ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L20
L36:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L49
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  jmp    L8
L49:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L8:
  addb   $0x2,-0xa(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L36
  movzbl -0x9(%rbp),%eax
  lea    0x10(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)16;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x45(%rax),%edx
  movzbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L14
  mov    $0x0,%eax
  mov    $0x0,%r8d
L11:
  lea    0x0(,%rdx,4),%ecx
  cmp    %dl,%al
  cmovb  %r8d,%ecx
  mov    %ecx,%edx
  add    $0x2,%eax
  cmp    %dil,%al
  jb     L11
L14:
  add    $0x10,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)16;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  lea    0x45(%rax),%edx
  test   %dil,%dil
  je     L3
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    %dl,%al
  lea    0x0(,%rdx,4),%ecx
  cmovb  %r8d,%ecx
  add    $0x2,%eax
  mov    %ecx,%edx
  cmp    %dil,%al
  jb     L2
L3:
  add    $0x10,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)16;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  lea    0x45(%rax),%edx
  test   %dil,%dil
  je     L13
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %al,%dl
  lea    0x0(,%rdx,4),%ecx
  cmova  %r8d,%ecx
  add    $0x2,%eax
  mov    %ecx,%edx
  cmp    %al,%dil
  ja     L7
L13:
  add    $0x10,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        state[local1] = state[0UL] + state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)16;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x2c(%rsp)
  movl   $0x0,0x34(%rsp)
  lea    0x2c(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jne    L47
  mov    %rbx,%rax
  lea    0x36(%rsp),%rdx
L16:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
  movsbl 0x2e(%rsp),%eax
  lea    (%rax,%rax,4),%edx
  movsbl 0x2f(%rsp),%eax
  lea    (%rax,%rdx,2),%ecx
  mov    $0x1,%esi
  cmp    $0x35,%ecx
  ja     L22
  movabs $0x3ffe03ffe01ffe,%rsi
  shr    %cl,%rsi
  xor    $0x1,%rsi
  and    $0x1,%esi
L22:
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  mov    $0x0,%eax
  mov    $0x0,%ecx
  lea    0x2c(%rsp),%r8
  mov    %rsp,%rdi
L38:
  movsbl (%rax,%r8,1),%edx
  imul   (%rdi,%rax,4),%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L38
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  movsbl 0x35(%rsp),%edx
  xor    $0x1,%esi
  movzbl %sil,%esi
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmovne %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L47:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L13
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D15: %s

tool: D3: %d

assistant: ```c
int main() {
  int result = 0;
  char egn[12] = {0};
  scanf("%s", egn);
  if (strlen(egn) == 10) {
    for (int i = 0; i < 10; i++)
      egn[i] -= '0';
    int month = egn[3] + egn[2] * 10;
    if ((month >= 1 && month <= 12) || (month >= 21 && month <= 33) || (month >= 41 && month <= 53)) {
      result = 1;
    } else {
      result = 0;
    }
    int tmp = 0;
    int tmps[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
    for (int i = 0; i < 10; i++) {
      tmp += egn[i] * tmps[i];
    }
    tmp %= 11;
    if (tmp == 10)
      tmp = 0;
    if (tmp == egn[9]) {
    } else {
      result = 0;
    }
  } else {
    printf("0");
    return 0;
  }
  printf("%d", result);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rbx
  movl   $0x0,0x34(%rsp)
  movq   $0x0,0x2c(%rsp)
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jne    L55
  mov    %rbx,%rax
  lea    0x36(%rsp),%rdx
  nopw   0x0(%rax,%rax,1)
L12:
  subb   $0x30,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  movsbl 0x2e(%rsp),%eax
  mov    $0x1,%esi
  lea    (%rax,%rax,4),%edx
  movsbl 0x2f(%rsp),%eax
  lea    (%rax,%rdx,2),%ecx
  cmp    $0x35,%ecx
  jbe    L42
L32:
  movabs $0x800000004,%rax
  mov    $0x2,%edi
  xor    %ecx,%ecx
  mov    %rax,0x4(%rsp)
  movabs $0xa00000005,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x700000009,%rax
  mov    %rax,0x14(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x1c(%rsp)
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax)
L79:
  mov    (%rsp,%rax,4),%edi
L67:
  movsbl (%rbx,%rax,1),%edx
  add    $0x1,%rax
  imul   %edi,%edx
  add    %edx,%ecx
  cmp    $0xa,%rax
  jne    L79
  movslq %ecx,%rax
  mov    %ecx,%edx
  lea    D1(%rip),%rdi
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  movsbl 0x35(%rsp),%ecx
  sub    %edx,%eax
  xor    %edx,%edx
  cmp    $0xa,%eax
  cmove  %edx,%eax
  xor    $0x1,%esi
  movzbl %sil,%esi
  cmp    %eax,%ecx
  cmovne %edx,%esi
  xor    %eax,%eax
  call   <printf@plt>
L37:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L42:
  movabs $0xffc001fc001fe001,%rsi
  sar    %cl,%rsi
  and    $0x1,%esi
  jmp    L32
L55:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L37
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D10: %s

tool: D1: %d

assistant: ```c
int main() {
  int result = 0;
  char egn[12] = {0};
  scanf("%s", egn);
  if (strlen(egn) == 10) {
    for (int i = 0; i < 10; i++)
      egn[i] -= '0';
    int month = egn[3] + egn[2] * 10;
    if ((month >= 1 && month <= 12) || (month >= 21 && month <= 33) || (month >= 41 && month <= 53)) {
      result = 1;
    } else {
      result = 0;
    }
    int tmp = 0;
    int tmps[9] = {2, 4, 8, 5, 10, 9, 7, 3, 6};
    for (int i = 0; i < 10; i++) {
      tmp += egn[i] * tmps[i];
    }
    tmp %= 11;
    if (tmp == 10)
      tmp = 0;
    if (tmp == egn[9]) {
    } else {
      result = 0;
    }
  } else {
    printf("0");
    return 0;
  }
  printf("%d", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prio_in_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L14
  cmpl   $0x7,-0x4(%rbp)
  jle    L29
L14:
  mov    $0x0,%eax
  jmp    L9
L29:
  mov    $0x1,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int prio_in_range(int prio) {
  if ((prio < 0) || (prio > 7))
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prio_in_range>:
  endbr64
  cmp    $0x7,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int prio_in_range(int prio) {
  if ((prio < 0) || (prio > 7))
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prio_in_range>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%edi
  setbe  %al
  ret
```

assistant: ```c
int prio_in_range(int prio) {
  if ((prio < 0) || (prio > 7))
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<prio_in_range>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7,%edi
  setbe  %al
  ret
```

assistant: ```c
int prio_in_range(int prio) {
  if ((prio < 0) || (prio > 7))
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L133
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D37(%rip),%r12
L39:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  mov    %eax,0x60(%rsp,%rbx,4)
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jne    L39
L133:
  movl   $0x0,0x10(%rsp)
  cltq
  movl   $0x0,0x10(%rsp,%rax,4)
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0x60(%rsp,%rax,4)
  mov    $0x3e8,%r13d
  lea    D35(%rip),%r14
  jmp    L43
L132:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  je     L5
L123:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  je     L84
L36:
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  jne    L132
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L132
L5:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r15d,%r12d
  jmp    L123
L84:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x60(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  call   <next_generation@plt>
  cmp    $0x1,%r12d
  je     L13
  sub    $0x1,%r13d
  je     L16
L43:
  cmpl   $0x0,0xc(%rsp)
  je     L51
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  lea    0x10(%rsp),%rbp
  mov    $0x0,%r15d
  jmp    L36
L16:
  mov    $0x0,%eax
  jmp    L13
L51:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x60(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  call   <next_generation@plt>
L13:
  mov    0xb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L121
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L121:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D37
type_infered: string
name: unpack_data
arguments: tag: D35
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D37: %d

tool: D35: .

tool: D5: *

tool: D12: 


assistant: ```c
int main(void) {
  int old_cells[20];
  int new_cells[20];
  int limiter;
  int counter;
  scanf("%d", &limiter);
  counter = 0;
  while (counter != limiter) {
    scanf("%d", &old_cells[counter]);
    new_cells[counter] = old_cells[counter];
    counter++;
  }
  old_cells[0] = 0;
  old_cells[counter] = 0;
  new_cells[0] = 0;
  new_cells[counter] = 0;
  int generation_counter = 0;
  int deadflag = 1;
  while (generation_counter != 1000) {
    counter = 0;
    while (counter != limiter) {
      if (old_cells[counter] == 0) {
        printf(".");
      }
      if (old_cells[counter] == 1) {
        printf("*");
        deadflag = 0;
      }
      counter++;
    }
    printf("\n");
    next_generation(old_cells, new_cells, limiter);
    generation_counter++;
    if (deadflag == 1) {
      return;
    }
    deadflag = 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0xa,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <f2@plt>
  nop
  leave
  ret
```

assistant: ```c
void f1(int age) {
  int local = 10;
  f2(age + local);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f1>:
  endbr64
  sub    $0x8,%rsp
  add    $0xa,%edi
  call   <f2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f1(int age) {
  int local = 10;
  f2(age + local);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f1>:
  endbr64
  add    $0xa,%edi
  jmp    1050 <f2@plt>
```

assistant: ```c
void f1(int age) {
  int local = 10;
  f2(age + local);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f1>:
  endbr64
  add    $0xa,%edi
  jmp    1050 <f2@plt>
```

assistant: ```c
void f1(int age) {
  int local = 10;
  f2(age + local);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<allocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <error@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: allocate: not enuf memory (%d bytes)


assistant: ```c
void *allocate(nb)
int nb;
{
  void *mem;
  mem = (void *)calloc(nb, 1);
  if (mem == 0)
    error("allocate: not enuf memory (%d bytes)\n", nb);
  return (mem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  movslq %edi,%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L17:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: allocate: not enuf memory (%d bytes)


assistant: ```c
void *allocate(nb)
int nb;
{
  void *mem;
  mem = (void *)calloc(nb, 1);
  if (mem == 0)
    error("allocate: not enuf memory (%d bytes)\n", nb);
  return (mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocate>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: allocate: not enuf memory (%d bytes)


assistant: ```c
void *allocate(nb)
int nb;
{
  void *mem;
  mem = (void *)calloc(nb, 1);
  if (mem == 0)
    error("allocate: not enuf memory (%d bytes)\n", nb);
  return (mem);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<allocate>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  mov    $0x1,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: allocate: not enuf memory (%d bytes)


assistant: ```c
void *allocate(nb)
int nb;
{
  void *mem;
  mem = (void *)calloc(nb, 1);
  if (mem == 0)
    error("allocate: not enuf memory (%d bytes)\n", nb);
  return (mem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L15
L7:
  movl   $0x0,-0x54(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x5c(%rbp)
  jmp    L43
L48:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L47
L29:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  movsbl %al,%eax
  lea    -0x41(%rax),%edx
  mov    -0x5c(%rbp),%eax
  add    %eax,%edx
  mov    -0x58(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x54(%rbp)
  addl   $0x1,-0x58(%rbp)
L47:
  mov    -0x58(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L29
  addl   $0x1,-0x5c(%rbp)
L43:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x5c(%rbp)
  jl     L48
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  mov    -0x64(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x64(%rbp)
  test   %eax,%eax
  jg     L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D39
datatype: string

tool: D31: %d


tool: D39: %s


assistant: ```c
int main(void) {
  int casos, quantidadeDeLinhas, indiceDaLinha, indiceDaPalavra, hash;
  char palavra[64];
  scanf("%d\n", &casos);
  while (casos-- > 0) {
    hash = 0;
    scanf("%d\n", &quantidadeDeLinhas);
    for (indiceDaLinha = 0; indiceDaLinha < quantidadeDeLinhas; indiceDaLinha++) {
      scanf("%s\n", palavra);
      indiceDaPalavra = 0;
      while (palavra[indiceDaPalavra] != '\0') {
        hash += ((palavra[indiceDaPalavra]) - 'A') + indiceDaLinha + indiceDaPalavra;
        indiceDaPalavra++;
      }
    }
    printf("%d\n", hash);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jle    L8
  lea    0xc(%rsp),%r15
  lea    D26(%rip),%r14
  lea    D24(%rip),%r13
  lea    0x10(%rsp),%r12
L31:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L57
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L52:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L7
  mov    $0x0,%edx
L24:
  movsbl %al,%eax
  lea    -0x41(%rbp,%rax,1),%eax
  add    %edx,%eax
  add    %eax,%ebx
  add    $0x1,%rdx
  movzbl (%rdx,%r12,1),%eax
  test   %al,%al
  jne    L24
L7:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L52
L42:
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jg     L31
L8:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    $0x0,%ebx
  jmp    L42
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D24
data_type: string

tool: D26: %d


tool: D24: %s


assistant: ```c
int main(void) {
  int casos, quantidadeDeLinhas, indiceDaLinha, indiceDaPalavra, hash;
  char palavra[64];
  scanf("%d\n", &casos);
  while (casos-- > 0) {
    hash = 0;
    scanf("%d\n", &quantidadeDeLinhas);
    for (indiceDaLinha = 0; indiceDaLinha < quantidadeDeLinhas; indiceDaLinha++) {
      scanf("%s\n", palavra);
      indiceDaPalavra = 0;
      while (palavra[indiceDaPalavra] != '\0') {
        hash += ((palavra[indiceDaPalavra]) - 'A') + indiceDaLinha + indiceDaPalavra;
        indiceDaPalavra++;
      }
    }
    printf("%d\n", hash);
  }
  return 0;
}
```