ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  shr    $0x6,%rax
  and    $0xd4,%eax
  or     $0x889f,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
        } else {
          state[0UL] >>= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else if (state[0UL] & (unsigned short)1) {
        state[0UL] >>= (state[0UL] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy15;
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] <<= ((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 415518632UL) >> (unsigned short)7;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  shr    $0x6,%rax
  and    $0xd4,%eax
  or     $0x889f,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
        } else {
          state[0UL] >>= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else if (state[0UL] & (unsigned short)1) {
        state[0UL] >>= (state[0UL] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy15;
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] <<= ((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 415518632UL) >> (unsigned short)7;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  shl    $0x7,%eax
  shr    $0x6,%rax
  and    $0xd4,%eax
  or     $0x889f,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy15;
  {
    state[0UL] = (input[0UL] & 914778474UL) << (unsigned short)7;
    if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
        } else {
          state[0UL] >>= ((state[0UL] >> (unsigned short)3) & (unsigned short)7) | 1UL;
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else if (state[0UL] & (unsigned short)1) {
        state[0UL] >>= (state[0UL] & (unsigned short)7) | 1UL;
      } else {
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
        state[0UL] <<= ((state[0UL] >> (unsigned short)4) & (unsigned short)7) | 1UL;
      }
    } else if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
      copy15 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy15;
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] <<= ((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL;
    } else {
      state[0UL] <<= ((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL;
    }
    output[0UL] = (state[0UL] | 415518632UL) >> (unsigned short)7;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<m_lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L4
  cmpl   $0x5a,-0x4(%rbp)
  jg     L4
  addl   $0x20,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int m_lower(c)
int c;
{
  if (c >= 'A' && c <= 'Z')
    c += 'a' - 'A';
  return (c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<m_lower>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%ecx
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int m_lower(c)
int c;
{
  if (c >= 'A' && c <= 'Z')
    c += 'a' - 'A';
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_lower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int m_lower(c)
int c;
{
  if (c >= 'A' && c <= 'Z')
    c += 'a' - 'A';
  return (c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<m_lower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int m_lower(c)
int c;
{
  if (c >= 'A' && c <= 'Z')
    c += 'a' - 'A';
  return (c);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset_soc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L12:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset_soc(void *s, char c, int count) {
  char *xs = (char *)s;
  while (count--)
    *xs++ = c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memset_soc>:
  endbr64
  test   %edx,%edx
  je     L9
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rax
L2:
  add    $0x1,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L2
L9:
  ret
```

assistant: ```c
void memset_soc(void *s, char c, int count) {
  char *xs = (char *)s;
  while (count--)
    *xs++ = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset_soc>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L3
  mov    %eax,%edx
  movsbl %sil,%esi
  add    $0x1,%rdx
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void memset_soc(void *s, char c, int count) {
  char *xs = (char *)s;
  while (count--)
    *xs++ = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset_soc>:
  endbr64
  test   %edx,%edx
  je     L2
  sub    $0x1,%edx
  movsbl %sil,%esi
  add    $0x1,%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void memset_soc(void *s, char c, int count) {
  char *xs = (char *)s;
  while (count--)
    *xs++ = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wl_wep_decode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  add    $0xc,%rdi
  mov    $0x0,%eax
L82:
  xor    (%rdx),%al
  add    (%rdx),%al
  mov    %eax,%ebx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L82
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,2),%edx
  lea    0x3(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    $0x3,%edx
  jle    L71
  mov    %r12,%rsi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  jmp    L9
L26:
  movslq %edi,%r8
  movsbl 0x1(%rbp,%r8,1),%edx
  lea    0x68(,%rdx,4),%edx
  shr    $0x4,%dl
  movsbl 0x0(%rbp,%r8,1),%r8d
  sub    $0x26,%r8d
  shl    $0x4,%r8d
  add    %r8d,%edx
  mov    %dl,(%rsi)
L11:
  lea    (%rbx,%rcx,1),%edx
  xor    %dl,(%rsi)
  add    $0x1,%ecx
  add    $0x1,%edi
  add    $0x1,%rsi
  cmp    %ecx,%eax
  jle    L90
L9:
  movslq %ecx,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ecx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,2),%r8d
  mov    %ecx,%edx
  sub    %r8d,%edx
  cmp    $0x1,%edx
  je     L26
  cmp    $0x2,%edx
  je     L30
  test   %edx,%edx
  jne    L11
  movslq %edi,%r8
  movsbl 0x1(%rbp,%r8,1),%edx
  lea    0x68(,%rdx,4),%edx
  shr    $0x6,%dl
  movsbl 0x0(%rbp,%r8,1),%r8d
  lea    0x68(%rdx,%r8,4),%edx
  mov    %dl,(%rsi)
  jmp    L11
L30:
  movslq %edi,%r8
  movzbl 0x1(%rbp,%r8,1),%edx
  sub    $0x26,%edx
  and    $0x3f,%edx
  movsbl 0x0(%rbp,%r8,1),%r8d
  sub    $0x26,%r8d
  shl    $0x6,%r8d
  add    %r8d,%edx
  mov    %dl,(%rsi)
  add    $0x1,%edi
  jmp    L11
L90:
  test   %eax,%eax
  mov    $0x1,%edx
  cmovle %edx,%eax
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L71:
  mov    $0x0,%eax
  jmp    L55
```

assistant: ```c
int wl_wep_decode(char *szCrypt, void *Dest, char *szData) {
  int i;
  int t;
  int nLen;
  char bits;
  char *szDest = Dest;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  nLen = (strlen(szData) * 3) / 4;
  for (i = t = 0; i < nLen; i++, t++) {
    switch (i % 3) {
    case 0:
      szDest[i] = (((szData[t] - '&') & 0x3f) << 2) + (((szData[t + 1] - '&') & 0x30) >> 4);
      break;
    case 1:
      szDest[i] = (((szData[t] - '&') & 0x0f) << 4) + (((szData[t + 1] - '&') & 0x3c) >> 2);
      break;
    case 2:
      szDest[i] = (((szData[t] - '&') & 0x03) << 6) + ((szData[t + 1] - '&') & 0x3f);
      t++;
      break;
    }
    szDest[i] ^= (bits + i);
  }
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wl_wep_decode>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdx,%r12
  lea    0xc(%rdi),%rdx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L24:
  xor    (%rdi),%al
  add    $0x1,%rdi
  add    -0x1(%rdi),%al
  mov    %eax,%ebx
  cmp    %rdi,%rdx
  jne    L24
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%rax,%rax,2),%edx
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    $0x3,%edx
  jle    L4
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0xaaaaaaab,%edi
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%r9),%edx
  lea    0x68(,%rdx,4),%edx
  shr    $0x6,%dl
  lea    0x68(%rdx,%r8,4),%edx
L42:
  lea    (%rbx,%rcx,1),%r8d
  add    $0x1,%esi
  xor    %r8d,%edx
  mov    %dl,0x0(%rbp,%rcx,1)
  add    $0x1,%rcx
  cmp    %ecx,%eax
  jle    L41
L59:
  mov    %ecx,%edx
  movslq %esi,%r9
  imul   %rdi,%rdx
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%r8d
  mov    %ecx,%edx
  sub    %r8d,%edx
  movsbl (%r12,%r9,1),%r8d
  lea    0x1(%r12,%r9,1),%r9
  cmp    $0x1,%edx
  je     L27
  cmp    $0x2,%edx
  jne    L18
  movzbl (%r9),%edx
  sub    $0x26,%r8d
  add    $0x1,%esi
  shl    $0x6,%r8d
  sub    $0x26,%edx
  and    $0x3f,%edx
  add    %r8d,%edx
  jmp    L42
  nopl   (%rax)
L27:
  movsbl (%r9),%edx
  sub    $0x26,%r8d
  shl    $0x4,%r8d
  lea    0x68(,%rdx,4),%edx
  shr    $0x4,%dl
  add    %r8d,%edx
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L41:
  test   %eax,%eax
  mov    $0x1,%edx
  pop    %rbx
  pop    %rbp
  cmovle %edx,%eax
  pop    %r12
  ret
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wl_wep_decode(char *szCrypt, void *Dest, char *szData) {
  int i;
  int t;
  int nLen;
  char bits;
  char *szDest = Dest;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  nLen = (strlen(szData) * 3) / 4;
  for (i = t = 0; i < nLen; i++, t++) {
    switch (i % 3) {
    case 0:
      szDest[i] = (((szData[t] - '&') & 0x3f) << 2) + (((szData[t + 1] - '&') & 0x30) >> 4);
      break;
    case 1:
      szDest[i] = (((szData[t] - '&') & 0x0f) << 4) + (((szData[t + 1] - '&') & 0x3c) >> 2);
      break;
    case 2:
      szDest[i] = (((szData[t] - '&') & 0x03) << 6) + ((szData[t + 1] - '&') & 0x3f);
      t++;
      break;
    }
    szDest[i] ^= (bits + i);
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wl_wep_decode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl 0x1(%rdi),%r14d
  movzbl 0xa(%rbx),%edx
  movzbl 0x8(%rbx),%esi
  movzbl 0x9(%rbx),%ecx
  movzbl 0xb(%rbx),%eax
  movzbl (%rbx),%ebx
  movzbl 0x2(%rdi),%r13d
  movzbl 0x3(%rdi),%r11d
  movzbl 0x4(%rdi),%r10d
  add    %ebx,%ebx
  movzbl 0x5(%rdi),%r9d
  movzbl 0x6(%rdi),%r8d
  xor    %r14d,%ebx
  movzbl 0x7(%rdi),%edi
  add    %r14d,%ebx
  xor    %r13d,%ebx
  add    %r13d,%ebx
  xor    %r11d,%ebx
  add    %r11d,%ebx
  xor    %r10d,%ebx
  add    %r10d,%ebx
  xor    %r9d,%ebx
  add    %r9d,%ebx
  xor    %r8d,%ebx
  add    %r8d,%ebx
  xor    %edi,%ebx
  add    %edi,%ebx
  mov    %r12,%rdi
  xor    %esi,%ebx
  add    %esi,%ebx
  xor    %ecx,%ebx
  add    %ecx,%ebx
  xor    %edx,%ebx
  add    %edx,%ebx
  xor    %eax,%ebx
  add    %eax,%ebx
  call   <strlen@plt>
  lea    (%rax,%rax,2),%edx
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    $0x3,%edx
  jle    L36
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0xaaaaaaab,%edi
  jmp    L47
  xchg   %ax,%ax
L22:
  movsbl (%r9),%edx
  lea    0x68(,%rdx,4),%edx
  shr    $0x6,%dl
  lea    0x68(%rdx,%r8,4),%edx
L9:
  lea    (%rbx,%rcx,1),%r8d
  add    $0x1,%esi
  xor    %r8d,%edx
  mov    %dl,0x0(%rbp,%rcx,1)
  add    $0x1,%rcx
  cmp    %ecx,%eax
  jle    L18
L47:
  mov    %ecx,%edx
  movslq %esi,%r9
  imul   %rdi,%rdx
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%r8d
  mov    %ecx,%edx
  sub    %r8d,%edx
  movsbl (%r12,%r9,1),%r8d
  lea    0x1(%r12,%r9,1),%r9
  cmp    $0x1,%edx
  je     L68
  cmp    $0x2,%edx
  jne    L22
  movzbl (%r9),%edx
  sub    $0x26,%r8d
  add    $0x1,%esi
  shl    $0x6,%r8d
  sub    $0x26,%edx
  and    $0x3f,%edx
  add    %r8d,%edx
  jmp    L9
  nopl   (%rax)
L68:
  movsbl (%r9),%edx
  sub    $0x26,%r8d
  shl    $0x4,%r8d
  lea    0x68(,%rdx,4),%edx
  shr    $0x4,%dl
  add    %r8d,%edx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L18:
  test   %eax,%eax
  mov    $0x1,%edx
  pop    %rbx
  pop    %rbp
  cmovle %edx,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int wl_wep_decode(char *szCrypt, void *Dest, char *szData) {
  int i;
  int t;
  int nLen;
  char bits;
  char *szDest = Dest;
  for (i = bits = 0; i < 12; i++) {
    bits ^= szCrypt[i];
    bits += szCrypt[i];
  }
  nLen = (strlen(szData) * 3) / 4;
  for (i = t = 0; i < nLen; i++, t++) {
    switch (i % 3) {
    case 0:
      szDest[i] = (((szData[t] - '&') & 0x3f) << 2) + (((szData[t + 1] - '&') & 0x30) >> 4);
      break;
    case 1:
      szDest[i] = (((szData[t] - '&') & 0x0f) << 4) + (((szData[t + 1] - '&') & 0x3c) >> 2);
      break;
    case 2:
      szDest[i] = (((szData[t] - '&') & 0x03) << 6) + ((szData[t + 1] - '&') & 0x3f);
      t++;
      break;
    }
    szDest[i] ^= (bits + i);
  }
  return (i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L15
  movsd  -0x18(%rbp),%xmm0
  jmp    L7
L15:
  movsd  -0x8(%rbp),%xmm0
L7:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double abs(const double value) {
  double rvalue = -value;
  if (value > 0)
    return value;
  return rvalue;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x662061206d612049,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x676f72,-0xc(%rbp)
  movl   $0x676f7266,-0x1e(%rbp)
  movb   $0x0,-0x1a(%rbp)
  movl   $0x6b637564,-0x19(%rbp)
  movb   $0x0,-0x15(%rbp)
  lea    -0x1e(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x19(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main() {
  char s[] = "I am a frog";
  char t1[] = "frog";
  char t2[] = "duck";
  printf("%d\n", strend(s, t1));
  printf("%d\n", strend(s, t2));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x662061206d612049,%rax
  mov    %rax,0xc(%rsp)
  movl   $0x676f72,0x14(%rsp)
  movl   $0x676f7266,0x2(%rsp)
  movb   $0x0,0x6(%rsp)
  movl   $0x6b637564,0x7(%rsp)
  movb   $0x0,0xb(%rsp)
  lea    0x2(%rsp),%rsi
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strend@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strend@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  char s[] = "I am a frog";
  char t1[] = "frog";
  char t2[] = "duck";
  printf("%d\n", strend(s, t1));
  printf("%d\n", strend(s, t2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x662061206d612049,%rax
  lea    0xc(%rsp),%r12
  lea    0x2(%rsp),%rsi
  movl   $0x676f72,0x14(%rsp)
  mov    %r12,%rdi
  movl   $0x676f7266,0x2(%rsp)
  movb   $0x0,0x6(%rsp)
  movl   $0x6b637564,0x7(%rsp)
  movb   $0x0,0xb(%rsp)
  mov    %rax,0xc(%rsp)
  call   <strend@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  mov    %r12,%rdi
  call   <strend@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: %d


assistant: ```c
int main() {
  char s[] = "I am a frog";
  char t1[] = "frog";
  char t2[] = "duck";
  printf("%d\n", strend(s, t1));
  printf("%d\n", strend(s, t2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x662061206d612049,%rax
  lea    0xc(%rsp),%r12
  lea    0x2(%rsp),%rsi
  movl   $0x676f72,0x14(%rsp)
  mov    %r12,%rdi
  movl   $0x676f7266,0x2(%rsp)
  movb   $0x0,0x6(%rsp)
  movl   $0x6b637564,0x7(%rsp)
  movb   $0x0,0xb(%rsp)
  mov    %rax,0xc(%rsp)
  call   <strend@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  mov    %r12,%rdi
  call   <strend@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  char s[] = "I am a frog";
  char t1[] = "frog";
  char t2[] = "duck";
  printf("%d\n", strend(s, t1));
  printf("%d\n", strend(s, t2));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrop3_198_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_198_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```