ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_safelen>:
  endbr64
  push   %r14
  mov    $0x32,%ecx
  xor    %edx,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0xffffffffffffffff,%rax
  lea    0x190(%rsp),%rbx
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0x32,%ecx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rcx
  xor    %eax,%eax
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L67:
  cmp    $0x1,%eax
  je     L35
  mov    -0x4(%rcx),%edi
  lea    0x2(%rdi),%edx
L77:
  add    $0x4,%rcx
L92:
  add    $0x1,%eax
  mov    %edx,(%rcx)
  cmp    $0x64,%eax
  jne    L67
  xor    %eax,%eax
  nop
L98:
  mov    %eax,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L98
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  lea    D4(%rip),%r14
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rbp
  cmp    $0x64,%rbp
  je     L41
L39:
  mov    0x0(%r13,%rbp,4),%edx
  mov    (%rbx,%rbp,4),%ecx
  mov    %ebp,%esi
  cmp    %ecx,%edx
  je     L72
  add    $0x1,%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r12d,%r8d
  call   <printf@plt>
L72:
  cmp    $0xb,%r12d
  jne    L34
  lea    D8(%rip),%rdi
  call   <puts@plt>
L41:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x330,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  mov    $0x1,%edx
  jmp    L77
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D4: %d: a %d != %d (error %d)


tool: D8: abort

assistant: ```c
int test_safelen() {
  int a[100], aa[100];
  int i, error = 0;
  for (i = 0; i < 100; i++)
    aa[i] = a[i] = -1;
#pragma omp target simd map(tofrom : a [0:100]) safelen(2)
  for (int k = 0; k < 100; k++) {
    if (k > 1) {
      a[k] = a[k - 2] + 2;
    } else {
      a[k] = k;
    }
  }
  for (i = 0; i < 100; i++)
    aa[i] = i;
  for (i = 0; i < 100; i++) {
    if (a[i] != aa[i])
      printf("%d: a %d != %d (error %d)\n", i, a[i], aa[i], ++error);
    if (error > 10) {
      printf("abort\n");
      return error;
    }
  }
  return error;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_safelen>:
  endbr64
  push   %r14
  mov    $0x32,%ecx
  mov    $0x1,%edx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    $0xffffffffffffffff,%rax
  lea    0x190(%rsp),%rbp
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rsp)
  mov    $0x32,%ecx
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  lea    0x4(%rsp),%rax
  nop
L19:
  cmp    $0x1,%edx
  je     L16
L68:
  mov    -0x8(%rax),%edi
  add    $0x1,%edx
  add    $0x4,%rax
  lea    0x2(%rdi),%ecx
  mov    %ecx,-0x4(%rax)
  cmp    $0x64,%edx
  jne    L19
  movdqa D9(%rip),%xmm0
  movdqa D30(%rip),%xmm2
  mov    %rbp,%rax
  lea    0x320(%rsp),%rdx
  nopl   0x0(%rax)
L74:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L74
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  lea    D37(%rip),%r14
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L85:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L81
L28:
  mov    0x0(%r13,%rbx,4),%edx
  mov    0x0(%rbp,%rbx,4),%ecx
  mov    %ebx,%esi
  cmp    %ecx,%edx
  je     L22
  add    $0x1,%r12d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r12d,%r8d
  call   <printf@plt>
L22:
  cmp    $0xb,%r12d
  jne    L85
  lea    D2(%rip),%rdi
  call   <puts@plt>
L81:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x330,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    -0x4(%rax),%esi
  movl   $0x1,(%rax)
  add    $0x8,%rax
  lea    0x2(%rsi),%edx
  mov    %edx,-0x4(%rax)
  mov    $0x3,%edx
  jmp    L68
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D30
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D37
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D30": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D37: %d: a %d != %d (error %d)


tool: D2: abort

assistant: ```c
int test_safelen() {
  int a[100], aa[100];
  int i, error = 0;
  for (i = 0; i < 100; i++)
    aa[i] = a[i] = -1;
#pragma omp target simd map(tofrom : a [0:100]) safelen(2)
  for (int k = 0; k < 100; k++) {
    if (k > 1) {
      a[k] = a[k - 2] + 2;
    } else {
      a[k] = k;
    }
  }
  for (i = 0; i < 100; i++)
    aa[i] = i;
  for (i = 0; i < 100; i++) {
    if (a[i] != aa[i])
      printf("%d: a %d != %d (error %d)\n", i, a[i], aa[i], ++error);
    if (error > 10) {
      printf("abort\n");
      return error;
    }
  }
  return error;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x2,-0x14(%rbp)
  jle    L16
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compute_checksum(uint8_t bytes[3], uint8_t sum[2]) {
  uint8_t first_sum = 0;
  uint8_t second_sum = 0;
  for (int i = 0; i < 3; i++) {
    first_sum += bytes[i];
    second_sum += first_sum;
  }
  sum[0] = first_sum;
  sum[1] = second_sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compute_checksum>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  add    0x8(%rdi),%rax
  add    %rax,%rdx
  add    0x10(%rdi),%rax
  mov    %rax,(%rsi)
  add    %rdx,%rax
  mov    %rax,0x8(%rsi)
  ret
```

assistant: ```c
void compute_checksum(uint8_t bytes[3], uint8_t sum[2]) {
  uint8_t first_sum = 0;
  uint8_t second_sum = 0;
  for (int i = 0; i < 3; i++) {
    first_sum += bytes[i];
    second_sum += first_sum;
  }
  sum[0] = first_sum;
  sum[1] = second_sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<compute_checksum>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdx
  add    %rax,%rdx
  add    %rdx,%rax
  add    0x10(%rdi),%rdx
  add    %rdx,%rax
  mov    %rdx,(%rsi)
  mov    %rax,0x8(%rsi)
  ret
```

assistant: ```c
void compute_checksum(uint8_t bytes[3], uint8_t sum[2]) {
  uint8_t first_sum = 0;
  uint8_t second_sum = 0;
  for (int i = 0; i < 3; i++) {
    first_sum += bytes[i];
    second_sum += first_sum;
  }
  sum[0] = first_sum;
  sum[1] = second_sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute_checksum>:
  endbr64
  mov    0x8(%rdi),%rcx
  mov    (%rdi),%rdx
  mov    0x10(%rdi),%rax
  movdqu (%rdi),%xmm0
  add    %rcx,%rdx
  movq   %rcx,%xmm1
  movq   %rdx,%xmm2
  punpcklqdq %xmm0,%xmm0
  add    %rax,%rdx
  punpcklqdq %xmm2,%xmm1
  movq   %rdx,%xmm3
  paddq  %xmm1,%xmm0
  movq   %rax,%xmm1
  punpcklqdq %xmm3,%xmm1
  paddq  %xmm1,%xmm0
  movups %xmm0,(%rsi)
  ret
```

assistant: ```c
void compute_checksum(uint8_t bytes[3], uint8_t sum[2]) {
  uint8_t first_sum = 0;
  uint8_t second_sum = 0;
  for (int i = 0; i < 3; i++) {
    first_sum += bytes[i];
    second_sum += first_sum;
  }
  sum[0] = first_sum;
  sum[1] = second_sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x31,-0x4(%rbp)
  jne    L148
  mov    $0x1,%eax
  jmp    L43
L148:
  cmpb   $0x32,-0x4(%rbp)
  jne    L155
  mov    $0x2,%eax
  jmp    L43
L155:
  cmpb   $0x33,-0x4(%rbp)
  jne    L72
  mov    $0x3,%eax
  jmp    L43
L72:
  cmpb   $0x34,-0x4(%rbp)
  jne    L127
  mov    $0x4,%eax
  jmp    L43
L127:
  cmpb   $0x35,-0x4(%rbp)
  jne    L69
  mov    $0x5,%eax
  jmp    L43
L69:
  cmpb   $0x36,-0x4(%rbp)
  jne    L114
  mov    $0x6,%eax
  jmp    L43
L114:
  cmpb   $0x37,-0x4(%rbp)
  jne    L17
  mov    $0x7,%eax
  jmp    L43
L17:
  cmpb   $0x38,-0x4(%rbp)
  jne    L113
  mov    $0x8,%eax
  jmp    L43
L113:
  cmpb   $0x39,-0x4(%rbp)
  jne    L178
  mov    $0x9,%eax
  jmp    L43
L178:
  mov    $0x0,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int val(char c) {
  if (c == '1')
    return 1;
  else if (c == '2')
    return 2;
  else if (c == '3')
    return 3;
  else if (c == '4')
    return 4;
  else if (c == '5')
    return 5;
  else if (c == '6')
    return 6;
  else if (c == '7')
    return 7;
  else if (c == '8')
    return 8;
  else if (c == '9')
    return 9;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<val>:
  endbr64
  sub    $0x31,%edi
  cmp    $0x8,%dil
  ja     L5
  movzbl %dil,%edi
  lea    D7(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
  mov    $0x1,%eax
  ret
```

assistant: ```c
int val(char c) {
  if (c == '1')
    return 1;
  else if (c == '2')
    return 2;
  else if (c == '3')
    return 3;
  else if (c == '4')
    return 4;
  else if (c == '5')
    return 5;
  else if (c == '6')
    return 6;
  else if (c == '7')
    return 7;
  else if (c == '8')
    return 8;
  else if (c == '9')
    return 9;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<val>:
  endbr64
  lea    -0x31(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x30,%eax
  cmp    $0x9,%dl
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
int val(char c) {
  if (c == '1')
    return 1;
  else if (c == '2')
    return 2;
  else if (c == '3')
    return 3;
  else if (c == '4')
    return 4;
  else if (c == '5')
    return 5;
  else if (c == '6')
    return 6;
  else if (c == '7')
    return 7;
  else if (c == '8')
    return 8;
  else if (c == '9')
    return 9;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<val>:
  endbr64
  lea    -0x31(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x30,%eax
  cmp    $0x9,%dl
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
```

assistant: ```c
int val(char c) {
  if (c == '1')
    return 1;
  else if (c == '2')
    return 2;
  else if (c == '3')
    return 3;
  else if (c == '4')
    return 4;
  else if (c == '5')
    return 5;
  else if (c == '6')
    return 6;
  else if (c == '7')
    return 7;
  else if (c == '8')
    return 8;
  else if (c == '9')
    return 9;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L28
L7:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  jmp    L26
L28:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    $0x30,%eax
  sub    %edx,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x8(%rbp),%rax
L26:
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[12 + 2];
  char *p = buf + 12 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  mov    %edi,%ecx
  lea    D4(%rip),%rdi
  mov    $0x30,%r8d
  test   %ecx,%ecx
  jns    L25
L39:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%r8,%rsi,2),%esi
  sub    %ecx,%esi
  mov    %sil,(%rdi)
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L39
  lea    -0x2(%rax),%rdx
  movb   $0x2d,-0x1(%rdi)
L9:
  mov    %rdx,%rax
  ret
L25:
  mov    %rdi,%rdx
L20:
  sub    $0x1,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx)
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L20
  jmp    L9
```

assistant: ```c
char *itoa(int i) {
  static char buf[12 + 2];
  char *p = buf + 12 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D2(%rip),%rdi
  test   %edx,%edx
  jns    L3
  nopw   0x0(%rax,%rax,1)
L25:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L25
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L23
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[12 + 2];
  char *p = buf + 12 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D1(%rip),%rdi
  test   %edx,%edx
  jns    L13
  nopw   0x0(%rax,%rax,1)
L14:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L14
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L18
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[12 + 2];
  char *p = buf + 12 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L15
  mov    -0x4(%rbp),%eax
  jmp    L1
L15:
  mov    -0x8(%rbp),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int Max(int x, int y) {
  if (x > y)
    return x;
  else
    return y;
}
```
user: What is the c source code of the assembly code below?

```asm
<Max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int Max(int x, int y) {
  if (x > y)
    return x;
  else
    return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int Max(int x, int y) {
  if (x > y)
    return x;
  else
    return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int Max(int x, int y) {
  if (x > y)
    return x;
  else
    return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L26:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void substring(const char source[], int start, int count, char result[]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; i++)
    result[i] = source[i + start];
  result[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<substring>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L31
  mov    %edx,%edx
  mov    $0x0,%eax
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rdi
L17:
  mov    %eax,%esi
  cmpb   $0x0,(%r8,%rax,1)
  je     L8
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rcx,%rax,1)
  lea    0x1(%rax),%esi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L8:
  movslq %esi,%rsi
  movb   $0x0,(%rcx,%rsi,1)
  ret
L31:
  mov    $0x0,%esi
  jmp    L8
```

assistant: ```c
void substring(const char source[], int start, int count, char result[]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; i++)
    result[i] = source[i + start];
  result[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substring>:
  endbr64
  mov    %rdi,%r9
  test   %edx,%edx
  jle    L11
  movslq %esi,%rsi
  mov    %rcx,%rdi
  lea    0x1(%rdx),%r10d
  mov    $0x1,%eax
  lea    (%r9,%rsi,1),%r8
  jmp    L47
L39:
  movzbl -0x1(%r8,%rax,1),%esi
  mov    %sil,(%rdi)
  movslq %eax,%rsi
  add    $0x1,%rax
  lea    0x1(%rdx),%rdi
  cmp    %r10,%rax
  je     L41
L47:
  cmpb   $0x0,-0x1(%r9,%rax,1)
  mov    %rdi,%rdx
  jne    L39
L5:
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  lea    (%rcx,%rsi,1),%rdx
  movb   $0x0,(%rdx)
  ret
L11:
  mov    %rcx,%rdx
  jmp    L5
```

assistant: ```c
void substring(const char source[], int start, int count, char result[]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; i++)
    result[i] = source[i + start];
  result[i] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substring>:
  endbr64
  mov    %rdi,%r9
  test   %edx,%edx
  jle    L23
  movslq %esi,%rsi
  mov    %rcx,%rdi
  lea    0x1(%rdx),%r10d
  mov    $0x1,%eax
  lea    (%r9,%rsi,1),%r8
  jmp    L33
L10:
  movzbl -0x1(%r8,%rax,1),%esi
  mov    %sil,(%rdi)
  movslq %eax,%rsi
  add    $0x1,%rax
  lea    0x1(%rdx),%rdi
  cmp    %r10,%rax
  je     L14
L33:
  cmpb   $0x0,-0x1(%r9,%rax,1)
  mov    %rdi,%rdx
  jne    L10
L28:
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  lea    (%rcx,%rsi,1),%rdx
  movb   $0x0,(%rdx)
  ret
L23:
  mov    %rcx,%rdx
  jmp    L28
```

assistant: ```c
void substring(const char source[], int start, int count, char result[]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; i++)
    result[i] = source[i + start];
  result[i] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<degRange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  jmp    L35
L37:
  movsd  -0x8(%rbp),%xmm0
  movsd  D2(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L35:
  movsd  -0x8(%rbp),%xmm0
  comisd D2(%rip),%xmm0
  jae    L37
  jmp    L19
L8:
  movsd  -0x8(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L19:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L8
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: f64

tool: D2: 360

assistant: ```c
double degRange(double d) {
  while (d >= 360.0)
    d -= 360.0;
  while (d < 0.0)
    d += 360.0;
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<degRange>:
  endbr64
  movsd  D2(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L12
L37:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  jae    L37
L12:
  movsd  D2(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L5
L39:
  addsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  ja     L39
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: f64

tool: D2: 360

assistant: ```c
double degRange(double d) {
  while (d >= 360.0)
    d -= 360.0;
  while (d < 0.0)
    d += 360.0;
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<degRange>:
  endbr64
  movsd  D9(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L10
  nopw   0x0(%rax,%rax,1)
L24:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  jae    L24
L10:
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  jbe    L8
  nopl   0x0(%rax)
L16:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L16
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: f64

tool: D9: 360

assistant: ```c
double degRange(double d) {
  while (d >= 360.0)
    d -= 360.0;
  while (d < 0.0)
    d += 360.0;
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<degRange>:
  endbr64
  movsd  D6(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L2
  nopw   0x0(%rax,%rax,1)
L10:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  jae    L10
L2:
  pxor   %xmm2,%xmm2
  comisd %xmm0,%xmm2
  jbe    L3
  nopl   0x0(%rax)
L32:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L32
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: f64

tool: D6: 360

assistant: ```c
double degRange(double d) {
  while (d >= 360.0)
    d -= 360.0;
  while (d < 0.0)
    d += 360.0;
  return d;
}
```