ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<map20indexto34>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl (%rdi),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %al,0x1(%rdi)
  mov    %al,0x2(%rdi)
  mov    %al,0x3(%rdi)
  mov    %al,0x4(%rdi)
  mov    %al,0x5(%rdi)
  mov    %al,0x6(%rdi)
  mov    %al,0x7(%rdi)
  mov    %al,0x8(%rdi)
  mov    %al,0x9(%rdi)
  mov    %al,0xa(%rdi)
  mov    %al,0xb(%rdi)
  mov    %al,0xc(%rdi)
  mov    %al,0xd(%rdi)
  mov    %al,0xe(%rdi)
  mov    %al,0xf(%rdi)
  mov    %al,0x10(%rdi)
  cmp    $0x22,%sil
  je     L3
  ret
  nopl   (%rax)
L3:
  mov    %al,0x11(%rdi)
  mov    %al,0x12(%rdi)
  mov    %al,0x13(%rdi)
  mov    %al,0x14(%rdi)
  mov    %al,0x15(%rdi)
  mov    %al,0x16(%rdi)
  mov    %al,0x17(%rdi)
  mov    %al,0x18(%rdi)
  mov    %al,0x19(%rdi)
  mov    %al,0x1a(%rdi)
  mov    %al,0x1b(%rdi)
  mov    %al,0x1c(%rdi)
  mov    %al,0x1d(%rdi)
  mov    %al,0x1e(%rdi)
  mov    %al,0x1f(%rdi)
  mov    %al,0x20(%rdi)
  mov    %al,0x21(%rdi)
  ret
```

assistant: ```c
void map20indexto34(signed char *index, unsigned char bins) {
  index[0] = index[0];
  index[1] = (index[0] + index[1]) / 2;
  index[2] = index[1];
  index[3] = index[2];
  index[4] = (index[2] + index[3]) / 2;
  index[5] = index[3];
  index[6] = index[4];
  index[7] = index[4];
  index[8] = index[5];
  index[9] = index[5];
  index[10] = index[6];
  index[11] = index[7];
  index[12] = index[8];
  index[13] = index[8];
  index[14] = index[9];
  index[15] = index[9];
  index[16] = index[10];
  if (bins == 34) {
    index[17] = index[11];
    index[18] = index[12];
    index[19] = index[13];
    index[20] = index[14];
    index[21] = index[14];
    index[22] = index[15];
    index[23] = index[15];
    index[24] = index[16];
    index[25] = index[16];
    index[26] = index[17];
    index[27] = index[17];
    index[28] = index[18];
    index[29] = index[18];
    index[30] = index[18];
    index[31] = index[18];
    index[32] = index[19];
    index[33] = index[19];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<map20indexto34>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl (%rdi),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movd   %eax,%xmm0
  punpcklbw %xmm0,%xmm0
  punpcklwd %xmm0,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  movups %xmm0,0x1(%rdi)
  cmp    $0x22,%sil
  je     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %al,0x21(%rdi)
  movups %xmm0,0x11(%rdi)
  ret
```

assistant: ```c
void map20indexto34(signed char *index, unsigned char bins) {
  index[0] = index[0];
  index[1] = (index[0] + index[1]) / 2;
  index[2] = index[1];
  index[3] = index[2];
  index[4] = (index[2] + index[3]) / 2;
  index[5] = index[3];
  index[6] = index[4];
  index[7] = index[4];
  index[8] = index[5];
  index[9] = index[5];
  index[10] = index[6];
  index[11] = index[7];
  index[12] = index[8];
  index[13] = index[8];
  index[14] = index[9];
  index[15] = index[9];
  index[16] = index[10];
  if (bins == 34) {
    index[17] = index[11];
    index[18] = index[12];
    index[19] = index[13];
    index[20] = index[14];
    index[21] = index[14];
    index[22] = index[15];
    index[23] = index[15];
    index[24] = index[16];
    index[25] = index[16];
    index[26] = index[17];
    index[27] = index[17];
    index[28] = index[18];
    index[29] = index[18];
    index[30] = index[18];
    index[31] = index[18];
    index[32] = index[19];
    index[33] = index[19];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_blocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L18
  mov    -0x428(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L18:
  movl   $0x0,-0x41c(%rbp)
  jmp    L0
L47:
  lea    -0x410(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <keyword@plt>
  test   %rax,%rax
  je     L0
  addl   $0x1,-0x41c(%rbp)
L0:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x401,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x41c(%rbp),%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string

tool: D17: r

tool: D29: Could not open block file %s

tool: D21: GLOBALCOREBLOCK

assistant: ```c
int count_blocks(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nblocks;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open block file %s", filename);
    return -1;
  }
  nblocks = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "GLOBALCOREBLOCK")) {
      nblocks++;
    }
  }
  fclose(fin);
  return nblocks;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_blocks>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L48
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D25(%rip),%r12
  jmp    L7
L48:
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <error@plt>
  mov    $0xffffffff,%ebx
  jmp    L46
L44:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
L7:
  mov    %rsp,%rdi
  mov    %rbp,%rdx
  mov    $0x401,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L44
  mov    %rbp,%rdi
  call   <fclose@plt>
L46:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    %ebx,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D27
type_guessed: string

tool: D11: r

tool: D25: GLOBALCOREBLOCK

tool: D27: Could not open block file %s

assistant: ```c
int count_blocks(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nblocks;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open block file %s", filename);
    return -1;
  }
  nblocks = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "GLOBALCOREBLOCK")) {
      nblocks++;
    }
  }
  fclose(fin);
  return nblocks;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_blocks>:
  endbr64
  push   %r13
  lea    D10(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  xor    %r12d,%r12d
  lea    D5(%rip),%r13
  mov    %rsp,%rbx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
L11:
  mov    %rbp,%rdx
  mov    $0x401,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L42
  mov    %rbp,%rdi
  call   <fclose@plt>
L45:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <error@plt>
  jmp    L45
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D10: r

tool: D5: GLOBALCOREBLOCK

tool: D11: Could not open block file %s

assistant: ```c
int count_blocks(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nblocks;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open block file %s", filename);
    return -1;
  }
  nblocks = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "GLOBALCOREBLOCK")) {
      nblocks++;
    }
  }
  fclose(fin);
  return nblocks;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count_blocks>:
  endbr64
  push   %r13
  lea    D2(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L32
  mov    %rax,%rbp
  xor    %r12d,%r12d
  lea    D26(%rip),%r13
  mov    %rsp,%rbx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
L40:
  mov    %rbp,%rdx
  mov    $0x401,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbp,%rdi
  call   <fclose@plt>
L39:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <error@plt>
  jmp    L39
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D2: r

tool: D26: GLOBALCOREBLOCK

tool: D11: Could not open block file %s

assistant: ```c
int count_blocks(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nblocks;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open block file %s", filename);
    return -1;
  }
  nblocks = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "GLOBALCOREBLOCK")) {
      nblocks++;
    }
  }
  fclose(fin);
  return nblocks;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<removeTopWall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeTopWall(int (*maze)[25], int startRow, int startCol) {
  int removeRow, removeCol;
  removeRow = ((startRow - 1) + 1) * 2;
  removeCol = (startCol)*2 - 1 + 2;
  maze[removeRow][removeCol] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<removeTopWall>:
  endbr64
  mov    %edx,%ecx
  add    %esi,%esi
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,4),%rdx
  lea    0x1(%rcx,%rcx,1),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  ret
```

assistant: ```c
void removeTopWall(int (*maze)[25], int startRow, int startCol) {
  int removeRow, removeCol;
  removeRow = ((startRow - 1) + 1) * 2;
  removeCol = (startCol)*2 - 1 + 2;
  maze[removeRow][removeCol] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<removeTopWall>:
  endbr64
  add    %esi,%esi
  mov    %edx,%r8d
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,4),%rdx
  lea    0x1(%r8,%r8,1),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  ret
```

assistant: ```c
void removeTopWall(int (*maze)[25], int startRow, int startCol) {
  int removeRow, removeCol;
  removeRow = ((startRow - 1) + 1) * 2;
  removeCol = (startCol)*2 - 1 + 2;
  maze[removeRow][removeCol] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L37
L17:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L12:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L14:
  cmpl   $0x2,-0x14(%rbp)
  jle    L12
  addl   $0x1,-0x18(%rbp)
L37:
  cmpl   $0x6,-0x18(%rbp)
  jle    L17
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D29
type_infered: string
name: read_data
arguments: label: D20
type_infered: string

tool: D25: sapxsum

tool: D29: # c::%s:len=%d


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sapxsum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D13(%rip),%r15
  jmp    L19
L9:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L6
L19:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L35:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L35
  jmp    L9
L6:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
datatype: string
name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string

tool: D13: sapxsum

tool: D15: # c::%s:len=%d


tool: D24: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sapxsum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D23(%rip),%r15
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L17:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L6:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L6
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L17
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D29
type: string

tool: D23: sapxsum

tool: D24: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sapxsum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D2(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L10:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L17:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L17
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L10
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string

tool: D2: sapxsum

tool: D22: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sapxsum", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<search_no_hyphen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L52
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L34
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  jmp    L52
L13:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
L52:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: 

assistant: ```c
void search_no_hyphen(const int argc, char *const argv[], const int starting_point, char result[]) {
  int i;
  strcpy(result, "");
  if (starting_point < argc) {
    for (i = starting_point; i < argc; i++) {
      if (argv[i][0] != '-' && argv[i][0] != '\0') {
        strcpy(result, argv[i]);
        break;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<search_no_hyphen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%rbp
  lea    D1(%rip),%rsi
  mov    %rcx,%rdi
  call   <strcpy@plt>
  cmp    %ebx,%r13d
  jge    L8
  movslq %r13d,%rdx
  lea    (%r12,%rdx,8),%rax
  sub    $0x1,%ebx
  sub    %r13d,%ebx
  add    %rdx,%rbx
  lea    0x8(%r12,%rbx,8),%rcx
  jmp    L3
L2:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L8
L3:
  mov    (%rax),%rsi
  movzbl (%rsi),%edx
  cmp    $0x2d,%dl
  je     L2
  test   %dl,%dl
  je     L2
  mov    %rbp,%rdi
  call   <strcpy@plt>
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: 

assistant: ```c
void search_no_hyphen(const int argc, char *const argv[], const int starting_point, char result[]) {
  int i;
  strcpy(result, "");
  if (starting_point < argc) {
    for (i = starting_point; i < argc; i++) {
      if (argv[i][0] != '-' && argv[i][0] != '\0') {
        strcpy(result, argv[i]);
        break;
      }
    }
  }
}
```