ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  mov    %ebx,%edx
  mov    %ebx,%esi
  add    $0x1,%ebx
  mov    %r12d,%edi
  call   <mpz_ui_pow_ui@plt>
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    %edi,%esi
  call   <mpz_add@plt>
  cmp    $0x3e9,%ebx
  jne    L3
  mov    %rsp,%r8
  xor    %edx,%edx
  lea    D7(%rip),%rsi
  mov    %r8,%rdi
  call   <gmp_asprintf@plt>
  mov    (%rsp),%rdx
  lea    D2(%rip),%rdi
  cltq
  lea    -0xa(%rdx,%rax,1),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D7: %Zd

tool: D2: %s


assistant: ```c
int main(void) {
  int i;
  char *s = NULL;
  mpz_t n, temp;
  mpz_init(n);
  mpz_init(temp);
  for (i = 1; i <= 1000; i++) {
    mpz_ui_pow_ui(temp, i, i);
    mpz_add(n, n, temp);
  }
  i = gmp_asprintf(&s, "%Zd", n);
  printf("%s\n", s + i - 10);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %r12d,%r12d
  mov    %ebx,%edx
  mov    %ebx,%esi
  add    $0x1,%ebx
  mov    %r12d,%edi
  call   <mpz_ui_pow_ui@plt>
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    %edi,%esi
  call   <mpz_add@plt>
  cmp    $0x3e9,%ebx
  jne    L7
  mov    %rsp,%r8
  xor    %edx,%edx
  lea    D10(%rip),%rsi
  mov    %r8,%rdi
  call   <gmp_asprintf@plt>
  mov    (%rsp),%rdx
  lea    D15(%rip),%rdi
  cltq
  lea    -0xa(%rdx,%rax,1),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D10: %Zd

tool: D15: %s


assistant: ```c
int main(void) {
  int i;
  char *s = NULL;
  mpz_t n, temp;
  mpz_init(n);
  mpz_init(temp);
  for (i = 1; i <= 1000; i++) {
    mpz_ui_pow_ui(temp, i, i);
    mpz_add(n, n, temp);
  }
  i = gmp_asprintf(&s, "%Zd", n);
  printf("%s\n", s + i - 10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<menu1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exibeMenuAnt@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: ATUAL: 1


assistant: ```c
void menu1(int at) {
  exibeMenuAnt(at);
  printf("ATUAL: 1\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<menu1>:
  endbr64
  sub    $0x8,%rsp
  call   <exibeMenuAnt@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: ATUAL: 1


assistant: ```c
void menu1(int at) {
  exibeMenuAnt(at);
  printf("ATUAL: 1\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<menu1>:
  endbr64
  sub    $0x8,%rsp
  call   <exibeMenuAnt@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: ATUAL: 1


assistant: ```c
void menu1(int at) {
  exibeMenuAnt(at);
  printf("ATUAL: 1\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<menu1>:
  endbr64
  sub    $0x8,%rsp
  call   <exibeMenuAnt@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: ATUAL: 1


assistant: ```c
void menu1(int at) {
  exibeMenuAnt(at);
  printf("ATUAL: 1\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrop3_132_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_132_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ T;
  stk2 = ~stk2;
  stk1 = S & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_132_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    $0xffffff00,%eax
  and    %edi,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_132_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ T;
  stk2 = ~stk2;
  stk1 = S & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_132_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    $0xffffff00,%eax
  and    %edi,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_132_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ T;
  stk2 = ~stk2;
  stk1 = S & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_132_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    $0xffffff00,%eax
  and    %edi,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_132_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ T;
  stk2 = ~stk2;
  stk1 = S & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L10
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   -0x4(%rbp),%eax
  jmp    L16
L10:
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int factorial(int N) {
  if (N > 1) {
    return N * factorial(N - 1);
  } else {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L9
  ret
L9:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int factorial(int N) {
  if (N > 1) {
    return N * factorial(N - 1);
  } else {
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L9
  xchg   %ax,%ax
L14:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L14
  ret
  xchg   %ax,%ax
L9:
  ret
```

assistant: ```c
int factorial(int N) {
  if (N > 1) {
    return N * factorial(N - 1);
  } else {
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L12
  xchg   %ax,%ax
L4:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L4
  ret
  xchg   %ax,%ax
L12:
  ret
```

assistant: ```c
int factorial(int N) {
  if (N > 1) {
    return N * factorial(N - 1);
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void foo(void) {
  unsigned int a[2];
  unsigned int b[2];
  unsigned int c[2];
  unsigned int d[2];
#pragma acc kernels copyin(a) create(b) copyout(c) copy(d)
  {
    a[0] = 0;
    b[0] = 0;
    c[0] = 0;
    d[0] = 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  unsigned int a[2];
  unsigned int b[2];
  unsigned int c[2];
  unsigned int d[2];
#pragma acc kernels copyin(a) create(b) copyout(c) copy(d)
  {
    a[0] = 0;
    b[0] = 0;
    c[0] = 0;
    d[0] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  unsigned int a[2];
  unsigned int b[2];
  unsigned int c[2];
  unsigned int d[2];
#pragma acc kernels copyin(a) create(b) copyout(c) copy(d)
  {
    a[0] = 0;
    b[0] = 0;
    c[0] = 0;
    d[0] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  unsigned int a[2];
  unsigned int b[2];
  unsigned int c[2];
  unsigned int d[2];
#pragma acc kernels copyin(a) create(b) copyout(c) copy(d)
  {
    a[0] = 0;
    b[0] = 0;
    c[0] = 0;
    d[0] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L8
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int chksum(const unsigned char *buff, int n) {
  unsigned char cs = 0;
  int i;
  for (i = 1; i < n - 1; i++)
    cs += buff[i];
  return buff[n - 1] == cs;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chksum>:
  endbr64
  cmp    $0x2,%esi
  jle    L9
  lea    0x1(%rdi),%rax
  lea    -0x3(%rsi),%edx
  lea    0x2(%rdi,%rdx,1),%rcx
  mov    $0x0,%edx
L0:
  add    (%rax),%dl
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L0
L10:
  movslq %esi,%rsi
  cmp    %dl,-0x1(%rdi,%rsi,1)
  sete   %al
  movzbl %al,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
int chksum(const unsigned char *buff, int n) {
  unsigned char cs = 0;
  int i;
  for (i = 1; i < n - 1; i++)
    cs += buff[i];
  return buff[n - 1] == cs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chksum>:
  endbr64
  cmp    $0x2,%esi
  jle    L9
  lea    -0x3(%rsi),%edx
  lea    0x1(%rdi),%rax
  lea    0x2(%rdi,%rdx,1),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L7:
  add    (%rax),%dl
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L7
  movslq %esi,%rsi
  xor    %eax,%eax
  cmp    %dl,-0x1(%rdi,%rsi,1)
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movslq %esi,%rsi
  xor    %edx,%edx
  xor    %eax,%eax
  cmp    %dl,-0x1(%rdi,%rsi,1)
  sete   %al
  ret
```

assistant: ```c
int chksum(const unsigned char *buff, int n) {
  unsigned char cs = 0;
  int i;
  for (i = 1; i < n - 1; i++)
    cs += buff[i];
  return buff[n - 1] == cs;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<chksum>:
  endbr64
  lea    -0x1(%rsi),%r8d
  mov    %rdi,%rdx
  cmp    $0x1,%r8d
  jle    L85
  lea    -0x3(%rsi),%eax
  lea    -0x2(%rsi),%r9d
  cmp    $0xe,%eax
  jbe    L125
  mov    %r9d,%ecx
  lea    0x1(%rdi),%rax
  pxor   %xmm0,%xmm0
  shr    $0x4,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x11(%rdi,%rcx,1),%rcx
  nop
L21:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddb  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L21
  movdqa %xmm0,%xmm1
  mov    %r9d,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffff0,%edi
  paddb  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  lea    0x1(%rdi),%ecx
  psadbw %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edi,%r9d
  je     L34
L15:
  mov    %esi,%r9d
  sub    %edi,%r9d
  lea    -0x2(%r9),%r10d
  sub    $0x3,%r9d
  cmp    $0x6,%r9d
  jbe    L95
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  movq   (%rdx,%rdi,1),%xmm1
  movdqa %xmm1,%xmm3
  psadbw %xmm0,%xmm3
  movq   %xmm3,%rdi
  movq   %xmm3,-0x10(%rsp)
  mov    %edi,%r9d
  mov    %r10d,%edi
  and    $0xfffffff8,%edi
  add    %r9d,%eax
  add    %edi,%ecx
  cmp    %edi,%r10d
  je     L34
L95:
  movslq %ecx,%rdi
  add    (%rdx,%rdi,1),%al
  lea    0x1(%rcx),%edi
  cmp    %r8d,%edi
  jge    L34
  movslq %edi,%rdi
  add    (%rdx,%rdi,1),%al
  lea    0x2(%rcx),%edi
  cmp    %r8d,%edi
  jge    L34
  movslq %edi,%rdi
  add    (%rdx,%rdi,1),%al
  lea    0x3(%rcx),%edi
  cmp    %edi,%r8d
  jle    L34
  movslq %edi,%rdi
  add    (%rdx,%rdi,1),%al
  lea    0x4(%rcx),%edi
  cmp    %edi,%r8d
  jle    L34
  movslq %edi,%rdi
  add    (%rdx,%rdi,1),%al
  lea    0x5(%rcx),%edi
  cmp    %edi,%r8d
  jle    L34
  movslq %edi,%rdi
  add    $0x6,%ecx
  add    (%rdx,%rdi,1),%al
  cmp    %ecx,%r8d
  jle    L34
  movslq %ecx,%rcx
  add    (%rdx,%rcx,1),%al
L34:
  movslq %esi,%rsi
  cmp    %al,-0x1(%rdx,%rsi,1)
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L85:
  movslq %esi,%rsi
  xor    %eax,%eax
  cmp    %al,-0x1(%rdx,%rsi,1)
  sete   %al
  movzbl %al,%eax
  ret
L125:
  xor    %edi,%edi
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int chksum(const unsigned char *buff, int n) {
  unsigned char cs = 0;
  int i;
  for (i = 1; i < n - 1; i++)
    cs += buff[i];
  return buff[n - 1] == cs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zero_dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L19
L36:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L20:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L20
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jle    L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero_dmatrix(double **m, long nrl, long nrh, long ncl, long nch) {
  long i, j;
  double *mi;
  for (i = nrl; i <= nrh; i++) {
    mi = m[i];
    for (j = ncl; j <= nch; j++) {
      mi[j] = 0.0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zero_dmatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L3
  lea    (%rdi,%rsi,8),%rsi
  lea    0x8(%rdi,%rdx,8),%rdi
  lea    0x0(,%rcx,8),%r10
  lea    0x8(,%r8,8),%r9
L21:
  mov    (%rsi),%rdx
  cmp    %r8,%rcx
  jg     L4
  lea    (%rdx,%r10,1),%rax
  add    %r9,%rdx
L35:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L35
L4:
  add    $0x8,%rsi
  cmp    %rdi,%rsi
  jne    L21
L3:
  ret
```

assistant: ```c
void zero_dmatrix(double **m, long nrl, long nrh, long ncl, long nch) {
  long i, j;
  double *mi;
  for (i = nrl; i <= nrh; i++) {
    mi = m[i];
    for (j = ncl; j <= nch; j++) {
      mi[j] = 0.0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zero_dmatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L23
  push   %r15
  mov    %r8,%rax
  push   %r14
  sub    %rcx,%rax
  lea    0x0(,%rcx,8),%r14
  push   %r13
  lea    0x8(,%rax,8),%r15
  lea    0x8(%rdi,%rdx,8),%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  lea    (%rdi,%rsi,8),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%rdi
  cmp    %r12,%rbp
  jg     L0
  add    %r14,%rdi
  mov    %r15,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L0:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

assistant: ```c
void zero_dmatrix(double **m, long nrl, long nrh, long ncl, long nch) {
  long i, j;
  double *mi;
  for (i = nrl; i <= nrh; i++) {
    mi = m[i];
    for (j = ncl; j <= nch; j++) {
      mi[j] = 0.0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zero_dmatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L10
  cmp    %r8,%rcx
  jg     L10
  push   %r13
  sub    %rcx,%r8
  lea    0x8(%rdi,%rdx,8),%r13
  push   %r12
  lea    0x8(,%r8,8),%r12
  push   %rbp
  lea    0x0(,%rcx,8),%rbp
  push   %rbx
  lea    (%rdi,%rsi,8),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  add    %rbp,%rdi
  call   <memset@plt>
  cmp    %rbx,%r13
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  ret
```

assistant: ```c
void zero_dmatrix(double **m, long nrl, long nrh, long ncl, long nch) {
  long i, j;
  double *mi;
  for (i = nrl; i <= nrh; i++) {
    mi = m[i];
    for (j = ncl; j <= nch; j++) {
      mi[j] = 0.0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L12
L19:
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  movsd  D23(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D28(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x14(%rbp),%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x8(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
L12:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jae    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D23
type: byte[8]
name: parse_data
arguments: data_label: D28
type: f64
name: parse_data
arguments: data_label: D30
type: string

tool: D33:   C      F

tool: {"D23": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D28: 32

tool: D30: %3.0f %6.1f


assistant: ```c
int main() {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  celsius = lower;
  printf("  C      F\n");
  while (celsius <= upper) {
    fahr = (9.0 / 5.0) * celsius + 32.0;
    printf("%3.0f %6.1f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%ebx
  pxor   %xmm4,%xmm4
  movss  %xmm4,0xc(%rsp)
  lea    D28(%rip),%rbp
L5:
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  movsd  D41(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  D16(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  D27(%rip),%xmm2
  addss  0xc(%rsp),%xmm2
  movss  %xmm2,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string
name: parse_data
arguments: label: D41
type_guessed: byte[8]
name: parse_data
arguments: label: D16
type_guessed: f64
name: parse_data
arguments: label: D27
type_guessed: byte[4]

tool: D8:   C      F

tool: D28: %3.0f %6.1f


tool: {"D41": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D16: 32

tool: {"D27": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  celsius = lower;
  printf("  C      F\n");
  while (celsius <= upper) {
    fahr = (9.0 / 5.0) * celsius + 32.0;
    printf("%3.0f %6.1f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D15(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L6:
  movsd  D2(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D11(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D22(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D49
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D11
type_infered: f64
name: unpack_data
arguments: data_tag: D22
type_infered: byte[4]

tool: D49:   C      F

tool: D15: %3.0f %6.1f


tool: {"D2": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D11: 32

tool: {"D22": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  celsius = lower;
  printf("  C      F\n");
  while (celsius <= upper) {
    fahr = (9.0 / 5.0) * celsius + 32.0;
    printf("%3.0f %6.1f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```