ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D69
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D26
type_infered: string

tool: D7: 
-----------


tool: D15: rr reg       - register read, used to read a register


tool: D69: rw reg value - register write, used to write a value to a register


tool: D10: md offset    - memory dump, used to dump 128 bytes in memory


tool: D12: mw reg value - memory write, used to write a value to a physical memory


tool: D30: quit - exit from tool


tool: D26: -----------


assistant: ```c
void show_help(void) {
  printf("\n-----------\n");
  printf("rr reg       - register read, used to read a register\n");
  printf("rw reg value - register write, used to write a value to a register\n");
  printf("md offset    - memory dump, used to dump 128 bytes in memory\n");
  printf("mw reg value - memory write, used to write a value to a physical memory\n");
  printf("quit - exit from tool\n");
  printf("-----------\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8_string_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L32:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  add    %rax,-0x18(%rbp)
  addq   $0x4,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L27
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L32
  jmp    L27
L68:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x20,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_count_non_start_bytes_in_word@plt>
  add    %rax,-0x18(%rbp)
L27:
  mov    -0x30(%rbp),%rax
  sub    $0x20,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L68
  jmp    L54
L10:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  add    %rax,-0x18(%rbp)
  addq   $0x4,-0x10(%rbp)
L54:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L10
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t utf8_string_length(const uint8_t *start, const uint8_t *end) {
  ssize_t non_start_count = 0;
  const uint8_t *p = start;
  while ((uintptr_t)(p) & (sizeof(uintptr_t) - 1) && p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  while (p < (end - sizeof(uintptr_t))) {
    uintptr_t w = *(uintptr_t *)(p);
    p += sizeof(uintptr_t);
    non_start_count += utf8_count_non_start_bytes_in_word(w);
  }
  while (p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  return end - start - non_start_count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8_string_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  test   $0x7,%dil
  je     L71
  cmp    %rsi,%rdi
  jae    L71
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L33:
  mov    (%rbx),%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  add    $0x4,%rbx
  test   $0x7,%bl
  je     L21
  cmp    %rbx,%r13
  ja     L33
L21:
  lea    -0x20(%r13),%r15
  cmp    %rbx,%r15
  jbe    L29
  mov    %rbx,%r12
L42:
  mov    (%r12),%rdi
  add    $0x20,%r12
  call   <utf8_count_non_start_bytes_in_word@plt>
  add    %rax,%rbp
  cmp    %r15,%r12
  jb     L42
  lea    -0x21(%r13),%rax
  sub    %rbx,%rax
  and    $0xffffffffffffffe0,%rax
  lea    0x20(%rbx,%rax,1),%rbx
L29:
  cmp    %rbx,%r13
  jbe    L0
L63:
  mov    (%rbx),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  add    $0x4,%rbx
  cmp    %rbx,%r13
  ja     L63
L0:
  mov    %r13,%rax
  sub    %r14,%rax
  sar    $0x2,%rax
  sub    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  mov    %r14,%rbx
  mov    $0x0,%ebp
  jmp    L21
```

assistant: ```c
ssize_t utf8_string_length(const uint8_t *start, const uint8_t *end) {
  ssize_t non_start_count = 0;
  const uint8_t *p = start;
  while ((uintptr_t)(p) & (sizeof(uintptr_t) - 1) && p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  while (p < (end - sizeof(uintptr_t))) {
    uintptr_t w = *(uintptr_t *)(p);
    p += sizeof(uintptr_t);
    non_start_count += utf8_count_non_start_bytes_in_word(w);
  }
  while (p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  return end - start - non_start_count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf8_string_length>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  and    $0x7,%edi
  je     L25
  cmp    %rsi,%r13
  jb     L64
  jmp    L25
  nopl   0x0(%rax)
L55:
  cmp    %rbx,%r14
  jbe    L25
L64:
  mov    (%rbx),%edx
  xor    %eax,%eax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  sete   %al
  add    $0x4,%rbx
  add    %rax,%rbp
  test   $0x7,%bl
  jne    L55
L25:
  lea    -0x20(%r14),%r15
  cmp    %rbx,%r15
  jbe    L14
  mov    %rbx,%r12
L5:
  mov    (%r12),%rdi
  add    $0x20,%r12
  call   <utf8_count_non_start_bytes_in_word@plt>
  add    %rax,%rbp
  cmp    %r15,%r12
  jb     L5
  lea    -0x21(%r14),%rax
  sub    %rbx,%rax
  and    $0xffffffffffffffe0,%rax
  lea    0x20(%rbx,%rax,1),%rbx
  cmp    %rbx,%r14
  jbe    L3
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rbx),%edx
  xor    %eax,%eax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  sete   %al
  add    $0x4,%rbx
  add    %rax,%rbp
L14:
  cmp    %rbx,%r14
  ja     L22
L3:
  mov    %r14,%rax
  add    $0x8,%rsp
  sub    %r13,%rax
  pop    %rbx
  sar    $0x2,%rax
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t utf8_string_length(const uint8_t *start, const uint8_t *end) {
  ssize_t non_start_count = 0;
  const uint8_t *p = start;
  while ((uintptr_t)(p) & (sizeof(uintptr_t) - 1) && p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  while (p < (end - sizeof(uintptr_t))) {
    uintptr_t w = *(uintptr_t *)(p);
    p += sizeof(uintptr_t);
    non_start_count += utf8_count_non_start_bytes_in_word(w);
  }
  while (p < end) {
    non_start_count += !((*p & 0xC0) != 0x80);
    ++p;
  }
  return end - start - non_start_count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__fpp_protect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <fpp_mutex_lock@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__fpp_protect_internal@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <fpp_mutex_unlock@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__fpp_protect(void *p) {
  void *ret;
  fpp_mutex_lock();
  ret = __fpp_protect_internal(p);
  fpp_mutex_unlock();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__fpp_protect>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <fpp_mutex_lock@plt>
  mov    %rbx,%rdi
  call   <__fpp_protect_internal@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <fpp_mutex_unlock@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *__fpp_protect(void *p) {
  void *ret;
  fpp_mutex_lock();
  ret = __fpp_protect_internal(p);
  fpp_mutex_unlock();
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__fpp_protect>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <fpp_mutex_lock@plt>
  mov    %r12,%rdi
  call   <__fpp_protect_internal@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <fpp_mutex_unlock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *__fpp_protect(void *p) {
  void *ret;
  fpp_mutex_lock();
  ret = __fpp_protect_internal(p);
  fpp_mutex_unlock();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__fpp_protect>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <fpp_mutex_lock@plt>
  mov    %r12,%rdi
  call   <__fpp_protect_internal@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <fpp_mutex_unlock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *__fpp_protect(void *p) {
  void *ret;
  fpp_mutex_lock();
  ret = __fpp_protect_internal(p);
  fpp_mutex_unlock();
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<I2CFIFODataPutNonBlocking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xf08,%eax
  cltq
  mov    (%rax),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L2
  mov    $0x0,%eax
  jmp    L15
L2:
  mov    -0x4(%rbp),%eax
  add    $0xf00,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x1,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t I2CFIFODataPutNonBlocking(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
    return (0);
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
    return (1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<I2CFIFODataPutNonBlocking>:
  endbr64
  lea    0xf08(%rdi),%eax
  cltq
  mov    (%rax),%rdx
  mov    $0x0,%eax
  test   $0x2,%dl
  jne    L2
  add    $0xf00,%edi
  movslq %edi,%rdi
  mov    %rsi,(%rdi)
  mov    $0x1,%eax
L2:
  ret
```

assistant: ```c
uint32_t I2CFIFODataPutNonBlocking(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
    return (0);
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
    return (1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<I2CFIFODataPutNonBlocking>:
  endbr64
  lea    0xf08(%rdi),%eax
  cltq
  mov    (%rax),%rdx
  xor    %eax,%eax
  and    $0x2,%edx
  jne    L5
  add    $0xf00,%edi
  mov    $0x1,%eax
  movslq %edi,%rdi
  mov    %rsi,(%rdi)
L5:
  ret
```

assistant: ```c
uint32_t I2CFIFODataPutNonBlocking(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
    return (0);
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
    return (1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<I2CFIFODataPutNonBlocking>:
  endbr64
  lea    0xf08(%rdi),%eax
  cltq
  mov    (%rax),%rdx
  xor    %eax,%eax
  and    $0x2,%edx
  jne    L8
  add    $0xf00,%edi
  mov    $0x1,%eax
  movslq %edi,%rdi
  mov    %rsi,(%rdi)
L8:
  ret
```

assistant: ```c
uint32_t I2CFIFODataPutNonBlocking(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
    return (0);
  } else {
    (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
    return (1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<higher_prime_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L2:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x3,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L10
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L33
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: 

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: Translate the below assembly code into C programming language:

```asm
<higher_prime_number>:
  endbr64
  lea    D0(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
L35:
  cmp    %rdx,%rcx
  je     L16
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  sar    $0x3,%rsi
  shr    $0x3f,%rax
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L23
  mov    %rax,%rcx
  jmp    L35
L23:
  lea    0x8(%rax),%rdx
  jmp    L35
L16:
  mov    (%rdx),%rax
  ret
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<higher_prime_number>:
  endbr64
  lea    D2(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
  jmp    L31
  nopl   0x0(%rax)
L3:
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rax
  sar    $0x3,%rsi
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L17
  mov    %rax,%rcx
L31:
  cmp    %rdx,%rcx
  jne    L3
  mov    (%rcx),%rax
  ret
  nopl   0x0(%rax)
L17:
  lea    0x8(%rax),%rdx
  jmp    L31
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<higher_prime_number>:
  endbr64
  lea    D9(%rip),%rcx
  lea    -0xf0(%rcx),%rdx
  jmp    L13
  nopl   0x0(%rax)
L2:
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  shr    $0x3f,%rax
  sar    $0x3,%rsi
  add    %rsi,%rax
  sar    %rax
  lea    (%rdx,%rax,8),%rax
  cmp    %rdi,(%rax)
  jb     L15
  mov    %rax,%rcx
L13:
  cmp    %rdx,%rcx
  jne    L2
  mov    (%rcx),%rax
  ret
  nopl   0x0(%rax)
L15:
  lea    0x8(%rax),%rdx
  jmp    L13
```

assistant: ```c
unsigned long higher_prime_number(unsigned long n) {
  static const unsigned long primes[] = {
      (unsigned long)7, (unsigned long)13, (unsigned long)31, (unsigned long)61, (unsigned long)127, (unsigned long)251, (unsigned long)509, (unsigned long)1021, (unsigned long)2039, (unsigned long)4093, (unsigned long)8191, (unsigned long)16381, (unsigned long)32749, (unsigned long)65521, (unsigned long)131071, (unsigned long)262139, (unsigned long)524287, (unsigned long)1048573, (unsigned long)2097143, (unsigned long)4194301, (unsigned long)8388593, (unsigned long)16777213, (unsigned long)33554393, (unsigned long)67108859, (unsigned long)134217689, (unsigned long)268435399, (unsigned long)536870909, (unsigned long)1073741789, (unsigned long)2147483647, ((unsigned long)2147483647) + ((unsigned long)2147483644),
  };
  const unsigned long *low = &primes[0];
  const unsigned long *high = &primes[sizeof(primes) / sizeof(primes[0])];
  while (low != high) {
    const unsigned long *mid = low + (high - low) / 2;
    if (n > *mid)
      low = mid + 1;
    else
      high = mid;
  }
  return *low;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0xa,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x6,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L22
L27:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L22:
  mov    -0x34(%rbp),%eax
  cmp    $0x6,%eax
  jbe    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: %d	

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  merge_sort(nums, 0, sizeof(nums) / sizeof(nums[0]) - 1);
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0xa,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x6,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <merge_sort@plt>
  lea    0x1c(%rsp),%r12
  lea    D9(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d	

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  merge_sort(nums, 0, sizeof(nums) / sizeof(nums[0]) - 1);
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000005,%rax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  movl   $0xa,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x900000002,%rax
  mov    %rax,0x10(%rsp)
  call   <merge_sort@plt>
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: %d	

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  merge_sort(nums, 0, sizeof(nums) / sizeof(nums[0]) - 1);
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x6,%edx
  xor    %esi,%esi
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    D15(%rip),%rax
  mov    %rbx,%rdi
  movl   $0xa,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <merge_sort@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D24
data_type: string
name: unpack_data
arguments: data_tag: D19
data_type: byte[16]
name: unpack_data
arguments: data_tag: D15
data_type: byte[8]

tool: D24: %d	

tool: {"D19": [0x05,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D15": [0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  merge_sort(nums, 0, sizeof(nums) / sizeof(nums[0]) - 1);
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```