ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_memprint>:
  endbr64
  test   %rsi,%rsi
  jle    L47
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L24
  nopl   (%rax)
L51:
  cmp    %r12,%rbx
  je     L22
L24:
  test   $0xf,%bl
  jne    L59
  test   %rbx,%rbx
  je     L60
  mov    $0xa,%edi
  call   <putchar@plt>
L60:
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L59:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  test   $0x1,%bl
  jne    L51
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L24
L22:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L47:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D2: %08lx: 

tool: D3: %02x

assistant: ```c
void test_memprint(char *addr, long len) {
  long i;
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i)
        printf("\n");
      printf("%08lx: ", (long)(addr + i));
    }
    printf("%02x", (unsigned char)*(addr + i));
    if (((i + 1) % 2) == 0)
      printf(" ");
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_memprint>:
  endbr64
  test   %rsi,%rsi
  jle    L48
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L28
  nopl   (%rax)
L65:
  cmp    %r12,%rbx
  je     L43
L28:
  test   $0xf,%bl
  jne    L24
  test   %rbx,%rbx
  je     L5
  mov    $0xa,%edi
  call   <putchar@plt>
L5:
  lea    0x0(%rbp,%rbx,1),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L24:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  test   $0x1,%bl
  jne    L65
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L28
L43:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L48:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D15: %08lx: 

tool: D19: %02x

assistant: ```c
void test_memprint(char *addr, long len) {
  long i;
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i)
        printf("\n");
      printf("%08lx: ", (long)(addr + i));
    }
    printf("%02x", (unsigned char)*(addr + i));
    if (((i + 1) % 2) == 0)
      printf(" ");
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcr_encode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  mov    $0x7,%ecx
  lea    D1(%rip),%rdx
  jmp    L27
L17:
  lea    D14(%rip),%rax
  mov    %r13b,(%rax)
  mov    %rax,%rdi
L21:
  mov    %rdi,%r10
L27:
  mov    %rcx,%rax
  and    $0xf,%eax
  movzbl (%rdx,%rax,1),%r8d
  movzbl (%r10),%eax
  mov    %rax,%rdi
  and    $0xf,%edi
  movzbl (%rdx,%rdi,1),%r11d
  mov    %eax,%edi
  shr    $0x4,%dil
  and    $0xf,%edi
  movzbl (%rdx,%rdi,1),%edi
  add    %edi,%edi
  mov    %r11d,%ebx
  shr    $0x4,%bl
  mov    %r8d,%r9d
  shl    $0x6,%r9d
  or     %ebx,%r9d
  or     %edi,%r9d
  shl    $0x4,%r11d
  mov    %r11b,-0x1(%rsp)
  movzbl 0x1(%r10),%ebp
  mov    %ebp,%edi
  shr    $0x4,%dil
  and    $0xf,%edi
  movzbl (%rdx,%rdi,1),%r11d
  mov    %rbp,%rdi
  and    $0xf,%edi
  movzbl (%rdx,%rdi,1),%edi
  shl    $0x2,%edi
  mov    %r11d,%ebx
  shl    $0x7,%ebx
  or     %edi,%ebx
  mov    %bl,-0x2(%rsp)
  movzbl 0x2(%r10),%ebx
  mov    %ebx,%edi
  shr    $0x4,%dil
  and    $0xf,%edi
  movzbl (%rdx,%rdi,1),%edi
  mov    %rbx,%r14
  and    $0xf,%r14d
  mov    %edi,%r12d
  shl    $0x5,%r12d
  or     (%rdx,%r14,1),%r12b
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%rdx,%rcx,1),%ecx
  shl    $0x3,%ecx
  shr    $0x2,%r8b
  or     %ecx,%r8d
  mov    %r8b,(%rsi)
  mov    %r9b,0x1(%rsi)
  shr    %r11b
  movzbl -0x1(%rsp),%ecx
  or     %r11d,%ecx
  mov    %cl,0x2(%rsi)
  shr    $0x3,%dil
  or     -0x2(%rsp),%dil
  mov    %dil,0x3(%rsi)
  add    $0x5,%rsi
  mov    %r12b,-0x1(%rsi)
  lea    0x4(%r10),%rdi
  movzbl 0x3(%r10),%ecx
  xor    %ebp,%eax
  xor    %ebx,%eax
  xor    %ecx,%eax
  xor    %eax,%r13d
  add    $0x4,%r15d
  cmp    $0x104,%r15d
  je     L39
  cmp    $0x100,%r15d
  jne    L21
  jmp    L17
L39:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int gcr_encode(unsigned const char *block, unsigned char *encoded) {
  register unsigned char c = 0x07, h, l, g0, g1, g2, g3, g4;
  unsigned char chk = 0;
  int i;
  static const unsigned char gcr[] = {0x0a, 0x0b, 0x12, 0x13, 0x0e, 0x0f, 0x16, 0x17, 0x09, 0x19, 0x1a, 0x1b, 0x0d, 0x1d, 0x1e, 0x15};
  static unsigned char empty[] = {0x00, 0x00, 0x00, 0x00};
  for (i = 0; i <= 256; i += 4) {
    if (i == 256) {
      block = empty;
      empty[0] = chk;
    }
    h = gcr[c >> 4];
    l = gcr[c & 0x0f];
    g0 = (h << 3) | (l >> 2);
    g1 = (l & 0x03) << 6;
    chk ^= c = *(block++);
    h = gcr[c >> 4];
    l = gcr[c & 0x0f];
    g1 |= (h << 1) | (l >> 4);
    g2 = (l & 0x0f) << 4;
    chk ^= c = *(block++);
    h = gcr[c >> 4];
    l = gcr[c & 0x0f];
    g2 |= (h >> 1);
    g3 = ((h & 0x01) << 7) | (l << 2);
    chk ^= c = *(block++);
    h = gcr[c >> 4];
    l = gcr[c & 0x0f];
    g3 |= (h >> 3);
    g4 = ((h & 0x07) << 5) | (l);
    *(encoded++) = g0;
    *(encoded++) = g1;
    *(encoded++) = g2;
    *(encoded++) = g3;
    *(encoded++) = g4;
    chk ^= c = *(block++);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<computeOmega>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  mov    %edi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movss  -0x14(%rbp),%xmm0
  addss  -0x18(%rbp),%xmm0
  mov    -0x24(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x1c(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%eax
  imul   -0x28(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: f64

tool: D4: 1e-05

assistant: ```c
float computeOmega(float LS, float RS, float TS, int k, int ksel2, int m, int msel2) {
  float numerator = (LS + RS) / (ksel2 + msel2);
  float denominator = (TS - LS - RS) / (k * m) + 0.00001;
  float omega = numerator / denominator;
  return omega;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<computeOmega>:
  endbr64
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm3
  addss  %xmm1,%xmm0
  add    %ecx,%esi
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  subss  %xmm4,%xmm2
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  imul   %edx,%edi
  pxor   %xmm2,%xmm2
  cvtsi2ss %edi,%xmm2
  divss  %xmm2,%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  D5(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 1e-05

assistant: ```c
float computeOmega(float LS, float RS, float TS, int k, int ksel2, int m, int msel2) {
  float numerator = (LS + RS) / (ksel2 + msel2);
  float denominator = (TS - LS - RS) / (k * m) + 0.00001;
  float omega = numerator / denominator;
  return omega;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<computeOmega>:
  endbr64
  movaps %xmm0,%xmm3
  imul   %edx,%edi
  addss  %xmm1,%xmm0
  add    %ecx,%esi
  subss  %xmm3,%xmm2
  pxor   %xmm4,%xmm4
  cvtsi2ss %esi,%xmm4
  subss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  divss  %xmm4,%xmm0
  divss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  addsd  D4(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: f64

tool: D4: 1e-05

assistant: ```c
float computeOmega(float LS, float RS, float TS, int k, int ksel2, int m, int msel2) {
  float numerator = (LS + RS) / (ksel2 + msel2);
  float denominator = (TS - LS - RS) / (k * m) + 0.00001;
  float omega = numerator / denominator;
  return omega;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeOmega>:
  endbr64
  movaps %xmm0,%xmm3
  imul   %edx,%edi
  addss  %xmm1,%xmm0
  add    %ecx,%esi
  subss  %xmm3,%xmm2
  pxor   %xmm4,%xmm4
  cvtsi2ss %esi,%xmm4
  subss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  divss  %xmm4,%xmm0
  divss  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  addsd  D4(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: f64

tool: D4: 1e-05

assistant: ```c
float computeOmega(float LS, float RS, float TS, int k, int ksel2, int m, int msel2) {
  float numerator = (LS + RS) / (ksel2 + msel2);
  float denominator = (TS - LS - RS) / (k * m) + 0.00001;
  float omega = numerator / denominator;
  return omega;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tcache_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xdeadbeef,%edx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  mov    $0x1,%eax
  jmp    L17
L15:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int tcache_enable() {
  void **p = malloc(sizeof(size_t) * 32);
  *p = (void *)0xdeadbeefu;
  free(p);
  if (*p == 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tcache_enable>:
  endbr64
  push   %rbx
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xdeadbeef,%eax
  mov    %rax,(%rbx)
  mov    %rbx,%rdi
  call   <free@plt>
  cmpq   $0x0,(%rbx)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tcache_enable() {
  void **p = malloc(sizeof(size_t) * 32);
  *p = (void *)0xdeadbeefu;
  free(p);
  if (*p == 0)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tcache_enable>:
  endbr64
  push   %rbx
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xdeadbeef,%eax
  mov    %rax,(%rbx)
  mov    %rbx,%rdi
  call   <free@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int tcache_enable() {
  void **p = malloc(sizeof(size_t) * 32);
  *p = (void *)0xdeadbeefu;
  free(p);
  if (*p == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tcache_enable>:
  endbr64
  push   %rbx
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0xdeadbeef,%eax
  mov    %rax,(%rbx)
  mov    %rbx,%rdi
  call   <free@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int tcache_enable() {
  void **p = malloc(sizeof(size_t) * 32);
  *p = (void *)0xdeadbeefu;
  free(p);
  if (*p == 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printResults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x5f5e0ff,-0x3c(%rbp)
  jmp    L17
L27:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L38
  cmpl   $0x9,-0x44(%rbp)
  jg     L9
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x3c(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L9:
  addl   $0x1,-0x44(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x40(%rbp)
L38:
  subl   $0x2,-0x3c(%rbp)
L17:
  cmpl   $0x1,-0x3c(%rbp)
  jg     L27
  addl   $0x2,-0x40(%rbp)
  addl   $0x1,-0x44(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <getTimeElapsed@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x9,-0x38(%rbp)
L8:
  cmpq   $0x0,-0x38(%rbp)
  je     L57
  lea    D30(%rip),%rax
  jmp    L46
L57:
  lea    D60(%rip),%rax
L46:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp,%rdx,4),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subq   $0x1,-0x38(%rbp)
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: string
name: unpack_data
arguments: data_label: D52
type: string
name: unpack_data
arguments: data_label: D2
type: string
name: unpack_data
arguments: data_label: D57
type: string
name: unpack_data
arguments: data_label: D30
type: string
name: unpack_data
arguments: data_label: D60
type: string
name: unpack_data
arguments: data_label: D9
type: string

tool: D23: Execution time: %fs


tool: D52: Found %u primes.


tool: D2: Sum of primes = %lu


tool: D57: Top ten maximum primes: 

tool: D30: , 

tool: D60: 


tool: D9: %u%s

assistant: ```c
void printResults(struct timeval *begTime, volatile uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printResults>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x17d783fc(%rsi),%rdx
  mov    $0x5f5e0ff,%eax
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L3
L18:
  add    $0x1,%ebx
  add    %eax,%ebp
L20:
  sub    $0x2,%eax
  sub    $0x8,%rdx
  cmp    $0x1,%eax
  je     L52
L3:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  jne    L20
  cmp    $0x9,%ebx
  jg     L18
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
  jmp    L18
L52:
  call   <getTimeElapsed@plt>
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%ebx
  lea    D68(%rip),%rdx
  lea    D34(%rip),%r13
  mov    %rdx,%r12
  lea    D32(%rip),%rbp
L46:
  mov    (%rsp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L46
```

tool_calls: name: unpack_data
arguments: label: D58
datatype: string
name: unpack_data
arguments: label: D64
datatype: string
name: unpack_data
arguments: label: D48
datatype: string
name: unpack_data
arguments: label: D69
datatype: string
name: unpack_data
arguments: label: D68
datatype: string
name: unpack_data
arguments: label: D34
datatype: string
name: unpack_data
arguments: label: D32
datatype: string

tool: D58: Execution time: %fs


tool: D64: Found %u primes.


tool: D48: Sum of primes = %lu


tool: D69: Top ten maximum primes: 

tool: D68: , 

tool: D34: %u%s

tool: D32: 


assistant: ```c
void printResults(struct timeval *begTime, volatile uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printResults>:
  endbr64
  push   %r14
  lea    0x17d783fc(%rsi),%rdx
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x5f5e0ff,%eax
L7:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  jne    L26
  cmp    $0x9,%ebx
  jg     L14
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
L14:
  add    $0x1,%ebx
  add    %eax,%ebp
L26:
  sub    $0x2,%eax
  sub    $0x8,%rdx
  cmp    $0x1,%eax
  jne    L7
  call   <getTimeElapsed@plt>
  lea    D59(%rip),%rdi
  mov    %rsp,%r14
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  xor    %eax,%eax
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    $0x9,%ebx
  call   <printf@plt>
  lea    D61(%rip),%rdx
  lea    D10(%rip),%r13
  mov    %rdx,%r12
  lea    D8(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%r14,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_label: D59
type: string
name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D65
type: string
name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D61
type: string
name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D59: Execution time: %fs


tool: D19: Found %u primes.


tool: D65: Sum of primes = %lu


tool: D0: Top ten maximum primes: 

tool: D61: , 

tool: D10: %u%s

tool: D8: 


assistant: ```c
void printResults(struct timeval *begTime, volatile uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printResults>:
  endbr64
  push   %r14
  lea    0x17d783fc(%rsi),%rdx
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x5f5e0ff,%eax
L2:
  mov    (%rdx),%ecx
  test   %ecx,%ecx
  jne    L26
  cmp    $0x9,%ebx
  jg     L21
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
L21:
  add    $0x1,%ebx
  add    %eax,%ebp
L26:
  sub    $0x2,%eax
  sub    $0x8,%rdx
  cmp    $0x1,%eax
  jne    L2
  call   <getTimeElapsed@plt>
  lea    D52(%rip),%rdi
  mov    %rsp,%r14
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  mov    $0x9,%ebx
  call   <printf@plt>
  lea    D49(%rip),%rdx
  lea    D21(%rip),%r13
  mov    %rdx,%r12
  lea    D45(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%r14,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_tag: D52
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string
name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D49
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string
name: unpack_data
arguments: data_tag: D45
data_type: string

tool: D52: Execution time: %fs


tool: D10: Found %u primes.


tool: D37: Sum of primes = %lu


tool: D19: Top ten maximum primes: 

tool: D49: , 

tool: D21: %u%s

tool: D45: 


assistant: ```c
void printResults(struct timeval *begTime, volatile uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <werase@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <wmove@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <wrefresh@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(int sig) {
  signal(sig, SIG_IGN);
  werase(curscr);
  wmove(curscr, 0, 0);
  wrefresh(curscr);
  endwin();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <signal@plt>
  mov    D1(%rip),%rbx
  mov    (%rbx),%edi
  call   <werase@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    (%rbx),%edi
  call   <wmove@plt>
  mov    (%rbx),%edi
  call   <wrefresh@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void die(int sig) {
  signal(sig, SIG_IGN);
  werase(curscr);
  wmove(curscr, 0, 0);
  wrefresh(curscr);
  endwin();
  exit(0);
}
```