user: What would the C source look like for the assembly code provided here?

```asm
<print_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L98
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L63
L72:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L92
  mov    $0x20,%edi
  call   <putchar@plt>
L92:
  mov    -0x8(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L63
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <print_asc@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <print_asc@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L63
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L63:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L72
  mov    -0x8(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  je     L23
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%edi
  call   <putchar@plt>
  cmpl   $0x8,-0x4(%rbp)
  jle    L89
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L89
L28:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L89:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L28
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  jle    L91
  movl   $0x8,-0x4(%rbp)
L91:
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <print_asc@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L127
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <print_asc@plt>
L127:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L23
L98:
  nop
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D34
datatype: string
name: read_data
arguments: data_tag: D37
datatype: string

tool: D5: [%03X] 

tool: D34: %02X 

tool: D37:    

assistant: ```c
void print_data(const char *buf, int len) {
  int i = 0;
  if (len <= 0)
    return;
  printf("[%03X] ", i);
  for (i = 0; i < len;) {
    printf("%02X ", (int)buf[i]);
    i++;
    if (i % 8 == 0)
      printf(" ");
    if (i % 16 == 0) {
      print_asc(&buf[i - 16], 8);
      printf(" ");
      print_asc(&buf[i - 8], 8);
      printf("\n");
      if (i < len)
        printf("[%03X] ", i);
    }
  }
  if (i % 16) {
    int n;
    n = 16 - (i % 16);
    printf(" ");
    if (n > 8)
      printf(" ");
    while (n--)
      printf("   ");
    n = i % 16;
    if (n > 8)
      n = 8;
    print_asc(&buf[i - (i % 16)], n);
    printf(" ");
    n = (i % 16) - n;
    if (n > 0)
      print_asc(&buf[i - n], n);
    printf("\n");
  }
}
```