ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vlog_err@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_err(int mode, const char *msg, ...) {
  va_list az;
  va_start(az, msg);
  vlog_err(mode, msg, az);
  va_end(az);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<log_err>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <vlog_err@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_err(int mode, const char *msg, ...) {
  va_list az;
  va_start(az, msg);
  vlog_err(mode, msg, az);
  va_end(az);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<log_err>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <vlog_err@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void log_err(int mode, const char *msg, ...) {
  va_list az;
  va_start(az, msg);
  vlog_err(mode, msg, az);
  va_end(az);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPrimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L16
L28:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L25
  mov    $0x1,%eax
  jmp    L31
L25:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L28
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int isPrimer(int a) {
  int i = 2;
  for (; i < a; i++) {
    if (a % i == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrimer>:
  endbr64
  cmp    $0x2,%edi
  jle    L19
  test   $0x1,%dil
  je     L4
  mov    $0x2,%ecx
L16:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L22
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L16
  mov    $0x1,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPrimer(int a) {
  int i = 2;
  for (; i < a; i++) {
    if (a % i == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPrimer>:
  endbr64
  cmp    $0x2,%edi
  jle    L16
  test   $0x1,%dil
  je     L39
  mov    $0x2,%ecx
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L39
L25:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L26
L16:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPrimer(int a) {
  int i = 2;
  for (; i < a; i++) {
    if (a % i == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<isPrimer>:
  endbr64
  cmp    $0x2,%edi
  jle    L28
  test   $0x1,%dil
  je     L14
  mov    $0x2,%ecx
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L14
L38:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L1
L28:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isPrimer(int a) {
  int i = 2;
  for (; i < a; i++) {
    if (a % i == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itobInterruptor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L14:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <power2@plt>
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  cmp    $0x1,%rax
  jne    L16
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <power2@plt>
  sub    %rax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L4
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L4:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void itobInterruptor(unsigned long integer, int length, int bit2Interruptor[]) {
  int i;
  for (i = 0; i < length; i++) {
    if ((integer / power2(length - 1 - i)) == 1) {
      integer -= power2(length - 1 - i);
      bit2Interruptor[i] = 1;
    } else
      bit2Interruptor[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itobInterruptor>:
  endbr64
  test   %esi,%esi
  jle    L35
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    -0x1(%rsi),%ebx
  mov    %rdx,%rbp
  jmp    L25
L29:
  mov    %ebx,%edi
  call   <power2@plt>
  sub    %rax,%r12
  movl   $0x1,0x0(%rbp)
L28:
  sub    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0xffffffff,%ebx
  je     L36
L25:
  mov    %ebx,%edi
  call   <power2@plt>
  mov    %rax,%rcx
  mov    %r12,%rax
  mov    $0x0,%edx
  div    %rcx
  cmp    $0x1,%rax
  je     L29
  movl   $0x0,0x0(%rbp)
  jmp    L28
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  ret
```

assistant: ```c
void itobInterruptor(unsigned long integer, int length, int bit2Interruptor[]) {
  int i;
  for (i = 0; i < length; i++) {
    if ((integer / power2(length - 1 - i)) == 1) {
      integer -= power2(length - 1 - i);
      bit2Interruptor[i] = 1;
    } else
      bit2Interruptor[i] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itobInterruptor>:
  endbr64
  test   %esi,%esi
  jle    L48
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L33:
  sub    $0x1,%ebx
  mov    %edx,0x0(%rbp)
  add    $0x4,%rbp
  cmp    $0xffffffff,%ebx
  je     L47
L9:
  mov    %ebx,%edi
  call   <power2@plt>
  xor    %edx,%edx
  mov    %rax,%r8
  mov    %r12,%rax
  div    %r8
  xor    %edx,%edx
  cmp    $0x1,%rax
  jne    L33
  mov    %ebx,%edi
  sub    $0x1,%ebx
  add    $0x4,%rbp
  call   <power2@plt>
  mov    $0x1,%edx
  mov    %edx,-0x4(%rbp)
  sub    %rax,%r12
  cmp    $0xffffffff,%ebx
  jne    L9
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L48:
  ret
```

assistant: ```c
void itobInterruptor(unsigned long integer, int length, int bit2Interruptor[]) {
  int i;
  for (i = 0; i < length; i++) {
    if ((integer / power2(length - 1 - i)) == 1) {
      integer -= power2(length - 1 - i);
      bit2Interruptor[i] = 1;
    } else
      bit2Interruptor[i] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itobInterruptor>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %esi,%esi
  jle    L23
  nopl   (%rax)
L12:
  mov    %ebx,%edi
  call   <power2@plt>
  xor    %edx,%edx
  mov    %rax,%r8
  mov    %r12,%rax
  div    %r8
  cmp    $0x1,%rax
  je     L26
  sub    $0x1,%ebx
  movl   $0x0,0x0(%rbp)
  add    $0x4,%rbp
  cmp    $0xffffffff,%ebx
  jne    L12
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  add    $0x4,%rbp
  call   <power2@plt>
  movl   $0x1,-0x4(%rbp)
  sub    %rax,%r12
  cmp    $0xffffffff,%ebx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void itobInterruptor(unsigned long integer, int length, int bit2Interruptor[]) {
  int i;
  for (i = 0; i < length; i++) {
    if ((integer / power2(length - 1 - i)) == 1) {
      integer -= power2(length - 1 - i);
      bit2Interruptor[i] = 1;
    } else
      bit2Interruptor[i] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  __asm__(".p2align 4");
  __asm__(".p2align 4, 0");
  __asm__(".p2align 4, 0, 99");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  data16 cs nopw 0x0(%rax,%rax,1)
  nop
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  __asm__(".p2align 4");
  __asm__(".p2align 4, 0");
  __asm__(".p2align 4, 0, 99");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  data16 cs nopw 0x0(%rax,%rax,1)
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  __asm__(".p2align 4");
  __asm__(".p2align 4, 0");
  __asm__(".p2align 4, 0, 99");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  data16 cs nopw 0x0(%rax,%rax,1)
  nop
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  __asm__(".p2align 4");
  __asm__(".p2align 4, 0");
  __asm__(".p2align 4, 0, 99");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<intersect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L54
  addl   $0x1,-0xc(%rbp)
  jmp    L22
L54:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L58
  addl   $0x1,-0x8(%rbp)
  jmp    L22
L58:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    (%rdx),%edx
  add    $0x4,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L6
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L19
L6:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int intersect(int **res, int **list_a, int len_a, int **list_b, int len_b) {
  int i = 0, j = 0, insert = 0;
  while (i < len_a && j < len_b) {
    if (list_a[i][0] < list_b[j][0])
      i++;
    else if (list_a[i][0] > list_b[j][0])
      j++;
    else {
      res[insert] = list_a[i++];
      res[insert++][1] += list_b[j++][1];
    }
  }
  return insert;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<intersect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L56
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %edx,%r10d
  mov    %rcx,%rbp
  test   %r8d,%r8d
  jle    L56
  mov    $0x0,%r12d
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L88
L66:
  jle    L68
  add    $0x1,%edx
L49:
  cmp    %r10d,%eax
  jge    L83
  cmp    %r8d,%edx
  jge    L83
L88:
  movslq %eax,%rcx
  mov    (%rbx,%rcx,8),%rcx
  mov    (%rcx),%edi
  movslq %edx,%rsi
  lea    0x0(%rbp,%rsi,8),%r9
  mov    (%r9),%rsi
  mov    (%rsi),%esi
  cmp    %esi,%edi
  jge    L66
  add    $0x1,%eax
  jmp    L49
L68:
  add    $0x1,%eax
  movslq %r12d,%rsi
  mov    %rcx,(%r11,%rsi,8)
  add    $0x1,%edx
  add    $0x1,%r12d
  mov    (%r9),%rsi
  mov    0x4(%rsi),%esi
  add    %esi,0x4(%rcx)
  jmp    L49
L56:
  mov    $0x0,%r12d
L83:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int intersect(int **res, int **list_a, int len_a, int **list_b, int len_b) {
  int i = 0, j = 0, insert = 0;
  while (i < len_a && j < len_b) {
    if (list_a[i][0] < list_b[j][0])
      i++;
    else if (list_a[i][0] > list_b[j][0])
      j++;
    else {
      res[insert] = list_a[i++];
      res[insert++][1] += list_b[j++][1];
    }
  }
  return insert;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intersect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L4
  test   %r8d,%r8d
  jle    L4
  mov    %edx,%r10d
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  xor    %r12d,%r12d
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x1,%eax
L35:
  cmp    %r10d,%eax
  jge    L49
L74:
  cmp    %r8d,%edx
  jge    L49
L48:
  movslq %edx,%rsi
  movslq %eax,%rcx
  lea    0x0(%rbp,%rsi,8),%r9
  mov    (%rbx,%rcx,8),%rcx
  mov    (%r9),%rsi
  mov    (%rcx),%edi
  mov    (%rsi),%esi
  cmp    %esi,%edi
  jl     L11
  add    $0x1,%edx
  cmp    %esi,%edi
  jg     L35
  movslq %r12d,%rsi
  add    $0x1,%eax
  add    $0x1,%r12d
  mov    %rcx,(%r11,%rsi,8)
  mov    (%r9),%rsi
  mov    0x4(%rsi),%esi
  add    %esi,0x4(%rcx)
  cmp    %r10d,%eax
  jl     L74
L49:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int intersect(int **res, int **list_a, int len_a, int **list_b, int len_b) {
  int i = 0, j = 0, insert = 0;
  while (i < len_a && j < len_b) {
    if (list_a[i][0] < list_b[j][0])
      i++;
    else if (list_a[i][0] > list_b[j][0])
      j++;
    else {
      res[insert] = list_a[i++];
      res[insert++][1] += list_b[j++][1];
    }
  }
  return insert;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<intersect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L6
  test   %r8d,%r8d
  jle    L6
  mov    %edx,%r10d
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  xor    %r12d,%r12d
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L50:
  add    $0x1,%eax
L15:
  cmp    %r10d,%eax
  jge    L26
L52:
  cmp    %r8d,%edx
  jge    L26
L10:
  movslq %edx,%rsi
  movslq %eax,%rcx
  lea    0x0(%rbp,%rsi,8),%r9
  mov    (%rbx,%rcx,8),%rcx
  mov    (%r9),%rsi
  mov    (%rcx),%edi
  mov    (%rsi),%esi
  cmp    %esi,%edi
  jl     L50
  add    $0x1,%edx
  cmp    %esi,%edi
  jg     L15
  movslq %r12d,%rsi
  add    $0x1,%eax
  add    $0x1,%r12d
  mov    %rcx,(%r11,%rsi,8)
  mov    (%r9),%rsi
  mov    0x4(%rsi),%esi
  add    %esi,0x4(%rcx)
  cmp    %r10d,%eax
  jl     L52
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int intersect(int **res, int **list_a, int len_a, int **list_b, int len_b) {
  int i = 0, j = 0, insert = 0;
  while (i < len_a && j < len_b) {
    if (list_a[i][0] < list_b[j][0])
      i++;
    else if (list_a[i][0] > list_b[j][0])
      j++;
    else {
      res[insert] = list_a[i++];
      res[insert++][1] += list_b[j++][1];
    }
  }
  return insert;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<winsh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <move@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <winsh0@plt>
  nop
  leave
  ret
```

assistant: ```c
int winsh(int x, int y) {
  move(x * 2 - 2, y - 1);
  winsh0(x, y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<winsh>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    -0x1(%rsi),%esi
  lea    -0x2(%rdi,%rdi,1),%edi
  call   <move@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <winsh0@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int winsh(int x, int y) {
  move(x * 2 - 2, y - 1);
  winsh0(x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<winsh>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    -0x1(%rsi),%esi
  push   %rbp
  mov    %edi,%ebp
  lea    -0x2(%rdi,%rdi,1),%edi
  sub    $0x8,%rsp
  call   <move@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <winsh0@plt>
```

assistant: ```c
int winsh(int x, int y) {
  move(x * 2 - 2, y - 1);
  winsh0(x, y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<winsh>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    -0x1(%rsi),%esi
  push   %rbp
  mov    %edi,%ebp
  lea    -0x2(%rdi,%rdi,1),%edi
  sub    $0x8,%rsp
  call   <move@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <winsh0@plt>
```

assistant: ```c
int winsh(int x, int y) {
  move(x * 2 - 2, y - 1);
  winsh0(x, y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CreatePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x2f,-0x9(%rbp)
  je     L38
  cmpb   $0x5c,-0x9(%rbp)
  jne    L5
L38:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_mkdir@plt>
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L5:
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void CreatePath(char *path) {
  char *ofs, c;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      *ofs = 0;
      Q_mkdir(path);
      *ofs = c;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<CreatePath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x1(%rdi),%rbp
  movzbl 0x1(%rdi),%ebx
  test   %bl,%bl
  jne    L32
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rdi
  call   <Q_mkdir@plt>
  mov    %bl,0x0(%rbp)
L27:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L31
L32:
  cmp    $0x2f,%bl
  je     L28
  cmp    $0x5c,%bl
  jne    L27
  jmp    L28
```

assistant: ```c
void CreatePath(char *path) {
  char *ofs, c;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      *ofs = 0;
      Q_mkdir(path);
      *ofs = c;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CreatePath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl 0x1(%rdi),%ebx
  test   %bl,%bl
  je     L4
  mov    %rdi,%r12
  lea    0x1(%rdi),%rbp
  jmp    L15
  nopl   0x0(%rax)
L43:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L4
L15:
  cmp    $0x2f,%bl
  je     L32
  cmp    $0x5c,%bl
  jne    L43
L32:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <Q_mkdir@plt>
  mov    %bl,-0x1(%rbp)
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  jne    L15
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CreatePath(char *path) {
  char *ofs, c;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      *ofs = 0;
      Q_mkdir(path);
      *ofs = c;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CreatePath>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  movzbl 0x1(%rdi),%ebx
  test   %bl,%bl
  je     L46
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    $0x2f,%bl
  je     L2
  cmp    $0x5c,%bl
  je     L2
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  jne    L21
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <Q_mkdir@plt>
  mov    %bl,-0x1(%rbp)
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CreatePath(char *path) {
  char *ofs, c;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      *ofs = 0;
      Q_mkdir(path);
      *ofs = c;
    }
  }
}
```