ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main() {
  int i = 0;
  int a = 1;
  int b = 2;
  int c;
  printf("%d\n", c = a++ + b);
  ++i + ++i;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main() {
  int i = 0;
  int a = 1;
  int b = 2;
  int c;
  printf("%d\n", c = a++ + b);
  ++i + ++i;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main() {
  int i = 0;
  int a = 1;
  int b = 2;
  int c;
  printf("%d\n", c = a++ + b);
  ++i + ++i;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int i = 0;
  int a = 1;
  int b = 2;
  int c;
  printf("%d\n", c = a++ + b);
  ++i + ++i;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string

tool: D19: %lf %lf %lf %lf

tool: D5: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((pow(x2 - x1, 2) + pow(y2 - y1, 2))));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %rax,%rbx
  movsd  0x20(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D16
type: string

tool: D13: %lf %lf %lf %lf

tool: D16: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((pow(x2 - x1, 2) + pow(y2 - y1, 2))));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0x30,%rsp
  lea    0x8(%rsp),%rsi
  lea    0x18(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm0
  mov    $0x2,%edi
  subsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm0
  mov    $0x2,%edi
  subsd  0x10(%rsp),%xmm0
  mov    %rax,%rbx
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string

tool: D13: %lf %lf %lf %lf

tool: D18: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((pow(x2 - x1, 2) + pow(y2 - y1, 2))));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D16(%rip),%rdi
  sub    $0x30,%rsp
  lea    0x8(%rsp),%rsi
  lea    0x18(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm0
  mov    $0x2,%edi
  subsd  0x8(%rsp),%xmm0
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm0
  mov    $0x2,%edi
  subsd  0x10(%rsp),%xmm0
  mov    %rax,%rbx
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string

tool: D16: %lf %lf %lf %lf

tool: D10: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  printf("%.4lf\n", sqrt((pow(x2 - x1, 2) + pow(y2 - y1, 2))));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: Zdravo, kako si?


assistant: ```c
int main() {
  printf("Zdravo, kako si?\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: Zdravo, kako si?


assistant: ```c
int main() {
  printf("Zdravo, kako si?\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: Zdravo, kako si?


assistant: ```c
int main() {
  printf("Zdravo, kako si?\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: Zdravo, kako si?


assistant: ```c
int main() {
  printf("Zdravo, kako si?\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leapyear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L10
  mov    $0x0,%eax
  jmp    L28
L10:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L41
  mov    $0x1,%eax
  jmp    L28
L41:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L48
  mov    $0x0,%eax
  jmp    L28
L48:
  mov    $0x1,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int leapyear(int yy) {
  if (yy % 4 != 0)
    return 0;
  if (yy % 400 == 0)
    return 1;
  if (yy % 100 == 0)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<leapyear>:
  endbr64
  mov    $0x0,%edx
  test   $0x3,%dil
  jne    L16
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  mov    $0x1,%edx
  cmp    %eax,%edi
  je     L16
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,%edi
  setne  %dl
  movzbl %dl,%edx
L16:
  mov    %edx,%eax
  ret
```

assistant: ```c
int leapyear(int yy) {
  if (yy % 4 != 0)
    return 0;
  if (yy % 400 == 0)
    return 1;
  if (yy % 100 == 0)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<leapyear>:
  endbr64
  xor    %eax,%eax
  test   $0x3,%dil
  jne    L19
  imul   $0xc28f5c29,%edi,%edi
  mov    $0x1,%eax
  add    $0x51eb850,%edi
  mov    %edi,%edx
  ror    $0x4,%edx
  cmp    $0xa3d70a,%edx
  jbe    L19
  ror    $0x2,%edi
  xor    %eax,%eax
  cmp    $0x28f5c28,%edi
  seta   %al
L19:
  ret
```

assistant: ```c
int leapyear(int yy) {
  if (yy % 4 != 0)
    return 0;
  if (yy % 400 == 0)
    return 1;
  if (yy % 100 == 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<leapyear>:
  endbr64
  xor    %eax,%eax
  test   $0x3,%dil
  jne    L1
  imul   $0xc28f5c29,%edi,%edi
  mov    $0x1,%eax
  add    $0x51eb850,%edi
  mov    %edi,%edx
  ror    $0x4,%edx
  cmp    $0xa3d70a,%edx
  jbe    L1
  ror    $0x2,%edi
  xor    %eax,%eax
  cmp    $0x28f5c28,%edi
  seta   %al
L1:
  ret
```

assistant: ```c
int leapyear(int yy) {
  if (yy % 4 != 0)
    return 0;
  if (yy % 400 == 0)
    return 1;
  if (yy % 100 == 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Gen_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L10:
  mov    $0x0,%eax
  call   <random@plt>
  movq   %xmm0,%rax
  mov    D7(%rip),%rdx
  mov    (%rdx),%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdx,%xmm1
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  imul   -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movq   %rax,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L10
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void Gen_matrix(double A[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      A[i * n + j] = random() / ((double)RAND_MAX);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Gen_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  test   %esi,%esi
  jle    L53
  mov    %rdi,%r15
  mov    %edx,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  lea    -0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  jmp    L58
L18:
  movslq %r13d,%rdx
  lea    (%r15,%rdx,8),%rbx
  mov    0xc(%rsp),%eax
  add    %rdx,%rax
  lea    0x8(%r15,%rax,8),%rbp
L21:
  mov    $0x0,%eax
  call   <random@plt>
  mov    D3(%rip),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L21
L31:
  add    $0x1,%r12d
  add    %r14d,%r13d
  cmp    %r12d,0x8(%rsp)
  je     L53
L58:
  test   %r14d,%r14d
  jg     L18
  jmp    L31
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Gen_matrix(double A[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      A[i * n + j] = random() / ((double)RAND_MAX);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Gen_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0x8(%rsp)
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rdx),%eax
  mov    %edx,%r14d
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  mov    %eax,0xc(%rsp)
  xchg   %ax,%ax
L9:
  test   %r14d,%r14d
  jle    L14
  mov    0xc(%rsp),%eax
  mov    (%rsp),%rdx
  movslq %r13d,%rcx
  mov    D1(%rip),%rbx
  add    %rcx,%rax
  lea    (%rdx,%rcx,8),%r15
  lea    0x8(%rdx,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <random@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rbx),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L16
L14:
  add    $0x1,%r12d
  add    %r14d,%r13d
  cmp    %r12d,0x8(%rsp)
  jne    L9
L35:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Gen_matrix(double A[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      A[i * n + j] = random() / ((double)RAND_MAX);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Gen_matrix>:
  endbr64
  test   %esi,%esi
  jle    L16
  test   %edx,%edx
  jle    L16
  push   %r15
  movslq %edx,%r15
  push   %r14
  lea    0x0(,%r15,8),%rax
  mov    $0xfffffffffffffff8,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D1(%rip),%rbp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%eax
  shl    $0x3,%rax
  lea    0x8(%rdi,%rax,1),%rbx
  sub    %rax,%r14
  nopl   (%rax)
L25:
  lea    (%r14,%rbx,1),%r15
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <random@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x0(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbx,%r15
  jne    L12
  add    $0x1,%r12d
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  ret
```

assistant: ```c
void Gen_matrix(double A[], int m, int n) {
  int i, j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      A[i * n + j] = random() / ((double)RAND_MAX);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    D71(%rip),%rax
  mov    %rax,0x30(%rsp)
  movsd  D58(%rip),%xmm0
  movsd  %xmm0,0x38(%rsp)
  mov    D101(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    D116(%rip),%rax
  mov    %rax,0x48(%rsp)
  mov    D119(%rip),%rax
  mov    %rax,0x50(%rsp)
  mov    D68(%rip),%rax
  mov    %rax,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  mov    D25(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D17(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x30(%rsp),%r12
  lea    0xc(%rsp),%r8
  mov    $0x4,%ecx
  mov    %rbp,%rdx
  mov    $0x5,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  mov    %rax,%rbx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %r12,%rdi
  call   <print_arr@plt>
  lea    D83(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <print_arr@plt>
  lea    D107(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <print_arr@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D71
type_guessed: f64
name: disassemble_data
arguments: data_tag: D58
type_guessed: f64
name: disassemble_data
arguments: data_tag: D101
type_guessed: f64
name: disassemble_data
arguments: data_tag: D116
type_guessed: f64
name: disassemble_data
arguments: data_tag: D119
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D68
type_guessed: f64
name: disassemble_data
arguments: data_tag: D25
type_guessed: f64
name: disassemble_data
arguments: data_tag: D17
type_guessed: f64
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D83
type_guessed: string
name: disassemble_data
arguments: data_tag: D107
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D71: 1.2

tool: D58: 2

tool: D101: 4.6

tool: D116: 10.125

tool: {"D119": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: D68: 0.1

tool: D25: 6.9

tool: D17: 17

tool: D14: Array #1: 

tool: D83: 
Array #2: 

tool: D107: 
Merged array: 

tool: D5: 


assistant: ```c
int main(void) {
  const int arr1_size = 5;
  const int arr2_size = 4;
  double arr1[5] = {1.2, 2., 4.6, 10.125, 50};
  double arr2[4] = {0.1, 2., 6.9, 17.};
  int merged_size;
  double *merged = merge(arr1, arr1_size, arr2, arr2_size, &merged_size);
  printf("Array #1: ");
  print_arr(arr1, arr1_size);
  printf("\nArray #2: ");
  print_arr(arr2, arr2_size);
  printf("\nMerged array: ");
  print_arr(merged, merged_size);
  printf("\n");
  free(merged);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x4,%ecx
  mov    $0x5,%esi
  push   %r12
  push   %rbp
  sub    $0x60,%rsp
  movsd  D30(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x30(%rsp),%r13
  mov    D32(%rip),%rax
  lea    0xc(%rsp),%r8
  mov    %r12,%rdx
  mov    %r13,%rdi
  movsd  %xmm0,0x38(%rsp)
  mov    %rax,0x30(%rsp)
  mov    D40(%rip),%rax
  movsd  %xmm0,0x18(%rsp)
  mov    %rax,0x40(%rsp)
  mov    D26(%rip),%rax
  mov    %rax,0x48(%rsp)
  mov    D116(%rip),%rax
  mov    %rax,0x50(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D55(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D9(%rip),%rax
  mov    %rax,0x28(%rsp)
  call   <merge@plt>
  lea    D52(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %r13,%rdi
  call   <print_arr@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <print_arr@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <print_arr@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D30
type_guessed: f64
name: parse_data
arguments: tag: D32
type_guessed: f64
name: parse_data
arguments: tag: D40
type_guessed: f64
name: parse_data
arguments: tag: D26
type_guessed: f64
name: parse_data
arguments: tag: D116
type_guessed: byte[8]
name: parse_data
arguments: tag: D23
type_guessed: f64
name: parse_data
arguments: tag: D55
type_guessed: f64
name: parse_data
arguments: tag: D9
type_guessed: f64
name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D85
type_guessed: string
name: parse_data
arguments: tag: D47
type_guessed: string
name: parse_data
arguments: tag: D87
type_guessed: string

tool: D30: 2

tool: D32: 1.2

tool: D40: 4.6

tool: D26: 10.125

tool: {"D116": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: D23: 0.1

tool: D55: 6.9

tool: D9: 17

tool: D52: Array #1: 

tool: D85: 
Array #2: 

tool: D47: 
Merged array: 

tool: D87: 


assistant: ```c
int main(void) {
  const int arr1_size = 5;
  const int arr2_size = 4;
  double arr1[5] = {1.2, 2., 4.6, 10.125, 50};
  double arr2[4] = {0.1, 2., 6.9, 17.};
  int merged_size;
  double *merged = merge(arr1, arr1_size, arr2, arr2_size, &merged_size);
  printf("Array #1: ");
  print_arr(arr1, arr1_size);
  printf("\nArray #2: ");
  print_arr(arr2, arr2_size);
  printf("\nMerged array: ");
  print_arr(merged, merged_size);
  printf("\n");
  free(merged);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x4,%ecx
  mov    $0x5,%esi
  push   %r12
  push   %rbp
  sub    $0x60,%rsp
  movapd D45(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x30(%rsp),%r13
  mov    D51(%rip),%rax
  movaps %xmm0,0x30(%rsp)
  lea    0xc(%rsp),%r8
  mov    %r12,%rdx
  mov    %r13,%rdi
  movapd D9(%rip),%xmm0
  mov    %rax,0x50(%rsp)
  movaps %xmm0,0x40(%rsp)
  movapd D40(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D26(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <merge@plt>
  lea    D50(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %r13,%rdi
  call   <print_arr@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <print_arr@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <print_arr@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D45
data_type: f64[2]
name: parse_data
arguments: tag: D51
data_type: byte[8]
name: parse_data
arguments: tag: D9
data_type: f64[2]
name: parse_data
arguments: tag: D40
data_type: f64[2]
name: parse_data
arguments: tag: D26
data_type: f64[2]
name: parse_data
arguments: tag: D50
data_type: string
name: parse_data
arguments: tag: D43
data_type: string
name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D2
data_type: string

tool: {"D45": [1.2,2.0]}

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: {"D9": [4.6,10.125]}

tool: {"D40": [0.1,2.0]}

tool: {"D26": [6.9,17.0]}

tool: D50: Array #1: 

tool: D43: 
Array #2: 

tool: D4: 
Merged array: 

tool: D2: 


assistant: ```c
int main(void) {
  const int arr1_size = 5;
  const int arr2_size = 4;
  double arr1[5] = {1.2, 2., 4.6, 10.125, 50};
  double arr2[4] = {0.1, 2., 6.9, 17.};
  int merged_size;
  double *merged = merge(arr1, arr1_size, arr2, arr2_size, &merged_size);
  printf("Array #1: ");
  print_arr(arr1, arr1_size);
  printf("\nArray #2: ");
  print_arr(arr2, arr2_size);
  printf("\nMerged array: ");
  print_arr(merged, merged_size);
  printf("\n");
  free(merged);
  return 0;
}
```