ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cmd_BotRemove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  je     L16
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L5
L16:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <GetCvarInt@plt>
  test   %eax,%eax
  jg     L32
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L5
L32:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D37: Usage: bot_remove <client number>


tool: D23: sv_running

tool: D7: Server is not running.


tool: D4: Would attempt to remove client %i here


assistant: ```c
void Cmd_BotRemove() {
  int argc = Cmd_Argc();
  if (argc != 2) {
    Com_Printf("Usage: bot_remove <client number>\n");
    return;
  }
  if (GetCvarInt("sv_running") < 1) {
    Com_Printf("Server is not running.\n");
    return;
  }
  char *client = Cmd_Argv(1);
  Com_Printf("Would attempt to remove client %i here\n", atoi(client));
}
```
user: What is the c source code of the assembly code below?

```asm
<Cmd_BotRemove>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L31
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
L26:
  add    $0x8,%rsp
  ret
L31:
  lea    D0(%rip),%rdi
  call   <GetCvarInt@plt>
  test   %eax,%eax
  jle    L38
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L26
L38:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <Com_Printf@plt>
  jmp    L26
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D5: Usage: bot_remove <client number>


tool: D0: sv_running

tool: D36: Would attempt to remove client %i here


tool: D15: Server is not running.


assistant: ```c
void Cmd_BotRemove() {
  int argc = Cmd_Argc();
  if (argc != 2) {
    Com_Printf("Usage: bot_remove <client number>\n");
    return;
  }
  if (GetCvarInt("sv_running") < 1) {
    Com_Printf("Server is not running.\n");
    return;
  }
  char *client = Cmd_Argv(1);
  Com_Printf("Would attempt to remove client %i here\n", atoi(client));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Cmd_BotRemove>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L2
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <Com_Printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    D0(%rip),%rdi
  call   <GetCvarInt@plt>
  test   %eax,%eax
  jle    L7
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    D24(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <Com_Printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <Com_Printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string

tool: D36: Usage: bot_remove <client number>


tool: D0: sv_running

tool: D24: Would attempt to remove client %i here


tool: D35: Server is not running.


assistant: ```c
void Cmd_BotRemove() {
  int argc = Cmd_Argc();
  if (argc != 2) {
    Com_Printf("Usage: bot_remove <client number>\n");
    return;
  }
  if (GetCvarInt("sv_running") < 1) {
    Com_Printf("Server is not running.\n");
    return;
  }
  char *client = Cmd_Argv(1);
  Com_Printf("Would attempt to remove client %i here\n", atoi(client));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Cmd_BotRemove>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L4
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <Com_Printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    D12(%rip),%rdi
  call   <GetCvarInt@plt>
  test   %eax,%eax
  jle    L16
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <Com_Printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <Com_Printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D28
type: string
name: disassemble_data
arguments: tag: D11
type: string

tool: D23: Usage: bot_remove <client number>


tool: D12: sv_running

tool: D28: Would attempt to remove client %i here


tool: D11: Server is not running.


assistant: ```c
void Cmd_BotRemove() {
  int argc = Cmd_Argc();
  if (argc != 2) {
    Com_Printf("Usage: bot_remove <client number>\n");
    return;
  }
  if (GetCvarInt("sv_running") < 1) {
    Com_Printf("Server is not running.\n");
    return;
  }
  char *client = Cmd_Argv(1);
  Com_Printf("Would attempt to remove client %i here\n", atoi(client));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_119_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_119_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & S;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_119_0_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  movzbl (%rcx),%eax
  mov    %esi,%edx
  not    %edx
  and    %edi,%edx
  and    %eax,%edx
  mov    %eax,%r8d
  not    %r8d
  and    %esi,%r8d
  or     %r8d,%edx
  and    %esi,%eax
  or     %edi,%eax
  not    %eax
  or     %eax,%edx
  mov    %dl,(%rcx)
  ret
```

assistant: ```c
void rop3_119_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & S;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_119_0_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %esi,%edx
  movzbl (%rcx),%eax
  not    %edx
  and    %edi,%edx
  mov    %eax,%r8d
  and    %eax,%edx
  and    %esi,%eax
  not    %r8d
  or     %edi,%eax
  and    %esi,%r8d
  not    %eax
  or     %r8d,%edx
  or     %eax,%edx
  mov    %dl,(%rcx)
  ret
```

assistant: ```c
void rop3_119_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & S;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rop3_119_0_1>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %esi,%edx
  movzbl (%rcx),%eax
  not    %edx
  and    %edi,%edx
  mov    %eax,%r8d
  and    %eax,%edx
  and    %esi,%eax
  not    %r8d
  or     %edi,%eax
  and    %esi,%r8d
  not    %eax
  or     %r8d,%edx
  or     %eax,%edx
  mov    %dl,(%rcx)
  ret
```

assistant: ```c
void rop3_119_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = *D & S;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<slurp_small>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L39:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <load32@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
  subl   $0x4,-0x1c(%rbp)
L10:
  cmpl   $0x3,-0x1c(%rbp)
  jg     L39
  mov    -0x1c(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L30
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <load16@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x2,-0x8(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
__attribute__((optimize("no-unroll-loops"))) __attribute__((always_)) uint64_t slurp_small(const void *ptr, uint32_t nbytes) {
  const unsigned char *cptr = ptr;
  uint64_t sum = 0;
  while (nbytes >= 4) {
    sum += load32(cptr);
    cptr += 4;
    nbytes -= 4;
  }
  if (nbytes & 2) {
    sum += load16(cptr);
    cptr += 2;
  }
  if (nbytes & 1) {
    sum += (uint8_t)*cptr;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<slurp_small>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  cmp    $0x3,%esi
  jle    L20
  lea    -0x4(%rsi),%r14d
  shr    $0x2,%r14d
  lea    0x1(%r14),%eax
  mov    %eax,%eax
  lea    (%rdi,%rax,4),%r12
  mov    $0x0,%ebp
L45:
  mov    %rbx,%rdi
  call   <load32@plt>
  add    %eax,%ebp
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L45
  neg    %r14d
  lea    -0x4(%r13,%r14,4),%r13d
L46:
  test   $0x2,%r13b
  jne    L48
L32:
  test   $0x1,%r13b
  je     L39
  movzbl (%r12),%eax
  add    %eax,%ebp
L39:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    %rdi,%r12
  mov    $0x0,%ebp
  jmp    L46
L48:
  mov    %r12,%rdi
  call   <load16@plt>
  add    %eax,%ebp
  add    $0x2,%r12
  jmp    L32
```

assistant: ```c
__attribute__((optimize("no-unroll-loops"))) __attribute__((always_)) uint64_t slurp_small(const void *ptr, uint32_t nbytes) {
  const unsigned char *cptr = ptr;
  uint64_t sum = 0;
  while (nbytes >= 4) {
    sum += load32(cptr);
    cptr += 4;
    nbytes -= 4;
  }
  if (nbytes & 2) {
    sum += load16(cptr);
    cptr += 2;
  }
  if (nbytes & 1) {
    sum += (uint8_t)*cptr;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slurp_small>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x3,%esi
  jle    L30
  sub    $0x4,%r13d
  xor    %r12d,%r12d
  mov    %r13d,%r14d
  shr    $0x2,%r14d
  lea    0x1(%r14),%eax
  lea    (%rdi,%rax,4),%rbp
  nopl   (%rax)
L20:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <load32@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L20
  neg    %r14d
  lea    0x0(%r13,%r14,4),%r13d
L19:
  test   $0x2,%r13b
  jne    L58
L49:
  and    $0x1,%r13d
  je     L11
  movzbl 0x0(%rbp),%eax
  add    %eax,%r12d
L11:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbp,%rdi
  add    $0x2,%rbp
  call   <load16@plt>
  add    %eax,%r12d
  jmp    L49
  nopl   0x0(%rax)
L30:
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  jmp    L19
```

assistant: ```c
__attribute__((optimize("no-unroll-loops"))) __attribute__((always_)) uint64_t slurp_small(const void *ptr, uint32_t nbytes) {
  const unsigned char *cptr = ptr;
  uint64_t sum = 0;
  while (nbytes >= 4) {
    sum += load32(cptr);
    cptr += 4;
    nbytes -= 4;
  }
  if (nbytes & 2) {
    sum += load16(cptr);
    cptr += 2;
  }
  if (nbytes & 1) {
    sum += (uint8_t)*cptr;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<slurp_small>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x3,%esi
  jle    L32
  sub    $0x4,%r13d
  xor    %r15d,%r15d
  mov    %r13d,%r14d
  shr    $0x2,%r14d
  lea    0x1(%r14),%eax
  lea    (%rdi,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <load32@plt>
  lea    (%r15,%rax,1),%ebp
  mov    %ebp,%r15d
  cmp    %r12,%rbx
  jne    L23
  neg    %r14d
  lea    0x0(%r13,%r14,4),%r13d
L11:
  test   $0x2,%r13b
  jne    L21
L39:
  and    $0x1,%r13d
  je     L49
  movzbl (%r12),%r15d
  add    %ebp,%r15d
L49:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L21:
  mov    %r12,%rdi
  add    $0x2,%r12
  call   <load16@plt>
  add    %eax,%ebp
  mov    %ebp,%r15d
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rdi,%r12
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  jmp    L11
```

assistant: ```c
__attribute__((optimize("no-unroll-loops"))) __attribute__((always_)) uint64_t slurp_small(const void *ptr, uint32_t nbytes) {
  const unsigned char *cptr = ptr;
  uint64_t sum = 0;
  while (nbytes >= 4) {
    sum += load32(cptr);
    cptr += 4;
    nbytes -= 4;
  }
  if (nbytes & 2) {
    sum += load16(cptr);
    cptr += 2;
  }
  if (nbytes & 1) {
    sum += (uint8_t)*cptr;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L26
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L31:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x0,-0x8(%rbp)
  jle    L44
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L31
L44:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int *lista, int total) {
  int primero, segundo, indice;
  for (primero = 1; primero <= total - 1; primero++) {
    segundo = primero;
    while (segundo > 0 && lista[segundo] < lista[segundo - 1]) {
      indice = lista[segundo];
      lista[segundo] = lista[segundo - 1];
      lista[segundo - 1] = indice;
      segundo--;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  jmp    L29
L56:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  je     L12
L29:
  test   %r8d,%r8d
  jle    L56
  mov    %r9,%rax
L14:
  mov    (%rax),%ecx
  mov    -0x4(%rax),%edx
  cmp    %edx,%ecx
  jge    L56
  mov    %edx,(%rax)
  mov    %ecx,-0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L14
  jmp    L56
L12:
  ret
```

assistant: ```c
void insertion_sort(int *lista, int total) {
  int primero, segundo, indice;
  for (primero = 1; primero <= total - 1; primero++) {
    segundo = primero;
    while (segundo > 0 && lista[segundo] < lista[segundo - 1]) {
      indice = lista[segundo];
      lista[segundo] = lista[segundo - 1];
      lista[segundo - 1] = indice;
      segundo--;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L17
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rax),%ecx
  mov    -0x4(%rax),%edx
  cmp    %edx,%ecx
  jge    L1
  mov    %edx,(%rax)
  sub    $0x4,%rax
  mov    %ecx,(%rax)
  cmp    %rdi,%rax
  jne    L3
L1:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L26
  ret
L17:
  ret
```

assistant: ```c
void insertion_sort(int *lista, int total) {
  int primero, segundo, indice;
  for (primero = 1; primero <= total - 1; primero++) {
    segundo = primero;
    while (segundo > 0 && lista[segundo] < lista[segundo - 1]) {
      indice = lista[segundo];
      lista[segundo] = lista[segundo - 1];
      lista[segundo - 1] = indice;
      segundo--;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<insertion_sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L20
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L5:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L34
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L5
L34:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L23
  ret
L20:
  ret
```

assistant: ```c
void insertion_sort(int *lista, int total) {
  int primero, segundo, indice;
  for (primero = 1; primero <= total - 1; primero++) {
    segundo = primero;
    while (segundo > 0 && lista[segundo] < lista[segundo - 1]) {
      indice = lista[segundo];
      lista[segundo] = lista[segundo - 1];
      lista[segundo - 1] = indice;
      segundo--;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L6
  mov    $0x1,%eax
  jmp    L39
L6:
  movl   $0x0,-0x4(%rbp)
  jmp    L77
L75:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L49
  mov    $0x1,%eax
  jmp    L39
L49:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L56
  mov    $0xffffffff,%eax
  jmp    L39
L56:
  addl   $0x1,-0x4(%rbp)
L77:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L75
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int cmp(char *a, char *b, int a_len, int b_len) {
  if (a_len > b_len)
    return 1;
  int i = 0;
  while (i < b_len) {
    if (a[i] > b[i])
      return 1;
    else if (a[i] < b[i])
      return -1;
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp>:
  endbr64
  mov    $0x1,%eax
  cmp    %ecx,%edx
  jg     L36
  test   %ecx,%ecx
  jle    L14
  lea    -0x1(%rcx),%r8d
  mov    $0x0,%eax
  jmp    L57
L8:
  mov    %rdx,%rax
L57:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  cmp    %dl,%cl
  jg     L1
  jl     L56
  lea    0x1(%rax),%rdx
  cmp    %r8,%rax
  jne    L8
  mov    $0x0,%eax
  ret
L14:
  mov    $0x0,%eax
  ret
L1:
  mov    $0x1,%eax
  ret
L56:
  mov    $0xffffffff,%eax
L36:
  ret
```

assistant: ```c
int cmp(char *a, char *b, int a_len, int b_len) {
  if (a_len > b_len)
    return 1;
  int i = 0;
  while (i < b_len) {
    if (a[i] > b[i])
      return 1;
    else if (a[i] < b[i])
      return -1;
    i++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp>:
  endbr64
  mov    $0x1,%eax
  cmp    %ecx,%edx
  jg     L55
  test   %ecx,%ecx
  jle    L7
  movslq %ecx,%rcx
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L35:
  jl     L11
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L7
L0:
  movzbl (%rsi,%rax,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  jle    L35
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
L55:
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmp(char *a, char *b, int a_len, int b_len) {
  if (a_len > b_len)
    return 1;
  int i = 0;
  while (i < b_len) {
    if (a[i] > b[i])
      return 1;
    else if (a[i] < b[i])
      return -1;
    i++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp>:
  endbr64
  mov    $0x1,%eax
  cmp    %ecx,%edx
  jg     L12
  test   %ecx,%ecx
  jle    L43
  movslq %ecx,%rcx
  xor    %eax,%eax
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L27:
  jl     L19
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L43
L48:
  movzbl (%rsi,%rax,1),%edx
  cmp    %dl,(%rdi,%rax,1)
  jle    L27
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%eax
L12:
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmp(char *a, char *b, int a_len, int b_len) {
  if (a_len > b_len)
    return 1;
  int i = 0;
  while (i < b_len) {
    if (a[i] > b[i])
      return 1;
    else if (a[i] < b[i])
      return -1;
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xdab,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4d2,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x213,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: %s


assistant: ```c
int main() {
  printf("%s\n", intToRoman(3499));
  printf("%s\n", intToRoman(1234));
  printf("%s\n", intToRoman(531));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xdab,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4d2,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x213,%edi
  call   <intToRoman@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: %s


assistant: ```c
int main() {
  printf("%s\n", intToRoman(3499));
  printf("%s\n", intToRoman(1234));
  printf("%s\n", intToRoman(531));
  return 0;
}
```