ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_mvwinnstr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L18
  mov    (%rbx),%rdi
  lea    0x10(%rsp),%rdx
  lea    D20(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L35
  lea    D12(%rip),%rbp
  mov    0x8(%rbx),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L35
  mov    0x10(%rbx),%rdi
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L35
  mov    0x18(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L35
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L68
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %rbp,%rcx
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%rdi
  call   <mvwinnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D27(%rip),%rdi
  call   <report_error@plt>
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L68:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D29(%rip),%rdi
  call   <report_error@plt>
  jmp    L18
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string

tool: D20: %p

tool: D12: %d

tool: D27: BAD ARGUMENT

tool: D29: MALLOC_FAILED

assistant: ```c
void cmd_mvwinnstr(int nargs, char **args) {
  int y, x, count;
  char *string;
  WINDOW *win;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if ((string = malloc(count + 1)) == NULL) {
    report_count(1);
    report_error("MALLOC_FAILED");
    return;
  }
  report_count(2);
  report_return(mvwinnstr(win, y, x, string, count));
  report_status(string);
  free(string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_mvwinnstr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L81
  mov    (%rbx),%rdi
  lea    0x10(%rsp),%rdx
  lea    D5(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L30
  lea    D32(%rip),%rbp
  mov    0x8(%rbx),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L30
  mov    0x10(%rbx),%rdi
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L30
  mov    0x18(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L30
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %rbp,%rcx
  mov    0xc(%rsp),%r8d
  mov    0x10(%rsp),%rdi
  call   <mvwinnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L30:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  call   <report_error@plt>
L81:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
  jmp    L81
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D32
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string

tool: D5: %p

tool: D32: %d

tool: D9: BAD ARGUMENT

tool: D4: MALLOC_FAILED

assistant: ```c
void cmd_mvwinnstr(int nargs, char **args) {
  int y, x, count;
  char *string;
  WINDOW *win;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if ((string = malloc(count + 1)) == NULL) {
    report_count(1);
    report_error("MALLOC_FAILED");
    return;
  }
  report_count(2);
  report_return(mvwinnstr(win, y, x, string, count));
  report_status(string);
  free(string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x1c(%rax),%edx
  shl    $0x2,%edx
  mov    0x20(%rax),%r9d
  sar    $0x6,%r9d
  xor    %r9d,%edx
  mov    0x28(%rax),%r9d
  shl    $0x5,%r9d
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x4c(%rax),%edx
  shl    $0x2,%edx
  mov    0x50(%rax),%r9d
  sar    $0x6,%r9d
  xor    %r9d,%edx
  mov    0x54(%rax),%r11d
  lea    (%r11,%r11,1),%r9d
  xor    %r9d,%edx
  mov    0x58(%rax),%r9d
  sar    $0x7,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x74(%rax),%edx
  shl    $0x3,%edx
  mov    0x78(%rax),%r9d
  sar    $0x5,%r9d
  xor    %r9d,%edx
  xor    0x8c(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x28(%rax),%r8d
  mov    0x2c(%rax),%r9d
  lea    0x0(,%r8,8),%edx
  mov    %r9d,%r10d
  sar    $0x5,%r10d
  xor    %r10d,%edx
  shl    $0x4,%r8d
  sar    $0x4,%r9d
  xor    %r9d,%r8d
  and    %r8d,%edx
  mov    0x50(%rax),%r11d
  lea    0x0(,%r11,8),%r8d
  mov    0x54(%rax),%r9d
  sar    $0x5,%r9d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x54(%rax),%edi
  mov    0x50(%rax),%edx
  shl    $0x7,%edx
  mov    %edi,%r8d
  sar    %r8d
  xor    %r8d,%edx
  and    %edi,%edx
  mov    (%rsi),%edi
  xor    0x80(%rax),%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x88(%rax),%esi
  mov    0x8c(%rax),%edi
  mov    %esi,%edx
  shl    $0x6,%edx
  mov    %edi,%r8d
  sar    $0x2,%r8d
  xor    %r8d,%edx
  shl    $0x7,%esi
  sar    %edi
  xor    %edi,%esi
  and    %esi,%edx
  mov    0x1c(%rax),%esi
  shl    $0x5,%esi
  mov    0x20(%rax),%eax
  sar    $0x3,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3, uint8_t *stream) {
  uint8_t x1, x2, x3;
  x1 = (state[7] << 2) ^ (state[8] >> 6);
  x2 = (state[10] << 5) ^ (state[11] >> 3);
  *t1 = x1 ^ x2;
  x1 = (state[19] << 2) ^ (state[20] >> 6);
  x2 = (state[21] << 1) ^ (state[22] >> 7);
  *t2 = x1 ^ x2;
  x1 = (state[29] << 3) ^ (state[30] >> 5);
  x2 = state[35];
  *t3 = x1 ^ x2;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x1 = (state[10] << 3) ^ (state[11] >> 5);
  x2 = (state[10] << 4) ^ (state[11] >> 4);
  x3 = (state[20] << 3) ^ (state[21] >> 5);
  *t1 ^= (x1 & x2) ^ x3;
  x1 = (state[20] << 7) ^ (state[21] >> 1);
  x2 = state[21];
  x3 = state[32];
  *t2 ^= (x1 & x2) ^ x3;
  x1 = (state[34] << 6) ^ (state[35] >> 2);
  x2 = (state[34] << 7) ^ (state[35] >> 1);
  x3 = (state[7] << 5) ^ (state[8] >> 3);
  *t3 ^= (x1 & x2) ^ x3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x20(%rax),%r9d
  mov    0x1c(%rax),%edx
  sar    $0x6,%r9d
  shl    $0x2,%edx
  xor    %r9d,%edx
  mov    0x28(%rax),%r9d
  shl    $0x5,%r9d
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x4c(%rax),%edx
  mov    0x50(%rax),%r9d
  mov    0x54(%rax),%r11d
  shl    $0x2,%edx
  sar    $0x6,%r9d
  xor    %r9d,%edx
  lea    (%r11,%r11,1),%r9d
  xor    %r9d,%edx
  mov    0x58(%rax),%r9d
  sar    $0x7,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x74(%rax),%edx
  mov    0x78(%rax),%r9d
  shl    $0x3,%edx
  sar    $0x5,%r9d
  xor    %r9d,%edx
  xor    0x8c(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x28(%rax),%r8d
  mov    0x2c(%rax),%r9d
  mov    0x50(%rax),%r11d
  lea    0x0(,%r8,8),%edx
  shl    $0x4,%r8d
  mov    %r9d,%r10d
  sar    $0x4,%r9d
  xor    %r9d,%r8d
  sar    $0x5,%r10d
  mov    0x54(%rax),%r9d
  xor    %r10d,%edx
  and    %r8d,%edx
  sar    $0x5,%r9d
  lea    0x0(,%r11,8),%r8d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x54(%rax),%edi
  mov    0x50(%rax),%edx
  mov    %edi,%r8d
  sar    %r8d
  shl    $0x7,%edx
  xor    %r8d,%edx
  and    %edi,%edx
  mov    (%rsi),%edi
  xor    0x80(%rax),%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x88(%rax),%esi
  mov    0x8c(%rax),%edi
  mov    %esi,%edx
  shl    $0x7,%esi
  mov    %edi,%r8d
  shl    $0x6,%edx
  sar    $0x2,%r8d
  sar    %edi
  xor    %edi,%esi
  xor    %r8d,%edx
  and    %esi,%edx
  mov    0x1c(%rax),%esi
  mov    0x20(%rax),%eax
  shl    $0x5,%esi
  sar    $0x3,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3, uint8_t *stream) {
  uint8_t x1, x2, x3;
  x1 = (state[7] << 2) ^ (state[8] >> 6);
  x2 = (state[10] << 5) ^ (state[11] >> 3);
  *t1 = x1 ^ x2;
  x1 = (state[19] << 2) ^ (state[20] >> 6);
  x2 = (state[21] << 1) ^ (state[22] >> 7);
  *t2 = x1 ^ x2;
  x1 = (state[29] << 3) ^ (state[30] >> 5);
  x2 = state[35];
  *t3 = x1 ^ x2;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x1 = (state[10] << 3) ^ (state[11] >> 5);
  x2 = (state[10] << 4) ^ (state[11] >> 4);
  x3 = (state[20] << 3) ^ (state[21] >> 5);
  *t1 ^= (x1 & x2) ^ x3;
  x1 = (state[20] << 7) ^ (state[21] >> 1);
  x2 = state[21];
  x3 = state[32];
  *t2 ^= (x1 & x2) ^ x3;
  x1 = (state[34] << 6) ^ (state[35] >> 2);
  x2 = (state[34] << 7) ^ (state[35] >> 1);
  x3 = (state[7] << 5) ^ (state[8] >> 3);
  *t3 ^= (x1 & x2) ^ x3;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x20(%rax),%r9d
  mov    0x1c(%rax),%edx
  sar    $0x6,%r9d
  shl    $0x2,%edx
  xor    %r9d,%edx
  mov    0x28(%rax),%r9d
  shl    $0x5,%r9d
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x4c(%rax),%edx
  mov    0x50(%rax),%r9d
  mov    0x54(%rax),%r11d
  shl    $0x2,%edx
  sar    $0x6,%r9d
  xor    %r9d,%edx
  lea    (%r11,%r11,1),%r9d
  xor    %r9d,%edx
  mov    0x58(%rax),%r9d
  sar    $0x7,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x74(%rax),%edx
  mov    0x78(%rax),%r9d
  shl    $0x3,%edx
  sar    $0x5,%r9d
  xor    %r9d,%edx
  xor    0x8c(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x28(%rax),%r8d
  mov    0x2c(%rax),%r9d
  mov    0x50(%rax),%r11d
  lea    0x0(,%r8,8),%edx
  shl    $0x4,%r8d
  mov    %r9d,%r10d
  sar    $0x4,%r9d
  xor    %r9d,%r8d
  sar    $0x5,%r10d
  mov    0x54(%rax),%r9d
  xor    %r10d,%edx
  and    %r8d,%edx
  sar    $0x5,%r9d
  lea    0x0(,%r11,8),%r8d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x54(%rax),%edi
  mov    0x50(%rax),%edx
  mov    %edi,%r8d
  sar    %r8d
  shl    $0x7,%edx
  xor    %r8d,%edx
  and    %edi,%edx
  mov    (%rsi),%edi
  xor    0x80(%rax),%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x88(%rax),%esi
  mov    0x8c(%rax),%edi
  mov    %esi,%edx
  shl    $0x7,%esi
  mov    %edi,%r8d
  shl    $0x6,%edx
  sar    $0x2,%r8d
  sar    %edi
  xor    %edi,%esi
  xor    %r8d,%edx
  and    %esi,%edx
  mov    0x1c(%rax),%esi
  mov    0x20(%rax),%eax
  shl    $0x5,%esi
  sar    $0x3,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3, uint8_t *stream) {
  uint8_t x1, x2, x3;
  x1 = (state[7] << 2) ^ (state[8] >> 6);
  x2 = (state[10] << 5) ^ (state[11] >> 3);
  *t1 = x1 ^ x2;
  x1 = (state[19] << 2) ^ (state[20] >> 6);
  x2 = (state[21] << 1) ^ (state[22] >> 7);
  *t2 = x1 ^ x2;
  x1 = (state[29] << 3) ^ (state[30] >> 5);
  x2 = state[35];
  *t3 = x1 ^ x2;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x1 = (state[10] << 3) ^ (state[11] >> 5);
  x2 = (state[10] << 4) ^ (state[11] >> 4);
  x3 = (state[20] << 3) ^ (state[21] >> 5);
  *t1 ^= (x1 & x2) ^ x3;
  x1 = (state[20] << 7) ^ (state[21] >> 1);
  x2 = state[21];
  x3 = state[32];
  *t2 ^= (x1 & x2) ^ x3;
  x1 = (state[34] << 6) ^ (state[35] >> 2);
  x2 = (state[34] << 7) ^ (state[35] >> 1);
  x3 = (state[7] << 5) ^ (state[8] >> 3);
  *t3 ^= (x1 & x2) ^ x3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L52
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L5
L28:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L45
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L60
L33:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x10(%rbp)
L60:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L33
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L45:
  subl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L28
  jmp    L30
L52:
  nop
L30:
  pop    %rbp
  ret
```

assistant: ```c
void merge(int *V, int inicio, int meio, int fim) {
  int aux, pDown;
  int i, j;
  if (V[meio] <= V[meio + 1])
    return;
  j = meio + 1;
  i = inicio;
  for (j = meio + 1; j >= i; j--) {
    if (V[i] > V[j]) {
      aux = V[j];
      pDown = j;
      while (pDown < i) {
        V[pDown] = V[pDown - 1];
        pDown--;
      }
      V[pDown] = aux;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<merge>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  movslq %edx,%rax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    (%rdi),%ebx
  cmp    %ebx,(%r10,%rax,4)
  jle    L64
  mov    %esi,%r8d
  lea    0x1(%rdx),%ecx
  cmp    %esi,%ecx
  jl     L64
  movslq %esi,%rax
  lea    (%r10,%rax,4),%rbx
  lea    -0x1(%rsi),%r11d
  jmp    L59
L29:
  mov    %ecx,%edx
L25:
  movslq %edx,%rdx
  mov    %r9d,(%r10,%rdx,4)
L15:
  sub    $0x1,%ecx
  sub    $0x4,%rdi
  cmp    %r11d,%ecx
  je     L64
L59:
  mov    (%rdi),%r9d
  cmp    %r9d,(%rbx)
  jle    L15
  cmp    %ecx,%r8d
  jle    L29
  mov    %rdi,%rax
  mov    %ecx,%edx
L60:
  mov    -0x4(%rax),%esi
  mov    %esi,(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    %edx,%r8d
  jg     L60
  jmp    L25
L64:
  pop    %rbx
  ret
```

assistant: ```c
void merge(int *V, int inicio, int meio, int fim) {
  int aux, pDown;
  int i, j;
  if (V[meio] <= V[meio + 1])
    return;
  j = meio + 1;
  i = inicio;
  for (j = meio + 1; j >= i; j--) {
    if (V[i] > V[j]) {
      aux = V[j];
      pDown = j;
      while (pDown < i) {
        V[pDown] = V[pDown - 1];
        pDown--;
      }
      V[pDown] = aux;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<merge>:
  endbr64
  ret
```

assistant: ```c
void merge(int *V, int inicio, int meio, int fim) {
  int aux, pDown;
  int i, j;
  if (V[meio] <= V[meio + 1])
    return;
  j = meio + 1;
  i = inicio;
  for (j = meio + 1; j >= i; j--) {
    if (V[i] > V[j]) {
      aux = V[j];
      pDown = j;
      while (pDown < i) {
        V[pDown] = V[pDown - 1];
        pDown--;
      }
      V[pDown] = aux;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<merge>:
  endbr64
  ret
```

assistant: ```c
void merge(int *V, int inicio, int meio, int fim) {
  int aux, pDown;
  int i, j;
  if (V[meio] <= V[meio + 1])
    return;
  j = meio + 1;
  i = inicio;
  for (j = meio + 1; j >= i; j--) {
    if (V[i] > V[j]) {
      aux = V[j];
      pDown = j;
      while (pDown < i) {
        V[pDown] = V[pDown - 1];
        pDown--;
      }
      V[pDown] = aux;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<zero_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L18
L48:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  addq   $0x8,-0x8(%rbp)
  subq   $0x8,-0x10(%rbp)
L18:
  cmpq   $0x7,-0x10(%rbp)
  seta   %al
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L48
  cmpq   $0x3,-0x10(%rbp)
  jbe    L38
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  addq   $0x4,-0x8(%rbp)
  subq   $0x4,-0x10(%rbp)
L38:
  cmpq   $0x1,-0x10(%rbp)
  jbe    L27
  mov    -0x8(%rbp),%rax
  movw   $0x0,(%rax)
  addq   $0x2,-0x8(%rbp)
  subq   $0x2,-0x10(%rbp)
L27:
  cmpq   $0x0,-0x10(%rbp)
  je     L33
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L33:
  nop
  leave
  ret
```

assistant: ```c
void zero_memory(char *buf, size_t len) {
  while (__builtin_expect(len >= sizeof(unsigned long), 1)) {
    *(unsigned long *)(buf) = 0;
    buf += sizeof(unsigned long);
    len -= sizeof(unsigned long);
  }
  if (len >= sizeof(unsigned int)) {
    *(unsigned int *)(buf) = 0;
    buf += sizeof(unsigned int);
    len -= sizeof(unsigned int);
  }
  if (len >= sizeof(unsigned short)) {
    *(unsigned short *)(buf) = 0;
    buf += sizeof(unsigned short);
    len -= sizeof(unsigned short);
  }
  if (len)
    *buf = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zero_memory>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  jmp    L34
L28:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rbp
  sub    $0x8,%rbx
L34:
  cmp    $0x7,%rbx
  seta   %dil
  movzbl %dil,%edi
  mov    $0x1,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L28
  cmp    $0x3,%rbx
  jbe    L3
  movl   $0x0,0x0(%rbp)
  add    $0x4,%rbp
  sub    $0x4,%rbx
L3:
  cmp    $0x1,%rbx
  jbe    L42
  movw   $0x0,0x0(%rbp)
  add    $0x2,%rbp
  sub    $0x2,%rbx
L42:
  test   %rbx,%rbx
  je     L41
  movb   $0x0,0x0(%rbp)
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zero_memory(char *buf, size_t len) {
  while (__builtin_expect(len >= sizeof(unsigned long), 1)) {
    *(unsigned long *)(buf) = 0;
    buf += sizeof(unsigned long);
    len -= sizeof(unsigned long);
  }
  if (len >= sizeof(unsigned int)) {
    *(unsigned int *)(buf) = 0;
    buf += sizeof(unsigned int);
    len -= sizeof(unsigned int);
  }
  if (len >= sizeof(unsigned short)) {
    *(unsigned short *)(buf) = 0;
    buf += sizeof(unsigned short);
    len -= sizeof(unsigned short);
  }
  if (len)
    *buf = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zero_memory>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L23:
  movq   $0x0,0x0(%rbp)
  sub    $0x8,%rbx
  add    $0x8,%rbp
L2:
  xor    %edi,%edi
  cmp    $0x7,%rbx
  mov    $0x1,%esi
  seta   %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L23
  cmp    $0x3,%rbx
  jbe    L37
  movl   $0x0,0x0(%rbp)
  sub    $0x4,%rbx
  add    $0x4,%rbp
L37:
  cmp    $0x1,%rbx
  jbe    L10
  xor    %eax,%eax
  add    $0x2,%rbp
  sub    $0x2,%rbx
  mov    %ax,-0x2(%rbp)
L10:
  test   %rbx,%rbx
  je     L27
  movb   $0x0,0x0(%rbp)
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zero_memory(char *buf, size_t len) {
  while (__builtin_expect(len >= sizeof(unsigned long), 1)) {
    *(unsigned long *)(buf) = 0;
    buf += sizeof(unsigned long);
    len -= sizeof(unsigned long);
  }
  if (len >= sizeof(unsigned int)) {
    *(unsigned int *)(buf) = 0;
    buf += sizeof(unsigned int);
    len -= sizeof(unsigned int);
  }
  if (len >= sizeof(unsigned short)) {
    *(unsigned short *)(buf) = 0;
    buf += sizeof(unsigned short);
    len -= sizeof(unsigned short);
  }
  if (len)
    *buf = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zero_memory>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L46:
  movq   $0x0,0x0(%rbp)
  sub    $0x8,%rbx
  add    $0x8,%rbp
L32:
  xor    %edi,%edi
  cmp    $0x7,%rbx
  mov    $0x1,%esi
  seta   %dil
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L46
  cmp    $0x3,%rbx
  jbe    L28
  movl   $0x0,0x0(%rbp)
  sub    $0x4,%rbx
  add    $0x4,%rbp
L28:
  cmp    $0x1,%rbx
  jbe    L12
  xor    %eax,%eax
  add    $0x2,%rbp
  sub    $0x2,%rbx
  mov    %ax,-0x2(%rbp)
L12:
  test   %rbx,%rbx
  je     L20
  movb   $0x0,0x0(%rbp)
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zero_memory(char *buf, size_t len) {
  while (__builtin_expect(len >= sizeof(unsigned long), 1)) {
    *(unsigned long *)(buf) = 0;
    buf += sizeof(unsigned long);
    len -= sizeof(unsigned long);
  }
  if (len >= sizeof(unsigned int)) {
    *(unsigned int *)(buf) = 0;
    buf += sizeof(unsigned int);
    len -= sizeof(unsigned int);
  }
  if (len >= sizeof(unsigned short)) {
    *(unsigned short *)(buf) = 0;
    buf += sizeof(unsigned short);
    len -= sizeof(unsigned short);
  }
  if (len)
    *buf = 0;
}
```