ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x34(%rbp)
  je     L52
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L52:
  movl   $0x0,-0x28(%rbp)
  jmp    L39
L28:
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x18(%rbp,%rax,8)
  addl   $0x1,-0x28(%rbp)
L39:
  cmpl   $0x0,-0x28(%rbp)
  jle    L28
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0x10(%rbp),%rax
  movabs $0x137026cf13eacf17,%rdx
  cmp    %rdx,%rax
  jne    L40
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L40:
  movl   $0x0,-0x24(%rbp)
  jmp    L3
L46:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L3:
  cmpl   $0x0,-0x24(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string

tool: D10: Call this program with %i arguments


tool: D14: You win!

tool: D5: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1400662154946465559UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L15
L26:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0x137026cf13eacf17,%rax
  cmp    %rax,0x10(%rsp)
  je     L49
L5:
  mov    0x10(%rsp),%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L26
L49:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D4: %lu


tool: D26: Call this program with %i arguments


tool: D1: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1400662154946465559UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L0
  lea    D4(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L0:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x137026cf13eacf17,%rax
  cmp    %rax,%rsi
  je     L11
L34:
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L34
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D4: Call this program with %i arguments


tool: D16: %lu


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1400662154946465559UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L29
  lea    D1(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x137026cf13eacf17,%rax
  cmp    %rax,%rsi
  je     L32
L10:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L10
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D24
data_type: string

tool: D1: Call this program with %i arguments


tool: D17: %lu


tool: D24: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1400662154946465559UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<save_smatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x10(%rbp),%rcx
  mov    %rax,%rdx
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  push   %rdi
  lea    D34(%rip),%r9
  mov    %rax,%rdi
  call   <write_smatrix@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D34
type_guessed: string

tool: D33: %s/%s

tool: D34: %4d

assistant: ```c
void save_smatrix(short **m, long nrl, long nrh, long ncl, long nch, char *path, char *filename) {
  static char complete_filename[256];
  sprintf(complete_filename, "%s/%s", path, filename);
  write_smatrix(m, nrl, nrh, ncl, nch, "%4d", complete_filename);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<save_smatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %r9,%rdx
  mov    0x40(%rsp),%rcx
  lea    D1(%rip),%rsi
  lea    D16(%rip),%r15
  mov    %r15,%rdi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  push   %r15
  lea    D20(%rip),%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <write_smatrix@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string

tool: D1: %s/%s

tool: D20: %4d

assistant: ```c
void save_smatrix(short **m, long nrl, long nrh, long ncl, long nch, char *path, char *filename) {
  static char complete_filename[256];
  sprintf(complete_filename, "%s/%s", path, filename);
  write_smatrix(m, nrl, nrh, ncl, nch, "%4d", complete_filename);
}
```
user: Translate the below assembly code into C programming language:

```asm
<save_smatrix>:
  endbr64
  push   %r15
  lea    D2(%rip),%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r9,%rdx
  push   %r12
  mov    %rsi,%r12
  lea    D1(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r15,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%rcx
  call   <sprintf@plt>
  mov    %r15,0x40(%rsp)
  mov    %rbx,%r8
  mov    %r14,%rcx
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  lea    D4(%rip),%r9
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <write_smatrix@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D1: %s/%s

tool: D4: %4d

assistant: ```c
void save_smatrix(short **m, long nrl, long nrh, long ncl, long nch, char *path, char *filename) {
  static char complete_filename[256];
  sprintf(complete_filename, "%s/%s", path, filename);
  write_smatrix(m, nrl, nrh, ncl, nch, "%4d", complete_filename);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<save_smatrix>:
  endbr64
  push   %r15
  lea    D21(%rip),%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r9,%rdx
  push   %r12
  mov    %rsi,%r12
  lea    D15(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r15,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%rcx
  call   <sprintf@plt>
  mov    %r15,0x40(%rsp)
  mov    %rbx,%r8
  mov    %r14,%rcx
  add    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  lea    D23(%rip),%r9
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <write_smatrix@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string

tool: D15: %s/%s

tool: D23: %4d

assistant: ```c
void save_smatrix(short **m, long nrl, long nrh, long ncl, long nch, char *path, char *filename) {
  static char complete_filename[256];
  sprintf(complete_filename, "%s/%s", path, filename);
  write_smatrix(m, nrl, nrh, ncl, nch, "%4d", complete_filename);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x2a,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L2
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  mov    -0xc(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  int l, count, i, end = 42, k;
  l = strlen(word);
  for (count = 0, i = 1; count < l; count++, i++) {
    k = word[count];
    k = k * i;
    end = end + k;
  }
  return end;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  lea    0x1(%rax),%esi
  mov    $0x1,%edx
  mov    $0x2a,%eax
L24:
  movsbl -0x1(%rbx,%rdx,1),%ecx
  imul   %edx,%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L24
L12:
  cltq
  pop    %rbx
  ret
L13:
  mov    $0x2a,%eax
  jmp    L12
```

assistant: ```c
long hash(char *word) {
  int l, count, i, end = 42, k;
  l = strlen(word);
  for (count = 0, i = 1; count < l; count++, i++) {
    k = word[count];
    k = k * i;
    end = end + k;
  }
  return end;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  lea    0x1(%rax),%esi
  mov    $0x1,%edx
  mov    $0x2a,%eax
  xchg   %ax,%ax
L5:
  movsbl -0x1(%rbx,%rdx,1),%ecx
  imul   %edx,%ecx
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L5
  cltq
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x2a,%eax
  pop    %rbx
  ret
```

assistant: ```c
long hash(char *word) {
  int l, count, i, end = 42, k;
  l = strlen(word);
  for (count = 0, i = 1; count < l; count++, i++) {
    k = word[count];
    k = k * i;
    end = end + k;
  }
  return end;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fourcc_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %al,D37(%rip)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %al,D1(%rip)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %al,D0(%rip)
  mov    -0x4(%rbp),%eax
  sar    $0x18,%eax
  mov    %al,D20(%rip)
  movb   $0x0,D45(%rip)
  lea    D37(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *fourcc_str(int i) {
  static char str[5];
  str[0] = ((char)(i & 0xFF)), str[1] = ((char)((i >> 8) & 0xFF)), str[2] = ((char)((i >> 16) & 0xFF)), str[3] = ((char)((i >> 24) & 0xFF)), str[4] = '\0';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fourcc_str>:
  endbr64
  mov    %edi,%eax
  mov    %dil,D30(%rip)
  mov    %ah,D27(%rip)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %dl,D22(%rip)
  sar    $0x18,%eax
  mov    %al,D2(%rip)
  movb   $0x0,D49(%rip)
  lea    D30(%rip),%rax
  ret
```

assistant: ```c
char *fourcc_str(int i) {
  static char str[5];
  str[0] = ((char)(i & 0xFF)), str[1] = ((char)((i >> 8) & 0xFF)), str[2] = ((char)((i >> 16) & 0xFF)), str[3] = ((char)((i >> 24) & 0xFF)), str[4] = '\0';
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fourcc_str>:
  endbr64
  mov    %edi,D29(%rip)
  lea    D29(%rip),%rax
  movb   $0x0,D8(%rip)
  ret
```

assistant: ```c
char *fourcc_str(int i) {
  static char str[5];
  str[0] = ((char)(i & 0xFF)), str[1] = ((char)((i >> 8) & 0xFF)), str[2] = ((char)((i >> 16) & 0xFF)), str[3] = ((char)((i >> 24) & 0xFF)), str[4] = '\0';
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<fourcc_str>:
  endbr64
  mov    %edi,D21(%rip)
  lea    D21(%rip),%rax
  movb   $0x0,D28(%rip)
  ret
```

assistant: ```c
char *fourcc_str(int i) {
  static char str[5];
  str[0] = ((char)(i & 0xFF)), str[1] = ((char)((i >> 8) & 0xFF)), str[2] = ((char)((i >> 16) & 0xFF)), str[3] = ((char)((i >> 24) & 0xFF)), str[4] = '\0';
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L31
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L53
  mov    D9(%rip),%rax
  mov    (%rax),%rdx
  mov    D38(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L53
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L53
L31:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L53
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    %rdx,(%rax)
  movl   $0xffffffff,-0x14(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st = {0};
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0 && errno != EEXIST)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L58
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L24
  mov    D39(%rip),%rdx
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L24
L58:
  mov    (%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L13
  mov    $0x0,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    D17(%rip),%rax
  mov    (%rax),%rdx
  mov    D39(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L24
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st = {0};
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0 && errno != EEXIST)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_mkdir>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <stat@plt>
  test   %rax,%rax
  je     L51
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jne    L35
L6:
  xor    %eax,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L51:
  mov    (%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L6
  mov    D36(%rip),%rax
  mov    (%rax),%rdx
  mov    D26(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L35:
  mov    D26(%rip),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L24
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st = {0};
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0 && errno != EEXIST)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_mkdir>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <stat@plt>
  test   %rax,%rax
  je     L40
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jne    L20
L55:
  xor    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    (%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L55
  mov    D35(%rip),%rax
  mov    (%rax),%rdx
  mov    D21(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L20:
  mov    D21(%rip),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L4
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st = {0};
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0 && errno != EEXIST)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ieee1888_mk_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ieee1888_mk_string(const char *str) {
  int len = strlen(str);
  char *p = (char *)malloc(len + 1);
  strcpy(p, str);
  return p;
}
```