ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x21,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  cmp    $0x4,%eax
  ja     L43
  lea    D3(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D74(%rip),%rdi
  call   <printf@plt>
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D55(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D74
type_guessed: string
name: read_data
arguments: data_tag: D34
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D55
type_guessed: string
name: read_data
arguments: data_tag: D69
type_guessed: string

tool: D33:  Think of your question and enter your favorite number?


tool: D39: %d

tool: D74:  Definitely not


tool: D34:  Ask again


tool: D7:  Outcome unclear


tool: D55:  Absolutely certain


tool: D69:  The answer is no


assistant: ```c
int main() {
  int x;
  int chose;
  printf(" Think of your question and enter your favorite number?\n");
  scanf("%d", &x);
  srand(time(NULL));
  chose = rand() % 5;
  switch (chose) {
  case 0:
    printf(" Outcome unclear\n");
    break;
  case 1:
    printf(" Absolutely certain\n");
    break;
  case 2:
    printf(" The answer is no\n");
    break;
  case 3:
    printf(" Ask again\n");
    break;
  case 4:
    printf(" Definitely not\n");
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L38
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L38:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L12
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L12
L50:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L8
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L8:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L12:
  cmpl   $0x1,-0x4(%rbp)
  jne    L50
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D3: Number required!

tool: D39: Number MUST be greater than zero.

tool: D8: %d 

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  if (argc != 2) {
    printf("Number required!\n");
    exit(1);
  }
  n = atoi(argv[1]);
  if (n <= 0) {
    printf("Number MUST be greater than zero.\n");
    exit(1);
  }
  while (n != 1) {
    printf("%d ", n);
    if (n % 2 == 0) {
      n = n / 2;
    } else {
      n = 3 * n + 1;
    }
  }
  printf("%d\n", n);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L75
L63:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L85
  cmp    $0x1,%eax
  je     L3
L50:
  lea    D23(%rip),%rbp
  jmp    L52
L75:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L63
L85:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L50
L67:
  lea    0x1(%rbx,%rbx,2),%ebx
L4:
  cmp    $0x1,%ebx
  je     L3
L52:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   $0x1,%bl
  jne    L67
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  sar    %ebx
  jmp    L4
L3:
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D34
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D23: %d 

tool: D34: Number required!

tool: D14: Number MUST be greater than zero.

tool: D19: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  if (argc != 2) {
    printf("Number required!\n");
    exit(1);
  }
  n = atoi(argv[1]);
  if (n <= 0) {
    printf("Number MUST be greater than zero.\n");
    exit(1);
  }
  while (n != 1) {
    printf("%d ", n);
    if (n % 2 == 0) {
      n = n / 2;
    } else {
      n = 3 * n + 1;
    }
  }
  printf("%d\n", n);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L6
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L67
  cmp    $0x1,%eax
  je     L34
L64:
  lea    D1(%rip),%rbp
  jmp    L9
  nopl   (%rax)
L3:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  sar    %ebx
  cmp    $0x1,%ebx
  je     L34
L9:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   $0x1,%bl
  je     L3
  lea    0x1(%rbx,%rbx,2),%ebx
  cmp    $0x1,%ebx
  jne    L9
L34:
  mov    $0x1,%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L67:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L64
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D24
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D14: Number required!

tool: D1: %d 

tool: D24: %d


tool: D19: Number MUST be greater than zero.

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  if (argc != 2) {
    printf("Number required!\n");
    exit(1);
  }
  n = atoi(argv[1]);
  if (n <= 0) {
    printf("Number MUST be greater than zero.\n");
    exit(1);
  }
  while (n != 1) {
    printf("%d ", n);
    if (n % 2 == 0) {
      n = n / 2;
    } else {
      n = 3 * n + 1;
    }
  }
  printf("%d\n", n);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L36
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L36:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L52
  cmp    $0x1,%eax
  je     L6
L35:
  lea    D31(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  test   $0x1,%bl
  jne    L33
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  sar    %ebx
  cmp    $0x1,%ebx
  jne    L15
L6:
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  lea    0x1(%rbx,%rbx,2),%ebx
  jmp    L15
L52:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string

tool: D38: Number required!

tool: D31: %d 

tool: D19: %d


tool: D32: Number MUST be greater than zero.

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  if (argc != 2) {
    printf("Number required!\n");
    exit(1);
  }
  n = atoi(argv[1]);
  if (n <= 0) {
    printf("Number MUST be greater than zero.\n");
    exit(1);
  }
  while (n != 1) {
    printf("%d ", n);
    if (n % 2 == 0) {
      n = n / 2;
    } else {
      n = 3 * n + 1;
    }
  }
  printf("%d\n", n);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *array, int i, int j) {
  int t = array[i];
  array[i] = array[j];
  array[j] = t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *array, int i, int j) {
  int t = array[i];
  array[i] = array[j];
  array[j] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *array, int i, int j) {
  int t = array[i];
  array[i] = array[j];
  array[j] = t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *array, int i, int j) {
  int t = array[i];
  array[i] = array[j];
  array[j] = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<p_secstodate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x76c(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%esi
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    0x14(%rax),%r8d
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%edi
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  push   %rsi
  push   %rcx
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string

tool: D15: %04d%02d%02d%02d%02d%02d

assistant: ```c
char *p_secstodate(u_long secs) {
  static char output[15];
  time_t clock = (time_t)secs;
  struct tm *time;
  time = gmtime(&clock);
  time->tm_year += 1900;
  time->tm_mon += 1;
  sprintf(output, "%04d%02d%02d%02d%02d%02d", time->tm_year, time->tm_mon, time->tm_mday, time->tm_hour, time->tm_min, time->tm_sec);
  return (output);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p_secstodate>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    (%rax),%ebx
  lea    0x76c(%rbx),%edx
  mov    %edx,(%rax)
  mov    0x4(%rax),%ecx
  add    $0x1,%ecx
  mov    %ecx,0x4(%rax)
  mov    0x14(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0xc(%rax),%esi
  push   %rsi
  mov    0x10(%rax),%eax
  push   %rax
  lea    D4(%rip),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: %04d%02d%02d%02d%02d%02d

assistant: ```c
char *p_secstodate(u_long secs) {
  static char output[15];
  time_t clock = (time_t)secs;
  struct tm *time;
  time = gmtime(&clock);
  time->tm_year += 1900;
  time->tm_mon += 1;
  sprintf(output, "%04d%02d%02d%02d%02d%02d", time->tm_year, time->tm_mon, time->tm_mday, time->tm_hour, time->tm_min, time->tm_sec);
  return (output);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<p_secstodate>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    %r12,%rdi
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  mov    0xc(%rax),%esi
  mov    0x14(%rax),%r9d
  add    $0x76c,%edx
  add    $0x1,%ecx
  mov    0x8(%rax),%r8d
  mov    %edx,(%rax)
  mov    %ecx,0x4(%rax)
  push   %rsi
  mov    0x10(%rax),%eax
  lea    D8(%rip),%rsi
  push   %rax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: %04d%02d%02d%02d%02d%02d

assistant: ```c
char *p_secstodate(u_long secs) {
  static char output[15];
  time_t clock = (time_t)secs;
  struct tm *time;
  time = gmtime(&clock);
  time->tm_year += 1900;
  time->tm_mon += 1;
  sprintf(output, "%04d%02d%02d%02d%02d%02d", time->tm_year, time->tm_mon, time->tm_mday, time->tm_hour, time->tm_min, time->tm_sec);
  return (output);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<p_secstodate>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    %r12,%rdi
  movq   D2(%rip),%xmm1
  movq   (%rax),%xmm0
  mov    0xc(%rax),%esi
  mov    0x14(%rax),%r9d
  mov    0x8(%rax),%r8d
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rax)
  movd   %xmm0,%edx
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%ecx
  push   %rsi
  mov    0x10(%rax),%eax
  lea    D10(%rip),%rsi
  push   %rax
  call   <sprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type: byte[8]
name: disassemble_data
arguments: label: D10
type: string

tool: {"D2": [0x6c,0x07,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D10: %04d%02d%02d%02d%02d%02d

assistant: ```c
char *p_secstodate(u_long secs) {
  static char output[15];
  time_t clock = (time_t)secs;
  struct tm *time;
  time = gmtime(&clock);
  time->tm_year += 1900;
  time->tm_mon += 1;
  sprintf(output, "%04d%02d%02d%02d%02d%02d", time->tm_year, time->tm_mon, time->tm_mday, time->tm_hour, time->tm_min, time->tm_sec);
  return (output);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simplesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L32:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L48
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L48:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
L12:
  cmpl   $0x0,-0xc(%rbp)
  jg     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void simplesort(int *a, int n) {
  int i, j, aux;
  i = 1;
  for (; i > 0;) {
    i = 0;
    for (j = 0; j < n - 1; j++)
      if (a[j] > a[j + 1]) {
        i++;
        aux = a[j + 1];
        a[j + 1] = a[j];
        a[j] = aux;
      }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<simplesort>:
  endbr64
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r9
  jmp    L60
L48:
  add    $0x4,%rax
  cmp    %r9,%rax
  je     L5
L13:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L48
  add    $0x1,%r8d
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L48
L5:
  test   %r8d,%r8d
  jle    L41
L60:
  cmp    $0x1,%esi
  jle    L41
  mov    %rdi,%rax
  mov    $0x0,%r8d
  jmp    L13
L41:
  ret
```

assistant: ```c
void simplesort(int *a, int n) {
  int i, j, aux;
  i = 1;
  for (; i > 0;) {
    i = 0;
    for (j = 0; j < n - 1; j++)
      if (a[j] > a[j + 1]) {
        i++;
        aux = a[j + 1];
        a[j + 1] = a[j];
        a[j] = aux;
      }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simplesort>:
  endbr64
  lea    -0x1(%rsi),%r10d
  xor    %edx,%edx
  xor    %r9d,%r9d
  nopl   (%rax)
L52:
  cmp    %r10d,%edx
  jge    L41
L58:
  movslq %edx,%rax
  add    $0x1,%edx
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  add    $0x4,%rax
L45:
  add    %rdi,%rax
  mov    (%r8),%esi
  mov    (%rax),%ecx
  cmp    %ecx,%esi
  jle    L52
  mov    %esi,(%rax)
  add    $0x1,%r9d
  mov    %ecx,(%r8)
  cmp    %r10d,%edx
  jl     L58
L41:
  test   %r9d,%r9d
  je     L28
  test   %r10d,%r10d
  jle    L28
  mov    %rdi,%r8
  mov    $0x1,%edx
  mov    $0x4,%eax
  xor    %r9d,%r9d
  jmp    L45
  nopl   (%rax)
L28:
  ret
```

assistant: ```c
void simplesort(int *a, int n) {
  int i, j, aux;
  i = 1;
  for (; i > 0;) {
    i = 0;
    for (j = 0; j < n - 1; j++)
      if (a[j] > a[j + 1]) {
        i++;
        aux = a[j + 1];
        a[j + 1] = a[j];
        a[j] = aux;
      }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<simplesort>:
  endbr64
  lea    -0x1(%rsi),%r10d
  xor    %edx,%edx
  xor    %r9d,%r9d
  test   %r10d,%r10d
  jle    L14
  nopw   0x0(%rax,%rax,1)
L34:
  cmp    %edx,%r10d
  jle    L3
L15:
  movslq %edx,%rax
  add    $0x1,%edx
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  add    $0x4,%rax
L0:
  add    %rdi,%rax
  mov    (%rcx),%r8d
  mov    (%rax),%esi
  cmp    %esi,%r8d
  jle    L34
  mov    %r8d,(%rax)
  add    $0x1,%r9d
  mov    %esi,(%rcx)
  cmp    %edx,%r10d
  jg     L15
L3:
  test   %r9d,%r9d
  je     L30
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%eax
  xor    %r9d,%r9d
  jmp    L0
L30:
  ret
L14:
  ret
```

assistant: ```c
void simplesort(int *a, int n) {
  int i, j, aux;
  i = 1;
  for (; i > 0;) {
    i = 0;
    for (j = 0; j < n - 1; j++)
      if (a[j] > a[j + 1]) {
        i++;
        aux = a[j + 1];
        a[j + 1] = a[j];
        a[j] = aux;
      }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<addNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  ja     L17
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <addChar@plt>
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <addNum>
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <addNum>
L4:
  nop
  leave
  ret
```

assistant: ```c
void addNum(unsigned int n, unsigned int *i) {
  if (n < 10) {
    addChar(((char)((n % 10) + ((unsigned int)('0')))), i);
  } else {
    addNum(n / 10, i);
    addNum(n % 10, i);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addNum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  cmp    $0x9,%edi
  ja     L4
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  movsbl %dil,%edi
  call   <addChar@plt>
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %edi,%r12d
  mov    $0xcccccccd,%eax
  imul   %rax,%r12
  shr    $0x23,%r12
  mov    %r12d,%edi
  call   <addNum>
  lea    (%r12,%r12,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <addNum>
  jmp    L11
```

assistant: ```c
void addNum(unsigned int n, unsigned int *i) {
  if (n < 10) {
    addChar(((char)((n % 10) + ((unsigned int)('0')))), i);
  } else {
    addNum(n / 10, i);
    addNum(n % 10, i);
  }
}
```