ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<embedChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x7,-0x18(%rbp)
  jmp    L68
L59:
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x2c(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L50
  orl    $0x1,-0x14(%rbp)
  jmp    L55
L50:
  andl   $0xfe,-0x14(%rbp)
L55:
  mov    -0x28(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x19(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L18
L4:
  addq   $0x1,-0x28(%rbp)
L18:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L41
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L4
L41:
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L64
  addq   $0x1,-0x28(%rbp)
L64:
  subl   $0x1,-0x18(%rbp)
L68:
  cmpl   $0x0,-0x18(%rbp)
  jns    L59
  mov    -0x28(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: %i

assistant: ```c
unsigned char *embedChar(unsigned char *ptr, unsigned char c) {
  for (int k = (sizeof(char) * 8) - 1; k >= 0; k--) {
    int mask = 1 << k;
    int masked_c = c & mask;
    int bit = masked_c >> k;
    int toEmbed = atoi(ptr);
    if (bit) {
      toEmbed |= 0x01;
    } else {
      toEmbed &= 0xFE;
    }
    unsigned char t = *(ptr + sizeof(char) * 3);
    unsigned int loc = sprintf(ptr, "%i", toEmbed);
    ptr[loc] = t;
    toEmbed = atoi(ptr);
    while (*ptr != ' ' && *ptr != '\n') {
      ptr += sizeof(char);
    }
    ptr += sizeof(char);
    if (*ptr == '\n')
      ptr += sizeof(char);
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<embedChar>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    $0x7,%ebp
  lea    D6(%rip),%r13
  jmp    L38
L20:
  cmpb   $0xa,0x1(%rbx)
  je     L43
  add    $0x1,%rbx
L52:
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  je     L35
L38:
  mov    $0x1,%r14d
  mov    %ebp,%ecx
  shl    %cl,%r14d
  movzbl %r12b,%eax
  and    %eax,%r14d
  sar    %cl,%r14d
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  or     $0x1,%edx
  and    $0xfe,%eax
  test   %r14d,%r14d
  cmove  %eax,%edx
  movzbl 0x3(%rbx),%r14d
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %eax,%eax
  mov    %r14b,(%rbx,%rax,1)
  mov    %rbx,%rdi
  call   <atoi@plt>
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L20
  cmp    $0xa,%al
  je     L20
L87:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L20
  cmp    $0xa,%al
  jne    L87
  jmp    L20
L43:
  add    $0x2,%rbx
  jmp    L52
L35:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %i

assistant: ```c
unsigned char *embedChar(unsigned char *ptr, unsigned char c) {
  for (int k = (sizeof(char) * 8) - 1; k >= 0; k--) {
    int mask = 1 << k;
    int masked_c = c & mask;
    int bit = masked_c >> k;
    int toEmbed = atoi(ptr);
    if (bit) {
      toEmbed |= 0x01;
    } else {
      toEmbed &= 0xFE;
    }
    unsigned char t = *(ptr + sizeof(char) * 3);
    unsigned int loc = sprintf(ptr, "%i", toEmbed);
    ptr[loc] = t;
    toEmbed = atoi(ptr);
    while (*ptr != ' ' && *ptr != '\n') {
      ptr += sizeof(char);
    }
    ptr += sizeof(char);
    if (*ptr == '\n')
      ptr += sizeof(char);
  }
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<embedChar>:
  endbr64
  push   %r15
  mov    $0x7,%r15d
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  movzbl %sil,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %r15d,%ecx
  mov    %ebp,%r14d
  mov    %r12,%rdi
  shl    %cl,%r14d
  and    %ebx,%r14d
  sar    %cl,%r14d
  call   <atoi@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  and    $0xfe,%eax
  or     $0x1,%edx
  test   %r14d,%r14d
  movzbl 0x3(%r12),%r14d
  cmove  %eax,%edx
  call   <sprintf@plt>
  mov    %r12,%rdi
  mov    %eax,%eax
  mov    %r14b,(%r12,%rax,1)
  call   <atoi@plt>
  movzbl (%r12),%eax
  cmp    $0xa,%al
  je     L12
  cmp    $0x20,%al
  je     L12
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    $0x20,%al
  je     L12
  cmp    $0xa,%al
  jne    L45
L12:
  cmpb   $0xa,0x1(%r12)
  je     L34
  add    $0x1,%r12
L21:
  sub    $0x1,%r15d
  jae    L63
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L34:
  add    $0x2,%r12
  jmp    L21
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: %i

assistant: ```c
unsigned char *embedChar(unsigned char *ptr, unsigned char c) {
  for (int k = (sizeof(char) * 8) - 1; k >= 0; k--) {
    int mask = 1 << k;
    int masked_c = c & mask;
    int bit = masked_c >> k;
    int toEmbed = atoi(ptr);
    if (bit) {
      toEmbed |= 0x01;
    } else {
      toEmbed &= 0xFE;
    }
    unsigned char t = *(ptr + sizeof(char) * 3);
    unsigned int loc = sprintf(ptr, "%i", toEmbed);
    ptr[loc] = t;
    toEmbed = atoi(ptr);
    while (*ptr != ' ' && *ptr != '\n') {
      ptr += sizeof(char);
    }
    ptr += sizeof(char);
    if (*ptr == '\n')
      ptr += sizeof(char);
  }
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<embedChar>:
  endbr64
  push   %r15
  mov    $0x7,%r15d
  push   %r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  movzbl %sil,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r15d,%ecx
  mov    %ebp,%r14d
  mov    %r12,%rdi
  shl    %cl,%r14d
  and    %ebx,%r14d
  sar    %cl,%r14d
  call   <atoi@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  and    $0xfe,%eax
  or     $0x1,%edx
  test   %r14d,%r14d
  movzbl 0x3(%r12),%r14d
  cmove  %eax,%edx
  call   <sprintf@plt>
  mov    %r12,%rdi
  mov    %eax,%eax
  mov    %r14b,(%r12,%rax,1)
  call   <atoi@plt>
  movzbl (%r12),%eax
  cmp    $0xa,%al
  je     L37
  cmp    $0x20,%al
  je     L37
  nopl   0x0(%rax,%rax,1)
L24:
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  cmp    $0x20,%al
  je     L37
  cmp    $0xa,%al
  jne    L24
L37:
  cmpb   $0xa,0x1(%r12)
  je     L44
  add    $0x1,%r12
L41:
  sub    $0x1,%r15d
  jae    L21
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L44:
  add    $0x2,%r12
  jmp    L41
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %i

assistant: ```c
unsigned char *embedChar(unsigned char *ptr, unsigned char c) {
  for (int k = (sizeof(char) * 8) - 1; k >= 0; k--) {
    int mask = 1 << k;
    int masked_c = c & mask;
    int bit = masked_c >> k;
    int toEmbed = atoi(ptr);
    if (bit) {
      toEmbed |= 0x01;
    } else {
      toEmbed &= 0xFE;
    }
    unsigned char t = *(ptr + sizeof(char) * 3);
    unsigned int loc = sprintf(ptr, "%i", toEmbed);
    ptr[loc] = t;
    toEmbed = atoi(ptr);
    while (*ptr != ' ' && *ptr != '\n') {
      ptr += sizeof(char);
    }
    ptr += sizeof(char);
    if (*ptr == '\n')
      ptr += sizeof(char);
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D3: %s


assistant: ```c
void die(char *error) {
  printf("%s\n", error);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: %s


assistant: ```c
void die(char *error) {
  printf("%s\n", error);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %s


assistant: ```c
void die(char *error) {
  printf("%s\n", error);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: %s


assistant: ```c
void die(char *error) {
  printf("%s\n", error);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_unknown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x2d,%eax
  je     L36
  cmp    $0x2d,%eax
  jl     L58
  cmp    $0x6e,%eax
  jg     L58
  cmp    $0x3f,%eax
  jl     L58
  sub    $0x3f,%eax
  movabs $0x800000008001,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L58
L36:
  mov    $0x1,%eax
  jmp    L10
L58:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int is_unknown(char base) {
  switch (base) {
  case 'N':
  case 'n':
  case '-':
  case '?':
    return 1;
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_unknown>:
  endbr64
  cmp    $0x2d,%dil
  je     L13
  lea    -0x3f(%rdi),%ecx
  cmp    $0x2f,%cl
  ja     L11
  movabs $0x800000008001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_unknown(char base) {
  switch (base) {
  case 'N':
  case 'n':
  case '-':
  case '?':
    return 1;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_unknown>:
  endbr64
  cmp    $0x2d,%dil
  je     L10
  lea    -0x3f(%rdi),%ecx
  cmp    $0x2f,%cl
  ja     L3
  movabs $0x800000008001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_unknown(char base) {
  switch (base) {
  case 'N':
  case 'n':
  case '-':
  case '?':
    return 1;
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_unknown>:
  endbr64
  cmp    $0x2d,%dil
  je     L18
  lea    -0x3f(%rdi),%ecx
  cmp    $0x2f,%cl
  ja     L11
  movabs $0x800000008001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_unknown(char base) {
  switch (base) {
  case 'N':
  case 'n':
  case '-':
  case '?':
    return 1;
  default:
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<SU_Uncapitalized>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SU_Uncapitalize@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *SU_Uncapitalized(char *The_String) {
  SU_Uncapitalize(The_String);
  return The_String;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SU_Uncapitalized>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <SU_Uncapitalize@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *SU_Uncapitalized(char *The_String) {
  SU_Uncapitalize(The_String);
  return The_String;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SU_Uncapitalized>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <SU_Uncapitalize@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SU_Uncapitalized(char *The_String) {
  SU_Uncapitalize(The_String);
  return The_String;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SU_Uncapitalized>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <SU_Uncapitalize@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SU_Uncapitalized(char *The_String) {
  SU_Uncapitalize(The_String);
  return The_String;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GlbspStrDup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L11
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UtilStrDup@plt>
L11:
  leave
  ret
```

assistant: ```c
const char *GlbspStrDup(const char *str) {
  if (!str)
    return NULL;
  return UtilStrDup(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GlbspStrDup>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   <UtilStrDup@plt>
  add    $0x8,%rsp
  ret
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *GlbspStrDup(const char *str) {
  if (!str)
    return NULL;
  return UtilStrDup(str);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GlbspStrDup>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <UtilStrDup@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *GlbspStrDup(const char *str) {
  if (!str)
    return NULL;
  return UtilStrDup(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GlbspStrDup>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1050 <UtilStrDup@plt>
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *GlbspStrDup(const char *str) {
  if (!str)
    return NULL;
  return UtilStrDup(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: Hi world


assistant: ```c
void *printme(void *arg) {
  printf("Hi world\n");
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printme>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: Hi world


assistant: ```c
void *printme(void *arg) {
  printf("Hi world\n");
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printme>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: Hi world


assistant: ```c
void *printme(void *arg) {
  printf("Hi world\n");
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printme>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Hi world


assistant: ```c
void *printme(void *arg) {
  printf("Hi world\n");
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parlcd_delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <clock_nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void parlcd_delay(int msec) {
  struct timespec wait_delay = {.tv_sec = msec / 1000, .tv_nsec = (msec % 1000) * 1000 * 1000};
  clock_nanosleep(CLOCK_MONOTONIC, 0, &wait_delay, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parlcd_delay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <clock_nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void parlcd_delay(int msec) {
  struct timespec wait_delay = {.tv_sec = msec / 1000, .tv_nsec = (msec % 1000) * 1000 * 1000};
  clock_nanosleep(CLOCK_MONOTONIC, 0, &wait_delay, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parlcd_delay>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %rsp,%rdx
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  mov    D1(%rip),%rax
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    (%rax),%edi
  call   <clock_nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void parlcd_delay(int msec) {
  struct timespec wait_delay = {.tv_sec = msec / 1000, .tv_nsec = (msec % 1000) * 1000 * 1000};
  clock_nanosleep(CLOCK_MONOTONIC, 0, &wait_delay, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parlcd_delay>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  mov    D1(%rip),%rax
  sub    %edx,%edi
  mov    %rsp,%rdx
  imul   $0xf4240,%edi,%edi
  movd   %edi,%xmm1
  mov    (%rax),%edi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  call   <clock_nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void parlcd_delay(int msec) {
  struct timespec wait_delay = {.tv_sec = msec / 1000, .tv_nsec = (msec % 1000) * 1000 * 1000};
  clock_nanosleep(CLOCK_MONOTONIC, 0, &wait_delay, NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L1
L8:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L29
  addl   $0x1,-0x4(%rbp)
  jmp    L1
L29:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int N, x;
  N = num;
  x = 2;
  for (x = 2; x < N;) {
    if ((N % x) != 0) {
      x = x + 1;
    } else {
      N = N + 1;
    }
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L33
  mov    $0x2,%ecx
  jmp    L12
L37:
  add    $0x1,%edi
L2:
  cmp    %edi,%ecx
  jge    L26
L12:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L37
  add    $0x1,%ecx
  jmp    L2
L33:
  mov    $0x2,%ecx
L26:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int N, x;
  N = num;
  x = 2;
  for (x = 2; x < N;) {
    if ((N % x) != 0) {
      x = x + 1;
    } else {
      N = N + 1;
    }
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_prime>:
  endbr64
  mov    $0x2,%r8d
  cmp    $0x2,%edi
  jg     L37
  jmp    L44
  nopl   0x0(%rax)
L31:
  add    $0x1,%r8d
  cmp    %r8d,%edi
  jle    L44
L37:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L31
  add    $0x1,%edi
  cmp    %r8d,%edi
  jg     L37
L44:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int N, x;
  N = num;
  x = 2;
  for (x = 2; x < N;) {
    if ((N % x) != 0) {
      x = x + 1;
    } else {
      N = N + 1;
    }
  }
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_prime>:
  endbr64
  mov    $0x2,%r8d
  cmp    $0x2,%edi
  jle    L17
  nop
L9:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L3
  add    $0x1,%r8d
  cmp    %r8d,%edi
  jg     L9
L17:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%edi
  cmp    %edi,%r8d
  jl     L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_prime(int num) {
  int N, x;
  N = num;
  x = 2;
  for (x = 2; x < N;) {
    if ((N % x) != 0) {
      x = x + 1;
    } else {
      N = N + 1;
    }
  }
  return x;
}
```