ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_hex_01c>:
  endbr64
  sub    $0x58,%rsp
  movdqa D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D11(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D40(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <is_hex@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  lea    D26(%rip),%rax
  cmovne %rdx,%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x58,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type: byte[16]
name: extract_symbolic_data
arguments: tag: D11
type: byte[16]
name: extract_symbolic_data
arguments: tag: D40
type: byte[16]
name: extract_symbolic_data
arguments: tag: D2
type: byte[16]
name: extract_symbolic_data
arguments: tag: D26
type: string

tool: {"D37": [0x42,0x33,0x30,0x30,0x35,0x36,0x32,0x46,0x38,0x46,0x39,0x41,0x39,0x36,0x31,0x45]}

tool: {"D11": [0x31,0x35,0x38,0x42,0x44,0x45,0x32,0x44,0x34,0x43,0x43,0x44,0x32,0x41,0x36,0x34]}

tool: {"D40": [0x42,0x42,0x31,0x44,0x39,0x32,0x33,0x32,0x30,0x38,0x39,0x33,0x39,0x37,0x31,0x34]}

tool: {"D2": [0x36,0x37,0x35,0x42,0x46,0x46,0x42,0x31,0x37,0x42,0x42,0x41,0x46,0x32,0x41,0x33]}

tool: D26: return true for hex strings without leading '0x's

assistant: ```c
char *is_hex_01c() {
  char hex[] = "B300562F8F9A961E158BDE2D4CCD2A64BB1D923208939714675BFFB17BBAF2A3";
  do {
    if (!(is_hex(hex)))
      return "return true for hex strings without leading '0x's";
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_hex_01c>:
  endbr64
  sub    $0x58,%rsp
  movdqa D21(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movb   $0x0,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D43(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <is_hex@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  lea    D25(%rip),%rax
  cmovne %rdx,%rax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D23
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D20
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D43
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D25
type_guessed: string

tool: {"D21": [0x42,0x33,0x30,0x30,0x35,0x36,0x32,0x46,0x38,0x46,0x39,0x41,0x39,0x36,0x31,0x45]}

tool: {"D23": [0x31,0x35,0x38,0x42,0x44,0x45,0x32,0x44,0x34,0x43,0x43,0x44,0x32,0x41,0x36,0x34]}

tool: {"D20": [0x42,0x42,0x31,0x44,0x39,0x32,0x33,0x32,0x30,0x38,0x39,0x33,0x39,0x37,0x31,0x34]}

tool: {"D43": [0x36,0x37,0x35,0x42,0x46,0x46,0x42,0x31,0x37,0x42,0x42,0x41,0x46,0x32,0x41,0x33]}

tool: D25: return true for hex strings without leading '0x's

assistant: ```c
char *is_hex_01c() {
  char hex[] = "B300562F8F9A961E158BDE2D4CCD2A64BB1D923208939714675BFFB17BBAF2A3";
  do {
    if (!(is_hex(hex)))
      return "return true for hex strings without leading '0x's";
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<srepeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L6:
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L7:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L7
  addl   $0x1,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *srepeat(char *str, int n) {
  int l = strlen(str);
  char *tmp = (char *)malloc(n * l);
  int i, z = 0;
  for (i = 0; i < n; ++i) {
    for (z = 0; z < l; ++z) {
      tmp[(i * l) + z] = str[z];
    }
  }
  strcpy(str, tmp);
  free(tmp);
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<srepeat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  imul   %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L8
  mov    $0x0,%r8d
  mov    $0x0,%edi
  lea    -0x1(%rbx),%eax
  lea    0x1(%r13,%rax,1),%r9
  jmp    L19
L48:
  movslq %r8d,%rcx
  lea    0x0(%r13,%rcx,1),%rdx
  add    %r9,%rcx
  mov    %rdx,%rax
  mov    %rbp,%rsi
  sub    %rdx,%rsi
L38:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L38
L27:
  add    $0x1,%edi
  add    %ebx,%r8d
  cmp    %edi,%r12d
  je     L8
L19:
  test   %ebx,%ebx
  jg     L48
  jmp    L27
L8:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *srepeat(char *str, int n) {
  int l = strlen(str);
  char *tmp = (char *)malloc(n * l);
  int i, z = 0;
  for (i = 0; i < n; ++i) {
    for (z = 0; z < l; ++z) {
      tmp[(i * l) + z] = str[z];
    }
  }
  strcpy(str, tmp);
  free(tmp);
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<srepeat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  imul   %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L22
  lea    -0x1(%rbx),%eax
  xor    %r8d,%r8d
  xor    %edi,%edi
  lea    0x1(%r13,%rax,1),%r9
  nopl   0x0(%rax,%rax,1)
L5:
  test   %ebx,%ebx
  jle    L26
  movslq %r8d,%rax
  mov    %r12,%rcx
  lea    (%r9,%rax,1),%rsi
  add    %r13,%rax
  sub    %rax,%rcx
  nopl   0x0(%rax)
L13:
  movzbl (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L13
L26:
  add    $0x1,%edi
  add    %ebx,%r8d
  cmp    %edi,%ebp
  jne    L5
L22:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *srepeat(char *str, int n) {
  int l = strlen(str);
  char *tmp = (char *)malloc(n * l);
  int i, z = 0;
  for (i = 0; i < n; ++i) {
    for (z = 0; z < l; ++z) {
      tmp[(i * l) + z] = str[z];
    }
  }
  strcpy(str, tmp);
  free(tmp);
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: usage: todo-completion


assistant: ```c
void usage() {
  printf("usage: todo-completion\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: usage: todo-completion


assistant: ```c
void usage() {
  printf("usage: todo-completion\n");
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: usage: todo-completion


assistant: ```c
void usage() {
  printf("usage: todo-completion\n");
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: usage: todo-completion


assistant: ```c
void usage() {
  printf("usage: todo-completion\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fiat_p384_nonzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%esi
  mov    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edi
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%r8d
  mov    -0x20(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  or     %r8d,%eax
  or     %edi,%eax
  or     %esi,%eax
  or     %ecx,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fiat_p384_nonzero(uint64_t *out1, const uint64_t arg1[6]) {
  uint64_t x1;
  x1 = ((arg1[0]) | ((arg1[1]) | ((arg1[2]) | ((arg1[3]) | ((arg1[4]) | (arg1[5]))))));
  *out1 = x1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fiat_p384_nonzero>:
  endbr64
  mov    (%rsi),%eax
  or     0x4(%rsi),%eax
  or     0x8(%rsi),%eax
  or     0xc(%rsi),%eax
  or     0x10(%rsi),%eax
  or     0x14(%rsi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fiat_p384_nonzero(uint64_t *out1, const uint64_t arg1[6]) {
  uint64_t x1;
  x1 = ((arg1[0]) | ((arg1[1]) | ((arg1[2]) | ((arg1[3]) | ((arg1[4]) | (arg1[5]))))));
  *out1 = x1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fiat_p384_nonzero>:
  endbr64
  mov    (%rsi),%eax
  or     0x4(%rsi),%eax
  or     0x8(%rsi),%eax
  or     0xc(%rsi),%eax
  or     0x10(%rsi),%eax
  or     0x14(%rsi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fiat_p384_nonzero(uint64_t *out1, const uint64_t arg1[6]) {
  uint64_t x1;
  x1 = ((arg1[0]) | ((arg1[1]) | ((arg1[2]) | ((arg1[3]) | ((arg1[4]) | (arg1[5]))))));
  *out1 = x1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fiat_p384_nonzero>:
  endbr64
  mov    (%rsi),%eax
  or     0x4(%rsi),%eax
  or     0x8(%rsi),%eax
  or     0xc(%rsi),%eax
  or     0x10(%rsi),%eax
  or     0x14(%rsi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void fiat_p384_nonzero(uint64_t *out1, const uint64_t arg1[6]) {
  uint64_t x1;
  x1 = ((arg1[0]) | ((arg1[1]) | ((arg1[2]) | ((arg1[3]) | ((arg1[4]) | (arg1[5]))))));
  *out1 = x1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D5: enter the number 

tool: D2: the number in after conversion from string to int is %d

assistant: ```c
int main() {
  int i1;
  char num[123];
  printf("enter the number ");
  gets(num);
  i1 = atoi(num);
  printf("the number in after conversion from string to int is %d", i1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D10: enter the number 

tool: D5: the number in after conversion from string to int is %d

assistant: ```c
int main() {
  int i1;
  char num[123];
  printf("enter the number ");
  gets(num);
  i1 = atoi(num);
  printf("the number in after conversion from string to int is %d", i1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string

tool: D10: enter the number 

tool: D14: the number in after conversion from string to int is %d

assistant: ```c
int main() {
  int i1;
  char num[123];
  printf("enter the number ");
  gets(num);
  i1 = atoi(num);
  printf("the number in after conversion from string to int is %d", i1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D7
type: string

tool: D13: enter the number 

tool: D7: the number in after conversion from string to int is %d

assistant: ```c
int main() {
  int i1;
  char num[123];
  printf("enter the number ");
  gets(num);
  i1 = atoi(num);
  printf("the number in after conversion from string to int is %d", i1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deleteArrItem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L18:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L18
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char **deleteArrItem(char **arr, int *size, int index) {
  int i;
  for (i = index; i < (*size) - 1; ++i)
    arr[i] = arr[i + 1];
  (*size)--;
  return arr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<deleteArrItem>:
  endbr64
  mov    %rdi,%rax
  mov    (%rsi),%edi
  lea    -0x1(%rdi),%ecx
  cmp    %ecx,%edx
  jge    L13
  movslq %edx,%rdx
L14:
  mov    0x8(%rax,%rdx,8),%rcx
  mov    %rcx,(%rax,%rdx,8)
  mov    (%rsi),%edi
  lea    -0x1(%rdi),%ecx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L14
L13:
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
char **deleteArrItem(char **arr, int *size, int index) {
  int i;
  for (i = index; i < (*size) - 1; ++i)
    arr[i] = arr[i + 1];
  (*size)--;
  return arr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<deleteArrItem>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%eax
  mov    %rsi,%rbx
  lea    -0x1(%rax),%ebp
  cmp    %ebp,%edx
  jge    L6
  movslq %edx,%rdi
  sub    $0x2,%eax
  shl    $0x3,%rdi
  sub    %edx,%eax
  lea    0x8(%r12,%rdi,1),%rsi
  lea    0x8(,%rax,8),%rdx
  add    %r12,%rdi
  call   <memmove@plt>
L6:
  mov    %ebp,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **deleteArrItem(char **arr, int *size, int index) {
  int i;
  for (i = index; i < (*size) - 1; ++i)
    arr[i] = arr[i + 1];
  (*size)--;
  return arr;
}
```
user: What is the c source code of the assembly code below?

```asm
<deleteArrItem>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rsi),%eax
  mov    %rsi,%rbx
  lea    -0x1(%rax),%ebp
  cmp    %ebp,%edx
  jge    L6
  movslq %edx,%rdi
  sub    $0x2,%eax
  shl    $0x3,%rdi
  sub    %edx,%eax
  lea    0x8(%r12,%rdi,1),%rsi
  lea    0x8(,%rax,8),%rdx
  add    %r12,%rdi
  call   <memmove@plt>
L6:
  mov    %ebp,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **deleteArrItem(char **arr, int *size, int index) {
  int i;
  for (i = index; i < (*size) - 1; ++i)
    arr[i] = arr[i + 1];
  (*size)--;
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip_marker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void strip_marker(char *s, const char *targ) {
  int i, n = strlen(targ);
  for (i = 0; i < n; i++) {
    s[i] = ' ';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_marker>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rax
L13:
  movb   $0x20,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L13
L0:
  pop    %rbx
  ret
```

assistant: ```c
void strip_marker(char *s, const char *targ) {
  int i, n = strlen(targ);
  for (i = 0; i < n; i++) {
    s[i] = ' ';
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strip_marker>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    $0x20,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
  nopl   (%rax)
L8:
  pop    %rbp
  ret
```

assistant: ```c
void strip_marker(char *s, const char *targ) {
  int i, n = strlen(targ);
  for (i = 0; i < n; i++) {
    s[i] = ' ';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip_marker>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    $0x20,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
  nopl   (%rax)
L2:
  pop    %rbp
  ret
```

assistant: ```c
void strip_marker(char *s, const char *targ) {
  int i, n = strlen(targ);
  for (i = 0; i < n; i++) {
    s[i] = ' ';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <_shm@plt>
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return _shm(argv[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_shm@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return _shm(argv[0]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    (%rsi),%rdi
  jmp    1050 <_shm@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return _shm(argv[0]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    (%rsi),%rdi
  jmp    1050 <_shm@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return _shm(argv[0]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rax,%rbx
  jmp    L37
L24:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rdx),%edx
  cmp    $0x2f,%dl
  jne    L37
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L37
  mov    %rbx,%rax
L37:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L24
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *dname(name)
register char *name;
{
  register char *p;
  p = name;
  while (*p)
    if (*p++ == '/' && *p)
      name = p;
  return name;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dname>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L1
  mov    %rdi,%rcx
  jmp    L46
L41:
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L30
L46:
  add    $0x1,%rcx
  cmp    $0x2f,%dl
  jne    L41
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L16
  ret
L30:
  ret
L16:
  mov    %rcx,%rax
  jmp    L46
L1:
  ret
```

assistant: ```c
char *dname(name)
register char *name;
{
  register char *p;
  p = name;
  while (*p)
    if (*p++ == '/' && *p)
      name = p;
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dname>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%r8
  test   %dl,%dl
  je     L53
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x2f,%dl
  je     L23
  nopw   0x0(%rax,%rax,1)
L15:
  test   %al,%al
  je     L53
  mov    %eax,%edx
L46:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x2f,%dl
  jne    L15
L23:
  test   %al,%al
  jne    L6
L53:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%r8
  mov    %eax,%edx
  jmp    L46
```

assistant: ```c
char *dname(name)
register char *name;
{
  register char *p;
  p = name;
  while (*p)
    if (*p++ == '/' && *p)
      name = p;
  return name;
}
```