ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0xa8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0xa4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  movl   $0x1,-0xb0(%rbp)
  movl   $0x1,-0xac(%rbp)
  jmp    L3
L37:
  lea    -0x90(%rbp),%rax
  mov    %rax,-0xa0(%rbp)
  jmp    L2
L51:
  addq   $0x1,-0xa0(%rbp)
L2:
  mov    -0xa0(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L51
  mov    -0xa0(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x90(%rbp),%rcx
  mov    -0xa8(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <mpz_set_str@plt>
  mov    -0xa0(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0xa8(%rbp),%ecx
  mov    -0xa8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_pow_ui@plt>
  mov    -0xa4(%rbp),%edx
  mov    -0xa8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jle    L21
  mov    -0xa8(%rbp),%edx
  mov    -0xa4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  mov    -0xac(%rbp),%eax
  mov    %eax,-0xb0(%rbp)
L21:
  addl   $0x1,-0xac(%rbp)
  addl   $0x1,-0xac(%rbp)
L3:
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L37
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xb0(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D27
type: string

tool: D6: r

tool: D7: resources/p099_base_exp.txt

tool: D27: %d


assistant: ```c
int main(int argc, char **argv) {
  FILE *file = fopen("resources/p099_base_exp.txt", "r");
  mpz_t current;
  mpz_init(current);
  mpz_t max;
  mpz_init(max);
  int max_index = 1;
  char line[128];
  for (int current_index = 1; fgets(line, sizeof line, file); ++current_index) {
    char *c = line;
    for (; *c != ','; ++c)
      ;
    *c = 0;
    mpz_set_str(current, line, 10);
    mpz_pow_ui(current, current, atoi(c + 1));
    if (mpz_cmp(current, max) > 0) {
      mpz_set(max, current);
      max_index = current_index;
    }
    current_index++;
  }
  fclose(file);
  printf("%d\n", max_index);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r14
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    $0x0,%edi
  call   <mpz_init@plt>
  mov    $0x1,%r12d
  mov    $0x1,%r15d
  mov    %rsp,%r13
  jmp    L52
L63:
  add    $0x2,%r12d
L52:
  mov    %r14,%rdx
  mov    $0x80,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L15
  mov    %rsp,%rbx
  cmpb   $0x2c,(%rsp)
  je     L44
L54:
  add    $0x1,%rbx
  cmpb   $0x2c,(%rbx)
  jne    L54
L44:
  movb   $0x0,(%rbx)
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_set_str@plt>
  lea    0x1(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_pow_ui@plt>
  mov    $0x0,%edi
  mov    %edi,%esi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jle    L63
  mov    %ebp,%esi
  mov    $0x0,%edi
  call   <mpz_set@plt>
  mov    %r12d,%r15d
  jmp    L63
L15:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    %r15d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D18
type_guessed: string

tool: D17: r

tool: D15: resources/p099_base_exp.txt

tool: D18: %d


assistant: ```c
int main(int argc, char **argv) {
  FILE *file = fopen("resources/p099_base_exp.txt", "r");
  mpz_t current;
  mpz_init(current);
  mpz_t max;
  mpz_init(max);
  int max_index = 1;
  char line[128];
  for (int current_index = 1; fgets(line, sizeof line, file); ++current_index) {
    char *c = line;
    for (; *c != ','; ++c)
      ;
    *c = 0;
    mpz_set_str(current, line, 10);
    mpz_pow_ui(current, current, atoi(c + 1));
    if (mpz_cmp(current, max) > 0) {
      mpz_set(max, current);
      max_index = current_index;
    }
    current_index++;
  }
  fclose(file);
  printf("%d\n", max_index);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rsi
  lea    D10(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fopen@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r13,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L45
  cmpb   $0x2c,(%rsp)
  mov    %rbp,%rbx
  je     L37
  xchg   %ax,%ax
L44:
  add    $0x1,%rbx
  cmpb   $0x2c,(%rbx)
  jne    L44
L37:
  movb   $0x0,(%rbx)
  xor    %r15d,%r15d
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <mpz_set_str@plt>
  lea    0x1(%rbx),%rdi
  call   <atoi@plt>
  mov    %r15d,%esi
  mov    %r15d,%edi
  mov    %eax,%edx
  call   <mpz_pow_ui@plt>
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jle    L1
  mov    %r15d,%esi
  xor    %edi,%edi
  mov    %r12d,%r14d
  call   <mpz_set@plt>
L1:
  add    $0x2,%r12d
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14d,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string

tool: D26: r

tool: D10: resources/p099_base_exp.txt

tool: D23: %d


assistant: ```c
int main(int argc, char **argv) {
  FILE *file = fopen("resources/p099_base_exp.txt", "r");
  mpz_t current;
  mpz_init(current);
  mpz_t max;
  mpz_init(max);
  int max_index = 1;
  char line[128];
  for (int current_index = 1; fgets(line, sizeof line, file); ++current_index) {
    char *c = line;
    for (; *c != ','; ++c)
      ;
    *c = 0;
    mpz_set_str(current, line, 10);
    mpz_pow_ui(current, current, atoi(c + 1));
    if (mpz_cmp(current, max) > 0) {
      mpz_set(max, current);
      max_index = current_index;
    }
    current_index++;
  }
  fclose(file);
  printf("%d\n", max_index);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%rsi
  lea    D28(%rip),%rdi
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fopen@plt>
  xor    %edi,%edi
  mov    %rax,%r13
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %r13,%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L48
  cmpb   $0x2c,(%rsp)
  mov    %rbp,%rbx
  je     L31
  xchg   %ax,%ax
L13:
  add    $0x1,%rbx
  cmpb   $0x2c,(%rbx)
  jne    L13
L31:
  movb   $0x0,(%rbx)
  xor    %r15d,%r15d
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <mpz_set_str@plt>
  lea    0x1(%rbx),%rdi
  call   <atoi@plt>
  mov    %r15d,%esi
  mov    %r15d,%edi
  mov    %eax,%edx
  call   <mpz_pow_ui@plt>
  xor    %esi,%esi
  mov    %r15d,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jle    L19
  mov    %r15d,%esi
  xor    %edi,%edi
  mov    %r12d,%r14d
  call   <mpz_set@plt>
L19:
  add    $0x2,%r12d
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14d,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D28
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string

tool: D19: r

tool: D28: resources/p099_base_exp.txt

tool: D23: %d


assistant: ```c
int main(int argc, char **argv) {
  FILE *file = fopen("resources/p099_base_exp.txt", "r");
  mpz_t current;
  mpz_init(current);
  mpz_t max;
  mpz_init(max);
  int max_index = 1;
  char line[128];
  for (int current_index = 1; fgets(line, sizeof line, file); ++current_index) {
    char *c = line;
    for (; *c != ','; ++c)
      ;
    *c = 0;
    mpz_set_str(current, line, 10);
    mpz_pow_ui(current, current, atoi(c + 1));
    if (mpz_cmp(current, max) > 0) {
      mpz_set(max, current);
      max_index = current_index;
    }
    current_index++;
  }
  fclose(file);
  printf("%d\n", max_index);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gffi_get_uint_16_swapped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
uint16_t gffi_get_uint_16_swapped(uint8_t *location, int offset) {
  uint8_t buf[2];
  buf[1] = location[offset];
  buf[0] = location[offset + 1];
  return *(uint16_t *)buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<gffi_get_uint_16_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x4(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
uint16_t gffi_get_uint_16_swapped(uint8_t *location, int offset) {
  uint8_t buf[2];
  buf[1] = location[offset];
  buf[0] = location[offset + 1];
  return *(uint16_t *)buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gffi_get_uint_16_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x4(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
uint16_t gffi_get_uint_16_swapped(uint8_t *location, int offset) {
  uint8_t buf[2];
  buf[1] = location[offset];
  buf[0] = location[offset + 1];
  return *(uint16_t *)buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gffi_get_uint_16_swapped>:
  endbr64
  movslq %esi,%rsi
  mov    0x4(%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
uint16_t gffi_get_uint_16_swapped(uint8_t *location, int offset) {
  uint8_t buf[2];
  buf[1] = location[offset];
  buf[0] = location[offset + 1];
  return *(uint16_t *)buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<screen_cursor_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x2(%rbp)
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzwl -0x2(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x3d5,%edi
  call   <port_byte_out@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzwl -0x2(%rbp),%eax
  shr    $0x8,%ax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x3d5,%edi
  call   <port_byte_out@plt>
  nop
  leave
  ret
```

assistant: ```c
void screen_cursor_to(unsigned int row, unsigned int col) {
  unsigned short position = (row * 80) + col;
  port_byte_out(0x3D4, 0x0F);
  port_byte_out(0x3D5, (unsigned char)(position & 0xFF));
  port_byte_out(0x3D4, 0x0E);
  port_byte_out(0x3D5, (unsigned char)((position >> 8) & 0xFF));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<screen_cursor_to>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%ebx
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  call   <port_byte_out@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  shr    $0x8,%bx
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  call   <port_byte_out@plt>
  pop    %rbx
  ret
```

assistant: ```c
void screen_cursor_to(unsigned int row, unsigned int col) {
  unsigned short position = (row * 80) + col;
  port_byte_out(0x3D4, 0x0F);
  port_byte_out(0x3D5, (unsigned char)(position & 0xFF));
  port_byte_out(0x3D4, 0x0E);
  port_byte_out(0x3D5, (unsigned char)((position >> 8) & 0xFF));
}
```
user: What is the c source code of the assembly code below:

```asm
<screen_cursor_to>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%ebx
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  shr    $0x8,%bx
  call   <port_byte_out@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzwl %bx,%esi
  mov    $0x3d5,%edi
  pop    %rbx
  jmp    1050 <port_byte_out@plt>
```

assistant: ```c
void screen_cursor_to(unsigned int row, unsigned int col) {
  unsigned short position = (row * 80) + col;
  port_byte_out(0x3D4, 0x0F);
  port_byte_out(0x3D5, (unsigned char)(position & 0xFF));
  port_byte_out(0x3D4, 0x0E);
  port_byte_out(0x3D5, (unsigned char)((position >> 8) & 0xFF));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<screen_cursor_to>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%ebx
  mov    $0xf,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzbl %bl,%esi
  mov    $0x3d5,%edi
  shr    $0x8,%bx
  call   <port_byte_out@plt>
  mov    $0xe,%esi
  mov    $0x3d4,%edi
  call   <port_byte_out@plt>
  movzwl %bx,%esi
  mov    $0x3d5,%edi
  pop    %rbx
  jmp    1050 <port_byte_out@plt>
```

assistant: ```c
void screen_cursor_to(unsigned int row, unsigned int col) {
  unsigned short position = (row * 80) + col;
  port_byte_out(0x3D4, 0x0F);
  port_byte_out(0x3D5, (unsigned char)(position & 0xFF));
  port_byte_out(0x3D4, 0x0E);
  port_byte_out(0x3D5, (unsigned char)((position >> 8) & 0xFF));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nl2sp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L28
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L27
L22:
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L27:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nl2sp(char *p) {
  while (*p != 0) {
    if (*p == '\n' || *p == '\r')
      *p = ' ';
    p++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nl2sp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L1:
  ret
L9:
  movb   $0x20,(%rdi)
L24:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
L4:
  cmp    $0xa,%al
  je     L9
  cmp    $0xd,%al
  jne    L24
  jmp    L9
```

assistant: ```c
void nl2sp(char *p) {
  while (*p != 0) {
    if (*p == '\n' || *p == '\r')
      *p = ' ';
    p++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<nl2sp>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x1,%rdi
L16:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  cmp    $0xa,%al
  je     L46
  cmp    $0xd,%al
  jne    L11
L46:
  movb   $0x20,(%rdi)
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L30:
  ret
```

assistant: ```c
void nl2sp(char *p) {
  while (*p != 0) {
    if (*p == '\n' || *p == '\r')
      *p = ' ';
    p++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nl2sp>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L40:
  add    $0x1,%rdi
L10:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
L3:
  cmp    $0xa,%al
  je     L15
  cmp    $0xd,%al
  jne    L40
L15:
  movb   $0x20,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void nl2sp(char *p) {
  while (*p != 0) {
    if (*p == '\n' || *p == '\r')
      *p = ' ';
    p++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_array_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  jmp    L3
L11:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int string_array_len(const char *array[]) {
  int i = 0;
  if (array) {
    while (array[i])
      ++i;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_array_len>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L15
  cmpq   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
L29:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L29
L15:
  mov    %edx,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int string_array_len(const char *array[]) {
  int i = 0;
  if (array) {
    while (array[i])
      ++i;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_array_len>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L7
  cmpq   $0x0,(%rdi)
  je     L7
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L16
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_array_len(const char *array[]) {
  int i = 0;
  if (array) {
    while (array[i])
      ++i;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_array_len>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L20
  cmpq   $0x0,(%rdi)
  je     L20
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L3
L20:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int string_array_len(const char *array[]) {
  int i = 0;
  if (array) {
    while (array[i])
      ++i;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L17
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L17
  mov    $0x1,%eax
  jmp    L4
L17:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
bool isin(const char c, const char *set) {
  int i = -1;
  while (set[++i] != '\0')
    if (c == set[i])
      return true;
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isin>:
  endbr64
L9:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L10
  add    $0x1,%rsi
  cmp    %dil,%al
  jne    L9
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool isin(const char c, const char *set) {
  int i = -1;
  while (set[++i] != '\0')
    if (c == set[i])
      return true;
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isin>:
  endbr64
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L27:
  add    $0x1,%rsi
  cmp    %dil,%al
  je     L25
L1:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L27
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool isin(const char c, const char *set) {
  int i = -1;
  while (set[++i] != '\0')
    if (c == set[i])
      return true;
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isin>:
  endbr64
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x1,%rsi
  cmp    %dil,%al
  je     L28
L25:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool isin(const char c, const char *set) {
  int i = -1;
  while (set[++i] != '\0')
    if (c == set[i])
      return true;
  return false;
}
```