user: 这段汇编代码用C语言表示是什么样的？

```asm
<cpuE>:
  endbr64
  push   %r15
  mov    %edx,%eax
  mov    %rdi,%r10
  movapd %xmm0,%xmm4
  push   %r14
  mov    %r8d,%r15d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x8(%rsp)
  mov    %eax,-0x30(%rsp)
  mov    %ecx,-0x2c(%rsp)
  test   %eax,%eax
  jle    L21
  mov    %eax,%r11d
  lea    -0x1(%rax),%ebx
  mov    %rax,-0x18(%rsp)
  lea    -0x1(%rcx),%eax
  imul   %r8d,%r11d
  mov    %ebx,-0xc(%rsp)
  pxor   %xmm3,%xmm3
  lea    -0x1(%r8),%r14d
  movq   $0x0,-0x38(%rsp)
  mov    %eax,-0x10(%rsp)
  movslq %r11d,%rdi
  shl    $0x2,%rdi
  nopl   0x0(%rax)
L28:
  mov    -0x38(%rsp),%rcx
  mov    -0x2c(%rsp),%eax
  mov    %ecx,%ebx
  test   %eax,%eax
  jle    L0
  mov    %ecx,%eax
  xor    %esi,%esi
  add    $0x1,%eax
  cmp    %ecx,-0xc(%rsp)
  cmove  %esi,%eax
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  cltq
  sub    %rax,%rcx
  mov    %rax,-0x28(%rsp)
  mov    %rcx,-0x20(%rsp)
  xchg   %ax,%ax
L73:
  mov    %r12d,%eax
  add    $0x1,%r12d
  test   %r15d,%r15d
  jle    L68
  xor    %ebp,%ebp
  cmp    %eax,-0x10(%rsp)
  mov    -0x38(%rsp),%rax
  movslq %r8d,%r13
  cmovne %r12d,%ebp
  imul   -0x30(%rsp),%ebp
  mov    -0x20(%rsp),%r9
  lea    (%r11,%r8,1),%esi
  add    %r13,%rax
  lea    (%r10,%rax,4),%rcx
  mov    -0x28(%rsp),%rax
  sub    %r13,%r9
  movslq %ebp,%rbp
  add    %r13,%rax
  add    %rbp,%r9
  lea    (%r10,%rax,4),%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L19:
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cmp    %r14d,%eax
  cvtsi2sdl (%rcx),%xmm2
  mov    %esi,%ebp
  cvtsi2sdl (%rdx,%r9,4),%xmm0
  cmove  %r8d,%ebp
  add    $0x1,%eax
  add    %r11d,%esi
  cvtsi2sdl (%rdx),%xmm1
  add    %rdi,%rcx
  add    %rdi,%rdx
  add    %ebx,%ebp
  movslq %ebp,%rbp
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%r10,%rbp,4),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  cmp    %eax,%r15d
  jne    L19
L68:
  add    -0x30(%rsp),%r8d
  cmp    %r12d,-0x2c(%rsp)
  jne    L73
L0:
  addq   $0x1,-0x38(%rsp)
  mov    -0x38(%rsp),%rax
  cmp    %rax,-0x18(%rsp)
  jne    L28
L55:
  mov    -0x30(%rsp),%eax
  imul   %r15d,%eax
  imul   -0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L89
  mov    -0x8(%rsp),%rcx
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L65:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rcx,%rdx,4),%xmm0
  cvtsi2sdl (%r10,%rdx,4),%xmm1
  add    $0x1,%rdx
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  cmp    %rdx,%rax
  jne    L65
L89:
  xorpd  D1(%rip),%xmm3
  pop    %rbx
  pop    %rbp
  pop    %r12
  movapd %xmm3,%xmm0
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  pxor   %xmm3,%xmm3
  jmp    L55
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: f32[4]

tool: {"D1": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double cpuE(int *hlat, int *hH, double h, int width, int height, int length) {
  double E = 0.0;
  int idx, idy, idz;
  for (idx = 0; idx < width; idx++) {
    for (idy = 0; idy < height; idy++) {
      for (idz = 0; idz < length; idz++) {
        int down = idz + 1;
        int right = idx + 1;
        int front = idy + 1;
        if (idx == width - 1)
          right = 0;
        if (idy == height - 1)
          front = 0;
        if (idz == length - 1)
          down = 0;
        int i = idz * width * length + idy * width + idx;
        E += (double)hlat[i] * hlat[width * length * idz + width * idy + right] + (double)hlat[i] * hlat[width * length * idz + width * front + idx] + (double)hlat[i] * hlat[width * length * down + width * idy + idx];
      }
    }
  }
  for (int i = 0; i < width * length * height; i++)
    E += (double)h * hH[i] * hlat[i];
  return -E;
}
```