ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    $0x10,%ebx
  jmp    L15
L13:
  movzbl %bl,%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl %bl,%ecx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%ecx
  movzbl %bl,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl %bl,%esi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzbl %bl,%eax
  add    $0x10,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl %bl,%edx
  add    $0x10,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L15:
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  test   %al,%al
  jne    L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--) {
    buf[i] ^= (cpk[i] = key[i]);
    cpk[16 + i] = key[16 + i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    $0xf,%eax
L4:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  xor    %cl,(%rdi,%rax,1)
  movzbl 0x10(%rsi,%rax,1),%ecx
  mov    %cl,0x10(%rdx,%rax,1)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L4
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--) {
    buf[i] ^= (cpk[i] = key[i]);
    cpk[16 + i] = key[16 + i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    $0xf,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  xor    %cl,(%rdi,%rax,1)
  movzbl 0x10(%rsi,%rax,1),%ecx
  mov    %cl,0x10(%rdx,%rax,1)
  sub    $0x1,%rax
  jae    L5
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--) {
    buf[i] ^= (cpk[i] = key[i]);
    cpk[16 + i] = key[16 + i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<aes_addRoundKey_cpy>:
  endbr64
  mov    %rdx,%rax
  movzbl 0xf(%rsi),%edx
  mov    %dl,0xf(%rax)
  xor    %dl,0xf(%rdi)
  movzbl 0x1f(%rsi),%edx
  mov    %dl,0x1f(%rax)
  movzbl 0xe(%rsi),%edx
  mov    %dl,0xe(%rax)
  xor    %dl,0xe(%rdi)
  movzbl 0x1e(%rsi),%edx
  mov    %dl,0x1e(%rax)
  movzbl 0xd(%rsi),%edx
  mov    %dl,0xd(%rax)
  xor    %dl,0xd(%rdi)
  movzbl 0x1d(%rsi),%edx
  mov    %dl,0x1d(%rax)
  movzbl 0xc(%rsi),%edx
  mov    %dl,0xc(%rax)
  xor    %dl,0xc(%rdi)
  movzbl 0x1c(%rsi),%edx
  mov    %dl,0x1c(%rax)
  movzbl 0xb(%rsi),%edx
  mov    %dl,0xb(%rax)
  xor    %dl,0xb(%rdi)
  movzbl 0x1b(%rsi),%edx
  mov    %dl,0x1b(%rax)
  movzbl 0xa(%rsi),%edx
  mov    %dl,0xa(%rax)
  xor    %dl,0xa(%rdi)
  movzbl 0x1a(%rsi),%edx
  mov    %dl,0x1a(%rax)
  movzbl 0x9(%rsi),%edx
  mov    %dl,0x9(%rax)
  xor    %dl,0x9(%rdi)
  movzbl 0x19(%rsi),%edx
  mov    %dl,0x19(%rax)
  movzbl 0x8(%rsi),%edx
  mov    %dl,0x8(%rax)
  xor    %dl,0x8(%rdi)
  movzbl 0x18(%rsi),%edx
  mov    %dl,0x18(%rax)
  movzbl 0x7(%rsi),%edx
  mov    %dl,0x7(%rax)
  xor    %dl,0x7(%rdi)
  movzbl 0x17(%rsi),%edx
  mov    %dl,0x17(%rax)
  movzbl 0x6(%rsi),%edx
  mov    %dl,0x6(%rax)
  xor    %dl,0x6(%rdi)
  movzbl 0x16(%rsi),%edx
  mov    %dl,0x16(%rax)
  movzbl 0x5(%rsi),%edx
  mov    %dl,0x5(%rax)
  xor    %dl,0x5(%rdi)
  movzbl 0x15(%rsi),%edx
  mov    %dl,0x15(%rax)
  movzbl 0x4(%rsi),%edx
  mov    %dl,0x4(%rax)
  xor    %dl,0x4(%rdi)
  movzbl 0x14(%rsi),%edx
  mov    %dl,0x14(%rax)
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x3(%rax)
  xor    %dl,0x3(%rdi)
  movzbl 0x13(%rsi),%edx
  mov    %dl,0x13(%rax)
  movzbl 0x2(%rsi),%edx
  mov    %dl,0x2(%rax)
  xor    %dl,0x2(%rdi)
  movzbl 0x12(%rsi),%edx
  mov    %dl,0x12(%rax)
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  xor    %dl,0x1(%rdi)
  movzbl 0x11(%rsi),%edx
  mov    %dl,0x11(%rax)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  xor    %dl,(%rdi)
  movzbl 0x10(%rsi),%edx
  mov    %dl,0x10(%rax)
  ret
```

assistant: ```c
void aes_addRoundKey_cpy(unsigned char *buf, unsigned char *key, unsigned char *cpk) {
  register unsigned char i = 16;
  while (i--) {
    buf[i] ^= (cpk[i] = key[i]);
    cpk[16 + i] = key[16 + i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_gtd7@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_gtd7();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_gtd7@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_gtd7();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_gtd7@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_gtd7();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_gtd7@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_gtd7();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L11
L4:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ebx
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movsbl %al,%eax
  imul   %ebx,%eax
  add    %eax,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
L11:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L4
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int bin(char a[]) {
  int len = strlen(a);
  int i, sum = 0;
  for (i = len - 1; i >= 0; i--) {
    sum += (a[i] - '0') * pow(2, len - i - 1);
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L1
  movslq %ebx,%rbx
  mov    $0x0,%ebp
  lea    -0x1(%rax),%r12d
L4:
  movsbl 0x0(%r13,%rbx,1),%r14d
  sub    $0x30,%r14d
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movsbl %al,%eax
  imul   %r14d,%eax
  add    %eax,%ebp
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L4
L19:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    $0x0,%ebp
  jmp    L19
```

assistant: ```c
int bin(char a[]) {
  int len = strlen(a);
  int i, sum = 0;
  for (i = len - 1; i >= 0; i--) {
    sum += (a[i] - '0') * pow(2, len - i - 1);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L13
  mov    %eax,%ebx
  movslq %eax,%r14
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L6:
  mov    %ebx,%esi
  movsbl 0x0(%rbp,%r14,1),%r13d
  mov    $0x2,%edi
  sub    %r14d,%esi
  sub    $0x1,%r14
  call   <pow@plt>
  sub    $0x30,%r13d
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
  test   %r14d,%r14d
  jns    L6
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin(char a[]) {
  int len = strlen(a);
  int i, sum = 0;
  for (i = len - 1; i >= 0; i--) {
    sum += (a[i] - '0') * pow(2, len - i - 1);
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L13
  mov    %eax,%ebx
  movslq %eax,%r14
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L0:
  mov    %ebx,%esi
  movsbl 0x0(%rbp,%r14,1),%r13d
  mov    $0x2,%edi
  sub    %r14d,%esi
  sub    $0x1,%r14
  call   <pow@plt>
  sub    $0x30,%r13d
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
  test   %r14d,%r14d
  jns    L0
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin(char a[]) {
  int len = strlen(a);
  int i, sum = 0;
  for (i = len - 1; i >= 0; i--) {
    sum += (a[i] - '0') * pow(2, len - i - 1);
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<debug_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void debug_p(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<debug_p>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void debug_p(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<debug_p>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug_p(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<debug_p>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void debug_p(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<finalize_flash_access>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <deregister_chip_restore@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unmap_flash@plt>
  nop
  leave
  ret
```

assistant: ```c
void finalize_flash_access(struct flashrom_flashctx *const flash) {
  deregister_chip_restore(flash);
  unmap_flash(flash);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<finalize_flash_access>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <deregister_chip_restore@plt>
  mov    %rbx,%rdi
  call   <unmap_flash@plt>
  pop    %rbx
  ret
```

assistant: ```c
void finalize_flash_access(struct flashrom_flashctx *const flash) {
  deregister_chip_restore(flash);
  unmap_flash(flash);
}
```
user: What is the c source code of the assembly code below:

```asm
<finalize_flash_access>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <deregister_chip_restore@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <unmap_flash@plt>
```

assistant: ```c
void finalize_flash_access(struct flashrom_flashctx *const flash) {
  deregister_chip_restore(flash);
  unmap_flash(flash);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<finalize_flash_access>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <deregister_chip_restore@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <unmap_flash@plt>
```

assistant: ```c
void finalize_flash_access(struct flashrom_flashctx *const flash) {
  deregister_chip_restore(flash);
  unmap_flash(flash);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ntoh64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <htonl@plt>
  cmp    $0x1,%rax
  jne    L28
  mov    -0x34(%rbp),%eax
  jmp    L23
L28:
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ntohl@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ntohl@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
uint64_t ntoh64(uint64_t val) {
  union {
    uint64_t ll;
    uint32_t l[2];
  } w, r;
  if (htonl(1) == 1L)
    return val;
  w.ll = val;
  r.l[0] = ntohl(w.l[1]);
  r.l[1] = ntohl(w.l[0]);
  return r.ll;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ntoh64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <htonl@plt>
  mov    %rax,%rdx
  mov    %ebx,%eax
  cmp    $0x1,%rdx
  je     L3
  mov    %ebx,%ebx
  mov    $0x0,%edi
  call   <ntohl@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <ntohl@plt>
  mov    %ebp,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ntoh64(uint64_t val) {
  union {
    uint64_t ll;
    uint32_t l[2];
  } w, r;
  if (htonl(1) == 1L)
    return val;
  w.ll = val;
  r.l[0] = ntohl(w.l[1]);
  r.l[1] = ntohl(w.l[0]);
  return r.ll;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ntoh64>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <htonl@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cmp    $0x1,%r8
  je     L6
  xor    %edi,%edi
  mov    %ebx,%ebp
  call   <ntohl@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <ntohl@plt>
  mov    %ebx,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ntoh64(uint64_t val) {
  union {
    uint64_t ll;
    uint32_t l[2];
  } w, r;
  if (htonl(1) == 1L)
    return val;
  w.ll = val;
  r.l[0] = ntohl(w.l[1]);
  r.l[1] = ntohl(w.l[0]);
  return r.ll;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ntoh64>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <htonl@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cmp    $0x1,%r8
  je     L4
  xor    %edi,%edi
  mov    %ebx,%ebp
  call   <ntohl@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <ntohl@plt>
  mov    %ebx,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ntoh64(uint64_t val) {
  union {
    uint64_t ll;
    uint32_t l[2];
  } w, r;
  if (htonl(1) == 1L)
    return val;
  w.ll = val;
  r.l[0] = ntohl(w.l[1]);
  r.l[1] = ntohl(w.l[0]);
  return r.ll;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <notnull@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L4
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
L4:
  leave
  ret
```

assistant: ```c
int g3(int *y) {
  if (notnull(y)) {
    return 0;
  }
  return *y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <notnull@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L2
  mov    (%rbx),%eax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int g3(int *y) {
  if (notnull(y)) {
    return 0;
  }
  return *y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <notnull@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L1
  mov    (%rbx),%eax
L1:
  pop    %rbx
  ret
```

assistant: ```c
int g3(int *y) {
  if (notnull(y)) {
    return 0;
  }
  return *y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <notnull@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L7
  mov    (%rbx),%eax
L7:
  pop    %rbx
  ret
```

assistant: ```c
int g3(int *y) {
  if (notnull(y)) {
    return 0;
  }
  return *y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InverseSR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x18(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  and    $0xf0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  and    $0xf0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  and    $0xf,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void InverseSR(uint8_t *block) {
  uint8_t temp0, temp1;
  temp0 = block[1];
  block[1] = (block[1] & 0xF0) ^ (block[3] & 0x0F);
  block[3] = (block[3] & 0xF0) ^ (block[5] & 0x0F);
  block[5] = (block[5] & 0xF0) ^ (block[7] & 0x0F);
  block[7] = (block[7] & 0xF0) ^ (temp0 & 0x0F);
  temp0 = block[6];
  temp1 = block[4];
  block[6] = (block[2] & 0xF0) ^ (block[4] & 0x0F);
  block[4] = (block[0] & 0xF0) ^ (block[2] & 0x0F);
  block[2] = (temp0 & 0xF0) ^ (block[0] & 0x0F);
  block[0] = (temp1 & 0xF0) ^ (temp0 & 0x0F);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InverseSR>:
  endbr64
  mov    %rdi,%rax
  mov    0x4(%rdi),%esi
  mov    0xc(%rdi),%edx
  mov    %esi,%ecx
  and    $0xf0,%ecx
  mov    %edx,%edi
  and    $0xf,%edi
  or     %edi,%ecx
  mov    %ecx,0x4(%rax)
  mov    0x14(%rax),%ecx
  and    $0xf0,%edx
  mov    %ecx,%edi
  and    $0xf,%edi
  or     %edi,%edx
  mov    %edx,0xc(%rax)
  mov    0x1c(%rax),%edx
  and    $0xf0,%ecx
  mov    %edx,%edi
  and    $0xf,%edi
  or     %edi,%ecx
  mov    %ecx,0x14(%rax)
  and    $0xf0,%edx
  and    $0xf,%esi
  or     %esi,%edx
  mov    %edx,0x1c(%rax)
  mov    0x18(%rax),%ecx
  mov    0x10(%rax),%edx
  mov    0x8(%rax),%edi
  mov    %edi,%esi
  and    $0xf0,%esi
  mov    %edx,%r8d
  and    $0xf,%r8d
  or     %r8d,%esi
  mov    %esi,0x18(%rax)
  mov    (%rax),%esi
  mov    %esi,%r8d
  and    $0xf0,%r8d
  and    $0xf,%edi
  or     %r8d,%edi
  mov    %edi,0x10(%rax)
  mov    %ecx,%edi
  and    $0xf0,%edi
  and    $0xf,%esi
  or     %edi,%esi
  mov    %esi,0x8(%rax)
  and    $0xf0,%edx
  and    $0xf,%ecx
  or     %ecx,%edx
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void InverseSR(uint8_t *block) {
  uint8_t temp0, temp1;
  temp0 = block[1];
  block[1] = (block[1] & 0xF0) ^ (block[3] & 0x0F);
  block[3] = (block[3] & 0xF0) ^ (block[5] & 0x0F);
  block[5] = (block[5] & 0xF0) ^ (block[7] & 0x0F);
  block[7] = (block[7] & 0xF0) ^ (temp0 & 0x0F);
  temp0 = block[6];
  temp1 = block[4];
  block[6] = (block[2] & 0xF0) ^ (block[4] & 0x0F);
  block[4] = (block[0] & 0xF0) ^ (block[2] & 0x0F);
  block[2] = (temp0 & 0xF0) ^ (block[0] & 0x0F);
  block[0] = (temp1 & 0xF0) ^ (temp0 & 0x0F);
}
```