ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_page_access>:
  endbr64
  cmp    $0x4000,%esi
  jg     L7
  cmp    $0x3fff,%edi
  jg     L7
  add    %esi,%edi
  cmp    $0x4000,%edi
  setle  %al
  movzbl %al,%eax
  lea    -0x3(%rax,%rax,2),%eax
  ret
L7:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int check_page_access(uint32_t page, uint32_t count) {
  if (page >= ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if (count > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if ((page + count) > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_page_access>:
  endbr64
  cmp    $0x3fff,%edi
  jg     L10
  cmp    $0x4000,%esi
  jg     L10
  add    %esi,%edi
  xor    %eax,%eax
  cmp    $0x4000,%edi
  setle  %al
  lea    -0x3(%rax,%rax,2),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int check_page_access(uint32_t page, uint32_t count) {
  if (page >= ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if (count > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if ((page + count) > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_page_access>:
  endbr64
  cmp    $0x3fff,%edi
  jg     L4
  cmp    $0x4000,%esi
  jg     L4
  add    %esi,%edi
  xor    %eax,%eax
  cmp    $0x4000,%edi
  setle  %al
  lea    -0x3(%rax,%rax,2),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0xfffffffd,%eax
  ret
```

assistant: ```c
int check_page_access(uint32_t page, uint32_t count) {
  if (page >= ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if (count > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else if ((page + count) > ((4 * 1024 * 1024) / 256)) {
    do {
      do {
      } while (0);
    } while (0);
    return (-3);
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L35
L32:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L32
  mov    -0x8(%rbp),%rax
  jmp    L34
L35:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    $0x30,%eax
  sub    %edx,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L35
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x8(%rbp),%rax
L34:
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[5 + 2];
  char *p = buf + 5 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  mov    %edi,%ecx
  lea    D2(%rip),%rdi
  mov    $0x30,%r8d
  test   %ecx,%ecx
  jns    L39
L35:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%r8,%rsi,2),%esi
  sub    %ecx,%esi
  mov    %sil,(%rdi)
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L35
  lea    -0x2(%rax),%rdx
  movb   $0x2d,-0x1(%rdi)
L30:
  mov    %rdx,%rax
  ret
L39:
  mov    %rdi,%rdx
L15:
  sub    $0x1,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx)
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L15
  jmp    L30
```

assistant: ```c
char *itoa(int i) {
  static char buf[5 + 2];
  char *p = buf + 5 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D3(%rip),%rdi
  test   %edx,%edx
  jns    L19
  nopw   0x0(%rax,%rax,1)
L23:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L23
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L10
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[5 + 2];
  char *p = buf + 5 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D7(%rip),%rdi
  test   %edx,%edx
  jns    L1
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L15
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L28
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[5 + 2];
  char *p = buf + 5 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nr4sframe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <htonnr4@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L18
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <free_p@plt>
  jmp    L15
L18:
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <append@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <nr3output@plt>
L15:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void nr4sframe(dest, hdr, bp) struct ax25_addr *dest;
struct nr4hdr *hdr;
struct mbuf *bp;
{
  void nr3output();
  struct mbuf *n4b;
  if ((n4b = htonnr4(hdr)) == (struct mbuf *)0) {
    free_p(bp);
    return;
  } else {
    append(&n4b, bp);
    nr3output(dest, n4b);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nr4sframe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <htonnr4@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rsp)
  test   %eax,%eax
  je     L28
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  mov    $0x0,%eax
  call   <append@plt>
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <nr3output@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %rbp,%rdi
  call   <free_p@plt>
  jmp    L18
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nr4sframe(dest, hdr, bp) struct ax25_addr *dest;
struct nr4hdr *hdr;
struct mbuf *bp;
{
  void nr3output();
  struct mbuf *n4b;
  if ((n4b = htonnr4(hdr)) == (struct mbuf *)0) {
    free_p(bp);
    return;
  } else {
    append(&n4b, bp);
    nr3output(dest, n4b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nr4sframe>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <htonnr4@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rsp)
  test   %eax,%eax
  je     L18
  mov    %rsp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <append@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <nr3output@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  call   <free_p@plt>
  jmp    L8
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nr4sframe(dest, hdr, bp) struct ax25_addr *dest;
struct nr4hdr *hdr;
struct mbuf *bp;
{
  void nr3output();
  struct mbuf *n4b;
  if ((n4b = htonnr4(hdr)) == (struct mbuf *)0) {
    free_p(bp);
    return;
  } else {
    append(&n4b, bp);
    nr3output(dest, n4b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nr4sframe>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <htonnr4@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rsp)
  test   %eax,%eax
  je     L19
  mov    %rsp,%rdi
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <append@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <nr3output@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rdi
  call   <free_p@plt>
  jmp    L17
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nr4sframe(dest, hdr, bp) struct ax25_addr *dest;
struct nr4hdr *hdr;
struct mbuf *bp;
{
  void nr3output();
  struct mbuf *n4b;
  if ((n4b = htonnr4(hdr)) == (struct mbuf *)0) {
    free_p(bp);
    return;
  } else {
    append(&n4b, bp);
    nr3output(dest, n4b);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ns_skiprr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L78
L42:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dn_skipname@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L43
  mov    D95(%rip),%rax
  mov    (%rax),%edx
  mov    D104(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L4
L43:
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  mov    D43(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  je     L46
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L56
  mov    D95(%rip),%rax
  mov    (%rax),%edx
  mov    D104(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L4
L56:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <NS_GET16@plt>
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
L46:
  subl   $0x1,-0x2c(%rbp)
L78:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L42
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L17
  mov    D95(%rip),%rax
  mov    (%rax),%edx
  mov    D104(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L4
L17:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sar    $0x2,%rax
L4:
  leave
  ret
```

assistant: ```c
int ns_skiprr(const u_char *ptr, const u_char *eom, ns_sect section, int count) {
  const u_char *optr = ptr;
  for ((void)NULL; count > 0; count--) {
    int b, rdlength;
    b = dn_skipname(ptr, eom);
    if (b < 0)
      do {
        errno = (EMSGSIZE);
        return (-1);
      } while (0);
    ptr += b + NS_INT16SZ + NS_INT16SZ;
    if (section != ns_s_qd) {
      if (ptr + NS_INT32SZ + NS_INT16SZ > eom)
        do {
          errno = (EMSGSIZE);
          return (-1);
        } while (0);
      ptr += NS_INT32SZ;
      NS_GET16(rdlength, ptr);
      ptr += rdlength;
    }
  }
  if (ptr > eom)
    do {
      errno = (EMSGSIZE);
      return (-1);
    } while (0);
  return (ptr - optr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ns_skiprr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  test   %ecx,%ecx
  jle    L53
  mov    %rdx,%r13
  mov    %ecx,%ebp
  mov    $0x0,%r15d
  mov    %rdi,%rbx
  jmp    L71
L79:
  mov    D52(%rip),%rax
  mov    (%rax),%edx
  mov    D47(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L96
L72:
  lea    (%rbx,%rax,4),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <NS_GET16@plt>
  add    %r15,%rbx
L27:
  sub    $0x1,%ebp
  je     L80
L71:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <dn_skipname@plt>
  test   %eax,%eax
  js     L79
  mov    D23(%rip),%rdx
  mov    (%rdx),%edx
  lea    (%rax,%rdx,2),%eax
  cltq
  lea    (%rbx,%rax,4),%rbx
  mov    D86(%rip),%rax
  cmp    %r13,(%rax)
  je     L27
  mov    D13(%rip),%rax
  movslq (%rax),%rax
  movslq %edx,%rdx
  add    %rax,%rdx
  lea    (%rbx,%rdx,4),%rdx
  cmp    %rdx,%r12
  jae    L72
  mov    D52(%rip),%rax
  mov    (%rax),%edx
  mov    D47(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L96
L53:
  mov    %rdi,%rbx
L80:
  cmp    %rbx,%r12
  jb     L66
  mov    %rbx,%rax
  sub    %r14,%rax
  sar    $0x2,%rax
L96:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  mov    D52(%rip),%rax
  mov    (%rax),%edx
  mov    D47(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L96
```

assistant: ```c
int ns_skiprr(const u_char *ptr, const u_char *eom, ns_sect section, int count) {
  const u_char *optr = ptr;
  for ((void)NULL; count > 0; count--) {
    int b, rdlength;
    b = dn_skipname(ptr, eom);
    if (b < 0)
      do {
        errno = (EMSGSIZE);
        return (-1);
      } while (0);
    ptr += b + NS_INT16SZ + NS_INT16SZ;
    if (section != ns_s_qd) {
      if (ptr + NS_INT32SZ + NS_INT16SZ > eom)
        do {
          errno = (EMSGSIZE);
          return (-1);
        } while (0);
      ptr += NS_INT32SZ;
      NS_GET16(rdlength, ptr);
      ptr += rdlength;
    }
  }
  if (ptr > eom)
    do {
      errno = (EMSGSIZE);
      return (-1);
    } while (0);
  return (ptr - optr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ns_skiprr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L67
  mov    %rdx,%r13
  mov    %ecx,%ebp
  xor    %r15d,%r15d
  mov    %rdi,%rbx
  jmp    L60
  nopl   (%rax)
L5:
  mov    D0(%rip),%rdx
  movslq (%rdx),%rdx
  lea    (%rax,%rdx,2),%eax
  cltq
  lea    (%rbx,%rax,4),%rbx
  mov    D36(%rip),%rax
  cmp    %r13,(%rax)
  je     L48
  mov    D13(%rip),%rax
  movslq (%rax),%rax
  add    %rax,%rdx
  lea    (%rbx,%rdx,4),%rdx
  cmp    %rdx,%r12
  jb     L20
  lea    (%rbx,%rax,4),%rbx
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    %r15,%rbx
  call   <NS_GET16@plt>
L48:
  sub    $0x1,%ebp
  je     L63
L60:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <dn_skipname@plt>
  test   %eax,%eax
  jns    L5
L20:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L63:
  cmp    %rbx,%r12
  jb     L20
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %r14,%rax
  pop    %rbx
  pop    %rbp
  sar    $0x2,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ns_skiprr(const u_char *ptr, const u_char *eom, ns_sect section, int count) {
  const u_char *optr = ptr;
  for ((void)NULL; count > 0; count--) {
    int b, rdlength;
    b = dn_skipname(ptr, eom);
    if (b < 0)
      do {
        errno = (EMSGSIZE);
        return (-1);
      } while (0);
    ptr += b + NS_INT16SZ + NS_INT16SZ;
    if (section != ns_s_qd) {
      if (ptr + NS_INT32SZ + NS_INT16SZ > eom)
        do {
          errno = (EMSGSIZE);
          return (-1);
        } while (0);
      ptr += NS_INT32SZ;
      NS_GET16(rdlength, ptr);
      ptr += rdlength;
    }
  }
  if (ptr > eom)
    do {
      errno = (EMSGSIZE);
      return (-1);
    } while (0);
  return (ptr - optr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ns_skiprr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L22
  mov    %rdx,%r13
  mov    %ecx,%ebp
  xor    %r15d,%r15d
  mov    %rdi,%rbx
  jmp    L69
  nopl   (%rax)
L44:
  mov    D47(%rip),%rdx
  movslq (%rdx),%rdx
  lea    (%rax,%rdx,2),%eax
  cltq
  lea    (%rbx,%rax,4),%rbx
  mov    D26(%rip),%rax
  cmp    %r13,(%rax)
  je     L65
  mov    D0(%rip),%rax
  movslq (%rax),%rax
  add    %rax,%rdx
  lea    (%rbx,%rdx,4),%rdx
  cmp    %rdx,%r12
  jb     L64
  lea    (%rbx,%rax,4),%rbx
  xor    %edi,%edi
  mov    %rbx,%rsi
  add    %r15,%rbx
  call   <NS_GET16@plt>
L65:
  sub    $0x1,%ebp
  je     L54
L69:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <dn_skipname@plt>
  test   %eax,%eax
  jns    L44
L64:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L54:
  cmp    %rbx,%r12
  jb     L64
  mov    %rbx,%rax
  add    $0x8,%rsp
  sub    %r14,%rax
  pop    %rbx
  pop    %rbp
  sar    $0x2,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ns_skiprr(const u_char *ptr, const u_char *eom, ns_sect section, int count) {
  const u_char *optr = ptr;
  for ((void)NULL; count > 0; count--) {
    int b, rdlength;
    b = dn_skipname(ptr, eom);
    if (b < 0)
      do {
        errno = (EMSGSIZE);
        return (-1);
      } while (0);
    ptr += b + NS_INT16SZ + NS_INT16SZ;
    if (section != ns_s_qd) {
      if (ptr + NS_INT32SZ + NS_INT16SZ > eom)
        do {
          errno = (EMSGSIZE);
          return (-1);
        } while (0);
      ptr += NS_INT32SZ;
      NS_GET16(rdlength, ptr);
      ptr += rdlength;
    }
  }
  if (ptr > eom)
    do {
      errno = (EMSGSIZE);
      return (-1);
    } while (0);
  return (ptr - optr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L7
L14:
  nop
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  if (!s)
    return;
  write(fd, s, ft_strlen(s));
  write(fd, "\n", 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putendl_fd>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D9(%rip),%rsi
  mov    %ebp,%edi
  call   <write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  if (!s)
    return;
  write(fd, s, ft_strlen(s));
  write(fd, "\n", 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_putendl_fd>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  mov    $0x1,%edx
  pop    %rbp
  lea    D8(%rip),%rsi
  pop    %r12
  jmp    1060 <write@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: 


assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  if (!s)
    return;
  write(fd, s, ft_strlen(s));
  write(fd, "\n", 1);
}
```