ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_mul>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <mul_i8@plt>
  cmp    $0xffffffff,%eax
  jne    L39
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <mul_i8@plt>
  cmp    $0x1,%eax
  je     L22
L39:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <fail@plt>
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <mul_i8@plt>
  cmp    $0x1,%eax
  jne    L39
  mov    $0x23,%esi
  mov    $0x11,%edi
  call   <mul_i8@plt>
  cmp    $0x53,%eax
  jne    L39
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <mul_i16@plt>
  cmp    $0xffffffff,%eax
  jne    L39
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <mul_i16@plt>
  cmp    $0x1,%eax
  jne    L39
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <mul_i16@plt>
  cmp    $0x1,%eax
  jne    L39
  mov    $0x367,%esi
  mov    $0xb3,%edi
  call   <mul_i16@plt>
  cmp    $0x6105,%eax
  jne    L39
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <mul_i32@plt>
  cmp    $0xffffffff,%eax
  jne    L39
  mov    $0xffffffff,%esi
  mov    $0xffffffff,%edi
  call   <mul_i32@plt>
  cmp    $0x1,%eax
  jne    L39
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <mul_i32@plt>
  sub    $0x1,%eax
  jne    L39
  mov    $0xd4de8,%esi
  mov    $0x2bd50,%edi
  call   <mul_i32@plt>
  cmp    $0x727ca080,%eax
  jne    L39
  or     $0xffffffff,%edi
  mov    $0x1,%esi
  call   <mul_i64@plt>
  add    $0x1,%eax
  jne    L39
  or     $0xffffffff,%esi
  or     $0xffffffff,%edi
  call   <mul_i64@plt>
  sub    $0x1,%eax
  jne    L39
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <mul_i64@plt>
  sub    $0x1,%eax
  jne    L39
  mov    $0x7b34a7f,%esi
  mov    $0x2e1e871d,%edi
  call   <mul_i64@plt>
  jmp    L39
```

assistant: ```c
int test_mul(void) {
  if (mul_i8(-1, 1) != -1)
    return fail(0);
  if (mul_i8(-1, -1) != 1)
    return fail(0);
  if (mul_i8(1, 1) != 1)
    return fail(0);
  if (mul_i8(17, 35) != 83)
    return fail(0);
  if (mul_i16(-1, 1) != -1)
    return fail(0);
  if (mul_i16(-1, -1) != 1)
    return fail(0);
  if (mul_i16(1, 1) != 1)
    return fail(0);
  if (mul_i16(179, 871) != 24837)
    return fail(0);
  if (mul_i32(-1, 1) != -1)
    return fail(0);
  if (mul_i32(-1, -1) != 1)
    return fail(0);
  if (mul_i32(1, 1) != 1)
    return fail(0);
  if (mul_i32(179536, 871912) != 1920770176)
    return fail(0);
  if (mul_i64(-1, 1) != -1)
    return fail(0);
  if (mul_i64(-1, -1) != 1)
    return fail(0);
  if (mul_i64(1, 1) != 1)
    return fail(0);
  if (mul_i64(17953621789, 8719125119) != 8965922127819204963)
    return fail(0);
  return 0x10;
}
```
user: Translate the below assembly code into C programming language:

```asm
<radixToTen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L10:
  addq   $0x4,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L15:
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    -0x10(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <power@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L37:
  addq   $0x4,-0x18(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0xc(%rbp)
L6:
  cmpq   $0x0,-0x18(%rbp)
  jne    L37
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int radixToTen(unsigned int *num, int radix) {
  unsigned power(int x, int y);
  unsigned highestPower = 0;
  int *temp = num;
  while (temp != NULL) {
    temp++;
    highestPower++;
  }
  highestPower = power(highestPower, radix);
  unsigned ans = highestPower * (*num);
  while (num != NULL) {
    num++;
    ans += (highestPower / radix) * (*num);
  }
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<radixToTen>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <power@plt>
  imul   0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int radixToTen(unsigned int *num, int radix) {
  unsigned power(int x, int y);
  unsigned highestPower = 0;
  int *temp = num;
  while (temp != NULL) {
    temp++;
    highestPower++;
  }
  highestPower = power(highestPower, radix);
  unsigned ans = highestPower * (*num);
  while (num != NULL) {
    num++;
    ans += (highestPower / radix) * (*num);
  }
  return ans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<radixToTen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <power@plt>
  imul   (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int radixToTen(unsigned int *num, int radix) {
  unsigned power(int x, int y);
  unsigned highestPower = 0;
  int *temp = num;
  while (temp != NULL) {
    temp++;
    highestPower++;
  }
  highestPower = power(highestPower, radix);
  unsigned ans = highestPower * (*num);
  while (num != NULL) {
    num++;
    ans += (highestPower / radix) * (*num);
  }
  return ans;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<radixToTen>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <power@plt>
  imul   (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int radixToTen(unsigned int *num, int radix) {
  unsigned power(int x, int y);
  unsigned highestPower = 0;
  int *temp = num;
  while (temp != NULL) {
    temp++;
    highestPower++;
  }
  highestPower = power(highestPower, radix);
  unsigned ans = highestPower * (*num);
  while (num != NULL) {
    num++;
    ans += (highestPower / radix) * (*num);
  }
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isfixable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %rdi,-0x3f8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rax
  movw   $0x5f,(%rax)
  mov    -0x3f8(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  lea    -0x3f0(%rbp),%rax
  add    %rdx,%rax
  movl   $0x727470,(%rax)
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <istype@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int isfixable(name)
char *name;
{
  char buffer[1000];
  strcpy(buffer, "_");
  strcat(buffer, name);
  strcat(buffer, "ptr");
  return istype(buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isfixable>:
  endbr64
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movw   $0x5f,(%rsp)
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movl   $0x727470,(%rbx,%rax,1)
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <istype@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x3f0,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfixable(name)
char *name;
{
  char buffer[1000];
  strcpy(buffer, "_");
  strcat(buffer, name);
  strcat(buffer, "ptr");
  return istype(buffer);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isfixable>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%rdi
  movb   $0x5f,(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  movl   $0x727470,0x0(%rbp,%rax,1)
  xor    %eax,%eax
  call   <istype@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x3f0,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfixable(name)
char *name;
{
  char buffer[1000];
  strcpy(buffer, "_");
  strcat(buffer, name);
  strcat(buffer, "ptr");
  return istype(buffer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isfixable>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%rdi
  movb   $0x5f,(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  movl   $0x727470,0x0(%rbp,%rax,1)
  xor    %eax,%eax
  call   <istype@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x3f0,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isfixable(name)
char *name;
{
  char buffer[1000];
  strcpy(buffer, "_");
  strcat(buffer, name);
  strcat(buffer, "ptr");
  return istype(buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no)) bar(int k) {
  int n = k % 2;
  if (n == 0)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  test   $0x1,%dil
  je     L0
  ret
L0:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no)) bar(int k) {
  int n = k % 2;
  if (n == 0)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bar>:
  endbr64
  and    $0x1,%edi
  je     L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) bar(int k) {
  int n = k % 2;
  if (n == 0)
    abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  and    $0x1,%edi
  je     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) bar(int k) {
  int n = k % 2;
  if (n == 0)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_double>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movapd %xmm0,%xmm4
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  comisd %xmm4,%xmm0
  ja     L39
L79:
  movsd  0x8(%rsp),%xmm3
  cvttsd2si %xmm3,%rax
  mov    %eax,%edx
  mov    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  %xmm0,%xmm3
  movq   %xmm3,%r14
  lea    0x10(%rsp),%r8
  lea    0x1c(%rsp),%r9
  mov    %r8,%rcx
  mov    $0xcccccccd,%edi
L63:
  mov    %edx,%eax
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,(%rcx)
  mov    %eax,%edx
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L63
  lea    0x1b(%rsp),%rdx
  mov    $0xb,%eax
L46:
  cmpb   $0x0,(%rdx)
  jne    L9
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L46
L9:
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  movslq %eax,%rdx
  lea    0x10(%rsp,%rdx,1),%rbx
  lea    -0x1(%r8,%rdx,1),%rbp
  mov    %eax,%eax
  sub    %rax,%rbp
L35:
  movzbl (%rbx),%eax
  lea    0x30(%rax),%edi
  movsbl %dil,%edi
  call   <myputc@plt>
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L35
  mov    $0x2e,%edi
  call   <myputc@plt>
  mov    $0xe,%ebp
L66:
  movsd  D12(%rip),%xmm1
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  cvttsd2si %xmm1,%rbx
  lea    0x30(%rbx),%edi
  movsbl %dil,%edi
  call   <myputc@plt>
  mov    %ebx,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  movq   %xmm1,%r14
  sub    $0x1,%ebp
  jne    L66
  mov    $0xa,%edi
  call   <myputc@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L39:
  mov    $0x2d,%edi
  call   <myputc@plt>
  movsd  0x8(%rsp),%xmm5
  xorpd  D15(%rip),%xmm5
  movsd  %xmm5,0x8(%rsp)
  jmp    L79
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
data_type: f64
name: unpack_data
arguments: data_label: D15
data_type: byte[16]

tool: D12: 10

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void print_double(double x) {
  unsigned int xi;
  char buf[16];
  int i;
  if (x < 0) {
    myputc('-');
    x = -x;
  }
  xi = (unsigned int)x;
  x -= (double)xi;
  for (i = 0; i < 12; i++) {
    buf[i] = xi % 10;
    xi /= 10;
  }
  for (i--; i >= 0; i--)
    if (buf[i] != 0)
      break;
  if (i < 0)
    i = 0;
  for (; i >= 0; i--)
    myputc('0' + buf[i]);
  myputc('.');
  for (i = 0; i < 14; i++) {
    x *= 10.0;
    xi = (unsigned int)x;
    myputc('0' + xi);
    x -= (double)xi;
  }
  myputc('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_double>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  ja     L73
L83:
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  lea    0x10(%rsp),%rbx
  mov    $0xcccccccd,%edi
  mov    %rbx,%rcx
  lea    0x1c(%rsp),%r8
  mov    %eax,%edx
  mov    %eax,%eax
  cvtsi2sd %rax,%xmm1
  subsd  %xmm1,%xmm0
L11:
  mov    %edx,%eax
  add    $0x1,%rcx
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  mov    %dl,-0x1(%rcx)
  mov    %eax,%edx
  cmp    %rcx,%r8
  jne    L11
  mov    $0xb,%eax
  nopl   0x0(%rax)
L2:
  movzbl (%rbx,%rax,1),%edi
  mov    %eax,%ebp
  test   %dil,%dil
  jne    L93
  sub    $0x1,%rax
  jae    L2
  movzbl 0x10(%rsp),%eax
  movsd  %xmm0,0x8(%rsp)
  lea    0x30(%rax),%edi
  movsbl %dil,%edi
  call   <myputc@plt>
  movsd  0x8(%rsp),%xmm0
L29:
  mov    $0x2e,%edi
  movsd  %xmm0,0x8(%rsp)
  mov    $0xe,%ebp
  call   <myputc@plt>
  movsd  0x8(%rsp),%xmm0
  nopl   (%rax)
L14:
  mulsd  D16(%rip),%xmm0
  cvttsd2si %xmm0,%rbx
  movsd  %xmm0,0x8(%rsp)
  lea    0x30(%rbx),%edi
  mov    %ebx,%ebx
  movsbl %dil,%edi
  call   <myputc@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rbx,%xmm1
  subsd  %xmm1,%xmm0
  sub    $0x1,%ebp
  jne    L14
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <myputc@plt>
  nopl   0x0(%rax)
L93:
  sub    $0x1,%ebp
  movslq %ebp,%rbp
  jmp    L90
L99:
  movzbl (%rbx,%rbp,1),%edi
  sub    $0x1,%rbp
L90:
  add    $0x30,%edi
  movsd  %xmm0,0x8(%rsp)
  movsbl %dil,%edi
  call   <myputc@plt>
  cmp    $0xffffffff,%ebp
  movsd  0x8(%rsp),%xmm0
  jne    L99
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L73:
  mov    $0x2d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <myputc@plt>
  movsd  0x8(%rsp),%xmm0
  xorpd  D14(%rip),%xmm0
  jmp    L83
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: f64
name: parse_data
arguments: tag: D14
datatype: byte[16]

tool: D16: 10

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void print_double(double x) {
  unsigned int xi;
  char buf[16];
  int i;
  if (x < 0) {
    myputc('-');
    x = -x;
  }
  xi = (unsigned int)x;
  x -= (double)xi;
  for (i = 0; i < 12; i++) {
    buf[i] = xi % 10;
    xi /= 10;
  }
  for (i--; i >= 0; i--)
    if (buf[i] != 0)
      break;
  if (i < 0)
    i = 0;
  for (; i >= 0; i--)
    myputc('0' + buf[i]);
  myputc('.');
  for (i = 0; i < 14; i++) {
    x *= 10.0;
    xi = (unsigned int)x;
    myputc('0' + xi);
    x -= (double)xi;
  }
  myputc('\n');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x3d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x13d0(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x13c8(%rbp)
  jmp    L33
L14:
  movl   $0x0,-0x13c4(%rbp)
  movl   $0x0,-0x13cc(%rbp)
  jmp    L49
L0:
  lea    -0x13c0(%rbp),%rdx
  mov    -0x13cc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  lea    -0x1390(%rbp),%rcx
  mov    -0x13cc(%rbp),%eax
  cltq
  imul   $0x1f4,%rax,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x13cc(%rbp),%eax
  cltq
  mov    -0x13c0(%rbp,%rax,4),%eax
  cmp    %eax,-0x13c4(%rbp)
  jge    L58
  mov    -0x13cc(%rbp),%eax
  cltq
  mov    -0x13c0(%rbp,%rax,4),%eax
  mov    %eax,-0x13c4(%rbp)
L58:
  addl   $0x1,-0x13cc(%rbp)
L49:
  cmpl   $0x9,-0x13cc(%rbp)
  jle    L0
  mov    -0x13c8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x13cc(%rbp)
  jmp    L80
L38:
  mov    -0x13cc(%rbp),%eax
  cltq
  mov    -0x13c0(%rbp,%rax,4),%eax
  cmp    %eax,-0x13c4(%rbp)
  jne    L89
  lea    -0x1390(%rbp),%rdx
  mov    -0x13cc(%rbp),%eax
  cltq
  imul   $0x1f4,%rax,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <puts@plt>
L89:
  addl   $0x1,-0x13cc(%rbp)
L80:
  cmpl   $0x9,-0x13cc(%rbp)
  jle    L38
  addl   $0x1,-0x13c8(%rbp)
L33:
  mov    -0x13d0(%rbp),%eax
  cmp    %eax,-0x13c8(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D29: %d

tool: D5: %s%d

tool: D1: Case #%d:


assistant: ```c
int main() {
  int t, i, j, rank[10];
  char in[10][500];
  scanf("%d", &t);
  for (j = 1; j <= t; j++) {
    int max = 0;
    for (i = 0; i < 10; i++) {
      scanf("%s%d", in[i], &rank[i]);
      if (rank[i] > max)
        max = rank[i];
    }
    printf("Case #%d:\n", j);
    for (i = 0; i < 10; i++) {
      if (rank[i] == max)
        printf("%s\n", in[i]);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x3e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13d8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  movl   $0x1,0xc(%rsp)
  lea    0x13d8(%rsp),%r15
  cmpl   $0x0,0x1c(%rsp)
  jg     L11
L38:
  mov    0x13d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x13e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  add    $0x4,%r14
  add    $0x1f4,%r13
  cmp    %r15,%r13
  je     L34
L18:
  cmp    %ebx,(%r14)
  jne    L53
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L53
L34:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jl     L38
L11:
  lea    0x50(%rsp),%r13
  lea    0x20(%rsp),%r14
  mov    %r14,%r12
  mov    %r13,%rbp
  mov    $0x0,%ebx
L60:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%r12),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    $0x1f4,%rbp
  add    $0x4,%r12
  cmp    %r15,%rbp
  jne    L60
  mov    0xc(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D29
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string

tool: D7: %d

tool: D29: %s%d

tool: D10: Case #%d:


assistant: ```c
int main() {
  int t, i, j, rank[10];
  char in[10][500];
  scanf("%d", &t);
  for (j = 1; j <= t; j++) {
    int max = 0;
    for (i = 0; i < 10; i++) {
      scanf("%s%d", in[i], &rank[i]);
      if (rank[i] > max)
        max = rank[i];
    }
    printf("Case #%d:\n", j);
    for (i = 0; i < 10; i++) {
      if (rank[i] == max)
        printf("%s\n", in[i]);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x3f8,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x13e8(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L69
  lea    0x60(%rsp),%rax
  movl   $0x1,0xc(%rsp)
  lea    D20(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0x13e8(%rsp),%rax
  mov    %rax,(%rsp)
L34:
  mov    0x10(%rsp),%r12
  mov    0x18(%rsp),%rbx
  xor    %r13d,%r13d
  mov    %r12,%r15
  mov    %rbx,%r14
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  add    $0x1f4,%r12
  add    $0x4,%rbx
  cmp    (%rsp),%r12
  jne    L36
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L79
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x4,%r14
  add    $0x1f4,%r15
  cmp    (%rsp),%r15
  je     L61
L79:
  cmp    %r13d,(%r14)
  jne    L1
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L1
L61:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jge    L34
L69:
  mov    0x13e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x13f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D8
data_type: string

tool: D11: %d

tool: D20: %s%d

tool: D8: Case #%d:


assistant: ```c
int main() {
  int t, i, j, rank[10];
  char in[10][500];
  scanf("%d", &t);
  for (j = 1; j <= t; j++) {
    int max = 0;
    for (i = 0; i < 10; i++) {
      scanf("%s%d", in[i], &rank[i]);
      if (rank[i] > max)
        max = rank[i];
    }
    printf("Case #%d:\n", j);
    for (i = 0; i < 10; i++) {
      if (rank[i] == max)
        printf("%s\n", in[i]);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<removeMonitor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <removeCommand@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <removeCommand@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: ?

assistant: ```c
void removeMonitor(const char *command) {
  char *buf;
  removeCommand(command);
  buf = (char *)malloc(strlen(command) + 2);
  strcpy(buf, command);
  strcat(buf, "?");
  removeCommand(buf);
  free(buf);
}
```