ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D32(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  D16(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  0x10(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D0(%rip),%xmm0
  call   <abs@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: byte[8]
name: parse_data
arguments: data_tag: D0
data_type: f64
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D32: %lf

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D0: 0.5

tool: D11: The total meal cost is %d dollars.


assistant: ```c
int main() {
  double mealCost, tipPercent, taxPercent, totalCost;
  scanf("%lf", &mealCost);
  scanf("%lf", &tipPercent);
  scanf("%lf", &taxPercent);
  totalCost = mealCost + (tipPercent * mealCost) / 100 + (taxPercent * mealCost) / 100;
  printf("The total meal cost is %d dollars.\n", abs(totalCost + 0.5));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  D3(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  0x10(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D8(%rip),%xmm0
  call   <abs@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D3
type_infered: byte[8]
name: parse_data
arguments: data_tag: D8
type_infered: f64
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D12: %lf

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D8: 0.5

tool: D10: The total meal cost is %d dollars.


assistant: ```c
int main() {
  double mealCost, tipPercent, taxPercent, totalCost;
  scanf("%lf", &mealCost);
  scanf("%lf", &tipPercent);
  scanf("%lf", &taxPercent);
  totalCost = mealCost + (tipPercent * mealCost) / 100 + (taxPercent * mealCost) / 100;
  printf("The total meal cost is %d dollars.\n", abs(totalCost + 0.5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  D19(%rip),%xmm2
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  0x10(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D39(%rip),%xmm0
  call   <abs@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D19
type: byte[8]
name: parse_data
arguments: label: D39
type: f64
name: parse_data
arguments: label: D25
type: string

tool: D12: %lf

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D39: 0.5

tool: D25: The total meal cost is %d dollars.


assistant: ```c
int main() {
  double mealCost, tipPercent, taxPercent, totalCost;
  scanf("%lf", &mealCost);
  scanf("%lf", &tipPercent);
  scanf("%lf", &taxPercent);
  totalCost = mealCost + (tipPercent * mealCost) / 100 + (taxPercent * mealCost) / 100;
  printf("The total meal cost is %d dollars.\n", abs(totalCost + 0.5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L15
  mov    -0x10(%rbp),%rax
  mov    $0x2d,%edi
  call   *%rax
  negq   -0x8(%rbp)
L15:
  cmpq   $0x9,-0x8(%rbp)
  jle    L16
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <printnum>
L16:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  nop
  leave
  ret
```

assistant: ```c
void printnum(long n, void (*p)(char)) {
  if (n < 0) {
    (*p)('-');
    n = -n;
  }
  if (n >= 10)
    printnum(n / 10, p);
  (*p)((int)(n % 10) + '0');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  js     L18
L30:
  cmp    $0x9,%rbx
  jg     L13
L5:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%edi
  movsbl %dil,%edi
  call   *%rbp
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x2d,%edi
  call   *%rsi
  neg    %rbx
  jmp    L30
L13:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rdx,%rdi
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdi
  mov    %rbp,%rsi
  call   <printnum>
  jmp    L5
```

assistant: ```c
void printnum(long n, void (*p)(char)) {
  if (n < 0) {
    (*p)('-');
    n = -n;
  }
  if (n >= 10)
    printnum(n / 10, p);
  (*p)((int)(n % 10) + '0');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printnum>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jns    L24
  mov    $0x2d,%edi
  neg    %rbx
  call   *%rsi
L24:
  cmp    $0x9,%rbx
  jg     L15
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  mov    %rbp,%rax
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  movzbl %dil,%edi
  jmp    *%rax
  nopl   (%rax)
L15:
  movabs $0xcccccccccccccccd,%rdi
  mov    %rbx,%rax
  mov    %rbp,%rsi
  mul    %rdi
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <printnum>
  jmp    L12
```

assistant: ```c
void printnum(long n, void (*p)(char)) {
  if (n < 0) {
    (*p)('-');
    n = -n;
  }
  if (n >= 10)
    printnum(n / 10, p);
  (*p)((int)(n % 10) + '0');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printnum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jns    L61
  mov    $0x2d,%edi
  neg    %rbx
  call   *%rsi
L61:
  cmp    $0x9,%rbx
  jg     L1
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  mov    %rbp,%rax
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  movzbl %dil,%edi
  pop    %r12
  pop    %r13
  jmp    *%rax
  nopl   (%rax)
L1:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rbx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r12
  cmp    $0x63,%rbx
  jg     L51
L65:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%edi
  movzbl %dil,%edi
  call   *%rbp
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %r12,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r13
  cmp    $0x3e7,%rbx
  jg     L32
L13:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r13,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r13
  lea    0x30(%r13),%edi
  movzbl %dil,%edi
  call   *%rbp
  jmp    L65
L32:
  mov    %r13,%rax
  mov    %rbp,%rsi
  mul    %rcx
  mov    %rdx,%rdi
  shr    $0x3,%rdi
  call   <printnum>
  jmp    L13
```

assistant: ```c
void printnum(long n, void (*p)(char)) {
  if (n < 0) {
    (*p)('-');
    n = -n;
  }
  if (n >= 10)
    printnum(n / 10, p);
  (*p)((int)(n % 10) + '0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L13
L17:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int square(int num, int power) {
  int n = 1;
  int product = 1;
  for (; n <= power; n++) {
    product = product * num;
  }
  return product;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<square>:
  endbr64
  test   %esi,%esi
  jle    L13
  add    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
L10:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L10
L28:
  mov    %edx,%eax
  ret
L13:
  mov    $0x1,%edx
  jmp    L28
```

assistant: ```c
int square(int num, int power) {
  int n = 1;
  int product = 1;
  for (; n <= power; n++) {
    product = product * num;
  }
  return product;
}
```
user: What is the c source code of the assembly code below:

```asm
<square>:
  endbr64
  test   %esi,%esi
  jle    L16
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L7
  mov    %r8d,%eax
  ret
  nop
L16:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int square(int num, int power) {
  int n = 1;
  int product = 1;
  for (; n <= power; n++) {
    product = product * num;
  }
  return product;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<square>:
  endbr64
  test   %esi,%esi
  jle    L18
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %esi,%eax
  jne    L16
  mov    %r8d,%eax
  ret
  nop
L18:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int square(int num, int power) {
  int n = 1;
  int product = 1;
  for (; n <= power; n++) {
    product = product * num;
  }
  return product;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L46
  mov    $0x1,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L46:
  movl   $0x0,-0x14(%rbp)
  jmp    L41
L56:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L41:
  cmpl   $0x0,-0x14(%rbp)
  jle    L56
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0xdc1e,%ax
  jne    L48
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L48:
  movl   $0x0,-0x10(%rbp)
  jmp    L52
L53:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L52:
  cmpl   $0x0,-0x10(%rbp)
  jle    L53
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D9
datatype: string

tool: D21: Call this program with %i arguments


tool: D15: You win!

tool: D9: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56350) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L32
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0xdc1e,0x6(%rsp)
  je     L20
L9:
  movzwl 0x6(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L0
L20:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D11: %u


tool: D4: Call this program with %i arguments


tool: D17: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56350) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L6
  lea    D26(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L6:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xdc1e,%si
  je     L2
L25:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L25
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D21
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string

tool: D26: Call this program with %i arguments


tool: D21: %u


tool: D18: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56350) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L23
  lea    D18(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L23:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xdc1e,%si
  je     L10
L5:
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L5
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D18: Call this program with %i arguments


tool: D3: %u


tool: D10: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56350) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix_multiply_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  mov    %r8d,-0x50(%rbp)
  mov    %r9d,-0x54(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L59
L19:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L0
L4:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L49
L20:
  mov    -0x28(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x28(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
L49:
  cmpl   $0x1f,-0x28(%rbp)
  jbe    L20
  mov    -0x4c(%rbp),%eax
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%eax
  shl    $0x3,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x2c(%rbp)
L0:
  cmpl   $0x1f,-0x2c(%rbp)
  jbe    L4
  mov    -0x54(%rbp),%eax
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L59:
  cmpl   $0x1f,-0x24(%rbp)
  jbe    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_multiply_block(double C[], const double A[], const double B[], const unsigned int ldc, const unsigned int lda, const unsigned int ldb) {
  unsigned int i, j, k;
  const double *B_k = B;
  for (k = 0; k < 32; ++k) {
    double *C_i = C;
    const double *Ap = A + k;
    for (i = 0; i < 32; ++i) {
      const double A_i_k = *Ap;
      for (j = 0; j < 32; ++j) {
        C_i[j] += A_i_k * B_k[j];
      }
      C_i += ldc;
      Ap += lda;
    }
    B_k += ldb;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix_multiply_block>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %ecx,%ecx
  lea    0x0(,%rcx,8),%r11
  mov    %r8d,%r8d
  shl    $0x3,%r8
  mov    %r9d,%r9d
  shl    $0x3,%r9
  mov    %rax,%rbx
  lea    0x100(%rax),%rbp
L22:
  mov    %rbx,%rdi
  mov    %r10,%rdx
  mov    $0x20,%ecx
L13:
  movsd  (%rdi),%xmm1
  mov    $0x0,%eax
L12:
  movapd %xmm1,%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x100,%rax
  jne    L12
  add    %r11,%rdx
  add    %r8,%rdi
  sub    $0x1,%ecx
  jne    L13
  add    %r9,%rsi
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L22
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void matrix_multiply_block(double C[], const double A[], const double B[], const unsigned int ldc, const unsigned int lda, const unsigned int ldb) {
  unsigned int i, j, k;
  const double *B_k = B;
  for (k = 0; k < 32; ++k) {
    double *C_i = C;
    const double *Ap = A + k;
    for (i = 0; i < 32; ++i) {
      const double A_i_k = *Ap;
      for (j = 0; j < 32; ++j) {
        C_i[j] += A_i_k * B_k[j];
      }
      C_i += ldc;
      Ap += lda;
    }
    B_k += ldb;
  }
}
```