ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  push   $0x8
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  push   $0x7
  mov    $0x2,%ecx
  mov    $0x1,%edx
  push   $0x6
  push   $0x5
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <add10@plt>
  add    $0x20,%rsp
  lea    D14(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D15: %d

tool: D14: Sum = %ld


assistant: ```c
int main() {
  int n;
  int m;
  long result;
  scanf("%d", &n);
  scanf("%d", &m);
  result = add10(n, m, 1, 2, 3, 4, 5, 6, 7, 8);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  push   $0x8
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  push   $0x7
  mov    $0x2,%ecx
  mov    $0x1,%edx
  push   $0x6
  push   $0x5
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <add10@plt>
  add    $0x20,%rsp
  lea    D14(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D14
datatype: string

tool: D12: %d

tool: D14: Sum = %ld


assistant: ```c
int main() {
  int n;
  int m;
  long result;
  scanf("%d", &n);
  scanf("%d", &m);
  result = add10(n, m, 1, 2, 3, 4, 5, 6, 7, 8);
  printf("Sum = %ld\n", result);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<display_help_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D57
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D29
type_infered: string
name: disassemble_data
arguments: data_label: D42
type_infered: string

tool: D57: Usage:

tool: D0: 
With direct text: %s [text] [-k or --key KEY]

	or

With file as input: %s [-f or --file] [filename] [-k or --key KEY]


tool: D11: 
[text]: string with the text to work on
[-f or --file] [filename]: the file path to read the text

tool: D28: [-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode

tool: D29: [-d or --decrypt]: Try to decrypt instead of encrypt

tool: D42: [-h or --help]: displays this help message

assistant: ```c
void display_help_message(char *program_name) {
  printf("Usage:\n");
  printf("\nWith direct text: %s [text] [-k or --key KEY]\n\n\tor\n\nWith file as input: %s [-f or --file] [filename] [-k or --key KEY]\n", program_name, program_name);
  printf("\n[text]: string with the text to work on\n[-f or --file] [filename]: the file path to read the text\n");
  printf("[-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode\n");
  printf("[-d or --decrypt]: Try to decrypt instead of encrypt\n");
  printf("[-h or --help]: displays this help message\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<display_help_message>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D52
datatype: string
name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D40
datatype: string

tool: D2: Usage:

tool: D26: 
With direct text: %s [text] [-k or --key KEY]

	or

With file as input: %s [-f or --file] [filename] [-k or --key KEY]


tool: D23: 
[text]: string with the text to work on
[-f or --file] [filename]: the file path to read the text

tool: D52: [-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode

tool: D28: [-d or --decrypt]: Try to decrypt instead of encrypt

tool: D40: [-h or --help]: displays this help message

assistant: ```c
void display_help_message(char *program_name) {
  printf("Usage:\n");
  printf("\nWith direct text: %s [text] [-k or --key KEY]\n\n\tor\n\nWith file as input: %s [-f or --file] [filename] [-k or --key KEY]\n", program_name, program_name);
  printf("\n[text]: string with the text to work on\n[-f or --file] [filename]: the file path to read the text\n");
  printf("[-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode\n");
  printf("[-d or --decrypt]: Try to decrypt instead of encrypt\n");
  printf("[-h or --help]: displays this help message\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<display_help_message>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D47
type: string
name: extract_symbolic_data
arguments: tag: D38
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D51
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: D31: Usage:

tool: D47: 
With direct text: %s [text] [-k or --key KEY]

	or

With file as input: %s [-f or --file] [filename] [-k or --key KEY]


tool: D38: 
[text]: string with the text to work on
[-f or --file] [filename]: the file path to read the text

tool: D16: [-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode

tool: D51: [-d or --decrypt]: Try to decrypt instead of encrypt

tool: D20: [-h or --help]: displays this help message

assistant: ```c
void display_help_message(char *program_name) {
  printf("Usage:\n");
  printf("\nWith direct text: %s [text] [-k or --key KEY]\n\n\tor\n\nWith file as input: %s [-f or --file] [filename] [-k or --key KEY]\n", program_name, program_name);
  printf("\n[text]: string with the text to work on\n[-f or --file] [filename]: the file path to read the text\n");
  printf("[-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode\n");
  printf("[-d or --decrypt]: Try to decrypt instead of encrypt\n");
  printf("[-h or --help]: displays this help message\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<display_help_message>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D38
type: string
name: retrieve_data
arguments: data_tag: D27
type: string
name: retrieve_data
arguments: data_tag: D24
type: string
name: retrieve_data
arguments: data_tag: D41
type: string
name: retrieve_data
arguments: data_tag: D22
type: string

tool: D9: Usage:

tool: D38: 
With direct text: %s [text] [-k or --key KEY]

	or

With file as input: %s [-f or --file] [filename] [-k or --key KEY]


tool: D27: 
[text]: string with the text to work on
[-f or --file] [filename]: the file path to read the text

tool: D24: [-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode

tool: D41: [-d or --decrypt]: Try to decrypt instead of encrypt

tool: D22: [-h or --help]: displays this help message

assistant: ```c
void display_help_message(char *program_name) {
  printf("Usage:\n");
  printf("\nWith direct text: %s [text] [-k or --key KEY]\n\n\tor\n\nWith file as input: %s [-f or --file] [filename] [-k or --key KEY]\n", program_name, program_name);
  printf("\n[text]: string with the text to work on\n[-f or --file] [filename]: the file path to read the text\n");
  printf("[-k or --key] [KEY]: Key value [required for encrypt mode], if not specified the program will run in bruteforce mode\n");
  printf("[-d or --decrypt]: Try to decrypt instead of encrypt\n");
  printf("[-h or --help]: displays this help message\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isoperator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x5e,-0x4(%rbp)
  je     L53
  cmpb   $0x2a,-0x4(%rbp)
  je     L53
  cmpb   $0x2f,-0x4(%rbp)
  je     L53
  cmpb   $0x2b,-0x4(%rbp)
  je     L53
  cmpb   $0x2d,-0x4(%rbp)
  je     L53
  mov    $0x0,%eax
  jmp    L3
L53:
  mov    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int isoperator(char c) {
  if (c != '^' && c != '*' && c != '/' && c != '+' && c != '-')
    return 0;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isoperator>:
  endbr64
  lea    -0x2a(%rdi),%ecx
  mov    $0x1,%eax
  cmp    $0x34,%cl
  ja     L7
  movabs $0x1000000000002b,%rax
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L7:
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int isoperator(char c) {
  if (c != '^' && c != '*' && c != '/' && c != '+' && c != '-')
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isoperator>:
  endbr64
  lea    -0x2a(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x34,%cl
  ja     L7
  movabs $0xffefffffffffffd4,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int isoperator(char c) {
  if (c != '^' && c != '*' && c != '/' && c != '+' && c != '-')
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isoperator>:
  endbr64
  lea    -0x2a(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x34,%cl
  ja     L8
  movabs $0xffefffffffffffd4,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int isoperator(char c) {
  if (c != '^' && c != '*' && c != '/' && c != '+' && c != '-')
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__stpcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy(char *__restrict to, const char *__restrict from) {
  __stpcpy(to, from);
  return (to);
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <__stpcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strcpy(char *__restrict to, const char *__restrict from) {
  __stpcpy(to, from);
  return (to);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <__stpcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *__restrict to, const char *__restrict from) {
  __stpcpy(to, from);
  return (to);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <__stpcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *__restrict to, const char *__restrict from) {
  __stpcpy(to, from);
  return (to);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <v_fini_cb@plt>
  mov    $0x0,%eax
  call   <nl_fini@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void sig_handler(int signo) {
  if (signo == SIGINT) {
    v_fini_cb();
    nl_fini();
    exit(EXIT_SUCCESS);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sig_handler>:
  endbr64
  mov    D5(%rip),%rax
  cmp    %edi,(%rax)
  je     L0
  ret
L0:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <v_fini_cb@plt>
  mov    $0x0,%eax
  call   <nl_fini@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sig_handler(int signo) {
  if (signo == SIGINT) {
    v_fini_cb();
    nl_fini();
    exit(EXIT_SUCCESS);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sig_handler>:
  endbr64
  mov    D17(%rip),%rax
  cmp    %edi,(%rax)
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <v_fini_cb@plt>
  xor    %eax,%eax
  call   <nl_fini@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

assistant: ```c
void sig_handler(int signo) {
  if (signo == SIGINT) {
    v_fini_cb();
    nl_fini();
    exit(EXIT_SUCCESS);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sig_handler>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %edi,(%rax)
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <v_fini_cb@plt>
  xor    %eax,%eax
  call   <nl_fini@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

assistant: ```c
void sig_handler(int signo) {
  if (signo == SIGINT) {
    v_fini_cb();
    nl_fini();
    exit(EXIT_SUCCESS);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<all_points_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L22
  mov    $0x0,%eax
  jmp    L15
L22:
  addl   $0x1,-0x4(%rbp)
L32:
  cmpl   $0x7,-0x4(%rbp)
  jle    L2
  mov    $0x1,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int all_points_set(int *p2c) {
  int i;
  for (i = 0; i < 8; i++)
    if (p2c[i] == 1)
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_points_set>:
  endbr64
  lea    0x20(%rdi),%rax
L18:
  cmpl   $0x1,(%rdi)
  je     L2
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L18
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int all_points_set(int *p2c) {
  int i;
  for (i = 0; i < 8; i++)
    if (p2c[i] == 1)
      return (0);
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<all_points_set>:
  endbr64
  lea    0x20(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L3:
  cmpl   $0x1,(%rdi)
  je     L11
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L3
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int all_points_set(int *p2c) {
  int i;
  for (i = 0; i < 8; i++)
    if (p2c[i] == 1)
      return (0);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<all_points_set>:
  endbr64
  cmpl   $0x1,(%rdi)
  je     L24
  cmpl   $0x1,0x4(%rdi)
  je     L24
  cmpl   $0x1,0x8(%rdi)
  je     L24
  cmpl   $0x1,0xc(%rdi)
  je     L24
  cmpl   $0x1,0x10(%rdi)
  je     L24
  cmpl   $0x1,0x14(%rdi)
  je     L24
  cmpl   $0x1,0x18(%rdi)
  je     L24
  xor    %eax,%eax
  cmpl   $0x1,0x1c(%rdi)
  setne  %al
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int all_points_set(int *p2c) {
  int i;
  for (i = 0; i < 8; i++)
    if (p2c[i] == 1)
      return (0);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compute_gemv_dimension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x18(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movsd  D8(%rip),%xmm1
  movq   %rax,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_infered: f64
name: unpack_data
arguments: data_label: D8
type_infered: f64

tool: D19: 4

tool: D8: 2

assistant: ```c
int compute_gemv_dimension(int maxmem, int datasize) {
  double rt;
  rt = (4.0 * (double)maxmem / (double)datasize) + 4.0;
  rt = sqrt(rt) - 2.0;
  rt = rt / 2;
  return ((int)rt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_gemv_dimension>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  movsd  D2(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L16
  sqrtsd %xmm0,%xmm0
L18:
  subsd  D28(%rip),%xmm0
  mulsd  D11(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x8,%rsp
  ret
L16:
  call   <sqrt@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: tag: D2
datatype: f64
name: read_data
arguments: tag: D28
datatype: f64
name: read_data
arguments: tag: D11
datatype: byte[8]

tool: D2: 4

tool: D28: 2

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int compute_gemv_dimension(int maxmem, int datasize) {
  double rt;
  rt = (4.0 * (double)maxmem / (double)datasize) + 4.0;
  rt = sqrt(rt) - 2.0;
  rt = rt / 2;
  return ((int)rt);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<compute_gemv_dimension>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  movsd  D6(%rip),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm0
  cvtsi2sd %esi,%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L18
  sqrtsd %xmm0,%xmm0
L11:
  subsd  D14(%rip),%xmm0
  mulsd  D3(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%eax
  ret
L18:
  call   <sqrt@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D6
type: f64
name: disassemble_data
arguments: label: D14
type: f64
name: disassemble_data
arguments: label: D3
type: byte[8]

tool: D6: 4

tool: D14: 2

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int compute_gemv_dimension(int maxmem, int datasize) {
  double rt;
  rt = (4.0 * (double)maxmem / (double)datasize) + 4.0;
  rt = sqrt(rt) - 2.0;
  rt = rt / 2;
  return ((int)rt);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compute_gemv_dimension>:
  endbr64
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  movsd  D1(%rip),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm0
  cvtsi2sd %esi,%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L11
  sqrtsd %xmm0,%xmm0
L13:
  subsd  D16(%rip),%xmm0
  mulsd  D20(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%eax
  ret
L11:
  call   <sqrt@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: f64
name: parse_data
arguments: tag: D16
type_guessed: f64
name: parse_data
arguments: tag: D20
type_guessed: byte[8]

tool: D1: 4

tool: D16: 2

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int compute_gemv_dimension(int maxmem, int datasize) {
  double rt;
  rt = (4.0 * (double)maxmem / (double)datasize) + 4.0;
  rt = sqrt(rt) - 2.0;
  rt = rt / 2;
  return ((int)rt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_proto_aes_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  cmpl   $0x0,0x10(%rbp)
  je     L32
  cmpl   $0x1,0x10(%rbp)
  je     L9
  jmp    L34
L32:
  mov    D16(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <AES_ecb_encrypt@plt>
  jmp    L34
L9:
  mov    D16(%rip),%rax
  mov    (%rax),%r8d
  mov    -0x30(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <AES_cbc_encrypt@plt>
  nop
L34:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
void hash_proto_aes_encrypt(const unsigned char *key, int keysize, const unsigned char *in, int len, unsigned char *vec, unsigned char *out, int mode) {
  AES_KEY akey;
  AES_set_encrypt_key(key, keysize * 8, &akey);
  switch (mode) {
  case 0:
    AES_ecb_encrypt(in, out, &akey, AES_ENCRYPT);
    break;
  case 1:
    AES_cbc_encrypt(in, out, len, &akey, vec, AES_ENCRYPT);
    break;
  default:
    return;
  }
}
```