ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<c_alloc5d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L39
L43:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x10(%rbp)
  jmp    L77
L58:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x14(%rbp)
  jmp    L50
L9:
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L14:
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L14
  addl   $0x1,-0x14(%rbp)
L50:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  addl   $0x1,-0x10(%rbp)
L77:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L58
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L43
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *****c_alloc5d(int dim1, int dim2, int dim3, int dim4, int dim5) {
  int i, k, j, l;
  double *****data;
  data = (double *****)malloc(dim1 * sizeof(double ****));
  for (i = 0; i < dim1; i++) {
    data[i] = (double ****)malloc(dim2 * sizeof(double ***));
    for (j = 0; j < dim2; j++) {
      data[i][j] = (double ***)malloc(dim3 * sizeof(double **));
      for (k = 0; k < dim3; k++) {
        data[i][j][k] = (double **)malloc(dim4 * sizeof(double *));
        for (l = 0; l < dim4; l++) {
          data[i][j][k][l] = (double *)malloc(dim5 * sizeof(double));
        }
      }
    }
  }
  return data;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<c_alloc5d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  mov    %esi,%r15d
  mov    %esi,0x3c(%rsp)
  mov    %edx,%ebp
  mov    %edx,0x1c(%rsp)
  mov    %ecx,%r13d
  mov    %ecx,0xc(%rsp)
  mov    %r8d,%r14d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x28(%rsp)
  test   %ebx,%ebx
  jle    L56
  lea    0x0(,%r15,8),%ecx
  mov    %ecx,0x38(%rsp)
  lea    0x0(,%rbp,8),%ecx
  mov    %ecx,0x18(%rsp)
  lea    0x0(,%r13,8),%edx
  mov    %edx,0x8(%rsp)
  shl    $0x3,%r14d
  mov    %rax,0x20(%rsp)
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%rax
  mov    %rax,0x30(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x8(,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x8(,%rax,8),%r15
L76:
  mov    0x38(%rsp),%edi
  call   <malloc@plt>
  mov    0x20(%rsp),%rcx
  mov    %rcx,%r13
  mov    %rax,(%rcx)
  cmpl   $0x0,0x3c(%rsp)
  jle    L75
  mov    $0x0,%r12d
L59:
  mov    0x18(%rsp),%edi
  call   <malloc@plt>
  mov    0x0(%r13),%rdx
  mov    %rax,(%rdx,%r12,1)
  cmpl   $0x0,0x1c(%rsp)
  jle    L67
  mov    $0x0,%ebp
L50:
  mov    0x8(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    0x0(%r13),%rax
  mov    (%rax,%r12,1),%rax
  mov    %rdx,(%rax,%rbp,1)
  cmpl   $0x0,0xc(%rsp)
  jle    L13
  mov    $0x0,%ebx
L34:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    0x0(%r13),%rax
  mov    (%rax,%r12,1),%rax
  mov    (%rax,%rbp,1),%rax
  mov    %rdx,(%rax,%rbx,1)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L34
L13:
  add    $0x8,%rbp
  cmp    %rbp,(%rsp)
  jne    L50
L67:
  add    $0x8,%r12
  cmp    0x10(%rsp),%r12
  jne    L59
L75:
  addq   $0x8,0x20(%rsp)
  mov    0x20(%rsp),%rax
  cmp    0x30(%rsp),%rax
  jne    L76
L56:
  mov    0x28(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double *****c_alloc5d(int dim1, int dim2, int dim3, int dim4, int dim5) {
  int i, k, j, l;
  double *****data;
  data = (double *****)malloc(dim1 * sizeof(double ****));
  for (i = 0; i < dim1; i++) {
    data[i] = (double ****)malloc(dim2 * sizeof(double ***));
    for (j = 0; j < dim2; j++) {
      data[i][j] = (double ***)malloc(dim3 * sizeof(double **));
      for (k = 0; k < dim3; k++) {
        data[i][j][k] = (double **)malloc(dim4 * sizeof(double *));
        for (l = 0; l < dim4; l++) {
          data[i][j][k][l] = (double *)malloc(dim5 * sizeof(double));
        }
      }
    }
  }
  return data;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<c_alloc5d>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x48,%rsp
  mov    %esi,0x3c(%rsp)
  mov    %edx,0x24(%rsp)
  mov    %ecx,0x14(%rsp)
  call   <malloc@plt>
  mov    %rax,0x30(%rsp)
  test   %ebx,%ebx
  jle    L51
  lea    0x0(,%r14,8),%ecx
  mov    %r14d,%esi
  mov    %rax,%r14
  shl    $0x3,%r12d
  lea    (%rax,%rbx,8),%rax
  mov    %ecx,0x38(%rsp)
  lea    0x0(,%rbp,8),%edi
  mov    %rax,0x28(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x0(,%r15,8),%ecx
  lea    0x8(,%rax,8),%rax
  mov    %ecx,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x8(,%rax,8),%rax
  mov    %edi,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%r13
L38:
  mov    0x38(%rsp),%edi
  call   <malloc@plt>
  mov    0x3c(%rsp),%ecx
  mov    %rax,(%r14)
  test   %ecx,%ecx
  jle    L57
  xor    %ebp,%ebp
L54:
  mov    0x20(%rsp),%edi
  call   <malloc@plt>
  mov    (%r14),%rdx
  mov    %rax,(%rdx,%rbp,1)
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jle    L71
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    0x10(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    (%r14),%rax
  mov    (%rax,%rbp,1),%rax
  mov    %r8,(%rax,%rbx,1)
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    (%r14),%rax
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r8,(%rax,%r15,1)
  add    $0x8,%r15
  cmp    %r15,%r13
  jne    L42
L27:
  add    $0x8,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L4
L71:
  add    $0x8,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L54
L57:
  add    $0x8,%r14
  cmp    0x28(%rsp),%r14
  jne    L38
L51:
  mov    0x30(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double *****c_alloc5d(int dim1, int dim2, int dim3, int dim4, int dim5) {
  int i, k, j, l;
  double *****data;
  data = (double *****)malloc(dim1 * sizeof(double ****));
  for (i = 0; i < dim1; i++) {
    data[i] = (double ****)malloc(dim2 * sizeof(double ***));
    for (j = 0; j < dim2; j++) {
      data[i][j] = (double ***)malloc(dim3 * sizeof(double **));
      for (k = 0; k < dim3; k++) {
        data[i][j][k] = (double **)malloc(dim4 * sizeof(double *));
        for (l = 0; l < dim4; l++) {
          data[i][j][k][l] = (double *)malloc(dim5 * sizeof(double));
        }
      }
    }
  }
  return data;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<c_alloc5d>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,8),%edi
  sub    $0x48,%rsp
  mov    %esi,0x3c(%rsp)
  mov    %edx,0x24(%rsp)
  mov    %ecx,0x14(%rsp)
  call   <malloc@plt>
  mov    %rax,0x30(%rsp)
  test   %ebx,%ebx
  jle    L48
  lea    0x0(,%r14,8),%ecx
  mov    %r14d,%esi
  mov    %rax,%r14
  shl    $0x3,%r12d
  lea    (%rax,%rbx,8),%rax
  mov    %ecx,0x38(%rsp)
  lea    0x0(,%rbp,8),%edi
  mov    %rax,0x28(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x0(,%r15,8),%ecx
  lea    0x8(,%rax,8),%rax
  mov    %ecx,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x8(,%rax,8),%rax
  mov    %edi,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x8(,%rax,8),%r13
L29:
  mov    0x38(%rsp),%edi
  call   <malloc@plt>
  mov    0x3c(%rsp),%ecx
  mov    %rax,(%r14)
  test   %ecx,%ecx
  jle    L64
  xor    %ebp,%ebp
L71:
  mov    0x20(%rsp),%edi
  call   <malloc@plt>
  mov    (%r14),%rdx
  mov    %rax,(%rdx,%rbp,1)
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  jle    L31
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x10(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    (%r14),%rax
  mov    (%rax,%rbp,1),%rax
  mov    %r8,(%rax,%rbx,1)
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L37
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    (%r14),%rax
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%rax
  mov    %r8,(%rax,%r15,1)
  add    $0x8,%r15
  cmp    %r15,%r13
  jne    L76
L37:
  add    $0x8,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L10
L31:
  add    $0x8,%rbp
  cmp    0x18(%rsp),%rbp
  jne    L71
L64:
  add    $0x8,%r14
  cmp    0x28(%rsp),%r14
  jne    L29
L48:
  mov    0x30(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double *****c_alloc5d(int dim1, int dim2, int dim3, int dim4, int dim5) {
  int i, k, j, l;
  double *****data;
  data = (double *****)malloc(dim1 * sizeof(double ****));
  for (i = 0; i < dim1; i++) {
    data[i] = (double ****)malloc(dim2 * sizeof(double ***));
    for (j = 0; j < dim2; j++) {
      data[i][j] = (double ***)malloc(dim3 * sizeof(double **));
      for (k = 0; k < dim3; k++) {
        data[i][j][k] = (double **)malloc(dim4 * sizeof(double *));
        for (l = 0; l < dim4; l++) {
          data[i][j][k][l] = (double *)malloc(dim5 * sizeof(double));
        }
      }
    }
  }
  return data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myPow1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L0
  movsd  D29(%rip),%xmm0
  jmp    L10
L0:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jns    L29
  movsd  D29(%rip),%xmm0
  divsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  negq   -0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movsd  D29(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L51:
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L39
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L39:
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  sarq   -0x10(%rbp)
L18:
  cmpq   $0x0,-0x10(%rbp)
  jg     L51
  movsd  -0x8(%rbp),%xmm0
L10:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: f64

tool: D29: 1

assistant: ```c
double myPow1(double x, int n) {
  if (n == 0)
    return 1;
  long n0 = n;
  if (n < 0) {
    x = 1 / x;
    n0 *= -1;
  }
  long b = n0;
  double res = 1;
  while (b > 0) {
    if (b & 1)
      res *= x;
    x *= x;
    b >>= 1;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myPow1>:
  endbr64
  test   %edi,%edi
  movsd  D5(%rip),%xmm1
  je     L45
  movslq %edi,%rax
  js     L73
L65:
  test   %rax,%rax
  jle    L14
  movsd  D5(%rip),%xmm1
  jmp    L50
L73:
  movsd  D5(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  neg    %rax
  jmp    L65
L51:
  mulsd  %xmm0,%xmm0
  sar    %rax
  test   %rax,%rax
  jle    L45
L50:
  test   $0x1,%al
  je     L51
  mulsd  %xmm0,%xmm1
  jmp    L51
L14:
  movsd  D5(%rip),%xmm1
L45:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: f64

tool: D5: 1

assistant: ```c
double myPow1(double x, int n) {
  if (n == 0)
    return 1;
  long n0 = n;
  if (n < 0) {
    x = 1 / x;
    n0 *= -1;
  }
  long b = n0;
  double res = 1;
  while (b > 0) {
    if (b & 1)
      res *= x;
    x *= x;
    b >>= 1;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myPow1>:
  endbr64
  movsd  D20(%rip),%xmm1
  test   %edi,%edi
  je     L36
  movslq %edi,%rdi
  js     L53
L52:
  mov    D20(%rip),%rax
  movq   %rax,%xmm1
  test   %rdi,%rdi
  jle    L36
  cs nopw 0x0(%rax,%rax,1)
L22:
  test   $0x1,%dil
  je     L56
  mulsd  %xmm0,%xmm1
L56:
  mulsd  %xmm0,%xmm0
  sar    %rdi
  jne    L22
L36:
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  movsd  D20(%rip),%xmm2
  neg    %rdi
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  jmp    L52
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
type: f64

tool: D20: 1

assistant: ```c
double myPow1(double x, int n) {
  if (n == 0)
    return 1;
  long n0 = n;
  if (n < 0) {
    x = 1 / x;
    n0 *= -1;
  }
  long b = n0;
  double res = 1;
  while (b > 0) {
    if (b & 1)
      res *= x;
    x *= x;
    b >>= 1;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<myPow1>:
  endbr64
  movsd  D5(%rip),%xmm1
  test   %edi,%edi
  je     L5
  movslq %edi,%rdi
  js     L45
L47:
  mov    D5(%rip),%rax
  movq   %rax,%xmm1
  test   %rdi,%rdi
  jle    L5
  cs nopw 0x0(%rax,%rax,1)
L38:
  test   $0x1,%dil
  je     L18
  mulsd  %xmm0,%xmm1
L18:
  mulsd  %xmm0,%xmm0
  sar    %rdi
  jne    L38
L5:
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  D5(%rip),%xmm2
  neg    %rdi
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  jmp    L47
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: f64

tool: D5: 1

assistant: ```c
double myPow1(double x, int n) {
  if (n == 0)
    return 1;
  long n0 = n;
  if (n < 0) {
    x = 1 / x;
    n0 *= -1;
  }
  long b = n0;
  double res = 1;
  while (b > 0) {
    if (b & 1)
      res *= x;
    x *= x;
    b >>= 1;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetColumnValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %edx,-0x834(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x810(%rbp),%rax
  mov    %rax,-0x818(%rbp)
  mov    -0x828(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  mov    $0x7ff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L39
L120:
  addq   $0x1,-0x818(%rbp)
L4:
  mov    -0x818(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L120
  jmp    L88
L66:
  mov    -0x818(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L108
  jmp    L118
L67:
  addq   $0x1,-0x818(%rbp)
L118:
  mov    -0x818(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L67
  subl   $0x1,-0x834(%rbp)
L108:
  addq   $0x1,-0x818(%rbp)
L88:
  mov    -0x818(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L123
  cmpl   $0x1,-0x834(%rbp)
  jne    L66
L123:
  cmpl   $0x1,-0x834(%rbp)
  jne    L0
  mov    -0x818(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x830(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
  jmp    L39
L0:
  mov    $0x0,%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L94
  call   <__stack_chk_fail@plt>
L94:
  leave
  ret
```

assistant: ```c
int GetColumnValue(FILE *file, int *histo_cell, int column) {
  char line[2048];
  char *lineptr = line;
  if (fgets(line, 2047, file) == NULL)
    return -1;
  while (isspace(*lineptr))
    lineptr++;
  for (; *lineptr != '\0' && column != 1; lineptr++) {
    if (!isspace(*lineptr)) {
      while (!isspace(*lineptr))
        lineptr++;
      column--;
    }
  }
  if (column == 1 && *lineptr != '\0') {
    *histo_cell = atoi(lineptr);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetColumnValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rdx
  mov    $0x7ff,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L136
  mov    %rsp,%rbx
  jmp    L52
L107:
  add    $0x1,%rbx
L52:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L107
  movzbl (%rbx),%edi
  cmp    $0x1,%ebp
  je     L14
  test   %dil,%dil
  jne    L5
L14:
  test   %dil,%dil
  je     L21
  cmp    $0x1,%ebp
  je     L51
L21:
  mov    $0x0,%eax
L82:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L130
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  add    $0x1,%rbx
L40:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L37
  sub    $0x1,%ebp
  mov    %rbx,%rax
L27:
  lea    0x1(%rax),%rbx
  movzbl 0x1(%rax),%edi
  cmp    $0x1,%ebp
  je     L14
  test   %dil,%dil
  je     L14
L5:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L40
  mov    %rbx,%rax
  jmp    L27
L51:
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L82
L136:
  mov    $0xffffffff,%eax
  jmp    L82
L130:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetColumnValue(FILE *file, int *histo_cell, int column) {
  char line[2048];
  char *lineptr = line;
  if (fgets(line, 2047, file) == NULL)
    return -1;
  while (isspace(*lineptr))
    lineptr++;
  for (; *lineptr != '\0' && column != 1; lineptr++) {
    if (!isspace(*lineptr)) {
      while (!isspace(*lineptr))
        lineptr++;
      column--;
    }
  }
  if (column == 1 && *lineptr != '\0') {
    *histo_cell = atoi(lineptr);
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetColumnValue>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x7ff,%esi
  push   %rbp
  mov    %edx,%ebp
  mov    %rdi,%rdx
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L78
  jmp    L63
  nopl   0x0(%rax)
L29:
  add    $0x1,%rbx
L78:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L124
  cmp    $0x1,%ebp
  jne    L31
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rbx),%edi
  lea    0x1(%rbx),%r8
  test   %dil,%dil
  je     L124
L85:
  mov    %r8,%rbx
L31:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  nopw   0x0(%rax,%rax,1)
L44:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rbx,%rdx
  add    $0x1,%rbx
  test   %rax,%rax
  je     L44
  movsbl 0x1(%rdx),%edi
  sub    $0x1,%ebp
  mov    %rbx,%r8
  test   %dil,%dil
  je     L124
  cmp    $0x1,%ebp
  jne    L85
L138:
  mov    %r8,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L124:
  xor    %eax,%eax
L22:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  mov    $0xffffffff,%eax
  jmp    L22
L47:
  mov    %rbx,%r8
  jmp    L138
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetColumnValue(FILE *file, int *histo_cell, int column) {
  char line[2048];
  char *lineptr = line;
  if (fgets(line, 2047, file) == NULL)
    return -1;
  while (isspace(*lineptr))
    lineptr++;
  for (; *lineptr != '\0' && column != 1; lineptr++) {
    if (!isspace(*lineptr)) {
      while (!isspace(*lineptr))
        lineptr++;
      column--;
    }
  }
  if (column == 1 && *lineptr != '\0') {
    *histo_cell = atoi(lineptr);
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GetColumnValue>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x7ff,%esi
  push   %rbp
  mov    %edx,%ebp
  mov    %rdi,%rdx
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L23
  jmp    L11
  nopl   0x0(%rax)
L117:
  add    $0x1,%rbx
L23:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L117
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L21
  cmp    $0x1,%ebp
  jne    L121
  jmp    L138
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rbx),%edi
  lea    0x1(%rbx),%r8
  test   %dil,%dil
  je     L21
L100:
  mov    %r8,%rbx
L121:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rbx,%rdx
  add    $0x1,%rbx
  test   %rax,%rax
  je     L5
  movsbl 0x1(%rdx),%edi
  sub    $0x1,%ebp
  mov    %rbx,%r8
  test   %dil,%dil
  je     L21
  cmp    $0x1,%ebp
  jne    L100
L142:
  mov    %r8,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
L60:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L128
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  mov    $0xffffffff,%eax
  jmp    L60
L138:
  mov    %rbx,%r8
  jmp    L142
L128:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetColumnValue(FILE *file, int *histo_cell, int column) {
  char line[2048];
  char *lineptr = line;
  if (fgets(line, 2047, file) == NULL)
    return -1;
  while (isspace(*lineptr))
    lineptr++;
  for (; *lineptr != '\0' && column != 1; lineptr++) {
    if (!isspace(*lineptr)) {
      while (!isspace(*lineptr))
        lineptr++;
      column--;
    }
  }
  if (column == 1 && *lineptr != '\0') {
    *histo_cell = atoi(lineptr);
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isVowel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  sub    $0x61,%eax
  cmp    $0x14,%eax
  seta   %dl
  test   %dl,%dl
  jne    L24
  mov    $0x104111,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L24
  mov    $0x1,%eax
  jmp    L11
L24:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int isVowel(char c) {
  switch (tolower(c)) {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
    return 1;
  default:
    return 0;
  }
}
```