ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  add    $0x1c,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L7
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L15
L9:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L15
L7:
  movzbl -0x9(%rbp),%eax
  movzbl -0x9(%rbp),%edx
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
L15:
  movzbl -0x9(%rbp),%edx
  mov    %edx,%eax
  shl    $0x7,%eax
  sub    %edx,%eax
  lea    -0x49(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = (state[0UL] + 238420169UL) * (unsigned char)127;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%edx
  mov    %edx,%eax
  mulb   (%rdi)
  add    $0x1c,%eax
  imul   %eax,%eax
  neg    %eax
  sub    $0x49,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = (state[0UL] + 238420169UL) * (unsigned char)127;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  add    $0x1c,%eax
  imul   %eax,%eax
  neg    %eax
  sub    $0x49,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = (state[0UL] + 238420169UL) * (unsigned char)127;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  add    $0x1c,%eax
  imul   %eax,%eax
  neg    %eax
  sub    $0x49,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        state[0UL] += state[0UL];
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] *= state[0UL];
    }
    output[0UL] = (state[0UL] + 238420169UL) * (unsigned char)127;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unbit_magic_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L17
  mov    $0xffffffff,%eax
  jmp    L8
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  sub    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int unbit_magic_buf(char *what, size_t len, char **buffer, size_t *buflen) {
  if (len >= *buflen - 1)
    return -1;
  strcpy(*buffer, what);
  *buflen -= len + 1;
  *buffer += len + 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unbit_magic_buf>:
  endbr64
  mov    (%rcx),%rax
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jbe    L0
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %rdi,%rsi
  mov    (%rdx),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  not    %rax
  add    %rax,0x0(%rbp)
  add    $0x1,%rbx
  add    %rbx,(%r12)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int unbit_magic_buf(char *what, size_t len, char **buffer, size_t *buflen) {
  if (len >= *buflen - 1)
    return -1;
  strcpy(*buffer, what);
  *buflen -= len + 1;
  *buffer += len + 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unbit_magic_buf>:
  endbr64
  mov    (%rcx),%rax
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jbe    L0
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    (%rdx),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  not    %rax
  add    %rax,0x0(%rbp)
  xor    %eax,%eax
  add    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int unbit_magic_buf(char *what, size_t len, char **buffer, size_t *buflen) {
  if (len >= *buflen - 1)
    return -1;
  strcpy(*buffer, what);
  *buflen -= len + 1;
  *buffer += len + 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<unbit_magic_buf>:
  endbr64
  mov    (%rcx),%rax
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jbe    L9
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    (%rdx),%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  not    %rax
  add    %rax,0x0(%rbp)
  xor    %eax,%eax
  add    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int unbit_magic_buf(char *what, size_t len, char **buffer, size_t *buflen) {
  if (len >= *buflen - 1)
    return -1;
  strcpy(*buffer, what);
  *buflen -= len + 1;
  *buffer += len + 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: %d

assistant: ```c
char *itoa(int value) {
  char *s;
  s = (char *)malloc(sizeof(char) * 256);
  sprintf(s, "%d", value);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: %d

assistant: ```c
char *itoa(int value) {
  char *s;
  s = (char *)malloc(sizeof(char) * 256);
  sprintf(s, "%d", value);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x100,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: %d

assistant: ```c
char *itoa(int value) {
  char *s;
  s = (char *)malloc(sizeof(char) * 256);
  sprintf(s, "%d", value);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x100,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
char *itoa(int value) {
  char *s;
  s = (char *)malloc(sizeof(char) * 256);
  sprintf(s, "%d", value);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<LOGf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %rdi,-0x4d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L17
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L17:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x4d8(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%ecx
  mov    -0x4d8(%rbp),%rdx
  lea    -0x4c0(%rbp),%rax
  mov    $0x3ff,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  movb   $0xa,-0xc2(%rbp)
  movb   $0x0,-0xc1(%rbp)
  lea    -0x4c0(%rbp),%rax
  mov    %rax,%rdi
  call   <LOG@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void LOGf(const char *fmt, ...) {
  char msg[1024];
  va_list args;
  va_start(args, fmt);
  vsnprintf(msg, sizeof(msg) - 1, fmt, args);
  va_end(args);
  msg[sizeof(msg) - 2] = '\n';
  msg[sizeof(msg) - 1] = '\0';
  LOG(msg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LOGf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x3ff,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0xa,0x3fe(%rsp)
  movb   $0x0,0x3ff(%rsp)
  mov    %r12,%rdi
  call   <LOG@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGf(const char *fmt, ...) {
  char msg[1024];
  va_list args;
  va_start(args, fmt);
  vsnprintf(msg, sizeof(msg) - 1, fmt, args);
  va_end(args);
  msg[sizeof(msg) - 2] = '\n';
  msg[sizeof(msg) - 1] = '\0';
  LOG(msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LOGf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x3ff,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xa,%eax
  mov    %r13,%rdi
  mov    %ax,0x3fe(%rsp)
  call   <LOG@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGf(const char *fmt, ...) {
  char msg[1024];
  va_list args;
  va_start(args, fmt);
  vsnprintf(msg, sizeof(msg) - 1, fmt, args);
  va_end(args);
  msg[sizeof(msg) - 2] = '\n';
  msg[sizeof(msg) - 1] = '\0';
  LOG(msg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LOGf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x3ff,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0xa,%eax
  mov    %r13,%rdi
  mov    %ax,0x3fe(%rsp)
  call   <LOG@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGf(const char *fmt, ...) {
  char msg[1024];
  va_list args;
  va_start(args, fmt);
  vsnprintf(msg, sizeof(msg) - 1, fmt, args);
  va_end(args);
  msg[sizeof(msg) - 2] = '\n';
  msg[sizeof(msg) - 1] = '\0';
  LOG(msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L55
  mov    -0x34(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L55
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L18
L55:
  mov    $0x0,%eax
  jmp    L5
L18:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L9
L64:
  mov    -0x18(%rbp),%eax
  lea    -0x2(%rax),%esi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <helper>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  lea    0x2(%rax),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  call   <helper>
  lea    (%rbx,%rax,1),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L33
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L33:
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L64
  mov    -0x1c(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int helper(int i, int j, int *nums, int n) {
  if (i < 0 || j > n - 1 || i > j)
    return 0;
  int res = INT_MIN;
  for (int k = i; k <= j; k++) {
    int tmp = helper(i, k - 2, nums, n) + helper(k + 2, j, nums, n) + nums[k];
    if (res < tmp)
      res = tmp;
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r12
  mov    %edi,%edx
  shr    $0x1f,%edx
  cmp    %esi,%edi
  setg   %al
  or     %dl,%al
  jne    L17
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %ecx,%r14d
  cmp    %esi,%ecx
  jle    L17
  mov    D3(%rip),%rax
  mov    (%rax),%r15d
  movslq %edi,%rbx
L10:
  lea    -0x2(%rbx),%esi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %r13d,%edi
  call   <helper>
  mov    %eax,0xc(%rsp)
  lea    0x2(%rbx),%edi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  call   <helper>
  add    0xc(%rsp),%eax
  add    (%r12,%rbx,4),%eax
  cmp    %eax,%r15d
  cmovl  %eax,%r15d
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L10
  jmp    L0
L17:
  mov    $0x0,%r15d
L0:
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int helper(int i, int j, int *nums, int n) {
  if (i < 0 || j > n - 1 || i > j)
    return 0;
  int res = INT_MIN;
  for (int k = i; k <= j; k++) {
    int tmp = helper(i, k - 2, nums, n) + helper(k + 2, j, nums, n) + nums[k];
    if (res < tmp)
      res = tmp;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    %edi,%edx
  push   %r12
  shr    $0x1f,%edx
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %esi,%edi
  setg   %al
  or     %dl,%al
  jne    L1
  mov    %esi,%r12d
  mov    %ecx,%r15d
  cmp    %esi,%ecx
  jle    L1
  mov    D5(%rip),%rax
  mov    %edi,%r14d
  movslq %edi,%rbp
  mov    (%rax),%r8d
L39:
  lea    -0x2(%rbp),%esi
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r14d,%edi
  mov    %r8d,0xc(%rsp)
  call   <helper>
  lea    0x2(%rbp),%edi
  mov    %r15d,%ecx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %eax,%ebx
  call   <helper>
  mov    0xc(%rsp),%r8d
  add    %ebx,%eax
  add    0x0(%r13,%rbp,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rbp
  cmp    %ebp,%r12d
  jge    L39
  jmp    L2
  nopl   0x0(%rax)
L1:
  xor    %r8d,%r8d
L2:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int helper(int i, int j, int *nums, int n) {
  if (i < 0 || j > n - 1 || i > j)
    return 0;
  int res = INT_MIN;
  for (int k = i; k <= j; k++) {
    int tmp = helper(i, k - 2, nums, n) + helper(k + 2, j, nums, n) + nums[k];
    if (res < tmp)
      res = tmp;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clearInputStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L9
  nop
L18:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L9
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L18
L9:
  nop
  leave
  ret
```

assistant: ```c
void clearInputStream(char *in) {
  int c, len;
  len = strlen(in);
  if (in[len - 1] != '\n')
    while ((c = getchar()) != '\n' && c != EOF)
      ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clearInputStream>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L7
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L7
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L5
L7:
  pop    %rbx
  ret
```

assistant: ```c
void clearInputStream(char *in) {
  int c, len;
  len = strlen(in);
  if (in[len - 1] != '\n')
    while ((c = getchar()) != '\n' && c != EOF)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clearInputStream>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  jne    L30
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L5:
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L8
L30:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L5
L8:
  pop    %rbx
  ret
```

assistant: ```c
void clearInputStream(char *in) {
  int c, len;
  len = strlen(in);
  if (in[len - 1] != '\n')
    while ((c = getchar()) != '\n' && c != EOF)
      ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clearInputStream>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  jne    L7
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L35
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L6
L35:
  pop    %rbx
  ret
```

assistant: ```c
void clearInputStream(char *in) {
  int c, len;
  len = strlen(in);
  if (in[len - 1] != '\n')
    while ((c = getchar()) != '\n' && c != EOF)
      ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add_vectors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_vectors(float *v1, float *v2, float *v3, int i0, int i1) {
  int i;
  for (i = 0; i < i1 - i0; i++)
    v3[i] = v1[i] + v2[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_vectors>:
  endbr64
  sub    %ecx,%r8d
  test   %r8d,%r8d
  jle    L9
  mov    %r8d,%r8d
  mov    $0x0,%eax
L16:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L16
L9:
  ret
```

assistant: ```c
void add_vectors(float *v1, float *v2, float *v3, int i0, int i1) {
  int i;
  for (i = 0; i < i1 - i0; i++)
    v3[i] = v1[i] + v2[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<add_vectors>:
  endbr64
  sub    %ecx,%r8d
  test   %r8d,%r8d
  jle    L5
  movslq %r8d,%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L17
L5:
  ret
```

assistant: ```c
void add_vectors(float *v1, float *v2, float *v3, int i0, int i1) {
  int i;
  for (i = 0; i < i1 - i0; i++)
    v3[i] = v1[i] + v2[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<add_vectors>:
  endbr64
  sub    %ecx,%r8d
  test   %r8d,%r8d
  jle    L49
  lea    0x4(%rdi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  seta   %cl
  cmp    $0x1,%r8d
  setne  %al
  test   %al,%cl
  je     L35
  lea    0x4(%rsi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L35
  lea    -0x1(%r8),%eax
  mov    %r8d,%r9d
  cmp    $0x2,%eax
  jbe    L2
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
L1:
  movups (%rdi,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L1
  mov    %r8d,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%r8d
  je     L49
  mov    %r8d,%r9d
  sub    %ecx,%r9d
  cmp    $0x1,%r9d
  je     L10
L89:
  movq   (%rdi,%rcx,4),%xmm0
  movq   (%rsi,%rcx,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdx,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L49
L10:
  cltq
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  ret
  nopl   0x0(%rax)
L35:
  movslq %r8d,%r8
  xor    %eax,%eax
  nopl   (%rax)
L14:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L14
L49:
  ret
L2:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L89
```

assistant: ```c
void add_vectors(float *v1, float *v2, float *v3, int i0, int i1) {
  int i;
  for (i = 0; i < i1 - i0; i++)
    v3[i] = v1[i] + v2[i];
}
```