ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<AsserT>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%ebx
  test   %esi,%esi
  je     L23
  test   %edx,%edx
  je     L23
  test   %ecx,%ecx
  je     L23
  test   %r8d,%r8d
  je     L23
  test   %r9d,%r9d
  je     L23
  mov    $0x1,%edi
  test   %ebx,%ebx
  jne    L27
  nopl   0x0(%rax)
L23:
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x2,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x3,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x4,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x5,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  mov    %ebx,%esi
  call   <AsserT0@plt>
  xor    %edi,%edi
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <assert@plt>
```

assistant: ```c
void AsserT(char *sContexte, int bAssertion1, int bAssertion2, int bAssertion3, int bAssertion4, int bAssertion5, int bAssertion6) {
  int bAssertion = bAssertion1 && bAssertion2 && bAssertion3 && bAssertion4 && bAssertion5 && bAssertion6;
  if (!bAssertion) {
    AsserT0(sContexte, bAssertion1, 1);
    AsserT0(sContexte, bAssertion2, 2);
    AsserT0(sContexte, bAssertion3, 3);
    AsserT0(sContexte, bAssertion4, 4);
    AsserT0(sContexte, bAssertion5, 5);
    AsserT0(sContexte, bAssertion6, 6);
  }
  assert(bAssertion);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AsserT>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%ebx
  test   %esi,%esi
  je     L34
  test   %edx,%edx
  je     L34
  test   %ecx,%ecx
  je     L34
  test   %r8d,%r8d
  je     L34
  test   %r9d,%r9d
  je     L34
  mov    $0x1,%edi
  test   %ebx,%ebx
  jne    L27
  nopl   0x0(%rax)
L34:
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x2,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x3,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x4,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    $0x5,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <AsserT0@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  mov    %ebx,%esi
  call   <AsserT0@plt>
  xor    %edi,%edi
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <assert@plt>
```

assistant: ```c
void AsserT(char *sContexte, int bAssertion1, int bAssertion2, int bAssertion3, int bAssertion4, int bAssertion5, int bAssertion6) {
  int bAssertion = bAssertion1 && bAssertion2 && bAssertion3 && bAssertion4 && bAssertion5 && bAssertion6;
  if (!bAssertion) {
    AsserT0(sContexte, bAssertion1, 1);
    AsserT0(sContexte, bAssertion2, 2);
    AsserT0(sContexte, bAssertion3, 3);
    AsserT0(sContexte, bAssertion4, 4);
    AsserT0(sContexte, bAssertion5, 5);
    AsserT0(sContexte, bAssertion6, 6);
  }
  assert(bAssertion);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strcoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  nop
L10:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L10
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_strcoll(const char *str1, const char *str2) {
  int i;
  i = -1;
  while (str1[i++] && str1[i] == str2[i])
    ;
  return (str1[i] - str2[i]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strcoll>:
  endbr64
  mov    $0x0,%eax
L14:
  mov    %eax,%ecx
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  je     L12
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  je     L14
L12:
  movslq %ecx,%rcx
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int my_strcoll(const char *str1, const char *str2) {
  int i;
  i = -1;
  while (str1[i++] && str1[i] == str2[i])
    ;
  return (str1[i] - str2[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_strcoll>:
  endbr64
  movzbl -0x1(%rdi),%eax
  xor    %edx,%edx
  jmp    L29
  nopl   0x0(%rax)
L3:
  add    $0x1,%rdx
  cmp    %cl,%al
  jne    L17
L29:
  mov    %eax,%r8d
  movsbl (%rsi,%rdx,1),%ecx
  movsbl (%rdi,%rdx,1),%eax
  test   %r8b,%r8b
  jne    L3
L17:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int my_strcoll(const char *str1, const char *str2) {
  int i;
  i = -1;
  while (str1[i++] && str1[i] == str2[i])
    ;
  return (str1[i] - str2[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strcoll>:
  endbr64
  movzbl -0x1(%rdi),%eax
  xor    %edx,%edx
  jmp    L28
  nopl   0x0(%rax)
L7:
  add    $0x1,%rdx
  cmp    %cl,%al
  jne    L8
L28:
  mov    %eax,%r8d
  movsbl (%rsi,%rdx,1),%ecx
  movsbl (%rdi,%rdx,1),%eax
  test   %r8b,%r8b
  jne    L7
L8:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int my_strcoll(const char *str1, const char *str2) {
  int i;
  i = -1;
  while (str1[i++] && str1[i] == str2[i])
    ;
  return (str1[i] - str2[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x30,%eax
  leave
  ret
```

assistant: ```c
int f2(int a, int b) {
  assert(a - b == 0);
  assert(a == b);
  return 48;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f2>:
  endbr64
  push   %rbx
  cmp    %esi,%edi
  sete   %bl
  movzbl %bl,%ebx
  mov    %ebx,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  call   <assert@plt>
  mov    $0x30,%eax
  pop    %rbx
  ret
```

assistant: ```c
int f2(int a, int b) {
  assert(a - b == 0);
  assert(a == b);
  return 48;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f2>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  cmp    %esi,%edi
  sete   %bpl
  mov    %ebp,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <assert@plt>
  mov    $0x30,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f2(int a, int b) {
  assert(a - b == 0);
  assert(a == b);
  return 48;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  cmp    %esi,%edi
  sete   %bpl
  mov    %ebp,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <assert@plt>
  mov    $0x30,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f2(int a, int b) {
  assert(a - b == 0);
  assert(a == b);
  return 48;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_base_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x200,%edx
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x200,%edx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <readlink@plt>
  mov    $0x2f,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
L8:
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
L19:
  lea    D48(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D35
datatype: string

tool: D35: /proc/self/exe

assistant: ```c
char const *get_base_path(char const *argv0) {
  static char base_path[512];
  char *e;
  strncpy(base_path, argv0, sizeof(base_path));
  e = strrchr(base_path, '/');
  if (!e) {
    readlink("/proc/self/exe", base_path, sizeof(base_path));
    e = strrchr(base_path, '/');
  }
  if (e) {
    ;
    e[1] = 0;
  } else {
    ;
  }
  return base_path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_base_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    $0x200,%edx
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
L23:
  movb   $0x0,0x1(%rax)
L4:
  lea    D17(%rip),%rax
  pop    %rbx
  ret
L19:
  mov    $0x200,%edx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <readlink@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  jmp    L23
```

tool_calls: name: unpack_data
arguments: data_label: D12
type: string

tool: D12: /proc/self/exe

assistant: ```c
char const *get_base_path(char const *argv0) {
  static char base_path[512];
  char *e;
  strncpy(base_path, argv0, sizeof(base_path));
  e = strrchr(base_path, '/');
  if (!e) {
    readlink("/proc/self/exe", base_path, sizeof(base_path));
    e = strrchr(base_path, '/');
  }
  if (e) {
    ;
    e[1] = 0;
  } else {
    ;
  }
  return base_path;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_base_path>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  mov    %rdi,%rsi
  mov    $0x200,%edx
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L11
L10:
  movb   $0x0,0x1(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  mov    $0x200,%edx
  call   <readlink@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string

tool: D12: /proc/self/exe

assistant: ```c
char const *get_base_path(char const *argv0) {
  static char base_path[512];
  char *e;
  strncpy(base_path, argv0, sizeof(base_path));
  e = strrchr(base_path, '/');
  if (!e) {
    readlink("/proc/self/exe", base_path, sizeof(base_path));
    e = strrchr(base_path, '/');
  }
  if (e) {
    ;
    e[1] = 0;
  } else {
    ;
  }
  return base_path;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_base_path>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  mov    %rdi,%rsi
  mov    $0x200,%edx
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
L15:
  movb   $0x0,0x1(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  mov    $0x200,%edx
  call   <readlink@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
datatype: string

tool: D10: /proc/self/exe

assistant: ```c
char const *get_base_path(char const *argv0) {
  static char base_path[512];
  char *e;
  strncpy(base_path, argv0, sizeof(base_path));
  e = strrchr(base_path, '/');
  if (!e) {
    readlink("/proc/self/exe", base_path, sizeof(base_path));
    e = strrchr(base_path, '/');
  }
  if (e) {
    ;
    e[1] = 0;
  } else {
    ;
  }
  return base_path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L51
L12:
  cmpq   $0x0,-0x28(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
L22:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L51:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  je     L19
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L12
  jmp    L19
L20:
  nop
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n-- && tolower((unsigned char)*s1) == tolower((unsigned char)*s2)) {
    if (!n && !*s1) {
      break;
    }
    s1++;
    s2++;
  }
  return (tolower((unsigned char)*s1) - tolower((unsigned char)*s2));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rdx,%rdx
  je     L20
  lea    -0x1(%rdx),%r13
  add    %rdi,%r13
  jmp    L26
L37:
  add    $0x1,%rbp
  add    $0x1,%r12
L26:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L20
  cmp    %rbp,%r13
  jne    L37
  cmpb   $0x0,0x0(%rbp)
  je     L20
  add    $0x1,%rbp
  add    $0x1,%r12
L20:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n-- && tolower((unsigned char)*s1) == tolower((unsigned char)*s2)) {
    if (!n && !*s1) {
      break;
    }
    s1++;
    s2++;
  }
  return (tolower((unsigned char)*s1) - tolower((unsigned char)*s2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %rdx,%rdx
  je     L39
  lea    -0x1(%rdx),%r13
  add    %rbp,%r13
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L43
  cmp    %rbp,%r13
  jne    L25
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L39
  movzbl 0x1(%r13),%edi
  add    $0x1,%r12
L39:
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L25:
  add    $0x1,%rbp
  add    $0x1,%r12
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L43:
  movzbl 0x0(%rbp),%edi
  jmp    L39
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n-- && tolower((unsigned char)*s1) == tolower((unsigned char)*s2)) {
    if (!n && !*s1) {
      break;
    }
    s1++;
    s2++;
  }
  return (tolower((unsigned char)*s1) - tolower((unsigned char)*s2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %rdx,%rdx
  je     L3
  lea    -0x1(%rdx),%r13
  add    %rbp,%r13
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L34
  cmp    %rbp,%r13
  jne    L7
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L3
  movzbl 0x1(%r13),%edi
  add    $0x1,%r12
L3:
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  add    $0x1,%rbp
  add    $0x1,%r12
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl 0x0(%rbp),%edi
  jmp    L3
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  while (n-- && tolower((unsigned char)*s1) == tolower((unsigned char)*s2)) {
    if (!n && !*s1) {
      break;
    }
    s1++;
    s2++;
  }
  return (tolower((unsigned char)*s1) - tolower((unsigned char)*s2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<normv3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <norm@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L15
  mov    $0x0,%eax
  jmp    L9
L15:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x1,%eax
L9:
  leave
  ret
```

assistant: ```c
extern int normv3(const double *a, double *b) {
  double r;
  if ((r = norm(a, 3)) <= 0.0) {
    return 0;
  }
  b[0] = a[0] / r;
  b[1] = a[1] / r;
  b[2] = a[2] / r;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<normv3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x3,%esi
  call   <norm@plt>
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jae    L5
  movsd  (%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern int normv3(const double *a, double *b) {
  double r;
  if ((r = norm(a, 3)) <= 0.0) {
    return 0;
  }
  b[0] = a[0] / r;
  b[1] = a[1] / r;
  b[2] = a[2] / r;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normv3>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <norm@plt>
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  jae    L7
  movsd  (%rbx),%xmm1
  mov    $0x1,%eax
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern int normv3(const double *a, double *b) {
  double r;
  if ((r = norm(a, 3)) <= 0.0) {
    return 0;
  }
  b[0] = a[0] / r;
  b[1] = a[1] / r;
  b[2] = a[2] / r;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<normv3>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <norm@plt>
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  jae    L2
  movsd  (%rbx),%xmm1
  mov    $0x1,%eax
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  movsd  0x8(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbp)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern int normv3(const double *a, double *b) {
  double r;
  if ((r = norm(a, 3)) <= 0.0) {
    return 0;
  }
  b[0] = a[0] / r;
  b[1] = a[1] / r;
  b[2] = a[2] / r;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getDims>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L53
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L12:
  cmpl   $0x0,-0x8(%rbp)
  jle    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,(%rcx)
  subl   $0x1,-0x8(%rbp)
  jmp    L59
L11:
  cmpl   $0x0,-0xc(%rbp)
  jle    L59
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  add    %edx,%edx
  mov    %edx,(%rax)
  subl   $0x1,-0xc(%rbp)
L59:
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
L53:
  cmpl   $0x0,-0xc(%rbp)
  jg     L10
  cmpl   $0x0,-0x8(%rbp)
  jg     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getDims(int ndims, int *n, int *dims) {
  int n2 = n[0];
  int n3 = n[1];
  while (n2 > 0 || n3 > 0) {
    for (int i = 0; i < ndims; i++) {
      if (n3 > 0) {
        dims[i] = dims[i] * 3;
        n3--;
      } else if (n2 > 0) {
        dims[i] = dims[i] * 2;
        n2--;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getDims>:
  endbr64
  mov    (%rsi),%r9d
  mov    0x4(%rsi),%esi
  test   %r9d,%r9d
  jg     L97
  test   %esi,%esi
  jg     L97
  ret
L39:
  test   %r9d,%r9d
  jle    L35
  shll   (%rax)
  sub    $0x1,%r9d
L9:
  cmp    %ecx,%edi
  jle    L7
L66:
  add    $0x1,%ecx
  add    $0x4,%rax
L20:
  test   %esi,%esi
  jle    L39
  mov    (%rax),%r8d
  lea    (%r8,%r8,2),%r8d
  mov    %r8d,(%rax)
  sub    $0x1,%esi
  jmp    L9
L7:
  test   %r9d,%r9d
  jg     L97
  test   %esi,%esi
  jle    L59
L97:
  test   %edi,%edi
  jle    L7
  mov    %rdx,%rax
  mov    $0x1,%ecx
  jmp    L20
L35:
  cmp    %edi,%ecx
  jl     L66
L59:
  ret
```

assistant: ```c
void getDims(int ndims, int *n, int *dims) {
  int n2 = n[0];
  int n3 = n[1];
  while (n2 > 0 || n3 > 0) {
    for (int i = 0; i < ndims; i++) {
      if (n3 > 0) {
        dims[i] = dims[i] * 3;
        n3--;
      } else if (n2 > 0) {
        dims[i] = dims[i] * 2;
        n2--;
      }
    }
  }
}
```