ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<puts>:
  endbr64
  push   %rbx
  lea    0x1(%rdi),%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
  nopl   0x0(%rax)
L10:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L10
L2:
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
int puts(const char *s) {
  int a;
  while ((a = *s++))
    putchar(a);
  return putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<puts>:
  endbr64
  push   %rbx
  lea    0x1(%rdi),%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
  nopl   0x0(%rax)
L15:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L15
L16:
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
int puts(const char *s) {
  int a;
  while ((a = *s++))
    putchar(a);
  return putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L85:
  cmp    %rdx,%rsp
  je     L78
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L85
L78:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L64
  orq    $0x0,-0x8(%rsp,%rax,1)
L64:
  mov    %rsp,%rbx
  mov    $0x0,%r12d
  lea    D28(%rip),%r13
L95:
  cmp    %r12d,-0x30(%rbp)
  jle    L16
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jne    L95
  mov    %edx,(%rbx,%r12,4)
  add    $0x1,%r12
  jmp    L95
L16:
  mov    $0x0,%r12d
  lea    D37(%rip),%r13
  lea    D28(%rip),%r14
  jmp    L90
L96:
  add    $0x1,%r12
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %r12d,%eax
  jle    L61
L90:
  mov    %r12d,%eax
  not    %eax
  add    -0x30(%rbp),%eax
  cltq
  mov    (%rbx,%r12,4),%esi
  sub    (%rbx,%rax,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L96
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rbx,%rax,4),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L96
L61:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D28
type_guessed: string
name: read_data
arguments: data_label: D37
type_guessed: string

tool: D28: %d

tool: D37: %d


assistant: ```c
int main() {
  int z, l, a, t;
  a = 0;
  t = 0;
  scanf("%d", &z);
  int popo[z];
  while (a < z) {
    scanf("%d", &l);
    if (l % 2 == 1) {
      popo[a] = l;
      a++;
    }
  }
  do {
    printf("%d\n", (popo[t] - popo[z - t - 1]));
    if (z % 2 != 0)
      printf("%d", popo[z / 2]);
    t++;
  } while (t < z / 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  lea    D18(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L101
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L72
L101:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L37
L61:
  mov    %rsp,%rbx
  xor    %r13d,%r13d
  lea    -0x2c(%rbp),%r14
  jmp    L11
L16:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L54
  mov    -0x30(%rbp),%eax
L11:
  cmp    %r13d,%eax
  jg     L16
  xor    %r14d,%r14d
  lea    D7(%rip),%r13
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %eax,%edx
  add    $0x1,%r14
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r14d,%edx
  jle    L48
L20:
  sub    %r14d,%eax
  mov    (%rbx,%r14,4),%esi
  mov    %r13,%rdi
  sub    $0x1,%eax
  cltq
  sub    (%rbx,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L19
  mov    %eax,%edx
  mov    %r12,%rdi
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rbx,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L48:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L54:
  mov    %edx,(%rbx,%r13,4)
  mov    -0x30(%rbp),%eax
  add    $0x1,%r13
  jmp    L11
L37:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L61
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string

tool: D18: %d

tool: D7: %d


assistant: ```c
int main() {
  int z, l, a, t;
  a = 0;
  t = 0;
  scanf("%d", &z);
  int popo[z];
  while (a < z) {
    scanf("%d", &l);
    if (l % 2 == 1) {
      popo[a] = l;
      a++;
    }
  }
  do {
    printf("%d\n", (popo[t] - popo[z - t - 1]));
    if (z % 2 != 0)
      printf("%d", popo[z / 2]);
    t++;
  } while (t < z / 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  lea    D4(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L127
L71:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L71
L127:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L57
L74:
  mov    %rsp,%rbx
  xor    %r13d,%r13d
  lea    -0x2c(%rbp),%r14
  jmp    L101
L45:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L106
  mov    -0x30(%rbp),%eax
L101:
  cmp    %r13d,%eax
  jg     L45
  xor    %r14d,%r14d
  lea    D13(%rip),%r13
  jmp    L128
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %eax,%edx
  add    $0x1,%r14
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r14d,%edx
  jle    L47
L128:
  sub    %r14d,%eax
  mov    (%rbx,%r14,4),%esi
  mov    %r13,%rdi
  sub    $0x1,%eax
  cltq
  sub    (%rbx,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L54
  mov    %eax,%edx
  mov    %r12,%rdi
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rbx,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L47:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L106:
  mov    %edx,(%rbx,%r13,4)
  mov    -0x30(%rbp),%eax
  add    $0x1,%r13
  jmp    L101
L57:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L74
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D13
data_type: string

tool: D4: %d

tool: D13: %d


assistant: ```c
int main() {
  int z, l, a, t;
  a = 0;
  t = 0;
  scanf("%d", &z);
  int popo[z];
  while (a < z) {
    scanf("%d", &l);
    if (l % 2 == 1) {
      popo[a] = l;
      a++;
    }
  }
  do {
    printf("%d\n", (popo[t] - popo[z - t - 1]));
    if (z % 2 != 0)
      printf("%d", popo[z / 2]);
    t++;
  } while (t < z / 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<computeNormal2EdgeOfTriangle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movss  (%rsi),%xmm0
  subss  (%rdi),%xmm0
  movss  %xmm0,0x4(%rsp)
  movss  0x4(%rsi),%xmm0
  subss  0x4(%rdi),%xmm0
  movss  %xmm0,0x8(%rsp)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdi),%xmm0
  movss  %xmm0,0xc(%rsp)
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <normalizeVector@plt>
  movss  (%r12),%xmm0
  subss  (%rbx),%xmm0
  movss  %xmm0,0x10(%rsp)
  movss  0x4(%r12),%xmm0
  subss  0x4(%rbx),%xmm0
  movss  %xmm0,0x14(%rsp)
  movss  0x8(%r12),%xmm0
  subss  0x8(%rbx),%xmm0
  movss  %xmm0,0x18(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <normalizeVector@plt>
  lea    0x1c(%rsp),%r12
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %r12,%rdi
  call   <normalizeVector@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %rbp,%rdi
  call   <normalizeVector@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <dotVectors@plt>
  test   %rax,%rax
  js     L15
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  movss  0x0(%rbp),%xmm0
  movss  D4(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x4(%rbp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbp)
  movss  0x8(%rbp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rbp)
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x80]}

assistant: ```c
void computeNormal2EdgeOfTriangle(const float *v0, const float *v1, const float *v2, float *norm2edge) {
  float v0v1[3], v0v2[3], norm2triangle[3];
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  normalizeVector(v0v1);
  v0v2[0] = v2[0] - v0[0];
  v0v2[1] = v2[1] - v0[1];
  v0v2[2] = v2[2] - v0[2];
  normalizeVector(v0v2);
  crossVectors(v0v1, v0v2, norm2triangle);
  normalizeVector(norm2triangle);
  crossVectors(v0v1, norm2triangle, norm2edge);
  normalizeVector(norm2edge);
  if (dotVectors(v0v2, norm2edge) < 0) {
    norm2edge[0] = -norm2edge[0];
    norm2edge[1] = -norm2edge[1];
    norm2edge[2] = -norm2edge[2];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<computeNormal2EdgeOfTriangle>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movss  (%rsi),%xmm0
  subss  (%rdi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  lea    0x1c(%rsp),%r14
  movss  %xmm0,0x4(%rsp)
  movss  0x4(%rsi),%xmm0
  subss  0x4(%rdi),%xmm0
  movss  %xmm0,0x8(%rsp)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdi),%xmm0
  mov    %r13,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <normalizeVector@plt>
  movss  (%r12),%xmm0
  subss  (%rbx),%xmm0
  movss  %xmm0,0x10(%rsp)
  movss  0x4(%r12),%xmm0
  subss  0x4(%rbx),%xmm0
  movss  %xmm0,0x14(%rsp)
  movss  0x8(%r12),%xmm0
  subss  0x8(%rbx),%xmm0
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  movss  %xmm0,0x18(%rsp)
  call   <normalizeVector@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %r14,%rdi
  call   <normalizeVector@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %rbp,%rdi
  call   <normalizeVector@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <dotVectors@plt>
  test   %rax,%rax
  jns    L16
  movss  0x0(%rbp),%xmm0
  movss  D1(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x4(%rbp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbp)
  movss  0x8(%rbp),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rbp)
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
void computeNormal2EdgeOfTriangle(const float *v0, const float *v1, const float *v2, float *norm2edge) {
  float v0v1[3], v0v2[3], norm2triangle[3];
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  normalizeVector(v0v1);
  v0v2[0] = v2[0] - v0[0];
  v0v2[1] = v2[1] - v0[1];
  v0v2[2] = v2[2] - v0[2];
  normalizeVector(v0v2);
  crossVectors(v0v1, v0v2, norm2triangle);
  normalizeVector(norm2triangle);
  crossVectors(v0v1, norm2triangle, norm2edge);
  normalizeVector(norm2edge);
  if (dotVectors(v0v2, norm2edge) < 0) {
    norm2edge[0] = -norm2edge[0];
    norm2edge[1] = -norm2edge[1];
    norm2edge[2] = -norm2edge[2];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<computeNormal2EdgeOfTriangle>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  movq   (%rsi),%xmm0
  movq   (%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  subps  %xmm1,%xmm0
  movlps %xmm0,(%rsp)
  movss  0x8(%rsi),%xmm0
  subss  0x8(%rdi),%xmm0
  mov    %r13,%rdi
  movss  %xmm0,0x8(%rsp)
  call   <normalizeVector@plt>
  movq   0x0(%rbp),%xmm1
  movq   (%r12),%xmm0
  subps  %xmm1,%xmm0
  movlps %xmm0,0x10(%rsp)
  movss  0x8(%r12),%xmm0
  subss  0x8(%rbp),%xmm0
  lea    0x10(%rsp),%rbp
  lea    0x1c(%rsp),%r12
  mov    %rbp,%rdi
  movss  %xmm0,0x18(%rsp)
  call   <normalizeVector@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %r12,%rdi
  call   <normalizeVector@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <crossVectors@plt>
  mov    %rbx,%rdi
  call   <normalizeVector@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <dotVectors@plt>
  test   %rax,%rax
  jns    L18
  movq   D18(%rip),%xmm2
  movq   (%rbx),%xmm0
  xorps  %xmm2,%xmm0
  movlps %xmm0,(%rbx)
  movss  0x8(%rbx),%xmm0
  xorps  D14(%rip),%xmm0
  movss  %xmm0,0x8(%rbx)
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: byte[8]
name: unpack_data
arguments: label: D14
type_guessed: byte[16]

tool: {"D18": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80]}

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void computeNormal2EdgeOfTriangle(const float *v0, const float *v1, const float *v2, float *norm2edge) {
  float v0v1[3], v0v2[3], norm2triangle[3];
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  normalizeVector(v0v1);
  v0v2[0] = v2[0] - v0[0];
  v0v2[1] = v2[1] - v0[1];
  v0v2[2] = v2[2] - v0[2];
  normalizeVector(v0v2);
  crossVectors(v0v1, v0v2, norm2triangle);
  normalizeVector(norm2triangle);
  crossVectors(v0v1, norm2triangle, norm2edge);
  normalizeVector(norm2edge);
  if (dotVectors(v0v2, norm2edge) < 0) {
    norm2edge[0] = -norm2edge[0];
    norm2edge[1] = -norm2edge[1];
    norm2edge[2] = -norm2edge[2];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strtoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L11
L7:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L7
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int strtoint(char string[]) {
  unsigned int N = 0, tens = 1;
  char *newstring = trim(string);
  int i = 0, len = strlen(newstring);
  while (i < len) {
    N += (newstring[len - i - 1] - 48) * tens;
    tens *= 10;
    i++;
  }
  return N;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtoint>:
  endbr64
  push   %rbx
  call   <trim@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rcx
  lea    -0x2(%rbx,%rdx,1),%rdi
  lea    -0x1(%rax),%eax
  sub    %rax,%rdi
  mov    $0x1,%eax
  mov    $0x0,%esi
L13:
  movsbl (%rcx),%edx
  sub    $0x30,%edx
  imul   %eax,%edx
  add    %edx,%esi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L13
L29:
  mov    %esi,%eax
  pop    %rbx
  ret
L12:
  mov    $0x0,%esi
  jmp    L29
```

assistant: ```c
unsigned int strtoint(char string[]) {
  unsigned int N = 0, tens = 1;
  char *newstring = trim(string);
  int i = 0, len = strlen(newstring);
  while (i < len) {
    N += (newstring[len - i - 1] - 48) * tens;
    tens *= 10;
    i++;
  }
  return N;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtoint>:
  endbr64
  push   %rbx
  call   <trim@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  movslq %eax,%rdx
  sub    $0x1,%eax
  xor    %r8d,%r8d
  lea    -0x2(%rbx,%rdx,1),%rsi
  lea    -0x1(%rbx,%rdx,1),%rcx
  sub    %rax,%rsi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L11:
  movsbl (%rcx),%edx
  sub    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rcx,%rsi
  jne    L11
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int strtoint(char string[]) {
  unsigned int N = 0, tens = 1;
  char *newstring = trim(string);
  int i = 0, len = strlen(newstring);
  while (i < len) {
    N += (newstring[len - i - 1] - 48) * tens;
    tens *= 10;
    i++;
  }
  return N;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strtoint>:
  endbr64
  push   %rbx
  call   <trim@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  movslq %eax,%rdx
  sub    $0x1,%eax
  xor    %r8d,%r8d
  lea    -0x2(%rbx,%rdx,1),%rsi
  lea    -0x1(%rbx,%rdx,1),%rcx
  sub    %rax,%rsi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L19:
  movsbl (%rcx),%edx
  sub    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rcx,%rsi
  jne    L19
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int strtoint(char string[]) {
  unsigned int N = 0, tens = 1;
  char *newstring = trim(string);
  int i = 0, len = strlen(newstring);
  while (i < len) {
    N += (newstring[len - i - 1] - 48) * tens;
    tens *= 10;
    i++;
  }
  return N;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_arcs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x30(%rbp)
  jmp    L41
L2:
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L30
L34:
  mov    -0x38(%rbp),%rax
  movsd  -0x10(%rax),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  movsd  -0x8(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  subq   $0x10,-0x38(%rbp)
L30:
  mov    -0x38(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jbe    L55
  mov    -0x38(%rbp),%rax
  sub    $0x10,%rax
  movsd  (%rax),%xmm0
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm1,%xmm0
  ja     L34
L55:
  movsd  -0x20(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x10,-0x30(%rbp)
L41:
  mov    -0x30(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
void sort_arcs(double *restrict arc, int n) {
  double tmp[2];
  double *end = arc + 2 * n, *arcj, *arci;
  for (arci = arc + 2; arci < end; arci += 2) {
    *tmp = *arci;
    *(tmp + 1) = *(arci + 1);
    arcj = arci;
    while (arcj > arc && *(arcj - 2) > tmp[0]) {
      *arcj = *(arcj - 2);
      *(arcj + 1) = *(arcj - 1);
      arcj -= 2;
    }
    *arcj = *tmp;
    *(arcj + 1) = *(tmp + 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort_arcs>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  cltq
  lea    (%rdi,%rax,8),%rcx
  lea    0x10(%rdi),%rdx
  cmp    %rdx,%rcx
  ja     L17
L16:
  ret
L14:
  movsd  %xmm1,(%rax)
  movsd  %xmm2,0x8(%rax)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jbe    L16
L17:
  movsd  (%rdx),%xmm1
  movsd  0x8(%rdx),%xmm2
  mov    %rdx,%rax
  cmp    %rdx,%rdi
  jae    L14
L56:
  movsd  -0x10(%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L14
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rax)
  sub    $0x10,%rax
  cmp    %rax,%rdi
  jb     L56
  jmp    L14
```

assistant: ```c
void sort_arcs(double *restrict arc, int n) {
  double tmp[2];
  double *end = arc + 2 * n, *arcj, *arci;
  for (arci = arc + 2; arci < end; arci += 2) {
    *tmp = *arci;
    *(tmp + 1) = *(arci + 1);
    arcj = arci;
    while (arcj > arc && *(arcj - 2) > tmp[0]) {
      *arcj = *(arcj - 2);
      *(arcj + 1) = *(arcj - 1);
      arcj -= 2;
    }
    *arcj = *tmp;
    *(arcj + 1) = *(tmp + 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sort_arcs>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  lea    0x10(%rdi),%rdx
  cltq
  lea    (%rdi,%rax,8),%rcx
  cmp    %rdx,%rcx
  jbe    L20
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsd  (%rdx),%xmm1
  movsd  0x8(%rdx),%xmm2
  mov    %rdx,%rax
  cmp    %rdx,%rdi
  jb     L28
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L42:
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rax),%xmm0
  sub    $0x10,%rax
  movsd  %xmm0,0x18(%rax)
  cmp    %rax,%rdi
  jae    L10
L28:
  movsd  -0x10(%rax),%xmm0
  comisd %xmm1,%xmm0
  ja     L42
L10:
  add    $0x10,%rdx
  movsd  %xmm1,(%rax)
  movsd  %xmm2,0x8(%rax)
  cmp    %rdx,%rcx
  ja     L4
L20:
  ret
```

assistant: ```c
void sort_arcs(double *restrict arc, int n) {
  double tmp[2];
  double *end = arc + 2 * n, *arcj, *arci;
  for (arci = arc + 2; arci < end; arci += 2) {
    *tmp = *arci;
    *(tmp + 1) = *(arci + 1);
    arcj = arci;
    while (arcj > arc && *(arcj - 2) > tmp[0]) {
      *arcj = *(arcj - 2);
      *(arcj + 1) = *(arcj - 1);
      arcj -= 2;
    }
    *arcj = *tmp;
    *(arcj + 1) = *(tmp + 1);
  }
}
```