ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_valid_pattern>:
  endbr64
  movl   $0x0,(%rsi)
L165:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L97
L182:
  movzbl 0x1(%rdi),%eax
  cmp    $0x5b,%dl
  je     L162
  cmp    $0x5c,%dl
  jne    L144
  test   %al,%al
  je     L178
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L182
L97:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L162:
  add    $0x1,%rdi
  cmp    $0x5d,%al
  je     L168
  test   %al,%al
  jne    L116
  jmp    L180
  nopw   0x0(%rax,%rax,1)
L104:
  add    $0x1,%rdi
L84:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L180
  cmp    $0x2d,%al
  je     L163
L116:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5d,%al
  je     L139
  cmp    $0x5c,%al
  jne    L104
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L84
L178:
  movl   $0xffffffff,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L144:
  add    $0x1,%rdi
  jmp    L165
  cs nopw 0x0(%rax,%rax,1)
L180:
  movl   $0xfffffffd,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L139:
  mov    $0x5d,%edx
  jmp    L182
  nopw   0x0(%rax,%rax,1)
L163:
  movzbl 0x1(%rdi),%eax
  cmp    $0x5d,%al
  je     L43
  test   %al,%al
  je     L43
  cmp    $0x5c,%al
  je     L49
  lea    0x1(%rdi),%rax
  add    $0x2,%rdi
L164:
  movzbl 0x1(%rax),%eax
  jmp    L116
L49:
  movzbl 0x2(%rdi),%edx
  lea    0x2(%rdi),%rax
  add    $0x3,%rdi
  test   %dl,%dl
  jne    L164
  jmp    L178
L168:
  movl   $0xfffffffc,(%rsi)
  xor    %eax,%eax
  ret
L43:
  movl   $0xfffffffe,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid_pattern(char *p, int *error_type) {
  *error_type = 0;
  while (*p) {
    switch (*p) {
    case '\\':
      if (!*++p) {
        *error_type = -1;
        return 0;
      }
      p++;
      break;
    case '[':
      p++;
      if (*p == ']') {
        *error_type = -4;
        return 0;
      }
      if (!*p) {
        *error_type = -3;
        return 0;
      }
      while (*p != ']') {
        if (*p == '\\') {
          p++;
          if (!*p++) {
            *error_type = -1;
            return 0;
          }
        } else
          p++;
        if (!*p) {
          *error_type = -3;
          return 0;
        }
        if (*p == '-') {
          if (!*++p || *p == ']') {
            *error_type = -2;
            return 0;
          } else {
            if (*p == '\\')
              p++;
            if (!*p++) {
              *error_type = -1;
              return 0;
            }
          }
        }
      }
      break;
    case '*':
    case '?':
    default:
      p++;
      break;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_valid_pattern>:
  endbr64
  movl   $0x0,(%rsi)
L52:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L177
L57:
  movzbl 0x1(%rdi),%eax
  cmp    $0x5b,%dl
  je     L121
  cmp    $0x5c,%dl
  jne    L35
  test   %al,%al
  je     L104
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L57
L177:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L121:
  add    $0x1,%rdi
  cmp    $0x5d,%al
  je     L180
  test   %al,%al
  jne    L89
  jmp    L154
  nopw   0x0(%rax,%rax,1)
L208:
  add    $0x1,%rdi
L47:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L154
  cmp    $0x2d,%al
  je     L100
L89:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5d,%al
  je     L162
  cmp    $0x5c,%al
  jne    L208
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L47
L104:
  movl   $0xffffffff,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L35:
  add    $0x1,%rdi
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L154:
  movl   $0xfffffffd,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L162:
  mov    $0x5d,%edx
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L100:
  movzbl 0x1(%rdi),%eax
  cmp    $0x5d,%al
  je     L110
  test   %al,%al
  je     L110
  cmp    $0x5c,%al
  je     L43
  lea    0x1(%rdi),%rax
  add    $0x2,%rdi
L36:
  movzbl 0x1(%rax),%eax
  jmp    L89
L43:
  movzbl 0x2(%rdi),%edx
  lea    0x2(%rdi),%rax
  add    $0x3,%rdi
  test   %dl,%dl
  jne    L36
  jmp    L104
L180:
  movl   $0xfffffffc,(%rsi)
  xor    %eax,%eax
  ret
L110:
  movl   $0xfffffffe,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_valid_pattern(char *p, int *error_type) {
  *error_type = 0;
  while (*p) {
    switch (*p) {
    case '\\':
      if (!*++p) {
        *error_type = -1;
        return 0;
      }
      p++;
      break;
    case '[':
      p++;
      if (*p == ']') {
        *error_type = -4;
        return 0;
      }
      if (!*p) {
        *error_type = -3;
        return 0;
      }
      while (*p != ']') {
        if (*p == '\\') {
          p++;
          if (!*p++) {
            *error_type = -1;
            return 0;
          }
        } else
          p++;
        if (!*p) {
          *error_type = -3;
          return 0;
        }
        if (*p == '-') {
          if (!*++p || *p == ']') {
            *error_type = -2;
            return 0;
          } else {
            if (*p == '\\')
              p++;
            if (!*p++) {
              *error_type = -1;
              return 0;
            }
          }
        }
      }
      break;
    case '*':
    case '?':
    default:
      p++;
      break;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dstrcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L83
L8:
  mov    $0x0,%ebx
L83:
  cmpq   $0x0,-0x30(%rbp)
  je     L65
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L33
L65:
  mov    $0x0,%eax
L33:
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L61
  mov    -0x28(%rbp),%rax
  jmp    L79
L61:
  lea    D19(%rip),%rax
L79:
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L16
  mov    -0x30(%rbp),%rax
  jmp    L82
L16:
  lea    D19(%rip),%rax
L82:
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcat@plt>
  cmpq   $0x0,-0x28(%rbp)
  je     L92
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L92:
  cmpq   $0x0,-0x30(%rbp)
  je     L52
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L52:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: 

assistant: ```c
char *dstrcat(char *a, char *b) {
  char *r = (char *)malloc((a ? strlen(a) : 0) + (b ? strlen(b) : 0) + 1);
  strcpy(r, a ? a : "");
  strcat(r, b ? b : "");
  if (a)
    free(a);
  if (b)
    free(b);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dstrcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  test   %rdi,%rdi
  je     L25
  call   <strlen@plt>
  mov    %eax,%r12d
L25:
  mov    $0x0,%eax
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rdi
  call   <strlen@plt>
L16:
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L49
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L77
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  test   %rbx,%rbx
  je     L4
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L4
L77:
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  test   %rbx,%rbx
  je     L9
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L9
L49:
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L77
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L4:
  mov    %rbp,%rdi
  call   <free@plt>
L9:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: 

assistant: ```c
char *dstrcat(char *a, char *b) {
  char *r = (char *)malloc((a ? strlen(a) : 0) + (b ? strlen(b) : 0) + 1);
  strcpy(r, a ? a : "");
  strcat(r, b ? b : "");
  if (a)
    free(a);
  if (b)
    free(b);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dstrcat>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L15
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %r13,%r13
  jne    L1
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D12(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L12:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  test   %rsi,%rsi
  je     L7
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    D12(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L12
  nopl   0x0(%rax)
L7:
  mov    $0x1,%edi
  lea    D12(%rip),%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string

tool: 

assistant: ```c
char *dstrcat(char *a, char *b) {
  char *r = (char *)malloc((a ? strlen(a) : 0) + (b ? strlen(b) : 0) + 1);
  strcpy(r, a ? a : "");
  strcat(r, b ? b : "");
  if (a)
    free(a);
  if (b)
    free(b);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dstrcat>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L30
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %r13,%r13
  jne    L32
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D10(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  test   %rsi,%rsi
  je     L11
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  lea    D10(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L3
  nopl   0x0(%rax)
L11:
  mov    $0x1,%edi
  lea    D10(%rip),%rbp
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string

tool: 

assistant: ```c
char *dstrcat(char *a, char *b) {
  char *r = (char *)malloc((a ? strlen(a) : 0) + (b ? strlen(b) : 0) + 1);
  strcpy(r, a ? a : "");
  strcat(r, b ? b : "");
  if (a)
    free(a);
  if (b)
    free(b);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pos_to_col>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %esi,-0x408(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rdx
  mov    -0x404(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <b_gets@plt>
  movl   $0x1,-0x3f8(%rbp)
  movl   $0x0,-0x3f4(%rbp)
  jmp    L27
L46:
  mov    -0x3f4(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0x9,%al
  jne    L23
  jmp    L45
L37:
  addl   $0x1,-0x3f8(%rbp)
L45:
  mov    -0x3f8(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L37
L23:
  addl   $0x1,-0x3f8(%rbp)
  addl   $0x1,-0x3f4(%rbp)
L27:
  mov    -0x3f4(%rbp),%eax
  cmp    -0x408(%rbp),%eax
  jge    L15
  mov    -0x3f4(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L46
L15:
  mov    -0x3f8(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int pos_to_col(int line, int pos) {
  int c, p;
  char text[1000 - 1];
  b_gets(line, text);
  for (c = 1, p = 0; p < pos && text[p] != '\0'; ++c, ++p)
    if (text[p] == '\t')
      while (c % 8 != 0)
        ++c;
  return (c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pos_to_col>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <b_gets@plt>
  test   %ebx,%ebx
  jle    L85
  mov    %rsp,%rdx
  lea    -0x1(%rbx),%eax
  lea    0x1(%rsp,%rax,1),%rsi
  mov    $0x1,%eax
  jmp    L8
L21:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L53
L8:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L53
  cmp    $0x9,%cl
  jne    L21
  test   $0x7,%al
  je     L21
L50:
  add    $0x1,%eax
  test   $0x7,%al
  jne    L50
  jmp    L21
L85:
  mov    $0x1,%eax
L53:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L76
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pos_to_col(int line, int pos) {
  int c, p;
  char text[1000 - 1];
  b_gets(line, text);
  for (c = 1, p = 0; p < pos && text[p] != '\0'; ++c, ++p)
    if (text[p] == '\t')
      while (c % 8 != 0)
        ++c;
  return (c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pos_to_col>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <b_gets@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdx
  lea    0x1(%rsp,%rax,1),%rsi
  mov    $0x1,%eax
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rdx
  add    $0x1,%eax
  cmp    %rsi,%rdx
  je     L85
  nopl   0x0(%rax)
L58:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L85
  cmp    $0x9,%cl
  je     L63
  add    $0x1,%rdx
  add    $0x1,%eax
  cmp    %rsi,%rdx
  jne    L58
L85:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  add    $0x1,%eax
L63:
  test   $0x7,%al
  jne    L2
  jmp    L29
L0:
  mov    $0x1,%eax
  jmp    L85
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pos_to_col(int line, int pos) {
  int c, p;
  char text[1000 - 1];
  b_gets(line, text);
  for (c = 1, p = 0; p < pos && text[p] != '\0'; ++c, ++p)
    if (text[p] == '\t')
      while (c % 8 != 0)
        ++c;
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pos_to_col>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <b_gets@plt>
  test   %ebp,%ebp
  jle    L33
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdx
  lea    0x1(%rsp,%rax,1),%rsi
  mov    $0x1,%eax
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rdx
  add    $0x1,%eax
  cmp    %rsi,%rdx
  je     L7
  nopl   0x0(%rax)
L43:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L7
  cmp    $0x9,%cl
  je     L53
  add    $0x1,%rdx
  add    $0x1,%eax
  cmp    %rsi,%rdx
  jne    L43
L7:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L49:
  add    $0x1,%eax
L53:
  test   $0x7,%al
  jne    L49
  jmp    L34
L33:
  mov    $0x1,%eax
  jmp    L7
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pos_to_col(int line, int pos) {
  int c, p;
  char text[1000 - 1];
  b_gets(line, text);
  for (c = 1, p = 0; p < pos && text[p] != '\0'; ++c, ++p)
    if (text[p] == '\t')
      while (c % 8 != 0)
        ++c;
  return (c);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_username>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
char *get_username() {
  struct passwd *p = getpwuid(getuid());
  return p->pw_name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_username>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_username() {
  struct passwd *p = getpwuid(getuid());
  return p->pw_name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_username>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_username() {
  struct passwd *p = getpwuid(getuid());
  return p->pw_name;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_username>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *get_username() {
  struct passwd *p = getpwuid(getuid());
  return p->pw_name;
}
```
user: What is the c source code of the assembly code below?

```asm
<cpytill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  jmp    L40
L6:
  movzbl (%rax),%esi
  cmp    $0x5c,%sil
  jne    L36
  lea    0x1(%rax),%rsi
  movzbl (%rsi),%esi
  movsbl %sil,%esi
  cmp    %esi,%edx
  jne    L36
  add    $0x1,%rax
  jmp    L41
L36:
  movzbl (%rax),%esi
  movsbl %sil,%esi
  cmp    %esi,%edx
  je     L0
L41:
  movzbl (%rax),%esi
  mov    %sil,(%rcx)
  add    $0x1,%rax
  add    $0x1,%rcx
L40:
  movzbl (%rax),%esi
  test   %sil,%sil
  jne    L6
  jmp    L62
L0:
  nop
L62:
  movb   $0x0,(%rcx)
  pop    %rbp
  ret
```

assistant: ```c
char *cpytill(to, from, delim)
register char *to, *from;
register int delim;
{
  for (; *from; from++, to++) {
    if (*from == '\\' && from[1] == delim)
      from++;
    else if (*from == delim)
      break;
    *to = *from;
  }
  *to = '\0';
  return from;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpytill>:
  endbr64
  mov    %rsi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  jne    L51
L16:
  movb   $0x0,(%rdi)
  ret
L11:
  movsbl %cl,%ecx
  cmp    %edx,%ecx
  je     L16
  mov    %rax,%rcx
L34:
  movzbl (%rcx),%eax
  mov    %al,(%rdi)
  lea    0x1(%rcx),%rax
  add    $0x1,%rdi
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L16
L51:
  cmp    $0x5c,%cl
  jne    L11
  movsbl 0x1(%rax),%esi
  cmp    %edx,%esi
  jne    L11
  lea    0x1(%rax),%rcx
  jmp    L34
```

assistant: ```c
char *cpytill(to, from, delim)
register char *to, *from;
register int delim;
{
  for (; *from; from++, to++) {
    if (*from == '\\' && from[1] == delim)
      from++;
    else if (*from == delim)
      break;
    *to = *from;
  }
  *to = '\0';
  return from;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cpytill>:
  endbr64
  movsbl (%rsi),%ecx
  mov    %rsi,%rax
  test   %cl,%cl
  jne    L29
  jmp    L22
L12:
  cmp    %edx,%ecx
  je     L22
  movzbl (%rax),%esi
  mov    %rax,%rcx
L52:
  mov    %sil,(%rdi)
  lea    0x1(%rcx),%rax
  movsbl 0x1(%rcx),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  je     L22
L29:
  cmp    $0x5c,%cl
  jne    L12
  movsbl 0x1(%rax),%r8d
  mov    %r8d,%esi
  cmp    %edx,%r8d
  jne    L12
  lea    0x1(%rax),%rcx
  jmp    L52
  nopl   (%rax)
L22:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
char *cpytill(to, from, delim)
register char *to, *from;
register int delim;
{
  for (; *from; from++, to++) {
    if (*from == '\\' && from[1] == delim)
      from++;
    else if (*from == delim)
      break;
    *to = *from;
  }
  *to = '\0';
  return from;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpytill>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rsi,%rax
  test   %cl,%cl
  jne    L16
  jmp    L43
L0:
  movsbl %cl,%esi
  cmp    %edx,%esi
  je     L43
  mov    %rax,%r8
L6:
  mov    %cl,(%rdi)
  movzbl 0x1(%r8),%ecx
  lea    0x1(%r8),%rax
  add    $0x1,%rdi
  test   %cl,%cl
  je     L43
L16:
  cmp    $0x5c,%cl
  jne    L0
  movsbl 0x1(%rax),%r8d
  mov    %r8d,%esi
  cmp    %edx,%r8d
  jne    L0
  lea    0x1(%rax),%r8
  mov    %esi,%ecx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L43:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
char *cpytill(to, from, delim)
register char *to, *from;
register int delim;
{
  for (; *from; from++, to++) {
    if (*from == '\\' && from[1] == delim)
      from++;
    else if (*from == delim)
      break;
    *to = *from;
  }
  *to = '\0';
  return from;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```