user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x13000(%rsp),%r11
L40:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L40
  sub    $0xcb8,%rsp
  lea    D4(%rip),%r12
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x13ca8(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%ecx
  test   %ecx,%ecx
  je     L2
  lea    0x28(%rsp),%rax
  lea    0x9c70(%rsp),%rbp
  mov    %rax,0x18(%rsp)
  lea    0x24(%rsp),%rax
  lea    0x30(%rsp),%rbx
  mov    %rax,0x10(%rsp)
  lea    0x138b0(%rsp),%rax
  mov    %rax,(%rsp)
  xchg   %ax,%ax
L72:
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rcx
  xor    %eax,%eax
  xor    %r14d,%r14d
  mov    (%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  jle    L55
  mov    %rbp,0x8(%rsp)
  mov    %eax,%r15d
  nopl   0x0(%rax)
L116:
  mov    0x28(%rsp),%eax
  lea    (%rbx,%r14,4),%rbp
  xor    %r13d,%r13d
  test   %eax,%eax
  jle    L49
  nopw   0x0(%rax,%rax,1)
L89:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r13d,0x28(%rsp)
  jg     L89
L49:
  add    $0x1,%r15d
  add    $0x64,%r14
  cmp    %r15d,0x24(%rsp)
  jg     L116
  mov    0x8(%rsp),%rbp
L55:
  mov    $0x9c40,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %r15d,%r15d
  call   <memset@plt>
  mov    0x24(%rsp),%esi
  mov    0x28(%rsp),%edx
  xor    %r13d,%r13d
  test   %esi,%esi
  jle    L83
  nopl   0x0(%rax)
L9:
  xor    %r14d,%r14d
  test   %edx,%edx
  jle    L74
  nop
L17:
  mov    %r14d,%r8d
  mov    %rbp,%r9
  mov    %r13d,%ecx
  mov    %rbx,%rdi
  call   <findLongestLengthDP@plt>
  mov    0x28(%rsp),%edx
  mov    0x24(%rsp),%esi
  cmp    %eax,%r15d
  cmovl  %eax,%r15d
  add    $0x1,%r14d
  cmp    %r14d,%edx
  jg     L17
L74:
  add    $0x1,%r13d
  cmp    %r13d,%esi
  jg     L9
L83:
  mov    (%rsp),%rsi
  mov    %r15d,%edx
  lea    D24(%rip),%rdi
  call   <printf@plt>
  subl   $0x1,0x2c(%rsp)
  jne    L72
L2:
  mov    0x13ca8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x13cb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D24
type_guessed: string

tool: D4: %d

tool: D29: %s %d %d

tool: D24: %s: %d


assistant: ```c
int main(void) {
  char name[1000 + 1];
  int heightArr[100][100], longestLength[100][100], numRow, numCol, T, row, col, maxLength, length;
  scanf("%d", &T);
  while (T) {
    scanf("%s %d %d", name, &numRow, &numCol);
    for (row = 0; row < numRow; row++)
      for (col = 0; col < numCol; col++)
        scanf("%d", &heightArr[row][col]);
    memset(longestLength, 0, 100 * 100 * sizeof(int));
    maxLength = 0;
    for (row = 0; row < numRow; row++)
      for (col = 0; col < numCol; col++) {
        length = findLongestLengthDP(heightArr, numRow, numCol, row, col, longestLength);
        if (length > maxLength)
          maxLength = length;
      }
    printf("%s: %d\n", name, maxLength);
    T--;
  }
  return 0;
}
```