user: 请将以下的汇编代码转换成C语言代码:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  call   <countStrStr@plt>
  mov    %rbp,%rdi
  mov    %eax,%r15d
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %rbp,%r8
  mov    %eax,0x8(%rsp)
  cmp    %eax,%r13d
  jne    L18
  mov    %r12d,%r11d
  xor    %r9d,%r9d
  xor    %edi,%edi
  sub    %r13d,%r11d
  js     L144
L25:
  movslq 0x8(%rsp),%r15
  lea    -0x1(%r13),%esi
  mov    %esi,(%rsp)
  lea    0x1(%r13),%esi
  mov    %r15,%rax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  nopl   0x0(%rax)
L147:
  movslq %edi,%r10
  mov    $0x1,%eax
  xor    %ecx,%ecx
  lea    0x0(%rbp,%r10,1),%rdx
  test   %r13d,%r13d
  jg     L29
  jmp    L12
  nopl   0x0(%rax)
L141:
  mov    %eax,%ecx
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L12
L29:
  movzbl -0x1(%rbx,%rax,1),%ecx
  cmp    %cl,-0x1(%rax,%rdx,1)
  je     L141
L83:
  movzbl 0x0(%rbp,%r10,1),%edx
  movslq %r9d,%rax
  mov    %dl,(%r8,%rax,1)
L110:
  add    $0x1,%edi
  add    $0x1,%r9d
  cmp    %r11d,%edi
  jle    L147
  movslq %r9d,%rdx
  add    %r8,%rdx
L47:
  lea    0x1(%r11),%eax
  cmp    %eax,%r12d
  jle    L102
  movslq %r9d,%rdx
  movslq %r11d,%rcx
  cltq
  sub    %rcx,%rdx
  add    %r8,%rdx
L93:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    %cl,-0x1(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L93
  lea    -0x1(%r12),%eax
  sub    %r11d,%eax
  add    %r9d,%eax
  cltq
  lea    (%r8,%rax,1),%rdx
L102:
  movb   $0x0,(%rdx)
L111:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  movslq %edi,%r10
  cmp    %ecx,%r13d
  jne    L83
  mov    0x8(%rsp),%edx
  movslq %r9d,%rcx
  xor    %eax,%eax
  add    %r8,%rcx
  test   %edx,%edx
  jle    L153
  nopl   0x0(%rax)
L63:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L63
L153:
  add    (%rsp),%edi
  add    0xc(%rsp),%r9d
  jmp    L110
L18:
  sub    %r13d,%eax
  imul   %eax,%r15d
  add    %r12d,%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L111
  mov    %rax,%rdi
  mov    %r15d,%edx
  xor    %esi,%esi
  mov    %rax,(%rsp)
  call   <memset@plt>
  mov    %r12d,%r11d
  mov    (%rsp),%r8
  xor    %r9d,%r9d
  xor    %edi,%edi
  sub    %r13d,%r11d
  jns    L25
L144:
  mov    %r8,%rdx
  jmp    L47
```

assistant: ```c
char *replace(char *line, char *pattern, char *replace) {
  int i, j, k, llen, plen, rlen, count;
  char *newline;
  count = countStrStr(line, pattern);
  llen = strlen(line);
  plen = strlen(pattern);
  rlen = strlen(replace);
  if (rlen != plen) {
    newline = malloc(llen + count * (rlen - plen));
    if (!newline) {
      return NULL;
    }
    memset(newline, 0, llen + count * (rlen - plen));
  } else {
    newline = line;
  }
  for (i = 0, k = 0; i <= llen - plen; i++, k++) {
    for (j = 0; j < plen; j++) {
      if (line[i + j] != pattern[j]) {
        break;
      }
    }
    if (j == plen) {
      for (j = 0; j < rlen; j++) {
        newline[k + j] = replace[j];
      }
      i += plen - 1;
      k += rlen - 1;
      count++;
    } else {
      newline[k] = line[i];
    }
  }
  for (i = llen - plen + 1; i < llen; i++, k++) {
    newline[k] = line[i];
  }
  newline[k] = '\0';
  return newline;
}
```