ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aui2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  je     L9
  shl    $0x2,%ebp
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L0
L9:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int **aui2d(unsigned int X, unsigned int Y) {
  unsigned int i;
  unsigned int **A = (unsigned int **)malloc(X * sizeof(unsigned int *));
  for (i = 0; i < X; i++)
    A[i] = (unsigned int *)malloc(Y * sizeof(unsigned int));
  return A;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<malloc_double_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <message_exit@plt>
L6:
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L8:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <message_exit@plt>
L2:
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_infered: string

tool: D12: double

assistant: ```c
double **malloc_double_image(int xres, int yres) {
  double **image;
  int j;
  image = (double **)malloc(sizeof(double *) * yres);
  if (image == NULL)
    message_exit("double");
  for (j = 0; j < yres; j++) {
    image[j] = (double *)malloc(sizeof(double) * xres);
    if (image[j] == NULL)
      message_exit("double");
  }
  return (image);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<malloc_double_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L55
L31:
  test   %r12d,%r12d
  jle    L69
  shl    $0x3,%ebp
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x0(%r13,%r12,8),%r12
  lea    D9(%rip),%r14
  jmp    L25
L55:
  lea    D9(%rip),%rdi
  call   <message_exit@plt>
  jmp    L31
L59:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L69
L25:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L59
  mov    %r14,%rdi
  call   <message_exit@plt>
  jmp    L59
L69:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: double

assistant: ```c
double **malloc_double_image(int xres, int yres) {
  double **image;
  int j;
  image = (double **)malloc(sizeof(double *) * yres);
  if (image == NULL)
    message_exit("double");
  for (j = 0; j < yres; j++) {
    image[j] = (double *)malloc(sizeof(double) * xres);
    if (image[j] == NULL)
      message_exit("double");
  }
  return (image);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_double_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L48
L21:
  test   %ebp,%ebp
  jle    L55
  shl    $0x3,%ebx
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D17(%rip),%r13
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%r14
  cmp    %rbp,%r14
  je     L55
L1:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L7
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <message_exit@plt>
  cmp    %rbp,%r14
  jne    L1
L55:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L48:
  lea    D17(%rip),%rdi
  call   <message_exit@plt>
  jmp    L21
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string

tool: D17: double

assistant: ```c
double **malloc_double_image(int xres, int yres) {
  double **image;
  int j;
  image = (double **)malloc(sizeof(double *) * yres);
  if (image == NULL)
    message_exit("double");
  for (j = 0; j < yres; j++) {
    image[j] = (double *)malloc(sizeof(double) * xres);
    if (image[j] == NULL)
      message_exit("double");
  }
  return (image);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<malloc_double_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L28
L42:
  test   %ebp,%ebp
  jle    L24
  shl    $0x3,%ebx
  mov    %r12,%r14
  lea    (%r12,%rbp,8),%rbp
  lea    D10(%rip),%r13
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x8,%r14
  cmp    %rbp,%r14
  je     L24
L18:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L10
  mov    %r13,%rdi
  add    $0x8,%r14
  call   <message_exit@plt>
  cmp    %rbp,%r14
  jne    L18
L24:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L28:
  lea    D10(%rip),%rdi
  call   <message_exit@plt>
  jmp    L42
```

tool_calls: name: unpack_data
arguments: label: D10
type: string

tool: D10: double

assistant: ```c
double **malloc_double_image(int xres, int yres) {
  double **image;
  int j;
  image = (double **)malloc(sizeof(double *) * yres);
  if (image == NULL)
    message_exit("double");
  for (j = 0; j < yres; j++) {
    image[j] = (double *)malloc(sizeof(double) * xres);
    if (image[j] == NULL)
      message_exit("double");
  }
  return (image);
}
```
user: Translate the below assembly code into C programming language:

```asm
<json_calc_escaped_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L23
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <escape_as@plt>
  test   %rax,%rax
  je     L13
  addq   $0x1,-0x10(%rbp)
L13:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L4
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t json_calc_escaped_len(const char *str, size_t len) {
  size_t escaped_len = len;
  size_t pos;
  for (pos = 0; pos < len; pos++) {
    if (escape_as(str[pos])) {
      escaped_len++;
    }
  }
  return escaped_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<json_calc_escaped_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L6
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%r12
L1:
  movsbl (%rbx),%edi
  call   <escape_as@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L1
L6:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t json_calc_escaped_len(const char *str, size_t len) {
  size_t escaped_len = len;
  size_t pos;
  for (pos = 0; pos < len; pos++) {
    if (escape_as(str[pos])) {
      escaped_len++;
    }
  }
  return escaped_len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<json_calc_escaped_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L14
  mov    %rsi,%r12
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl (%rbx),%edi
  call   <escape_as@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t json_calc_escaped_len(const char *str, size_t len) {
  size_t escaped_len = len;
  size_t pos;
  for (pos = 0; pos < len; pos++) {
    if (escape_as(str[pos])) {
      escaped_len++;
    }
  }
  return escaped_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<json_calc_escaped_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L4
  mov    %rsi,%r12
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  call   <escape_as@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t json_calc_escaped_len(const char *str, size_t len) {
  size_t escaped_len = len;
  size_t pos;
  for (pos = 0; pos < len; pos++) {
    if (escape_as(str[pos])) {
      escaped_len++;
    }
  }
  return escaped_len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D69(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D52(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D79(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  mov    %rax,-0x8(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printlist@plt>
  mov    -0x8(%rbp),%rax
  lea    D52(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <searchlist@plt>
  mov    -0x8(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <searchlist@plt>
  mov    -0x8(%rbp),%rax
  lea    D52(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  mov    %rax,-0x8(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printlist@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <freeList@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D69
type_guessed: string
name: extract_symbolic_data
arguments: label: D52
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D79
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D69: Word One

tool: D52: Word Two

tool: D29: Word Three

tool: D79: Word Four

tool: D16: --- Initial list ---


tool: D39: Dumplings

tool: D7: 

--- Updated list ---


assistant: ```c
int main() {
  struct node *start = NULL;
  start = updateList(start, "Word One");
  start = updateList(start, "Word Two");
  start = updateList(start, "Word Three");
  start = updateList(start, "Word Four");
  printf("--- Initial list ---\n");
  printlist(start);
  searchlist(start, "Word Two");
  searchlist(start, "Dumplings");
  start = updateList(start, "Word Two");
  printf("\n\n--- Updated list ---\n");
  printlist(start);
  freeList(start);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D46(%rip),%rsi
  mov    $0x0,%edi
  call   <updateList@plt>
  mov    %rax,%rdi
  lea    D6(%rip),%rbp
  mov    %rbp,%rsi
  call   <updateList@plt>
  mov    %rax,%rdi
  lea    D13(%rip),%rsi
  call   <updateList@plt>
  mov    %rax,%rdi
  lea    D12(%rip),%rsi
  call   <updateList@plt>
  mov    %rax,%rbx
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printlist@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <searchlist@plt>
  lea    D43(%rip),%rsi
  mov    %rbx,%rdi
  call   <searchlist@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <updateList@plt>
  mov    %rax,%rbx
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printlist@plt>
  mov    %rbx,%rdi
  call   <freeList@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D46
type: string
name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D43
type: string
name: retrieve_data
arguments: label: D30
type: string

tool: D46: Word One

tool: D6: Word Two

tool: D13: Word Three

tool: D12: Word Four

tool: D21: --- Initial list ---


tool: D43: Dumplings

tool: D30: 

--- Updated list ---


assistant: ```c
int main() {
  struct node *start = NULL;
  start = updateList(start, "Word One");
  start = updateList(start, "Word Two");
  start = updateList(start, "Word Three");
  start = updateList(start, "Word Four");
  printf("--- Initial list ---\n");
  printlist(start);
  searchlist(start, "Word Two");
  searchlist(start, "Dumplings");
  start = updateList(start, "Word Two");
  printf("\n\n--- Updated list ---\n");
  printlist(start);
  freeList(start);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D37(%rip),%rsi
  xor    %edi,%edi
  lea    D18(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <updateList@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D36(%rip),%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D32(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printlist@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <searchlist@plt>
  mov    %rbp,%rdi
  lea    D46(%rip),%rsi
  call   <searchlist@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <updateList@plt>
  lea    D63(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printlist@plt>
  mov    %rbp,%rdi
  call   <freeList@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D37
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D36
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string
name: unpack_data
arguments: data_tag: D46
type_guessed: string
name: unpack_data
arguments: data_tag: D63
type_guessed: string

tool: D37: Word One

tool: D18: Word Two

tool: D36: Word Three

tool: D9: Word Four

tool: D32: --- Initial list ---


tool: D46: Dumplings

tool: D63: 

--- Updated list ---


assistant: ```c
int main() {
  struct node *start = NULL;
  start = updateList(start, "Word One");
  start = updateList(start, "Word Two");
  start = updateList(start, "Word Three");
  start = updateList(start, "Word Four");
  printf("--- Initial list ---\n");
  printlist(start);
  searchlist(start, "Word Two");
  searchlist(start, "Dumplings");
  start = updateList(start, "Word Two");
  printf("\n\n--- Updated list ---\n");
  printlist(start);
  freeList(start);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D57(%rip),%rsi
  xor    %edi,%edi
  lea    D51(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <updateList@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D39(%rip),%rsi
  mov    %rax,%rdi
  call   <updateList@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printlist@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <searchlist@plt>
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  call   <searchlist@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <updateList@plt>
  lea    D63(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printlist@plt>
  mov    %rbp,%rdi
  call   <freeList@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D57
type: string
name: parse_data
arguments: tag: D51
type: string
name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D39
type: string
name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D63
type: string

tool: D57: Word One

tool: D51: Word Two

tool: D19: Word Three

tool: D39: Word Four

tool: D5: --- Initial list ---


tool: D12: Dumplings

tool: D63: 

--- Updated list ---


assistant: ```c
int main() {
  struct node *start = NULL;
  start = updateList(start, "Word One");
  start = updateList(start, "Word Two");
  start = updateList(start, "Word Three");
  start = updateList(start, "Word Four");
  printf("--- Initial list ---\n");
  printlist(start);
  searchlist(start, "Word Two");
  searchlist(start, "Dumplings");
  start = updateList(start, "Word Two");
  printf("\n\n--- Updated list ---\n");
  printlist(start);
  freeList(start);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cli
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L1:
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: D7: Kernel panic! Aborting...

assistant: ```c
void abort(void) {
  asm("cli");
  printf("Kernel panic! Aborting...\n");
  while (1) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  cli
  lea    D8(%rip),%rdi
  call   <puts@plt>
L7:
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: Kernel panic! Aborting...

assistant: ```c
void abort(void) {
  asm("cli");
  printf("Kernel panic! Aborting...\n");
  while (1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  push   %rax
  cli
  lea    D3(%rip),%rdi
  call   <puts@plt>
L7:
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: Kernel panic! Aborting...

assistant: ```c
void abort(void) {
  asm("cli");
  printf("Kernel panic! Aborting...\n");
  while (1) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  push   %rax
  cli
  lea    D3(%rip),%rdi
  call   <puts@plt>
L2:
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: Kernel panic! Aborting...

assistant: ```c
void abort(void) {
  asm("cli");
  printf("Kernel panic! Aborting...\n");
  while (1) {
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<percentile_value>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  fnstcw 0x1e(%rsp)
  movzwl 0x1e(%rsp),%eax
  and    $0xf3,%ah
  or     $0x4,%ah
  mov    %ax,0x1a(%rsp)
  fldt   0x40(%rsp)
  fldcw  0x1a(%rsp)
  frndint
  fldcw  0x1e(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  flds   0xea8(%rip)        # 2000 <_fini+0xd70>
  fxch   %st(1)
  fcomi  %st(1),%st
  fstp   %st(1)
  jae    L93
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldcw  0x1c(%rsp)
  fistpll 0x10(%rsp)
  fldcw  0x1e(%rsp)
  mov    0x10(%rsp),%r12
L51:
  push   0x48(%rsp)
  push   0x48(%rsp)
  call   <ceill@plt>
  add    $0x10,%rsp
  cmp    %rbp,%rax
  jae    L23
  mov    (%rbx,%r12,8),%rdx
  mov    (%rbx,%rax,8),%rax
  test   %rax,%rax
  js     L57
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
L31:
  test   %rdx,%rdx
  js     L28
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
L25:
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rsp)
  fldt   (%rsp)
  fldt   0x40(%rsp)
  fsubp  %st,%st(1)
  fmull  0x10(%rsp)
  mov    %rdx,(%rsp)
  fildll (%rsp)
  test   %rdx,%rdx
  js     L59
L79:
  faddp  %st,%st(1)
L90:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L93:
  fstp   %st(0)
  fnstcw 0x1e(%rsp)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldt   (%rsp)
  fsubs  0xdea(%rip)        # 2000 <_fini+0xd70>
  fldcw  0x1c(%rsp)
  fistpll 0x10(%rsp)
  fldcw  0x1e(%rsp)
  mov    0x10(%rsp),%r12
  btc    $0x3f,%r12
  jmp    L51
L23:
  fildll (%rbx,%r12,8)
  cmpq   $0x0,(%rbx,%r12,8)
  jns    L90
  fadds  0xdc2(%rip)        # 2004 <_fini+0xd74>
  jmp    L90
L57:
  mov    %rax,%rcx
  shr    %rcx
  and    $0x1,%eax
  or     %rax,%rcx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rcx,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L31
L28:
  mov    %rdx,%rax
  shr    %rax
  mov    %rdx,%rcx
  and    $0x1,%ecx
  or     %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L25
L59:
  fadds  0xd7b(%rip)        # 2004 <_fini+0xd74>
  jmp    L79
```

assistant: ```c
long double percentile_value(long long unsigned *samples, const long double index, const long long unsigned total_number) {
  long long unsigned prev, next;
  long double value;
  prev = (long long unsigned int)floorl(index);
  next = (long long unsigned int)ceill(index);
  if (next >= total_number)
    return (long double)samples[prev];
  value = (long double)samples[prev] + (index - floorl(index)) * ((double)samples[next] - samples[prev]);
  return value;
}
```