ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  nop
  leave
  ret
```

assistant: ```c
void kputs(const char *s) {
  extern void uart_puts(const char *);
  uart_puts(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kputs>:
  endbr64
  sub    $0x8,%rsp
  call   <uart_puts@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void kputs(const char *s) {
  extern void uart_puts(const char *);
  uart_puts(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kputs>:
  endbr64
  jmp    1050 <uart_puts@plt>
```

assistant: ```c
void kputs(const char *s) {
  extern void uart_puts(const char *);
  uart_puts(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<kputs>:
  endbr64
  jmp    1050 <uart_puts@plt>
```

assistant: ```c
void kputs(const char *s) {
  extern void uart_puts(const char *);
  uart_puts(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binEval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x8(%rbp)
  movsbl -0x8(%rbp),%eax
  cmp    $0x76,%eax
  je     L77
  cmp    $0x76,%eax
  jg     L91
  cmp    $0x3e,%eax
  je     L13
  cmp    $0x5e,%eax
  je     L40
  jmp    L91
L13:
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jle    L98
  mov    $0x1,%eax
  jmp    L112
L98:
  mov    $0x0,%eax
  jmp    L112
L40:
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  jmp    L112
L77:
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jle    L61
  mov    $0x1,%eax
  jmp    L112
L61:
  mov    $0x0,%eax
  jmp    L112
L91:
  nop
  mov    $0x0,%eax
L112:
  pop    %rbp
  ret
```

assistant: ```c
int binEval(int left, char bin, int right) {
  switch (bin) {
  case '>':
    if (!left + right >= 1)
      return 1;
    else
      return 0;
  case '^':
    return left * right;
  case 'v':
    if (left + right >= 1)
      return 1;
    else
      return 0;
  default:
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binEval>:
  endbr64
  cmp    $0x5e,%sil
  je     L5
  cmp    $0x76,%sil
  je     L34
  mov    $0x0,%eax
  cmp    $0x3e,%sil
  je     L19
L6:
  ret
L19:
  cmp    $0x1,%edi
  adc    $0x0,%edx
  test   %edx,%edx
  setg   %al
  movzbl %al,%eax
  ret
L5:
  mov    %edi,%eax
  imul   %edx,%eax
  ret
L34:
  add    %edx,%edi
  test   %edi,%edi
  setg   %al
  movzbl %al,%eax
  jmp    L6
```

assistant: ```c
int binEval(int left, char bin, int right) {
  switch (bin) {
  case '>':
    if (!left + right >= 1)
      return 1;
    else
      return 0;
  case '^':
    return left * right;
  case 'v':
    if (left + right >= 1)
      return 1;
    else
      return 0;
  default:
    break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<binEval>:
  endbr64
  cmp    $0x5e,%sil
  je     L28
  cmp    $0x76,%sil
  je     L10
  xor    %eax,%eax
  cmp    $0x3e,%sil
  je     L7
  ret
  nopl   0x0(%rax)
L7:
  cmp    $0x1,%edi
  adc    $0x0,%edx
  xor    %eax,%eax
  test   %edx,%edx
  setg   %al
  ret
  xchg   %ax,%ax
L10:
  add    %edx,%edi
  xor    %eax,%eax
  test   %edi,%edi
  setg   %al
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %edi,%eax
  imul   %edx,%eax
  ret
```

assistant: ```c
int binEval(int left, char bin, int right) {
  switch (bin) {
  case '>':
    if (!left + right >= 1)
      return 1;
    else
      return 0;
  case '^':
    return left * right;
  case 'v':
    if (left + right >= 1)
      return 1;
    else
      return 0;
  default:
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binEval>:
  endbr64
  cmp    $0x5e,%sil
  je     L27
  cmp    $0x76,%sil
  je     L20
  xor    %eax,%eax
  cmp    $0x3e,%sil
  je     L26
  ret
  nopl   0x0(%rax)
L26:
  cmp    $0x1,%edi
  adc    $0x0,%edx
  xor    %eax,%eax
  test   %edx,%edx
  setg   %al
  ret
  xchg   %ax,%ax
L20:
  add    %edx,%edi
  xor    %eax,%eax
  test   %edi,%edi
  setg   %al
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %edi,%eax
  imul   %edx,%eax
  ret
```

assistant: ```c
int binEval(int left, char bin, int right) {
  switch (bin) {
  case '>':
    if (!left + right >= 1)
      return 1;
    else
      return 0;
  case '^':
    return left * right;
  case 'v':
    if (left + right >= 1)
      return 1;
    else
      return 0;
  default:
    break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x51e22cdb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L37:
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L21:
  mov    -0xc(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  shr    %eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  rol    %cl,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0x0,-0x14(%rbp)
  je     L21
  addl   $0x1,-0x10(%rbp)
L14:
  cmpl   $0x0,-0x10(%rbp)
  je     L37
  mov    -0xc(%rbp),%eax
  ror    $0xb,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %edx,%eax
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x51e22cdb,%edx
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    %ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x4,%eax
  and    $0x1f0,%eax
  or     %edx,%eax
  ror    $0xb,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> 1U) & 15U) | 1UL)) | (state[local2] >> (32 - (((state[0UL] >> 1U) & 15U) | 1UL)))) & 31U) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 11U) | (state[0UL] << 21U);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L59
L3:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L79
  mov    D1(%rip),%rax
  mov    (%rax),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L48
  jmp    L59
L48:
  mov    $0xffffffff,%eax
  jmp    L52
L79:
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L52
L8:
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L59:
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  mov    -0x38(%rbp),%rax
L52:
  leave
  ret
```

assistant: ```c
ssize_t readn(int fd, void *buf, size_t count) {
  size_t nleft = count;
  ssize_t nread;
  char *bufp = (char *)buf;
  while (nleft > 0) {
    if ((nread = read(fd, buf, count)) < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    } else if (nread == 0) {
      return count - nleft;
    }
    nleft -= nread;
    bufp += nread;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L55
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  jmp    L40
L53:
  mov    D17(%rip),%rdx
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L74
L75:
  test   %rbx,%rbx
  je     L55
L40:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L53
  je     L28
  cltq
  sub    %rax,%rbx
  jmp    L75
L74:
  mov    $0xffffffff,%eax
  jmp    L10
L28:
  mov    %ebp,%eax
  sub    %ebx,%eax
  jmp    L10
L55:
  mov    %ebp,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(int fd, void *buf, size_t count) {
  size_t nleft = count;
  ssize_t nread;
  char *bufp = (char *)buf;
  while (nleft > 0) {
    if ((nread = read(fd, buf, count)) < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    } else if (nread == 0) {
      return count - nleft;
    }
    nleft -= nread;
    bufp += nread;
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L27
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  nop
L28:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L43
  je     L31
  cltq
  sub    %rax,%rbx
  jne    L28
L27:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    D7(%rip),%rax
  mov    D12(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L28
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  mov    %ebp,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(int fd, void *buf, size_t count) {
  size_t nleft = count;
  ssize_t nread;
  char *bufp = (char *)buf;
  while (nleft > 0) {
    if ((nread = read(fd, buf, count)) < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    } else if (nread == 0) {
      return count - nleft;
    }
    nleft -= nread;
    bufp += nread;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L47
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbx
  nop
L48:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L9
  je     L26
  cltq
  sub    %rax,%rbx
  jne    L48
L47:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    D5(%rip),%rax
  mov    D7(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L48
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  mov    %ebp,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(int fd, void *buf, size_t count) {
  size_t nleft = count;
  ssize_t nread;
  char *bufp = (char *)buf;
  while (nleft > 0) {
    if ((nread = read(fd, buf, count)) < 0) {
      if (errno == EINTR) {
        continue;
      }
      return -1;
    } else if (nread == 0) {
      return count - nleft;
    }
    nleft -= nread;
    bufp += nread;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmio_out>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  divsd  %xmm1,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  jae    L8
L0:
  mov    0x38(%rsp),%eax
  add    $0x1,%eax
  test   $0xfffffffd,%eax
  jne    L76
  mov    $0x1,%eax
  cmp    $0x1,%ebx
  jle    L92
L91:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L91
  mov    $0x1,%eax
L85:
  mov    %eax,%ecx
  add    $0x1,%eax
  cmp    %ecx,%edx
  jne    L85
  mov    $0x1,%eax
  jmp    L75
L8:
  movapd %xmm2,%xmm0
  call   <log10@plt>
  jmp    L0
L76:
  mov    $0x1,%eax
  cmp    $0x1,%ebx
  jle    L92
L75:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jg     L75
  mov    $0x1,%eax
L93:
  add    $0x1,%eax
  cmp    %eax,%ebx
  jg     L93
L92:
  mov    0x48(%rsp),%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int cmio_out(double time, double jcen[3], double rcen, double rmax, int nbod, int nbig, double *m, double **xh, double **vh, double **s, double *rho, int *stat, char **id, int opt[8], int opflag, int algor, FILE *outfile) {
  int len, nchar;
  double rhocgs, k_2, rfac, rcen_2, fr, fv, theta, phi, vtheta, vphi;
  char header[80];
  char c[2000][80];
  char mio_fl2c_out[8], mio_re2c_out[8];
  char fout[5] = {'(', 'a', ' ', ' ', ')'};
  rhocgs = 1.4959787e13 * 1.4959787e13 * 1.4959787e13 * 2.959122082855911e-4 / 1.9891e33;
  k_2 = 1.0 / 2.959122082855911e-4;
  rcen_2 = 1.0 / (rcen * rcen);
  rfac = log10(rmax / rcen);
  if (opt[3] == 1) {
    nchar = 2;
  }
  if (opt[3] == 2) {
    nchar = 4;
  }
  if (opt[3] == 3) {
    nchar = 7;
  }
  len = 3 + 6 * nchar;
  if (opflag == -1 || opflag == 1) {
    for (int k = 1; k < nbod; k++) {
    }
    for (int k = 1; k < nbod; k++) {
    }
  }
  for (int k = 1; k < nbod; k++) {
  }
  for (int k = 1; k < nbod; k++) {
  }
  fclose(outfile);
  opflag = 0;
  return opflag;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmio_out>:
  endbr64
  divsd  %xmm1,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  ucomisd %xmm2,%xmm0
  jae    L14
L12:
  mov    0x48(%rsp),%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L14:
  movapd %xmm2,%xmm0
  call   <log10@plt>
  jmp    L12
```

assistant: ```c
int cmio_out(double time, double jcen[3], double rcen, double rmax, int nbod, int nbig, double *m, double **xh, double **vh, double **s, double *rho, int *stat, char **id, int opt[8], int opflag, int algor, FILE *outfile) {
  int len, nchar;
  double rhocgs, k_2, rfac, rcen_2, fr, fv, theta, phi, vtheta, vphi;
  char header[80];
  char c[2000][80];
  char mio_fl2c_out[8], mio_re2c_out[8];
  char fout[5] = {'(', 'a', ' ', ' ', ')'};
  rhocgs = 1.4959787e13 * 1.4959787e13 * 1.4959787e13 * 2.959122082855911e-4 / 1.9891e33;
  k_2 = 1.0 / 2.959122082855911e-4;
  rcen_2 = 1.0 / (rcen * rcen);
  rfac = log10(rmax / rcen);
  if (opt[3] == 1) {
    nchar = 2;
  }
  if (opt[3] == 2) {
    nchar = 4;
  }
  if (opt[3] == 3) {
    nchar = 7;
  }
  len = 3 + 6 * nchar;
  if (opflag == -1 || opflag == 1) {
    for (int k = 1; k < nbod; k++) {
    }
    for (int k = 1; k < nbod; k++) {
    }
  }
  for (int k = 1; k < nbod; k++) {
  }
  for (int k = 1; k < nbod; k++) {
  }
  fclose(outfile);
  opflag = 0;
  return opflag;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmio_out>:
  endbr64
  divsd  %xmm1,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  ucomisd %xmm2,%xmm0
  jae    L5
L10:
  mov    0x48(%rsp),%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L5:
  movapd %xmm2,%xmm0
  call   <log10@plt>
  jmp    L10
```

assistant: ```c
int cmio_out(double time, double jcen[3], double rcen, double rmax, int nbod, int nbig, double *m, double **xh, double **vh, double **s, double *rho, int *stat, char **id, int opt[8], int opflag, int algor, FILE *outfile) {
  int len, nchar;
  double rhocgs, k_2, rfac, rcen_2, fr, fv, theta, phi, vtheta, vphi;
  char header[80];
  char c[2000][80];
  char mio_fl2c_out[8], mio_re2c_out[8];
  char fout[5] = {'(', 'a', ' ', ' ', ')'};
  rhocgs = 1.4959787e13 * 1.4959787e13 * 1.4959787e13 * 2.959122082855911e-4 / 1.9891e33;
  k_2 = 1.0 / 2.959122082855911e-4;
  rcen_2 = 1.0 / (rcen * rcen);
  rfac = log10(rmax / rcen);
  if (opt[3] == 1) {
    nchar = 2;
  }
  if (opt[3] == 2) {
    nchar = 4;
  }
  if (opt[3] == 3) {
    nchar = 7;
  }
  len = 3 + 6 * nchar;
  if (opflag == -1 || opflag == 1) {
    for (int k = 1; k < nbod; k++) {
    }
    for (int k = 1; k < nbod; k++) {
    }
  }
  for (int k = 1; k < nbod; k++) {
  }
  for (int k = 1; k < nbod; k++) {
  }
  fclose(outfile);
  opflag = 0;
  return opflag;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fgt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L17
  mov    $0xd,%eax
  jmp    L0
L17:
  mov    $0x8c,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
fgt(int x, int y) {
  if (x > y)
    return 13;
  else
    return 140;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fgt>:
  endbr64
  cmp    %esi,%edi
  mov    $0xd,%eax
  mov    $0x8c,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
fgt(int x, int y) {
  if (x > y)
    return 13;
  else
    return 140;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fgt>:
  endbr64
  cmp    %esi,%edi
  mov    $0x8c,%edx
  mov    $0xd,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
fgt(int x, int y) {
  if (x > y)
    return 13;
  else
    return 140;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fgt>:
  endbr64
  cmp    %esi,%edi
  mov    $0x8c,%edx
  mov    $0xd,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
fgt(int x, int y) {
  if (x > y)
    return 13;
  else
    return 140;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x20,-0x8(%rbp)
  jle    L24
  mov    $0x0,%eax
  jmp    L17
L24:
  cmpl   $0x10,-0x8(%rbp)
  jle    L14
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x10(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L9
  mov    $0x0,%eax
  jmp    L17
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  jmp    L17
L14:
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %llx

assistant: ```c
int read_128(char *s, uint64_t *v) {
  int l, t;
  char save;
  l = strlen(s);
  if (l > 32)
    return 0;
  if (l > 16) {
    if (sscanf(s + (l - 16), "%llx", (long long unsigned int *)&(v[1])) == 0)
      return 0;
    save = s[l - 16];
    s[l - 16] = '\0';
    t = sscanf(s, "%llx", (long long unsigned int *)&(v[0]));
    s[l - 16] = save;
    return t;
  } else {
    v[0] = 0;
    return sscanf(s, "%llx", (long long unsigned int *)&(v[1]));
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_128>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    $0x20,%eax
  jg     L39
  cmp    $0x10,%eax
  jle    L10
  cltq
  lea    -0x10(%rbx,%rax,1),%r12
  lea    0x8(%rbp),%rdx
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <sscanf@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L33
L39:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  movzbl (%r12),%r13d
  movb   $0x0,(%r12)
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    %eax,%edx
  mov    %r13b,(%r12)
  jmp    L39
L10:
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rbp),%rdx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    %eax,%edx
  jmp    L39
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %llx

assistant: ```c
int read_128(char *s, uint64_t *v) {
  int l, t;
  char save;
  l = strlen(s);
  if (l > 32)
    return 0;
  if (l > 16) {
    if (sscanf(s + (l - 16), "%llx", (long long unsigned int *)&(v[1])) == 0)
      return 0;
    save = s[l - 16];
    s[l - 16] = '\0';
    t = sscanf(s, "%llx", (long long unsigned int *)&(v[0]));
    s[l - 16] = save;
    return t;
  } else {
    v[0] = 0;
    return sscanf(s, "%llx", (long long unsigned int *)&(v[1]));
  }
  return 1;
}
```