ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%r9d
  xor    %r8d,%r8d
  xor    %esi,%esi
  push   $0x2
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    $0xfffffffd,%edi
  push   $0x9
  call   <test@plt>
  push   $0x2
  mov    $0xfffffffe,%r9d
  mov    $0xfffffffe,%r8d
  push   $0x2
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0xfffffffe,%esi
  mov    $0xfffffffe,%edi
  call   <test@plt>
  add    $0x20,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   $0x1
  mov    $0xffffffff,%r9d
  mov    $0xffffffff,%r8d
  xor    %esi,%esi
  push   $0x1
  xor    %edi,%edi
  call   <test@plt>
  push   $0x4
  mov    $0x3,%r9d
  mov    $0x3,%r8d
  push   $0x4
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0xfffffffe,%esi
  mov    $0xfffffffe,%edi
  call   <test@plt>
  add    $0x20,%rsp
  mov    $0xfffffffd,%r9d
  mov    $0xfffffffd,%r8d
  push   $0xffffffffffffffff
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0xfffffffe,%esi
  push   $0x3
  mov    $0xfffffffe,%edi
  call   <test@plt>
  push   $0x6
  mov    $0x4,%r9d
  mov    $0xffffffff,%r8d
  push   $0x1
  mov    $0x2,%ecx
  mov    $0x2,%edx
  mov    $0xfffffffe,%esi
  mov    $0xfffffffe,%edi
  call   <test@plt>
  add    $0x20,%rsp
  xor    %r9d,%r9d
  xor    %esi,%esi
  push   $0x1
  mov    $0x59682f00,%r8d
  mov    $0x1,%ecx
  mov    $0xa697d100,%edx
  push   $0x59682f01
  mov    $0xa697d0ff,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(void) {
  test(-3, 0, 3, 4, 0, -1, 9, 2);
  test(-2, -2, 2, 2, -2, -2, 2, 2);
  test(0, 0, 0, 0, -1, -1, 1, 1);
  test(-2, -2, 2, 2, 3, 3, 4, 4);
  test(-2, -2, 2, 2, -3, -3, 3, -1);
  test(-2, -2, 2, 2, -1, 4, 1, 6);
  test(-1500000001, 0, -1500000000, 1, 1500000000, 0, 1500000001, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ezplib_get_subrule>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2118(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L100
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8,%r14
  mov    %r9d,%r15d
  test   %r8,%r8
  sete   %al
  cmp    %ecx,%edx
  setg   %dl
  or     %dl,%al
  jne    L110
  cmpb   $0x0,(%rdi)
  je     L110
  mov    %r9d,%edx
  mov    $0x0,%esi
  mov    %r8,%rdi
  call   <memset@plt>
  lea    0x110(%rsp),%rdx
  mov    $0x2000,%ecx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <ezplib_get_rule@plt>
  test   %eax,%eax
  js     L91
  mov    %rsp,%rdx
  lea    0x110(%rsp),%rdi
  mov    $0x22,%ecx
  lea    D3(%rip),%rsi
  call   <sep_string@plt>
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L108
L123:
  add    $0x1,%rbx
  cmp    $0x22,%rbx
  je     L124
L108:
  mov    (%rsp,%rbx,8),%rcx
  test   %rcx,%rcx
  je     L124
  cmp    %ebx,%r12d
  jg     L123
  cmp    %ebx,%r13d
  jl     L123
  mov    %r15d,%esi
  sub    %ebp,%esi
  movslq %ebp,%rdi
  add    %r14,%rdi
  lea    D3(%rip),%r8
  lea    D22(%rip),%rdx
  call   <snprintf@plt>
  add    %eax,%ebp
  jmp    L123
L124:
  mov    $0x0,%eax
  test   %ebp,%ebp
  jle    L91
  movslq %ebp,%rbp
  lea    -0x1(%r14,%rbp,1),%rdx
  cmpb   $0x0,(%rdx)
  je     L91
  movb   $0x0,(%rdx)
L91:
  mov    0x2118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x2128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L100:
  mov    $0xffffffff,%eax
  jmp    L91
L110:
  mov    $0xffffffff,%eax
  jmp    L91
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D22
datatype: string

tool: D3: ^

tool: D22: %s%s

assistant: ```c
int ezplib_get_subrule(const char *rule_set, int nth, int start, int end, char *buf, int bsize) {
  char *ptr_array[34];
  char word[8192];
  int ret, i, j, len;
  if (!rule_set || !*rule_set || !buf) {
    return -1;
  }
  if (start > end) {
    return -1;
  }
  memset(buf, '\0', bsize);
  ret = ezplib_get_rule(rule_set, nth, word, 8192);
  if (ret < 0) {
    return ret;
  }
  sep_string(word, "^", ptr_array, 34);
  for (i = j = 0; i < 34; i++) {
    if (!ptr_array[i]) {
      break;
    }
    if (start <= i && i <= end) {
      len = snprintf(buf + j, bsize - j, "%s%s", ptr_array[i], "^");
      j += len;
    }
  }
  if (j > 0 && buf[j - 1]) {
    buf[j - 1] = '\0';
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ezplib_get_subrule>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x138,%rsp
  mov    %r9d,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x2128(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L30
  test   %r8,%r8
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %r8,%r13
  sete   %al
  cmp    %ecx,%edx
  setg   %dl
  or     %dl,%al
  jne    L30
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r15
  je     L30
  mov    %r8,%rdi
  mov    %esi,%r14d
  mov    %r9d,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x2000,%ecx
  mov    %r14d,%esi
  mov    %r15,%rdi
  lea    0x120(%rsp),%r8
  mov    %r8,%rdx
  mov    %r8,0x8(%rsp)
  call   <ezplib_get_rule@plt>
  test   %eax,%eax
  js     L25
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  mov    $0x22,%ecx
  mov    %r14,%rdx
  lea    D24(%rip),%rsi
  call   <sep_string@plt>
  jmp    L44
  xchg   %ax,%ax
L114:
  cmp    %ebx,%ebp
  jg     L9
  cmp    %ebx,%r12d
  jl     L9
  mov    0x4(%rsp),%esi
  movslq %r15d,%rdi
  lea    D24(%rip),%r8
  lea    D23(%rip),%rdx
  add    %r13,%rdi
  sub    %r15d,%esi
  call   <snprintf@plt>
  add    %eax,%r15d
L9:
  add    $0x1,%rbx
  cmp    $0x22,%rbx
  je     L63
L44:
  mov    (%r14,%rbx,8),%rcx
  test   %rcx,%rcx
  jne    L114
L63:
  xor    %eax,%eax
  test   %r15d,%r15d
  jle    L25
  movslq %r15d,%r9
  lea    -0x1(%r13,%r9,1),%rdx
  cmpb   $0x0,(%rdx)
  jne    L103
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x2128(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L128
  add    $0x2138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L103:
  movb   $0x0,(%rdx)
  jmp    L25
L30:
  mov    $0xffffffff,%eax
  jmp    L25
L128:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string

tool: D24: ^

tool: D23: %s%s

assistant: ```c
int ezplib_get_subrule(const char *rule_set, int nth, int start, int end, char *buf, int bsize) {
  char *ptr_array[34];
  char word[8192];
  int ret, i, j, len;
  if (!rule_set || !*rule_set || !buf) {
    return -1;
  }
  if (start > end) {
    return -1;
  }
  memset(buf, '\0', bsize);
  ret = ezplib_get_rule(rule_set, nth, word, 8192);
  if (ret < 0) {
    return ret;
  }
  sep_string(word, "^", ptr_array, 34);
  for (i = j = 0; i < 34; i++) {
    if (!ptr_array[i]) {
      break;
    }
    if (start <= i && i <= end) {
      len = snprintf(buf + j, bsize - j, "%s%s", ptr_array[i], "^");
      j += len;
    }
  }
  if (j > 0 && buf[j - 1]) {
    buf[j - 1] = '\0';
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ezplib_get_subrule>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x138,%rsp
  mov    %r9d,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x2128(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L110
  test   %r8,%r8
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %r8,%r13
  sete   %al
  cmp    %ecx,%edx
  setg   %dl
  or     %dl,%al
  jne    L110
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r15
  je     L110
  mov    %r8,%rdi
  mov    %esi,%r14d
  mov    %r9d,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x2000,%ecx
  mov    %r14d,%esi
  mov    %r15,%rdi
  lea    0x120(%rsp),%r8
  mov    %r8,%rdx
  mov    %r8,0x8(%rsp)
  call   <ezplib_get_rule@plt>
  test   %eax,%eax
  js     L112
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r14
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  mov    $0x22,%ecx
  mov    %r14,%rdx
  lea    D20(%rip),%rsi
  call   <sep_string@plt>
  jmp    L130
  xchg   %ax,%ax
L93:
  cmp    %ebx,%ebp
  jg     L89
  cmp    %ebx,%r12d
  jl     L89
  mov    0x4(%rsp),%esi
  movslq %r15d,%rdi
  lea    D20(%rip),%r8
  lea    D1(%rip),%rdx
  add    %r13,%rdi
  sub    %r15d,%esi
  call   <snprintf@plt>
  add    %eax,%r15d
L89:
  add    $0x1,%rbx
  cmp    $0x22,%rbx
  je     L60
L130:
  mov    (%r14,%rbx,8),%rcx
  test   %rcx,%rcx
  jne    L93
L60:
  xor    %eax,%eax
  test   %r15d,%r15d
  jle    L112
  movslq %r15d,%r9
  lea    -0x1(%r13,%r9,1),%rdx
  cmpb   $0x0,(%rdx)
  jne    L59
  nopl   0x0(%rax,%rax,1)
L112:
  mov    0x2128(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L131
  add    $0x2138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L59:
  movb   $0x0,(%rdx)
  jmp    L112
L110:
  mov    $0xffffffff,%eax
  jmp    L112
L131:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D20
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D20: ^

tool: D1: %s%s

assistant: ```c
int ezplib_get_subrule(const char *rule_set, int nth, int start, int end, char *buf, int bsize) {
  char *ptr_array[34];
  char word[8192];
  int ret, i, j, len;
  if (!rule_set || !*rule_set || !buf) {
    return -1;
  }
  if (start > end) {
    return -1;
  }
  memset(buf, '\0', bsize);
  ret = ezplib_get_rule(rule_set, nth, word, 8192);
  if (ret < 0) {
    return ret;
  }
  sep_string(word, "^", ptr_array, 34);
  for (i = j = 0; i < 34; i++) {
    if (!ptr_array[i]) {
      break;
    }
    if (start <= i && i <= end) {
      len = snprintf(buf + j, bsize - j, "%s%s", ptr_array[i], "^");
      j += len;
    }
  }
  if (j > 0 && buf[j - 1]) {
    buf[j - 1] = '\0';
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<dav_parse_hexpair>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x30,-0x8(%rbp)
  jle    L25
  mov    -0x8(%rbp),%eax
  sub    $0x27,%eax
  shl    $0x4,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L25:
  cmpl   $0x10,-0x8(%rbp)
  jle    L68
  mov    -0x8(%rbp),%eax
  sub    $0x7,%eax
  shl    $0x4,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L68:
  shll   $0x4,-0x8(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x30,-0x4(%rbp)
  jle    L34
  mov    -0x4(%rbp),%eax
  sub    $0x27,%eax
  or     %eax,-0x8(%rbp)
  jmp    L47
L34:
  cmpl   $0x10,-0x4(%rbp)
  jle    L58
  mov    -0x4(%rbp),%eax
  sub    $0x7,%eax
  or     %eax,-0x8(%rbp)
  jmp    L47
L58:
  mov    -0x4(%rbp),%eax
  or     %eax,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int dav_parse_hexpair(const char *s) {
  int result;
  int temp;
  result = s[0] - '0';
  if (result > 48)
    result = (result - 39) << 4;
  else if (result > 16)
    result = (result - 7) << 4;
  else
    result = result << 4;
  temp = s[1] - '0';
  if (temp > 48)
    result |= temp - 39;
  else if (temp > 16)
    result |= temp - 7;
  else
    result |= temp;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dav_parse_hexpair>:
  endbr64
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L18
  lea    -0x57(%rax),%edx
  shl    $0x4,%edx
L6:
  movsbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L9
  sub    $0x57,%eax
  or     %edx,%eax
  ret
L18:
  sub    $0x37,%eax
  shl    $0x4,%eax
  mov    %ecx,%edx
  shl    $0x4,%edx
  cmp    $0x11,%ecx
  cmovge %eax,%edx
  jmp    L6
L9:
  sub    $0x37,%eax
  or     %edx,%eax
  or     %ecx,%edx
  cmp    $0x11,%ecx
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int dav_parse_hexpair(const char *s) {
  int result;
  int temp;
  result = s[0] - '0';
  if (result > 48)
    result = (result - 39) << 4;
  else if (result > 16)
    result = (result - 7) << 4;
  else
    result = result << 4;
  temp = s[1] - '0';
  if (temp > 48)
    result |= temp - 39;
  else if (temp > 16)
    result |= temp - 7;
  else
    result |= temp;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dav_parse_hexpair>:
  endbr64
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L1
  lea    -0x57(%rax),%edx
  movsbl 0x1(%rdi),%eax
  shl    $0x4,%edx
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L18
L5:
  sub    $0x57,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sub    $0x37,%eax
  mov    %ecx,%edx
  shl    $0x4,%eax
  shl    $0x4,%edx
  cmp    $0x11,%ecx
  cmovge %eax,%edx
  movsbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jg     L5
L18:
  sub    $0x37,%eax
  or     %edx,%eax
  or     %ecx,%edx
  cmp    $0x11,%ecx
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int dav_parse_hexpair(const char *s) {
  int result;
  int temp;
  result = s[0] - '0';
  if (result > 48)
    result = (result - 39) << 4;
  else if (result > 16)
    result = (result - 7) << 4;
  else
    result = result << 4;
  temp = s[1] - '0';
  if (temp > 48)
    result |= temp - 39;
  else if (temp > 16)
    result |= temp - 7;
  else
    result |= temp;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dav_parse_hexpair>:
  endbr64
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L29
  lea    -0x57(%rax),%edx
  movsbl 0x1(%rdi),%eax
  shl    $0x4,%edx
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jle    L7
L18:
  sub    $0x57,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  sub    $0x37,%eax
  mov    %ecx,%edx
  shl    $0x4,%eax
  shl    $0x4,%edx
  cmp    $0x11,%ecx
  cmovge %eax,%edx
  movsbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x30,%ecx
  jg     L18
L7:
  sub    $0x37,%eax
  or     %edx,%eax
  or     %ecx,%edx
  cmp    $0x11,%ecx
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int dav_parse_hexpair(const char *s) {
  int result;
  int temp;
  result = s[0] - '0';
  if (result > 48)
    result = (result - 39) << 4;
  else if (result > 16)
    result = (result - 7) << 4;
  else
    result = result << 4;
  temp = s[1] - '0';
  if (temp > 48)
    result |= temp - 39;
  else if (temp > 16)
    result |= temp - 7;
  else
    result |= temp;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_on_puzzle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  lea    0x0(,%rdx,4),%ecx
  mov    -0x20(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_on_puzzle(int *matrix, int x, int y, int new_x, int new_y) {
  int aux = matrix[x * 4 + y];
  matrix[x * 4 + y] = matrix[new_x * 4 + new_y];
  matrix[new_x * 4 + new_y] = aux;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<swap_on_puzzle>:
  endbr64
  mov    %esi,%eax
  mov    %ecx,%esi
  lea    (%rdx,%rax,4),%eax
  cltq
  lea    (%rdi,%rax,4),%rdx
  mov    (%rdx),%ecx
  lea    (%r8,%rsi,4),%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void swap_on_puzzle(int *matrix, int x, int y, int new_x, int new_y) {
  int aux = matrix[x * 4 + y];
  matrix[x * 4 + y] = matrix[new_x * 4 + new_y];
  matrix[new_x * 4 + new_y] = aux;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_on_puzzle>:
  endbr64
  lea    (%rdx,%rsi,4),%eax
  mov    %ecx,%r9d
  cltq
  lea    (%rdi,%rax,4),%rdx
  lea    (%r8,%r9,4),%eax
  cltq
  mov    (%rdx),%ecx
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void swap_on_puzzle(int *matrix, int x, int y, int new_x, int new_y) {
  int aux = matrix[x * 4 + y];
  matrix[x * 4 + y] = matrix[new_x * 4 + new_y];
  matrix[new_x * 4 + new_y] = aux;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap_on_puzzle>:
  endbr64
  lea    (%rdx,%rsi,4),%eax
  mov    %ecx,%r9d
  cltq
  lea    (%rdi,%rax,4),%rdx
  lea    (%r8,%r9,4),%eax
  cltq
  mov    (%rdx),%ecx
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void swap_on_puzzle(int *matrix, int x, int y, int new_x, int new_y) {
  int aux = matrix[x * 4 + y];
  matrix[x * 4 + y] = matrix[new_x * 4 + new_y];
  matrix[new_x * 4 + new_y] = aux;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fs_bit_mask_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  jne    L120
  mov    $0xffffff80,%eax
  jmp    L24
L120:
  cmpw   $0x1,-0x4(%rbp)
  jne    L118
  mov    $0x40,%eax
  jmp    L24
L118:
  cmpw   $0x2,-0x4(%rbp)
  jne    L100
  mov    $0x20,%eax
  jmp    L24
L100:
  cmpw   $0x3,-0x4(%rbp)
  jne    L156
  mov    $0x10,%eax
  jmp    L24
L156:
  cmpw   $0x4,-0x4(%rbp)
  jne    L8
  mov    $0x8,%eax
  jmp    L24
L8:
  cmpw   $0x5,-0x4(%rbp)
  jne    L44
  mov    $0x4,%eax
  jmp    L24
L44:
  cmpw   $0x6,-0x4(%rbp)
  jne    L34
  mov    $0x2,%eax
  jmp    L24
L34:
  cmpw   $0x7,-0x4(%rbp)
  jne    L52
  mov    $0x1,%eax
  jmp    L24
L52:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
char fs_bit_mask_get(short nbit) {
  if (nbit == 0)
    return 0x80;
  else if (nbit == 1)
    return 0x40;
  else if (nbit == 2)
    return 0x20;
  else if (nbit == 3)
    return 0x10;
  else if (nbit == 4)
    return 0x08;
  else if (nbit == 5)
    return 0x04;
  else if (nbit == 6)
    return 0x02;
  else if (nbit == 7)
    return 0x01;
  return 0x00;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fs_bit_mask_get>:
  endbr64
  cmp    $0x7,%di
  ja     L3
  movzwl %di,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xffffff80,%eax
  ret
  mov    $0x40,%eax
  ret
  mov    $0x20,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x1,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char fs_bit_mask_get(short nbit) {
  if (nbit == 0)
    return 0x80;
  else if (nbit == 1)
    return 0x40;
  else if (nbit == 2)
    return 0x20;
  else if (nbit == 3)
    return 0x10;
  else if (nbit == 4)
    return 0x08;
  else if (nbit == 5)
    return 0x04;
  else if (nbit == 6)
    return 0x02;
  else if (nbit == 7)
    return 0x01;
  return 0x00;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fs_bit_mask_get>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%di
  ja     L6
  movzwl %di,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L6:
  ret
```

assistant: ```c
char fs_bit_mask_get(short nbit) {
  if (nbit == 0)
    return 0x80;
  else if (nbit == 1)
    return 0x40;
  else if (nbit == 2)
    return 0x20;
  else if (nbit == 3)
    return 0x10;
  else if (nbit == 4)
    return 0x08;
  else if (nbit == 5)
    return 0x04;
  else if (nbit == 6)
    return 0x02;
  else if (nbit == 7)
    return 0x01;
  return 0x00;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fs_bit_mask_get>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%di
  ja     L1
  movzwl %di,%edi
  lea    D9(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L1:
  ret
```

assistant: ```c
char fs_bit_mask_get(short nbit) {
  if (nbit == 0)
    return 0x80;
  else if (nbit == 1)
    return 0x40;
  else if (nbit == 2)
    return 0x20;
  else if (nbit == 3)
    return 0x10;
  else if (nbit == 4)
    return 0x08;
  else if (nbit == 5)
    return 0x04;
  else if (nbit == 6)
    return 0x02;
  else if (nbit == 7)
    return 0x01;
  return 0x00;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trapezoid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  movsd  -0x48(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L9:
  cmpl   $0x0,-0x24(%rbp)
  jne    L32
  mov    -0x40(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L37
L32:
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x24(%rbp)
  jne    L52
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x38(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L37
L52:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x38(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L37:
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L9
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movsd  -0x20(%rbp),%xmm1
  addsd  -0x18(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: f64

tool: D9: 0.5

assistant: ```c
double trapezoid(double (*fp)(double), double a, double b, int N) {
  double h = (b - a) / (N - 1);
  double f_a, f_b, trapezoid = 0.0;
  for (int i = 0; i < N; ++i) {
    if (i == 0) {
      f_a = (*fp)(a);
      trapezoid += f_a;
    } else if (i == N - 1) {
      f_b = (*fp)(a + h * i);
      trapezoid += f_b;
    } else {
      trapezoid += (*fp)(a + h * i);
    }
  }
  trapezoid = h * (trapezoid)-0.5 * h * (f_a + f_b);
  return trapezoid;
}
```