ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gf8mul_00011000>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm4,%xmm1
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm3,%xmm0
  ret
```

assistant: ```c
void gf8mul_00011000(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm3, %xmm0\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gf8mul_00011000>:
  endbr64
  pxor   %xmm7,%xmm6
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm3
  pxor   %xmm6,%xmm2
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm3
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm5,%xmm4
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm6,%xmm3
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm5,%xmm2
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm4,%xmm1
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm3,%xmm0
  ret
```

assistant: ```c
void gf8mul_00011000(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm6\n"
                       "\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm3\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm3, %xmm0\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xstrcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L10
L6:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
char *xstrcpy(char *src) {
  char *tmp;
  if (src == NULL)
    return (NULL);
  tmp = xmalloc(strlen(src) + 1);
  strcpy(tmp, src);
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<xstrcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L12
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rdi,%rbp
  jmp    L3
```

assistant: ```c
char *xstrcpy(char *src) {
  char *tmp;
  if (src == NULL)
    return (NULL);
  tmp = xmalloc(strlen(src) + 1);
  strcpy(tmp, src);
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xstrcpy>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xstrcpy(char *src) {
  char *tmp;
  if (src == NULL)
    return (NULL);
  tmp = xmalloc(strlen(src) + 1);
  strcpy(tmp, src);
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrcpy>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xstrcpy(char *src) {
  char *tmp;
  if (src == NULL)
    return (NULL);
  tmp = xmalloc(strlen(src) + 1);
  strcpy(tmp, src);
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pack_seg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x8,-0x30(%rbp)
  subl   $0x1,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L35
  movq   $0x0,-0x8(%rbp)
L35:
  movl   $0x0,-0x14(%rbp)
  jmp    L40
L87:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L59
  addl   $0x1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,-0x10(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jle    L59
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x30(%rbp)
  subl   $0x1,-0x34(%rbp)
L59:
  addl   $0x1,-0x14(%rbp)
L40:
  cmpl   $0x7,-0x14(%rbp)
  jle    L87
  cmpl   $0x7,-0x18(%rbp)
  je     L8
  cmpl   $0x6,-0x18(%rbp)
  jne    L18
L8:
  cmpl   $0x0,-0x38(%rbp)
  jle    L18
  movl   $0x8,-0x18(%rbp)
L18:
  cmpl   $0x8,-0x18(%rbp)
  jne    L98
  cmpl   $0x0,-0x38(%rbp)
  jle    L92
  mov    $0x8,%eax
  jmp    L36
L92:
  mov    $0xa,%eax
  jmp    L36
L98:
  cmpq   $0x0,-0x8(%rbp)
  je     L111
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L111:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int pack_seg(const uint8_t *src, uint8_t *buffer, int sz, int n) {
  uint8_t header = 0;
  int notzero = 0;
  int i;
  uint8_t *obuffer = buffer;
  ++buffer;
  --sz;
  if (sz < 0)
    obuffer = NULL;
  for (i = 0; i < 8; i++) {
    if (src[i] != 0) {
      notzero++;
      header |= 1 << i;
      if (sz > 0) {
        *buffer = src[i];
        ++buffer;
        --sz;
      }
    }
  }
  if ((notzero == 7 || notzero == 6) && n > 0) {
    notzero = 8;
  }
  if (notzero == 8) {
    if (n > 0) {
      return 8;
    } else {
      return 10;
    }
  }
  if (obuffer) {
    *obuffer = header;
  }
  return notzero + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_seg>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r11
  mov    %ecx,%ebp
  lea    0x8(%rsi),%r10
  sub    $0x1,%edx
  mov    $0x0,%eax
  cmovs  %rax,%r11
  mov    $0x0,%ecx
  mov    $0x0,%edi
  mov    $0x0,%r9d
  mov    $0x1,%ebx
  jmp    L20
L82:
  add    $0x1,%rcx
  cmp    $0x8,%rcx
  je     L12
L20:
  mov    (%r8,%rcx,8),%rax
  test   %rax,%rax
  je     L82
  add    $0x1,%edi
  mov    %ebx,%esi
  shl    %cl,%esi
  movslq %esi,%rsi
  or     %rsi,%r9
  test   %edx,%edx
  jle    L82
  mov    %rax,(%r10)
  add    $0x8,%r10
  sub    $0x1,%edx
  jmp    L82
L12:
  lea    -0x6(%rdi),%eax
  cmp    $0x1,%eax
  ja     L54
  test   %ebp,%ebp
  jg     L87
L54:
  cmp    $0x8,%edi
  je     L36
  test   %r11,%r11
  je     L23
  mov    %r9,(%r11)
L23:
  add    $0x1,%edi
L30:
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  test   %ebp,%ebp
  mov    $0xa,%eax
  cmovle %eax,%edi
  jmp    L30
L87:
  mov    $0x8,%edi
  jmp    L30
```

assistant: ```c
int pack_seg(const uint8_t *src, uint8_t *buffer, int sz, int n) {
  uint8_t header = 0;
  int notzero = 0;
  int i;
  uint8_t *obuffer = buffer;
  ++buffer;
  --sz;
  if (sz < 0)
    obuffer = NULL;
  for (i = 0; i < 8; i++) {
    if (src[i] != 0) {
      notzero++;
      header |= 1 << i;
      if (sz > 0) {
        *buffer = src[i];
        ++buffer;
        --sz;
      }
    }
  }
  if ((notzero == 7 || notzero == 6) && n > 0) {
    notzero = 8;
  }
  if (notzero == 8) {
    if (n > 0) {
      return 8;
    } else {
      return 10;
    }
  }
  if (obuffer) {
    *obuffer = header;
  }
  return notzero + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pack_seg>:
  endbr64
  sub    $0x1,%edx
  mov    %rsi,%r11
  mov    $0x0,%eax
  push   %rbp
  cmovs  %rax,%r11
  push   %rbx
  mov    %ecx,%ebp
  lea    0x8(%rsi),%r10
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L66:
  mov    (%rdi,%rcx,8),%rax
  test   %rax,%rax
  je     L25
  mov    %ebx,%esi
  add    $0x1,%r8d
  shl    %cl,%esi
  movslq %esi,%rsi
  or     %rsi,%r9
  test   %edx,%edx
  jle    L25
  mov    %rax,(%r10)
  sub    $0x1,%edx
  add    $0x8,%r10
L25:
  add    $0x1,%rcx
  cmp    $0x8,%rcx
  jne    L66
  lea    -0x6(%r8),%eax
  cmp    $0x1,%eax
  jbe    L59
  cmp    $0x8,%r8d
  je     L5
L58:
  test   %r11,%r11
  je     L21
  mov    %r9,(%r11)
L21:
  add    $0x1,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
L5:
  test   %ebp,%ebp
  mov    $0xa,%eax
  pop    %rbx
  pop    %rbp
  cmovle %eax,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L59:
  test   %ebp,%ebp
  jle    L58
  mov    $0x8,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pack_seg(const uint8_t *src, uint8_t *buffer, int sz, int n) {
  uint8_t header = 0;
  int notzero = 0;
  int i;
  uint8_t *obuffer = buffer;
  ++buffer;
  --sz;
  if (sz < 0)
    obuffer = NULL;
  for (i = 0; i < 8; i++) {
    if (src[i] != 0) {
      notzero++;
      header |= 1 << i;
      if (sz > 0) {
        *buffer = src[i];
        ++buffer;
        --sz;
      }
    }
  }
  if ((notzero == 7 || notzero == 6) && n > 0) {
    notzero = 8;
  }
  if (notzero == 8) {
    if (n > 0) {
      return 8;
    } else {
      return 10;
    }
  }
  if (obuffer) {
    *obuffer = header;
  }
  return notzero + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6548,%rax
  mov    %rax,-0x2f(%rbp)
  movl   $0x21646c72,-0x27(%rbp)
  movw   $0xa,-0x23(%rbp)
  movb   $0x0,-0x21(%rbp)
  lea    -0x2f(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: %s

assistant: ```c
int main() {
  char t[15] = "Hello world!\n";
  char s[20];
  strcpy(s, t);
  printf("%s", s);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f77206f6c6c6548,%rax
  mov    %rax,0x1(%rsp)
  movl   $0x21646c72,0x9(%rsp)
  movw   $0xa,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0x1(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %s

assistant: ```c
int main() {
  char t[15] = "Hello world!\n";
  char s[20];
  strcpy(s, t);
  printf("%s", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6f77206f6c6c6548,%rax
  lea    0x10(%rsp),%rbp
  lea    0x1(%rsp),%rsi
  movl   $0x21646c72,0x9(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x1(%rsp)
  mov    $0xa,%eax
  mov    %ax,0xd(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %s

assistant: ```c
int main() {
  char t[15] = "Hello world!\n";
  char s[20];
  strcpy(s, t);
  printf("%s", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x6f77206f6c6c6548,%rax
  lea    0x10(%rsp),%rbp
  lea    0x1(%rsp),%rsi
  movl   $0x21646c72,0x9(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x1(%rsp)
  mov    $0xa,%eax
  mov    %ax,0xd(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: %s

assistant: ```c
int main() {
  char t[15] = "Hello world!\n";
  char s[20];
  strcpy(s, t);
  printf("%s", s);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xerox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L23
L1:
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L21:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L21
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
char *xerox(char *s) {
  int i, len;
  char *copy;
  len = str_length(s);
  if ((copy = (char *)malloc(len + 1)) == NULL) {
    return NULL;
  }
  for (i = 0; i < len; i++) {
    copy[i] = s[i];
  }
  copy[len] = '\0';
  return copy;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xerox>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <str_length@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L21
  lea    -0x1(%rbp),%edx
  lea    0x1(%rax,%rdx,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rsi
L29:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L29
L21:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
L23:
  mov    %r8,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0x0,%r8d
  jmp    L23
```

assistant: ```c
char *xerox(char *s) {
  int i, len;
  char *copy;
  len = str_length(s);
  if ((copy = (char *)malloc(len + 1)) == NULL) {
    return NULL;
  }
  for (i = 0; i < len; i++) {
    copy[i] = s[i];
  }
  copy[len] = '\0';
  return copy;
}
```
user: What is the c source code of the assembly code below?

```asm
<xerox>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <str_length@plt>
  movslq %eax,%rbp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  test   %ebp,%ebp
  jle    L24
  lea    -0x1(%rbp),%edx
  sub    %rax,%rbx
  lea    0x1(%rax,%rdx,1),%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%rdi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L11
L24:
  movb   $0x0,(%rax,%rbp,1)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *xerox(char *s) {
  int i, len;
  char *copy;
  len = str_length(s);
  if ((copy = (char *)malloc(len + 1)) == NULL) {
    return NULL;
  }
  for (i = 0; i < len; i++) {
    copy[i] = s[i];
  }
  copy[len] = '\0';
  return copy;
}
```
user: What is the c source code of the assembly code below?

```asm
<xerox>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <str_length@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L32
  test   %ebx,%ebx
  jle    L66
  lea    0x1(%rbp),%rsi
  mov    %r8,%rdx
  lea    -0x1(%rbx),%eax
  mov    %ebx,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L23
  cmp    $0x6,%eax
  jbe    L23
  cmp    $0xe,%eax
  jbe    L119
  mov    %ebx,%eax
  mov    %rbp,%rdx
  shr    $0x4,%eax
  sub    %r8,%rdx
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%r8,%rax,1),%rcx
  mov    %r8,%rax
  cs nopw 0x0(%rax,%rax,1)
L110:
  movdqu (%rax,%rdx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rcx
  jne    L110
  mov    %ebx,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebx
  je     L66
  mov    %ebx,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L85
L57:
  mov    0x0(%rbp,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L66
L85:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L66
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L66
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L66
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L66
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L66
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebx
  jle    L66
  cltq
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L66:
  movb   $0x0,(%r8,%rbx,1)
L32:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L23:
  lea    0x1(%r8,%rax,1),%rcx
  sub    %r8,%rbp
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L127:
  movzbl 0x0(%rbp,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L127
  jmp    L66
L119:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L57
```

assistant: ```c
char *xerox(char *s) {
  int i, len;
  char *copy;
  len = str_length(s);
  if ((copy = (char *)malloc(len + 1)) == NULL) {
    return NULL;
  }
  for (i = 0; i < len; i++) {
    copy[i] = s[i];
  }
  copy[len] = '\0';
  return copy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fwriteUpdateSha1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
L23:
  mov    $0x0,%eax
  jmp    L2
L8:
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA1_Update@plt>
  cmp    $0x1,%eax
  je     L16
  mov    $0x0,%eax
  jmp    L2
L16:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L2:
  leave
  ret
```

assistant: ```c
size_t fwriteUpdateSha1(const void *p, size_t size, size_t nmemb, FILE *fp, SHA_CTX *c) {
  if (p == NULL || c == NULL)
    return 0;
  if (SHA1_Update(c, p, size * nmemb) != 1)
    return 0;
  return fwrite(p, size, nmemb, fp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fwriteUpdateSha1>:
  endbr64
  test   %rdi,%rdi
  je     L23
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    $0x0,%eax
  test   %r8,%r8
  je     L32
  mov    %rsi,%rdx
  imul   %r12,%rdx
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <SHA1_Update@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  je     L31
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  jmp    L32
L23:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t fwriteUpdateSha1(const void *p, size_t size, size_t nmemb, FILE *fp, SHA_CTX *c) {
  if (p == NULL || c == NULL)
    return 0;
  if (SHA1_Update(c, p, size * nmemb) != 1)
    return 0;
  return fwrite(p, size, nmemb, fp);
}
```