ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<IO_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L21
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L21:
  cmpq   $0x0,-0xc8(%rbp)
  je     L7
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  jmp    L22
L7:
  nop
L22:
  leave
  ret
```

assistant: ```c
void IO_write(const char *format, ...) {
  if (format == NULL) {
    return;
  }
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IO_write>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  ret
```

assistant: ```c
void IO_write(const char *format, ...) {
  if (format == NULL) {
    return;
  }
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IO_write>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void IO_write(const char *format, ...) {
  if (format == NULL) {
    return;
  }
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IO_write>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void IO_write(const char *format, ...) {
  if (format == NULL) {
    return;
  }
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x5,%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <local_irq_save@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <local_irq_restore@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_bit(int nr, volatile void *addr) {
  int mask;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  *a |= mask;
  local_irq_restore(flags);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_bit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,4),%r12
  mov    $0x0,%ebp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <local_irq_save@plt>
  mov    (%r12),%eax
  bts    %ebx,%eax
  mov    %eax,(%r12)
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <local_irq_restore@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void set_bit(int nr, volatile void *addr) {
  int mask;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  *a |= mask;
  local_irq_restore(flags);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_bit>:
  endbr64
  mov    %edi,%eax
  push   %r12
  sar    $0x5,%eax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  cltq
  mov    %edi,%ebx
  mov    %rbp,%rdi
  lea    (%rsi,%rax,4),%r12
  xor    %eax,%eax
  call   <local_irq_save@plt>
  mov    (%r12),%eax
  mov    %rbp,%rdi
  bts    %ebx,%eax
  mov    %eax,(%r12)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <local_irq_restore@plt>
```

assistant: ```c
void set_bit(int nr, volatile void *addr) {
  int mask;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  *a |= mask;
  local_irq_restore(flags);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_bit>:
  endbr64
  mov    %edi,%eax
  push   %r12
  sar    $0x5,%eax
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  cltq
  mov    %edi,%ebx
  mov    %rbp,%rdi
  lea    (%rsi,%rax,4),%r12
  xor    %eax,%eax
  call   <local_irq_save@plt>
  mov    (%r12),%eax
  mov    %rbp,%rdi
  bts    %ebx,%eax
  mov    %eax,(%r12)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <local_irq_restore@plt>
```

assistant: ```c
void set_bit(int nr, volatile void *addr) {
  int mask;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  *a |= mask;
  local_irq_restore(flags);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CheckExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L54
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0x0,%eax
  jmp    L54
L24:
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L54
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L78
  mov    $0x1,%eax
  jmp    L54
L78:
  mov    $0x0,%eax
L54:
  leave
  ret
```

assistant: ```c
int CheckExtension(char *filename, char *ext) {
  char *s;
  if (!filename)
    return (0);
  if (strlen(filename) == 0)
    return (0);
  s = strrchr(filename, '.');
  if (!s)
    return (0);
  if (!strcmp(s, ext))
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CheckExtension>:
  endbr64
  test   %rdi,%rdi
  je     L32
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L22
L8:
  pop    %rbx
  ret
L22:
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L41
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L8
L32:
  mov    $0x0,%eax
  ret
L41:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
int CheckExtension(char *filename, char *ext) {
  char *s;
  if (!filename)
    return (0);
  if (strlen(filename) == 0)
    return (0);
  s = strrchr(filename, '.');
  if (!s)
    return (0);
  if (!strcmp(s, ext))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CheckExtension>:
  endbr64
  test   %rdi,%rdi
  je     L11
  cmpb   $0x0,(%rdi)
  jne    L5
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
L7:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int CheckExtension(char *filename, char *ext) {
  char *s;
  if (!filename)
    return (0);
  if (strlen(filename) == 0)
    return (0);
  s = strrchr(filename, '.');
  if (!s)
    return (0);
  if (!strcmp(s, ext))
    return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CheckExtension>:
  endbr64
  test   %rdi,%rdi
  je     L7
  cmpb   $0x0,(%rdi)
  jne    L26
L7:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L26:
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L15
  mov    %rbp,%rsi
  call   <strcmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
L15:
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int CheckExtension(char *filename, char *ext) {
  char *s;
  if (!filename)
    return (0);
  if (strlen(filename) == 0)
    return (0);
  s = strrchr(filename, '.');
  if (!s)
    return (0);
  if (!strcmp(s, ext))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<valch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L30
  cmpl   $0x19,-0x14(%rbp)
  jle    L6
L30:
  mov    $0x0,%eax
  jmp    L13
L6:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <aclamp@plt>
  lea    D2(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L34
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: abcdefghijklmnopqrstuvwxyz

assistant: ```c
int valch(int c, bool upper) {
  static const char chars[] = "abcdefghijklmnopqrstuvwxyz";
  int ret;
  if (c < 0 || c > 25)
    return 0;
  ret = chars[aclamp(c)];
  if (upper)
    ret = toupper(ret);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<valch>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x19,%edi
  jbe    L6
  ret
L6:
  push   %rbx
  mov    %esi,%ebx
  call   <aclamp@plt>
  lea    D0(%rip),%rdx
  movsbl (%rdx,%rax,1),%eax
  test   %ebx,%ebx
  je     L9
  mov    %eax,%edi
  call   <toupper@plt>
L9:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: abcdefghijklmnopqrstuvwxyz

assistant: ```c
int valch(int c, bool upper) {
  static const char chars[] = "abcdefghijklmnopqrstuvwxyz";
  int ret;
  if (c < 0 || c > 25)
    return 0;
  ret = chars[aclamp(c)];
  if (upper)
    ret = toupper(ret);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<valch>:
  endbr64
  cmp    $0x19,%edi
  jbe    L19
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L19:
  push   %rbx
  mov    %esi,%ebx
  call   <aclamp@plt>
  lea    D7(%rip),%rdx
  movsbl (%rdx,%rax,1),%eax
  test   %ebx,%ebx
  je     L16
  mov    %eax,%edi
  pop    %rbx
  jmp    1060 <toupper@plt>
  nop
L16:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: abcdefghijklmnopqrstuvwxyz

assistant: ```c
int valch(int c, bool upper) {
  static const char chars[] = "abcdefghijklmnopqrstuvwxyz";
  int ret;
  if (c < 0 || c > 25)
    return 0;
  ret = chars[aclamp(c)];
  if (upper)
    ret = toupper(ret);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<valch>:
  endbr64
  cmp    $0x19,%edi
  jbe    L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L9:
  push   %rbx
  mov    %esi,%ebx
  call   <aclamp@plt>
  lea    D7(%rip),%rdx
  movsbl (%rdx,%rax,1),%eax
  test   %ebx,%ebx
  je     L7
  mov    %eax,%edi
  pop    %rbx
  jmp    1060 <toupper@plt>
  nop
L7:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: abcdefghijklmnopqrstuvwxyz

assistant: ```c
int valch(int c, bool upper) {
  static const char chars[] = "abcdefghijklmnopqrstuvwxyz";
  int ret;
  if (c < 0 || c > 25)
    return 0;
  ret = chars[aclamp(c)];
  if (upper)
    ret = toupper(ret);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<flip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
L25:
  addl   $0x2,-0x4(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void flip(char *cp) {
  int i;
  for (i = 0; i < strlen(cp); i += 2) {
    if (cp[i] && cp[i + 1]) {
      char ch = cp[i];
      cp[i] = cp[i + 1];
      cp[i + 1] = ch;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<flip>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L13
L31:
  add    $0x2,%rbx
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L9
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L31
  movzbl 0x1(%rbp,%rbx,1),%edx
  test   %dl,%dl
  je     L31
  mov    %dl,0x0(%rbp,%rbx,1)
  mov    %al,0x1(%rbp,%rbx,1)
  jmp    L31
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void flip(char *cp) {
  int i;
  for (i = 0; i < strlen(cp); i += 2) {
    if (cp[i] && cp[i + 1]) {
      char ch = cp[i];
      cp[i] = cp[i + 1];
      cp[i + 1] = ch;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flip>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L2
  nopl   0x0(%rax)
L7:
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L8
  movzbl 0x1(%rbp,%rbx,1),%edx
  test   %dl,%dl
  je     L8
  mov    %dl,0x0(%rbp,%rbx,1)
  mov    %al,0x1(%rbp,%rbx,1)
L8:
  add    $0x2,%rbx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void flip(char *cp) {
  int i;
  for (i = 0; i < strlen(cp); i += 2) {
    if (cp[i] && cp[i + 1]) {
      char ch = cp[i];
      cp[i] = cp[i + 1];
      cp[i + 1] = ch;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<flip>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax)
L0:
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L29
  movzbl 0x1(%rbp,%rbx,1),%edx
  test   %dl,%dl
  je     L29
  mov    %dl,0x0(%rbp,%rbx,1)
  mov    %al,0x1(%rbp,%rbx,1)
L29:
  add    $0x2,%rbx
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void flip(char *cp) {
  int i;
  for (i = 0; i < strlen(cp); i += 2) {
    if (cp[i] && cp[i + 1]) {
      char ch = cp[i];
      cp[i] = cp[i + 1];
      cp[i + 1] = ch;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<irand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <frand@plt>
  mov    -0x14(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int irand(int max_plus_1) {
  int i = (int)(frand() * max_plus_1);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<irand>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <frand@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int irand(int max_plus_1) {
  int i = (int)(frand() * max_plus_1);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<irand>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <frand@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int irand(int max_plus_1) {
  int i = (int)(frand() * max_plus_1);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<irand>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <frand@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int irand(int max_plus_1) {
  int i = (int)(frand() * max_plus_1);
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<update_struct_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <clear_crc@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L12
L14:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <do_crc16@plt>
  addl   $0x1,-0x1c(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L14
  mov    -0x18(%rbp),%rbx
  lea    0x4(%rbx),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <get_crc_h@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rbx
  lea    0x4(%rbx),%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <get_crc_l@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void update_struct_crc(uint8_t *sp, int16_t size) {
  int16_t i;
  uint8_t *ptr = sp;
  clear_crc();
  for (i = 0; i < size - 2; i++) {
    do_crc16(*ptr++);
  }
  *ptr++ = get_crc_h();
  *ptr++ = get_crc_l();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<update_struct_crc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <clear_crc@plt>
  cmp    $0x2,%ebp
  jle    L28
  lea    -0x3(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rbp
L1:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  call   <do_crc16@plt>
  cmp    %rbp,%rbx
  jne    L1
L7:
  mov    $0x0,%eax
  call   <get_crc_h@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <get_crc_l@plt>
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %rbx,%rbp
  jmp    L7
```

assistant: ```c
void update_struct_crc(uint8_t *sp, int16_t size) {
  int16_t i;
  uint8_t *ptr = sp;
  clear_crc();
  for (i = 0; i < size - 2; i++) {
    do_crc16(*ptr++);
  }
  *ptr++ = get_crc_h();
  *ptr++ = get_crc_l();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<update_struct_crc>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <clear_crc@plt>
  cmp    $0x2,%ebp
  jle    L28
  lea    -0x3(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <do_crc16@plt>
  cmp    %rbp,%rbx
  jne    L26
L20:
  xor    %eax,%eax
  call   <get_crc_h@plt>
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <get_crc_l@plt>
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rbp
  jmp    L20
```

assistant: ```c
void update_struct_crc(uint8_t *sp, int16_t size) {
  int16_t i;
  uint8_t *ptr = sp;
  clear_crc();
  for (i = 0; i < size - 2; i++) {
    do_crc16(*ptr++);
  }
  *ptr++ = get_crc_h();
  *ptr++ = get_crc_l();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<update_struct_crc>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <clear_crc@plt>
  cmp    $0x2,%ebp
  jle    L13
  lea    -0x3(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <do_crc16@plt>
  cmp    %rbp,%rbx
  jne    L10
L20:
  xor    %eax,%eax
  call   <get_crc_h@plt>
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <get_crc_l@plt>
  mov    %eax,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbx,%rbp
  jmp    L20
```

assistant: ```c
void update_struct_crc(uint8_t *sp, int16_t size) {
  int16_t i;
  uint8_t *ptr = sp;
  clear_crc();
  for (i = 0; i < size - 2; i++) {
    do_crc16(*ptr++);
  }
  *ptr++ = get_crc_h();
  *ptr++ = get_crc_l();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hdd_size_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sizestrtod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x42,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L57:
  movsd  -0x10(%rbp),%xmm0
  comisd D5(%rip),%xmm0
  jbe    L53
  mov    $0xfffffffe,%eax
  jmp    L45
L53:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <round@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
  jmp    L45
L29:
  mov    $0xffffffff,%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: f64

tool: D5: 1.8446744073709552e+19

assistant: ```c
int hdd_size_parse(const char *str, uint64_t *ret) {
  double val;
  const char *endptr;
  val = sizestrtod(str, &endptr);
  if (endptr[0] == '\0' || (endptr[0] == 'B' && endptr[1] == '\0')) {
    if (val > 18446744073709551615.0) {
      return -2;
    }
    *ret = round(val);
    return 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hdd_size_parse>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <sizestrtod@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L59
  cmp    $0x42,%al
  jne    L24
  cmpb   $0x0,0x1(%rdx)
  jne    L10
L59:
  comisd D4(%rip),%xmm0
  ja     L62
  call   <round@plt>
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L65
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L38
L10:
  mov    $0xffffffff,%eax
  jmp    L38
L62:
  mov    $0xfffffffe,%eax
  jmp    L38
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: f64

tool: D4: 1.8446744073709552e+19

assistant: ```c
int hdd_size_parse(const char *str, uint64_t *ret) {
  double val;
  const char *endptr;
  val = sizestrtod(str, &endptr);
  if (endptr[0] == '\0' || (endptr[0] == 'B' && endptr[1] == '\0')) {
    if (val > 18446744073709551615.0) {
      return -2;
    }
    *ret = round(val);
    return 1;
  }
  return -1;
}
```