ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<showprice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L19
L14:
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L14
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D16: 1

tool: D12: 0.95

tool: D9: The total cost will be $%0.2f.


assistant: ```c
void showprice(double rate, int nights) {
  int n;
  double total = 0.0;
  double factor = 1.0;
  for (n = 1; n <= nights; n++, factor *= 0.95)
    total += rate * factor;
  printf("The total cost will be $%0.2f.\n", total);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<showprice>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L6
  movapd %xmm0,%xmm3
  add    $0x1,%edi
  movsd  D19(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  movsd  D9(%rip),%xmm4
L13:
  movapd %xmm3,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  add    $0x1,%eax
  mulsd  %xmm4,%xmm1
  cmp    %edi,%eax
  jne    L13
L26:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L6:
  pxor   %xmm0,%xmm0
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_guessed: f64
name: extract_symbolic_data
arguments: label: D9
type_guessed: f64
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D19: 1

tool: D9: 0.95

tool: D15: The total cost will be $%0.2f.


assistant: ```c
void showprice(double rate, int nights) {
  int n;
  double total = 0.0;
  double factor = 1.0;
  for (n = 1; n <= nights; n++, factor *= 0.95)
    total += rate * factor;
  printf("The total cost will be $%0.2f.\n", total);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<showprice>:
  endbr64
  movapd %xmm0,%xmm3
  test   %edi,%edi
  jle    L18
  movsd  D10(%rip),%xmm1
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  movsd  D18(%rip),%xmm4
  nopl   0x0(%rax,%rax,1)
L10:
  movapd %xmm3,%xmm2
  add    $0x1,%eax
  mulsd  %xmm1,%xmm2
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  cmp    %eax,%edi
  jne    L10
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  pxor   %xmm0,%xmm0
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type: f64
name: read_data
arguments: tag: D18
type: f64
name: read_data
arguments: tag: D19
type: string

tool: D10: 1

tool: D18: 0.95

tool: D19: The total cost will be $%0.2f.


assistant: ```c
void showprice(double rate, int nights) {
  int n;
  double total = 0.0;
  double factor = 1.0;
  for (n = 1; n <= nights; n++, factor *= 0.95)
    total += rate * factor;
  printf("The total cost will be $%0.2f.\n", total);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<showprice>:
  endbr64
  movapd %xmm0,%xmm3
  test   %edi,%edi
  jle    L4
  movsd  D34(%rip),%xmm1
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  movsd  D31(%rip),%xmm4
  nopl   0x0(%rax,%rax,1)
L11:
  movapd %xmm3,%xmm2
  add    $0x1,%eax
  mulsd  %xmm1,%xmm2
  mulsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  cmp    %eax,%edi
  jne    L11
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  pxor   %xmm0,%xmm0
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D34
type_guessed: f64
name: disassemble_data
arguments: data_label: D31
type_guessed: f64
name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D34: 1

tool: D31: 0.95

tool: D0: The total cost will be $%0.2f.


assistant: ```c
void showprice(double rate, int nights) {
  int n;
  double total = 0.0;
  double factor = 1.0;
  for (n = 1; n <= nights; n++, factor *= 0.95)
    total += rate * factor;
  printf("The total cost will be $%0.2f.\n", total);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<msg_outif_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x190,%rsp
  mov    %rdi,-0x168(%rbp)
  mov    %rsi,-0x170(%rbp)
  mov    %rdx,-0x178(%rbp)
  mov    %rcx,-0x180(%rbp)
  mov    %r8d,-0x184(%rbp)
  mov    %r9d,-0x188(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x150(%rbp),%rdx
  mov    -0x184(%rbp),%esi
  mov    -0x170(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0xf,%edx
  mov    %rax,%rdi
  call   <cnfImpn@plt>
  lea    -0x140(%rbp),%rdx
  mov    -0x188(%rbp),%esi
  mov    -0x178(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x12c,%edx
  mov    %rax,%rdi
  call   <cnfImpn@plt>
  mov    -0x180(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x158(%rbp)
  mov    -0x168(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x154(%rbp)
  lea    -0x158(%rbp),%rcx
  lea    -0x140(%rbp),%rdx
  lea    -0x150(%rbp),%rsi
  mov    -0x154(%rbp),%eax
  mov    %eax,%edi
  call   <msgOutif@plt>
  mov    -0x158(%rbp),%edx
  mov    -0x180(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void msg_outif_(int *const PRIOR, char *const PARAM, char *const TEXT, int *const STATUS, int PARAM_length, int TEXT_length) {
  char param[15 + 1];
  char text[300 + 1];
  int prior;
  int status;
  cnfImpn(PARAM, PARAM_length, 15, param);
  cnfImpn(TEXT, TEXT_length, 300, text);
  status = *STATUS;
  prior = *PRIOR;
  msgOutif(prior, param, text, &status);
  *STATUS = status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msg_outif_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x168,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %r8d,%esi
  mov    %r9d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  mov    %r14,%rcx
  mov    $0xf,%edx
  call   <cnfImpn@plt>
  lea    0x20(%rsp),%r15
  mov    %r15,%rcx
  mov    $0x12c,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <cnfImpn@plt>
  mov    (%rbx),%eax
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    0x0(%rbp),%edi
  call   <msgOutif@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_outif_(int *const PRIOR, char *const PARAM, char *const TEXT, int *const STATUS, int PARAM_length, int TEXT_length) {
  char param[15 + 1];
  char text[300 + 1];
  int prior;
  int status;
  cnfImpn(PARAM, PARAM_length, 15, param);
  cnfImpn(TEXT, TEXT_length, 300, text);
  status = *STATUS;
  prior = *PRIOR;
  msgOutif(prior, param, text, &status);
  *STATUS = status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msg_outif_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    $0xf,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r8d,%esi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x20(%rsp),%r15
  mov    %r14,%rcx
  call   <cnfImpn@plt>
  mov    %r15,%rcx
  mov    $0x12c,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <cnfImpn@plt>
  mov    (%rbx),%eax
  mov    0x0(%rbp),%edi
  lea    0xc(%rsp),%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %eax,0xc(%rsp)
  call   <msgOutif@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_outif_(int *const PRIOR, char *const PARAM, char *const TEXT, int *const STATUS, int PARAM_length, int TEXT_length) {
  char param[15 + 1];
  char text[300 + 1];
  int prior;
  int status;
  cnfImpn(PARAM, PARAM_length, 15, param);
  cnfImpn(TEXT, TEXT_length, 300, text);
  status = *STATUS;
  prior = *PRIOR;
  msgOutif(prior, param, text, &status);
  *STATUS = status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<msg_outif_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    $0xf,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r8d,%esi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x20(%rsp),%r15
  mov    %r14,%rcx
  call   <cnfImpn@plt>
  mov    %r15,%rcx
  mov    $0x12c,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <cnfImpn@plt>
  mov    (%rbx),%eax
  mov    0x0(%rbp),%edi
  lea    0xc(%rsp),%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %eax,0xc(%rsp)
  call   <msgOutif@plt>
  mov    0xc(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x168,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_outif_(int *const PRIOR, char *const PARAM, char *const TEXT, int *const STATUS, int PARAM_length, int TEXT_length) {
  char param[15 + 1];
  char text[300 + 1];
  int prior;
  int status;
  cnfImpn(PARAM, PARAM_length, 15, param);
  cnfImpn(TEXT, TEXT_length, 300, text);
  status = *STATUS;
  prior = *PRIOR;
  msgOutif(prior, param, text, &status);
  *STATUS = status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pythag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movq   D1(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L7
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x10(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  jmp    L23
L7:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L6
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x8(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  jmp    L23
L6:
  pxor   %xmm0,%xmm0
L23:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: qword
name: retrieve_data
arguments: data_tag: D12
datatype: f64

tool: D1: 9223372036854775807

tool: D12: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb / absa) * (absb / absa));
  if (absb > absa)
    return absb * sqrt(1.0 + (absa / absb) * (absa / absb));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pythag>:
  endbr64
  sub    $0x18,%rsp
  movq   D14(%rip),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm2,%xmm3
  movsd  %xmm3,(%rsp)
  andpd  %xmm1,%xmm2
  movsd  %xmm2,0x8(%rsp)
  comisd %xmm2,%xmm3
  ja     L20
  movsd  0x8(%rsp),%xmm5
  comisd (%rsp),%xmm5
  ja     L60
  pxor   %xmm0,%xmm0
L7:
  add    $0x18,%rsp
  ret
L20:
  divsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  D21(%rip),%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L32
  sqrtsd %xmm1,%xmm1
L72:
  movsd  (%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  jmp    L7
L32:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L72
L60:
  divsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  D21(%rip),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L15
  sqrtsd %xmm0,%xmm0
L36:
  mulsd  0x8(%rsp),%xmm0
  jmp    L7
L15:
  call   <sqrt@plt>
  jmp    L36
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: qword
name: read_data
arguments: data_label: D21
type_infered: f64

tool: D14: 9223372036854775807

tool: D21: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb / absa) * (absb / absa));
  if (absb > absa)
    return absb * sqrt(1.0 + (absa / absb) * (absa / absb));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pythag>:
  endbr64
  sub    $0x18,%rsp
  movq   D0(%rip),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm2,%xmm3
  andpd  %xmm1,%xmm2
  comisd %xmm2,%xmm3
  ja     L19
  comisd %xmm3,%xmm2
  ja     L6
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L19:
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  D9(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  ja     L36
  sqrtsd %xmm1,%xmm1
L7:
  mulsd  %xmm1,%xmm3
  add    $0x18,%rsp
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  D9(%rip),%xmm0
  ucomisd %xmm0,%xmm1
  ja     L41
  sqrtsd %xmm0,%xmm0
L10:
  mulsd  %xmm2,%xmm0
  add    $0x18,%rsp
  ret
L41:
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L10
L36:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D0
type: qword
name: read_data
arguments: tag: D9
type: f64

tool: D0: 9223372036854775807

tool: D9: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb / absa) * (absb / absa));
  if (absb > absa)
    return absb * sqrt(1.0 + (absa / absb) * (absa / absb));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<pythag>:
  endbr64
  sub    $0x18,%rsp
  movq   D2(%rip),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm2,%xmm3
  andpd  %xmm1,%xmm2
  comisd %xmm2,%xmm3
  ja     L2
  comisd %xmm3,%xmm2
  ja     L44
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L2:
  divsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  D9(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  ja     L49
  sqrtsd %xmm1,%xmm1
L47:
  mulsd  %xmm1,%xmm3
  add    $0x18,%rsp
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  D9(%rip),%xmm0
  ucomisd %xmm0,%xmm1
  ja     L57
  sqrtsd %xmm0,%xmm0
L29:
  mulsd  %xmm2,%xmm0
  add    $0x18,%rsp
  ret
L57:
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  jmp    L29
L49:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L47
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: qword
name: extract_symbolic_data
arguments: label: D9
data_type: f64

tool: D2: 9223372036854775807

tool: D9: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb / absa) * (absb / absa));
  if (absb > absa)
    return absb * sqrt(1.0 + (absa / absb) * (absa / absb));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<create_search_targets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L13
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,(%rcx)
  addq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L16
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint32_t *create_search_targets(size_t count, size_t max) {
  uint32_t *targets = malloc(count * sizeof(*targets));
  for (size_t i = 0; i < count; i++)
    targets[i] = rand() % max;
  return targets;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<create_search_targets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x0(,%rdi,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12,%r12
  je     L14
  mov    $0x0,%ebx
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    $0x0,%edx
  div    %rbp
  mov    %rdx,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L3
L14:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *create_search_targets(size_t count, size_t max) {
  uint32_t *targets = malloc(count * sizeof(*targets));
  for (size_t i = 0; i < count; i++)
    targets[i] = rand() % max;
  return targets;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<create_search_targets>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  shl    $0x3,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12,%r12
  je     L11
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edx,%edx
  div    %rbp
  mov    %rdx,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L8
L11:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *create_search_targets(size_t count, size_t max) {
  uint32_t *targets = malloc(count * sizeof(*targets));
  for (size_t i = 0; i < count; i++)
    targets[i] = rand() % max;
  return targets;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<create_search_targets>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  shl    $0x3,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12,%r12
  je     L4
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  call   <rand@plt>
  xor    %edx,%edx
  div    %rbp
  mov    %rdx,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L15
L4:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint32_t *create_search_targets(size_t count, size_t max) {
  uint32_t *targets = malloc(count * sizeof(*targets));
  for (size_t i = 0; i < count; i++)
    targets[i] = rand() % max;
  return targets;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<typeCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x420,%rsp
  mov    %rdi,-0x3418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3418(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x3410(%rbp),%rdx
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x3,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  lea    -0x3410(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void typeCommand(char *args[]) {
  char buffer[(32 - 6) * 512];
  interrupt(0x21, 0x3, args[1], buffer, 0);
  interrupt(0x21, 0x0, buffer, 0, 0);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<typeCommand>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    0x8(%rdi),%rdx
  mov    $0x0,%r8d
  mov    %rbx,%rcx
  mov    $0x3,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  mov    0x3408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3410,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void typeCommand(char *args[]) {
  char buffer[(32 - 6) * 512];
  interrupt(0x21, 0x3, args[1], buffer, 0);
  interrupt(0x21, 0x0, buffer, 0, 0);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<typeCommand>:
  endbr64
  push   %r12
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x410,%rsp
  xor    %r8d,%r8d
  mov    $0x3,%esi
  mov    0x8(%rdi),%rdx
  mov    $0x21,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x3408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rcx
  call   <interrupt@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %r12,%rdx
  mov    $0x21,%edi
  call   <interrupt@plt>
  mov    0x3408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x3410,%rsp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void typeCommand(char *args[]) {
  char buffer[(32 - 6) * 512];
  interrupt(0x21, 0x3, args[1], buffer, 0);
  interrupt(0x21, 0x0, buffer, 0, 0);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<typeCommand>:
  endbr64
  push   %r12
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x410,%rsp
  xor    %r8d,%r8d
  mov    $0x3,%esi
  mov    0x8(%rdi),%rdx
  mov    $0x21,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x3408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rcx
  call   <interrupt@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    %r12,%rdx
  mov    $0x21,%edi
  call   <interrupt@plt>
  mov    0x3408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x3410,%rsp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void typeCommand(char *args[]) {
  char buffer[(32 - 6) * 512];
  interrupt(0x21, 0x3, args[1], buffer, 0);
  interrupt(0x21, 0x0, buffer, 0, 0);
  return;
}
```