ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<warn_memcpy_chain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x9,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x7,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x5,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void warn_memcpy_chain(const void *s) {
  extern char cpy_a8[8];
  char *p = cpy_a8;
  p = memcpy(p, s, 9);
  sink(p);
  p = memcpy(p + 2, s, 7);
  sink(p);
  p = memcpy(p + 3, s, 5);
  sink(p);
  p = memcpy(p + 3, s, 3);
  sink(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<warn_memcpy_chain>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x9,%edx
  mov    %rdi,%rsi
  mov    D6(%rip),%rdi
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  lea    0x2(%rbx),%rdi
  mov    $0x7,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  lea    0x3(%rbx),%rdi
  mov    $0x5,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  lea    0x3(%rbx),%rdi
  mov    $0x3,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rax,%rdi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void warn_memcpy_chain(const void *s) {
  extern char cpy_a8[8];
  char *p = cpy_a8;
  p = memcpy(p, s, 9);
  sink(p);
  p = memcpy(p + 2, s, 7);
  sink(p);
  p = memcpy(p + 3, s, 5);
  sink(p);
  p = memcpy(p + 3, s, 3);
  sink(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<warn_memcpy_chain>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    $0x9,%edx
  push   %rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%rdi
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    0x2(%rbx),%rdi
  mov    $0x7,%edx
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    0x3(%rbx),%rdi
  mov    $0x5,%edx
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  lea    0x3(%rbx),%rdi
  mov    %rbp,%rsi
  mov    $0x3,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <sink@plt>
```

assistant: ```c
void warn_memcpy_chain(const void *s) {
  extern char cpy_a8[8];
  char *p = cpy_a8;
  p = memcpy(p, s, 9);
  sink(p);
  p = memcpy(p + 2, s, 7);
  sink(p);
  p = memcpy(p + 3, s, 5);
  sink(p);
  p = memcpy(p + 3, s, 3);
  sink(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<warn_memcpy_chain>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    $0x9,%edx
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rdi
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    0x2(%rbx),%rdi
  mov    $0x7,%edx
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    0x3(%rbx),%rdi
  mov    $0x5,%edx
  call   <memcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <sink@plt>
  lea    0x3(%rbx),%rdi
  mov    %rbp,%rsi
  mov    $0x3,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <sink@plt>
```

assistant: ```c
void warn_memcpy_chain(const void *s) {
  extern char cpy_a8[8];
  char *p = cpy_a8;
  p = memcpy(p, s, 9);
  sink(p);
  p = memcpy(p + 2, s, 7);
  sink(p);
  p = memcpy(p + 3, s, 5);
  sink(p);
  p = memcpy(p + 3, s, 3);
  sink(p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_sdcard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L13:
  mov    $0xff,%edi
  call   <spi_tx@plt>
  addl   $0x1,-0x8(%rbp)
L21:
  cmpl   $0xc7,-0x8(%rbp)
  jle    L13
  mov    $0x95,%edx
  mov    $0x0,%esi
  mov    $0x40,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x87,%edx
  mov    $0x1aa,%esi
  mov    $0x48,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x0,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L32
L22:
  mov    $0x0,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  mov    %eax,-0x4(%rbp)
L32:
  cmpl   $0x0,-0x4(%rbp)
  jne    L22
  mov    $0x0,%eax
  call   <spi_incr_cspeed@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int init_sdcard(void) {
  int i, ret;
  for (i = 0; i < 200; ++i) {
    spi_tx(0xff);
  }
  spi_sendpackcrc(0x40 + 0, 0x00000000, 0x95);
  spi_sendpackcrc(0x40 + 8, 0x000001aa, 0x87);
  spi_sendpack(0x40 + 55, 0x00000000);
  ret = spi_sendpack(0x40 + 41, 0x40000000);
  while (ret != 0x00) {
    spi_sendpack(0x40 + 55, 0x00000000);
    ret = spi_sendpack(0x40 + 41, 0x40000000);
  }
  spi_incr_cspeed();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_sdcard>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
L18:
  mov    $0xff,%edi
  call   <spi_tx@plt>
  sub    $0x1,%ebx
  jne    L18
  mov    $0x95,%edx
  mov    $0x0,%esi
  mov    $0x40,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x87,%edx
  mov    $0x1aa,%esi
  mov    $0x48,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x0,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  test   %eax,%eax
  je     L26
L21:
  mov    $0x0,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  test   %eax,%eax
  jne    L21
L26:
  mov    $0x0,%eax
  call   <spi_incr_cspeed@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int init_sdcard(void) {
  int i, ret;
  for (i = 0; i < 200; ++i) {
    spi_tx(0xff);
  }
  spi_sendpackcrc(0x40 + 0, 0x00000000, 0x95);
  spi_sendpackcrc(0x40 + 8, 0x000001aa, 0x87);
  spi_sendpack(0x40 + 55, 0x00000000);
  ret = spi_sendpack(0x40 + 41, 0x40000000);
  while (ret != 0x00) {
    spi_sendpack(0x40 + 55, 0x00000000);
    ret = spi_sendpack(0x40 + 41, 0x40000000);
  }
  spi_incr_cspeed();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<init_sdcard>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xff,%edi
  call   <spi_tx@plt>
  sub    $0x1,%ebx
  jne    L16
  mov    $0x95,%edx
  xor    %esi,%esi
  mov    $0x40,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x87,%edx
  mov    $0x1aa,%esi
  mov    $0x48,%edi
  call   <spi_sendpackcrc@plt>
  nopl   0x0(%rax)
L19:
  xor    %esi,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  test   %eax,%eax
  jne    L19
  xor    %eax,%eax
  call   <spi_incr_cspeed@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int init_sdcard(void) {
  int i, ret;
  for (i = 0; i < 200; ++i) {
    spi_tx(0xff);
  }
  spi_sendpackcrc(0x40 + 0, 0x00000000, 0x95);
  spi_sendpackcrc(0x40 + 8, 0x000001aa, 0x87);
  spi_sendpack(0x40 + 55, 0x00000000);
  ret = spi_sendpack(0x40 + 41, 0x40000000);
  while (ret != 0x00) {
    spi_sendpack(0x40 + 55, 0x00000000);
    ret = spi_sendpack(0x40 + 41, 0x40000000);
  }
  spi_incr_cspeed();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_sdcard>:
  endbr64
  push   %rbx
  mov    $0xc8,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xff,%edi
  call   <spi_tx@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    $0x95,%edx
  xor    %esi,%esi
  mov    $0x40,%edi
  call   <spi_sendpackcrc@plt>
  mov    $0x87,%edx
  mov    $0x1aa,%esi
  mov    $0x48,%edi
  call   <spi_sendpackcrc@plt>
  nopl   0x0(%rax)
L2:
  xor    %esi,%esi
  mov    $0x77,%edi
  call   <spi_sendpack@plt>
  mov    $0x40000000,%esi
  mov    $0x69,%edi
  call   <spi_sendpack@plt>
  test   %eax,%eax
  jne    L2
  xor    %eax,%eax
  call   <spi_incr_cspeed@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int init_sdcard(void) {
  int i, ret;
  for (i = 0; i < 200; ++i) {
    spi_tx(0xff);
  }
  spi_sendpackcrc(0x40 + 0, 0x00000000, 0x95);
  spi_sendpackcrc(0x40 + 8, 0x000001aa, 0x87);
  spi_sendpack(0x40 + 55, 0x00000000);
  ret = spi_sendpack(0x40 + 41, 0x40000000);
  while (ret != 0x00) {
    spi_sendpack(0x40 + 55, 0x00000000);
    ret = spi_sendpack(0x40 + 41, 0x40000000);
  }
  spi_incr_cspeed();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<raster_game>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    $0x80000,%eax
  cltd
  idivl  -0x3c(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x80000,%eax
  cltd
  idivl  -0x40(%rbp)
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L35
L1:
  movl   $0x1,-0x14(%rbp)
  jmp    L48
L30:
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L32
  mov    -0x34(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  cltq
  movw   $0xf0,(%rdx,%rax,2)
  jmp    L20
L32:
  mov    -0x34(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  cltq
  movw   $0x0,(%rdx,%rax,2)
L20:
  addl   $0x1,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L30
  addl   $0x1,-0x18(%rbp)
L35:
  mov    -0x18(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void raster_game(int game_grid[8][8], short current_frame[480][640], int x, int y, int width, int height) {
  int i, j;
  int x_ratio = (int)((8 << 16) / width) + 1;
  int y_ratio = (int)((8 << 16) / height) + 1;
  int x2, y2;
  for (i = 1; i < width; i++) {
    for (j = 1; j < height; j++) {
      x2 = ((j * x_ratio) >> 16);
      y2 = ((i * y_ratio) >> 16);
      if (game_grid[x2][y2]) {
        current_frame[x + i][y + j] = 0x00F0;
      } else {
        current_frame[x + i][y + j] = 0x0000;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<raster_game>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    $0x80000,%r14d
  mov    %r14d,%eax
  cltd
  idiv   %r8d
  lea    0x1(%rax),%r10d
  mov    %r14d,%eax
  cltd
  idiv   %r9d
  mov    %eax,%r14d
  add    $0x1,%r14d
  cmp    $0x1,%r8d
  jle    L52
  mov    %rdi,%r11
  mov    %ecx,%ebp
  mov    %r9d,%r13d
  lea    0x1(%rsi),%r9d
  lea    (%r8,%rsi,1),%r15d
  mov    %r14d,%r12d
  lea    0x0(%r13,%rcx,1),%r8d
  jmp    L9
L3:
  movslq %edx,%rax
  movw   $0x0,(%rsi,%rax,2)
L11:
  add    %r10d,%ecx
  add    $0x1,%edx
  cmp    %r8d,%edx
  je     L6
L0:
  mov    %ecx,%eax
  sar    $0x10,%eax
  cltq
  shl    $0x5,%rax
  add    %r11,%rax
  cmpl   $0x0,(%rax,%rdi,4)
  je     L3
  movslq %edx,%rax
  movw   $0xf0,(%rsi,%rax,2)
  jmp    L11
L6:
  add    %r14d,%r12d
  add    $0x1,%r9d
  cmp    %r15d,%r9d
  je     L52
L9:
  cmp    $0x1,%r13d
  jle    L6
  mov    %r12d,%edi
  sar    $0x10,%edi
  movslq %r9d,%rax
  lea    (%rax,%rax,4),%rsi
  shl    $0x8,%rsi
  add    %rbx,%rsi
  lea    0x1(%rbp),%edx
  mov    %r10d,%ecx
  movslq %edi,%rdi
  jmp    L0
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void raster_game(int game_grid[8][8], short current_frame[480][640], int x, int y, int width, int height) {
  int i, j;
  int x_ratio = (int)((8 << 16) / width) + 1;
  int y_ratio = (int)((8 << 16) / height) + 1;
  int x2, y2;
  for (i = 1; i < width; i++) {
    for (j = 1; j < height; j++) {
      x2 = ((j * x_ratio) >> 16);
      y2 = ((i * y_ratio) >> 16);
      if (game_grid[x2][y2]) {
        current_frame[x + i][y + j] = 0x00F0;
      } else {
        current_frame[x + i][y + j] = 0x0000;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<raster_game>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x80000,%ebp
  mov    %ebp,%eax
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  cltd
  idiv   %r8d
  lea    0x1(%rax),%r10d
  mov    %ebp,%eax
  cltd
  idiv   %r9d
  mov    %eax,%ebp
  add    $0x1,%ebp
  cmp    $0x1,%r8d
  jle    L4
  movslq %ecx,%rcx
  lea    -0x2(%r9),%eax
  mov    %r8d,%r12d
  mov    %r9d,%r13d
  lea    0x1(%rcx,%rax,1),%r14
  mov    %rdi,%r11
  lea    0x1(%rsi),%r8d
  add    %esi,%r12d
  lea    (%rcx,%rcx,1),%r15
  mov    %ebp,%r9d
  add    %r14,%r14
  nopl   (%rax)
L24:
  cmp    $0x1,%r13d
  jle    L15
  movslq %r8d,%rax
  mov    %r9d,%edi
  mov    %r10d,%ecx
  lea    (%rax,%rax,4),%rsi
  sar    $0x10,%edi
  shl    $0x8,%rsi
  movslq %edi,%rdi
  add    %rbx,%rsi
  lea    (%rsi,%r15,1),%rdx
  add    %r14,%rsi
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %ecx,%eax
  sar    $0x10,%eax
  cltq
  shl    $0x5,%rax
  add    %r11,%rax
  mov    (%rax,%rdi,4),%eax
  neg    %eax
  sbb    %ax,%ax
  add    $0x2,%rdx
  add    %r10d,%ecx
  and    $0xf0,%ax
  mov    %ax,(%rdx)
  cmp    %rdx,%rsi
  jne    L20
L15:
  add    $0x1,%r8d
  add    %ebp,%r9d
  cmp    %r12d,%r8d
  jne    L24
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void raster_game(int game_grid[8][8], short current_frame[480][640], int x, int y, int width, int height) {
  int i, j;
  int x_ratio = (int)((8 << 16) / width) + 1;
  int y_ratio = (int)((8 << 16) / height) + 1;
  int x2, y2;
  for (i = 1; i < width; i++) {
    for (j = 1; j < height; j++) {
      x2 = ((j * x_ratio) >> 16);
      y2 = ((i * y_ratio) >> 16);
      if (game_grid[x2][y2]) {
        current_frame[x + i][y + j] = 0x00F0;
      } else {
        current_frame[x + i][y + j] = 0x0000;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<raster_game>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x80000,%ebp
  mov    %ebp,%eax
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  cltd
  idiv   %r8d
  lea    0x1(%rax),%r10d
  mov    %ebp,%eax
  cltd
  idiv   %r9d
  mov    %eax,%ebp
  add    $0x1,%ebp
  cmp    $0x1,%r8d
  jle    L45
  cmp    $0x1,%r9d
  jle    L45
  movslq %ecx,%rcx
  lea    -0x2(%r9),%eax
  mov    %r8d,%r12d
  mov    %rdi,%r11
  lea    0x1(%rcx,%rax,1),%r13
  lea    0x1(%rsi),%r8d
  add    %esi,%r12d
  mov    %ebp,%r9d
  lea    (%rcx,%rcx,1),%r14
  add    %r13,%r13
  xchg   %ax,%ax
L34:
  movslq %r8d,%rax
  mov    %r9d,%edi
  mov    %r10d,%ecx
  lea    (%rax,%rax,4),%rsi
  sar    $0x10,%edi
  shl    $0x8,%rsi
  movslq %edi,%rdi
  add    %rbx,%rsi
  lea    (%rsi,%r14,1),%rdx
  add    %r13,%rsi
  nopl   0x0(%rax)
L21:
  mov    %ecx,%eax
  sar    $0x10,%eax
  cltq
  shl    $0x5,%rax
  add    %r11,%rax
  mov    (%rax,%rdi,4),%eax
  test   %eax,%eax
  jne    L57
  xor    %eax,%eax
  add    $0x2,%rdx
  add    %r10d,%ecx
  mov    %ax,(%rdx)
  cmp    %rdx,%rsi
  jne    L21
  add    $0x1,%r8d
  add    %ebp,%r9d
  cmp    %r12d,%r8d
  jne    L34
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    $0xf0,%eax
  add    $0x2,%rdx
  add    %r10d,%ecx
  mov    %ax,(%rdx)
  cmp    %rdx,%rsi
  jne    L21
  add    $0x1,%r8d
  add    %ebp,%r9d
  cmp    %r12d,%r8d
  jne    L34
  jmp    L45
```

assistant: ```c
void raster_game(int game_grid[8][8], short current_frame[480][640], int x, int y, int width, int height) {
  int i, j;
  int x_ratio = (int)((8 << 16) / width) + 1;
  int y_ratio = (int)((8 << 16) / height) + 1;
  int x2, y2;
  for (i = 1; i < width; i++) {
    for (j = 1; j < height; j++) {
      x2 = ((j * x_ratio) >> 16);
      y2 = ((i * y_ratio) >> 16);
      if (game_grid[x2][y2]) {
        current_frame[x + i][y + j] = 0x00F0;
      } else {
        current_frame[x + i][y + j] = 0x0000;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_arraySum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <arraySum@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L9
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D15: . sum = %d, expected = %d.

tool: D0:  FAIL

assistant: ```c
void test_arraySum(int *array, int len, int expected) {
  printArray(array, len);
  int sum = arraySum(array, len);
  printf(". sum = %d, expected = %d.", sum, expected);
  if (sum != expected)
    printf(" FAIL");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_arraySum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  call   <printArray@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <arraySum@plt>
  mov    %eax,%ebp
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L9
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D11: . sum = %d, expected = %d.

tool: D16:  FAIL

assistant: ```c
void test_arraySum(int *array, int len, int expected) {
  printArray(array, len);
  int sum = arraySum(array, len);
  printf(". sum = %d, expected = %d.", sum, expected);
  if (sum != expected)
    printf(" FAIL");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_arraySum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <printArray@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <arraySum@plt>
  mov    %ebx,%edx
  lea    D7(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  je     L2
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D7: . sum = %d, expected = %d.

tool: D8:  FAIL

assistant: ```c
void test_arraySum(int *array, int len, int expected) {
  printArray(array, len);
  int sum = arraySum(array, len);
  printf(". sum = %d, expected = %d.", sum, expected);
  if (sum != expected)
    printf(" FAIL");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<test_arraySum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <printArray@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <arraySum@plt>
  mov    %ebx,%edx
  lea    D11(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  je     L9
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L9:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string

tool: D11: . sum = %d, expected = %d.

tool: D19:  FAIL

assistant: ```c
void test_arraySum(int *array, int len, int expected) {
  printArray(array, len);
  int sum = arraySum(array, len);
  printf(". sum = %d, expected = %d.", sum, expected);
  if (sum != expected)
    printf(" FAIL");
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xtoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L94
  mov    $0x0,%eax
  jmp    L60
L94:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L15
  cmpb   $0x39,-0x4(%rbp)
  jg     L15
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L60
L15:
  cmpb   $0x40,-0x4(%rbp)
  jle    L78
  cmpb   $0x46,-0x4(%rbp)
  jg     L78
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L60
L78:
  cmpb   $0x60,-0x4(%rbp)
  jle    L9
  cmpb   $0x66,-0x4(%rbp)
  jg     L9
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L60
L9:
  mov    $0xffffffff,%eax
L60:
  leave
  ret
```

assistant: ```c
int xtoi(char c) {
  if (isspace(c))
    return 0;
  if (c >= '0' && c <= '9')
    return (int)c - 48;
  if (c >= 'A' && c <= 'F')
    return (int)c - 55;
  if (c >= 'a' && c <= 'f')
    return (int)c - 87;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xtoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movsbl %dil,%ebp
  mov    %ebp,%edi
  call   <isspace@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L36
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  jbe    L8
  lea    -0x41(%rbx),%eax
  cmp    $0x5,%al
  jbe    L40
  sub    $0x61,%ebx
  sub    $0x57,%ebp
  cmp    $0x6,%bl
  mov    $0xffffffff,%eax
  cmovb  %ebp,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    -0x30(%rbp),%eax
  jmp    L36
L40:
  lea    -0x37(%rbp),%eax
  jmp    L36
```

assistant: ```c
int xtoi(char c) {
  if (isspace(c))
    return 0;
  if (c >= '0' && c <= '9')
    return (int)c - 48;
  if (c >= 'A' && c <= 'F')
    return (int)c - 55;
  if (c >= 'a' && c <= 'f')
    return (int)c - 87;
  return -1;
}
```