ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int scan(int n, const int cc[], int ss[]) {
  int i, s;
  ss[0] = 0;
  for (i = s = 0; i < n; ++i)
    ss[i + 1] = (s += cc[i]);
  return ss[n];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scan>:
  endbr64
  movl   $0x0,(%rdx)
  test   %edi,%edi
  jle    L17
  mov    %edi,%r9d
  mov    $0x0,%eax
  mov    $0x0,%r8d
L7:
  mov    %r8d,%ecx
  add    (%rsi,%rax,4),%ecx
  mov    %ecx,%r8d
  mov    %ecx,0x4(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L7
L17:
  movslq %edi,%rdi
  mov    (%rdx,%rdi,4),%eax
  ret
```

assistant: ```c
int scan(int n, const int cc[], int ss[]) {
  int i, s;
  ss[0] = 0;
  for (i = s = 0; i < n; ++i)
    ss[i + 1] = (s += cc[i]);
  return ss[n];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scan>:
  endbr64
  test   %edi,%edi
  movl   $0x0,(%rdx)
  movslq %edi,%rdi
  jle    L17
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L7:
  add    (%rsi,%rax,4),%ecx
  mov    %ecx,0x4(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L7
L17:
  mov    (%rdx,%rdi,4),%eax
  ret
```

assistant: ```c
int scan(int n, const int cc[], int ss[]) {
  int i, s;
  ss[0] = 0;
  for (i = s = 0; i < n; ++i)
    ss[i + 1] = (s += cc[i]);
  return ss[n];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scan>:
  endbr64
  test   %edi,%edi
  movl   $0x0,(%rdx)
  movslq %edi,%rdi
  jle    L3
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L16:
  add    (%rsi,%rax,4),%ecx
  mov    %ecx,0x4(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L16
L3:
  mov    (%rdx,%rdi,4),%eax
  ret
```

assistant: ```c
int scan(int n, const int cc[], int ss[]) {
  int i, s;
  ss[0] = 0;
  for (i = s = 0; i < n; ++i)
    ss[i + 1] = (s += cc[i]);
  return ss[n];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encodeInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x69,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  mov    -0xb8(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x60(%rbp),%rcx
  lea    -0xb0(%rbp),%rax
  mov    $0x2710,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  lea    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movw   $0x65,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %d

assistant: ```c
char *encodeInt(int *input) {
  char ans[80] = "i";
  char num[80];
  sprintf(num, "%d", input);
  strncat(ans, num, 10000);
  strncat(ans, "e", 10000);
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encodeInt>:
  endbr64
  push   %rbx
  sub    $0xb0,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movq   $0x69,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  lea    0x50(%rsp),%rbx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rsp,%rdi
  mov    $0x2710,%edx
  mov    %rbx,%rsi
  call   <strncat@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %d

assistant: ```c
char *encodeInt(int *input) {
  char ans[80] = "i";
  char num[80];
  sprintf(num, "%d", input);
  strncat(ans, num, 10000);
  strncat(ans, "e", 10000);
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<encodeInt>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %rdi,%rdx
  lea    D8(%rip),%rsi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  movq   $0x69,(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <sprintf@plt>
  mov    %rsp,%rdi
  mov    $0x2710,%edx
  mov    %rbp,%rsi
  call   <strncat@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
char *encodeInt(int *input) {
  char ans[80] = "i";
  char num[80];
  sprintf(num, "%d", input);
  strncat(ans, num, 10000);
  strncat(ans, "e", 10000);
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encodeInt>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  mov    %rdi,%rdx
  lea    D4(%rip),%rsi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  movq   $0x69,(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  call   <sprintf@plt>
  mov    %rsp,%rdi
  mov    $0x2710,%edx
  mov    %rbp,%rsi
  call   <strncat@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: %d

assistant: ```c
char *encodeInt(int *input) {
  char ans[80] = "i";
  char num[80];
  sprintf(num, "%d", input);
  strncat(ans, num, 10000);
  strncat(ans, "e", 10000);
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_at_tests_callee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x1c(%rbp)
  movl   $0xb,-0x18(%rbp)
  movl   $0xc,-0x14(%rbp)
  movl   $0x7,-0x10(%rbp)
  movl   $0xd,-0xc(%rbp)
  movl   $0xe,-0x8(%rbp)
  movl   $0xf,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<jReadFindTok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <jReadSkipWhitespace@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L166
  mov    -0x20(%rbp),%rax
  movl   $0x9,(%rax)
  jmp    L63
L166:
  cmpb   $0x22,-0x1(%rbp)
  je     L138
  cmpb   $0x27,-0x1(%rbp)
  jne    L43
L138:
  mov    -0x20(%rbp),%rax
  movl   $0x3,(%rax)
  jmp    L63
L43:
  cmpb   $0x2f,-0x1(%rbp)
  jle    L253
  cmpb   $0x39,-0x1(%rbp)
  jg     L253
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
  jmp    L63
L253:
  cmpb   $0x2d,-0x1(%rbp)
  jne    L40
  mov    -0x20(%rbp),%rax
  movl   $0x4,(%rax)
  jmp    L63
L40:
  cmpb   $0x7b,-0x1(%rbp)
  jne    L213
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L63
L213:
  cmpb   $0x5b,-0x1(%rbp)
  jne    L126
  mov    -0x20(%rbp),%rax
  movl   $0x2,(%rax)
  jmp    L63
L126:
  cmpb   $0x7d,-0x1(%rbp)
  jne    L19
  mov    -0x20(%rbp),%rax
  movl   $0xb,(%rax)
  jmp    L63
L19:
  cmpb   $0x5d,-0x1(%rbp)
  jne    L89
  mov    -0x20(%rbp),%rax
  movl   $0xc,(%rax)
  jmp    L63
L89:
  cmpb   $0x74,-0x1(%rbp)
  je     L93
  cmpb   $0x66,-0x1(%rbp)
  jne    L205
L93:
  mov    -0x20(%rbp),%rax
  movl   $0x5,(%rax)
  jmp    L63
L205:
  cmpb   $0x6e,-0x1(%rbp)
  jne    L283
  mov    -0x20(%rbp),%rax
  movl   $0x6,(%rax)
  jmp    L63
L283:
  cmpb   $0x3a,-0x1(%rbp)
  jne    L259
  mov    -0x20(%rbp),%rax
  movl   $0x8,(%rax)
  jmp    L63
L259:
  cmpb   $0x2c,-0x1(%rbp)
  jne    L76
  mov    -0x20(%rbp),%rax
  movl   $0xa,(%rax)
  jmp    L63
L76:
  cmpb   $0x2a,-0x1(%rbp)
  jne    L7
  mov    -0x20(%rbp),%rax
  movl   $0xd,(%rax)
  jmp    L63
L7:
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
L63:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *jReadFindTok(char *sp, int *tokType) {
  char c;
  sp = jReadSkipWhitespace(sp);
  c = *sp;
  if (c == '\0')
    *tokType = 9;
  else if ((c == '"') || (c == '\''))
    *tokType = 3;
  else if ((c >= '0') && (c <= '9'))
    *tokType = 4;
  else if (c == '-')
    *tokType = 4;
  else if (c == '{')
    *tokType = 1;
  else if (c == '[')
    *tokType = 2;
  else if (c == '}')
    *tokType = 11;
  else if (c == ']')
    *tokType = 12;
  else if ((c == 't') || (c == 'f'))
    *tokType = 5;
  else if (c == 'n')
    *tokType = 6;
  else if (c == ':')
    *tokType = 8;
  else if (c == ',')
    *tokType = 10;
  else if (c == '*')
    *tokType = 13;
  else
    *tokType = 0;
  return sp;
}
```
user: What is the c source code of the assembly code below?

```asm
<jReadFindTok>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <jReadSkipWhitespace@plt>
  movzbl (%rax),%edx
  mov    $0x9,%ecx
  test   %dl,%dl
  je     L0
  sub    $0x22,%edx
  cmp    $0x5b,%dl
  ja     L73
  movzbl %dl,%edx
  lea    D1(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x3,%ecx
  jmp    L0
  mov    $0x1,%ecx
  jmp    L0
  mov    $0x2,%ecx
  jmp    L0
  mov    $0xb,%ecx
  jmp    L0
  mov    $0xc,%ecx
  jmp    L0
  mov    $0x5,%ecx
  jmp    L0
  mov    $0x6,%ecx
  jmp    L0
  mov    $0x8,%ecx
  jmp    L0
  mov    $0xa,%ecx
  jmp    L0
  mov    $0xd,%ecx
  jmp    L0
L73:
  mov    $0x0,%ecx
  jmp    L0
  mov    $0x4,%ecx
L0:
  mov    %ecx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
char *jReadFindTok(char *sp, int *tokType) {
  char c;
  sp = jReadSkipWhitespace(sp);
  c = *sp;
  if (c == '\0')
    *tokType = 9;
  else if ((c == '"') || (c == '\''))
    *tokType = 3;
  else if ((c >= '0') && (c <= '9'))
    *tokType = 4;
  else if (c == '-')
    *tokType = 4;
  else if (c == '{')
    *tokType = 1;
  else if (c == '[')
    *tokType = 2;
  else if (c == '}')
    *tokType = 11;
  else if (c == ']')
    *tokType = 12;
  else if ((c == 't') || (c == 'f'))
    *tokType = 5;
  else if (c == 'n')
    *tokType = 6;
  else if (c == ':')
    *tokType = 8;
  else if (c == ',')
    *tokType = 10;
  else if (c == '*')
    *tokType = 13;
  else
    *tokType = 0;
  return sp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jReadFindTok>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <jReadSkipWhitespace@plt>
  mov    $0x9,%ecx
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L97
  sub    $0x22,%edx
  cmp    $0x5b,%dl
  ja     L109
  lea    D3(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  mov    $0x4,%ecx
L97:
  mov    %ecx,(%rbx)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L109:
  xor    %ecx,%ecx
  jmp    L97
  nopl   0x0(%rax)
  mov    $0x5,%ecx
  jmp    L97
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%ecx
  jmp    L97
  mov    $0x8,%ecx
  jmp    L97
  mov    $0x2,%ecx
  jmp    L97
  mov    $0xd,%ecx
  jmp    L97
  mov    $0xc,%ecx
  jmp    L97
  mov    $0x6,%ecx
  jmp    L97
  mov    $0x1,%ecx
  jmp    L97
  mov    $0xa,%ecx
  jmp    L97
  mov    $0xb,%ecx
  jmp    L97
```

assistant: ```c
char *jReadFindTok(char *sp, int *tokType) {
  char c;
  sp = jReadSkipWhitespace(sp);
  c = *sp;
  if (c == '\0')
    *tokType = 9;
  else if ((c == '"') || (c == '\''))
    *tokType = 3;
  else if ((c >= '0') && (c <= '9'))
    *tokType = 4;
  else if (c == '-')
    *tokType = 4;
  else if (c == '{')
    *tokType = 1;
  else if (c == '[')
    *tokType = 2;
  else if (c == '}')
    *tokType = 11;
  else if (c == ']')
    *tokType = 12;
  else if ((c == 't') || (c == 'f'))
    *tokType = 5;
  else if (c == 'n')
    *tokType = 6;
  else if (c == ':')
    *tokType = 8;
  else if (c == ',')
    *tokType = 10;
  else if (c == '*')
    *tokType = 13;
  else
    *tokType = 0;
  return sp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<jReadFindTok>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <jReadSkipWhitespace@plt>
  mov    $0x9,%ecx
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L30
  sub    $0x22,%edx
  cmp    $0x5b,%dl
  ja     L104
  lea    D7(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  mov    $0x4,%ecx
L30:
  mov    %ecx,(%rbx)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L104:
  xor    %ecx,%ecx
  jmp    L30
  nopl   0x0(%rax)
  mov    $0x5,%ecx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%ecx
  jmp    L30
  mov    $0x8,%ecx
  jmp    L30
  mov    $0x2,%ecx
  jmp    L30
  mov    $0xd,%ecx
  jmp    L30
  mov    $0xc,%ecx
  jmp    L30
  mov    $0x6,%ecx
  jmp    L30
  mov    $0x1,%ecx
  jmp    L30
  mov    $0xa,%ecx
  jmp    L30
  mov    $0xb,%ecx
  jmp    L30
```

assistant: ```c
char *jReadFindTok(char *sp, int *tokType) {
  char c;
  sp = jReadSkipWhitespace(sp);
  c = *sp;
  if (c == '\0')
    *tokType = 9;
  else if ((c == '"') || (c == '\''))
    *tokType = 3;
  else if ((c >= '0') && (c <= '9'))
    *tokType = 4;
  else if (c == '-')
    *tokType = 4;
  else if (c == '{')
    *tokType = 1;
  else if (c == '[')
    *tokType = 2;
  else if (c == '}')
    *tokType = 11;
  else if (c == ']')
    *tokType = 12;
  else if ((c == 't') || (c == 'f'))
    *tokType = 5;
  else if (c == 'n')
    *tokType = 6;
  else if (c == ':')
    *tokType = 8;
  else if (c == ',')
    *tokType = 10;
  else if (c == '*')
    *tokType = 13;
  else
    *tokType = 0;
  return sp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd1p2_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D58
datatype: string
name: parse_data
arguments: tag: D55
datatype: string
name: parse_data
arguments: tag: D56
datatype: string
name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D31
datatype: string

tool: D58: cmd1p2_handler 

tool: D55: cmd1p1

tool: D56: p: %s 


tool: D20: cmd1p2

tool: D31: cmd1p3

assistant: ```c
void cmd1p2_handler(struct parsed_params *params) {
  printf("cmd1p2_handler \n");
  printf("p: %s \n", get_param_val("cmd1p1", params));
  printf("p: %s \n", get_param_val("cmd1p2", params));
  printf("p: %s \n", get_param_val("cmd1p3", params));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmd1p2_handler>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D36(%rip),%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D44(%rip),%rdi
  call   <get_param_val@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
type_guessed: string
name: read_data
arguments: data_tag: D36
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D44
type_guessed: string

tool: D31: cmd1p2_handler 

tool: D36: cmd1p1

tool: D13: p: %s 


tool: D29: cmd1p2

tool: D44: cmd1p3

assistant: ```c
void cmd1p2_handler(struct parsed_params *params) {
  printf("cmd1p2_handler \n");
  printf("p: %s \n", get_param_val("cmd1p1", params));
  printf("p: %s \n", get_param_val("cmd1p2", params));
  printf("p: %s \n", get_param_val("cmd1p3", params));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmd1p2_handler>:
  endbr64
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <get_param_val@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D40(%rip),%rdi
  call   <get_param_val@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D38(%rip),%rdi
  call   <get_param_val@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  mov    %rax,%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1080 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D13
data_type: string
name: parse_data
arguments: tag: D35
data_type: string
name: parse_data
arguments: tag: D40
data_type: string
name: parse_data
arguments: tag: D38
data_type: string

tool: D24: p: %s 


tool: D13: cmd1p2_handler 

tool: D35: cmd1p1

tool: D40: cmd1p2

tool: D38: cmd1p3

assistant: ```c
void cmd1p2_handler(struct parsed_params *params) {
  printf("cmd1p2_handler \n");
  printf("p: %s \n", get_param_val("cmd1p1", params));
  printf("p: %s \n", get_param_val("cmd1p2", params));
  printf("p: %s \n", get_param_val("cmd1p3", params));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd1p2_handler>:
  endbr64
  push   %r12
  lea    D40(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D43(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  call   <get_param_val@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  call   <get_param_val@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D48(%rip),%rdi
  call   <get_param_val@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  mov    %rax,%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1080 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D40
datatype: string
name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D34
datatype: string
name: parse_data
arguments: label: D30
datatype: string
name: parse_data
arguments: label: D48
datatype: string

tool: D40: p: %s 


tool: D43: cmd1p2_handler 

tool: D34: cmd1p1

tool: D30: cmd1p2

tool: D48: cmd1p3

assistant: ```c
void cmd1p2_handler(struct parsed_params *params) {
  printf("cmd1p2_handler \n");
  printf("p: %s \n", get_param_val("cmd1p1", params));
  printf("p: %s \n", get_param_val("cmd1p2", params));
  printf("p: %s \n", get_param_val("cmd1p3", params));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash_djb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1505,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L15
L0:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t hash_djb(void *key, size_t len) {
  size_t i, hash = 5381;
  int c;
  for (i = 0; i < len; i++) {
    c = ((char *)key)[i];
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_djb>:
  endbr64
  test   %rsi,%rsi
  je     L8
  mov    %rdi,%rdx
  add    %rsi,%rdi
  mov    $0x1505,%eax
L2:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rax
  movsbq (%rdx),%rcx
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L2
  ret
L8:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t hash_djb(void *key, size_t len) {
  size_t i, hash = 5381;
  int c;
  for (i = 0; i < len; i++) {
    c = ((char *)key)[i];
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_djb>:
  endbr64
  test   %rsi,%rsi
  je     L15
  add    %rdi,%rsi
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L8:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  add    %rdx,%rax
  cmp    %rsi,%rdi
  jne    L8
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t hash_djb(void *key, size_t len) {
  size_t i, hash = 5381;
  int c;
  for (i = 0; i < len; i++) {
    c = ((char *)key)[i];
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_djb>:
  endbr64
  test   %rsi,%rsi
  je     L9
  add    %rdi,%rsi
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L16:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  add    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L16
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
size_t hash_djb(void *key, size_t len) {
  size_t i, hash = 5381;
  int c;
  for (i = 0; i < len; i++) {
    c = ((char *)key)[i];
    hash = ((hash << 5) + hash) + c;
  }
  return hash;
}
```