ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<RemoveShuffledArrayValue>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  call   <ShuffledBinarySearch@plt>
  test   %eax,%eax
  jns    L27
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  mov    %r12d,%esi
  mov    %eax,%ebp
  mov    %r13,%rdi
  call   <SortShuffledArray@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    $0x1,%r12d
  call   <DeshuffleIndex@plt>
  cmp    %eax,%r12d
  jg     L29
L2:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <ShuffleSortedArray@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  movslq %eax,%rdx
  lea    0x4(,%rdx,4),%rcx
  mov    %r12d,%edx
  sub    %eax,%edx
  lea    0x0(%r13,%rcx,1),%rsi
  lea    -0x4(%r13,%rcx,1),%rdi
  shl    $0x2,%edx
  call   <memmove@plt>
  jmp    L2
```

assistant: ```c
int RemoveShuffledArrayValue(int value, int *shuffled_array, int count) {
  int index = ShuffledBinarySearch(value, shuffled_array, count);
  if (index >= 0) {
    SortShuffledArray(shuffled_array, count);
    int deshuf = DeshuffleIndex(index, count);
    if (deshuf < (count - 1))
      memmove(shuffled_array + deshuf, shuffled_array + deshuf + 1, (count - 1 - deshuf) * sizeof(int));
    count--;
    ShuffleSortedArray(shuffled_array, count);
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RemoveShuffledArrayValue>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  call   <ShuffledBinarySearch@plt>
  test   %eax,%eax
  jns    L5
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %r12d,%esi
  mov    %eax,%ebp
  mov    %r13,%rdi
  call   <SortShuffledArray@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    $0x1,%r12d
  call   <DeshuffleIndex@plt>
  cmp    %eax,%r12d
  jg     L26
L2:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <ShuffleSortedArray@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  movslq %eax,%rdx
  lea    0x4(,%rdx,4),%rcx
  mov    %r12d,%edx
  sub    %eax,%edx
  lea    0x0(%r13,%rcx,1),%rsi
  lea    -0x4(%r13,%rcx,1),%rdi
  shl    $0x2,%edx
  call   <memmove@plt>
  jmp    L2
```

assistant: ```c
int RemoveShuffledArrayValue(int value, int *shuffled_array, int count) {
  int index = ShuffledBinarySearch(value, shuffled_array, count);
  if (index >= 0) {
    SortShuffledArray(shuffled_array, count);
    int deshuf = DeshuffleIndex(index, count);
    if (deshuf < (count - 1))
      memmove(shuffled_array + deshuf, shuffled_array + deshuf + 1, (count - 1 - deshuf) * sizeof(int));
    count--;
    ShuffleSortedArray(shuffled_array, count);
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xilinxcorelib_a_2866867632_0543512595_p_4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x7820(%rdi),%rax
  mov    0x38(%rax),%rax
  movb   $0x3,(%rax)
  lea    0x77e8(%rdi),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f38(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_p_4(char *t0) {
  unsigned char t1;
  unsigned char t2;
  char *t3;
  char *t4;
  int t5;
  unsigned char t6;
  char *t7;
  unsigned char t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
LAB0:
  t2 = (0 == 1);
  if (t2 == 1)
    goto LAB5;
LAB6:
  t1 = (unsigned char)0;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB8:
  t13 = (t0 + 30696);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  t16 = (t15 + 56U);
  t17 = *((char **)t16);
  *((unsigned char *)t17) = (unsigned char)3;
  xsi_driver_first_trans_fast(t13);
LAB2:
  t18 = (t0 + 28472);
  *((int *)t18) = 1;
LAB1:
  return;
LAB3:
  t3 = (t0 + 2896U);
  t7 = *((char **)t3);
  t8 = *((unsigned char *)t7);
  t3 = (t0 + 30696);
  t9 = (t3 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  *((unsigned char *)t12) = t8;
  xsi_driver_first_trans_fast(t3);
  goto LAB2;
LAB5:
  t3 = (t0 + 19312U);
  t4 = *((char **)t3);
  t5 = *((int *)t4);
  t6 = (t5 == 1);
  t1 = t6;
  goto LAB7;
LAB9:
  goto LAB2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xilinxcorelib_a_2866867632_0543512595_p_4>:
  endbr64
  push   %rbx
  mov    0x7820(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x77e8(%rdi),%rdi
  mov    0x38(%rax),%rax
  movb   $0x3,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f38(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_p_4(char *t0) {
  unsigned char t1;
  unsigned char t2;
  char *t3;
  char *t4;
  int t5;
  unsigned char t6;
  char *t7;
  unsigned char t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
LAB0:
  t2 = (0 == 1);
  if (t2 == 1)
    goto LAB5;
LAB6:
  t1 = (unsigned char)0;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB8:
  t13 = (t0 + 30696);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  t16 = (t15 + 56U);
  t17 = *((char **)t16);
  *((unsigned char *)t17) = (unsigned char)3;
  xsi_driver_first_trans_fast(t13);
LAB2:
  t18 = (t0 + 28472);
  *((int *)t18) = 1;
LAB1:
  return;
LAB3:
  t3 = (t0 + 2896U);
  t7 = *((char **)t3);
  t8 = *((unsigned char *)t7);
  t3 = (t0 + 30696);
  t9 = (t3 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  *((unsigned char *)t12) = t8;
  xsi_driver_first_trans_fast(t3);
  goto LAB2;
LAB5:
  t3 = (t0 + 19312U);
  t4 = *((char **)t3);
  t5 = *((int *)t4);
  t6 = (t5 == 1);
  t1 = t6;
  goto LAB7;
LAB9:
  goto LAB2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xilinxcorelib_a_2866867632_0543512595_p_4>:
  endbr64
  push   %rbx
  mov    0x7820(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x77e8(%rdi),%rdi
  mov    0x38(%rax),%rax
  movb   $0x3,(%rax)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f38(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_p_4(char *t0) {
  unsigned char t1;
  unsigned char t2;
  char *t3;
  char *t4;
  int t5;
  unsigned char t6;
  char *t7;
  unsigned char t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
  char *t17;
  char *t18;
LAB0:
  t2 = (0 == 1);
  if (t2 == 1)
    goto LAB5;
LAB6:
  t1 = (unsigned char)0;
LAB7:
  if (t1 != 0)
    goto LAB3;
LAB4:
LAB8:
  t13 = (t0 + 30696);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  t16 = (t15 + 56U);
  t17 = *((char **)t16);
  *((unsigned char *)t17) = (unsigned char)3;
  xsi_driver_first_trans_fast(t13);
LAB2:
  t18 = (t0 + 28472);
  *((int *)t18) = 1;
LAB1:
  return;
LAB3:
  t3 = (t0 + 2896U);
  t7 = *((char **)t3);
  t8 = *((unsigned char *)t7);
  t3 = (t0 + 30696);
  t9 = (t3 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  *((unsigned char *)t12) = t8;
  xsi_driver_first_trans_fast(t3);
  goto LAB2;
LAB5:
  t3 = (t0 + 19312U);
  t4 = *((char **)t3);
  t5 = *((int *)t4);
  t6 = (t5 == 1);
  t1 = t6;
  goto LAB7;
LAB9:
  goto LAB2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_labeled@plt>
  test   %rax,%rax
  je     L6
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *remove_label(char *s) {
  if (is_labeled(s))
    s[strlen(s) - 1] = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_label>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <is_labeled@plt>
  test   %rax,%rax
  jne    L16
L0:
  mov    %rbx,%rax
  pop    %rbx
  ret
L16:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L0
```

assistant: ```c
char *remove_label(char *s) {
  if (is_labeled(s))
    s[strlen(s) - 1] = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_label>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <is_labeled@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_label(char *s) {
  if (is_labeled(s))
    s[strlen(s) - 1] = '\0';
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<remove_label>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <is_labeled@plt>
  test   %rax,%rax
  jne    L6
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *remove_label(char *s) {
  if (is_labeled(s))
    s[strlen(s) - 1] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_dma_residue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  ja     L34
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  and    $0x6,%eax
  add    $0x1,%eax
  jmp    L37
L34:
  mov    -0x14(%rbp),%eax
  shl    $0x2,%eax
  and    $0xc,%eax
  add    $0xc2,%eax
L37:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <inb@plt>
  add    $0x1,%eax
  mov    %ax,-0x6(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <inb@plt>
  shl    $0x8,%eax
  add    %ax,-0x6(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  ja     L38
  movzwl -0x6(%rbp),%eax
  jmp    L9
L38:
  movzwl -0x6(%rbp),%eax
  add    %eax,%eax
L9:
  leave
  ret
```

assistant: ```c
int get_dma_residue(unsigned int dmanr) {
  unsigned int io_port;
  unsigned short count;
  io_port = (dmanr <= 3) ? ((dmanr & 3) << 1) + 1 + 0x00 : ((dmanr & 3) << 2) + 2 + 0xC0;
  count = 1 + inb(io_port);
  count += inb(io_port) << 8;
  return (dmanr <= 3) ? count : (count << 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_dma_residue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  ja     L10
  lea    0x1(%rdi,%rdi,1),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  lea    0x1(%rax),%ebx
  mov    %ebp,%edi
  call   <inb@plt>
  shl    $0x8,%eax
  add    %ebx,%eax
  movzwl %ax,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  shl    $0x2,%edi
  and    $0xc,%edi
  lea    0xc2(%rdi),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  lea    0x1(%rax),%ebx
  mov    %ebp,%edi
  call   <inb@plt>
  shl    $0x8,%eax
  add    %ebx,%eax
  movzwl %ax,%eax
  add    %eax,%eax
  jmp    L13
```

assistant: ```c
int get_dma_residue(unsigned int dmanr) {
  unsigned int io_port;
  unsigned short count;
  io_port = (dmanr <= 3) ? ((dmanr & 3) << 1) + 1 + 0x00 : ((dmanr & 3) << 2) + 2 + 0xC0;
  count = 1 + inb(io_port);
  count += inb(io_port) << 8;
  return (dmanr <= 3) ? count : (count << 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_dma_residue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  ja     L6
  lea    0x1(%rdi,%rdi,1),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%ebx
  call   <inb@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  movzwl %ax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  shl    $0x2,%edi
  and    $0xc,%edi
  lea    0xc2(%rdi),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%ebx
  call   <inb@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  movzwl %ax,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int get_dma_residue(unsigned int dmanr) {
  unsigned int io_port;
  unsigned short count;
  io_port = (dmanr <= 3) ? ((dmanr & 3) << 1) + 1 + 0x00 : ((dmanr & 3) << 2) + 2 + 0xC0;
  count = 1 + inb(io_port);
  count += inb(io_port) << 8;
  return (dmanr <= 3) ? count : (count << 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_dma_residue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  ja     L3
  lea    0x1(%rdi,%rdi,1),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%ebx
  call   <inb@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  movzwl %ax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  shl    $0x2,%edi
  and    $0xc,%edi
  lea    0xc2(%rdi),%ebp
  mov    %ebp,%edi
  call   <inb@plt>
  mov    %ebp,%edi
  lea    0x1(%rax),%ebx
  call   <inb@plt>
  add    $0x8,%rsp
  shl    $0x8,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  movzwl %ax,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int get_dma_residue(unsigned int dmanr) {
  unsigned int io_port;
  unsigned short count;
  io_port = (dmanr <= 3) ? ((dmanr & 3) << 1) + 1 + 0x00 : ((dmanr & 3) << 2) + 2 + 0xC0;
  count = 1 + inb(io_port);
  count += inb(io_port) << 8;
  return (dmanr <= 3) ? count : (count << 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parseDecimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  addq   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  imul   $0x64,%eax,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L74
L11:
  addq   $0x1,-0x18(%rbp)
L74:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L9
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L9
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L9
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x4(%rbp)
  je     L18
  mov    -0x8(%rbp),%eax
  neg    %eax
  jmp    L70
L18:
  mov    -0x8(%rbp),%eax
L70:
  leave
  ret
```

assistant: ```c
int32_t parseDecimal(const char *term) {
  bool negative = *term == '-';
  if (negative)
    ++term;
  int32_t ret = 100 * (int32_t)atol(term);
  while (isdigit(*term))
    ++term;
  if (*term == '.' && isdigit(term[1])) {
    ret += 10 * (term[1] - '0');
    if (isdigit(term[2]))
      ret += term[2] - '0';
  }
  return negative ? -ret : ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parseDecimal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%r12d
  cmp    $0x2d,%r12b
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <atol@plt>
  imul   $0x64,%eax,%ebp
  jmp    L48
L11:
  add    $0x1,%rbx
L48:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L11
  cmpb   $0x2e,(%rbx)
  je     L47
L10:
  mov    %ebp,%eax
  neg    %eax
  cmp    $0x2d,%r12b
  cmove  %eax,%ebp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L10
  movsbl 0x1(%rbx),%eax
  lea    -0xf0(%rax,%rax,4),%eax
  lea    0x0(%rbp,%rax,2),%ebp
  movsbl 0x2(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L10
  movsbl 0x2(%rbx),%eax
  lea    -0x30(%rbp,%rax,1),%ebp
  jmp    L10
```

assistant: ```c
int32_t parseDecimal(const char *term) {
  bool negative = *term == '-';
  if (negative)
    ++term;
  int32_t ret = 100 * (int32_t)atol(term);
  while (isdigit(*term))
    ++term;
  if (*term == '.' && isdigit(term[1])) {
    ret += 10 * (term[1] - '0');
    if (isdigit(term[2]))
      ret += term[2] - '0';
  }
  return negative ? -ret : ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parseDecimal>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebp
  mov    %rdi,%rbx
  cmp    $0x2d,%bpl
  sete   %al
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <atol@plt>
  imul   $0x64,%eax,%r12d
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rbx
L47:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L32
  cmpb   $0x2e,(%rbx)
  je     L35
L23:
  mov    %r12d,%eax
  pop    %rbx
  neg    %eax
  cmp    $0x2d,%bpl
  pop    %rbp
  cmove  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L23
  movsbl 0x1(%rbx),%eax
  movsbl 0x2(%rbx),%edi
  lea    -0xf0(%rax,%rax,4),%eax
  lea    (%r12,%rax,2),%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L23
  movsbl 0x2(%rbx),%eax
  lea    -0x30(%r12,%rax,1),%r12d
  jmp    L23
```

assistant: ```c
int32_t parseDecimal(const char *term) {
  bool negative = *term == '-';
  if (negative)
    ++term;
  int32_t ret = 100 * (int32_t)atol(term);
  while (isdigit(*term))
    ++term;
  if (*term == '.' && isdigit(term[1])) {
    ret += 10 * (term[1] - '0');
    if (isdigit(term[2]))
      ret += term[2] - '0';
  }
  return negative ? -ret : ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parseDecimal>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebp
  mov    %rdi,%rbx
  cmp    $0x2d,%bpl
  sete   %al
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <atol@plt>
  imul   $0x64,%eax,%r12d
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x1,%rbx
L24:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L41
  cmpb   $0x2e,(%rbx)
  je     L44
L20:
  mov    %r12d,%eax
  pop    %rbx
  neg    %eax
  cmp    $0x2d,%bpl
  pop    %rbp
  cmove  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L20
  movsbl 0x1(%rbx),%eax
  movsbl 0x2(%rbx),%edi
  lea    -0xf0(%rax,%rax,4),%eax
  lea    (%r12,%rax,2),%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  je     L20
  movsbl 0x2(%rbx),%eax
  lea    -0x30(%r12,%rax,1),%r12d
  jmp    L20
```

assistant: ```c
int32_t parseDecimal(const char *term) {
  bool negative = *term == '-';
  if (negative)
    ++term;
  int32_t ret = 100 * (int32_t)atol(term);
  while (isdigit(*term))
    ++term;
  if (*term == '.' && isdigit(term[1])) {
    ret += 10 * (term[1] - '0');
    if (isdigit(term[2]))
      ret += term[2] - '0';
  }
  return negative ? -ret : ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x3ade68b1,-0x8(%rbp)
  jmp    L0
L16:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shl    $0x10,%edx
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x8(%rbp),%eax
  and    $0x7f,%eax
  leave
  ret
```

assistant: ```c
int hashfunc(const char *str) {
  unsigned hash = 987654321;
  unsigned c;
  while (*str) {
    c = *str++;
    c = toupper(c);
    hash = hash * 65537;
    hash = hash ^ c;
  }
  return hash % 128;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hashfunc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L14
  mov    $0x3ade68b1,%ebx
L20:
  add    $0x1,%rbp
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %ebx,%edx
  shl    $0x10,%edx
  add    %edx,%ebx
  xor    %eax,%ebx
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L20
L19:
  mov    %ebx,%eax
  and    $0x7f,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x3ade68b1,%ebx
  jmp    L19
```

assistant: ```c
int hashfunc(const char *str) {
  unsigned hash = 987654321;
  unsigned c;
  while (*str) {
    c = *str++;
    c = toupper(c);
    hash = hash * 65537;
    hash = hash ^ c;
  }
  return hash % 128;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashfunc>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L15
  mov    $0x3ade68b1,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  call   <toupper@plt>
  mov    %ebx,%edx
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  shl    $0x10,%edx
  add    %edx,%ebx
  xor    %eax,%ebx
  test   %dil,%dil
  jne    L12
  mov    %ebx,%eax
  add    $0x8,%rsp
  and    $0x7f,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    $0x31,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hashfunc(const char *str) {
  unsigned hash = 987654321;
  unsigned c;
  while (*str) {
    c = *str++;
    c = toupper(c);
    hash = hash * 65537;
    hash = hash ^ c;
  }
  return hash % 128;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hashfunc>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L8
  mov    $0x3ade68b1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  call   <toupper@plt>
  mov    %ebx,%edx
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  shl    $0x10,%edx
  add    %edx,%ebx
  xor    %eax,%ebx
  test   %dil,%dil
  jne    L2
  mov    %ebx,%eax
  add    $0x8,%rsp
  and    $0x7f,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    $0x31,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hashfunc(const char *str) {
  unsigned hash = 987654321;
  unsigned c;
  while (*str) {
    c = *str++;
    c = toupper(c);
    hash = hash * 65537;
    hash = hash ^ c;
  }
  return hash % 128;
}
```
user: What is the c source code of the assembly code below?

```asm
<find_max_multi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L14:
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L15:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L12
  movsd  -0x8(%rbp),%xmm0
  jmp    L21
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
L21:
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  addl   $0x1,-0x10(%rbp)
L52:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double find_max_multi(double **array, int *n, int m) {
  int i;
  int j;
  double max = array[0][0];
  for (i = 0; i < m; i++) {
    for (j = 0; j < n[i]; j++) {
      max = (array[i][j] < max) ? max : array[i][j];
    }
  }
  return max;
}
```