ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_time>:
  endbr64
  movabs $0x91a2b3c4d5e6f81,%rcx
  mov    %rdi,%rdx
  push   %r12
  lea    D15(%rip),%r12
  shr    $0x4,%rdx
  push   %rbp
  mov    %rdx,%rax
  push   %rbx
  mov    %rdi,%rbx
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <print_format@plt>
  imul   $0xe10,%rbp,%rbp
  mov    %r12,%rdi
  call   <printf@plt>
  movabs $0x8888888888888889,%rdx
  sub    %rbp,%rbx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x5,%rdx
  mov    %rdx,%rdi
  mov    %rdx,%rbp
  call   <print_format@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rax
  shl    $0x4,%rax
  sub    %rbp,%rax
  shl    $0x2,%rax
  sub    %rax,%rbx
  mov    %rbx,%rdi
  call   <print_format@plt>
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string

tool: D15: :

tool: D13: 


assistant: ```c
void print_time(unsigned long sec) {
  const unsigned int SECONDS_IN_AN_HOUR = 3600;
  const unsigned int SECONDS_IN_A_MINUTE = 60;
  print_format((unsigned long)(sec / SECONDS_IN_AN_HOUR));
  printf(":");
  print_format((unsigned long)((sec % SECONDS_IN_AN_HOUR) / SECONDS_IN_A_MINUTE));
  printf(":");
  print_format((unsigned long)((sec % SECONDS_IN_AN_HOUR) % SECONDS_IN_A_MINUTE));
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L15:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L42:
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L10
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L42
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D25
type_infered: string

tool: D19: Insert matrix length:

tool: D16: %d %d

tool: D25: %d

assistant: ```c
void read_matrix(int ***matrix, int *n, int *m) {
  printf("Insert matrix length:");
  scanf("%d %d", n, m);
  (*matrix) = (int **)malloc(*m * sizeof(int *));
  for (int i = 0; i < *n; i++)
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  for (int i = 0; i < *n; i++)
    for (int j = 0; j < *m; j++)
      scanf("%d", &(*matrix)[i][j]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%rbp
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  cmpl   $0x0,(%rbx)
  jle    L73
  mov    $0x0,%ebx
L27:
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%r12),%rdx
  mov    %rax,(%rdx,%rbx,8)
  mov    0x8(%rsp),%rax
  mov    (%rax),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L27
  test   %eax,%eax
  jle    L73
  mov    $0x0,%r15d
  lea    D19(%rip),%r14
  jmp    L70
L20:
  mov    (%r12),%rax
  mov    (%rax,%r13,1),%rax
  lea    (%rax,%rbx,4),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%rbp)
  jg     L20
L10:
  add    $0x1,%r15
  mov    0x8(%rsp),%rax
  cmp    %r15d,(%rax)
  jle    L73
L70:
  lea    0x0(,%r15,8),%r13
  mov    $0x0,%ebx
  cmpl   $0x0,0x0(%rbp)
  jg     L20
  jmp    L10
L73:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D19
type: string

tool: D18: Insert matrix length:

tool: D12: %d %d

tool: D19: %d

assistant: ```c
void read_matrix(int ***matrix, int *n, int *m) {
  printf("Insert matrix length:");
  scanf("%d %d", n, m);
  (*matrix) = (int **)malloc(*m * sizeof(int *));
  for (int i = 0; i < *n; i++)
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  for (int i = 0; i < *n; i++)
    for (int j = 0; j < *m; j++)
      scanf("%d", &(*matrix)[i][j]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_matrix>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  lea    D8(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    (%rbx),%edx
  mov    %rax,(%r15)
  test   %edx,%edx
  jle    L31
  xor    %ebx,%ebx
  xchg   %ax,%ax
L39:
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%r15),%rdx
  mov    %rax,(%rdx,%rbx,8)
  mov    0x8(%rsp),%rax
  add    $0x1,%rbx
  mov    (%rax),%eax
  cmp    %ebx,%eax
  jg     L39
  test   %eax,%eax
  jle    L31
  xor    %r14d,%r14d
  lea    D29(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp),%eax
  lea    0x0(,%r14,8),%r12
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L42
  nopl   0x0(%rax)
L40:
  mov    (%r15),%rax
  mov    %r13,%rdi
  mov    (%rax,%r12,1),%rax
  lea    (%rax,%rbx,4),%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  cmp    %ebx,0x0(%rbp)
  jg     L40
L42:
  mov    0x8(%rsp),%rax
  add    $0x1,%r14
  cmp    %r14d,(%rax)
  jg     L1
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D29
type_infered: string

tool: D8: Insert matrix length:

tool: D10: %d %d

tool: D29: %d

assistant: ```c
void read_matrix(int ***matrix, int *n, int *m) {
  printf("Insert matrix length:");
  scanf("%d %d", n, m);
  (*matrix) = (int **)malloc(*m * sizeof(int *));
  for (int i = 0; i < *n; i++)
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  for (int i = 0; i < *n; i++)
    for (int j = 0; j < *m; j++)
      scanf("%d", &(*matrix)[i][j]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_matrix>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  lea    D10(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L25
  xor    %ebx,%ebx
  xchg   %ax,%ax
L29:
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%r15),%rdx
  mov    %rax,(%rdx,%rbx,8)
  mov    0x8(%rsp),%rax
  add    $0x1,%rbx
  mov    (%rax),%eax
  cmp    %ebx,%eax
  jg     L29
  test   %eax,%eax
  jle    L25
  mov    0x0(%rbp),%eax
  xor    %r14d,%r14d
  lea    D4(%rip),%r13
  test   %eax,%eax
  jle    L25
  nopw   0x0(%rax,%rax,1)
L32:
  lea    0x0(,%r14,8),%r12
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L49:
  mov    (%r15),%rax
  mov    %r13,%rdi
  mov    (%rax,%r12,1),%rax
  lea    (%rax,%rbx,4),%rsi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  cmp    %ebx,%eax
  jg     L49
  mov    0x8(%rsp),%rcx
  lea    0x1(%r14),%edx
  cmp    (%rcx),%edx
  jge    L25
  add    $0x1,%r14
  test   %eax,%eax
  jg     L32
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D10: Insert matrix length:

tool: D14: %d %d

tool: D4: %d

assistant: ```c
void read_matrix(int ***matrix, int *n, int *m) {
  printf("Insert matrix length:");
  scanf("%d %d", n, m);
  (*matrix) = (int **)malloc(*m * sizeof(int *));
  for (int i = 0; i < *n; i++)
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  for (int i = 0; i < *n; i++)
    for (int j = 0; j < *m; j++)
      scanf("%d", &(*matrix)[i][j]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<draw_func_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <plot_func@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string

tool: D5: (%s) %d %d name


assistant: ```c
void draw_func_name(FILE *fp, int x, int index) {
  char *string = plot_func(index);
  fprintf(fp, "(%s) %d %d name\n", string, x, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<draw_func_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%edi
  call   <plot_func@plt>
  mov    %rax,%rdx
  mov    $0x0,%r8d
  mov    %ebp,%ecx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: (%s) %d %d name


assistant: ```c
void draw_func_name(FILE *fp, int x, int index) {
  char *string = plot_func(index);
  fprintf(fp, "(%s) %d %d name\n", string, x, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<draw_func_name>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <plot_func@plt>
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  lea    D5(%rip),%rsi
  jmp    1070 <fprintf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: (%s) %d %d name


assistant: ```c
void draw_func_name(FILE *fp, int x, int index) {
  char *string = plot_func(index);
  fprintf(fp, "(%s) %d %d name\n", string, x, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<draw_func_name>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <plot_func@plt>
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %rax,%rdx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  lea    D7(%rip),%rsi
  jmp    1070 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: (%s) %d %d name


assistant: ```c
void draw_func_name(FILE *fp, int x, int index) {
  char *string = plot_func(index);
  fprintf(fp, "(%s) %d %d name\n", string, x, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string

tool: D23: Don't be a fool.

tool: D8: mesg = %s, &mesg = %p, value = %p


tool: D16: copy = %s, &copy = %p, value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool.";
  const char *copy;
  copy = mesg;
  puts(copy);
  printf("mesg = %s, &mesg = %p, value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s, &copy = %p, value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  mov    %rdi,0x8(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  mov    %rsi,%rcx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %rsi,%rcx
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string

tool: D24: Don't be a fool.

tool: D12: mesg = %s, &mesg = %p, value = %p


tool: D26: copy = %s, &copy = %p, value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool.";
  const char *copy;
  copy = mesg;
  puts(copy);
  printf("mesg = %s, &mesg = %p, value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s, &copy = %p, value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  lea    D0(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  lea    D4(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D2: Don't be a fool.

tool: D0: mesg = %s, &mesg = %p, value = %p


tool: D4: copy = %s, &copy = %p, value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool.";
  const char *copy;
  copy = mesg;
  puts(copy);
  printf("mesg = %s, &mesg = %p, value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s, &copy = %p, value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  lea    D2(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  lea    D16(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string

tool: D0: Don't be a fool.

tool: D2: mesg = %s, &mesg = %p, value = %p


tool: D16: copy = %s, &copy = %p, value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool.";
  const char *copy;
  copy = mesg;
  puts(copy);
  printf("mesg = %s, &mesg = %p, value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s, &copy = %p, value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_xmm_uint8_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <load_xmm@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <print_vec_uint8_hex@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
data_type: string

tool: D22: xmm%d = 

assistant: ```c
void print_xmm_uint8_hex(int i) {
  static uint8_t v[16];
  load_xmm(i, (void *)v);
  printf("xmm%d = ", i);
  print_vec_uint8_hex(v);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_xmm_uint8_hex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    D1(%rip),%rbp
  mov    %rbp,%rsi
  call   <load_xmm@plt>
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_vec_uint8_hex@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type_infered: string

tool: D18: xmm%d = 

assistant: ```c
void print_xmm_uint8_hex(int i) {
  static uint8_t v[16];
  load_xmm(i, (void *)v);
  printf("xmm%d = ", i);
  print_vec_uint8_hex(v);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_xmm_uint8_hex>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <load_xmm@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print_vec_uint8_hex@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0: xmm%d = 

assistant: ```c
void print_xmm_uint8_hex(int i) {
  static uint8_t v[16];
  load_xmm(i, (void *)v);
  printf("xmm%d = ", i);
  print_vec_uint8_hex(v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_xmm_uint8_hex>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <load_xmm@plt>
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print_vec_uint8_hex@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string

tool: D12: xmm%d = 

assistant: ```c
void print_xmm_uint8_hex(int i) {
  static uint8_t v[16];
  load_xmm(i, (void *)v);
  printf("xmm%d = ", i);
  print_vec_uint8_hex(v);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const volatile int v = argc;
  return v - argc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    %edi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const volatile int v = argc;
  return v - argc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    %edi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const volatile int v = argc;
  return v - argc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    %edi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const volatile int v = argc;
  return v - argc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat4f_rotateQuatVec_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat3f_rotateQuatVec_new@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat4f_from_mat3f@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void mat4f_rotateQuatVec_new(float matrix[16], const float quat[4]) {
  float tmpMat[9];
  mat3f_rotateQuatVec_new(tmpMat, quat);
  mat4f_from_mat3f(matrix, tmpMat);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat4f_rotateQuatVec_new>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <mat3f_rotateQuatVec_new@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mat4f_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4f_rotateQuatVec_new(float matrix[16], const float quat[4]) {
  float tmpMat[9];
  mat3f_rotateQuatVec_new(tmpMat, quat);
  mat4f_from_mat3f(matrix, tmpMat);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mat4f_rotateQuatVec_new>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_rotateQuatVec_new@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mat4f_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4f_rotateQuatVec_new(float matrix[16], const float quat[4]) {
  float tmpMat[9];
  mat3f_rotateQuatVec_new(tmpMat, quat);
  mat4f_from_mat3f(matrix, tmpMat);
}
```