ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_atoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L82
L54:
  add    $0x1,%rbx
L82:
  movsbl (%rbx),%edi
  call   <ft_isspace@plt>
  test   %rax,%rax
  jne    L54
  movzbl (%rbx),%eax
  cmp    $0x2d,%al
  je     L93
  mov    $0x1,%ebp
  cmp    $0x2b,%al
  je     L109
L124:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L38
  mov    $0x0,%r13d
  movabs $0x7ffffffffffffffe,%r12
  jmp    L39
L93:
  add    $0x1,%rbx
  mov    $0xffffffff,%ebp
  jmp    L124
L109:
  add    $0x1,%rbx
  jmp    L124
L60:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L45
L39:
  movsbl %dil,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L45
  lea    0x0(%r13,%r13,4),%rdx
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%r13
  cmp    %r12,%r13
  jbe    L132
  cmp    $0x1,%ebp
  je     L139
L132:
  test   %r13,%r13
  jns    L60
  cmp    $0xffffffff,%ebp
  jne    L60
  mov    $0x0,%eax
  jmp    L100
L38:
  mov    $0x0,%r13d
L45:
  mov    %r13d,%eax
  imul   %ebp,%eax
L100:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L139:
  mov    $0xffffffff,%eax
  jmp    L100
```

assistant: ```c
int ft_atoi(const char *str) {
  int s;
  unsigned long int r;
  r = 0;
  s = 1;
  while (ft_isspace(*str))
    str++;
  if (*str == '-') {
    s = -1;
    str++;
  } else if (*str == '+')
    str++;
  while (*str && ft_isdigit(*str)) {
    r = r * 10 + (*str - '0');
    if (r >= 9223372036854775807 && s == 1)
      return (-1);
    if (r > 9223372036854775807 && s == -1)
      return (0);
    str++;
  }
  return ((int)(r * s));
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_atoi>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1,%rbx
L61:
  movsbl (%rbx),%edi
  call   <ft_isspace@plt>
  test   %rax,%rax
  jne    L37
  movsbl (%rbx),%edi
  cmp    $0x2d,%dil
  je     L123
  mov    $0x1,%ebp
  cmp    $0x2b,%dil
  je     L16
L94:
  test   %dil,%dil
  je     L18
  movabs $0x7ffffffffffffffe,%r12
  xor    %r13d,%r13d
  jmp    L92
  nopl   0x0(%rax)
L31:
  movsbl (%rbx),%eax
  lea    0x0(%r13,%r13,4),%rdx
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%r13
  cmp    %r12,%r13
  jbe    L98
  cmp    $0x1,%ebp
  je     L87
L98:
  test   %r13,%r13
  jns    L76
  cmp    $0xffffffff,%ebp
  je     L18
L76:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L81
L92:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L31
L81:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  imul   %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L94
  nopw   0x0(%rax,%rax,1)
L123:
  movsbl 0x1(%rbx),%edi
  mov    $0xffffffff,%ebp
  add    $0x1,%rbx
  jmp    L94
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L87:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int s;
  unsigned long int r;
  r = 0;
  s = 1;
  while (ft_isspace(*str))
    str++;
  if (*str == '-') {
    s = -1;
    str++;
  } else if (*str == '+')
    str++;
  while (*str && ft_isdigit(*str)) {
    r = r * 10 + (*str - '0');
    if (r >= 9223372036854775807 && s == 1)
      return (-1);
    if (r > 9223372036854775807 && s == -1)
      return (0);
    str++;
  }
  return ((int)(r * s));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_atoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L112
  nopl   0x0(%rax)
L91:
  add    $0x1,%rbx
L112:
  movsbl (%rbx),%edi
  call   <ft_isspace@plt>
  test   %rax,%rax
  jne    L91
  movsbl (%rbx),%edi
  cmp    $0x2d,%dil
  je     L46
  mov    $0x1,%r13d
  mov    $0x1,%ebp
  cmp    $0x2b,%dil
  je     L116
L45:
  test   %dil,%dil
  je     L126
  movabs $0x7ffffffffffffffe,%r12
  xor    %r14d,%r14d
  jmp    L18
  nop
L113:
  movsbl (%rbx),%eax
  lea    (%r14,%r14,4),%rdx
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%r14
  cmp    %r12,%r14
  jbe    L96
  cmp    $0x1,%ebp
  je     L65
L96:
  test   %r14,%r14
  jns    L118
  cmp    $0xffffffff,%ebp
  je     L126
L118:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L50
L18:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L113
L50:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  imul   %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L116:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L46:
  movsbl 0x1(%rbx),%edi
  mov    $0xffffffff,%r13d
  add    $0x1,%rbx
  mov    $0xffffffff,%ebp
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L126:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int s;
  unsigned long int r;
  r = 0;
  s = 1;
  while (ft_isspace(*str))
    str++;
  if (*str == '-') {
    s = -1;
    str++;
  } else if (*str == '+')
    str++;
  while (*str && ft_isdigit(*str)) {
    r = r * 10 + (*str - '0');
    if (r >= 9223372036854775807 && s == 1)
      return (-1);
    if (r > 9223372036854775807 && s == -1)
      return (0);
    str++;
  }
  return ((int)(r * s));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nuclear_mep>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,0x30(%rsp)
  mov    %ecx,%r14d
  mov    %ecx,0x28(%rsp)
  mov    %r8,0x38(%rsp)
  mov    $0x8,%esi
  mov    %ecx,%edi
  call   <calloc@plt>
  mov    %rax,0x20(%rsp)
  test   %ebx,%ebx
  jle    L14
  mov    %rax,%rsi
  mov    %rbp,0x18(%rsp)
  lea    (%rbx,%rbx,2),%eax
  mov    %eax,0x2c(%rsp)
  lea    -0x1(%r14),%eax
  lea    0x8(%rsi,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  movl   $0x0,0x14(%rsp)
  jmp    L43
L60:
  movslq 0x14(%rsp),%rax
  shl    $0x3,%rax
  mov    0x30(%rsp),%rdx
  lea    (%rdx,%rax,1),%r15
  lea    0x8(%rdx,%rax,1),%r14
  lea    0x10(%rdx,%rax,1),%r13
  mov    0x38(%rsp),%r12
  mov    0x20(%rsp),%rbp
  mov    0x18(%rsp),%rbx
L56:
  movsd  (%r15),%xmm0
  subsd  (%r12),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movsd  %xmm0,(%rsp)
  movsd  (%r14),%xmm0
  subsd  0x8(%r12),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  movsd  0x0(%r13),%xmm0
  subsd  0x10(%r12),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  addsd  (%rsp),%xmm0
  movsd  (%rbx),%xmm4
  movsd  %xmm4,(%rsp)
  pxor   %xmm5,%xmm5
  ucomisd %xmm0,%xmm5
  ja     L71
  sqrtsd %xmm0,%xmm0
L48:
  movsd  (%rsp),%xmm1
  divsd  %xmm0,%xmm1
  addsd  0x0(%rbp),%xmm1
  movsd  %xmm1,0x0(%rbp)
  add    $0x18,%r12
  add    $0x8,%rbp
  cmp    0x8(%rsp),%rbp
  jne    L56
L52:
  addq   $0x8,0x18(%rsp)
  addl   $0x3,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    0x2c(%rsp),%eax
  je     L14
L43:
  cmpl   $0x0,0x28(%rsp)
  jg     L60
  jmp    L52
L71:
  call   <sqrt@plt>
  jmp    L48
L14:
  mov    0x20(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double *nuclear_mep(int nr_nuclei, double charges[nr_nuclei], double coordinates[3 * nr_nuclei], int grid_size, double grid[3 * grid_size]) {
  double *mep = (double *)calloc(grid_size, sizeof(double));
  for (int i = 0; i < nr_nuclei; i++) {
    for (int j = 0; j < grid_size; j++) {
      double dist = pow((coordinates[i * 3] - grid[j * 3]), 2) + pow((coordinates[i * 3 + 1] - grid[j * 3 + 1]), 2) + pow((coordinates[i * 3 + 2] - grid[j * 3 + 2]), 2);
      mep[j] += charges[i] / sqrt(dist);
    }
  }
  return mep;
}
```
user: What is the c source code of the assembly code below?

```asm
<nuclear_mep>:
  endbr64
  push   %r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %ecx,%edi
  sub    $0x48,%rsp
  mov    %rdx,0x30(%rsp)
  mov    %ecx,0x28(%rsp)
  mov    %r8,0x38(%rsp)
  call   <calloc@plt>
  mov    %rax,0x20(%rsp)
  test   %ebx,%ebx
  jle    L35
  mov    %rax,%rsi
  lea    (%rbx,%rbx,2),%eax
  movl   $0x0,0x1c(%rsp)
  mov    %eax,0x2c(%rsp)
  lea    -0x1(%r14),%eax
  lea    0x8(%rsi,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax)
L27:
  mov    0x28(%rsp),%eax
  test   %eax,%eax
  jle    L47
  movslq 0x1c(%rsp),%rax
  mov    0x30(%rsp),%rdx
  mov    0x38(%rsp),%rbx
  mov    0x20(%rsp),%r15
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%r14
  lea    0x8(%rdx,%rax,1),%r13
  lea    0x10(%rdx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  movsd  (%r14),%xmm0
  subsd  (%rbx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  0x0(%r13),%xmm0
  subsd  0x8(%rbx),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  mov    $0x2,%edi
  addsd  %xmm0,%xmm2
  movsd  (%r12),%xmm0
  subsd  0x10(%rbx),%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm4,%xmm4
  movsd  0x0(%rbp),%xmm1
  ucomisd %xmm0,%xmm4
  ja     L46
  sqrtsd %xmm0,%xmm0
L56:
  divsd  %xmm0,%xmm1
  add    $0x18,%rbx
  add    $0x8,%r15
  addsd  -0x8(%r15),%xmm1
  movsd  %xmm1,-0x8(%r15)
  cmp    %r15,0x10(%rsp)
  jne    L2
L47:
  addl   $0x3,0x1c(%rsp)
  add    $0x8,%rbp
  mov    0x1c(%rsp),%eax
  cmp    0x2c(%rsp),%eax
  jne    L27
L35:
  mov    0x20(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  jmp    L56
```

assistant: ```c
double *nuclear_mep(int nr_nuclei, double charges[nr_nuclei], double coordinates[3 * nr_nuclei], int grid_size, double grid[3 * grid_size]) {
  double *mep = (double *)calloc(grid_size, sizeof(double));
  for (int i = 0; i < nr_nuclei; i++) {
    for (int j = 0; j < grid_size; j++) {
      double dist = pow((coordinates[i * 3] - grid[j * 3]), 2) + pow((coordinates[i * 3 + 1] - grid[j * 3 + 1]), 2) + pow((coordinates[i * 3 + 2] - grid[j * 3 + 2]), 2);
      mep[j] += charges[i] / sqrt(dist);
    }
  }
  return mep;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nuclear_mep>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %ecx,%ebx
  mov    %ebx,%edi
  sub    $0x28,%rsp
  mov    %r8,0x10(%rsp)
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r15d,%r15d
  jle    L12
  test   %ebx,%ebx
  jle    L12
  lea    -0x1(%r15),%eax
  lea    0x0(%r13,%rbx,8),%r12
  lea    0x8(%rbp,%rax,8),%rax
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L28:
  mov    0x10(%rsp),%rbx
  mov    %r13,%r15
L8:
  movsd  (%r14),%xmm0
  subsd  (%rbx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  0x8(%r14),%xmm0
  subsd  0x8(%rbx),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  mov    $0x2,%edi
  addsd  %xmm0,%xmm2
  movsd  0x10(%r14),%xmm0
  subsd  0x10(%rbx),%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm4,%xmm4
  movsd  0x0(%rbp),%xmm1
  ucomisd %xmm0,%xmm4
  ja     L61
  sqrtsd %xmm0,%xmm0
  add    $0x8,%r15
  add    $0x18,%rbx
  divsd  %xmm0,%xmm1
  addsd  -0x8(%r15),%xmm1
  movsd  %xmm1,-0x8(%r15)
  cmp    %r15,%r12
  jne    L8
L37:
  add    $0x18,%r14
  add    $0x8,%rbp
  cmp    %rbp,0x18(%rsp)
  jne    L28
L12:
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%r15
  add    $0x18,%rbx
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  addsd  -0x8(%r15),%xmm1
  movsd  %xmm1,-0x8(%r15)
  cmp    %r12,%r15
  jne    L8
  jmp    L37
```

assistant: ```c
double *nuclear_mep(int nr_nuclei, double charges[nr_nuclei], double coordinates[3 * nr_nuclei], int grid_size, double grid[3 * grid_size]) {
  double *mep = (double *)calloc(grid_size, sizeof(double));
  for (int i = 0; i < nr_nuclei; i++) {
    for (int j = 0; j < grid_size; j++) {
      double dist = pow((coordinates[i * 3] - grid[j * 3]), 2) + pow((coordinates[i * 3 + 1] - grid[j * 3 + 1]), 2) + pow((coordinates[i * 3 + 2] - grid[j * 3 + 2]), 2);
      mep[j] += charges[i] / sqrt(dist);
    }
  }
  return mep;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmdsockstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x16,%edi
  call   <lngtxt@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <p_log@plt>
  mov    $0x7a69,%edi
  call   <usr1_error@plt>
  mov    $0x17,%edi
  call   <lngtxt@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <p_log@plt>
  nop
  leave
  ret
```

assistant: ```c
int cmdsockstat(int usern) {
  p_log(0x0000, usern, lngtxt(22));
  usr1_error(31337);
  p_log(0x0000, usern, lngtxt(23));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmdsockstat>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x16,%edi
  call   <lngtxt@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <p_log@plt>
  mov    $0x7a69,%edi
  call   <usr1_error@plt>
  mov    $0x17,%edi
  call   <lngtxt@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <p_log@plt>
  pop    %rbx
  ret
```

assistant: ```c
int cmdsockstat(int usern) {
  p_log(0x0000, usern, lngtxt(22));
  usr1_error(31337);
  p_log(0x0000, usern, lngtxt(23));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmdsockstat>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x16,%edi
  call   <lngtxt@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <p_log@plt>
  mov    $0x7a69,%edi
  call   <usr1_error@plt>
  mov    $0x17,%edi
  call   <lngtxt@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  mov    %eax,%edx
  jmp    1080 <p_log@plt>
```

assistant: ```c
int cmdsockstat(int usern) {
  p_log(0x0000, usern, lngtxt(22));
  usr1_error(31337);
  p_log(0x0000, usern, lngtxt(23));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<az_list_swap_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void az_list_swap_(int *num1, int *max1, void **items1, int *num2, int *max2, void **items2) {
  const int temp_num = *num1;
  const int temp_max = *max1;
  void *temp_items = *items1;
  *num1 = *num2;
  *max1 = *max2;
  *items1 = *items2;
  *num2 = temp_num;
  *max2 = temp_max;
  *items2 = temp_items;
}
```
user: Translate the below assembly code into C programming language:

```asm
<az_list_swap_>:
  endbr64
  push   %rbx
  mov    %rcx,%rax
  mov    (%rdi),%r11d
  mov    (%rsi),%r10d
  mov    (%rdx),%rcx
  mov    (%rax),%ebx
  mov    %ebx,(%rdi)
  mov    (%r8),%edi
  mov    %edi,(%rsi)
  mov    (%r9),%rsi
  mov    %rsi,(%rdx)
  mov    %r11d,(%rax)
  mov    %r10d,(%r8)
  mov    %rcx,(%r9)
  pop    %rbx
  ret
```

assistant: ```c
void az_list_swap_(int *num1, int *max1, void **items1, int *num2, int *max2, void **items2) {
  const int temp_num = *num1;
  const int temp_max = *max1;
  void *temp_items = *items1;
  *num1 = *num2;
  *max1 = *max2;
  *items1 = *items2;
  *num2 = temp_num;
  *max2 = temp_max;
  *items2 = temp_items;
}
```
user: What is the c source code of the assembly code below?

```asm
<az_list_swap_>:
  endbr64
  mov    %rcx,%rax
  push   %rbx
  mov    (%rdx),%rcx
  mov    (%rax),%ebx
  mov    (%rdi),%r11d
  mov    (%rsi),%r10d
  mov    %ebx,(%rdi)
  mov    (%r8),%edi
  mov    %edi,(%rsi)
  mov    (%r9),%rsi
  pop    %rbx
  mov    %rsi,(%rdx)
  mov    %r11d,(%rax)
  mov    %r10d,(%r8)
  mov    %rcx,(%r9)
  ret
```

assistant: ```c
void az_list_swap_(int *num1, int *max1, void **items1, int *num2, int *max2, void **items2) {
  const int temp_num = *num1;
  const int temp_max = *max1;
  void *temp_items = *items1;
  *num1 = *num2;
  *max1 = *max2;
  *items1 = *items2;
  *num2 = temp_num;
  *max2 = temp_max;
  *items2 = temp_items;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<az_list_swap_>:
  endbr64
  mov    %rcx,%rax
  push   %rbx
  mov    (%rdx),%rcx
  mov    (%rax),%ebx
  mov    (%rdi),%r11d
  mov    (%rsi),%r10d
  mov    %ebx,(%rdi)
  mov    (%r8),%edi
  mov    %edi,(%rsi)
  mov    (%r9),%rsi
  pop    %rbx
  mov    %rsi,(%rdx)
  mov    %r11d,(%rax)
  mov    %r10d,(%r8)
  mov    %rcx,(%r9)
  ret
```

assistant: ```c
void az_list_swap_(int *num1, int *max1, void **items1, int *num2, int *max2, void **items2) {
  const int temp_num = *num1;
  const int temp_max = *max1;
  void *temp_items = *items1;
  *num1 = *num2;
  *max1 = *max2;
  *items1 = *items2;
  *num2 = temp_num;
  *max2 = temp_max;
  *items2 = temp_items;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<newton>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rbx
  mov    -0x20(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   D5(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L16
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L9
L16:
  nop
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: qword

tool: D5: 9223372036854775807

assistant: ```c
double newton(double x0, double epsilon, double (*f)(double), double (*fprim)(double)) {
  double x_pre, x;
  x_pre = x0;
  for (;;) {
    x = x_pre - f(x_pre) * 1.0 / fprim(x_pre);
    if (fabs(x - x_pre) < epsilon)
      break;
    x_pre = x;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<newton>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  mov    %rdi,%r13
  mov    %rsi,%r12
L6:
  movq   %rbx,%xmm0
  call   *%r13
  movq   %xmm0,%rbp
  movq   %rbx,%xmm0
  call   *%r12
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm1
  movq   %rbp,%xmm0
  divsd  %xmm2,%xmm0
  movq   %rbx,%xmm3
  subsd  %xmm0,%xmm3
  movq   %xmm3,%rbx
  movapd %xmm3,%xmm0
  subsd  %xmm1,%xmm0
  andpd  D3(%rip),%xmm0
  movq   %r14,%xmm4
  comisd %xmm0,%xmm4
  jbe    L6
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: qword[2]

tool: {"D3": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double newton(double x0, double epsilon, double (*f)(double), double (*fprim)(double)) {
  double x_pre, x;
  x_pre = x0;
  for (;;) {
    x = x_pre - f(x_pre) * 1.0 / fprim(x_pre);
    if (fabs(x - x_pre) < epsilon)
      break;
    x_pre = x;
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<newton>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm2
  movq   %xmm1,%r14
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   *%rbp
  movsd  (%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   *%rbx
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm2
  movq   %r14,%xmm5
  divsd  %xmm0,%xmm3
  movapd %xmm2,%xmm1
  subsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  andpd  D8(%rip),%xmm0
  comisd %xmm0,%xmm5
  jbe    L2
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: qword[2]

tool: {"D8": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double newton(double x0, double epsilon, double (*f)(double), double (*fprim)(double)) {
  double x_pre, x;
  x_pre = x0;
  for (;;) {
    x = x_pre - f(x_pre) * 1.0 / fprim(x_pre);
    if (fabs(x - x_pre) < epsilon)
      break;
    x_pre = x;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<newton>:
  endbr64
  push   %r14
  movapd %xmm0,%xmm2
  movq   %xmm1,%r14
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   *%rbp
  movsd  (%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   *%rbx
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm2
  movq   %r14,%xmm5
  divsd  %xmm0,%xmm3
  movapd %xmm2,%xmm1
  subsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  andpd  D1(%rip),%xmm0
  comisd %xmm0,%xmm5
  jbe    L0
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: qword[2]

tool: {"D1": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double newton(double x0, double epsilon, double (*f)(double), double (*fprim)(double)) {
  double x_pre, x;
  x_pre = x0;
  for (;;) {
    x = x_pre - f(x_pre) * 1.0 / fprim(x_pre);
    if (fabs(x - x_pre) < epsilon)
      break;
    x_pre = x;
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<fftw_find_generator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x58(%rbp)
  cmpl   $0x2,-0x64(%rbp)
  jne    L41
  mov    $0x1,%eax
  jmp    L2
L41:
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_prime_factors@plt>
  mov    %eax,-0x54(%rbp)
  movl   $0x2,-0x60(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L6
L9:
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%ecx
  mov    -0x58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ecx
  mov    -0x64(%rbp),%edx
  mov    -0x60(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fftw_power_mod@plt>
  cmp    $0x1,%eax
  jne    L19
  movl   $0xffffffff,-0x5c(%rbp)
  addl   $0x1,-0x60(%rbp)
L19:
  addl   $0x1,-0x5c(%rbp)
L6:
  mov    -0x5c(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L9
  mov    -0x60(%rbp),%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int fftw_find_generator(int p) {
  int n, i, size;
  int primef[16];
  int pm1 = p - 1;
  if (p == 2)
    return 1;
  size = get_prime_factors(pm1, primef);
  n = 2;
  for (i = 0; i < size; i++)
    if (fftw_power_mod(n, pm1 / primef[i], p) == 1) {
      i = -1;
      n++;
    }
  return n;
}
```