x0,%eax
  call   <DrawCursor@plt>
  mov    $0x0,%eax
  call   <DrawMissileCommand@plt>
  mov    $0x0,%eax
  call   <DrawCities@plt>
  mov    $0x0,%eax
  call   <DrawMissiles@plt>
  mov    $0x0,%eax
  call   <DrawMeteors@plt>
  mov    $0x0,%eax
  call   <lc4_blt_vmem@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Redraw() {
  lc4_reset_vmem();
  DrawCursor();
  DrawMissileCommand();
  DrawCities();
  DrawMissiles();
  DrawMeteors();
  lc4_blt_vmem();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Redraw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lc4_reset_vmem@plt>
  xor    %eax,%eax
  call   <DrawCursor@plt>
  xor    %eax,%eax
  call   <DrawMissileCommand@plt>
  xor    %eax,%eax
  call   <DrawCities@plt>
  xor    %eax,%eax
  call   <DrawMissiles@plt>
  xor    %eax,%eax
  call   <DrawMeteors@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <lc4_blt_vmem@plt>
```

assistant: ```c
void Redraw() {
  lc4_reset_vmem();
  DrawCursor();
  DrawMissileCommand();
  DrawCities();
  DrawMissiles();
  DrawMeteors();
  lc4_blt_vmem();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Redraw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lc4_reset_vmem@plt>
  xor    %eax,%eax
  call   <DrawCursor@plt>
  xor    %eax,%eax
  call   <DrawMissileCommand@plt>
  xor    %eax,%eax
  call   <DrawCities@plt>
  xor    %eax,%eax
  call   <DrawMissiles@plt>
  xor    %eax,%eax
  call   <DrawMeteors@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <lc4_blt_vmem@plt>
```

assistant: ```c
void Redraw() {
  lc4_reset_vmem();
  DrawCursor();
  DrawMissileCommand();
  DrawCities();
  DrawMissiles();
  DrawMeteors();
  lc4_blt_vmem();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pokehint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x63,-0x1c(%rbp)
  jle    L10
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%edi
  mov    $0xe,%ecx
  mov    %eax,%esi
  call   <pokech@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x9,-0x1c(%rbp)
  jle    L11
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%edi
  mov    $0xe,%ecx
  mov    %eax,%esi
  call   <pokech@plt>
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  lea    0x30(%rax),%edx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%edi
  mov    $0xe,%ecx
  mov    %eax,%esi
  call   <pokech@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pokehint(int row, int column, int n, int color) {
  int i = 1;
  if (n > 99) {
    pokech(row, column++, '0' + n / 100, 14);
    n %= 100;
    i++;
  }
  if (n > 9) {
    pokech(row, column++, '0' + n / 10, 14);
    n %= 10;
    i++;
  }
  pokech(row, column++, '0' + n, 14);
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pokehint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %edx,%ebx
  mov    $0x1,%ebp
  cmp    $0x63,%edx
  jg     L10
L19:
  cmp    $0x9,%ebx
  jg     L33
L9:
  lea    0x30(%rbx),%edx
  mov    $0xe,%ecx
  mov    %r12d,%edi
  call   <pokech@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  lea    0x1(%rsi),%r13d
  movslq %edx,%rbp
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  lea    0x30(%rbp),%edx
  mov    $0xe,%ecx
  call   <pokech@plt>
  imul   $0x64,%ebp,%ebp
  sub    %ebp,%ebx
  mov    %r13d,%esi
  mov    $0x2,%ebp
  jmp    L19
L33:
  lea    0x1(%rsi),%r13d
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%r14d
  lea    0x30(%rax),%edx
  mov    $0xe,%ecx
  mov    %r12d,%edi
  call   <pokech@plt>
  lea    (%r14,%r14,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x1,%ebp
  mov    %r13d,%esi
  jmp    L9
```

assistant: ```c
int pokehint(int row, int column, int n, int color) {
  int i = 1;
  if (n > 99) {
    pokech(row, column++, '0' + n / 100, 14);
    n %= 100;
    i++;
  }
  if (n > 9) {
    pokech(row, column++, '0' + n / 10, 14);
    n %= 10;
    i++;
  }
  pokech(row, column++, '0' + n, 14);
  return i;
}
```