ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L6
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *ptr, int c, unsigned int len) {
  unsigned int i;
  char *p;
  p = ptr;
  for (i = 0; i < len; i++)
    p[i] = c;
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L6
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *ptr, int c, unsigned int len) {
  unsigned int i;
  char *p;
  p = ptr;
  for (i = 0; i < len; i++)
    p[i] = c;
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bzero(buf, num) char *buf;
unsigned int num;
{
  int i;
  for (i = 0; i < num; i++)
    buf[i] = buf[i] ^ buf[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bzero>:
  endbr64
  test   %esi,%esi
  je     L2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L6:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L2:
  ret
```

assistant: ```c
void bzero(buf, num) char *buf;
unsigned int num;
{
  int i;
  for (i = 0; i < num; i++)
    buf[i] = buf[i] ^ buf[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<bzero>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void bzero(buf, num) char *buf;
unsigned int num;
{
  int i;
  for (i = 0; i < num; i++)
    buf[i] = buf[i] ^ buf[i];
}
```
user: What is the c source code of the assembly code below?

```asm
<bzero>:
  endbr64
  test   %esi,%esi
  je     L9
  mov    %esi,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void bzero(buf, num) char *buf;
unsigned int num;
{
  int i;
  for (i = 0; i < num; i++)
    buf[i] = buf[i] ^ buf[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
char *my_strcat(char *dest, char *src, size_t len) {
  if (0 == len)
    len = strlen(src);
  memcpy(dest, src, len);
  return dest + len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_strcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L4
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
L4:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strcat(char *dest, char *src, size_t len) {
  if (0 == len)
    len = strlen(src);
  memcpy(dest, src, len);
  return dest + len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strcat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L2
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
L2:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strcat(char *dest, char *src, size_t len) {
  if (0 == len)
    len = strlen(src);
  memcpy(dest, src, len);
  return dest + len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strcat>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jne    L5
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
L5:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strcat(char *dest, char *src, size_t len) {
  if (0 == len)
    len = strlen(src);
  memcpy(dest, src, len);
  return dest + len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: Hello, world!

assistant: ```c
int main() {
  printf("Hello, world!");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: Hello, world!

assistant: ```c
int main() {
  printf("Hello, world!");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: Hello, world!

assistant: ```c
int main() {
  printf("Hello, world!");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: Hello, world!

assistant: ```c
int main() {
  printf("Hello, world!");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_optchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L43
  mov    $0x1,%eax
  jmp    L22
L43:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%eax
  jmp    L22
L7:
  cmpb   $0x2d,-0x4(%rbp)
  jne    L2
  mov    $0x1,%eax
  jmp    L22
L2:
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int is_optchar(char c) {
  if (isupper(c))
    return (1);
  if (islower(c))
    return (1);
  if (c == '-')
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_optchar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isupper@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L6
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %ebp,%edi
  call   <islower@plt>
  mov    %rax,%rdx
  cmp    $0x2d,%bl
  sete   %al
  test   %rdx,%rdx
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  jmp    L3
```

assistant: ```c
int is_optchar(char c) {
  if (isupper(c))
    return (1);
  if (islower(c))
    return (1);
  if (c == '-')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_optchar>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <isupper@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L4
  mov    %ebp,%edi
  call   <islower@plt>
  cmp    $0x2d,%bl
  mov    %rax,%r8
  sete   %al
  test   %r8,%r8
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_optchar(char c) {
  if (isupper(c))
    return (1);
  if (islower(c))
    return (1);
  if (c == '-')
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_optchar>:
  endbr64
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <isupper@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L1
  mov    %ebp,%edi
  call   <islower@plt>
  cmp    $0x2d,%bl
  mov    %rax,%r8
  sete   %al
  test   %r8,%r8
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_optchar(char c) {
  if (isupper(c))
    return (1);
  if (islower(c))
    return (1);
  if (c == '-')
    return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcCRC16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L51
L45:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x8,%eax
  xor    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L38:
  mov    -0xc(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L68
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L57
L68:
  shll   -0xc(%rbp)
L57:
  addl   $0x1,-0x10(%rbp)
L7:
  cmpl   $0x7,-0x10(%rbp)
  jle    L38
L19:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L45
  mov    -0xc(%rbp),%eax
L51:
  pop    %rbp
  ret
```

assistant: ```c
uint16_t calcCRC16(void *buf, int len) {
  uint8_t i;
  uint16_t crc = 0;
  uint8_t *b = (uint8_t *)buf;
  if (!len)
    return -1;
  while (len--) {
    crc ^= (((uint16_t)*b++) << 8);
    for (i = 0; i < 8; ++i) {
      if (crc & 0x8000)
        crc = (crc << 1) ^ 0x1021;
      else
        crc <<= 1;
    }
  }
  return crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcCRC16>:
  endbr64
  test   %esi,%esi
  je     L1
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%r8
  mov    $0x0,%eax
  jmp    L47
L42:
  cmp    %r8,%rdi
  je     L41
L47:
  add    $0x4,%rdi
  mov    -0x4(%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L22:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%edx
  lea    (%rax,%rax,1),%esi
  test   $0x80,%ah
  mov    %edx,%eax
  cmove  %esi,%eax
  sub    $0x1,%ecx
  jne    L22
  jmp    L42
L41:
  ret
L1:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint16_t calcCRC16(void *buf, int len) {
  uint8_t i;
  uint16_t crc = 0;
  uint8_t *b = (uint8_t *)buf;
  if (!len)
    return -1;
  while (len--) {
    crc ^= (((uint16_t)*b++) << 8);
    for (i = 0; i < 8; ++i) {
      if (crc & 0x8000)
        crc = (crc << 1) ^ 0x1021;
      else
        crc <<= 1;
    }
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcCRC16>:
  endbr64
  test   %esi,%esi
  je     L2
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,4),%r8
L11:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%edx
L29:
  mov    %eax,%esi
  add    %eax,%eax
  mov    %eax,%ecx
  and    $0x8000,%esi
  xor    $0x1021,%ecx
  test   %esi,%esi
  cmovne %ecx,%eax
  sub    $0x1,%edx
  jne    L29
  cmp    %r8,%rdi
  jne    L11
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint16_t calcCRC16(void *buf, int len) {
  uint8_t i;
  uint16_t crc = 0;
  uint8_t *b = (uint8_t *)buf;
  if (!len)
    return -1;
  while (len--) {
    crc ^= (((uint16_t)*b++) << 8);
    for (i = 0; i < 8; ++i) {
      if (crc & 0x8000)
        crc = (crc << 1) ^ 0x1021;
      else
        crc <<= 1;
    }
  }
  return crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcCRC16>:
  endbr64
  test   %esi,%esi
  je     L20
  mov    %esi,%esi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,4),%rsi
  nopl   (%rax)
L18:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  shl    $0x8,%eax
  xor    %r8d,%eax
  lea    (%rax,%rax,1),%ecx
  mov    %ecx,%edx
  xor    $0x1021,%edx
  test   $0x80,%ah
  cmovne %edx,%ecx
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,%eax
  xor    $0x1021,%eax
  and    $0x80,%ch
  cmovne %eax,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%ecx
  xor    $0x1021,%ecx
  test   $0x80,%ah
  cmovne %ecx,%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %eax,%ecx
  xor    $0x1021,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  lea    (%rax,%rax,1),%r8d
  mov    %r8d,%edx
  xor    $0x1021,%edx
  test   $0x80,%ah
  cmovne %edx,%r8d
  cmp    %rdi,%rsi
  jne    L18
L0:
  mov    %r8d,%eax
  ret
L20:
  mov    $0xffffffff,%r8d
  jmp    L0
```

assistant: ```c
uint16_t calcCRC16(void *buf, int len) {
  uint8_t i;
  uint16_t crc = 0;
  uint8_t *b = (uint8_t *)buf;
  if (!len)
    return -1;
  while (len--) {
    crc ^= (((uint16_t)*b++) << 8);
    for (i = 0; i < 8; ++i) {
      if (crc & 0x8000)
        crc = (crc << 1) ^ 0x1021;
      else
        crc <<= 1;
    }
  }
  return crc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_crtc_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  mov    $0x3d4,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x3d5,%edi
  call   <inb@plt>
  leave
  ret
```

assistant: ```c
unsigned char read_crtc_b(unsigned short addr) {
  outb(addr, 0x3D4);
  return inb(0x3D5);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_crtc_b>:
  endbr64
  sub    $0x8,%rsp
  movzwl %di,%edi
  mov    $0x3d4,%esi
  call   <outb@plt>
  mov    $0x3d5,%edi
  call   <inb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char read_crtc_b(unsigned short addr) {
  outb(addr, 0x3D4);
  return inb(0x3D5);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_crtc_b>:
  endbr64
  sub    $0x8,%rsp
  movzwl %di,%edi
  mov    $0x3d4,%esi
  call   <outb@plt>
  mov    $0x3d5,%edi
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
unsigned char read_crtc_b(unsigned short addr) {
  outb(addr, 0x3D4);
  return inb(0x3D5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_crtc_b>:
  endbr64
  sub    $0x8,%rsp
  movzwl %di,%edi
  mov    $0x3d4,%esi
  call   <outb@plt>
  mov    $0x3d5,%edi
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
unsigned char read_crtc_b(unsigned short addr) {
  outb(addr, 0x3D4);
  return inb(0x3D5);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x40000000,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x80000000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x20,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x64,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x20,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x64,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20000000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x80000000,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x80000000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  x = 1073741824;
  int y;
  y = x << 1;
  assert(y == -2147483648);
  y = x << 32;
  assert(y == 0);
  y = x << 100;
  assert(y == 0);
  y = x >> 32;
  assert(y == 0);
  y = x >> 100;
  assert(y == 0);
  y = x >> 1;
  assert(y == 536870912);
  x = -2147483648;
  y = x >> 31;
  assert(y == -1);
  x = 1;
  y = x << 31;
  assert(y == -2147483648);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  x = 1073741824;
  int y;
  y = x << 1;
  assert(y == -2147483648);
  y = x << 32;
  assert(y == 0);
  y = x << 100;
  assert(y == 0);
  y = x >> 32;
  assert(y == 0);
  y = x >> 100;
  assert(y == 0);
  y = x >> 1;
  assert(y == 536870912);
  x = -2147483648;
  y = x >> 31;
  assert(y == -1);
  x = 1;
  y = x << 31;
  assert(y == -2147483648);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  x = 1073741824;
  int y;
  y = x << 1;
  assert(y == -2147483648);
  y = x << 32;
  assert(y == 0);
  y = x << 100;
  assert(y == 0);
  y = x >> 32;
  assert(y == 0);
  y = x >> 100;
  assert(y == 0);
  y = x >> 1;
  assert(y == 536870912);
  x = -2147483648;
  y = x >> 31;
  assert(y == -1);
  x = 1;
  y = x << 31;
  assert(y == -2147483648);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  x = 1073741824;
  int y;
  y = x << 1;
  assert(y == -2147483648);
  y = x << 32;
  assert(y == 0);
  y = x << 100;
  assert(y == 0);
  y = x >> 32;
  assert(y == 0);
  y = x >> 100;
  assert(y == 0);
  y = x >> 1;
  assert(y == 536870912);
  x = -2147483648;
  y = x >> 31;
  assert(y == -1);
  x = 1;
  y = x << 31;
  assert(y == -2147483648);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<search_first_hit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L105
  mov    $0x1,%eax
  jmp    L68
L105:
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L116:
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L81
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jb     L116
  jmp    L1
L81:
  nop
L1:
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L118:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L16
  mov    $0x1,%eax
  jmp    L68
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L101
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0xf,%eax
  cmp    %eax,-0xc(%rbp)
  jb     L118
  jmp    L113
L101:
  nop
L113:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L68:
  leave
  ret
```

assistant: ```c
int search_first_hit(char *search, char *line, char *ret) {
  unsigned int searchLen;
  unsigned int i;
  unsigned int j;
  unsigned int lineLen;
  lineLen = strlen(line);
  searchLen = strlen(search);
  if (searchLen > lineLen) {
    return (1);
  }
  for (i = 0; i < lineLen - searchLen + 1; i++) {
    if (!strncasecmp((char *)&line[i], search, searchLen)) {
      break;
    }
  }
  for (j = i + searchLen; j < i + 15 + searchLen; j++) {
    if (j > lineLen) {
      return (1);
    }
    if (line[j] == ' ') {
      break;
    }
  }
  memcpy(ret, &line[i + searchLen], j - i - searchLen);
  return (0);
}
```