ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<setsampling0>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%edi
  test   %edx,%edx
  je     L7
  test   %esi,%esi
  je     L12
  mov    %rax,%rdx
  mov    %esi,%ecx
  lea    (%rax,%rcx,4),%rax
L26:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L26
  ret
L7:
  mulsd  %xmm0,%xmm2
  test   %r8d,%r8d
  je     L12
  lea    -0x1(%rcx),%edx
  lea    0x4(,%rdx,4),%r10
  mov    $0x0,%esi
  movsd  D7(%rip),%xmm0
  mov    $0x1,%r9d
  jmp    L31
L51:
  test   %edi,%edi
  je     L18
  lea    (%rax,%r10,1),%rdx
L59:
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L59
  mov    %rdx,%rax
L18:
  mulsd  %xmm1,%xmm2
  add    $0x1,%esi
  cmp    %esi,%r8d
  je     L12
L31:
  mov    %r9d,%ecx
  comisd %xmm2,%xmm0
  ja     L51
  cvttsd2si %xmm2,%rcx
  jmp    L51
L12:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setsampling0(unsigned int *DownSmpl, unsigned int S, int continuous, unsigned int V, unsigned int J, double b0, double a0, double s0) {
  double da1;
  unsigned int s, j, v, ua1;
  if (continuous)
    for (s = 0; s < S; s++)
      DownSmpl[s] = 1;
  else {
    da1 = s0 * b0;
    for (j = 0; j < J; j++) {
      ua1 = (da1 < 1) ? 1 : (unsigned int)da1;
      for (v = 0; v < V; v++)
        *DownSmpl++ = ua1;
      da1 *= a0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setsampling0>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L49
  test   %esi,%esi
  je     L72
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rdx
  nopl   (%rax)
L34:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L34
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mulsd  %xmm0,%xmm2
  test   %r8d,%r8d
  je     L72
  lea    -0x1(%rcx),%edx
  movsd  D8(%rip),%xmm0
  xor    %edi,%edi
  lea    0x4(,%rdx,4),%r9
  xchg   %ax,%ax
L73:
  comisd %xmm2,%xmm0
  mov    $0x1,%edx
  ja     L2
  cvttsd2si %xmm2,%rdx
L2:
  test   %ecx,%ecx
  je     L20
  lea    (%rax,%r9,1),%rsi
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L7
L20:
  mulsd  %xmm1,%xmm2
  add    $0x1,%edi
  cmp    %edi,%r8d
  jne    L73
L72:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setsampling0(unsigned int *DownSmpl, unsigned int S, int continuous, unsigned int V, unsigned int J, double b0, double a0, double s0) {
  double da1;
  unsigned int s, j, v, ua1;
  if (continuous)
    for (s = 0; s < S; s++)
      DownSmpl[s] = 1;
  else {
    da1 = s0 * b0;
    for (j = 0; j < J; j++) {
      ua1 = (da1 < 1) ? 1 : (unsigned int)da1;
      for (v = 0; v < V; v++)
        *DownSmpl++ = ua1;
      da1 *= a0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setsampling0>:
  endbr64
  test   %edx,%edx
  je     L49
  mov    %esi,%r9d
  test   %esi,%esi
  je     L131
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L132
  mov    %esi,%edx
  movdqa D10(%rip),%xmm0
  mov    %rdi,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L16:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L16
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r9b
  je     L108
L47:
  mov    %eax,%edx
  movl   $0x1,(%rdi,%rdx,4)
  lea    0x1(%rax),%edx
  cmp    %edx,%r9d
  jbe    L131
  add    $0x2,%eax
  movl   $0x1,(%rdi,%rdx,4)
  cmp    %r9d,%eax
  jae    L131
  movl   $0x1,(%rdi,%rax,4)
  ret
  nopl   0x0(%rax)
L49:
  mulsd  %xmm0,%xmm2
  test   %r8d,%r8d
  je     L131
  mov    %ecx,%eax
  mov    %ecx,%r10d
  push   %r13
  movsd  D19(%rip),%xmm0
  shr    $0x2,%eax
  push   %r12
  and    $0xfffffffc,%r10d
  mov    %ecx,%esi
  push   %rbp
  lea    -0x1(%rax),%r11d
  lea    -0x1(%rcx),%ebp
  xor    %r9d,%r9d
  push   %rbx
  mov    %ebp,%eax
  mov    %r10d,%ebx
  add    $0x1,%r11
  shl    $0x2,%rbx
  lea    0x4(,%rax,4),%r12
  shl    $0x4,%r11
  nopl   0x0(%rax)
L6:
  comisd %xmm2,%xmm0
  mov    $0x1,%ecx
  ja     L34
  cvttsd2si %xmm2,%rcx
L34:
  test   %esi,%esi
  je     L8
  cmp    $0x2,%ebp
  jbe    L166
  movd   %ecx,%xmm4
  mov    %rdi,%rax
  lea    (%r11,%rdi,1),%rdx
  pshufd $0x0,%xmm4,%xmm3
  nopl   0x0(%rax)
L160:
  movups %xmm3,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L160
  lea    (%rdi,%rbx,1),%rdx
  mov    %r10d,%eax
  cmp    %r10d,%esi
  je     L113
L56:
  lea    0x1(%rax),%r13d
  mov    %ecx,(%rdx)
  cmp    %r13d,%esi
  jbe    L113
  add    $0x2,%eax
  mov    %ecx,0x4(%rdx)
  cmp    %eax,%esi
  jbe    L113
  mov    %ecx,0x8(%rdx)
L113:
  add    %r12,%rdi
L8:
  mulsd  %xmm1,%xmm2
  add    $0x1,%r9d
  cmp    %r9d,%r8d
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L166:
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L56
L131:
  ret
L108:
  ret
L132:
  xor    %eax,%eax
  jmp    L47
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: byte[16]
name: read_data
arguments: data_label: D19
type_infered: byte[8]

tool: {"D10": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void setsampling0(unsigned int *DownSmpl, unsigned int S, int continuous, unsigned int V, unsigned int J, double b0, double a0, double s0) {
  double da1;
  unsigned int s, j, v, ua1;
  if (continuous)
    for (s = 0; s < S; s++)
      DownSmpl[s] = 1;
  else {
    da1 = s0 * b0;
    for (j = 0; j < J; j++) {
      ua1 = (da1 < 1) ? 1 : (unsigned int)da1;
      for (v = 0; v < V; v++)
        *DownSmpl++ = ua1;
      da1 *= a0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L14
L27:
  cmpl   $0xa,-0x4(%rbp)
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L14
L21:
  mov    -0x4(%rbp),%eax
  sub    $0x7,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L14:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L27
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      printf("\n");
    else
      printf("%c", c - 7);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L31
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
L31:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L3
  cmp    $0xa,%eax
  je     L16
  lea    -0x7(%rax),%edi
  call   <putchar@plt>
  jmp    L31
L3:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      printf("\n");
    else
      printf("%c", c - 7);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
L1:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L27
L26:
  cmp    $0xa,%eax
  je     L25
  lea    -0x7(%rax),%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L26
L27:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L1
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      printf("\n");
    else
      printf("%c", c - 7);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L17
L4:
  cmp    $0xa,%eax
  je     L28
  lea    -0x7(%rax),%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L4
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L32
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\n')
      printf("\n");
    else
      printf("%c", c - 7);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_time_seconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtotime@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L8
  mov    $0xffffffff,%eax
  jmp    L9
L8:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int parse_time_seconds(const char **str, struct timespec *ts) {
  ts->tv_sec = strtotime(*str, str);
  return errno ? -1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_time_seconds>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    (%rdi),%rdi
  call   <strtotime@plt>
  mov    %eax,(%rbx)
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  neg    %rax
  sbb    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int parse_time_seconds(const char **str, struct timespec *ts) {
  ts->tv_sec = strtotime(*str, str);
  return errno ? -1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_time_seconds>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    (%rdi),%rdi
  call   <strtotime@plt>
  mov    %eax,(%rbx)
  mov    D6(%rip),%rax
  pop    %rbx
  mov    (%rax),%rax
  neg    %rax
  sbb    %eax,%eax
  ret
```

assistant: ```c
int parse_time_seconds(const char **str, struct timespec *ts) {
  ts->tv_sec = strtotime(*str, str);
  return errno ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checkname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <letter@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  jmp    L35
L31:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <letnum@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  jmp    L35
L1:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L31
  mov    $0x1,%eax
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int checkname(cp)
register char *cp;
{
  if (!letter(*cp++))
    return (0);
  while (*cp)
    if (!letnum(*cp++))
      return (0);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  mov    $0x0,%eax
  call   <letter@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  je     L9
L6:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L24
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <letnum@plt>
  test   %eax,%eax
  jne    L6
  jmp    L9
L24:
  mov    $0x1,%eax
L9:
  pop    %rbx
  ret
```

assistant: ```c
int checkname(cp)
register char *cp;
{
  if (!letter(*cp++))
    return (0);
  while (*cp)
    if (!letnum(*cp++))
      return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<checkname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <letter@plt>
  test   %eax,%eax
  jne    L6
  jmp    L39
  nopl   0x0(%rax)
L37:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <letnum@plt>
  test   %eax,%eax
  je     L39
L6:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L37
  mov    $0x1,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L39:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int checkname(cp)
register char *cp;
{
  if (!letter(*cp++))
    return (0);
  while (*cp)
    if (!letnum(*cp++))
      return (0);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checkname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <letter@plt>
  test   %eax,%eax
  jne    L12
  jmp    L34
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <letnum@plt>
  test   %eax,%eax
  je     L34
L12:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L6
  mov    $0x1,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L34:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int checkname(cp)
register char *cp;
{
  if (!letter(*cp++))
    return (0);
  while (*cp)
    if (!letnum(*cp++))
      return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<yahoo_f01_3e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  lea    D3(%rip),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <yahoo_M1TableCommon@plt>
  leave
  ret
```

assistant: ```c
int yahoo_f01_3e(int Salt, int Parameter) {
  static unsigned char Table[256] = {
      0x7B, 0x0F, 0x56, 0x2F, 0x1E, 0x2A, 0x7A, 0xD1, 0x02, 0x91, 0x4E, 0x37, 0x6C, 0x10, 0xA7, 0xF2, 0x38, 0xAC, 0x9E, 0x2B, 0x5E, 0x23, 0xE3, 0x19, 0x9B, 0xF6, 0xB0, 0x59, 0x14, 0xB9, 0xA9, 0x46, 0x84, 0x1D, 0xC0, 0x98, 0xF3, 0xE1, 0xE8, 0x94, 0x52, 0x35, 0xBA, 0xD8, 0x07, 0xEF, 0x31, 0xF8, 0x03, 0x76, 0x9C, 0xD7, 0xE4, 0x8B, 0xAF, 0x60, 0xDD, 0x51, 0x00, 0xDF, 0x11, 0x7F, 0x1C, 0xED, 0x49, 0xC9, 0xF4, 0x87, 0x64, 0xFC, 0x5D, 0xAD, 0x88, 0x85, 0xF7, 0x5A, 0x92, 0xDB, 0x72, 0x1A, 0x83, 0x15, 0x30, 0x24, 0x9F, 0xFF, 0x5B, 0xF1, 0xD2, 0xFD, 0xC2, 0xB5, 0x25, 0x22, 0x18, 0x3D, 0xCD, 0x97, 0x8C, 0xCC, 0x78, 0x90, 0xAA, 0x5F, 0x0A, 0x57, 0x05, 0x61, 0xD4, 0xA0, 0x3A, 0xDE, 0x3B, 0xF9, 0x65, 0x68, 0x4F, 0x28, 0xFA, 0xEB, 0x63, 0x2D, 0x8D, 0xD0, 0xA1, 0xFE, 0x12, 0x96, 0x3C, 0x42, 0x29, 0xD6, 0xA4, 0x34, 0xBD, 0x70, 0x89, 0xBE, 0xF5, 0x79, 0xAB, 0x8F, 0x32, 0xB4, 0xEE, 0xE7, 0x2C, 0x04, 0x4B, 0xD5, 0xB1, 0x54, 0xF0, 0xDA, 0x16, 0x77, 0xA6, 0x53, 0xB2, 0xE2, 0x73, 0xBF, 0x17, 0xA8, 0x75, 0x26, 0xE0, 0xBC, 0x0C, 0x71, 0xFB, 0x6D, 0x7E, 0xC5, 0xEA, 0x21, 0x9D, 0x95, 0x8E, 0xA5, 0x48, 0xB8, 0x7D, 0xCB, 0x01, 0x99, 0xE5, 0xBB, 0x82, 0xC4, 0xCA, 0xC1, 0x58, 0x6E, 0x5C, 0x7C, 0xDC, 0x33, 0xB6, 0xC3, 0x09, 0xC7, 0x1F, 0x0D, 0x43, 0x6F, 0xE9, 0x86, 0x27, 0xC8, 0x44, 0xB3, 0xD3, 0xCF, 0x08, 0x66, 0x1B, 0x20, 0x4D, 0xD9, 0xC6, 0x36, 0x40, 0x74, 0x62, 0x6A, 0x55, 0xEC, 0x06, 0x2E, 0xE6, 0x80, 0x13, 0x93, 0x50, 0xCE, 0x69, 0x3E, 0x67, 0x4A, 0x81, 0x4C, 0x0B, 0x3F, 0xB7, 0x0E, 0x39, 0xAE, 0x47, 0x6B, 0x8A, 0xA2, 0x9A, 0xA3, 0x45, 0x41,
  };
  return yahoo_M1TableCommon(Salt, Parameter, Table);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yahoo_f01_3e>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdx
  call   <yahoo_M1TableCommon@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yahoo_f01_3e(int Salt, int Parameter) {
  static unsigned char Table[256] = {
      0x7B, 0x0F, 0x56, 0x2F, 0x1E, 0x2A, 0x7A, 0xD1, 0x02, 0x91, 0x4E, 0x37, 0x6C, 0x10, 0xA7, 0xF2, 0x38, 0xAC, 0x9E, 0x2B, 0x5E, 0x23, 0xE3, 0x19, 0x9B, 0xF6, 0xB0, 0x59, 0x14, 0xB9, 0xA9, 0x46, 0x84, 0x1D, 0xC0, 0x98, 0xF3, 0xE1, 0xE8, 0x94, 0x52, 0x35, 0xBA, 0xD8, 0x07, 0xEF, 0x31, 0xF8, 0x03, 0x76, 0x9C, 0xD7, 0xE4, 0x8B, 0xAF, 0x60, 0xDD, 0x51, 0x00, 0xDF, 0x11, 0x7F, 0x1C, 0xED, 0x49, 0xC9, 0xF4, 0x87, 0x64, 0xFC, 0x5D, 0xAD, 0x88, 0x85, 0xF7, 0x5A, 0x92, 0xDB, 0x72, 0x1A, 0x83, 0x15, 0x30, 0x24, 0x9F, 0xFF, 0x5B, 0xF1, 0xD2, 0xFD, 0xC2, 0xB5, 0x25, 0x22, 0x18, 0x3D, 0xCD, 0x97, 0x8C, 0xCC, 0x78, 0x90, 0xAA, 0x5F, 0x0A, 0x57, 0x05, 0x61, 0xD4, 0xA0, 0x3A, 0xDE, 0x3B, 0xF9, 0x65, 0x68, 0x4F, 0x28, 0xFA, 0xEB, 0x63, 0x2D, 0x8D, 0xD0, 0xA1, 0xFE, 0x12, 0x96, 0x3C, 0x42, 0x29, 0xD6, 0xA4, 0x34, 0xBD, 0x70, 0x89, 0xBE, 0xF5, 0x79, 0xAB, 0x8F, 0x32, 0xB4, 0xEE, 0xE7, 0x2C, 0x04, 0x4B, 0xD5, 0xB1, 0x54, 0xF0, 0xDA, 0x16, 0x77, 0xA6, 0x53, 0xB2, 0xE2, 0x73, 0xBF, 0x17, 0xA8, 0x75, 0x26, 0xE0, 0xBC, 0x0C, 0x71, 0xFB, 0x6D, 0x7E, 0xC5, 0xEA, 0x21, 0x9D, 0x95, 0x8E, 0xA5, 0x48, 0xB8, 0x7D, 0xCB, 0x01, 0x99, 0xE5, 0xBB, 0x82, 0xC4, 0xCA, 0xC1, 0x58, 0x6E, 0x5C, 0x7C, 0xDC, 0x33, 0xB6, 0xC3, 0x09, 0xC7, 0x1F, 0x0D, 0x43, 0x6F, 0xE9, 0x86, 0x27, 0xC8, 0x44, 0xB3, 0xD3, 0xCF, 0x08, 0x66, 0x1B, 0x20, 0x4D, 0xD9, 0xC6, 0x36, 0x40, 0x74, 0x62, 0x6A, 0x55, 0xEC, 0x06, 0x2E, 0xE6, 0x80, 0x13, 0x93, 0x50, 0xCE, 0x69, 0x3E, 0x67, 0x4A, 0x81, 0x4C, 0x0B, 0x3F, 0xB7, 0x0E, 0x39, 0xAE, 0x47, 0x6B, 0x8A, 0xA2, 0x9A, 0xA3, 0x45, 0x41,
  };
  return yahoo_M1TableCommon(Salt, Parameter, Table);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<yahoo_f01_3e>:
  endbr64
  lea    D0(%rip),%rdx
  jmp    1050 <yahoo_M1TableCommon@plt>
```

assistant: ```c
int yahoo_f01_3e(int Salt, int Parameter) {
  static unsigned char Table[256] = {
      0x7B, 0x0F, 0x56, 0x2F, 0x1E, 0x2A, 0x7A, 0xD1, 0x02, 0x91, 0x4E, 0x37, 0x6C, 0x10, 0xA7, 0xF2, 0x38, 0xAC, 0x9E, 0x2B, 0x5E, 0x23, 0xE3, 0x19, 0x9B, 0xF6, 0xB0, 0x59, 0x14, 0xB9, 0xA9, 0x46, 0x84, 0x1D, 0xC0, 0x98, 0xF3, 0xE1, 0xE8, 0x94, 0x52, 0x35, 0xBA, 0xD8, 0x07, 0xEF, 0x31, 0xF8, 0x03, 0x76, 0x9C, 0xD7, 0xE4, 0x8B, 0xAF, 0x60, 0xDD, 0x51, 0x00, 0xDF, 0x11, 0x7F, 0x1C, 0xED, 0x49, 0xC9, 0xF4, 0x87, 0x64, 0xFC, 0x5D, 0xAD, 0x88, 0x85, 0xF7, 0x5A, 0x92, 0xDB, 0x72, 0x1A, 0x83, 0x15, 0x30, 0x24, 0x9F, 0xFF, 0x5B, 0xF1, 0xD2, 0xFD, 0xC2, 0xB5, 0x25, 0x22, 0x18, 0x3D, 0xCD, 0x97, 0x8C, 0xCC, 0x78, 0x90, 0xAA, 0x5F, 0x0A, 0x57, 0x05, 0x61, 0xD4, 0xA0, 0x3A, 0xDE, 0x3B, 0xF9, 0x65, 0x68, 0x4F, 0x28, 0xFA, 0xEB, 0x63, 0x2D, 0x8D, 0xD0, 0xA1, 0xFE, 0x12, 0x96, 0x3C, 0x42, 0x29, 0xD6, 0xA4, 0x34, 0xBD, 0x70, 0x89, 0xBE, 0xF5, 0x79, 0xAB, 0x8F, 0x32, 0xB4, 0xEE, 0xE7, 0x2C, 0x04, 0x4B, 0xD5, 0xB1, 0x54, 0xF0, 0xDA, 0x16, 0x77, 0xA6, 0x53, 0xB2, 0xE2, 0x73, 0xBF, 0x17, 0xA8, 0x75, 0x26, 0xE0, 0xBC, 0x0C, 0x71, 0xFB, 0x6D, 0x7E, 0xC5, 0xEA, 0x21, 0x9D, 0x95, 0x8E, 0xA5, 0x48, 0xB8, 0x7D, 0xCB, 0x01, 0x99, 0xE5, 0xBB, 0x82, 0xC4, 0xCA, 0xC1, 0x58, 0x6E, 0x5C, 0x7C, 0xDC, 0x33, 0xB6, 0xC3, 0x09, 0xC7, 0x1F, 0x0D, 0x43, 0x6F, 0xE9, 0x86, 0x27, 0xC8, 0x44, 0xB3, 0xD3, 0xCF, 0x08, 0x66, 0x1B, 0x20, 0x4D, 0xD9, 0xC6, 0x36, 0x40, 0x74, 0x62, 0x6A, 0x55, 0xEC, 0x06, 0x2E, 0xE6, 0x80, 0x13, 0x93, 0x50, 0xCE, 0x69, 0x3E, 0x67, 0x4A, 0x81, 0x4C, 0x0B, 0x3F, 0xB7, 0x0E, 0x39, 0xAE, 0x47, 0x6B, 0x8A, 0xA2, 0x9A, 0xA3, 0x45, 0x41,
  };
  return yahoo_M1TableCommon(Salt, Parameter, Table);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yahoo_f01_3e>:
  endbr64
  lea    D3(%rip),%rdx
  jmp    1050 <yahoo_M1TableCommon@plt>
```

assistant: ```c
int yahoo_f01_3e(int Salt, int Parameter) {
  static unsigned char Table[256] = {
      0x7B, 0x0F, 0x56, 0x2F, 0x1E, 0x2A, 0x7A, 0xD1, 0x02, 0x91, 0x4E, 0x37, 0x6C, 0x10, 0xA7, 0xF2, 0x38, 0xAC, 0x9E, 0x2B, 0x5E, 0x23, 0xE3, 0x19, 0x9B, 0xF6, 0xB0, 0x59, 0x14, 0xB9, 0xA9, 0x46, 0x84, 0x1D, 0xC0, 0x98, 0xF3, 0xE1, 0xE8, 0x94, 0x52, 0x35, 0xBA, 0xD8, 0x07, 0xEF, 0x31, 0xF8, 0x03, 0x76, 0x9C, 0xD7, 0xE4, 0x8B, 0xAF, 0x60, 0xDD, 0x51, 0x00, 0xDF, 0x11, 0x7F, 0x1C, 0xED, 0x49, 0xC9, 0xF4, 0x87, 0x64, 0xFC, 0x5D, 0xAD, 0x88, 0x85, 0xF7, 0x5A, 0x92, 0xDB, 0x72, 0x1A, 0x83, 0x15, 0x30, 0x24, 0x9F, 0xFF, 0x5B, 0xF1, 0xD2, 0xFD, 0xC2, 0xB5, 0x25, 0x22, 0x18, 0x3D, 0xCD, 0x97, 0x8C, 0xCC, 0x78, 0x90, 0xAA, 0x5F, 0x0A, 0x57, 0x05, 0x61, 0xD4, 0xA0, 0x3A, 0xDE, 0x3B, 0xF9, 0x65, 0x68, 0x4F, 0x28, 0xFA, 0xEB, 0x63, 0x2D, 0x8D, 0xD0, 0xA1, 0xFE, 0x12, 0x96, 0x3C, 0x42, 0x29, 0xD6, 0xA4, 0x34, 0xBD, 0x70, 0x89, 0xBE, 0xF5, 0x79, 0xAB, 0x8F, 0x32, 0xB4, 0xEE, 0xE7, 0x2C, 0x04, 0x4B, 0xD5, 0xB1, 0x54, 0xF0, 0xDA, 0x16, 0x77, 0xA6, 0x53, 0xB2, 0xE2, 0x73, 0xBF, 0x17, 0xA8, 0x75, 0x26, 0xE0, 0xBC, 0x0C, 0x71, 0xFB, 0x6D, 0x7E, 0xC5, 0xEA, 0x21, 0x9D, 0x95, 0x8E, 0xA5, 0x48, 0xB8, 0x7D, 0xCB, 0x01, 0x99, 0xE5, 0xBB, 0x82, 0xC4, 0xCA, 0xC1, 0x58, 0x6E, 0x5C, 0x7C, 0xDC, 0x33, 0xB6, 0xC3, 0x09, 0xC7, 0x1F, 0x0D, 0x43, 0x6F, 0xE9, 0x86, 0x27, 0xC8, 0x44, 0xB3, 0xD3, 0xCF, 0x08, 0x66, 0x1B, 0x20, 0x4D, 0xD9, 0xC6, 0x36, 0x40, 0x74, 0x62, 0x6A, 0x55, 0xEC, 0x06, 0x2E, 0xE6, 0x80, 0x13, 0x93, 0x50, 0xCE, 0x69, 0x3E, 0x67, 0x4A, 0x81, 0x4C, 0x0B, 0x3F, 0xB7, 0x0E, 0x39, 0xAE, 0x47, 0x6B, 0x8A, 0xA2, 0x9A, 0xA3, 0x45, 0x41,
  };
  return yahoo_M1TableCommon(Salt, Parameter, Table);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<detectPresence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x206863696877,%rax
  mov    $0x0,%edx
  mov    %rax,-0x410(%rbp)
  mov    %rdx,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x828(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x410(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x818(%rbp)
  mov    -0x818(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L38
  lea    -0x810(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L38
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  mov    $0x1,%eax
  jmp    L13
L38:
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string

tool: D5: r

assistant: ```c
int detectPresence(char const *const aExecutable) {
  char lBuff[1024];
  char lTestedString[1024] = "which ";
  FILE *lIn;
  strcat(lTestedString, aExecutable);
  lIn = popen(lTestedString, "r");
  if ((fgets(lBuff, sizeof(lBuff), lIn) != NULL) && (!strchr(lBuff, ':'))) {
    pclose(lIn);
    return 1;
  } else {
    pclose(lIn);
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<detectPresence>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  movabs $0x206863696877,%rax
  mov    $0x0,%edx
  mov    %rax,0x400(%rsp)
  mov    %rdx,0x408(%rsp)
  lea    0x410(%rsp),%rdi
  mov    $0x7e,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x400(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    %rax,%rdx
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L8
  mov    %rsp,%rdi
  mov    $0x3a,%esi
  call   <strchr@plt>
  test   %eax,%eax
  je     L33
L8:
  mov    %rbx,%rdi
  call   <pclose@plt>
  mov    $0x0,%eax
L1:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x810,%rsp
  pop    %rbx
  ret
L33:
  mov    %rbx,%rdi
  call   <pclose@plt>
  mov    $0x1,%eax
  jmp    L1
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: r

assistant: ```c
int detectPresence(char const *const aExecutable) {
  char lBuff[1024];
  char lTestedString[1024] = "which ";
  FILE *lIn;
  strcat(lTestedString, aExecutable);
  lIn = popen(lTestedString, "r");
  if ((fgets(lBuff, sizeof(lBuff), lIn) != NULL) && (!strchr(lBuff, ':'))) {
    pclose(lIn);
    return 1;
  } else {
    pclose(lIn);
    return 0;
  }
}
```