ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D12
datatype: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c

tool: D12: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D17
type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c

tool: D17: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c

tool: D5: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c

tool: D2: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/vincent040/lab/refs/heads/master/GNU-tools/make/demo/b.c");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_turnover>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L31
  mov    $0x1,%eax
  jmp    L15
L31:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int is_turnover(const char *board, const char *turnover) {
  char target = board[0];
  for (int i = 0; turnover[i] != '\0'; i++) {
    if (turnover[i] == target)
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_turnover>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  test   %al,%al
  je     L28
  add    $0x1,%rsi
L0:
  cmp    %al,%dl
  je     L26
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L0
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_turnover(const char *board, const char *turnover) {
  char target = board[0];
  for (int i = 0; turnover[i] != '\0'; i++) {
    if (turnover[i] == target)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_turnover>:
  endbr64
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  test   %al,%al
  je     L27
  add    $0x1,%rsi
  jmp    L31
  nopl   0x0(%rax)
L33:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L27
L31:
  cmp    %al,%dl
  jne    L33
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_turnover(const char *board, const char *turnover) {
  char target = board[0];
  for (int i = 0; turnover[i] != '\0'; i++) {
    if (turnover[i] == target)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_turnover>:
  endbr64
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  test   %al,%al
  je     L5
  add    $0x1,%rsi
  jmp    L7
  nopl   0x0(%rax)
L34:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L5
L7:
  cmp    %al,%dl
  jne    L34
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_turnover(const char *board, const char *turnover) {
  char target = board[0];
  for (int i = 0; turnover[i] != '\0'; i++) {
    if (turnover[i] == target)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__ogg_fdrfftb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <drftb1@plt>
  jmp    L5
L13:
  nop
L5:
  leave
  ret
```

assistant: ```c
void __ogg_fdrfftb(int n, double *r, double *wsave, int *ifac) {
  if (n == 1)
    return;
  drftb1(n, r, wsave, wsave + n, ifac);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__ogg_fdrfftb>:
  endbr64
  cmp    $0x1,%edi
  je     L2
  sub    $0x8,%rsp
  mov    %rcx,%r8
  movslq %edi,%rax
  lea    (%rdx,%rax,8),%rcx
  call   <drftb1@plt>
  add    $0x8,%rsp
  ret
L2:
  ret
```

assistant: ```c
void __ogg_fdrfftb(int n, double *r, double *wsave, int *ifac) {
  if (n == 1)
    return;
  drftb1(n, r, wsave, wsave + n, ifac);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__ogg_fdrfftb>:
  endbr64
  mov    %rcx,%r8
  cmp    $0x1,%edi
  je     L0
  movslq %edi,%rax
  lea    (%rdx,%rax,8),%rcx
  jmp    1050 <drftb1@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void __ogg_fdrfftb(int n, double *r, double *wsave, int *ifac) {
  if (n == 1)
    return;
  drftb1(n, r, wsave, wsave + n, ifac);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ogg_fdrfftb>:
  endbr64
  mov    %rcx,%r8
  cmp    $0x1,%edi
  je     L9
  movslq %edi,%rax
  lea    (%rdx,%rax,8),%rcx
  jmp    1050 <drftb1@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void __ogg_fdrfftb(int n, double *r, double *wsave, int *ifac) {
  if (n == 1)
    return;
  drftb1(n, r, wsave, wsave + n, ifac);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dup_token_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L16
  mov    $0x0,%eax
  jmp    L140
L25:
  subq   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %eax,%eax
  je     L80
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L25
L80:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L136
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L136:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L61
L38:
  subq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %eax,%eax
  jne    L124
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L38
L124:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L10
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L90
L10:
  addq   $0x1,-0x10(%rbp)
L90:
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L97
  subq   $0x1,-0x10(%rbp)
  jmp    L63
L105:
  subq   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L42
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %eax,%eax
  jne    L105
L42:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L65
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L65:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
L97:
  mov    -0x8(%rbp),%rax
L140:
  leave
  ret
```

assistant: ```c
char *dup_token_r(char *start, char *start_string, char **nptr, int (*isdelimiter)(int)) {
  char *ptr, *rv;
  if (start <= start_string)
    return NULL;
  while (isdelimiter(*start) && (start > start_string))
    start--;
  if (start < start_string)
    start = start_string;
  ptr = start;
  while (!isdelimiter(*ptr) && (ptr > start_string))
    ptr--;
  if (ptr <= start_string)
    ptr = start_string;
  else
    ptr++;
  rv = xmalloc(start - ptr + 2);
  memcpy(rv, ptr, start - ptr + 1);
  rv[start - ptr + 1] = '\0';
  if (nptr != NULL) {
    ptr--;
    while ((ptr > start_string) && isdelimiter(*ptr))
      ptr--;
    if (ptr < start_string)
      ptr = start_string;
    *nptr = ptr;
  }
  return rv;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dup_token_r>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rcx,%r13
  cmp    %rsi,%rdi
  jbe    L27
L67:
  movsbl (%rbx),%edi
  call   *%r13
  cmp    %r12,%rbx
  jbe    L105
  test   %eax,%eax
  je     L105
  sub    $0x1,%rbx
  jmp    L67
L105:
  cmp    %r12,%rbx
  cmovb  %r12,%rbx
  mov    %rbx,%rbp
L82:
  movsbl 0x0(%rbp),%edi
  call   *%r13
  cmp    %r12,%rbp
  jbe    L96
  test   %eax,%eax
  jne    L96
  sub    $0x1,%rbp
  jmp    L82
L96:
  lea    0x1(%rbp),%r15
  cmp    %r12,%rbp
  cmovbe %r12,%r15
  sub    %r15,%rbx
  lea    0x2(%rbx),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%rbp,%rbx,1)
  test   %r14,%r14
  je     L9
  sub    $0x1,%r15
  cmp    %r15,%r12
  jae    L24
L21:
  movsbl (%r15),%edi
  call   *%r13
  test   %eax,%eax
  je     L24
  sub    $0x1,%r15
  cmp    %r15,%r12
  jne    L21
  mov    %r12,%r15
L24:
  cmp    %r15,%r12
  cmovb  %r15,%r12
  mov    %r12,(%r14)
L9:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    $0x0,%ebp
  jmp    L9
```

assistant: ```c
char *dup_token_r(char *start, char *start_string, char **nptr, int (*isdelimiter)(int)) {
  char *ptr, *rv;
  if (start <= start_string)
    return NULL;
  while (isdelimiter(*start) && (start > start_string))
    start--;
  if (start < start_string)
    start = start_string;
  ptr = start;
  while (!isdelimiter(*ptr) && (ptr > start_string))
    ptr--;
  if (ptr <= start_string)
    ptr = start_string;
  else
    ptr++;
  rv = xmalloc(start - ptr + 2);
  memcpy(rv, ptr, start - ptr + 1);
  rv[start - ptr + 1] = '\0';
  if (nptr != NULL) {
    ptr--;
    while ((ptr > start_string) && isdelimiter(*ptr))
      ptr--;
    if (ptr < start_string)
      ptr = start_string;
    *nptr = ptr;
  }
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dup_token_r>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdi
  jbe    L106
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rcx,%r13
  jmp    L66
  nopl   0x0(%rax)
L27:
  test   %eax,%eax
  je     L127
  sub    $0x1,%rbx
L66:
  movsbl (%rbx),%edi
  call   *%r13
  cmp    %r12,%rbx
  ja     L27
L127:
  cmp    %r12,%rbx
  cmovb  %r12,%rbx
  mov    %rbx,%rbp
  jmp    L56
  nop
L95:
  test   %eax,%eax
  jne    L32
  sub    $0x1,%rbp
L56:
  movsbl 0x0(%rbp),%edi
  call   *%r13
  cmp    %r12,%rbp
  ja     L95
L32:
  cmp    %r12,%rbp
  lea    0x1(%rbp),%rax
  cmovbe %r12,%rax
  sub    %rax,%rbx
  mov    %rax,%rbp
  lea    0x2(%rbx),%edi
  call   <xmalloc@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r15,%rbx,1)
  test   %r14,%r14
  je     L80
  sub    $0x1,%rbp
  cmp    %rbp,%r12
  jb     L6
  jmp    L61
  nopl   0x0(%rax)
L44:
  sub    $0x1,%rbp
  cmp    %rbp,%r12
  je     L61
L6:
  movsbl 0x0(%rbp),%edi
  call   *%r13
  test   %eax,%eax
  jne    L44
L61:
  cmp    %rbp,%r12
  cmovb  %rbp,%r12
  mov    %r12,(%r14)
L80:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L106:
  xor    %r15d,%r15d
  jmp    L80
```

assistant: ```c
char *dup_token_r(char *start, char *start_string, char **nptr, int (*isdelimiter)(int)) {
  char *ptr, *rv;
  if (start <= start_string)
    return NULL;
  while (isdelimiter(*start) && (start > start_string))
    start--;
  if (start < start_string)
    start = start_string;
  ptr = start;
  while (!isdelimiter(*ptr) && (ptr > start_string))
    ptr--;
  if (ptr <= start_string)
    ptr = start_string;
  else
    ptr++;
  rv = xmalloc(start - ptr + 2);
  memcpy(rv, ptr, start - ptr + 1);
  rv[start - ptr + 1] = '\0';
  if (nptr != NULL) {
    ptr--;
    while ((ptr > start_string) && isdelimiter(*ptr))
      ptr--;
    if (ptr < start_string)
      ptr = start_string;
    *nptr = ptr;
  }
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dup_token_r>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%rdi
  jbe    L92
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rcx,%r13
  jmp    L98
  nopl   0x0(%rax)
L36:
  test   %eax,%eax
  je     L49
  sub    $0x1,%rbx
L98:
  movsbl (%rbx),%edi
  call   *%r13
  cmp    %r12,%rbx
  ja     L36
L49:
  cmp    %r12,%rbx
  cmovb  %r12,%rbx
  mov    %rbx,%rbp
  jmp    L5
  nop
L74:
  test   %eax,%eax
  jne    L75
  sub    $0x1,%rbp
L5:
  movsbl 0x0(%rbp),%edi
  call   *%r13
  cmp    %r12,%rbp
  ja     L74
L75:
  cmp    %r12,%rbp
  lea    0x1(%rbp),%rax
  cmovbe %r12,%rax
  sub    %rax,%rbx
  mov    %rax,%rbp
  lea    0x2(%rbx),%edi
  call   <xmalloc@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r15,%rbx,1)
  test   %r14,%r14
  je     L77
  sub    $0x1,%rbp
  cmp    %rbp,%r12
  jb     L107
  jmp    L66
  nopl   0x0(%rax)
L12:
  sub    $0x1,%rbp
  cmp    %rbp,%r12
  je     L66
L107:
  movsbl 0x0(%rbp),%edi
  call   *%r13
  test   %eax,%eax
  jne    L12
L66:
  cmp    %rbp,%r12
  cmovb  %rbp,%r12
  mov    %r12,(%r14)
L77:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  xor    %r15d,%r15d
  jmp    L77
```

assistant: ```c
char *dup_token_r(char *start, char *start_string, char **nptr, int (*isdelimiter)(int)) {
  char *ptr, *rv;
  if (start <= start_string)
    return NULL;
  while (isdelimiter(*start) && (start > start_string))
    start--;
  if (start < start_string)
    start = start_string;
  ptr = start;
  while (!isdelimiter(*ptr) && (ptr > start_string))
    ptr--;
  if (ptr <= start_string)
    ptr = start_string;
  else
    ptr++;
  rv = xmalloc(start - ptr + 2);
  memcpy(rv, ptr, start - ptr + 1);
  rv[start - ptr + 1] = '\0';
  if (nptr != NULL) {
    ptr--;
    while ((ptr > start_string) && isdelimiter(*ptr))
      ptr--;
    if (ptr < start_string)
      ptr = start_string;
    *nptr = ptr;
  }
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<len_of_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L13:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int len_of_tab(char **tab) {
  int i;
  i = 0;
  while (tab[i])
    i++;
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<len_of_tab>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L28
  mov    $0x1,%eax
L22:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L22
L15:
  mov    %edx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int len_of_tab(char **tab) {
  int i;
  i = 0;
  while (tab[i])
    i++;
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<len_of_tab>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L16
  mov    $0x1,%eax
  nop
L3:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int len_of_tab(char **tab) {
  int i;
  i = 0;
  while (tab[i])
    i++;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<len_of_tab>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L12
  mov    $0x1,%eax
  nop
L0:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int len_of_tab(char **tab) {
  int i;
  i = 0;
  while (tab[i])
    i++;
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<increaseWay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void increaseWay(int *way, int x, int y) {
  int size = way[0] + 2;
  way[size - 1] = y;
  way[size] = x;
  way[0] = size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<increaseWay>:
  endbr64
  mov    %edx,%ecx
  mov    (%rdi),%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  mov    %ecx,-0x4(%rdi,%rdx,4)
  mov    %esi,(%rdi,%rdx,4)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void increaseWay(int *way, int x, int y) {
  int size = way[0] + 2;
  way[size - 1] = y;
  way[size] = x;
  way[0] = size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<increaseWay>:
  endbr64
  mov    (%rdi),%eax
  mov    %edx,%r8d
  add    $0x2,%eax
  movslq %eax,%rdx
  mov    %r8d,-0x4(%rdi,%rdx,4)
  mov    %esi,(%rdi,%rdx,4)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void increaseWay(int *way, int x, int y) {
  int size = way[0] + 2;
  way[size - 1] = y;
  way[size] = x;
  way[0] = size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<increaseWay>:
  endbr64
  mov    (%rdi),%eax
  movd   %edx,%xmm0
  movd   %esi,%xmm1
  punpckldq %xmm1,%xmm0
  add    $0x2,%eax
  movslq %eax,%rcx
  movq   %xmm0,-0x4(%rdi,%rcx,4)
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void increaseWay(int *way, int x, int y) {
  int size = way[0] + 2;
  way[size - 1] = y;
  way[size] = x;
  way[0] = size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lvprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lprintf(const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = lvprintf(format, ap);
  va_end(ap);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <lvprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int lprintf(const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = lvprintf(format, ap);
  va_end(ap);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <lvprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int lprintf(const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = lvprintf(format, ap);
  va_end(ap);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <lvprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int lprintf(const char *format, ...) {
  int ret;
  va_list ap;
  va_start(ap, format);
  ret = lvprintf(format, ap);
  va_end(ap);
  return ret;
}
```