user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%edi
  call   <count@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <append@plt>
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <append@plt>
  mov    $0x19,%esi
  mov    %rbx,%rdi
  call   <append@plt>
  mov    $0x2a,%esi
  mov    %rbx,%rdi
  call   <append@plt>
  mov    $0x11,%esi
  mov    %rbx,%rdi
  call   <append@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    $0x3e7,%esi
  mov    %rbx,%rdi
  call   <prepend@plt>
  mov    $0x378,%esi
  mov    %rbx,%rdi
  call   <prepend@plt>
  mov    $0x309,%esi
  mov    %rbx,%rdi
  call   <prepend@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    (%rsp),%rdi
  call   <insert_after@plt>
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    (%rsp),%rdi
  call   <insert_after@plt>
  mov    $0x63,%edx
  mov    $0x5,%esi
  mov    (%rsp),%rdi
  call   <insert_after@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    $0xa,%edx
  mov    $0x63,%esi
  mov    (%rsp),%rdi
  call   <insert_after@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <delete@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <delete@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <delete@plt>
  mov    (%rsp),%rdi
  call   <count@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <display@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: No of elements in linked list = %d


assistant: ```c
int main(void) {
  struct node *list;
  list = NULL;
  printf("No of elements in linked list = %d\n", count(list));
  append(&list, 14);
  append(&list, 30);
  append(&list, 25);
  append(&list, 42);
  append(&list, 17);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  prepend(&list, 999);
  prepend(&list, 888);
  prepend(&list, 777);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  insert_after(list, 1, 0);
  insert_after(list, 2, 1);
  insert_after(list, 5, 99);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  insert_after(list, 99, 10);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  delete (&list, 99);
  delete (&list, 1);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  delete (&list, 10);
  printf("No of elements in linked list = %d\n", count(list));
  display(list);
  return 0;
}
```