ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<days_last_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  mov    -0x10(%rbp),%eax
  add    $0x76b,%eax
  mov    %eax,%edi
  call   <leap@plt>
  test   %rax,%rax
  je     L3
  mov    $0x16e,%eax
  jmp    L22
L3:
  mov    $0x16d,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int days_last_year(void) {
  struct tm time_record;
  time_t current_time;
  time(&current_time);
  localtime_r(&current_time, &time_record);
  if (leap(time_record.tm_year - 1 + 1900)) {
    return 366;
  }
  return 365;
}
```
user: What is the c source code of the assembly code below:

```asm
<days_last_year>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <localtime_r@plt>
  mov    (%rsp),%eax
  lea    0x76b(%rax),%edi
  call   <leap@plt>
  cmp    $0x1,%rax
  mov    $0x16d,%eax
  sbb    $0xffffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int days_last_year(void) {
  struct tm time_record;
  time_t current_time;
  time(&current_time);
  localtime_r(&current_time, &time_record);
  if (leap(time_record.tm_year - 1 + 1900)) {
    return 366;
  }
  return 365;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<days_last_year>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    (%rsp),%eax
  lea    0x76b(%rax),%edi
  call   <leap@plt>
  cmp    $0x1,%rax
  mov    $0x16d,%eax
  sbb    $0xffffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int days_last_year(void) {
  struct tm time_record;
  time_t current_time;
  time(&current_time);
  localtime_r(&current_time, &time_record);
  if (leap(time_record.tm_year - 1 + 1900)) {
    return 366;
  }
  return 365;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<days_last_year>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  mov    (%rsp),%eax
  lea    0x76b(%rax),%edi
  call   <leap@plt>
  cmp    $0x1,%rax
  mov    $0x16d,%eax
  sbb    $0xffffffff,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int days_last_year(void) {
  struct tm time_record;
  time_t current_time;
  time(&current_time);
  localtime_r(&current_time, &time_record);
  if (leap(time_record.tm_year - 1 + 1900)) {
    return 366;
  }
  return 365;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
L10:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L16
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c;
  c = getchar();
  while (c != EOF) {
    putchar(c);
    c = getchar();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D0(%rip),%rax
  cmp    (%rax),%edi
  je     L11
L19:
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D0(%rip),%rax
  cmp    %edi,(%rax)
  jne    L19
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int c;
  c = getchar();
  while (c != EOF) {
    putchar(c);
    c = getchar();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rbx
  cmp    (%rbx),%eax
  je     L8
  mov    %eax,%edi
  nopl   0x0(%rax)
L5:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L5
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int c;
  c = getchar();
  while (c != EOF) {
    putchar(c);
    c = getchar();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rbx
  cmp    (%rbx),%eax
  je     L15
  mov    %eax,%edi
  nopl   0x0(%rax)
L11:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L11
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int c;
  c = getchar();
  while (c != EOF) {
    putchar(c);
    c = getchar();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0x8(%rbp)
  jne    L18
  cmpl   $0x0,-0x4(%rbp)
  jne    L45
  cmpl   $0x0,-0x8(%rbp)
  jne    L15
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L54
L15:
  mov    $0x0,%eax
L54:
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L42
L18:
  nop
  jmp    L42
L45:
  nop
L42:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i, j;
  if (i)
    goto l;
  if (j)
    goto l;
  assert(!i && !j);
l:;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j;
  if (i)
    goto l;
  if (j)
    goto l;
  assert(!i && !j);
l:;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j;
  if (i)
    goto l;
  if (j)
    goto l;
  assert(!i && !j);
l:;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i, j;
  if (i)
    goto l;
  if (j)
    goto l;
  assert(!i && !j);
l:;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_69_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_69_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_69_1_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edx,%eax
  mov    %esi,%edx
  or     (%rdi),%dl
  or     %edx,%eax
  not    %eax
  mov    %esi,%edx
  and    (%rdi),%dl
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_69_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_69_1_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edx,%eax
  movzbl (%rdi),%edx
  or     %esi,%edx
  or     %edx,%eax
  movzbl (%rdi),%edx
  not    %eax
  and    %esi,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_69_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_69_1_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    %edx,%eax
  movzbl (%rdi),%edx
  or     %esi,%edx
  or     %edx,%eax
  movzbl (%rdi),%edx
  not    %eax
  and    %esi,%edx
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_69_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = *D | stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lin_hgN>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r10
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    D8(%rip),%rdi
  mov    %rdi,0x10(%rsp)
  test   %ecx,%ecx
  jle    L14
  mov    %rsi,%r11
  mov    %rax,%rbx
  lea    0x58(%rsi),%rsi
  add    $0xa0,%r11
  lea    -0x1(%rcx),%edx
  lea    0x4(%rax,%rdx,4),%rbp
  movq   %rdi,%xmm7
  movq   D19(%rip),%xmm6
  movq   %rdi,%xmm5
  movapd %xmm6,%xmm4
  jmp    L39
L37:
  add    $0x4,%rbx
  add    $0x90,%rsi
  add    $0x90,%r11
  cmp    %rbx,%rbp
  je     L14
L39:
  mov    (%rbx),%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  cltq
  lea    (%r10,%rax,8),%rax
  movsd  (%r8),%xmm0
  movapd %xmm0,%xmm2
  mulsd  (%rax),%xmm2
  addsd  0x8(%r8),%xmm2
  mulsd  0x8(%rax),%xmm0
  addsd  0x10(%r8),%xmm0
  movsd  (%r9),%xmm1
  movapd %xmm1,%xmm3
  mulsd  0x18(%rax),%xmm3
  addsd  0x8(%r9),%xmm3
  movsd  %xmm3,(%rsp)
  mulsd  0x20(%rax),%xmm1
  addsd  0x10(%r9),%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    %rsi,%rax
  movsd  %xmm3,-0x58(%rsi)
  movsd  %xmm1,-0x40(%rsi)
  movsd  %xmm7,-0x28(%rsi)
  movq   $0x0,-0x50(%rsi)
  movq   $0x0,-0x38(%rsi)
  movq   $0x0,-0x20(%rsi)
  lea    -0x48(%rsi),%rdx
  mov    %rsp,%rcx
  mov    %rcx,%rdi
  xorpd  %xmm6,%xmm2
L12:
  movapd %xmm2,%xmm8
  mulsd  (%rdi),%xmm8
  movsd  %xmm8,(%rdx)
  add    $0x18,%rdx
  add    $0x8,%rdi
  cmp    %rax,%rdx
  jne    L12
  movq   $0x0,-0x10(%rax)
  movq   $0x0,0x8(%rax)
  movq   $0x0,0x20(%rax)
  movsd  %xmm3,-0x8(%rax)
  movsd  %xmm1,0x10(%rax)
  movsd  %xmm5,0x28(%rax)
  xorpd  %xmm4,%xmm0
L24:
  movapd %xmm0,%xmm1
  mulsd  (%rcx),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x18,%rax
  add    $0x8,%rcx
  cmp    %r11,%rax
  jne    L24
  jmp    L37
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: byte[8]
name: read_data
arguments: data_label: D19
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void lin_hgN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, j;
  a[2] = 1;
  b[2] = 1;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[0] * b[j];
    p -= 2;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[1] * b[j];
    p -= 2;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lin_hgN>:
  endbr64
  mov    %rsi,%rax
  test   %ecx,%ecx
  jle    L7
  sub    $0x1,%ecx
  movsd  D18(%rip),%xmm5
  movq   D17(%rip),%xmm4
  lea    0x4(%rdx,%rcx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rdx),%ecx
  movsd  (%r8),%xmm1
  add    $0x4,%rdx
  add    $0x90,%rax
  movsd  (%r9),%xmm0
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,8),%rcx
  movsd  (%rcx),%xmm3
  movsd  0x18(%rcx),%xmm2
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  0x8(%r8),%xmm3
  addsd  0x8(%r9),%xmm2
  mulsd  0x8(%rcx),%xmm1
  mulsd  0x20(%rcx),%xmm0
  addsd  0x10(%r8),%xmm1
  xorpd  %xmm4,%xmm3
  addsd  0x10(%r9),%xmm0
  movsd  %xmm5,-0x60(%rax)
  movapd %xmm2,%xmm6
  movsd  %xmm2,-0x40(%rax)
  mulsd  %xmm3,%xmm6
  xorpd  %xmm4,%xmm1
  movsd  %xmm2,-0x90(%rax)
  movsd  %xmm0,-0x78(%rax)
  mulsd  %xmm1,%xmm2
  movsd  %xmm0,-0x28(%rax)
  movq   $0x0,-0x88(%rax)
  movq   $0x0,-0x70(%rax)
  movsd  %xmm6,-0x80(%rax)
  movapd %xmm0,%xmm6
  mulsd  %xmm3,%xmm6
  movq   $0x0,-0x58(%rax)
  mulsd  %xmm1,%xmm0
  movsd  %xmm3,-0x50(%rax)
  movq   $0x0,-0x48(%rax)
  movq   $0x0,-0x30(%rax)
  movq   $0x0,-0x18(%rax)
  movsd  %xmm6,-0x68(%rax)
  movsd  %xmm5,-0x10(%rax)
  movsd  %xmm2,-0x38(%rax)
  movsd  %xmm0,-0x20(%rax)
  movsd  %xmm1,-0x8(%rax)
  cmp    %rdx,%rsi
  jne    L12
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D17
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void lin_hgN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, j;
  a[2] = 1;
  b[2] = 1;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[0] * b[j];
    p -= 2;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[1] * b[j];
    p -= 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_hgN>:
  endbr64
  mov    %rsi,%rax
  test   %ecx,%ecx
  jle    L3
  sub    $0x1,%ecx
  movsd  D0(%rip),%xmm5
  movq   D18(%rip),%xmm4
  lea    0x4(%rdx,%rcx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rdx),%ecx
  movsd  (%r8),%xmm1
  add    $0x90,%rax
  add    $0x4,%rdx
  movsd  (%r9),%xmm0
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,8),%rcx
  movsd  (%rcx),%xmm3
  movsd  0x18(%rcx),%xmm2
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  0x8(%r8),%xmm3
  addsd  0x8(%r9),%xmm2
  mulsd  0x20(%rcx),%xmm0
  addsd  0x10(%r9),%xmm0
  mulsd  0x8(%rcx),%xmm1
  xorpd  %xmm4,%xmm3
  addsd  0x10(%r8),%xmm1
  movsd  %xmm5,-0x60(%rax)
  movapd %xmm2,%xmm6
  movq   $0x0,-0x70(%rax)
  mulsd  %xmm3,%xmm6
  movq   $0x0,-0x58(%rax)
  movq   $0x0,-0x88(%rax)
  xorpd  %xmm4,%xmm1
  movq   $0x0,-0x48(%rax)
  movq   $0x0,-0x30(%rax)
  movq   $0x0,-0x18(%rax)
  movsd  %xmm6,-0x80(%rax)
  movapd %xmm0,%xmm6
  mulsd  %xmm3,%xmm6
  movsd  %xmm2,-0x90(%rax)
  movsd  %xmm0,-0x78(%rax)
  movsd  %xmm3,-0x50(%rax)
  movsd  %xmm6,-0x68(%rax)
  movsd  %xmm2,-0x40(%rax)
  mulsd  %xmm1,%xmm2
  movsd  %xmm0,-0x28(%rax)
  mulsd  %xmm1,%xmm0
  movsd  %xmm5,-0x10(%rax)
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm2,-0x38(%rax)
  movsd  %xmm0,-0x20(%rax)
  cmp    %rdx,%rsi
  jne    L10
L3:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: byte[8]
name: parse_data
arguments: data_tag: D18
type: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void lin_hgN(const double *u, double *p, const int *inl, int len, double *A1, double *A2) {
  const double *s;
  double a[3], b[3];
  int i, j;
  a[2] = 1;
  b[2] = 1;
  for (i = 0; i < len; i++) {
    s = u + 6 * inl[i];
    a[0] = *(s)*A1[0] + A1[1];
    a[1] = *(s + 1) * A1[0] + A1[2];
    b[0] = *(s + 3) * A2[0] + A2[1];
    b[1] = *(s + 4) * A2[0] + A2[2];
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[0] * b[j];
    p -= 2;
    for (j = 0; j < 3; j++, p += 3)
      *p = 0;
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = b[j];
    p -= 8;
    for (j = 0; j < 3; j++, p += 3)
      *p = -a[1] * b[j];
    p -= 2;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L23
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jg     L2
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L2:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D36
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D37: %d

tool: D36: %d


tool: D14: sem multiplos menores que %d

assistant: ```c
int main() {
  int num1, num2;
  scanf("%d", &num1);
  scanf("%d", &num2);
  if (num1 > num2) {
    int temp = num1;
    num1 = num2;
    num2 = temp;
  }
  int multiplo = (num2 / num1) * num1;
  if (multiplo <= num2)
    printf("%d\n", multiplo);
  else
    printf("sem multiplos menores que %d", num2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    %edx,%eax
  jle    L18
  mov    %edx,(%rsp)
  mov    %eax,0x4(%rsp)
L18:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  cmp    %eax,%esi
  jl     L37
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L37:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D20: %d

tool: D10: %d


tool: D9: sem multiplos menores que %d

assistant: ```c
int main() {
  int num1, num2;
  scanf("%d", &num1);
  scanf("%d", &num2);
  if (num1 > num2) {
    int temp = num1;
    num1 = num2;
    num2 = temp;
  }
  int multiplo = (num2 / num1) * num1;
  if (multiplo <= num2)
    printf("%d\n", multiplo);
  else
    printf("sem multiplos menores que %d", num2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%esi
  cmp    %esi,%ecx
  jle    L9
  mov    %ecx,%eax
  mov    %esi,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %esi,%ecx
  mov    %eax,%esi
L9:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  cmp    %eax,%esi
  jl     L6
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D0: %d

tool: D5: %d


tool: D18: sem multiplos menores que %d

assistant: ```c
int main() {
  int num1, num2;
  scanf("%d", &num1);
  scanf("%d", &num2);
  if (num1 > num2) {
    int temp = num1;
    num1 = num2;
    num2 = temp;
  }
  int multiplo = (num2 / num1) * num1;
  if (multiplo <= num2)
    printf("%d\n", multiplo);
  else
    printf("sem multiplos menores que %d", num2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%esi
  cmp    %esi,%ecx
  jle    L4
  mov    %ecx,%eax
  mov    %esi,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %esi,%ecx
  mov    %eax,%esi
L4:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  imul   %ecx,%eax
  cmp    %eax,%esi
  jl     L21
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L21:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D26: %d

tool: D19: %d


tool: D16: sem multiplos menores que %d

assistant: ```c
int main() {
  int num1, num2;
  scanf("%d", &num1);
  scanf("%d", &num2);
  if (num1 > num2) {
    int temp = num1;
    num1 = num2;
    num2 = temp;
  }
  int multiplo = (num2 / num1) * num1;
  if (multiplo <= num2)
    printf("%d\n", multiplo);
  else
    printf("sem multiplos menores que %d", num2);
}
```