ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  cmp    %rsi,%rdi
  je     L14
  mov    %edi,%eax
  or     %esi,%eax
  test   $0x7,%al
  jne    L48
  cmp    $0x7,%rdx
  jbe    L48
  lea    -0x8(%rdx),%rax
  shr    $0x3,%rax
  lea    0x8(,%rax,8),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L53:
  mov    (%rsi,%rax,1),%rcx
  mov    %rcx,(%r8,%rax,1)
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L53
  and    $0x7,%edx
  lea    (%r8,%rax,1),%rdi
  add    %rax,%rsi
L48:
  test   %rdx,%rdx
  je     L14
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L22
L14:
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t count) {
  unsigned long *dl = (unsigned long *)dest, *sl = (unsigned long *)src;
  char *d8, *s8;
  if (src == dest)
    return dest;
  if ((((uint32_t)dest | (uint32_t)src) & (sizeof(*dl) - 1)) == 0) {
    while (count >= sizeof(*dl)) {
      *dl++ = *sl++;
      count -= sizeof(*dl);
    }
  }
  d8 = (char *)dl;
  s8 = (char *)sl;
  while (count--) {
    *d8++ = *s8++;
  }
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<eigsrt_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L68
L71:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L21
L17:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L35
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L35:
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L17
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L14
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L43
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L43:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L4
L14:
  addl   $0x1,-0xc(%rbp)
L68:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L71
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void eigsrt_d(d, v, n) double d[], **v;
int n;
{
  int k, j, i;
  double p;
  for (i = 1; i < n; i++) {
    k = i;
    p = d[i];
    for (j = i + 1; j <= n; j++) {
      if (d[j] >= p) {
        k = j;
        p = d[j];
      }
    }
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eigsrt_d>:
  endbr64
  cmp    $0x1,%edx
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %edx,%edi
  mov    %edx,%ebp
  lea    -0x1(%rdx),%eax
  lea    0x10(%rsi,%rax,8),%r11
  mov    $0x1,%r8d
  mov    $0x2,%r10d
  jmp    L44
L36:
  add    $0x1,%rax
  cmp    %eax,%edi
  jl     L99
L101:
  movsd  (%rcx,%rax,8),%xmm0
  comisd %xmm1,%xmm0
  jb     L36
  movapd %xmm0,%xmm1
  mov    %eax,%edx
  jmp    L36
L99:
  cmp    %r8d,%edx
  jne    L40
L53:
  add    $0x1,%r10
  add    $0x1,%r8
  cmp    %rbp,%r8
  je     L109
L44:
  mov    %r8d,%edx
  lea    0x0(,%r8,8),%r9
  movsd  (%rcx,%r8,8),%xmm2
  cmp    %r10d,%edi
  jl     L53
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  jmp    L101
L40:
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r12
  movsd  %xmm2,(%rcx,%rdx,8)
  movsd  %xmm1,(%rcx,%r8,8)
  lea    0x8(%rbx),%rax
L1:
  mov    (%rax),%rsi
  lea    (%rsi,%r9,1),%rdx
  movsd  (%rdx),%xmm0
  movsd  (%rsi,%r12,1),%xmm1
  movsd  %xmm1,(%rdx)
  mov    (%rax),%rdx
  movsd  %xmm0,(%rdx,%r12,1)
  add    $0x8,%rax
  cmp    %rax,%r11
  jne    L1
  jmp    L53
L109:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

assistant: ```c
void eigsrt_d(d, v, n) double d[], **v;
int n;
{
  int k, j, i;
  double p;
  for (i = 1; i < n; i++) {
    k = i;
    p = d[i];
    for (j = i + 1; j <= n; j++) {
      if (d[j] >= p) {
        k = j;
        p = d[j];
      }
    }
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eigsrt_d>:
  endbr64
  cmp    $0x1,%edx
  jle    L72
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r8d
  push   %rbp
  mov    %edx,%edi
  movslq %edx,%rbp
  lea    0x10(%rsi,%rax,8),%r11
  push   %rbx
  mov    $0x2,%r10d
  mov    %rsi,%rbx
L0:
  movsd  (%rcx,%r8,8),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,8),%r9
  cmp    %r10d,%edi
  jl     L25
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L14:
  movsd  (%rcx,%rax,8),%xmm0
  comisd %xmm1,%xmm0
  jb     L17
  movapd %xmm0,%xmm1
  movslq %eax,%rdx
L17:
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L14
  cmp    %r8d,%edx
  jne    L63
L25:
  add    $0x1,%r8
  add    $0x1,%r10
  cmp    %rbp,%r8
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  movsd  %xmm2,(%rcx,%rdx,8)
  lea    0x0(,%rdx,8),%r12
  lea    0x8(%rbx),%rdx
  movsd  %xmm1,(%rcx,%r8,8)
  nop
L61:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movsd  (%rsi),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  %xmm0,(%rax)
  cmp    %rdx,%r11
  jne    L61
  jmp    L25
L72:
  ret
```

assistant: ```c
void eigsrt_d(d, v, n) double d[], **v;
int n;
{
  int k, j, i;
  double p;
  for (i = 1; i < n; i++) {
    k = i;
    p = d[i];
    for (j = i + 1; j <= n; j++) {
      if (d[j] >= p) {
        k = j;
        p = d[j];
      }
    }
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eigsrt_d>:
  endbr64
  cmp    $0x1,%edx
  jle    L26
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r8d
  push   %rbp
  mov    %edx,%edi
  movslq %edx,%rbp
  lea    0x10(%rsi,%rax,8),%r11
  push   %rbx
  mov    $0x2,%r10d
  mov    %rsi,%rbx
L25:
  movsd  (%rcx,%r8,8),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,8),%r9
  cmp    %r10d,%edi
  jl     L52
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L27:
  movsd  (%rcx,%rax,8),%xmm0
  comisd %xmm1,%xmm0
  jb     L65
  movapd %xmm0,%xmm1
  movslq %eax,%rdx
L65:
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L27
  cmp    %r8d,%edx
  jne    L28
L52:
  add    $0x1,%r8
  add    $0x1,%r10
  cmp    %r8,%rbp
  jne    L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  movsd  %xmm2,(%rcx,%rdx,8)
  lea    0x0(,%rdx,8),%r12
  lea    0x8(%rbx),%rdx
  movsd  %xmm1,(%rcx,%r8,8)
  nop
L79:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movsd  (%rsi),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rsi)
  movsd  %xmm0,(%rax)
  cmp    %rdx,%r11
  jne    L79
  jmp    L52
L26:
  ret
```

assistant: ```c
void eigsrt_d(d, v, n) double d[], **v;
int n;
{
  int k, j, i;
  double p;
  for (i = 1; i < n; i++) {
    k = i;
    p = d[i];
    for (j = i + 1; j <= n; j++) {
      if (d[j] >= p) {
        k = j;
        p = d[j];
      }
    }
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qd_mul_pwr2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void qd_mul_pwr2(const double *a, double b, double *c) {
  c[0] = a[0] * b;
  c[1] = a[1] * b;
  c[2] = a[2] * b;
  c[3] = a[3] * b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qd_mul_pwr2>:
  endbr64
  movapd %xmm0,%xmm1
  mulsd  (%rdi),%xmm1
  movsd  %xmm1,(%rsi)
  movapd %xmm0,%xmm1
  mulsd  0x8(%rdi),%xmm1
  movsd  %xmm1,0x8(%rsi)
  movapd %xmm0,%xmm1
  mulsd  0x10(%rdi),%xmm1
  movsd  %xmm1,0x10(%rsi)
  mulsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  ret
```

assistant: ```c
void qd_mul_pwr2(const double *a, double b, double *c) {
  c[0] = a[0] * b;
  c[1] = a[1] * b;
  c[2] = a[2] * b;
  c[3] = a[3] * b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qd_mul_pwr2>:
  endbr64
  movsd  (%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  0x8(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsi)
  movsd  0x10(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rsi)
  mulsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  ret
```

assistant: ```c
void qd_mul_pwr2(const double *a, double b, double *c) {
  c[0] = a[0] * b;
  c[1] = a[1] * b;
  c[2] = a[2] * b;
  c[3] = a[3] * b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<probe1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x4,%eax
  xor    -0x18(%rbp),%eax
  and    $0xfff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int probe1(unsigned char root, int codeword) {
  int newHashCode = ((root << 4) ^ codeword) & 0xfff;
  return (newHashCode);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<probe1>:
  endbr64
  movzbl %dil,%edi
  shl    $0x4,%edi
  xor    %esi,%edi
  mov    %edi,%eax
  and    $0xfff,%eax
  ret
```

assistant: ```c
int probe1(unsigned char root, int codeword) {
  int newHashCode = ((root << 4) ^ codeword) & 0xfff;
  return (newHashCode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<probe1>:
  endbr64
  movzbl %dil,%edi
  shl    $0x4,%edi
  xor    %esi,%edi
  mov    %edi,%eax
  and    $0xfff,%eax
  ret
```

assistant: ```c
int probe1(unsigned char root, int codeword) {
  int newHashCode = ((root << 4) ^ codeword) & 0xfff;
  return (newHashCode);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findsed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %rcx,-0x440(%rbp)
  mov    %r8,-0x448(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x448(%rbp),%rdx
  mov    -0x428(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <build_find_string_buffer@plt>
  lea    -0x210(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x418(%rbp)
  jmp    L19
L6:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x440(%rbp),%rcx
  mov    -0x438(%rbp),%rdx
  mov    -0x430(%rbp),%rsi
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <sed_this_file@plt>
L19:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D16: r

tool: D1: %s


assistant: ```c
void findsed(char *find_string, char *search_string, char *replace_string, char *testing_string, char *excludedir_string) {
  FILE *p;
  char this_file[512];
  char find_string_buffer[512];
  build_find_string_buffer(find_string_buffer, find_string, excludedir_string);
  p = popen(find_string_buffer, "r");
  while (get_line(this_file, p)) {
    printf("%s\n", this_file);
    sed_this_file(this_file, search_string, replace_string, testing_string);
  }
  pclose(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<findsed>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %r8,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <build_find_string_buffer@plt>
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    %rax,%rbp
  lea    D19(%rip),%r15
  jmp    L16
L1:
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <sed_this_file@plt>
L16:
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D6: r

tool: D19: %s


assistant: ```c
void findsed(char *find_string, char *search_string, char *replace_string, char *testing_string, char *excludedir_string) {
  FILE *p;
  char this_file[512];
  char find_string_buffer[512];
  build_find_string_buffer(find_string_buffer, find_string, excludedir_string);
  p = popen(find_string_buffer, "r");
  while (get_line(this_file, p)) {
    printf("%s\n", this_file);
    sed_this_file(this_file, search_string, replace_string, testing_string);
  }
  pclose(p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findsed>:
  endbr64
  push   %r15
  lea    D10(%rip),%r15
  push   %r14
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdx,%r13
  mov    %r8,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rdi
  call   <build_find_string_buffer@plt>
  mov    %rbp,%rdi
  lea    D14(%rip),%rsi
  call   <popen@plt>
  mov    %rax,%rbp
  jmp    L8
  nopl   (%rax)
L3:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <sed_this_file@plt>
L8:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L3
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D10: %s


tool: D14: r

assistant: ```c
void findsed(char *find_string, char *search_string, char *replace_string, char *testing_string, char *excludedir_string) {
  FILE *p;
  char this_file[512];
  char find_string_buffer[512];
  build_find_string_buffer(find_string_buffer, find_string, excludedir_string);
  p = popen(find_string_buffer, "r");
  while (get_line(this_file, p)) {
    printf("%s\n", this_file);
    sed_this_file(this_file, search_string, replace_string, testing_string);
  }
  pclose(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findsed>:
  endbr64
  push   %r15
  lea    D18(%rip),%r15
  push   %r14
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdx,%r13
  mov    %r8,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rdi
  call   <build_find_string_buffer@plt>
  mov    %rbp,%rdi
  lea    D11(%rip),%rsi
  call   <popen@plt>
  mov    %rax,%rbp
  jmp    L4
  nopl   (%rax)
L2:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <sed_this_file@plt>
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L2
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
data_type: string
name: disassemble_data
arguments: data_label: D11
data_type: string

tool: D18: %s


tool: D11: r

assistant: ```c
void findsed(char *find_string, char *search_string, char *replace_string, char *testing_string, char *excludedir_string) {
  FILE *p;
  char this_file[512];
  char find_string_buffer[512];
  build_find_string_buffer(find_string_buffer, find_string, excludedir_string);
  p = popen(find_string_buffer, "r");
  while (get_line(this_file, p)) {
    printf("%s\n", this_file);
    sed_this_file(this_file, search_string, replace_string, testing_string);
  }
  pclose(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <linePointDist@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: c to AB segment distance is %f


assistant: ```c
int main() {
  int a[2] = {1, 2};
  int b[2] = {2, 1};
  int c[2] = {0, 0};
  printf("c to AB segment distance is %f\n", linePointDist(a, b, c, 1));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x1,%ecx
  call   <linePointDist@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: c to AB segment distance is %f


assistant: ```c
int main() {
  int a[2] = {1, 2};
  int b[2] = {2, 1};
  int c[2] = {0, 0};
  printf("c to AB segment distance is %f\n", linePointDist(a, b, c, 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x8(%rsp)
  call   <linePointDist@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: c to AB segment distance is %f


assistant: ```c
int main() {
  int a[2] = {1, 2};
  int b[2] = {2, 1};
  int c[2] = {0, 0};
  printf("c to AB segment distance is %f\n", linePointDist(a, b, c, 1));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,(%rsp)
  mov    D22(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <linePointDist@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D22
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string

tool: {"D2": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D22": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D15: c to AB segment distance is %f


assistant: ```c
int main() {
  int a[2] = {1, 2};
  int b[2] = {2, 1};
  int c[2] = {0, 0};
  printf("c to AB segment distance is %f\n", linePointDist(a, b, c, 1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<array_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jae    L29
  mov    $0x0,%eax
  jmp    L0
L29:
  cmpl   $0x0,-0x14(%rbp)
  jns    L19
  mov    $0x0,%eax
  jmp    L0
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
void *array_get(void **base, size_t length, int position) {
  if (position > length)
    return (void *)0;
  if (position < 0)
    return (void *)0;
  return base[position];
}
```