ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<determine_size>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <rand@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D22(%rip),%xmm3
  movsd  (%rsp),%xmm1
  movsd  D29(%rip),%xmm2
  addsd  %xmm3,%xmm0
  divsd  %xmm0,%xmm1
  comisd %xmm1,%xmm2
  jbe    L3
  movsd  D20(%rip),%xmm4
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
L13:
  cvttsd2si %xmm2,%ecx
  cltd
  pxor   %xmm2,%xmm2
  add    $0x18,%rsp
  idiv   %ecx
  cvtsi2sd %edx,%xmm2
  divsd  %xmm4,%xmm2
  movapd %xmm3,%xmm4
  divsd  %xmm1,%xmm2
  movapd %xmm3,%xmm1
  subsd  %xmm2,%xmm4
  divsd  %xmm4,%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movapd %xmm1,%xmm2
  movapd %xmm3,%xmm4
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D22
data_type: byte[8]
name: read_data
arguments: data_tag: D29
data_type: byte[8]
name: read_data
arguments: data_tag: D20
data_type: byte[8]

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x90,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x41]}

assistant: ```c
int determine_size(double median_size, double max_size) {
  int nr_random, granularity_reducer;
  double size, double_nr_random;
  nr_random = rand();
  median_size++;
  if (max_size / median_size < 1024)
    granularity_reducer = 1024 * 1024;
  else
    granularity_reducer = 1;
  nr_random = nr_random % ((int)(granularity_reducer * (((double)max_size) / ((double)median_size))));
  double_nr_random = ((double)nr_random) / (granularity_reducer);
  size = median_size * (1 / (1 - (double_nr_random) / (((double)max_size) / ((double)median_size))) - 1);
  return ((int)size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<determine_size>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <rand@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  D24(%rip),%xmm3
  movsd  (%rsp),%xmm1
  movsd  D2(%rip),%xmm2
  addsd  %xmm3,%xmm0
  divsd  %xmm0,%xmm1
  comisd %xmm1,%xmm2
  jbe    L15
  movsd  D16(%rip),%xmm4
  movapd %xmm1,%xmm2
  mulsd  %xmm4,%xmm2
L18:
  cvttsd2si %xmm2,%ecx
  cltd
  pxor   %xmm2,%xmm2
  add    $0x18,%rsp
  idiv   %ecx
  cvtsi2sd %edx,%xmm2
  divsd  %xmm4,%xmm2
  movapd %xmm3,%xmm4
  divsd  %xmm1,%xmm2
  movapd %xmm3,%xmm1
  subsd  %xmm2,%xmm4
  divsd  %xmm4,%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movapd %xmm1,%xmm2
  movapd %xmm3,%xmm4
  jmp    L18
```

tool_calls: name: read_data
arguments: label: D24
type_guessed: byte[8]
name: read_data
arguments: label: D2
type_guessed: byte[8]
name: read_data
arguments: label: D16
type_guessed: byte[8]

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x90,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x41]}

assistant: ```c
int determine_size(double median_size, double max_size) {
  int nr_random, granularity_reducer;
  double size, double_nr_random;
  nr_random = rand();
  median_size++;
  if (max_size / median_size < 1024)
    granularity_reducer = 1024 * 1024;
  else
    granularity_reducer = 1;
  nr_random = nr_random % ((int)(granularity_reducer * (((double)max_size) / ((double)median_size))));
  double_nr_random = ((double)nr_random) / (granularity_reducer);
  size = median_size * (1 / (1 - (double_nr_random) / (((double)max_size) / ((double)median_size))) - 1);
  return ((int)size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<psk_key_exchange_mode_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  cmpl   $0x1,-0x4(%rbp)
  je     L14
  lea    D10(%rip),%rax
  jmp    L1
L13:
  lea    D16(%rip),%rax
  jmp    L1
L14:
  lea    D23(%rip),%rax
L1:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D23
data_type: string

tool: D10: UNKNOWN_PSK_EXCHANGE_MODE

tool: D16: PSK_KE

tool: D23: PSK_DHE_KE

assistant: ```c
const char *psk_key_exchange_mode_name(unsigned code) {
  switch (code) {
  default:
    return "UNKNOWN_PSK_EXCHANGE_MODE";
    break;
  case 0x0000:
    return "PSK_KE";
    break;
  case 0x0001:
    return "PSK_DHE_KE";
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psk_key_exchange_mode_name>:
  endbr64
  lea    D17(%rip),%rax
  test   %edi,%edi
  je     L2
  cmp    $0x1,%edi
  lea    D2(%rip),%rax
  lea    D10(%rip),%rdx
  cmove  %rdx,%rax
L2:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D17: PSK_KE

tool: D2: UNKNOWN_PSK_EXCHANGE_MODE

tool: D10: PSK_DHE_KE

assistant: ```c
const char *psk_key_exchange_mode_name(unsigned code) {
  switch (code) {
  default:
    return "UNKNOWN_PSK_EXCHANGE_MODE";
    break;
  case 0x0000:
    return "PSK_KE";
    break;
  case 0x0001:
    return "PSK_DHE_KE";
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<psk_key_exchange_mode_name>:
  endbr64
  lea    D24(%rip),%rax
  test   %edi,%edi
  je     L8
  cmp    $0x1,%edi
  lea    D9(%rip),%rax
  lea    D11(%rip),%rdx
  cmove  %rdx,%rax
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D11
type_infered: string

tool: D24: PSK_KE

tool: D9: UNKNOWN_PSK_EXCHANGE_MODE

tool: D11: PSK_DHE_KE

assistant: ```c
const char *psk_key_exchange_mode_name(unsigned code) {
  switch (code) {
  default:
    return "UNKNOWN_PSK_EXCHANGE_MODE";
    break;
  case 0x0000:
    return "PSK_KE";
    break;
  case 0x0001:
    return "PSK_DHE_KE";
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<psk_key_exchange_mode_name>:
  endbr64
  lea    D20(%rip),%rax
  test   %edi,%edi
  je     L5
  cmp    $0x1,%edi
  lea    D24(%rip),%rax
  lea    D1(%rip),%rdx
  cmove  %rdx,%rax
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string

tool: D20: PSK_KE

tool: D24: UNKNOWN_PSK_EXCHANGE_MODE

tool: D1: PSK_DHE_KE

assistant: ```c
const char *psk_key_exchange_mode_name(unsigned code) {
  switch (code) {
  default:
    return "UNKNOWN_PSK_EXCHANGE_MODE";
    break;
  case 0x0000:
    return "PSK_KE";
    break;
  case 0x0001:
    return "PSK_DHE_KE";
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<candp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x18(%rbp)
  jmp    L2
L7:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  subl   $0x1,-0x18(%rbp)
L2:
  cmpl   $0x1,-0x18(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
int candp(int a, int b, int c) {
  int r = 1;
  b = b + 1;
  while (b != 1) {
    r = r * a;
    r = r % c;
    b--;
  }
  printf("%d\n", r);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<candp>:
  endbr64
  push   %rbx
  lea    0x1(%rsi),%ecx
  test   %esi,%esi
  je     L15
  mov    %edx,%esi
  mov    $0x1,%ebx
L1:
  mov    %ebx,%eax
  imul   %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%ebx
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  jne    L1
L24:
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L15:
  mov    %ecx,%ebx
  jmp    L24
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: %d


assistant: ```c
int candp(int a, int b, int c) {
  int r = 1;
  b = b + 1;
  while (b != 1) {
    r = r * a;
    r = r % c;
    b--;
  }
  printf("%d\n", r);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<candp>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%r8d
  test   %esi,%esi
  je     L13
  mov    %edx,%esi
  lea    0x1(%r8),%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edx,%eax
  sub    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%ecx
  jne    L3
L19:
  mov    %edx,%esi
  lea    D7(%rip),%rdi
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%edx
  jmp    L19
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int candp(int a, int b, int c) {
  int r = 1;
  b = b + 1;
  while (b != 1) {
    r = r * a;
    r = r % c;
    b--;
  }
  printf("%d\n", r);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<candp>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%r8d
  test   %esi,%esi
  je     L2
  mov    %edx,%esi
  lea    0x1(%r8),%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %edx,%eax
  sub    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%ecx
  jne    L14
L10:
  mov    %edx,%esi
  lea    D0(%rip),%rdi
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%edx
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int candp(int a, int b, int c) {
  int r = 1;
  b = b + 1;
  while (b != 1) {
    r = r * a;
    r = r % c;
    b--;
  }
  printf("%d\n", r);
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<touch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L12:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1000,-0x8(%rbp)
  subl   $0x1000,-0x24(%rbp)
L10:
  cmpl   $0x0,-0x24(%rbp)
  jle    L25
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L12
L25:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void touch(char *p, char *end, int range) {
  char *tmp = p;
  while (range > 0 && (tmp < end)) {
    *tmp = 0;
    tmp += 4096;
    range -= 4096;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<touch>:
  endbr64
  test   %edx,%edx
  jle    L21
  cmp    %rsi,%rdi
  jae    L21
  mov    %rdi,%rax
  add    %edi,%edx
L25:
  movb   $0x0,(%rax)
  add    $0x1000,%rax
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L21
  cmp    %rax,%rsi
  ja     L25
L21:
  ret
```

assistant: ```c
void touch(char *p, char *end, int range) {
  char *tmp = p;
  while (range > 0 && (tmp < end)) {
    *tmp = 0;
    tmp += 4096;
    range -= 4096;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<touch>:
  endbr64
  test   %edx,%edx
  jle    L9
  cmp    %rsi,%rdi
  jae    L9
  add    %edi,%edx
  nop
L33:
  movb   $0x0,(%rdi)
  mov    %edx,%eax
  add    $0x1000,%rdi
  sub    %edi,%eax
  test   %eax,%eax
  jle    L9
  cmp    %rdi,%rsi
  ja     L33
L9:
  ret
```

assistant: ```c
void touch(char *p, char *end, int range) {
  char *tmp = p;
  while (range > 0 && (tmp < end)) {
    *tmp = 0;
    tmp += 4096;
    range -= 4096;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<touch>:
  endbr64
  test   %edx,%edx
  jle    L28
  cmp    %rsi,%rdi
  jae    L28
  add    %edi,%edx
  nop
L14:
  movb   $0x0,(%rdi)
  mov    %edx,%eax
  add    $0x1000,%rdi
  sub    %edi,%eax
  test   %eax,%eax
  jle    L28
  cmp    %rdi,%rsi
  ja     L14
L28:
  ret
```

assistant: ```c
void touch(char *p, char *end, int range) {
  char *tmp = p;
  while (range > 0 && (tmp < end)) {
    *tmp = 0;
    tmp += 4096;
    range -= 4096;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<filename_non_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  jmp    L0
L7:
  sub    $0x1,%rbx
L0:
  cmp    -0x18(%rbp),%rbx
  jbe    L3
  lea    -0x1(%rbx),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L7
L3:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if ((0))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return filename;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<filename_non_directory>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jae    L29
L16:
  cmpb   $0x2f,-0x1(%rax)
  je     L29
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L16
  mov    %rbx,%rax
L29:
  pop    %rbx
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if ((0))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return filename;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<filename_non_directory>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L1
  jmp    L18
  nopl   0x0(%rax)
L32:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L18
L1:
  cmpb   $0x2f,-0x1(%rax)
  jne    L32
L18:
  pop    %rbx
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if ((0))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return filename;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filename_non_directory>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L29
  jmp    L20
  nopl   0x0(%rax)
L19:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L20
L29:
  cmpb   $0x2f,-0x1(%rax)
  jne    L19
L20:
  pop    %rbx
  ret
```

assistant: ```c
char *filename_non_directory(char *pathname) {
  register char *filename = pathname + strlen(pathname);
  if ((0))
    pathname += 2;
  while (filename > pathname && !((filename[-1]) == '/'))
    filename--;
  return filename;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bilinear_interpolate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%r12
  movsd  %xmm1,0x8(%rsp)
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %rdx,%r13
  call   <floor@plt>
  mov    %rax,%rbx
  movsd  0x8(%rsp),%xmm0
  call   <floor@plt>
  mov    %rax,%rbp
  cmp    %ebx,%r14d
  je     L37
  test   %ebx,%ebx
  je     L37
  cmp    %eax,%r15d
  je     L37
  test   %eax,%eax
  je     L37
  pxor   %xmm5,%xmm5
  cvtsi2sd %ebx,%xmm5
  movsd  D12(%rip),%xmm0
  movapd %xmm5,%xmm2
  addsd  %xmm0,%xmm2
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  movapd %xmm0,%xmm3
  addsd  %xmm4,%xmm3
  movslq %eax,%rbp
  mov    0x0(%r13,%rbp,8),%rdx
  movslq %ebx,%rbx
  mov    0x8(%r13,%rbp,8),%rax
  movapd %xmm2,%xmm0
  subsd  %xmm5,%xmm0
  movq   %r12,%xmm6
  subsd  %xmm6,%xmm2
  divsd  %xmm0,%xmm2
  movq   %r12,%xmm1
  subsd  %xmm5,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm3,%xmm5
  subsd  %xmm4,%xmm5
  movapd %xmm2,%xmm0
  mulsd  (%rdx,%rbx,8),%xmm0
  movapd %xmm1,%xmm6
  mulsd  0x8(%rdx,%rbx,8),%xmm6
  addsd  %xmm6,%xmm0
  movsd  0x8(%rsp),%xmm7
  subsd  %xmm7,%xmm3
  divsd  %xmm5,%xmm3
  mulsd  %xmm3,%xmm0
  mulsd  (%rax,%rbx,8),%xmm2
  mulsd  0x8(%rax,%rbx,8),%xmm1
  addsd  %xmm1,%xmm2
  subsd  %xmm4,%xmm7
  movapd %xmm7,%xmm1
  divsd  %xmm5,%xmm1
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  jmp    L5
L37:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  movslq %ebp,%rbp
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbp,8),%rax
  movsd  (%rax,%rbx,8),%xmm0
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_guessed: byte[8]
name: read_data
arguments: data_label: D2
type_guessed: string

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D2: Interpolation boundary issues.


assistant: ```c
double bilinear_interpolate(double x, double y, int naxis1, int naxis2, double **image) {
  double f_R[2];
  double f_Q[2][2];
  double x1, x2, y1, y2;
  int xi, yi;
  double new_value;
  xi = (int)floor(x);
  yi = (int)floor(y);
  x1 = (double)xi;
  x2 = x1 + 1;
  y1 = (double)yi;
  y2 = y1 + 1;
  if ((xi == naxis1) || (xi == 0) || (yi == naxis2) || (yi == 0)) {
    printf("Interpolation boundary issues.\n");
    new_value = image[yi][xi];
  } else {
    f_Q[0][0] = image[yi][xi];
    f_Q[1][0] = image[yi][xi + 1];
    f_Q[0][1] = image[yi + 1][xi];
    f_Q[1][1] = image[yi + 1][xi + 1];
    f_R[0] = ((x2 - x) / (x2 - x1)) * f_Q[0][0] + ((x - x1) / (x2 - x1)) * f_Q[1][0];
    f_R[1] = ((x2 - x) / (x2 - x1)) * f_Q[0][1] + ((x - x1) / (x2 - x1)) * f_Q[1][1];
    new_value = ((y2 - y) / (y2 - y1)) * f_R[0] + ((y - y1) / (y2 - y1)) * f_R[1];
  }
  return new_value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bilinear_interpolate>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  movsd  (%rsp),%xmm0
  mov    %rax,%rbx
  call   <floor@plt>
  mov    %rax,%rbp
  cmp    %ebx,%r13d
  je     L12
  test   %ebx,%ebx
  je     L12
  cmp    %eax,%r14d
  je     L12
  test   %eax,%eax
  movsd  0x8(%rsp),%xmm2
  je     L12
  pxor   %xmm5,%xmm5
  pxor   %xmm4,%xmm4
  movslq %eax,%rbp
  movsd  (%rsp),%xmm7
  cvtsi2sd %ebx,%xmm5
  movsd  D7(%rip),%xmm0
  mov    (%r12,%rbp,8),%rdx
  movslq %ebx,%rbx
  cvtsi2sd %eax,%xmm4
  mov    0x8(%r12,%rbp,8),%rax
  movapd %xmm0,%xmm3
  movsd  0x8(%rdx,%rbx,8),%xmm6
  movapd %xmm5,%xmm1
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm3
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm1
  subsd  %xmm5,%xmm2
  subsd  %xmm5,%xmm0
  movapd %xmm3,%xmm5
  subsd  %xmm7,%xmm3
  subsd  %xmm4,%xmm7
  subsd  %xmm4,%xmm5
  divsd  %xmm0,%xmm1
  divsd  %xmm0,%xmm2
  movsd  (%rdx,%rbx,8),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  (%rax,%rbx,8),%xmm1
  divsd  %xmm5,%xmm3
  mulsd  %xmm2,%xmm6
  mulsd  0x8(%rax,%rbx,8),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  addsd  %xmm6,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm7,%xmm2
  divsd  %xmm5,%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
L12:
  movslq %ebp,%rbp
  lea    D10(%rip),%rdi
  movslq %ebx,%rbx
  call   <printf@plt>
  mov    (%r12,%rbp,8),%rax
  movsd  (%rax,%rbx,8),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D10: Interpolation boundary issues.


assistant: ```c
double bilinear_interpolate(double x, double y, int naxis1, int naxis2, double **image) {
  double f_R[2];
  double f_Q[2][2];
  double x1, x2, y1, y2;
  int xi, yi;
  double new_value;
  xi = (int)floor(x);
  yi = (int)floor(y);
  x1 = (double)xi;
  x2 = x1 + 1;
  y1 = (double)yi;
  y2 = y1 + 1;
  if ((xi == naxis1) || (xi == 0) || (yi == naxis2) || (yi == 0)) {
    printf("Interpolation boundary issues.\n");
    new_value = image[yi][xi];
  } else {
    f_Q[0][0] = image[yi][xi];
    f_Q[1][0] = image[yi][xi + 1];
    f_Q[0][1] = image[yi + 1][xi];
    f_Q[1][1] = image[yi + 1][xi + 1];
    f_R[0] = ((x2 - x) / (x2 - x1)) * f_Q[0][0] + ((x - x1) / (x2 - x1)) * f_Q[1][0];
    f_R[1] = ((x2 - x) / (x2 - x1)) * f_Q[0][1] + ((x - x1) / (x2 - x1)) * f_Q[1][1];
    new_value = ((y2 - y) / (y2 - y1)) * f_R[0] + ((y - y1) / (y2 - y1)) * f_R[1];
  }
  return new_value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bilinear_interpolate>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm1,(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  movsd  (%rsp),%xmm0
  mov    %rax,%rbx
  call   <floor@plt>
  mov    %rax,%rbp
  cmp    %ebx,%r13d
  je     L36
  test   %ebx,%ebx
  je     L36
  cmp    %eax,%r14d
  je     L36
  test   %eax,%eax
  movsd  0x8(%rsp),%xmm2
  je     L36
  pxor   %xmm5,%xmm5
  pxor   %xmm4,%xmm4
  movslq %eax,%rbp
  movsd  (%rsp),%xmm7
  cvtsi2sd %ebx,%xmm5
  movsd  D1(%rip),%xmm0
  mov    (%r12,%rbp,8),%rdx
  movslq %ebx,%rbx
  cvtsi2sd %eax,%xmm4
  mov    0x8(%r12,%rbp,8),%rax
  movapd %xmm0,%xmm3
  movsd  0x8(%rdx,%rbx,8),%xmm6
  movapd %xmm5,%xmm1
  addsd  %xmm0,%xmm1
  addsd  %xmm4,%xmm3
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm1
  subsd  %xmm5,%xmm2
  subsd  %xmm5,%xmm0
  movapd %xmm3,%xmm5
  subsd  %xmm7,%xmm3
  subsd  %xmm4,%xmm7
  subsd  %xmm4,%xmm5
  divsd  %xmm0,%xmm1
  divsd  %xmm0,%xmm2
  movsd  (%rdx,%rbx,8),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  (%rax,%rbx,8),%xmm1
  divsd  %xmm5,%xmm3
  mulsd  %xmm2,%xmm6
  mulsd  0x8(%rax,%rbx,8),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  addsd  %xmm6,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm7,%xmm2
  divsd  %xmm5,%xmm2
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
L36:
  movslq %ebp,%rbp
  lea    D19(%rip),%rdi
  movslq %ebx,%rbx
  call   <printf@plt>
  mov    (%r12,%rbp,8),%rax
  movsd  (%rax,%rbx,8),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: byte[8]
name: disassemble_data
arguments: tag: D19
datatype: string

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D19: Interpolation boundary issues.


assistant: ```c
double bilinear_interpolate(double x, double y, int naxis1, int naxis2, double **image) {
  double f_R[2];
  double f_Q[2][2];
  double x1, x2, y1, y2;
  int xi, yi;
  double new_value;
  xi = (int)floor(x);
  yi = (int)floor(y);
  x1 = (double)xi;
  x2 = x1 + 1;
  y1 = (double)yi;
  y2 = y1 + 1;
  if ((xi == naxis1) || (xi == 0) || (yi == naxis2) || (yi == 0)) {
    printf("Interpolation boundary issues.\n");
    new_value = image[yi][xi];
  } else {
    f_Q[0][0] = image[yi][xi];
    f_Q[1][0] = image[yi][xi + 1];
    f_Q[0][1] = image[yi + 1][xi];
    f_Q[1][1] = image[yi + 1][xi + 1];
    f_R[0] = ((x2 - x) / (x2 - x1)) * f_Q[0][0] + ((x - x1) / (x2 - x1)) * f_Q[1][0];
    f_R[1] = ((x2 - x) / (x2 - x1)) * f_Q[0][1] + ((x - x1) / (x2 - x1)) * f_Q[1][1];
    new_value = ((y2 - y) / (y2 - y1)) * f_R[0] + ((y - y1) / (y2 - y1)) * f_R[1];
  }
  return new_value;
}
```