ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x8,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L64
L77:
  cmpl   $0xa,-0x4(%rbp)
  jne    L86
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L86:
  cmpl   $0x20,-0x4(%rbp)
  jne    L59
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L64
  mov    $0x9,%edi
  call   <putchar@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L59:
  cmpl   $0x0,-0x10(%rbp)
  jle    L47
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L41:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L41
  movl   $0x0,-0x10(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L64:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L77
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int c;
  int col = 0;
  int tab = 8;
  int sp = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n') {
      putchar(c);
      col = 0;
    } else if (c == ' ') {
      sp++;
      if ((col + sp) % tab == 0) {
        putchar('\t');
        sp = 0;
        col = 0;
      }
    } else {
      if (sp > 0) {
        for (int i = 0; i < sp; i++) {
          putchar(' ');
          col++;
        }
        sp = 0;
      }
      putchar(c);
      col++;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L32
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%r13d
  jmp    L32
L24:
  add    $0x1,%r12d
  lea    0x0(%r13,%r12,1),%eax
  test   $0x7,%al
  jne    L32
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L32
L61:
  mov    %ebx,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
L32:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D0(%rip),%rax
  cmp    %ebx,(%rax)
  je     L56
  cmp    $0xa,%ebx
  je     L1
  cmp    $0x20,%ebx
  je     L24
  test   %r12d,%r12d
  jle    L61
  mov    $0x0,%ebp
L43:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jne    L43
  add    %r12d,%r13d
  mov    $0x0,%r12d
  jmp    L61
L56:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(void) {
  int c;
  int col = 0;
  int tab = 8;
  int sp = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n') {
      putchar(c);
      col = 0;
    } else if (c == ' ') {
      sp++;
      if ((col + sp) % tab == 0) {
        putchar('\t');
        sp = 0;
        col = 0;
      }
    } else {
      if (sp > 0) {
        for (int i = 0; i < sp; i++) {
          putchar(' ');
          col++;
        }
        sp = 0;
      }
      putchar(c);
      col++;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    D8(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
L70:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  je     L16
L80:
  cmp    $0xa,%ebp
  je     L12
  cmp    $0x20,%ebp
  je     L74
  test   %r12d,%r12d
  jne    L64
L38:
  mov    %ebp,%edi
  add    $0x1,%r13d
  xor    %r12d,%r12d
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L80
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L74:
  add    $0x1,%r12d
  lea    0x0(%r13,%r12,1),%eax
  test   $0x7,%al
  jne    L70
  mov    $0x9,%edi
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  call   <putchar@plt>
  jmp    L70
  nop
L12:
  mov    $0xa,%edi
  xor    %r13d,%r13d
  call   <putchar@plt>
  jmp    L70
  nop
L64:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L58:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L58
  add    %r12d,%r13d
  jmp    L38
```

assistant: ```c
int main(void) {
  int c;
  int col = 0;
  int tab = 8;
  int sp = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n') {
      putchar(c);
      col = 0;
    } else if (c == ' ') {
      sp++;
      if ((col + sp) % tab == 0) {
        putchar('\t');
        sp = 0;
        col = 0;
      }
    } else {
      if (sp > 0) {
        for (int i = 0; i < sp; i++) {
          putchar(' ');
          col++;
        }
        sp = 0;
      }
      putchar(c);
      col++;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    D9(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  je     L88
L56:
  cmp    $0xa,%ebp
  je     L39
  cmp    $0x20,%ebp
  je     L81
  test   %r12d,%r12d
  jne    L4
L28:
  mov    %ebp,%edi
  add    $0x1,%r13d
  xor    %r12d,%r12d
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%r14)
  jne    L56
L88:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L81:
  add    $0x1,%r12d
  lea    0x0(%r13,%r12,1),%eax
  test   $0x7,%al
  jne    L2
  mov    $0x9,%edi
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  call   <putchar@plt>
  jmp    L2
  nop
L39:
  mov    $0xa,%edi
  xor    %r13d,%r13d
  call   <putchar@plt>
  jmp    L2
  nop
L4:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L76:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L76
  add    %r12d,%r13d
  jmp    L28
```

assistant: ```c
int main(void) {
  int c;
  int col = 0;
  int tab = 8;
  int sp = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\n') {
      putchar(c);
      col = 0;
    } else if (c == ' ') {
      sp++;
      if ((col + sp) % tab == 0) {
        putchar('\t');
        sp = 0;
        col = 0;
      }
    } else {
      if (sp > 0) {
        for (int i = 0; i < sp; i++) {
          putchar(' ');
          col++;
        }
        sp = 0;
      }
      putchar(c);
      col++;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L86:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L86
  subq   $0x2,-0x28(%rbp)
  cmpq   $0x3,-0x38(%rbp)
  jbe    L19
  mov    -0x38(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x10(%rbp)
L64:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x11(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  jmp    L152
L11:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x11(%rbp)
  jne    L77
  mov    -0x8(%rbp),%rax
  jmp    L152
L77:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x11(%rbp)
  jne    L34
  mov    -0x8(%rbp),%rax
  jmp    L152
L34:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x11(%rbp)
  jne    L126
  mov    -0x8(%rbp),%rax
  jmp    L152
L126:
  subq   $0x1,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L64
  andq   $0x3,-0x38(%rbp)
  jmp    L19
L44:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x11(%rbp)
  jne    L93
  mov    -0x8(%rbp),%rax
  jmp    L152
L93:
  subq   $0x1,-0x38(%rbp)
L19:
  cmpq   $0x0,-0x38(%rbp)
  jne    L44
  cmpb   $0x0,-0x11(%rbp)
  je     L97
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
L97:
  mov    -0x8(%rbp),%rax
L152:
  pop    %rbp
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char c;
  char *s = s1;
  do
    c = *s1++;
  while (c != '\0');
  s1 -= 2;
  if (n >= 4) {
    size_t n4 = n >> 2;
    do {
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
    } while (--n4 > 0);
    n &= 3;
  }
  while (n > 0) {
    c = *s2++;
    *++s1 = c;
    if (c == '\0')
      return s;
    n--;
  }
  if (c != '\0')
    *++s1 = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncat>:
  endbr64
  mov    %rsi,%rax
  mov    %rdx,%r8
  mov    %rdi,%rdx
L96:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L96
  lea    -0x1(%rcx),%rdx
  cmp    $0x3,%r8
  jbe    L77
  mov    %r8,%rsi
  and    $0xfffffffffffffffc,%rsi
  lea    -0x1(%rcx,%rsi,1),%rsi
L32:
  movzbl (%rax),%ecx
  mov    %cl,0x1(%rdx)
  test   %cl,%cl
  je     L83
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x2(%rdx)
  test   %cl,%cl
  je     L83
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x3(%rdx)
  test   %cl,%cl
  je     L83
  add    $0x4,%rax
  movzbl -0x1(%rax),%ecx
  add    $0x4,%rdx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L83
  cmp    %rdx,%rsi
  jne    L32
  and    $0x3,%r8d
  jne    L97
  mov    %rdx,%rcx
  jmp    L5
L77:
  test   %r8,%r8
  je     L83
L97:
  mov    %rdx,%rcx
L84:
  add    $0x1,%rax
  movzbl -0x1(%rax),%esi
  add    $0x1,%rcx
  mov    %sil,(%rcx)
  test   %sil,%sil
  je     L83
  mov    %r8,%rsi
  sub    %rcx,%rsi
  add    %rdx,%rsi
  jne    L84
L5:
  movb   $0x0,0x1(%rcx)
L83:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char c;
  char *s = s1;
  do
    c = *s1++;
  while (c != '\0');
  s1 -= 2;
  if (n >= 4) {
    size_t n4 = n >> 2;
    do {
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
    } while (--n4 > 0);
    n &= 3;
  }
  while (n > 0) {
    c = *s2++;
    *++s1 = c;
    if (c == '\0')
      return s;
    n--;
  }
  if (c != '\0')
    *++s1 = '\0';
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncat>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  mov    %rdx,%rdi
  mov    %r8,%rdx
L54:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L54
  lea    -0x1(%rcx),%rdx
  cmp    $0x3,%rdi
  ja     L92
  test   %rdi,%rdi
  je     L8
L78:
  mov    %rdx,%rcx
  jmp    L50
  nopl   0x0(%rax)
L87:
  mov    %rdi,%rsi
  sub    %rcx,%rsi
  add    %rdx,%rsi
  je     L106
L50:
  movzbl (%rax),%esi
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %sil,(%rcx)
  test   %sil,%sil
  jne    L87
L8:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L92:
  mov    %rdi,%rsi
  and    $0xfffffffffffffffc,%rsi
  lea    -0x1(%rcx,%rsi,1),%rsi
  jmp    L43
  xchg   %ax,%ax
L123:
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x2(%rdx)
  test   %cl,%cl
  je     L8
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x3(%rdx)
  test   %cl,%cl
  je     L8
  movzbl 0x3(%rax),%ecx
  add    $0x4,%rax
  add    $0x4,%rdx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L8
  cmp    %rsi,%rdx
  je     L68
L43:
  movzbl (%rax),%ecx
  mov    %cl,0x1(%rdx)
  test   %cl,%cl
  jne    L123
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  and    $0x3,%edi
  jne    L78
  mov    %rdx,%rcx
L106:
  movb   $0x0,0x1(%rcx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char c;
  char *s = s1;
  do
    c = *s1++;
  while (c != '\0');
  s1 -= 2;
  if (n >= 4) {
    size_t n4 = n >> 2;
    do {
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
    } while (--n4 > 0);
    n &= 3;
  }
  while (n > 0) {
    c = *s2++;
    *++s1 = c;
    if (c == '\0')
      return s;
    n--;
  }
  if (c != '\0')
    *++s1 = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<strncat>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rax
  mov    %rdx,%rdi
  mov    %r8,%rdx
L126:
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L126
  lea    -0x1(%rcx),%rdx
  cmp    $0x3,%rdi
  ja     L62
  test   %rdi,%rdi
  je     L80
L29:
  mov    %rdx,%rcx
  jmp    L54
  nopl   0x0(%rax)
L70:
  mov    %rdi,%rsi
  sub    %rcx,%rsi
  add    %rdx,%rsi
  je     L55
L54:
  movzbl (%rax),%esi
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %sil,(%rcx)
  test   %sil,%sil
  jne    L70
L80:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %rdi,%rsi
  and    $0xfffffffffffffffc,%rsi
  lea    -0x1(%rcx,%rsi,1),%rsi
  jmp    L121
  xchg   %ax,%ax
L90:
  movzbl 0x1(%rax),%ecx
  mov    %cl,0x2(%rdx)
  test   %cl,%cl
  je     L80
  movzbl 0x2(%rax),%ecx
  mov    %cl,0x3(%rdx)
  test   %cl,%cl
  je     L80
  movzbl 0x3(%rax),%ecx
  add    $0x4,%rax
  add    $0x4,%rdx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L80
  cmp    %rsi,%rdx
  je     L30
L121:
  movzbl (%rax),%ecx
  mov    %cl,0x1(%rdx)
  test   %cl,%cl
  jne    L90
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  and    $0x3,%edi
  jne    L29
  mov    %rdx,%rcx
L55:
  movb   $0x0,0x1(%rcx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char c;
  char *s = s1;
  do
    c = *s1++;
  while (c != '\0');
  s1 -= 2;
  if (n >= 4) {
    size_t n4 = n >> 2;
    do {
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
      c = *s2++;
      *++s1 = c;
      if (c == '\0')
        return s;
    } while (--n4 > 0);
    n &= 3;
  }
  while (n > 0) {
    c = *s2++;
    *++s1 = c;
    if (c == '\0')
      return s;
    n--;
  }
  if (c != '\0')
    *++s1 = '\0';
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L29
L21:
  mov    -0x10(%rbp),%rax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int get_file_size(int fd) {
  struct stat stat_struct;
  if (fstat(fd, &stat_struct) == -1)
    return -1;
  return (int)stat_struct.st_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L13
  mov    (%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_file_size(int fd) {
  struct stat stat_struct;
  if (fstat(fd, &stat_struct) == -1)
    return -1;
  return (int)stat_struct.st_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    (%rsp),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_file_size(int fd) {
  struct stat stat_struct;
  if (fstat(fd, &stat_struct) == -1)
    return -1;
  return (int)stat_struct.st_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L16
  mov    (%rsp),%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_file_size(int fd) {
  struct stat stat_struct;
  if (fstat(fd, &stat_struct) == -1)
    return -1;
  return (int)stat_struct.st_size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prefetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void prefetch() {
  __builtin_arm_prefetch(0, 1, 2, 0, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 0, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prefetch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_arm_prefetch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void prefetch() {
  __builtin_arm_prefetch(0, 1, 2, 0, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 0, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<prefetch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%ecx
  xor    %edi,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%ecx
  xor    %edi,%edi
  call   <__builtin_arm_prefetch@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1050 <__builtin_arm_prefetch@plt>
```

assistant: ```c
void prefetch() {
  __builtin_arm_prefetch(0, 1, 2, 0, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prefetch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%r8d
  xor    %ecx,%ecx
  xor    %edi,%edi
  mov    $0x2,%edx
  mov    $0x1,%esi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%ecx
  xor    %edi,%edi
  call   <__builtin_arm_prefetch@plt>
  mov    $0x1,%r8d
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x1,%ecx
  xor    %edi,%edi
  call   <__builtin_arm_prefetch@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1050 <__builtin_arm_prefetch@plt>
```

assistant: ```c
void prefetch() {
  __builtin_arm_prefetch(0, 1, 2, 0, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 1, 1);
  __builtin_arm_prefetch(0, 0, 0, 0, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L0:
  cmpl   $0x2a,-0x4(%rbp)
  jne    L8
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  while (x != 42) {
    x++;
    assert(x >= 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L1:
  add    $0x1,%ebx
  test   %ebx,%ebx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x2a,%ebx
  jne    L1
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  while (x != 42) {
    x++;
    assert(x >= 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2a,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L9
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  while (x != 42) {
    x++;
    assert(x >= 1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2a,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int x = 0;
  while (x != 42) {
    x++;
    assert(x >= 1);
  }
}
```