ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D26(%rip),%r13
  mov    %r14,%rsi
  push   %r12
  mov    %r13,%rdi
  lea    D10(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fprintf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D26
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string

tool: D12: a

tool: D26: test.txt

tool: D10: Testing...


assistant: ```c
int main() {
  FILE *fp1;
  fp1 = fopen("test.txt", "a");
  fprintf(fp1, "Testing...\n");
  FILE *fp2;
  fp2 = fopen("test.txt", "a");
  fprintf(fp2, "Testing...\n");
  fp2 = fp1;
  fclose(fp2);
  fclose(fp1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L18
  mov    $0x0,%eax
  jmp    L6
L18:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, f;
  if (argc != 2)
    return 0;
  n = atoi(argv[1]);
  f = factorial(n);
  printf("%d\n", f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L3
  mov    $0x0,%eax
  ret
L3:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, f;
  if (argc != 2)
    return 0;
  n = atoi(argv[1]);
  f = factorial(n);
  printf("%d\n", f);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L6
  xor    %eax,%eax
  ret
L6:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <factorial@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, f;
  if (argc != 2)
    return 0;
  n = atoi(argv[1]);
  f = factorial(n);
  printf("%d\n", f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L3
  xor    %eax,%eax
  ret
L3:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <factorial@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, f;
  if (argc != 2)
    return 0;
  n = atoi(argv[1]);
  f = factorial(n);
  printf("%d\n", f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jne    L19
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L10
L19:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string

tool: D14: True


tool: D11: False


assistant: ```c
int main(int argc, char const *argv[]) {
  int x = 5;
  if (5 == x) {
    printf("True\n");
  } else {
    printf("False\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: True


assistant: ```c
int main(int argc, char const *argv[]) {
  int x = 5;
  if (5 == x) {
    printf("True\n");
  } else {
    printf("False\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: True


assistant: ```c
int main(int argc, char const *argv[]) {
  int x = 5;
  if (5 == x) {
    printf("True\n");
  } else {
    printf("False\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: True


assistant: ```c
int main(int argc, char const *argv[]) {
  int x = 5;
  if (5 == x) {
    printf("True\n");
  } else {
    printf("False\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unlink_secure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <file_exists@plt>
  test   %rax,%rax
  jne    L15
  mov    -0x8(%rbp),%rax
  mov    $0xf1ff,%esi
  mov    %rax,%rdi
  call   <sysLv2FsChmod@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sysLv2FsUnlink@plt>
  jmp    L18
L15:
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

assistant: ```c
int unlink_secure(void *path) {
  if (file_exists(path) == 0) {
    sysLv2FsChmod(path, 0170000 | 0777);
    return sysLv2FsUnlink(path);
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unlink_secure>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <file_exists@plt>
  test   %rax,%rax
  jne    L7
  mov    $0xf1ff,%esi
  mov    %rbx,%rdi
  call   <sysLv2FsChmod@plt>
  mov    %rbx,%rdi
  call   <sysLv2FsUnlink@plt>
L5:
  pop    %rbx
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int unlink_secure(void *path) {
  if (file_exists(path) == 0) {
    sysLv2FsChmod(path, 0170000 | 0777);
    return sysLv2FsUnlink(path);
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unlink_secure>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <file_exists@plt>
  test   %rax,%rax
  jne    L4
  mov    %rbp,%rdi
  mov    $0xf1ff,%esi
  call   <sysLv2FsChmod@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <sysLv2FsUnlink@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int unlink_secure(void *path) {
  if (file_exists(path) == 0) {
    sysLv2FsChmod(path, 0170000 | 0777);
    return sysLv2FsUnlink(path);
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<unlink_secure>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <file_exists@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  mov    $0xf1ff,%esi
  call   <sysLv2FsChmod@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <sysLv2FsUnlink@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int unlink_secure(void *path) {
  if (file_exists(path) == 0) {
    sysLv2FsChmod(path, 0170000 | 0777);
    return sysLv2FsUnlink(path);
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
clock_t _times(void *buf) {
  assert(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_times>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t _times(void *buf) {
  assert(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_times>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t _times(void *buf) {
  assert(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_times>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
clock_t _times(void *buf) {
  assert(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sb1_cmd_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L58
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D20(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D62(%rip),%rax
  jmp    L44
  lea    D73(%rip),%rax
  jmp    L44
  lea    D22(%rip),%rax
  jmp    L44
  lea    D60(%rip),%rax
  jmp    L44
  lea    D4(%rip),%rax
  jmp    L44
  lea    D68(%rip),%rax
  jmp    L44
L58:
  lea    D14(%rip),%rax
L44:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D62
data_type: string
name: extract_symbolic_data
arguments: data_label: D73
data_type: string
name: extract_symbolic_data
arguments: data_label: D22
data_type: string
name: extract_symbolic_data
arguments: data_label: D60
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D68
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string

tool: D62: load

tool: D73: fill

tool: D22: jump

tool: D60: call

tool: D4: mode

tool: D68: sdram

tool: D14: unknown

assistant: ```c
const char *sb1_cmd_name(int cmd) {
  switch (cmd) {
  case 0x1:
    return "load";
  case 0x2:
    return "fill";
  case 0x3:
    return "jump";
  case 0x4:
    return "call";
  case 0x5:
    return "mode";
  case 0x6:
    return "sdram";
  default:
    return "unknown";
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sb1_cmd_name>:
  endbr64
  cmp    $0x6,%edi
  ja     L8
  mov    %edi,%edi
  lea    D74(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D60(%rip),%rax
  ret
  lea    D4(%rip),%rax
  ret
  lea    D67(%rip),%rax
  ret
  lea    D21(%rip),%rax
  ret
  lea    D40(%rip),%rax
  ret
L8:
  lea    D68(%rip),%rax
  ret
  lea    D25(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D60
datatype: string
name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D67
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D40
datatype: string
name: parse_data
arguments: label: D68
datatype: string
name: parse_data
arguments: label: D25
datatype: string

tool: D60: fill

tool: D4: jump

tool: D67: call

tool: D21: mode

tool: D40: sdram

tool: D68: unknown

tool: D25: load

assistant: ```c
const char *sb1_cmd_name(int cmd) {
  switch (cmd) {
  case 0x1:
    return "load";
  case 0x2:
    return "fill";
  case 0x3:
    return "jump";
  case 0x4:
    return "call";
  case 0x5:
    return "mode";
  case 0x6:
    return "sdram";
  default:
    return "unknown";
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sb1_cmd_name>:
  endbr64
  cmp    $0x6,%edi
  ja     L8
  lea    D71(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D16(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D44(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D31(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D41(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D26(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D49(%rip),%rax
  ret
L8:
  lea    D45(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D44
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D41
type: string
name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D49
type: string
name: extract_symbolic_data
arguments: label: D45
type: string

tool: D16: fill

tool: D44: load

tool: D31: sdram

tool: D41: jump

tool: D26: call

tool: D49: mode

tool: D45: unknown

assistant: ```c
const char *sb1_cmd_name(int cmd) {
  switch (cmd) {
  case 0x1:
    return "load";
  case 0x2:
    return "fill";
  case 0x3:
    return "jump";
  case 0x4:
    return "call";
  case 0x5:
    return "mode";
  case 0x6:
    return "sdram";
  default:
    return "unknown";
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sb1_cmd_name>:
  endbr64
  cmp    $0x6,%edi
  ja     L3
  lea    D38(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D2(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D77(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D79(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D34(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D32(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D60(%rip),%rax
  ret
L3:
  lea    D51(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D77
data_type: string
name: disassemble_data
arguments: data_label: D79
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string
name: disassemble_data
arguments: data_label: D32
data_type: string
name: disassemble_data
arguments: data_label: D60
data_type: string
name: disassemble_data
arguments: data_label: D51
data_type: string

tool: D2: fill

tool: D77: load

tool: D79: sdram

tool: D34: jump

tool: D32: call

tool: D60: mode

tool: D51: unknown

assistant: ```c
const char *sb1_cmd_name(int cmd) {
  switch (cmd) {
  case 0x1:
    return "load";
  case 0x2:
    return "fill";
  case 0x3:
    return "jump";
  case 0x4:
    return "call";
  case 0x5:
    return "mode";
  case 0x6:
    return "sdram";
  default:
    return "unknown";
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testFuncCompOpti3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L11
L12:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cmp    $0x63,%eax
  jbe    L12
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testFuncCompOpti3(void) {
  int i = 1U;
  int counter = 0U;
  int a = 0U;
  int b = 10U;
  int sum = 0U;
  for (i = 1U; i < 100U; i++) {
    counter = counter + 1U;
    sum = a + b;
  }
  sum = sum * 2U;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testFuncCompOpti3>:
  endbr64
  mov    $0x63,%eax
L9:
  sub    $0x1,%eax
  jne    L9
  ret
```

assistant: ```c
void testFuncCompOpti3(void) {
  int i = 1U;
  int counter = 0U;
  int a = 0U;
  int b = 10U;
  int sum = 0U;
  for (i = 1U; i < 100U; i++) {
    counter = counter + 1U;
    sum = a + b;
  }
  sum = sum * 2U;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testFuncCompOpti3>:
  endbr64
  ret
```

assistant: ```c
void testFuncCompOpti3(void) {
  int i = 1U;
  int counter = 0U;
  int a = 0U;
  int b = 10U;
  int sum = 0U;
  for (i = 1U; i < 100U; i++) {
    counter = counter + 1U;
    sum = a + b;
  }
  sum = sum * 2U;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testFuncCompOpti3>:
  endbr64
  ret
```

assistant: ```c
void testFuncCompOpti3(void) {
  int i = 1U;
  int counter = 0U;
  int a = 0U;
  int b = 10U;
  int sum = 0U;
  for (i = 1U; i < 100U; i++) {
    counter = counter + 1U;
    sum = a + b;
  }
  sum = sum * 2U;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  call   <func0>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func0(void) {
  if (1) {
    func0();
    return (1);
  } else if (2) {
    func0();
    return (2);
  } else {
    func0();
    return (0);
  }
  while (1) {
    func0();
    return (1);
  }
  for (; 1;) {
    func0();
    return (1);
  }
  do {
    func0();
    return (1);
  } while (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<func0>:
  endbr64
  sub    $0x8,%rsp
  call   <func0>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func0(void) {
  if (1) {
    func0();
    return (1);
  } else if (2) {
    func0();
    return (2);
  } else {
    func0();
    return (0);
  }
  while (1) {
    func0();
    return (1);
  }
  for (; 1;) {
    func0();
    return (1);
  }
  do {
    func0();
    return (1);
  } while (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<func0>:
  endbr64
  sub    $0x8,%rsp
  call   <func0>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func0(void) {
  if (1) {
    func0();
    return (1);
  } else if (2) {
    func0();
    return (2);
  } else {
    func0();
    return (0);
  }
  while (1) {
    func0();
    return (1);
  }
  for (; 1;) {
    func0();
    return (1);
  }
  do {
    func0();
    return (1);
  } while (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func0>:
  endbr64
  sub    $0x8,%rsp
  call   <func0>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int func0(void) {
  if (1) {
    func0();
    return (1);
  } else if (2) {
    func0();
    return (2);
  } else {
    func0();
    return (0);
  }
  while (1) {
    func0();
    return (1);
  }
  for (; 1;) {
    func0();
    return (1);
  }
  do {
    func0();
    return (1);
  } while (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_array(float *a, float *b, float *r, int n) {
  int i;
  for (i = 0; i < n; i++) {
    r[i] = a[i] + b[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add_array>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  mov    %ecx,%ecx
  mov    $0x0,%eax
L1:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L1
L9:
  ret
```

assistant: ```c
void add_array(float *a, float *b, float *r, int n) {
  int i;
  for (i = 0; i < n; i++) {
    r[i] = a[i] + b[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_array>:
  endbr64
  test   %ecx,%ecx
  jle    L13
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L12:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L12
L13:
  ret
```

assistant: ```c
void add_array(float *a, float *b, float *r, int n) {
  int i;
  for (i = 0; i < n; i++) {
    r[i] = a[i] + b[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_array>:
  endbr64
  test   %ecx,%ecx
  jle    L70
  lea    0x4(%rsi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  seta   %r8b
  cmp    $0x1,%ecx
  setne  %al
  test   %al,%r8b
  je     L10
  lea    0x4(%rdi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L10
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r9d
  cmp    $0x2,%eax
  jbe    L76
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L71:
  movups (%rdi,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L71
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ecx
  je     L70
  sub    %r8d,%ecx
  mov    %ecx,%r9d
  cmp    $0x1,%ecx
  je     L5
L34:
  mov    %r8d,%ecx
  movq   (%rdi,%rcx,4),%xmm0
  movq   (%rsi,%rcx,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdx,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L70
L5:
  cltq
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  ret
  nopl   (%rax)
L10:
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L69:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L69
L70:
  ret
L76:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L34
```

assistant: ```c
void add_array(float *a, float *b, float *r, int n) {
  int i;
  for (i = 0; i < n; i++) {
    r[i] = a[i] + b[i];
  }
}
```