ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<arr_uint16_copy>:
  endbr64
  test   %rdx,%rdx
  je     L9
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L10:
  movzwl (%rsi,%rax,2),%r8d
  add    $0x1,%ecx
  mov    %r8w,(%rdi,%rax,2)
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jb     L10
L9:
  ret
```

assistant: ```c
void arr_uint16_copy(unsigned short int *pDest, unsigned short int *pSrc, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    pDest[i] = pSrc[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arr_uint16_copy>:
  endbr64
  test   %rdx,%rdx
  je     L19
  xor    %ecx,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L11:
  movzwl (%rsi,%rax,2),%r8d
  add    $0x1,%ecx
  mov    %r8w,(%rdi,%rax,2)
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jb     L11
L19:
  ret
```

assistant: ```c
void arr_uint16_copy(unsigned short int *pDest, unsigned short int *pSrc, unsigned long int num) {
  unsigned short int i;
  for (i = 0; i < num; i++) {
    pDest[i] = pSrc[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  foo();
  bar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  foo();
  bar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  foo();
  bar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  foo();
  bar();
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_17_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0x10(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  or     -0xc(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    -0x8(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_17_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_17_0_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %eax,%edi
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  or     $0xff,%al
  mov    %eax,%edx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  not    %edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_17_0_1>:
  endbr64
  movzbl %sil,%edx
  movzbl %dil,%edi
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %eax,%edi
  or     %edx,%esi
  or     $0xff,%al
  mov    %eax,%edx
  mov    %esi,%eax
  not    %eax
  not    %edx
  or     %edi,%eax
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_17_0_1>:
  endbr64
  movzbl %sil,%edx
  movzbl %dil,%edi
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %eax,%edi
  or     %edx,%esi
  or     $0xff,%al
  mov    %eax,%edx
  mov    %esi,%eax
  not    %eax
  not    %edx
  or     %edi,%eax
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_17_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L18
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gen>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gen>
  jmp    L13
L18:
  nop
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: %d


assistant: ```c
void gen(int lo, int hi) {
  if (lo > hi)
    return;
  int mid = (lo + hi) / 2;
  printf("%d\n", mid);
  gen(lo, mid - 1);
  gen(mid + 1, hi);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen>:
  endbr64
  cmp    %esi,%edi
  jle    L6
  ret
L6:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebx
  lea    (%rdi,%rsi,1),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    -0x1(%rbp),%esi
  mov    %r12d,%edi
  call   <gen>
  lea    0x1(%rbp),%edi
  mov    %ebx,%esi
  call   <gen>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: %d


assistant: ```c
void gen(int lo, int hi) {
  if (lo > hi)
    return;
  int mid = (lo + hi) / 2;
  printf("%d\n", mid);
  gen(lo, mid - 1);
  gen(mid + 1, hi);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FloorPowerOfTwo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x4,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x8,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x20,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t FloorPowerOfTwo(const size_t value) {
  size_t x = value;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  x = x | (x >> 32);
  return x - (x >> 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FloorPowerOfTwo>:
  endbr64
  mov    %rdi,%rdx
  shr    %rdx
  or     %rdi,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x4,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x20,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t FloorPowerOfTwo(const size_t value) {
  size_t x = value;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  x = x | (x >> 32);
  return x - (x >> 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FloorPowerOfTwo>:
  endbr64
  mov    %rdi,%rdx
  shr    %rdx
  or     %rdi,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x4,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x20,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t FloorPowerOfTwo(const size_t value) {
  size_t x = value;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  x = x | (x >> 32);
  return x - (x >> 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FloorPowerOfTwo>:
  endbr64
  mov    %rdi,%rdx
  shr    %rdx
  or     %rdi,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x4,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x20,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    %rdx
  sub    %rdx,%rax
  ret
```

assistant: ```c
size_t FloorPowerOfTwo(const size_t value) {
  size_t x = value;
  x = x | (x >> 1);
  x = x | (x >> 2);
  x = x | (x >> 4);
  x = x | (x >> 8);
  x = x | (x >> 16);
  x = x | (x >> 32);
  return x - (x >> 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <solve1@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <solve2@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <solve3@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string

tool: D0: %d%d

tool: 

assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  solve1(n, m);
  puts("");
  solve2(n, m);
  puts("");
  solve3(n, m);
  puts("");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve1@plt>
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve2@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve3@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string

tool: D16: %d%d

tool: 

assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  solve1(n, m);
  puts("");
  solve2(n, m);
  puts("");
  solve3(n, m);
  puts("");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D17(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve1@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve2@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    (%rsp),%edi
  mov    0x4(%rsp),%esi
  call   <solve3@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D17
type: string

tool: D12: %d%d

tool: 

assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  solve1(n, m);
  puts("");
  solve2(n, m);
  puts("");
  solve3(n, m);
  puts("");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  lea    D16(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve1@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <solve2@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    (%rsp),%edi
  mov    0x4(%rsp),%esi
  call   <solve3@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string

tool: D7: %d%d

tool: 

assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  solve1(n, m);
  puts("");
  solve2(n, m);
  puts("");
  solve3(n, m);
  puts("");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qromb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x2f0,%rsp
  mov    %rdi,-0x2d8(%rbp)
  movsd  %xmm0,-0x2e0(%rbp)
  movsd  %xmm1,-0x2e8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x158(%rbp)
  movl   $0x1,-0x2c4(%rbp)
  jmp    L16
L17:
  mov    -0x2c4(%rbp),%ecx
  movsd  -0x2e8(%rbp),%xmm0
  mov    -0x2e0(%rbp),%rdx
  mov    -0x2d8(%rbp),%rax
  mov    %ecx,%esi
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <trapzd@plt>
  movq   %xmm0,%rax
  mov    -0x2c4(%rbp),%edx
  movslq %edx,%rdx
  mov    %rax,-0x2b0(%rbp,%rdx,8)
  cmpl   $0x4,-0x2c4(%rbp)
  jle    L12
  mov    -0x2c4(%rbp),%eax
  sub    $0x5,%eax
  lea    -0x2b0(%rbp),%rdx
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x2c4(%rbp),%eax
  sub    $0x5,%eax
  lea    -0x160(%rbp),%rdx
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rdi
  lea    -0x2b8(%rbp),%rdx
  lea    -0x2c0(%rbp),%rax
  mov    %rdx,%r8
  mov    %rax,%rcx
  mov    D5(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x5,%edx
  call   <polint@plt>
  movsd  -0x2b8(%rbp),%xmm0
  movq   D54(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x2c0(%rbp),%xmm0
  movq   D54(%rip),%xmm2
  andpd  %xmm0,%xmm2
  movsd  D45(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  jb     L12
  movsd  -0x2c0(%rbp),%xmm0
  jmp    L3
L12:
  mov    -0x2c4(%rbp),%eax
  cltq
  movsd  -0x160(%rbp,%rax,8),%xmm1
  mov    -0x2c4(%rbp),%eax
  add    $0x1,%eax
  movsd  D55(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cltq
  movsd  %xmm0,-0x160(%rbp,%rax,8)
  addl   $0x1,-0x2c4(%rbp)
L16:
  cmpl   $0x28,-0x2c4(%rbp)
  jle    L17
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L3:
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_guessed: f64
name: extract_symbolic_data
arguments: label: D5
type_guessed: f64
name: extract_symbolic_data
arguments: label: D54
type_guessed: qword
name: extract_symbolic_data
arguments: label: D45
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D55
type_guessed: f64
name: extract_symbolic_data
arguments: label: D52
type_guessed: string

tool: D11: 1

tool: D5: 0

tool: D54: 9223372036854775807

tool: {"D45": [0x3a,0x8c,0x30,0xe2,0x8e,0x79,0x45,0x3e]}

tool: D55: 0.25

tool: D52: Too many steps in routine qromb

assistant: ```c
double qromb(double (*func)(double), double a, double b) {
  void polint(double xa[], double ya[], int n, double x, double *y, double *dy);
  double trapzd(double (*func)(double), double a, double b, int n);
  void nrerror(char error_text[]);
  double ss, dss;
  double s[(40 + 1)], h[(40 + 1) + 1];
  int j;
  h[1] = 1.0;
  for (j = 1; j <= 40; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) <= 1.0e-8 * fabs(ss))
        return ss;
    }
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine qromb");
  return 0.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qromb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x2d8,%rsp
  mov    %rdi,%r14
  movsd  %xmm0,0x8(%rsp)
  movq   %xmm1,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x2c8(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    %rax,0x178(%rsp)
  mov    $0x1,%esi
  call   <trapzd@plt>
  movsd  %xmm0,0x28(%rsp)
  lea    0x158(%rsp),%rbp
  lea    0x8(%rsp),%r12
  mov    $0x1,%ebx
  jmp    L22
L20:
  add    $0x8,%rbp
  add    $0x8,%r12
L22:
  mov    %rbp,%r13
  add    $0x1,%ebx
  movsd  D28(%rip),%xmm0
  mulsd  0x20(%rbp),%xmm0
  movsd  %xmm0,0x28(%rbp)
  cmp    $0x29,%ebx
  je     L32
  mov    %ebx,%esi
  movq   %r15,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r14,%rdi
  call   <trapzd@plt>
  movsd  %xmm0,0x28(%r12)
  cmp    $0x4,%ebx
  jle    L20
  lea    0x10(%rsp),%rcx
  lea    0x18(%rsp),%r8
  pxor   %xmm0,%xmm0
  mov    $0x5,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <polint@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm0
  andpd  D43(%rip),%xmm0
  movapd %xmm2,%xmm1
  andpd  D43(%rip),%xmm1
  mulsd  D59(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L20
L28:
  mov    0x2c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  movapd %xmm2,%xmm0
  add    $0x2d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  lea    D31(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm2,%xmm2
  jmp    L28
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: f64
name: retrieve_data
arguments: tag: D28
data_type: f64
name: retrieve_data
arguments: tag: D43
data_type: qword[2]
name: retrieve_data
arguments: tag: D59
data_type: byte[8]
name: retrieve_data
arguments: tag: D31
data_type: string

tool: D18: 1

tool: D28: 0.25

tool: {"D43": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D59": [0x3a,0x8c,0x30,0xe2,0x8e,0x79,0x45,0x3e]}

tool: D31: Too many steps in routine qromb

assistant: ```c
double qromb(double (*func)(double), double a, double b) {
  void polint(double xa[], double ya[], int n, double x, double *y, double *dy);
  double trapzd(double (*func)(double), double a, double b, int n);
  void nrerror(char error_text[]);
  double ss, dss;
  double s[(40 + 1)], h[(40 + 1) + 1];
  int j;
  h[1] = 1.0;
  for (j = 1; j <= 40; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) <= 1.0e-8 * fabs(ss))
        return ss;
    }
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine qromb");
  return 0.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qromb>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x2d8,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%r15
  lea    0x18(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x2c8(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  movsd  %xmm1,(%rsp)
  lea    0x158(%rsp),%rbp
  lea    0x10(%rsp),%r13
  mov    %rax,0x178(%rsp)
  call   <trapzd@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x28(%rsp)
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rbp
  add    $0x8,%r15
L31:
  movsd  D52(%rip),%xmm0
  mulsd  0x20(%rbp),%xmm0
  add    $0x1,%ebx
  movsd  %xmm0,0x28(%rbp)
  cmp    $0x29,%ebx
  je     L33
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  mov    %r12,%rdi
  movsd  %xmm1,(%rsp)
  call   <trapzd@plt>
  cmp    $0x4,%ebx
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x28(%r15)
  jle    L2
  pxor   %xmm0,%xmm0
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    $0x5,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,(%rsp)
  call   <polint@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm0
  andpd  D48(%rip),%xmm0
  movsd  (%rsp),%xmm1
  movapd %xmm3,%xmm2
  andpd  D48(%rip),%xmm2
  mulsd  D39(%rip),%xmm2
  comisd %xmm0,%xmm2
  jb     L2
L41:
  mov    0x2c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x2d8,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  lea    D13(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm3,%xmm3
  jmp    L41
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D29
data_type: f64
name: retrieve_data
arguments: data_label: D52
data_type: f64
name: retrieve_data
arguments: data_label: D48
data_type: qword[2]
name: retrieve_data
arguments: data_label: D39
data_type: byte[8]
name: retrieve_data
arguments: data_label: D13
data_type: string

tool: D29: 1

tool: D52: 0.25

tool: {"D48": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D39": [0x3a,0x8c,0x30,0xe2,0x8e,0x79,0x45,0x3e]}

tool: D13: Too many steps in routine qromb

assistant: ```c
double qromb(double (*func)(double), double a, double b) {
  void polint(double xa[], double ya[], int n, double x, double *y, double *dy);
  double trapzd(double (*func)(double), double a, double b, int n);
  void nrerror(char error_text[]);
  double ss, dss;
  double s[(40 + 1)], h[(40 + 1) + 1];
  int j;
  h[1] = 1.0;
  for (j = 1; j <= 40; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) <= 1.0e-8 * fabs(ss))
        return ss;
    }
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine qromb");
  return 0.0;
}
```