ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<conv_num>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %edx,%r10d
  mov    %ecx,%r11d
  mov    (%rdi),%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  mov    $0x0,%edx
  cmp    $0x9,%al
  ja     L42
L69:
  lea    (%rdx,%rdx,4),%edx
  mov    (%r8),%rdi
  lea    0x1(%rdi),%rax
  mov    %rax,(%r8)
  movsbl (%rdi),%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  cmp    %r11d,%esi
  jg     L55
  test   %eax,%eax
  je     L55
  movzbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L69
L55:
  cmp    %r10d,%edx
  jl     L32
  cmp    %edx,%r11d
  jl     L32
  mov    %edx,(%r9)
  mov    $0x1,%edx
L42:
  mov    %edx,%eax
  ret
L32:
  mov    $0x0,%edx
  jmp    L42
```

assistant: ```c
int conv_num(buf, dest, llim, ulim) const char **buf;
int *dest;
int llim, ulim;
{
  int result = 0;
  int rulim = ulim;
  if (**buf < '0' || **buf > '9')
    return (0);
  do {
    result *= 10;
    result += *(*buf)++ - '0';
    rulim /= 10;
  } while ((result * 10 <= ulim) && rulim && **buf >= '0' && **buf <= '9');
  if (result < llim || result > ulim)
    return (0);
  *dest = result;
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<conv_num>:
  endbr64
  mov    %edx,%r10d
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L47
  push   %rbx
  mov    %rsi,%r9
  mov    %ecx,%r11d
  mov    %ecx,%esi
  mov    %rdi,%r8
  add    $0x1,%rdx
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rdx,(%r8)
  movsbl -0x1(%rdx),%eax
  lea    (%rcx,%rcx,4),%ecx
  mov    %esi,%edi
  sar    $0x1f,%edi
  mov    %rdx,%rbx
  lea    -0x30(%rax,%rcx,2),%ecx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %eax,%esi
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  cmp    %r11d,%eax
  jg     L20
  test   %esi,%esi
  je     L20
  movzbl (%rbx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L21
L20:
  cmp    %r10d,%ecx
  jl     L5
  cmp    %ecx,%r11d
  jl     L5
  mov    %ecx,(%r9)
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
int conv_num(buf, dest, llim, ulim) const char **buf;
int *dest;
int llim, ulim;
{
  int result = 0;
  int rulim = ulim;
  if (**buf < '0' || **buf > '9')
    return (0);
  do {
    result *= 10;
    result += *(*buf)++ - '0';
    rulim /= 10;
  } while ((result * 10 <= ulim) && rulim && **buf >= '0' && **buf <= '9');
  if (result < llim || result > ulim)
    return (0);
  *dest = result;
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<conv_num>:
  endbr64
  mov    %edx,%r10d
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L53
  push   %rbx
  mov    %rsi,%r9
  mov    %ecx,%r11d
  mov    %ecx,%esi
  mov    %rdi,%r8
  add    $0x1,%rdx
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %rdx,(%r8)
  movsbl -0x1(%rdx),%eax
  lea    (%rcx,%rcx,4),%ecx
  mov    %esi,%edi
  sar    $0x1f,%edi
  mov    %rdx,%rbx
  lea    -0x30(%rax,%rcx,2),%ecx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edi,%eax
  mov    %eax,%esi
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  cmp    %r11d,%eax
  jg     L58
  test   %esi,%esi
  je     L58
  movzbl (%rbx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L52
L58:
  cmp    %r10d,%ecx
  jl     L36
  cmp    %ecx,%r11d
  jl     L36
  mov    %ecx,(%r9)
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  ret
```

assistant: ```c
int conv_num(buf, dest, llim, ulim) const char **buf;
int *dest;
int llim, ulim;
{
  int result = 0;
  int rulim = ulim;
  if (**buf < '0' || **buf > '9')
    return (0);
  do {
    result *= 10;
    result += *(*buf)++ - '0';
    rulim /= 10;
  } while ((result * 10 <= ulim) && rulim && **buf >= '0' && **buf <= '9');
  if (result < llim || result > ulim)
    return (0);
  *dest = result;
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 5;
  assert(a > b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 5;
  assert(a > b);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 5;
  assert(a > b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 4;
  int b = 5;
  assert(a > b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_url>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <tsk_url_decode@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <tsk_url_encode@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <tsk_free@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <tsk_free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D4
type: string

tool: D0: http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D

tool: D13: test_url/// decoded url:%s


tool: D4: test_url/// encoded url:%s


assistant: ```c
void test_url() {
  const char *url = "http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D";
  char *str1, *str2;
  str1 = tsk_url_decode(url);
  printf("test_url/// decoded url:%s\n", str1);
  str2 = tsk_url_encode(str1);
  printf("test_url/// encoded url:%s\n", str2);
  tsk_free((void **)&str1);
  tsk_free((void **)&str2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_url>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <tsk_url_decode@plt>
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <tsk_url_encode@plt>
  mov    %rax,%rsi
  mov    %rax,0x10(%rsp)
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rdi
  call   <tsk_free@plt>
  lea    0x10(%rsp),%rdi
  call   <tsk_free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D17: http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D

tool: D24: test_url/// decoded url:%s


tool: D2: test_url/// encoded url:%s


assistant: ```c
void test_url() {
  const char *url = "http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D";
  char *str1, *str2;
  str1 = tsk_url_decode(url);
  printf("test_url/// decoded url:%s\n", str1);
  str2 = tsk_url_encode(str1);
  printf("test_url/// encoded url:%s\n", str2);
  tsk_free((void **)&str1);
  tsk_free((void **)&str2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_url>:
  endbr64
  sub    $0x28,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <tsk_url_decode@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <tsk_url_encode@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rdi
  call   <tsk_free@plt>
  lea    0x10(%rsp),%rdi
  call   <tsk_free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D29: http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D

tool: D12: test_url/// decoded url:%s


tool: D10: test_url/// encoded url:%s


assistant: ```c
void test_url() {
  const char *url = "http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D";
  char *str1, *str2;
  str1 = tsk_url_decode(url);
  printf("test_url/// decoded url:%s\n", str1);
  str2 = tsk_url_encode(str1);
  printf("test_url/// encoded url:%s\n", str2);
  tsk_free((void **)&str1);
  tsk_free((void **)&str2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_url>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <tsk_url_decode@plt>
  lea    D16(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <tsk_url_encode@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  lea    0x8(%rsp),%rdi
  call   <tsk_free@plt>
  lea    0x10(%rsp),%rdi
  call   <tsk_free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D16
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D15: http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D

tool: D16: test_url/// decoded url:%s


tool: D14: test_url/// encoded url:%s


assistant: ```c
void test_url() {
  const char *url = "http://xcap.example.org/resource-lists/users/sip:RCSUser@example.org/index/~~/resource-lists/list%5B@name=%22rcs%22%5D";
  char *str1, *str2;
  str1 = tsk_url_decode(url);
  printf("test_url/// decoded url:%s\n", str1);
  str2 = tsk_url_encode(str1);
  printf("test_url/// encoded url:%s\n", str2);
  tsk_free((void **)&str1);
  tsk_free((void **)&str2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  addss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void v(float *d, float s) {
  d[0] += s;
  d[1] += s;
  d[2] += s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<v>:
  endbr64
  movaps %xmm0,%xmm1
  addss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  addss  0x4(%rdi),%xmm1
  movss  %xmm1,0x4(%rdi)
  addss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void v(float *d, float s) {
  d[0] += s;
  d[1] += s;
  d[2] += s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<v>:
  endbr64
  movss  (%rdi),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdi),%xmm1
  addss  %xmm0,%xmm1
  addss  0x8(%rdi),%xmm0
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void v(float *d, float s) {
  d[0] += s;
  d[1] += s;
  d[2] += s;
}
```
user: What is the c source code of the assembly code below:

```asm
<v>:
  endbr64
  movq   (%rdi),%xmm1
  movaps %xmm0,%xmm2
  addss  0x8(%rdi),%xmm0
  shufps $0xe0,%xmm2,%xmm2
  addps  %xmm2,%xmm1
  movss  %xmm0,0x8(%rdi)
  movlps %xmm1,(%rdi)
  ret
```

assistant: ```c
void v(float *d, float s) {
  d[0] += s;
  d[1] += s;
  d[2] += s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  jmp    L25
L23:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L36
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L25
L36:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L23
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ub(int a[], int s, int e, int k) {
  int m;
  while (e > s) {
    m = (s + e) / 2;
    if (a[m] <= k)
      s = m + 1;
    else
      e = m;
  }
  return e + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ub>:
  endbr64
L2:
  cmp    %esi,%edx
  jle    L35
  lea    (%rdx,%rsi,1),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  movslq %r8d,%rax
  cmp    %ecx,(%rdi,%rax,4)
  jle    L4
  mov    %r8d,%edx
  jmp    L2
L4:
  lea    0x1(%r8),%esi
  jmp    L2
L35:
  lea    0x1(%rdx),%eax
  ret
```

assistant: ```c
int ub(int a[], int s, int e, int k) {
  int m;
  while (e > s) {
    m = (s + e) / 2;
    if (a[m] <= k)
      s = m + 1;
    else
      e = m;
  }
  return e + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ub>:
  endbr64
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L23:
  lea    (%rdx,%rsi,1),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  movslq %r8d,%rax
  cmp    %ecx,(%rdi,%rax,4)
  jle    L34
  mov    %r8d,%edx
L21:
  cmp    %esi,%edx
  jg     L23
  lea    0x1(%rdx),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  lea    0x1(%r8),%esi
  jmp    L21
```

assistant: ```c
int ub(int a[], int s, int e, int k) {
  int m;
  while (e > s) {
    m = (s + e) / 2;
    if (a[m] <= k)
      s = m + 1;
    else
      e = m;
  }
  return e + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ub>:
  endbr64
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    (%rdx,%rsi,1),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  movslq %r8d,%rax
  cmp    %ecx,(%rdi,%rax,4)
  jle    L29
  mov    %r8d,%edx
L34:
  cmp    %esi,%edx
  jg     L5
  lea    0x1(%rdx),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x1(%r8),%esi
  jmp    L34
```

assistant: ```c
int ub(int a[], int s, int e, int k) {
  int m;
  while (e > s) {
    m = (s + e) / 2;
    if (a[m] <= k)
      s = m + 1;
    else
      e = m;
  }
  return e + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__convert_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L35
L37:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L32
  mov    -0x4(%rbp),%eax
  jmp    L6
L32:
  subl   $0x30,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jle    L2
  subl   $0x7,-0x4(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L35:
  cmpl   $0x1,-0xc(%rbp)
  jle    L37
  mov    -0x8(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int __convert_char(char *hexstr, int *source) {
  int i, ch, temp_ch;
  for (ch = i = 0; i < 2; i++) {
    temp_ch = hexstr[(*source)++];
    if (!isxdigit(temp_ch))
      return temp_ch;
    temp_ch -= '0';
    if (temp_ch > 9)
      temp_ch -= 'A' - '9' - 1;
    ch = (ch << 4) + temp_ch;
  }
  return ch;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__convert_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    $0x2,%r13d
  mov    $0x0,%ebp
L27:
  mov    (%r12),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%r12)
  cltq
  movsbl (%r14,%rax,1),%ebx
  mov    %ebx,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L26
  lea    -0x30(%rbx),%eax
  sub    $0x37,%ebx
  cmp    $0x9,%eax
  cmovg  %ebx,%eax
  shl    $0x4,%ebp
  add    %eax,%ebp
  sub    $0x1,%r13d
  jne    L27
L22:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    %ebx,%ebp
  jmp    L22
```

assistant: ```c
int __convert_char(char *hexstr, int *source) {
  int i, ch, temp_ch;
  for (ch = i = 0; i < 2; i++) {
    temp_ch = hexstr[(*source)++];
    if (!isxdigit(temp_ch))
      return temp_ch;
    temp_ch -= '0';
    if (temp_ch > 9)
      temp_ch -= 'A' - '9' - 1;
    ch = (ch << 4) + temp_ch;
  }
  return ch;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__convert_char>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq (%rsi),%r14
  lea    0x1(%r14),%ebx
  add    $0x3,%r14
  movslq %ebx,%rbx
L24:
  mov    %ebx,(%r15)
  movsbl -0x1(%r13,%rbx,1),%ebp
  mov    %ebp,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L20
  lea    -0x30(%rbp),%eax
  sub    $0x37,%ebp
  cmp    $0x9,%eax
  cmovg  %ebp,%eax
  shl    $0x4,%r12d
  add    $0x1,%rbx
  add    %eax,%r12d
  cmp    %r14,%rbx
  jne    L24
L29:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebp,%r12d
  jmp    L29
```

assistant: ```c
int __convert_char(char *hexstr, int *source) {
  int i, ch, temp_ch;
  for (ch = i = 0; i < 2; i++) {
    temp_ch = hexstr[(*source)++];
    if (!isxdigit(temp_ch))
      return temp_ch;
    temp_ch -= '0';
    if (temp_ch > 9)
      temp_ch -= 'A' - '9' - 1;
    ch = (ch << 4) + temp_ch;
  }
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__convert_char>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq (%rsi),%rax
  lea    0x1(%rax),%r15d
  mov    %rax,%r13
  mov    %r15d,(%rsi)
  movsbl (%rdi,%rax,1),%r12d
  mov    %r12d,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L16
  lea    -0x30(%r12),%ebx
  sub    $0x37,%r12d
  movslq %r15d,%r15
  cmp    $0x9,%ebx
  cmovg  %r12d,%ebx
  add    $0x2,%r13d
  mov    %r13d,0x0(%rbp)
  movsbl (%r14,%r15,1),%r12d
  mov    %r12d,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L16
  lea    -0x30(%r12),%eax
  sub    $0x37,%r12d
  cmp    $0x9,%eax
  cmovg  %r12d,%eax
  shl    $0x4,%ebx
  lea    (%rbx,%rax,1),%r12d
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __convert_char(char *hexstr, int *source) {
  int i, ch, temp_ch;
  for (ch = i = 0; i < 2; i++) {
    temp_ch = hexstr[(*source)++];
    if (!isxdigit(temp_ch))
      return temp_ch;
    temp_ch -= '0';
    if (temp_ch > 9)
      temp_ch -= 'A' - '9' - 1;
    ch = (ch << 4) + temp_ch;
  }
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vector_fill_unique>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L32:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vector_swap@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *vector_fill_unique(int n) {
  int *v = (int *)malloc(sizeof(int) * n);
  int i;
  for (i = 0; i < n; i++) {
    v[i] = i;
  }
  for (i = 0; i < n; i++) {
    vector_swap(&v[i], &v[rand() % n]);
  }
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_fill_unique>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L4
  mov    %rax,%rbp
  mov    $0x0,%ebx
L12:
  mov    %ebx,(%rax)
  mov    %ebx,%edx
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %ebx,%r13d
  jne    L12
  mov    %edx,%edx
  lea    0x4(%r12,%rdx,4),%r13
L21:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rsi
  mov    %rbp,%rdi
  call   <vector_swap@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L21
L4:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *vector_fill_unique(int n) {
  int *v = (int *)malloc(sizeof(int) * n);
  int i;
  for (i = 0; i < n; i++) {
    v[i] = i;
  }
  for (i = 0; i < n; i++) {
    vector_swap(&v[i], &v[rand() % n]);
  }
  return v;
}
```