ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quat_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x2,%edi
  movss  (%rbx),%xmm0
  call   <pow@plt>
  mov    %rax,%rbp
  movss  0x4(%rbx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  add    %rax,%rbp
  movss  0x8(%rbx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  add    %rax,%rbp
  movss  0xc(%rbx),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  call   <sqrt@plt>
  movss  (%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rbx)
  movss  0x4(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movss  0x8(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  movss  0xc(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void quat_normalize(float *quat) {
  float norm = sqrt(pow(*((float *)(quat)), 2) + pow(*((float *)(quat + 1)), 2) + pow(*((float *)(quat + 2)), 2) + pow(*((float *)(quat + 3)), 2));
  *quat = *quat / norm;
  *(quat + 1) = *(quat + 1) / norm;
  *(quat + 2) = *(quat + 2) / norm;
  *(quat + 3) = *(quat + 3) / norm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quat_normalize>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  sub    $0x8,%rsp
  movss  (%rbx),%xmm0
  call   <pow@plt>
  movss  0x4(%rbx),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbp
  call   <pow@plt>
  movss  0x8(%rbx),%xmm0
  mov    $0x2,%edi
  add    %rax,%rbp
  call   <pow@plt>
  movss  0xc(%rbx),%xmm0
  mov    $0x2,%edi
  add    %rax,%rbp
  call   <pow@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  call   <sqrt@plt>
  movss  (%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rbx)
  movss  0x4(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rbx)
  movss  0x8(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rbx)
  movss  0xc(%rbx),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void quat_normalize(float *quat) {
  float norm = sqrt(pow(*((float *)(quat)), 2) + pow(*((float *)(quat + 1)), 2) + pow(*((float *)(quat + 2)), 2) + pow(*((float *)(quat + 3)), 2));
  *quat = *quat / norm;
  *(quat + 1) = *(quat + 1) / norm;
  *(quat + 2) = *(quat + 2) / norm;
  *(quat + 3) = *(quat + 3) / norm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quat_normalize>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  movss  0x0(%rbp),%xmm0
  call   <pow@plt>
  movss  0x4(%rbp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  call   <pow@plt>
  movss  0x8(%rbp),%xmm0
  mov    $0x2,%edi
  add    %rax,%rbx
  call   <pow@plt>
  movss  0xc(%rbp),%xmm0
  mov    $0x2,%edi
  add    %rax,%rbx
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  movups 0x0(%rbp),%xmm1
  shufps $0x0,%xmm0,%xmm0
  divps  %xmm0,%xmm1
  movups %xmm1,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void quat_normalize(float *quat) {
  float norm = sqrt(pow(*((float *)(quat)), 2) + pow(*((float *)(quat + 1)), 2) + pow(*((float *)(quat + 2)), 2) + pow(*((float *)(quat + 3)), 2));
  *quat = *quat / norm;
  *(quat + 1) = *(quat + 1) / norm;
  *(quat + 2) = *(quat + 2) / norm;
  *(quat + 3) = *(quat + 3) / norm;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D82(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D76(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D60(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D87(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x4,-0x54(%rbp)
  lea    -0x54(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    $0x0,%eax
  call   <clr@plt>
  movl   $0x1,-0x50(%rbp)
  jmp    L20
L27:
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0x50(%rbp)
L20:
  cmpl   $0x4,-0x50(%rbp)
  jle    L27
  movl   $0x0,-0x4c(%rbp)
  jmp    L8
L29:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4c(%rbp)
L8:
  cmpl   $0x3,-0x4c(%rbp)
  jle    L29
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <hello@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D82
datatype: string
name: extract_symbolic_data
arguments: data_label: D76
datatype: string
name: extract_symbolic_data
arguments: data_label: D60
datatype: string
name: extract_symbolic_data
arguments: data_label: D58
datatype: string
name: extract_symbolic_data
arguments: data_label: D87
datatype: string
name: extract_symbolic_data
arguments: data_label: D49
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string
name: extract_symbolic_data
arguments: data_label: D55
datatype: string
name: extract_symbolic_data
arguments: data_label: D44
datatype: string

tool: D82: Olga

tool: D76: Peter

tool: D60: Barbara

tool: D58: John

tool: D87: Dave

tool: D49: Value of names [%d] = %s


tool: D14: Printing elements of the array: %d: x[%d]


tool: D55: Printing p: %d

tool: D44: 
Prints output of function hello()

assistant: ```c
int main() {
  char *names[5] = {"Olga", "Peter", "Barbara", "John", "Dave"};
  void *p;
  int x[4] = {1, 2, 3, 4};
  int a = 4;
  p = &a;
  clr();
  for (int i = 1; i < 5; i = i + 2) {
    printf("Value of names [%d] = %s\n", i, names[i]);
  }
  for (int j = 0; j < 4; j++) {
    printf("Printing elements of the array: %d: x[%d]\n", j, x[j]);
  }
  printf("Printing p: %d", *(int *)p);
  printf("\nPrints output of function hello()");
  hello();
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  call   <clr@plt>
  lea    D21(%rip),%rdx
  mov    $0x1,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D26(%rip),%rbp
L0:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L0
  mov    $0x4,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <hello@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D8
type_infered: string
name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D44
type_infered: string

tool: D21: Peter

tool: D4: Value of names [%d] = %s


tool: D8: John

tool: D26: Printing elements of the array: %d: x[%d]


tool: D32: Printing p: %d

tool: D44: 
Prints output of function hello()

assistant: ```c
int main() {
  char *names[5] = {"Olga", "Peter", "Barbara", "John", "Dave"};
  void *p;
  int x[4] = {1, 2, 3, 4};
  int a = 4;
  p = &a;
  clr();
  for (int i = 1; i < 5; i = i + 2) {
    printf("Value of names [%d] = %s\n", i, names[i]);
  }
  for (int j = 0; j < 4; j++) {
    printf("Printing elements of the array: %d: x[%d]\n", j, x[j]);
  }
  printf("Printing p: %d", *(int *)p);
  printf("\nPrints output of function hello()");
  hello();
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x4(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <clr@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D36(%rip),%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdx
  lea    D15(%rip),%rbp
  call   <printf@plt>
  mov    $0x1,%edx
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L8
  mov    (%rsp,%rbx,4),%edx
  jmp    L3
  nopl   0x0(%rax)
L8:
  mov    $0x4,%esi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <hello@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D59
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D53
datatype: string
name: disassemble_data
arguments: tag: D55
datatype: string

tool: D59: Value of names [%d] = %s


tool: D36: Peter

tool: D17: John

tool: D15: Printing elements of the array: %d: x[%d]


tool: D53: Printing p: %d

tool: D55: 
Prints output of function hello()

assistant: ```c
int main() {
  char *names[5] = {"Olga", "Peter", "Barbara", "John", "Dave"};
  void *p;
  int x[4] = {1, 2, 3, 4};
  int a = 4;
  p = &a;
  clr();
  for (int i = 1; i < 5; i = i + 2) {
    printf("Value of names [%d] = %s\n", i, names[i]);
  }
  for (int j = 0; j < 4; j++) {
    printf("Printing elements of the array: %d: x[%d]\n", j, x[j]);
  }
  printf("Printing p: %d", *(int *)p);
  printf("\nPrints output of function hello()");
  hello();
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  movdqa D56(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  call   <clr@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D68(%rip),%rdx
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  lea    D29(%rip),%rdx
  lea    D58(%rip),%rbp
  call   <printf@plt>
L2:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L2
  mov    $0x4,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <hello@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D47
type: string
name: parse_data
arguments: label: D56
type: byte[16]
name: parse_data
arguments: label: D68
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D58
type: string
name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D17
type: string

tool: D47: Value of names [%d] = %s


tool: {"D56": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D68: Peter

tool: D29: John

tool: D58: Printing elements of the array: %d: x[%d]


tool: D31: Printing p: %d

tool: D17: 
Prints output of function hello()

assistant: ```c
int main() {
  char *names[5] = {"Olga", "Peter", "Barbara", "John", "Dave"};
  void *p;
  int x[4] = {1, 2, 3, 4};
  int a = 4;
  p = &a;
  clr();
  for (int i = 1; i < 5; i = i + 2) {
    printf("Value of names [%d] = %s\n", i, names[i]);
  }
  for (int j = 0; j < 4; j++) {
    printf("Printing elements of the array: %d: x[%d]\n", j, x[j]);
  }
  printf("Printing p: %d", *(int *)p);
  printf("\nPrints output of function hello()");
  hello();
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D44
datatype: string

tool: D44: %8d  %d = %d + %d


assistant: ```c
int main(void) {
  struct mallinfo m;
  void *p, *q;
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  q = malloc(16 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  p = malloc(1024 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(q);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(p);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%r8
  mov    %edx,%ecx
  shr    $0x20,%rax
  mov    %rax,%rdx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%r8
  mov    %edx,%ecx
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%r8
  mov    %edx,%ecx
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%r8
  mov    %edx,%ecx
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <mallinfo@plt>
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%r8
  mov    %edx,%ecx
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: string

tool: D3: %8d  %d = %d + %d


assistant: ```c
int main(void) {
  struct mallinfo m;
  void *p, *q;
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  q = malloc(16 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  p = malloc(1024 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(q);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(p);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: %8d  %d = %d + %d


assistant: ```c
int main(void) {
  struct mallinfo m;
  void *p, *q;
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  q = malloc(16 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  p = malloc(1024 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(q);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(p);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x4000,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x100000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <mallinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rdx,%r8
  shr    $0x20,%rax
  mov    %edx,%ecx
  shr    $0x20,%r8
  mov    %rax,%rdx
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %8d  %d = %d + %d


assistant: ```c
int main(void) {
  struct mallinfo m;
  void *p, *q;
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  q = malloc(16 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  p = malloc(1024 * 1024);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(q);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  free(p);
  m = mallinfo();
  printf("%8d  %d = %d + %d\n", m.hblkhd, m.arena, m.uordblks, m.fordblks);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<nearest_neighbor_interpolator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  movd   %eax,%xmm0
  call   <round@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  movd   %eax,%xmm0
  call   <round@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L39
  movl   $0x0,-0x8(%rbp)
L39:
  cmpl   $0x0,-0x4(%rbp)
  jns    L30
  movl   $0x0,-0x4(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  leave
  ret
```

assistant: ```c
float nearest_neighbor_interpolator(float *x, int w, int h, float p, float q) {
  int ip = round(p);
  int iq = round(q);
  if (ip < 0)
    ip = 0;
  if (iq < 0)
    iq = 0;
  if (ip >= w)
    ip = w - 1;
  if (iq >= h)
    iq = h - 1;
  return x[w * iq + ip];
}
```