ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <problem1@plt>
  mov    $0x4,%edi
  call   <moveForward@plt>
  movsd  D4(%rip),%xmm0
  call   <turn@plt>
  xor    %eax,%eax
  call   <done@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: f64

tool: D4: 3.14159265

assistant: ```c
int main() {
  problem1();
  moveForward(4);
  turn(3.14159265);
  done();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  movw   $0xffff,-0x12(%rbp)
  lea    -0x15(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D51(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  jmp    L0
L35:
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movzwl -0x14(%rbp),%eax
  cmp    %ax,-0x12(%rbp)
  jge    L54
  movzwl -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %ax,%ax
  jne    L54
  movzwl -0x14(%rbp),%eax
  jmp    L18
L54:
  movzwl -0x12(%rbp),%eax
L18:
  mov    %ax,-0x12(%rbp)
  movzbl -0x15(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x15(%rbp)
L0:
  movzbl -0x15(%rbp),%eax
  test   %al,%al
  jne    L35
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  movswl -0x12(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D48(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D39
type_guessed: string
name: retrieve_data
arguments: tag: D49
type_guessed: string
name: retrieve_data
arguments: tag: D51
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D59
type_guessed: string
name: retrieve_data
arguments: tag: D66
type_guessed: string
name: retrieve_data
arguments: tag: D48
type_guessed: string

tool: D39: r

tool: D49: INP.TXT

tool: D51: %hhd

tool: D13: %hd

tool: D59: w

tool: D66: OUT.TXT

tool: D48: %hd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n;
  short a, tmp = -1;
  fscanf(f, "%hhd", &n);
  for (; n; n--) {
    fscanf(f, "%hd", &a);
    tmp = (a > tmp && a % 2 == 0) ? a : tmp;
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hd\n", tmp);
  fclose(f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x5(%rsp),%rdx
  lea    D31(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  cmpb   $0x0,0x5(%rsp)
  je     L26
  mov    $0xffffffff,%ebx
  lea    D1(%rip),%r12
  jmp    L8
L14:
  movzbl 0x5(%rsp),%eax
  sub    $0x1,%eax
  mov    %al,0x5(%rsp)
  test   %al,%al
  je     L22
L8:
  lea    0x6(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movzwl 0x6(%rsp),%eax
  cmp    %bx,%ax
  jle    L14
  test   $0x1,%al
  cmove  %eax,%ebx
  jmp    L14
L26:
  mov    $0xffffffff,%ebx
L22:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D62(%rip),%rsi
  lea    D67(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  movswl %bx,%edx
  lea    D30(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D40
data_type: string
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D31
data_type: string
name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D62
data_type: string
name: read_data
arguments: tag: D67
data_type: string
name: read_data
arguments: tag: D30
data_type: string

tool: D40: r

tool: D0: INP.TXT

tool: D31: %hhd

tool: D1: %hd

tool: D62: w

tool: D67: OUT.TXT

tool: D30: %hd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n;
  short a, tmp = -1;
  fscanf(f, "%hhd", &n);
  for (; n; n--) {
    fscanf(f, "%hd", &a);
    tmp = (a > tmp && a % 2 == 0) ? a : tmp;
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hd\n", tmp);
  fclose(f);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  lea    D20(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x5(%rsp),%rdx
  lea    D47(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  cmpb   $0x0,0x5(%rsp)
  je     L18
  lea    0x6(%rsp),%r13
  lea    D21(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movzwl 0x6(%rsp),%eax
  cmp    %bx,%ax
  jle    L23
  test   $0x1,%al
  cmove  %eax,%ebx
L23:
  subb   $0x1,0x5(%rsp)
  jne    L32
L18:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D14(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  movswl %bx,%edx
  lea    D29(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D20
datatype: string
name: unpack_data
arguments: data_tag: D47
datatype: string
name: unpack_data
arguments: data_tag: D21
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D29
datatype: string

tool: D4: r

tool: D20: INP.TXT

tool: D47: %hhd

tool: D21: %hd

tool: D14: w

tool: D13: OUT.TXT

tool: D29: %hd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n;
  short a, tmp = -1;
  fscanf(f, "%hhd", &n);
  for (; n; n--) {
    fscanf(f, "%hd", &a);
    tmp = (a > tmp && a % 2 == 0) ? a : tmp;
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hd\n", tmp);
  fclose(f);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D51(%rip),%rsi
  lea    D56(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x5(%rsp),%rdx
  lea    D36(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  cmpb   $0x0,0x5(%rsp)
  je     L6
  lea    0x6(%rsp),%r13
  lea    D14(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movzwl 0x6(%rsp),%eax
  cmp    %bx,%ax
  jle    L17
  test   $0x1,%al
  cmove  %eax,%ebx
L17:
  subb   $0x1,0x5(%rsp)
  jne    L12
L6:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D26(%rip),%rsi
  lea    D22(%rip),%rdi
  call   <fopen@plt>
  movswl %bx,%edx
  lea    D38(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D51
datatype: string
name: unpack_data
arguments: label: D56
datatype: string
name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D38
datatype: string

tool: D51: r

tool: D56: INP.TXT

tool: D36: %hhd

tool: D14: %hd

tool: D26: w

tool: D22: OUT.TXT

tool: D38: %hd


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char n;
  short a, tmp = -1;
  fscanf(f, "%hhd", &n);
  for (; n; n--) {
    fscanf(f, "%hd", &a);
    tmp = (a > tmp && a % 2 == 0) ? a : tmp;
  }
  fclose(f);
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%hd\n", tmp);
  fclose(f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<palindrome8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  add    %edx,%edx
  sub    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L9
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void palindrome8(char *s, char *dest) {
  int n = strlen(s);
  for (int i = 0; i < n; i++) {
    dest[i] = s[i];
    dest[2 * n - i - 1] = s[i];
  }
  dest[2 * n] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<palindrome8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  lea    (%rax,%rax,1),%edx
  movslq %edx,%rdx
  lea    -0x1(%rbx,%rdx,1),%rcx
  mov    %eax,%edi
  mov    $0x0,%edx
L11:
  movzbl 0x0(%rbp,%rdx,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %sil,(%rcx)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %rdi,%rdx
  jne    L11
L16:
  add    %eax,%eax
  cltq
  movb   $0x0,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void palindrome8(char *s, char *dest) {
  int n = strlen(s);
  for (int i = 0; i < n; i++) {
    dest[i] = s[i];
    dest[2 * n - i - 1] = s[i];
  }
  dest[2 * n] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<palindrome8>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%rax,1),%esi
  movslq %esi,%rsi
  test   %eax,%eax
  jle    L7
  lea    -0x1(%rbx,%rsi,1),%rcx
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl 0x0(%rbp,%rdx,1),%r8d
  sub    $0x1,%rcx
  mov    %r8b,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %r8b,0x1(%rcx)
  cmp    %rax,%rdx
  jne    L13
L7:
  movb   $0x0,(%rbx,%rsi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void palindrome8(char *s, char *dest) {
  int n = strlen(s);
  for (int i = 0; i < n; i++) {
    dest[i] = s[i];
    dest[2 * n - i - 1] = s[i];
  }
  dest[2 * n] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<palindrome8>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    (%rax,%rax,1),%esi
  movslq %esi,%rsi
  test   %eax,%eax
  jle    L0
  lea    -0x1(%rbx,%rsi,1),%rcx
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl 0x0(%rbp,%rdx,1),%r8d
  sub    $0x1,%rcx
  mov    %r8b,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %r8b,0x1(%rcx)
  cmp    %rdx,%rax
  jne    L1
L0:
  movb   $0x0,(%rbx,%rsi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void palindrome8(char *s, char *dest) {
  int n = strlen(s);
  for (int i = 0; i < n; i++) {
    dest[i] = s[i];
    dest[2 * n - i - 1] = s[i];
  }
  dest[2 * n] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trim_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L18
L19:
  subq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L18:
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
L27:
  nop
  leave
  ret
```

assistant: ```c
void trim_right(char str[]) {
  size_t len = strlen(str);
  while (len > 0U && isspace(str[len - 1U])) {
    str[--len] = '\0';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_right>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L28:
  sub    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L18
  movb   $0x0,0x0(%rbp,%rbx,1)
  test   %rbx,%rbx
  jne    L28
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_right(char str[]) {
  size_t len = strlen(str);
  while (len > 0U && isspace(str[len - 1U])) {
    str[--len] = '\0';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim_right>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L29
  jmp    L2
  nopl   0x0(%rax)
L12:
  movb   $0x0,0x0(%rbp,%rbx,1)
  test   %rbx,%rbx
  je     L2
L29:
  sub    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_right(char str[]) {
  size_t len = strlen(str);
  while (len > 0U && isspace(str[len - 1U])) {
    str[--len] = '\0';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim_right>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L25
  jmp    L19
  nopl   0x0(%rax)
L21:
  movb   $0x0,0x0(%rbp,%rbx,1)
  test   %rbx,%rbx
  je     L19
L25:
  sub    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trim_right(char str[]) {
  size_t len = strlen(str);
  while (len > 0U && isspace(str[len - 1U])) {
    str[--len] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <DesKeyInit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: ~!@#%^$<

assistant: ```c
int main() {
  int a = 5;
  a++;
  DesKeyInit("~!@#%^$<");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <DesKeyInit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: ~!@#%^$<

assistant: ```c
int main() {
  int a = 5;
  a++;
  DesKeyInit("~!@#%^$<");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <DesKeyInit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: ~!@#%^$<

assistant: ```c
int main() {
  int a = 5;
  a++;
  DesKeyInit("~!@#%^$<");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <DesKeyInit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: ~!@#%^$<

assistant: ```c
int main() {
  int a = 5;
  a++;
  DesKeyInit("~!@#%^$<");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_mul_overflow_uint_uint_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  je     L1
  mov    $0x0,%eax
  call   <overflowed@plt>
L1:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
unsigned test_mul_overflow_uint_uint_uint(unsigned x, unsigned y) {
  unsigned r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_mul_overflow_uint_uint_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L16
L19:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L16:
  mov    $0x0,%eax
  call   <overflowed@plt>
  jmp    L19
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned test_mul_overflow_uint_uint_uint(unsigned x, unsigned y) {
  unsigned r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_mul_overflow_uint_uint_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L16
L19:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L16:
  xor    %eax,%eax
  call   <overflowed@plt>
  jmp    L19
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned test_mul_overflow_uint_uint_uint(unsigned x, unsigned y) {
  unsigned r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_mul_overflow_uint_uint_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  test   %rax,%rax
  jne    L20
L9:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L20:
  xor    %eax,%eax
  call   <overflowed@plt>
  jmp    L9
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned test_mul_overflow_uint_uint_uint(unsigned x, unsigned y) {
  unsigned r;
  if (__builtin_mul_overflow(x, y, &r))
    overflowed();
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L14:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fix_backwards_sequences@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
bool reverse(char *string, size_t max_len) {
  char *p = string;
  char *q = p + strnlen(p, max_len) - 1;
  while (p < q) {
    swap(p, q);
    p++;
    q--;
  }
  fix_backwards_sequences(string);
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strnlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jae    L13
  mov    %r12,%rbp
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%rbp
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jb     L5
L13:
  mov    %r12,%rdi
  call   <fix_backwards_sequences@plt>
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool reverse(char *string, size_t max_len) {
  char *p = string;
  char *q = p + strnlen(p, max_len) - 1;
  while (p < q) {
    swap(p, q);
    p++;
    q--;
  }
  fix_backwards_sequences(string);
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strnlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jae    L16
  mov    %r12,%rbp
  nop
L6:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L6
L16:
  mov    %r12,%rdi
  call   <fix_backwards_sequences@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool reverse(char *string, size_t max_len) {
  char *p = string;
  char *q = p + strnlen(p, max_len) - 1;
  while (p < q) {
    swap(p, q);
    p++;
    q--;
  }
  fix_backwards_sequences(string);
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strnlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jae    L12
  mov    %r12,%rbp
  nop
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  add    $0x1,%rbp
  call   <swap@plt>
  cmp    %rbx,%rbp
  jb     L5
L12:
  mov    %r12,%rdi
  call   <fix_backwards_sequences@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool reverse(char *string, size_t max_len) {
  char *p = string;
  char *q = p + strnlen(p, max_len) - 1;
  while (p < q) {
    swap(p, q);
    p++;
    q--;
  }
  fix_backwards_sequences(string);
  return true;
}
```