ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L30
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L30:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x786d9717,%rsi
  je     L22
L14:
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L14
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D24: Call this program with %i arguments


tool: D16: %lu


tool: D5: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2020448023UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dump_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L94
L78:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L21
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L66
  mov    -0x30(%rbp),%eax
  mov    %eax,%edx
  jmp    L95
L66:
  mov    $0x2e,%edx
L95:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  cmpl   $0xf,-0x2c(%rbp)
  jne    L87
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L87:
  addl   $0x1,-0x34(%rbp)
L94:
  mov    -0x34(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L78
  mov    -0x34(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L36
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  jmp    L18
L1:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cmp    $0xf,%eax
  jle    L1
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D25: %08x  

tool: D21: %02x 

tool: D40:  %-16s


tool: D12:    

assistant: ```c
void dump_hex(const void *buf, int len) {
  const uint8_t *data = buf;
  int i;
  char ascii_buf[17];
  ascii_buf[16] = '\0';
  for (i = 0; i < len; i++) {
    int val = data[i];
    int off = i % 16;
    if (off == 0)
      printf("%08x  ", i);
    printf("%02x ", val);
    ascii_buf[off] = isprint(val) ? val : '.';
    if (off == 15)
      printf(" %-16s\n", ascii_buf);
  }
  i %= 16;
  if (i) {
    ascii_buf[i] = '\0';
    while (i++ < 16)
      printf("   ");
    printf(" %-16s\n", ascii_buf);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x20(%rsp)
  test   %esi,%esi
  jle    L1
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    $0x0,%ebx
  mov    $0x2e,%r14d
  jmp    L84
L17:
  mov    %r12d,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%edi
  call   <isprint@plt>
  test   %rax,%rax
  cmove  %r14d,%r12d
  movslq %ebp,%rax
  mov    %r12b,0x10(%rsp,%rax,1)
  cmp    $0xf,%ebp
  je     L59
L61:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L40
L84:
  mov    %ebx,%esi
  mov    0x0(%r13,%rbx,4),%r12d
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rax,%rbx,1),%ebp
  and    $0xf,%ebp
  sub    %eax,%ebp
  test   $0xf,%bl
  jne    L17
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L59:
  lea    0x10(%rsp),%rsi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L61
L40:
  mov    0xc(%rsp),%edx
  test   $0xf,%dl
  je     L1
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  add    %eax,%edx
  mov    %edx,%ebx
  and    $0xf,%ebx
  sub    %eax,%ebx
  movslq %ebx,%rax
  movb   $0x0,0x10(%rsp,%rax,1)
  add    $0x1,%ebx
  lea    D10(%rip),%rbp
L99:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x11,%ebx
  jne    L99
  lea    0x10(%rsp),%rsi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D41
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string

tool: D27: %02x 

tool: D6: %08x  

tool: D41:  %-16s


tool: D10:    

assistant: ```c
void dump_hex(const void *buf, int len) {
  const uint8_t *data = buf;
  int i;
  char ascii_buf[17];
  ascii_buf[16] = '\0';
  for (i = 0; i < len; i++) {
    int val = data[i];
    int off = i % 16;
    if (off == 0)
      printf("%08x  ", i);
    printf("%02x ", val);
    ascii_buf[off] = isprint(val) ? val : '.';
    if (off == 15)
      printf(" %-16s\n", ascii_buf);
  }
  i %= 16;
  if (i) {
    ascii_buf[i] = '\0';
    while (i++ < 16)
      printf("   ");
    printf(" %-16s\n", ascii_buf);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dump_hex>:
  endbr64
  push   %r15
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  movb   $0x0,0x20(%rsp)
  mov    %rax,(%rsp)
  test   %esi,%esi
  jle    L74
  mov    %rdi,%rbp
  xor    %r15d,%r15d
  lea    D17(%rip),%r13
  jmp    L72
  xchg   %ax,%ax
L33:
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edi
  call   <isprint@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmove  %eax,%r12d
  movslq %ebx,%rax
  mov    %r12b,0x10(%rsp,%rax,1)
  cmp    $0xf,%ebx
  je     L49
  add    $0x1,%r15
  cmp    %r15,%r14
  je     L36
L72:
  mov    %r15d,%ebx
  mov    0x0(%rbp,%r15,4),%r12d
  mov    %r15d,%esi
  and    $0xf,%ebx
  jne    L33
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L49:
  mov    (%rsp),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%r14
  jne    L72
L36:
  mov    0xc(%rsp),%ebx
  and    $0xf,%ebx
  je     L74
  movslq %ebx,%rax
  lea    D8(%rip),%rbp
  add    $0x1,%ebx
  movb   $0x0,0x10(%rsp,%rax,1)
  cs nopw 0x0(%rax,%rax,1)
L92:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x11,%ebx
  jne    L92
  lea    0x10(%rsp),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L74:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D17: %02x 

tool: D19: %08x  

tool: D10:  %-16s


tool: D8:    

assistant: ```c
void dump_hex(const void *buf, int len) {
  const uint8_t *data = buf;
  int i;
  char ascii_buf[17];
  ascii_buf[16] = '\0';
  for (i = 0; i < len; i++) {
    int val = data[i];
    int off = i % 16;
    if (off == 0)
      printf("%08x  ", i);
    printf("%02x ", val);
    ascii_buf[off] = isprint(val) ? val : '.';
    if (off == 15)
      printf(" %-16s\n", ascii_buf);
  }
  i %= 16;
  if (i) {
    ascii_buf[i] = '\0';
    while (i++ < 16)
      printf("   ");
    printf(" %-16s\n", ascii_buf);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_hex>:
  endbr64
  push   %r15
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  movb   $0x0,0x20(%rsp)
  mov    %rax,(%rsp)
  test   %esi,%esi
  jle    L12
  mov    %rdi,%rbp
  xor    %r15d,%r15d
  lea    D16(%rip),%r13
  jmp    L44
  xchg   %ax,%ax
L0:
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%edi
  call   <isprint@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmove  %eax,%r12d
  movslq %ebx,%rax
  mov    %r12b,0x10(%rsp,%rax,1)
  cmp    $0xf,%ebx
  je     L60
  add    $0x1,%r15
  cmp    %r15,%r14
  je     L21
L44:
  mov    %r15d,%ebx
  mov    0x0(%rbp,%r15,4),%r12d
  mov    %r15d,%esi
  and    $0xf,%ebx
  jne    L0
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rsp),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,%r14
  jne    L44
L21:
  mov    0xc(%rsp),%ebx
  and    $0xf,%ebx
  je     L12
  movslq %ebx,%rax
  lea    D15(%rip),%rbp
  add    $0x1,%ebx
  movb   $0x0,0x10(%rsp,%rax,1)
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x11,%ebx
  jne    L14
  lea    0x10(%rsp),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L12:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D16: %02x 

tool: D34: %08x  

tool: D29:  %-16s


tool: D15:    

assistant: ```c
void dump_hex(const void *buf, int len) {
  const uint8_t *data = buf;
  int i;
  char ascii_buf[17];
  ascii_buf[16] = '\0';
  for (i = 0; i < len; i++) {
    int val = data[i];
    int off = i % 16;
    if (off == 0)
      printf("%08x  ", i);
    printf("%02x ", val);
    ascii_buf[off] = isprint(val) ? val : '.';
    if (off == 15)
      printf(" %-16s\n", ascii_buf);
  }
  i %= 16;
  if (i) {
    ascii_buf[i] = '\0';
    while (i++ < 16)
      printf("   ");
    printf(" %-16s\n", ascii_buf);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isPerfectSquare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  cmp    %rax,-0x18(%rbp)
  jne    L9
  mov    $0x1,%eax
  jmp    L10
L9:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
long int isPerfectSquare(long int n) {
  long int s = sqrt(n);
  if (s * s == n) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPerfectSquare>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <sqrt@plt>
  imul   %rax,%rax
  cmp    %rbx,%rax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
long int isPerfectSquare(long int n) {
  long int s = sqrt(n);
  if (s * s == n) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPerfectSquare>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <sqrt@plt>
  imul   %rax,%rax
  cmp    %rbx,%rax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
long int isPerfectSquare(long int n) {
  long int s = sqrt(n);
  if (s * s == n) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPerfectSquare>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <sqrt@plt>
  imul   %rax,%rax
  cmp    %rbx,%rax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
long int isPerfectSquare(long int n) {
  long int s = sqrt(n);
  if (s * s == n) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byte_chr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L12:
  cmpl   $0x0,-0x1c(%rbp)
  je     L85
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L130
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L88
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L74
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L43
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L105
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  jmp    L12
L85:
  nop
  jmp    L148
L130:
  nop
  jmp    L148
L1:
  nop
  jmp    L148
L88:
  nop
  jmp    L148
L30:
  nop
  jmp    L148
L74:
  nop
  jmp    L148
L43:
  nop
  jmp    L148
L105:
  nop
L148:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int byte_chr(const char *s, unsigned int n, int c) {
  char ch;
  const char *t;
  ch = c;
  t = s;
  for (;;) {
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
  }
  return t - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_chr>:
  endbr64
  test   %esi,%esi
  je     L63
  mov    %rdi,%rcx
L102:
  cmp    %dl,(%rcx)
  je     L50
  lea    0x1(%rcx),%rax
  cmp    $0x1,%esi
  je     L75
  cmp    %dl,0x1(%rcx)
  je     L75
  lea    0x2(%rcx),%rax
  cmp    $0x2,%esi
  je     L75
  cmp    %dl,0x2(%rcx)
  je     L75
  lea    0x3(%rcx),%rax
  cmp    $0x3,%esi
  je     L75
  cmp    %dl,0x3(%rcx)
  je     L75
  lea    0x4(%rcx),%rcx
  sub    $0x4,%esi
  jne    L102
  mov    %rcx,%rax
  jmp    L75
L63:
  mov    %rdi,%rax
  jmp    L75
L50:
  mov    %rcx,%rax
L75:
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int byte_chr(const char *s, unsigned int n, int c) {
  char ch;
  const char *t;
  ch = c;
  t = s;
  for (;;) {
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
  }
  return t - s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<byte_chr>:
  endbr64
  test   %esi,%esi
  je     L28
  mov    %rdi,%rcx
  jmp    L16
  nopl   (%rax)
L63:
  lea    0x1(%rcx),%rax
  cmp    $0x1,%esi
  je     L81
  cmp    %dl,0x1(%rcx)
  je     L81
  lea    0x2(%rcx),%rax
  cmp    $0x2,%esi
  je     L81
  cmp    %dl,0x2(%rcx)
  je     L81
  lea    0x3(%rcx),%rax
  cmp    $0x3,%esi
  je     L81
  cmp    %dl,0x3(%rcx)
  je     L81
  add    $0x4,%rcx
  sub    $0x4,%esi
  je     L25
L16:
  cmp    %dl,(%rcx)
  jne    L63
L25:
  mov    %ecx,%eax
L81:
  sub    %edi,%eax
  ret
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int byte_chr(const char *s, unsigned int n, int c) {
  char ch;
  const char *t;
  ch = c;
  t = s;
  for (;;) {
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
  }
  return t - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byte_chr>:
  endbr64
  test   %esi,%esi
  je     L69
  mov    %rdi,%rcx
  jmp    L83
  nopl   (%rax)
L18:
  lea    0x1(%rcx),%rax
  cmp    $0x1,%esi
  je     L49
  cmp    %dl,0x1(%rcx)
  je     L49
  lea    0x2(%rcx),%rax
  cmp    $0x2,%esi
  je     L49
  cmp    %dl,0x2(%rcx)
  je     L49
  lea    0x3(%rcx),%rax
  cmp    $0x3,%esi
  je     L49
  cmp    %dl,0x3(%rcx)
  je     L49
  add    $0x4,%rcx
  sub    $0x4,%esi
  je     L58
L83:
  cmp    %dl,(%rcx)
  jne    L18
L58:
  mov    %ecx,%eax
L49:
  sub    %edi,%eax
  ret
L69:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int byte_chr(const char *s, unsigned int n, int c) {
  char ch;
  const char *t;
  ch = c;
  t = s;
  for (;;) {
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
    if (!n)
      break;
    if (*t == ch)
      break;
    ++t;
    --n;
  }
  return t - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_doc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  lea    D36(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  mov    $0x0,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string

tool: D36: <?xml version="1.0" encoding="UTF-8"?>


tool: D24: ganttproject.gan

tool: D13: <project name="Exported GitPro Project" >


assistant: ```c
void init_doc() {
  write("ganttproject.gan", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n", NULL);
  write("ganttproject.gan", "<project name=\"Exported GitPro Project\" >\n", NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_doc>:
  endbr64
  push   %rbx
  mov    $0x0,%edx
  lea    D7(%rip),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <write@plt>
  mov    $0x0,%edx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <write@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D7: <?xml version="1.0" encoding="UTF-8"?>


tool: D9: ganttproject.gan

tool: D2: <project name="Exported GitPro Project" >


assistant: ```c
void init_doc() {
  write("ganttproject.gan", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n", NULL);
  write("ganttproject.gan", "<project name=\"Exported GitPro Project\" >\n", NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_doc>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rbp
  xor    %edx,%edx
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <write@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  lea    D11(%rip),%rsi
  jmp    1050 <write@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D11
datatype: string

tool: D25: ganttproject.gan

tool: D26: <?xml version="1.0" encoding="UTF-8"?>


tool: D11: <project name="Exported GitPro Project" >


assistant: ```c
void init_doc() {
  write("ganttproject.gan", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n", NULL);
  write("ganttproject.gan", "<project name=\"Exported GitPro Project\" >\n", NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_doc>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rbp
  xor    %edx,%edx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <write@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  pop    %rbp
  lea    D15(%rip),%rsi
  jmp    1050 <write@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D22: ganttproject.gan

tool: D6: <?xml version="1.0" encoding="UTF-8"?>


tool: D15: <project name="Exported GitPro Project" >


assistant: ```c
void init_doc() {
  write("ganttproject.gan", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n", NULL);
  write("ganttproject.gan", "<project name=\"Exported GitPro Project\" >\n", NULL);
}
```