ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<rma>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  test   %edx,%edx
  jle    L84
  mov    %rdi,%r12
  mov    $0x0,%esi
  pxor   %xmm0,%xmm0
  mov    $0x0,%ebp
  lea    -0x1(%rbx),%r8d
  lea    0x4(%rdi),%rdi
  jmp    L88
L91:
  movslq %esi,%rcx
  lea    (%r12,%rcx,4),%rax
  add    %r8,%rcx
  lea    (%rdi,%rcx,4),%rcx
L30:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rax),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L30
L45:
  lea    0x1(%rbp),%eax
  add    %ebx,%esi
  cmp    %eax,%edx
  je     L41
  mov    %eax,%ebp
L88:
  test   %ebx,%ebx
  jg     L91
  jmp    L45
L51:
  movslq %esi,%rdx
  lea    (%r12,%rdx,4),%rax
  add    %r8,%rdx
  lea    (%rdi,%rdx,4),%rdx
L81:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  subsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L81
L10:
  lea    0x1(%rcx),%eax
  add    %ebx,%esi
  cmp    %ecx,%ebp
  je     L1
  mov    %eax,%ecx
L18:
  test   %ebx,%ebx
  jg     L51
  jmp    L10
L41:
  imul   %ebx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  lea    D0(%rip),%rdi
  call   <vmess@plt>
  mov    $0x0,%esi
  mov    $0x0,%ecx
  lea    -0x1(%rbx),%r8d
  lea    0x4(%r12),%rdi
  jmp    L18
L84:
  imul   %esi,%edx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  lea    D0(%rip),%rdi
  call   <vmess@plt>
L1:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: average value subtracted: %f

assistant: ```c
void rma(float *data, int nsam, int nrec) {
  int ix, it;
  double avg = 0.0;
  for (ix = 0; ix < nrec; ix++)
    for (it = 0; it < nsam; it++)
      avg += data[ix * nsam + it];
  avg /= nrec * nsam;
  vmess("average value subtracted: %f", avg);
  for (ix = 0; ix < nrec; ix++)
    for (it = 0; it < nsam; it++)
      data[ix * nsam + it] -= avg;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rma>:
  endbr64
  mov    %edx,%eax
  pxor   %xmm2,%xmm2
  imul   %esi,%eax
  cvtsi2sd %eax,%xmm2
  test   %edx,%edx
  jle    L23
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x4(%rdi),%rdi
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  lea    -0x1(%rbx),%r8d
  sub    $0x10,%rsp
  nopw   0x0(%rax,%rax,1)
L38:
  test   %ebx,%ebx
  jle    L24
  movslq %esi,%rcx
  lea    0x0(%rbp,%rcx,4),%rax
  add    %r8,%rcx
  lea    (%rdi,%rcx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L14:
  pxor   %xmm1,%xmm1
  add    $0x4,%rax
  cvtss2sd -0x4(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L14
L24:
  lea    0x1(%r12),%eax
  add    %ebx,%esi
  cmp    %eax,%edx
  je     L54
  mov    %eax,%r12d
  jmp    L38
  xchg   %ax,%ax
L54:
  movapd %xmm0,%xmm1
  lea    D2(%rip),%rdi
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <vmess@plt>
  movsd  0x8(%rsp),%xmm1
  xor    %esi,%esi
  xor    %ecx,%ecx
  lea    -0x1(%rbx),%r8d
  lea    0x4(%rbp),%rdi
L64:
  test   %ebx,%ebx
  jle    L78
  movslq %esi,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  add    %r8,%rdx
  lea    (%rdi,%rdx,4),%rdx
  nopl   0x0(%rax,%rax,1)
L26:
  pxor   %xmm0,%xmm0
  add    $0x4,%rax
  cvtss2sd -0x4(%rax),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rax)
  cmp    %rax,%rdx
  jne    L26
L78:
  lea    0x1(%rcx),%eax
  add    %ebx,%esi
  cmp    %r12d,%ecx
  je     L33
  mov    %eax,%ecx
  jmp    L64
  nopl   (%rax)
L33:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  pxor   %xmm0,%xmm0
  lea    D2(%rip),%rdi
  divsd  %xmm2,%xmm0
  jmp    1050 <vmess@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: average value subtracted: %f

assistant: ```c
void rma(float *data, int nsam, int nrec) {
  int ix, it;
  double avg = 0.0;
  for (ix = 0; ix < nrec; ix++)
    for (it = 0; it < nsam; it++)
      avg += data[ix * nsam + it];
  avg /= nrec * nsam;
  vmess("average value subtracted: %f", avg);
  for (ix = 0; ix < nrec; ix++)
    for (it = 0; it < nsam; it++)
      data[ix * nsam + it] -= avg;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<net_initSocket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L3
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int net_initSocket(struct sockaddr_in *name, const char *host, int port) {
  struct hostent *hostinfo;
  name->sin_family = AF_INET;
  name->sin_port = htons(port);
  hostinfo = gethostbyname(host);
  if (hostinfo == NULL) {
    return -1;
  }
  name->sin_addr = *(struct in_addr *)hostinfo->h_addr;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<net_initSocket>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%edi
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  call   <htons@plt>
  mov    %eax,0x4(%rbx)
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L3
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int net_initSocket(struct sockaddr_in *name, const char *host, int port) {
  struct hostent *hostinfo;
  name->sin_family = AF_INET;
  name->sin_port = htons(port);
  hostinfo = gethostbyname(host);
  if (hostinfo == NULL) {
    return -1;
  }
  name->sin_addr = *(struct in_addr *)hostinfo->h_addr;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<net_initSocket>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  call   <htons@plt>
  mov    %rbp,%rdi
  mov    %eax,0x4(%rbx)
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L14
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int net_initSocket(struct sockaddr_in *name, const char *host, int port) {
  struct hostent *hostinfo;
  name->sin_family = AF_INET;
  name->sin_port = htons(port);
  hostinfo = gethostbyname(host);
  if (hostinfo == NULL) {
    return -1;
  }
  name->sin_addr = *(struct in_addr *)hostinfo->h_addr;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<net_initSocket>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  call   <htons@plt>
  mov    %rbp,%rdi
  mov    %eax,0x4(%rbx)
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L17
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int net_initSocket(struct sockaddr_in *name, const char *host, int port) {
  struct hostent *hostinfo;
  name->sin_family = AF_INET;
  name->sin_port = htons(port);
  hostinfo = gethostbyname(host);
  if (hostinfo == NULL) {
    return -1;
  }
  name->sin_addr = *(struct in_addr *)hostinfo->h_addr;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D19
type_guessed: string

tool: D13: hello

tool: D18: world

tool: D19: 


assistant: ```c
main() {
  printf("hello");
  printf("world");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D21
type: string

tool: D20: hello

tool: D28: world

tool: D21: 


assistant: ```c
main() {
  printf("hello");
  printf("world");
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D8: hello

tool: D4: world

tool: D12: 


assistant: ```c
main() {
  printf("hello");
  printf("world");
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D20: hello

tool: D16: world

tool: D10: 


assistant: ```c
main() {
  printf("hello");
  printf("world");
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_keydefs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: What is the c source code of the assembly code below:

```asm
<gen_keydefs>:
  endbr64
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gen_keydefs>:
  endbr64
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<nCrModpLucas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L8
L18:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,%esi
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,%ecx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%edi
  call   <nCrModpLucas>
  mov    %eax,%ebx
  mov    -0x2c(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nCrModpDP@plt>
  imul   %ebx,%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int nCrModpLucas(int n, int r, int p) {
  if (r == 0)
    return 1;
  int ni = n % p, ri = r % p;
  return (nCrModpLucas(n / p, r / p, p) * nCrModpDP(ni, ri, p)) % p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nCrModpLucas>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  mov    $0x1,%edx
  test   %esi,%esi
  jne    L15
L13:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %edi,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r12d
  mov    %eax,%edi
  mov    %esi,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r13d
  mov    %eax,%esi
  mov    %ebx,%edx
  call   <nCrModpLucas>
  mov    %eax,%ebp
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <nCrModpDP@plt>
  imul   %ebp,%eax
  cltd
  idiv   %ebx
  jmp    L13
```

assistant: ```c
int nCrModpLucas(int n, int r, int p) {
  if (r == 0)
    return 1;
  int ni = n % p, ri = r % p;
  return (nCrModpLucas(n / p, r / p, p) * nCrModpDP(ni, ri, p)) % p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nCrModpLucas>:
  endbr64
  test   %esi,%esi
  jne    L7
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L7:
  mov    %edi,%eax
  push   %r15
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  cltd
  idiv   %ebx
  sub    $0x18,%rsp
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%ebp
  cltd
  idiv   %ebx
  mov    %edx,%r12d
  mov    %eax,%esi
  test   %eax,%eax
  je     L27
  mov    %edi,%eax
  mov    $0x1,%r15d
  cltd
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r13d
  cltd
  idiv   %ebx
  mov    %edx,%r14d
  mov    %eax,%esi
  test   %eax,%eax
  jne    L24
L19:
  mov    %ebx,%edx
  mov    %r13d,%edi
  mov    %r14d,%esi
  call   <nCrModpDP@plt>
  imul   %r15d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r13d
L27:
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <nCrModpDP@plt>
  add    $0x18,%rsp
  imul   %r13d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  mov    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %edi,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %ebx
  mov    %edx,%r9d
  mov    %eax,%esi
  test   %eax,%eax
  je     L11
  mov    %edi,%eax
  mov    %edx,0xc(%rsp)
  cltd
  mov    %r8d,0x8(%rsp)
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r15d
  cltd
  idiv   %ebx
  mov    %edx,0x4(%rsp)
  mov    %eax,%esi
  mov    %ebx,%edx
  call   <nCrModpLucas>
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %r15d,%edi
  mov    %eax,(%rsp)
  call   <nCrModpDP@plt>
  imul   (%rsp),%eax
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  cltd
  idiv   %ebx
  mov    %edx,%r15d
L11:
  mov    %ebx,%edx
  mov    %r9d,%esi
  mov    %r8d,%edi
  call   <nCrModpDP@plt>
  imul   %r15d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r15d
  jmp    L19
```

assistant: ```c
int nCrModpLucas(int n, int r, int p) {
  if (r == 0)
    return 1;
  int ni = n % p, ri = r % p;
  return (nCrModpLucas(n / p, r / p, p) * nCrModpDP(ni, ri, p)) % p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nCrModpLucas>:
  endbr64
  test   %esi,%esi
  jne    L32
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L32:
  mov    %edi,%eax
  push   %r15
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  cltd
  idiv   %ebx
  sub    $0x18,%rsp
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%ebp
  cltd
  idiv   %ebx
  mov    %edx,%r12d
  mov    %eax,%esi
  test   %eax,%eax
  je     L40
  mov    %edi,%eax
  mov    $0x1,%r15d
  cltd
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r13d
  cltd
  idiv   %ebx
  mov    %edx,%r14d
  mov    %eax,%esi
  test   %eax,%eax
  jne    L19
L13:
  mov    %ebx,%edx
  mov    %r13d,%edi
  mov    %r14d,%esi
  call   <nCrModpDP@plt>
  imul   %r15d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r13d
L40:
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <nCrModpDP@plt>
  add    $0x18,%rsp
  imul   %r13d,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  mov    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %edi,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %ebx
  mov    %edx,%r9d
  mov    %eax,%esi
  test   %eax,%eax
  je     L1
  mov    %edi,%eax
  mov    %edx,0xc(%rsp)
  cltd
  mov    %r8d,0x8(%rsp)
  idiv   %ebx
  mov    %eax,%edi
  mov    %esi,%eax
  mov    %edx,%r15d
  cltd
  idiv   %ebx
  mov    %edx,0x4(%rsp)
  mov    %eax,%esi
  mov    %ebx,%edx
  call   <nCrModpLucas>
  mov    0x4(%rsp),%esi
  mov    %ebx,%edx
  mov    %r15d,%edi
  mov    %eax,(%rsp)
  call   <nCrModpDP@plt>
  imul   (%rsp),%eax
  mov    0xc(%rsp),%r9d
  mov    0x8(%rsp),%r8d
  cltd
  idiv   %ebx
  mov    %edx,%r15d
L1:
  mov    %ebx,%edx
  mov    %r9d,%esi
  mov    %r8d,%edi
  call   <nCrModpDP@plt>
  imul   %r15d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r15d
  jmp    L13
```

assistant: ```c
int nCrModpLucas(int n, int r, int p) {
  if (r == 0)
    return 1;
  int ni = n % p, ri = r % p;
  return (nCrModpLucas(n / p, r / p, p) * nCrModpDP(ni, ri, p)) % p;
}
```
user: What is the c source code of the assembly code below:

```asm
<isoptype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x3d,-0x4(%rbp)
  je     L92
  cmpb   $0x2b,-0x4(%rbp)
  je     L92
  cmpb   $0x2d,-0x4(%rbp)
  je     L92
  cmpb   $0x40,-0x4(%rbp)
  je     L92
  cmpb   $0x7c,-0x4(%rbp)
  je     L92
  cmpb   $0x5e,-0x4(%rbp)
  je     L92
  cmpb   $0x26,-0x4(%rbp)
  je     L92
  cmpb   $0x2a,-0x4(%rbp)
  je     L92
  cmpb   $0x2f,-0x4(%rbp)
  je     L92
  cmpb   $0x3c,-0x4(%rbp)
  je     L92
  cmpb   $0x3e,-0x4(%rbp)
  je     L92
  cmpb   $0x21,-0x4(%rbp)
  je     L92
  cmpb   $0x7e,-0x4(%rbp)
  je     L92
  cmpb   $0x25,-0x4(%rbp)
  jne    L119
L92:
  mov    $0x1,%eax
  jmp    L5
L119:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int isoptype(char c) {
  if (c == '=' || c == '+' || c == '-' || c == '@' || c == '|' || c == '^' || c == '&' || c == '*' || c == '/' || c == '<' || c == '>' || c == '!' || c == '~' || c == '%')
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isoptype>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%dil
  jg     L15
  cmp    $0x20,%dil
  jg     L17
  mov    $0x0,%eax
  ret
L17:
  movabs $0x7000ac6200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L15:
  sub    $0x40,%ecx
  movabs $0x5000000040000001,%rdx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  cmp    $0x3f,%cl
  mov    $0x0,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int isoptype(char c) {
  if (c == '=' || c == '+' || c == '-' || c == '@' || c == '|' || c == '^' || c == '&' || c == '*' || c == '/' || c == '<' || c == '>' || c == '!' || c == '~' || c == '%')
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isoptype>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%dil
  jg     L10
  cmp    $0x20,%dil
  jg     L0
  xor    %eax,%eax
  ret
  nopl   (%rax)
L10:
  movabs $0x5000000040000001,%rdx
  sub    $0x40,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3f,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  movabs $0x7000ac6200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int isoptype(char c) {
  if (c == '=' || c == '+' || c == '-' || c == '@' || c == '|' || c == '^' || c == '&' || c == '*' || c == '/' || c == '<' || c == '>' || c == '!' || c == '~' || c == '%')
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isoptype>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%dil
  jg     L18
  cmp    $0x20,%dil
  jg     L15
  xor    %eax,%eax
  ret
  nopl   (%rax)
L18:
  movabs $0x5000000040000001,%rdx
  sub    $0x40,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3f,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movabs $0x7000ac6200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int isoptype(char c) {
  if (c == '=' || c == '+' || c == '-' || c == '@' || c == '|' || c == '^' || c == '&' || c == '*' || c == '/' || c == '<' || c == '>' || c == '!' || c == '~' || c == '%')
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<om2roLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  movq   $0x9,-0x20(%rbp)
  movq   $0x4,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L8
L19:
  mov    -0x28(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <om2ro@plt>
  mov    %eax,-0x2c(%rbp)
  addq   $0x1,-0x28(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L19
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int om2roLoop(double *om, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, omstep = 9, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(omstep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * omstep;
    iOut = i * rostep;
    trash = om2ro(&(om[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<om2roLoop>:
  endbr64
  test   %rdx,%rdx
  je     L6
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%r14d
L12:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <om2ro@plt>
  add    $0x1,%r14
  add    $0x48,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L12
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int om2roLoop(double *om, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, omstep = 9, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(omstep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * omstep;
    iOut = i * rostep;
    trash = om2ro(&(om[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<om2roLoop>:
  endbr64
  test   %rdx,%rdx
  je     L14
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  call   <om2ro@plt>
  add    $0x48,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L2
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int om2roLoop(double *om, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, omstep = 9, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(omstep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * omstep;
    iOut = i * rostep;
    trash = om2ro(&(om[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```