ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L17
  mov    (%rsp),%esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L17:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D32
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D35
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string

tool: D32: Enter two numbers: 

tool: D17: %i%i

tool: D35: %i / %i = %.3f


tool: D39: Division by zero.

assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value2)
    printf("%i / %i = %.3f\n", value1, value2, (float)value1 / value2);
  else
    printf("Division by zero.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L24
  mov    (%rsp),%esi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %edx,%xmm1
  lea    D20(%rip),%rdi
  cvtsi2ss %esi,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L24:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string

tool: D38: Enter two numbers: 

tool: D4: %i%i

tool: D20: %i / %i = %.3f


tool: D28: Division by zero.

assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value2)
    printf("%i / %i = %.3f\n", value1, value2, (float)value1 / value2);
  else
    printf("Division by zero.\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L28
  mov    (%rsp),%esi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %edx,%xmm1
  lea    D0(%rip),%rdi
  cvtsi2ss %esi,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L28:
  lea    D34(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D31
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D34
type_guessed: string

tool: D28: Enter two numbers: 

tool: D31: %i%i

tool: D0: %i / %i = %.3f


tool: D34: Division by zero.

assistant: ```c
int main(void) {
  int value1, value2;
  printf("Enter two numbers: ");
  scanf("%i%i", &value1, &value2);
  if (value2)
    printf("%i / %i = %.3f\n", value1, value2, (float)value1 / value2);
  else
    printf("Division by zero.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jne    L1
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <bench_snprintf@plt>
  neg    %eax
  jmp    L2
L1:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x7,%eax
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: USAGE : bench_snprintf type count


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1 + 2) {
    return -bench_snprintf(atoi(argv[1]), atol(argv[2]));
  } else {
    printf("USAGE : bench_snprintf type count\n");
    return 7;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L16
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%ebp
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <bench_snprintf@plt>
  neg    %eax
  jmp    L5
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: USAGE : bench_snprintf type count


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1 + 2) {
    return -bench_snprintf(atoi(argv[1]), atol(argv[2]));
  } else {
    printf("USAGE : bench_snprintf type count\n");
    return 7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L12
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atol@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <bench_snprintf@plt>
  neg    %eax
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: USAGE : bench_snprintf type count


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1 + 2) {
    return -bench_snprintf(atoi(argv[1]), atol(argv[2]));
  } else {
    printf("USAGE : bench_snprintf type count\n");
    return 7;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L5
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atol@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <bench_snprintf@plt>
  neg    %eax
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: USAGE : bench_snprintf type count


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc == 1 + 2) {
    return -bench_snprintf(atoi(argv[1]), atol(argv[2]));
  } else {
    printf("USAGE : bench_snprintf type count\n");
    return 7;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movzwl -0x1c(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzwl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_u16(void *vd, unsigned short int v) {
  unsigned char *d = (unsigned char *)vd;
  d[0] = v >> 8;
  d[1] = v >> 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_u16>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rdi)
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
void set_u16(void *vd, unsigned short int v) {
  unsigned char *d = (unsigned char *)vd;
  d[0] = v >> 8;
  d[1] = v >> 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_u16>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void set_u16(void *vd, unsigned short int v) {
  unsigned char *d = (unsigned char *)vd;
  d[0] = v >> 8;
  d[1] = v >> 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_u16>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void set_u16(void *vd, unsigned short int v) {
  unsigned char *d = (unsigned char *)vd;
  d[0] = v >> 8;
  d[1] = v >> 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <my_sqrt@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: f64

tool: D6: 19.5

assistant: ```c
int main(void) {
  my_sqrt(19.5);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D8(%rip),%xmm0
  call   <my_sqrt@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: f64

tool: D8: 19.5

assistant: ```c
int main(void) {
  my_sqrt(19.5);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D5(%rip),%xmm0
  call   <my_sqrt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: f64

tool: D5: 19.5

assistant: ```c
int main(void) {
  my_sqrt(19.5);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  call   <my_sqrt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: f64

tool: D9: 19.5

assistant: ```c
int main(void) {
  my_sqrt(19.5);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<gridprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L29:
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L10:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <fprintf@plt>
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string

tool: D19: w+

tool: D2: filedata.out

tool: D23: %f  

assistant: ```c
void gridprint(double **grid, int gridSize) {
  FILE *fp;
  fp = fopen("filedata.out", "w+");
  for (int i = 0; i < gridSize; i++) {
    for (int j = 0; j < gridSize; j++) {
      fprintf(fp, "%f  ", grid[i][j]);
    }
    fprintf(fp, "\n");
  }
  fclose(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gridprint>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  lea    D2(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L18
  mov    %r13,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r13,%rax,8),%r15
  mov    %ebx,%ebx
  lea    0x0(,%rbx,8),%r13
  lea    D22(%rip),%r14
L29:
  mov    $0x0,%ebx
L20:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <fprintf@plt>
  add    $0x8,%rbx
  cmp    %rbx,%r13
  jne    L20
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  jne    L29
L18:
  mov    %r12,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D14
type: string
name: parse_data
arguments: data_tag: D22
type: string

tool: D2: w+

tool: D14: filedata.out

tool: D22: %f  

assistant: ```c
void gridprint(double **grid, int gridSize) {
  FILE *fp;
  fp = fopen("filedata.out", "w+");
  for (int i = 0; i < gridSize; i++) {
    for (int j = 0; j < gridSize; j++) {
      fprintf(fp, "%f  ", grid[i][j]);
    }
    fprintf(fp, "\n");
  }
  fclose(fp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gridprint>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  lea    D2(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    D0(%rip),%rsi
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r15
  test   %ebx,%ebx
  jle    L0
  lea    -0x1(%rbx),%eax
  lea    0x0(,%rbx,8),%rbp
  lea    0x8(%r14,%rax,8),%r13
  lea    D10(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%r14),%rax
  mov    %r12,%rsi
  mov    %r15,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%rbp
  jne    L24
  mov    %r15,%rsi
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <fputc@plt>
  cmp    %r13,%r14
  jne    L17
L0:
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <fclose@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string

tool: D2: filedata.out

tool: D0: w+

tool: D10: %f  

assistant: ```c
void gridprint(double **grid, int gridSize) {
  FILE *fp;
  fp = fopen("filedata.out", "w+");
  for (int i = 0; i < gridSize; i++) {
    for (int j = 0; j < gridSize; j++) {
      fprintf(fp, "%f  ", grid[i][j]);
    }
    fprintf(fp, "\n");
  }
  fclose(fp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gridprint>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  lea    D1(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    D11(%rip),%rsi
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r15
  test   %ebx,%ebx
  jle    L1
  lea    -0x1(%rbx),%eax
  lea    0x0(,%rbx,8),%rbp
  lea    0x8(%r14,%rax,8),%r13
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%r14),%rax
  mov    %r12,%rsi
  mov    %r15,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <fprintf@plt>
  cmp    %rbx,%rbp
  jne    L10
  mov    %r15,%rsi
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <fputc@plt>
  cmp    %r13,%r14
  jne    L27
L1:
  add    $0x8,%rsp
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <fclose@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D11
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D1: filedata.out

tool: D11: w+

tool: D0: %f  

assistant: ```c
void gridprint(double **grid, int gridSize) {
  FILE *fp;
  fp = fopen("filedata.out", "w+");
  for (int i = 0; i < gridSize; i++) {
    for (int j = 0; j < gridSize; j++) {
      fprintf(fp, "%f  ", grid[i][j]);
    }
    fprintf(fp, "\n");
  }
  fclose(fp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%r13
  lea    D27(%rip),%r12
  lea    D11(%rip),%rbp
  lea    D44(%rip),%rbx
  jmp    L16
  mov    $0x0,%edi
  call   <add_ch@plt>
L27:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x5,%eax
  ja     L54
L16:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L54
  mov    0x4(%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <remove_ch@plt>
  jmp    L27
  mov    $0x0,%eax
  call   <display@plt>
  jmp    L27
  mov    $0x0,%eax
  call   <peek@plt>
  jmp    L27
  mov    $0x0,%eax
  call   <size@plt>
  jmp    L27
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D46
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D46: 
..IMPLEMENTING A QUEUE OF CHARS IN C..


tool: D3: ----------------------------------------



tool: D2: 1.To ADD a character:
2.To REMOVE a character:
3.To DISPLAY Queue:
4.PEEK of Queue:
5.SIZE of Queue:
6.EXIT: 

tool: D27: 
Enter a choice: 

tool: D11: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int option;
  char Mem[5];
  int front = -1;
  int rear = -1;
  char ch;
  char fro = Mem[front];
  int pek = rear + 1 - front;
  printf("\n..IMPLEMENTING A QUEUE OF CHARS IN C..\n");
  printf("----------------------------------------\n\n");
  do {
    printf("1.To ADD a character:\n2.To REMOVE a character:\n3.To DISPLAY Queue:\n4.PEEK of Queue:\n5.SIZE of Queue:\n6.EXIT: ");
    printf("\nEnter a choice: ");
    scanf("%d", &option);
    switch (option) {
    case 1:
      add_ch(ch);
      break;
    case 2:
      remove_ch();
      break;
    case 3:
      display();
      break;
    case 4:
      fro = peek();
      break;
    case 5:
      pek = size();
      break;
    case 6:
      return 0;
    default:
      return 0;
    }
  } while (option > 0 && option < 7);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  lea    D47(%rip),%r14
  push   %r13
  lea    D32(%rip),%r13
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D31(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
L22:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L0
  mov    0x4(%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <size@plt>
L4:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x5,%eax
  jbe    L22
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <peek@plt>
  jmp    L4
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <display@plt>
  jmp    L4
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <remove_ch@plt>
  jmp    L4
  nopl   0x0(%rax)
  xor    %edi,%edi
  call   <add_ch@plt>
  jmp    L4
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D47
data_type: string
name: disassemble_data
arguments: data_tag: D32
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D24
data_type: string

tool: D15: 
..IMPLEMENTING A QUEUE OF CHARS IN C..


tool: D47: 1.To ADD a character:
2.To REMOVE a character:
3.To DISPLAY Queue:
4.PEEK of Queue:
5.SIZE of Queue:
6.EXIT: 

tool: D32: 
Enter a choice: 

tool: D14: %d

tool: D24: ----------------------------------------



assistant: ```c
int main(int argc, char *argv[]) {
  int option;
  char Mem[5];
  int front = -1;
  int rear = -1;
  char ch;
  char fro = Mem[front];
  int pek = rear + 1 - front;
  printf("\n..IMPLEMENTING A QUEUE OF CHARS IN C..\n");
  printf("----------------------------------------\n\n");
  do {
    printf("1.To ADD a character:\n2.To REMOVE a character:\n3.To DISPLAY Queue:\n4.PEEK of Queue:\n5.SIZE of Queue:\n6.EXIT: ");
    printf("\nEnter a choice: ");
    scanf("%d", &option);
    switch (option) {
    case 1:
      add_ch(ch);
      break;
    case 2:
      remove_ch();
      break;
    case 3:
      display();
      break;
    case 4:
      fro = peek();
      break;
    case 5:
      pek = size();
      break;
    case 6:
      return 0;
    default:
      return 0;
    }
  } while (option > 0 && option < 7);
  return 0;
}
```