ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x4a0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x498(%rbp)
  lea    -0x4a9(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x4a8(%rbp)
  jmp    L74
L7:
  movl   $0x0,-0x4a4(%rbp)
  jmp    L87
L8:
  lea    -0x490(%rbp),%rcx
  mov    -0x4a4(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x4a8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x4a8(%rbp),%eax
  cmp    -0x4a4(%rbp),%eax
  jge    L63
  mov    -0x4a4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x4a8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  movsd  -0x490(%rbp,%rax,8),%xmm0
  movsd  -0x4a0(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x4a0(%rbp)
  movsd  -0x498(%rbp),%xmm1
  movsd  D35(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x498(%rbp)
L63:
  addl   $0x1,-0x4a4(%rbp)
L87:
  cmpl   $0xb,-0x4a4(%rbp)
  jle    L8
  addl   $0x1,-0x4a8(%rbp)
L74:
  cmpl   $0xb,-0x4a8(%rbp)
  jle    L7
  movzbl -0x4a9(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x4d,%eax
  je     L47
  cmp    $0x53,%eax
  jne    L9
  mov    -0x4a0(%rbp),%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L47:
  movsd  -0x4a0(%rbp),%xmm0
  divsd  -0x498(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D35
type_guessed: f32[2]
name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D0:  %c

tool: D6:  %lf

tool: {"D35": [0.0,1.875]}

tool: D7: %0.1lf


assistant: ```c
int main() {
  double M[12][12], soma = 0, cont_n = 0;
  int i, j, L;
  char T;
  scanf(" %c", &T);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      scanf(" %lf", &M[i][j]);
      if (i < j) {
        soma += M[i][j];
        cont_n++;
      }
    }
  }
  switch (T) {
  case 'S':
    printf("%0.1lf\n", soma);
    break;
  case 'M':
    printf("%0.1lf\n", soma / cont_n);
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  lea    0x2f(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    D21(%rip),%r13
  jmp    L77
L56:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0xc,%ebx
  je     L98
L71:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    %r12d,%ebx
  jle    L56
  lea    0x0(%rbp,%r14,1),%rax
  movsd  0x8(%rsp),%xmm1
  addsd  (%rax,%r15,1),%xmm1
  movsd  %xmm1,0x8(%rsp)
  movsd  0x10(%rsp),%xmm2
  addsd  D8(%rip),%xmm2
  movsd  %xmm2,0x10(%rsp)
  jmp    L56
L98:
  add    $0x1,%r12
  sub    $0x60,%r14
  add    $0x60,%r15
  cmp    $0xc,%r12
  je     L0
L77:
  mov    0x18(%rsp),%rbp
  sub    %r14,%rbp
  mov    $0x0,%ebx
  jmp    L71
L0:
  movzbl 0x2f(%rsp),%eax
  cmp    $0x4d,%al
  je     L13
  cmp    $0x53,%al
  jne    L16
  movsd  0x8(%rsp),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x4c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D8
datatype: f32[2]
name: read_data
arguments: data_tag: D0
datatype: string

tool: D28:  %c

tool: D21:  %lf

tool: {"D8": [0.0,1.875]}

tool: D0: %0.1lf


assistant: ```c
int main() {
  double M[12][12], soma = 0, cont_n = 0;
  int i, j, L;
  char T;
  scanf(" %c", &T);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      scanf(" %lf", &M[i][j]);
      if (i < j) {
        soma += M[i][j];
        cont_n++;
      }
    }
  }
  switch (T) {
  case 'S':
    printf("%0.1lf\n", soma);
    break;
  case 'M':
    printf("%0.1lf\n", soma / cont_n);
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D49(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x4c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  lea    0x2f(%rsp),%rsi
  call   <scanf@plt>
  lea    0x30(%rsp),%rax
  pxor   %xmm4,%xmm4
  mov    %rax,0x18(%rsp)
  lea    0x38(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  nopl   0x0(%rax,%rax,1)
L57:
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  xor    %r14d,%r14d
  sub    %r12,%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%r15
  sub    %r12,%r15
  jmp    L66
  nop
L68:
  xor    %eax,%eax
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,%r14d
  jle    L29
  lea    (%r15,%r12,1),%rax
  movsd  (%rsp),%xmm1
  movsd  D33(%rip),%xmm2
  addsd  (%rax,%r13,1),%xmm1
  addsd  0x8(%rsp),%xmm2
  movsd  %xmm1,(%rsp)
  movsd  %xmm2,0x8(%rsp)
L29:
  add    $0x8,%r15
L66:
  add    $0x1,%r14d
  cmp    $0xc,%r14d
  jne    L68
  add    $0x1,%rbx
  sub    $0x60,%r12
  add    $0x60,%r13
  cmp    $0xc,%rbx
  jne    L57
  movzbl 0x2f(%rsp),%eax
  cmp    $0x4d,%al
  je     L8
  cmp    $0x53,%al
  jne    L58
  movsd  (%rsp),%xmm0
  lea    D28(%rip),%rdi
  call   <printf@plt>
L58:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x4c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  lea    D28(%rip),%rdi
  movsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  jmp    L58
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D49
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D33
datatype: f32[2]
name: disassemble_data
arguments: label: D28
datatype: string

tool: D49:  %c

tool: D17:  %lf

tool: {"D33": [0.0,1.875]}

tool: D28: %0.1lf


assistant: ```c
int main() {
  double M[12][12], soma = 0, cont_n = 0;
  int i, j, L;
  char T;
  scanf(" %c", &T);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      scanf(" %lf", &M[i][j]);
      if (i < j) {
        soma += M[i][j];
        cont_n++;
      }
    }
  }
  switch (T) {
  case 'S':
    printf("%0.1lf\n", soma);
    break;
  case 'M':
    printf("%0.1lf\n", soma / cont_n);
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D30(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x4c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  lea    0x2f(%rsp),%rsi
  call   <scanf@plt>
  lea    0x30(%rsp),%rax
  pxor   %xmm4,%xmm4
  mov    %rax,0x18(%rsp)
  lea    0x38(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x1,%r14d
  sub    %r12,%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%r15
  sub    %r12,%r15
L17:
  xor    %eax,%eax
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    %ebx,%r14d
  jle    L10
  lea    (%r15,%r12,1),%rax
  movsd  (%rsp),%xmm1
  movsd  D33(%rip),%xmm2
  addsd  (%rax,%r13,1),%xmm1
  addsd  0x8(%rsp),%xmm2
  movsd  %xmm1,(%rsp)
  movsd  %xmm2,0x8(%rsp)
L10:
  add    $0x1,%r14d
  add    $0x8,%r15
  cmp    $0xc,%r14d
  jne    L17
  add    $0x1,%rbx
  sub    $0x60,%r12
  add    $0x60,%r13
  cmp    $0xc,%rbx
  jne    L29
  movzbl 0x2f(%rsp),%eax
  cmp    $0x4d,%al
  je     L32
  cmp    $0x53,%al
  jne    L63
  movsd  (%rsp),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
L63:
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x4c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  lea    D6(%rip),%rdi
  movsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  jmp    L63
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D47
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: f32[2]
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D30:  %c

tool: D47:  %lf

tool: {"D33": [0.0,1.875]}

tool: D6: %0.1lf


assistant: ```c
int main() {
  double M[12][12], soma = 0, cont_n = 0;
  int i, j, L;
  char T;
  scanf(" %c", &T);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      scanf(" %lf", &M[i][j]);
      if (i < j) {
        soma += M[i][j];
        cont_n++;
      }
    }
  }
  switch (T) {
  case 'S':
    printf("%0.1lf\n", soma);
    break;
  case 'M':
    printf("%0.1lf\n", soma / cont_n);
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2f,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <factor@plt>
  mov    $0x0,%eax
  call   <popDiv@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void divide() {
  match('/');
  factor();
  popDiv();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<divide>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <factor@plt>
  mov    $0x0,%eax
  call   <popDiv@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void divide() {
  match('/');
  factor();
  popDiv();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<divide>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <factor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <popDiv@plt>
```

assistant: ```c
void divide() {
  match('/');
  factor();
  popDiv();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <factor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <popDiv@plt>
```

assistant: ```c
void divide() {
  match('/');
  factor();
  popDiv();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ra_func_orig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  %xmm5,-0x60(%rbp)
  movsd  %xmm6,-0x68(%rbp)
  movsd  %xmm7,-0x70(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x70(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  divsd  -0x48(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  divsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x60(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x58(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: f64

tool: D8: 2

assistant: ```c
double ra_func_orig(double Zt, double d0m, double z0m, double Psih, double U, double K, double Psim, double Zu) {
  double ra;
  double numer1, numer2, denom;
  double kB_1 = 2.0;
  double z0h;
  z0h = z0m / exp(kB_1);
  numer1 = log((Zu - d0m) / z0m) - Psim;
  numer2 = log((Zt - d0m) / z0h) - Psih;
  denom = K * K * U;
  ra = (numer1 * numer2) / denom;
  return (ra);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ra_func_orig>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%rbp
  movsd  %xmm2,0x8(%rsp)
  movq   %xmm3,%r14
  movq   %xmm4,%r15
  movsd  %xmm5,0x18(%rsp)
  movq   %xmm6,%r12
  movsd  %xmm1,0x10(%rsp)
  subsd  %xmm1,%xmm7
  movapd %xmm7,%xmm0
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  subsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
  call   <log@plt>
  movq   %rbx,%xmm1
  movq   %r12,%xmm6
  subsd  %xmm6,%xmm1
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  0x18(%rsp),%xmm4
  mulsd  %xmm4,%xmm4
  movq   %r15,%xmm5
  mulsd  %xmm5,%xmm4
  divsd  %xmm4,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[8]

tool: {"D9": [0xae,0xdd,0xd4,0xb8,0x64,0x8e,0x1d,0x40]}

assistant: ```c
double ra_func_orig(double Zt, double d0m, double z0m, double Psih, double U, double K, double Psim, double Zu) {
  double ra;
  double numer1, numer2, denom;
  double kB_1 = 2.0;
  double z0h;
  z0h = z0m / exp(kB_1);
  numer1 = log((Zu - d0m) / z0m) - Psim;
  numer2 = log((Zt - d0m) / z0h) - Psih;
  denom = K * K * U;
  ra = (numer1 * numer2) / denom;
  return (ra);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ra_func_orig>:
  endbr64
  subsd  %xmm1,%xmm7
  sub    $0x48,%rsp
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm3,(%rsp)
  movapd %xmm7,%xmm0
  movsd  %xmm5,0x30(%rsp)
  divsd  %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x20(%rsp)
  call   <log@plt>
  movsd  0x28(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm8
  movsd  %xmm0,0x18(%rsp)
  movsd  0x20(%rsp),%xmm2
  divsd  D6(%rip),%xmm2
  subsd  %xmm1,%xmm8
  movapd %xmm8,%xmm0
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  movapd %xmm0,%xmm1
  subsd  (%rsp),%xmm1
  mulsd  %xmm5,%xmm5
  movapd %xmm3,%xmm0
  subsd  0x10(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm5
  add    $0x48,%rsp
  mulsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[8]

tool: {"D6": [0xae,0xdd,0xd4,0xb8,0x64,0x8e,0x1d,0x40]}

assistant: ```c
double ra_func_orig(double Zt, double d0m, double z0m, double Psih, double U, double K, double Psim, double Zu) {
  double ra;
  double numer1, numer2, denom;
  double kB_1 = 2.0;
  double z0h;
  z0h = z0m / exp(kB_1);
  numer1 = log((Zu - d0m) / z0m) - Psim;
  numer2 = log((Zt - d0m) / z0h) - Psih;
  denom = K * K * U;
  ra = (numer1 * numer2) / denom;
  return (ra);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ra_func_orig>:
  endbr64
  subsd  %xmm1,%xmm7
  sub    $0x48,%rsp
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm3,(%rsp)
  movapd %xmm7,%xmm0
  movsd  %xmm5,0x30(%rsp)
  divsd  %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x20(%rsp)
  call   <log@plt>
  movsd  0x28(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm8
  movsd  %xmm0,0x18(%rsp)
  movsd  0x20(%rsp),%xmm2
  divsd  D9(%rip),%xmm2
  subsd  %xmm1,%xmm8
  movapd %xmm8,%xmm0
  divsd  %xmm2,%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  movapd %xmm0,%xmm1
  subsd  (%rsp),%xmm1
  mulsd  %xmm5,%xmm5
  movapd %xmm3,%xmm0
  subsd  0x10(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm5
  add    $0x48,%rsp
  mulsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: byte[8]

tool: {"D9": [0xae,0xdd,0xd4,0xb8,0x64,0x8e,0x1d,0x40]}

assistant: ```c
double ra_func_orig(double Zt, double d0m, double z0m, double Psih, double U, double K, double Psim, double Zu) {
  double ra;
  double numer1, numer2, denom;
  double kB_1 = 2.0;
  double z0h;
  z0h = z0m / exp(kB_1);
  numer1 = log((Zu - d0m) / z0m) - Psim;
  numer2 = log((Zt - d0m) / z0h) - Psih;
  denom = K * K * U;
  ra = (numer1 * numer2) / denom;
  return (ra);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_quaddobl_start_Laurent_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x300,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int write_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(768, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_quaddobl_start_Laurent_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x300,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int write_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(768, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_quaddobl_start_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x300,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(768, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_quaddobl_start_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x300,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int write_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(768, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_le_int32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void write_le_int32(FILE *dfile, int num) {
  fputc((num)&0xFF, dfile);
  fputc((num >> 8) & 0xFF, dfile);
  fputc((num >> 16) & 0xFF, dfile);
  fputc((num >> 24) & 0xFF, dfile);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_le_int32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movzbl %sil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  sar    $0x10,%edi
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  shr    $0x18,%ebx
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_le_int32(FILE *dfile, int num) {
  fputc((num)&0xFF, dfile);
  fputc((num >> 8) & 0xFF, dfile);
  fputc((num >> 16) & 0xFF, dfile);
  fputc((num >> 24) & 0xFF, dfile);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_le_int32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  shr    $0x18,%ebx
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void write_le_int32(FILE *dfile, int num) {
  fputc((num)&0xFF, dfile);
  fputc((num >> 8) & 0xFF, dfile);
  fputc((num >> 16) & 0xFF, dfile);
  fputc((num >> 24) & 0xFF, dfile);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_le_int32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movzbl %sil,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <fputc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  shr    $0x18,%ebx
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void write_le_int32(FILE *dfile, int num) {
  fputc((num)&0xFF, dfile);
  fputc((num >> 8) & 0xFF, dfile);
  fputc((num >> 16) & 0xFF, dfile);
  fputc((num >> 24) & 0xFF, dfile);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMinute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%edi
  call   <getLocalTime@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getMinute() {
  struct tm *mytime;
  int min = 0;
  mytime = getLocalTime((time_t *)NULL);
  min = mytime->tm_min;
  free(mytime);
  return min;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMinute>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <getLocalTime@plt>
  mov    %rax,%rdi
  mov    (%rax),%ebx
  call   <free@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getMinute() {
  struct tm *mytime;
  int min = 0;
  mytime = getLocalTime((time_t *)NULL);
  min = mytime->tm_min;
  free(mytime);
  return min;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getMinute>:
  endbr64
  push   %r12
  xor    %edi,%edi
  call   <getLocalTime@plt>
  mov    (%rax),%r12d
  mov    %rax,%rdi
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int getMinute() {
  struct tm *mytime;
  int min = 0;
  mytime = getLocalTime((time_t *)NULL);
  min = mytime->tm_min;
  free(mytime);
  return min;
}
```