ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<rie_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int rie_max(int a, int b) {
  if (a < b) {
    return b;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x14(%rbp)
  mov    $0x0,%eax
  call   <twenty_one@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <twenty_one@plt>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  i = twenty_one() + twenty_one();
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <twenty_one@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <twenty_one@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  i = twenty_one() + twenty_one();
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <twenty_one@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <twenty_one@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  i = twenty_one() + twenty_one();
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <twenty_one@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <twenty_one@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  i = twenty_one() + twenty_one();
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subroutine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L10:
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x63,-0x4(%rbp)
  jle    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subroutine(int in) {
  int count = in;
  while (count < 100)
    count++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<subroutine>:
  endbr64
  cmp    $0x63,%edi
  jg     L0
L11:
  add    $0x1,%edi
  cmp    $0x64,%edi
  jne    L11
L0:
  ret
```

assistant: ```c
void subroutine(int in) {
  int count = in;
  while (count < 100)
    count++;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<subroutine>:
  endbr64
  ret
```

assistant: ```c
void subroutine(int in) {
  int count = in;
  while (count < 100)
    count++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subroutine>:
  endbr64
  ret
```

assistant: ```c
void subroutine(int in) {
  int count = in;
  while (count < 100)
    count++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<htrehash>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  call   <htalloc@plt>
  mov    %rax,%r14
  mov    %rax,(%rsp)
  mov    %r13,%rdi
  call   <malloc_usable_size@plt>
  movslq %eax,%rcx
  lea    0x7(%rbx),%r12
  and    $0xfffffffffffffff8,%r12
  add    $0x8,%r12
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %r12
  test   %r14,%r14
  je     L3
  mov    %rax,%r15
  cmp    %r12,%rcx
  jb     L29
  mov    $0x0,%r14d
  add    $0x7,%ebx
  and    $0xfffffff8,%ebx
  lea    0x8(%rbx),%eax
  mov    %eax,0x14(%rsp)
  jmp    L71
L20:
  mov    0x14(%rsp),%edx
  mov    0x8(%rsp),%rsi
  call   <memcpy@plt>
L72:
  cmp    %rbx,%rbp
  je     L61
L40:
  add    $0x1,%r14
  add    %r12,%r13
  cmp    %r14,%r15
  jbe    L29
L71:
  mov    %r13,0x8(%rsp)
  mov    0x0(%r13),%rdi
  test   %rdi,%rdi
  je     L40
  call   <strhash@plt>
  mov    %rax,%rcx
  test   %rbp,%rbp
  je     L61
  mov    $0x0,%ebx
L9:
  lea    (%rcx,%rbx,1),%rax
  mov    $0x0,%edx
  div    %rbp
  imul   %r12,%rdx
  mov    (%rsp),%rax
  lea    (%rax,%rdx,1),%rdi
  cmpq   $0x0,(%rdi)
  je     L20
  add    $0x5,%rbx
  cmp    %rbx,%rbp
  ja     L9
  jmp    L72
L61:
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L3
L29:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
L3:
  mov    (%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *htrehash(void *table, size_t new_cap, size_t size) {
  void *old = table;
  void *new = htalloc(new_cap, size);
  size_t i, j, index, hash;
  void *old_slot, *new_slot;
  size_t old_cap = (malloc_usable_size(table) / (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
  if (!new)
    return NULL;
  for (j = 0; j < old_cap; j++) {
    old_slot = ((old) + j * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
    if (!(*(const char **)((old_slot) + 0)))
      continue;
    hash = strhash((*(const char **)((old_slot) + 0)));
    for (i = 0; i < new_cap; i += (5)) {
      index = (hash + i) % new_cap;
      new_slot = ((new) + index * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
      if (!(*(const char **)((new_slot) + 0))) {
        memcpy(new_slot, old_slot, (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
        break;
      }
    }
    if (i == new_cap) {
      free(new);
      return old;
    }
  }
  free(old);
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<htrehash>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x7(%r13),%r15
  push   %rbp
  and    $0xfffffffffffffff8,%r15
  push   %rbx
  mov    %rdi,%rbx
  add    $0x8,%r15
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %r14,%rdi
  call   <htalloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <malloc_usable_size@plt>
  xor    %edx,%edx
  movslq %eax,%rcx
  mov    %rcx,%rax
  div    %r15
  mov    %rax,0x8(%rsp)
  test   %r12,%r12
  je     L7
  cmp    %r15,%rcx
  jb     L92
  lea    0x7(%r13),%eax
  xor    %ebp,%ebp
  and    $0xfffffff8,%eax
  add    $0x8,%eax
  mov    %eax,0x14(%rsp)
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbp
  add    %r15,%rbx
  cmp    %rbp,0x8(%rsp)
  jbe    L92
L3:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L12
  call   <strhash@plt>
  mov    %rax,%r9
  test   %r14,%r14
  je     L52
  xor    %r13d,%r13d
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x5,%r13
  cmp    %r13,%r14
  jbe    L104
L27:
  xor    %edx,%edx
  lea    (%r9,%r13,1),%rax
  div    %r14
  imul   %r15,%rdx
  lea    (%r12,%rdx,1),%rdi
  cmpq   $0x0,(%rdi)
  jne    L14
  mov    0x14(%rsp),%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L104:
  cmp    %r13,%r14
  jne    L12
L52:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%r12
L7:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  jmp    L7
```

assistant: ```c
void *htrehash(void *table, size_t new_cap, size_t size) {
  void *old = table;
  void *new = htalloc(new_cap, size);
  size_t i, j, index, hash;
  void *old_slot, *new_slot;
  size_t old_cap = (malloc_usable_size(table) / (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
  if (!new)
    return NULL;
  for (j = 0; j < old_cap; j++) {
    old_slot = ((old) + j * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
    if (!(*(const char **)((old_slot) + 0)))
      continue;
    hash = strhash((*(const char **)((old_slot) + 0)));
    for (i = 0; i < new_cap; i += (5)) {
      index = (hash + i) % new_cap;
      new_slot = ((new) + index * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
      if (!(*(const char **)((new_slot) + 0))) {
        memcpy(new_slot, old_slot, (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
        break;
      }
    }
    if (i == new_cap) {
      free(new);
      return old;
    }
  }
  free(old);
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<htrehash>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x7(%r13),%r15
  push   %rbp
  and    $0xfffffffffffffff8,%r15
  push   %rbx
  mov    %rdi,%rbx
  add    $0x8,%r15
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %r14,%rdi
  call   <htalloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <malloc_usable_size@plt>
  xor    %edx,%edx
  movslq %eax,%rcx
  mov    %rcx,%rax
  div    %r15
  mov    %rax,0x8(%rsp)
  test   %r12,%r12
  je     L9
  cmp    %r15,%rcx
  jb     L46
  lea    0x7(%r13),%eax
  xor    %ebp,%ebp
  and    $0xfffffff8,%eax
  add    $0x8,%eax
  mov    %eax,0x14(%rsp)
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L70:
  add    $0x1,%rbp
  add    %r15,%rbx
  cmp    %rbp,0x8(%rsp)
  jbe    L46
L59:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L70
  call   <strhash@plt>
  mov    %rax,%r9
  test   %r14,%r14
  je     L48
  xor    %r13d,%r13d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x5,%r13
  cmp    %r13,%r14
  jbe    L82
L8:
  xor    %edx,%edx
  lea    (%r9,%r13,1),%rax
  div    %r14
  imul   %r15,%rdx
  lea    (%r12,%rdx,1),%rdi
  cmpq   $0x0,(%rdi)
  jne    L0
  mov    0x14(%rsp),%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L82:
  cmp    %r13,%r14
  jne    L70
L48:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%r12
L9:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  mov    0x18(%rsp),%rdi
  call   <free@plt>
  jmp    L9
```

assistant: ```c
void *htrehash(void *table, size_t new_cap, size_t size) {
  void *old = table;
  void *new = htalloc(new_cap, size);
  size_t i, j, index, hash;
  void *old_slot, *new_slot;
  size_t old_cap = (malloc_usable_size(table) / (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
  if (!new)
    return NULL;
  for (j = 0; j < old_cap; j++) {
    old_slot = ((old) + j * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
    if (!(*(const char **)((old_slot) + 0)))
      continue;
    hash = strhash((*(const char **)((old_slot) + 0)));
    for (i = 0; i < new_cap; i += (5)) {
      index = (hash + i) % new_cap;
      new_slot = ((new) + index * (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
      if (!(*(const char **)((new_slot) + 0))) {
        memcpy(new_slot, old_slot, (sizeof(const char *) + (((size) + ((sizeof(void *)) - 1)) & ~((sizeof(void *)) - 1))));
        break;
      }
    }
    if (i == new_cap) {
      free(new);
      return old;
    }
  }
  free(old);
  return new;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pesquisa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  jmp    L22
L4:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x9,-0x4(%rbp)
  jle    L21
  mov    $0xffffffff,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int pesquisa(int p, int *vetor) {
  for (int i = 0; i <= 9; i++) {
    if (p == vetor[i]) {
      return i;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pesquisa>:
  endbr64
  mov    $0x0,%eax
L13:
  mov    %eax,%edx
  cmp    %edi,(%rsi,%rax,4)
  je     L2
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L13
  mov    $0xffffffff,%edx
L2:
  mov    %edx,%eax
  ret
```

assistant: ```c
int pesquisa(int p, int *vetor) {
  for (int i = 0; i <= 9; i++) {
    if (p == vetor[i]) {
      return i;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pesquisa>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %eax,%r8d
  cmp    %edi,(%rsi,%rax,4)
  je     L13
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L19
  mov    $0xffffffff,%r8d
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pesquisa(int p, int *vetor) {
  for (int i = 0; i <= 9; i++) {
    if (p == vetor[i]) {
      return i;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pesquisa>:
  endbr64
  cmp    (%rsi),%edi
  je     L82
  cmp    0x4(%rsi),%edi
  je     L61
  cmp    0x8(%rsi),%edi
  je     L24
  cmp    0xc(%rsi),%edi
  je     L87
  cmp    0x10(%rsi),%edi
  je     L6
  cmp    0x14(%rsi),%edi
  je     L63
  cmp    0x18(%rsi),%edi
  je     L25
  cmp    0x1c(%rsi),%edi
  je     L28
  cmp    0x20(%rsi),%edi
  je     L86
  cmp    %edi,0x24(%rsi)
  mov    $0x9,%edx
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
L82:
  xor    %eax,%eax
  ret
L61:
  mov    $0x1,%eax
  ret
L24:
  mov    $0x2,%eax
  ret
L87:
  mov    $0x3,%eax
  ret
L6:
  mov    $0x4,%eax
  ret
L63:
  mov    $0x5,%eax
  ret
L25:
  mov    $0x6,%eax
  ret
L28:
  mov    $0x7,%eax
  ret
L86:
  mov    $0x8,%eax
  ret
```

assistant: ```c
int pesquisa(int p, int *vetor) {
  for (int i = 0; i <= 9; i++) {
    if (p == vetor[i]) {
      return i;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rpi_dev_smbus_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L13
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x703,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
extern int rpi_dev_smbus_open(char *filename, int address) {
  int fd;
  int ir;
  fd = open(filename, O_RDWR);
  if (fd >= 0) {
    if ((ir = ioctl(fd, 0x0703, address)) < 0) {
      fd = ir;
    }
  }
  return fd;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rpi_dev_smbus_open>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L15
L0:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %ebp,%edx
  mov    $0x703,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovs  %eax,%ebx
  jmp    L0
```

assistant: ```c
extern int rpi_dev_smbus_open(char *filename, int address) {
  int fd;
  int ir;
  fd = open(filename, O_RDWR);
  if (fd >= 0) {
    if ((ir = ioctl(fd, 0x0703, address)) < 0) {
      fd = ir;
    }
  }
  return fd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rpi_dev_smbus_open>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
  mov    %r13d,%edx
  mov    $0x703,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovs  %eax,%r12d
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
extern int rpi_dev_smbus_open(char *filename, int address) {
  int fd;
  int ir;
  fd = open(filename, O_RDWR);
  if (fd >= 0) {
    if ((ir = ioctl(fd, 0x0703, address)) < 0) {
      fd = ir;
    }
  }
  return fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rpi_dev_smbus_open>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L4
  mov    %r13d,%edx
  mov    $0x703,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovs  %eax,%r12d
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
extern int rpi_dev_smbus_open(char *filename, int address) {
  int fd;
  int ir;
  fd = open(filename, O_RDWR);
  if (fd >= 0) {
    if ((ir = ioctl(fd, 0x0703, address)) < 0) {
      fd = ir;
    }
  }
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ensure_buffer_reserve_copes_with_null_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400,%esi
  mov    $0x0,%edi
  call   <buffer_reserve@plt>
  test   %rax,%rax
  je     L6
  lea    D16(%rip),%rax
  mov    %rax,%rcx
  mov    $0x172,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D24
type: string

tool: D16: buffer_reserve( 0, 1024 ) == 0

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c

tool: D24: %s:%d - test '%s' failed


assistant: ```c
void _ensure_buffer_reserve_copes_with_null_buffer(void) {
  if (!(buffer_reserve(0, 1024) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c", 370, "buffer_reserve( 0, 1024 ) == 0");
    exit(1);
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ensure_buffer_reserve_copes_with_null_buffer>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%esi
  mov    $0x0,%edi
  call   <buffer_reserve@plt>
  test   %rax,%rax
  jne    L12
L19:
  add    $0x8,%rsp
  ret
L12:
  lea    D26(%rip),%rcx
  mov    $0x172,%edx
  lea    D12(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D26: buffer_reserve( 0, 1024 ) == 0

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c

tool: D4: %s:%d - test '%s' failed


assistant: ```c
void _ensure_buffer_reserve_copes_with_null_buffer(void) {
  if (!(buffer_reserve(0, 1024) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c", 370, "buffer_reserve( 0, 1024 ) == 0");
    exit(1);
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_ensure_buffer_reserve_copes_with_null_buffer>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x400,%esi
  call   <buffer_reserve@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L9:
  lea    D17(%rip),%rdi
  lea    D25(%rip),%rcx
  mov    $0x172,%edx
  lea    D2(%rip),%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D17: %s:%d - test '%s' failed


tool: D25: buffer_reserve( 0, 1024 ) == 0

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c

assistant: ```c
void _ensure_buffer_reserve_copes_with_null_buffer(void) {
  if (!(buffer_reserve(0, 1024) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c", 370, "buffer_reserve( 0, 1024 ) == 0");
    exit(1);
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ensure_buffer_reserve_copes_with_null_buffer>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  mov    $0x400,%esi
  call   <buffer_reserve@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L8:
  lea    D17(%rip),%rdi
  lea    D14(%rip),%rcx
  mov    $0x172,%edx
  lea    D11(%rip),%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D11
type_guessed: string

tool: D17: %s:%d - test '%s' failed


tool: D14: buffer_reserve( 0, 1024 ) == 0

tool: D11: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c

assistant: ```c
void _ensure_buffer_reserve_copes_with_null_buffer(void) {
  if (!(buffer_reserve(0, 1024) == 0)) {
    printf("%s:%d - test '%s' failed\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jbrd/libmem/refs/heads/master/src/tests/buffer_tests.c", 370, "buffer_reserve( 0, 1024 ) == 0");
    exit(1);
  };
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <vassert@plt>
  jmp    L6
L31:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L24
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x0,%eax
L24:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: str == NULL

assistant: ```c
char *strchr(const char *str, int ch) {
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      return (char *)(str - 1);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strchr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <vassert@plt>
L15:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L37
  lea    0x1(%rbx),%rdx
  movsbl %al,%eax
  cmp    %ebp,%eax
  je     L22
  mov    %rdx,%rbx
  jmp    L15
L37:
  mov    $0x0,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %rbx,%rax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: str == NULL

assistant: ```c
char *strchr(const char *str, int ch) {
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      return (char *)(str - 1);
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D3(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <vassert@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L15:
  lea    0x1(%rbx),%rax
  cmp    %ebp,%edx
  je     L23
  mov    %rax,%rbx
L22:
  movsbl (%rbx),%edx
  test   %dl,%dl
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: str == NULL

assistant: ```c
char *strchr(const char *str, int ch) {
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      return (char *)(str - 1);
  }
  return NULL;
}
```