ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ip_hdr_csum>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x5,%esi
  je     L68
  lea    (%rsi,%rsi,1),%edx
  test   %edx,%edx
  jle    L9
  lea    -0x1(%rdx),%eax
  cmp    $0x6,%eax
  jbe    L78
  mov    %edx,%esi
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %rdi,%rax
  shr    $0x3,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax,%rax,1)
L28:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm3
  punpcklwd %xmm2,%xmm0
  punpckhwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L28
  movdqa %xmm1,%xmm0
  mov    %edx,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffff8,%esi
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x7,%dl
  je     L52
L48:
  movslq %esi,%r8
  lea    (%r8,%r8,1),%rdi
  movzwl (%rcx,%r8,2),%r8d
  add    %r8d,%eax
  lea    0x1(%rsi),%r8d
  cmp    %edx,%r8d
  jge    L52
  movzwl 0x2(%rcx,%rdi,1),%r8d
  add    %r8d,%eax
  lea    0x2(%rsi),%r8d
  cmp    %edx,%r8d
  jge    L52
  movzwl 0x4(%rcx,%rdi,1),%r8d
  add    %r8d,%eax
  lea    0x3(%rsi),%r8d
  cmp    %edx,%r8d
  jge    L52
  movzwl 0x6(%rcx,%rdi,1),%r8d
  add    %r8d,%eax
  lea    0x4(%rsi),%r8d
  cmp    %r8d,%edx
  jle    L52
  movzwl 0x8(%rcx,%rdi,1),%r8d
  add    %r8d,%eax
  lea    0x5(%rsi),%r8d
  cmp    %r8d,%edx
  jle    L52
  movzwl 0xa(%rcx,%rdi,1),%r8d
  add    $0x6,%esi
  add    %r8d,%eax
  cmp    %esi,%edx
  jle    L52
  movzwl 0xc(%rcx,%rdi,1),%edx
  add    %edx,%eax
L52:
  movzwl %ax,%edx
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  add    %edx,%eax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  movzwl 0x2(%rdi),%eax
  movzwl (%rdi),%edx
  add    %eax,%edx
  movzwl 0x4(%rdi),%eax
  add    %eax,%edx
  movzwl 0x6(%rdi),%eax
  add    %eax,%edx
  movzwl 0x8(%rdi),%eax
  add    %eax,%edx
  movzwl 0xa(%rdi),%eax
  add    %eax,%edx
  movzwl 0xc(%rdi),%eax
  add    %eax,%edx
  movzwl 0xe(%rdi),%eax
  add    %eax,%edx
  movzwl 0x10(%rdi),%eax
  add    %eax,%edx
  movzwl 0x12(%rdi),%eax
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  ret
L78:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
unsigned short ip_hdr_csum(unsigned int *ip, int len) {
  unsigned int sum = 0;
  int i;
  unsigned short *sp = (unsigned short *)ip;
  if (len == 5) {
    sum = sp[0] + sp[1] + sp[2] + sp[3] + sp[4] + sp[5] + sp[6] + sp[7] + sp[8] + sp[9];
  } else {
    for (i = 0; i < 2 * len; i++)
      sum += sp[i];
  }
  sum = (sum & 0xFFFF) + (sum >> 16);
  sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setge  %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Compare(const void *A, const void *B) {
  int a = *(int *)A;
  int b = *(int *)B;
  return (a >= b) - (a <= b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Compare>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  movzbl %al,%eax
  setle  %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int Compare(const void *A, const void *B) {
  int a = *(int *)A;
  int b = *(int *)B;
  return (a >= b) - (a <= b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Compare>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  setle  %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int Compare(const void *A, const void *B) {
  int a = *(int *)A;
  int b = *(int *)B;
  return (a >= b) - (a <= b);
}
```
user: What is the c source code of the assembly code below:

```asm
<Compare>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setge  %al
  setle  %dl
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int Compare(const void *A, const void *B) {
  int a = *(int *)A;
  int b = *(int *)B;
  return (a >= b) - (a <= b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D33
type: string
name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D34
type: string

tool: D33: r

tool: D9: archivo1.txt

tool: D34: %s

assistant: ```c
int main() {
  char line[255];
  FILE *fpointer = fopen("archivo1.txt", "r");
  fgets(line, 255, fpointer);
  printf("%s", line);
  fgets(line, 255, fpointer);
  printf("%s", line);
  fclose(fpointer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rsp,%rbp
  mov    %rax,%rdx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    $0xff,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string

tool: D24: r

tool: D6: archivo1.txt

tool: D23: %s

assistant: ```c
int main() {
  char line[255];
  FILE *fpointer = fopen("archivo1.txt", "r");
  fgets(line, 255, fpointer);
  printf("%s", line);
  fgets(line, 255, fpointer);
  printf("%s", line);
  fclose(fpointer);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%rsi
  lea    D13(%rip),%rdi
  push   %r12
  lea    D28(%rip),%r13
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <fopen@plt>
  mov    $0xff,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string

tool: D6: r

tool: D13: archivo1.txt

tool: D28: %s

assistant: ```c
int main() {
  char line[255];
  FILE *fpointer = fopen("archivo1.txt", "r");
  fgets(line, 255, fpointer);
  printf("%s", line);
  fgets(line, 255, fpointer);
  printf("%s", line);
  fclose(fpointer);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  lea    D3(%rip),%rdi
  push   %r12
  lea    D26(%rip),%r13
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <fopen@plt>
  mov    $0xff,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D26
type_infered: string

tool: D4: r

tool: D3: archivo1.txt

tool: D26: %s

assistant: ```c
int main() {
  char line[255];
  FILE *fpointer = fopen("archivo1.txt", "r");
  fgets(line, 255, fpointer);
  printf("%s", line);
  fgets(line, 255, fpointer);
  printf("%s", line);
  fclose(fpointer);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f13>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D28(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D24(%rip),%xmm2
  movq   D22(%rip),%xmm1
  andpd  %xmm2,%xmm0
  orpd   %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <bar@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: f64
name: parse_data
arguments: label: D24
type_guessed: byte[8]
name: parse_data
arguments: label: D22
type_guessed: f64

tool: D28: 7.5

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D22: 2

assistant: ```c
double f13(double x) {
  double tmp1 = 7.5;
  double tmp2 = __builtin_copysign(2.0, x);
  return bar(tmp1 * tmp2, tmp2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f13>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm0,%xmm1
  andpd  D19(%rip),%xmm1
  orpd   D15(%rip),%xmm1
  movapd %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  call   <bar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D19
datatype: byte[16]
name: read_data
arguments: label: D15
datatype: f64[2]
name: read_data
arguments: label: D7
datatype: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [2.0,0.0]}

tool: D7: 7.5

assistant: ```c
double f13(double x) {
  double tmp1 = 7.5;
  double tmp2 = __builtin_copysign(2.0, x);
  return bar(tmp1 * tmp2, tmp2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f13>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D13(%rip),%xmm0
  andpd  D27(%rip),%xmm1
  orpd   D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  jmp    1050 <bar@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: f64
name: read_data
arguments: data_label: D27
datatype: byte[16]
name: read_data
arguments: data_label: D9
datatype: f64[2]

tool: D13: 7.5

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D9": [2.0,0.0]}

assistant: ```c
double f13(double x) {
  double tmp1 = 7.5;
  double tmp2 = __builtin_copysign(2.0, x);
  return bar(tmp1 * tmp2, tmp2);
}
```
user: What is the c source code of the assembly code below:

```asm
<f13>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  andpd  D5(%rip),%xmm1
  orpd   D10(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  jmp    1050 <bar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D5
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D10
type_infered: f64[2]

tool: D6: 7.5

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D10": [2.0,0.0]}

assistant: ```c
double f13(double x) {
  double tmp1 = 7.5;
  double tmp2 = __builtin_copysign(2.0, x);
  return bar(tmp1 * tmp2, tmp2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<compression_G>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x2028(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  call   <xor_blocks@plt>
  lea    0x1020(%rsp),%r14
  lea    0x1220(%rsp),%r15
  mov    %r15,%r12
  mov    $0x0,%r13d
  lea    0x20(%rsp),%rax
  mov    %rax,(%rsp)
L8:
  lea    -0x200(%r12),%rbx
  mov    %r13,%rbp
  shl    $0x6,%rbp
  add    (%rsp),%rbp
L55:
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x40,%rbx
  add    $0x40,%rbp
  cmp    %r12,%rbx
  jne    L55
  add    $0x8,%r13
  add    $0x200,%r12
  cmp    $0x40,%r13
  jne    L8
  lea    0x1000(%r14),%rbp
  mov    %r14,%rbx
L0:
  lea    0xc0(%rbx),%rcx
  lea    0x80(%rbx),%rdx
  lea    0x40(%rbx),%rsi
  lea    0x1c0(%rbx),%rax
  push   %rax
  lea    0x180(%rbx),%rax
  push   %rax
  lea    0x140(%rbx),%r9
  lea    0x100(%rbx),%r8
  mov    %rbx,%rdi
  call   <P@plt>
  add    $0x200,%rbx
  add    $0x10,%rsp
  cmp    %rbp,%rbx
  jne    L0
  mov    %r14,%rbx
L64:
  lea    0x600(%rbx),%rcx
  lea    0x400(%rbx),%rdx
  lea    0x200(%rbx),%rsi
  lea    0xe00(%rbx),%rax
  push   %rax
  lea    0xc00(%rbx),%rax
  push   %rax
  lea    0xa00(%rbx),%r9
  lea    0x800(%rbx),%r8
  mov    %rbx,%rdi
  call   <P@plt>
  add    $0x40,%rbx
  add    $0x10,%rsp
  cmp    %r15,%rbx
  jne    L64
  mov    (%rsp),%r12
  add    $0x200,%r12
  mov    $0x0,%r13d
L34:
  lea    -0x200(%r12),%rbx
  mov    %r13,%rbp
  shl    $0x6,%rbp
  add    %r14,%rbp
L13:
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x40,%rbx
  add    $0x40,%rbp
  cmp    %r12,%rbx
  jne    L13
  add    $0x8,%r13
  add    $0x200,%r12
  cmp    $0x40,%r13
  jne    L34
  mov    0x18(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rdi
  call   <xor_blocks@plt>
  lea    0x20(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <xor_blocks@plt>
  mov    0x2028(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x2038,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void compression_G(uint8_t *Result, uint8_t *X, uint8_t *Y) {
  uint8_t R_array[1024];
  xor_blocks(R_array, X, Y);
  uint8_t R[8][8][16];
  int h = 0;
  for (int i = 0; i < 8; i++) {
    for (int j = 0; j < 8; j++) {
      memcpy(R[i][j], R_array + 16 * h, 16);
      h++;
    }
  }
  for (int i = 0; i < 8; i++) {
    P(R[i][0], R[i][1], R[i][2], R[i][3], R[i][4], R[i][5], R[i][6], R[i][7]);
  }
  for (int j = 0; j < 8; j++) {
    P(R[0][j], R[1][j], R[2][j], R[3][j], R[4][j], R[5][j], R[6][j], R[7][j]);
  }
  h = 0;
  for (int i = 0; i < 8; i++) {
    for (int j = 0; j < 8; j++) {
      memcpy(R_array + 16 * h, R[i][j], 16);
      h++;
    }
  }
  xor_blocks(Result, X, Y);
  xor_blocks(Result, Result, R_array);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x1e8480,%edi
  call   <sieve@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L20
L25:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L37
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L31
L37:
  mov    -0x10(%rbp),%rax
L31:
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L20:
  cmpq   $0x1e8480,-0x18(%rbp)
  jle    L25
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: %lld

assistant: ```c
void main() {
  int *is_prime = sieve(2000000);
  long i;
  long long sum = 0;
  for (i = 0; i < 2000001; i++)
    sum = is_prime[i] ? sum + i : sum;
  printf("%lld", sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve@plt>
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L3
L30:
  add    $0x1,%rdx
  cmp    $0x1e8481,%rdx
  je     L26
L3:
  cmpl   $0x0,(%rax,%rdx,4)
  je     L30
  add    %rdx,%rsi
  jmp    L30
L26:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: %lld

assistant: ```c
void main() {
  int *is_prime = sieve(2000000);
  long i;
  long long sum = 0;
  for (i = 0; i < 2000001; i++)
    sum = is_prime[i] ? sum + i : sum;
  printf("%lld", sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve@plt>
  xor    %esi,%esi
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rax,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L1
  add    %rdx,%rsi
L1:
  add    $0x1,%rdx
  cmp    $0x1e8481,%rdx
  jne    L18
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: %lld

assistant: ```c
void main() {
  int *is_prime = sieve(2000000);
  long i;
  long long sum = 0;
  for (i = 0; i < 2000001; i++)
    sum = is_prime[i] ? sum + i : sum;
  printf("%lld", sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e8480,%edi
  call   <sieve@plt>
  xor    %esi,%esi
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    (%rax,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L7
  add    %rdx,%rsi
L7:
  add    $0x1,%rdx
  cmp    $0x1e8481,%rdx
  jne    L19
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: %lld

assistant: ```c
void main() {
  int *is_prime = sieve(2000000);
  long i;
  long long sum = 0;
  for (i = 0; i < 2000001; i++)
    sum = is_prime[i] ? sum + i : sum;
  printf("%lld", sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x18,%esi
  mov    $0x10,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x11,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string

tool: D15: %d


assistant: ```c
int main() {
  printf("%d\n", gcd(16, 24));
  printf("%d\n", gcd(17, 31));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x18,%esi
  mov    $0x10,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x11,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main() {
  printf("%d\n", gcd(16, 24));
  printf("%d\n", gcd(17, 31));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x18,%esi
  mov    $0x10,%edi
  lea    D5(%rip),%rbp
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x11,%edi
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: %d


assistant: ```c
int main() {
  printf("%d\n", gcd(16, 24));
  printf("%d\n", gcd(17, 31));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x18,%esi
  mov    $0x10,%edi
  lea    D2(%rip),%rbp
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x11,%edi
  call   <gcd@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  printf("%d\n", gcd(16, 24));
  printf("%d\n", gcd(17, 31));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <powf@plt>
  movd   %xmm0,%eax
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  D7(%rip),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movd   %eax,%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: f64
name: unpack_data
arguments: data_label: D7
datatype: byte[4]

tool: D12: 1

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float f(float x, float y) {
  float e, f;
  e = exp(1.0);
  f = powf(e, x) / (x * x + y * y - 1);
  return f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  movsd  D12(%rip),%xmm0
  call   <exp@plt>
  movss  0x8(%rsp),%xmm1
  call   <powf@plt>
  movss  0x8(%rsp),%xmm3
  mulss  %xmm3,%xmm3
  movaps %xmm3,%xmm1
  movss  0xc(%rsp),%xmm2
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm1
  subss  D1(%rip),%xmm1
  divss  %xmm1,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: f64
name: disassemble_data
arguments: tag: D1
data_type: byte[4]

tool: D12: 1

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float f(float x, float y) {
  float e, f;
  e = exp(1.0);
  f = powf(e, x) / (x * x + y * y - 1);
  return f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movsd  D8(%rip),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <exp@plt>
  movss  0x8(%rsp),%xmm2
  movaps %xmm2,%xmm1
  call   <powf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm3
  mulss  %xmm2,%xmm2
  mulss  %xmm3,%xmm3
  addss  %xmm3,%xmm2
  subss  D3(%rip),%xmm2
  add    $0x18,%rsp
  divss  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: f64
name: retrieve_data
arguments: tag: D3
type: byte[4]

tool: D8: 1

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float f(float x, float y) {
  float e, f;
  e = exp(1.0);
  f = powf(e, x) / (x * x + y * y - 1);
  return f;
}
```