ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_min>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %ecx,%edi
  push   %rbp
  sub    %edx,%edi
  push   %rbx
  sub    $0x8,%rsp
  add    $0x1,%edi
  js     L3
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%ebx
  call   <log2@plt>
  mov    %ebp,%esi
  imul   %eax,%esi
  sub    %eax,%ebx
  add    %esi,%ebx
  add    %r13d,%esi
  movslq %ebx,%rbx
  movslq %esi,%rsi
  mov    (%r12,%rbx,4),%eax
  mov    (%r12,%rsi,4),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_min(int *B, int N, int a, int b) {
  int d = b - a + 1;
  if (d < 0)
    return INT_MAX;
  int k = log2(d);
  return B[a + k * N] < B[b - k + k * N] ? B[a + k * N] : B[b - k + k * N];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_min>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %ecx,%edi
  push   %rbp
  sub    %edx,%edi
  push   %rbx
  sub    $0x8,%rsp
  add    $0x1,%edi
  js     L6
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %ecx,%ebx
  call   <log2@plt>
  mov    %ebp,%esi
  imul   %eax,%esi
  sub    %eax,%ebx
  add    %esi,%ebx
  add    %r13d,%esi
  movslq %ebx,%rbx
  movslq %esi,%rsi
  mov    (%r12,%rbx,4),%eax
  mov    (%r12,%rsi,4),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_min(int *B, int N, int a, int b) {
  int d = b - a + 1;
  if (d < 0)
    return INT_MAX;
  int k = log2(d);
  return B[a + k * N] < B[b - k + k * N] ? B[a + k * N] : B[b - k + k * N];
}
```
user: Translate the below assembly code into C programming language:

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <getLimInt@plt>
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: 1- List all items
2- Search for an item
3- Sort Items
0- Exit program
> 

assistant: ```c
int menu() {
  printf("1- List all items\n"
         "2- Search for an item\n"
         "3- Sort Items\n"
         "0- Exit program\n> ");
  return getLimInt(0, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <getLimInt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: 1- List all items
2- Search for an item
3- Sort Items
0- Exit program
> 

assistant: ```c
int menu() {
  printf("1- List all items\n"
         "2- Search for an item\n"
         "3- Sort Items\n"
         "0- Exit program\n> ");
  return getLimInt(0, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <getLimInt@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: 1- List all items
2- Search for an item
3- Sort Items
0- Exit program
> 

assistant: ```c
int menu() {
  printf("1- List all items\n"
         "2- Search for an item\n"
         "3- Sort Items\n"
         "0- Exit program\n> ");
  return getLimInt(0, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <getLimInt@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: 1- List all items
2- Search for an item
3- Sort Items
0- Exit program
> 

assistant: ```c
int menu() {
  printf("1- List all items\n"
         "2- Search for an item\n"
         "3- Sort Items\n"
         "0- Exit program\n> ");
  return getLimInt(0, 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<hashFunction_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hashFunction_2@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x7d00,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
int hashFunction_3(char a[20]) {
  srand(hashFunction_2(a));
  return rand() % 32000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hashFunction_3>:
  endbr64
  sub    $0x8,%rsp
  call   <hashFunction_2@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x10624dd3,%rax,%rax
  sar    $0x2b,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x7d00,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int hashFunction_3(char a[20]) {
  srand(hashFunction_2(a));
  return rand() % 32000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashFunction_3>:
  endbr64
  sub    $0x8,%rsp
  call   <hashFunction_2@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x10624dd3,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x2b,%rax
  sub    %ecx,%eax
  imul   $0x7d00,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int hashFunction_3(char a[20]) {
  srand(hashFunction_2(a));
  return rand() % 32000;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hashFunction_3>:
  endbr64
  sub    $0x8,%rsp
  call   <hashFunction_2@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x10624dd3,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x2b,%rax
  sub    %ecx,%eax
  imul   $0x7d00,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int hashFunction_3(char a[20]) {
  srand(hashFunction_2(a));
  return rand() % 32000;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<x11_create_win>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  mov    0x38(%rbp),%eax
  mov    %eax,%edi
  call   <count_bits@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  or     $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x28(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x34(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x3c(%rbp),%eax
  shl    $0x10,%eax
  mov    -0x8(%rbp),%rdx
  add    $0xc,%rdx
  or     -0x38(%rbp),%eax
  mov    %eax,(%rdx)
  mov    0x18(%rbp),%eax
  shl    $0x10,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x10,%rdx
  or     0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    0x20(%rbp),%eax
  shl    $0x10,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x14,%rdx
  or     0x28(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    0x30(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1c(%rax),%rdx
  mov    0x38(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L5:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    $0x8,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L5
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0xc(%rbp),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <sbrk@plt>
  nop
  leave
  ret
```

assistant: ```c
void x11_create_win(int sock, struct x11_connection *conn, uint32_t id, uint32_t parent, uint16_t x, uint16_t y, uint16_t w, uint16_t h, uint16_t border, uint16_t group, uint32_t visual, uint32_t flags, uint32_t *list) {
  uint16_t flag_count = count_bits(flags);
  uint16_t length = 8 + flag_count;
  uint32_t *packet = sbrk(length * 4);
  packet[0] = 0x01 | length << 16;
  packet[1] = id;
  packet[2] = parent;
  packet[3] = x | y << 16;
  packet[4] = w | h << 16;
  packet[5] = border << 16 | group;
  packet[6] = visual;
  packet[7] = flags;
  int i;
  for (i = 0; i < flag_count; i++)
    packet[8 + i] = list[i];
  write(sock, packet, length * 4);
  sbrk(-(length * 4));
  return;
  (void)conn;
}
```
user: Translate the below assembly code into C programming language:

```asm
<x11_create_win>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  mov    %edx,%r15d
  mov    %ecx,%r14d
  mov    %r8d,0x8(%rsp)
  mov    %r9d,0xc(%rsp)
  mov    0x80(%rsp),%rbp
  mov    0x78(%rsp),%edi
  call   <count_bits@plt>
  mov    %eax,%ebx
  lea    0x8(%rax),%r12d
  lea    0x0(,%r12,4),%r13d
  mov    %r13d,%edi
  call   <sbrk@plt>
  mov    %rax,%rsi
  shl    $0x10,%r12d
  or     $0x1,%r12d
  mov    %r12d,(%rax)
  mov    %r15d,0x4(%rax)
  mov    %r14d,0x8(%rax)
  mov    0xc(%rsp),%eax
  shl    $0x10,%eax
  or     0x8(%rsp),%eax
  mov    %eax,0xc(%rsi)
  mov    0x58(%rsp),%eax
  shl    $0x10,%eax
  or     0x50(%rsp),%eax
  mov    %eax,0x10(%rsi)
  mov    0x60(%rsp),%eax
  shl    $0x10,%eax
  or     0x68(%rsp),%eax
  mov    %eax,0x14(%rsi)
  mov    0x70(%rsp),%eax
  mov    %eax,0x18(%rsi)
  mov    0x78(%rsp),%eax
  mov    %eax,0x1c(%rsi)
  test   %ebx,%ebx
  jle    L17
  mov    %ebx,%ebx
  mov    $0x0,%eax
L12:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,0x20(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L12
L17:
  mov    %r13d,%edx
  mov    0x4(%rsp),%edi
  call   <write@plt>
  mov    %r13d,%edi
  neg    %edi
  call   <sbrk@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void x11_create_win(int sock, struct x11_connection *conn, uint32_t id, uint32_t parent, uint16_t x, uint16_t y, uint16_t w, uint16_t h, uint16_t border, uint16_t group, uint32_t visual, uint32_t flags, uint32_t *list) {
  uint16_t flag_count = count_bits(flags);
  uint16_t length = 8 + flag_count;
  uint32_t *packet = sbrk(length * 4);
  packet[0] = 0x01 | length << 16;
  packet[1] = id;
  packet[2] = parent;
  packet[3] = x | y << 16;
  packet[4] = w | h << 16;
  packet[5] = border << 16 | group;
  packet[6] = visual;
  packet[7] = flags;
  int i;
  for (i = 0; i < flag_count; i++)
    packet[8 + i] = list[i];
  write(sock, packet, length * 4);
  sbrk(-(length * 4));
  return;
  (void)conn;
}
```
user: What is the c source code of the assembly code below?

```asm
<x11_create_win>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  shl    $0x10,%r12d
  push   %rbx
  sub    $0x38,%rsp
  mov    0x70(%rsp),%eax
  mov    0x90(%rsp),%r9d
  mov    %r8d,0xc(%rsp)
  mov    0x98(%rsp),%r8d
  mov    0x78(%rsp),%r13d
  mov    %ecx,0x28(%rsp)
  mov    %eax,0x10(%rsp)
  mov    0x88(%rsp),%ecx
  mov    0x80(%rsp),%eax
  mov    %r8d,%edi
  mov    %edx,0x2c(%rsp)
  shl    $0x10,%r13d
  mov    %ecx,0x18(%rsp)
  mov    0xa0(%rsp),%rbp
  mov    %r9d,0x24(%rsp)
  mov    %r8d,0x20(%rsp)
  mov    %eax,0x14(%rsp)
  call   <count_bits@plt>
  movslq %eax,%rbx
  lea    0x8(%rbx),%edx
  lea    0x0(,%rdx,4),%r14d
  mov    %edx,0x1c(%rsp)
  mov    %r14d,%edi
  call   <sbrk@plt>
  mov    0x1c(%rsp),%edx
  mov    0x2c(%rsp),%r10d
  mov    0x28(%rsp),%ecx
  or     0xc(%rsp),%r12d
  mov    %rax,%rsi
  shl    $0x10,%edx
  or     0x10(%rsp),%r13d
  mov    %r10d,0x4(%rax)
  or     $0x1,%edx
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    %ecx,0x8(%rax)
  mov    %edx,(%rax)
  mov    %r12d,0xc(%rax)
  mov    %r13d,0x10(%rax)
  mov    0x14(%rsp),%eax
  mov    %r9d,0x18(%rsi)
  shl    $0x10,%eax
  or     0x18(%rsp),%eax
  mov    %r8d,0x1c(%rsi)
  mov    %eax,0x14(%rsi)
  test   %ebx,%ebx
  jle    L17
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %edx,0x20(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L11
L17:
  mov    %r15d,%edi
  mov    %r14d,%edx
  call   <write@plt>
  add    $0x38,%rsp
  mov    %r14d,%edi
  pop    %rbx
  neg    %edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <sbrk@plt>
```

assistant: ```c
void x11_create_win(int sock, struct x11_connection *conn, uint32_t id, uint32_t parent, uint16_t x, uint16_t y, uint16_t w, uint16_t h, uint16_t border, uint16_t group, uint32_t visual, uint32_t flags, uint32_t *list) {
  uint16_t flag_count = count_bits(flags);
  uint16_t length = 8 + flag_count;
  uint32_t *packet = sbrk(length * 4);
  packet[0] = 0x01 | length << 16;
  packet[1] = id;
  packet[2] = parent;
  packet[3] = x | y << 16;
  packet[4] = w | h << 16;
  packet[5] = border << 16 | group;
  packet[6] = visual;
  packet[7] = flags;
  int i;
  for (i = 0; i < flag_count; i++)
    packet[8 + i] = list[i];
  write(sock, packet, length * 4);
  sbrk(-(length * 4));
  return;
  (void)conn;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x18(%rbp)
  jmp    L25
L8:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <fiber_yield@plt>
  addl   $0x1,-0x18(%rbp)
L25:
  cmpl   $0x63,-0x18(%rbp)
  jle    L8
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void fib(void) {
  int i;
  int fib[2] = {0, 1};
  for (i = 2; i < 100; i++) {
    int next = fib[0] + fib[1];
    fib[0] = fib[1];
    fib[1] = next;
    fiber_yield();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fib>:
  endbr64
  push   %rbx
  mov    $0x62,%ebx
L7:
  mov    $0x0,%eax
  call   <fiber_yield@plt>
  sub    $0x1,%ebx
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void fib(void) {
  int i;
  int fib[2] = {0, 1};
  for (i = 2; i < 100; i++) {
    int next = fib[0] + fib[1];
    fib[0] = fib[1];
    fib[1] = next;
    fiber_yield();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fib>:
  endbr64
  push   %rbx
  mov    $0x62,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <fiber_yield@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void fib(void) {
  int i;
  int fib[2] = {0, 1};
  for (i = 2; i < 100; i++) {
    int next = fib[0] + fib[1];
    fib[0] = fib[1];
    fib[1] = next;
    fiber_yield();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fib>:
  endbr64
  push   %rbx
  mov    $0x62,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <fiber_yield@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void fib(void) {
  int i;
  int fib[2] = {0, 1};
  for (i = 2; i < 100; i++) {
    int next = fib[0] + fib[1];
    fib[0] = fib[1];
    fib[1] = next;
    fiber_yield();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x61,-0x12(%rbp)
  movb   $0x30,-0x11(%rbp)
  movb   $0x63,-0x10(%rbp)
  movb   $0x0,-0xf(%rbp)
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x30,-0x24(%rbp)
  mov    -0x24(%rbp),%edi
  mov    -0x24(%rbp),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  add    $0x5,%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%esi
  lea    -0x12(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %esi,%r9d
  mov    %rcx,%r8
  mov    $0x31,%ecx
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x24(%rbp),%esi
  lea    -0x12(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r9d
  mov    %rcx,%r8
  mov    $0x31,%ecx
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_infered: string
name: unpack_data
arguments: data_tag: D42
type_infered: string
name: unpack_data
arguments: data_tag: D33
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D11: abcdefg0123

tool: D42: 
s=%s , s1=%s, code0=%0x %d %c


tool: D33: 
s=%s , s1=%s, code0=%0x %ld %c


tool: D10: &s1=%ld s1=%s, code0=%0x %ld %c


tool: D6: s1=%s s=%s

assistant: ```c
void main(int argc, char **argv) {
  char s[10];
  s[0] = 'a';
  *(s + 1) = '0';
  s[2] = 'c';
  s[3] = 0;
  char *s1 = malloc(15);
  strcpy(s1, "abcdefg0123");
  int code0 = '0';
  printf("\ns=%s , s1=%s, code0=%0x %d %c\n", s, s1, code0, code0, code0);
  s1[5] = 0;
  printf("\ns=%s , s1=%s, code0=%0x %ld %c\n", s, s1, '1', s, code0);
  printf("&s1=%ld s1=%s, code0=%0x %ld %c\n", s1, s1 + 6, '1', s, code0);
  s1 = s;
  printf("s1=%s s=%s");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x61,0xe(%rsp)
  movb   $0x30,0xf(%rsp)
  movb   $0x63,0x10(%rsp)
  movb   $0x0,0x11(%rsp)
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D32(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xe(%rsp),%rbp
  mov    $0x30,%r9d
  mov    $0x30,%r8d
  mov    $0x30,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x0,0x5(%rbx)
  mov    $0x30,%r9d
  mov    %rbp,%r8
  mov    $0x31,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x6(%rbx),%rdx
  mov    $0x30,%r9d
  mov    %rbp,%r8
  mov    $0x31,%ecx
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D32
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D40
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D32: abcdefg0123

tool: D4: 
s=%s , s1=%s, code0=%0x %d %c


tool: D39: 
s=%s , s1=%s, code0=%0x %ld %c


tool: D40: &s1=%ld s1=%s, code0=%0x %ld %c


tool: D9: s1=%s s=%s

assistant: ```c
void main(int argc, char **argv) {
  char s[10];
  s[0] = 'a';
  *(s + 1) = '0';
  s[2] = 'c';
  s[3] = 0;
  char *s1 = malloc(15);
  strcpy(s1, "abcdefg0123");
  int code0 = '0';
  printf("\ns=%s , s1=%s, code0=%0x %d %c\n", s, s1, code0, code0, code0);
  s1[5] = 0;
  printf("\ns=%s , s1=%s, code0=%0x %ld %c\n", s, s1, '1', s, code0);
  printf("&s1=%ld s1=%s, code0=%0x %ld %c\n", s1, s1 + 6, '1', s, code0);
  s1 = s;
  printf("s1=%s s=%s");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xf,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x633061,0xe(%rsp)
  lea    0xe(%rsp),%rbx
  call   <malloc@plt>
  lea    D40(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x30,%r9d
  mov    %rbp,%rdx
  xor    %eax,%eax
  mov    $0x30,%r8d
  mov    $0x30,%ecx
  mov    %rbx,%rsi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  movb   $0x0,0x5(%rbp)
  mov    %rbx,%r8
  mov    %rbp,%rdx
  mov    $0x30,%r9d
  mov    $0x31,%ecx
  mov    %rbx,%rsi
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x6(%rbp),%rdx
  mov    %rbx,%r8
  lea    D12(%rip),%rdi
  mov    $0x30,%r9d
  mov    $0x31,%ecx
  mov    %rbp,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D40
type: string
name: unpack_data
arguments: tag: D44
type: string
name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D29
type: string

tool: D40: abcdefg0123

tool: D44: 
s=%s , s1=%s, code0=%0x %d %c


tool: D35: 
s=%s , s1=%s, code0=%0x %ld %c


tool: D12: &s1=%ld s1=%s, code0=%0x %ld %c


tool: D29: s1=%s s=%s

assistant: ```c
void main(int argc, char **argv) {
  char s[10];
  s[0] = 'a';
  *(s + 1) = '0';
  s[2] = 'c';
  s[3] = 0;
  char *s1 = malloc(15);
  strcpy(s1, "abcdefg0123");
  int code0 = '0';
  printf("\ns=%s , s1=%s, code0=%0x %d %c\n", s, s1, code0, code0, code0);
  s1[5] = 0;
  printf("\ns=%s , s1=%s, code0=%0x %ld %c\n", s, s1, '1', s, code0);
  printf("&s1=%ld s1=%s, code0=%0x %ld %c\n", s1, s1 + 6, '1', s, code0);
  s1 = s;
  printf("s1=%s s=%s");
}
```