ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_binary_search_recursive_with_one_element_returns_index>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <binary_search_recursive@plt>
  test   %eax,%eax
  jne    L19
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  ret
L19:
  mov    $0x2e,%ecx
  lea    D12(%rip),%rdx
  lea    D10(%rip),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
  jmp    L20
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D22
type: string

tool: D12: test_binary_search_recursive_with_one_element_returns_index

tool: D10: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c

tool: D22: index == 0

assistant: ```c
void test_binary_search_recursive_with_one_element_returns_index(void) {
  int length = 1;
  int array[] = {1};
  int element = 1;
  int index = binary_search_recursive(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c", __FUNCTION__, 46)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_binary_search_recursive_with_one_element_returns_index>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <binary_search_recursive@plt>
  test   %eax,%eax
  jne    L20
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L20:
  mov    $0x2e,%ecx
  lea    D11(%rip),%rdx
  lea    D6(%rip),%rsi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <__test_fail@plt>
  jmp    L23
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D26
type: string

tool: D11: test_binary_search_recursive_with_one_element_returns_index

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c

tool: D26: index == 0

assistant: ```c
void test_binary_search_recursive_with_one_element_returns_index(void) {
  int length = 1;
  int array[] = {1};
  int element = 1;
  int index = binary_search_recursive(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c", __FUNCTION__, 46)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_binary_search_recursive_with_one_element_returns_index>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x1,0x4(%rsp)
  call   <binary_search_recursive@plt>
  test   %eax,%eax
  jne    L8
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L8:
  mov    $0x2e,%ecx
  lea    D2(%rip),%rdx
  lea    D26(%rip),%rsi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <__test_fail@plt>
  jmp    L26
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D26
type: string
name: read_data
arguments: tag: D19
type: string

tool: D2: test_binary_search_recursive_with_one_element_returns_index

tool: D26: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c

tool: D19: index == 0

assistant: ```c
void test_binary_search_recursive_with_one_element_returns_index(void) {
  int length = 1;
  int array[] = {1};
  int element = 1;
  int index = binary_search_recursive(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_binary_search_recursive.c", __FUNCTION__, 46)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<show_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: todo: write the help


assistant: ```c
void show_help() {
  printf("todo: write the help\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: todo: write the help


assistant: ```c
void show_help() {
  printf("todo: write the help\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: todo: write the help


assistant: ```c
void show_help() {
  printf("todo: write the help\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: todo: write the help


assistant: ```c
void show_help() {
  printf("todo: write the help\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<incA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void incA(__attribute__((unused)) void **alloc, __attribute__((unused)) void **in, __attribute__((unused)) void **inout, __attribute__((unused)) void **out) {
  unsigned *v = inout[0];
  v[0]++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<incA>:
  endbr64
  mov    (%rdx),%rax
  addl   $0x1,(%rax)
  ret
```

assistant: ```c
void incA(__attribute__((unused)) void **alloc, __attribute__((unused)) void **in, __attribute__((unused)) void **inout, __attribute__((unused)) void **out) {
  unsigned *v = inout[0];
  v[0]++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<incA>:
  endbr64
  mov    (%rdx),%rax
  addl   $0x1,(%rax)
  ret
```

assistant: ```c
void incA(__attribute__((unused)) void **alloc, __attribute__((unused)) void **in, __attribute__((unused)) void **inout, __attribute__((unused)) void **out) {
  unsigned *v = inout[0];
  v[0]++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<incA>:
  endbr64
  mov    (%rdx),%rax
  addl   $0x1,(%rax)
  ret
```

assistant: ```c
void incA(__attribute__((unused)) void **alloc, __attribute__((unused)) void **in, __attribute__((unused)) void **inout, __attribute__((unused)) void **out) {
  unsigned *v = inout[0];
  v[0]++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NewKreuz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidKnotenName@plt>
  test   %rax,%rax
  je     L58
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L58:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  je     L79
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L79:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  je     L24
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L24:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  je     L90
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L90:
  mov    0x10(%rbp),%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  je     L101
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L101:
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  je     L97
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L97:
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r9d
  mov    0x10(%rbp),%r8
  mov    %rax,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  je     L26
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  jmp    L110
L26:
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <NewAusfahrt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%r9d
  mov    0x10(%rbp),%r8
  mov    %rax,%rdi
  call   <NewAusfahrt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L110:
  leave
  ret
```

assistant: ```c
int NewKreuz(struct Knoten *meineKnoten, int AnzahlKnoten, char *Kname, char *Aname1, char *Akm1, char *Aname2, char *Akm2) {
  int NeueAnzahlKnoten = 0;
  if (isValidKnotenName(Kname))
    return INT_MAX;
  if (isValidAutobahnName(Aname1))
    return INT_MAX;
  if (isValidAutobahnName(Aname2))
    return INT_MAX;
  if (isValidAutobahnKM(Akm1))
    return INT_MAX;
  if (isValidAutobahnKM(Akm2))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname2, Akm2, 0))
    return INT_MAX;
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0);
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, NeueAnzahlKnoten, Kname, Aname2, Akm2, 1);
  return NeueAnzahlKnoten;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<NewKreuz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r8,%r13
  mov    %r9,%r12
  mov    %rdx,%rdi
  call   <isValidKnotenName@plt>
  test   %rax,%rax
  je     L39
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L74:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    %rbp,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  je     L85
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L85:
  mov    %r12,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  je     L57
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L57:
  mov    %r13,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  je     L11
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L11:
  mov    0x40(%rsp),%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  je     L25
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L25:
  mov    $0x0,%r9d
  mov    %r13,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  je     L31
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L31:
  mov    $0x0,%r9d
  mov    0x40(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  je     L40
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L74
L40:
  mov    $0x0,%r9d
  mov    %r13,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <NewAusfahrt@plt>
  mov    %eax,%esi
  mov    $0x1,%r9d
  mov    0x40(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbx,%rdx
  mov    %r14,%rdi
  call   <NewAusfahrt@plt>
  jmp    L74
```

assistant: ```c
int NewKreuz(struct Knoten *meineKnoten, int AnzahlKnoten, char *Kname, char *Aname1, char *Akm1, char *Aname2, char *Akm2) {
  int NeueAnzahlKnoten = 0;
  if (isValidKnotenName(Kname))
    return INT_MAX;
  if (isValidAutobahnName(Aname1))
    return INT_MAX;
  if (isValidAutobahnName(Aname2))
    return INT_MAX;
  if (isValidAutobahnKM(Akm1))
    return INT_MAX;
  if (isValidAutobahnKM(Akm2))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname2, Akm2, 0))
    return INT_MAX;
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0);
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, NeueAnzahlKnoten, Kname, Aname2, Akm2, 1);
  return NeueAnzahlKnoten;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<NewKreuz>:
  endbr64
  push   %r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    0x50(%rsp),%r15
  call   <isValidKnotenName@plt>
  test   %rax,%rax
  je     L15
L7:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L15:
  mov    %r13,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  jne    L7
  mov    %r14,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbx,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  jne    L7
  mov    %r15,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  jne    L7
  mov    0xc(%rsp),%esi
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  jne    L7
  mov    0xc(%rsp),%esi
  xor    %r9d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  jne    L7
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %r9d,%r9d
  call   <NewAusfahrt@plt>
  add    $0x18,%rsp
  mov    %r15,%r8
  mov    %r14,%rcx
  pop    %rbx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%r9d
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <NewAusfahrt@plt>
```

assistant: ```c
int NewKreuz(struct Knoten *meineKnoten, int AnzahlKnoten, char *Kname, char *Aname1, char *Akm1, char *Aname2, char *Akm2) {
  int NeueAnzahlKnoten = 0;
  if (isValidKnotenName(Kname))
    return INT_MAX;
  if (isValidAutobahnName(Aname1))
    return INT_MAX;
  if (isValidAutobahnName(Aname2))
    return INT_MAX;
  if (isValidAutobahnKM(Akm1))
    return INT_MAX;
  if (isValidAutobahnKM(Akm2))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname2, Akm2, 0))
    return INT_MAX;
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0);
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, NeueAnzahlKnoten, Kname, Aname2, Akm2, 1);
  return NeueAnzahlKnoten;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NewKreuz>:
  endbr64
  push   %r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    0x50(%rsp),%r15
  call   <isValidKnotenName@plt>
  test   %rax,%rax
  je     L54
L51:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L54:
  mov    %r13,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  jne    L51
  mov    %r14,%rdi
  call   <isValidAutobahnName@plt>
  test   %rax,%rax
  jne    L51
  mov    %rbx,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  jne    L51
  mov    %r15,%rdi
  call   <isValidAutobahnKM@plt>
  test   %rax,%rax
  jne    L51
  mov    0xc(%rsp),%esi
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  jne    L51
  mov    0xc(%rsp),%esi
  xor    %r9d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <isNewInValid@plt>
  test   %rax,%rax
  jne    L51
  mov    0xc(%rsp),%esi
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %r9d,%r9d
  call   <NewAusfahrt@plt>
  add    $0x18,%rsp
  mov    %r15,%r8
  mov    %r14,%rcx
  pop    %rbx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%r9d
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <NewAusfahrt@plt>
```

assistant: ```c
int NewKreuz(struct Knoten *meineKnoten, int AnzahlKnoten, char *Kname, char *Aname1, char *Akm1, char *Aname2, char *Akm2) {
  int NeueAnzahlKnoten = 0;
  if (isValidKnotenName(Kname))
    return INT_MAX;
  if (isValidAutobahnName(Aname1))
    return INT_MAX;
  if (isValidAutobahnName(Aname2))
    return INT_MAX;
  if (isValidAutobahnKM(Akm1))
    return INT_MAX;
  if (isValidAutobahnKM(Akm2))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0))
    return INT_MAX;
  if (isNewInValid(meineKnoten, AnzahlKnoten, Kname, Aname2, Akm2, 0))
    return INT_MAX;
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, AnzahlKnoten, Kname, Aname1, Akm1, 0);
  NeueAnzahlKnoten = NewAusfahrt(meineKnoten, NeueAnzahlKnoten, Kname, Aname2, Akm2, 1);
  return NeueAnzahlKnoten;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mystrcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L39
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
L39:
  mov    -0x20(%rbp),%rax
  jmp    L9
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L9:
  pop    %rbp
  ret
```

assistant: ```c
char *mystrcpy(const char *src, char *dest) {
  char *current = dest;
  if (!src || !dest)
    return dest;
  while (*src != '\0') {
    *current = *src;
    ++src;
    ++current;
  }
  *current = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mystrcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L5
  test   %rsi,%rsi
  je     L5
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L22
  mov    %rsi,%rcx
L18:
  mov    %dl,(%rcx)
  add    $0x1,%rdi
  add    $0x1,%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L18
L46:
  movb   $0x0,(%rcx)
L5:
  ret
L22:
  mov    %rsi,%rcx
  jmp    L46
```

assistant: ```c
char *mystrcpy(const char *src, char *dest) {
  char *current = dest;
  if (!src || !dest)
    return dest;
  while (*src != '\0') {
    *current = *src;
    ++src;
    ++current;
  }
  *current = '\0';
  return dest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mystrcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L4
  test   %rsi,%rsi
  je     L4
  movzbl (%rdi),%edx
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L19
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rdi
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L15
L19:
  movb   $0x0,(%rcx)
L4:
  ret
```

assistant: ```c
char *mystrcpy(const char *src, char *dest) {
  char *current = dest;
  if (!src || !dest)
    return dest;
  while (*src != '\0') {
    *current = *src;
    ++src;
    ++current;
  }
  *current = '\0';
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<mystrcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L29
  test   %rsi,%rsi
  je     L29
  movzbl (%rdi),%edx
  mov    %rsi,%rcx
  test   %dl,%dl
  je     L19
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
L19:
  movb   $0x0,(%rcx)
L29:
  ret
```

assistant: ```c
char *mystrcpy(const char *src, char *dest) {
  char *current = dest;
  if (!src || !dest)
    return dest;
  while (*src != '\0') {
    *current = *src;
    ++src;
    ++current;
  }
  *current = '\0';
  return dest;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_nl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L69
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L33
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L8
  addl   $0x1,-0x8(%rbp)
  jmp    L33
L8:
  mov    $0x0,%eax
  jmp    L25
L33:
  addl   $0x1,-0x4(%rbp)
L69:
  cmpl   $0x13,-0x4(%rbp)
  jle    L15
  cmpl   $0x4,-0x8(%rbp)
  jne    L74
  mov    $0x1,%eax
  jmp    L25
L74:
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int check_nl(char *str) {
  int n_l;
  int i;
  n_l = 0;
  i = 0;
  while (i < 20) {
    if (str[i] == '\n') {
      if (!((i + 1) % 5))
        n_l++;
      else
        return (0);
    }
    i++;
  }
  if (n_l == 4)
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_nl>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%esi
L2:
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  je     L14
L3:
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L2
  cmp    $0x4,%esi
  sete   %al
  movzbl %al,%eax
  ret
L14:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %eax,%edx
  je     L26
  mov    $0x0,%eax
  ret
L26:
  add    $0x1,%esi
  jmp    L3
```

assistant: ```c
int check_nl(char *str) {
  int n_l;
  int i;
  n_l = 0;
  i = 0;
  while (i < 20) {
    if (str[i] == '\n') {
      if (!((i + 1) % 5))
        n_l++;
      else
        return (0);
    }
    i++;
  }
  if (n_l == 4)
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_nl>:
  endbr64
  mov    $0x1,%eax
  xor    %ecx,%ecx
L8:
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  je     L35
L39:
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L8
  xor    %eax,%eax
  cmp    $0x4,%ecx
  sete   %al
  ret
  nopl   (%rax)
L35:
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  jbe    L2
  xor    %eax,%eax
  ret
L2:
  add    $0x1,%ecx
  jmp    L39
```

assistant: ```c
int check_nl(char *str) {
  int n_l;
  int i;
  n_l = 0;
  i = 0;
  while (i < 20) {
    if (str[i] == '\n') {
      if (!((i + 1) % 5))
        n_l++;
      else
        return (0);
    }
    i++;
  }
  if (n_l == 4)
    return (1);
  return (0);
}
```