ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int rc = vscanf(fmt, ap);
  va_end(ap);
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scanf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int rc = vscanf(fmt, ap);
  va_end(ap);
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int rc = vscanf(fmt, ap);
  va_end(ap);
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <vscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int scanf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int rc = vscanf(fmt, ap);
  va_end(ap);
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Disperse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x75,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L10:
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x1ff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    -0x2c(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L10
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Disperse(char *palavra, int m) {
  unsigned int i, p = 117;
  unsigned int h = 0, pp = 0;
  int n = strlen(palavra);
  for (i = 0; i < (unsigned int)n; i++) {
    pp = ((unsigned int)palavra[i]) % 512;
    h = (pp * p + h) % m;
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Disperse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  je     L4
  mov    %rbp,%rcx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rsi
  mov    $0x0,%edx
L12:
  movsbl (%rcx),%eax
  and    $0x1ff,%eax
  imul   $0x75,%eax,%eax
  add    %edx,%eax
  mov    $0x0,%edx
  div    %ebx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L12
L4:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Disperse(char *palavra, int m) {
  unsigned int i, p = 117;
  unsigned int h = 0, pp = 0;
  int n = strlen(palavra);
  for (i = 0; i < (unsigned int)n; i++) {
    pp = ((unsigned int)palavra[i]) % 512;
    h = (pp * p + h) % m;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Disperse>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L14
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   (%rax)
L12:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  and    $0x1ff,%eax
  imul   $0x75,%eax,%eax
  add    %edx,%eax
  xor    %edx,%edx
  div    %ebp
  cmp    %rdi,%rcx
  jne    L12
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Disperse(char *palavra, int m) {
  unsigned int i, p = 117;
  unsigned int h = 0, pp = 0;
  int n = strlen(palavra);
  for (i = 0; i < (unsigned int)n; i++) {
    pp = ((unsigned int)palavra[i]) % 512;
    h = (pp * p + h) % m;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Disperse>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L19
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %edx,%edx
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   (%rax)
L10:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  and    $0x1ff,%eax
  imul   $0x75,%eax,%eax
  add    %edx,%eax
  xor    %edx,%edx
  div    %ebp
  cmp    %rdi,%rcx
  jne    L10
  add    $0x8,%rsp
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Disperse(char *palavra, int m) {
  unsigned int i, p = 117;
  unsigned int h = 0, pp = 0;
  int n = strlen(palavra);
  for (i = 0; i < (unsigned int)n; i++) {
    pp = ((unsigned int)palavra[i]) % 512;
    h = (pp * p + h) % m;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<big_bad_setup_fixture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <print_message@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <print_message@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D11
type_infered: string

tool: D17: big hashset (bad hash)


tool: D11: ----------------------


assistant: ```c
void big_bad_setup_fixture() {
  print_message("big hashset (bad hash)\n");
  print_message("----------------------\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<big_bad_setup_fixture>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <print_message@plt>
  lea    D18(%rip),%rdi
  call   <print_message@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D18
datatype: string

tool: D9: big hashset (bad hash)


tool: D18: ----------------------


assistant: ```c
void big_bad_setup_fixture() {
  print_message("big hashset (bad hash)\n");
  print_message("----------------------\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<big_bad_setup_fixture>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <print_message@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <print_message@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D16: big hashset (bad hash)


tool: D7: ----------------------


assistant: ```c
void big_bad_setup_fixture() {
  print_message("big hashset (bad hash)\n");
  print_message("----------------------\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<big_bad_setup_fixture>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <print_message@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <print_message@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D7: big hashset (bad hash)


tool: D17: ----------------------


assistant: ```c
void big_bad_setup_fixture() {
  print_message("big hashset (bad hash)\n");
  print_message("----------------------\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<deye2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L34
L6:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L28:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L28
  addq   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
double **deye2(double **m, const size_t n) {
  size_t i, j;
  for (i = 0; i < n; i++) {
    m[i][i] = 1.;
    for (j = i + 1; j < n; j++) {
      m[i][j] = m[j][i] = 0.;
    }
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<deye2>:
  endbr64
  test   %rsi,%rsi
  je     L8
  mov    %rdi,%r11
  lea    0x0(,%rsi,8),%r9
  mov    $0x0,%r10d
  movsd  D0(%rip),%xmm0
L0:
  lea    0x0(,%r10,8),%rcx
  mov    %r11,%r8
  mov    (%r11),%rax
  movsd  %xmm0,(%rax,%r10,8)
  add    $0x1,%r10
  cmp    %r10,%rsi
  je     L8
  lea    0x8(%rcx),%rax
L2:
  mov    (%rdi,%rax,1),%rdx
  movq   $0x0,(%rdx,%rcx,1)
  mov    (%r8),%rdx
  movq   $0x0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%r9
  jne    L2
  add    $0x8,%r11
  jmp    L0
L8:
  mov    %rdi,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: f64

tool: D0: 1

assistant: ```c
double **deye2(double **m, const size_t n) {
  size_t i, j;
  for (i = 0; i < n; i++) {
    m[i][i] = 1.;
    for (j = i + 1; j < n; j++) {
      m[i][j] = m[j][i] = 0.;
    }
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<deye2>:
  endbr64
  mov    %rdi,%r8
  test   %rsi,%rsi
  je     L16
  movsd  D2(%rip),%xmm0
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%r8,%r9,8),%rcx
  lea    0x0(,%r9,8),%rdi
  movsd  %xmm0,(%rcx,%r9,8)
  add    $0x1,%r9
  cmp    %r9,%rsi
  je     L16
  mov    %r9,%rax
  xchg   %ax,%ax
L35:
  mov    (%r8,%rax,8),%rdx
  movq   $0x0,(%rdx,%rdi,1)
  movq   $0x0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L35
  jmp    L5
  nop
L16:
  mov    %r8,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
double **deye2(double **m, const size_t n) {
  size_t i, j;
  for (i = 0; i < n; i++) {
    m[i][i] = 1.;
    for (j = i + 1; j < n; j++) {
      m[i][j] = m[j][i] = 0.;
    }
  }
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<deye2>:
  endbr64
  mov    %rdi,%r9
  test   %rsi,%rsi
  je     L35
  mov    (%rdi),%r8
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,(%r8)
  cmp    $0x1,%rsi
  je     L35
  lea    -0x8(,%rsi,8),%r10
  mov    $0x1,%edi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L7:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%r9,%rax,8),%rdx
  movq   $0x0,(%rdx,%rcx,1)
  movq   $0x0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  ja     L0
  add    $0x8,%rcx
  add    $0x1,%rdi
  mov    (%r9,%rcx,1),%r8
  movsd  %xmm0,(%r8,%rcx,1)
  cmp    %rcx,%r10
  jne    L7
L35:
  mov    %r9,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: f64

tool: D3: 1

assistant: ```c
double **deye2(double **m, const size_t n) {
  size_t i, j;
  for (i = 0; i < n; i++) {
    m[i][i] = 1.;
    for (j = i + 1; j < n; j++) {
      m[i][j] = m[j][i] = 0.;
    }
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L8
L15:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
void *calloc(size_t nelem, size_t elsize) {
  void *tmp;
  int size = nelem * elsize;
  tmp = malloc(size);
  if (!tmp)
    return NULL;
  memset((char *)tmp, 0, size);
  return tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  imul   %esi,%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t nelem, size_t elsize) {
  void *tmp;
  int size = nelem * elsize;
  tmp = malloc(size);
  if (!tmp)
    return NULL;
  memset((char *)tmp, 0, size);
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  imul   %esi,%r13d
  sub    $0x8,%rsp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nelem, size_t elsize) {
  void *tmp;
  int size = nelem * elsize;
  tmp = malloc(size);
  if (!tmp)
    return NULL;
  memset((char *)tmp, 0, size);
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  imul   %esi,%r13d
  sub    $0x8,%rsp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nelem, size_t elsize) {
  void *tmp;
  int size = nelem * elsize;
  tmp = malloc(size);
  if (!tmp)
    return NULL;
  memset((char *)tmp, 0, size);
  return tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jne    L4
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp)
  jmp    L4
L30:
  mov    -0x38(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%ecx
  movslq %edx,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
L4:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jg     L30
  movl   $0x0,-0x34(%rbp)
  jmp    L58
L46:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L47
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  addl   $0x1,-0x34(%rbp)
L58:
  cmpl   $0x9,-0x34(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string

tool: D5: Enter a number:

tool: D17: %d

tool: D29: 
Digit %d = %d times

assistant: ```c
int main() {
  int n, i;
  int d[10] = {0};
  printf("Enter a number:\n");
  scanf("%d", &n);
  if (n == 0)
    d[0]++;
  while (n > 0) {
    d[n % 10]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (d[i] != 0) {
      printf("\nDigit %d = %d times", i, d[i]);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  je     L40
  jle    L42
L22:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %edx,%eax
  mov    %esi,%edx
  cmp    $0x9,%eax
  jg     L22
  mov    %esi,0xc(%rsp)
L42:
  mov    $0x0,%ebx
  lea    D2(%rip),%rbp
  jmp    L48
L25:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L35
L48:
  mov    %ebx,%esi
  mov    0x10(%rsp,%rbx,4),%edx
  test   %edx,%edx
  je     L25
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L35:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  movl   $0x1,0x10(%rsp)
  jmp    L42
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D7: Enter a number:

tool: D26: %d

tool: D2: 
Digit %d = %d times

assistant: ```c
int main() {
  int n, i;
  int d[10] = {0};
  printf("Enter a number:\n");
  scanf("%d", &n);
  if (n == 0)
    d[0]++;
  while (n > 0) {
    d[n % 10]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (d[i] != 0) {
      printf("\nDigit %d = %d times", i, d[i]);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D0(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movq   $0x0,0x30(%rsp)
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jne    L35
  movl   $0x1,0x10(%rsp)
L47:
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D26(%rip),%r12
  jmp    L42
L66:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L87
L42:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  test   %edx,%edx
  je     L66
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L42
L87:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  movl   $0x0,0x10(%rsp)
  jle    L47
  mov    $0xcccccccd,%edi
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %edx,%eax
  imul   %rdi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %edx,%eax
  mov    %ecx,%edx
  cmp    $0x9,%eax
  jg     L16
  mov    %ecx,0xc(%rsp)
  jmp    L47
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D6
data_type: string
name: read_data
arguments: data_label: D26
data_type: string

tool: D0: Enter a number:

tool: D6: %d

tool: D26: 
Digit %d = %d times

assistant: ```c
int main() {
  int n, i;
  int d[10] = {0};
  printf("Enter a number:\n");
  scanf("%d", &n);
  if (n == 0)
    d[0]++;
  while (n > 0) {
    d[n % 10]++;
    n = n / 10;
  }
  for (i = 0; i < 10; i++) {
    if (d[i] != 0) {
      printf("\nDigit %d = %d times", i, d[i]);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L97:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L75
  mov    $0x0,%eax
  call   <__pcrlf@plt>
  addq   $0x1,-0x20(%rbp)
  jmp    L25
L75:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L77
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L73
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__outln@plt>
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L77
L73:
  addq   $0x1,-0x10(%rbp)
L77:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L5
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  cmp    $0xfd,%rax
  jle    L12
L5:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L25
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__outstr@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L25:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L97
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int write(fd, ptr, len)
int fd;
char *ptr;
unsigned len;
{
  char *done = ptr + len;
  char *q;
  unsigned len2;
  while (ptr < done) {
    if (*ptr == '\n') {
      __pcrlf();
      ptr++;
    } else {
      q = ptr;
      while ((q < done) && ((ptr - q) < 254)) {
        if (*q == '\n') {
          __outln(ptr, q);
          ptr = ++q;
        } else
          q++;
      }
      if (ptr != q) {
        __outstr(ptr, q);
        ptr = q;
      }
    }
  }
  return len;
}
```