ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D68(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D51(%rip),%rsi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <getExponent@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D58(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D68
type_guessed: string
name: parse_data
arguments: tag: D51
type_guessed: string
name: parse_data
arguments: tag: D65
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D58
type_guessed: string

tool: D15: Welcome to Fast Exponentiator!

tool: D68: %d

tool: D51: Enter base: 

tool: D65: %s

tool: D20: Enter power: 

tool: D27: 
%s

tool: D58: 
%d to the %dth power equals %d


assistant: ```c
int main() {
  int base = 0, power = 0;
  printf("%s\n", "Welcome to Fast Exponentiator!");
  printf("%s", "Enter base: ");
  scanf("%d", &base);
  printf("\n%s", "Enter power: ");
  scanf("%d", &power);
  printf("\n%d to the %dth power equals %d\n", base, power, getExponent(base, power));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__change_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x3f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x6,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  xor    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  *p ^= mask;
}
```
user: What is the c source code of the assembly code below?

```asm
<__change_bit>:
  endbr64
  mov    %edi,%ecx
  lea    0x3f(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x6,%eax
  cltq
  mov    $0x1,%edx
  shl    %cl,%rdx
  xor    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  *p ^= mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__change_bit>:
  endbr64
  test   %edi,%edi
  lea    0x3f(%rdi),%eax
  mov    %edi,%ecx
  mov    $0x1,%edx
  cmovns %edi,%eax
  shl    %cl,%rdx
  sar    $0x6,%eax
  cltq
  xor    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  *p ^= mask;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__change_bit>:
  endbr64
  test   %edi,%edi
  lea    0x3f(%rdi),%eax
  mov    %edi,%ecx
  mov    $0x1,%edx
  cmovns %edi,%eax
  shl    %cl,%rdx
  sar    $0x6,%eax
  cltq
  xor    %rdx,(%rsi,%rax,8)
  ret
```

assistant: ```c
void __change_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = (1UL << ((nr) % ((int)sizeof(unsigned long) * 8)));
  unsigned long *p = ((unsigned long *)addr) + ((nr) / ((int)sizeof(unsigned long) * 8));
  *p ^= mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int swap32(unsigned int x) {
  unsigned char *ptr = (unsigned char *)&x;
  return (unsigned int)((unsigned int)ptr[0] << 24 | (unsigned int)ptr[1] << 16 | (unsigned int)ptr[2] << 8 | ptr[3]);
}
```
user: What is the c source code of the assembly code below:

```asm
<swap32>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  shl    $0x18,%eax
  movzbl %dh,%ecx
  shl    $0x10,%ecx
  or     %ecx,%eax
  mov    %edi,%ecx
  shr    $0x18,%ecx
  or     %ecx,%eax
  shr    $0x8,%edx
  and    $0xff00,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int swap32(unsigned int x) {
  unsigned char *ptr = (unsigned char *)&x;
  return (unsigned int)((unsigned int)ptr[0] << 24 | (unsigned int)ptr[1] << 16 | (unsigned int)ptr[2] << 8 | ptr[3]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap32>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int swap32(unsigned int x) {
  unsigned char *ptr = (unsigned char *)&x;
  return (unsigned int)((unsigned int)ptr[0] << 24 | (unsigned int)ptr[1] << 16 | (unsigned int)ptr[2] << 8 | ptr[3]);
}
```
user: What is the c source code of the assembly code below:

```asm
<swap32>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int swap32(unsigned int x) {
  unsigned char *ptr = (unsigned char *)&x;
  return (unsigned int)((unsigned int)ptr[0] << 24 | (unsigned int)ptr[1] << 16 | (unsigned int)ptr[2] << 8 | ptr[3]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L29
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L64:
  subl   $0x1,-0x8(%rbp)
L97:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L15
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L64
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L82
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L82
L96:
  addl   $0x1,-0xc(%rbp)
L82:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L11
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L96
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L97
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L92
L29:
  nop
L92:
  leave
  ret
```

assistant: ```c
void quicksort(int a[], int left, int right) {
  if (left >= right)
    return;
  int l = left;
  int r = right;
  int m = a[l];
  while (l < r) {
    while (l < r && a[r] >= m)
      --r;
    if (l < r)
      a[l++] = a[r];
    while (l < r && a[l] < m)
      ++l;
    if (l < r)
      a[r--] = a[l];
  }
  a[l] = m;
  quicksort(a, left, l - 1);
  quicksort(a, l + 1, right);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jge    L75
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r11d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r8d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rdx
  lea    -0x1(%r12),%ecx
  mov    %r12d,%esi
  mov    %r11d,%ebx
  jmp    L39
L19:
  mov    %esi,%r10d
  cmp    %esi,%ebx
  jge    L57
  lea    0x1(%rbx),%eax
  movslq %ebx,%rbx
  mov    %edi,0x0(%rbp,%rbx,4)
  cmp    %esi,%eax
  jge    L51
  cltq
L63:
  mov    %eax,%ebx
  cmp    %r8d,0x0(%rbp,%rax,4)
  jge    L27
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%r10d
  jg     L63
L57:
  movslq %ebx,%rax
  mov    %r8d,0x0(%rbp,%rax,4)
  lea    -0x1(%rbx),%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  cmp    %r10d,%eax
  jge    L57
  cltq
  mov    0x0(%rbp,%rax,4),%eax
  mov    %eax,(%r9)
  cmp    %ebx,%ecx
  jle    L57
L60:
  sub    $0x4,%rdx
  sub    $0x1,%ecx
  sub    $0x1,%esi
L39:
  mov    %rdx,%r9
  mov    (%rdx),%edi
  cmp    %r8d,%edi
  jl     L19
  cmp    %ebx,%ecx
  jg     L60
  jmp    L57
L51:
  mov    %eax,%ebx
  jmp    L57
L75:
  ret
```

assistant: ```c
void quicksort(int a[], int left, int right) {
  if (left >= right)
    return;
  int l = left;
  int r = right;
  int m = a[l];
  while (l < r) {
    while (l < r && a[r] >= m)
      --r;
    if (l < r)
      a[l++] = a[r];
    while (l < r && a[l] < m)
      ++l;
    if (l < r)
      a[r--] = a[l];
  }
  a[l] = m;
  quicksort(a, left, l - 1);
  quicksort(a, l + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<quicksort>:
  endbr64
  cmp    %esi,%edx
  jle    L4
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L99:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,4),%edi
  cs nopw 0x0(%rax,%rax,1)
L107:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L104:
  mov    (%rcx),%eax
  cmp    %edi,%eax
  jl     L96
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jg     L104
L59:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L1:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %edi,0x0(%rbp,%rax,4)
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L99
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L96:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,4),%rsi
  cmp    %edx,%r8d
  jge    L59
  mov    %eax,(%rsi)
  cmp    %edx,%ebx
  jge    L1
  movslq %ebx,%rax
  jmp    L31
  nopl   0x0(%rax)
L70:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L1
L31:
  mov    0x0(%rbp,%rax,4),%esi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %edi,%esi
  jl     L70
  sub    $0x1,%edx
  mov    %esi,(%rcx)
  cmp    %eax,%edx
  jg     L107
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void quicksort(int a[], int left, int right) {
  if (left >= right)
    return;
  int l = left;
  int r = right;
  int m = a[l];
  while (l < r) {
    while (l < r && a[r] >= m)
      --r;
    if (l < r)
      a[l++] = a[r];
    while (l < r && a[l] < m)
      ++l;
    if (l < r)
      a[r--] = a[l];
  }
  a[l] = m;
  quicksort(a, left, l - 1);
  quicksort(a, l + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<quicksort>:
  endbr64
  cmp    %esi,%edx
  jle    L65
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L105:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,4),%edi
  cs nopw 0x0(%rax,%rax,1)
L47:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%rcx),%eax
  cmp    %edi,%eax
  jl     L104
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jg     L32
L28:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L20:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %edi,0x0(%rbp,%rax,4)
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L105
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L104:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,4),%rsi
  cmp    %edx,%r8d
  jge    L28
  mov    %eax,(%rsi)
  cmp    %ebx,%edx
  jle    L20
  movslq %ebx,%rax
  jmp    L1
  nopl   0x0(%rax)
L95:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L20
L1:
  mov    0x0(%rbp,%rax,4),%esi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %edi,%esi
  jl     L95
  sub    $0x1,%edx
  mov    %esi,(%rcx)
  cmp    %eax,%edx
  jg     L47
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L65:
  ret
```

assistant: ```c
void quicksort(int a[], int left, int right) {
  if (left >= right)
    return;
  int l = left;
  int r = right;
  int m = a[l];
  while (l < r) {
    while (l < r && a[r] >= m)
      --r;
    if (l < r)
      a[l++] = a[r];
    while (l < r && a[l] < m)
      ++l;
    if (l < r)
      a[r--] = a[l];
  }
  a[l] = m;
  quicksort(a, left, l - 1);
  quicksort(a, l + 1, right);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<neverGetHere1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x19,%ecx
  lea    D20(%rip),%rax
  mov    %rax,%rdx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <__fail@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D20: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c

tool: D14: "Shouldn't get here 1"

tool: D19: Shouldn't get here 1

assistant: ```c
neverGetHere1(void) {
  __fail("Shouldn't get here 1", "\"Shouldn't get here 1\"", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c", 25);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<neverGetHere1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%ecx
  lea    D19(%rip),%rdx
  lea    D10(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <__fail@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c

tool: D10: "Shouldn't get here 1"

tool: D23: Shouldn't get here 1

assistant: ```c
neverGetHere1(void) {
  __fail("Shouldn't get here 1", "\"Shouldn't get here 1\"", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c", 25);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<neverGetHere1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%ecx
  lea    D13(%rip),%rdx
  lea    D29(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <__fail@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D13: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c

tool: D29: "Shouldn't get here 1"

tool: D4: Shouldn't get here 1

assistant: ```c
neverGetHere1(void) {
  __fail("Shouldn't get here 1", "\"Shouldn't get here 1\"", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c", 25);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<neverGetHere1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x19,%ecx
  lea    D3(%rip),%rdx
  lea    D1(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <__fail@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c

tool: D1: "Shouldn't get here 1"

tool: D13: Shouldn't get here 1

assistant: ```c
neverGetHere1(void) {
  __fail("Shouldn't get here 1", "\"Shouldn't get here 1\"", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/atsidaev/sdcc-z80-gas/refs/heads/master/cpctelera/tools/sdcc-3.6.8-r9946/src/support/regression/tests/logic.c", 25);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isTidy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %esi,-0xbc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x9,-0xb8(%rbp)
  jg     L58
  mov    $0x1,%eax
  jmp    L53
L58:
  lea    -0xa0(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x13,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <zero@plt>
  lea    -0xa0(%rbp),%rdx
  mov    -0xbc(%rbp),%ecx
  mov    -0xb8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <putDigitsIntoArr@plt>
  movl   $0x0,-0xa4(%rbp)
  jmp    L48
L19:
  mov    -0xa4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    -0xa0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xa4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  lea    -0xa0(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L67
  mov    $0x0,%eax
  jmp    L53
L67:
  addl   $0x1,-0xa4(%rbp)
L48:
  mov    -0xbc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xa4(%rbp)
  jl     L19
  mov    $0x1,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
_Bool isTidy(long long int num, int numDigs) {
  if (num < 10) {
    return 1;
  } else {
    long long int arr[19];
    zero(arr, 19, 10);
    putDigitsIntoArr(num, numDigs, arr);
    int i;
    for (i = 0; i < numDigs - 1; i++) {
      if (*(arr + i) < *(arr + i + 1)) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isTidy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x9,%rdi
  jg     L74
L38:
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L74:
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rsp,%r12
  mov    $0xa,%edx
  mov    $0x13,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <zero@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <putDigitsIntoArr@plt>
  cmp    $0x1,%ebp
  jle    L3
  mov    %rsp,%rax
  lea    -0x2(%rbp),%edx
  lea    0x8(%rsp,%rdx,8),%rdx
L13:
  mov    0x8(%rax),%rcx
  cmp    %rcx,(%rax)
  jl     L32
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
  mov    $0x1,%eax
  jmp    L38
L3:
  mov    $0x1,%eax
  jmp    L38
L32:
  mov    $0x0,%eax
  jmp    L38
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_Bool isTidy(long long int num, int numDigs) {
  if (num < 10) {
    return 1;
  } else {
    long long int arr[19];
    zero(arr, 19, 10);
    putDigitsIntoArr(num, numDigs, arr);
    int i;
    for (i = 0; i < numDigs - 1; i++) {
      if (*(arr + i) < *(arr + i + 1)) {
        return 0;
      }
    }
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isTidy>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  cmp    $0x9,%rdi
  jg     L57
L38:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xa8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %rsp,%rbx
  mov    %esi,%r12d
  mov    %rdi,%rbp
  mov    $0xa,%edx
  mov    $0x13,%esi
  mov    %rbx,%rdi
  call   <zero@plt>
  xor    %eax,%eax
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <putDigitsIntoArr@plt>
  cmp    $0x1,%r12d
  jle    L38
  lea    -0x2(%r12),%edx
  mov    %rbx,%rax
  lea    0x8(%rsp,%rdx,8),%rdx
  jmp    L73
L39:
  add    $0x8,%rax
  cmp    %rdx,%rax
  je     L35
L73:
  mov    0x8(%rax),%rcx
  cmp    %rcx,(%rax)
  jge    L39
  xor    %r13d,%r13d
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L35:
  mov    $0x1,%r13d
  jmp    L38
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_Bool isTidy(long long int num, int numDigs) {
  if (num < 10) {
    return 1;
  } else {
    long long int arr[19];
    zero(arr, 19, 10);
    putDigitsIntoArr(num, numDigs, arr);
    int i;
    for (i = 0; i < numDigs - 1; i++) {
      if (*(arr + i) < *(arr + i + 1)) {
        return 0;
      }
    }
    return 1;
  }
}
```