user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
L54:
  lea    D67(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  je     L1
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  cmp    $0x28,%eax
  jle    L30
  mov    -0x24(%rbp),%eax
  sub    $0x28,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  test   %rax,%rax
  js     L35
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L56
L35:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L56:
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm0,%xmm1
  movss  D11(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x20(%rbp),%xmm1
  movss  D35(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L22
L30:
  mov    -0x24(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
L22:
  movss  -0x18(%rbp),%xmm0
  addss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L1:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L54
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D67
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D83
type: string
name: extract_symbolic_data
arguments: data_tag: D54
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: f32
name: extract_symbolic_data
arguments: data_tag: D35
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D67: Inserire numero di ore di lavoro (-1 per uscire): 

tool: D8: %s

tool: D83: %u

tool: D54: Inserire paga oraria per il lavoratore ($00.00): 

tool: D31: %f

tool: D11: 1.5

tool: {"D35": [0x00,0x00,0x20,0x42]}

tool: D18: Il Salario e: $%.02f


assistant: ```c
int main(void) {
  int oreDiLavoro = 0;
  float pagaStandard = 0;
  int valoreSentinella = -1;
  unsigned int oreStraordinario = 0;
  float importoStraordinario = 0;
  float importoStandard = 0;
  float importoSalario = 0;
  do {
    printf("%s", "Inserire numero di ore di lavoro (-1 per uscire): ");
    scanf("%u", &oreDiLavoro);
    if (oreDiLavoro != valoreSentinella) {
      printf("%s", "Inserire paga oraria per il lavoratore ($00.00): ");
      scanf("%f", &pagaStandard);
      if (oreDiLavoro > (int)40) {
        oreStraordinario = (oreDiLavoro - (int)40);
        importoStraordinario = ((pagaStandard * (float)oreStraordinario) * (float)1.5);
        importoStandard = (pagaStandard * (float)40);
      } else {
        importoStandard = (pagaStandard * (float)oreDiLavoro);
      }
      importoSalario = (importoStandard + importoStraordinario);
      printf("Il Salario e: $%.02f\n", importoSalario);
    }
  } while (oreDiLavoro != valoreSentinella);
  return 0;
}
```