ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rastafont8x8_blit8>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  mov    $0x1f,%ecx
  push   %r12
  sub    %r13d,%ecx
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  shl    %cl,%edx
  push   %rbx
  mov    %rdi,%rbx
  sar    $0x1f,%edx
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <rastafont8x8_select@plt>
  mov    $0x1e,%ecx
  mov    %ebp,%edx
  mov    0x4(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1d,%ecx
  mov    %ebp,%edx
  mov    0x8(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x4(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1c,%ecx
  mov    %ebp,%edx
  mov    0xc(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x8(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1b,%ecx
  mov    %ebp,%edx
  mov    0x10(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0xc(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x1a,%ecx
  mov    %ebp,%edx
  mov    0x14(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x10(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x19,%ecx
  mov    %ebp,%edx
  mov    0x18(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x14(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    $0x18,%ecx
  mov    %ebp,%edx
  mov    0x1c(%rbx),%edi
  sub    %r13d,%ecx
  mov    %eax,0x18(%rbx)
  mov    %r12d,%esi
  shl    %cl,%edx
  sar    $0x1f,%edx
  call   <rastafont8x8_select@plt>
  mov    %eax,0x1c(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((always_)) void rastafont8x8_blit8(unsigned *output, unsigned colour, unsigned m, unsigned b) {
  output[0] = rastafont8x8_select(output[0], colour, (int)(m << (31 - b)) >> 31);
  output[1] = rastafont8x8_select(output[1], colour, (int)(m << (30 - b)) >> 31);
  output[2] = rastafont8x8_select(output[2], colour, (int)(m << (29 - b)) >> 31);
  output[3] = rastafont8x8_select(output[3], colour, (int)(m << (28 - b)) >> 31);
  output[4] = rastafont8x8_select(output[4], colour, (int)(m << (27 - b)) >> 31);
  output[5] = rastafont8x8_select(output[5], colour, (int)(m << (26 - b)) >> 31);
  output[6] = rastafont8x8_select(output[6], colour, (int)(m << (25 - b)) >> 31);
  output[7] = rastafont8x8_select(output[7], colour, (int)(m << (24 - b)) >> 31);
}
```
user: What is the c source code of the assembly code below:

```asm
<strhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x811c9dc5,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L13:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    -0x4(%rbp),%eax
  imul   $0x1000193,%eax,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int strhash(const char *str, unsigned int sz) {
  unsigned int i, hash = 2166136261U;
  for (i = 0; i < sz; i++) {
    hash = (hash ^ str[i]) * 0x01000193;
  }
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strhash>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x811c9dc5,%eax
L11:
  movsbl (%rdx),%ecx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L11
  ret
L6:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned int strhash(const char *str, unsigned int sz) {
  unsigned int i, hash = 2166136261U;
  for (i = 0; i < sz; i++) {
    hash = (hash ^ str[i]) * 0x01000193;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<strhash>:
  endbr64
  test   %esi,%esi
  je     L9
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  mov    $0x811c9dc5,%eax
  nopl   (%rax)
L15:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rcx,%rdi
  jne    L15
  ret
  nopl   (%rax)
L9:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned int strhash(const char *str, unsigned int sz) {
  unsigned int i, hash = 2166136261U;
  for (i = 0; i < sz; i++) {
    hash = (hash ^ str[i]) * 0x01000193;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strhash>:
  endbr64
  test   %esi,%esi
  je     L16
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  mov    $0x811c9dc5,%eax
  nopl   (%rax)
L5:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  xor    %edx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rdi,%rcx
  jne    L5
  ret
  nopl   (%rax)
L16:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned int strhash(const char *str, unsigned int sz) {
  unsigned int i, hash = 2166136261U;
  for (i = 0; i < sz; i++) {
    hash = (hash ^ str[i]) * 0x01000193;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scl_shift_left_by>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L50
L51:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  test   %eax,%eax
  js     L48
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L55
L48:
  mov    $0x0,%eax
L55:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L50:
  cmpl   $0x0,-0xc(%rbp)
  jns    L51
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    $0x20,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  or     %esi,%edx
  mov    %edx,(%rax)
  subl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x0,-0xc(%rbp)
  jg     L38
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scl_shift_left_by(uint32_t v[], const uint32_t x[], int sz, int s) {
  int w = s / 32;
  int b = s % 32;
  int i;
  ;
  v[sz - 1] = 0u;
  for (i = sz - 2; i >= 0; i--) {
    v[i] = ((i - w) >= 0) ? x[i - w] : 0u;
  }
  for (i = sz - 1; i > 0; i--) {
    v[i] = (v[i] << b) | (v[i - 1] >> (32 - b));
  }
  v[0] = (v[0] << b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scl_shift_left_by>:
  endbr64
  mov    %edx,%r8d
  mov    %ecx,%r10d
  lea    0x1f(%rcx),%ecx
  test   %r10d,%r10d
  cmovns %r10d,%ecx
  sar    $0x5,%ecx
  mov    %r10d,%eax
  sar    $0x1f,%eax
  shr    $0x1b,%eax
  lea    (%r10,%rax,1),%r11d
  and    $0x1f,%r11d
  sub    %eax,%r11d
  movslq %edx,%rax
  movl   $0x0,-0x4(%rdi,%rax,4)
  sub    $0x2,%edx
  js     L40
  movslq %edx,%rax
  sub    %ecx,%edx
  movslq %ecx,%rcx
  neg    %rcx
  lea    (%rsi,%rcx,4),%r9
  mov    $0x0,%ecx
  jmp    L9
L58:
  mov    (%r9,%rax,4),%esi
L46:
  mov    %esi,(%rdi,%rax,4)
  sub    $0x1,%rax
  sub    $0x1,%edx
  test   %eax,%eax
  js     L40
L9:
  mov    %ecx,%esi
  test   %edx,%edx
  jns    L58
  jmp    L46
L40:
  lea    -0x1(%r8),%eax
  test   %eax,%eax
  jle    L26
  push   %rbx
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    -0x4(%rdi,%rdx,1),%r9
  lea    -0x2(%r8),%edx
  shl    $0x2,%rdx
  sub    %rdx,%r9
  mov    %r10d,%ebx
  and    $0x1f,%ebx
  mov    $0x20,%r8d
  sub    %r11d,%r8d
L5:
  mov    (%rax),%edx
  mov    %ebx,%ecx
  shl    %cl,%edx
  mov    -0x4(%rax),%esi
  mov    %r8d,%ecx
  shr    %cl,%esi
  or     %esi,%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %r9,%rax
  jne    L5
  mov    %r10d,%ecx
  shll   %cl,(%rdi)
  pop    %rbx
  ret
L26:
  mov    %r10d,%ecx
  shll   %cl,(%rdi)
  ret
```

assistant: ```c
void scl_shift_left_by(uint32_t v[], const uint32_t x[], int sz, int s) {
  int w = s / 32;
  int b = s % 32;
  int i;
  ;
  v[sz - 1] = 0u;
  for (i = sz - 2; i >= 0; i--) {
    v[i] = ((i - w) >= 0) ? x[i - w] : 0u;
  }
  for (i = sz - 1; i > 0; i--) {
    v[i] = (v[i] << b) | (v[i - 1] >> (32 - b));
  }
  v[0] = (v[0] << b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scl_shift_left_by>:
  endbr64
  mov    %rdi,%r8
  mov    %ecx,%edi
  add    $0x1f,%ecx
  push   %rbx
  test   %edi,%edi
  mov    %edi,%eax
  mov    %edx,%r10d
  mov    %edx,%r9d
  cmovns %edi,%ecx
  sar    $0x1f,%eax
  shr    $0x1b,%eax
  lea    (%rdi,%rax,1),%ebx
  sar    $0x5,%ecx
  and    $0x1f,%ebx
  sub    %eax,%ebx
  movslq %edx,%rax
  movl   $0x0,-0x4(%r8,%rax,4)
  sub    $0x2,%r10d
  js     L1
  mov    %r10d,%edx
  movslq %r10d,%rax
  sub    %ecx,%edx
  movslq %ecx,%rcx
  neg    %rcx
  lea    (%rsi,%rcx,4),%rcx
  nop
L13:
  xor    %esi,%esi
  test   %edx,%edx
  js     L0
  mov    (%rcx,%rax,4),%esi
L0:
  mov    %esi,(%r8,%rax,4)
  sub    $0x1,%rax
  sub    $0x1,%edx
  test   %eax,%eax
  jns    L13
L1:
  sub    $0x1,%r9d
  and    $0x1f,%edi
  test   %r9d,%r9d
  jle    L24
  movslq %r9d,%r9
  mov    %r10d,%r10d
  mov    $0x20,%r11d
  shl    $0x2,%r9
  shl    $0x2,%r10
  sub    %ebx,%r11d
  lea    (%r8,%r9,1),%rax
  lea    -0x4(%r8,%r9,1),%r9
  sub    %r10,%r9
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rax),%edx
  mov    -0x4(%rax),%esi
  mov    %edi,%ecx
  sub    $0x4,%rax
  shl    %cl,%edx
  mov    %r11d,%ecx
  shr    %cl,%esi
  or     %esi,%edx
  mov    %edx,0x4(%rax)
  cmp    %rax,%r9
  jne    L26
L24:
  mov    %edi,%ecx
  pop    %rbx
  shll   %cl,(%r8)
  ret
```

assistant: ```c
void scl_shift_left_by(uint32_t v[], const uint32_t x[], int sz, int s) {
  int w = s / 32;
  int b = s % 32;
  int i;
  ;
  v[sz - 1] = 0u;
  for (i = sz - 2; i >= 0; i--) {
    v[i] = ((i - w) >= 0) ? x[i - w] : 0u;
  }
  for (i = sz - 1; i > 0; i--) {
    v[i] = (v[i] << b) | (v[i - 1] >> (32 - b));
  }
  v[0] = (v[0] << b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scl_shift_left_by>:
  endbr64
  mov    %rsi,%r9
  mov    %ecx,%esi
  add    $0x1f,%ecx
  movslq %edx,%r11
  test   %esi,%esi
  mov    %esi,%eax
  mov    %r11,%r10
  push   %rbp
  cmovns %esi,%ecx
  sar    $0x1f,%eax
  push   %rbx
  mov    %r10d,%ebx
  shr    $0x1b,%eax
  lea    (%rsi,%rax,1),%r8d
  shl    $0x2,%r11
  sar    $0x5,%ecx
  movl   $0x0,-0x4(%rdi,%r11,1)
  and    $0x1f,%r8d
  sub    %eax,%r8d
  sub    $0x2,%ebx
  js     L31
  mov    %ebx,%edx
  movslq %ebx,%rax
  sub    %ecx,%edx
  movslq %ecx,%rcx
  neg    %rcx
  lea    (%r9,%rcx,4),%r9
  nopl   (%rax)
L48:
  test   %edx,%edx
  js     L78
  mov    (%r9,%rax,4),%ecx
  sub    $0x1,%edx
  mov    %ecx,(%rdi,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L48
L31:
  lea    -0x1(%r10),%eax
  and    $0x1f,%esi
  test   %eax,%eax
  jle    L30
  mov    $0x20,%ecx
  mov    %eax,%ebp
  sub    %r8d,%ecx
  cmp    $0x2,%ebx
  jbe    L54
  mov    %eax,%r8d
  lea    -0x10(%rdi,%r11,1),%r9
  lea    -0x14(%rdi,%r11,1),%rbx
  xor    %edx,%edx
  shr    $0x2,%r8d
  movd   %esi,%xmm3
  movd   %ecx,%xmm2
  neg    %r8
  shl    $0x4,%r8
  cs nopw 0x0(%rax,%rax,1)
L105:
  movdqu (%r9,%rdx,1),%xmm4
  movdqu (%rbx,%rdx,1),%xmm5
  pshufd $0x1b,%xmm4,%xmm0
  pshufd $0x1b,%xmm5,%xmm1
  pslld  %xmm3,%xmm0
  psrld  %xmm2,%xmm1
  por    %xmm1,%xmm0
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm0,(%r9,%rdx,1)
  sub    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L105
  mov    %eax,%edx
  and    $0xfffffffc,%edx
  sub    %edx,%eax
  cmp    %ebp,%edx
  je     L30
L38:
  sub    %edx,%r10d
  lea    -0x1(%r10),%r8d
  cmp    $0x2,%r10d
  je     L17
  neg    %rdx
  movd   %esi,%xmm2
  lea    (%r11,%rdx,4),%r9
  lea    -0x8(%rdi,%r9,1),%rdx
  movq   -0xc(%rdi,%r9,1),%xmm1
  movq   (%rdx),%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pslld  %xmm2,%xmm0
  movd   %ecx,%xmm2
  psrld  %xmm2,%xmm1
  por    %xmm1,%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rdx)
  mov    %r8d,%edx
  and    $0xfffffffe,%edx
  sub    %edx,%eax
  cmp    %edx,%r8d
  je     L30
L17:
  cltq
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  mov    -0x4(%rdi,%rax,1),%eax
  mov    (%r8),%edx
  shr    %cl,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
  mov    %eax,(%r8)
L30:
  mov    %esi,%ecx
  pop    %rbx
  pop    %rbp
  shll   %cl,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L78:
  movl   $0x0,(%rdi,%rax,4)
  sub    $0x1,%rax
  sub    $0x1,%edx
  test   %eax,%eax
  jns    L48
  jmp    L31
L54:
  xor    %edx,%edx
  jmp    L38
```

assistant: ```c
void scl_shift_left_by(uint32_t v[], const uint32_t x[], int sz, int s) {
  int w = s / 32;
  int b = s % 32;
  int i;
  ;
  v[sz - 1] = 0u;
  for (i = sz - 2; i >= 0; i--) {
    v[i] = ((i - w) >= 0) ? x[i - w] : 0u;
  }
  for (i = sz - 1; i > 0; i--) {
    v[i] = (v[i] << b) | (v[i - 1] >> (32 - b));
  }
  v[0] = (v[0] << b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: This is main!


assistant: ```c
int main() {
  printf("This is main!\n");
  bar();
  foo();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: This is main!


assistant: ```c
int main() {
  printf("This is main!\n");
  bar();
  foo();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: This is main!


assistant: ```c
int main() {
  printf("This is main!\n");
  bar();
  foo();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: This is main!


assistant: ```c
int main() {
  printf("This is main!\n");
  bar();
  foo();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L4
  cmpl   $0x0,-0x1c(%rbp)
  js     L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x20(%rbp)
  jge    L4
  jmp    L56
L26:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L26
  jmp    L0
L4:
  nop
L0:
  leave
  ret
```

assistant: ```c
void reverse_str(char *strInput, int nStart, int nEnd) {
  if (nStart >= nEnd || nStart < 0 || nEnd >= strlen(strInput)) {
    return;
  }
  while (nStart < nEnd) {
    char cTemp = strInput[nStart];
    strInput[nStart] = strInput[nEnd];
    strInput[nEnd] = cTemp;
    nStart++;
    nEnd--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse_str>:
  endbr64
  cmp    %edx,%esi
  jge    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  test   %esi,%esi
  js     L10
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L10
  movslq %ebx,%rsi
  movslq %ebp,%rdx
L27:
  movzbl (%r12,%rsi,1),%eax
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%r12,%rsi,1)
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %edx,%esi
  jl     L27
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void reverse_str(char *strInput, int nStart, int nEnd) {
  if (nStart >= nEnd || nStart < 0 || nEnd >= strlen(strInput)) {
    return;
  }
  while (nStart < nEnd) {
    char cTemp = strInput[nStart];
    strInput[nStart] = strInput[nEnd];
    strInput[nEnd] = cTemp;
    nStart++;
    nEnd--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse_str>:
  endbr64
  cmp    %edx,%esi
  jge    L20
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  js     L31
  mov    %edx,%ebp
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L31
  movslq %ebx,%rsi
  movslq %ebp,%rdx
  cs nopw 0x0(%rax,%rax,1)
L29:
  movzbl (%r12,%rsi,1),%eax
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%r12,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%r12,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L29
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
void reverse_str(char *strInput, int nStart, int nEnd) {
  if (nStart >= nEnd || nStart < 0 || nEnd >= strlen(strInput)) {
    return;
  }
  while (nStart < nEnd) {
    char cTemp = strInput[nStart];
    strInput[nStart] = strInput[nEnd];
    strInput[nEnd] = cTemp;
    nStart++;
    nEnd--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse_str>:
  endbr64
  cmp    %edx,%esi
  jge    L8
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  js     L28
  mov    %edx,%ebp
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L28
  movslq %ebx,%rsi
  movslq %ebp,%rdx
  cs nopw 0x0(%rax,%rax,1)
L36:
  movzbl (%r12,%rsi,1),%eax
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%r12,%rsi,1)
  add    $0x1,%rsi
  mov    %al,(%r12,%rdx,1)
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jg     L36
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void reverse_str(char *strInput, int nStart, int nEnd) {
  if (nStart >= nEnd || nStart < 0 || nEnd >= strlen(strInput)) {
    return;
  }
  while (nStart < nEnd) {
    char cTemp = strInput[nStart];
    strInput[nStart] = strInput[nEnd];
    strInput[nEnd] = cTemp;
    nStart++;
    nEnd--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_mesa_reference_pipeline_object>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  je     L1
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_mesa_reference_pipeline_object_@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void _mesa_reference_pipeline_object(struct gl_context *ctx, struct gl_pipeline_object **ptr, struct gl_pipeline_object *obj) {
  if (*ptr != obj)
    _mesa_reference_pipeline_object_(ctx, ptr, obj);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_mesa_reference_pipeline_object>:
  endbr64
  cmp    %rdx,(%rsi)
  je     L4
  sub    $0x8,%rsp
  call   <_mesa_reference_pipeline_object_@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void _mesa_reference_pipeline_object(struct gl_context *ctx, struct gl_pipeline_object **ptr, struct gl_pipeline_object *obj) {
  if (*ptr != obj)
    _mesa_reference_pipeline_object_(ctx, ptr, obj);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mesa_reference_pipeline_object>:
  endbr64
  cmp    %rdx,(%rsi)
  je     L6
  jmp    1050 <_mesa_reference_pipeline_object_@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void _mesa_reference_pipeline_object(struct gl_context *ctx, struct gl_pipeline_object **ptr, struct gl_pipeline_object *obj) {
  if (*ptr != obj)
    _mesa_reference_pipeline_object_(ctx, ptr, obj);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_mesa_reference_pipeline_object>:
  endbr64
  cmp    %rdx,(%rsi)
  je     L8
  jmp    1050 <_mesa_reference_pipeline_object_@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void _mesa_reference_pipeline_object(struct gl_context *ctx, struct gl_pipeline_object **ptr, struct gl_pipeline_object *obj) {
  if (*ptr != obj)
    _mesa_reference_pipeline_object_(ctx, ptr, obj);
}
```