ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_rotclsr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <emit_lsrs_imm@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <emit_adcs@plt>
  add    $0x8,%rsp
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <emit_adc@plt>
```

assistant: ```c
void emit_rotclsr(int t, int sr) {
  emit_lsrs_imm(sr, 1, sr);
  emit_adcs(t, t, t);
  emit_adc(sr, sr, sr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rysujPlanszeBlokow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L36:
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L9:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x3,%eax
  add    %ecx,%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <rysujBlok@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x4,-0x4(%rbp)
  jbe    L9
  addl   $0x1,-0x8(%rbp)
L32:
  cmpl   $0xd,-0x8(%rbp)
  jbe    L36
  nop
  nop
  leave
  ret
```

assistant: ```c
void rysujPlanszeBlokow(unsigned char *bufferL) {
  unsigned i = 0, j = 0;
  for (i = 0; i < (128 / (7 + 2)); i++)
    for (j = 0; j < 5; j++)
      rysujBlok(bufferL, i * (7 + 2) + 1, j * (3 + 2) + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rysujPlanszeBlokow>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x1,%ebp
  jmp    L17
L27:
  add    $0x9,%ebp
  cmp    $0x7f,%ebp
  je     L28
L17:
  mov    $0x1,%ebx
L1:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <rysujBlok@plt>
  add    $0x5,%ebx
  cmp    $0x1a,%ebx
  jne    L1
  jmp    L27
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rysujPlanszeBlokow(unsigned char *bufferL) {
  unsigned i = 0, j = 0;
  for (i = 0; i < (128 / (7 + 2)); i++)
    for (j = 0; j < 5; j++)
      rysujBlok(bufferL, i * (7 + 2) + 1, j * (3 + 2) + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rysujPlanszeBlokow>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L2:
  mov    $0x1,%ebx
L4:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  add    $0x5,%ebx
  call   <rysujBlok@plt>
  cmp    $0x1a,%ebx
  jne    L4
  add    $0x9,%ebp
  cmp    $0x7f,%ebp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rysujPlanszeBlokow(unsigned char *bufferL) {
  unsigned i = 0, j = 0;
  for (i = 0; i < (128 / (7 + 2)); i++)
    for (j = 0; j < 5; j++)
      rysujBlok(bufferL, i * (7 + 2) + 1, j * (3 + 2) + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rysujPlanszeBlokow>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L3:
  mov    $0x1,%ebx
L6:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  add    $0x5,%ebx
  call   <rysujBlok@plt>
  cmp    $0x1a,%ebx
  jne    L6
  add    $0x9,%ebp
  cmp    $0x7f,%ebp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rysujPlanszeBlokow(unsigned char *bufferL) {
  unsigned i = 0, j = 0;
  for (i = 0; i < (128 / (7 + 2)); i++)
    for (j = 0; j < 5; j++)
      rysujBlok(bufferL, i * (7 + 2) + 1, j * (3 + 2) + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<takeDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  sub    $0x30,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jb     L15
  nop
  leave
  ret
```

assistant: ```c
int takeDigits(char a[], int nums[]) {
  for (unsigned int i = 0; i < strlen(a); i++) {
    nums[i] = a[i] - '0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<takeDigits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  jmp    L17
L15:
  mov    %ebx,%edx
  movsbl 0x0(%rbp,%rdx,1),%eax
  sub    $0x30,%eax
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%ebx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int takeDigits(char a[], int nums[]) {
  for (unsigned int i = 0; i < strlen(a); i++) {
    nums[i] = a[i] - '0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<takeDigits>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  add    $0x1,%ebx
  movsbl 0x0(%rbp,%rdx,1),%eax
  sub    $0x30,%eax
  mov    %eax,(%r12,%rdx,4)
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int takeDigits(char a[], int nums[]) {
  for (unsigned int i = 0; i < strlen(a); i++) {
    nums[i] = a[i] - '0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<takeDigits>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%edx
  add    $0x1,%ebx
  movsbl 0x0(%rbp,%rdx,1),%eax
  sub    $0x30,%eax
  mov    %eax,(%r12,%rdx,4)
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int takeDigits(char a[], int nums[]) {
  for (unsigned int i = 0; i < strlen(a); i++) {
    nums[i] = a[i] - '0';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L11
  lea    D34(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
L11:
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L6
L17:
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rcx,%xmm0
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <fprintf@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D34
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D3:  

tool: 

tool: D12: %s?

tool: D0: %s%f

assistant: ```c
void fout(FILE *out, uint *first, uint known, double value) {
  char *space = " ";
  if (*first) {
    space = "";
    *first = 0;
  }
  if (!known) {
    fprintf(out, "%s?", space);
    return;
  }
  fprintf(out, "%s%f", space, value);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fout>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rax
  cmpq   $0x0,(%rsi)
  je     L25
  movq   $0x0,(%rsi)
  lea    D13(%rip),%rax
L25:
  test   %rdx,%rdx
  je     L3
  mov    %rax,%rdx
  lea    D39(%rip),%rsi
  mov    $0x1,%eax
  call   <fprintf@plt>
L18:
  add    $0x8,%rsp
  ret
L3:
  mov    %rax,%rdx
  lea    D5(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D4:  

tool: 

tool: D39: %s%f

tool: D5: %s?

assistant: ```c
void fout(FILE *out, uint *first, uint known, double value) {
  char *space = " ";
  if (*first) {
    space = "";
    *first = 0;
  }
  if (!known) {
    fprintf(out, "%s?", space);
    return;
  }
  fprintf(out, "%s%f", space, value);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fout>:
  endbr64
  cmpq   $0x0,(%rsi)
  lea    D27(%rip),%r8
  je     L3
  movq   $0x0,(%rsi)
  lea    D9(%rip),%r8
L3:
  test   %rdx,%rdx
  mov    %r8,%rdx
  je     L8
  lea    D28(%rip),%rsi
  mov    $0x1,%eax
  jmp    1050 <fprintf@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D28
type: string
name: disassemble_data
arguments: tag: D38
type: string

tool: D27:  

tool: 

tool: D28: %s%f

tool: D38: %s?

assistant: ```c
void fout(FILE *out, uint *first, uint known, double value) {
  char *space = " ";
  if (*first) {
    space = "";
    *first = 0;
  }
  if (!known) {
    fprintf(out, "%s?", space);
    return;
  }
  fprintf(out, "%s%f", space, value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fout>:
  endbr64
  cmpq   $0x0,(%rsi)
  lea    D39(%rip),%r8
  je     L0
  movq   $0x0,(%rsi)
  lea    D29(%rip),%r8
L0:
  test   %rdx,%rdx
  mov    %r8,%rdx
  je     L7
  lea    D30(%rip),%rsi
  mov    $0x1,%eax
  jmp    1050 <fprintf@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D28(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
data_type: string
name: retrieve_data
arguments: data_tag: D29
data_type: string
name: retrieve_data
arguments: data_tag: D30
data_type: string
name: retrieve_data
arguments: data_tag: D28
data_type: string

tool: D39:  

tool: 

tool: D30: %s%f

tool: D28: %s?

assistant: ```c
void fout(FILE *out, uint *first, uint known, double value) {
  char *space = " ";
  if (*first) {
    space = "";
    *first = 0;
  }
  if (!known) {
    fprintf(out, "%s?", space);
    return;
  }
  fprintf(out, "%s%f", space, value);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strstrnmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strnstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L37
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  jmp    L33
L37:
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
L33:
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L22
L14:
  mov    $0x0,%eax
L22:
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x40(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strstrnmove(char *whither, const char *whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstrnmove>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%rsi
  mov    %rcx,%rbp
  mov    %rcx,%rdx
  mov    %r14,%rdi
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  sub    %r14,%r12
  mov    %r12,%r13
  lea    (%rbx,%r12,1),%r12
L10:
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  mov    %rbp,%rdx
  sub    %r13,%rdx
  lea    (%rbx,%r13,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strnlen@plt>
  mov    %rax,%r13
  jmp    L10
```

assistant: ```c
char *strstrnmove(char *whither, const char *whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<strstrnmove>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  push   %rbx
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %rax,%r14
  sub    %rbp,%r14
  lea    0x0(%r13,%r14,1),%r12
  mov    %r12,%r15
L16:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %r14,%rbx
  call   <memmove@plt>
  mov    %rbx,%rdx
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L8:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rax,%r14
  lea    0x0(%r13,%rax,1),%r15
  jmp    L16
```

assistant: ```c
char *strstrnmove(char *whither, const char *whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strstrnmove>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  push   %rbx
  mov    %rbp,%rdi
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strnstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rax,%r14
  sub    %rbp,%r14
  lea    0x0(%r13,%r14,1),%r12
  mov    %r12,%r15
L19:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %r14,%rbx
  call   <memmove@plt>
  mov    %rbx,%rdx
  mov    %r15,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L6:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strnlen@plt>
  mov    %rax,%r14
  lea    0x0(%r13,%rax,1),%r15
  jmp    L19
```

assistant: ```c
char *strstrnmove(char *whither, const char *whence, const char *restrict str, size_t maxlen) {
  const char *stop = strnstr(whence, str, maxlen);
  size_t n = stop == NULL ? strnlen(whence, maxlen) : (size_t)(stop - whence);
  char *r = stop == NULL ? NULL : (whither + n);
  memmove(whither, whence, n);
  memset(whither + n, 0, maxlen - n);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L21
  addl   $0x1,-0x8(%rbp)
L21:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L4
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned count(char m[], unsigned size, char candidate) {
  unsigned cnt, i;
  for (i = cnt = 0; i < size; i++)
    if (m[i] == candidate)
      cnt++;
  return cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rdi
  mov    $0x0,%eax
L18:
  cmp    %dl,(%rcx)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%eax
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L18
  ret
L3:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned count(char m[], unsigned size, char candidate) {
  unsigned cnt, i;
  for (i = cnt = 0; i < size; i++)
    if (m[i] == candidate)
      cnt++;
  return cnt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count>:
  endbr64
  test   %esi,%esi
  je     L9
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %ecx,%ecx
  cmp    %dl,(%rdi)
  sete   %cl
  add    $0x1,%rdi
  add    %ecx,%eax
  cmp    %rsi,%rdi
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned count(char m[], unsigned size, char candidate) {
  unsigned cnt, i;
  for (i = cnt = 0; i < size; i++)
    if (m[i] == candidate)
      cnt++;
  return cnt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nextseq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <readentry@plt>
  cltq
  leave
  ret
```

assistant: ```c
extern struct Sequence *nextseq(dbase)
struct Database *dbase;
{
  return (readentry(dbase));
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextseq>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <readentry@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern struct Sequence *nextseq(dbase)
struct Database *dbase;
{
  return (readentry(dbase));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nextseq>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readentry@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
extern struct Sequence *nextseq(dbase)
struct Database *dbase;
{
  return (readentry(dbase));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextseq>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <readentry@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
extern struct Sequence *nextseq(dbase)
struct Database *dbase;
{
  return (readentry(dbase));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_user_name_to_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <crc16@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned short _user_name_to_hash(const char *username) {
  char buf[40];
  strcpy(buf, username);
  return crc16(buf, strlen(buf));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_user_name_to_hash>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <crc16@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short _user_name_to_hash(const char *username) {
  char buf[40];
  strcpy(buf, username);
  return crc16(buf, strlen(buf));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_user_name_to_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <crc16@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short _user_name_to_hash(const char *username) {
  char buf[40];
  strcpy(buf, username);
  return crc16(buf, strlen(buf));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_user_name_to_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <crc16@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short _user_name_to_hash(const char *username) {
  char buf[40];
  strcpy(buf, username);
  return crc16(buf, strlen(buf));
}
```