ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<_memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %edx,%esi
  test   %r8,%r8
  sete   %al
  test   %rdi,%rdi
  sete   %dl
  or     %dl,%al
  jne    L13
  test   %esi,%esi
  je     L13
  lea    0x1(%rdi),%rdx
  mov    %r8,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L32
  cmp    $0x6,%esi
  jbe    L32
  lea    0x1(%rsi),%r10d
  cmp    $0xe,%esi
  jbe    L61
  lea    -0xf(%rsi),%ecx
  xor    %eax,%eax
  xor    %edx,%edx
  shr    $0x4,%ecx
  add    $0x1,%ecx
  nop
L43:
  movdqu (%rdi,%rax,1),%xmm0
  add    $0x1,%edx
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %edx,%ecx
  ja     L43
  shl    $0x4,%ecx
  mov    %esi,%eax
  mov    %ecx,%r11d
  sub    %ecx,%eax
  lea    (%r8,%r11,1),%rdx
  lea    (%rdi,%r11,1),%r9
  cmp    %ecx,%r10d
  je     L13
  lea    0x1(%rax),%r10d
  cmp    $0x6,%eax
  jbe    L54
L56:
  mov    (%rdi,%r11,1),%rcx
  mov    %rcx,(%r8,%r11,1)
  mov    %r10d,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  sub    %ecx,%eax
  add    %rsi,%rdx
  add    %rsi,%r9
  cmp    %ecx,%r10d
  je     L13
L54:
  movzbl (%r9),%ecx
  mov    %cl,(%rdx)
  test   %eax,%eax
  je     L13
  movzbl 0x1(%r9),%ecx
  mov    %cl,0x1(%rdx)
  cmp    $0x1,%eax
  je     L13
  movzbl 0x2(%r9),%ecx
  mov    %cl,0x2(%rdx)
  cmp    $0x2,%eax
  je     L13
  movzbl 0x3(%r9),%ecx
  mov    %cl,0x3(%rdx)
  cmp    $0x3,%eax
  je     L13
  movzbl 0x4(%r9),%ecx
  mov    %cl,0x4(%rdx)
  cmp    $0x4,%eax
  je     L13
  movzbl 0x5(%r9),%ecx
  mov    %cl,0x5(%rdx)
  cmp    $0x5,%eax
  je     L13
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdx)
L13:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L12
  mov    %r8,%rax
  ret
L61:
  mov    %esi,%eax
  mov    %rdi,%r9
  mov    %r8,%rdx
  xor    %r11d,%r11d
  jmp    L56
```

assistant: ```c
void *_memcpy(void *dst, const void *src, unsigned n) {
  if (n == 0 || dst == ((void *)0) || src == ((void *)0))
    return dst;
  void *dst_orig = dst;
  do {
    *((char *)dst++) = *((char *)src++);
  } while (n--);
  return dst_orig;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_dbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L15
  mov    $0x1,%eax
  jmp    L30
L15:
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L0
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L0
  mov    $0x0,%eax
  jmp    L30
L0:
  mov    $0xffffffff,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_dbl(const void *a, const void *b) {
  const double x = *(const double *)a;
  const double y = *(const double *)b;
  if (x > y)
    return 1;
  if (x == y)
    return 0;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp_dbl>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L0
  ucomisd %xmm0,%xmm1
  setp   %al
  movzbl %al,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  neg    %eax
L0:
  ret
```

assistant: ```c
int cmp_dbl(const void *a, const void *b) {
  const double x = *(const double *)a;
  const double y = *(const double *)b;
  if (x > y)
    return 1;
  if (x == y)
    return 0;
  else
    return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<cmp_dbl>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L2
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L2:
  ret
```

assistant: ```c
int cmp_dbl(const void *a, const void *b) {
  const double x = *(const double *)a;
  const double y = *(const double *)b;
  if (x > y)
    return 1;
  if (x == y)
    return 0;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmp_dbl>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0x1,%eax
  comisd %xmm0,%xmm1
  ja     L3
  xor    %edx,%edx
  ucomisd %xmm0,%xmm1
  setp   %dl
  cmove  %edx,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int cmp_dbl(const void *a, const void *b) {
  const double x = *(const double *)a;
  const double y = *(const double *)b;
  if (x > y)
    return 1;
  if (x == y)
    return 0;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L45
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x0,-0xc(%rbp)
  jns    L5
  jmp    L23
L45:
  nop
L23:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <applyInversion@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L55
L66:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L22
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L22:
  subl   $0x1,-0xc(%rbp)
L55:
  cmpl   $0x0,-0xc(%rbp)
  jns    L66
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getFileName(char *destiny, const char *fileWithPath) {
  int i, pos;
  for (i = (strlen(fileWithPath) - 1), pos = 0; (i >= 0); i--, pos++) {
    if (fileWithPath[i] == '/')
      break;
    destiny[pos] = fileWithPath[i];
  }
  destiny[pos] = '\0';
  applyInversion(destiny);
  const int endIdx = strlen(destiny) - 1;
  for (i = endIdx; (i >= 0); i--) {
    if (destiny[i] == '.')
      destiny[i] = '\0';
  }
  return destiny;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getFileName>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L45
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%edx
L88:
  movzbl (%rsi),%ecx
  cmp    $0x2f,%cl
  je     L32
  mov    %cl,(%rdi)
  add    $0x1,%edx
  sub    $0x1,%rsi
  add    $0x1,%rdi
  cmp    %edx,%eax
  jne    L88
  mov    %eax,%edx
L32:
  movslq %edx,%rdx
  movb   $0x0,0x0(%rbp,%rdx,1)
  mov    %rbp,%rdi
  call   <applyInversion@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L69
  movslq %edx,%rdx
  add    %rbp,%rdx
  cltq
  lea    -0x2(%rbp,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
  jmp    L17
L45:
  mov    $0x0,%edx
  jmp    L32
L50:
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L69
L17:
  cmpb   $0x2e,(%rdx)
  jne    L50
  movb   $0x0,(%rdx)
  jmp    L50
L69:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getFileName(char *destiny, const char *fileWithPath) {
  int i, pos;
  for (i = (strlen(fileWithPath) - 1), pos = 0; (i >= 0); i--, pos++) {
    if (fileWithPath[i] == '/')
      break;
    destiny[pos] = fileWithPath[i];
  }
  destiny[pos] = '\0';
  applyInversion(destiny);
  const int endIdx = strlen(destiny) - 1;
  for (i = endIdx; (i >= 0); i--) {
    if (destiny[i] == '.')
      destiny[i] = '\0';
  }
  return destiny;
}
```
user: What is the c source code of the assembly code below:

```asm
<getFileName>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L76
  movslq %eax,%rdx
  mov    $0x1,%edi
  mov    %eax,%eax
  lea    0x1(%r12,%rax,1),%r8
  lea    (%rbx,%rdx,1),%rsi
  mov    %r12,%rax
  sub    %r12d,%edi
  jmp    L40
  nopl   (%rax)
L5:
  mov    %cl,(%rax)
  lea    (%rdi,%rax,1),%ecx
  lea    0x1(%rax),%rax
  sub    $0x1,%rsi
  cmp    %r8,%rax
  je     L12
L40:
  movzbl (%rsi),%ecx
  mov    %rax,%rdx
  cmp    $0x2f,%cl
  jne    L5
L66:
  movb   $0x0,(%rdx)
  mov    %r12,%rdi
  call   <applyInversion@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L22
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%r12,%rax,1),%rax
  add    %r12,%rdx
  sub    %rcx,%rax
  nopl   0x0(%rax)
L74:
  cmpb   $0x2e,(%rdx)
  jne    L31
  movb   $0x0,(%rdx)
L31:
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L74
L22:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  movslq %ecx,%rcx
  lea    (%r12,%rcx,1),%rdx
  jmp    L66
L76:
  mov    %r12,%rdx
  jmp    L66
```

assistant: ```c
char *getFileName(char *destiny, const char *fileWithPath) {
  int i, pos;
  for (i = (strlen(fileWithPath) - 1), pos = 0; (i >= 0); i--, pos++) {
    if (fileWithPath[i] == '/')
      break;
    destiny[pos] = fileWithPath[i];
  }
  destiny[pos] = '\0';
  applyInversion(destiny);
  const int endIdx = strlen(destiny) - 1;
  for (i = endIdx; (i >= 0); i--) {
    if (destiny[i] == '.')
      destiny[i] = '\0';
  }
  return destiny;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getFileName>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L36
  movslq %eax,%rdx
  mov    $0x1,%edi
  mov    %eax,%eax
  lea    0x1(%r12,%rax,1),%r8
  lea    (%rbx,%rdx,1),%rsi
  mov    %r12,%rax
  sub    %r12d,%edi
  jmp    L65
  nopl   (%rax)
L38:
  mov    %cl,(%rax)
  lea    (%rdi,%rax,1),%ecx
  lea    0x1(%rax),%rax
  sub    $0x1,%rsi
  cmp    %r8,%rax
  je     L40
L65:
  movzbl (%rsi),%ecx
  mov    %rax,%rdx
  cmp    $0x2f,%cl
  jne    L38
L54:
  movb   $0x0,(%rdx)
  mov    %r12,%rdi
  call   <applyInversion@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L33
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%r12,%rax,1),%rax
  add    %r12,%rdx
  sub    %rcx,%rax
  nopl   0x0(%rax)
L30:
  cmpb   $0x2e,(%rdx)
  jne    L17
  movb   $0x0,(%rdx)
L17:
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L30
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  movslq %ecx,%rcx
  lea    (%r12,%rcx,1),%rdx
  jmp    L54
L36:
  mov    %r12,%rdx
  jmp    L54
```

assistant: ```c
char *getFileName(char *destiny, const char *fileWithPath) {
  int i, pos;
  for (i = (strlen(fileWithPath) - 1), pos = 0; (i >= 0); i--, pos++) {
    if (fileWithPath[i] == '/')
      break;
    destiny[pos] = fileWithPath[i];
  }
  destiny[pos] = '\0';
  applyInversion(destiny);
  const int endIdx = strlen(destiny) - 1;
  for (i = endIdx; (i >= 0); i--) {
    if (destiny[i] == '.')
      destiny[i] = '\0';
  }
  return destiny;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printlf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L10
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D13: .lf %d %s


tool: D9: .lf %d


assistant: ```c
void printlf(int n, char *f) {
  if (f)
    printf(".lf %d %s\n", n, f);
  else
    printf(".lf %d\n", n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printlf>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L15
  mov    %rsi,%rdx
  mov    %edi,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  add    $0x8,%rsp
  ret
L15:
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D15: .lf %d %s


tool: D3: .lf %d


assistant: ```c
void printlf(int n, char *f) {
  if (f)
    printf(".lf %d %s\n", n, f);
  else
    printf(".lf %d\n", n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printlf>:
  endbr64
  mov    %rsi,%rdx
  mov    %edi,%esi
  test   %rdx,%rdx
  je     L8
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L8:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string

tool: D17: .lf %d %s


tool: D14: .lf %d


assistant: ```c
void printlf(int n, char *f) {
  if (f)
    printf(".lf %d %s\n", n, f);
  else
    printf(".lf %d\n", n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printlf>:
  endbr64
  mov    %rsi,%rdx
  mov    %edi,%esi
  test   %rdx,%rdx
  je     L0
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L0:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D11
type: string

tool: D1: .lf %d %s


tool: D11: .lf %d


assistant: ```c
void printlf(int n, char *f) {
  if (f)
    printf(".lf %d %s\n", n, f);
  else
    printf(".lf %d\n", n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drawField>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L71
L73:
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L10:
  cmpl   $0x0,-0x8(%rbp)
  je     L53
  cmpl   $0x18,-0x8(%rbp)
  jne    L22
L53:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x2d,(%rdx,%rax,1)
  jmp    L54
L22:
  cmpl   $0x0,-0x4(%rbp)
  je     L43
  cmpl   $0x31,-0x4(%rbp)
  jne    L82
L43:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x7c,(%rdx,%rax,1)
  jmp    L54
L82:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
L54:
  addl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0x31,-0x4(%rbp)
  jle    L10
  addl   $0x1,-0x8(%rbp)
L71:
  cmpl   $0x18,-0x8(%rbp)
  jle    L73
  mov    -0x18(%rbp),%rax
  movb   $0x2b,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x2b,0x31(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4b0,%rax
  movb   $0x2b,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4b0,%rax
  movb   $0x2b,0x31(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void drawField(char campo[25][50]) {
  int i, j;
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0 || i == 25 - 1)
        campo[i][j] = '-';
      else if (j == 0 || j == 50 - 1)
        campo[i][j] = '|';
      else
        campo[i][j] = ' ';
    }
  }
  campo[0][0] = '+';
  campo[0][50 - 1] = '+';
  campo[25 - 1][0] = '+';
  campo[25 - 1][50 - 1] = '+';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drawField>:
  endbr64
  mov    %rdi,%rsi
  mov    $0x0,%edx
  jmp    L66
L13:
  movb   $0x2d,(%rcx,%rax,1)
L0:
  add    $0x1,%rax
  cmp    $0x32,%rax
  je     L91
L54:
  test   %edx,%edx
  je     L13
  cmp    $0x18,%edx
  je     L13
  test   %eax,%eax
  je     L23
  cmp    $0x31,%eax
  je     L23
  movb   $0x20,(%rcx,%rax,1)
  jmp    L0
L23:
  movb   $0x7c,(%rcx,%rax,1)
  jmp    L0
L91:
  add    $0x1,%edx
  add    $0x32,%rsi
  cmp    $0x19,%edx
  je     L57
L66:
  mov    %rsi,%rcx
  mov    $0x0,%eax
  jmp    L54
L57:
  movb   $0x2b,(%rdi)
  movb   $0x2b,0x31(%rdi)
  movb   $0x2b,0x4b0(%rdi)
  movb   $0x2b,0x4e1(%rdi)
  ret
```

assistant: ```c
void drawField(char campo[25][50]) {
  int i, j;
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0 || i == 25 - 1)
        campo[i][j] = '-';
      else if (j == 0 || j == 50 - 1)
        campo[i][j] = '|';
      else
        campo[i][j] = ' ';
    }
  }
  campo[0][0] = '+';
  campo[0][50 - 1] = '+';
  campo[25 - 1][0] = '+';
  campo[25 - 1][50 - 1] = '+';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<drawField>:
  endbr64
  mov    %rdi,%r10
  mov    %rdi,%rsi
  xor    %r8d,%r8d
  mov    $0x1000001,%r9d
  movabs $0x2000000000001,%rdi
  nopl   (%rax)
L23:
  mov    %r8d,%ecx
  mov    %r9,%rdx
  shr    %cl,%rdx
  xor    %ecx,%ecx
  and    $0x1,%edx
  xchg   %ax,%ax
L10:
  mov    $0x2d,%eax
  test   %rdx,%rdx
  jne    L2
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xffffffa4,%eax
  add    $0x7c,%eax
L2:
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    $0x32,%rcx
  jne    L10
  add    $0x1,%r8d
  add    $0x32,%rsi
  cmp    $0x19,%r8d
  jne    L23
  movb   $0x2b,(%r10)
  movb   $0x2b,0x31(%r10)
  movb   $0x2b,0x4b0(%r10)
  movb   $0x2b,0x4e1(%r10)
  ret
```

assistant: ```c
void drawField(char campo[25][50]) {
  int i, j;
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0 || i == 25 - 1)
        campo[i][j] = '-';
      else if (j == 0 || j == 50 - 1)
        campo[i][j] = '|';
      else
        campo[i][j] = ' ';
    }
  }
  campo[0][0] = '+';
  campo[0][50 - 1] = '+';
  campo[25 - 1][0] = '+';
  campo[25 - 1][50 - 1] = '+';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<drawField>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  mov    $0x1000001,%edi
  movabs $0x2000000000001,%rsi
  jmp    L54
L16:
  mov    $0x2d2d,%eax
  movdqa D3(%rip),%xmm0
  mov    %ax,0x30(%rdx)
  movups %xmm0,(%rdx)
  movups %xmm0,0x10(%rdx)
  movups %xmm0,0x20(%rdx)
L57:
  add    $0x1,%ecx
  add    $0x32,%rdx
  cmp    $0x19,%ecx
  je     L23
L54:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  jne    L16
L2:
  bt     %rax,%rsi
  jb     L62
L69:
  movb   $0x20,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x32,%rax
  je     L57
  bt     %rax,%rsi
  jae    L69
L62:
  movb   $0x7c,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x32,%rax
  jne    L2
  add    $0x1,%ecx
  add    $0x32,%rdx
  cmp    $0x19,%ecx
  jne    L54
L23:
  movb   $0x2b,(%r8)
  movb   $0x2b,0x31(%r8)
  movb   $0x2b,0x4b0(%r8)
  movb   $0x2b,0x4e1(%r8)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: byte[16]

tool: {"D3": [0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d,0x2d]}

assistant: ```c
void drawField(char campo[25][50]) {
  int i, j;
  for (i = 0; i < 25; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0 || i == 25 - 1)
        campo[i][j] = '-';
      else if (j == 0 || j == 50 - 1)
        campo[i][j] = '|';
      else
        campo[i][j] = ' ';
    }
  }
  campo[0][0] = '+';
  campo[0][50 - 1] = '+';
  campo[25 - 1][0] = '+';
  campo[25 - 1][50 - 1] = '+';
}
```
user: What is the c source code of the assembly code below:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L47
L14:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L38
  mov    $0x0,%eax
  jmp    L54
L38:
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L14
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L54
  mov    $0x1,%eax
  jmp    L54
L54:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int a) {
  int c;
  for (c = 2; c <= a - 1; c++) {
    if (a % c == 0)
      return 0;
  }
  if (c == a)
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L21
  test   $0x1,%dil
  je     L31
  mov    $0x2,%ecx
L15:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L29
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L15
L46:
  ret
L29:
  mov    $0x1,%eax
  ret
L21:
  je     L17
  ret
L31:
  mov    $0x0,%eax
  ret
L17:
  mov    $0x1,%eax
  jmp    L46
```

assistant: ```c
int check_prime(int a) {
  int c;
  for (c = 2; c <= a - 1; c++) {
    if (a % c == 0)
      return 0;
  }
  if (c == a)
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L39
  test   $0x1,%dil
  je     L13
  mov    $0x2,%ecx
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L25
L18:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L33
L68:
  mov    $0x1,%edx
L25:
  mov    %edx,%eax
  ret
L39:
  je     L68
  mov    %edx,%eax
  ret
L13:
  xor    %edx,%edx
  jmp    L25
```

assistant: ```c
int check_prime(int a) {
  int c;
  for (c = 2; c <= a - 1; c++) {
    if (a % c == 0)
      return 0;
  }
  if (c == a)
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L47
  test   $0x1,%dil
  je     L30
  mov    $0x2,%ecx
  jmp    L65
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L44
L65:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L8
L28:
  mov    $0x1,%edx
L44:
  mov    %edx,%eax
  ret
L47:
  je     L28
  mov    %edx,%eax
  ret
L30:
  xor    %edx,%edx
  jmp    L44
```

assistant: ```c
int check_prime(int a) {
  int c;
  for (c = 2; c <= a - 1; c++) {
    if (a % c == 0)
      return 0;
  }
  if (c == a)
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copydate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lchmod@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  lea    -0x2c(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utime@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int copydate(const char *pszToFile, const char *pszFromFile) {
  struct stat stFrom = {0};
  struct utimbuf utbTo = {0};
  int err;
  do {
  } while (0);
  err = lstat(pszFromFile, &stFrom);
  err = lchmod(pszToFile, stFrom.st_mode);
  utbTo.actime = stFrom.st_atime;
  utbTo.modtime = stFrom.st_mtime;
  err = utime(pszToFile, &utbTo);

  ;
  return err;
}
```