ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<show>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L19
  mov    %ebp,%r15d
  mov    $0x0,%ebx
  sub    $0x1,%ebp
  lea    D37(%rip),%r14
  lea    D25(%rip),%r13
L14:
  cmp    %ebx,%ebp
  mov    %r13,%rdx
  cmovg  %r14,%rdx
  mov    (%r12,%rbx,8),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L14
L19:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D37
data_type: string
name: read_data
arguments: label: D25
data_type: string
name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D12
data_type: string

tool: D37: , 

tool: 

tool: D0: %#018llx%s

tool: D12: ]

assistant: ```c
void show(unsigned long long int *a, int cnt) {
  printf("[");
  int i;
  for (i = 0; i < cnt; i++)
    printf("%#018llx%s", a[i], i < cnt - 1 ? ", " : "");
  printf("]\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<show>:
  endbr64
  push   %r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x5b,%edi
  push   %rbx
  movslq %esi,%rbx
  lea    -0x1(%rbx),%r15d
  sub    $0x8,%rsp
  call   <putchar@plt>
  test   %ebx,%ebx
  jle    L2
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    %r12d,%r15d
  lea    D21(%rip),%rdx
  mov    0x0(%rbp,%r12,8),%rsi
  mov    %r14,%rdi
  cmovle %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L19
L2:
  add    $0x8,%rsp
  lea    D32(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D32
type_infered: string

tool: D0: %#018llx%s

tool: 

tool: D21: , 

tool: D32: ]

assistant: ```c
void show(unsigned long long int *a, int cnt) {
  printf("[");
  int i;
  for (i = 0; i < cnt; i++)
    printf("%#018llx%s", a[i], i < cnt - 1 ? ", " : "");
  printf("]\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    $0x5b,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <putchar@plt>
  test   %r13d,%r13d
  jle    L20
  mov    %r13d,%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jne    L39
  lea    D16(%rip),%r12
L37:
  movslq 0xc(%rsp),%rbx
  lea    D48(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    (%r14,%rbx,8),%rsi
  mov    %rbp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jg     L3
L20:
  add    $0x18,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L39:
  mov    %r14,%rbx
  xor    %ebp,%ebp
  lea    D11(%rip),%r15
  lea    D16(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L58:
  mov    (%rbx),%rsi
  mov    %r15,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    0xc(%rsp),%ebp
  jl     L58
  mov    %ebp,0xc(%rsp)
  cmp    %ebp,%r13d
  jg     L37
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D48
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string

tool: D16: %#018llx%s

tool: 

tool: D9: ]

tool: D11: , 

assistant: ```c
void show(unsigned long long int *a, int cnt) {
  printf("[");
  int i;
  for (i = 0; i < cnt; i++)
    printf("%#018llx%s", a[i], i < cnt - 1 ? ", " : "");
  printf("]\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<core_tick_at_100us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <TypeCTickAt100us@plt>
  mov    $0x0,%eax
  call   <ProtocolTickAt100us@plt>
  mov    $0x0,%eax
  call   <PolicyTickAt100us@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void core_tick_at_100us(void) {
  TypeCTickAt100us();
  ProtocolTickAt100us();
  PolicyTickAt100us();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<core_tick_at_100us>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TypeCTickAt100us@plt>
  mov    $0x0,%eax
  call   <ProtocolTickAt100us@plt>
  mov    $0x0,%eax
  call   <PolicyTickAt100us@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void core_tick_at_100us(void) {
  TypeCTickAt100us();
  ProtocolTickAt100us();
  PolicyTickAt100us();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<core_tick_at_100us>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TypeCTickAt100us@plt>
  xor    %eax,%eax
  call   <ProtocolTickAt100us@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <PolicyTickAt100us@plt>
```

assistant: ```c
void core_tick_at_100us(void) {
  TypeCTickAt100us();
  ProtocolTickAt100us();
  PolicyTickAt100us();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<core_tick_at_100us>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <TypeCTickAt100us@plt>
  xor    %eax,%eax
  call   <ProtocolTickAt100us@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <PolicyTickAt100us@plt>
```

assistant: ```c
void core_tick_at_100us(void) {
  TypeCTickAt100us();
  ProtocolTickAt100us();
  PolicyTickAt100us();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <initdb@plt>
  cmp    $0xffffffff,%eax
  je     L46
  test   %eax,%eax
  jns    L30
  cmp    $0xfffffffd,%eax
  je     L4
  cmp    $0xfffffffe,%eax
  jne    L30
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L4:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L46:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L30:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L36:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D49
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D38
type_infered: string

tool: D49: Initializing Prism...


tool: D17:   ERR: already initialized


tool: D23:   ERR: permissions error


tool: D10:   ERR: general error


tool: D38:   OK: initialized


assistant: ```c
void init_task() {
  printf("Initializing Prism...\n");
  switch (initdb()) {
  case -2:
    printf("  ERR: already initialized\n");
    break;
  case -3:
    printf("  ERR: permissions error\n");
    break;
  case -1:
    printf("  ERR: general error\n");
    break;
  default:
    printf("  OK: initialized\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<init_task>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <initdb@plt>
  cmp    $0xfffffffe,%eax
  je     L22
  cmp    $0xffffffff,%eax
  je     L48
  cmp    $0xfffffffd,%eax
  je     L59
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L22:
  lea    D39(%rip),%rdi
  call   <printf@plt>
L2:
  add    $0x8,%rsp
  ret
L59:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L48:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string

tool: D34: Initializing Prism...


tool: D13:   OK: initialized


tool: D39:   ERR: already initialized


tool: D11:   ERR: permissions error


tool: D19:   ERR: general error


assistant: ```c
void init_task() {
  printf("Initializing Prism...\n");
  switch (initdb()) {
  case -2:
    printf("  ERR: already initialized\n");
    break;
  case -3:
    printf("  ERR: permissions error\n");
    break;
  case -1:
    printf("  ERR: general error\n");
    break;
  default:
    printf("  OK: initialized\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_task>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <initdb@plt>
  cmp    $0xfffffffe,%eax
  je     L6
  cmp    $0xffffffff,%eax
  je     L8
  cmp    $0xfffffffd,%eax
  je     L16
  lea    D38(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D29(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
L16:
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
L8:
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D38
data_type: string
name: read_data
arguments: label: D29
data_type: string
name: read_data
arguments: label: D17
data_type: string
name: read_data
arguments: label: D28
data_type: string

tool: D6: Initializing Prism...


tool: D38:   OK: initialized


tool: D29:   ERR: already initialized


tool: D17:   ERR: permissions error


tool: D28:   ERR: general error


assistant: ```c
void init_task() {
  printf("Initializing Prism...\n");
  switch (initdb()) {
  case -2:
    printf("  ERR: already initialized\n");
    break;
  case -3:
    printf("  ERR: permissions error\n");
    break;
  case -1:
    printf("  ERR: general error\n");
    break;
  default:
    printf("  OK: initialized\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_task>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <initdb@plt>
  cmp    $0xfffffffe,%eax
  je     L7
  cmp    $0xffffffff,%eax
  je     L26
  cmp    $0xfffffffd,%eax
  je     L4
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
L4:
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
L26:
  lea    D37(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: string

tool: D26: Initializing Prism...


tool: D19:   OK: initialized


tool: D18:   ERR: already initialized


tool: D17:   ERR: permissions error


tool: D37:   ERR: general error


assistant: ```c
void init_task() {
  printf("Initializing Prism...\n");
  switch (initdb()) {
  case -2:
    printf("  ERR: already initialized\n");
    break;
  case -3:
    printf("  ERR: permissions error\n");
    break;
  case -1:
    printf("  ERR: general error\n");
    break;
  default:
    printf("  OK: initialized\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L24
L16:
  mov    -0x7e4(%rbp),%edx
  lea    -0x3f0(%rbp),%rcx
  lea    -0x7e0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <entab@plt>
  mov    %eax,-0x7e4(%rbp)
  lea    -0x3f0(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getlinelength@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
main() {
  int length;
  char line[1000];
  char aux[1000];
  while ((length = getlinelength(line, 1000)) > 0) {
    length = entab(line, aux, length);
    copy(line, aux);
    printf("%s\n", line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%r12
  jmp    L18
L12:
  lea    0x3f0(%rsp),%rbp
  mov    %rsp,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <entab@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <copy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L18:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getlinelength@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L12
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: %s


assistant: ```c
main() {
  int length;
  char line[1000];
  char aux[1000];
  while ((length = getlinelength(line, 1000)) > 0) {
    length = entab(line, aux, length);
    copy(line, aux);
    printf("%s\n", line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L14
  xchg   %ax,%ax
L16:
  lea    0x3f0(%rsp),%rbp
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <entab@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <copy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L14:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinelength@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L16
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: %s


assistant: ```c
main() {
  int length;
  char line[1000];
  char aux[1000];
  while ((length = getlinelength(line, 1000)) > 0) {
    length = entab(line, aux, length);
    copy(line, aux);
    printf("%s\n", line);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L18
  xchg   %ax,%ax
L20:
  lea    0x3f0(%rsp),%rbp
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <entab@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <copy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L18:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <getlinelength@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L20
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: %s


assistant: ```c
main() {
  int length;
  char line[1000];
  char aux[1000];
  while ((length = getlinelength(line, 1000)) > 0) {
    length = entab(line, aux, length);
    copy(line, aux);
    printf("%s\n", line);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<WaitFor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_ReceiveChar@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  cmp    -0x1c(%rbp),%al
  je     L5
  jmp    L8
L5:
  nop
  nop
  leave
  ret
```

assistant: ```c
void WaitFor(long lPort, char cWaitChar) {
  char cChar;
  while (1) {
    cChar = _ReceiveChar(lPort);
    if (cChar == cWaitChar) {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<WaitFor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
L8:
  mov    %rbp,%rdi
  call   <_ReceiveChar@plt>
  cmp    %bl,%al
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void WaitFor(long lPort, char cWaitChar) {
  char cChar;
  while (1) {
    cChar = _ReceiveChar(lPort);
    if (cChar == cWaitChar) {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<WaitFor>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nop
L2:
  mov    %rbp,%rdi
  call   <_ReceiveChar@plt>
  cmp    %bl,%al
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void WaitFor(long lPort, char cWaitChar) {
  char cChar;
  while (1) {
    cChar = _ReceiveChar(lPort);
    if (cChar == cWaitChar) {
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<WaitFor>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nop
L8:
  mov    %rbp,%rdi
  call   <_ReceiveChar@plt>
  cmp    %bl,%al
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void WaitFor(long lPort, char cWaitChar) {
  char cChar;
  while (1) {
    cChar = _ReceiveChar(lPort);
    if (cChar == cWaitChar) {
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8d,-0x48(%rbp)
  mov    -0x34(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x20(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L9:
  mov    -0x24(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  je     L10
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L10
  mov    -0x44(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x38(%rbp),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <find_max>
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L10
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L10:
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  mov    -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int find_max(int n, bool a[n][n], int node, int cur_len, int prev_node) {
  int j, length = 0, temp = -1;
  for (j = 0; j < n; j++)
    if (j != prev_node)
      if (a[node][j]) {
        temp = 1 + find_max(n, a, j, cur_len + 1, node);
        if (temp > length)
          length = temp;
      }
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_max>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    %edx,0x8(%rsp)
  mov    $0x0,%r13d
  test   %edi,%edi
  jle    L38
  mov    %edi,%ebp
  mov    %edx,%eax
  mov    %r8d,%r12d
  movslq %edi,%rdx
  cltq
  imul   %rdx,%rax
  lea    (%rsi,%rax,4),%r15
  mov    %edi,%r14d
  mov    $0x0,%ebx
  lea    0x1(%rcx),%eax
  mov    %eax,0xc(%rsp)
  jmp    L21
L26:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L38
L21:
  mov    %ebx,%edx
  cmp    %ebx,%r12d
  je     L26
  cmpl   $0x0,(%r15,%rbx,4)
  je     L26
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    (%rsp),%rsi
  mov    %ebp,%edi
  call   <find_max>
  add    $0x1,%eax
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  jmp    L26
L38:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int find_max(int n, bool a[n][n], int node, int cur_len, int prev_node) {
  int j, length = 0, temp = -1;
  for (j = 0; j < n; j++)
    if (j != prev_node)
      if (a[node][j]) {
        temp = 1 + find_max(n, a, j, cur_len + 1, node);
        if (temp > length)
          length = temp;
      }
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_max>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  movslq %edi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %r14d,%r14d
  jle    L5
  movslq %edx,%rax
  mov    %r14,%r12
  mov    %edx,%r9d
  mov    %r8d,%ebp
  imul   %r14,%rax
  xor    %ebx,%ebx
  lea    0x1(%rcx),%r13d
  lea    (%rsi,%rax,4),%r10
L8:
  mov    %ebx,%edx
  cmp    %ebx,%ebp
  je     L1
  mov    (%r10,%rbx,4),%eax
  test   %eax,%eax
  jne    L9
L1:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L8
L5:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %r9d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edi
  mov    %r10,0x18(%rsp)
  mov    %r9d,0x14(%rsp)
  mov    %rsi,0x8(%rsp)
  call   <find_max>
  mov    0x18(%rsp),%r10
  mov    0x14(%rsp),%r9d
  add    $0x1,%eax
  mov    0x8(%rsp),%rsi
  cmp    %eax,%r15d
  cmovl  %eax,%r15d
  jmp    L1
```

assistant: ```c
int find_max(int n, bool a[n][n], int node, int cur_len, int prev_node) {
  int j, length = 0, temp = -1;
  for (j = 0; j < n; j++)
    if (j != prev_node)
      if (a[node][j]) {
        temp = 1 + find_max(n, a, j, cur_len + 1, node);
        if (temp > length)
          length = temp;
      }
  return length;
}
```