ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_ok>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <log_end@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_ok() {
  log_end();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_ok>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <log_end@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void test_ok() {
  log_end();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_ok>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <log_end@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void test_ok() {
  log_end();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<guest_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x114(%rbp)
L1:
  mov    -0x124(%rbp),%eax
  mov    %eax,%edi
  call   <socket_accept@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0x0,-0x114(%rbp)
  jle    L10
  mov    -0x114(%rbp),%eax
  mov    %eax,%edi
  call   <user_enter@plt>
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D12(%rip),%r8
  mov    %edx,%ecx
  lea    D11(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <logging@plt>
L10:
  cmpl   $0xffffffff,-0x114(%rbp)
  jne    L1
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D12: entered.

tool: D11: <- socket[%d] %s

assistant: ```c
void guest_new(int fd_server) {
  int fd_guest = -1;
  do {
    fd_guest = socket_accept(fd_server);
    if (fd_guest > 0) {
      char str_buf[128 * 2];
      user_enter(fd_guest);
      snprintf(str_buf, 128 * 2, "<- socket[%d] %s", fd_guest, "entered.");
      logging(str_buf);
    }
  } while (fd_guest != -1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<guest_new>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%r13
  jmp    L7
L16:
  mov    %eax,%edi
  call   <user_enter@plt>
  mov    %rsp,%r12
  lea    D15(%rip),%r8
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <logging@plt>
L7:
  mov    %ebp,%edi
  call   <socket_accept@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L16
  cmp    $0xffffffff,%eax
  jne    L7
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D10: <- socket[%d] %s

tool: D15: entered.

assistant: ```c
void guest_new(int fd_server) {
  int fd_guest = -1;
  do {
    fd_guest = socket_accept(fd_server);
    if (fd_guest > 0) {
      char str_buf[128 * 2];
      user_enter(fd_guest);
      snprintf(str_buf, 128 * 2, "<- socket[%d] %s", fd_guest, "entered.");
      logging(str_buf);
    }
  } while (fd_guest != -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<guest_new>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  nopl   (%rax)
L9:
  mov    %ebx,%edi
  call   <socket_accept@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L26
  cmp    $0xffffffff,%eax
  jne    L9
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  mov    %rsp,%rbp
  mov    %eax,%edi
  call   <user_enter@plt>
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  lea    D2(%rip),%r8
  mov    $0x100,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <logging@plt>
  jmp    L9
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D3: <- socket[%d] %s

tool: D2: entered.

assistant: ```c
void guest_new(int fd_server) {
  int fd_guest = -1;
  do {
    fd_guest = socket_accept(fd_server);
    if (fd_guest > 0) {
      char str_buf[128 * 2];
      user_enter(fd_guest);
      snprintf(str_buf, 128 * 2, "<- socket[%d] %s", fd_guest, "entered.");
      logging(str_buf);
    }
  } while (fd_guest != -1);
}
```
user: What is the c source code of the assembly code below:

```asm
<guest_new>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  nopl   (%rax)
L33:
  mov    %ebx,%edi
  call   <socket_accept@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L32
  cmp    $0xffffffff,%eax
  jne    L33
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L32:
  mov    %rsp,%rbp
  mov    %eax,%edi
  call   <user_enter@plt>
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  lea    D16(%rip),%r8
  mov    $0x100,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <logging@plt>
  jmp    L33
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D16
data_type: string

tool: D18: <- socket[%d] %s

tool: D16: entered.

assistant: ```c
void guest_new(int fd_server) {
  int fd_guest = -1;
  do {
    fd_guest = socket_accept(fd_server);
    if (fd_guest > 0) {
      char str_buf[128 * 2];
      user_enter(fd_guest);
      snprintf(str_buf, 128 * 2, "<- socket[%d] %s", fd_guest, "entered.");
      logging(str_buf);
    }
  } while (fd_guest != -1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <process_command_line@plt>
  mov    $0x0,%eax
  call   <print_settings@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  process_command_line(argc, argv);
  print_settings();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <process_command_line@plt>
  mov    $0x0,%eax
  call   <print_settings@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  process_command_line(argc, argv);
  print_settings();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <process_command_line@plt>
  xor    %eax,%eax
  call   <print_settings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  process_command_line(argc, argv);
  print_settings();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <process_command_line@plt>
  xor    %eax,%eax
  call   <print_settings@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  process_command_line(argc, argv);
  print_settings();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  fldz
  fstpt  -0x60(%rbp)
  push   -0x58(%rbp)
  push   -0x60(%rbp)
  call   <foo@plt>
  add    $0x10,%rsp
  fstpt  -0x50(%rbp)
  fldpi
  fstpt  -0x40(%rbp)
  push   -0x38(%rbp)
  push   -0x40(%rbp)
  call   <foo@plt>
  add    $0x10,%rsp
  fstpt  -0x30(%rbp)
  fldt   0xea0(%rip)        # 2000 <_fini+0xe84>
  fstpt  -0x20(%rbp)
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  call   <foo@plt>
  add    $0x10,%rsp
  fstpt  -0x10(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long double const zero = 0.0L;
  long double const zero_copy = foo(zero);
  long double const positive = 3.14159265358979323846264338328L;
  long double const positive_copy = foo(positive);
  long double const negative = -3.14159265358979323846264338328L;
  long double const negative_copy = foo(negative);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  call   <foo@plt>
  fstp   %st(0)
  push   $0x4000
  push   $0x2168c235
  movl   $0xc90fdaa2,0x4(%rsp)
  call   <foo@plt>
  fstp   %st(0)
  add    $0x20,%rsp
  push   $0xc000
  push   $0x2168c235
  movl   $0xc90fdaa2,0x4(%rsp)
  call   <foo@plt>
  fstp   %st(0)
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long double const zero = 0.0L;
  long double const zero_copy = foo(zero);
  long double const positive = 3.14159265358979323846264338328L;
  long double const positive_copy = foo(positive);
  long double const negative = -3.14159265358979323846264338328L;
  long double const negative_copy = foo(negative);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  call   <foo@plt>
  fstp   %st(0)
  push   $0x4000
  movabs $0xc90fdaa22168c235,%rax
  push   %rax
  call   <foo@plt>
  fstp   %st(0)
  add    $0x20,%rsp
  movabs $0xc90fdaa22168c235,%rdx
  push   $0xc000
  push   %rdx
  call   <foo@plt>
  fstp   %st(0)
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long double const zero = 0.0L;
  long double const zero_copy = foo(zero);
  long double const positive = 3.14159265358979323846264338328L;
  long double const positive_copy = foo(positive);
  long double const negative = -3.14159265358979323846264338328L;
  long double const negative_copy = foo(negative);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  call   <foo@plt>
  fstp   %st(0)
  push   $0x4000
  movabs $0xc90fdaa22168c235,%rax
  push   %rax
  call   <foo@plt>
  fstp   %st(0)
  add    $0x20,%rsp
  movabs $0xc90fdaa22168c235,%rdx
  push   $0xc000
  push   %rdx
  call   <foo@plt>
  fstp   %st(0)
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long double const zero = 0.0L;
  long double const zero_copy = foo(zero);
  long double const positive = 3.14159265358979323846264338328L;
  long double const positive_copy = foo(positive);
  long double const negative = -3.14159265358979323846264338328L;
  long double const negative_copy = foo(negative);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L30
  mov    $0x1,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L30:
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L7:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x0,-0x14(%rbp)
  jle    L7
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x79,%al
  jne    L42
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L42:
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L56:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L13:
  cmpl   $0x0,-0x10(%rbp)
  jle    L56
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D23
data_type: string

tool: D25: Call this program with %i arguments


tool: D9: You win!

tool: D23: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 121) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L36
L7:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %al,0x6(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpb   $0x79,0x7(%rsp)
  je     L42
L46:
  movzbl 0x7(%rsp),%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L7
L42:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L46
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string

tool: D21: %u


tool: D18: Call this program with %i arguments


tool: D17: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 121) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L15
  lea    D9(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L15:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x79,%sil
  je     L22
L13:
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D25
data_type: string

tool: D9: Call this program with %i arguments


tool: D24: %u


tool: D25: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 121) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L1
  lea    D21(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L1:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x79,%sil
  je     L4
L16:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L16
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D21: Call this program with %i arguments


tool: D5: %u


tool: D0: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 121) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L13
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L10
L13:
  nop
L10:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 2;
  switch (x) {
  default:
    assert(0);
    break;
  case 2:
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x = 2;
  switch (x) {
  default:
    assert(0);
    break;
  case 2:
    break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 2;
  switch (x) {
  default:
    assert(0);
    break;
  case 2:
    break;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x = 2;
  switch (x) {
  default:
    assert(0);
    break;
  case 2:
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ands_si_test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  jmp    L14
L7:
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ands_si_test3(int a, int b, int c) {
  int d = a & (b << 3);
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: What is the c source code of the assembly code below?

```asm
<ands_si_test3>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  and    %edi,%ecx
  add    %edx,%edi
  lea    (%rsi,%rcx,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int ands_si_test3(int a, int b, int c) {
  int d = a & (b << 3);
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ands_si_test3>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  and    %edi,%ecx
  add    %edx,%edi
  lea    (%rsi,%rcx,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int ands_si_test3(int a, int b, int c) {
  int d = a & (b << 3);
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ands_si_test3>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  and    %edi,%ecx
  add    %edx,%edi
  lea    (%rsi,%rcx,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int ands_si_test3(int a, int b, int c) {
  int d = a & (b << 3);
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<purge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L10
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L4
L10:
  nop
  leave
  ret
```

assistant: ```c
void purge(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    ;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<purge>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L6
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L9
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void purge(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    ;
  }
}
```