ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isEmpty>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L28
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L16
  cmp    $0x9,%al
  je     L16
  mov    $0x0,%eax
  jmp    L31
L28:
  mov    $0x1,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int isEmpty(char *string) {
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] != ' ' && string[i] != '\t') {
      return (0);
    }
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isEmpty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L10
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L11
  cmp    $0x9,%al
  je     L11
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int isEmpty(char *string) {
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] != ' ' && string[i] != '\t') {
      return (0);
    }
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isEmpty>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L23
  movzbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L17
  cmp    $0x9,%al
  je     L17
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int isEmpty(char *string) {
  for (int i = 0; i < strlen(string); i++) {
    if (string[i] != ' ' && string[i] != '\t') {
      return (0);
    }
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L13:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_strlen(char *palabra) {
  unsigned int indice;
  for (indice = 0; *(palabra + indice) != '\0'; indice++) {
  }
  indice++;
  return indice;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L27
  mov    $0x0,%eax
L9:
  add    $0x1,%eax
  mov    %eax,%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L9
L19:
  add    $0x1,%eax
  ret
L27:
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
int my_strlen(char *palabra) {
  unsigned int indice;
  for (indice = 0; *(palabra + indice) != '\0'; indice++) {
  }
  indice++;
  return indice;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x1(%rdx),%ecx
  mov    %edx,%eax
  cmpb   $0x0,(%rdi,%rcx,1)
  mov    %rcx,%rdx
  jne    L11
  add    $0x2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int my_strlen(char *palabra) {
  unsigned int indice;
  for (indice = 0; *(palabra + indice) != '\0'; indice++) {
  }
  indice++;
  return indice;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L10:
  lea    0x1(%rdx),%ecx
  mov    %edx,%eax
  cmpb   $0x0,(%rdi,%rcx,1)
  mov    %rcx,%rdx
  jne    L10
  add    $0x2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int my_strlen(char *palabra) {
  unsigned int indice;
  for (indice = 0; *(palabra + indice) != '\0'; indice++) {
  }
  indice++;
  return indice;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<freeMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeMatrix(int **matrix, int sizeofmatrix) {
  int i;
  for (i = 0; i < sizeofmatrix; ++i) {
    free(matrix[i]);
  }
  free(matrix);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<freeMatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L7:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L7
L4:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void freeMatrix(int **matrix, int sizeofmatrix) {
  int i;
  for (i = 0; i < sizeofmatrix; ++i) {
    free(matrix[i]);
  }
  free(matrix);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<freeMatrix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L15
L11:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeMatrix(int **matrix, int sizeofmatrix) {
  int i;
  for (i = 0; i < sizeofmatrix; ++i) {
    free(matrix[i]);
  }
  free(matrix);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<freeMatrix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L7
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeMatrix(int **matrix, int sizeofmatrix) {
  int i;
  for (i = 0; i < sizeofmatrix; ++i) {
    free(matrix[i]);
  }
  free(matrix);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L18
L10:
  mov    -0x40(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x40(%rbp)
L18:
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jne    L10
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x38(%rbp)
  jmp    L9
L32:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x38(%rbp)
L9:
  cmpl   $0x0,-0x38(%rbp)
  jns    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string

tool: D15: 
 Entre com inteiro:

tool: D26: %d

assistant: ```c
int main() {
  int numero;
  int bin[10];
  int i = 0, resto, j;
  printf("\n Entre com inteiro:");
  scanf("%d", &numero);
  while (numero != 0) {
    resto = numero % 2;
    bin[i] = resto;
    i++;
    numero = numero / 2;
  }
  for (j = i - 1; j >= 0; j--) {
    printf("%d", bin[j]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L35
  mov    $0x0,%ecx
L14:
  mov    %ecx,%edi
  mov    %edx,%esi
  shr    $0x1f,%esi
  lea    (%rdx,%rsi,1),%eax
  and    $0x1,%eax
  sub    %esi,%eax
  mov    %eax,0x10(%rsp,%rcx,4)
  mov    %esi,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    %rcx,%rsi
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L14
  movl   $0x0,0xc(%rsp)
  test   %edi,%edi
  js     L35
  movslq %edi,%rdi
  shl    $0x2,%rdi
  lea    0x10(%rsp,%rdi,1),%rbx
  lea    0xc(%rsp,%rdi,1),%rbp
  mov    %esi,%esi
  shl    $0x2,%rsi
  sub    %rsi,%rbp
  lea    D4(%rip),%r12
L49:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L49
L35:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D8: 
 Entre com inteiro:

tool: D4: %d

assistant: ```c
int main() {
  int numero;
  int bin[10];
  int i = 0, resto, j;
  printf("\n Entre com inteiro:");
  scanf("%d", &numero);
  while (numero != 0) {
    resto = numero % 2;
    bin[i] = resto;
    i++;
    numero = numero / 2;
  }
  for (j = i - 1; j >= 0; j--) {
    printf("%d", bin[j]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  xor    %edx,%edx
  test   %eax,%eax
  je     L6
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %eax,%ecx
  mov    %edx,%ebp
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%esi
  and    $0x1,%esi
  sub    %ecx,%esi
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  mov    %esi,(%r12,%rdx,4)
  add    $0x1,%rdx
  add    %ecx,%eax
  sar    %eax
  jne    L17
  sub    $0x1,%ebp
  movl   $0x0,0xc(%rsp)
  movslq %ebp,%rbp
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%r12,%rbp,4),%esi
  sub    $0x1,%rbp
L44:
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0xffffffff,%ebp
  jne    L10
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D15
datatype: string

tool: D9: 
 Entre com inteiro:

tool: D15: %d

assistant: ```c
int main() {
  int numero;
  int bin[10];
  int i = 0, resto, j;
  printf("\n Entre com inteiro:");
  scanf("%d", &numero);
  while (numero != 0) {
    resto = numero % 2;
    bin[i] = resto;
    i++;
    numero = numero / 2;
  }
  for (j = i - 1; j >= 0; j--) {
    printf("%d", bin[j]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L64
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  mov    %edx,0x10(%rsp)
  mov    %ecx,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    %eax
  je     L107
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  mov    %eax,%edx
  shr    $0x1f,%edx
  mov    %ecx,0x14(%rsp)
  add    %eax,%edx
  mov    %edx,%eax
  sar    %eax
  je     L56
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  mov    %eax,%edx
  shr    $0x1f,%edx
  mov    %ecx,0x18(%rsp)
  add    %edx,%eax
  sar    %eax
  je     L69
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  je     L146
  cltd
  idiv   %ecx
  mov    %edx,0x20(%rsp)
  test   %eax,%eax
  je     L208
  cltd
  idiv   %ecx
  mov    %edx,0x24(%rsp)
  test   %eax,%eax
  je     L25
  cltd
  idiv   %ecx
  mov    %edx,0x28(%rsp)
  test   %eax,%eax
  je     L108
  cltd
  idiv   %ecx
  mov    %edx,0x2c(%rsp)
  test   %eax,%eax
  je     L129
  cltd
  idiv   %ecx
  mov    %edx,0x30(%rsp)
  test   %eax,%eax
  je     L110
  mov    $0x2,%esi
  cltd
  idiv   %esi
  mov    %edx,0x34(%rsp)
  mov    $0x9,%edx
L134:
  mov    %eax,0xc(%rsp)
  movslq %edx,%rax
  lea    0x10(%rsp,%rax,4),%rbx
  nopl   0x0(%rax)
L153:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L153
L64:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L138
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L208:
  mov    $0x4,%edx
  jmp    L134
L107:
  xor    %edx,%edx
  jmp    L134
L56:
  mov    $0x1,%edx
  jmp    L134
L69:
  mov    $0x2,%edx
  jmp    L134
L146:
  mov    $0x3,%edx
  jmp    L134
L25:
  mov    $0x5,%edx
  jmp    L134
L108:
  mov    $0x6,%edx
  jmp    L134
L129:
  mov    $0x7,%edx
  jmp    L134
L110:
  mov    $0x8,%edx
  jmp    L134
L138:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string

tool: D14: 
 Entre com inteiro:

tool: D17: %d

assistant: ```c
int main() {
  int numero;
  int bin[10];
  int i = 0, resto, j;
  printf("\n Entre com inteiro:");
  scanf("%d", &numero);
  while (numero != 0) {
    resto = numero % 2;
    bin[i] = resto;
    i++;
    numero = numero / 2;
  }
  for (j = i - 1; j >= 0; j--) {
    printf("%d", bin[j]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clear_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void clear_line(char *line) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    *line++ = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_line>:
  endbr64
  lea    0x3e8(%rdi),%rax
L7:
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  cmp    %rdi,%rax
  jne    L7
  ret
```

assistant: ```c
void clear_line(char *line) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    *line++ = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<clear_line>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0x3d8(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x3e8(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void clear_line(char *line) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    *line++ = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_line>:
  endbr64
  movq   $0x0,(%rdi)
  mov    %rdi,%rax
  lea    0x8(%rdi),%rdi
  movq   $0x0,0x3d8(%rdi)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rax
  lea    0x3e8(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  ret
```

assistant: ```c
void clear_line(char *line) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    *line++ = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L13
  mov    $0x0,%edx
L3:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L3
L22:
  movb   $0x0,(%rax,%rdx,1)
  ret
L13:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L6
  xor    %edx,%edx
L13:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L13
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L9
  xor    %edx,%edx
L15:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L15
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CR_Deadly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <WriteInstruction@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <WriteInstruction@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <WriteInstruction@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <WriteInstruction@plt>
  mov    $0x0,%eax
  call   <CompileCondition@plt>
  mov    $0x0,%eax
  call   <ResetIf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D34
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string
name: extract_symbolic_data
arguments: label: D27
type_infered: string

tool: D34: ld b,DEADLY

tool: D15: call tded

tool: D21: cp b

tool: D27: jp nz,      

assistant: ```c
void CR_Deadly(void) {
  WriteInstruction("ld b,DEADLY");
  WriteInstruction("call tded");
  WriteInstruction("cp b");
  WriteInstruction("jp nz,      ");
  CompileCondition();
  ResetIf();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CR_Deadly>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D6(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D17(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D18(%rip),%rdi
  call   <WriteInstruction@plt>
  mov    $0x0,%eax
  call   <CompileCondition@plt>
  mov    $0x0,%eax
  call   <ResetIf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string

tool: D34: ld b,DEADLY

tool: D6: call tded

tool: D17: cp b

tool: D18: jp nz,      

assistant: ```c
void CR_Deadly(void) {
  WriteInstruction("ld b,DEADLY");
  WriteInstruction("call tded");
  WriteInstruction("cp b");
  WriteInstruction("jp nz,      ");
  CompileCondition();
  ResetIf();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CR_Deadly>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D3(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D35(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D15(%rip),%rdi
  call   <WriteInstruction@plt>
  xor    %eax,%eax
  call   <CompileCondition@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ResetIf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D35
type: string
name: disassemble_data
arguments: data_tag: D15
type: string

tool: D0: ld b,DEADLY

tool: D3: call tded

tool: D35: cp b

tool: D15: jp nz,      

assistant: ```c
void CR_Deadly(void) {
  WriteInstruction("ld b,DEADLY");
  WriteInstruction("call tded");
  WriteInstruction("cp b");
  WriteInstruction("jp nz,      ");
  CompileCondition();
  ResetIf();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CR_Deadly>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D13(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D24(%rip),%rdi
  call   <WriteInstruction@plt>
  lea    D22(%rip),%rdi
  call   <WriteInstruction@plt>
  xor    %eax,%eax
  call   <CompileCondition@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ResetIf@plt>
```

tool_calls: name: parse_data
arguments: tag: D31
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string

tool: D31: ld b,DEADLY

tool: D13: call tded

tool: D24: cp b

tool: D22: jp nz,      

assistant: ```c
void CR_Deadly(void) {
  WriteInstruction("ld b,DEADLY");
  WriteInstruction("call tded");
  WriteInstruction("cp b");
  WriteInstruction("jp nz,      ");
  CompileCondition();
  ResetIf();
}
```