ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bin_lc_parse_header_record>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  je     L30
  mov    %rax,%rdx
  sub    %rbp,%rdx
  mov    %edx,0x0(%r13)
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r14)
  cmpb   $0x20,0x1(%rax)
  jne    L36
  lea    0x2(%rax),%rdx
  nopl   0x0(%rax)
L80:
  mov    %rdx,(%r14)
  add    $0x1,%rdx
  cmpb   $0x20,-0x1(%rdx)
  je     L80
  cmpb   $0x20,-0x1(%rax)
  jne    L107
  nopl   0x0(%rax,%rax,1)
L91:
  sub    $0x1,%rax
L36:
  cmpb   $0x20,-0x1(%rax)
  je     L91
L107:
  movb   $0x0,(%rax)
  mov    (%r14),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,(%r12)
  mov    (%r14),%rdx
  cmpb   $0x2f,(%rdx)
  je     L15
  test   %rax,%rax
  jne    L128
  lea    -0x1(%rbp,%rbx,1),%rax
  cmpb   $0x20,-0x1(%rax)
  jne    L41
  nopw   0x0(%rax,%rax,1)
L45:
  sub    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L45
L41:
  movb   $0x0,(%rax)
  mov    %rax,(%r12)
L89:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L143:
  sub    $0x1,%rax
L128:
  cmpb   $0x20,-0x1(%rax)
  je     L143
  movb   $0x0,(%rax)
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movzbl 0x1(%rax),%edx
  cmp    $0x20,%dl
  jne    L136
  add    $0x2,%rax
  xchg   %ax,%ax
L1:
  mov    %rax,(%r12)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L1
L136:
  test   %dl,%dl
  je     L89
  lea    -0x1(%rbp,%rbx,1),%rax
  cmpb   $0x20,-0x1(%rax)
  jne    L140
  nop
L87:
  sub    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L87
L140:
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  pop    %rbx
  pop    %rbp
  movq   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bin_lc_parse_header_record(char *hdr_record, int record_len, char **value, char **comment, int *kwsize) {
  char *pos;
  *value = strchr(hdr_record, '=');
  if (*value == NULL) {
    *comment = NULL;
    return;
  }
  *kwsize = *value - hdr_record;
  pos = *value;
  (*value)++;
  while (**value == ' ')
    (*value)++;
  while (pos[-1] == ' ')
    pos--;
  *pos = '\0';
  *comment = strchr(*value, '/');
  if (**value == '/')
    **value = '\0';
  else if (*comment) {
    pos = *comment;
    while (pos[-1] == ' ')
      pos--;
    *pos = '\0';
    (*comment)++;
    while (**comment == ' ')
      (*comment)++;
    if (**comment) {
      pos = hdr_record + record_len - 1;
      while (pos[-1] == ' ')
        pos--;
      *pos = '\0';
    }
  } else {
    pos = hdr_record + record_len - 1;
    while (pos[-1] == ' ')
      pos--;
    *pos = '\0';
    *comment = pos;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bin_lc_parse_header_record>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  je     L135
  mov    %rax,%rdx
  sub    %rbp,%rdx
  mov    %edx,0x0(%r13)
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r14)
  cmpb   $0x20,0x1(%rax)
  jne    L133
  lea    0x2(%rax),%rdx
  nopl   0x0(%rax)
L142:
  mov    %rdx,(%r14)
  add    $0x1,%rdx
  cmpb   $0x20,-0x1(%rdx)
  je     L142
  cmpb   $0x20,-0x1(%rax)
  jne    L84
  nopl   0x0(%rax,%rax,1)
L52:
  sub    $0x1,%rax
L133:
  cmpb   $0x20,-0x1(%rax)
  je     L52
L84:
  movb   $0x0,(%rax)
  mov    (%r14),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,(%r12)
  mov    (%r14),%rdx
  cmpb   $0x2f,(%rdx)
  je     L58
  test   %rax,%rax
  jne    L65
  lea    -0x1(%rbp,%rbx,1),%rax
  cmpb   $0x20,-0x1(%rax)
  jne    L136
  nopw   0x0(%rax,%rax,1)
L39:
  sub    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L39
L136:
  movb   $0x0,(%rax)
  mov    %rax,(%r12)
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L94:
  sub    $0x1,%rax
L65:
  cmpb   $0x20,-0x1(%rax)
  je     L94
  movb   $0x0,(%rax)
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movzbl 0x1(%rax),%edx
  cmp    $0x20,%dl
  jne    L82
  add    $0x2,%rax
  xchg   %ax,%ax
L24:
  mov    %rax,(%r12)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L24
L82:
  test   %dl,%dl
  je     L70
  lea    -0x1(%rbp,%rbx,1),%rax
  cmpb   $0x20,-0x1(%rax)
  jne    L53
  nop
L49:
  sub    $0x1,%rax
  cmpb   $0x20,-0x1(%rax)
  je     L49
L53:
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L58:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L135:
  pop    %rbx
  pop    %rbp
  movq   $0x0,(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bin_lc_parse_header_record(char *hdr_record, int record_len, char **value, char **comment, int *kwsize) {
  char *pos;
  *value = strchr(hdr_record, '=');
  if (*value == NULL) {
    *comment = NULL;
    return;
  }
  *kwsize = *value - hdr_record;
  pos = *value;
  (*value)++;
  while (**value == ' ')
    (*value)++;
  while (pos[-1] == ' ')
    pos--;
  *pos = '\0';
  *comment = strchr(*value, '/');
  if (**value == '/')
    **value = '\0';
  else if (*comment) {
    pos = *comment;
    while (pos[-1] == ' ')
      pos--;
    *pos = '\0';
    (*comment)++;
    while (**comment == ' ')
      (*comment)++;
    if (**comment) {
      pos = hdr_record + record_len - 1;
      while (pos[-1] == ' ')
        pos--;
      *pos = '\0';
    }
  } else {
    pos = hdr_record + record_len - 1;
    while (pos[-1] == ' ')
      pos--;
    *pos = '\0';
    *comment = pos;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart0_getc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L8:
  mov    $0xe2900010,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    $0xe2900024,%eax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t uart0_getc() {
  while (!((*((volatile uint32_t *)0xE2900010)) & 0x01))
    ;
  return (*((volatile uint32_t *)0xE2900024));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uart0_getc>:
  endbr64
  mov    $0xe2900010,%edx
L0:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L0
  movabs 0xe2900024,%eax
  ret
```

assistant: ```c
uint32_t uart0_getc() {
  while (!((*((volatile uint32_t *)0xE2900010)) & 0x01))
    ;
  return (*((volatile uint32_t *)0xE2900024));
}
```
user: What is the c source code of the assembly code below?

```asm
<uart0_getc>:
  endbr64
  mov    $0xe2900010,%edx
  nopl   0x0(%rax)
L3:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L3
  movabs 0xe2900024,%eax
  ret
```

assistant: ```c
uint32_t uart0_getc() {
  while (!((*((volatile uint32_t *)0xE2900010)) & 0x01))
    ;
  return (*((volatile uint32_t *)0xE2900024));
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart0_getc>:
  endbr64
  mov    $0xe2900010,%edx
  nopl   0x0(%rax)
L3:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L3
  movabs 0xe2900024,%eax
  ret
```

assistant: ```c
uint32_t uart0_getc() {
  while (!((*((volatile uint32_t *)0xE2900010)) & 0x01))
    ;
  return (*((volatile uint32_t *)0xE2900024));
}
```
user: What is the c source code of the assembly code below:

```asm
<wr_strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  jmp    L49
L53:
  movzbl (%r12),%edx
  movzbl (%rbx),%eax
  cmp    %al,%dl
  je     L40
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%r13
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%r13
  jne    L42
L40:
  add    $0x1,%r12
  add    $0x1,%rbx
L49:
  movzbl (%r12),%eax
  test   %al,%al
  je     L45
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L53
  jmp    L45
L42:
  nop
L45:
  movzbl (%r12),%eax
  movsbl %al,%eax
  movzbl (%rbx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int wr_strcasecmp(register const char *lStr, register const char *rStr) {
  while (*lStr && *rStr) {
    if (*lStr != *rStr && tolower(*lStr) != tolower(*rStr))
      break;
    ++lStr;
    ++rStr;
  }
  return *lStr - *rStr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wr_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L4
  jmp    L50
L11:
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L50
L4:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L50
  cmp    %dil,%al
  je     L11
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%r12
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %rax,%r12
  je     L11
L50:
  movsbl 0x0(%rbp),%eax
  movsbl (%rbx),%edx
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wr_strcasecmp(register const char *lStr, register const char *rStr) {
  while (*lStr && *rStr) {
    if (*lStr != *rStr && tolower(*lStr) != tolower(*rStr))
      break;
    ++lStr;
    ++rStr;
  }
  return *lStr - *rStr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wr_strcasecmp>:
  endbr64
  push   %r12
  movsbl (%rsi),%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L13
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    %dil,%dl
  je     L2
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jne    L25
L2:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  lea    0x1(%rbx),%rax
  test   %dil,%dil
  je     L31
  mov    %rax,%rbx
L13:
  movsbl (%rbx),%edx
  test   %dl,%dl
  jne    L8
  movzbl 0x0(%rbp),%edi
L29:
  movsbl %dil,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L31:
  movsbl 0x1(%rbx),%edx
  movsbl %dil,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  sub    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl 0x0(%rbp),%edi
  movsbl (%rbx),%edx
  pop    %rbx
  pop    %rbp
  movsbl %dil,%eax
  pop    %r12
  sub    %edx,%eax
  ret
```

assistant: ```c
int wr_strcasecmp(register const char *lStr, register const char *rStr) {
  while (*lStr && *rStr) {
    if (*lStr != *rStr && tolower(*lStr) != tolower(*rStr))
      break;
    ++lStr;
    ++rStr;
  }
  return *lStr - *rStr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wr_strcasecmp>:
  endbr64
  push   %r12
  movsbl (%rsi),%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L26
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L32:
  cmp    %dil,%dl
  je     L51
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jne    L28
L51:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  lea    0x1(%rbx),%rax
  test   %dil,%dil
  je     L20
  mov    %rax,%rbx
L26:
  movsbl (%rbx),%edx
  test   %dl,%dl
  jne    L32
L52:
  movsbl %dil,%eax
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  ret
L20:
  movsbl 0x1(%rbx),%edx
  movsbl %dil,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  sub    %edx,%eax
  ret
  nop
L28:
  movzbl 0x0(%rbp),%edi
  movsbl (%rbx),%edx
  pop    %rbx
  pop    %rbp
  movsbl %dil,%eax
  pop    %r12
  sub    %edx,%eax
  ret
```

assistant: ```c
int wr_strcasecmp(register const char *lStr, register const char *rStr) {
  while (*lStr && *rStr) {
    if (*lStr != *rStr && tolower(*lStr) != tolower(*rStr))
      break;
    ++lStr;
    ++rStr;
  }
  return *lStr - *rStr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bit_array_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bit_array_and(int len, uint64_t *dst, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    dst[i] = a[i] & b[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bit_array_and>:
  endbr64
  test   %edi,%edi
  jle    L19
  mov    %edi,%edi
  mov    $0x0,%eax
L18:
  mov    (%rdx,%rax,4),%r8d
  and    (%rcx,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L19:
  ret
```

assistant: ```c
void bit_array_and(int len, uint64_t *dst, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    dst[i] = a[i] & b[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bit_array_and>:
  endbr64
  test   %edi,%edi
  jle    L11
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L3:
  mov    (%rdx,%rax,4),%r8d
  and    (%rcx,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L3
L11:
  ret
```

assistant: ```c
void bit_array_and(int len, uint64_t *dst, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    dst[i] = a[i] & b[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bit_array_and>:
  endbr64
  test   %edi,%edi
  jle    L50
  lea    0x4(%rcx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  seta   %r8b
  cmp    $0x1,%edi
  setne  %al
  test   %al,%r8b
  je     L64
  lea    0x4(%rdx),%r8
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L64
  lea    -0x1(%rdi),%eax
  mov    %edi,%r9d
  cmp    $0x2,%eax
  jbe    L45
  mov    %edi,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L3:
  movdqu (%rdx,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm2
  pand   %xmm2,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L3
  mov    %edi,%r8d
  and    $0xfffffffc,%r8d
  mov    %r8d,%eax
  cmp    %r8d,%edi
  je     L50
  sub    %r8d,%edi
  mov    %edi,%r9d
  cmp    $0x1,%edi
  je     L85
L77:
  mov    %r8d,%edi
  movq   (%rdx,%rdi,4),%xmm0
  movq   (%rcx,%rdi,4),%xmm1
  pand   %xmm1,%xmm0
  movq   %xmm0,(%rsi,%rdi,4)
  mov    %r9d,%edi
  and    $0xfffffffe,%edi
  add    %edi,%eax
  cmp    %edi,%r9d
  je     L50
L85:
  cltq
  mov    (%rdx,%rax,4),%edx
  and    (%rcx,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  ret
  nopl   0x0(%rax)
L64:
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L91:
  mov    (%rdx,%rax,4),%r8d
  and    (%rcx,%rax,4),%r8d
  mov    %r8d,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L91
L50:
  ret
L45:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L77
```

assistant: ```c
void bit_array_and(int len, uint64_t *dst, uint64_t *a, uint64_t *b) {
  for (int i = 0; i < len; i++) {
    dst[i] = a[i] & b[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  sub    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <solve>
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <solve>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <naive_printf@plt>
  jmp    L15
L3:
  nop
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: %c

assistant: ```c
void solve(char *s1, char *s2, int len) {
  if (len == 0)
    return;
  int nlen = strchr(s2, *s1) - s2;
  solve(s1 + 1, s2, nlen);
  solve(s1 + nlen + 1, s2 + nlen + 1, len - nlen - 1);
  naive_printf("%c", (*s1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<solve>:
  endbr64
  test   %edx,%edx
  jne    L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  movsbl (%rdi),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  sub    %rbp,%rax
  mov    %rax,%r13
  mov    %eax,%edx
  lea    0x1(%r12),%rdi
  mov    %rbp,%rsi
  call   <solve>
  movslq %r13d,%rdi
  add    $0x1,%rdi
  sub    %r13d,%ebx
  lea    -0x1(%rbx),%edx
  lea    0x0(%rbp,%rdi,1),%rsi
  add    %r12,%rdi
  call   <solve>
  movsbl (%r12),%esi
  lea    D8(%rip),%rdi
  call   <naive_printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: %c

assistant: ```c
void solve(char *s1, char *s2, int len) {
  if (len == 0)
    return;
  int nlen = strchr(s2, *s1) - s2;
  solve(s1 + 1, s2, nlen);
  solve(s1 + nlen + 1, s2 + nlen + 1, len - nlen - 1);
  naive_printf("%c", (*s1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<solve>:
  endbr64
  test   %edx,%edx
  jne    L5
  ret
  nopl   0x0(%rax)
L5:
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  lea    0x1(%r12),%rdi
  mov    %rbp,%rsi
  sub    %rbp,%rax
  mov    %rax,%r13
  mov    %eax,%edx
  call   <solve>
  movslq %r13d,%rdi
  sub    %r13d,%ebx
  add    $0x1,%rdi
  lea    -0x1(%rbx),%edx
  lea    0x0(%rbp,%rdi,1),%rsi
  add    %r12,%rdi
  call   <solve>
  movsbl (%r12),%esi
  add    $0x8,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <naive_printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %c

assistant: ```c
void solve(char *s1, char *s2, int len) {
  if (len == 0)
    return;
  int nlen = strchr(s2, *s1) - s2;
  solve(s1 + 1, s2, nlen);
  solve(s1 + nlen + 1, s2 + nlen + 1, len - nlen - 1);
  naive_printf("%c", (*s1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<baud_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: Unknown baud


assistant: ```c
int baud_encode(int bps) {
  switch (bps) {}
  printf("Unknown baud\n");
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<baud_encode>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: Unknown baud


assistant: ```c
int baud_encode(int bps) {
  switch (bps) {}
  printf("Unknown baud\n");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<baud_encode>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: Unknown baud


assistant: ```c
int baud_encode(int bps) {
  switch (bps) {}
  printf("Unknown baud\n");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<baud_encode>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: Unknown baud


assistant: ```c
int baud_encode(int bps) {
  switch (bps) {}
  printf("Unknown baud\n");
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<classify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x38(%rbp)
  cmpb   $0x0,-0x38(%rbp)
  je     L16
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L54:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <ClassFromChWS@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L54
  mov    -0x14(%rbp),%eax
  jmp    L37
L16:
  movl   $0x0,-0x14(%rbp)
  jmp    L43
L19:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <ClassFromChN@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L43:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  mov    -0x14(%rbp),%eax
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int classify(const char *pszText, int *pcls, int cch, char fWS) {
  int ich;
  if (fWS) {
    for (ich = 0; ich < cch; ich++) {
      pcls[ich] = ClassFromChWS(pszText[ich]);
    }
    return ich;
  } else {
    for (ich = 0; ich < cch; ich++) {
      pcls[ich] = ClassFromChN(pszText[ich]);
    }
    return ich;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<classify>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  test   %cl,%cl
  jne    L67
  mov    %edx,%r14d
  mov    $0x0,%ebx
  test   %edx,%edx
  jle    L39
L53:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <ClassFromChN@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L53
  jmp    L37
L39:
  mov    $0x0,%r13d
  jmp    L37
L67:
  test   %edx,%edx
  jle    L17
  mov    %edx,%r14d
  mov    $0x0,%ebx
L72:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <ClassFromChWS@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L72
L37:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0x0,%r13d
  jmp    L37
```

assistant: ```c
int classify(const char *pszText, int *pcls, int cch, char fWS) {
  int ich;
  if (fWS) {
    for (ich = 0; ich < cch; ich++) {
      pcls[ich] = ClassFromChWS(pszText[ich]);
    }
    return ich;
  } else {
    for (ich = 0; ich < cch; ich++) {
      pcls[ich] = ClassFromChN(pszText[ich]);
    }
    return ich;
  }
}
```