ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L25
L30:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L35
L4:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L35:
  cmpl   $0x2,-0x14(%rbp)
  jle    L4
  addl   $0x1,-0x18(%rbp)
L25:
  cmpl   $0x6,-0x18(%rbp)
  jle    L30
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D18: srev

tool: D7: # c::%s:len=%d


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "srev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D25(%rip),%r15
  jmp    L19
L17:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L39
L19:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L3:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L3
  jmp    L17
L39:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string

tool: D25: srev

tool: D4: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "srev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D26(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L1:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L15:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L15
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L1
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D26
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D21
type: string

tool: D26: srev

tool: D22: # c::%s:len=%d


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "srev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D0(%rip),%r15
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L14:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L14
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L7
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string

tool: D0: srev

tool: D20: # c::%s:len=%d


tool: D18: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "srev", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mockable_is_surrounded_by_whitespaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_space@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_space@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L22
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    $0x1,%eax
  jmp    L2
L22:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int mockable_is_surrounded_by_whitespaces(const char *buf, int pos, int end) {
  const int left = is_space(buf[pos - 1]);
  const int right = is_space(buf[end + 1]);
  return (left && right);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mockable_is_surrounded_by_whitespaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %edx,%ebx
  movslq %esi,%rsi
  movsbl -0x1(%rdi,%rsi,1),%edi
  call   <is_space@plt>
  mov    %eax,%ebp
  movslq %ebx,%rbx
  movsbl 0x1(%r12,%rbx,1),%edi
  call   <is_space@plt>
  test   %ebp,%ebp
  setne  %dl
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mockable_is_surrounded_by_whitespaces(const char *buf, int pos, int end) {
  const int left = is_space(buf[pos - 1]);
  const int right = is_space(buf[end + 1]);
  return (left && right);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mockable_is_surrounded_by_whitespaces>:
  endbr64
  push   %r12
  movslq %esi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl -0x1(%rdi,%rsi,1),%edi
  movslq %edx,%rbx
  call   <is_space@plt>
  movsbl 0x1(%rbp,%rbx,1),%edi
  mov    %eax,%r12d
  call   <is_space@plt>
  test   %r12d,%r12d
  pop    %rbx
  pop    %rbp
  setne  %dl
  test   %eax,%eax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int mockable_is_surrounded_by_whitespaces(const char *buf, int pos, int end) {
  const int left = is_space(buf[pos - 1]);
  const int right = is_space(buf[end + 1]);
  return (left && right);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mockable_is_surrounded_by_whitespaces>:
  endbr64
  push   %r12
  movslq %esi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl -0x1(%rdi,%rsi,1),%edi
  movslq %edx,%rbx
  call   <is_space@plt>
  movsbl 0x1(%rbp,%rbx,1),%edi
  mov    %eax,%r12d
  call   <is_space@plt>
  test   %r12d,%r12d
  pop    %rbx
  pop    %rbp
  setne  %dl
  test   %eax,%eax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int mockable_is_surrounded_by_whitespaces(const char *buf, int pos, int end) {
  const int left = is_space(buf[pos - 1]);
  const int right = is_space(buf[end + 1]);
  return (left && right);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <move_to_next_token@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
L5:
  mov    $0x0,%eax
  jmp    L12
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <find_token_end@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract_token@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L12:
  leave
  ret
```

assistant: ```c
const char *read_token(const char *s, char **token) {
  size_t l;
  *token = NULL;
  s = move_to_next_token(s);
  if ((s == NULL) || (*s == '\0'))
    return NULL;
  l = find_token_end(s);
  *token = extract_token(s, l);
  return (s + l);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_token>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  movq   $0x0,(%rsi)
  call   <move_to_next_token@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  cmpb   $0x0,(%rax)
  je     L21
  mov    %rax,%rdi
  call   <find_token_end@plt>
  mov    %rax,%r12
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <extract_token@plt>
  mov    %rax,0x0(%rbp)
  add    %r12,%rbx
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0x0,%ebx
  jmp    L2
```

assistant: ```c
const char *read_token(const char *s, char **token) {
  size_t l;
  *token = NULL;
  s = move_to_next_token(s);
  if ((s == NULL) || (*s == '\0'))
    return NULL;
  l = find_token_end(s);
  *token = extract_token(s, l);
  return (s + l);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_token>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movq   $0x0,(%rsi)
  call   <move_to_next_token@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
  cmpb   $0x0,(%rax)
  je     L7
  mov    %rax,%rdi
  call   <find_token_end@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <extract_token@plt>
  add    %rbp,%r12
  mov    %rax,(%rbx)
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *read_token(const char *s, char **token) {
  size_t l;
  *token = NULL;
  s = move_to_next_token(s);
  if ((s == NULL) || (*s == '\0'))
    return NULL;
  l = find_token_end(s);
  *token = extract_token(s, l);
  return (s + l);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_token>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movq   $0x0,(%rsi)
  call   <move_to_next_token@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  cmpb   $0x0,(%rax)
  je     L15
  mov    %rax,%rdi
  call   <find_token_end@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <extract_token@plt>
  add    %rbp,%r12
  mov    %rax,(%rbx)
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *read_token(const char *s, char **token) {
  size_t l;
  *token = NULL;
  s = move_to_next_token(s);
  if ((s == NULL) || (*s == '\0'))
    return NULL;
  l = find_token_end(s);
  *token = extract_token(s, l);
  return (s + l);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %02x

assistant: ```c
void print_bytes(uint8_t *bytes, uint16_t byteslen) {
  int i;
  for (i = 0; i < byteslen; i++) {
    printf("%02x", bytes[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_bytes>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D5(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string

tool: D5: %02x

assistant: ```c
void print_bytes(uint8_t *bytes, uint16_t byteslen) {
  int i;
  for (i = 0; i < byteslen; i++) {
    printf("%02x", bytes[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_bytes>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %02x

assistant: ```c
void print_bytes(uint8_t *bytes, uint16_t byteslen) {
  int i;
  for (i = 0; i < byteslen; i++) {
    printf("%02x", bytes[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_bytes>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %02x

assistant: ```c
void print_bytes(uint8_t *bytes, uint16_t byteslen) {
  int i;
  for (i = 0; i < byteslen; i++) {
    printf("%02x", bytes[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_user_auth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x60,%rsp
  mov    %rdi,-0x1048(%rbp)
  mov    %rsi,-0x1050(%rbp)
  mov    %rdx,-0x1058(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1034(%rbp)
  mov    $0x65,%edi
  call   <malloc@plt>
  mov    %rax,-0x1028(%rbp)
  cmpq   $0x0,-0x1028(%rbp)
  jne    L105
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L51
L105:
  mov    -0x1028(%rbp),%rax
  mov    $0x65,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L60
L91:
  mov    -0x1028(%rbp),%rcx
  lea    -0x101d(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  lea    D38(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x1048(%rbp),%rdx
  lea    -0x101d(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L60
  mov    -0x1028(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x1030(%rbp)
  jmp    L26
L74:
  mov    -0x1050(%rbp),%rdx
  mov    -0x1030(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  movl   $0x1,-0x1034(%rbp)
  jmp    L60
L21:
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x1030(%rbp)
L26:
  cmpq   $0x0,-0x1030(%rbp)
  jne    L74
L60:
  mov    -0x1058(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L99
  cmpl   $0x0,-0x1034(%rbp)
  je     L91
L99:
  mov    -0x1028(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L51:
  mov    -0x1034(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D38
data_type: string
name: extract_symbolic_data
arguments: label: D39
data_type: string

tool: D1: malloc user_list

tool: D38: %12s	%100s[^
]

tool: D39: ,

assistant: ```c
int check_user_auth(const char *from_user, const char *to_user, FILE *fp) {
  int ret = 0;
  char buf[4096];
  char user[13];
  char *user_list;
  char *token;
  user_list = malloc(101);
  if (!user_list) {
    perror("malloc user_list");
    goto out;
  }
  memset(user_list, 0, 101);
  while (fgets(buf, 4096, fp) && !ret) {
    sscanf(buf, "%12s\t%100s[^\n]", user, user_list);
    if (strcmp(user, from_user) == 0) {
      token = strtok(user_list, ",");
      while (token != NULL) {
        if (strcmp(token, to_user) == 0) {
          ret = 1;
          break;
        }
        token = strtok(NULL, ",");
      }
    }
  }
  free(user_list);
out:
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_user_auth>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x1038(%rsp)
  xor    %eax,%eax
  mov    $0x65,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L81
  mov    %rax,%r12
  mov    $0x65,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,0x1c(%rsp)
  lea    D39(%rip),%r15
  lea    0x30(%rsp),%rbx
L22:
  mov    0x1c(%rsp),%r14d
  lea    0x23(%rsp),%rbp
L78:
  mov    %r13,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %r14d,%r14d
  jne    L66
  test   %rax,%rax
  je     L66
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L78
  lea    D29(%rip),%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L99
L39:
  mov    0x10(%rsp),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  lea    D29(%rip),%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L39
L99:
  mov    $0x0,%r14d
  jmp    L78
L81:
  lea    D35(%rip),%rdi
  call   <perror@plt>
  movl   $0x0,0x1c(%rsp)
  jmp    L71
L6:
  movl   $0x1,0x1c(%rsp)
  jmp    L22
L66:
  mov    %r12,%rdi
  call   <free@plt>
L71:
  mov    0x1038(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  mov    0x1c(%rsp),%eax
  add    $0x1048,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D39
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D35
data_type: string

tool: D39: %12s	%100s[^
]

tool: D29: ,

tool: D35: malloc user_list

assistant: ```c
int check_user_auth(const char *from_user, const char *to_user, FILE *fp) {
  int ret = 0;
  char buf[4096];
  char user[13];
  char *user_list;
  char *token;
  user_list = malloc(101);
  if (!user_list) {
    perror("malloc user_list");
    goto out;
  }
  memset(user_list, 0, 101);
  while (fgets(buf, 4096, fp) && !ret) {
    sscanf(buf, "%12s\t%100s[^\n]", user, user_list);
    if (strcmp(user, from_user) == 0) {
      token = strtok(user_list, ",");
      while (token != NULL) {
        if (strcmp(token, to_user) == 0) {
          ret = 1;
          break;
        }
        token = strtok(NULL, ",");
      }
    }
  }
  free(user_list);
out:
  return ret;
}
```