ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L6
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%ebx
  jmp    L18
L39:
  add    $0x1,%ebx
L18:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  je     L39
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: string

tool: D13: %d

assistant: ```c
int main() {
  int a, b, n, i, c = 0, d, x = 0;
  scanf("%d", &n);
  a = check_prime(n);
  if (a == 0) {
    for (i = n + 1; 1; i++) {
      b = check_prime(i);
      if (b != 0) {
        printf("%d", b);
        break;
      }
    }
  } else
    printf("%d", a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L23
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%ebx
  jmp    L2
  nopl   0x0(%rax)
L33:
  add    $0x1,%ebx
L2:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  je     L33
L23:
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int main() {
  int a, b, n, i, c = 0, d, x = 0;
  scanf("%d", &n);
  a = check_prime(n);
  if (a == 0) {
    for (i = n + 1; 1; i++) {
      b = check_prime(i);
      if (b != 0) {
        printf("%d", b);
        break;
      }
    }
  } else
    printf("%d", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L6
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%ebx
  jmp    L14
  nopl   0x0(%rax)
L10:
  add    $0x1,%ebx
L14:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  je     L10
L6:
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int a, b, n, i, c = 0, d, x = 0;
  scanf("%d", &n);
  a = check_prime(n);
  if (a == 0) {
    for (i = n + 1; 1; i++) {
      b = check_prime(i);
      if (b != 0) {
        printf("%d", b);
        break;
      }
    }
  } else
    printf("%d", a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L13:
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L24:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: %d 

assistant: ```c
void print_matrix(int **matrix, int n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      printf("%d ", matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r14
  mov    %esi,%esi
  lea    0x0(,%rsi,4),%r12
  lea    D8(%rip),%r13
L21:
  mov    $0x0,%ebx
L25:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
void print_matrix(int **matrix, int n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      printf("%d ", matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %r14
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  mov    %rdi,%r14
  push   %r13
  lea    0x8(%rdi,%rax,8),%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  nopl   0x0(%rax)
L17:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%r14),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L26
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r13,%r14
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: %d 

assistant: ```c
void print_matrix(int **matrix, int n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      printf("%d ", matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r14
  lea    -0x1(%rsi),%eax
  mov    %esi,%esi
  mov    %rdi,%r14
  push   %r13
  lea    0x8(%rdi,%rax,8),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  nopl   0x0(%rax)
L14:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%r14),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L2
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r13,%r14
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: %d 

assistant: ```c
void print_matrix(int **matrix, int n) {
  int i, j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      printf("%d ", matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stringmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  je     L44
  mov    $0x0,%eax
  jmp    L29
L44:
  movq   $0x0,-0x18(%rbp)
  jmp    L49
L50:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L17
  mov    $0x0,%eax
  jmp    L29
L17:
  nop
  addq   $0x1,-0x18(%rbp)
L49:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  cmpq   $0xff,-0x18(%rbp)
  jbe    L50
L79:
  mov    $0x1,%eax
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char stringmatch(char *str1, char *str2) {
  uint8_t i;
  if (strlen(str1) != strlen(str2)) {
    return 0;
  }
  for (i = 0; str1[i] != '\0' && str2[i] != '\0' && i < 256; i++) {
    if (*(str1 + i) == *(str2 + i)) {
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringmatch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jne    L78
  movzbl (%rbx),%eax
  test   %al,%al
  je     L65
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L28
  mov    $0x0,%ecx
L47:
  cmp    %dl,%al
  je     L26
  mov    $0x0,%eax
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%eax
  test   %al,%al
  je     L69
  movzbl 0x0(%rbp,%rcx,1),%edx
  cmp    $0xff,%rcx
  ja     L37
  test   %dl,%dl
  jne    L47
L37:
  mov    $0x1,%eax
  jmp    L78
L65:
  mov    $0x1,%eax
  jmp    L78
L28:
  mov    $0x1,%eax
  jmp    L78
L69:
  mov    $0x1,%eax
  jmp    L78
```

assistant: ```c
char stringmatch(char *str1, char *str2) {
  uint8_t i;
  if (strlen(str1) != strlen(str2)) {
    return 0;
  }
  for (i = 0; str1[i] != '\0' && str2[i] != '\0' && i < 256; i++) {
    if (*(str1 + i) == *(str2 + i)) {
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stringmatch>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jne    L65
  movzbl (%rbx),%eax
  test   %al,%al
  je     L74
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L74
  xor    %ecx,%ecx
L38:
  cmp    %dl,%al
  je     L5
  xor    %eax,%eax
L65:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%eax
  test   %al,%al
  je     L74
  movzbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  je     L74
  cmp    $0x100,%rcx
  jne    L38
  cs nopw 0x0(%rax,%rax,1)
L74:
  mov    $0x1,%eax
  jmp    L65
```

assistant: ```c
char stringmatch(char *str1, char *str2) {
  uint8_t i;
  if (strlen(str1) != strlen(str2)) {
    return 0;
  }
  for (i = 0; str1[i] != '\0' && str2[i] != '\0' && i < 256; i++) {
    if (*(str1 + i) == *(str2 + i)) {
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stringmatch>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jne    L62
  movzbl (%rbx),%eax
  test   %al,%al
  je     L45
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L45
  xor    %ecx,%ecx
L43:
  cmp    %dl,%al
  je     L15
  xor    %eax,%eax
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  add    $0x1,%rcx
  movzbl (%rbx,%rcx,1),%eax
  test   %al,%al
  je     L45
  movzbl 0x0(%rbp,%rcx,1),%edx
  test   %dl,%dl
  je     L45
  cmp    $0x100,%rcx
  jne    L43
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    $0x1,%eax
  jmp    L62
```

assistant: ```c
char stringmatch(char *str1, char *str2) {
  uint8_t i;
  if (strlen(str1) != strlen(str2)) {
    return 0;
  }
  for (i = 0; str1[i] != '\0' && str2[i] != '\0' && i < 256; i++) {
    if (*(str1 + i) == *(str2 + i)) {
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bad_if_not_alias>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L14
  movb   $0x42,-0x8(%rbp)
L14:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void bad_if_not_alias(int *x, int *y) {
  char a[1];
  if (x != y) {
    a[1] = 'B';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bad_if_not_alias>:
  endbr64
  ret
```

assistant: ```c
void bad_if_not_alias(int *x, int *y) {
  char a[1];
  if (x != y) {
    a[1] = 'B';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bad_if_not_alias>:
  endbr64
  ret
```

assistant: ```c
void bad_if_not_alias(int *x, int *y) {
  char a[1];
  if (x != y) {
    a[1] = 'B';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_mem2Ddouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L28
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <no_mem_exit@plt>
L28:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,(%rax)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L3
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <no_mem_exit@plt>
L3:
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  add    %rsi,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  shl    $0x3,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string

tool: D19: get_mem2Ddouble: array2D

assistant: ```c
int get_mem2Ddouble(double ***array2D, int rows, int columns) {
  int i;
  if ((*array2D = (double **)calloc(rows, sizeof(double *))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  if (((*array2D)[0] = (double *)calloc(rows * columns, sizeof(double))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  for (i = 1; i < rows; i++)
    (*array2D)[i] = (*array2D)[i - 1] + columns;
  return rows * columns * sizeof(double);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_mem2Ddouble>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    $0x8,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L37
L33:
  mov    %r13d,%ebp
  imul   %r12d,%ebp
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    (%rbx),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  je     L12
L26:
  cmp    $0x1,%r13d
  jle    L27
  movslq %r12d,%rsi
  shl    $0x3,%rsi
  lea    -0x1(%r13),%edi
  shl    $0x3,%rdi
  mov    $0x0,%eax
L3:
  mov    (%rbx),%rdx
  mov    %rax,%rcx
  add    $0x8,%rax
  mov    %rsi,%r8
  add    (%rdx,%rcx,1),%r8
  mov    %r8,(%rdx,%rax,1)
  cmp    %rdi,%rax
  jne    L3
L27:
  lea    0x0(,%rbp,8),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  lea    D6(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L33
L12:
  lea    D6(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L26
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: get_mem2Ddouble: array2D

assistant: ```c
int get_mem2Ddouble(double ***array2D, int rows, int columns) {
  int i;
  if ((*array2D = (double **)calloc(rows, sizeof(double *))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  if (((*array2D)[0] = (double *)calloc(rows * columns, sizeof(double))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  for (i = 1; i < rows; i++)
    (*array2D)[i] = (*array2D)[i - 1] + columns;
  return rows * columns * sizeof(double);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_mem2Ddouble>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L34
L15:
  mov    %ebp,%r13d
  mov    $0x8,%esi
  imul   %ebx,%r13d
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    (%r12),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  je     L10
L13:
  cmp    $0x1,%ebp
  jle    L12
  mov    (%r12),%rdx
  movslq %ebx,%rsi
  lea    -0x2(%rbp),%ecx
  shl    $0x3,%rsi
  lea    0x8(%rdx),%rax
  lea    (%rax,%rcx,8),%rdi
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L47:
  add    $0x8,%rax
L53:
  mov    (%rdx),%rcx
  add    %rsi,%rcx
  mov    %rcx,0x8(%rdx)
  mov    %rax,%rdx
  cmp    %rdi,%rax
  jne    L47
L12:
  add    $0x8,%rsp
  lea    0x0(,%r13,8),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L34:
  lea    D2(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L15
  nopl   0x0(%rax)
L10:
  lea    D2(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: get_mem2Ddouble: array2D

assistant: ```c
int get_mem2Ddouble(double ***array2D, int rows, int columns) {
  int i;
  if ((*array2D = (double **)calloc(rows, sizeof(double *))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  if (((*array2D)[0] = (double *)calloc(rows * columns, sizeof(double))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  for (i = 1; i < rows; i++)
    (*array2D)[i] = (*array2D)[i - 1] + columns;
  return rows * columns * sizeof(double);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_mem2Ddouble>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  mov    %ebp,%edi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L33
L27:
  mov    %ebp,%r13d
  mov    $0x8,%esi
  imul   %ebx,%r13d
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    (%r12),%rdx
  mov    %rax,(%rdx)
  test   %rax,%rax
  je     L9
L32:
  cmp    $0x1,%ebp
  jle    L7
  mov    (%r12),%rsi
  movslq %ebx,%rcx
  lea    -0x2(%rbp),%edi
  shl    $0x3,%rcx
  mov    (%rsi),%rdx
  lea    0x8(%rsi),%rax
  lea    0x10(%rsi,%rdi,8),%rsi
  nopl   0x0(%rax)
L26:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L26
L7:
  add    $0x8,%rsp
  lea    0x0(,%r13,8),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D11(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L9:
  lea    D11(%rip),%rdi
  call   <no_mem_exit@plt>
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D11: get_mem2Ddouble: array2D

assistant: ```c
int get_mem2Ddouble(double ***array2D, int rows, int columns) {
  int i;
  if ((*array2D = (double **)calloc(rows, sizeof(double *))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  if (((*array2D)[0] = (double *)calloc(rows * columns, sizeof(double))) == NULL)
    no_mem_exit("get_mem2Ddouble: array2D");
  for (i = 1; i < rows; i++)
    (*array2D)[i] = (*array2D)[i - 1] + columns;
  return rows * columns * sizeof(double);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_data_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x40(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    $0x14,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fopen_read@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L17
L21:
  movl   $0x0,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L22
L43:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  mov    -0x24(%rbp),%edx
  mov    %edx,%ecx
  imul   -0x40(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x48(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x20(%rbp)
L22:
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  mov    -0x20(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L43
L50:
  addl   $0x1,-0x24(%rbp)
  mov    -0x18(%rbp),%r8
  mov    -0x40(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <test_column@plt>
L17:
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L3
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L21
L3:
  mov    -0x3c(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <test_line@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D18:  	


assistant: ```c
void read_data_int(char *file_data, int N, int M, int *dat) {
  FILE *m_File = NULL;
  int i = 0;
  int j = 0;
  int max_char_per_line = 5 * M + 20;
  char *szbuff;
  char *token;
  szbuff = (char *)malloc(max_char_per_line * sizeof(char));
  m_File = fopen_read(file_data);
  i = 0;
  while (fgets(szbuff, max_char_per_line, m_File) && (i < N)) {
    j = 0;
    token = strtok(szbuff, " \t\n");
    while (token && j < M) {
      dat[i * M + j] = (int)atof(token);
      token = strtok(NULL, " \t\n");
      j++;
    }
    i++;
    test_column(file_data, m_File, j, i, M, token);
  }
  test_line(file_data, m_File, i, N);
  fclose(m_File);
  free(szbuff);
}
```