ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getMedianOfMedians>:
  endbr64
  push   %r15
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  push   %r13
  add    $0x1,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x5,%eax
  jle    L43
  lea    0x1(%rsi),%eax
  mov    %edx,%r15d
  mov    %rdi,%rbx
  mov    %eax,0xc(%rsp)
  cmp    %r15d,%r12d
  jg     L65
  nopw   0x0(%rax,%rax,1)
L3:
  movslq 0xc(%rsp),%r14
  mov    %r12d,%r13d
  nopl   0x0(%rax,%rax,1)
L44:
  lea    0x4(%r13),%ebp
  mov    %r13d,%esi
  mov    %rbx,%rdi
  cmp    %r15d,%ebp
  cmovg  %r15d,%ebp
  mov    %ebp,%edx
  call   <insertionSort@plt>
  mov    %ebp,%edx
  mov    -0x4(%rbx,%r14,4),%esi
  sub    %r13d,%edx
  add    $0x1,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %r13d,%eax
  lea    0x1(%rbp),%r13d
  cltq
  lea    (%rbx,%rax,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%rbx,%r14,4)
  mov    %r14d,%edx
  add    $0x1,%r14
  mov    %esi,(%rax)
  cmp    %r15d,%r13d
  jle    L44
  mov    %edx,%eax
  sub    %r12d,%eax
  add    $0x1,%eax
  cmp    $0x5,%eax
  jle    L57
  mov    %edx,%r15d
  cmp    %r15d,%r12d
  jle    L3
L65:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,%r12d
  jmp    L65
L57:
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  add    %eax,%r12d
  jmp    L65
```

assistant: ```c
int getMedianOfMedians(int array[], int beg, int end) {
  int arraySize = end - beg + 1;
  if (arraySize <= 5)
    return beg + (arraySize / 2);
  int i = beg, medGroupsEnd = beg, medianPos, j, swapVar;
  while (i <= end) {
    j = i + 5 - 1;
    if (j > end)
      j = end;
    insertionSort(array, i, j);
    medianPos = i + (j - i + 1) / 2;
    swapVar = array[medGroupsEnd];
    array[medGroupsEnd] = array[medianPos];
    array[medianPos] = swapVar;
    medGroupsEnd++;
    i = j + 1;
  }
  return getMedianOfMedians(array, beg, medGroupsEnd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMedianOfMedians>:
  endbr64
  push   %r15
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  push   %r13
  add    $0x1,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x5,%eax
  jle    L34
  lea    0x1(%rsi),%eax
  mov    %edx,%r15d
  mov    %rdi,%rbx
  mov    %eax,0xc(%rsp)
  cmp    %r15d,%r12d
  jg     L67
  nopw   0x0(%rax,%rax,1)
L24:
  movslq 0xc(%rsp),%r14
  mov    %r12d,%r13d
  nopl   0x0(%rax,%rax,1)
L66:
  lea    0x4(%r13),%ebp
  mov    %r13d,%esi
  mov    %rbx,%rdi
  cmp    %r15d,%ebp
  cmovg  %r15d,%ebp
  mov    %ebp,%edx
  call   <insertionSort@plt>
  mov    %ebp,%edx
  mov    -0x4(%rbx,%r14,4),%esi
  sub    %r13d,%edx
  add    $0x1,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %r13d,%eax
  lea    0x1(%rbp),%r13d
  cltq
  lea    (%rbx,%rax,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%rbx,%r14,4)
  mov    %r14d,%edx
  add    $0x1,%r14
  mov    %esi,(%rax)
  cmp    %r15d,%r13d
  jle    L66
  mov    %edx,%eax
  sub    %r12d,%eax
  add    $0x1,%eax
  cmp    $0x5,%eax
  jle    L4
  mov    %edx,%r15d
  cmp    %r15d,%r12d
  jle    L24
L67:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,%r12d
  jmp    L67
L4:
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  add    %eax,%r12d
  jmp    L67
```

assistant: ```c
int getMedianOfMedians(int array[], int beg, int end) {
  int arraySize = end - beg + 1;
  if (arraySize <= 5)
    return beg + (arraySize / 2);
  int i = beg, medGroupsEnd = beg, medianPos, j, swapVar;
  while (i <= end) {
    j = i + 5 - 1;
    if (j > end)
      j = end;
    insertionSort(array, i, j);
    medianPos = i + (j - i + 1) / 2;
    swapVar = array[medGroupsEnd];
    array[medGroupsEnd] = array[medianPos];
    array[medianPos] = swapVar;
    medGroupsEnd++;
    i = j + 1;
  }
  return getMedianOfMedians(array, beg, medGroupsEnd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_sym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L7
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  or     -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  movslq %eax,%rdx
  imul   $0x14f8b589,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xc,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xc350,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash_sym(char *s, int arity) {
  unsigned x = arity;
  while (*s != '\0') {
    unsigned c = *s;
    x = (x << 4) | c;
    s++;
  }
  return abs(x) % 50000;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_sym>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
L19:
  shl    $0x4,%esi
  movsbl %al,%eax
  or     %eax,%esi
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
L15:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  movslq %edx,%rax
  imul   $0x14f8b589,%rax,%rax
  sar    $0x2c,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xc350,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned hash_sym(char *s, int arity) {
  unsigned x = arity;
  while (*s != '\0') {
    unsigned c = *s;
    x = (x << 4) | c;
    s++;
  }
  return abs(x) % 50000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash_sym>:
  endbr64
  movsbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  je     L19
  nopl   (%rax)
L18:
  shl    $0x4,%edx
  add    $0x1,%rdi
  or     %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L18
  mov    %edx,%esi
L19:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0xc350,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned hash_sym(char *s, int arity) {
  unsigned x = arity;
  while (*s != '\0') {
    unsigned c = *s;
    x = (x << 4) | c;
    s++;
  }
  return abs(x) % 50000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_sym>:
  endbr64
  movsbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  je     L10
  nopl   (%rax)
L15:
  shl    $0x4,%edx
  add    $0x1,%rdi
  or     %eax,%edx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L15
  mov    %edx,%esi
L10:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0xc350,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
unsigned hash_sym(char *s, int arity) {
  unsigned x = arity;
  while (*s != '\0') {
    unsigned c = *s;
    x = (x << 4) | c;
    s++;
  }
  return abs(x) % 50000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_subabs4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  and    $0xff,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x34(%rbp),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x38(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jns    L31
  negl   -0x30(%rbp)
L31:
  cmpl   $0x0,-0x2c(%rbp)
  jns    L11
  negl   -0x2c(%rbp)
L11:
  cmpl   $0x0,-0x28(%rbp)
  jns    L29
  negl   -0x28(%rbp)
L29:
  cmpl   $0x0,-0x24(%rbp)
  jns    L38
  negl   -0x24(%rbp)
L38:
  mov    -0x24(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x30(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _subabs4(int src1, int src2) {
  int res0, res1, res2, res3;
  unsigned int s1_0 = (src1 & 0xff);
  unsigned int s1_1 = (src1 & 0xff00) >> 8;
  unsigned int s1_2 = (src1 & 0xff0000) >> 16;
  unsigned int s1_3 = (src1 & 0xff000000) >> 24;
  unsigned int s2_0 = (src2 & 0xff);
  unsigned int s2_1 = (src2 & 0xff00) >> 8;
  unsigned int s2_2 = (src2 & 0xff0000) >> 16;
  unsigned int s2_3 = (src2 & 0xff000000) >> 24;
  res0 = s1_0 - s2_0;
  res1 = s1_1 - s2_1;
  res2 = s1_2 - s2_2;
  res3 = s1_3 - s2_3;
  if (res0 < 0)
    res0 = -res0;
  if (res1 < 0)
    res1 = -res1;
  if (res2 < 0)
    res2 = -res2;
  if (res3 < 0)
    res3 = -res3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_subabs4>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  movzbl %dil,%edi
  movzbl %sil,%ecx
  sub    %ecx,%edi
  movzbl %dh,%esi
  movzbl %ah,%ecx
  sub    %ecx,%esi
  mov    %edx,%ecx
  sar    $0x10,%ecx
  movzbl %cl,%ecx
  mov    %eax,%r8d
  sar    $0x10,%r8d
  movzbl %r8b,%r8d
  sub    %r8d,%ecx
  shr    $0x18,%edx
  shr    $0x18,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  shl    $0x18,%eax
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  or     %edx,%eax
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  shl    $0x10,%edx
  or     %edx,%eax
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int _subabs4(int src1, int src2) {
  int res0, res1, res2, res3;
  unsigned int s1_0 = (src1 & 0xff);
  unsigned int s1_1 = (src1 & 0xff00) >> 8;
  unsigned int s1_2 = (src1 & 0xff0000) >> 16;
  unsigned int s1_3 = (src1 & 0xff000000) >> 24;
  unsigned int s2_0 = (src2 & 0xff);
  unsigned int s2_1 = (src2 & 0xff00) >> 8;
  unsigned int s2_2 = (src2 & 0xff0000) >> 16;
  unsigned int s2_3 = (src2 & 0xff000000) >> 24;
  res0 = s1_0 - s2_0;
  res1 = s1_1 - s2_1;
  res2 = s1_2 - s2_2;
  res3 = s1_3 - s2_3;
  if (res0 < 0)
    res0 = -res0;
  if (res1 < 0)
    res1 = -res1;
  if (res2 < 0)
    res2 = -res2;
  if (res3 < 0)
    res3 = -res3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_subabs4>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  movzbl %sil,%ecx
  movzbl %dil,%edi
  sub    %ecx,%edi
  movzbl %dh,%esi
  movzbl %ah,%ecx
  mov    %eax,%r8d
  shr    $0x18,%eax
  sub    %ecx,%esi
  mov    %edx,%ecx
  shr    $0x18,%edx
  sar    $0x10,%ecx
  sub    %eax,%edx
  sar    $0x10,%r8d
  movzbl %r8b,%r8d
  mov    %edx,%eax
  movzbl %cl,%ecx
  sub    %r8d,%ecx
  neg    %eax
  cmovs  %edx,%eax
  mov    %edi,%edx
  shl    $0x18,%eax
  neg    %edx
  cmovs  %edi,%edx
  or     %edx,%eax
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  shl    $0x10,%edx
  or     %edx,%eax
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int _subabs4(int src1, int src2) {
  int res0, res1, res2, res3;
  unsigned int s1_0 = (src1 & 0xff);
  unsigned int s1_1 = (src1 & 0xff00) >> 8;
  unsigned int s1_2 = (src1 & 0xff0000) >> 16;
  unsigned int s1_3 = (src1 & 0xff000000) >> 24;
  unsigned int s2_0 = (src2 & 0xff);
  unsigned int s2_1 = (src2 & 0xff00) >> 8;
  unsigned int s2_2 = (src2 & 0xff0000) >> 16;
  unsigned int s2_3 = (src2 & 0xff000000) >> 24;
  res0 = s1_0 - s2_0;
  res1 = s1_1 - s2_1;
  res2 = s1_2 - s2_2;
  res3 = s1_3 - s2_3;
  if (res0 < 0)
    res0 = -res0;
  if (res1 < 0)
    res1 = -res1;
  if (res2 < 0)
    res2 = -res2;
  if (res3 < 0)
    res3 = -res3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_subabs4>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  movzbl %sil,%ecx
  movzbl %dil,%edi
  sub    %ecx,%edi
  movzbl %dh,%esi
  movzbl %ah,%ecx
  mov    %eax,%r8d
  shr    $0x18,%eax
  sub    %ecx,%esi
  mov    %edx,%ecx
  shr    $0x18,%edx
  sar    $0x10,%ecx
  sub    %eax,%edx
  sar    $0x10,%r8d
  movzbl %r8b,%r8d
  mov    %edx,%eax
  movzbl %cl,%ecx
  sub    %r8d,%ecx
  neg    %eax
  cmovs  %edx,%eax
  mov    %edi,%edx
  shl    $0x18,%eax
  neg    %edx
  cmovs  %edi,%edx
  or     %edx,%eax
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  shl    $0x10,%edx
  or     %edx,%eax
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int _subabs4(int src1, int src2) {
  int res0, res1, res2, res3;
  unsigned int s1_0 = (src1 & 0xff);
  unsigned int s1_1 = (src1 & 0xff00) >> 8;
  unsigned int s1_2 = (src1 & 0xff0000) >> 16;
  unsigned int s1_3 = (src1 & 0xff000000) >> 24;
  unsigned int s2_0 = (src2 & 0xff);
  unsigned int s2_1 = (src2 & 0xff00) >> 8;
  unsigned int s2_2 = (src2 & 0xff0000) >> 16;
  unsigned int s2_3 = (src2 & 0xff000000) >> 24;
  res0 = s1_0 - s2_0;
  res1 = s1_1 - s2_1;
  res2 = s1_2 - s2_2;
  res3 = s1_3 - s2_3;
  if (res0 < 0)
    res0 = -res0;
  if (res1 < 0)
    res1 = -res1;
  if (res2 < 0)
    res2 = -res2;
  if (res3 < 0)
    res3 = -res3;
  return (res3 << 24) | (res2 << 16) | (res1 << 8) | res0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  je     L1
  add    %eax,%eax
L15:
  sub    $0x2f72bca5,%eax
  mov    %eax,(%rsi)
  ret
L1:
  rol    $0x10,%eax
  add    %eax,%eax
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 953497306UL) + 157448757U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  xor    %eax,%eax
  sub    $0x99f4bb,%edx
  je     L9
  lea    (%rdx,%rdx,1),%eax
L9:
  sub    $0x2f72bca5,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 953497306UL) + 157448757U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  je     L4
  add    %eax,%eax
L4:
  sub    $0x2f72bca5,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
          state[local1] += state[local1];
        } else {
          copy12 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy12;
          copy13 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy13;
        }
      } else {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        state[local1] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 953497306UL) + 157448757U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__set_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <BIT_MASK@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <BIT_WORD@plt>
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  or     -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void __set_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = BIT_MASK(nr);
  unsigned long *p = ((unsigned long *)addr) + BIT_WORD(nr);
  *p |= mask;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__set_bit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  call   <BIT_MASK@plt>
  mov    %rax,%r12
  mov    %ebp,%edi
  call   <BIT_WORD@plt>
  cltq
  or     %r12,(%rbx,%rax,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void __set_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = BIT_MASK(nr);
  unsigned long *p = ((unsigned long *)addr) + BIT_WORD(nr);
  *p |= mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__set_bit>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <BIT_MASK@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <BIT_WORD@plt>
  cltq
  or     %r12,(%rbx,%rax,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void __set_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = BIT_MASK(nr);
  unsigned long *p = ((unsigned long *)addr) + BIT_WORD(nr);
  *p |= mask;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__set_bit>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <BIT_MASK@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <BIT_WORD@plt>
  cltq
  or     %r12,(%rbx,%rax,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void __set_bit(int nr, volatile unsigned long *addr) {
  unsigned long mask = BIT_MASK(nr);
  unsigned long *p = ((unsigned long *)addr) + BIT_WORD(nr);
  *p |= mask;
}
```
user: What is the c source code of the assembly code below:

```asm
<direct_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  seta   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  setb   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  leave
  ret
```

assistant: ```c
int32_t direct_compare(const void *a, const void *b) {
  assert(a != NULL);
  assert(b != NULL);
  return (a > b) - (a < b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<direct_compare>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %rbx,%rbp
  seta   %al
  movzbl %al,%eax
  sbb    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int32_t direct_compare(const void *a, const void *b) {
  assert(a != NULL);
  assert(b != NULL);
  return (a > b) - (a < b);
}
```