ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clr@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D11
type_infered: string
name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D18
type_infered: string

tool: D11: Hello world! I am in.

tool: D7: i = %d


tool: D18: 
This is test

assistant: ```c
int main() {
  clr();
  goto printme;
  for (int i = 0; i <= 5; i++) {
    printf("i = %d", i);
    if (i == 5) {
    printme:
      printf("Hello world! I am in.\n");
    }
    printf("i = %d\n", i + 1);
  }
  printf("\nThis is test");
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clr@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D14: Hello world! I am in.

tool: D4: i = %d


tool: D16: 
This is test

assistant: ```c
int main() {
  clr();
  goto printme;
  for (int i = 0; i <= 5; i++) {
    printf("i = %d", i);
    if (i == 5) {
    printme:
      printf("Hello world! I am in.\n");
    }
    printf("i = %d\n", i + 1);
  }
  printf("\nThis is test");
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <_tigermain@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D9: 
Executing!

tool: D2: 
Result = %d


assistant: ```c
int main() {
  printf("\nExecuting!\n");
  printf("\nResult = %d\n", _tigermain(0));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <_tigermain@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D13: 
Executing!

tool: D4: 
Result = %d


assistant: ```c
int main() {
  printf("\nExecuting!\n");
  printf("\nResult = %d\n", _tigermain(0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <_tigermain@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string

tool: D8: 
Executing!

tool: D2: 
Result = %d


assistant: ```c
int main() {
  printf("\nExecuting!\n");
  printf("\nResult = %d\n", _tigermain(0));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <_tigermain@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D8: 
Executing!

tool: D14: 
Result = %d


assistant: ```c
int main() {
  printf("\nExecuting!\n");
  printf("\nResult = %d\n", _tigermain(0));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  jg     L27
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x32,-0x4(%rbp)
  jbe    L27
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L28
L27:
  mov    $0x0,%eax
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: Surprise! Bad input : %x 


assistant: ```c
int main(int argc, char **argv) {
  int i = atol(argv[1]);
  unsigned int j = 0;
  if (i < 10) {
    j = i;
    if (j > 50) {
      printf("Surprise! Bad input : %x \n", j);
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    $0x0,%edx
  cmp    $0x9,%eax
  jg     L9
  cmp    $0x32,%eax
  ja     L27
L9:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L27:
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edx
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: Surprise! Bad input : %x 


assistant: ```c
int main(int argc, char **argv) {
  int i = atol(argv[1]);
  unsigned int j = 0;
  if (i < 10) {
    j = i;
    if (j > 50) {
      printf("Surprise! Bad input : %x \n", j);
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%esi
  xor    %eax,%eax
  cmp    $0x9,%esi
  jg     L20
  cmp    $0x32,%esi
  ja     L24
L20:
  add    $0x8,%rsp
  ret
L24:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L20
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: Surprise! Bad input : %x 


assistant: ```c
int main(int argc, char **argv) {
  int i = atol(argv[1]);
  unsigned int j = 0;
  if (i < 10) {
    j = i;
    if (j > 50) {
      printf("Surprise! Bad input : %x \n", j);
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%esi
  xor    %eax,%eax
  cmp    $0x9,%esi
  jg     L22
  cmp    $0x32,%esi
  ja     L6
L22:
  add    $0x8,%rsp
  ret
L6:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L22
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: Surprise! Bad input : %x 


assistant: ```c
int main(int argc, char **argv) {
  int i = atol(argv[1]);
  unsigned int j = 0;
  if (i < 10) {
    j = i;
    if (j > 50) {
      printf("Surprise! Bad input : %x \n", j);
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x3a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L20
L60:
  lea    -0x1390(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fold@plt>
  mov    %eax,-0x1394(%rbp)
  movl   $0x0,-0x13a0(%rbp)
  jmp    L7
L24:
  mov    -0x13a0(%rbp),%eax
  cltq
  mov    -0x1390(%rbp,%rax,4),%eax
  mov    %eax,-0x139c(%rbp)
  jmp    L18
L54:
  mov    -0x139c(%rbp),%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x139c(%rbp)
L18:
  mov    -0x13a0(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1390(%rbp,%rax,4),%eax
  cmp    %eax,-0x139c(%rbp)
  jle    L54
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x2,-0x13a0(%rbp)
L7:
  mov    -0x1394(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x13a0(%rbp)
  jl     L24
L20:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x1398(%rbp)
  cmpl   $0x0,-0x1398(%rbp)
  jg     L60
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int main() {
  int len, y, x, numpos;
  char input[1000];
  char shortline[1000];
  int posic[1000];
  while ((len = getline(input, 1000)) > 0) {
    numpos = fold(input, posic);
    for (y = 0; y < numpos - 1; y += 2) {
      for (x = posic[y]; x <= posic[y + 1]; ++x)
        printf("%c", input[x]);
      printf("\n");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x390,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1388(%rsp)
  xor    %eax,%eax
  lea    0xfa0(%rsp),%r12
L27:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jle    L33
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <fold@plt>
  cmp    $0x1,%eax
  jle    L27
  lea    0x4(%rsp),%r13
  sub    $0x2,%eax
  shr    %eax
  mov    %eax,%eax
  lea    0xc(%rsp,%rax,8),%r14
L3:
  mov    %r13,%rbp
  mov    -0x4(%r13),%ebx
  cmp    0x0(%r13),%ebx
  jg     L50
  movslq %ebx,%rbx
L60:
  movsbl (%rbx,%r12,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%rbp)
  jge    L60
L50:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r13
  cmp    %r14,%r13
  jne    L3
  jmp    L27
L33:
  mov    0x1388(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x1390,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int len, y, x, numpos;
  char input[1000];
  char shortline[1000];
  int posic[1000];
  while ((len = getline(input, 1000)) > 0) {
    numpos = fold(input, posic);
    for (y = 0; y < numpos - 1; y += 2) {
      for (x = posic[y]; x <= posic[y + 1]; ++x)
        printf("%c", input[x]);
      printf("\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x390,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1388(%rsp)
  xor    %eax,%eax
  lea    0xfa0(%rsp),%r12
  mov    %rsp,%r14
  nopl   (%rax)
L65:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jle    L51
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fold@plt>
  cmp    $0x1,%eax
  jle    L65
  sub    $0x2,%eax
  lea    0x4(%rsp),%rbp
  shr    %eax
  lea    0xc(%rsp,%rax,8),%r13
L22:
  movslq -0x4(%rbp),%rbx
  cmp    0x0(%rbp),%ebx
  jg     L47
  nopl   0x0(%rax)
L48:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jge    L48
L47:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L22
  jmp    L65
L51:
  mov    0x1388(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x1390,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int len, y, x, numpos;
  char input[1000];
  char shortline[1000];
  int posic[1000];
  while ((len = getline(input, 1000)) > 0) {
    numpos = fold(input, posic);
    for (y = 0; y < numpos - 1; y += 2) {
      for (x = posic[y]; x <= posic[y + 1]; ++x)
        printf("%c", input[x]);
      printf("\n");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x390,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1388(%rsp)
  xor    %eax,%eax
  lea    0xfa0(%rsp),%r12
  mov    %rsp,%r14
  nopl   (%rax)
L57:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  test   %eax,%eax
  jle    L47
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fold@plt>
  cmp    $0x1,%eax
  jle    L57
  sub    $0x2,%eax
  lea    0x4(%rsp),%rbp
  shr    %eax
  lea    0xc(%rsp,%rax,8),%r13
L69:
  movslq -0x4(%rbp),%rbx
  cmp    0x0(%rbp),%ebx
  jg     L63
  nopl   0x0(%rax)
L24:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,0x0(%rbp)
  jge    L24
L63:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L69
  jmp    L57
L47:
  mov    0x1388(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x1390,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int len, y, x, numpos;
  char input[1000];
  char shortline[1000];
  int posic[1000];
  while ((len = getline(input, 1000)) > 0) {
    numpos = fold(input, posic);
    for (y = 0; y < numpos - 1; y += 2) {
      for (x = posic[y]; x <= posic[y + 1]; ++x)
        printf("%c", input[x]);
      printf("\n");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nextpkg>:
  endbr64
  push   %r12
  mov    %rdx,%r10
  push   %rbx
  mov    (%rcx),%r8d
  mov    (%rdx),%r9
  movl   $0x0,(%rdi)
  test   %r8d,%r8d
  je     L64
  mov    %rsi,%r11
  movzbl (%r9),%esi
  lea    -0x1(%r8),%eax
  test   %sil,%sil
  jns    L64
  test   %eax,%eax
  jle    L64
  mov    %rcx,%rdx
  test   $0x40,%sil
  jne    L21
  mov    %esi,%ecx
  and    $0x3,%ecx
  cmp    $0x3,%cl
  je     L64
  mov    $0x1,%ebx
  shl    %cl,%ebx
  cmp    %ebx,%eax
  jl     L64
  lea    0x1(%rbx),%r12d
  lea    0x1(%r9),%rcx
  xor    %eax,%eax
  add    %r9,%r12
L112:
  movzbl (%rcx),%r9d
  shl    $0x8,%eax
  add    $0x1,%rcx
  or     %r9d,%eax
  cmp    %rcx,%r12
  jne    L112
  not    %ebx
  shr    $0x2,%esi
  lea    (%rbx,%r8,1),%ecx
  and    $0xf,%esi
L119:
  cmp    %ecx,%eax
  jg     L64
  movslq %eax,%r8
  sub    %eax,%ecx
  add    %r12,%r8
  mov    %r8,(%r10)
  mov    %ecx,(%rdx)
  mov    %eax,(%r11)
  mov    %r12,%rax
  pop    %rbx
  mov    %esi,(%rdi)
  pop    %r12
  ret
  xchg   %ax,%ax
L65:
  cmp    $0x4,%ecx
  jle    L64
  cmp    $0xff,%eax
  je     L109
L64:
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  movzbl 0x1(%r9),%eax
  and    $0x3f,%esi
  lea    -0x2(%r8),%ecx
  lea    0x2(%r9),%r12
  cmp    $0xbf,%eax
  jle    L119
  lea    -0xc0(%rax),%ebx
  cmp    $0x1f,%ebx
  ja     L65
  test   %ecx,%ecx
  jle    L64
  movzbl 0x2(%r9),%eax
  shl    $0x8,%ebx
  lea    0x3(%r9),%r12
  lea    -0x3(%r8),%ecx
  lea    0xc0(%rbx,%rax,1),%eax
  jmp    L119
  nop
L109:
  mov    0x2(%r9),%eax
  lea    0x6(%r9),%r12
  lea    -0x6(%r8),%ecx
  bswap  %eax
  jmp    L119
```

assistant: ```c
unsigned char *nextpkg(int *tagp, int *pkgl, unsigned char **pp, int *ppl) {
  int x, l;
  unsigned char *p = *pp;
  int pl = *ppl;
  int tag;
  *tagp = 0;
  if (!pl)
    return 0;
  x = *p++;
  pl--;
  if (!(x & 128) || pl <= 0)
    return 0;
  if ((x & 64) == 0) {
    tag = (x & 0x3c) >> 2;
    x &= 3;
    if (x == 3)
      return 0;
    l = 1 << x;
    if (pl < l)
      return 0;
    x = 0;
    while (l--) {
      x = x << 8 | *p++;
      pl--;
    }
    l = x;
  } else {
    tag = (x & 0x3f);
    x = *p++;
    pl--;
    if (x < 192)
      l = x;
    else if (x >= 192 && x < 224) {
      if (pl <= 0)
        return 0;
      l = ((x - 192) << 8) + *p++ + 192;
      pl--;
    } else if (x == 255) {
      if (pl <= 4)
        return 0;
      l = p[0] << 24 | p[1] << 16 | p[2] << 8 | p[3];
      p += 4;
      pl -= 4;
    } else
      return 0;
  }
  if (pl < l)
    return 0;
  *pp = p + l;
  *ppl = pl - l;
  *pkgl = l;
  *tagp = tag;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nextpkg>:
  endbr64
  push   %r12
  mov    %rdx,%r9
  push   %rbx
  mov    (%rcx),%ebx
  mov    (%rdx),%r8
  movl   $0x0,(%rdi)
  test   %ebx,%ebx
  je     L39
  mov    %rdi,%rax
  movzbl (%r8),%edi
  mov    %rsi,%r10
  lea    -0x1(%rbx),%esi
  test   %dil,%dil
  jns    L39
  test   %esi,%esi
  jle    L39
  mov    %rcx,%rdx
  test   $0x40,%dil
  jne    L80
  mov    %edi,%ecx
  and    $0x3,%ecx
  cmp    $0x3,%cl
  je     L39
  mov    $0x1,%r11d
  shl    %cl,%r11d
  cmp    %r11d,%esi
  jl     L39
  movzbl 0x1(%r8),%esi
  cmp    $0x1,%r11d
  je     L141
  movzbl 0x2(%r8),%r12d
  shl    $0x8,%esi
  or     %r12d,%esi
  cmp    $0x1,%cl
  je     L141
  movzbl 0x3(%r8),%ecx
  shl    $0x8,%esi
  or     %esi,%ecx
  movzbl 0x4(%r8),%esi
  shl    $0x8,%ecx
  or     %ecx,%esi
L141:
  lea    0x1(%r11),%r12d
  shr    $0x2,%edi
  not    %r11d
  movslq %r12d,%r12
  lea    (%r11,%rbx,1),%ecx
  and    $0xf,%edi
  add    %r8,%r12
L122:
  cmp    %ecx,%esi
  jg     L39
  movslq %esi,%r8
  sub    %esi,%ecx
  add    %r12,%r8
  mov    %r8,(%r9)
  mov    %ecx,(%rdx)
  mov    %esi,(%r10)
  mov    %edi,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L155:
  cmp    $0x4,%ecx
  jle    L39
  cmp    $0xff,%esi
  je     L113
L39:
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  movzbl 0x1(%r8),%esi
  and    $0x3f,%edi
  lea    -0x2(%rbx),%ecx
  lea    0x2(%r8),%r12
  cmp    $0xbf,%esi
  jle    L122
  lea    -0xc0(%rsi),%r11d
  cmp    $0x1f,%r11d
  ja     L155
  test   %ecx,%ecx
  jle    L39
  movzbl 0x2(%r8),%ecx
  shl    $0x8,%r11d
  lea    0x3(%r8),%r12
  lea    0xc0(%r11,%rcx,1),%esi
  lea    -0x3(%rbx),%ecx
  jmp    L122
  nopl   (%rax)
L113:
  mov    0x2(%r8),%esi
  lea    0x6(%r8),%r12
  lea    -0x6(%rbx),%ecx
  bswap  %esi
  jmp    L122
```

assistant: ```c
unsigned char *nextpkg(int *tagp, int *pkgl, unsigned char **pp, int *ppl) {
  int x, l;
  unsigned char *p = *pp;
  int pl = *ppl;
  int tag;
  *tagp = 0;
  if (!pl)
    return 0;
  x = *p++;
  pl--;
  if (!(x & 128) || pl <= 0)
    return 0;
  if ((x & 64) == 0) {
    tag = (x & 0x3c) >> 2;
    x &= 3;
    if (x == 3)
      return 0;
    l = 1 << x;
    if (pl < l)
      return 0;
    x = 0;
    while (l--) {
      x = x << 8 | *p++;
      pl--;
    }
    l = x;
  } else {
    tag = (x & 0x3f);
    x = *p++;
    pl--;
    if (x < 192)
      l = x;
    else if (x >= 192 && x < 224) {
      if (pl <= 0)
        return 0;
      l = ((x - 192) << 8) + *p++ + 192;
      pl--;
    } else if (x == 255) {
      if (pl <= 4)
        return 0;
      l = p[0] << 24 | p[1] << 16 | p[2] << 8 | p[3];
      p += 4;
      pl -= 4;
    } else
      return 0;
  }
  if (pl < l)
    return 0;
  *pp = p + l;
  *ppl = pl - l;
  *pkgl = l;
  *tagp = tag;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_vector(double *from_vector, double *to_vector, int size) {
  int i;
  for (i = 0; i < size; ++i)
    to_vector[i] = from_vector[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_vector>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  mov    $0x0,%eax
L7:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
L18:
  ret
```

assistant: ```c
void copy_vector(double *from_vector, double *to_vector, int size) {
  int i;
  for (i = 0; i < size; ++i)
    to_vector[i] = from_vector[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_vector>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L10:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L14:
  ret
```

assistant: ```c
void copy_vector(double *from_vector, double *to_vector, int size) {
  int i;
  for (i = 0; i < size; ++i)
    to_vector[i] = from_vector[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_vector>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L56
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L54
  lea    0x8(%rdi),%rax
  cmp    %rax,%rsi
  je     L54
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L3:
  movupd (%rcx,%rax,1),%xmm1
  movups %xmm1,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L3
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L56
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L58:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L58
L56:
  ret
```

assistant: ```c
void copy_vector(double *from_vector, double *to_vector, int size) {
  int i;
  for (i = 0; i < size; ++i)
    to_vector[i] = from_vector[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L22
L4:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  not    %eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D23
type: string

tool: D5: %d

tool: D0: %lld

tool: D23: %lld


assistant: ```c
int main() {
  int t;
  long long int a;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &a);
    printf("%lld\n", 4294967295 - a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
  lea    0x10(%rsp),%r12
  lea    D12(%rip),%rbp
  lea    D9(%rip),%rbx
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  not    %esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L9
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string

tool: D29: %d

tool: D12: %lld

tool: D9: %lld


assistant: ```c
int main() {
  int t;
  long long int a;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &a);
    printf("%lld\n", 4294967295 - a);
  }
  return 0;
}
```