ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    (%r8),%edx
  sub    $0x17447d68,%edx
  mov    %edx,%eax
  jne    L2
  xor    %ax,%ax
  add    %eax,%eax
  add    $0x5dc2c1a0,%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L2:
  mov    %edx,%ecx
  shl    $0x4,%ecx
  movzbl %cl,%ecx
  or     %edx,%ecx
  movzbl %dh,%edx
  mov    %ecx,%eax
  mov    %ecx,%esi
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  shl    $0x8,%esi
  or     %edx,%eax
  sar    $0x18,%esi
  xor    %edx,%edx
  mov    %sil,%dl
  mov    %cl,%dh
  mov    %dx,%ax
  add    $0x5dc2c1a0,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] == local2 * local1) {
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] += state[0UL];
        } else {
          state[local2] |= ((state[local1] + state[local2]) & 31U) << 3UL;
          copy12 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 2721922656U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unit_uses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int unit_uses(int count, int cvalue) {
  int total_unit;
  total_unit = 15 * count + cvalue;
  return total_unit;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unit_uses>:
  endbr64
  mov    %edi,%eax
  shl    $0x4,%eax
  sub    %edi,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int unit_uses(int count, int cvalue) {
  int total_unit;
  total_unit = 15 * count + cvalue;
  return total_unit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unit_uses>:
  endbr64
  mov    %edi,%eax
  shl    $0x4,%eax
  sub    %edi,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int unit_uses(int count, int cvalue) {
  int total_unit;
  total_unit = 15 * count + cvalue;
  return total_unit;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unit_uses>:
  endbr64
  mov    %edi,%eax
  shl    $0x4,%eax
  sub    %edi,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int unit_uses(int count, int cvalue) {
  int total_unit;
  total_unit = 15 * count + cvalue;
  return total_unit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <string_compress@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: abc  efg   hij

assistant: ```c
void main() {
  const char *str = "abc  efg   hij";
  string_compress(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <string_compress@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: abc  efg   hij

assistant: ```c
void main() {
  const char *str = "abc  efg   hij";
  string_compress(str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <string_compress@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: abc  efg   hij

assistant: ```c
void main() {
  const char *str = "abc  efg   hij";
  string_compress(str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <string_compress@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: abc  efg   hij

assistant: ```c
void main() {
  const char *str = "abc  efg   hij";
  string_compress(str);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sweep_dobldobl_complex_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x38(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x2,-0x54(%rbp)
  jne    L17
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x60(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x68(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x68(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L17:
  lea    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x26c,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int sweep_dobldobl_complex_run(int gchoice, double *regamma, double *imgamma) {
  int fail;
  int pg[2];
  int *b;
  double c[4];
  pg[0] = 1;
  pg[1] = gchoice;
  if (gchoice == 2) {
    c[0] = regamma[0];
    c[1] = regamma[1];
    c[2] = imgamma[0];
    c[3] = imgamma[1];
  }
  fail = _ada_use_c2phc4c(620, pg, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sweep_dobldobl_complex_run>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  mov    %edi,0xc(%rsp)
  cmp    $0x2,%edi
  je     L15
L16:
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x26c,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x48,%rsp
  ret
L15:
  movsd  (%rsi),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x28(%rsp)
  jmp    L16
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_dobldobl_complex_run(int gchoice, double *regamma, double *imgamma) {
  int fail;
  int pg[2];
  int *b;
  double c[4];
  pg[0] = 1;
  pg[1] = gchoice;
  if (gchoice == 2) {
    c[0] = regamma[0];
    c[1] = regamma[1];
    c[2] = imgamma[0];
    c[3] = imgamma[1];
  }
  fail = _ada_use_c2phc4c(620, pg, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sweep_dobldobl_complex_run>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  mov    %edi,0xc(%rsp)
  cmp    $0x2,%edi
  jne    L1
  movsd  (%rsi),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rsi),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  (%rdx),%xmm0
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x28(%rsp)
L1:
  xor    %r8d,%r8d
  xor    %edx,%edx
  lea    0x10(%rsp),%rcx
  mov    $0x26c,%edi
  lea    0x8(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x48,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_dobldobl_complex_run(int gchoice, double *regamma, double *imgamma) {
  int fail;
  int pg[2];
  int *b;
  double c[4];
  pg[0] = 1;
  pg[1] = gchoice;
  if (gchoice == 2) {
    c[0] = regamma[0];
    c[1] = regamma[1];
    c[2] = imgamma[0];
    c[3] = imgamma[1];
  }
  fail = _ada_use_c2phc4c(620, pg, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sweep_dobldobl_complex_run>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  mov    %edi,0xc(%rsp)
  cmp    $0x2,%edi
  jne    L13
  movupd (%rsi),%xmm0
  movupd (%rdx),%xmm1
  movaps %xmm0,0x10(%rsp)
  movaps %xmm1,0x20(%rsp)
L13:
  xor    %r8d,%r8d
  xor    %edx,%edx
  lea    0x10(%rsp),%rcx
  mov    $0x26c,%edi
  lea    0x8(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x48,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sweep_dobldobl_complex_run(int gchoice, double *regamma, double *imgamma) {
  int fail;
  int pg[2];
  int *b;
  double c[4];
  pg[0] = 1;
  pg[1] = gchoice;
  if (gchoice == 2) {
    c[0] = regamma[0];
    c[1] = regamma[1];
    c[2] = imgamma[0];
    c[3] = imgamma[1];
  }
  fail = _ada_use_c2phc4c(620, pg, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tree_track_get_prev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <tree_album_selected@plt>
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_track_get_prev_by_album@plt>
  jmp    L0
L3:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_track_get_prev_by_artist@plt>
L0:
  leave
  ret
```

assistant: ```c
int tree_track_get_prev(struct iter *iter) {
  if (tree_album_selected())
    return tree_track_get_prev_by_album(iter);
  else
    return tree_track_get_prev_by_artist(iter);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tree_track_get_prev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <tree_album_selected@plt>
  test   %rax,%rax
  je     L19
  mov    %rbx,%rdi
  call   <tree_track_get_prev_by_album@plt>
L13:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <tree_track_get_prev_by_artist@plt>
  jmp    L13
```

assistant: ```c
int tree_track_get_prev(struct iter *iter) {
  if (tree_album_selected())
    return tree_track_get_prev_by_album(iter);
  else
    return tree_track_get_prev_by_artist(iter);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tree_track_get_prev>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <tree_album_selected@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L2
  pop    %rbp
  jmp    1070 <tree_track_get_prev_by_album@plt>
  nopl   (%rax)
L2:
  pop    %rbp
  jmp    1080 <tree_track_get_prev_by_artist@plt>
```

assistant: ```c
int tree_track_get_prev(struct iter *iter) {
  if (tree_album_selected())
    return tree_track_get_prev_by_album(iter);
  else
    return tree_track_get_prev_by_artist(iter);
}
```
user: What is the c source code of the assembly code below?

```asm
<tree_track_get_prev>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <tree_album_selected@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L1
  pop    %rbp
  jmp    1070 <tree_track_get_prev_by_album@plt>
  nopl   (%rax)
L1:
  pop    %rbp
  jmp    1080 <tree_track_get_prev_by_artist@plt>
```

assistant: ```c
int tree_track_get_prev(struct iter *iter) {
  if (tree_album_selected())
    return tree_track_get_prev_by_album(iter);
  else
    return tree_track_get_prev_by_artist(iter);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<volatile_fetch_and_u64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t volatile_fetch_and_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<volatile_fetch_and_u64>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint64_t volatile_fetch_and_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<volatile_fetch_and_u64>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint64_t volatile_fetch_and_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<volatile_fetch_and_u64>:
  endbr64
  mov    %esi,-0x14(%rsp)
  mov    (%rdi),%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    -0x14(%rsp),%edx
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint64_t volatile_fetch_and_u64(volatile uint64_t *dest, uint64_t val) {
  uint64_t result = *dest;
  *dest = result & val;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <string_fromlit@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printstring@plt>
  jmp    L10
L9:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <Writer_io_write@plt>
L10:
  mov    $0x0,%edi
  call   <Reader_io_read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xa,-0xc(%rbp)
  jne    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: Type some data and press enter: 

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  struct String *s;
  s = string_fromlit("Type some data and press enter: ");
  printstring(s);
  while ((c = Reader_io_read(0)) != '\n') {
    Writer_io_write(0, c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <string_fromlit@plt>
  mov    %rax,%rdi
  call   <printstring@plt>
  jmp    L5
L7:
  mov    $0x0,%edi
  call   <Writer_io_write@plt>
L5:
  mov    $0x0,%edi
  call   <Reader_io_read@plt>
  mov    %eax,%esi
  cmp    $0xa,%eax
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: Type some data and press enter: 

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  struct String *s;
  s = string_fromlit("Type some data and press enter: ");
  printstring(s);
  while ((c = Reader_io_read(0)) != '\n') {
    Writer_io_write(0, c);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <string_fromlit@plt>
  mov    %rax,%rdi
  call   <printstring@plt>
  jmp    L3
  xchg   %ax,%ax
L12:
  xor    %edi,%edi
  call   <Writer_io_write@plt>
L3:
  xor    %edi,%edi
  call   <Reader_io_read@plt>
  mov    %eax,%esi
  cmp    $0xa,%eax
  jne    L12
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: Type some data and press enter: 

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  struct String *s;
  s = string_fromlit("Type some data and press enter: ");
  printstring(s);
  while ((c = Reader_io_read(0)) != '\n') {
    Writer_io_write(0, c);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <string_fromlit@plt>
  mov    %rax,%rdi
  call   <printstring@plt>
  jmp    L18
  xchg   %ax,%ax
L5:
  xor    %edi,%edi
  call   <Writer_io_write@plt>
L18:
  xor    %edi,%edi
  call   <Reader_io_read@plt>
  mov    %eax,%esi
  cmp    $0xa,%eax
  jne    L5
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: Type some data and press enter: 

assistant: ```c
int main(int argc, char *argv[]) {
  int c;
  struct String *s;
  s = string_fromlit("Type some data and press enter: ");
  printstring(s);
  while ((c = Reader_io_read(0)) != '\n') {
    Writer_io_write(0, c);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0xa5,%eax
  movslq %eax,%rdx
  imul   $0x3159721f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D37
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string
name: unpack_data
arguments: tag: D60
data_type: string
name: unpack_data
arguments: tag: D36
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D51
data_type: string

tool: D37: Enter height of box: 

tool: D3: %d

tool: D60: Enter length of box: 

tool: D36: Enter width of box: 

tool: D16: Volume (cubic inches): %d


tool: D51: Dimensional weight (pounds): %d


assistant: ```c
int main(int argc, char **argv) {
  int height, length, width, volume, weight;
  printf("Enter height of box: ");
  scanf("%d", &height);
  printf("Enter length of box: ");
  scanf("%d", &length);
  printf("Enter width of box: ");
  scanf("%d", &width);
  volume = height * length * width;
  weight = (volume + 166 - 1) / 166;
  printf("Volume (cubic inches): %d\n", volume);
  printf("Dimensional weight (pounds): %d\n", weight);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  imul   0x10(%rsp),%ebx
  imul   0x14(%rsp),%ebx
  mov    %ebx,%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0xa5,%ebx
  movslq %ebx,%rsi
  imul   $0x3159721f,%rsi,%rsi
  sar    $0x25,%rsi
  sar    $0x1f,%ebx
  sub    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D50
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D40
type: string
name: extract_symbolic_data
arguments: tag: D43
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string

tool: D50: Enter height of box: 

tool: D26: %d

tool: D27: Enter length of box: 

tool: D40: Enter width of box: 

tool: D43: Volume (cubic inches): %d


tool: D22: Dimensional weight (pounds): %d


assistant: ```c
int main(int argc, char **argv) {
  int height, length, width, volume, weight;
  printf("Enter height of box: ");
  scanf("%d", &height);
  printf("Enter length of box: ");
  scanf("%d", &length);
  printf("Enter width of box: ");
  scanf("%d", &width);
  volume = height * length * width;
  weight = (volume + 166 - 1) / 166;
  printf("Volume (cubic inches): %d\n", volume);
  printf("Dimensional weight (pounds): %d\n", weight);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  imul   0x10(%rsp),%ebx
  xor    %eax,%eax
  imul   0x14(%rsp),%ebx
  lea    D39(%rip),%rdi
  mov    %ebx,%esi
  add    $0xa5,%ebx
  call   <printf@plt>
  movslq %ebx,%rsi
  sar    $0x1f,%ebx
  xor    %eax,%eax
  imul   $0x3159721f,%rsi,%rsi
  lea    D30(%rip),%rdi
  sar    $0x25,%rsi
  sub    %ebx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D49
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D57
data_type: string
name: disassemble_data
arguments: data_label: D59
data_type: string
name: disassemble_data
arguments: data_label: D39
data_type: string
name: disassemble_data
arguments: data_label: D30
data_type: string

tool: D49: Enter height of box: 

tool: D1: %d

tool: D57: Enter length of box: 

tool: D59: Enter width of box: 

tool: D39: Volume (cubic inches): %d


tool: D30: Dimensional weight (pounds): %d


assistant: ```c
int main(int argc, char **argv) {
  int height, length, width, volume, weight;
  printf("Enter height of box: ");
  scanf("%d", &height);
  printf("Enter length of box: ");
  scanf("%d", &length);
  printf("Enter width of box: ");
  scanf("%d", &width);
  volume = height * length * width;
  weight = (volume + 166 - 1) / 166;
  printf("Volume (cubic inches): %d\n", volume);
  printf("Dimensional weight (pounds): %d\n", weight);
  return 0;
}
```