ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L21
  mov    %rsp,%rcx
  movslq %eax,%rdx
  add    %rbx,%rdx
  mov    %eax,%esi
L16:
  movzbl (%rcx),%edi
  sub    $0x1,%esi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rcx)
  mov    %dil,-0x1(%rdx)
  add    $0x1,%rcx
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %esi,%edi
  cmp    %edi,%esi
  jg     L16
L21:
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: %s

assistant: ```c
int main() {
  char str[125], temp;
  int i, lenght;
  scanf("%s", str);
  lenght = strlen(str);
  for (i = 0; i < lenght; i++) {
    temp = str[i];
    str[i] = str[lenght - 1];
    str[lenght - 1] = temp;
    lenght--;
  }
  printf("%s", str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  movslq %eax,%rdx
  mov    %rbp,%rsi
  mov    %eax,%ecx
  add    %rbp,%rdx
  nopl   (%rax)
L15:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  cmp    %edi,%ecx
  jg     L15
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: %s

assistant: ```c
int main() {
  char str[125], temp;
  int i, lenght;
  scanf("%s", str);
  lenght = strlen(str);
  for (i = 0; i < lenght; i++) {
    temp = str[i];
    str[i] = str[lenght - 1];
    str[lenght - 1] = temp;
    lenght--;
  }
  printf("%s", str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  movslq %eax,%rdx
  mov    %rbp,%rsi
  mov    %eax,%ecx
  add    %rbp,%rdx
  nopl   (%rax)
L10:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  cmp    %edi,%ecx
  jg     L10
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %s

assistant: ```c
int main() {
  char str[125], temp;
  int i, lenght;
  scanf("%s", str);
  lenght = strlen(str);
  for (i = 0; i < lenght; i++) {
    temp = str[i];
    str[i] = str[lenght - 1];
    str[lenght - 1] = temp;
    lenght--;
  }
  printf("%s", str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<U64_AT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <bswap64@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
uint64_t U64_AT(const void *p) {
  uint64_t x;
  memcpy(&x, p, sizeof(x));
  return bswap64(x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<U64_AT>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <bswap64@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t U64_AT(const void *p) {
  uint64_t x;
  memcpy(&x, p, sizeof(x));
  return bswap64(x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<U64_AT>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <bswap64@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t U64_AT(const void *p) {
  uint64_t x;
  memcpy(&x, p, sizeof(x));
  return bswap64(x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<U64_AT>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%edi
  call   <bswap64@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t U64_AT(const void *p) {
  uint64_t x;
  memcpy(&x, p, sizeof(x));
  return bswap64(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L19:
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int a) {
  int k;
  k = 0;
  while (a) {
    k = k * 10 + a % 10;
    a /= 10;
  }
  return k;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  test   %edi,%edi
  je     L8
  mov    $0x0,%edx
L9:
  lea    (%rdx,%rdx,4),%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%edx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L9
L20:
  mov    %edx,%eax
  ret
L8:
  mov    %edi,%edx
  jmp    L20
```

assistant: ```c
int reverse(int a) {
  int k;
  k = 0;
  while (a) {
    k = k * 10 + a % 10;
    a /= 10;
  }
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L12
  nopl   0x0(%rax,%rax,1)
L1:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    (%r8,%r8,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L1
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int a) {
  int k;
  k = 0;
  while (a) {
    k = k * 10 + a % 10;
    a /= 10;
  }
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L18
  nopl   0x0(%rax,%rax,1)
L17:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    (%r8,%r8,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L17
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int a) {
  int k;
  k = 0;
  while (a) {
    k = k * 10 + a % 10;
    a /= 10;
  }
  return k;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  movzwl (%rdi),%ebx
  add    $0x696a,%bx
  xor    $0xb,%ebx
  movzwl %bx,%eax
  test   $0x1,%bl
  je     L37
  mov    %ebx,%esi
  shr    %si
  test   $0x2,%bl
  je     L13
  and    $0xe,%esi
  or     $0x1,%esi
  mov    $0x10,%ecx
  sub    %esi,%ecx
  mov    %eax,%edi
  sar    %cl,%edi
  mov    %esi,%ecx
  shl    %cl,%eax
  or     %eax,%edi
  lea    0x0(,%rdi,4),%eax
  and    $0x1c,%eax
  or     %ebx,%eax
L15:
  shr    $0x7,%ax
  mov    %ax,(%rdx)
  pop    %rbx
  ret
L13:
  imul   %eax,%eax
  shl    $0x3,%eax
  movzbl %al,%ecx
  or     %ebx,%ecx
  lea    0x0(,%rcx,4),%eax
  and    $0x1c,%eax
  or     %ecx,%eax
  jmp    L15
L37:
  test   $0x4,%bl
  je     L5
  shl    $0x4,%eax
  and    $0x70,%eax
  or     %ebx,%eax
  add    %eax,%eax
  jmp    L15
L5:
  movsbl %bh,%ecx
  mov    $0x0,%eax
  mov    %cl,%al
  mov    %bl,%ah
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)7) << 2UL;
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned short)31) << 3UL;
        state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
      }
    } else if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 3UL;
      state[0UL] += state[0UL];
    } else {
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy12;
      copy12 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy12;
      copy13 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzwl (%r8),%eax
  add    $0x696a,%ax
  xor    $0xb,%eax
  movzwl %ax,%esi
  test   $0x1,%al
  je     L12
  mov    %eax,%r8d
  shr    %r8w
  test   $0x2,%al
  je     L20
  and    $0xe,%r8d
  mov    $0x10,%ecx
  mov    %esi,%edx
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %eax,%edx
L14:
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %eax,%edx
  rol    $0x8,%dx
  test   $0x4,%al
  je     L14
  shl    $0x4,%esi
  and    $0x70,%esi
  or     %eax,%esi
  lea    (%rsi,%rsi,1),%edx
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
  nopl   (%rax)
L20:
  imul   %esi,%esi
  shl    $0x3,%esi
  movzbl %sil,%esi
  or     %eax,%esi
  lea    0x0(,%rsi,4),%edx
  and    $0x1c,%edx
  or     %esi,%edx
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)7) << 2UL;
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned short)31) << 3UL;
        state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
      }
    } else if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 3UL;
      state[0UL] += state[0UL];
    } else {
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy12;
      copy12 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy12;
      copy13 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  movzwl (%r8),%eax
  add    $0x696a,%ax
  xor    $0xb,%eax
  movzwl %ax,%esi
  test   $0x1,%al
  je     L9
  mov    %eax,%r8d
  shr    %r8w
  test   $0x2,%al
  je     L7
  and    $0xe,%r8d
  mov    $0x10,%ecx
  mov    %esi,%edx
  or     $0x1,%r8d
  sub    %r8d,%ecx
  sar    %cl,%edx
  mov    %r8d,%ecx
  shl    %cl,%esi
  or     %esi,%edx
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %eax,%edx
L26:
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  rol    $0x8,%dx
  test   $0x4,%al
  je     L26
  shl    $0x4,%esi
  and    $0x70,%esi
  or     %eax,%esi
  lea    (%rsi,%rsi,1),%edx
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
  nopl   (%rax)
L7:
  imul   %esi,%esi
  shl    $0x3,%esi
  movzbl %sil,%esi
  or     %eax,%esi
  lea    0x0(,%rsi,4),%edx
  and    $0x1c,%edx
  or     %esi,%edx
  shr    $0x7,%dx
  mov    %dx,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    if (state[0UL] & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)1) & (unsigned short)1) {
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)7) << 2UL;
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned short)31) << 3UL;
        state[0UL] |= (state[0UL] & (unsigned short)7) << 2UL;
      }
    } else if ((state[0UL] >> (unsigned short)2) & (unsigned short)1) {
      state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 3UL;
      state[0UL] += state[0UL];
    } else {
      copy12 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy12;
      copy12 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy12;
      copy13 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_swap_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  rolq   $0x20,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  mov    %rax,%rdx
  movabs $0xffff0000ffff0000,%rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rcx
  movabs $0xffff0000ffff,%rax
  and    %rcx,%rax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  movabs $0xff00ff00ff00ff00,%rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  mov    %rax,%rcx
  movabs $0xff00ff00ff00ff,%rax
  and    %rcx,%rax
  or     %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long byte_swap_8(unsigned long long v) {
  v = ((v & 0x00000000FFFFFFFFULL) << 32) | (v >> 32);
  v = ((v & 0x0000FFFF0000FFFFULL) << 16) | ((v & 0xFFFF0000FFFF0000ULL) >> 16);
  return ((v & 0x00FF00FF00FF00FFULL) << 8) | ((v & 0xFF00FF00FF00FF00ULL) >> 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_swap_8>:
  endbr64
  mov    %rdi,%rax
  rol    $0x20,%rax
  mov    %rax,%rdi
  shl    $0x10,%rdi
  movabs $0xffff0000ffff0000,%rdx
  and    %rdx,%rdi
  shr    $0x10,%rax
  movabs $0xffff0000ffff,%rdx
  and    %rdx,%rax
  or     %rax,%rdi
  mov    %rdi,%rax
  shl    $0x8,%rax
  movabs $0xff00ff00ff00ff00,%rdx
  and    %rdx,%rax
  shr    $0x8,%rdi
  movabs $0xff00ff00ff00ff,%rdx
  and    %rdx,%rdi
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long long byte_swap_8(unsigned long long v) {
  v = ((v & 0x00000000FFFFFFFFULL) << 32) | (v >> 32);
  v = ((v & 0x0000FFFF0000FFFFULL) << 16) | ((v & 0xFFFF0000FFFF0000ULL) >> 16);
  return ((v & 0x00FF00FF00FF00FFULL) << 8) | ((v & 0xFF00FF00FF00FF00ULL) >> 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_swap_8>:
  endbr64
  mov    %rdi,%rax
  bswap  %rax
  ret
```

assistant: ```c
unsigned long long byte_swap_8(unsigned long long v) {
  v = ((v & 0x00000000FFFFFFFFULL) << 32) | (v >> 32);
  v = ((v & 0x0000FFFF0000FFFFULL) << 16) | ((v & 0xFFFF0000FFFF0000ULL) >> 16);
  return ((v & 0x00FF00FF00FF00FFULL) << 8) | ((v & 0xFF00FF00FF00FF00ULL) >> 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<byte_swap_8>:
  endbr64
  mov    %rdi,%rax
  bswap  %rax
  ret
```

assistant: ```c
unsigned long long byte_swap_8(unsigned long long v) {
  v = ((v & 0x00000000FFFFFFFFULL) << 32) | (v >> 32);
  v = ((v & 0x0000FFFF0000FFFFULL) << 16) | ((v & 0xFFFF0000FFFF0000ULL) >> 16);
  return ((v & 0x00FF00FF00FF00FFULL) << 8) | ((v & 0xFF00FF00FF00FF00ULL) >> 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L24
L30:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L25
  mov    $0x0,%eax
  jmp    L35
L25:
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    $0x1,%eax
L35:
  leave
  ret
```

assistant: ```c
bool isnum(const char *token) {
  for (size_t i = 0; token[i] != 0; i++) {
    if (!isdigit(token[i]))
      return false;
  }
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  add    $0x1,%rbx
L0:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L31
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L0
  mov    $0x1,%eax
L31:
  pop    %rbx
  ret
L29:
  mov    $0x1,%eax
  jmp    L31
```

assistant: ```c
bool isnum(const char *token) {
  for (size_t i = 0; token[i] != 0; i++) {
    if (!isdigit(token[i]))
      return false;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L39
  add    $0x1,%rbx
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L39
L3:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L19
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool isnum(const char *token) {
  for (size_t i = 0; token[i] != 0; i++) {
    if (!isdigit(token[i]))
      return false;
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isnum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
  add    $0x1,%rbx
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L21:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L5
L3:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L21
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool isnum(const char *token) {
  for (size_t i = 0; token[i] != 0; i++) {
    if (!isdigit(token[i]))
      return false;
  }
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bs>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm7
  movsd  %xmm1,0x8(%rsp)
  mov    %rdi,%rbx
  subsd  %xmm0,%xmm7
  comisd D11(%rip),%xmm7
  jbe    L12
L1:
  movsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  movapd %xmm0,%xmm3
  mulsd  D23(%rip),%xmm3
  movq   %xmm3,%r14
  movapd %xmm3,%xmm0
  call   *%rbx
  pxor   %xmm1,%xmm1
  cmpltsd %xmm0,%xmm1
  movsd  (%rsp),%xmm2
  andpd  %xmm1,%xmm2
  movq   %r14,%xmm4
  andnpd %xmm4,%xmm1
  movapd %xmm1,%xmm5
  orpd   %xmm2,%xmm5
  movsd  %xmm5,(%rsp)
  pxor   %xmm1,%xmm1
  cmpltsd %xmm0,%xmm1
  andpd  %xmm1,%xmm4
  movsd  0x8(%rsp),%xmm6
  andnpd %xmm6,%xmm1
  orpd   %xmm4,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm0
  subsd  %xmm5,%xmm0
  comisd D11(%rip),%xmm0
  ja     L1
L12:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D23
data_type: byte[8]

tool: {"D11": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double bs(double a, double b, double (*f)(double)) {
  while (b - a > 1e-6) {
    double m = (a + b) / 2;
    if (f(m) > 0)
      b = m;
    else
      a = m;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bs>:
  endbr64
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  comisd D25(%rip),%xmm0
  jbe    L16
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  cs nopw 0x0(%rax,%rax,1)
L15:
  movapd %xmm4,%xmm2
  movsd  %xmm4,0x18(%rsp)
  addsd  %xmm1,%xmm2
  mulsd  D9(%rip),%xmm2
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rbx
  pxor   %xmm3,%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  cmpltsd %xmm0,%xmm3
  movsd  0x18(%rsp),%xmm4
  movapd %xmm3,%xmm0
  andpd  %xmm3,%xmm4
  andnpd %xmm2,%xmm0
  andpd  %xmm3,%xmm2
  andnpd %xmm1,%xmm3
  movapd %xmm3,%xmm1
  orpd   %xmm0,%xmm4
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
  subsd  %xmm4,%xmm0
  comisd D25(%rip),%xmm0
  ja     L15
  add    $0x20,%rsp
  movapd %xmm4,%xmm0
  pop    %rbx
  ret
  nop
L16:
  movapd %xmm4,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_infered: byte[16]
name: extract_symbolic_data
arguments: label: D9
type_infered: byte[8]

tool: {"D25": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double bs(double a, double b, double (*f)(double)) {
  while (b - a > 1e-6) {
    double m = (a + b) / 2;
    if (f(m) > 0)
      b = m;
    else
      a = m;
  }
  return a;
}
```