ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<kr1_hash_str>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L181
  lea    -0x1(%rsi),%rax
  cmp    $0xe,%rax
  jbe    L60
  mov    %rsi,%rcx
  pxor   %xmm2,%xmm2
  pxor   %xmm6,%xmm6
  mov    %rdi,%rax
  and    $0xfffffffffffffff0,%rcx
  pxor   %xmm4,%xmm4
  add    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L110:
  movdqu (%rax),%xmm0
  movdqa %xmm6,%xmm3
  add    $0x10,%rax
  pcmpgtb %xmm0,%xmm3
  movdqa %xmm0,%xmm1
  punpcklbw %xmm3,%xmm1
  punpckhbw %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm0,%xmm3
  movdqa %xmm0,%xmm5
  punpcklwd %xmm3,%xmm5
  punpckhwd %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm1,%xmm3
  paddd  %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpcklwd %xmm3,%xmm5
  punpckhwd %xmm3,%xmm1
  paddd  %xmm5,%xmm1
  paddd  %xmm1,%xmm0
  paddd  %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L110
  movdqa %xmm2,%xmm0
  mov    %rdx,%rcx
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffff0,%rcx
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%eax
  test   $0xf,%dl
  je     L139
L74:
  movsbl (%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x1(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x1(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x2(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x2(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x3(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x3(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x4(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x4(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x5(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x5(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x6(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x6(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x7(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x7(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x8(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x8(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0x9(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0x9(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0xa(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0xa(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0xb(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0xb(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0xc(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0xc(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0xd(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0xd(%rdi,%rcx,1),%esi
  add    %esi,%eax
  lea    0xe(%rcx),%rsi
  cmp    %rsi,%rdx
  jbe    L39
  movsbl 0xe(%rdi,%rcx,1),%edx
  add    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L181:
  xor    %eax,%eax
L39:
  ret
L60:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L74
L139:
  ret
```

assistant: ```c
unsigned int kr1_hash_str(const char *str, size_t str_len) {
  unsigned int hash;
  size_t i;
  hash = 0;
  for (i = 0; i < str_len; ++i) {
    hash += (unsigned int)str[i];
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<wait_more>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x389fd97f,%rax
  jg     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2faf080(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wait_more(long *wait) {
  if (*wait + 50000000L <= 999999999L)
    *wait += 50000000L;
}
```
user: What is the c source code of the assembly code below:

```asm
<wait_more>:
  endbr64
  mov    (%rdi),%rax
  cmp    $0x389fd97f,%rax
  jg     L7
  add    $0x2faf080,%rax
  mov    %rax,(%rdi)
L7:
  ret
```

assistant: ```c
void wait_more(long *wait) {
  if (*wait + 50000000L <= 999999999L)
    *wait += 50000000L;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wait_more>:
  endbr64
  mov    (%rdi),%rax
  cmp    $0x389fd97f,%rax
  jg     L7
  add    $0x2faf080,%rax
  mov    %rax,(%rdi)
L7:
  ret
```

assistant: ```c
void wait_more(long *wait) {
  if (*wait + 50000000L <= 999999999L)
    *wait += 50000000L;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait_more>:
  endbr64
  mov    (%rdi),%rax
  cmp    $0x389fd97f,%rax
  jg     L4
  add    $0x2faf080,%rax
  mov    %rax,(%rdi)
L4:
  ret
```

assistant: ```c
void wait_more(long *wait) {
  if (*wait + 50000000L <= 999999999L)
    *wait += 50000000L;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inttoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  jbe    L3
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  sub    %eax,%ecx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <inttoa>
L3:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void inttoa(int i, char *s, int n) {
  if (i / 10) {
    inttoa(i / 10, s, n - 1);
  }
  s[n] = (char)(((int)'0') + i % 10);
}
```
user: What is the c source code of the assembly code below:

```asm
<inttoa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    0x9(%rdi),%eax
  cmp    $0x12,%eax
  ja     L2
L3:
  movslq %r12d,%r12
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    -0x1(%rdx),%edx
  movslq %edi,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <inttoa>
  jmp    L3
```

assistant: ```c
void inttoa(int i, char *s, int n) {
  if (i / 10) {
    inttoa(i / 10, s, n - 1);
  }
  s[n] = (char)(((int)'0') + i % 10);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inttoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x9(%rbp),%eax
  mov    %rbp,%rbx
  sub    $0x28,%rsp
  cmp    $0x12,%eax
  ja     L2
L32:
  imul   $0x66666667,%rbp,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x0(%r13,%r12,1)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  imul   $0x66666667,%rbp,%r14
  mov    %ebp,%eax
  lea    -0x1(%r12),%ecx
  sar    $0x1f,%eax
  sar    $0x22,%r14
  sub    %eax,%r14d
  lea    0x9(%r14),%eax
  movslq %r14d,%r15
  cmp    $0x12,%eax
  ja     L13
L34:
  imul   $0x66666667,%r15,%rax
  movslq %ecx,%rdx
  mov    %r14d,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  add    $0x30,%r14d
  mov    %r14b,0x0(%r13,%rdx,1)
  jmp    L32
L13:
  imul   $0x66666667,%r15,%rax
  mov    %r14d,%edx
  lea    -0x2(%r12),%r9d
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    0x9(%rax),%edx
  movslq %eax,%r8
  cmp    $0x12,%edx
  ja     L5
L6:
  imul   $0x66666667,%r8,%rdx
  mov    %eax,%edi
  movslq %r9d,%rsi
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,0x0(%r13,%rsi,1)
  jmp    L34
  nopl   0x0(%rax)
L5:
  imul   $0x66666667,%r8,%rdi
  mov    %eax,%esi
  lea    -0x3(%r12),%edx
  mov    %ecx,0x18(%rsp)
  sar    $0x1f,%esi
  mov    %r9d,0x1c(%rsp)
  mov    %r8,0x10(%rsp)
  sar    $0x22,%rdi
  mov    %eax,0xc(%rsp)
  sub    %esi,%edi
  mov    %r13,%rsi
  call   <inttoa>
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  mov    0x10(%rsp),%r8
  mov    0xc(%rsp),%eax
  jmp    L6
```

assistant: ```c
void inttoa(int i, char *s, int n) {
  if (i / 10) {
    inttoa(i / 10, s, n - 1);
  }
  s[n] = (char)(((int)'0') + i % 10);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inttoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x9(%rbp),%eax
  mov    %rbp,%rbx
  sub    $0x28,%rsp
  cmp    $0x12,%eax
  ja     L12
L33:
  imul   $0x66666667,%rbp,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x0(%r13,%r12,1)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  imul   $0x66666667,%rbp,%r14
  mov    %ebp,%eax
  lea    -0x1(%r12),%ecx
  sar    $0x1f,%eax
  sar    $0x22,%r14
  sub    %eax,%r14d
  lea    0x9(%r14),%eax
  movslq %r14d,%r15
  cmp    $0x12,%eax
  ja     L26
L50:
  imul   $0x66666667,%r15,%rax
  movslq %ecx,%rdx
  mov    %r14d,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  add    $0x30,%r14d
  mov    %r14b,0x0(%r13,%rdx,1)
  jmp    L33
L26:
  imul   $0x66666667,%r15,%rax
  mov    %r14d,%edx
  lea    -0x2(%r12),%r9d
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    0x9(%rax),%edx
  movslq %eax,%r8
  cmp    $0x12,%edx
  ja     L30
L32:
  imul   $0x66666667,%r8,%rdx
  mov    %eax,%edi
  movslq %r9d,%rsi
  sar    $0x1f,%edi
  sar    $0x22,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,0x0(%r13,%rsi,1)
  jmp    L50
  nopl   0x0(%rax)
L30:
  imul   $0x66666667,%r8,%rdi
  mov    %eax,%esi
  lea    -0x3(%r12),%edx
  mov    %ecx,0x18(%rsp)
  sar    $0x1f,%esi
  mov    %r9d,0x1c(%rsp)
  mov    %r8,0x10(%rsp)
  sar    $0x22,%rdi
  mov    %eax,0xc(%rsp)
  sub    %esi,%edi
  mov    %r13,%rsi
  call   <inttoa>
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  mov    0x10(%rsp),%r8
  mov    0xc(%rsp),%eax
  jmp    L32
```

assistant: ```c
void inttoa(int i, char *s, int n) {
  if (i / 10) {
    inttoa(i / 10, s, n - 1);
  }
  s[n] = (char)(((int)'0') + i % 10);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<op_clip_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L13
  lea    D39(%rip),%rax
  mov    %rax,-0x40(%rbp)
L13:
  cmpl   $0x0,-0x14(%rbp)
  jle    L8
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D31(%rip),%r9
  mov    %esi,%r8d
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L0
L8:
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D48(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L0:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x46,%edx
  mov    $0x1,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D39
data_type: string
name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D48
data_type: string
name: read_data
arguments: data_label: D47
data_type: string

tool: 

tool: D31:  

tool: D12: %s%s:%*s

tool: D48: %s%s: 

tool: D47: clip the current set of interval values to a specified min and/or max


assistant: ```c
void op_clip_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "clip the current set of interval values to a specified min and/or max\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<op_clip_short>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x2(%rbx),%eax
  sub    %edx,%eax
  test   %rbp,%rbp
  lea    D19(%rip),%rdx
  cmove  %rdx,%rbp
  test   %eax,%eax
  jle    L19
  lea    D20(%rip),%r9
  lea    0x1(%rax),%r8d
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D29(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L12:
  mov    %r12,%rcx
  mov    $0x46,%edx
  mov    $0x1,%esi
  lea    D32(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D28(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string

tool: 

tool: D20:  

tool: D29: %s%s:%*s

tool: D32: clip the current set of interval values to a specified min and/or max


tool: D28: %s%s: 

assistant: ```c
void op_clip_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "clip the current set of interval values to a specified min and/or max\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<op_clip_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D23(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L19
  lea    0x1(%rax),%r8d
  lea    D5(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D34(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L10:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x46,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D38(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L19:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D37(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: tag: D37
type_guessed: string

tool: 

tool: D5:  

tool: D34: %s%s:%*s

tool: D38: clip the current set of interval values to a specified min and/or max


tool: D37: %s%s: 

assistant: ```c
void op_clip_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "clip the current set of interval values to a specified min and/or max\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<op_clip_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D45(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L18
  lea    0x1(%rax),%r8d
  lea    D30(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D49(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L8:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x46,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D21(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L18:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D8(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_tag: D45
datatype: string
name: parse_data
arguments: data_tag: D30
datatype: string
name: parse_data
arguments: data_tag: D49
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string

tool: 

tool: D30:  

tool: D49: %s%s:%*s

tool: D21: clip the current set of interval values to a specified min and/or max


tool: D8: %s%s: 

assistant: ```c
void op_clip_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "clip the current set of interval values to a specified min and/or max\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TS_RESP_verify_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <TS_RESP_get_token@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <TS_RESP_get_tst_info@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <TS_check_status_info@plt>
  test   %eax,%eax
  je     L25
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <int_TS_RESP_verify_token@plt>
  test   %eax,%eax
  je     L14
  movl   $0x1,-0x14(%rbp)
  jmp    L22
L25:
  nop
  jmp    L22
L14:
  nop
L22:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int TS_RESP_verify_response(TS_VERIFY_CTX *ctx, TS_RESP *response) {
  PKCS7 *token = TS_RESP_get_token(response);
  TS_TST_INFO *tst_info = TS_RESP_get_tst_info(response);
  int ret = 0;
  if (!TS_check_status_info(response))
    goto err;
  if (!int_TS_RESP_verify_token(ctx, token, tst_info))
    goto err;
  ret = 1;
err:
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TS_RESP_verify_response>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <TS_RESP_get_token@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <TS_RESP_get_tst_info@plt>
  mov    %rax,%r13
  mov    %rbx,%rdi
  call   <TS_check_status_info@plt>
  test   %eax,%eax
  jne    L14
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <int_TS_RESP_verify_token@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L3
```

assistant: ```c
int TS_RESP_verify_response(TS_VERIFY_CTX *ctx, TS_RESP *response) {
  PKCS7 *token = TS_RESP_get_token(response);
  TS_TST_INFO *tst_info = TS_RESP_get_tst_info(response);
  int ret = 0;
  if (!TS_check_status_info(response))
    goto err;
  if (!int_TS_RESP_verify_token(ctx, token, tst_info))
    goto err;
  ret = 1;
err:
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TS_RESP_verify_response>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <TS_RESP_get_token@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <TS_RESP_get_tst_info@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <TS_check_status_info@plt>
  test   %eax,%eax
  je     L7
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <int_TS_RESP_verify_token@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int TS_RESP_verify_response(TS_VERIFY_CTX *ctx, TS_RESP *response) {
  PKCS7 *token = TS_RESP_get_token(response);
  TS_TST_INFO *tst_info = TS_RESP_get_tst_info(response);
  int ret = 0;
  if (!TS_check_status_info(response))
    goto err;
  if (!int_TS_RESP_verify_token(ctx, token, tst_info))
    goto err;
  ret = 1;
err:
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TS_RESP_verify_response>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <TS_RESP_get_token@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <TS_RESP_get_tst_info@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <TS_check_status_info@plt>
  test   %eax,%eax
  je     L7
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <int_TS_RESP_verify_token@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int TS_RESP_verify_response(TS_VERIFY_CTX *ctx, TS_RESP *response) {
  PKCS7 *token = TS_RESP_get_token(response);
  TS_TST_INFO *tst_info = TS_RESP_get_tst_info(response);
  int ret = 0;
  if (!TS_check_status_info(response))
    goto err;
  if (!int_TS_RESP_verify_token(ctx, token, tst_info))
    goto err;
  ret = 1;
err:
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  fldt   0xef5(%rip)        # 2020 <_fini+0xe8c>
  fstl   -0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  movsd  -0x8(%rbp),%xmm1
  movsd  %xmm1,-0x18(%rbp)
  fldl   -0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D19: ld = %.21LG, d = %.17g


assistant: ```c
int main() {
  register long double ld = -2.83090232717332442064e-324L;
  volatile double d;
  d = ld;
  printf("ld = %.21LG, d = %.17g\n", ld, d);
  ld = d;
  printf("ld = %.21LG, d = %.17g\n", ld, d);
}
```