user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x94(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L70
L93:
  movl   $0x0,-0x98(%rbp)
  jmp    L122
L119:
  mov    -0x94(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x94(%rbp)
  addl   $0x1,-0x98(%rbp)
L122:
  cmpl   $0x3,-0x98(%rbp)
  jle    L119
  addl   $0x1,-0x9c(%rbp)
L70:
  cmpl   $0x3,-0x9c(%rbp)
  jle    L93
  movl   $0x0,-0x9c(%rbp)
  jmp    L128
L103:
  movl   $0x0,-0x98(%rbp)
  jmp    L26
L99:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x9c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x98(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x50(%rbp,%rdx,4)
  addl   $0x1,-0x98(%rbp)
L26:
  cmpl   $0x3,-0x98(%rbp)
  jle    L99
  addl   $0x1,-0x9c(%rbp)
L128:
  cmpl   $0x3,-0x9c(%rbp)
  jle    L103
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L65
L81:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x98(%rbp)
  jmp    L29
L0:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x98(%rbp)
L29:
  cmpl   $0x3,-0x98(%rbp)
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x9c(%rbp)
L65:
  cmpl   $0x3,-0x9c(%rbp)
  jle    L81
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D27
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D37
datatype: string

tool: D27: 
	 Enter Numbers: 

tool: D6: 
 Cell %d: 

tool: D19: %d

tool: D5: 
	 The Transpose is: 

tool: D37: 	 %d 	

assistant: ```c
int main() {
  int a[4][4], b[4][4], m, n, i = 1;
  printf("\n\t Enter Numbers: \n");
  for (m = 0; m < 4; m++) {
    for (n = 0; n < 4; n++) {
      printf("\n Cell %d: ", i);
      scanf("%d", &a[m][n]);
      i++;
    }
  }
  for (m = 0; m < 4; m++) {
    for (n = 0; n < 4; n++) {
      b[n][m] = a[m][n];
    }
  }
  printf("\n\t The Transpose is: \n");
  for (m = 0; m < 4; m++) {
    printf("\n");
    for (n = 0; n < 4; n++) {
      printf("\t %d \t", b[m][n]);
    }
    printf("\n");
  }
  printf("\n");
  return 0;
}
```