ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<___func_in_stat>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rax
  cmp    $0x7f,%ecx
  jle    L5
  cmpb   $0x0,(%rsi)
  jne    L37
L48:
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <____func_in_stat@plt>
  jmp    L21
L5:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L48
  movslq %ecx,%r8
  mov    %dl,(%rax,%r8,1)
  add    $0x1,%ecx
  add    $0x1,%rsi
  mov    %rax,%rdx
  call   <___func_in_stat>
L21:
  add    $0x8,%rsp
  ret
L37:
  mov    $0x0,%eax
  jmp    L21
```

assistant: ```c
int *___func_in_stat(struct struct_automata *p, char *s, char buf[], int i) {
  if (i >= 128 && *s != '\0')
    return NULL;
  if (*s == '\0') {
    buf[i] = '\0';
    return ____func_in_stat(p, buf, 0);
  }
  buf[i] = *s;
  return ___func_in_stat(p, s + 1, buf, i + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<___func_in_stat>:
  endbr64
  mov    %rsi,%r8
  movslq %ecx,%rcx
  mov    %rdx,%rsi
  mov    %r8,%rdx
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl (%rdx,%rcx,1),%eax
  movslq %ecx,%r8
  cmp    $0x7f,%ecx
  jle    L18
  test   %al,%al
  jne    L5
L33:
  movb   $0x0,(%rsi,%r8,1)
  xor    %edx,%edx
  jmp    1050 <____func_in_stat@plt>
  nopl   0x0(%rax)
L18:
  test   %al,%al
  je     L33
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  jmp    L22
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *___func_in_stat(struct struct_automata *p, char *s, char buf[], int i) {
  if (i >= 128 && *s != '\0')
    return NULL;
  if (*s == '\0') {
    buf[i] = '\0';
    return ____func_in_stat(p, buf, 0);
  }
  buf[i] = *s;
  return ___func_in_stat(p, s + 1, buf, i + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<___func_in_stat>:
  endbr64
  mov    %rsi,%r8
  movslq %ecx,%rcx
  mov    %rdx,%rsi
  mov    %r8,%rdx
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rdx,%rcx,1),%eax
  movslq %ecx,%r8
  cmp    $0x7f,%ecx
  jle    L37
  test   %al,%al
  jne    L31
L0:
  movb   $0x0,(%rsi,%r8,1)
  xor    %edx,%edx
  jmp    1050 <____func_in_stat@plt>
  nopl   0x0(%rax)
L37:
  test   %al,%al
  je     L0
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  jmp    L21
  nopl   (%rax)
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int *___func_in_stat(struct struct_automata *p, char *s, char buf[], int i) {
  if (i >= 128 && *s != '\0')
    return NULL;
  if (*s == '\0') {
    buf[i] = '\0';
    return ____func_in_stat(p, buf, 0);
  }
  buf[i] = *s;
  return ___func_in_stat(p, s + 1, buf, i + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init_app@plt>
L1:
  mov    $0x0,%eax
  call   <choose_mode@plt>
  jmp    L1
```

assistant: ```c
void main(void) {
  init_app();
  while (1) {
    choose_mode();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_app@plt>
L6:
  mov    $0x0,%eax
  call   <choose_mode@plt>
  jmp    L6
```

assistant: ```c
void main(void) {
  init_app();
  while (1) {
    choose_mode();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_app@plt>
  nop
L6:
  xor    %eax,%eax
  call   <choose_mode@plt>
  jmp    L6
```

assistant: ```c
void main(void) {
  init_app();
  while (1) {
    choose_mode();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_app@plt>
  nop
L2:
  xor    %eax,%eax
  call   <choose_mode@plt>
  jmp    L2
```

assistant: ```c
void main(void) {
  init_app();
  while (1) {
    choose_mode();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solveSudoku>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    $0x9,%edx
L24:
  lea    -0x9(%rdx),%rax
L33:
  movb   $0x0,0xc0(%rsp,%rax,1)
  movb   $0x0,0x60(%rsp,%rax,1)
  movb   $0x0,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L33
  add    $0x9,%rdx
  cmp    $0x5a,%rdx
  jne    L24
  mov    $0x0,%r10d
  mov    $0x0,%r8d
  jmp    L63
L72:
  add    $0x1,%r8d
L18:
  add    $0x1,%rcx
  cmp    $0x9,%rcx
  je     L45
L46:
  movzbl (%rsi,%rcx,1),%eax
  cmp    $0x2e,%al
  je     L72
  movsbl %al,%edx
  sub    $0x31,%edx
  movslq %edx,%rdx
  movslq %ecx,%rbx
  imul   $0x55555556,%rbx,%rax
  shr    $0x20,%rax
  mov    %ecx,%ebp
  sar    $0x1f,%ebp
  sub    %ebp,%eax
  add    %r11d,%eax
  cltq
  lea    (%rax,%rax,8),%rax
  lea    0x120(%rax),%rax
  add    %rsp,%rax
  movb   $0x1,-0x60(%rdx,%rax,1)
  lea    (%rbx,%rbx,8),%rax
  lea    0x120(%rax),%rax
  add    %rsp,%rax
  movb   $0x1,-0xc0(%rdx,%rax,1)
  movb   $0x1,-0x120(%rdx,%r9,1)
  jmp    L18
L45:
  add    $0x1,%r10
  cmp    $0x9,%r10
  je     L88
L63:
  movslq %r10d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r10d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r11d
  mov    (%rdi,%r10,8),%rsi
  mov    $0x0,%ecx
  movslq %r10d,%rax
  lea    (%rax,%rax,8),%r9
  lea    0x120(%r9),%rax
  lea    (%rsp,%rax,1),%r9
  jmp    L46
L88:
  lea    0xc0(%rsp),%rcx
  lea    0x60(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  call   <aux@plt>
  add    $0x10,%rsp
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void solveSudoku(char **board, int boardRowSize, int boardColSize) {
  char rows[9][9];
  char cols[9][9];
  char blks[9][9];
  int row, col, blk, nUnfilled;
  nUnfilled = 0;
  for (row = 0; row < 9; ++row) {
    for (col = 0; col < 9; ++col) {
      rows[row][col] = cols[row][col] = blks[row][col] = 0;
    }
  }
  for (row = 0; row < 9; ++row) {
    for (col = 0; col < 9; ++col) {
      blk = (row / 3) * 3 + col / 3;
      if (board[row][col] == '.') {
        nUnfilled++;
      } else {
        int i;
        i = board[row][col] - '1';
        rows[row][i] = cols[col][i] = blks[blk][i] = 1;
      }
    }
  }
  int ret;
  ret = aux(board, rows, cols, blks, nUnfilled, 0, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solveSudoku>:
  endbr64
  push   %r13
  mov    %rdi,%r10
  mov    $0xa,%ecx
  xor    %r13d,%r13d
  push   %r12
  xor    %r8d,%r8d
  push   %rbp
  mov    $0xaaaaaaab,%ebp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xc0(%rsp),%r11
  lea    0x60(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r11,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0xa,%ecx
  movb   $0x0,(%rdi)
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0xa,%ecx
  movb   $0x0,(%rdi)
  mov    %rsi,%rdi
  rep stos %rax,%es:(%rdi)
  movb   $0x0,(%rdi)
  nopl   0x0(%rax)
L24:
  mov    %r13d,%eax
  mov    (%r10,%r13,8),%r9
  xor    %edi,%edi
  imul   %rbp,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%r12d
  movslq %r13d,%rax
  lea    (%rax,%rax,8),%rbx
  lea    0x120(%rbx),%rax
  lea    (%rsp,%rax,1),%rbx
  jmp    L17
  nopl   0x0(%rax)
L26:
  mov    %edi,%ecx
  sub    $0x31,%eax
  imul   %rbp,%rcx
  cltq
  movb   $0x1,-0x120(%rax,%rbx,1)
  shr    $0x21,%rcx
  add    %r12d,%ecx
  movslq %ecx,%rcx
  lea    (%rcx,%rcx,8),%rcx
  add    $0x120,%rcx
  add    %rsp,%rcx
  movb   $0x1,-0x60(%rax,%rcx,1)
  movslq %edi,%rcx
  add    $0x1,%rdi
  lea    (%rcx,%rcx,8),%rcx
  add    $0x120,%rcx
  add    %rsp,%rcx
  movb   $0x1,-0xc0(%rax,%rcx,1)
  cmp    $0x9,%rdi
  je     L55
L17:
  movsbl (%r9,%rdi,1),%eax
  cmp    $0x2e,%al
  jne    L26
  add    $0x1,%rdi
  add    $0x1,%r8d
  cmp    $0x9,%rdi
  jne    L17
L55:
  add    $0x1,%r13
  cmp    $0x9,%r13
  jne    L24
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  mov    %r11,%rcx
  mov    %r10,%rdi
  push   $0x0
  call   <aux@plt>
  pop    %rax
  pop    %rdx
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void solveSudoku(char **board, int boardRowSize, int boardColSize) {
  char rows[9][9];
  char cols[9][9];
  char blks[9][9];
  int row, col, blk, nUnfilled;
  nUnfilled = 0;
  for (row = 0; row < 9; ++row) {
    for (col = 0; col < 9; ++col) {
      rows[row][col] = cols[row][col] = blks[row][col] = 0;
    }
  }
  for (row = 0; row < 9; ++row) {
    for (col = 0; col < 9; ++col) {
      blk = (row / 3) * 3 + col / 3;
      if (board[row][col] == '.') {
        nUnfilled++;
      } else {
        int i;
        i = board[row][col] - '1';
        rows[row][i] = cols[col][i] = blks[blk][i] = 1;
      }
    }
  }
  int ret;
  ret = aux(board, rows, cols, blks, nUnfilled, 0, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<raw_input_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <raw_input@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movss  -0xc(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float raw_input_float(char *input) {
  char *get_input = raw_input(input);
  float numero = atof(get_input);
  free(get_input);
  return numero;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<raw_input_float>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  call   <raw_input@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <atof@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %rbx,%rdi
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
float raw_input_float(char *input) {
  char *get_input = raw_input(input);
  float numero = atof(get_input);
  free(get_input);
  return numero;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<raw_input_float>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  call   <raw_input@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <atof@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
float raw_input_float(char *input) {
  char *get_input = raw_input(input);
  float numero = atof(get_input);
  free(get_input);
  return numero;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<raw_input_float>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  call   <raw_input@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <atof@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
float raw_input_float(char *input) {
  char *get_input = raw_input(input);
  float numero = atof(get_input);
  free(get_input);
  return numero;
}
```
user: Translate the below assembly code into C programming language:

```asm
<process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x10(%rax),%esi
  mov    -0x28(%rbp),%rax
  lea    0x80(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <safe_fread@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x4,%eax
  jmp    L81
L12:
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <put32@plt>
  movl   $0x0,-0xc(%rbp)
  movl   $0x10,-0x10(%rbp)
  jmp    L55
L94:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L94
  mov    -0x28(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <put32@plt>
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <safe_fwrite@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x4,%eax
  jmp    L81
L36:
  mov    -0x18(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <safe_fread@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L40
  mov    $0x4,%eax
  jmp    L81
L40:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <safe_fwrite@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x4,%eax
  jmp    L81
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L36
  mov    $0x0,%eax
L81:
  leave
  ret
```

assistant: ```c
int process(FILE *input, FILE *output, uint8_t *buf, unsigned bufsize) {
  size_t rd;
  unsigned i;
  uint32_t cksum;
  rd = safe_fread(buf + 16, bufsize - 16, input);
  if (!rd)
    return 4;
  put32(buf + 0, bufsize);
  cksum = 0;
  for (i = 16; i < bufsize; ++i)
    cksum += (uint32_t)buf[i];
  put32(buf + 8, cksum);
  if (!safe_fwrite(buf, bufsize, output))
    return 4;
  while (!feof(input)) {
    rd = safe_fread(buf, bufsize, input);
    if (!rd)
      return 4;
    if (!safe_fwrite(buf, rd, output))
      return 4;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<process>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  lea    0x80(%rdx),%rbx
  lea    -0x10(%rcx),%esi
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <safe_fread@plt>
  mov    %rax,%rdx
  mov    $0x4,%eax
  test   %rdx,%rdx
  je     L24
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <put32@plt>
  cmp    $0x10,%r13d
  jbe    L2
  mov    %rbx,%rax
  lea    -0x11(%r13),%edx
  lea    0x88(%rbp,%rdx,8),%rdx
  mov    $0x0,%esi
L0:
  add    (%rax),%esi
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L0
L86:
  lea    0x40(%rbp),%rdi
  call   <put32@plt>
  mov    %r13d,%esi
  mov    %r14,%rdx
  mov    %rbp,%rdi
  call   <safe_fwrite@plt>
  mov    %eax,%edx
  mov    $0x4,%eax
  test   %edx,%edx
  je     L24
L91:
  mov    %r12,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L33
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <safe_fread@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L65
  mov    %r14,%rdx
  mov    %rbp,%rdi
  call   <safe_fwrite@plt>
  test   %eax,%eax
  jne    L91
  mov    $0x4,%eax
  jmp    L24
L2:
  mov    $0x0,%esi
  jmp    L86
L33:
  mov    $0x0,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  mov    $0x4,%eax
  jmp    L24
```

assistant: ```c
int process(FILE *input, FILE *output, uint8_t *buf, unsigned bufsize) {
  size_t rd;
  unsigned i;
  uint32_t cksum;
  rd = safe_fread(buf + 16, bufsize - 16, input);
  if (!rd)
    return 4;
  put32(buf + 0, bufsize);
  cksum = 0;
  for (i = 16; i < bufsize; ++i)
    cksum += (uint32_t)buf[i];
  put32(buf + 8, cksum);
  if (!safe_fwrite(buf, bufsize, output))
    return 4;
  while (!feof(input)) {
    rd = safe_fread(buf, bufsize, input);
    if (!rd)
      return 4;
    if (!safe_fwrite(buf, rd, output))
      return 4;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<process>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  lea    -0x10(%rcx),%esi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    0x80(%rdx),%rbx
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <safe_fread@plt>
  test   %rax,%rax
  je     L39
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <put32@plt>
  cmp    $0x10,%r13d
  jbe    L49
  lea    -0x11(%r13),%edx
  mov    %rbx,%rax
  xor    %esi,%esi
  lea    0x88(%rbp,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L45:
  add    (%rax),%esi
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L45
L69:
  lea    0x40(%rbp),%rdi
  call   <put32@plt>
  mov    %r13d,%esi
  jmp    L56
  nopl   0x0(%rax)
L33:
  mov    %r12,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L10
  mov    %r13d,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <safe_fread@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L39
L56:
  mov    %r14,%rdx
  mov    %rbp,%rdi
  call   <safe_fwrite@plt>
  test   %eax,%eax
  jne    L33
L39:
  pop    %rbx
  mov    $0x4,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L10:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %esi,%esi
  jmp    L69
```

assistant: ```c
int process(FILE *input, FILE *output, uint8_t *buf, unsigned bufsize) {
  size_t rd;
  unsigned i;
  uint32_t cksum;
  rd = safe_fread(buf + 16, bufsize - 16, input);
  if (!rd)
    return 4;
  put32(buf + 0, bufsize);
  cksum = 0;
  for (i = 16; i < bufsize; ++i)
    cksum += (uint32_t)buf[i];
  put32(buf + 8, cksum);
  if (!safe_fwrite(buf, bufsize, output))
    return 4;
  while (!feof(input)) {
    rd = safe_fread(buf, bufsize, input);
    if (!rd)
      return 4;
    if (!safe_fwrite(buf, rd, output))
      return 4;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<process>:
  endbr64
  push   %r15
  lea    -0x10(%rcx),%r15d
  push   %r14
  lea    0x80(%rdx),%r14
  push   %r13
  mov    %rsi,%r13
  mov    %r15d,%esi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdi,%rdx
  mov    %r14,%rdi
  sub    $0x8,%rsp
  call   <safe_fread@plt>
  test   %rax,%rax
  je     L11
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <put32@plt>
  cmp    $0x10,%r12d
  jbe    L27
  lea    -0x11(%r12),%eax
  cmp    $0x2,%eax
  jbe    L91
  mov    %r15d,%edx
  mov    %r14,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x5,%rdx
  lea    0xa0(%rbx,%rdx,1),%rdx
  nop
L93:
  movdqu (%rax),%xmm1
  movdqu 0x10(%rax),%xmm2
  add    $0x20,%rax
  shufps $0x88,%xmm2,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L93
  movdqa %xmm0,%xmm1
  mov    %r15d,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  lea    0x10(%rdx),%eax
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  cmp    %edx,%r15d
  je     L38
L22:
  mov    %eax,%edx
  add    (%rbx,%rdx,8),%esi
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jbe    L38
  add    $0x2,%eax
  add    (%rbx,%rdx,8),%esi
  cmp    %eax,%r12d
  jbe    L38
  add    (%rbx,%rax,8),%esi
L38:
  lea    0x40(%rbx),%rdi
  call   <put32@plt>
  mov    %r12d,%esi
  jmp    L76
  nop
L47:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L110
  mov    %r12d,%esi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <safe_fread@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L11
L76:
  mov    %r13,%rdx
  mov    %rbx,%rdi
  call   <safe_fwrite@plt>
  test   %eax,%eax
  jne    L47
L11:
  add    $0x8,%rsp
  mov    $0x4,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L110:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L27:
  xor    %esi,%esi
  jmp    L38
L91:
  xor    %esi,%esi
  mov    $0x10,%eax
  jmp    L22
```

assistant: ```c
int process(FILE *input, FILE *output, uint8_t *buf, unsigned bufsize) {
  size_t rd;
  unsigned i;
  uint32_t cksum;
  rd = safe_fread(buf + 16, bufsize - 16, input);
  if (!rd)
    return 4;
  put32(buf + 0, bufsize);
  cksum = 0;
  for (i = 16; i < bufsize; ++i)
    cksum += (uint32_t)buf[i];
  put32(buf + 8, cksum);
  if (!safe_fwrite(buf, bufsize, output))
    return 4;
  while (!feof(input)) {
    rd = safe_fread(buf, bufsize, input);
    if (!rd)
      return 4;
    if (!safe_fwrite(buf, rd, output))
      return 4;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<firstblank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    -0x10(%rbp),%rbx
  jmp    L34
L39:
  add    $0x1,%rbx
L34:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L36
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L36
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  jne    L39
L36:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *firstblank(char *str) {
  register char *ptr;
  for (ptr = str; *ptr && *ptr != ' ' && *ptr != '\t'; ptr++)
    ;
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<firstblank>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   $0xdf,%dl
  je     L35
  cmp    $0x9,%dl
  je     L35
L5:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   $0xdf,%dl
  je     L35
  cmp    $0x9,%dl
  jne    L5
L35:
  ret
```

assistant: ```c
char *firstblank(char *str) {
  register char *ptr;
  for (ptr = str; *ptr && *ptr != ' ' && *ptr != '\t'; ptr++)
    ;
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<firstblank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   $0xdf,%dl
  jne    L28
  jmp    L26
  nopl   0x0(%rax)
L15:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  je     L26
L28:
  cmp    $0x9,%dl
  jne    L15
L26:
  ret
```

assistant: ```c
char *firstblank(char *str) {
  register char *ptr;
  for (ptr = str; *ptr && *ptr != ' ' && *ptr != '\t'; ptr++)
    ;
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<firstblank>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   $0xdf,%dl
  jne    L5
  jmp    L27
  nopl   0x0(%rax)
L36:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  je     L27
L5:
  cmp    $0x9,%dl
  jne    L36
L27:
  ret
```

assistant: ```c
char *firstblank(char *str) {
  register char *ptr;
  for (ptr = str; *ptr && *ptr != ' ' && *ptr != '\t'; ptr++)
    ;
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findfirstline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  je     L41
  mov    $0xffffffff,%eax
  jmp    L0
L41:
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edi
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <__findline@plt>
  mov    %eax,-0x10(%rbp)
  jmp    L27
L10:
  mov    -0x28(%rbp),%edi
  mov    -0x10(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <__findline@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L18
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L27:
  cmpl   $0x0,-0x10(%rbp)
  jg     L10
  jmp    L68
L18:
  nop
L68:
  mov    -0x10(%rbp),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
ssize_t findfirstline(int fd, int (*comp)(const char *, void *), void *param, int maxlen) {
  struct stat state;
  ssize_t pos;
  if (fstat(fd, &state))
    return -1;
  ssize_t init_pos = __findline(fd, comp, param, 0, state.st_size, maxlen);
  while (init_pos > 0) {
    pos = __findline(fd, comp, param, 0, init_pos, maxlen);
    if (pos == -1)
      break;
    init_pos = pos;
  }
  return init_pos;
}
```