ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<TimerPrescaleMatchSet>:
  endbr64
  test   %sil,%sil
  je     L3
  lea    0x40(%rdi),%eax
  movslq %edx,%rcx
  cltq
  mov    %rcx,(%rax)
L3:
  and    $0xff00,%esi
  je     L19
  add    $0x44,%edi
  movslq %edx,%rdx
  movslq %edi,%rdi
  mov    %rdx,(%rdi)
L19:
  ret
```

assistant: ```c
void TimerPrescaleMatchSet(uint32_t ui32Base, uint32_t ui32Timer, uint32_t ui32Value) {
  ;

  ;
  ;
  if (ui32Timer & 0x000000ff) {
    (*((volatile unsigned long *)(ui32Base + 0x00000040))) = ui32Value;
  }
  if (ui32Timer & 0x0000ff00) {
    (*((volatile unsigned long *)(ui32Base + 0x00000044))) = ui32Value;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerPrescaleMatchSet>:
  endbr64
  test   %sil,%sil
  je     L15
  lea    0x40(%rdi),%eax
  movslq %edx,%rcx
  cltq
  mov    %rcx,(%rax)
L15:
  and    $0xff00,%esi
  je     L4
  add    $0x44,%edi
  movslq %edx,%rdx
  movslq %edi,%rdi
  mov    %rdx,(%rdi)
L4:
  ret
```

assistant: ```c
void TimerPrescaleMatchSet(uint32_t ui32Base, uint32_t ui32Timer, uint32_t ui32Value) {
  ;

  ;
  ;
  if (ui32Timer & 0x000000ff) {
    (*((volatile unsigned long *)(ui32Base + 0x00000040))) = ui32Value;
  }
  if (ui32Timer & 0x0000ff00) {
    (*((volatile unsigned long *)(ui32Base + 0x00000044))) = ui32Value;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_non_option_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x50,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L35
L13:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    D27(%rip),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L4
  mov    $0xffffffff,%eax
  jmp    L14
L4:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x20,(%rax)
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L35:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jg     L13
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int copy_non_option_args(int argc, char **argv, char *bpf_expr) {
  size_t room = 80;
  char *p = bpf_expr;
  while (optind < argc) {
    char *m;
    size_t sz;
    m = argv[optind++];
    sz = strlen(m);
    if (room < sz + 1)
      return -1;
    memcpy(p, m, sz);
    p += sz;
    *p++ = ' ';
    room -= sz + 1;
  }
  *p = '\0';
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_non_option_args>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edi
  jle    L36
  mov    %edi,%r14d
  mov    %rsi,%r15
  mov    $0x50,%ebp
L5:
  lea    0x1(%rax),%edx
  mov    D27(%rip),%rcx
  mov    %edx,(%rcx)
  cltq
  mov    (%r15,%rax,8),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    %rbp,%rax
  ja     L34
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rax
  lea    0x1(%rax),%r12
  movb   $0x20,(%rax)
  sub    %rbx,%rbp
  sub    $0x1,%rbp
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %r14d,%eax
  jl     L5
L36:
  movb   $0x0,(%r12)
  mov    $0x0,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int copy_non_option_args(int argc, char **argv, char *bpf_expr) {
  size_t room = 80;
  char *p = bpf_expr;
  while (optind < argc) {
    char *m;
    size_t sz;
    m = argv[optind++];
    sz = strlen(m);
    if (room < sz + 1)
      return -1;
    memcpy(p, m, sz);
    p += sz;
    *p++ = ' ';
    room -= sz + 1;
  }
  *p = '\0';
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<copy_non_option_args>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D5(%rip),%r13
  mov    %edi,0xc(%rsp)
  movslq 0x0(%r13),%rax
  cmp    %eax,%edi
  jle    L5
  mov    %rsi,%r15
  mov    $0x50,%ebp
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %r12,%rdi
  mov    %rbx,%rdx
  mov    %r14,%rsi
  sub    %rbx,%rbp
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rax
  sub    $0x1,%rbp
  movb   $0x20,(%rax)
  lea    0x1(%rax),%r12
  movslq 0x0(%r13),%rax
  cmp    0xc(%rsp),%eax
  jge    L5
L20:
  mov    (%r15,%rax,8),%r14
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%r13)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    %rbp,%rax
  jbe    L31
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L5:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int copy_non_option_args(int argc, char **argv, char *bpf_expr) {
  size_t room = 80;
  char *p = bpf_expr;
  while (optind < argc) {
    char *m;
    size_t sz;
    m = argv[optind++];
    sz = strlen(m);
    if (room < sz + 1)
      return -1;
    memcpy(p, m, sz);
    p += sz;
    *p++ = ' ';
    room -= sz + 1;
  }
  *p = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy_non_option_args>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D6(%rip),%r13
  mov    %edi,0xc(%rsp)
  movslq 0x0(%r13),%rax
  cmp    %eax,%edi
  jle    L32
  mov    %rsi,%r15
  mov    $0x50,%ebp
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r12,%rdi
  mov    %rbx,%rdx
  mov    %r14,%rsi
  sub    %rbx,%rbp
  call   <memcpy@plt>
  lea    (%r12,%rbx,1),%rax
  sub    $0x1,%rbp
  movb   $0x20,(%rax)
  lea    0x1(%rax),%r12
  movslq 0x0(%r13),%rax
  cmp    0xc(%rsp),%eax
  jge    L32
L7:
  mov    (%r15,%rax,8),%r14
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%r13)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    %rbp,%rax
  jbe    L29
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L32:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int copy_non_option_args(int argc, char **argv, char *bpf_expr) {
  size_t room = 80;
  char *p = bpf_expr;
  while (optind < argc) {
    char *m;
    size_t sz;
    m = argv[optind++];
    sz = strlen(m);
    if (room < sz + 1)
      return -1;
    memcpy(p, m, sz);
    p += sz;
    *p++ = ' ';
    room -= sz + 1;
  }
  *p = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decode_buttons_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x2(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  lea    D1(%rip),%rsi
  mov    %eax,%edi
  call   <print_idx_field_unicode@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: Buttons status

assistant: ```c
int decode_buttons_status(uint8_t idx, const uint8_t *ptr, int len) {
  print_idx_field_unicode(idx, "Buttons status", ptr + 2, len - 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_buttons_status>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x2(%rdx),%ecx
  lea    0x8(%rsi),%rdx
  lea    D6(%rip),%rsi
  call   <print_idx_field_unicode@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D6: Buttons status

assistant: ```c
int decode_buttons_status(uint8_t idx, const uint8_t *ptr, int len) {
  print_idx_field_unicode(idx, "Buttons status", ptr + 2, len - 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_buttons_status>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x2(%rdx),%ecx
  lea    0x8(%rsi),%rdx
  lea    D8(%rip),%rsi
  call   <print_idx_field_unicode@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: Buttons status

assistant: ```c
int decode_buttons_status(uint8_t idx, const uint8_t *ptr, int len) {
  print_idx_field_unicode(idx, "Buttons status", ptr + 2, len - 2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_buttons_status>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x2(%rdx),%ecx
  lea    0x8(%rsi),%rdx
  lea    D4(%rip),%rsi
  call   <print_idx_field_unicode@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: Buttons status

assistant: ```c
int decode_buttons_status(uint8_t idx, const uint8_t *ptr, int len) {
  print_idx_field_unicode(idx, "Buttons status", ptr + 2, len - 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1e,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L61
L3:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L3
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L38
L66:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L66
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L9:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x3,(%rax)
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L9
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L40
L53:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x4,(%rax)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L53
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int *a, int i) {
  int j, k = 1, l = 30, m = 4;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = 0; j <= l; j++)
    a[j] = 1;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 2;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = 0; j <= l; j++)
    a[j] = 3;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    %rdi,%rax
  lea    0x7c(%rdi),%rcx
  mov    %rdi,%rdx
L21:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L21
  lea    0x4(%rdi),%rdx
  mov    %rdx,%rsi
L32:
  movl   $0x2,(%rsi)
  add    $0xc,%rsi
  cmp    %rcx,%rsi
  jne    L32
L33:
  movl   $0x3,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L33
L39:
  movl   $0x4,(%rdx)
  add    $0xc,%rdx
  cmp    %rcx,%rdx
  jne    L39
  ret
```

assistant: ```c
void foo(int *a, int i) {
  int j, k = 1, l = 30, m = 4;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = 0; j <= l; j++)
    a[j] = 1;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 2;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = 0; j <= l; j++)
    a[j] = 3;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  mov    %rdi,%rax
  lea    0x7c(%rdi),%rcx
  mov    %rdi,%rdx
  xchg   %ax,%ax
L26:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L26
  lea    0x4(%rdi),%rdx
  mov    %rdx,%rsi
  cs nopw 0x0(%rax,%rax,1)
L29:
  movl   $0x2,(%rsi)
  add    $0xc,%rsi
  cmp    %rcx,%rsi
  jne    L29
  nop
L6:
  movl   $0x3,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
  nop
L1:
  movl   $0x4,(%rdx)
  add    $0xc,%rdx
  cmp    %rcx,%rdx
  jne    L1
  ret
```

assistant: ```c
void foo(int *a, int i) {
  int j, k = 1, l = 30, m = 4;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = 0; j <= l; j++)
    a[j] = 1;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 2;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = 0; j <= l; j++)
    a[j] = 3;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 4;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  movabs $0x400000003,%rcx
  movl   $0x3,0x78(%rdi)
  movabs $0x300000003,%rdx
  movabs $0x300000004,%rax
  mov    %rcx,(%rdi)
  mov    %rdx,0x8(%rdi)
  mov    %rax,0x10(%rdi)
  mov    %rcx,0x18(%rdi)
  mov    %rdx,0x20(%rdi)
  mov    %rax,0x28(%rdi)
  mov    %rcx,0x30(%rdi)
  mov    %rdx,0x38(%rdi)
  mov    %rax,0x40(%rdi)
  mov    %rcx,0x48(%rdi)
  mov    %rdx,0x50(%rdi)
  mov    %rax,0x58(%rdi)
  mov    %rcx,0x60(%rdi)
  mov    %rdx,0x68(%rdi)
  mov    %rax,0x70(%rdi)
  ret
```

assistant: ```c
void foo(int *a, int i) {
  int j, k = 1, l = 30, m = 4;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = 0; j <= l; j++)
    a[j] = 1;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, i * 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 2;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = 0; j <= l; j++)
    a[j] = 3;
#pragma omp parallel for num_threads(3 * i) schedule(dynamic, 4)
  for (j = k; j <= l; j += (m - 1))
    a[j] = 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<IceAuthFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x18(%rbp),%rax
  jmp    L93
L1:
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L93
L31:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    D31(%rip),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L34
  mov    D36(%rip),%rax
  test   %rax,%rax
  je     L15
  mov    D36(%rip),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,D51(%rip)
  mov    D51(%rip),%rax
  test   %rax,%rax
  jne    L84
  mov    $0x0,%eax
  jmp    L93
L84:
  mov    -0x1c(%rbp),%eax
  mov    %eax,D51(%rip)
L34:
  mov    D51(%rip),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  lea    D26(%rip),%rax
  jmp    L19
L0:
  lea    D51(%rip),%rax
L19:
  mov    D51(%rip),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcat@plt>
  mov    D51(%rip),%rax
L93:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D86
type_infered: string

tool: D57: ICEAUTHORITY

tool: D86: HOME

assistant: ```c
char *IceAuthFileName() {
  static char slashDotICEauthority[] = "/.ICEauthority";
  char *name;
  static char *buf;
  static int bsize;
  int size;
  if ((name = getenv("ICEAUTHORITY")))
    return (name);
  name = getenv("HOME");
  if (!name) {
    return (NULL);
  }
  size = strlen(name) + strlen(&slashDotICEauthority[1]) + 2;
  if (size > bsize) {
    if (buf)
      free(buf);
    buf = malloc((unsigned)size);
    if (!buf)
      return (NULL);
    bsize = size;
  }
  strcpy(buf, name);
  strcat(buf, slashDotICEauthority + (name[1] == '\0' ? 1 : 0));
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eratos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L24
  mov    $0x0,%eax
  jmp    L32
L24:
  movl   $0x2,-0x10(%rbp)
  jmp    L34
L60:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L60
  movl   $0x2,-0x10(%rbp)
  jmp    L16
L77:
  movl   $0x2,-0xc(%rbp)
  jmp    L70
L37:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L70:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L37
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L77
L32:
  leave
  ret
```

assistant: ```c
int *eratos(int n) {
  int i, j;
  int *primeArray = malloc(sizeof(int) * (n + 1));
  if (n < 2)
    return NULL;
  for (i = 2; i <= n; i++)
    primeArray[i] = 1;
  for (i = 2; i * i <= n; i++) {
    for (j = 2; i * j <= n; j++)
      primeArray[i * j] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eratos>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L29
  lea    0x8(%rax),%rdx
  lea    -0x2(%rbx),%ecx
  lea    0xc(%rax,%rcx,4),%rcx
L11:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L11
  mov    $0x2,%ecx
  mov    $0x4,%edi
  cmp    $0x3,%ebx
  jg     L48
  jmp    L76
L29:
  mov    $0x0,%eax
L76:
  pop    %rbx
  ret
L58:
  movl   $0x0,(%rax,%rdx,4)
  add    %rcx,%rdx
  cmp    %edx,%ebx
  jge    L58
L65:
  lea    0x1(%rsi),%edx
  add    $0x2,%rdi
  add    $0x1,%rcx
  imul   %edx,%edx
  cmp    %ebx,%edx
  jg     L76
L48:
  mov    %ecx,%esi
  mov    %rdi,%rdx
  cmp    %edi,%ebx
  jge    L58
  jmp    L65
```

assistant: ```c
int *eratos(int n) {
  int i, j;
  int *primeArray = malloc(sizeof(int) * (n + 1));
  if (n < 2)
    return NULL;
  for (i = 2; i <= n; i++)
    primeArray[i] = 1;
  for (i = 2; i * i <= n; i++) {
    for (j = 2; i * j <= n; j++)
      primeArray[i * j] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eratos>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L47
  lea    -0x2(%rbx),%ecx
  lea    0x8(%rax),%rdx
  lea    0xc(%rax,%rcx,4),%rcx
  nopl   0x0(%rax)
L28:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L28
  mov    $0x2,%ecx
  mov    $0x4,%edi
  cmp    $0x3,%ebx
  jle    L15
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %ecx,%esi
  mov    %rdi,%rdx
  cmp    %edi,%ebx
  jl     L54
  nopl   0x0(%rax)
L52:
  movl   $0x0,(%rax,%rdx,4)
  add    %rcx,%rdx
  cmp    %edx,%ebx
  jge    L52
L54:
  lea    0x1(%rsi),%edx
  add    $0x2,%rdi
  add    $0x1,%rcx
  imul   %edx,%edx
  cmp    %ebx,%edx
  jle    L8
L15:
  pop    %rbx
  ret
L47:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int *eratos(int n) {
  int i, j;
  int *primeArray = malloc(sizeof(int) * (n + 1));
  if (n < 2)
    return NULL;
  for (i = 2; i <= n; i++)
    primeArray[i] = 1;
  for (i = 2; i * i <= n; i++) {
    for (j = 2; i * j <= n; j++)
      primeArray[i * j] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<eratos>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x4(,%rdi,4),%edi
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L5
  mov    %rax,%rcx
  lea    -0x2(%rbx),%eax
  lea    -0x1(%rbx),%esi
  cmp    $0x2,%eax
  jbe    L1
  mov    %esi,%edx
  movdqa D4(%rip),%xmm0
  lea    0x8(%rcx),%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%rcx,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L90:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L90
  mov    %esi,%edx
  and    $0xfffffffc,%edx
  lea    0x2(%rdx),%eax
  cmp    %esi,%edx
  je     L10
L98:
  movslq %eax,%rdx
  movl   $0x1,(%rcx,%rdx,4)
  lea    0x0(,%rdx,4),%rsi
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jl     L37
  add    $0x2,%eax
  movl   $0x1,0x4(%rcx,%rsi,1)
  cmp    %eax,%ebx
  jl     L37
  movl   $0x1,0x8(%rcx,%rsi,1)
L10:
  mov    $0x2,%edx
  mov    $0x4,%edi
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %edx,%esi
  mov    %rdi,%rax
  cmp    %edi,%ebx
  jl     L79
  nopl   0x0(%rax)
L6:
  movl   $0x0,(%rcx,%rax,4)
  add    %rdx,%rax
  cmp    %eax,%ebx
  jge    L6
L79:
  lea    0x1(%rsi),%eax
  add    $0x2,%rdi
  add    $0x1,%rdx
  imul   %eax,%eax
  cmp    %ebx,%eax
  jle    L73
  pop    %rbx
  ret
L5:
  xor    %eax,%eax
  pop    %rbx
  ret
L37:
  cmp    $0x3,%ebx
  jg     L10
  pop    %rbx
  ret
L1:
  mov    $0x2,%eax
  jmp    L98
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: byte[16]

tool: {"D4": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int *eratos(int n) {
  int i, j;
  int *primeArray = malloc(sizeof(int) * (n + 1));
  if (n < 2)
    return NULL;
  for (i = 2; i <= n; i++)
    primeArray[i] = 1;
  for (i = 2; i * i <= n; i++) {
    for (j = 2; i * j <= n; j++)
      primeArray[i * j] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sf_g2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((no, noclone)) sf_g2(float *__restrict a, float *__restrict b, float *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    c[i * 2] = a[i];
    c[i * 2 + 1] = b[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sf_g2>:
  endbr64
  mov    $0x0,%eax
L6:
  movss  (%rdi,%rax,1),%xmm0
  movss  %xmm0,(%rdx,%rax,2)
  movss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,0x4(%rdx,%rax,2)
  add    $0x4,%rax
  cmp    $0x1000,%rax
  jne    L6
  ret
```

assistant: ```c
void __attribute__((no, noclone)) sf_g2(float *__restrict a, float *__restrict b, float *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    c[i * 2] = a[i];
    c[i * 2 + 1] = b[i];
  }
}
```