ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<vectorNorm>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  lea    0xc(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L3:
  movss  (%rbx),%xmm0
  mov    $0x2,%edi
  movss  %xmm1,0xc(%rsp)
  add    $0x4,%rbx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rbp,%rbx
  jne    L3
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  jmp    1060 <sqrt@plt>
```

assistant: ```c
float vectorNorm(const float *vector) {
  float sum = 0;
  int i;
  int length = (sizeof(vector) / sizeof((vector)[0])) + 1;
  for (i = 0; i < length; i++) {
    sum += pow(vector[i], 2);
  }
  return sqrt(sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<umlReplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9f,%al
  jne    L165
  mov    -0x8(%rbp),%rax
  movb   $0xe0,(%rax)
  jmp    L191
L165:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xb0,%al
  jne    L124
  mov    -0x8(%rbp),%rax
  movb   $0xf8,(%rax)
  jmp    L191
L124:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xbd,%al
  jne    L159
  mov    -0x8(%rbp),%rax
  movb   $0xab,(%rax)
  jmp    L191
L159:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xb2,%al
  jne    L119
  mov    -0x8(%rbp),%rax
  movb   $0xfd,(%rax)
  jmp    L191
L119:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa4,%al
  jne    L74
  mov    -0x8(%rbp),%rax
  movb   $0x84,(%rax)
  jmp    L191
L74:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xb6,%al
  jne    L79
  mov    -0x8(%rbp),%rax
  movb   $0x94,(%rax)
  jmp    L191
L79:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xbc,%al
  jne    L210
  mov    -0x8(%rbp),%rax
  movb   $0x81,(%rax)
  jmp    L191
L210:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x84,%al
  jne    L66
  mov    -0x8(%rbp),%rax
  movb   $0x8e,(%rax)
  jmp    L191
L66:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x96,%al
  jne    L110
  mov    -0x8(%rbp),%rax
  movb   $0x99,(%rax)
  jmp    L191
L110:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9c,%al
  jne    L90
  mov    -0x8(%rbp),%rax
  movb   $0x9a,(%rax)
  jmp    L191
L90:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xab,%al
  jne    L205
  mov    -0x8(%rbp),%rax
  movb   $0xae,(%rax)
  jmp    L191
L205:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xbb,%al
  jne    L191
  mov    -0x8(%rbp),%rax
  movb   $0xaf,(%rax)
L191:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void umlReplace(char *inChar) {
  if (*inChar == -97) {
    *inChar = 224;
  } else if (*inChar == -80) {
    *inChar = 248;
  } else if (*inChar == -67) {
    *inChar = 171;
  } else if (*inChar == -78) {
    *inChar = 253;
  } else if (*inChar == -92) {
    *inChar = 132;
  } else if (*inChar == -74) {
    *inChar = 148;
  } else if (*inChar == -68) {
    *inChar = 129;
  } else if (*inChar == -124) {
    *inChar = 142;
  } else if (*inChar == -106) {
    *inChar = 153;
  } else if (*inChar == -100) {
    *inChar = 154;
  } else if (*inChar == -85) {
    *inChar = 0xAE;
  } else if (*inChar == -69) {
    *inChar = 0xAF;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<umlReplace>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9f,%al
  je     L9
  add    $0x7c,%eax
  cmp    $0x39,%al
  ja     L14
  movzbl %al,%eax
  lea    D8(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L9:
  movb   $0xe0,(%rdi)
  ret
  movb   $0xf8,(%rdi)
  ret
  movb   $0xab,(%rdi)
  ret
  movb   $0xfd,(%rdi)
  ret
  movb   $0x84,(%rdi)
  ret
  movb   $0x94,(%rdi)
  ret
  movb   $0x81,(%rdi)
  ret
  movb   $0x8e,(%rdi)
  ret
  movb   $0x99,(%rdi)
  ret
  movb   $0x9a,(%rdi)
  ret
  movb   $0xae,(%rdi)
  ret
  movb   $0xaf,(%rdi)
L14:
  ret
```

assistant: ```c
void umlReplace(char *inChar) {
  if (*inChar == -97) {
    *inChar = 224;
  } else if (*inChar == -80) {
    *inChar = 248;
  } else if (*inChar == -67) {
    *inChar = 171;
  } else if (*inChar == -78) {
    *inChar = 253;
  } else if (*inChar == -92) {
    *inChar = 132;
  } else if (*inChar == -74) {
    *inChar = 148;
  } else if (*inChar == -68) {
    *inChar = 129;
  } else if (*inChar == -124) {
    *inChar = 142;
  } else if (*inChar == -106) {
    *inChar = 153;
  } else if (*inChar == -100) {
    *inChar = 154;
  } else if (*inChar == -85) {
    *inChar = 0xAE;
  } else if (*inChar == -69) {
    *inChar = 0xAF;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<umlReplace>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9f,%al
  je     L13
  add    $0x7c,%eax
  cmp    $0x39,%al
  ja     L15
  lea    D5(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
  movb   $0xaf,(%rdi)
L15:
  ret
  nopl   0x0(%rax)
L13:
  movb   $0xe0,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xab,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x81,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x94,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xfd,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xf8,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xae,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x84,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x9a,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x99,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x8e,(%rdi)
  ret
```

assistant: ```c
void umlReplace(char *inChar) {
  if (*inChar == -97) {
    *inChar = 224;
  } else if (*inChar == -80) {
    *inChar = 248;
  } else if (*inChar == -67) {
    *inChar = 171;
  } else if (*inChar == -78) {
    *inChar = 253;
  } else if (*inChar == -92) {
    *inChar = 132;
  } else if (*inChar == -74) {
    *inChar = 148;
  } else if (*inChar == -68) {
    *inChar = 129;
  } else if (*inChar == -124) {
    *inChar = 142;
  } else if (*inChar == -106) {
    *inChar = 153;
  } else if (*inChar == -100) {
    *inChar = 154;
  } else if (*inChar == -85) {
    *inChar = 0xAE;
  } else if (*inChar == -69) {
    *inChar = 0xAF;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<umlReplace>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9f,%al
  je     L18
  add    $0x7c,%eax
  cmp    $0x39,%al
  ja     L11
  lea    D5(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
  movb   $0xaf,(%rdi)
L11:
  ret
  nopl   0x0(%rax)
L18:
  movb   $0xe0,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xab,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x81,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x94,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xfd,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xf8,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0xae,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x84,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x9a,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x99,(%rdi)
  ret
  nopl   0x0(%rax)
  movb   $0x8e,(%rdi)
  ret
```

assistant: ```c
void umlReplace(char *inChar) {
  if (*inChar == -97) {
    *inChar = 224;
  } else if (*inChar == -80) {
    *inChar = 248;
  } else if (*inChar == -67) {
    *inChar = 171;
  } else if (*inChar == -78) {
    *inChar = 253;
  } else if (*inChar == -92) {
    *inChar = 132;
  } else if (*inChar == -74) {
    *inChar = 148;
  } else if (*inChar == -68) {
    *inChar = 129;
  } else if (*inChar == -124) {
    *inChar = 142;
  } else if (*inChar == -106) {
    *inChar = 153;
  } else if (*inChar == -100) {
    *inChar = 154;
  } else if (*inChar == -85) {
    *inChar = 0xAE;
  } else if (*inChar == -69) {
    *inChar = 0xAF;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<skipjack_g_inv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  shll   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x3(%rax),%ecx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %eax,%edx
  lea    -0x4(%rbp),%rax
  mov    (%rax),%ecx
  lea    -0x4(%rbp),%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  lea    -0x4(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %eax,%edx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %eax,%edx
  lea    -0x4(%rbp),%rax
  mov    (%rax),%ecx
  lea    -0x4(%rbp),%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  lea    -0x4(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %eax,%edx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  lea    -0x4(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint16_t skipjack_g_inv(uint16_t g, uint8_t k, uint8_t *key) {
  k *= 4;
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 3, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 2, key);
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 1, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 0, key);
  return g;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipjack_g_inv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rdx,%r12
  lea    0x0(,%rsi,4),%ebp
  mov    %edi,0xc(%rsp)
  mov    0x10(%rsp),%r13d
  lea    0x3(%rbp),%esi
  mov    %r13d,%edi
  call   <skipjack_sub_g@plt>
  xor    %eax,%ebx
  lea    0x2(%rbp),%esi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  lea    0x1(%rbp),%esi
  mov    %r13d,%edi
  xor    %eax,%edi
  mov    %r12,%rdx
  call   <skipjack_sub_g@plt>
  xor    %eax,%ebx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint16_t skipjack_g_inv(uint16_t g, uint8_t k, uint8_t *key) {
  k *= 4;
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 3, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 2, key);
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 1, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 0, key);
  return g;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skipjack_g_inv>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  lea    0x0(,%rsi,4),%ebp
  push   %rbx
  lea    0x3(%rbp),%esi
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x10(%rsp),%r12d
  mov    %edi,0xc(%rsp)
  mov    %r12d,%edi
  call   <skipjack_sub_g@plt>
  lea    0x2(%rbp),%esi
  mov    %r13,%rdx
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  mov    %r12d,%edi
  lea    0x1(%rbp),%esi
  mov    %r13,%rdx
  xor    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %r13,%rdx
  mov    %ebp,%esi
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  add    $0x18,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint16_t skipjack_g_inv(uint16_t g, uint8_t k, uint8_t *key) {
  k *= 4;
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 3, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 2, key);
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 1, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 0, key);
  return g;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skipjack_g_inv>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  lea    0x0(,%rsi,4),%ebp
  push   %rbx
  lea    0x3(%rbp),%esi
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    0x10(%rsp),%r12d
  mov    %edi,0xc(%rsp)
  mov    %r12d,%edi
  call   <skipjack_sub_g@plt>
  lea    0x2(%rbp),%esi
  mov    %r13,%rdx
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  mov    %r12d,%edi
  lea    0x1(%rbp),%esi
  mov    %r13,%rdx
  xor    %eax,%edi
  call   <skipjack_sub_g@plt>
  mov    %r13,%rdx
  mov    %ebp,%esi
  xor    %eax,%ebx
  mov    %ebx,%edi
  call   <skipjack_sub_g@plt>
  add    $0x18,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint16_t skipjack_g_inv(uint16_t g, uint8_t k, uint8_t *key) {
  k *= 4;
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 3, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 2, key);
  (((uint8_t *)&g)[0]) ^= skipjack_sub_g((((uint8_t *)&g)[1]), k + 1, key);
  (((uint8_t *)&g)[1]) ^= skipjack_sub_g((((uint8_t *)&g)[0]), k + 0, key);
  return g;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swab2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swab2(char *b, int n) {
  char *e, p;
  for (e = b + n; b < e; b++) {
    p = *b;
    *b = b[1];
    *++b = p;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swab2>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L9
L11:
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x1(%rdi)
  add    $0x2,%rdi
  cmp    %rdi,%rsi
  ja     L11
L9:
  ret
```

assistant: ```c
void swab2(char *b, int n) {
  char *e, p;
  for (e = b + n; b < e; b++) {
    p = *b;
    *b = b[1];
    *++b = p;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swab2>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L1
  nop
L14:
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  add    $0x2,%rdi
  mov    %dl,-0x2(%rdi)
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  ja     L14
L1:
  ret
```

assistant: ```c
void swab2(char *b, int n) {
  char *e, p;
  for (e = b + n; b < e; b++) {
    p = *b;
    *b = b[1];
    *++b = p;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swab2>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%rdx
  lea    (%rdi,%rsi,1),%rdi
  cmp    %rdi,%rdx
  jae    L70
  sub    $0x1,%rsi
  mov    %rdx,%rax
  mov    %rsi,%r8
  shr    %r8
  add    $0x1,%r8
  cmp    $0x1d,%rsi
  jbe    L174
  mov    %r8,%rcx
  movdqa D6(%rip),%xmm3
  shr    $0x4,%rcx
  shl    $0x5,%rcx
  add    %rdx,%rcx
  nopl   0x0(%rax)
L168:
  movdqu (%rax),%xmm1
  movdqu 0x10(%rax),%xmm0
  add    $0x20,%rax
  movdqu -0x10(%rax),%xmm2
  pand   %xmm3,%xmm0
  pand   %xmm3,%xmm1
  packuswb %xmm0,%xmm1
  movdqu -0x20(%rax),%xmm0
  psrlw  $0x8,%xmm2
  psrlw  $0x8,%xmm0
  packuswb %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  punpckhbw %xmm1,%xmm0
  punpcklbw %xmm1,%xmm2
  movups %xmm0,-0x10(%rax)
  movups %xmm2,-0x20(%rax)
  cmp    %rcx,%rax
  jne    L168
  mov    %r8,%rax
  and    $0xfffffffffffffff0,%rax
  lea    (%rdx,%rax,2),%rdx
  cmp    %rax,%r8
  je     L70
L174:
  lea    0x2(%rdx),%rax
  rolw   $0x8,(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x4(%rdx),%rax
  rolw   $0x8,0x2(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x6(%rdx),%rax
  rolw   $0x8,0x4(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x8(%rdx),%rax
  rolw   $0x8,0x6(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0xa(%rdx),%rax
  rolw   $0x8,0x8(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0xc(%rdx),%rax
  rolw   $0x8,0xa(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0xe(%rdx),%rax
  rolw   $0x8,0xc(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x10(%rdx),%rax
  rolw   $0x8,0xe(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x12(%rdx),%rax
  rolw   $0x8,0x10(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x14(%rdx),%rax
  rolw   $0x8,0x12(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x16(%rdx),%rax
  rolw   $0x8,0x14(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x18(%rdx),%rax
  rolw   $0x8,0x16(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x1a(%rdx),%rax
  rolw   $0x8,0x18(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  lea    0x1c(%rdx),%rax
  rolw   $0x8,0x1a(%rdx)
  cmp    %rax,%rdi
  jbe    L70
  rolw   $0x8,0x1c(%rdx)
L70:
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: byte[16]

tool: {"D6": [0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00]}

assistant: ```c
void swab2(char *b, int n) {
  char *e, p;
  for (e = b + n; b < e; b++) {
    p = *b;
    *b = b[1];
    *++b = p;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <practice@plt>
L23:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  je     L8
  jmp    L32
L25:
  mov    $0x0,%eax
  call   <firstClassProb@plt>
  jmp    L62
L32:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L62
L8:
  nop
L62:
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jne    L23
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D20
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D11: 
Enter Choice: 

tool: D20: %d

tool: D18: 
Error in Input

assistant: ```c
void main() {
  int choice;
  practice();
  do {
    printf("\nEnter Choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      firstClassProb();
      break;
    case 2:
      break;
    default:
      printf("\nError in Input");
      break;
    }
  } while (choice != 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <practice@plt>
  lea    D19(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D24(%rip),%rbx
  lea    D4(%rip),%r13
  jmp    L25
L3:
  mov    $0x0,%eax
  call   <firstClassProb@plt>
L8:
  cmpl   $0x2,0x4(%rsp)
  je     L45
L25:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L3
  cmp    $0x2,%eax
  je     L45
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L8
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D19: 
Enter Choice: 

tool: D24: %d

tool: D4: 
Error in Input

assistant: ```c
void main() {
  int choice;
  practice();
  do {
    printf("\nEnter Choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      firstClassProb();
      break;
    case 2:
      break;
    default:
      printf("\nError in Input");
      break;
    }
  } while (choice != 2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <practice@plt>
  nopl   (%rax)
L24:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L8
  cmp    $0x2,%eax
  jne    L38
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <firstClassProb@plt>
  mov    0x4(%rsp),%eax
L11:
  cmp    $0x2,%eax
  jne    L24
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L11
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string

tool: D19: 
Error in Input

tool: D2: 
Enter Choice: 

tool: D9: %d

assistant: ```c
void main() {
  int choice;
  practice();
  do {
    printf("\nEnter Choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      firstClassProb();
      break;
    case 2:
      break;
    default:
      printf("\nError in Input");
      break;
    }
  } while (choice != 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <practice@plt>
  nopl   (%rax)
L59:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L8
  cmp    $0x2,%eax
  jne    L44
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <firstClassProb@plt>
  mov    0x4(%rsp),%eax
L39:
  cmp    $0x2,%eax
  jne    L59
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L39
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D28
datatype: string

tool: D13: 
Error in Input

tool: D19: 
Enter Choice: 

tool: D28: %d

assistant: ```c
void main() {
  int choice;
  practice();
  do {
    printf("\nEnter Choice: ");
    scanf("%d", &choice);
    switch (choice) {
    case 1:
      firstClassProb();
      break;
    case 2:
      break;
    default:
      printf("\nError in Input");
      break;
    }
  } while (choice != 2);
}
```