user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x27000(%rsp),%r11
L117:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L117
  sub    $0x138,%rsp
  lea    D7(%rip),%r13
  lea    D66(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x27128(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
L167:
  lea    0x1(%rax),%ebp
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  lea    0x4(%rbx),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L65
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  call   <kontrolaCasu@plt>
  test   %rax,%rax
  je     L65
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  call   <naMinuty@plt>
  test   %eax,%eax
  je     L65
  add    $0x8,%rbx
  mov    $0x1,%eax
  cmp    $0x2,%ebp
  jne    L167
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <naMinuty@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  mov    %eax,%ebp
  call   <naMinuty@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L157
L65:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L52:
  mov    0x27128(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L182
  add    $0x27138,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L157:
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <kontrolaCasu@plt>
  test   %rax,%rax
  je     L65
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <naMinuty@plt>
  cmp    %ebx,%eax
  jg     L65
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <naMinuty@plt>
  cmp    %ebx,%eax
  je     L65
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <naMinuty@plt>
  mov    %ebx,%edi
  mov    $0x270f,%esi
  sub    %eax,%edi
  movslq %edi,%rax
  mov    %rax,0x138a0(%rsp)
  mov    $0x1,%eax
  nopl   0x0(%rax)
L99:
  mov    %ebp,%ecx
  lea    -0x1(%rax),%edx
  imul   %eax,%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    %rcx,0x20(%rsp,%rdx,8)
  mov    %ebx,%edx
  movslq %eax,%rcx
  imul   %eax,%edx
  add    $0x1,%eax
  add    %edi,%edx
  movslq %edx,%rdx
  mov    %rdx,0x138a0(%rsp,%rcx,8)
  sub    $0x1,%esi
  jne    L99
  lea    0x138a0(%rsp),%r8
  xor    %r9d,%r9d
  lea    0x20(%rsp),%r10
  mov    %r8,%rsi
L32:
  mov    (%r8,%r9,8),%rdi
  mov    %r10,%rdx
  mov    %rsi,%r8
  jmp    L64
  nop
L42:
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  je     L105
L64:
  mov    (%rdx),%rax
  lea    0x1(%rax),%rcx
  cmp    %rcx,%rdi
  jne    L42
  test   %rax,%rax
  jne    L55
  lea    D19(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L52
L55:
  mov    $0x3c,%ecx
  cqto
  lea    D3(%rip),%rdi
  idiv   %rcx
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L52
L105:
  add    $0x1,%r9
  cmp    $0x2710,%r9
  jne    L32
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L52
L182:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D66
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D7: Interval spoje #%d:


tool: D66: %d:%d

tool: D18: Cas od odjezdu spoje #2:

tool: D13: Nespravny vstup.

tool: D19: Spoj #2 bude odjizdet 1 minutu po prijezdu spoje #1 prave nyni.

tool: D3: Spoj #2 bude odjizdet 1 minutu po prijezdu spoje #1 za %ld:%02ld.


tool: D0: Spoj #2 nikdy nebude odjizdet 1 minutu po prijezdu spoje #1.

assistant: ```c
int main() {
  int spoje[3][2];
  int c, d = 0, ival1, ival2, odjezd, bejk = 0, p = 10000;
  long s1[10000], s2[10000], t = 0;
  for (c = 0; c < 2; c++) {
    printf("Interval spoje #%d:\n", c + 1);
    if (scanf("%d:%d", &spoje[c][0], &spoje[c][1]) != 2 || kontrolaCasu(spoje[c][0], spoje[c][1]) == 0 || naMinuty(spoje[c][0], spoje[c][1]) == 0) {
      printf("Nespravny vstup.\n");
      return 1;
    }
  }
  ival1 = naMinuty(spoje[0][0], spoje[0][1]);
  ival2 = naMinuty(spoje[1][0], spoje[1][1]);
  printf("Cas od odjezdu spoje #2:\n");
  if (scanf("%d:%d", &spoje[2][0], &spoje[2][1]) != 2 || kontrolaCasu(spoje[2][0], spoje[2][1]) == 0 || (naMinuty(spoje[2][0], spoje[2][1]) > ival2) || (naMinuty(spoje[2][0], spoje[2][1]) == ival2)) {
    printf("Nespravny vstup.\n");
    return 1;
  }
  s2[0] = odjezd = ival2 - naMinuty(spoje[2][0], spoje[2][1]);
  for (c = 1; c < p; c++) {
    s1[c - 1] = c * ival1;
    s2[c] = odjezd + (c * ival2);
  }
  for (c = 0; c < p; c++) {
    for (d = 0; d < p; d++) {
      if (s2[c] == s1[d] + 1) {
        bejk = 1;
        t = s1[d];
        break;
      }
    }
    if (bejk == 1)
      break;
  }
  if (bejk == 1) {
    if (t == 0)
      printf("Spoj #2 bude odjizdet 1 minutu po prijezdu spoje #1 prave nyni.\n");
    else
      printf("Spoj #2 bude odjizdet 1 minutu po prijezdu spoje #1 za %ld:%02ld.\n", t / 60, t % 60);
  } else
    printf("Spoj #2 nikdy nebude odjizdet 1 minutu po prijezdu spoje #1.\n");
  return 0;
}
```