ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<checkNoNans>:
  endbr64
  test   %rdi,%rdi
  je     L35
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L2:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L5
  movsd  0x0(%rbp,%rbx,8),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L26
L5:
  mov    D6(%rip),%rax
  mov    %r13,%rsi
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
L26:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  ret
```

assistant: ```c
void checkNoNans(size_t n, double *buff, const char *err_msg) {
  size_t i;
  for (i = 0; i < n; i++)
    if (isnan(buff[i]) || isinf(buff[i])) {
      fprintf(stderr, err_msg);
      exit(EXIT_FAILURE);
    }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkNoNans>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L34:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L30
  movsd  0x0(%rbp,%rbx,8),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L19
L30:
  mov    D17(%rip),%rax
  mov    %r13,%rsi
  mov    (%rax),%edi
  call   <fprintf@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
L19:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  ret
```

assistant: ```c
void checkNoNans(size_t n, double *buff, const char *err_msg) {
  size_t i;
  for (i = 0; i < n; i++)
    if (isnan(buff[i]) || isinf(buff[i])) {
      fprintf(stderr, err_msg);
      exit(EXIT_FAILURE);
    }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<encoderRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <writeCommand@plt>
  mov    $0x0,%eax
  call   <readInt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  neg    %eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: EDR

assistant: ```c
int encoderRight() {
  int counter = 0;
  writeCommand("EDR");
  counter = readInt();
  return -counter;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encoderRight>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <writeCommand@plt>
  mov    $0x0,%eax
  call   <readInt@plt>
  neg    %eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: EDR

assistant: ```c
int encoderRight() {
  int counter = 0;
  writeCommand("EDR");
  counter = readInt();
  return -counter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<encoderRight>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <writeCommand@plt>
  xor    %eax,%eax
  call   <readInt@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: EDR

assistant: ```c
int encoderRight() {
  int counter = 0;
  writeCommand("EDR");
  counter = readInt();
  return -counter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encoderRight>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <writeCommand@plt>
  xor    %eax,%eax
  call   <readInt@plt>
  add    $0x8,%rsp
  neg    %eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: EDR

assistant: ```c
int encoderRight() {
  int counter = 0;
  writeCommand("EDR");
  counter = readInt();
  return -counter;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <EVP_DecryptInit_ex@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x30(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <EVP_DecryptUpdate@plt>
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EVP_DecryptFinal_ex@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
unsigned char *aes_decrypt(EVP_CIPHER_CTX *e, unsigned char *ciphertext, int *len) {
  int p_len = *len, f_len = 0;
  unsigned char *plaintext = malloc(p_len + AES_BLOCK_SIZE);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, &p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, &f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdx),%edi
  mov    %edi,(%rsp)
  movl   $0x0,0x4(%rsp)
  movslq %edi,%rdi
  mov    D3(%rip),%rax
  add    (%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <EVP_DecryptInit_ex@plt>
  mov    %rsp,%rdx
  mov    (%rbx),%r8d
  mov    %r12,%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  lea    0x4(%rsp),%rdx
  movslq (%rsp),%rsi
  add    %r13,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptFinal_ex@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_decrypt(EVP_CIPHER_CTX *e, unsigned char *ciphertext, int *len) {
  int p_len = *len, f_len = 0;
  unsigned char *plaintext = malloc(p_len + AES_BLOCK_SIZE);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, &p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, &f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: What is the c source code of the assembly code below?

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movslq (%rdx),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    %edi,(%rsp)
  add    (%rax),%rdi
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_DecryptInit_ex@plt>
  mov    (%rbx),%r8d
  mov    %rsp,%rdx
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  movslq (%rsp),%rsi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <EVP_DecryptFinal_ex@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_decrypt(EVP_CIPHER_CTX *e, unsigned char *ciphertext, int *len) {
  int p_len = *len, f_len = 0;
  unsigned char *plaintext = malloc(p_len + AES_BLOCK_SIZE);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, &p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, &f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aes_decrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movslq (%rdx),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    %edi,(%rsp)
  add    (%rax),%rdi
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_DecryptInit_ex@plt>
  mov    (%rbx),%r8d
  mov    %rsp,%rdx
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_DecryptUpdate@plt>
  movslq (%rsp),%rsi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <EVP_DecryptFinal_ex@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_decrypt(EVP_CIPHER_CTX *e, unsigned char *ciphertext, int *len) {
  int p_len = *len, f_len = 0;
  unsigned char *plaintext = malloc(p_len + AES_BLOCK_SIZE);
  EVP_DecryptInit_ex(e, NULL, NULL, NULL, NULL);
  EVP_DecryptUpdate(e, plaintext, &p_len, ciphertext, *len);
  EVP_DecryptFinal_ex(e, plaintext + p_len, &f_len);
  *len = p_len + f_len;
  return plaintext;
}
```
user: What is the c source code of the assembly code below:

```asm
<crc32_ipmce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L8
L4:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <crc32_ipmce_byte@plt>
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long crc32_ipmce(unsigned long sum, unsigned const char *buf, unsigned int len) {
  if (len) {
    do {
      sum = crc32_ipmce_byte(sum, *buf++);
    } while (--len);
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crc32_ipmce>:
  endbr64
  test   %edx,%edx
  je     L16
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%edx
  lea    (%rsi,%rdx,1),%rbp
L3:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%esi
  call   <crc32_ipmce_byte@plt>
  mov    %rax,%rdi
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned long crc32_ipmce(unsigned long sum, unsigned const char *buf, unsigned int len) {
  if (len) {
    do {
      sum = crc32_ipmce_byte(sum, *buf++);
    } while (--len);
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crc32_ipmce>:
  endbr64
  test   %edx,%edx
  je     L6
  push   %rbp
  mov    %edx,%edx
  push   %rbx
  lea    (%rsi,%rdx,1),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  call   <crc32_ipmce_byte@plt>
  mov    %rax,%rdi
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned long crc32_ipmce(unsigned long sum, unsigned const char *buf, unsigned int len) {
  if (len) {
    do {
      sum = crc32_ipmce_byte(sum, *buf++);
    } while (--len);
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<crc32_ipmce>:
  endbr64
  test   %edx,%edx
  je     L15
  push   %rbp
  mov    %edx,%edx
  push   %rbx
  lea    (%rsi,%rdx,1),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  call   <crc32_ipmce_byte@plt>
  mov    %rax,%rdi
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned long crc32_ipmce(unsigned long sum, unsigned const char *buf, unsigned int len) {
  if (len) {
    do {
      sum = crc32_ipmce_byte(sum, *buf++);
    } while (--len);
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<puthex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *puthex(char *b, unsigned int dword) {
  b = puthex_tetra(b, (dword & 0xFF000000) >> 24);
  b = puthex_tetra(b, (dword & 0x00FF0000) >> 16);
  b = puthex_tetra(b, (dword & 0x0000FF00) >> 8);
  b = puthex_tetra(b, (dword & 0x000000FF));
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<puthex>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  shr    $0x18,%esi
  call   <puthex_tetra@plt>
  mov    %rax,%rdi
  mov    %ebx,%esi
  shr    $0x10,%esi
  movzbl %sil,%esi
  call   <puthex_tetra@plt>
  mov    %rax,%rdi
  movzbl %bh,%esi
  call   <puthex_tetra@plt>
  mov    %rax,%rdi
  movzbl %bl,%esi
  call   <puthex_tetra@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *puthex(char *b, unsigned int dword) {
  b = puthex_tetra(b, (dword & 0xFF000000) >> 24);
  b = puthex_tetra(b, (dword & 0x00FF0000) >> 16);
  b = puthex_tetra(b, (dword & 0x0000FF00) >> 8);
  b = puthex_tetra(b, (dword & 0x000000FF));
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<puthex>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  shr    $0x18,%esi
  call   <puthex_tetra@plt>
  mov    %ebx,%esi
  shr    $0x10,%esi
  mov    %rax,%rdi
  movzbl %sil,%esi
  call   <puthex_tetra@plt>
  movzbl %bh,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  movzbl %bl,%esi
  pop    %rbx
  mov    %rax,%rdi
  jmp    1050 <puthex_tetra@plt>
```

assistant: ```c
char *puthex(char *b, unsigned int dword) {
  b = puthex_tetra(b, (dword & 0xFF000000) >> 24);
  b = puthex_tetra(b, (dword & 0x00FF0000) >> 16);
  b = puthex_tetra(b, (dword & 0x0000FF00) >> 8);
  b = puthex_tetra(b, (dword & 0x000000FF));
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<puthex>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  shr    $0x18,%esi
  call   <puthex_tetra@plt>
  mov    %ebx,%esi
  shr    $0x10,%esi
  mov    %rax,%rdi
  movzbl %sil,%esi
  call   <puthex_tetra@plt>
  movzbl %bh,%esi
  mov    %rax,%rdi
  call   <puthex_tetra@plt>
  movzbl %bl,%esi
  pop    %rbx
  mov    %rax,%rdi
  jmp    1050 <puthex_tetra@plt>
```

assistant: ```c
char *puthex(char *b, unsigned int dword) {
  b = puthex_tetra(b, (dword & 0xFF000000) >> 24);
  b = puthex_tetra(b, (dword & 0x00FF0000) >> 16);
  b = puthex_tetra(b, (dword & 0x0000FF00) >> 8);
  b = puthex_tetra(b, (dword & 0x000000FF));
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<concatenate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void concatenate(char string1[], char string2[], char string[]) {
  int i, j;
  for (i = 0; string1[i] != '\0'; i++)
    string[i] = string1[i];
  for (j = 0; string2[j] != '\0'; j++)
    string[i + j] = string2[j];
  string[i + j] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<concatenate>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L33
  mov    $0x1,%eax
L37:
  mov    %cl,-0x1(%rdx,%rax,1)
  mov    %eax,%r8d
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L37
L39:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L55
  mov    $0x1,%eax
  movslq %r8d,%rdi
  add    %rdx,%rdi
L5:
  mov    %cl,-0x1(%rdi,%rax,1)
  mov    %eax,%r9d
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L5
L22:
  add    %r9d,%r8d
  movslq %r8d,%r8
  movb   $0x0,(%rdx,%r8,1)
  ret
L33:
  mov    $0x0,%r8d
  jmp    L39
L55:
  mov    $0x0,%r9d
  jmp    L22
```

assistant: ```c
void concatenate(char string1[], char string2[], char string[]) {
  int i, j;
  for (i = 0; string1[i] != '\0'; i++)
    string[i] = string1[i];
  for (j = 0; string2[j] != '\0'; j++)
    string[i + j] = string2[j];
  string[i + j] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<concatenate>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L34
  mov    $0x1,%eax
L33:
  mov    %cl,-0x1(%rdx,%rax,1)
  mov    %eax,%r9d
  mov    %rax,%r8
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L33
  add    %rdx,%r8
L39:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L24
  movslq %r9d,%r8
  mov    $0x1,%eax
  add    %rdx,%r8
  nopl   0x0(%rax)
L25:
  mov    %cl,-0x1(%r8,%rax,1)
  mov    %eax,%edi
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L25
  lea    (%rdi,%r9,1),%r8d
  movslq %r8d,%r8
  add    %rdx,%r8
L24:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rdx,%r8
  xor    %r9d,%r9d
  jmp    L39
```

assistant: ```c
void concatenate(char string1[], char string2[], char string[]) {
  int i, j;
  for (i = 0; string1[i] != '\0'; i++)
    string[i] = string1[i];
  for (j = 0; string2[j] != '\0'; j++)
    string[i + j] = string2[j];
  string[i + j] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<concatenate>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L39
  mov    $0x1,%eax
L35:
  mov    %cl,-0x1(%rdx,%rax,1)
  mov    %eax,%r9d
  mov    %rax,%r8
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L35
  add    %rdx,%r8
L7:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L19
  movslq %r9d,%r8
  mov    $0x1,%eax
  add    %rdx,%r8
  nopl   0x0(%rax)
L22:
  mov    %cl,-0x1(%r8,%rax,1)
  mov    %eax,%edi
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L22
  lea    (%rdi,%r9,1),%r8d
  movslq %r8d,%r8
  add    %rdx,%r8
L19:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rdx,%r8
  xor    %r9d,%r9d
  jmp    L7
```

assistant: ```c
void concatenate(char string1[], char string2[], char string[]) {
  int i, j;
  for (i = 0; string1[i] != '\0'; i++)
    string[i] = string1[i];
  for (j = 0; string2[j] != '\0'; j++)
    string[i + j] = string2[j];
  string[i + j] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lastblank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L30
L14:
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L12
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L12
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L14
L12:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lastblank(char line[], int pos) {
  while (line[pos + 1] == ' ' && line[pos + 1] != '\t' && line[pos + 1] != '\n')
    ++pos;
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lastblank>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x20,0x1(%rdi,%rax,1)
  jne    L9
  add    $0x1,%esi
  movslq %esi,%rax
L10:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x20,(%rdi,%rax,1)
  je     L10
L9:
  mov    %esi,%eax
  ret
```

assistant: ```c
int lastblank(char line[], int pos) {
  while (line[pos + 1] == ' ' && line[pos + 1] != '\t' && line[pos + 1] != '\n')
    ++pos;
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lastblank>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x20,0x1(%rdi,%rax,1)
  lea    0x1(%rax),%rdx
  jne    L1
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0x20,(%rdi,%rdx,1)
  je     L17
  ret
  nopl   (%rax)
L1:
  mov    %esi,%eax
  ret
```

assistant: ```c
int lastblank(char line[], int pos) {
  while (line[pos + 1] == ' ' && line[pos + 1] != '\t' && line[pos + 1] != '\n')
    ++pos;
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lastblank>:
  endbr64
  movslq %esi,%rax
  cmpb   $0x20,0x1(%rdi,%rax,1)
  lea    0x1(%rax),%rdx
  jne    L4
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0x20,(%rdi,%rdx,1)
  je     L17
  ret
  nopl   (%rax)
L4:
  mov    %esi,%eax
  ret
```

assistant: ```c
int lastblank(char line[], int pos) {
  while (line[pos + 1] == ' ' && line[pos + 1] != '\t' && line[pos + 1] != '\n')
    ++pos;
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L16
L4:
  mov    %rbx,%rax
  shl    $0x5,%rax
  lea    (%rax,%rbx,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    (%rcx,%rax,1),%rbx
L16:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L4
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long hashf(unsigned char const *mem, size_t size) {
  register unsigned long i = 0;
  while (size--)
    i = i * 33 + *mem++;
  return i;
}
```