ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_valid_int>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  jne    L6
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L6:
  test   %dil,%dil
  jne    L0
  jmp    L15
L45:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L11
L0:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L45
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool is_valid_int(const char *str) {
  if (*str == '-')
    ++str;
  if (!*str)
    return false;
  while (*str) {
    if (!isdigit(*str))
      return false;
    else
      ++str;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<k_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  jmp    L3
L12:
  cmpq   $0x0,-0x18(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
L9:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int k_write(int *nwritten, int fd, const void *addr, int count) {
  int rc = write(fd, addr, count);
  if (rc < 0)
    return errno;
  if (nwritten)
    *nwritten = rc;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<k_write>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <write@plt>
  test   %eax,%eax
  js     L15
  mov    $0x0,%edx
  test   %rbx,%rbx
  je     L7
  mov    %eax,(%rbx)
L7:
  mov    %edx,%eax
  pop    %rbx
  ret
L15:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  jmp    L7
```

assistant: ```c
int k_write(int *nwritten, int fd, const void *addr, int count) {
  int rc = write(fd, addr, count);
  if (rc < 0)
    return errno;
  if (nwritten)
    *nwritten = rc;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<k_write>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <write@plt>
  test   %eax,%eax
  js     L12
  xor    %r8d,%r8d
  test   %rbx,%rbx
  je     L19
  mov    %eax,(%rbx)
L19:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    D2(%rip),%rax
  pop    %rbx
  mov    (%rax),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int k_write(int *nwritten, int fd, const void *addr, int count) {
  int rc = write(fd, addr, count);
  if (rc < 0)
    return errno;
  if (nwritten)
    *nwritten = rc;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<k_write>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <write@plt>
  test   %eax,%eax
  js     L5
  xor    %r8d,%r8d
  test   %rbx,%rbx
  je     L12
  mov    %eax,(%rbx)
L12:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D4(%rip),%rax
  pop    %rbx
  mov    (%rax),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int k_write(int *nwritten, int fd, const void *addr, int count) {
  int rc = write(fd, addr, count);
  if (rc < 0)
    return errno;
  if (nwritten)
    *nwritten = rc;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<new_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L2
L13:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int new_arg(int *cnt, char **argv[]) {
  char **p;
  p = realloc(*argv, sizeof(char *) * (*cnt + 1));
  if (p == ((void *)0))
    return -1;
  *argv = p;
  (*argv)[*cnt] = ((void *)0);
  (*cnt)++;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_arg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%eax
  lea    0x1(%rax),%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,0x0(%rbp)
  movslq (%rbx),%rdx
  movq   $0x0,(%rax,%rdx,8)
  addl   $0x1,(%rbx)
  mov    $0x0,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int new_arg(int *cnt, char **argv[]) {
  char **p;
  p = realloc(*argv, sizeof(char *) * (*cnt + 1));
  if (p == ((void *)0))
    return -1;
  *argv = p;
  (*argv)[*cnt] = ((void *)0);
  (*cnt)++;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<new_arg>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  mov    0x0(%rbp),%rdi
  lea    0x1(%rax),%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L1
  movslq (%rbx),%rcx
  mov    %rax,0x0(%rbp)
  mov    %rcx,%rdx
  movq   $0x0,(%rax,%rcx,8)
  xor    %eax,%eax
  add    $0x1,%edx
  mov    %edx,(%rbx)
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  or     $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int new_arg(int *cnt, char **argv[]) {
  char **p;
  p = realloc(*argv, sizeof(char *) * (*cnt + 1));
  if (p == ((void *)0))
    return -1;
  *argv = p;
  (*argv)[*cnt] = ((void *)0);
  (*cnt)++;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_arg>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  mov    0x0(%rbp),%rdi
  lea    0x1(%rax),%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L10
  movslq (%rbx),%rcx
  mov    %rax,0x0(%rbp)
  mov    %rcx,%rdx
  movq   $0x0,(%rax,%rcx,8)
  xor    %eax,%eax
  add    $0x1,%edx
  mov    %edx,(%rbx)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  or     $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int new_arg(int *cnt, char **argv[]) {
  char **p;
  p = realloc(*argv, sizeof(char *) * (*cnt + 1));
  if (p == ((void *)0))
    return -1;
  *argv = p;
  (*argv)[*cnt] = ((void *)0);
  (*cnt)++;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<argcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L10
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L9
  lea    D14(%rip),%rax
  jmp    L24
L9:
  lea    D29(%rip),%rax
L24:
  mov    -0x8(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <lerror@plt>
L10:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D14: few

tool: D29: many

tool: D19: %s: error: too %s arguments


assistant: ```c
void argcount(char *fname, int nargs, int c) {
  if (nargs != c)
    lerror("%s: error: too %s arguments\n", fname, nargs < c ? "few" : "many");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argcount>:
  endbr64
  sub    $0x8,%rsp
  cmp    %edx,%esi
  je     L8
  lea    D7(%rip),%rdx
  lea    D18(%rip),%rax
  cmovge %rax,%rdx
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  call   <lerror@plt>
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D26
type: string

tool: D7: few

tool: D18: many

tool: D26: %s: error: too %s arguments


assistant: ```c
void argcount(char *fname, int nargs, int c) {
  if (nargs != c)
    lerror("%s: error: too %s arguments\n", fname, nargs < c ? "few" : "many");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<argcount>:
  endbr64
  cmp    %edx,%esi
  je     L2
  lea    D0(%rip),%rdx
  lea    D19(%rip),%rax
  mov    %rdi,%rsi
  cmovge %rax,%rdx
  lea    D2(%rip),%rdi
  jmp    1050 <lerror@plt>
  nopl   0x0(%rax)
L2:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string

tool: D0: few

tool: D19: many

tool: D2: %s: error: too %s arguments


assistant: ```c
void argcount(char *fname, int nargs, int c) {
  if (nargs != c)
    lerror("%s: error: too %s arguments\n", fname, nargs < c ? "few" : "many");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<argcount>:
  endbr64
  cmp    %edx,%esi
  je     L0
  lea    D4(%rip),%rdx
  lea    D23(%rip),%rax
  mov    %rdi,%rsi
  cmovge %rax,%rdx
  lea    D20(%rip),%rdi
  jmp    1050 <lerror@plt>
  nopl   0x0(%rax)
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D23
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string

tool: D4: few

tool: D23: many

tool: D20: %s: error: too %s arguments


assistant: ```c
void argcount(char *fname, int nargs, int c) {
  if (nargs != c)
    lerror("%s: error: too %s arguments\n", fname, nargs < c ? "few" : "many");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xilinxcorelib_a_4172306344_2959432447_p_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x790,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x29e8,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  mov    -0x48(%rbp),%rax
  add    $0x28a8,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void xilinxcorelib_a_4172306344_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xilinxcorelib_a_4172306344_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x790(%rdi),%rsi
  mov    0x2a20(%rdi),%rax
  mov    0x38(%rax),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_4172306344_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xilinxcorelib_a_4172306344_2959432447_p_3>:
  endbr64
  push   %rbx
  mov    0x2a20(%rdi),%rax
  mov    %rdi,%rbx
  mov    $0x10,%edx
  mov    0x790(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  lea    0x29e8(%rbx),%rdi
  call   <xsi_driver_first_trans_fast_port@plt>
  movl   $0x1,0x28a8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_4172306344_2959432447_p_3(char *t0) {
  char *t1;
  char *t2;
  char *t3;
  char *t4;
  char *t5;
  char *t6;
  char *t7;
LAB0:
LAB3:
  t1 = (t0 + 1936U);
  t2 = *((char **)t1);
  t1 = (t0 + 10728);
  t3 = (t1 + 56U);
  t4 = *((char **)t3);
  t5 = (t4 + 56U);
  t6 = *((char **)t5);
  memcpy(t6, t2, 16U);
  xsi_driver_first_trans_fast_port(t1);
LAB2:
  t7 = (t0 + 10408);
  *((int *)t7) = 1;
LAB1:
  return;
LAB4:
  goto LAB2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <createList@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <removeNthFromEnd@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct ListNode *head = NULL;
  int arr[1] = {1};
  head = createList(arr, 1);
  printList(head);
  head = removeNthFromEnd(head, 1);
  printList(head);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x1,%esi
  call   <createList@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <printList@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <removeNthFromEnd@plt>
  mov    %rax,%rdi
  call   <printList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *head = NULL;
  int arr[1] = {1};
  head = createList(arr, 1);
  printList(head);
  head = removeNthFromEnd(head, 1);
  printList(head);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <createList@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <removeNthFromEnd@plt>
  mov    %rax,%rdi
  call   <printList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *head = NULL;
  int arr[1] = {1};
  head = createList(arr, 1);
  printList(head);
  head = removeNthFromEnd(head, 1);
  printList(head);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <createList@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <removeNthFromEnd@plt>
  mov    %rax,%rdi
  call   <printList@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct ListNode *head = NULL;
  int arr[1] = {1};
  head = createList(arr, 1);
  printList(head);
  head = removeNthFromEnd(head, 1);
  printList(head);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list_add_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <kl_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_add@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_add_copy(void *rptr, void *node, int size) {
  void *nptr = kl_malloc(size);
  memcpy(nptr, node, size);
  list_add(rptr, nptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_add_copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %edx,%edi
  call   <kl_malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <list_add@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void list_add_copy(void *rptr, void *node, int size) {
  void *nptr = kl_malloc(size);
  memcpy(nptr, node, size);
  list_add(rptr, nptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_add_copy>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <kl_malloc@plt>
  mov    %r14,%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <list_add@plt>
```

assistant: ```c
void list_add_copy(void *rptr, void *node, int size) {
  void *nptr = kl_malloc(size);
  memcpy(nptr, node, size);
  list_add(rptr, nptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list_add_copy>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    $0x8,%rsp
  call   <kl_malloc@plt>
  mov    %r14,%rsi
  mov    %r12d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <list_add@plt>
```

assistant: ```c
void list_add_copy(void *rptr, void *node, int size) {
  void *nptr = kl_malloc(size);
  memcpy(nptr, node, size);
  list_add(rptr, nptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Slcd_Bit_Swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x2(%rbp)
  jmp    L2
L19:
  shlb   -0x1(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x2(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x1(%rbp)
  addb   $0x1,-0x2(%rbp)
L2:
  cmpb   $0x7,-0x2(%rbp)
  jbe    L19
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char Slcd_Bit_Swap(unsigned char DATA) {
  unsigned char i = 0;
  unsigned char RESULT = 0;
  for (i = 0; i <= 7; i += 1) {
    RESULT = RESULT << 1;
    RESULT = RESULT | ((DATA >> i) & 0x01);
  }
  return RESULT;
}
```
user: What is the c source code of the assembly code below:

```asm
<Slcd_Bit_Swap>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%eax
  movzbl %dil,%edi
L1:
  add    %eax,%eax
  mov    %edi,%edx
  sar    %cl,%edx
  and    $0x1,%edx
  or     %edx,%eax
  add    $0x1,%ecx
  cmp    $0x8,%ecx
  jne    L1
  ret
```

assistant: ```c
unsigned char Slcd_Bit_Swap(unsigned char DATA) {
  unsigned char i = 0;
  unsigned char RESULT = 0;
  for (i = 0; i <= 7; i += 1) {
    RESULT = RESULT << 1;
    RESULT = RESULT | ((DATA >> i) & 0x01);
  }
  return RESULT;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Slcd_Bit_Swap>:
  endbr64
  movzbl %dil,%edi
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  mov    %edi,%edx
  add    %eax,%eax
  sar    %cl,%edx
  add    $0x1,%ecx
  and    $0x1,%edx
  or     %edx,%eax
  cmp    $0x8,%ecx
  jne    L4
  ret
```

assistant: ```c
unsigned char Slcd_Bit_Swap(unsigned char DATA) {
  unsigned char i = 0;
  unsigned char RESULT = 0;
  for (i = 0; i <= 7; i += 1) {
    RESULT = RESULT << 1;
    RESULT = RESULT | ((DATA >> i) & 0x01);
  }
  return RESULT;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Slcd_Bit_Swap>:
  endbr64
  movzbl %dil,%edx
  add    %edi,%edi
  mov    %edx,%ecx
  and    $0x2,%edi
  mov    %edx,%eax
  sar    %ecx
  sar    $0x2,%eax
  and    $0x1,%ecx
  and    $0x1,%eax
  or     %edi,%ecx
  add    %ecx,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  sar    $0x3,%ecx
  add    %eax,%eax
  and    $0x1,%ecx
  or     %eax,%ecx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %ecx,%ecx
  and    $0x1,%eax
  or     %ecx,%eax
  mov    %edx,%ecx
  sar    $0x5,%ecx
  add    %eax,%eax
  and    $0x1,%ecx
  or     %eax,%ecx
  mov    %edx,%eax
  sar    $0x7,%edx
  sar    $0x6,%eax
  add    %ecx,%ecx
  and    $0x1,%eax
  or     %ecx,%eax
  add    %eax,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned char Slcd_Bit_Swap(unsigned char DATA) {
  unsigned char i = 0;
  unsigned char RESULT = 0;
  for (i = 0; i <= 7; i += 1) {
    RESULT = RESULT << 1;
    RESULT = RESULT | ((DATA >> i) & 0x01);
  }
  return RESULT;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stripExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STRDUP@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <findExt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *stripExt(const char *in) {
  char *out = STRDUP(in);
  char *ext = findExt(out);
  if (ext)
    *ext = '\0';
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stripExt>:
  endbr64
  push   %rbx
  call   <STRDUP@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <findExt@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *stripExt(const char *in) {
  char *out = STRDUP(in);
  char *ext = findExt(out);
  if (ext)
    *ext = '\0';
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stripExt>:
  endbr64
  push   %r12
  call   <STRDUP@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <findExt@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
L3:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *stripExt(const char *in) {
  char *out = STRDUP(in);
  char *ext = findExt(out);
  if (ext)
    *ext = '\0';
  return out;
}
```