ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipspaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r12
L9:
  movzbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipspaces(char *p) {
  while (isspace((unsigned char)*p))
    p++;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kitoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  negl   -0x14(%rbp)
L6:
  movl   $0x0,-0x8(%rbp)
L20:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L20
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <kreverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void kitoa(int n, char s[]) {
  int i, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  kreverse(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kitoa>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r9d
  mov    %rsi,%r10
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  mov    %rsi,%r8
  mov    $0x0,%edi
L6:
  mov    %edi,%r11d
  add    $0x1,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  add    $0x1,%r8
  cmp    $0x9,%ecx
  jg     L6
  test   %r9d,%r9d
  js     L24
L14:
  movslq %edi,%rdi
  movb   $0x0,(%r10,%rdi,1)
  mov    %r10,%rdi
  call   <kreverse@plt>
  add    $0x8,%rsp
  ret
L24:
  movslq %edi,%rdi
  movb   $0x2d,(%r10,%rdi,1)
  lea    0x2(%r11),%edi
  jmp    L14
```

assistant: ```c
void kitoa(int n, char s[]) {
  int i, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  kreverse(s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kitoa>:
  endbr64
  mov    %edi,%edx
  push   %rbx
  mov    %edi,%r10d
  mov    %rsi,%r9
  neg    %edx
  mov    %rsi,%r8
  mov    $0xcccccccd,%ebx
  cmovs  %edi,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L2:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edi,%r11d
  imul   %rbx,%rax
  add    $0x1,%edi
  add    $0x1,%r8
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L2
  test   %r10d,%r10d
  jns    L14
  movslq %edi,%rdi
  movb   $0x2d,(%r9,%rdi,1)
  lea    0x2(%r11),%edi
L14:
  movslq %edi,%rdi
  pop    %rbx
  movb   $0x0,(%r9,%rdi,1)
  mov    %r9,%rdi
  jmp    1050 <kreverse@plt>
```

assistant: ```c
void kitoa(int n, char s[]) {
  int i, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  kreverse(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<kitoa>:
  endbr64
  mov    %edi,%edx
  push   %rbx
  mov    %edi,%r10d
  mov    %rsi,%r9
  neg    %edx
  mov    %rsi,%r8
  mov    $0xcccccccd,%ebx
  cmovs  %edi,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L8:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edi,%r11d
  imul   %rbx,%rax
  add    $0x1,%edi
  add    $0x1,%r8
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L8
  test   %r10d,%r10d
  jns    L12
  movslq %edi,%rdi
  movb   $0x2d,(%r9,%rdi,1)
  lea    0x2(%r11),%edi
L12:
  movslq %edi,%rdi
  pop    %rbx
  movb   $0x0,(%r9,%rdi,1)
  mov    %r9,%rdi
  jmp    1050 <kreverse@plt>
```

assistant: ```c
void kitoa(int n, char s[]) {
  int i, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = n % 10 + '0';
  } while ((n /= 10) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  kreverse(s);
}
```
user: What is the c source code of the assembly code below:

```asm
<GB_UpdateCounterToClocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_TimersUpdateClocksCounterReference@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_PPUUpdateClocksCounterReference@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_SerialUpdateClocksCounterReference@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_SoundUpdateClocksCounterReference@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_DMAUpdateClocksCounterReference@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <GB_CameraUpdateClocksCounterReference@plt>
  nop
  leave
  ret
```

assistant: ```c
void GB_UpdateCounterToClocks(int reference_clocks) {
  GB_TimersUpdateClocksCounterReference(reference_clocks);
  GB_PPUUpdateClocksCounterReference(reference_clocks);
  GB_SerialUpdateClocksCounterReference(reference_clocks);
  GB_SoundUpdateClocksCounterReference(reference_clocks);
  GB_DMAUpdateClocksCounterReference(reference_clocks);
  GB_CameraUpdateClocksCounterReference(reference_clocks);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GB_UpdateCounterToClocks>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <GB_TimersUpdateClocksCounterReference@plt>
  mov    %ebx,%edi
  call   <GB_PPUUpdateClocksCounterReference@plt>
  mov    %ebx,%edi
  call   <GB_SerialUpdateClocksCounterReference@plt>
  mov    %ebx,%edi
  call   <GB_SoundUpdateClocksCounterReference@plt>
  mov    %ebx,%edi
  call   <GB_DMAUpdateClocksCounterReference@plt>
  mov    %ebx,%edi
  call   <GB_CameraUpdateClocksCounterReference@plt>
  pop    %rbx
  ret
```

assistant: ```c
void GB_UpdateCounterToClocks(int reference_clocks) {
  GB_TimersUpdateClocksCounterReference(reference_clocks);
  GB_PPUUpdateClocksCounterReference(reference_clocks);
  GB_SerialUpdateClocksCounterReference(reference_clocks);
  GB_SoundUpdateClocksCounterReference(reference_clocks);
  GB_DMAUpdateClocksCounterReference(reference_clocks);
  GB_CameraUpdateClocksCounterReference(reference_clocks);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GB_UpdateCounterToClocks>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <GB_TimersUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_PPUUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_SerialUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_SoundUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_DMAUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    10c0 <GB_CameraUpdateClocksCounterReference@plt>
```

assistant: ```c
void GB_UpdateCounterToClocks(int reference_clocks) {
  GB_TimersUpdateClocksCounterReference(reference_clocks);
  GB_PPUUpdateClocksCounterReference(reference_clocks);
  GB_SerialUpdateClocksCounterReference(reference_clocks);
  GB_SoundUpdateClocksCounterReference(reference_clocks);
  GB_DMAUpdateClocksCounterReference(reference_clocks);
  GB_CameraUpdateClocksCounterReference(reference_clocks);
}
```
user: What is the c source code of the assembly code below?

```asm
<GB_UpdateCounterToClocks>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <GB_TimersUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_PPUUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_SerialUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_SoundUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  call   <GB_DMAUpdateClocksCounterReference@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    10c0 <GB_CameraUpdateClocksCounterReference@plt>
```

assistant: ```c
void GB_UpdateCounterToClocks(int reference_clocks) {
  GB_TimersUpdateClocksCounterReference(reference_clocks);
  GB_PPUUpdateClocksCounterReference(reference_clocks);
  GB_SerialUpdateClocksCounterReference(reference_clocks);
  GB_SoundUpdateClocksCounterReference(reference_clocks);
  GB_DMAUpdateClocksCounterReference(reference_clocks);
  GB_CameraUpdateClocksCounterReference(reference_clocks);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  xor    %esi,%esi
  mov    $0x1,%edi
  jmp    1050 <SEND_ACKDOWN_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BrzUnaryFuncPush_ackdown>:
  endbr64
  xor    %esi,%esi
  mov    $0x1,%edi
  jmp    1050 <SEND_ACKDOWN_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFuncPush_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(1, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<insert_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <my_malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L47
  mov    $0x0,%eax
  jmp    L52
L47:
  mov    -0x38(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L25
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L48
L25:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <my_malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L52
L0:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  lea    0x1(%rax),%rsi
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D10(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x20(%rbp),%rsi
  mov    -0x40(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L48:
  mov    -0x28(%rbp),%rax
L52:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D7: %s%s

tool: D10: %s

tool: D11: %s%s%s

assistant: ```c
char *insert_suffix(char *name, char *suffix) {
  char *new_name, *name1;
  new_name = my_malloc(strlen(name) + strlen(suffix) + 1);
  if (new_name == NULL)
    return NULL;
  char *p;
  p = strrchr(name, '.');
  if (p == NULL) {
    sprintf(new_name, "%s%s", name, suffix);
  } else {
    name1 = my_malloc(strlen(name) - strlen(p) + 1);
    if (name1 == NULL)
      return NULL;
    snprintf(name1, strlen(name) - strlen(p) + 1, "%s", name);
    sprintf(new_name, "%s%s%s", name1, suffix, p);
    free(name1);
  }
  return new_name;
}
```
user: What is the c source code of the assembly code below?

```asm
<insert_suffix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <my_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L42
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %rax,%r14
  lea    0x1(%r14),%rdi
  call   <my_malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L14
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %rax,%r14
  lea    0x1(%r14),%rsi
  mov    %rbx,%rcx
  lea    D2(%rip),%rdx
  mov    %r15,%rdi
  call   <snprintf@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    %r15,%rdx
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <free@plt>
L42:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %r13,%rcx
  mov    %rbx,%rdx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L42
L14:
  mov    %rax,%rbp
  jmp    L42
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D2: %s

tool: D25: %s%s%s

tool: D3: %s%s

assistant: ```c
char *insert_suffix(char *name, char *suffix) {
  char *new_name, *name1;
  new_name = my_malloc(strlen(name) + strlen(suffix) + 1);
  if (new_name == NULL)
    return NULL;
  char *p;
  p = strrchr(name, '.');
  if (p == NULL) {
    sprintf(new_name, "%s%s", name, suffix);
  } else {
    name1 = my_malloc(strlen(name) - strlen(p) + 1);
    if (name1 == NULL)
      return NULL;
    snprintf(name1, strlen(name) - strlen(p) + 1, "%s", name);
    sprintf(new_name, "%s%s%s", name1, suffix, p);
    free(name1);
  }
  return new_name;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insert_suffix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <my_malloc@plt>
  test   %rax,%rax
  je     L41
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  sub    %rax,%rbp
  lea    0x1(%rbp),%rdi
  call   <my_malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L41
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D3(%rip),%rdx
  mov    %r15,%rdi
  sub    %rax,%rbp
  lea    0x1(%rbp),%rsi
  call   <snprintf@plt>
  mov    %r13,%rdi
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r15,%rdx
  lea    D29(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <free@plt>
L33:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L33
  nopl   0x0(%rax)
L41:
  xor    %r13d,%r13d
  jmp    L33
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D2
type: string

tool: D3: %s

tool: D29: %s%s%s

tool: D2: %s%s

assistant: ```c
char *insert_suffix(char *name, char *suffix) {
  char *new_name, *name1;
  new_name = my_malloc(strlen(name) + strlen(suffix) + 1);
  if (new_name == NULL)
    return NULL;
  char *p;
  p = strrchr(name, '.');
  if (p == NULL) {
    sprintf(new_name, "%s%s", name, suffix);
  } else {
    name1 = my_malloc(strlen(name) - strlen(p) + 1);
    if (name1 == NULL)
      return NULL;
    snprintf(name1, strlen(name) - strlen(p) + 1, "%s", name);
    sprintf(new_name, "%s%s%s", name1, suffix, p);
    free(name1);
  }
  return new_name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_suffix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <my_malloc@plt>
  test   %rax,%rax
  je     L25
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strrchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L41
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  sub    %rax,%rbp
  lea    0x1(%rbp),%rdi
  call   <my_malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L25
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D26(%rip),%rdx
  mov    %r15,%rdi
  sub    %rax,%rbp
  lea    0x1(%rbp),%rsi
  call   <snprintf@plt>
  mov    %r13,%rdi
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r15,%rdx
  lea    D7(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <free@plt>
L11:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D13(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L11
  nopl   0x0(%rax)
L25:
  xor    %r13d,%r13d
  jmp    L11
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D26: %s

tool: D7: %s%s%s

tool: D13: %s%s

assistant: ```c
char *insert_suffix(char *name, char *suffix) {
  char *new_name, *name1;
  new_name = my_malloc(strlen(name) + strlen(suffix) + 1);
  if (new_name == NULL)
    return NULL;
  char *p;
  p = strrchr(name, '.');
  if (p == NULL) {
    sprintf(new_name, "%s%s", name, suffix);
  } else {
    name1 = my_malloc(strlen(name) - strlen(p) + 1);
    if (name1 == NULL)
      return NULL;
    snprintf(name1, strlen(name) - strlen(p) + 1, "%s", name);
    sprintf(new_name, "%s%s%s", name1, suffix, p);
    free(name1);
  }
  return new_name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<might_be_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswupper@plt>
  test   %eax,%eax
  jne    L76
  mov    $0x0,%eax
  jmp    L58
L21:
  addq   $0x1,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswalnum@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L21
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswspace@plt>
  test   %rax,%rax
  je     L0
  mov    $0x1,%eax
  jmp    L58
L0:
  mov    $0x0,%eax
L58:
  leave
  ret
```

assistant: ```c
int might_be_header(const wchar_t *line) {
  if (!iswupper(*line++))
    return 0;
  while (*line && (iswalnum(*line) || *line == '-'))
    ++line;
  return (*line == ':' && iswspace(line[1]));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<might_be_header>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <iswupper@plt>
  test   %eax,%eax
  je     L52
  movzbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L17
  add    $0x1,%rbx
  jmp    L48
L31:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L17
L48:
  movsbl %dil,%edi
  call   <iswalnum@plt>
  test   %rax,%rax
  jne    L31
  cmpb   $0x2d,(%rbx)
  je     L31
  cmpb   $0x3a,(%rbx)
  jne    L52
  movsbl 0x1(%rbx),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L52
L17:
  mov    $0x0,%eax
L52:
  pop    %rbx
  ret
```

assistant: ```c
int might_be_header(const wchar_t *line) {
  if (!iswupper(*line++))
    return 0;
  while (*line && (iswalnum(*line) || *line == '-'))
    ++line;
  return (*line == ':' && iswspace(line[1]));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<might_be_header>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <iswupper@plt>
  test   %eax,%eax
  je     L6
  movsbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L6
  add    $0x1,%rbx
  nopl   0x0(%rax)
L7:
  call   <iswalnum@plt>
  test   %rax,%rax
  jne    L29
  movzbl (%rbx),%eax
  cmp    $0x2d,%al
  jne    L22
L29:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    $0x3a,%al
  jne    L6
  movsbl 0x1(%rbx),%edi
  call   <iswspace@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int might_be_header(const wchar_t *line) {
  if (!iswupper(*line++))
    return 0;
  while (*line && (iswalnum(*line) || *line == '-'))
    ++line;
  return (*line == ':' && iswspace(line[1]));
}
```