ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<transitive_closure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x4c(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x40(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L15
L55:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L62
L36:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L81
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L30
L28:
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    (%rax),%edx
  or     %ecx,%edx
  mov    %edx,(%rax)
L30:
  mov    -0x38(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L28
  jmp    L43
L81:
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x38(%rbp)
L43:
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
L62:
  mov    -0x38(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L36
  addl   $0x1,-0x40(%rbp)
  cmpl   $0x1f,-0x40(%rbp)
  jbe    L78
  movl   $0x0,-0x40(%rbp)
  addq   $0x4,-0x20(%rbp)
L78:
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L55
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transitive_closure(unsigned *R, int n) {
  int rowsize;
  unsigned i;
  unsigned *rowj;
  unsigned *rp;
  unsigned *rend;
  unsigned *ccol;
  unsigned *relend;
  unsigned *cword;
  unsigned *rowi;
  rowsize = (((n) + (32 - 1) / 32));
  relend = R + n * rowsize;
  cword = R;
  i = 0;
  rowi = R;
  while (rowi < relend) {
    ccol = cword;
    rowj = R;
    while (rowj < relend) {
      if (*ccol & (1 << i)) {
        rp = rowi;
        rend = rowj + rowsize;
        while (rowj < rend)
          *rowj++ |= *rp++;
      } else {
        rowj += rowsize;
      }
      ccol += rowsize;
    }
    if (++i >= 32) {
      i = 0;
      cword++;
    }
    rowi += rowsize;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<transitive_closure>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  cltq
  lea    (%rdi,%rax,4),%r11
  cmp    %r11,%rdi
  jae    L59
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%r10
  mov    %rdi,%rbp
  mov    %rdi,%r12
  mov    $0x0,%ecx
  mov    $0x1,%r15d
  mov    %r10,%r13
  jmp    L85
L58:
  lea    (%rdi,%r10,1),%r9
  cmp    %rdi,%r9
  jbe    L14
  mov    %rbp,%rdx
  mov    %rdi,%rax
L72:
  add    $0x4,%rdx
  add    $0x4,%rax
  mov    -0x4(%rdx),%esi
  or     %esi,-0x4(%rax)
  cmp    %rax,%r9
  ja     L72
  add    %r13,%rdi
L14:
  add    %r10,%r8
  cmp    %r11,%rdi
  jae    L18
L78:
  mov    %ebx,%eax
  and    (%r8),%eax
  jne    L58
  add    %r10,%rdi
  jmp    L14
L18:
  add    $0x1,%ecx
  cmp    $0x1f,%ecx
  jbe    L10
  add    $0x4,%r12
  mov    $0x0,%ecx
L10:
  add    %r10,%rbp
  cmp    %rbp,%r11
  jbe    L38
L85:
  mov    %r15d,%ebx
  shl    %cl,%ebx
  mov    %r12,%r8
  mov    %r14,%rdi
  jmp    L78
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  ret
```

assistant: ```c
void transitive_closure(unsigned *R, int n) {
  int rowsize;
  unsigned i;
  unsigned *rowj;
  unsigned *rp;
  unsigned *rend;
  unsigned *ccol;
  unsigned *relend;
  unsigned *cword;
  unsigned *rowi;
  rowsize = (((n) + (32 - 1) / 32));
  relend = R + n * rowsize;
  cword = R;
  i = 0;
  rowi = R;
  while (rowi < relend) {
    ccol = cword;
    rowj = R;
    while (rowj < relend) {
      if (*ccol & (1 << i)) {
        rp = rowi;
        rend = rowj + rowsize;
        while (rowj < rend)
          *rowj++ |= *rp++;
      } else {
        rowj += rowsize;
      }
      ccol += rowsize;
    }
    if (++i >= 32) {
      i = 0;
      cword++;
    }
    rowi += rowsize;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<transitive_closure>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  cltq
  lea    (%rdi,%rax,4),%r11
  cmp    %r11,%rdi
  jae    L66
  push   %r15
  movslq %esi,%rsi
  xor    %ecx,%ecx
  mov    $0x1,%r15d
  push   %r14
  lea    0x0(,%rsi,4),%r10
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r10,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L47:
  mov    %r15d,%ebx
  mov    %r14,%r9
  mov    %r13,%r8
  shl    %cl,%ebx
  jmp    L80
  nopl   (%rax)
L82:
  mov    %rdi,%r8
L72:
  add    %r10,%r9
  cmp    %r11,%r8
  jae    L35
L80:
  mov    %ebx,%eax
  and    (%r9),%eax
  lea    (%r8,%r10,1),%rdi
  je     L82
  cmp    %r8,%rdi
  jbe    L72
  mov    %rbp,%rdx
  mov    %r8,%rax
  nopl   0x0(%rax)
L41:
  add    $0x4,%rax
  add    $0x4,%rdx
  mov    -0x4(%rdx),%esi
  or     %esi,-0x4(%rax)
  cmp    %rax,%rdi
  ja     L41
  add    %r12,%r8
  add    %r10,%r9
  cmp    %r11,%r8
  jb     L80
L35:
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L55
  add    $0x4,%r14
  xor    %ecx,%ecx
L55:
  add    %r10,%rbp
  cmp    %rbp,%r11
  ja     L47
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  ret
```

assistant: ```c
void transitive_closure(unsigned *R, int n) {
  int rowsize;
  unsigned i;
  unsigned *rowj;
  unsigned *rp;
  unsigned *rend;
  unsigned *ccol;
  unsigned *relend;
  unsigned *cword;
  unsigned *rowi;
  rowsize = (((n) + (32 - 1) / 32));
  relend = R + n * rowsize;
  cword = R;
  i = 0;
  rowi = R;
  while (rowi < relend) {
    ccol = cword;
    rowj = R;
    while (rowj < relend) {
      if (*ccol & (1 << i)) {
        rp = rowi;
        rend = rowj + rowsize;
        while (rowj < rend)
          *rowj++ |= *rp++;
      } else {
        rowj += rowsize;
      }
      ccol += rowsize;
    }
    if (++i >= 32) {
      i = 0;
      cword++;
    }
    rowi += rowsize;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<terminate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x73,-0xe(%rbp)
  movb   $0x68,-0xd(%rbp)
  movb   $0x65,-0xc(%rbp)
  movb   $0x6c,-0xb(%rbp)
  movb   $0x6c,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xe(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x2000,%ecx
  mov    %rax,%rdx
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void terminate() {
  char shell[6];
  shell[0] = 's';
  shell[1] = 'h';
  shell[2] = 'e';
  shell[3] = 'l';
  shell[4] = 'l';
  shell[5] = '\0';
  interrupt(0x21, 4, shell, 0x2000, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<terminate>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x73,0x2(%rsp)
  movb   $0x68,0x3(%rsp)
  movb   $0x65,0x4(%rsp)
  movb   $0x6c,0x5(%rsp)
  movb   $0x6c,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x2(%rsp),%rdx
  mov    $0x0,%r8d
  mov    $0x2000,%ecx
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <interrupt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void terminate() {
  char shell[6];
  shell[0] = 's';
  shell[1] = 'h';
  shell[2] = 'e';
  shell[3] = 'l';
  shell[4] = 'l';
  shell[5] = '\0';
  interrupt(0x21, 4, shell, 0x2000, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<terminate>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  mov    $0x2000,%ecx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rdx
  mov    $0x6c,%eax
  mov    $0x21,%edi
  movl   $0x6c656873,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <interrupt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void terminate() {
  char shell[6];
  shell[0] = 's';
  shell[1] = 'h';
  shell[2] = 'e';
  shell[3] = 'l';
  shell[4] = 'l';
  shell[5] = '\0';
  interrupt(0x21, 4, shell, 0x2000, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<terminate>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  mov    $0x2000,%ecx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x6c,%eax
  mov    $0x21,%edi
  movl   $0x6c656873,(%rsp)
  mov    %ax,0x4(%rsp)
  call   <interrupt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void terminate() {
  char shell[6];
  shell[0] = 's';
  shell[1] = 'h';
  shell[2] = 'e';
  shell[3] = 'l';
  shell[4] = 'l';
  shell[5] = '\0';
  interrupt(0x21, 4, shell, 0x2000, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L40
  mov    $0x0,%eax
  jmp    L32
L40:
  cmpl   $0x2,-0x14(%rbp)
  jne    L1
  mov    $0x1,%eax
  jmp    L32
L1:
  movl   $0x2,-0x4(%rbp)
  jmp    L18
L38:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  mov    $0x0,%eax
  jmp    L32
L12:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L38
  mov    $0x1,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int num) {
  int y;
  if (num < 2) {
    return 0;
  } else if (num == 2) {
    return 1;
  }
  for (y = 2; y < num; y++) {
    if (num % y == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L47
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L47
  test   $0x1,%dil
  je     L19
  mov    $0x2,%ecx
L42:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jle    L45
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L42
L47:
  ret
L45:
  mov    $0x1,%eax
  ret
L19:
  mov    $0x0,%eax
  jmp    L47
```

assistant: ```c
int is_prime(int num) {
  int y;
  if (num < 2) {
    return 0;
  } else if (num == 2) {
    return 1;
  }
  for (y = 2; y < num; y++) {
    if (num % y == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_prime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L11
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L11
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L11
L41:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L9
  mov    $0x1,%edx
L11:
  mov    %edx,%eax
  ret
L22:
  xor    %edx,%edx
  jmp    L11
```

assistant: ```c
int is_prime(int num) {
  int y;
  if (num < 2) {
    return 0;
  } else if (num == 2) {
    return 1;
  }
  for (y = 2; y < num; y++) {
    if (num % y == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_prime>:
  endbr64
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L49
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L49
  test   $0x1,%dil
  je     L8
  mov    $0x2,%ecx
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L49
L51:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L38
  mov    $0x1,%edx
L49:
  mov    %edx,%eax
  ret
L8:
  xor    %edx,%edx
  jmp    L49
```

assistant: ```c
int is_prime(int num) {
  int y;
  if (num < 2) {
    return 0;
  } else if (num == 2) {
    return 1;
  }
  for (y = 2; y < num; y++) {
    if (num % y == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_aln_fasta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
L2:
  cmpq   $0x0,-0x28(%rbp)
  je     L9
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L9:
  mov    -0x2c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_fasta_alignment@plt>
  leave
  ret
```

assistant: ```c
int parse_aln_fasta(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_fasta_alignment(fp, names, aln, verbosity);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_aln_fasta>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L4
  movq   $0x0,(%rax)
L4:
  test   %r8,%r8
  je     L1
  movq   $0x0,(%r8)
L1:
  call   <parse_fasta_alignment@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int parse_aln_fasta(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_fasta_alignment(fp, names, aln, verbosity);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_aln_fasta>:
  endbr64
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L10
  movq   $0x0,(%rax)
L10:
  test   %r8,%r8
  je     L14
  movq   $0x0,(%r8)
L14:
  jmp    1050 <parse_fasta_alignment@plt>
```

assistant: ```c
int parse_aln_fasta(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_fasta_alignment(fp, names, aln, verbosity);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_aln_fasta>:
  endbr64
  mov    %rcx,%rax
  mov    %r9d,%ecx
  test   %rax,%rax
  je     L8
  movq   $0x0,(%rax)
L8:
  test   %r8,%r8
  je     L3
  movq   $0x0,(%r8)
L3:
  jmp    1050 <parse_fasta_alignment@plt>
```

assistant: ```c
int parse_aln_fasta(FILE *fp, char ***names, char ***aln, char **id, char **structure, int verbosity) {
  if (id)
    *id = NULL;
  if (structure)
    *structure = NULL;
  return parse_fasta_alignment(fp, names, aln, verbosity);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<alpha2angle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movsd  D23(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  D5(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D18(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  D20(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
type: byte[8]
name: disassemble_data
arguments: label: D5
type: byte[4]
name: disassemble_data
arguments: label: D18
type: byte[4]
name: disassemble_data
arguments: label: D20
type: byte[4]

tool: {"D23": [0xe6,0x0d,0xf7,0x6f,0x4a,0xdc,0xe2,0x3f]}

tool: {"D5": [0x00,0x00,0x00,0x80]}

tool: {"D18": [0x00,0x00,0x07,0x43]}

tool: {"D20": [0x00,0x00,0x90,0x41]}

assistant: ```c
float alpha2angle(float alpha) {
  alpha = 20 / 33.9333333 * alpha * -1;
  alpha = alpha + 135 - 18;
  return alpha;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<alpha2angle>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mulsd  D17(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  D5(%rip),%xmm0
  subss  %xmm1,%xmm0
  subss  D12(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D17
data_type: byte[8]
name: read_data
arguments: label: D5
data_type: byte[4]
name: read_data
arguments: label: D12
data_type: byte[4]

tool: {"D17": [0xe6,0x0d,0xf7,0x6f,0x4a,0xdc,0xe2,0x3f]}

tool: {"D5": [0x00,0x00,0x07,0x43]}

tool: {"D12": [0x00,0x00,0x90,0x41]}

assistant: ```c
float alpha2angle(float alpha) {
  alpha = 20 / 33.9333333 * alpha * -1;
  alpha = alpha + 135 - 18;
  return alpha;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alpha2angle>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mulsd  D4(%rip),%xmm1
  movss  D6(%rip),%xmm0
  cvtsd2ss %xmm1,%xmm1
  subss  %xmm1,%xmm0
  subss  D13(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D6
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D13
type: byte[4]

tool: {"D4": [0xe6,0x0d,0xf7,0x6f,0x4a,0xdc,0xe2,0x3f]}

tool: {"D6": [0x00,0x00,0x07,0x43]}

tool: {"D13": [0x00,0x00,0x90,0x41]}

assistant: ```c
float alpha2angle(float alpha) {
  alpha = 20 / 33.9333333 * alpha * -1;
  alpha = alpha + 135 - 18;
  return alpha;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alpha2angle>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mulsd  D11(%rip),%xmm1
  movss  D26(%rip),%xmm0
  cvtsd2ss %xmm1,%xmm1
  subss  %xmm1,%xmm0
  subss  D16(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D26
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D16
type_infered: byte[4]

tool: {"D11": [0xe6,0x0d,0xf7,0x6f,0x4a,0xdc,0xe2,0x3f]}

tool: {"D26": [0x00,0x00,0x07,0x43]}

tool: {"D16": [0x00,0x00,0x90,0x41]}

assistant: ```c
float alpha2angle(float alpha) {
  alpha = 20 / 33.9333333 * alpha * -1;
  alpha = alpha + 135 - 18;
  return alpha;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int foo() {
  int a, b, c;
  a = b + c;
  b = bar();
  c = bar();
  return a + b + c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <bar@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  int a, b, c;
  a = b + c;
  b = bar();
  c = bar();
  return a + b + c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <bar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <bar@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  int a, b, c;
  a = b + c;
  b = bar();
  c = bar();
  return a + b + c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <bar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <bar@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int foo() {
  int a, b, c;
  a = b + c;
  b = bar();
  c = bar();
  return a + b + c;
}
```
user: What is the c source code of the assembly code below:

```asm
<setbpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<setbpt>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int setbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cc2400_pktstatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  lea    D69(%rip),%r8
  lea    D133(%rip),%rax
  mov    %rax,%rcx
  lea    D116(%rip),%rax
  mov    %rax,%rdx
  mov    $0xb,%esi
  mov    $0xf,%edi
  call   <bits@plt>
  lea    D69(%rip),%r8
  lea    D125(%rip),%rax
  mov    %rax,%rcx
  lea    D73(%rip),%rax
  mov    %rax,%rdx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <bits@plt>
  lea    D69(%rip),%r8
  lea    D125(%rip),%rax
  mov    %rax,%rcx
  lea    D127(%rip),%rax
  mov    %rax,%rdx
  mov    $0x9,%esi
  mov    $0x9,%edi
  call   <bits@plt>
  lea    D69(%rip),%r8
  lea    D125(%rip),%rax
  mov    %rax,%rcx
  lea    D116(%rip),%rax
  mov    %rax,%rdx
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <bits@plt>
  lea    D69(%rip),%r8
  lea    D125(%rip),%rax
  mov    %rax,%rcx
  lea    D116(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <bits@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D69
datatype: string
name: retrieve_data
arguments: tag: D133
datatype: string
name: retrieve_data
arguments: tag: D116
datatype: string
name: retrieve_data
arguments: tag: D125
datatype: string
name: retrieve_data
arguments: tag: D73
datatype: string
name: retrieve_data
arguments: tag: D127
datatype: string

tool: 

tool: D133: W0

tool: D116: -

tool: D125: RO

tool: D73: SYNC_WORD_RECEIVED

tool: D127: CRC_OK

assistant: ```c
void cc2400_pktstatus(unsigned short v) {
  (void)(v);
  bits(15, 11, "-", "W0", "");
  bits(10, 10, "SYNC_WORD_RECEIVED", "RO", "");
  bits(9, 9, "CRC_OK", "RO", "");
  bits(8, 8, "-", "RO", "");
  bits(7, 0, "-", "RO", "");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cc2400_pktstatus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D91(%rip),%r8
  lea    D29(%rip),%rcx
  lea    D4(%rip),%rbp
  mov    %rbp,%rdx
  mov    $0xb,%esi
  mov    $0xf,%edi
  call   <bits@plt>
  lea    D91(%rip),%r8
  lea    D21(%rip),%rbx
  mov    %rbx,%rcx
  lea    D80(%rip),%rdx
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <bits@plt>
  lea    D91(%rip),%r8
  mov    %rbx,%rcx
  lea    D82(%rip),%rdx
  mov    $0x9,%esi
  mov    $0x9,%edi
  call   <bits@plt>
  lea    D91(%rip),%r8
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x8,%esi
  mov    $0x8,%edi
  call   <bits@plt>
  lea    D91(%rip),%r8
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    $0x7,%edi
  call   <bits@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D91
data_type: string
name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D80
data_type: string
name: read_data
arguments: tag: D82
data_type: string

tool: 

tool: D29: W0

tool: D4: -

tool: D21: RO

tool: D80: SYNC_WORD_RECEIVED

tool: D82: CRC_OK

assistant: ```c
void cc2400_pktstatus(unsigned short v) {
  (void)(v);
  bits(15, 11, "-", "W0", "");
  bits(10, 10, "SYNC_WORD_RECEIVED", "RO", "");
  bits(9, 9, "CRC_OK", "RO", "");
  bits(8, 8, "-", "RO", "");
  bits(7, 0, "-", "RO", "");
}
```