ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rsi,%r12
  mov    $0x0,%ebp
L4:
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x30,%eax
  mov    %al,(%r12)
  mov    %ebx,%edi
  add    $0x1,%r12
  test   %ebx,%ebx
  jne    L4
  test   %r15d,%r15d
  js     L39
L41:
  cmp    %ebp,%r14d
  jle    L58
  movslq %ebp,%rdx
  lea    0x0(%r13,%rdx,1),%rax
  lea    0x1(%r13,%rdx,1),%rdx
  lea    -0x1(%r14),%ecx
  sub    %ebp,%ecx
  add    %rcx,%rdx
L47:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L47
L55:
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
  mov    %r13,%rdi
  call   <Reverse@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  movslq %ebp,%rbp
  movb   $0x2d,0x0(%r13,%rbp,1)
  lea    0x2(%rdx),%ebp
  jmp    L41
L58:
  mov    %ebp,%r14d
  jmp    L55
```

assistant: ```c
void itoa(int n, char s[], int b) {
  void Reverse(char s[]);
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((n /= 10) != 0);
  if (sign < 0)
    s[i++] = '-';
  while (i < b)
    s[i++] = ' ';
  s[i] = '\0';
  Reverse(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  movslq %edi,%rbx
  mov    %edi,%eax
  add    $0x1,%r15
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r14d,%edx
  mov    %ebx,%edi
  add    $0x1,%r14d
  add    $0x30,%eax
  mov    %al,-0x1(%r15)
  test   %ebx,%ebx
  jne    L3
  test   %r13d,%r13d
  jns    L12
  movslq %r14d,%r14
  movb   $0x2d,(%r12,%r14,1)
  lea    0x2(%rdx),%r14d
L12:
  cmp    %r14d,%ebp
  jle    L33
  lea    -0x1(%rbp),%edx
  movslq %r14d,%rdi
  mov    $0x20,%esi
  sub    %r14d,%edx
  add    %r12,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L25:
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <Reverse@plt>
  nopl   0x0(%rax)
L33:
  movslq %r14d,%rbp
  jmp    L25
```

assistant: ```c
void itoa(int n, char s[], int b) {
  void Reverse(char s[]);
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((n /= 10) != 0);
  if (sign < 0)
    s[i++] = '-';
  while (i < b)
    s[i++] = ' ';
  s[i] = '\0';
  Reverse(s);
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  movslq %edi,%rbx
  mov    %edi,%eax
  add    $0x1,%r15
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r14d,%edx
  mov    %ebx,%edi
  add    $0x1,%r14d
  add    $0x30,%eax
  mov    %al,-0x1(%r15)
  test   %ebx,%ebx
  jne    L7
  test   %r13d,%r13d
  jns    L35
  movslq %r14d,%r14
  movb   $0x2d,(%r12,%r14,1)
  lea    0x2(%rdx),%r14d
L35:
  cmp    %r14d,%ebp
  jle    L33
  lea    -0x1(%rbp),%edx
  movslq %r14d,%rdi
  mov    $0x20,%esi
  sub    %r14d,%edx
  add    %r12,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L11:
  movb   $0x0,(%r12,%rbp,1)
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <Reverse@plt>
  nopl   0x0(%rax)
L33:
  movslq %r14d,%rbp
  jmp    L11
```

assistant: ```c
void itoa(int n, char s[], int b) {
  void Reverse(char s[]);
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((n /= 10) != 0);
  if (sign < 0)
    s[i++] = '-';
  while (i < b)
    s[i++] = ' ';
  s[i] = '\0';
  Reverse(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<flags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %esi,-0xc8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc4(%rbp),%edx
  mov    -0xb4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  nop
  leave
  ret
```

assistant: ```c
int flags(int a, int b, ...) {
  va_list args;
  va_start(args, a);
  foo(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<flags>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edi
  call   <foo@plt>
  pop    %rbx
  ret
```

assistant: ```c
int flags(int a, int b, ...) {
  va_list args;
  va_start(args, a);
  foo(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flags>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <foo@plt>
  pop    %rbp
  ret
```

assistant: ```c
int flags(int a, int b, ...) {
  va_list args;
  va_start(args, a);
  foo(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<flags>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <foo@plt>
  pop    %rbp
  ret
```

assistant: ```c
int flags(int a, int b, ...) {
  va_list args;
  va_start(args, a);
  foo(args);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L34:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sbrk@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L23
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L25
L23:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0xbb7,-0xc(%rbp)
  jle    L34
  mov    $0x0,%eax
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: sbrk() failed!

assistant: ```c
int main() {
  char *ptr;
  int i;
  for (i = 0; i < 3000; i++) {
    ptr = sbrk(1);
    if (ptr == (void *)-1) {
      printf("sbrk() failed!\n");
      return 0;
    }
    *ptr = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xbb8,%ebx
L1:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sbrk@plt>
  movslq %eax,%rdx
  cmp    $0xffffffff,%eax
  je     L6
  movb   $0x0,(%rdx)
  sub    $0x1,%ebx
  jne    L1
  jmp    L18
L6:
  lea    D3(%rip),%rdi
  call   <puts@plt>
L18:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: sbrk() failed!

assistant: ```c
int main() {
  char *ptr;
  int i;
  for (i = 0; i < 3000; i++) {
    ptr = sbrk(1);
    if (ptr == (void *)-1) {
      printf("sbrk() failed!\n");
      return 0;
    }
    *ptr = 0;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xbb8,%ebx
  jmp    L22
  nopl   0x0(%rax)
L19:
  movb   $0x0,(%rdx)
  sub    $0x1,%ebx
  je     L2
L22:
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sbrk@plt>
  movslq %eax,%rdx
  cmp    $0xffffffff,%eax
  jne    L19
  lea    D3(%rip),%rdi
  call   <puts@plt>
L2:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: sbrk() failed!

assistant: ```c
int main() {
  char *ptr;
  int i;
  for (i = 0; i < 3000; i++) {
    ptr = sbrk(1);
    if (ptr == (void *)-1) {
      printf("sbrk() failed!\n");
      return 0;
    }
    *ptr = 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xbb8,%ebx
  jmp    L0
  nopl   0x0(%rax)
L6:
  movb   $0x0,(%rdx)
  sub    $0x1,%ebx
  je     L22
L0:
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sbrk@plt>
  movslq %eax,%rdx
  cmp    $0xffffffff,%eax
  jne    L6
  lea    D0(%rip),%rdi
  call   <puts@plt>
L22:
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: sbrk() failed!

assistant: ```c
int main() {
  char *ptr;
  int i;
  for (i = 0; i < 3000; i++) {
    ptr = sbrk(1);
    if (ptr == (void *)-1) {
      printf("sbrk() failed!\n");
      return 0;
    }
    *ptr = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pblkl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L31:
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L27:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L23
  mov    -0x24(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
L23:
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L31
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D8: %08x


tool: D5: %4d 

assistant: ```c
void pblkl(void *a, int w, int h, int s) {
  unsigned *p = a;
  int x, y;
  printf("%08x\n", p);
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++)
      printf("%4d ", *p++);
    printf("\n");
    if (s)
      p += (s - w);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<pblkl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r14d
  mov    %edx,%ebp
  mov    %edx,0xc(%rsp)
  mov    %ecx,%r15d
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L30
  mov    %r15d,%eax
  sub    %r14d,%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r14),%eax
  lea    0x4(,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%r13d
  lea    D17(%rip),%r12
  jmp    L49
L52:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L52
L59:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%rax
  lea    0x0(%rbp,%rax,1),%rbx
  test   %r15d,%r15d
  cmove  %rbp,%rbx
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  je     L30
L49:
  mov    0x18(%rsp),%rax
  lea    (%rbx,%rax,1),%rbp
  test   %r14d,%r14d
  jg     L52
  mov    %rbx,%rbp
  jmp    L59
L30:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string

tool: D0: %08x


tool: D17: %4d 

assistant: ```c
void pblkl(void *a, int w, int h, int s) {
  unsigned *p = a;
  int x, y;
  printf("%08x\n", p);
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++)
      printf("%4d ", *p++);
    printf("\n");
    if (s)
      p += (s - w);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pblkl>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L12
  mov    %r14d,%eax
  xor    %r12d,%r12d
  lea    D12(%rip),%rbp
  sub    %r13d,%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    0x18(%rsp),%rax
  lea    (%r15,%rax,1),%rbx
  test   %r13d,%r13d
  jle    L26
  xchg   %ax,%ax
L34:
  mov    (%r15),%esi
  add    $0x4,%r15
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L34
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%rax
  test   %r14d,%r14d
  lea    (%rbx,%rax,1),%r8
  cmovne %r8,%rbx
  add    $0x1,%r12d
  mov    %rbx,%r15
  cmp    %r12d,0xc(%rsp)
  jne    L27
L12:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %r15,%rbx
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string
name: extract_symbolic_data
arguments: label: D12
type: string

tool: D1: %08x


tool: D12: %4d 

assistant: ```c
void pblkl(void *a, int w, int h, int s) {
  unsigned *p = a;
  int x, y;
  printf("%08x\n", p);
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++)
      printf("%4d ", *p++);
    printf("\n");
    if (s)
      p += (s - w);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pblkl>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdi,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %edx,0xc(%rsp)
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L30
  mov    %r14d,%eax
  xor    %r12d,%r12d
  lea    D11(%rip),%rbp
  sub    %r13d,%eax
  cltq
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x4(,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    0x18(%rsp),%rax
  lea    (%r15,%rax,1),%rbx
  test   %r13d,%r13d
  jle    L45
  xchg   %ax,%ax
L2:
  mov    (%r15),%esi
  add    $0x4,%r15
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L2
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x10(%rsp),%rax
  test   %r14d,%r14d
  lea    (%rbx,%rax,1),%r8
  cmovne %r8,%rbx
  add    $0x1,%r12d
  mov    %rbx,%r15
  cmp    %r12d,0xc(%rsp)
  jne    L15
L30:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %r15,%rbx
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D4: %08x


tool: D11: %4d 

assistant: ```c
void pblkl(void *a, int w, int h, int s) {
  unsigned *p = a;
  int x, y;
  printf("%08x\n", p);
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++)
      printf("%4d ", *p++);
    printf("\n");
    if (s)
      p += (s - w);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D48(%rip),%rdi
  push   %rbp
  lea    D22(%rip),%rbp
  sub    $0x158,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0xd0(%rsp)
  movl   $0x0,0x140(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L89
  movzbl 0x70(%rsp),%r8d
  lea    0x1(%rsp),%rsi
  xor    %edi,%edi
  nopl   0x0(%rax)
L47:
  lea    0x71(%rsp),%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  jne    L8
  jmp    L94
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L94
L8:
  cmp    %cl,%al
  jne    L15
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  test   %cl,%cl
  jne    L47
L67:
  movslq %edi,%rdi
  xor    %eax,%eax
  lea    0xe0(%rsp),%rsi
  movb   $0x0,0xe0(%rsp,%rdi,1)
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x158,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  movslq %edi,%rax
  add    $0x1,%rsi
  add    $0x1,%edi
  mov    %cl,0xe0(%rsp,%rax,1)
  movzbl -0x1(%rsi),%ecx
  test   %cl,%cl
  jne    L47
  jmp    L67
L89:
  xor    %edi,%edi
  jmp    L67
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D31
data_type: string
name: parse_data
arguments: data_label: D23
data_type: string

tool: D48: Enter orig_str: 

tool: D22:  %s

tool: D0: orig_str : %s


tool: D31: Enter string(whose chars)to remove

tool: D23: new str : %s


assistant: ```c
int main() {
  char orig_str[100] = {0};
  char squeeze_str[100] = {0};
  char new_str[100] = {0};
  int i, j, k;
  int flag = 0;
  printf("Enter orig_str: ");
  scanf(" %s", orig_str);
  printf("orig_str : %s\n", orig_str);
  printf("Enter string(whose chars)to remove\n");
  scanf(" %s", squeeze_str);
  for (i = 0, k = 0; orig_str[i] != '\0'; i++) {
    flag = 0;
    for (j = 0; squeeze_str[j] != '\0'; j++) {
      if (orig_str[i] == squeeze_str[j]) {
        flag = 1;
        break;
      }
    }
    if (flag != 1) {
      new_str[k++] = orig_str[i];
    }
  }
  new_str[k] = '\0';
  printf("new str : %s\n", new_str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nasm_get_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <nasm_skip_spaces@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <nasm_skip_word@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L15
L14:
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L15:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *nasm_get_word(char *p, char **tail) {
  char *word = nasm_skip_spaces(p);
  char *next = nasm_skip_word(word);
  if (word && *word) {
    if (*next)
      *next++ = '\0';
  } else
    word = next = NULL;
  *tail = next;
  return word;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nasm_get_word>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <nasm_skip_spaces@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <nasm_skip_word@plt>
  test   %rbx,%rbx
  je     L41
  cmpb   $0x0,(%rbx)
  je     L20
  cmpb   $0x0,(%rax)
  je     L19
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rax
L19:
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  mov    %rbx,%rax
  jmp    L19
L20:
  mov    $0x0,%eax
  mov    $0x0,%ebx
  jmp    L19
```

assistant: ```c
char *nasm_get_word(char *p, char **tail) {
  char *word = nasm_skip_spaces(p);
  char *next = nasm_skip_word(word);
  if (word && *word) {
    if (*next)
      *next++ = '\0';
  } else
    word = next = NULL;
  *tail = next;
  return word;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nasm_get_word>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <nasm_skip_spaces@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <nasm_skip_word@plt>
  test   %r12,%r12
  je     L0
  cmpb   $0x0,(%r12)
  je     L25
  cmpb   $0x0,(%rax)
  je     L2
  movb   $0x0,(%rax)
  add    $0x1,%rax
L2:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *nasm_get_word(char *p, char **tail) {
  char *word = nasm_skip_spaces(p);
  char *next = nasm_skip_word(word);
  if (word && *word) {
    if (*next)
      *next++ = '\0';
  } else
    word = next = NULL;
  *tail = next;
  return word;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nasm_get_word>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <nasm_skip_spaces@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <nasm_skip_word@plt>
  test   %r12,%r12
  je     L8
  cmpb   $0x0,(%r12)
  je     L15
  cmpb   $0x0,(%rax)
  je     L25
  movb   $0x0,(%rax)
  add    $0x1,%rax
L25:
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *nasm_get_word(char *p, char **tail) {
  char *word = nasm_skip_spaces(p);
  char *next = nasm_skip_word(word);
  if (word && *word) {
    if (*next)
      *next++ = '\0';
  } else
    word = next = NULL;
  *tail = next;
  return word;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<finn_vec2_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void finn_vec2_create(float *result, float x, float y) {
  result[0] = x;
  result[1] = y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<finn_vec2_create>:
  endbr64
  movss  %xmm0,(%rdi)
  movss  %xmm1,0x4(%rdi)
  ret
```

assistant: ```c
void finn_vec2_create(float *result, float x, float y) {
  result[0] = x;
  result[1] = y;
}
```