user: 这段汇编代码用C语言表示是什么样的：

```asm
<token_next_from_string>:
  endbr64
  push   %r12
  mov    %rsi,%r9
  mov    %ecx,%r11d
  mov    %rdx,%r10
  push   %rbp
  push   %rbx
  movslq (%rdx),%rax
  mov    %rdi,%rbx
  add    %rax,%rsi
  mov    %eax,%edi
  movzbl (%rsi),%ecx
  cmp    $0x20,%cl
  ja     L280
  movabs $0xfffffffeffffd9ff,%r8
  bt     %rcx,%r8
  jb     L280
  lea    0x1(%r9,%rax,1),%rax
  lea    0x1(%rdi),%ecx
  sub    %eax,%ecx
  xchg   %ax,%ax
L11:
  movzbl (%rax),%edx
  lea    (%rcx,%rax,1),%edi
  mov    %rax,%rsi
  cmp    $0x20,%dl
  jbe    L35
L280:
  mov    %edi,(%r10)
  movzbl (%rsi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L107
L34:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rax
  bt     %rdx,%r8
  jae    L11
  jmp    L280
L107:
  cmp    $0x22,%al
  je     L266
  cmp    $0x20,%al
  ja     L277
  movabs $0xfffffffeffffd9fe,%rdx
  mov    %edi,%r8d
  bt     %rax,%rdx
  jae    L263
L277:
  movslq %edi,%rdx
  sub    $0x1,%r11d
  movabs $0xfffffffeffffd9fe,%r12
  lea    0x1(%r9,%rdx,1),%rcx
  xor    %edx,%edx
  jmp    L68
L24:
  mov    %ebp,%edx
  mov    %r8d,%edi
L68:
  mov    %edx,%ebp
  cmp    %edx,%r11d
  jle    L285
  movslq %edx,%rsi
  lea    0x1(%rdx),%ebp
  mov    %al,(%rbx,%rsi,1)
L285:
  movzbl (%rcx),%eax
  lea    0x1(%rdi),%r8d
  mov    %rcx,%rsi
  cmp    $0x20,%al
  ja     L81
  bt     %rax,%r12
  jae    L74
L81:
  add    $0x1,%rcx
  cmp    %edx,%r11d
  jle    1040 <token_next_from_string.cold>
  jmp    L24
L74:
  movslq %ebp,%rbp
  add    %rbp,%rbx
L263:
  movb   $0x0,(%rbx)
L48:
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  ja     L41
  movabs $0xfffffffeffffd9ff,%rcx
  bt     %rax,%rcx
  jb     L41
  lea    0x1(%r8),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L103:
  movzbl (%r9,%rax,1),%edx
  mov    %eax,%r8d
  cmp    $0x20,%dl
  jbe    L118
L41:
  mov    %r8d,(%r10)
  mov    $0xffffffff,%r8d
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L118:
  add    $0x1,%rax
  bt     %rdx,%rcx
  jae    L103
  jmp    L41
L266:
  lea    0x1(%rdi),%r8d
  movslq %r8d,%rsi
  add    %r9,%rsi
  movzbl (%rsi),%ecx
  cmp    $0x22,%cl
  je     L287
  test   %cl,%cl
  je     L287
  lea    0x2(%rdi),%eax
  sub    $0x1,%r11d
  xor    %edx,%edx
  cltq
  cmp    %r11d,%edx
  jge    L102
L311:
  mov    %cl,(%rbx,%rdx,1)
  movzbl (%r9,%rax,1),%ecx
  lea    0x1(%rdx),%edi
  mov    %eax,%r8d
  lea    (%r9,%rax,1),%rsi
  cmp    $0x22,%cl
  je     L64
  test   %cl,%cl
  je     L64
  movslq %edi,%rdx
  add    $0x1,%rax
  cmp    %r11d,%edx
  jl     L311
L102:
  mov    %eax,%ecx
  mov    %eax,%r8d
  lea    (%r9,%rax,1),%rsi
  movzbl (%r9,%rax,1),%eax
  test   %al,%al
  je     L60
  cmp    $0x22,%al
  je     L60
  movslq %ecx,%rax
  lea    0x1(%rcx),%edi
  lea    0x1(%r9,%rax,1),%rax
  sub    %eax,%edi
  jmp    L62
L114:
  cmp    $0x22,%cl
  je     L60
L62:
  movzbl (%rax),%ecx
  lea    (%rdi,%rax,1),%r8d
  mov    %rax,%rsi
  add    $0x1,%rax
  test   %cl,%cl
  jne    L114
L60:
  add    %rdx,%rbx
L287:
  movb   $0x0,(%rbx)
  cmpb   $0x22,(%rsi)
  jne    L48
  add    $0x1,%r8d
  movslq %r8d,%rsi
  add    %r9,%rsi
  jmp    L48
L64:
  movslq %edi,%rdx
  jmp    L60
```

assistant: ```c
int token_next_from_string(char *dst, char *src, int *index, int max) {
  int i, j;
  i = (*index);
  for (; src[i] == ' ' || src[i] == '\t' || src[i] == '\n' || src[i] == '\r'; i++)
    ;
  (*index) = i;
  if (src[i] == '\0')
    return (0);
  if (src[i] == '\"') {
    for (j = 0, i++; src[i] != '\"' && src[i] != '\0'; i++) {
      if (j < max - 1)
        dst[j++] = src[i];
    }
    dst[j] = '\0';
    if (src[i] == '\"')
      i++;
  } else {
    for (j = 0; src[i] != ' ' && src[i] != '\t' && src[i] != '\n' && src[i] != '\r' && src[i] != '\0'; i++)
      if (j < max - 1)
        dst[j++] = src[i];
    dst[j] = '\0';
  }
  for (; src[i] == ' ' || src[i] == '\t' || src[i] == '\n' || src[i] == '\r'; i++)
    ;
  (*index) = i;
  return (-1);
}
```