ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<nand_read_page2048>:
  endbr64
  mov    0x4e000004,%rax
  and    $0xfffffffffffffffd,%rax
  mov    %rax,0x4e000004
  mov    0x4e000020,%rax
  or     $0x4,%rax
  mov    %rax,0x4e000020
  mov    %edi,%eax
  movb   $0x0,0x4e000008
  shr    $0x8,%eax
  movb   $0x0,0x4e00000c
  movb   $0x0,0x4e00000c
  mov    %dil,0x4e00000c
  shr    $0x10,%edi
  mov    %al,0x4e00000c
  mov    %dil,0x4e00000c
  movb   $0x30,0x4e000008
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x4e000020,%rax
  test   $0x4,%al
  je     L10
  lea    0x800(%rsi),%r8
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x4e000010,%edi
  movzbl 0x4e000010,%eax
  add    $0x4,%rsi
  movzbl 0x4e000010,%ecx
  movzbl 0x4e000010,%edx
  shl    $0x8,%eax
  shl    $0x18,%edx
  shl    $0x10,%ecx
  or     %edi,%edx
  or     %ecx,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %r8,%rsi
  jne    L9
  mov    0x4e000004,%rax
  or     $0x2,%rax
  mov    %rax,0x4e000004
  ret
```

assistant: ```c
void nand_read_page2048(unsigned int page, unsigned char *buf) {
  unsigned int i;
  unsigned int *word_buf = (unsigned int *)buf;
  unsigned int word32;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  for (i = 0; i < ((1 << 11) >> 2); ++i) {
    word32 = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 8);
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 16);
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 24);
    *word_buf++ = word32;
  }
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nand_read_page2048>:
  endbr64
  mov    0x4e000004,%rax
  and    $0xfffffffffffffffd,%rax
  mov    %rax,0x4e000004
  mov    0x4e000020,%rax
  or     $0x4,%rax
  mov    %rax,0x4e000020
  mov    %edi,%eax
  movb   $0x0,0x4e000008
  shr    $0x8,%eax
  movb   $0x0,0x4e00000c
  movb   $0x0,0x4e00000c
  mov    %dil,0x4e00000c
  shr    $0x10,%edi
  mov    %al,0x4e00000c
  mov    %dil,0x4e00000c
  movb   $0x30,0x4e000008
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x4e000020,%rax
  test   $0x4,%al
  je     L8
  lea    0x800(%rsi),%r8
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl 0x4e000010,%edi
  movzbl 0x4e000010,%eax
  add    $0x4,%rsi
  movzbl 0x4e000010,%ecx
  movzbl 0x4e000010,%edx
  shl    $0x8,%eax
  shl    $0x18,%edx
  shl    $0x10,%ecx
  or     %edi,%edx
  or     %ecx,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %r8,%rsi
  jne    L4
  mov    0x4e000004,%rax
  or     $0x2,%rax
  mov    %rax,0x4e000004
  ret
```

assistant: ```c
void nand_read_page2048(unsigned int page, unsigned char *buf) {
  unsigned int i;
  unsigned int *word_buf = (unsigned int *)buf;
  unsigned int word32;
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) &= (~(1 << 1));
  } while (0);
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x20)) |= (1 << 2);
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = 0x00;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = page & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 8) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x0C)) = (page >> 16) & 0xFF;
  } while (0);
  do {
    (*(volatile unsigned char *)(0x4E000000 + 0x08)) = 0x30;
  } while (0);
  while (!((*(volatile unsigned long *)(0x4E000000 + 0x20)) & (1 << 2)))
    ;
  for (i = 0; i < ((1 << 11) >> 2); ++i) {
    word32 = ((*(volatile unsigned char *)(0x4E000000 + 0x10)));
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 8);
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 16);
    word32 |= (((*(volatile unsigned char *)(0x4E000000 + 0x10))) << 24);
    *word_buf++ = word32;
  }
  do {
    (*(volatile unsigned long *)(0x4E000000 + 0x04)) |= (1 << 1);
  } while (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timer_to_gmtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L7
  mov    $0x0,%eax
  jmp    L29
L7:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x8(%rbp)
L20:
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  imul   $0x2710,%rax,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  jmp    L29
L15:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
long timer_to_gmtime(time_t time_secs) {
  struct tm *time_struct;
  if (time_secs == 0)
    return (0);
  else {
    time_struct = gmtime(&time_secs);
    if (time_struct == NULL)
      time_struct = localtime(&time_secs);
    if (time_struct)
      return ((long)(time_struct->tm_hour) * 1000000L + (long)(time_struct->tm_min) * 10000L + (long)(time_struct->tm_sec) * 100 + (0));
    else
      return (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<timer_to_gmtime>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  jne    L36
L48:
  add    $0x18,%rsp
  ret
L36:
  lea    0x8(%rsp),%rdi
  call   <gmtime@plt>
  test   %rax,%rax
  je     L16
L42:
  imul   $0xf4240,0x10(%rax),%rdx
  imul   $0x2710,0x8(%rax),%rcx
  add    %rcx,%rdx
  mov    (%rax),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rdx,%rax,4),%rax
  jmp    L48
L16:
  lea    0x8(%rsp),%rdi
  call   <localtime@plt>
  test   %rax,%rax
  jne    L42
  mov    $0x0,%eax
  jmp    L48
```

assistant: ```c
long timer_to_gmtime(time_t time_secs) {
  struct tm *time_struct;
  if (time_secs == 0)
    return (0);
  else {
    time_struct = gmtime(&time_secs);
    if (time_struct == NULL)
      time_struct = localtime(&time_secs);
    if (time_struct)
      return ((long)(time_struct->tm_hour) * 1000000L + (long)(time_struct->tm_min) * 10000L + (long)(time_struct->tm_sec) * 100 + (0));
    else
      return (0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timer_to_gmtime>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  jne    L8
L37:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gmtime@plt>
  test   %rax,%rax
  je     L13
L3:
  imul   $0xf4240,0x10(%rax),%rdx
  imul   $0x2710,0x8(%rax),%rcx
  mov    (%rax),%rax
  add    $0x10,%rsp
  pop    %rbp
  lea    (%rax,%rax,4),%rax
  add    %rcx,%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rdx,%rax,4),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L37
  jmp    L3
```

assistant: ```c
long timer_to_gmtime(time_t time_secs) {
  struct tm *time_struct;
  if (time_secs == 0)
    return (0);
  else {
    time_struct = gmtime(&time_secs);
    if (time_struct == NULL)
      time_struct = localtime(&time_secs);
    if (time_struct)
      return ((long)(time_struct->tm_hour) * 1000000L + (long)(time_struct->tm_min) * 10000L + (long)(time_struct->tm_sec) * 100 + (0));
    else
      return (0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<timer_to_gmtime>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  jne    L35
L20:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gmtime@plt>
  test   %rax,%rax
  je     L10
L23:
  imul   $0xf4240,0x10(%rax),%rdx
  imul   $0x2710,0x8(%rax),%rcx
  mov    (%rax),%rax
  add    $0x10,%rsp
  pop    %rbp
  lea    (%rax,%rax,4),%rax
  add    %rcx,%rdx
  lea    (%rax,%rax,4),%rax
  lea    (%rdx,%rax,4),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L20
  jmp    L23
```

assistant: ```c
long timer_to_gmtime(time_t time_secs) {
  struct tm *time_struct;
  if (time_secs == 0)
    return (0);
  else {
    time_struct = gmtime(&time_secs);
    if (time_struct == NULL)
      time_struct = localtime(&time_secs);
    if (time_struct)
      return ((long)(time_struct->tm_hour) * 1000000L + (long)(time_struct->tm_min) * 10000L + (long)(time_struct->tm_sec) * 100 + (0));
    else
      return (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ex2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L20:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x14,%eax
  jg     L59
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jle    L59
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L59:
  mov    -0x14(%rbp),%eax
  cmp    $0x32,%eax
  jle    L14
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L20
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D15
data_type: string

tool: D9: Digite a idade da pessoa, para sair digite 0: 

tool: D20: %d

tool: D15: Menos de 21: %d.
Mais de 50: %d.

assistant: ```c
void ex2() {
  int idade[3] = {1, 0, 0};
  while (idade[0] > 0) {
    printf("Digite a idade da pessoa, para sair digite 0: ");
    scanf("%d", &idade[0]);
    if (idade[0] < 21 && idade[0] > 0)
      idade[1]++;
    if (idade[0] > 50)
      idade[2]++;
  }
  printf("Menos de 21: %d.\nMais de 50: %d.", idade[1], idade[2]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ex2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  lea    D25(%rip),%r12
  lea    0xc(%rsp),%rbp
  lea    D3(%rip),%rbx
L69:
  mov    %eax,0x14(%rsp)
  jmp    L40
L56:
  cmp    $0x32,%eax
  jg     L23
L40:
  cmpl   $0x0,0xc(%rsp)
  jle    L38
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L56
  addl   $0x1,0x10(%rsp)
  jmp    L40
L23:
  mov    0x14(%rsp),%eax
  add    $0x1,%eax
  jmp    L69
L38:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D25: Digite a idade da pessoa, para sair digite 0: 

tool: D3: %d

tool: D19: Menos de 21: %d.
Mais de 50: %d.

assistant: ```c
void ex2() {
  int idade[3] = {1, 0, 0};
  while (idade[0] > 0) {
    printf("Digite a idade da pessoa, para sair digite 0: ");
    scanf("%d", &idade[0]);
    if (idade[0] < 21 && idade[0] > 0)
      idade[1]++;
    if (idade[0] > 50)
      idade[2]++;
  }
  printf("Menos de 21: %d.\nMais de 50: %d.", idade[1], idade[2]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ex2>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rbp
  movq   $0x1,0xc(%rsp)
L29:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L27
  addl   $0x1,0x10(%rsp)
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L27:
  cmp    $0x32,%eax
  jg     L1
  test   %eax,%eax
  jg     L29
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  addl   $0x1,0x14(%rsp)
  jmp    L29
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D2
type: string

tool: D7: Digite a idade da pessoa, para sair digite 0: 

tool: D14: %d

tool: D2: Menos de 21: %d.
Mais de 50: %d.

assistant: ```c
void ex2() {
  int idade[3] = {1, 0, 0};
  while (idade[0] > 0) {
    printf("Digite a idade da pessoa, para sair digite 0: ");
    scanf("%d", &idade[0]);
    if (idade[0] < 21 && idade[0] > 0)
      idade[1]++;
    if (idade[0] > 50)
      idade[2]++;
  }
  printf("Menos de 21: %d.\nMais de 50: %d.", idade[1], idade[2]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ex2>:
  endbr64
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  movl   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rbp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x13,%edx
  ja     L23
  addl   $0x1,0xc(%rsp)
  jmp    L12
L23:
  cmp    $0x32,%eax
  jg     L50
  test   %eax,%eax
  jg     L12
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  addl   $0x1,0x10(%rsp)
  jmp    L12
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D38
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D4
data_type: byte[8]
name: retrieve_data
arguments: data_label: D13
data_type: string

tool: D38: Digite a idade da pessoa, para sair digite 0: 

tool: D7: %d

tool: {"D4": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D13: Menos de 21: %d.
Mais de 50: %d.

assistant: ```c
void ex2() {
  int idade[3] = {1, 0, 0};
  while (idade[0] > 0) {
    printf("Digite a idade da pessoa, para sair digite 0: ");
    scanf("%d", &idade[0]);
    if (idade[0] < 21 && idade[0] > 0)
      idade[1]++;
    if (idade[0] > 50)
      idade[2]++;
  }
  printf("Menos de 21: %d.\nMais de 50: %d.", idade[1], idade[2]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<keyboard_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L5
L8:
  mov    $0x60,%edi
  call   <inportb@plt>
L5:
  mov    $0x64,%edi
  call   <inportb@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void keyboard_init() {
  while (inportb(0x64) & 1)
    inportb(0x60);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<keyboard_init>:
  endbr64
  sub    $0x8,%rsp
  jmp    L14
L0:
  mov    $0x60,%edi
  call   <inportb@plt>
L14:
  mov    $0x64,%edi
  call   <inportb@plt>
  test   $0x1,%al
  jne    L0
  add    $0x8,%rsp
  ret
```

assistant: ```c
void keyboard_init() {
  while (inportb(0x64) & 1)
    inportb(0x60);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<keyboard_init>:
  endbr64
  sub    $0x8,%rsp
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x60,%edi
  call   <inportb@plt>
L7:
  mov    $0x64,%edi
  call   <inportb@plt>
  test   $0x1,%al
  jne    L12
  add    $0x8,%rsp
  ret
```

assistant: ```c
void keyboard_init() {
  while (inportb(0x64) & 1)
    inportb(0x60);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<keyboard_init>:
  endbr64
  sub    $0x8,%rsp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x60,%edi
  call   <inportb@plt>
L18:
  mov    $0x64,%edi
  call   <inportb@plt>
  test   $0x1,%al
  jne    L3
  add    $0x8,%rsp
  ret
```

assistant: ```c
void keyboard_init() {
  while (inportb(0x64) & 1)
    inportb(0x60);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L17
  cmpl   $0x2,-0x14(%rbp)
  jne    L2
L17:
  mov    $0x1,%eax
  jmp    L25
L2:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibonacci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibonacci>
  add    %ebx,%eax
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibonacci(int zahl) {
  if (zahl == 1 || zahl == 2) {
    return 1;
  }
  return fibonacci(zahl - 1) + fibonacci(zahl - 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fibonacci>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jbe    L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edx,%edi
  call   <fibonacci>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fibonacci>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
int fibonacci(int zahl) {
  if (zahl == 1 || zahl == 2) {
    return 1;
  }
  return fibonacci(zahl - 1) + fibonacci(zahl - 2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_winsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <ioctl@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L5
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L39
L5:
  mov    $0x1,%eax
  jmp    L8
L39:
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int get_winsize(int *row, int *col) {
  struct winsize w;
  int n;
  n = ioctl(1, TIOCGWINSZ, &w);
  if (n < 0 || w.ws_col == 0) {
    return 1;
  }
  *row = w.ws_row;
  *col = w.ws_col;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_winsize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1,%edi
  call   <ioctl@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  js     L28
  mov    (%rsp),%edx
  test   %edx,%edx
  je     L28
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    %edx,0x0(%rbp)
  mov    $0x0,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_winsize(int *row, int *col) {
  struct winsize w;
  int n;
  n = ioctl(1, TIOCGWINSZ, &w);
  if (n < 0 || w.ws_col == 0) {
    return 1;
  }
  *row = w.ws_row;
  *col = w.ws_col;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_winsize>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  js     L23
  mov    (%rsp),%edx
  test   %edx,%edx
  je     L23
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  mov    %edx,0x0(%rbp)
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_winsize(int *row, int *col) {
  struct winsize w;
  int n;
  n = ioctl(1, TIOCGWINSZ, &w);
  if (n < 0 || w.ws_col == 0) {
    return 1;
  }
  *row = w.ws_row;
  *col = w.ws_col;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_winsize>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  js     L23
  mov    (%rsp),%edx
  test   %edx,%edx
  je     L23
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  mov    %edx,0x0(%rbp)
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_winsize(int *row, int *col) {
  struct winsize w;
  int n;
  n = ioctl(1, TIOCGWINSZ, &w);
  if (n < 0 || w.ws_col == 0) {
    return 1;
  }
  *row = w.ws_row;
  *col = w.ws_col;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LPCCOMxIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x120,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x120,%rdx
  or     -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LPCCOMxIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000120))) |= ulIntFlags;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LPCCOMxIntEnable>:
  endbr64
  mov    0x120(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x120(%rdi)
  ret
```

assistant: ```c
void LPCCOMxIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000120))) |= ulIntFlags;
}
```