ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1a0,%rsp
  mov    %edi,-0x194(%rbp)
  mov    %rsi,-0x1a0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x190(%rbp)
  movl   $0x0,-0x188(%rbp)
  mov    -0x1a0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x184(%rbp)
  mov    -0x1a0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  lea    -0x180(%rbp),%rax
  mov    $0x64,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L29
L6:
  movl   $0x0,-0x18c(%rbp)
  jmp    L8
L4:
  mov    -0x18c(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%edx
  mov    -0x190(%rbp),%eax
  cltq
  movzbl -0x180(%rbp,%rax,1),%eax
  xor    %eax,%edx
  mov    -0x18c(%rbp),%eax
  cltq
  mov    %dl,-0x110(%rbp,%rax,1)
  mov    -0x190(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x184(%rbp)
  mov    %edx,-0x190(%rbp)
  addl   $0x1,-0x18c(%rbp)
L8:
  mov    -0x18c(%rbp),%eax
  cmp    -0x188(%rbp),%eax
  jl     L4
  mov    -0x188(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L29:
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x188(%rbp)
  cmpl   $0x0,-0x188(%rbp)
  jne    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char kulcs[100];
  char buffer[256];
  int kulcs_index = 0;
  int olvasott_bajtok = 0;
  int kulcs_meret = strlen(argv[1]);
  strncpy(kulcs, argv[1], 100);
  while ((olvasott_bajtok = read(0, (void *)buffer, 256))) {
    for (int i = 0; i < olvasott_bajtok; ++i) {
      buffer[i] = buffer[i] ^ kulcs[kulcs_index];
      kulcs_index = (kulcs_index + 1) % kulcs_meret;
    }
    write(1, buffer, olvasott_bajtok);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x180,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rdi
  mov    $0x64,%edx
  call   <strncpy@plt>
  mov    $0x0,%ebx
  lea    0x70(%rsp),%r12
  jmp    L32
L52:
  lea    0x70(%rsp),%rcx
  lea    -0x1(%rdi),%eax
  lea    0x71(%rsp,%rax,1),%rsi
L12:
  movslq %ebx,%rax
  movzbl (%rsp,%rax,1),%eax
  xor    %al,(%rcx)
  lea    0x1(%rbx),%eax
  cltd
  idiv   %ebp
  mov    %edx,%ebx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L12
L16:
  mov    %edi,%edx
  mov    %r12,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L32:
  mov    $0x100,%edx
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%edi
  test   %eax,%eax
  je     L40
  jg     L52
  jmp    L16
L40:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x180,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char kulcs[100];
  char buffer[256];
  int kulcs_index = 0;
  int olvasott_bajtok = 0;
  int kulcs_meret = strlen(argv[1]);
  strncpy(kulcs, argv[1], 100);
  while ((olvasott_bajtok = read(0, (void *)buffer, 256))) {
    for (int i = 0; i < olvasott_bajtok; ++i) {
      buffer[i] = buffer[i] ^ kulcs[kulcs_index];
      kulcs_index = (kulcs_index + 1) % kulcs_meret;
    }
    write(1, buffer, olvasott_bajtok);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x188,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%r13
  lea    0x71(%rsp),%r12
  call   <strlen@plt>
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rdi
  xor    %ebx,%ebx
  mov    $0x64,%edx
  mov    %eax,%ebp
  call   <strncpy@plt>
  nop
L17:
  mov    $0x100,%edx
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  je     L0
  jle    L36
  lea    -0x1(%r8),%esi
  mov    %r13,%rcx
  add    %r12,%rsi
  nopw   0x0(%rax,%rax,1)
L41:
  lea    0x1(%rbx),%eax
  movslq %ebx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  xor    %dl,(%rcx)
  cltd
  add    $0x1,%rcx
  idiv   %ebp
  mov    %edx,%ebx
  cmp    %rsi,%rcx
  jne    L41
L36:
  mov    %r8d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  nopl   0x0(%rax)
L0:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x188,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char kulcs[100];
  char buffer[256];
  int kulcs_index = 0;
  int olvasott_bajtok = 0;
  int kulcs_meret = strlen(argv[1]);
  strncpy(kulcs, argv[1], 100);
  while ((olvasott_bajtok = read(0, (void *)buffer, 256))) {
    for (int i = 0; i < olvasott_bajtok; ++i) {
      buffer[i] = buffer[i] ^ kulcs[kulcs_index];
      kulcs_index = (kulcs_index + 1) % kulcs_meret;
    }
    write(1, buffer, olvasott_bajtok);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x188,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%r13
  lea    0x71(%rsp),%r12
  call   <strlen@plt>
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rdi
  xor    %ebx,%ebx
  mov    $0x64,%edx
  mov    %eax,%ebp
  call   <strncpy@plt>
  nop
L44:
  mov    $0x100,%edx
  mov    %r13,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  je     L30
  jle    L4
  lea    -0x1(%r8),%esi
  mov    %r13,%rcx
  add    %r12,%rsi
  nopw   0x0(%rax,%rax,1)
L17:
  lea    0x1(%rbx),%eax
  movslq %ebx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  xor    %dl,(%rcx)
  cltd
  add    $0x1,%rcx
  idiv   %ebp
  mov    %edx,%ebx
  cmp    %rsi,%rcx
  jne    L17
L4:
  mov    %r8d,%edx
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L44
  nopl   0x0(%rax)
L30:
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x188,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char kulcs[100];
  char buffer[256];
  int kulcs_index = 0;
  int olvasott_bajtok = 0;
  int kulcs_meret = strlen(argv[1]);
  strncpy(kulcs, argv[1], 100);
  while ((olvasott_bajtok = read(0, (void *)buffer, 256))) {
    for (int i = 0; i < olvasott_bajtok; ++i) {
      buffer[i] = buffer[i] ^ kulcs[kulcs_index];
      kulcs_index = (kulcs_index + 1) % kulcs_meret;
    }
    write(1, buffer, olvasott_bajtok);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xfff,-0xc(%rbp)
  jle    L35
  movl   $0xfff,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L51
L9:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L55
  subq   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  jmp    L15
L55:
  nop
L15:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rtrim(char *totrim) {
  int smlen;
  char *pnt;
  pnt = totrim;
  smlen = strlen(totrim);
  if (smlen > 4095)
    smlen = 4095;
  pnt = pnt + smlen;
  while (*pnt == ' ' || *pnt == 0x0) {
    *pnt = 0x0;
    if (pnt == totrim)
      break;
    else
      pnt--;
  }
  return totrim;
}
```
user: What is the c source code of the assembly code below?

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    $0xfff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cltq
  add    %rbx,%rax
  testb  $0xdf,(%rax)
  jne    L25
  movb   $0x0,(%rax)
  cmp    %rax,%rbx
  je     L25
L33:
  sub    $0x1,%rax
  testb  $0xdf,(%rax)
  jne    L25
  movb   $0x0,(%rax)
  cmp    %rax,%rbx
  jne    L33
L25:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *rtrim(char *totrim) {
  int smlen;
  char *pnt;
  pnt = totrim;
  smlen = strlen(totrim);
  if (smlen > 4095)
    smlen = 4095;
  pnt = pnt + smlen;
  while (*pnt == ' ' || *pnt == 0x0) {
    *pnt = 0x0;
    if (pnt == totrim)
      break;
    else
      pnt--;
  }
  return totrim;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    $0xfff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cltq
  add    %r12,%rax
  testb  $0xdf,(%rax)
  je     L36
  jmp    L13
  nopl   0x0(%rax)
L7:
  sub    $0x1,%rax
  testb  $0xdf,(%rax)
  jne    L13
L36:
  movb   $0x0,(%rax)
  cmp    %rax,%r12
  jne    L7
L13:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *totrim) {
  int smlen;
  char *pnt;
  pnt = totrim;
  smlen = strlen(totrim);
  if (smlen > 4095)
    smlen = 4095;
  pnt = pnt + smlen;
  while (*pnt == ' ' || *pnt == 0x0) {
    *pnt = 0x0;
    if (pnt == totrim)
      break;
    else
      pnt--;
  }
  return totrim;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    $0xfff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cltq
  add    %r12,%rax
  testb  $0xdf,(%rax)
  je     L8
  jmp    L37
  nopl   0x0(%rax)
L13:
  sub    $0x1,%rax
  testb  $0xdf,(%rax)
  jne    L37
L8:
  movb   $0x0,(%rax)
  cmp    %rax,%r12
  jne    L13
L37:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *totrim) {
  int smlen;
  char *pnt;
  pnt = totrim;
  smlen = strlen(totrim);
  if (smlen > 4095)
    smlen = 4095;
  pnt = pnt + smlen;
  while (*pnt == ' ' || *pnt == 0x0) {
    *pnt = 0x0;
    if (pnt == totrim)
      break;
    else
      pnt--;
  }
  return totrim;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  and    -0x20(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x20(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int a, int b, int c, int d) {
  int e = (a & b) & (c & d);
  int f = (c & a) & (b & d);
  return e & f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  and    %ecx,%edx
  and    %esi,%edx
  mov    %edx,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int main(int a, int b, int c, int d) {
  int e = (a & b) & (c & d);
  int f = (c & a) & (b & d);
  return e & f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  and    %ecx,%edx
  and    %esi,%edx
  mov    %edx,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int main(int a, int b, int c, int d) {
  int e = (a & b) & (c & d);
  int f = (c & a) & (b & d);
  return e & f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<abcdefghi12>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: abcdefghi12

assistant: ```c
void abcdefghi12(void) {
  const char(*ss)[12] = &__func__;
  static int arr[sizeof(__func__) == 12 ? 1 : -1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abcdefghi12>:
  endbr64
  ret
```

assistant: ```c
void abcdefghi12(void) {
  const char(*ss)[12] = &__func__;
  static int arr[sizeof(__func__) == 12 ? 1 : -1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<abcdefghi12>:
  endbr64
  ret
```

assistant: ```c
void abcdefghi12(void) {
  const char(*ss)[12] = &__func__;
  static int arr[sizeof(__func__) == 12 ? 1 : -1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abcdefghi12>:
  endbr64
  ret
```

assistant: ```c
void abcdefghi12(void) {
  const char(*ss)[12] = &__func__;
  static int arr[sizeof(__func__) == 12 ? 1 : -1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<projectString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %ecx,%eax
  mov    %dl,-0x44(%rbp)
  mov    %al,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <needMem@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  movsbl -0x44(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <countChars@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  cmp    %eax,%ebx
  je     L47
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <errAbort@plt>
L47:
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L1
L21:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x44(%rbp)
  jne    L44
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x48(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L39
L44:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L39:
  addl   $0x1,-0x24(%rbp)
L1:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    -0x18(%rbp),%rax
  add    $0x40,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: ERROR from rnautil::projectString: Input string 's' has wrong length.


assistant: ```c
char *projectString(char *s, char *ref, char refChar, char insertChar) {
  int i, j, size = strlen(ref);
  char *copy = (char *)needMem(size + 1);
  if (strlen(s) != strlen(ref) - countChars(ref, refChar))
    errAbort("ERROR from rnautil::projectString: Input string 's' has wrong length.\n");
  for (i = 0, j = 0; i < size; i++) {
    if (ref[i] == refChar)
      copy[i] = insertChar;
    else {
      copy[i] = s[j];
      j++;
    }
  }
  return copy;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<projectString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,0xc(%rsp)
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x1(%rax),%edi
  call   <needMem@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0x8(%rsp)
  movsbl 0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <countChars@plt>
  mov    %eax,%edx
  mov    0x8(%rsp),%eax
  sub    %edx,%eax
  cmp    %eax,0x4(%rsp)
  jne    L53
L27:
  test   %r14d,%r14d
  jle    L52
  lea    -0x1(%r14),%eax
  lea    0x1(%r13,%rax,1),%rsi
  mov    %r13,%rax
  mov    $0x0,%edx
  sub    %r13,%rbx
  jmp    L63
L53:
  lea    D6(%rip),%rdi
  call   <errAbort@plt>
  jmp    L27
L0:
  mov    %r15b,(%rax)
L2:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L52
L63:
  cmp    %r12b,(%rbx,%rax,1)
  je     L0
  movslq %edx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%ecx
  mov    %cl,(%rax)
  add    $0x1,%edx
  jmp    L2
L52:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: ERROR from rnautil::projectString: Input string 's' has wrong length.


assistant: ```c
char *projectString(char *s, char *ref, char refChar, char insertChar) {
  int i, j, size = strlen(ref);
  char *copy = (char *)needMem(size + 1);
  if (strlen(s) != strlen(ref) - countChars(ref, refChar))
    errAbort("ERROR from rnautil::projectString: Input string 's' has wrong length.\n");
  for (i = 0, j = 0; i < size; i++) {
    if (ref[i] == refChar)
      copy[i] = insertChar;
    else {
      copy[i] = s[j];
      j++;
    }
  }
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<projectString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,0x8(%rsp)
  call   <needMem@plt>
  mov    %r12,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,0x4(%rsp)
  call   <strlen@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    %eax,%r14d
  movsbl %sil,%esi
  call   <countChars@plt>
  mov    0x8(%rsp),%edx
  sub    %eax,%r14d
  cmp    %r14d,0x4(%rsp)
  je     L15
  lea    D9(%rip),%rdi
  mov    %edx,0x4(%rsp)
  call   <errAbort@plt>
  mov    0x4(%rsp),%edx
L15:
  test   %edx,%edx
  jle    L19
  lea    -0x1(%rdx),%eax
  sub    %r15,%rbx
  xor    %ecx,%ecx
  lea    0x1(%r15,%rax,1),%rdi
  mov    %rbx,%rsi
  mov    %r15,%rax
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebp,%edx
  cmp    %r13b,(%rsi,%rax,1)
  je     L2
  movslq %ecx,%rdx
  add    $0x1,%ecx
  movzbl (%r12,%rdx,1),%edx
L2:
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L20
L19:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: ERROR from rnautil::projectString: Input string 's' has wrong length.


assistant: ```c
char *projectString(char *s, char *ref, char refChar, char insertChar) {
  int i, j, size = strlen(ref);
  char *copy = (char *)needMem(size + 1);
  if (strlen(s) != strlen(ref) - countChars(ref, refChar))
    errAbort("ERROR from rnautil::projectString: Input string 's' has wrong length.\n");
  for (i = 0, j = 0; i < size; i++) {
    if (ref[i] == refChar)
      copy[i] = insertChar;
    else {
      copy[i] = s[j];
      j++;
    }
  }
  return copy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<projectString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  mov    %cl,0xb(%rsp)
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%r15d
  call   <needMem@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,0x4(%rsp)
  call   <strlen@plt>
  mov    0xc(%rsp),%edx
  mov    %rbx,%rdi
  mov    %eax,%r14d
  movsbl %dl,%esi
  call   <countChars@plt>
  movzbl 0xb(%rsp),%r8d
  sub    %eax,%r14d
  cmp    %r14d,0x4(%rsp)
  je     L52
  lea    D2(%rip),%rdi
  mov    %r8b,0x4(%rsp)
  call   <errAbort@plt>
  movzbl 0x4(%rsp),%r8d
L52:
  test   %r15d,%r15d
  jle    L19
  lea    -0x1(%r15),%eax
  sub    %r13,%rbx
  xor    %edx,%edx
  lea    0x1(%r13,%rax,1),%rdi
  mov    %rbx,%rcx
  mov    %r13,%rax
  nop
L30:
  cmp    %r12b,(%rcx,%rax,1)
  je     L18
  movslq %edx,%rsi
  add    $0x1,%rax
  add    $0x1,%edx
  movzbl 0x0(%rbp,%rsi,1),%esi
  mov    %sil,-0x1(%rax)
  cmp    %rdi,%rax
  jne    L30
L19:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    %r8b,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L30
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: ERROR from rnautil::projectString: Input string 's' has wrong length.


assistant: ```c
char *projectString(char *s, char *ref, char refChar, char insertChar) {
  int i, j, size = strlen(ref);
  char *copy = (char *)needMem(size + 1);
  if (strlen(s) != strlen(ref) - countChars(ref, refChar))
    errAbort("ERROR from rnautil::projectString: Input string 's' has wrong length.\n");
  for (i = 0, j = 0; i < size; i++) {
    if (ref[i] == refChar)
      copy[i] = insertChar;
    else {
      copy[i] = s[j];
      j++;
    }
  }
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    $0x28,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    $0x30,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t load64(const void *src) {
  const uint8_t *p = (const uint8_t *)src;
  uint64_t w = *p++;
  w |= (uint64_t)(*p++) << 8;
  w |= (uint64_t)(*p++) << 16;
  w |= (uint64_t)(*p++) << 24;
  w |= (uint64_t)(*p++) << 32;
  w |= (uint64_t)(*p++) << 40;
  w |= (uint64_t)(*p++) << 48;
  w |= (uint64_t)(*p++) << 56;
  return w;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<load64>:
  endbr64
  mov    0x4(%rdi),%edx
  shl    $0x8,%edx
  mov    0x8(%rdi),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  or     (%rdi),%edx
  mov    0xc(%rdi),%eax
  shl    $0x18,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint64_t load64(const void *src) {
  const uint8_t *p = (const uint8_t *)src;
  uint64_t w = *p++;
  w |= (uint64_t)(*p++) << 8;
  w |= (uint64_t)(*p++) << 16;
  w |= (uint64_t)(*p++) << 24;
  w |= (uint64_t)(*p++) << 32;
  w |= (uint64_t)(*p++) << 40;
  w |= (uint64_t)(*p++) << 48;
  w |= (uint64_t)(*p++) << 56;
  return w;
}
```