user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movb   $0x0,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  cmpl   $0x3,-0x54(%rbp)
  je     L21
  mov    -0x60(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L33
L21:
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  lea    -0x4c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  lea    -0x4c(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  lea    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  mov    -0x60(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  lea    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  lea    -0x48(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L8
L23:
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L20
  mov    -0x60(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rsi
  lea    -0x40(%rbp),%rdx
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L33
L20:
  addl   $0x1,-0x44(%rbp)
L8:
  cmpl   $0xf,-0x44(%rbp)
  jle    L23
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x40(%rbp),%rdx
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D27
datatype: string

tool: D11: Usage:
	%s <prog> <prog2>


tool: D22: Two values are not the same.
%s: %s
%s: %s


tool: D27: Two values are the same: %s: %s


assistant: ```c
int main(int argc, char *argv[]) {
  MD5_CTX prog_md5;
  MD5_CTX prog2_md5;
  char prog_hash[17] = {0};
  char prog_hash2[17] = {0};
  int i;
  if (argc != 3) {
    printf("Usage:\n\t%s <prog> <prog2>\n", argv[0]);
    return 1;
  }
  MD5_Init(&prog_md5);
  MD5_Update(&prog_md5, argv[1], strlen(argv[1]));
  MD5_Final(prog_hash, &prog_md5);
  MD5_Init(&prog2_md5);
  MD5_Update(&prog2_md5, argv[2], strlen(argv[2]));
  MD5_Final(prog_hash2, &prog2_md5);
  for (i = 0; i < 16; ++i) {
    if (prog_hash[i] != prog_hash2[i]) {
      printf("Two values are not the same.\n%s: %s\n%s: %s\n", argv[1], prog_hash, argv[2], prog_hash2);
      return 1;
    }
  }
  printf("Two values are the same: %s: %s\n", argv[1], prog_hash);
  return 0;
}
```