ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<mytest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int mytest(char const *recp, int reclen, char const *udata, int uleng) {
  (void)recp, (void)reclen, (void)udata, (void)uleng;
  assert(reclen > 0);
  int ret = 0;
  return !!ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mytest>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mytest(char const *recp, int reclen, char const *udata, int uleng) {
  (void)recp, (void)reclen, (void)udata, (void)uleng;
  assert(reclen > 0);
  int ret = 0;
  return !!ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<mytest>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  test   %esi,%esi
  setg   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mytest(char const *recp, int reclen, char const *udata, int uleng) {
  (void)recp, (void)reclen, (void)udata, (void)uleng;
  assert(reclen > 0);
  int ret = 0;
  return !!ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mytest>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  test   %esi,%esi
  setg   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mytest(char const *recp, int reclen, char const *udata, int uleng) {
  (void)recp, (void)reclen, (void)udata, (void)uleng;
  assert(reclen > 0);
  int ret = 0;
  return !!ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L13
L9:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long int atol(const char *nptr) {
  long val = 0;
  while (*nptr) {
    val = val * 10 + (*nptr - '0');
    nptr++;
  }
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  mov    $0x0,%edx
L20:
  lea    (%rdx,%rdx,4),%rdx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
L9:
  mov    %rdx,%rax
  ret
L22:
  mov    $0x0,%edx
  jmp    L9
```

assistant: ```c
long int atol(const char *nptr) {
  long val = 0;
  while (*nptr) {
    val = val * 10 + (*nptr - '0');
    nptr++;
  }
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atol>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L0
  xchg   %ax,%ax
L10:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  cltq
  lea    (%rax,%rdx,2),%r8
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L10
L0:
  mov    %r8,%rax
  ret
```

assistant: ```c
long int atol(const char *nptr) {
  long val = 0;
  while (*nptr) {
    val = val * 10 + (*nptr - '0');
    nptr++;
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<atol>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L6
  xchg   %ax,%ax
L3:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  cltq
  lea    (%rax,%rdx,2),%r8
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L3
L6:
  mov    %r8,%rax
  ret
```

assistant: ```c
long int atol(const char *nptr) {
  long val = 0;
  while (*nptr) {
    val = val * 10 + (*nptr - '0');
    nptr++;
  }
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<karpekarnumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %edi,%r12
  movslq %esi,%r13
  cmp    %r13,%r12
  jg     L159
  mov    %rdx,%rbp
  mov    $0x0,%edi
  mov    $0x0,%r14d
  movabs $0x6666666666666667,%rbx
  lea    D10(%rip),%r15
  jmp    L11
L3:
  mov    %r14,%rdx
  test   %r9,%r9
  jle    L111
  jmp    L100
L85:
  mov    %r14,%rdx
  jmp    L111
L66:
  add    $0x1,%r12
  cmp    %r13,%r12
  jg     L13
L11:
  mov    %r12,%rcx
  imul   %r12,%rcx
  test   %r12,%r12
  jle    L85
  mov    %r12,%rsi
  mov    $0x0,%r9d
L65:
  mov    %rsi,%r10
  mov    %rsi,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  mov    %r9,%r8
  add    $0x1,%r9
  cmp    $0x9,%r10
  jg     L65
  test   %rcx,%rcx
  jle    L3
  test   %r9,%r9
  jle    L3
  lea    0x0(%rbp,%r8,1),%rsi
  mov    %rsi,%r9
L118:
  mov    %rcx,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%r10
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  mov    %r10,%rcx
  mov    %dl,(%rsi)
  mov    %r9,%rdx
  sub    %rsi,%rdx
  cmp    %r8,%rdx
  setl   %dl
  cmp    $0x9,%rax
  setg   %al
  sub    $0x1,%rsi
  test   %al,%dl
  jne    L118
L100:
  mov    $0x0,%eax
  mov    %r14,%rdx
L7:
  lea    (%rdx,%rdx,4),%rsi
  movsbq 0x0(%rbp,%rax,1),%rdx
  lea    (%rdx,%rsi,2),%rdx
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %r8,%rsi
  jl     L7
L111:
  add    %rdx,%rcx
  cmp    %r12,%rcx
  jne    L66
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  jmp    L66
L13:
  test   %rdi,%rdi
  je     L159
L102:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L159:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L102
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D10: %ld 

tool: D2: INVALID RANGE

assistant: ```c
void karpekarnumber(int p, int q, char *arr) {
  long int i, num, j, k, m, d, sq, rem, flag = 0, temp;
  for (i = p; i <= q; i++) {
    sq = i * i;
    d = 0;
    temp = i;
    while (temp > 0) {
      temp = temp / 10;
      d++;
    }
    m = d - 1;
    k = 0;
    while (sq > 0 && k < d) {
      rem = sq % 10;
      sq = sq / 10;
      arr[m] = rem;
      m--;
      k++;
    }
    num = 0;
    for (j = 0; j < d; j++) {
      num = num * 10 + arr[j];
    }
    if ((sq + num) == i) {
      printf("%ld ", i);
      flag = 1;
    }
  }
  if (flag == 0)
    printf("INVALID RANGE");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<karpekarnumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %r13,%rbp
  jg     L25
  mov    %rdx,%r12
  lea    0x1(%rdx),%r14
  lea    D13(%rip),%r15
  xor    %edi,%edi
  movabs $0xcccccccccccccccd,%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rcx
  imul   %rbp,%rcx
  test   %rbp,%rbp
  jle    L48
  mov    %rbp,%rdx
  xor    %r9d,%r9d
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rdx,%rax
  mov    %rdx,%r8
  mov    %r9,%rsi
  mul    %rbx
  lea    0x1(%r9),%r9
  shr    $0x3,%rdx
  cmp    $0x9,%r8
  jg     L1
  test   %rcx,%rcx
  je     L98
  lea    (%r12,%rsi,1),%r9
  mov    %r9,%r8
  cs nopw 0x0(%rax,%rax,1)
L97:
  mov    %rcx,%rax
  mul    %rbx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r10
  mov    %rdx,%rax
  mov    %rcx,%rdx
  add    %r10,%r10
  sub    %r10,%rdx
  mov    %rcx,%r10
  mov    %rax,%rcx
  mov    %r9,%rax
  sub    %r8,%rax
  mov    %dl,(%r8)
  cmp    %rsi,%rax
  setl   %dl
  cmp    $0x9,%r10
  setg   %al
  sub    $0x1,%r8
  test   %al,%dl
  jne    L97
L98:
  mov    %r12,%rax
  add    %r14,%rsi
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L62:
  lea    (%rdx,%rdx,4),%r8
  movsbq (%rax),%rdx
  add    $0x1,%rax
  lea    (%rdx,%r8,2),%rdx
  cmp    %rax,%rsi
  jne    L62
  add    %rdx,%rcx
L48:
  cmp    %rbp,%rcx
  je     L99
L16:
  add    $0x1,%rbp
  cmp    %rbp,%r13
  jge    L29
  test   %rdi,%rdi
  je     L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L99:
  mov    %r15,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  jmp    L16
L25:
  add    $0x8,%rsp
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string

tool: D13: %ld 

tool: D12: INVALID RANGE

assistant: ```c
void karpekarnumber(int p, int q, char *arr) {
  long int i, num, j, k, m, d, sq, rem, flag = 0, temp;
  for (i = p; i <= q; i++) {
    sq = i * i;
    d = 0;
    temp = i;
    while (temp > 0) {
      temp = temp / 10;
      d++;
    }
    m = d - 1;
    k = 0;
    while (sq > 0 && k < d) {
      rem = sq % 10;
      sq = sq / 10;
      arr[m] = rem;
      m--;
      k++;
    }
    num = 0;
    for (j = 0; j < d; j++) {
      num = num * 10 + arr[j];
    }
    if ((sq + num) == i) {
      printf("%ld ", i);
      flag = 1;
    }
  }
  if (flag == 0)
    printf("INVALID RANGE");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x10,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x1,-0x14(%rbp)
  jle    L27
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <omp_set_num_threads@plt>
L27:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L22:
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: Thread %d performed iteration %d


assistant: ```c
int main(int argc, char **argv) {
  const int REPS = 16;
  printf("\n");
  if (argc > 1) {
    omp_set_num_threads(atoi(argv[1]));
  }
#pragma omp parallel for schedule(static, 1)
  for (int i = 0; i < REPS; i++) {
    int id = omp_get_thread_num();
    printf("Thread %d performed iteration %d\n", id, i);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x1,%ebx
  jg     L17
L15:
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L8:
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <omp_set_num_threads@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: Thread %d performed iteration %d


assistant: ```c
int main(int argc, char **argv) {
  const int REPS = 16;
  printf("\n");
  if (argc > 1) {
    omp_set_num_threads(atoi(argv[1]));
  }
#pragma omp parallel for schedule(static, 1)
  for (int i = 0; i < REPS; i++) {
    int id = omp_get_thread_num();
    printf("Thread %d performed iteration %d\n", id, i);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xa,%edi
  sub    $0x8,%rsp
  call   <putchar@plt>
  cmp    $0x1,%ebx
  jle    L1
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <omp_set_num_threads@plt>
L1:
  xor    %ebx,%ebx
  lea    D7(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: Thread %d performed iteration %d


assistant: ```c
int main(int argc, char **argv) {
  const int REPS = 16;
  printf("\n");
  if (argc > 1) {
    omp_set_num_threads(atoi(argv[1]));
  }
#pragma omp parallel for schedule(static, 1)
  for (int i = 0; i < REPS; i++) {
    int id = omp_get_thread_num();
    printf("Thread %d performed iteration %d\n", id, i);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xa,%edi
  sub    $0x8,%rsp
  call   <putchar@plt>
  cmp    $0x1,%ebx
  jle    L14
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <omp_set_num_threads@plt>
L14:
  xor    %ebx,%ebx
  lea    D0(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: Thread %d performed iteration %d


assistant: ```c
int main(int argc, char **argv) {
  const int REPS = 16;
  printf("\n");
  if (argc > 1) {
    omp_set_num_threads(atoi(argv[1]));
  }
#pragma omp parallel for schedule(static, 1)
  for (int i = 0; i < REPS; i++) {
    int id = omp_get_thread_num();
    printf("Thread %d performed iteration %d\n", id, i);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L16
L56:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L35
L2:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L65
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L65:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x0,-0x14(%rbp)
  jg     L56
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type_infered: string

tool: D23: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, j, k;
  for (i = n; i >= 1; i--) {
    k = i;
    for (j = 1; j <= n; j++) {
      if (k <= n) {
        printf("%d", k);
      } else {
        printf("%d", n);
      }
      k++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r13d
  lea    D16(%rip),%r12
  test   %r13d,%r13d
  jg     L70
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %eax,%esi
  jl     L47
L19:
  cmp    %ebx,%esi
  jl     L79
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  je     L46
L70:
  mov    0x4(%rsp),%esi
  mov    %r13d,%ebx
  mov    $0x1,%ebp
  sub    %r13d,%ebp
  test   %esi,%esi
  jg     L19
  jmp    L47
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string

tool: D16: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, j, k;
  for (i = n; i >= 1; i--) {
    k = i;
    for (j = 1; j <= n; j++) {
      if (k <= n) {
        printf("%d", k);
      } else {
        printf("%d", n);
      }
      k++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%r13d
  test   %esi,%esi
  jle    L50
  nopl   (%rax)
L0:
  mov    %r14d,%ebp
  mov    %r13d,%ebx
  sub    %r13d,%ebp
  test   %esi,%esi
  jg     L38
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %eax,%esi
  jl     L3
L38:
  cmp    %ebx,%esi
  jge    L15
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %eax,%esi
  jge    L38
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  je     L50
  mov    0x4(%rsp),%esi
  jmp    L0
  xchg   %ax,%ax
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, j, k;
  for (i = n; i >= 1; i--) {
    k = i;
    for (j = 1; j <= n; j++) {
      if (k <= n) {
        printf("%d", k);
      } else {
        printf("%d", n);
      }
      k++;
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%ebp
  test   %esi,%esi
  jle    L41
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %ebp,%ebx
  test   %esi,%esi
  jle    L61
  xchg   %ax,%ax
L47:
  cmp    %ebx,%esi
  jl     L39
  mov    %ebx,%esi
L39:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r13d,%eax
  mov    0x4(%rsp),%esi
  sub    %ebp,%eax
  add    %ebx,%eax
  cmp    %eax,%esi
  jge    L47
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L41
  mov    0x4(%rsp),%esi
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i, j, k;
  for (i = n; i >= 1; i--) {
    k = i;
    for (j = 1; j <= n; j++) {
      if (k <= n) {
        printf("%d", k);
      } else {
        printf("%d", n);
      }
      k++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getDecimalVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L0:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getDecimalVal(char binary[]) {
  int decimal = 0, i;
  for (i = 0; binary[i] != '\0'; i++)
    decimal = (decimal << 1) + (binary[i] - '0');
  return decimal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getDecimalVal>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  add    $0x1,%rdi
  mov    $0x0,%edx
L28:
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L28
L23:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int getDecimalVal(char binary[]) {
  int decimal = 0, i;
  for (i = 0; binary[i] != '\0'; i++)
    decimal = (decimal << 1) + (binary[i] - '0');
  return decimal;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getDecimalVal>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L3
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
  lea    -0x30(%rax,%r8,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L9
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getDecimalVal(char binary[]) {
  int decimal = 0, i;
  for (i = 0; binary[i] != '\0'; i++)
    decimal = (decimal << 1) + (binary[i] - '0');
  return decimal;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getDecimalVal>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
  lea    -0x30(%rax,%r8,2),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L13
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getDecimalVal(char binary[]) {
  int decimal = 0, i;
  for (i = 0; binary[i] != '\0'; i++)
    decimal = (decimal << 1) + (binary[i] - '0');
  return decimal;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<raiz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  jmp    L17
L33:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  addl   $0x2,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x14(%rbp)
  jg     L33
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L30
L18:
  mov    $0x0,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int raiz(int x) {
  int i;
  while (x > 0) {
    x = x - i;
    i = i + 2;
  }
  if (x == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<raiz>:
  endbr64
  test   %edi,%edi
  jle    L0
L16:
  sub    %eax,%edi
  add    $0x2,%eax
  test   %edi,%edi
  jg     L16
L0:
  test   %edi,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int raiz(int x) {
  int i;
  while (x > 0) {
    x = x - i;
    i = i + 2;
  }
  if (x == 0) {
    return 1;
  } else {
    return 0;
  }
}
```