ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L58:
  cmp    %rdx,%rsp
  je     L89
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L58
L89:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L46
  orq    $0x0,-0x8(%rsp,%rax,1)
L46:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L5
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
L63:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D1(%rip),%xmm0
  subss  D11(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L63
L5:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L75
  mov    $0x0,%ebx
L19:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <stdlib_strided_ssumkbn@plt>
  ucomiss %xmm0,%xmm0
  jp     L54
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L19
L75:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L2:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L54:
  lea    D0(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L2
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
data_type: byte[4]
name: parse_data
arguments: label: D11
data_type: byte[4]
name: parse_data
arguments: label: D0
data_type: string

tool: {"D1": [0x00,0x40,0x9c,0x46]}

tool: {"D11": [0x00,0x40,0x1c,0x46]}

tool: D0: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_ssumkbn(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L76
L107:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L107
L76:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L31
L109:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L13
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D3(%rip),%xmm0
  subss  D10(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L39
L13:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L115
  xor    %r14d,%r14d
  jmp    L28
  nopl   0x0(%rax)
L8:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L115
L28:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_ssumkbn@plt>
  ucomiss %xmm0,%xmm0
  jnp    L8
  lea    D24(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L82:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L115:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L82
  xchg   %ax,%ax
L31:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L109
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D10
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D24
type_guessed: string

tool: {"D3": [0x00,0x40,0x9c,0x46]}

tool: {"D10": [0x00,0x40,0x1c,0x46]}

tool: D24: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_ssumkbn(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L31
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L42
L31:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L66
L56:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L34
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L117:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D29(%rip),%xmm0
  subss  D23(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L117
L34:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L30
  xor    %r14d,%r14d
  jmp    L49
  nopl   0x0(%rax)
L95:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L30
L49:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_ssumkbn@plt>
  ucomiss %xmm0,%xmm0
  jnp    L95
  lea    D22(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L32:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L30:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L32
  xchg   %ax,%ax
L66:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L56
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: byte[4]
name: read_data
arguments: label: D23
type_guessed: byte[4]
name: read_data
arguments: label: D22
type_guessed: string

tool: {"D29": [0x00,0x40,0x9c,0x46]}

tool: {"D23": [0x00,0x40,0x1c,0x46]}

tool: D22: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_ssumkbn(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L39
L10:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    $0xffffffff,%eax
L39:
  leave
  ret
```

assistant: ```c
int find_string(const char **table, int n, const char *elem) {
  int i;
  for (i = 0; i < n; ++i) {
    if (strcasecmp(table[i], elem) == 0)
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L32
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L30:
  mov    %ebx,%r14d
  mov    (%r12,%rbx,8),%rdi
  mov    %r13,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L4
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L30
  mov    $0xffffffff,%r14d
L4:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  mov    $0xffffffff,%r14d
  jmp    L4
```

assistant: ```c
int find_string(const char **table, int n, const char *elem) {
  int i;
  for (i = 0; i < n; ++i) {
    if (strcasecmp(table[i], elem) == 0)
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L4
  mov    %rdi,%r14
  mov    %rdx,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L12
  nopl   (%rax)
L26:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L4
L12:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L26
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int find_string(const char **table, int n, const char *elem) {
  int i;
  for (i = 0; i < n; ++i) {
    if (strcasecmp(table[i], elem) == 0)
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L17
  mov    %rdi,%r14
  mov    %rdx,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L5
  nopl   (%rax)
L39:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L17
L5:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L39
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int find_string(const char **table, int n, const char *elem) {
  int i;
  for (i = 0; i < n; ++i) {
    if (strcasecmp(table[i], elem) == 0)
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L14:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L14
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverse(char *str) {
  int len = strlen(str);
  char *tmp = (char *)malloc(sizeof(char) * len);
  for (int i = 0; i < len; i++) {
    tmp[i] = str[len - i - 1];
  }
  tmp[len] = '\0';
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L17
  movslq %ebp,%rcx
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%r8
  lea    -0x1(%rbp),%esi
  sub    %rsi,%r8
  add    %rax,%rcx
  lea    (%rbx,%rcx,1),%rdi
L6:
  movzbl -0x1(%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  mov    %sil,(%rcx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L6
L17:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse(char *str) {
  int len = strlen(str);
  char *tmp = (char *)malloc(sizeof(char) * len);
  for (int i = 0; i < len; i++) {
    tmp[i] = str[len - i - 1];
  }
  tmp[len] = '\0';
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebp,%r9
  test   %ebp,%ebp
  jle    L17
  lea    -0x1(%rbp),%ecx
  lea    -0x1(%rbx,%r9,1),%r8
  sub    %rcx,%r8
  lea    (%rax,%r9,1),%rcx
  lea    (%rbx,%r9,1),%rdx
  lea    (%rbx,%rcx,1),%rdi
  nopl   0x0(%rax)
L11:
  movzbl -0x1(%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L11
L17:
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse(char *str) {
  int len = strlen(str);
  char *tmp = (char *)malloc(sizeof(char) * len);
  for (int i = 0; i < len; i++) {
    tmp[i] = str[len - i - 1];
  }
  tmp[len] = '\0';
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  movslq %ebp,%r9
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%ecx
  lea    -0x1(%rbx,%r9,1),%r8
  sub    %rcx,%r8
  lea    (%rax,%r9,1),%rcx
  lea    (%rbx,%r9,1),%rdx
  lea    (%rbx,%rcx,1),%rdi
  nopl   0x0(%rax)
L13:
  movzbl -0x1(%rdx),%esi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  sub    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %r8,%rdx
  jne    L13
L0:
  movb   $0x0,(%rax,%r9,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse(char *str) {
  int len = strlen(str);
  char *tmp = (char *)malloc(sizeof(char) * len);
  for (int i = 0; i < len; i++) {
    tmp[i] = str[len - i - 1];
  }
  tmp[len] = '\0';
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %r10,%rax
  pop    %rbp
  ret
```

assistant: ```c
void *__attribute__((no, noclone)) foo(void) {
  register void *chain __asm__("%r10");
  return chain;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    %r10,%rax
  ret
```

assistant: ```c
void *__attribute__((no, noclone)) foo(void) {
  register void *chain __asm__("%r10");
  return chain;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  mov    %r10,%rax
  ret
```

assistant: ```c
void *__attribute__((no, noclone)) foo(void) {
  register void *chain __asm__("%r10");
  return chain;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    %r10,%rax
  ret
```

assistant: ```c
void *__attribute__((no, noclone)) foo(void) {
  register void *chain __asm__("%r10");
  return chain;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FillTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <InitTable@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Add@plt>
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void FillTable(uint8_t table[], char str[]) {
  int k, len;
  InitTable(table);
  len = strlen(str);
  for (k = 0; k < len; k++)
    Add(table, str[k]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FillTable>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <InitTable@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r12
L16:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <Add@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L16
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void FillTable(uint8_t table[], char str[]) {
  int k, len;
  InitTable(table);
  len = strlen(str);
  for (k = 0; k < len; k++)
    Add(table, str[k]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FillTable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <InitTable@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <Add@plt>
  cmp    %r12,%rbx
  jne    L19
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void FillTable(uint8_t table[], char str[]) {
  int k, len;
  InitTable(table);
  len = strlen(str);
  for (k = 0; k < len; k++)
    Add(table, str[k]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FillTable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <InitTable@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L5
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L7:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <Add@plt>
  cmp    %r12,%rbx
  jne    L7
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void FillTable(uint8_t table[], char str[]) {
  int k, len;
  InitTable(table);
  len = strlen(str);
  for (k = 0; k < len; k++)
    Add(table, str[k]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<derivative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L6
L13:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subl   $0x1,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *derivative(double *a, int len) {
  double *d = (double *)malloc(len * sizeof(double));
  d[0] = 0;
  int j = len;
  for (int i = 1; i < len; i++) {
    d[i] = a[i - 1] * --j;
  }
  return d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<derivative>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  movq   $0x0,(%rax)
  cmp    $0x1,%ebx
  jle    L10
  lea    0x8(%rax),%rdx
  mov    %rbp,%rcx
  sub    %rax,%rcx
L14:
  sub    $0x1,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  -0x8(%rcx,%rdx,1),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    $0x1,%ebx
  jne    L14
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *derivative(double *a, int len) {
  double *d = (double *)malloc(len * sizeof(double));
  d[0] = 0;
  int j = len;
  for (int i = 1; i < len; i++) {
    d[i] = a[i - 1] * --j;
  }
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<derivative>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,8),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movq   $0x0,(%rax)
  cmp    $0x1,%ebx
  jle    L4
  mov    %rbp,%rcx
  lea    0x8(%rax),%rdx
  sub    %rax,%rcx
  nopl   0x0(%rax)
L3:
  sub    $0x1,%ebx
  pxor   %xmm0,%xmm0
  add    $0x8,%rdx
  cvtsi2sd %ebx,%xmm0
  mulsd  -0x10(%rdx,%rcx,1),%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    $0x1,%ebx
  jne    L3
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double *derivative(double *a, int len) {
  double *d = (double *)malloc(len * sizeof(double));
  d[0] = 0;
  int j = len;
  for (int i = 1; i < len; i++) {
    d[i] = a[i - 1] * --j;
  }
  return d;
}
```