ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  xor    %r12d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rbp
L55:
  xor    %r14d,%r14d
  jmp    L3
  nopl   0x0(%rax)
L65:
  add    $0x1,%r14
  cmp    $0x20,%al
  je     L19
L3:
  xor    %eax,%eax
  movslq %r14d,%rbx
  call   <getchar@plt>
  mov    %al,0x0(%rbp,%r14,1)
  cmp    $0xa,%al
  jne    L65
  movslq %r12d,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  lea    0x2720(%rax),%rcx
  lea    (%rsp,%rcx,1),%rdx
  movb   $0x0,-0x2720(%rbx,%rdx,1)
  test   %r12d,%r12d
  je     L20
  lea    -0x64(%r13,%rax,1),%rbp
  lea    0x0(%r13,%rax,1),%rbx
  lea    -0x1(%r12),%eax
  lea    D13(%rip),%r12
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rax
  sub    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  sub    $0x64,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L66
L20:
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x2720,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  movslq %r12d,%rax
  add    $0x64,%rbp
  add    $0x1,%r12d
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%rbx,%rax,1)
  jmp    L55
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D9
data_type: string

tool: D13: %s 

tool: D9: %s

assistant: ```c
int main() {
  char a[100][100];
  int len = 0;
  int i = 0;
  while ((a[len][i++] = getchar()) != '\n') {
    if (a[len][i - 1] == ' ') {
      a[len][i - 1] = '\0';
      i = 0;
      len++;
    }
  }
  a[len][i - 1] = '\0';
  for (int j = len; j > 0; j--)
    printf("%s ", a[j]);
  printf("%s", a[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<floating>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movss  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  divss  -0x18(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x20(%rbp),%xmm0
  fldt   0x10(%rbp)
  fstps  -0x28(%rbp)
  movss  -0x28(%rbp),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int floating(int a, float b, double c, long double d, int e) {
  int i;
  i = (int)((float)a / b + ((float)c / (float)d));
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floating>:
  endbr64
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  divss  %xmm2,%xmm0
  cvtsd2ss %xmm1,%xmm1
  fldt   0x8(%rsp)
  fstps  -0xc(%rsp)
  movss  -0xc(%rsp),%xmm2
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  ret
```

assistant: ```c
int floating(int a, float b, double c, long double d, int e) {
  int i;
  i = (int)((float)a / b + ((float)c / (float)d));
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floating>:
  endbr64
  fldt   0x8(%rsp)
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  cvtsi2ss %edi,%xmm0
  fstps  -0xc(%rsp)
  divss  %xmm2,%xmm0
  movss  -0xc(%rsp),%xmm2
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  ret
```

assistant: ```c
int floating(int a, float b, double c, long double d, int e) {
  int i;
  i = (int)((float)a / b + ((float)c / (float)d));
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<floating>:
  endbr64
  fldt   0x8(%rsp)
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  cvtsi2ss %edi,%xmm0
  fstps  -0xc(%rsp)
  divss  %xmm2,%xmm0
  movss  -0xc(%rsp),%xmm2
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  ret
```

assistant: ```c
int floating(int a, float b, double c, long double d, int e) {
  int i;
  i = (int)((float)a / b + ((float)c / (float)d));
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fexecl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc4(%rbp),%edx
  mov    -0xb8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xc4(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <vfexec@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D10(%rip),%rax
  mov    -0xb4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int fexecl(int fd, ...) {
  int saved_errno;
  va_list argv;
  va_start(argv, fd);
  vfexec(fd, argv, 0);
  saved_errno = errno;
  va_end(argv);
  return errno = saved_errno, -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fexecl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <vfexec@plt>
  mov    D1(%rip),%rbx
  mov    (%rbx),%r12d
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12d,(%rbx)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fexecl(int fd, ...) {
  int saved_errno;
  va_list argv;
  va_start(argv, fd);
  vfexec(fd, argv, 0);
  saved_errno = errno;
  va_end(argv);
  return errno = saved_errno, -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fexecl>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  xor    %edx,%edx
  call   <vfexec@plt>
  mov    D2(%rip),%rbp
  mov    %r12d,%edi
  mov    0x0(%rbp),%ebx
  call   <va_end@plt>
  mov    $0xffffffff,%eax
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fexecl(int fd, ...) {
  int saved_errno;
  va_list argv;
  va_start(argv, fd);
  vfexec(fd, argv, 0);
  saved_errno = errno;
  va_end(argv);
  return errno = saved_errno, -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fexecl>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %edi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  xor    %edx,%edx
  call   <vfexec@plt>
  mov    D5(%rip),%rbp
  mov    %r12d,%edi
  mov    0x0(%rbp),%ebx
  call   <va_end@plt>
  mov    $0xffffffff,%eax
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fexecl(int fd, ...) {
  int saved_errno;
  va_list argv;
  va_start(argv, fd);
  vfexec(fd, argv, 0);
  saved_errno = errno;
  va_end(argv);
  return errno = saved_errno, -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_multiply_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matrix_multiply_ext@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *matrix_multiply_new(const float matrix1[4 * 4], const float matrix2[4 * 4]) {
  float *matrix_out = (float *)malloc(sizeof(float) * 4);
  matrix_multiply_ext(matrix1, matrix2, matrix_out);
  return matrix_out;
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_multiply_new>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float *matrix_multiply_new(const float matrix1[4 * 4], const float matrix2[4 * 4]) {
  float *matrix_out = (float *)malloc(sizeof(float) * 4);
  matrix_multiply_ext(matrix1, matrix2, matrix_out);
  return matrix_out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix_multiply_new>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <matrix_multiply_ext@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *matrix_multiply_new(const float matrix1[4 * 4], const float matrix2[4 * 4]) {
  float *matrix_out = (float *)malloc(sizeof(float) * 4);
  matrix_multiply_ext(matrix1, matrix2, matrix_out);
  return matrix_out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrix_multiply_new>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <matrix_multiply_ext@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *matrix_multiply_new(const float matrix1[4 * 4], const float matrix2[4 * 4]) {
  float *matrix_out = (float *)malloc(sizeof(float) * 4);
  matrix_multiply_ext(matrix1, matrix2, matrix_out);
  return matrix_out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movb   $0x61,-0x21(%rbp)
  lea    -0x21(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D17: %d


tool: D0: %c


assistant: ```c
int main(void) {
  int n = 10;
  printf("%d\n", n);
  char cc = 'a';
  char *ptr = &cc;
  printf("%c\n", *ptr);
  int *c = &n;
  printf("%d\n", *c);
  int r;
  r = 0;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%esi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D8
datatype: string

tool: D13: %d


tool: D8: %c


assistant: ```c
int main(void) {
  int n = 10;
  printf("%d\n", n);
  char cc = 'a';
  char *ptr = &cc;
  printf("%c\n", *ptr);
  int *c = &n;
  printf("%d\n", *c);
  int r;
  r = 0;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D0: %d


tool: D4: %c


assistant: ```c
int main(void) {
  int n = 10;
  printf("%d\n", n);
  char cc = 'a';
  char *ptr = &cc;
  printf("%c\n", *ptr);
  int *c = &n;
  printf("%d\n", *c);
  int r;
  r = 0;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D3: %d


tool: D5: %c


assistant: ```c
int main(void) {
  int n = 10;
  printf("%d\n", n);
  char cc = 'a';
  char *ptr = &cc;
  printf("%c\n", *ptr);
  int *c = &n;
  printf("%d\n", *c);
  int r;
  r = 0;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movb   $0x0,-0x11(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L4:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x11(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  cmpb   $0x63,-0x11(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d, 

assistant: ```c
int main() {
  int g, d, g1, d1;
  char i;
  g = 1;
  d = 2;
  i = 0;
  printf("%d, ", g);
  while (i < 100) {
    g1 = g + d;
    d1 = g;
    g = g1;
    d = d1;
    i = i + 1;
    printf("%d, ", g);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ebx
  mov    $0x2,%eax
  mov    $0x1,%ebp
  lea    D17(%rip),%r13
  jmp    L9
L4:
  mov    %r12d,%ebp
L9:
  lea    0x0(%rbp,%rax,1),%r12d
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebp,%eax
  sub    $0x1,%bl
  jne    L4
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string

tool: D17: %d, 

assistant: ```c
int main() {
  int g, d, g1, d1;
  char i;
  g = 1;
  d = 2;
  i = 0;
  printf("%d, ", g);
  while (i < 100) {
    g1 = g + d;
    d1 = g;
    g = g1;
    d = d1;
    i = i + 1;
    printf("%d, ", g);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  mov    $0x1,%esi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x2,%eax
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r12d,%ebp
L2:
  lea    0x0(%rbp,%rax,1),%r12d
  mov    %r13,%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  sub    $0x1,%bl
  jne    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: %d, 

assistant: ```c
int main() {
  int g, d, g1, d1;
  char i;
  g = 1;
  d = 2;
  i = 0;
  printf("%d, ", g);
  while (i < 100) {
    g1 = g + d;
    d1 = g;
    g = g1;
    d = d1;
    i = i + 1;
    printf("%d, ", g);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  mov    $0x1,%esi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x2,%eax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12d,%ebp
L5:
  lea    0x0(%rbp,%rax,1),%r12d
  mov    %r13,%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  sub    $0x1,%bl
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: %d, 

assistant: ```c
int main() {
  int g, d, g1, d1;
  char i;
  g = 1;
  d = 2;
  i = 0;
  printf("%d, ", g);
  while (i < 100) {
    g1 = g + d;
    d1 = g;
    g = g1;
    d = d1;
    i = i + 1;
    printf("%d, ", g);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<permute_sudirript>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void permute_sudirript(int N, int *sudirript, int *permutation, int *out) {
  int i;
  for (i = 0; i < N; i++) {
    out[permutation[i]] = sudirript[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<permute_sudirript>:
  endbr64
  test   %edi,%edi
  jle    L4
  mov    %edi,%edi
  mov    $0x0,%eax
L10:
  mov    (%rsi,%rax,4),%r9d
  movslq (%rdx,%rax,4),%r8
  mov    %r9d,(%rcx,%r8,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L10
L4:
  ret
```

assistant: ```c
void permute_sudirript(int N, int *sudirript, int *permutation, int *out) {
  int i;
  for (i = 0; i < N; i++) {
    out[permutation[i]] = sudirript[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<permute_sudirript>:
  endbr64
  test   %edi,%edi
  jle    L14
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L12:
  mov    (%rsi,%rax,4),%r9d
  movslq (%rdx,%rax,4),%r8
  add    $0x1,%rax
  mov    %r9d,(%rcx,%r8,4)
  cmp    %rax,%rdi
  jne    L12
L14:
  ret
```

assistant: ```c
void permute_sudirript(int N, int *sudirript, int *permutation, int *out) {
  int i;
  for (i = 0; i < N; i++) {
    out[permutation[i]] = sudirript[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permute_sudirript>:
  endbr64
  test   %edi,%edi
  jle    L2
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L16:
  mov    (%rsi,%rax,4),%r9d
  movslq (%rdx,%rax,4),%r8
  add    $0x1,%rax
  mov    %r9d,(%rcx,%r8,4)
  cmp    %rax,%rdi
  jne    L16
L2:
  ret
```

assistant: ```c
void permute_sudirript(int N, int *sudirript, int *permutation, int *out) {
  int i;
  for (i = 0; i < N; i++) {
    out[permutation[i]] = sudirript[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_bool@plt>
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L15
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L15:
  cmpl   $0x0,-0xc(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  movl   $0x29a,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L16:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  bool selector = __VERIFIER_nondet_bool();
  int *ptr = NULL;
  if (!selector) {
    ptr = malloc(sizeof(int));
  }
  if (!selector) {
    *ptr = 666;
    free(ptr);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_bool@plt>
  test   %eax,%eax
  je     L10
L12:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x29a,(%rax)
  call   <free@plt>
  jmp    L12
```

assistant: ```c
int main() {
  bool selector = __VERIFIER_nondet_bool();
  int *ptr = NULL;
  if (!selector) {
    ptr = malloc(sizeof(int));
  }
  if (!selector) {
    *ptr = 666;
    free(ptr);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_bool@plt>
  test   %eax,%eax
  je     L16
L17:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x29a,(%rax)
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L17
```

assistant: ```c
int main() {
  bool selector = __VERIFIER_nondet_bool();
  int *ptr = NULL;
  if (!selector) {
    ptr = malloc(sizeof(int));
  }
  if (!selector) {
    *ptr = 666;
    free(ptr);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_bool@plt>
  test   %eax,%eax
  je     L16
L14:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L16:
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x29a,(%rax)
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L14
```

assistant: ```c
int main() {
  bool selector = __VERIFIER_nondet_bool();
  int *ptr = NULL;
  if (!selector) {
    ptr = malloc(sizeof(int));
  }
  if (!selector) {
    *ptr = 666;
    free(ptr);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checktoken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L49
L92:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x20,-0x9(%rbp)
  jle    L143
  cmpb   $0x28,-0x9(%rbp)
  je     L146
  cmpb   $0x29,-0x9(%rbp)
  je     L43
  cmpb   $0x7b,-0x9(%rbp)
  je     L60
  cmpb   $0x7d,-0x9(%rbp)
  je     L17
  cmpb   $0x3b,-0x9(%rbp)
  je     L19
  cmpb   $0x22,-0x9(%rbp)
  je     L33
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L92
  jmp    L9
L143:
  nop
  jmp    L9
L146:
  nop
  jmp    L9
L43:
  nop
  jmp    L9
L60:
  nop
  jmp    L9
L17:
  nop
  jmp    L9
L19:
  nop
  jmp    L9
L33:
  nop
L9:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L49
  addq   $0x1,-0x18(%rbp)
L49:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *checktoken(char *s, char *s1) {
  char *s0 = s;
  if (s < s1) {
    do {
      char c = *s;
      if (c <= ' ')
        break;
      if (c == ', ')
        break;
      if (c == '(')
        break;
      if (c == ')')
        break;
      if (c == '{')
        break;
      if (c == '}')
        break;
      if (c == ';')
        break;
      if (c == '\x22')
        break;
      s++;
    } while (s < s1);
    if (s == s0)
      s++;
  }
  return s;
}
```