ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<error_check>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x20(%rsp)
  test   %edi,%edi
  jle    L5
  lea    -0x1(%rdi),%ecx
  mov    %edi,%r13d
  pxor   %xmm6,%xmm6
  mov    %rsi,%r15
  shl    $0x3,%r13
  mov    %ecx,0x2c(%rsp)
  mov    $0xffffffff,%ebp
  lea    (%rsi,%r13,1),%r12
  movsd  %xmm6,(%rsp)
  mov    %r12,%rbx
  nop
L37:
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x18(%rsp),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  0x20(%rsp),%xmm0
  mulsd  D11(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L8:
  movsd  0x8(%rsp),%xmm0
  add    $0x8,%r15
  call   <exp@plt>
  mulsd  0x10(%rsp),%xmm0
  movsd  -0x8(%r15),%xmm1
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  (%rsp),%xmm1
  movsd  %xmm1,(%rsp)
  cmp    %rbx,%r15
  jne    L8
  mov    %r12,%r15
  add    %r13,%rbx
  add    $0x1,%ebp
  cmp    %ebp,0x2c(%rsp)
  je     L24
  mov    %r14d,%eax
  add    %r13,%r12
  jmp    L37
  nopl   0x0(%rax)
L24:
  movapd %xmm1,%xmm0
L28:
  call   <sqrt@plt>
  imul   %r14d,%r14d
  pxor   %xmm0,%xmm0
  add    $0x38,%rsp
  cltd
  pop    %rbx
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  idiv   %r14d
  pop    %r14
  pop    %r15
  cvtsi2sd %eax,%xmm0
  jmp    1070 <printf@plt>
L5:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  movapd %xmm7,%xmm0
  jmp    L28
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: f32[2]
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: {"D11": [0.0,-2.0]}

tool: D17: Erro : %g


assistant: ```c
void error_check(int n, double dx, double dy, double *u) {
  int i, j;
  double xx, yy, temp, error;
  double *up = u;
  error = 0.0;
  for (j = 0; j < n; j++) {
    xx = exp(dx * (i - 1));
    for (i = 0; i < n; i++) {
      yy = exp(-2.0 * (dy * (j - 1)));
      temp = *up++ - xx * yy;
      error += temp * temp;
    }
  }
  error = sqrt(error) / (n * n);
  printf("Erro : %g\n", error);
}
```
user: Translate the below assembly code into C programming language:

```asm
<makeTexture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc30,%rsp
  mov    %rdi,-0xc28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc10(%rbp),%rax
  mov    %rax,-0xc18(%rbp)
  movl   $0x0,-0xc1c(%rbp)
  jmp    L40
L62:
  movl   $0x0,-0xc20(%rbp)
  jmp    L21
L66:
  mov    -0xc1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc20(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L54
  mov    -0xc18(%rbp),%rax
  movl   $0x6f,(%rax)
  mov    -0xc18(%rbp),%rax
  add    $0x4,%rax
  movl   $0x8f,(%rax)
  mov    -0xc18(%rbp),%rax
  add    $0x8,%rax
  movl   $0x1f,(%rax)
  jmp    L50
L54:
  mov    -0xc18(%rbp),%rax
  movl   $0xaa,(%rax)
  mov    -0xc18(%rbp),%rax
  add    $0x4,%rax
  movl   $0xaa,(%rax)
  mov    -0xc18(%rbp),%rax
  add    $0x8,%rax
  movl   $0xaa,(%rax)
L50:
  addq   $0xc,-0xc18(%rbp)
  addl   $0x1,-0xc20(%rbp)
L21:
  cmpl   $0xf,-0xc20(%rbp)
  jle    L66
  addl   $0x1,-0xc1c(%rbp)
L40:
  cmpl   $0xf,-0xc1c(%rbp)
  jle    L62
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <glPixelStorei@plt>
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D41(%rip),%rax
  mov    (%rax),%ecx
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <glTexParameteri@plt>
  mov    D58(%rip),%rax
  mov    (%rax),%ecx
  mov    D57(%rip),%rax
  mov    (%rax),%edx
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  sub    $0x8,%rsp
  lea    -0xc10(%rbp),%rsi
  push   %rsi
  push   %rcx
  push   %rdx
  mov    $0x0,%r9d
  mov    $0x10,%r8d
  mov    $0x10,%ecx
  mov    $0x3,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <glTexImage2D@plt>
  add    $0x20,%rsp
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void makeTexture(char *pattern[]) {
  GLubyte floorTexture[16][16][3];
  GLubyte *loc;
  int s, t;
  loc = (GLubyte *)floorTexture;
  for (t = 0; t < 16; t++) {
    for (s = 0; s < 16; s++) {
      if (pattern[t][s] == 'x') {
        loc[0] = 0x6f;
        loc[1] = 0x8f;
        loc[2] = 0x1f;
      } else {
        loc[0] = 0xaa;
        loc[1] = 0xaa;
        loc[2] = 0xaa;
      }
      loc += 3;
    }
  }
  glPixelStorei(GL_UNPACK_ALIGNMENT, 1);
  glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST);
  glTexImage2D(GL_TEXTURE_2D, 0, 3, 16, 16, 0, GL_RGB, GL_UNSIGNED_BYTE, floorTexture);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makeTexture>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  lea    0xc0(%rsp),%r10
  mov    %rdi,%rbp
  lea    0xcc0(%rsp),%r12
  mov    $0xaa,%ecx
  mov    $0x6f,%ebx
  mov    $0x8f,%edi
  mov    $0x1f,%r11d
L2:
  lea    -0xc0(%r10),%rax
  mov    0x0(%rbp),%rdx
L9:
  cmpb   $0x78,(%rdx)
  mov    %ebx,%r9d
  cmovne %ecx,%r9d
  mov    %edi,%r8d
  cmovne %ecx,%r8d
  mov    %r11d,%esi
  cmovne %ecx,%esi
  mov    %r9d,(%rax)
  mov    %r8d,0x4(%rax)
  mov    %esi,0x8(%rax)
  add    $0xc,%rax
  add    $0x1,%rdx
  cmp    %r10,%rax
  jne    L9
  add    $0xc0,%r10
  add    $0x8,%rbp
  cmp    %r12,%r10
  jne    L2
  mov    $0x1,%esi
  mov    D42(%rip),%rax
  mov    (%rax),%edi
  call   <glPixelStorei@plt>
  mov    D35(%rip),%rbx
  mov    D38(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    (%rbx),%edi
  call   <glTexParameteri@plt>
  sub    $0x8,%rsp
  lea    0x8(%rsp),%rax
  push   %rax
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  push   %rax
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  push   %rax
  mov    $0x0,%r9d
  mov    $0x10,%r8d
  mov    $0x10,%ecx
  mov    $0x3,%edx
  mov    $0x0,%esi
  mov    (%rbx),%edi
  call   <glTexImage2D@plt>
  add    $0x20,%rsp
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void makeTexture(char *pattern[]) {
  GLubyte floorTexture[16][16][3];
  GLubyte *loc;
  int s, t;
  loc = (GLubyte *)floorTexture;
  for (t = 0; t < 16; t++) {
    for (s = 0; s < 16; s++) {
      if (pattern[t][s] == 'x') {
        loc[0] = 0x6f;
        loc[1] = 0x8f;
        loc[2] = 0x1f;
      } else {
        loc[0] = 0xaa;
        loc[1] = 0xaa;
        loc[2] = 0xaa;
      }
      loc += 3;
    }
  }
  glPixelStorei(GL_UNPACK_ALIGNMENT, 1);
  glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST);
  glTexImage2D(GL_TEXTURE_2D, 0, 3, 16, 16, 0, GL_RGB, GL_UNSIGNED_BYTE, floorTexture);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<makeTexture>:
  endbr64
  push   %r12
  mov    $0xaa,%ecx
  mov    $0x1f,%r11d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8f,%edi
  push   %rbx
  mov    $0x6f,%ebx
  sub    $0xc10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  lea    0xc0(%rsp),%r10
  lea    0xcc0(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp),%rdx
  lea    -0xc0(%r10),%rax
  nopl   0x0(%rax,%rax,1)
L4:
  cmpb   $0x78,(%rdx)
  mov    %ebx,%r9d
  mov    %edi,%r8d
  mov    %r11d,%esi
  cmovne %ecx,%r9d
  cmovne %ecx,%r8d
  cmovne %ecx,%esi
  add    $0xc,%rax
  add    $0x1,%rdx
  mov    %r9d,-0xc(%rax)
  mov    %r8d,-0x8(%rax)
  mov    %esi,-0x4(%rax)
  cmp    %r10,%rax
  jne    L4
  lea    0xc0(%rax),%r10
  add    $0x8,%rbp
  cmp    %r12,%r10
  jne    L0
  mov    D7(%rip),%rax
  mov    $0x1,%esi
  mov    (%rax),%edi
  call   <glPixelStorei@plt>
  mov    D53(%rip),%rax
  mov    D17(%rip),%rbx
  mov    (%rax),%edx
  mov    D57(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <glTexParameteri@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %esi,%esi
  lea    0x8(%rsp),%rax
  mov    $0x10,%r8d
  mov    $0x10,%ecx
  mov    $0x3,%edx
  push   %rax
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  push   %rax
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  push   %rax
  mov    (%rbx),%edi
  call   <glTexImage2D@plt>
  add    $0x20,%rsp
  mov    0xc08(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void makeTexture(char *pattern[]) {
  GLubyte floorTexture[16][16][3];
  GLubyte *loc;
  int s, t;
  loc = (GLubyte *)floorTexture;
  for (t = 0; t < 16; t++) {
    for (s = 0; s < 16; s++) {
      if (pattern[t][s] == 'x') {
        loc[0] = 0x6f;
        loc[1] = 0x8f;
        loc[2] = 0x1f;
      } else {
        loc[0] = 0xaa;
        loc[1] = 0xaa;
        loc[2] = 0xaa;
      }
      loc += 3;
    }
  }
  glPixelStorei(GL_UNPACK_ALIGNMENT, 1);
  glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST);
  glTexImage2D(GL_TEXTURE_2D, 0, 3, 16, 16, 0, GL_RGB, GL_UNSIGNED_BYTE, floorTexture);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L1:
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L3
  test   %eax,%eax
  je     L36
  jmp    L35
L3:
  mov    $0x1,%eax
  jmp    L13
L35:
  mov    $0x0,%edi
  call   <wait@plt>
L36:
  mov    $0x0,%eax
  call   <a@plt>
  add    %eax,-0x4(%rbp)
  nop
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
L13:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  if (argc > 1)
    ret = atoi(argv[1]);
  switch (fork()) {
  case -1:
    return 1;
  default:
    wait(NULL);
  case 0:
    ret += a();
    break;
  }
  return ret ? 0 : 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  cmp    $0x1,%edi
  jg     L37
L17:
  call   <fork@plt>
  mov    $0x1,%edx
  cmp    $0xffffffff,%eax
  je     L14
  test   %eax,%eax
  je     L9
  mov    $0x0,%edi
  call   <wait@plt>
L9:
  mov    $0x0,%eax
  call   <a@plt>
  add    %ebx,%eax
  sete   %dl
  movzbl %dl,%edx
L14:
  mov    %edx,%eax
  pop    %rbx
  ret
L37:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L17
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  if (argc > 1)
    ret = atoi(argv[1]);
  switch (fork()) {
  case -1:
    return 1;
  default:
    wait(NULL);
  case 0:
    ret += a();
    break;
  }
  return ret ? 0 : 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  cmp    $0x1,%edi
  jle    L23
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
L23:
  call   <fork@plt>
  mov    $0x1,%r8d
  cmp    $0xffffffff,%eax
  je     L26
  test   %eax,%eax
  je     L14
  xor    %edi,%edi
  call   <wait@plt>
L14:
  xor    %eax,%eax
  call   <a@plt>
  xor    %r8d,%r8d
  add    %ebx,%eax
  sete   %r8b
L26:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  if (argc > 1)
    ret = atoi(argv[1]);
  switch (fork()) {
  case -1:
    return 1;
  default:
    wait(NULL);
  case 0:
    ret += a();
    break;
  }
  return ret ? 0 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  cmp    $0x1,%edi
  jle    L25
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
L25:
  call   <fork@plt>
  mov    $0x1,%r8d
  cmp    $0xffffffff,%eax
  je     L2
  test   %eax,%eax
  je     L4
  xor    %edi,%edi
  call   <wait@plt>
L4:
  xor    %eax,%eax
  call   <a@plt>
  xor    %r8d,%r8d
  add    %ebx,%eax
  sete   %r8b
L2:
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  if (argc > 1)
    ret = atoi(argv[1]);
  switch (fork()) {
  case -1:
    return 1;
  default:
    wait(NULL);
  case 0:
    ret += a();
    break;
  }
  return ret ? 0 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syncsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L49
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmpl   $0x1,-0x8(%rbp)
  ja     L54
  mov    $0x0,%edx
  jmp    L44
L54:
  mov    $0xff,%edx
L44:
  cmp    %eax,%edx
  jne    L89
  addl   $0x1,-0x8(%rbp)
  jmp    L47
L89:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L21
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L21:
  mov    $0x4,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L47:
  addl   $0x1,-0x4(%rbp)
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jae    L74
  cmpl   $0x3,-0x8(%rbp)
  jbe    L2
L74:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned syncsearch(unsigned *have, unsigned char *buf, unsigned len) {
  unsigned got;
  unsigned next;
  got = *have;
  next = 0;
  while (next < len && got < 4) {
    if ((int)(buf[next]) == (got < 2 ? 0 : 0xff))
      got++;
    else if (buf[next])
      got = 0;
    else
      got = 4 - got;
    next++;
  }
  *have = got;
  return next;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<syncsearch>:
  endbr64
  mov    %rdi,%r11
  mov    (%rdi),%ecx
  test   %edx,%edx
  je     L64
  cmp    $0x3,%ecx
  ja     L64
  push   %rbx
  mov    $0x0,%edi
  mov    $0x0,%ebx
  mov    $0x4,%r10d
  jmp    L47
L22:
  mov    %r10d,%eax
  sub    %ecx,%eax
  test   %r8b,%r8b
  cmovne %ebx,%eax
  mov    %eax,%ecx
L0:
  add    $0x1,%edi
  cmp    %edi,%edx
  jbe    L51
  cmp    $0x3,%ecx
  ja     L51
L47:
  mov    %edi,%eax
  movzbl (%rsi,%rax,1),%r8d
  movzbl %r8b,%r9d
  cmp    $0x2,%ecx
  sbb    %eax,%eax
  not    %eax
  movzbl %al,%eax
  cmp    %eax,%r9d
  jne    L22
  add    $0x1,%ecx
  jmp    L0
L64:
  mov    $0x0,%edi
  mov    %ecx,(%r11)
  mov    %edi,%eax
  ret
L51:
  mov    %ecx,(%r11)
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned syncsearch(unsigned *have, unsigned char *buf, unsigned len) {
  unsigned got;
  unsigned next;
  got = *have;
  next = 0;
  while (next < len && got < 4) {
    if ((int)(buf[next]) == (got < 2 ? 0 : 0xff))
      got++;
    else if (buf[next])
      got = 0;
    else
      got = 4 - got;
    next++;
  }
  *have = got;
  return next;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<syncsearch>:
  endbr64
  mov    %rdi,%r10
  mov    (%rdi),%edi
  test   %edx,%edx
  setne  %r9b
  cmp    $0x3,%edi
  setbe  %al
  and    %al,%r9b
  mov    $0x0,%eax
  je     L19
  mov    $0x4,%r11d
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L54:
  test   %r8b,%r8b
  jne    L8
  mov    %r11d,%ecx
  sub    %edi,%ecx
  cmp    $0x3,%ecx
  mov    %ecx,%edi
  setbe  %cl
L43:
  add    $0x1,%eax
  cmp    %eax,%edx
  jbe    L19
L79:
  test   %cl,%cl
  je     L19
L46:
  mov    %eax,%ecx
  cmp    $0x2,%edi
  movzbl (%rsi,%rcx,1),%r8d
  sbb    %ecx,%ecx
  not    %ecx
  cmp    %cl,%r8b
  jne    L54
  add    $0x1,%edi
  cmp    $0x3,%edi
  setbe  %cl
  add    $0x1,%eax
  cmp    %eax,%edx
  ja     L79
L19:
  mov    %edi,(%r10)
  ret
  nopl   0x0(%rax)
L8:
  mov    %r9d,%ecx
  xor    %edi,%edi
  jmp    L43
```

assistant: ```c
unsigned syncsearch(unsigned *have, unsigned char *buf, unsigned len) {
  unsigned got;
  unsigned next;
  got = *have;
  next = 0;
  while (next < len && got < 4) {
    if ((int)(buf[next]) == (got < 2 ? 0 : 0xff))
      got++;
    else if (buf[next])
      got = 0;
    else
      got = 4 - got;
    next++;
  }
  *have = got;
  return next;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<syncsearch>:
  endbr64
  mov    %rdi,%r10
  mov    (%rdi),%edi
  test   %edx,%edx
  setne  %r9b
  cmp    $0x3,%edi
  setbe  %al
  and    %al,%r9b
  mov    $0x0,%eax
  je     L10
  mov    $0x4,%r11d
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L72:
  test   %r8b,%r8b
  jne    L62
  mov    %r11d,%ecx
  sub    %edi,%ecx
  cmp    $0x3,%ecx
  mov    %ecx,%edi
  setbe  %cl
L58:
  add    $0x1,%eax
  cmp    %eax,%edx
  jbe    L10
L7:
  test   %cl,%cl
  je     L10
L11:
  mov    %eax,%ecx
  cmp    $0x2,%edi
  movzbl (%rsi,%rcx,1),%r8d
  sbb    %ecx,%ecx
  not    %ecx
  cmp    %cl,%r8b
  jne    L72
  add    $0x1,%edi
  cmp    $0x3,%edi
  setbe  %cl
  add    $0x1,%eax
  cmp    %eax,%edx
  ja     L7
L10:
  mov    %edi,(%r10)
  ret
  nopl   0x0(%rax)
L62:
  mov    %r9d,%ecx
  xor    %edi,%edi
  jmp    L58
```

assistant: ```c
unsigned syncsearch(unsigned *have, unsigned char *buf, unsigned len) {
  unsigned got;
  unsigned next;
  got = *have;
  next = 0;
  while (next < len && got < 4) {
    if ((int)(buf[next]) == (got < 2 ? 0 : 0xff))
      got++;
    else if (buf[next])
      got = 0;
    else
      got = 4 - got;
    next++;
  }
  *have = got;
  return next;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Synthese_Checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x4(%rbp)
  movw   $0x0,-0x2(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L13
L1:
  movswq -0x2(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L13:
  cmpw   $0xa,-0x2(%rbp)
  jle    L1
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short Synthese_Checksum(short *Statu_checksum) {
  short synthese = 0;
  short i = 0;
  for (i = 0; i < 12 - 1; i++) {
    synthese = synthese + Statu_checksum[i];
  }
  return synthese;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Synthese_Checksum>:
  endbr64
  lea    0x16(%rdi),%rdx
  mov    $0x0,%eax
L1:
  add    (%rdi),%ax
  add    $0x2,%rdi
  cmp    %rdx,%rdi
  jne    L1
  ret
```

assistant: ```c
short Synthese_Checksum(short *Statu_checksum) {
  short synthese = 0;
  short i = 0;
  for (i = 0; i < 12 - 1; i++) {
    synthese = synthese + Statu_checksum[i];
  }
  return synthese;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Synthese_Checksum>:
  endbr64
  lea    0x16(%rdi),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  add    (%rdi),%ax
  add    $0x2,%rdi
  cmp    %rdi,%rdx
  jne    L7
  ret
```

assistant: ```c
short Synthese_Checksum(short *Statu_checksum) {
  short synthese = 0;
  short i = 0;
  for (i = 0; i < 12 - 1; i++) {
    synthese = synthese + Statu_checksum[i];
  }
  return synthese;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Synthese_Checksum>:
  endbr64
  movdqu (%rdi),%xmm0
  movdqu (%rdi),%xmm2
  psrldq $0x8,%xmm0
  paddw  %xmm2,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddw  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  paddw  %xmm1,%xmm0
  pextrw $0x0,%xmm0,%eax
  add    0x10(%rdi),%ax
  add    0x12(%rdi),%ax
  add    0x14(%rdi),%ax
  ret
```

assistant: ```c
short Synthese_Checksum(short *Statu_checksum) {
  short synthese = 0;
  short i = 0;
  for (i = 0; i < 12 - 1; i++) {
    synthese = synthese + Statu_checksum[i];
  }
  return synthese;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim_leadspc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L15
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L61
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L24
L61:
  addq   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  jmp    L57
L24:
  nop
L57:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L54
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void trim_leadspc(char *line) {
  char *line_strt;
  char *ptr1, *ptr2;
  for (line_strt = line; *line_strt != '\0'; line_strt++)
    if (*line_strt != ' ' && *line_strt != '\t')
      break;
  for (ptr1 = line, ptr2 = line_strt; *ptr2 != '\0'; ptr1++, ptr2++)
    *ptr1 = *ptr2;
  *ptr1 = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim_leadspc>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L22
  mov    %rdi,%rax
  jmp    L45
L14:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L22
L45:
  cmp    $0x20,%dl
  je     L14
  cmp    $0x9,%dl
  je     L14
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L22
L1:
  mov    %dl,(%rdi)
  add    $0x1,%rdi
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L1
L22:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void trim_leadspc(char *line) {
  char *line_strt;
  char *ptr1, *ptr2;
  for (line_strt = line; *line_strt != '\0'; line_strt++)
    if (*line_strt != ' ' && *line_strt != '\t')
      break;
  for (ptr1 = line, ptr2 = line_strt; *ptr2 != '\0'; ptr1++, ptr2++)
    *ptr1 = *ptr2;
  *ptr1 = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim_leadspc>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L24
  mov    %rdi,%rax
  jmp    L42
L13:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L24
L42:
  cmp    $0x20,%dl
  je     L13
  cmp    $0x9,%dl
  jne    L51
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L42
L24:
  movb   $0x0,(%rdi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    %dl,(%rdi)
  add    $0x1,%rax
  add    $0x1,%rdi
L51:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L57
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void trim_leadspc(char *line) {
  char *line_strt;
  char *ptr1, *ptr2;
  for (line_strt = line; *line_strt != '\0'; line_strt++)
    if (*line_strt != ' ' && *line_strt != '\t')
      break;
  for (ptr1 = line, ptr2 = line_strt; *ptr2 != '\0'; ptr1++, ptr2++)
    *ptr1 = *ptr2;
  *ptr1 = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_leadspc>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  mov    %rdi,%rdx
  jmp    L14
L16:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L26
L14:
  cmp    $0x20,%al
  je     L16
  cmp    $0x9,%al
  je     L16
  nopl   0x0(%rax)
L2:
  add    $0x1,%rdx
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L2
L26:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void trim_leadspc(char *line) {
  char *line_strt;
  char *ptr1, *ptr2;
  for (line_strt = line; *line_strt != '\0'; line_strt++)
    if (*line_strt != ' ' && *line_strt != '\t')
      break;
  for (ptr1 = line, ptr2 = line_strt; *ptr2 != '\0'; ptr1++, ptr2++)
    *ptr1 = *ptr2;
  *ptr1 = '\0';
}
```