ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<poly_area_no_adjust>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %r14
  pxor   %xmm3,%xmm3
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  jmp    L7
  nop
L42:
  addsd  %xmm4,%xmm0
  mulsd  D34(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <sin@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
L19:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L27
L7:
  mov    %ebx,%eax
  pxor   %xmm6,%xmm6
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  movsd  0x0(%r13,%rdx,8),%xmm1
  subsd  -0x8(%r13,%rbx,8),%xmm1
  ucomisd %xmm6,%xmm1
  jp     L62
  je     L19
L62:
  movsd  (%r14,%rdx,8),%xmm0
  movsd  -0x8(%r14,%rbx,8),%xmm4
  movsd  D28(%rip),%xmm7
  movapd %xmm0,%xmm5
  subsd  %xmm4,%xmm5
  movapd %xmm5,%xmm2
  andpd  D32(%rip),%xmm2
  comisd %xmm2,%xmm7
  ja     L42
  movsd  %xmm1,0x20(%rsp)
  add    $0x1,%rbx
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm4,0x28(%rsp)
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm4,%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm3
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  addsd  %xmm0,%xmm3
  cmp    %r12,%rbx
  jne    L7
L27:
  movsd  D0(%rip),%xmm1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  mulsd  %xmm1,%xmm3
  pop    %r12
  pop    %r13
  pop    %r14
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  ret
  nop
L16:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type: f64
name: extract_symbolic_data
arguments: tag: D28
type: byte[8]
name: extract_symbolic_data
arguments: tag: D32
type: qword[2]
name: extract_symbolic_data
arguments: tag: D0
type: f64

tool: D34: 0.5

tool: {"D28": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

tool: {"D32": [0x7fffffffffffffff,0x0000000000000000]}

tool: D0: 6371000

assistant: ```c
double poly_area_no_adjust(const double x[], const double y[], int n) {
  double area = 0.0;
  int i;
  for (i = 0; i < n; i++) {
    int ip = (i + 1) % n;
    double dx = (x[ip] - x[i]);
    double lat1, lat2;
    lat1 = y[ip];
    lat2 = y[i];
    if (dx == 0.0)
      continue;
    if (fabs(lat1 - lat2) < (1.e-10))
      area -= dx * sin(0.5 * (lat1 + lat2));
    else
      area += dx * (cos(lat1) - cos(lat2)) / (lat1 - lat2);
  }
  return area * (6371000.) * (6371000.);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fac@plt>
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L23
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D27
datatype: string

tool: D25: Enter n to find 1! + 2! + . . . + n! : 

tool: D5: %d

tool: D27: 1! + 2! + . . . + %d! = %d


assistant: ```c
main() {
  int n, sum = 0, i;
  printf("Enter n to find 1! + 2! + . . . + n! : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    sum = sum + fac(i);
  printf("1! + 2! + . . . + %d! = %d\n", n, sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L14
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L1:
  mov    %ebx,%edi
  call   <fac@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jge    L1
L12:
  mov    %ebp,%edx
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x0,%ebp
  jmp    L12
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string

tool: D6: Enter n to find 1! + 2! + . . . + n! : 

tool: D25: %d

tool: D16: 1! + 2! + . . . + %d! = %d


assistant: ```c
main() {
  int n, sum = 0, i;
  printf("Enter n to find 1! + 2! + . . . + n! : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    sum = sum + fac(i);
  printf("1! + 2! + . . . + %d! = %d\n", n, sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L39
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fac@plt>
  mov    0x4(%rsp),%esi
  add    %eax,%r12d
  cmp    %ebx,%esi
  jge    L13
L31:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L39:
  xor    %r12d,%r12d
  jmp    L31
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: string

tool: D10: Enter n to find 1! + 2! + . . . + n! : 

tool: D13: %d

tool: D3: 1! + 2! + . . . + %d! = %d


assistant: ```c
main() {
  int n, sum = 0, i;
  printf("Enter n to find 1! + 2! + . . . + n! : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    sum = sum + fac(i);
  printf("1! + 2! + . . . + %d! = %d\n", n, sum);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L30
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fac@plt>
  mov    0x4(%rsp),%esi
  add    %eax,%r12d
  cmp    %ebx,%esi
  jge    L26
L4:
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L30:
  xor    %r12d,%r12d
  jmp    L4
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D24
type: string

tool: D0: Enter n to find 1! + 2! + . . . + n! : 

tool: D23: %d

tool: D24: 1! + 2! + . . . + %d! = %d


assistant: ```c
main() {
  int n, sum = 0, i;
  printf("Enter n to find 1! + 2! + . . . + n! : ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    sum = sum + fac(i);
  printf("1! + 2! + . . . + %d! = %d\n", n, sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ps_daemon_sigchld_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L15:
  nop
L8:
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L15
  mov    D2(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void ps_daemon_sigchld_handler(int sig) {
  int errno_process = errno;
  while (waitpid(-1, NULL, WNOHANG) > 0)
    continue;
  errno = errno_process;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ps_daemon_sigchld_handler>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D27(%rip),%rax
  mov    (%rax),%ebp
  mov    D23(%rip),%rbx
L2:
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L2
  mov    D27(%rip),%rax
  mov    %ebp,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ps_daemon_sigchld_handler(int sig) {
  int errno_process = errno;
  while (waitpid(-1, NULL, WNOHANG) > 0)
    continue;
  errno = errno_process;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ps_daemon_sigchld_handler>:
  endbr64
  push   %r12
  push   %rbp
  mov    D1(%rip),%rbp
  push   %rbx
  mov    D3(%rip),%rbx
  mov    (%rbx),%r12d
L3:
  mov    0x0(%rbp),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L3
  mov    %r12d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ps_daemon_sigchld_handler(int sig) {
  int errno_process = errno;
  while (waitpid(-1, NULL, WNOHANG) > 0)
    continue;
  errno = errno_process;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ps_daemon_sigchld_handler>:
  endbr64
  push   %r12
  push   %rbp
  mov    D2(%rip),%rbp
  push   %rbx
  mov    D17(%rip),%rbx
  mov    (%rbx),%r12d
L7:
  mov    0x0(%rbp),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L7
  mov    %r12d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ps_daemon_sigchld_handler(int sig) {
  int errno_process = errno;
  while (waitpid(-1, NULL, WNOHANG) > 0)
    continue;
  errno = errno_process;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itracku_rt_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <itracku_rd_ser_init@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <itracku_device_write_string@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: WP AP-Exit

assistant: ```c
void itracku_rt_init(const char *fname) {
  itracku_rd_ser_init(fname);
  itracku_device_write_string("WP AP-Exit");
}
```
user: What is the c source code of the assembly code below?

```asm
<itracku_rt_init>:
  endbr64
  sub    $0x8,%rsp
  call   <itracku_rd_ser_init@plt>
  lea    D5(%rip),%rdi
  call   <itracku_device_write_string@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: WP AP-Exit

assistant: ```c
void itracku_rt_init(const char *fname) {
  itracku_rd_ser_init(fname);
  itracku_device_write_string("WP AP-Exit");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itracku_rt_init>:
  endbr64
  sub    $0x8,%rsp
  call   <itracku_rd_ser_init@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <itracku_device_write_string@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: WP AP-Exit

assistant: ```c
void itracku_rt_init(const char *fname) {
  itracku_rd_ser_init(fname);
  itracku_device_write_string("WP AP-Exit");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itracku_rt_init>:
  endbr64
  sub    $0x8,%rsp
  call   <itracku_rd_ser_init@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <itracku_device_write_string@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: WP AP-Exit

assistant: ```c
void itracku_rt_init(const char *fname) {
  itracku_rd_ser_init(fname);
  itracku_device_write_string("WP AP-Exit");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L10
L17:
  mov    -0x4(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int _abs(int n) {
  if (n < 0)
    return (-n);
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int n) {
  if (n < 0)
    return (-n);
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int n) {
  if (n < 0)
    return (-n);
  return (n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int _abs(int n) {
  if (n < 0)
    return (-n);
  return (n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L0:
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L0
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8:  

assistant: ```c
void indent(FILE *out, int d) {
  int i;
  for (i = 0; i <= d; i++)
    fprintf(out, " ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<indent>:
  endbr64
  test   %esi,%esi
  js     L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9:  

assistant: ```c
void indent(FILE *out, int d) {
  int i;
  for (i = 0; i <= d; i++)
    fprintf(out, " ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<indent>:
  endbr64
  test   %esi,%esi
  js     L11
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jge    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L11:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3:  

assistant: ```c
void indent(FILE *out, int d) {
  int i;
  for (i = 0; i <= d; i++)
    fprintf(out, " ");
}
```
user: What is the c source code of the assembly code below:

```asm
<indent>:
  endbr64
  test   %esi,%esi
  js     L14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jge    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8:  

assistant: ```c
void indent(FILE *out, int d) {
  int i;
  for (i = 0; i <= d; i++)
    fprintf(out, " ");
}
```
user: What is the c source code of the assembly code below:

```asm
<nextPermutation>:
  endbr64
  cmp    $0x1,%esi
  je     L127
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%eax
  sub    $0x2,%esi
  js     L84
  movslq %esi,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rcx
  lea    -0x1(%rax),%r8d
  movslq %r8d,%r8
  lea    (%rdi,%r8,4),%r12
  lea    -0x1(%rax),%ebp
  mov    %rcx,%r10
  mov    %esi,%r13d
  jmp    L66
L7:
  sub    $0x4,%r8
  cmp    %r14,%r8
  jne    L18
L58:
  sub    $0x1,%esi
  sub    $0x4,%rcx
  cmp    $0xffffffff,%esi
  je     L84
L66:
  mov    %rcx,%r11
  mov    (%rcx),%edx
  cmp    0x4(%rcx),%edx
  jg     L58
  cmp    %esi,%ebp
  jle    L58
  mov    %esi,%r9d
  mov    %r13d,%r8d
  sub    %esi,%r8d
  shl    $0x2,%r8
  mov    %r10,%r14
  sub    %r8,%r14
  mov    %r12,%r8
L18:
  mov    (%r8),%r15d
  cmp    %r15d,%edx
  jge    L7
  xor    %r15d,%edx
  mov    %edx,(%r11)
  xor    (%r8),%edx
  mov    %edx,(%r8)
  xor    %edx,(%r11)
  lea    0x1(%rsi),%edx
  lea    -0x1(%rsi,%rax,1),%ecx
  mov    %ecx,%r8d
  shr    $0x1f,%r8d
  add    %ecx,%r8d
  sar    %r8d
  cmp    %r8d,%edx
  jg     L53
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rdx
  cltq
  lea    -0x4(%rdi,%rax,4),%rcx
  sub    %r9d,%r8d
  lea    -0x1(%r8),%eax
  movslq %esi,%rsi
  add    %rsi,%rax
  lea    0x8(%rdi,%rax,4),%rsi
L104:
  mov    (%rdx),%eax
  xor    (%rcx),%eax
  mov    %eax,(%rdx)
  xor    (%rcx),%eax
  mov    %eax,(%rcx)
  xor    %eax,(%rdx)
  add    $0x4,%rdx
  sub    $0x4,%rcx
  cmp    %rsi,%rdx
  jne    L104
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L84:
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L53
  cltq
  mov    $0x0,%ecx
L35:
  mov    (%rdi,%rcx,4),%edx
  xor    (%rdi,%rax,4),%edx
  mov    %edx,(%rdi,%rcx,4)
  xor    (%rdi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  xor    %edx,(%rdi,%rcx,4)
  add    $0x1,%rcx
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jl     L35
  jmp    L53
L127:
  ret
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  if (numsSize == 1)
    return;
  for (int i = numsSize - 2; i >= 0; i--) {
    if (nums[i] > nums[i + 1])
      continue;
    for (int j = numsSize - 1; j > i; j--) {
      if (nums[i] >= nums[j])
        continue;
      nums[i] ^= nums[j];
      nums[j] ^= nums[i];
      nums[i] ^= nums[j];
      for (int k = i + 1; k <= (i + numsSize - 1) / 2; k++) {
        nums[k] ^= nums[numsSize + i - k];
        nums[numsSize + i - k] ^= nums[k];
        nums[k] ^= nums[numsSize + i - k];
      }
      return;
    }
  }
  for (int k = 0; k < numsSize - 1 - k; k++) {
    nums[k] ^= nums[numsSize - 1 - k];
    nums[numsSize - 1 - k] ^= nums[k];
    nums[k] ^= nums[numsSize - 1 - k];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nextPermutation>:
  endbr64
  mov    %rdi,%rax
  movslq %esi,%rdi
  cmp    $0x1,%edi
  je     L115
  lea    -0x2(%rdi),%r11d
  push   %r12
  lea    -0x1(%rdi),%r8d
  push   %rbp
  mov    %r11d,%esi
  push   %rbx
  test   %r11d,%r11d
  js     L24
  movslq %r11d,%rdx
  movslq %r8d,%r9
  shl    $0x2,%rdx
  lea    (%rax,%r9,4),%rbp
  lea    (%rax,%rdx,1),%rcx
  mov    %rcx,%r9
L58:
  mov    (%rcx),%edx
  cmp    0x4(%rcx),%edx
  jle    L51
L37:
  sub    $0x1,%esi
  sub    $0x4,%rcx
  cmp    $0xffffffff,%esi
  jne    L58
L24:
  test   %r8d,%r8d
  jle    L78
  movslq %r8d,%rdx
  xor    %esi,%esi
  nopl   0x0(%rax)
L54:
  mov    (%rax,%rsi,4),%ecx
  xor    (%rax,%rdx,4),%ecx
  mov    %ecx,(%rax,%rsi,4)
  xor    (%rax,%rdx,4),%ecx
  mov    %ecx,(%rax,%rdx,4)
  sub    $0x1,%rdx
  xor    %ecx,(%rax,%rsi,4)
  add    $0x1,%rsi
  cmp    %edx,%esi
  jl     L54
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  cmp    %r8d,%esi
  jge    L37
  mov    %r11d,%r10d
  mov    %r9,%r12
  sub    %esi,%r10d
  shl    $0x2,%r10
  sub    %r10,%r12
  mov    %rbp,%r10
L36:
  mov    (%r10),%ebx
  cmp    %ebx,%edx
  jge    L89
  xor    %ebx,%edx
  mov    %edx,(%rcx)
  xor    (%r10),%edx
  mov    %edx,(%r10)
  xor    %edx,(%rcx)
  lea    -0x1(%rsi,%rdi,1),%ecx
  lea    0x1(%rsi),%edx
  mov    %ecx,%r8d
  shr    $0x1f,%r8d
  add    %ecx,%r8d
  sar    %r8d
  cmp    %edx,%r8d
  jl     L78
  sub    %esi,%r8d
  lea    -0x4(%rax,%rdi,4),%rcx
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    -0x1(%r8),%edi
  lea    (%rax,%rdx,4),%rdx
  add    %rdi,%rsi
  lea    0x8(%rax,%rsi,4),%rsi
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%rdx),%eax
  xor    (%rcx),%eax
  sub    $0x4,%rcx
  mov    %eax,(%rdx)
  xor    0x4(%rcx),%eax
  mov    %eax,0x4(%rcx)
  xor    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L57
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L89:
  sub    $0x4,%r10
  cmp    %r12,%r10
  jne    L36
  jmp    L37
  xchg   %ax,%ax
L115:
  ret
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  if (numsSize == 1)
    return;
  for (int i = numsSize - 2; i >= 0; i--) {
    if (nums[i] > nums[i + 1])
      continue;
    for (int j = numsSize - 1; j > i; j--) {
      if (nums[i] >= nums[j])
        continue;
      nums[i] ^= nums[j];
      nums[j] ^= nums[i];
      nums[i] ^= nums[j];
      for (int k = i + 1; k <= (i + numsSize - 1) / 2; k++) {
        nums[k] ^= nums[numsSize + i - k];
        nums[numsSize + i - k] ^= nums[k];
        nums[k] ^= nums[numsSize + i - k];
      }
      return;
    }
  }
  for (int k = 0; k < numsSize - 1 - k; k++) {
    nums[k] ^= nums[numsSize - 1 - k];
    nums[numsSize - 1 - k] ^= nums[k];
    nums[k] ^= nums[numsSize - 1 - k];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<produto_interno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int produto_interno(int vetor1[], int vetor2[], int N) {
  int p;
  int i;
  p = 0;
  for (i = 0; i < N; i++)
    p = p + (vetor1[i] * vetor2[i]);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<produto_interno>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0x0,%r8d
L3:
  mov    (%rdi,%rax,4),%ecx
  imul   (%rsi,%rax,4),%ecx
  add    %ecx,%r8d
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L4:
  mov    %r8d,%eax
  ret
L14:
  mov    $0x0,%r8d
  jmp    L4
```

assistant: ```c
int produto_interno(int vetor1[], int vetor2[], int N) {
  int p;
  int i;
  p = 0;
  for (i = 0; i < N; i++)
    p = p + (vetor1[i] * vetor2[i]);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<produto_interno>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r8d,%r8d
L18:
  mov    (%rdi,%rax,4),%ecx
  imul   (%rsi,%rax,4),%ecx
  add    $0x1,%rax
  add    %ecx,%r8d
  cmp    %rax,%rdx
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int produto_interno(int vetor1[], int vetor2[], int N) {
  int p;
  int i;
  p = 0;
  for (i = 0; i < N; i++)
    p = p + (vetor1[i] * vetor2[i]);
  return p;
}
```