user: 请从给定的汇编指令推导出C源代码：

```asm
<tabPrintTransform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %ecx,-0x54(%rbp)
  mov    -0x48(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  cmpl   $0x0,-0x44(%rbp)
  je     L0
  cmpl   $0x0,-0x48(%rbp)
  jne    L108
L0:
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D99(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <tabprintf@plt>
  jmp    L98
L108:
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <tabprintf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L93
L149:
  movl   $0x0,-0x34(%rbp)
  jmp    L76
L55:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  mov    (%rdx,%rax,8),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <signbit@plt>
  test   %eax,%eax
  je     L18
  lea    D46(%rip),%rax
  jmp    L59
L18:
  lea    D15(%rip),%rax
L59:
  mov    %rax,-0x28(%rbp)
  lea    D121(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jne    L53
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jne    L15
  lea    D46(%rip),%rax
  jmp    L52
L15:
  lea    D119(%rip),%rax
  jmp    L52
L53:
  lea    D15(%rip),%rax
L52:
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  mov    (%rdx,%rax,8),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rax,%rsi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L76:
  mov    -0x34(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L55
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x38(%rbp)
  jne    L122
  lea    D36(%rip),%rax
  jmp    L87
L122:
  lea    D56(%rip),%rax
L87:
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <tabprintf@plt>
  addl   $0x1,-0x38(%rbp)
L93:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L149
  mov    $0xa,%edi
  call   <putchar@plt>
L98:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D99
data_type: string
name: parse_data
arguments: tag: D57
data_type: string
name: parse_data
arguments: tag: D46
data_type: string
name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D121
data_type: string
name: parse_data
arguments: tag: D119
data_type: string
name: parse_data
arguments: tag: D77
data_type: string
name: parse_data
arguments: tag: D36
data_type: string
name: parse_data
arguments: tag: D56
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: 

tool: D57: [

tool: 

tool: D15:  

tool: D121: 	

tool: D119: ;

tool: D77: %s%.3lf%s%s

tool: D36: ]


tool: D56: 
 

tool: D10: %s

assistant: ```c
void tabPrintTransform(int r, int c, double M[r][c], int indent) {
  if (r == 0 || c == 0) {
    tabprintf("[]\n", indent);
    return;
  }
  tabprintf("[", indent);
  for (int i = 0; i < r; i++) {
    for (int j = 0; j < c; j++) {
      char *pre = signbit(M[i][j]) ? "" : " ";
      char *post1 = "\t";
      char *post2 = (j == (c - 1)) ? (i == (r - 1)) ? "" : ";" : " ";
      printf("%s%.3lf%s%s", pre, M[i][j], post1, post2);
    }
    printf("%s", (i == (r - 1)) ? "]\n" : "\n ");
    tabprintf(" ", indent);
  }
  printf("\n");
}
```