ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<glb_fd_setfd>:
  endbr64
  mov    D7(%rip),%rax
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %eax,%eax
  js     L17
  mov    %ebx,%edx
  not    %ebx
  or     %eax,%edx
  and    %eax,%ebx
  test   %ebp,%ebp
  cmove  %ebx,%edx
  cmp    %eax,%edx
  je     L19
  mov    D22(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  test   %rax,%rax
  jns    L19
L17:
  mov    D14(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int glb_fd_setfd(int const fd, int const flag, bool const on) {
  int const old_flags = fcntl(fd, F_GETFD);
  if (old_flags >= 0) {
    int const new_flags = on ? (old_flags | flag) : (old_flags & ~flag);
    if (new_flags == old_flags || fcntl(fd, F_SETFD, new_flags) >= 0)
      return 0;
  }
  return -errno;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mat4_subtract>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  subss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  subss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  subss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  subss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  subss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  subss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  movss  0x24(%rdi),%xmm0
  subss  0x24(%rsi),%xmm0
  movss  %xmm0,0x24(%rdi)
  movss  0x28(%rdi),%xmm0
  subss  0x28(%rsi),%xmm0
  movss  %xmm0,0x28(%rdi)
  movss  0x2c(%rdi),%xmm0
  subss  0x2c(%rsi),%xmm0
  movss  %xmm0,0x2c(%rdi)
  movss  0x30(%rdi),%xmm0
  subss  0x30(%rsi),%xmm0
  movss  %xmm0,0x30(%rdi)
  movss  0x34(%rdi),%xmm0
  subss  0x34(%rsi),%xmm0
  movss  %xmm0,0x34(%rdi)
  movss  0x38(%rdi),%xmm0
  subss  0x38(%rsi),%xmm0
  movss  %xmm0,0x38(%rdi)
  movss  0x3c(%rdi),%xmm0
  subss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
void mat4_subtract(float *dst, float *b) {
  dst[0] = dst[0] - b[0];
  dst[1] = dst[1] - b[1];
  dst[2] = dst[2] - b[2];
  dst[3] = dst[3] - b[3];
  dst[4] = dst[4] - b[4];
  dst[5] = dst[5] - b[5];
  dst[6] = dst[6] - b[6];
  dst[7] = dst[7] - b[7];
  dst[8] = dst[8] - b[8];
  dst[9] = dst[9] - b[9];
  dst[10] = dst[10] - b[10];
  dst[11] = dst[11] - b[11];
  dst[12] = dst[12] - b[12];
  dst[13] = dst[13] - b[13];
  dst[14] = dst[14] - b[14];
  dst[15] = dst[15] - b[15];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat4_subtract>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  subss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  subss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  subss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  subss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  subss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  subss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  movss  0x24(%rdi),%xmm0
  subss  0x24(%rsi),%xmm0
  movss  %xmm0,0x24(%rdi)
  movss  0x28(%rdi),%xmm0
  subss  0x28(%rsi),%xmm0
  movss  %xmm0,0x28(%rdi)
  movss  0x2c(%rdi),%xmm0
  subss  0x2c(%rsi),%xmm0
  movss  %xmm0,0x2c(%rdi)
  movss  0x30(%rdi),%xmm0
  subss  0x30(%rsi),%xmm0
  movss  %xmm0,0x30(%rdi)
  movss  0x34(%rdi),%xmm0
  subss  0x34(%rsi),%xmm0
  movss  %xmm0,0x34(%rdi)
  movss  0x38(%rdi),%xmm0
  subss  0x38(%rsi),%xmm0
  movss  %xmm0,0x38(%rdi)
  movss  0x3c(%rdi),%xmm0
  subss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
void mat4_subtract(float *dst, float *b) {
  dst[0] = dst[0] - b[0];
  dst[1] = dst[1] - b[1];
  dst[2] = dst[2] - b[2];
  dst[3] = dst[3] - b[3];
  dst[4] = dst[4] - b[4];
  dst[5] = dst[5] - b[5];
  dst[6] = dst[6] - b[6];
  dst[7] = dst[7] - b[7];
  dst[8] = dst[8] - b[8];
  dst[9] = dst[9] - b[9];
  dst[10] = dst[10] - b[10];
  dst[11] = dst[11] - b[11];
  dst[12] = dst[12] - b[12];
  dst[13] = dst[13] - b[13];
  dst[14] = dst[14] - b[14];
  dst[15] = dst[15] - b[15];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mat4_subtract>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  subss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  subss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  subss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  subss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  subss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  subss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  movss  0x24(%rdi),%xmm0
  subss  0x24(%rsi),%xmm0
  movss  %xmm0,0x24(%rdi)
  movss  0x28(%rdi),%xmm0
  subss  0x28(%rsi),%xmm0
  movss  %xmm0,0x28(%rdi)
  movss  0x2c(%rdi),%xmm0
  subss  0x2c(%rsi),%xmm0
  movss  %xmm0,0x2c(%rdi)
  movss  0x30(%rdi),%xmm0
  subss  0x30(%rsi),%xmm0
  movss  %xmm0,0x30(%rdi)
  movss  0x34(%rdi),%xmm0
  subss  0x34(%rsi),%xmm0
  movss  %xmm0,0x34(%rdi)
  movss  0x38(%rdi),%xmm0
  subss  0x38(%rsi),%xmm0
  movss  %xmm0,0x38(%rdi)
  movss  0x3c(%rdi),%xmm0
  subss  0x3c(%rsi),%xmm0
  movss  %xmm0,0x3c(%rdi)
  ret
```

assistant: ```c
void mat4_subtract(float *dst, float *b) {
  dst[0] = dst[0] - b[0];
  dst[1] = dst[1] - b[1];
  dst[2] = dst[2] - b[2];
  dst[3] = dst[3] - b[3];
  dst[4] = dst[4] - b[4];
  dst[5] = dst[5] - b[5];
  dst[6] = dst[6] - b[6];
  dst[7] = dst[7] - b[7];
  dst[8] = dst[8] - b[8];
  dst[9] = dst[9] - b[9];
  dst[10] = dst[10] - b[10];
  dst[11] = dst[11] - b[11];
  dst[12] = dst[12] - b[12];
  dst[13] = dst[13] - b[13];
  dst[14] = dst[14] - b[14];
  dst[15] = dst[15] - b[15];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<aOrB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L91
L76:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L132
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L132
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
  jmp    L91
L132:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L75
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L38
L75:
  movl   $0x1,-0x4(%rbp)
  jmp    L38
L18:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L38
L27:
  movl   $0x1,-0x4(%rbp)
  jmp    L38
L91:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
L38:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int aOrB(char a[], int a_i, char b[], int b_i, int val) {
  int ret = 0;
  while (a[a_i] || b[b_i]) {
    if (a[a_i] && b[b_i]) {
      if (a[a_i] == b[b_i] && a[a_i] <= val) {
        a_i++;
        b_i++;
      } else if (a[a_i] < b[b_i]) {
        ret = -1;
        break;
      } else {
        ret = 1;
        break;
      }
    } else if (a[a_i]) {
      ret = -1;
      break;
    } else {
      ret = 1;
      break;
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aOrB>:
  endbr64
  mov    %rdx,%r9
  movslq %ecx,%rcx
  mov    %rcx,%rdx
  movslq %esi,%rsi
  sub    %rcx,%rsi
  add    %rsi,%rdi
  jmp    L48
L14:
  movzbl (%r9,%rdx,1),%ecx
  test   %cl,%cl
  je     L44
  cmp    %al,%cl
  jne    L49
  add    $0x1,%rdx
  movsbl %al,%eax
  cmp    %r8d,%eax
  jg     L2
L48:
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L14
  cmpb   $0x0,(%r9,%rdx,1)
  setne  %al
  movzbl %al,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L49:
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
L44:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int aOrB(char a[], int a_i, char b[], int b_i, int val) {
  int ret = 0;
  while (a[a_i] || b[b_i]) {
    if (a[a_i] && b[b_i]) {
      if (a[a_i] == b[b_i] && a[a_i] <= val) {
        a_i++;
        b_i++;
      } else if (a[a_i] < b[b_i]) {
        ret = -1;
        break;
      } else {
        ret = 1;
        break;
      }
    } else if (a[a_i]) {
      ret = -1;
      break;
    } else {
      ret = 1;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<aOrB>:
  endbr64
  mov    %rdi,%r9
  movslq %esi,%rsi
  mov    %rdx,%rdi
  movsbl (%r9,%rsi,1),%eax
  test   %al,%al
  je     L49
  lea    0x1(%rcx),%edx
  movslq %ecx,%rcx
  sub    %rcx,%rsi
  movslq %edx,%rdx
  add    %r9,%rsi
  nopl   (%rax)
L45:
  movzbl -0x1(%rdi,%rdx,1),%ecx
  test   %cl,%cl
  je     L0
  cmp    %al,%cl
  jne    L6
  cmp    %r8d,%eax
  jg     L31
  mov    %edx,%ecx
  add    $0x1,%rdx
  movsbl -0x1(%rsi,%rdx,1),%eax
  test   %al,%al
  jne    L45
L49:
  movslq %ecx,%rcx
  xor    %eax,%eax
  cmpb   $0x0,(%rdi,%rcx,1)
  setne  %al
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int aOrB(char a[], int a_i, char b[], int b_i, int val) {
  int ret = 0;
  while (a[a_i] || b[b_i]) {
    if (a[a_i] && b[b_i]) {
      if (a[a_i] == b[b_i] && a[a_i] <= val) {
        a_i++;
        b_i++;
      } else if (a[a_i] < b[b_i]) {
        ret = -1;
        break;
      } else {
        ret = 1;
        break;
      }
    } else if (a[a_i]) {
      ret = -1;
      break;
    } else {
      ret = 1;
      break;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aOrB>:
  endbr64
  mov    %rdi,%r9
  movslq %esi,%rsi
  mov    %rdx,%rdi
  movsbl (%r9,%rsi,1),%eax
  test   %al,%al
  je     L0
  lea    0x1(%rcx),%edx
  movslq %ecx,%rcx
  sub    %rcx,%rsi
  movslq %edx,%rdx
  add    %r9,%rsi
  nopl   (%rax)
L38:
  movzbl -0x1(%rdi,%rdx,1),%ecx
  test   %cl,%cl
  je     L39
  cmp    %al,%cl
  jne    L13
  cmp    %r8d,%eax
  jg     L2
  mov    %edx,%ecx
  add    $0x1,%rdx
  movsbl -0x1(%rsi,%rdx,1),%eax
  test   %al,%al
  jne    L38
L0:
  movslq %ecx,%rcx
  xor    %eax,%eax
  cmpb   $0x0,(%rdi,%rcx,1)
  setne  %al
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int aOrB(char a[], int a_i, char b[], int b_i, int val) {
  int ret = 0;
  while (a[a_i] || b[b_i]) {
    if (a[a_i] && b[b_i]) {
      if (a[a_i] == b[b_i] && a[a_i] <= val) {
        a_i++;
        b_i++;
      } else if (a[a_i] < b[b_i]) {
        ret = -1;
        break;
      } else {
        ret = 1;
        break;
      }
    } else if (a[a_i]) {
      ret = -1;
      break;
    } else {
      ret = 1;
      break;
    }
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: %s

assistant: ```c
void ptime(int64_t secs) {
  time_t t;
  t = (time_t)secs;
  printf("%s", ctime(&t));
}
```
user: What is the c source code of the assembly code below?

```asm
<ptime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %s

assistant: ```c
void ptime(int64_t secs) {
  time_t t;
  t = (time_t)secs;
  printf("%s", ctime(&t));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ptime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <ctime@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: %s

assistant: ```c
void ptime(int64_t secs) {
  time_t t;
  t = (time_t)secs;
  printf("%s", ctime(&t));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ptime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  call   <ctime@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %s

assistant: ```c
void ptime(int64_t secs) {
  time_t t;
  t = (time_t)secs;
  printf("%s", ctime(&t));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,0x8(%rsp)
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x1(%rax),%r14
  sub    %rdx,%rcx
  lea    0x1(%rcx),%rbp
  lea    0x10(,%rax,8),%edi
  mov    %edi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
L16:
  mov    $0x1,%eax
  sub    %r12,%rax
  lea    (%rbx,%rax,8),%r15
  imul   %rbp,%r14
  lea    0x8(,%r14,8),%edi
  mov    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  test   %rax,%rax
  je     L19
L11:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  shl    $0x3,%rax
  add    %rax,0x8(%rbx)
  cmp    %r12,%r13
  jle    L2
  shl    $0x3,%rbp
  add    $0x8,%rbx
  lea    (%r15,%r13,8),%rdx
L29:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L29
L2:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <nrerror@plt>
  jmp    L16
L19:
  lea    D12(%rip),%rdi
  call   <nrerror@plt>
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D6: allocation failure 1 in matrix()

tool: D12: allocation failure 2 in matrix()

assistant: ```c
double **dmatrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%edi
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x1(%rcx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L57
L36:
  imul   %rbp,%r15
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%rbx,%rax,8),%r8
  lea    0x8(,%r15,8),%edi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%rbx)
  je     L28
L53:
  mov    $0x1,%edx
  sub    %r14,%rdx
  lea    (%rax,%rdx,8),%rax
  mov    %rax,0x8(%rbx)
  cmp    %r13,%r12
  jle    L24
  lea    0x0(,%rbp,8),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r12,8),%rsi
  nopl   (%rax)
L3:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rax,%rsi
  jne    L3
L24:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L36
L28:
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%rbx),%rax
  mov    0x8(%rsp),%r8
  jmp    L53
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D4: allocation failure 1 in matrix()

tool: D3: allocation failure 2 in matrix()

assistant: ```c
double **dmatrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: What is the c source code of the assembly code below:

```asm
<dmatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  sub    %rdx,%rcx
  push   %r14
  sub    %rdi,%rax
  mov    %rdx,%r14
  push   %r13
  lea    0x1(%rax),%r15
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rax,8),%edi
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L42
L14:
  imul   %rbx,%r15
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    0x0(%r13,%rax,8),%r8
  lea    0x8(,%r15,8),%edi
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  mov    %rax,0x8(%r13)
  je     L34
L23:
  mov    $0x1,%edx
  add    $0x1,%rbp
  sub    %r14,%rdx
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,0x8(%r13)
  cmp    %rbp,%r12
  jl     L46
  lea    0x0(,%rbx,8),%rcx
  lea    (%r8,%rbp,8),%rax
  lea    0x8(%r8,%r12,8),%rsi
  nop
L13:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L13
L46:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L14
L34:
  lea    D12(%rip),%rdi
  call   <nrerror@plt>
  mov    0x8(%r13),%rax
  mov    0x8(%rsp),%r8
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D9: allocation failure 1 in matrix()

tool: D12: allocation failure 2 in matrix()

assistant: ```c
double **dmatrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  double **m;
  m = (double **)malloc((unsigned int)((nrow + 1) * sizeof(double *)));
  if (!m)
    nrerror("allocation failure 1 in matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = (double *)malloc((unsigned int)((nrow * ncol + 1) * sizeof(double)));
  if (!m[nrl])
    nrerror("allocation failure 2 in matrix()");
  m[nrl] += 1;
  m[nrl] -= ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
L2:
  movq   $0x0,-0x10(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L6
  mov    -0x28(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L44
L6:
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x2c(%rbp)
  jmp    L18
L24:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  add    %rax,-0x10(%rbp)
  subl   $0x1,-0x2c(%rbp)
L18:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L24
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L44:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D28
datatype: string
name: parse_data
arguments: tag: D14
datatype: string

tool: D24: %lld%lld

tool: D28: %lld

tool: D14: %lld


assistant: ```c
int main() {
  long long int m, n, sum = 0, x;
  int i;
  while (1) {
    sum = 0;
    scanf("%lld%lld", &n, &m);
    if (n == -1 && m == -1)
      break;
    for (i = n; i >= 1; i--) {
      scanf("%lld", &x);
      sum += (x * i);
    }
    sum *= m;
    printf("%lld\n", sum);
  }
  return 0;
}
```