ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<create_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x63,-0x4(%rbp)
  jle    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void create_random(int tab[]) {
  srand(time(NULL));
  for (int i = 0; i < 100; i++) {
    tab[i] = (rand() % 100);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_random>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rbp,%rbx
  add    $0x190,%rbp
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_random(int tab[]) {
  srand(time(NULL));
  for (int i = 0; i < 100; i++) {
    tab[i] = (rand() % 100);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<create_random>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  lea    0x190(%rbp),%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_random(int tab[]) {
  srand(time(NULL));
  for (int i = 0; i < 100; i++) {
    tab[i] = (rand() % 100);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<create_random>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  lea    0x190(%rbp),%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_random(int tab[]) {
  srand(time(NULL));
  for (int i = 0; i < 100; i++) {
    tab[i] = (rand() % 100);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exist_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L7
L12:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int exist_arg(char *str_to_find, int narg, char **arg) {
  int i;
  for (i = 0; i < narg; i++)
    if (strstr(arg[i], str_to_find))
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exist_arg>:
  endbr64
  test   %esi,%esi
  jle    L29
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdx,%rax,8),%r12
L38:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L38
  jmp    L36
L29:
  mov    $0x0,%eax
  ret
L3:
  mov    $0x1,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int exist_arg(char *str_to_find, int narg, char **arg) {
  int i;
  for (i = 0; i < narg; i++)
    if (strstr(arg[i], str_to_find))
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exist_arg>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdx,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L35
  nopl   0x0(%rax)
L8:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L24
L35:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L8
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int exist_arg(char *str_to_find, int narg, char **arg) {
  int i;
  for (i = 0; i < narg; i++)
    if (strstr(arg[i], str_to_find))
      return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<exist_arg>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdx,%rax,8),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L14
  nopl   0x0(%rax)
L9:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L37
L14:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int exist_arg(char *str_to_find, int narg, char **arg) {
  int i;
  for (i = 0; i < narg; i++)
    if (strstr(arg[i], str_to_find))
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x8(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  mov    $0x0,%eax
  call   <set_next_sendto@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <dobind@plt>
  mov    -0x24(%rbp),%r8d
  mov    -0x20(%rbp),%rdi
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <next_sendto@plt>
  leave
  ret
```

assistant: ```c
ssize_t sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  set_next_sendto();
  dobind(sockfd);
  return next_sendto(sockfd, buf, len, flags, dest_addr, addrlen);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sendto>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %r8,%r14
  mov    %r9d,%r15d
  mov    $0x0,%eax
  call   <set_next_sendto@plt>
  mov    %ebx,%edi
  call   <dobind@plt>
  mov    %r15d,%r9d
  mov    %r14,%r8
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <next_sendto@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  set_next_sendto();
  dobind(sockfd);
  return next_sendto(sockfd, buf, len, flags, dest_addr, addrlen);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sendto>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %r9d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <set_next_sendto@plt>
  mov    %ebp,%edi
  call   <dobind@plt>
  add    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %rbx,%r8
  mov    %r14d,%ecx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <next_sendto@plt>
```

assistant: ```c
ssize_t sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  set_next_sendto();
  dobind(sockfd);
  return next_sendto(sockfd, buf, len, flags, dest_addr, addrlen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sendto>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %r9d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <set_next_sendto@plt>
  mov    %ebp,%edi
  call   <dobind@plt>
  add    $0x8,%rsp
  mov    %r15d,%r9d
  mov    %rbx,%r8
  mov    %r14d,%ecx
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <next_sendto@plt>
```

assistant: ```c
ssize_t sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  set_next_sendto();
  dobind(sockfd);
  return next_sendto(sockfd, buf, len, flags, dest_addr, addrlen);
}
```
user: What is the c source code of the assembly code below:

```asm
<port_word_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%ax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short port_word_in(unsigned short port) {
  unsigned short result;
  __asm__("in %%dx, %%ax" : "=a"(result) : "d"(port));
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<port_word_in>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short port_word_in(unsigned short port) {
  unsigned short result;
  __asm__("in %%dx, %%ax" : "=a"(result) : "d"(port));
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<port_word_in>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short port_word_in(unsigned short port) {
  unsigned short result;
  __asm__("in %%dx, %%ax" : "=a"(result) : "d"(port));
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<port_word_in>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short port_word_in(unsigned short port) {
  unsigned short result;
  __asm__("in %%dx, %%ax" : "=a"(result) : "d"(port));
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: Hello World again !


assistant: ```c
int main() {
  printf("Hello World again !\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: Hello World again !


assistant: ```c
int main() {
  printf("Hello World again !\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: Hello World again !


assistant: ```c
int main() {
  printf("Hello World again !\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: Hello World again !


assistant: ```c
int main() {
  printf("Hello World again !\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<function_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L13
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L13:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <function_d>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <function_d>
L8:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: %d, %d


assistant: ```c
int function_d(int n, int o, int p) {
  if (n <= 0)
    printf("%d, %d\n", o, p);
  else {
    function_d(n - 1, o + 1, p);
    function_d(n - 1, o, p + 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<function_d>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  test   %edi,%edi
  jle    L10
  lea    -0x1(%rdi),%ebx
  lea    0x1(%rsi),%esi
  mov    %ebx,%edi
  call   <function_d>
  lea    0x1(%rbp),%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <function_d>
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: %d, %d


assistant: ```c
int function_d(int n, int o, int p) {
  if (n <= 0)
    printf("%d, %d\n", o, p);
  else {
    function_d(n - 1, o + 1, p);
    function_d(n - 1, o, p + 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffd,%eax
  mov    %al,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  and    $0x1,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffe,%eax
  or     %edx,%eax
  mov    %al,-0xc(%rbp)
  shll   -0x14(%rbp)
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0xc(%rbp),%eax
  shr    %al
  and    $0x1,%eax
  movzbl %al,%eax
  add    %eax,%edx
  movzbl -0xc(%rbp),%eax
  and    $0x1,%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0xc(%rbp),%eax
  shr    $0x2,%al
  and    $0x1,%eax
  movzbl %al,%eax
  add    %eax,%edx
  movzbl -0xc(%rbp),%eax
  and    $0x1,%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0xc(%rbp),%eax
  shr    %al
  and    $0x1,%eax
  movzbl %al,%eax
  add    %eax,%edx
  movzbl -0xc(%rbp),%eax
  and    $0x1,%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movzbl -0xc(%rbp),%eax
  shr    %al
  and    $0x1,%eax
  and    $0x1,%eax
  lea    0x0(,%rax,4),%edx
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffb,%eax
  or     %edx,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%eax
  and    $0x1,%eax
  and    $0x1,%eax
  lea    (%rax,%rax,1),%edx
  movzbl -0xc(%rbp),%eax
  and    $0xfffffffd,%eax
  or     %edx,%eax
  mov    %al,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x7,-0x4(%rbp)
  jle    L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int encode(int code) {
  struct {
    unsigned input : 1;
    unsigned reg1 : 1;
    unsigned reg2 : 1;
  } status;
  int encoded = 0;
  status.reg2 = 0;
  status.reg1 = 0;
  for (int j = 0; j < 8; j++) {
    status.input = ((code)&128) >> 7;
    code <<= 1;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    encoded = (encoded << 1) + status.reg2 ^ status.input;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    status.reg2 = status.reg1;
    status.reg1 = status.input;
  }
  return encoded;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<encode>:
  endbr64
  mov    $0x8,%esi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L10
L13:
  mov    %r10d,%r8d
L10:
  mov    %edi,%edx
  sar    $0x7,%edx
  mov    %edi,%r10d
  shr    $0x7,%r10b
  add    %edi,%edi
  movzbl %r8b,%r9d
  lea    (%r9,%rax,2),%eax
  and    $0x1,%edx
  xor    %edx,%eax
  movzbl %cl,%ecx
  lea    (%rcx,%rax,2),%eax
  xor    %edx,%eax
  lea    (%r9,%rax,2),%eax
  xor    %edx,%eax
  mov    %r8d,%ecx
  sub    $0x1,%esi
  jne    L13
  ret
```

assistant: ```c
int encode(int code) {
  struct {
    unsigned input : 1;
    unsigned reg1 : 1;
    unsigned reg2 : 1;
  } status;
  int encoded = 0;
  status.reg2 = 0;
  status.reg1 = 0;
  for (int j = 0; j < 8; j++) {
    status.input = ((code)&128) >> 7;
    code <<= 1;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    encoded = (encoded << 1) + status.reg2 ^ status.input;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    status.reg2 = status.reg1;
    status.reg1 = status.input;
  }
  return encoded;
}
```
user: What is the c source code of the assembly code below?

```asm
<encode>:
  endbr64
  mov    $0x8,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r10d,%r8d
L9:
  mov    %edi,%edx
  movzbl %r8b,%r9d
  mov    %edi,%r10d
  add    %edi,%edi
  sar    $0x7,%edx
  lea    (%r9,%rax,2),%eax
  shr    $0x7,%r10b
  and    $0x1,%edx
  xor    %edx,%eax
  lea    (%rcx,%rax,2),%eax
  movzbl %r8b,%ecx
  xor    %edx,%eax
  lea    (%r9,%rax,2),%eax
  xor    %edx,%eax
  sub    $0x1,%esi
  jne    L5
  ret
```

assistant: ```c
int encode(int code) {
  struct {
    unsigned input : 1;
    unsigned reg1 : 1;
    unsigned reg2 : 1;
  } status;
  int encoded = 0;
  status.reg2 = 0;
  status.reg1 = 0;
  for (int j = 0; j < 8; j++) {
    status.input = ((code)&128) >> 7;
    code <<= 1;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    encoded = (encoded << 1) + status.reg2 ^ status.input;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    status.reg2 = status.reg1;
    status.reg1 = status.input;
  }
  return encoded;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<encode>:
  endbr64
  mov    %edi,%esi
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0x7,%esi
  shr    $0x6,%ecx
  and    $0x1,%esi
  and    $0x1,%ecx
  lea    (%rsi,%rsi,1),%edx
  xor    %esi,%edx
  add    %edx,%edx
  xor    %esi,%edx
  lea    (%rsi,%rdx,2),%edx
  xor    %ecx,%edx
  add    %edx,%edx
  xor    %ecx,%edx
  lea    (%rsi,%rdx,2),%edx
  xor    %ecx,%edx
  lea    (%rcx,%rdx,2),%edi
  mov    %eax,%edx
  shr    $0x5,%edx
  and    $0x1,%edx
  xor    %edx,%edi
  lea    (%rsi,%rdi,2),%esi
  xor    %edx,%esi
  lea    (%rcx,%rsi,2),%esi
  xor    %edx,%esi
  lea    (%rdx,%rsi,2),%edi
  mov    %eax,%esi
  shr    $0x4,%esi
  and    $0x1,%esi
  xor    %esi,%edi
  lea    (%rcx,%rdi,2),%ecx
  xor    %esi,%ecx
  lea    (%rdx,%rcx,2),%ecx
  xor    %esi,%ecx
  lea    (%rsi,%rcx,2),%edi
  mov    %eax,%ecx
  shr    $0x3,%ecx
  and    $0x1,%ecx
  xor    %ecx,%edi
  lea    (%rdx,%rdi,2),%edx
  xor    %ecx,%edx
  lea    (%rsi,%rdx,2),%edx
  xor    %ecx,%edx
  lea    (%rcx,%rdx,2),%edi
  mov    %eax,%edx
  shr    $0x2,%edx
  and    $0x1,%edx
  xor    %edx,%edi
  lea    (%rsi,%rdi,2),%esi
  xor    %edx,%esi
  lea    (%rcx,%rsi,2),%esi
  xor    %edx,%esi
  lea    (%rdx,%rsi,2),%edi
  mov    %eax,%esi
  shr    %esi
  and    $0x1,%esi
  and    $0x1,%eax
  xor    %esi,%edi
  lea    (%rcx,%rdi,2),%ecx
  xor    %esi,%ecx
  lea    (%rdx,%rcx,2),%ecx
  xor    %esi,%ecx
  lea    (%rsi,%rcx,2),%ecx
  xor    %eax,%ecx
  lea    (%rdx,%rcx,2),%edx
  xor    %eax,%edx
  lea    (%rsi,%rdx,2),%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
int encode(int code) {
  struct {
    unsigned input : 1;
    unsigned reg1 : 1;
    unsigned reg2 : 1;
  } status;
  int encoded = 0;
  status.reg2 = 0;
  status.reg1 = 0;
  for (int j = 0; j < 8; j++) {
    status.input = ((code)&128) >> 7;
    code <<= 1;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    encoded = (encoded << 1) + status.reg2 ^ status.input;
    encoded = (encoded << 1) + status.reg1 ^ status.input;
    status.reg2 = status.reg1;
    status.reg1 = status.input;
  }
  return encoded;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D30
type: string
name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D17
type: string
name: parse_data
arguments: data_tag: D3
type: string

tool: D30: 
Please enter first numb   : 

tool: D20: %d

tool: D17: Please enter second number: 

tool: D3: 
Multiplication of entered numbers = %d


assistant: ```c
void multiplication() {
  int a, b, mul = 0;
  printf("\nPlease enter first numb   : ");
  scanf("%d", &a);
  printf("Please enter second number: ");
  scanf("%d", &b);
  mul = a * b;
  printf("\nMultiplication of entered numbers = %d\n", mul);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiplication>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D14: 
Please enter first numb   : 

tool: D11: %d

tool: D10: Please enter second number: 

tool: D17: 
Multiplication of entered numbers = %d


assistant: ```c
void multiplication() {
  int a, b, mul = 0;
  printf("\nPlease enter first numb   : ");
  scanf("%d", &a);
  printf("Please enter second number: ");
  scanf("%d", &b);
  mul = a * b;
  printf("\nMultiplication of entered numbers = %d\n", mul);
}
```