ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<hff2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L12
L20:
  mov    -0x94(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x94(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x94(%rbp),%eax
  cltq
  movsd  %xmm0,-0x40(%rbp,%rax,8)
  addl   $0x1,-0x94(%rbp)
L12:
  cmpl   $0x2,-0x94(%rbp)
  jle    L20
  movl   $0x0,-0x90(%rbp)
  jmp    L32
L48:
  mov    -0x90(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x90(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x90(%rbp),%eax
  cltq
  movsd  %xmm0,-0x20(%rbp,%rax,8)
  addl   $0x1,-0x90(%rbp)
L32:
  cmpl   $0x2,-0x90(%rbp)
  jle    L48
  lea    -0x80(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crossProduct@plt>
  lea    -0x60(%rbp),%rdx
  lea    -0x80(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crossProduct@plt>
  movl   $0x0,-0x8c(%rbp)
  jmp    L47
L78:
  mov    -0x8c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8c(%rbp),%eax
  cltq
  movsd  -0x60(%rbp,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x88(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  addl   $0x1,-0x8c(%rbp)
L47:
  cmpl   $0x2,-0x8c(%rbp)
  jle    L78
  pxor   %xmm0,%xmm0
  comisd -0x88(%rbp),%xmm0
  jbe    L80
  mov    $0x1,%eax
  jmp    L34
L80:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

assistant: ```c
int hff2(const double *p, const double *q, const double *r) {
  double ntmp[3];
  double n[3], pq[3], pr[3];
  double tmp = 0;
  for (int i = 0; i < 3; i++)
    pq[i] = q[i] - p[i];
  for (int i = 0; i < 3; i++)
    pr[i] = r[i] - p[i];
  crossProduct(pq, pr, ntmp);
  crossProduct(pq, ntmp, n);
#pragma omp simd reduction(+ : tmp)
  for (int i = 0; i < 3; i++)
    tmp = tmp + (p[i] * n[i]);
  if (tmp < 0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hff2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
L21:
  movsd  (%rsi,%rax,1),%xmm0
  subsd  (%rbx,%rax,1),%xmm0
  movsd  %xmm0,0x40(%rsp,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L21
  mov    $0x0,%eax
L26:
  movsd  (%rdx,%rax,1),%xmm0
  subsd  (%rbx,%rax,1),%xmm0
  movsd  %xmm0,0x60(%rsp,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L26
  mov    %rsp,%r12
  lea    0x60(%rsp),%rsi
  lea    0x40(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <crossProduct@plt>
  lea    0x20(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crossProduct@plt>
  movsd  (%rbx),%xmm0
  mulsd  0x20(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x8(%rbx),%xmm1
  mulsd  0x28(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x10(%rbx),%xmm0
  mulsd  0x30(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  seta   %al
  movzbl %al,%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int hff2(const double *p, const double *q, const double *r) {
  double ntmp[3];
  double n[3], pq[3], pr[3];
  double tmp = 0;
  for (int i = 0; i < 3; i++)
    pq[i] = q[i] - p[i];
  for (int i = 0; i < 3; i++)
    pr[i] = r[i] - p[i];
  crossProduct(pq, pr, ntmp);
  crossProduct(pq, ntmp, n);
#pragma omp simd reduction(+ : tmp)
  for (int i = 0; i < 3; i++)
    tmp = tmp + (p[i] * n[i]);
  if (tmp < 0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hff2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbp
L15:
  movsd  (%rsi,%rax,1),%xmm0
  subsd  (%rbx,%rax,1),%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L15
  xor    %eax,%eax
  lea    0x60(%rsp),%rsi
L16:
  movsd  (%rdx,%rax,1),%xmm0
  subsd  (%rbx,%rax,1),%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L16
  mov    %rsp,%r12
  mov    %rbp,%rdi
  mov    %r12,%rdx
  call   <crossProduct@plt>
  lea    0x20(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crossProduct@plt>
  movsd  0x20(%rsp),%xmm0
  mulsd  (%rbx),%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x28(%rsp),%xmm1
  mulsd  0x8(%rbx),%xmm1
  xor    %eax,%eax
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rbx),%xmm0
  mulsd  0x30(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  seta   %al
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int hff2(const double *p, const double *q, const double *r) {
  double ntmp[3];
  double n[3], pq[3], pr[3];
  double tmp = 0;
  for (int i = 0; i < 3; i++)
    pq[i] = q[i] - p[i];
  for (int i = 0; i < 3; i++)
    pr[i] = r[i] - p[i];
  crossProduct(pq, pr, ntmp);
  crossProduct(pq, ntmp, n);
#pragma omp simd reduction(+ : tmp)
  for (int i = 0; i < 3; i++)
    tmp = tmp + (p[i] * n[i]);
  if (tmp < 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hff2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  add    $0xffffffffffffff80,%rsp
  movupd (%rdi),%xmm3
  movupd (%rsi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movsd  0x10(%rdi),%xmm1
  mov    %rsp,%r12
  lea    0x40(%rsp),%rbp
  subpd  %xmm3,%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,0x40(%rsp)
  movsd  0x10(%rsi),%xmm0
  lea    0x60(%rsp),%rsi
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x50(%rsp)
  movupd (%rdx),%xmm0
  subpd  %xmm3,%xmm0
  movaps %xmm0,0x60(%rsp)
  movsd  0x10(%rdx),%xmm0
  mov    %r12,%rdx
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x70(%rsp)
  call   <crossProduct@plt>
  lea    0x20(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crossProduct@plt>
  movupd (%rbx),%xmm0
  mulpd  0x20(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x30(%rsp),%xmm0
  mulsd  0x10(%rbx),%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  seta   %al
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  sub    $0xffffffffffffff80,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int hff2(const double *p, const double *q, const double *r) {
  double ntmp[3];
  double n[3], pq[3], pr[3];
  double tmp = 0;
  for (int i = 0; i < 3; i++)
    pq[i] = q[i] - p[i];
  for (int i = 0; i < 3; i++)
    pr[i] = r[i] - p[i];
  crossProduct(pq, pr, ntmp);
  crossProduct(pq, ntmp, n);
#pragma omp simd reduction(+ : tmp)
  for (int i = 0; i < 3; i++)
    tmp = tmp + (p[i] * n[i]);
  if (tmp < 0)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L0
  mov    $0x0,%eax
  jmp    L28
L0:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L46
L7:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L38
  mov    $0x0,%eax
  jmp    L28
L38:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L7
  mov    $0x1,%eax
L28:
  leave
  ret
```

assistant: ```c
int is_prime(int number) {
  if (number < 2)
    return 0;
  int root = sqrt(number);
  for (int i = 2; i <= root; i++) {
    if (number % i == 0)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L60
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L66
  test   $0x1,%bl
  je     L20
  mov    $0x2,%ecx
L65:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L53
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L65
  jmp    L36
L53:
  mov    $0x1,%eax
L36:
  pop    %rbx
  ret
L66:
  mov    $0x1,%eax
  jmp    L36
L20:
  mov    $0x0,%eax
  jmp    L36
L60:
  ret
```

assistant: ```c
int is_prime(int number) {
  if (number < 2)
    return 0;
  int root = sqrt(number);
  for (int i = 2; i <= root; i++) {
    if (number % i == 0)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L22
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L2
  test   $0x1,%r12b
  je     L41
  mov    $0x2,%ecx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L41
L0:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L3
L2:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_prime(int number) {
  if (number < 2)
    return 0;
  int root = sqrt(number);
  for (int i = 2; i <= root; i++) {
    if (number % i == 0)
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L43
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L3
  test   $0x1,%r12b
  je     L28
  mov    $0x2,%ecx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L28
L26:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L5
L3:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  pop    %r12
  ret
  nopl   (%rax)
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_prime(int number) {
  if (number < 2)
    return 0;
  int root = sqrt(number);
  for (int i = 2; i <= root; i++) {
    if (number % i == 0)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_mem2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L17:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_mem2(void **mem, int xmax) {
  unsigned int x;
  for (x = 0; x < xmax; x++)
    free(mem[x]);
  free(mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<free_mem2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  je     L8
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L5:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L5
L8:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_mem2(void **mem, int xmax) {
  unsigned int x;
  for (x = 0; x < xmax; x++)
    free(mem[x]);
  free(mem);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_mem2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L2
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L14
L2:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_mem2(void **mem, int xmax) {
  unsigned int x;
  for (x = 0; x < xmax; x++)
    free(mem[x]);
  free(mem);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_mem2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L8
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_mem2(void **mem, int xmax) {
  unsigned int x;
  for (x = 0; x < xmax; x++)
    free(mem[x]);
  free(mem);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<airEndsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L51
  cmpq   $0x0,-0x20(%rbp)
  jne    L65
L51:
  mov    $0x0,%eax
  jmp    L20
L65:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jge    L23
  mov    $0x0,%eax
  jmp    L20
L23:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%r12
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %r12,%rdx
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    %ebx,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L37
  mov    $0x1,%eax
  jmp    L20
L37:
  mov    $0x0,%eax
L20:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int airEndsWith(const char *s, const char *suff) {
  if (!(s && suff))
    return 0;
  if (!(strlen(s) >= strlen(suff)))
    return 0;
  if (!strncmp(s + strlen(s) - strlen(suff), suff, strlen(suff)))
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<airEndsWith>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L25
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%r12d
  jge    L12
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %r12d,%r12
  cltq
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L25
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int airEndsWith(const char *s, const char *suff) {
  if (!(s && suff))
    return 0;
  if (!(strlen(s) >= strlen(suff)))
    return 0;
  if (!strncmp(s + strlen(s) - strlen(suff), suff, strlen(suff)))
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<airEndsWith>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L27
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L27
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  cltq
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int airEndsWith(const char *s, const char *suff) {
  if (!(s && suff))
    return 0;
  if (!(strlen(s) >= strlen(suff)))
    return 0;
  if (!strncmp(s + strlen(s) - strlen(suff), suff, strlen(suff)))
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<airEndsWith>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L11
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  jl     L11
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  cltq
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int airEndsWith(const char *s, const char *suff) {
  if (!(s && suff))
    return 0;
  if (!(strlen(s) >= strlen(suff)))
    return 0;
  if (!strncmp(s + strlen(s) - strlen(suff), suff, strlen(suff)))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swptst_>:
  endbr64
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rdx,%rdi
  mov    0x8(%rsp),%rax
  sub    $0x8,%rax
  sub    $0x8,%r9
  sub    $0x8,%r8
  movslq (%rcx),%rdx
  movsd  (%r8,%rdx,8),%xmm5
  movsd  (%r9,%rdx,8),%xmm9
  movsd  (%rax,%rdx,8),%xmm8
  movslq (%r11),%rsi
  movsd  (%r8,%rsi,8),%xmm3
  subsd  %xmm5,%xmm3
  movslq (%r10),%rcx
  movsd  (%r8,%rcx,8),%xmm1
  subsd  %xmm5,%xmm1
  movslq (%rdi),%rdx
  movsd  (%r9,%rsi,8),%xmm7
  subsd  %xmm9,%xmm7
  movsd  (%r9,%rcx,8),%xmm6
  subsd  %xmm9,%xmm6
  movsd  (%rax,%rsi,8),%xmm2
  subsd  %xmm8,%xmm2
  movsd  (%rax,%rcx,8),%xmm4
  subsd  %xmm8,%xmm4
  movsd  (%r8,%rdx,8),%xmm0
  subsd  %xmm5,%xmm0
  movapd %xmm6,%xmm5
  mulsd  %xmm2,%xmm5
  movapd %xmm7,%xmm10
  mulsd  %xmm4,%xmm10
  subsd  %xmm10,%xmm5
  mulsd  %xmm5,%xmm0
  movsd  (%r9,%rdx,8),%xmm5
  subsd  %xmm9,%xmm5
  mulsd  %xmm1,%xmm2
  mulsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm2
  mulsd  %xmm5,%xmm2
  subsd  %xmm2,%xmm0
  movsd  (%rax,%rdx,8),%xmm2
  subsd  %xmm8,%xmm2
  mulsd  %xmm7,%xmm1
  mulsd  %xmm6,%xmm3
  subsd  %xmm3,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  comisd D3(%rip),%xmm0
  seta   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: f64

tool: D3: 0

assistant: ```c
int swptst_(int *n1, int *n2, int *n3, int *n4, double *x, double *y, double *z__) {
  int ret_val;
  static double x4, y4, z4, dx1, dx2, dx3, dy1, dy2, dy3, dz1, dz2, dz3;
  --z__;
  --y;
  --x;
  x4 = x[*n4];
  y4 = y[*n4];
  z4 = z__[*n4];
  dx1 = x[*n1] - x4;
  dx2 = x[*n2] - x4;
  dx3 = x[*n3] - x4;
  dy1 = y[*n1] - y4;
  dy2 = y[*n2] - y4;
  dy3 = y[*n3] - y4;
  dz1 = z__[*n1] - z4;
  dz2 = z__[*n2] - z4;
  dz3 = z__[*n3] - z4;
  ret_val = dx3 * (dy2 * dz1 - dy1 * dz2) - dy3 * (dx2 * dz1 - dx1 * dz2) + dz3 * (dx2 * dy1 - dx1 * dy2) > 0.;
  return ret_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swptst_>:
  endbr64
  mov    %rsi,%r11
  mov    %rdx,%r10
  movslq (%rdi),%rsi
  movslq (%rcx),%rdx
  mov    0x8(%rsp),%rax
  movslq (%r11),%rcx
  sub    $0x8,%r9
  sub    $0x8,%r8
  movsd  (%r9,%rdx,8),%xmm9
  movsd  (%r9,%rsi,8),%xmm6
  sub    $0x8,%rax
  movsd  (%r9,%rcx,8),%xmm5
  movsd  (%r8,%rdx,8),%xmm8
  movsd  (%rax,%rdx,8),%xmm7
  movsd  (%rax,%rsi,8),%xmm2
  subsd  %xmm9,%xmm6
  movslq (%r10),%rdx
  movsd  (%rax,%rcx,8),%xmm4
  subsd  %xmm9,%xmm5
  subsd  %xmm7,%xmm2
  movsd  (%r8,%rsi,8),%xmm3
  movsd  (%r8,%rcx,8),%xmm1
  subsd  %xmm7,%xmm4
  movsd  (%r8,%rdx,8),%xmm0
  movapd %xmm6,%xmm10
  subsd  %xmm8,%xmm3
  subsd  %xmm8,%xmm1
  subsd  %xmm8,%xmm0
  movapd %xmm5,%xmm8
  mulsd  %xmm4,%xmm10
  mulsd  %xmm2,%xmm8
  mulsd  %xmm3,%xmm4
  mulsd  %xmm1,%xmm2
  mulsd  %xmm5,%xmm3
  mulsd  %xmm6,%xmm1
  subsd  %xmm10,%xmm8
  subsd  %xmm4,%xmm2
  mulsd  %xmm8,%xmm0
  movsd  (%r9,%rdx,8),%xmm8
  subsd  %xmm3,%xmm1
  subsd  %xmm9,%xmm8
  mulsd  %xmm8,%xmm2
  subsd  %xmm2,%xmm0
  movsd  (%rax,%rdx,8),%xmm2
  xor    %eax,%eax
  subsd  %xmm7,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  comisd D0(%rip),%xmm0
  seta   %al
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: f64

tool: D0: 0

assistant: ```c
int swptst_(int *n1, int *n2, int *n3, int *n4, double *x, double *y, double *z__) {
  int ret_val;
  static double x4, y4, z4, dx1, dx2, dx3, dy1, dy2, dy3, dz1, dz2, dz3;
  --z__;
  --y;
  --x;
  x4 = x[*n4];
  y4 = y[*n4];
  z4 = z__[*n4];
  dx1 = x[*n1] - x4;
  dx2 = x[*n2] - x4;
  dx3 = x[*n3] - x4;
  dy1 = y[*n1] - y4;
  dy2 = y[*n2] - y4;
  dy3 = y[*n3] - y4;
  dz1 = z__[*n1] - z4;
  dz2 = z__[*n2] - z4;
  dz3 = z__[*n3] - z4;
  ret_val = dx3 * (dy2 * dz1 - dy1 * dz2) - dy3 * (dx2 * dz1 - dx1 * dz2) + dz3 * (dx2 * dy1 - dx1 * dy2) > 0.;
  return ret_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swptst_>:
  endbr64
  mov    %rsi,%r11
  mov    %rdx,%r10
  movslq (%rdi),%rsi
  movslq (%rcx),%rdx
  mov    0x8(%rsp),%rax
  movslq (%r11),%rcx
  sub    $0x8,%r9
  sub    $0x8,%r8
  movsd  (%r9,%rdx,8),%xmm9
  movsd  (%r9,%rsi,8),%xmm6
  sub    $0x8,%rax
  movsd  (%r9,%rcx,8),%xmm5
  movsd  (%r8,%rdx,8),%xmm8
  movsd  (%rax,%rdx,8),%xmm7
  movsd  (%rax,%rsi,8),%xmm2
  subsd  %xmm9,%xmm6
  movslq (%r10),%rdx
  movsd  (%rax,%rcx,8),%xmm4
  subsd  %xmm9,%xmm5
  subsd  %xmm7,%xmm2
  movsd  (%r8,%rsi,8),%xmm3
  movsd  (%r8,%rcx,8),%xmm1
  subsd  %xmm7,%xmm4
  movsd  (%r8,%rdx,8),%xmm0
  movapd %xmm6,%xmm10
  subsd  %xmm8,%xmm3
  subsd  %xmm8,%xmm1
  subsd  %xmm8,%xmm0
  movapd %xmm5,%xmm8
  mulsd  %xmm4,%xmm10
  mulsd  %xmm2,%xmm8
  mulsd  %xmm3,%xmm4
  mulsd  %xmm1,%xmm2
  mulsd  %xmm5,%xmm3
  mulsd  %xmm6,%xmm1
  subsd  %xmm10,%xmm8
  subsd  %xmm4,%xmm2
  mulsd  %xmm8,%xmm0
  movsd  (%r9,%rdx,8),%xmm8
  subsd  %xmm3,%xmm1
  subsd  %xmm9,%xmm8
  mulsd  %xmm8,%xmm2
  subsd  %xmm2,%xmm0
  movsd  (%rax,%rdx,8),%xmm2
  xor    %eax,%eax
  subsd  %xmm7,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  comisd D2(%rip),%xmm0
  seta   %al
  ret
```

tool_calls: name: read_data
arguments: tag: D2
datatype: f64

tool: D2: 0

assistant: ```c
int swptst_(int *n1, int *n2, int *n3, int *n4, double *x, double *y, double *z__) {
  int ret_val;
  static double x4, y4, z4, dx1, dx2, dx3, dy1, dy2, dy3, dz1, dz2, dz3;
  --z__;
  --y;
  --x;
  x4 = x[*n4];
  y4 = y[*n4];
  z4 = z__[*n4];
  dx1 = x[*n1] - x4;
  dx2 = x[*n2] - x4;
  dx3 = x[*n3] - x4;
  dy1 = y[*n1] - y4;
  dy2 = y[*n2] - y4;
  dy3 = y[*n3] - y4;
  dz1 = z__[*n1] - z4;
  dz2 = z__[*n2] - z4;
  dz3 = z__[*n3] - z4;
  ret_val = dx3 * (dy2 * dz1 - dy1 * dz2) - dy3 * (dx2 * dz1 - dx1 * dz2) + dz3 * (dx2 * dy1 - dx1 * dy2) > 0.;
  return ret_val;
}
```