ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strcpy3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L5:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcpy3(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy3>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L2
  mov    $0x1,%eax
L16:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L16
L2:
  ret
```

assistant: ```c
void strcpy3(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy3>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L7
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L0
L7:
  ret
```

assistant: ```c
void strcpy3(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcpy3>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  test   %al,%al
  je     L17
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L12
L17:
  ret
```

assistant: ```c
void strcpy3(char *s, char *t) {
  int i;
  i = 0;
  while ((s[i] = t[i]) != '\0')
    i++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<taylor_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  movsd  D83(%rip),%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L64
  movsd  D83(%rip),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   D37(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L17
L56:
  movsd  D83(%rip),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <exponent@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  divsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D83(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L17:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L72
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L36
L72:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L36:
  comisd -0x10(%rbp),%xmm0
  ja     L56
  jmp    L51
L64:
  movsd  -0x28(%rbp),%xmm0
  movsd  D83(%rip),%xmm1
  subsd  %xmm1,%xmm0
  divsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D33(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L67
L0:
  movsd  -0x28(%rbp),%xmm0
  movsd  D83(%rip),%xmm1
  subsd  %xmm1,%xmm0
  divsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <exponent@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D83(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L67:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L69
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L6
L69:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L6:
  comisd -0x8(%rbp),%xmm0
  ja     L0
L51:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D83
datatype: byte[8]
name: read_data
arguments: data_tag: D37
datatype: byte[8]
name: read_data
arguments: data_tag: D33
datatype: f64

tool: {"D83": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D33: 2

assistant: ```c
double taylor_log(double x, unsigned int n) {
  double result;
  if (x < 1) {
    result = -(1 - x);
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result - exponent(1 - x, i) / i;
  } else {
    result = (x - 1) / x;
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result + exponent((x - 1) / x, i) / i;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<taylor_log>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movsd  D52(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L39
  movapd %xmm0,%xmm1
  subsd  D52(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  add    $0x1,%edi
  mov    %edi,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%r14
  cmp    $0x2,%edi
  jbe    L13
  mov    %rbx,(%rsp)
  movsd  D59(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
L8:
  movsd  0x8(%rsp),%xmm1
  movq   %rbx,%xmm0
  call   <exponent@plt>
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm2,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  movsd  D52(%rip),%xmm3
  addsd  %xmm2,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movq   %r14,%xmm7
  comisd %xmm3,%xmm7
  ja     L8
L52:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L39:
  subsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  movapd %xmm1,%xmm6
  xorpd  D56(%rip),%xmm6
  movsd  %xmm6,(%rsp)
  add    $0x1,%edi
  mov    %edi,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%r14
  cmp    $0x2,%edi
  jbe    L52
  movsd  D59(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
L9:
  movsd  0x8(%rsp),%xmm1
  movq   %rbx,%xmm0
  call   <exponent@plt>
  movsd  0x8(%rsp),%xmm4
  divsd  %xmm4,%xmm0
  movsd  (%rsp),%xmm6
  subsd  %xmm0,%xmm6
  movsd  %xmm6,(%rsp)
  movsd  D52(%rip),%xmm5
  addsd  %xmm4,%xmm5
  movsd  %xmm5,0x8(%rsp)
  movq   %r14,%xmm6
  comisd %xmm5,%xmm6
  ja     L9
  jmp    L52
L13:
  mov    %rbx,(%rsp)
  jmp    L52
```

tool_calls: name: parse_data
arguments: data_label: D52
type_guessed: byte[8]
name: parse_data
arguments: data_label: D59
type_guessed: f64
name: parse_data
arguments: data_label: D56
type_guessed: byte[16]

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D59: 2

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double taylor_log(double x, unsigned int n) {
  double result;
  if (x < 1) {
    result = -(1 - x);
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result - exponent(1 - x, i) / i;
  } else {
    result = (x - 1) / x;
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result + exponent((x - 1) / x, i) / i;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<taylor_log>:
  endbr64
  push   %r14
  lea    0x1(%rdi),%eax
  pxor   %xmm6,%xmm6
  push   %rbx
  cvtsi2sd %rax,%xmm6
  sub    $0x18,%rsp
  movsd  D27(%rip),%xmm7
  movq   %xmm6,%rbx
  comisd %xmm0,%xmm7
  ja     L26
  movapd %xmm0,%xmm1
  subsd  D27(%rip),%xmm1
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movq   %xmm2,%r14
  cmp    $0x2,%eax
  jbe    L45
  movsd  D33(%rip),%xmm1
L9:
  movq   %r14,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <exponent@plt>
  movsd  (%rsp),%xmm1
  movq   %rbx,%xmm3
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm0
  addsd  D27(%rip),%xmm1
  comisd %xmm1,%xmm3
  addsd  %xmm0,%xmm2
  ja     L9
L45:
  add    $0x18,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movapd %xmm7,%xmm5
  subsd  %xmm0,%xmm5
  movapd %xmm5,%xmm2
  movq   %xmm5,%r14
  xorpd  D19(%rip),%xmm2
  cmp    $0x2,%eax
  jbe    L45
  movsd  D33(%rip),%xmm1
  cs nopw 0x0(%rax,%rax,1)
L44:
  movq   %r14,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <exponent@plt>
  movsd  (%rsp),%xmm1
  movq   %rbx,%xmm4
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm0
  addsd  D27(%rip),%xmm1
  comisd %xmm1,%xmm4
  subsd  %xmm0,%xmm2
  ja     L44
  add    $0x18,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D33
type_infered: f64
name: extract_symbolic_data
arguments: tag: D19
type_infered: byte[16]

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D33: 2

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double taylor_log(double x, unsigned int n) {
  double result;
  if (x < 1) {
    result = -(1 - x);
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result - exponent(1 - x, i) / i;
  } else {
    result = (x - 1) / x;
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result + exponent((x - 1) / x, i) / i;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<taylor_log>:
  endbr64
  push   %r14
  lea    0x1(%rdi),%eax
  pxor   %xmm6,%xmm6
  push   %rbx
  cvtsi2sd %rax,%xmm6
  sub    $0x18,%rsp
  movsd  D65(%rip),%xmm7
  movq   %xmm6,%rbx
  comisd %xmm0,%xmm7
  ja     L17
  movapd %xmm0,%xmm1
  subsd  D65(%rip),%xmm1
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movq   %xmm2,%r14
  cmp    $0x2,%eax
  jbe    L24
  movsd  D25(%rip),%xmm1
L0:
  movq   %r14,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <exponent@plt>
  movsd  (%rsp),%xmm1
  movq   %rbx,%xmm3
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm0
  addsd  D65(%rip),%xmm1
  comisd %xmm1,%xmm3
  addsd  %xmm0,%xmm2
  ja     L0
L24:
  add    $0x18,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movapd %xmm7,%xmm5
  subsd  %xmm0,%xmm5
  movapd %xmm5,%xmm2
  movq   %xmm5,%r14
  xorpd  D16(%rip),%xmm2
  cmp    $0x2,%eax
  jbe    L24
  movsd  D25(%rip),%xmm1
  cs nopw 0x0(%rax,%rax,1)
L3:
  movq   %r14,%xmm0
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <exponent@plt>
  movsd  (%rsp),%xmm1
  movq   %rbx,%xmm4
  movsd  0x8(%rsp),%xmm2
  divsd  %xmm1,%xmm0
  addsd  D65(%rip),%xmm1
  comisd %xmm1,%xmm4
  subsd  %xmm0,%xmm2
  ja     L3
  add    $0x18,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D65
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D25
type_guessed: f64
name: parse_data
arguments: data_tag: D16
type_guessed: byte[16]

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D25: 2

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double taylor_log(double x, unsigned int n) {
  double result;
  if (x < 1) {
    result = -(1 - x);
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result - exponent(1 - x, i) / i;
  } else {
    result = (x - 1) / x;
    for (double i = 2.0; i < n + 2 - 1; ++i)
      result = result + exponent((x - 1) / x, i) / i;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<passes_sa_constraints_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L17
L49:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L34
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L34
  mov    $0x0,%eax
  jmp    L23
L34:
  subl   $0x1,-0x14(%rbp)
L17:
  cmpl   $0x0,-0x14(%rbp)
  jns    L49
  mov    $0x1,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int passes_sa_constraints_full(int **walk_points, int curr_num_pts) {
  int *p1 = walk_points[curr_num_pts - 1];
  int i;
  for (i = curr_num_pts - 2; i >= 0; i--) {
    int *p2 = walk_points[i];
    if ((p1[0] == p2[0]) && (p1[1] == p2[1]))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<passes_sa_constraints_full>:
  endbr64
  mov    %esi,%eax
  movslq %esi,%rdx
  mov    -0x8(%rdi,%rdx,8),%rsi
  sub    $0x2,%eax
  js     L35
  mov    (%rsi),%ecx
  cltq
  jmp    L29
L21:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L10
L29:
  mov    (%rdi,%rax,8),%rdx
  cmp    (%rdx),%ecx
  jne    L21
  mov    0x4(%rdx),%edx
  cmp    %edx,0x4(%rsi)
  jne    L21
  mov    $0x0,%eax
  ret
L10:
  mov    $0x1,%eax
  ret
L35:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int passes_sa_constraints_full(int **walk_points, int curr_num_pts) {
  int *p1 = walk_points[curr_num_pts - 1];
  int i;
  for (i = curr_num_pts - 2; i >= 0; i--) {
    int *p2 = walk_points[i];
    if ((p1[0] == p2[0]) && (p1[1] == p2[1]))
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<passes_sa_constraints_full>:
  endbr64
  movslq %esi,%rdx
  mov    %rdx,%rax
  mov    -0x8(%rdi,%rdx,8),%rsi
  sub    $0x2,%eax
  js     L47
  mov    (%rsi),%ecx
  cltq
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L47
L44:
  mov    (%rdi,%rax,8),%rdx
  cmp    (%rdx),%ecx
  jne    L10
  mov    0x4(%rdx),%edx
  cmp    %edx,0x4(%rsi)
  jne    L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int passes_sa_constraints_full(int **walk_points, int curr_num_pts) {
  int *p1 = walk_points[curr_num_pts - 1];
  int i;
  for (i = curr_num_pts - 2; i >= 0; i--) {
    int *p2 = walk_points[i];
    if ((p1[0] == p2[0]) && (p1[1] == p2[1]))
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<passes_sa_constraints_full>:
  endbr64
  movslq %esi,%rdx
  mov    %rdx,%rax
  mov    -0x8(%rdi,%rdx,8),%rsi
  sub    $0x2,%eax
  js     L29
  mov    (%rsi),%ecx
  cltq
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L29
L47:
  mov    (%rdi,%rax,8),%rdx
  cmp    (%rdx),%ecx
  jne    L2
  mov    0x4(%rdx),%edx
  cmp    %edx,0x4(%rsi)
  jne    L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int passes_sa_constraints_full(int **walk_points, int curr_num_pts) {
  int *p1 = walk_points[curr_num_pts - 1];
  int i;
  for (i = curr_num_pts - 2; i >= 0; i--) {
    int *p2 = walk_points[i];
    if ((p1[0] == p2[0]) && (p1[1] == p2[1]))
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0xb133,%edi
  call   <contAlgarismo@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: O soma dos algarismos de 45363 eh: %d

assistant: ```c
main() {
  printf("O soma dos algarismos de 45363 eh: %d", contAlgarismo(45363, 0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0xb133,%edi
  call   <contAlgarismo@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: O soma dos algarismos de 45363 eh: %d

assistant: ```c
main() {
  printf("O soma dos algarismos de 45363 eh: %d", contAlgarismo(45363, 0));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xb133,%edi
  call   <contAlgarismo@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: O soma dos algarismos de 45363 eh: %d

assistant: ```c
main() {
  printf("O soma dos algarismos de 45363 eh: %d", contAlgarismo(45363, 0));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xb133,%edi
  call   <contAlgarismo@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D2: O soma dos algarismos de 45363 eh: %d

assistant: ```c
main() {
  printf("O soma dos algarismos de 45363 eh: %d", contAlgarismo(45363, 0));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x49,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func1() {
  func2();
  return 73;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x49,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func1() {
  func2();
  return 73;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <func2@plt>
  mov    $0x49,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func1() {
  func2();
  return 73;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <int_t@plt>
  pop    %rbp
  ret
```

assistant: ```c
f() {
  const int int_t(void);
  int const int_t(void);
  const int(int_t)(void);
  int const(int_t)(void);
  return int_t();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  call   <int_t@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
f() {
  const int int_t(void);
  int const int_t(void);
  const int(int_t)(void);
  int const(int_t)(void);
  return int_t();
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  jmp    1050 <int_t@plt>
```

assistant: ```c
f() {
  const int int_t(void);
  int const int_t(void);
  const int(int_t)(void);
  int const(int_t)(void);
  return int_t();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  jmp    1050 <int_t@plt>
```

assistant: ```c
f() {
  const int int_t(void);
  int const int_t(void);
  const int(int_t)(void);
  int const(int_t)(void);
  return int_t();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bot_vector_dist_3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bot_vector_subtract_3d@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <bot_vector_magnitude_3d@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double bot_vector_dist_3d(const double v1[3], const double v2[3]) {
  double v[3];
  bot_vector_subtract_3d(v1, v2, v);
  return bot_vector_magnitude_3d(v);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bot_vector_dist_3d>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  call   <bot_vector_subtract_3d@plt>
  mov    %rbx,%rdi
  call   <bot_vector_magnitude_3d@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double bot_vector_dist_3d(const double v1[3], const double v2[3]) {
  double v[3];
  bot_vector_subtract_3d(v1, v2, v);
  return bot_vector_magnitude_3d(v);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bot_vector_dist_3d>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <bot_vector_subtract_3d@plt>
  mov    %rbp,%rdi
  call   <bot_vector_magnitude_3d@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double bot_vector_dist_3d(const double v1[3], const double v2[3]) {
  double v[3];
  bot_vector_subtract_3d(v1, v2, v);
  return bot_vector_magnitude_3d(v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bot_vector_dist_3d>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <bot_vector_subtract_3d@plt>
  mov    %rbp,%rdi
  call   <bot_vector_magnitude_3d@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double bot_vector_dist_3d(const double v1[3], const double v2[3]) {
  double v[3];
  bot_vector_subtract_3d(v1, v2, v);
  return bot_vector_magnitude_3d(v);
}
```