ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<one_pad_check>:
  endbr64
  push   %r13
  lea    0xd9(%rdi),%r13
  push   %r12
  lea    0x3e0(%rdi),%r12
  push   %rbp
  lea    0x3c1(%rdi),%rbp
  push   %rbx
L22:
  mov    %rbp,%r9
  mov    %rsi,%rbx
  mov    %rdi,%r11
L47:
  movzbl (%r11),%r10d
  lea    -0x3c1(%r9),%rax
  mov    %rbx,%rdx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1f,%rax
  add    $0x1,%rdx
  cmp    %rax,%r9
  je     L25
L14:
  xor    %r8d,%r8d
  movzbl (%rax),%ecx
  cmp    %r10b,(%rdx)
  setne  %r8b
  cmp    %ecx,%r8d
  je     L37
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%r9
  add    $0x1,%r11
  add    $0x1f,%rbx
  cmp    %r12,%r9
  jne    L47
  add    $0x1f,%rdi
  add    $0x3c1,%rsi
  cmp    %r13,%rdi
  jne    L22
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int one_pad_check(unsigned char m[7][31], unsigned char xor [7][31][31]) {
  int i, j, k;
  for (i = 0; i < 7; i++) {
    for (j = 0; j < 31; j++) {
      for (k = 0; k < 31; k++) {
        if (xor[i][j][k] != m[i][j] ^ m[k][j]) {
          return 0;
        }
      }
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<one_pad_check>:
  endbr64
  push   %r13
  lea    0xd9(%rdi),%r13
  push   %r12
  lea    0x3e0(%rdi),%r12
  push   %rbp
  lea    0x3c1(%rdi),%rbp
  push   %rbx
L28:
  mov    %rbp,%r9
  mov    %rsi,%rbx
  mov    %rdi,%r11
L47:
  movzbl (%r11),%r10d
  lea    -0x3c1(%r9),%rax
  mov    %rbx,%rdx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1f,%rax
  add    $0x1,%rdx
  cmp    %rax,%r9
  je     L42
L8:
  xor    %r8d,%r8d
  movzbl (%rax),%ecx
  cmp    %r10b,(%rdx)
  setne  %r8b
  cmp    %ecx,%r8d
  je     L19
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%r9
  add    $0x1,%r11
  add    $0x1f,%rbx
  cmp    %r12,%r9
  jne    L47
  add    $0x1f,%rdi
  add    $0x3c1,%rsi
  cmp    %r13,%rdi
  jne    L28
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int one_pad_check(unsigned char m[7][31], unsigned char xor [7][31][31]) {
  int i, j, k;
  for (i = 0; i < 7; i++) {
    for (j = 0; j < 31; j++) {
      for (k = 0; k < 31; k++) {
        if (xor[i][j][k] != m[i][j] ^ m[k][j]) {
          return 0;
        }
      }
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stradd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x408,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %r12d,%r12d
  je     L123
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L53
  mov    %rbx,%rdi
  call   <revstring@plt>
  jmp    L16
L123:
  mov    %r13,%rdi
  call   <revstring@plt>
  jmp    L16
L53:
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <lenmax@plt>
  lea    -0x1(%r12),%ecx
  movslq %ecx,%rcx
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    %ebp,%r8d
  sub    %r12d,%r8d
  movslq %ebp,%rbp
  movslq %r12d,%rdi
  sub    %rdi,%rbp
  lea    0x0(%r13,%rbp,1),%rdi
  mov    $0x0,%r10d
  sub    %r12d,%eax
  mov    %eax,%r9d
  jmp    L60
L31:
  movb   $0x30,(%rdi,%rcx,1)
  jmp    L6
L98:
  sub    $0xa,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r12d
  sar    $0x1f,%r12d
  sub    %r12d,%edx
L55:
  add    %r9d,%r11d
  js     L15
  add    $0x30,%eax
L97:
  mov    %al,(%rsp,%rsi,1)
  add    $0x1,%rsi
  sub    $0x1,%rcx
L60:
  mov    %esi,%ebp
  test   %ecx,%ecx
  jns    L99
  movb   $0x30,(%rbx,%rcx,1)
L99:
  mov    %ecx,%r11d
  mov    %r8d,%eax
  add    %ecx,%eax
  js     L31
L6:
  movsbl (%rdi,%rcx,1),%r12d
  movsbl (%rbx,%rcx,1),%eax
  lea    -0x60(%r12,%rax,1),%eax
  add    %edx,%eax
  mov    %r10d,%edx
  cmp    $0x9,%eax
  jle    L55
  jmp    L98
L15:
  mov    %eax,%r11d
  or     %edx,%r11d
  je     L134
  add    $0x30,%eax
  jmp    L97
L134:
  movslq %ebp,%rbp
  movb   $0x0,(%rsp,%rbp,1)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <revstring@plt>
L16:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L90
  add    $0x408,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: Main::: %s


assistant: ```c
char *stradd(char a[], char b[]) {
  char c[1010];
  int len1 = strlen(a);
  int len2 = strlen(b);
  if (len1 == 0)
    return revstring(b);
  else if (len2 == 0)
    return revstring(a);
  else {
    int sum = 0, extra = 0;
    int len = lenmax(len1, len2);
    int j = 0;
    while (1) {
      len1--;
      len2--;
      len--;
      if (len1 < 0)
        a[len1] = '0';
      if (len2 < 0)
        b[len2] = '0';
      sum = a[len1] - '0' + b[len2] - '0' + extra;
      if (sum >= 10) {
        sum -= 10;
        extra = (int)sum / 10;
      } else
        extra = 0;
      if (len >= 0) {
        c[j] = sum + '0';
      } else if (len < 0) {
        if (extra == 0 && sum == 0) {
          break;
        } else {
          c[j] = sum + '0';
        }
      }
      j++;
    }
    c[j] = '\0';
    printf("Main::: %s\n", c);
    return revstring(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stradd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  test   %ebx,%ebx
  je     L114
  mov    %eax,%r14d
  test   %eax,%eax
  je     L105
  mov    %eax,%esi
  mov    %ebx,%edi
  mov    %rsp,%r13
  call   <lenmax@plt>
  movslq %r14d,%r9
  movslq %ebx,%rdx
  lea    -0x1(%rbx),%esi
  mov    %eax,%r10d
  sub    %rdx,%r9
  mov    %r14d,%eax
  movslq %esi,%rsi
  xor    %edi,%edi
  xor    %ecx,%ecx
  sub    %ebx,%eax
  add    %r12,%r9
  mov    $0xcccccccd,%r11d
  sub    %ebx,%r10d
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L58:
  movsbl (%r9,%rsi,1),%ebx
L20:
  movsbl 0x0(%rbp,%rsi,1),%edx
  lea    -0x60(%rbx,%rdx,1),%edx
  add    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x9,%edx
  jle    L13
  lea    -0xa(%rdx),%ecx
  mov    %rcx,%rdx
  imul   %r11,%rcx
  shr    $0x23,%rcx
L13:
  add    %r10d,%r8d
  js     L106
L46:
  add    $0x30,%edx
  sub    $0x1,%rsi
  mov    %dl,0x0(%r13,%rdi,1)
  add    $0x1,%rdi
L85:
  movslq %edi,%r12
  test   %esi,%esi
  jns    L69
  movb   $0x30,0x0(%rbp,%rsi,1)
L69:
  mov    %eax,%ebx
  mov    %esi,%r8d
  add    %esi,%ebx
  jns    L58
  movb   $0x30,(%r9,%rsi,1)
  mov    $0x30,%ebx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L105:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %rbp,%rdi
L60:
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <revstring@plt>
  nopw   0x0(%rax,%rax,1)
L106:
  mov    %edx,%ebx
  or     %ecx,%ebx
  jne    L46
  lea    D5(%rip),%rdi
  mov    %r13,%rsi
  movb   $0x0,(%rsp,%r12,1)
  call   <printf@plt>
  mov    %r13,%rdi
  call   <revstring@plt>
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L114:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %r12,%rdi
  jmp    L60
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: Main::: %s


assistant: ```c
char *stradd(char a[], char b[]) {
  char c[1010];
  int len1 = strlen(a);
  int len2 = strlen(b);
  if (len1 == 0)
    return revstring(b);
  else if (len2 == 0)
    return revstring(a);
  else {
    int sum = 0, extra = 0;
    int len = lenmax(len1, len2);
    int j = 0;
    while (1) {
      len1--;
      len2--;
      len--;
      if (len1 < 0)
        a[len1] = '0';
      if (len2 < 0)
        b[len2] = '0';
      sum = a[len1] - '0' + b[len2] - '0' + extra;
      if (sum >= 10) {
        sum -= 10;
        extra = (int)sum / 10;
      } else
        extra = 0;
      if (len >= 0) {
        c[j] = sum + '0';
      } else if (len < 0) {
        if (extra == 0 && sum == 0) {
          break;
        } else {
          c[j] = sum + '0';
        }
      }
      j++;
    }
    c[j] = '\0';
    printf("Main::: %s\n", c);
    return revstring(c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stradd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  test   %ebx,%ebx
  je     L112
  mov    %eax,%r14d
  test   %eax,%eax
  je     L7
  mov    %eax,%esi
  mov    %ebx,%edi
  mov    %rsp,%r13
  call   <lenmax@plt>
  movslq %r14d,%r9
  movslq %ebx,%rdx
  lea    -0x1(%rbx),%esi
  mov    %eax,%r10d
  sub    %rdx,%r9
  mov    %r14d,%eax
  movslq %esi,%rsi
  xor    %edi,%edi
  xor    %ecx,%ecx
  sub    %ebx,%eax
  add    %r12,%r9
  mov    $0xcccccccd,%r11d
  sub    %ebx,%r10d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl (%r9,%rsi,1),%ebx
L85:
  movsbl 0x0(%rbp,%rsi,1),%edx
  lea    -0x60(%rbx,%rdx,1),%edx
  add    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x9,%edx
  jle    L73
  lea    -0xa(%rdx),%ecx
  mov    %rcx,%rdx
  imul   %r11,%rcx
  shr    $0x23,%rcx
L73:
  add    %r10d,%r8d
  js     L23
L21:
  add    $0x30,%edx
  sub    $0x1,%rsi
  mov    %dl,0x0(%r13,%rdi,1)
  add    $0x1,%rdi
L45:
  movslq %edi,%r12
  test   %esi,%esi
  jns    L39
  movb   $0x30,0x0(%rbp,%rsi,1)
L39:
  mov    %eax,%ebx
  mov    %esi,%r8d
  add    %esi,%ebx
  jns    L31
  movb   $0x30,(%r9,%rsi,1)
  mov    $0x30,%ebx
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  mov    %rbp,%rdi
L40:
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <revstring@plt>
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %edx,%ebx
  or     %ecx,%ebx
  jne    L21
  lea    D5(%rip),%rdi
  mov    %r13,%rsi
  movb   $0x0,(%rsp,%r12,1)
  call   <printf@plt>
  mov    %r13,%rdi
  call   <revstring@plt>
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L116
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L112:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  mov    %r12,%rdi
  jmp    L40
L116:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: Main::: %s


assistant: ```c
char *stradd(char a[], char b[]) {
  char c[1010];
  int len1 = strlen(a);
  int len2 = strlen(b);
  if (len1 == 0)
    return revstring(b);
  else if (len2 == 0)
    return revstring(a);
  else {
    int sum = 0, extra = 0;
    int len = lenmax(len1, len2);
    int j = 0;
    while (1) {
      len1--;
      len2--;
      len--;
      if (len1 < 0)
        a[len1] = '0';
      if (len2 < 0)
        b[len2] = '0';
      sum = a[len1] - '0' + b[len2] - '0' + extra;
      if (sum >= 10) {
        sum -= 10;
        extra = (int)sum / 10;
      } else
        extra = 0;
      if (len >= 0) {
        c[j] = sum + '0';
      } else if (len < 0) {
        if (extra == 0 && sum == 0) {
          break;
        } else {
          c[j] = sum + '0';
        }
      }
      j++;
    }
    c[j] = '\0';
    printf("Main::: %s\n", c);
    return revstring(c);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RunEncryptionKeySchedule>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L35:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  add    $0x8,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x3,-0x14(%rbp)
  jle    L35
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L16:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  shl    $0xf,%eax
  movzwl %ax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x2,-0x14(%rbp)
  jle    L16
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shl    $0xf,%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  sar    $0xf,%eax
  and    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RunEncryptionKeySchedule(uint8_t *key, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *Key = (uint16_t *)key;
  uint16_t *RoundKeys = (uint16_t *)roundKeys;
  for (i = 0; i < 4; i++) {
    RoundKeys[i] = Key[i];
    RoundKeys[i + 8] = Key[i + 4];
  }
  for (i = 0; i < 3; i++) {
    RoundKeys[i + 4] = ((Key[i + 1] << 15) & 0x8000) ^ (Key[i] >> 1);
  }
  RoundKeys[7] = ((Key[0] << 15) & 0x8000) ^ (Key[3] >> 1);
  RoundKeys[4] = RoundKeys[4] ^ ((Key[3] >> 15) & 0x0001);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RunEncryptionKeySchedule>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%eax
L8:
  mov    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rsi,%rax,1)
  mov    0x10(%rdx,%rax,1),%ecx
  mov    %ecx,0x20(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L8
  mov    $0x0,%ecx
L10:
  mov    0x4(%rdx,%rcx,1),%eax
  shl    $0xf,%eax
  movzwl %ax,%eax
  mov    (%rdx,%rcx,1),%edi
  sar    %edi
  xor    %edi,%eax
  mov    %eax,0x10(%rsi,%rcx,1)
  add    $0x4,%rcx
  cmp    $0xc,%rcx
  jne    L10
  mov    (%rdx),%eax
  shl    $0xf,%eax
  movzwl %ax,%eax
  mov    0xc(%rdx),%ecx
  sar    %ecx
  xor    %ecx,%eax
  mov    %eax,0x1c(%rsi)
  mov    0xc(%rdx),%eax
  sar    $0xf,%eax
  and    $0x1,%eax
  xor    %eax,0x10(%rsi)
  ret
```

assistant: ```c
void RunEncryptionKeySchedule(uint8_t *key, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *Key = (uint16_t *)key;
  uint16_t *RoundKeys = (uint16_t *)roundKeys;
  for (i = 0; i < 4; i++) {
    RoundKeys[i] = Key[i];
    RoundKeys[i + 8] = Key[i + 4];
  }
  for (i = 0; i < 3; i++) {
    RoundKeys[i + 4] = ((Key[i + 1] << 15) & 0x8000) ^ (Key[i] >> 1);
  }
  RoundKeys[7] = ((Key[0] << 15) & 0x8000) ^ (Key[3] >> 1);
  RoundKeys[4] = RoundKeys[4] ^ ((Key[3] >> 15) & 0x0001);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RunEncryptionKeySchedule>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
L9:
  mov    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rsi,%rax,1)
  mov    0x10(%rdx,%rax,1),%ecx
  mov    %ecx,0x20(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L9
  xor    %ecx,%ecx
L14:
  mov    0x4(%rdx,%rcx,1),%eax
  mov    (%rdx,%rcx,1),%edi
  shl    $0xf,%eax
  sar    %edi
  movzwl %ax,%eax
  xor    %edi,%eax
  mov    %eax,0x10(%rsi,%rcx,1)
  add    $0x4,%rcx
  cmp    $0xc,%rcx
  jne    L14
  mov    (%rdx),%eax
  mov    0xc(%rdx),%ecx
  shl    $0xf,%eax
  sar    %ecx
  movzwl %ax,%eax
  xor    %ecx,%eax
  mov    %eax,0x1c(%rsi)
  mov    0xc(%rdx),%eax
  sar    $0xf,%eax
  and    $0x1,%eax
  xor    %eax,0x10(%rsi)
  ret
```

assistant: ```c
void RunEncryptionKeySchedule(uint8_t *key, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *Key = (uint16_t *)key;
  uint16_t *RoundKeys = (uint16_t *)roundKeys;
  for (i = 0; i < 4; i++) {
    RoundKeys[i] = Key[i];
    RoundKeys[i + 8] = Key[i + 4];
  }
  for (i = 0; i < 3; i++) {
    RoundKeys[i + 4] = ((Key[i + 1] << 15) & 0x8000) ^ (Key[i] >> 1);
  }
  RoundKeys[7] = ((Key[0] << 15) & 0x8000) ^ (Key[3] >> 1);
  RoundKeys[4] = RoundKeys[4] ^ ((Key[3] >> 15) & 0x0001);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RunEncryptionKeySchedule>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  lea    0x4(%rdi),%rsi
  lea    0x10(%rax),%rdx
  lea    0x30(%rcx),%rdi
  cmp    %rdx,%rdi
  lea    0x20(%rax),%rdi
  setbe  %dl
  cmp    %rdi,%rcx
  setae  %dil
  or     %dil,%dl
  je     L45
  mov    %rcx,%rdx
  sub    %rsi,%rdx
  add    $0x20,%rdx
  cmp    $0x28,%rdx
  jbe    L45
  movdqu (%rax),%xmm2
  lea    0x10(%rcx),%rdx
  sub    %rsi,%rdx
  movups %xmm2,(%rcx)
  movdqu 0x10(%rax),%xmm3
  movups %xmm3,0x20(%rcx)
  cmp    $0x4,%rdx
  jbe    L5
L15:
  movq   D9(%rip),%xmm1
  movq   0x4(%rax),%xmm0
  pslld  $0xf,%xmm0
  pand   %xmm1,%xmm0
  movq   (%rax),%xmm1
  psrad  $0x1,%xmm1
  pxor   %xmm1,%xmm0
  movq   %xmm0,0x10(%rcx)
L30:
  mov    0xc(%rax),%edx
  mov    0x8(%rax),%esi
  shl    $0xf,%edx
  sar    %esi
  movzwl %dx,%edx
  xor    %esi,%edx
  mov    %edx,0x18(%rcx)
  mov    (%rax),%edx
  mov    0xc(%rax),%esi
  shl    $0xf,%edx
  movzwl %dx,%edx
  sar    %esi
  xor    %esi,%edx
  mov    %edx,0x1c(%rcx)
  mov    0xc(%rax),%eax
  sar    $0xf,%eax
  and    $0x1,%eax
  xor    %eax,0x10(%rcx)
  ret
  nop
L45:
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    0x10(%rax),%edx
  mov    %edx,0x20(%rcx)
  mov    0x4(%rax),%edx
  mov    %edx,0x4(%rcx)
  mov    0x14(%rax),%edx
  mov    %edx,0x24(%rcx)
  mov    0x8(%rax),%edx
  mov    %edx,0x8(%rcx)
  mov    0x18(%rax),%edx
  mov    %edx,0x28(%rcx)
  mov    0xc(%rax),%edx
  mov    %edx,0xc(%rcx)
  mov    0x1c(%rax),%edx
  mov    %edx,0x2c(%rcx)
  lea    0x10(%rcx),%rdx
  sub    %rsi,%rdx
  cmp    $0x4,%rdx
  ja     L15
  nop
L5:
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  shl    $0xf,%edx
  sar    %esi
  movzwl %dx,%edx
  xor    %esi,%edx
  mov    %edx,0x10(%rcx)
  mov    0x8(%rax),%edx
  mov    0x4(%rax),%esi
  shl    $0xf,%edx
  movzwl %dx,%edx
  sar    %esi
  xor    %esi,%edx
  mov    %edx,0x14(%rcx)
  jmp    L30
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D9": [0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00]}

assistant: ```c
void RunEncryptionKeySchedule(uint8_t *key, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *Key = (uint16_t *)key;
  uint16_t *RoundKeys = (uint16_t *)roundKeys;
  for (i = 0; i < 4; i++) {
    RoundKeys[i] = Key[i];
    RoundKeys[i + 8] = Key[i + 4];
  }
  for (i = 0; i < 3; i++) {
    RoundKeys[i + 4] = ((Key[i + 1] << 15) & 0x8000) ^ (Key[i] >> 1);
  }
  RoundKeys[7] = ((Key[0] << 15) & 0x8000) ^ (Key[3] >> 1);
  RoundKeys[4] = RoundKeys[4] ^ ((Key[3] >> 15) & 0x0001);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<earlyAbortHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: </BODY></HTML>

assistant: ```c
void earlyAbortHandler() {
  printf("</BODY></HTML>");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<earlyAbortHandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: </BODY></HTML>

assistant: ```c
void earlyAbortHandler() {
  printf("</BODY></HTML>");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<earlyAbortHandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: </BODY></HTML>

assistant: ```c
void earlyAbortHandler() {
  printf("</BODY></HTML>");
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<earlyAbortHandler>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: </BODY></HTML>

assistant: ```c
void earlyAbortHandler() {
  printf("</BODY></HTML>");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L41
L42:
  mov    $0x0,%eax
  call   <rand_float@plt>
  movss  D32(%rip),%xmm1
  mulss  %xmm1,%xmm0
  movss  D36(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <rampf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0x1c(%rbp),%xmm0
  jnp    L43
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L4
L43:
  addl   $0x1,-0x18(%rbp)
L41:
  cmpl   $0xf423f,-0x18(%rbp)
  jle    L42
L4:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0x1c(%rbp),%xmm0
  jnp    L7
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D32
data_type: byte[4]
name: parse_data
arguments: tag: D36
data_type: byte[4]
name: parse_data
arguments: tag: D4
data_type: string

tool: {"D32": [0x00,0x00,0xc8,0x42]}

tool: {"D36": [0x00,0x00,0x48,0x42]}

tool: D4: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  float x;
  float y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (100.0f * rand_float()) - 50.0f;
    y = rampf(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```