ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mkdir>:
  endbr64
  push   %r12
  lea    D9(%rip),%rsi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x208,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: mkdir -p 

assistant: ```c
void mkdir(char *c_file) {
  char c_aux[500];
  strcpy(c_aux, "mkdir -p ");
  strcat(c_aux, c_file);
  system(c_aux);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L4
L6:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x64,-0xc(%rbp)
  jle    L6
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D19
type: string

tool: D12: result[1-100] = %d


tool: D19: result[1-250] = %d


assistant: ```c
main() {
  int i;
  long result = 0;
  for (i = 1; i <= 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x13ba,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string

tool: D13: result[1-100] = %d


tool: D12: result[1-250] = %d


assistant: ```c
main() {
  int i;
  long result = 0;
  for (i = 1; i <= 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13ba,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string

tool: D16: result[1-100] = %d


tool: D19: result[1-250] = %d


assistant: ```c
main() {
  int i;
  long result = 0;
  for (i = 1; i <= 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13ba,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D13
datatype: string

tool: D16: result[1-100] = %d


tool: D13: result[1-250] = %d


assistant: ```c
main() {
  int i;
  long result = 0;
  for (i = 1; i <= 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L29:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  je     L20
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L20:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *source, char *target, unsigned int length) {
  char *source_start = source;
  while (length-- && *target != '\0')
    *source++ = *target++;
  *source = '\0';
  return source_start;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  je     L21
  mov    %ecx,%ecx
  lea    0x1(%rdi,%rcx,1),%r8
  mov    %rdi,%rdx
L2:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L8
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %r8,%rdx
  jne    L2
  mov    %r8,%rdx
L8:
  movb   $0x0,(%rdx)
  ret
L21:
  mov    %rdi,%rdx
  jmp    L8
```

assistant: ```c
char *strncpy(char *source, char *target, unsigned int length) {
  char *source_start = source;
  while (length-- && *target != '\0')
    *source++ = *target++;
  *source = '\0';
  return source_start;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L5
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rdx
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L27:
  add    $0x1,%rdx
  add    $0x1,%rsi
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%r8
  je     L14
L40:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L27
L14:
  movb   $0x0,(%rdx)
  ret
L5:
  mov    %rdi,%rdx
  jmp    L14
```

assistant: ```c
char *strncpy(char *source, char *target, unsigned int length) {
  char *source_start = source;
  while (length-- && *target != '\0')
    *source++ = *target++;
  *source = '\0';
  return source_start;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L25
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rdx
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdx
  add    $0x1,%rsi
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%r8
  je     L47
L24:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L10
L47:
  movb   $0x0,(%rdx)
  ret
L25:
  mov    %rdi,%rdx
  jmp    L47
```

assistant: ```c
char *strncpy(char *source, char *target, unsigned int length) {
  char *source_start = source;
  while (length-- && *target != '\0')
    *source++ = *target++;
  *source = '\0';
  return source_start;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <tambah_datamhs@plt>
  mov    $0x0,%eax
  call   <tampil_data@plt>
  mov    $0x0,%eax
  call   <Coba@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  tambah_datamhs();
  tampil_data();
  Coba();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tambah_datamhs@plt>
  mov    $0x0,%eax
  call   <tampil_data@plt>
  mov    $0x0,%eax
  call   <Coba@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  tambah_datamhs();
  tampil_data();
  Coba();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tambah_datamhs@plt>
  xor    %eax,%eax
  call   <tampil_data@plt>
  xor    %eax,%eax
  call   <Coba@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  tambah_datamhs();
  tampil_data();
  Coba();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tambah_datamhs@plt>
  xor    %eax,%eax
  call   <tampil_data@plt>
  xor    %eax,%eax
  call   <Coba@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  tambah_datamhs();
  tampil_data();
  Coba();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<artio_double_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L19
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movzbl -0x11(%rbp),%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x12(%rbp),%eax
  mov    %al,-0xf(%rbp)
  movzbl -0x13(%rbp),%eax
  mov    %al,-0xe(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0xd(%rbp)
  movzbl -0x15(%rbp),%eax
  mov    %al,-0xc(%rbp)
  movzbl -0x16(%rbp),%eax
  mov    %al,-0xb(%rbp)
  movzbl -0x17(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L23
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void artio_double_swap(double *src, int count) {
  int i;
  union {
    double d;
    unsigned char c[8];
  } d1, d2;
  for (i = 0; i < count; i++) {
    d1.d = src[i];
    d2.c[0] = d1.c[7];
    d2.c[1] = d1.c[6];
    d2.c[2] = d1.c[5];
    d2.c[3] = d1.c[4];
    d2.c[4] = d1.c[3];
    d2.c[5] = d1.c[2];
    d2.c[6] = d1.c[1];
    d2.c[7] = d1.c[0];
    src[i] = d2.d;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<artio_double_swap>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r10
  movabs $0xffffffff00ffffff,%r9
  movabs $0xffffff00ffffffff,%r8
  movabs $0xffff00ffffffffff,%rdi
  movabs $0xff00ffffffffffff,%rsi
  movabs $0xffffffffffffff,%r12
L4:
  mov    (%rdx),%rbx
  mov    %rbx,%rax
  shr    $0x38,%rax
  mov    %al,%cl
  mov    %rbx,%rax
  shr    $0x30,%rax
  mov    %al,%ch
  mov    %rbx,%rbp
  shr    $0x18,%rbp
  and    $0xff0000,%ebp
  mov    %rcx,%rax
  and    $0xffffffffff00ffff,%rax
  or     %rbp,%rax
  mov    %rbx,%r11
  shr    $0x8,%r11
  and    $0xff000000,%r11d
  and    %r9,%rax
  or     %r11,%rax
  mov    %rbx,%r11
  shr    $0x18,%r11
  movzbl %r11b,%r11d
  shl    $0x20,%r11
  and    %r8,%rax
  or     %r11,%rax
  mov    %rbx,%r11
  shr    $0x10,%r11
  movzbl %r11b,%r11d
  shl    $0x28,%r11
  and    %rdi,%rax
  or     %r11,%rax
  movzbl %bh,%ecx
  mov    %rcx,%r11
  shl    $0x30,%r11
  and    %rsi,%rax
  or     %r11,%rax
  shl    $0x38,%rbx
  and    %r12,%rax
  or     %rbx,%rax
  mov    %rax,%rcx
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  cmp    %r10,%rdx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void artio_double_swap(double *src, int count) {
  int i;
  union {
    double d;
    unsigned char c[8];
  } d1, d2;
  for (i = 0; i < count; i++) {
    d1.d = src[i];
    d2.c[0] = d1.c[7];
    d2.c[1] = d1.c[6];
    d2.c[2] = d1.c[5];
    d2.c[3] = d1.c[4];
    d2.c[4] = d1.c[3];
    d2.c[5] = d1.c[2];
    d2.c[6] = d1.c[1];
    d2.c[7] = d1.c[0];
    src[i] = d2.d;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<artio_double_swap>:
  endbr64
  test   %esi,%esi
  jle    L7
  movabs $0xffffffff00ffffff,%r9
  push   %r14
  lea    -0x1(%rsi),%edx
  movabs $0xffffff00ffffffff,%r8
  movabs $0xffff00ffffffffff,%rsi
  push   %rbx
  lea    0x8(%rdi,%rdx,8),%r10
  movabs $0xff00ffffffffffff,%rcx
  movabs $0xffffffffffffff,%r14
  nopl   0x0(%rax)
L18:
  mov    (%rdi),%rbx
  add    $0x8,%rdi
  mov    %rbx,%r11
  shr    $0x38,%r11
  mov    %r11b,%al
  mov    %rbx,%r11
  shr    $0x30,%r11
  mov    %r11,%rdx
  mov    %rbx,%r11
  mov    %dl,%ah
  shr    $0x18,%r11
  movzbl %bh,%edx
  and    $0xff0000,%r11d
  and    $0xffffffffff00ffff,%rax
  or     %r11,%rax
  mov    %rbx,%r11
  shr    $0x8,%r11
  and    %r9,%rax
  and    $0xff000000,%r11d
  or     %r11,%rax
  mov    %rbx,%r11
  shr    $0x18,%r11
  and    %r8,%rax
  movzbl %r11b,%r11d
  shl    $0x20,%r11
  or     %r11,%rax
  mov    %rbx,%r11
  shl    $0x38,%rbx
  shr    $0x10,%r11
  and    %rsi,%rax
  movzbl %r11b,%r11d
  shl    $0x28,%r11
  or     %r11,%rax
  mov    %rdx,%r11
  shl    $0x30,%r11
  and    %rcx,%rax
  or     %r11,%rax
  and    %r14,%rax
  or     %rbx,%rax
  mov    %rax,-0x8(%rdi)
  cmp    %r10,%rdi
  jne    L18
  pop    %rbx
  pop    %r14
  ret
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void artio_double_swap(double *src, int count) {
  int i;
  union {
    double d;
    unsigned char c[8];
  } d1, d2;
  for (i = 0; i < count; i++) {
    d1.d = src[i];
    d2.c[0] = d1.c[7];
    d2.c[1] = d1.c[6];
    d2.c[2] = d1.c[5];
    d2.c[3] = d1.c[4];
    d2.c[4] = d1.c[3];
    d2.c[5] = d1.c[2];
    d2.c[6] = d1.c[1];
    d2.c[7] = d1.c[0];
    src[i] = d2.d;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<artio_double_swap>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdx
  nopl   (%rax)
L1:
  mov    (%rdi),%rcx
  add    $0x8,%rdi
  movzbl %cl,%eax
  mov    %rcx,%r11
  movzbl %ch,%ebx
  mov    %rcx,%r10
  shl    $0x8,%rax
  shr    $0x10,%r11
  mov    %rcx,%r9
  mov    %rcx,%r8
  or     %rbx,%rax
  movzbl %r11b,%r11d
  shr    $0x18,%r10
  mov    %rcx,%rsi
  shl    $0x8,%rax
  movzbl %r10b,%r10d
  shr    $0x20,%r9
  shr    $0x28,%r8
  or     %r11,%rax
  movzbl %r9b,%r9d
  shr    $0x30,%rsi
  shl    $0x8,%rax
  movzbl %r8b,%r8d
  movzbl %sil,%esi
  shr    $0x38,%rcx
  or     %r10,%rax
  shl    $0x8,%rax
  or     %r9,%rax
  shl    $0x8,%rax
  or     %r8,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  mov    %rax,-0x8(%rdi)
  cmp    %rdi,%rdx
  jne    L1
  pop    %rbx
  ret
L12:
  ret
```

assistant: ```c
void artio_double_swap(double *src, int count) {
  int i;
  union {
    double d;
    unsigned char c[8];
  } d1, d2;
  for (i = 0; i < count; i++) {
    d1.d = src[i];
    d2.c[0] = d1.c[7];
    d2.c[1] = d1.c[6];
    d2.c[2] = d1.c[5];
    d2.c[3] = d1.c[4];
    d2.c[4] = d1.c[3];
    d2.c[5] = d1.c[2];
    d2.c[6] = d1.c[1];
    d2.c[7] = d1.c[0];
    src[i] = d2.d;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<intel_pt_get_ext>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L68
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%eax
  cmp    $0x83,%al
  je     L22
  ja     L77
  cmp    $0x43,%al
  je     L268
  jbe    L63
  cmp    $0x73,%al
  je     L1
  cmp    $0x82,%al
  jne    L7
  call   <intel_pt_get_psb@plt>
  jmp    L92
L63:
  cmp    $0x3,%al
  je     L23
  cmp    $0x23,%al
  jne    L127
  mov    %rdx,%rdi
  call   <intel_pt_get_psbend@plt>
  jmp    L92
L127:
  mov    $0xfffffffe,%eax
  jmp    L92
L7:
  mov    $0xfffffffe,%eax
  jmp    L92
L77:
  cmp    $0xc8,%al
  je     L172
  jbe    L93
  cmp    $0xf3,%al
  jne    L183
  mov    %rdx,%rdi
  call   <intel_pt_get_ovf@plt>
  jmp    L92
L93:
  cmp    $0xa3,%al
  je     L240
  cmp    $0xc3,%al
  jne    L79
  call   <intel_pt_get_3byte@plt>
  jmp    L92
L79:
  mov    $0xfffffffe,%eax
  jmp    L92
L183:
  mov    $0xfffffffe,%eax
L92:
  add    $0x8,%rsp
  ret
L240:
  call   <intel_pt_get_long_tnt@plt>
  jmp    L92
L268:
  call   <intel_pt_get_pip@plt>
  jmp    L92
L22:
  mov    %rdx,%rdi
  call   <intel_pt_get_tracestop@plt>
  jmp    L92
L23:
  call   <intel_pt_get_cbr@plt>
  jmp    L92
L172:
  call   <intel_pt_get_vmcs@plt>
  jmp    L92
L1:
  call   <intel_pt_get_tma@plt>
  jmp    L92
L68:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int intel_pt_get_ext(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  if (len < 2) {
    return -1;
  }
  switch (buf[1]) {
  case 0xa3:
    return intel_pt_get_long_tnt(buf, len, packet);
  case 0x43:
    return intel_pt_get_pip(buf, len, packet);
  case 0x83:
    return intel_pt_get_tracestop(packet);
  case 0x03:
    return intel_pt_get_cbr(buf, len, packet);
  case 0xc8:
    return intel_pt_get_vmcs(buf, len, packet);
  case 0xf3:
    return intel_pt_get_ovf(packet);
  case 0x82:
    return intel_pt_get_psb(buf, len, packet);
  case 0x23:
    return intel_pt_get_psbend(packet);
  case 0x73:
    return intel_pt_get_tma(buf, len, packet);
  case 0xC3:
    return intel_pt_get_3byte(buf, len, packet);
  default:
    return -2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<intel_pt_get_ext>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L37
  movzbl 0x1(%rdi),%eax
  cmp    $0x83,%al
  je     L83
  ja     L74
  cmp    $0x43,%al
  je     L32
  jbe    L108
  cmp    $0x73,%al
  je     L75
  cmp    $0x82,%al
  jne    L53
  jmp    1100 <intel_pt_get_psb@plt>
  nopl   0x0(%rax,%rax,1)
L74:
  cmp    $0xc8,%al
  je     L112
  jbe    L129
  cmp    $0xf3,%al
  jne    L53
  mov    %rdx,%rdi
  jmp    1120 <intel_pt_get_ovf@plt>
  nopw   0x0(%rax,%rax,1)
L108:
  cmp    $0x3,%al
  je     L16
  cmp    $0x23,%al
  jne    L53
  mov    %rdx,%rdi
  jmp    1150 <intel_pt_get_psbend@plt>
L129:
  cmp    $0xa3,%al
  je     L59
  cmp    $0xc3,%al
  jne    L53
  jmp    10e0 <intel_pt_get_3byte@plt>
  nopl   (%rax)
L53:
  mov    $0xfffffffe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L112:
  jmp    10f0 <intel_pt_get_vmcs@plt>
  nopl   (%rax)
L16:
  jmp    1160 <intel_pt_get_cbr@plt>
  nopl   (%rax)
L59:
  jmp    1140 <intel_pt_get_long_tnt@plt>
  nopl   (%rax)
L83:
  mov    %rdx,%rdi
  jmp    1110 <intel_pt_get_tracestop@plt>
L32:
  jmp    1170 <intel_pt_get_pip@plt>
  nopl   (%rax)
L75:
  jmp    1130 <intel_pt_get_tma@plt>
L37:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int intel_pt_get_ext(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  if (len < 2) {
    return -1;
  }
  switch (buf[1]) {
  case 0xa3:
    return intel_pt_get_long_tnt(buf, len, packet);
  case 0x43:
    return intel_pt_get_pip(buf, len, packet);
  case 0x83:
    return intel_pt_get_tracestop(packet);
  case 0x03:
    return intel_pt_get_cbr(buf, len, packet);
  case 0xc8:
    return intel_pt_get_vmcs(buf, len, packet);
  case 0xf3:
    return intel_pt_get_ovf(packet);
  case 0x82:
    return intel_pt_get_psb(buf, len, packet);
  case 0x23:
    return intel_pt_get_psbend(packet);
  case 0x73:
    return intel_pt_get_tma(buf, len, packet);
  case 0xC3:
    return intel_pt_get_3byte(buf, len, packet);
  default:
    return -2;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intel_pt_get_ext>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L62
  movzbl 0x1(%rdi),%eax
  cmp    $0x83,%al
  je     L26
  ja     L2
  cmp    $0x43,%al
  je     L116
  jbe    L59
  cmp    $0x73,%al
  je     L39
  cmp    $0x82,%al
  jne    L111
  jmp    1100 <intel_pt_get_psb@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    $0xc8,%al
  je     L86
  jbe    L15
  cmp    $0xf3,%al
  jne    L111
  mov    %rdx,%rdi
  jmp    1120 <intel_pt_get_ovf@plt>
  nopw   0x0(%rax,%rax,1)
L59:
  cmp    $0x3,%al
  je     L57
  cmp    $0x23,%al
  jne    L111
  mov    %rdx,%rdi
  jmp    1150 <intel_pt_get_psbend@plt>
L15:
  cmp    $0xa3,%al
  je     L110
  cmp    $0xc3,%al
  jne    L111
  jmp    10e0 <intel_pt_get_3byte@plt>
  nopl   (%rax)
L111:
  mov    $0xfffffffe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L86:
  jmp    10f0 <intel_pt_get_vmcs@plt>
  nopl   (%rax)
L57:
  jmp    1160 <intel_pt_get_cbr@plt>
  nopl   (%rax)
L110:
  jmp    1140 <intel_pt_get_long_tnt@plt>
  nopl   (%rax)
L26:
  mov    %rdx,%rdi
  jmp    1110 <intel_pt_get_tracestop@plt>
L116:
  jmp    1170 <intel_pt_get_pip@plt>
  nopl   (%rax)
L39:
  jmp    1130 <intel_pt_get_tma@plt>
L62:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int intel_pt_get_ext(const unsigned char *buf, size_t len, struct intel_pt_pkt *packet) {
  if (len < 2) {
    return -1;
  }
  switch (buf[1]) {
  case 0xa3:
    return intel_pt_get_long_tnt(buf, len, packet);
  case 0x43:
    return intel_pt_get_pip(buf, len, packet);
  case 0x83:
    return intel_pt_get_tracestop(packet);
  case 0x03:
    return intel_pt_get_cbr(buf, len, packet);
  case 0xc8:
    return intel_pt_get_vmcs(buf, len, packet);
  case 0xf3:
    return intel_pt_get_ovf(packet);
  case 0x82:
    return intel_pt_get_psb(buf, len, packet);
  case 0x23:
    return intel_pt_get_psbend(packet);
  case 0x73:
    return intel_pt_get_tma(buf, len, packet);
  case 0xC3:
    return intel_pt_get_3byte(buf, len, packet);
  default:
    return -2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<myFunction3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L5
  mov    -0x10(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  jmp    L8
L5:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
const int myFunction3(int const i[5], int const j[]) {
  if (i[3] == 0)
    return j[5];
  else {
    return j[0];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<myFunction3>:
  endbr64
  cmpl   $0x0,0xc(%rdi)
  jne    L6
  mov    0x14(%rsi),%eax
  ret
L6:
  mov    (%rsi),%eax
  ret
```

assistant: ```c
const int myFunction3(int const i[5], int const j[]) {
  if (i[3] == 0)
    return j[5];
  else {
    return j[0];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<myFunction3>:
  endbr64
  mov    0xc(%rdi),%eax
  test   %eax,%eax
  jne    L5
  mov    0x14(%rsi),%eax
  ret
  nop
L5:
  mov    (%rsi),%eax
  ret
```

assistant: ```c
const int myFunction3(int const i[5], int const j[]) {
  if (i[3] == 0)
    return j[5];
  else {
    return j[0];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myFunction3>:
  endbr64
  mov    0xc(%rdi),%eax
  test   %eax,%eax
  jne    L0
  mov    0x14(%rsi),%eax
  ret
  nop
L0:
  mov    (%rsi),%eax
  ret
```

assistant: ```c
const int myFunction3(int const i[5], int const j[]) {
  if (i[3] == 0)
    return j[5];
  else {
    return j[0];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldz
  fldt   0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L18
  fldt   0x10(%rbp)
  jmp    L33
L18:
  fldt   0x10(%rbp)
  fldz
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L2
  fldt   0x10(%rbp)
  fchs
  jmp    L33
L2:
  fldt   0x10(%rbp)
L33:
  pop    %rbp
  ret
```

assistant: ```c
long double func2(long double x) {
  if (x > 0.0)
    return x;
  else if (x < 0.0)
    return -x;
  else
    return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func2>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fcomi  %st(1),%st
  ja     L2
  fxch   %st(1)
  fcomip %st(1),%st
  ja     L0
  jmp    L14
L2:
  fstp   %st(1)
L14:
  ret
L0:
  fchs
  jmp    L14
```

assistant: ```c
long double func2(long double x) {
  if (x > 0.0)
    return x;
  else if (x < 0.0)
    return -x;
  else
    return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func2>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fcomi  %st(1),%st
  ja     L15
  fxch   %st(1)
  fcomip %st(1),%st
  ja     L26
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L15:
  fstp   %st(1)
L9:
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  fchs
  ret
```

assistant: ```c
long double func2(long double x) {
  if (x > 0.0)
    return x;
  else if (x < 0.0)
    return -x;
  else
    return x;
}
```