ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_user>:
  endbr64
  push   %r13
  mov    %rdx,%rdi
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  call   <strlen@plt>
  lea    0x2(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D5(%rip),%rdx
  mov    %rbp,%rdi
  lea    0x2(%rax),%rsi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <send_msg@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: u%s

assistant: ```c
int send_user(void *room_data, void *user_data, const char *message) {
  char *nm = malloc(strlen(message) + 2);
  snprintf(nm, strlen(message) + 2, "u%s", message);
  send_msg((char *)user_data, nm);
  free(nm);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<send_user>:
  endbr64
  push   %r13
  mov    %rdx,%rdi
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  call   <strlen@plt>
  lea    0x2(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D3(%rip),%rdx
  mov    %rbp,%rdi
  lea    0x2(%rax),%rsi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <send_msg@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: u%s

assistant: ```c
int send_user(void *room_data, void *user_data, const char *message) {
  char *nm = malloc(strlen(message) + 2);
  snprintf(nm, strlen(message) + 2, "u%s", message);
  send_msg((char *)user_data, nm);
  free(nm);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  jmp    L6
L3:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int isError(int code) {
  if (code == -1) {
    return code;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isError>:
  endbr64
  cmp    $0xffffffff,%edi
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int isError(int code) {
  if (code == -1) {
    return code;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isError>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  sete   %al
  neg    %eax
  ret
```

assistant: ```c
int isError(int code) {
  if (code == -1) {
    return code;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isError>:
  endbr64
  xor    %eax,%eax
  cmp    $0xffffffff,%edi
  sete   %al
  neg    %eax
  ret
```

assistant: ```c
int isError(int code) {
  if (code == -1) {
    return code;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7ec(%rbp)
  movl   $0x0,-0x7e8(%rbp)
L21:
  lea    -0x7f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x7f0(%rbp),%eax
  test   %eax,%eax
  jg     L25
  mov    -0x7f0(%rbp),%eax
  cmp    $0x1f4,%eax
  jg     L21
L25:
  movl   $0x0,-0x7e4(%rbp)
  jmp    L5
L6:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e4(%rbp)
L5:
  mov    -0x7f0(%rbp),%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L6
  mov    -0x7f0(%rbp),%esi
  lea    -0x7e8(%rbp),%rcx
  lea    -0x7ec(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D16: %d

assistant: ```c
int main() {
  int arr[500];
  int number_of_elem, count, min = 0, max = 0;
  do {
    scanf("%d", &number_of_elem);
  } while (number_of_elem < 1 && number_of_elem > 500);
  for (count = 0; count < number_of_elem; count++)
    scanf("%d", &arr[count]);
  minmax(arr, number_of_elem, &min, &max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L13
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D15(%rip),%r12
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L0
L13:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D15: %d

assistant: ```c
int main() {
  int arr[500];
  int number_of_elem, count, min = 0, max = 0;
  do {
    scanf("%d", &number_of_elem);
  } while (number_of_elem < 1 && number_of_elem > 500);
  for (count = 0; count < number_of_elem; count++)
    scanf("%d", &arr[count]);
  minmax(arr, number_of_elem, &min, &max);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L13
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L29
L13:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main() {
  int arr[500];
  int number_of_elem, count, min = 0, max = 0;
  do {
    scanf("%d", &number_of_elem);
  } while (number_of_elem < 1 && number_of_elem > 500);
  for (count = 0; count < number_of_elem; count++)
    scanf("%d", &arr[count]);
  minmax(arr, number_of_elem, &min, &max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L15
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L3
L15:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d

assistant: ```c
int main() {
  int arr[500];
  int number_of_elem, count, min = 0, max = 0;
  do {
    scanf("%d", &number_of_elem);
  } while (number_of_elem < 1 && number_of_elem > 500);
  for (count = 0; count < number_of_elem; count++)
    scanf("%d", &arr[count]);
  minmax(arr, number_of_elem, &min, &max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%edi
  call   <queuea_create@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L46
  mov    $0xffffffff,%eax
  jmp    L17
L46:
  movl   $0x1,-0xc(%rbp)
  jmp    L20
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L23
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queuea_dequeue@plt>
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
L23:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <queuea_enqueue@plt>
L3:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <queuea_destroy@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D12: -

tool: D19: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  struct queuea *queuea;
  queuea = queuea_create(0);
  if (queuea == NULL) {
    return -1;
  }
  for (i = 1; i < argc; i++) {
    if (strcmp(argv[i], "-") == 0) {
      printf("%s ", (char *)queuea_dequeue(queuea));
    } else {
      queuea_enqueue(queuea, argv[i]);
    }
  }
  queuea_destroy(queuea);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x0,%edi
  call   <queuea_create@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rbp
  cmp    $0x1,%r12d
  jle    L42
  lea    0x8(%r13),%rbx
  lea    -0x2(%r12),%eax
  lea    0x10(%r13,%rax,8),%r13
  lea    D19(%rip),%r12
  lea    D2(%rip),%r14
  jmp    L59
L63:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <queuea_enqueue@plt>
L51:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L42
L59:
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L63
  mov    %rbp,%rdi
  call   <queuea_dequeue@plt>
  mov    %rax,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L51
L42:
  mov    %rbp,%rdi
  call   <queuea_destroy@plt>
  mov    $0x0,%eax
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L58
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D19: -

tool: D2: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  struct queuea *queuea;
  queuea = queuea_create(0);
  if (queuea == NULL) {
    return -1;
  }
  for (i = 1; i < argc; i++) {
    if (strcmp(argv[i], "-") == 0) {
      printf("%s ", (char *)queuea_dequeue(queuea));
    } else {
      queuea_enqueue(queuea, argv[i]);
    }
  }
  queuea_destroy(queuea);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  call   <queuea_create@plt>
  test   %rax,%rax
  je     L52
  mov    %rax,%rbp
  cmp    $0x1,%r12d
  jle    L32
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    D5(%rip),%r12
  lea    0x10(%r13,%rax,8),%r13
  lea    D6(%rip),%r14
  jmp    L48
  nopl   (%rax)
L42:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <queuea_dequeue@plt>
  mov    %r14,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L32
L48:
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L42
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <queuea_enqueue@plt>
  cmp    %r13,%rbx
  jne    L48
L32:
  mov    %rbp,%rdi
  call   <queuea_destroy@plt>
  xor    %eax,%eax
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  or     $0xffffffff,%eax
  jmp    L55
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D5: -

tool: D6: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  struct queuea *queuea;
  queuea = queuea_create(0);
  if (queuea == NULL) {
    return -1;
  }
  for (i = 1; i < argc; i++) {
    if (strcmp(argv[i], "-") == 0) {
      printf("%s ", (char *)queuea_dequeue(queuea));
    } else {
      queuea_enqueue(queuea, argv[i]);
    }
  }
  queuea_destroy(queuea);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  call   <queuea_create@plt>
  test   %rax,%rax
  je     L44
  mov    %rax,%rbp
  cmp    $0x1,%r12d
  jle    L0
  lea    -0x2(%r12),%eax
  lea    0x8(%r13),%rbx
  lea    D5(%rip),%r12
  lea    0x10(%r13,%rax,8),%r13
  lea    D18(%rip),%r14
  jmp    L2
  nopl   (%rax)
L57:
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <queuea_dequeue@plt>
  mov    %r14,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L0
L2:
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <queuea_enqueue@plt>
  cmp    %r13,%rbx
  jne    L2
L0:
  mov    %rbp,%rdi
  call   <queuea_destroy@plt>
  xor    %eax,%eax
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  or     $0xffffffff,%eax
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D5: -

tool: D18: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  struct queuea *queuea;
  queuea = queuea_create(0);
  if (queuea == NULL) {
    return -1;
  }
  for (i = 1; i < argc; i++) {
    if (strcmp(argv[i], "-") == 0) {
      printf("%s ", (char *)queuea_dequeue(queuea));
    } else {
      queuea_enqueue(queuea, argv[i]);
    }
  }
  queuea_destroy(queuea);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<____build_time_check_for_reserved_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ____build_time_check_for_reserved_bits(void) {
  (void)(sizeof(int[(((((1ULL << 0) | (1ULL << 1) | (1ULL << 2) | (1ULL << 3) | (1ULL << 4) | (1ULL << 5) | (1ULL << 6) | (1ULL << 7) | (1ULL << 8) | (1ULL << 9) | (1ULL << 10) | (1ULL << 11) | (1ULL << 12) | (1ULL << 13) | (1ULL << 14) | (1ULL << 16) | (1ULL << 15) | (1ULL << 17) | (1ULL << 18) | (1ULL << 19) | (1ULL << 20) | (1ULL << 21) | (1ULL << 22) | (1ULL << 23) | (1ULL << 24) | (1ULL << 25) | (1ULL << 26) | (1ULL << 27) | (1ULL << 28) | (1ULL << 29) | (1ULL << 30) | (1ULL << 31) | (1ULL << 32) | (1ULL << 33) | (1ULL << 34) | (1ULL << 35) | (1ULL << 36) | (1ULL << 37) | (1ULL << 38) | (1ULL << 39) | (1ULL << 40) | (1ULL << 41) | (1ULL << 41) | (1ULL << 42) | (1ULL << 43) | (1ULL << 44) | (1ULL << 45) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 47) | (1ULL << 48) | (1ULL << 49) | (1ULL << 50) | (1ULL << 51) | (1ULL << 53) | (1ULL << 52) | (1ULL << 54) | (1ULL << 55) | 0ULL) &
                       ((1ULL << 62) | (1ULL << 61) | (1ULL << 63))) == 0) == 0)
                        ? -1
                        : 0]));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<____build_time_check_for_reserved_bits>:
  endbr64
  ret
```

assistant: ```c
void ____build_time_check_for_reserved_bits(void) {
  (void)(sizeof(int[(((((1ULL << 0) | (1ULL << 1) | (1ULL << 2) | (1ULL << 3) | (1ULL << 4) | (1ULL << 5) | (1ULL << 6) | (1ULL << 7) | (1ULL << 8) | (1ULL << 9) | (1ULL << 10) | (1ULL << 11) | (1ULL << 12) | (1ULL << 13) | (1ULL << 14) | (1ULL << 16) | (1ULL << 15) | (1ULL << 17) | (1ULL << 18) | (1ULL << 19) | (1ULL << 20) | (1ULL << 21) | (1ULL << 22) | (1ULL << 23) | (1ULL << 24) | (1ULL << 25) | (1ULL << 26) | (1ULL << 27) | (1ULL << 28) | (1ULL << 29) | (1ULL << 30) | (1ULL << 31) | (1ULL << 32) | (1ULL << 33) | (1ULL << 34) | (1ULL << 35) | (1ULL << 36) | (1ULL << 37) | (1ULL << 38) | (1ULL << 39) | (1ULL << 40) | (1ULL << 41) | (1ULL << 41) | (1ULL << 42) | (1ULL << 43) | (1ULL << 44) | (1ULL << 45) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 47) | (1ULL << 48) | (1ULL << 49) | (1ULL << 50) | (1ULL << 51) | (1ULL << 53) | (1ULL << 52) | (1ULL << 54) | (1ULL << 55) | 0ULL) &
                       ((1ULL << 62) | (1ULL << 61) | (1ULL << 63))) == 0) == 0)
                        ? -1
                        : 0]));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<____build_time_check_for_reserved_bits>:
  endbr64
  ret
```

assistant: ```c
void ____build_time_check_for_reserved_bits(void) {
  (void)(sizeof(int[(((((1ULL << 0) | (1ULL << 1) | (1ULL << 2) | (1ULL << 3) | (1ULL << 4) | (1ULL << 5) | (1ULL << 6) | (1ULL << 7) | (1ULL << 8) | (1ULL << 9) | (1ULL << 10) | (1ULL << 11) | (1ULL << 12) | (1ULL << 13) | (1ULL << 14) | (1ULL << 16) | (1ULL << 15) | (1ULL << 17) | (1ULL << 18) | (1ULL << 19) | (1ULL << 20) | (1ULL << 21) | (1ULL << 22) | (1ULL << 23) | (1ULL << 24) | (1ULL << 25) | (1ULL << 26) | (1ULL << 27) | (1ULL << 28) | (1ULL << 29) | (1ULL << 30) | (1ULL << 31) | (1ULL << 32) | (1ULL << 33) | (1ULL << 34) | (1ULL << 35) | (1ULL << 36) | (1ULL << 37) | (1ULL << 38) | (1ULL << 39) | (1ULL << 40) | (1ULL << 41) | (1ULL << 41) | (1ULL << 42) | (1ULL << 43) | (1ULL << 44) | (1ULL << 45) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 47) | (1ULL << 48) | (1ULL << 49) | (1ULL << 50) | (1ULL << 51) | (1ULL << 53) | (1ULL << 52) | (1ULL << 54) | (1ULL << 55) | 0ULL) &
                       ((1ULL << 62) | (1ULL << 61) | (1ULL << 63))) == 0) == 0)
                        ? -1
                        : 0]));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<____build_time_check_for_reserved_bits>:
  endbr64
  ret
```

assistant: ```c
void ____build_time_check_for_reserved_bits(void) {
  (void)(sizeof(int[(((((1ULL << 0) | (1ULL << 1) | (1ULL << 2) | (1ULL << 3) | (1ULL << 4) | (1ULL << 5) | (1ULL << 6) | (1ULL << 7) | (1ULL << 8) | (1ULL << 9) | (1ULL << 10) | (1ULL << 11) | (1ULL << 12) | (1ULL << 13) | (1ULL << 14) | (1ULL << 16) | (1ULL << 15) | (1ULL << 17) | (1ULL << 18) | (1ULL << 19) | (1ULL << 20) | (1ULL << 21) | (1ULL << 22) | (1ULL << 23) | (1ULL << 24) | (1ULL << 25) | (1ULL << 26) | (1ULL << 27) | (1ULL << 28) | (1ULL << 29) | (1ULL << 30) | (1ULL << 31) | (1ULL << 32) | (1ULL << 33) | (1ULL << 34) | (1ULL << 35) | (1ULL << 36) | (1ULL << 37) | (1ULL << 38) | (1ULL << 39) | (1ULL << 40) | (1ULL << 41) | (1ULL << 41) | (1ULL << 42) | (1ULL << 43) | (1ULL << 44) | (1ULL << 45) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 46) | (1ULL << 47) | (1ULL << 48) | (1ULL << 49) | (1ULL << 50) | (1ULL << 51) | (1ULL << 53) | (1ULL << 52) | (1ULL << 54) | (1ULL << 55) | 0ULL) &
                       ((1ULL << 62) | (1ULL << 61) | (1ULL << 63))) == 0) == 0)
                        ? -1
                        : 0]));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DoCountTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %rdx,-0x238(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x210(%rbp)
  movq   $0x0,-0x208(%rbp)
  lea    -0x200(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0xffffffff,-0x214(%rbp)
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <_countof@plt>
  mov    %eax,%esi
  lea    -0x214(%rbp),%rcx
  mov    -0x228(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <sprintf_s@plt>
  mov    -0x214(%rbp),%eax
  cmp    %eax,-0x22c(%rbp)
  je     L4
  mov    -0x214(%rbp),%edx
  mov    -0x22c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
L4:
  mov    -0x238(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x238(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L19
  lea    -0x210(%rbp),%rdx
  mov    -0x238(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D0: ERROR: Expected count parameter to resolve to %d, got %X


tool: D1: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoCountTest(const char *formatstr, int param, const char *checkstr) {
  char buf[512] = {0};
  int n = -1;
  sprintf_s(buf, _countof(buf), formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<DoCountTest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x3e,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0xffffffff,0xc(%rsp)
  lea    0x10(%rsp),%r13
  mov    %r13,%rdi
  call   <_countof@plt>
  mov    %eax,%esi
  lea    0xc(%rsp),%rcx
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <sprintf_s@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebp,%edx
  jne    L28
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L6
L36:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
  jmp    L18
L6:
  lea    0x10(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <Fail@plt>
  jmp    L36
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D7
type: string

tool: D15: ERROR: Expected count parameter to resolve to %d, got %X


tool: D7: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoCountTest(const char *formatstr, int param, const char *checkstr) {
  char buf[512] = {0};
  int n = -1;
  sprintf_s(buf, _countof(buf), formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```