user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  jmp    L24
L23:
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L23
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L14
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L40
L14:
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L40
L1:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L40:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D65
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D56
data_type: string
name: extract_symbolic_data
arguments: label: D57
data_type: string
name: extract_symbolic_data
arguments: label: D63
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string

tool: D65: Enter the number

tool: D9: %d

tool: D13:  No. of digit is  %d


tool: D56:  No. in Reverse order is  %d


tool: D57: The given No. is a penindrome number

tool: D63: The given No. is  not a penindrome number

tool: D19: No. of digits is 1

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b = 0, c, count1 = 0, count = 0;
  printf("Enter the number");
  scanf("%d", &a);
  if (c = a) {
    while (a != 0) {
      b = b * 10 + a % 10;
      a = a / 10;
      count1 = count1 + 1;
    }
    printf(" No. of digit is  %d\n", count1);
    printf(" No. in Reverse order is  %d\n", b);
    if (c == b)
      printf("The given No. is a penindrome number\n");
    else
      printf("The given No. is  not a penindrome number\n");
  } else
    printf("No. of digits is 1\n");
  return 0;
}
```