user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shr    $0x3,%rax
  or     $0xffffffb5,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L2
L75:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L68
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L71
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L64
L71:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L64
L68:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L15
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  movzbl -0xa(%rbp),%eax
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L64
L15:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  and    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L64:
  addb   $0x2,-0xa(%rbp)
L2:
  cmpb   $0x0,-0xa(%rbp)
  je     L75
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shr    $0x5,%rax
  or     $0x7f,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned char)7) | 1UL);
          state[local1] = state[0UL] << (((state[local1] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        } else {
          state[local1] |= state[0UL];
          state[local1] = state[0UL] | state[local1];
        }
      } else if (state[0UL] < local1) {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL);
        state[local1] |= state[0UL];
      } else {
        state[local1] &= state[0UL];
        state[local1] |= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] | 116928511UL) >> (unsigned char)5;
  }
}
```