ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CdsObjectToDidl_Helper_DoubleEscape>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L23
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%r12
  mov    %r15,%rbp
  lea    D20(%rip),%r15
  lea    D36(%rip),%r14
  lea    D21(%rip),%r13
  jmp    L84
L75:
  mov    $0xa,%edx
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0xa,%rbp
L120:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L122
L84:
  movzbl (%rbx),%eax
  cmp    $0x22,%al
  je     L75
  cmp    $0x27,%al
  je     L11
  cmp    $0x3c,%al
  je     L87
  cmp    $0x3e,%al
  je     L35
  cmp    $0x26,%al
  je     L66
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L120
L11:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0xa,%rbp
  jmp    L120
L87:
  mov    $0x8,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rbp
  jmp    L120
L35:
  mov    $0x8,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rbp
  jmp    L120
L66:
  mov    $0x9,%edx
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x9,%rbp
  jmp    L120
L23:
  mov    0x8(%rsp),%rbp
L122:
  movb   $0x0,0x0(%rbp)
  mov    %ebp,%eax
  sub    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D32
data_type: string
name: extract_symbolic_data
arguments: data_tag: D16
data_type: string

tool: D20: &amp;gt;

tool: D36: &amp;lt;

tool: D21: &amp;apos;

tool: D32: &amp;quot;

tool: D16: &amp;amp;

assistant: ```c
int CdsObjectToDidl_Helper_DoubleEscape(char *outdata, const char *indata) {
  int i = 0;
  int inlen;
  char *out;
  out = outdata;
  inlen = (int)strlen(indata);
  for (i = 0; i < inlen; i++) {
    if (indata[i] == '"') {
      memcpy(out, "&amp;quot;", 10);
      out = out + 10;
    } else if (indata[i] == '\'') {
      memcpy(out, "&amp;apos;", 10);
      out = out + 10;
    } else if (indata[i] == '<') {
      memcpy(out, "&amp;lt;", 8);
      out = out + 8;
    } else if (indata[i] == '>') {
      memcpy(out, "&amp;gt;", 8);
      out = out + 8;
    } else if (indata[i] == '&') {
      memcpy(out, "&amp;amp;", 9);
      out = out + 9;
    } else {
      out[0] = indata[i];
      out++;
    }
  }
  out[0] = 0;
  return (int)(out - outdata);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CdsObjectToDidl_Helper_DoubleEscape>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L92
  sub    $0x1,%eax
  mov    %rbp,%r15
  lea    D24(%rip),%r13
  lea    0x1(%r14,%rax,1),%rbx
  lea    D43(%rip),%r12
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L127:
  cmp    $0x27,%al
  je     L111
  cmp    $0x3c,%al
  je     L135
  cmp    $0x3e,%al
  je     L51
  cmp    $0x26,%al
  je     L26
  mov    %al,(%r15)
  add    $0x1,%r15
L32:
  add    $0x1,%r14
  cmp    %rbx,%r14
  je     L0
L52:
  movzbl (%r14),%eax
  cmp    $0x22,%al
  jne    L127
  mov    %r15,%rdi
  mov    $0xa,%edx
  add    $0x1,%r14
  add    $0xa,%r15
  lea    D45(%rip),%rsi
  call   <memcpy@plt>
  cmp    %rbx,%r14
  jne    L52
L0:
  mov    %r15d,%eax
  sub    %ebp,%eax
L36:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L111:
  mov    %r15,%rdi
  mov    $0xa,%edx
  mov    %r12,%rsi
  add    $0xa,%r15
  call   <memcpy@plt>
  jmp    L32
  xchg   %ax,%ax
L135:
  mov    %r15,%rdi
  mov    $0x8,%edx
  mov    %r13,%rsi
  add    $0x8,%r15
  call   <memcpy@plt>
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L51:
  mov    %r15,%rdi
  mov    $0x8,%edx
  lea    D28(%rip),%rsi
  add    $0x8,%r15
  call   <memcpy@plt>
  jmp    L32
  nopl   (%rax)
L26:
  mov    %r15,%rdi
  mov    $0x9,%edx
  lea    D30(%rip),%rsi
  add    $0x9,%r15
  call   <memcpy@plt>
  jmp    L32
  nopl   (%rax)
L92:
  mov    %rbp,%r15
  xor    %eax,%eax
  jmp    L36
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
data_type: string
name: extract_symbolic_data
arguments: label: D43
data_type: string
name: extract_symbolic_data
arguments: label: D45
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D30
data_type: string

tool: D24: &amp;lt;

tool: D43: &amp;apos;

tool: D45: &amp;quot;

tool: D28: &amp;gt;

tool: D30: &amp;amp;

assistant: ```c
int CdsObjectToDidl_Helper_DoubleEscape(char *outdata, const char *indata) {
  int i = 0;
  int inlen;
  char *out;
  out = outdata;
  inlen = (int)strlen(indata);
  for (i = 0; i < inlen; i++) {
    if (indata[i] == '"') {
      memcpy(out, "&amp;quot;", 10);
      out = out + 10;
    } else if (indata[i] == '\'') {
      memcpy(out, "&amp;apos;", 10);
      out = out + 10;
    } else if (indata[i] == '<') {
      memcpy(out, "&amp;lt;", 8);
      out = out + 8;
    } else if (indata[i] == '>') {
      memcpy(out, "&amp;gt;", 8);
      out = out + 8;
    } else if (indata[i] == '&') {
      memcpy(out, "&amp;amp;", 9);
      out = out + 9;
    } else {
      out[0] = indata[i];
      out++;
    }
  }
  out[0] = 0;
  return (int)(out - outdata);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CdsObjectToDidl_Helper_DoubleEscape>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L25
  sub    $0x1,%eax
  mov    %rbp,%r15
  lea    D14(%rip),%r13
  lea    0x1(%r14,%rax,1),%rbx
  lea    D21(%rip),%r12
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L135:
  cmp    $0x27,%al
  je     L108
  cmp    $0x3c,%al
  je     L8
  cmp    $0x3e,%al
  je     L54
  cmp    $0x26,%al
  je     L44
  mov    %al,(%r15)
  add    $0x1,%r15
L45:
  add    $0x1,%r14
  cmp    %r14,%rbx
  je     L106
L63:
  movzbl (%r14),%eax
  cmp    $0x22,%al
  jne    L135
  mov    %r15,%rdi
  mov    $0xa,%edx
  add    $0x1,%r14
  add    $0xa,%r15
  lea    D8(%rip),%rsi
  call   <memcpy@plt>
  cmp    %r14,%rbx
  jne    L63
L106:
  mov    %r15d,%eax
  sub    %ebp,%eax
L100:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L108:
  mov    %r15,%rdi
  mov    $0xa,%edx
  mov    %r12,%rsi
  add    $0xa,%r15
  call   <memcpy@plt>
  jmp    L45
  xchg   %ax,%ax
L8:
  mov    %r15,%rdi
  mov    $0x8,%edx
  mov    %r13,%rsi
  add    $0x8,%r15
  call   <memcpy@plt>
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %r15,%rdi
  mov    $0x8,%edx
  lea    D18(%rip),%rsi
  add    $0x8,%r15
  call   <memcpy@plt>
  jmp    L45
  nopl   (%rax)
L44:
  mov    %r15,%rdi
  mov    $0x9,%edx
  lea    D0(%rip),%rsi
  add    $0x9,%r15
  call   <memcpy@plt>
  jmp    L45
  nopl   (%rax)
L25:
  mov    %rbp,%r15
  xor    %eax,%eax
  jmp    L100
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string

tool: D14: &amp;lt;

tool: D21: &amp;apos;

tool: D8: &amp;quot;

tool: D18: &amp;gt;

tool: D0: &amp;amp;

assistant: ```c
int CdsObjectToDidl_Helper_DoubleEscape(char *outdata, const char *indata) {
  int i = 0;
  int inlen;
  char *out;
  out = outdata;
  inlen = (int)strlen(indata);
  for (i = 0; i < inlen; i++) {
    if (indata[i] == '"') {
      memcpy(out, "&amp;quot;", 10);
      out = out + 10;
    } else if (indata[i] == '\'') {
      memcpy(out, "&amp;apos;", 10);
      out = out + 10;
    } else if (indata[i] == '<') {
      memcpy(out, "&amp;lt;", 8);
      out = out + 8;
    } else if (indata[i] == '>') {
      memcpy(out, "&amp;gt;", 8);
      out = out + 8;
    } else if (indata[i] == '&') {
      memcpy(out, "&amp;amp;", 9);
      out = out + 9;
    } else {
      out[0] = indata[i];
      out++;
    }
  }
  out[0] = 0;
  return (int)(out - outdata);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <access_filesystem@plt>
  mov    $0x0,%eax
  call   <unaddr_open@plt>
  mov    $0x0,%eax
  call   <wild_open@plt>
  mov    $0x1,%edi
  call   <uninit_open@plt>
  mov    $0x0,%edi
  call   <uninit_open@plt>
  mov    $0x0,%eax
  call   <unaddr_finit_module@plt>
  mov    $0x0,%edi
  call   <uninit_finit_module@plt>
  mov    $0x1,%edi
  call   <uninit_finit_module@plt>
  mov    $0x0,%eax
  call   <unaddr_uninit_execve@plt>
  mov    $0x1,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  mov    $0x0,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: done


assistant: ```c
int main(void) {
  access_filesystem();
  unaddr_open();
  wild_open();
  uninit_open(1);
  uninit_open(0);
  unaddr_finit_module();
  uninit_finit_module(0);
  uninit_finit_module(1);
  unaddr_uninit_execve();
  unaddr_process_vm_readv_writev(1);
  unaddr_process_vm_readv_writev(0);
  printf("done\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <access_filesystem@plt>
  mov    $0x0,%eax
  call   <unaddr_open@plt>
  mov    $0x0,%eax
  call   <wild_open@plt>
  mov    $0x1,%edi
  call   <uninit_open@plt>
  mov    $0x0,%edi
  call   <uninit_open@plt>
  mov    $0x0,%eax
  call   <unaddr_finit_module@plt>
  mov    $0x0,%edi
  call   <uninit_finit_module@plt>
  mov    $0x1,%edi
  call   <uninit_finit_module@plt>
  mov    $0x0,%eax
  call   <unaddr_uninit_execve@plt>
  mov    $0x1,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  mov    $0x0,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: done


assistant: ```c
int main(void) {
  access_filesystem();
  unaddr_open();
  wild_open();
  uninit_open(1);
  uninit_open(0);
  unaddr_finit_module();
  uninit_finit_module(0);
  uninit_finit_module(1);
  unaddr_uninit_execve();
  unaddr_process_vm_readv_writev(1);
  unaddr_process_vm_readv_writev(0);
  printf("done\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <access_filesystem@plt>
  xor    %eax,%eax
  call   <unaddr_open@plt>
  xor    %eax,%eax
  call   <wild_open@plt>
  mov    $0x1,%edi
  call   <uninit_open@plt>
  xor    %edi,%edi
  call   <uninit_open@plt>
  xor    %eax,%eax
  call   <unaddr_finit_module@plt>
  xor    %edi,%edi
  call   <uninit_finit_module@plt>
  mov    $0x1,%edi
  call   <uninit_finit_module@plt>
  xor    %eax,%eax
  call   <unaddr_uninit_execve@plt>
  mov    $0x1,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  xor    %edi,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: done


assistant: ```c
int main(void) {
  access_filesystem();
  unaddr_open();
  wild_open();
  uninit_open(1);
  uninit_open(0);
  unaddr_finit_module();
  uninit_finit_module(0);
  uninit_finit_module(1);
  unaddr_uninit_execve();
  unaddr_process_vm_readv_writev(1);
  unaddr_process_vm_readv_writev(0);
  printf("done\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <access_filesystem@plt>
  xor    %eax,%eax
  call   <unaddr_open@plt>
  xor    %eax,%eax
  call   <wild_open@plt>
  mov    $0x1,%edi
  call   <uninit_open@plt>
  xor    %edi,%edi
  call   <uninit_open@plt>
  xor    %eax,%eax
  call   <unaddr_finit_module@plt>
  xor    %edi,%edi
  call   <uninit_finit_module@plt>
  mov    $0x1,%edi
  call   <uninit_finit_module@plt>
  xor    %eax,%eax
  call   <unaddr_uninit_execve@plt>
  mov    $0x1,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  xor    %edi,%edi
  call   <unaddr_process_vm_readv_writev@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: done


assistant: ```c
int main(void) {
  access_filesystem();
  unaddr_open();
  wild_open();
  uninit_open(1);
  uninit_open(0);
  unaddr_finit_module();
  uninit_finit_module(0);
  uninit_finit_module(1);
  unaddr_uninit_execve();
  unaddr_process_vm_readv_writev(1);
  unaddr_process_vm_readv_writev(0);
  printf("done\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <timer0_reset@plt>
  mov    $0x0,%eax
  call   <timer0_start@plt>
  jmp    L1
L19:
  nop
L1:
  mov    $0x0,%eax
  call   <timer0_get_us@plt>
  cmp    %eax,-0x4(%rbp)
  jg     L19
  mov    $0x0,%eax
  call   <timer0_stop@plt>
  nop
  leave
  ret
```

assistant: ```c
void delay_us(int us) {
  timer0_reset();
  timer0_start();
  while (timer0_get_us() < us) {
    asm volatile("NOP");
  }
  timer0_stop();
}
```
user: Translate the below assembly code into C programming language:

```asm
<delay_us>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <timer0_reset@plt>
  mov    $0x0,%eax
  call   <timer0_start@plt>
  jmp    L0
L18:
  nop
L0:
  mov    $0x0,%eax
  call   <timer0_get_us@plt>
  cmp    %ebx,%eax
  jl     L18
  mov    $0x0,%eax
  call   <timer0_stop@plt>
  pop    %rbx
  ret
```

assistant: ```c
void delay_us(int us) {
  timer0_reset();
  timer0_start();
  while (timer0_get_us() < us) {
    asm volatile("NOP");
  }
  timer0_stop();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<delay_us>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <timer0_reset@plt>
  xor    %eax,%eax
  call   <timer0_start@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L14:
  nop
L6:
  xor    %eax,%eax
  call   <timer0_get_us@plt>
  cmp    %ebx,%eax
  jl     L14
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <timer0_stop@plt>
```

assistant: ```c
void delay_us(int us) {
  timer0_reset();
  timer0_start();
  while (timer0_get_us() < us) {
    asm volatile("NOP");
  }
  timer0_stop();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delay_us>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <timer0_reset@plt>
  xor    %eax,%eax
  call   <timer0_start@plt>
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L8:
  nop
L19:
  xor    %eax,%eax
  call   <timer0_get_us@plt>
  cmp    %ebx,%eax
  jl     L8
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <timer0_stop@plt>
```

assistant: ```c
void delay_us(int us) {
  timer0_reset();
  timer0_start();
  while (timer0_get_us() < us) {
    asm volatile("NOP");
  }
  timer0_stop();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ax25_ntoa_pretty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L44
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    %eax
  and    $0x7f,%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x20,-0xd(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
L20:
  addl   $0x1,-0xc(%rbp)
L44:
  cmpl   $0x5,-0xc(%rbp)
  jle    L14
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x18,%rax
  mov    (%rax),%eax
  sar    %eax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
  cmpl   $0x9,-0xc(%rbp)
  jle    L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x31,(%rax)
  subl   $0xa,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L16:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  lea    D12(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ax25_ntoa_pretty(const ax25_address *a) {
  static char buf[11];
  char c, *s;
  int n;
  for (n = 0, s = buf; n < 6; n++) {
    c = (a->ax25_call[n] >> 1) & 0x7F;
    if (c != ' ')
      *s++ = c;
  }
  if ((n = ((a->ax25_call[6] >> 1) & 0x0F))) {
    *s++ = '-';
    if (n > 9) {
      *s++ = '1';
      n -= 10;
    }
    *s++ = n + '0';
  }
  *s++ = '\0';
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ax25_ntoa_pretty>:
  endbr64
  mov    $0x0,%edx
  lea    D1(%rip),%rcx
  jmp    L56
L9:
  add    $0x4,%rdx
  cmp    $0x18,%rdx
  je     L21
L56:
  mov    (%rdi),%rax
  mov    (%rax,%rdx,1),%eax
  shr    %al
  cmp    $0x20,%al
  je     L9
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rcx
  jmp    L9
L21:
  mov    (%rdi),%rax
  mov    0x18(%rax),%eax
  sar    %eax
  and    $0xf,%eax
  je     L34
  movb   $0x2d,(%rcx)
  lea    0x1(%rcx),%rdx
  cmp    $0x9,%eax
  jle    L52
  lea    0x2(%rcx),%rdx
  movb   $0x31,0x1(%rcx)
  sub    $0xa,%eax
L52:
  lea    0x1(%rdx),%rcx
  add    $0x30,%eax
  mov    %al,(%rdx)
L34:
  movb   $0x0,(%rcx)
  lea    D1(%rip),%rax
  ret
```

assistant: ```c
char *ax25_ntoa_pretty(const ax25_address *a) {
  static char buf[11];
  char c, *s;
  int n;
  for (n = 0, s = buf; n < 6; n++) {
    c = (a->ax25_call[n] >> 1) & 0x7F;
    if (c != ' ')
      *s++ = c;
  }
  if ((n = ((a->ax25_call[6] >> 1) & 0x0F))) {
    *s++ = '-';
    if (n > 9) {
      *s++ = '1';
      n -= 10;
    }
    *s++ = n + '0';
  }
  *s++ = '\0';
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ax25_ntoa_pretty>:
  endbr64
  lea    D6(%rip),%r8
  mov    (%rdi),%rsi
  xor    %edx,%edx
  mov    %r8,%rcx
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl (%rsi,%rdx,1),%eax
  shr    %al
  cmp    $0x20,%al
  je     L25
  mov    %al,(%rcx)
  mov    (%rdi),%rsi
  add    $0x1,%rcx
L25:
  add    $0x4,%rdx
  cmp    $0x18,%rdx
  jne    L24
  mov    0x18(%rsi),%eax
  sar    %eax
  and    $0xf,%eax
  je     L23
  movb   $0x2d,(%rcx)
  lea    0x1(%rcx),%rdx
  cmp    $0x9,%eax
  jg     L28
L12:
  add    $0x30,%eax
  lea    0x1(%rdx),%rcx
  mov    %al,(%rdx)
L23:
  movb   $0x0,(%rcx)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movb   $0x31,0x1(%rcx)
  lea    0x2(%rcx),%rdx
  sub    $0xa,%eax
  jmp    L12
```

assistant: ```c
char *ax25_ntoa_pretty(const ax25_address *a) {
  static char buf[11];
  char c, *s;
  int n;
  for (n = 0, s = buf; n < 6; n++) {
    c = (a->ax25_call[n] >> 1) & 0x7F;
    if (c != ' ')
      *s++ = c;
  }
  if ((n = ((a->ax25_call[6] >> 1) & 0x0F))) {
    *s++ = '-';
    if (n > 9) {
      *s++ = '1';
      n -= 10;
    }
    *s++ = n + '0';
  }
  *s++ = '\0';
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ax25_ntoa_pretty>:
  endbr64
  mov    (%rdi),%rdx
  lea    D19(%rip),%r8
  mov    %r8,%rax
  movzbl (%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L72
  mov    %cl,D9(%rip)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L72:
  movzbl 0x4(%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L88
  mov    %cl,(%rax)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L88:
  movzbl 0x8(%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L37
  mov    %cl,(%rax)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L37:
  movzbl 0xc(%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L1
  mov    %cl,(%rax)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L1:
  movzbl 0x10(%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L48
  mov    %cl,(%rax)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L48:
  movzbl 0x14(%rdx),%ecx
  shr    %cl
  cmp    $0x20,%cl
  je     L62
  mov    %cl,(%rax)
  mov    (%rdi),%rdx
  add    $0x1,%rax
L62:
  mov    0x18(%rdx),%edx
  sar    %edx
  and    $0xf,%edx
  je     L82
  movb   $0x2d,(%rax)
  lea    0x1(%rax),%rcx
  cmp    $0x9,%edx
  jg     L32
L35:
  add    $0x30,%edx
  lea    0x1(%rcx),%rax
  mov    %dl,(%rcx)
L82:
  movb   $0x0,(%rax)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  movb   $0x31,0x1(%rax)
  lea    0x2(%rax),%rcx
  sub    $0xa,%edx
  jmp    L35
```

assistant: ```c
char *ax25_ntoa_pretty(const ax25_address *a) {
  static char buf[11];
  char c, *s;
  int n;
  for (n = 0, s = buf; n < 6; n++) {
    c = (a->ax25_call[n] >> 1) & 0x7F;
    if (c != ' ')
      *s++ = c;
  }
  if ((n = ((a->ax25_call[6] >> 1) & 0x0F))) {
    *s++ = '-';
    if (n > 9) {
      *s++ = '1';
      n -= 10;
    }
    *s++ = n + '0';
  }
  *s++ = '\0';
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<rgb565_to_rgb888_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L38
  cmpl   $0x0,-0x1c(%rbp)
  jle    L38
  cmpl   $0x0,-0x20(%rbp)
  jle    L38
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rgb565_to_rgb888@plt>
L38:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *rgb565_to_rgb888_buffer(const void *p565, int w, int h) {
  int size = w * h * 3;
  void *p888 = NULL;
  if (p565 && w > 0 && h > 0) {
    p888 = malloc(size);
    if (p888)
      rgb565_to_rgb888(p565, w, h, p888);
  }
  return p888;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rgb565_to_rgb888_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  test   %rdi,%rdi
  setne  %dl
  test   %ebx,%ebx
  setg   %al
  test   %al,%dl
  je     L6
  mov    %rdi,%r12
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L6
  mov    %esi,%eax
  imul   %ebx,%eax
  lea    (%rax,%rax,2),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L16
  mov    %rax,%rcx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <rgb565_to_rgb888@plt>
  jmp    L16
L6:
  mov    $0x0,%r13d
L16:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *rgb565_to_rgb888_buffer(const void *p565, int w, int h) {
  int size = w * h * 3;
  void *p888 = NULL;
  if (p565 && w > 0 && h > 0) {
    p888 = malloc(size);
    if (p888)
      rgb565_to_rgb888(p565, w, h, p888);
  }
  return p888;
}
```