ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_banner>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localhost@plt>
  lea    0x10(%rsp),%rdi
  mov    %rax,%rbx
  call   <uname@plt>
  test   %rax,%rax
  je     L1
  mov    0x18(%rsp),%rax
  movb   $0x0,(%rax)
  mov    0x10(%rsp),%rax
  movb   $0x0,(%rax)
L1:
  mov    %r12,%rdi
  call   <basename@plt>
  test   %rbx,%rbx
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  mov    %eax,%r9d
  lea    D8(%rip),%rax
  lea    0x8(%rsp),%rdi
  cmove  %rax,%rbx
  lea    D17(%rip),%rsi
  mov    %rbx,%r8
  call   <asprintf@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string

tool: D8: ?

tool: D17: 

%s %s (%s) (%s)



assistant: ```c
void print_banner(int fd, char *ttyname) {
  int cc;
  char *s;
  struct utsname u;
  char *hostname = localhost();
  if (uname(&u))
    u.sysname[0] = u.release[0] = '\0';
  cc = asprintf(&s, "\r\n\n%s %s (%s) (%s)\r\n\n", u.sysname, u.release, hostname ?: "?", basename(ttyname));
  write(fd, s, cc);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_banner>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localhost@plt>
  lea    0x10(%rsp),%rdi
  mov    %rax,%rbx
  call   <uname@plt>
  test   %rax,%rax
  je     L14
  mov    0x18(%rsp),%rax
  movb   $0x0,(%rax)
  mov    0x10(%rsp),%rax
  movb   $0x0,(%rax)
L14:
  mov    %r12,%rdi
  call   <basename@plt>
  test   %rbx,%rbx
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  mov    %eax,%r9d
  lea    D3(%rip),%rax
  lea    0x8(%rsp),%rdi
  cmove  %rax,%rbx
  lea    D11(%rip),%rsi
  mov    %rbx,%r8
  call   <asprintf@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string

tool: D3: ?

tool: D11: 

%s %s (%s) (%s)



assistant: ```c
void print_banner(int fd, char *ttyname) {
  int cc;
  char *s;
  struct utsname u;
  char *hostname = localhost();
  if (uname(&u))
    u.sysname[0] = u.release[0] = '\0';
  cc = asprintf(&s, "\r\n\n%s %s (%s) (%s)\r\n\n", u.sysname, u.release, hostname ?: "?", basename(ttyname));
  write(fd, s, cc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readMatrixDouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L35
L33:
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addq   $0x1,-0x28(%rbp)
L8:
  mov    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0xffffffff,-0x3c(%rbp)
  jne    L33
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L35:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: r

assistant: ```c
int readMatrixDouble(double *mat, const char *fileName) {
  long i = 0;
  FILE *fp;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  fp = fopen(fileName, "r");
  if (fp == NULL)
    return -1;
  while ((read = getline(&line, &len, fp)) != -1) {
    mat[i] = atof(line);
    i++;
  }
  free(line);
  fclose(fp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readMatrixDouble>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L44
  mov    %rax,%rbp
  lea    0x10(%rsp),%r12
  jmp    L32
L31:
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
L32:
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  jne    L31
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0xffffffff,%eax
  jmp    L10
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: r

assistant: ```c
int readMatrixDouble(double *mat, const char *fileName) {
  long i = 0;
  FILE *fp;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  fp = fopen(fileName, "r");
  if (fp == NULL)
    return -1;
  while ((read = getline(&line, &len, fp)) != -1) {
    mat[i] = atof(line);
    i++;
  }
  free(line);
  fclose(fp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readMatrixDouble>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  lea    D8(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%rbp
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L17:
  call   <atof@plt>
  add    $0x8,%rbx
  movsd  %xmm0,-0x8(%rbx)
L16:
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <getline@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0xffffffff,%eax
  jne    L17
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  mov    $0xffffffff,%eax
  jmp    L2
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: r

assistant: ```c
int readMatrixDouble(double *mat, const char *fileName) {
  long i = 0;
  FILE *fp;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  fp = fopen(fileName, "r");
  if (fp == NULL)
    return -1;
  while ((read = getline(&line, &len, fp)) != -1) {
    mat[i] = atof(line);
    i++;
  }
  free(line);
  fclose(fp);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readMatrixDouble>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  lea    D2(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%rbp
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L27:
  call   <atof@plt>
  add    $0x8,%rbx
  movsd  %xmm0,-0x8(%rbx)
L12:
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <getline@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0xffffffff,%eax
  jne    L27
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L24
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: r

assistant: ```c
int readMatrixDouble(double *mat, const char *fileName) {
  long i = 0;
  FILE *fp;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  fp = fopen(fileName, "r");
  if (fp == NULL)
    return -1;
  while ((read = getline(&line, &len, fp)) != -1) {
    mat[i] = atof(line);
    i++;
  }
  free(line);
  fclose(fp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x2,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x6,-0x10(%rbp)
  jle    L10
  cmpl   $0xc7,-0x24(%rbp)
  jg     L14
  addl   $0x2,-0x28(%rbp)
  jmp    L23
L14:
  addl   $0x4,-0x28(%rbp)
L23:
  mov    $0x0,%eax
  call   <g@plt>
  jmp    L39
L10:
  addl   $0x6,-0x28(%rbp)
L39:
  addl   $0x2,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int f(int c, int i) {
  int a1, a2, a3, x1, x2, x3, x;
  a1 = i * 16;
  x1 = c + a1;
  i = i + 2;
  a2 = i * 16;
  x2 = c + a2;
  if (x2 > 6) {
    if (c < 200)
      i = i + 2;
    else
      i = i + 4;
    g();
  } else
    i = i + 6;
  i = i + 2;
  a3 = i * 16;
  x3 = c + a3;
  x = x1 + x2 + x3;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  shl    $0x4,%esi
  lea    (%rsi,%rdi,1),%ebp
  lea    0x20(%rsi,%rdi,1),%r12d
  lea    0x80(%rsi),%r13d
  cmp    $0x6,%r12d
  jle    L3
  lea    0x40(%rsi),%r13d
  add    $0x60,%esi
  cmp    $0xc7,%edi
  cmovg  %esi,%r13d
  mov    $0x0,%eax
  call   <g@plt>
L3:
  lea    0x20(%r13,%rbx,1),%eax
  add    %r12d,%ebp
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int f(int c, int i) {
  int a1, a2, a3, x1, x2, x3, x;
  a1 = i * 16;
  x1 = c + a1;
  i = i + 2;
  a2 = i * 16;
  x2 = c + a2;
  if (x2 > 6) {
    if (c < 200)
      i = i + 2;
    else
      i = i + 4;
    g();
  } else
    i = i + 6;
  i = i + 2;
  a3 = i * 16;
  x3 = c + a3;
  x = x1 + x2 + x3;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  push   %r13
  shl    $0x4,%esi
  push   %r12
  lea    0x20(%rsi,%rdi,1),%r13d
  lea    0x80(%rsi),%r12d
  push   %rbp
  lea    (%rsi,%rdi,1),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x6,%r13d
  jle    L4
  lea    0x40(%rsi),%r12d
  add    $0x60,%esi
  cmp    $0xc7,%edi
  cmovg  %esi,%r12d
  xor    %eax,%eax
  call   <g@plt>
L4:
  add    $0x8,%rsp
  lea    0x20(%r12,%rbx,1),%eax
  add    %r13d,%ebp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int f(int c, int i) {
  int a1, a2, a3, x1, x2, x3, x;
  a1 = i * 16;
  x1 = c + a1;
  i = i + 2;
  a2 = i * 16;
  x2 = c + a2;
  if (x2 > 6) {
    if (c < 200)
      i = i + 2;
    else
      i = i + 4;
    g();
  } else
    i = i + 6;
  i = i + 2;
  a3 = i * 16;
  x3 = c + a3;
  x = x1 + x2 + x3;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  push   %r13
  shl    $0x4,%esi
  push   %r12
  lea    0x20(%rsi,%rdi,1),%r13d
  lea    0x80(%rsi),%r12d
  push   %rbp
  lea    (%rsi,%rdi,1),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x6,%r13d
  jle    L4
  lea    0x40(%rsi),%r12d
  add    $0x60,%esi
  cmp    $0xc7,%edi
  cmovg  %esi,%r12d
  xor    %eax,%eax
  call   <g@plt>
L4:
  add    $0x8,%rsp
  lea    0x20(%r12,%rbx,1),%eax
  add    %r13d,%ebp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int f(int c, int i) {
  int a1, a2, a3, x1, x2, x3, x;
  a1 = i * 16;
  x1 = c + a1;
  i = i + 2;
  a2 = i * 16;
  x2 = c + a2;
  if (x2 > 6) {
    if (c < 200)
      i = i + 2;
    else
      i = i + 4;
    g();
  } else
    i = i + 6;
  i = i + 2;
  a3 = i * 16;
  x3 = c + a3;
  x = x1 + x2 + x3;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mvpw_get_rgba>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mvpw_get_rgba(unsigned long c, unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a) {
  *a = (c >> 24) & 0xff;
  *b = (c >> 16) & 0xff;
  *g = (c >> 8) & 0xff;
  *r = (c >> 0) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mvpw_get_rgba>:
  endbr64
  mov    %rdi,%rax
  shr    $0x18,%rdi
  mov    %dil,(%r8)
  mov    %rax,%rdi
  shr    $0x10,%rdi
  mov    %dil,(%rcx)
  movzbl %ah,%ecx
  mov    %cl,(%rdx)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void mvpw_get_rgba(unsigned long c, unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a) {
  *a = (c >> 24) & 0xff;
  *b = (c >> 16) & 0xff;
  *g = (c >> 8) & 0xff;
  *r = (c >> 0) & 0xff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mvpw_get_rgba>:
  endbr64
  mov    %rdi,%rax
  shr    $0x18,%rdi
  mov    %dil,(%r8)
  mov    %rax,%rdi
  shr    $0x10,%rdi
  mov    %dil,(%rcx)
  mov    %ah,(%rdx)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void mvpw_get_rgba(unsigned long c, unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a) {
  *a = (c >> 24) & 0xff;
  *b = (c >> 16) & 0xff;
  *g = (c >> 8) & 0xff;
  *r = (c >> 0) & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mvpw_get_rgba>:
  endbr64
  mov    %rdi,%rax
  shr    $0x18,%rdi
  mov    %dil,(%r8)
  mov    %rax,%rdi
  shr    $0x10,%rdi
  mov    %dil,(%rcx)
  mov    %ah,(%rdx)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void mvpw_get_rgba(unsigned long c, unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a) {
  *a = (c >> 24) & 0xff;
  *b = (c >> 16) & 0xff;
  *g = (c >> 8) & 0xff;
  *r = (c >> 0) & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_str_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L43:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  movl   $0x1,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_str_cmp(const char s1[], const char s2[]) {
  int i = 0;
  int are_equal = 0;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0') {
    ++i;
  }
  if (s1[i] == '\0' && s2[i] == '\0') {
    are_equal = 1;
  }
  return are_equal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_str_cmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  test   %dl,%dl
  setne  %r8b
  cmp    %cl,%dl
  sete   %al
  test   %al,%r8b
  je     L23
  test   %cl,%cl
  je     L23
  mov    $0x1,%eax
L15:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  setne  %r9b
  cmp    %cl,%dl
  sete   %r8b
  test   %r8b,%r9b
  je     L23
  test   %cl,%cl
  jne    L15
L23:
  or     %cl,%dl
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int my_str_cmp(const char s1[], const char s2[]) {
  int i = 0;
  int are_equal = 0;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0') {
    ++i;
  }
  if (s1[i] == '\0' && s2[i] == '\0') {
    are_equal = 1;
  }
  return are_equal;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_str_cmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %dl,%cl
  je     L12
  jmp    L43
  nopl   (%rax)
L16:
  test   %cl,%cl
  je     L46
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L43
L12:
  test   %dl,%dl
  jne    L16
L0:
  xor    %eax,%eax
  test   %cl,%cl
  sete   %al
  ret
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  test   %dl,%dl
  je     L0
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_str_cmp(const char s1[], const char s2[]) {
  int i = 0;
  int are_equal = 0;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0') {
    ++i;
  }
  if (s1[i] == '\0' && s2[i] == '\0') {
    are_equal = 1;
  }
  return are_equal;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_str_cmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %dl,%cl
  je     L27
  jmp    L49
  nopl   (%rax)
L42:
  test   %cl,%cl
  je     L43
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L49
L27:
  test   %dl,%dl
  jne    L42
L23:
  xor    %eax,%eax
  test   %cl,%cl
  sete   %al
  ret
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  test   %dl,%dl
  je     L23
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_str_cmp(const char s1[], const char s2[]) {
  int i = 0;
  int are_equal = 0;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0') {
    ++i;
  }
  if (s1[i] == '\0' && s2[i] == '\0') {
    are_equal = 1;
  }
  return are_equal;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <glutBitmapCharacter@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void printstring(void *font, const char *string) {
  const char *c;
  for (c = string; *c; c++)
    glutBitmapCharacter(font, *c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L8
L16:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <glutBitmapCharacter@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L16
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(void *font, const char *string) {
  const char *c;
  for (c = string; *c; c++)
    glutBitmapCharacter(font, *c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L18
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L9
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(void *font, const char *string) {
  const char *c;
  for (c = string; *c; c++)
    glutBitmapCharacter(font, *c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L11
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L15
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(void *font, const char *string) {
  const char *c;
  for (c = string; *c; c++)
    glutBitmapCharacter(font, *c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x8(%rbp)
  mov    D0(%rip),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    D3(%rip),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7fffffff,-0x4(%rbp)
  je     L1
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int32_t a = -1;
  static int32_t b = -2147483647 - 1;
  static int32_t c = 0;
  int32_t t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int32_t a = -1;
  static int32_t b = -2147483647 - 1;
  static int32_t c = 0;
  int32_t t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int32_t a = -1;
  static int32_t b = -2147483647 - 1;
  static int32_t c = 0;
  int32_t t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int32_t a = -1;
  static int32_t b = -2147483647 - 1;
  static int32_t c = 0;
  int32_t t = a - (b + c * -2);
  if (t != 2147483647)
    __builtin_abort();
  return 0;
}
```