ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<preencheVetor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L40
L32:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L32
L40:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L43
L47:
  mov    %rsp,%rcx
  movl   $0x0,-0x3c(%rbp)
  mov    %rcx,-0x50(%rbp)
  test   %r14d,%r14d
  jle    L36
  mov    %r14d,%eax
  mov    %rcx,%r15
  lea    -0x3c(%rbp),%r12
  lea    (%rcx,%rax,4),%r13
  lea    D2(%rip),%rbx
  nopl   0x0(%rax)
L65:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x4(%r15)
  cmp    %r13,%r15
  jne    L65
L36:
  mov    -0x44(%rbp),%edx
  mov    -0x50(%rbp),%rsi
  mov    %r14d,%edi
  call   <shortArray@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L47
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: %d

assistant: ```c
void preencheVetor(int n, int m) {
  int vet[n];
  int i = 0;
  int num = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &num);
    vet[i] = num;
  }
  shortArray(n, vet, m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<preencheVetor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,-0x44(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L26
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L26:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L32
L62:
  mov    %rsp,%rcx
  movl   $0x0,-0x3c(%rbp)
  mov    %rcx,-0x50(%rbp)
  test   %r14d,%r14d
  jle    L34
  mov    %r14d,%eax
  mov    %rcx,%r15
  lea    -0x3c(%rbp),%r12
  lea    (%rcx,%rax,4),%r13
  lea    D5(%rip),%rbx
  nopl   0x0(%rax)
L59:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x4(%r15)
  cmp    %r13,%r15
  jne    L59
L34:
  mov    -0x44(%rbp),%edx
  mov    -0x50(%rbp),%rsi
  mov    %r14d,%edi
  call   <shortArray@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L62
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: %d

assistant: ```c
void preencheVetor(int n, int m) {
  int vet[n];
  int i = 0;
  int num = 0;
  for (i = 0; i < n; i++) {
    scanf("%d", &num);
    vet[i] = num;
  }
  shortArray(n, vet, m);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum_of_squares>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  add    %eax,-0xc(%rbp)
  addq   $0x4,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L14
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum_of_squares(const int16_t *speech, int length, int offset, int shift) {
  const int16_t *speech_end;
  int sum = 0;
  for (speech_end = speech + length; speech < speech_end; speech++)
    sum += (speech[0] * speech[offset]) >> shift;
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_of_squares>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%r8
  cmp    %r8,%rdi
  jae    L9
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    $0x0,%edx
L13:
  mov    (%rdi),%eax
  imul   (%rdi,%rsi,1),%eax
  sar    %cl,%eax
  add    %eax,%edx
  add    $0x4,%rdi
  cmp    %rdi,%r8
  ja     L13
L5:
  mov    %edx,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
int sum_of_squares(const int16_t *speech, int length, int offset, int shift) {
  const int16_t *speech_end;
  int sum = 0;
  for (speech_end = speech + length; speech < speech_end; speech++)
    sum += (speech[0] * speech[offset]) >> shift;
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sum_of_squares>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rsi
  cmp    %rsi,%rdi
  jae    L13
  movslq %edx,%rdx
  xor    %r8d,%r8d
  shl    $0x2,%rdx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rdi),%eax
  imul   (%rdi,%rdx,1),%eax
  add    $0x4,%rdi
  sar    %cl,%eax
  add    %eax,%r8d
  cmp    %rdi,%rsi
  ja     L17
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum_of_squares(const int16_t *speech, int length, int offset, int shift) {
  const int16_t *speech_end;
  int sum = 0;
  for (speech_end = speech + length; speech < speech_end; speech++)
    sum += (speech[0] * speech[offset]) >> shift;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum_of_squares>:
  endbr64
  movslq %esi,%rsi
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%r10
  cmp    %r10,%rdi
  jae    L17
  sub    $0x1,%rsi
  movslq %edx,%rdx
  mov    %rsi,%r9
  lea    0x0(,%rdx,4),%rax
  shr    $0x2,%r9
  add    $0x1,%r9
  cmp    $0xb,%rsi
  jbe    L61
  mov    %r9,%r8
  lea    (%rdi,%rax,1),%rsi
  movslq %ecx,%r11
  xor    %eax,%eax
  shr    $0x2,%r8
  pxor   %xmm3,%xmm3
  movq   %r11,%xmm4
  shl    $0x4,%r8
  nopl   0x0(%rax)
L38:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  movdqu (%rdi,%rax,1),%xmm1
  movdqu (%rsi,%rax,1),%xmm5
  add    $0x10,%rax
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm2
  pmuludq %xmm5,%xmm1
  pmuludq %xmm2,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  psrad  %xmm4,%xmm1
  paddd  %xmm1,%xmm3
  cmp    %r8,%rax
  jne    L38
  movdqa %xmm3,%xmm0
  mov    %r9,%rsi
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffffc,%rsi
  paddd  %xmm0,%xmm3
  lea    (%rdi,%rsi,4),%rdi
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%eax
  cmp    %rsi,%r9
  je     L50
L30:
  mov    (%rdi,%rdx,4),%esi
  imul   (%rdi),%esi
  sar    %cl,%esi
  add    %esi,%eax
  lea    0x4(%rdi),%rsi
  cmp    %rsi,%r10
  jbe    L58
  mov    (%rsi,%rdx,4),%esi
  imul   0x4(%rdi),%esi
  sar    %cl,%esi
  add    %esi,%eax
  lea    0x8(%rdi),%rsi
  cmp    %rsi,%r10
  jbe    L58
  mov    (%rsi,%rdx,4),%edx
  imul   0x8(%rdi),%edx
  sar    %cl,%edx
  add    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
L58:
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  ret
L61:
  xor    %eax,%eax
  jmp    L30
```

assistant: ```c
int sum_of_squares(const int16_t *speech, int length, int offset, int shift) {
  const int16_t *speech_end;
  int sum = 0;
  for (speech_end = speech + length; speech < speech_end; speech++)
    sum += (speech[0] * speech[offset]) >> shift;
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<RSA2048_generate_key_CRT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <RSA2048_execute@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
L3:
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D18: BF10C08000

tool: D7: ERR:RSA2048_generate_key_CRT failed!


assistant: ```c
int RSA2048_generate_key_CRT(int fd) {
  int ret;
  ret = RSA2048_execute(fd, "BF10C08000");
  if (ret != 0) {
    printf("ERR:RSA2048_generate_key_CRT failed!\n");
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RSA2048_generate_key_CRT>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <RSA2048_execute@plt>
  test   %eax,%eax
  jne    L14
L2:
  add    $0x8,%rsp
  ret
L14:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D7: BF10C08000

tool: D1: ERR:RSA2048_generate_key_CRT failed!


assistant: ```c
int RSA2048_generate_key_CRT(int fd) {
  int ret;
  ret = RSA2048_execute(fd, "BF10C08000");
  if (ret != 0) {
    printf("ERR:RSA2048_generate_key_CRT failed!\n");
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RSA2048_generate_key_CRT>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  call   <RSA2048_execute@plt>
  test   %eax,%eax
  jne    L1
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L1:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D19
type: string

tool: D17: BF10C08000

tool: D19: ERR:RSA2048_generate_key_CRT failed!


assistant: ```c
int RSA2048_generate_key_CRT(int fd) {
  int ret;
  ret = RSA2048_execute(fd, "BF10C08000");
  if (ret != 0) {
    printf("ERR:RSA2048_generate_key_CRT failed!\n");
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RSA2048_generate_key_CRT>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <RSA2048_execute@plt>
  test   %eax,%eax
  jne    L1
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L1:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D1: BF10C08000

tool: D8: ERR:RSA2048_generate_key_CRT failed!


assistant: ```c
int RSA2048_generate_key_CRT(int fd) {
  int ret;
  ret = RSA2048_execute(fd, "BF10C08000");
  if (ret != 0) {
    printf("ERR:RSA2048_generate_key_CRT failed!\n");
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0xe80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4e70(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movl   $0x0,-0x4e74(%rbp)
  jmp    L28
L39:
  mov    -0x4e74(%rbp),%eax
  cltq
  mov    -0x4e50(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <shashawen@plt>
  addl   $0x1,-0x4e74(%rbp)
L28:
  cmpl   $0x1391,-0x4e74(%rbp)
  jle    L39
  lea    -0x4e60(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x4e60(%rbp),%eax
  mov    -0x4e70(%rbp),%edx
  sub    %edx,%eax
  imul   $0x3e8,%eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x4e58(%rbp),%rax
  mov    -0x4e68(%rbp),%rdx
  sub    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D16(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type: byte[8]
name: parse_data
arguments: data_label: D1
type: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D1: %lf s used


assistant: ```c
void main() {
  int test[5010];
  int i;
  struct timeval start, end;
  gettimeofday(&start, NULL);
  for (i = 0; i < 5010; ++i)
    shashawen(test[i]);
  gettimeofday(&end, NULL);
  printf("%lf s used\n", (end.tv_sec - start.tv_sec) * 1000 + (double)(end.tv_usec - start.tv_usec) / 1000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xe78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0x20(%rsp),%rbx
  lea    0x4e68(%rsp),%rbp
L17:
  mov    (%rbx),%edi
  call   <shashawen@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L17
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x10(%rsp),%eax
  sub    (%rsp),%eax
  imul   $0x3e8,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    0x18(%rsp),%rax
  sub    0x8(%rsp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  D3(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x4e68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x4e78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: byte[8]
name: retrieve_data
arguments: label: D10
datatype: string

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D10: %lf s used


assistant: ```c
void main() {
  int test[5010];
  int i;
  struct timeval start, end;
  gettimeofday(&start, NULL);
  for (i = 0; i < 5010; ++i)
    shashawen(test[i]);
  gettimeofday(&end, NULL);
  printf("%lf s used\n", (end.tv_sec - start.tv_sec) * 1000 + (double)(end.tv_usec - start.tv_usec) / 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xe78,%rsp
  xor    %esi,%esi
  mov    %rsp,%rdi
  lea    0x20(%rsp),%rbx
  lea    0x4e68(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e68(%rsp)
  xor    %eax,%eax
  call   <gettimeofday@plt>
L13:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <shashawen@plt>
  cmp    %rbp,%rbx
  jne    L13
  xor    %esi,%esi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x10(%rsp),%eax
  sub    (%rsp),%eax
  pxor   %xmm0,%xmm0
  imul   $0x3e8,%eax,%eax
  pxor   %xmm1,%xmm1
  lea    D7(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  mov    0x18(%rsp),%rax
  sub    0x8(%rsp),%rax
  cvtsi2sd %rax,%xmm1
  divsd  D0(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x4e68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x4e78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: byte[8]

tool: D7: %lf s used


tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
void main() {
  int test[5010];
  int i;
  struct timeval start, end;
  gettimeofday(&start, NULL);
  for (i = 0; i < 5010; ++i)
    shashawen(test[i]);
  gettimeofday(&end, NULL);
  printf("%lf s used\n", (end.tv_sec - start.tv_sec) * 1000 + (double)(end.tv_usec - start.tv_usec) / 1000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0xe78,%rsp
  xor    %esi,%esi
  mov    %rsp,%rdi
  lea    0x20(%rsp),%rbx
  lea    0x4e68(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e68(%rsp)
  xor    %eax,%eax
  call   <gettimeofday@plt>
L19:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <shashawen@plt>
  cmp    %rbp,%rbx
  jne    L19
  xor    %esi,%esi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    0x10(%rsp),%eax
  sub    (%rsp),%eax
  pxor   %xmm0,%xmm0
  imul   $0x3e8,%eax,%eax
  pxor   %xmm1,%xmm1
  lea    D10(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  mov    0x18(%rsp),%rax
  sub    0x8(%rsp),%rax
  cvtsi2sd %rax,%xmm1
  divsd  D7(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x4e68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x4e78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: byte[8]

tool: D10: %lf s used


tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
void main() {
  int test[5010];
  int i;
  struct timeval start, end;
  gettimeofday(&start, NULL);
  for (i = 0; i < 5010; ++i)
    shashawen(test[i]);
  gettimeofday(&end, NULL);
  printf("%lf s used\n", (end.tv_sec - start.tv_sec) * 1000 + (double)(end.tv_usec - start.tv_usec) / 1000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getusec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned getusec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: What is the c source code of the assembly code below?

```asm
<getusec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned getusec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getusec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned getusec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getusec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  add    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned getusec() {
  struct timeval tv;
  gettimeofday(&tv, 0);
  return tv.tv_sec * 1000000 + tv.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<c_read_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: %d

assistant: ```c
int c_read_int() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<c_read_int>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: %d

assistant: ```c
int c_read_int() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<c_read_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int c_read_int() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<c_read_int>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: %d

assistant: ```c
int c_read_int() {
  int n;
  scanf("%d", &n);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  jle    L2
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L2:
  movl   $0x9,-0xc(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D36
data_type: string

tool: D0: Enter a number 

tool: D14: %d

tool: D16: %d is larger than 9 


tool: D36: Your input was 9 

assistant: ```c
void main() {
  int var;
  printf("Enter a number \n");
  scanf("%d", &var);
  if (var > 9)
    printf("%d is larger than 9 \n", var);
  else if (var = 9)
    printf("Your input was 9 \n");
  else
    printf("%d is smaller than 9 \n", var);
}
```