user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<go_self>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x5c(%rbp)
  cmpl   $0x0,-0x5c(%rbp)
  js     L16
  movb   $0x2f,-0x40(%rbp)
  movb   $0x70,-0x3f(%rbp)
  movb   $0x72,-0x3e(%rbp)
  movb   $0x6f,-0x3d(%rbp)
  movb   $0x63,-0x3c(%rbp)
  movb   $0x2f,-0x3b(%rbp)
  movb   $0x0,-0x3a(%rbp)
  movb   $0x0,-0x39(%rbp)
  lea    -0x40(%rbp),%rbx
  add    $0x6,%rbx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <upx_itoa@plt>
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  movb   $0x2f,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0x1,%rax
  movb   $0x66,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0x2,%rax
  movb   $0x64,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0x3,%rax
  movb   $0x2f,(%rax)
  mov    -0x50(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x5c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <upx_itoa@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <access@plt>
  cmp    $0x32585055,%eax
  jne    L12
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    -0x5c(%rbp),%eax
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x78(%rbp),%rdx
  mov    -0x70(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execve@plt>
  mov    -0x5c(%rbp),%eax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0x58(%rbp)
  mov    -0x5c(%rbp),%edx
  mov    -0x58(%rbp),%eax
  mov    $0x0,%r9d
  mov    %edx,%r8d
  mov    $0x2,%ecx
  mov    $0x3,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x68(%rbp),%rax
  mov    $0x1c0,%edx
  mov    $0xc1,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x58(%rbp),%edx
  mov    -0x48(%rbp),%rcx
  mov    -0x54(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %eax,-0x58(%rbp)
  je     L29
  mov    $0x7f,%edi
  call   <exit@plt>
L29:
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L12:
  mov    -0x5c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L16:
  mov    -0x5c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __attribute__((__no__, __used__, __stdcall__)) go_self(char const *tmpname, char *argv[], char *envp[]) {
  int const fdi = open(tmpname, 00, 0);
  if (0 <= fdi) {
    char procself_buf[31 + 1];
    (procself_buf + 0)[0] = '/', (procself_buf + 0)[1] = 'p', (procself_buf + 0)[2] = 'r', (procself_buf + 0)[3] = 'o';
    (procself_buf + 4)[0] = 'c', (procself_buf + 4)[1] = '/', (procself_buf + 4)[2] = 0, (procself_buf + 4)[3] = 0;
    {
      char *const procself = upx_itoa(getpid(), procself_buf + 6);
      (procself)[0] = '/', (procself)[1] = 'f', (procself)[2] = 'd', (procself)[3] = '/';
      upx_itoa(fdi, procself + 4);
    }
    if (0x32585055 == (unsigned)access(procself_buf, 4 | 1)) {
      unlink(tmpname);
      fcntl(fdi, 2, 1);
      execve(procself_buf, argv, envp);
      unsigned const lenf = lseek(fdi, 0, 2);
      char *const buf = mmap((char *)0, lenf, 0x1 | 0x2, 0x02, fdi, 0);
      int const fdo = open(tmpname, 01 | 0100 | 0200, 0700);
      if (lenf != (unsigned)write(fdo, buf, lenf)) {
        exit(127);
      }
      close(fdo);
    }
    close(fdi);
  }
  return fdi;
}
```