ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0xa,0x18(%rsp)
  mov    %rsp,%rbx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <insert_sort_version3@plt>
  lea    0x1c(%rsp),%r12
  lea    D9(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %d	

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  insert_sort_version3(nums, sizeof(nums) / sizeof(nums[0]));
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000005,%rax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  movl   $0xa,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x900000002,%rax
  mov    %rax,0x10(%rsp)
  call   <insert_sort_version3@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D5: %d	

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  insert_sort_version3(nums, sizeof(nums) / sizeof(nums[0]));
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    D10(%rip),%rax
  mov    %rbx,%rdi
  movl   $0xa,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <insert_sort_version3@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D26
type: byte[16]
name: extract_symbolic_data
arguments: label: D10
type: byte[8]

tool: D21: %d	

tool: {"D26": [0x05,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D10": [0x02,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int nums[] = {5, 9, 1, 6, 2, 9, 10};
  int i;
  insert_sort_version3(nums, sizeof(nums) / sizeof(nums[0]));
  for (i = 0; i < sizeof(nums) / sizeof(nums[0]); i++)
    printf("%d\t", nums[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <run_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  run_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <run_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_test();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_test();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <run_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  run_test();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_tableline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L27:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L161
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L27
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L27
L161:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L169
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  jne    L169
  addl   $0x1,-0xc(%rbp)
L169:
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L151:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <is_table_sep@plt>
  test   %rax,%rax
  je     L131
  addl   $0x1,-0x10(%rbp)
L131:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L43
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L151
  jmp    L43
L117:
  subq   $0x1,-0x8(%rbp)
L43:
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L117
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L117
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L117
L13:
  cmpq   $0x0,-0x8(%rbp)
  je     L101
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <is_table_sep@plt>
  test   %rax,%rax
  je     L101
  addl   $0x1,-0xc(%rbp)
L101:
  cmpl   $0x0,-0x10(%rbp)
  jle    L140
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L130
L140:
  mov    $0x0,%eax
L130:
  leave
  ret
```

assistant: ```c
int is_tableline(char *data, size_t size) {
  size_t i = 0;
  int n_sep = 0, outer_sep = 0;
  while (i < size && (data[i] == ' ' || data[i] == '\t'))
    i += 1;
  if (i < size && data[i] == '|')
    outer_sep += 1;
  for (n_sep = 0; i < size && data[i] != '\n'; i += 1)
    if (is_table_sep(data, i))
      n_sep += 1;
  while (i && (data[i - 1] == ' ' || data[i - 1] == '\t' || data[i - 1] == '\n'))
    i -= 1;
  if (i && is_table_sep(data, i - 1))
    outer_sep += 1;
  return (n_sep > 0) ? (n_sep - outer_sep + 1) : 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_tableline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    $0x0,%ebx
  test   %rsi,%rsi
  jne    L83
L46:
  mov    %r14,%rbx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  jmp    L8
L23:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  je     L46
L83:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x20,%al
  je     L23
  cmp    $0x9,%al
  je     L23
  cmp    %rbx,%r14
  jbe    L36
  cmp    $0x7c,%al
  sete   %r13b
  movzbl %r13b,%r13d
  mov    $0x0,%r12d
L42:
  cmpb   $0xa,0x0(%rbp,%rbx,1)
  je     L8
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L42
  mov    %r14,%rbx
  jmp    L8
L36:
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  jmp    L8
L77:
  mov    %rcx,%rbx
L8:
  test   %rbx,%rbx
  je     L116
  lea    -0x1(%rbx),%rcx
  movzbl -0x1(%rbp,%rbx,1),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L77
  cmp    $0x20,%al
  je     L77
  mov    %rcx,%rsi
  mov    %rbp,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r13d
L116:
  mov    %r12d,%eax
  sub    %r13d,%eax
  add    $0x1,%eax
  test   %r12d,%r12d
  mov    $0x0,%edx
  cmovle %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int is_tableline(char *data, size_t size) {
  size_t i = 0;
  int n_sep = 0, outer_sep = 0;
  while (i < size && (data[i] == ' ' || data[i] == '\t'))
    i += 1;
  if (i < size && data[i] == '|')
    outer_sep += 1;
  for (n_sep = 0; i < size && data[i] != '\n'; i += 1)
    if (is_table_sep(data, i))
      n_sep += 1;
  while (i && (data[i - 1] == ' ' || data[i - 1] == '\t' || data[i - 1] == '\n'))
    i -= 1;
  if (i && is_table_sep(data, i - 1))
    outer_sep += 1;
  return (n_sep > 0) ? (n_sep - outer_sep + 1) : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_tableline>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L123
  mov    %rdi,%r12
  mov    %rsi,%r14
  xor    %ebp,%ebp
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L66:
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L127
L75:
  movzbl (%r12,%rbp,1),%eax
  cmp    $0x20,%al
  je     L66
  cmp    $0x9,%al
  je     L66
  xor    %ebx,%ebx
  cmp    $0x7c,%al
  sete   %bl
  cmp    %rbp,%r14
  jbe    L50
  xor    %r13d,%r13d
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r13d
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L85
  movzbl (%r12,%rbp,1),%eax
L51:
  cmp    $0xa,%al
  jne    L29
  nopl   (%rax)
L85:
  test   %rbp,%rbp
  je     L46
  sub    $0x1,%rbp
  movzbl (%r12,%rbp,1),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L85
  cmp    $0x20,%al
  je     L85
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
L46:
  mov    %r13d,%eax
  sub    %ebx,%eax
  add    $0x1,%eax
  test   %r13d,%r13d
  cmovne %eax,%r13d
L123:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L127:
  xor    %ebx,%ebx
L50:
  xor    %r13d,%r13d
  jmp    L85
```

assistant: ```c
int is_tableline(char *data, size_t size) {
  size_t i = 0;
  int n_sep = 0, outer_sep = 0;
  while (i < size && (data[i] == ' ' || data[i] == '\t'))
    i += 1;
  if (i < size && data[i] == '|')
    outer_sep += 1;
  for (n_sep = 0; i < size && data[i] != '\n'; i += 1)
    if (is_table_sep(data, i))
      n_sep += 1;
  while (i && (data[i - 1] == ' ' || data[i - 1] == '\t' || data[i - 1] == '\n'))
    i -= 1;
  if (i && is_table_sep(data, i - 1))
    outer_sep += 1;
  return (n_sep > 0) ? (n_sep - outer_sep + 1) : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_tableline>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L61
  mov    %rdi,%r12
  mov    %rsi,%r14
  xor    %ebp,%ebp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L101
L8:
  movzbl (%r12,%rbp,1),%eax
  cmp    $0x20,%al
  je     L59
  cmp    $0x9,%al
  je     L59
  xor    %ebx,%ebx
  cmp    $0x7c,%al
  sete   %bl
  cmp    %rbp,%r14
  jbe    L56
  xor    %r13d,%r13d
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r13d
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L125
L58:
  cmpb   $0xa,(%r12,%rbp,1)
  jne    L42
  nopl   0x0(%rax,%rax,1)
L125:
  test   %rbp,%rbp
  je     L47
  sub    $0x1,%rbp
  movzbl (%r12,%rbp,1),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L125
  cmp    $0x20,%al
  je     L125
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <is_table_sep@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
L47:
  mov    %r13d,%eax
  sub    %ebx,%eax
  add    $0x1,%eax
  test   %r13d,%r13d
  cmovne %eax,%r13d
L61:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L101:
  xor    %ebx,%ebx
L56:
  xor    %r13d,%r13d
  jmp    L125
```

assistant: ```c
int is_tableline(char *data, size_t size) {
  size_t i = 0;
  int n_sep = 0, outer_sep = 0;
  while (i < size && (data[i] == ' ' || data[i] == '\t'))
    i += 1;
  if (i < size && data[i] == '|')
    outer_sep += 1;
  for (n_sep = 0; i < size && data[i] != '\n'; i += 1)
    if (is_table_sep(data, i))
      n_sep += 1;
  while (i && (data[i - 1] == ' ' || data[i - 1] == '\t' || data[i - 1] == '\n'))
    i -= 1;
  if (i && is_table_sep(data, i - 1))
    outer_sep += 1;
  return (n_sep > 0) ? (n_sep - outer_sep + 1) : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_acpi_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_acpi_file@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L14
L15:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <scan_acpi_value@plt>
L14:
  leave
  ret
```

assistant: ```c
char *get_acpi_value(const char *file, const char *key) {
  char *buf = get_acpi_file(file);
  if (!buf)
    return NULL;
  return scan_acpi_value(buf, key);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_acpi_value>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <get_acpi_file@plt>
  test   %rax,%rax
  je     L3
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <scan_acpi_value@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
char *get_acpi_value(const char *file, const char *key) {
  char *buf = get_acpi_file(file);
  if (!buf)
    return NULL;
  return scan_acpi_value(buf, key);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_acpi_value>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <get_acpi_file@plt>
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <scan_acpi_value@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *get_acpi_value(const char *file, const char *key) {
  char *buf = get_acpi_file(file);
  if (!buf)
    return NULL;
  return scan_acpi_value(buf, key);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_acpi_value>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <get_acpi_file@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <scan_acpi_value@plt>
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *get_acpi_value(const char *file, const char *key) {
  char *buf = get_acpi_file(file);
  if (!buf)
    return NULL;
  return scan_acpi_value(buf, key);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1c0(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b0(%rbp)
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x1a8(%rbp)
  lea    -0x1a0(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  lea    -0x1a0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1b0(%rbp),%rax
  movl   $0x11,(%rax)
  lea    -0x1c4(%rbp),%rax
  mov    %rax,%rdi
  call   <free_anything@plt>
  mov    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1b8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, -1);
  read_element(array1, 100);
  read_element(array2, -1);
  read_element(array2, 100);
  *never_free = 17;
  free_anything(&never_allocated);
  free(free_twice);
  free(use_after_free);
  free(never_free);
  free(array2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%r14
  mov    $0xffffffff,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  movl   $0x11,0x0(%rbp)
  lea    0xc(%rsp),%rdi
  call   <free_anything@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, -1);
  read_element(array1, 100);
  read_element(array2, -1);
  read_element(array2, 100);
  *never_free = 17;
  free_anything(&never_allocated);
  free(free_twice);
  free(use_after_free);
  free(never_free);
  free(array2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0xffffffff,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,(%r12)
  lea    0xc(%rsp),%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, -1);
  read_element(array1, 100);
  read_element(array2, -1);
  read_element(array2, 100);
  *never_free = 17;
  free_anything(&never_allocated);
  free(free_twice);
  free(use_after_free);
  free(never_free);
  free(array2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0xffffffff,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,(%r12)
  lea    0xc(%rsp),%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int never_allocated;
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, -1);
  read_element(array1, 100);
  read_element(array2, -1);
  read_element(array2, 100);
  *never_free = 17;
  free_anything(&never_allocated);
  free(free_twice);
  free(use_after_free);
  free(never_free);
  free(array2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L6:
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0xf,-0x4(%rbp)
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy64(uint32_t *M, uint8_t *in) {
  int32_t i;
  for (i = 0; i < 16; i++)
    M[i] = (in[i * 4 + 3] << 24) | (in[i * 4 + 2] << 16) | (in[i * 4 + 1] << 8) | (in[i * 4 + 0] << 0);
}
```