user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x40(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  je     L30
  cmpq   $0x0,-0x38(%rbp)
  je     L30
  mov    $0x1,%eax
  jmp    L72
L30:
  mov    $0x0,%eax
L72:
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x54(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x1c,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x48(%rbp)
  movl   $0x76c,-0x44(%rbp)
  jmp    L6
L2:
  movl   $0x0,-0x4c(%rbp)
  jmp    L106
L31:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x48(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x4c(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <month_len@plt>
  mov    -0x48(%rbp),%edx
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x48(%rbp)
  mov    -0x48(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x48(%rbp)
  addl   $0x1,-0x4c(%rbp)
L106:
  cmpl   $0xb,-0x4c(%rbp)
  jle    L31
  addl   $0x1,-0x44(%rbp)
L6:
  mov    -0x54(%rbp),%eax
  add    $0x76b,%eax
  cmp    %eax,-0x44(%rbp)
  jle    L2
  movl   $0x0,-0x50(%rbp)
  jmp    L60
L68:
  cmpl   $0x0,-0x50(%rbp)
  je     L49
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <fputc@plt>
L49:
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addl   $0x1,-0x50(%rbp)
L60:
  cmpl   $0x6,-0x50(%rbp)
  jle    L68
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D47
datatype: string
name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D59
datatype: string
name: parse_data
arguments: tag: D1
datatype: string

tool: D47: r

tool: D20: friday.in

tool: D29: w

tool: D59: friday.out

tool: D1: %d

assistant: ```c
int main(void) {
  FILE *fin;
  FILE *fout;
  int i;
  int m;
  int day_of_week;
  int N;
  int y;
  int day_of_week_numbers[7];
  fin = fopen("friday.in", "r");
  fout = fopen("friday.out", "w");
  assert(fin != NULL && fout != NULL);
  fscanf(fin, "%d", &N);
  memset(day_of_week_numbers, 0, sizeof(day_of_week_numbers));
  day_of_week = 0;
  for (y = 1900; y < 1900 + N; ++y) {
    for (m = 0; m < 12; ++m) {
      ++day_of_week_numbers[day_of_week];
      day_of_week = (day_of_week + month_len(y, m)) % 7;
    }
  }
  for (i = 0; i < 7; ++i) {
    if (i) {
      fprintf(fout, " ");
    }
    fprintf(fout, "%d", day_of_week_numbers[i]);
  }
  fprintf(fout, "\n");
  fclose(fin);
  fclose(fout);
  return 0;
}
```