ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<LucasLehmerTest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    $0x4,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init_set_ui@plt>
  cmp    $0x2,%r12d
  jle    L1
  mov    $0x2,%ebp
L13:
  mov    $0x0,%ebx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mod@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jne    L13
L1:
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_cmp_ui@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  test   %rbp,%rbp
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int LucasLehmerTest(mpz_t m, int p) {
  int i, ret;
  mpz_t s;
  mpz_init_set_ui(s, 4);
  for (i = 2; i <= p - 1; i++) {
    mpz_mul(s, s, s);
    mpz_sub_ui(s, s, 2);
    mpz_mod(s, s, m);
  }
  ret = (mpz_cmp_ui(s, 0) == 0);
  mpz_clear(s);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LucasLehmerTest>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpz_init_set_ui@plt>
  cmp    $0x2,%r12d
  jle    L6
  mov    $0x2,%ebx
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %ebp,%ebp
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_sub_ui@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mod@plt>
  cmp    %ebx,%r12d
  jne    L15
L6:
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <mpz_cmp_ui@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <mpz_clear@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int LucasLehmerTest(mpz_t m, int p) {
  int i, ret;
  mpz_t s;
  mpz_init_set_ui(s, 4);
  for (i = 2; i <= p - 1; i++) {
    mpz_mul(s, s, s);
    mpz_sub_ui(s, s, 2);
    mpz_mod(s, s, m);
  }
  ret = (mpz_cmp_ui(s, 0) == 0);
  mpz_clear(s);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LucasLehmerTest>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpz_init_set_ui@plt>
  cmp    $0x2,%r12d
  jle    L11
  mov    $0x2,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %ebp,%ebp
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    $0x2,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_sub_ui@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_mod@plt>
  cmp    %ebx,%r12d
  jne    L18
L11:
  xor    %ebp,%ebp
  xor    %esi,%esi
  mov    %ebp,%edi
  call   <mpz_cmp_ui@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <mpz_clear@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int LucasLehmerTest(mpz_t m, int p) {
  int i, ret;
  mpz_t s;
  mpz_init_set_ui(s, 4);
  for (i = 2; i <= p - 1; i++) {
    mpz_mul(s, s, s);
    mpz_sub_ui(s, s, 2);
    mpz_mod(s, s, m);
  }
  ret = (mpz_cmp_ui(s, 0) == 0);
  mpz_clear(s);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sethostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    $0x1a4,%esi
  mov    %eax,%edi
  call   <openhostname@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L1
  mov    $0xffffffff,%eax
  jmp    L22
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %rax,-0x20(%rbp)
  je     L23
  mov    $0xffffffff,%eax
  jmp    L22
L23:
  mov    -0x4(%rbp),%eax
  mov    $0x1a4,%esi
  mov    %eax,%edi
  call   <fchmod@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  int fd = openhostname(O_TRUNC | O_CREAT, 0644);
  if (fd == -1)
    return -1;
  if (write(fd, name, len) != len)
    return -1;
  fchmod(fd, 0644);
  close(fd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sethostname>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  mov    D13(%rip),%rax
  or     (%rax),%edi
  mov    $0x1a4,%esi
  call   <openhostname@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L27
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %rbp,%rax
  jne    L23
  mov    $0x1a4,%esi
  mov    %ebx,%edi
  call   <fchmod@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%ebx
L27:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%ebx
  jmp    L27
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  int fd = openhostname(O_TRUNC | O_CREAT, 0644);
  if (fd == -1)
    return -1;
  if (write(fd, name, len) != len)
    return -1;
  fchmod(fd, 0644);
  close(fd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sethostname>:
  endbr64
  mov    D12(%rip),%rax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rax),%edi
  mov    %rsi,%rbx
  mov    $0x1a4,%esi
  mov    D2(%rip),%rax
  or     (%rax),%edi
  call   <openhostname@plt>
  cmp    $0xffffffff,%eax
  je     L24
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <write@plt>
  cmp    %rbx,%rax
  jne    L24
  mov    $0x1a4,%esi
  mov    %ebp,%edi
  call   <fchmod@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L24:
  mov    $0xffffffff,%eax
  jmp    L8
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  int fd = openhostname(O_TRUNC | O_CREAT, 0644);
  if (fd == -1)
    return -1;
  if (write(fd, name, len) != len)
    return -1;
  fchmod(fd, 0644);
  close(fd);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sethostname>:
  endbr64
  mov    D2(%rip),%rax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rax),%edi
  mov    %rsi,%rbx
  mov    $0x1a4,%esi
  mov    D12(%rip),%rax
  or     (%rax),%edi
  call   <openhostname@plt>
  cmp    $0xffffffff,%eax
  je     L11
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <write@plt>
  cmp    %rbx,%rax
  jne    L11
  mov    $0x1a4,%esi
  mov    %ebp,%edi
  call   <fchmod@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L11:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  int fd = openhostname(O_TRUNC | O_CREAT, 0644);
  if (fd == -1)
    return -1;
  if (write(fd, name, len) != len)
    return -1;
  fchmod(fd, 0644);
  close(fd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lsmod_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lsmod_name(char *input_line, char *mod_name) {
  int i = 0;
  while (input_line[i] != ' ') {
    mod_name[i] = input_line[i];
    i++;
  }
  mod_name[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lsmod_name>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L7
  mov    $0x0,%eax
L10:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L10
L13:
  movb   $0x0,(%rsi,%rax,1)
  ret
L7:
  mov    $0x0,%eax
  jmp    L13
```

assistant: ```c
void lsmod_name(char *input_line, char *mod_name) {
  int i = 0;
  while (input_line[i] != ' ') {
    mod_name[i] = input_line[i];
    i++;
  }
  mod_name[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lsmod_name>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L9
  xor    %eax,%eax
  xchg   %ax,%ax
L7:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L7
  add    %rax,%rsi
L9:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void lsmod_name(char *input_line, char *mod_name) {
  int i = 0;
  while (input_line[i] != ' ') {
    mod_name[i] = input_line[i];
    i++;
  }
  mod_name[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lsmod_name>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L17
  xor    %eax,%eax
  xchg   %ax,%ax
L14:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L14
  add    %rax,%rsi
L17:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void lsmod_name(char *input_line, char *mod_name) {
  int i = 0;
  while (input_line[i] != ' ') {
    mod_name[i] = input_line[i];
    i++;
  }
  mod_name[i] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_196_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_196_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = T | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_196_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  or     $0xffffff00,%eax
  mov    %edi,%edx
  not    %edx
  and    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_196_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = T | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_196_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  or     $0xffffff00,%eax
  not    %edx
  and    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_196_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = T | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_196_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  or     $0xffffff00,%eax
  not    %edx
  and    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_196_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~D;
  stk2 = T | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_be_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L21
  mov    $0x1,%eax
  jmp    L22
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int read_be_uint32(FILE *fp, uint32_t *ptr) {
  uint32_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohl(lv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_be_uint32>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  je     L17
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint32(FILE *fp, uint32_t *ptr) {
  uint32_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohl(lv);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_be_uint32>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L24
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L26
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint32(FILE *fp, uint32_t *ptr) {
  uint32_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohl(lv);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_be_uint32>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x1,%edx
  mov    $0x4,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  je     L24
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  jmp    L10
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_be_uint32(FILE *fp, uint32_t *ptr) {
  uint32_t lv;
  if (fread(&lv, sizeof(lv), 1, fp) != 1) {
    return 1;
  }
  *ptr = ntohl(lv);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dub_rot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    %ecx,%edx
  movslq %esi,%r9
  lea    0x4(,%r9,4),%rbx
  lea    (%rax,%rbx,1),%r11
  mov    (%r11),%ecx
  movslq %edi,%rbp
  movslq %edx,%rdx
  mov    %rbp,%r8
  sub    %rdx,%r8
  lea    0x4(%rax,%r8,4),%r15
  mov    (%r15),%r8d
  movslq %r8d,%r10
  lea    0x1(%rdx),%r14
  lea    (%r10,%r14,1),%r12
  lea    (%rax,%r12,4),%r12
  mov    (%r12),%r13d
  mov    %r13d,(%r15)
  test   %r13d,%r13d
  je     L25
  movslq %r13d,%r13
  mov    %edi,0x4(%rax,%r13,4)
L25:
  mov    %r10,%r13
  sub    %rdx,%r13
  lea    0x4(%rax,%r13,4),%r13
  mov    0x0(%r13),%edx
  add    %r14,%r9
  mov    %edx,(%rax,%r9,4)
  test   %edx,%edx
  je     L3
  movslq %edx,%rdx
  mov    %esi,0x4(%rax,%rdx,4)
L3:
  mov    %edi,(%r12)
  mov    %esi,0x0(%r13)
  lea    0xc(,%r10,4),%r9
  lea    (%rax,%r9,1),%rdx
  lea    0xc(,%rbp,4),%r10
  lea    (%rax,%r10,1),%rbp
  mov    0x0(%rbp),%r12d
  mov    %r12d,%edi
  neg    %edi
  cmp    %r12d,(%rdx)
  mov    $0x0,%r12d
  cmovne %r12d,%edi
  mov    %edi,0x0(%rbp)
  lea    0x8(%rax,%rbx,1),%rbx
  mov    (%rbx),%ebp
  mov    %ebp,%edi
  neg    %edi
  cmp    %ebp,(%rdx)
  mov    $0x0,%ebp
  cmovne %ebp,%edi
  mov    %edi,(%rbx)
  movl   $0x0,(%rdx)
  mov    %r8d,-0x8(%rax,%r10,1)
  mov    %r8d,(%r11)
  mov    %ecx,-0x8(%rax,%r9,1)
  test   %ecx,%ecx
  jle    L2
  movslq %ecx,%rcx
  cmp    %esi,(%rax,%rcx,4)
  setne  %dl
  movzbl %dl,%edx
  lea    0x4(%rax,%rcx,4),%rax
  mov    %r8d,-0x4(%rax,%rdx,8)
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    %r8d,0x4(%rax)
  jmp    L32
```

assistant: ```c
void dub_rot(int *root, int parent, int child, int dir) {
  int gparent = *(root + parent + 1);
  int gchild = *(root + child + 1 - dir);
  *(root + child + 1 - dir) = *(root + gchild + 1 + dir);
  if (*(root + gchild + 1 + dir))
    *(root + *(root + gchild + 1 + dir) + 1) = child;
  *(root + parent + 1 + dir) = *(root + gchild + 1 - dir);
  if (*(root + gchild + 1 - dir))
    *(root + *(root + gchild + 1 - dir) + 1) = parent;
  *(root + gchild + 1 + dir) = child;
  *(root + gchild + 1 - dir) = parent;
  if (*(root + gchild + 3) == *(root + child + 3))
    *(root + child + 3) *= -1;
  else
    *(root + child + 3) = 0;
  if (*(root + gchild + 3) == *(root + parent + 3))
    *(root + parent + 3) *= -1;
  else
    *(root + parent + 3) = 0;
  *(root + gchild + 3) = 0;
  *(root + child + 1) = gchild;
  *(root + parent + 1) = gchild;
  *(root + gchild + 1) = gparent;
  if (gparent > 0)
    *(root + gparent + 1 + (*(root + gparent + 1 + -1) == parent ? -1 : 1)) = gchild;
  else
    *(root + 1) = gchild;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dub_rot>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  movslq %esi,%r9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  movslq %ecx,%rdx
  mov    %rbp,%r8
  push   %rbx
  lea    0x1(%rdx),%r14
  lea    0x4(,%r9,4),%rbx
  sub    %rdx,%r8
  lea    (%rax,%rbx,1),%r11
  mov    %rbp,%rdi
  lea    0x4(%rax,%r8,4),%r15
  movslq (%r11),%rcx
  movslq (%r15),%r10
  lea    (%r10,%r14,1),%r12
  mov    %r10,%r8
  lea    (%rax,%r12,4),%r12
  movslq (%r12),%r13
  mov    %r13d,(%r15)
  test   %r13d,%r13d
  je     L32
  mov    %ebp,0x4(%rax,%r13,4)
L32:
  mov    %r10,%r13
  add    %r14,%r9
  sub    %rdx,%r13
  lea    0x4(%rax,%r13,4),%r13
  movslq 0x0(%r13),%rdx
  mov    %edx,(%rax,%r9,4)
  test   %edx,%edx
  je     L30
  mov    %esi,0x4(%rax,%rdx,4)
L30:
  lea    0xc(,%r10,4),%r9
  mov    %edi,(%r12)
  lea    0x8(%rax,%rbx,1),%rbx
  lea    0xc(,%rbp,4),%r10
  mov    %esi,0x0(%r13)
  lea    (%rax,%r9,1),%rdx
  xor    %ebp,%ebp
  lea    (%rax,%r10,1),%r12
  mov    (%r12),%r13d
  mov    %r13d,%edi
  neg    %edi
  cmp    %r13d,(%rdx)
  cmovne %ebp,%edi
  mov    %edi,(%r12)
  mov    (%rbx),%r12d
  mov    %r12d,%edi
  neg    %edi
  cmp    %r12d,(%rdx)
  cmovne %ebp,%edi
  mov    %edi,(%rbx)
  movl   $0x0,(%rdx)
  mov    %r8d,-0x8(%rax,%r10,1)
  mov    %r8d,(%r11)
  mov    %ecx,-0x8(%rax,%r9,1)
  test   %ecx,%ecx
  jle    L17
  lea    (%rax,%rcx,4),%rdx
  lea    0x4(,%rcx,4),%rdi
  cmp    %esi,(%rdx)
  je     L37
  lea    0x4(%rax,%rdi,1),%rdx
L37:
  mov    %r8d,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L17:
  pop    %rbx
  pop    %rbp
  mov    %r8d,0x4(%rax)
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void dub_rot(int *root, int parent, int child, int dir) {
  int gparent = *(root + parent + 1);
  int gchild = *(root + child + 1 - dir);
  *(root + child + 1 - dir) = *(root + gchild + 1 + dir);
  if (*(root + gchild + 1 + dir))
    *(root + *(root + gchild + 1 + dir) + 1) = child;
  *(root + parent + 1 + dir) = *(root + gchild + 1 - dir);
  if (*(root + gchild + 1 - dir))
    *(root + *(root + gchild + 1 - dir) + 1) = parent;
  *(root + gchild + 1 + dir) = child;
  *(root + gchild + 1 - dir) = parent;
  if (*(root + gchild + 3) == *(root + child + 3))
    *(root + child + 3) *= -1;
  else
    *(root + child + 3) = 0;
  if (*(root + gchild + 3) == *(root + parent + 3))
    *(root + parent + 3) *= -1;
  else
    *(root + parent + 3) = 0;
  *(root + gchild + 3) = 0;
  *(root + child + 1) = gchild;
  *(root + parent + 1) = gchild;
  *(root + gchild + 1) = gparent;
  if (gparent > 0)
    *(root + gparent + 1 + (*(root + gparent + 1 + -1) == parent ? -1 : 1)) = gchild;
  else
    *(root + 1) = gchild;
}
```