ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_sqrt>:
  endbr64
  xor    %r9d,%r9d
  mov    $0x1f,%eax
  xor    %r8d,%r8d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L11:
  mov    %eax,%ecx
  mov    %r8d,%edx
  mov    %rsi,%r10
  shl    %cl,%edx
  lea    (%rax,%rax,1),%ecx
  lea    (%r9,%rdx,2),%edx
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L17
  mov    %rsi,%r11
  mov    %eax,%ecx
  mov    %edx,%r9d
  shl    %cl,%r11
  add    %r11d,%r8d
L17:
  sub    $0x1,%eax
  jae    L11
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  int s;
  uint64_t ret_sq = 0;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_duplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x6,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <search@plt>
  cmp    $0x7,%eax
  jne    L6
  lea    -0x30(%rbp),%rax
  mov    $0x5,%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <search@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  mov    $0x1,%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int test_duplicates() {
  int input[] = {6, 6, 6, 6, 6, 6, 6, 1, 2, 6};
  return 7 == search(input, 0, 9, 1) && -1 == search(input, 0, 9, 5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_duplicates>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x6,(%rsp)
  movl   $0x6,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x6,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  call   <search@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x7,%edx
  je     L1
L22:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  ret
L1:
  mov    %rsp,%rdi
  mov    $0x5,%ecx
  mov    $0x9,%edx
  mov    $0x0,%esi
  call   <search@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L22
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_duplicates() {
  int input[] = {6, 6, 6, 6, 6, 6, 6, 1, 2, 6};
  return 7 == search(input, 0, 9, 1) && -1 == search(input, 0, 9, 5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_duplicates>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x9,%edx
  xor    %esi,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000006,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x100000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x600000002,%rax
  mov    %rax,0x20(%rsp)
  call   <search@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x7,%r8d
  je     L16
L4:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x30,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  xor    %esi,%esi
  mov    $0x5,%ecx
  mov    $0x9,%edx
  mov    %rbp,%rdi
  call   <search@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L4
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_duplicates() {
  int input[] = {6, 6, 6, 6, 6, 6, 6, 1, 2, 6};
  return 7 == search(input, 0, 9, 1) && -1 == search(input, 0, 9, 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_duplicates>:
  endbr64
  push   %rbp
  mov    $0x1,%ecx
  mov    $0x9,%edx
  xor    %esi,%esi
  sub    $0x30,%rsp
  movdqa D14(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D25(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D12(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <search@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x7,%r8d
  je     L19
L26:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x30,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %esi,%esi
  mov    $0x5,%ecx
  mov    $0x9,%edx
  mov    %rbp,%rdi
  call   <search@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L26
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
data_type: byte[16]
name: parse_data
arguments: label: D25
data_type: byte[8]
name: parse_data
arguments: label: D12
data_type: byte[16]

tool: {"D14": [0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D25": [0x02,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D12": [0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int test_duplicates() {
  int input[] = {6, 6, 6, 6, 6, 6, 6, 1, 2, 6};
  return 7 == search(input, 0, 9, 1) && -1 == search(input, 0, 9, 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D14
type: string

tool: D23: Usage: %s int_0 int_1 int_2 ... int_n



tool: D13: Sort an array composed by [int_0, int_1, int_2, ..., int_n]


tool: D15: Example: %s 2 6 5


tool: D14: Outputs: 2 5 6

assistant: ```c
void usage(char *command) {
  printf("Usage: %s int_0 int_1 int_2 ... int_n\n\n", command);
  printf("Sort an array composed by [int_0, int_1, int_2, ..., int_n]\n\n");
  printf("Example: %s 2 6 5\n", command);
  printf("Outputs: 2 5 6\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D20
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string

tool: D31: Usage: %s int_0 int_1 int_2 ... int_n



tool: D20: Sort an array composed by [int_0, int_1, int_2, ..., int_n]


tool: D7: Example: %s 2 6 5


tool: D26: Outputs: 2 5 6

assistant: ```c
void usage(char *command) {
  printf("Usage: %s int_0 int_1 int_2 ... int_n\n\n", command);
  printf("Sort an array composed by [int_0, int_1, int_2, ..., int_n]\n\n");
  printf("Example: %s 2 6 5\n", command);
  printf("Outputs: 2 5 6\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D34
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string

tool: D21: Usage: %s int_0 int_1 int_2 ... int_n



tool: D34: Sort an array composed by [int_0, int_1, int_2, ..., int_n]


tool: D18: Example: %s 2 6 5


tool: D38: Outputs: 2 5 6

assistant: ```c
void usage(char *command) {
  printf("Usage: %s int_0 int_1 int_2 ... int_n\n\n", command);
  printf("Sort an array composed by [int_0, int_1, int_2, ..., int_n]\n\n");
  printf("Example: %s 2 6 5\n", command);
  printf("Outputs: 2 5 6\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string

tool: D16: Usage: %s int_0 int_1 int_2 ... int_n



tool: D13: Sort an array composed by [int_0, int_1, int_2, ..., int_n]


tool: D11: Example: %s 2 6 5


tool: D36: Outputs: 2 5 6

assistant: ```c
void usage(char *command) {
  printf("Usage: %s int_0 int_1 int_2 ... int_n\n\n", command);
  printf("Sort an array composed by [int_0, int_1, int_2, ..., int_n]\n\n");
  printf("Example: %s 2 6 5\n", command);
  printf("Outputs: 2 5 6\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<anonname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D29(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D11(%rip)
  mov    -0x8(%rbp),%rcx
  mov    %eax,%edx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_infered: string

tool: D11: _anonymous_%d

assistant: ```c
void anonname(char *buf) {
  static int anon_id = 0;
  sprintf(buf, "_anonymous_%d", anon_id++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<anonname>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%edx
  lea    0x1(%rdx),%eax
  mov    %eax,D23(%rip)
  lea    D23(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
data_type: string

tool: D23: _anonymous_%d

assistant: ```c
void anonname(char *buf) {
  static int anon_id = 0;
  sprintf(buf, "_anonymous_%d", anon_id++);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    D8(%rip),%r13
  lea    D11(%rip),%r12
  jmp    L50
  mov    %r9d,%esi
L94:
  mov    %sil,(%rcx)
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L72
L56:
  mov    %rax,%rcx
  movzbl (%rax),%edx
  mov    %edx,%edi
  and    $0xfffffffb,%edi
  mov    %r8d,%esi
  cmp    $0x42,%dil
  je     L94
  sub    $0x43,%edx
  cmp    $0x17,%dl
  ja     L164
  movzbl %dl,%edx
  movslq (%r12,%rdx,4),%rdx
  add    %r12,%rdx
  notrack jmp *%rdx
  mov    $0x33,%esi
  jmp    L94
  mov    $0x34,%esi
  jmp    L94
  mov    %r10d,%esi
  jmp    L94
  mov    %r11d,%esi
  jmp    L94
L164:
  mov    %r15d,%esi
  jmp    L94
L37:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L74
L72:
  movzbl (%rbx),%edi
  lea    -0x31(%rdi),%eax
  cmp    $0x5,%al
  ja     L37
  cmp    -0x1(%rbx),%dil
  je     L37
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L37
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
L50:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L117
  mov    %r14,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L74
  mov    %rsp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%rbp
  mov    %rbx,%rax
  mov    $0x31,%r8d
  mov    $0x20,%r15d
  mov    $0x36,%r11d
  mov    $0x35,%r10d
  mov    $0x32,%r9d
  jmp    L56
L117:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L120:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: %s

assistant: ```c
int main() {
  char b[25];
  int i, len;
  while (scanf("%s", b) == 1) {
    len = strlen(b);
    for (i = 0; i < len; i++) {
      if (b[i] == 'B' || b[i] == 'F' || b[i] == 'P' || b[i] == 'V')
        b[i] = '1';
      else if (b[i] == 'C' || b[i] == 'G' || b[i] == 'J' || b[i] == 'K' || b[i] == 'Q' || b[i] == 'S' || b[i] == 'X' || b[i] == 'Z')
        b[i] = '2';
      else if (b[i] == 'D' || b[i] == 'T')
        b[i] = '3';
      else if (b[i] == 'L')
        b[i] = '4';
      else if (b[i] == 'M' || b[i] == 'N')
        b[i] = '5';
      else if (b[i] == 'R')
        b[i] = '6';
      else
        b[i] = ' ';
    }
    for (i = 0; i < len; i++) {
      if (b[i] >= '1' && b[i] <= '6') {
        if (b[i] != b[i - 1]) {
          printf("%c", b[i]);
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L110
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L97
  lea    -0x1(%rax),%r15d
  mov    %rbp,%r14
  mov    %rbp,%rax
  add    %r13,%r15
  nopl   0x0(%rax)
L152:
  movzbl (%rax),%edx
  mov    $0x31,%ecx
  mov    %edx,%esi
  and    $0xfffffffb,%esi
  cmp    $0x42,%sil
  je     L96
  sub    $0x43,%edx
  cmp    $0x17,%dl
  ja     L62
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  mov    $0x32,%ecx
  nopl   (%rax)
L96:
  mov    %cl,(%rax)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L152
  nopl   0x0(%rax,%rax,1)
L38:
  movsbl (%r14),%edi
  lea    -0x31(%rdi),%eax
  cmp    $0x5,%al
  ja     L23
  cmp    -0x1(%r14),%dil
  je     L23
  call   <putchar@plt>
L23:
  add    $0x1,%r14
  cmp    %r14,%r15
  jne    L38
L97:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L3
L110:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L159
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    $0x20,%ecx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
  mov    $0x35,%ecx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
  mov    $0x33,%ecx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
  mov    $0x31,%ecx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
  mov    $0x34,%ecx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
  mov    $0x36,%ecx
  jmp    L96
L159:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string

tool: D11: %s

assistant: ```c
int main() {
  char b[25];
  int i, len;
  while (scanf("%s", b) == 1) {
    len = strlen(b);
    for (i = 0; i < len; i++) {
      if (b[i] == 'B' || b[i] == 'F' || b[i] == 'P' || b[i] == 'V')
        b[i] = '1';
      else if (b[i] == 'C' || b[i] == 'G' || b[i] == 'J' || b[i] == 'K' || b[i] == 'Q' || b[i] == 'S' || b[i] == 'X' || b[i] == 'Z')
        b[i] = '2';
      else if (b[i] == 'D' || b[i] == 'T')
        b[i] = '3';
      else if (b[i] == 'L')
        b[i] = '4';
      else if (b[i] == 'M' || b[i] == 'N')
        b[i] = '5';
      else if (b[i] == 'R')
        b[i] = '6';
      else
        b[i] = ' ';
    }
    for (i = 0; i < len; i++) {
      if (b[i] >= '1' && b[i] <= '6') {
        if (b[i] != b[i - 1]) {
          printf("%c", b[i]);
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L22
  nopl   0x0(%rax)
L131:
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L133
  lea    -0x1(%rax),%r15d
  mov    %rbp,%r14
  mov    %rbp,%rax
  add    %r13,%r15
  nopl   0x0(%rax)
L149:
  movzbl (%rax),%edx
  mov    $0x31,%ecx
  mov    %edx,%esi
  and    $0xfffffffb,%esi
  cmp    $0x42,%sil
  je     L114
  sub    $0x43,%edx
  cmp    $0x17,%dl
  ja     L30
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  mov    $0x32,%ecx
  nopl   (%rax)
L114:
  mov    %cl,(%rax)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L149
  nopl   0x0(%rax,%rax,1)
L134:
  movsbl (%r14),%edi
  lea    -0x31(%rdi),%eax
  cmp    $0x5,%al
  ja     L130
  cmp    -0x1(%r14),%dil
  je     L130
  call   <putchar@plt>
L130:
  add    $0x1,%r14
  cmp    %r15,%r14
  jne    L134
L133:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L131
L22:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L154
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    $0x20,%ecx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x35,%ecx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x33,%ecx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x31,%ecx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x34,%ecx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x36,%ecx
  jmp    L114
L154:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D10: %s

assistant: ```c
int main() {
  char b[25];
  int i, len;
  while (scanf("%s", b) == 1) {
    len = strlen(b);
    for (i = 0; i < len; i++) {
      if (b[i] == 'B' || b[i] == 'F' || b[i] == 'P' || b[i] == 'V')
        b[i] = '1';
      else if (b[i] == 'C' || b[i] == 'G' || b[i] == 'J' || b[i] == 'K' || b[i] == 'Q' || b[i] == 'S' || b[i] == 'X' || b[i] == 'Z')
        b[i] = '2';
      else if (b[i] == 'D' || b[i] == 'T')
        b[i] = '3';
      else if (b[i] == 'L')
        b[i] = '4';
      else if (b[i] == 'M' || b[i] == 'N')
        b[i] = '5';
      else if (b[i] == 'R')
        b[i] = '6';
      else
        b[i] = ' ';
    }
    for (i = 0; i < len; i++) {
      if (b[i] >= '1' && b[i] <= '6') {
        if (b[i] != b[i - 1]) {
          printf("%c", b[i]);
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<destroy_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void destroy_table(char **table, int width) {
  for (int i = 0; i < width; i++)
    free(table[i]);
  free(table);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<destroy_table>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L18:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L18
L17:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void destroy_table(char **table, int width) {
  for (int i = 0; i < width; i++)
    free(table[i]);
  free(table);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_table>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L14
L6:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void destroy_table(char **table, int width) {
  for (int i = 0; i < width; i++)
    free(table[i]);
  free(table);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<destroy_table>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L10
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void destroy_table(char **table, int width) {
  for (int i = 0; i < width; i++)
    free(table[i]);
  free(table);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<overlappingWriteFunction_bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bcopy@plt>
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bcopy@plt>
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bcopy@plt>
  nop
  leave
  ret
```

assistant: ```c
void overlappingWriteFunction_bcopy(char *buf, const size_t count) {
  bcopy(&buf[0], &buf[3], count);
  bcopy(&buf[0], &buf[3], 3U);
  bcopy(&buf[0], &buf[3], 4U);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<overlappingWriteFunction_bcopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  lea    0x3(%rdi),%rbp
  mov    %rbp,%rsi
  call   <bcopy@plt>
  mov    $0x3,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcopy@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcopy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void overlappingWriteFunction_bcopy(char *buf, const size_t count) {
  bcopy(&buf[0], &buf[3], count);
  bcopy(&buf[0], &buf[3], 3U);
  bcopy(&buf[0], &buf[3], 4U);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<overlappingWriteFunction_bcopy>:
  endbr64
  push   %r12
  lea    0x3(%rdi),%r12
  mov    %rsi,%rdx
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <bcopy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x3,%edx
  call   <bcopy@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x4,%edx
  pop    %rbp
  pop    %r12
  jmp    1050 <bcopy@plt>
```

assistant: ```c
void overlappingWriteFunction_bcopy(char *buf, const size_t count) {
  bcopy(&buf[0], &buf[3], count);
  bcopy(&buf[0], &buf[3], 3U);
  bcopy(&buf[0], &buf[3], 4U);
}
```