ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<srgb_sample_to_linear_reference>:
  endbr64
  sub    $0x8,%rsp
  fldt   0x10(%rsp)
  fldt   0xece(%rip)        # 2000 <_fini+0xe80>
  fcomip %st(1),%st
  jb     L5
  fldt   0xed4(%rip)        # 2010 <_fini+0xe90>
  add    $0x8,%rsp
  fdivrp %st,%st(1)
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  fldt   0xed2(%rip)        # 2020 <_fini+0xea0>
  push   $0x4000
  movabs $0x999999999999999a,%rax
  push   %rax
  faddp  %st,%st(1)
  fldt   0xeca(%rip)        # 2030 <_fini+0xeb0>
  sub    $0x10,%rsp
  fdivrp %st,%st(1)
  fstpt  (%rsp)
  call   <powl@plt>
  add    $0x20,%rsp
  add    $0x8,%rsp
  ret
```

assistant: ```c
long double srgb_sample_to_linear_reference(long double in_f) {
  long double tmp;
  if (in_f <= 0.0404482362771082L) {
    return in_f / 12.92L;
  } else {
    tmp = ((in_f + 0.055L) / 1.055L);
    return powl(tmp, 2.4L);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<srgb_sample_to_linear_reference>:
  endbr64
  sub    $0x8,%rsp
  fldt   0x10(%rsp)
  fldt   0xece(%rip)        # 2000 <_fini+0xe80>
  fcomip %st(1),%st
  jb     L1
  fldt   0xed4(%rip)        # 2010 <_fini+0xe90>
  add    $0x8,%rsp
  fdivrp %st,%st(1)
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  fldt   0xed2(%rip)        # 2020 <_fini+0xea0>
  push   $0x4000
  movabs $0x999999999999999a,%rax
  push   %rax
  faddp  %st,%st(1)
  fldt   0xeca(%rip)        # 2030 <_fini+0xeb0>
  sub    $0x10,%rsp
  fdivrp %st,%st(1)
  fstpt  (%rsp)
  call   <powl@plt>
  add    $0x20,%rsp
  add    $0x8,%rsp
  ret
```

assistant: ```c
long double srgb_sample_to_linear_reference(long double in_f) {
  long double tmp;
  if (in_f <= 0.0404482362771082L) {
    return in_f / 12.92L;
  } else {
    tmp = ((in_f + 0.055L) / 1.055L);
    return powl(tmp, 2.4L);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<McASPDITChanStatRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0xf0,-0x1c(%rbp)
  jne    L1
  mov    -0x18(%rbp),%eax
  add    $0x40,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L1:
  cmpl   $0xf,-0x1c(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  add    $0x46,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int McASPDITChanStatRead(unsigned int baseAddr, unsigned int chStatBits, unsigned int channel) {
  unsigned int retVal = 0;
  if ((0x000000F0) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x100 + (chStatBits * 4)))));
  }
  if ((0x0000000F) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x118 + (chStatBits * 4)))));
  }
  return retVal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<McASPDITChanStatRead>:
  endbr64
  cmp    $0xf0,%edx
  je     L5
  mov    $0x0,%eax
  cmp    $0xf,%edx
  jne    L14
  lea    0x118(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
L14:
  ret
L5:
  lea    0x100(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  ret
```

assistant: ```c
unsigned int McASPDITChanStatRead(unsigned int baseAddr, unsigned int chStatBits, unsigned int channel) {
  unsigned int retVal = 0;
  if ((0x000000F0) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x100 + (chStatBits * 4)))));
  }
  if ((0x0000000F) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x118 + (chStatBits * 4)))));
  }
  return retVal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<McASPDITChanStatRead>:
  endbr64
  cmp    $0xf0,%edx
  je     L6
  xor    %eax,%eax
  cmp    $0xf,%edx
  jne    L1
  lea    0x118(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
L1:
  ret
  xchg   %ax,%ax
L6:
  lea    0x100(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  ret
```

assistant: ```c
unsigned int McASPDITChanStatRead(unsigned int baseAddr, unsigned int chStatBits, unsigned int channel) {
  unsigned int retVal = 0;
  if ((0x000000F0) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x100 + (chStatBits * 4)))));
  }
  if ((0x0000000F) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x118 + (chStatBits * 4)))));
  }
  return retVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<McASPDITChanStatRead>:
  endbr64
  cmp    $0xf0,%edx
  je     L15
  xor    %eax,%eax
  cmp    $0xf,%edx
  jne    L7
  lea    0x118(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
L7:
  ret
  xchg   %ax,%ax
L15:
  lea    0x100(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  ret
```

assistant: ```c
unsigned int McASPDITChanStatRead(unsigned int baseAddr, unsigned int chStatBits, unsigned int channel) {
  unsigned int retVal = 0;
  if ((0x000000F0) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x100 + (chStatBits * 4)))));
  }
  if ((0x0000000F) == channel) {
    retVal = (*((volatile unsigned int *)(baseAddr + (0x118 + (chStatBits * 4)))));
  }
  return retVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dtimer_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dtimer@plt>
  nop
  leave
  ret
```

assistant: ```c
void dtimer_(double *time, unsigned long *itime, int *icntrl) {
  dtimer(time, (struct timeval *)itime, *icntrl);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<dtimer_>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  call   <dtimer@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dtimer_(double *time, unsigned long *itime, int *icntrl) {
  dtimer(time, (struct timeval *)itime, *icntrl);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dtimer_>:
  endbr64
  mov    (%rdx),%edx
  jmp    1050 <dtimer@plt>
```

assistant: ```c
void dtimer_(double *time, unsigned long *itime, int *icntrl) {
  dtimer(time, (struct timeval *)itime, *icntrl);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dtimer_>:
  endbr64
  mov    (%rdx),%edx
  jmp    1050 <dtimer@plt>
```

assistant: ```c
void dtimer_(double *time, unsigned long *itime, int *icntrl) {
  dtimer(time, (struct timeval *)itime, *icntrl);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <left_rotate32@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  left_rotate32();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <left_rotate32@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  left_rotate32();
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <left_rotate32@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  left_rotate32();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <left_rotate32@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  left_rotate32();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitset_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitset_cb(void *arg, unsigned size, void *dummy, void *data) {
  unsigned *total = arg;
  *total += size;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bitset_cb>:
  endbr64
  add    %esi,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bitset_cb(void *arg, unsigned size, void *dummy, void *data) {
  unsigned *total = arg;
  *total += size;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitset_cb>:
  endbr64
  add    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int bitset_cb(void *arg, unsigned size, void *dummy, void *data) {
  unsigned *total = arg;
  *total += size;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitset_cb>:
  endbr64
  add    %esi,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int bitset_cb(void *arg, unsigned size, void *dummy, void *data) {
  unsigned *total = arg;
  *total += size;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_large_chunked_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  imul   $0x407,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x6,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  add    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L1
L2:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0x5,%edx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x5,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0x400,%edx
  mov    $0x43,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addq   $0x400,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x2,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L1:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0x6,%edx
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x6,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string

tool: D19: 400


tool: D14: 


tool: D15: 0



assistant: ```c
char *create_large_chunked_message(int body_size_in_kb, const char *headers) {
  int i;
  size_t wrote = 0;
  size_t headers_len = strlen(headers);
  size_t bufsize = headers_len + (5 + 1024 + 2) * body_size_in_kb + 6;
  char *buf = malloc(bufsize);
  memcpy(buf, headers, headers_len);
  wrote += headers_len;
  for (i = 0; i < body_size_in_kb; i++) {
    memcpy(buf + wrote, "400\r\n", 5);
    wrote += 5;
    memset(buf + wrote, 'C', 1024);
    wrote += 1024;
    strcpy(buf + wrote, "\r\n");
    wrote += 2;
  }
  memcpy(buf + wrote, "0\r\n\r\n", 6);
  wrote += 6;
  assert(wrote == bufsize);
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<create_large_chunked_message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rax,%r15
  imul   $0x407,%ebp,%eax
  cltq
  add    %r12,%rax
  mov    %rax,0x8(%rsp)
  lea    0x6(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L5
  lea    (%r14,%r12,1),%rbx
  mov    %ebp,%ebp
  imul   $0x407,%rbp,%rbp
  lea    (%r12,%rbp,1),%r15
  lea    (%r14,%r15,1),%r13
  lea    D1(%rip),%r12
  lea    D15(%rip),%rbp
L7:
  mov    $0x5,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x5(%rbx),%rdi
  mov    $0x400,%edx
  mov    $0x43,%esi
  call   <memset@plt>
  lea    0x405(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  add    $0x407,%rbx
  cmp    %r13,%rbx
  jne    L7
L5:
  lea    (%r14,%r15,1),%rdi
  mov    $0x6,%edx
  lea    D17(%rip),%rsi
  call   <memcpy@plt>
  cmp    %r15,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D1: 400


tool: D15: 


tool: D17: 0



assistant: ```c
char *create_large_chunked_message(int body_size_in_kb, const char *headers) {
  int i;
  size_t wrote = 0;
  size_t headers_len = strlen(headers);
  size_t bufsize = headers_len + (5 + 1024 + 2) * body_size_in_kb + 6;
  char *buf = malloc(bufsize);
  memcpy(buf, headers, headers_len);
  wrote += headers_len;
  for (i = 0; i < body_size_in_kb; i++) {
    memcpy(buf + wrote, "400\r\n", 5);
    wrote += 5;
    memset(buf + wrote, 'C', 1024);
    wrote += 1024;
    strcpy(buf + wrote, "\r\n");
    wrote += 2;
  }
  memcpy(buf + wrote, "0\r\n\r\n", 6);
  wrote += 6;
  assert(wrote == bufsize);
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<create_large_chunked_message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  imul   $0x407,%ebp,%r14d
  sub    $0x18,%rsp
  movslq %r14d,%r14
  call   <strlen@plt>
  mov    %rax,%rbx
  add    %r14,%rax
  lea    0x6(%rax),%rdi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L14
  imul   $0x407,%rbp,%rbp
  lea    (%r15,%rbx,1),%r14
  lea    D19(%rip),%r13
  lea    D13(%rip),%r12
  add    %rbp,%rbx
  lea    (%r15,%rbx,1),%rbp
  nopl   (%rax)
L29:
  mov    %r14,%rdi
  mov    $0x5,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  lea    0x5(%r14),%rdi
  mov    $0x400,%edx
  mov    $0x43,%esi
  call   <memset@plt>
  lea    0x405(%r14),%rdi
  mov    %r12,%rsi
  add    $0x407,%r14
  call   <strcpy@plt>
  cmp    %rbp,%r14
  jne    L29
L22:
  mov    %rbp,%rdi
  mov    $0x6,%edx
  lea    D14(%rip),%rsi
  call   <memcpy@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  lea    (%r15,%rbx,1),%rbp
  jmp    L22
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D19: 400


tool: D13: 


tool: D14: 0



assistant: ```c
char *create_large_chunked_message(int body_size_in_kb, const char *headers) {
  int i;
  size_t wrote = 0;
  size_t headers_len = strlen(headers);
  size_t bufsize = headers_len + (5 + 1024 + 2) * body_size_in_kb + 6;
  char *buf = malloc(bufsize);
  memcpy(buf, headers, headers_len);
  wrote += headers_len;
  for (i = 0; i < body_size_in_kb; i++) {
    memcpy(buf + wrote, "400\r\n", 5);
    wrote += 5;
    memset(buf + wrote, 'C', 1024);
    wrote += 1024;
    strcpy(buf + wrote, "\r\n");
    wrote += 2;
  }
  memcpy(buf + wrote, "0\r\n\r\n", 6);
  wrote += 6;
  assert(wrote == bufsize);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_large_chunked_message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  push   %rbx
  imul   $0x407,%ebp,%r14d
  sub    $0x18,%rsp
  movslq %r14d,%r14
  call   <strlen@plt>
  mov    %rax,%rbx
  add    %r14,%rax
  lea    0x6(%rax),%rdi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L27
  imul   $0x407,%rbp,%rbp
  lea    (%r15,%rbx,1),%r14
  lea    D5(%rip),%r13
  lea    D3(%rip),%r12
  add    %rbp,%rbx
  lea    (%r15,%rbx,1),%rbp
  nopl   (%rax)
L28:
  mov    %r14,%rdi
  mov    $0x5,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  lea    0x5(%r14),%rdi
  mov    $0x400,%edx
  mov    $0x43,%esi
  call   <memset@plt>
  lea    0x405(%r14),%rdi
  mov    %r12,%rsi
  add    $0x407,%r14
  call   <strcpy@plt>
  cmp    %rbp,%r14
  jne    L28
L7:
  mov    %rbp,%rdi
  mov    $0x6,%edx
  lea    D4(%rip),%rsi
  call   <memcpy@plt>
  xor    %edi,%edi
  cmp    %rbx,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L27:
  lea    (%r15,%rbx,1),%rbp
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D5: 400


tool: D3: 


tool: D4: 0



assistant: ```c
char *create_large_chunked_message(int body_size_in_kb, const char *headers) {
  int i;
  size_t wrote = 0;
  size_t headers_len = strlen(headers);
  size_t bufsize = headers_len + (5 + 1024 + 2) * body_size_in_kb + 6;
  char *buf = malloc(bufsize);
  memcpy(buf, headers, headers_len);
  wrote += headers_len;
  for (i = 0; i < body_size_in_kb; i++) {
    memcpy(buf + wrote, "400\r\n", 5);
    wrote += 5;
    memset(buf + wrote, 'C', 1024);
    wrote += 1024;
    strcpy(buf + wrote, "\r\n");
    wrote += 2;
  }
  memcpy(buf + wrote, "0\r\n\r\n", 6);
  wrote += 6;
  assert(wrote == bufsize);
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <doubles_mat44_identity@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x10(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x20,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = sin(rad), c = cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  lea    0x8(%rsp),%rdi
  mov    %rsp,%rsi
  call   <sincos@plt>
  mov    (%rsp),%rbp
  mov    0x8(%rsp),%r12
  mov    %rbx,%rdi
  call   <doubles_mat44_identity@plt>
  mov    %rbp,(%rbx)
  movq   %r12,%xmm0
  xorpd  D2(%rip),%xmm0
  movsd  %xmm0,0x8(%rbx)
  mov    %r12,0x20(%rbx)
  mov    %rbp,0x28(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = sin(rad), c = cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  movapd %xmm1,%xmm2
  xorpd  D8(%rip),%xmm2
  movsd  %xmm0,(%rbx)
  movsd  %xmm1,0x20(%rbx)
  movsd  %xmm2,0x8(%rbx)
  movsd  %xmm0,0x28(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = sin(rad), c = cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<doubles_mat44_rotate_z>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    %rbx,%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm3
  xorpd  D5(%rip),%xmm3
  movapd %xmm1,%xmm2
  unpcklpd %xmm1,%xmm0
  unpcklpd %xmm3,%xmm2
  movups %xmm0,0x20(%rbx)
  movups %xmm2,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_z(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = sin(rad), c = cos(rad);
  out[0 * 4 + 0] = c;
  out[0 * 4 + 1] = -s;
  out[1 * 4 + 0] = s;
  out[1 * 4 + 1] = c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<build_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L30
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L28
L30:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L28
L2:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *build_name(char *dirid, char *name) {
  char *full;
  if (!dirid)
    return strdup(name);
  full = malloc(strlen(dirid) + strlen(name) + 1);
  if (!full)
    return NULL;
  strcpy(full, dirid);
  strcat(full, name);
  return full;
}
```