ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binario_para_decimal>:
  endbr64
  sub    $0x1,%edx
  cmp    %esi,%edx
  jl     L3
  movslq %edx,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  cs nopw 0x0(%rax,%rax,1)
L8:
  movswl (%rdi,%rdx,2),%eax
  sub    $0x1,%rdx
  imul   %ecx,%eax
  add    %ecx,%ecx
  add    %eax,%r8d
  cmp    %edx,%esi
  jle    L8
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int binario_para_decimal(short *binarios, int inicio, int fim) {
  int i, n = 1;
  int valorNumerico = 0;
  for (i = fim - 1; i >= inicio; i--, n = n << 1) {
    valorNumerico += n * (binarios[i]);
  }
  return valorNumerico;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binario_para_decimal>:
  endbr64
  sub    $0x1,%edx
  cmp    %esi,%edx
  jl     L1
  movslq %edx,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movswl (%rdi,%rdx,2),%eax
  sub    $0x1,%rdx
  imul   %ecx,%eax
  add    %ecx,%ecx
  add    %eax,%r8d
  cmp    %edx,%esi
  jle    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int binario_para_decimal(short *binarios, int inicio, int fim) {
  int i, n = 1;
  int valorNumerico = 0;
  for (i = fim - 1; i >= inicio; i--, n = n << 1) {
    valorNumerico += n * (binarios[i]);
  }
  return valorNumerico;
}
```
user: What is the c source code of the assembly code below?

```asm
<DumpDecodedBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L26:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L10:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x7,-0x4(%rbp)
  jle    L10
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x7,-0x8(%rbp)
  jle    L26
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
data_type: string
name: unpack_data
arguments: data_tag: D16
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D21: # Decoded 8x8 Block#


tool: D16: %2x 

tool: D18: 


assistant: ```c
void DumpDecodedBlock(int val[8][8]) {
  dprintf("# Decoded 8x8 Block#\n");
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      dprintf("%2x ", val[x][y]);
    }
    dprintf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DumpDecodedBlock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  lea    0x100(%r13),%rbp
  add    $0x120,%r13
  lea    D5(%rip),%r12
  lea    D1(%rip),%r14
L1:
  lea    -0x100(%rbp),%rbx
L8:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  add    $0x20,%rbx
  cmp    %rbp,%rbx
  jne    L8
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <dprintf@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D1
type: string

tool: D16: # Decoded 8x8 Block#


tool: D5: %2x 

tool: D1: 


assistant: ```c
void DumpDecodedBlock(int val[8][8]) {
  dprintf("# Decoded 8x8 Block#\n");
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      dprintf("%2x ", val[x][y]);
    }
    dprintf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DumpDecodedBlock>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D13(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  lea    D18(%rip),%rdi
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    0x100(%r13),%rbp
  add    $0x120,%r13
  push   %rbx
  call   <dprintf@plt>
  nopl   0x0(%rax)
L17:
  lea    -0x100(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x20,%rbx
  call   <dprintf@plt>
  cmp    %rbp,%rbx
  jne    L12
  mov    %r14,%rdi
  xor    %eax,%eax
  lea    0x4(%rbx),%rbp
  call   <dprintf@plt>
  cmp    %r13,%rbp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D13
data_type: string
name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D13: 


tool: D18: # Decoded 8x8 Block#


tool: D2: %2x 

assistant: ```c
void DumpDecodedBlock(int val[8][8]) {
  dprintf("# Decoded 8x8 Block#\n");
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      dprintf("%2x ", val[x][y]);
    }
    dprintf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DumpDecodedBlock>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D11(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  lea    D5(%rip),%rdi
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    0x100(%r13),%rbp
  add    $0x120,%r13
  push   %rbx
  call   <dprintf@plt>
  nopl   0x0(%rax)
L0:
  lea    -0x100(%rbp),%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x20,%rbx
  call   <dprintf@plt>
  cmp    %rbp,%rbx
  jne    L6
  mov    %r14,%rdi
  xor    %eax,%eax
  lea    0x4(%rbx),%rbp
  call   <dprintf@plt>
  cmp    %r13,%rbp
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string

tool: D11: 


tool: D5: # Decoded 8x8 Block#


tool: D25: %2x 

assistant: ```c
void DumpDecodedBlock(int val[8][8]) {
  dprintf("# Decoded 8x8 Block#\n");
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      dprintf("%2x ", val[x][y]);
    }
    dprintf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strTolong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L8:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  add    %rax,-0x8(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  je     L1
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,-0x8(%rbp)
L1:
  addl   $0x1,-0xc(%rbp)
L16:
  cmpl   $0x3,-0xc(%rbp)
  jbe    L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long strTolong(const char *str) {
  unsigned long ret = 0;
  unsigned int i;
  for (i = 0; i < 4; i++) {
    ret += (str[i] - 'a');
    if (i != 3)
      ret *= 100;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strTolong>:
  endbr64
  movsbl (%rdi),%eax
  sub    $0x61,%eax
  cltq
  lea    0x1(%rdi),%rdx
  add    $0x4,%rdi
L3:
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rcx
  movsbl (%rdx),%eax
  sub    $0x61,%eax
  cltq
  lea    (%rax,%rcx,4),%rax
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L3
  ret
```

assistant: ```c
unsigned long strTolong(const char *str) {
  unsigned long ret = 0;
  unsigned int i;
  for (i = 0; i < 4; i++) {
    ret += (str[i] - 'a');
    if (i != 3)
      ret *= 100;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strTolong>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  add    $0x4,%rdi
  sub    $0x61,%eax
  cltq
L7:
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rdx
  lea    (%rax,%rax,4),%rcx
  movsbl -0x1(%rdx),%eax
  sub    $0x61,%eax
  cltq
  lea    (%rax,%rcx,4),%rax
  cmp    %rdi,%rdx
  jne    L7
  ret
```

assistant: ```c
unsigned long strTolong(const char *str) {
  unsigned long ret = 0;
  unsigned int i;
  for (i = 0; i < 4; i++) {
    ret += (str[i] - 'a');
    if (i != 3)
      ret *= 100;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strTolong>:
  endbr64
  movsbl (%rdi),%edx
  movsbl 0x3(%rdi),%eax
  sub    $0x61,%edx
  sub    $0x61,%eax
  movslq %edx,%rdx
  cltq
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbl 0x1(%rdi),%edx
  sub    $0x61,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbl 0x2(%rdi),%edx
  sub    $0x61,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rax
  ret
```

assistant: ```c
unsigned long strTolong(const char *str) {
  unsigned long ret = 0;
  unsigned int i;
  for (i = 0; i < 4; i++) {
    ret += (str[i] - 'a');
    if (i != 3)
      ret *= 100;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L57
L1:
  sarq   -0x10(%rbp)
L57:
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  cmp    %rax,-0x10(%rbp)
  jg     L1
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x3,-0x18(%rbp)
  jmp    L30
L10:
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L25
L32:
  addq   $0x2,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L10
  mov    $0x1,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(long i) {
  long f, d, squirt;
  for (squirt = i; i / squirt < squirt; squirt >>= 1)
    ;
  squirt = (squirt << 1) + 1;
  for (f = 3; f <= squirt; f += 2) {
    d = i / f;
    if (d * f == i) {
      return (0 != 0);
    }
  }
  return (0 == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isprime>:
  endbr64
  mov    %rdi,%rsi
  cmp    $0x1,%rdi
  jle    L42
  mov    %rdi,%rcx
L13:
  sar    %rcx
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  cmp    %rcx,%rax
  jl     L13
L43:
  lea    0x1(%rcx,%rcx,1),%rdi
  cmp    $0x2,%rdi
  jle    L15
  movabs $0x5555555555555556,%rdx
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  cmp    %rax,%rsi
  je     L22
  mov    $0x3,%ecx
L3:
  add    $0x2,%rcx
  cmp    %rcx,%rdi
  jl     L53
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  imul   %rcx,%rax
  cmp    %rsi,%rax
  jne    L3
  mov    $0x0,%eax
  ret
L42:
  mov    %rdi,%rcx
  jmp    L43
L53:
  mov    $0x1,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isprime(long i) {
  long f, d, squirt;
  for (squirt = i; i / squirt < squirt; squirt >>= 1)
    ;
  squirt = (squirt << 1) + 1;
  for (f = 3; f <= squirt; f += 2) {
    d = i / f;
    if (d * f == i) {
      return (0 != 0);
    }
  }
  return (0 == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isprime>:
  endbr64
  mov    %rdi,%rsi
  mov    %rdi,%rcx
  cmp    $0x1,%rdi
  jle    L64
L26:
  mov    %rsi,%rax
  sar    %rcx
  cqto
  idiv   %rcx
  cmp    %rcx,%rax
  jl     L26
L64:
  lea    0x1(%rcx,%rcx,1),%rdi
  cmp    $0x2,%rdi
  jle    L51
  movabs $0x5555555555555556,%rdx
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  cmp    %rax,%rsi
  je     L45
  mov    $0x3,%ecx
  jmp    L49
  nopl   (%rax)
L25:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  imul   %rcx,%rax
  cmp    %rsi,%rax
  je     L45
L49:
  add    $0x2,%rcx
  cmp    %rcx,%rdi
  jge    L25
L51:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isprime(long i) {
  long f, d, squirt;
  for (squirt = i; i / squirt < squirt; squirt >>= 1)
    ;
  squirt = (squirt << 1) + 1;
  for (f = 3; f <= squirt; f += 2) {
    d = i / f;
    if (d * f == i) {
      return (0 != 0);
    }
  }
  return (0 == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isprime>:
  endbr64
  mov    %rdi,%rsi
  mov    %rdi,%rcx
  cmp    $0x1,%rdi
  jle    L25
L42:
  mov    %rsi,%rax
  sar    %rcx
  cqto
  idiv   %rcx
  cmp    %rcx,%rax
  jl     L42
L25:
  lea    0x1(%rcx,%rcx,1),%rdi
  cmp    $0x2,%rdi
  jle    L30
  movabs $0x5555555555555556,%rdx
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  cmp    %rax,%rsi
  je     L64
  mov    $0x3,%ecx
  jmp    L0
  nopl   (%rax)
L6:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  imul   %rcx,%rax
  cmp    %rsi,%rax
  je     L64
L0:
  add    $0x2,%rcx
  cmp    %rcx,%rdi
  jge    L6
L30:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isprime(long i) {
  long f, d, squirt;
  for (squirt = i; i / squirt < squirt; squirt >>= 1)
    ;
  squirt = (squirt << 1) + 1;
  for (f = 3; f <= squirt; f += 2) {
    d = i / f;
    if (d * f == i) {
      return (0 != 0);
    }
  }
  return (0 == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strtok_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L96
  cmpq   $0x0,-0x18(%rbp)
  je     L96
  cmpq   $0x0,-0x8(%rbp)
  jne    L118
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L118
L96:
  mov    $0x0,%eax
  jmp    L103
L118:
  cmpq   $0x0,-0x8(%rbp)
  jne    L115
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L115
L52:
  addq   $0x1,-0x8(%rbp)
L115:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L52
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L114
  mov    $0x0,%eax
  jmp    L103
L114:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L31
L68:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L31:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L68
L33:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
L19:
  mov    -0x8(%rbp),%rax
L103:
  leave
  ret
```

assistant: ```c
char *strtok_s(char *str, const char *delim, char **ctx) {
  if (delim == NULL || ctx == NULL || (str == NULL && *ctx == NULL)) {
    return NULL;
  }
  if (!str)
    str = *ctx;
  while (*str && strchr(delim, *str))
    str++;
  if (!*str)
    return NULL;
  *ctx = str + 1;
  while (**ctx && !strchr(delim, **ctx))
    (*ctx)++;
  if (**ctx)
    *(*ctx)++ = '\0';
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strtok_s>:
  endbr64
  test   %rsi,%rsi
  je     L105
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L114
  test   %rdi,%rdi
  je     L40
L15:
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L47
L167:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L100
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L167
L47:
  mov    $0x0,%eax
  jmp    L153
L40:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L15
  mov    %rbx,%rax
  jmp    L153
L100:
  cmpb   $0x0,(%rbx)
  je     L177
  lea    0x1(%rbx),%rax
  mov    %rax,(%r12)
  movzbl 0x1(%rbx),%esi
  test   %sil,%sil
  je     L4
L116:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L164
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movzbl 0x1(%rax),%esi
  test   %sil,%sil
  jne    L116
L4:
  mov    %rbx,%rax
  jmp    L153
L164:
  mov    (%r12),%rax
  cmpb   $0x0,(%rax)
  je     L151
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L153:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L114:
  mov    $0x0,%eax
  jmp    L153
L177:
  mov    $0x0,%eax
  jmp    L153
L151:
  mov    %rbx,%rax
  jmp    L153
L105:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strtok_s(char *str, const char *delim, char **ctx) {
  if (delim == NULL || ctx == NULL || (str == NULL && *ctx == NULL)) {
    return NULL;
  }
  if (!str)
    str = *ctx;
  while (*str && strchr(delim, *str))
    str++;
  if (!*str)
    return NULL;
  *ctx = str + 1;
  while (**ctx && !strchr(delim, **ctx))
    (*ctx)++;
  if (**ctx)
    *(*ctx)++ = '\0';
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtok_s>:
  endbr64
  test   %rsi,%rsi
  je     L24
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L126
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  jne    L78
  jmp    L39
  nopl   0x0(%rax)
L59:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L53
  add    $0x1,%rbx
L78:
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L59
L126:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L53:
  cmpb   $0x0,(%rbx)
  je     L126
  lea    0x1(%rbx),%rax
  mov    %rax,(%r12)
  movsbl 0x1(%rbx),%esi
  test   %sil,%sil
  jne    L112
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movsbl 0x1(%rax),%esi
  test   %sil,%sil
  je     L8
L112:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  mov    (%r12),%rax
  je     L5
  cmpb   $0x0,(%rax)
  je     L8
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L78
  jmp    L126
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strtok_s(char *str, const char *delim, char **ctx) {
  if (delim == NULL || ctx == NULL || (str == NULL && *ctx == NULL)) {
    return NULL;
  }
  if (!str)
    str = *ctx;
  while (*str && strchr(delim, *str))
    str++;
  if (!*str)
    return NULL;
  *ctx = str + 1;
  while (**ctx && !strchr(delim, **ctx))
    (*ctx)++;
  if (**ctx)
    *(*ctx)++ = '\0';
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtok_s>:
  endbr64
  test   %rsi,%rsi
  je     L47
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L7
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  jne    L0
  jmp    L95
  nopl   0x0(%rax)
L103:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L118
  add    $0x1,%rbx
L0:
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L103
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L118:
  cmpb   $0x0,(%rbx)
  je     L7
  lea    0x1(%rbx),%rax
  mov    %rax,(%r12)
  movsbl 0x1(%rbx),%esi
  test   %sil,%sil
  jne    L60
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movsbl 0x1(%rax),%esi
  test   %sil,%sil
  je     L37
L60:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  mov    (%r12),%rax
  je     L5
  cmpb   $0x0,(%rax)
  je     L37
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L95:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L0
  jmp    L7
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strtok_s(char *str, const char *delim, char **ctx) {
  if (delim == NULL || ctx == NULL || (str == NULL && *ctx == NULL)) {
    return NULL;
  }
  if (!str)
    str = *ctx;
  while (*str && strchr(delim, *str))
    str++;
  if (!*str)
    return NULL;
  *ctx = str + 1;
  while (**ctx && !strchr(delim, **ctx))
    (*ctx)++;
  if (**ctx)
    *(*ctx)++ = '\0';
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<helpReadLines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L1
L15:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <helpReadLines>
  mov    %rax,-0x10(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **helpReadLines(int soFar) {
  char *str;
  char **rtnVal;
  str = readLine();
  if (str == NULL) {
    rtnVal = malloc(soFar + 1);
  } else {
    rtnVal = helpReadLines(soFar + 1);
  }
  rtnVal[soFar] = str;
  return rtnVal;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<helpReadLines>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <readLine@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  lea    0x1(%rbx),%edi
  call   <helpReadLines>
L18:
  movslq %ebx,%rbx
  mov    %rbp,(%rax,%rbx,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  jmp    L18
```

assistant: ```c
char **helpReadLines(int soFar) {
  char *str;
  char **rtnVal;
  str = readLine();
  if (str == NULL) {
    rtnVal = malloc(soFar + 1);
  } else {
    rtnVal = helpReadLines(soFar + 1);
  }
  rtnVal[soFar] = str;
  return rtnVal;
}
```