ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<_bin_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  add    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _bin_double(const void *a, const void *b) {
  double b0, b1;
  b0 = (*(double *)a - *(double *)b);
  b1 = (*(double *)a - *((double *)b + 1));
  return (int)(((b0 >= 0) - (b0 < 0)) + ((b1 >= 0) - (b1 < 0)));
}
```
user: What is the c source code of the assembly code below?

```asm
<_bin_double>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm2
  subsd  (%rsi),%xmm2
  subsd  0x8(%rsi),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm2
  setae  %al
  movzbl %al,%eax
  comisd %xmm2,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  comisd %xmm1,%xmm0
  setae  %dl
  movzbl %dl,%edx
  comisd %xmm0,%xmm1
  seta   %cl
  movzbl %cl,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int _bin_double(const void *a, const void *b) {
  double b0, b1;
  b0 = (*(double *)a - *(double *)b);
  b1 = (*(double *)a - *((double *)b + 1));
  return (int)(((b0 >= 0) - (b0 < 0)) + ((b1 >= 0) - (b1 < 0)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_bin_double>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  movapd %xmm0,%xmm2
  subsd  (%rsi),%xmm2
  subsd  0x8(%rsi),%xmm0
  comisd %xmm1,%xmm2
  setae  %al
  xor    %edx,%edx
  comisd %xmm2,%xmm1
  seta   %dl
  sub    %edx,%eax
  xor    %edx,%edx
  comisd %xmm1,%xmm0
  setae  %dl
  xor    %ecx,%ecx
  comisd %xmm0,%xmm1
  seta   %cl
  sub    %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int _bin_double(const void *a, const void *b) {
  double b0, b1;
  b0 = (*(double *)a - *(double *)b);
  b1 = (*(double *)a - *((double *)b + 1));
  return (int)(((b0 >= 0) - (b0 < 0)) + ((b1 >= 0) - (b1 < 0)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exp_on_vec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L14:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L14
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void exp_on_vec(double *vec, int length) {
  int i;
  for (i = 0; i < length; i++)
    vec[i] = exp(vec[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exp_on_vec>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L10:
  movsd  (%rbx),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  ret
```

assistant: ```c
void exp_on_vec(double *vec, int length) {
  int i;
  for (i = 0; i < length; i++)
    vec[i] = exp(vec[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exp_on_vec>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  movsd  (%rbx),%xmm0
  add    $0x8,%rbx
  call   <exp@plt>
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L15:
  ret
```

assistant: ```c
void exp_on_vec(double *vec, int length) {
  int i;
  for (i = 0; i < length; i++)
    vec[i] = exp(vec[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exp_on_vec>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  movsd  (%rbx),%xmm0
  add    $0x8,%rbx
  call   <exp@plt>
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void exp_on_vec(double *vec, int length) {
  int i;
  for (i = 0; i < length; i++)
    vec[i] = exp(vec[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rb_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  cmpq   $0x0,-0x10(%rbp)
  je     L27
  mov    $0x1,%eax
  jmp    L15
L27:
  mov    $0x0,%eax
L15:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void rb_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rb_free>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void rb_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rb_free>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rb_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rb_free>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rb_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comp_descend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L16
  mov    $0xffffffff,%eax
  jmp    L10
L16:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L9
  mov    $0x1,%eax
  jmp    L10
L9:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int comp_descend(const void *s1, const void *s2) {
  double *ss1, *ss2;
  ss1 = (double *)s1;
  ss2 = (double *)s2;
  if ((ss1)[0] > (ss2)[0]) {
    return -1;
  } else if ((ss1)[0] < (ss2)[0]) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comp_descend>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L4
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
int comp_descend(const void *s1, const void *s2) {
  double *ss1, *ss2;
  ss1 = (double *)s1;
  ss2 = (double *)s2;
  if ((ss1)[0] > (ss2)[0]) {
    return -1;
  } else if ((ss1)[0] < (ss2)[0]) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<comp_descend>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L4
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L4:
  ret
```

assistant: ```c
int comp_descend(const void *s1, const void *s2) {
  double *ss1, *ss2;
  ss1 = (double *)s1;
  ss2 = (double *)s2;
  if ((ss1)[0] > (ss2)[0]) {
    return -1;
  } else if ((ss1)[0] < (ss2)[0]) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<comp_descend>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L1:
  ret
```

assistant: ```c
int comp_descend(const void *s1, const void *s2) {
  double *ss1, *ss2;
  ss1 = (double *)s1;
  ss2 = (double *)s2;
  if ((ss1)[0] > (ss2)[0]) {
    return -1;
  } else if ((ss1)[0] < (ss2)[0]) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4d2,-0x74(%rbp)
  lea    -0x70(%rbp),%rdx
  mov    -0x74(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: %s


assistant: ```c
int main() {
  int test = 1234;
  char result[100];
  itoa(test, result);
  printf("%s\n", result);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    $0x4d2,%edi
  call   <itoa@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: %s


assistant: ```c
int main() {
  int test = 1234;
  char result[100];
  itoa(test, result);
  printf("%s\n", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4d2,%edi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %s


assistant: ```c
int main() {
  int test = 1234;
  char result[100];
  itoa(test, result);
  printf("%s\n", result);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4d2,%edi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: %s


assistant: ```c
int main() {
  int test = 1234;
  char result[100];
  itoa(test, result);
  printf("%s\n", result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printer@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printer@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct node *head = NULL;
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 2);
  insert(&head, 3);
  insert(&head, 4);
  insert(&head, 5);
  insert(&head, 6);
  insert(&head, 7);
  insert(&head, 7);
  printer(head);
  head = reverse(head);
  printer(head);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    (%rsp),%rdi
  call   <printer@plt>
  mov    (%rsp),%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <printer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct node *head = NULL;
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 2);
  insert(&head, 3);
  insert(&head, 4);
  insert(&head, 5);
  insert(&head, 6);
  insert(&head, 7);
  insert(&head, 7);
  printer(head);
  head = reverse(head);
  printer(head);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    (%rsp),%rdi
  call   <printer@plt>
  mov    (%rsp),%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <printer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct node *head = NULL;
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 2);
  insert(&head, 3);
  insert(&head, 4);
  insert(&head, 5);
  insert(&head, 6);
  insert(&head, 7);
  insert(&head, 7);
  printer(head);
  head = reverse(head);
  printer(head);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  mov    (%rsp),%rdi
  call   <printer@plt>
  mov    (%rsp),%rdi
  call   <reverse@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <printer@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct node *head = NULL;
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 1);
  insert(&head, 2);
  insert(&head, 3);
  insert(&head, 4);
  insert(&head, 5);
  insert(&head, 6);
  insert(&head, 7);
  insert(&head, 7);
  printer(head);
  head = reverse(head);
  printer(head);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Strcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    $0x0,%r13d
  mov    -0x20(%rbp),%rbx
  jmp    L23
L15:
  mov    -0x28(%rbp),%r12
  jmp    L11
L21:
  movzwl (%rbx),%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %ax,%dx
  jne    L11
  mov    %r13d,%eax
  jmp    L27
L11:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L21
  add    $0x1,%r13d
  add    $0x2,%rbx
L23:
  movzwl (%rbx),%eax
  test   %ax,%ax
  jne    L15
  mov    %r13d,%eax
L27:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int Strcspn(s1, s2)
unsigned short *s1;
unsigned char *s2;
{
  register unsigned short *scan1;
  register unsigned char *scan2;
  register int count;
  count = 0;
  for (scan1 = s1; *scan1 != '\0'; scan1++) {
    for (scan2 = s2; *scan2 != '\0';)
      if (*scan1 == *scan2++)
        return (count);
    count++;
  }
  return (count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Strcspn>:
  endbr64
  movzwl (%rdi),%ecx
  mov    $0x0,%r8d
  test   %cx,%cx
  je     L8
L7:
  mov    %rsi,%rdx
L26:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L45
  add    $0x1,%rdx
  movzbl %al,%eax
  cmp    %cx,%ax
  jne    L26
L8:
  mov    %r8d,%eax
  ret
L45:
  add    $0x1,%r8d
  add    $0x2,%rdi
  movzwl (%rdi),%ecx
  test   %cx,%cx
  jne    L7
  jmp    L8
```

assistant: ```c
int Strcspn(s1, s2)
unsigned short *s1;
unsigned char *s2;
{
  register unsigned short *scan1;
  register unsigned char *scan2;
  register int count;
  count = 0;
  for (scan1 = s1; *scan1 != '\0'; scan1++) {
    for (scan2 = s2; *scan2 != '\0';)
      if (*scan1 == *scan2++)
        return (count);
    count++;
  }
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Strcspn>:
  endbr64
  movzwl (%rdi),%ecx
  xor    %r8d,%r8d
  test   %cx,%cx
  je     L2
L28:
  mov    %rsi,%rdx
  jmp    L22
  nopl   0x0(%rax)
L21:
  add    $0x1,%rdx
  cmp    %cx,%ax
  je     L2
L22:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L21
  movzwl 0x2(%rdi),%ecx
  add    $0x2,%rdi
  add    $0x1,%r8d
  test   %cx,%cx
  jne    L28
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Strcspn(s1, s2)
unsigned short *s1;
unsigned char *s2;
{
  register unsigned short *scan1;
  register unsigned char *scan2;
  register int count;
  count = 0;
  for (scan1 = s1; *scan1 != '\0'; scan1++) {
    for (scan2 = s2; *scan2 != '\0';)
      if (*scan1 == *scan2++)
        return (count);
    count++;
  }
  return (count);
}
```