ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<BTIC4B_DecImageClrDec2T_RCT>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    %r8d,%eax
  sar    %eax
  sub    %eax,%esi
  mov    %esi,%r13d
  lea    (%r8,%rsi,1),%ebx
  test   $0x40,%dil
  je     L57
  mov    %r9d,%eax
  sar    %eax
  sub    %eax,%ebp
  add    %ebp,%r9d
  mov    0x40(%rsp),%eax
  sar    %eax
  sub    %eax,%r12d
  mov    %r12d,%eax
  add    0x40(%rsp),%eax
  lea    0x0(%rbp,%r12,1),%edx
  sar    $0x2,%edx
  sub    %edx,%r13d
  lea    0x0(%rbp,%r13,1),%r14d
  lea    (%r12,%r13,1),%r15d
  lea    (%r9,%rax,1),%edx
  sar    $0x2,%edx
  sub    %edx,%ebx
  lea    (%r9,%rbx,1),%ebp
  lea    (%rax,%rbx,1),%r12d
L32:
  mov    %r15d,%eax
  or     %r13d,%eax
  or     %r14d,%eax
  shr    $0x8,%eax
  jne    L14
L9:
  mov    %r12d,%eax
  or     %ebx,%eax
  or     %ebp,%eax
  shr    $0x8,%eax
  jne    L40
L39:
  mov    0x48(%rsp),%rax
  mov    %r15d,(%rax)
  mov    0x50(%rsp),%rax
  mov    %r13d,(%rax)
  mov    0x58(%rsp),%rax
  mov    %r14d,(%rax)
  mov    0x60(%rsp),%rax
  mov    %r12d,(%rax)
  mov    0x68(%rsp),%rax
  mov    %ebx,(%rax)
  mov    0x70(%rsp),%rax
  mov    %ebp,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  lea    (%rdx,%rcx,1),%eax
  sar    $0x2,%eax
  sub    %eax,%r13d
  lea    (%rdx,%r13,1),%r14d
  lea    (%rcx,%r13,1),%r15d
  sub    %eax,%ebx
  add    %ebx,%ebp
  add    %ebx,%r12d
  jmp    L32
L14:
  mov    %r15d,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%r15d
  mov    %r13d,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%r13d
  mov    %r14d,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%r14d
  jmp    L9
L40:
  mov    %r12d,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <lqtvq_clamp255@plt>
  mov    %eax,%ebp
  jmp    L39
```

assistant: ```c
void BTIC4B_DecImageClrDec2T_RCT(int tag, int acy, int acu, int acv, int dcy, int dcu, int dcv, int *rr0, int *rg0, int *rb0, int *rr1, int *rg1, int *rb1) {
  int mcy, mcu, mcv;
  int ncy, ncu, ncv;
  int cr0, cg0, cb0;
  int cr3, cg3, cb3;
  mcy = acy - (dcy >> 1);
  ncy = mcy + dcy;
  mcu = acu - (dcu >> 1);
  ncu = mcu + dcu;
  mcv = acv - (dcv >> 1);
  ncv = mcv + dcv;
  if (tag & 0x40) {
    cg0 = mcy - ((mcu + mcv) >> 2);
    cb0 = cg0 + mcu;
    cr0 = cg0 + mcv;
    cg3 = ncy - ((ncu + ncv) >> 2);
    cb3 = cg3 + ncu;
    cr3 = cg3 + ncv;
  } else {
    cg0 = mcy - ((acu + acv) >> 2);
    cb0 = cg0 + acu;
    cr0 = cg0 + acv;
    cg3 = ncy - ((acu + acv) >> 2);
    cb3 = cg3 + acu;
    cr3 = cg3 + acv;
  }
  if ((cr0 | cg0 | cb0) >> 8) {
    cr0 = lqtvq_clamp255(cr0);
    cg0 = lqtvq_clamp255(cg0);
    cb0 = lqtvq_clamp255(cb0);
  }
  if ((cr3 | cg3 | cb3) >> 8) {
    cr3 = lqtvq_clamp255(cr3);
    cg3 = lqtvq_clamp255(cg3);
    cb3 = lqtvq_clamp255(cb3);
  }
  *rr0 = cr0;
  *rg0 = cg0;
  *rb0 = cb0;
  *rr1 = cr3;
  *rg1 = cg3;
  *rb1 = cb3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unique_id_to_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%eax
  imul   $0x6b5fca6b,%rax,%rax
  shr    $0x20,%rax
  shr    $0x16,%eax
  add    $0x708,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x6b5fca6b,%rax,%rax
  shr    $0x20,%rax
  shr    $0x16,%eax
  imul   $0x989680,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%eax
  imul   $0x6b5fca6b,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x6b5fca6b,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  imul   $0x98968,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0xc,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unique_id_to_date(unsigned int id, int *y, int *m, int *d) {
  *y = id / 10000000 + 1800;
  *m = ((id % 10000000) / 625000) + 1;
  *d = ((id % 625000) / 15625) + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unique_id_to_date>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  mov    %rdx,%r8
  mov    %rcx,%rsi
  mov    %eax,%edx
  imul   $0x6b5fca6b,%rdx,%rdx
  mov    %rdx,%rcx
  shr    $0x36,%rcx
  lea    0x708(%rcx),%r9d
  mov    %r9d,(%rdi)
  imul   $0x989680,%ecx,%edi
  mov    %eax,%ecx
  sub    %edi,%ecx
  imul   $0x6b5fca6b,%rcx,%rcx
  shr    $0x32,%rcx
  add    $0x1,%ecx
  mov    %ecx,(%r8)
  shr    $0x32,%rdx
  imul   $0x98968,%edx,%edx
  sub    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x2c,%rax
  add    $0x1,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void unique_id_to_date(unsigned int id, int *y, int *m, int *d) {
  *y = id / 10000000 + 1800;
  *m = ((id % 10000000) / 625000) + 1;
  *d = ((id % 625000) / 15625) + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unique_id_to_date>:
  endbr64
  mov    %rdx,%r9
  mov    %edi,%edx
  mov    %edi,%eax
  mov    %rcx,%r8
  imul   $0x6b5fca6b,%rdx,%rdx
  mov    %rdx,%rdi
  shr    $0x32,%rdx
  shr    $0x36,%rdi
  imul   $0x98968,%edx,%edx
  mov    %rdi,%rcx
  lea    0x708(%rdi),%edi
  mov    %edi,(%rsi)
  imul   $0x989680,%ecx,%esi
  mov    %eax,%ecx
  sub    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  sub    %esi,%ecx
  imul   $0x6b5fca6b,%rcx,%rcx
  shr    $0x2c,%rax
  add    $0x1,%eax
  shr    $0x32,%rcx
  add    $0x1,%ecx
  mov    %ecx,(%r9)
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void unique_id_to_date(unsigned int id, int *y, int *m, int *d) {
  *y = id / 10000000 + 1800;
  *m = ((id % 10000000) / 625000) + 1;
  *d = ((id % 625000) / 15625) + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<unique_id_to_date>:
  endbr64
  mov    %rdx,%r9
  mov    %edi,%edx
  mov    %edi,%eax
  mov    %rcx,%r8
  imul   $0x6b5fca6b,%rdx,%rdx
  mov    %rdx,%rdi
  shr    $0x32,%rdx
  shr    $0x36,%rdi
  imul   $0x98968,%edx,%edx
  mov    %rdi,%rcx
  lea    0x708(%rdi),%edi
  mov    %edi,(%rsi)
  imul   $0x989680,%ecx,%esi
  mov    %eax,%ecx
  sub    %edx,%eax
  imul   $0x431bde83,%rax,%rax
  sub    %esi,%ecx
  imul   $0x6b5fca6b,%rcx,%rcx
  shr    $0x2c,%rax
  add    $0x1,%eax
  shr    $0x32,%rcx
  add    $0x1,%ecx
  mov    %ecx,(%r9)
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void unique_id_to_date(unsigned int id, int *y, int *m, int *d) {
  *y = id / 10000000 + 1800;
  *m = ((id % 10000000) / 625000) + 1;
  *d = ((id % 625000) / 15625) + 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x60(%rbp)
  movl   $0x4,-0x5c(%rbp)
  movl   $0x2,-0x58(%rbp)
  movl   $0x1,-0x54(%rbp)
  movl   $0x3,-0x50(%rbp)
  movl   $0x6,-0x4c(%rbp)
  movl   $0x5,-0x48(%rbp)
  movl   $0x9,-0x44(%rbp)
  movl   $0x8,-0x40(%rbp)
  movl   $0xa,-0x3c(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    $0xa,%ecx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <buildTree@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <P@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int preorder[] = {7, 4, 2, 1, 3, 6, 5, 9, 8, 10};
  int inorder[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  struct TreeNode *root = buildTree(preorder, sizeof(preorder) / sizeof(int), inorder, sizeof(inorder) / sizeof(int));
  P(root);
  putchar('\n');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x7,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x9,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x2,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x4,0x3c(%rsp)
  movl   $0x5,0x40(%rsp)
  movl   $0x6,0x44(%rsp)
  movl   $0x7,0x48(%rsp)
  movl   $0x8,0x4c(%rsp)
  movl   $0x9,0x50(%rsp)
  movl   $0xa,0x54(%rsp)
  lea    0x30(%rsp),%rdx
  mov    %rsp,%rdi
  mov    $0xa,%ecx
  mov    $0xa,%esi
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <P@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int preorder[] = {7, 4, 2, 1, 3, 6, 5, 9, 8, 10};
  int inorder[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  struct TreeNode *root = buildTree(preorder, sizeof(preorder) / sizeof(int), inorder, sizeof(inorder) / sizeof(int));
  P(root);
  putchar('\n');
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0xa,%ecx
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x400000007,%rax
  lea    0x30(%rsp),%rdx
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x900000005,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000008,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x48(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x50(%rsp)
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <P@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int preorder[] = {7, 4, 2, 1, 3, 6, 5, 9, 8, 10};
  int inorder[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  struct TreeNode *root = buildTree(preorder, sizeof(preorder) / sizeof(int), inorder, sizeof(inorder) / sizeof(int));
  P(root);
  putchar('\n');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0xa,%ecx
  mov    $0xa,%esi
  movdqa D42(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D25(%rip),%rax
  lea    0x30(%rsp),%rdx
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D55(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  mov    D54(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D24(%rip),%xmm0
  mov    %rax,0x50(%rsp)
  movaps %xmm0,0x30(%rsp)
  movdqa D47(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <buildTree@plt>
  mov    %rax,%rdi
  call   <P@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D42
data_type: byte[16]
name: unpack_data
arguments: data_tag: D25
data_type: byte[8]
name: unpack_data
arguments: data_tag: D55
data_type: byte[16]
name: unpack_data
arguments: data_tag: D54
data_type: byte[8]
name: unpack_data
arguments: data_tag: D24
data_type: byte[16]
name: unpack_data
arguments: data_tag: D47
data_type: byte[16]

tool: {"D42": [0x07,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D25": [0x08,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D55": [0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D54": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D24": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D47": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int preorder[] = {7, 4, 2, 1, 3, 6, 5, 9, 8, 10};
  int inorder[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  struct TreeNode *root = buildTree(preorder, sizeof(preorder) / sizeof(int), inorder, sizeof(inorder) / sizeof(int));
  P(root);
  putchar('\n');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dup_dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  jmp    L23
L33:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  jmp    L5
L25:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x48(%rbp)
  jge    L25
  addl   $0x1,-0x18(%rbp)
L23:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dup_dmatrix(double **X, long nrl, long nrh, long ncl, long nch, double **Y) {
  int i, j;
  double *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = X[i];
    Yi = Y[i];
    for (j = ncl; j <= nch; j++) {
      Yi[j] = Xi[j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dup_dmatrix>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L36
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  lea    0x0(,%rax,8),%rdi
  lea    0x8(,%rdx,8),%rbp
  movslq %ecx,%rbx
  shl    $0x3,%rbx
  lea    0x8(,%r8,8),%rsi
  movslq %ecx,%r10
L3:
  mov    (%r11,%rdi,1),%rdx
  mov    (%r9,%rdi,1),%rcx
  cmp    %r10,%r8
  jl     L32
  mov    %rbx,%rax
L10:
  movsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L10
L32:
  add    $0x8,%rdi
  cmp    %rbp,%rdi
  jne    L3
  pop    %rbx
  pop    %rbp
  ret
L36:
  ret
```

assistant: ```c
void dup_dmatrix(double **X, long nrl, long nrh, long ncl, long nch, double **Y) {
  int i, j;
  double *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = X[i];
    Yi = Y[i];
    for (j = ncl; j <= nch; j++) {
      Yi[j] = Xi[j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dup_dmatrix>:
  endbr64
  mov    %rdi,%r11
  movslq %esi,%rdi
  cmp    %rdi,%rdx
  jl     L10
  movslq %ecx,%r10
  push   %rbp
  shl    $0x3,%rdi
  lea    0x8(,%rdx,8),%rbp
  push   %rbx
  lea    0x8(,%r8,8),%rsi
  lea    0x0(,%r10,8),%rbx
L32:
  mov    (%r11,%rdi,1),%rcx
  mov    (%r9,%rdi,1),%rdx
  mov    %rbx,%rax
  cmp    %r10,%r8
  jl     L29
L6:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L6
L29:
  add    $0x8,%rdi
  cmp    %rdi,%rbp
  jne    L32
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void dup_dmatrix(double **X, long nrl, long nrh, long ncl, long nch, double **Y) {
  int i, j;
  double *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = X[i];
    Yi = Y[i];
    for (j = ncl; j <= nch; j++) {
      Yi[j] = Xi[j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dup_dmatrix>:
  endbr64
  movslq %esi,%r10
  cmp    %r10,%rdx
  jl     L19
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  movslq %ecx,%r9
  push   %rbp
  push   %rbx
  cmp    %r9,%r8
  jl     L69
  mov    %r8,%r14
  mov    %rdi,%rbx
  lea    0x8(,%rdx,8),%rdi
  shl    $0x3,%r10
  sub    %r9,%r14
  mov    %rdi,-0x18(%rsp)
  shl    $0x3,%r9
  lea    0x8(,%r8,8),%rbp
  lea    0x1(%r14),%r13
  lea    0x8(%r9),%r15
  mov    %r13,%rdi
  mov    %r13,%r11
  and    $0xfffffffffffffffe,%rdi
  shr    %r11
  lea    (%rdi,%rcx,1),%edx
  mov    %rdi,-0x10(%rsp)
  shl    $0x4,%r11
  movslq %edx,%rdx
  shl    $0x3,%rdx
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rbx,%r10,1),%rcx
  mov    (%r12,%r10,1),%rsi
  lea    (%rcx,%r15,1),%rax
  lea    (%rsi,%r9,1),%rdi
  cmp    %rax,%rdi
  je     L15
  cmp    $0x2,%r14
  jbe    L15
  lea    (%rcx,%r9,1),%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L74:
  movupd (%r8,%rax,1),%xmm1
  movups %xmm1,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r11
  jne    L74
  cmp    -0x10(%rsp),%r13
  je     L51
  movsd  (%rcx,%rdx,1),%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
L51:
  add    $0x8,%r10
  cmp    -0x18(%rsp),%r10
  jne    L39
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L45
  jmp    L51
L19:
  ret
```

assistant: ```c
void dup_dmatrix(double **X, long nrl, long nrh, long ncl, long nch, double **Y) {
  int i, j;
  double *Xi, *Yi;
  for (i = nrl; i <= nrh; i++) {
    Xi = X[i];
    Yi = Y[i];
    for (j = ncl; j <= nch; j++) {
      Yi[j] = Xi[j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  movl   $0x2,-0x4(%rbp)
  jmp    L0
L9:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  imul   $0x64,%eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x12b,-0x4(%rbp)
  jle    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void create(int *fibo) {
  int i;
  fibo[0] = 0;
  fibo[1] = 1;
  for (i = 2; i < 300; i++) {
    fibo[i] = (fibo[i - 1] + fibo[i - 2]) % 100;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<create>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x1,0x4(%rdi)
  mov    %rdi,%rcx
  add    $0x4a8,%rdi
L5:
  mov    (%rcx),%edx
  add    0x4(%rcx),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  mov    %edx,0x8(%rcx)
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L5
  ret
```

assistant: ```c
void create(int *fibo) {
  int i;
  fibo[0] = 0;
  fibo[1] = 1;
  for (i = 2; i < 300; i++) {
    fibo[i] = (fibo[i - 1] + fibo[i - 2]) % 100;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<create>:
  endbr64
  movabs $0x100000000,%rax
  lea    0x4(%rdi),%rcx
  lea    0x4a8(%rdi),%r8
  xor    %edx,%edx
  mov    %rax,(%rdi)
  jmp    L12
L18:
  add    $0x4,%rcx
  mov    %esi,%edx
L12:
  mov    (%rcx),%esi
  add    %esi,%edx
  movslq %edx,%rax
  mov    %edx,%edi
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x25,%rax
  sub    %edi,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  mov    %edx,0x4(%rcx)
  cmp    %rcx,%r8
  jne    L18
  ret
```

assistant: ```c
void create(int *fibo) {
  int i;
  fibo[0] = 0;
  fibo[1] = 1;
  for (i = 2; i < 300; i++) {
    fibo[i] = (fibo[i - 1] + fibo[i - 2]) % 100;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create>:
  endbr64
  mov    D5(%rip),%rax
  mov    %rdi,%rsi
  mov    $0x4,%ecx
  mov    $0x1,%edx
  mov    %rax,(%rdi)
  xor    %eax,%eax
L13:
  lea    (%rax,%rdx,1),%edi
  movslq %edi,%rax
  mov    %edi,%r8d
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%r8d
  sar    $0x25,%rax
  sub    %r8d,%eax
  imul   $0x64,%eax,%r8d
  mov    %edi,%eax
  sub    %r8d,%eax
  lea    (%rax,%rdx,1),%edi
  movd   %eax,%xmm0
  movslq %edi,%rdx
  mov    %edi,%r8d
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%r8d
  sar    $0x25,%rdx
  sub    %r8d,%edx
  imul   $0x64,%edx,%r8d
  sub    %r8d,%edi
  movd   %edi,%xmm1
  mov    %edi,%edx
  movslq %ecx,%rdi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%rsi,%rcx,4)
  add    $0x2,%rcx
  cmp    $0x12c,%rcx
  jne    L13
  lea    (%rsi,%rdi,4),%rcx
  lea    0x8(%rsi,%rdi,4),%rdi
L3:
  mov    -0x4(%rcx),%edx
  add    -0x8(%rcx),%edx
  add    $0x4,%rcx
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x25,%rax
  sub    %esi,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rcx)
  cmp    %rcx,%rdi
  jne    L3
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void create(int *fibo) {
  int i;
  fibo[0] = 0;
  fibo[1] = 1;
  for (i = 2; i < 300; i++) {
    fibo[i] = (fibo[i - 1] + fibo[i - 2]) % 100;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<st2rvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movss  %xmm0,-0x34(%rbp)
  movss  %xmm1,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  movss  D49(%rip),%xmm0
  subss  -0x34(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x34(%rbp),%xmm1
  movss  D49(%rip),%xmm0
  subss  -0x38(%rbp),%xmm0
  mulss  -0x38(%rbp),%xmm0
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D40(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movss  -0x34(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  D49(%rip),%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movss  -0x38(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  D49(%rip),%xmm1
  subss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D66(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D67(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x18(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movss  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x10(%rbp),%xmm0
  mov    -0x48(%rbp),%rax
  movss  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x8(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D49
type_infered: byte[4]
name: parse_data
arguments: label: D22
type_infered: byte[8]
name: parse_data
arguments: label: D40
type_infered: byte[8]
name: parse_data
arguments: label: D66
type_infered: byte[8]
name: parse_data
arguments: label: D67
type_infered: byte[8]

tool: {"D49": [0x00,0x00,0x80,0x3f]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D66": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
void st2rvec(float s, float t, float *xp, float *yp, float *zp) {
  double rx, ry, rz;
  double tmp1, tmp2;
  tmp1 = s * (1 - s) + t * (1 - t);
  tmp2 = 2 * sqrt(4 * tmp1 - 1);
  rx = tmp2 * (2 * s - 1);
  ry = tmp2 * (2 * t - 1);
  rz = 8 * tmp1 - 3;
  *xp = (float)rx;
  *yp = (float)ry;
  *zp = (float)rz;
}
```