ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D5(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L43:
  test   %rcx,%rcx
  je     L58
  mov    $0xffffffffffffffff,%rax
  cqto
  idiv   %rcx
L42:
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L62:
  add    $0x1,%rbx
L0:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L58
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  test   %rax,%rax
  je     L43
  sub    $0x1,%rax
  cqto
  idiv   %rcx
  cmp    $0x1a,%rax
  jle    L42
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L62
  nopl   (%rax)
L58:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D21
type_guessed: string

tool: D5: Case %lld: %lld


tool: D8: Case %lld: impossible


tool: D21: %lld %lld

assistant: ```c
int main() {
  long long int n, r, temp, i = 1;
  while (scanf("%lld %lld", &r, &n) == 2) {
    if (r == 0 && n == 0)
      break;
    temp = (r - 1) / n;
    if (temp > 26)
      printf("Case %lld: impossible\n", i);
    else
      printf("Case %lld: %lld\n", i, temp);
    i++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcn5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L16:
  mov    -0x8(%rbp),%eax
  lea    0x5(%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  imul   -0x8(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x4(%rbp)
  addl   $0x3,-0x8(%rbp)
L19:
  cmpl   $0x63,-0x8(%rbp)
  jle    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fcn5() {
  int count, other;
  for (count = 0; count < 100; count += 3) {
    other = count % (count + 5);
    other /= count * (count * count * count);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fcn5>:
  endbr64
  mov    $0x22,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  ret
```

assistant: ```c
void fcn5() {
  int count, other;
  for (count = 0; count < 100; count += 3) {
    other = count % (count + 5);
    other /= count * (count * count * count);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fcn5>:
  endbr64
  ret
```

assistant: ```c
void fcn5() {
  int count, other;
  for (count = 0; count < 100; count += 3) {
    other = count % (count + 5);
    other /= count * (count * count * count);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fcn5>:
  endbr64
  ret
```

assistant: ```c
void fcn5() {
  int count, other;
  for (count = 0; count < 100; count += 3) {
    other = count % (count + 5);
    other /= count * (count * count * count);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<phi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x1,-0x18(%rbp)
  jne    L76
  mov    $0x0,%eax
  jmp    L19
L76:
  movl   $0x2,-0x8(%rbp)
  jmp    L38
L37:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L6
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  sub    %eax,-0xc(%rbp)
  jmp    L6
L78:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x18(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  je     L78
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jae    L37
  cmpq   $0x1,-0x18(%rbp)
  jbe    L14
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <phi>
  add    $0x1,%eax
L19:
  leave
  ret
```

assistant: ```c
int phi(unsigned long long n) {
  int result = n, count = 0;
  int i;
  if (n == 1)
    return 0;
  for (i = 2; i * i <= n; i++) {
    if (n % i == 0)
      result -= result / i;
    while (n % i == 0)
      n /= i;
  }
  if (n > 1)
    result -= result / n;
  return 1 + phi(result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<phi>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rdi
  je     L0
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %edi,%r8d
  cmp    $0x3,%rdi
  jbe    L45
  mov    $0x2,%esi
  jmp    L55
L31:
  mov    %r8d,%eax
  cltd
  idiv   %esi
  sub    %eax,%r8d
L36:
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,%rcx
  mov    $0x0,%edx
  div    %rsi
  test   %rdx,%rdx
  je     L36
L58:
  lea    0x1(%rdi),%eax
  add    $0x1,%rsi
  imul   %eax,%eax
  cltq
  cmp    %rcx,%rax
  ja     L45
L55:
  mov    %esi,%edi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  test   %rdx,%rdx
  jne    L58
  jmp    L31
L45:
  cmp    $0x1,%rcx
  jbe    L68
  movslq %r8d,%rax
  mov    $0x0,%edx
  div    %rcx
  sub    %eax,%r8d
L68:
  movslq %r8d,%rdi
  call   <phi>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
int phi(unsigned long long n) {
  int result = n, count = 0;
  int i;
  if (n == 1)
    return 0;
  for (i = 2; i * i <= n; i++) {
    if (n % i == 0)
      result -= result / i;
    while (n % i == 0)
      n /= i;
  }
  if (n > 1)
    result -= result / n;
  return 1 + phi(result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<phi>:
  endbr64
  mov    %rdi,%rcx
  mov    %edi,%r8d
  cmp    $0x1,%rdi
  je     L9
  mov    $0x1,%r9d
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x2,%esi
  cmp    $0x3,%rcx
  jbe    L11
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rcx,%rax
  xor    %edx,%edx
  mov    %esi,%edi
  div    %rsi
  test   %rdx,%rdx
  jne    L48
  mov    %r8d,%eax
  cltd
  idiv   %esi
  sub    %eax,%r8d
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  xor    %edx,%edx
  mov    %rax,%rcx
  div    %rsi
  test   %rdx,%rdx
  je     L27
L48:
  add    $0x1,%edi
  add    $0x1,%rsi
  imul   %edi,%edi
  movslq %edi,%rdi
  cmp    %rcx,%rdi
  jbe    L17
L11:
  cmp    $0x1,%rcx
  jbe    L15
  movslq %r8d,%rax
  xor    %edx,%edx
  div    %rcx
  sub    %eax,%r8d
L15:
  mov    %r9d,%eax
  movslq %r8d,%rcx
  add    $0x1,%r9d
  cmp    $0x1,%r8d
  jne    L12
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int phi(unsigned long long n) {
  int result = n, count = 0;
  int i;
  if (n == 1)
    return 0;
  for (i = 2; i * i <= n; i++) {
    if (n % i == 0)
      result -= result / i;
    while (n % i == 0)
      n /= i;
  }
  if (n > 1)
    result -= result / n;
  return 1 + phi(result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<phi>:
  endbr64
  mov    %rdi,%rcx
  mov    %edi,%r8d
  cmp    $0x1,%rdi
  je     L79
  mov    $0x1,%r9d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    $0x2,%esi
  cmp    $0x3,%rcx
  jbe    L37
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rcx,%rax
  xor    %edx,%edx
  mov    %esi,%edi
  div    %rsi
  test   %rdx,%rdx
  jne    L67
  mov    %r8d,%eax
  cltd
  idiv   %esi
  sub    %eax,%r8d
  nopl   0x0(%rax,%rax,1)
L76:
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  xor    %edx,%edx
  mov    %rax,%rcx
  div    %rsi
  test   %rdx,%rdx
  je     L76
L67:
  add    $0x1,%edi
  add    $0x1,%rsi
  imul   %edi,%edi
  movslq %edi,%rdi
  cmp    %rcx,%rdi
  jbe    L32
L37:
  cmp    $0x1,%rcx
  jbe    L74
  movslq %r8d,%rax
  xor    %edx,%edx
  div    %rcx
  sub    %eax,%r8d
  mov    %r9d,%eax
  add    $0x1,%r9d
  movslq %r8d,%rcx
  cmp    $0x1,%r8d
  jne    L19
  ret
L74:
  mov    %r9d,%eax
  movslq %r8d,%rcx
  add    $0x1,%r9d
  cmp    $0x1,%r8d
  jne    L19
  ret
L79:
  xor    %eax,%eax
  ret
```

assistant: ```c
int phi(unsigned long long n) {
  int result = n, count = 0;
  int i;
  if (n == 1)
    return 0;
  for (i = 2; i * i <= n; i++) {
    if (n % i == 0)
      result -= result / i;
    while (n % i == 0)
      n /= i;
  }
  if (n > 1)
    result -= result / n;
  return 1 + phi(result);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<time_pretty>:
  endbr64
  push   %rbx
  mov    %edi,%r9d
  mov    %rsi,%rbx
  movb   $0x0,(%rsi)
  mov    $0x0,%eax
  cmp    $0x15180,%edi
  jle    L24
  movslq %edi,%rax
  imul   $0xffffffffc22e4507,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x10,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0xfffeae80,%eax,%edx
  add    %edx,%r9d
L24:
  mov    $0x0,%esi
  cmp    $0xe10,%r9d
  jle    L1
  movslq %r9d,%rsi
  imul   $0xffffffff91a2b3c5,%rsi,%rsi
  shr    $0x20,%rsi
  add    %r9d,%esi
  sar    $0xb,%esi
  mov    %r9d,%edx
  sar    $0x1f,%edx
  sub    %edx,%esi
  imul   $0xfffff1f0,%esi,%edx
  add    %edx,%r9d
L1:
  mov    $0x0,%edx
  cmp    $0x3c,%r9d
  jle    L57
  movslq %r9d,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r9d,%edx
  sar    $0x5,%edx
  mov    %r9d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%edi
  shl    $0x4,%edi
  mov    %edx,%ecx
  sub    %edi,%ecx
  lea    (%r9,%rcx,4),%r9d
L57:
  test   %eax,%eax
  jne    L78
  test   %esi,%esi
  jne    L82
  test   %edx,%edx
  je     L26
  mov    %r9d,%ecx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L11
L78:
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    %eax,%edx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L11:
  mov    %rbx,%rax
  pop    %rbx
  ret
L82:
  mov    %r9d,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L11
L26:
  mov    %r9d,%edx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D34
type_guessed: string
name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D0: %dm %ds

tool: D11: %dd %dh %dm %ds

tool: D34: %dh %dm %ds

tool: D5: %ds

assistant: ```c
char *time_pretty(int32_t time, char *buffer, int32_t size) {
  int32_t days = 0, hours = 0, minutes = 0, seconds = 0;
  buffer[0] = '\0';
  if (time > (24 * 60 * 60)) {
    days = time / (24 * 60 * 60);
    time -= (days * 24 * 60 * 60);
  }
  if (time > (60 * 60)) {
    hours = time / (60 * 60);
    time -= (hours * 60 * 60);
  }
  if (time > 60) {
    minutes = time / 60;
    time -= (minutes * 60);
  }
  seconds = time;
  if (days) {
    sprintf(buffer, "%dd %dh %dm %ds", days, hours, minutes, seconds);
  } else if (hours) {
    sprintf(buffer, "%dh %dm %ds", hours, minutes, seconds);
  } else if (minutes) {
    sprintf(buffer, "%dm %ds", minutes, seconds);
  } else {
    sprintf(buffer, "%ds", seconds);
  }
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MwSnprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int MwSnprintf(char *str, size_t n, const char *format, ...) {
  int m;
  va_list ap;
  va_start(ap, format);
  m = vsprintf(str, format, ap);
  va_end(ap);
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<MwSnprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int MwSnprintf(char *str, size_t n, const char *format, ...) {
  int m;
  va_list ap;
  va_start(ap, format);
  m = vsprintf(str, format, ap);
  va_end(ap);
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MwSnprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int MwSnprintf(char *str, size_t n, const char *format, ...) {
  int m;
  va_list ap;
  va_start(ap, format);
  m = vsprintf(str, format, ap);
  va_end(ap);
  return m;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MwSnprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int MwSnprintf(char *str, size_t n, const char *format, ...) {
  int m;
  va_list ap;
  va_start(ap, format);
  m = vsprintf(str, format, ap);
  va_end(ap);
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<diff_dc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x40,-0x8(%rbp)
  jmp    L16
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x40,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void diff_dc(int num_pixel, int dct_quant[]) {
  int i;
  int last = dct_quant[0];
  for (i = 64; i < num_pixel; i += 64) {
    dct_quant[i] -= last;
    last += dct_quant[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<diff_dc>:
  endbr64
  mov    (%rsi),%edx
  cmp    $0x40,%edi
  jle    L11
  lea    0x100(%rsi),%rax
  sub    $0x41,%edi
  shr    $0x6,%edi
  mov    %edi,%edi
  shl    $0x8,%rdi
  lea    0x200(%rsi,%rdi,1),%rdi
L19:
  mov    %edx,%esi
  mov    (%rax),%edx
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,(%rax)
  add    $0x100,%rax
  cmp    %rdi,%rax
  jne    L19
L11:
  ret
```

assistant: ```c
void diff_dc(int num_pixel, int dct_quant[]) {
  int i;
  int last = dct_quant[0];
  for (i = 64; i < num_pixel; i += 64) {
    dct_quant[i] -= last;
    last += dct_quant[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<diff_dc>:
  endbr64
  mov    (%rsi),%edx
  cmp    $0x40,%edi
  jle    L16
  sub    $0x41,%edi
  lea    0x100(%rsi),%rax
  shr    $0x6,%edi
  shl    $0x8,%rdi
  lea    0x200(%rsi,%rdi,1),%rdi
  nopl   0x0(%rax)
L17:
  mov    %edx,%esi
  mov    (%rax),%edx
  add    $0x100,%rax
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,-0x100(%rax)
  cmp    %rdi,%rax
  jne    L17
L16:
  ret
```

assistant: ```c
void diff_dc(int num_pixel, int dct_quant[]) {
  int i;
  int last = dct_quant[0];
  for (i = 64; i < num_pixel; i += 64) {
    dct_quant[i] -= last;
    last += dct_quant[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<diff_dc>:
  endbr64
  mov    (%rsi),%edx
  cmp    $0x40,%edi
  jle    L9
  sub    $0x41,%edi
  lea    0x100(%rsi),%rax
  shr    $0x6,%edi
  shl    $0x8,%rdi
  lea    0x200(%rsi,%rdi,1),%rdi
  nopl   0x0(%rax)
L14:
  mov    %edx,%esi
  mov    (%rax),%edx
  add    $0x100,%rax
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,-0x100(%rax)
  cmp    %rdi,%rax
  jne    L14
L9:
  ret
```

assistant: ```c
void diff_dc(int num_pixel, int dct_quant[]) {
  int i;
  int last = dct_quant[0];
  for (i = 64; i < num_pixel; i += 64) {
    dct_quant[i] -= last;
    last += dct_quant[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GF_mul_manual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    %esi,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L36
L31:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L42
  xor    -0xc(%rbp),%ebx
L42:
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L48
  shll   -0xc(%rbp)
  xorl   $0x1b,-0xc(%rbp)
  jmp    L37
L48:
  shll   -0xc(%rbp)
L37:
  sarl   -0x10(%rbp)
L36:
  cmpl   $0x0,-0x10(%rbp)
  jne    L31
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint8_t GF_mul_manual(uint8_t a, uint8_t b) {
  register uint8_t rv;
  rv = 0;
  while (b) {
    if (b & 0x01)
      rv ^= a;
    if (a & 0x80) {
      a <<= 1;
      a ^= (0x11b) & 0xFF;
    } else {
      a <<= 1;
    }
    b >>= 1;
  }
  return rv;
}
```
user: What is the c source code of the assembly code below?

```asm
<GF_mul_manual>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    $0x0,%edx
L10:
  mov    %edx,%eax
  xor    %edi,%eax
  test   $0x1,%sil
  cmovne %eax,%edx
  lea    (%rdi,%rdi,1),%eax
  xor    $0x1b,%eax
  lea    (%rdi,%rdi,1),%ecx
  test   $0x80,%dil
  cmove  %ecx,%eax
  mov    %eax,%edi
  sar    %esi
  jne    L10
L14:
  mov    %edx,%eax
  ret
L12:
  mov    %esi,%edx
  jmp    L14
```

assistant: ```c
uint8_t GF_mul_manual(uint8_t a, uint8_t b) {
  register uint8_t rv;
  rv = 0;
  while (b) {
    if (b & 0x01)
      rv ^= a;
    if (a & 0x80) {
      a <<= 1;
      a ^= (0x11b) & 0xFF;
    } else {
      a <<= 1;
    }
    b >>= 1;
  }
  return rv;
}
```
user: What is the c source code of the assembly code below?

```asm
<GF_mul_manual>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L17
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %eax,%edx
  mov    %edi,%ecx
  xor    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%eax
  add    %edi,%edi
  and    $0x80,%ecx
  mov    %edi,%edx
  xor    $0x1b,%edx
  test   %ecx,%ecx
  cmovne %edx,%edi
  sar    %esi
  jne    L18
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
uint8_t GF_mul_manual(uint8_t a, uint8_t b) {
  register uint8_t rv;
  rv = 0;
  while (b) {
    if (b & 0x01)
      rv ^= a;
    if (a & 0x80) {
      a <<= 1;
      a ^= (0x11b) & 0xFF;
    } else {
      a <<= 1;
    }
    b >>= 1;
  }
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GF_mul_manual>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L7
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %eax,%edx
  mov    %edi,%ecx
  xor    %edi,%edx
  test   $0x1,%sil
  cmovne %edx,%eax
  add    %edi,%edi
  and    $0x80,%ecx
  mov    %edi,%edx
  xor    $0x1b,%edx
  test   %ecx,%ecx
  cmovne %edx,%edi
  sar    %esi
  jne    L17
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
uint8_t GF_mul_manual(uint8_t a, uint8_t b) {
  register uint8_t rv;
  rv = 0;
  while (b) {
    if (b & 0x01)
      rv ^= a;
    if (a & 0x80) {
      a <<= 1;
      a ^= (0x11b) & 0xFF;
    } else {
      a <<= 1;
    }
    b >>= 1;
  }
  return rv;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<babl_matrix_mul_matrixf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x24,%edx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x30(%rsp),%rdi
  mov    $0x24,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  mov    $0x0,%r8d
  lea    0x3c(%rsp),%rdi
  jmp    L35
L6:
  add    $0xc,%rcx
  add    $0xc,%rsi
  add    $0x3,%r8d
  cmp    $0x9,%r8d
  je     L21
L35:
  movss  (%rcx),%xmm4
  movss  0x4(%rcx),%xmm3
  movss  0x8(%rcx),%xmm2
  lea    0x30(%rsp),%rax
  mov    %rsi,%rdx
L28:
  movaps %xmm4,%xmm0
  mulss  (%rax),%xmm0
  movaps %xmm3,%xmm1
  mulss  0xc(%rax),%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm2,%xmm1
  mulss  0x18(%rax),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  add    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rdi,%rax
  jne    L28
  jmp    L6
L21:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void babl_matrix_mul_matrixf(const float *matA_, const float *matB_, float *out) {
  int i, j;
  float matA[9];
  float matB[9];
  float t1, t2, t3;
  memcpy(matA, matA_, sizeof(matA));
  memcpy(matB, matB_, sizeof(matB));
  for (i = 0; i < 3; i++) {
    t1 = matA[i * 3 + 0];
    t2 = matA[i * 3 + 1];
    t3 = matA[i * 3 + 2];
    for (j = 0; j < 3; j++) {
      out[i * 3 + j] = t1 * matB[0 * 3 + j];
      out[i * 3 + j] += t2 * matB[1 * 3 + j];
      out[i * 3 + j] += t3 * matB[2 * 3 + j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<babl_matrix_mul_matrixf>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x24,%edx
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x24,%edx
  call   <memcpy@plt>
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  xor    %r8d,%r8d
  lea    0x3c(%rsp),%rdi
L12:
  movss  (%rcx),%xmm4
  movss  0x4(%rcx),%xmm3
  mov    %r12,%rax
  mov    %rsi,%rdx
  movss  0x8(%rcx),%xmm2
L6:
  movss  (%rax),%xmm0
  movss  0xc(%rax),%xmm1
  add    $0x4,%rax
  add    $0x4,%rdx
  mulss  %xmm3,%xmm1
  mulss  %xmm4,%xmm0
  addss  %xmm1,%xmm0
  movss  0x14(%rax),%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdx)
  cmp    %rax,%rdi
  jne    L6
  add    $0x3,%r8d
  add    $0xc,%rcx
  add    $0xc,%rsi
  cmp    $0x9,%r8d
  jne    L12
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void babl_matrix_mul_matrixf(const float *matA_, const float *matB_, float *out) {
  int i, j;
  float matA[9];
  float matB[9];
  float t1, t2, t3;
  memcpy(matA, matA_, sizeof(matA));
  memcpy(matB, matB_, sizeof(matB));
  for (i = 0; i < 3; i++) {
    t1 = matA[i * 3 + 0];
    t2 = matA[i * 3 + 1];
    t3 = matA[i * 3 + 2];
    for (j = 0; j < 3; j++) {
      out[i * 3 + j] = t1 * matB[0 * 3 + j];
      out[i * 3 + j] += t2 * matB[1 * 3 + j];
      out[i * 3 + j] += t3 * matB[2 * 3 + j];
    }
  }
}
```