ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test4>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1700000009,%rax
  mov    %rax,0x10(%rsp)
  call   <CreateList@plt>
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    %rax,%rdi
  call   <PrintList@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <DeleteNode@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test4() {
  int values[] = {1, 3, 5, 7, 9, 23};
  struct node *llist = CreateList(values, 6);
  llist = DeleteNode(llist, -1);
  llist = DeleteNode(llist, 0);
  llist = DeleteNode(llist, 9);
  llist = DeleteNode(llist, 1);
  llist = DeleteNode(llist, 5);
  llist = DeleteNode(llist, 3);
  PrintList(llist);
  DeleteNode(NULL, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test4>:
  endbr64
  sub    $0x28,%rsp
  movdqa D15(%rip),%xmm0
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <CreateList@plt>
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <DeleteNode@plt>
  mov    %rax,%rdi
  call   <PrintList@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <DeleteNode@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: byte[16]
name: read_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D15": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D2": [0x09,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

assistant: ```c
void test4() {
  int values[] = {1, 3, 5, 7, 9, 23};
  struct node *llist = CreateList(values, 6);
  llist = DeleteNode(llist, -1);
  llist = DeleteNode(llist, 0);
  llist = DeleteNode(llist, 9);
  llist = DeleteNode(llist, 1);
  llist = DeleteNode(llist, 5);
  llist = DeleteNode(llist, 3);
  PrintList(llist);
  DeleteNode(NULL, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x1c(%rbp)
  movq   $0x2,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int i = 1;
  long l = 2;
  int *p = &i;
  foo(0, i, l, p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 1;
  long l = 2;
  int *p = &i;
  foo(0, i, l, p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 1;
  long l = 2;
  int *p = &i;
  foo(0, i, l, p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  call   <foo@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i = 1;
  long l = 2;
  int *p = &i;
  foo(0, i, l, p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <concat@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <concat@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D3: welcome: <b>

tool: D4: </b> from C++

assistant: ```c
char *getString(char *input) {
  char *test = "welcome: <b>";
  test = concat(test, input);
  test = concat(test, "</b> from C++");
  return test;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getString>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <concat@plt>
  mov    %rax,%rdi
  lea    D14(%rip),%rsi
  call   <concat@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D14
data_type: string

tool: D7: welcome: <b>

tool: D14: </b> from C++

assistant: ```c
char *getString(char *input) {
  char *test = "welcome: <b>";
  test = concat(test, input);
  test = concat(test, "</b> from C++");
  return test;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getString>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <concat@plt>
  lea    D4(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1050 <concat@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D17: welcome: <b>

tool: D4: </b> from C++

assistant: ```c
char *getString(char *input) {
  char *test = "welcome: <b>";
  test = concat(test, input);
  test = concat(test, "</b> from C++");
  return test;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getString>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <concat@plt>
  lea    D11(%rip),%rsi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1050 <concat@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D11
type_infered: string

tool: D14: welcome: <b>

tool: D11: </b> from C++

assistant: ```c
char *getString(char *input) {
  char *test = "welcome: <b>";
  test = concat(test, input);
  test = concat(test, "</b> from C++");
  return test;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ri64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  shl    $0x8,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  shl    $0x10,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  shl    $0x18,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    $0x20,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    $0x28,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    $0x30,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    $0x38,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ri64(const uint8_t a[8]) {
  uint64_t x;
  x = (uint64_t)a[0] << 0;
  x |= (uint64_t)a[1] << 8;
  x |= (uint64_t)a[2] << 16;
  x |= (uint64_t)a[3] << 24;
  x |= (uint64_t)a[4] << 32;
  x |= (uint64_t)a[5] << 40;
  x |= (uint64_t)a[6] << 48;
  x |= (uint64_t)a[7] << 56;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ri64>:
  endbr64
  mov    0x8(%rdi),%edx
  shl    $0x8,%edx
  mov    0x10(%rdi),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  or     (%rdi),%edx
  mov    0x18(%rdi),%rax
  shl    $0x18,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint64_t ri64(const uint8_t a[8]) {
  uint64_t x;
  x = (uint64_t)a[0] << 0;
  x |= (uint64_t)a[1] << 8;
  x |= (uint64_t)a[2] << 16;
  x |= (uint64_t)a[3] << 24;
  x |= (uint64_t)a[4] << 32;
  x |= (uint64_t)a[5] << 40;
  x |= (uint64_t)a[6] << 48;
  x |= (uint64_t)a[7] << 56;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ri64>:
  endbr64
  mov    0x8(%rdi),%edx
  mov    0x10(%rdi),%eax
  shl    $0x8,%edx
  shl    $0x10,%eax
  or     %eax,%edx
  mov    0x18(%rdi),%rax
  or     (%rdi),%edx
  shl    $0x18,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint64_t ri64(const uint8_t a[8]) {
  uint64_t x;
  x = (uint64_t)a[0] << 0;
  x |= (uint64_t)a[1] << 8;
  x |= (uint64_t)a[2] << 16;
  x |= (uint64_t)a[3] << 24;
  x |= (uint64_t)a[4] << 32;
  x |= (uint64_t)a[5] << 40;
  x |= (uint64_t)a[6] << 48;
  x |= (uint64_t)a[7] << 56;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<os_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <scheduler_init@plt>
  mov    $0x0,%eax
  call   <cpu_enable_int@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void os_init(void) {
  scheduler_init();
  cpu_enable_int();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<os_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <scheduler_init@plt>
  mov    $0x0,%eax
  call   <cpu_enable_int@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void os_init(void) {
  scheduler_init();
  cpu_enable_int();
}
```
user: What is the c source code of the assembly code below:

```asm
<os_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <scheduler_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cpu_enable_int@plt>
```

assistant: ```c
void os_init(void) {
  scheduler_init();
  cpu_enable_int();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<os_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <scheduler_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cpu_enable_int@plt>
```

assistant: ```c
void os_init(void) {
  scheduler_init();
  cpu_enable_int();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<alarmInterrupt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <printProgress@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x14,%edi
  call   <alarm@plt>
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void alarmInterrupt() {
  if (!printProgress())
    alarm(20);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<alarmInterrupt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <printProgress@plt>
  test   %eax,%eax
  je     L4
L5:
  add    $0x8,%rsp
  ret
L4:
  mov    $0x14,%edi
  call   <alarm@plt>
  jmp    L5
```

assistant: ```c
void alarmInterrupt() {
  if (!printProgress())
    alarm(20);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<alarmInterrupt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printProgress@plt>
  test   %eax,%eax
  je     L7
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1060 <alarm@plt>
```

assistant: ```c
void alarmInterrupt() {
  if (!printProgress())
    alarm(20);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alarmInterrupt>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printProgress@plt>
  test   %eax,%eax
  je     L5
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1060 <alarm@plt>
```

assistant: ```c
void alarmInterrupt() {
  if (!printProgress())
    alarm(20);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<splitcommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  jmp    L13
L11:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
L13:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string

tool: D12:  	


assistant: ```c
void splitcommand(char *zeile, char **vec) {
  int i = 0;
  for (vec[i] = strtok(zeile, " \t\n"); vec[i]; vec[++i] = strtok(NULL, " \t\n"))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<splitcommand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    D15(%rip),%rsi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L6
  add    $0x8,%rbx
  lea    D15(%rip),%rbp
L19:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L19
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string

tool: D15:  	


assistant: ```c
void splitcommand(char *zeile, char **vec) {
  int i = 0;
  for (vec[i] = strtok(zeile, " \t\n"); vec[i]; vec[++i] = strtok(NULL, " \t\n"))
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<splitcommand>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L8
  add    $0x8,%rbx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L1
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0:  	


assistant: ```c
void splitcommand(char *zeile, char **vec) {
  int i = 0;
  for (vec[i] = strtok(zeile, " \t\n"); vec[i]; vec[++i] = strtok(NULL, " \t\n"))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<splitcommand>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L15
  add    $0x8,%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rsi
  xor    %edi,%edi
  add    $0x8,%rbx
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L8
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2:  	


assistant: ```c
void splitcommand(char *zeile, char **vec) {
  int i = 0;
  for (vec[i] = strtok(zeile, " \t\n"); vec[i]; vec[++i] = strtok(NULL, " \t\n"))
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<matches>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L84
L13:
  movl   $0x0,-0x10(%rbp)
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rsi,%r8
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L59
  movl   $0x1,-0x10(%rbp)
  addq   $0x1,-0x30(%rbp)
L59:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L54
  addq   $0x1,-0x30(%rbp)
L54:
  cmpl   $0x1,-0xc(%rbp)
  jle    L114
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L28
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jl     L139
  cmpl   $0x0,-0x10(%rbp)
  jne    L92
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L30
L92:
  mov    $0x1,%eax
  jmp    L19
L114:
  nop
  jmp    L84
L28:
  nop
  jmp    L84
L139:
  nop
  jmp    L84
L30:
  nop
L84:
  cmpq   $0x0,-0x30(%rbp)
  je     L85
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L85:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L90
  call   <__stack_chk_fail@plt>
L90:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %d.%d%n

assistant: ```c
int matches(int major, int minor, char *pyversions) {
  while (pyversions && *pyversions) {
    int target_major, target_minor, chars;
    int inexact = 0;
    int r = sscanf(pyversions, "%d.%d%n", &target_major, &target_minor, &chars);
    pyversions += chars;
    if (*pyversions == '+') {
      inexact = 1;
      pyversions++;
    }
    if (*pyversions == ',') {
      pyversions++;
    }
    if (r < 2) {
      continue;
    }
    if (major != target_major) {
      continue;
    }
    if (minor < target_minor) {
      continue;
    }
    if (!inexact && (minor != target_minor)) {
      continue;
    }
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matches>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%r13
  test   %rdx,%rdx
  je     L91
L7:
  cmpb   $0x0,(%rbx)
  jne    L101
  mov    $0x0,%eax
L91:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L101:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  movslq 0x14(%rsp),%rdx
  add    %rdx,%rbx
  mov    $0x0,%ecx
  cmpb   $0x2b,(%rbx)
  je     L27
L51:
  cmpb   $0x2c,(%rbx)
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rbx
  cmp    $0x1,%eax
  jle    L7
  cmp    %r12d,0xc(%rsp)
  jne    L7
  mov    0x10(%rsp),%eax
  cmp    %ebp,%eax
  jg     L7
  je     L93
  test   %ecx,%ecx
  je     L7
L93:
  mov    $0x1,%eax
  jmp    L91
L27:
  add    $0x1,%rbx
  mov    $0x1,%ecx
  jmp    L51
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: %d.%d%n

assistant: ```c
int matches(int major, int minor, char *pyversions) {
  while (pyversions && *pyversions) {
    int target_major, target_minor, chars;
    int inexact = 0;
    int r = sscanf(pyversions, "%d.%d%n", &target_major, &target_minor, &chars);
    pyversions += chars;
    if (*pyversions == '+') {
      inexact = 1;
      pyversions++;
    }
    if (*pyversions == ',') {
      pyversions++;
    }
    if (r < 2) {
      continue;
    }
    if (major != target_major) {
      continue;
    }
    if (minor < target_minor) {
      continue;
    }
    if (!inexact && (minor != target_minor)) {
      continue;
    }
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matches>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L13
L39:
  cmpb   $0x0,(%rbx)
  jne    L6
L13:
  xor    %eax,%eax
L62:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rbx,%rdi
  mov    %r13,%rsi
  lea    0x14(%rsp),%r8
  call   <sscanf@plt>
  movslq 0x14(%rsp),%rdx
  xor    %ecx,%ecx
  add    %rdx,%rbx
  movzbl (%rbx),%edx
  cmp    $0x2b,%dl
  jne    L8
  movzbl 0x1(%rbx),%edx
  mov    $0x1,%ecx
  add    $0x1,%rbx
L8:
  cmp    $0x2c,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rbx
  cmp    $0x1,%eax
  jle    L39
  cmp    %r12d,0xc(%rsp)
  jne    L39
  cmp    %ebp,0x10(%rsp)
  jg     L39
  je     L32
  test   %ecx,%ecx
  je     L39
L32:
  mov    $0x1,%eax
  jmp    L62
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: %d.%d%n

assistant: ```c
int matches(int major, int minor, char *pyversions) {
  while (pyversions && *pyversions) {
    int target_major, target_minor, chars;
    int inexact = 0;
    int r = sscanf(pyversions, "%d.%d%n", &target_major, &target_minor, &chars);
    pyversions += chars;
    if (*pyversions == '+') {
      inexact = 1;
      pyversions++;
    }
    if (*pyversions == ',') {
      pyversions++;
    }
    if (r < 2) {
      continue;
    }
    if (major != target_major) {
      continue;
    }
    if (minor < target_minor) {
      continue;
    }
    if (!inexact && (minor != target_minor)) {
      continue;
    }
    return 1;
  }
  return 0;
}
```