ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<all_ada_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_ada_comments@plt>
  mov    $0x0,%eax
  call   <test_ada_comment_entities@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void all_ada_tests() {
  test_ada_comments();
  test_ada_comment_entities();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<all_ada_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_ada_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_ada_comment_entities@plt>
```

assistant: ```c
void all_ada_tests() {
  test_ada_comments();
  test_ada_comment_entities();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_ada_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_ada_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_ada_comment_entities@plt>
```

assistant: ```c
void all_ada_tests() {
  test_ada_comments();
  test_ada_comment_entities();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L21
L0:
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rsi,%r8
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x2c(%rbp),%edx
  add    $0x1,%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L21:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D44
type: string
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D29
type: string

tool: D23: r

tool: D44: minion.in

tool: D25: %d

tool: D7: %lf %lf %lf

tool: D29: Scenario #%d: %.2f


assistant: ```c
int main() {
  int x, i;
  double m1, t1, m2;
  FILE *ifp = fopen("minion.in", "r");
  fscanf(ifp, "%d", &x);
  for (i = 0; i < x; i++) {
    fscanf(ifp, "%lf %lf %lf", &m1, &t1, &m2);
    printf("Scenario #%d: %.2f\n", i + 1, (m1 * t1) / m2);
  }
  fclose(ifp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rsi
  lea    D35(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0xc(%rsp),%rdx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L14
  mov    $0x0,%ebx
  lea    0x20(%rsp),%r15
  lea    0x18(%rsp),%r14
  lea    D47(%rip),%r13
  lea    D25(%rip),%r12
L23:
  lea    0x10(%rsp),%rdx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  add    $0x1,%ebx
  movsd  0x10(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  divsd  0x20(%rsp),%xmm0
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    0xc(%rsp),%ebx
  jl     L23
L14:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D35
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D47
type: string
name: extract_symbolic_data
arguments: tag: D25
type: string

tool: D23: r

tool: D35: minion.in

tool: D6: %d

tool: D47: %lf %lf %lf

tool: D25: Scenario #%d: %.2f


assistant: ```c
int main() {
  int x, i;
  double m1, t1, m2;
  FILE *ifp = fopen("minion.in", "r");
  fscanf(ifp, "%d", &x);
  for (i = 0; i < x; i++) {
    fscanf(ifp, "%lf %lf %lf", &m1, &t1, &m2);
    printf("Scenario #%d: %.2f\n", i + 1, (m1 * t1) / m2);
  }
  fclose(ifp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D27(%rip),%rsi
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0xc(%rsp),%rdx
  lea    D48(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L23
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D42(%rip),%rbx
  nop
L1:
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  call   <fscanf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mulsd  0x18(%rsp),%xmm0
  divsd  0x20(%rsp),%xmm0
  call   <printf@plt>
  cmp    0xc(%rsp),%r15d
  jl     L1
L23:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D48
type: string
name: disassemble_data
arguments: data_tag: D42
type: string
name: disassemble_data
arguments: data_tag: D37
type: string

tool: D27: r

tool: D12: minion.in

tool: D48: %d

tool: D42: Scenario #%d: %.2f


tool: D37: %lf %lf %lf

assistant: ```c
int main() {
  int x, i;
  double m1, t1, m2;
  FILE *ifp = fopen("minion.in", "r");
  fscanf(ifp, "%d", &x);
  for (i = 0; i < x; i++) {
    fscanf(ifp, "%lf %lf %lf", &m1, &t1, &m2);
    printf("Scenario #%d: %.2f\n", i + 1, (m1 * t1) / m2);
  }
  fclose(ifp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D47(%rip),%rsi
  lea    D38(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0xc(%rsp),%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L22
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D3(%rip),%rbx
  nop
L15:
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  call   <fscanf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mulsd  0x18(%rsp),%xmm0
  divsd  0x20(%rsp),%xmm0
  call   <printf@plt>
  cmp    0xc(%rsp),%r15d
  jl     L15
L22:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D47
data_type: string
name: unpack_data
arguments: label: D38
data_type: string
name: unpack_data
arguments: label: D5
data_type: string
name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D47: r

tool: D38: minion.in

tool: D5: %d

tool: D3: Scenario #%d: %.2f


tool: D4: %lf %lf %lf

assistant: ```c
int main() {
  int x, i;
  double m1, t1, m2;
  FILE *ifp = fopen("minion.in", "r");
  fscanf(ifp, "%d", &x);
  for (i = 0; i < x; i++) {
    fscanf(ifp, "%lf %lf %lf", &m1, &t1, &m2);
    printf("Scenario #%d: %.2f\n", i + 1, (m1 * t1) / m2);
  }
  fclose(ifp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stat(const char *__restrict filename, struct stat *__restrict buf) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<stat>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stat(const char *__restrict filename, struct stat *__restrict buf) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stat>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stat(const char *__restrict filename, struct stat *__restrict buf) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stat>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int stat(const char *__restrict filename, struct stat *__restrict buf) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D68(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  lea    D50(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D53
type_infered: string
name: unpack_data
arguments: data_label: D68
type_infered: string
name: unpack_data
arguments: data_label: D50
type_infered: string

tool: D23: abc

tool: D53: %s


tool: D68: abcd

tool: D50: a

assistant: ```c
int main() {
  char *string;
  strcpy(string, "abc");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "abcd");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "a");
  reverse(string);
  printf("%s\n", string);
  string = NULL;
  reverse(string);
  printf("%s\n", string);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D26(%rip),%rsi
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  lea    D35(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <reverse@plt>
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D35
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D26: abc

tool: D35: %s


tool: D13: abcd

tool: D10: a

assistant: ```c
int main() {
  char *string;
  strcpy(string, "abc");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "abcd");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "a");
  reverse(string);
  printf("%s\n", string);
  string = NULL;
  reverse(string);
  printf("%s\n", string);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rsi
  lea    D27(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <reverse@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D5: abc

tool: D27: %s


tool: D20: abcd

tool: D9: a

assistant: ```c
int main() {
  char *string;
  strcpy(string, "abc");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "abcd");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "a");
  reverse(string);
  printf("%s\n", string);
  string = NULL;
  reverse(string);
  printf("%s\n", string);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%rsi
  lea    D39(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <reverse@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D39
type: string
name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D36: abc

tool: D39: %s


tool: D33: abcd

tool: D11: a

assistant: ```c
int main() {
  char *string;
  strcpy(string, "abc");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "abcd");
  reverse(string);
  printf("%s\n", string);
  strcpy(string, "a");
  reverse(string);
  printf("%s\n", string);
  string = NULL;
  reverse(string);
  printf("%s\n", string);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,-0x220(%rbp)
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x228(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x228(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L43
  lea    -0x210(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x218(%rbp)
  je     L26
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x218(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x220(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L28
L26:
  mov    -0x220(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L28
L43:
  mov    -0x220(%rbp),%rax
  movb   $0x0,(%rax)
L28:
  mov    -0x220(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6:  

assistant: ```c
char *get_prefix(char *line) {
  char *prefix = malloc(512);
  char clone[512];
  strncpy(clone, line, strlen(line) + 1);
  if (line[0] == ':') {
    char *splitted = strtok(clone, " ");
    if (splitted != NULL) {
      strncpy(prefix, splitted + 1, strlen(splitted) + 1);
    } else {
      prefix[0] = '\0';
    }
  } else {
    prefix[0] = '\0';
  }
  return prefix;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_prefix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x200,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <strncpy@plt>
  cmpb   $0x3a,(%rbx)
  je     L18
  movb   $0x0,0x0(%rbp)
L17:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %rbp,%rax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rsp,%rdi
  lea    D5(%rip),%rsi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  jmp    L17
L33:
  movb   $0x0,0x0(%rbp)
  jmp    L17
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5:  

assistant: ```c
char *get_prefix(char *line) {
  char *prefix = malloc(512);
  char clone[512];
  strncpy(clone, line, strlen(line) + 1);
  if (line[0] == ':') {
    char *splitted = strtok(clone, " ");
    if (splitted != NULL) {
      strncpy(prefix, splitted + 1, strlen(splitted) + 1);
    } else {
      prefix[0] = '\0';
    }
  } else {
    prefix[0] = '\0';
  }
  return prefix;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_prefix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x200,%edi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  cmpb   $0x3a,(%rbx)
  je     L14
L33:
  movb   $0x0,(%r12)
L26:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x210,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  jmp    L26
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D3:  

assistant: ```c
char *get_prefix(char *line) {
  char *prefix = malloc(512);
  char clone[512];
  strncpy(clone, line, strlen(line) + 1);
  if (line[0] == ':') {
    char *splitted = strtok(clone, " ");
    if (splitted != NULL) {
      strncpy(prefix, splitted + 1, strlen(splitted) + 1);
    } else {
      prefix[0] = '\0';
    }
  } else {
    prefix[0] = '\0';
  }
  return prefix;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_prefix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x200,%edi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  cmpb   $0x3a,(%rbx)
  je     L26
L29:
  movb   $0x0,(%r12)
L38:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x210,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L29
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  jmp    L38
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string

tool: D4:  

assistant: ```c
char *get_prefix(char *line) {
  char *prefix = malloc(512);
  char clone[512];
  strncpy(clone, line, strlen(line) + 1);
  if (line[0] == ':') {
    char *splitted = strtok(clone, " ");
    if (splitted != NULL) {
      strncpy(prefix, splitted + 1, strlen(splitted) + 1);
    } else {
      prefix[0] = '\0';
    }
  } else {
    prefix[0] = '\0';
  }
  return prefix;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yyerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: Exiting with -1 status

assistant: ```c
void yyerror(s) char *s;
{
  printf("%s\n", s);
  printf("Exiting with -1 status\n");
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yyerror>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: Exiting with -1 status

assistant: ```c
void yyerror(s) char *s;
{
  printf("%s\n", s);
  printf("Exiting with -1 status\n");
  exit(-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<yyerror>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: Exiting with -1 status

assistant: ```c
void yyerror(s) char *s;
{
  printf("%s\n", s);
  printf("Exiting with -1 status\n");
  exit(-1);
}
```