ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readNextBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  sub    -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x50(%rbp),%eax
  sub    -0x4c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L30:
  mov    -0x60(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0xffffffff,-0x2c(%rbp)
  je     L14
  mov    -0x28(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x58(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
L14:
  addl   $0x1,-0x34(%rbp)
L7:
  mov    -0x34(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L30
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void readNextBlock(int i0, int i1, int j0, int j1, double *mat, FILE *store) {
  int i;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  int size = (i1 - i0) * (j1 - j0);
  for (i = 0; i < size; i++) {
    if ((read = getline(&line, &len, store)) != -1) {
      mat[i] = atof(line);
    }
  }
  free(line);
}
```
user: Translate the below assembly code into C programming language:

```asm
<readNextBlock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  sub    %edi,%esi
  sub    %edx,%ecx
  imul   %ecx,%esi
  test   %esi,%esi
  jle    L25
  mov    %r9,%rbp
  mov    %r8,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%r8,%rax,8),%r13
  lea    0x10(%rsp),%r12
  jmp    L41
L30:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L25
L41:
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L30
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  movsd  %xmm0,(%rbx)
  jmp    L30
L25:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void readNextBlock(int i0, int i1, int j0, int j1, double *mat, FILE *store) {
  int i;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  int size = (i1 - i0) * (j1 - j0);
  for (i = 0; i < size; i++) {
    if ((read = getline(&line, &len, store)) != -1) {
      mat[i] = atof(line);
    }
  }
  free(line);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readNextBlock>:
  endbr64
  push   %r14
  sub    %edi,%esi
  sub    %edx,%ecx
  push   %r13
  imul   %ecx,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  test   %esi,%esi
  jle    L30
  lea    -0x1(%rsi),%eax
  mov    %r9,%rbp
  lea    0x10(%rsp),%r13
  mov    %r8,%rbx
  lea    0x8(%r8,%rax,8),%r14
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L19:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L4
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  movsd  %xmm0,(%rbx)
L4:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L19
  mov    0x8(%rsp),%rdi
L25:
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L30:
  xor    %edi,%edi
  jmp    L25
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void readNextBlock(int i0, int i1, int j0, int j1, double *mat, FILE *store) {
  int i;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  int size = (i1 - i0) * (j1 - j0);
  for (i = 0; i < size; i++) {
    if ((read = getline(&line, &len, store)) != -1) {
      mat[i] = atof(line);
    }
  }
  free(line);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readNextBlock>:
  endbr64
  push   %r14
  sub    %edi,%esi
  sub    %edx,%ecx
  push   %r13
  imul   %ecx,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  mov    %r9,%rbp
  lea    0x10(%rsp),%r13
  mov    %r8,%rbx
  lea    0x8(%r8,%rax,8),%r14
  lea    0x8(%rsp),%r12
  nopl   (%rax)
L9:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <getline@plt>
  cmp    $0xffffffff,%eax
  je     L40
  mov    0x8(%rsp),%rdi
  call   <atof@plt>
  movsd  %xmm0,(%rbx)
L40:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L9
  mov    0x8(%rsp),%rdi
L35:
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L16:
  xor    %edi,%edi
  jmp    L35
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void readNextBlock(int i0, int i1, int j0, int j1, double *mat, FILE *store) {
  int i;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  int size = (i1 - i0) * (j1 - j0);
  for (i = 0; i < size; i++) {
    if ((read = getline(&line, &len, store)) != -1) {
      mat[i] = atof(line);
    }
  }
  free(line);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0xa98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    $0x2625a00,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r14,%rdi
  call   <generate_samples@plt>
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x61a80(%rsp),%r13
  mov    %rbx,%rbp
L1:
  mov    %rbp,%rdi
  call   <omp_init_lock@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L1
  mov    %r14,%rbp
  add    $0x2625a00,%r14
  mov    %rsp,%r15
L12:
  movslq 0x0(%rbp),%rax
  lea    (%r15,%rax,4),%r12
  mov    %r12,%rdi
  call   <omp_set_lock@plt>
  mov    %r12,%rdi
  call   <omp_unset_lock@plt>
  add    $0x4,%rbp
  cmp    %r14,%rbp
  jne    L12
L48:
  mov    %rbx,%rdi
  call   <omp_destroy_lock@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L48
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x61a98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: [%d] Total threads: %d


assistant: ```c
int main(void) {
  omp_lock_t hist_locks[100000];
  int hist[100000];
  int *samples;
  int i, ival;
  samples = (int *)malloc(sizeof(int) * 10000000);
  assert(samples != NULL);
  generate_samples(samples);
#pragma omp parallel
  {
    printf("[%d] Total threads: %d\n", omp_get_thread_num(), omp_get_num_threads());
#pragma omp for
    for (i = 0; i < 100000; ++i) {
      omp_init_lock(&hist_locks[i]);
      hist[i] = 0;
    }
  }
#pragma omp parallel for private(ival)
  for (i = 0; i < 10000000; ++i) {
    ival = samples[i];
    omp_set_lock(&hist_locks[ival]);
    hist[ival]++;
    omp_unset_lock(&hist_locks[ival]);
  }
#pragma omp parallel for
  for (i = 0; i < 100000; ++i) {
    omp_destroy_lock(&hist_locks[i]);
  }
  if (0) {
    printf("Histogram:\n");
    for (i = 0; i < 100000; ++i) {
      printf("%d ---> %d\n", i, hist[i]);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0xa98,%rsp
  mov    $0x2625a00,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x61a80(%rsp),%r13
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %r14,%rbp
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <generate_samples@plt>
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %r14,%r12
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L9:
  mov    %r12,%rdi
  add    $0x4,%r12
  call   <omp_init_lock@plt>
  cmp    %r13,%r12
  jne    L9
  lea    0x2625a00(%rbx),%r15
  nopl   0x0(%rax,%rax,1)
L3:
  movslq (%rbx),%rax
  add    $0x4,%rbx
  lea    (%r14,%rax,4),%r12
  mov    %r12,%rdi
  call   <omp_set_lock@plt>
  mov    %r12,%rdi
  call   <omp_unset_lock@plt>
  cmp    %r15,%rbx
  jne    L3
L31:
  mov    %rbp,%rdi
  add    $0x4,%rbp
  call   <omp_destroy_lock@plt>
  cmp    %r13,%rbp
  jne    L31
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x61a98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: [%d] Total threads: %d


assistant: ```c
int main(void) {
  omp_lock_t hist_locks[100000];
  int hist[100000];
  int *samples;
  int i, ival;
  samples = (int *)malloc(sizeof(int) * 10000000);
  assert(samples != NULL);
  generate_samples(samples);
#pragma omp parallel
  {
    printf("[%d] Total threads: %d\n", omp_get_thread_num(), omp_get_num_threads());
#pragma omp for
    for (i = 0; i < 100000; ++i) {
      omp_init_lock(&hist_locks[i]);
      hist[i] = 0;
    }
  }
#pragma omp parallel for private(ival)
  for (i = 0; i < 10000000; ++i) {
    ival = samples[i];
    omp_set_lock(&hist_locks[ival]);
    hist[ival]++;
    omp_unset_lock(&hist_locks[ival]);
  }
#pragma omp parallel for
  for (i = 0; i < 100000; ++i) {
    omp_destroy_lock(&hist_locks[i]);
  }
  if (0) {
    printf("Histogram:\n");
    for (i = 0; i < 100000; ++i) {
      printf("%d ---> %d\n", i, hist[i]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0xa98,%rsp
  mov    $0x2625a00,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x61a88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x61a80(%rsp),%r13
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %r14,%rbp
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <generate_samples@plt>
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %r12d,%edx
  lea    D2(%rip),%rdi
  mov    %r14,%r12
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  add    $0x4,%r12
  call   <omp_init_lock@plt>
  cmp    %r12,%r13
  jne    L4
  lea    0x2625a00(%rbx),%r15
  nopl   0x0(%rax,%rax,1)
L31:
  movslq (%rbx),%rax
  add    $0x4,%rbx
  lea    (%r14,%rax,4),%r12
  mov    %r12,%rdi
  call   <omp_set_lock@plt>
  mov    %r12,%rdi
  call   <omp_unset_lock@plt>
  cmp    %rbx,%r15
  jne    L31
L38:
  mov    %rbp,%rdi
  add    $0x4,%rbp
  call   <omp_destroy_lock@plt>
  cmp    %rbp,%r13
  jne    L38
  mov    0x61a88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x61a98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: [%d] Total threads: %d


assistant: ```c
int main(void) {
  omp_lock_t hist_locks[100000];
  int hist[100000];
  int *samples;
  int i, ival;
  samples = (int *)malloc(sizeof(int) * 10000000);
  assert(samples != NULL);
  generate_samples(samples);
#pragma omp parallel
  {
    printf("[%d] Total threads: %d\n", omp_get_thread_num(), omp_get_num_threads());
#pragma omp for
    for (i = 0; i < 100000; ++i) {
      omp_init_lock(&hist_locks[i]);
      hist[i] = 0;
    }
  }
#pragma omp parallel for private(ival)
  for (i = 0; i < 10000000; ++i) {
    ival = samples[i];
    omp_set_lock(&hist_locks[ival]);
    hist[ival]++;
    omp_unset_lock(&hist_locks[ival]);
  }
#pragma omp parallel for
  for (i = 0; i < 100000; ++i) {
    omp_destroy_lock(&hist_locks[i]);
  }
  if (0) {
    printf("Histogram:\n");
    for (i = 0; i < 100000; ++i) {
      printf("%d ---> %d\n", i, hist[i]);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <LinkedList_test@plt>
  mov    $0x0,%eax
  call   <DoubleLinkedList_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  LinkedList_test();
  DoubleLinkedList_test();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <LinkedList_test@plt>
  mov    $0x0,%eax
  call   <DoubleLinkedList_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  LinkedList_test();
  DoubleLinkedList_test();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <LinkedList_test@plt>
  xor    %eax,%eax
  call   <DoubleLinkedList_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  LinkedList_test();
  DoubleLinkedList_test();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <LinkedList_test@plt>
  xor    %eax,%eax
  call   <DoubleLinkedList_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  LinkedList_test();
  DoubleLinkedList_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_segment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L11
L49:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L33
  cmpq   $0x1,-0x20(%rbp)
  jbe    L29
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L29
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L27
L29:
  mov    $0xffffffff,%eax
  jmp    L47
L27:
  addq   $0x2,-0x18(%rbp)
  subq   $0x2,-0x20(%rbp)
L33:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x20(%rbp)
L11:
  cmpq   $0x0,-0x20(%rbp)
  jne    L49
  mov    -0x8(%rbp),%rax
L47:
  leave
  ret
```

assistant: ```c
int check_segment(const unsigned char *s, size_t length) {
  size_t n = 0;
  while (length) {
    if (*s == '%') {
      if (length < 2 || !(isxdigit(s[1]) && isxdigit(s[2])))
        return -1;
      s += 2;
      length -= 2;
    }
    ++s;
    ++n;
    --length;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_segment>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  jmp    L108
L14:
  add    $0x1,%rbx
  add    $0x1,%r12
  sub    $0x1,%rbp
  je     L75
L108:
  cmpb   $0x25,(%rbx)
  jne    L14
  cmp    $0x1,%rbp
  jbe    L45
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L109
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L86
  add    $0x2,%rbx
  sub    $0x2,%rbp
  jmp    L14
L3:
  mov    %rsi,%r12
L75:
  mov    %r12d,%eax
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    $0xffffffff,%eax
  jmp    L57
L109:
  mov    $0xffffffff,%eax
  jmp    L57
L86:
  mov    $0xffffffff,%eax
  jmp    L57
```

assistant: ```c
int check_segment(const unsigned char *s, size_t length) {
  size_t n = 0;
  while (length) {
    if (*s == '%') {
      if (length < 2 || !(isxdigit(s[1]) && isxdigit(s[2])))
        return -1;
      s += 2;
      length -= 2;
    }
    ++s;
    ++n;
    --length;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_segment>:
  endbr64
  test   %rsi,%rsi
  je     L7
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L63:
  add    $0x1,%rbx
  add    $0x1,%r12
  sub    $0x1,%rbp
  je     L66
L20:
  cmpb   $0x25,(%rbx)
  jne    L63
  cmp    $0x1,%rbp
  je     L54
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L54
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L54
  add    $0x2,%rbx
  sub    $0x2,%rbp
  add    $0x1,%r12
  add    $0x1,%rbx
  sub    $0x1,%rbp
  jne    L20
L66:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_segment(const unsigned char *s, size_t length) {
  size_t n = 0;
  while (length) {
    if (*s == '%') {
      if (length < 2 || !(isxdigit(s[1]) && isxdigit(s[2])))
        return -1;
      s += 2;
      length -= 2;
    }
    ++s;
    ++n;
    --length;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_segment>:
  endbr64
  test   %rsi,%rsi
  je     L31
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x1,%rbx
  add    $0x1,%r12
  sub    $0x1,%rbp
  je     L28
L44:
  cmpb   $0x25,(%rbx)
  jne    L48
  cmp    $0x1,%rbp
  je     L3
  movzbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L3
  movzbl 0x2(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L3
  add    $0x2,%rbx
  sub    $0x2,%rbp
  add    $0x1,%r12
  add    $0x1,%rbx
  sub    $0x1,%rbp
  jne    L44
L28:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_segment(const unsigned char *s, size_t length) {
  size_t n = 0;
  while (length) {
    if (*s == '%') {
      if (length < 2 || !(isxdigit(s[1]) && isxdigit(s[2])))
        return -1;
      s += 2;
      length -= 2;
    }
    ++s;
    ++n;
    --length;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  cmp    $0xffffffff,%eax
  jne    L24
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xff,%edi
  call   <exit@plt>
L24:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strstr@plt>
  test   %rax,%rax
  je     L37
  lea    D36(%rip),%rax
  mov    %rax,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  jmp    L45
L2:
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execv@plt>
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: string

tool: D28: uname

tool: D9: 32

tool: D36: 64

assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname sys_uname;
  char *newprog;
  const char *suffix = 0;
  if (-1 == uname(&sys_uname)) {
    perror("uname");
    exit(255);
  }
  newprog = malloc(strlen(argv[0]) + 3);
  strcpy(newprog, argv[0]);
  suffix = "32";
  if ((char *)0 != strstr(sys_uname.machine, "64"))
    suffix = "64";
  strcat(newprog, suffix);
  if ((char *)0 == strchr(newprog, '/')) {
    return execvp(newprog, argv);
  } else {
    return execv(newprog, argv);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <uname@plt>
  cmp    $0xffffffff,%eax
  je     L32
L38:
  mov    0x0(%rbp),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x3(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D35(%rip),%rsi
  mov    0x4(%rsp),%edi
  call   <strstr@plt>
  test   %rax,%rax
  lea    D31(%rip),%rsi
  lea    D35(%rip),%rax
  cmovne %rax,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <execv@plt>
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  lea    D19(%rip),%rdi
  call   <perror@plt>
  mov    $0xff,%edi
  call   <exit@plt>
  jmp    L38
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <execvp@plt>
  jmp    L47
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D31
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D35: 64

tool: D31: 32

tool: D19: uname

assistant: ```c
int main(int argc, char *argv[]) {
  struct utsname sys_uname;
  char *newprog;
  const char *suffix = 0;
  if (-1 == uname(&sys_uname)) {
    perror("uname");
    exit(255);
  }
  newprog = malloc(strlen(argv[0]) + 3);
  strcpy(newprog, argv[0]);
  suffix = "32";
  if ((char *)0 != strstr(sys_uname.machine, "64"))
    suffix = "64";
  strcat(newprog, suffix);
  if ((char *)0 == strchr(newprog, '/')) {
    return execvp(newprog, argv);
  } else {
    return execv(newprog, argv);
  }
}
```