user: 这段汇编代码用C语言表示是什么样的:

```asm
<transpose_alignment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  lea    0x10(,%rsi,8),%edi
  mov    %rcx,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L79
L116:
  mov    0x10(%rsp),%r13
  lea    0x0(,%rbp,4),%r12d
  xor    %r14d,%r14d
  lea    D18(%rip),%r15
  cmp    $0xffffffff,%ebx
  jge    L121
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L54:
  lea    0x1(%r14),%eax
  add    $0x8,%r13
  cmp    %r14d,%ebx
  jl     L27
L31:
  mov    %eax,%r14d
L121:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  jne    L54
  mov    %r15,%rdi
  add    $0x8,%r13
  call   <Die@plt>
  lea    0x1(%r14),%eax
  cmp    %r14d,%ebx
  jge    L31
  cs nopw 0x0(%rax,%rax,1)
L27:
  test   %ebp,%ebp
  jle    L65
  mov    0x10(%rsp),%rax
  movslq %ebx,%r12
  lea    0x0(,%rbp,4),%r14
  lea    -0x1(%rbp),%r13d
  mov    0x8(%rax,%r12,8),%r15
  mov    (%rax),%rdi
  lea    (%r15,%r14,1),%rax
  cmp    %rax,%rdi
  jae    L0
  lea    (%rdi,%r14,1),%rax
  cmp    %rax,%r15
  jb     L84
L0:
  mov    %r14,%rdx
  mov    $0xff,%esi
  call   <memset@plt>
  mov    %r14,%rdx
  mov    $0xff,%esi
  mov    %r15,%rdi
  call   <memset@plt>
L147:
  test   %ebx,%ebx
  jle    L65
  movabs $0x8000000000006001,%r14
  mov    (%rsp),%r15
  lea    0x8(%r15,%r13,8),%rax
  xor    %r13d,%r13d
  mov    %rax,(%rsp)
  mov    0x10(%rsp),%rax
  add    $0x8,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L86:
  mov    0x8(%rsp),%rbp
  xor    %ebx,%ebx
L120:
  mov    (%r15),%r9
L142:
  movsbl (%r9,%rbx,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x3f,%al
  jbe    L17
L104:
  call   <SymbolIndex@plt>
  mov    0x0(%rbp),%rdx
  add    $0x1,%rbx
  add    $0x8,%rbp
  mov    %eax,(%rdx,%r13,1)
  cmp    %r12,%rbx
  jne    L120
  add    $0x4,%r13
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L86
L65:
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rcx
  mov    %rcx,(%rax)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  bt     %rax,%r14
  jae    L104
  mov    0x0(%rbp),%rax
  add    $0x1,%rbx
  add    $0x8,%rbp
  movl   $0xffffffff,(%rax,%r13,1)
  cmp    %rbx,%r12
  jne    L142
  add    $0x4,%r13
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L86
  jmp    L65
L79:
  lea    D18(%rip),%rdi
  call   <Die@plt>
  jmp    L116
L84:
  xor    %eax,%eax
  xchg   %ax,%ax
L135:
  movl   $0xffffffff,(%rdi,%rax,4)
  movl   $0xffffffff,(%r15,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L135
  jmp    L147
```

tool_calls: name: unpack_data
arguments: label: D18
type: string

tool: D18: malloc failed

assistant: ```c
void transpose_alignment(char **aseqs, int alen, int nseq, int ***ret_aseqsT) {
  int **aseqsT;
  int acol;
  int seqidx;
  if ((aseqsT = (int **)malloc((alen + 2) * sizeof(int *))) == NULL)
    Die("malloc failed");
  for (acol = 0; acol <= alen + 1; acol++)
    if ((aseqsT[acol] = (int *)malloc(nseq * sizeof(int))) == NULL)
      Die("malloc failed");
  for (seqidx = 0; seqidx < nseq; seqidx++) {
    aseqsT[0][seqidx] = -1;
    aseqsT[alen + 1][seqidx] = -1;
  }
  for (seqidx = 0; seqidx < nseq; seqidx++)
    for (acol = 0; acol < alen; acol++)
      aseqsT[acol + 1][seqidx] = ((aseqs[seqidx][acol]) == ' ' || (aseqs[seqidx][acol]) == '.' || (aseqs[seqidx][acol]) == '_' || (aseqs[seqidx][acol]) == '-') ? -1 : SymbolIndex(aseqs[seqidx][acol]);
  *ret_aseqsT = aseqsT;
}
```