ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<char_to_str>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *char_to_str(char src) {
  char *ret = malloc(sizeof(char) * 2);
  *ret = src;
  *(ret + 1) = '\0';
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<char_to_str>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *char_to_str(char src) {
  char *ret = malloc(sizeof(char) * 2);
  *ret = src;
  *(ret + 1) = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<char_to_str>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *char_to_str(char src) {
  char *ret = malloc(sizeof(char) * 2);
  *ret = src;
  *(ret + 1) = '\0';
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<writes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,%eax
  and    $0xfffffffc,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  and    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L17
  mov    -0x28(%rbp),%rax
  mov    %eax,%eax
  and    $0xfffffffc,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L27
  mov    $0x80000000,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x28(%rbp)
L27:
  cmpl   $0x0,-0xc(%rbp)
  jne    L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void writes(char const *str) {
  char const *word_addr;
  unsigned word;
  unsigned index;
  unsigned c;
  word_addr = (char const *const)((unsigned const)str & ~0x3);
  word = *(unsigned const *const)word_addr;
  do {
    index = (unsigned const)str & 0x3;
    if (index == 0) {
      word_addr = (char const *const)((unsigned const)str & ~0x3);
      word = *(unsigned const *const)word_addr;
    }
    c = (word >> (index << 3)) & 0xff;
    if (c != '\0') {
      *(unsigned volatile *const)0x80000000 = c;
      ++str;
    }
  } while (c != '\0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writes>:
  endbr64
  mov    %rdi,%rax
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
  mov    $0x80000000,%esi
  jmp    L10
L29:
  mov    %eax,(%rsi)
  add    $0x1,%rdi
L10:
  mov    %edi,%ecx
  and    $0x3,%ecx
  jne    L27
  mov    %rdi,%rax
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
L27:
  shl    $0x3,%ecx
  mov    %edx,%eax
  shr    %cl,%eax
  and    $0xff,%eax
  jne    L29
  ret
```

assistant: ```c
void writes(char const *str) {
  char const *word_addr;
  unsigned word;
  unsigned index;
  unsigned c;
  word_addr = (char const *const)((unsigned const)str & ~0x3);
  word = *(unsigned const *const)word_addr;
  do {
    index = (unsigned const)str & 0x3;
    if (index == 0) {
      word_addr = (char const *const)((unsigned const)str & ~0x3);
      word = *(unsigned const *const)word_addr;
    }
    c = (word >> (index << 3)) & 0xff;
    if (c != '\0') {
      *(unsigned volatile *const)0x80000000 = c;
      ++str;
    }
  } while (c != '\0');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writes>:
  endbr64
  mov    %rdi,%rax
  mov    $0x80000000,%esi
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
  nopl   0x0(%rax)
L15:
  mov    %edi,%ecx
  and    $0x3,%ecx
  jne    L6
  mov    %rdi,%rax
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
L6:
  shl    $0x3,%ecx
  mov    %edx,%eax
  shr    %cl,%eax
  and    $0xff,%eax
  jne    L19
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %eax,(%rsi)
  add    $0x1,%rdi
  jmp    L15
```

assistant: ```c
void writes(char const *str) {
  char const *word_addr;
  unsigned word;
  unsigned index;
  unsigned c;
  word_addr = (char const *const)((unsigned const)str & ~0x3);
  word = *(unsigned const *const)word_addr;
  do {
    index = (unsigned const)str & 0x3;
    if (index == 0) {
      word_addr = (char const *const)((unsigned const)str & ~0x3);
      word = *(unsigned const *const)word_addr;
    }
    c = (word >> (index << 3)) & 0xff;
    if (c != '\0') {
      *(unsigned volatile *const)0x80000000 = c;
      ++str;
    }
  } while (c != '\0');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<writes>:
  endbr64
  mov    %rdi,%rax
  mov    $0x80000000,%esi
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
  nopl   0x0(%rax)
L22:
  mov    %edi,%ecx
  and    $0x3,%ecx
  jne    L34
  mov    %rdi,%rax
  and    $0xfffffffc,%eax
  mov    (%rax),%edx
  mov    %edx,%eax
  and    $0xff,%eax
  jne    L30
  ret
  nopl   0x0(%rax)
L34:
  shl    $0x3,%ecx
  mov    %edx,%eax
  shr    %cl,%eax
  and    $0xff,%eax
  jne    L30
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %eax,(%rsi)
  add    $0x1,%rdi
  jmp    L22
```

assistant: ```c
void writes(char const *str) {
  char const *word_addr;
  unsigned word;
  unsigned index;
  unsigned c;
  word_addr = (char const *const)((unsigned const)str & ~0x3);
  word = *(unsigned const *const)word_addr;
  do {
    index = (unsigned const)str & 0x3;
    if (index == 0) {
      word_addr = (char const *const)((unsigned const)str & ~0x3);
      word = *(unsigned const *const)word_addr;
    }
    c = (word >> (index << 3)) & 0xff;
    if (c != '\0') {
      *(unsigned volatile *const)0x80000000 = c;
      ++str;
    }
  } while (c != '\0');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7: %.2lf 

assistant: ```c
void print_vector(int n, double *a) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.2lf ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_vector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L4
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  lea    D9(%rip),%rbp
L13:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: %.2lf 

assistant: ```c
void print_vector(int n, double *a) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.2lf ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_vector>:
  endbr64
  test   %edi,%edi
  jle    L12
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L15:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %.2lf 

assistant: ```c
void print_vector(int n, double *a) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.2lf ", a[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_vector>:
  endbr64
  test   %edi,%edi
  jle    L7
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L13:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: %.2lf 

assistant: ```c
void print_vector(int n, double *a) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.2lf ", a[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<b64lenn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L139
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <xmlc_white_space@plt>
  test   %eax,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L2
  addq   $0x1,-0x8(%rbp)
  jmp    L48
L139:
  nop
L48:
  jmp    L8
L144:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <xmlc_white_space@plt>
  test   %eax,%eax
  jne    L72
  addl   $0x1,-0x10(%rbp)
L72:
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L144
  mov    -0x10(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  je     L63
  cmp    $0x3,%eax
  jg     L132
  cmp    $0x2,%eax
  je     L69
  cmp    $0x2,%eax
  jg     L132
  test   %eax,%eax
  je     L12
  cmp    $0x1,%eax
  jne    L132
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L132
L69:
  addl   $0x1,-0xc(%rbp)
  jmp    L132
L63:
  addl   $0x2,-0xc(%rbp)
  jmp    L132
L12:
  nop
L132:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int b64lenn(char *s, int n) {
  char *end = s + n;
  int l = 0, len;
  for (;;) {
    if (end == s)
      break;
    --end;
    if (!xmlc_white_space(*end) && *end != '=') {
      ++end;
      break;
    }
  }
  while (s != end) {
    if (!xmlc_white_space(*s))
      ++l;
    ++s;
  }
  len = l / 4 * 3;
  switch (l % 4) {
  case 0:
    break;
  case 1:
    len = -1;
    break;
  case 2:
    len += 1;
    break;
  case 3:
    len += 2;
    break;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<b64lenn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movslq %esi,%rbp
  add    %rdi,%rbp
  cmp    %rbp,%rdi
  jne    L104
L15:
  mov    $0x0,%edx
  jmp    L10
L91:
  cmp    %rbp,%r12
  je     L15
L104:
  mov    %rbp,%r13
  sub    $0x1,%rbp
  movsbl 0x0(%rbp),%edi
  call   <xmlc_white_space@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L91
  cmpb   $0x3d,0x0(%rbp)
  je     L91
  cmp    %r13,%r12
  je     L15
L23:
  movsbl (%r12),%edi
  call   <xmlc_white_space@plt>
  cmp    $0x1,%eax
  adc    $0x0,%ebx
  add    $0x1,%r12
  cmp    %r13,%r12
  jne    L23
  lea    0x3(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x2,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %ecx,%edx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  cmp    $0x2,%ebx
  je     L14
  cmp    $0x3,%ebx
  je     L45
  cmp    $0x1,%ebx
  mov    $0xffffffff,%eax
  cmove  %eax,%edx
L10:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    0x1(%rcx),%edx
  jmp    L10
L45:
  lea    0x2(%rcx),%edx
  jmp    L10
```

assistant: ```c
int b64lenn(char *s, int n) {
  char *end = s + n;
  int l = 0, len;
  for (;;) {
    if (end == s)
      break;
    --end;
    if (!xmlc_white_space(*end) && *end != '=') {
      ++end;
      break;
    }
  }
  while (s != end) {
    if (!xmlc_white_space(*s))
      ++l;
    ++s;
  }
  len = l / 4 * 3;
  switch (l % 4) {
  case 0:
    break;
  case 1:
    len = -1;
    break;
  case 2:
    len += 1;
    break;
  case 3:
    len += 2;
    break;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b64lenn>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  add    %rdi,%r13
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %r13,%rdi
  je     L26
  nopl   0x0(%rax)
L68:
  mov    %r13,%rbp
  lea    -0x1(%r13),%r13
  movsbl -0x1(%rbp),%edi
  call   <xmlc_white_space@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L18
  cmpb   $0x3d,-0x1(%rbp)
  jne    L44
L18:
  cmp    %r13,%r12
  jne    L68
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L44:
  cmp    %rbp,%r12
  je     L26
  nopl   (%rax)
L11:
  movsbl (%r12),%edi
  call   <xmlc_white_space@plt>
  cmp    $0x1,%eax
  adc    $0x0,%ebx
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L11
  mov    %ebx,%eax
  and    $0x3,%ebx
  sar    $0x2,%eax
  lea    (%rax,%rax,2),%edx
  lea    0x1(%rdx),%eax
  cmp    $0x2,%ebx
  je     L76
  lea    0x2(%rdx),%eax
  cmp    $0x3,%ebx
  je     L76
  cmp    $0x1,%ebx
  mov    $0xffffffff,%eax
  cmovne %edx,%eax
L76:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int b64lenn(char *s, int n) {
  char *end = s + n;
  int l = 0, len;
  for (;;) {
    if (end == s)
      break;
    --end;
    if (!xmlc_white_space(*end) && *end != '=') {
      ++end;
      break;
    }
  }
  while (s != end) {
    if (!xmlc_white_space(*s))
      ++l;
    ++s;
  }
  len = l / 4 * 3;
  switch (l % 4) {
  case 0:
    break;
  case 1:
    len = -1;
    break;
  case 2:
    len += 1;
    break;
  case 3:
    len += 2;
    break;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b64lenn>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  add    %rdi,%r13
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %r13,%rdi
  je     L34
  nopl   0x0(%rax)
L29:
  mov    %r13,%rbp
  lea    -0x1(%r13),%r13
  movsbl -0x1(%rbp),%edi
  call   <xmlc_white_space@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L31
  cmpb   $0x3d,-0x1(%rbp)
  jne    L14
L31:
  cmp    %r13,%r12
  jne    L29
L34:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L14:
  cmp    %rbp,%r12
  je     L34
  nopl   (%rax)
L6:
  movsbl (%r12),%edi
  call   <xmlc_white_space@plt>
  cmp    $0x1,%eax
  adc    $0x0,%ebx
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L6
  mov    %ebx,%eax
  and    $0x3,%ebx
  sar    $0x2,%eax
  lea    (%rax,%rax,2),%edx
  lea    0x1(%rdx),%eax
  cmp    $0x2,%ebx
  je     L46
  lea    0x2(%rdx),%eax
  cmp    $0x3,%ebx
  je     L46
  cmp    $0x1,%ebx
  mov    $0xffffffff,%eax
  cmovne %edx,%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int b64lenn(char *s, int n) {
  char *end = s + n;
  int l = 0, len;
  for (;;) {
    if (end == s)
      break;
    --end;
    if (!xmlc_white_space(*end) && *end != '=') {
      ++end;
      break;
    }
  }
  while (s != end) {
    if (!xmlc_white_space(*s))
      ++l;
    ++s;
  }
  len = l / 4 * 3;
  switch (l % 4) {
  case 0:
    break;
  case 1:
    len = -1;
    break;
  case 2:
    len += 1;
    break;
  case 3:
    len += 2;
    break;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ec_bad_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
void ec_bad_exit(char *msg) {
  (void)write(2, msg, strlen(msg));
  (void)write(2, "\n", 1);
  exit(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ec_bad_exit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D4(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: 


assistant: ```c
void ec_bad_exit(char *msg) {
  (void)write(2, msg, strlen(msg));
  (void)write(2, "\n", 1);
  exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ec_bad_exit>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x2,%edi
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  call   <write@plt>
  mov    $0xffffffff,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: 


assistant: ```c
void ec_bad_exit(char *msg) {
  (void)write(2, msg, strlen(msg));
  (void)write(2, "\n", 1);
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ec_bad_exit>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x2,%edi
  mov    $0x1,%edx
  lea    D3(%rip),%rsi
  call   <write@plt>
  mov    $0xffffffff,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: 


assistant: ```c
void ec_bad_exit(char *msg) {
  (void)write(2, msg, strlen(msg));
  (void)write(2, "\n", 1);
  exit(-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ARGB32_manhattan_distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x10,%rax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  sar    $0x10,%rdx
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  neg    %eax
  cmovns %eax,%ebx
  mov    %ebx,%r12d
  mov    -0x18(%rbp),%rax
  sar    $0x8,%rax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  sar    $0x8,%rdx
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  add    %eax,%r12d
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  add    %r12d,%eax
  cltq
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
long ARGB32_manhattan_distance(long a, long b) {
  register int d = (int)(((a) >> 16) & 0x00FF) - (int)(((b) >> 16) & 0x00FF);
  register int t = (d < 0) ? -d : d;
  d = (int)(((a) >> 8) & 0x00FF) - (int)(((b) >> 8) & 0x00FF);
  t += (d < 0) ? -d : d;
  d = (int)((a)&0x00FF) - (int)((b)&0x00FF);
  return (t + ((d < 0) ? -d : d));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ARGB32_manhattan_distance>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %rdi,%rax
  sar    $0x10,%rax
  movzbl %al,%eax
  sar    $0x10,%rsi
  movzbl %sil,%esi
  sub    %esi,%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  movzbl %dh,%esi
  movzbl %ch,%eax
  sub    %eax,%esi
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  add    %edi,%eax
  movzbl %dl,%edx
  movzbl %cl,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  neg    %ecx
  cmovns %ecx,%edx
  add    %edx,%eax
  cltq
  ret
```

assistant: ```c
long ARGB32_manhattan_distance(long a, long b) {
  register int d = (int)(((a) >> 16) & 0x00FF) - (int)(((b) >> 16) & 0x00FF);
  register int t = (d < 0) ? -d : d;
  d = (int)(((a) >> 8) & 0x00FF) - (int)(((b) >> 8) & 0x00FF);
  t += (d < 0) ? -d : d;
  d = (int)((a)&0x00FF) - (int)((b)&0x00FF);
  return (t + ((d < 0) ? -d : d));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ARGB32_manhattan_distance>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  sar    $0x10,%rsi
  mov    %rdi,%rdx
  sar    $0x10,%rax
  movzbl %sil,%esi
  movzbl %al,%eax
  sub    %esi,%eax
  movzbl %dh,%esi
  movzbl %dl,%edx
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  movzbl %ch,%eax
  movzbl %cl,%ecx
  sub    %eax,%esi
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  sub    %ecx,%edx
  mov    %edx,%ecx
  add    %edi,%eax
  neg    %ecx
  cmovns %ecx,%edx
  add    %edx,%eax
  cltq
  ret
```

assistant: ```c
long ARGB32_manhattan_distance(long a, long b) {
  register int d = (int)(((a) >> 16) & 0x00FF) - (int)(((b) >> 16) & 0x00FF);
  register int t = (d < 0) ? -d : d;
  d = (int)(((a) >> 8) & 0x00FF) - (int)(((b) >> 8) & 0x00FF);
  t += (d < 0) ? -d : d;
  d = (int)((a)&0x00FF) - (int)((b)&0x00FF);
  return (t + ((d < 0) ? -d : d));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ARGB32_manhattan_distance>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rcx
  sar    $0x10,%rsi
  mov    %rdi,%rdx
  sar    $0x10,%rax
  movzbl %sil,%esi
  movzbl %al,%eax
  sub    %esi,%eax
  movzbl %dh,%esi
  movzbl %dl,%edx
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  movzbl %ch,%eax
  movzbl %cl,%ecx
  sub    %eax,%esi
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  sub    %ecx,%edx
  mov    %edx,%ecx
  add    %edi,%eax
  neg    %ecx
  cmovns %ecx,%edx
  add    %edx,%eax
  cltq
  ret
```

assistant: ```c
long ARGB32_manhattan_distance(long a, long b) {
  register int d = (int)(((a) >> 16) & 0x00FF) - (int)(((b) >> 16) & 0x00FF);
  register int t = (d < 0) ? -d : d;
  d = (int)(((a) >> 8) & 0x00FF) - (int)(((b) >> 8) & 0x00FF);
  t += (d < 0) ? -d : d;
  d = (int)((a)&0x00FF) - (int)((b)&0x00FF);
  return (t + ((d < 0) ? -d : d));
}
```