ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<container_add>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    (%rsi),%eax
  mov    %rsi,%rbx
  mov    (%rdi),%rdi
  lea    0x80(%rax),%esi
  lea    (%rsi,%rsi,1),%eax
  shl    $0x4,%esi
  mov    %eax,(%rdx)
  call   <realloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L27
  mov    (%rbx),%edx
  lea    0x1(%rbp),%edi
  lea    (%rax,%rdx,8),%r14
  call   <malloc@plt>
  mov    (%rbx),%edx
  mov    %rax,(%r14)
  mov    (%r12),%rax
  mov    (%rax,%rdx,8),%rdi
  test   %rdi,%rdi
  je     L27
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%edx
  mov    (%r12),%rax
  mov    (%rax,%rdx,8),%rax
  movb   $0x0,(%rax,%rbp,1)
  xor    %eax,%eax
  addl   $0x1,(%rbx)
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L27:
  mov    $0xffffffff,%eax
  jmp    L28
```

assistant: ```c
int container_add(char ***map, unsigned *mac, unsigned *max, const char *s, unsigned len) {
  if (*mac >= *mac) {
    *max = 256 + *mac * 2;
    *map = realloc(*map, *max * sizeof(char *));
    if (!*map) {
      return -1;
    }
  }
  (*map)[*mac] = malloc(len + 1);
  if (!(*map)[*mac]) {
    return -1;
  }
  memcpy((*map)[*mac], s, len);
  (*map)[*mac][len] = 0;
  *mac += 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mus_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  call   <creat@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mus_create(char *arg) {
  int fd;
  fd = creat(arg, 0666);
  return (fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mus_create>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1b6,%esi
  call   <creat@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mus_create(char *arg) {
  int fd;
  fd = creat(arg, 0666);
  return (fd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mus_create>:
  endbr64
  mov    $0x1b6,%esi
  jmp    1050 <creat@plt>
```

assistant: ```c
int mus_create(char *arg) {
  int fd;
  fd = creat(arg, 0666);
  return (fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mus_create>:
  endbr64
  mov    $0x1b6,%esi
  jmp    1050 <creat@plt>
```

assistant: ```c
int mus_create(char *arg) {
  int fd;
  fd = creat(arg, 0666);
  return (fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_typename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_typename(void) {
  char s;
  int y;
  int x = _Generic((s), _Bool : 1, char : 2, int : 3, default : 4);
  int z = _Generic((y), _Bool : 1, char : 2, int : 3, default : 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_typename>:
  endbr64
  ret
```

assistant: ```c
void test_typename(void) {
  char s;
  int y;
  int x = _Generic((s), _Bool : 1, char : 2, int : 3, default : 4);
  int z = _Generic((y), _Bool : 1, char : 2, int : 3, default : 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<test_typename>:
  endbr64
  ret
```

assistant: ```c
void test_typename(void) {
  char s;
  int y;
  int x = _Generic((s), _Bool : 1, char : 2, int : 3, default : 4);
  int z = _Generic((y), _Bool : 1, char : 2, int : 3, default : 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Cannot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <Pause@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string

tool: D5: TERM

tool: D3: 
This %s terminal %s



assistant: ```c
void Cannot(const char *what) {
  printw("\nThis %s terminal %s\n\n", getenv("TERM"), what);
  Pause();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Cannot>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D19(%rip),%rdi
  call   <printw@plt>
  mov    $0x0,%eax
  call   <Pause@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D19
type_guessed: string

tool: D1: TERM

tool: D19: 
This %s terminal %s



assistant: ```c
void Cannot(const char *what) {
  printw("\nThis %s terminal %s\n\n", getenv("TERM"), what);
  Pause();
}
```
user: What is the c source code of the assembly code below:

```asm
<Cannot>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  call   <getenv@plt>
  mov    %r12,%rdx
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printw@plt>
  xor    %eax,%eax
  pop    %r12
  jmp    1080 <Pause@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D17
type: string

tool: D18: TERM

tool: D17: 
This %s terminal %s



assistant: ```c
void Cannot(const char *what) {
  printw("\nThis %s terminal %s\n\n", getenv("TERM"), what);
  Pause();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Cannot>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  call   <getenv@plt>
  mov    %r12,%rdx
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printw@plt>
  xor    %eax,%eax
  pop    %r12
  jmp    1080 <Pause@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D5
datatype: string

tool: D18: TERM

tool: D5: 
This %s terminal %s



assistant: ```c
void Cannot(const char *what) {
  printw("\nThis %s terminal %s\n\n", getenv("TERM"), what);
  Pause();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inet6_rth_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L0
  mov    $0xffffffff,%eax
  jmp    L13
L0:
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rax)
  mov    %rdx,%rax
  shl    $0x7,%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x10,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int inet6_rth_add(void *bp, const struct in6_addr *addr) {
  if (((uint8_t *)bp)[2] != IPV6_RTHDR_TYPE_0)
    return -1;
  memcpy(((uint8_t *)bp) + 8 + 16 * ((uint8_t *)bp)[3]++, addr, 16);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inet6_rth_add>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,0x10(%rdi)
  jne    L2
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x18(%rdi)
  shl    $0x7,%rax
  lea    0x40(%rdi,%rax,1),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inet6_rth_add(void *bp, const struct in6_addr *addr) {
  if (((uint8_t *)bp)[2] != IPV6_RTHDR_TYPE_0)
    return -1;
  memcpy(((uint8_t *)bp) + 8 + 16 * ((uint8_t *)bp)[3]++, addr, 16);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inet6_rth_add>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,0x10(%rdi)
  jne    L0
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rax
  lea    0x1(%rax),%rdx
  shl    $0x7,%rax
  mov    %rdx,0x18(%rdi)
  lea    0x40(%rdi,%rax,1),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inet6_rth_add(void *bp, const struct in6_addr *addr) {
  if (((uint8_t *)bp)[2] != IPV6_RTHDR_TYPE_0)
    return -1;
  memcpy(((uint8_t *)bp) + 8 + 16 * ((uint8_t *)bp)[3]++, addr, 16);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inet6_rth_add>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,0x10(%rdi)
  jne    L7
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rax
  lea    0x1(%rax),%rdx
  shl    $0x7,%rax
  mov    %rdx,0x18(%rdi)
  lea    0x40(%rdi,%rax,1),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inet6_rth_add(void *bp, const struct in6_addr *addr) {
  if (((uint8_t *)bp)[2] != IPV6_RTHDR_TYPE_0)
    return -1;
  memcpy(((uint8_t *)bp) + 8 + 16 * ((uint8_t *)bp)[3]++, addr, 16);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<irc_pong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%r8
  lea    D2(%rip),%rdx
  mov    %rdx,%rcx
  lea    D18(%rip),%rdx
  mov    $0x1fd,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <net_send@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D2: PONG

tool: D18: %s %s

assistant: ```c
void irc_pong(char *server) {
  char msg[(512 - 3)];
  snprintf(msg, (512 - 3), "%s %s", "PONG", server);
  net_send(msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<irc_pong>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D2(%rip),%rcx
  lea    D0(%rip),%rdx
  mov    $0x1fd,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <net_send@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x210,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D2: PONG

tool: D0: %s %s

assistant: ```c
void irc_pong(char *server) {
  char msg[(512 - 3)];
  snprintf(msg, (512 - 3), "%s %s", "PONG", server);
  net_send(msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<irc_pong>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    D15(%rip),%rcx
  mov    $0x1fd,%esi
  lea    D11(%rip),%rdx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <net_send@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x210,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D11
type_infered: string

tool: D15: PONG

tool: D11: %s %s

assistant: ```c
void irc_pong(char *server) {
  char msg[(512 - 3)];
  snprintf(msg, (512 - 3), "%s %s", "PONG", server);
  net_send(msg);
}
```
user: What is the c source code of the assembly code below?

```asm
<irc_pong>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    D17(%rip),%rcx
  mov    $0x1fd,%esi
  lea    D9(%rip),%rdx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <net_send@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x210,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D9
data_type: string

tool: D17: PONG

tool: D9: %s %s

assistant: ```c
void irc_pong(char *server) {
  char msg[(512 - 3)];
  snprintf(msg, (512 - 3), "%s %s", "PONG", server);
  net_send(msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x24(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D37
datatype: string
name: retrieve_data
arguments: data_label: D41
datatype: string
name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D79
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D46
datatype: string

tool: D37: value of *ptr1 %d


tool: D41: value of **ptr2 %d


tool: D16: value of ***ptr3 %d


tool: D79: address of ptr1 %p


tool: D26: address of ptr2 %p


tool: D7: address of ptr3 %p


tool: D4: address of *ptr2 %p


tool: D46: address of *ptr3 %p


assistant: ```c
int main() {
  int p = 5;
  int *ptr1 = &p;
  int **ptr2 = &ptr1;
  int ***ptr3 = &ptr2;
  printf("value of *ptr1 %d\n", *ptr1);
  printf("value of **ptr2 %d\n", **ptr2);
  printf("value of ***ptr3 %d\n", ***ptr3);
  printf("address of ptr1 %p\n", (void *)&ptr1);
  printf("address of ptr2 %p\n", (void *)&ptr2);
  printf("address of ptr3 %p\n", (void *)&ptr3);
  printf("address of *ptr2 %p\n", (void *)ptr2);
  printf("address of *ptr3 %p\n", (void *)ptr3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,0xc(%rsp)
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rbp,0x18(%rsp)
  lea    0x18(%rsp),%rbx
  mov    %rbx,0x20(%rsp)
  mov    $0x5,%esi
  lea    D68(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  mov    (%rax),%rax
  movslq (%rax),%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  movslq (%rax),%rsi
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D78(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D68
type: string
name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D67
type: string
name: extract_symbolic_data
arguments: label: D34
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D37
type: string
name: extract_symbolic_data
arguments: label: D78
type: string
name: extract_symbolic_data
arguments: label: D27
type: string

tool: D68: value of *ptr1 %d


tool: D24: value of **ptr2 %d


tool: D67: value of ***ptr3 %d


tool: D34: address of ptr1 %p


tool: D21: address of ptr2 %p


tool: D37: address of ptr3 %p


tool: D78: address of *ptr2 %p


tool: D27: address of *ptr3 %p


assistant: ```c
int main() {
  int p = 5;
  int *ptr1 = &p;
  int **ptr2 = &ptr1;
  int ***ptr3 = &ptr2;
  printf("value of *ptr1 %d\n", *ptr1);
  printf("value of **ptr2 %d\n", **ptr2);
  printf("value of ***ptr3 %d\n", ***ptr3);
  printf("address of ptr1 %p\n", (void *)&ptr1);
  printf("address of ptr2 %p\n", (void *)&ptr2);
  printf("address of ptr3 %p\n", (void *)&ptr3);
  printf("address of *ptr2 %p\n", (void *)ptr2);
  printf("address of *ptr3 %p\n", (void *)ptr3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  lea    D44(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rax
  movl   $0x5,0xc(%rsp)
  lea    0x18(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  mov    %r12,0x18(%rsp)
  mov    %rbp,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    D13(%rip),%rdi
  mov    (%rax),%rax
  movslq (%rax),%rsi
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  lea    D75(%rip),%rdi
  mov    (%rax),%rax
  mov    (%rax),%rax
  movslq (%rax),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D76(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D72(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D44
type: string
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D75
type: string
name: extract_symbolic_data
arguments: label: D76
type: string
name: extract_symbolic_data
arguments: label: D72
type: string
name: extract_symbolic_data
arguments: label: D41
type: string
name: extract_symbolic_data
arguments: label: D69
type: string
name: extract_symbolic_data
arguments: label: D64
type: string

tool: D44: value of *ptr1 %d


tool: D13: value of **ptr2 %d


tool: D75: value of ***ptr3 %d


tool: D76: address of ptr1 %p


tool: D72: address of ptr2 %p


tool: D41: address of ptr3 %p


tool: D69: address of *ptr2 %p


tool: D64: address of *ptr3 %p


assistant: ```c
int main() {
  int p = 5;
  int *ptr1 = &p;
  int **ptr2 = &ptr1;
  int ***ptr3 = &ptr2;
  printf("value of *ptr1 %d\n", *ptr1);
  printf("value of **ptr2 %d\n", **ptr2);
  printf("value of ***ptr3 %d\n", ***ptr3);
  printf("address of ptr1 %p\n", (void *)&ptr1);
  printf("address of ptr2 %p\n", (void *)&ptr2);
  printf("address of ptr3 %p\n", (void *)&ptr3);
  printf("address of *ptr2 %p\n", (void *)ptr2);
  printf("address of *ptr3 %p\n", (void *)ptr3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  lea    D68(%rip),%rdi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rax
  movl   $0x5,0xc(%rsp)
  lea    0x18(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  mov    %r12,0x18(%rsp)
  mov    %rbp,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    D28(%rip),%rdi
  mov    (%rax),%rax
  movslq (%rax),%rsi
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  lea    D41(%rip),%rdi
  mov    (%rax),%rax
  mov    (%rax),%rax
  movslq (%rax),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x20(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D68
type_guessed: string
name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D57
type_guessed: string
name: unpack_data
arguments: data_label: D53
type_guessed: string
name: unpack_data
arguments: data_label: D50
type_guessed: string
name: unpack_data
arguments: data_label: D31
type_guessed: string
name: unpack_data
arguments: data_label: D37
type_guessed: string

tool: D68: value of *ptr1 %d


tool: D28: value of **ptr2 %d


tool: D41: value of ***ptr3 %d


tool: D57: address of ptr1 %p


tool: D53: address of ptr2 %p


tool: D50: address of ptr3 %p


tool: D31: address of *ptr2 %p


tool: D37: address of *ptr3 %p


assistant: ```c
int main() {
  int p = 5;
  int *ptr1 = &p;
  int **ptr2 = &ptr1;
  int ***ptr3 = &ptr2;
  printf("value of *ptr1 %d\n", *ptr1);
  printf("value of **ptr2 %d\n", **ptr2);
  printf("value of ***ptr3 %d\n", ***ptr3);
  printf("address of ptr1 %p\n", (void *)&ptr1);
  printf("address of ptr2 %p\n", (void *)&ptr2);
  printf("address of ptr3 %p\n", (void *)&ptr3);
  printf("address of *ptr2 %p\n", (void *)ptr2);
  printf("address of *ptr3 %p\n", (void *)ptr3);
  return 0;
}
```