ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<log_stat>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <basename@plt>
  lea    D24(%rip),%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  movdqa D30(%rip),%xmm0
  movups %xmm0,(%rbx)
  movdqa D27(%rip),%xmm0
  movups %xmm0,0x10(%rbx)
  movdqa D25(%rip),%xmm0
  movups %xmm0,0x20(%rbx)
  pop    %rbx
  ret
  nopl   (%rax)
L4:
  mov    $0xffffea4d,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D30
datatype: byte[16]
name: disassemble_data
arguments: data_label: D27
datatype: byte[16]
name: disassemble_data
arguments: data_label: D25
datatype: byte[16]

tool: D24: ncsvc.log

tool: {"D30": [0xe8,0x03,0x00,0x00,0xe8,0x03,0x00,0x00,0x8b,0x6f,0xee,0x00,0xad,0x5e,0x99,0x00]}

tool: {"D27": [0x06,0x08,0x00,0x00,0xb8,0x4c,0x00,0x00,0x00,0x10,0x00,0x00,0xa4,0x81,0x00,0x00]}

tool: {"D25": [0x01,0x00,0x00,0x00,0xa1,0x62,0x81,0x52,0xb6,0xe2,0xa3,0x52,0xb6,0xe2,0xa3,0x52]}

assistant: ```c
int log_stat(const char *pathname, struct stat *st) {
  if (strcmp(basename((char *)pathname), "ncsvc.log"))
    return -5555;
  do {
  } while (0);
  st->st_uid = st->st_gid = 0x3e8;
  st->st_ino = 0xee6f8b;
  st->st_size = 0x995ead;
  st->st_dev = 0x806;
  st->st_blocks = 0x4cb8;
  st->st_blksize = 0x1000;
  st->st_mode = 0x81a4;
  st->st_nlink = 1;
  st->st_atime = 0x528162a1;
  st->st_mtime = 0x52a3e2b6;
  st->st_ctime = 0x52a3e2b6;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L14:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string

tool: D19: %d 

tool: D16: ----

assistant: ```c
void print_matrix(int *mat, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      printf("%d ", mat[(((i)*2) + (j))]);
    }
    printf("\n");
  }
  printf("----");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L48
  mov    %rdi,%r15
  mov    %edx,%r14d
  lea    (%rsi,%rsi,1),%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%r13d
  lea    D7(%rip),%r12
  jmp    L18
L56:
  movslq %r13d,%rdx
  lea    (%r15,%rdx,4),%rbx
  lea    -0x1(%r14),%eax
  add    %rdx,%rax
  lea    0x4(%r15,%rax,4),%rbp
L47:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L47
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x2,%r13d
  cmp    0xc(%rsp),%r13d
  je     L48
L18:
  test   %r14d,%r14d
  jg     L56
  jmp    L0
L48:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D7: %d 

tool: D2: ----

assistant: ```c
void print_matrix(int *mat, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      printf("%d ", mat[(((i)*2) + (j))]);
    }
    printf("\n");
  }
  printf("----");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L32
  lea    (%rsi,%rsi,1),%eax
  mov    %rdi,%r14
  mov    %edx,%r13d
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  lea    D1(%rip),%rbp
  nopl   (%rax)
L21:
  test   %r13d,%r13d
  jle    L9
  movslq %r12d,%rcx
  lea    -0x1(%r13),%eax
  add    %rcx,%rax
  lea    (%r14,%rcx,4),%r15
  lea    0x4(%r14,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L0
L9:
  mov    $0xa,%edi
  add    $0x2,%r12d
  call   <putchar@plt>
  cmp    0xc(%rsp),%r12d
  jne    L21
L32:
  add    $0x18,%rsp
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D1: %d 

tool: D16: ----

assistant: ```c
void print_matrix(int *mat, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      printf("%d ", mat[(((i)*2) + (j))]);
    }
    printf("\n");
  }
  printf("----");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L30
  lea    (%rsi,%rsi,1),%eax
  mov    %rdi,%r14
  mov    %edx,%r13d
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  lea    D0(%rip),%rbp
  nopl   (%rax)
L32:
  test   %r13d,%r13d
  jle    L13
  movslq %r12d,%rcx
  lea    -0x1(%r13),%eax
  add    %rcx,%rax
  lea    (%r14,%rcx,4),%r15
  lea    0x4(%r14,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L29
L13:
  mov    $0xa,%edi
  add    $0x2,%r12d
  call   <putchar@plt>
  cmp    0xc(%rsp),%r12d
  jne    L32
L30:
  add    $0x18,%rsp
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string

tool: D0: %d 

tool: D14: ----

assistant: ```c
void print_matrix(int *mat, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      printf("%d ", mat[(((i)*2) + (j))]);
    }
    printf("\n");
  }
  printf("----");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<replace_cr_ln_in_place>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x20,%ecx
  mov    $0xd,%edx
  mov    %rax,%rdi
  call   <strtr_in_place@plt>
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x20,%ecx
  mov    $0xa,%edx
  mov    %rax,%rdi
  call   <strtr_in_place@plt>
  nop
  leave
  ret
```

assistant: ```c
void replace_cr_ln_in_place(char *s, size_t l) {
  strtr_in_place(s, l, '\r', ' ');
  strtr_in_place(s, l, '\n', ' ');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace_cr_ln_in_place>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x20,%ecx
  mov    $0xd,%edx
  call   <strtr_in_place@plt>
  mov    $0x20,%ecx
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strtr_in_place@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void replace_cr_ln_in_place(char *s, size_t l) {
  strtr_in_place(s, l, '\r', ' ');
  strtr_in_place(s, l, '\n', ' ');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<replace_cr_ln_in_place>:
  endbr64
  push   %r12
  mov    $0x20,%ecx
  mov    $0xd,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strtr_in_place@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x20,%ecx
  pop    %rbp
  mov    $0xa,%edx
  pop    %r12
  jmp    1050 <strtr_in_place@plt>
```

assistant: ```c
void replace_cr_ln_in_place(char *s, size_t l) {
  strtr_in_place(s, l, '\r', ' ');
  strtr_in_place(s, l, '\n', ' ');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replace_cr_ln_in_place>:
  endbr64
  push   %r12
  mov    $0x20,%ecx
  mov    $0xd,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strtr_in_place@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x20,%ecx
  pop    %rbp
  mov    $0xa,%edx
  pop    %r12
  jmp    1050 <strtr_in_place@plt>
```

assistant: ```c
void replace_cr_ln_in_place(char *s, size_t l) {
  strtr_in_place(s, l, '\r', ' ');
  strtr_in_place(s, l, '\n', ' ');
}
```
user: Translate the below assembly code into C programming language:

```asm
<plgndr_a>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  call   <cos@plt>
  movapd %xmm0,%xmm6
  movsd  %xmm0,0x8(%rsp)
  movsd  D9(%rip),%xmm0
  test   %ebx,%ebx
  jg     L26
L76:
  cmp    %ebp,%ebx
  je     L79
  lea    (%rbx,%rbx,1),%edx
  lea    0x1(%rdx),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  lea    0x1(%rbx),%eax
  cmp    %ebp,%eax
  je     L16
  lea    0x2(%rbx),%eax
  cmp    %eax,%ebp
  jl     L79
  add    $0x3,%edx
  add    $0x1,%ebp
  sub    %ebx,%ebp
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mov    $0x2,%eax
  lea    -0x1(%rbx,%rbx,1),%esi
L8:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  lea    (%rsi,%rax,1),%ecx
  pxor   %xmm2,%xmm2
  cvtsi2sd %ecx,%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm0,%xmm3
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  add    $0x2,%edx
  add    $0x1,%eax
  cmp    %ebp,%eax
  jne    L8
L79:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  movapd %xmm0,%xmm2
  subsd  %xmm6,%xmm2
  addsd  %xmm6,%xmm0
  mulsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L93
  sqrtsd %xmm2,%xmm2
L12:
  lea    0x1(%rbx),%edx
  movsd  D9(%rip),%xmm0
  movapd %xmm0,%xmm1
  mov    $0x1,%eax
  movq   D24(%rip),%xmm4
  movsd  D36(%rip),%xmm3
L1:
  xorpd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm1
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L1
  jmp    L76
L93:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L12
L16:
  movapd %xmm1,%xmm0
  jmp    L79
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: f64
name: disassemble_data
arguments: label: D24
type_infered: byte[8]
name: disassemble_data
arguments: label: D36
type_infered: f64

tool: D9: 1

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D36: 2

assistant: ```c
double plgndr_a(l, m, t)
int l, m;
double t;
{
  int i, ll;
  double x, fact, pll, pmm, pmmp1, somx2, plgndr;
  const double two = 2.0;
  const double one = 1.0;
  x = cos(t);
  pmm = one;
  if (m > 0) {
    somx2 = sqrt((one - x) * (one + x));
    fact = one;
    for (i = 1; i <= m; i++) {
      pmm = -pmm * fact * somx2;
      fact = fact + two;
    }
  }
  if (l == m)
    plgndr = pmm;
  else {
    pmmp1 = x * (2 * m + 1) * pmm;
    if (l == m + 1)
      plgndr = pmmp1;
    else {
      for (ll = m + 2; ll <= l; ll++) {
        pll = (x * (2 * ll - 1) * pmmp1 - (ll + m - 1) * pmm) / (ll - m);
        pmm = pmmp1;
        pmmp1 = pll;
      }
      plgndr = pll;
    }
  }
  return plgndr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plgndr_a>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  call   <cos@plt>
  movapd %xmm0,%xmm3
  movsd  D37(%rip),%xmm0
  test   %ebp,%ebp
  jg     L22
L37:
  cmp    %ebx,%ebp
  je     L85
  lea    0x0(%rbp,%rbp,1),%esi
  pxor   %xmm1,%xmm1
  lea    0x1(%rsi),%eax
  cvtsi2sd %eax,%xmm1
  lea    0x1(%rbp),%eax
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  cmp    %ebx,%eax
  je     L20
  lea    0x2(%rbp),%eax
  cmp    %eax,%ebx
  jl     L85
  lea    0x1(%rbx),%ecx
  movapd %xmm0,%xmm4
  lea    0x3(%rsi),%edx
  mov    $0x2,%eax
  sub    %ebp,%ecx
  movapd %xmm1,%xmm0
  lea    -0x1(%rsi),%edi
  nopl   0x0(%rax)
L77:
  pxor   %xmm1,%xmm1
  lea    (%rdi,%rax,1),%esi
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm1
  add    $0x2,%edx
  cvtsi2sd %esi,%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm4,%xmm2
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  cmp    %eax,%ecx
  jne    L77
L85:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L41
  sqrtsd %xmm2,%xmm2
L26:
  movq   D9(%rip),%xmm5
  lea    0x1(%rbp),%edx
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  movsd  D5(%rip),%xmm4
  nopw   0x0(%rax,%rax,1)
L65:
  xorpd  %xmm5,%xmm0
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L65
  jmp    L37
L41:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  mov    D37(%rip),%rax
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm2
  movq   %rax,%xmm1
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: f64

tool: D37: 1

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D5: 2

assistant: ```c
double plgndr_a(l, m, t)
int l, m;
double t;
{
  int i, ll;
  double x, fact, pll, pmm, pmmp1, somx2, plgndr;
  const double two = 2.0;
  const double one = 1.0;
  x = cos(t);
  pmm = one;
  if (m > 0) {
    somx2 = sqrt((one - x) * (one + x));
    fact = one;
    for (i = 1; i <= m; i++) {
      pmm = -pmm * fact * somx2;
      fact = fact + two;
    }
  }
  if (l == m)
    plgndr = pmm;
  else {
    pmmp1 = x * (2 * m + 1) * pmm;
    if (l == m + 1)
      plgndr = pmmp1;
    else {
      for (ll = m + 2; ll <= l; ll++) {
        pll = (x * (2 * ll - 1) * pmmp1 - (ll + m - 1) * pmm) / (ll - m);
        pmm = pmmp1;
        pmmp1 = pll;
      }
      plgndr = pll;
    }
  }
  return plgndr;
}
```
user: What is the c source code of the assembly code below?

```asm
<plgndr_a>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  call   <cos@plt>
  movapd %xmm0,%xmm3
  movsd  D17(%rip),%xmm0
  test   %ebp,%ebp
  jg     L64
L83:
  cmp    %ebx,%ebp
  je     L32
  lea    0x0(%rbp,%rbp,1),%esi
  pxor   %xmm1,%xmm1
  lea    0x1(%rsi),%eax
  cvtsi2sd %eax,%xmm1
  lea    0x1(%rbp),%eax
  mulsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  cmp    %ebx,%eax
  je     L0
  lea    0x2(%rbp),%eax
  cmp    %eax,%ebx
  jl     L32
  lea    0x1(%rbx),%ecx
  movapd %xmm0,%xmm4
  lea    0x3(%rsi),%edx
  mov    $0x2,%eax
  sub    %ebp,%ecx
  movapd %xmm1,%xmm0
  lea    -0x1(%rsi),%edi
  nopl   0x0(%rax)
L44:
  pxor   %xmm1,%xmm1
  lea    (%rdi,%rax,1),%esi
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm1
  add    $0x2,%edx
  cvtsi2sd %esi,%xmm2
  mulsd  %xmm3,%xmm1
  mulsd  %xmm4,%xmm2
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  cmp    %eax,%ecx
  jne    L44
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L39
  sqrtsd %xmm2,%xmm2
L74:
  movq   D12(%rip),%xmm5
  lea    0x1(%rbp),%edx
  movapd %xmm1,%xmm0
  mov    $0x1,%eax
  movsd  D30(%rip),%xmm4
  nopw   0x0(%rax,%rax,1)
L16:
  xorpd  %xmm5,%xmm0
  add    $0x1,%eax
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm0
  cmp    %edx,%eax
  jne    L16
  jmp    L83
L39:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  mov    D17(%rip),%rax
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm2
  movq   %rax,%xmm1
  jmp    L74
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: f64
name: extract_symbolic_data
arguments: label: D12
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D30
data_type: f64

tool: D17: 1

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D30: 2

assistant: ```c
double plgndr_a(l, m, t)
int l, m;
double t;
{
  int i, ll;
  double x, fact, pll, pmm, pmmp1, somx2, plgndr;
  const double two = 2.0;
  const double one = 1.0;
  x = cos(t);
  pmm = one;
  if (m > 0) {
    somx2 = sqrt((one - x) * (one + x));
    fact = one;
    for (i = 1; i <= m; i++) {
      pmm = -pmm * fact * somx2;
      fact = fact + two;
    }
  }
  if (l == m)
    plgndr = pmm;
  else {
    pmmp1 = x * (2 * m + 1) * pmm;
    if (l == m + 1)
      plgndr = pmmp1;
    else {
      for (ll = m + 2; ll <= l; ll++) {
        pll = (x * (2 * ll - 1) * pmmp1 - (ll + m - 1) * pmm) / (ll - m);
        pmm = pmmp1;
        pmmp1 = pll;
      }
      plgndr = pll;
    }
  }
  return plgndr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval = 0;
  for (int i = 0; *(s + i) != '\0'; ++i) {
    hashval = s + hashval * 31;
  }
  return hashval % 100;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  lea    0x1(%rdi),%rcx
  mov    $0x0,%edx
L23:
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  lea    (%rdi,%rax,1),%edx
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L23
L28:
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L7:
  mov    $0x0,%edx
  jmp    L28
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval = 0;
  for (int i = 0; *(s + i) != '\0'; ++i) {
    hashval = s + hashval * 31;
  }
  return hashval % 100;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  lea    0x1(%rdi),%rcx
  xor    %edx,%edx
  nop
L1:
  mov    %edx,%eax
  add    $0x1,%rcx
  shl    $0x5,%eax
  sub    %edx,%eax
  cmpb   $0x0,-0x1(%rcx)
  lea    (%rdi,%rax,1),%edx
  jne    L1
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval = 0;
  for (int i = 0; *(s + i) != '\0'; ++i) {
    hashval = s + hashval * 31;
  }
  return hashval % 100;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  lea    0x1(%rdi),%rcx
  xor    %edx,%edx
  nop
L14:
  mov    %edx,%eax
  add    $0x1,%rcx
  shl    $0x5,%eax
  sub    %edx,%eax
  cmpb   $0x0,-0x1(%rcx)
  lea    (%rdi,%rax,1),%edx
  jne    L14
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval = 0;
  for (int i = 0; *(s + i) != '\0'; ++i) {
    hashval = s + hashval * 31;
  }
  return hashval % 100;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_valid_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L56
L74:
  addl   $0x1,-0x8(%rbp)
L56:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L54
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L54
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L74
  jmp    L54
L82:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L82
  subl   $0x1,-0x8(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jne    L91
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L91
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L91
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L31
L91:
  mov    $0x0,%eax
  jmp    L95
L31:
  mov    $0x1,%eax
L95:
  pop    %rbp
  ret
```

assistant: ```c
int ft_valid_key(char *str) {
  int i;
  int ch_count;
  i = 0;
  ch_count = 0;
  while (str[i] <= '9' && str[i] >= '0' && str[i] != '\n')
    i++;
  while (str[i] != '\n') {
    ch_count++;
    i++;
  }
  i--;
  if (ch_count != 3 || str[i] == str[i - 1] || str[i] == str[i - 2] || str[i - 1] == str[i - 2])
    return (0);
  else
    return (1);
}
```