ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<questiona_tempo>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
  lea    D109(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <ler_intervalo@plt>
  cmp    $0x2,%eax
  je     L33
  cmp    $0x3,%eax
  je     L27
  cmp    $0x1,%eax
  je     L15
L3:
  movss  0x4(%rsp),%xmm0
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x18,%rsp
  ret
L15:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  movss  D9(%rip),%xmm0
  jmp    L64
L33:
  lea    D57(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L64
L27:
  lea    D98(%rip),%rdi
  call   <printf@plt>
  lea    D76(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D94(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L3
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D72
type_infered: string
name: parse_data
arguments: data_tag: D109
type_infered: string
name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D82
type_infered: string
name: parse_data
arguments: data_tag: D22
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: byte[4]
name: parse_data
arguments: data_tag: D57
type_infered: string
name: parse_data
arguments: data_tag: D98
type_infered: string
name: parse_data
arguments: data_tag: D76
type_infered: string
name: parse_data
arguments: data_tag: D94
type_infered: string

tool: D5: Ha tres modos para a exibicao:


tool: D72: 	1 - Exibicao direta;


tool: D109: 	2 - Exibicao pausada por ENTER;


tool: D56: 	3 - Exibicao pausada por tempo.


tool: D82: 
Sabendo das opcoes, digite a sua escolha:


tool: D22: 
A exibicao direta foi selecionada


tool: {"D9": [0x00,0x00,0x80,0xbf]}

tool: D57: 
A exibicao pausada por ENTER foi selecionada


tool: D98: 
Entao, agora digite o tempo digitado 

tool: D76: (lembrando que pode ser decimal
separado por ponto (.), recomendando valores acima de 1.0):


tool: D94: %f

assistant: ```c
float questiona_tempo() {
  float tempo;
  printf("Ha tres modos para a exibicao:\n");
  printf("\t1 - Exibicao direta;\n");
  printf("\t2 - Exibicao pausada por ENTER;\n");
  printf("\t3 - Exibicao pausada por tempo.\n");
  printf("\nSabendo das opcoes, digite a sua escolha:\n");
  switch (ler_intervalo(1, 3)) {
  case 1:
    printf("\nA exibicao direta foi selecionada\n");
    return -1;
  case 2:
    printf("\nA exibicao pausada por ENTER foi selecionada\n");
    return 0.0;
  case 3:
    printf("\nEntao, agora digite o tempo digitado ");
    printf("(lembrando que pode ser decimal\nseparado por ponto (.), recomendando valores acima de 1.0):\n");
    scanf("%f", &tempo);
    getchar();
  }
  return tempo;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<questiona_tempo>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <ler_intervalo@plt>
  cmp    $0x2,%eax
  je     L15
  cmp    $0x3,%eax
  je     L61
  cmp    $0x1,%eax
  je     L22
L60:
  movss  0x4(%rsp),%xmm0
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L15:
  lea    D101(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L22:
  lea    D70(%rip),%rdi
  call   <printf@plt>
  movss  D81(%rip),%xmm0
  jmp    L31
  xchg   %ax,%ax
L61:
  lea    D78(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  jmp    L60
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D62
type: string
name: parse_data
arguments: tag: D49
type: string
name: parse_data
arguments: tag: D101
type: string
name: parse_data
arguments: tag: D70
type: string
name: parse_data
arguments: tag: D81
type: byte[4]
name: parse_data
arguments: tag: D78
type: string
name: parse_data
arguments: tag: D28
type: string
name: parse_data
arguments: tag: D22
type: string

tool: D24: Ha tres modos para a exibicao:


tool: D16: 	1 - Exibicao direta;


tool: D27: 	2 - Exibicao pausada por ENTER;


tool: D62: 	3 - Exibicao pausada por tempo.


tool: D49: 
Sabendo das opcoes, digite a sua escolha:


tool: D101: 
A exibicao pausada por ENTER foi selecionada


tool: D70: 
A exibicao direta foi selecionada


tool: {"D81": [0x00,0x00,0x80,0xbf]}

tool: D78: 
Entao, agora digite o tempo digitado 

tool: D28: (lembrando que pode ser decimal
separado por ponto (.), recomendando valores acima de 1.0):


tool: D22: %f

assistant: ```c
float questiona_tempo() {
  float tempo;
  printf("Ha tres modos para a exibicao:\n");
  printf("\t1 - Exibicao direta;\n");
  printf("\t2 - Exibicao pausada por ENTER;\n");
  printf("\t3 - Exibicao pausada por tempo.\n");
  printf("\nSabendo das opcoes, digite a sua escolha:\n");
  switch (ler_intervalo(1, 3)) {
  case 1:
    printf("\nA exibicao direta foi selecionada\n");
    return -1;
  case 2:
    printf("\nA exibicao pausada por ENTER foi selecionada\n");
    return 0.0;
  case 3:
    printf("\nEntao, agora digite o tempo digitado ");
    printf("(lembrando que pode ser decimal\nseparado por ponto (.), recomendando valores acima de 1.0):\n");
    scanf("%f", &tempo);
    getchar();
  }
  return tempo;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<questiona_tempo>:
  endbr64
  sub    $0x18,%rsp
  lea    D61(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D88(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    $0x1,%edi
  call   <ler_intervalo@plt>
  cmp    $0x2,%eax
  je     L43
  cmp    $0x3,%eax
  je     L13
  cmp    $0x1,%eax
  je     L38
L14:
  movss  0x4(%rsp),%xmm0
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L43:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L38:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  movss  D9(%rip),%xmm0
  jmp    L34
  xchg   %ax,%ax
L13:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  jmp    L14
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D61
type_infered: string
name: retrieve_data
arguments: label: D42
type_infered: string
name: retrieve_data
arguments: label: D44
type_infered: string
name: retrieve_data
arguments: label: D88
type_infered: string
name: retrieve_data
arguments: label: D31
type_infered: string
name: retrieve_data
arguments: label: D49
type_infered: string
name: retrieve_data
arguments: label: D23
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: byte[4]
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string

tool: D61: Ha tres modos para a exibicao:


tool: D42: 	1 - Exibicao direta;


tool: D44: 	2 - Exibicao pausada por ENTER;


tool: D88: 	3 - Exibicao pausada por tempo.


tool: D31: 
Sabendo das opcoes, digite a sua escolha:


tool: D49: 
A exibicao pausada por ENTER foi selecionada


tool: D23: 
A exibicao direta foi selecionada


tool: {"D9": [0x00,0x00,0x80,0xbf]}

tool: D26: 
Entao, agora digite o tempo digitado 

tool: D12: (lembrando que pode ser decimal
separado por ponto (.), recomendando valores acima de 1.0):


tool: D25: %f

assistant: ```c
float questiona_tempo() {
  float tempo;
  printf("Ha tres modos para a exibicao:\n");
  printf("\t1 - Exibicao direta;\n");
  printf("\t2 - Exibicao pausada por ENTER;\n");
  printf("\t3 - Exibicao pausada por tempo.\n");
  printf("\nSabendo das opcoes, digite a sua escolha:\n");
  switch (ler_intervalo(1, 3)) {
  case 1:
    printf("\nA exibicao direta foi selecionada\n");
    return -1;
  case 2:
    printf("\nA exibicao pausada por ENTER foi selecionada\n");
    return 0.0;
  case 3:
    printf("\nEntao, agora digite o tempo digitado ");
    printf("(lembrando que pode ser decimal\nseparado por ponto (.), recomendando valores acima de 1.0):\n");
    scanf("%f", &tempo);
    getchar();
  }
  return tempo;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<int_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    D28(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L2:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x30(%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%ecx
  cltq
  lea    D28(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L2
  lea    D28(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string

tool: D10: 01

assistant: ```c
char *int_string(int a, int len, int base) {
  static char ss[100];
  int t = a, k, i;
  char *binary = "01";
  ss[len] = '\0';
  for (i = 0; i < len; i++) {
    k = t % base;
    ss[len - i - 1] = '0' + k;
    t = t / base;
  }
  return ss;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_string>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  mov    %edx,%edi
  movslq %esi,%rdx
  lea    D12(%rip),%rcx
  movb   $0x0,(%rcx,%rdx,1)
  test   %esi,%esi
  jle    L16
  mov    %rdx,%rsi
  add    %rdx,%rcx
  lea    D20(%rip),%rdx
  add    %rdx,%rsi
  lea    -0x1(%r8),%edx
  sub    %rdx,%rsi
L18:
  cltd
  idiv   %edi
  add    $0x30,%edx
  mov    %dl,-0x1(%rcx)
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L18
L16:
  lea    D12(%rip),%rax
  ret
```

assistant: ```c
char *int_string(int a, int len, int base) {
  static char ss[100];
  int t = a, k, i;
  char *binary = "01";
  ss[len] = '\0';
  for (i = 0; i < len; i++) {
    k = t % base;
    ss[len - i - 1] = '0' + k;
    t = t / base;
  }
  return ss;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_string>:
  endbr64
  movslq %esi,%rsi
  lea    D3(%rip),%r9
  mov    %edi,%eax
  mov    %edx,%edi
  movb   $0x0,(%r9,%rsi,1)
  mov    %rsi,%r8
  test   %esi,%esi
  jle    L0
  lea    -0x1(%r9),%rdx
  lea    (%r9,%rsi,1),%rcx
  add    %rdx,%rsi
  lea    -0x1(%r8),%edx
  sub    %rdx,%rsi
L10:
  cltd
  sub    $0x1,%rcx
  idiv   %edi
  add    $0x30,%edx
  mov    %dl,(%rcx)
  cmp    %rsi,%rcx
  jne    L10
L0:
  mov    %r9,%rax
  ret
```

assistant: ```c
char *int_string(int a, int len, int base) {
  static char ss[100];
  int t = a, k, i;
  char *binary = "01";
  ss[len] = '\0';
  for (i = 0; i < len; i++) {
    k = t % base;
    ss[len - i - 1] = '0' + k;
    t = t / base;
  }
  return ss;
}
```
user: What is the c source code of the assembly code below:

```asm
<int_string>:
  endbr64
  movslq %esi,%rsi
  lea    D8(%rip),%r9
  mov    %edi,%eax
  mov    %edx,%edi
  movb   $0x0,(%r9,%rsi,1)
  mov    %rsi,%r8
  test   %esi,%esi
  jle    L6
  lea    -0x1(%r9),%rdx
  lea    (%r9,%rsi,1),%rcx
  add    %rdx,%rsi
  lea    -0x1(%r8),%edx
  sub    %rdx,%rsi
L7:
  cltd
  sub    $0x1,%rcx
  idiv   %edi
  add    $0x30,%edx
  mov    %dl,(%rcx)
  cmp    %rcx,%rsi
  jne    L7
L6:
  mov    %r9,%rax
  ret
```

assistant: ```c
char *int_string(int a, int len, int base) {
  static char ss[100];
  int t = a, k, i;
  char *binary = "01";
  ss[len] = '\0';
  for (i = 0; i < len; i++) {
    k = t % base;
    ss[len - i - 1] = '0' + k;
    t = t / base;
  }
  return ss;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<slaAddet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  mov    %rdi,-0x50(%rbp)
  mov    %rsi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x10(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x30(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <sla_addet_@plt>
  movsd  -0x18(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void slaAddet(double rm, double dm, double eq, double *rc, double *dc) {
  double RM;
  double DM;
  double EQ;
  double RC;
  double DC;
  RM = rm;
  DM = dm;
  EQ = eq;
  sla_addet_(&RM, &DM, &EQ, &RC, &DC);
  *rc = RC;
  *dc = DC;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<slaAddet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x10(%rsp)
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x20(%rsp),%r8
  call   <sla_addet_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaAddet(double rm, double dm, double eq, double *rc, double *dc) {
  double RM;
  double DM;
  double EQ;
  double RC;
  double DC;
  RM = rm;
  DM = dm;
  EQ = eq;
  sla_addet_(&RM, &DM, &EQ, &RC, &DC);
  *rc = RC;
  *dc = DC;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<slaAddet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <sla_addet_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaAddet(double rm, double dm, double eq, double *rc, double *dc) {
  double RM;
  double DM;
  double EQ;
  double RC;
  double DC;
  RM = rm;
  DM = dm;
  EQ = eq;
  sla_addet_(&RM, &DM, &EQ, &RC, &DC);
  *rc = RC;
  *dc = DC;
}
```
user: What is the c source code of the assembly code below?

```asm
<slaAddet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <sla_addet_@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaAddet(double rm, double dm, double eq, double *rc, double *dc) {
  double RM;
  double DM;
  double EQ;
  double RC;
  double DC;
  RM = rm;
  DM = dm;
  EQ = eq;
  sla_addet_(&RM, &DM, &EQ, &RC, &DC);
  *rc = RC;
  *dc = DC;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: string

tool: D18: %3d

tool: D46: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D16(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D16
data_type: string

tool: D0: %3d

tool: D16: %d


assistant: ```c
int main() {
  int a, b;
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string

tool: D12: %d


tool: D1: %3d

assistant: ```c
int main() {
  int a, b;
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string

tool: D6: %d


tool: D15: %3d

assistant: ```c
int main() {
  int a, b;
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  scanf("%3d", &a);
  printf("%d\n", a);
  scanf("%3d", &a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getpwnam_error_translate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L55
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L55
  mov    D48(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L55
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L55
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L33
L55:
  mov    -0x4(%rbp),%eax
  jmp    L45
L33:
  mov    D50(%rip),%rax
  mov    (%rax),%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int getpwnam_error_translate(int err) {
  if ((err == EIO) || (err == EMFILE) || (err == ENFILE) || (err == ENOMEM) || (err == ERANGE)) {
    return err;
  }
  return ENOENT;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getpwnam_error_translate>:
  endbr64
  mov    %edi,%eax
  mov    D58(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L26
  mov    D37(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L26
  mov    D24(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L26
  mov    D9(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L26
  mov    D55(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L26
  mov    D33(%rip),%rax
  mov    (%rax),%eax
L26:
  ret
```

assistant: ```c
int getpwnam_error_translate(int err) {
  if ((err == EIO) || (err == EMFILE) || (err == ENFILE) || (err == ENOMEM) || (err == ERANGE)) {
    return err;
  }
  return ENOENT;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getpwnam_error_translate>:
  endbr64
  mov    D53(%rip),%rdx
  mov    %edi,%eax
  cmp    %edi,(%rdx)
  je     L29
  mov    D10(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L29
  mov    D58(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L29
  mov    D48(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L29
  mov    D17(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L29
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L29:
  ret
```

assistant: ```c
int getpwnam_error_translate(int err) {
  if ((err == EIO) || (err == EMFILE) || (err == ENFILE) || (err == ENOMEM) || (err == ERANGE)) {
    return err;
  }
  return ENOENT;
}
```