ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tputC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x60,%eax
  test   %eax,%eax
  jne    L63
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L56
  mov    $0x24,%edx
  jmp    L41
L56:
  mov    $0x5e,%edx
L41:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <shf_putchar@plt>
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  or     $0x40,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <shf_putchar@plt>
  jmp    L55
L63:
  mov    -0x4(%rbp),%eax
  and    $0x7f,%eax
  cmp    $0x7f,%eax
  jne    L2
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L36
  mov    $0x24,%edx
  jmp    L33
L36:
  mov    $0x5e,%edx
L33:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <shf_putchar@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3f,%edi
  call   <shf_putchar@plt>
  jmp    L55
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <shf_putchar@plt>
L55:
  nop
  leave
  ret
```

assistant: ```c
void tputC(int c, struct shf *shf) {
  if ((c & 0x60) == 0) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar(((c & 0x7F) | 0x40), shf);
    ;
  } else if ((c & 0x7F) == 0x7F) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar('?', shf);
    ;
  } else
    shf_putchar(c, shf);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tputC>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   $0x60,%dil
  jne    L5
  mov    %edi,%eax
  and    $0x80,%eax
  cmp    $0x1,%eax
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  and    $0x3f,%ebx
  mov    %ebx,%edi
  or     $0x40,%edi
  mov    %rbp,%rsi
  call   <shf_putchar@plt>
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %edi,%eax
  and    $0x7f,%eax
  cmp    $0x7f,%eax
  jne    L22
  and    $0x80,%ebx
  cmp    $0x1,%ebx
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  mov    %rbp,%rsi
  mov    $0x3f,%edi
  call   <shf_putchar@plt>
  jmp    L20
L22:
  call   <shf_putchar@plt>
  jmp    L20
```

assistant: ```c
void tputC(int c, struct shf *shf) {
  if ((c & 0x60) == 0) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar(((c & 0x7F) | 0x40), shf);
    ;
  } else if ((c & 0x7F) == 0x7F) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar('?', shf);
    ;
  } else
    shf_putchar(c, shf);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tputC>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  and    $0x60,%edi
  jne    L1
  and    $0x80,%eax
  cmp    $0x1,%eax
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  mov    %ebp,%edi
  add    $0x8,%rsp
  mov    %r12,%rsi
  and    $0x3f,%edi
  pop    %rbp
  pop    %r12
  or     $0x40,%edi
  jmp    1050 <shf_putchar@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  and    $0x7f,%eax
  cmp    $0x7f,%eax
  jne    L19
  and    $0x80,%ebp
  cmp    $0x1,%ebp
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    $0x3f,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <shf_putchar@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <shf_putchar@plt>
```

assistant: ```c
void tputC(int c, struct shf *shf) {
  if ((c & 0x60) == 0) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar(((c & 0x7F) | 0x40), shf);
    ;
  } else if ((c & 0x7F) == 0x7F) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar('?', shf);
    ;
  } else
    shf_putchar(c, shf);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tputC>:
  endbr64
  push   %r12
  mov    %edi,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  and    $0x60,%edi
  jne    L8
  and    $0x80,%eax
  cmp    $0x1,%eax
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  mov    %ebp,%edi
  add    $0x8,%rsp
  mov    %r12,%rsi
  and    $0x3f,%edi
  pop    %rbp
  pop    %r12
  or     $0x40,%edi
  jmp    1050 <shf_putchar@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  and    $0x7f,%eax
  cmp    $0x7f,%eax
  jne    L16
  and    $0x80,%ebp
  cmp    $0x1,%ebp
  sbb    %edi,%edi
  and    $0x3a,%edi
  add    $0x24,%edi
  call   <shf_putchar@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    $0x3f,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <shf_putchar@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <shf_putchar@plt>
```

assistant: ```c
void tputC(int c, struct shf *shf) {
  if ((c & 0x60) == 0) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar(((c & 0x7F) | 0x40), shf);
    ;
  } else if ((c & 0x7F) == 0x7F) {
    shf_putchar((c & 0x80) ? '$' : '^', shf);
    ;
    shf_putchar('?', shf);
    ;
  } else
    shf_putchar(c, shf);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fits_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x20,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fits_bits(int x, int n) {
  int bits_of_int = sizeof(int) << 3;
  int shift_size = bits_of_int - n;
  int shift_left_then_right = (x << shift_size) >> shift_size;
  return x == shift_left_then_right;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fits_bits>:
  endbr64
  mov    $0x20,%ecx
  sub    %esi,%ecx
  mov    %edi,%eax
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fits_bits(int x, int n) {
  int bits_of_int = sizeof(int) << 3;
  int shift_size = bits_of_int - n;
  int shift_left_then_right = (x << shift_size) >> shift_size;
  return x == shift_left_then_right;
}
```
user: What is the c source code of the assembly code below:

```asm
<fits_bits>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fits_bits(int x, int n) {
  int bits_of_int = sizeof(int) << 3;
  int shift_size = bits_of_int - n;
  int shift_left_then_right = (x << shift_size) >> shift_size;
  return x == shift_left_then_right;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fits_bits>:
  endbr64
  mov    $0x20,%ecx
  mov    %edi,%eax
  sub    %esi,%ecx
  shl    %cl,%eax
  sar    %cl,%eax
  cmp    %edi,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fits_bits(int x, int n) {
  int bits_of_int = sizeof(int) << 3;
  int shift_size = bits_of_int - n;
  int shift_left_then_right = (x << shift_size) >> shift_size;
  return x == shift_left_then_right;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BN_GF2m_mod_sqrt_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_check_top@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L31
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_zero@plt>
  mov    $0x1,%eax
  jmp    L43
L31:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_start@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BN_set_bit@plt>
  test   %eax,%eax
  je     L42
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <BN_GF2m_mod_exp_arr@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bn_check_top@plt>
  jmp    L19
L2:
  nop
  jmp    L19
L42:
  nop
L19:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_CTX_end@plt>
  mov    -0xc(%rbp),%eax
L43:
  leave
  ret
```

assistant: ```c
int BN_GF2m_mod_sqrt_arr(BIGNUM *r, const BIGNUM *a, const int p[], BN_CTX *ctx) {
  int ret = 0;
  BIGNUM *u;
  bn_check_top(a);
  if (!p[0]) {
    BN_zero(r);
    return 1;
  }
  BN_CTX_start(ctx);
  if ((u = BN_CTX_get(ctx)) == NULL)
    goto err;
  if (!BN_set_bit(u, p[0] - 1))
    goto err;
  ret = BN_GF2m_mod_exp_arr(r, a, u, p, ctx);
  bn_check_top(r);
err:
  BN_CTX_end(ctx);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BN_GF2m_mod_sqrt_arr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %rsi,%rdi
  call   <bn_check_top@plt>
  cmpl   $0x0,0x0(%rbp)
  je     L6
  mov    %rbx,%rdi
  call   <BN_CTX_start@plt>
  mov    %rbx,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r15
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L14
  mov    0x0(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    %r15,%rdi
  call   <BN_set_bit@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L32
L14:
  mov    %rbx,%rdi
  call   <BN_CTX_end@plt>
L45:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    %r14,%rdi
  call   <BN_zero@plt>
  mov    $0x1,%r12d
  jmp    L45
L32:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <BN_GF2m_mod_exp_arr@plt>
  mov    %eax,%r12d
  mov    %r14,%rdi
  call   <bn_check_top@plt>
  jmp    L14
```

assistant: ```c
int BN_GF2m_mod_sqrt_arr(BIGNUM *r, const BIGNUM *a, const int p[], BN_CTX *ctx) {
  int ret = 0;
  BIGNUM *u;
  bn_check_top(a);
  if (!p[0]) {
    BN_zero(r);
    return 1;
  }
  BN_CTX_start(ctx);
  if ((u = BN_CTX_get(ctx)) == NULL)
    goto err;
  if (!BN_set_bit(u, p[0] - 1))
    goto err;
  ret = BN_GF2m_mod_exp_arr(r, a, u, p, ctx);
  bn_check_top(r);
err:
  BN_CTX_end(ctx);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BN_GF2m_mod_sqrt_arr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <bn_check_top@plt>
  mov    (%r12),%eax
  test   %eax,%eax
  je     L25
  mov    %rbp,%rdi
  call   <BN_CTX_start@plt>
  mov    %rbp,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L27
  mov    (%r12),%eax
  mov    %r15,%rdi
  lea    -0x1(%rax),%esi
  call   <BN_set_bit@plt>
  test   %eax,%eax
  je     L27
  mov    %r12,%rcx
  mov    %r14,%rdi
  mov    %rbp,%r8
  mov    %r15,%rdx
  mov    %r13,%rsi
  call   <BN_GF2m_mod_exp_arr@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <bn_check_top@plt>
L3:
  mov    %rbp,%rdi
  call   <BN_CTX_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %r12d,%r12d
  jmp    L3
  nopl   (%rax)
L25:
  mov    %r14,%rdi
  mov    $0x1,%r12d
  call   <BN_zero@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int BN_GF2m_mod_sqrt_arr(BIGNUM *r, const BIGNUM *a, const int p[], BN_CTX *ctx) {
  int ret = 0;
  BIGNUM *u;
  bn_check_top(a);
  if (!p[0]) {
    BN_zero(r);
    return 1;
  }
  BN_CTX_start(ctx);
  if ((u = BN_CTX_get(ctx)) == NULL)
    goto err;
  if (!BN_set_bit(u, p[0] - 1))
    goto err;
  ret = BN_GF2m_mod_exp_arr(r, a, u, p, ctx);
  bn_check_top(r);
err:
  BN_CTX_end(ctx);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BN_GF2m_mod_sqrt_arr>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  call   <bn_check_top@plt>
  mov    (%r12),%eax
  test   %eax,%eax
  je     L22
  mov    %rbp,%rdi
  call   <BN_CTX_start@plt>
  mov    %rbp,%rdi
  call   <BN_CTX_get@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L0
  mov    (%r12),%eax
  mov    %r15,%rdi
  lea    -0x1(%rax),%esi
  call   <BN_set_bit@plt>
  test   %eax,%eax
  je     L0
  mov    %r12,%rcx
  mov    %r14,%rdi
  mov    %rbp,%r8
  mov    %r15,%rdx
  mov    %r13,%rsi
  call   <BN_GF2m_mod_exp_arr@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <bn_check_top@plt>
L30:
  mov    %rbp,%rdi
  call   <BN_CTX_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  jmp    L30
  nopl   (%rax)
L22:
  mov    %r14,%rdi
  mov    $0x1,%r12d
  call   <BN_zero@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int BN_GF2m_mod_sqrt_arr(BIGNUM *r, const BIGNUM *a, const int p[], BN_CTX *ctx) {
  int ret = 0;
  BIGNUM *u;
  bn_check_top(a);
  if (!p[0]) {
    BN_zero(r);
    return 1;
  }
  BN_CTX_start(ctx);
  if ((u = BN_CTX_get(ctx)) == NULL)
    goto err;
  if (!BN_set_bit(u, p[0] - 1))
    goto err;
  ret = BN_GF2m_mod_exp_arr(r, a, u, p, ctx);
  bn_check_top(r);
err:
  BN_CTX_end(ctx);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<coef_deriv_d>:
  endbr64
  cmp    $0x1,%rdi
  je     L27
  cmp    $0x2,%rdi
  je     L20
  test   %rdi,%rdi
  je     L35
L23:
  ret
L35:
  movq   $0x0,(%rdx)
  movsd  D33(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  D15(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x18(%rsi),%xmm0
  xorpd  D25(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rsi),%xmm0
  subsd  0x8(%rsi),%xmm0
  mulsd  D93(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
L27:
  movsd  D15(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movq   $0x0,0x8(%rdx)
  movsd  D33(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x28(%rsi),%xmm0
  xorpd  D25(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  (%rsi),%xmm0
  subsd  0x10(%rsi),%xmm0
  mulsd  D93(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
L20:
  movsd  D33(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  D15(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movq   $0x0,0x10(%rdx)
  movsd  0x8(%rsi),%xmm0
  subsd  (%rsi),%xmm0
  mulsd  D93(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x20(%rsi),%xmm0
  xorpd  D25(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D15
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D25
data_type: f32[4]
name: retrieve_data
arguments: data_tag: D93
data_type: byte[8]

tool: {"D33": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0x3f]}

tool: {"D15": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0xbf]}

tool: {"D25": [0.0,-0.0,0.0,0.0]}

tool: {"D93": [0x1d,0x33,0x90,0x45,0xa7,0x79,0xf2,0x3f]}

assistant: ```c
void coef_deriv_d(size_t axis, const double *coef, double *der) {
  const double sqrt3 = sqrt(3.0);
  switch (axis) {
  case 0:
    der[0] = 0.0;
    der[1] = sqrt3 * coef[5];
    der[2] = -sqrt3 * coef[5];
    der[3] = coef[4];
    der[4] = -coef[3];
    der[5] = 2.0 / sqrt3 * (coef[2] - coef[1]);
    break;
  case 1:
    der[0] = -sqrt3 * coef[4];
    der[1] = 0.0;
    der[2] = sqrt3 * coef[4];
    der[3] = -coef[5];
    der[4] = 2.0 / sqrt3 * (coef[0] - coef[2]);
    der[5] = coef[3];
    break;
  case 2:
    der[0] = sqrt3 * coef[3];
    der[1] = -sqrt3 * coef[3];
    der[2] = 0.0;
    der[3] = 2.0 / sqrt3 * (coef[1] - coef[0]);
    der[4] = coef[5];
    der[5] = -coef[4];
    break;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<coef_deriv_d>:
  endbr64
  cmp    $0x1,%rdi
  je     L22
  cmp    $0x2,%rdi
  je     L4
  test   %rdi,%rdi
  je     L16
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  movq   $0x0,(%rdx)
  movsd  D53(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  D88(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x18(%rsi),%xmm0
  xorpd  D94(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rsi),%xmm0
  subsd  0x8(%rsi),%xmm0
  mulsd  D25(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
  nop
L4:
  movsd  D53(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  D88(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movq   $0x0,0x10(%rdx)
  movsd  %xmm0,0x8(%rdx)
  movsd  0x8(%rsi),%xmm0
  subsd  (%rsi),%xmm0
  mulsd  D25(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x20(%rsi),%xmm0
  xorpd  D94(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
  xchg   %ax,%ax
L22:
  movsd  D88(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movq   $0x0,0x8(%rdx)
  movsd  %xmm0,(%rdx)
  movsd  D53(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x28(%rsi),%xmm0
  xorpd  D94(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  (%rsi),%xmm0
  subsd  0x10(%rsi),%xmm0
  mulsd  D25(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
```

tool_calls: name: read_data
arguments: tag: D53
datatype: byte[8]
name: read_data
arguments: tag: D88
datatype: byte[8]
name: read_data
arguments: tag: D94
datatype: f32[4]
name: read_data
arguments: tag: D25
datatype: byte[8]

tool: {"D53": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0x3f]}

tool: {"D88": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0xbf]}

tool: {"D94": [0.0,-0.0,0.0,0.0]}

tool: {"D25": [0x1d,0x33,0x90,0x45,0xa7,0x79,0xf2,0x3f]}

assistant: ```c
void coef_deriv_d(size_t axis, const double *coef, double *der) {
  const double sqrt3 = sqrt(3.0);
  switch (axis) {
  case 0:
    der[0] = 0.0;
    der[1] = sqrt3 * coef[5];
    der[2] = -sqrt3 * coef[5];
    der[3] = coef[4];
    der[4] = -coef[3];
    der[5] = 2.0 / sqrt3 * (coef[2] - coef[1]);
    break;
  case 1:
    der[0] = -sqrt3 * coef[4];
    der[1] = 0.0;
    der[2] = sqrt3 * coef[4];
    der[3] = -coef[5];
    der[4] = 2.0 / sqrt3 * (coef[0] - coef[2]);
    der[5] = coef[3];
    break;
  case 2:
    der[0] = sqrt3 * coef[3];
    der[1] = -sqrt3 * coef[3];
    der[2] = 0.0;
    der[3] = 2.0 / sqrt3 * (coef[1] - coef[0]);
    der[4] = coef[5];
    der[5] = -coef[4];
    break;
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<coef_deriv_d>:
  endbr64
  cmp    $0x1,%rdi
  je     L28
  cmp    $0x2,%rdi
  je     L18
  test   %rdi,%rdi
  je     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movq   $0x0,(%rdx)
  movsd  D72(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  D7(%rip),%xmm0
  mulsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x18(%rsi),%xmm0
  xorpd  D119(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x10(%rsi),%xmm0
  subsd  0x8(%rsi),%xmm0
  mulsd  D57(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
  nop
L18:
  movsd  D72(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  D7(%rip),%xmm0
  mulsd  0x18(%rsi),%xmm0
  movq   $0x0,0x10(%rdx)
  movsd  %xmm0,0x8(%rdx)
  movsd  0x8(%rsi),%xmm0
  subsd  (%rsi),%xmm0
  mulsd  D57(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  0x28(%rsi),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x20(%rsi),%xmm0
  xorpd  D119(%rip),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
  xchg   %ax,%ax
L28:
  movsd  D7(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movq   $0x0,0x8(%rdx)
  movsd  %xmm0,(%rdx)
  movsd  D72(%rip),%xmm0
  mulsd  0x20(%rsi),%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x28(%rsi),%xmm0
  xorpd  D119(%rip),%xmm0
  movsd  %xmm0,0x18(%rdx)
  movsd  (%rsi),%xmm0
  subsd  0x10(%rsi),%xmm0
  mulsd  D57(%rip),%xmm0
  movsd  %xmm0,0x20(%rdx)
  movsd  0x18(%rsi),%xmm0
  movsd  %xmm0,0x28(%rdx)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D72
datatype: byte[8]
name: disassemble_data
arguments: tag: D7
datatype: byte[8]
name: disassemble_data
arguments: tag: D119
datatype: f32[4]
name: disassemble_data
arguments: tag: D57
datatype: byte[8]

tool: {"D72": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0x3f]}

tool: {"D7": [0xaa,0x4c,0x58,0xe8,0x7a,0xb6,0xfb,0xbf]}

tool: {"D119": [0.0,-0.0,0.0,0.0]}

tool: {"D57": [0x1d,0x33,0x90,0x45,0xa7,0x79,0xf2,0x3f]}

assistant: ```c
void coef_deriv_d(size_t axis, const double *coef, double *der) {
  const double sqrt3 = sqrt(3.0);
  switch (axis) {
  case 0:
    der[0] = 0.0;
    der[1] = sqrt3 * coef[5];
    der[2] = -sqrt3 * coef[5];
    der[3] = coef[4];
    der[4] = -coef[3];
    der[5] = 2.0 / sqrt3 * (coef[2] - coef[1]);
    break;
  case 1:
    der[0] = -sqrt3 * coef[4];
    der[1] = 0.0;
    der[2] = sqrt3 * coef[4];
    der[3] = -coef[5];
    der[4] = 2.0 / sqrt3 * (coef[0] - coef[2]);
    der[5] = coef[3];
    break;
  case 2:
    der[0] = sqrt3 * coef[3];
    der[1] = -sqrt3 * coef[3];
    der[2] = 0.0;
    der[3] = 2.0 / sqrt3 * (coef[1] - coef[0]);
    der[4] = coef[5];
    der[5] = -coef[4];
    break;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_trial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <genrand@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double run_trial(struct mt19937p *mt) {
  double X = 0;
  X = genrand(mt);
  return X;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_trial>:
  endbr64
  sub    $0x8,%rsp
  call   <genrand@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double run_trial(struct mt19937p *mt) {
  double X = 0;
  X = genrand(mt);
  return X;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_trial>:
  endbr64
  jmp    1050 <genrand@plt>
```

assistant: ```c
double run_trial(struct mt19937p *mt) {
  double X = 0;
  X = genrand(mt);
  return X;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<run_trial>:
  endbr64
  jmp    1050 <genrand@plt>
```

assistant: ```c
double run_trial(struct mt19937p *mt) {
  double X = 0;
  X = genrand(mt);
  return X;
}
```