ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<getheader>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r14
  call   <gettimeofday@plt>
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    $0x80,%esi
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <gethostname@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L46
  mov    %r14,%rdx
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L46
L50:
  cmp    $0x2e,%al
  jne    L35
  movb   $0x0,(%rdx)
L46:
  mov    0x4(%rbx),%eax
  mov    (%rbx),%ecx
  mov    0x14(%rbx),%edi
  mov    0x10(%rbx),%esi
  mov    0xc(%rbx),%edx
  mov    0x8(%rbx),%r9d
  lea    0x1(%rax),%r8d
  add    $0x76c,%ecx
  test   %ebp,%ebp
  je     L5
  sub    $0x8,%rsp
  push   %r14
  movslq 0x18(%rsp),%rax
  mov    %rax,%r10
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%r10d
  sar    $0x26,%rax
  sub    %r10d,%eax
  push   %rax
  xor    %eax,%eax
  push   %rdi
  mov    %r12,%rdi
  push   %rsi
  mov    %r13d,%esi
  push   %rdx
  lea    D6(%rip),%rdx
  call   <snprintf@plt>
  add    $0x30,%rsp
L25:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  push   %r14
  xor    %eax,%eax
  push   %rdi
  mov    %r12,%rdi
  push   %rsi
  mov    %r13d,%esi
  push   %rdx
  lea    D17(%rip),%rdx
  call   <snprintf@plt>
  add    $0x20,%rsp
  jmp    L25
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string
name: disassemble_data
arguments: label: D17
type: string

tool: D6: %04d/%02d/%02d %02d:%02d:%02d.%03d %s 

tool: D17: %04d/%02d/%02d %02d:%02d:%02d %s 

assistant: ```c
void getheader(char *head, int size, int msec) {
  struct timeval tv;
  struct tm *t_st;
  char host[128];
  char *p;
  (void)gettimeofday(&tv, NULL);
  t_st = localtime(&tv.tv_sec);
  (void)gethostname(host, sizeof(host));
  p = host;
  while (*p != '\0') {
    if (*p == '.') {
      *p = '\0';
      break;
    }
    p++;
  }
  if (msec) {
    snprintf(head, size, "%04d/%02d/%02d %02d:%02d:%02d.%03d %s ", t_st->tm_year + 1900, t_st->tm_mon + 1, t_st->tm_mday, t_st->tm_hour, t_st->tm_min, t_st->tm_sec, tv.tv_usec / 1000, host);
  } else {
    snprintf(head, size, "%04d/%02d/%02d %02d:%02d:%02d %s ", t_st->tm_year + 1900, t_st->tm_mon + 1, t_st->tm_mday, t_st->tm_hour, t_st->tm_min, t_st->tm_sec, host);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<comnt_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L15
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x2f,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0x2f,%eax
  jne    L15
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movl   $0x1,(%rax)
  jmp    L65
L15:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L27
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L27
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x2f,%eax
  jne    L27
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0x2a,%eax
  jne    L27
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  jmp    L65
L27:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L74
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x5c,%eax
  je     L74
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0xa,%eax
  jne    L74
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movl   $0x0,(%rax)
  jmp    L65
L74:
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L65
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    $0x2a,%eax
  jne    L65
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    $0x2f,%eax
  jne    L65
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  jmp    L65
L65:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void comnt_check(int cquad[], int pnctn_sts[]) {
  if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '/') {
    pnctn_sts[2] = 1;
  } else if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '*') {
    pnctn_sts[1] = 1;
  } else if (pnctn_sts[2] == 1 && cquad[2] != '\\' && cquad[3] == '\n') {
    pnctn_sts[2] = 0;
  } else if (pnctn_sts[1] == 1 && cquad[2] == '*' && cquad[3] == '/') {
    pnctn_sts[1] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comnt_check>:
  endbr64
  mov    0x8(%rsi),%eax
  test   %eax,%eax
  jne    L83
  cmpl   $0x0,0x4(%rsi)
  jne    L67
  cmpl   $0x2f,0x8(%rdi)
  je     L42
L61:
  cmpl   $0x2f,0x8(%rdi)
  jne    L89
  cmpl   $0x2a,0xc(%rdi)
  jne    L89
  movl   $0x1,0x4(%rsi)
  ret
L42:
  cmpl   $0x2f,0xc(%rdi)
  jne    L61
  movl   $0x1,0x8(%rsi)
  ret
L83:
  cmp    $0x1,%eax
  jne    L67
  cmpl   $0x5c,0x8(%rdi)
  je     L89
  cmpl   $0xa,0xc(%rdi)
  je     L5
L67:
  cmpl   $0x1,0x4(%rsi)
  je     L29
L89:
  ret
L5:
  movl   $0x0,0x8(%rsi)
  ret
L29:
  cmpl   $0x2a,0x8(%rdi)
  jne    L89
  cmpl   $0x2f,0xc(%rdi)
  jne    L89
  movl   $0x0,0x4(%rsi)
  ret
```

assistant: ```c
void comnt_check(int cquad[], int pnctn_sts[]) {
  if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '/') {
    pnctn_sts[2] = 1;
  } else if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '*') {
    pnctn_sts[1] = 1;
  } else if (pnctn_sts[2] == 1 && cquad[2] != '\\' && cquad[3] == '\n') {
    pnctn_sts[2] = 0;
  } else if (pnctn_sts[1] == 1 && cquad[2] == '*' && cquad[3] == '/') {
    pnctn_sts[1] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comnt_check>:
  endbr64
  mov    0x8(%rsi),%eax
  test   %eax,%eax
  jne    L11
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  jne    L41
  cmpl   $0x2f,0x8(%rdi)
  je     L20
L109:
  ret
  nopl   0x0(%rax)
L11:
  cmp    $0x1,%eax
  jne    L64
  cmpl   $0x5c,0x8(%rdi)
  je     L109
  cmpl   $0xa,0xc(%rdi)
  je     L86
L64:
  mov    0x4(%rsi),%eax
L41:
  cmp    $0x1,%eax
  jne    L109
  cmpl   $0x2a,0x8(%rdi)
  jne    L109
  cmpl   $0x2f,0xc(%rdi)
  jne    L109
  movl   $0x0,0x4(%rsi)
  ret
  nopl   (%rax)
L20:
  cmpl   $0x2f,0xc(%rdi)
  je     L12
  cmpl   $0x2a,0xc(%rdi)
  jne    L109
  movl   $0x1,0x4(%rsi)
  ret
  nopl   0x0(%rax)
L86:
  movl   $0x0,0x8(%rsi)
  ret
L12:
  movl   $0x1,0x8(%rsi)
  ret
```

assistant: ```c
void comnt_check(int cquad[], int pnctn_sts[]) {
  if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '/') {
    pnctn_sts[2] = 1;
  } else if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '*') {
    pnctn_sts[1] = 1;
  } else if (pnctn_sts[2] == 1 && cquad[2] != '\\' && cquad[3] == '\n') {
    pnctn_sts[2] = 0;
  } else if (pnctn_sts[1] == 1 && cquad[2] == '*' && cquad[3] == '/') {
    pnctn_sts[1] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comnt_check>:
  endbr64
  mov    0x8(%rsi),%eax
  test   %eax,%eax
  jne    L73
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  jne    L21
  cmpl   $0x2f,0x8(%rdi)
  je     L53
L77:
  ret
  nopl   0x0(%rax)
L73:
  cmp    $0x1,%eax
  jne    L34
  cmpl   $0x5c,0x8(%rdi)
  je     L77
  cmpl   $0xa,0xc(%rdi)
  je     L101
L34:
  mov    0x4(%rsi),%eax
L21:
  cmp    $0x1,%eax
  jne    L77
  cmpl   $0x2a,0x8(%rdi)
  jne    L77
  cmpl   $0x2f,0xc(%rdi)
  jne    L77
  movl   $0x0,0x4(%rsi)
  ret
  nopl   (%rax)
L53:
  cmpl   $0x2f,0xc(%rdi)
  je     L17
  cmpl   $0x2a,0xc(%rdi)
  jne    L77
  movl   $0x1,0x4(%rsi)
  ret
  nopl   0x0(%rax)
L101:
  movl   $0x0,0x8(%rsi)
  ret
L17:
  movl   $0x1,0x8(%rsi)
  ret
```

assistant: ```c
void comnt_check(int cquad[], int pnctn_sts[]) {
  if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '/') {
    pnctn_sts[2] = 1;
  } else if (pnctn_sts[2] == 0 && pnctn_sts[1] == 0 && cquad[2] == '/' && cquad[3] == '*') {
    pnctn_sts[1] = 1;
  } else if (pnctn_sts[2] == 1 && cquad[2] != '\\' && cquad[3] == '\n') {
    pnctn_sts[2] = 0;
  } else if (pnctn_sts[1] == 1 && cquad[2] == '*' && cquad[3] == '/') {
    pnctn_sts[1] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vst(double *a, double *b, double c, int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] = b[i] * c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vst>:
  endbr64
  test   %edx,%edx
  jle    L8
  mov    %edx,%edx
  mov    $0x0,%eax
L19:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
L8:
  ret
```

assistant: ```c
void vst(double *a, double *b, double c, int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] = b[i] * c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vst>:
  endbr64
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L3
L12:
  ret
```

assistant: ```c
void vst(double *a, double *b, double c, int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] = b[i] * c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vst>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L48
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L12
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L12
  mov    %edx,%edi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  xchg   %ax,%ax
L31:
  movupd (%rsi,%rax,1),%xmm1
  mulpd  %xmm2,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L31
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L48
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L35:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L35
L48:
  ret
```

assistant: ```c
void vst(double *a, double *b, double c, int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] = b[i] * c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L3
L0:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  char *r;
  if (s == 0)
    return 0;
  r = malloc(n + 1);
  assert(r);
  strncpy(r, s, n);
  r[n] = 0;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  char *r;
  if (s == 0)
    return 0;
  r = malloc(n + 1);
  assert(r);
  strncpy(r, s, n);
  r[n] = 0;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  char *r;
  if (s == 0)
    return 0;
  r = malloc(n + 1);
  assert(r);
  strncpy(r, s, n);
  r[n] = 0;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  char *r;
  if (s == 0)
    return 0;
  r = malloc(n + 1);
  assert(r);
  strncpy(r, s, n);
  r[n] = 0;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lpfc_is_LC_HBA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  cmpw   $0xf0a5,-0x4(%rbp)
  je     L27
  cmpw   $0xf098,-0x4(%rbp)
  je     L27
  cmpw   $0xf0a1,-0x4(%rbp)
  je     L27
  cmpw   $0xf0d5,-0x4(%rbp)
  je     L27
  cmpw   $0xf0d1,-0x4(%rbp)
  je     L27
  cmpw   $0xf0e5,-0x4(%rbp)
  je     L27
  cmpw   $0xf0e1,-0x4(%rbp)
  je     L27
  cmpw   $0xf095,-0x4(%rbp)
  jne    L80
L27:
  mov    $0x1,%eax
  jmp    L79
L80:
  mov    $0x0,%eax
L79:
  pop    %rbp
  ret
```

assistant: ```c
int lpfc_is_LC_HBA(unsigned short device) {
  if ((device == 0xf0a5) || (device == 0xf098) || (device == 0xf0a1) || (device == 0xf0d5) || (device == 0xf0d1) || (device == 0xf0e5) || (device == 0xf0e1) || (device == 0xf095))
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lpfc_is_LC_HBA>:
  endbr64
  cmp    $0xf0a5,%di
  ja     L20
  cmp    $0xf094,%di
  ja     L28
  mov    $0x0,%eax
  ret
L28:
  lea    0xf6b(%rdi),%ecx
  mov    $0x11009,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L20:
  lea    0xf2f(%rdi),%ecx
  cmp    $0x14,%cx
  ja     L23
  mov    $0x110011,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int lpfc_is_LC_HBA(unsigned short device) {
  if ((device == 0xf0a5) || (device == 0xf098) || (device == 0xf0a1) || (device == 0xf0d5) || (device == 0xf0d1) || (device == 0xf0e5) || (device == 0xf0e1) || (device == 0xf095))
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lpfc_is_LC_HBA>:
  endbr64
  cmp    $0xf0a5,%di
  ja     L14
  cmp    $0xf094,%di
  ja     L3
L29:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L14:
  lea    0xf2f(%rdi),%ecx
  cmp    $0x14,%cx
  ja     L29
  mov    $0x110011,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L3:
  lea    0xf6b(%rdi),%ecx
  mov    $0x11009,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int lpfc_is_LC_HBA(unsigned short device) {
  if ((device == 0xf0a5) || (device == 0xf098) || (device == 0xf0a1) || (device == 0xf0d5) || (device == 0xf0d1) || (device == 0xf0e5) || (device == 0xf0e1) || (device == 0xf095))
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lpfc_is_LC_HBA>:
  endbr64
  cmp    $0xf0a5,%di
  ja     L16
  cmp    $0xf094,%di
  ja     L29
L23:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L16:
  lea    0xf2f(%rdi),%ecx
  cmp    $0x14,%cx
  ja     L23
  mov    $0x110011,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L29:
  lea    0xf6b(%rdi),%ecx
  mov    $0x11009,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
int lpfc_is_LC_HBA(unsigned short device) {
  if ((device == 0xf0a5) || (device == 0xf098) || (device == 0xf0a1) || (device == 0xf0d5) || (device == 0xf0d1) || (device == 0xf0e5) || (device == 0xf0e1) || (device == 0xf095))
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stdlib_ndarray_get_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L19
L16:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr_int16@plt>
L19:
  leave
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_int16(const struct ndarray *arr, const int64_t *sub, int16_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_int16(idx, out);
}
```
user: What is the c source code of the assembly code below:

```asm
<stdlib_ndarray_get_int16>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <stdlib_ndarray_get_ptr_int16@plt>
L15:
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int8_t stdlib_ndarray_get_int16(const struct ndarray *arr, const int64_t *sub, int16_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_int16(idx, out);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stdlib_ndarray_get_int16>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L6
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <stdlib_ndarray_get_ptr_int16@plt>
L6:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_int16(const struct ndarray *arr, const int64_t *sub, int16_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_int16(idx, out);
}
```
user: What is the c source code of the assembly code below?

```asm
<stdlib_ndarray_get_int16>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1070 <stdlib_ndarray_get_ptr_int16@plt>
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_get_int16(const struct ndarray *arr, const int64_t *sub, int16_t *out) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_get_ptr_int16(idx, out);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<buffer_find_str_prev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <buffer_get_content@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
L24:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x2c(%rbp)
  jle    L9
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  jmp    L24
L20:
  nop
  jmp    L34
L9:
  nop
L34:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <str_newlines@plt>
  mov    -0x40(%rbp),%rdx
  mov    (%rdx),%edx
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L21:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int buffer_find_str_prev(struct buffer *buf, int from, const char *str, int *newlines) {
  char *text, *s;
  int p = -1;
  text = buffer_get_content(buf);
  *newlines = 0;
  s = strstr(text, str);
  if (s) {
    while (1) {
      int len;
      s = strstr(text + p + 1, str);
      if (s) {
        len = s - (text + p);
        if (p + len < from)
          p += len;
        else
          break;
      } else {
        break;
      }
    }
    *newlines += str_newlines(text, p);
  }
  free(text);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buffer_find_str_prev>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %rcx,%r15
  call   <buffer_get_content@plt>
  mov    %rax,%r12
  movl   $0x0,(%r15)
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L17
  mov    $0xffffffff,%ebx
  mov    $0xffffffffffffffff,%rbp
L2:
  mov    %ebx,%edx
  add    %r12,%rbp
  sub    %rbp,%rax
  add    %eax,%ebx
  cmp    %r14d,%ebx
  jge    L38
  movslq %ebx,%rbp
  lea    0x1(%r12,%rbp,1),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L2
L29:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <str_newlines@plt>
  add    %eax,(%r15)
L21:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0xffffffff,%ebx
  jmp    L21
L38:
  mov    %edx,%ebx
  jmp    L29
```

assistant: ```c
int buffer_find_str_prev(struct buffer *buf, int from, const char *str, int *newlines) {
  char *text, *s;
  int p = -1;
  text = buffer_get_content(buf);
  *newlines = 0;
  s = strstr(text, str);
  if (s) {
    while (1) {
      int len;
      s = strstr(text + p + 1, str);
      if (s) {
        len = s - (text + p);
        if (p + len < from)
          p += len;
        else
          break;
      } else {
        break;
      }
    }
    *newlines += str_newlines(text, p);
  }
  free(text);
  return p;
}
```