ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x200,%edi
  call   <vlog@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int log_trace(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(512, msg, ap);
  va_end(ap);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<log_trace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x200,%edi
  call   <vlog@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int log_trace(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(512, msg, ap);
  va_end(ap);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<log_trace>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    $0x200,%edi
  call   <vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int log_trace(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(512, msg, ap);
  va_end(ap);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<log_trace>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    $0x200,%edi
  call   <vlog@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int log_trace(const char *msg, ...) {
  va_list ap;
  int r;
  va_start(ap, msg);
  r = vlog(512, msg, ap);
  va_end(ap);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy32_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L7
L13:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x5,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sar    $0x5,%eax
  shl    $0x3,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  and    $0xffffffc0,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x8(%rbp)
  addq   $0x10,-0x10(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy32_8(uint8_t *dst, const uint8_t *src, int count) {
  while (count--) {
    dst[0] = ((src[0] >> 5)) + ((src[1] >> 5) << 3) + ((src[2] >> 6) << 6);
    dst += 1;
    src += 4;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcpy32_8>:
  endbr64
  test   %edx,%edx
  je     L17
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rcx
L9:
  mov    0x4(%rsi),%edx
  sar    $0x5,%edx
  mov    (%rsi),%eax
  sar    $0x5,%eax
  lea    (%rax,%rdx,8),%eax
  mov    0x8(%rsi),%edx
  and    $0xffffffc0,%edx
  add    %edx,%eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  add    $0x10,%rsi
  cmp    %rcx,%rdi
  jne    L9
L17:
  ret
```

assistant: ```c
void memcpy32_8(uint8_t *dst, const uint8_t *src, int count) {
  while (count--) {
    dst[0] = ((src[0] >> 5)) + ((src[1] >> 5) << 3) + ((src[2] >> 6) << 6);
    dst += 1;
    src += 4;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy32_8>:
  endbr64
  test   %edx,%edx
  je     L8
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rcx
  xchg   %ax,%ax
L0:
  mov    0x4(%rsi),%edx
  mov    (%rsi),%eax
  add    $0x4,%rdi
  add    $0x10,%rsi
  sar    $0x5,%edx
  sar    $0x5,%eax
  lea    (%rax,%rdx,8),%eax
  mov    -0x8(%rsi),%edx
  and    $0xffffffc0,%edx
  add    %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rcx,%rdi
  jne    L0
L8:
  ret
```

assistant: ```c
void memcpy32_8(uint8_t *dst, const uint8_t *src, int count) {
  while (count--) {
    dst[0] = ((src[0] >> 5)) + ((src[1] >> 5) << 3) + ((src[2] >> 6) << 6);
    dst += 1;
    src += 4;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bjnp_get_id_from_named_printer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bjnp_get_address_for_named_printer@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L23
  mov    -0xc(%rbp),%eax
  jmp    L7
L23:
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bjnp_get_printer_id@plt>
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int bjnp_get_id_from_named_printer(const int port, const char *device_uri, char *device_id) {
  struct sockaddr_in addr;
  int retval;
  if ((retval = bjnp_get_address_for_named_printer(device_uri, &addr)) != 0)
    return retval;
  return bjnp_get_printer_id(&addr, device_id);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bjnp_get_id_from_named_printer>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <bjnp_get_address_for_named_printer@plt>
  test   %eax,%eax
  je     L24
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rsi
  call   <bjnp_get_printer_id@plt>
  jmp    L21
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bjnp_get_id_from_named_printer(const int port, const char *device_uri, char *device_id) {
  struct sockaddr_in addr;
  int retval;
  if ((retval = bjnp_get_address_for_named_printer(device_uri, &addr)) != 0)
    return retval;
  return bjnp_get_printer_id(&addr, device_id);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bjnp_get_id_from_named_printer>:
  endbr64
  push   %r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <bjnp_get_address_for_named_printer@plt>
  test   %eax,%eax
  jne    L18
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <bjnp_get_printer_id@plt>
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bjnp_get_id_from_named_printer(const int port, const char *device_uri, char *device_id) {
  struct sockaddr_in addr;
  int retval;
  if ((retval = bjnp_get_address_for_named_printer(device_uri, &addr)) != 0)
    return retval;
  return bjnp_get_printer_id(&addr, device_id);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bjnp_get_id_from_named_printer>:
  endbr64
  push   %r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <bjnp_get_address_for_named_printer@plt>
  test   %eax,%eax
  jne    L13
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <bjnp_get_printer_id@plt>
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bjnp_get_id_from_named_printer(const int port, const char *device_uri, char *device_id) {
  struct sockaddr_in addr;
  int retval;
  if ((retval = bjnp_get_address_for_named_printer(device_uri, &addr)) != 0)
    return retval;
  return bjnp_get_printer_id(&addr, device_id);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alock_alloc_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L95
  cmpl   $0x0,-0x1c(%rbp)
  je     L95
  cmpq   $0x0,-0x30(%rbp)
  je     L95
  cmpq   $0x0,-0x38(%rbp)
  jne    L12
L95:
  mov    $0x0,%eax
  jmp    L43
L12:
  cmpq   $0x0,-0x28(%rbp)
  je     L97
  mov    -0x38(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <XAllocNamedColor@plt>
  test   %rax,%rax
  jne    L32
L97:
  mov    -0x38(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <XAllocNamedColor@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x0,%eax
  jmp    L43
L32:
  mov    $0x1,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int alock_alloc_color(Display *display, Colormap colormap, const char *color_name, const char *fallback_name, XColor *result) {
  if (!display || !colormap || !fallback_name || !result)
    return 0;
  XColor tmp;
  if (!color_name || XAllocNamedColor(display, colormap, color_name, &tmp, result) == 0)
    if (XAllocNamedColor(display, colormap, fallback_name, &tmp, result) == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alock_alloc_color>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L25
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rcx,%r13
  mov    %r8,%r12
  test   %esi,%esi
  je     L25
  test   %rcx,%rcx
  je     L5
  test   %r8,%r8
  je     L5
  test   %rdx,%rdx
  je     L62
  lea    0x4(%rsp),%rcx
  call   <XAllocNamedColor@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L34
L62:
  lea    0x4(%rsp),%rcx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <XAllocNamedColor@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L34
L25:
  mov    $0x0,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%eax
  jmp    L34
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alock_alloc_color(Display *display, Colormap colormap, const char *color_name, const char *fallback_name, XColor *result) {
  if (!display || !colormap || !fallback_name || !result)
    return 0;
  XColor tmp;
  if (!color_name || XAllocNamedColor(display, colormap, color_name, &tmp, result) == 0)
    if (XAllocNamedColor(display, colormap, fallback_name, &tmp, result) == 0)
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alock_alloc_color>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L49
  mov    %esi,%r12d
  test   %esi,%esi
  je     L49
  mov    %rcx,%r13
  test   %rcx,%rcx
  je     L49
  test   %r8,%r8
  je     L49
  mov    %rdi,%rbp
  lea    0x14(%rsp),%r14
  test   %rdx,%rdx
  je     L30
  mov    %r14,%rcx
  mov    %r8,0x8(%rsp)
  call   <XAllocNamedColor@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  jne    L68
L30:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <XAllocNamedColor@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
L41:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L68:
  mov    $0x1,%eax
  jmp    L41
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alock_alloc_color(Display *display, Colormap colormap, const char *color_name, const char *fallback_name, XColor *result) {
  if (!display || !colormap || !fallback_name || !result)
    return 0;
  XColor tmp;
  if (!color_name || XAllocNamedColor(display, colormap, color_name, &tmp, result) == 0)
    if (XAllocNamedColor(display, colormap, fallback_name, &tmp, result) == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<alock_alloc_color>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L24
  mov    %esi,%r12d
  test   %esi,%esi
  je     L24
  mov    %rcx,%r13
  test   %rcx,%rcx
  je     L24
  test   %r8,%r8
  je     L24
  mov    %rdi,%rbp
  lea    0x14(%rsp),%r14
  test   %rdx,%rdx
  je     L36
  mov    %r14,%rcx
  mov    %r8,0x8(%rsp)
  call   <XAllocNamedColor@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  jne    L76
L36:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <XAllocNamedColor@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L76:
  mov    $0x1,%eax
  jmp    L23
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alock_alloc_color(Display *display, Colormap colormap, const char *color_name, const char *fallback_name, XColor *result) {
  if (!display || !colormap || !fallback_name || !result)
    return 0;
  XColor tmp;
  if (!color_name || XAllocNamedColor(display, colormap, color_name, &tmp, result) == 0)
    if (XAllocNamedColor(display, colormap, fallback_name, &tmp, result) == 0)
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<glmGenerateConjugateQuaternionf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  D15(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  D15(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  D15(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: byte[4]

tool: {"D15": [0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaternionf(float result[4], const float q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<glmGenerateConjugateQuaternionf>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  D6(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaternionf(float result[4], const float q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<glmGenerateConjugateQuaternionf>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D4(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaternionf(float result[4], const float q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glmGenerateConjugateQuaternionf>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D8(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateConjugateQuaternionf(float result[4], const float q[4]) {
  result[0] = q[0];
  result[1] = -q[1];
  result[2] = -q[2];
  result[3] = -q[3];
}
```
user: What is the c source code of the assembly code below?

```asm
<EPIDividerSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EPIDividerSet(uint32_t ui32Base, uint32_t ui32Divider) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000004))) = ui32Divider;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EPIDividerSet>:
  endbr64
  mov    %rsi,0x4(%rdi)
  ret
```

assistant: ```c
void EPIDividerSet(uint32_t ui32Base, uint32_t ui32Divider) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000004))) = ui32Divider;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EPIDividerSet>:
  endbr64
  mov    %rsi,0x4(%rdi)
  ret
```

assistant: ```c
void EPIDividerSet(uint32_t ui32Base, uint32_t ui32Divider) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000004))) = ui32Divider;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EPIDividerSet>:
  endbr64
  mov    %rsi,0x4(%rdi)
  ret
```

assistant: ```c
void EPIDividerSet(uint32_t ui32Base, uint32_t ui32Divider) {
  ;
  (*((volatile unsigned long *)(ui32Base + 0x00000004))) = ui32Divider;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %edi,-0x14(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L11
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  imul   -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x8(%rbp),%xmm0
  jmp    L1
L11:
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  imul   -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x10(%rbp),%xmm0
L1:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double add_log(double a, double b, int add_sub) {
  if (a > b)
    return a + log(1 + add_sub * exp(b - a));
  else
    return b + log(1 + add_sub * exp(a - b));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<add_log>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  mov    %edi,%ebx
  movsd  (%rsp),%xmm2
  comisd %xmm1,%xmm2
  jbe    L1
  movapd %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  addsd  (%rsp),%xmm0
L11:
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  movsd  (%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  addsd  0x8(%rsp),%xmm0
  jmp    L11
```

assistant: ```c
double add_log(double a, double b, int add_sub) {
  if (a > b)
    return a + log(1 + add_sub * exp(b - a));
  else
    return b + log(1 + add_sub * exp(a - b));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_log>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  mov    %edi,%ebx
  sub    $0x10,%rsp
  comisd %xmm1,%xmm0
  jbe    L9
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  subsd  %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double add_log(double a, double b, int add_sub) {
  if (a > b)
    return a + log(1 + add_sub * exp(b - a));
  else
    return b + log(1 + add_sub * exp(a - b));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_log>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm2
  mov    %edi,%ebx
  sub    $0x10,%rsp
  comisd %xmm1,%xmm0
  jbe    L0
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  subsd  %xmm1,%xmm2
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <exp@plt>
  imul   %ebx,%eax
  lea    0x1(%rax),%edi
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbx
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double add_log(double a, double b, int add_sub) {
  if (a > b)
    return a + log(1 + add_sub * exp(b - a));
  else
    return b + log(1 + add_sub * exp(a - b));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strstrnull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *strstrnull(const char *s, const char *c) {
  const char *result = strstr(s, c);
  if (!result) {
    result = s + strlen(s);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strstrnull>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L7
L5:
  pop    %rbx
  ret
L7:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jmp    L5
```

assistant: ```c
const char *strstrnull(const char *s, const char *c) {
  const char *result = strstr(s, c);
  if (!result) {
    result = s + strlen(s);
  }
  return result;
}
```