ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exit_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <error@plt>
  mov    $0x45,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: unexpected null pointer. Out of memory?


assistant: ```c
void exit_if_null(void *ptr) {
  if (ptr == NULL) {
    error("unexpected null pointer. Out of memory?\n");
    exit(69);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exit_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <error@plt>
  mov    $0x45,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: unexpected null pointer. Out of memory?


assistant: ```c
void exit_if_null(void *ptr) {
  if (ptr == NULL) {
    error("unexpected null pointer. Out of memory?\n");
    exit(69);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<exit_if_null>:
  endbr64
  test   %rdi,%rdi
  je     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <error@plt>
  mov    $0x45,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: unexpected null pointer. Out of memory?


assistant: ```c
void exit_if_null(void *ptr) {
  if (ptr == NULL) {
    error("unexpected null pointer. Out of memory?\n");
    exit(69);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
void *f(void) {
  void *r;
  r = (long unsigned int)(void *)0;
  return (long unsigned int)(void *)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *f(void) {
  void *r;
  r = (long unsigned int)(void *)0;
  return (long unsigned int)(void *)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *f(void) {
  void *r;
  r = (long unsigned int)(void *)0;
  return (long unsigned int)(void *)0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  mov    %rax,(%rsp)
  lea    D41(%rip),%r12
  mov    %rsp,%rbp
  lea    D23(%rip),%rbx
L62:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  pxor   %xmm7,%xmm7
  comisd %xmm2,%xmm7
  ja     L62
  movsd  D54(%rip),%xmm0
  comisd %xmm2,%xmm0
  jb     L66
  mov    $0x2,%eax
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm5
  jmp    L7
L51:
  add    $0x1,%rax
  comisd %xmm2,%xmm3
  jb     L65
L7:
  lea    -0x1(%rax),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  mulsd  %xmm1,%xmm0
  movapd %xmm5,%xmm3
  divsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm4
  mov    %eax,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm5,%xmm6
  divsd  %xmm1,%xmm6
  comisd %xmm6,%xmm2
  jbe    L51
L65:
  movapd %xmm4,%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  mov    $0x1,%ebx
  movsd  D54(%rip),%xmm4
  jmp    L65
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D36
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D41
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D54
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D41: Please enter a positive decimal number (to represent how precise you want e to be approximated): 

tool: D23: %lf

tool: D54: 1

tool: D13: this is the value of e: %.15lf 


tool: D25: Number of terms required to read this value: %d 


assistant: ```c
int main(void) {
  double accuracy = -1;
  double eVal = 1;
  double fact = 1;
  long nextFact = 0;
  int numbTerms = 1;
  bool loopChecker = true;
  while (accuracy < 0) {
    printf("Please enter a positive decimal number (to represent how precise you want e to be approximated): \n");
    scanf("%lf", &accuracy);
  }
  while ((1 / fact >= accuracy) && (loopChecker == true)) {
    nextFact = nextFact + 1;
    fact = fact * nextFact;
    eVal = eVal + (1 / fact);
    numbTerms++;
    if (1 / (fact * (nextFact + 1)) < accuracy) {
      loopChecker = false;
    }
  }
  printf("this is the value of e: %.15lf \n", eVal);
  printf("Number of terms required to read this value: %d \n", numbTerms);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D59(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rbx
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  pxor   %xmm6,%xmm6
  comisd %xmm2,%xmm6
  ja     L21
  movsd  D17(%rip),%xmm3
  mov    $0x2,%eax
  mov    $0x1,%edx
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm4
  nopl   0x0(%rax)
L2:
  movapd %xmm3,%xmm1
  mov    %edx,%ebp
  divsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  jb     L3
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm5
  mov    %eax,%ebp
  cvtsi2sd %rdx,%xmm1
  add    $0x1,%rdx
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm1
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm4
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  add    $0x1,%rax
  mulsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm2
  jbe    L2
L3:
  lea    D53(%rip),%rdi
  movapd %xmm4,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D59
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D17
data_type: f64
name: extract_symbolic_data
arguments: tag: D53
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D5: Please enter a positive decimal number (to represent how precise you want e to be approximated): 

tool: D59: %lf

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D17: 1

tool: D53: this is the value of e: %.15lf 


tool: D1: Number of terms required to read this value: %d 


assistant: ```c
int main(void) {
  double accuracy = -1;
  double eVal = 1;
  double fact = 1;
  long nextFact = 0;
  int numbTerms = 1;
  bool loopChecker = true;
  while (accuracy < 0) {
    printf("Please enter a positive decimal number (to represent how precise you want e to be approximated): \n");
    scanf("%lf", &accuracy);
  }
  while ((1 / fact >= accuracy) && (loopChecker == true)) {
    nextFact = nextFact + 1;
    fact = fact * nextFact;
    eVal = eVal + (1 / fact);
    numbTerms++;
    if (1 / (fact * (nextFact + 1)) < accuracy) {
      loopChecker = false;
    }
  }
  printf("this is the value of e: %.15lf \n", eVal);
  printf("Number of terms required to read this value: %d \n", numbTerms);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  lea    D53(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D42(%rip),%rax
  mov    %rsp,%rbx
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  pxor   %xmm6,%xmm6
  comisd %xmm2,%xmm6
  ja     L10
  movsd  D13(%rip),%xmm3
  mov    $0x2,%eax
  mov    $0x1,%edx
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm4
  nopl   0x0(%rax)
L6:
  movapd %xmm3,%xmm1
  mov    %edx,%ebp
  divsd  %xmm0,%xmm1
  comisd %xmm2,%xmm1
  jb     L3
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm5
  mov    %eax,%ebp
  cvtsi2sd %rdx,%xmm1
  add    $0x1,%rdx
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm1
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm4
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  add    $0x1,%rax
  mulsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm5
  comisd %xmm5,%xmm2
  jbe    L6
L3:
  lea    D52(%rip),%rdi
  movapd %xmm4,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D53
type_guessed: string
name: disassemble_data
arguments: label: D42
type_guessed: byte[8]
name: disassemble_data
arguments: label: D13
type_guessed: f64
name: disassemble_data
arguments: label: D52
type_guessed: string
name: disassemble_data
arguments: label: D58
type_guessed: string

tool: D10: Please enter a positive decimal number (to represent how precise you want e to be approximated): 

tool: D53: %lf

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D13: 1

tool: D52: this is the value of e: %.15lf 


tool: D58: Number of terms required to read this value: %d 


assistant: ```c
int main(void) {
  double accuracy = -1;
  double eVal = 1;
  double fact = 1;
  long nextFact = 0;
  int numbTerms = 1;
  bool loopChecker = true;
  while (accuracy < 0) {
    printf("Please enter a positive decimal number (to represent how precise you want e to be approximated): \n");
    scanf("%lf", &accuracy);
  }
  while ((1 / fact >= accuracy) && (loopChecker == true)) {
    nextFact = nextFact + 1;
    fact = fact * nextFact;
    eVal = eVal + (1 / fact);
    numbTerms++;
    if (1 / (fact * (nextFact + 1)) < accuracy) {
      loopChecker = false;
    }
  }
  printf("this is the value of e: %.15lf \n", eVal);
  printf("Number of terms required to read this value: %d \n", numbTerms);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<bitOperation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x20(%rbp)
  movl   $0xc,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  and    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  not    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  xor    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  or     -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  mov    $0x78,%edi
  call   <printInt@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x79,%edi
  call   <printInt@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x7a,%edi
  call   <printInt@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x76,%edi
  call   <printInt@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  mov    $0x62,%edi
  call   <printInt@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6e,%edi
  call   <printInt@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6d,%edi
  call   <printInt@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  nop
  leave
  ret
```

assistant: ```c
void bitOperation() {
  int x = 10;
  int y = 12;
  int z = x & y;
  int v = ~x;
  int b = x ^ y;
  int n = x | y;
  int m = x << 3;
  int l = x >> 3;
  printInt('x', x);
  printInt('y', y);
  printInt('z', z);
  printInt('v', v);
  printInt('b', b);
  printInt('n', n);
  printInt('m', m);
  printInt('l', l);
  printInt('l', l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitOperation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  mov    $0x78,%edi
  call   <printInt@plt>
  mov    $0xc,%esi
  mov    $0x79,%edi
  call   <printInt@plt>
  mov    $0x8,%esi
  mov    $0x7a,%edi
  call   <printInt@plt>
  mov    $0xfffffff5,%esi
  mov    $0x76,%edi
  call   <printInt@plt>
  mov    $0x6,%esi
  mov    $0x62,%edi
  call   <printInt@plt>
  mov    $0xe,%esi
  mov    $0x6e,%edi
  call   <printInt@plt>
  mov    $0x50,%esi
  mov    $0x6d,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bitOperation() {
  int x = 10;
  int y = 12;
  int z = x & y;
  int v = ~x;
  int b = x ^ y;
  int n = x | y;
  int m = x << 3;
  int l = x >> 3;
  printInt('x', x);
  printInt('y', y);
  printInt('z', z);
  printInt('v', v);
  printInt('b', b);
  printInt('n', n);
  printInt('m', m);
  printInt('l', l);
  printInt('l', l);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitOperation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  mov    $0x78,%edi
  call   <printInt@plt>
  mov    $0xc,%esi
  mov    $0x79,%edi
  call   <printInt@plt>
  mov    $0x8,%esi
  mov    $0x7a,%edi
  call   <printInt@plt>
  mov    $0xfffffff5,%esi
  mov    $0x76,%edi
  call   <printInt@plt>
  mov    $0x6,%esi
  mov    $0x62,%edi
  call   <printInt@plt>
  mov    $0xe,%esi
  mov    $0x6e,%edi
  call   <printInt@plt>
  mov    $0x50,%esi
  mov    $0x6d,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  add    $0x8,%rsp
  jmp    1050 <printInt@plt>
```

assistant: ```c
void bitOperation() {
  int x = 10;
  int y = 12;
  int z = x & y;
  int v = ~x;
  int b = x ^ y;
  int n = x | y;
  int m = x << 3;
  int l = x >> 3;
  printInt('x', x);
  printInt('y', y);
  printInt('z', z);
  printInt('v', v);
  printInt('b', b);
  printInt('n', n);
  printInt('m', m);
  printInt('l', l);
  printInt('l', l);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitOperation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  mov    $0x78,%edi
  call   <printInt@plt>
  mov    $0xc,%esi
  mov    $0x79,%edi
  call   <printInt@plt>
  mov    $0x8,%esi
  mov    $0x7a,%edi
  call   <printInt@plt>
  mov    $0xfffffff5,%esi
  mov    $0x76,%edi
  call   <printInt@plt>
  mov    $0x6,%esi
  mov    $0x62,%edi
  call   <printInt@plt>
  mov    $0xe,%esi
  mov    $0x6e,%edi
  call   <printInt@plt>
  mov    $0x50,%esi
  mov    $0x6d,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  call   <printInt@plt>
  mov    $0x1,%esi
  mov    $0x6c,%edi
  add    $0x8,%rsp
  jmp    1050 <printInt@plt>
```

assistant: ```c
void bitOperation() {
  int x = 10;
  int y = 12;
  int z = x & y;
  int v = ~x;
  int b = x ^ y;
  int n = x | y;
  int m = x << 3;
  int l = x >> 3;
  printInt('x', x);
  printInt('y', y);
  printInt('z', z);
  printInt('v', v);
  printInt('b', b);
  printInt('n', n);
  printInt('m', m);
  printInt('l', l);
  printInt('l', l);
}
```
user: What is the c source code of the assembly code below?

```asm
<cbm_upload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x4c(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8d,-0x50(%rbp)
  mov    %al,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L8
L26:
  movsbl -0x48(%rbp),%ecx
  mov    -0x44(%rbp),%eax
  mov    $0xf,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cbm_listen@plt>
  mov    -0x50(%rbp),%eax
  sub    -0x38(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x20,-0x3c(%rbp)
  jle    L20
  movl   $0x20,-0x3c(%rbp)
L20:
  mov    -0x4c(%rbp),%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4c(%rbp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  mov    -0x3c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%r8d
  mov    %esi,%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x4c(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x58(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rax,-0x58(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x34(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <cbm_unlisten@plt>
  addl   $0x20,-0x38(%rbp)
L8:
  mov    -0x38(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L26
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: M-W%c%c%c

assistant: ```c
int cbm_upload(int f, __u_char dev, int adr, __u_char *prog, int size) {
  int c, i, rv = 0;
  char cmd[40];
  for (i = 0; i < size; i += 32) {
    cbm_listen(f, dev, 15);
    c = size - i;
    if (c > 32)
      c = 32;
    sprintf(cmd, "M-W%c%c%c", adr % 256, adr / 256, c);
    adr += c;
    write(f, cmd, 6);
    write(f, prog, c);
    prog += c;
    rv += c;
    cbm_unlisten(f);
  }
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cbm_upload>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %sil,0xb(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L6
  mov    %edi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r14
  mov    %r8d,%r12d
  lea    -0x20(%r8),%eax
  sub    $0x1,%r8d
  and    $0xffffffe0,%r8d
  sub    %r8d,%eax
  mov    %eax,0xc(%rsp)
  movl   $0x0,0x4(%rsp)
L24:
  movsbl 0xb(%rsp),%esi
  mov    $0xf,%edx
  mov    %r13d,%edi
  call   <cbm_listen@plt>
  mov    $0x20,%ebx
  cmp    %ebx,%r12d
  cmovle %r12d,%ebx
  lea    0xff(%rbp),%ecx
  test   %ebp,%ebp
  cmovns %ebp,%ecx
  sar    $0x8,%ecx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  shr    $0x18,%eax
  lea    0x0(%rbp,%rax,1),%edx
  movzbl %dl,%edx
  sub    %eax,%edx
  lea    0x10(%rsp),%r15
  mov    %ebx,%r8d
  lea    D5(%rip),%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  add    %ebx,%ebp
  mov    $0x6,%edx
  mov    %r15,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  movslq %ebx,%rax
  add    %rax,%r14
  add    %ebx,0x4(%rsp)
  mov    %r13d,%edi
  call   <cbm_unlisten@plt>
  sub    $0x20,%r12d
  cmp    0xc(%rsp),%r12d
  jne    L24
L10:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    0x4(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  movl   $0x0,0x4(%rsp)
  jmp    L10
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: M-W%c%c%c

assistant: ```c
int cbm_upload(int f, __u_char dev, int adr, __u_char *prog, int size) {
  int c, i, rv = 0;
  char cmd[40];
  for (i = 0; i < size; i += 32) {
    cbm_listen(f, dev, 15);
    c = size - i;
    if (c > 32)
      c = 32;
    sprintf(cmd, "M-W%c%c%c", adr % 256, adr / 256, c);
    adr += c;
    write(f, cmd, 6);
    write(f, prog, c);
    prog += c;
    rv += c;
    cbm_unlisten(f);
  }
  return rv;
}
```
user: What is the c source code of the assembly code below?

```asm
<cbm_upload>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L12
  movsbl %sil,%eax
  mov    %edx,%r15d
  lea    -0x20(%r8),%edx
  mov    %edi,%ebx
  mov    %eax,0xc(%rsp)
  lea    -0x1(%r8),%eax
  mov    %rcx,%rbp
  mov    %r8d,%r14d
  and    $0xffffffe0,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x10(%rsp),%r13
  sub    %eax,%edx
  mov    %edx,0x8(%rsp)
  nopl   0x0(%rax)
L26:
  mov    0xc(%rsp),%esi
  mov    $0xf,%edx
  mov    %ebx,%edi
  call   <cbm_listen@plt>
  mov    $0x20,%r8d
  mov    %r15d,%eax
  lea    0xff(%r15),%ecx
  cmp    %r8d,%r14d
  lea    D3(%rip),%rsi
  mov    %r13,%rdi
  cmovle %r14d,%r8d
  test   %r15d,%r15d
  cmovns %r15d,%ecx
  sar    $0x1f,%eax
  sub    $0x20,%r14d
  shr    $0x18,%eax
  mov    %r8d,%r12d
  lea    (%r15,%rax,1),%edx
  sar    $0x8,%ecx
  add    %r12d,%r15d
  movzbl %dl,%edx
  sub    %eax,%edx
  call   <sprintf@plt>
  mov    $0x6,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %ebx,%edi
  call   <write@plt>
  movslq %r12d,%rax
  mov    %ebx,%edi
  add    %r12d,0x4(%rsp)
  add    %rax,%rbp
  call   <cbm_unlisten@plt>
  cmp    0x8(%rsp),%r14d
  jne    L26
L10:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    0x4(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  movl   $0x0,0x4(%rsp)
  jmp    L10
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: M-W%c%c%c

assistant: ```c
int cbm_upload(int f, __u_char dev, int adr, __u_char *prog, int size) {
  int c, i, rv = 0;
  char cmd[40];
  for (i = 0; i < size; i += 32) {
    cbm_listen(f, dev, 15);
    c = size - i;
    if (c > 32)
      c = 32;
    sprintf(cmd, "M-W%c%c%c", adr % 256, adr / 256, c);
    adr += c;
    write(f, cmd, 6);
    write(f, prog, c);
    prog += c;
    rv += c;
    cbm_unlisten(f);
  }
  return rv;
}
```