ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ftp_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    $0x15,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <connect_to_ftpserver@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L23
L10:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <login@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ftp_reset@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ftp_type@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ftp_pasv@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L14
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ftp_retr@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ftp_close_datasockfd@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ftp_quit@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D16
datatype: string

tool: D14: 192.168.5.110

tool: D16: ###%s(),ftp_pasv failed!


assistant: ```c
int ftp_get(char *filename) {
  int sockfd = -1;
  int pasv_sockfd = -1;
  int ret = -1;
  sockfd = connect_to_ftpserver("192.168.5.110", 21);
  if (sockfd < 0) {
    return -1;
  }
  login(sockfd);
  ftp_reset(sockfd);
  ftp_type(sockfd);
  pasv_sockfd = ftp_pasv(sockfd);
  if (pasv_sockfd < 0) {
    printf("###%s(),ftp_pasv failed!\n");
  }
  ret = ftp_retr(sockfd, filename, pasv_sockfd);
  ftp_close_datasockfd(sockfd, pasv_sockfd);
  ftp_quit(sockfd);
out:
  close(sockfd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ftp_get>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x15,%esi
  lea    D6(%rip),%rdi
  call   <connect_to_ftpserver@plt>
  test   %eax,%eax
  js     L20
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <login@plt>
  mov    %ebx,%edi
  call   <ftp_reset@plt>
  mov    %ebx,%edi
  call   <ftp_type@plt>
  mov    %ebx,%edi
  call   <ftp_pasv@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L17
L37:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <ftp_retr@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <ftp_close_datasockfd@plt>
  mov    %ebx,%edi
  call   <ftp_quit@plt>
  mov    %ebx,%edi
  call   <close@plt>
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0xffffffff,%eax
  jmp    L10
L17:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L37
```

tool_calls: name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D14
type: string

tool: D6: 192.168.5.110

tool: D14: ###%s(),ftp_pasv failed!


assistant: ```c
int ftp_get(char *filename) {
  int sockfd = -1;
  int pasv_sockfd = -1;
  int ret = -1;
  sockfd = connect_to_ftpserver("192.168.5.110", 21);
  if (sockfd < 0) {
    return -1;
  }
  login(sockfd);
  ftp_reset(sockfd);
  ftp_type(sockfd);
  pasv_sockfd = ftp_pasv(sockfd);
  if (pasv_sockfd < 0) {
    printf("###%s(),ftp_pasv failed!\n");
  }
  ret = ftp_retr(sockfd, filename, pasv_sockfd);
  ftp_close_datasockfd(sockfd, pasv_sockfd);
  ftp_quit(sockfd);
out:
  close(sockfd);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ftp_get>:
  endbr64
  push   %r13
  mov    $0x15,%esi
  mov    %rdi,%r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  call   <connect_to_ftpserver@plt>
  test   %eax,%eax
  js     L14
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <login@plt>
  mov    %ebp,%edi
  call   <ftp_reset@plt>
  mov    %ebp,%edi
  call   <ftp_type@plt>
  mov    %ebp,%edi
  call   <ftp_pasv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L1
L15:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <ftp_retr@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <ftp_close_datasockfd@plt>
  mov    %ebp,%edi
  call   <ftp_quit@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1130 <close@plt>
L14:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D19: 192.168.5.110

tool: D14: ###%s(),ftp_pasv failed!


assistant: ```c
int ftp_get(char *filename) {
  int sockfd = -1;
  int pasv_sockfd = -1;
  int ret = -1;
  sockfd = connect_to_ftpserver("192.168.5.110", 21);
  if (sockfd < 0) {
    return -1;
  }
  login(sockfd);
  ftp_reset(sockfd);
  ftp_type(sockfd);
  pasv_sockfd = ftp_pasv(sockfd);
  if (pasv_sockfd < 0) {
    printf("###%s(),ftp_pasv failed!\n");
  }
  ret = ftp_retr(sockfd, filename, pasv_sockfd);
  ftp_close_datasockfd(sockfd, pasv_sockfd);
  ftp_quit(sockfd);
out:
  close(sockfd);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ftp_get>:
  endbr64
  push   %r13
  mov    $0x15,%esi
  mov    %rdi,%r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  call   <connect_to_ftpserver@plt>
  test   %eax,%eax
  js     L2
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <login@plt>
  mov    %ebp,%edi
  call   <ftp_reset@plt>
  mov    %ebp,%edi
  call   <ftp_type@plt>
  mov    %ebp,%edi
  call   <ftp_pasv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L19
L22:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <ftp_retr@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <ftp_close_datasockfd@plt>
  mov    %ebp,%edi
  call   <ftp_quit@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1130 <close@plt>
L2:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L22
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string
name: unpack_data
arguments: data_tag: D16
data_type: string

tool: D2: 192.168.5.110

tool: D16: ###%s(),ftp_pasv failed!


assistant: ```c
int ftp_get(char *filename) {
  int sockfd = -1;
  int pasv_sockfd = -1;
  int ret = -1;
  sockfd = connect_to_ftpserver("192.168.5.110", 21);
  if (sockfd < 0) {
    return -1;
  }
  login(sockfd);
  ftp_reset(sockfd);
  ftp_type(sockfd);
  pasv_sockfd = ftp_pasv(sockfd);
  if (pasv_sockfd < 0) {
    printf("###%s(),ftp_pasv failed!\n");
  }
  ret = ftp_retr(sockfd, filename, pasv_sockfd);
  ftp_close_datasockfd(sockfd, pasv_sockfd);
  ftp_quit(sockfd);
out:
  close(sockfd);
}
```
user: What is the c source code of the assembly code below:

```asm
<ptsname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1e,%edx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ptsname_r@plt>
  test   %rax,%rax
  jne    L5
  lea    D4(%rip),%rax
  jmp    L2
L5:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buffer[sizeof("/dev/pts/") + 20];
  return ptsname_r(fd, buffer, sizeof(buffer)) != 0 ? NULL : buffer;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ptsname>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%edx
  lea    D9(%rip),%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  lea    D9(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buffer[sizeof("/dev/pts/") + 20];
  return ptsname_r(fd, buffer, sizeof(buffer)) != 0 ? NULL : buffer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptsname>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  mov    $0x1e,%edx
  mov    %rbx,%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buffer[sizeof("/dev/pts/") + 20];
  return ptsname_r(fd, buffer, sizeof(buffer)) != 0 ? NULL : buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptsname>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    $0x1e,%edx
  mov    %rbx,%rsi
  call   <ptsname_r@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ptsname(int fd) {
  static char buffer[sizeof("/dev/pts/") + 20];
  return ptsname_r(fd, buffer, sizeof(buffer)) != 0 ? NULL : buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_224_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_224_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_224_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  or     (%rdi),%sil
  and    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_224_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_224_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  or     (%rdi),%sil
  and    %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_224_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D | S;
  stk1 = T & stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remlpord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  movsd  %xmm0,-0x68(%rbp)
  movsd  %xmm1,-0x70(%rbp)
  movsd  %xmm2,-0x78(%rbp)
  movsd  %xmm3,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x80(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x80(%rbp)
  movsd  -0x78(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x78(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L15
L45:
  mov    -0x60(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D14(%rip),%rax
  movsd  (%rdx,%rax,1),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x80(%rbp),%xmm1
  mov    -0x60(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D56(%rip),%rax
  movsd  (%rdx,%rax,1),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x20(%rbp,%rax,8)
  addl   $0x1,-0x60(%rbp)
L15:
  cmpl   $0x2,-0x60(%rbp)
  jle    L45
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L13
L17:
  mov    -0x5c(%rbp),%eax
  cltq
  movsd  -0x20(%rbp,%rax,8),%xmm1
  mov    -0x5c(%rbp),%eax
  cltq
  movsd  -0x40(%rbp,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x58(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  addl   $0x1,-0x5c(%rbp)
L13:
  cmpl   $0x2,-0x5c(%rbp)
  jle    L17
  movsd  -0x78(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x80(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D54(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  -0x70(%rbp),%xmm0
  subsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x58(%rbp),%xmm0
  divsd  -0x48(%rbp),%xmm0
  movsd  -0x50(%rbp),%xmm1
  movapd %xmm1,%xmm2
  mulsd  -0x48(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D24(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D24
type_infered: f32[2]
name: unpack_data
arguments: tag: D1
type_infered: f64
name: unpack_data
arguments: tag: D54
type_infered: f64

tool: {"D24": [0.0,1.875]}

tool: D1: 0.51244

tool: D54: 11.01217

assistant: ```c
double remlpord(double f1, double f2, double d1, double d2) {
  static double A1A3[3] = {5.309e-03, 7.114e-02, -4.761e-01};
  static double A4A6[3] = {-2.660e-03, -5.941e-01, -4.278e-01};
  d1 = log10(d1);
  d2 = log10(d2);
  double lh[3] = {d1 * d1, d1, 1};
  double DD1[3] = {0, 0, 0};
  for (int i = 0; i < 3; i++)
    DD1[i] = d2 * A1A3[i] + A4A6[i];
  double D = 0.0;
  for (int i = 0; i < 3; i++)
    D += DD1[i] * lh[i];
  double fK = 11.01217 + (d1 - d2) * 0.51244;
  double df = f2 - f1;
  return D / df - fK * df + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remlpord>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%r14
  movq   %xmm1,%rbx
  movapd %xmm2,%xmm0
  movq   %xmm3,%rbp
  call   <log10@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %rbp,%xmm0
  call   <log10@plt>
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm1
  mulsd  D21(%rip),%xmm1
  subsd  D99(%rip),%xmm1
  movsd  0x8(%rsp),%xmm6
  movapd %xmm6,%xmm0
  mulsd  %xmm6,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  D53(%rip),%xmm1
  movapd %xmm4,%xmm3
  mulsd  D86(%rip),%xmm3
  subsd  D19(%rip),%xmm3
  mulsd  %xmm6,%xmm3
  addsd  %xmm1,%xmm3
  movq   %rbx,%xmm5
  movq   %r14,%xmm7
  subsd  %xmm7,%xmm5
  movapd %xmm4,%xmm2
  mulsd  D90(%rip),%xmm2
  subsd  D39(%rip),%xmm2
  addsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  divsd  %xmm5,%xmm0
  subsd  %xmm4,%xmm6
  movapd %xmm6,%xmm1
  mulsd  D20(%rip),%xmm1
  addsd  D50(%rip),%xmm1
  mulsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm0
  addsd  D43(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D99
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D53
type_guessed: f64
name: extract_symbolic_data
arguments: label: D86
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D19
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D90
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D39
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D20
type_guessed: f64
name: extract_symbolic_data
arguments: label: D50
type_guessed: f64
name: extract_symbolic_data
arguments: label: D43
type_guessed: byte[8]

tool: {"D21": [0xf7,0xcd,0xfd,0xd5,0xe3,0xbe,0x75,0x3f]}

tool: {"D99": [0x0a,0x4b,0x3c,0xa0,0x6c,0xca,0x65,0x3f]}

tool: D53: 0

tool: {"D86": [0x11,0xfc,0x6f,0x25,0x3b,0x36,0xb2,0x3f]}

tool: {"D19": [0x17,0xb7,0xd1,0x00,0xde,0x02,0xe3,0x3f]}

tool: {"D90": [0xd5,0x09,0x68,0x22,0x6c,0x78,0xde,0xbf]}

tool: {"D39": [0xa9,0xa4,0x4e,0x40,0x13,0x61,0xdb,0x3f]}

tool: D20: 0.51244

tool: D50: 11.01217

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double remlpord(double f1, double f2, double d1, double d2) {
  static double A1A3[3] = {5.309e-03, 7.114e-02, -4.761e-01};
  static double A4A6[3] = {-2.660e-03, -5.941e-01, -4.278e-01};
  d1 = log10(d1);
  d2 = log10(d2);
  double lh[3] = {d1 * d1, d1, 1};
  double DD1[3] = {0, 0, 0};
  for (int i = 0; i < 3; i++)
    DD1[i] = d2 * A1A3[i] + A4A6[i];
  double D = 0.0;
  for (int i = 0; i < 3; i++)
    D += DD1[i] * lh[i];
  double fK = 11.01217 + (d1 - d2) * 0.51244;
  double df = f2 - f1;
  return D / df - fK * df + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<remlpord>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  call   <log10@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm3,%xmm0
  call   <log10@plt>
  movsd  D87(%rip),%xmm6
  movsd  0x8(%rsp),%xmm2
  movsd  D73(%rip),%xmm3
  movapd %xmm0,%xmm5
  movsd  0x18(%rsp),%xmm4
  mulsd  %xmm0,%xmm6
  movapd %xmm2,%xmm1
  subsd  (%rsp),%xmm4
  mulsd  %xmm2,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  D75(%rip),%xmm3
  movapd %xmm6,%xmm0
  subsd  D49(%rip),%xmm0
  mulsd  %xmm2,%xmm3
  subsd  %xmm5,%xmm2
  mulsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm1
  addsd  D77(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  D5(%rip),%xmm1
  addsd  %xmm0,%xmm3
  movsd  D72(%rip),%xmm0
  mulsd  %xmm5,%xmm0
  subsd  D29(%rip),%xmm0
  mulsd  %xmm4,%xmm1
  addsd  %xmm3,%xmm0
  divsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  addsd  D96(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D87
type_infered: byte[8]
name: disassemble_data
arguments: tag: D73
type_infered: byte[8]
name: disassemble_data
arguments: tag: D75
type_infered: byte[8]
name: disassemble_data
arguments: tag: D49
type_infered: byte[8]
name: disassemble_data
arguments: tag: D2
type_infered: f64
name: disassemble_data
arguments: tag: D77
type_infered: f64
name: disassemble_data
arguments: tag: D5
type_infered: f64
name: disassemble_data
arguments: tag: D72
type_infered: byte[8]
name: disassemble_data
arguments: tag: D29
type_infered: byte[8]
name: disassemble_data
arguments: tag: D96
type_infered: byte[8]

tool: {"D87": [0xf7,0xcd,0xfd,0xd5,0xe3,0xbe,0x75,0x3f]}

tool: {"D73": [0x11,0xfc,0x6f,0x25,0x3b,0x36,0xb2,0x3f]}

tool: {"D75": [0x17,0xb7,0xd1,0x00,0xde,0x02,0xe3,0x3f]}

tool: {"D49": [0x0a,0x4b,0x3c,0xa0,0x6c,0xca,0x65,0x3f]}

tool: D2: 0.51244

tool: D77: 0

tool: D5: 11.01217

tool: {"D72": [0xd5,0x09,0x68,0x22,0x6c,0x78,0xde,0xbf]}

tool: {"D29": [0xa9,0xa4,0x4e,0x40,0x13,0x61,0xdb,0x3f]}

tool: {"D96": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double remlpord(double f1, double f2, double d1, double d2) {
  static double A1A3[3] = {5.309e-03, 7.114e-02, -4.761e-01};
  static double A4A6[3] = {-2.660e-03, -5.941e-01, -4.278e-01};
  d1 = log10(d1);
  d2 = log10(d2);
  double lh[3] = {d1 * d1, d1, 1};
  double DD1[3] = {0, 0, 0};
  for (int i = 0; i < 3; i++)
    DD1[i] = d2 * A1A3[i] + A4A6[i];
  double D = 0.0;
  for (int i = 0; i < 3; i++)
    D += DD1[i] * lh[i];
  double fK = 11.01217 + (d1 - d2) * 0.51244;
  double df = f2 - f1;
  return D / df - fK * df + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remlpord>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x10(%rsp)
  call   <log10@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm3,%xmm0
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm5,%xmm5
  movsd  0x18(%rsp),%xmm1
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm6
  movapd D7(%rip),%xmm0
  subsd  (%rsp),%xmm1
  movapd %xmm2,%xmm3
  unpcklpd %xmm6,%xmm6
  mulsd  %xmm2,%xmm3
  mulpd  %xmm6,%xmm0
  addpd  D38(%rip),%xmm0
  unpcklpd %xmm2,%xmm3
  subsd  %xmm4,%xmm2
  mulpd  %xmm3,%xmm0
  movapd %xmm1,%xmm3
  addsd  %xmm0,%xmm5
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm5
  movsd  D29(%rip),%xmm0
  mulsd  %xmm4,%xmm0
  subsd  D65(%rip),%xmm0
  addsd  %xmm5,%xmm0
  divsd  %xmm1,%xmm0
  movsd  D48(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D55(%rip),%xmm1
  mulsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  addsd  D19(%rip),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: byte[16]
name: read_data
arguments: data_label: D38
type_guessed: byte[16]
name: read_data
arguments: data_label: D29
type_guessed: byte[8]
name: read_data
arguments: data_label: D65
type_guessed: byte[8]
name: read_data
arguments: data_label: D48
type_guessed: f64
name: read_data
arguments: data_label: D55
type_guessed: f64
name: read_data
arguments: data_label: D19
type_guessed: f32[2]

tool: {"D7": [0xf7,0xcd,0xfd,0xd5,0xe3,0xbe,0x75,0x3f,0x11,0xfc,0x6f,0x25,0x3b,0x36,0xb2,0x3f]}

tool: {"D38": [0x0a,0x4b,0x3c,0xa0,0x6c,0xca,0x65,0xbf,0x17,0xb7,0xd1,0x00,0xde,0x02,0xe3,0xbf]}

tool: {"D29": [0xd5,0x09,0x68,0x22,0x6c,0x78,0xde,0xbf]}

tool: {"D65": [0xa9,0xa4,0x4e,0x40,0x13,0x61,0xdb,0x3f]}

tool: D48: 0.51244

tool: D55: 11.01217

tool: {"D19": [0.0,1.875]}

assistant: ```c
double remlpord(double f1, double f2, double d1, double d2) {
  static double A1A3[3] = {5.309e-03, 7.114e-02, -4.761e-01};
  static double A4A6[3] = {-2.660e-03, -5.941e-01, -4.278e-01};
  d1 = log10(d1);
  d2 = log10(d2);
  double lh[3] = {d1 * d1, d1, 1};
  double DD1[3] = {0, 0, 0};
  for (int i = 0; i < 3; i++)
    DD1[i] = d2 * A1A3[i] + A4A6[i];
  double D = 0.0;
  for (int i = 0; i < 3; i++)
    D += DD1[i] * lh[i];
  double fK = 11.01217 + (d1 - d2) * 0.51244;
  double df = f2 - f1;
  return D / df - fK * df + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x4e4d4c4b4a494847,%rax
  movabs $0x565554535251504f,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x5a595857,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  cmpl   $0x1,-0x48(%rbp)
  jle    L47
  cmpl   $0x24,-0x48(%rbp)
  jg     L47
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L67
  negl   -0x44(%rbp)
L67:
  movl   $0x0,-0x38(%rbp)
L49:
  mov    -0x44(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %edx,%ecx
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x30(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x44(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %eax,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jg     L49
  cmpl   $0x0,-0x34(%rbp)
  jns    L40
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L40:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L1
L47:
  nop
L1:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void itob(int n, char s[], int b) {
  const char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int i, sign;
  if (b < 2 || b > 36) {
    return;
  }
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  do {
    s[i++] = digits[n % b];
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```