ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <sieve@plt>
  jmp    L49
L26:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L83
  movl   $0x0,-0xc(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L72
L17:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L12
  movl   $0x1,-0xc(%rbp)
  jmp    L11
L12:
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L72:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x10(%rbp)
  jle    L17
L11:
  cmpl   $0x1,-0xc(%rbp)
  jne    L18
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L49
L18:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L49:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L26
  jmp    L104
L83:
  nop
L104:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string

tool: D12: %d:
%d+%d


tool: D15: %d:
NO WAY!


tool: D26: %d

assistant: ```c
int main() {
  int n, k;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    int flag = 0;
    for (k = 2; k <= n / 2; k++) {
      if (is_prime(k) == 1 && is_prime(n - k) == 1) {
        flag = 1;
        break;
      } else
        flag = 0;
    }
    if (flag == 1)
      printf("%d:\n%d+%d\n", n, k, n - k);
    else
      printf("%d:\nNO WAY!\n", n);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sieve@plt>
  lea    0x4(%rsp),%r12
  lea    D25(%rip),%rbp
  lea    D3(%rip),%r13
  lea    D11(%rip),%r14
  jmp    L54
L85:
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jl     L48
L47:
  mov    %ebx,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L85
  mov    0x4(%rsp),%edi
  sub    %ebx,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L85
  mov    0x4(%rsp),%esi
  mov    %esi,%ecx
  sub    %ebx,%ecx
  mov    %ebx,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L54
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L54:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L69
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L69
  cmp    $0x3,%eax
  jle    L48
  mov    $0x2,%ebx
  jmp    L47
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string

tool: D25: %d

tool: D3: %d:
NO WAY!


tool: D11: %d:
%d+%d


assistant: ```c
int main() {
  int n, k;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    int flag = 0;
    for (k = 2; k <= n / 2; k++) {
      if (is_prime(k) == 1 && is_prime(n - k) == 1) {
        flag = 1;
        break;
      } else
        flag = 0;
    }
    if (flag == 1)
      printf("%d:\n%d+%d\n", n, k, n - k);
    else
      printf("%d:\nNO WAY!\n", n);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <sieve@plt>
  nop
L92:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L53
L38:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L53
  cmp    $0x3,%esi
  jle    L44
  mov    $0x2,%r14d
  jmp    L26
  nopl   0x0(%rax)
L91:
  mov    0x4(%rsp),%esi
  add    $0x1,%r14d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %r14d,%eax
  jl     L44
L26:
  mov    %r14d,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L91
  mov    0x4(%rsp),%edi
  sub    %r14d,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L91
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r14d,%edx
  mov    %esi,%ecx
  sub    %r14d,%ecx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L38
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L44:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L92
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D18: %d:
%d+%d


tool: D9: %d:
NO WAY!


tool: D6: %d

assistant: ```c
int main() {
  int n, k;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    int flag = 0;
    for (k = 2; k <= n / 2; k++) {
      if (is_prime(k) == 1 && is_prime(n - k) == 1) {
        flag = 1;
        break;
      } else
        flag = 0;
    }
    if (flag == 1)
      printf("%d:\n%d+%d\n", n, k, n - k);
    else
      printf("%d:\nNO WAY!\n", n);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <sieve@plt>
  nop
L49:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L43
L77:
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L43
  cmp    $0x3,%esi
  jle    L82
  mov    $0x2,%r14d
  jmp    L99
  nopl   0x0(%rax)
L70:
  mov    0x4(%rsp),%esi
  add    $0x1,%r14d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cmp    %r14d,%eax
  jl     L82
L99:
  mov    %r14d,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L70
  mov    0x4(%rsp),%edi
  sub    %r14d,%edi
  call   <is_prime@plt>
  cmp    $0x1,%eax
  jne    L70
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %r14d,%edx
  mov    %esi,%ecx
  sub    %r14d,%ecx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L77
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L82:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string

tool: D18: %d:
%d+%d


tool: D11: %d:
NO WAY!


tool: D24: %d

assistant: ```c
int main() {
  int n, k;
  sieve();
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    int flag = 0;
    for (k = 2; k <= n / 2; k++) {
      if (is_prime(k) == 1 && is_prime(n - k) == 1) {
        flag = 1;
        break;
      } else
        flag = 0;
    }
    if (flag == 1)
      printf("%d:\n%d+%d\n", n, k, n - k);
    else
      printf("%d:\nNO WAY!\n", n);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<klogHexWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <klogHexByte@plt>
  movzwl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <klogHexByte@plt>
  nop
  leave
  ret
```

assistant: ```c
void klogHexWord(unsigned short wd) {
  klogHexByte((unsigned char)((wd & 0xFF00) >> 8));
  klogHexByte((unsigned char)(wd & 0xFF));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<klogHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <klogHexByte@plt>
  movzbl %bl,%edi
  call   <klogHexByte@plt>
  pop    %rbx
  ret
```

assistant: ```c
void klogHexWord(unsigned short wd) {
  klogHexByte((unsigned char)((wd & 0xFF00) >> 8));
  klogHexByte((unsigned char)(wd & 0xFF));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<klogHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <klogHexByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <klogHexByte@plt>
```

assistant: ```c
void klogHexWord(unsigned short wd) {
  klogHexByte((unsigned char)((wd & 0xFF00) >> 8));
  klogHexByte((unsigned char)(wd & 0xFF));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<klogHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <klogHexByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <klogHexByte@plt>
```

assistant: ```c
void klogHexWord(unsigned short wd) {
  klogHexByte((unsigned char)((wd & 0xFF00) >> 8));
  klogHexByte((unsigned char)(wd & 0xFF));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xff,-0x88(%rbp)
  movb   $0xff,-0x89(%rbp)
  mov    -0x88(%rbp),%rax
  movsbl %al,%ecx
  lea    -0x80(%rbp),%rax
  mov    $0x78,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x0,-0x88(%rbp)
  jmp    L32
L14:
  mov    -0x88(%rbp),%rax
  mov    -0x80(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addq   $0x1,-0x88(%rbp)
L32:
  cmpq   $0xe,-0x88(%rbp)
  jle    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  movsbl -0x89(%rbp),%ecx
  lea    -0x80(%rbp),%rax
  mov    $0x78,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x0,-0x88(%rbp)
  jmp    L0
L23:
  mov    -0x88(%rbp),%rax
  mov    -0x80(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addq   $0x1,-0x88(%rbp)
L0:
  cmpq   $0xe,-0x88(%rbp)
  jle    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %e 

assistant: ```c
void main() {
  double la[15];
  long i = 255;
  char a = 0xff;
  memset(&la, i, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  memset(&la, a, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rbp
  lea    0x78(%rsp),%r12
  lea    D4(%rip),%r13
L0:
  movsd  (%rbx),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdi
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  lea    D4(%rip),%rbx
L17:
  movsd  0x0(%rbp),%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: %e 

assistant: ```c
void main() {
  double la[15];
  long i = 255;
  char a = 0xff;
  memset(&la, i, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  memset(&la, a, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x78(%rsp),%r12
  mov    %r14,%rdi
  mov    %r14,%rbx
  mov    %r14,%rbp
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  movsd  0x0(%rbp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  movsd  (%rbx),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: %e 

assistant: ```c
void main() {
  double la[15];
  long i = 255;
  char a = 0xff;
  memset(&la, i, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  memset(&la, a, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x78(%rsp),%r12
  mov    %r14,%rdi
  mov    %r14,%rbx
  mov    %r14,%rbp
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  0x0(%rbp),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x78,%edx
  mov    $0xffffffff,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  movsd  (%rbx),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: %e 

assistant: ```c
void main() {
  double la[15];
  long i = 255;
  char a = 0xff;
  memset(&la, i, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  memset(&la, a, sizeof(la));
  for (i = 0; i < 15; i++)
    printf("%e ", la[i]);
  printf("\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mammoth_leaf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x40000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0x20,%rsp
  mov    %edi,-0x40014(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40014(%rbp),%eax
  cltq
  movl   $0x4,-0x40010(%rbp,%rax,4)
  mov    -0x40014(%rbp),%eax
  cltq
  mov    -0x40010(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int mammoth_leaf(int arg) {
  int array[65536];
  array[arg] = 4;
  return array[arg];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mammoth_leaf>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mammoth_leaf(int arg) {
  int array[65536];
  array[arg] = 4;
  return array[arg];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mammoth_leaf>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mammoth_leaf(int arg) {
  int array[65536];
  array[arg] = 4;
  return array[arg];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mammoth_leaf>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int mammoth_leaf(int arg) {
  int array[65536];
  array[arg] = 4;
  return array[arg];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ref_asma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rsi
  mov    -0x28(%rbp),%rcx
  add    %rsi,%rcx
  cmp    %al,%dl
  cmovae %edx,%eax
  mov    %al,(%rcx)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0xf,-0x4(%rbp)
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ref_asma(unsigned char *s, unsigned char *t, unsigned char *u) {
  int i;
  for (i = 0; i < 16; i++)
    u[i] = (s[i] > t[i]) ? s[i] : t[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ref_asma>:
  endbr64
  mov    $0x0,%eax
L7:
  movzbl (%rsi,%rax,1),%ecx
  movzbl (%rdi,%rax,1),%r8d
  cmp    %r8b,%cl
  cmovb  %r8d,%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L7
  ret
```

assistant: ```c
void ref_asma(unsigned char *s, unsigned char *t, unsigned char *u) {
  int i;
  for (i = 0; i < 16; i++)
    u[i] = (s[i] > t[i]) ? s[i] : t[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ref_asma>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%rsi,%rax,1),%ecx
  movzbl (%rdi,%rax,1),%r8d
  cmp    %r8b,%cl
  cmovb  %r8d,%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L9
  ret
```

assistant: ```c
void ref_asma(unsigned char *s, unsigned char *t, unsigned char *u) {
  int i;
  for (i = 0; i < 16; i++)
    u[i] = (s[i] > t[i]) ? s[i] : t[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ref_asma>:
  endbr64
  lea    0x1(%rsi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L18
  lea    0x1(%rdi),%rcx
  mov    %rax,%rdx
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L18
  movdqu (%rsi),%xmm0
  movdqu (%rdi),%xmm1
  pmaxub %xmm1,%xmm0
  movups %xmm0,(%rax)
  ret
  nopl   0x0(%rax)
L18:
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,(%rax)
  movzbl 0x1(%rdi),%ecx
  movzbl 0x1(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x1(%rax)
  movzbl 0x2(%rdi),%ecx
  movzbl 0x2(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x2(%rax)
  movzbl 0x3(%rdi),%ecx
  movzbl 0x3(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x3(%rax)
  movzbl 0x4(%rdi),%ecx
  movzbl 0x4(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x4(%rax)
  movzbl 0x5(%rdi),%ecx
  movzbl 0x5(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x5(%rax)
  movzbl 0x6(%rdi),%ecx
  movzbl 0x6(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x6(%rax)
  movzbl 0x7(%rdi),%ecx
  movzbl 0x7(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x7(%rax)
  movzbl 0x8(%rdi),%ecx
  movzbl 0x8(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x8(%rax)
  movzbl 0x9(%rdi),%ecx
  movzbl 0x9(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0x9(%rax)
  movzbl 0xa(%rdi),%ecx
  movzbl 0xa(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xa(%rax)
  movzbl 0xb(%rdi),%ecx
  movzbl 0xb(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xb(%rax)
  movzbl 0xc(%rdi),%ecx
  movzbl 0xc(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xc(%rax)
  movzbl 0xd(%rdi),%ecx
  movzbl 0xd(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xd(%rax)
  movzbl 0xe(%rdi),%ecx
  movzbl 0xe(%rsi),%edx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xe(%rax)
  movzbl 0xf(%rsi),%edx
  movzbl 0xf(%rdi),%ecx
  cmp    %cl,%dl
  cmovb  %ecx,%edx
  mov    %dl,0xf(%rax)
  ret
```

assistant: ```c
void ref_asma(unsigned char *s, unsigned char *t, unsigned char *u) {
  int i;
  for (i = 0; i < 16; i++)
    u[i] = (s[i] > t[i]) ? s[i] : t[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4746454443,%rax
  mov    $0x0,%edx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movb   $0x46,-0x71(%rbp)
  movsbl -0x71(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <any@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %d


assistant: ```c
int main() {
  char s1[100] = "CDEFG";
  char s2 = 'F';
  printf("%d\n", any(s1, s2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x4746454443,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rdi
  mov    $0x46,%esi
  call   <any@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  char s1[100] = "CDEFG";
  char s2 = 'F';
  printf("%d\n", any(s1, s2));
}
```