user: 请从给定的汇编指令推导出C源代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  movslq %esi,%r15
  push   %r14
  push   %r13
  mov    %r15,%r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x48(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(%r15),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L87
L57:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L57
L87:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L134
L45:
  lea    0xf(,%r15,8),%rax
  mov    %rsp,%rcx
  mov    %rsp,%rbx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L17
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L96
L17:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L18
L107:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L150
  xor    %r14d,%r14d
  nopl   (%rax)
L51:
  xor    %eax,%eax
  call   <rand_double@plt>
  movsd  D9(%rip),%xmm1
  comisd %xmm0,%xmm1
  seta   (%rbx,%r14,1)
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D14(%rip),%xmm0
  subsd  D23(%rip),%xmm0
  movsd  %xmm0,(%r12,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%r15
  jne    L51
L150:
  xor    %eax,%eax
  call   <tic@plt>
  mov    -0x48(%rbp),%eax
  movsd  %xmm0,-0x50(%rbp)
  test   %eax,%eax
  jle    L143
  xor    %r15d,%r15d
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L41:
  add    $0x1,%r15d
  cmp    %r15d,-0x48(%rbp)
  je     L143
L39:
  mov    $0x1,%r8d
  mov    %rbx,%rcx
  mov    %r12,%rsi
  mov    %r13d,%edi
  mov    $0x1,%edx
  call   <stdlib_strided_dmskmax@plt>
  ucomisd %xmm0,%xmm0
  jnp    L41
  lea    D25(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x50(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L0:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L131
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L134:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L143:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x50(%rbp),%xmm0
  jmp    L0
L18:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L107
L131:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: f64
name: retrieve_data
arguments: data_tag: D14
type_guessed: f64
name: retrieve_data
arguments: data_tag: D23
type_guessed: f64
name: retrieve_data
arguments: data_tag: D25
type_guessed: string

tool: D9: 0.2

tool: D14: 20000

tool: D23: 10000

tool: D25: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  unsigned char mask[len];
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    if (rand_double() < 0.2) {
      mask[i] = 1;
    } else {
      mask[i] = 0;
    }
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dmskmax(len, x, 1, mask, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```