ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<_concat_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x34(%rbp)
  jne    L31
  cmpq   $0x0,-0x48(%rbp)
  je     L44
  mov    -0x48(%rbp),%rax
  mov    -0x38(%rbp),%edx
  mov    %edx,(%rax)
L44:
  mov    -0x38(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_pbcS_build@plt>
  jmp    L4
L31:
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x48(%rbp)
  je     L23
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
L23:
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_pbcS_build@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
const char *_concat_name(struct _stringpool *p, const char *prefix, int prefix_sz, const char *name, int name_sz, int *sz) {
  if (prefix_sz == 0) {
    if (sz) {
      *sz = name_sz;
    }
    return _pbcS_build(p, name, name_sz);
  }
  char *temp = (char *)alloca(name_sz + prefix_sz + 2);
  memcpy(temp, prefix, prefix_sz);
  temp[prefix_sz] = '.';
  memcpy(temp + prefix_sz + 1, name, name_sz);
  temp[name_sz + prefix_sz + 1] = '\0';
  if (sz) {
    *sz = name_sz + prefix_sz + 1;
  }
  const char *ret = _pbcS_build(p, temp, name_sz + prefix_sz + 1);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_concat_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x58(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8d,%r12d
  mov    %r9,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %edx,%edx
  jne    L2
  test   %r9,%r9
  je     L17
  mov    %r8d,0x0(%r13)
L17:
  mov    %r12d,%edx
  mov    -0x50(%rbp),%rsi
  mov    -0x48(%rbp),%rdi
  call   <_pbcS_build@plt>
L31:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  mov    %edx,%ebx
  lea    (%rdx,%r8,1),%r15d
  lea    0x2(%r15),%edi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    -0x58(%rbp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x2e,(%r14,%rbx,1)
  lea    0x1(%r14,%rbx,1),%rdi
  mov    %r12d,%edx
  mov    -0x50(%rbp),%rsi
  call   <memcpy@plt>
  movslq %r15d,%rax
  movb   $0x0,0x1(%r14,%rax,1)
  test   %r13,%r13
  je     L32
  lea    0x1(%r15),%eax
  mov    %eax,0x0(%r13)
L32:
  lea    0x1(%r15),%edx
  mov    %r14,%rsi
  mov    -0x48(%rbp),%rdi
  call   <_pbcS_build@plt>
  jmp    L31
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *_concat_name(struct _stringpool *p, const char *prefix, int prefix_sz, const char *name, int name_sz, int *sz) {
  if (prefix_sz == 0) {
    if (sz) {
      *sz = name_sz;
    }
    return _pbcS_build(p, name, name_sz);
  }
  char *temp = (char *)alloca(name_sz + prefix_sz + 2);
  memcpy(temp, prefix, prefix_sz);
  temp[prefix_sz] = '.';
  memcpy(temp + prefix_sz + 1, name, name_sz);
  temp[name_sz + prefix_sz + 1] = '\0';
  if (sz) {
    *sz = name_sz + prefix_sz + 1;
  }
  const char *ret = _pbcS_build(p, temp, name_sz + prefix_sz + 1);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_concat_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbx
  movslq %edx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %ebx,%ebx
  jne    L35
  test   %r9,%r9
  je     L14
  mov    %r8d,0x0(%r13)
L14:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <_pbcS_build@plt>
L39:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L35:
  lea    (%rbx,%r8,1),%ecx
  mov    %rsi,-0x48(%rbp)
  lea    0x2(%rcx),%edi
  mov    %ecx,-0x4c(%rbp)
  call   <alloca@plt>
  mov    -0x48(%rbp),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  mov    %rax,-0x48(%rbp)
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r8
  mov    %r12d,%edx
  mov    %r15,%rsi
  movb   $0x2e,(%r8,%rbx,1)
  lea    0x1(%r8,%rbx,1),%rdi
  call   <memcpy@plt>
  movslq -0x4c(%rbp),%rax
  mov    -0x48(%rbp),%r8
  lea    0x1(%rax),%edx
  movb   $0x0,0x1(%r8,%rax,1)
  test   %r13,%r13
  je     L31
  mov    %edx,0x0(%r13)
L31:
  mov    %r8,%rsi
  mov    %r14,%rdi
  call   <_pbcS_build@plt>
  jmp    L39
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *_concat_name(struct _stringpool *p, const char *prefix, int prefix_sz, const char *name, int name_sz, int *sz) {
  if (prefix_sz == 0) {
    if (sz) {
      *sz = name_sz;
    }
    return _pbcS_build(p, name, name_sz);
  }
  char *temp = (char *)alloca(name_sz + prefix_sz + 2);
  memcpy(temp, prefix, prefix_sz);
  temp[prefix_sz] = '.';
  memcpy(temp + prefix_sz + 1, name, name_sz);
  temp[name_sz + prefix_sz + 1] = '\0';
  if (sz) {
    *sz = name_sz + prefix_sz + 1;
  }
  const char *ret = _pbcS_build(p, temp, name_sz + prefix_sz + 1);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_concat_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r9,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbx
  movslq %edx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  test   %ebx,%ebx
  jne    L49
  test   %r9,%r9
  je     L6
  mov    %r8d,0x0(%r13)
L6:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <_pbcS_build@plt>
L16:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L49:
  lea    (%rbx,%r8,1),%ecx
  mov    %rsi,-0x48(%rbp)
  lea    0x2(%rcx),%edi
  mov    %ecx,-0x4c(%rbp)
  call   <alloca@plt>
  mov    -0x48(%rbp),%rsi
  mov    %ebx,%edx
  mov    %rax,%rdi
  mov    %rax,-0x48(%rbp)
  call   <memcpy@plt>
  mov    -0x48(%rbp),%r8
  mov    %r12d,%edx
  mov    %r15,%rsi
  movb   $0x2e,(%r8,%rbx,1)
  lea    0x1(%r8,%rbx,1),%rdi
  call   <memcpy@plt>
  movslq -0x4c(%rbp),%rax
  mov    -0x48(%rbp),%r8
  lea    0x1(%rax),%edx
  movb   $0x0,0x1(%r8,%rax,1)
  test   %r13,%r13
  je     L22
  mov    %edx,0x0(%r13)
L22:
  mov    %r8,%rsi
  mov    %r14,%rdi
  call   <_pbcS_build@plt>
  jmp    L16
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *_concat_name(struct _stringpool *p, const char *prefix, int prefix_sz, const char *name, int name_sz, int *sz) {
  if (prefix_sz == 0) {
    if (sz) {
      *sz = name_sz;
    }
    return _pbcS_build(p, name, name_sz);
  }
  char *temp = (char *)alloca(name_sz + prefix_sz + 2);
  memcpy(temp, prefix, prefix_sz);
  temp[prefix_sz] = '.';
  memcpy(temp + prefix_sz + 1, name, name_sz);
  temp[name_sz + prefix_sz + 1] = '\0';
  if (sz) {
    *sz = name_sz + prefix_sz + 1;
  }
  const char *ret = _pbcS_build(p, temp, name_sz + prefix_sz + 1);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ip_checksum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebp
  mov    $0xffff,%r12d
  mov    %edi,%eax
  and    $0x3,%eax
  jne    L101
L38:
  mov    %r15,%r13
  and    $0xfffffffffffffffc,%r13
  add    %rbx,%r13
  cmp    %r13,%rbx
  je     L16
  lea    0x7(%rsp),%r14
L89:
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  movsbl 0x7(%rsp),%edi
  call   <ntohl@plt>
  add    %eax,%r12d
  add    $0x4,%rbx
  cmp    %rbx,%r13
  jne    L89
L33:
  and    $0x3,%r15d
  jne    L19
L41:
  mov    %r12d,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  add    %r12d,%edx
  mov    %edx,%eax
  sar    $0x10,%edx
  je     L97
L82:
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  jne    L82
L97:
  test   $0x1,%bpl
  je     L22
  movzbl %ah,%edx
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %edx,%eax
L22:
  not    %eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L105
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  mov    $0x4,%r13d
  sub    %eax,%r13d
  cmp    %rsi,%r13
  cmova  %rsi,%r13
  movb   $0x0,0x7(%rsp)
  mov    %eax,%eax
  lea    0x7(%rsp,%rax,1),%rdi
  mov    %r13,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  movsbl 0x7(%rsp),%edi
  call   <ntohl@plt>
  lea    0xffff(%rax),%r12d
  add    %r13,%rbx
  sub    %r13,%r15
  jmp    L38
L16:
  mov    %r13,%rbx
  jmp    L33
L19:
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  mov    %r15,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  movsbl 0x7(%rsp),%edi
  call   <ntohl@plt>
  add    %eax,%r12d
  jmp    L41
L105:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t ip_checksum(void *vdata, size_t length) {
  char *data = (char *)vdata;
  uint64_t acc = 0xffff;
  unsigned int offset = ((uintptr_t)data) & 3;
  if (offset) {
    size_t count = 4 - offset;
    if (count > length)
      count = length;
    uint32_t word = 0;
    memcpy(offset + (char *)&word, data, count);
    acc += ntohl(word);
    data += count;
    length -= count;
  }
  char *data_end = data + (length & ~3);
  while (data != data_end) {
    uint32_t word;
    memcpy(&word, data, 4);
    acc += ntohl(word);
    data += 4;
  }
  length &= 3;
  if (length) {
    uint32_t word = 0;
    memcpy(&word, data, length);
    acc += ntohl(word);
  }
  acc = (acc & 0xffffffff) + (acc >> 32);
  while (acc >> 16) {
    acc = (acc & 0xffff) + (acc >> 16);
  }
  if (offset & 1) {
    acc = ((acc & 0xff00) >> 8) | ((acc & 0x00ff) << 8);
  }
  return htons(~acc);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ip_checksum>:
  endbr64
  push   %r15
  mov    $0xffff,%edx
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xffff,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  and    $0x3,%eax
  jne    L32
L42:
  mov    %r15,%r13
  and    $0xfffffffffffffffc,%r13
  add    %rbp,%r13
  cmp    %r13,%rbp
  je     L97
  lea    0x17(%rsp),%r14
  nopl   0x0(%rax)
L91:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbp
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%ebx
  cmp    %rbp,%r13
  jne    L91
L97:
  and    $0x3,%r15d
  jne    L77
L41:
  mov    $0x20,%ecx
  sar    %cl,%ebx
  lea    (%rbx,%rdx,1),%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  je     L98
  nopl   0x0(%rax,%rax,1)
L6:
  movzwl %di,%edi
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  jne    L6
L98:
  and    $0x1,%r12d
  je     L12
  mov    %edi,%eax
  shl    $0x8,%edi
  sar    $0x8,%eax
  movzwl %di,%edi
  or     %eax,%edi
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x28,%rsp
  not    %edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <htons@plt>
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x4,%r13d
  movb   $0x0,0x17(%rsp)
  sub    %eax,%r13d
  mov    %eax,%eax
  cmp    %rsi,%r13
  lea    0x17(%rsp,%rax,1),%rdi
  cmova  %rsi,%r13
  mov    %rbp,%rsi
  mov    %r13,%rdx
  add    %r13,%rbp
  sub    %r13,%r15
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  lea    0xffff(%rax),%edx
  mov    %edx,%ebx
  jmp    L42
  nopl   0x0(%rax)
L77:
  mov    %edx,0xc(%rsp)
  lea    0x17(%rsp),%rdi
  mov    %r15,%rdx
  mov    %rbp,%rsi
  movb   $0x0,0x17(%rsp)
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  mov    0xc(%rsp),%edx
  add    %eax,%edx
  mov    %edx,%ebx
  jmp    L41
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t ip_checksum(void *vdata, size_t length) {
  char *data = (char *)vdata;
  uint64_t acc = 0xffff;
  unsigned int offset = ((uintptr_t)data) & 3;
  if (offset) {
    size_t count = 4 - offset;
    if (count > length)
      count = length;
    uint32_t word = 0;
    memcpy(offset + (char *)&word, data, count);
    acc += ntohl(word);
    data += count;
    length -= count;
  }
  char *data_end = data + (length & ~3);
  while (data != data_end) {
    uint32_t word;
    memcpy(&word, data, 4);
    acc += ntohl(word);
    data += 4;
  }
  length &= 3;
  if (length) {
    uint32_t word = 0;
    memcpy(&word, data, length);
    acc += ntohl(word);
  }
  acc = (acc & 0xffffffff) + (acc >> 32);
  while (acc >> 16) {
    acc = (acc & 0xffff) + (acc >> 16);
  }
  if (offset & 1) {
    acc = ((acc & 0xff00) >> 8) | ((acc & 0x00ff) << 8);
  }
  return htons(~acc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ip_checksum>:
  endbr64
  push   %r15
  mov    $0xffff,%edx
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xffff,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  and    $0x3,%eax
  jne    L71
L22:
  mov    %r15,%r13
  and    $0xfffffffffffffffc,%r13
  add    %rbp,%r13
  cmp    %r13,%rbp
  je     L96
  lea    0x17(%rsp),%r14
  nopl   0x0(%rax)
L39:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x4,%rbp
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  lea    (%rbx,%rax,1),%edx
  mov    %edx,%ebx
  cmp    %rbp,%r13
  jne    L39
L96:
  and    $0x3,%r15d
  jne    L14
L88:
  mov    $0x20,%ecx
  sar    %cl,%ebx
  lea    (%rbx,%rdx,1),%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  je     L25
  nopl   0x0(%rax,%rax,1)
L7:
  movzwl %di,%edi
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0x10,%eax
  jne    L7
L25:
  and    $0x1,%r12d
  je     L84
  mov    %edi,%eax
  shl    $0x8,%edi
  sar    $0x8,%eax
  movzwl %di,%edi
  or     %eax,%edi
L84:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x28,%rsp
  not    %edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <htons@plt>
  nopl   0x0(%rax,%rax,1)
L71:
  mov    $0x4,%r13d
  movb   $0x0,0x17(%rsp)
  sub    %eax,%r13d
  mov    %eax,%eax
  cmp    %rsi,%r13
  lea    0x17(%rsp,%rax,1),%rdi
  cmova  %rsi,%r13
  mov    %rbp,%rsi
  mov    %r13,%rdx
  add    %r13,%rbp
  sub    %r13,%r15
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  lea    0xffff(%rax),%edx
  mov    %edx,%ebx
  jmp    L22
  nopl   0x0(%rax)
L14:
  mov    %edx,0xc(%rsp)
  lea    0x17(%rsp),%rdi
  mov    %r15,%rdx
  mov    %rbp,%rsi
  movb   $0x0,0x17(%rsp)
  call   <memcpy@plt>
  movsbl 0x17(%rsp),%edi
  call   <ntohl@plt>
  mov    0xc(%rsp),%edx
  add    %eax,%edx
  mov    %edx,%ebx
  jmp    L88
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t ip_checksum(void *vdata, size_t length) {
  char *data = (char *)vdata;
  uint64_t acc = 0xffff;
  unsigned int offset = ((uintptr_t)data) & 3;
  if (offset) {
    size_t count = 4 - offset;
    if (count > length)
      count = length;
    uint32_t word = 0;
    memcpy(offset + (char *)&word, data, count);
    acc += ntohl(word);
    data += count;
    length -= count;
  }
  char *data_end = data + (length & ~3);
  while (data != data_end) {
    uint32_t word;
    memcpy(&word, data, 4);
    acc += ntohl(word);
    data += 4;
  }
  length &= 3;
  if (length) {
    uint32_t word = 0;
    memcpy(&word, data, length);
    acc += ntohl(word);
  }
  acc = (acc & 0xffffffff) + (acc >> 32);
  while (acc >> 16) {
    acc = (acc & 0xffff) + (acc >> 16);
  }
  if (offset & 1) {
    acc = ((acc & 0xff00) >> 8) | ((acc & 0x00ff) << 8);
  }
  return htons(~acc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  js     L1
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  jns    L1
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  mov    %rax,%r8
  mov    %rdx,%rcx
  not    %rdi
  test   %rdx,%rdi
  js     L7
L15:
  mov    %r8,%rax
  mov    %rcx,%rdx
  ret
L7:
  lea    0x1(%rax),%r8
  sub    %rsi,%rcx
  jmp    L15
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  not    %rdi
  cqto
  idiv   %rsi
  test   %rdx,%rdi
  js     L6
  ret
  nopl   (%rax)
L6:
  add    $0x1,%rax
  sub    %rsi,%rdx
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  not    %rdi
  cqto
  idiv   %rsi
  test   %rdx,%rdi
  js     L7
  ret
  nopl   (%rax)
L7:
  add    $0x1,%rax
  sub    %rsi,%rdx
  ret
```

assistant: ```c
ldiv_t ldiv(long int numer, long int denom) {
  ldiv_t result;
  result.quot = numer / denom;
  result.rem = numer % denom;
  if (numer >= 0 && result.rem < 0) {
    ++result.quot;
    result.rem -= denom;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __attribute__((warn_unused_result)) addstr(char **dst, const char *str) {
  int len = strlen(str);
  if (dst != NULL) {
    memcpy(*dst, str, len);
    *dst += len;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<addstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  test   %rbx,%rbx
  je     L6
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <memcpy@plt>
  movslq %ebp,%rax
  add    %rax,(%rbx)
L6:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((warn_unused_result)) addstr(char **dst, const char *str) {
  int len = strlen(str);
  if (dst != NULL) {
    memcpy(*dst, str, len);
    *dst += len;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<addstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %rbx,%rbx
  je     L5
  mov    (%rbx),%rdi
  mov    %eax,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movslq %r12d,%rax
  add    %rax,(%rbx)
L5:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((warn_unused_result)) addstr(char **dst, const char *str) {
  int len = strlen(str);
  if (dst != NULL) {
    memcpy(*dst, str, len);
    *dst += len;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<addstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %rbx,%rbx
  je     L7
  mov    (%rbx),%rdi
  mov    %eax,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movslq %r12d,%rax
  add    %rax,(%rbx)
L7:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((warn_unused_result)) addstr(char **dst, const char *str) {
  int len = strlen(str);
  if (dst != NULL) {
    memcpy(*dst, str, len);
    *dst += len;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<borked_pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Connection with network has broken.

assistant: ```c
void borked_pipe(int signo) {
  printf("Connection with network has broken.");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<borked_pipe>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: Connection with network has broken.

assistant: ```c
void borked_pipe(int signo) {
  printf("Connection with network has broken.");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<borked_pipe>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: Connection with network has broken.

assistant: ```c
void borked_pipe(int signo) {
  printf("Connection with network has broken.");
  exit(0);
}
```