ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<execute_qpu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %esi,-0xa8(%rbp)
  mov    %edx,-0xac(%rbp)
  mov    %ecx,-0xb0(%rbp)
  mov    %r8d,-0xb4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x30011,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x10,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x10,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xa8(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xac(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xb0(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  mov    -0xb4(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x94(%rbp)
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  mov    -0x94(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x90(%rbp)
  lea    -0x90(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mbox_property@plt>
  mov    -0x7c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
unsigned int execute_qpu(int file_desc, unsigned int num_qpus, unsigned int control, unsigned int noflush, unsigned int timeout) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30011;
  p[i++] = 16;
  p[i++] = 16;
  p[i++] = num_qpus;
  p[i++] = control;
  p[i++] = noflush;
  p[i++] = timeout;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: Translate the below assembly code into C programming language:

```asm
<execute_qpu>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x30011,0x8(%rsp)
  movl   $0x10,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x28,(%rsp)
  mov    %rsp,%rsi
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x98,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int execute_qpu(int file_desc, unsigned int num_qpus, unsigned int control, unsigned int noflush, unsigned int timeout) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30011;
  p[i++] = 16;
  p[i++] = 16;
  p[i++] = num_qpus;
  p[i++] = control;
  p[i++] = noflush;
  p[i++] = timeout;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<execute_qpu>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %esi,0x14(%rsp)
  mov    %rsp,%rsi
  movabs $0x1000030011,%rax
  mov    %edx,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movq   $0x28,(%rsp)
  mov    %rax,0x8(%rsp)
  movl   $0x10,0x10(%rsp)
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x98,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int execute_qpu(int file_desc, unsigned int num_qpus, unsigned int control, unsigned int noflush, unsigned int timeout) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30011;
  p[i++] = 16;
  p[i++] = 16;
  p[i++] = num_qpus;
  p[i++] = control;
  p[i++] = noflush;
  p[i++] = timeout;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<execute_qpu>:
  endbr64
  movd   %ecx,%xmm1
  movd   %r8d,%xmm2
  movd   %esi,%xmm0
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  mov    %rsp,%rsi
  punpckldq %xmm3,%xmm0
  movl   $0x10,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movl   $0x0,0x24(%rsp)
  movups %xmm0,0x14(%rsp)
  movdqa D5(%rip),%xmm0
  movaps %xmm0,(%rsp)
  call   <mbox_property@plt>
  mov    0x14(%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x98,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: byte[16]

tool: {"D5": [0x28,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x11,0x00,0x03,0x00,0x10,0x00,0x00,0x00]}

assistant: ```c
unsigned int execute_qpu(int file_desc, unsigned int num_qpus, unsigned int control, unsigned int noflush, unsigned int timeout) {
  int i = 0;
  unsigned int p[32];
  p[i++] = 0;
  p[i++] = 0x00000000;
  p[i++] = 0x30011;
  p[i++] = 16;
  p[i++] = 16;
  p[i++] = num_qpus;
  p[i++] = control;
  p[i++] = noflush;
  p[i++] = timeout;
  p[i++] = 0x00000000;
  p[0] = i * sizeof *p;
  mbox_property(file_desc, p);
  return p[5];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x77202c6f6c6c6548,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x646c726f,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D68
datatype: string
name: extract_symbolic_data
arguments: data_label: D40
datatype: string
name: extract_symbolic_data
arguments: data_label: D46
datatype: string
name: extract_symbolic_data
arguments: data_label: D44
datatype: string
name: extract_symbolic_data
arguments: data_label: D47
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D16
datatype: string
name: extract_symbolic_data
arguments: data_label: D29
datatype: string
name: extract_symbolic_data
arguments: data_label: D24
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string

tool: D68: 123456789012345678901234567890

tool: D40: %s*


tool: D46: %20s*


tool: D44: %.20s*


tool: D47: %-20s*


tool: D13: %.10s*


tool: D16: %-10s*


tool: D29: %25.10s*


tool: D24: %25.5s*


tool: D36: %-25.10s*


assistant: ```c
int main() {
  char text[13] = "Hello, world";
  printf("123456789012345678901234567890\n");
  printf("%s*\n", text);
  printf("%20s*\n", text);
  printf("%.20s*\n", text);
  printf("%-20s*\n", text);
  printf("%.10s*\n", text);
  printf("%-10s*\n", text);
  printf("%25.10s*\n", text);
  printf("%25.5s*\n", text);
  printf("%-25.10s*\n", text);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x77202c6f6c6c6548,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x646c726f,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0xb(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D73(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D79(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D75(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string
name: disassemble_data
arguments: data_tag: D73
datatype: string
name: disassemble_data
arguments: data_tag: D48
datatype: string
name: disassemble_data
arguments: data_tag: D58
datatype: string
name: disassemble_data
arguments: data_tag: D79
datatype: string
name: disassemble_data
arguments: data_tag: D46
datatype: string
name: disassemble_data
arguments: data_tag: D66
datatype: string
name: disassemble_data
arguments: data_tag: D38
datatype: string
name: disassemble_data
arguments: data_tag: D75
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D3: 123456789012345678901234567890

tool: D73: %s*


tool: D48: %20s*


tool: D58: %.20s*


tool: D79: %-20s*


tool: D46: %.10s*


tool: D66: %-10s*


tool: D38: %25.10s*


tool: D75: %25.5s*


tool: D7: %-25.10s*


assistant: ```c
int main() {
  char text[13] = "Hello, world";
  printf("123456789012345678901234567890\n");
  printf("%s*\n", text);
  printf("%20s*\n", text);
  printf("%.20s*\n", text);
  printf("%-20s*\n", text);
  printf("%.10s*\n", text);
  printf("%-10s*\n", text);
  printf("%25.10s*\n", text);
  printf("%25.5s*\n", text);
  printf("%-25.10s*\n", text);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D43(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x77202c6f6c6c6548,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x646c726f,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D91(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D78(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D91
type_infered: string
name: unpack_data
arguments: data_label: D49
type_infered: string
name: unpack_data
arguments: data_label: D71
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D88
type_infered: string
name: unpack_data
arguments: data_label: D78
type_infered: string

tool: D43: 123456789012345678901234567890

tool: D9: %s*


tool: D91: %20s*


tool: D49: %.20s*


tool: D71: %-20s*


tool: D12: %.10s*


tool: D23: %-10s*


tool: D10: %25.10s*


tool: D88: %25.5s*


tool: D78: %-25.10s*


assistant: ```c
int main() {
  char text[13] = "Hello, world";
  printf("123456789012345678901234567890\n");
  printf("%s*\n", text);
  printf("%20s*\n", text);
  printf("%.20s*\n", text);
  printf("%-20s*\n", text);
  printf("%.10s*\n", text);
  printf("%-10s*\n", text);
  printf("%25.10s*\n", text);
  printf("%25.5s*\n", text);
  printf("%-25.10s*\n", text);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D98(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x77202c6f6c6c6548,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x646c726f,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D74(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D85(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D98
type_guessed: string
name: read_data
arguments: data_tag: D41
type_guessed: string
name: read_data
arguments: data_tag: D61
type_guessed: string
name: read_data
arguments: data_tag: D52
type_guessed: string
name: read_data
arguments: data_tag: D71
type_guessed: string
name: read_data
arguments: data_tag: D40
type_guessed: string
name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D74
type_guessed: string
name: read_data
arguments: data_tag: D85
type_guessed: string
name: read_data
arguments: data_tag: D72
type_guessed: string

tool: D98: 123456789012345678901234567890

tool: D41: %s*


tool: D61: %20s*


tool: D52: %.20s*


tool: D71: %-20s*


tool: D40: %.10s*


tool: D39: %-10s*


tool: D74: %25.10s*


tool: D85: %25.5s*


tool: D72: %-25.10s*


assistant: ```c
int main() {
  char text[13] = "Hello, world";
  printf("123456789012345678901234567890\n");
  printf("%s*\n", text);
  printf("%20s*\n", text);
  printf("%.20s*\n", text);
  printf("%-20s*\n", text);
  printf("%.10s*\n", text);
  printf("%-10s*\n", text);
  printf("%25.10s*\n", text);
  printf("%25.5s*\n", text);
  printf("%-25.10s*\n", text);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rop3_217_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_217_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_217_1_0>:
  endbr64
  mov    %esi,%eax
  or     (%rdi),%sil
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_217_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_217_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_217_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_217_1_0>:
  endbr64
  mov    %esi,%eax
  movzbl (%rdi),%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_217_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_alarm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <set_cooked@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_alarm(int x) {
  set_cooked();
  exit(2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<handle_alarm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <set_cooked@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handle_alarm(int x) {
  set_cooked();
  exit(2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_alarm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <set_cooked@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void handle_alarm(int x) {
  set_cooked();
  exit(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBFIFOFlush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  add    $0x102,%eax
  cltq
  mov    (%rax),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L49
  mov    -0x4(%rbp),%eax
  add    $0x103,%eax
  cltq
  movl   $0x1,(%rax)
  jmp    L49
L29:
  mov    -0xc(%rbp),%eax
  and    $0x2000,%eax
  test   %eax,%eax
  je     L12
  mov    -0x4(%rbp),%eax
  lea    0x112(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L49
  mov    -0x4(%rbp),%eax
  lea    0x112(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  lea    0x112(%rdx),%ecx
  mov    -0x8(%rbp),%edx
  sub    $0x10,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  or     $0x8,%eax
  mov    %eax,(%rdx)
  jmp    L49
L12:
  mov    -0x4(%rbp),%eax
  lea    0x116(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L49
  mov    -0x4(%rbp),%eax
  lea    0x116(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    $0x10,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  lea    0x116(%rdx),%ecx
  mov    -0x8(%rbp),%edx
  sub    $0x10,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  or     $0x10,%eax
  mov    %eax,(%rdx)
L49:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBFIFOFlush(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if (((*((volatile uint8_t *)(ui32Base + 0x00000102))) & (0x00000001 | 0x00000002)) != 0) {
      (*((volatile uint8_t *)(ui32Base + 0x00000103))) = 0x00000001;
    }
  } else {
    if (ui32Flags & (0x00002000 | 0x00002000)) {
      if ((*((volatile uint8_t *)(ui32Base + 0x00000112 + (ui32Endpoint - 0x10)))) & 0x00000001) {
        (*((volatile uint8_t *)(ui32Base + 0x00000112 + (ui32Endpoint - 0x10)))) |= 0x00000008;
      }
    } else {
      if ((*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) & 0x00000001) {
        (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) |= 0x00000010;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<USBFIFOFlush>:
  endbr64
  test   %esi,%esi
  jne    L34
  lea    0x102(%rdi),%eax
  cltq
  mov    (%rax),%eax
  test   $0x3,%al
  je     L8
  add    $0x103,%edi
  movslq %edi,%rdi
  movl   $0x1,(%rdi)
  ret
L34:
  test   $0x20,%dh
  je     L37
  lea    0x102(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  test   $0x1,%dl
  je     L8
  mov    (%rax),%edx
  or     $0x8,%edx
  mov    %edx,(%rax)
  ret
L37:
  lea    0x106(%rdi,%rsi,1),%eax
  cltq
  mov    (%rax),%edx
  test   $0x1,%dl
  je     L8
  mov    (%rax),%edx
  or     $0x10,%edx
  mov    %edx,(%rax)
L8:
  ret
```

assistant: ```c
void USBFIFOFlush(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Flags) {
  ;

  ;
  if (ui32Endpoint == 0x00000000) {
    if (((*((volatile uint8_t *)(ui32Base + 0x00000102))) & (0x00000001 | 0x00000002)) != 0) {
      (*((volatile uint8_t *)(ui32Base + 0x00000103))) = 0x00000001;
    }
  } else {
    if (ui32Flags & (0x00002000 | 0x00002000)) {
      if ((*((volatile uint8_t *)(ui32Base + 0x00000112 + (ui32Endpoint - 0x10)))) & 0x00000001) {
        (*((volatile uint8_t *)(ui32Base + 0x00000112 + (ui32Endpoint - 0x10)))) |= 0x00000008;
      }
    } else {
      if ((*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) & 0x00000001) {
        (*((volatile uint8_t *)(ui32Base + 0x00000116 + (ui32Endpoint - 0x10)))) |= 0x00000010;
      }
    }
  }
}
```