ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<precess_3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  ucomisd D0(%rip),%xmm0
  jp     L76
  je     L63
L76:
  cmp    $0xa,%ecx
  je     L57
  lea    0x20(%rsp),%rdi
  call   <pre_pmat@plt>
L74:
  cmp    $0xffffffff,%ebp
  je     L31
  movsd  (%rbx),%xmm4
  movsd  0x8(%rbx),%xmm3
  movsd  0x10(%rbx),%xmm2
  lea    0x20(%rsp),%rax
  mov    %rsp,%rdx
  lea    0x38(%rsp),%rcx
L80:
  movapd %xmm4,%xmm0
  mulsd  (%rax),%xmm0
  movapd %xmm3,%xmm1
  mulsd  0x18(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  0x30(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L80
L36:
  movsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rbx)
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
L63:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L57:
  lea    0x20(%rsp),%rdi
  mov    %edx,%esi
  call   <owen_pre_matrix@plt>
  jmp    L74
L31:
  movsd  (%rbx),%xmm4
  movsd  0x8(%rbx),%xmm3
  movsd  0x10(%rbx),%xmm2
  lea    0x20(%rsp),%rax
  mov    %rsp,%rdx
  lea    0x68(%rsp),%rcx
L1:
  movapd %xmm4,%xmm0
  mulsd  (%rax),%xmm0
  movapd %xmm3,%xmm1
  mulsd  0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  0x10(%rax),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x18,%rax
  add    $0x8,%rdx
  cmp    %rcx,%rax
  jne    L1
  jmp    L36
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: f64

tool: D0: 2451545

assistant: ```c
int precess_3(double *R, double J, int direction, int iflag, int prec_meth) {
  double x[3], pmat[9];
  int i, j;
  if (J == 2451545.0)
    return (0);
  if (prec_meth == 10)
    owen_pre_matrix(J, pmat, iflag);
  else
    pre_pmat(J, pmat);
  if (direction == -1) {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[j + 0] + R[1] * pmat[j + 1] + R[2] * pmat[j + 2];
    }
  } else {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[i + 0] + R[1] * pmat[i + 3] + R[2] * pmat[i + 6];
    }
  }
  for (i = 0; i < 3; i++)
    R[i] = x[i];
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<precess_3>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  ucomisd D5(%rip),%xmm0
  jp     L26
  je     L38
L26:
  lea    0x20(%rsp),%rbx
  cmp    $0xa,%ecx
  je     L12
  mov    %rbx,%rdi
  call   <pre_pmat@plt>
L54:
  movsd  0x0(%rbp),%xmm1
  movsd  0x8(%rbp),%xmm2
  mov    %rbx,%rax
  mov    %rsp,%rdx
  movsd  0x10(%rbp),%xmm3
  lea    0x38(%rsp),%rcx
  cmp    $0xffffffff,%r12d
  je     L71
L65:
  movsd  (%rax),%xmm0
  movsd  0x18(%rax),%xmm4
  add    $0x8,%rax
  add    $0x8,%rdx
  mulsd  %xmm2,%xmm4
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm0
  movsd  0x28(%rax),%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rax,%rcx
  jne    L65
L88:
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rbp)
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbp)
L38:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %edx,%esi
  mov    %rbx,%rdi
  call   <owen_pre_matrix@plt>
  jmp    L54
  nop
L71:
  lea    0x68(%rsp),%rcx
L5:
  movsd  (%rax),%xmm0
  movsd  0x8(%rax),%xmm4
  add    $0x18,%rax
  add    $0x8,%rdx
  mulsd  %xmm2,%xmm4
  mulsd  %xmm1,%xmm0
  addsd  %xmm4,%xmm0
  movsd  -0x8(%rax),%xmm4
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rax,%rcx
  jne    L5
  jmp    L88
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: f64

tool: D5: 2451545

assistant: ```c
int precess_3(double *R, double J, int direction, int iflag, int prec_meth) {
  double x[3], pmat[9];
  int i, j;
  if (J == 2451545.0)
    return (0);
  if (prec_meth == 10)
    owen_pre_matrix(J, pmat, iflag);
  else
    pre_pmat(J, pmat);
  if (direction == -1) {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[j + 0] + R[1] * pmat[j + 1] + R[2] * pmat[j + 2];
    }
  } else {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[i + 0] + R[1] * pmat[i + 3] + R[2] * pmat[i + 6];
    }
  }
  for (i = 0; i < 3; i++)
    R[i] = x[i];
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<precess_3>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  ucomisd D2(%rip),%xmm0
  jp     L47
  je     L30
L47:
  lea    0x20(%rsp),%rdi
  cmp    $0xa,%ecx
  je     L5
  call   <pre_pmat@plt>
L60:
  movsd  (%rbx),%xmm3
  movsd  0x8(%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  cmp    $0xffffffff,%ebp
  je     L45
  movapd %xmm0,%xmm4
  movupd 0x38(%rsp),%xmm7
  movapd %xmm3,%xmm1
  mulsd  0x48(%rsp),%xmm0
  unpcklpd %xmm4,%xmm4
  unpcklpd %xmm1,%xmm1
  mulpd  %xmm7,%xmm4
  mulpd  0x20(%rsp),%xmm1
  mulsd  0x30(%rsp),%xmm3
  addpd  %xmm4,%xmm1
  movapd %xmm2,%xmm4
  unpcklpd %xmm4,%xmm4
  mulpd  0x50(%rsp),%xmm4
  addpd  %xmm4,%xmm1
  movaps %xmm1,(%rsp)
L63:
  mulsd  0x60(%rsp),%xmm2
  addsd  %xmm3,%xmm0
  movups %xmm1,(%rbx)
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm0,0x10(%rbx)
L30:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %edx,%esi
  call   <owen_pre_matrix@plt>
  jmp    L60
  nopl   0x0(%rax)
L45:
  movapd 0x20(%rsp),%xmm5
  movapd %xmm0,%xmm4
  movapd %xmm3,%xmm6
  mulsd  0x58(%rsp),%xmm0
  unpcklpd %xmm4,%xmm4
  unpcklpd %xmm6,%xmm6
  mulsd  0x50(%rsp),%xmm3
  movapd %xmm5,%xmm1
  shufpd $0x1,%xmm5,%xmm1
  movhpd 0x40(%rsp),%xmm1
  mulpd  %xmm4,%xmm1
  movapd %xmm5,%xmm4
  movhps 0x38(%rsp),%xmm4
  mulpd  %xmm6,%xmm4
  addpd  %xmm4,%xmm1
  movapd 0x30(%rsp),%xmm4
  unpcklpd %xmm5,%xmm4
  movapd %xmm2,%xmm5
  movhps 0x48(%rsp),%xmm4
  unpcklpd %xmm5,%xmm5
  mulpd  %xmm5,%xmm4
  addpd  %xmm4,%xmm1
  movaps %xmm1,(%rsp)
  jmp    L63
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: f64

tool: D2: 2451545

assistant: ```c
int precess_3(double *R, double J, int direction, int iflag, int prec_meth) {
  double x[3], pmat[9];
  int i, j;
  if (J == 2451545.0)
    return (0);
  if (prec_meth == 10)
    owen_pre_matrix(J, pmat, iflag);
  else
    pre_pmat(J, pmat);
  if (direction == -1) {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[j + 0] + R[1] * pmat[j + 1] + R[2] * pmat[j + 2];
    }
  } else {
    for (i = 0, j = 0; i <= 2; i++, j = i * 3) {
      x[i] = R[0] * pmat[i + 0] + R[1] * pmat[i + 3] + R[2] * pmat[i + 6];
    }
  }
  for (i = 0; i < 3; i++)
    R[i] = x[i];
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<charcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int charcount(char *word, int len) {
  int i, ct;
  ct = 0;
  for (i = 0; i < len; i++) {
    ct += isalnum(word[i]) ? 1 : 0;
  }
  return ct;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<charcount>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L23
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%ebp
L22:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L22
L2:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x0,%ebp
  jmp    L2
```

assistant: ```c
int charcount(char *word, int len) {
  int i, ct;
  ct = 0;
  for (i = 0; i < len; i++) {
    ct += isalnum(word[i]) ? 1 : 0;
  }
  return ct;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<charcount>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int charcount(char *word, int len) {
  int i, ct;
  ct = 0;
  for (i = 0; i < len; i++) {
    ct += isalnum(word[i]) ? 1 : 0;
  }
  return ct;
}
```
user: Translate the below assembly code into C programming language:

```asm
<charcount>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  call   <isalnum@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int charcount(char *word, int len) {
  int i, ct;
  ct = 0;
  for (i = 0; i < len; i++) {
    ct += isalnum(word[i]) ? 1 : 0;
  }
  return ct;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<module_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: Welcome to dark ocean! hope you will not give up learning me!


assistant: ```c
int module_start(void) {
  printk("Welcome to dark ocean! hope you will not give up learning me!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<module_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printk@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Welcome to dark ocean! hope you will not give up learning me!


assistant: ```c
int module_start(void) {
  printk("Welcome to dark ocean! hope you will not give up learning me!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<module_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: Welcome to dark ocean! hope you will not give up learning me!


assistant: ```c
int module_start(void) {
  printk("Welcome to dark ocean! hope you will not give up learning me!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<module_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Welcome to dark ocean! hope you will not give up learning me!


assistant: ```c
int module_start(void) {
  printk("Welcome to dark ocean! hope you will not give up learning me!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<grouping_algorithm_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <new_puzzle@plt>
  test   %rax,%rax
  je     L1
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <print_target_grid_valid_values@plt>
  movl   $0x1,-0x34(%rbp)
  jmp    L40
L50:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L21
L37:
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%ecx
  mov    -0x34(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <grouping_algorithm@plt>
  addl   $0x1,-0x30(%rbp)
L21:
  cmpl   $0x8,-0x30(%rbp)
  jle    L37
  addl   $0x1,-0x34(%rbp)
L40:
  cmpl   $0x3,-0x34(%rbp)
  jle    L50
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <print_target_grid_valid_values@plt>
L1:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D46
type: string
name: retrieve_data
arguments: tag: D23
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D58
type: string
name: retrieve_data
arguments: tag: D43
type: string
name: retrieve_data
arguments: tag: D64
type: string
name: retrieve_data
arguments: tag: D60
type: string

tool: D46: test/resources/grouping_algorithm.puzzle

tool: D23: =-=-=-Choice=-=-=-

tool: D20: Row

tool: D58: Column

tool: D43: Chamber

tool: D64: Choice: %s


tool: D60: Choice_index: %i


assistant: ```c
char *grouping_algorithm_test() {
  char *test_puzzle = "test/resources/grouping_algorithm.puzzle";
  if (new_puzzle(test_puzzle)) {
    print_target_grid_valid_values(test_puzzle);
    for (int choice = 1; choice <= 3; ++choice) {
      puts("=-=-=-Choice=-=-=-");
      char *choice_array[] = {"Row", "Column", "Chamber"};
      int choice_index = choice - 1;
      printf("Choice: %s\n", choice_array[choice_index]);
      for (int choice_index = 0; choice_index < 9; ++choice_index) {
        printf("Choice_index: %i\n", choice_index);
        grouping_algorithm(choice, choice_index, test_puzzle);
      }
    }
    print_target_grid_valid_values(test_puzzle);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<grouping_algorithm_test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D86(%rip),%rdi
  call   <new_puzzle@plt>
  test   %rax,%rax
  jne    L23
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  lea    D86(%rip),%rdi
  call   <print_target_grid_valid_values@plt>
  mov    $0x1,%r14d
  lea    D59(%rip),%r15
L18:
  mov    %r14d,%r13d
  lea    D91(%rip),%rdi
  call   <puts@plt>
  mov    %r15,(%rsp)
  lea    D23(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    -0x8(%rsp,%r14,8),%rsi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D65(%rip),%r12
  lea    D86(%rip),%rbp
L49:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <grouping_algorithm@plt>
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L49
  add    $0x1,%r14
  cmp    $0x4,%r14
  jne    L18
  lea    D86(%rip),%rdi
  call   <print_target_grid_valid_values@plt>
  jmp    L48
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D86
data_type: string
name: parse_data
arguments: label: D59
data_type: string
name: parse_data
arguments: label: D91
data_type: string
name: parse_data
arguments: label: D23
data_type: string
name: parse_data
arguments: label: D44
data_type: string
name: parse_data
arguments: label: D41
data_type: string
name: parse_data
arguments: label: D65
data_type: string

tool: D86: test/resources/grouping_algorithm.puzzle

tool: D59: Row

tool: D91: =-=-=-Choice=-=-=-

tool: D23: Column

tool: D44: Chamber

tool: D41: Choice: %s


tool: D65: Choice_index: %i


assistant: ```c
char *grouping_algorithm_test() {
  char *test_puzzle = "test/resources/grouping_algorithm.puzzle";
  if (new_puzzle(test_puzzle)) {
    print_target_grid_valid_values(test_puzzle);
    for (int choice = 1; choice <= 3; ++choice) {
      puts("=-=-=-Choice=-=-=-");
      char *choice_array[] = {"Row", "Column", "Chamber"};
      int choice_index = choice - 1;
      printf("Choice: %s\n", choice_array[choice_index]);
      for (int choice_index = 0; choice_index < 9; ++choice_index) {
        printf("Choice_index: %i\n", choice_index);
        grouping_algorithm(choice, choice_index, test_puzzle);
      }
    }
    print_target_grid_valid_values(test_puzzle);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<grouping_algorithm_test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <new_puzzle@plt>
  test   %rax,%rax
  jne    L0
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  mov    $0x1,%r13d
  mov    %rsp,%r14
  call   <print_target_grid_valid_values@plt>
  lea    D34(%rip),%r12
L34:
  lea    D25(%rip),%rdi
  mov    %r13d,%ebx
  xor    %r15d,%r15d
  call   <puts@plt>
  lea    D18(%rip),%rax
  lea    D27(%rip),%rdi
  mov    %rax,(%rsp)
  lea    D4(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D46(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    -0x8(%r14,%r13,8),%rsi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    %r15d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%esi
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <grouping_algorithm@plt>
  add    $0x1,%r15d
  cmp    $0x9,%r15d
  jne    L11
  add    $0x1,%r13
  cmp    $0x4,%r13
  jne    L34
  mov    %rbp,%rdi
  call   <print_target_grid_valid_values@plt>
  jmp    L19
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D34
type: string
name: unpack_data
arguments: data_label: D25
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D46
type: string

tool: D9: test/resources/grouping_algorithm.puzzle

tool: D34: Choice_index: %i


tool: D25: =-=-=-Choice=-=-=-

tool: D18: Row

tool: D27: Choice: %s


tool: D4: Column

tool: D46: Chamber

assistant: ```c
char *grouping_algorithm_test() {
  char *test_puzzle = "test/resources/grouping_algorithm.puzzle";
  if (new_puzzle(test_puzzle)) {
    print_target_grid_valid_values(test_puzzle);
    for (int choice = 1; choice <= 3; ++choice) {
      puts("=-=-=-Choice=-=-=-");
      char *choice_array[] = {"Row", "Column", "Chamber"};
      int choice_index = choice - 1;
      printf("Choice: %s\n", choice_array[choice_index]);
      for (int choice_index = 0; choice_index < 9; ++choice_index) {
        printf("Choice_index: %i\n", choice_index);
        grouping_algorithm(choice, choice_index, test_puzzle);
      }
    }
    print_target_grid_valid_values(test_puzzle);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<grouping_algorithm_test>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdx
  push   %r14
  movq   %rdx,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  lea    D66(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D30(%rip),%rax
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <new_puzzle@plt>
  test   %rax,%rax
  jne    L9
L44:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  mov    %rbp,%rdi
  mov    $0x1,%r13d
  lea    0x10(%rsp),%r14
  call   <print_target_grid_valid_values@plt>
  lea    D18(%rip),%r12
L14:
  lea    D2(%rip),%rdi
  mov    %r13d,%ebx
  xor    %r15d,%r15d
  call   <puts@plt>
  movdqa (%rsp),%xmm2
  lea    D13(%rip),%rax
  lea    D63(%rip),%rdi
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm2,0x10(%rsp)
  mov    -0x8(%r14,%r13,8),%rsi
  call   <printf@plt>
  nopl   (%rax)
L1:
  mov    %r15d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%esi
  mov    %rbp,%rdx
  mov    %ebx,%edi
  call   <grouping_algorithm@plt>
  add    $0x1,%r15d
  cmp    $0x9,%r15d
  jne    L1
  add    $0x1,%r13
  cmp    $0x4,%r13
  jne    L14
  mov    %rbp,%rdi
  call   <print_target_grid_valid_values@plt>
  jmp    L44
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D66
type: string
name: parse_data
arguments: data_tag: D30
type: string
name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D63
type: string

tool: D10: Row

tool: D66: test/resources/grouping_algorithm.puzzle

tool: D30: Column

tool: D18: Choice_index: %i


tool: D2: =-=-=-Choice=-=-=-

tool: D13: Chamber

tool: D63: Choice: %s


assistant: ```c
char *grouping_algorithm_test() {
  char *test_puzzle = "test/resources/grouping_algorithm.puzzle";
  if (new_puzzle(test_puzzle)) {
    print_target_grid_valid_values(test_puzzle);
    for (int choice = 1; choice <= 3; ++choice) {
      puts("=-=-=-Choice=-=-=-");
      char *choice_array[] = {"Row", "Column", "Chamber"};
      int choice_index = choice - 1;
      printf("Choice: %s\n", choice_array[choice_index]);
      for (int choice_index = 0; choice_index < 9; ++choice_index) {
        printf("Choice_index: %i\n", choice_index);
        grouping_algorithm(choice, choice_index, test_puzzle);
      }
    }
    print_target_grid_valid_values(test_puzzle);
  }
  return 0;
}
```