user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L121:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jne    L73
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L73
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L124
L73:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L12
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L119
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jne    L12
L119:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L128
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jne    L128
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  je     L128
L12:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L94
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L2
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jl     L94
L2:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L18
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jne    L18
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jl     L94
L18:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L154
L128:
  nop
  jmp    L121
L94:
  nop
L154:
  jmp    L121
L124:
  nop
  mov    -0x14(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L140
  call   <__stack_chk_fail@plt>
L140:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D46
data_type: string
name: read_data
arguments: tag: D33
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D23: Enter first date (mm/dd/yy) : 

tool: D46: %d/%d/%d

tool: D33: Enter a date (mm/dd/yy) : 

tool: D9: %d/%d/%.2d is the earliest date


assistant: ```c
int main(void) {
  int s = 0, m1, m2, d1, d2, y1, y2;
  printf("Enter first date (mm/dd/yy) : ");
  scanf("%d/%d/%d", &m1, &d1, &y1);
  while (1) {
    printf("Enter a date (mm/dd/yy) : ");
    scanf("%d/%d/%d", &m2, &d2, &y2);
    if (m2 == 0 && y2 == 0 && d2 == 0)
      break;
    if (y1 != y2 || (y1 == y2 && m1 != m2) || (y1 == y2 && m1 == m2 && d1 != d2)) {
      if (y1 < y2 || (y1 == y2 && m1 < m2) || (y1 == y2 && m1 == m2 && d1 < d2)) {
        continue;
      } else {
        m1 = m2;
        y1 = y2;
        d1 = d2;
      }
    } else {
      continue;
    }
  }
  printf("%d/%d/%.2d is the earliest date\n", m1, d1, y1);
  return 0;
}
```