ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<glob_path>:
  endbr64
  push   %r13
  xor    %edx,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <glob@plt>
  test   %rax,%rax
  jne    L17
  cmpl   $0x1,(%rsp)
  je     L29
  lea    D0(%rip),%rdi
  call   <printf@plt>
L38:
  mov    %rbp,%rdi
  call   <globfree@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L29:
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  mov    $0xffffffff,%r12d
  mov    (%rax),%esi
  call   <strcpy@plt>
  jmp    L38
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: Ambiguous input


assistant: ```c
int glob_path(const char *pattern, char *buffer) {
  glob_t globbuf;
  int status = 0;
  if (glob(pattern, 0, NULL, &globbuf)) {
    if (status & GLOB_ABORTED)
      printf("GLOB_ABORTED\n");
    if (status & GLOB_NOMATCH)
      printf("GLOB_NOMATCH\n");
    if (status & GLOB_NOSPACE)
      printf("GLOB_NOSPACE\n");
    return 0;
  }
  if (globbuf.gl_pathc == 1) {
    strcpy(buffer, globbuf.gl_pathv[0]);
    status = -1;
  } else {
    printf("Ambiguous input\n");
    status = 0;
  }
  globfree(&globbuf);
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glob_path>:
  endbr64
  push   %r13
  xor    %edx,%edx
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <glob@plt>
  test   %rax,%rax
  jne    L25
  cmpl   $0x1,(%rsp)
  je     L21
  lea    D2(%rip),%rdi
  call   <printf@plt>
L24:
  mov    %rbp,%rdi
  call   <globfree@plt>
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L21:
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  mov    $0xffffffff,%r12d
  mov    (%rax),%esi
  call   <strcpy@plt>
  jmp    L24
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: Ambiguous input


assistant: ```c
int glob_path(const char *pattern, char *buffer) {
  glob_t globbuf;
  int status = 0;
  if (glob(pattern, 0, NULL, &globbuf)) {
    if (status & GLOB_ABORTED)
      printf("GLOB_ABORTED\n");
    if (status & GLOB_NOMATCH)
      printf("GLOB_NOMATCH\n");
    if (status & GLOB_NOSPACE)
      printf("GLOB_NOSPACE\n");
    return 0;
  }
  if (globbuf.gl_pathc == 1) {
    strcpy(buffer, globbuf.gl_pathv[0]);
    status = -1;
  } else {
    printf("Ambiguous input\n");
    status = 0;
  }
  globfree(&globbuf);
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AllPoleFilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L33:
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L7:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  neg    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L7
  addq   $0x4,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AllPoleFilter(float *InOut, const float *Coef, int lengthInOut, int orderCoef) {
  int n;
  int k;
  for (n = 0; n < lengthInOut; n++) {
    for (k = 1; k <= orderCoef; k++)
      *InOut -= Coef[k] * InOut[-k];
    InOut++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<AllPoleFilter>:
  endbr64
  test   %edx,%edx
  jle    L10
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%r9
  lea    -0x1(%rcx),%eax
  lea    0x8(%rsi,%rax,4),%r8
  jmp    L5
L26:
  movss  (%rax),%xmm1
  mulss  (%rdx),%xmm1
  movss  (%rdi),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  add    $0x4,%rax
  sub    $0x4,%rdx
  cmp    %r8,%rax
  jne    L26
L14:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  je     L10
L5:
  lea    0x4(%rsi),%rax
  lea    -0x4(%rdi),%rdx
  test   %ecx,%ecx
  jg     L26
  jmp    L14
L10:
  ret
```

assistant: ```c
void AllPoleFilter(float *InOut, const float *Coef, int lengthInOut, int orderCoef) {
  int n;
  int k;
  for (n = 0; n < lengthInOut; n++) {
    for (k = 1; k <= orderCoef; k++)
      *InOut -= Coef[k] * InOut[-k];
    InOut++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AllPoleFilter>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  lea    -0x1(%rcx),%eax
  lea    (%rdi,%rdx,4),%r9
  lea    0x8(%rsi,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L8:
  test   %ecx,%ecx
  jle    L31
  movss  (%rdi),%xmm1
  lea    0x4(%rsi),%rax
  lea    -0x4(%rdi),%rdx
L1:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  sub    $0x4,%rdx
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %rax,%r8
  jne    L1
L31:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L8
L2:
  ret
```

assistant: ```c
void AllPoleFilter(float *InOut, const float *Coef, int lengthInOut, int orderCoef) {
  int n;
  int k;
  for (n = 0; n < lengthInOut; n++) {
    for (k = 1; k <= orderCoef; k++)
      *InOut -= Coef[k] * InOut[-k];
    InOut++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AllPoleFilter>:
  endbr64
  test   %edx,%edx
  jle    L16
  test   %ecx,%ecx
  jle    L16
  movslq %edx,%rdx
  lea    -0x1(%rcx),%eax
  lea    0x8(%rsi,%rax,4),%rcx
  lea    (%rdi,%rdx,4),%r8
  add    $0x4,%rsi
  nop
L31:
  movss  (%rdi),%xmm1
  mov    %rsi,%rax
  lea    -0x4(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L10:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  sub    $0x4,%rdx
  subss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  cmp    %rax,%rcx
  jne    L10
  add    $0x4,%rdi
  cmp    %rdi,%r8
  jne    L31
L16:
  ret
```

assistant: ```c
void AllPoleFilter(float *InOut, const float *Coef, int lengthInOut, int orderCoef) {
  int n;
  int k;
  for (n = 0; n < lengthInOut; n++) {
    for (k = 1; k <= orderCoef; k++)
      *InOut -= Coef[k] * InOut[-k];
    InOut++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<asn1Encap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ax,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movzwl -0x24(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <asn1StoreTag@plt>
  mov    -0x28(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <asn1StoreLength@plt>
  mov    -0x18(%rbp),%rax
  lea    -0xe(%rbp),%rdx
  sub    %rdx,%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  mov    -0x1c(%rbp),%edx
  lea    -0xe(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int asn1Encap(unsigned short Tag, unsigned char *Msg, int MsgLen) {
  unsigned char tmpbuf[6], *po;
  int len;
  po = tmpbuf;
  asn1StoreTag(&po, Tag);
  asn1StoreLength(&po, MsgLen);
  len = (int)(po - tmpbuf);
  memmove(Msg + len, Msg, MsgLen);
  memmove(Msg, tmpbuf, len);
  return MsgLen + len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<asn1Encap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x12(%rsp),%r13
  mov    %r13,0x8(%rsp)
  movzwl %di,%esi
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rdi
  call   <asn1StoreTag@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <asn1StoreLength@plt>
  mov    0x8(%rsp),%rbp
  sub    %r13,%rbp
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <memmove@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1Encap(unsigned short Tag, unsigned char *Msg, int MsgLen) {
  unsigned char tmpbuf[6], *po;
  int len;
  po = tmpbuf;
  asn1StoreTag(&po, Tag);
  asn1StoreLength(&po, MsgLen);
  len = (int)(po - tmpbuf);
  memmove(Msg + len, Msg, MsgLen);
  memmove(Msg, tmpbuf, len);
  return MsgLen + len;
}
```
user: What is the c source code of the assembly code below:

```asm
<asn1Encap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  movzwl %di,%esi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x12(%rsp),%r13
  mov    %rbp,%rdi
  mov    %r13,0x8(%rsp)
  call   <asn1StoreTag@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  call   <asn1StoreLength@plt>
  mov    0x8(%rsp),%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  sub    %r13,%rbp
  movslq %ebp,%rdi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1Encap(unsigned short Tag, unsigned char *Msg, int MsgLen) {
  unsigned char tmpbuf[6], *po;
  int len;
  po = tmpbuf;
  asn1StoreTag(&po, Tag);
  asn1StoreLength(&po, MsgLen);
  len = (int)(po - tmpbuf);
  memmove(Msg + len, Msg, MsgLen);
  memmove(Msg, tmpbuf, len);
  return MsgLen + len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<asn1Encap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  movzwl %di,%esi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x12(%rsp),%r13
  mov    %rbp,%rdi
  mov    %r13,0x8(%rsp)
  call   <asn1StoreTag@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  call   <asn1StoreLength@plt>
  mov    0x8(%rsp),%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  sub    %r13,%rbp
  movslq %ebp,%rdi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int asn1Encap(unsigned short Tag, unsigned char *Msg, int MsgLen) {
  unsigned char tmpbuf[6], *po;
  int len;
  po = tmpbuf;
  asn1StoreTag(&po, Tag);
  asn1StoreLength(&po, MsgLen);
  len = (int)(po - tmpbuf);
  memmove(Msg + len, Msg, MsgLen);
  memmove(Msg, tmpbuf, len);
  return MsgLen + len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L39
L24:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L3
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L4
L3:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L24
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D13: %d

tool: D25: NO

tool: D1: YES

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 2; i < num; i++) {
    if (0 == num % i) {
      printf("NO");
      return 0;
    }
  }
  printf("YES");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L50
  test   $0x1,%sil
  je     L13
  mov    $0x2,%ecx
L19:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L50
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L19
L13:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L56
L50:
  lea    D18(%rip),%rdi
  call   <printf@plt>
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D25: %d

tool: D0: NO

tool: D18: YES

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 2; i < num; i++) {
    if (0 == num % i) {
      printf("NO");
      return 0;
    }
  }
  printf("YES");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L22
  test   $0x1,%sil
  je     L14
  mov    $0x2,%ecx
  jmp    L38
  nop
L66:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L14
L38:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L66
L22:
  lea    D7(%rip),%rdi
  call   <printf@plt>
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D6: %d

tool: D7: YES

tool: D3: NO

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 2; i < num; i++) {
    if (0 == num % i) {
      printf("NO");
      return 0;
    }
  }
  printf("YES");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L56
  test   $0x1,%sil
  je     L15
  mov    $0x2,%ecx
  jmp    L47
  nop
L27:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L15
L47:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L27
L56:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D28
type: string

tool: D3: %d

tool: D8: YES

tool: D28: NO

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  for (i = 2; i < num; i++) {
    if (0 == num % i) {
      printf("NO");
      return 0;
    }
  }
  printf("YES");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rf_bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int rf_bitcount(unsigned int v) {
  v = v - ((v >> 1) & 0x55555555);
  v = (v & 0x33333333) + ((v >> 2) & 0x33333333);
  return (((v + (v >> 4)) & 0xF0F0F0F) * 0x1010101) >> 24;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rf_bitcount>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
unsigned int rf_bitcount(unsigned int v) {
  v = v - ((v >> 1) & 0x55555555);
  v = (v & 0x33333333) + ((v >> 2) & 0x33333333);
  return (((v + (v >> 4)) & 0xF0F0F0F) * 0x1010101) >> 24;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rf_bitcount>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
unsigned int rf_bitcount(unsigned int v) {
  v = v - ((v >> 1) & 0x55555555);
  v = (v & 0x33333333) + ((v >> 2) & 0x33333333);
  return (((v + (v >> 4)) & 0xF0F0F0F) * 0x1010101) >> 24;
}
```
user: What is the c source code of the assembly code below?

```asm
<rf_bitcount>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  shr    $0x18,%eax
  ret
```

assistant: ```c
unsigned int rf_bitcount(unsigned int v) {
  v = v - ((v >> 1) & 0x55555555);
  v = (v & 0x33333333) + ((v >> 2) & 0x33333333);
  return (((v + (v >> 4)) & 0xF0F0F0F) * 0x1010101) >> 24;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<least_common_multiple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <greatest_common_divisor@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L17
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  jmp    L10
L17:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
L10:
  leave
  ret
```

assistant: ```c
int least_common_multiple(int a, int b) {
  int i;
  int gcd = greatest_common_divisor(a, b);
  if (gcd == 1)
    return a * b;
  return a * b / gcd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<least_common_multiple>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <greatest_common_divisor@plt>
  cmp    $0x1,%eax
  je     L13
  mov    %eax,%ecx
  mov    %ebx,%eax
  imul   %ebp,%eax
  cltd
  idiv   %ecx
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %ebx,%eax
  imul   %ebp,%eax
  jmp    L6
```

assistant: ```c
int least_common_multiple(int a, int b) {
  int i;
  int gcd = greatest_common_divisor(a, b);
  if (gcd == 1)
    return a * b;
  return a * b / gcd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<least_common_multiple>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <greatest_common_divisor@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  imul   %ebp,%eax
  pop    %rbp
  cltd
  idiv   %r8d
  ret
```

assistant: ```c
int least_common_multiple(int a, int b) {
  int i;
  int gcd = greatest_common_divisor(a, b);
  if (gcd == 1)
    return a * b;
  return a * b / gcd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<least_common_multiple>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <greatest_common_divisor@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  imul   %ebp,%eax
  pop    %rbp
  cltd
  idiv   %r8d
  ret
```

assistant: ```c
int least_common_multiple(int a, int b) {
  int i;
  int gcd = greatest_common_divisor(a, b);
  if (gcd == 1)
    return a * b;
  return a * b / gcd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L15
L6:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L22
  negl   -0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L6
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string

tool: D12: Enter an integer > 

tool: D9: %d

tool: D13: %d


tool: D33: That's all, have a nice day!

assistant: ```c
int main(void) {
  int userint, remainder;
  printf("Enter an integer > ");
  scanf("%d", &userint);
  printf("\n");
  while (userint != 0) {
    remainder = userint % 10;
    userint = (userint - remainder) / 10;
    if (userint < 0) {
      remainder = (-1) * remainder;
    }
    printf("%d\n", remainder);
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```