user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1d(%rsp),%rbx
  nopl   0x0(%rax)
L65:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  cmpb   $0x2d,0x1d(%rsp)
  je     L18
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L121
  cmpb   $0x30,0x1d(%rsp)
  mov    %rbx,%rdi
  jne    L39
  cmpb   $0x78,0x1e(%rsp)
  je     L120
L39:
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
  xchg   %ax,%ax
L121:
  lea    D58(%rip),%rdi
  call   <puts@plt>
  jmp    L65
  xchg   %ax,%ax
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L199
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L120:
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L133
  movslq %eax,%r15
  xor    %ecx,%ecx
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L110:
  movzbl (%rbx,%r15,1),%edx
  cmp    $0x78,%dl
  je     L142
  cmp    $0x30,%dl
  je     L166
  lea    -0x41(%rdx),%eax
  cmp    $0x25,%al
  ja     L1
  lea    D33(%rip),%rsi
  movzbl %al,%eax
  movslq (%rsi,%rax,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
L142:
  cmpb   $0x30,0x1c(%rsp,%r15,1)
  je     L148
L1:
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %dl,0xf(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  movsbl 0xf(%rsp),%edx
  mov    0x8(%rsp),%ecx
  mov    %rax,%r9
  sub    $0x30,%edx
  movslq %edx,%rax
  imul   %r9,%rax
  add    %rax,%r14
  nopl   0x0(%rax,%rax,1)
L148:
  sub    $0x1,%r15
  add    $0x1,%ecx
  test   %r15d,%r15d
  jns    L110
L36:
  mov    %r14,%rsi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L65
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xf,%rax,%rax
  add    %rax,%r14
  jmp    L148
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xe,%rax,%rax
  add    %rax,%r14
  jmp    L148
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xd,%rax,%rax
  add    %rax,%r14
  jmp    L148
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xc,%rax,%rax
  add    %rax,%r14
  jmp    L148
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xb,%rax,%rax
  add    %rax,%r14
  jmp    L148
  mov    %ecx,%esi
  mov    $0x10,%edi
  mov    %ecx,0x8(%rsp)
  call   <pow@plt>
  mov    0x8(%rsp),%ecx
  imul   $0xa,%rax,%rax
  add    %rax,%r14
  jmp    L148
L166:
  lea    0x1(%r15),%eax
  cltq
  cmpb   $0x78,0x1d(%rsp,%rax,1)
  jne    L1
  jmp    L148
L133:
  xor    %r14d,%r14d
  jmp    L36
L199:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D23
type_infered: string
name: extract_symbolic_data
arguments: data_label: D58
type_infered: string
name: extract_symbolic_data
arguments: data_label: D55
type_infered: string

tool: D18: 0x%X


tool: D12: 0x80000000

tool: D23: %s

tool: D58: 2147483648

tool: D55: %i


assistant: ```c
int main() {
  int tam, k = 0, l = 0, pos = 0;
  long long r = 0, resul = 0;
  char ent[11], val;
  unsigned int v = 0, v1 = 0, v2 = 0, v3 = 0, j = 0, conv = 0;
  int q = 0, i = 0;
  while ((ent[0] == '0' && ent[1] == 'x') || conv >= 0) {
    scanf("%s", ent);
    conv = atoi(ent);
    resul = 0;
    if (ent[0] == '-') {
      break;
    } else if (strcmp(ent, "0x80000000") == 0) {
      printf("2147483648\n");
    } else if (ent[0] == '0' && ent[1] == 'x') {
      tam = strlen(ent) - 1;
      for (i = tam; i >= 0; i--) {
        val = ent[i];
        if (val == 'x' && ent[i - 1] == '0') {
        } else if (val == '0' && ent[i + 1] == 'x') {
        } else if (val == 'A' || val == 'a') {
          r = 10;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else if (val == 'B' || val == 'b') {
          r = 11;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else if (val == 'C' || val == 'c') {
          r = 12;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else if (val == 'D' || val == 'd') {
          r = 13;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else if (val == 'E' || val == 'e') {
          r = 14;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else if (val == 'F' || val == 'f') {
          r = 15;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        } else {
          r = val - 48;
          pos = tam - i;
          resul = resul + (r * pow(16, pos));
        }
      }
      printf("%i\n", resul);
    } else {
      v = atoi(ent);
      printf("0x%X\n", v);
    }
  }
  return 0;
}
```