ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<Rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x23,-0x4(%rbp)
  jmp    L55
L26:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L55:
  cmpl   $0x17,-0x4(%rbp)
  jg     L26
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x58,%rax
  mov    (%rax),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x5c,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x54,%rax
  mov    (%rax),%eax
  and    $0x80,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x58,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  movl   $0x15,-0x4(%rbp)
  jmp    L52
L56:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L52:
  cmpl   $0xc,-0x4(%rbp)
  jg     L56
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x18(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%eax
  and    $0x7,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%eax
  and    $0xf8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x5,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2c,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  movl   $0xa,-0x4(%rbp)
  jmp    L37
L41:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x0,-0x4(%rbp)
  jg     L41
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Rotate(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3) {
  uint8_t i;
  for (i = 35; i > 23; i--) {
    state[i] = state[i - 1];
  }
  state[23] = (*t2 << 7) ^ (state[22] & 0x7F);
  state[22] = (state[21] & 0x80) ^ (*t2 >> 1);
  for (i = 21; i > 12; i--) {
    state[i] = state[i - 1];
  }
  state[12] = (*t1 << 3) ^ (state[11] & 0x07);
  state[11] = (state[10] & 0xF8) ^ (*t1 >> 5);
  for (i = 10; i > 0; i--) {
    state[i] = state[i - 1];
  }
  state[0] = *t3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Rotate>:
  endbr64
  mov    %rsi,%r9
  mov    %rcx,%r8
  lea    0x88(%rdi),%rax
  lea    0x58(%rdi),%rsi
L4:
  mov    (%rax),%ecx
  mov    %ecx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L4
  mov    (%rdx),%eax
  shl    $0x7,%eax
  mov    0x58(%rdi),%ecx
  and    $0x7f,%ecx
  xor    %ecx,%eax
  mov    %eax,0x5c(%rdi)
  mov    0x54(%rdi),%eax
  and    $0x80,%eax
  mov    (%rdx),%edx
  sar    %edx
  xor    %edx,%eax
  mov    %eax,0x58(%rdi)
  lea    0x50(%rdi),%rax
  lea    0x2c(%rdi),%rcx
L9:
  mov    (%rax),%edx
  mov    %edx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
  mov    (%r9),%eax
  shl    $0x3,%eax
  mov    0x2c(%rdi),%edx
  and    $0x7,%edx
  xor    %edx,%eax
  mov    %eax,0x30(%rdi)
  mov    0x28(%rdi),%eax
  and    $0xf8,%eax
  mov    (%r9),%edx
  sar    $0x5,%edx
  xor    %edx,%eax
  mov    %eax,0x2c(%rdi)
  lea    0x24(%rdi),%rax
L2:
  mov    %rax,%rdx
  mov    (%rax),%ecx
  mov    %ecx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rdx
  jne    L2
  mov    (%r8),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void Rotate(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3) {
  uint8_t i;
  for (i = 35; i > 23; i--) {
    state[i] = state[i - 1];
  }
  state[23] = (*t2 << 7) ^ (state[22] & 0x7F);
  state[22] = (state[21] & 0x80) ^ (*t2 >> 1);
  for (i = 21; i > 12; i--) {
    state[i] = state[i - 1];
  }
  state[12] = (*t1 << 3) ^ (state[11] & 0x07);
  state[11] = (state[10] & 0xF8) ^ (*t1 >> 5);
  for (i = 10; i > 0; i--) {
    state[i] = state[i - 1];
  }
  state[0] = *t3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Rotate>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x30,%edx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x5c(%rdi),%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    0x60(%rdi),%rdi
  sub    $0x8,%rsp
  call   <memmove@plt>
  mov    0x0(%r13),%eax
  mov    0x58(%rbx),%edx
  lea    0x30(%rbx),%rsi
  lea    0x34(%rbx),%rdi
  and    $0x7f,%edx
  shl    $0x7,%eax
  xor    %edx,%eax
  mov    %eax,0x5c(%rbx)
  mov    0x54(%rbx),%eax
  mov    0x0(%r13),%edx
  and    $0x80,%eax
  sar    %edx
  xor    %edx,%eax
  mov    $0x24,%edx
  mov    %eax,0x58(%rbx)
  call   <memmove@plt>
  mov    0x0(%rbp),%eax
  mov    0x2c(%rbx),%edx
  lea    0x4(%rbx),%rdi
  mov    %rbx,%rsi
  and    $0x7,%edx
  shl    $0x3,%eax
  xor    %edx,%eax
  mov    %eax,0x30(%rbx)
  mov    0x28(%rbx),%eax
  mov    0x0(%rbp),%edx
  and    $0xf8,%eax
  sar    $0x5,%edx
  xor    %edx,%eax
  mov    $0x28,%edx
  mov    %eax,0x2c(%rbx)
  call   <memmove@plt>
  mov    (%r12),%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Rotate(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3) {
  uint8_t i;
  for (i = 35; i > 23; i--) {
    state[i] = state[i - 1];
  }
  state[23] = (*t2 << 7) ^ (state[22] & 0x7F);
  state[22] = (state[21] & 0x80) ^ (*t2 >> 1);
  for (i = 21; i > 12; i--) {
    state[i] = state[i - 1];
  }
  state[12] = (*t1 << 3) ^ (state[11] & 0x07);
  state[11] = (state[10] & 0xF8) ^ (*t1 >> 5);
  for (i = 10; i > 0; i--) {
    state[i] = state[i - 1];
  }
  state[0] = *t3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Rotate>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  mov    $0x30,%edx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    0x5c(%rdi),%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    0x60(%rdi),%rdi
  sub    $0x8,%rsp
  call   <memmove@plt>
  mov    0x0(%r13),%eax
  mov    0x58(%rbx),%edx
  lea    0x30(%rbx),%rsi
  lea    0x34(%rbx),%rdi
  and    $0x7f,%edx
  shl    $0x7,%eax
  xor    %edx,%eax
  mov    %eax,0x5c(%rbx)
  mov    0x54(%rbx),%eax
  mov    0x0(%r13),%edx
  and    $0x80,%eax
  sar    %edx
  xor    %edx,%eax
  mov    $0x24,%edx
  mov    %eax,0x58(%rbx)
  call   <memmove@plt>
  mov    0x0(%rbp),%eax
  mov    0x2c(%rbx),%edx
  lea    0x4(%rbx),%rdi
  mov    %rbx,%rsi
  and    $0x7,%edx
  shl    $0x3,%eax
  xor    %edx,%eax
  mov    %eax,0x30(%rbx)
  mov    0x28(%rbx),%eax
  mov    0x0(%rbp),%edx
  and    $0xf8,%eax
  sar    $0x5,%edx
  xor    %edx,%eax
  mov    $0x28,%edx
  mov    %eax,0x2c(%rbx)
  call   <memmove@plt>
  mov    (%r12),%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Rotate(uint8_t *state, uint8_t *t1, uint8_t *t2, uint8_t *t3) {
  uint8_t i;
  for (i = 35; i > 23; i--) {
    state[i] = state[i - 1];
  }
  state[23] = (*t2 << 7) ^ (state[22] & 0x7F);
  state[22] = (state[21] & 0x80) ^ (*t2 >> 1);
  for (i = 21; i > 12; i--) {
    state[i] = state[i - 1];
  }
  state[12] = (*t1 << 3) ^ (state[11] & 0x07);
  state[11] = (state[10] & 0xF8) ^ (*t1 >> 5);
  for (i = 10; i > 0; i--) {
    state[i] = state[i - 1];
  }
  state[0] = *t3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_dobldobl_homotopy_with_given_gamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xad,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int create_dobldobl_homotopy_with_given_gamma(double gamma_re, double gamma_im, int pwt) {
  int *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc(173, &pwt, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<create_dobldobl_homotopy_with_given_gamma>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0xad,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_dobldobl_homotopy_with_given_gamma(double gamma_re, double gamma_im, int pwt) {
  int *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc(173, &pwt, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<create_dobldobl_homotopy_with_given_gamma>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0xad,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_dobldobl_homotopy_with_given_gamma(double gamma_re, double gamma_im, int pwt) {
  int *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc(173, &pwt, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<create_dobldobl_homotopy_with_given_gamma>:
  endbr64
  sub    $0x38,%rsp
  unpcklpd %xmm1,%xmm0
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0xad,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_dobldobl_homotopy_with_given_gamma(double gamma_re, double gamma_im, int pwt) {
  int *b, fail;
  double c[2];
  c[0] = gamma_re;
  c[1] = gamma_im;
  fail = _ada_use_c2phc(173, &pwt, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_block_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L33:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L72
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_line@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L66
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L2
  cmpl   $0x0,-0x14(%rbp)
  jne    L56
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L46
L56:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
L46:
  addl   $0x1,-0x14(%rbp)
  jmp    L33
L66:
  nop
  jmp    L33
L72:
  nop
  jmp    L53
L2:
  nop
L53:
  cmpq   $0x0,-0x10(%rbp)
  je     L24
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **get_block_lines(FILE *fp, char *delimeter, int *num_line) {
  char *buffer = NULL;
  int count = 0;
  char **data = 0;
  data = (char **)malloc(sizeof(char *));
  while (1) {
    if (feof(fp))
      break;
    buffer = get_line(fp);
    if (buffer == NULL)
      continue;
    if (strstr(buffer, delimeter) != NULL)
      break;
    if (count == 0) {
      data[count] = buffer;
    } else {
      data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
      data[count] = buffer;
    }
    count++;
  }
  if (buffer != NULL) {
    data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
    data[count] = buffer;
    count++;
  }
  *num_line = (count - 1);
  return data;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_block_lines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L37
L61:
  lea    0x8(,%rbp,8),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rax
  mov    %rbx,(%r12,%rax,8)
L33:
  add    $0x1,%ebp
L37:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L22
  mov    %r13,%rdi
  call   <get_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L64
  test   %ebp,%ebp
  jne    L61
  mov    %rbx,(%r12)
  jmp    L33
L22:
  test   %rbx,%rbx
  je     L20
L64:
  lea    0x1(%rbp),%r13d
  lea    0x0(,%r13,8),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  movslq %ebp,%rbp
  mov    %rbx,(%rax,%rbp,8)
  mov    %r13d,%ebp
L20:
  sub    $0x1,%ebp
  mov    %ebp,(%r14)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_block_lines(FILE *fp, char *delimeter, int *num_line) {
  char *buffer = NULL;
  int count = 0;
  char **data = 0;
  data = (char **)malloc(sizeof(char *));
  while (1) {
    if (feof(fp))
      break;
    buffer = get_line(fp);
    if (buffer == NULL)
      continue;
    if (strstr(buffer, delimeter) != NULL)
      break;
    if (count == 0) {
      data[count] = buffer;
    } else {
      data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
      data[count] = buffer;
    }
    count++;
  }
  if (buffer != NULL) {
    data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
    data[count] = buffer;
    count++;
  }
  *num_line = (count - 1);
  return data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_block_lines>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x8,%edi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L74
L1:
  mov    %rbx,(%r12)
L20:
  add    $0x1,%rbp
L74:
  mov    %ebp,0x4(%rsp)
  mov    %ebp,%r14d
L14:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L23
  mov    %r13,%rdi
  call   <get_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L51
  test   %rbp,%rbp
  je     L1
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  mov    %rbx,(%rax,%rbp,8)
  mov    %rax,%r12
  jmp    L20
  nopl   (%rax)
L23:
  test   %rbx,%rbx
  jne    L51
  sub    $0x1,%r14d
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %r12,%rdi
  lea    0x8(,%r14,8),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  movslq %r14d,%rax
  mov    %rbx,(%r12,%rax,8)
L48:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_block_lines(FILE *fp, char *delimeter, int *num_line) {
  char *buffer = NULL;
  int count = 0;
  char **data = 0;
  data = (char **)malloc(sizeof(char *));
  while (1) {
    if (feof(fp))
      break;
    buffer = get_line(fp);
    if (buffer == NULL)
      continue;
    if (strstr(buffer, delimeter) != NULL)
      break;
    if (count == 0) {
      data[count] = buffer;
    } else {
      data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
      data[count] = buffer;
    }
    count++;
  }
  if (buffer != NULL) {
    data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
    data[count] = buffer;
    count++;
  }
  *num_line = (count - 1);
  return data;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_block_lines>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x8,%edi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L46
L35:
  mov    %rbx,(%r12)
L32:
  add    $0x1,%rbp
L46:
  mov    %ebp,0x4(%rsp)
  mov    %ebp,%r14d
L0:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L64
  mov    %r13,%rdi
  call   <get_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L55
  test   %rbp,%rbp
  je     L35
  mov    0x4(%rsp),%eax
  mov    %r12,%rdi
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  mov    %rbx,(%rax,%rbp,8)
  mov    %rax,%r12
  jmp    L32
  nopl   (%rax)
L64:
  test   %rbx,%rbx
  jne    L55
  sub    $0x1,%r14d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %r12,%rdi
  lea    0x8(,%r14,8),%esi
  call   <realloc@plt>
  mov    %rax,%r12
  movslq %r14d,%rax
  mov    %rbx,(%r12,%rax,8)
L3:
  mov    0x8(%rsp),%rax
  mov    %r14d,(%rax)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_block_lines(FILE *fp, char *delimeter, int *num_line) {
  char *buffer = NULL;
  int count = 0;
  char **data = 0;
  data = (char **)malloc(sizeof(char *));
  while (1) {
    if (feof(fp))
      break;
    buffer = get_line(fp);
    if (buffer == NULL)
      continue;
    if (strstr(buffer, delimeter) != NULL)
      break;
    if (count == 0) {
      data[count] = buffer;
    } else {
      data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
      data[count] = buffer;
    }
    count++;
  }
  if (buffer != NULL) {
    data = (char **)realloc(data, (sizeof(char *) * (count + 1)));
    data[count] = buffer;
    count++;
  }
  *num_line = (count - 1);
  return data;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<distPtSeg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movss  %xmm2,-0x2c(%rbp)
  movss  %xmm3,-0x30(%rbp)
  movss  %xmm4,-0x34(%rbp)
  movss  %xmm5,-0x38(%rbp)
  movss  -0x34(%rbp),%xmm0
  subss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x38(%rbp),%xmm0
  subss  -0x30(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x24(%rbp),%xmm0
  subss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x28(%rbp),%xmm0
  subss  -0x30(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L21
  movss  -0x18(%rbp),%xmm0
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
L21:
  pxor   %xmm0,%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L16
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  jmp    L30
L16:
  movss  -0x18(%rbp),%xmm0
  movss  D11(%rip),%xmm1
  comiss %xmm1,%xmm0
  jbe    L30
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
L30:
  movss  -0x18(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  addss  -0x2c(%rbp),%xmm0
  subss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x18(%rbp),%xmm0
  mulss  -0x10(%rbp),%xmm0
  addss  -0x30(%rbp),%xmm0
  subss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x8(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: byte[4]

tool: {"D11": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float distPtSeg(float x, float y, float px, float py, float qx, float qy) {
  float pqx, pqy, dx, dy, d, t;
  pqx = qx - px;
  pqy = qy - py;
  dx = x - px;
  dy = y - py;
  d = pqx * pqx + pqy * pqy;
  t = pqx * dx + pqy * dy;
  if (d > 0)
    t /= d;
  if (t < 0)
    t = 0;
  else if (t > 1)
    t = 1;
  dx = px + t * pqx - x;
  dy = py + t * pqy - y;
  return dx * dx + dy * dy;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<distPtSeg>:
  endbr64
  subss  %xmm2,%xmm4
  subss  %xmm3,%xmm5
  movaps %xmm4,%xmm8
  mulss  %xmm4,%xmm8
  movaps %xmm5,%xmm6
  mulss  %xmm5,%xmm6
  addss  %xmm6,%xmm8
  movaps %xmm0,%xmm7
  subss  %xmm2,%xmm7
  mulss  %xmm4,%xmm7
  movaps %xmm1,%xmm6
  subss  %xmm3,%xmm6
  mulss  %xmm5,%xmm6
  addss  %xmm7,%xmm6
  comiss D4(%rip),%xmm8
  jbe    L37
  divss  %xmm8,%xmm6
L37:
  pxor   %xmm7,%xmm7
  comiss %xmm6,%xmm7
  ja     L16
  comiss D2(%rip),%xmm6
  jbe    L28
  movss  D2(%rip),%xmm6
  jmp    L28
L16:
  pxor   %xmm6,%xmm6
L28:
  mulss  %xmm6,%xmm4
  addss  %xmm2,%xmm4
  subss  %xmm0,%xmm4
  mulss  %xmm5,%xmm6
  addss  %xmm3,%xmm6
  subss  %xmm1,%xmm6
  mulss  %xmm4,%xmm4
  mulss  %xmm6,%xmm6
  movaps %xmm4,%xmm0
  addss  %xmm6,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: byte[4]
name: disassemble_data
arguments: tag: D2
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x00]}

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float distPtSeg(float x, float y, float px, float py, float qx, float qy) {
  float pqx, pqy, dx, dy, d, t;
  pqx = qx - px;
  pqy = qy - py;
  dx = x - px;
  dy = y - py;
  d = pqx * pqx + pqy * pqy;
  t = pqx * dx + pqy * dy;
  if (d > 0)
    t /= d;
  if (t < 0)
    t = 0;
  else if (t > 1)
    t = 1;
  dx = px + t * pqx - x;
  dy = py + t * pqy - y;
  return dx * dx + dy * dy;
}
```