ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rax
  mov    %rsp,%rcx
  shl    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L50
L67:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L67
L50:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L58
L6:
  lea    0x0(,%rbx,4),%eax
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %rsp,-0x48(%rbp)
  mov    %eax,-0x54(%rbp)
  call   <get_identity_matrix@plt>
  test   %ebx,%ebx
  jle    L74
  mov    %r13,%r12
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L68:
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rdi
  mov    %ebx,%edx
  mov    %r15d,%esi
  call   <get_pivot_index@plt>
  mov    %eax,%ecx
  cmp    %r15d,%eax
  je     L8
  mov    %ebx,%r8d
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <switch_columns@plt>
L8:
  mov    %r15d,%edx
  mov    %ebx,%ecx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <normalize_pivot_row@plt>
  mov    %r15d,%edx
  mov    %ebx,%ecx
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <eliminate_by_row@plt>
  add    -0x50(%rbp),%r12
  cmp    %r15d,%ebx
  jne    L68
L74:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L58:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invert_matrix(uint8_t *matrix, uint8_t *result, int size) {
  int row;
  int pivotIndex;
  uint8_t currentRow[size];
  int currentRowSize = size * sizeof(uint8_t);
  get_identity_matrix(result, size);
  for (row = 0; row < size; row++) {
    int index = row;
    memcpy(&currentRow, matrix + row * size, currentRowSize);
    pivotIndex = get_pivot_index(currentRow, index, size);
    if (pivotIndex != row) {
      switch_columns(matrix, result, index, pivotIndex, size);
    }
    normalize_pivot_row(matrix, result, index, size);
    eliminate_by_row(matrix, result, row, size);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rax
  mov    %rsp,%rcx
  shl    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L59
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L72
L59:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L37
L39:
  lea    0x0(,%rbx,4),%eax
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %rsp,-0x48(%rbp)
  mov    %eax,-0x54(%rbp)
  call   <get_identity_matrix@plt>
  test   %ebx,%ebx
  jle    L78
  mov    %r13,%r12
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L68:
  mov    -0x54(%rbp),%edx
  mov    -0x48(%rbp),%rdi
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rdi
  mov    %ebx,%edx
  mov    %r15d,%esi
  call   <get_pivot_index@plt>
  mov    %eax,%ecx
  cmp    %r15d,%eax
  je     L77
  mov    %ebx,%r8d
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <switch_columns@plt>
L77:
  mov    %r15d,%edx
  mov    %ebx,%ecx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <normalize_pivot_row@plt>
  mov    %r15d,%edx
  mov    %ebx,%ecx
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <eliminate_by_row@plt>
  add    -0x50(%rbp),%r12
  cmp    %r15d,%ebx
  jne    L68
L78:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L37:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L39
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invert_matrix(uint8_t *matrix, uint8_t *result, int size) {
  int row;
  int pivotIndex;
  uint8_t currentRow[size];
  int currentRowSize = size * sizeof(uint8_t);
  get_identity_matrix(result, size);
  for (row = 0; row < size; row++) {
    int index = row;
    memcpy(&currentRow, matrix + row * size, currentRowSize);
    pivotIndex = get_pivot_index(currentRow, index, size);
    if (pivotIndex != row) {
      switch_columns(matrix, result, index, pivotIndex, size);
    }
    normalize_pivot_row(matrix, result, index, size);
    eliminate_by_row(matrix, result, row, size);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<action_referentiel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %edi,-0x114(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x114(%rbp)
  jne    L24
  lea    D69(%rip),%rax
  jmp    L18
L24:
  lea    D82(%rip),%rax
L18:
  lea    D81(%rip),%rdx
  mov    %rax,%rsi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x2,-0x114(%rbp)
  je     L53
  cmpl   $0x3,-0x114(%rbp)
  je     L69
  jmp    L52
L53:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <lecture@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L74
L69:
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L74
L52:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L74:
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D69
datatype: string
name: read_data
arguments: tag: D82
datatype: string
name: read_data
arguments: tag: D81
datatype: string
name: read_data
arguments: tag: D77
datatype: string
name: read_data
arguments: tag: D79
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D43
datatype: string
name: read_data
arguments: tag: D65
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D69: lire

tool: D82: telecharger

tool: D81: ? 

tool: D77: quel fichier souhaitez vous %s%s

tool: D79: %s

tool: D10: -------------------

tool: D43: -------------------


tool: D65: Virus loaded!!

tool: D16: je n'ai pas compris votre choix

assistant: ```c
int action_referentiel(int choix) {
  char nom_fichier[256];
  printf("quel fichier souhaitez vous %s%s", (choix == 2) ? "lire" : "telecharger", "? ");
  scanf("%s", &nom_fichier);
  printf("-------------------\n");
  printf("%s\n", nom_fichier);
  printf("-------------------\n");
  switch (choix) {
  case 2:
    lecture(nom_fichier);
    printf("-------------------\n\n");
    break;
  case 3:
    printf("Virus loaded!!\n");
    break;
  default:
    printf("je n'ai pas compris votre choix\n");
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<action_referentiel>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L48
  mov    %edi,%ebx
  lea    D40(%rip),%rdx
  lea    D78(%rip),%rsi
  lea    D89(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%r12
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  cmp    $0x3,%ebx
  jne    L46
  lea    D12(%rip),%rdi
  call   <puts@plt>
L2:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  lea    D109(%rip),%rdi
  call   <puts@plt>
  jmp    L2
L48:
  lea    D40(%rip),%rdx
  lea    D126(%rip),%rsi
  lea    D89(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <lecture@plt>
  lea    D115(%rip),%rdi
  call   <puts@plt>
  jmp    L2
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D40
type_guessed: string
name: disassemble_data
arguments: tag: D78
type_guessed: string
name: disassemble_data
arguments: tag: D89
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D109
type_guessed: string
name: disassemble_data
arguments: tag: D126
type_guessed: string
name: disassemble_data
arguments: tag: D115
type_guessed: string

tool: D40: ? 

tool: D78: telecharger

tool: D89: quel fichier souhaitez vous %s%s

tool: D11: %s

tool: D6: -------------------

tool: D12: Virus loaded!!

tool: D109: je n'ai pas compris votre choix

tool: D126: lire

tool: D115: -------------------


assistant: ```c
int action_referentiel(int choix) {
  char nom_fichier[256];
  printf("quel fichier souhaitez vous %s%s", (choix == 2) ? "lire" : "telecharger", "? ");
  scanf("%s", &nom_fichier);
  printf("-------------------\n");
  printf("%s\n", nom_fichier);
  printf("-------------------\n");
  switch (choix) {
  case 2:
    lecture(nom_fichier);
    printf("-------------------\n\n");
    break;
  case 3:
    printf("Virus loaded!!\n");
    break;
  default:
    printf("je n'ai pas compris votre choix\n");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<action_referentiel>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L31
  lea    D68(%rip),%rdx
  mov    %edi,%ebx
  lea    D14(%rip),%rsi
  mov    %rsp,%r12
  lea    D55(%rip),%rdi
  lea    D60(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D106(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  cmp    $0x3,%ebx
  jne    L49
  lea    D16(%rip),%rdi
  call   <puts@plt>
L32:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L49:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L32
  xchg   %ax,%ax
L31:
  lea    D68(%rip),%rdx
  mov    %rsp,%rbp
  lea    D90(%rip),%rsi
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  lea    D60(%rip),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D106(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <lecture@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  jmp    L32
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D68
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D55
type_infered: string
name: retrieve_data
arguments: label: D60
type_infered: string
name: retrieve_data
arguments: label: D106
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D90
type_infered: string
name: retrieve_data
arguments: label: D47
type_infered: string

tool: D68: ? 

tool: D14: telecharger

tool: D55: quel fichier souhaitez vous %s%s

tool: D60: -------------------

tool: D106: %s

tool: D16: Virus loaded!!

tool: D6: je n'ai pas compris votre choix

tool: D90: lire

tool: D47: -------------------


assistant: ```c
int action_referentiel(int choix) {
  char nom_fichier[256];
  printf("quel fichier souhaitez vous %s%s", (choix == 2) ? "lire" : "telecharger", "? ");
  scanf("%s", &nom_fichier);
  printf("-------------------\n");
  printf("%s\n", nom_fichier);
  printf("-------------------\n");
  switch (choix) {
  case 2:
    lecture(nom_fichier);
    printf("-------------------\n\n");
    break;
  case 3:
    printf("Virus loaded!!\n");
    break;
  default:
    printf("je n'ai pas compris votre choix\n");
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<action_referentiel>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L43
  lea    D22(%rip),%rdx
  mov    %edi,%ebx
  lea    D2(%rip),%rsi
  mov    %rsp,%r12
  lea    D23(%rip),%rdi
  lea    D129(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  cmp    $0x3,%ebx
  jne    L2
  lea    D106(%rip),%rdi
  call   <puts@plt>
L29:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L29
  xchg   %ax,%ax
L43:
  lea    D22(%rip),%rdx
  mov    %rsp,%rbp
  lea    D39(%rip),%rsi
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  lea    D129(%rip),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <lecture@plt>
  lea    D87(%rip),%rdi
  call   <puts@plt>
  jmp    L29
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D22
datatype: string
name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D129
datatype: string
name: read_data
arguments: label: D31
datatype: string
name: read_data
arguments: label: D106
datatype: string
name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D39
datatype: string
name: read_data
arguments: label: D87
datatype: string

tool: D22: ? 

tool: D2: telecharger

tool: D23: quel fichier souhaitez vous %s%s

tool: D129: -------------------

tool: D31: %s

tool: D106: Virus loaded!!

tool: D0: je n'ai pas compris votre choix

tool: D39: lire

tool: D87: -------------------


assistant: ```c
int action_referentiel(int choix) {
  char nom_fichier[256];
  printf("quel fichier souhaitez vous %s%s", (choix == 2) ? "lire" : "telecharger", "? ");
  scanf("%s", &nom_fichier);
  printf("-------------------\n");
  printf("%s\n", nom_fichier);
  printf("-------------------\n");
  switch (choix) {
  case 2:
    lecture(nom_fichier);
    printf("-------------------\n\n");
    break;
  case 3:
    printf("Virus loaded!!\n");
    break;
  default:
    printf("je n'ai pas compris votre choix\n");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex2raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hval@plt>
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L20
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hval@plt>
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  shll   $0x4,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hval@plt>
  or     %eax,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  shr    %rax
  leave
  ret
```

assistant: ```c
size_t hex2raw(const char *hex, unsigned char *out) {
  size_t l = strlen(hex);
  int c;
  if (l & 1) {
    *(out++) = hval(*hex);
    hex++;
    l++;
  }
  while (*hex) {
    c = hval(*hex);
    hex++;
    c = c << 4;
    c |= hval(*hex);
    hex++;
    *out = c;
    out++;
  }
  return l / 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2raw>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%r13
  test   $0x1,%al
  jne    L31
L19:
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L24
L30:
  movsbl %dil,%edi
  call   <hval@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  movsbl 0x1(%rbp),%edi
  call   <hval@plt>
  add    $0x2,%rbp
  or     %eax,%ebx
  mov    %bl,(%r12)
  add    $0x1,%r12
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L30
L24:
  mov    %r13,%rax
  shr    %rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  movsbl 0x0(%rbp),%edi
  call   <hval@plt>
  mov    %al,(%r12)
  add    $0x1,%rbp
  lea    0x1(%r13),%r13
  lea    0x1(%r12),%r12
  jmp    L19
```

assistant: ```c
size_t hex2raw(const char *hex, unsigned char *out) {
  size_t l = strlen(hex);
  int c;
  if (l & 1) {
    *(out++) = hval(*hex);
    hex++;
    l++;
  }
  while (*hex) {
    c = hval(*hex);
    hex++;
    c = c << 4;
    c |= hval(*hex);
    hex++;
    *out = c;
    out++;
  }
  return l / 2;
}
```
user: What is the c source code of the assembly code below?

```asm
<hex2raw>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  test   $0x1,%al
  jne    L11
L17:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L22
  nopl   0x0(%rax)
L12:
  call   <hval@plt>
  movsbl 0x1(%rbp),%edi
  add    $0x2,%rbp
  add    $0x1,%r13
  shl    $0x4,%eax
  mov    %eax,%ebx
  call   <hval@plt>
  or     %eax,%ebx
  mov    %bl,-0x1(%r13)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L12
L22:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  shr    %rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  add    $0x1,%r13
  call   <hval@plt>
  mov    %al,-0x1(%r13)
  jmp    L17
```

assistant: ```c
size_t hex2raw(const char *hex, unsigned char *out) {
  size_t l = strlen(hex);
  int c;
  if (l & 1) {
    *(out++) = hval(*hex);
    hex++;
    l++;
  }
  while (*hex) {
    c = hval(*hex);
    hex++;
    c = c << 4;
    c |= hval(*hex);
    hex++;
    *out = c;
    out++;
  }
  return l / 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hex2raw>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  test   $0x1,%al
  jne    L35
L6:
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L19
  nopl   0x0(%rax)
L9:
  call   <hval@plt>
  movsbl 0x1(%rbp),%edi
  add    $0x2,%rbp
  add    $0x1,%r13
  shl    $0x4,%eax
  mov    %eax,%ebx
  call   <hval@plt>
  or     %eax,%ebx
  mov    %bl,-0x1(%r13)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L9
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  shr    %rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl 0x0(%rbp),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  add    $0x1,%r13
  call   <hval@plt>
  mov    %al,-0x1(%r13)
  jmp    L6
```

assistant: ```c
size_t hex2raw(const char *hex, unsigned char *out) {
  size_t l = strlen(hex);
  int c;
  if (l & 1) {
    *(out++) = hval(*hex);
    hex++;
    l++;
  }
  while (*hex) {
    c = hval(*hex);
    hex++;
    c = c << 4;
    c |= hval(*hex);
    hex++;
    *out = c;
    out++;
  }
  return l / 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L26:
  mov    -0x18(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    %edx,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L26
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  comiss D8(%rip),%xmm0
  jbe    L19
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L19:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D8
data_type: byte[4]
name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D12
data_type: string

tool: D29: %d

tool: {"D8": [0x00,0x00,0xe0,0x40]}

tool: D16: 
 heavy

tool: D12: 
 light

assistant: ```c
int main() {
  int number, sum = 0, i = 0;
  float avarage;
  scanf("%d", &number);
  do {
    sum = sum + number % 10;
    i++;
    number = number / 10;
  } while (number > 0);
  avarage = (float)sum / i;
  if (avarage > 7) {
    printf("\n heavy");
  } else {
    printf("\n light");
  }
  return 0;
}
```