ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<horn_dx>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r10
  mov    %ecx,%r11d
  mov    %r8d,%ebp
  lea    -0x1(%r8),%r14d
  test   %r14d,%r14d
  jle    L6
  mov    %r14d,%r13d
  movslq %ecx,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rcx
  add    %rsi,%rdx
  mov    $0x0,%ebx
  mov    $0x0,%r8d
  lea    -0x2(%r11),%r12d
  add    $0x1,%r12
  movsd  D2(%rip),%xmm2
  jmp    L12
L72:
  movslq %ebx,%r9
  lea    0x0(,%r9,4),%rax
  add    %r12,%r9
  shl    $0x2,%r9
L42:
  movss  0x4(%rdi,%rax,1),%xmm0
  addss  0x4(%rsi,%rax,1),%xmm0
  addss  0x4(%rcx,%rax,1),%xmm0
  addss  0x4(%rdx,%rax,1),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm2,%xmm0
  movss  (%rdi,%rax,1),%xmm1
  addss  (%rsi,%rax,1),%xmm1
  addss  (%rcx,%rax,1),%xmm1
  addss  (%rdx,%rax,1),%xmm1
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r10,%rax,1)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L42
L39:
  add    $0x1,%r8d
  add    %r11d,%ebx
  cmp    %r13d,%r8d
  je     L6
L12:
  cmp    $0x1,%r11d
  jg     L72
  jmp    L39
L6:
  test   %r11d,%r11d
  jle    L86
  imul   %r11d,%r14d
  movslq %r14d,%rdx
  lea    (%r10,%rdx,4),%rax
  lea    -0x1(%r11),%ecx
  add    %rcx,%rdx
  lea    0x4(%r10,%rdx,4),%rdx
L93:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L93
L86:
  test   %ebp,%ebp
  jle    L35
  movslq %r11d,%rax
  shl    $0x2,%rax
  add    %rax,%r10
  mov    $0x0,%edx
L3:
  movl   $0x0,-0x4(%r10)
  add    $0x1,%edx
  add    %rax,%r10
  cmp    %edx,%ebp
  jne    L3
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: f32[2]

tool: {"D2": [0.0,1.625]}

assistant: ```c
void horn_dx(image1, image2, dx, nx, ny) float *dx, *image1, *image2;
int nx, ny;
{
  int index, i, j;
  for (i = 0; i < ny - 1; i++) {
    for (j = 0; j < nx - 1; j++) {
      index = (i * nx) + j;
      dx[index] = ((image1[index + 1] + image2[index + 1] + image1[index + nx + 1] + image2[index + nx + 1]) / 4.0) - ((image1[index] + image2[index] + image1[index + nx] + image2[index + nx]) / 4.0);
    }
  }
  for (j = 0; j < nx; j++) {
    dx[(ny - 1) * nx + j] = 0.0;
  }
  for (i = 0; i < ny; i++) {
    dx[(i * nx) + (nx - 1)] = 0.0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<horn_dx>:
  endbr64
  push   %r13
  lea    -0x1(%r8),%r11d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %r11d,%r11d
  jle    L26
  movslq %ecx,%rdx
  lea    -0x2(%rbp),%r13d
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  shl    $0x2,%rdx
  movsd  D6(%rip),%xmm2
  add    $0x1,%r13
  lea    (%rdi,%rdx,1),%rcx
  add    %rsi,%rdx
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    $0x1,%ebp
  jle    L44
  movslq %r10d,%r9
  lea    0x0(,%r9,4),%rax
  add    %r13,%r9
  shl    $0x2,%r9
  nopw   0x0(%rax,%rax,1)
L52:
  movss  0x4(%rdi,%rax,1),%xmm0
  movss  (%rdi,%rax,1),%xmm1
  addss  0x4(%rsi,%rax,1),%xmm0
  addss  (%rsi,%rax,1),%xmm1
  addss  0x4(%rcx,%rax,1),%xmm0
  addss  (%rcx,%rax,1),%xmm1
  addss  0x4(%rdx,%rax,1),%xmm0
  addss  (%rdx,%rax,1),%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rbx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L52
L44:
  add    $0x1,%r8d
  add    %ebp,%r10d
  cmp    %r11d,%r8d
  jne    L30
L26:
  test   %ebp,%ebp
  jle    L41
  imul   %ebp,%r11d
  movslq %ebp,%rdx
  xor    %esi,%esi
  shl    $0x2,%rdx
  movslq %r11d,%rax
  lea    (%rbx,%rax,4),%rdi
  call   <memset@plt>
L41:
  test   %r12d,%r12d
  jle    L29
  movslq %ebp,%rax
  xor    %edx,%edx
  shl    $0x2,%rax
  lea    -0x4(%rbx,%rax,1),%rcx
  xchg   %ax,%ax
L59:
  add    $0x1,%edx
  movl   $0x0,(%rcx)
  add    %rax,%rcx
  cmp    %edx,%r12d
  jne    L59
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: f32[2]

tool: {"D6": [0.0,1.625]}

assistant: ```c
void horn_dx(image1, image2, dx, nx, ny) float *dx, *image1, *image2;
int nx, ny;
{
  int index, i, j;
  for (i = 0; i < ny - 1; i++) {
    for (j = 0; j < nx - 1; j++) {
      index = (i * nx) + j;
      dx[index] = ((image1[index + 1] + image2[index + 1] + image1[index + nx + 1] + image2[index + nx + 1]) / 4.0) - ((image1[index] + image2[index] + image1[index + nx] + image2[index + nx]) / 4.0);
    }
  }
  for (j = 0; j < nx; j++) {
    dx[(ny - 1) * nx + j] = 0.0;
  }
  for (i = 0; i < ny; i++) {
    dx[(i * nx) + (nx - 1)] = 0.0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<average>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sum@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  test   %rax,%rax
  js     L18
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L9
L18:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L9:
  movss  -0x4(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  leave
  ret
```

assistant: ```c
float average(signed *numbers, unsigned length) {
  float s = (float)sum(numbers, length);
  return s / length;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<average>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <sum@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    %ebx,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
  divss  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
float average(signed *numbers, unsigned length) {
  float s = (float)sum(numbers, length);
  return s / length;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<average>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%esi
  call   <sum@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
  pop    %rbx
  cvtsi2ss %rax,%xmm0
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float average(signed *numbers, unsigned length) {
  float s = (float)sum(numbers, length);
  return s / length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<average>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %ebx,%esi
  call   <sum@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rbx,%xmm1
  pop    %rbx
  cvtsi2ss %rax,%xmm0
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float average(signed *numbers, unsigned length) {
  float s = (float)sum(numbers, length);
  return s / length;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x12(%rbp)
  jne    L10
  movzbl -0x12(%rbp),%eax
  movzbl -0x11(%rbp),%edx
  sub    %edx,%eax
  jmp    L28
L10:
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  je     L4
  movzbl -0x12(%rbp),%eax
  movzbl -0x11(%rbp),%edx
  sub    %edx,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *p1, const char *p2) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  unsigned char c1, c2;
  do {
    c1 = (unsigned char)*s1++;
    c2 = (unsigned char)*s2++;
    if (c1 == '\0')
      return c1 - c2;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  mov    $0x0,%eax
L7:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  je     L11
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L7
  movzbl %dl,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
L11:
  movzbl %cl,%eax
  neg    %eax
  ret
```

assistant: ```c
int strcmp(const char *p1, const char *p2) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  unsigned char c1, c2;
  do {
    c1 = (unsigned char)*s1++;
    c2 = (unsigned char)*s2++;
    if (c1 == '\0')
      return c1 - c2;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L14
L21:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L13
  movzbl %cl,%eax
  neg    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *p1, const char *p2) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  unsigned char c1, c2;
  do {
    c1 = (unsigned char)*s1++;
    c2 = (unsigned char)*s2++;
    if (c1 == '\0')
      return c1 - c2;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L8
L16:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L28
  movzbl %cl,%eax
  neg    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *p1, const char *p2) {
  const unsigned char *s1 = (const unsigned char *)p1;
  const unsigned char *s2 = (const unsigned char *)p2;
  unsigned char c1, c2;
  do {
    c1 = (unsigned char)*s1++;
    c2 = (unsigned char)*s2++;
    if (c1 == '\0')
      return c1 - c2;
  } while (c1 == c2);
  return c1 - c2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x312e312e312e31,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0xb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x14,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x10(%rbp),%rax
  mov    %rax,-0xc0(%rbp)
  lea    -0xc0(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0xb8(%rbp)
  movl   $0x0,-0xc4(%rbp)
  jmp    L63
L32:
  lea    -0xb0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc0(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0xb8(%rbp)
  addl   $0x1,-0xc4(%rbp)
L63:
  cmpq   $0x0,-0xb8(%rbp)
  jne    L32
  movl   $0x0,-0xc4(%rbp)
  jmp    L12
L77:
  lea    -0xb0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L88
  lea    -0xb0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L88:
  addl   $0x1,-0xc4(%rbp)
L12:
  cmpl   $0x9,-0xc4(%rbp)
  jle    L77
  movl   $0x0,-0xc4(%rbp)
  jmp    L55
L45:
  lea    -0xb0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L30
  lea    -0xb0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  add    %rax,%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  addl   $0x1,-0xc4(%rbp)
L55:
  cmpl   $0x9,-0xc4(%rbp)
  jle    L45
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D20
type: string

tool: D9: ,

tool: D20: aa[%d]=%s


assistant: ```c
int main() {
  char str[] = "1.1.1.1";
  char aa[10][16] = {0};
  char *p;
  char *buff;
  buff = str;
  p = strsep(&buff, ",");
  int i = 0;
  while (p) {
    strcpy(aa[i], p);
    printf("%s\n", p);
    p = strsep(&buff, ",");
    ++i;
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  movabs $0x312e312e312e31,%rax
  mov    %rax,0xb0(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x14,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    0xb0(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  lea    D30(%rip),%rsi
  call   <strsep@plt>
  test   %rax,%rax
  je     L84
  mov    %rax,%rbx
  lea    0x10(%rsp),%rbp
  lea    D30(%rip),%r12
L68:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rdi
  mov    %r12,%rsi
  call   <strsep@plt>
  mov    %rax,%rbx
  add    $0x10,%rbp
  test   %rax,%rax
  jne    L68
L84:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D33(%rip),%r13
  jmp    L66
L57:
  add    $0x1,%ebp
  add    $0x10,%r12
  cmp    $0xa,%ebp
  je     L12
L66:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L57
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L12:
  mov    $0x0,%ebp
  lea    D33(%rip),%r12
  jmp    L109
L56:
  add    $0x1,%ebp
  add    $0x10,%rbx
  cmp    $0xa,%ebp
  je     L30
L109:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L56
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L56
L30:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    $0x0,%eax
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D33
type: string

tool: D30: ,

tool: D33: aa[%d]=%s


assistant: ```c
int main() {
  char str[] = "1.1.1.1";
  char aa[10][16] = {0};
  char *p;
  char *buff;
  buff = str;
  p = strsep(&buff, ",");
  int i = 0;
  while (p) {
    strcpy(aa[i], p);
    printf("%s\n", p);
    p = strsep(&buff, ",");
    ++i;
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x14,%ecx
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  movabs $0x312e312e312e31,%rax
  lea    0x10(%rsp),%rbx
  lea    0x8(%rsp),%r13
  mov    %rbx,%rdi
  mov    %rax,0xb0(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0xb0(%rsp),%rax
  mov    %r13,%rdi
  mov    %rax,0x8(%rsp)
  call   <strsep@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rbp
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x10,%r14
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strsep@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L26
L14:
  mov    %rbx,%rbp
  mov    %rbx,%r12
  lea    D24(%rip),%r13
  xor    %ebx,%ebx
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L94:
  add    $0x1,%ebx
  add    $0x10,%r12
  cmp    $0xa,%ebx
  je     L51
L102:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L94
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x10,%r12
  cmp    $0xa,%ebx
  jne    L102
L51:
  xor    %ebx,%ebx
  lea    D24(%rip),%r12
  jmp    L79
  nop
L28:
  add    $0x1,%ebx
  add    $0x10,%rbp
  cmp    $0xa,%ebx
  je     L86
L79:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L28
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x10,%rbp
  cmp    $0xa,%ebx
  jne    L79
L86:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D24
data_type: string

tool: D18: ,

tool: D24: aa[%d]=%s


assistant: ```c
int main() {
  char str[] = "1.1.1.1";
  char aa[10][16] = {0};
  char *p;
  char *buff;
  buff = str;
  p = strsep(&buff, ",");
  int i = 0;
  while (p) {
    strcpy(aa[i], p);
    printf("%s\n", p);
    p = strsep(&buff, ",");
    ++i;
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x14,%ecx
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  movabs $0x312e312e312e31,%rax
  lea    0x10(%rsp),%rbx
  lea    0x8(%rsp),%r13
  mov    %rbx,%rdi
  mov    %rax,0xb0(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0xb0(%rsp),%rax
  mov    %r13,%rdi
  mov    %rax,0x8(%rsp)
  call   <strsep@plt>
  test   %rax,%rax
  je     L74
  mov    %rax,%rbp
  mov    %rbx,%r14
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x10,%r14
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strsep@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L11
L74:
  mov    %rbx,%rbp
  mov    %rbx,%r12
  lea    D4(%rip),%r13
  xor    %ebx,%ebx
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%ebx
  add    $0x10,%r12
  cmp    $0xa,%ebx
  je     L21
L54:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L56
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x10,%r12
  cmp    $0xa,%ebx
  jne    L54
L21:
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  jmp    L86
  nop
L79:
  add    $0x1,%ebx
  add    $0x10,%rbp
  cmp    $0xa,%ebx
  je     L8
L86:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x6,%eax
  jle    L79
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x10,%rbp
  cmp    $0xa,%ebx
  jne    L86
L8:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D15: ,

tool: D4: aa[%d]=%s


assistant: ```c
int main() {
  char str[] = "1.1.1.1";
  char aa[10][16] = {0};
  char *p;
  char *buff;
  buff = str;
  p = strsep(&buff, ",");
  int i = 0;
  while (p) {
    strcpy(aa[i], p);
    printf("%s\n", p);
    p = strsep(&buff, ",");
    ++i;
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  for (i = 0; i < 10; ++i) {
    if (strlen(aa[i]) >= 7)
      printf("aa[%d]=%s\n", i, aa[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cnmgrMatrixMultiply4x4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L24:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm2
  mov    -0x20(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  0x8(%rax),%xmm2
  mov    -0x20(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  0xc(%rax),%xmm2
  mov    -0x20(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x4,-0x8(%rbp)
  jne    L12
  movl   $0x0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jne    L12
  movl   $0x0,-0xc(%rbp)
L12:
  cmpl   $0x0,-0xc(%rbp)
  jne    L24
  nop
  pop    %rbp
  ret
```

assistant: ```c
cnmgrMatrixMultiply4x4(float matrixOne[4][4], float matrixTwo[4][4], float outputMatrix[4][4]) {
  int notDone = 1;
  int x = 0;
  int y = 0;
  while (notDone) {
    outputMatrix[y][x] = matrixOne[y][0] * matrixTwo[0][x] + matrixOne[y][1] * matrixTwo[1][x] + matrixOne[y][2] * matrixTwo[2][x] + matrixOne[y][3] * matrixTwo[3][x];
    x++;
    if (x == 4) {
      x = 0;
      y++;
      if (y == 4) {
        notDone = 0;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cnmgrMatrixMultiply4x4>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    $0x0,%r9d
  mov    $0x0,%r8d
L24:
  movslq %r9d,%rcx
  shl    $0x4,%rcx
  lea    (%r10,%rcx,1),%rdi
  movslq %r8d,%rax
  shl    $0x2,%rax
  lea    (%r11,%rax,1),%rsi
  add    %rdx,%rax
  movss  (%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  0x10(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x20(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%rdi),%xmm1
  mulss  0x30(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax,%rcx,1)
  add    $0x1,%r8d
  cmp    $0x4,%r8d
  jne    L24
  add    $0x1,%r9d
  cmp    $0x4,%r9d
  je     L17
  mov    $0x0,%r8d
  jmp    L24
L17:
  ret
```

assistant: ```c
cnmgrMatrixMultiply4x4(float matrixOne[4][4], float matrixTwo[4][4], float outputMatrix[4][4]) {
  int notDone = 1;
  int x = 0;
  int y = 0;
  while (notDone) {
    outputMatrix[y][x] = matrixOne[y][0] * matrixTwo[0][x] + matrixOne[y][1] * matrixTwo[1][x] + matrixOne[y][2] * matrixTwo[2][x] + matrixOne[y][3] * matrixTwo[3][x];
    x++;
    if (x == 4) {
      x = 0;
      y++;
      if (y == 4) {
        notDone = 0;
      }
    }
  }
}
```