ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  pxor   %xmm0,%xmm0
  imul   0x4(%rsp),%eax
  lea    D16(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  divss  D0(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: byte[4]

tool: D17: %d%d

tool: D16: %0.3f


tool: {"D0": [0x00,0x00,0x40,0x41]}

assistant: ```c
int main() {
  int a, b, total_km;
  float litters;
  scanf("%d%d", &a, &b);
  total_km = a * b;
  litters = (float)total_km / 12;
  printf("%0.3f\n", litters);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  pxor   %xmm0,%xmm0
  imul   0x4(%rsp),%eax
  lea    D6(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  divss  D18(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: byte[4]

tool: D14: %d%d

tool: D6: %0.3f


tool: {"D18": [0x00,0x00,0x40,0x41]}

assistant: ```c
int main() {
  int a, b, total_km;
  float litters;
  scanf("%d%d", &a, &b);
  total_km = a * b;
  litters = (float)total_km / 12;
  printf("%0.3f\n", litters);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BitSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    %edx,%ecx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edi
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  or     %eax,%edi
  mov    %edi,%ecx
  mov    %edx,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BitSet(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  D[Bit / 8] |= 0x01 << (Bit % 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BitSet>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  and    $0x7,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  or     %dl,(%rdi,%rax,1)
  ret
```

assistant: ```c
void BitSet(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  D[Bit / 8] |= 0x01 << (Bit % 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BitSet>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  mov    $0x1,%edx
  shr    $0x3,%eax
  and    $0x7,%ecx
  shl    %cl,%edx
  or     %dl,(%rdi,%rax,1)
  ret
```

assistant: ```c
void BitSet(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  D[Bit / 8] |= 0x01 << (Bit % 8);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nnadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L4:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nnadd(float *dst, float *x, float *y, size_t len) {
  int i;
  for (i = 0; i < len; i++) {
    *dst++ = *x++ + *y++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nnadd>:
  endbr64
  test   %rcx,%rcx
  je     L19
  shl    $0x2,%rcx
  mov    $0x0,%eax
L7:
  movss  (%rsi,%rax,1),%xmm0
  addss  (%rdx,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L7
L19:
  ret
```

assistant: ```c
void nnadd(float *dst, float *x, float *y, size_t len) {
  int i;
  for (i = 0; i < len; i++) {
    *dst++ = *x++ + *y++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nnadd>:
  endbr64
  test   %rcx,%rcx
  je     L0
  shl    $0x2,%rcx
  xor    %eax,%eax
  nop
L7:
  movss  (%rsi,%rax,1),%xmm0
  addss  (%rdx,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L7
L0:
  ret
```

assistant: ```c
void nnadd(float *dst, float *x, float *y, size_t len) {
  int i;
  for (i = 0; i < len; i++) {
    *dst++ = *x++ + *y++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nnadd>:
  endbr64
  mov    %rdx,%r8
  mov    %rcx,%rdx
  test   %rcx,%rcx
  je     L40
  lea    0x4(%rsi),%rcx
  mov    %rdi,%rax
  lea    0x4(%r8),%r9
  sub    %rcx,%rax
  cmp    $0x8,%rax
  mov    %rdi,%rax
  seta   %cl
  sub    %r9,%rax
  cmp    $0x8,%rax
  seta   %al
  test   %al,%cl
  je     L39
  cmp    $0x1,%rdx
  je     L39
  lea    -0x1(%rdx),%rax
  cmp    $0x2,%rax
  jbe    L34
  mov    %rdx,%rcx
  xor    %eax,%eax
  shr    $0x2,%rcx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L60:
  movups (%rsi,%rax,1),%xmm0
  movups (%r8,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L60
  mov    %rdx,%r10
  and    $0xfffffffffffffffc,%r10
  lea    0x0(,%r10,4),%rax
  lea    (%rdi,%rax,1),%rcx
  lea    (%rsi,%rax,1),%r9
  add    %r8,%rax
  cmp    %r10,%rdx
  je     L40
  sub    %r10,%rdx
  cmp    $0x1,%rdx
  je     L17
L44:
  movq   (%rsi,%r10,4),%xmm0
  movq   (%r8,%r10,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdi,%r10,4)
  mov    %rdx,%rdi
  and    $0xfffffffffffffffe,%rdi
  lea    0x0(,%rdi,4),%rsi
  add    %rsi,%rcx
  add    %rsi,%r9
  add    %rsi,%rax
  cmp    %rdi,%rdx
  je     L40
L17:
  movss  (%r9),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  shl    $0x2,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L66:
  movss  (%rsi,%rax,1),%xmm0
  addss  (%r8,%rax,1),%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L66
L40:
  ret
L34:
  mov    %r8,%rax
  mov    %rsi,%r9
  mov    %rdi,%rcx
  xor    %r10d,%r10d
  jmp    L44
```

assistant: ```c
void nnadd(float *dst, float *x, float *y, size_t len) {
  int i;
  for (i = 0; i < len; i++) {
    *dst++ = *x++ + *y++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SIM_power_gatecap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D34(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D31(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D43(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D34(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D24
type: f64
name: parse_data
arguments: data_label: D34
type: byte[8]
name: parse_data
arguments: data_label: D31
type: byte[8]
name: parse_data
arguments: data_label: D43
type: byte[8]

tool: D24: 0.1525

tool: {"D34": [0xeb,0x51,0xb8,0x1e,0x85,0xeb,0xb1,0x3f]}

tool: {"D31": [0xef,0xf3,0x87,0xd4,0x64,0x90,0xe1,0x3c]}

tool: {"D43": [0x70,0x8d,0x53,0xa1,0x4e,0xf7,0xf0,0x3c]}

assistant: ```c
double SIM_power_gatecap(width, wirelength)
double width;
double wirelength;
{
  double overlapCap;
  double gateCap;
  double l = 0.1525;
  return (width * (0.8 * 0.0875) * (1.950000e-15) + wirelength * (0.25e-15 * (172.2157) * 0.0875) * (0.8 * 0.0875));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SIM_power_gatecap>:
  endbr64
  movsd  D15(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D13(%rip),%xmm0
  mulsd  D8(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: byte[8]
name: unpack_data
arguments: data_tag: D13
datatype: byte[8]
name: unpack_data
arguments: data_tag: D8
datatype: byte[8]

tool: {"D15": [0xeb,0x51,0xb8,0x1e,0x85,0xeb,0xb1,0x3f]}

tool: {"D13": [0xef,0xf3,0x87,0xd4,0x64,0x90,0xe1,0x3c]}

tool: {"D8": [0x70,0x8d,0x53,0xa1,0x4e,0xf7,0xf0,0x3c]}

assistant: ```c
double SIM_power_gatecap(width, wirelength)
double width;
double wirelength;
{
  double overlapCap;
  double gateCap;
  double l = 0.1525;
  return (width * (0.8 * 0.0875) * (1.950000e-15) + wirelength * (0.25e-15 * (172.2157) * 0.0875) * (0.8 * 0.0875));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SIM_power_gatecap>:
  endbr64
  mulsd  D21(%rip),%xmm1
  movsd  D1(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D27(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: byte[8]

tool: {"D21": [0x70,0x8d,0x53,0xa1,0x4e,0xf7,0xf0,0x3c]}

tool: {"D1": [0xeb,0x51,0xb8,0x1e,0x85,0xeb,0xb1,0x3f]}

tool: {"D27": [0xef,0xf3,0x87,0xd4,0x64,0x90,0xe1,0x3c]}

assistant: ```c
double SIM_power_gatecap(width, wirelength)
double width;
double wirelength;
{
  double overlapCap;
  double gateCap;
  double l = 0.1525;
  return (width * (0.8 * 0.0875) * (1.950000e-15) + wirelength * (0.25e-15 * (172.2157) * 0.0875) * (0.8 * 0.0875));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SIM_power_gatecap>:
  endbr64
  mulsd  D20(%rip),%xmm1
  movsd  D14(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  mulsd  D21(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D20
datatype: byte[8]
name: unpack_data
arguments: label: D14
datatype: byte[8]
name: unpack_data
arguments: label: D21
datatype: byte[8]

tool: {"D20": [0x70,0x8d,0x53,0xa1,0x4e,0xf7,0xf0,0x3c]}

tool: {"D14": [0xeb,0x51,0xb8,0x1e,0x85,0xeb,0xb1,0x3f]}

tool: {"D21": [0xef,0xf3,0x87,0xd4,0x64,0x90,0xe1,0x3c]}

assistant: ```c
double SIM_power_gatecap(width, wirelength)
double width;
double wirelength;
{
  double overlapCap;
  double gateCap;
  double l = 0.1525;
  return (width * (0.8 * 0.0875) * (1.950000e-15) + wirelength * (0.25e-15 * (172.2157) * 0.0875) * (0.8 * 0.0875));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<udev_device_copy_properties>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_get_properties_list_entry@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L1
L18:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_list_entry_get_name@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_list_entry_get_value@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <udev_device_add_property@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_list_entry_get_next@plt>
  mov    %rax,-0x18(%rbp)
L1:
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int udev_device_copy_properties(struct udev_device *dst, struct udev_device *src) {
  struct udev_list_entry *entry;
  for ((entry = udev_device_get_properties_list_entry(src)); entry; entry = udev_list_entry_get_next(entry)) {
    const char *key, *value;
    key = udev_list_entry_get_name(entry);
    value = udev_list_entry_get_value(entry);
    udev_device_add_property(dst, key, value);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<udev_device_copy_properties>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <udev_device_get_properties_list_entry@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L4:
  mov    %rbx,%rdi
  call   <udev_list_entry_get_name@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <udev_list_entry_get_value@plt>
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <udev_device_add_property@plt>
  mov    %rbx,%rdi
  call   <udev_list_entry_get_next@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L4
L2:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int udev_device_copy_properties(struct udev_device *dst, struct udev_device *src) {
  struct udev_list_entry *entry;
  for ((entry = udev_device_get_properties_list_entry(src)); entry; entry = udev_list_entry_get_next(entry)) {
    const char *key, *value;
    key = udev_list_entry_get_name(entry);
    value = udev_list_entry_get_value(entry);
    udev_device_add_property(dst, key, value);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<udev_device_copy_properties>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <udev_device_get_properties_list_entry@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <udev_list_entry_get_name@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <udev_list_entry_get_value@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <udev_device_add_property@plt>
  mov    %rbp,%rdi
  call   <udev_list_entry_get_next@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L6
L15:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int udev_device_copy_properties(struct udev_device *dst, struct udev_device *src) {
  struct udev_list_entry *entry;
  for ((entry = udev_device_get_properties_list_entry(src)); entry; entry = udev_list_entry_get_next(entry)) {
    const char *key, *value;
    key = udev_list_entry_get_name(entry);
    value = udev_list_entry_get_value(entry);
    udev_device_add_property(dst, key, value);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<udev_device_copy_properties>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <udev_device_get_properties_list_entry@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  call   <udev_list_entry_get_name@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <udev_list_entry_get_value@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <udev_device_add_property@plt>
  mov    %rbp,%rdi
  call   <udev_list_entry_get_next@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L18
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int udev_device_copy_properties(struct udev_device *dst, struct udev_device *src) {
  struct udev_list_entry *entry;
  for ((entry = udev_device_get_properties_list_entry(src)); entry; entry = udev_list_entry_get_next(entry)) {
    const char *key, *value;
    key = udev_list_entry_get_name(entry);
    value = udev_list_entry_get_value(entry);
    udev_device_add_property(dst, key, value);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<se_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <se_processid@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L33
  mov    $0xffffffff,%eax
  jmp    L12
L33:
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  mov    $0x1,%eax
  jmp    L12
L31:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: .incomplete

assistant: ```c
int se_process(char *name, uint32_t *bsn) {
  char *token = name;
  ssize_t id = se_processid(&token);
  if (__builtin_expect(!!(id == -1), 0))
    return -1;
  *bsn = id;
  if (strcmp(token, ".incomplete") == 0)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<se_process>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <se_processid@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  je     L19
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %ebx,0x0(%rbp)
  lea    D4(%rip),%rsi
  mov    (%rsp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L14
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4: .incomplete

assistant: ```c
int se_process(char *name, uint32_t *bsn) {
  char *token = name;
  ssize_t id = se_processid(&token);
  if (__builtin_expect(!!(id == -1), 0))
    return -1;
  *bsn = id;
  if (strcmp(token, ".incomplete") == 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<se_process>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <se_processid@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  mov    %eax,%ebx
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L18
  mov    %ebx,0x0(%rbp)
  mov    (%rsp),%rdi
  lea    D0(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: .incomplete

assistant: ```c
int se_process(char *name, uint32_t *bsn) {
  char *token = name;
  ssize_t id = se_processid(&token);
  if (__builtin_expect(!!(id == -1), 0))
    return -1;
  *bsn = id;
  if (strcmp(token, ".incomplete") == 0)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<se_process>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <se_processid@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  mov    %eax,%ebx
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L4
  mov    %ebx,0x0(%rbp)
  mov    (%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: .incomplete

assistant: ```c
int se_process(char *name, uint32_t *bsn) {
  char *token = name;
  ssize_t id = se_processid(&token);
  if (__builtin_expect(!!(id == -1), 0))
    return -1;
  *bsn = id;
  if (strcmp(token, ".incomplete") == 0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp_names>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int cmp_names(const void *p1, const void *p2) {
  const char *const *s1 = p1, *const *s2 = p2;
  return strcmp(*s1, *s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmp_names>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmp_names(const void *p1, const void *p2) {
  const char *const *s1 = p1, *const *s2 = p2;
  return strcmp(*s1, *s2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmp_names>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmp_names(const void *p1, const void *p2) {
  const char *const *s1 = p1, *const *s2 = p2;
  return strcmp(*s1, *s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmp_names>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmp_names(const void *p1, const void *p2) {
  const char *const *s1 = p1, *const *s2 = p2;
  return strcmp(*s1, *s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x14(%rbp),%eax
  cmp    $0x58,%eax
  je     L23
  cmp    $0x58,%eax
  jg     L5
  cmp    $0x51,%eax
  je     L47
  cmp    $0x51,%eax
  jg     L5
  cmp    $0x41,%eax
  je     L115
  cmp    $0x41,%eax
  jl     L5
  sub    $0x4a,%eax
  cmp    $0x1,%eax
  ja     L5
L47:
  movl   $0xa,-0x10(%rbp)
  jmp    L34
L115:
  movl   $0xa,-0x10(%rbp)
  jmp    L34
L23:
  movl   $0xfffffffe,-0x10(%rbp)
  jmp    L34
L5:
  movzbl -0x14(%rbp),%eax
  mov    %al,-0xb(%rbp)
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jle    L4
  cmpl   $0xa,-0x10(%rbp)
  jle    L34
L4:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0xffffffff,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D9: %c


tool: D8: not valid

assistant: ```c
int getVal(char card) {
  int val = 0;
  char name[3];
  printf("%c\n", card);
  switch (card) {
  case 'K':
  case 'Q':
  case 'J':
    val = 10;
    break;
  case 'A':
    val = 10;
    break;
  case 'X':
    val = -2;
    break;
  default:
    name[0] = card;
    val = atoi(name);
    if ((val < 1) || (val > 10)) {
      puts("not valid");
      val = -1;
    }
  }
  return val;
}
```