ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fp_locate>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    %esi,%ecx
  ja     L96
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %ecx,%esi
  mov    $0x0,%eax
  lea    -0x1(%rcx),%r11d
  mov    $0x0,%ebp
  sub    %ecx,%ebx
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L49
L23:
  mov    %rcx,%rdx
L99:
  mov    %edx,%edi
  lea    (%rax,%rdx,1),%ecx
  movzbl (%r9,%rcx,1),%ecx
  xor    (%r10,%rdx,1),%cl
  and    (%r8,%rdx,1),%cl
  jne    L97
  lea    0x1(%rdx),%edi
  lea    0x1(%rdx),%rcx
  cmp    %r11,%rdx
  jne    L23
L97:
  cmp    %edi,%esi
  je     L49
  add    $0x1,%eax
  cmp    %ebx,%eax
  je     L84
L4:
  test   %esi,%esi
  je     L49
  mov    %rbp,%rdx
  jmp    L99
L96:
  mov    $0xffffffff,%eax
  jmp    L49
L84:
  mov    $0xffffffff,%eax
L49:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fp_locate(unsigned char *data_buff, unsigned int data_len, unsigned char *find_buff, unsigned int find_len, unsigned char *mask_buff) {
  unsigned int s, i;
  if (find_len > data_len)
    return -1;
  for (s = 0; s < data_len - find_len; s++) {
    for (i = 0; i < find_len; i++) {
      if ((data_buff[s + i] & mask_buff[i]) != (find_buff[i] & mask_buff[i]))
        break;
    }
    if (i == find_len)
      return s;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fp_locate>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    %esi,%ecx
  ja     L11
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %ecx,%esi
  xor    %eax,%eax
  mov    %ecx,%r11d
  sub    %ecx,%ebx
  je     L11
  nopl   0x0(%rax)
L59:
  test   %esi,%esi
  je     L9
  xor    %edx,%edx
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L57:
  lea    0x1(%rdx),%edi
  add    $0x1,%rdx
  cmp    %rdx,%r11
  je     L39
L69:
  lea    (%rax,%rdx,1),%ecx
  mov    %edx,%edi
  movzbl (%r9,%rcx,1),%ecx
  xor    (%r10,%rdx,1),%cl
  and    (%r8,%rdx,1),%cl
  je     L57
L39:
  cmp    %edi,%esi
  je     L9
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L59
L11:
  mov    $0xffffffff,%eax
L9:
  pop    %rbx
  ret
```

assistant: ```c
int fp_locate(unsigned char *data_buff, unsigned int data_len, unsigned char *find_buff, unsigned int find_len, unsigned char *mask_buff) {
  unsigned int s, i;
  if (find_len > data_len)
    return -1;
  for (s = 0; s < data_len - find_len; s++) {
    for (i = 0; i < find_len; i++) {
      if ((data_buff[s + i] & mask_buff[i]) != (find_buff[i] & mask_buff[i]))
        break;
    }
    if (i == find_len)
      return s;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fp_locate>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    %esi,%ecx
  ja     L16
  mov    %rdi,%r9
  mov    %rdx,%r10
  mov    %ecx,%esi
  xor    %eax,%eax
  mov    %ecx,%r11d
  sub    %ecx,%ebx
  je     L16
  nopl   0x0(%rax)
L69:
  test   %esi,%esi
  je     L45
  xor    %edx,%edx
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rdx),%edi
  add    $0x1,%rdx
  cmp    %rdx,%r11
  je     L41
L59:
  lea    (%rax,%rdx,1),%ecx
  mov    %edx,%edi
  movzbl (%r9,%rcx,1),%ecx
  xor    (%r10,%rdx,1),%cl
  and    (%r8,%rdx,1),%cl
  je     L5
L41:
  cmp    %edi,%esi
  je     L45
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L69
L16:
  mov    $0xffffffff,%eax
L45:
  pop    %rbx
  ret
```

assistant: ```c
int fp_locate(unsigned char *data_buff, unsigned int data_len, unsigned char *find_buff, unsigned int find_len, unsigned char *mask_buff) {
  unsigned int s, i;
  if (find_len > data_len)
    return -1;
  for (s = 0; s < data_len - find_len; s++) {
    for (i = 0; i < find_len; i++) {
      if ((data_buff[s + i] & mask_buff[i]) != (find_buff[i] & mask_buff[i]))
        break;
    }
    if (i == find_len)
      return s;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<caesar_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L0:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L16
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <caesar_encrypt_char@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  jmp    L44
L16:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L44:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *caesar_encrypt(const char *plaintext, int key) {
  size_t plaintext_size = strlen(plaintext);
  char *ciphertext = (char *)malloc(plaintext_size + 1);
  char *ciphertext_start = ciphertext;
  while (*plaintext != '\0') {
    if (isalpha(*plaintext)) {
      *ciphertext = caesar_encrypt_char(tolower(*plaintext), key);
      if (isupper(*plaintext)) {
        *ciphertext = toupper(*ciphertext);
      }
    } else {
      *ciphertext = *plaintext;
    }
    ++plaintext;
    ++ciphertext;
  }
  *ciphertext = '\0';
  return ciphertext_start;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<caesar_encrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L5
  mov    %rax,%rbp
  jmp    L46
L56:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
L55:
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L10
L46:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L56
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <caesar_encrypt_char@plt>
  mov    %al,0x0(%rbp)
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L55
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp)
  jmp    L55
L5:
  mov    %rax,%rbp
L10:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *caesar_encrypt(const char *plaintext, int key) {
  size_t plaintext_size = strlen(plaintext);
  char *ciphertext = (char *)malloc(plaintext_size + 1);
  char *ciphertext_start = ciphertext;
  while (*plaintext != '\0') {
    if (isalpha(*plaintext)) {
      *ciphertext = caesar_encrypt_char(tolower(*plaintext), key);
      if (isupper(*plaintext)) {
        *ciphertext = toupper(*ciphertext);
      }
    } else {
      *ciphertext = *plaintext;
    }
    ++plaintext;
    ++ciphertext;
  }
  *ciphertext = '\0';
  return ciphertext_start;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<caesar_encrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r13
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L58
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
L30:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  test   %dil,%dil
  je     L8
L58:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L39
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <caesar_encrypt_char@plt>
  mov    %al,0x0(%rbp)
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L30
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <toupper@plt>
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L58
L8:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *caesar_encrypt(const char *plaintext, int key) {
  size_t plaintext_size = strlen(plaintext);
  char *ciphertext = (char *)malloc(plaintext_size + 1);
  char *ciphertext_start = ciphertext;
  while (*plaintext != '\0') {
    if (isalpha(*plaintext)) {
      *ciphertext = caesar_encrypt_char(tolower(*plaintext), key);
      if (isupper(*plaintext)) {
        *ciphertext = toupper(*ciphertext);
      }
    } else {
      *ciphertext = *plaintext;
    }
    ++plaintext;
    ++ciphertext;
  }
  *ciphertext = '\0';
  return ciphertext_start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<caesar_encrypt>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r13
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L23
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
L19:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  test   %dil,%dil
  je     L16
L23:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L35
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <caesar_encrypt_char@plt>
  mov    %al,0x0(%rbp)
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L19
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  add    $0x1,%rbp
  call   <toupper@plt>
  mov    %al,-0x1(%rbp)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L23
L16:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *caesar_encrypt(const char *plaintext, int key) {
  size_t plaintext_size = strlen(plaintext);
  char *ciphertext = (char *)malloc(plaintext_size + 1);
  char *ciphertext_start = ciphertext;
  while (*plaintext != '\0') {
    if (isalpha(*plaintext)) {
      *ciphertext = caesar_encrypt_char(tolower(*plaintext), key);
      if (isupper(*plaintext)) {
        *ciphertext = toupper(*ciphertext);
      }
    } else {
      *ciphertext = *plaintext;
    }
    ++plaintext;
    ++ciphertext;
  }
  *ciphertext = '\0';
  return ciphertext_start;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rotstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L13
L19:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <rot@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *rotstr(char str[]) {
  int slen = strlen(str);
  char *res = (char *)malloc(sizeof(char) * (slen + 1));
  int i;
  for (i = 0; i < slen; i++) {
    res[i] = rot(str[i]);
  }
  res[slen] = '\0';
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rotstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L16
  lea    -0x1(%r13),%eax
  lea    0x1(%r14,%rax,1),%r12
  mov    %r14,%rbx
  sub    %r14,%rbp
L13:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <rot@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L13
L16:
  movslq %r13d,%r13
  movb   $0x0,(%r14,%r13,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rotstr(char str[]) {
  int slen = strlen(str);
  char *res = (char *)malloc(sizeof(char) * (slen + 1));
  int i;
  for (i = 0; i < slen; i++) {
    res[i] = rot(str[i]);
  }
  res[slen] = '\0';
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%r13
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L6
  lea    -0x1(%r13),%eax
  mov    %r14,%rbx
  sub    %r14,%rbp
  lea    0x1(%r14,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <rot@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L5
L6:
  movb   $0x0,(%r14,%r13,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rotstr(char str[]) {
  int slen = strlen(str);
  char *res = (char *)malloc(sizeof(char) * (slen + 1));
  int i;
  for (i = 0; i < slen; i++) {
    res[i] = rot(str[i]);
  }
  res[slen] = '\0';
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rotstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%r13
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L1
  lea    -0x1(%r13),%eax
  mov    %r14,%rbx
  sub    %r14,%rbp
  lea    0x1(%r14,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <rot@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L6
L1:
  movb   $0x0,(%r14,%r13,1)
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *rotstr(char str[]) {
  int slen = strlen(str);
  char *res = (char *)malloc(sizeof(char) * (slen + 1));
  int i;
  for (i = 0; i < slen; i++) {
    res[i] = rot(str[i]);
  }
  res[slen] = '\0';
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  je     L16
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L17
L16:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bmount@plt>
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mi_chmod_f@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <imprimirInodoInfo@plt>
  mov    $0x0,%eax
  call   <bumount@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: Uso: permitir <nombre_dispositivo> <ninodo> <permisos>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 4) {
    puts("Uso: permitir <nombre_dispositivo> <ninodo> <permisos>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int ninodo = atoi(argv[2]), permisos = atoi(argv[3]);
  mi_chmod_f(ninodo, permisos);
  imprimirInodoInfo(ninodo);
  bumount();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  jne    L13
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <mi_chmod_f@plt>
  mov    %ebp,%edi
  call   <imprimirInodoInfo@plt>
  mov    $0x0,%eax
  call   <bumount@plt>
  mov    $0x0,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: Uso: permitir <nombre_dispositivo> <ninodo> <permisos>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 4) {
    puts("Uso: permitir <nombre_dispositivo> <ninodo> <permisos>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int ninodo = atoi(argv[2]), permisos = atoi(argv[3]);
  mi_chmod_f(ninodo, permisos);
  imprimirInodoInfo(ninodo);
  bumount();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  jne    L19
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <mi_chmod_f@plt>
  mov    %ebp,%edi
  call   <imprimirInodoInfo@plt>
  xor    %eax,%eax
  call   <bumount@plt>
  xor    %eax,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Uso: permitir <nombre_dispositivo> <ninodo> <permisos>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 4) {
    puts("Uso: permitir <nombre_dispositivo> <ninodo> <permisos>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int ninodo = atoi(argv[2]), permisos = atoi(argv[3]);
  mi_chmod_f(ninodo, permisos);
  imprimirInodoInfo(ninodo);
  bumount();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x4,%edi
  jne    L4
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <bmount@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x18(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <mi_chmod_f@plt>
  mov    %ebp,%edi
  call   <imprimirInodoInfo@plt>
  xor    %eax,%eax
  call   <bumount@plt>
  xor    %eax,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: Uso: permitir <nombre_dispositivo> <ninodo> <permisos>

assistant: ```c
int main(int argc, char const *argv[]) {
  if (argc != 4) {
    puts("Uso: permitir <nombre_dispositivo> <ninodo> <permisos>");
    return -1;
  }
  bmount(argv[1]);
  unsigned int ninodo = atoi(argv[2]), permisos = atoi(argv[3]);
  mi_chmod_f(ninodo, permisos);
  imprimirInodoInfo(ninodo);
  bumount();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<limpia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L39
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L39
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L23
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L15
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L2
L39:
  nop
L2:
  pop    %rbp
  ret
```

assistant: ```c
void limpia(int *tabla, int *n) {
  int i, j;
  if ((tabla == NULL) || ((*n) == 0))
    return;
  j = 0;
  for (i = 0; i < (*n); i++) {
    if (tabla[i] != -1) {
      tabla[j] = tabla[i];
      j++;
    }
  }
  *n = j;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<limpia>:
  endbr64
  test   %rdi,%rdi
  je     L51
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L51
  jle    L68
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L17
L30:
  movslq %ecx,%r8
  mov    %edx,(%rdi,%r8,4)
  add    $0x1,%ecx
L62:
  add    $0x1,%rax
  cmp    %eax,(%rsi)
  jle    L8
L17:
  mov    (%rdi,%rax,4),%edx
  cmp    $0xffffffff,%edx
  jne    L30
  jmp    L62
L68:
  mov    $0x0,%ecx
L8:
  mov    %ecx,(%rsi)
L51:
  ret
```

assistant: ```c
void limpia(int *tabla, int *n) {
  int i, j;
  if ((tabla == NULL) || ((*n) == 0))
    return;
  j = 0;
  for (i = 0; i < (*n); i++) {
    if (tabla[i] != -1) {
      tabla[j] = tabla[i];
      j++;
    }
  }
  *n = j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<limpia>:
  endbr64
  test   %rdi,%rdi
  je     L57
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L57
  jle    L2
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L28:
  mov    (%rdi,%rax,4),%edx
  cmp    $0xffffffff,%edx
  je     L5
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %edx,(%rdi,%r8,4)
L5:
  add    $0x1,%rax
  cmp    %eax,(%rsi)
  jg     L28
  mov    %ecx,(%rsi)
L57:
  ret
  nopl   (%rax)
L2:
  xor    %ecx,%ecx
  mov    %ecx,(%rsi)
  jmp    L57
```

assistant: ```c
void limpia(int *tabla, int *n) {
  int i, j;
  if ((tabla == NULL) || ((*n) == 0))
    return;
  j = 0;
  for (i = 0; i < (*n); i++) {
    if (tabla[i] != -1) {
      tabla[j] = tabla[i];
      j++;
    }
  }
  *n = j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<limpia>:
  endbr64
  test   %rdi,%rdi
  je     L49
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  je     L49
  jle    L53
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L55:
  mov    (%rdi,%rax,4),%edx
  cmp    $0xffffffff,%edx
  je     L63
  movslq %ecx,%r8
  add    $0x1,%rax
  add    $0x1,%ecx
  mov    %edx,(%rdi,%r8,4)
  mov    (%rsi),%r8d
  cmp    %eax,%r8d
  jg     L55
  mov    %ecx,(%rsi)
L49:
  ret
  nopl   0x0(%rax)
L63:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L55
  mov    %ecx,(%rsi)
  jmp    L49
  nopl   (%rax)
L53:
  xor    %ecx,%ecx
  mov    %ecx,(%rsi)
  jmp    L49
```

assistant: ```c
void limpia(int *tabla, int *n) {
  int i, j;
  if ((tabla == NULL) || ((*n) == 0))
    return;
  j = 0;
  for (i = 0; i < (*n); i++) {
    if (tabla[i] != -1) {
      tabla[j] = tabla[i];
      j++;
    }
  }
  *n = j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strdup_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <check@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strdup_check(char *str) {
  str = strdup(str);
  check((void *)str);
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strdup_check>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <check@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strdup_check(char *str) {
  str = strdup(str);
  check((void *)str);
  return str;
}
```