user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  mov    -0x64(%rbp),%edx
  mov    -0x68(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,-0x70(%rbp)
  cmpl   $0x0,-0x70(%rbp)
  jne    L16
  mov    -0x64(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x68(%rbp),%eax
  lea    -0x60(%rbp),%rcx
  mov    $0x50,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x6c(%rbp)
  cmpl   $0x0,-0x6c(%rbp)
  jg     L33
  mov    $0x17,%edx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  jmp    L36
L33:
  mov    $0x17,%edx
  lea    D64(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  mov    -0x6c(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  mov    $0x0,%edi
  call   <exit@plt>
L16:
  mov    -0x68(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x50,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x6c(%rbp)
  mov    -0x64(%rbp),%eax
  mov    -0x6c(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x64(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%edi
  call   <wait@plt>
  mov    $0x19,%edx
  lea    D57(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  mov    -0x6c(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D48
data_type: string
name: parse_data
arguments: tag: D64
data_type: string
name: parse_data
arguments: tag: D49
data_type: string
name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D57
data_type: string
name: parse_data
arguments: tag: D61
data_type: string

tool: D26: ipc[0] = %d ipc[1] =%d 
 

tool: D48: 
Error al leer tuberia

tool: D64: 
Leido de la tuberia: 

tool: D49: , por el proceso hijo, pid %d 


tool: D15: 
Ingrese una cadena de caracteres por consola:

tool: D57: 
Escrito en la tuberia: 

tool: D61: , por el proceso padre, pid %d 


assistant: ```c
int main() {
  int ipc[2], proc;
  int leido;
  char buff[80];
  pipe(ipc);
  printf("ipc[0] = %d ipc[1] =%d \n ", ipc[0], ipc[1]);
  proc = fork();
  if (proc == 0) {
    close(ipc[1]);
    leido = read(ipc[0], buff, sizeof(buff));
    if (leido < 1) {
      write(0, "\nError al leer tuberia", sizeof("\nError al leer tuberia"));
    } else {
      write(0, "\nLeido de la tuberia: ", sizeof("\nLeido de la tuberia: "));
      write(0, buff, leido - 1);
      printf(", por el proceso hijo, pid %d \n", getpid());
    }
    exit(0);
  }
  close(ipc[0]);
  printf("\nIngrese una cadena de caracteres por consola:\n");
  leido = read(0, buff, sizeof(buff));
  write(ipc[1], buff, leido);
  close(ipc[1]);
  wait(NULL);
  write(0, "\nEscrito en la tuberia: ", sizeof("\nEscrito en la tuberia: "));
  write(0, buff, leido - 1);
  printf(", por el proceso padre, pid %d \n", getpid());
  exit(0);
}
```