ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<bcd2_div>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%r10
  mov    (%rdi),%r13
  mov    (%rsi),%r12
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  mov    $0x34,%r9d
  mov    $0x18,%r8d
  mov    $0xc,%edi
  mov    $0x0,%edx
  mov    $0xf,%ebp
  jmp    L2
L26:
  mov    %ebp,%esi
  mov    %r9d,%ecx
  shl    %cl,%esi
  movslq %esi,%rax
  and    %r13,%rax
  sar    %cl,%rax
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,2),%rax
  cqto
  idiv   %r10
  xor    $0xfffffff,%esi
  movslq %esi,%rsi
  and    (%r11),%rsi
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%r11)
  test   %rdi,%rdi
  js     L12
L27:
  sub    $0x1,%rdi
  sub    $0x4,%r8d
  sub    $0x4,%r9d
L2:
  lea    0x1(%rdi),%rax
  cmp    $0x6,%rax
  jle    L26
  mov    %ebp,%esi
  mov    %r8d,%ecx
  shl    %cl,%esi
  movslq %esi,%rax
  and    %r12,%rax
  sar    %cl,%rax
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,2),%rax
  cqto
  idiv   %r10
  xor    $0xfffffff,%esi
  movslq %esi,%rsi
  and    (%rbx),%rsi
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%rbx)
  jmp    L27
L12:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int bcd2_div(long *bcd_low, long *bcd_high, long divisor) {
  long tmp_lo, tmp_hi, carry, d1, res, digit;
  carry = 0;
  tmp_lo = *bcd_low;
  tmp_hi = *bcd_high;
  *bcd_low = *bcd_high = 0;
  for (digit = 13; digit >= 0; digit--) {
    d1 = ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    d1 += 10 * carry;
    res = d1 / divisor;
    carry = d1 % divisor;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bcd2_div>:
  endbr64
  push   %r12
  mov    %rdi,%r10
  mov    %rdx,%r9
  mov    %rsi,%r11
  push   %rbp
  mov    $0xd,%eax
  xor    %edx,%edx
  push   %rbx
  mov    $0xf,%ebx
  mov    (%rdi),%r12
  mov    (%rsi),%rbp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  mov    $0x34,%edi
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L9:
  lea    -0x1c(%rdi),%ecx
  mov    %ebx,%esi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %rbp,%rax
  movslq %esi,%rsi
  and    (%r11),%rsi
  sar    %cl,%rax
  add    %rdx,%rax
  cqto
  idiv   %r9
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%r11)
L3:
  sub    $0x4,%edi
  mov    %r8,%rax
L2:
  lea    (%rdx,%rdx,4),%rdx
  lea    -0x1(%rax),%r8
  add    %rdx,%rdx
  cmp    $0x6,%rax
  jg     L9
  mov    %edi,%ecx
  mov    %ebx,%esi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %r12,%rax
  movslq %esi,%rsi
  and    (%r10),%rsi
  sar    %cl,%rax
  add    %rdx,%rax
  cqto
  idiv   %r9
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%r10)
  cmp    $0xffffffffffffffff,%r8
  jne    L3
  pop    %rbx
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int bcd2_div(long *bcd_low, long *bcd_high, long divisor) {
  long tmp_lo, tmp_hi, carry, d1, res, digit;
  carry = 0;
  tmp_lo = *bcd_low;
  tmp_hi = *bcd_high;
  *bcd_low = *bcd_high = 0;
  for (digit = 13; digit >= 0; digit--) {
    d1 = ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    d1 += 10 * carry;
    res = d1 / divisor;
    carry = d1 % divisor;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bcd2_div>:
  endbr64
  push   %r12
  mov    %rdi,%r10
  mov    %rdx,%r9
  mov    %rsi,%r11
  push   %rbp
  mov    $0xd,%eax
  xor    %edx,%edx
  push   %rbx
  mov    $0xf,%ebx
  mov    (%rdi),%r12
  mov    (%rsi),%rbp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  mov    $0x34,%edi
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L26:
  lea    -0x1c(%rdi),%ecx
  mov    %ebx,%esi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %rbp,%rax
  movslq %esi,%rsi
  and    (%r11),%rsi
  sar    %cl,%rax
  add    %rdx,%rax
  cqto
  idiv   %r9
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%r11)
L9:
  sub    $0x4,%edi
  mov    %r8,%rax
L3:
  lea    (%rdx,%rdx,4),%rdx
  lea    -0x1(%rax),%r8
  add    %rdx,%rdx
  cmp    $0x6,%rax
  jg     L26
  mov    %edi,%ecx
  mov    %ebx,%esi
  shl    %cl,%esi
  movslq %esi,%rax
  xor    $0xfffffff,%esi
  and    %r12,%rax
  movslq %esi,%rsi
  and    (%r10),%rsi
  sar    %cl,%rax
  add    %rdx,%rax
  cqto
  idiv   %r9
  shl    %cl,%rax
  or     %rax,%rsi
  mov    %rsi,(%r10)
  cmp    $0xffffffffffffffff,%r8
  jne    L9
  pop    %rbx
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int bcd2_div(long *bcd_low, long *bcd_high, long divisor) {
  long tmp_lo, tmp_hi, carry, d1, res, digit;
  carry = 0;
  tmp_lo = *bcd_low;
  tmp_hi = *bcd_high;
  *bcd_low = *bcd_high = 0;
  for (digit = 13; digit >= 0; digit--) {
    d1 = ((digit) >= 7) ? (tmp_hi & (0xF << (4 * ((digit)-7)))) >> (((digit)-7) * 4) : (tmp_lo & (0xF << (4 * (digit)))) >> ((digit)*4);
    d1 += 10 * carry;
    res = d1 / divisor;
    carry = d1 % divisor;
    if ((digit) >= 7) {
      *bcd_high &= (0xFFFFFFF ^ (0xF << (4 * ((digit)-7))));
      *bcd_high |= (res << (4 * ((digit)-7)));
    } else {
      *bcd_low = (*bcd_low & (0xFFFFFFF ^ (0xF << (4 * (digit)))));
      *bcd_low |= (res << (4 * (digit)));
    };
  }
  return (carry);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  sub    $0x108,%rsp
  movapd D114(%rip),%xmm0
  mov    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movapd D16(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D99(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D110(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd D123(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movapd D104(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movapd D31(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movapd D15(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  movapd D19(%rip),%xmm0
  movaps %xmm0,0x80(%rsp)
  movapd D64(%rip),%xmm0
  movaps %xmm0,0x90(%rsp)
  movapd D142(%rip),%xmm0
  movaps %xmm0,0xa0(%rsp)
  movapd D98(%rip),%xmm0
  movaps %xmm0,0xb0(%rsp)
  movapd D85(%rip),%xmm0
  movaps %xmm0,0xc0(%rsp)
  movapd D115(%rip),%xmm0
  movaps %xmm0,0xd0(%rsp)
  movapd D69(%rip),%xmm0
  movaps %xmm0,0xe0(%rsp)
  movsd  (%rsp,%rdi,8),%xmm0
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x108,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D114
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D16
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D99
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D110
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D123
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D104
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D31
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D15
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D19
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D64
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D142
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D98
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D85
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D115
type_guessed: f64[2]
name: unpack_data
arguments: data_tag: D69
type_guessed: f64[2]

tool: {"D114": [0.0,12.706]}

tool: {"D16": [4.303,3.182]}

tool: {"D99": [2.776,2.571]}

tool: {"D110": [2.447,2.365]}

tool: {"D123": [2.306,2.262]}

tool: {"D104": [2.228,2.201]}

tool: {"D31": [2.179,2.16]}

tool: {"D15": [2.145,2.131]}

tool: {"D19": [2.12,2.11]}

tool: {"D64": [2.101,2.093]}

tool: {"D142": [2.086,2.08]}

tool: {"D98": [2.074,2.069]}

tool: {"D85": [2.064,2.06]}

tool: {"D115": [2.056,2.052]}

tool: {"D69": [2.048,2.045]}

assistant: ```c
double test(unsigned X) {
  double student_t[30] = {0.0, 12.706, 4.303, 3.182, 2.776, 2.571, 2.447, 2.365, 2.306, 2.262, 2.228, 2.201, 2.179, 2.160, 2.145, 2.131, 2.120, 2.110, 2.101, 2.093, 2.086, 2.080, 2.074, 2.069, 2.064, 2.060, 2.056, 2.052, 2.048, 2.045};
  return student_t[X];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__ctype_tolower_loc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffff80,-0xc(%rbp)
  jmp    L16
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0xff,-0xc(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: %d->0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  const int **lower_loc = __ctype_tolower_loc();
  for (int i = -128; i < 256; i++) {
    printf("%d->0x%x\n", i, (*lower_loc)[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <__ctype_tolower_loc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L7:
  mov    0x0(%rbp),%rax
  mov    -0x200(%rax,%rbx,4),%edx
  lea    -0x80(%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x180,%rbx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string

tool: D7: %d->0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  const int **lower_loc = __ctype_tolower_loc();
  for (int i = -128; i < 256; i++) {
    printf("%d->0x%x\n", i, (*lower_loc)[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <__ctype_tolower_loc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp),%rax
  lea    -0x80(%rbx),%esi
  mov    %r12,%rdi
  mov    -0x200(%rax,%rbx,4),%edx
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x180,%rbx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: %d->0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  const int **lower_loc = __ctype_tolower_loc();
  for (int i = -128; i < 256; i++) {
    printf("%d->0x%x\n", i, (*lower_loc)[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <__ctype_tolower_loc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x0(%rbp),%rax
  lea    -0x80(%rbx),%esi
  mov    %r12,%rdi
  mov    -0x200(%rax,%rbx,4),%edx
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x180,%rbx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: %d->0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  const int **lower_loc = __ctype_tolower_loc();
  for (int i = -128; i < 256; i++) {
    printf("%d->0x%x\n", i, (*lower_loc)[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_skip_bad_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_is_space_or_newline@plt>
  test   %rax,%rax
  jne    L2
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L38
  jmp    L28
L2:
  nop
L28:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _skip_bad_tag(const char *buffer, const int length) {
  int offset;
  for (offset = 0; offset < length; offset++) {
    if (_is_space_or_newline(buffer[offset])) {
      break;
    }
  }
  return offset;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_skip_bad_tag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L32
  mov    %esi,%r12d
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L0:
  movsbl (%rbx),%edi
  call   <_is_space_or_newline@plt>
  test   %rax,%rax
  jne    L33
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jne    L0
  mov    %r12d,%ebp
L33:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    $0x0,%ebp
  jmp    L33
```

assistant: ```c
int _skip_bad_tag(const char *buffer, const int length) {
  int offset;
  for (offset = 0; offset < length; offset++) {
    if (_is_space_or_newline(buffer[offset])) {
      break;
    }
  }
  return offset;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_skip_bad_tag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L30
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L5:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L26
L36:
  movsbl (%rbx),%edi
  call   <_is_space_or_newline@plt>
  test   %rax,%rax
  je     L5
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  xor    %r12d,%r12d
  jmp    L26
```

assistant: ```c
int _skip_bad_tag(const char *buffer, const int length) {
  int offset;
  for (offset = 0; offset < length; offset++) {
    if (_is_space_or_newline(buffer[offset])) {
      break;
    }
  }
  return offset;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_skip_bad_tag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L47
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L22:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L28
L29:
  movsbl (%rbx),%edi
  call   <_is_space_or_newline@plt>
  test   %rax,%rax
  je     L22
L28:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  xor    %r12d,%r12d
  jmp    L28
```

assistant: ```c
int _skip_bad_tag(const char *buffer, const int length) {
  int offset;
  for (offset = 0; offset < length; offset++) {
    if (_is_space_or_newline(buffer[offset])) {
      break;
    }
  }
  return offset;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max_heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L26
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L26
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L18
L26:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L50
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L50
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L32
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x20(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_heapify>
L32:
  nop
  leave
  ret
```

assistant: ```c
void max_heapify(int a[], int i, int heap_size) {
  int left = 2 * i + 1;
  int right = 2 * i + 2;
  int largest;
  if (left < heap_size && a[left] > a[i]) {
    largest = left;
  } else {
    largest = i;
  }
  if ((right < heap_size) && (a[right] > a[largest])) {
    largest = right;
  }
  if (largest != i) {
    swap(&a[largest], &a[i]);
    max_heapify(a, largest, heap_size);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_heapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%eax
  mov    %edx,%r12d
  lea    (%rsi,%rsi,1),%ebx
  lea    0x1(%rbx),%edx
  add    $0x2,%ebx
  cmp    %r12d,%edx
  jge    L62
  movslq %edx,%rcx
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jle    L62
  cmp    %r12d,%ebx
  jge    L54
  movslq %ebx,%rsi
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rsi,4)
  cmovle %edx,%ebx
  jmp    L30
L54:
  mov    %edx,%ebx
  jmp    L30
L62:
  cmp    %r12d,%ebx
  jge    L4
  movslq %ebx,%rdx
  movslq %eax,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rdx,4)
  jle    L4
L30:
  cmp    %eax,%ebx
  je     L4
  cltq
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <max_heapify>
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void max_heapify(int a[], int i, int heap_size) {
  int left = 2 * i + 1;
  int right = 2 * i + 2;
  int largest;
  if (left < heap_size && a[left] > a[i]) {
    largest = left;
  } else {
    largest = i;
  }
  if ((right < heap_size) && (a[right] > a[largest])) {
    largest = right;
  }
  if (largest != i) {
    swap(&a[largest], &a[i]);
    max_heapify(a, largest, heap_size);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_heapify>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L61
L58:
  movslq %esi,%rax
  movslq %edx,%rcx
  mov    0x0(%rbp,%rax,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jle    L13
  cmp    %r12d,%ebx
  jl     L21
  mov    %edx,%ebx
L43:
  cmp    %esi,%ebx
  je     L33
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  mov    %ebx,%esi
L61:
  lea    (%rsi,%rsi,1),%ebx
  lea    0x1(%rbx),%edx
  add    $0x2,%ebx
  cmp    %r12d,%edx
  jl     L58
L13:
  cmp    %r12d,%ebx
  jge    L33
  movslq %esi,%rax
  movslq %ebx,%rdx
  mov    0x0(%rbp,%rax,4),%ecx
  cmp    %ecx,0x0(%rbp,%rdx,4)
  jg     L43
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  movslq %ebx,%rdi
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rdi,4)
  cmovle %edx,%ebx
  jmp    L43
```

assistant: ```c
void max_heapify(int a[], int i, int heap_size) {
  int left = 2 * i + 1;
  int right = 2 * i + 2;
  int largest;
  if (left < heap_size && a[left] > a[i]) {
    largest = left;
  } else {
    largest = i;
  }
  if ((right < heap_size) && (a[right] > a[largest])) {
    largest = right;
  }
  if (largest != i) {
    swap(&a[largest], &a[i]);
    max_heapify(a, largest, heap_size);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_heapify>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    (%rsi,%rsi,1),%ebx
  lea    0x1(%rbx),%edx
  add    $0x2,%ebx
  cmp    %r12d,%edx
  jge    L65
  nopl   0x0(%rax)
L5:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  movslq %esi,%rax
  mov    0x0(%rbp,%rax,4),%ecx
  cmp    %ecx,(%rdi)
  jle    L65
  cmp    %r12d,%ebx
  jl     L2
L4:
  mov    %edx,%ebx
L42:
  cmp    %esi,%ebx
  je     L27
  lea    0x0(%rbp,%rax,4),%rsi
  call   <swap@plt>
  mov    %ebx,%esi
  lea    (%rsi,%rsi,1),%ebx
  lea    0x1(%rbx),%edx
  add    $0x2,%ebx
  cmp    %r12d,%edx
  jl     L5
L65:
  cmp    %r12d,%ebx
  jge    L27
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  movslq %esi,%rax
  mov    (%rdi),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jl     L42
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  movslq %ebx,%rcx
  mov    (%rdi),%r8d
  lea    0x0(%rbp,%rcx,4),%rcx
  cmp    %r8d,(%rcx)
  jle    L4
  mov    %rcx,%rdi
  jmp    L42
```

assistant: ```c
void max_heapify(int a[], int i, int heap_size) {
  int left = 2 * i + 1;
  int right = 2 * i + 2;
  int largest;
  if (left < heap_size && a[left] > a[i]) {
    largest = left;
  } else {
    largest = i;
  }
  if ((right < heap_size) && (a[right] > a[largest])) {
    largest = right;
  }
  if (largest != i) {
    swap(&a[largest], &a[i]);
    max_heapify(a, largest, heap_size);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memdup(const void *str, size_t n) {
  void *new = malloc(n);
  if (new)
    memcpy(new, str, n);
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(const void *str, size_t n) {
  void *new = malloc(n);
  if (new)
    memcpy(new, str, n);
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *str, size_t n) {
  void *new = malloc(n);
  if (new)
    memcpy(new, str, n);
  return new;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *str, size_t n) {
  void *new = malloc(n);
  if (new)
    memcpy(new, str, n);
  return new;
}
```