ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<isIsomorphic>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L68
  mov    %rdi,%r9
  mov    $0x0,%ecx
  jmp    L29
L61:
  cmp    %al,%dil
  jne    L18
  movsbq %al,%rax
  cmp    %dl,0x80(%rsp,%rax,1)
  jne    L118
L27:
  add    $0x1,%rcx
  movzbl (%r9,%rcx,1),%edx
  test   %dl,%dl
  je     L52
L29:
  movzbl (%rsi,%rcx,1),%eax
  movsbl %dl,%r8d
  movsbq %dl,%rdi
  movzbl (%rsp,%rdi,1),%edi
  test   %dil,%dil
  jne    L61
  movsbl %al,%r11d
  movsbq %al,%r10
  cmpb   $0x0,0x80(%rsp,%r10,1)
  jne    L61
  movslq %r8d,%r8
  mov    %al,(%rsp,%r8,1)
  movslq %r11d,%r11
  mov    %dl,0x80(%rsp,%r11,1)
  jmp    L27
L52:
  mov    $0x1,%eax
L35:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x118,%rsp
  ret
L68:
  mov    $0x1,%eax
  jmp    L35
L18:
  mov    $0x0,%eax
  jmp    L35
L118:
  mov    $0x0,%eax
  jmp    L35
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isIsomorphic(char *s, char *t) {
  char ss[128] = {0}, tt[128] = {0};
  while (*s) {
    char a = *s++, b = *t++;
    if (ss[a] == 0 && tt[b] == 0) {
      ss[a] = b;
      tt[b] = a;
      continue;
    }
    if (ss[a] != b || tt[b] != a)
      return false;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isIsomorphic>:
  endbr64
  sub    $0x118,%rsp
  movzbl (%rdi),%edx
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  test   %dl,%dl
  je     L79
  xor    %ecx,%ecx
  jmp    L42
  nopl   0x0(%rax)
L49:
  cmp    %r8b,%al
  jne    L53
  cmp    %dl,0x80(%rsp,%rax,1)
  jne    L53
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  je     L79
L42:
  movsbq %dl,%r9
  movzbl (%rsi,%rcx,1),%r8d
  movsbq (%rsp,%r9,1),%rax
  test   %al,%al
  jne    L49
  movsbq %r8b,%r10
  cmpb   $0x0,0x80(%rsp,%r10,1)
  jne    L49
  add    $0x1,%rcx
  mov    %dl,0x80(%rsp,%r10,1)
  movzbl (%rdi,%rcx,1),%edx
  mov    %r8b,(%rsp,%r9,1)
  test   %dl,%dl
  jne    L42
  nopl   0x0(%rax,%rax,1)
L79:
  mov    $0x1,%eax
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L53:
  xor    %eax,%eax
L6:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x118,%rsp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isIsomorphic(char *s, char *t) {
  char ss[128] = {0}, tt[128] = {0};
  while (*s) {
    char a = *s++, b = *t++;
    if (ss[a] == 0 && tt[b] == 0) {
      ss[a] = b;
      tt[b] = a;
      continue;
    }
    if (ss[a] != b || tt[b] != a)
      return false;
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isIsomorphic>:
  endbr64
  sub    $0x118,%rsp
  movzbl (%rdi),%edx
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  test   %dl,%dl
  je     L35
  xor    %ecx,%ecx
  jmp    L6
  nopl   0x0(%rax)
L11:
  cmp    %r8b,%al
  jne    L79
  cmp    %dl,0x80(%rsp,%rax,1)
  jne    L79
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  je     L35
L6:
  movsbq %dl,%r9
  movzbl (%rsi,%rcx,1),%r8d
  movsbq (%rsp,%r9,1),%rax
  test   %al,%al
  jne    L11
  movsbq %r8b,%r10
  cmpb   $0x0,0x80(%rsp,%r10,1)
  jne    L11
  add    $0x1,%rcx
  mov    %dl,0x80(%rsp,%r10,1)
  movzbl (%rdi,%rcx,1),%edx
  mov    %r8b,(%rsp,%r9,1)
  test   %dl,%dl
  jne    L6
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0x1,%eax
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L79:
  xor    %eax,%eax
L58:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x118,%rsp
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool isIsomorphic(char *s, char *t) {
  char ss[128] = {0}, tt[128] = {0};
  while (*s) {
    char a = *s++, b = *t++;
    if (ss[a] == 0 && tt[b] == 0) {
      ss[a] = b;
      tt[b] = a;
      continue;
    }
    if (ss[a] != b || tt[b] != a)
      return false;
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x11,-0x30(%rbp)
  movl   $0x1f,-0x2c(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L5:
  mov    -0x2c(%rbp),%eax
  movzwl %ax,%eax
  imul   $0x9069,%eax,%edx
  mov    -0x2c(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  movzwl %ax,%eax
  imul   $0x4650,%eax,%edx
  mov    -0x30(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x34(%rbp)
  addq   $0x4,-0x28(%rbp)
L7:
  cmpl   $0x4,-0x34(%rbp)
  jbe    L5
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reduzAND@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reduzOR@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reduzSUM@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D25
type_infered: string

tool: D25: %08x


assistant: ```c
int main(void) {
  int dat[5];
  int *ptr = dat;
  unsigned int i, m_w, m_z;
  m_w = 17;
  m_z = 31;
  for (i = 0; i < 5; i++, ptr++) {
    m_z = 36969 * (m_z & 65535) + (m_z >> 16);
    m_w = 18000 * (m_w & 65535) + (m_w >> 16);
    *ptr = (m_z << 16) + m_w;
  }
  printf("%08x\n", reduzAND(dat));
  printf("%08x\n", reduzOR(dat));
  printf("%08x\n", reduzSUM(dat));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1f,%edx
  mov    $0x11,%eax
  mov    %rsp,%rcx
  lea    0x14(%rsp),%rdi
L2:
  movzwl %dx,%esi
  imul   $0x9069,%esi,%esi
  shr    $0x10,%edx
  add    %esi,%edx
  movzwl %ax,%esi
  imul   $0x4650,%esi,%esi
  shr    $0x10,%eax
  add    %esi,%eax
  mov    %edx,%esi
  shl    $0x10,%esi
  add    %eax,%esi
  mov    %esi,(%rcx)
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L2
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <reduzAND@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reduzOR@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reduzSUM@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: %08x


assistant: ```c
int main(void) {
  int dat[5];
  int *ptr = dat;
  unsigned int i, m_w, m_z;
  m_w = 17;
  m_z = 31;
  for (i = 0; i < 5; i++, ptr++) {
    m_z = 36969 * (m_z & 65535) + (m_z >> 16);
    m_w = 18000 * (m_w & 65535) + (m_w >> 16);
    *ptr = (m_z << 16) + m_w;
  }
  printf("%08x\n", reduzAND(dat));
  printf("%08x\n", reduzOR(dat));
  printf("%08x\n", reduzSUM(dat));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1f,%edx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x11,%eax
  lea    0x14(%rsp),%rdi
  mov    %rbp,%rcx
L5:
  movzwl %dx,%esi
  shr    $0x10,%edx
  add    $0x4,%rcx
  imul   $0x9069,%esi,%esi
  add    %esi,%edx
  movzwl %ax,%esi
  shr    $0x10,%eax
  imul   $0x4650,%esi,%esi
  add    %esi,%eax
  mov    %edx,%esi
  shl    $0x10,%esi
  add    %eax,%esi
  mov    %esi,-0x4(%rcx)
  cmp    %rdi,%rcx
  jne    L5
  mov    %rbp,%rdi
  lea    D0(%rip),%r12
  call   <reduzAND@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reduzOR@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <reduzSUM@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: %08x


assistant: ```c
int main(void) {
  int dat[5];
  int *ptr = dat;
  unsigned int i, m_w, m_z;
  m_w = 17;
  m_z = 31;
  for (i = 0; i < 5; i++, ptr++) {
    m_z = 36969 * (m_z & 65535) + (m_z >> 16);
    m_w = 18000 * (m_w & 65535) + (m_w >> 16);
    *ptr = (m_z << 16) + m_w;
  }
  printf("%08x\n", reduzAND(dat));
  printf("%08x\n", reduzOR(dat));
  printf("%08x\n", reduzSUM(dat));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  sub    $0x28,%rsp
  movdqa D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0xd4d95f2c,0x10(%rsp)
  mov    %r12,%rdi
  movaps %xmm0,(%rsp)
  call   <reduzAND@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <reduzOR@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <reduzSUM@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D15
type: byte[16]

tool: D7: %08x


tool: {"D15": [0x50,0xab,0xbb,0x7c,0x04,0x69,0x2d,0x46,0x4d,0x18,0x52,0xdf,0xe8,0xc2,0xc1,0x77]}

assistant: ```c
int main(void) {
  int dat[5];
  int *ptr = dat;
  unsigned int i, m_w, m_z;
  m_w = 17;
  m_z = 31;
  for (i = 0; i < 5; i++, ptr++) {
    m_z = 36969 * (m_z & 65535) + (m_z >> 16);
    m_w = 18000 * (m_w & 65535) + (m_w >> 16);
    *ptr = (m_z << 16) + m_w;
  }
  printf("%08x\n", reduzAND(dat));
  printf("%08x\n", reduzOR(dat));
  printf("%08x\n", reduzSUM(dat));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<k_idletask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L5:
  jmp    L5
```

assistant: ```c
k_idletask() {
l1:
  goto l1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<k_idletask>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
k_idletask() {
l1:
  goto l1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<k_idletask>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
k_idletask() {
l1:
  goto l1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<k_idletask>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
k_idletask() {
l1:
  goto l1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L40
L22:
  cmpl   $0x4,-0x10(%rbp)
  je     L42
  cmpl   $0x4,-0x10(%rbp)
  jg     L57
  cmpl   $0x3,-0x10(%rbp)
  je     L11
  cmpl   $0x3,-0x10(%rbp)
  jg     L57
  cmpl   $0x1,-0x10(%rbp)
  je     L128
  cmpl   $0x2,-0x10(%rbp)
  je     L79
  jmp    L57
L128:
  movsd  D36(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L54
L79:
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L54
L11:
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L54
L42:
  movsd  D51(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L54
L57:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L54:
  mov    $0x0,%eax
  call   <getnights@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <showprice@plt>
L40:
  mov    $0x0,%eax
  call   <menu@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x5,-0x10(%rbp)
  jne    L22
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D36
type: f64
name: read_data
arguments: tag: D0
type: f64
name: read_data
arguments: tag: D11
type: f64
name: read_data
arguments: tag: D51
type: f64
name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D28
type: string

tool: D36: 180

tool: D0: 225

tool: D11: 255

tool: D51: 355

tool: D23: Oops!


tool: D28: Thank you and goodbye.


assistant: ```c
int main(void) {
  int nights;
  double hotel_rate;
  int code;
  while ((code = menu()) != 5) {
    switch (code) {
    case 1:
      hotel_rate = 180.00;
      break;
    case 2:
      hotel_rate = 225.00;
      break;
    case 3:
      hotel_rate = 255.00;
      break;
    case 4:
      hotel_rate = 355.00;
      break;
    default:
      hotel_rate = 0.0;
      printf("Oops!\n");
      break;
    }
    nights = getnights();
    showprice(hotel_rate, nights);
  }
  printf("Thank you and goodbye.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D30(%rip),%rbp
  mov    D69(%rip),%r12
  jmp    L79
L60:
  cmp    $0x2,%eax
  jne    L12
  mov    D48(%rip),%rbx
L30:
  mov    $0x0,%eax
  call   <getnights@plt>
  mov    %eax,%edi
  movq   %rbx,%xmm0
  call   <showprice@plt>
L79:
  mov    $0x0,%eax
  call   <menu@plt>
  cmp    $0x5,%eax
  je     L52
  cmp    $0x3,%eax
  je     L74
  jg     L39
  mov    D66(%rip),%rbx
  cmp    $0x1,%eax
  jne    L60
  jmp    L30
L39:
  mov    %r12,%rbx
  cmp    $0x4,%eax
  je     L30
L12:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    D46(%rip),%rbx
  jmp    L30
L74:
  mov    D16(%rip),%rbx
  jmp    L30
L52:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D69
type_guessed: f64
name: read_data
arguments: tag: D48
type_guessed: f64
name: read_data
arguments: tag: D66
type_guessed: f64
name: read_data
arguments: tag: D46
type_guessed: f64
name: read_data
arguments: tag: D16
type_guessed: f64
name: read_data
arguments: tag: D19
type_guessed: string

tool: D30: Oops!


tool: D69: 355

tool: D48: 225

tool: D66: 180

tool: D46: 0

tool: D16: 255

tool: D19: Thank you and goodbye.


assistant: ```c
int main(void) {
  int nights;
  double hotel_rate;
  int code;
  while ((code = menu()) != 5) {
    switch (code) {
    case 1:
      hotel_rate = 180.00;
      break;
    case 2:
      hotel_rate = 225.00;
      break;
    case 3:
      hotel_rate = 255.00;
      break;
    case 4:
      hotel_rate = 355.00;
      break;
    default:
      hotel_rate = 0.0;
      printf("Oops!\n");
      break;
    }
    nights = getnights();
    showprice(hotel_rate, nights);
  }
  printf("Thank you and goodbye.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x18,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L35:
  movsd  (%rbx,%rax,8),%xmm0
L32:
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <getnights@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%edi
  call   <showprice@plt>
L17:
  xor    %eax,%eax
  call   <menu@plt>
  cmp    $0x5,%eax
  je     L37
  sub    $0x1,%eax
  cmp    $0x3,%eax
  jbe    L35
  mov    %rbp,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L32
  nopl   0x0(%rax)
L37:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D14
data_type: f64
name: disassemble_data
arguments: label: D20
data_type: string

tool: D23: Oops!


tool: D14: 180

tool: D20: Thank you and goodbye.


assistant: ```c
int main(void) {
  int nights;
  double hotel_rate;
  int code;
  while ((code = menu()) != 5) {
    switch (code) {
    case 1:
      hotel_rate = 180.00;
      break;
    case 2:
      hotel_rate = 225.00;
      break;
    case 3:
      hotel_rate = 255.00;
      break;
    case 4:
      hotel_rate = 355.00;
      break;
    default:
      hotel_rate = 0.0;
      printf("Oops!\n");
      break;
    }
    nights = getnights();
    showprice(hotel_rate, nights);
  }
  printf("Thank you and goodbye.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x18,%rsp
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L5:
  movsd  (%rbx,%rax,8),%xmm0
L21:
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <getnights@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%edi
  call   <showprice@plt>
L1:
  xor    %eax,%eax
  call   <menu@plt>
  cmp    $0x5,%eax
  je     L12
  sub    $0x1,%eax
  cmp    $0x3,%eax
  jbe    L5
  mov    %rbp,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  jmp    L21
  nopl   0x0(%rax)
L12:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: f64
name: read_data
arguments: tag: D3
type_guessed: string

tool: D19: Oops!


tool: D23: 180

tool: D3: Thank you and goodbye.


assistant: ```c
int main(void) {
  int nights;
  double hotel_rate;
  int code;
  while ((code = menu()) != 5) {
    switch (code) {
    case 1:
      hotel_rate = 180.00;
      break;
    case 2:
      hotel_rate = 225.00;
      break;
    case 3:
      hotel_rate = 255.00;
      break;
    case 4:
      hotel_rate = 355.00;
      break;
    default:
      hotel_rate = 0.0;
      printf("Oops!\n");
      break;
    }
    nights = getnights();
    showprice(hotel_rate, nights);
  }
  printf("Thank you and goodbye.\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BCD_TO_ASCII>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  add    $0x30,%edx
  mov    %dl,(%rax)
  movzbl -0x4(%rbp),%eax
  shr    $0x4,%al
  lea    0x30(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BCD_TO_ASCII(unsigned char bcd_value, unsigned char *ascii_text) {
  ascii_text[1] = ((unsigned char)bcd_value & 0x0F) + 0x30;
  ascii_text[0] = ((unsigned char)bcd_value >> 4) + 0x30;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BCD_TO_ASCII>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %al,0x1(%rsi)
  shr    $0x4,%dil
  add    $0x30,%edi
  mov    %dil,(%rsi)
  ret
```

assistant: ```c
void BCD_TO_ASCII(unsigned char bcd_value, unsigned char *ascii_text) {
  ascii_text[1] = ((unsigned char)bcd_value & 0x0F) + 0x30;
  ascii_text[0] = ((unsigned char)bcd_value >> 4) + 0x30;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BCD_TO_ASCII>:
  endbr64
  mov    %edi,%eax
  shr    $0x4,%dil
  and    $0xf,%eax
  add    $0x30,%edi
  add    $0x30,%eax
  mov    %dil,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void BCD_TO_ASCII(unsigned char bcd_value, unsigned char *ascii_text) {
  ascii_text[1] = ((unsigned char)bcd_value & 0x0F) + 0x30;
  ascii_text[0] = ((unsigned char)bcd_value >> 4) + 0x30;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BCD_TO_ASCII>:
  endbr64
  mov    %edi,%eax
  shr    $0x4,%dil
  and    $0xf,%eax
  add    $0x30,%edi
  add    $0x30,%eax
  mov    %dil,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void BCD_TO_ASCII(unsigned char bcd_value, unsigned char *ascii_text) {
  ascii_text[1] = ((unsigned char)bcd_value & 0x0F) + 0x30;
  ascii_text[0] = ((unsigned char)bcd_value >> 4) + 0x30;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L18:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L33
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  jmp    L36
L33:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
L39:
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x10,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <alloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    D16(%rip),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,D4(%rip)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
L36:
  leave
  ret
```

assistant: ```c
char *string(const char *str) {
  static struct string {
    struct string *link;
    char str[1];
  } * list;
  struct string *p;
  for (p = list; p; p = p->link)
    if (strcmp(p->str, str) == 0)
      return p->str;
  p = alloc(strlen(str) + sizeof *p);
  strcpy(p->str, str);
  p->link = list;
  list = p;
  return p->str;
}
```