ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bswap_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L7
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <SwapByteOrder_64@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void bswap_64(const int n, void *u) {
  uint64_t *T = u;
  int i;
  for (i = 0; i < n; i++) {
    *(T + i) = SwapByteOrder_64(*(T + i));
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bswap_64>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
L13:
  mov    (%rbx),%edi
  call   <SwapByteOrder_64@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
void bswap_64(const int n, void *u) {
  uint64_t *T = u;
  int i;
  for (i = 0; i < n; i++) {
    *(T + i) = SwapByteOrder_64(*(T + i));
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bswap_64>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <SwapByteOrder_64@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void bswap_64(const int n, void *u) {
  uint64_t *T = u;
  int i;
  for (i = 0; i < n; i++) {
    *(T + i) = SwapByteOrder_64(*(T + i));
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bswap_64>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L13:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <SwapByteOrder_64@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void bswap_64(const int n, void *u) {
  uint64_t *T = u;
  int i;
  for (i = 0; i < n; i++) {
    *(T + i) = SwapByteOrder_64(*(T + i));
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <call_ddv@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  {
    { call_ddv(); }
    return (0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <call_ddv@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  {
    { call_ddv(); }
    return (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <call_ddv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  {
    { call_ddv(); }
    return (0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <call_ddv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  {
    { call_ddv(); }
    return (0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mapcon_number_of_maps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1b2,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mapcon_number_of_maps(int dim, int *nbmaps) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(434, &dim, nbmaps, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mapcon_number_of_maps>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x1b2,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int mapcon_number_of_maps(int dim, int *nbmaps) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(434, &dim, nbmaps, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mapcon_number_of_maps>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1b2,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int mapcon_number_of_maps(int dim, int *nbmaps) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(434, &dim, nbmaps, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<mapcon_number_of_maps>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1b2,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int mapcon_number_of_maps(int dim, int *nbmaps) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(434, &dim, nbmaps, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_json_indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L17:
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4:  

assistant: ```c
void write_json_indent(FILE *file, int level) {
  for (int i = 0; i < level; i++) {
    fprintf(file, " ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_json_indent>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7:  

assistant: ```c
void write_json_indent(FILE *file, int level) {
  for (int i = 0; i < level; i++) {
    fprintf(file, " ");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_json_indent>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5:  

assistant: ```c
void write_json_indent(FILE *file, int level) {
  for (int i = 0; i < level; i++) {
    fprintf(file, " ");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_json_indent>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <fprintf@plt>
  cmp    %ebx,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9:  

assistant: ```c
void write_json_indent(FILE *file, int level) {
  for (int i = 0; i < level; i++) {
    fprintf(file, " ");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L48
  mov    -0x18(%rbp),%rax
  jmp    L44
L48:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L51
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L44
L51:
  mov    -0x28(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x8(%rbp)
  jmp    L16
L13:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L16:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
L44:
  leave
  ret
```

assistant: ```c
void *memmove(void *dst_, const void *src_, size_t n) {
  const char *src = src_;
  char *dst = dst_;
  if (!n)
    return (dst_);
  if (dst_ <= src_)
    return (memcpy(dst_, src_, n));
  src += n;
  dst += n;
  while (n--) {
    *--dst;
    *--src;
    *dst = *src;
  }
  return (dst_);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L15
  lea    -0x1(%rdx),%rcx
  cmp    %rdi,%rsi
  jae    L28
L7:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L7
  ret
L28:
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
L15:
  ret
```

assistant: ```c
void *memmove(void *dst_, const void *src_, size_t n) {
  const char *src = src_;
  char *dst = dst_;
  if (!n)
    return (dst_);
  if (dst_ <= src_)
    return (memcpy(dst_, src_, n));
  src += n;
  dst += n;
  while (n--) {
    *--dst;
    *--src;
    *dst = *src;
  }
  return (dst_);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L7
  lea    -0x1(%rdx),%rcx
  cmp    %rdi,%rsi
  jae    L19
  nopl   (%rax)
L20:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L20
L7:
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void *memmove(void *dst_, const void *src_, size_t n) {
  const char *src = src_;
  char *dst = dst_;
  if (!n)
    return (dst_);
  if (dst_ <= src_)
    return (memcpy(dst_, src_, n));
  src += n;
  dst += n;
  while (n--) {
    *--dst;
    *--src;
    *dst = *src;
  }
  return (dst_);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L17
  lea    -0x1(%rdx),%rcx
  cmp    %rdi,%rsi
  jae    L14
  nopl   (%rax)
L22:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L22
L17:
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void *memmove(void *dst_, const void *src_, size_t n) {
  const char *src = src_;
  char *dst = dst_;
  if (!n)
    return (dst_);
  if (dst_ <= src_)
    return (memcpy(dst_, src_, n));
  src += n;
  dst += n;
  while (n--) {
    *--dst;
    *--src;
    *dst = *src;
  }
  return (dst_);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PicocInitialise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <BasicIOInit@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <HeapInit@plt>
  mov    $0x0,%eax
  call   <TableInit@plt>
  mov    $0x0,%eax
  call   <VariableInit@plt>
  mov    $0x0,%eax
  call   <LexInit@plt>
  mov    $0x0,%eax
  call   <TypeInit@plt>
  mov    $0x0,%eax
  call   <IncludeInit@plt>
  mov    $0x0,%eax
  call   <LibraryInit@plt>
  mov    $0x0,%eax
  call   <PlatformLibraryInit@plt>
  nop
  leave
  ret
```

assistant: ```c
void PicocInitialise(int StackSize) {
  BasicIOInit();
  HeapInit(StackSize);
  TableInit();
  VariableInit();
  LexInit();
  TypeInit();
  IncludeInit();
  LibraryInit();
  PlatformLibraryInit();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PicocInitialise>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <BasicIOInit@plt>
  mov    %ebx,%edi
  call   <HeapInit@plt>
  mov    $0x0,%eax
  call   <TableInit@plt>
  mov    $0x0,%eax
  call   <VariableInit@plt>
  mov    $0x0,%eax
  call   <LexInit@plt>
  mov    $0x0,%eax
  call   <TypeInit@plt>
  mov    $0x0,%eax
  call   <IncludeInit@plt>
  mov    $0x0,%eax
  call   <LibraryInit@plt>
  mov    $0x0,%eax
  call   <PlatformLibraryInit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void PicocInitialise(int StackSize) {
  BasicIOInit();
  HeapInit(StackSize);
  TableInit();
  VariableInit();
  LexInit();
  TypeInit();
  IncludeInit();
  LibraryInit();
  PlatformLibraryInit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PicocInitialise>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <BasicIOInit@plt>
  mov    %ebp,%edi
  call   <HeapInit@plt>
  xor    %eax,%eax
  call   <TableInit@plt>
  xor    %eax,%eax
  call   <VariableInit@plt>
  xor    %eax,%eax
  call   <LexInit@plt>
  xor    %eax,%eax
  call   <TypeInit@plt>
  xor    %eax,%eax
  call   <IncludeInit@plt>
  xor    %eax,%eax
  call   <LibraryInit@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1100 <PlatformLibraryInit@plt>
```

assistant: ```c
void PicocInitialise(int StackSize) {
  BasicIOInit();
  HeapInit(StackSize);
  TableInit();
  VariableInit();
  LexInit();
  TypeInit();
  IncludeInit();
  LibraryInit();
  PlatformLibraryInit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PicocInitialise>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <BasicIOInit@plt>
  mov    %ebp,%edi
  call   <HeapInit@plt>
  xor    %eax,%eax
  call   <TableInit@plt>
  xor    %eax,%eax
  call   <VariableInit@plt>
  xor    %eax,%eax
  call   <LexInit@plt>
  xor    %eax,%eax
  call   <TypeInit@plt>
  xor    %eax,%eax
  call   <IncludeInit@plt>
  xor    %eax,%eax
  call   <LibraryInit@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1100 <PlatformLibraryInit@plt>
```

assistant: ```c
void PicocInitialise(int StackSize) {
  BasicIOInit();
  HeapInit(StackSize);
  TableInit();
  VariableInit();
  LexInit();
  TypeInit();
  IncludeInit();
  LibraryInit();
  PlatformLibraryInit();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_rotate_left_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffff0000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0xc,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x20,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x24,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x28,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x2c,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L87
  mov    -0x4(%rbp),%eax
  mov    $0x30,%esi
  mov    %eax,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  jne    L87
  mov    $0x1,%eax
  jmp    L26
L87:
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
int test_rotate_left_negative() {
  int num = 0xFFFF0000;
  return 0xFFFF0000 == rotate_left(num, 0) && 0xFFF0000F == rotate_left(num, 4) && 0xFF0000FF == rotate_left(num, 8) && 0xF0000FFF == rotate_left(num, 12) && 0x0000FFFF == rotate_left(num, 16) && 0xFFFF0000 == rotate_left(num, 32) && 0xFFF0000F == rotate_left(num, 36) && 0xFF0000FF == rotate_left(num, 40) && 0xF0000FFF == rotate_left(num, 44) && 0x0000FFFF == rotate_left(num, 48);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_rotate_left_negative>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff0000,%edx
  je     L64
L2:
  add    $0x8,%rsp
  ret
L64:
  mov    $0x4,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xfff0000f,%edx
  jne    L2
  mov    $0x8,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xff0000ff,%edx
  jne    L2
  mov    $0xc,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xf0000fff,%edx
  jne    L2
  mov    $0x10,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff,%edx
  jne    L2
  mov    $0x20,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffff0000,%edx
  jne    L2
  mov    $0x24,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xfff0000f,%edx
  jne    L2
  mov    $0x28,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xff0000ff,%edx
  jne    L2
  mov    $0x2c,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xf0000fff,%edx
  jne    L2
  mov    $0x30,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L2
```

assistant: ```c
int test_rotate_left_negative() {
  int num = 0xFFFF0000;
  return 0xFFFF0000 == rotate_left(num, 0) && 0xFFF0000F == rotate_left(num, 4) && 0xFF0000FF == rotate_left(num, 8) && 0xF0000FFF == rotate_left(num, 12) && 0x0000FFFF == rotate_left(num, 16) && 0xFFFF0000 == rotate_left(num, 32) && 0xFFF0000F == rotate_left(num, 36) && 0xFF0000FF == rotate_left(num, 40) && 0xF0000FFF == rotate_left(num, 44) && 0x0000FFFF == rotate_left(num, 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_rotate_left_negative>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  je     L10
L51:
  xor    %eax,%eax
L38:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x4,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L51
  mov    $0x8,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L51
  mov    $0xc,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L51
  mov    $0x10,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  jne    L51
  mov    $0x20,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L51
  mov    $0x24,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L51
  mov    $0x28,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L51
  mov    $0x2c,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L51
  mov    $0x30,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L38
```

assistant: ```c
int test_rotate_left_negative() {
  int num = 0xFFFF0000;
  return 0xFFFF0000 == rotate_left(num, 0) && 0xFFF0000F == rotate_left(num, 4) && 0xFF0000FF == rotate_left(num, 8) && 0xF0000FFF == rotate_left(num, 12) && 0x0000FFFF == rotate_left(num, 16) && 0xFFFF0000 == rotate_left(num, 32) && 0xFFF0000F == rotate_left(num, 36) && 0xFF0000FF == rotate_left(num, 40) && 0xF0000FFF == rotate_left(num, 44) && 0x0000FFFF == rotate_left(num, 48);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_rotate_left_negative>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  je     L8
L55:
  xor    %eax,%eax
L95:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x4,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L55
  mov    $0x8,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L55
  mov    $0xc,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L55
  mov    $0x10,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  jne    L55
  mov    $0x20,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff0000,%eax
  jne    L55
  mov    $0x24,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xfff0000f,%eax
  jne    L55
  mov    $0x28,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xff0000ff,%eax
  jne    L55
  mov    $0x2c,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xf0000fff,%eax
  jne    L55
  mov    $0x30,%esi
  mov    $0xffff0000,%edi
  call   <rotate_left@plt>
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L95
```

assistant: ```c
int test_rotate_left_negative() {
  int num = 0xFFFF0000;
  return 0xFFFF0000 == rotate_left(num, 0) && 0xFFF0000F == rotate_left(num, 4) && 0xFF0000FF == rotate_left(num, 8) && 0xF0000FFF == rotate_left(num, 12) && 0x0000FFFF == rotate_left(num, 16) && 0xFFFF0000 == rotate_left(num, 32) && 0xFFF0000F == rotate_left(num, 36) && 0xFF0000FF == rotate_left(num, 40) && 0xF0000FFF == rotate_left(num, 44) && 0x0000FFFF == rotate_left(num, 48);
}
```