ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L29
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  nop
L49:
  xor    %eax,%eax
  call   <clear_cache@plt>
  mov    %ebx,%edi
  call   <cal_loop@plt>
  cmp    %ebp,%eax
  jle    L30
  mov    %ebx,%r12d
  mov    %eax,%ebp
L30:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L49
L35:
  mov    %r12d,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  xor    %r12d,%r12d
  jmp    L35
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D7: %d

tool: D14: %d


assistant: ```c
int main() {
  int n;
  int max_loop = 0;
  int max_num = 0;
  scanf("%d", &n);
  int i = 1;
  while (i <= n) {
    clear_cache();
    int loop = cal_loop(i);
    if (loop > max_loop) {
      max_loop = loop;
      max_num = i;
    }
    i++;
  }
  printf("%d\n", max_num);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L28:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L18
  addl   $0x1,-0xc(%rbp)
L18:
  addl   $0x1,-0x10(%rbp)
L31:
  cmpl   $0x5,-0x10(%rbp)
  jle    L28
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D1: %f

tool: D15: %d valores positivos


assistant: ```c
int main(void) {
  float x;
  int i, c = 0;
  for (i = 0; i < 6; i++) {
    scanf("%f", &x);
    if (x > 0)
      c++;
  }
  printf("%d valores positivos\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x6,%ebx
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r13
  lea    D11(%rip),%r12
L18:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L18
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D11: %f

tool: D16: %d valores positivos


assistant: ```c
int main(void) {
  float x;
  int i, c = 0;
  for (i = 0; i < 6; i++) {
    scanf("%f", &x);
    if (x > 0)
      c++;
  }
  printf("%d valores positivos\n", c);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L8
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D10: %f

tool: D16: %d valores positivos


assistant: ```c
int main(void) {
  float x;
  int i, c = 0;
  for (i = 0; i < 6; i++) {
    scanf("%f", &x);
    if (x > 0)
      c++;
  }
  printf("%d valores positivos\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L3
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D12: %f

tool: D13: %d valores positivos


assistant: ```c
int main(void) {
  float x;
  int i, c = 0;
  for (i = 0; i < 6; i++) {
    scanf("%f", &x);
    if (x > 0)
      c++;
  }
  printf("%d valores positivos\n", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L7
L8:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sin@plt>
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <cos@plt>
  movapd %xmm0,%xmm2
  mulsd  -0x20(%rbp),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <tan@plt>
  mulsd  -0x20(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  cmpq   $0x98967f,-0x10(%rbp)
  jle    L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string

tool: D8: Task %ld started


tool: D16: Task %ld completed with result %e


assistant: ```c
void task(long id) {
  printf("Task %ld started\n", id);
  long i;
  double result = 0.0;
  for (i = 0; i < 10000000; i++) {
    result = result + sin(i) * cos(i) * tan(i);
  }
  printf("Task %ld completed with result %e\n", id, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<task>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
  mov    $0x0,%ebx
L9:
  mov    %rbx,%rdi
  call   <sin@plt>
  movq   %xmm0,%r14
  mov    %rbx,%rdi
  call   <cos@plt>
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbx,%rdi
  call   <tan@plt>
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%rbx
  cmp    $0x989680,%rbx
  jne    L9
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string

tool: D14: Task %ld started


tool: D7: Task %ld completed with result %e


assistant: ```c
void task(long id) {
  printf("Task %ld started\n", id);
  long i;
  double result = 0.0;
  for (i = 0; i < 10000000; i++) {
    result = result + sin(i) * cos(i) * tan(i);
  }
  printf("Task %ld completed with result %e\n", id, result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<task>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  push   %rbx
  lea    D16(%rip),%rdi
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rdi
  call   <sin@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbx,%rdi
  add    $0x1,%rbx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <tan@plt>
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x989680,%rbx
  jne    L7
  add    $0x18,%rsp
  mov    %rbp,%rsi
  mov    $0x1,%eax
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  jmp    1080 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string

tool: D16: Task %ld started


tool: D13: Task %ld completed with result %e


assistant: ```c
void task(long id) {
  printf("Task %ld started\n", id);
  long i;
  double result = 0.0;
  for (i = 0; i < 10000000; i++) {
    result = result + sin(i) * cos(i) * tan(i);
  }
  printf("Task %ld completed with result %e\n", id, result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<task>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  push   %rbx
  lea    D2(%rip),%rdi
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdi
  call   <sin@plt>
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbx,%rdi
  add    $0x1,%rbx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <tan@plt>
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x989680,%rbx
  jne    L2
  add    $0x18,%rsp
  mov    %rbp,%rsi
  mov    $0x1,%eax
  pop    %rbx
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    1080 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D2: Task %ld started


tool: D6: Task %ld completed with result %e


assistant: ```c
void task(long id) {
  printf("Task %ld started\n", id);
  long i;
  double result = 0.0;
  for (i = 0; i < 10000000; i++) {
    result = result + sin(i) * cos(i) * tan(i);
  }
  printf("Task %ld completed with result %e\n", id, result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<access>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L43
  mov    $0xffffffff,%eax
  jmp    L78
L43:
  movl   $0x1,-0xc(%rbp)
  mov    D105(%rip),%rax
  mov    (%rax),%eax
  and    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L15
  mov    -0x10(%rbp),%edx
  mov    D119(%rip),%rax
  mov    (%rax),%ecx
  mov    D139(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D93(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  and    %eax,-0xc(%rbp)
L15:
  mov    D101(%rip),%rax
  mov    (%rax),%eax
  and    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L63
  mov    -0x10(%rbp),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D78(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  and    %eax,-0xc(%rbp)
L63:
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  and    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L25
  mov    -0x10(%rbp),%edx
  mov    D87(%rip),%rax
  mov    (%rax),%ecx
  mov    D118(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%ecx
  mov    D130(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  and    %eax,-0xc(%rbp)
L25:
  cmpl   $0x0,-0xc(%rbp)
  jne    L68
  mov    D73(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L78
L68:
  mov    $0x0,%eax
L78:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
int access(const char *path, int mode) {
  struct stat st;
  if (stat(path, &st) < 0) {
    return -1;
  }
  bool accessible = true;
  if (mode & R_OK) {
    accessible &= !!(st.st_mode & (S_IRUSR | S_IRGRP | S_IROTH));
  }
  if (mode & W_OK) {
    accessible &= !!(st.st_mode & (S_IWUSR | S_IWGRP | S_IWOTH));
  }
  if (mode & X_OK) {
    accessible &= !!(st.st_mode & (S_IXUSR | S_IXGRP | S_IXOTH));
  }
  if (!accessible) {
    errno = EACCES;
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<access>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L11
  mov    D1(%rip),%rax
  mov    %ebx,%edx
  and    (%rax),%edx
  mov    $0x1,%eax
  je     L72
  mov    D130(%rip),%rax
  mov    (%rax),%eax
  mov    D30(%rip),%rdx
  or     (%rdx),%eax
  mov    D78(%rip),%rdx
  or     (%rdx),%eax
  and    0x4(%rsp),%eax
  setne  %al
  movzbl %al,%eax
L72:
  mov    D38(%rip),%rdx
  mov    %ebx,%ecx
  and    (%rdx),%ecx
  je     L63
  mov    D106(%rip),%rdx
  mov    (%rdx),%edx
  mov    D47(%rip),%rcx
  or     (%rcx),%edx
  mov    D16(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
L63:
  mov    D124(%rip),%rdx
  and    (%rdx),%ebx
  je     L12
  mov    D17(%rip),%rdx
  mov    (%rdx),%edx
  mov    D122(%rip),%rcx
  or     (%rcx),%edx
  mov    D25(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
L12:
  test   %eax,%eax
  je     L40
  mov    $0x0,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  ret
L40:
  mov    D82(%rip),%rax
  mov    (%rax),%edx
  mov    D61(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L41
L11:
  mov    $0xffffffff,%eax
  jmp    L41
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int access(const char *path, int mode) {
  struct stat st;
  if (stat(path, &st) < 0) {
    return -1;
  }
  bool accessible = true;
  if (mode & R_OK) {
    accessible &= !!(st.st_mode & (S_IRUSR | S_IRGRP | S_IROTH));
  }
  if (mode & W_OK) {
    accessible &= !!(st.st_mode & (S_IWUSR | S_IWGRP | S_IWOTH));
  }
  if (mode & X_OK) {
    accessible &= !!(st.st_mode & (S_IXUSR | S_IXGRP | S_IXOTH));
  }
  if (!accessible) {
    errno = EACCES;
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<access>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L31
  mov    D111(%rip),%rax
  mov    %ebx,%edx
  and    (%rax),%edx
  mov    $0x1,%eax
  je     L86
  mov    D123(%rip),%rdx
  mov    D80(%rip),%rax
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D0(%rip),%rdx
  or     (%rdx),%eax
  and    0x4(%rsp),%eax
  setne  %al
  movzbl %al,%eax
L86:
  mov    D48(%rip),%rdx
  mov    %ebx,%ecx
  and    (%rdx),%ecx
  je     L8
  mov    D104(%rip),%rcx
  mov    D38(%rip),%rdx
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D25(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
L8:
  mov    D59(%rip),%rdx
  and    (%rdx),%ebx
  jne    L12
L71:
  test   %eax,%eax
  je     L60
  xor    %eax,%eax
L89:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  ret
L12:
  mov    D90(%rip),%rcx
  mov    D3(%rip),%rdx
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D118(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
  jmp    L71
  nopl   0x0(%rax)
L60:
  mov    D73(%rip),%rax
  mov    (%rax),%edx
  mov    D94(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L89
L31:
  mov    $0xffffffff,%eax
  jmp    L89
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int access(const char *path, int mode) {
  struct stat st;
  if (stat(path, &st) < 0) {
    return -1;
  }
  bool accessible = true;
  if (mode & R_OK) {
    accessible &= !!(st.st_mode & (S_IRUSR | S_IRGRP | S_IROTH));
  }
  if (mode & W_OK) {
    accessible &= !!(st.st_mode & (S_IWUSR | S_IWGRP | S_IWOTH));
  }
  if (mode & X_OK) {
    accessible &= !!(st.st_mode & (S_IXUSR | S_IXGRP | S_IXOTH));
  }
  if (!accessible) {
    errno = EACCES;
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<access>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L69
  mov    D59(%rip),%rax
  mov    %ebx,%edx
  and    (%rax),%edx
  mov    $0x1,%eax
  je     L6
  mov    D38(%rip),%rdx
  mov    D130(%rip),%rax
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D85(%rip),%rdx
  or     (%rdx),%eax
  and    0x4(%rsp),%eax
  setne  %al
  movzbl %al,%eax
L6:
  mov    D93(%rip),%rdx
  mov    %ebx,%ecx
  and    (%rdx),%ecx
  je     L20
  mov    D50(%rip),%rcx
  mov    D120(%rip),%rdx
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D91(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
L20:
  mov    D70(%rip),%rdx
  and    (%rdx),%ebx
  jne    L23
L75:
  test   %eax,%eax
  je     L7
  xor    %eax,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L86
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  mov    D65(%rip),%rcx
  mov    D73(%rip),%rdx
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D42(%rip),%rcx
  or     (%rcx),%edx
  and    0x4(%rsp),%edx
  setne  %dl
  movzbl %dl,%edx
  and    %edx,%eax
  jmp    L75
  nopl   0x0(%rax)
L7:
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D46(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L32
L69:
  mov    $0xffffffff,%eax
  jmp    L32
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int access(const char *path, int mode) {
  struct stat st;
  if (stat(path, &st) < 0) {
    return -1;
  }
  bool accessible = true;
  if (mode & R_OK) {
    accessible &= !!(st.st_mode & (S_IRUSR | S_IRGRP | S_IROTH));
  }
  if (mode & W_OK) {
    accessible &= !!(st.st_mode & (S_IWUSR | S_IWGRP | S_IWOTH));
  }
  if (mode & X_OK) {
    accessible &= !!(st.st_mode & (S_IXUSR | S_IXGRP | S_IXOTH));
  }
  if (!accessible) {
    errno = EACCES;
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Q_StrReplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  movq   $0x0,0x400(%rsp)
  movq   $0x0,0x408(%rsp)
  lea    0x410(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  cmpb   $0x0,(%rbx)
  je     L113
  mov    %rsi,%r12
  mov    %rdx,%rsi
  cmpb   $0x0,(%r12)
  je     L27
  cmpb   $0x0,(%rdx)
  jne    L67
L71:
  movb   $0x0,(%rsp)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x400(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  cmpb   $0x0,(%rbx)
  je     L69
  mov    %rsp,%rbp
  mov    %rsp,%r14
  jmp    L38
L27:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <Q_strncpyz@plt>
  jmp    L113
L67:
  lea    0x400(%rsp),%rdi
  mov    $0x400,%edx
  mov    $0x0,%eax
  call   <Q_strncpyz@plt>
  jmp    L71
L94:
  lea    0x400(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r14,%rdi
  call   <Q_strcat@plt>
  movslq %r13d,%rax
  add    %rax,%rbx
  movslq %r15d,%rax
  add    %rax,%rbp
  jmp    L84
L40:
  add    $0x1,%rbx
L84:
  cmpb   $0x0,(%rbx)
  je     L69
L38:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <Q_stricmpn@plt>
  test   %eax,%eax
  je     L94
  mov    %r14,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  ja     L40
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  movb   $0x0,0x1(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L40
L69:
  mov    %rsp,%rsi
  mov    $0x400,%edx
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <Q_strncpyz@plt>
L113:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  lea    D18(%rip),%rax
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *Q_StrReplace(char *haystack, char *needle, char *newp) {
  static char final[1024] = {""};
  char dest[1024] = {""};
  char newStr[1024] = {""};
  char *destp;
  int needle_len = 0;
  int new_len = 0;
  if (!*haystack) {
    return final;
  }
  if (!*needle) {
    Q_strncpyz(final, haystack, sizeof(final));
    return final;
  }
  if (*newp) {
    Q_strncpyz(newStr, newp, sizeof(newStr));
  }
  dest[0] = '\0';
  needle_len = strlen(needle);
  new_len = strlen(newStr);
  destp = &dest[0];
  while (*haystack) {
    if (!Q_stricmpn(haystack, needle, needle_len)) {
      Q_strcat(dest, sizeof(dest), newStr);
      haystack += needle_len;
      destp += new_len;
      continue;
    }
    if (1024 > (strlen(dest) + 1)) {
      *destp = *haystack;
      *++destp = '\0';
    }
    haystack++;
  }
  Q_strncpyz(final, dest, sizeof(final));
  return final;
}
```