ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<any_substring>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %ecx,(%rsp)
  mov    %r8,0x18(%rsp)
  mov    (%rdx),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x1,%esi
  mov    $0xff,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L12
L22:
  lea    0x1(%rbx),%r12d
  movslq %ebx,%rbx
  movb   $0x82,0x0(%r13,%rbx,1)
L41:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%r12),%r15d
  movslq %r12d,%r12
  mov    %al,0x0(%r13,%r12,1)
  movslq %r15d,%rdi
  add    %r13,%rdi
  mov    %eax,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    %r15d,%ebx
  add    $0x1,%r14d
  mov    $0x0,%ebp
L12:
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L46
  mov    (%rsp),%eax
  sub    $0x1,%eax
  cmp    %r14d,%eax
  je     L22
  lea    0x1(%rbx),%r12d
  movslq %ebx,%rbx
  movb   $0x81,0x0(%r13,%rbx,1)
  jmp    L41
L46:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%ebx
  cltq
  mov    0x8(%rsp),%r15
  mov    %dl,(%r15,%rax,1)
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  movslq %ebx,%rdi
  add    %r15,%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  test   %r14d,%r14d
  jle    L8
  mov    0x18(%rsp),%rax
  movslq (%rax),%rax
  lea    -0x2(%rbx),%edx
  mov    %dl,(%r15,%rax,1)
L8:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    %ebx,(%rax)
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: *

assistant: ```c
int any_substring(char *filt_p, char *b_filt, int *filt_len, int count_sub, int *edit_len) {
  char *sub_p;
  int len_filt = *filt_len;
  int index_sub = 0, index_of_temp_sub = 0;
  int len = 0;
  char *temp_sub = (char *)calloc(255, sizeof(char));
  sub_p = filt_p;
  int loop_num = 0;
  while ((sub_p = strtok(sub_p, "*")) != NULL) {
    if (index_sub == count_sub - 1) {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x82;
    } else {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x81;
    }
    len = (int)strlen(sub_p);
    temp_sub[index_of_temp_sub++] = len;
    memcpy(&temp_sub[index_of_temp_sub], sub_p, len);
    index_of_temp_sub += len;
    ++index_sub;
    sub_p = NULL;
  }
  b_filt[len_filt++] = strlen(temp_sub);
  memcpy(&b_filt[len_filt], temp_sub, strlen(temp_sub));
  len_filt += strlen(temp_sub);
  if (loop_num > 0) {
    b_filt[*edit_len] = (len_filt - 2);
  }
  free(temp_sub);
  *filt_len = len_filt;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<any_substring>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xff,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    (%rdx),%eax
  mov    %rsi,0x8(%rsp)
  mov    $0x1,%esi
  mov    %rdx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %eax,0x4(%rsp)
  call   <calloc@plt>
  mov    %rax,%r12
  lea    -0x1(%r14),%eax
  mov    %eax,(%rsp)
  jmp    L14
  nopl   (%rax)
L26:
  cmp    %r13d,(%rsp)
  movslq %ebx,%rdx
  lea    0x1(%rbx),%ebp
  mov    %r14,%rdi
  sete   %al
  movslq %ebp,%rbp
  add    $0x2,%ebx
  add    $0x1,%r13d
  sub    $0x7f,%eax
  mov    %al,(%r12,%rdx,1)
  call   <strlen@plt>
  movslq %ebx,%rdi
  mov    %r14,%rsi
  mov    %al,(%r12,%rbp,1)
  mov    %eax,%r15d
  add    %r12,%rdi
  mov    %eax,%edx
  add    %r15d,%ebx
  xor    %ebp,%ebp
  call   <memcpy@plt>
L14:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L26
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%r15
  mov    %r12,%rdi
  mov    %eax,%r8d
  movslq 0x4(%rsp),%rax
  mov    %r8b,(%r15,%rax,1)
  lea    0x1(%rax),%ebx
  call   <strlen@plt>
  movslq %ebx,%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  add    %r15,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  test   %r13d,%r13d
  je     L27
  mov    0x18(%rsp),%rax
  lea    -0x2(%rbx),%edx
  movslq (%rax),%rax
  mov    %dl,(%r15,%rax,1)
L27:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    %ebx,(%rax)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: *

assistant: ```c
int any_substring(char *filt_p, char *b_filt, int *filt_len, int count_sub, int *edit_len) {
  char *sub_p;
  int len_filt = *filt_len;
  int index_sub = 0, index_of_temp_sub = 0;
  int len = 0;
  char *temp_sub = (char *)calloc(255, sizeof(char));
  sub_p = filt_p;
  int loop_num = 0;
  while ((sub_p = strtok(sub_p, "*")) != NULL) {
    if (index_sub == count_sub - 1) {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x82;
    } else {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x81;
    }
    len = (int)strlen(sub_p);
    temp_sub[index_of_temp_sub++] = len;
    memcpy(&temp_sub[index_of_temp_sub], sub_p, len);
    index_of_temp_sub += len;
    ++index_sub;
    sub_p = NULL;
  }
  b_filt[len_filt++] = strlen(temp_sub);
  memcpy(&b_filt[len_filt], temp_sub, strlen(temp_sub));
  len_filt += strlen(temp_sub);
  if (loop_num > 0) {
    b_filt[*edit_len] = (len_filt - 2);
  }
  free(temp_sub);
  *filt_len = len_filt;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<any_substring>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xff,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    (%rdx),%eax
  mov    %rsi,0x8(%rsp)
  mov    $0x1,%esi
  mov    %rdx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %eax,0x4(%rsp)
  call   <calloc@plt>
  mov    %rax,%r12
  lea    -0x1(%r14),%eax
  mov    %eax,(%rsp)
  jmp    L17
  nopl   (%rax)
L18:
  cmp    %r13d,(%rsp)
  movslq %ebx,%rdx
  lea    0x1(%rbx),%ebp
  mov    %r14,%rdi
  sete   %al
  movslq %ebp,%rbp
  add    $0x2,%ebx
  add    $0x1,%r13d
  sub    $0x7f,%eax
  mov    %al,(%r12,%rdx,1)
  call   <strlen@plt>
  movslq %ebx,%rdi
  mov    %r14,%rsi
  mov    %al,(%r12,%rbp,1)
  mov    %eax,%r15d
  add    %r12,%rdi
  mov    %eax,%edx
  add    %r15d,%ebx
  xor    %ebp,%ebp
  call   <memcpy@plt>
L17:
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L18
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%r15
  mov    %r12,%rdi
  mov    %eax,%r8d
  movslq 0x4(%rsp),%rax
  mov    %r8b,(%r15,%rax,1)
  lea    0x1(%rax),%ebx
  call   <strlen@plt>
  movslq %ebx,%rdi
  mov    %r12,%rsi
  mov    %eax,%edx
  add    %r15,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  test   %r13d,%r13d
  je     L0
  mov    0x18(%rsp),%rax
  lea    -0x2(%rbx),%edx
  movslq (%rax),%rax
  mov    %dl,(%r15,%rax,1)
L0:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rax
  mov    %ebx,(%rax)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: *

assistant: ```c
int any_substring(char *filt_p, char *b_filt, int *filt_len, int count_sub, int *edit_len) {
  char *sub_p;
  int len_filt = *filt_len;
  int index_sub = 0, index_of_temp_sub = 0;
  int len = 0;
  char *temp_sub = (char *)calloc(255, sizeof(char));
  sub_p = filt_p;
  int loop_num = 0;
  while ((sub_p = strtok(sub_p, "*")) != NULL) {
    if (index_sub == count_sub - 1) {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x82;
    } else {
      ++loop_num;
      temp_sub[index_of_temp_sub++] = 0x81;
    }
    len = (int)strlen(sub_p);
    temp_sub[index_of_temp_sub++] = len;
    memcpy(&temp_sub[index_of_temp_sub], sub_p, len);
    index_of_temp_sub += len;
    ++index_sub;
    sub_p = NULL;
  }
  b_filt[len_filt++] = strlen(temp_sub);
  memcpy(&b_filt[len_filt], temp_sub, strlen(temp_sub));
  len_filt += strlen(temp_sub);
  if (loop_num > 0) {
    b_filt[*edit_len] = (len_filt - 2);
  }
  free(temp_sub);
  *filt_len = len_filt;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L26
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  js     L5
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L30
L5:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  nop
  pop    %rbp
  ret
```

assistant: ```c
int insertionSort(int arr[], int n) {
  int i, key, j;
  for (i = 1; i < n; i++) {
    key = arr[i];
    j = i - 1;
    while (j >= 0 && arr[j] > key) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = key;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertionSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L61
L22:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L1
L61:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L22
L13:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L22
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L13
  jmp    L22
L1:
  ret
```

assistant: ```c
int insertionSort(int arr[], int n) {
  int i, key, j;
  for (i = 1; i < n; i++) {
    key = arr[i];
    j = i - 1;
    while (j >= 0 && arr[j] > key) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = key;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertionSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L17
L7:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L5
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L37
  mov    %rdi,%rax
L2:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L7
L17:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L2
```

assistant: ```c
int insertionSort(int arr[], int n) {
  int i, key, j;
  for (i = 1; i < n; i++) {
    key = arr[i];
    j = i - 1;
    while (j >= 0 && arr[j] > key) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = key;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<insertionSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L27
L35:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L48:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L46
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L48
  mov    %rdi,%rax
L23:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L35
L27:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L23
```

assistant: ```c
int insertionSort(int arr[], int n) {
  int i, key, j;
  for (i = 1; i < n; i++) {
    key = arr[i];
    j = i - 1;
    while (j >= 0 && arr[j] > key) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = key;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  cmpl   $0x1,-0x4(%rbp)
  je     L56
  jmp    L1
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <split_h@plt>
  test   %eax,%eax
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <split_v@plt>
  jmp    L14
L56:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <split_v@plt>
  test   %eax,%eax
  jne    L50
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <split_h@plt>
  jmp    L50
L14:
  nop
  jmp    L1
L50:
  nop
L1:
  nop
  leave
  ret
```

assistant: ```c
void split(struct node *cnode) {
  int direction = 0;
  direction = rand() % 2;
  switch (direction) {
  case 0:
    if (!split_h(cnode))
      split_v(cnode);
    break;
  case 1:
    if (!split_v(cnode))
      split_h(cnode);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<split>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  test   $0x1,%al
  je     L51
  cmp    $0x1,%edx
  je     L33
L10:
  pop    %rbx
  ret
L51:
  mov    %rbx,%rdi
  call   <split_h@plt>
  test   %eax,%eax
  jne    L10
  mov    %rbx,%rdi
  call   <split_v@plt>
  jmp    L10
L33:
  mov    %rbx,%rdi
  call   <split_v@plt>
  test   %eax,%eax
  jne    L10
  mov    %rbx,%rdi
  call   <split_h@plt>
  jmp    L10
```

assistant: ```c
void split(struct node *cnode) {
  int direction = 0;
  direction = rand() % 2;
  switch (direction) {
  case 0:
    if (!split_h(cnode))
      split_v(cnode);
    break;
  case 1:
    if (!split_v(cnode))
      split_h(cnode);
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<split>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <rand@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  test   $0x1,%al
  je     L18
  cmp    $0x1,%edx
  jne    L29
  mov    %rbp,%rdi
  call   <split_v@plt>
  test   %eax,%eax
  je     L37
L29:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  call   <split_h@plt>
  test   %eax,%eax
  jne    L29
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <split_v@plt>
  nopl   (%rax)
L37:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <split_h@plt>
```

assistant: ```c
void split(struct node *cnode) {
  int direction = 0;
  direction = rand() % 2;
  switch (direction) {
  case 0:
    if (!split_h(cnode))
      split_v(cnode);
    break;
  case 1:
    if (!split_v(cnode))
      split_h(cnode);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <rand@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  test   $0x1,%al
  je     L27
  cmp    $0x1,%edx
  jne    L34
  mov    %rbp,%rdi
  call   <split_v@plt>
  test   %eax,%eax
  je     L37
L34:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdi
  call   <split_h@plt>
  test   %eax,%eax
  jne    L34
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <split_v@plt>
  nopl   (%rax)
L37:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <split_h@plt>
```

assistant: ```c
void split(struct node *cnode) {
  int direction = 0;
  direction = rand() % 2;
  switch (direction) {
  case 0:
    if (!split_h(cnode))
      split_v(cnode);
    break;
  case 1:
    if (!split_v(cnode))
      split_h(cnode);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__dup2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L46
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L4
L46:
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L24
  mov    $0xffffffff,%eax
  jmp    L4
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L37
  mov    -0x18(%rbp),%eax
  jmp    L4
L37:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    D29(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
L4:
  leave
  ret
```

assistant: ```c
int __dup2(int fd, int fd2) {
  int save;
  if (fd2 < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (fcntl(fd, F_GETFL) < 0)
    return -1;
  if (fd == fd2)
    return fd2;
  save = errno;
  (void)close(fd2);
  __set_errno(save);
  return fcntl(fd, F_DUPFD, fd2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__dup2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  js     L27
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L18
  mov    %ebx,%eax
  cmp    %ebx,%ebp
  je     L41
  mov    D10(%rip),%rax
  mov    (%rax),%r12d
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r12d,%edi
  call   <__set_errno@plt>
  mov    %ebp,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L41
L18:
  mov    $0xffffffff,%eax
  jmp    L41
```

assistant: ```c
int __dup2(int fd, int fd2) {
  int save;
  if (fd2 < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (fcntl(fd, F_GETFL) < 0)
    return -1;
  if (fd == fd2)
    return fd2;
  save = errno;
  (void)close(fd2);
  __set_errno(save);
  return fcntl(fd, F_DUPFD, fd2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__dup2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %esi,%esi
  js     L24
  mov    D34(%rip),%rax
  mov    %esi,%r12d
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L28
  cmp    %ebp,%r12d
  je     L10
  mov    D39(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%r13d
  call   <close@plt>
  mov    %r13d,%edi
  call   <__set_errno@plt>
  mov    D19(%rip),%rax
  mov    %r12d,%edx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    (%rax),%esi
  pop    %r13
  xor    %eax,%eax
  jmp    1080 <fcntl@plt>
  nop
L10:
  mov    %r12d,%eax
L3:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    D20(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L3
L28:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int __dup2(int fd, int fd2) {
  int save;
  if (fd2 < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (fcntl(fd, F_GETFL) < 0)
    return -1;
  if (fd == fd2)
    return fd2;
  save = errno;
  (void)close(fd2);
  __set_errno(save);
  return fcntl(fd, F_DUPFD, fd2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__dup2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %esi,%esi
  js     L4
  mov    D37(%rip),%rax
  mov    %esi,%r12d
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L16
  cmp    %ebp,%r12d
  je     L46
  mov    D32(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%r13d
  call   <close@plt>
  mov    %r13d,%edi
  call   <__set_errno@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    (%rax),%esi
  pop    %r13
  xor    %eax,%eax
  jmp    1080 <fcntl@plt>
  nop
L46:
  mov    %r12d,%eax
L2:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L16:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int __dup2(int fd, int fd2) {
  int save;
  if (fd2 < 0) {
    __set_errno(EBADF);
    return -1;
  }
  if (fcntl(fd, F_GETFL) < 0)
    return -1;
  if (fd == fd2)
    return fd2;
  save = errno;
  (void)close(fd2);
  __set_errno(save);
  return fcntl(fd, F_DUPFD, fd2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mutexInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ASSERT@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pthread_mutex_init@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x4(%rbp),%eax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <log_error@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: Error pthread_mutex_init()

assistant: ```c
void mutexInit(pthread_mutex_t *mutex, pthread_mutexattr_t *attrs) {
  ASSERT(mutex);
  int r = pthread_mutex_init(mutex, attrs);
  if (r != 0) {
    log_error(r, "Error pthread_mutex_init()");
    abort();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mutexInit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <ASSERT@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pthread_mutex_init@plt>
  test   %eax,%eax
  jne    L11
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D2(%rip),%rsi
  mov    %eax,%edi
  call   <log_error@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: Error pthread_mutex_init()

assistant: ```c
void mutexInit(pthread_mutex_t *mutex, pthread_mutexattr_t *attrs) {
  ASSERT(mutex);
  int r = pthread_mutex_init(mutex, attrs);
  if (r != 0) {
    log_error(r, "Error pthread_mutex_init()");
    abort();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mutexInit>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ASSERT@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pthread_mutex_init@plt>
  test   %eax,%eax
  jne    L9
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L9:
  lea    D0(%rip),%rsi
  mov    %eax,%edi
  call   <log_error@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <abort@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: Error pthread_mutex_init()

assistant: ```c
void mutexInit(pthread_mutex_t *mutex, pthread_mutexattr_t *attrs) {
  ASSERT(mutex);
  int r = pthread_mutex_init(mutex, attrs);
  if (r != 0) {
    log_error(r, "Error pthread_mutex_init()");
    abort();
  }
}
```