ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blockmix_salsa8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%r13
  mov    %rdi,(%rsp)
  mov    %rsi,%r12
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rax
  shl    $0x9,%rax
  lea    -0x100(%rdi,%rax,1),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x40,%edx
  call   <blkcpy@plt>
  mov    %r14,%r15
  add    %r15,%r15
  je     L29
  mov    $0x0,%ebp
  lea    0x10(%rsp),%rbx
L8:
  mov    $0x40,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <blkxor@plt>
  mov    %rbx,%rdi
  call   <salsa20_8@plt>
  mov    $0x40,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <blkcpy@plt>
  add    $0x1,%rbp
  add    $0x100,%r13
  add    $0x100,%r12
  cmp    %r15,%rbp
  jne    L8
L29:
  test   %r14,%r14
  je     L3
  mov    (%rsp),%r12
  mov    0x8(%rsp),%rbp
  mov    $0x0,%ebx
L22:
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <blkcpy@plt>
  mov    %rbx,%r13
  add    $0x1,%rbx
  add    $0x100,%r12
  add    $0x200,%rbp
  cmp    %rbx,%r14
  jne    L22
  shl    $0x8,%rbx
  add    (%rsp),%rbx
  mov    0x8(%rsp),%rbp
  add    $0x100,%rbp
  mov    $0x0,%r12d
L43:
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <blkcpy@plt>
  mov    %r12,%rax
  add    $0x1,%r12
  add    $0x100,%rbx
  add    $0x200,%rbp
  cmp    %rax,%r13
  jne    L43
L3:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void blockmix_salsa8(uint8_t *B, uint8_t *Y, size_t r) {
  uint8_t X[64];
  size_t i;
  blkcpy(X, &B[(2 * r - 1) * 64], 64);
  for (i = 0; i < 2 * r; i++) {
    blkxor(X, &B[i * 64], 64);
    salsa20_8(X);
    blkcpy(&Y[i * 64], X, 64);
  }
  for (i = 0; i < r; i++)
    blkcpy(&B[i * 64], &Y[(i * 2) * 64], 64);
  for (i = 0; i < r; i++)
    blkcpy(&B[(i + r) * 64], &Y[(i * 2 + 1) * 64], 64);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<blockmix_salsa8>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rbx,%r15
  sub    $0x138,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x20(%rsp),%r12
  mov    %rsi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  mov    %rdx,%rax
  mov    $0x40,%edx
  shl    $0x9,%rax
  lea    -0x100(%rdi,%rax,1),%rsi
  mov    %r12,%rdi
  mov    %rax,0x18(%rsp)
  call   <blkcpy@plt>
  add    %r15,%r15
  je     L39
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L15:
  mov    %r14,%rsi
  mov    $0x40,%edx
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <blkxor@plt>
  mov    %r12,%rdi
  add    $0x100,%r14
  call   <salsa20_8@plt>
  mov    %r13,%rdi
  mov    $0x40,%edx
  mov    %r12,%rsi
  call   <blkcpy@plt>
  add    $0x100,%r13
  cmp    %r15,%rbp
  jne    L15
L39:
  test   %rbx,%rbx
  je     L19
  mov    0x10(%rsp),%r15
  mov    0x8(%rsp),%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L25:
  mov    %r15,%rsi
  mov    %r13,%rdi
  mov    $0x40,%edx
  add    $0x1,%r12
  call   <blkcpy@plt>
  add    $0x100,%r13
  add    $0x200,%r15
  cmp    %r12,%rbx
  jne    L25
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rbp
  shl    $0x8,%rbx
  add    %rax,%rbx
  add    0x18(%rsp),%rax
  add    $0x100,%rbp
  mov    %rax,%r14
  nop
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x40,%edx
  add    $0x100,%rbx
  call   <blkcpy@plt>
  add    $0x200,%rbp
  cmp    %rbx,%r14
  jne    L29
L19:
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void blockmix_salsa8(uint8_t *B, uint8_t *Y, size_t r) {
  uint8_t X[64];
  size_t i;
  blkcpy(X, &B[(2 * r - 1) * 64], 64);
  for (i = 0; i < 2 * r; i++) {
    blkxor(X, &B[i * 64], 64);
    salsa20_8(X);
    blkcpy(&Y[i * 64], X, 64);
  }
  for (i = 0; i < r; i++)
    blkcpy(&B[i * 64], &Y[(i * 2) * 64], 64);
  for (i = 0; i < r; i++)
    blkcpy(&B[(i + r) * 64], &Y[(i * 2 + 1) * 64], 64);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blockmix_salsa8>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rbx,%r15
  sub    $0x138,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x20(%rsp),%r12
  mov    %rsi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  mov    %rdx,%rax
  mov    $0x40,%edx
  shl    $0x9,%rax
  lea    -0x100(%rdi,%rax,1),%rsi
  mov    %r12,%rdi
  mov    %rax,0x18(%rsp)
  call   <blkcpy@plt>
  add    %r15,%r15
  je     L19
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L21:
  mov    %r14,%rsi
  mov    $0x40,%edx
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <blkxor@plt>
  mov    %r12,%rdi
  add    $0x100,%r14
  call   <salsa20_8@plt>
  mov    %r13,%rdi
  mov    $0x40,%edx
  mov    %r12,%rsi
  call   <blkcpy@plt>
  add    $0x100,%r13
  cmp    %r15,%rbp
  jne    L21
L19:
  test   %rbx,%rbx
  je     L5
  mov    0x10(%rsp),%r15
  mov    0x8(%rsp),%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L23:
  mov    %r15,%rsi
  mov    %r13,%rdi
  mov    $0x40,%edx
  add    $0x1,%r12
  call   <blkcpy@plt>
  add    $0x100,%r13
  add    $0x200,%r15
  cmp    %r12,%rbx
  jne    L23
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rbp
  shl    $0x8,%rbx
  add    %rax,%rbx
  add    0x18(%rsp),%rax
  add    $0x100,%rbp
  mov    %rax,%r14
  nop
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x40,%edx
  add    $0x100,%rbx
  call   <blkcpy@plt>
  add    $0x200,%rbp
  cmp    %rbx,%r14
  jne    L6
L5:
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void blockmix_salsa8(uint8_t *B, uint8_t *Y, size_t r) {
  uint8_t X[64];
  size_t i;
  blkcpy(X, &B[(2 * r - 1) * 64], 64);
  for (i = 0; i < 2 * r; i++) {
    blkxor(X, &B[i * 64], 64);
    salsa20_8(X);
    blkcpy(&Y[i * 64], X, 64);
  }
  for (i = 0; i < r; i++)
    blkcpy(&B[i * 64], &Y[(i * 2) * 64], 64);
  for (i = 0; i < r; i++)
    blkcpy(&B[(i + r) * 64], &Y[(i * 2 + 1) * 64], 64);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<socket_udp_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0xc(%rbp)
  lea    -0xc(%rbp),%r8
  mov    -0x20(%rbp),%rdi
  mov    -0x2c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int socket_udp_recv(int sock, struct sockaddr_storage *addr, void *buffer, int n, int flags) {
  socklen_t addr_size;
  addr_size = sizeof(struct sockaddr_storage);
  return (recvfrom(sock, buffer, n, flags, (struct sockaddr *)addr, &addr_size));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<socket_udp_recv>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %r8d,%ecx
  mov    %fs:0x28,%r8
  mov    %r8,0x8(%rsp)
  xor    %r8d,%r8d
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%r9
  mov    %rax,%r8
  call   <recvfrom@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_udp_recv(int sock, struct sockaddr_storage *addr, void *buffer, int n, int flags) {
  socklen_t addr_size;
  addr_size = sizeof(struct sockaddr_storage);
  return (recvfrom(sock, buffer, n, flags, (struct sockaddr *)addr, &addr_size));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<socket_udp_recv>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r8d,%ecx
  lea    0x4(%rsp),%r9
  mov    %r10,%r8
  movl   $0x4,0x4(%rsp)
  call   <recvfrom@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_udp_recv(int sock, struct sockaddr_storage *addr, void *buffer, int n, int flags) {
  socklen_t addr_size;
  addr_size = sizeof(struct sockaddr_storage);
  return (recvfrom(sock, buffer, n, flags, (struct sockaddr *)addr, &addr_size));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<socket_udp_recv>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r8d,%ecx
  lea    0x4(%rsp),%r9
  mov    %r10,%r8
  movl   $0x4,0x4(%rsp)
  call   <recvfrom@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int socket_udp_recv(int sock, struct sockaddr_storage *addr, void *buffer, int n, int flags) {
  socklen_t addr_size;
  addr_size = sizeof(struct sockaddr_storage);
  return (recvfrom(sock, buffer, n, flags, (struct sockaddr *)addr, &addr_size));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sprintf(char *s, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vsprintf(s, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sprintf(char *s, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vsprintf(s, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *s, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vsprintf(s, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *s, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vsprintf(s, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<TimerETRConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  andq   $0xffffffffffff40ff,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  or     -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerETRConfigure(unsigned long ulBase, unsigned long ulExtTRGPrescaler, unsigned long ulExtTRGPolarity, unsigned long ulExtTRGFilter) {
  unsigned long ulTempsmcr = 0;

  ;

  ;

  ;
  ;
  ulTempsmcr = (*((volatile unsigned long *)(ulBase + 0x00000008)));
  ulTempsmcr &= ~(0x00008000 | 0x00003000 | 0x00000F00);
  ulTempsmcr |= (ulExtTRGPrescaler | ulExtTRGPolarity | (ulExtTRGFilter << 8));
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ulTempsmcr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TimerETRConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  and    $0x40,%ah
  shl    $0x8,%rcx
  or     %rdx,%rcx
  or     %rsi,%rcx
  or     %rax,%rcx
  mov    %rcx,0x8(%rdi)
  ret
```

assistant: ```c
void TimerETRConfigure(unsigned long ulBase, unsigned long ulExtTRGPrescaler, unsigned long ulExtTRGPolarity, unsigned long ulExtTRGFilter) {
  unsigned long ulTempsmcr = 0;

  ;

  ;

  ;
  ;
  ulTempsmcr = (*((volatile unsigned long *)(ulBase + 0x00000008)));
  ulTempsmcr &= ~(0x00008000 | 0x00003000 | 0x00000F00);
  ulTempsmcr |= (ulExtTRGPrescaler | ulExtTRGPolarity | (ulExtTRGFilter << 8));
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ulTempsmcr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<TimerETRConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  shl    $0x8,%rcx
  or     %rdx,%rcx
  and    $0x40,%ah
  or     %rsi,%rcx
  or     %rax,%rcx
  mov    %rcx,0x8(%rdi)
  ret
```

assistant: ```c
void TimerETRConfigure(unsigned long ulBase, unsigned long ulExtTRGPrescaler, unsigned long ulExtTRGPolarity, unsigned long ulExtTRGFilter) {
  unsigned long ulTempsmcr = 0;

  ;

  ;

  ;
  ;
  ulTempsmcr = (*((volatile unsigned long *)(ulBase + 0x00000008)));
  ulTempsmcr &= ~(0x00008000 | 0x00003000 | 0x00000F00);
  ulTempsmcr |= (ulExtTRGPrescaler | ulExtTRGPolarity | (ulExtTRGFilter << 8));
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ulTempsmcr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TimerETRConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  shl    $0x8,%rcx
  or     %rdx,%rcx
  and    $0x40,%ah
  or     %rsi,%rcx
  or     %rax,%rcx
  mov    %rcx,0x8(%rdi)
  ret
```

assistant: ```c
void TimerETRConfigure(unsigned long ulBase, unsigned long ulExtTRGPrescaler, unsigned long ulExtTRGPolarity, unsigned long ulExtTRGFilter) {
  unsigned long ulTempsmcr = 0;

  ;

  ;

  ;
  ;
  ulTempsmcr = (*((volatile unsigned long *)(ulBase + 0x00000008)));
  ulTempsmcr &= ~(0x00008000 | 0x00003000 | 0x00000F00);
  ulTempsmcr |= (ulExtTRGPrescaler | ulExtTRGPolarity | (ulExtTRGFilter << 8));
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ulTempsmcr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<glmASinD3f_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <glmASin3f_@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <glmDegrees3f_@plt>
  nop
  leave
  ret
```

assistant: ```c
void glmASinD3f_(float x[3]) {
  glmASin3f_(x);
  glmDegrees3f_(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmASinD3f_>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <glmASin3f_@plt>
  mov    %rbx,%rdi
  call   <glmDegrees3f_@plt>
  pop    %rbx
  ret
```

assistant: ```c
void glmASinD3f_(float x[3]) {
  glmASin3f_(x);
  glmDegrees3f_(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmASinD3f_>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmASin3f_@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <glmDegrees3f_@plt>
```

assistant: ```c
void glmASinD3f_(float x[3]) {
  glmASin3f_(x);
  glmDegrees3f_(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<glmASinD3f_>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <glmASin3f_@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <glmDegrees3f_@plt>
```

assistant: ```c
void glmASinD3f_(float x[3]) {
  glmASin3f_(x);
  glmDegrees3f_(x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_fcp_dev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  cmpq   $0x0,-0x10(%rbp)
  je     L12
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
L12:
  mov    $0xffffffff,%eax
  jmp    L22
L1:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int get_fcp_dev(char *partition, char *device) {
  char *start, *stop;
  size_t len;
  start = strchr(partition, '/');
  stop = strrchr(partition, '/');
  len = stop - start;
  if (start == NULL || stop == NULL || len <= 0)
    return -1;
  strncpy(device, stop + 1, len - 1);
  device[len] = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_fcp_dev>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  mov    %rax,%r12
  sub    %rbx,%r12
  test   %rbx,%rbx
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %cl,%dl
  jne    L13
  test   %r12,%r12
  je     L13
  lea    -0x1(%r12),%rdx
  lea    0x1(%rax),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    $0x0,%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    $0xffffffff,%eax
  jmp    L4
```

assistant: ```c
int get_fcp_dev(char *partition, char *device) {
  char *start, *stop;
  size_t len;
  start = strchr(partition, '/');
  stop = strrchr(partition, '/');
  len = stop - start;
  if (start == NULL || stop == NULL || len <= 0)
    return -1;
  strncpy(device, stop + 1, len - 1);
  device[len] = '\0';
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_fcp_dev>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  push   %rbx
  call   <strchr@plt>
  mov    %r12,%rdi
  mov    $0x2f,%esi
  mov    %rax,%rbx
  call   <strrchr@plt>
  mov    %rax,%r12
  sub    %rbx,%r12
  test   %rbx,%rbx
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %cl,%dl
  jne    L5
  test   %r12,%r12
  je     L5
  lea    -0x1(%r12),%rdx
  lea    0x1(%rax),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  xor    %eax,%eax
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int get_fcp_dev(char *partition, char *device) {
  char *start, *stop;
  size_t len;
  start = strchr(partition, '/');
  stop = strrchr(partition, '/');
  len = stop - start;
  if (start == NULL || stop == NULL || len <= 0)
    return -1;
  strncpy(device, stop + 1, len - 1);
  device[len] = '\0';
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_fcp_dev>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2f,%esi
  push   %rbx
  call   <strchr@plt>
  mov    %r12,%rdi
  mov    $0x2f,%esi
  mov    %rax,%rbx
  call   <strrchr@plt>
  mov    %rax,%r12
  sub    %rbx,%r12
  test   %rbx,%rbx
  sete   %dl
  test   %rax,%rax
  sete   %cl
  or     %cl,%dl
  jne    L14
  test   %r12,%r12
  je     L14
  lea    -0x1(%r12),%rdx
  lea    0x1(%rax),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  xor    %eax,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    $0xffffffff,%eax
  jmp    L21
```

assistant: ```c
int get_fcp_dev(char *partition, char *device) {
  char *start, *stop;
  size_t len;
  start = strchr(partition, '/');
  stop = strrchr(partition, '/');
  len = stop - start;
  if (start == NULL || stop == NULL || len <= 0)
    return -1;
  strncpy(device, stop + 1, len - 1);
  device[len] = '\0';
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<return_alloca_plus_cst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x8(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L18:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L18
L38:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L23
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L23:
  mov    %rsp,%rax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x4,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
__attribute__((noipa)) void *return_alloca_plus_cst(int n) {
  int *p = (int *)__builtin_alloca(n);
  p += 1;
  sink(p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<return_alloca_plus_cst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movslq %edi,%rdi
  add    $0x17,%rdi
  mov    %rdi,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rdi
  mov    %rsp,%rax
  sub    %rdi,%rax
L27:
  cmp    %rax,%rsp
  je     L22
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L22:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L25
  orq    $0x0,-0x8(%rsp,%rax,1)
L25:
  lea    0xf(%rsp),%rbx
  and    $0xfffffffffffffff0,%rbx
  add    $0x4,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((noipa)) void *return_alloca_plus_cst(int n) {
  int *p = (int *)__builtin_alloca(n);
  p += 1;
  sink(p);
  return p;
}
```