ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_concat_params>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  call   <ft_argvlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%ebp
  jle    L46
  mov    $0x2,%ebx
  lea    D7(%rip),%r14
  jmp    L10
L16:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jl     L46
L10:
  mov    -0x8(%r12,%rbx,8),%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  call   <ft_strncat@plt>
  cmp    %ebx,%ebp
  jle    L16
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <ft_strncat@plt>
  jmp    L16
L46:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: 


assistant: ```c
char *ft_concat_params(int argc, char **argv) {
  int i;
  char *dest;
  char *bn;
  i = 1;
  bn = "\n";
  dest = (char *)malloc(sizeof(char) * ft_argvlen(argc, argv));
  if (argc > 1)
    while (++i < argc + 1) {
      ft_strncat(dest, argv[i - 1], ft_strlen(argv[i - 1]));
      if (i < argc)
        ft_strncat(dest, bn, 1);
    }
  return (dest);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_concat_params>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <ft_argvlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%ebp
  jle    L8
  mov    $0x2,%ebx
  lea    D6(%rip),%r14
  nopl   0x0(%rax)
L23:
  mov    -0x8(%r12,%rbx,8),%rdi
  call   <ft_strlen@plt>
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <ft_strncat@plt>
  cmp    %ebx,%ebp
  jle    L11
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <ft_strncat@plt>
L11:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L23
L8:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: 


assistant: ```c
char *ft_concat_params(int argc, char **argv) {
  int i;
  char *dest;
  char *bn;
  i = 1;
  bn = "\n";
  dest = (char *)malloc(sizeof(char) * ft_argvlen(argc, argv));
  if (argc > 1)
    while (++i < argc + 1) {
      ft_strncat(dest, argv[i - 1], ft_strlen(argv[i - 1]));
      if (i < argc)
        ft_strncat(dest, bn, 1);
    }
  return (dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_concat_params>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <ft_argvlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%ebp
  jle    L17
  mov    $0x2,%ebx
  lea    D0(%rip),%r14
  nopl   0x0(%rax)
L7:
  mov    -0x8(%r12,%rbx,8),%rdi
  call   <ft_strlen@plt>
  mov    -0x8(%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    %eax,%edx
  call   <ft_strncat@plt>
  cmp    %ebx,%ebp
  jle    L28
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <ft_strncat@plt>
L28:
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L7
L17:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: 


assistant: ```c
char *ft_concat_params(int argc, char **argv) {
  int i;
  char *dest;
  char *bn;
  i = 1;
  bn = "\n";
  dest = (char *)malloc(sizeof(char) * ft_argvlen(argc, argv));
  if (argc > 1)
    while (++i < argc + 1) {
      ft_strncat(dest, argv[i - 1], ft_strlen(argv[i - 1]));
      if (i < argc)
        ft_strncat(dest, bn, 1);
    }
  return (dest);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crc_ibm_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sar    $0xf,%eax
  xor    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  shll   -0x18(%rbp)
  xorl   $0x8005,-0x18(%rbp)
  jmp    L16
L5:
  shll   -0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  movzwl %ax,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t crc_ibm_shift(unsigned bit, uint16_t bcc) {
  unsigned val = ((bcc >> 15) ^ bit) & 1;
  if (val != 0) {
    bcc <<= 1;
    bcc ^= 0x8005;
  } else {
    bcc <<= 1;
  }
  return bcc & 0xffff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crc_ibm_shift>:
  endbr64
  mov    %esi,%eax
  sar    $0xf,%eax
  xor    %edi,%eax
  mov    %eax,%ecx
  lea    (%rsi,%rsi,1),%edx
  xor    $0x8005,%edx
  lea    (%rsi,%rsi,1),%eax
  test   $0x1,%cl
  cmovne %edx,%eax
  movzwl %ax,%eax
  ret
```

assistant: ```c
uint16_t crc_ibm_shift(unsigned bit, uint16_t bcc) {
  unsigned val = ((bcc >> 15) ^ bit) & 1;
  if (val != 0) {
    bcc <<= 1;
    bcc ^= 0x8005;
  } else {
    bcc <<= 1;
  }
  return bcc & 0xffff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crc_ibm_shift>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  sar    $0xf,%esi
  xor    %edi,%esi
  mov    %eax,%edx
  xor    $0x8005,%edx
  and    $0x1,%esi
  cmovne %edx,%eax
  movzwl %ax,%eax
  ret
```

assistant: ```c
uint16_t crc_ibm_shift(unsigned bit, uint16_t bcc) {
  unsigned val = ((bcc >> 15) ^ bit) & 1;
  if (val != 0) {
    bcc <<= 1;
    bcc ^= 0x8005;
  } else {
    bcc <<= 1;
  }
  return bcc & 0xffff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<crc_ibm_shift>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  sar    $0xf,%esi
  xor    %edi,%esi
  mov    %eax,%edx
  xor    $0x8005,%edx
  and    $0x1,%esi
  cmovne %edx,%eax
  movzwl %ax,%eax
  ret
```

assistant: ```c
uint16_t crc_ibm_shift(unsigned bit, uint16_t bcc) {
  unsigned val = ((bcc >> 15) ^ bit) & 1;
  if (val != 0) {
    bcc <<= 1;
    bcc ^= 0x8005;
  } else {
    bcc <<= 1;
  }
  return bcc & 0xffff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  D50(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  D47(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm1
  movss  D45(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D50
type_guessed: byte[4]
name: parse_data
arguments: data_label: D47
type_guessed: byte[4]
name: parse_data
arguments: data_label: D45
type_guessed: byte[4]
name: parse_data
arguments: data_label: D79
type_guessed: string

tool: D22: Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)

tool: D16: %f

tool: D12: Enter the current mix -> e.g for EAN36 enter 36 or air enter 21

tool: {"D50": [0x00,0x00,0xc8,0x42]}

tool: {"D47": [0x00,0x00,0x80,0x3f]}

tool: {"D45": [0x00,0x00,0x20,0x41]}

tool: D79: The MOD of your mix is %.2f metres

assistant: ```c
int main(void) {
  float mix, depth, pp02, p_depth;
  printf("Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)\n");
  scanf("%f", &pp02);
  printf("Enter the current mix -> e.g for EAN36 enter 36 or air enter 21\n");
  scanf("%f", &mix);
  mix /= 100;
  p_depth = pp02 / mix;
  depth = p_depth - 1;
  depth *= 10;
  printf("The MOD of your mix is %.2f metres", depth);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm1
  divss  D40(%rip),%xmm1
  movss  %xmm1,(%rsp)
  movss  0x4(%rsp),%xmm0
  divss  %xmm1,%xmm0
  subss  D42(%rip),%xmm0
  mulss  D50(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D40
datatype: byte[4]
name: parse_data
arguments: tag: D42
datatype: byte[4]
name: parse_data
arguments: tag: D50
datatype: byte[4]
name: parse_data
arguments: tag: D12
datatype: string

tool: D20: Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)

tool: D5: %f

tool: D45: Enter the current mix -> e.g for EAN36 enter 36 or air enter 21

tool: {"D40": [0x00,0x00,0xc8,0x42]}

tool: {"D42": [0x00,0x00,0x80,0x3f]}

tool: {"D50": [0x00,0x00,0x20,0x41]}

tool: D12: The MOD of your mix is %.2f metres

assistant: ```c
int main(void) {
  float mix, depth, pp02, p_depth;
  printf("Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)\n");
  scanf("%f", &pp02);
  printf("Enter the current mix -> e.g for EAN36 enter 36 or air enter 21\n");
  scanf("%f", &mix);
  mix /= 100;
  p_depth = pp02 / mix;
  depth = p_depth - 1;
  depth *= 10;
  printf("The MOD of your mix is %.2f metres", depth);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D39(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  (%rsp),%xmm1
  divss  D7(%rip),%xmm1
  lea    D65(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm1,(%rsp)
  divss  %xmm1,%xmm0
  subss  D3(%rip),%xmm0
  mulss  D4(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D50
data_type: string
name: read_data
arguments: tag: D7
data_type: byte[4]
name: read_data
arguments: tag: D65
data_type: string
name: read_data
arguments: tag: D3
data_type: byte[4]
name: read_data
arguments: tag: D4
data_type: byte[4]

tool: D0: Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)

tool: D39: %f

tool: D50: Enter the current mix -> e.g for EAN36 enter 36 or air enter 21

tool: {"D7": [0x00,0x00,0xc8,0x42]}

tool: D65: The MOD of your mix is %.2f metres

tool: {"D3": [0x00,0x00,0x80,0x3f]}

tool: {"D4": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float mix, depth, pp02, p_depth;
  printf("Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)\n");
  scanf("%f", &pp02);
  printf("Enter the current mix -> e.g for EAN36 enter 36 or air enter 21\n");
  scanf("%f", &mix);
  mix /= 100;
  p_depth = pp02 / mix;
  depth = p_depth - 1;
  depth *= 10;
  printf("The MOD of your mix is %.2f metres", depth);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D54(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  (%rsp),%xmm1
  divss  D38(%rip),%xmm1
  lea    D42(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm1,(%rsp)
  divss  %xmm1,%xmm0
  subss  D1(%rip),%xmm0
  mulss  D3(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D54
data_type: string
name: read_data
arguments: data_tag: D64
data_type: string
name: read_data
arguments: data_tag: D38
data_type: byte[4]
name: read_data
arguments: data_tag: D42
data_type: string
name: read_data
arguments: data_tag: D1
data_type: byte[4]
name: read_data
arguments: data_tag: D3
data_type: byte[4]

tool: D5: Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)

tool: D54: %f

tool: D64: Enter the current mix -> e.g for EAN36 enter 36 or air enter 21

tool: {"D38": [0x00,0x00,0xc8,0x42]}

tool: D42: The MOD of your mix is %.2f metres

tool: {"D1": [0x00,0x00,0x80,0x3f]}

tool: {"D3": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float mix, depth, pp02, p_depth;
  printf("Enter the required max PP02 (1.4 suggested for normal diving, 1.6 for decompression stops)\n");
  scanf("%f", &pp02);
  printf("Enter the current mix -> e.g for EAN36 enter 36 or air enter 21\n");
  scanf("%f", &mix);
  mix /= 100;
  p_depth = pp02 / mix;
  depth = p_depth - 1;
  depth *= 10;
  printf("The MOD of your mix is %.2f metres", depth);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ConfigConvertModeToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L17:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ConfigConvertModeToInt(const char *str) {
  int i;
  int r;
  r = 0;
  for (i = 0; str[i] != '\0'; i++)
    r = (r * 8) + ((int)str[i] - (int)'0');
  return (r);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ConfigConvertModeToInt>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L14
  add    $0x1,%rdi
  mov    $0x0,%edx
L3:
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,8),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L3
L6:
  mov    %edx,%eax
  ret
L14:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int ConfigConvertModeToInt(const char *str) {
  int i;
  int r;
  r = 0;
  for (i = 0; str[i] != '\0'; i++)
    r = (r * 8) + ((int)str[i] - (int)'0');
  return (r);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ConfigConvertModeToInt>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L12
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rdi
  lea    -0x30(%rax,%r8,8),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L14
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ConfigConvertModeToInt(const char *str) {
  int i;
  int r;
  r = 0;
  for (i = 0; str[i] != '\0'; i++)
    r = (r * 8) + ((int)str[i] - (int)'0');
  return (r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ConfigConvertModeToInt>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L0
  add    $0x1,%rdi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
  lea    -0x30(%rax,%r8,8),%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L9
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ConfigConvertModeToInt(const char *str) {
  int i;
  int r;
  r = 0;
  for (i = 0; str[i] != '\0'; i++)
    r = (r * 8) + ((int)str[i] - (int)'0');
  return (r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D1(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: f64

tool: D1: 1000000

assistant: ```c
double get_time() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return (double)(t.tv_sec + t.tv_usec / 1e6);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rsp),%xmm0
  divsd  D6(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: f64

tool: D6: 1000000

assistant: ```c
double get_time() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return (double)(t.tv_sec + t.tv_usec / 1e6);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  cvtsi2sdl (%rsp),%xmm0
  divsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: f64

tool: D3: 1000000

assistant: ```c
double get_time() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return (double)(t.tv_sec + t.tv_usec / 1e6);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_time>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x8(%rsp),%xmm1
  cvtsi2sdl (%rsp),%xmm0
  divsd  D5(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: f64

tool: D5: 1000000

assistant: ```c
double get_time() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return (double)(t.tv_sec + t.tv_usec / 1e6);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fBlaMka>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x8(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  const uint64_t m = UINT64_C(0xFFFFFFFF);
  const uint64_t xy = (x & m) * (y & m);
  return x + y + 2 * xy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fBlaMka>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,%edx
  and    %ebx,%edx
  and    %ebp,%eax
  imul   %edx,%eax
  add    %ebp,%ebx
  lea    (%rbx,%rax,2),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  const uint64_t m = UINT64_C(0xFFFFFFFF);
  const uint64_t xy = (x & m) * (y & m);
  return x + y + 2 * xy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fBlaMka>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  and    %ebp,%eax
  and    %ebx,%edx
  add    %ebp,%ebx
  imul   %edx,%eax
  lea    (%rbx,%rax,2),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  const uint64_t m = UINT64_C(0xFFFFFFFF);
  const uint64_t xy = (x & m) * (y & m);
  return x + y + 2 * xy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fBlaMka>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  and    %ebp,%eax
  and    %ebx,%edx
  add    %ebp,%ebx
  imul   %edx,%eax
  lea    (%rbx,%rax,2),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t fBlaMka(uint64_t x, uint64_t y) {
  const uint64_t m = UINT64_C(0xFFFFFFFF);
  const uint64_t xy = (x & m) * (y & m);
  return x + y + 2 * xy;
}
```