ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_sock_srv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <_sock_srvname@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    $0x1b6,%esi
  mov    %rbx,%rdi
  call   <creat@plt>
  test   %eax,%eax
  js     L40
  mov    %eax,%ebx
  mov    %rsp,%r12
  mov    %ebp,%ecx
  lea    D7(%rip),%rdx
  mov    $0x109,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L28
  mov    %ebx,%edi
  call   <close@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0x0,%eax
L2:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0x0,%eax
  call   <_syserrno@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L28:
  mov    $0x0,%eax
  call   <_syserrno@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: %d

assistant: ```c
int _sock_srv(char *path, int fd) {
  int sfd;
  char msg[8 + 256 + 1];
  _sock_srvname(msg, path);
  unlink(msg);
  sfd = creat(msg, 0666);
  if (sfd < 0) {
    close(fd);
    _syserrno();
    return -1;
  }
  snprintf(msg, sizeof msg, "%d", fd);
  if (write(sfd, msg, strlen(msg)) < 0) {
    _syserrno();
    close(sfd);
    close(fd);
    return -1;
  }
  close(sfd);
  close(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sock_srv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <_sock_srvname@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    $0x1b6,%esi
  mov    %rbp,%rdi
  call   <creat@plt>
  test   %eax,%eax
  js     L26
  lea    D1(%rip),%rdx
  mov    %r13d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    $0x109,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L20
  mov    %r12d,%edi
  call   <close@plt>
  mov    %r13d,%edi
  call   <close@plt>
  xor    %eax,%eax
L19:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    %r13d,%edi
  call   <close@plt>
  xor    %eax,%eax
  call   <_syserrno@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L20:
  xor    %eax,%eax
  call   <_syserrno@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    %r13d,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D1: %d

assistant: ```c
int _sock_srv(char *path, int fd) {
  int sfd;
  char msg[8 + 256 + 1];
  _sock_srvname(msg, path);
  unlink(msg);
  sfd = creat(msg, 0666);
  if (sfd < 0) {
    close(fd);
    _syserrno();
    return -1;
  }
  snprintf(msg, sizeof msg, "%d", fd);
  if (write(sfd, msg, strlen(msg)) < 0) {
    _syserrno();
    close(sfd);
    close(fd);
    return -1;
  }
  close(sfd);
  close(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_sock_srv>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <_sock_srvname@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    $0x1b6,%esi
  mov    %rbp,%rdi
  call   <creat@plt>
  test   %eax,%eax
  js     L10
  lea    D1(%rip),%rdx
  mov    %r13d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    $0x109,%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L43
  mov    %r12d,%edi
  call   <close@plt>
  mov    %r13d,%edi
  call   <close@plt>
  xor    %eax,%eax
L30:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r13d,%edi
  call   <close@plt>
  xor    %eax,%eax
  call   <_syserrno@plt>
  mov    $0xffffffff,%eax
  jmp    L30
L43:
  xor    %eax,%eax
  call   <_syserrno@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    %r13d,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L30
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int _sock_srv(char *path, int fd) {
  int sfd;
  char msg[8 + 256 + 1];
  _sock_srvname(msg, path);
  unlink(msg);
  sfd = creat(msg, 0666);
  if (sfd < 0) {
    close(fd);
    _syserrno();
    return -1;
  }
  snprintf(msg, sizeof msg, "%d", fd);
  if (write(sfd, msg, strlen(msg)) < 0) {
    _syserrno();
    close(sfd);
    close(fd);
    return -1;
  }
  close(sfd);
  close(fd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L19
L11:
  mov    $0x0,%eax
  call   <process@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  int count;
  scanf("%d\n", &count);
  for (count; count > 0; count--) {
    process();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L6
L19:
  mov    $0x0,%eax
  call   <process@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L19
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  int count;
  scanf("%d\n", &count);
  for (count; count > 0; count--) {
    process();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L20
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  call   <process@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L23
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main() {
  int count;
  scanf("%d\n", &count);
  for (count; count > 0; count--) {
    process();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L3
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  call   <process@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L21
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  int count;
  scanf("%d\n", &count);
  for (count; count > 0; count--) {
    process();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eeprom_unlock_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5064,%eax
  movb   $0xae,(%rax)
  mov    $0x5064,%eax
  movb   $0x56,(%rax)
  mov    $0x505f,%eax
  movzbl (%rax),%eax
  and    $0x8,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t eeprom_unlock_data(void) {
  *(unsigned char *)0x5064 = 0xAE;
  *(unsigned char *)0x5064 = 0x56;
  return (*(unsigned char *)0x505F & (1 << 3));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eeprom_unlock_data>:
  endbr64
  movb   $0x56,0x5064
  movzbl 0x505f,%eax
  and    $0x8,%eax
  ret
```

assistant: ```c
uint8_t eeprom_unlock_data(void) {
  *(unsigned char *)0x5064 = 0xAE;
  *(unsigned char *)0x5064 = 0x56;
  return (*(unsigned char *)0x505F & (1 << 3));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eeprom_unlock_data>:
  endbr64
  movzbl 0x505f,%eax
  movb   $0x56,0x5064
  and    $0x8,%eax
  ret
```

assistant: ```c
uint8_t eeprom_unlock_data(void) {
  *(unsigned char *)0x5064 = 0xAE;
  *(unsigned char *)0x5064 = 0x56;
  return (*(unsigned char *)0x505F & (1 << 3));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eeprom_unlock_data>:
  endbr64
  movzbl 0x505f,%eax
  movb   $0x56,0x5064
  and    $0x8,%eax
  ret
```

assistant: ```c
uint8_t eeprom_unlock_data(void) {
  *(unsigned char *)0x5064 = 0xAE;
  *(unsigned char *)0x5064 = 0x56;
  return (*(unsigned char *)0x505F & (1 << 3));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L42
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L65
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmp@plt>
  test   %rax,%rax
  jg     L24
  addl   $0x1,-0xc(%rbp)
  jmp    L65
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmp@plt>
  test   %rax,%rax
  js     L77
  subl   $0x1,-0x8(%rbp)
  jmp    L65
L77:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L65:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmp@plt>
  test   %rax,%rax
  jle    L74
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L74:
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sort_lines>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sort_lines>
  jmp    L51
L42:
  nop
L51:
  leave
  ret
```

assistant: ```c
void sort_lines(char *line_pointer_array[], int left, int right, int flags[]) {
  if (left >= right)
    return;
  int current_left = left, current_right = right - 1, pivot = right;
  while (current_left < current_right) {
    if (cmp(line_pointer_array[current_left], line_pointer_array[pivot], flags) <= 0) {
      ++current_left;
      continue;
    } else if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) >= 0) {
      --current_right;
      continue;
    } else
      swap(line_pointer_array, current_left, current_right);
  }
  if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) > 0)
    swap(line_pointer_array, pivot, current_right);
  sort_lines(line_pointer_array, left, current_right, flags);
  sort_lines(line_pointer_array, current_right + 1, right, flags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort_lines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    %edx,%esi
  jge    L26
  mov    %rdi,%r12
  mov    %edx,%r15d
  mov    %rcx,%r13
  lea    -0x1(%rdx),%ebx
  mov    %esi,%ebp
  cmp    %ebx,%esi
  jge    L57
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%r14
  jmp    L14
L91:
  add    $0x1,%ebp
L87:
  cmp    %ebx,%ebp
  jge    L57
L14:
  movslq %ebp,%rax
  mov    (%r12,%rax,8),%rdi
  mov    %r13,%rdx
  mov    (%r14),%rsi
  call   <cmp@plt>
  test   %rax,%rax
  jle    L91
  movslq %ebx,%rax
  mov    (%r12,%rax,8),%rdi
  mov    %r13,%rdx
  mov    (%r14),%rsi
  call   <cmp@plt>
  test   %rax,%rax
  js     L68
  sub    $0x1,%ebx
  jmp    L87
L68:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L87
L57:
  movslq %r15d,%rax
  mov    (%r12,%rax,8),%rsi
  movslq %ebx,%rax
  mov    (%r12,%rax,8),%rdi
  mov    %r13,%rdx
  call   <cmp@plt>
  test   %rax,%rax
  jg     L7
L89:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <sort_lines>
  lea    0x1(%rbx),%esi
  mov    %r13,%rcx
  mov    %r15d,%edx
  mov    %r12,%rdi
  call   <sort_lines>
L26:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L89
```

assistant: ```c
void sort_lines(char *line_pointer_array[], int left, int right, int flags[]) {
  if (left >= right)
    return;
  int current_left = left, current_right = right - 1, pivot = right;
  while (current_left < current_right) {
    if (cmp(line_pointer_array[current_left], line_pointer_array[pivot], flags) <= 0) {
      ++current_left;
      continue;
    } else if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) >= 0) {
      --current_right;
      continue;
    } else
      swap(line_pointer_array, current_left, current_right);
  }
  if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) > 0)
    swap(line_pointer_array, pivot, current_right);
  sort_lines(line_pointer_array, left, current_right, flags);
  sort_lines(line_pointer_array, current_right + 1, right, flags);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort_lines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    0xc(%rsp),%eax
  mov    %edx,0x10(%rsp)
  mov    0x10(%rsp),%edx
  cmp    %eax,%edx
  jle    L74
L36:
  movslq %edx,%rax
  lea    -0x1(%rdx),%esi
  mov    0xc(%rsp),%ebx
  shl    $0x3,%rax
  mov    %esi,0x14(%rsp)
  mov    0x14(%rsp),%r12d
  lea    0x0(%rbp,%rax,1),%r14
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %rax,0x18(%rsp)
  cmp    %r12d,%ebx
  jl     L76
  jmp    L123
L87:
  mov    (%r14),%rsi
  mov    (%r15),%rdi
  mov    %r13,%rdx
  mov    %rcx,(%rsp)
  call   <cmp@plt>
  test   %rax,%rax
  js     L42
  mov    (%rsp),%rcx
  sub    $0x1,%r12d
  lea    -0x8(%rbp,%rcx,1),%r15
L35:
  cmp    %ebx,%r12d
  jle    L105
L76:
  movslq %ebx,%rax
  mov    (%r14),%rsi
  mov    %r13,%rdx
  mov    0x0(%rbp,%rax,8),%rdi
  call   <cmp@plt>
  movslq %r12d,%rcx
  shl    $0x3,%rcx
  lea    0x0(%rbp,%rcx,1),%r15
  test   %rax,%rax
  jg     L87
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L76
L105:
  mov    (%r14),%rsi
  mov    (%r15),%rdi
  mov    %r13,%rdx
  lea    0x1(%r12),%ebx
  call   <cmp@plt>
  test   %rax,%rax
  jg     L120
L31:
  mov    0xc(%rsp),%esi
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <sort_lines>
  cmp    0x10(%rsp),%ebx
  jge    L74
  mov    %ebx,0xc(%rsp)
  mov    0x14(%rsp),%r12d
  mov    0xc(%rsp),%ebx
  cmp    %r12d,%ebx
  jl     L76
L123:
  mov    0x18(%rsp),%rax
  mov    (%r14),%rsi
  mov    %r13,%rdx
  mov    (%rax),%rdi
  call   <cmp@plt>
  test   %rax,%rax
  jg     L119
  mov    0x14(%rsp),%eax
  mov    %eax,0x10(%rsp)
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edx
  cmp    %eax,%edx
  jg     L36
L74:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L42:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L35
L119:
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%r12d
  nopl   0x0(%rax,%rax,1)
L120:
  mov    0x10(%rsp),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L31
```

assistant: ```c
void sort_lines(char *line_pointer_array[], int left, int right, int flags[]) {
  if (left >= right)
    return;
  int current_left = left, current_right = right - 1, pivot = right;
  while (current_left < current_right) {
    if (cmp(line_pointer_array[current_left], line_pointer_array[pivot], flags) <= 0) {
      ++current_left;
      continue;
    } else if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) >= 0) {
      --current_right;
      continue;
    } else
      swap(line_pointer_array, current_left, current_right);
  }
  if (cmp(line_pointer_array[current_right], line_pointer_array[pivot], flags) > 0)
    swap(line_pointer_array, pivot, current_right);
  sort_lines(line_pointer_array, left, current_right, flags);
  sort_lines(line_pointer_array, current_right + 1, right, flags);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tcsg__plane_sort_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmpfloats@plt>
  leave
  ret
```

assistant: ```c
int tcsg__plane_sort_cmp(const void *i_a, const void *i_b) {
  const float *a = (const float *)i_a;
  const float *b = (const float *)i_b;
  return cmpfloats(a, b, 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tcsg__plane_sort_cmp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edx
  call   <cmpfloats@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tcsg__plane_sort_cmp(const void *i_a, const void *i_b) {
  const float *a = (const float *)i_a;
  const float *b = (const float *)i_b;
  return cmpfloats(a, b, 4);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tcsg__plane_sort_cmp>:
  endbr64
  mov    $0x4,%edx
  jmp    1050 <cmpfloats@plt>
```

assistant: ```c
int tcsg__plane_sort_cmp(const void *i_a, const void *i_b) {
  const float *a = (const float *)i_a;
  const float *b = (const float *)i_b;
  return cmpfloats(a, b, 4);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tcsg__plane_sort_cmp>:
  endbr64
  mov    $0x4,%edx
  jmp    1050 <cmpfloats@plt>
```

assistant: ```c
int tcsg__plane_sort_cmp(const void *i_a, const void *i_b) {
  const float *a = (const float *)i_a;
  const float *b = (const float *)i_b;
  return cmpfloats(a, b, 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<addToDict>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movss  %xmm0,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  -0x34(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L11
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int addToDict(int dictSize, int features, float *weights, float **dict, float *x, float newWeight, int idx) {
  weights[idx] = newWeight;
  int i;
  for (i = 0; i < features; i++)
    dict[idx][i] = x[i];
  return (idx + 1) % dictSize;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addToDict>:
  endbr64
  movslq %r9d,%rax
  movss  %xmm0,(%rdx,%rax,4)
  test   %esi,%esi
  jle    L14
  lea    (%rcx,%rax,8),%rax
  mov    %esi,%esi
  shl    $0x2,%rsi
  mov    $0x0,%edx
L3:
  movss  (%r8,%rdx,1),%xmm0
  mov    (%rax),%rcx
  movss  %xmm0,(%rcx,%rdx,1)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L3
L14:
  lea    0x1(%r9),%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
```

assistant: ```c
int addToDict(int dictSize, int features, float *weights, float **dict, float *x, float newWeight, int idx) {
  weights[idx] = newWeight;
  int i;
  for (i = 0; i < features; i++)
    dict[idx][i] = x[i];
  return (idx + 1) % dictSize;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<addToDict>:
  endbr64
  movslq %r9d,%rax
  movss  %xmm0,(%rdx,%rax,4)
  test   %esi,%esi
  jle    L17
  mov    (%rcx,%rax,8),%rax
  xor    %edx,%edx
  movslq %esi,%rcx
  nopl   0x0(%rax)
L6:
  movss  (%r8,%rdx,4),%xmm0
  movss  %xmm0,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L6
L17:
  lea    0x1(%r9),%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
```

assistant: ```c
int addToDict(int dictSize, int features, float *weights, float **dict, float *x, float newWeight, int idx) {
  weights[idx] = newWeight;
  int i;
  for (i = 0; i < features; i++)
    dict[idx][i] = x[i];
  return (idx + 1) % dictSize;
}
```