ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<soru_2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <kare_al@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void soru_2(int a) {
  int sonuc;
  kare_al(a, &sonuc);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<soru_2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <kare_al@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void soru_2(int a) {
  int sonuc;
  kare_al(a, &sonuc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<soru_2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <kare_al@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void soru_2(int a) {
  int sonuc;
  kare_al(a, &sonuc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x78,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  char x[1] = "x";
  int a = strlen(x);
  printf("%d\n", a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x78,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: %d


assistant: ```c
int main() {
  char x[1] = "x";
  int a = strlen(x);
  printf("%d\n", a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x78,0x7(%rsp)
  call   <strlen@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  char x[1] = "x";
  int a = strlen(x);
  printf("%d\n", a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x78,0x7(%rsp)
  call   <strlen@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main() {
  char x[1] = "x";
  int a = strlen(x);
  printf("%d\n", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L134
  negl   -0x14(%rbp)
L134:
  cmpl   $0x0,-0x18(%rbp)
  jns    L93
  negl   -0x18(%rbp)
L93:
  cmpl   $0x0,-0x14(%rbp)
  jne    L54
  mov    -0x18(%rbp),%eax
  jmp    L55
L54:
  cmpl   $0x0,-0x18(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  jmp    L55
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L137
L74:
  sarl   -0x14(%rbp)
  sarl   -0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L137:
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L74
  jmp    L82
L50:
  sarl   -0x14(%rbp)
L82:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L50
  jmp    L2
L64:
  sarl   -0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L64
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L135
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L135:
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L2
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0)
    return b;
  if (b == 0)
    return a;
  int shift;
  for (shift = 0; ((a | b) & 1) == 0; ++shift) {
    a >>= 1;
    b >>= 1;
  }
  while ((a & 1) == 0)
    a >>= 1;
  do {
    while ((b & 1) == 0)
      b >>= 1;
    if (a > b) {
      int t = b;
      b = a;
      a = t;
    }
    b = b - a;
  } while (b != 0);
  return a << shift;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %edi,%edi
  je     L5
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  test   %esi,%esi
  je     L57
  mov    %eax,%ecx
  or     %edx,%ecx
  and    $0x1,%ecx
  jne    L30
L59:
  sar    %edx
  sar    %eax
  add    $0x1,%ecx
  mov    %edx,%esi
  or     %eax,%esi
  test   $0x1,%sil
  je     L59
L27:
  test   $0x1,%dl
  jne    L3
L18:
  sar    %edx
  test   $0x1,%dl
  je     L18
  jmp    L3
L30:
  mov    $0x0,%ecx
  jmp    L27
L65:
  sar    %eax
L3:
  test   $0x1,%al
  je     L65
  cmp    %eax,%edx
  jle    L96
  mov    %edx,%esi
  mov    %eax,%edx
  mov    %esi,%eax
L96:
  sub    %edx,%eax
  jne    L3
  mov    %edx,%eax
  shl    %cl,%eax
  ret
L57:
  mov    %edx,%eax
L5:
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0)
    return b;
  if (b == 0)
    return a;
  int shift;
  for (shift = 0; ((a | b) & 1) == 0; ++shift) {
    a >>= 1;
    b >>= 1;
  }
  while ((a & 1) == 0)
    a >>= 1;
  do {
    while ((b & 1) == 0)
      b >>= 1;
    if (a > b) {
      int t = b;
      b = a;
      a = t;
    }
    b = b - a;
  } while (b != 0);
  return a << shift;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %edi,%edi
  je     L34
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  test   %esi,%esi
  je     L11
  mov    %eax,%ecx
  or     %edx,%ecx
  and    $0x1,%ecx
  jne    L78
  nopl   0x0(%rax,%rax,1)
L93:
  sar    %edx
  sar    %eax
  add    $0x1,%ecx
  mov    %edx,%esi
  or     %eax,%esi
  and    $0x1,%esi
  je     L93
L96:
  test   $0x1,%dl
  jne    L82
  nopl   (%rax)
L27:
  sar    %edx
  test   $0x1,%dl
  je     L27
  nopw   0x0(%rax,%rax,1)
L82:
  test   $0x1,%al
  je     L69
  cmp    %eax,%edx
  jle    L89
  mov    %edx,%esi
  mov    %eax,%edx
  mov    %esi,%eax
L89:
  sub    %edx,%eax
  jne    L82
  mov    %edx,%eax
  shl    %cl,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edx,%eax
L34:
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  sar    %eax
  jmp    L82
L78:
  xor    %ecx,%ecx
  jmp    L96
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0)
    return b;
  if (b == 0)
    return a;
  int shift;
  for (shift = 0; ((a | b) & 1) == 0; ++shift) {
    a >>= 1;
    b >>= 1;
  }
  while ((a & 1) == 0)
    a >>= 1;
  do {
    while ((b & 1) == 0)
      b >>= 1;
    if (a > b) {
      int t = b;
      b = a;
      a = t;
    }
    b = b - a;
  } while (b != 0);
  return a << shift;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %edi,%edi
  je     L13
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  test   %esi,%esi
  je     L65
  mov    %eax,%ecx
  or     %edx,%ecx
  and    $0x1,%ecx
  jne    L37
  nopl   0x0(%rax,%rax,1)
L11:
  sar    %edx
  sar    %eax
  add    $0x1,%ecx
  mov    %edx,%esi
  or     %eax,%esi
  and    $0x1,%esi
  je     L11
L95:
  test   $0x1,%dl
  jne    L49
  nopl   (%rax)
L70:
  sar    %edx
  test   $0x1,%dl
  je     L70
  nopw   0x0(%rax,%rax,1)
L49:
  test   $0x1,%al
  je     L80
  cmp    %eax,%edx
  jle    L24
  mov    %edx,%esi
  mov    %eax,%edx
  mov    %esi,%eax
L24:
  sub    %edx,%eax
  jne    L49
  mov    %edx,%eax
  shl    %cl,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %edx,%eax
L13:
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  sar    %eax
  jmp    L49
L37:
  xor    %ecx,%ecx
  jmp    L95
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0)
    return b;
  if (b == 0)
    return a;
  int shift;
  for (shift = 0; ((a | b) & 1) == 0; ++shift) {
    a >>= 1;
    b >>= 1;
  }
  while ((a & 1) == 0)
    a >>= 1;
  do {
    while ((b & 1) == 0)
      b >>= 1;
    if (a > b) {
      int t = b;
      b = a;
      a = t;
    }
    b = b - a;
  } while (b != 0);
  return a << shift;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<OPENSSL_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D10(%rip),%eax
  test   %eax,%eax
  jne    L12
  movl   $0x1,D10(%rip)
  jmp    L9
L12:
  nop
L9:
  pop    %rbp
  ret
```

assistant: ```c
void OPENSSL_init(void) {
  static int done = 0;
  if (done)
    return;
  done = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<OPENSSL_init>:
  endbr64
  cmpl   $0x0,D1(%rip)
  jne    L2
  movl   $0x1,D1(%rip)
L2:
  ret
```

assistant: ```c
void OPENSSL_init(void) {
  static int done = 0;
  if (done)
    return;
  done = 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<OPENSSL_init>:
  endbr64
  mov    D11(%rip),%eax
  test   %eax,%eax
  jne    L6
  movl   $0x1,D11(%rip)
L6:
  ret
```

assistant: ```c
void OPENSSL_init(void) {
  static int done = 0;
  if (done)
    return;
  done = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<OPENSSL_init>:
  endbr64
  mov    D9(%rip),%eax
  test   %eax,%eax
  jne    L9
  movl   $0x1,D9(%rip)
L9:
  ret
```

assistant: ```c
void OPENSSL_init(void) {
  static int done = 0;
  if (done)
    return;
  done = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<COM_StripExtension3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Q_strncpyz@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L35
L8:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L16
L35:
  cmpl   $0x0,-0x4(%rbp)
  jle    L11
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L8
L11:
  cmpl   $0x0,-0x4(%rbp)
  je     L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L41
L16:
  nop
L41:
  leave
  ret
```

assistant: ```c
void COM_StripExtension3(const char *src, char *dest, int destsize) {
  int length;
  Q_strncpyz(dest, src, destsize);
  length = strlen(dest) - 1;
  while (length > 0 && dest[length] != '.') {
    length--;
    if (dest[length] == '/')
      return;
  }
  if (length) {
    dest[length] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<COM_StripExtension3>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <Q_strncpyz@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
L37:
  mov    %eax,%edx
  test   %eax,%eax
  jle    L30
  cmpb   $0x2e,(%rbx,%rax,1)
  je     L46
  sub    $0x1,%rax
  cmpb   $0x2f,(%rbx,%rax,1)
  jne    L37
  jmp    L31
L30:
  test   %eax,%eax
  jne    L46
L31:
  pop    %rbx
  ret
L46:
  movslq %edx,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  jmp    L31
```

assistant: ```c
void COM_StripExtension3(const char *src, char *dest, int destsize) {
  int length;
  Q_strncpyz(dest, src, destsize);
  length = strlen(dest) - 1;
  while (length > 0 && dest[length] != '.') {
    length--;
    if (dest[length] == '/')
      return;
  }
  if (length) {
    dest[length] = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<COM_StripExtension3>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <Q_strncpyz@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L32:
  cmpb   $0x2e,(%rdx)
  mov    %rdx,%rcx
  je     L12
  sub    $0x1,%rdx
  sub    $0x1,%eax
  cmpb   $0x2f,(%rdx)
  je     L46
L48:
  test   %eax,%eax
  jg     L32
  jne    L10
L46:
  pop    %rbx
  ret
L10:
  cltq
  lea    (%rbx,%rax,1),%rcx
L12:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
void COM_StripExtension3(const char *src, char *dest, int destsize) {
  int length;
  Q_strncpyz(dest, src, destsize);
  length = strlen(dest) - 1;
  while (length > 0 && dest[length] != '.') {
    length--;
    if (dest[length] == '/')
      return;
  }
  if (length) {
    dest[length] = 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<COM_StripExtension3>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <Q_strncpyz@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmpb   $0x2e,(%rdx)
  mov    %rdx,%rcx
  je     L0
  sub    $0x1,%rdx
  sub    $0x1,%eax
  cmpb   $0x2f,(%rdx)
  je     L37
L25:
  test   %eax,%eax
  jg     L13
  jne    L26
L37:
  pop    %rbx
  ret
L26:
  cltq
  lea    (%rbx,%rax,1),%rcx
L0:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
```

assistant: ```c
void COM_StripExtension3(const char *src, char *dest, int destsize) {
  int length;
  Q_strncpyz(dest, src, destsize);
  length = strlen(dest) - 1;
  while (length > 0 && dest[length] != '.') {
    length--;
    if (dest[length] == '/')
      return;
  }
  if (length) {
    dest[length] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lirc_parse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L38
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lirc_parse_escape@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
  jmp    L17
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void lirc_parse_string(char *s, int line) {
  char *t;
  t = s;
  while (*s != 0) {
    if (*s == '\\') {
      s++;
      *t = lirc_parse_escape(&s, line);
      t++;
    } else {
      *t = *s;
      s++;
      t++;
    }
  }
  *t = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lirc_parse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rdx
  mov    %rdi,0x8(%rsp)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L45
  mov    %esi,%ebp
  lea    0x1(%rdi),%rbx
  lea    0x8(%rsp),%r12
  jmp    L38
L4:
  add    $0x1,%rdx
  mov    %rdx,0x8(%rsp)
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <lirc_parse_escape@plt>
  mov    %rbx,%rcx
  mov    %al,-0x1(%rbx)
L43:
  mov    0x8(%rsp),%rdx
  movzbl (%rdx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L9
L38:
  cmp    $0x5c,%al
  je     L4
  mov    %rbx,%rcx
  mov    %al,-0x1(%rbx)
  addq   $0x1,0x8(%rsp)
  jmp    L43
L45:
  mov    %rdi,%rcx
L9:
  movb   $0x0,(%rcx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lirc_parse_string(char *s, int line) {
  char *t;
  t = s;
  while (*s != 0) {
    if (*s == '\\') {
      s++;
      *t = lirc_parse_escape(&s, line);
      t++;
    } else {
      *t = *s;
      s++;
      t++;
    }
  }
  *t = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lirc_parse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L33
  mov    %esi,%ebp
  mov    %rdi,%rax
  lea    0x8(%rsp),%r12
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L42:
  mov    0x8(%rsp),%rax
  mov    %dl,-0x1(%rbx)
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L33
L12:
  add    $0x1,%rbx
  cmp    $0x5c,%dl
  jne    L42
  add    $0x1,%rax
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %rax,0x8(%rsp)
  call   <lirc_parse_escape@plt>
  mov    %al,-0x1(%rbx)
  mov    0x8(%rsp),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L12
L33:
  movb   $0x0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lirc_parse_string(char *s, int line) {
  char *t;
  t = s;
  while (*s != 0) {
    if (*s == '\\') {
      s++;
      *t = lirc_parse_escape(&s, line);
      t++;
    } else {
      *t = *s;
      s++;
      t++;
    }
  }
  *t = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lirc_parse_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  mov    %esi,%ebp
  mov    %rdi,%rdx
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L12:
  add    $0x1,%rbx
  cmp    $0x5c,%al
  je     L5
  mov    %al,-0x1(%rbx)
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L12
L26:
  movb   $0x0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L5:
  add    $0x1,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %rdx,0x8(%rsp)
  call   <lirc_parse_escape@plt>
  mov    0x8(%rsp),%rdx
  mov    %al,-0x1(%rbx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L12
  movb   $0x0,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lirc_parse_string(char *s, int line) {
  char *t;
  t = s;
  while (*s != 0) {
    if (*s == '\\') {
      s++;
      *t = lirc_parse_escape(&s, line);
      t++;
    } else {
      *t = *s;
      s++;
      t++;
    }
  }
  *t = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_cals>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L58
  mov    %rdi,%r9
  mov    %edx,%esi
  mov    %ecx,%r11d
  mov    %r8,%r13
  mov    %edx,%r10d
  shr    $0x1f,%r10d
  add    %edx,%r10d
  sar    %r10d
  mov    %r8,%rbx
  lea    -0x1(%r12),%eax
  lea    0x4(%r8,%rax,4),%r14
  mov    %r8,%rbp
  lea    (%rdx,%rcx,1),%r8d
L37:
  mov    %rbp,%rdi
  movl   $0x0,0x0(%rbp)
  cmp    $0x1,%esi
  jle    L21
  mov    $0x0,%ecx
L27:
  lea    (%r11,%rcx,1),%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  mov    (%r9),%rax
  movss  (%rdi),%xmm0
  addss  (%rax,%rdx,4),%xmm0
  movss  %xmm0,(%rdi)
  add    $0x1,%ecx
  cmp    %r10d,%ecx
  jl     L27
L21:
  cmp    %r10d,%esi
  jle    L1
  lea    (%r11,%r10,1),%ecx
L61:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  mov    (%r9),%rax
  movss  (%rdi),%xmm0
  subss  (%rax,%rdx,4),%xmm0
  movss  %xmm0,(%rdi)
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L61
L1:
  add    $0x4,%rbp
  add    $0x8,%r9
  cmp    %r14,%rbp
  jne    L37
  pxor   %xmm1,%xmm1
L16:
  addss  0x0(%r13),%xmm1
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L16
  pxor   %xmm2,%xmm2
  cvtsi2ss %r12d,%xmm2
  divss  %xmm2,%xmm1
L42:
  movss  (%rbx),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L42
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void find_cals(float **tot, int nchan, int period, int phase, float *cal) {
  for (int i = 0; i < nchan; i++) {
    cal[i] = 0;
    for (int j = 0; j < period / 2; j++)
      cal[i] += tot[i][(j + phase) % period];
    for (int j = period / 2; j < period; j++)
      cal[i] -= tot[i][(j + phase) % period];
  }
  float norm = 0;
  for (int i = 0; i < nchan; i++)
    norm += cal[i];
  norm /= nchan;
  for (int i = 0; i < nchan; i++)
    cal[i] /= norm;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_cals>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  test   %esi,%esi
  jle    L18
  mov    %edx,%r9d
  lea    -0x1(%rbp),%eax
  mov    %rdi,%r12
  mov    %edx,%esi
  shr    $0x1f,%r9d
  mov    %ecx,%r10d
  mov    %r8,%rbx
  mov    %r8,%rdi
  lea    0x4(%r8,%rax,4),%r13
  pxor   %xmm1,%xmm1
  lea    (%rcx,%rdx,1),%r11d
  add    %edx,%r9d
  sar    %r9d
  nopl   0x0(%rax)
L59:
  movl   $0x0,(%rdi)
  cmp    $0x1,%esi
  jle    L43
  mov    (%r12),%r14
  movaps %xmm1,%xmm0
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L10:
  lea    (%rcx,%r10,1),%eax
  add    $0x1,%ecx
  cltd
  idiv   %esi
  movslq %edx,%rdx
  addss  (%r14,%rdx,4),%xmm0
  movss  %xmm0,(%rdi)
  cmp    %r9d,%ecx
  jl     L10
L43:
  cmp    %r9d,%esi
  jle    L71
  mov    (%r12),%r14
  movss  (%rdi),%xmm0
  lea    (%r10,%r9,1),%ecx
  nopl   (%rax)
L11:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cltd
  idiv   %esi
  movslq %edx,%rdx
  subss  (%r14,%rdx,4),%xmm0
  movss  %xmm0,(%rdi)
  cmp    %ecx,%r11d
  jne    L11
L71:
  add    $0x4,%rdi
  add    $0x8,%r12
  cmp    %r13,%rdi
  jne    L59
  movaps %xmm1,%xmm0
  nopw   0x0(%rax,%rax,1)
L47:
  addss  (%rbx),%xmm0
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L47
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  divss  %xmm1,%xmm0
  nopl   0x0(%rax)
L8:
  movss  (%r8),%xmm1
  add    $0x4,%r8
  divss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%r8)
  cmp    %r13,%r8
  jne    L8
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void find_cals(float **tot, int nchan, int period, int phase, float *cal) {
  for (int i = 0; i < nchan; i++) {
    cal[i] = 0;
    for (int j = 0; j < period / 2; j++)
      cal[i] += tot[i][(j + phase) % period];
    for (int j = period / 2; j < period; j++)
      cal[i] -= tot[i][(j + phase) % period];
  }
  float norm = 0;
  for (int i = 0; i < nchan; i++)
    norm += cal[i];
  norm /= nchan;
  for (int i = 0; i < nchan; i++)
    cal[i] /= norm;
}
```