ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CharToInt>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L17
  xchg   %ax,%ax
L5:
  and    $0xf,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L5
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CharToInt(char *str) {
  int res = 0;
  while (*str != '\0') {
    res *= 10;
    res += *str++ & 0x0F;
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CharToInt>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  xchg   %ax,%ax
L10:
  and    $0xf,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CharToInt(char *str) {
  int res = 0;
  while (*str != '\0') {
    res *= 10;
    res += *str++ & 0x0F;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<liw_strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L36
L88:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L36:
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L88
L12:
  cmpq   $0x0,-0x18(%rbp)
  je     L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L55
L40:
  mov    $0x0,%eax
  jmp    L65
L55:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L71
  mov    $0xffffffff,%eax
  jmp    L65
L71:
  mov    $0x1,%eax
L65:
  pop    %rbp
  ret
```

assistant: ```c
int liw_strncmp(const char *cs, const char *ct, size_t n) {
  while (n > 0 && *cs == *ct && *cs != '\0') {
    ++cs;
    ++ct;
    --n;
  }
  if (n == 0 || *cs == *ct)
    return 0;
  if (*(unsigned char *)cs < *(unsigned char *)ct)
    return -1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<liw_strncmp>:
  endbr64
  test   %rdx,%rdx
  je     L11
L22:
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L5
  test   %al,%al
  je     L5
  add    $0x1,%rdi
  add    $0x1,%rsi
  sub    $0x1,%rdx
  jne    L22
  mov    $0x0,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
L5:
  test   %rdx,%rdx
  je     L45
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0x0,%eax
  cmp    %dl,%cl
  je     L2
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
L45:
  mov    $0x0,%eax
L2:
  ret
```

assistant: ```c
int liw_strncmp(const char *cs, const char *ct, size_t n) {
  while (n > 0 && *cs == *ct && *cs != '\0') {
    ++cs;
    ++ct;
    --n;
  }
  if (n == 0 || *cs == *ct)
    return 0;
  if (*(unsigned char *)cs < *(unsigned char *)ct)
    return -1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<liw_strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L6
  jmp    L11
  nopl   (%rax)
L27:
  cmp    %r8b,%cl
  jne    L10
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L6:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L27
L10:
  xor    %eax,%eax
  cmp    %r8b,%cl
  je     L28
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  ret
L11:
  ret
```

assistant: ```c
int liw_strncmp(const char *cs, const char *ct, size_t n) {
  while (n > 0 && *cs == *ct && *cs != '\0') {
    ++cs;
    ++ct;
    --n;
  }
  if (n == 0 || *cs == *ct)
    return 0;
  if (*(unsigned char *)cs < *(unsigned char *)ct)
    return -1;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<liw_strncmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L21
  jmp    L24
  nopl   (%rax)
L33:
  cmp    %r8b,%cl
  jne    L14
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L5
L21:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  test   %cl,%cl
  jne    L33
L14:
  xor    %eax,%eax
  cmp    %r8b,%cl
  je     L35
  sbb    %eax,%eax
  or     $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
L24:
  ret
```

assistant: ```c
int liw_strncmp(const char *cs, const char *ct, size_t n) {
  while (n > 0 && *cs == *ct && *cs != '\0') {
    ++cs;
    ++ct;
    --n;
  }
  if (n == 0 || *cs == *ct)
    return 0;
  if (*(unsigned char *)cs < *(unsigned char *)ct)
    return -1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x38(%rbp)
  movl   $0xffffffff,-0x34(%rbp)
  movl   $0xffffffff,-0x30(%rbp)
  movl   $0xffffffff,-0x2c(%rbp)
  movl   $0xffffffff,-0x28(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L12
L11:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xorshift128plus@plt>
  mov    %rax,%rbx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <xorshift128plus_32@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x3c(%rbp)
L12:
  cmpl   $0x3b9ac9ff,-0x3c(%rbp)
  jle    L11
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xorshift128plus(s) == xorshift128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  movl   $0xffffffff,0x18(%rsp)
  movl   $0xffffffff,0x1c(%rsp)
  mov    $0x3b9aca00,%ebp
  lea    0x8(%rsp),%r12
L0:
  mov    %r12,%rdi
  call   <xorshift128plus@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rdi
  call   <xorshift128plus_32@plt>
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xorshift128plus(s) == xorshift128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x3b9aca00,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  movq   $0xffffffffffffffff,0x8(%rsp)
  movq   $0xffffffffffffffff,0x10(%rsp)
  movq   $0xffffffffffffffff,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r13,%rdi
  call   <xorshift128plus@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <xorshift128plus_32@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L15
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xorshift128plus(s) == xorshift128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  pcmpeqd %xmm0,%xmm0
  push   %r12
  push   %rbp
  mov    $0x3b9aca00,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D13(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rdi
  call   <xorshift128plus@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <xorshift128plus_32@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L9
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: byte[8]
name: unpack_data
arguments: data_tag: D16
data_type: string

tool: {"D13": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: D16: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xorshift128plus(s) == xorshift128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitmap_shift_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpl   $0x40,-0x18(%rbp)
  jg     L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L9
L0:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__bitmap_shift_right@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitmap_shift_right>:
  endbr64
  cmp    $0x40,%ecx
  jg     L6
  mov    (%rsi),%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  mov    %rax,(%rdi)
  ret
L6:
  sub    $0x8,%rsp
  call   <__bitmap_shift_right@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmap_shift_right>:
  endbr64
  cmp    $0x40,%ecx
  jg     L2
  mov    (%rsi),%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  mov    %rax,(%rdi)
  ret
  nopl   (%rax)
L2:
  jmp    1050 <__bitmap_shift_right@plt>
```

assistant: ```c
void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmap_shift_right>:
  endbr64
  cmp    $0x40,%ecx
  jg     L9
  mov    (%rsi),%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  mov    %rax,(%rdi)
  ret
  nopl   (%rax)
L9:
  jmp    1050 <__bitmap_shift_right@plt>
```

assistant: ```c
void bitmap_shift_right(unsigned long *dst, const unsigned long *src, int n, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src >> n;
  else
    __bitmap_shift_right(dst, src, n, nbits);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,-0xc(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string

tool: D35: This program adds two numbers.

tool: D16: 1st number? 

tool: D0: 2nd number? 

tool: D10: The total is %d.


assistant: ```c
main() {
  int n1, n2, total;
  printf("This program adds two numbers.\n");
  printf("1st number? ");
  n1 = GetInteger();
  printf("2nd number? ");
  n2 = GetInteger();
  total = n1 + n2;
  printf("The total is %d.\n", total);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  mov    %eax,%ebx
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInteger@plt>
  lea    (%rbx,%rax,1),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D31: This program adds two numbers.

tool: D17: 1st number? 

tool: D4: 2nd number? 

tool: D19: The total is %d.


assistant: ```c
main() {
  int n1, n2, total;
  printf("This program adds two numbers.\n");
  printf("1st number? ");
  n1 = GetInteger();
  printf("2nd number? ");
  n2 = GetInteger();
  total = n1 + n2;
  printf("The total is %d.\n", total);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D0(%rip),%rdi
  lea    (%rbx,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D33
data_type: string
name: read_data
arguments: tag: D0
data_type: string

tool: D1: This program adds two numbers.

tool: D26: 1st number? 

tool: D33: 2nd number? 

tool: D0: The total is %d.


assistant: ```c
main() {
  int n1, n2, total;
  printf("This program adds two numbers.\n");
  printf("1st number? ");
  n1 = GetInteger();
  printf("2nd number? ");
  n2 = GetInteger();
  total = n1 + n2;
  printf("The total is %d.\n", total);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D39(%rip),%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInteger@plt>
  lea    D13(%rip),%rdi
  lea    (%rbx,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D39
type: string
name: read_data
arguments: label: D13
type: string

tool: D15: This program adds two numbers.

tool: D26: 1st number? 

tool: D39: 2nd number? 

tool: D13: The total is %d.


assistant: ```c
main() {
  int n1, n2, total;
  printf("This program adds two numbers.\n");
  printf("1st number? ");
  n1 = GetInteger();
  printf("2nd number? ");
  n2 = GetInteger();
  total = n1 + n2;
  printf("The total is %d.\n", total);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocateArrayF2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L6:
  mov    -0x18(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float **allocateArrayF2(int dim1, int dim2) {
  int i;
  float **array = (float **)calloc(dim1, sizeof(float **));
  for (i = 0; i < dim1; i++)
    array[i] = (float *)calloc(dim2, sizeof(float *));
  return (float **)array;
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocateArrayF2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L5
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L13:
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
L5:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **allocateArrayF2(int dim1, int dim2) {
  int i;
  float **array = (float **)calloc(dim1, sizeof(float **));
  for (i = 0; i < dim1; i++)
    array[i] = (float *)calloc(dim2, sizeof(float *));
  return (float **)array;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allocateArrayF2>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L8
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L18:
  mov    $0x8,%esi
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L18
L8:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **allocateArrayF2(int dim1, int dim2) {
  int i;
  float **array = (float **)calloc(dim1, sizeof(float **));
  for (i = 0; i < dim1; i++)
    array[i] = (float *)calloc(dim2, sizeof(float *));
  return (float **)array;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<allocateArrayF2>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L16
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L13:
  mov    $0x8,%esi
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L13
L16:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **allocateArrayF2(int dim1, int dim2) {
  int i;
  float **array = (float **)calloc(dim1, sizeof(float **));
  for (i = 0; i < dim1; i++)
    array[i] = (float *)calloc(dim2, sizeof(float *));
  return (float **)array;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nibble_sort_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x11111111,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xf,%eax
  imul   -0x8(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L4
  mov    -0x24(%rbp),%eax
  jmp    L5
L4:
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L52
L39:
  mov    -0x24(%rbp),%eax
  and    $0xf,%eax
  shl    $0x2,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  sarl   $0x4,-0x24(%rbp)
  addl   $0x1,-0x18(%rbp)
L52:
  cmpl   $0xf,-0x18(%rbp)
  jle    L39
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L51:
  mov    -0x1c(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  sarl   $0x4,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  and    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shll   %cl,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0xf,-0xc(%rbp)
  jle    L51
  mov    -0x10(%rbp),%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
uint64_t nibble_sort_word(uint64_t arg) {
  const uint64_t ones = 0x1111111111111111ULL;
  if (arg == (arg & 0xf) * ones) {
    return arg;
  }
  uint64_t count = 0;
  for (int i = 0; i < 16; i++) {
    count += 1ULL << (4 * (arg & 0xf));
    arg >>= 4;
  }
  uint64_t mask = ~0ULL;
  uint64_t result = 0;
  for (int i = 0; i < 16; i++) {
    int n = count & 0xf;
    count >>= 4;
    result = (result & ~mask) | ((ones & mask) * i);
    mask <<= 4 * n;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nibble_sort_word>:
  endbr64
  mov    %edi,%edx
  and    $0xf,%edx
  imul   $0x11111111,%edx,%edx
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L0
  mov    $0x10,%eax
  mov    $0x0,%edx
  mov    $0x1,%esi
L12:
  mov    %edi,%ecx
  and    $0xf,%ecx
  shl    $0x2,%ecx
  mov    %rsi,%r9
  shl    %cl,%r9
  add    %r9d,%edx
  sar    $0x4,%edi
  sub    $0x1,%eax
  jne    L12
  mov    $0x0,%edi
  mov    $0x0,%eax
  mov    $0xffffffff,%esi
L18:
  mov    %edx,%ecx
  and    $0xf,%ecx
  sar    $0x4,%edx
  mov    %esi,%r8d
  not    %r8d
  and    %r8d,%eax
  mov    %esi,%r8d
  and    $0x11111111,%r8d
  imul   %edi,%r8d
  or     %r8d,%eax
  shl    $0x2,%ecx
  shl    %cl,%esi
  add    $0x1,%edi
  cmp    $0x10,%edi
  jne    L18
L0:
  ret
```

assistant: ```c
uint64_t nibble_sort_word(uint64_t arg) {
  const uint64_t ones = 0x1111111111111111ULL;
  if (arg == (arg & 0xf) * ones) {
    return arg;
  }
  uint64_t count = 0;
  for (int i = 0; i < 16; i++) {
    count += 1ULL << (4 * (arg & 0xf));
    arg >>= 4;
  }
  uint64_t mask = ~0ULL;
  uint64_t result = 0;
  for (int i = 0; i < 16; i++) {
    int n = count & 0xf;
    count >>= 4;
    result = (result & ~mask) | ((ones & mask) * i);
    mask <<= 4 * n;
  }
  return result;
}
```