ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %rcx,0x30(%rsp)
  test   %esi,%esi
  jle    L12
  mov    %esi,%eax
  mov    %rax,0x28(%rsp)
  mov    $0x0,%r15d
  movl   $0x0,0x38(%rsp)
  lea    -0x2(%rdx),%eax
  mov    %eax,0x3c(%rsp)
  lea    -0x1(%rdx),%eax
  mov    %eax,0x24(%rsp)
  jmp    L13
L16:
  mov    0x18(%rsp),%rax
  lea    0x8(%rax),%r13
  mov    0x3c(%rsp),%eax
  add    $0x2,%rax
  mov    %rax,0x10(%rsp)
  movq   $0x1,0x8(%rsp)
  mov    $0x0,%r12d
L20:
  mov    0x8(%rsp),%rdx
  cmp    %edx,0x20(%rsp)
  jle    L30
  mov    0x24(%rsp),%eax
  sub    %edx,%eax
  lea    -0x1(%rdx,%rax,1),%rax
  mov    0x18(%rsp),%rcx
  lea    0x10(%rcx,%rax,8),%r14
  mov    %r13,%rbp
L68:
  mov    -0x8(%r13),%rax
  movsbl (%rax,%r15,1),%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%rax
  movsbl (%rax,%r15,1),%edi
  call   <tolower@plt>
  movsbl %al,%esi
  movsbl %bl,%edi
  call   <WeightNt@plt>
  add    %eax,%r12d
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L68
L30:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  add    $0x8,%r13
  cmp    0x10(%rsp),%rax
  jne    L20
L33:
  mov    0x30(%rsp),%rax
  mov    %r12d,(%rax,%r15,4)
  add    %r12d,0x38(%rsp)
  add    $0x1,%r15
  cmp    0x28(%rsp),%r15
  je     L37
L13:
  mov    $0x0,%r12d
  cmpl   $0x1,0x20(%rsp)
  jg     L16
  jmp    L33
L12:
  movl   $0x0,0x38(%rsp)
L37:
  mov    0x38(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int Sop(char **aln_seq, int aln_len, int n_seq, int *col_cost) {
  int l, i, j;
  int col_score, sum;
  char nt[2];
  sum = 0;
  for (l = 0; l < aln_len; l++) {
    col_score = 0;
    for (i = 0; i < n_seq - 1; i++) {
      for (j = i + 1; j < n_seq; j++) {
        nt[0] = (char)tolower(aln_seq[i][l]);
        nt[1] = (char)tolower(aln_seq[j][l]);
        col_score += WeightNt(nt[0], nt[1]);
      }
    }
    col_cost[l] = col_score;
    sum += col_score;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Sop>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %rcx,0x30(%rsp)
  test   %eax,%eax
  jle    L58
  mov    %rax,0x28(%rsp)
  lea    -0x2(%rdx),%eax
  xor    %ebp,%ebp
  mov    %eax,0x3c(%rsp)
  lea    -0x1(%rdx),%eax
  movl   $0x0,0x38(%rsp)
  mov    %eax,0x24(%rsp)
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %r12d,%r12d
  cmpl   $0x1,0x20(%rsp)
  jle    L44
  mov    0x18(%rsp),%rax
  xor    %r12d,%r12d
  movq   $0x1,0x8(%rsp)
  lea    0x8(%rax),%r15
  mov    0x3c(%rsp),%eax
  add    $0x2,%rax
  mov    %rax,0x10(%rsp)
L19:
  mov    0x8(%rsp),%rdx
  cmp    %edx,0x20(%rsp)
  jle    L66
  mov    0x24(%rsp),%eax
  mov    0x18(%rsp),%rcx
  mov    %r15,%r14
  sub    %edx,%eax
  lea    -0x1(%rdx,%rax,1),%rax
  lea    0x10(%rcx,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L29:
  mov    -0x8(%r15),%rax
  add    $0x8,%r14
  movsbl (%rax,%rbp,1),%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x8(%r14),%rax
  movsbl (%rax,%rbp,1),%edi
  call   <tolower@plt>
  movsbl %bl,%edi
  movsbl %al,%esi
  call   <WeightNt@plt>
  add    %eax,%r12d
  cmp    %r14,%r13
  jne    L29
L66:
  addq   $0x1,0x8(%rsp)
  add    $0x8,%r15
  mov    0x8(%rsp),%rax
  cmp    0x10(%rsp),%rax
  jne    L19
  add    %r12d,0x38(%rsp)
L44:
  mov    0x30(%rsp),%rax
  mov    %r12d,(%rax,%rbp,4)
  add    $0x1,%rbp
  cmp    0x28(%rsp),%rbp
  jne    L24
L20:
  mov    0x38(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  movl   $0x0,0x38(%rsp)
  jmp    L20
```

assistant: ```c
int Sop(char **aln_seq, int aln_len, int n_seq, int *col_cost) {
  int l, i, j;
  int col_score, sum;
  char nt[2];
  sum = 0;
  for (l = 0; l < aln_len; l++) {
    col_score = 0;
    for (i = 0; i < n_seq - 1; i++) {
      for (j = i + 1; j < n_seq; j++) {
        nt[0] = (char)tolower(aln_seq[i][l]);
        nt[1] = (char)tolower(aln_seq[j][l]);
        col_score += WeightNt(nt[0], nt[1]);
      }
    }
    col_cost[l] = col_score;
    sum += col_score;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Sop>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %rcx,0x30(%rsp)
  test   %eax,%eax
  jle    L32
  mov    %rax,0x28(%rsp)
  lea    -0x2(%rdx),%eax
  xor    %ebp,%ebp
  mov    %eax,0x3c(%rsp)
  lea    -0x1(%rdx),%eax
  movl   $0x0,0x38(%rsp)
  mov    %eax,0x24(%rsp)
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %r12d,%r12d
  cmpl   $0x1,0x20(%rsp)
  jle    L68
  mov    0x18(%rsp),%rax
  xor    %r12d,%r12d
  movq   $0x1,0x8(%rsp)
  lea    0x8(%rax),%r15
  mov    0x3c(%rsp),%eax
  add    $0x2,%rax
  mov    %rax,0x10(%rsp)
L31:
  mov    0x8(%rsp),%rdx
  cmp    %edx,0x20(%rsp)
  jle    L62
  mov    0x24(%rsp),%eax
  mov    0x18(%rsp),%rcx
  mov    %r15,%r14
  sub    %edx,%eax
  lea    -0x1(%rdx,%rax,1),%rax
  lea    0x10(%rcx,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    -0x8(%r15),%rax
  add    $0x8,%r14
  movsbl (%rax,%rbp,1),%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x8(%r14),%rax
  movsbl (%rax,%rbp,1),%edi
  call   <tolower@plt>
  movsbl %bl,%edi
  movsbl %al,%esi
  call   <WeightNt@plt>
  add    %eax,%r12d
  cmp    %r14,%r13
  jne    L2
L62:
  addq   $0x1,0x8(%rsp)
  add    $0x8,%r15
  mov    0x8(%rsp),%rax
  cmp    0x10(%rsp),%rax
  jne    L31
  add    %r12d,0x38(%rsp)
L68:
  mov    0x30(%rsp),%rax
  mov    %r12d,(%rax,%rbp,4)
  add    $0x1,%rbp
  cmp    0x28(%rsp),%rbp
  jne    L9
L49:
  mov    0x38(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  movl   $0x0,0x38(%rsp)
  jmp    L49
```

assistant: ```c
int Sop(char **aln_seq, int aln_len, int n_seq, int *col_cost) {
  int l, i, j;
  int col_score, sum;
  char nt[2];
  sum = 0;
  for (l = 0; l < aln_len; l++) {
    col_score = 0;
    for (i = 0; i < n_seq - 1; i++) {
      for (j = i + 1; j < n_seq; j++) {
        nt[0] = (char)tolower(aln_seq[i][l]);
        nt[1] = (char)tolower(aln_seq[j][l]);
        col_score += WeightNt(nt[0], nt[1]);
      }
    }
    col_cost[l] = col_score;
    sum += col_score;
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L68
L9:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L17
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L12:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L12
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <escreve@plt>
L17:
  addl   $0x1,-0xc(%rbp)
L68:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L9
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L50
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick>
L50:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L38
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick>
L38:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: NOT loop


assistant: ```c
void quick(int vet[], int esq, int dir) {
  int pivo = esq, i, ch, j;
  for (i = esq + 1; i <= dir; i++) {
    j = i;
    if (vet[j] < vet[pivo]) {
      ch = vet[j];
      while (j > pivo) {
        vet[j] = vet[j - 1];
        j--;
      }
      vet[j] = ch;
      pivo++;
      printf("NOT loop\n");
      escreve(vet, esq, dir);
    }
  }
  if (pivo - 1 >= esq) {
    quick(vet, esq, pivo - 1);
  }
  if (pivo + 1 <= dir) {
    quick(vet, pivo + 1, dir);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quick>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    %edx,%r14d
  lea    0x1(%rsi),%ebx
  cmp    %edx,%ebx
  jg     L115
  movslq %ebx,%rax
  lea    (%rdi,%rax,4),%rbp
  mov    %esi,%r12d
  jmp    L32
L3:
  mov    %ebx,%eax
L16:
  cltq
  mov    %esi,0x0(%r13,%rax,4)
  add    $0x1,%r12d
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <escreve@plt>
L109:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r14d
  jl     L88
L32:
  mov    0x0(%rbp),%esi
  movslq %r12d,%rax
  cmp    0x0(%r13,%rax,4),%esi
  jge    L109
  cmp    %ebx,%r12d
  jge    L3
  lea    -0x4(%rbp),%rcx
  mov    %ebx,%eax
  sub    %r12d,%eax
  lea    -0x1(%rax),%eax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rbp,%rax
L34:
  mov    -0x4(%rax),%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L34
  mov    %r12d,%eax
  jmp    L16
L88:
  cmp    %r15d,%r12d
  jg     L107
L102:
  cmp    %r14d,%r12d
  jl     L9
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L107:
  lea    -0x1(%r12),%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <quick>
  jmp    L102
L115:
  mov    %esi,%r12d
  jmp    L102
L9:
  lea    0x1(%r12),%esi
  mov    %r14d,%edx
  mov    %r13,%rdi
  call   <quick>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: NOT loop


assistant: ```c
void quick(int vet[], int esq, int dir) {
  int pivo = esq, i, ch, j;
  for (i = esq + 1; i <= dir; i++) {
    j = i;
    if (vet[j] < vet[pivo]) {
      ch = vet[j];
      while (j > pivo) {
        vet[j] = vet[j - 1];
        j--;
      }
      vet[j] = ch;
      pivo++;
      printf("NOT loop\n");
      escreve(vet, esq, dir);
    }
  }
  if (pivo - 1 >= esq) {
    quick(vet, esq, pivo - 1);
  }
  if (pivo + 1 <= dir) {
    quick(vet, pivo + 1, dir);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%r14),%ebp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r13d,%ebp
  jg     L11
L58:
  movslq %ebp,%rbx
  mov    %r14d,%r15d
  shl    $0x2,%rbx
  jmp    L49
  nopl   0x0(%rax)
L20:
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r13d
  jl     L85
L49:
  movslq %r15d,%rax
  mov    (%r12,%rbx,1),%r9d
  lea    (%r12,%rbx,1),%rdx
  lea    (%r12,%rax,4),%r8
  cmp    (%r8),%r9d
  jge    L20
  mov    %r8,(%rsp)
  cmp    %ebp,%r15d
  jge    L41
  mov    %ebp,%eax
  mov    %r9d,0xc(%rsp)
  sub    %r15d,%eax
  sub    $0x1,%eax
  mov    %rax,%rdi
  lea    0x4(,%rax,4),%rdx
  neg    %rdi
  shl    $0x2,%rdi
  lea    -0x4(%rbx,%rdi,1),%rsi
  add    %rbx,%rdi
  add    %r12,%rsi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    0xc(%rsp),%r9d
  mov    (%rsp),%r8
L86:
  mov    %r9d,(%r8)
  add    $0x1,%ebp
  add    $0x1,%r15d
  add    $0x4,%rbx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <escreve@plt>
  cmp    %ebp,%r13d
  jge    L49
L85:
  cmp    %r14d,%r15d
  jg     L18
L68:
  cmp    %r13d,%r15d
  jge    L112
L80:
  lea    0x1(%r15),%r14d
  lea    0x1(%r14),%ebp
  cmp    %r13d,%ebp
  jle    L58
L11:
  mov    %r14d,%r15d
  cmp    %r13d,%r15d
  jl     L80
L112:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %rdx,%r8
  jmp    L86
  nopl   (%rax)
L18:
  lea    -0x1(%r15),%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <quick>
  jmp    L68
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: NOT loop


assistant: ```c
void quick(int vet[], int esq, int dir) {
  int pivo = esq, i, ch, j;
  for (i = esq + 1; i <= dir; i++) {
    j = i;
    if (vet[j] < vet[pivo]) {
      ch = vet[j];
      while (j > pivo) {
        vet[j] = vet[j - 1];
        j--;
      }
      vet[j] = ch;
      pivo++;
      printf("NOT loop\n");
      escreve(vet, esq, dir);
    }
  }
  if (pivo - 1 >= esq) {
    quick(vet, esq, pivo - 1);
  }
  if (pivo + 1 <= dir) {
    quick(vet, pivo + 1, dir);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<quick>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%r14),%ebp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %r13d,%ebp
  jg     L52
L10:
  movslq %ebp,%rbx
  mov    %r14d,%r15d
  shl    $0x2,%rbx
  jmp    L84
  nopl   0x0(%rax)
L36:
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r13d
  jl     L26
L84:
  movslq %r15d,%rax
  mov    (%r12,%rbx,1),%r9d
  lea    (%r12,%rbx,1),%rdx
  lea    (%r12,%rax,4),%r8
  cmp    (%r8),%r9d
  jge    L36
  mov    %r8,(%rsp)
  cmp    %ebp,%r15d
  jge    L3
  mov    %ebp,%eax
  mov    %r9d,0xc(%rsp)
  sub    %r15d,%eax
  sub    $0x1,%eax
  mov    %rax,%rdi
  lea    0x4(,%rax,4),%rdx
  neg    %rdi
  shl    $0x2,%rdi
  lea    -0x4(%rbx,%rdi,1),%rsi
  add    %rbx,%rdi
  add    %r12,%rsi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    0xc(%rsp),%r9d
  mov    (%rsp),%r8
L50:
  mov    %r9d,(%r8)
  add    $0x1,%ebp
  add    $0x1,%r15d
  add    $0x4,%rbx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <escreve@plt>
  cmp    %ebp,%r13d
  jge    L84
L26:
  cmp    %r14d,%r15d
  jg     L30
L111:
  cmp    %r13d,%r15d
  jge    L6
L19:
  lea    0x1(%r15),%r14d
  lea    0x1(%r14),%ebp
  cmp    %r13d,%ebp
  jle    L10
L52:
  mov    %r14d,%r15d
  cmp    %r13d,%r15d
  jl     L19
L6:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdx,%r8
  jmp    L50
  nopl   (%rax)
L30:
  lea    -0x1(%r15),%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <quick>
  jmp    L111
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D6: NOT loop


assistant: ```c
void quick(int vet[], int esq, int dir) {
  int pivo = esq, i, ch, j;
  for (i = esq + 1; i <= dir; i++) {
    j = i;
    if (vet[j] < vet[pivo]) {
      ch = vet[j];
      while (j > pivo) {
        vet[j] = vet[j - 1];
        j--;
      }
      vet[j] = ch;
      pivo++;
      printf("NOT loop\n");
      escreve(vet, esq, dir);
    }
  }
  if (pivo - 1 >= esq) {
    quick(vet, esq, pivo - 1);
  }
  if (pivo + 1 <= dir) {
    quick(vet, pivo + 1, dir);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L5:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L10:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < w; y++)
    for (int x = 0; x < h; x++)
      result[x + y * h] = pattern[y + x * w];
  result[w * h] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<transpose>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  mov    %rcx,%r11
  test   %edi,%edi
  jle    L52
  mov    %rdx,%rbp
  mov    %edi,%r12d
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  movslq %edi,%rdi
  lea    -0x1(%rsi),%eax
  lea    0x1(%rcx,%rax,1),%r13
  jmp    L0
L14:
  lea    0x0(%rbp,%r8,1),%rdx
  movslq %r9d,%rsi
  lea    (%r11,%rsi,1),%rax
  add    %r13,%rsi
L38:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  add    %rdi,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L38
L18:
  add    $0x1,%r8
  add    %r10d,%r9d
  cmp    %r12,%r8
  je     L52
L0:
  test   %r10d,%r10d
  jg     L14
  jmp    L18
L52:
  imul   %r10d,%ebx
  movslq %ebx,%rax
  movb   $0x0,(%r11,%rax,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void transpose(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < w; y++)
    for (int x = 0; x < h; x++)
      result[x + y * h] = pattern[y + x * w];
  result[w * h] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<transpose>:
  endbr64
  push   %r12
  mov    %esi,%r10d
  mov    %rcx,%r11
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L27
  lea    -0x1(%rsi),%eax
  mov    %rdx,%r12
  movslq %edi,%rdi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  lea    0x1(%rcx,%rax,1),%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  test   %r10d,%r10d
  jle    L30
  movslq %r9d,%rsi
  lea    (%r12,%r8,1),%rdx
  lea    (%r11,%rsi,1),%rax
  add    %rbp,%rsi
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    %rdi,%rdx
  mov    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L18
L30:
  add    $0x1,%r8
  add    %r10d,%r9d
  cmp    %rdi,%r8
  jne    L0
L27:
  imul   %r10d,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r11,%rax,1)
  pop    %r12
  ret
```

assistant: ```c
void transpose(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < w; y++)
    for (int x = 0; x < h; x++)
      result[x + y * h] = pattern[y + x * w];
  result[w * h] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<transpose>:
  endbr64
  push   %r12
  mov    %edi,%r11d
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  test   %edi,%edi
  jle    L3
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%ecx
  movslq %esi,%rbx
  movslq %edi,%r9
  xor    %r10d,%r10d
  lea    0x1(%r12,%rcx,1),%r8
  nopl   0x0(%rax)
L37:
  mov    %r8,%rax
  lea    (%rdx,%r10,1),%rsi
  sub    %rcx,%rax
  sub    $0x1,%rax
  xchg   %ax,%ax
L30:
  movzbl (%rsi),%edi
  add    $0x1,%rax
  add    %r9,%rsi
  mov    %dil,-0x1(%rax)
  cmp    %r8,%rax
  jne    L30
  add    $0x1,%r10
  add    %rbx,%r8
  cmp    %r9,%r10
  jne    L37
L3:
  imul   %ebp,%r11d
  pop    %rbx
  pop    %rbp
  movslq %r11d,%rax
  movb   $0x0,(%r12,%rax,1)
  pop    %r12
  ret
```

assistant: ```c
void transpose(int w, int h, char *pattern, char *result) {
  for (int y = 0; y < w; y++)
    for (int x = 0; x < h; x++)
      result[x + y * h] = pattern[y + x * w];
  result[w * h] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ChangeTHEX2CPTR>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%r14
  mov    %rsi,%r15
  test   %rsi,%rsi
  je     L2
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L41
  and    $0xfffffffe,%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%ebp
L58:
  movzbl (%r14,%rbp,1),%r12d
  movzbl 0x1(%r14,%rbp,1),%r13d
  mov    %r13b,0xb(%rsp)
  mov    %ebp,%ebx
  shr    $0x1f,%ebx
  add    %ebp,%ebx
  sar    %ebx
  movslq %ebx,%rbx
  movb   $0x0,0x1(%r15,%rbx,1)
  movsbl %r12b,%r12d
  mov    %r12d,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L35
  movsbl %r13b,%r13d
  mov    %r13d,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L35
  mov    %r12d,%edi
  call   <oneHexCharToHex@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <oneHexCharToHex@plt>
  shl    $0x4,%r12d
  or     %eax,%r12d
  mov    %r12b,(%r15,%rbx,1)
  add    $0x2,%rbp
  cmp    %ebp,0xc(%rsp)
  jg     L58
  mov    $0x0,%eax
  jmp    L81
L2:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L81
L41:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L81
L35:
  movsbl 0xb(%rsp),%edx
  mov    %r12d,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
L81:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string

tool: D12: error: inHexString or outHex is null!

tool: D27: error: strlen(inHexString) <= 1!

tool: D17: error: %c or %c is not hex digit!


assistant: ```c
int ChangeTHEX2CPTR(const char *inHexString, char *outHex) {
  int success = -1;
  int len = 0;
  int i;
  char ch1, ch2;
  do {
    if (NULL == inHexString || NULL == outHex) {
      printf("error: inHexString or outHex is null!\n");
      break;
    }
    len = strlen(inHexString);
    if (len <= 1) {
      printf("error: strlen(inHexString) <= 1!\n");
      break;
    }
    len &= ~1;
    for (i = 0; i < len; i += 2) {
      ch1 = inHexString[i];
      ch2 = inHexString[i + 1];
      outHex[i / 2 + 1] = 0;
      if (isxdigit(ch1) && isxdigit(ch2)) {
        ch1 = oneHexCharToHex(ch1);
        ch2 = oneHexCharToHex(ch2);
        outHex[i / 2] = (ch1 << 4) | ch2;
      } else {
        printf("error: %c or %c is not hex digit!\n", ch1, ch2);
        goto exit;
      }
    }
    success = 0;
  } while (0);
exit:
  return success;
}
```