ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<simple_strtoull>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <_parse_integer_fixup_radix@plt>
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdx
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <_parse_integer@plt>
  test   %rbp,%rbp
  je     L6
  and    $0x7fffffff,%eax
  add    %rax,%rbx
  mov    %rbx,0x0(%rbp)
L6:
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long simple_strtoull(const char *cp, char **endp, unsigned int base) {
  unsigned long long result;
  unsigned int rv;
  cp = _parse_integer_fixup_radix(cp, &base);
  rv = _parse_integer(cp, base, &result);
  cp += (rv & ~(1U << 31));
  if (endp)
    *endp = (char *)cp;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string

tool: D0: list is: 

tool: D18: %d, 

assistant: ```c
void printList(int data[], int len) {
  printf("list is: ");
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%d, ", data[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printList>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L8
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D6(%rip),%rbp
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D11: list is: 

tool: D6: %d, 

assistant: ```c
void printList(int data[], int len) {
  printf("list is: ");
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%d, ", data[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printList>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D18(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L3
  lea    -0x1(%rbp),%eax
  lea    D7(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L3:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D18: list is: 

tool: D7: %d, 

assistant: ```c
void printList(int data[], int len) {
  printf("list is: ");
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%d, ", data[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printList>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D17(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L5
  lea    -0x1(%rbp),%eax
  lea    D18(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
L5:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D17: list is: 

tool: D18: %d, 

assistant: ```c
void printList(int data[], int len) {
  printf("list is: ");
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%d, ", data[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L10
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *tmp;
  if ((tmp = malloc(size)) == NULL)
    return (NULL);
  ft_bzero(tmp, size);
  return (tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *tmp;
  if ((tmp = malloc(size)) == NULL)
    return (NULL);
  ft_bzero(tmp, size);
  return (tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_memalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *tmp;
  if ((tmp = malloc(size)) == NULL)
    return (NULL);
  ft_bzero(tmp, size);
  return (tmp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_memalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *tmp;
  if ((tmp = malloc(size)) == NULL)
    return (NULL);
  ft_bzero(tmp, size);
  return (tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<p_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x28,%edx
  lea    D37(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ns_format_ttl@plt>
  test   %rax,%rax
  jns    L4
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
L4:
  lea    D37(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
datatype: string

tool: D24: %u

assistant: ```c
const char *p_time(u_int32_t value) {
  static char nbuf[40];
  if (ns_format_ttl(value, nbuf, sizeof nbuf) < 0)
    sprintf(nbuf, "%u", value);
  return (nbuf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<p_time>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x28,%edx
  lea    D8(%rip),%rsi
  call   <ns_format_ttl@plt>
  test   %rax,%rax
  js     L10
L9:
  lea    D8(%rip),%rax
  pop    %rbx
  ret
L10:
  mov    %ebx,%edx
  lea    D15(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <sprintf@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type: string

tool: D15: %u

assistant: ```c
const char *p_time(u_int32_t value) {
  static char nbuf[40];
  if (ns_format_ttl(value, nbuf, sizeof nbuf) < 0)
    sprintf(nbuf, "%u", value);
  return (nbuf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<p_time>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  mov    $0x28,%edx
  push   %r12
  mov    %r13,%rsi
  mov    %edi,%r12d
  sub    $0x8,%rsp
  call   <ns_format_ttl@plt>
  test   %rax,%rax
  js     L2
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  mov    %r12d,%edx
  mov    %r13,%rdi
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %u

assistant: ```c
const char *p_time(u_int32_t value) {
  static char nbuf[40];
  if (ns_format_ttl(value, nbuf, sizeof nbuf) < 0)
    sprintf(nbuf, "%u", value);
  return (nbuf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<p_time>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  mov    $0x28,%edx
  push   %r12
  mov    %r13,%rsi
  mov    %edi,%r12d
  sub    $0x8,%rsp
  call   <ns_format_ttl@plt>
  test   %rax,%rax
  js     L0
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  mov    %r12d,%edx
  mov    %r13,%rdi
  lea    D17(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string

tool: D17: %u

assistant: ```c
const char *p_time(u_int32_t value) {
  static char nbuf[40];
  if (ns_format_ttl(value, nbuf, sizeof nbuf) < 0)
    sprintf(nbuf, "%u", value);
  return (nbuf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x_putint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
bool_t x_putint32(XDR *xdrs, const int32_t *int32p) {
  xdrs->x_handy += BYTES_PER_XDR_UNIT;
  return TRUE;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<x_putint32>:
  endbr64
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  add    %eax,(%rdi)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t x_putint32(XDR *xdrs, const int32_t *int32p) {
  xdrs->x_handy += BYTES_PER_XDR_UNIT;
  return TRUE;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x_putint32>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  add    %eax,(%rdi)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t x_putint32(XDR *xdrs, const int32_t *int32p) {
  xdrs->x_handy += BYTES_PER_XDR_UNIT;
  return TRUE;
}
```
user: Translate the below assembly code into C programming language:

```asm
<x_putint32>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  add    %eax,(%rdi)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
bool_t x_putint32(XDR *xdrs, const int32_t *int32p) {
  xdrs->x_handy += BYTES_PER_XDR_UNIT;
  return TRUE;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crypto_scalarmult_curve25519>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1c8(%rbp)
  mov    %rsi,-0x1d0(%rbp)
  mov    %rdx,-0x1d8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1b4(%rbp)
  jmp    L34
L17:
  mov    -0x1b4(%rbp),%edx
  mov    -0x1d0(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1b4(%rbp),%eax
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x1b4(%rbp)
L34:
  cmpl   $0x1f,-0x1b4(%rbp)
  jbe    L17
  movzbl -0x30(%rbp),%eax
  and    $0xfffffff8,%eax
  mov    %al,-0x30(%rbp)
  movzbl -0x11(%rbp),%eax
  and    $0x7f,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  or     $0x40,%eax
  mov    %al,-0x11(%rbp)
  movl   $0x0,-0x1b4(%rbp)
  jmp    L58
L61:
  mov    -0x1b4(%rbp),%edx
  mov    -0x1d8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1b4(%rbp),%eax
  mov    %edx,-0x1b0(%rbp,%rax,4)
  addl   $0x1,-0x1b4(%rbp)
L58:
  cmpl   $0x1f,-0x1b4(%rbp)
  jbe    L61
  lea    -0x30(%rbp),%rdx
  lea    -0x1b0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mainloop@plt>
  lea    -0x1b0(%rbp),%rdx
  sub    $0xffffffffffffff80,%rdx
  lea    -0x1b0(%rbp),%rax
  sub    $0xffffffffffffff80,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <recip@plt>
  lea    -0x1b0(%rbp),%rdx
  sub    $0xffffffffffffff80,%rdx
  lea    -0x1b0(%rbp),%rax
  add    $0x100,%rax
  lea    -0x1b0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mult@plt>
  lea    -0x1b0(%rbp),%rax
  add    $0x100,%rax
  mov    %rax,%rdi
  call   <freeze@plt>
  movl   $0x0,-0x1b4(%rbp)
  jmp    L64
L49:
  mov    -0x1b4(%rbp),%eax
  add    $0x40,%eax
  mov    %eax,%eax
  mov    -0x1b0(%rbp,%rax,4),%edx
  mov    -0x1b4(%rbp),%ecx
  mov    -0x1c8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x1b4(%rbp)
L64:
  cmpl   $0x1f,-0x1b4(%rbp)
  jbe    L49
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
int crypto_scalarmult_curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  unsigned int work[96];
  unsigned char e[32];
  unsigned int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  for (i = 0; i < 32; ++i)
    work[i] = p[i];
  mainloop(work, e);
  recip(work + 32, work + 32);
  mult(work + 64, work, work + 32);
  freeze(work + 64);
  for (i = 0; i < 32; ++i)
    q[i] = work[64 + i];
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crypto_scalarmult_curve25519>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
L24:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x180(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L24
  andb   $0xf8,0x180(%rsp)
  movzbl 0x19f(%rsp),%eax
  and    $0x7f,%eax
  or     $0x40,%eax
  mov    %al,0x19f(%rsp)
  mov    $0x0,%eax
L22:
  movzbl (%rdx,%rax,1),%ecx
  mov    %ecx,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L22
  lea    0x180(%rsp),%rsi
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <mainloop@plt>
  lea    0x80(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <recip@plt>
  lea    0x100(%rsp),%r12
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mult@plt>
  mov    %r12,%rdi
  call   <freeze@plt>
  mov    $0x0,%eax
L2:
  mov    0x100(%rsp,%rax,4),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L2
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_scalarmult_curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  unsigned int work[96];
  unsigned char e[32];
  unsigned int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  for (i = 0; i < 32; ++i)
    work[i] = p[i];
  mainloop(work, e);
  recip(work + 32, work + 32);
  mult(work + 64, work, work + 32);
  freeze(work + 64);
  for (i = 0; i < 32; ++i)
    q[i] = work[64 + i];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crypto_scalarmult_curve25519>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x1b8,%rsp
  movdqu 0x10(%rsi),%xmm1
  movdqu (%rsi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm1,0x190(%rsp)
  movzbl 0x19f(%rsp),%eax
  movaps %xmm0,0x180(%rsp)
  andb   $0xf8,0x180(%rsp)
  and    $0x7f,%eax
  or     $0x40,%eax
  mov    %al,0x19f(%rsp)
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%rdx,%rax,1),%ecx
  mov    %ecx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L5
  lea    0x80(%rsp),%r12
  lea    0x180(%rsp),%rsi
  mov    %rbx,%rdi
  call   <mainloop@plt>
  lea    0x100(%rsp),%r13
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <recip@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <mult@plt>
  mov    %r13,%rdi
  call   <freeze@plt>
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  mov    0x100(%rbx,%rax,4),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L26
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_scalarmult_curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  unsigned int work[96];
  unsigned char e[32];
  unsigned int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  for (i = 0; i < 32; ++i)
    work[i] = p[i];
  mainloop(work, e);
  recip(work + 32, work + 32);
  mult(work + 64, work, work + 32);
  freeze(work + 64);
  for (i = 0; i < 32; ++i)
    q[i] = work[64 + i];
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MyGemm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L21:
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L25:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L5:
  mov    -0xc(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  imul   0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  addl   $0x1,-0x8(%rbp)
L57:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j++)
    for (int p = 0; p < k; p++)
      for (int i = 0; i < m; i++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,-0x14(%rsp)
  test   %esi,%esi
  jle    L74
  mov    %edi,%r10d
  mov    %edx,%r12d
  mov    %rcx,%rbp
  mov    %r8d,%r11d
  mov    %r9,%r13
  mov    %edx,%r9d
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    -0x1(%rdi),%eax
  mov    %rax,-0x10(%rsp)
  mov    0x40(%rsp),%rax
  add    $0x8,%rax
  mov    %rax,-0x8(%rsp)
  jmp    L9
L14:
  movslq %edi,%rax
  lea    0x0(%r13,%rax,8),%rcx
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,8),%rdx
  mov    %rbx,%rax
L77:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  jne    L77
L66:
  add    %r11d,%r8d
  add    $0x1,%edi
  cmp    %r9d,%edi
  je     L28
L64:
  test   %r10d,%r10d
  jg     L14
  jmp    L66
L28:
  add    $0x1,%r14d
  add    0x38(%rsp),%r9d
  add    0x48(%rsp),%r15d
  cmp    %r14d,-0x14(%rsp)
  je     L74
L9:
  test   %r12d,%r12d
  jle    L28
  mov    %r9d,%edi
  sub    %r12d,%edi
  movslq %r15d,%rax
  mov    0x40(%rsp),%rbx
  lea    (%rbx,%rax,8),%rbx
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rcx
  lea    (%rcx,%rax,8),%rsi
  mov    $0x0,%r8d
  jmp    L64
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j++)
    for (int p = 0; p < k; p++)
      for (int i = 0; i < m; i++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,-0x14(%rsp)
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rdi),%eax
  mov    %r9,%r13
  mov    %edi,%r10d
  mov    %edx,%r12d
  mov    %rax,-0x10(%rsp)
  mov    0x40(%rsp),%rax
  mov    %rcx,%rbp
  mov    %r8d,%r11d
  mov    %edx,%r9d
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  add    $0x8,%rax
  mov    %rax,-0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L44:
  test   %r12d,%r12d
  jle    L57
  mov    0x40(%rsp),%rbx
  movslq %r15d,%rax
  mov    -0x8(%rsp),%rcx
  mov    %r9d,%edi
  sub    %r12d,%edi
  xor    %r8d,%r8d
  lea    (%rbx,%rax,8),%rbx
  add    -0x10(%rsp),%rax
  lea    (%rcx,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L6:
  test   %r10d,%r10d
  jle    L21
  movslq %edi,%rax
  lea    0x0(%r13,%rax,8),%rcx
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,8),%rdx
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L32:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    $0x8,%rdx
  addsd  -0x8(%rax),%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L32
L21:
  add    $0x1,%edi
  add    %r11d,%r8d
  cmp    %r9d,%edi
  jne    L6
L57:
  add    $0x1,%r14d
  add    0x38(%rsp),%r9d
  add    0x48(%rsp),%r15d
  cmp    %r14d,-0x14(%rsp)
  jne    L44
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int j = 0; j < n; j++)
    for (int p = 0; p < k; p++)
      for (int i = 0; i < m; i++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```