ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmd_sym_del>:
  endbr64
  push   %rbx
  call   <get_arg@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <stab_del@plt>
  test   %rax,%rax
  js     L15
  mov    $0x1,%edi
  call   <mark_modified@plt>
  mov    $0x0,%eax
L6:
  pop    %rbx
  ret
L35:
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  jmp    L6
L15:
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D8: sym: need a name to delete symbol table entries


tool: D11: sym: can't delete nonexistent symbol: %s


assistant: ```c
int cmd_sym_del(char **arg) {
  char *name = get_arg(arg);
  if (!name) {
    printc_err("sym: need a name to delete "
               "symbol table entries\n");
    return -1;
  }
  if (stab_del(name) < 0) {
    printc_err("sym: can't delete nonexistent symbol: %s\n", name);
    return -1;
  }
  mark_modified(0x01);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_sym_del>:
  endbr64
  push   %rbp
  call   <get_arg@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <stab_del@plt>
  test   %rax,%rax
  js     L0
  mov    $0x1,%edi
  call   <mark_modified@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L6:
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D16
data_type: string

tool: D10: sym: can't delete nonexistent symbol: %s


tool: D16: sym: need a name to delete symbol table entries


assistant: ```c
int cmd_sym_del(char **arg) {
  char *name = get_arg(arg);
  if (!name) {
    printc_err("sym: need a name to delete "
               "symbol table entries\n");
    return -1;
  }
  if (stab_del(name) < 0) {
    printc_err("sym: can't delete nonexistent symbol: %s\n", name);
    return -1;
  }
  mark_modified(0x01);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmd_sym_del>:
  endbr64
  push   %rbp
  call   <get_arg@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <stab_del@plt>
  test   %rax,%rax
  js     L8
  mov    $0x1,%edi
  call   <mark_modified@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L1:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printc_err@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D4: sym: can't delete nonexistent symbol: %s


tool: D7: sym: need a name to delete symbol table entries


assistant: ```c
int cmd_sym_del(char **arg) {
  char *name = get_arg(arg);
  if (!name) {
    printc_err("sym: need a name to delete "
               "symbol table entries\n");
    return -1;
  }
  if (stab_del(name) < 0) {
    printc_err("sym: can't delete nonexistent symbol: %s\n", name);
    return -1;
  }
  mark_modified(0x01);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x68,-0x12(%rbp)
  movb   $0x65,-0x11(%rbp)
  movb   $0x6c,-0x10(%rbp)
  movb   $0x6c,-0xf(%rbp)
  movb   $0x6f,-0xe(%rbp)
  movb   $0x0,-0xd(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x20(%rbp)
  jmp    L23
L16:
  lea    -0x12(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x20(%rbp)
L23:
  lea    -0x12(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D12
type_guessed: string

tool: D22: The individual characters: [

tool: D25: '%c', 

tool: D6: ]

tool: D12: The string: (%s)


assistant: ```c
int main(int argc, char **argv) {
  char values[10];
  size_t i;
  values[0] = 'h';
  values[1] = 'e';
  values[2] = 'l';
  values[3] = 'l';
  values[4] = 'o';
  values[5] = '\0';
  printf("The individual characters: [");
  for (i = 0; values[i] != '\0'; i++) {
    printf("'%c', ", values[i]);
  }
  printf("]\n");
  printf("The string: (%s)\n", values);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x68,0xe(%rsp)
  movb   $0x65,0xf(%rsp)
  movb   $0x6c,0x10(%rsp)
  movb   $0x6c,0x11(%rsp)
  movb   $0x6f,0x12(%rsp)
  movb   $0x0,0x13(%rsp)
  lea    D33(%rip),%rdi
  call   <printf@plt>
  movzbl 0xe(%rsp),%esi
  test   %sil,%sil
  je     L6
  lea    0xf(%rsp),%rbx
  lea    D19(%rip),%rbp
L8:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L8
L6:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0xe(%rsp),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D33
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string

tool: D33: The individual characters: [

tool: D19: '%c', 

tool: D18: ]

tool: D16: The string: (%s)


assistant: ```c
int main(int argc, char **argv) {
  char values[10];
  size_t i;
  values[0] = 'h';
  values[1] = 'e';
  values[2] = 'l';
  values[3] = 'l';
  values[4] = 'o';
  values[5] = '\0';
  printf("The individual characters: [");
  for (i = 0; values[i] != '\0'; i++) {
    printf("'%c', ", values[i]);
  }
  printf("]\n");
  printf("The string: (%s)\n", values);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6f,%edx
  lea    D18(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6568,0xe(%rsp)
  mov    %dx,0x12(%rsp)
  call   <printf@plt>
  movsbl 0xe(%rsp),%esi
  test   %sil,%sil
  je     L14
  lea    0xf(%rsp),%rbx
  lea    D7(%rip),%rbp
  xchg   %ax,%ax
L0:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L0
L14:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0xe(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D16
datatype: string

tool: D18: The individual characters: [

tool: D7: '%c', 

tool: D8: ]

tool: D16: The string: (%s)


assistant: ```c
int main(int argc, char **argv) {
  char values[10];
  size_t i;
  values[0] = 'h';
  values[1] = 'e';
  values[2] = 'l';
  values[3] = 'l';
  values[4] = 'o';
  values[5] = '\0';
  printf("The individual characters: [");
  for (i = 0; values[i] != '\0'; i++) {
    printf("'%c', ", values[i]);
  }
  printf("]\n");
  printf("The string: (%s)\n", values);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6f,%edx
  lea    D19(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6568,0xc(%rsp)
  mov    %dx,0x10(%rsp)
  call   <printf@plt>
  movsbl 0xc(%rsp),%esi
  test   %sil,%sil
  je     L25
  lea    0xd(%rsp),%rbx
  lea    D33(%rip),%rbp
  xchg   %ax,%ax
L7:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%esi
  test   %sil,%sil
  jne    L7
L25:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D33
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D27
type_guessed: string

tool: D19: The individual characters: [

tool: D33: '%c', 

tool: D26: ]

tool: D27: The string: (%s)


assistant: ```c
int main(int argc, char **argv) {
  char values[10];
  size_t i;
  values[0] = 'h';
  values[1] = 'e';
  values[2] = 'l';
  values[3] = 'l';
  values[4] = 'o';
  values[5] = '\0';
  printf("The individual characters: [");
  for (i = 0; values[i] != '\0'; i++) {
    printf("'%c', ", values[i]);
  }
  printf("]\n");
  printf("The string: (%s)\n", values);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<clear_dlt_WORM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_WORM@plt>
  leave
  ret
```

assistant: ```c
uint8_t clear_dlt_WORM(struct list_head *m) {
  ;
  return clear_WORM(m);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clear_dlt_WORM>:
  endbr64
  sub    $0x8,%rsp
  call   <clear_WORM@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t clear_dlt_WORM(struct list_head *m) {
  ;
  return clear_WORM(m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_dlt_WORM>:
  endbr64
  jmp    1050 <clear_WORM@plt>
```

assistant: ```c
uint8_t clear_dlt_WORM(struct list_head *m) {
  ;
  return clear_WORM(m);
}
```
user: What is the c source code of the assembly code below:

```asm
<clear_dlt_WORM>:
  endbr64
  jmp    1050 <clear_WORM@plt>
```

assistant: ```c
uint8_t clear_dlt_WORM(struct list_head *m) {
  ;
  return clear_WORM(m);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <main2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: Hello!


assistant: ```c
int main() {
  printf("Hello!\n");
  main2();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <main2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: Hello!


assistant: ```c
int main() {
  printf("Hello!\n");
  main2();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <main2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: Hello!


assistant: ```c
int main() {
  printf("Hello!\n");
  main2();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <main2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: Hello!


assistant: ```c
int main() {
  printf("Hello!\n");
  main2();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<error_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xfffff830,-0x4(%rbp)
  jl     L18
  cmpl   $0xfffff844,-0x4(%rbp)
  jge    L18
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash_error_string@plt>
  jmp    L4
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
L4:
  leave
  ret
```

assistant: ```c
const char *error_string(int error) {
  if ((((error) >= -2000) && ((error) < (-2000 + 20))))
    return hash_error_string(error);
  return strerror(error);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<error_string>:
  endbr64
  sub    $0x8,%rsp
  lea    0x7d0(%rdi),%eax
  cmp    $0x13,%eax
  jbe    L17
  call   <strerror@plt>
L5:
  add    $0x8,%rsp
  ret
L17:
  call   <hash_error_string@plt>
  jmp    L5
```

assistant: ```c
const char *error_string(int error) {
  if ((((error) >= -2000) && ((error) < (-2000 + 20))))
    return hash_error_string(error);
  return strerror(error);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error_string>:
  endbr64
  lea    0x7d0(%rdi),%eax
  cmp    $0x13,%eax
  jbe    L9
  jmp    1070 <strerror@plt>
  nopl   0x0(%rax)
L9:
  jmp    1060 <hash_error_string@plt>
```

assistant: ```c
const char *error_string(int error) {
  if ((((error) >= -2000) && ((error) < (-2000 + 20))))
    return hash_error_string(error);
  return strerror(error);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<error_string>:
  endbr64
  lea    0x7d0(%rdi),%eax
  cmp    $0x13,%eax
  jbe    L7
  jmp    1070 <strerror@plt>
  nopl   0x0(%rax)
L7:
  jmp    1060 <hash_error_string@plt>
```

assistant: ```c
const char *error_string(int error) {
  if ((((error) >= -2000) && ((error) < (-2000 + 20))))
    return hash_error_string(error);
  return strerror(error);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L15:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L15
  jmp    L20
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L20:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dest, char const *src, int n) {
  char *p = dest;
  while (((*(p++) = *(src++)) != '\0') && (n--))
    ;
  while (n--)
    *p++ = 0;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  lea    0x1(%rsi,%rcx,1),%r9
  mov    %rdi,%rcx
L12:
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%r8d
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L39
  sub    $0x1,%edx
  cmp    %r9,%rsi
  jne    L12
L39:
  mov    %edx,%esi
  add    %rcx,%rsi
  test   %edx,%edx
  je     L36
L16:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rsi,%rcx
  jne    L16
  ret
L36:
  ret
```

assistant: ```c
char *strncpy(char *dest, char const *src, int n) {
  char *p = dest;
  while (((*(p++) = *(src++)) != '\0') && (n--))
    ;
  while (n--)
    *p++ = 0;
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncpy>:
  endbr64
  mov    %edx,%eax
  push   %r12
  mov    %rdi,%r12
  lea    0x1(%rdi,%rax,1),%r8
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rsi
  cmp    %r8,%rdi
  je     L19
L14:
  movzbl (%rsi),%eax
  add    $0x1,%rdi
  mov    %edx,%ecx
  sub    $0x1,%edx
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L38
  test   %ecx,%ecx
  je     L3
L28:
  add    $0x1,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L3:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  mov    $0xfffffffe,%edx
  jmp    L28
```

assistant: ```c
char *strncpy(char *dest, char const *src, int n) {
  char *p = dest;
  while (((*(p++) = *(src++)) != '\0') && (n--))
    ;
  while (n--)
    *p++ = 0;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy>:
  endbr64
  mov    %edx,%eax
  push   %r12
  mov    %rdi,%r12
  lea    0x1(%rdi,%rax,1),%r8
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rsi
  cmp    %r8,%rdi
  je     L7
L28:
  movzbl (%rsi),%eax
  add    $0x1,%rdi
  mov    %edx,%ecx
  sub    $0x1,%edx
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L12
  test   %ecx,%ecx
  je     L10
L14:
  add    $0x1,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L10:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xfffffffe,%edx
  jmp    L14
```

assistant: ```c
char *strncpy(char *dest, char const *src, int n) {
  char *p = dest;
  while (((*(p++) = *(src++)) != '\0') && (n--))
    ;
  while (n--)
    *p++ = 0;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strnicmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L3
L21:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L45
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L45
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L3
L45:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L33
L3:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  jne    L21
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strnicmp(const char *s1, const char *s2, size_t n) {
  char *ts1 = (char *)s1;
  char *ts2 = (char *)s2;
  while (n--) {
    if (*ts1 && (toupper(*ts1) == toupper(*ts2))) {
      ts1++;
      ts2++;
    } else {
      return (*ts1 - *ts2);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnicmp>:
  endbr64
  test   %rdx,%rdx
  je     L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    (%rdi,%rdx,1),%r13
L33:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L23
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%rbp
  movsbl (%r12),%edi
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L23
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %r13,%rbx
  jne    L33
  mov    $0x0,%eax
  jmp    L13
L23:
  movsbl (%rbx),%eax
  movsbl (%r12),%edx
  sub    %edx,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strnicmp(const char *s1, const char *s2, size_t n) {
  char *ts1 = (char *)s1;
  char *ts2 = (char *)s2;
  while (n--) {
    if (*ts1 && (toupper(*ts1) == toupper(*ts2))) {
      ts1++;
      ts2++;
    } else {
      return (*ts1 - *ts2);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnicmp>:
  endbr64
  push   %r13
  lea    (%rdi,%rdx,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L40
  jmp    L31
  nop
L12:
  call   <toupper@plt>
  movsbl (%r12),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L34
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %r13,%rbx
  je     L31
L40:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L49:
  movsbl (%r12),%edx
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  pop    %r13
  ret
L31:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L34:
  movsbl (%rbx),%edi
  jmp    L49
```

assistant: ```c
int strnicmp(const char *s1, const char *s2, size_t n) {
  char *ts1 = (char *)s1;
  char *ts2 = (char *)s2;
  while (n--) {
    if (*ts1 && (toupper(*ts1) == toupper(*ts2))) {
      ts1++;
      ts2++;
    } else {
      return (*ts1 - *ts2);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnicmp>:
  endbr64
  push   %r13
  lea    (%rdi,%rdx,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L8
  jmp    L48
  nop
L54:
  call   <toupper@plt>
  movsbl (%r12),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L15
  add    $0x1,%rbx
  add    $0x1,%r12
  cmp    %r13,%rbx
  je     L48
L8:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L54
L59:
  movsbl (%r12),%edx
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  sub    %edx,%eax
  pop    %r12
  pop    %r13
  ret
L48:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L15:
  movsbl (%rbx),%edi
  jmp    L59
```

assistant: ```c
int strnicmp(const char *s1, const char *s2, size_t n) {
  char *ts1 = (char *)s1;
  char *ts2 = (char *)s2;
  while (n--) {
    if (*ts1 && (toupper(*ts1) == toupper(*ts2))) {
      ts1++;
      ts2++;
    } else {
      return (*ts1 - *ts2);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getopt_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <getopt_internal@plt>
  leave
  ret
```

assistant: ```c
int getopt_long(nargc, nargv, options, long_options, idx)
int nargc;
char *const *nargv;
const char *options;
const struct option *long_options;
int *idx;
{ return (getopt_internal(nargc, nargv, options, long_options, idx, 0x01)); }
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getopt_long>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  mov    $0x0,%eax
  call   <getopt_internal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int getopt_long(nargc, nargv, options, long_options, idx)
int nargc;
char *const *nargv;
const char *options;
const struct option *long_options;
int *idx;
{ return (getopt_internal(nargc, nargv, options, long_options, idx, 0x01)); }
```