ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ighmm_determinant>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    $0x1,%esi
  je     L61
  mov    %esi,%r12d
  cmp    $0x2,%esi
  je     L88
  test   %esi,%esi
  jle    L60
  lea    -0x1(%rsi),%r15d
  pxor   %xmm4,%xmm4
  xor    %r13d,%r13d
  mov    %r15d,%ebx
  movsd  %xmm4,(%rsp)
  imul   %r15d,%ebx
  lea    0x0(,%rbx,8),%eax
  mov    %eax,0x14(%rsp)
  movslq %esi,%rax
  mov    %rax,0x18(%rsp)
L18:
  mov    0x14(%rsp),%edi
  mov    %r13d,%ebx
  call   <malloc@plt>
  mov    %r12d,%edi
  xor    %esi,%esi
  mov    $0x1,%r10d
  mov    %rax,%rbp
  cs nopw 0x0(%rax,%rax,1)
L73:
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L84:
  cmp    %r13d,%eax
  je     L56
  lea    (%rax,%rdi,1),%edx
  add    $0x1,%eax
  movslq %edx,%rdx
  movsd  (%r14,%rdx,8),%xmm0
  lea    (%rsi,%rcx,1),%edx
  add    $0x1,%ecx
  movslq %edx,%rdx
  movsd  %xmm0,0x0(%rbp,%rdx,8)
  cmp    %r12d,%eax
  jne    L84
  add    $0x1,%r10d
  add    %r12d,%edi
  add    %r15d,%esi
  cmp    %r10d,%r12d
  jne    L73
L102:
  pxor   %xmm1,%xmm1
  mov    D25(%rip),%rax
  cvtsi2sd %ebx,%xmm1
  addsd  D17(%rip),%xmm1
  addsd  D17(%rip),%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  mulsd  (%r14,%r13,8),%xmm0
  mov    %r15d,%esi
  mov    %rbp,%rdi
  add    $0x1,%r13
  movsd  %xmm0,0x8(%rsp)
  call   <ighmm_determinant>
  mulsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  call   <free@plt>
  cmp    %r13,0x18(%rsp)
  jne    L18
L63:
  movsd  (%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L56:
  add    $0x1,%eax
  cmp    %eax,%r12d
  jne    L84
  add    $0x1,%r10d
  add    %r12d,%edi
  add    %r15d,%esi
  cmp    %r10d,%r12d
  jne    L73
  jmp    L102
L61:
  movsd  (%rdi),%xmm5
  movsd  %xmm5,(%rsp)
  jmp    L63
L60:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,(%rsp)
  jmp    L63
L88:
  movsd  (%rdi),%xmm0
  movsd  0x18(%rdi),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  0x10(%rdi),%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  jmp    L63
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D17
type_guessed: f64

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D17: 1

assistant: ```c
double ighmm_determinant(double *cov, int n) {
  int j1, i, j, jm;
  double *m;
  double det;
  if (n == 1)
    return cov[0];
  if (n == 2)
    return cov[0] * cov[3] - cov[1] * cov[2];
  det = 0;
  for (j1 = 0; j1 < n; j1++) {
    m = malloc((n - 1) * (n - 1) * sizeof(double));
    for (i = 1; i < n; i++) {
      jm = 0;
      for (j = 0; j < n; j++) {
        if (j == j1)
          continue;
        m[(i - 1) * (n - 1) + jm] = cov[i * n + j];
        jm++;
      }
    }
    det += pow(-1.0, 1.0 + j1 + 1.0) * cov[j1] * ighmm_determinant(m, n - 1);
    free(m);
  }
  return det;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<call_dtrsm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %ecx,%eax
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %edi,%ecx
  mov    %cl,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  lea    -0x18(%rbp),%r9
  lea    -0x14(%rbp),%r8
  lea    -0x10(%rbp),%rcx
  lea    -0xc(%rbp),%rdx
  lea    -0x8(%rbp),%rsi
  lea    -0x4(%rbp),%rax
  sub    $0x8,%rsp
  lea    0x28(%rbp),%rdi
  push   %rdi
  push   0x20(%rbp)
  lea    0x18(%rbp),%rdi
  push   %rdi
  push   0x10(%rbp)
  lea    -0x20(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <dtrsm_@plt>
  add    $0x30,%rsp
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int call_dtrsm(char side, char uplo, char transa, char diag, int m, int n, double alpha, const double *a, int lda, double *b, int ldb) {
  dtrsm_(&side, &uplo, &transa, &diag, &m, &n, &alpha, a, &lda, b, &ldb);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_dtrsm>:
  endbr64
  sub    $0x28,%rsp
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  mov    %dil,0x1c(%rsp)
  mov    %sil,0x18(%rsp)
  mov    %dl,0x14(%rsp)
  mov    %cl,0x10(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x1c(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x38(%rsp),%r9
  lea    0x3c(%rsp),%r8
  call   <dtrsm_@plt>
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
```

assistant: ```c
int call_dtrsm(char side, char uplo, char transa, char diag, int m, int n, double alpha, const double *a, int lda, double *b, int ldb) {
  dtrsm_(&side, &uplo, &transa, &diag, &m, &n, &alpha, a, &lda, b, &ldb);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call_dtrsm>:
  endbr64
  sub    $0x28,%rsp
  mov    %dil,0x1c(%rsp)
  lea    0x1c(%rsp),%rdi
  mov    %sil,0x18(%rsp)
  lea    0x18(%rsp),%rsi
  mov    %dl,0x14(%rsp)
  lea    0x14(%rsp),%rdx
  mov    %cl,0x10(%rsp)
  lea    0x10(%rsp),%rcx
  sub    $0x8,%rsp
  mov    %r8d,0x14(%rsp)
  mov    %r9d,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x38(%rsp),%r9
  lea    0x3c(%rsp),%r8
  call   <dtrsm_@plt>
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
```

assistant: ```c
int call_dtrsm(char side, char uplo, char transa, char diag, int m, int n, double alpha, const double *a, int lda, double *b, int ldb) {
  dtrsm_(&side, &uplo, &transa, &diag, &m, &n, &alpha, a, &lda, b, &ldb);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call_dtrsm>:
  endbr64
  sub    $0x28,%rsp
  mov    %dil,0x1c(%rsp)
  lea    0x1c(%rsp),%rdi
  mov    %sil,0x18(%rsp)
  lea    0x18(%rsp),%rsi
  mov    %dl,0x14(%rsp)
  lea    0x14(%rsp),%rdx
  mov    %cl,0x10(%rsp)
  lea    0x10(%rsp),%rcx
  sub    $0x8,%rsp
  mov    %r8d,0x14(%rsp)
  mov    %r9d,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x50(%rsp),%rax
  push   %rax
  push   0x50(%rsp)
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x38(%rsp),%r9
  lea    0x3c(%rsp),%r8
  call   <dtrsm_@plt>
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
```

assistant: ```c
int call_dtrsm(char side, char uplo, char transa, char diag, int m, int n, double alpha, const double *a, int lda, double *b, int ldb) {
  dtrsm_(&side, &uplo, &transa, &diag, &m, &n, &alpha, a, &lda, b, &ldb);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L6
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *str, size_t n) {
  size_t len = strlen(str);
  if (len > n)
    len = n;
  char *ptr = (char *)malloc(len + 1);
  memcpy(ptr, str, len);
  ptr[len] = 0;
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *str, size_t n) {
  size_t len = strlen(str);
  if (len > n)
    len = n;
  char *ptr = (char *)malloc(len + 1);
  memcpy(ptr, str, len);
  ptr[len] = 0;
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *str, size_t n) {
  size_t len = strlen(str);
  if (len > n)
    len = n;
  char *ptr = (char *)malloc(len + 1);
  memcpy(ptr, str, len);
  ptr[len] = 0;
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %rbx,%rax
  cmovbe %rax,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *str, size_t n) {
  size_t len = strlen(str);
  if (len > n)
    len = n;
  char *ptr = (char *)malloc(len + 1);
  memcpy(ptr, str, len);
  ptr[len] = 0;
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: %d 

assistant: ```c
void dump(int a[], int low, int high) {
  for (int i = low; i <= high; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dump>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jg     L18
  mov    %rdi,%r12
  mov    %edx,%ebp
  movslq %esi,%rbx
  lea    D5(%rip),%r13
L1:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L1
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: %d 

assistant: ```c
void dump(int a[], int low, int high) {
  for (int i = low; i <= high; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump>:
  endbr64
  cmp    %edx,%esi
  jg     L6
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L2
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D2: %d 

assistant: ```c
void dump(int a[], int low, int high) {
  for (int i = low; i <= high; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<dump>:
  endbr64
  cmp    %edx,%esi
  jg     L9
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L10
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %d 

assistant: ```c
void dump(int a[], int low, int high) {
  for (int i = low; i <= high; i++)
    printf("%d ", a[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *v, int i, int j) {
  int t = v[i];
  v[i] = v[j];
  v[j] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *v, int i, int j) {
  int t = v[i];
  v[i] = v[j];
  v[j] = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *v, int i, int j) {
  int t = v[i];
  v[i] = v[j];
  v[j] = t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *v, int i, int j) {
  int t = v[i];
  v[i] = v[j];
  v[j] = t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    -0x17447d68(%rax),%edx
  test   $0x8,%al
  jne    L15
  test   $0x1,%dl
  je     L23
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  jmp    L0
L23:
  mov    %edx,%eax
  shl    $0x10,%eax
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%ah
  mov    %dl,%al
  shr    $0x18,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  jmp    L0
L15:
  mov    %edx,%ecx
  shr    $0x3,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %edx,%eax
  rol    %cl,%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
L0:
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> 3U) & 15U) | 1UL)) | (state[0UL] >> (32 - (((state[0UL] >> 3U) & 15U) | 1UL)))) & 7U) << 2UL;
      state[0UL] <<= (state[0UL] & 7U) | 1UL;
    }
    output[0UL] = state[0UL] - 413274705UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    -0x17447d68(%rax),%edx
  test   $0x8,%al
  jne    L6
  test   $0x1,%dl
  je     L5
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L6:
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    $0x3,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L5:
  mov    %edx,%ecx
  mov    %edx,%eax
  shl    $0x8,%ecx
  shl    $0x10,%eax
  sar    $0x18,%ecx
  mov    %cl,%ah
  mov    %dl,%al
  shr    $0x18,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> 3U) & 15U) | 1UL)) | (state[0UL] >> (32 - (((state[0UL] >> 3U) & 15U) | 1UL)))) & 7U) << 2UL;
      state[0UL] <<= (state[0UL] & 7U) | 1UL;
    }
    output[0UL] = state[0UL] - 413274705UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    -0x17447d68(%rax),%edx
  test   $0x8,%al
  jne    L3
  test   $0x1,%dl
  je     L16
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L3:
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    $0x3,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax)
L16:
  push   %rbx
  mov    %edx,%ebx
  xor    %ecx,%ecx
  mov    %edx,%eax
  shl    $0x8,%ebx
  mov    %dl,%cl
  shl    $0x10,%eax
  sar    $0x18,%ebx
  shr    $0x18,%edx
  mov    %bl,%ch
  shl    $0x10,%edx
  pop    %rbx
  mov    %cx,%ax
  and    $0xff00ffff,%eax
  or     %edx,%eax
  sub    $0x18a21251,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> 3U) & 15U) | 1UL)) | (state[0UL] >> (32 - (((state[0UL] >> 3U) & 15U) | 1UL)))) & 7U) << 2UL;
      state[0UL] <<= (state[0UL] & 7U) | 1UL;
    }
    output[0UL] = state[0UL] - 413274705UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<formats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L22
L57:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  je     L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L15
L50:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L15:
  subl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x0,-0x4(%rbp)
  jns    L57
  jmp    L21
L6:
  nop
L21:
  leave
  ret
```

assistant: ```c
void formats(char *s) {
  int i;
  if (!s)
    return;
  for (i = (int)strlen(s); i >= 0; i--) {
    if ((s[i] == '|') || (s[i] == '\n'))
      s[i] = ' ';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<formats>:
  endbr64
  test   %rdi,%rdi
  je     L33
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  js     L66
  movslq %eax,%rcx
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%rsi
  mov    %eax,%eax
  sub    %rax,%rsi
  jmp    L46
L51:
  movb   $0x20,(%rcx)
L8:
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L66
L46:
  mov    %rdx,%rcx
  movzbl (%rdx),%eax
  cmp    $0x7c,%al
  je     L51
  cmp    $0xa,%al
  jne    L8
  jmp    L51
L66:
  pop    %rbx
  ret
L33:
  ret
```

assistant: ```c
void formats(char *s) {
  int i;
  if (!s)
    return;
  for (i = (int)strlen(s); i >= 0; i--) {
    if ((s[i] == '|') || (s[i] == '\n'))
      s[i] = ' ';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<formats>:
  endbr64
  test   %rdi,%rdi
  je     L35
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  js     L29
  movslq %eax,%rcx
  mov    %eax,%eax
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%rcx
  sub    %rax,%rcx
  jmp    L50
  nopl   0x0(%rax)
L56:
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  je     L29
L50:
  movzbl (%rdx),%eax
  cmp    $0x7c,%al
  je     L60
  cmp    $0xa,%al
  jne    L56
L60:
  movb   $0x20,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L50
L29:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  ret
```

assistant: ```c
void formats(char *s) {
  int i;
  if (!s)
    return;
  for (i = (int)strlen(s); i >= 0; i--) {
    if ((s[i] == '|') || (s[i] == '\n'))
      s[i] = ' ';
  }
}
```