ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<score>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  movss  D6(%rip),%xmm0
  test   %rax,%rax
  je     L92
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  jne    L74
L92:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <min_match_length@plt>
  pxor   %xmm0,%xmm0
  test   %rax,%rax
  je     L92
  test   %rbx,%rbx
  js     L23
  pxor   %xmm0,%xmm0
  cvtsi2ss %rbx,%xmm0
L75:
  test   %rax,%rax
  js     L25
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
L32:
  divss  %xmm1,%xmm0
  test   %r12,%r12
  js     L69
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12,%xmm1
L31:
  divss  %xmm1,%xmm0
  jmp    L92
L23:
  mov    %rbx,%rdx
  shr    %rdx
  and    $0x1,%ebx
  or     %rbx,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
  jmp    L75
L25:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2ss %rdx,%xmm1
  addss  %xmm1,%xmm1
  jmp    L32
L69:
  mov    %r12,%rax
  shr    %rax
  and    $0x1,%r12d
  or     %r12,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L31
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float score(char *string, char *query) {
  size_t string_length, query_length, match_length;
  string_length = strlen(string);
  query_length = strlen(query);
  if (query_length == 0) {
    return 1;
  }
  if (string_length == 0) {
    return 0;
  }
  match_length = min_match_length(string, query);
  if (match_length == 0) {
    return 0;
  }
  return (float)query_length / (float)match_length / (float)string_length;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<score>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movss  D1(%rip),%xmm0
  test   %rax,%rax
  je     L45
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L41
L15:
  pxor   %xmm0,%xmm0
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <min_match_length@plt>
  test   %rax,%rax
  je     L15
  pxor   %xmm0,%xmm0
  cvtsi2ss %rbx,%xmm0
  js     L39
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
L11:
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  add    $0x8,%rsp
  cvtsi2ss %r13,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  divss  %xmm1,%xmm0
  ret
L39:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  shr    %rdx
  or     %rax,%rdx
  cvtsi2ss %rdx,%xmm1
  addss  %xmm1,%xmm1
  jmp    L11
```

tool_calls: name: read_data
arguments: data_label: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float score(char *string, char *query) {
  size_t string_length, query_length, match_length;
  string_length = strlen(string);
  query_length = strlen(query);
  if (query_length == 0) {
    return 1;
  }
  if (string_length == 0) {
    return 0;
  }
  match_length = min_match_length(string, query);
  if (match_length == 0) {
    return 0;
  }
  return (float)query_length / (float)match_length / (float)string_length;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<score>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movss  D7(%rip),%xmm0
  test   %rax,%rax
  je     L48
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L34
L22:
  pxor   %xmm0,%xmm0
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <min_match_length@plt>
  test   %rax,%rax
  je     L22
  pxor   %xmm0,%xmm0
  cvtsi2ss %rbx,%xmm0
  js     L40
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
L44:
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  add    $0x8,%rsp
  cvtsi2ss %r13,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  divss  %xmm1,%xmm0
  ret
L40:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  shr    %rdx
  or     %rax,%rdx
  cvtsi2ss %rdx,%xmm1
  addss  %xmm1,%xmm1
  jmp    L44
```

tool_calls: name: parse_data
arguments: data_label: D7
type: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float score(char *string, char *query) {
  size_t string_length, query_length, match_length;
  string_length = strlen(string);
  query_length = strlen(query);
  if (query_length == 0) {
    return 1;
  }
  if (string_length == 0) {
    return 0;
  }
  match_length = min_match_length(string, query);
  if (match_length == 0) {
    return 0;
  }
  return (float)query_length / (float)match_length / (float)string_length;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <soru_sor@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L19:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L35
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L35:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  cmpl   $0x0,-0xc(%rbp)
  jle    L19
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D38
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: string

tool: D38: Sonuc = 

tool: D28: %d

tool: D5: Cok Guzel Dogru Bildin :)

tool: D21: Yanlis Cevap Verdiniz Tekrar Deneyiniz :(


assistant: ```c
int main() {
  srand(time(NULL));
  int carpim_sonucu;
  carpim_sonucu = soru_sor();
  int sonsuz_dongu = 0;
  while (sonsuz_dongu < 1) {
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    if (girilen_cevap == carpim_sonucu) {
      printf("Cok Guzel Dogru Bildin :)");
      break;
    } else {
      printf("Yanlis Cevap Verdiniz Tekrar Deneyiniz :(\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <soru_sor@plt>
  mov    %eax,%ebx
  lea    D24(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D35(%rip),%rbp
  lea    D20(%rip),%r14
  jmp    L22
L29:
  mov    %r14,%rdi
  call   <printf@plt>
L22:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L29
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string
name: disassemble_data
arguments: data_label: D20
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string

tool: D24: Sonuc = 

tool: D35: %d

tool: D20: Yanlis Cevap Verdiniz Tekrar Deneyiniz :(


tool: D29: Cok Guzel Dogru Bildin :)

assistant: ```c
int main() {
  srand(time(NULL));
  int carpim_sonucu;
  carpim_sonucu = soru_sor();
  int sonsuz_dongu = 0;
  while (sonsuz_dongu < 1) {
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    if (girilen_cevap == carpim_sonucu) {
      printf("Cok Guzel Dogru Bildin :)");
      break;
    } else {
      printf("Yanlis Cevap Verdiniz Tekrar Deneyiniz :(\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D2(%rip),%r14
  push   %r13
  lea    D35(%rip),%r13
  push   %r12
  push   %rbp
  lea    D34(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <soru_sor@plt>
  mov    %eax,%ebx
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r14,%rdi
  call   <printf@plt>
L25:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L24
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type: string
name: read_data
arguments: data_label: D35
type: string
name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D2: Yanlis Cevap Verdiniz Tekrar Deneyiniz :(


tool: D35: Sonuc = 

tool: D34: %d

tool: D15: Cok Guzel Dogru Bildin :)

assistant: ```c
int main() {
  srand(time(NULL));
  int carpim_sonucu;
  carpim_sonucu = soru_sor();
  int sonsuz_dongu = 0;
  while (sonsuz_dongu < 1) {
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    if (girilen_cevap == carpim_sonucu) {
      printf("Cok Guzel Dogru Bildin :)");
      break;
    } else {
      printf("Yanlis Cevap Verdiniz Tekrar Deneyiniz :(\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D17(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <soru_sor@plt>
  mov    %eax,%ebx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r14,%rdi
  call   <printf@plt>
L11:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L22
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string

tool: D17: Yanlis Cevap Verdiniz Tekrar Deneyiniz :(


tool: D2: Sonuc = 

tool: D14: %d

tool: D38: Cok Guzel Dogru Bildin :)

assistant: ```c
int main() {
  srand(time(NULL));
  int carpim_sonucu;
  carpim_sonucu = soru_sor();
  int sonsuz_dongu = 0;
  while (sonsuz_dongu < 1) {
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    if (girilen_cevap == carpim_sonucu) {
      printf("Cok Guzel Dogru Bildin :)");
      break;
    } else {
      printf("Yanlis Cevap Verdiniz Tekrar Deneyiniz :(\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L44
L18:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdi
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  add    %rdi,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L44:
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    D16(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jg     L35
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jge    L47
L35:
  mov    $0x0,%eax
  jmp    L1
L47:
  mov    -0x8(%rbp),%rax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int x) {
  long res = 0;
  while (x != 0) {
    res = res * 10 + x % 10;
    x = x / 10;
  }
  if (res > INT_MAX || res < INT_MIN)
    return 0;
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverse>:
  endbr64
  test   %edi,%edi
  je     L37
  mov    $0x0,%edx
L34:
  lea    (%rdx,%rdx,4),%rcx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  lea    (%rdi,%rcx,2),%rdx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L34
L19:
  mov    $0x0,%eax
  mov    D15(%rip),%rcx
  cmp    %rdx,(%rcx)
  jl     L26
  mov    D17(%rip),%rax
  cmp    %rdx,(%rax)
  mov    $0x0,%eax
  cmovle %edx,%eax
L26:
  ret
L37:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int reverse(int x) {
  long res = 0;
  while (x != 0) {
    res = res * 10 + x % 10;
    x = x / 10;
  }
  if (res > INT_MAX || res < INT_MIN)
    return 0;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  xor    %edx,%edx
  test   %edi,%edi
  je     L8
  nopw   0x0(%rax,%rax,1)
L25:
  movslq %edi,%rax
  lea    (%rdx,%rdx,4),%rcx
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  lea    (%rdi,%rcx,2),%rdx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L25
L8:
  mov    D15(%rip),%rcx
  xor    %eax,%eax
  cmp    %rdx,(%rcx)
  jl     L15
  mov    D12(%rip),%rcx
  cmp    %rdx,(%rcx)
  cmovle %edx,%eax
L15:
  ret
```

assistant: ```c
int reverse(int x) {
  long res = 0;
  while (x != 0) {
    res = res * 10 + x % 10;
    x = x / 10;
  }
  if (res > INT_MAX || res < INT_MIN)
    return 0;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  xor    %edx,%edx
  test   %edi,%edi
  je     L17
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %edi,%rax
  lea    (%rdx,%rdx,4),%rcx
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  movslq %edi,%rdi
  lea    (%rdi,%rcx,2),%rdx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L19
L17:
  mov    D7(%rip),%rcx
  xor    %eax,%eax
  cmp    %rdx,(%rcx)
  jl     L27
  mov    D13(%rip),%rcx
  cmp    %rdx,(%rcx)
  cmovle %edx,%eax
L27:
  ret
```

assistant: ```c
int reverse(int x) {
  long res = 0;
  while (x != 0) {
    res = res * 10 + x % 10;
    x = x / 10;
  }
  if (res > INT_MAX || res < INT_MIN)
    return 0;
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bin8_to_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bin8_to_16(unsigned char *a) {
  signed int tmp = (a[0] << 8) + a[1];
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bin8_to_16>:
  endbr64
  movzbl (%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int bin8_to_16(unsigned char *a) {
  signed int tmp = (a[0] << 8) + a[1];
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin8_to_16>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int bin8_to_16(unsigned char *a) {
  signed int tmp = (a[0] << 8) + a[1];
  return tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bin8_to_16>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int bin8_to_16(unsigned char *a) {
  signed int tmp = (a[0] << 8) + a[1];
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L1
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(long long unsigned *arr, long long unsigned l, long long unsigned r) {
  if (l < r) {
    long long unsigned m = l + (r - l) / 2;
    mergeSort(arr, l, m);
    mergeSort(arr, m + 1, r);
    merge(arr, l, m, r);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mergeSort>:
  endbr64
  cmp    %rdx,%rsi
  jb     L0
  ret
L0:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%r13
  sub    %rsi,%r13
  shr    %r13
  add    %rsi,%r13
  mov    %r13,%rdx
  call   <mergeSort>
  lea    0x1(%r13),%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSort(long long unsigned *arr, long long unsigned l, long long unsigned r) {
  if (l < r) {
    long long unsigned m = l + (r - l) / 2;
    mergeSort(arr, l, m);
    mergeSort(arr, m + 1, r);
    merge(arr, l, m, r);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mergeSort>:
  endbr64
  cmp    %rdx,%rsi
  jb     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  push   %r14
  mov    %rdx,%r14
  push   %r13
  sub    %rsi,%r14
  mov    %rdi,%r13
  push   %r12
  shr    %r14
  mov    %rdx,%r12
  push   %rbp
  add    %rsi,%r14
  mov    %rsi,%rbp
  mov    %r14,%rdx
  sub    $0x8,%rsp
  call   <mergeSort>
  lea    0x1(%r14),%rsi
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <mergeSort>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <merge@plt>
```

assistant: ```c
void mergeSort(long long unsigned *arr, long long unsigned l, long long unsigned r) {
  if (l < r) {
    long long unsigned m = l + (r - l) / 2;
    mergeSort(arr, l, m);
    mergeSort(arr, m + 1, r);
    merge(arr, l, m, r);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mergeSort>:
  endbr64
  cmp    %rdx,%rsi
  jb     L30
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rdx,%rax
  push   %r15
  sub    %rsi,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rax,%r13
  push   %r12
  shr    %r13
  mov    %rdx,%r12
  push   %rbp
  add    %rsi,%r13
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r13,%rsi
  jb     L90
  lea    0x1(%r13),%r15
  cmp    %r12,%r15
  jb     L107
L102:
  add    $0x18,%rsp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  pop    %rbx
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <merge@plt>
  nopl   0x0(%rax,%rax,1)
L90:
  mov    %rax,%rbx
  shr    $0x2,%rbx
  add    %rsi,%rbx
  cmp    %rbx,%rsi
  jb     L0
L52:
  lea    0x1(%rbx),%r15
  cmp    %r15,%r13
  ja     L45
L124:
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  lea    0x1(%r13),%r15
  cmp    %r12,%r15
  jae    L102
L107:
  mov    %r12,%rax
  sub    %r15,%rax
  mov    %rax,%rbx
  shr    %rbx
  add    %r15,%rbx
  cmp    %rbx,%r15
  jb     L33
L129:
  lea    0x1(%rbx),%r8
  cmp    %r8,%r12
  ja     L113
L111:
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  jmp    L102
  nopl   (%rax)
L0:
  shr    $0x3,%rax
  lea    (%rax,%rsi,1),%r15
  mov    %r15,%rdx
  call   <mergeSort>
  lea    0x1(%r15),%rsi
  mov    %rbx,%rdx
  mov    %r14,%rdi
  call   <mergeSort>
  mov    %rbx,%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  jmp    L52
  nopl   (%rax)
L113:
  mov    %r12,%r9
  mov    %r8,%rsi
  mov    %r14,%rdi
  mov    %r8,0x8(%rsp)
  sub    %r8,%r9
  shr    %r9
  add    %r8,%r9
  mov    %r9,%rdx
  mov    %r9,(%rsp)
  call   <mergeSort>
  mov    (%rsp),%r9
  mov    %r12,%rdx
  mov    %r14,%rdi
  lea    0x1(%r9),%rsi
  call   <mergeSort>
  mov    (%rsp),%rdx
  mov    %r12,%rcx
  mov    %r14,%rdi
  mov    0x8(%rsp),%rsi
  call   <merge@plt>
  jmp    L111
  nop
L33:
  shr    $0x2,%rax
  mov    %r15,%rsi
  mov    %r14,%rdi
  lea    (%rax,%r15,1),%r8
  mov    %r8,%rdx
  mov    %r8,(%rsp)
  call   <mergeSort>
  mov    (%rsp),%r8
  mov    %rbx,%rdx
  mov    %r14,%rdi
  lea    0x1(%r8),%rsi
  call   <mergeSort>
  mov    (%rsp),%rdx
  mov    %rbx,%rcx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  jmp    L129
  nopl   0x0(%rax)
L45:
  mov    %r13,%r8
  mov    %r15,%rsi
  mov    %r14,%rdi
  sub    %r15,%r8
  shr    %r8
  add    %r15,%r8
  mov    %r8,%rdx
  mov    %r8,(%rsp)
  call   <mergeSort>
  mov    (%rsp),%r8
  mov    %r13,%rdx
  mov    %r14,%rdi
  lea    0x1(%r8),%rsi
  call   <mergeSort>
  mov    (%rsp),%rdx
  mov    %r13,%rcx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  jmp    L124
```

assistant: ```c
void mergeSort(long long unsigned *arr, long long unsigned l, long long unsigned r) {
  if (l < r) {
    long long unsigned m = l + (r - l) / 2;
    mergeSort(arr, l, m);
    mergeSort(arr, m + 1, r);
    merge(arr, l, m, r);
  }
}
```