ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  movl   $0x2a,(%rax)
  jmp    L1
L7:
  mov    -0x8(%rbp),%rax
  movl   $0x2b,(%rax)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *test_4(void) {
  int *ptr = (int *)malloc(sizeof(int));
  if (ptr)
    *ptr = 42;
  else
    *ptr = 43;
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  cmp    $0x1,%rax
  mov    $0x2a,%edx
  adc    $0x0,%edx
  mov    %edx,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *test_4(void) {
  int *ptr = (int *)malloc(sizeof(int));
  if (ptr)
    *ptr = 42;
  else
    *ptr = 43;
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L0
  movl   $0x0,0x0
  ud2
  nopl   0x0(%rax)
L0:
  movl   $0x2a,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *test_4(void) {
  int *ptr = (int *)malloc(sizeof(int));
  if (ptr)
    *ptr = 42;
  else
    *ptr = 43;
  return ptr;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L9
  movl   $0x0,0x0
  ud2
  nopl   0x0(%rax)
L9:
  movl   $0x2a,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *test_4(void) {
  int *ptr = (int *)malloc(sizeof(int));
  if (ptr)
    *ptr = 42;
  else
    *ptr = 43;
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0x8000000000000000,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x20,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long foo(void) {
  long long C = 1ULL << 63, X;
  int Y = 32;
  X = C >> (Y & 31);
  return X;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  movabs $0x8000000000000000,%rax
  ret
```

assistant: ```c
long long foo(void) {
  long long C = 1ULL << 63, X;
  int Y = 32;
  X = C >> (Y & 31);
  return X;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  movabs $0x8000000000000000,%rax
  ret
```

assistant: ```c
long long foo(void) {
  long long C = 1ULL << 63, X;
  int Y = 32;
  X = C >> (Y & 31);
  return X;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  movabs $0x8000000000000000,%rax
  ret
```

assistant: ```c
long long foo(void) {
  long long C = 1ULL << 63, X;
  int Y = 32;
  X = C >> (Y & 31);
  return X;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_trigger_from_trigfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  movss  %xmm0,-0x8c(%rbp)
  mov    %rsi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
L26:
  mov    -0x88(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L12
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  movzbl -0x60(%rbp),%eax
  cmp    $0x23,%al
  je     L26
  movzbl -0x60(%rbp),%eax
  cmp    $0xa,%al
  jne    L5
  jmp    L26
L5:
  mov    -0x70(%rbp),%rax
  lea    -0x70(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x70(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x6d,%eax
  je     L6
  cmp    $0x73,%eax
  je     L51
  jmp    L8
L6:
  movsd  -0x68(%rbp),%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  mov    -0x70(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x70(%rbp)
L51:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8c(%rbp),%xmm0
  movsd  -0x68(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  mov    -0x70(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x70(%rbp)
L8:
  movsd  -0x68(%rbp),%xmm0
  cvttsd2si %xmm0,%rdx
  mov    -0x98(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x70(%rbp),%rax
  lea    -0x70(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x74(%rbp)
L12:
  nop
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: f64

tool: D4: 1000

assistant: ```c
int read_trigger_from_trigfile(FILE *triggerfile, float sfreq, long *trigpoint) {
  char buffer[80];
  int code = 0;
  do {
    if (fgets(buffer, 80, triggerfile) != NULL) {
      char *inbuffer = buffer;
      double trigpos;
      if (*buffer == '#' || *buffer == '\n')
        continue;
      trigpos = strtod(inbuffer, &inbuffer);
      switch (*inbuffer) {
      case 'm':
        trigpos /= 1000.0;
        inbuffer++;
      case 's':
        trigpos *= sfreq;
        inbuffer++;
      default:
        *trigpoint = (long)trigpos;
        break;
      }
      code = strtol(inbuffer, &inbuffer, 10);
    }
    break;
  } while (1);
  return code;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_trigger_from_trigfile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%rbx
  movss  %xmm0,0xc(%rsp)
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
L34:
  mov    %rbx,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L59
  mov    %rbp,0x18(%rsp)
  movzbl 0x20(%rsp),%eax
  cmp    $0x23,%al
  je     L34
  cmp    $0xa,%al
  je     L34
  lea    0x18(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  call   <strtod@plt>
  mov    0x18(%rsp),%rdx
  movzbl (%rdx),%eax
  cmp    $0x6d,%al
  je     L13
  cmp    $0x73,%al
  jne    L14
L48:
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  addq   $0x1,0x18(%rsp)
L14:
  cvttsd2si %xmm0,%rax
  mov    %rax,(%r12)
  lea    0x18(%rsp),%rsi
  mov    $0xa,%edx
  mov    0x18(%rsp),%rdi
  call   <strtol@plt>
L40:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  divsd  D7(%rip),%xmm0
  add    $0x1,%rdx
  mov    %rdx,0x18(%rsp)
  jmp    L48
L59:
  mov    $0x0,%eax
  jmp    L40
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: f64

tool: D7: 1000

assistant: ```c
int read_trigger_from_trigfile(FILE *triggerfile, float sfreq, long *trigpoint) {
  char buffer[80];
  int code = 0;
  do {
    if (fgets(buffer, 80, triggerfile) != NULL) {
      char *inbuffer = buffer;
      double trigpos;
      if (*buffer == '#' || *buffer == '\n')
        continue;
      trigpos = strtod(inbuffer, &inbuffer);
      switch (*inbuffer) {
      case 'm':
        trigpos /= 1000.0;
        inbuffer++;
      case 's':
        trigpos *= sfreq;
        inbuffer++;
      default:
        *trigpoint = (long)trigpos;
        break;
      }
      code = strtol(inbuffer, &inbuffer, 10);
    }
    break;
  } while (1);
  return code;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_trigger_from_trigfile>:
  endbr64
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
L37:
  mov    %r12,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L36
  movzbl 0x10(%rsp),%eax
  mov    %rbp,0x8(%rsp)
  cmp    $0x23,%al
  je     L37
  cmp    $0xa,%al
  je     L37
  lea    0x8(%rsp),%r12
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strtod@plt>
  mov    0x8(%rsp),%rdi
  movzbl (%rdi),%eax
  cmp    $0x6d,%al
  je     L16
  cmp    $0x73,%al
  je     L71
L30:
  cvttsd2si %xmm0,%rax
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  call   <strtol@plt>
L61:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax)
L16:
  add    $0x1,%rdi
  divsd  D5(%rip),%xmm0
L71:
  movd   %r14d,%xmm2
  pxor   %xmm1,%xmm1
  add    $0x1,%rdi
  cvtss2sd %xmm2,%xmm1
  mov    %rdi,0x8(%rsp)
  mulsd  %xmm1,%xmm0
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %eax,%eax
  jmp    L61
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: f64

tool: D5: 1000

assistant: ```c
int read_trigger_from_trigfile(FILE *triggerfile, float sfreq, long *trigpoint) {
  char buffer[80];
  int code = 0;
  do {
    if (fgets(buffer, 80, triggerfile) != NULL) {
      char *inbuffer = buffer;
      double trigpos;
      if (*buffer == '#' || *buffer == '\n')
        continue;
      trigpos = strtod(inbuffer, &inbuffer);
      switch (*inbuffer) {
      case 'm':
        trigpos /= 1000.0;
        inbuffer++;
      case 's':
        trigpos *= sfreq;
        inbuffer++;
      default:
        *trigpoint = (long)trigpos;
        break;
      }
      code = strtol(inbuffer, &inbuffer, 10);
    }
    break;
  } while (1);
  return code;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_trigger_from_trigfile>:
  endbr64
  push   %r14
  movd   %xmm0,%r14d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
L63:
  mov    %r12,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L40
  movzbl 0x10(%rsp),%eax
  mov    %rbp,0x8(%rsp)
  cmp    $0x23,%al
  je     L63
  cmp    $0xa,%al
  je     L63
  lea    0x8(%rsp),%r12
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strtod@plt>
  mov    0x8(%rsp),%rdi
  movzbl (%rdi),%eax
  cmp    $0x6d,%al
  je     L15
  cmp    $0x73,%al
  je     L32
L78:
  cvttsd2si %xmm0,%rax
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    %rax,(%rbx)
  call   <strtol@plt>
L66:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  add    $0x1,%rdi
  divsd  D8(%rip),%xmm0
L32:
  movd   %r14d,%xmm2
  pxor   %xmm1,%xmm1
  add    $0x1,%rdi
  cvtss2sd %xmm2,%xmm1
  mov    %rdi,0x8(%rsp)
  mulsd  %xmm1,%xmm0
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  jmp    L66
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_infered: f64

tool: D8: 1000

assistant: ```c
int read_trigger_from_trigfile(FILE *triggerfile, float sfreq, long *trigpoint) {
  char buffer[80];
  int code = 0;
  do {
    if (fgets(buffer, 80, triggerfile) != NULL) {
      char *inbuffer = buffer;
      double trigpos;
      if (*buffer == '#' || *buffer == '\n')
        continue;
      trigpos = strtod(inbuffer, &inbuffer);
      switch (*inbuffer) {
      case 'm':
        trigpos /= 1000.0;
        inbuffer++;
      case 's':
        trigpos *= sfreq;
        inbuffer++;
      default:
        *trigpoint = (long)trigpos;
        break;
      }
      code = strtol(inbuffer, &inbuffer, 10);
    }
    break;
  } while (1);
  return code;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sortSelect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L44
L4:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L43
L37:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L40
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L40:
  addl   $0x1,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L37
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L44:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sortSelect(int *arr, int size) {
  int i;
  for (i = 0; i < size - 1; i++) {
    int *e, *m;
    e = m = &(arr[i]);
    int j;
    for (j = i; j < size; j++) {
      if (arr[j] < *m)
        m = &(arr[j]);
    }
    int t = *e;
    *e = *m;
    *m = t;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sortSelect>:
  endbr64
  cmp    $0x1,%esi
  jle    L32
  push   %r14
  push   %rbx
  mov    %esi,%r9d
  lea    -0x2(%rsi),%r11d
  mov    %rdi,%r8
  mov    $0x0,%esi
  lea    -0x1(%r9),%ebx
  lea    0x4(%rdi),%r10
  jmp    L1
L5:
  mov    %rax,%rsi
L1:
  mov    %r8,%rdi
  cmp    %esi,%r9d
  jle    L12
  mov    %ebx,%eax
  sub    %esi,%eax
  add    %rsi,%rax
  lea    (%r10,%rax,4),%rcx
  mov    %r8,%rax
  mov    %r8,%rdx
L59:
  mov    (%rdx),%r14d
  cmp    %r14d,(%rax)
  cmovl  %rax,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L59
L29:
  mov    (%rdi),%eax
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi)
  mov    %eax,(%rdx)
  lea    0x1(%rsi),%rax
  add    $0x4,%r8
  cmp    %r11,%rsi
  jne    L5
  pop    %rbx
  pop    %r14
  ret
L12:
  mov    %r8,%rdx
  jmp    L29
L32:
  ret
```

assistant: ```c
void sortSelect(int *arr, int size) {
  int i;
  for (i = 0; i < size - 1; i++) {
    int *e, *m;
    e = m = &(arr[i]);
    int j;
    for (j = i; j < size; j++) {
      if (arr[j] < *m)
        m = &(arr[j]);
    }
    int t = *e;
    *e = *m;
    *m = t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sortSelect>:
  endbr64
  cmp    $0x1,%esi
  jle    L50
  mov    %rdi,%r9
  xor    %r10d,%r10d
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  lea    -0x2(%rsi),%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%r9),%r11d
  cmp    %r10d,%esi
  jle    L75
  nopl   (%rax)
L20:
  mov    %r12d,%eax
  mov    %r11d,%ecx
  mov    %r9,%r8
  sub    %r10d,%eax
  add    %r10,%rax
  lea    (%rbx,%rax,4),%rdi
  mov    %r9,%rax
L12:
  cmp    %rdi,%rax
  je     L63
L48:
  mov    0x4(%rax),%edx
  add    $0x4,%rax
  cmp    %edx,%ecx
  jle    L12
  mov    %rax,%r8
  mov    %edx,%ecx
  cmp    %rdi,%rax
  jne    L48
L63:
  mov    %ecx,(%r9)
  lea    0x1(%r10),%rax
  add    $0x4,%r9
  mov    %r11d,(%r8)
  cmp    %rbp,%r10
  je     L74
  mov    %rax,%r10
  mov    (%r9),%r11d
  cmp    %r10d,%esi
  jg     L20
L75:
  mov    %r11d,%ecx
  mov    %r9,%r8
  jmp    L63
  xchg   %ax,%ax
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  ret
```

assistant: ```c
void sortSelect(int *arr, int size) {
  int i;
  for (i = 0; i < size - 1; i++) {
    int *e, *m;
    e = m = &(arr[i]);
    int j;
    for (j = i; j < size; j++) {
      if (arr[j] < *m)
        m = &(arr[j]);
    }
    int t = *e;
    *e = *m;
    *m = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sortSelect>:
  endbr64
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L25
  test   %esi,%esi
  jle    L25
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L46:
  mov    (%rdi),%r11d
  mov    %rdi,%rax
  mov    %r10d,%edx
  mov    %rdi,%r9
  mov    %r11d,%r8d
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rax),%ecx
  cmp    %ecx,%r8d
  jle    L47
  mov    %ecx,%r8d
  mov    %rax,%r9
L47:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%esi
  jg     L14
  add    $0x1,%r10d
  mov    %r8d,(%rdi)
  add    $0x4,%rdi
  mov    %r11d,(%r9)
  cmp    %r10d,%ebx
  jne    L46
L25:
  pop    %rbx
  ret
```

assistant: ```c
void sortSelect(int *arr, int size) {
  int i;
  for (i = 0; i < size - 1; i++) {
    int *e, *m;
    e = m = &(arr[i]);
    int j;
    for (j = i; j < size; j++) {
      if (arr[j] < *m)
        m = &(arr[j]);
    }
    int t = *e;
    *e = *m;
    *m = t;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_129_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_129_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_129_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  xor    %edi,%esi
  mov    %edi,%eax
  xor    $0xff,%al
  or     %esi,%eax
  or     %edi,%eax
  not    %eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_129_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_129_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  xor    %edi,%esi
  xor    $0xff,%al
  or     %esi,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_129_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_129_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  xor    %edi,%esi
  xor    $0xff,%al
  or     %esi,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_129_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ T;
  stk2 = D ^ S;
  stk1 = stk1 | stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setckl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%edx
  mov    $0x100,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  mov    -0x4(%rbp),%eax
  and    $0x2ff,%eax
  mov    %eax,%edx
  mov    $0x2ff,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  nop
  leave
  ret
```

assistant: ```c
void setckl(unsigned int data) {
  sdmmc_mask16(0x24, 0x100, 0);
  sdmmc_mask16(0x24, 0x2FF, data & 0x2FF);
  sdmmc_mask16(0x24, 0x0, 0x100);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setckl>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    $0x100,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  and    $0x2ff,%ebx
  mov    %ebx,%edx
  mov    $0x2ff,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  pop    %rbx
  ret
```

assistant: ```c
void setckl(unsigned int data) {
  sdmmc_mask16(0x24, 0x100, 0);
  sdmmc_mask16(0x24, 0x2FF, data & 0x2FF);
  sdmmc_mask16(0x24, 0x0, 0x100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setckl>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edx,%edx
  mov    $0x100,%esi
  mov    $0x24,%edi
  and    $0x2ff,%ebx
  call   <sdmmc_mask16@plt>
  mov    %ebx,%edx
  mov    $0x2ff,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  mov    $0x100,%edx
  xor    %esi,%esi
  pop    %rbx
  mov    $0x24,%edi
  jmp    1050 <sdmmc_mask16@plt>
```

assistant: ```c
void setckl(unsigned int data) {
  sdmmc_mask16(0x24, 0x100, 0);
  sdmmc_mask16(0x24, 0x2FF, data & 0x2FF);
  sdmmc_mask16(0x24, 0x0, 0x100);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setckl>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edx,%edx
  mov    $0x100,%esi
  mov    $0x24,%edi
  and    $0x2ff,%ebx
  call   <sdmmc_mask16@plt>
  mov    %ebx,%edx
  mov    $0x2ff,%esi
  mov    $0x24,%edi
  call   <sdmmc_mask16@plt>
  mov    $0x100,%edx
  xor    %esi,%esi
  pop    %rbx
  mov    $0x24,%edi
  jmp    1050 <sdmmc_mask16@plt>
```

assistant: ```c
void setckl(unsigned int data) {
  sdmmc_mask16(0x24, 0x100, 0);
  sdmmc_mask16(0x24, 0x2FF, data & 0x2FF);
  sdmmc_mask16(0x24, 0x0, 0x100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<output_readable_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x20,-0x8(%rbp)
  jle    L30
  cmpq   $0x5c,-0x8(%rbp)
  jne    L15
  mov    $0x5c,%edi
  call   <output_char@plt>
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <output_char@plt>
  jmp    L0
L30:
  mov    $0x5c,%edi
  call   <output_char@plt>
  cmpq   $0x9,-0x8(%rbp)
  jg     L14
  mov    $0x30,%edi
  call   <output_char@plt>
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <output_q@plt>
  nop
L0:
  leave
  ret
```

assistant: ```c
void output_readable_char(long c) {
  if (c > 32) {
    if (c == (long)'\\') {
      output_char('\\');
    }
    output_char(c);
  } else {
    output_char((long)'\\');
    if (c < 10) {
      output_char((long)'0');
    }
    output_q(c);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_readable_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x20,%rdi
  jle    L32
  cmp    $0x5c,%rdi
  je     L46
L56:
  mov    %rbx,%rdi
  call   <output_char@plt>
L10:
  pop    %rbx
  ret
L46:
  mov    $0x5c,%edi
  call   <output_char@plt>
  jmp    L56
L32:
  mov    $0x5c,%edi
  call   <output_char@plt>
  cmp    $0x9,%rbx
  jle    L11
L59:
  mov    %rbx,%rdi
  call   <output_q@plt>
  jmp    L10
L11:
  mov    $0x30,%edi
  call   <output_char@plt>
  jmp    L59
```

assistant: ```c
void output_readable_char(long c) {
  if (c > 32) {
    if (c == (long)'\\') {
      output_char('\\');
    }
    output_char(c);
  } else {
    output_char((long)'\\');
    if (c < 10) {
      output_char((long)'0');
    }
    output_q(c);
  }
  return;
}
```