ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<nmx_alloc>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *nmx_alloc(size_t size) {
  void *p;
  p = malloc(size);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nmx_alloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *nmx_alloc(size_t size) {
  void *p;
  p = malloc(size);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nmx_alloc>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *nmx_alloc(size_t size) {
  void *p;
  p = malloc(size);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L48
  mov    $0xffffffff,%eax
  jmp    L54
L48:
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L63
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L54
L16:
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L63
  mov    $0xffffffff,%eax
  jmp    L54
L63:
  mov    $0x0,%eax
L54:
  leave
  ret
```

assistant: ```c
int parse_range(const char *str, int *a, int *b, char **endptr) {
  if (!isdigit(*str))
    return -1;
  *a = *b = strtol(str, endptr, 10);
  if (**endptr == '-') {
    str = *endptr + 1;
    if (!isdigit(*str))
      return -1;
    *b = strtol(str, endptr, 10);
    if (*a > *b)
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_range>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%rbx
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L14
  mov    $0xa,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  mov    %eax,(%r12)
  mov    (%rbx),%rdx
  mov    $0x0,%eax
  cmpb   $0x2d,(%rdx)
  je     L39
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  lea    0x1(%rdx),%rbp
  movsbl 0x1(%rdx),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L56
  mov    $0xa,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  cmp    (%r12),%eax
  setl   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L42
L14:
  mov    $0xffffffff,%eax
  jmp    L42
L56:
  mov    $0xffffffff,%eax
  jmp    L42
```

assistant: ```c
int parse_range(const char *str, int *a, int *b, char **endptr) {
  if (!isdigit(*str))
    return -1;
  *a = *b = strtol(str, endptr, 10);
  if (**endptr == '-') {
    str = *endptr + 1;
    if (!isdigit(*str))
      return -1;
    *b = strtol(str, endptr, 10);
    if (*a > *b)
      return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_range>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L14
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    0x0(%rbp),%rdx
  mov    %eax,0x0(%r13)
  mov    %eax,(%rbx)
  xor    %eax,%eax
  cmpb   $0x2d,(%rdx)
  je     L1
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl 0x1(%rdx),%edi
  lea    0x1(%rdx),%r12
  call   <isdigit@plt>
  test   %eax,%eax
  je     L14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  cmp    (%rbx),%eax
  setl   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int parse_range(const char *str, int *a, int *b, char **endptr) {
  if (!isdigit(*str))
    return -1;
  *a = *b = strtol(str, endptr, 10);
  if (**endptr == '-') {
    str = *endptr + 1;
    if (!isdigit(*str))
      return -1;
    *b = strtol(str, endptr, 10);
    if (*a > *b)
      return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_range>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L10
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    0x0(%rbp),%rdx
  mov    %eax,0x0(%r13)
  mov    %eax,(%rbx)
  xor    %eax,%eax
  cmpb   $0x2d,(%rdx)
  je     L32
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  movsbl 0x1(%rdx),%edi
  lea    0x1(%rdx),%r12
  call   <isdigit@plt>
  test   %eax,%eax
  je     L10
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    %eax,0x0(%r13)
  cmp    (%rbx),%eax
  setl   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int parse_range(const char *str, int *a, int *b, char **endptr) {
  if (!isdigit(*str))
    return -1;
  *a = *b = strtol(str, endptr, 10);
  if (**endptr == '-') {
    str = *endptr + 1;
    if (!isdigit(*str))
      return -1;
    *b = strtol(str, endptr, 10);
    if (*a > *b)
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <lrand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x4,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <lrand@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rsize() {
  int rv = 8 << (lrand() % 15);
  rv = lrand() & (rv - 1);
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rsize>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <lrand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <lrand@plt>
  movslq %ebx,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ebx,%edx
  sar    $0x3,%edx
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%esi
  shl    $0x4,%esi
  sub    %edx,%esi
  sub    %esi,%ebx
  mov    %ebx,%ecx
  mov    $0x8,%edx
  shl    %cl,%edx
  sub    $0x1,%edx
  and    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rsize() {
  int rv = 8 << (lrand() % 15);
  rv = lrand() & (rv - 1);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rsize>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <lrand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <lrand@plt>
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %ebx,%edx
  sar    $0x3,%edx
  sub    %ecx,%edx
  mov    %edx,%esi
  shl    $0x4,%esi
  sub    %edx,%esi
  mov    $0x8,%edx
  sub    %esi,%ebx
  mov    %ebx,%ecx
  pop    %rbx
  shl    %cl,%edx
  sub    $0x1,%edx
  and    %edx,%eax
  ret
```

assistant: ```c
int rsize() {
  int rv = 8 << (lrand() % 15);
  rv = lrand() & (rv - 1);
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rsize>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <lrand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <lrand@plt>
  movslq %ebx,%rdx
  mov    %ebx,%ecx
  imul   $0xffffffff88888889,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %ebx,%edx
  sar    $0x3,%edx
  sub    %ecx,%edx
  mov    %edx,%esi
  shl    $0x4,%esi
  sub    %edx,%esi
  mov    $0x8,%edx
  sub    %esi,%ebx
  mov    %ebx,%ecx
  pop    %rbx
  shl    %cl,%edx
  sub    $0x1,%edx
  and    %edx,%eax
  ret
```

assistant: ```c
int rsize() {
  int rv = 8 << (lrand() % 15);
  rv = lrand() & (rv - 1);
  return rv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syscon_quaddobl_Laurent_drop_variable_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L1:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L13:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L58
L21:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L58:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L21
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x341,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int syscon_quaddobl_Laurent_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(833, &nc, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<syscon_quaddobl_Laurent_drop_variable_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L44:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L44
L39:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L53
  orq    $0x0,-0x8(%rsp,%rax,1)
L53:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L2
  mov    %ecx,%ecx
  mov    $0x0,%eax
L12:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L2:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x341,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  leave
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_quaddobl_Laurent_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(833, &nc, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<syscon_quaddobl_Laurent_drop_variable_by_name>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L38
L36:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L36
L38:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L40
L50:
  mov    %rsp,%r9
  test   %edx,%edx
  jle    L27
  xor    %eax,%eax
L28:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L28
L27:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x341,%edi
  lea    -0x14(%rbp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L50
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_quaddobl_Laurent_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(833, &nc, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xc,%eax
  je     L33
  cmp    $0xc,%eax
  jg     L64
  cmp    $0xa,%eax
  je     L70
  cmp    $0xb,%eax
  je     L85
  jmp    L64
L70:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L85:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L33:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L64:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L11:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D57
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string

tool: D0: enter number: 

tool: D57: %d

tool: D8: Number: %d


tool: D6: you have entered ten

tool: D35: you have entered eleven

tool: D38: you have entered twelve

tool: D18: default value

assistant: ```c
int main(int atgc, char **argv) {
  int num = 0;
  printf("enter number: ");
  scanf("%d", &num);
  printf("Number: %d\n", num);
  switch (num) {
  case 10:
    printf("you have entered ten\n");
    break;
  case 11:
    printf("you have entered eleven\n");
    break;
  case 12:
    printf("you have entered twelve\n");
    break;
  default:
    printf("default value\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D62(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xb,%eax
  je     L55
  cmp    $0xc,%eax
  je     L32
  cmp    $0xa,%eax
  je     L20
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L20:
  lea    D16(%rip),%rdi
  call   <puts@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L55:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L32:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D54
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D62
type_guessed: string
name: disassemble_data
arguments: tag: D32
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D20
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string

tool: D54: enter number: 

tool: D28: %d

tool: D62: Number: %d


tool: D32: default value

tool: D16: you have entered ten

tool: D20: you have entered eleven

tool: D21: you have entered twelve

assistant: ```c
int main(int atgc, char **argv) {
  int num = 0;
  printf("enter number: ");
  scanf("%d", &num);
  printf("Number: %d\n", num);
  switch (num) {
  case 10:
    printf("you have entered ten\n");
    break;
  case 11:
    printf("you have entered eleven\n");
    break;
  case 12:
    printf("you have entered twelve\n");
    break;
  default:
    printf("default value\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xb,%eax
  je     L64
  cmp    $0xc,%eax
  je     L59
  cmp    $0xa,%eax
  je     L50
  lea    D52(%rip),%rdi
  call   <puts@plt>
L60:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L64:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L60
L50:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L60
L59:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L60
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D25
data_type: string
name: parse_data
arguments: tag: D30
data_type: string
name: parse_data
arguments: tag: D52
data_type: string
name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D5: enter number: 

tool: D25: %d

tool: D30: Number: %d


tool: D52: default value

tool: D33: you have entered eleven

tool: D26: you have entered ten

tool: D8: you have entered twelve

assistant: ```c
int main(int atgc, char **argv) {
  int num = 0;
  printf("enter number: ");
  scanf("%d", &num);
  printf("Number: %d\n", num);
  switch (num) {
  case 10:
    printf("you have entered ten\n");
    break;
  case 11:
    printf("you have entered eleven\n");
    break;
  case 12:
    printf("you have entered twelve\n");
    break;
  default:
    printf("default value\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D56(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0xb,%eax
  je     L22
  cmp    $0xc,%eax
  je     L32
  cmp    $0xa,%eax
  je     L11
  lea    D36(%rip),%rdi
  call   <puts@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D44(%rip),%rdi
  call   <puts@plt>
  jmp    L3
L11:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L3
L32:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L3
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D56
data_type: string
name: extract_symbolic_data
arguments: data_tag: D60
data_type: string
name: extract_symbolic_data
arguments: data_tag: D52
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D44
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string

tool: D56: enter number: 

tool: D60: %d

tool: D52: Number: %d


tool: D36: default value

tool: D44: you have entered eleven

tool: D19: you have entered ten

tool: D24: you have entered twelve

assistant: ```c
int main(int atgc, char **argv) {
  int num = 0;
  printf("enter number: ");
  scanf("%d", &num);
  printf("Number: %d\n", num);
  switch (num) {
  case 10:
    printf("you have entered ten\n");
    break;
  case 11:
    printf("you have entered eleven\n");
    break;
  case 12:
    printf("you have entered twelve\n");
    break;
  default:
    printf("default value\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<obterNivel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L26
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  jmp    L23
L26:
  cmpl   $0x13,-0x4(%rbp)
  jg     L0
  mov    -0x8(%rbp),%eax
  mov    $0x2,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  jmp    L23
L0:
  mov    $0x3,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int obterNivel(int velocidade, int nivelAtual) {
  if (velocidade < 10) {
    return ((1) > (nivelAtual) ? (1) : (nivelAtual));
  } else if (velocidade < 20) {
    return ((2) > (nivelAtual) ? (2) : (nivelAtual));
  } else {
    return 3;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<obterNivel>:
  endbr64
  cmp    $0x9,%edi
  jle    L1
  mov    $0x2,%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x14,%edi
  mov    $0x3,%eax
  cmovl  %esi,%eax
  ret
L1:
  test   %esi,%esi
  mov    $0x1,%eax
  cmovg  %esi,%eax
  ret
```

assistant: ```c
int obterNivel(int velocidade, int nivelAtual) {
  if (velocidade < 10) {
    return ((1) > (nivelAtual) ? (1) : (nivelAtual));
  } else if (velocidade < 20) {
    return ((2) > (nivelAtual) ? (2) : (nivelAtual));
  } else {
    return 3;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<obterNivel>:
  endbr64
  cmp    $0x9,%edi
  jle    L8
  mov    $0x2,%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    $0x14,%edi
  mov    $0x3,%eax
  cmovl  %esi,%eax
  ret
  nop
L8:
  test   %esi,%esi
  mov    $0x1,%eax
  cmovg  %esi,%eax
  ret
```

assistant: ```c
int obterNivel(int velocidade, int nivelAtual) {
  if (velocidade < 10) {
    return ((1) > (nivelAtual) ? (1) : (nivelAtual));
  } else if (velocidade < 20) {
    return ((2) > (nivelAtual) ? (2) : (nivelAtual));
  } else {
    return 3;
  }
}
```