ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L39
  nopl   0x0(%rax)
L1:
  cmp    $0xb,%r14d
  je     L31
  mov    %r14d,%edx
  imul   %eax,%edx
  add    %edx,%ebx
  sub    %eax,%edx
  add    %edx,%ebp
L72:
  add    $0x1,%r14d
L23:
  cmp    $0xc,%r14d
  je     L94
L39:
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L23
  movsbl %al,%eax
  cmp    $0xa,%r14d
  jne    L1
  mov    %eax,%r12d
  jmp    L72
  nopl   0x0(%rax)
L94:
  mov    $0xba2e8ba3,%edi
  mov    %ebx,%eax
  mov    $0xcccccccd,%esi
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%ebx
  mov    %ebx,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,8),%edx
  lea    (%rdx,%rbp,1),%ecx
  mov    %rcx,%rdx
  imul   %rdi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%edi
  lea    (%rcx,%rdi,2),%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cmp    %r13d,%edx
  jne    L62
  cmp    %eax,%r12d
  jne    L62
  lea    D27(%rip),%rdi
  call   <printf@plt>
L52:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %eax,%r13d
  jmp    L72
L62:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L52
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D0: DIGITE O SEU CPF:

tool: D27: 
CPF VALIDO.

tool: D18: 
CPF INVALIDO.

assistant: ```c
int main(void) {
  int digitIndex = 1, term10sum = 0, term11sum = 0, digit10, digit11, term10, term11;
  char digit;
  printf("DIGITE O SEU CPF:");
  while (digitIndex <= 11) {
    digit = getchar();
    if (digit >= '0' && digit <= '9') {
      if (digitIndex == 10)
        digit10 = (int)(digit - '0');
      else if (digitIndex == 11)
        digit11 = (int)(digit - '0');
      else {
        term10sum += (int)(digit - '0') * (digitIndex);
        term11sum += (int)(digit - '0') * (digitIndex - 1);
      }
      digitIndex++;
    }
  }
  term10 = ((term10sum % 11) % 10);
  term11sum += term10 * 9;
  term11 = ((term11sum % 11) % 10);
  if ((term10 == digit10) && (term11 == digit11))
    printf("\nCPF VALIDO.");
  else
    printf("\nCPF INVALIDO.");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L49
  nopl   0x0(%rax)
L64:
  cmp    $0xb,%r14d
  je     L24
  mov    %r14d,%edx
  imul   %eax,%edx
  add    %edx,%ebx
  sub    %eax,%edx
  add    %edx,%ebp
L50:
  add    $0x1,%r14d
L65:
  cmp    $0xc,%r14d
  je     L13
L49:
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L65
  movsbl %al,%eax
  cmp    $0xa,%r14d
  jne    L64
  mov    %eax,%r12d
  jmp    L50
  nopl   0x0(%rax)
L13:
  mov    $0xba2e8ba3,%edi
  mov    %ebx,%eax
  mov    $0xcccccccd,%esi
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%ebx
  mov    %ebx,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,8),%edx
  lea    (%rdx,%rbp,1),%ecx
  mov    %rcx,%rdx
  imul   %rdi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%edi
  lea    (%rcx,%rdi,2),%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  imul   %rsi,%rcx
  shr    $0x23,%rcx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cmp    %r13d,%edx
  jne    L25
  cmp    %eax,%r12d
  jne    L25
  lea    D16(%rip),%rdi
  call   <printf@plt>
L97:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %eax,%r13d
  jmp    L50
L25:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L97
```

tool_calls: name: disassemble_data
arguments: label: D28
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: D28: DIGITE O SEU CPF:

tool: D16: 
CPF VALIDO.

tool: D8: 
CPF INVALIDO.

assistant: ```c
int main(void) {
  int digitIndex = 1, term10sum = 0, term11sum = 0, digit10, digit11, term10, term11;
  char digit;
  printf("DIGITE O SEU CPF:");
  while (digitIndex <= 11) {
    digit = getchar();
    if (digit >= '0' && digit <= '9') {
      if (digitIndex == 10)
        digit10 = (int)(digit - '0');
      else if (digitIndex == 11)
        digit11 = (int)(digit - '0');
      else {
        term10sum += (int)(digit - '0') * (digitIndex);
        term11sum += (int)(digit - '0') * (digitIndex - 1);
      }
      digitIndex++;
    }
  }
  term10 = ((term10sum % 11) % 10);
  term11sum += term10 * 9;
  term11 = ((term11sum % 11) % 10);
  if ((term10 == digit10) && (term11 == digit11))
    printf("\nCPF VALIDO.");
  else
    printf("\nCPF INVALIDO.");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<NewLintArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jg     L12
  mov    $0x0,%eax
  jmp    L15
L12:
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
long int *NewLintArray(long int N) {
  long int *vec;
  if (N <= 0)
    return (NULL);
  vec = NULL;
  vec = (long int *)malloc((size_t)N * sizeof(long int));
  return (vec);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NewLintArray>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  jle    L4
  sub    $0x8,%rsp
  shl    $0x3,%rdi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
long int *NewLintArray(long int N) {
  long int *vec;
  if (N <= 0)
    return (NULL);
  vec = NULL;
  vec = (long int *)malloc((size_t)N * sizeof(long int));
  return (vec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<NewLintArray>:
  endbr64
  test   %rdi,%rdi
  jle    L7
  shl    $0x3,%rdi
  jmp    1050 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
long int *NewLintArray(long int N) {
  long int *vec;
  if (N <= 0)
    return (NULL);
  vec = NULL;
  vec = (long int *)malloc((size_t)N * sizeof(long int));
  return (vec);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NewLintArray>:
  endbr64
  test   %rdi,%rdi
  jle    L8
  shl    $0x3,%rdi
  jmp    1050 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
long int *NewLintArray(long int N) {
  long int *vec;
  if (N <= 0)
    return (NULL);
  vec = NULL;
  vec = (long int *)malloc((size_t)N * sizeof(long int));
  return (vec);
}
```
user: What is the c source code of the assembly code below?

```asm
<repeat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  imul   %esi,%ebx
  lea    -0x1(%rcx),%edx
  test   %ecx,%ecx
  mov    $0xffffffff,%eax
  cmovs  %ecx,%eax
  add    $0x1,%eax
  test   %ecx,%ecx
  cmovle %eax,%edx
  mov    %edx,-0x14(%rsp)
  lea    -0x1(%r8),%eax
  test   %r8d,%r8d
  mov    $0xffffffff,%edx
  cmovs  %r8d,%edx
  add    $0x1,%edx
  test   %r8d,%r8d
  cmovg  %eax,%edx
  imul   %esi,%edx
  test   %ebx,%ebx
  jle    L62
  mov    %rdi,%r15
  mov    %esi,%r11d
  mov    %r9,%rax
  lea    -0x1(%rbx),%ecx
  lea    0x4(%r9,%rcx,4),%rcx
L45:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L45
  movslq %r11d,%rax
  shl    $0x2,%rax
  mov    %rax,-0x10(%rsp)
  mov    %edx,%edi
  mov    $0x0,%r12d
  mov    %r11d,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rsp)
  mov    -0x14(%rsp),%eax
  add    %r11d,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rsp)
  mov    $0x0,%r8d
  mov    %ebx,%r14d
  sub    %r11d,%r14d
  lea    -0x1(%r11),%r13d
  jmp    L75
L80:
  add    %esi,%eax
  cltq
  lea    (%r9,%rax,4),%rax
  movss  (%rax),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rax)
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%r10d
  je     L51
L76:
  mov    %r8d,%eax
  test   %edi,%edi
  js     L2
  cmp    %edi,%ebx
  mov    %ebp,%eax
  cmovle %r14d,%eax
L2:
  mov    %r8d,%esi
  test   %edx,%edx
  js     L80
  cmp    %edx,%r11d
  mov    %edx,%esi
  cmovle %r13d,%esi
  jmp    L80
L51:
  add    %r11d,%edi
  add    %r11d,%r12d
  add    -0x10(%rsp),%r15
  cmp    %r12d,%ebx
  jle    L62
L75:
  mov    -0x8(%rsp),%eax
  add    %edi,%eax
  cmp    %eax,%r12d
  jge    L51
  mov    -0x4(%rsp),%eax
  lea    (%rax,%rdi,1),%r10d
  sub    %r12d,%r10d
  mov    %r15,%rcx
  mov    -0x14(%rsp),%edx
  mov    %edi,%ebp
  jmp    L76
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void repeat(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int y_filt, x_filt, y_res, x_res;
  int filt_sz = x_dim * y_dim;
  int x_start = ((x_pos > 0) ? (x_pos - 1) : ((x_pos < 0) ? (x_pos + 1) : 0));
  int y_start = x_dim * ((y_pos > 0) ? (y_pos - 1) : ((y_pos < 0) ? (y_pos + 1) : 0));
  int i;
  for (i = 0; i < filt_sz; i++)
    result[i] = 0.0;
  for (y_filt = 0, y_res = y_start; y_filt < filt_sz; y_filt += x_dim, y_res += x_dim)
    for (x_filt = y_filt, x_res = x_start; x_filt < y_filt + x_dim; x_filt++, x_res++)
      result[((y_res >= 0) ? ((y_res < filt_sz) ? y_res : (filt_sz - x_dim)) : 0) + ((x_res >= 0) ? ((x_res < x_dim) ? x_res : (x_dim - 1)) : 0)] += filt[x_filt];
}
```
user: Translate the below assembly code into C programming language:

```asm
<repeat>:
  endbr64
  push   %r15
  imul   %esi,%edx
  mov    $0xffffffff,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  lea    -0x1(%rcx),%edx
  push   %rbx
  mov    %esi,%ebx
  mov    $0xffffffff,%esi
  sub    $0x18,%rsp
  test   %ecx,%ecx
  cmovs  %ecx,%eax
  add    $0x1,%eax
  test   %ecx,%ecx
  cmovle %eax,%edx
  test   %r8d,%r8d
  lea    -0x1(%r8),%eax
  cmovs  %r8d,%esi
  mov    %edx,0x8(%rsp)
  add    $0x1,%esi
  test   %r8d,%r8d
  cmovg  %eax,%esi
  imul   %ebx,%esi
  test   %ebp,%ebp
  jle    L36
  movslq %ebp,%rdx
  mov    %esi,%r12d
  mov    %rdi,%r13
  xor    %esi,%esi
  shl    $0x2,%rdx
  mov    %r9,%rdi
  mov    %ebx,%r15d
  movslq %ebx,%r14
  call   <memset@plt>
  mov    0x8(%rsp),%edx
  mov    %r12d,%esi
  sub    %r12d,%r15d
  mov    %rax,%r9
  shl    $0x2,%r14
  xor    %r10d,%r10d
  lea    -0x1(%rbx),%r11d
  lea    (%rdx,%rbx,1),%eax
  sub    %r12d,%eax
  mov    %ebp,%r12d
  mov    %eax,0xc(%rsp)
  sub    %ebx,%r12d
  nopl   0x0(%rax,%rax,1)
L17:
  lea    (%r15,%rsi,1),%eax
  cmp    %r10d,%eax
  jle    L1
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%edx
  mov    %r13,%rcx
  lea    (%rax,%rsi,1),%edi
  sub    %r10d,%edi
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  test   %esi,%esi
  js     L46
  cmp    %esi,%ebp
  mov    %esi,%eax
  cmovle %r12d,%eax
L46:
  test   %edx,%edx
  js     L29
  lea    (%rax,%rdx,1),%r8d
  add    %r11d,%eax
  cmp    %edx,%ebx
  cmovg  %r8d,%eax
L29:
  cltq
  add    $0x1,%edx
  add    $0x4,%rcx
  lea    (%r9,%rax,4),%rax
  movss  (%rax),%xmm0
  addss  -0x4(%rcx),%xmm0
  movss  %xmm0,(%rax)
  cmp    %edi,%edx
  jne    L8
L1:
  add    %ebx,%r10d
  add    %ebx,%esi
  add    %r14,%r13
  cmp    %r10d,%ebp
  jg     L17
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void repeat(filt, x_dim, y_dim, x_pos, y_pos, result, f_or_e) register float *filt, *result;
register int x_dim;
int y_dim, x_pos, y_pos, f_or_e;
{
  register int y_filt, x_filt, y_res, x_res;
  int filt_sz = x_dim * y_dim;
  int x_start = ((x_pos > 0) ? (x_pos - 1) : ((x_pos < 0) ? (x_pos + 1) : 0));
  int y_start = x_dim * ((y_pos > 0) ? (y_pos - 1) : ((y_pos < 0) ? (y_pos + 1) : 0));
  int i;
  for (i = 0; i < filt_sz; i++)
    result[i] = 0.0;
  for (y_filt = 0, y_res = y_start; y_filt < filt_sz; y_filt += x_dim, y_res += x_dim)
    for (x_filt = y_filt, x_res = x_start; x_filt < y_filt + x_dim; x_filt++, x_res++)
      result[((y_res >= 0) ? ((y_res < filt_sz) ? y_res : (filt_sz - x_dim)) : 0) + ((x_res >= 0) ? ((x_res < x_dim) ? x_res : (x_dim - 1)) : 0)] += filt[x_filt];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stradd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L7
L11:
  mov    $0x0,%eax
L7:
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L35
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L20
L35:
  mov    $0x0,%eax
L20:
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  cmpq   $0x0,-0x20(%rbp)
  je     L37
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  jmp    L3
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *stradd(char *src, const char *str1) {
  int len = ((src) ? strlen(src) : 0);
  char *dest;
  if ((dest = (char *)realloc(src, len + ((str1) ? strlen(str1) : 0) + 1))) {
    if (str1)
      strcpy(&dest[len], str1);
    else
      dest[len] = 0;
  }
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stradd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L45
  call   <strlen@plt>
  mov    %eax,%ebx
L45:
  test   %r12,%r12
  je     L11
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L35
  movslq %ebx,%rdi
  add    %rax,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L35:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L35
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L35
```

assistant: ```c
char *stradd(char *src, const char *str1) {
  int len = ((src) ? strlen(src) : 0);
  char *dest;
  if ((dest = (char *)realloc(src, len + ((str1) ? strlen(str1) : 0) + 1))) {
    if (str1)
      strcpy(&dest[len], str1);
    else
      dest[len] = 0;
  }
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stradd>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  call   <strlen@plt>
  movslq %eax,%rbx
L1:
  test   %r13,%r13
  je     L5
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L38
  movslq %ebx,%rdi
  mov    %r13,%rsi
  add    %rax,%rdi
  call   <strcpy@plt>
L38:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L38
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *stradd(char *src, const char *str1) {
  int len = ((src) ? strlen(src) : 0);
  char *dest;
  if ((dest = (char *)realloc(src, len + ((str1) ? strlen(str1) : 0) + 1))) {
    if (str1)
      strcpy(&dest[len], str1);
    else
      dest[len] = 0;
  }
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stradd>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L13
  call   <strlen@plt>
  movslq %eax,%rbx
L13:
  test   %r13,%r13
  je     L32
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L37
  movslq %ebx,%rdi
  mov    %r13,%rsi
  add    %rax,%rdi
  call   <strcpy@plt>
L37:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L37
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *stradd(char *src, const char *str1) {
  int len = ((src) ? strlen(src) : 0);
  char *dest;
  if ((dest = (char *)realloc(src, len + ((str1) ? strlen(str1) : 0) + 1))) {
    if (str1)
      strcpy(&dest[len], str1);
    else
      dest[len] = 0;
  }
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getttynam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <endttyent@plt>
  nop
L6:
  mov    $0x0,%eax
  call   <getttyent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
L13:
  mov    $0x0,%eax
  call   <endttyent@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct ttyent *getttynam(const char *name) {
  struct ttyent *tty;
  endttyent();
  while ((tty = getttyent()) != 0 && strcmp(tty->ty_name, name) != 0) {
  }
  endttyent();
  return tty;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getttynam>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <endttyent@plt>
L11:
  mov    $0x0,%eax
  call   <getttyent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L11
L14:
  mov    $0x0,%eax
  call   <endttyent@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct ttyent *getttynam(const char *name) {
  struct ttyent *tty;
  endttyent();
  while ((tty = getttyent()) != 0 && strcmp(tty->ty_name, name) != 0) {
  }
  endttyent();
  return tty;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getttynam>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <endttyent@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rax),%edi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L23
L13:
  xor    %eax,%eax
  call   <getttyent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L15
L23:
  xor    %eax,%eax
  call   <endttyent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
struct ttyent *getttynam(const char *name) {
  struct ttyent *tty;
  endttyent();
  while ((tty = getttyent()) != 0 && strcmp(tty->ty_name, name) != 0) {
  }
  endttyent();
  return tty;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getttynam>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <endttyent@plt>
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rax),%edi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
L12:
  xor    %eax,%eax
  call   <getttyent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L22
L28:
  xor    %eax,%eax
  call   <endttyent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
struct ttyent *getttynam(const char *name) {
  struct ttyent *tty;
  endttyent();
  while ((tty = getttyent()) != 0 && strcmp(tty->ty_name, name) != 0) {
  }
  endttyent();
  return tty;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<division>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D42
datatype: string
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D34: 
Please enter first number  : 

tool: D11: %d

tool: D42: Please enter second number : 

tool: D19: 
Division of entered numbers=%d


assistant: ```c
void division() {
  int a, b, d = 0;
  printf("\nPlease enter first number  : ");
  scanf("%d", &a);
  printf("Please enter second number : ");
  scanf("%d", &b);
  d = a / b;
  printf("\nDivision of entered numbers=%d\n", d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<division>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  mov    %eax,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D20
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D39
type: string

tool: D22: 
Please enter first number  : 

tool: D20: %d

tool: D13: Please enter second number : 

tool: D39: 
Division of entered numbers=%d


assistant: ```c
void division() {
  int a, b, d = 0;
  printf("\nPlease enter first number  : ");
  scanf("%d", &a);
  printf("Please enter second number : ");
  scanf("%d", &b);
  d = a / b;
  printf("\nDivision of entered numbers=%d\n", d);
}
```