ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<InicializaMap>:
  endbr64
  push   %r12
  lea    0x64(%rdi),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  add    $0x5,%rbx
  call   <strcpy@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: 0000

assistant: ```c
void InicializaMap(char map[20][5]) {
  int i;
  for (i = 0; i < 20; i++) {
    strcpy(map[i], "0000");
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qsort_desc_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L20
  mov    $0x1,%eax
  jmp    L39
L20:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L9
  ucomisd %xmm1,%xmm0
  jne    L9
  mov    $0x0,%eax
  jmp    L39
L9:
  mov    $0xffffffff,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int qsort_desc_dvector(const void *a, const void *b) {
  const double *aa = a;
  const double *bb = b;
  if (*aa < *bb)
    return 1;
  else if (*aa == *bb)
    return 0;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qsort_desc_dvector>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L3
  ucomisd %xmm0,%xmm1
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int qsort_desc_dvector(const void *a, const void *b) {
  const double *aa = a;
  const double *bb = b;
  if (*aa < *bb)
    return 1;
  else if (*aa == *bb)
    return 0;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort_desc_dvector>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L1
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L1:
  ret
```

assistant: ```c
int qsort_desc_dvector(const void *a, const void *b) {
  const double *aa = a;
  const double *bb = b;
  if (*aa < *bb)
    return 1;
  else if (*aa == *bb)
    return 0;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qsort_desc_dvector>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L4
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L4:
  ret
```

assistant: ```c
int qsort_desc_dvector(const void *a, const void *b) {
  const double *aa = a;
  const double *bb = b;
  if (*aa < *bb)
    return 1;
  else if (*aa == *bb)
    return 0;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<failwhale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: fail whale :(


assistant: ```c
void failwhale(void) {
  printf("fail whale :(\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<failwhale>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: fail whale :(


assistant: ```c
void failwhale(void) {
  printf("fail whale :(\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<failwhale>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: fail whale :(


assistant: ```c
void failwhale(void) {
  printf("fail whale :(\n");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<failwhale>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: fail whale :(


assistant: ```c
void failwhale(void) {
  printf("fail whale :(\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<forzarColumnaUnica>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <hayConflictoEnColumna@plt>
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  jmp    L27
L21:
  movl   $0x1,-0xc(%rbp)
  jmp    L20
L57:
  mov    -0xc(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <hayConflictoSoloEnColumna@plt>
  test   %rax,%rax
  je     L60
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <containsInt@plt>
  test   %eax,%eax
  jne    L60
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <addInt@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getFilaConflictoEnColumna@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L27
L60:
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x9,-0xc(%rbp)
  jle    L57
  mov    $0x0,%eax
L27:
  leave
  ret
```

assistant: ```c
int forzarColumnaUnica(int sudoku[9][9], int iPosicionAtratar, int jPosicionAtratar, int *j, int *blackList) {
  if (!hayConflictoEnColumna(sudoku, jPosicionAtratar)) {
    return 0;
  }
  int nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    if (hayConflictoSoloEnColumna(sudoku, iPosicionAtratar, jPosicionAtratar, nuevoCandidato) && !containsInt(blackList, 9, nuevoCandidato)) {
      addInt(blackList, 9, nuevoCandidato);
      int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, nuevoCandidato);
      int jPosicionConflicto = jPosicionAtratar;
      sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
      sudoku[iPosicionAtratar][jPosicionAtratar] = nuevoCandidato;
      *j -= 1;
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<forzarColumnaUnica>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r15
  mov    %r8,%r14
  mov    %edx,%esi
  call   <hayConflictoEnColumna@plt>
  test   %eax,%eax
  je     L29
  mov    $0x1,%ebx
  jmp    L2
L49:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L24
L2:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <hayConflictoSoloEnColumna@plt>
  test   %rax,%rax
  je     L49
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <containsInt@plt>
  test   %eax,%eax
  jne    L49
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <addInt@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r12,%rax,4),%rax
  movslq %ebp,%rbp
  movl   $0x0,(%rax,%rbp,4)
  movslq %r13d,%r13
  lea    0x0(%r13,%r13,8),%rax
  lea    (%r12,%rax,4),%rax
  mov    %ebx,(%rax,%rbp,4)
  subl   $0x1,(%r15)
  mov    $0x1,%eax
  jmp    L29
L24:
  mov    $0x0,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int forzarColumnaUnica(int sudoku[9][9], int iPosicionAtratar, int jPosicionAtratar, int *j, int *blackList) {
  if (!hayConflictoEnColumna(sudoku, jPosicionAtratar)) {
    return 0;
  }
  int nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    if (hayConflictoSoloEnColumna(sudoku, iPosicionAtratar, jPosicionAtratar, nuevoCandidato) && !containsInt(blackList, 9, nuevoCandidato)) {
      addInt(blackList, 9, nuevoCandidato);
      int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, nuevoCandidato);
      int jPosicionConflicto = jPosicionAtratar;
      sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
      sudoku[iPosicionAtratar][jPosicionAtratar] = nuevoCandidato;
      *j -= 1;
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<forzarColumnaUnica>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <hayConflictoEnColumna@plt>
  test   %eax,%eax
  je     L40
  mov    $0x1,%ebx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L40
L12:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <hayConflictoSoloEnColumna@plt>
  test   %rax,%rax
  je     L0
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <containsInt@plt>
  test   %eax,%eax
  jne    L0
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <addInt@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r12,%rax,4),%rax
  movl   $0x0,(%rax,%rbp,4)
  lea    0x0(%r13,%r13,8),%rax
  lea    (%r12,%rax,4),%rax
  mov    %ebx,(%rax,%rbp,4)
  mov    $0x1,%eax
  subl   $0x1,(%r15)
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int forzarColumnaUnica(int sudoku[9][9], int iPosicionAtratar, int jPosicionAtratar, int *j, int *blackList) {
  if (!hayConflictoEnColumna(sudoku, jPosicionAtratar)) {
    return 0;
  }
  int nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    if (hayConflictoSoloEnColumna(sudoku, iPosicionAtratar, jPosicionAtratar, nuevoCandidato) && !containsInt(blackList, 9, nuevoCandidato)) {
      addInt(blackList, 9, nuevoCandidato);
      int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, nuevoCandidato);
      int jPosicionConflicto = jPosicionAtratar;
      sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
      sudoku[iPosicionAtratar][jPosicionAtratar] = nuevoCandidato;
      *j -= 1;
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<forzarColumnaUnica>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <hayConflictoEnColumna@plt>
  test   %eax,%eax
  je     L21
  mov    $0x1,%ebx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L21
L34:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <hayConflictoSoloEnColumna@plt>
  test   %rax,%rax
  je     L40
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <containsInt@plt>
  test   %eax,%eax
  jne    L40
  mov    %ebx,%edx
  mov    $0x9,%esi
  mov    %r14,%rdi
  call   <addInt@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <getFilaConflictoEnColumna@plt>
  cltq
  lea    (%rax,%rax,8),%rax
  lea    (%r12,%rax,4),%rax
  movl   $0x0,(%rax,%rbp,4)
  lea    0x0(%r13,%r13,8),%rax
  lea    (%r12,%rax,4),%rax
  mov    %ebx,(%rax,%rbp,4)
  mov    $0x1,%eax
  subl   $0x1,(%r15)
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int forzarColumnaUnica(int sudoku[9][9], int iPosicionAtratar, int jPosicionAtratar, int *j, int *blackList) {
  if (!hayConflictoEnColumna(sudoku, jPosicionAtratar)) {
    return 0;
  }
  int nuevoCandidato;
  for (nuevoCandidato = 1; nuevoCandidato <= 9; nuevoCandidato++) {
    if (hayConflictoSoloEnColumna(sudoku, iPosicionAtratar, jPosicionAtratar, nuevoCandidato) && !containsInt(blackList, 9, nuevoCandidato)) {
      addInt(blackList, 9, nuevoCandidato);
      int iPosicionConflicto = getFilaConflictoEnColumna(sudoku, jPosicionAtratar, nuevoCandidato);
      int jPosicionConflicto = jPosicionAtratar;
      sudoku[iPosicionConflicto][jPosicionConflicto] = 0;
      sudoku[iPosicionAtratar][jPosicionAtratar] = nuevoCandidato;
      *j -= 1;
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_volts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x7000,-0x4(%rbp)
  jg     L0
  addl   $0x10000,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: f64

tool: D2: 3.3

assistant: ```c
double get_volts(int val, int zero, int range) {
  if (val <= 0x7000)
    val = val + 0x10000;
  val = val - zero;
  return ((double)val * 3.3) / range;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_volts>:
  endbr64
  lea    0x10000(%rdi),%eax
  cmp    $0x7001,%edi
  cmovl  %eax,%edi
  sub    %esi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D2(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: f64

tool: D2: 3.3

assistant: ```c
double get_volts(int val, int zero, int range) {
  if (val <= 0x7000)
    val = val + 0x10000;
  val = val - zero;
  return ((double)val * 3.3) / range;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_volts>:
  endbr64
  cmp    $0x7001,%edi
  lea    0x10000(%rdi),%eax
  pxor   %xmm0,%xmm0
  cmovl  %eax,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  sub    %esi,%edi
  cvtsi2sd %edi,%xmm0
  mulsd  D9(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: f64

tool: D9: 3.3

assistant: ```c
double get_volts(int val, int zero, int range) {
  if (val <= 0x7000)
    val = val + 0x10000;
  val = val - zero;
  return ((double)val * 3.3) / range;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_volts>:
  endbr64
  cmp    $0x7001,%edi
  lea    0x10000(%rdi),%eax
  pxor   %xmm0,%xmm0
  cmovl  %eax,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  sub    %esi,%edi
  cvtsi2sd %edi,%xmm0
  mulsd  D7(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: f64

tool: D7: 3.3

assistant: ```c
double get_volts(int val, int zero, int range) {
  if (val <= 0x7000)
    val = val + 0x10000;
  val = val - zero;
  return ((double)val * 3.3) / range;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x61,%edi
  call   <putchar@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  while (1) {
    putchar('a');
    return;
  }
  putchar(10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x61,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  while (1) {
    putchar('a');
    return;
  }
  putchar(10);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x61,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void main() {
  while (1) {
    putchar('a');
    return;
  }
  putchar(10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x61,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void main() {
  while (1) {
    putchar('a');
    return;
  }
  putchar(10);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x10,-0x14(%rbp)
  jle    L1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cpy@plt>
  mov    %rax,-0x8(%rbp)
L1:
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *foo = 0;
  if (argc > 16)
    foo = cpy(argv[0], argv[1], argc);
  return foo != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x10,%edi
  jg     L9
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
L9:
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  mov    0x8(%rsi),%rsi
  mov    %edi,%edx
  mov    (%rcx),%rdi
  call   <cpy@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *foo = 0;
  if (argc > 16)
    foo = cpy(argv[0], argv[1], argc);
  return foo != 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  cmp    $0x10,%edi
  jg     L7
  xor    %eax,%eax
  ret
L7:
  push   %rax
  mov    %rsi,%rax
  mov    %edi,%edx
  mov    0x8(%rsi),%rsi
  mov    (%rax),%rdi
  call   <cpy@plt>
  xor    %r8d,%r8d
  pop    %rdx
  test   %rax,%rax
  setne  %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *foo = 0;
  if (argc > 16)
    foo = cpy(argv[0], argv[1], argc);
  return foo != 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  cmp    $0x10,%edi
  jg     L2
  xor    %eax,%eax
  ret
L2:
  push   %rax
  mov    %rsi,%rax
  mov    %edi,%edx
  mov    0x8(%rsi),%rsi
  mov    (%rax),%rdi
  call   <cpy@plt>
  xor    %r8d,%r8d
  pop    %rdx
  test   %rax,%rax
  setne  %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *foo = 0;
  if (argc > 16)
    foo = cpy(argv[0], argv[1], argc);
  return foo != 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pretty_print>:
  endbr64
  test   %rdi,%rdi
  je     L100
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r12
  cmp    $0x2,%rcx
  je     L222
  cmp    $0x4,%rcx
  je     L211
  mov    $0xfffffffe,%eax
  cmp    $0x1,%rcx
  je     L42
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L211:
  test   %rsi,%rsi
  je     L168
  mov    $0x0,%r15d
  lea    D4(%rip),%r13
  jmp    L103
L222:
  test   %rsi,%rsi
  je     L277
  mov    $0x0,%r15d
  lea    D59(%rip),%r13
  jmp    L175
L42:
  test   %rsi,%rsi
  je     L106
  mov    $0x0,%r15d
  lea    D29(%rip),%r13
  jmp    L191
L236:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L236
L121:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r15
  add    $0x8,%rbp
  cmp    %r15,%r14
  je     L240
L191:
  mov    $0x0,%ebx
  test   %r12,%r12
  jne    L236
  jmp    L121
L80:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L80
L197:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r15
  add    $0x8,%rbp
  cmp    %r15,%r14
  je     L136
L175:
  mov    $0x0,%ebx
  test   %r12,%r12
  jne    L80
  jmp    L197
L99:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L99
L78:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r15
  add    $0x8,%rbp
  cmp    %r15,%r14
  je     L112
L103:
  mov    $0x0,%ebx
  test   %r12,%r12
  jne    L99
  jmp    L78
L100:
  mov    $0xffffffff,%eax
  ret
L168:
  mov    $0x0,%eax
  jmp    L66
L277:
  mov    $0x0,%eax
  jmp    L66
L106:
  mov    $0x0,%eax
  jmp    L66
L240:
  mov    $0x0,%eax
  jmp    L66
L136:
  mov    $0x0,%eax
  jmp    L66
L112:
  mov    $0x0,%eax
  jmp    L66
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string
name: read_data
arguments: data_tag: D59
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string

tool: D4: |%10d

tool: D59: |%5d

tool: D29: |%3d

tool: D20: |

assistant: ```c
int32_t pretty_print(void **tab, uint32_t lines, uint32_t columns, size_t type) {
  uint32_t i, j;
  if (tab == NULL)
    return -1;
  switch (type) {
  case ((size_t)1):
    for (i = 0; i < lines; i++) {
      for (j = 0; j < columns; j++)
        printf("|%3d", ((uint8_t **)tab)[i][j]);
      printf("|\n");
    }
    break;
  case ((size_t)2):
    for (i = 0; i < lines; i++) {
      for (j = 0; j < columns; j++)
        printf("|%5d", ((uint16_t **)tab)[i][j]);
      printf("|\n");
    }
    break;
  case ((size_t)4):
    for (i = 0; i < lines; i++) {
      for (j = 0; j < columns; j++)
        printf("|%10d", ((uint8_t **)tab)[i][j]);
      printf("|\n");
    }
    break;
  default:
    return -2;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void **copy_2d(void **dst, const void **src, size_t n, size_t m, size_t size) {
  memcpy(dst[0], src[0], n * m * size);
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy_2d>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  imul   %r8,%rcx
  imul   %rcx,%rdx
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void **copy_2d(void **dst, const void **src, size_t n, size_t m, size_t size) {
  memcpy(dst[0], src[0], n * m * size);
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_2d>:
  endbr64
  imul   %r8,%rcx
  push   %r12
  mov    %rdi,%r12
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  imul   %rcx,%rdx
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void **copy_2d(void **dst, const void **src, size_t n, size_t m, size_t size) {
  memcpy(dst[0], src[0], n * m * size);
  return dst;
}
```