ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<get_revoke_only_sys_string>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  cmp    $0x79,%sil
  je     L18
  mov    %rdi,%rcx
  lea    D21(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <sprintf@plt>
L0:
  lea    D3(%rip),%rax
  add    $0x8,%rsp
  ret
L18:
  mov    %rdi,%rcx
  lea    D42(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <sprintf@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D42
type_infered: string

tool: D21: echo "revoke all on *.* from %s; | sql.e" | html_paragraph_wrapper;echo "drop user %s | sql.e '^' mysql mysql" | html_paragraph_wrapper;echo "flush privileges; | sql.e '^' mysql mysql" | html_paragraph_wrapper

tool: D42: echo "revoke all on *.* from %s;" | sql.e;echo "drop user %s;" | sql.e '^' mysql mysql;echo "flush privileges;" | sql.e '^' mysql mysql

assistant: ```c
char *get_revoke_only_sys_string(char *login_host_name, char really_yn) {
  static char sys_string[1024];
  if (really_yn == 'y') {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s;\" | sql.e;"
            "echo \"drop user %s;\" | sql.e '^' mysql mysql;"
            "echo \"flush privileges;\" | sql.e '^' mysql mysql",
            login_host_name, login_host_name);
  } else {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s; | sql.e\" | html_paragraph_wrapper;"
            "echo \"drop user %s | sql.e '^' mysql mysql\" | html_paragraph_wrapper;"
            "echo \"flush privileges; | sql.e '^' mysql mysql\" | html_paragraph_wrapper",
            login_host_name, login_host_name);
  }
  return sys_string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_revoke_only_sys_string>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  cmp    $0x79,%sil
  je     L8
  lea    D21(%rip),%r12
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  lea    D21(%rip),%r12
  lea    D12(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D12
type: string

tool: D14: echo "revoke all on *.* from %s; | sql.e" | html_paragraph_wrapper;echo "drop user %s | sql.e '^' mysql mysql" | html_paragraph_wrapper;echo "flush privileges; | sql.e '^' mysql mysql" | html_paragraph_wrapper

tool: D12: echo "revoke all on *.* from %s;" | sql.e;echo "drop user %s;" | sql.e '^' mysql mysql;echo "flush privileges;" | sql.e '^' mysql mysql

assistant: ```c
char *get_revoke_only_sys_string(char *login_host_name, char really_yn) {
  static char sys_string[1024];
  if (really_yn == 'y') {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s;\" | sql.e;"
            "echo \"drop user %s;\" | sql.e '^' mysql mysql;"
            "echo \"flush privileges;\" | sql.e '^' mysql mysql",
            login_host_name, login_host_name);
  } else {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s; | sql.e\" | html_paragraph_wrapper;"
            "echo \"drop user %s | sql.e '^' mysql mysql\" | html_paragraph_wrapper;"
            "echo \"flush privileges; | sql.e '^' mysql mysql\" | html_paragraph_wrapper",
            login_host_name, login_host_name);
  }
  return sys_string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_revoke_only_sys_string>:
  endbr64
  push   %r12
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  cmp    $0x79,%sil
  je     L0
  lea    D32(%rip),%r12
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  lea    D32(%rip),%r12
  lea    D20(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D20
datatype: string

tool: D2: echo "revoke all on *.* from %s; | sql.e" | html_paragraph_wrapper;echo "drop user %s | sql.e '^' mysql mysql" | html_paragraph_wrapper;echo "flush privileges; | sql.e '^' mysql mysql" | html_paragraph_wrapper

tool: D20: echo "revoke all on *.* from %s;" | sql.e;echo "drop user %s;" | sql.e '^' mysql mysql;echo "flush privileges;" | sql.e '^' mysql mysql

assistant: ```c
char *get_revoke_only_sys_string(char *login_host_name, char really_yn) {
  static char sys_string[1024];
  if (really_yn == 'y') {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s;\" | sql.e;"
            "echo \"drop user %s;\" | sql.e '^' mysql mysql;"
            "echo \"flush privileges;\" | sql.e '^' mysql mysql",
            login_host_name, login_host_name);
  } else {
    sprintf(sys_string,
            "echo \"revoke all on *.* from %s; | sql.e\" | html_paragraph_wrapper;"
            "echo \"drop user %s | sql.e '^' mysql mysql\" | html_paragraph_wrapper;"
            "echo \"flush privileges; | sql.e '^' mysql mysql\" | html_paragraph_wrapper",
            login_host_name, login_host_name);
  }
  return sys_string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L52
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L17
L52:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  cmpb   $0x0,-0x5(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L17
L29:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strchr(const char *s, int c) {
  char target;
  int i;
  target = c;
  i = 0;
  while (s[i]) {
    if (s[i] == target)
      return ((char *)&(s[i]));
    i++;
  }
  if (target == 0)
    return ((char *)&(s[i]));
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strchr>:
  endbr64
  mov    %esi,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
L5:
  cmp    %al,%dl
  je     L29
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
L28:
  test   %sil,%sil
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L29:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(const char *s, int c) {
  char target;
  int i;
  target = c;
  i = 0;
  while (s[i]) {
    if (s[i] == target)
      return ((char *)&(s[i]));
    i++;
  }
  if (target == 0)
    return ((char *)&(s[i]));
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L16
  jmp    L8
  nop
L27:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L8
L16:
  cmp    %al,%dl
  jne    L27
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(const char *s, int c) {
  char target;
  int i;
  target = c;
  i = 0;
  while (s[i]) {
    if (s[i] == target)
      return ((char *)&(s[i]));
    i++;
  }
  if (target == 0)
    return ((char *)&(s[i]));
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L18
  jmp    L6
  nop
L1:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L6
L18:
  cmp    %al,%dl
  jne    L1
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *ft_strchr(const char *s, int c) {
  char target;
  int i;
  target = c;
  i = 0;
  while (s[i]) {
    if (s[i] == target)
      return ((char *)&(s[i]));
    i++;
  }
  if (target == 0)
    return ((char *)&(s[i]));
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  mov    $0x0,%eax
  jmp    L30
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <reverse@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    $0x1,%eax
  jmp    L30
L1:
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
bool isPalindrome(int x) {
  if (x < 0)
    return 0;
  if (x == reverse(x))
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPalindrome>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L9
  push   %rbx
  mov    %edi,%ebx
  call   <reverse@plt>
  cmp    %ebx,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
bool isPalindrome(int x) {
  if (x < 0)
    return 0;
  if (x == reverse(x))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  js     L8
  push   %rbx
  mov    %edi,%ebx
  call   <reverse@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPalindrome(int x) {
  if (x < 0)
    return 0;
  if (x == reverse(x))
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  js     L6
  push   %rbx
  mov    %edi,%ebx
  call   <reverse@plt>
  cmp    %ebx,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPalindrome(int x) {
  if (x < 0)
    return 0;
  if (x == reverse(x))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cart_norm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r12d
  mov    0x4(%rdi),%ebp
  mov    0x8(%rdi),%ebx
  movapd %xmm0,%xmm2
  movsd  %xmm0,(%rsp)
  addsd  %xmm0,%xmm2
  movapd %xmm2,%xmm3
  divsd  D47(%rip),%xmm3
  movq   %xmm3,%r14
  mov    $0x0,%edi
  movapd %xmm3,%xmm0
  call   <pow@plt>
  movq   %xmm0,%r13
  movsd  (%rsp),%xmm0
  mulsd  D2(%rip),%xmm0
  movq   %xmm0,%r15
  mov    %r12d,%edi
  call   <pow@plt>
  movslq %r12d,%r12
  lea    D37(%rip),%rax
  mulsd  (%rax,%r12,8),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L11
  sqrtsd %xmm0,%xmm0
L31:
  movq   %r13,%xmm5
  mulsd  %xmm5,%xmm0
  movsd  %xmm0,(%rsp)
  mov    $0x0,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %xmm0,%r13
  mov    %ebp,%edi
  movq   %r15,%xmm0
  call   <pow@plt>
  movslq %ebp,%rbp
  lea    D37(%rip),%rax
  mulsd  (%rax,%rbp,8),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L29
  sqrtsd %xmm0,%xmm0
L0:
  movq   %r13,%xmm6
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rbp
  mov    %ebx,%edi
  movq   %r15,%xmm0
  call   <pow@plt>
  movslq %ebx,%rbx
  lea    D37(%rip),%rax
  mulsd  (%rax,%rbx,8),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L41
  sqrtsd %xmm0,%xmm0
L25:
  movsd  (%rsp),%xmm1
  mulsd  0x8(%rsp),%xmm1
  movq   %rbp,%xmm4
  mulsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <sqrt@plt>
  jmp    L31
L29:
  call   <sqrt@plt>
  jmp    L0
L41:
  call   <sqrt@plt>
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: tag: D47
datatype: f64
name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D37
datatype: f64

tool: D47: 3.141592653589793

tool: D2: 4

tool: D37: 1

assistant: ```c
double cart_norm(double a, int *ijk) {
  static int dfac[] = {1, 1, 2, 3, 8, 15, 48, 105, 384, 945, 3840};
  static double inv_dfac[] = {1.0, 1.0, 1 / 2.0, 1 / 3.0, 1 / 8.0, 1 / 15.0, 1 / 48.0, 1 / 105.0, 1 / 384.0, 1 / 945.0, 1 / 3840.0};
  static const double PI = 3.14159265358979323846;
  int i = ijk[0];
  int j = ijk[1];
  int k = ijk[2];
  double ni = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, i) * inv_dfac[i]);
  double nj = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, j) * inv_dfac[j]);
  double nk = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, k) * inv_dfac[k]);
  return ni * nj * nk;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cart_norm>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm1
  push   %r13
  addsd  %xmm0,%xmm1
  push   %r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  divsd  D22(%rip),%xmm1
  movslq (%rdi),%r13
  movslq 0x4(%rdi),%r12
  movslq 0x8(%rdi),%rbx
  movsd  %xmm0,0x18(%rsp)
  xor    %edi,%edi
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  mov    %r13d,%edi
  mulsd  D6(%rip),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  movq   %xmm2,%r14
  call   <pow@plt>
  mulsd  0x0(%rbp,%r13,8),%xmm0
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  ucomisd %xmm0,%xmm3
  ja     L7
  sqrtsd %xmm0,%xmm0
L56:
  mulsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %r12d,%edi
  movsd  %xmm0,0x8(%rsp)
  movq   %r14,%xmm0
  call   <pow@plt>
  mulsd  0x0(%rbp,%r12,8),%xmm0
  pxor   %xmm5,%xmm5
  movsd  0x18(%rsp),%xmm1
  ucomisd %xmm0,%xmm5
  ja     L15
  sqrtsd %xmm0,%xmm0
L5:
  mulsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  movq   %r14,%xmm0
  call   <pow@plt>
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  pxor   %xmm7,%xmm7
  ucomisd %xmm0,%xmm7
  ja     L9
  sqrtsd %xmm0,%xmm0
L47:
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mulsd  0x18(%rsp),%xmm1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mulsd  %xmm1,%xmm0
  ret
L7:
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm1
  jmp    L56
L9:
  call   <sqrt@plt>
  jmp    L47
L15:
  movsd  %xmm1,0x18(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm1
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type: f64
name: extract_symbolic_data
arguments: data_tag: D22
type: f64
name: extract_symbolic_data
arguments: data_tag: D6
type: f64

tool: D24: 1

tool: D22: 3.141592653589793

tool: D6: 4

assistant: ```c
double cart_norm(double a, int *ijk) {
  static int dfac[] = {1, 1, 2, 3, 8, 15, 48, 105, 384, 945, 3840};
  static double inv_dfac[] = {1.0, 1.0, 1 / 2.0, 1 / 3.0, 1 / 8.0, 1 / 15.0, 1 / 48.0, 1 / 105.0, 1 / 384.0, 1 / 945.0, 1 / 3840.0};
  static const double PI = 3.14159265358979323846;
  int i = ijk[0];
  int j = ijk[1];
  int k = ijk[2];
  double ni = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, i) * inv_dfac[i]);
  double nj = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, j) * inv_dfac[j]);
  double nk = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, k) * inv_dfac[k]);
  return ni * nj * nk;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cart_norm>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm1
  push   %r13
  addsd  %xmm0,%xmm1
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  divsd  D24(%rip),%xmm1
  movslq (%rdi),%r13
  movslq 0x4(%rdi),%r12
  movslq 0x8(%rdi),%rbx
  movsd  %xmm0,0x18(%rsp)
  xor    %edi,%edi
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  mov    %r13d,%edi
  mulsd  D9(%rip),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  movq   %xmm2,%r14
  call   <pow@plt>
  mulsd  0x0(%rbp,%r13,8),%xmm0
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  ucomisd %xmm0,%xmm3
  ja     L13
  sqrtsd %xmm0,%xmm0
L38:
  mulsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %r12d,%edi
  movsd  %xmm0,0x8(%rsp)
  movq   %r14,%xmm0
  call   <pow@plt>
  mulsd  0x0(%rbp,%r12,8),%xmm0
  pxor   %xmm5,%xmm5
  movsd  0x18(%rsp),%xmm1
  ucomisd %xmm0,%xmm5
  ja     L54
  sqrtsd %xmm0,%xmm0
L25:
  mulsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  movq   %r14,%xmm0
  call   <pow@plt>
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  pxor   %xmm7,%xmm7
  ucomisd %xmm0,%xmm7
  ja     L34
  sqrtsd %xmm0,%xmm0
L45:
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mulsd  0x18(%rsp),%xmm1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  mulsd  %xmm1,%xmm0
  ret
L13:
  movsd  %xmm1,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm1
  jmp    L38
L34:
  call   <sqrt@plt>
  jmp    L45
L54:
  movsd  %xmm1,0x18(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm1
  jmp    L25
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: f64
name: unpack_data
arguments: data_label: D24
type_infered: f64
name: unpack_data
arguments: data_label: D9
type_infered: f64

tool: D17: 1

tool: D24: 3.141592653589793

tool: D9: 4

assistant: ```c
double cart_norm(double a, int *ijk) {
  static int dfac[] = {1, 1, 2, 3, 8, 15, 48, 105, 384, 945, 3840};
  static double inv_dfac[] = {1.0, 1.0, 1 / 2.0, 1 / 3.0, 1 / 8.0, 1 / 15.0, 1 / 48.0, 1 / 105.0, 1 / 384.0, 1 / 945.0, 1 / 3840.0};
  static const double PI = 3.14159265358979323846;
  int i = ijk[0];
  int j = ijk[1];
  int k = ijk[2];
  double ni = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, i) * inv_dfac[i]);
  double nj = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, j) * inv_dfac[j]);
  double nk = pow(2.0 * a / PI, 0.25) * sqrt(pow(4.0 * a, k) * inv_dfac[k]);
  return ni * nj * nk;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inet_netof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L36
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  mov    %ebx,%edx
  and    %eax,%edx
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L3
L36:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L38
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%ebx
  mov    %ebx,%edx
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L3
L38:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%ebx
  mov    %ebx,%edx
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_long i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L27
  mov    D28(%rip),%rax
  and    (%rax),%ebx
  mov    %ebx,%eax
  mov    D33(%rip),%rdx
  mov    (%rdx),%ecx
  sar    %cl,%eax
L25:
  pop    %rbx
  ret
L27:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L35
  mov    D58(%rip),%rax
  and    (%rax),%ebx
  mov    D59(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L25
L35:
  mov    D11(%rip),%rax
  and    (%rax),%ebx
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  sar    %cl,%eax
  jmp    L25
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_long i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L13
  mov    D36(%rip),%rax
  mov    D31(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L13:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L14
  mov    D15(%rip),%rax
  and    (%rax),%ebx
  mov    D19(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L14:
  mov    D22(%rip),%rax
  and    (%rax),%ebx
  mov    D16(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_long i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: What is the c source code of the assembly code below:

```asm
<inet_netof>:
  endbr64
  push   %rbx
  call   <ntohl@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <IN_CLASSA@plt>
  test   %rax,%rax
  je     L16
  mov    D55(%rip),%rax
  mov    D49(%rip),%rdx
  and    (%rax),%ebx
  mov    (%rdx),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
L16:
  mov    %ebx,%edi
  call   <IN_CLASSB@plt>
  test   %rax,%rax
  je     L10
  mov    D14(%rip),%rax
  and    (%rax),%ebx
  mov    D40(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
  nopl   0x0(%rax)
L10:
  mov    D11(%rip),%rax
  and    (%rax),%ebx
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  mov    %ebx,%eax
  pop    %rbx
  sar    %cl,%eax
  ret
```

assistant: ```c
in_addr_t inet_netof(struct in_addr in) {
  register u_long i = ntohl(in.s_addr);
  if (IN_CLASSA(i))
    return (((i)&IN_CLASSA_NET) >> IN_CLASSA_NSHIFT);
  else if (IN_CLASSB(i))
    return (((i)&IN_CLASSB_NET) >> IN_CLASSB_NSHIFT);
  else
    return (((i)&IN_CLASSC_NET) >> IN_CLASSC_NSHIFT);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cacguard2l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  lea    -0x18(%rbp),%rdi
  lea    -0x14(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0xc(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <acguard2l_@plt>
  nop
  leave
  ret
```

assistant: ```c
void cacguard2l(float cu[], int nx, int ny, int nxe, int nye) {
  acguard2l_(cu, &nx, &ny, &nxe, &nye);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cacguard2l>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %r8d,(%rsp)
  lea    0x4(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rsp,%r8
  call   <acguard2l_@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void cacguard2l(float cu[], int nx, int ny, int nxe, int nye) {
  acguard2l_(cu, &nx, &ny, &nxe, &nye);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cacguard2l>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %edx,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  mov    %ecx,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    %r8d,(%rsp)
  mov    %rsp,%r8
  call   <acguard2l_@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void cacguard2l(float cu[], int nx, int ny, int nxe, int nye) {
  acguard2l_(cu, &nx, &ny, &nxe, &nye);
  return;
}
```