ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <totalpos@plt>
  lea    D37(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D37
type_guessed: string

tool: D38: entre com uma frase: 

tool: D7: entre com uma letra: 

tool: D11:  %c

tool: D37: resposta = %d

assistant: ```c
int main() {
  int resp;
  char txt[10], let;
  printf("entre com uma frase: ");
  gets(txt);
  printf("entre com uma letra: ");
  scanf(" %c", &let);
  resp = totalpos(&txt[0], let);
  printf("resposta = %d", resp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flags_is_writing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L2
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
L2:
  mov    $0x1,%eax
  jmp    L1
L5:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
bool flags_is_writing(int flags) {
  int accmode = (flags & O_ACCMODE);
  return (accmode == O_WRONLY || accmode == O_RDWR);
}
```
user: Translate the below assembly code into C programming language:

```asm
<flags_is_writing>:
  endbr64
  mov    D17(%rip),%rax
  and    (%rax),%edi
  mov    $0x1,%eax
  mov    D4(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L2
  mov    D10(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
bool flags_is_writing(int flags) {
  int accmode = (flags & O_ACCMODE);
  return (accmode == O_WRONLY || accmode == O_RDWR);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<flags_is_writing>:
  endbr64
  mov    D19(%rip),%rax
  mov    D9(%rip),%rdx
  and    (%rax),%edi
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L7
  mov    D20(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
bool flags_is_writing(int flags) {
  int accmode = (flags & O_ACCMODE);
  return (accmode == O_WRONLY || accmode == O_RDWR);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flags_is_writing>:
  endbr64
  mov    D24(%rip),%rax
  mov    D3(%rip),%rdx
  and    (%rax),%edi
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L2
  mov    D7(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
bool flags_is_writing(int flags) {
  int accmode = (flags & O_ACCMODE);
  return (accmode == O_WRONLY || accmode == O_RDWR);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ms_dabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L4
  movsd  -0x8(%rbp),%xmm0
  movq   D6(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L4:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: f32[2]

tool: {"D6": [0.0,-0.0]}

assistant: ```c
double ms_dabs(double val) {
  if (val < 0.0)
    val *= -1.0;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ms_dabs>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L4
L12:
  ret
L4:
  xorpd  D8(%rip),%xmm0
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: f32[4]

tool: {"D8": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double ms_dabs(double val) {
  if (val < 0.0)
    val *= -1.0;
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ms_dabs>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  ret
  nop
L6:
  xorpd  D2(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: f32[4]

tool: {"D2": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double ms_dabs(double val) {
  if (val < 0.0)
    val *= -1.0;
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<ms_dabs>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L4
  ret
  nop
L4:
  xorpd  D7(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: f32[4]

tool: {"D7": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double ms_dabs(double val) {
  if (val < 0.0)
    val *= -1.0;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  movq   $0xfffffffffffffffe,-0x18(%rbp)
  mov    $0xfffffffffffffffc,%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L14:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L9:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    %rsi,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int main(void) {
  int off_t_is_large[((((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483629 == 721 && (((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483647 == 1) ? 1 : -1];
  (void)off_t_is_large;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int off_t_is_large[((((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483629 == 721 && (((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483647 == 1) ? 1 : -1];
  (void)off_t_is_large;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int off_t_is_large[((((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483629 == 721 && (((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483647 == 1) ? 1 : -1];
  (void)off_t_is_large;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int off_t_is_large[((((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483629 == 721 && (((off_t)1 << 62) - 1 + ((off_t)1 << 62)) % 2147483647 == 1) ? 1 : -1];
  (void)off_t_is_large;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L19:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L15
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *b, int c, unsigned int len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%ecx
  test   %edx,%edx
  je     L17
  mov    %ecx,%ecx
  lea    0x1(%rdi,%rcx,1),%rcx
  mov    %rdi,%rdx
L13:
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L13
L17:
  ret
```

assistant: ```c
void *memset(void *b, int c, unsigned int len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L8
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *b, int c, unsigned int len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset>:
  endbr64
  test   %edx,%edx
  je     L1
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *b, int c, unsigned int len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
L7:
  cmpl   $0x9,-0xc(%rbp)
  jle    L7
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int i;
  a = 5;
  b = 3;
  i = 0;
  while (i < 10) {
    i = i + 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
int main() {
  int a;
  int b;
  int i;
  a = 5;
  b = 3;
  i = 0;
  while (i < 10) {
    i = i + 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
int main() {
  int a;
  int b;
  int i;
  a = 5;
  b = 3;
  i = 0;
  while (i < 10) {
    i = i + 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
int main() {
  int a;
  int b;
  int i;
  a = 5;
  b = 3;
  i = 0;
  while (i < 10) {
    i = i + 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<moveInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <HiveX_motor_setMode@plt>
  mov    $0x32,%edi
  call   <HiveX_motor_setPeriod@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void moveInit() {
  HiveX_motor_setMode(1);
  HiveX_motor_setPeriod(50);
  stopRobot();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<moveInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <HiveX_motor_setMode@plt>
  mov    $0x32,%edi
  call   <HiveX_motor_setPeriod@plt>
  mov    $0x0,%eax
  call   <stopRobot@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void moveInit() {
  HiveX_motor_setMode(1);
  HiveX_motor_setPeriod(50);
  stopRobot();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<moveInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <HiveX_motor_setMode@plt>
  mov    $0x32,%edi
  call   <HiveX_motor_setPeriod@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <stopRobot@plt>
```

assistant: ```c
void moveInit() {
  HiveX_motor_setMode(1);
  HiveX_motor_setPeriod(50);
  stopRobot();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L59
L29:
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L59
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
L59:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: send

assistant: ```c
int send_msg(int t, const char *c, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  int len = strlen(c);
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_msg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L38
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
L23:
  cmp    %ebp,%ebx
  jge    L22
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r12,%rsi
  mov    %r14d,%ecx
  mov    %r13d,%edi
  call   <send@plt>
  add    %ebx,%eax
  mov    %eax,%ebx
  jns    L23
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%ebx
L22:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0xffffffff,%ebx
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: send

assistant: ```c
int send_msg(int t, const char *c, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  int len = strlen(c);
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_msg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L11
  mov    %edi,%r13d
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %edx,%r14d
  call   <strlen@plt>
  xor    %r12d,%r12d
  mov    %eax,%ebx
  jmp    L9
  nopl   0x0(%rax)
L35:
  movslq %r12d,%rsi
  mov    %ebx,%edx
  mov    %r14d,%ecx
  mov    %r13d,%edi
  sub    %r12d,%edx
  add    %rbp,%rsi
  call   <send@plt>
  add    %eax,%r12d
  js     L48
L9:
  cmp    %ebx,%r12d
  jl     L35
L2:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L48:
  mov    $0xffffffff,%r12d
  lea    D6(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    $0xffffffff,%r12d
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: send

assistant: ```c
int send_msg(int t, const char *c, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  int len = strlen(c);
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<send_msg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L11
  mov    %edi,%r13d
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %edx,%r14d
  call   <strlen@plt>
  xor    %r12d,%r12d
  mov    %eax,%ebx
  jmp    L42
  nopl   0x0(%rax)
L33:
  movslq %r12d,%rsi
  mov    %ebx,%edx
  mov    %r14d,%ecx
  mov    %r13d,%edi
  sub    %r12d,%edx
  add    %rbp,%rsi
  call   <send@plt>
  add    %eax,%r12d
  js     L47
L42:
  cmp    %ebx,%r12d
  jl     L33
L44:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L47:
  mov    $0xffffffff,%r12d
  lea    D5(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    $0xffffffff,%r12d
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: send

assistant: ```c
int send_msg(int t, const char *c, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  int len = strlen(c);
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L18:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void strupper(char *str) {
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    str[i] = toupper(str[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strupper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L2:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strupper(char *str) {
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    str[i] = toupper(str[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strupper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L18:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L18
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strupper(char *str) {
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    str[i] = toupper(str[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strupper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L19
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L2:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L2
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strupper(char *str) {
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    str[i] = toupper(str[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<g_numdays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    $0xb,%eax
  seta   %dl
  test   %dl,%dl
  jne    L2
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0xa50,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L22
  and    $0x4,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L2
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L57
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L7
L57:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L65
L7:
  mov    $0x1d,%eax
  jmp    L35
L65:
  mov    $0x1c,%eax
  jmp    L35
L22:
  mov    $0x1e,%eax
  jmp    L35
L2:
  mov    $0x1f,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int g_numdays(int month, int year) {
  int y;
  y = abs(year);
  switch (month) {
  case 2:
    if ((((y % 4) == 0) && ((y % 100) != 0)) || ((y % 400) == 0))
      return (29);
    else
      return (28);
  case 4:
  case 6:
  case 9:
  case 11:
    return (30);
  default:
    return (31);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g_numdays>:
  endbr64
  cmp    $0xb,%edi
  ja     L34
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%rax
  mov    %rax,%rdx
  mov    $0x1e,%eax
  test   $0xa50,%edx
  jne    L57
  mov    $0x1f,%eax
  cmp    $0x2,%edi
  je     L20
L57:
  ret
L20:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  test   $0x3,%dl
  jne    L10
  movslq %edx,%rcx
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x25,%rcx
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  imul   $0x64,%ecx,%ecx
  mov    $0x1d,%eax
  cmp    %ecx,%edx
  jne    L57
L10:
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  add    $0x1c,%eax
  ret
L34:
  mov    $0x1f,%eax
  jmp    L57
```

assistant: ```c
int g_numdays(int month, int year) {
  int y;
  y = abs(year);
  switch (month) {
  case 2:
    if ((((y % 4) == 0) && ((y % 100) != 0)) || ((y % 400) == 0))
      return (29);
    else
      return (28);
  case 4:
  case 6:
  case 9:
  case 11:
    return (30);
  default:
    return (31);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g_numdays>:
  endbr64
  cmp    $0xb,%edi
  ja     L0
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%rax
  mov    %rax,%rdx
  mov    $0x1e,%eax
  test   $0xa50,%edx
  jne    L39
  mov    $0x1f,%eax
  cmp    $0x2,%edi
  je     L36
L39:
  ret
  xchg   %ax,%ax
L36:
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  test   $0x3,%dl
  jne    L34
  imul   $0xc28f5c29,%edx,%ecx
  mov    $0x1d,%eax
  ror    $0x2,%ecx
  cmp    $0x28f5c28,%ecx
  ja     L39
L34:
  imul   $0xc28f5c29,%edx,%edx
  xor    %eax,%eax
  ror    $0x4,%edx
  cmp    $0xa3d70b,%edx
  setb   %al
  add    $0x1c,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1f,%eax
  ret
```

assistant: ```c
int g_numdays(int month, int year) {
  int y;
  y = abs(year);
  switch (month) {
  case 2:
    if ((((y % 4) == 0) && ((y % 100) != 0)) || ((y % 400) == 0))
      return (29);
    else
      return (28);
  case 4:
  case 6:
  case 9:
  case 11:
    return (30);
  default:
    return (31);
  }
}
```