ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d2bei_array>:
  endbr64
  push   %r14
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsd  D6(%rip),%xmm1
  movq   %xmm1,%r14
  test   %ecx,%ecx
  jne    L15
  movsd  D19(%rip),%xmm2
  movq   %xmm2,%r14
L15:
  lea    0x0(,%r12,4),%eax
  cltq
  lea    (%rsi,%rax,1),%rbx
  sub    $0x1,%r12d
  js     L21
  movslq %r12d,%r12
  nopl   0x0(%rax)
L9:
  movq   %r14,%xmm0
  sub    $0x4,%rbx
  mulsd  0x0(%rbp,%r12,8),%xmm0
  sub    $0x1,%r12
  call   <lrint@plt>
  mov    %eax,%edx
  mov    %ah,0x2(%rbx)
  sar    $0x18,%edx
  mov    %al,0x3(%rbx)
  mov    %dl,(%rbx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x1(%rbx)
  test   %r12d,%r12d
  jns    L9
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D19
type_infered: f64

tool: {"D6": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: D19: 1

assistant: ```c
void d2bei_array(const double *src, int *dest, int count, int normalize) {
  unsigned char *ucptr;
  int value;
  double normfact;
  normfact = normalize ? (1.0 * 0x7FFFFFFF) : 1.0;
  ucptr = ((unsigned char *)dest) + 4 * count;
  while (--count >= 0) {
    ucptr -= 4;
    value = lrint(src[count] * normfact);
    ucptr[0] = value >> 24;
    ucptr[1] = value >> 16;
    ucptr[2] = value >> 8;
    ucptr[3] = value;
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L18
  mov    $0x0,%eax
  call   <abort@plt>
L18:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int a[3];
  int *p = a;
  p[1] = 0;
  if (foo((struct U *)(p + 1), (struct U *)p) != 1)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <foo@plt>
  cmp    $0x1,%eax
  jne    L6
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L23
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[3];
  int *p = a;
  p[1] = 0;
  if (foo((struct U *)(p + 1), (struct U *)p) != 1)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[3];
  int *p = a;
  p[1] = 0;
  if (foo((struct U *)(p + 1), (struct U *)p) != 1)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movl   $0x0,0x10(%rsp)
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L7
  xor    %eax,%eax
  call   <abort@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[3];
  int *p = a;
  p[1] = 0;
  if (foo((struct U *)(p + 1), (struct U *)p) != 1)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort_utils_double_icmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sort_utils_double_icmp(const void *const a, const void *const b) {
  const double *const x = (const double *const)a;
  const double *const y = (const double *const)b;
  return (*x < *y) - (*x > *y);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort_utils_double_icmp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int sort_utils_double_icmp(const void *const a, const void *const b) {
  const double *const x = (const double *const)a;
  const double *const y = (const double *const)b;
  return (*x < *y) - (*x > *y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_utils_double_icmp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int sort_utils_double_icmp(const void *const a, const void *const b) {
  const double *const x = (const double *const)a;
  const double *const y = (const double *const)b;
  return (*x < *y) - (*x > *y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_utils_double_icmp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int sort_utils_double_icmp(const void *const a, const void *const b) {
  const double *const x = (const double *const)a;
  const double *const y = (const double *const)b;
  return (*x < *y) - (*x > *y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  mov    $0x2dc6c0,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L9:
  mov    $0x2dc6c0,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  mov    $0x2dc6c0,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L22:
  mov    $0x2dc6c0,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    $0x2dc6c0,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D41
datatype: string

tool: D2: 
First allocation of %d bytes successful.

tool: D40: 
Attempt to allocate %d bytes failed.


tool: D24: 
Second allocation of %d bytes successful.


tool: D19: 
Second attempt to allocate %d bytes failed.

tool: D44: 
Freeing first block.

tool: D41: 
After free(), allocation of %d bytes successful.


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1, *ptr2;
  ptr1 = malloc(3000000);
  if (ptr1 != NULL)
    printf("\nFirst allocation of %d bytes successful.", 3000000);
  else {
    printf("\nAttempt to allocate %d bytes failed.\n", 3000000);
    exit(1);
  }
  ptr2 = malloc(3000000);
  if (ptr2 != NULL) {
    printf("\nSecond allocation of %d bytes successful.\n", 3000000);
    exit(0);
  }
  printf("\nSecond attempt to allocate %d bytes failed.", 3000000);
  free(ptr1);
  printf("\nFreeing first block.");
  ptr2 = malloc(3000000);
  if (ptr2 != NULL)
    printf("\nAfter free(), allocation of %d bytes successful.\n", 3000000);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    $0x2dc6c0,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L30
  mov    $0x2dc6c0,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L30:
  mov    $0x2dc6c0,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  mov    $0x2dc6c0,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  pop    %rbx
  ret
L9:
  mov    $0x2dc6c0,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type: string
name: extract_symbolic_data
arguments: label: D46
type: string
name: extract_symbolic_data
arguments: label: D6
type: string
name: extract_symbolic_data
arguments: label: D55
type: string
name: extract_symbolic_data
arguments: label: D59
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D23: 
First allocation of %d bytes successful.

tool: D46: 
Second allocation of %d bytes successful.


tool: D6: 
Second attempt to allocate %d bytes failed.

tool: D55: 
Freeing first block.

tool: D59: 
After free(), allocation of %d bytes successful.


tool: D16: 
Attempt to allocate %d bytes failed.


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1, *ptr2;
  ptr1 = malloc(3000000);
  if (ptr1 != NULL)
    printf("\nFirst allocation of %d bytes successful.", 3000000);
  else {
    printf("\nAttempt to allocate %d bytes failed.\n", 3000000);
    exit(1);
  }
  ptr2 = malloc(3000000);
  if (ptr2 != NULL) {
    printf("\nSecond allocation of %d bytes successful.\n", 3000000);
    exit(0);
  }
  printf("\nSecond attempt to allocate %d bytes failed.", 3000000);
  free(ptr1);
  printf("\nFreeing first block.");
  ptr2 = malloc(3000000);
  if (ptr2 != NULL)
    printf("\nAfter free(), allocation of %d bytes successful.\n", 3000000);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    $0x2dc6c0,%esi
  mov    %rax,%rbp
  test   %rax,%rax
  je     L32
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L22
  lea    D0(%rip),%rdi
  mov    $0x2dc6c0,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L22:
  mov    $0x2dc6c0,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L33
  mov    $0x2dc6c0,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  xor    %eax,%eax
  pop    %rbp
  ret
L32:
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D54
type: string

tool: D10: 
First allocation of %d bytes successful.

tool: D0: 
Second allocation of %d bytes successful.


tool: D20: 
Second attempt to allocate %d bytes failed.

tool: D28: 
Freeing first block.

tool: D16: 
After free(), allocation of %d bytes successful.


tool: D54: 
Attempt to allocate %d bytes failed.


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1, *ptr2;
  ptr1 = malloc(3000000);
  if (ptr1 != NULL)
    printf("\nFirst allocation of %d bytes successful.", 3000000);
  else {
    printf("\nAttempt to allocate %d bytes failed.\n", 3000000);
    exit(1);
  }
  ptr2 = malloc(3000000);
  if (ptr2 != NULL) {
    printf("\nSecond allocation of %d bytes successful.\n", 3000000);
    exit(0);
  }
  printf("\nSecond attempt to allocate %d bytes failed.", 3000000);
  free(ptr1);
  printf("\nFreeing first block.");
  ptr2 = malloc(3000000);
  if (ptr2 != NULL)
    printf("\nAfter free(), allocation of %d bytes successful.\n", 3000000);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  mov    $0x2dc6c0,%esi
  mov    %rax,%rbp
  test   %rax,%rax
  je     L38
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L34:
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L19
  lea    D43(%rip),%rdi
  mov    $0x2dc6c0,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L19:
  mov    $0x2dc6c0,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2dc6c0,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    $0x2dc6c0,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  xor    %eax,%eax
  pop    %rbp
  ret
L38:
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: label: D36
type_infered: string
name: extract_symbolic_data
arguments: label: D43
type_infered: string
name: extract_symbolic_data
arguments: label: D35
type_infered: string
name: extract_symbolic_data
arguments: label: D29
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D54
type_infered: string

tool: D36: 
First allocation of %d bytes successful.

tool: D43: 
Second allocation of %d bytes successful.


tool: D35: 
Second attempt to allocate %d bytes failed.

tool: D29: 
Freeing first block.

tool: D6: 
After free(), allocation of %d bytes successful.


tool: D54: 
Attempt to allocate %d bytes failed.


assistant: ```c
int main(int argc, char *argv[]) {
  void *ptr1, *ptr2;
  ptr1 = malloc(3000000);
  if (ptr1 != NULL)
    printf("\nFirst allocation of %d bytes successful.", 3000000);
  else {
    printf("\nAttempt to allocate %d bytes failed.\n", 3000000);
    exit(1);
  }
  ptr2 = malloc(3000000);
  if (ptr2 != NULL) {
    printf("\nSecond allocation of %d bytes successful.\n", 3000000);
    exit(0);
  }
  printf("\nSecond attempt to allocate %d bytes failed.", 3000000);
  free(ptr1);
  printf("\nFreeing first block.");
  ptr2 = malloc(3000000);
  if (ptr2 != NULL)
    printf("\nAfter free(), allocation of %d bytes successful.\n", 3000000);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd_mvaddchnstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L56
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x14(%rbp),%rdx
  lea    D43(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L40
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L10
L40:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  lea    D43(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L10
L11:
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D43(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L10
L19:
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mvaddchnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L10
L56:
  nop
L10:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D43
datatype: string
name: unpack_data
arguments: data_tag: D31
datatype: string

tool: D43: %d

tool: D31: BAD ARGUMENT

assistant: ```c
void cmd_mvaddchnstr(int nargs, char **args) {
  int y, x, count;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(mvaddchnstr(y, x, (chtype *)args[2], count));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd_mvaddchnstr>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L28
  lea    0xc(%rsp),%rdx
  lea    D6(%rip),%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L79
  lea    0x10(%rsp),%rdx
  mov    0x8(%rbx),%rdi
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L52
  lea    0x14(%rsp),%rdx
  mov    0x18(%rbx),%rdi
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L60
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x10(%rbx),%rdx
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <mvaddchnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L28
L79:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  ret
L52:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
  jmp    L28
L60:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
  jmp    L28
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D6: %d

tool: D4: BAD ARGUMENT

assistant: ```c
void cmd_mvaddchnstr(int nargs, char **args) {
  int y, x, count;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(mvaddchnstr(y, x, (chtype *)args[2], count));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_mvaddchnstr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L2
  lea    D17(%rip),%rbp
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L10
  mov    0x8(%rbx),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L10
  mov    0x18(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L10
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0xc(%rsp),%edi
  mov    0x10(%rbx),%rdx
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%esi
  call   <mvaddchnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D5(%rip),%rdi
  call   <report_error@plt>
  jmp    L2
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D17: %d

tool: D5: BAD ARGUMENT

assistant: ```c
void cmd_mvaddchnstr(int nargs, char **args) {
  int y, x, count;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(mvaddchnstr(y, x, (chtype *)args[2], count));
}
```