ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r12
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <scanf@plt>
  jmp    L10
  nop
L11:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L33
L10:
  mov    0x8(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L11
  cmp    $0x1,%ecx
  jle    L7
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  lea    D7(%rip),%rbx
L44:
  sub    %ebp,%ecx
  mov    (%r12,%rbp,4),%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  sub    $0x1,%ecx
  movslq %ecx,%rcx
  sub    0x10(%rsp,%rcx,4),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %ebp,%eax
  jg     L44
L64:
  and    $0x1,%ecx
  jne    L56
L99:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %edx,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  jmp    L10
L56:
  cltq
  lea    D7(%rip),%rdi
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  jmp    L99
L7:
  mov    %ecx,%eax
  mov    $0x2,%esi
  cltd
  idiv   %esi
  jmp    L64
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D19: %d

tool: D7: %d


assistant: ```c
int main() {
  int n = 0, i = 0, j = 0, e = 0;
  scanf("%d", &n);
  int shot[100];
  for (i = 0; i < n;) {
    scanf("%d", &e);
    if (e % 2 == 1) {
      shot[i] = e;
      i++;
    }
  }
  for (i = 0; i < n / 2; i++) {
    j = shot[i] - shot[n - i - 1];
    printf("%d\n", j);
  }
  if (n % 2 != 0) {
    printf("%d\n", shot[n / 2]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pr2899>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L3:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x63,-0xc(%rbp)
  jbe    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void pr2899() {
  char *foo = malloc(0);
  for (unsigned i = 0; i < 100; i++) {
    foo[i] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pr2899>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <malloc@plt>
  lea    0x64(%rax),%rdx
L3:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pr2899() {
  char *foo = malloc(0);
  for (unsigned i = 0; i < 100; i++) {
    foo[i] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pr2899>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <malloc@plt>
  lea    0x8(%rax),%rdi
  movq   $0x0,(%rax)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x5c(%rax)
  sub    %rdi,%rax
  lea    0x64(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pr2899() {
  char *foo = malloc(0);
  for (unsigned i = 0; i < 100; i++) {
    foo[i] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pr2899>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <malloc@plt>
  lea    0x8(%rax),%rdi
  movq   $0x0,(%rax)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x5c(%rax)
  sub    %rdi,%rax
  lea    0x64(%rax),%ecx
  xor    %eax,%eax
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pr2899() {
  char *foo = malloc(0);
  for (unsigned i = 0; i < 100; i++) {
    foo[i] = 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x3,%eax
  ja     L16
  mov    $0x1,%eax
  jmp    L7
L16:
  nop
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
  case EINTR:
  case EAGAIN:
  case EINPROGRESS:
  case EALREADY:
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x3,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
  case EINTR:
  case EAGAIN:
  case EINPROGRESS:
  case EALREADY:
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x3,%edi
  setbe  %al
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
  case EINTR:
  case EAGAIN:
  case EINPROGRESS:
  case EALREADY:
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<BIO_dgram_non_fatal_error>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x3,%edi
  setbe  %al
  ret
```

assistant: ```c
int BIO_dgram_non_fatal_error(int err) {
  switch (err) {
  case EINTR:
  case EAGAIN:
  case EINPROGRESS:
  case EALREADY:
    return (1);
  default:
    break;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrusage@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L21
L7:
  addl   $0x1,-0x54(%rbp)
L21:
  cmpl   $0x3e7,-0x54(%rbp)
  jle    L7
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrusage@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x50(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x50(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jne    L38
  mov    -0x48(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L38:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int main() {
  struct rusage ru1;
  getrusage(RUSAGE_SELF, &ru1);
  for (int i = 0; i < 1000; i++) {
  }
  struct rusage ru2;
  getrusage(RUSAGE_SELF, &ru2);
  long long s1 = ru1.ru_utime.tv_sec;
  long long us1 = ru1.ru_utime.tv_usec;
  long long s2 = ru2.ru_utime.tv_sec;
  long long us2 = ru2.ru_utime.tv_usec;
  assert(s1 <= s2);
  if (s1 == s2) {
    assert(us1 < us2);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <getrusage@plt>
  mov    $0x3e8,%eax
L24:
  sub    $0x1,%eax
  jne    L24
  lea    0x10(%rsp),%rsi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <getrusage@plt>
  mov    (%rsp),%rbp
  mov    0x8(%rsp),%r13
  mov    0x10(%rsp),%rbx
  mov    0x18(%rsp),%r12
  cmp    %rbx,%rbp
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %rbx,%rbp
  je     L15
L33:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  cmp    %r12,%r13
  setl   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L33
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct rusage ru1;
  getrusage(RUSAGE_SELF, &ru1);
  for (int i = 0; i < 1000; i++) {
  }
  struct rusage ru2;
  getrusage(RUSAGE_SELF, &ru2);
  long long s1 = ru1.ru_utime.tv_sec;
  long long us1 = ru1.ru_utime.tv_usec;
  long long s2 = ru2.ru_utime.tv_sec;
  long long us2 = ru2.ru_utime.tv_usec;
  assert(s1 <= s2);
  if (s1 == s2) {
    assert(us1 < us2);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    D7(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    (%rbx),%edi
  call   <getrusage@plt>
  mov    (%rbx),%edi
  lea    0x10(%rsp),%rsi
  call   <getrusage@plt>
  mov    (%rsp),%rbp
  mov    0x10(%rsp),%rbx
  xor    %edi,%edi
  mov    0x8(%rsp),%r13
  mov    0x18(%rsp),%r12
  cmp    %rbx,%rbp
  setle  %dil
  call   <assert@plt>
  cmp    %rbx,%rbp
  je     L13
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  xor    %edi,%edi
  cmp    %r12,%r13
  setl   %dil
  call   <assert@plt>
  jmp    L3
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct rusage ru1;
  getrusage(RUSAGE_SELF, &ru1);
  for (int i = 0; i < 1000; i++) {
  }
  struct rusage ru2;
  getrusage(RUSAGE_SELF, &ru2);
  long long s1 = ru1.ru_utime.tv_sec;
  long long us1 = ru1.ru_utime.tv_usec;
  long long s2 = ru2.ru_utime.tv_sec;
  long long us2 = ru2.ru_utime.tv_usec;
  assert(s1 <= s2);
  if (s1 == s2) {
    assert(us1 < us2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    D2(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    (%rbx),%edi
  call   <getrusage@plt>
  mov    (%rbx),%edi
  lea    0x10(%rsp),%rsi
  call   <getrusage@plt>
  mov    (%rsp),%rbp
  mov    0x10(%rsp),%rbx
  xor    %edi,%edi
  mov    0x8(%rsp),%r13
  mov    0x18(%rsp),%r12
  cmp    %rbx,%rbp
  setle  %dil
  call   <assert@plt>
  cmp    %rbx,%rbp
  je     L27
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  xor    %edi,%edi
  cmp    %r12,%r13
  setl   %dil
  call   <assert@plt>
  jmp    L28
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct rusage ru1;
  getrusage(RUSAGE_SELF, &ru1);
  for (int i = 0; i < 1000; i++) {
  }
  struct rusage ru2;
  getrusage(RUSAGE_SELF, &ru2);
  long long s1 = ru1.ru_utime.tv_sec;
  long long us1 = ru1.ru_utime.tv_usec;
  long long s2 = ru2.ru_utime.tv_sec;
  long long us2 = ru2.ru_utime.tv_usec;
  assert(s1 <= s2);
  if (s1 == s2) {
    assert(us1 < us2);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1020304,0x4(%rsp)
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rbx
  mov    0x4(%rsp),%edx
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x5(%rsp),%rcx
  movsbl 0x4(%rsp),%edx
  sub    $0x8,%rsp
  movsbl 0xf(%rsp),%eax
  push   %rax
  lea    0x17(%rsp),%rax
  push   %rax
  movsbl 0x1e(%rsp),%eax
  push   %rax
  lea    0x26(%rsp),%r9
  movsbl 0x25(%rsp),%r8d
  mov    %rbx,%rsi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x24(%rsp),%eax
  add    $0x20,%rsp
  cmp    $0x1,%eax
  je     L0
  cmp    $0x4,%eax
  jne    L47
  cmpb   $0x3,0x5(%rsp)
  je     L56
L47:
  lea    D6(%rip),%rdi
  call   <puts@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  cmpb   $0x2,0x5(%rsp)
  jne    L47
  cmpb   $0x3,0x6(%rsp)
  jne    L47
  cmpb   $0x4,0x7(%rsp)
  jne    L47
  lea    D34(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L56:
  cmpb   $0x2,0x6(%rsp)
  jne    L47
  cmpb   $0x1,0x7(%rsp)
  jne    L47
  lea    D50(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D34
type: string
name: read_data
arguments: label: D50
type: string

tool: D19: Big/Little Endian Testing...

tool: D38: n is at address: 0x%x with value: 0x%x


tool: D44: n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]


tool: D6: Endian test : This is a unknown endian machine.

tool: D34: Endian test : This is a big endian machine.

tool: D50: Endian test : This is a little endian machine.

assistant: ```c
int main() {
  char *p0, *p1, *p2, *p3;
  int n, n0, n1, n2, n3;
  n = 0x01020304;
  p0 = ((char *)&n) + 0;
  p1 = ((char *)&n) + 1;
  p2 = ((char *)&n) + 2;
  p3 = ((char *)&n) + 3;
  n0 = (n & 0xff000000) >> 24;
  n1 = (n & 0x00ff0000) >> 16;
  n2 = (n & 0x0000ff00) >> 8;
  n3 = (n & 0x000000ff) >> 0;
  printf("Big/Little Endian Testing...\n");
  printf("n is at address: 0x%x with value: 0x%x\n", &n, n);
  printf("n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]\n", p0, *p0, p1, *p1, p2, *p2, p3, *p3);
  if ((*p0 == n0) && (*p1 == n1) && (*p2 == n2) && (*p3 == n3))
    printf("Endian test : This is a big endian machine.\n");
  else if ((*p0 == n3) && (*p1 == n2) && (*p2 == n1) && (*p3 == n0))
    printf("Endian test : This is a little endian machine.\n");
  else
    printf("Endian test : This is a unknown endian machine.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x1020304,0x4(%rsp)
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  movsbl 0x4(%rsp),%edx
  mov    %rbp,%rsi
  lea    0x5(%rsp),%rcx
  sub    $0x8,%rsp
  lea    D48(%rip),%rdi
  movsbl 0xf(%rsp),%eax
  push   %rax
  lea    0x17(%rsp),%rax
  push   %rax
  movsbl 0x1e(%rsp),%eax
  push   %rax
  movsbl 0x25(%rsp),%r8d
  xor    %eax,%eax
  lea    0x26(%rsp),%r9
  call   <printf@plt>
  movsbl 0x24(%rsp),%eax
  add    $0x20,%rsp
  cmp    $0x1,%eax
  je     L47
  cmp    $0x4,%eax
  jne    L97
  cmpb   $0x3,0x5(%rsp)
  je     L35
L97:
  lea    D49(%rip),%rdi
  call   <puts@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L47:
  cmpb   $0x2,0x5(%rsp)
  jne    L97
  cmpb   $0x3,0x6(%rsp)
  jne    L97
  cmpb   $0x4,0x7(%rsp)
  jne    L97
  lea    D47(%rip),%rdi
  call   <puts@plt>
  jmp    L20
L35:
  cmpb   $0x2,0x6(%rsp)
  jne    L97
  cmpb   $0x1,0x7(%rsp)
  jne    L97
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L20
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D24
datatype: string
name: disassemble_data
arguments: tag: D48
datatype: string
name: disassemble_data
arguments: tag: D49
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string

tool: D11: Big/Little Endian Testing...

tool: D24: n is at address: 0x%x with value: 0x%x


tool: D48: n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]


tool: D49: Endian test : This is a unknown endian machine.

tool: D47: Endian test : This is a big endian machine.

tool: D1: Endian test : This is a little endian machine.

assistant: ```c
int main() {
  char *p0, *p1, *p2, *p3;
  int n, n0, n1, n2, n3;
  n = 0x01020304;
  p0 = ((char *)&n) + 0;
  p1 = ((char *)&n) + 1;
  p2 = ((char *)&n) + 2;
  p3 = ((char *)&n) + 3;
  n0 = (n & 0xff000000) >> 24;
  n1 = (n & 0x00ff0000) >> 16;
  n2 = (n & 0x0000ff00) >> 8;
  n3 = (n & 0x000000ff) >> 0;
  printf("Big/Little Endian Testing...\n");
  printf("n is at address: 0x%x with value: 0x%x\n", &n, n);
  printf("n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]\n", p0, *p0, p1, *p1, p2, *p2, p3, *p3);
  if ((*p0 == n0) && (*p1 == n1) && (*p2 == n2) && (*p3 == n3))
    printf("Endian test : This is a big endian machine.\n");
  else if ((*p0 == n3) && (*p1 == n2) && (*p2 == n1) && (*p3 == n0))
    printf("Endian test : This is a little endian machine.\n");
  else
    printf("Endian test : This is a unknown endian machine.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D57(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x1020304,0x4(%rsp)
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  movsbl 0x4(%rsp),%edx
  mov    %rbp,%rsi
  lea    0x5(%rsp),%rcx
  sub    $0x8,%rsp
  lea    D52(%rip),%rdi
  movsbl 0xf(%rsp),%eax
  push   %rax
  lea    0x17(%rsp),%rax
  push   %rax
  movsbl 0x1e(%rsp),%eax
  push   %rax
  movsbl 0x25(%rsp),%r8d
  xor    %eax,%eax
  lea    0x26(%rsp),%r9
  call   <printf@plt>
  movsbl 0x24(%rsp),%eax
  add    $0x20,%rsp
  cmp    $0x1,%eax
  je     L52
  cmp    $0x4,%eax
  jne    L85
  cmpb   $0x3,0x5(%rsp)
  je     L55
L85:
  lea    D22(%rip),%rdi
  call   <puts@plt>
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L52:
  cmpb   $0x2,0x5(%rsp)
  jne    L85
  cmpb   $0x3,0x6(%rsp)
  jne    L85
  cmpb   $0x4,0x7(%rsp)
  jne    L85
  lea    D43(%rip),%rdi
  call   <puts@plt>
  jmp    L61
L55:
  cmpb   $0x2,0x6(%rsp)
  jne    L85
  cmpb   $0x1,0x7(%rsp)
  jne    L85
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L61
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D57
type_infered: string
name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D52
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D43
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string

tool: D57: Big/Little Endian Testing...

tool: D34: n is at address: 0x%x with value: 0x%x


tool: D52: n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]


tool: D22: Endian test : This is a unknown endian machine.

tool: D43: Endian test : This is a big endian machine.

tool: D14: Endian test : This is a little endian machine.

assistant: ```c
int main() {
  char *p0, *p1, *p2, *p3;
  int n, n0, n1, n2, n3;
  n = 0x01020304;
  p0 = ((char *)&n) + 0;
  p1 = ((char *)&n) + 1;
  p2 = ((char *)&n) + 2;
  p3 = ((char *)&n) + 3;
  n0 = (n & 0xff000000) >> 24;
  n1 = (n & 0x00ff0000) >> 16;
  n2 = (n & 0x0000ff00) >> 8;
  n3 = (n & 0x000000ff) >> 0;
  printf("Big/Little Endian Testing...\n");
  printf("n is at address: 0x%x with value: 0x%x\n", &n, n);
  printf("n is in sequence of [0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x, 0x%x:0x%x]\n", p0, *p0, p1, *p1, p2, *p2, p3, *p3);
  if ((*p0 == n0) && (*p1 == n1) && (*p2 == n2) && (*p3 == n3))
    printf("Endian test : This is a big endian machine.\n");
  else if ((*p0 == n3) && (*p1 == n2) && (*p2 == n1) && (*p3 == n0))
    printf("Endian test : This is a little endian machine.\n");
  else
    printf("Endian test : This is a unknown endian machine.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Jump_Ret>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D29: r3

tool: D26: mtctr

tool: 

tool: D1: bctr

assistant: ```c
void Jump_Ret(void) {
  Inst_Printf("mtctr", "r"
                       "3");
  Inst_Printf("bctr", "");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Jump_Ret>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D29(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <Inst_Printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D34: r3

tool: D4: mtctr

tool: 

tool: D9: bctr

assistant: ```c
void Jump_Ret(void) {
  Inst_Printf("mtctr", "r"
                       "3");
  Inst_Printf("bctr", "");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Jump_Ret>:
  endbr64
  sub    $0x8,%rsp
  lea    D30(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D27(%rip),%rsi
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D30
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D30: r3

tool: D13: mtctr

tool: 

tool: D6: bctr

assistant: ```c
void Jump_Ret(void) {
  Inst_Printf("mtctr", "r"
                       "3");
  Inst_Printf("bctr", "");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Jump_Ret>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D4(%rip),%rsi
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D17
data_type: string

tool: D21: r3

tool: D0: mtctr

tool: 

tool: D17: bctr

assistant: ```c
void Jump_Ret(void) {
  Inst_Printf("mtctr", "r"
                       "3");
  Inst_Printf("bctr", "");
}
```