ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<refreshPropPatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <enterPropCpeHdPatch@plt>
  mov    $0x0,%eax
  call   <configurePropPatch@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void refreshPropPatch(void) {
  enterPropCpeHdPatch();
  configurePropPatch();
}
```
user: What is the c source code of the assembly code below?

```asm
<refreshPropPatch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <enterPropCpeHdPatch@plt>
  mov    $0x0,%eax
  call   <configurePropPatch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void refreshPropPatch(void) {
  enterPropCpeHdPatch();
  configurePropPatch();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<refreshPropPatch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <enterPropCpeHdPatch@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <configurePropPatch@plt>
```

assistant: ```c
void refreshPropPatch(void) {
  enterPropCpeHdPatch();
  configurePropPatch();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<refreshPropPatch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <enterPropCpeHdPatch@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <configurePropPatch@plt>
```

assistant: ```c
void refreshPropPatch(void) {
  enterPropCpeHdPatch();
  configurePropPatch();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode_attributes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L42
L34:
  cmpl   $0x3,-0x14(%rbp)
  jg     L19
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L19:
  mov    -0x14(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    $0x8,%eax
  mov    %eax,-0x10(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L4
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,-0x8(%rbp)
L4:
  addl   $0x1,-0x14(%rbp)
L42:
  cmpl   $0x17,-0x14(%rbp)
  jle    L34
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long decode_attributes(const unsigned char *buf) {
  unsigned long attributes = 0;
  int bit;
  int attr;
  int byte = 0;
  for (bit = 0; bit < 24; bit++) {
    if (bit < 4)
      byte = 0;
    else
      byte = (bit / 4) + 0x8;
    attr = bit % 4;
    if (buf[byte] & (1 << attr))
      attributes |= (1 << bit);
  }
  return attributes;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<decode_attributes>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%eax
  mov    $0x1,%r8d
  mov    $0x0,%r9d
  jmp    L11
L6:
  mov    %r9d,%eax
  jmp    L11
L26:
  add    $0x1,%ecx
  cmp    $0x18,%ecx
  je     L7
  cmp    $0x3,%ecx
  jle    L6
  lea    0x3(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x2,%eax
  add    $0x8,%eax
L11:
  cltq
  movzbl (%rdi,%rax,1),%edx
  mov    %ecx,%eax
  and    $0x3,%eax
  bt     %eax,%edx
  jae    L26
  mov    %r8d,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%rsi
  jmp    L26
L7:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned long decode_attributes(const unsigned char *buf) {
  unsigned long attributes = 0;
  int bit;
  int attr;
  int byte = 0;
  for (bit = 0; bit < 24; bit++) {
    if (bit < 4)
      byte = 0;
    else
      byte = (bit / 4) + 0x8;
    attr = bit % 4;
    if (buf[byte] & (1 << attr))
      attributes |= (1 << bit);
  }
  return attributes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decode_attributes>:
  endbr64
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x1,%r9d
  xor    %esi,%esi
  jmp    L20
  nopl   (%rax)
L18:
  mov    %ecx,%eax
  sar    $0x2,%eax
  add    $0x8,%eax
  cmp    $0x3,%ecx
  cmovle %esi,%eax
L20:
  cltq
  movzbl (%rdi,%rax,1),%edx
  mov    %ecx,%eax
  and    $0x3,%eax
  bt     %eax,%edx
  jae    L15
  mov    %r9d,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r8
L15:
  add    $0x1,%ecx
  cmp    $0x18,%ecx
  jne    L18
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long decode_attributes(const unsigned char *buf) {
  unsigned long attributes = 0;
  int bit;
  int attr;
  int byte = 0;
  for (bit = 0; bit < 24; bit++) {
    if (bit < 4)
      byte = 0;
    else
      byte = (bit / 4) + 0x8;
    attr = bit % 4;
    if (buf[byte] & (1 << attr))
      attributes |= (1 << bit);
  }
  return attributes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<decode_attributes>:
  endbr64
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x1,%r9d
  xor    %esi,%esi
  jmp    L11
  nopl   (%rax)
L5:
  mov    %ecx,%eax
  sar    $0x2,%eax
  add    $0x8,%eax
  cmp    $0x3,%ecx
  cmovle %esi,%eax
L11:
  cltq
  movzbl (%rdi,%rax,1),%edx
  mov    %ecx,%eax
  and    $0x3,%eax
  bt     %eax,%edx
  jae    L16
  mov    %r9d,%eax
  shl    %cl,%eax
  cltq
  or     %rax,%r8
L16:
  add    $0x1,%ecx
  cmp    $0x18,%ecx
  jne    L5
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long decode_attributes(const unsigned char *buf) {
  unsigned long attributes = 0;
  int bit;
  int attr;
  int byte = 0;
  for (bit = 0; bit < 24; bit++) {
    if (bit < 4)
      byte = 0;
    else
      byte = (bit / 4) + 0x8;
    attr = bit % 4;
    if (buf[byte] & (1 << attr))
      attributes |= (1 << bit);
  }
  return attributes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sockMerchant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L40:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L37:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L0:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L37
  addl   $0x1,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L40
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sockMerchant(int n, int *ar) {
  int count = 0;
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (ar[i] == ar[j] && ar[i] > 0) {
        ar[i] = ar[j] = 0;
        count++;
      }
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sockMerchant>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %rbp
  push   %rbx
  lea    0x4(%rsi),%rcx
  lea    -0x1(%rdi),%ebp
  mov    %edi,%r11d
  mov    $0x1,%r9d
  mov    $0x0,%r10d
  lea    0x8(%rsi),%rbx
  jmp    L52
L39:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L64
L6:
  mov    -0x4(%rcx),%edx
  cmp    %edx,(%rax)
  jne    L39
  test   %edx,%edx
  jle    L39
  movl   $0x0,(%rax)
  movl   $0x0,-0x4(%rcx)
  add    $0x1,%r10d
  jmp    L39
L64:
  add    $0x1,%r9
  add    $0x4,%rcx
L52:
  cmp    %r11,%r9
  je     L49
  mov    %ebp,%eax
  sub    %r9d,%eax
  lea    -0x1(%r9,%rax,1),%rax
  lea    (%rbx,%rax,4),%r8
  mov    %rcx,%rax
  jmp    L6
L16:
  mov    $0x0,%r10d
  mov    %r10d,%eax
  ret
L49:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int sockMerchant(int n, int *ar) {
  int count = 0;
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (ar[i] == ar[j] && ar[i] > 0) {
        ar[i] = ar[j] = 0;
        count++;
      }
    }
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sockMerchant>:
  endbr64
  test   %edi,%edi
  jle    L44
  lea    -0x1(%rdi),%r11d
  mov    %edi,%r9d
  mov    $0x1,%edi
  xor    %r8d,%r8d
  lea    0x4(%rsi),%rcx
  lea    0x8(%rsi),%r10
  cmp    %r9,%rdi
  je     L20
  nopl   0x0(%rax)
L48:
  mov    %r11d,%eax
  sub    %edi,%eax
  lea    -0x1(%rdi,%rax,1),%rax
  lea    (%r10,%rax,4),%rsi
  mov    %rcx,%rax
  nopl   0x0(%rax)
L41:
  mov    -0x4(%rcx),%edx
  cmp    %edx,(%rax)
  jne    L11
  test   %edx,%edx
  jle    L11
  movl   $0x0,(%rax)
  add    $0x1,%r8d
  movl   $0x0,-0x4(%rcx)
L11:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L41
  add    $0x1,%rdi
  add    $0x4,%rcx
  cmp    %r9,%rdi
  jne    L48
L20:
  mov    %r8d,%eax
  ret
L44:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sockMerchant(int n, int *ar) {
  int count = 0;
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (ar[i] == ar[j] && ar[i] > 0) {
        ar[i] = ar[j] = 0;
        count++;
      }
    }
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<sockMerchant>:
  endbr64
  test   %edi,%edi
  jle    L50
  movslq %edi,%r9
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L31
  nopl   0x0(%rax,%rax,1)
L55:
  mov    -0x4(%rsi,%rcx,4),%edx
  mov    %rcx,%rax
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    %edx,(%rsi,%rax,4)
  jne    L40
  test   %edx,%edx
  jle    L40
  movl   $0x0,(%rsi,%rax,4)
  add    $0x1,%r8d
  xor    %edx,%edx
  movl   $0x0,-0x4(%rsi,%rcx,4)
L40:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L21
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L55
L31:
  mov    %r8d,%eax
  ret
L50:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sockMerchant(int n, int *ar) {
  int count = 0;
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (ar[i] == ar[j] && ar[i] > 0) {
        ar[i] = ar[j] = 0;
        count++;
      }
    }
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<es_primo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L5
L16:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L3
  movl   $0x0,-0x8(%rbp)
L3:
  addl   $0x2,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L32
  cmpl   $0x1,-0x8(%rbp)
  je     L16
L32:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int es_primo(int x) {
  int b = 1;
  int c;
  for (c = 2; c < x && b == 1; c += 2) {
    if (x % c == 0)
      b = 0;
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<es_primo>:
  endbr64
  cmp    $0x2,%edi
  jle    L6
  mov    $0x2,%ecx
  jmp    L48
L8:
  add    $0x2,%ecx
  cmp    %ecx,%edi
  jle    L30
L48:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L8
L16:
  ret
L30:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x1,%eax
  jmp    L16
```

assistant: ```c
int es_primo(int x) {
  int b = 1;
  int c;
  for (c = 2; c < x && b == 1; c += 2) {
    if (x % c == 0)
      b = 0;
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<es_primo>:
  endbr64
  cmp    $0x2,%edi
  jle    L4
  mov    $0x2,%ecx
  xchg   %ax,%ax
L17:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  setne  %al
  add    $0x2,%ecx
  cmp    %ecx,%edi
  jle    L22
  test   %al,%al
  jne    L17
L22:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int es_primo(int x) {
  int b = 1;
  int c;
  for (c = 2; c < x && b == 1; c += 2) {
    if (x % c == 0)
      b = 0;
  }
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<es_primo>:
  endbr64
  cmp    $0x2,%edi
  jle    L7
  mov    $0x2,%ecx
  xchg   %ax,%ax
L25:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  setne  %al
  add    $0x2,%ecx
  cmp    %ecx,%edi
  jle    L14
  test   %al,%al
  jne    L25
L14:
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int es_primo(int x) {
  int b = 1;
  int c;
  for (c = 2; c < x && b == 1; c += 2) {
    if (x % c == 0)
      b = 0;
  }
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L8
  mov    $0x1,%eax
  jmp    L14
L8:
  mov    $0x2,%eax
L14:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int b) {
  int a = (b > 1) ? 1 : 2;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  cmp    $0x1,%edi
  setle  %al
  movzbl %al,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int foo(int b) {
  int a = (b > 1) ? 1 : 2;
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  add    $0x1,%eax
  ret
```

assistant: ```c
int foo(int b) {
  int a = (b > 1) ? 1 : 2;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setle  %al
  add    $0x1,%eax
  ret
```

assistant: ```c
int foo(int b) {
  int a = (b > 1) ? 1 : 2;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%rbp
  lea    0x2(%rdi,%rdi,1),%r12d
  lea    0x3(%r12),%r13d
  lea    0x20(,%r12,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%rax
  mov    %rax,(%rbx)
  lea    D74(%rip),%rax
  mov    %rax,0x8(%rbx)
  lea    D36(%rip),%rax
  mov    %rax,0x10(%rbx)
  lea    D46(%rip),%rax
  mov    %rax,0x18(%rbx)
  lea    D55(%rip),%rax
  mov    %rax,0x20(%rbx)
  lea    -0x1(%r14),%edi
  test   %edi,%edi
  jle    L13
  lea    0x30(%rbx),%rdx
  lea    -0x2(%r14),%esi
  add    $0x2,%rsi
  mov    $0x1,%eax
  lea    D39(%rip),%r9
  lea    D10(%rip),%r8
  jmp    L16
L8:
  mov    %r9,(%rdx)
L11:
  add    $0x1,%rax
  add    $0x10,%rdx
  cmp    %rsi,%rax
  je     L13
L16:
  mov    0x0(%rbp,%rax,8),%rcx
  mov    %rcx,-0x8(%rdx)
  cmp    %eax,%edi
  jle    L8
  mov    %r8,(%rdx)
  jmp    L11
L13:
  movslq %r12d,%r12
  lea    0x1(%r12),%rax
  lea    D55(%rip),%rsi
  mov    %rsi,(%rbx,%rax,8)
  lea    D36(%rip),%rsi
  mov    %rsi,0x10(%rbx,%r12,8)
  movq   $0x0,0x10(%rbx,%rax,8)
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <lace_builtin_zec_main@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D74
type: string
name: parse_data
arguments: data_tag: D36
type: string
name: parse_data
arguments: data_tag: D46
type: string
name: parse_data
arguments: data_tag: D55
type: string
name: parse_data
arguments: data_tag: D39
type: string
name: parse_data
arguments: data_tag: D10
type: string

tool: D74: -o

tool: D36: -

tool: D46: --

tool: D55: /

tool: D39: 


tool: D10:  

assistant: ```c
int main(int argc, char **argv) {
  unsigned zec_argc = 4 + 2 * (argc - 1) + 3;
  const char **zec_argv = (const char **)malloc(sizeof(char *) * (zec_argc + 1));
  int i, istat;
  zec_argv[0] = argv[0];
  zec_argv[1] = "-o";
  zec_argv[2] = "-";
  zec_argv[3] = "--";
  zec_argv[4] = "/";
  for (i = 0; i < argc - 1; ++i) {
    zec_argv[5 + 2 * i] = argv[1 + i];
    if (i + 1 < argc - 1) {
      zec_argv[5 + 2 * i + 1] = " ";
    } else {
      zec_argv[5 + 2 * i + 1] = "\n";
    }
  }
  zec_argv[4 + 2 * (argc - 1) + 1] = "/";
  zec_argv[4 + 2 * (argc - 1) + 2] = "-";
  zec_argv[4 + 2 * (argc - 1) + 3] = NULL;
  istat = lace_builtin_zec_main(zec_argc, (char **)zec_argv, NULL, NULL);
  free(zec_argv);
  return istat;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  lea    D56(%rip),%r14
  push   %r13
  lea    0x2(%rdi,%rdi,1),%r13d
  push   %r12
  lea    0x20(,%r13,8),%edi
  lea    0x3(%r13),%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D24(%rip),%r11
  lea    -0x1(%r15),%r8d
  mov    %rax,%rbp
  mov    (%rbx),%rax
  mov    %r11,0x10(%rbp)
  mov    %rax,0x0(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,0x8(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,0x18(%rbp)
  mov    %r14,0x20(%rbp)
  test   %r8d,%r8d
  jle    L17
  lea    -0x2(%r15),%edi
  lea    0x28(%rbp),%rdx
  mov    $0x1,%eax
  add    $0x2,%rdi
  lea    D3(%rip),%r10
  lea    D51(%rip),%r9
  nopl   0x0(%rax)
L9:
  cmp    %eax,%r8d
  mov    %r9,%rcx
  mov    (%rbx,%rax,8),%rsi
  cmovle %r10,%rcx
  add    $0x1,%rax
  add    $0x10,%rdx
  mov    %rsi,-0x10(%rdx)
  mov    %rcx,-0x8(%rdx)
  cmp    %rax,%rdi
  jne    L9
L17:
  movslq %r13d,%r13
  mov    %rbp,%rsi
  mov    %r12d,%edi
  xor    %ecx,%ecx
  lea    0x1(%r13),%rax
  xor    %edx,%edx
  mov    %r14,0x0(%rbp,%rax,8)
  mov    %r11,0x10(%rbp,%r13,8)
  movq   $0x0,0x10(%rbp,%rax,8)
  call   <lace_builtin_zec_main@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D24
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D51
type_infered: string

tool: D56: /

tool: D24: -

tool: D34: -o

tool: D16: --

tool: D3: 


tool: D51:  

assistant: ```c
int main(int argc, char **argv) {
  unsigned zec_argc = 4 + 2 * (argc - 1) + 3;
  const char **zec_argv = (const char **)malloc(sizeof(char *) * (zec_argc + 1));
  int i, istat;
  zec_argv[0] = argv[0];
  zec_argv[1] = "-o";
  zec_argv[2] = "-";
  zec_argv[3] = "--";
  zec_argv[4] = "/";
  for (i = 0; i < argc - 1; ++i) {
    zec_argv[5 + 2 * i] = argv[1 + i];
    if (i + 1 < argc - 1) {
      zec_argv[5 + 2 * i + 1] = " ";
    } else {
      zec_argv[5 + 2 * i + 1] = "\n";
    }
  }
  zec_argv[4 + 2 * (argc - 1) + 1] = "/";
  zec_argv[4 + 2 * (argc - 1) + 2] = "-";
  zec_argv[4 + 2 * (argc - 1) + 3] = NULL;
  istat = lace_builtin_zec_main(zec_argc, (char **)zec_argv, NULL, NULL);
  free(zec_argv);
  return istat;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D11(%rip),%rdx
  lea    D67(%rip),%r15
  push   %r14
  movq   %rdx,%xmm3
  movq   %r15,%xmm1
  mov    %edi,%r14d
  push   %r13
  punpcklqdq %xmm3,%xmm1
  push   %r12
  lea    0x2(%rdi,%rdi,1),%r12d
  push   %rbp
  lea    0x20(,%r12,8),%edi
  lea    0x3(%r12),%r13d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movaps %xmm1,(%rsp)
  call   <malloc@plt>
  lea    -0x1(%r14),%edi
  movdqa (%rsp),%xmm1
  lea    D11(%rip),%rdx
  mov    %rax,%rbp
  mov    (%rbx),%rax
  test   %edi,%edi
  mov    %rdx,0x10(%rbp)
  mov    %rax,0x0(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,0x8(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,0x18(%rbp)
  mov    %r15,0x20(%rbp)
  jle    L7
  lea    -0x2(%r14),%esi
  lea    0x28(%rbp),%rdx
  mov    $0x1,%eax
  add    $0x2,%rsi
  lea    D47(%rip),%r9
  lea    D1(%rip),%r8
  nopw   0x0(%rax,%rax,1)
L18:
  cmp    %eax,%edi
  mov    %r8,%rcx
  movq   (%rbx,%rax,8),%xmm0
  cmovg  %r9,%rcx
  add    $0x1,%rax
  add    $0x10,%rdx
  movq   %rcx,%xmm2
  punpcklqdq %xmm2,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rax
  jne    L18
L7:
  movslq %r12d,%r12
  mov    %rbp,%rsi
  mov    %r13d,%edi
  xor    %ecx,%ecx
  add    $0x1,%r12
  xor    %edx,%edx
  movq   $0x0,0x10(%rbp,%r12,8)
  movups %xmm1,0x0(%rbp,%r12,8)
  call   <lace_builtin_zec_main@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D67
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D47
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string

tool: D11: -

tool: D67: /

tool: D15: -o

tool: D20: --

tool: D47:  

tool: D1: 


assistant: ```c
int main(int argc, char **argv) {
  unsigned zec_argc = 4 + 2 * (argc - 1) + 3;
  const char **zec_argv = (const char **)malloc(sizeof(char *) * (zec_argc + 1));
  int i, istat;
  zec_argv[0] = argv[0];
  zec_argv[1] = "-o";
  zec_argv[2] = "-";
  zec_argv[3] = "--";
  zec_argv[4] = "/";
  for (i = 0; i < argc - 1; ++i) {
    zec_argv[5 + 2 * i] = argv[1 + i];
    if (i + 1 < argc - 1) {
      zec_argv[5 + 2 * i + 1] = " ";
    } else {
      zec_argv[5 + 2 * i + 1] = "\n";
    }
  }
  zec_argv[4 + 2 * (argc - 1) + 1] = "/";
  zec_argv[4 + 2 * (argc - 1) + 2] = "-";
  zec_argv[4 + 2 * (argc - 1) + 3] = NULL;
  istat = lace_builtin_zec_main(zec_argc, (char **)zec_argv, NULL, NULL);
  free(zec_argv);
  return istat;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x64,-0x18(%rbp)
  movb   $0x6f,-0x1d(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movsbl -0x1d(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movsbl -0x1d(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x7a,(%rax)
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x78,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 100;
  char fill = 'o';
  char *s1 = (char *)malloc(size);
  memset(s1, fill, size);
  char *s2 = (char *)malloc(size);
  memset(s2, fill, size);
  s1[size - 1] = 'z';
  s2[size - 1] = 'x';
  int r = strcmp(s1, s2);
  assert(r == 1);
  free(s1);
  free(s2);
  return 0;
}
```