ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<evolveUniv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  movslq %esi,%rdx
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%rax
  mov    %rsp,%rcx
  mov    %rax,-0x68(%rbp)
  movslq %edi,%rax
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L120
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L1
L120:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L16
L15:
  mov    %rsp,%rax
  test   %r13d,%r13d
  je     L101
  mov    %r13d,%edi
  mov    %rax,-0x78(%rbp)
  mov    %r14,%r15
  mov    %r14,-0x80(%rbp)
  mov    %rdi,-0x70(%rbp)
  mov    %r14,-0x60(%rbp)
  mov    %rax,-0x48(%rbp)
  movq   $0x0,-0x58(%rbp)
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %ebx,%eax
  mov    -0x58(%rbp),%r14d
  xor    %r12d,%r12d
  mov    %rax,-0x50(%rbp)
  test   %ebx,%ebx
  je     L118
  mov    %r15,%rax
  mov    %ebx,%r15d
  mov    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L112:
  mov    %r13d,%edx
  mov    %rbx,%r8
  mov    %r15d,%ecx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <getNeighbours@plt>
  mov    $0x1,%edx
  cmp    $0x3,%eax
  je     L45
  xor    %edx,%edx
  cmp    $0x2,%eax
  jne    L45
  mov    -0x60(%rbp),%rax
  xor    %edx,%edx
  mov    (%rax,%r12,4),%eax
  test   %eax,%eax
  setne  %dl
L45:
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax,%r12,4)
  add    $0x1,%r12
  cmp    -0x50(%rbp),%r12
  jne    L112
  mov    %rbx,%rax
  mov    %r15d,%ebx
  mov    %rax,%r15
L118:
  mov    -0x68(%rbp),%rcx
  addq   $0x1,-0x58(%rbp)
  add    %rcx,-0x48(%rbp)
  mov    -0x58(%rbp),%rax
  add    %rcx,-0x60(%rbp)
  cmp    -0x70(%rbp),%rax
  jne    L66
  mov    %r13d,-0x48(%rbp)
  lea    -0x1(%rbx),%eax
  mov    -0x78(%rbp),%r15
  xor    %r14d,%r14d
  mov    -0x80(%rbp),%rcx
  mov    -0x68(%rbp),%r13
  lea    0x4(,%rax,4),%r12
  nopl   0x0(%rax)
L9:
  test   %ebx,%ebx
  je     L65
  mov    %rcx,%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  mov    %rax,%rcx
L65:
  add    $0x1,%r14d
  add    %r13,%rcx
  add    %r13,%r15
  cmp    %r14d,-0x48(%rbp)
  jne    L9
L101:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L16:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evolveUniv(int rows, int cols, int univ[][cols]) {
  int new_univ[rows][cols];
  int i, j;
  int live_neighbours;
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      live_neighbours = getNeighbours(i, j, rows, cols, univ);
      new_univ[i][j] = (live_neighbours == 3 || (live_neighbours == 2 && univ[i][j]));
    }
  }
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      univ[i][j] = new_univ[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<evolveUniv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %rdx,%rbx
  movslq %esi,%rdx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%rax
  mov    %rsp,%rcx
  mov    %rax,-0x68(%rbp)
  movslq %edi,%rax
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L37
L78:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L78
L37:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L63
L72:
  mov    %rsp,-0x78(%rbp)
  test   %r12d,%r12d
  je     L52
  test   %r14d,%r14d
  je     L52
  mov    %rsp,%rax
  mov    %rbx,-0x60(%rbp)
  mov    %r14d,%r15d
  mov    %rax,-0x48(%rbp)
  mov    %r12d,%eax
  mov    %rax,-0x70(%rbp)
  mov    %r14d,%eax
  movq   $0x0,-0x58(%rbp)
  mov    %rax,-0x50(%rbp)
  nopl   0x0(%rax)
L9:
  mov    -0x58(%rbp),%r14d
  xor    %r13d,%r13d
  nop
L55:
  mov    %r12d,%edx
  mov    %rbx,%r8
  mov    %r15d,%ecx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <getNeighbours@plt>
  mov    $0x1,%edx
  cmp    $0x3,%eax
  je     L12
  xor    %edx,%edx
  cmp    $0x2,%eax
  jne    L12
  mov    -0x60(%rbp),%rax
  xor    %edx,%edx
  mov    (%rax,%r13,4),%eax
  test   %eax,%eax
  setne  %dl
L12:
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax,%r13,4)
  add    $0x1,%r13
  cmp    -0x50(%rbp),%r13
  jne    L55
  mov    -0x68(%rbp),%rdi
  addq   $0x1,-0x58(%rbp)
  add    %rdi,-0x48(%rbp)
  mov    -0x58(%rbp),%rax
  add    %rdi,-0x60(%rbp)
  cmp    -0x70(%rbp),%rax
  jne    L9
  mov    %rbx,%r8
  mov    -0x78(%rbp),%rbx
  xor    %r14d,%r14d
  mov    %rdi,%r15
  lea    0x0(,%r13,4),%r13
  cs nopw 0x0(%rax,%rax,1)
L84:
  mov    %rbx,%rsi
  mov    %r8,%rdi
  mov    %r13,%rdx
  add    $0x1,%r14d
  call   <memcpy@plt>
  add    %r15,%rbx
  mov    %rax,%r8
  add    %r15,%r8
  cmp    %r14d,%r12d
  jne    L84
L52:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L63:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L72
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void evolveUniv(int rows, int cols, int univ[][cols]) {
  int new_univ[rows][cols];
  int i, j;
  int live_neighbours;
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      live_neighbours = getNeighbours(i, j, rows, cols, univ);
      new_univ[i][j] = (live_neighbours == 3 || (live_neighbours == 2 && univ[i][j]));
    }
  }
  for (i = 0; i != rows; i++) {
    for (j = 0; j != cols; j++) {
      univ[i][j] = new_univ[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp_trees>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_formula@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <get_formula@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int cmp_trees(struct Node *a, struct Node *b) {
  int ret;
  char *f, *g;
  f = get_formula(a);
  g = get_formula(b);
  ret = strcmp(f, g);
  free(f);
  free(g);
  return (!ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp_trees>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <get_formula@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <get_formula@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  test   %r12d,%r12d
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmp_trees(struct Node *a, struct Node *b) {
  int ret;
  char *f, *g;
  f = get_formula(a);
  g = get_formula(b);
  ret = strcmp(f, g);
  free(f);
  free(g);
  return (!ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp_trees>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <get_formula@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <get_formula@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <strcmp@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmp_trees(struct Node *a, struct Node *b) {
  int ret;
  char *f, *g;
  f = get_formula(a);
  g = get_formula(b);
  ret = strcmp(f, g);
  free(f);
  free(g);
  return (!ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmp_trees>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <get_formula@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <get_formula@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <strcmp@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmp_trees(struct Node *a, struct Node *b) {
  int ret;
  char *f, *g;
  f = get_formula(a);
  g = get_formula(b);
  ret = strcmp(f, g);
  free(f);
  free(g);
  return (!ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L47
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
  jmp    L39
L34:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L47:
  cmpl   $0x0,-0x14(%rbp)
  jg     L34
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0xc(%rbp)
  jmp    L26
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L9
L39:
  pop    %rbp
  ret
```

assistant: ```c
void convert_to_str(int int_in, unsigned char res[]) {
  int j = 0;
  int cur_num = 0;
  int k = 0;
  char temp;
  if (int_in == 0) {
    res[0] = '0';
    return;
  }
  while (int_in > 0) {
    cur_num = int_in % 10;
    int_in = int_in / 10;
    res[j] = cur_num + '0';
    j++;
  }
  res[j + 1] = '\0';
  j--;
  while (j > k) {
    temp = res[k];
    res[k] = res[j];
    res[j] = temp;
    k++;
    j--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert_to_str>:
  endbr64
  mov    %edi,%edx
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L44
  mov    %rsi,%r8
  mov    $0x0,%edi
  jle    L9
L17:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%r9d
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %edx,%esi
  mov    %r9d,%edx
  add    $0x30,%eax
  mov    %al,(%r8)
  mov    %edi,%eax
  add    $0x1,%edi
  add    $0x1,%r8
  cmp    $0x9,%esi
  jg     L17
  movslq %edi,%rdi
  movb   $0x0,0x1(%rcx,%rdi,1)
  test   %eax,%eax
  jle    L10
  cltq
  mov    $0x0,%edx
L35:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  mov    %sil,(%rcx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L35
  ret
L44:
  movb   $0x30,(%rsi)
  ret
L9:
  movb   $0x0,0x1(%rsi)
L10:
  ret
```

assistant: ```c
void convert_to_str(int int_in, unsigned char res[]) {
  int j = 0;
  int cur_num = 0;
  int k = 0;
  char temp;
  if (int_in == 0) {
    res[0] = '0';
    return;
  }
  while (int_in > 0) {
    cur_num = int_in % 10;
    int_in = int_in / 10;
    res[j] = cur_num + '0';
    j++;
  }
  res[j + 1] = '\0';
  j--;
  while (j > k) {
    temp = res[k];
    res[k] = res[j];
    res[j] = temp;
    k++;
    j--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<convert_to_str>:
  endbr64
  mov    %edi,%edx
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L45
  mov    %rsi,%r9
  mov    $0x0,%r8d
  mov    $0xcccccccd,%r10d
  jle    L9
  xchg   %ax,%ax
L43:
  mov    %edx,%eax
  add    $0x1,%r9
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  mov    %eax,%esi
  mov    %edx,%eax
  add    %edi,%edi
  sub    %edi,%eax
  mov    %edx,%edi
  mov    %esi,%edx
  add    $0x30,%eax
  mov    %al,-0x1(%r9)
  movslq %r8d,%rax
  add    $0x1,%r8d
  cmp    $0x9,%edi
  jg     L43
  movslq %r8d,%r8
  movb   $0x0,0x1(%rcx,%r8,1)
  test   %eax,%eax
  je     L4
  xor    %edx,%edx
  nop
L8:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L8
  ret
  nopl   (%rax)
L9:
  movb   $0x0,0x1(%rsi)
L4:
  ret
  nopl   (%rax)
L45:
  movb   $0x30,(%rsi)
  ret
```

assistant: ```c
void convert_to_str(int int_in, unsigned char res[]) {
  int j = 0;
  int cur_num = 0;
  int k = 0;
  char temp;
  if (int_in == 0) {
    res[0] = '0';
    return;
  }
  while (int_in > 0) {
    cur_num = int_in % 10;
    int_in = int_in / 10;
    res[j] = cur_num + '0';
    j++;
  }
  res[j + 1] = '\0';
  j--;
  while (j > k) {
    temp = res[k];
    res[k] = res[j];
    res[j] = temp;
    k++;
    j--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert_to_str>:
  endbr64
  mov    %edi,%edx
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L39
  mov    %rsi,%r9
  mov    $0x0,%r8d
  mov    $0xcccccccd,%r10d
  jle    L6
  xchg   %ax,%ax
L38:
  mov    %edx,%eax
  add    $0x1,%r9
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  mov    %eax,%esi
  mov    %edx,%eax
  add    %edi,%edi
  sub    %edi,%eax
  mov    %edx,%edi
  mov    %esi,%edx
  add    $0x30,%eax
  mov    %al,-0x1(%r9)
  movslq %r8d,%rax
  add    $0x1,%r8d
  cmp    $0x9,%edi
  jg     L38
  movslq %r8d,%r8
  movb   $0x0,0x1(%rcx,%r8,1)
  test   %eax,%eax
  je     L33
  xor    %edx,%edx
  nop
L18:
  movzbl (%rcx,%rdx,1),%esi
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rcx,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rcx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L18
  ret
  nopl   (%rax)
L6:
  movb   $0x0,0x1(%rsi)
L33:
  ret
  nopl   (%rax)
L39:
  movb   $0x30,(%rsi)
  ret
```

assistant: ```c
void convert_to_str(int int_in, unsigned char res[]) {
  int j = 0;
  int cur_num = 0;
  int k = 0;
  char temp;
  if (int_in == 0) {
    res[0] = '0';
    return;
  }
  while (int_in > 0) {
    cur_num = int_in % 10;
    int_in = int_in / 10;
    res[j] = cur_num + '0';
    j++;
  }
  res[j + 1] = '\0';
  j--;
  while (j > k) {
    temp = res[k];
    res[k] = res[j];
    res[j] = temp;
    k++;
    j--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rtrb_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rtrb_probe@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  jmp    L7
L15:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
void *rtrb_insert(struct rtrb_table *table, void *item) {
  void **p = rtrb_probe(table, item);
  return p == NULL || *p == item ? NULL : *p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rtrb_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <rtrb_probe@plt>
  test   %rax,%rax
  je     L3
  mov    (%rax),%rax
  cmp    %rbx,%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
L3:
  pop    %rbx
  ret
```

assistant: ```c
void *rtrb_insert(struct rtrb_table *table, void *item) {
  void **p = rtrb_probe(table, item);
  return p == NULL || *p == item ? NULL : *p;
}
```
user: What is the c source code of the assembly code below?

```asm
<rtrb_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <rtrb_probe@plt>
  test   %rax,%rax
  je     L9
  mov    (%rax),%rax
  xor    %edx,%edx
  cmp    %rbx,%rax
  cmove  %rdx,%rax
L9:
  pop    %rbx
  ret
```

assistant: ```c
void *rtrb_insert(struct rtrb_table *table, void *item) {
  void **p = rtrb_probe(table, item);
  return p == NULL || *p == item ? NULL : *p;
}
```
user: What is the c source code of the assembly code below:

```asm
<rtrb_insert>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <rtrb_probe@plt>
  test   %rax,%rax
  je     L6
  mov    (%rax),%rax
  xor    %edx,%edx
  cmp    %rbx,%rax
  cmove  %rdx,%rax
L6:
  pop    %rbx
  ret
```

assistant: ```c
void *rtrb_insert(struct rtrb_table *table, void *item) {
  void **p = rtrb_probe(table, item);
  return p == NULL || *p == item ? NULL : *p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mystrnicmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L5
L11:
  cmpq   $0x0,-0x8(%rbp)
  jne    L63
  cmpq   $0x0,-0x10(%rbp)
  je     L68
  mov    $0xffffffff,%eax
  jmp    L5
L68:
  mov    $0x0,%eax
  jmp    L5
L63:
  cmpq   $0x0,-0x10(%rbp)
  jne    L19
  mov    $0x1,%eax
  jmp    L5
L19:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strnicmp@plt>
L5:
  leave
  ret
```

assistant: ```c
int mystrnicmp(const char *str1, const char *str2, int n) {
  if (!n)
    return 0;
  if (!str1) {
    if (str2)
      return -1;
    return 0;
  }
  if (!str2)
    return 1;
  return strnicmp(str1, str2, n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mystrnicmp>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L22
  test   %rdi,%rdi
  je     L24
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L22
  sub    $0x8,%rsp
  call   <strnicmp@plt>
  add    $0x8,%rsp
  ret
L24:
  neg    %rsi
  sbb    %eax,%eax
  ret
L22:
  ret
```

assistant: ```c
int mystrnicmp(const char *str1, const char *str2, int n) {
  if (!n)
    return 0;
  if (!str1) {
    if (str2)
      return -1;
    return 0;
  }
  if (!str2)
    return 1;
  return strnicmp(str1, str2, n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mystrnicmp>:
  endbr64
  test   %edx,%edx
  je     L14
  test   %rdi,%rdi
  je     L19
  test   %rsi,%rsi
  je     L15
  jmp    1050 <strnicmp@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  neg    %rsi
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int mystrnicmp(const char *str1, const char *str2, int n) {
  if (!n)
    return 0;
  if (!str1) {
    if (str2)
      return -1;
    return 0;
  }
  if (!str2)
    return 1;
  return strnicmp(str1, str2, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mystrnicmp>:
  endbr64
  test   %edx,%edx
  je     L25
  test   %rdi,%rdi
  je     L21
  test   %rsi,%rsi
  je     L2
  jmp    1050 <strnicmp@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  neg    %rsi
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int mystrnicmp(const char *str1, const char *str2, int n) {
  if (!n)
    return 0;
  if (!str1) {
    if (str2)
      return -1;
    return 0;
  }
  if (!str2)
    return 1;
  return strnicmp(str1, str2, n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trim_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  mov    -0x8(%rbp),%rax
  jmp    L5
L27:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x8(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
char *trim_start(char *str) {
  while (0 != *str) {
    if (!isspace(*str)) {
      return str;
    }
    str++;
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim_start>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L36
L5:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L0
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
  mov    %rbx,%rax
  jmp    L26
L36:
  mov    %rbx,%rax
  jmp    L26
L0:
  mov    %rbx,%rax
L26:
  pop    %rbx
  ret
```

assistant: ```c
char *trim_start(char *str) {
  while (0 != *str) {
    if (!isspace(*str)) {
      return str;
    }
    str++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim_start>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L6
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L36:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L7
L6:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L36
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim_start(char *str) {
  while (0 != *str) {
    if (!isspace(*str)) {
      return str;
    }
    str++;
  }
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<trim_start>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L33
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L37:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L10
L33:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L37
L10:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim_start(char *str) {
  while (0 != *str) {
    if (!isspace(*str)) {
      return str;
    }
    str++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L11
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <split@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L14
L11:
  nop
L14:
  leave
  ret
```

assistant: ```c
void quicksort(const int a[], int *low, int *high) {
  int *middle;
  if (low >= high) {
    return;
  }
  middle = split(low, high);
  quicksort(a, low, (middle - 1));
  quicksort(a, (middle + 1), high);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quicksort>:
  endbr64
  cmp    %rdx,%rsi
  jb     L5
  ret
L5:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    %r13,%rdi
  call   <split@plt>
  mov    %rax,%rbp
  lea    -0x4(%rax),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x4(%rbp),%rsi
  mov    %rbx,%rdx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(const int a[], int *low, int *high) {
  int *middle;
  if (low >= high) {
    return;
  }
  middle = split(low, high);
  quicksort(a, low, (middle - 1));
  quicksort(a, (middle + 1), high);
}
```