user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x28,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0x28,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,%r14
L20:
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    $0x14,%edi
  mov    %rax,0x0(%rbp,%rbx,1)
  call   <malloc@plt>
  mov    %rax,(%r14,%rbx,1)
  add    $0x8,%rbx
  cmp    $0x28,%rbx
  jne    L20
  mov    %rbp,%r13
  lea    0x28(%rbp),%r15
  lea    D16(%rip),%r12
L111:
  xor    %ebx,%ebx
L41:
  mov    0x0(%r13),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %rbx,%rsi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    $0x14,%rbx
  jne    L41
  add    $0x8,%r13
  cmp    %r13,%r15
  jne    L111
  lea    0x7(%rsp),%r13
  lea    D18(%rip),%rbx
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L33:
  cmpb   $0x4c,0x7(%rsp)
  mov    %r14,%rdi
  mov    $0x10,%ecx
  je     L26
L71:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L33
  lea    0x28(%rbp),%r13
L14:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    $0x4,%ebx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x14,%rbx
  jne    L2
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L14
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L121:
  sub    $0x4,%rcx
  add    $0x8,%rdi
  cmp    $0xfffffffffffffffc,%rcx
  je     L69
L26:
  mov    (%rdi),%rsi
  xor    %eax,%eax
L29:
  mov    0x0(%rbp,%rax,8),%rdx
  mov    (%rdx,%rcx,1),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L29
  jmp    L121
  nopw   0x0(%rax,%rax,1)
L69:
  mov    %rbp,%rax
  mov    %r14,%rbp
  mov    %rax,%r14
  jmp    L71
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D18
type: string

tool: D16: %d

tool: D18: %c

assistant: ```c
int main() {
  int **Matrix = malloc(5 * sizeof(int *));
  int **result = malloc(5 * sizeof(int *));
  for (int x = 0; x < 5; x++) {
    Matrix[x] = malloc(5 * sizeof(int));
    result[x] = malloc(5 * sizeof(int));
  }
  for (int x = 0; x < 5; x++) {
    for (int y = 0; y < 5; y++) {
      scanf("%d", &Matrix[x][y]);
    }
  }
  char L;
  while (scanf("%c", &L) == 1) {
    if (L == 'L') {
      int i = 0;
      for (int x = 5 - 1; x >= 0; x--) {
        int j = 0;
        for (int y = 0; y < 5; y++) {
          result[i][j] = Matrix[y][x];
          ++j;
        }
        ++i;
      }
      int **temp = result;
      result = Matrix;
      Matrix = temp;
    }
  }
  for (int x = 0; x < 5; x++) {
    for (int y = 0, space = 0; y < 5; y++) {
      if (space)
        printf(" ");
      else
        space = 1;
      printf("%d", Matrix[x][y]);
    }
    printf("\n");
  }
  return 0;
}
```