ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_get_path>:
  endbr64
  test   %rsi,%rsi
  je     L17
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L49
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%r14d
  mov    %eax,%ecx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <snprintf@plt>
  mov    %eax,%r12d
  lea    0x1(%rax),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %r15d,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L43:
  movslq %r12d,%r12
  lea    -0x6(%rbx,%r12,1),%rdi
  lea    D10(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L45
  mov    %rbx,%rdi
  call   <mkstemp@plt>
  mov    %rbx,0x0(%r13)
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L43
  mov    $0xffffffff,%eax
  jmp    L50
L45:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L17:
  mov    $0xffffffff,%eax
  ret
L31:
  mov    $0xffffffff,%eax
  jmp    L50
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D5: %d

tool: D10: XXXXXX

assistant: ```c
int _get_path(char **out, const char *in) {
  int len;
  uid_t uid;
  int fd;
  char *buffer = NULL;
  if (!in)
    return -1;
  if (strstr(in, "%d") != NULL) {
    uid = getuid();
    len = snprintf(buffer, 0, in, uid);
    if ((buffer = malloc(len + 1)) == NULL)
      return -1;
    snprintf(buffer, len + 1, in, uid);
  } else {
    len = strlen(in);
    if ((buffer = strdup(in)) == NULL)
      return -1;
  }
  if (strcmp(&(buffer[len - 6]), "XXXXXX") != 0) {
    free(buffer);
    buffer = NULL;
    return -1;
  }
  fd = mkstemp(buffer);
  *out = buffer;
  return fd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_get_path>:
  endbr64
  test   %rsi,%rsi
  je     L60
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D10(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L43
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%ecx
  mov    %eax,%r13d
  call   <snprintf@plt>
  lea    0x1(%rax),%r14d
  mov    %eax,%r15d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L20
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L62:
  movslq %r15d,%rax
  lea    D0(%rip),%rsi
  lea    -0x6(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L8
  call   <mkstemp@plt>
  mov    %rbp,(%rbx)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L62
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0xffffffff,%eax
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L8:
  call   <free@plt>
  jmp    L20
L60:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D0
datatype: string

tool: D10: %d

tool: D0: XXXXXX

assistant: ```c
int _get_path(char **out, const char *in) {
  int len;
  uid_t uid;
  int fd;
  char *buffer = NULL;
  if (!in)
    return -1;
  if (strstr(in, "%d") != NULL) {
    uid = getuid();
    len = snprintf(buffer, 0, in, uid);
    if ((buffer = malloc(len + 1)) == NULL)
      return -1;
    snprintf(buffer, len + 1, in, uid);
  } else {
    len = strlen(in);
    if ((buffer = strdup(in)) == NULL)
      return -1;
  }
  if (strcmp(&(buffer[len - 6]), "XXXXXX") != 0) {
    free(buffer);
    buffer = NULL;
    return -1;
  }
  fd = mkstemp(buffer);
  *out = buffer;
  return fd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_get_path>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D8(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L33
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%ecx
  mov    %eax,%r13d
  call   <snprintf@plt>
  lea    0x1(%rax),%r14d
  mov    %eax,%r15d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L39
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L22:
  movslq %r15d,%rax
  lea    D16(%rip),%rsi
  lea    -0x6(%rbp,%rax,1),%rdi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L32
  call   <mkstemp@plt>
  mov    %rbp,(%rbx)
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r15d
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L22
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L32:
  call   <free@plt>
  jmp    L39
L9:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D8: %d

tool: D16: XXXXXX

assistant: ```c
int _get_path(char **out, const char *in) {
  int len;
  uid_t uid;
  int fd;
  char *buffer = NULL;
  if (!in)
    return -1;
  if (strstr(in, "%d") != NULL) {
    uid = getuid();
    len = snprintf(buffer, 0, in, uid);
    if ((buffer = malloc(len + 1)) == NULL)
      return -1;
    snprintf(buffer, len + 1, in, uid);
  } else {
    len = strlen(in);
    if ((buffer = strdup(in)) == NULL)
      return -1;
  }
  if (strcmp(&(buffer[len - 6]), "XXXXXX") != 0) {
    free(buffer);
    buffer = NULL;
    return -1;
  }
  fd = mkstemp(buffer);
  *out = buffer;
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movw   $0x17,(%rax)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  leave
  ret
```

assistant: ```c
int main() {
  volatile short *s = malloc(sizeof(short));
  *s = 23;
  return *s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  movw   $0x17,(%rax)
  movzwl (%rax),%eax
  cwtl
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  volatile short *s = malloc(sizeof(short));
  *s = 23;
  return *s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    $0x17,%edx
  mov    %dx,(%rax)
  movswl (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  volatile short *s = malloc(sizeof(short));
  *s = 23;
  return *s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    $0x17,%edx
  mov    %dx,(%rax)
  movswl (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  volatile short *s = malloc(sizeof(short));
  *s = 23;
  return *s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_serial_console>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ax,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movzwl -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <write_serial_data_until_is_empty@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_serial_console(unsigned short com, const char *message, int length) {
  int i;
  for (i = 0; i < length; i++) {
    write_serial_data_until_is_empty(com, message[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_serial_console>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%r12
  movzwl %di,%ebp
L14:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  call   <write_serial_data_until_is_empty@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void write_serial_console(unsigned short com, const char *message, int length) {
  int i;
  for (i = 0; i < length; i++) {
    write_serial_data_until_is_empty(com, message[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_serial_console>:
  endbr64
  test   %edx,%edx
  jle    L3
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x1(%rsi,%rax,1),%r12
  push   %rbp
  movzwl %di,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <write_serial_data_until_is_empty@plt>
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void write_serial_console(unsigned short com, const char *message, int length) {
  int i;
  for (i = 0; i < length; i++) {
    write_serial_data_until_is_empty(com, message[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_serial_console>:
  endbr64
  test   %edx,%edx
  jle    L16
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x1(%rsi,%rax,1),%r12
  push   %rbp
  movzwl %di,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%esi
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <write_serial_data_until_is_empty@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void write_serial_console(unsigned short com, const char *message, int length) {
  int i;
  for (i = 0; i < length; i++) {
    write_serial_data_until_is_empty(com, message[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <make_nodes@plt>
  mov    $0x0,%eax
  call   <test1@plt>
  test   %rax,%rax
  jne    L32
  addl   $0x1,-0x8(%rbp)
L32:
  mov    $0x0,%eax
  call   <test2@plt>
  test   %rax,%rax
  jne    L77
  addl   $0x1,-0x8(%rbp)
L77:
  mov    $0x0,%eax
  call   <test3@plt>
  test   %rax,%rax
  jne    L71
  addl   $0x1,-0x8(%rbp)
L71:
  mov    $0x0,%eax
  call   <test4@plt>
  test   %rax,%rax
  jne    L26
  addl   $0x1,-0x8(%rbp)
L26:
  mov    $0x0,%eax
  call   <test5@plt>
  test   %rax,%rax
  jne    L0
  addl   $0x1,-0x8(%rbp)
L0:
  mov    $0x0,%eax
  call   <test6@plt>
  test   %rax,%rax
  jne    L11
  addl   $0x1,-0x8(%rbp)
L11:
  mov    $0x0,%eax
  call   <test7@plt>
  test   %rax,%rax
  jne    L9
  addl   $0x1,-0x8(%rbp)
L9:
  mov    $0x0,%eax
  call   <test8@plt>
  test   %rax,%rax
  jne    L79
  addl   $0x1,-0x8(%rbp)
L79:
  mov    $0x0,%eax
  call   <test9@plt>
  test   %rax,%rax
  jne    L73
  addl   $0x1,-0x8(%rbp)
L73:
  mov    $0x0,%eax
  call   <remove_nodes@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string

tool: D9: testfile.in

tool: D8: testfile.out

tool: D26: 
Final score: %d/%d


assistant: ```c
int main(void) {
  int num_passed = 0;
  const int total = 9;
  srand(time(NULL));
  make_nodes();
  if (test1() == 0)
    num_passed++;
  if (test2() == 0)
    num_passed++;
  if (test3() == 0)
    num_passed++;
  if (test4() == 0)
    num_passed++;
  if (test5() == 0)
    num_passed++;
  if (test6() == 0)
    num_passed++;
  if (test7() == 0)
    num_passed++;
  if (test8() == 0)
    num_passed++;
  if (test9() == 0)
    num_passed++;
  remove_nodes();
  unlink("testfile.in");
  unlink("testfile.out");
  printf("\nFinal score: %d/%d\n", num_passed, total);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <make_nodes@plt>
  mov    $0x0,%eax
  call   <test1@plt>
  test   %rax,%rax
  sete   %bl
  movzbl %bl,%ebx
  mov    $0x0,%eax
  call   <test2@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test3@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test4@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test5@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test6@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test7@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test8@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <test9@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebx
  mov    $0x0,%eax
  call   <remove_nodes@plt>
  lea    D19(%rip),%rdi
  call   <unlink@plt>
  lea    D20(%rip),%rdi
  call   <unlink@plt>
  mov    $0x9,%edx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D20
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D19: testfile.in

tool: D20: testfile.out

tool: D8: 
Final score: %d/%d


assistant: ```c
int main(void) {
  int num_passed = 0;
  const int total = 9;
  srand(time(NULL));
  make_nodes();
  if (test1() == 0)
    num_passed++;
  if (test2() == 0)
    num_passed++;
  if (test3() == 0)
    num_passed++;
  if (test4() == 0)
    num_passed++;
  if (test5() == 0)
    num_passed++;
  if (test6() == 0)
    num_passed++;
  if (test7() == 0)
    num_passed++;
  if (test8() == 0)
    num_passed++;
  if (test9() == 0)
    num_passed++;
  remove_nodes();
  unlink("testfile.in");
  unlink("testfile.out");
  printf("\nFinal score: %d/%d\n", num_passed, total);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  xor    %ebp,%ebp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <make_nodes@plt>
  xor    %eax,%eax
  call   <test1@plt>
  test   %rax,%rax
  sete   %bpl
  xor    %eax,%eax
  call   <test2@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test3@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test4@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test5@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test6@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test7@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test8@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test9@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <remove_nodes@plt>
  lea    D6(%rip),%rdi
  call   <unlink@plt>
  lea    D5(%rip),%rdi
  call   <unlink@plt>
  mov    %ebp,%esi
  mov    $0x9,%edx
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D19
type: string

tool: D6: testfile.in

tool: D5: testfile.out

tool: D19: 
Final score: %d/%d


assistant: ```c
int main(void) {
  int num_passed = 0;
  const int total = 9;
  srand(time(NULL));
  make_nodes();
  if (test1() == 0)
    num_passed++;
  if (test2() == 0)
    num_passed++;
  if (test3() == 0)
    num_passed++;
  if (test4() == 0)
    num_passed++;
  if (test5() == 0)
    num_passed++;
  if (test6() == 0)
    num_passed++;
  if (test7() == 0)
    num_passed++;
  if (test8() == 0)
    num_passed++;
  if (test9() == 0)
    num_passed++;
  remove_nodes();
  unlink("testfile.in");
  unlink("testfile.out");
  printf("\nFinal score: %d/%d\n", num_passed, total);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  xor    %ebp,%ebp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <make_nodes@plt>
  xor    %eax,%eax
  call   <test1@plt>
  test   %rax,%rax
  sete   %bpl
  xor    %eax,%eax
  call   <test2@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test3@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test4@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test5@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test6@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test7@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test8@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <test9@plt>
  cmp    $0x1,%rax
  adc    $0x0,%ebp
  xor    %eax,%eax
  call   <remove_nodes@plt>
  lea    D13(%rip),%rdi
  call   <unlink@plt>
  lea    D19(%rip),%rdi
  call   <unlink@plt>
  mov    %ebp,%esi
  mov    $0x9,%edx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string

tool: D13: testfile.in

tool: D19: testfile.out

tool: D14: 
Final score: %d/%d


assistant: ```c
int main(void) {
  int num_passed = 0;
  const int total = 9;
  srand(time(NULL));
  make_nodes();
  if (test1() == 0)
    num_passed++;
  if (test2() == 0)
    num_passed++;
  if (test3() == 0)
    num_passed++;
  if (test4() == 0)
    num_passed++;
  if (test5() == 0)
    num_passed++;
  if (test6() == 0)
    num_passed++;
  if (test7() == 0)
    num_passed++;
  if (test8() == 0)
    num_passed++;
  if (test9() == 0)
    num_passed++;
  remove_nodes();
  unlink("testfile.in");
  unlink("testfile.out");
  printf("\nFinal score: %d/%d\n", num_passed, total);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dividing_code_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x3b,%eax
  seta   %dl
  test   %dl,%dl
  jne    L5
  movabs $0x800030100002600,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L5
  mov    $0x1,%eax
  jmp    L3
L5:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int dividing_code_p(int code) {
  switch (code) {
  case '\n':
  case '\r':
  case '\t':
  case ';':
  case ' ':
  case '(':
  case ')':
    return 1;
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dividing_code_p>:
  endbr64
  cmp    $0x3b,%edi
  ja     L5
  movabs $0x800030100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int dividing_code_p(int code) {
  switch (code) {
  case '\n':
  case '\r':
  case '\t':
  case ';':
  case ' ':
  case '(':
  case ')':
    return 1;
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dividing_code_p>:
  endbr64
  cmp    $0x3b,%edi
  ja     L3
  movabs $0x800030100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int dividing_code_p(int code) {
  switch (code) {
  case '\n':
  case '\r':
  case '\t':
  case ';':
  case ' ':
  case '(':
  case ')':
    return 1;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dividing_code_p>:
  endbr64
  cmp    $0x3b,%edi
  ja     L3
  movabs $0x800030100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int dividing_code_p(int code) {
  switch (code) {
  case '\n':
  case '\r':
  case '\t':
  case ';':
  case ' ':
  case '(':
  case ')':
    return 1;
  default:
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_to_sphere>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  fldt   (%rax)
  mov    -0x18(%rbp),%rax
  fldt   (%rax)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <atan2l@plt>
  add    $0x20,%rsp
  mov    -0x20(%rbp),%rdx
  lea    0x10(%rdx),%rbx
  mov    %eax,%edi
  call   <deg@plt>
  fstpt  (%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  fldt   (%rax)
  fldt   0xe46(%rip)        # 2000 <_fini+0xe18>
  fdivrp %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <asin@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  call   <deg@plt>
  mov    -0x20(%rbp),%rax
  fstpt  (%rax)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int _to_sphere(long double *x, long double *y) {
  y[1] = deg(atan2l(x[0], x[1]));
  y[0] = deg(asin(x[2] / 6371000.));
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_to_sphere>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  push   0x18(%rdi)
  push   0x10(%rdi)
  push   0x8(%rdi)
  push   (%rdi)
  call   <atan2l@plt>
  mov    %eax,%edi
  add    $0x20,%rsp
  call   <deg@plt>
  fstpt  0x10(%rbp)
  fldt   0x20(%rbx)
  fdivs  0xe70(%rip)        # 2000 <_fini+0xe4c>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <asin@plt>
  mov    %eax,%edi
  call   <deg@plt>
  fstpt  0x0(%rbp)
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _to_sphere(long double *x, long double *y) {
  y[1] = deg(atan2l(x[0], x[1]));
  y[0] = deg(asin(x[2] / 6371000.));
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_to_sphere>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  push   0x18(%rdi)
  push   0x10(%rdi)
  push   0x8(%rdi)
  push   (%rdi)
  call   <atan2l@plt>
  add    $0x20,%rsp
  mov    %eax,%edi
  call   <deg@plt>
  sub    $0x10,%rsp
  fstpt  0x10(%rbp)
  fldt   0x20(%rbx)
  fdivs  0xe65(%rip)        # 2000 <_fini+0xe44>
  fstpt  (%rsp)
  call   <asin@plt>
  mov    %eax,%edi
  call   <deg@plt>
  mov    $0x1,%eax
  fstpt  0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int _to_sphere(long double *x, long double *y) {
  y[1] = deg(atan2l(x[0], x[1]));
  y[0] = deg(asin(x[2] / 6371000.));
  return 1;
}
```