ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fwriteUpdateSha1>:
  endbr64
  test   %rdi,%rdi
  je     L8
  test   %r8,%r8
  je     L8
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  push   %rbp
  imul   %r12,%rdx
  mov    %rdi,%rbp
  mov    %r8,%rdi
  sub    $0x8,%rsp
  call   <SHA1_Update@plt>
  cmp    $0x1,%eax
  je     L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fwrite@plt>
```

assistant: ```c
size_t fwriteUpdateSha1(const void *p, size_t size, size_t nmemb, FILE *fp, SHA_CTX *c) {
  if (p == NULL || c == NULL)
    return 0;
  if (SHA1_Update(c, p, size * nmemb) != 1)
    return 0;
  return fwrite(p, size, nmemb, fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fwriteUpdateSha1>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %r8,%r8
  je     L10
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  push   %rbp
  imul   %r12,%rdx
  mov    %rdi,%rbp
  mov    %r8,%rdi
  sub    $0x8,%rsp
  call   <SHA1_Update@plt>
  cmp    $0x1,%eax
  je     L29
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fwrite@plt>
```

assistant: ```c
size_t fwriteUpdateSha1(const void *p, size_t size, size_t nmemb, FILE *fp, SHA_CTX *c) {
  if (p == NULL || c == NULL)
    return 0;
  if (SHA1_Update(c, p, size * nmemb) != 1)
    return 0;
  return fwrite(p, size, nmemb, fp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_strrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%r12d
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  jmp    L1
L25:
  mov    %rbx,%r12
  lea    0x1(%r12),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
L1:
  test   %rbx,%rbx
  jne    L25
L9:
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *my_strrstr(char const *s1, char const *s2) {
  register char *last;
  register char *current;
  last = NULL;
  if (*s2 != '\0') {
    current = strstr(s1, s2);
    while (current != NULL) {
      last = current;
      current = strstr(last + 1, s2);
    }
  }
  return last;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strrstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  cmpb   $0x0,(%rsi)
  je     L25
  mov    %rsi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L19
L14:
  lea    0x1(%rax),%rdi
  mov    %rax,%rbp
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L14
L25:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %rax,%rbp
  jmp    L25
```

assistant: ```c
char *my_strrstr(char const *s1, char const *s2) {
  register char *last;
  register char *current;
  last = NULL;
  if (*s2 != '\0') {
    current = strstr(s1, s2);
    while (current != NULL) {
      last = current;
      current = strstr(last + 1, s2);
    }
  }
  return last;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_strrstr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L24
  mov    %rsi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L24
L17:
  lea    0x1(%rax),%rdi
  mov    %rbx,%rsi
  mov    %rax,%r12
  call   <strstr@plt>
  test   %rax,%rax
  jne    L17
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *my_strrstr(char const *s1, char const *s2) {
  register char *last;
  register char *current;
  last = NULL;
  if (*s2 != '\0') {
    current = strstr(s1, s2);
    while (current != NULL) {
      last = current;
      current = strstr(last + 1, s2);
    }
  }
  return last;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strrstr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L20
  mov    %rsi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L20
L3:
  lea    0x1(%rax),%rdi
  mov    %rbx,%rsi
  mov    %rax,%r12
  call   <strstr@plt>
  test   %rax,%rax
  jne    L3
L20:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *my_strrstr(char const *s1, char const *s2) {
  register char *last;
  register char *current;
  last = NULL;
  if (*s2 != '\0') {
    current = strstr(s1, s2);
    while (current != NULL) {
      last = current;
      current = strstr(last + 1, s2);
    }
  }
  return last;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %esi,-0xec(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd8(%rbp),%rdx
  mov    -0xe8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xd4(%rbp)
  cmpl   $0xffffffff,-0xd4(%rbp)
  je     L70
  cmpl   $0x2,-0xec(%rbp)
  jne    L7
  mov    -0xd8(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%eax
  jmp    L28
L7:
  cmpl   $0x1,-0xec(%rbp)
  jne    L70
  mov    -0xd8(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L70
  mov    $0x1,%eax
  jmp    L28
L70:
  mov    $0x0,%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
int exists(char *fname, int t) {
  struct dirent *e;
  DIR *d;
  char cmd[200];
  struct stat s;
  int err = stat(fname, &s);
  if (err == -1) {
    if (errno == ENOENT) {
    }
  } else {
    if (t == 2) {
      if (S_ISDIR(s.st_mode)) {
        return 1;
      }
    }
    if (t == 1) {
      if (S_ISREG(s.st_mode)) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<exists>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L36
  cmp    $0x2,%ebx
  je     L11
  mov    $0x0,%eax
  cmp    $0x1,%ebx
  je     L17
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x10,%rsp
  pop    %rbx
  ret
L11:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L36
L17:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L36
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname, int t) {
  struct dirent *e;
  DIR *d;
  char cmd[200];
  struct stat s;
  int err = stat(fname, &s);
  if (err == -1) {
    if (errno == ENOENT) {
    }
  } else {
    if (t == 2) {
      if (S_ISDIR(s.st_mode)) {
        return 1;
      }
    }
    if (t == 1) {
      if (S_ISREG(s.st_mode)) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exists>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L47
  cmp    $0x2,%ebx
  je     L13
  cmp    $0x1,%ebx
  je     L17
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L47
  nopl   0x0(%rax)
L13:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L47
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname, int t) {
  struct dirent *e;
  DIR *d;
  char cmd[200];
  struct stat s;
  int err = stat(fname, &s);
  if (err == -1) {
    if (errno == ENOENT) {
    }
  } else {
    if (t == 2) {
      if (S_ISDIR(s.st_mode)) {
        return 1;
      }
    }
    if (t == 1) {
      if (S_ISREG(s.st_mode)) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exists>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L5
  cmp    $0x2,%ebx
  je     L4
  cmp    $0x1,%ebx
  je     L58
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  ret
L58:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L5
  nopl   0x0(%rax)
L4:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int exists(char *fname, int t) {
  struct dirent *e;
  DIR *d;
  char cmd[200];
  struct stat s;
  int err = stat(fname, &s);
  if (err == -1) {
    if (errno == ENOENT) {
    }
  } else {
    if (t == 2) {
      if (S_ISDIR(s.st_mode)) {
        return 1;
      }
    }
    if (t == 1) {
      if (S_ISREG(s.st_mode)) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<muggle_str_find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L135
  cmpq   $0x0,-0x30(%rbp)
  jne    L101
L135:
  mov    $0xffffffff,%eax
  jmp    L105
L101:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  js     L15
  cmpl   $0x0,-0x38(%rbp)
  jns    L50
L15:
  mov    $0xffffffff,%eax
  jmp    L105
L50:
  mov    -0x34(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  ja     L75
  mov    $0xffffffff,%eax
  jmp    L105
L75:
  cmpl   $0x0,-0x38(%rbp)
  jne    L79
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x38(%rbp)
L79:
  mov    -0x18(%rbp),%rax
  cmp    %eax,-0x38(%rbp)
  jle    L119
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x38(%rbp)
L119:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jg     L92
  mov    $0xffffffff,%eax
  jmp    L105
L92:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L138
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  cmp    %rax,%rdx
  jbe    L87
L138:
  mov    $0xffffffff,%eax
  jmp    L105
L87:
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
L105:
  leave
  ret
```

assistant: ```c
int muggle_str_find(const char *str, const char *sub, int start, int end) {
  if (str == NULL || sub == NULL) {
    return -1;
  }
  size_t str_len = strlen(str);
  size_t sub_len = strlen(sub);
  if (start < 0 || end < 0) {
    return -1;
  }
  if (start >= str_len) {
    return -1;
  }
  if (end == 0) {
    end = (int)str_len;
  }
  if (end > (int)str_len) {
    end = (int)str_len;
  }
  if (end <= start) {
    return -1;
  }
  const char *pos = strstr(str + start, sub);
  if (pos == NULL || pos + sub_len > str + end) {
    return -1;
  }
  return (int)(pos - str);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<muggle_str_find>:
  endbr64
  test   %rdi,%rdi
  je     L84
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%ebx
  test   %rsi,%rsi
  je     L46
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %r13d,%eax
  or     %ebx,%eax
  js     L28
  movslq %r13d,%rdi
  cmp    %r15,%rdi
  jae    L73
  test   %ebx,%ebx
  cmove  %r15d,%ebx
  cmp    %r15d,%ebx
  cmovg  %r15d,%ebx
  cmp    %ebx,%r13d
  jge    L14
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L48
  add    %rax,%r14
  movslq %ebx,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%r14
  ja     L91
  sub    %ebp,%eax
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  mov    $0xffffffff,%eax
  jmp    L80
L28:
  mov    $0xffffffff,%eax
  jmp    L80
L73:
  mov    $0xffffffff,%eax
  jmp    L80
L14:
  mov    $0xffffffff,%eax
  jmp    L80
L48:
  mov    $0xffffffff,%eax
  jmp    L80
L91:
  mov    $0xffffffff,%eax
  jmp    L80
L84:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int muggle_str_find(const char *str, const char *sub, int start, int end) {
  if (str == NULL || sub == NULL) {
    return -1;
  }
  size_t str_len = strlen(str);
  size_t sub_len = strlen(sub);
  if (start < 0 || end < 0) {
    return -1;
  }
  if (start >= str_len) {
    return -1;
  }
  if (end == 0) {
    end = (int)str_len;
  }
  if (end > (int)str_len) {
    end = (int)str_len;
  }
  if (end <= start) {
    return -1;
  }
  const char *pos = strstr(str + start, sub);
  if (pos == NULL || pos + sub_len > str + end) {
    return -1;
  }
  return (int)(pos - str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<muggle_str_find>:
  endbr64
  test   %rdi,%rdi
  je     L69
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L64
  mov    %edx,%r15d
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %r15d,%eax
  or     %r13d,%eax
  js     L64
  movslq %r15d,%rdi
  cmp    %rbx,%rdi
  jae    L64
  cmp    %ebx,%r13d
  mov    %ebx,%eax
  cmovle %r13d,%eax
  test   %r13d,%r13d
  cmovne %eax,%ebx
  cmp    %ebx,%r15d
  jge    L64
  add    %rbp,%rdi
  mov    %r14,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L64
  movslq %ebx,%rbx
  add    %rax,%r12
  add    %rbp,%rbx
  cmp    %rbx,%r12
  ja     L64
  sub    %ebp,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    $0xffffffff,%eax
  jmp    L43
L69:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int muggle_str_find(const char *str, const char *sub, int start, int end) {
  if (str == NULL || sub == NULL) {
    return -1;
  }
  size_t str_len = strlen(str);
  size_t sub_len = strlen(sub);
  if (start < 0 || end < 0) {
    return -1;
  }
  if (start >= str_len) {
    return -1;
  }
  if (end == 0) {
    end = (int)str_len;
  }
  if (end > (int)str_len) {
    end = (int)str_len;
  }
  if (end <= start) {
    return -1;
  }
  const char *pos = strstr(str + start, sub);
  if (pos == NULL || pos + sub_len > str + end) {
    return -1;
  }
  return (int)(pos - str);
}
```
user: What is the c source code of the assembly code below:

```asm
<muggle_str_find>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L68
  mov    %edx,%r15d
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %r15d,%eax
  or     %r13d,%eax
  js     L68
  movslq %r15d,%rdi
  cmp    %rbx,%rdi
  jae    L68
  cmp    %ebx,%r13d
  mov    %ebx,%eax
  cmovle %r13d,%eax
  test   %r13d,%r13d
  cmovne %eax,%ebx
  cmp    %ebx,%r15d
  jge    L68
  add    %rbp,%rdi
  mov    %r14,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L68
  movslq %ebx,%rbx
  add    %rax,%r12
  add    %rbp,%rbx
  cmp    %rbx,%r12
  ja     L68
  sub    %ebp,%eax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  mov    $0xffffffff,%eax
  jmp    L33
L9:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int muggle_str_find(const char *str, const char *sub, int start, int end) {
  if (str == NULL || sub == NULL) {
    return -1;
  }
  size_t str_len = strlen(str);
  size_t sub_len = strlen(sub);
  if (start < 0 || end < 0) {
    return -1;
  }
  if (start >= str_len) {
    return -1;
  }
  if (end == 0) {
    end = (int)str_len;
  }
  if (end > (int)str_len) {
    end = (int)str_len;
  }
  if (end <= start) {
    return -1;
  }
  const char *pos = strstr(str + start, sub);
  if (pos == NULL || pos + sub_len > str + end) {
    return -1;
  }
  return (int)(pos - str);
}
```
user: What is the c source code of the assembly code below:

```asm
<init_matrix_repr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L18:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2c,(%rax)
  addl   $0x2,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L18
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void init_matrix_repr(char *repr, unsigned length) {
  assert(length % 2 == 0);
  for (unsigned i = 1; i < length; i += 2) {
    repr[i] = ',';
  }
  repr[length - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_matrix_repr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  xor    $0x1,%edi
  and    $0x1,%edi
  call   <assert@plt>
  cmp    $0x1,%ebx
  jbe    L6
  lea    0x1(%rbp),%rax
  lea    -0x2(%rbx),%edx
  shr    %edx
  mov    %edx,%edx
  lea    0x3(%rbp,%rdx,2),%rdx
L12:
  movb   $0x2c,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L12
L6:
  lea    -0x1(%rbx),%eax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_matrix_repr(char *repr, unsigned length) {
  assert(length % 2 == 0);
  for (unsigned i = 1; i < length; i += 2) {
    repr[i] = ',';
  }
  repr[length - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_matrix_repr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  not    %edi
  mov    %esi,%ebx
  and    $0x1,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  cmp    $0x1,%ebx
  jbe    L11
  lea    -0x2(%rbx),%edx
  lea    0x1(%rbp),%rax
  shr    %edx
  lea    0x3(%rbp,%rdx,2),%rdx
  xchg   %ax,%ax
L9:
  movb   $0x2c,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L9
L11:
  lea    -0x1(%rbx),%eax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_matrix_repr(char *repr, unsigned length) {
  assert(length % 2 == 0);
  for (unsigned i = 1; i < length; i += 2) {
    repr[i] = ',';
  }
  repr[length - 1] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_matrix_repr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  not    %edi
  mov    %esi,%ebx
  and    $0x1,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  cmp    $0x1,%ebx
  jbe    L17
  lea    -0x2(%rbx),%edx
  lea    0x1(%rbp),%rax
  shr    %edx
  lea    0x3(%rbp,%rdx,2),%rdx
  xchg   %ax,%ax
L8:
  movb   $0x2c,(%rax)
  add    $0x2,%rax
  cmp    %rdx,%rax
  jne    L8
L17:
  lea    -0x1(%rbx),%eax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_matrix_repr(char *repr, unsigned length) {
  assert(length % 2 == 0);
  for (unsigned i = 1; i < length; i += 2) {
    repr[i] = ',';
  }
  repr[length - 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Sequential_Search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  jmp    L30
L18:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L0
  mov    $0x0,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int Sequential_Search(int *a, int n, int key) {
  int i;
  for (i = 1; i <= n; i++) {
    if (a[i] == key)
      return i;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Sequential_Search>:
  endbr64
  test   %esi,%esi
  jle    L28
  mov    $0x1,%eax
L25:
  mov    %eax,%ecx
  cmp    %edx,(%rdi,%rax,4)
  je     L37
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L25
  mov    $0x0,%ecx
L37:
  mov    %ecx,%eax
  ret
L28:
  mov    $0x0,%ecx
  jmp    L37
```

assistant: ```c
int Sequential_Search(int *a, int n, int key) {
  int i;
  for (i = 1; i <= n; i++) {
    if (a[i] == key)
      return i;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Sequential_Search>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    $0x1,%eax
  jmp    L22
  nop
L4:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L15
L22:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L4
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Sequential_Search(int *a, int n, int key) {
  int i;
  for (i = 1; i <= n; i++) {
    if (a[i] == key)
      return i;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sequential_Search>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    $0x1,%eax
  jmp    L34
  nop
L31:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L36
L34:
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jne    L31
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L36:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Sequential_Search(int *a, int n, int key) {
  int i;
  for (i = 1; i <= n; i++) {
    if (a[i] == key)
      return i;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<force_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strend@plt>
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *force_extension(char *filename, char *extension) {
  char *p;
  p = strrchr(filename, '.');
  if (!p)
    p = strend(filename);
  strcpy(p, extension);
  return filename;
}
```