ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x18(%rbp)
  je     L5
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D27
type: string
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D4
type: string
name: retrieve_data
arguments: data_tag: D25
type: string

tool: D2: newpath

tool: D27: %d %d %d %d %d arc


tool: D15: closepath

tool: D4: fill

tool: D25: ST

assistant: ```c
void arc(int x, int y, int r, int ang1, int ang2, int fill) {
  printf("newpath\n");
  printf("%d %d %d %d %d arc\n", x, y, r, ang1, ang2);
  printf("closepath\n");
  if (fill)
    printf("fill\n");
  printf("ST\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<arc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %ecx,%r14d
  mov    %r8d,%r15d
  mov    %r9d,%ebx
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jne    L1
L19:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D43
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D6: newpath

tool: D19: %d %d %d %d %d arc


tool: D38: closepath

tool: D43: ST

tool: D2: fill

assistant: ```c
void arc(int x, int y, int r, int ang1, int ang2, int fill) {
  printf("newpath\n");
  printf("%d %d %d %d %d arc\n", x, y, r, ang1, ang2);
  printf("closepath\n");
  if (fill)
    printf("fill\n");
  printf("ST\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arc>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D20(%rip),%rdi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jne    L12
L7:
  add    $0x8,%rsp
  lea    D22(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
  nopl   (%rax)
L12:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D20
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D12
datatype: string

tool: D20: newpath

tool: D17: %d %d %d %d %d arc


tool: D37: closepath

tool: D22: ST

tool: D12: fill

assistant: ```c
void arc(int x, int y, int r, int ang1, int ang2, int fill) {
  printf("newpath\n");
  printf("%d %d %d %d %d arc\n", x, y, r, ang1, ang2);
  printf("closepath\n");
  if (fill)
    printf("fill\n");
  printf("ST\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<arc>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D31(%rip),%rdi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jne    L1
L19:
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
  nopl   (%rax)
L1:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_label: D31
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D49
datatype: string

tool: D31: newpath

tool: D7: %d %d %d %d %d arc


tool: D22: closepath

tool: D0: ST

tool: D49: fill

assistant: ```c
void arc(int x, int y, int r, int ang1, int ang2, int fill) {
  printf("newpath\n");
  printf("%d %d %d %d %d arc\n", x, y, r, ang1, ang2);
  printf("closepath\n");
  if (fill)
    printf("fill\n");
  printf("ST\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x1c(%rbp)
  jmp    L11
L12:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L11:
  cmpl   $0x5d,-0x1c(%rbp)
  jle    L12
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string

tool: D12: %lli, 

tool: D27: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 

assistant: ```c
int main() {
  long long unsigned int L1, L2, L3;
  int a;
  L1 = 2;
  L2 = 1;
  printf("%lli, ", L1);
  printf("%lli, ", L2);
  for (a = 2; a <= 93; a++) {
    L3 = L2 + L1;
    printf("%lli, ", L3);
    L1 = L2;
    L2 = L3;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 ");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5c,%ebp
  mov    $0x1,%ebx
  mov    $0x2,%eax
  lea    D0(%rip),%r13
L9:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L9
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D0: %lli, 

tool: D9: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 

assistant: ```c
int main() {
  long long unsigned int L1, L2, L3;
  int a;
  L1 = 2;
  L2 = 1;
  printf("%lli, ", L1);
  printf("%lli, ", L2);
  for (a = 2; a <= 93; a++) {
    L3 = L2 + L1;
    printf("%lli, ", L3);
    L1 = L2;
    L2 = L3;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 ");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x5c,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L2
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D3: %lli, 

tool: D8: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 

assistant: ```c
int main() {
  long long unsigned int L1, L2, L3;
  int a;
  L1 = 2;
  L2 = 1;
  printf("%lli, ", L1);
  printf("%lli, ", L2);
  for (a = 2; a <= 93; a++) {
    L3 = L2 + L1;
    printf("%lli, ", L3);
    L1 = L2;
    L2 = L3;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 ");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%r13
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x5c,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%r12
  add    %rax,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rax
  sub    $0x1,%ebp
  jne    L8
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string

tool: D14: %lli, 

tool: D13: 27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 

assistant: ```c
int main() {
  long long unsigned int L1, L2, L3;
  int a;
  L1 = 2;
  L2 = 1;
  printf("%lli, ", L1);
  printf("%lli, ", L2);
  for (a = 2; a <= 93; a++) {
    L3 = L2 + L1;
    printf("%lli, ", L3);
    L1 = L2;
    L2 = L3;
  }
  printf("27280388024614569596, 44140595050111976643, 71420983074726546239, 115561578124838522882, 186982561199565069121, 302544139324403592003, 489526700523968661124, 792070839848372253127 ");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<suc_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L44:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L31
  cmpl   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L31
L19:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
L31:
  addl   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L44
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *suc_words(char *str) {
  int i;
  int x = strlen(str);
  for (i = 0; i < x; ++i) {
    if (isalpha(str[i]) && (!i || str[i - 1] == ' ')) {
      str[i] = toupper(str[i]);
    }
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<suc_words>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L20
  mov    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L62
L59:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
L37:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L20
L62:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L37
  test   %ebx,%ebx
  je     L59
  cmpb   $0x20,-0x1(%rbp,%rbx,1)
  jne    L37
  jmp    L59
L20:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *suc_words(char *str) {
  int i;
  int x = strlen(str);
  for (i = 0; i < x; ++i) {
    if (isalpha(str[i]) && (!i || str[i - 1] == ' ')) {
      str[i] = toupper(str[i]);
    }
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<suc_words>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L34
  movslq %eax,%rbp
  xor    %ebx,%ebx
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L64:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L34
L25:
  movsbl (%r12,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L64
  test   %rbx,%rbx
  je     L56
  cmpb   $0x20,-0x1(%r12,%rbx,1)
  jne    L64
L56:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L25
L34:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *suc_words(char *str) {
  int i;
  int x = strlen(str);
  for (i = 0; i < x; ++i) {
    if (isalpha(str[i]) && (!i || str[i - 1] == ' ')) {
      str[i] = toupper(str[i]);
    }
  }
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<suc_words>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L43
  movslq %eax,%rbp
  xor    %ebx,%ebx
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L55:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L43
L35:
  movsbl (%r12,%rbx,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L55
  test   %rbx,%rbx
  je     L30
  cmpb   $0x20,-0x1(%r12,%rbx,1)
  jne    L55
L30:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L35
L43:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *suc_words(char *str) {
  int i;
  int x = strlen(str);
  for (i = 0; i < x; ++i) {
    if (isalpha(str[i]) && (!i || str[i - 1] == ' ')) {
      str[i] = toupper(str[i]);
    }
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tcsendbreak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L18
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  jmp    L1
L18:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

assistant: ```c
int tcsendbreak(int fd, int duration) {
  if (duration <= 0)
    return ioctl(fd, TCSBRK, 0);
  __set_errno(EINVAL);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tcsendbreak>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jg     L8
  mov    $0x0,%edx
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
L13:
  add    $0x8,%rsp
  ret
L8:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L13
```

assistant: ```c
int tcsendbreak(int fd, int duration) {
  if (duration <= 0)
    return ioctl(fd, TCSBRK, 0);
  __set_errno(EINVAL);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tcsendbreak>:
  endbr64
  test   %esi,%esi
  jg     L6
  mov    D15(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1070 <ioctl@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tcsendbreak(int fd, int duration) {
  if (duration <= 0)
    return ioctl(fd, TCSBRK, 0);
  __set_errno(EINVAL);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tcsendbreak>:
  endbr64
  test   %esi,%esi
  jg     L9
  mov    D15(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%esi
  jmp    1070 <ioctl@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tcsendbreak(int fd, int duration) {
  if (duration <= 0)
    return ioctl(fd, TCSBRK, 0);
  __set_errno(EINVAL);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  mov    -0x4c(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <fcvt@plt>
  mov    %eax,%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  jne    L7
  mov    -0x38(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L0
L7:
  mov    -0x48(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x38(%rbp),%edx
  mov    -0x48(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L0:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void itoa(char *s, int nr) {
  int dec, sign;
  char temp[30];
  strcpy(temp, fcvt(nr, 0, &dec, &sign));
  if (sign == 0) {
    strncpy(s, temp, dec);
    s[dec] = '\0';
  } else {
    s[0] = '-';
    strncpy(s + 1, temp, dec);
    s[dec + 1] = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    $0x0,%esi
  call   <fcvt@plt>
  mov    %eax,%esi
  lea    0x10(%rsp),%rdi
  call   <strcpy@plt>
  cmpl   $0x0,0xc(%rsp)
  jne    L17
  lea    0x10(%rsp),%rsi
  mov    0x8(%rsp),%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,(%rbx,%rax,1)
L12:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  pop    %rbx
  ret
L17:
  movb   $0x2d,(%rbx)
  lea    0x10(%rsp),%rsi
  lea    0x1(%rbx),%rdi
  mov    0x8(%rsp),%edx
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,0x1(%rbx,%rax,1)
  jmp    L12
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *s, int nr) {
  int dec, sign;
  char temp[30];
  strcpy(temp, fcvt(nr, 0, &dec, &sign));
  if (sign == 0) {
    strncpy(s, temp, dec);
    s[dec] = '\0';
  } else {
    s[0] = '-';
    strncpy(s + 1, temp, dec);
    s[dec + 1] = '\0';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  xor    %esi,%esi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <fcvt@plt>
  lea    0x10(%rsp),%rbp
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L24
  mov    0x8(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,(%rbx,%rax,1)
L12:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  movb   $0x2d,(%rbx)
  mov    0x8(%rsp),%edx
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,0x1(%rbx,%rax,1)
  jmp    L12
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *s, int nr) {
  int dec, sign;
  char temp[30];
  strcpy(temp, fcvt(nr, 0, &dec, &sign));
  if (sign == 0) {
    strncpy(s, temp, dec);
    s[dec] = '\0';
  } else {
    s[0] = '-';
    strncpy(s + 1, temp, dec);
    s[dec + 1] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  xor    %esi,%esi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  call   <fcvt@plt>
  lea    0x10(%rsp),%rbp
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L10
  mov    0x8(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,(%rbx,%rax,1)
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  movb   $0x2d,(%rbx)
  mov    0x8(%rsp),%edx
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movslq 0x8(%rsp),%rax
  movb   $0x0,0x1(%rbx,%rax,1)
  jmp    L13
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa(char *s, int nr) {
  int dec, sign;
  char temp[30];
  strcpy(temp, fcvt(nr, 0, &dec, &sign));
  if (sign == 0) {
    strncpy(s, temp, dec);
    s[dec] = '\0';
  } else {
    s[0] = '-';
    strncpy(s + 1, temp, dec);
    s[dec + 1] = '\0';
  }
}
```