ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atol>:
  endbr64
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L62:
  add    $0x1,%rdi
L51:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L62
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  jne    L35
  xor    %esi,%esi
  cmp    $0x2d,%al
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  sete   %sil
  test   %al,%al
  je     L36
L65:
  xor    %r8d,%r8d
  nopl   (%rax)
L16:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  add    $0x1,%rdx
  cltq
  lea    (%rax,%rcx,2),%r8
  movsbl (%rdx),%eax
  test   %al,%al
  jne    L16
L30:
  mov    %r8,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%r8
L29:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl (%rdi),%eax
  mov    %rdi,%rdx
  xor    %esi,%esi
  xor    %r8d,%r8d
  test   %al,%al
  jne    L65
  jmp    L29
L36:
  xor    %r8d,%r8d
  jmp    L30
```

assistant: ```c
long atol(const char *str) {
  long res = 0;
  int sign = 0;
  while (*str == ' ')
    str++;
  if (*str == '-' || *str == '+') {
    sign = *str == '-';
    str++;
  }
  while (*str) {
    res *= 10;
    res += *str++ - '0';
  }
  return sign ? -res : res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atol>:
  endbr64
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L60:
  add    $0x1,%rdi
L41:
  movsbl (%rdi),%eax
  cmp    $0x20,%al
  je     L60
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  jne    L58
  xor    %esi,%esi
  cmp    $0x2d,%al
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  sete   %sil
  test   %al,%al
  je     L37
L22:
  xor    %r8d,%r8d
  nopl   (%rax)
L69:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rcx
  add    $0x1,%rdx
  cltq
  lea    (%rax,%rcx,2),%r8
  movsbl (%rdx),%eax
  test   %al,%al
  jne    L69
L25:
  mov    %r8,%rax
  neg    %rax
  test   %esi,%esi
  cmovne %rax,%r8
L73:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rdi,%rdx
  xor    %esi,%esi
  xor    %r8d,%r8d
  test   %al,%al
  jne    L22
  jmp    L73
L37:
  xor    %r8d,%r8d
  jmp    L25
```

assistant: ```c
long atol(const char *str) {
  long res = 0;
  int sign = 0;
  while (*str == ' ')
    str++;
  if (*str == '-' || *str == '+') {
    sign = *str == '-';
    str++;
  }
  while (*str) {
    res *= 10;
    res += *str++ - '0';
  }
  return sign ? -res : res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copyFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x1,%eax
  jmp    L39
L0:
  mov    -0x30(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L32
  mov    $0x1,%eax
  jmp    L39
L24:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
L32:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L24
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D16: r

tool: D7: w

assistant: ```c
int copyFile(char *src, char *dest) {
  int readblocks;
  FILE *infile, *outfile;
  void *buffer;
  infile = fopen(src, "r");
  if (infile == NULL)
    return 1;
  outfile = fopen(dest, "w");
  buffer = malloc(1024 * sizeof(char));
  if (outfile == NULL)
    return 1;
  while (!feof(infile)) {
    readblocks = fread(buffer, sizeof(char), 1024, infile);
    fwrite(buffer, sizeof(char), readblocks, outfile);
  }
  free(buffer);
  fclose(infile);
  fclose(outfile);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copyFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
  test   %rbx,%rbx
  je     L22
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12,%r12
  jne    L4
  mov    $0x1,%eax
  jmp    L22
L39:
  mov    %rbx,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  mov    %eax,%edx
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
L4:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L39
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: string

tool: D10: r

tool: D3: w

assistant: ```c
int copyFile(char *src, char *dest) {
  int readblocks;
  FILE *infile, *outfile;
  void *buffer;
  infile = fopen(src, "r");
  if (infile == NULL)
    return 1;
  outfile = fopen(dest, "w");
  buffer = malloc(1024 * sizeof(char));
  if (outfile == NULL)
    return 1;
  while (!feof(infile)) {
    readblocks = fread(buffer, sizeof(char), 1024, infile);
    fwrite(buffer, sizeof(char), readblocks, outfile);
  }
  free(buffer);
  fclose(infile);
  fclose(outfile);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copyFile>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D11(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    $0x400,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13,%r13
  jne    L18
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %r13,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <fwrite@plt>
L18:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L5
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D11
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D11: r

tool: D14: w

assistant: ```c
int copyFile(char *src, char *dest) {
  int readblocks;
  FILE *infile, *outfile;
  void *buffer;
  infile = fopen(src, "r");
  if (infile == NULL)
    return 1;
  outfile = fopen(dest, "w");
  buffer = malloc(1024 * sizeof(char));
  if (outfile == NULL)
    return 1;
  while (!feof(infile)) {
    readblocks = fread(buffer, sizeof(char), 1024, infile);
    fwrite(buffer, sizeof(char), readblocks, outfile);
  }
  free(buffer);
  fclose(infile);
  fclose(outfile);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copyFile>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D11(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  lea    D0(%rip),%rsi
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    $0x400,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13,%r13
  jne    L3
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rbp,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %r13,%rcx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <fwrite@plt>
L3:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L37
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type: string
name: disassemble_data
arguments: tag: D0
type: string

tool: D11: r

tool: D0: w

assistant: ```c
int copyFile(char *src, char *dest) {
  int readblocks;
  FILE *infile, *outfile;
  void *buffer;
  infile = fopen(src, "r");
  if (infile == NULL)
    return 1;
  outfile = fopen(dest, "w");
  buffer = malloc(1024 * sizeof(char));
  if (outfile == NULL)
    return 1;
  while (!feof(infile)) {
    readblocks = fread(buffer, sizeof(char), 1024, infile);
    fwrite(buffer, sizeof(char), readblocks, outfile);
  }
  free(buffer);
  fclose(infile);
  fclose(outfile);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testLevenshtein>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <levenshtein@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L33
L19:
  cmpl   $0x0,-0x4(%rbp)
  jne    L11
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L33
L11:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L33:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string
name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D26
data_type: string

tool: D29: Distance between "%s" and "%s": %d


tool: D34: strings are too big to be compared

tool: D21: strings are equal

tool: D26: strings are differents

assistant: ```c
void testLevenshtein(const char *s1, const char *s2) {
  int distance = levenshtein(s1, s2);
  printf("Distance between \"%s\" and \"%s\": %d\n", s1, s2, distance);
  if (distance < 0)
    puts("strings are too big to be compared");
  else if (distance == 0)
    puts("strings are equal");
  else
    puts("strings are differents");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testLevenshtein>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <levenshtein@plt>
  mov    %eax,%ebx
  mov    %eax,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  js     L15
  jne    L27
  lea    D24(%rip),%rdi
  call   <puts@plt>
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L27:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D8
data_type: string
name: parse_data
arguments: data_label: D33
data_type: string

tool: D13: Distance between "%s" and "%s": %d


tool: D24: strings are equal

tool: D8: strings are too big to be compared

tool: D33: strings are differents

assistant: ```c
void testLevenshtein(const char *s1, const char *s2) {
  int distance = levenshtein(s1, s2);
  printf("Distance between \"%s\" and \"%s\": %d\n", s1, s2, distance);
  if (distance < 0)
    puts("strings are too big to be compared");
  else if (distance == 0)
    puts("strings are equal");
  else
    puts("strings are differents");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<testLevenshtein>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <levenshtein@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%ecx
  call   <printf@plt>
  test   %ebx,%ebx
  js     L1
  jne    L4
  pop    %rbx
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
  nop
L4:
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
L1:
  pop    %rbx
  lea    D39(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D13
data_type: string
name: parse_data
arguments: tag: D39
data_type: string

tool: D18: Distance between "%s" and "%s": %d


tool: D2: strings are equal

tool: D13: strings are differents

tool: D39: strings are too big to be compared

assistant: ```c
void testLevenshtein(const char *s1, const char *s2) {
  int distance = levenshtein(s1, s2);
  printf("Distance between \"%s\" and \"%s\": %d\n", s1, s2, distance);
  if (distance < 0)
    puts("strings are too big to be compared");
  else if (distance == 0)
    puts("strings are equal");
  else
    puts("strings are differents");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testLevenshtein>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <levenshtein@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%ecx
  call   <printf@plt>
  test   %ebx,%ebx
  js     L10
  jne    L16
  pop    %rbx
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
  nop
L16:
  pop    %rbx
  lea    D28(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
L10:
  pop    %rbx
  lea    D24(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D28
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string

tool: D34: Distance between "%s" and "%s": %d


tool: D5: strings are equal

tool: D28: strings are differents

tool: D24: strings are too big to be compared

assistant: ```c
void testLevenshtein(const char *s1, const char *s2) {
  int distance = levenshtein(s1, s2);
  printf("Distance between \"%s\" and \"%s\": %d\n", s1, s2, distance);
  if (distance < 0)
    puts("strings are too big to be compared");
  else if (distance == 0)
    puts("strings are equal");
  else
    puts("strings are differents");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: Hello from vforked-prog...


assistant: ```c
int main(void) {
  printf("Hello from vforked-prog...\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Hello from vforked-prog...


assistant: ```c
int main(void) {
  printf("Hello from vforked-prog...\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: Hello from vforked-prog...


assistant: ```c
int main(void) {
  printf("Hello from vforked-prog...\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D3: Hello from vforked-prog...


assistant: ```c
int main(void) {
  printf("Hello from vforked-prog...\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<stateparent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x155,-0x4(%rbp)
  jle    L156
  cmpl   $0x188,-0x4(%rbp)
  jg     L156
  mov    $0x199,%eax
  jmp    L126
L156:
  cmpl   $0x10e,-0x4(%rbp)
  jle    L212
  cmpl   $0x131,-0x4(%rbp)
  jg     L212
  mov    $0x196,%eax
  jmp    L126
L212:
  cmpl   $0x188,-0x4(%rbp)
  jle    L32
  cmpl   $0x195,-0x4(%rbp)
  jg     L32
  mov    $0x1ee,%eax
  jmp    L126
L32:
  cmpl   $0x131,-0x4(%rbp)
  jle    L75
  cmpl   $0x13a,-0x4(%rbp)
  jg     L75
  mov    $0x197,%eax
  jmp    L126
L75:
  cmpl   $0xe8,-0x4(%rbp)
  jle    L19
  cmpl   $0x108,-0x4(%rbp)
  jg     L19
  mov    $0x19a,%eax
  jmp    L126
L19:
  cmpl   $0x13a,-0x4(%rbp)
  jle    L124
  cmpl   $0x155,-0x4(%rbp)
  jg     L124
  mov    $0x198,%eax
  jmp    L126
L124:
  cmpl   $0x19a,-0x4(%rbp)
  jle    L195
  cmpl   $0x1ed,-0x4(%rbp)
  jg     L195
  mov    $0x1ef,%eax
  jmp    L126
L195:
  cmpl   $0x1ef,-0x4(%rbp)
  jle    L45
  cmpl   $0x20e,-0x4(%rbp)
  jg     L45
  mov    $0x20f,%eax
  jmp    L126
L45:
  mov    $0xffffffff,%eax
L126:
  pop    %rbp
  ret
```

assistant: ```c
int stateparent(int ccode) {
  if (ccode >= 342 && ccode <= 392)
    return 409;
  if (ccode >= 271 && ccode <= 305)
    return 406;
  if (ccode >= 393 && ccode <= 405)
    return 494;
  if (ccode >= 306 && ccode <= 314)
    return 407;
  if (ccode >= 233 && ccode <= 264)
    return 410;
  if (ccode >= 315 && ccode <= 341)
    return 408;
  if (ccode >= 411 && ccode <= 493)
    return 495;
  if (ccode >= 496 && ccode <= 526)
    return 527;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<stateparent>:
  endbr64
  lea    -0x156(%rdi),%edx
  mov    $0x199,%eax
  cmp    $0x32,%edx
  jbe    L11
  lea    -0x10f(%rdi),%edx
  mov    $0x196,%eax
  cmp    $0x22,%edx
  jbe    L11
  lea    -0x189(%rdi),%edx
  mov    $0x1ee,%eax
  cmp    $0xc,%edx
  jbe    L11
  lea    -0x132(%rdi),%edx
  mov    $0x197,%eax
  cmp    $0x8,%edx
  jbe    L11
  lea    -0xe9(%rdi),%edx
  mov    $0x19a,%eax
  cmp    $0x1f,%edx
  jbe    L11
  lea    -0x13b(%rdi),%edx
  mov    $0x198,%eax
  cmp    $0x1a,%edx
  jbe    L11
  lea    -0x19b(%rdi),%edx
  mov    $0x1ef,%eax
  cmp    $0x52,%edx
  jbe    L11
  sub    $0x1f0,%edi
  cmp    $0x1f,%edi
  sbb    %eax,%eax
  and    $0x210,%eax
  sub    $0x1,%eax
L11:
  ret
```

assistant: ```c
int stateparent(int ccode) {
  if (ccode >= 342 && ccode <= 392)
    return 409;
  if (ccode >= 271 && ccode <= 305)
    return 406;
  if (ccode >= 393 && ccode <= 405)
    return 494;
  if (ccode >= 306 && ccode <= 314)
    return 407;
  if (ccode >= 233 && ccode <= 264)
    return 410;
  if (ccode >= 315 && ccode <= 341)
    return 408;
  if (ccode >= 411 && ccode <= 493)
    return 495;
  if (ccode >= 496 && ccode <= 526)
    return 527;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stateparent>:
  endbr64
  lea    -0x156(%rdi),%edx
  mov    $0x199,%eax
  cmp    $0x32,%edx
  jbe    L55
  lea    -0x10f(%rdi),%edx
  mov    $0x196,%eax
  cmp    $0x22,%edx
  jbe    L55
  lea    -0x189(%rdi),%edx
  mov    $0x1ee,%eax
  cmp    $0xc,%edx
  jbe    L55
  lea    -0x132(%rdi),%edx
  mov    $0x197,%eax
  cmp    $0x8,%edx
  jbe    L55
  lea    -0xe9(%rdi),%edx
  mov    $0x19a,%eax
  cmp    $0x1f,%edx
  jbe    L55
  lea    -0x13b(%rdi),%edx
  mov    $0x198,%eax
  cmp    $0x1a,%edx
  jbe    L55
  lea    -0x19b(%rdi),%edx
  mov    $0x1ef,%eax
  cmp    $0x52,%edx
  jbe    L55
  sub    $0x1f0,%edi
  cmp    $0x1f,%edi
  sbb    %eax,%eax
  and    $0x210,%eax
  sub    $0x1,%eax
L55:
  ret
```

assistant: ```c
int stateparent(int ccode) {
  if (ccode >= 342 && ccode <= 392)
    return 409;
  if (ccode >= 271 && ccode <= 305)
    return 406;
  if (ccode >= 393 && ccode <= 405)
    return 494;
  if (ccode >= 306 && ccode <= 314)
    return 407;
  if (ccode >= 233 && ccode <= 264)
    return 410;
  if (ccode >= 315 && ccode <= 341)
    return 408;
  if (ccode >= 411 && ccode <= 493)
    return 495;
  if (ccode >= 496 && ccode <= 526)
    return 527;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<stateparent>:
  endbr64
  lea    -0x156(%rdi),%edx
  mov    $0x199,%eax
  cmp    $0x32,%edx
  jbe    L23
  lea    -0x10f(%rdi),%edx
  mov    $0x196,%eax
  cmp    $0x22,%edx
  jbe    L23
  lea    -0x189(%rdi),%edx
  mov    $0x1ee,%eax
  cmp    $0xc,%edx
  jbe    L23
  lea    -0x132(%rdi),%edx
  mov    $0x197,%eax
  cmp    $0x8,%edx
  jbe    L23
  lea    -0xe9(%rdi),%edx
  mov    $0x19a,%eax
  cmp    $0x1f,%edx
  jbe    L23
  lea    -0x13b(%rdi),%edx
  mov    $0x198,%eax
  cmp    $0x1a,%edx
  jbe    L23
  lea    -0x19b(%rdi),%edx
  mov    $0x1ef,%eax
  cmp    $0x52,%edx
  jbe    L23
  sub    $0x1f0,%edi
  cmp    $0x1f,%edi
  sbb    %eax,%eax
  and    $0x210,%eax
  sub    $0x1,%eax
L23:
  ret
```

assistant: ```c
int stateparent(int ccode) {
  if (ccode >= 342 && ccode <= 392)
    return 409;
  if (ccode >= 271 && ccode <= 305)
    return 406;
  if (ccode >= 393 && ccode <= 405)
    return 494;
  if (ccode >= 306 && ccode <= 314)
    return 407;
  if (ccode >= 233 && ccode <= 264)
    return 410;
  if (ccode >= 315 && ccode <= 341)
    return 408;
  if (ccode >= 411 && ccode <= 493)
    return 495;
  if (ccode >= 496 && ccode <= 526)
    return 527;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L6:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x2,-0xc(%rbp)
  jle    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D39
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string

tool: D39: Berkeley eccentrics:
====================

tool: D26: Happy 

tool: D18: Yoshua

tool: D5: Go

tool: D21: 
%s BEARS!


assistant: ```c
int main(void) {
  int a;
  char *s;
  printf("Berkeley eccentrics:\n====================\n");
  for (a = 0; a < 3; a++) {
    printf("Happy ");
  }
  printf("\n");
  switch (3) {
  case 0:
    printf("Yoshua\n");
  case 1:
    printf("Triangle Man\n");
    break;
  case 2:
    printf("Chinese Erhu Guy\n");
  case 3:
    printf("Yoshua\n");
    break;
  case 4:
    printf("Dr. Jokemon\n");
    break;
  case 5:
    printf("Hat Lady\n");
  default:
    printf("I don't know these people!\n");
  }
  s = (3 == 3) ? "Go" : "Boo";
  if (1) {
    printf("\n%s BEARS!\n", s);
  } else {
    printf("\n%s CARDINAL!\n", s);
  }
  return 0;
}
```