ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dinverse>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <dvector@plt>
  mov    %r12,%rsi
  mov    $0x1,%edi
  mov    %rax,%rbp
  call   <lvector@plt>
  lea    0x20(%rsp),%rcx
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %rax,%rdx
  mov    %rax,%r13
  call   <dludcmp@plt>
  test   %r12,%r12
  jle    L14
  lea    0x0(,%r12,8),%rax
  mov    $0x1,%r15d
  lea    0x1(%r12),%r14
  mov    %rax,0x10(%rsp)
  lea    0x8(%rbp),%rax
  mov    %rax,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <memset@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    D1(%rip),%rax
  lea    0x0(,%r15,8),%r8
  mov    %r12,%rsi
  mov    %r8,(%rsp)
  mov    %rax,0x0(%rbp,%r15,8)
  call   <dlubksb@plt>
  mov    (%rsp),%r8
  mov    $0x1,%eax
  nopl   (%rax)
L31:
  movsd  0x0(%rbp,%rax,8),%xmm0
  mov    (%rbx,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%r8,1)
  cmp    %rax,%r14
  jne    L31
  add    $0x1,%r15
  cmp    %r15,%r12
  jge    L21
L14:
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <free_lvector@plt>
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <free_dvector@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: f64

tool: D1: 1

assistant: ```c
void dinverse(double **a, long n, double **y) {
  double d, *col;
  long i, j, *indx;
  col = dvector(1, n);
  indx = lvector(1, n);
  dludcmp(a, n, indx, &d);
  for (j = 1; j <= n; j++) {
    for (i = 1; i <= n; i++)
      col[i] = 0.0;
    col[j] = 1.0;
    dlubksb(a, n, indx, col);
    for (i = 1; i <= n; i++)
      y[i][j] = col[i];
  }
  free_lvector(indx, 1, n);
  free_dvector(col, 1, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initialize_outputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L19:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **initialize_outputs(int *structure, int hidden_layers) {
  double **out_NN = (double **)calloc((hidden_layers + 1), sizeof(double *));
  for (int i = 0; i <= hidden_layers; i++) {
    out_NN[i] = (double *)calloc(structure[i + 1], sizeof(double));
  }
  return out_NN;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<initialize_outputs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r12d
  lea    0x1(%rsi),%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  js     L15
  mov    %rax,%rbp
  mov    $0x0,%ebx
L9:
  mov    0x4(%r13,%rbx,4),%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  jge    L9
L15:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **initialize_outputs(int *structure, int hidden_layers) {
  double **out_NN = (double **)calloc((hidden_layers + 1), sizeof(double *));
  for (int i = 0; i <= hidden_layers; i++) {
    out_NN[i] = (double *)calloc(structure[i + 1], sizeof(double));
  }
  return out_NN;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initialize_outputs>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rsi),%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  js     L8
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L18:
  mov    0x4(%r13,%rbx,4),%edi
  mov    $0x8,%esi
  add    $0x1,%rbx
  add    $0x8,%rbp
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %ebx,%r12d
  jge    L18
L8:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **initialize_outputs(int *structure, int hidden_layers) {
  double **out_NN = (double **)calloc((hidden_layers + 1), sizeof(double *));
  for (int i = 0; i <= hidden_layers; i++) {
    out_NN[i] = (double *)calloc(structure[i + 1], sizeof(double));
  }
  return out_NN;
}
```
user: Translate the below assembly code into C programming language:

```asm
<initialize_outputs>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rsi),%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  js     L8
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L14:
  mov    0x4(%r13,%rbx,4),%edi
  mov    $0x8,%esi
  add    $0x1,%rbx
  add    $0x8,%rbp
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %ebx,%r12d
  jge    L14
L8:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double **initialize_outputs(int *structure, int hidden_layers) {
  double **out_NN = (double **)calloc((hidden_layers + 1), sizeof(double *));
  for (int i = 0; i <= hidden_layers; i++) {
    out_NN[i] = (double *)calloc(structure[i + 1], sizeof(double));
  }
  return out_NN;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pso_sphere>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double pso_sphere(double *vec, int dim, void *params) {
  double sum = 0;
  int i;
  for (i = 0; i < dim; i++)
    sum += pow(vec[i], 2);
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<pso_sphere>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L23
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
L18:
  mov    $0x2,%edi
  movsd  (%rbx),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L18
L1:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L1
```

assistant: ```c
double pso_sphere(double *vec, int dim, void *params) {
  double sum = 0;
  int i;
  for (i = 0; i < dim; i++)
    sum += pow(vec[i], 2);
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pso_sphere>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %rbp
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L10:
  movsd  (%rbx),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbp,%rbx
  jne    L10
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double pso_sphere(double *vec, int dim, void *params) {
  double sum = 0;
  int i;
  for (i = 0; i < dim; i++)
    sum += pow(vec[i], 2);
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pso_sphere>:
  endbr64
  test   %esi,%esi
  jle    L10
  push   %rbp
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  push   %rbx
  lea    0x8(%rdi,%rax,8),%rbp
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L18:
  movsd  (%rbx),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  add    $0x8,%rbx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbp,%rbx
  jne    L18
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double pso_sphere(double *vec, int dim, void *params) {
  double sum = 0;
  int i;
  for (i = 0; i < dim; i++)
    sum += pow(vec[i], 2);
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UMVLine16Y_11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L2
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  jmp    L1
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short UMVLine16Y_11(short unsigned int *Pic, int y, int width) {
  if (y != width) {
    y = y < 0 ? 0 : y;
    return Pic[y * width];
  }
  return Pic[y];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UMVLine16Y_11>:
  endbr64
  cmp    %edx,%esi
  je     L0
  test   %esi,%esi
  mov    $0x0,%eax
  cmovs  %eax,%esi
  imul   %edx,%esi
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
L0:
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
```

assistant: ```c
unsigned short UMVLine16Y_11(short unsigned int *Pic, int y, int width) {
  if (y != width) {
    y = y < 0 ? 0 : y;
    return Pic[y * width];
  }
  return Pic[y];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UMVLine16Y_11>:
  endbr64
  cmp    %edx,%esi
  je     L4
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  imul   %edx,%esi
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
```

assistant: ```c
unsigned short UMVLine16Y_11(short unsigned int *Pic, int y, int width) {
  if (y != width) {
    y = y < 0 ? 0 : y;
    return Pic[y * width];
  }
  return Pic[y];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UMVLine16Y_11>:
  endbr64
  cmp    %edx,%esi
  je     L8
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  imul   %edx,%esi
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %esi,%rsi
  movzwl (%rdi,%rsi,2),%eax
  ret
```

assistant: ```c
unsigned short UMVLine16Y_11(short unsigned int *Pic, int y, int width) {
  if (y != width) {
    y = y < 0 ? 0 : y;
    return Pic[y * width];
  }
  return Pic[y];
}
```
user: What is the c source code of the assembly code below?

```asm
<EPINonBlockingReadCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x400d0000,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x1,-0x18(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x28(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Channel < 2);
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: What is the c source code of the assembly code below?

```asm
<EPINonBlockingReadCount>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    $0x400d0000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x1,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  shl    $0x4,%ebx
  lea    0x28(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Channel < 2);
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EPINonBlockingReadCount>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebp
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x1,%ebx
  setle  %dil
  shl    $0x4,%ebx
  call   <ASSERT@plt>
  lea    0x28(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Channel < 2);
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EPINonBlockingReadCount>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebp
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x1,%ebx
  setle  %dil
  shl    $0x4,%ebx
  call   <ASSERT@plt>
  lea    0x28(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32Channel < 2);
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exact_square@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exact_square@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string

tool: D16: %d

tool: D12: %d


assistant: ```c
int main() {
  int number = 0;
  scanf("%d", &number);
  exact_square(number);
  printf("%d\n", exact_square(number));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D13: %d

tool: D14: %d


assistant: ```c
int main() {
  int number = 0;
  scanf("%d", &number);
  exact_square(number);
  printf("%d\n", exact_square(number));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string

tool: D7: %d

tool: D12: %d


assistant: ```c
int main() {
  int number = 0;
  scanf("%d", &number);
  exact_square(number);
  printf("%d\n", exact_square(number));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D6: %d

tool: D15: %d


assistant: ```c
int main() {
  int number = 0;
  scanf("%d", &number);
  exact_square(number);
  printf("%d\n", exact_square(number));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_getAvdTargetArch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_getAvdContentPath@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_getAvdTargetArch@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *path_getAvdTargetArch(const char *avdName) {
  char *avdPath = _getAvdContentPath(avdName);
  char *avdArch = _getAvdTargetArch(avdPath);
  return avdArch;
}
```
user: What is the c source code of the assembly code below:

```asm
<path_getAvdTargetArch>:
  endbr64
  sub    $0x8,%rsp
  call   <_getAvdContentPath@plt>
  mov    %rax,%rdi
  call   <_getAvdTargetArch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *path_getAvdTargetArch(const char *avdName) {
  char *avdPath = _getAvdContentPath(avdName);
  char *avdArch = _getAvdTargetArch(avdPath);
  return avdArch;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<path_getAvdTargetArch>:
  endbr64
  sub    $0x8,%rsp
  call   <_getAvdContentPath@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <_getAvdTargetArch@plt>
```

assistant: ```c
char *path_getAvdTargetArch(const char *avdName) {
  char *avdPath = _getAvdContentPath(avdName);
  char *avdArch = _getAvdTargetArch(avdPath);
  return avdArch;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<path_getAvdTargetArch>:
  endbr64
  sub    $0x8,%rsp
  call   <_getAvdContentPath@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <_getAvdTargetArch@plt>
```

assistant: ```c
char *path_getAvdTargetArch(const char *avdName) {
  char *avdPath = _getAvdContentPath(avdName);
  char *avdArch = _getAvdTargetArch(avdPath);
  return avdArch;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L8
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse_string@plt>
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *rstrdup(const char *str) {
  if (!str)
    return NULL;
  char *rstr = strdup(str);
  reverse_string(rstr);
  return rstr;
}
```
user: What is the c source code of the assembly code below:

```asm
<rstrdup>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L11
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <reverse_string@plt>
L16:
  mov    %rbx,%rax
  pop    %rbx
  ret
L11:
  mov    %rdi,%rbx
  jmp    L16
```

assistant: ```c
char *rstrdup(const char *str) {
  if (!str)
    return NULL;
  char *rstr = strdup(str);
  reverse_string(rstr);
  return rstr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rstrdup>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L4
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <reverse_string@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *rstrdup(const char *str) {
  if (!str)
    return NULL;
  char *rstr = strdup(str);
  reverse_string(rstr);
  return rstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rstrdup>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L8
  call   <strdup@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <reverse_string@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *rstrdup(const char *str) {
  if (!str)
    return NULL;
  char *rstr = strdup(str);
  reverse_string(rstr);
  return rstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<first_larger_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L19
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L13
L19:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <first_larger_prime>
L13:
  leave
  ret
```

assistant: ```c
int first_larger_prime(int n) {
  if (is_prime(n + 1, 3))
    return n + 1;
  else
    return first_larger_prime(n + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<first_larger_prime>:
  endbr64
  push   %rbx
  lea    0x1(%rdi),%ebx
  mov    $0x3,%esi
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L12
L13:
  mov    %ebx,%eax
  pop    %rbx
  ret
L12:
  mov    %ebx,%edi
  call   <first_larger_prime>
  mov    %eax,%ebx
  jmp    L13
```

assistant: ```c
int first_larger_prime(int n) {
  if (is_prime(n + 1, 3))
    return n + 1;
  else
    return first_larger_prime(n + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<first_larger_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  nopl   0x0(%rax)
L0:
  add    $0x1,%r12d
  mov    $0x3,%esi
  mov    %r12d,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L0
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int first_larger_prime(int n) {
  if (is_prime(n + 1, 3))
    return n + 1;
  else
    return first_larger_prime(n + 1);
}
```