ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<move_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L55:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  je     L58
  cmpb   $0x20,-0x5(%rbp)
  je     L58
  cmpb   $0xd,-0x5(%rbp)
  je     L58
  cmpb   $0xa,-0x5(%rbp)
  je     L58
  cmpb   $0x23,-0x5(%rbp)
  je     L58
  cmpb   $0x3a,-0x5(%rbp)
  jne    L31
L58:
  subq   $0x1,-0x20(%rbp)
  jmp    L77
L31:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L55
L77:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *move_string(char *dest, const char *src, unsigned cnt) {
  unsigned i = 0;
  while (i < cnt) {
    char c = *src++;
    if ((!c) || (c == ' ') || (c == 0x0d) || (c == '\n') || (c == '#') || (c == ':')) {
      src--;
      break;
    }
    dest[i++] = c;
  }
  dest[i] = '\0';
  return src;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<move_string>:
  endbr64
  test   %edx,%edx
  je     L45
  mov    %rdi,%r8
  mov    $0x0,%ecx
  movabs $0x400000800002400,%r10
  jmp    L31
L79:
  add    $0x1,%ecx
  mov    %al,(%r8)
  add    $0x1,%r8
  cmp    %ecx,%edx
  je     L11
L31:
  mov    %rsi,%r9
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  test   $0xdf,%al
  je     L66
  cmp    $0x3a,%al
  ja     L79
  bt     %rax,%r10
  jae    L79
L66:
  mov    %ecx,%ecx
  movb   $0x0,(%rdi,%rcx,1)
  mov    %r9,%rax
  ret
L11:
  mov    %edx,%ecx
  mov    %rsi,%r9
  jmp    L66
L45:
  mov    %edx,%ecx
  mov    %rsi,%r9
  jmp    L66
```

assistant: ```c
const char *move_string(char *dest, const char *src, unsigned cnt) {
  unsigned i = 0;
  while (i < cnt) {
    char c = *src++;
    if ((!c) || (c == ' ') || (c == 0x0d) || (c == '\n') || (c == '#') || (c == ':')) {
      src--;
      break;
    }
    dest[i++] = c;
  }
  dest[i] = '\0';
  return src;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<move_string>:
  endbr64
  mov    %rdi,%r11
  mov    %rsi,%rcx
  test   %edx,%edx
  je     L63
  movabs $0x400000800002400,%r10
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%r9
  mov    %rdi,%rax
  mov    $0x1,%edi
  sub    %r11d,%edi
  jmp    L52
  nopl   (%rax)
L14:
  mov    %dl,(%rax)
  lea    (%rdi,%rax,1),%esi
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L67
L52:
  mov    %rcx,%r8
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  mov    %rax,%rsi
  test   $0xdf,%dl
  je     L29
  cmp    $0x3a,%dl
  ja     L14
  bt     %rdx,%r10
  jae    L14
L29:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  add    %r11,%rsi
  mov    %rcx,%r8
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
L63:
  mov    %rdi,%rsi
  mov    %rcx,%r8
  jmp    L29
```

assistant: ```c
const char *move_string(char *dest, const char *src, unsigned cnt) {
  unsigned i = 0;
  while (i < cnt) {
    char c = *src++;
    if ((!c) || (c == ' ') || (c == 0x0d) || (c == '\n') || (c == '#') || (c == ':')) {
      src--;
      break;
    }
    dest[i++] = c;
  }
  dest[i] = '\0';
  return src;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<move_string>:
  endbr64
  mov    %rdi,%r11
  mov    %rsi,%rcx
  test   %edx,%edx
  je     L50
  movabs $0x400000800002400,%r10
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rax,1),%r9
  mov    %rdi,%rax
  mov    $0x1,%edi
  sub    %r11d,%edi
  jmp    L17
  nopl   (%rax)
L66:
  mov    %dl,(%rax)
  lea    (%rdi,%rax,1),%esi
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L33
L17:
  mov    %rcx,%r8
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  mov    %rax,%rsi
  test   $0xdf,%dl
  je     L15
  cmp    $0x3a,%dl
  ja     L66
  bt     %rdx,%r10
  jae    L66
L15:
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  add    %r11,%rsi
  mov    %rcx,%r8
  movb   $0x0,(%rsi)
  mov    %r8,%rax
  ret
L50:
  mov    %rdi,%rsi
  mov    %rcx,%r8
  jmp    L15
```

assistant: ```c
const char *move_string(char *dest, const char *src, unsigned cnt) {
  unsigned i = 0;
  while (i < cnt) {
    char c = *src++;
    if ((!c) || (c == ' ') || (c == 0x0d) || (c == '\n') || (c == '#') || (c == ':')) {
      src--;
      break;
    }
    dest[i++] = c;
  }
  dest[i] = '\0';
  return src;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fb_ConsoleGetX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fb_ConsoleGetXY@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int fb_ConsoleGetX(void) {
  int x;
  fb_ConsoleGetXY(&x, 0);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fb_ConsoleGetX>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <fb_ConsoleGetXY@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_ConsoleGetX(void) {
  int x;
  fb_ConsoleGetXY(&x, 0);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fb_ConsoleGetX>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fb_ConsoleGetXY@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_ConsoleGetX(void) {
  int x;
  fb_ConsoleGetXY(&x, 0);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fb_ConsoleGetX>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fb_ConsoleGetXY@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fb_ConsoleGetX(void) {
  int x;
  fb_ConsoleGetXY(&x, 0);
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<miniprintn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  cmpb   $0x0,-0x1c(%rbp)
  je     L3
  cmpq   $0x0,-0x18(%rbp)
  jns    L3
  mov    $0x2d,%edi
  call   <fputc_cons@plt>
  negq   -0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  movzbl -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <miniprintn>
L8:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  lea    0x30(%rdx),%rax
  mov    %rax,%rdi
  call   <fputc_cons@plt>
  nop
  leave
  ret
```

assistant: ```c
void miniprintn(long number, unsigned char flag) {
  unsigned long i;
  if (flag && number < 0) {
    fputc_cons('-');
    number = -number;
  }
  if ((i = (unsigned long)number / 10L) != 0)
    miniprintn(i, flag);
  fputc_cons(number % 10 + '0');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<miniprintn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %sil,%sil
  je     L49
  test   %rdi,%rdi
  js     L20
L49:
  cmp    $0x9,%rbx
  ja     L32
L13:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  call   <fputc_cons@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x2d,%edi
  call   <fputc_cons@plt>
  neg    %rbx
  jmp    L49
L32:
  movzbl %bpl,%esi
  movabs $0xcccccccccccccccd,%rdi
  mov    %rbx,%rax
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <miniprintn>
  jmp    L13
```

assistant: ```c
void miniprintn(long number, unsigned char flag) {
  unsigned long i;
  if (flag && number < 0) {
    fputc_cons('-');
    number = -number;
  }
  if ((i = (unsigned long)number / 10L) != 0)
    miniprintn(i, flag);
  fputc_cons(number % 10 + '0');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<miniprintn>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %sil,%sil
  je     L40
  test   %rdi,%rdi
  js     L46
L40:
  cmp    $0x9,%rbx
  ja     L36
L26:
  mov    %rbx,%rax
  add    $0x8,%rsp
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc_cons@plt>
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    $0x2d,%edi
  neg    %rbx
  call   <fputc_cons@plt>
  cmp    $0x9,%rbx
  jbe    L26
L36:
  movabs $0xcccccccccccccccd,%rdi
  mov    %rbx,%rax
  movzbl %bpl,%esi
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <miniprintn>
  jmp    L26
```

assistant: ```c
void miniprintn(long number, unsigned char flag) {
  unsigned long i;
  if (flag && number < 0) {
    fputc_cons('-');
    number = -number;
  }
  if ((i = (unsigned long)number / 10L) != 0)
    miniprintn(i, flag);
  fputc_cons(number % 10 + '0');
}
```
user: What is the c source code of the assembly code below:

```asm
<miniprintn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %sil,%sil
  je     L25
  test   %rdi,%rdi
  js     L20
L25:
  cmp    $0x9,%rbx
  ja     L86
L38:
  mov    %rbx,%rax
  add    $0x8,%rsp
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <fputc_cons@plt>
  xchg   %ax,%ax
L20:
  mov    $0x2d,%edi
  neg    %rbx
  call   <fputc_cons@plt>
  cmp    $0x9,%rbx
  jbe    L38
L86:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%r12
  cmp    $0x63,%rbx
  ja     L50
L22:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <fputc_cons@plt>
  jmp    L38
  nopl   (%rax)
L50:
  movabs $0x28f5c28f5c28f5c3,%rcx
  mov    %rbx,%rdx
  shr    $0x2,%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x2,%rdx
  mov    %rdx,%r13
  cmp    $0x3e7,%rbx
  ja     L16
L1:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r13,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r13
  lea    0x30(%r13),%rdi
  call   <fputc_cons@plt>
  jmp    L22
L16:
  mov    %rbx,%rdi
  movzbl %bpl,%esi
  movabs $0x20c49ba5e353f7cf,%rdx
  shr    $0x3,%rdi
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rdi
  shr    $0x4,%rdi
  call   <miniprintn>
  jmp    L1
```

assistant: ```c
void miniprintn(long number, unsigned char flag) {
  unsigned long i;
  if (flag && number < 0) {
    fputc_cons('-');
    number = -number;
  }
  if ((i = (unsigned long)number / 10L) != 0)
    miniprintn(i, flag);
  fputc_cons(number % 10 + '0');
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test_func_args@plt>
  mov    $0x0,%eax
  call   <test_binops@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_func_args(1, 2);
  test_binops();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test_func_args@plt>
  mov    $0x0,%eax
  call   <test_binops@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_func_args(1, 2);
  test_binops();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test_func_args@plt>
  xor    %eax,%eax
  call   <test_binops@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_func_args(1, 2);
  test_binops();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test_func_args@plt>
  xor    %eax,%eax
  call   <test_binops@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_func_args(1, 2);
  test_binops();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,D116(%rip)
  mov    D116(%rip),%rax
  test   %rax,%rax
  jne    L46
  mov    $0x0,%eax
  jmp    L14
L46:
  mov    D116(%rip),%rbx
  mov    D116(%rip),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,D99(%rip)
  mov    D99(%rip),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L56
  movq   $0x0,D99(%rip)
  mov    D99(%rip),%rax
  jmp    L14
L56:
  mov    D99(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    D99(%rip),%rax
  movb   $0x0,(%rax)
  mov    D99(%rip),%rax
  add    $0x1,%rax
  jmp    L13
L22:
  mov    $0x0,%eax
L13:
  mov    %rax,D99(%rip)
  mov    -0x18(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strtok(char *s, const char *d) {
  static char *p;
  if (!(p = (s) ? s : 0))
    return 0;
  s = p + strspn(p, d);
  p = s + strcspn(s, d);
  if (p == s)
    return p = 0;
  p = *p ? *p = 0, p + 1 : 0;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strtok>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L14
  mov    %rsi,%rbp
  call   <strspn@plt>
  add    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  add    %rbx,%rax
  cmp    %rbx,%rax
  je     L12
  cmpb   $0x0,(%rax)
  je     L14
  movb   $0x0,(%rax)
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0x0,%ebx
  jmp    L14
```

assistant: ```c
char *strtok(char *s, const char *d) {
  static char *p;
  if (!(p = (s) ? s : 0))
    return 0;
  s = p + strspn(p, d);
  p = s + strcspn(s, d);
  if (p == s)
    return p = 0;
  p = *p ? *p = 0, p + 1 : 0;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L24
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strspn@plt>
  mov    %rbp,%rsi
  add    %rax,%r12
  mov    %r12,%rdi
  call   <strcspn@plt>
  add    %r12,%rax
  cmp    %r12,%rax
  je     L24
  cmpb   $0x0,(%rax)
  je     L21
  movb   $0x0,(%rax)
L21:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L24:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *s, const char *d) {
  static char *p;
  if (!(p = (s) ? s : 0))
    return 0;
  s = p + strspn(p, d);
  p = s + strcspn(s, d);
  if (p == s)
    return p = 0;
  p = *p ? *p = 0, p + 1 : 0;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strspn@plt>
  mov    %rbp,%rsi
  add    %rax,%r12
  mov    %r12,%rdi
  call   <strcspn@plt>
  add    %r12,%rax
  cmp    %r12,%rax
  je     L12
  cmpb   $0x0,(%rax)
  je     L18
  movb   $0x0,(%rax)
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strtok(char *s, const char *d) {
  static char *p;
  if (!(p = (s) ? s : 0))
    return 0;
  s = p + strspn(p, d);
  p = s + strcspn(s, d);
  if (p == s)
    return p = 0;
  p = *p ? *p = 0, p + 1 : 0;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FilterFoldedBinsBlob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebx
  movss  %xmm0,-0x44(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L3:
  cmp    %rdx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L3
L36:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L56
  orq    $0x0,-0x8(%rsp,%rax,1)
L56:
  mov    %rsp,%r12
  cmpl   $0x0,-0x48(%rbp)
  jle    L4
  lea    0x0(,%rbx,4),%eax
  mov    %eax,-0x4c(%rbp)
  lea    (%rbx,%rbx,1),%r13d
  mov    $0x0,%r14d
L62:
  mov    -0x4c(%rbp),%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L57
  lea    0x1(%rbx),%ecx
  mov    %r15,%rsi
  pxor   %xmm0,%xmm0
  cvtss2sd -0x44(%rbp),%xmm0
  movsd  D7(%rip),%xmm2
  subsd  %xmm0,%xmm2
L69:
  lea    -0x2(%rcx),%eax
  cltd
  idiv   %ebx
  movslq %edx,%rdi
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  movss  (%r12,%rdi,4),%xmm0
  addss  (%r12,%rdx,4),%xmm0
  mulss  -0x44(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D6(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rsi),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsi)
  mov    %ecx,%eax
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    %r13d,%eax
  jne    L69
L57:
  add    $0x1,%r14d
  cmp    %r14d,-0x48(%rbp)
  jne    L62
L4:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: f64
name: read_data
arguments: data_label: D6
type: f64

tool: D7: 1

tool: D6: 0.5

assistant: ```c
void FilterFoldedBinsBlob(float *folded, int bins, float strength, int iter) {
  float tmp[bins];
  int i;
  int j;
  for (j = 0; j < iter; j++) {
    memcpy(tmp, folded, sizeof(tmp));
    for (i = 0; i < bins; i++) {
      float right = tmp[(i + bins + 1) % bins];
      float left = tmp[(i + bins - 1) % bins];
      folded[i] = folded[i] * (1. - strength) + (left + right) * strength * 0.5;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FilterFoldedBinsBlob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,-0x48(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L27
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L27:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L32
L80:
  lea    0x0(,%r13,4),%eax
  mov    %rsp,%rbx
  lea    0x0(%r13,%r13,1),%r14d
  xor    %r15d,%r15d
  mov    %eax,-0x4c(%rbp)
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  jle    L81
  nopl   0x0(%rax,%rax,1)
L21:
  mov    -0x4c(%rbp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  movss  %xmm0,-0x44(%rbp)
  call   <memcpy@plt>
  test   %r13d,%r13d
  movss  -0x44(%rbp),%xmm0
  movsd  D7(%rip),%xmm4
  jle    L68
  movsd  D4(%rip),%xmm3
  pxor   %xmm1,%xmm1
  lea    0x1(%r13),%ecx
  mov    %r12,%rsi
  cvtss2sd %xmm0,%xmm1
  subsd  %xmm1,%xmm3
L86:
  lea    -0x2(%rcx),%eax
  pxor   %xmm2,%xmm2
  add    $0x4,%rsi
  cltd
  cvtss2sd -0x4(%rsi),%xmm2
  idiv   %r13d
  mulsd  %xmm3,%xmm2
  mov    %ecx,%eax
  movslq %edx,%r9
  cltd
  idiv   %r13d
  movss  (%rbx,%r9,4),%xmm1
  mov    %ecx,%eax
  add    $0x1,%ecx
  movslq %edx,%rdx
  addss  (%rbx,%rdx,4),%xmm1
  mulss  %xmm0,%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,-0x4(%rsi)
  cmp    %r14d,%eax
  jne    L86
L68:
  add    $0x1,%r15d
  cmp    %r15d,-0x48(%rbp)
  jne    L21
L81:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L32:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L80
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: f64
name: retrieve_data
arguments: label: D4
datatype: f64

tool: D7: 0.5

tool: D4: 1

assistant: ```c
void FilterFoldedBinsBlob(float *folded, int bins, float strength, int iter) {
  float tmp[bins];
  int i;
  int j;
  for (j = 0; j < iter; j++) {
    memcpy(tmp, folded, sizeof(tmp));
    for (i = 0; i < bins; i++) {
      float right = tmp[(i + bins + 1) % bins];
      float left = tmp[(i + bins - 1) % bins];
      folded[i] = folded[i] * (1. - strength) + (left + right) * strength * 0.5;
    }
  }
}
```