user: What is the c source code of the assembly code below:

```asm
<create_letter_distribution_diagram>:
  endbr64
  push   %r14
  mov    $0x61,%edx
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xd0(%rsp),%rbx
  mov    %rbp,%rax
  nopl   0x0(%rax)
L3:
  mov    %edx,(%rax)
  add    $0x8,%rax
  add    $0x1,%edx
  movl   $0x0,-0x4(%rax)
  cmp    %rbx,%rax
  jne    L3
  mov    %r14,%rdi
  xor    %r13d,%r13d
  lea    0xd4(%rbp),%r12
  call   <strlen@plt>
  cmp    %r13d,%eax
  jle    L51
  nopl   0x0(%rax)
L128:
  movsbl (%r14,%r13,1),%ecx
  lea    0x4(%rsp),%rax
  jmp    L106
  nopl   0x0(%rax)
L163:
  sub    $0x20,%edx
  cmp    %ecx,%edx
  je     L57
  add    $0x8,%rax
  cmp    %r12,%rax
  je     L142
L106:
  mov    -0x4(%rax),%edx
  cmp    %ecx,%edx
  jne    L163
L57:
  addl   $0x1,(%rax)
  add    $0x8,%rax
  cmp    %r12,%rax
  jne    L106
L142:
  mov    %r14,%rdi
  add    $0x1,%r13
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L128
L51:
  mov    %rbp,%rdx
  nopw   0x0(%rax,%rax,1)
L162:
  mov    %rbp,%rax
  jmp    L135
  nopl   (%rax)
L62:
  mov    (%rdx),%edi
  mov    (%rax),%r8d
  mov    %r8d,(%rdx)
  mov    %edi,(%rax)
  mov    %esi,0x4(%rdx)
  mov    %ecx,0x4(%rax)
L0:
  add    $0x8,%rax
  cmp    %rbx,%rax
  je     L103
L135:
  mov    0x4(%rdx),%ecx
  mov    0x4(%rax),%esi
  cmp    %esi,%ecx
  jg     L62
  jne    L0
  mov    (%rdx),%esi
  mov    (%rax),%edi
  cmp    %edi,%esi
  jge    L0
  mov    %edi,(%rdx)
  add    $0x8,%rax
  mov    %esi,-0x8(%rax)
  mov    %ecx,0x4(%rdx)
  mov    %ecx,-0x4(%rax)
  cmp    %rbx,%rax
  jne    L135
  nopl   0x0(%rax)
L103:
  add    $0x8,%rdx
  cmp    %rbx,%rdx
  jne    L162
  lea    D4(%rip),%r12
L160:
  mov    0x4(%rbp),%edx
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x8,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L160
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: %c: %d 


assistant: ```c
int create_letter_distribution_diagram(char izrechenie[50]) {
  int alphabet[26][2];
  int counter = 0, lines, ascii = 97, asciicode, tmp;
  for (lines = 0; lines < 26; lines++) {
    alphabet[lines][0] = ascii + lines;
    alphabet[lines][1] = 0;
  }
  while (counter < strlen(izrechenie)) {
    asciicode = izrechenie[counter];
    for (lines = 0; lines < 26; lines++) {
      if (asciicode == alphabet[lines][0] || asciicode == alphabet[lines][0] - 32) {
        alphabet[lines][1]++;
      }
    }
    counter++;
  }
  for (lines = 0; lines < 26; lines++) {
    for (counter = 0; counter < 26; counter++) {
      if (alphabet[lines][1] > alphabet[counter][1]) {
        tmp = alphabet[lines][0];
        alphabet[lines][0] = alphabet[counter][0];
        alphabet[counter][0] = tmp;
        tmp = alphabet[lines][1];
        alphabet[lines][1] = alphabet[counter][1];
        alphabet[counter][1] = tmp;
      } else if (alphabet[lines][1] == alphabet[counter][1]) {
        if (alphabet[lines][0] < alphabet[counter][0]) {
          tmp = alphabet[lines][0];
          alphabet[lines][0] = alphabet[counter][0];
          alphabet[counter][0] = tmp;
          tmp = alphabet[lines][1];
          alphabet[lines][1] = alphabet[counter][1];
          alphabet[counter][1] = tmp;
        }
      }
    }
  }
  for (lines = 0; lines < 26; lines++) {
    printf("%c: %d \n", alphabet[lines][0], alphabet[lines][1]);
  }
  return 0;
}
```