ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L15
L32:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
L49:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L36
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L36
  addl   $0x1,-0x20(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L49
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L32
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D29
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D25: %d

tool: D29: %lld

tool: D9: %d


assistant: ```c
int main() {
  int t, ans, rem;
  long long int num, temp;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &num);
    temp = num;
    ans = 0;
    {
      do {
        rem = num % 10;
        num = num / 10;
        if (rem != 0) {
          if (temp % rem == 0)
            ans++;
        }
      } while (num != 0);
      printf("%d\n", ans);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L11
  lea    0x10(%rsp),%r13
  lea    D12(%rip),%r12
  movabs $0x6666666666666667,%rbx
  lea    D21(%rip),%rbp
  jmp    L63
L5:
  test   %rcx,%rcx
  je     L39
L23:
  mov    %rdi,%rax
  imul   %rbx
  sar    $0x2,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rdx
  add    %rdx,%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  mov    %rcx,%rdi
  test   %eax,%eax
  je     L5
  movslq %eax,%rsi
  mov    %r9,%rax
  cqto
  idiv   %rsi
  cmp    $0x1,%rdx
  adc    $0x0,%r8d
  jmp    L5
L39:
  movq   $0x0,0x10(%rsp)
  mov    %r8d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L11
L63:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%r9
  mov    %r9,%rdi
  mov    $0x0,%r8d
  jmp    L23
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D15: %d

tool: D12: %lld

tool: D21: %d


assistant: ```c
int main() {
  int t, ans, rem;
  long long int num, temp;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &num);
    temp = num;
    ans = 0;
    {
      do {
        rem = num % 10;
        num = num / 10;
        if (rem != 0) {
          if (temp % rem == 0)
            ans++;
        }
      } while (num != 0);
      printf("%d\n", ans);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  movabs $0x6666666666666667,%r13
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L13
  nop
L39:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%r9
  xor    %r8d,%r8d
  mov    %r9,%rsi
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rsi,%rax
  mov    %rsi,%rdi
  imul   %r13
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  mov    %rcx,%rsi
  add    %rax,%rax
  sub    %rax,%rdi
  je     L31
  mov    %r9,%rax
  cqto
  idiv   %rdi
  cmp    $0x1,%rdx
  adc    $0x0,%r8d
L31:
  test   %rcx,%rcx
  jne    L25
  movq   $0x0,0x10(%rsp)
  mov    %r8d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L39
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string

tool: D9: %d

tool: D19: %lld

tool: D12: %d


assistant: ```c
int main() {
  int t, ans, rem;
  long long int num, temp;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &num);
    temp = num;
    ans = 0;
    {
      do {
        rem = num % 10;
        num = num / 10;
        if (rem != 0) {
          if (temp % rem == 0)
            ans++;
        }
      } while (num != 0);
      printf("%d\n", ans);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  movabs $0x6666666666666667,%r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L48
  nop
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%r9
  xor    %r8d,%r8d
  mov    %r9,%rsi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rsi,%rax
  mov    %rsi,%rdi
  imul   %r13
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  lea    (%rcx,%rcx,4),%rax
  mov    %rcx,%rsi
  add    %rax,%rax
  sub    %rax,%rdi
  je     L21
  mov    %r9,%rax
  cqto
  idiv   %rdi
  cmp    $0x1,%rdx
  adc    $0x0,%r8d
L21:
  test   %rcx,%rcx
  jne    L1
  movq   $0x0,0x10(%rsp)
  mov    %r8d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L25
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D3: %d

tool: D1: %lld

tool: D11: %d


assistant: ```c
int main() {
  int t, ans, rem;
  long long int num, temp;
  scanf("%d", &t);
  while (t--) {
    scanf("%lld", &num);
    temp = num;
    ans = 0;
    {
      do {
        rem = num % 10;
        num = num / 10;
        if (rem != 0) {
          if (temp % rem == 0)
            ans++;
        }
      } while (num != 0);
      printf("%d\n", ans);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_good@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_bad@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D36
type: string
name: retrieve_data
arguments: label: D11
type: string
name: retrieve_data
arguments: label: D34
type: string

tool: D8: Calling good()...


tool: D36: Finished good()


tool: D11: Calling bad()...


tool: D34: Finished bad()


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Calling good()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_good();
  printf("Finished good()\n");
  printf("Calling bad()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_bad();
  printf("Finished bad()\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_good@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_bad@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string

tool: D31: Calling good()...


tool: D28: Finished good()


tool: D18: Calling bad()...


tool: D16: Finished bad()


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Calling good()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_good();
  printf("Finished good()\n");
  printf("Calling bad()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_bad();
  printf("Finished bad()\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_good@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_bad@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D32
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D32: Calling good()...


tool: D37: Finished good()


tool: D10: Calling bad()...


tool: D6: Finished bad()


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Calling good()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_good();
  printf("Finished good()\n");
  printf("Calling bad()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_bad();
  printf("Finished bad()\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D30(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_good@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <CWE535_Info_Exposure_Shell_Error__w32_char_01_bad@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D30
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D37
data_type: string
name: disassemble_data
arguments: data_tag: D22
data_type: string

tool: D30: Calling good()...


tool: D2: Finished good()


tool: D37: Calling bad()...


tool: D22: Finished bad()


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Calling good()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_good();
  printf("Finished good()\n");
  printf("Calling bad()...\n");
  CWE535_Info_Exposure_Shell_Error__w32_char_01_bad();
  printf("Finished bad()\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<pc_adoption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L48
  cmpq   $0x0,-0x20(%rbp)
  jne    L21
L48:
  mov    $0x0,%eax
  jmp    L1
L21:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <pc_get_partner@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pc_adoption_sub@plt>
  jmp    L1
L38:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int pc_adoption(struct map_session_data *sd, struct map_session_data *parent) {
  struct map_session_data *parent2;
  if (sd == NULL || parent == NULL)
    return 0;
  parent2 = pc_get_partner(parent);
  if (parent2)
    return pc_adoption_sub(sd, parent, parent2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pc_adoption>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L31
  mov    %rsi,%rdi
  call   <pc_get_partner@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L5
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <pc_adoption_sub@plt>
  jmp    L31
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int pc_adoption(struct map_session_data *sd, struct map_session_data *parent) {
  struct map_session_data *parent2;
  if (sd == NULL || parent == NULL)
    return 0;
  parent2 = pc_get_partner(parent);
  if (parent2)
    return pc_adoption_sub(sd, parent, parent2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pc_adoption>:
  endbr64
  test   %rdi,%rdi
  je     L22
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L27
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <pc_get_partner@plt>
  test   %rax,%rax
  jne    L29
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  pop    %rbp
  pop    %r12
  jmp    1070 <pc_adoption_sub@plt>
```

assistant: ```c
int pc_adoption(struct map_session_data *sd, struct map_session_data *parent) {
  struct map_session_data *parent2;
  if (sd == NULL || parent == NULL)
    return 0;
  parent2 = pc_get_partner(parent);
  if (parent2)
    return pc_adoption_sub(sd, parent, parent2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pc_adoption>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L13
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <pc_get_partner@plt>
  test   %rax,%rax
  jne    L8
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  pop    %rbp
  pop    %r12
  jmp    1070 <pc_adoption_sub@plt>
```

assistant: ```c
int pc_adoption(struct map_session_data *sd, struct map_session_data *parent) {
  struct map_session_data *parent2;
  if (sd == NULL || parent == NULL)
    return 0;
  parent2 = pc_get_partner(parent);
  if (parent2)
    return pc_adoption_sub(sd, parent, parent2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<recurSumOfDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L14
L5:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <sumOfDigits@plt>
  add    %ebx,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int recurSumOfDigits(int number) {
  if (number == 0)
    return 0;
  return ((number % 10) + sumOfDigits(number / 10));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<recurSumOfDigits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L11
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  movslq %edi,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  mov    %ebp,%edi
  call   <sumOfDigits@plt>
  mov    %eax,%edx
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    %edx,%ebx
  jmp    L17
```

assistant: ```c
int recurSumOfDigits(int number) {
  if (number == 0)
    return 0;
  return ((number % 10) + sumOfDigits(number / 10));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recurSumOfDigits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L6
  movslq %edi,%rbx
  mov    %edi,%eax
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  mov    %ebx,%edi
  call   <sumOfDigits@plt>
  mov    %eax,%r8d
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  add    %r8d,%r12d
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int recurSumOfDigits(int number) {
  if (number == 0)
    return 0;
  return ((number % 10) + sumOfDigits(number / 10));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<recurSumOfDigits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L4
  movslq %edi,%rbx
  mov    %edi,%eax
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  mov    %ebx,%edi
  call   <sumOfDigits@plt>
  mov    %eax,%r8d
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  add    %r8d,%r12d
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int recurSumOfDigits(int number) {
  if (number == 0)
    return 0;
  return ((number % 10) + sumOfDigits(number / 10));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_component>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L37
L64:
  addq   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L64
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L33:
  addq   $0x1,-0x18(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L67
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L67:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L24
L26:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L26
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_component(char *target, char **targname) {
  char *start;
  while (*target == '/')
    target++;
  start = target;
  while (*target != '/' && *target != '\0')
    target++;
  *targname = strndup(start, target - start);
  while (*target == '/')
    target++;
  return target;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_component>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  cmpb   $0x2f,(%rdi)
  jne    L62
L28:
  add    $0x1,%rdi
  cmpb   $0x2f,(%rdi)
  je     L28
L62:
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  je     L13
  test   %al,%al
  je     L13
  mov    %rdi,%rbx
L86:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  je     L67
  test   %al,%al
  jne    L86
L67:
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <strndup@plt>
  mov    %rax,0x0(%rbp)
  cmpb   $0x2f,(%rbx)
  jne    L77
L34:
  add    $0x1,%rbx
  cmpb   $0x2f,(%rbx)
  je     L34
L77:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %rdi,%rbx
  jmp    L67
```

assistant: ```c
char *get_component(char *target, char **targname) {
  char *start;
  while (*target == '/')
    target++;
  start = target;
  while (*target != '/' && *target != '\0')
    target++;
  *targname = strndup(start, target - start);
  while (*target == '/')
    target++;
  return target;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_component>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  cmp    $0x2f,%al
  jne    L54
  nopl   (%rax)
L1:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x2f,%al
  je     L1
L54:
  mov    %rdi,%r12
  test   %al,%al
  je     L64
  nopl   0x0(%rax,%rax,1)
L25:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    $0x2f,%al
  je     L71
  test   %al,%al
  jne    L25
L71:
  mov    %r12d,%esi
  sub    %edi,%esi
L74:
  call   <strndup@plt>
  mov    %rax,(%rbx)
  cmpb   $0x2f,(%r12)
  jne    L28
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x1,%r12
  cmpb   $0x2f,(%r12)
  je     L14
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L64:
  xor    %esi,%esi
  jmp    L74
```

assistant: ```c
char *get_component(char *target, char **targname) {
  char *start;
  while (*target == '/')
    target++;
  start = target;
  while (*target != '/' && *target != '\0')
    target++;
  *targname = strndup(start, target - start);
  while (*target == '/')
    target++;
  return target;
}
```