ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<p_safe_free>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L16
  call   <free@plt>
  movq   $0x0,(%rbx)
L16:
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void p_safe_free(void **pointerp) {
  if (pointerp != NULL && *pointerp != NULL) {
    free(*pointerp);
    *pointerp = NULL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<p_safe_free>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  call   <free@plt>
  movq   $0x0,(%rbx)
L4:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void p_safe_free(void **pointerp) {
  if (pointerp != NULL && *pointerp != NULL) {
    free(*pointerp);
    *pointerp = NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<p_safe_free>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  call   <free@plt>
  movq   $0x0,(%rbx)
L9:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void p_safe_free(void **pointerp) {
  if (pointerp != NULL && *pointerp != NULL) {
    free(*pointerp);
    *pointerp = NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_blank_with_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L42
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L24:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  jmp    L30
L42:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <get_blank_length@plt>
  mov    %eax,-0x8(%rbp)
  movsbl -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L37
L33:
  movsbl -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x8,-0xc(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L33
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L18:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L18
L30:
  nop
  leave
  ret
```

assistant: ```c
void print_blank_with_tab(int cur_line_length, int cur_blanks_length, int blank_num_per_tab, char tab_stop) {
  int remain_blank;
  int blank_index;
  int last_non_blank_length;
  int first_tab_equal_blank;
  if (cur_blanks_length < blank_num_per_tab) {
    for (blank_index = 0; blank_index < cur_blanks_length; blank_index++) {
      putchar(' ');
    }
  } else {
    last_non_blank_length = cur_line_length - cur_blanks_length;
    first_tab_equal_blank = get_blank_length(last_non_blank_length, 8);
    putchar(tab_stop);
    last_non_blank_length = last_non_blank_length + first_tab_equal_blank;
    while (cur_line_length - last_non_blank_length >= blank_num_per_tab) {
      putchar(tab_stop);
      last_non_blank_length += 8;
    }
    remain_blank = cur_line_length - last_non_blank_length;
    for (blank_index = 0; blank_index < remain_blank; blank_index++) {
      putchar(' ');
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_blank_with_tab>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  cmp    %edx,%esi
  jge    L22
  test   %esi,%esi
  jle    L75
  mov    $0x0,%ebx
L70:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L70
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    %edi,%ebx
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %edi,%r14d
  sub    %esi,%r14d
  mov    $0x8,%esi
  mov    %r14d,%edi
  call   <get_blank_length@plt>
  mov    %eax,%ebp
  movsbl %r13b,%r13d
  mov    %r13d,%edi
  call   <putchar@plt>
  lea    (%r14,%rbp,1),%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  cmp    %ebp,%r12d
  jg     L79
  add    $0x8,%eax
  sub    %eax,%ebx
L49:
  mov    %r13d,%edi
  call   <putchar@plt>
  mov    %ebx,%ebp
  sub    $0x8,%ebx
  cmp    %ebp,%r12d
  jle    L49
L79:
  test   %ebp,%ebp
  jle    L75
  mov    $0x0,%ebx
L26:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L26
  jmp    L75
```

assistant: ```c
void print_blank_with_tab(int cur_line_length, int cur_blanks_length, int blank_num_per_tab, char tab_stop) {
  int remain_blank;
  int blank_index;
  int last_non_blank_length;
  int first_tab_equal_blank;
  if (cur_blanks_length < blank_num_per_tab) {
    for (blank_index = 0; blank_index < cur_blanks_length; blank_index++) {
      putchar(' ');
    }
  } else {
    last_non_blank_length = cur_line_length - cur_blanks_length;
    first_tab_equal_blank = get_blank_length(last_non_blank_length, 8);
    putchar(tab_stop);
    last_non_blank_length = last_non_blank_length + first_tab_equal_blank;
    while (cur_line_length - last_non_blank_length >= blank_num_per_tab) {
      putchar(tab_stop);
      last_non_blank_length += 8;
    }
    remain_blank = cur_line_length - last_non_blank_length;
    for (blank_index = 0; blank_index < remain_blank; blank_index++) {
      putchar(' ');
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_blank_with_tab>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    %edx,%esi
  jge    L32
  test   %esi,%esi
  jle    L59
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L0
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %edi,%r14d
  mov    %edi,%ebx
  mov    %ecx,%r13d
  mov    %edx,%r12d
  sub    %esi,%r14d
  mov    $0x8,%esi
  movsbl %r13b,%r13d
  mov    %r14d,%edi
  call   <get_blank_length@plt>
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <putchar@plt>
  add    %ebp,%r14d
  mov    %ebx,%ebp
  sub    %r14d,%ebp
  cmp    %ebp,%r12d
  jg     L47
  add    $0x8,%r14d
  sub    %r14d,%ebx
  nopl   (%rax)
L37:
  mov    %r13d,%edi
  mov    %ebx,%ebp
  sub    $0x8,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebp
  jge    L37
L47:
  test   %ebp,%ebp
  jle    L59
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L43
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_blank_with_tab(int cur_line_length, int cur_blanks_length, int blank_num_per_tab, char tab_stop) {
  int remain_blank;
  int blank_index;
  int last_non_blank_length;
  int first_tab_equal_blank;
  if (cur_blanks_length < blank_num_per_tab) {
    for (blank_index = 0; blank_index < cur_blanks_length; blank_index++) {
      putchar(' ');
    }
  } else {
    last_non_blank_length = cur_line_length - cur_blanks_length;
    first_tab_equal_blank = get_blank_length(last_non_blank_length, 8);
    putchar(tab_stop);
    last_non_blank_length = last_non_blank_length + first_tab_equal_blank;
    while (cur_line_length - last_non_blank_length >= blank_num_per_tab) {
      putchar(tab_stop);
      last_non_blank_length += 8;
    }
    remain_blank = cur_line_length - last_non_blank_length;
    for (blank_index = 0; blank_index < remain_blank; blank_index++) {
      putchar(' ');
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_blank_with_tab>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  cmp    %edx,%esi
  jge    L36
  test   %esi,%esi
  jle    L15
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L25
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %edi,%r14d
  mov    %edi,%ebx
  mov    %ecx,%r13d
  mov    %edx,%r12d
  sub    %esi,%r14d
  mov    $0x8,%esi
  movsbl %r13b,%r13d
  mov    %r14d,%edi
  call   <get_blank_length@plt>
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <putchar@plt>
  add    %ebp,%r14d
  mov    %ebx,%ebp
  sub    %r14d,%ebp
  cmp    %ebp,%r12d
  jg     L6
  add    $0x8,%r14d
  sub    %r14d,%ebx
  nopl   (%rax)
L39:
  mov    %r13d,%edi
  mov    %ebx,%ebp
  sub    $0x8,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebp
  jge    L39
L6:
  test   %ebp,%ebp
  jle    L15
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L51:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L51
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_blank_with_tab(int cur_line_length, int cur_blanks_length, int blank_num_per_tab, char tab_stop) {
  int remain_blank;
  int blank_index;
  int last_non_blank_length;
  int first_tab_equal_blank;
  if (cur_blanks_length < blank_num_per_tab) {
    for (blank_index = 0; blank_index < cur_blanks_length; blank_index++) {
      putchar(' ');
    }
  } else {
    last_non_blank_length = cur_line_length - cur_blanks_length;
    first_tab_equal_blank = get_blank_length(last_non_blank_length, 8);
    putchar(tab_stop);
    last_non_blank_length = last_non_blank_length + first_tab_equal_blank;
    while (cur_line_length - last_non_blank_length >= blank_num_per_tab) {
      putchar(tab_stop);
      last_non_blank_length += 8;
    }
    remain_blank = cur_line_length - last_non_blank_length;
    for (blank_index = 0; blank_index < remain_blank; blank_index++) {
      putchar(' ');
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: string
name: extract_symbolic_data
arguments: data_label: D37
type: string
name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D3: This is your current working directory:


tool: D2: cd

tool: D31: This is your current PATH:


tool: D37: PATH

tool: D25: This is the date:


tool: D7: TIME /t

assistant: ```c
int main() {
  printf("This is your current working directory:\n");
  system("cd");
  printf("This is your current PATH:\n");
  system("PATH");
  printf("This is the date:\n");
  system("TIME /t");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <system@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <system@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D36
type: string
name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D47
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D56
type: string

tool: D36: This is your current working directory:


tool: D1: cd

tool: D47: This is your current PATH:


tool: D32: PATH

tool: D23: This is the date:


tool: D56: TIME /t

assistant: ```c
int main() {
  printf("This is your current working directory:\n");
  system("cd");
  printf("This is your current PATH:\n");
  system("PATH");
  printf("This is the date:\n");
  system("TIME /t");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <system@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D51
type_guessed: string
name: read_data
arguments: label: D4
type_guessed: string
name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string
name: read_data
arguments: label: D35
type_guessed: string
name: read_data
arguments: label: D54
type_guessed: string

tool: D51: This is your current working directory:


tool: D4: cd

tool: D2: This is your current PATH:


tool: D21: PATH

tool: D35: This is the date:


tool: D54: TIME /t

assistant: ```c
int main() {
  printf("This is your current working directory:\n");
  system("cd");
  printf("This is your current PATH:\n");
  system("PATH");
  printf("This is the date:\n");
  system("TIME /t");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <system@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <system@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D38
type_guessed: string
name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D39
type_guessed: string
name: parse_data
arguments: label: D49
type_guessed: string
name: parse_data
arguments: label: D54
type_guessed: string
name: parse_data
arguments: label: D36
type_guessed: string

tool: D38: This is your current working directory:


tool: D17: cd

tool: D39: This is your current PATH:


tool: D49: PATH

tool: D54: This is the date:


tool: D36: TIME /t

assistant: ```c
int main() {
  printf("This is your current working directory:\n");
  system("cd");
  printf("This is your current PATH:\n");
  system("PATH");
  printf("This is the date:\n");
  system("TIME /t");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<media>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L18:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movq   %xmm2,%rdx
  mov    -0x14(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D18: Digite o valor do dado de numero %i:	

tool: D10: %f

tool: D0: 
A media dos %i valores apresentados eh: %.4f


assistant: ```c
void media(int num, int *ponteiro) {
  int i;
  float avg = 0;
  for (i = 0; i < num; i++) {
    printf("Digite o valor do dado de numero %i:\t", i + 1);
    scanf("%f", &ponteiro[i]);
  }
  for (i = 0; i < num; i++)
    avg = avg + ponteiro[i];
  avg = avg / num;
  printf("\nA media dos %i valores apresentados eh: %.4f\n", num, avg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<media>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L6
  mov    %rsi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%ebp
  lea    D25(%rip),%r15
  lea    D4(%rip),%r14
L10:
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %r13d,%ebp
  jne    L10
  lea    -0x1(%r13),%eax
  mov    0x8(%rsp),%rdx
  lea    0x4(%rdx,%rax,4),%rax
  pxor   %xmm0,%xmm0
L26:
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rbx),%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rbx
  cmp    %rax,%rbx
  jne    L26
L2:
  pxor   %xmm1,%xmm1
  cvtsi2ss %r13d,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %r13d,%esi
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  pxor   %xmm0,%xmm0
  jmp    L2
```

tool_calls: name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D4
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string

tool: D25: Digite o valor do dado de numero %i:	

tool: D4: %f

tool: D15: 
A media dos %i valores apresentados eh: %.4f


assistant: ```c
void media(int num, int *ponteiro) {
  int i;
  float avg = 0;
  for (i = 0; i < num; i++) {
    printf("Digite o valor do dado de numero %i:\t", i + 1);
    scanf("%f", &ponteiro[i]);
  }
  for (i = 0; i < num; i++)
    avg = avg + ponteiro[i];
  avg = avg / num;
  printf("\nA media dos %i valores apresentados eh: %.4f\n", num, avg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<media>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L18
  mov    %rsi,%rbx
  mov    %rsi,%rbp
  lea    D4(%rip),%r14
  xor    %r15d,%r15d
  lea    D18(%rip),%r13
  nopl   0x0(%rax)
L29:
  add    $0x1,%r15d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r15d,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12d,%r15d
  jne    L29
  mov    0x8(%rsp),%rdx
  lea    -0x1(%r12),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdx,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L28:
  pxor   %xmm1,%xmm1
  add    $0x4,%rbx
  cvtsi2ssl -0x4(%rbx),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rbx,%rax
  jne    L28
L6:
  pxor   %xmm1,%xmm1
  add    $0x18,%rsp
  mov    %r12d,%esi
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L18:
  pxor   %xmm0,%xmm0
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D4: Digite o valor do dado de numero %i:	

tool: D18: %f

tool: D0: 
A media dos %i valores apresentados eh: %.4f


assistant: ```c
void media(int num, int *ponteiro) {
  int i;
  float avg = 0;
  for (i = 0; i < num; i++) {
    printf("Digite o valor do dado de numero %i:\t", i + 1);
    scanf("%f", &ponteiro[i]);
  }
  for (i = 0; i < num; i++)
    avg = avg + ponteiro[i];
  avg = avg / num;
  printf("\nA media dos %i valores apresentados eh: %.4f\n", num, avg);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<media>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L19
  mov    %rsi,%r15
  mov    %rsi,%rbp
  lea    D21(%rip),%r14
  xor    %ebx,%ebx
  lea    D5(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12d,%ebx
  jne    L34
  lea    -0x1(%r12),%eax
  cmp    $0x2,%eax
  jbe    L43
  mov    %r12d,%eax
  mov    0x8(%rsp),%rcx
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rcx,%rax,1),%rax
  nopl   0x0(%rax)
L69:
  movdqu (%r15),%xmm3
  add    $0x10,%r15
  cvtdq2ps %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rax,%r15
  jne    L69
  mov    %r12d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r12b
  je     L3
L67:
  mov    0x8(%rsp),%rdi
  movslq %eax,%rdx
  pxor   %xmm1,%xmm1
  lea    0x0(,%rdx,4),%rcx
  cvtsi2ssl (%rdi,%rdx,4),%xmm1
  lea    0x1(%rax),%edx
  addss  %xmm1,%xmm0
  cmp    %edx,%r12d
  jle    L3
  pxor   %xmm1,%xmm1
  add    $0x2,%eax
  cvtsi2ssl 0x4(%rdi,%rcx,1),%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%r12d
  jle    L3
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rdi,%rcx,1),%xmm1
  addss  %xmm1,%xmm0
L3:
  pxor   %xmm1,%xmm1
  add    $0x18,%rsp
  mov    %r12d,%esi
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  pxor   %xmm0,%xmm0
  jmp    L3
L43:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L67
```

tool_calls: name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string

tool: D21: Digite o valor do dado de numero %i:	

tool: D5: %f

tool: D2: 
A media dos %i valores apresentados eh: %.4f


assistant: ```c
void media(int num, int *ponteiro) {
  int i;
  float avg = 0;
  for (i = 0; i < num; i++) {
    printf("Digite o valor do dado de numero %i:\t", i + 1);
    scanf("%f", &ponteiro[i]);
  }
  for (i = 0; i < num; i++)
    avg = avg + ponteiro[i];
  avg = avg / num;
  printf("\nA media dos %i valores apresentados eh: %.4f\n", num, avg);
}
```