ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fib>:
  endbr64
  movsd  D93(%rip),%xmm2
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm2
  jbe    L75
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  sub    $0x28,%rsp
  movsd  D65(%rip),%xmm5
  movapd %xmm0,%xmm3
  subsd  %xmm5,%xmm3
  comisd %xmm3,%xmm2
  jbe    L86
  subsd  %xmm2,%xmm1
  comisd %xmm1,%xmm2
  jbe    L9
L13:
  addsd  %xmm3,%xmm1
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L86:
  movapd %xmm3,%xmm4
  subsd  %xmm5,%xmm4
  comisd %xmm4,%xmm2
  jbe    L57
L93:
  subsd  %xmm2,%xmm3
  comisd %xmm3,%xmm2
  jbe    L115
L28:
  subsd  %xmm2,%xmm1
  addsd  %xmm4,%xmm3
  comisd %xmm1,%xmm2
  ja     L13
L9:
  movapd %xmm1,%xmm4
  subsd  %xmm5,%xmm4
  comisd %xmm4,%xmm2
  jbe    L65
L46:
  subsd  %xmm2,%xmm1
  comisd %xmm1,%xmm2
  jbe    L77
L19:
  addsd  %xmm4,%xmm1
  add    $0x28,%rsp
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm4,%xmm0
  subsd  %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  call   <fib>
  mov    D93(%rip),%rax
  movsd  0x8(%rsp),%xmm4
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm2
  subsd  %xmm2,%xmm4
  movapd %xmm4,%xmm0
  call   <fib>
  movsd  (%rsp),%xmm4
  mov    D65(%rip),%rax
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  movq   %rax,%xmm5
  mov    D93(%rip),%rax
  addsd  %xmm0,%xmm4
  movq   %rax,%xmm2
  jmp    L93
  nopl   (%rax)
L77:
  movapd %xmm1,%xmm0
  movsd  %xmm4,0x18(%rsp)
  subsd  %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <fib>
  mov    D93(%rip),%rax
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  call   <fib>
  movsd  (%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  addsd  %xmm0,%xmm1
  jmp    L19
  nopl   (%rax)
L65:
  movapd %xmm4,%xmm0
  movsd  %xmm1,0x18(%rsp)
  subsd  %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  call   <fib>
  mov    D93(%rip),%rax
  movsd  0x8(%rsp),%xmm4
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm2
  subsd  %xmm2,%xmm4
  movapd %xmm4,%xmm0
  call   <fib>
  movsd  (%rsp),%xmm4
  mov    D65(%rip),%rax
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  movq   %rax,%xmm5
  mov    D93(%rip),%rax
  addsd  %xmm0,%xmm4
  movq   %rax,%xmm2
  jmp    L46
  nopl   (%rax)
L115:
  movapd %xmm3,%xmm0
  movsd  %xmm1,0x18(%rsp)
  subsd  %xmm5,%xmm0
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <fib>
  mov    D93(%rip),%rax
  movsd  0x8(%rsp),%xmm3
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm2
  subsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  call   <fib>
  movsd  (%rsp),%xmm3
  mov    D65(%rip),%rax
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm4
  movq   %rax,%xmm5
  mov    D93(%rip),%rax
  addsd  %xmm0,%xmm3
  movq   %rax,%xmm2
  jmp    L28
```

tool_calls: name: retrieve_data
arguments: tag: D93
type: f64
name: retrieve_data
arguments: tag: D65
type: f64

tool: D93: 2

tool: D65: 1

assistant: ```c
double fib(double n) {
  if (n < 2.)
    return n;
  else
    return fib(n - 1.) + fib(n - 2.);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x64(%rbp)
  jmp    L73
L27:
  lea    -0x60(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x64(%rbp)
L73:
  mov    -0x68(%rbp),%eax
  cmp    %eax,-0x64(%rbp)
  jl     L27
  movl   $0x0,-0x64(%rbp)
  jmp    L62
L54:
  mov    -0x64(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  jmp    L60
L3:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  lea    -0x2(%rax),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
L60:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jg     L3
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L6
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
L6:
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x64(%rbp)
L62:
  mov    -0x68(%rbp),%eax
  cmp    %eax,-0x64(%rbp)
  jne    L54
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string

tool: D8: %d

tool: D13: %d


assistant: ```c
int main() {
  int tc;
  int i = 0;
  int cycle[10];
  int height[10];
  scanf("%d", &tc);
  for (i = 0; i < tc; i++)
    scanf("%d", &cycle[i]);
  i = 0;
  while (i != tc) {
    height[i] = 1;
    while (cycle[i] > 1) {
      cycle[i] = cycle[i] - 2;
      height[i] = 2 * height[i] + 1;
    }
    if (cycle[i] == 1)
      height[i] = 2 * height[i];
    printf("%d\n", height[i]);
    i++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L50
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L94:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L94
L50:
  cmpl   $0x0,0xc(%rsp)
  je     L5
  lea    0x40(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
  jmp    L22
L12:
  mov    (%rdi),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  je     L5
L22:
  mov    %rbp,%rdi
  movl   $0x1,0x0(%rbp)
  mov    0x10(%rsp,%rbx,4),%ecx
  cmp    $0x1,%ecx
  jle    L30
  mov    %ecx,%esi
  mov    %ecx,%eax
  mov    $0x1,%edx
L54:
  lea    0x1(%rdx,%rdx,1),%edx
  sub    $0x2,%eax
  cmp    $0x1,%eax
  jg     L54
  lea    -0x2(%rsi),%eax
  and    $0xfffffffe,%eax
  sub    $0x2,%ecx
  sub    %eax,%ecx
  mov    %ecx,0x10(%rsp,%rbx,4)
  mov    %edx,(%rdi)
L30:
  cmp    $0x1,%ecx
  jne    L12
  shll   (%rdi)
  jmp    L12
L5:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D20
datatype: string

tool: D0: %d

tool: D20: %d


assistant: ```c
int main() {
  int tc;
  int i = 0;
  int cycle[10];
  int height[10];
  scanf("%d", &tc);
  for (i = 0; i < tc; i++)
    scanf("%d", &cycle[i]);
  i = 0;
  while (i != tc) {
    height[i] = 1;
    while (cycle[i] > 1) {
      cycle[i] = cycle[i] - 2;
      height[i] = 2 * height[i] + 1;
    }
    if (cycle[i] == 1)
      height[i] = 2 * height[i];
    printf("%d\n", height[i]);
    i++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L58
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L8
L58:
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D18(%rip),%r12
  test   %eax,%eax
  je     L61
  nopl   0x0(%rax)
L32:
  mov    (%rbx),%edx
  cmp    $0x1,%edx
  jle    L0
  mov    %edx,%eax
  mov    $0x1,%esi
  xchg   %ax,%ax
L64:
  sub    $0x2,%eax
  lea    0x1(%rsi,%rsi,1),%esi
  cmp    $0x1,%eax
  ja     L64
  and    $0x1,%edx
  mov    %edx,(%rbx)
L74:
  cmp    $0x1,%edx
  lea    (%rsi,%rsi,1),%eax
  mov    %r12,%rdi
  cmove  %eax,%esi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jne    L32
L61:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%esi
  jmp    L74
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D12: %d

tool: D18: %d


assistant: ```c
int main() {
  int tc;
  int i = 0;
  int cycle[10];
  int height[10];
  scanf("%d", &tc);
  for (i = 0; i < tc; i++)
    scanf("%d", &cycle[i]);
  i = 0;
  while (i != tc) {
    height[i] = 1;
    while (cycle[i] > 1) {
      cycle[i] = cycle[i] - 2;
      height[i] = 2 * height[i] + 1;
    }
    if (cycle[i] == 1)
      height[i] = 2 * height[i];
    printf("%d\n", height[i]);
    i++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L65
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L17
L65:
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D1(%rip),%r12
  test   %eax,%eax
  je     L2
  nopl   0x0(%rax)
L70:
  mov    (%rbx),%edx
  cmp    $0x1,%edx
  jle    L31
  mov    %edx,%eax
  mov    $0x1,%esi
  xchg   %ax,%ax
L49:
  sub    $0x2,%eax
  lea    0x1(%rsi,%rsi,1),%esi
  cmp    $0x1,%eax
  ja     L49
  and    $0x1,%edx
  mov    %edx,(%rbx)
L24:
  cmp    $0x1,%edx
  lea    (%rsi,%rsi,1),%eax
  mov    %r12,%rdi
  cmove  %eax,%esi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jne    L70
L2:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0x1,%esi
  jmp    L24
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D14: %d

tool: D1: %d


assistant: ```c
int main() {
  int tc;
  int i = 0;
  int cycle[10];
  int height[10];
  scanf("%d", &tc);
  for (i = 0; i < tc; i++)
    scanf("%d", &cycle[i]);
  i = 0;
  while (i != tc) {
    height[i] = 1;
    while (cycle[i] > 1) {
      cycle[i] = cycle[i] - 2;
      height[i] = 2 * height[i] + 1;
    }
    if (cycle[i] == 1)
      height[i] = 2 * height[i];
    printf("%d\n", height[i]);
    i++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cpuid_pkg_MaxPhysicalProcessorCores>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%r8
  lea    -0x18(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <cpuidInput_rax_rcx@plt>
  mov    -0x20(%rbp),%eax
  sar    $0x1a,%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int cpuid_pkg_MaxPhysicalProcessorCores(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leafa = 4;
  int leafc = 0;
  cpuidInput_rax_rcx(leafa, leafc, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((31)) - ((26)) + 1)) - 1) << ((26)))) >> (26)) + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<cpuid_pkg_MaxPhysicalProcessorCores>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <cpuidInput_rax_rcx@plt>
  mov    0x8(%rsp),%eax
  sar    $0x1a,%eax
  add    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_pkg_MaxPhysicalProcessorCores(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leafa = 4;
  int leafc = 0;
  cpuidInput_rax_rcx(leafa, leafc, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((31)) - ((26)) + 1)) - 1) << ((26)))) >> (26)) + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cpuid_pkg_MaxPhysicalProcessorCores>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    $0x4,%edi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <cpuidInput_rax_rcx@plt>
  mov    0x8(%rsp),%eax
  sar    $0x1a,%eax
  add    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_pkg_MaxPhysicalProcessorCores(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leafa = 4;
  int leafc = 0;
  cpuidInput_rax_rcx(leafa, leafc, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((31)) - ((26)) + 1)) - 1) << ((26)))) >> (26)) + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpuid_pkg_MaxPhysicalProcessorCores>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    $0x4,%edi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <cpuidInput_rax_rcx@plt>
  mov    0x8(%rsp),%eax
  sar    $0x1a,%eax
  add    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_pkg_MaxPhysicalProcessorCores(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leafa = 4;
  int leafc = 0;
  cpuidInput_rax_rcx(leafa, leafc, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((31)) - ((26)) + 1)) - 1) << ((26)))) >> (26)) + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<half2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L32
L4:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x0,-0xc(%rbp)
  jg     L4
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L38
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L38
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L38:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int half2(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 2 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<half2>:
  endbr64
  mov    %rdi,%r8
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L48
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  mov    $0x0,%eax
L40:
  mov    (%rcx),%edx
  lea    (%rdx,%rax,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,(%rcx)
  sub    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L40
L38:
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L47
  movslq %edx,%rcx
  cmpl   $0x0,(%r8,%rcx,4)
  jne    L47
  sub    $0x1,%edx
  mov    %edx,(%r8)
L47:
  ret
L48:
  mov    $0x0,%eax
  jmp    L38
```

assistant: ```c
int half2(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 2 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<half2>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L33
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  mov    (%rcx),%edx
  sub    $0x4,%rcx
  lea    (%rdx,%rax,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,0x4(%rcx)
  cmp    %rdi,%rcx
  jne    L16
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L25
  movslq %edx,%rcx
  mov    (%r8,%rcx,4),%ecx
  test   %ecx,%ecx
  jne    L25
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
L25:
  ret
```

assistant: ```c
int half2(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 2 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<half2>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L38
  movslq %edx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rcx
  lea    -0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rdx),%eax
  shl    $0x2,%rax
  sub    %rax,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L20:
  mov    (%rcx),%edx
  sub    $0x4,%rcx
  lea    (%rdx,%rax,2),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,0x4(%rcx)
  cmp    %rdi,%rcx
  jne    L20
  mov    (%r8),%edx
  cmp    $0x1,%edx
  jle    L22
  movslq %edx,%rcx
  mov    (%r8,%rcx,4),%ecx
  test   %ecx,%ecx
  jne    L22
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
  nopl   0x0(%rax)
L38:
  xor    %eax,%eax
L22:
  ret
```

assistant: ```c
int half2(int *x) {
  int i, c = 0, s;
  for (i = x[0]; i >= 1; i--) {
    s = c * 2 + x[i];
    c = s % 2;
    x[i] = s / 2;
  }
  if (x[0] > 1 && x[x[0]] == 0)
    x[0]--;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L26
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x10(%rbp)
  jmp    L23
L29:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L32
L26:
  nop
L32:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D0
type_guessed: string

tool: D10: %-16s: 

tool: D0: %02x 

assistant: ```c
void scan(const char *s, const char *t, const char *f, void *p, size_t n) {
  char *v;
  size_t i;
  if (sscanf(s, f, p) != 1)
    return;
  v = p;
  printf("%-16s: ", t);
  for (i = 0; i < n; i++)
    printf("%02x ", v[i] & 0xff);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scan>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%rbp
  mov    %r8,%r12
  mov    %rcx,%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L10
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12,%r12
  je     L1
  mov    %rbp,%rbx
  add    %r12,%rbp
  lea    D13(%rip),%r12
L2:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L33
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D18: %-16s: 

tool: D13: %02x 

assistant: ```c
void scan(const char *s, const char *t, const char *f, void *p, size_t n) {
  char *v;
  size_t i;
  if (sscanf(s, f, p) != 1)
    return;
  v = p;
  printf("%-16s: ", t);
  for (i = 0; i < n; i++)
    printf("%02x ", v[i] & 0xff);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scan>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  mov    %r12,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L5
  add    %rbx,%rbp
  lea    D8(%rip),%r12
L18:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L18
L5:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D8
type: string

tool: D14: %-16s: 

tool: D8: %02x 

assistant: ```c
void scan(const char *s, const char *t, const char *f, void *p, size_t n) {
  char *v;
  size_t i;
  if (sscanf(s, f, p) != 1)
    return;
  v = p;
  printf("%-16s: ", t);
  for (i = 0; i < n; i++)
    printf("%02x ", v[i] & 0xff);
  printf("\n");
}
```