user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xffffff8affffff9e,%rax
  lea    0x10(%rsp),%rbp
  lea    0x30(%rsp),%rbx
  mov    %rax,0x10(%rsp)
  movabs $0xcffffffa5,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x23ffffffcf,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x5f0000001c,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xfffffff80000000c,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x1efffffff8,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x7ffffffca,%rax
  mov    %rax,0x40(%rsp)
  movabs $0xffffffd8ffffffad,%rax
  mov    %rax,0x48(%rsp)
  call   <puts@plt>
  mov    %rsp,%r8
  mov    %rbp,%rsi
  mov    $0xffffff9e,%edx
L35:
  xor    %eax,%eax
  mov    %edx,%ecx
  xor    %edi,%edi
  imul   (%rbx,%rax,8),%ecx
  add    $0x1,%rax
  add    %ecx,%edi
  cmp    $0x4,%rax
  je     L58
L104:
  mov    (%rsi,%rax,4),%ecx
  imul   (%rbx,%rax,8),%ecx
  add    $0x1,%rax
  add    %ecx,%edi
  cmp    $0x4,%rax
  jne    L104
L58:
  mov    %edi,(%r8)
  mov    $0xfffffff8,%edi
  xor    %eax,%eax
  xor    %ecx,%ecx
  imul   %edi,%edx
  add    $0x1,%rax
  add    %edx,%ecx
  cmp    $0x4,%rax
  je     L18
L31:
  mov    (%rsi,%rax,4),%edx
  mov    0x4(%rbx,%rax,8),%edi
  add    $0x1,%rax
  imul   %edi,%edx
  add    %edx,%ecx
  cmp    $0x4,%rax
  jne    L31
L18:
  add    $0x10,%rsi
  mov    %ecx,0x4(%r8)
  add    $0x8,%r8
  cmp    %rbx,%rsi
  je     L78
  mov    (%rsi),%edx
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L78:
  lea    D2(%rip),%rdi
  lea    0x10(%rbp),%r14
  mov    %rbp,%r13
  call   <puts@plt>
  lea    D48(%rip),%r12
L94:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %r13,%r14
  jne    L94
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xffffffcf,%esi
L51:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r14
  je     L38
  mov    0x10(%rbp),%esi
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xa,%edi
  lea    0x50(%rsp),%rbp
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
L55:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L55
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D48
type: string
name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D14
type: string

tool: D45: Calculando Matriz C:

tool: D2: MatrizA:

tool: D48: %d	

tool: D4: MatrizB:

tool: D14: MatrizC:

assistant: ```c
int main() {
  int matrizA[2][4] = {-98, -118, -91, 12, -49, 35, 28, 95};
  int matrizB[4][2] = {12, -8, -8, 30, -54, 7, -83, -40};
  int matrizC[2][2];
  int soma = 0;
  int linA, linB;
  int colB;
  printf("Calculando Matriz C:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++) {
      soma = 0;
      for (linB = 0; linB < 4; linB++)
        soma += matrizA[linA][linB] * matrizB[linB][colB];
      matrizC[linA][colB] = soma;
    }
  }
  printf("MatrizA:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 4; colB++)
      printf("%d\t", matrizA[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizB:\n");
  for (linA = 0; linA < 4; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizB[linA][colB]);
    printf("\n");
  }
  printf("\n");
  printf("MatrizC:\n");
  for (linA = 0; linA < 2; linA++) {
    for (colB = 0; colB < 2; colB++)
      printf("%d\t", matrizC[linA][colB]);
    printf("\n");
  }
  return 0;
}
```