ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetCmdOpt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x8(%rdx),%rax
  mov    %esi,0xc(%rsp)
  test   %rax,%rax
  je     L39
  mov    %esi,%r15d
  cmp    $0x1,%esi
  jbe    L6
  mov    %rdi,%r14
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r15d,%eax
  mov    $0x1,%r15d
  mov    %rax,(%rsp)
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx,%r15,8),%r13
  mov    %r15d,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbp
  jne    L34
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L48
L34:
  add    $0x1,%r15
  cmp    %r15,(%rsp)
  jne    L17
L6:
  xor    %eax,%eax
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  je     L6
  mov    (%rbx,%r12,8),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *GetCmdOpt(const char *switch_name, int arg_argc, char *arg_argv[]) {
  unsigned int i;
  if (arg_argv[1] == NULL) {
    return (NULL);
  }
  for (i = 1; i < arg_argc; i++) {
    if (strlen(switch_name) != strlen(arg_argv[i])) {
      continue;
    }
    if (!strcmp(switch_name, arg_argv[i])) {
      if (i + 1 == arg_argc) {
        return (NULL);
      }
      return (arg_argv[i + 1]);
    }
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <prepare_free_list@plt>
  mov    $0x0,%eax
  call   <prepare_execution_context@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init(void) {
  prepare_free_list();
  prepare_execution_context();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prepare_free_list@plt>
  mov    $0x0,%eax
  call   <prepare_execution_context@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init(void) {
  prepare_free_list();
  prepare_execution_context();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prepare_free_list@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <prepare_execution_context@plt>
```

assistant: ```c
void init(void) {
  prepare_free_list();
  prepare_execution_context();
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prepare_free_list@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <prepare_execution_context@plt>
```

assistant: ```c
void init(void) {
  prepare_free_list();
  prepare_execution_context();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <cosintegral@plt>
  movq   %xmm0,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x5,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_infered: f64
name: read_data
arguments: label: D28
type_infered: string

tool: D10: 0.5

tool: D28: 
cosintegral(%3.1f)=%5.2f

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\ncosintegral(%3.1f)=%5.2f", 0.5 * n, cosintegral(0.5 * n));
  }
  getch();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D6(%rip),%rbp
L0:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D17(%rip),%xmm0
  movq   %xmm0,%r14
  call   <cosintegral@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L0
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: f64

tool: D6: 
cosintegral(%3.1f)=%5.2f

tool: D17: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\ncosintegral(%3.1f)=%5.2f", 0.5 * n, cosintegral(0.5 * n));
  }
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L0:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  mulsd  D8(%rip),%xmm2
  add    $0x1,%ebx
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <cosintegral@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L0
  xor    %eax,%eax
  call   <getch@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: f64

tool: D0: 
cosintegral(%3.1f)=%5.2f

tool: D8: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\ncosintegral(%3.1f)=%5.2f", 0.5 * n, cosintegral(0.5 * n));
  }
  getch();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L3:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  mulsd  D2(%rip),%xmm2
  add    $0x1,%ebx
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <cosintegral@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %rbp,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L3
  xor    %eax,%eax
  call   <getch@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: f64

tool: D8: 
cosintegral(%3.1f)=%5.2f

tool: D2: 0.5

assistant: ```c
main() {
  int n;
  for (n = 1; n < 6; n++) {
    printf("\ncosintegral(%3.1f)=%5.2f", 0.5 * n, cosintegral(0.5 * n));
  }
  getch();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0xc(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L25
L64:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L75
  mov    $0x0,%eax
  call   <menu@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L25
L75:
  cmpl   $0x1,-0x8(%rbp)
  je     L74
  cmpl   $0x2,-0x8(%rbp)
  jne    L29
L74:
  cmpl   $0x1,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <play@plt>
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L25
L29:
  cmpl   $0x0,-0x8(%rbp)
  jne    L25
  movl   $0x0,-0xc(%rbp)
L25:
  cmpl   $0x0,-0xc(%rbp)
  jne    L64
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  int stay_here = 1;
  int menu_choice = -1;
  while (stay_here) {
    if (menu_choice == -1) {
      menu_choice = menu();
    } else if (menu_choice == 1 || menu_choice == 2) {
      int generate_mystery = (menu_choice == 1) ? 1 : 0;
      play(7, 0, 100, generate_mystery);
      menu_choice = -1;
    } else if (menu_choice == 0) {
      stay_here = 0;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0xffffffff,%eax
  mov    $0xffffffff,%ebx
  jmp    L39
L35:
  mov    $0x0,%eax
  call   <menu@plt>
  jmp    L39
L11:
  cmp    $0x1,%eax
  sete   %cl
  movzbl %cl,%ecx
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <play@plt>
  mov    %ebx,%eax
L39:
  cmp    $0xffffffff,%eax
  je     L35
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L11
  test   %eax,%eax
  jne    L39
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  int stay_here = 1;
  int menu_choice = -1;
  while (stay_here) {
    if (menu_choice == -1) {
      menu_choice = menu();
    } else if (menu_choice == 1 || menu_choice == 2) {
      int generate_mystery = (menu_choice == 1) ? 1 : 0;
      play(7, 0, 100, generate_mystery);
      menu_choice = -1;
    } else if (menu_choice == 0) {
      stay_here = 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0xffffffff,%eax
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    $0xffffffff,%eax
  je     L15
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L24
  test   %eax,%eax
  jne    L11
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %ecx,%ecx
  cmp    $0x1,%eax
  mov    $0x64,%edx
  mov    $0x7,%edi
  sete   %cl
  xor    %esi,%esi
  call   <play@plt>
L15:
  xor    %eax,%eax
  call   <menu@plt>
  jmp    L11
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  int stay_here = 1;
  int menu_choice = -1;
  while (stay_here) {
    if (menu_choice == -1) {
      menu_choice = menu();
    } else if (menu_choice == 1 || menu_choice == 2) {
      int generate_mystery = (menu_choice == 1) ? 1 : 0;
      play(7, 0, 100, generate_mystery);
      menu_choice = -1;
    } else if (menu_choice == 0) {
      stay_here = 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0xffffffff,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    $0xffffffff,%eax
  je     L5
  lea    -0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L6
  test   %eax,%eax
  jne    L12
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %ecx,%ecx
  cmp    $0x1,%eax
  mov    $0x64,%edx
  mov    $0x7,%edi
  sete   %cl
  xor    %esi,%esi
  call   <play@plt>
L5:
  xor    %eax,%eax
  call   <menu@plt>
  jmp    L12
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  int stay_here = 1;
  int menu_choice = -1;
  while (stay_here) {
    if (menu_choice == -1) {
      menu_choice = menu();
    } else if (menu_choice == 1 || menu_choice == 2) {
      int generate_mystery = (menu_choice == 1) ? 1 : 0;
      play(7, 0, 100, generate_mystery);
      menu_choice = -1;
    } else if (menu_choice == 0) {
      stay_here = 0;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<softboundmpx_nl_langinfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <nl_langinfo@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x100000(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_nl_langinfo(nl_item item) {
  char *ret_ptr = nl_langinfo(item);
  __softboundmpx_store_return_metadata(ret_ptr, ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<softboundmpx_nl_langinfo>:
  endbr64
  push   %rbx
  call   <nl_langinfo@plt>
  mov    %rax,%rbx
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_nl_langinfo(nl_item item) {
  char *ret_ptr = nl_langinfo(item);
  __softboundmpx_store_return_metadata(ret_ptr, ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<softboundmpx_nl_langinfo>:
  endbr64
  push   %r12
  call   <nl_langinfo@plt>
  mov    %rax,%r12
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_nl_langinfo(nl_item item) {
  char *ret_ptr = nl_langinfo(item);
  __softboundmpx_store_return_metadata(ret_ptr, ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<softboundmpx_nl_langinfo>:
  endbr64
  push   %r12
  call   <nl_langinfo@plt>
  mov    %rax,%r12
  lea    0x100000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) char *softboundmpx_nl_langinfo(nl_item item) {
  char *ret_ptr = nl_langinfo(item);
  __softboundmpx_store_return_metadata(ret_ptr, ret_ptr + 1024 * 1024);
  return ret_ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x1c(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L35
L15:
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%r8
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L26:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%r8
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  addl   $0x1,-0x1c(%rbp)
L35:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D12
type_infered: string

tool: D24: i	son/pa	ppid	pid	fpid

tool: D17: %d	child	%4d	%4d	%4d


tool: D12: %d	parent	%4d	%4d	%4d


assistant: ```c
int main(void) {
  int i = 0;
  printf("i\tson/pa\tppid\tpid\tfpid\n");
  for (i = 0; i < 2; i++) {
    pid_t fpid = fork();
    if (fpid == 0)
      printf("%d\tchild\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
    else
      printf("%d\tparent\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D12(%rip),%r14
  lea    D9(%rip),%r13
  jmp    L33
L2:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%edx
  mov    %rbp,%r8
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  add    $0x1,%ebx
  cmp    $0x2,%ebx
  je     L4
L33:
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L2
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%edx
  mov    $0x0,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L4:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string

tool: D21: i	son/pa	ppid	pid	fpid

tool: D12: %d	parent	%4d	%4d	%4d


tool: D9: %d	child	%4d	%4d	%4d


assistant: ```c
int main(void) {
  int i = 0;
  printf("i\tson/pa\tppid\tpid\tfpid\n");
  for (i = 0; i < 2; i++) {
    pid_t fpid = fork();
    if (fpid == 0)
      printf("%d\tchild\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
    else
      printf("%d\tparent\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <puts@plt>
L17:
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  jne    L18
  call   <getpid@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <getppid@plt>
  xor    %r8d,%r8d
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %eax,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jne    L7
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  call   <getpid@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %rbx,%r8
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %eax,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  je     L3
L7:
  mov    $0x1,%ebp
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D6: i	son/pa	ppid	pid	fpid

tool: D25: %d	parent	%4d	%4d	%4d


tool: D10: %d	child	%4d	%4d	%4d


assistant: ```c
int main(void) {
  int i = 0;
  printf("i\tson/pa\tppid\tpid\tfpid\n");
  for (i = 0; i < 2; i++) {
    pid_t fpid = fork();
    if (fpid == 0)
      printf("%d\tchild\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
    else
      printf("%d\tparent\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <puts@plt>
L32:
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  jne    L8
  call   <getpid@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <getppid@plt>
  xor    %r8d,%r8d
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %eax,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jne    L6
L29:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  call   <getpid@plt>
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %rbx,%r8
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %eax,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  je     L29
L6:
  mov    $0x1,%ebp
  jmp    L32
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D14
data_type: string

tool: D13: i	son/pa	ppid	pid	fpid

tool: D17: %d	parent	%4d	%4d	%4d


tool: D14: %d	child	%4d	%4d	%4d


assistant: ```c
int main(void) {
  int i = 0;
  printf("i\tson/pa\tppid\tpid\tfpid\n");
  for (i = 0; i < 2; i++) {
    pid_t fpid = fork();
    if (fpid == 0)
      printf("%d\tchild\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
    else
      printf("%d\tparent\t%4d\t%4d\t%4d\n", i, getppid(), getpid(), fpid);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L36
L20:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L44
  mov    $0x0,%eax
  jmp    L36
L44:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L20
  mov    $0x1,%eax
L36:
  leave
  ret
```

assistant: ```c
int isPrime(int n) {
  int i = 1, sqr = sqrt(n);
  if (n == 1)
    return 0;
  while (++i < sqr)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPrime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%esi
  mov    $0x0,%eax
  mov    $0x1,%ecx
  cmp    $0x1,%ebx
  je     L0
L36:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jle    L31
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L36
  jmp    L0
L31:
  mov    $0x1,%eax
L0:
  pop    %rbx
  ret
```

assistant: ```c
int isPrime(int n) {
  int i = 1, sqr = sqrt(n);
  if (n == 1)
    return 0;
  while (++i < sqr)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  xor    %edx,%edx
  cmp    $0x1,%r12d
  je     L13
  mov    %eax,%esi
  mov    $0x1,%ecx
  jmp    L28
  nop
L24:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L13
L28:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jg     L24
  mov    $0x1,%edx
L13:
  mov    %edx,%eax
  pop    %r12
  ret
```

assistant: ```c
int isPrime(int n) {
  int i = 1, sqr = sqrt(n);
  if (n == 1)
    return 0;
  while (++i < sqr)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  xor    %edx,%edx
  cmp    $0x1,%r12d
  je     L30
  mov    %eax,%esi
  mov    $0x1,%ecx
  jmp    L35
  nop
L25:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L30
L35:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jg     L25
  mov    $0x1,%edx
L30:
  mov    %edx,%eax
  pop    %r12
  ret
```

assistant: ```c
int isPrime(int n) {
  int i = 1, sqr = sqrt(n);
  if (n == 1)
    return 0;
  while (++i < sqr)
    if (n % i == 0)
      return 0;
  return 1;
}
```