ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<resize_tag_field>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x20,-0x1(%rbx,%rax,1)
  jne    L7
  lea    -0x1(%rax),%rdx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rdx,%rax
  sub    $0x1,%rdx
  cmpb   $0x20,(%rbx,%rdx,1)
  je     L14
L7:
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void resize_tag_field(char *field) {
  int i;
  i = strlen(field);
  while (field[i - 1] == ' ')
    i--;
  field[i] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rte_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L77
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L77:
  cmpq   $0x0,-0xc8(%rbp)
  jne    L81
  cmpl   $0x0,-0xcc(%rbp)
  jne    L99
L81:
  cmpq   $0x0,-0xd8(%rbp)
  jne    L47
  cmpl   $0x0,-0xcc(%rbp)
  jle    L74
  mov    -0xc8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L74
L47:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  cmp    -0xcc(%rbp),%eax
  jl     L90
  cmpl   $0x0,-0xcc(%rbp)
  jle    L90
  mov    -0xcc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L90:
  mov    -0xb4(%rbp),%eax
  jmp    L33
L99:
  nop
  jmp    L85
L74:
  nop
L85:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
L33:
  leave
  ret
```

assistant: ```c
int rte_snprintf(char *buffer, int buflen, const char *format, ...) {
  int len;
  va_list ap;
  if (buffer == NULL && buflen != 0)
    goto einval_error;
  if (format == NULL) {
    if (buflen > 0)
      buffer[0] = '\0';
    goto einval_error;
  }
  va_start(ap, format);
  len = vsnprintf(buffer, buflen, format, ap);
  va_end(ap);
  if (len >= buflen && buflen > 0)
    buffer[buflen - 1] = '\0';
  return len;
einval_error:
  errno = EINVAL;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rte_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  test   %rdi,%rdi
  jne    L48
  test   %esi,%esi
  jne    L66
L48:
  test   %rbp,%rbp
  je     L4
  mov    %rbp,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <va_end@plt>
  cmp    %ebp,%ebx
  jg     L67
  test   %ebx,%ebx
  jle    L67
  movslq %ebx,%rbx
  movb   $0x0,-0x1(%r12,%rbx,1)
L67:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  test   %ebx,%ebx
  jle    L66
  movb   $0x0,(%r12)
L66:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%ebp
  jmp    L67
```

assistant: ```c
int rte_snprintf(char *buffer, int buflen, const char *format, ...) {
  int len;
  va_list ap;
  if (buffer == NULL && buflen != 0)
    goto einval_error;
  if (format == NULL) {
    if (buflen > 0)
      buffer[0] = '\0';
    goto einval_error;
  }
  va_start(ap, format);
  len = vsnprintf(buffer, buflen, format, ap);
  va_end(ap);
  if (len >= buflen && buflen > 0)
    buffer[buflen - 1] = '\0';
  return len;
einval_error:
  errno = EINVAL;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<rte_snprintf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L8
  test   %ebx,%ebx
  jne    L0
L8:
  test   %r12,%r12
  je     L13
  xor    %r13d,%r13d
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %ebx,%esi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmp    %r12d,%ebx
  jg     L48
  test   %ebx,%ebx
  jle    L48
  movb   $0x0,-0x1(%rbp,%rbx,1)
L48:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  test   %ebx,%ebx
  jle    L0
  movb   $0x0,0x0(%rbp)
L0:
  mov    D17(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  jmp    L48
```

assistant: ```c
int rte_snprintf(char *buffer, int buflen, const char *format, ...) {
  int len;
  va_list ap;
  if (buffer == NULL && buflen != 0)
    goto einval_error;
  if (format == NULL) {
    if (buflen > 0)
      buffer[0] = '\0';
    goto einval_error;
  }
  va_start(ap, format);
  len = vsnprintf(buffer, buflen, format, ap);
  va_end(ap);
  if (len >= buflen && buflen > 0)
    buffer[buflen - 1] = '\0';
  return len;
einval_error:
  errno = EINVAL;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rte_snprintf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L46
  test   %ebx,%ebx
  jne    L39
L46:
  test   %r12,%r12
  je     L12
  xor    %r13d,%r13d
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %ebx,%esi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmp    %r12d,%ebx
  jg     L5
  test   %ebx,%ebx
  jle    L5
  movb   $0x0,-0x1(%rbp,%rbx,1)
L5:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  test   %ebx,%ebx
  jle    L39
  movb   $0x0,0x0(%rbp)
L39:
  mov    D6(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  jmp    L5
```

assistant: ```c
int rte_snprintf(char *buffer, int buflen, const char *format, ...) {
  int len;
  va_list ap;
  if (buffer == NULL && buflen != 0)
    goto einval_error;
  if (format == NULL) {
    if (buflen > 0)
      buffer[0] = '\0';
    goto einval_error;
  }
  va_start(ap, format);
  len = vsnprintf(buffer, buflen, format, ap);
  va_end(ap);
  if (len >= buflen && buflen > 0)
    buffer[buflen - 1] = '\0';
  return len;
einval_error:
  errno = EINVAL;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<batsu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L0:
  mov    -0x18(%rbp),%eax
  lea    0x16(%rax),%ecx
  mov    -0x14(%rbp),%eax
  lea    0x15(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    0x9(%rax),%esi
  mov    -0x14(%rbp),%eax
  lea    0x8(%rax),%edi
  mov    -0x4(%rbp),%eax
  add    %edi,%eax
  mov    -0x1c(%rbp),%edi
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <draw_line@plt>
  mov    -0x18(%rbp),%eax
  lea    0x16(%rax),%ecx
  mov    -0x14(%rbp),%eax
  lea    0x8(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  lea    0x9(%rax),%esi
  mov    -0x14(%rbp),%eax
  lea    0x15(%rax),%edi
  mov    -0x4(%rbp),%eax
  add    %edi,%eax
  mov    -0x1c(%rbp),%edi
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <draw_line@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x3,-0x4(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void batsu(int x, int y, int c) {
  int i;
  for (i = 1; i < 4; i++) {
    draw_line(x + 8 + i, y + 9, x + 21 + i, y + 22, c);
    draw_line(x + 21 + i, y + 9, x + 8 + i, y + 22, c);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<batsu>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r15d
  mov    %edx,%ebp
  lea    0x9(%rdi),%ebx
  lea    0xc(%rdi),%eax
  mov    %eax,0xc(%rsp)
  lea    0x16(%rsi),%r14d
L5:
  lea    0xd(%rbx),%r12d
  lea    0x9(%r15),%r13d
  mov    %ebp,%r8d
  mov    %r14d,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <draw_line@plt>
  mov    %ebp,%r8d
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <draw_line@plt>
  add    $0x1,%ebx
  cmp    0xc(%rsp),%ebx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void batsu(int x, int y, int c) {
  int i;
  for (i = 1; i < 4; i++) {
    draw_line(x + 8 + i, y + 9, x + 21 + i, y + 22, c);
    draw_line(x + 21 + i, y + 9, x + 8 + i, y + 22, c);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<batsu>:
  endbr64
  push   %r15
  push   %r14
  lea    0x16(%rsi),%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0xc(%rdi),%r12d
  push   %rbp
  lea    0x9(%rsi),%ebp
  push   %rbx
  lea    0x9(%rdi),%ebx
  sub    $0x8,%rsp
L2:
  lea    0xd(%rbx),%r15d
  mov    %ebx,%edi
  mov    %r13d,%r8d
  mov    %r14d,%ecx
  mov    %r15d,%edx
  mov    %ebp,%esi
  call   <draw_line@plt>
  mov    %ebx,%edx
  mov    %r13d,%r8d
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %r15d,%edi
  add    $0x1,%ebx
  call   <draw_line@plt>
  cmp    %r12d,%ebx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void batsu(int x, int y, int c) {
  int i;
  for (i = 1; i < 4; i++) {
    draw_line(x + 8 + i, y + 9, x + 21 + i, y + 22, c);
    draw_line(x + 21 + i, y + 9, x + 8 + i, y + 22, c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<batsu>:
  endbr64
  push   %r15
  push   %r14
  lea    0x16(%rsi),%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0xc(%rdi),%r12d
  push   %rbp
  lea    0x9(%rsi),%ebp
  push   %rbx
  lea    0x9(%rdi),%ebx
  sub    $0x8,%rsp
L3:
  lea    0xd(%rbx),%r15d
  mov    %ebx,%edi
  mov    %r13d,%r8d
  mov    %r14d,%ecx
  mov    %r15d,%edx
  mov    %ebp,%esi
  call   <draw_line@plt>
  mov    %ebx,%edx
  mov    %r13d,%r8d
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %r15d,%edi
  add    $0x1,%ebx
  call   <draw_line@plt>
  cmp    %r12d,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void batsu(int x, int y, int c) {
  int i;
  for (i = 1; i < 4; i++) {
    draw_line(x + 8 + i, y + 9, x + 21 + i, y + 22, c);
    draw_line(x + 21 + i, y + 9, x + 8 + i, y + 22, c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RC4>:
  endbr64
  sub    $0x858,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x848(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %eax,(%rsp)
  mov    0x4(%rdi),%eax
  mov    %eax,0x4(%rsp)
  mov    0x8(%rdi),%eax
  mov    %eax,0x8(%rsp)
  mov    $0x0,%eax
  lea    0xc(%rsp),%rcx
L24:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x34,%rax
  jne    L24
  mov    $0x0,%eax
L33:
  mov    %eax,0x440(%rsp,%rax,4)
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rcx,%rax,1),%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%edx
  mov    %edx,0x40(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L33
  lea    0x440(%rsp),%rcx
  lea    0x40(%rsp),%rdi
  lea    0x840(%rsp),%r9
  mov    $0x0,%eax
L6:
  mov    (%rcx),%r8d
  add    %r8d,%eax
  add    (%rdi),%eax
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x18,%esi
  add    %esi,%eax
  movzbl %al,%edx
  sub    %esi,%edx
  mov    %edx,%eax
  movslq %edx,%rdx
  mov    0x440(%rsp,%rdx,4),%esi
  mov    %esi,(%rcx)
  mov    %r8d,0x440(%rsp,%rdx,4)
  add    $0x4,%rcx
  add    $0x4,%rdi
  cmp    %r9,%rcx
  jne    L6
  mov    0x444(%rsp),%eax
  movslq %eax,%rdx
  mov    0x440(%rsp,%rdx,4),%ecx
  mov    %ecx,0x444(%rsp)
  mov    %eax,0x440(%rsp,%rdx,4)
  add    0x444(%rsp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  cltq
  mov    0x440(%rsp,%rax,4),%eax
  mov    0x848(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x858,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int RC4(int *IV, int *key) {
  int K[256];
  int S[256];
  int seed[16];
  int i, j, k, t;
  for (k = 0; k < 3; k++)
    seed[k] = IV[k];
  for (k = 0; k < 13; k++)
    seed[k + 3] = key[k];
  for (k = 0; k < 256; k++) {
    S[k] = k;
    K[k] = seed[k % 16];
  }
  j = 0;
  for (i = 0; i < 256; i++) {
    j = (j + S[i] + K[i]) % 256;
    t = S[i];
    S[i] = S[j];
    S[j] = t;
  }
  i = 0;
  j = 0;
  i = i + 1;
  j = j + S[i];
  t = S[i];
  S[i] = S[j];
  S[j] = t;
  k = (S[i] + S[j]) % 256;
  return S[k];
}
```
user: What is the c source code of the assembly code below?

```asm
<RC4>:
  endbr64
  sub    $0x858,%rsp
  mov    (%rdi),%rdx
  movdqu (%rsi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x848(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdi),%eax
  movdqu 0x10(%rsi),%xmm1
  movdqu 0x20(%rsi),%xmm2
  mov    (%rdi),%ecx
  mov    %rdx,(%rsp)
  lea    0x440(%rsp),%rdx
  mov    %eax,0x8(%rsp)
  mov    0x30(%rsi),%eax
  lea    0x40(%rsp),%rsi
  movups %xmm0,0xc(%rsp)
  mov    %eax,0x3c(%rsp)
  xor    %eax,%eax
  movups %xmm1,0x1c(%rsp)
  movups %xmm2,0x2c(%rsp)
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L0:
  and    $0xf,%ecx
  mov    (%rsp,%rcx,4),%ecx
L39:
  mov    %ecx,(%rsi,%rax,4)
  lea    0x1(%rax),%ecx
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L0
  lea    0x840(%rsp),%r9
  xor    %eax,%eax
  nopl   (%rax)
L31:
  mov    (%rdx),%edi
  add    $0x4,%rdx
  add    $0x4,%rsi
  add    %edi,%eax
  add    -0x4(%rsi),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x18,%ecx
  add    %ecx,%eax
  movzbl %al,%eax
  sub    %ecx,%eax
  movslq %eax,%rcx
  mov    0x440(%rsp,%rcx,4),%r8d
  mov    %r8d,-0x4(%rdx)
  mov    %edi,0x440(%rsp,%rcx,4)
  cmp    %r9,%rdx
  jne    L31
  movslq 0x444(%rsp),%rdx
  mov    0x440(%rsp,%rdx,4),%ecx
  mov    %rdx,%rax
  mov    %ecx,0x444(%rsp)
  mov    %edx,0x440(%rsp,%rdx,4)
  add    0x444(%rsp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  cltq
  mov    0x440(%rsp,%rax,4),%eax
  mov    0x848(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x858,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int RC4(int *IV, int *key) {
  int K[256];
  int S[256];
  int seed[16];
  int i, j, k, t;
  for (k = 0; k < 3; k++)
    seed[k] = IV[k];
  for (k = 0; k < 13; k++)
    seed[k + 3] = key[k];
  for (k = 0; k < 256; k++) {
    S[k] = k;
    K[k] = seed[k % 16];
  }
  j = 0;
  for (i = 0; i < 256; i++) {
    j = (j + S[i] + K[i]) % 256;
    t = S[i];
    S[i] = S[j];
    S[j] = t;
  }
  i = 0;
  j = 0;
  i = i + 1;
  j = j + S[i];
  t = S[i];
  S[i] = S[j];
  S[j] = t;
  k = (S[i] + S[j]) % 256;
  return S[k];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RC4>:
  endbr64
  sub    $0x858,%rsp
  movq   (%rdi),%xmm0
  movdqu (%rsi),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x848(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdi),%eax
  movdqu 0x10(%rsi),%xmm4
  lea    0x440(%rsp),%rdx
  movdqu 0x20(%rsi),%xmm5
  movd   %xmm0,%ecx
  movq   %xmm0,(%rsp)
  movdqa D12(%rip),%xmm2
  mov    %eax,0x8(%rsp)
  mov    0x30(%rsi),%eax
  lea    0x840(%rsp),%r9
  movdqa D5(%rip),%xmm0
  movups %xmm3,0xc(%rsp)
  mov    %eax,0x3c(%rsp)
  mov    %rdx,%rax
  movups %xmm4,0x1c(%rsp)
  movups %xmm5,0x2c(%rsp)
  nopl   0x0(%rax)
L24:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %r9,%rax
  jne    L24
  mov    %ecx,0x40(%rsp)
  mov    $0x1,%eax
  lea    0x40(%rsp),%rsi
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rax,%rcx
  and    $0xf,%ecx
  mov    (%rsp,%rcx,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L2
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rdx),%edi
  add    $0x4,%rdx
  add    $0x4,%rsi
  add    %edi,%eax
  add    -0x4(%rsi),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x18,%ecx
  add    %ecx,%eax
  movzbl %al,%eax
  sub    %ecx,%eax
  movslq %eax,%rcx
  mov    0x440(%rsp,%rcx,4),%r8d
  mov    %r8d,-0x4(%rdx)
  mov    %edi,0x440(%rsp,%rcx,4)
  cmp    %r9,%rdx
  jne    L14
  movslq 0x444(%rsp),%rdx
  mov    0x440(%rsp,%rdx,4),%ecx
  mov    %rdx,%rax
  mov    %ecx,0x444(%rsp)
  mov    %edx,0x440(%rsp,%rdx,4)
  add    0x444(%rsp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  cltq
  mov    0x440(%rsp,%rax,4),%eax
  mov    0x848(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x858,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: byte[16]
name: retrieve_data
arguments: tag: D5
type: byte[16]

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int RC4(int *IV, int *key) {
  int K[256];
  int S[256];
  int seed[16];
  int i, j, k, t;
  for (k = 0; k < 3; k++)
    seed[k] = IV[k];
  for (k = 0; k < 13; k++)
    seed[k + 3] = key[k];
  for (k = 0; k < 256; k++) {
    S[k] = k;
    K[k] = seed[k % 16];
  }
  j = 0;
  for (i = 0; i < 256; i++) {
    j = (j + S[i] + K[i]) % 256;
    t = S[i];
    S[i] = S[j];
    S[j] = t;
  }
  i = 0;
  j = 0;
  i = i + 1;
  j = j + S[i];
  t = S[i];
  S[i] = S[j];
  S[j] = t;
  k = (S[i] + S[j]) % 256;
  return S[k];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<regex_flag_icase_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void regex_flag_icase_short(char c __attribute__((unused)), void *data) {
  int *cflags = data;
  *cflags |= REG_ICASE;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<regex_flag_icase_short>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  or     %eax,(%rsi)
  ret
```

assistant: ```c
void regex_flag_icase_short(char c __attribute__((unused)), void *data) {
  int *cflags = data;
  *cflags |= REG_ICASE;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<regex_flag_icase_short>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  or     %eax,(%rsi)
  ret
```

assistant: ```c
void regex_flag_icase_short(char c __attribute__((unused)), void *data) {
  int *cflags = data;
  *cflags |= REG_ICASE;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<regex_flag_icase_short>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  or     %eax,(%rsi)
  ret
```

assistant: ```c
void regex_flag_icase_short(char c __attribute__((unused)), void *data) {
  int *cflags = data;
  *cflags |= REG_ICASE;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TRAN_Set_MP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L10:
  cmpl   $0x0,-0x14(%rbp)
  je     L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L10
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TRAN_Set_MP(int job, int atomnum, int *WhatSpecies, int *Spe_Total_CNO, int *NUM, int *MP) {
  int Anum, i, wanA, tnoA;
  Anum = 1;
  for (i = 1; i <= atomnum; i++) {
    if (job)
      MP[i] = Anum;
    wanA = WhatSpecies[i];
    tnoA = Spe_Total_CNO[wanA];
    Anum = Anum + tnoA;
  }
  *NUM = Anum - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TRAN_Set_MP>:
  endbr64
  mov    %rdx,%r10
  test   %esi,%esi
  jle    L42
  lea    0x1(%rsi),%r11d
  mov    $0x1,%eax
  mov    $0x1,%edx
  jmp    L33
L27:
  movslq (%r10,%rax,4),%rsi
  add    (%rcx,%rsi,4),%edx
  add    $0x1,%rax
  cmp    %r11,%rax
  je     L6
L33:
  test   %edi,%edi
  je     L27
  mov    %edx,(%r9,%rax,4)
  jmp    L27
L42:
  mov    $0x1,%edx
L6:
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
```

assistant: ```c
void TRAN_Set_MP(int job, int atomnum, int *WhatSpecies, int *Spe_Total_CNO, int *NUM, int *MP) {
  int Anum, i, wanA, tnoA;
  Anum = 1;
  for (i = 1; i <= atomnum; i++) {
    if (job)
      MP[i] = Anum;
    wanA = WhatSpecies[i];
    tnoA = Spe_Total_CNO[wanA];
    Anum = Anum + tnoA;
  }
  *NUM = Anum - 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TRAN_Set_MP>:
  endbr64
  mov    %rdx,%r10
  test   %esi,%esi
  jle    L11
  lea    0x1(%rsi),%r11d
  mov    $0x1,%eax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L8:
  test   %edi,%edi
  je     L27
  mov    %edx,(%r9,%rax,4)
L27:
  movslq (%r10,%rax,4),%rsi
  add    $0x1,%rax
  add    (%rcx,%rsi,4),%edx
  cmp    %rax,%r11
  jne    L8
  sub    $0x1,%edx
  mov    %edx,(%r8)
  ret
  nop
L11:
  xor    %edx,%edx
  mov    %edx,(%r8)
  ret
```

assistant: ```c
void TRAN_Set_MP(int job, int atomnum, int *WhatSpecies, int *Spe_Total_CNO, int *NUM, int *MP) {
  int Anum, i, wanA, tnoA;
  Anum = 1;
  for (i = 1; i <= atomnum; i++) {
    if (job)
      MP[i] = Anum;
    wanA = WhatSpecies[i];
    tnoA = Spe_Total_CNO[wanA];
    Anum = Anum + tnoA;
  }
  *NUM = Anum - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<TRAN_Set_MP>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  test   %esi,%esi
  jle    L16
  test   %eax,%eax
  jne    L39
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdx),%rdx
  lea    0x8(%rdi,%rax,4),%rdi
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L47:
  movslq (%rdx),%rsi
  add    $0x4,%rdx
  add    (%rcx,%rsi,4),%eax
  cmp    %rdi,%rdx
  jne    L47
L31:
  sub    $0x1,%eax
  mov    %eax,(%r8)
  ret
  xchg   %ax,%ax
L39:
  lea    0x1(%rsi),%r10d
  mov    $0x1,%edx
  mov    $0x1,%eax
  xchg   %ax,%ax
L0:
  mov    %eax,(%r9,%rdx,4)
  movslq (%rdi,%rdx,4),%rsi
  add    $0x1,%rdx
  add    (%rcx,%rsi,4),%eax
  cmp    %r10,%rdx
  jne    L0
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void TRAN_Set_MP(int job, int atomnum, int *WhatSpecies, int *Spe_Total_CNO, int *NUM, int *MP) {
  int Anum, i, wanA, tnoA;
  Anum = 1;
  for (i = 1; i <= atomnum; i++) {
    if (job)
      MP[i] = Anum;
    wanA = WhatSpecies[i];
    tnoA = Spe_Total_CNO[wanA];
    Anum = Anum + tnoA;
  }
  *NUM = Anum - 1;
}
```