ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<valid_checksum>:
  endbr64
  push   %rbx
  xor    %r8d,%r8d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  cmpb   $0x24,(%rdi)
  jne    L54
  mov    %rdi,%rax
  xor    %ebx,%ebx
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rax),%eax
  cmp    $0x2a,%al
  je     L17
  test   %al,%al
  je     L17
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    $0x1,%rdi
  xor    %eax,%ebx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  cmp    $0x2a,%al
  jne    L39
L17:
  lea    0x7(%rsp),%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  xor    %r8d,%r8d
  cmp    %bl,0x7(%rsp)
  sete   %r8b
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: *%02hhx

assistant: ```c
int valid_checksum(char *str) {
  char *ptr = str;
  unsigned char c_cksum = 0;
  unsigned char r_cksum;
  if (str[0] != '$')
    return 0;
  str++;
  for (ptr = str; *ptr && (*ptr != '*'); ptr++)
    c_cksum ^= *ptr;
  sscanf(ptr, "*%02hhx", &r_cksum);
  return c_cksum == r_cksum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<valid_checksum>:
  endbr64
  push   %rbx
  xor    %r8d,%r8d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  cmpb   $0x24,(%rdi)
  jne    L6
  mov    %rdi,%rax
  xor    %ebx,%ebx
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rax),%eax
  cmp    $0x2a,%al
  je     L31
  test   %al,%al
  je     L31
  cs nopw 0x0(%rax,%rax,1)
L32:
  add    $0x1,%rdi
  xor    %eax,%ebx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
  cmp    $0x2a,%al
  jne    L32
L31:
  lea    0x7(%rsp),%rdx
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  xor    %r8d,%r8d
  cmp    %bl,0x7(%rsp)
  sete   %r8b
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: *%02hhx

assistant: ```c
int valid_checksum(char *str) {
  char *ptr = str;
  unsigned char c_cksum = 0;
  unsigned char r_cksum;
  if (str[0] != '$')
    return 0;
  str++;
  for (ptr = str; *ptr && (*ptr != '*'); ptr++)
    c_cksum ^= *ptr;
  sscanf(ptr, "*%02hhx", &r_cksum);
  return c_cksum == r_cksum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_uint_decimal_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    $0x1,%ebx
  jmp    L5
L2:
  add    $0x1,%ebx
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L2
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int get_uint_decimal_length(unsigned int num) {
  register unsigned int beta = 1;
  while ((num /= 10) != 0)
    beta++;
  return beta;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_uint_decimal_length>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L13
  mov    $0x1,%edx
  mov    $0xcccccccd,%esi
L24:
  add    $0x1,%edx
  mov    %eax,%ecx
  mov    %eax,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  ja     L24
L7:
  mov    %edx,%eax
  ret
L13:
  mov    $0x1,%edx
  jmp    L7
```

assistant: ```c
unsigned int get_uint_decimal_length(unsigned int num) {
  register unsigned int beta = 1;
  while ((num /= 10) != 0)
    beta++;
  return beta;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_uint_decimal_length>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%ecx
  mov    $0x1,%r8d
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L10
  xchg   %ax,%ax
L3:
  mov    %eax,%eax
  add    $0x1,%r8d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  ja     L3
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int get_uint_decimal_length(unsigned int num) {
  register unsigned int beta = 1;
  while ((num /= 10) != 0)
    beta++;
  return beta;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_uint_decimal_length>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%ecx
  mov    $0x1,%r8d
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L1
  xchg   %ax,%ax
L15:
  mov    %eax,%eax
  add    $0x1,%r8d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  ja     L15
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int get_uint_decimal_length(unsigned int num) {
  register unsigned int beta = 1;
  while ((num /= 10) != 0)
    beta++;
  return beta;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,%eax
  mov    %al,-0x3c(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L32
L73:
  movsbl -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_str_count_splits@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L46
  mov    $0x0,%eax
  jmp    L32
L46:
  movl   $0x0,-0x24(%rbp)
  jmp    L67
L48:
  movsbl -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <ft_str_find_next@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
  movsbl -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <ft_str_find_next@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_strsub@plt>
  mov    %rax,(%rbx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L22
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_tabledel@plt>
  jmp    L32
L22:
  addl   $0x1,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x38(%rbp)
L67:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **ft_strsplit(char const *str, char c) {
  char **ret;
  int i;
  const char *next;
  if (str == NULL)
    return (NULL);
  ret = (char **)malloc(sizeof(char *) * (ft_str_count_splits(str, c) + 1));
  if (ret == NULL)
    return (NULL);
  i = 0;
  while (*str != '\0') {
    str = ft_str_find_next(str, c, 1);
    if (*str != '\0') {
      next = ft_str_find_next(str, c, 0);
      ret[i] = ft_strsub(str, 0, next - str);
      if (ret[i] == NULL)
        return (ft_tabledel(ret, i));
      i++;
      str = next;
    }
  }
  ret[i] = 0;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L29
  movsbl %sil,%ebp
  mov    %ebp,%esi
  call   <ft_str_count_splits@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L51
  mov    %rax,%r15
  mov    $0x0,%r13d
L43:
  cmpb   $0x0,(%rbx)
  je     L39
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <ft_str_find_next@plt>
  mov    %rax,%rbx
  cmpb   $0x0,(%rax)
  je     L43
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <ft_str_find_next@plt>
  mov    %rax,%r14
  mov    %eax,%edx
  sub    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ft_strsub@plt>
  mov    %rax,(%r15)
  add    $0x8,%r15
  test   %rax,%rax
  je     L8
  add    $0x1,%r13d
  mov    %r14,%rbx
  jmp    L43
L8:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <ft_tabledel@plt>
  mov    %rax,0x8(%rsp)
  jmp    L36
L39:
  movslq %r13d,%r13
  movq   $0x0,(%r12,%r13,8)
L36:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %rdi,0x8(%rsp)
  jmp    L36
L51:
  movq   $0x0,0x8(%rsp)
  jmp    L36
```

assistant: ```c
char **ft_strsplit(char const *str, char c) {
  char **ret;
  int i;
  const char *next;
  if (str == NULL)
    return (NULL);
  ret = (char **)malloc(sizeof(char *) * (ft_str_count_splits(str, c) + 1));
  if (ret == NULL)
    return (NULL);
  i = 0;
  while (*str != '\0') {
    str = ft_str_find_next(str, c, 1);
    if (*str != '\0') {
      next = ft_str_find_next(str, c, 0);
      ret[i] = ft_strsub(str, 0, next - str);
      if (ret[i] == NULL)
        return (ft_tabledel(ret, i));
      i++;
      str = next;
    }
  }
  ret[i] = 0;
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  movsbl %sil,%ebx
  mov    %rdi,%r15
  mov    %ebx,%esi
  call   <ft_str_count_splits@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rax,%r14
  xor    %r13d,%r13d
L14:
  cmpb   $0x0,(%r15)
  je     L42
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <ft_str_find_next@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rbp
  jne    L49
L42:
  movslq %r13d,%r13
  movq   $0x0,(%r12,%r13,8)
L34:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L49:
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %rax,%rdi
  add    $0x8,%r14
  call   <ft_str_find_next@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %rax,%r15
  sub    %ebp,%edx
  call   <ft_strsub@plt>
  mov    %rax,-0x8(%r14)
  test   %rax,%rax
  je     L17
  add    $0x1,%r13d
  jmp    L14
L2:
  xor    %r12d,%r12d
  jmp    L34
L17:
  add    $0x8,%rsp
  mov    %r13d,%esi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <ft_tabledel@plt>
```

assistant: ```c
char **ft_strsplit(char const *str, char c) {
  char **ret;
  int i;
  const char *next;
  if (str == NULL)
    return (NULL);
  ret = (char **)malloc(sizeof(char *) * (ft_str_count_splits(str, c) + 1));
  if (ret == NULL)
    return (NULL);
  i = 0;
  while (*str != '\0') {
    str = ft_str_find_next(str, c, 1);
    if (*str != '\0') {
      next = ft_str_find_next(str, c, 0);
      ret[i] = ft_strsub(str, 0, next - str);
      if (ret[i] == NULL)
        return (ft_tabledel(ret, i));
      i++;
      str = next;
    }
  }
  ret[i] = 0;
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L7
  movsbl %sil,%ebx
  mov    %rdi,%r15
  mov    %ebx,%esi
  call   <ft_str_count_splits@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rax,%r14
  xor    %r13d,%r13d
L62:
  cmpb   $0x0,(%r15)
  je     L29
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <ft_str_find_next@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rbp
  jne    L1
L29:
  movslq %r13d,%r13
  movq   $0x0,(%r12,%r13,8)
L65:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L1:
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %rax,%rdi
  add    $0x8,%r14
  call   <ft_str_find_next@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %rax,%r15
  sub    %ebp,%edx
  call   <ft_strsub@plt>
  mov    %rax,-0x8(%r14)
  test   %rax,%rax
  je     L60
  add    $0x1,%r13d
  jmp    L62
L7:
  xor    %r12d,%r12d
  jmp    L65
L60:
  add    $0x8,%rsp
  mov    %r13d,%esi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <ft_tabledel@plt>
```

assistant: ```c
char **ft_strsplit(char const *str, char c) {
  char **ret;
  int i;
  const char *next;
  if (str == NULL)
    return (NULL);
  ret = (char **)malloc(sizeof(char *) * (ft_str_count_splits(str, c) + 1));
  if (ret == NULL)
    return (NULL);
  i = 0;
  while (*str != '\0') {
    str = ft_str_find_next(str, c, 1);
    if (*str != '\0') {
      next = ft_str_find_next(str, c, 0);
      ret[i] = ft_strsub(str, 0, next - str);
      if (ret[i] == NULL)
        return (ft_tabledel(ret, i));
      i++;
      str = next;
    }
  }
  ret[i] = 0;
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<grad2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movss  %xmm0,-0x18(%rbp)
  movss  %xmm1,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jg     L50
  movss  -0x18(%rbp),%xmm0
  jmp    L58
L50:
  movss  -0x1c(%rbp),%xmm0
L58:
  movss  %xmm0,-0x8(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jg     L33
  movss  -0x1c(%rbp),%xmm0
  jmp    L73
L33:
  movss  -0x18(%rbp),%xmm0
L73:
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L47
  movss  -0x8(%rbp),%xmm0
  movss  D15(%rip),%xmm1
  xorps  %xmm0,%xmm1
  jmp    L60
L47:
  movss  -0x8(%rbp),%xmm1
L60:
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L39
  movss  -0x4(%rbp),%xmm2
  movss  D17(%rip),%xmm0
  mulss  %xmm2,%xmm0
  jmp    L17
L39:
  movss  -0x4(%rbp),%xmm0
  addss  %xmm0,%xmm0
L17:
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: byte[4]
name: read_data
arguments: data_tag: D17
datatype: byte[4]

tool: {"D15": [0x00,0x00,0x00,0x80]}

tool: {"D17": [0x00,0x00,0x00,0xc0]}

assistant: ```c
float grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0f * v : 2.0f * v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<grad2>:
  endbr64
  test   $0x4,%dil
  jne    L5
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
L5:
  test   $0x1,%dil
  je     L25
  xorps  D11(%rip),%xmm1
L25:
  test   $0x2,%dil
  je     L15
  mulss  D13(%rip),%xmm0
L0:
  addss  %xmm1,%xmm0
  ret
L15:
  addss  %xmm0,%xmm0
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D13
type_guessed: byte[4]

tool: {"D11": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x00,0xc0]}

assistant: ```c
float grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0f * v : 2.0f * v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<grad2>:
  endbr64
  test   $0x4,%dil
  je     L25
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
L25:
  test   $0x1,%dil
  je     L5
  xorps  D9(%rip),%xmm0
L5:
  and    $0x2,%edi
  je     L3
  mulss  D13(%rip),%xmm1
  addss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  addss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D13
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x00,0xc0]}

assistant: ```c
float grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0f * v : 2.0f * v);
}
```
user: Translate the below assembly code into C programming language:

```asm
<grad2>:
  endbr64
  test   $0x4,%dil
  je     L24
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
L24:
  test   $0x1,%dil
  je     L20
  xorps  D14(%rip),%xmm0
L20:
  and    $0x2,%edi
  je     L17
  mulss  D16(%rip),%xmm1
  addss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  addss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: byte[16]
name: disassemble_data
arguments: label: D16
data_type: byte[4]

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0xc0]}

assistant: ```c
float grad2(int hash, float x, float y) {
  int h = hash & 7;
  float u = h < 4 ? x : y;
  float v = h < 4 ? y : x;
  return ((h & 1) ? -u : u) + ((h & 2) ? -2.0f * v : 2.0f * v);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hashpjw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L1:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L9
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  xor    %eax,-0x10(%rbp)
L9:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x10(%rbp),%edx
  mov    %edx,%ecx
  mov    $0x9b4c6f9f,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0x7,%eax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int hashpjw(char *s) {
  char *p;
  unsigned h = 0, g;
  for (p = s; *p != '\0'; p++) {
    h = (h << 4) + (*p);
    if (g = h & 0xf0000000) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h % 211;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hashpjw>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L33
  mov    $0x0,%edx
  jmp    L11
L26:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
L11:
  shl    $0x4,%edx
  movsbl %al,%eax
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  je     L26
  and    $0xfffffff,%edx
  shr    $0x18,%eax
  xor    %eax,%edx
  jmp    L26
L33:
  mov    $0x0,%edx
L6:
  mov    %edx,%eax
  mov    $0x9b4c6f9f,%ecx
  imul   %rcx,%rax
  shr    $0x27,%rax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int hashpjw(char *s) {
  char *p;
  unsigned h = 0, g;
  for (p = s; *p != '\0'; p++) {
    h = (h << 4) + (*p);
    if (g = h & 0xf0000000) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h % 211;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashpjw>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L9
  xor    %edx,%edx
  nopl   (%rax)
L24:
  shl    $0x4,%edx
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  je     L25
  and    $0xfffffff,%edx
  shr    $0x18,%eax
  xor    %eax,%edx
L25:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L24
  mov    %edx,%eax
  mov    $0x9b4c6f9f,%ecx
  imul   %rcx,%rax
  shr    $0x27,%rax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nop
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hashpjw(char *s) {
  char *p;
  unsigned h = 0, g;
  for (p = s; *p != '\0'; p++) {
    h = (h << 4) + (*p);
    if (g = h & 0xf0000000) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h % 211;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashpjw>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L24
  xor    %edx,%edx
  nopl   (%rax)
L11:
  shl    $0x4,%edx
  add    %eax,%edx
  mov    %edx,%eax
  and    $0xf0000000,%eax
  je     L18
  and    $0xfffffff,%edx
  shr    $0x18,%eax
  xor    %eax,%edx
L18:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L11
  mov    %edx,%eax
  mov    $0x9b4c6f9f,%ecx
  imul   %rcx,%rax
  shr    $0x27,%rax
  imul   $0xd3,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nop
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hashpjw(char *s) {
  char *p;
  unsigned h = 0, g;
  for (p = s; *p != '\0'; p++) {
    h = (h << 4) + (*p);
    if (g = h & 0xf0000000) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h % 211;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<x_bytes_to_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L7:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x4,-0x18(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t x_bytes_to_num(uint8_t *src, size_t len) {
  uint64_t num = 0;
  while (len--) {
    num = (num << 8) | (*src);
    src++;
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<x_bytes_to_num>:
  endbr64
  test   %rsi,%rsi
  je     L3
  mov    $0x0,%edx
  mov    $0x0,%eax
L16:
  shl    $0x8,%eax
  or     (%rdi,%rdx,4),%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L16
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint64_t x_bytes_to_num(uint8_t *src, size_t len) {
  uint64_t num = 0;
  while (len--) {
    num = (num << 8) | (*src);
    src++;
  }
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<x_bytes_to_num>:
  endbr64
  test   %rsi,%rsi
  je     L17
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   (%rax)
L15:
  shl    $0x8,%eax
  or     (%rdi,%rdx,4),%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L15
  ret
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t x_bytes_to_num(uint8_t *src, size_t len) {
  uint64_t num = 0;
  while (len--) {
    num = (num << 8) | (*src);
    src++;
  }
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<x_bytes_to_num>:
  endbr64
  test   %rsi,%rsi
  je     L12
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   (%rax)
L10:
  shl    $0x8,%eax
  or     (%rdi,%rdx,4),%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L10
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t x_bytes_to_num(uint8_t *src, size_t len) {
  uint64_t num = 0;
  while (len--) {
    num = (num << 8) | (*src);
    src++;
  }
  return num;
}
```