ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x3abcdef8,%edx
  mov    %eax,%edi
  call   <init_rng@plt>
  mov    %rax,-0x10(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <print_rng@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L24
L12:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_rn_dbl@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L24:
  cmpl   $0x2,-0x20(%rbp)
  jle    L12
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L11
L34:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_rn_int@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L11:
  cmpl   $0x2,-0x20(%rbp)
  jle    L34
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free_rng@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D35
type_guessed: string
name: read_data
arguments: data_label: D34
type_guessed: string
name: read_data
arguments: data_label: D44
type_guessed: string

tool: D17:  Print information about new stream:

tool: D7:  Printing 3 random numbers in [0,1):

tool: D35: %f


tool: D34:  Printing 3 random integers in [0,2^31):

tool: D44: %16d


assistant: ```c
main() {
  int streamnum, nstreams, *stream;
  double rn;
  int irn;
  int i;
  streamnum = 0;
  nstreams = 1;
  stream = init_rng(streamnum, nstreams, 985456376, 0);
  printf(" Print information about new stream:\n");
  print_rng(stream);
  printf(" Printing 3 random numbers in [0,1):\n");
  for (i = 0; i < 3; i++) {
    rn = get_rn_dbl(stream);
    printf("%f\n", rn);
  }
  printf(" Printing 3 random integers in [0,2^31):\n");
  for (i = 0; i < 3; i++) {
    irn = get_rn_int(stream);
    printf("%16d\n", irn);
  }
  free_rng(stream);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ecx
  mov    $0x3abcdef8,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <init_rng@plt>
  mov    %rax,%rbx
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <print_rng@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x3,%ebp
  lea    D39(%rip),%r12
L11:
  mov    %rbx,%rdi
  call   <get_rn_dbl@plt>
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L11
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x3,%ebp
  lea    D43(%rip),%r12
L15:
  mov    %rbx,%rdi
  call   <get_rn_int@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L15
  mov    %rbx,%rdi
  call   <free_rng@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D39
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D43
type_guessed: string

tool: D4:  Print information about new stream:

tool: D13:  Printing 3 random numbers in [0,1):

tool: D39: %f


tool: D8:  Printing 3 random integers in [0,2^31):

tool: D43: %16d


assistant: ```c
main() {
  int streamnum, nstreams, *stream;
  double rn;
  int irn;
  int i;
  streamnum = 0;
  nstreams = 1;
  stream = init_rng(streamnum, nstreams, 985456376, 0);
  printf(" Print information about new stream:\n");
  print_rng(stream);
  printf(" Printing 3 random numbers in [0,1):\n");
  for (i = 0; i < 3; i++) {
    rn = get_rn_dbl(stream);
    printf("%f\n", rn);
  }
  printf(" Printing 3 random integers in [0,2^31):\n");
  for (i = 0; i < 3; i++) {
    irn = get_rn_int(stream);
    printf("%16d\n", irn);
  }
  free_rng(stream);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0x3abcdef8,%edx
  mov    $0x1,%esi
  push   %rbp
  xor    %edi,%edi
  lea    D25(%rip),%r12
  push   %rbx
  mov    $0x3,%ebx
  call   <init_rng@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <print_rng@plt>
  lea    D32(%rip),%rdi
  call   <puts@plt>
L3:
  mov    %rbp,%rdi
  call   <get_rn_dbl@plt>
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  lea    D17(%rip),%rdi
  mov    $0x3,%ebx
  lea    D22(%rip),%r12
  call   <puts@plt>
L11:
  mov    %rbp,%rdi
  call   <get_rn_int@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L11
  mov    %rbp,%rdi
  call   <free_rng@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D17
type: string
name: parse_data
arguments: data_tag: D22
type: string

tool: D25: %f


tool: D3:  Print information about new stream:

tool: D32:  Printing 3 random numbers in [0,1):

tool: D17:  Printing 3 random integers in [0,2^31):

tool: D22: %16d


assistant: ```c
main() {
  int streamnum, nstreams, *stream;
  double rn;
  int irn;
  int i;
  streamnum = 0;
  nstreams = 1;
  stream = init_rng(streamnum, nstreams, 985456376, 0);
  printf(" Print information about new stream:\n");
  print_rng(stream);
  printf(" Printing 3 random numbers in [0,1):\n");
  for (i = 0; i < 3; i++) {
    rn = get_rn_dbl(stream);
    printf("%f\n", rn);
  }
  printf(" Printing 3 random integers in [0,2^31):\n");
  for (i = 0; i < 3; i++) {
    irn = get_rn_int(stream);
    printf("%16d\n", irn);
  }
  free_rng(stream);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  mov    $0x3abcdef8,%edx
  mov    $0x1,%esi
  push   %rbp
  xor    %edi,%edi
  lea    D9(%rip),%r12
  push   %rbx
  mov    $0x3,%ebx
  call   <init_rng@plt>
  lea    D19(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <print_rng@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
L10:
  mov    %rbp,%rdi
  call   <get_rn_dbl@plt>
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L10
  lea    D44(%rip),%rdi
  mov    $0x3,%ebx
  lea    D40(%rip),%r12
  call   <puts@plt>
L2:
  mov    %rbp,%rdi
  call   <get_rn_int@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    %rbp,%rdi
  call   <free_rng@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D44
type: string
name: unpack_data
arguments: data_tag: D40
type: string

tool: D9: %f


tool: D19:  Print information about new stream:

tool: D12:  Printing 3 random numbers in [0,1):

tool: D44:  Printing 3 random integers in [0,2^31):

tool: D40: %16d


assistant: ```c
main() {
  int streamnum, nstreams, *stream;
  double rn;
  int irn;
  int i;
  streamnum = 0;
  nstreams = 1;
  stream = init_rng(streamnum, nstreams, 985456376, 0);
  printf(" Print information about new stream:\n");
  print_rng(stream);
  printf(" Printing 3 random numbers in [0,1):\n");
  for (i = 0; i < 3; i++) {
    rn = get_rn_dbl(stream);
    printf("%f\n", rn);
  }
  printf(" Printing 3 random integers in [0,2^31):\n");
  for (i = 0; i < 3; i++) {
    irn = get_rn_int(stream);
    printf("%16d\n", irn);
  }
  free_rng(stream);
}
```
user: What is the c source code of the assembly code below?

```asm
<imprimeInversa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: %f 

assistant: ```c
void imprimeInversa(float dadosImp[], int tamVet) {
  int posicao;
  for (posicao = 0; posicao < tamVet; posicao++) {
    printf("%f ", dadosImp[posicao] / (tamVet / 2));
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imprimeInversa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L0
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movss  %xmm2,0xc(%rsp)
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D4(%rip),%rbp
L11:
  movss  (%rbx),%xmm0
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L11
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: %f 

assistant: ```c
void imprimeInversa(float dadosImp[], int tamVet) {
  int posicao;
  for (posicao = 0; posicao < tamVet; posicao++) {
    printf("%f ", dadosImp[posicao] / (tamVet / 2));
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imprimeInversa>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %esi,%eax
  pxor   %xmm2,%xmm2
  push   %r12
  sar    %eax
  push   %rbp
  lea    D0(%rip),%rbp
  cvtsi2ss %eax,%xmm2
  push   %rbx
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x4(%rdi,%rax,4),%r12
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
  nopl   0x0(%rax)
L1:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  add    $0x10,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L8:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: %f 

assistant: ```c
void imprimeInversa(float dadosImp[], int tamVet) {
  int posicao;
  for (posicao = 0; posicao < tamVet; posicao++) {
    printf("%f ", dadosImp[posicao] / (tamVet / 2));
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imprimeInversa>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    %esi,%eax
  pxor   %xmm2,%xmm2
  push   %r12
  sar    %eax
  push   %rbp
  lea    D3(%rip),%rbp
  cvtsi2ss %eax,%xmm2
  push   %rbx
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x4(%rdi,%rax,4),%r12
  sub    $0x10,%rsp
  movss  %xmm2,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  add    $0x10,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: %f 

assistant: ```c
void imprimeInversa(float dadosImp[], int tamVet) {
  int posicao;
  for (posicao = 0; posicao < tamVet; posicao++) {
    printf("%f ", dadosImp[posicao] / (tamVet / 2));
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<streq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L9
L39:
  movsbq -0x1(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movsbq -0x1(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L3
  mov    $0x0,%eax
  jmp    L10
L3:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %al,-0x1(%rbp)
  jl     L39
  mov    $0x1,%eax
L10:
  leave
  ret
```

assistant: ```c
char streq(char *x, char *y) {
  char i;
  for (i = 0; i < strlen(x); i++)
    if (x[i] != y[i])
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<streq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  jmp    L1
L29:
  add    $0x1,%ebx
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jle    L24
  movsbq %bl,%rax
  movzbl (%r12,%rax,1),%edx
  cmp    %dl,0x0(%rbp,%rax,1)
  je     L29
  mov    $0x0,%eax
  jmp    L3
L24:
  mov    $0x1,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char streq(char *x, char *y) {
  char i;
  for (i = 0; i < strlen(x); i++)
    if (x[i] != y[i])
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<streq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L19:
  movsbq %bl,%rax
  movzbl (%r12,%rax,1),%edx
  cmp    %dl,0x0(%rbp,%rax,1)
  jne    L26
  add    $0x1,%ebx
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L19
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char streq(char *x, char *y) {
  char i;
  for (i = 0; i < strlen(x); i++)
    if (x[i] != y[i])
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<streq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L26:
  movsbq %bl,%rax
  movzbl (%r12,%rax,1),%edx
  cmp    %dl,0x0(%rbp,%rax,1)
  jne    L4
  add    $0x1,%ebx
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %bl,%al
  jg     L26
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char streq(char *x, char *y) {
  char i;
  for (i = 0; i < strlen(x); i++)
    if (x[i] != y[i])
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mymalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  leave
  ret
```

assistant: ```c
void *mymalloc(size_t size, char *file, int line) {
  if (file == file && line == line) {
  }
  return malloc(size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mymalloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *mymalloc(size_t size, char *file, int line) {
  if (file == file && line == line) {
  }
  return malloc(size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mymalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *mymalloc(size_t size, char *file, int line) {
  if (file == file && line == line) {
  }
  return malloc(size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mymalloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *mymalloc(size_t size, char *file, int line) {
  if (file == file && line == line) {
  }
  return malloc(size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<generic_print>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L28
  lea    D86(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L84
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L1
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L4
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L127
  lea    D74(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L87
  lea    D73(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L91
  mov    %rbp,%rsi
  lea    D61(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L28:
  mov    0x0(%rbp),%esi
  lea    D127(%rip),%rdi
  call   <printf@plt>
L91:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L84:
  mov    0x0(%rbp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L1:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L91
L4:
  movsd  0x0(%rbp),%xmm0
  lea    D93(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L91
L127:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  jmp    L91
L87:
  mov    0x0(%rbp),%rsi
  lea    D57(%rip),%rdi
  call   <printf@plt>
  jmp    L91
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D86
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D74
type_guessed: string
name: parse_data
arguments: tag: D73
type_guessed: string
name: parse_data
arguments: tag: D61
type_guessed: string
name: parse_data
arguments: tag: D127
type_guessed: string
name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D93
type_guessed: string
name: parse_data
arguments: tag: D57
type_guessed: string

tool: D15: d

tool: D86: u

tool: D6: f

tool: D19: lf

tool: D17: c

tool: D74: s

tool: D73: p

tool: D61: %p

tool: D127: %d

tool: D21: %u

tool: D24: %f

tool: D93: %lf

tool: D57: %s

assistant: ```c
void generic_print(void *data, char *type) {
  if (strcmp(type, "d") == 0) {
    printf("%d", *(int *)data);
  } else if (strcmp(type, "u") == 0) {
    printf("%u", *(unsigned *)data);
  } else if (strcmp(type, "f") == 0) {
    printf("%f", *(float *)data);
  } else if (strcmp(type, "lf") == 0) {
    printf("%lf", *(double *)data);
  } else if (strcmp(type, "c") == 0) {
    printf("%c", *(char *)data);
  } else if (strcmp(type, "s") == 0) {
    printf("%s", *(char **)data);
  } else if (strcmp(type, "p") == 0) {
    printf("%p", data);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<generic_print>:
  endbr64
  movzbl (%rsi),%eax
  cmp    $0x64,%eax
  jne    L62
  cmpb   $0x0,0x1(%rsi)
  jne    L62
  mov    (%rdi),%esi
  xor    %eax,%eax
  lea    D41(%rip),%rdi
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L62:
  cmp    $0x75,%eax
  je     L68
L106:
  cmp    $0x66,%eax
  jne    L11
  cmpb   $0x0,0x1(%rsi)
  jne    L11
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd (%rdi),%xmm0
  lea    D58(%rip),%rdi
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L68:
  cmpb   $0x0,0x1(%rsi)
  jne    L106
  mov    (%rdi),%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L11:
  cmpb   $0x6c,(%rsi)
  jne    L19
  cmpb   $0x66,0x1(%rsi)
  jne    L19
  cmpb   $0x0,0x2(%rsi)
  jne    L19
  movsd  (%rdi),%xmm0
  mov    $0x1,%eax
  lea    D53(%rip),%rdi
  jmp    1070 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    $0x63,%eax
  je     L85
L97:
  cmp    $0x73,%eax
  jne    L64
  cmpb   $0x0,0x1(%rsi)
  jne    L64
  mov    (%rdi),%rsi
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L85:
  cmpb   $0x0,0x1(%rsi)
  jne    L97
  movsbl (%rdi),%edi
  jmp    1060 <putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L64:
  cmp    $0x70,%eax
  jne    L95
  cmpb   $0x0,0x1(%rsi)
  jne    L95
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L95:
  ret
```

tool_calls: name: read_data
arguments: label: D41
type_infered: string
name: read_data
arguments: label: D58
type_infered: string
name: read_data
arguments: label: D20
type_infered: string
name: read_data
arguments: label: D53
type_infered: string
name: read_data
arguments: label: D49
type_infered: string
name: read_data
arguments: label: D19
type_infered: string

tool: D41: %d

tool: D58: %f

tool: D20: %u

tool: D53: %lf

tool: D49: %s

tool: D19: %p

assistant: ```c
void generic_print(void *data, char *type) {
  if (strcmp(type, "d") == 0) {
    printf("%d", *(int *)data);
  } else if (strcmp(type, "u") == 0) {
    printf("%u", *(unsigned *)data);
  } else if (strcmp(type, "f") == 0) {
    printf("%f", *(float *)data);
  } else if (strcmp(type, "lf") == 0) {
    printf("%lf", *(double *)data);
  } else if (strcmp(type, "c") == 0) {
    printf("%c", *(char *)data);
  } else if (strcmp(type, "s") == 0) {
    printf("%s", *(char **)data);
  } else if (strcmp(type, "p") == 0) {
    printf("%p", data);
  }
}
```