user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  push   %r12
  lea    D70(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rbp
  call   <puts@plt>
  lea    0x18(%rsp),%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%edx
  test   %edx,%edx
  jle    L33
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x18(%rsp)
  jge    L37
L33:
  lea    D17(%rip),%rdi
  lea    0x54(%rsp),%rbp
  mov    $0x1,%ebx
  call   <puts@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L102
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x18(%rsp)
  jge    L6
L102:
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq 0x18(%rsp),%rbp
  movss  0x1c(%rsp),%xmm4
  movss  0x24(%rsp),%xmm0
  subss  0x20(%rsp),%xmm0
  subss  0x20(%rsp,%rbp,4),%xmm4
  movss  0x50(%rsp,%rbp,4),%xmm3
  mov    %rbp,%rbx
  divss  %xmm0,%xmm4
  test   %ebp,%ebp
  js     L101
  lea    0x80(%rsp),%r10
  lea    0x4(,%rbp,4),%rdx
  movss  %xmm3,0xc(%rsp)
  mov    %r10,%rdi
  lea    0x50(%rsp),%rsi
  movss  %xmm4,0x8(%rsp)
  call   <memcpy@plt>
  test   %ebp,%ebp
  movss  0x8(%rsp),%xmm4
  movss  0xc(%rsp),%xmm3
  mov    %rax,%r10
  jle    L101
  lea    0x84(%rsp),%r13
  lea    0x1(%rbx),%r9d
  mov    $0x28,%esi
  xor    %ecx,%ecx
  mov    %r13,%r12
  mov    $0x1,%r11d
  mov    $0x1,%r8d
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %r8d,%ebx
  jl     L60
  mov    %ebx,%eax
  sub    %r8d,%eax
  add    %r11,%rax
  lea    0x0(%r13,%rax,4),%rdi
  mov    %r12,%rax
  nopl   (%rax)
L43:
  movss  (%rax),%xmm0
  subss  -0x4(%rax),%xmm0
  lea    (%rax,%rcx,1),%rdx
  add    $0x4,%rax
  movss  %xmm0,(%rdx,%rsi,1)
  cmp    %rdi,%rax
  jne    L43
L60:
  add    $0x1,%r8d
  add    $0x2c,%r12
  sub    $0x28,%rcx
  add    $0x28,%rsi
  add    $0xb,%r11
  cmp    %r9d,%r8d
  jne    L1
  movss  D36(%rip),%xmm5
  lea    (%r10,%rbp,4),%rdx
  mov    $0x1,%eax
  movaps %xmm5,%xmm0
L32:
  pxor   %xmm2,%xmm2
  add    $0x28,%rdx
  cvtsi2ss %eax,%xmm2
  add    $0x1,%eax
  movaps %xmm2,%xmm1
  addss  %xmm4,%xmm1
  subss  %xmm5,%xmm1
  mulss  %xmm1,%xmm0
  movss  (%rdx),%xmm1
  divss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  addss  %xmm1,%xmm3
  cmp    %r9d,%eax
  jne    L32
L101:
  pxor   %xmm0,%xmm0
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm3,%xmm0
  call   <printf@plt>
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D70
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D58
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D52
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: f32
name: disassemble_data
arguments: tag: D7
data_type: string

tool: D1: Enter the value of n

tool: D70: %f

tool: D24: %d

tool: D58: Enter the x values

tool: D17: Enter the y values

tool: D52: Enter the interpolating point

tool: D36: 1

tool: D7: 
%f


assistant: ```c
int main() {
  int i, j, n;
  float x[10], y[10], f[10][10], h, s, p = 1.0, u, a;
  printf("Enter the value of n\n");
  scanf("%d", &n);
  printf("Enter the x values\n");
  for (i = 1; i <= n; i++)
    scanf("%f", &x[i]);
  printf("Enter the y values\n");
  for (i = 1; i <= n; i++)
    scanf("%f", &y[i]);
  printf("Enter the interpolating point");
  scanf("%f", &a);
  h = x[1] - x[0];
  u = (a - x[n]) / h;
  s = y[n];
  for (j = 0; j <= n; j++)
    f[0][j] = y[j];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++)
      f[i][j] = f[i - 1][j] - f[i - 1][j - 1];
  for (i = 1; i <= n; i++) {
    p = p * (u + i - 1) / i;
    s += p * f[i][n];
  }
  printf("\n%f\n", s);
}
```