ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bot_serial_translate_baud>:
  endbr64
  cmp    $0x4b00,%edi
  je     L110
  jg     L28
  cmp    $0x960,%edi
  je     L124
  jg     L11
  cmp    $0x12c,%edi
  je     L74
  cmp    $0x4b0,%edi
  jne    L68
  mov    D104(%rip),%rax
  mov    (%rax),%eax
  ret
L68:
  test   %edi,%edi
  jne    L53
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  ret
L53:
  mov    $0xffffffff,%eax
  ret
L11:
  cmp    $0x12c0,%edi
  je     L0
  cmp    $0x2580,%edi
  jne    L33
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  ret
L33:
  mov    $0xffffffff,%eax
  ret
L28:
  cmp    $0x1c200,%edi
  je     L76
  jle    L125
  cmp    $0x38400,%edi
  je     L12
  cmp    $0x70800,%edi
  jne    L39
  mov    D114(%rip),%rax
  mov    (%rax),%eax
  ret
L125:
  cmp    $0x9600,%edi
  je     L13
  cmp    $0xe100,%edi
  jne    L94
  mov    D74(%rip),%rax
  mov    (%rax),%eax
  ret
L94:
  mov    $0xffffffff,%eax
  ret
L39:
  mov    $0xffffffff,%eax
  ret
L74:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  ret
L124:
  mov    D75(%rip),%rax
  mov    (%rax),%eax
  ret
L0:
  mov    D60(%rip),%rax
  mov    (%rax),%eax
  ret
L110:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
L13:
  mov    D68(%rip),%rax
  mov    (%rax),%eax
  ret
L76:
  mov    D51(%rip),%rax
  mov    (%rax),%eax
  ret
L12:
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int bot_serial_translate_baud(int inrate) {
  switch (inrate) {
  case 0:
    return B0;
  case 300:
    return B300;
  case 1200:
    return B1200;
  case 2400:
    return B2400;
  case 4800:
    return B4800;
  case 9600:
    return B9600;
  case 19200:
    return B19200;
  case 38400:
    return B38400;
  case 57600:
    return B57600;
  case 115200:
    return B115200;
  case 230400:
    return B230400;
  case 460800:
    return B460800;
  default:
    return -1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bot_serial_translate_baud>:
  endbr64
  cmp    $0x4b00,%edi
  je     L33
  jg     L1
  cmp    $0x960,%edi
  je     L109
  jg     L119
  cmp    $0x12c,%edi
  je     L60
  cmp    $0x4b0,%edi
  jne    L70
  mov    D104(%rip),%rax
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L1:
  cmp    $0x1c200,%edi
  je     L85
  jle    L142
  cmp    $0x38400,%edi
  je     L6
  cmp    $0x70800,%edi
  jne    L113
  mov    D82(%rip),%rax
  mov    (%rax),%eax
  ret
L70:
  test   %edi,%edi
  jne    L113
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  cmp    $0x12c0,%edi
  je     L67
  cmp    $0x2580,%edi
  jne    L113
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L142:
  cmp    $0x9600,%edi
  je     L39
  cmp    $0xe100,%edi
  jne    L113
  mov    D62(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L109:
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  mov    D86(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    D117(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  mov    D95(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
L113:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int bot_serial_translate_baud(int inrate) {
  switch (inrate) {
  case 0:
    return B0;
  case 300:
    return B300;
  case 1200:
    return B1200;
  case 2400:
    return B2400;
  case 4800:
    return B4800;
  case 9600:
    return B9600;
  case 19200:
    return B19200;
  case 38400:
    return B38400;
  case 57600:
    return B57600;
  case 115200:
    return B115200;
  case 230400:
    return B230400;
  case 460800:
    return B460800;
  default:
    return -1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bot_serial_translate_baud>:
  endbr64
  cmp    $0x4b00,%edi
  je     L17
  jg     L16
  cmp    $0x960,%edi
  je     L15
  jg     L80
  cmp    $0x12c,%edi
  je     L60
  cmp    $0x4b0,%edi
  jne    L57
  mov    D52(%rip),%rax
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L16:
  cmp    $0x1c200,%edi
  je     L96
  jle    L124
  cmp    $0x38400,%edi
  je     L140
  cmp    $0x70800,%edi
  jne    L28
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  ret
L57:
  test   %edi,%edi
  jne    L28
  mov    D78(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  cmp    $0x12c0,%edi
  je     L136
  cmp    $0x2580,%edi
  jne    L28
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L124:
  cmp    $0x9600,%edi
  je     L106
  cmp    $0xe100,%edi
  jne    L28
  mov    D98(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    D109(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  mov    D79(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L140:
  mov    D90(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L136:
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L106:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  ret
L28:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int bot_serial_translate_baud(int inrate) {
  switch (inrate) {
  case 0:
    return B0;
  case 300:
    return B300;
  case 1200:
    return B1200;
  case 2400:
    return B2400;
  case 4800:
    return B4800;
  case 9600:
    return B9600;
  case 19200:
    return B19200;
  case 38400:
    return B38400;
  case 57600:
    return B57600;
  case 115200:
    return B115200;
  case 230400:
    return B230400;
  case 460800:
    return B460800;
  default:
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<blender_block_is_completed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <OS_disable_interrupts@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <dma_is_completed@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <OS_enable_interrupts@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int blender_block_is_completed(int transfer_size_8bit) {
  int finished;
  unsigned long ie;
  OS_disable_interrupts(&ie);
  finished = dma_is_completed(transfer_size_8bit);
  OS_enable_interrupts(ie);
  return finished;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blender_block_is_completed>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <OS_disable_interrupts@plt>
  mov    %ebx,%edi
  call   <dma_is_completed@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rdi
  call   <OS_enable_interrupts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blender_block_is_completed(int transfer_size_8bit) {
  int finished;
  unsigned long ie;
  OS_disable_interrupts(&ie);
  finished = dma_is_completed(transfer_size_8bit);
  OS_enable_interrupts(ie);
  return finished;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<blender_block_is_completed>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <OS_disable_interrupts@plt>
  mov    %ebp,%edi
  call   <dma_is_completed@plt>
  mov    (%rsp),%rdi
  mov    %eax,%r12d
  call   <OS_enable_interrupts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blender_block_is_completed(int transfer_size_8bit) {
  int finished;
  unsigned long ie;
  OS_disable_interrupts(&ie);
  finished = dma_is_completed(transfer_size_8bit);
  OS_enable_interrupts(ie);
  return finished;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<blender_block_is_completed>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <OS_disable_interrupts@plt>
  mov    %ebp,%edi
  call   <dma_is_completed@plt>
  mov    (%rsp),%rdi
  mov    %eax,%r12d
  call   <OS_enable_interrupts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int blender_block_is_completed(int transfer_size_8bit) {
  int finished;
  unsigned long ie;
  OS_disable_interrupts(&ie);
  finished = dma_is_completed(transfer_size_8bit);
  OS_enable_interrupts(ie);
  return finished;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mod_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D23
type: string

tool: D10:   %s_Size : constant Positive := %u;


tool: D25:   type %s_t is mod 2 ** %u;


tool: D24:   for %s_t'Size use %s_Size;


tool: D23:   pragma Convention (C, %s_t);


assistant: ```c
void mod_type(const char *name, size_t size) {
  (void)printf("  %s_Size : constant Positive := %u;\n", name, (unsigned int)size);
  (void)printf("  type %s_t is mod 2 ** %u;\n", name, (unsigned int)size);
  (void)printf("  for %s_t'Size use %s_Size;\n", name, name);
  (void)printf("  pragma Convention (C, %s_t);\n", name);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mod_type>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D30
type_infered: string

tool: D13:   %s_Size : constant Positive := %u;


tool: D3:   type %s_t is mod 2 ** %u;


tool: D10:   for %s_t'Size use %s_Size;


tool: D30:   pragma Convention (C, %s_t);


assistant: ```c
void mod_type(const char *name, size_t size) {
  (void)printf("  %s_Size : constant Positive := %u;\n", name, (unsigned int)size);
  (void)printf("  type %s_t is mod 2 ** %u;\n", name, (unsigned int)size);
  (void)printf("  for %s_t'Size use %s_Size;\n", name, name);
  (void)printf("  pragma Convention (C, %s_t);\n", name);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mod_type>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %esi,%r12d
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  xor    %eax,%eax
  pop    %rbp
  lea    D7(%rip),%rdi
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D7
data_type: string

tool: D19:   %s_Size : constant Positive := %u;


tool: D24:   type %s_t is mod 2 ** %u;


tool: D17:   for %s_t'Size use %s_Size;


tool: D7:   pragma Convention (C, %s_t);


assistant: ```c
void mod_type(const char *name, size_t size) {
  (void)printf("  %s_Size : constant Positive := %u;\n", name, (unsigned int)size);
  (void)printf("  type %s_t is mod 2 ** %u;\n", name, (unsigned int)size);
  (void)printf("  for %s_t'Size use %s_Size;\n", name, name);
  (void)printf("  pragma Convention (C, %s_t);\n", name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mod_type>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %esi,%r12d
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D20(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  xor    %eax,%eax
  pop    %rbp
  lea    D18(%rip),%rdi
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string

tool: D20:   %s_Size : constant Positive := %u;


tool: D10:   type %s_t is mod 2 ** %u;


tool: D2:   for %s_t'Size use %s_Size;


tool: D18:   pragma Convention (C, %s_t);


assistant: ```c
void mod_type(const char *name, size_t size) {
  (void)printf("  %s_Size : constant Positive := %u;\n", name, (unsigned int)size);
  (void)printf("  type %s_t is mod 2 ** %u;\n", name, (unsigned int)size);
  (void)printf("  for %s_t'Size use %s_Size;\n", name, name);
  (void)printf("  pragma Convention (C, %s_t);\n", name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int cmp(void *a, void *b) {
  char *as = (char *)a;
  char *bs = (char *)b;
  return strcmp(as, bs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmp(void *a, void *b) {
  char *as = (char *)a;
  char *bs = (char *)b;
  return strcmp(as, bs);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmp>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmp(void *a, void *b) {
  char *as = (char *)a;
  char *bs = (char *)b;
  return strcmp(as, bs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int cmp(void *a, void *b) {
  char *as = (char *)a;
  char *bs = (char *)b;
  return strcmp(as, bs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checaNumero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L24
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L46
L24:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L37
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L46
L37:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D45
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D49
type_infered: string
name: parse_data
arguments: label: D48
type_infered: string
name: parse_data
arguments: label: D47
type_infered: string

tool: D45: 
Entre com o numero: 

tool: D5: %d

tool: D49: NULO!!!

tool: D48: Par.

tool: D47: Impar.

assistant: ```c
void checaNumero() {
  int num;
  printf("\nEntre com o numero: ");
  scanf("%d", &num);
  if (num == 0) {
    printf("NULO!!!");
  } else {
    if (num % 2 == 0) {
      printf("Par.");
    } else {
      printf("Impar.");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checaNumero>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L42
  test   $0x1,%al
  jne    L30
  lea    D20(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L42:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L30:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D35
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string

tool: D35: 
Entre com o numero: 

tool: D19: %d

tool: D20: Par.

tool: D8: NULO!!!

tool: D49: Impar.

assistant: ```c
void checaNumero() {
  int num;
  printf("\nEntre com o numero: ");
  scanf("%d", &num);
  if (num == 0) {
    printf("NULO!!!");
  } else {
    if (num % 2 == 0) {
      printf("Par.");
    } else {
      printf("Impar.");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checaNumero>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L37
  test   $0x1,%al
  je     L31
  lea    D20(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L37:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D31
type_guessed: string
name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D41
type_guessed: string

tool: D11: 
Entre com o numero: 

tool: D31: %d

tool: D20: Impar.

tool: D2: Par.

tool: D41: NULO!!!

assistant: ```c
void checaNumero() {
  int num;
  printf("\nEntre com o numero: ");
  scanf("%d", &num);
  if (num == 0) {
    printf("NULO!!!");
  } else {
    if (num % 2 == 0) {
      printf("Par.");
    } else {
      printf("Impar.");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checaNumero>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L48
  test   $0x1,%al
  je     L35
  lea    D5(%rip),%rdi
  call   <printf@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L48:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D37
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string

tool: D3: 
Entre com o numero: 

tool: D0: %d

tool: D5: Impar.

tool: D37: Par.

tool: D28: NULO!!!

assistant: ```c
void checaNumero() {
  int num;
  printf("\nEntre com o numero: ");
  scanf("%d", &num);
  if (num == 0) {
    printf("NULO!!!");
  } else {
    if (num % 2 == 0) {
      printf("Par.");
    } else {
      printf("Impar.");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    $0x9,%esi
  call   <fill_roll_counts@plt>
  lea    0x90(%rsp),%rdi
  mov    $0x6,%edx
  mov    $0x6,%esi
  call   <fill_roll_counts@plt>
  mov    $0x1,%ecx
  mov    $0x0,%ebx
  mov    $0x0,%edi
  lea    0x90(%rsp),%rsi
L21:
  mov    %rcx,%rax
  mov    %edi,%edx
L14:
  add    (%rsp,%rax,4),%edx
  add    $0x1,%rax
  cmp    $0x23,%eax
  jle    L14
  imul   -0x4(%rsi,%rcx,4),%edx
  movslq %edx,%rdx
  add    %rdx,%rbx
  add    $0x1,%rcx
  cmp    $0x24,%rcx
  jne    L21
  mov    $0x9,%esi
  mov    $0x4,%edi
  call   <power@plt>
  mov    %rax,%rbp
  mov    $0x6,%esi
  mov    $0x6,%edi
  call   <power@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  imul   %rax,%rbp
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbp,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %.7f


assistant: ```c
int main(void) {
  int max_roll_a = 9 * 4;
  int max_roll_b = 6 * 6;
  int roll_counts_a[max_roll_a];
  int roll_counts_b[max_roll_b];
  fill_roll_counts(roll_counts_a, 9, 4);
  fill_roll_counts(roll_counts_b, 6, 6);
  long winning_rolls = 0;
  ;
  for (int i = 0; i < max_roll_b; i++) {
    int sum = 0;
    for (int j = i + 1; j < max_roll_a; j++)
      sum += roll_counts_a[j];
    winning_rolls += roll_counts_b[i] * sum;
  }
  long all_rolls = power(4, 9) * power(6, 6);
  printf("%.7f\n", winning_rolls / (double)all_rolls);
  return 0;
}
```