user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  lea    D38(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x190,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x188(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x100(%rsp),%rbp
  lea    0x80(%rsp),%r12
  mov    %r13,%rsi
  mov    %rbp,%rcx
  mov    %r12,%rdx
  call   <scanf@plt>
  lea    D16(%rip),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  lea    D69(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L97
  lea    D97(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L118
  lea    D114(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L106:
  mov    0x188(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L121
  add    $0x190,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  lea    D44(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L120
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L92
  lea    D106(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L120:
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L91
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L97:
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L141
  lea    D136(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L118:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L141:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L92:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L91:
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L106
L121:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D38
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D69
type_guessed: string
name: retrieve_data
arguments: tag: D97
type_guessed: string
name: retrieve_data
arguments: tag: D114
type_guessed: string
name: retrieve_data
arguments: tag: D44
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string
name: retrieve_data
arguments: tag: D106
type_guessed: string
name: retrieve_data
arguments: tag: D56
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D136
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D58
type_guessed: string

tool: D38: %s%s%s

tool: D16: vertebrado

tool: D69: ave

tool: D97: carnivoro

tool: D114: pomba


tool: D44: inseto

tool: D10: hematofago

tool: D106: pulga


tool: D56: sanguessuga


tool: D24: onivoro

tool: D136: homem


tool: D0: aguia


tool: D34: vaca


tool: D12: lagarta


tool: D58: minhoca


assistant: ```c
int main(void) {
  char a[128], b[128], c[128];
  scanf("%s%s%s", &a, &b, &c);
  if (strcmp(a, "vertebrado") == 0) {
    if (strcmp(b, "ave") == 0) {
      if (strcmp(c, "carnivoro") == 0) {
        printf("aguia\n");
      } else {
        printf("pomba\n");
      }
    } else {
      if (strcmp(c, "onivoro") == 0) {
        printf("homem\n");
      } else {
        printf("vaca\n");
      }
    }
  } else {
    if (strcmp(b, "inseto") == 0) {
      if (strcmp(c, "hematofago") == 0) {
        printf("pulga\n");
      } else {
        printf("lagarta\n");
      }
    } else {
      if (strcmp(c, "hematofago") == 0) {
        printf("sanguessuga\n");
      } else {
        printf("minhoca\n");
      }
    }
  }
  return 0;
}
```