ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dou2pre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x1,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L42
  movsd  -0x28(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
L42:
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L16
L10:
  movsd  -0x28(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  ucomisd -0x28(%rbp),%xmm2
  jp     L10
  movq   %rax,%xmm3
  ucomisd -0x28(%rbp),%xmm3
  jne    L10
  movsd  -0x28(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <int2bin@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <dec2bin3@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L19
L65:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  add    $0xc,%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L19:
  cmpl   $0x2,-0x18(%rbp)
  jle    L65
  cmpl   $0x0,-0x20(%rbp)
  jne    L76
  mov    -0x10(%rbp),%rax
  add    $0xf,%rax
  movb   $0x30,(%rax)
  jmp    L9
L76:
  mov    -0x10(%rbp),%rax
  add    $0xf,%rax
  movb   $0x31,(%rax)
L9:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: byte[8]
name: parse_data
arguments: data_tag: D15
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
char *dou2pre(double a) {
  int ifpositive = 1;
  if (a < 0) {
    a = -a;
    ifpositive = 0;
  }
  char *result;
  result = (char *)malloc(sizeof(char) * 20);
  int mul10 = 0;
  while (!(a == floor(a))) {
    a *= 10;
    mul10++;
  }
  int aint = (int)(a);
  result = int2bin(aint);
  char *mul10bin;
  mul10bin = (char *)malloc(sizeof(char) * 3);
  mul10bin = dec2bin3(mul10);
  for (int i = 0; i < 3; i++) {
    result[12 + i] = mul10bin[i];
  }
  if (ifpositive == 0) {
    result[15] = '0';
  } else {
    result[15] = '1';
  }
  result[16] = '\0';
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dou2pre>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm5
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  mov    $0x1,%ebp
  comisd %xmm5,%xmm0
  ja     L58
L12:
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    $0x0,%ebx
  movsd  D15(%rip),%xmm3
  movsd  D34(%rip),%xmm2
  movsd  D42(%rip),%xmm5
  movsd  D18(%rip),%xmm4
  jmp    L4
L58:
  xorpd  D48(%rip),%xmm5
  movsd  %xmm5,0x8(%rsp)
  mov    $0x0,%ebp
  jmp    L12
L66:
  movsd  0x8(%rsp),%xmm6
  ucomisd %xmm6,%xmm1
  jp     L36
  je     L22
L36:
  movsd  0x8(%rsp),%xmm7
  mulsd  %xmm4,%xmm7
  movsd  %xmm7,0x8(%rsp)
  add    $0x1,%ebx
L4:
  movsd  0x8(%rsp),%xmm7
  movapd %xmm7,%xmm1
  movapd %xmm7,%xmm0
  andpd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm3
  jbe    L66
  cvttsd2si %xmm7,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm1
  cmpnlesd %xmm7,%xmm1
  andpd  %xmm5,%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  andnpd %xmm7,%xmm1
  orpd   %xmm0,%xmm1
  jmp    L66
L22:
  cvttsd2si %xmm6,%edi
  call   <int2bin@plt>
  mov    %rax,%r12
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %ebx,%edi
  call   <dec2bin3@plt>
  movzbl (%rax),%edx
  mov    %dl,0xc(%r12)
  movzbl 0x1(%rax),%edx
  mov    %dl,0xd(%r12)
  movzbl 0x2(%rax),%eax
  mov    %al,0xe(%r12)
  add    $0x30,%ebp
  mov    %bpl,0xf(%r12)
  movb   $0x0,0x10(%r12)
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: byte[8]
name: retrieve_data
arguments: label: D34
datatype: byte[8]
name: retrieve_data
arguments: label: D42
datatype: byte[8]
name: retrieve_data
arguments: label: D18
datatype: byte[8]
name: retrieve_data
arguments: label: D48
datatype: byte[16]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D34": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
char *dou2pre(double a) {
  int ifpositive = 1;
  if (a < 0) {
    a = -a;
    ifpositive = 0;
  }
  char *result;
  result = (char *)malloc(sizeof(char) * 20);
  int mul10 = 0;
  while (!(a == floor(a))) {
    a *= 10;
    mul10++;
  }
  int aint = (int)(a);
  result = int2bin(aint);
  char *mul10bin;
  mul10bin = (char *)malloc(sizeof(char) * 3);
  mul10bin = dec2bin3(mul10);
  for (int i = 0; i < 3; i++) {
    result[12 + i] = mul10bin[i];
  }
  if (ifpositive == 0) {
    result[15] = '0';
  } else {
    result[15] = '1';
  }
  result[16] = '\0';
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dou2pre>:
  endbr64
  push   %r12
  pxor   %xmm1,%xmm1
  push   %rbp
  push   %rbx
  mov    $0x31,%ebx
  sub    $0x10,%rsp
  comisd %xmm0,%xmm1
  jbe    L29
  xorpd  D21(%rip),%xmm0
  mov    $0x30,%ebx
L29:
  mov    $0x14,%edi
  movsd  %xmm0,0x8(%rsp)
  xor    %ebp,%ebp
  call   <malloc@plt>
  movsd  D0(%rip),%xmm4
  movsd  D6(%rip),%xmm3
  movsd  D28(%rip),%xmm6
  movsd  D34(%rip),%xmm5
  movsd  0x8(%rsp),%xmm0
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L47:
  mulsd  %xmm5,%xmm0
  add    $0x1,%ebp
L3:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  andpd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm4
  jbe    L26
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm3,%xmm2
  andnpd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L26:
  ucomisd %xmm0,%xmm2
  jp     L47
  jne    L47
  cvttsd2si %xmm0,%edi
  call   <int2bin@plt>
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %ebp,%edi
  call   <dec2bin3@plt>
  movzbl (%rax),%edx
  mov    %dl,0xc(%r12)
  movzbl 0x1(%rax),%edx
  mov    %dl,0xd(%r12)
  movzbl 0x2(%rax),%eax
  mov    %bl,0xf(%r12)
  mov    %al,0xe(%r12)
  mov    %r12,%rax
  movb   $0x0,0x10(%r12)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
data_type: byte[16]
name: disassemble_data
arguments: data_label: D0
data_type: byte[8]
name: disassemble_data
arguments: data_label: D6
data_type: byte[8]
name: disassemble_data
arguments: data_label: D28
data_type: byte[8]
name: disassemble_data
arguments: data_label: D34
data_type: byte[8]

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D6": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
char *dou2pre(double a) {
  int ifpositive = 1;
  if (a < 0) {
    a = -a;
    ifpositive = 0;
  }
  char *result;
  result = (char *)malloc(sizeof(char) * 20);
  int mul10 = 0;
  while (!(a == floor(a))) {
    a *= 10;
    mul10++;
  }
  int aint = (int)(a);
  result = int2bin(aint);
  char *mul10bin;
  mul10bin = (char *)malloc(sizeof(char) * 3);
  mul10bin = dec2bin3(mul10);
  for (int i = 0; i < 3; i++) {
    result[12 + i] = mul10bin[i];
  }
  if (ifpositive == 0) {
    result[15] = '0';
  } else {
    result[15] = '1';
  }
  result[16] = '\0';
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dou2pre>:
  endbr64
  push   %r12
  pxor   %xmm1,%xmm1
  push   %rbp
  push   %rbx
  mov    $0x31,%ebx
  sub    $0x10,%rsp
  comisd %xmm0,%xmm1
  jbe    L32
  xorpd  D27(%rip),%xmm0
  mov    $0x30,%ebx
L32:
  mov    $0x14,%edi
  movsd  %xmm0,0x8(%rsp)
  xor    %ebp,%ebp
  call   <malloc@plt>
  movsd  D22(%rip),%xmm4
  movsd  D44(%rip),%xmm3
  movsd  D29(%rip),%xmm6
  movsd  D28(%rip),%xmm5
  movsd  0x8(%rsp),%xmm0
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L17:
  mulsd  %xmm5,%xmm0
  add    $0x1,%ebp
L43:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  andpd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm4
  jbe    L35
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm2
  cmpnlesd %xmm0,%xmm2
  andpd  %xmm6,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm3,%xmm2
  andnpd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L35:
  ucomisd %xmm0,%xmm2
  jp     L17
  jne    L17
  cvttsd2si %xmm0,%edi
  call   <int2bin@plt>
  mov    $0x3,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %ebp,%edi
  call   <dec2bin3@plt>
  movzbl (%rax),%edx
  mov    %dl,0xc(%r12)
  movzbl 0x1(%rax),%edx
  mov    %dl,0xd(%r12)
  movzbl 0x2(%rax),%eax
  mov    %bl,0xf(%r12)
  mov    %al,0xe(%r12)
  mov    %r12,%rax
  movb   $0x0,0x10(%r12)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D27
type_guessed: byte[16]
name: parse_data
arguments: tag: D22
type_guessed: byte[8]
name: parse_data
arguments: tag: D44
type_guessed: byte[8]
name: parse_data
arguments: tag: D29
type_guessed: byte[8]
name: parse_data
arguments: tag: D28
type_guessed: byte[8]

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D44": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
char *dou2pre(double a) {
  int ifpositive = 1;
  if (a < 0) {
    a = -a;
    ifpositive = 0;
  }
  char *result;
  result = (char *)malloc(sizeof(char) * 20);
  int mul10 = 0;
  while (!(a == floor(a))) {
    a *= 10;
    mul10++;
  }
  int aint = (int)(a);
  result = int2bin(aint);
  char *mul10bin;
  mul10bin = (char *)malloc(sizeof(char) * 3);
  mul10bin = dec2bin3(mul10);
  for (int i = 0; i < 3; i++) {
    result[12 + i] = mul10bin[i];
  }
  if (ifpositive == 0) {
    result[15] = '0';
  } else {
    result[15] = '1';
  }
  result[16] = '\0';
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L42
L39:
  cmpl   $0x0,-0x10(%rbp)
  jne    L41
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  je     L41
  addl   $0x1,-0xc(%rbp)
  jmp    L42
L41:
  movl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L42:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jb     L39
  jmp    L29
L55:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L29:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L55
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int d;
  int trim_start;
  unsigned int c;
  char *new_str;
  d = 0;
  c = 0;
  trim_start = 0;
  new_str = ft_strnew(ft_strlen(s));
  while (c < ft_strlen(s)) {
    if (!trim_start && ft_isblank(s[c]))
      c++;
    else {
      trim_start = 1;
      new_str[d++] = s[c++];
    }
  }
  while (ft_isblank(new_str[--d]))
    new_str[d] = '\0';
  return (new_str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strtrim>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  mov    $0x1,%r15d
  jmp    L36
L32:
  mov    %ebx,%eax
  movzbl (%r12,%rax,1),%edx
  movslq %ebp,%rax
  mov    %dl,0x0(%r13,%rax,1)
  lea    0x1(%rbp),%ebp
  mov    %r15d,%r14d
L61:
  add    $0x1,%ebx
L36:
  mov    %r12,%rdi
  call   <ft_strlen@plt>
  cmp    %ebx,%eax
  jbe    L60
  test   %r14d,%r14d
  jne    L32
  mov    %ebx,%eax
  movsbl (%r12,%rax,1),%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L61
  jmp    L32
L60:
  movslq %ebp,%rbp
  lea    -0x1(%r13,%rbp,1),%rbx
  jmp    L30
L25:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L30:
  movsbl (%rbx),%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L25
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int d;
  int trim_start;
  unsigned int c;
  char *new_str;
  d = 0;
  c = 0;
  trim_start = 0;
  new_str = ft_strnew(ft_strlen(s));
  while (c < ft_strlen(s)) {
    if (!trim_start && ft_isblank(s[c]))
      c++;
    else {
      trim_start = 1;
      new_str[d++] = s[c++];
    }
  }
  while (ft_isblank(new_str[--d]))
    new_str[d] = '\0';
  return (new_str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strtrim>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r13
L17:
  mov    %r15,%rdi
  call   <ft_strlen@plt>
  cmp    %ebx,%eax
  jbe    L6
L1:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  add    %r15,%rbp
  movsbl 0x0(%rbp),%edi
  test   %r14d,%r14d
  je     L5
L20:
  movslq %r12d,%rax
  mov    $0x1,%r14d
  add    $0x1,%r12d
  mov    %dil,0x0(%r13,%rax,1)
  mov    %r15,%rdi
  call   <ft_strlen@plt>
  cmp    %ebx,%eax
  ja     L1
L6:
  movslq %r12d,%r12
  lea    -0x1(%r13,%r12,1),%rbx
  jmp    L69
  nopl   0x0(%rax)
L50:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L69:
  movsbl (%rbx),%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L50
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L5:
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L17
  movzbl 0x0(%rbp),%edi
  jmp    L20
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int d;
  int trim_start;
  unsigned int c;
  char *new_str;
  d = 0;
  c = 0;
  trim_start = 0;
  new_str = ft_strnew(ft_strlen(s));
  while (c < ft_strlen(s)) {
    if (!trim_start && ft_isblank(s[c]))
      c++;
    else {
      trim_start = 1;
      new_str[d++] = s[c++];
    }
  }
  while (ft_isblank(new_str[--d]))
    new_str[d] = '\0';
  return (new_str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strtrim>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r13
L44:
  mov    %r15,%rdi
  call   <ft_strlen@plt>
  cmp    %ebx,%eax
  jbe    L60
L36:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  add    %r15,%rbp
  movsbl 0x0(%rbp),%edi
  test   %r14d,%r14d
  je     L34
L64:
  movslq %r12d,%rax
  mov    $0x1,%r14d
  add    $0x1,%r12d
  mov    %dil,0x0(%r13,%rax,1)
  mov    %r15,%rdi
  call   <ft_strlen@plt>
  cmp    %ebx,%eax
  ja     L36
L60:
  movslq %r12d,%r12
  lea    -0x1(%r13,%r12,1),%rbx
  jmp    L8
  nopl   0x0(%rax)
L3:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L8:
  movsbl (%rbx),%edi
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L34:
  call   <ft_isblank@plt>
  test   %rax,%rax
  jne    L44
  movzbl 0x0(%rbp),%edi
  jmp    L64
```

assistant: ```c
char *ft_strtrim(char const *s) {
  int d;
  int trim_start;
  unsigned int c;
  char *new_str;
  d = 0;
  c = 0;
  trim_start = 0;
  new_str = ft_strnew(ft_strlen(s));
  while (c < ft_strlen(s)) {
    if (!trim_start && ft_isblank(s[c]))
      c++;
    else {
      trim_start = 1;
      new_str[d++] = s[c++];
    }
  }
  while (ft_isblank(new_str[--d]))
    new_str[d] = '\0';
  return (new_str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x11,-0x14(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <countBits@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L4
L26:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int retsz;
  int num = 17;
  int *a = countBits(num, &retsz);
  int i;
  for (i = 0; i < retsz; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x11,%edi
  call   <countBits@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L5
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D1(%rip),%r12
L19:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L19
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int retsz;
  int num = 17;
  int *a = countBits(num, &retsz);
  int i;
  for (i = 0; i < retsz; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x11,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <countBits@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L1
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D2(%rip),%r12
  nop
L4:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L4
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int retsz;
  int num = 17;
  int *a = countBits(num, &retsz);
  int i;
  for (i = 0; i < retsz; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x11,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <countBits@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L25
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D0(%rip),%r12
  nop
L26:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L26
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int retsz;
  int num = 17;
  int *a = countBits(num, &retsz);
  int i;
  for (i = 0; i < retsz; ++i)
    printf("%d ", a[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_scan@plt>
  mov    $0x0,%eax
  call   <test_find@plt>
  mov    $0x0,%eax
  call   <test_sort@plt>
  mov    $0x0,%eax
  call   <test_freq@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_scan();
  test_find();
  test_sort();
  test_freq();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_scan@plt>
  mov    $0x0,%eax
  call   <test_find@plt>
  mov    $0x0,%eax
  call   <test_sort@plt>
  mov    $0x0,%eax
  call   <test_freq@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_scan();
  test_find();
  test_sort();
  test_freq();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_scan@plt>
  xor    %eax,%eax
  call   <test_find@plt>
  xor    %eax,%eax
  call   <test_sort@plt>
  xor    %eax,%eax
  call   <test_freq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_scan();
  test_find();
  test_sort();
  test_freq();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_scan@plt>
  xor    %eax,%eax
  call   <test_find@plt>
  xor    %eax,%eax
  call   <test_sort@plt>
  xor    %eax,%eax
  call   <test_freq@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_scan();
  test_find();
  test_sort();
  test_freq();
  return 0;
}
```