user: What would the C source look like for the assembly code provided here:

```asm
<dump_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  lea    -0x60(%rbp),%rax
  mov    $0x4f,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,-0x11(%rbp)
  movl   $0x0,-0x68(%rbp)
  jmp    L20
L68:
  mov    -0x68(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L67
  cmpl   $0x0,-0x64(%rbp)
  je     L82
  movb   $0x20,-0x2b(%rbp)
  movb   $0x20,-0x2a(%rbp)
  movb   $0x20,-0x29(%rbp)
  movb   $0x0,-0x17(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <log_info@plt>
L82:
  lea    -0x60(%rbp),%rax
  mov    $0x4f,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,-0x11(%rbp)
  mov    -0x68(%rbp),%edx
  lea    -0x60(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movl   $0x4,-0x64(%rbp)
  jmp    L83
L67:
  mov    -0x68(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L83
  mov    -0x64(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x64(%rbp)
  cltq
  movb   $0x20,-0x60(%rbp,%rax,1)
L83:
  mov    -0x68(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %eax,%eax
  je     L41
  mov    -0x68(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x68(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  add    $0x38,%eax
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  jmp    L4
L41:
  mov    -0x68(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  add    $0x38,%eax
  cltq
  movb   $0x2e,-0x60(%rbp,%rax,1)
L4:
  mov    -0x68(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    -0x60(%rbp),%rcx
  mov    -0x64(%rbp),%edx
  movslq %edx,%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  addl   $0x3,-0x64(%rbp)
  mov    -0x64(%rbp),%eax
  cltq
  movb   $0x20,-0x60(%rbp,%rax,1)
  addl   $0x1,-0x68(%rbp)
L20:
  mov    -0x68(%rbp),%eax
  cmp    %eax,-0x7c(%rbp)
  ja     L68
  movb   $0x20,-0x2b(%rbp)
  movb   $0x20,-0x2a(%rbp)
  movb   $0x20,-0x29(%rbp)
  movb   $0x0,-0x17(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <log_info@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D3: %03x:

tool: D13:  %02x

assistant: ```c
void dump_raw(buf, len) const unsigned char *buf;
unsigned len;
{
  int i;
  char lbuf[80];
  int lbix = 0;
  memset(lbuf, ' ', 79);
  lbuf[79] = 0;
  for (i = 0; i < len; i++) {
    if ((i & 15) == 0) {
      if (lbix) {
        lbuf[53] = ' ';
        lbuf[54] = ' ';
        lbuf[55] = ' ';
        lbuf[73] = '\0';
        log_info(lbuf);
      }
      memset(lbuf, ' ', 79);
      lbuf[79] = 0;
      sprintf(lbuf, "%03x:", i);
      lbix = 4;
    } else if ((i & 7) == 0)
      lbuf[lbix++] = ' ';
    if (isprint(buf[i])) {
      lbuf[56 + (i % 16)] = buf[i];
    } else {
      lbuf[56 + (i % 16)] = '.';
    }
    sprintf(&lbuf[lbix], " %02x", buf[i]);
    lbix += 3;
    lbuf[lbix] = ' ';
  }
  lbuf[53] = ' ';
  lbuf[54] = ' ';
  lbuf[55] = ' ';
  lbuf[73] = '\0';
  log_info(lbuf);
}
```