ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<midi_note_off>:
  endbr64
  push   %r12
  mov    %edx,%r9d
  mov    %rcx,%r12
  mov    %edi,%r10d
  mov    %edx,%ecx
  mov    %edx,%edi
  mov    %esi,%r11d
  mov    %edx,%esi
  sar    $0x15,%edi
  sar    $0xe,%esi
  push   %rbx
  and    $0x7f,%edx
  sar    $0x7,%ecx
  sar    $0x1c,%r9d
  mov    (%r12),%rax
  and    $0x7f,%edi
  and    $0x7f,%esi
  and    $0x7f,%ecx
  and    $0x7f,%r9d
  je     L5
  movslq (%r8),%rbx
  sub    $0xffffff80,%r9d
  lea    0x1(%rbx),%r12d
  mov    %r12d,(%r8)
  mov    %r9d,(%rax,%rbx,4)
L5:
  test   %edi,%edi
  je     L11
  movslq (%r8),%r9
  sub    $0xffffff80,%edi
  lea    0x1(%r9),%ebx
  mov    %ebx,(%r8)
  mov    %edi,(%rax,%r9,4)
L11:
  test   %esi,%esi
  je     L12
  movslq (%r8),%rdi
  sub    $0xffffff80,%esi
  lea    0x1(%rdi),%r9d
  mov    %r9d,(%r8)
  mov    %esi,(%rax,%rdi,4)
L12:
  test   %ecx,%ecx
  je     L37
  movslq (%r8),%rsi
  sub    $0xffffff80,%ecx
  lea    0x1(%rsi),%edi
  mov    %edi,(%r8)
  mov    %ecx,(%rax,%rsi,4)
L37:
  movslq (%r8),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%r8)
  mov    %edx,(%rax,%rcx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  movl   $0x80,(%rax,%rdx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  mov    %r10d,(%rax,%rdx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  mov    %r11d,(%rax,%rdx,4)
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
void midi_note_off(uint8_t curValue0, uint8_t curValue1, uint32_t timediff, uint8_t **buf, int *curBufferPosition) {
  uint32_t timediff4 = (timediff >> 28) & 0x7F;
  uint32_t timediff3 = (timediff >> 21) & 0x7F;
  uint32_t timediff2 = (timediff >> 14) & 0x7F;
  uint32_t timediff1 = (timediff >> 7) & 0x7F;
  uint32_t timediff0 = (timediff >> 0) & 0x7F;
  if (timediff4 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff4;
  if (timediff3 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff3;
  if (timediff2 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff2;
  if (timediff1 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff1;
  (*buf)[(*curBufferPosition)++] = timediff0;
  (*buf)[(*curBufferPosition)++] = 128;
  (*buf)[(*curBufferPosition)++] = curValue0;
  (*buf)[(*curBufferPosition)++] = curValue1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<midi_note_off>:
  endbr64
  push   %r12
  mov    %edx,%r9d
  mov    %rcx,%r12
  mov    %edi,%r10d
  mov    %edx,%ecx
  mov    %edx,%edi
  mov    %esi,%r11d
  mov    %edx,%esi
  sar    $0x15,%edi
  sar    $0xe,%esi
  push   %rbx
  and    $0x7f,%edx
  sar    $0x7,%ecx
  sar    $0x1c,%r9d
  mov    (%r12),%rax
  and    $0x7f,%edi
  and    $0x7f,%esi
  and    $0x7f,%ecx
  and    $0x7f,%r9d
  je     L18
  movslq (%r8),%rbx
  sub    $0xffffff80,%r9d
  lea    0x1(%rbx),%r12d
  mov    %r12d,(%r8)
  mov    %r9d,(%rax,%rbx,4)
L18:
  test   %edi,%edi
  je     L4
  movslq (%r8),%r9
  sub    $0xffffff80,%edi
  lea    0x1(%r9),%ebx
  mov    %ebx,(%r8)
  mov    %edi,(%rax,%r9,4)
L4:
  test   %esi,%esi
  je     L13
  movslq (%r8),%rdi
  sub    $0xffffff80,%esi
  lea    0x1(%rdi),%r9d
  mov    %r9d,(%r8)
  mov    %esi,(%rax,%rdi,4)
L13:
  test   %ecx,%ecx
  je     L36
  movslq (%r8),%rsi
  sub    $0xffffff80,%ecx
  lea    0x1(%rsi),%edi
  mov    %edi,(%r8)
  mov    %ecx,(%rax,%rsi,4)
L36:
  movslq (%r8),%rcx
  lea    0x1(%rcx),%esi
  mov    %esi,(%r8)
  mov    %edx,(%rax,%rcx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  movl   $0x80,(%rax,%rdx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  mov    %r10d,(%rax,%rdx,4)
  movslq (%r8),%rdx
  lea    0x1(%rdx),%ecx
  mov    %ecx,(%r8)
  mov    %r11d,(%rax,%rdx,4)
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
void midi_note_off(uint8_t curValue0, uint8_t curValue1, uint32_t timediff, uint8_t **buf, int *curBufferPosition) {
  uint32_t timediff4 = (timediff >> 28) & 0x7F;
  uint32_t timediff3 = (timediff >> 21) & 0x7F;
  uint32_t timediff2 = (timediff >> 14) & 0x7F;
  uint32_t timediff1 = (timediff >> 7) & 0x7F;
  uint32_t timediff0 = (timediff >> 0) & 0x7F;
  if (timediff4 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff4;
  if (timediff3 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff3;
  if (timediff2 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff2;
  if (timediff1 > 0)
    (*buf)[(*curBufferPosition)++] = 128 + timediff1;
  (*buf)[(*curBufferPosition)++] = timediff0;
  (*buf)[(*curBufferPosition)++] = 128;
  (*buf)[(*curBufferPosition)++] = curValue0;
  (*buf)[(*curBufferPosition)++] = curValue1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<try_factor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <lg2@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x3,%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x4,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <invmod2pow_ul@plt>
  neg    %eax
  mov    %eax,%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <invpowmod_REDClr@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L9
  mov    -0x20(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L9:
  mov    -0x20(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int try_factor(uint64_t K, unsigned int N, int sign, unsigned int p) {
  unsigned int kcalc;
  int bbits;
  unsigned int r0;
  bbits = lg2(N);
  r0 = ((unsigned int)1) << (16 - (N >> (bbits - 3)));
  bbits = bbits - 4;
  kcalc = invpowmod_REDClr(N, p, -invmod2pow_ul(p), bbits, r0);
  if (sign > 0)
    kcalc = p - kcalc;
  return (kcalc == (unsigned int)(K % (uint64_t)p));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<try_factor>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%r14d
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %esi,%edi
  call   <lg2@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <invmod2pow_ul@plt>
  lea    -0x3(%rbp),%ecx
  mov    %r14d,%edx
  shr    %cl,%edx
  mov    $0x10,%ecx
  sub    %edx,%ecx
  sub    $0x4,%ebp
  neg    %eax
  mov    %eax,%edx
  mov    $0x1,%r8d
  shl    %cl,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <invpowmod_REDClr@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  test   %r13d,%r13d
  cmovg  %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  cmp    %ecx,%edx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int try_factor(uint64_t K, unsigned int N, int sign, unsigned int p) {
  unsigned int kcalc;
  int bbits;
  unsigned int r0;
  bbits = lg2(N);
  r0 = ((unsigned int)1) << (16 - (N >> (bbits - 3)));
  bbits = bbits - 4;
  kcalc = invpowmod_REDClr(N, p, -invmod2pow_ul(p), bbits, r0);
  if (sign > 0)
    kcalc = p - kcalc;
  return (kcalc == (unsigned int)(K % (uint64_t)p));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<try_factor>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <lg2@plt>
  mov    %ebx,%edi
  mov    %eax,%ebp
  call   <invmod2pow_ul@plt>
  lea    -0x3(%rbp),%ecx
  mov    %r13d,%edx
  lea    -0x4(%rbp),%r9d
  shr    %cl,%edx
  mov    $0x10,%ecx
  neg    %eax
  mov    $0x1,%r8d
  sub    %edx,%ecx
  mov    %ebx,%esi
  mov    %eax,%edx
  mov    %r13d,%edi
  shl    %cl,%r8d
  mov    %r9d,%ecx
  call   <invpowmod_REDClr@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  test   %r14d,%r14d
  cmovg  %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  cmp    %ecx,%edx
  sete   %al
  ret
```

assistant: ```c
int try_factor(uint64_t K, unsigned int N, int sign, unsigned int p) {
  unsigned int kcalc;
  int bbits;
  unsigned int r0;
  bbits = lg2(N);
  r0 = ((unsigned int)1) << (16 - (N >> (bbits - 3)));
  bbits = bbits - 4;
  kcalc = invpowmod_REDClr(N, p, -invmod2pow_ul(p), bbits, r0);
  if (sign > 0)
    kcalc = p - kcalc;
  return (kcalc == (unsigned int)(K % (uint64_t)p));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<try_factor>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  call   <lg2@plt>
  mov    %ebx,%edi
  mov    %eax,%ebp
  call   <invmod2pow_ul@plt>
  lea    -0x3(%rbp),%ecx
  mov    %r13d,%edx
  lea    -0x4(%rbp),%r9d
  shr    %cl,%edx
  mov    $0x10,%ecx
  neg    %eax
  mov    $0x1,%r8d
  sub    %edx,%ecx
  mov    %ebx,%esi
  mov    %eax,%edx
  mov    %r13d,%edi
  shl    %cl,%r8d
  mov    %r9d,%ecx
  call   <invpowmod_REDClr@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  test   %r14d,%r14d
  cmovg  %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  cmp    %ecx,%edx
  sete   %al
  ret
```

assistant: ```c
int try_factor(uint64_t K, unsigned int N, int sign, unsigned int p) {
  unsigned int kcalc;
  int bbits;
  unsigned int r0;
  bbits = lg2(N);
  r0 = ((unsigned int)1) << (16 - (N >> (bbits - 3)));
  bbits = bbits - 4;
  kcalc = invpowmod_REDClr(N, p, -invmod2pow_ul(p), bbits, r0);
  if (sign > 0)
    kcalc = p - kcalc;
  return (kcalc == (unsigned int)(K % (uint64_t)p));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<radix_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L14
  cmpb   $0x39,-0x4(%rbp)
  jg     L14
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L3
L14:
  cmpb   $0x60,-0x4(%rbp)
  jle    L62
  cmpb   $0x7a,-0x4(%rbp)
  jg     L62
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L3
L62:
  cmpb   $0x40,-0x4(%rbp)
  jle    L66
  cmpb   $0x5a,-0x4(%rbp)
  jg     L66
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L3
L66:
  mov    $0x24,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
unsigned radix_val(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'z')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'Z')
    return 10 + (x - 'A');
  return 36;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<radix_val>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L16
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L6
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x1a,%dl
  mov    $0x24,%edx
  cmovae %edx,%eax
  ret
L16:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L6:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
unsigned radix_val(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'z')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'Z')
    return 10 + (x - 'A');
  return 36;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<radix_val>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L11
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L5
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x1a,%dl
  movsbl %al,%eax
  mov    $0x24,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl %al,%eax
  ret
```

assistant: ```c
unsigned radix_val(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'z')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'Z')
    return 10 + (x - 'A');
  return 36;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<radix_val>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L19
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L6
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x1a,%dl
  movsbl %al,%eax
  mov    $0x24,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  movsbl %al,%eax
  ret
```

assistant: ```c
unsigned radix_val(char x) {
  if (x >= '0' && x <= '9')
    return x - '0';
  if (x >= 'a' && x <= 'z')
    return 10 + (x - 'a');
  if (x >= 'A' && x <= 'Z')
    return 10 + (x - 'A');
  return 36;
}
```
user: What is the c source code of the assembly code below:

```asm
<riotboot_flashwrite_verify_sha256>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
riotboot_flashwrite_verify_sha256(digest, img_size, target_slot) {
  (void)digest;
  (void)img_size;
  (void)target_slot;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<riotboot_flashwrite_verify_sha256>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
riotboot_flashwrite_verify_sha256(digest, img_size, target_slot) {
  (void)digest;
  (void)img_size;
  (void)target_slot;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<riotboot_flashwrite_verify_sha256>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
riotboot_flashwrite_verify_sha256(digest, img_size, target_slot) {
  (void)digest;
  (void)img_size;
  (void)target_slot;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<append_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void append_char(char *s, char c) {
  char *a = strchr(s, 0);
  *a = c;
  a[1] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  add    %rax,%rbx
  mov    %bpl,(%rbx)
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void append_char(char *s, char c) {
  char *a = strchr(s, 0);
  *a = c;
  a[1] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<append_char>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    %rax,%rbx
  mov    %bpl,(%rbx)
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void append_char(char *s, char c) {
  char *a = strchr(s, 0);
  *a = c;
  a[1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<append_char>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    %rax,%rbx
  mov    %bpl,(%rbx)
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void append_char(char *s, char c) {
  char *a = strchr(s, 0);
  *a = c;
  a[1] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <doMalloc@plt>
  mov    $0x0,%eax
  call   <doIoctl@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  doMalloc();
  doIoctl();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <doMalloc@plt>
  mov    $0x0,%eax
  call   <doIoctl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doMalloc();
  doIoctl();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <doMalloc@plt>
  xor    %eax,%eax
  call   <doIoctl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doMalloc();
  doIoctl();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <doMalloc@plt>
  xor    %eax,%eax
  call   <doIoctl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doMalloc();
  doIoctl();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shell_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L32:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L52
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x1,-0x8(%rbp)
L52:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L5
  cmpl   $0x0,-0x8(%rbp)
  jne    L32
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
L21:
  cmpl   $0x0,-0x10(%rbp)
  jg     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shell_sort(int a[], int n) {
  int gap = n / 2;
  int temp, i;
  int flag = 0;
  while (gap >= 1) {
    do {
      flag = 0;
      for (i = 0; i < n - gap; ++i) {
        if (a[i] > a[i + gap]) {
          temp = a[i];
          a[i] = a[i + gap];
          a[i + gap] = temp;
          flag = 1;
        }
      }
    } while (flag != 0);
    gap = gap / 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<shell_sort>:
  endbr64
  cmp    $0x1,%esi
  jg     L15
  ret
L15:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r8d
  mov    %esi,%r10d
  shr    $0x1f,%r10d
  add    %esi,%r10d
  sar    %r10d
  lea    0x4(%rdi),%r12
  mov    $0x0,%ebp
  mov    $0x1,%r11d
L7:
  mov    %r8d,%r13d
  sub    %r10d,%r13d
  lea    -0x1(%r13),%eax
  lea    (%r12,%rax,4),%rdi
  movslq %r10d,%rsi
L83:
  test   %r13d,%r13d
  jle    L50
  mov    %rbx,%rax
  mov    %ebp,%r9d
  jmp    L6
L45:
  mov    %eax,%r10d
  jmp    L7
L85:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L25
L6:
  mov    (%rax),%edx
  mov    (%rax,%rsi,4),%ecx
  cmp    %ecx,%edx
  jle    L85
  mov    %ecx,(%rax)
  mov    %edx,(%rax,%rsi,4)
  mov    %r11d,%r9d
  jmp    L85
L25:
  test   %r9d,%r9d
  jne    L83
L50:
  mov    %r10d,%eax
  shr    $0x1f,%eax
  add    %r10d,%eax
  sar    %eax
  cmp    $0x1,%r10d
  jg     L45
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void shell_sort(int a[], int n) {
  int gap = n / 2;
  int temp, i;
  int flag = 0;
  while (gap >= 1) {
    do {
      flag = 0;
      for (i = 0; i < n - gap; ++i) {
        if (a[i] > a[i + gap]) {
          temp = a[i];
          a[i] = a[i + gap];
          a[i + gap] = temp;
          flag = 1;
        }
      }
    } while (flag != 0);
    gap = gap / 2;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<shell_sort>:
  endbr64
  mov    %esi,%r11d
  shr    $0x1f,%r11d
  add    %esi,%r11d
  sar    %r11d
  cmp    $0x1,%esi
  jle    L34
  push   %rbp
  mov    %rdi,%r10
  lea    0x4(%rdi),%rbp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax)
L29:
  mov    %ebx,%r9d
  movslq %r11d,%rsi
  sub    %r11d,%r9d
  lea    -0x1(%r9),%eax
  lea    0x0(%rbp,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L21:
  test   %r9d,%r9d
  jle    L46
  mov    %r10,%rax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L31:
  mov    (%rax),%edx
  mov    (%rax,%rsi,4),%ecx
  cmp    %ecx,%edx
  jle    L13
  mov    %ecx,(%rax)
  mov    $0x1,%r8d
  mov    %edx,(%rax,%rsi,4)
L13:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L31
  test   %r8d,%r8d
  jne    L21
  nopw   0x0(%rax,%rax,1)
L46:
  sar    %r11d
  jne    L29
  pop    %rbx
  pop    %rbp
  ret
L34:
  ret
```

assistant: ```c
void shell_sort(int a[], int n) {
  int gap = n / 2;
  int temp, i;
  int flag = 0;
  while (gap >= 1) {
    do {
      flag = 0;
      for (i = 0; i < n - gap; ++i) {
        if (a[i] > a[i + gap]) {
          temp = a[i];
          a[i] = a[i + gap];
          a[i + gap] = temp;
          flag = 1;
        }
      }
    } while (flag != 0);
    gap = gap / 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shell_sort>:
  endbr64
  mov    %esi,%r11d
  shr    $0x1f,%r11d
  add    %esi,%r11d
  sar    %r11d
  cmp    $0x1,%esi
  jle    L44
  push   %rbp
  mov    %rdi,%r10
  lea    0x4(%rdi),%rbp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax)
L42:
  mov    %ebx,%r9d
  movslq %r11d,%rsi
  sub    %r11d,%r9d
  lea    -0x1(%r9),%eax
  lea    0x0(%rbp,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L56:
  test   %r9d,%r9d
  jle    L35
  mov    %r10,%rax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rax),%edx
  mov    (%rax,%rsi,4),%ecx
  cmp    %ecx,%edx
  jle    L0
  mov    %ecx,(%rax)
  mov    $0x1,%r8d
  mov    %edx,(%rax,%rsi,4)
L0:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L1
  test   %r8d,%r8d
  jne    L56
  nopw   0x0(%rax,%rax,1)
L35:
  sar    %r11d
  jne    L42
  pop    %rbx
  pop    %rbp
  ret
L44:
  ret
```

assistant: ```c
void shell_sort(int a[], int n) {
  int gap = n / 2;
  int temp, i;
  int flag = 0;
  while (gap >= 1) {
    do {
      flag = 0;
      for (i = 0; i < n - gap; ++i) {
        if (a[i] > a[i + gap]) {
          temp = a[i];
          a[i] = a[i + gap];
          a[i + gap] = temp;
          flag = 1;
        }
      }
    } while (flag != 0);
    gap = gap / 2;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putfonts8_asc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,%eax
  mov    %r9,-0x20(%rbp)
  mov    %al,-0x18(%rbp)
  jmp    L16
L8:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x4,%eax
  movslq %eax,%rdx
  mov    D0(%rip),%rax
  lea    (%rdx,%rax,1),%r8
  movsbl -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <putfont8@plt>
  addl   $0x8,-0x10(%rbp)
  addq   $0x1,-0x20(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  leave
  ret
```

assistant: ```c
void putfonts8_asc(unsigned char *vram, int xsize, int x, int y, char c, char *s) {
  extern char hankaku[4096];
  for (; *s != 0x00; s++) {
    putfont8(vram, xsize, x, y, c, hankaku + *s * 16);
    x += 8;
  }
  return;
}
```