ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<odwroc>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L29
  lea    0x1(%rdi),%rdx
  mov    $0x0,%eax
L6:
  mov    %eax,%esi
  add    $0x1,%eax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L6
  cmp    $0x1,%eax
  jle    L29
  movslq %esi,%rcx
  add    %rdi,%rcx
  mov    $0x0,%eax
  add    $0x1,%esi
L39:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rcx),%r8d
  mov    %r8b,(%rdi,%rax,1)
  mov    %dl,(%rcx)
  mov    %esi,%r8d
  sub    %eax,%r8d
  mov    %r8d,%edx
  shr    $0x1f,%edx
  add    %r8d,%edx
  sar    %edx
  add    $0x1,%rax
  sub    $0x1,%rcx
  cmp    %eax,%edx
  jge    L39
L29:
  ret
```

assistant: ```c
void odwroc(char tab[]) {
  char a;
  int i, j;
  i = 0;
  while (tab[i] != 0) {
    i++;
  }
  if (i > 1) {
    i -= 1;
    for (j = 0; j <= (i + 2) / 2; j++) {
      a = tab[j];
      tab[j] = tab[i];
      tab[i] = a;
      i--;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<odwroc>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L28
  lea    0x1(%rdi),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdx
  mov    %eax,%r8d
  add    $0x1,%eax
  cmpb   $0x0,-0x1(%rdx)
  jne    L9
  cmp    $0x1,%eax
  je     L28
  movslq %r8d,%rcx
  xor    %eax,%eax
  add    $0x1,%r8d
  add    %rdi,%rcx
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L49:
  movzbl (%rdi,%rax,1),%esi
L46:
  movzbl (%rcx),%edx
  sub    $0x1,%rcx
  mov    %dl,(%rdi,%rax,1)
  mov    %sil,0x1(%rcx)
  mov    %r8d,%esi
  sub    %eax,%esi
  add    $0x1,%rax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  cmp    %eax,%edx
  jge    L49
L28:
  ret
```

assistant: ```c
void odwroc(char tab[]) {
  char a;
  int i, j;
  i = 0;
  while (tab[i] != 0) {
    i++;
  }
  if (i > 1) {
    i -= 1;
    for (j = 0; j <= (i + 2) / 2; j++) {
      a = tab[j];
      tab[j] = tab[i];
      tab[i] = a;
      i--;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<odwroc>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  lea    0x1(%rdi),%rdx
  xor    %eax,%eax
  nop
L36:
  add    $0x1,%rdx
  mov    %eax,%esi
  add    $0x1,%eax
  cmpb   $0x0,-0x1(%rdx)
  jne    L36
  cmp    $0x1,%eax
  je     L37
  movslq %esi,%rcx
  xor    %eax,%eax
  lea    0x1(%rsi),%r8d
  add    %rdi,%rcx
L24:
  movzbl (%rcx),%esi
  movzbl (%rdi,%rax,1),%edx
  sub    $0x1,%rcx
  mov    %sil,(%rdi,%rax,1)
  mov    %r8d,%esi
  sub    %eax,%esi
  mov    %dl,0x1(%rcx)
  add    $0x1,%rax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  cmp    %eax,%edx
  jge    L24
L37:
  ret
```

assistant: ```c
void odwroc(char tab[]) {
  char a;
  int i, j;
  i = 0;
  while (tab[i] != 0) {
    i++;
  }
  if (i > 1) {
    i -= 1;
    for (j = 0; j <= (i + 2) / 2; j++) {
      a = tab[j];
      tab[j] = tab[i];
      tab[i] = a;
      i--;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ordena>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L56
L34:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L15
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm0
  comiss -0x14(%rbp),%xmm0
  jbe    L59
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
L59:
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L8
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L36
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,0x4(%rax)
L36:
  addl   $0x1,-0x18(%rbp)
L56:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ordena(float notas[][2], int N) {
  for (int i = 0; i < N; ++i) {
    float max = notas[i][1];
    int index = i;
    for (int j = i + 1; j < N; ++j) {
      if (notas[j][1] > max) {
        index = j;
        max = notas[j][1];
      }
    }
    if (index != i) {
      do {
        float temp = (notas[i][0]);
        (notas[i][0]) = (notas[index][0]);
        (notas[index][0]) = temp;
      } while (0);
      do {
        float temp = (notas[i][1]);
        (notas[i][1]) = (notas[index][1]);
        (notas[index][1]) = temp;
      } while (0);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ordena>:
  endbr64
  test   %esi,%esi
  jle    L57
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  jmp    L44
L46:
  movss  (%rdi,%rcx,8),%xmm0
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,(%rdi,%rcx,8)
  movss  %xmm0,(%rax)
  movss  0x4(%rdi,%rcx,8),%xmm0
  movss  0x4(%rax),%xmm1
  movss  %xmm1,0x4(%rdi,%rcx,8)
  movss  %xmm0,0x4(%rax)
L24:
  add    $0x1,%rcx
  add    $0x1,%r8
L44:
  mov    %ecx,%edx
  movss  0x4(%rdi,%rcx,8),%xmm0
  cmp    %r8d,%esi
  jle    L57
  mov    %r8,%rax
L26:
  movss  0x4(%rdi,%rax,8),%xmm1
  comiss %xmm0,%xmm1
  cmova  %eax,%edx
  maxss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L26
  cmp    %ecx,%edx
  jne    L46
  jmp    L24
L57:
  ret
```

assistant: ```c
void ordena(float notas[][2], int N) {
  for (int i = 0; i < N; ++i) {
    float max = notas[i][1];
    int index = i;
    for (int j = i + 1; j < N; ++j) {
      if (notas[j][1] > max) {
        index = j;
        max = notas[j][1];
      }
    }
    if (index != i) {
      do {
        float temp = (notas[i][0]);
        (notas[i][0]) = (notas[index][0]);
        (notas[index][0]) = temp;
      } while (0);
      do {
        float temp = (notas[i][1]);
        (notas[i][1]) = (notas[index][1]);
        (notas[index][1]) = temp;
      } while (0);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ordena>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  movss  -0x4(%rdi,%rcx,8),%xmm0
  mov    %r8d,%edx
  cmp    %ecx,%esi
  jle    L15
  nopl   0x0(%rax)
L10:
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  movss  0x4(%rdi,%rax,8),%xmm1
  comiss %xmm0,%xmm1
  maxss  %xmm0,%xmm1
  cmova  %eax,%edx
  add    $0x1,%rax
  movaps %xmm1,%xmm0
  cmp    %eax,%esi
  jg     L38
  cmp    %r8d,%edx
  je     L3
  movslq %edx,%rdx
  movss  (%rdi,%r8,8),%xmm0
  lea    (%rdi,%rdx,8),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,(%rdi,%r8,8)
  movss  0x4(%rax),%xmm1
  movss  %xmm0,(%rax)
  movss  -0x4(%rdi,%rcx,8),%xmm0
  movss  %xmm1,-0x4(%rdi,%rcx,8)
  movss  %xmm0,0x4(%rax)
L3:
  add    $0x1,%r8
  add    $0x1,%rcx
  movss  -0x4(%rdi,%rcx,8),%xmm0
  mov    %r8d,%edx
  cmp    %ecx,%esi
  jg     L10
L15:
  ret
```

assistant: ```c
void ordena(float notas[][2], int N) {
  for (int i = 0; i < N; ++i) {
    float max = notas[i][1];
    int index = i;
    for (int j = i + 1; j < N; ++j) {
      if (notas[j][1] > max) {
        index = j;
        max = notas[j][1];
      }
    }
    if (index != i) {
      do {
        float temp = (notas[i][0]);
        (notas[i][0]) = (notas[index][0]);
        (notas[index][0]) = temp;
      } while (0);
      do {
        float temp = (notas[i][1]);
        (notas[i][1]) = (notas[index][1]);
        (notas[index][1]) = temp;
      } while (0);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ordena>:
  endbr64
  test   %esi,%esi
  jle    L39
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  movss  -0x4(%rdi,%rcx,8),%xmm0
  mov    %r8d,%edx
  cmp    %ecx,%esi
  jle    L39
  nopl   0x0(%rax)
L28:
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L22:
  movss  0x4(%rdi,%rax,8),%xmm1
  comiss %xmm0,%xmm1
  maxss  %xmm0,%xmm1
  cmova  %eax,%edx
  add    $0x1,%rax
  movaps %xmm1,%xmm0
  cmp    %eax,%esi
  jg     L22
  cmp    %r8d,%edx
  je     L35
  movslq %edx,%rdx
  movss  (%rdi,%r8,8),%xmm0
  lea    (%rdi,%rdx,8),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,(%rdi,%r8,8)
  movss  0x4(%rax),%xmm1
  movss  %xmm0,(%rax)
  movss  -0x4(%rdi,%rcx,8),%xmm0
  movss  %xmm1,-0x4(%rdi,%rcx,8)
  movss  %xmm0,0x4(%rax)
L35:
  add    $0x1,%r8
  add    $0x1,%rcx
  movss  -0x4(%rdi,%rcx,8),%xmm0
  mov    %r8d,%edx
  cmp    %ecx,%esi
  jg     L28
L39:
  ret
```

assistant: ```c
void ordena(float notas[][2], int N) {
  for (int i = 0; i < N; ++i) {
    float max = notas[i][1];
    int index = i;
    for (int j = i + 1; j < N; ++j) {
      if (notas[j][1] > max) {
        index = j;
        max = notas[j][1];
      }
    }
    if (index != i) {
      do {
        float temp = (notas[i][0]);
        (notas[i][0]) = (notas[index][0]);
        (notas[index][0]) = temp;
      } while (0);
      do {
        float temp = (notas[i][1]);
        (notas[i][1]) = (notas[index][1]);
        (notas[index][1]) = temp;
      } while (0);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<digitprocess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,%eax
  mov    %al,-0x424(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  jmp    L11
L6:
  mov    -0x414(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x414(%rbp)
  cltq
  movzbl -0x424(%rbp),%edx
  mov    %dl,-0x410(%rbp,%rax,1)
  mov    $0x0,%eax
  call   <nextChar@plt>
  mov    %al,-0x424(%rbp)
L11:
  movsbl -0x424(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  cmpb   $0x2e,-0x424(%rbp)
  je     L6
  mov    -0x414(%rbp),%eax
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x424(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: (3, "%s")


assistant: ```c
char digitprocess(char ch) {
  char buffer[1024];
  int bufPtr = 0;
  while (isdigit(ch) || '.' == ch) {
    buffer[bufPtr++] = ch;
    ch = nextChar();
  }
  buffer[bufPtr] = '\0';
  printf("(3, \"%s\")\n", buffer);
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<digitprocess>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  jmp    L29
L7:
  mov    %bl,(%rsp,%rbp,1)
  mov    $0x0,%eax
  call   <nextChar@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
L29:
  movsbl %bl,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%bl
  je     L7
  test   %rax,%rax
  jne    L7
  movslq %ebp,%r12
  movb   $0x0,(%rsp,%r12,1)
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    %ebx,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: (3, "%s")


assistant: ```c
char digitprocess(char ch) {
  char buffer[1024];
  int bufPtr = 0;
  while (isdigit(ch) || '.' == ch) {
    buffer[bufPtr++] = ch;
    ch = nextChar();
  }
  buffer[bufPtr] = '\0';
  printf("(3, \"%s\")\n", buffer);
  return ch;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<digitprocess>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L22
  xchg   %ax,%ax
L14:
  xor    %eax,%eax
  mov    %r12b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  call   <nextChar@plt>
  mov    %eax,%r12d
L22:
  movsbl %r12b,%edi
  movslq %ebx,%r13
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L14
  cmp    $0x2e,%r12b
  je     L14
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  movb   $0x0,(%rsp,%r13,1)
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: (3, "%s")


assistant: ```c
char digitprocess(char ch) {
  char buffer[1024];
  int bufPtr = 0;
  while (isdigit(ch) || '.' == ch) {
    buffer[bufPtr++] = ch;
    ch = nextChar();
  }
  buffer[bufPtr] = '\0';
  printf("(3, \"%s\")\n", buffer);
  return ch;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<digitprocess>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L15
  xchg   %ax,%ax
L13:
  xor    %eax,%eax
  mov    %r12b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  call   <nextChar@plt>
  mov    %eax,%r12d
L15:
  movsbl %r12b,%edi
  movslq %ebx,%r13
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  cmp    $0x2e,%r12b
  je     L13
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  movb   $0x0,(%rsp,%r13,1)
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: (3, "%s")


assistant: ```c
char digitprocess(char ch) {
  char buffer[1024];
  int bufPtr = 0;
  while (isdigit(ch) || '.' == ch) {
    buffer[bufPtr++] = ch;
    ch = nextChar();
  }
  buffer[bufPtr] = '\0';
  printf("(3, \"%s\")\n", buffer);
  return ch;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findarg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,%eax
  mov    %al,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movb   $0x0,-0x21(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L33
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x3c(%rbp)
  jne    L32
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L29
L32:
  mov    -0x20(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L17
L33:
  nop
L29:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
char *findarg(char *argbuf, char argtype) {
  char *ptr1;
  char *found = NULL;
  char type = 0;
  size_t size;
  ptr1 = argbuf;
  while (1) {
    memcpy((char *)&size, ptr1, 4);
    if (size == 0) {
      break;
    }
    if (ptr1[4] == argtype) {
      found = &ptr1[5];
      break;
    }
    ptr1 += size;
  }
  return found;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findarg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L32
L34:
  add    %rax,%rbx
L32:
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L9
  cmp    %bpl,0x4(%rbx)
  jne    L34
  lea    0x5(%rbx),%rax
  jmp    L19
L9:
  mov    $0x0,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *findarg(char *argbuf, char argtype) {
  char *ptr1;
  char *found = NULL;
  char type = 0;
  size_t size;
  ptr1 = argbuf;
  while (1) {
    memcpy((char *)&size, ptr1, 4);
    if (size == 0) {
      break;
    }
    if (ptr1[4] == argtype) {
      found = &ptr1[5];
      break;
    }
    ptr1 += size;
  }
  return found;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findarg>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    %bpl,0x4(%rbx)
  je     L37
  add    %rax,%rbx
L49:
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  jne    L0
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L37:
  lea    0x5(%rbx),%rax
  jmp    L4
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *findarg(char *argbuf, char argtype) {
  char *ptr1;
  char *found = NULL;
  char type = 0;
  size_t size;
  ptr1 = argbuf;
  while (1) {
    memcpy((char *)&size, ptr1, 4);
    if (size == 0) {
      break;
    }
    if (ptr1[4] == argtype) {
      found = &ptr1[5];
      break;
    }
    ptr1 += size;
  }
  return found;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findarg>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L3:
  cmp    %bpl,0x4(%rbx)
  je     L5
  add    %rax,%rbx
L15:
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  jne    L3
  xor    %eax,%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L5:
  lea    0x5(%rbx),%rax
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *findarg(char *argbuf, char argtype) {
  char *ptr1;
  char *found = NULL;
  char type = 0;
  size_t size;
  ptr1 = argbuf;
  while (1) {
    memcpy((char *)&size, ptr1, 4);
    if (size == 0) {
      break;
    }
    if (ptr1[4] == argtype) {
      found = &ptr1[5];
      break;
    }
    ptr1 += size;
  }
  return found;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Create_Report>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %edx,-0xb0(%rbp)
  mov    %ecx,-0xb4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xa8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D72(%rip),%rdx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x90(%rbp),%rax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x98(%rbp)
  cmpq   $0x0,-0x98(%rbp)
  jne    L15
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L15:
  mov    -0xa8(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  lea    D39(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0xac(%rbp),%edx
  mov    -0x98(%rbp),%rax
  lea    D67(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0xb0(%rbp),%edx
  mov    -0x98(%rbp),%rax
  lea    D57(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0x98(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x98(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D72
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D55
type_guessed: string
name: disassemble_data
arguments: label: D75
type_guessed: string
name: disassemble_data
arguments: label: D39
type_guessed: string
name: disassemble_data
arguments: label: D67
type_guessed: string
name: disassemble_data
arguments: label: D57
type_guessed: string
name: disassemble_data
arguments: label: D21
type_guessed: string

tool: D72: ./trials

tool: D4: %s/%s/report.txt

tool: D55: w

tool: D75: report file cannot be opened at %s


tool: D39: Seq:     "%s"


tool: D67: Start:   %4d


tool: D57: End:     %4d


tool: D21: MSpF:     %3d


assistant: ```c
FILE *Create_Report(char *SeqName, int Start, int End, int MSpF) {
  char ReportPath[128];
  FILE *Report;
  sprintf(ReportPath, "%s/%s/report.txt", "./trials", SeqName);
  Report = fopen(ReportPath, "w");
  if (Report == NULL) {
    printf("report file cannot be opened at %s\n", ReportPath);
    exit(1);
  }
  fprintf(Report, "Seq:     \"%s\"\n", SeqName);
  fprintf(Report, "Start:   %4d\n", Start);
  fprintf(Report, "End:     %4d\n", End);
  fprintf(Report, "MSpF:     %3d\n", MSpF);
  return (Report);
}
```