ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__glLightModelfv_size>:
  endbr64
  cmp    $0x82,%edi
  jle    L4
  xor    %eax,%eax
  cmp    $0x83,%edi
  sete   %al
  shl    $0x2,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  cmp    $0x7f,%edi
  setg   %al
  ret
```

assistant: ```c
__attribute__((visibility("internal"))) __attribute__((pure)) GLint __glLightModelfv_size(GLenum e) {
  switch (e) {
  case GL_LIGHT_MODEL_LOCAL_VIEWER:
  case GL_LIGHT_MODEL_TWO_SIDE:
  case GL_LIGHT_MODEL_COLOR_CONTROL:
    return 1;
  case GL_LIGHT_MODEL_AMBIENT:
    return 4;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8: %d

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", n * 3 / 10);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,2),%eax
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sar    $0x1f,%eax
  sub    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: %d

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", n * 3 / 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  lea    (%rax,%rax,2),%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: %d

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", n * 3 / 10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  lea    (%rax,%rax,2),%eax
  movslq %eax,%rsi
  sar    $0x1f,%eax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: %d

assistant: ```c
int main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", n * 3 / 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smooth_linearstep>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L44
  je     L41
L44:
  subss  %xmm0,%xmm1
  movss  D0(%rip),%xmm4
  divss  %xmm1,%xmm4
  mulss  %xmm4,%xmm3
  subss  %xmm0,%xmm2
  mulss  %xmm4,%xmm2
  movaps %xmm2,%xmm0
  movaps %xmm3,%xmm1
  xorps  D48(%rip),%xmm1
  comiss %xmm2,%xmm1
  jae    L56
  comiss %xmm3,%xmm2
  jb     L39
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm3,%xmm4
  movsd  D52(%rip),%xmm2
  subsd  %xmm4,%xmm2
  comisd %xmm1,%xmm2
  jae    L22
L39:
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm3,%xmm1
  addsd  D52(%rip),%xmm1
  comisd %xmm1,%xmm2
  jae    L4
  comiss %xmm0,%xmm3
  jbe    L42
  addss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  addss  %xmm3,%xmm3
  cvtss2sd %xmm3,%xmm3
  movsd  D66(%rip),%xmm1
  divsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L42:
  subsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  addss  %xmm3,%xmm3
  cvtss2sd %xmm3,%xmm3
  movsd  D66(%rip),%xmm1
  divsd  %xmm3,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  D0(%rip),%xmm0
  subss  %xmm1,%xmm0
  ret
L41:
  sub    $0x8,%rsp
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  mov    $0x2,%eax
  call   <step@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  add    $0x8,%rsp
  ret
L56:
  pxor   %xmm0,%xmm0
  ret
L4:
  movss  D0(%rip),%xmm0
  ret
L22:
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: f32
name: read_data
arguments: tag: D48
type: byte[16]
name: read_data
arguments: tag: D52
type: byte[8]
name: read_data
arguments: tag: D66
type: f64

tool: D0: 1

tool: {"D48": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D66: 0.5

assistant: ```c
float smooth_linearstep(float edge0, float edge1, float x_, float eps_) {
  float result;
  if (edge0 != edge1) {
    float rampup(float x, float r) { return 0.5 / r * x * x; }
    float width_inv = 1.0 / (edge1 - edge0);
    float eps = eps_ * width_inv;
    float x = (x_ - edge0) * width_inv;
    if (x <= -eps)
      result = 0;
    else if (x >= eps && x <= 1.0 - eps)
      result = x;
    else if (x >= 1.0 + eps)
      result = 1;
    else if (x < eps)
      result = rampup(x + eps, 2.0 * eps);
    else
      result = 1.0 - rampup(1.0 + eps - x, 2.0 * eps);
  } else {
    result = step(edge0, x_);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smooth_linearstep>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L18
  je     L14
L18:
  subss  %xmm0,%xmm1
  movss  D29(%rip),%xmm5
  subss  %xmm0,%xmm2
  movaps %xmm5,%xmm4
  divss  %xmm1,%xmm4
  mulss  %xmm4,%xmm3
  mulss  %xmm4,%xmm2
  movaps %xmm3,%xmm1
  xorps  D32(%rip),%xmm1
  movaps %xmm2,%xmm0
  comiss %xmm2,%xmm1
  jb     L51
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L51:
  comiss %xmm3,%xmm0
  pxor   %xmm4,%xmm4
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm4
  cvtss2sd %xmm3,%xmm1
  movsd  D16(%rip),%xmm2
  jb     L24
  movapd %xmm2,%xmm6
  subsd  %xmm1,%xmm6
  comisd %xmm4,%xmm6
  jb     L24
  ret
  nopl   0x0(%rax)
L24:
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm4
  jae    L66
  movaps %xmm3,%xmm6
  comiss %xmm0,%xmm3
  movsd  D25(%rip),%xmm2
  addss  %xmm3,%xmm6
  cvtss2sd %xmm6,%xmm6
  divsd  %xmm6,%xmm2
  jbe    L44
  addss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  sub    $0x8,%rsp
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm1
  call   <step@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %eax,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  movaps %xmm5,%xmm0
  ret
  nopl   0x0(%rax)
L44:
  subsd  %xmm4,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  cvtsd2ss %xmm2,%xmm2
  subss  %xmm2,%xmm5
  movaps %xmm5,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D29
datatype: f32
name: disassemble_data
arguments: label: D32
datatype: byte[16]
name: disassemble_data
arguments: label: D16
datatype: byte[8]
name: disassemble_data
arguments: label: D25
datatype: f64

tool: D29: 1

tool: {"D32": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D25: 0.5

assistant: ```c
float smooth_linearstep(float edge0, float edge1, float x_, float eps_) {
  float result;
  if (edge0 != edge1) {
    float rampup(float x, float r) { return 0.5 / r * x * x; }
    float width_inv = 1.0 / (edge1 - edge0);
    float eps = eps_ * width_inv;
    float x = (x_ - edge0) * width_inv;
    if (x <= -eps)
      result = 0;
    else if (x >= eps && x <= 1.0 - eps)
      result = x;
    else if (x >= 1.0 + eps)
      result = 1;
    else if (x < eps)
      result = rampup(x + eps, 2.0 * eps);
    else
      result = 1.0 - rampup(1.0 + eps - x, 2.0 * eps);
  } else {
    result = step(edge0, x_);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smooth_linearstep>:
  endbr64
  ucomiss %xmm1,%xmm0
  jp     L63
  je     L25
L63:
  subss  %xmm0,%xmm1
  movss  D27(%rip),%xmm5
  subss  %xmm0,%xmm2
  movaps %xmm5,%xmm4
  divss  %xmm1,%xmm4
  mulss  %xmm4,%xmm3
  mulss  %xmm4,%xmm2
  movaps %xmm3,%xmm1
  xorps  D9(%rip),%xmm1
  movaps %xmm2,%xmm0
  comiss %xmm2,%xmm1
  jb     L57
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L57:
  comiss %xmm3,%xmm0
  pxor   %xmm4,%xmm4
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm4
  cvtss2sd %xmm3,%xmm1
  movsd  D25(%rip),%xmm2
  jb     L0
  movapd %xmm2,%xmm6
  subsd  %xmm1,%xmm6
  comisd %xmm4,%xmm6
  jb     L0
  ret
  nopl   0x0(%rax)
L0:
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm4
  jae    L43
  movaps %xmm3,%xmm6
  comiss %xmm0,%xmm3
  movsd  D32(%rip),%xmm2
  addss  %xmm3,%xmm6
  cvtss2sd %xmm6,%xmm6
  divsd  %xmm6,%xmm2
  jbe    L62
  addss  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  cvtsd2ss %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  sub    $0x8,%rsp
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm1
  call   <step@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %eax,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  movaps %xmm5,%xmm0
  ret
  nopl   0x0(%rax)
L62:
  subsd  %xmm4,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  cvtsd2ss %xmm2,%xmm2
  subss  %xmm2,%xmm5
  movaps %xmm5,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D27
type_guessed: f32
name: read_data
arguments: tag: D9
type_guessed: byte[16]
name: read_data
arguments: tag: D25
type_guessed: byte[8]
name: read_data
arguments: tag: D32
type_guessed: f64

tool: D27: 1

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D32: 0.5

assistant: ```c
float smooth_linearstep(float edge0, float edge1, float x_, float eps_) {
  float result;
  if (edge0 != edge1) {
    float rampup(float x, float r) { return 0.5 / r * x * x; }
    float width_inv = 1.0 / (edge1 - edge0);
    float eps = eps_ * width_inv;
    float x = (x_ - edge0) * width_inv;
    if (x <= -eps)
      result = 0;
    else if (x >= eps && x <= 1.0 - eps)
      result = x;
    else if (x >= 1.0 + eps)
      result = 1;
    else if (x < eps)
      result = rampup(x + eps, 2.0 * eps);
    else
      result = 1.0 - rampup(1.0 + eps - x, 2.0 * eps);
  } else {
    result = step(edge0, x_);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn2(int a, int b) {
  int tem1 = b & a;
  int tem2 = a ^ b;
  return tem1 + tem2;
}
```
user: What is the c source code of the assembly code below?

```asm
<fn2>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn2(int a, int b) {
  int tem1 = b & a;
  int tem2 = a ^ b;
  return tem1 + tem2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn2>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn2(int a, int b) {
  int tem1 = b & a;
  int tem2 = a ^ b;
  return tem1 + tem2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fn2>:
  endbr64
  mov    %esi,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
int fn2(int a, int b) {
  int tem1 = b & a;
  int tem2 = a ^ b;
  return tem1 + tem2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <waitchildren@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void xexit(const char *name, const int exit_code) {
  waitchildren(name, 1);
  exit(exit_code);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xexit>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    $0x1,%esi
  call   <waitchildren@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void xexit(const char *name, const int exit_code) {
  waitchildren(name, 1);
  exit(exit_code);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xexit>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  call   <waitchildren@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void xexit(const char *name, const int exit_code) {
  waitchildren(name, 1);
  exit(exit_code);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xexit>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  call   <waitchildren@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void xexit(const char *name, const int exit_code) {
  waitchildren(name, 1);
  exit(exit_code);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dp_count_decoding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L83
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L83
  cmpq   $0x0,-0x20(%rbp)
  jne    L5
L83:
  mov    $0x0,%eax
  jmp    L22
L5:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  movl   $0x2,-0x10(%rbp)
  jmp    L66
L88:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jle    L62
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L62:
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L32
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  jne    L99
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x36,%al
  jg     L99
L32:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L99:
  addl   $0x1,-0x10(%rbp)
L66:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jae    L88
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L22:
  leave
  ret
```

assistant: ```c
int dp_count_decoding(char *str, size_t len) {
  int i, ret = 0;
  int *pc = NULL;
  if (NULL == str || str[0] == '0' || len == 0) {
    return 0;
  }
  pc = malloc(sizeof(int) * (len + 1));
  pc[0] = 1;
  pc[1] = 1;
  for (i = 2; i <= len; i++) {
    pc[i] = 0;
    if (str[i - 1] > '0') {
      pc[i] = pc[i - 1];
    }
    if (str[i - 2] == '1' || (str[i - 2] == '2' && str[i - 1] < '7')) {
      pc[i] += pc[i - 2];
    }
  }
  ret = pc[len];
  free(pc);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dp_count_decoding>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L99
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x30,(%rdi)
  je     L85
  test   %rsi,%rsi
  je     L85
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x1,(%rax)
  movl   $0x1,0x4(%rax)
  cmp    $0x1,%rbp
  jbe    L14
  mov    %rax,%rdx
  mov    %rbx,%rcx
  lea    -0x4(%rax,%rbp,4),%r10
  jmp    L53
L71:
  mov    (%r8),%eax
  add    %eax,0x8(%r8)
L106:
  add    $0x4,%rdx
  add    $0x1,%rcx
  cmp    %r10,%rdx
  je     L14
L53:
  mov    %rdx,%r8
  movl   $0x0,0x8(%rdx)
  mov    %rcx,%r9
  cmpb   $0x30,0x1(%rcx)
  jle    L22
  mov    0x4(%rdx),%eax
  mov    %eax,0x8(%rdx)
L22:
  movzbl (%r9),%esi
  cmp    $0x31,%sil
  je     L71
  cmp    $0x32,%sil
  jne    L106
  cmpb   $0x36,0x1(%r9)
  jg     L106
  jmp    L71
L14:
  mov    (%rdi,%rbp,4),%ebx
  call   <free@plt>
  jmp    L44
L99:
  mov    $0x0,%ebx
  jmp    L44
L85:
  mov    $0x0,%ebx
L44:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int dp_count_decoding(char *str, size_t len) {
  int i, ret = 0;
  int *pc = NULL;
  if (NULL == str || str[0] == '0' || len == 0) {
    return 0;
  }
  pc = malloc(sizeof(int) * (len + 1));
  pc[0] = 1;
  pc[1] = 1;
  for (i = 2; i <= len; i++) {
    pc[i] = 0;
    if (str[i - 1] > '0') {
      pc[i] = pc[i - 1];
    }
    if (str[i - 2] == '1' || (str[i - 2] == '2' && str[i - 1] < '7')) {
      pc[i] += pc[i - 2];
    }
  }
  ret = pc[len];
  free(pc);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dp_count_decoding>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L188
  cmpb   $0x30,(%rdi)
  mov    %rdi,%rbx
  je     L188
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L188
  lea    0x1(%rsi),%r12
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movabs $0x100000001,%rax
  mov    %rax,0x0(%r13)
  cmp    $0x1,%rbp
  je     L38
  lea    0x0(,%r12,4),%rcx
  lea    0x1(%rbx),%rax
  lea    0x0(%r13,%rcx,1),%rsi
  lea    -0x1(%rbp),%rdx
  cmp    %rax,%rsi
  lea    0x8(%r13),%rdi
  lea    (%rbx,%rdx,1),%r12
  setbe  %al
  cmp    %r12,%rdi
  setae  %r8b
  or     %r8b,%al
  je     L195
  lea    (%rbx,%rbp,1),%rax
  cmp    %rax,%rdi
  setae  %al
  cmp    %rsi,%rbx
  setae  %sil
  or     %sil,%al
  je     L195
  shl    $0x2,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rbx,%rax
  mov    %r13,%rdx
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L182:
  cmp    $0x32,%cl
  je     L7
L76:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    %r12,%rax
  je     L38
L58:
  cmpb   $0x30,0x1(%rax)
  jle    L166
  mov    0x4(%rdx),%ecx
  mov    %ecx,0x8(%rdx)
L166:
  movzbl (%rax),%ecx
  cmp    $0x31,%cl
  jne    L182
  mov    (%rdx),%ecx
  add    %ecx,0x8(%rdx)
L130:
  add    $0x1,%rax
  add    $0x4,%rdx
  cmp    %r12,%rax
  jne    L58
L38:
  mov    0x0(%r13,%rbp,4),%r12d
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L188:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  cmpb   $0x36,0x1(%rax)
  jg     L76
  mov    (%rdx),%ecx
  add    %ecx,0x8(%rdx)
  jmp    L130
L195:
  mov    %r13,%rdx
  mov    %rbx,%rax
  lea    -0x8(%r13,%rcx,1),%rsi
  jmp    L202
  nopw   0x0(%rax,%rax,1)
L43:
  cmp    $0x32,%cl
  je     L134
L201:
  add    $0x4,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  je     L38
L202:
  movl   $0x0,0x8(%rdx)
  cmpb   $0x30,0x1(%rax)
  jle    L33
  mov    0x4(%rdx),%ecx
  mov    %ecx,0x8(%rdx)
L33:
  movzbl (%rax),%ecx
  cmp    $0x31,%cl
  jne    L43
L32:
  mov    (%rdx),%ecx
  add    %ecx,0x8(%rdx)
  jmp    L201
  nopl   0x0(%rax)
L134:
  cmpb   $0x36,0x1(%rax)
  jg     L201
  jmp    L32
```

assistant: ```c
int dp_count_decoding(char *str, size_t len) {
  int i, ret = 0;
  int *pc = NULL;
  if (NULL == str || str[0] == '0' || len == 0) {
    return 0;
  }
  pc = malloc(sizeof(int) * (len + 1));
  pc[0] = 1;
  pc[1] = 1;
  for (i = 2; i <= len; i++) {
    pc[i] = 0;
    if (str[i - 1] > '0') {
      pc[i] = pc[i - 1];
    }
    if (str[i - 2] == '1' || (str[i - 2] == '2' && str[i - 1] < '7')) {
      pc[i] += pc[i - 2];
    }
  }
  ret = pc[len];
  free(pc);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dp_count_decoding>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L90
  cmpb   $0x30,(%rdi)
  mov    %rdi,%rbx
  je     L90
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L90
  lea    0x4(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    D1(%rip),%rax
  mov    %rax,(%rdi)
  cmp    $0x1,%rbp
  je     L3
  mov    %rdi,%rax
  lea    -0x4(%rdi,%rbp,4),%rsi
L44:
  movl   $0x0,0x8(%rax)
  xor    %edx,%edx
  cmpb   $0x30,0x1(%rbx)
  jle    L42
  mov    0x4(%rax),%edx
  mov    %edx,0x8(%rax)
L42:
  movzbl (%rbx),%ecx
  cmp    $0x31,%cl
  je     L22
  cmp    $0x32,%cl
  je     L43
L81:
  add    $0x4,%rax
  add    $0x1,%rbx
  cmp    %rsi,%rax
  jne    L44
L3:
  mov    (%rdi,%rbp,4),%r12d
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L90:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  cmpb   $0x36,0x1(%rbx)
  jg     L81
L22:
  add    (%rax),%edx
  mov    %edx,0x8(%rax)
  jmp    L81
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: byte[8]

tool: {"D1": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int dp_count_decoding(char *str, size_t len) {
  int i, ret = 0;
  int *pc = NULL;
  if (NULL == str || str[0] == '0' || len == 0) {
    return 0;
  }
  pc = malloc(sizeof(int) * (len + 1));
  pc[0] = 1;
  pc[1] = 1;
  for (i = 2; i <= len; i++) {
    pc[i] = 0;
    if (str[i - 1] > '0') {
      pc[i] = pc[i - 1];
    }
    if (str[i - 2] == '1' || (str[i - 2] == '2' && str[i - 1] < '7')) {
      pc[i] += pc[i - 2];
    }
  }
  ret = pc[len];
  free(pc);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3e8,%edi
  call   <search@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  search(1000);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <search@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  search(1000);
  return 0;
}
```