ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<split_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L7
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L7:
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L20
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int split_words(char *sentence) {
  int i, count = 1, length = strlen(sentence);
  for (i = 0; i < length; i++) {
    if (sentence[i] == ' ') {
      sentence[i] = '\0';
      count++;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split_words>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rax
  mov    $0x1,%ecx
  jmp    L21
L22:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L35
L21:
  cmpb   $0x20,(%rdx)
  jne    L22
  movb   $0x0,(%rdx)
  add    $0x1,%ecx
  jmp    L22
L9:
  mov    $0x1,%ecx
L35:
  mov    %ecx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int split_words(char *sentence) {
  int i, count = 1, length = strlen(sentence);
  for (i = 0; i < length; i++) {
    if (sentence[i] == ' ') {
      sentence[i] = '\0';
      count++;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<split_words>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L21
  sub    $0x1,%eax
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  lea    0x1(%rbx,%rax,1),%rax
  nopw   0x0(%rax,%rax,1)
L18:
  cmpb   $0x20,(%rdi)
  jne    L26
  movb   $0x0,(%rdi)
  add    $0x1,%r8d
L26:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L18
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int split_words(char *sentence) {
  int i, count = 1, length = strlen(sentence);
  for (i = 0; i < length; i++) {
    if (sentence[i] == ' ') {
      sentence[i] = '\0';
      count++;
    }
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split_words>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  sub    $0x1,%eax
  mov    %rbx,%rdi
  mov    $0x1,%r8d
  lea    0x1(%rbx,%rax,1),%rax
  nopw   0x0(%rax,%rax,1)
L22:
  cmpb   $0x20,(%rdi)
  jne    L0
  movb   $0x0,(%rdi)
  add    $0x1,%r8d
L0:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L22
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int split_words(char *sentence) {
  int i, count = 1, length = strlen(sentence);
  for (i = 0; i < length; i++) {
    if (sentence[i] == ' ') {
      sentence[i] = '\0';
      count++;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x1211100f0e0d0c0b,%rax
  movabs $0x605040302011413,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x181716150a090807,%rax
  movabs $0x201f1e1d1c1b1a19,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <condition_reduction@plt>
  mov    %al,-0x31(%rbp)
  cmpb   $0xa,-0x31(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned char a[32] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32};
  unsigned char ret = condition_reduction(a, 16, 32);
  if (ret != 10)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x1211100f0e0d0c0b,%rax
  movabs $0x605040302011413,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x181716150a090807,%rax
  movabs $0x201f1e1d1c1b1a19,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x20,%edx
  mov    $0x10,%esi
  call   <condition_reduction@plt>
  cmp    $0xa,%al
  jne    L11
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L11:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned char a[32] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32};
  unsigned char ret = condition_reduction(a, 16, 32);
  if (ret != 10)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x20,%edx
  mov    $0x10,%esi
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <condition_reduction@plt>
  cmp    $0xa,%al
  je     L16
  xor    %eax,%eax
  call   <abort@plt>
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D10
type_infered: byte[16]

tool: {"D13": [0x0b,0x0c,0x0d,0x0e,0x0f,0x10,0x11,0x12,0x13,0x14,0x01,0x02,0x03,0x04,0x05,0x06]}

tool: {"D10": [0x07,0x08,0x09,0x0a,0x15,0x16,0x17,0x18,0x19,0x1a,0x1b,0x1c,0x1d,0x1e,0x1f,0x20]}

assistant: ```c
int main(void) {
  unsigned char a[32] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32};
  unsigned char ret = condition_reduction(a, 16, 32);
  if (ret != 10)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x20,%edx
  mov    $0x10,%esi
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <condition_reduction@plt>
  cmp    $0xa,%al
  je     L18
  xor    %eax,%eax
  call   <abort@plt>
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type: byte[16]
name: disassemble_data
arguments: label: D2
type: byte[16]

tool: {"D18": [0x0b,0x0c,0x0d,0x0e,0x0f,0x10,0x11,0x12,0x13,0x14,0x01,0x02,0x03,0x04,0x05,0x06]}

tool: {"D2": [0x07,0x08,0x09,0x0a,0x15,0x16,0x17,0x18,0x19,0x1a,0x1b,0x1c,0x1d,0x1e,0x1f,0x20]}

assistant: ```c
int main(void) {
  unsigned char a[32] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32};
  unsigned char ret = condition_reduction(a, 16, 32);
  if (ret != 10)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pioneer_sync2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2,%edi
  call   <pioneer_send_command0@plt>
  lea    -0x110(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <pioneer_read_string@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int pioneer_sync2(void) {
  unsigned char buf[256];
  pioneer_send_command0(2);
  pioneer_read_string(buf, 5, NULL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pioneer_sync2>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edi
  call   <pioneer_send_command0@plt>
  mov    %rsp,%rdi
  mov    $0x0,%edx
  mov    $0x5,%esi
  call   <pioneer_read_string@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x118,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pioneer_sync2(void) {
  unsigned char buf[256];
  pioneer_send_command0(2);
  pioneer_read_string(buf, 5, NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<pioneer_sync2>:
  endbr64
  sub    $0x118,%rsp
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <pioneer_send_command0@plt>
  xor    %edx,%edx
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <pioneer_read_string@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x118,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pioneer_sync2(void) {
  unsigned char buf[256];
  pioneer_send_command0(2);
  pioneer_read_string(buf, 5, NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pioneer_sync2>:
  endbr64
  sub    $0x118,%rsp
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <pioneer_send_command0@plt>
  xor    %edx,%edx
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <pioneer_read_string@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x118,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pioneer_sync2(void) {
  unsigned char buf[256];
  pioneer_send_command0(2);
  pioneer_read_string(buf, 5, NULL);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<state_change_fire1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <state_change_fire@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void state_change_fire1(int event_type, int data0) {
  int data[1];
  data[0] = data0;
  state_change_fire(event_type, data, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<state_change_fire1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <state_change_fire@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void state_change_fire1(int event_type, int data0) {
  int data[1];
  data[0] = data0;
  state_change_fire(event_type, data, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<state_change_fire1>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <state_change_fire@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void state_change_fire1(int event_type, int data0) {
  int data[1];
  data[0] = data0;
  state_change_fire(event_type, data, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<state_change_fire1>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <state_change_fire@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void state_change_fire1(int event_type, int data0) {
  int data[1];
  data[0] = data0;
  state_change_fire(event_type, data, 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L15:
  mov    $0x8,%edi
  call   <malloc@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xc7,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 200; i++) {
    malloc(8);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
L6:
  mov    $0x8,%edi
  call   <malloc@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 200; i++) {
    malloc(8);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x8,%edi
  call   <malloc@plt>
  sub    $0x1,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 200; i++) {
    malloc(8);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x8,%edi
  call   <malloc@plt>
  sub    $0x1,%ebx
  jne    L9
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 200; i++) {
    malloc(8);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eb_tim_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edx,%eax
  mov    %rcx,-0x18(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x4(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x8(%rbp)
  mov    %al,-0xc(%rbp)
  cmpb   $0x17,-0x4(%rbp)
  ja     L26
  cmpb   $0x3b,-0x8(%rbp)
  ja     L26
  cmpb   $0x3b,-0xc(%rbp)
  ja     L26
  movzbl -0xc(%rbp),%esi
  movzbl -0x8(%rbp),%ecx
  movzbl -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %esi,%r8d
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x0,%eax
  jmp    L13
L26:
  mov    $0xffffffff,%eax
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %02d:%02d:%02d

assistant: ```c
int eb_tim_to_str(unsigned char hh, unsigned char mm, unsigned char ss, char *tgt) {
  if (hh >= 0x00 && hh <= 0x17 && mm >= 0x00 && mm <= 0x3B && ss >= 0x00 && ss <= 0x3B)
    sprintf(tgt, "%02d:%02d:%02d", hh, mm, ss);
  else
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eb_tim_to_str>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    %rcx,%rdi
  cmp    $0x3b,%sil
  setbe  %cl
  cmp    $0x3b,%dl
  setbe  %dl
  test   %dl,%cl
  je     L6
  cmp    $0x17,%al
  ja     L6
  sub    $0x8,%rsp
  movzbl %sil,%ecx
  movzbl %al,%edx
  movzbl %r8b,%r8d
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: %02d:%02d:%02d

assistant: ```c
int eb_tim_to_str(unsigned char hh, unsigned char mm, unsigned char ss, char *tgt) {
  if (hh >= 0x00 && hh <= 0x17 && mm >= 0x00 && mm <= 0x3B && ss >= 0x00 && ss <= 0x3B)
    sprintf(tgt, "%02d:%02d:%02d", hh, mm, ss);
  else
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eb_tim_to_str>:
  endbr64
  cmp    $0x3b,%sil
  mov    %edi,%eax
  mov    %rcx,%rdi
  mov    %edx,%r8d
  setbe  %cl
  cmp    $0x3b,%dl
  setbe  %dl
  test   %dl,%cl
  je     L14
  cmp    $0x17,%al
  ja     L14
  sub    $0x8,%rsp
  movzbl %sil,%ecx
  movzbl %al,%edx
  movzbl %r8b,%r8d
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: %02d:%02d:%02d

assistant: ```c
int eb_tim_to_str(unsigned char hh, unsigned char mm, unsigned char ss, char *tgt) {
  if (hh >= 0x00 && hh <= 0x17 && mm >= 0x00 && mm <= 0x3B && ss >= 0x00 && ss <= 0x3B)
    sprintf(tgt, "%02d:%02d:%02d", hh, mm, ss);
  else
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eb_tim_to_str>:
  endbr64
  cmp    $0x3b,%sil
  mov    %edi,%eax
  mov    %rcx,%rdi
  mov    %edx,%r8d
  setbe  %cl
  cmp    $0x3b,%dl
  setbe  %dl
  test   %dl,%cl
  je     L18
  cmp    $0x17,%al
  ja     L18
  sub    $0x8,%rsp
  movzbl %sil,%ecx
  movzbl %al,%edx
  movzbl %r8b,%r8d
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: %02d:%02d:%02d

assistant: ```c
int eb_tim_to_str(unsigned char hh, unsigned char mm, unsigned char ss, char *tgt) {
  if (hh >= 0x00 && hh <= 0x17 && mm >= 0x00 && mm <= 0x3B && ss >= 0x00 && ss <= 0x3B)
    sprintf(tgt, "%02d:%02d:%02d", hh, mm, ss);
  else
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<close_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L19
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void close_file(FILE *f) {
  if (f && f != stdout && f != stderr)
    fclose(f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<close_file>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    D2(%rip),%rax
  cmp    %rdi,(%rax)
  je     L5
  mov    D18(%rip),%rax
  cmp    %rdi,(%rax)
  je     L5
  sub    $0x8,%rsp
  call   <fclose@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void close_file(FILE *f) {
  if (f && f != stdout && f != stderr)
    fclose(f);
}
```
user: What is the c source code of the assembly code below?

```asm
<close_file>:
  endbr64
  test   %rdi,%rdi
  je     L22
  mov    D0(%rip),%rax
  cmp    %rdi,(%rax)
  je     L22
  mov    D15(%rip),%rax
  cmp    %rdi,(%rax)
  je     L22
  jmp    1050 <fclose@plt>
  cs nopw 0x0(%rax,%rax,1)
L22:
  ret
```

assistant: ```c
void close_file(FILE *f) {
  if (f && f != stdout && f != stderr)
    fclose(f);
}
```
user: Translate the below assembly code into C programming language:

```asm
<close_file>:
  endbr64
  test   %rdi,%rdi
  je     L24
  mov    D7(%rip),%rax
  cmp    %rdi,(%rax)
  je     L24
  mov    D13(%rip),%rax
  cmp    %rdi,(%rax)
  je     L24
  jmp    1050 <fclose@plt>
  cs nopw 0x0(%rax,%rax,1)
L24:
  ret
```

assistant: ```c
void close_file(FILE *f) {
  if (f && f != stdout && f != stderr)
    fclose(f);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x10000(%rsp),%r11
L58:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L58
  sub    $0x40,%rsp
  mov    %edi,-0x10024(%rbp)
  mov    %rsi,-0x10030(%rbp)
  mov    %rdx,-0x10038(%rbp)
  mov    %rcx,-0x10040(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10024(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x10018(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movl   $0x0,-0x10020(%rbp)
  jmp    L42
L94:
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10010(%rbp,%rdx,8)
  addl   $0x1,-0x10020(%rbp)
L42:
  mov    -0x10020(%rbp),%edx
  cmp    -0x10024(%rbp),%edx
  jl     L94
  movl   $0x0,-0x10020(%rbp)
  jmp    L100
L16:
  movl   $0x0,-0x1001c(%rbp)
  jmp    L109
L119:
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10030(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x1001c(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rcx,%rdx,8),%xmm1
  mov    -0x1001c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10038(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  movsd  -0x10010(%rbp,%rdx,8),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  movsd  %xmm0,-0x10010(%rbp,%rdx,8)
  addl   $0x1,-0x1001c(%rbp)
L109:
  mov    -0x1001c(%rbp),%edx
  cmp    -0x10024(%rbp),%edx
  jl     L119
  addl   $0x1,-0x10020(%rbp)
L100:
  mov    -0x10020(%rbp),%edx
  cmp    -0x10024(%rbp),%edx
  jl     L16
  movl   $0x0,-0x10020(%rbp)
  jmp    L2
L98:
  movl   $0x0,-0x1001c(%rbp)
  jmp    L56
L110:
  mov    -0x1001c(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10030(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  movsd  (%rcx,%rdx,8),%xmm1
  mov    -0x1001c(%rbp),%edx
  movslq %edx,%rdx
  movsd  -0x10010(%rbp,%rdx,8),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10040(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm0
  mov    -0x10020(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10040(%rbp),%rdx
  add    %rcx,%rdx
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0x1001c(%rbp)
L56:
  mov    -0x1001c(%rbp),%edx
  cmp    -0x10024(%rbp),%edx
  jl     L110
  addl   $0x1,-0x10020(%rbp)
L2:
  mov    -0x10020(%rbp),%edx
  cmp    -0x10024(%rbp),%edx
  jl     L98
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void atax(int n, double A[][n], double x[n], double y[n]) {
  int i, j;
  double temp[8192];
  for (i = 0; i < n; i++)
    temp[i] = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      temp[i] += A[i][j] * x[j];
    }
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++) {
      y[i] += A[j][i] * temp[j];
    }
}
```