ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calculateIsotropicDisplacementSquared>:
  endbr64
  mov    %edi,%r9d
  mov    %rdx,%rdi
  test   %r9d,%r9d
  jle    L34
  imul   %r9d,%ecx
  movslq %ecx,%rdx
  movslq %r9d,%rcx
  lea    (%rdx,%rdx,2),%rax
  mov    %rdx,%r8
  add    %rcx,%rdx
  lea    (%rdx,%rdx,2),%rdx
  lea    (%rsi,%rcx,8),%rcx
  lea    (%rdi,%rdx,8),%rdx
  lea    (%rdi,%rax,8),%rax
  cmp    %rdx,%rsi
  setae  %dl
  cmp    %rcx,%rax
  setae  %cl
  or     %cl,%dl
  je     L59
  cmp    $0x1,%r9d
  je     L59
  mov    %r9d,%ecx
  pxor   %xmm3,%xmm3
  pxor   %xmm5,%xmm5
  mov    %rsi,%rdx
  shr    %ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rsi,%rcx,1),%rcx
  nopl   0x0(%rax)
L15:
  movups %xmm5,(%rdx)
  movupd (%rax),%xmm4
  movupd 0x10(%rax),%xmm1
  add    $0x10,%rdx
  add    $0x30,%rax
  movapd %xmm4,%xmm0
  movapd %xmm4,%xmm2
  movhps -0x18(%rax),%xmm0
  unpcklpd %xmm4,%xmm1
  shufpd $0x1,%xmm4,%xmm2
  movhpd -0x10(%rax),%xmm2
  movhps -0x8(%rax),%xmm1
  mulpd  %xmm0,%xmm0
  mulpd  %xmm2,%xmm2
  mulpd  %xmm1,%xmm1
  addpd  %xmm2,%xmm0
  addpd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  movups %xmm0,-0x10(%rdx)
  unpckhpd %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  movapd %xmm0,%xmm3
  addsd  %xmm1,%xmm3
  cmp    %rcx,%rdx
  jne    L15
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%r9d
  je     L26
  mov    %ecx,%eax
  add    %r8d,%ecx
  lea    (%rsi,%rax,8),%rdx
  lea    (%rcx,%rcx,2),%eax
  cltq
  movq   $0x0,(%rdx)
  movsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  movsd  (%rdi,%rax,8),%xmm2
  movsd  0x8(%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  movsd  %xmm0,(%rdx)
L26:
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L59:
  lea    (%r8,%r8,2),%eax
  lea    -0x1(%r9),%edx
  pxor   %xmm3,%xmm3
  cltq
  lea    0x8(%rsi,%rdx,8),%rdx
  lea    (%rdi,%rax,8),%rax
  nop
L5:
  movq   $0x0,(%rsi)
  movsd  (%rax),%xmm0
  add    $0x8,%rsi
  add    $0x18,%rax
  movsd  -0x10(%rax),%xmm2
  movsd  -0x8(%rax),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rsi)
  addsd  %xmm0,%xmm3
  cmp    %rdx,%rsi
  jne    L5
  movapd %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L34:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double calculateIsotropicDisplacementSquared(int N, double *displacementSquared, double *A, int mode_no) {
  int i = mode_no;
  int j = 0;
  double totalAreaTheoretical = 0.0;
  for (j = 0; j < N; j++) {
    displacementSquared[j] = 0.0;
    displacementSquared[j] = ((A[3 * N * i + 3 * j] * A[3 * N * i + 3 * j]) + (A[3 * N * i + 3 * j + 1] * A[3 * N * i + 3 * j + 1]) + (A[3 * N * i + 3 * j + 2] * A[3 * N * i + 3 * j + 2]));
    totalAreaTheoretical += displacementSquared[j];
  }
  return totalAreaTheoretical;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makebcpl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %edx,%ebx
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L3
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
L3:
  movslq %ebx,%rax
  shl    $0x18,%rax
  mov    %rax,%r13
  mov    $0x10,%r15d
  jmp    L45
L35:
  mov    %r14,%rax
  lea    0x1(%rax),%r14
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %r15d,%edx
  mov    %edx,%ecx
  shl    %cl,%rax
  or     %rax,%r13
  sub    $0x8,%r15
  test   %r15,%r15
  jns    L46
  mov    %r12,%rax
  lea    0x8(%rax),%r12
  mov    %r13,(%rax)
  mov    $0x0,%r13d
  mov    $0x18,%r15d
L46:
  sub    $0x1,%ebx
L45:
  test   %ebx,%ebx
  jg     L35
  test   %r13,%r13
  je     L4
  mov    %r12,%rax
  lea    0x8(%rax),%r12
  mov    %r13,(%rax)
L4:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
long *makebcpl(register long *p, register char *s, register int n) {
  register long t;
  register long sc;
  if (strlen(s) < n)
    n = strlen(s);
  t = ((long)n) << 24;
  sc = 16;
  while (n > 0) {
    t |= ((long)(*(unsigned char *)s++)) << sc;
    sc -= 8;
    if (sc < 0) {
      *p++ = t;
      t = 0;
      sc = 24;
    }
    n--;
  }
  if (t)
    *p++ = t;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<makebcpl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L16
L6:
  movslq %r12d,%rdi
  shl    $0x18,%rdi
  mov    %rbx,%rax
  test   %r12d,%r12d
  jle    L68
  lea    0x1(%rbp),%rdx
  movzbl 0x0(%rbp),%eax
  shl    $0x10,%rax
  or     %rax,%rdi
  mov    %r12d,%r12d
  lea    0x0(%rbp,%r12,1),%r8
  mov    %rbx,%rax
  mov    $0x8,%ecx
L63:
  cmp    %rdx,%r8
  je     L68
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%esi
  shl    %cl,%rsi
  or     %rsi,%rdi
  sub    $0x8,%rcx
  jns    L63
  mov    %rdi,(%rax)
  lea    0x8(%rax),%rax
  mov    $0x18,%ecx
  mov    $0x0,%edi
  jmp    L63
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L6
L68:
  test   %rdi,%rdi
  je     L30
  mov    %rdi,(%rax)
  lea    0x8(%rax),%rax
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long *makebcpl(register long *p, register char *s, register int n) {
  register long t;
  register long sc;
  if (strlen(s) < n)
    n = strlen(s);
  t = ((long)n) << 24;
  sc = 16;
  while (n > 0) {
    t |= ((long)(*(unsigned char *)s++)) << sc;
    sc -= 8;
    if (sc < 0) {
      *p++ = t;
      t = 0;
      sc = 24;
    }
    n--;
  }
  if (t)
    *p++ = t;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<makebcpl>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L44
L57:
  movslq %r12d,%rcx
  mov    %rbp,%rax
  mov    %rcx,%r8
  shl    $0x18,%r8
  test   %r12d,%r12d
  jle    L5
  movzbl (%rbx),%eax
  lea    (%rbx,%rcx,1),%rsi
  lea    0x1(%rbx),%rdx
  mov    $0x8,%ecx
  shl    $0x10,%rax
  or     %rax,%r8
  mov    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L39:
  cmp    %rdx,%rsi
  je     L5
L28:
  movzbl (%rdx),%edi
  add    $0x1,%rdx
  shl    %cl,%rdi
  or     %rdi,%r8
  sub    $0x8,%rcx
  jns    L39
  mov    %r8,(%rax)
  mov    $0x18,%ecx
  add    $0x8,%rax
  xor    %r8d,%r8d
  cmp    %rdx,%rsi
  jne    L28
L5:
  test   %r8,%r8
  je     L10
  mov    %r8,(%rax)
  add    $0x8,%rax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L44:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L57
```

assistant: ```c
long *makebcpl(register long *p, register char *s, register int n) {
  register long t;
  register long sc;
  if (strlen(s) < n)
    n = strlen(s);
  t = ((long)n) << 24;
  sc = 16;
  while (n > 0) {
    t |= ((long)(*(unsigned char *)s++)) << sc;
    sc -= 8;
    if (sc < 0) {
      *p++ = t;
      t = 0;
      sc = 24;
    }
    n--;
  }
  if (t)
    *p++ = t;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<makebcpl>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L31
  movslq %ebp,%r8
  shl    $0x18,%r8
  test   %ebp,%ebp
  jle    L19
L9:
  movzbl (%r12),%eax
  lea    0x1(%r12),%rdi
  shl    $0x10,%rax
  or     %rax,%r8
  cmp    $0x1,%ebp
  je     L19
  lea    -0x2(%rbp),%eax
  mov    $0x8,%ecx
  lea    0x2(%r12,%rax,1),%rsi
  mov    %rbx,%rax
  nopl   0x0(%rax)
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  shl    %cl,%rdx
  or     %rdx,%r8
  sub    $0x8,%rcx
  jns    L34
  mov    %r8,(%rax)
  mov    $0x18,%ecx
  add    $0x8,%rax
  xor    %r8d,%r8d
L34:
  cmp    %rsi,%rdi
  jne    L12
L52:
  test   %r8,%r8
  je     L43
  mov    %r8,(%rax)
  add    $0x8,%rax
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  movslq %ebp,%r8
  shl    $0x18,%r8
  test   %ebp,%ebp
  jg     L9
  nopl   (%rax)
L19:
  mov    %rbx,%rax
  jmp    L52
```

assistant: ```c
long *makebcpl(register long *p, register char *s, register int n) {
  register long t;
  register long sc;
  if (strlen(s) < n)
    n = strlen(s);
  t = ((long)n) << 24;
  sc = 16;
  while (n > 0) {
    t |= ((long)(*(unsigned char *)s++)) << sc;
    sc -= 8;
    if (sc < 0) {
      *p++ = t;
      t = 0;
      sc = 24;
    }
    n--;
  }
  if (t)
    *p++ = t;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libdax_audioxtr_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L31
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  jmp    L29
L31:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L51
L39:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x0,-0x4(%rbp)
  jns    L39
L29:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned libdax_audioxtr_to_int(struct libdax_audioxtr *o, unsigned char *bytes, int len, int flag) {
  unsigned int ret = 0;
  int i;
  if (flag & 1)
    for (i = 0; i < len; i++)
      ret = ret * 256 + bytes[i];
  else
    for (i = len - 1; i >= 0; i--)
      ret = ret * 256 + bytes[i];
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<libdax_audioxtr_to_int>:
  endbr64
  test   $0x1,%cl
  je     L19
  test   %edx,%edx
  jle    L18
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rsi
  mov    $0x0,%eax
L14:
  shl    $0x8,%eax
  movzbl (%rcx),%edx
  add    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L14
  ret
L19:
  mov    %edx,%ecx
  sub    $0x1,%ecx
  js     L44
  movslq %ecx,%rcx
  add    %rsi,%rcx
  movslq %edx,%rax
  lea    -0x2(%rsi,%rax,1),%rsi
  lea    -0x1(%rdx),%eax
  sub    %rax,%rsi
  mov    $0x0,%eax
L30:
  shl    $0x8,%eax
  movzbl (%rcx),%edx
  add    %edx,%eax
  sub    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L30
  ret
L18:
  mov    $0x0,%eax
  ret
L44:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned libdax_audioxtr_to_int(struct libdax_audioxtr *o, unsigned char *bytes, int len, int flag) {
  unsigned int ret = 0;
  int i;
  if (flag & 1)
    for (i = 0; i < len; i++)
      ret = ret * 256 + bytes[i];
  else
    for (i = len - 1; i >= 0; i--)
      ret = ret * 256 + bytes[i];
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libdax_audioxtr_to_int>:
  endbr64
  and    $0x1,%ecx
  je     L42
  test   %edx,%edx
  jle    L21
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl (%rsi),%edx
  shl    $0x8,%eax
  add    $0x1,%rsi
  add    %edx,%eax
  cmp    %rsi,%rcx
  jne    L35
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L21
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %eax,%eax
  add    %rsi,%rcx
  lea    -0x2(%rsi,%rdx,1),%rsi
  sub    %rax,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L46:
  movzbl (%rcx),%edx
  shl    $0x8,%eax
  sub    $0x1,%rcx
  add    %edx,%eax
  cmp    %rsi,%rcx
  jne    L46
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned libdax_audioxtr_to_int(struct libdax_audioxtr *o, unsigned char *bytes, int len, int flag) {
  unsigned int ret = 0;
  int i;
  if (flag & 1)
    for (i = 0; i < len; i++)
      ret = ret * 256 + bytes[i];
  else
    for (i = len - 1; i >= 0; i--)
      ret = ret * 256 + bytes[i];
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libdax_audioxtr_to_int>:
  endbr64
  and    $0x1,%ecx
  je     L2
  test   %edx,%edx
  jle    L48
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  movzbl (%rsi),%edx
  shl    $0x8,%eax
  add    $0x1,%rsi
  add    %edx,%eax
  cmp    %rsi,%rcx
  jne    L3
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L48
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %eax,%eax
  add    %rsi,%rcx
  lea    -0x2(%rsi,%rdx,1),%rsi
  sub    %rax,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  movzbl (%rcx),%edx
  shl    $0x8,%eax
  sub    $0x1,%rcx
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L7
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned libdax_audioxtr_to_int(struct libdax_audioxtr *o, unsigned char *bytes, int len, int flag) {
  unsigned int ret = 0;
  int i;
  if (flag & 1)
    for (i = 0; i < len; i++)
      ret = ret * 256 + bytes[i];
  else
    for (i = len - 1; i >= 0; i--)
      ret = ret * 256 + bytes[i];
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<index_of_first_difference>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <str_length@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L136
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L25:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L101
  mov    -0xc(%rbp),%eax
  jmp    L90
L101:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L25
  jmp    L90
L136:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L165
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L75:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L106
  mov    -0xc(%rbp),%eax
  jmp    L90
L106:
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L75
  jmp    L90
L165:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L90
  movl   $0x0,-0xc(%rbp)
  jmp    L85
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L15
  mov    -0xc(%rbp),%eax
  jmp    L90
L15:
  addl   $0x1,-0xc(%rbp)
L85:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L9
  mov    $0xffffffff,%eax
  jmp    L90
L90:
  leave
  ret
```

assistant: ```c
int index_of_first_difference(char *s1, char *s2) {
  int i, len1, len2;
  len1 = str_length(s1);
  len2 = str_length(s2);
  if (len1 > len2) {
    for (i = 0; i < len2; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
  } else if (len2 > len1) {
    for (i = 0; i < len1; i++) {
      if (s2[i] != s1[i]) {
        return i;
      }
    }
  } else if (len1 == len2) {
    for (i = 0; i < len1; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
    return (-1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<index_of_first_difference>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <str_length@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <str_length@plt>
  cmp    %eax,%r12d
  jle    L56
  test   %eax,%eax
  jle    L64
  lea    -0x1(%rax),%ecx
  mov    $0x0,%eax
  jmp    L86
L29:
  mov    %rdx,%rax
L86:
  mov    %eax,%edx
  movzbl 0x0(%rbp,%rax,1),%esi
  cmp    %sil,(%rbx,%rax,1)
  jne    L64
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  jne    L29
L64:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  jge    L77
  test   %r12d,%r12d
  jle    L64
  lea    -0x1(%r12),%ecx
  mov    $0x0,%eax
  jmp    L32
L25:
  mov    %rdx,%rax
L32:
  mov    %eax,%edx
  movzbl (%rbx,%rax,1),%edi
  cmp    %dil,0x0(%rbp,%rax,1)
  jne    L64
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  jne    L25
  jmp    L64
L77:
  jne    L64
  test   %r12d,%r12d
  jle    L55
  lea    -0x1(%r12),%ecx
  mov    $0x0,%eax
  jmp    L19
L179:
  mov    %rdx,%rax
L19:
  mov    %eax,%edx
  movzbl 0x0(%rbp,%rax,1),%edi
  cmp    %dil,(%rbx,%rax,1)
  jne    L64
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  jne    L179
  mov    $0xffffffff,%edx
  jmp    L64
L55:
  mov    $0xffffffff,%edx
  jmp    L64
```

assistant: ```c
int index_of_first_difference(char *s1, char *s2) {
  int i, len1, len2;
  len1 = str_length(s1);
  len2 = str_length(s2);
  if (len1 > len2) {
    for (i = 0; i < len2; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
  } else if (len2 > len1) {
    for (i = 0; i < len1; i++) {
      if (s2[i] != s1[i]) {
        return i;
      }
    }
  } else if (len1 == len2) {
    for (i = 0; i < len1; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
    return (-1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<index_of_first_difference>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <str_length@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <str_length@plt>
  cmp    %eax,%r12d
  jle    L48
  test   %eax,%eax
  jle    L126
  cltq
  xor    %edx,%edx
  jmp    L84
  nopl   (%rax)
L86:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L126
L84:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %edx,%r8d
  cmp    %cl,(%rbx,%rdx,1)
  je     L86
L126:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L48:
  jge    L18
  test   %r12d,%r12d
  jle    L126
  xor    %eax,%eax
  jmp    L141
  nopl   0x0(%rax,%rax,1)
L65:
  add    $0x1,%rax
  cmp    %r12,%rax
  je     L126
L141:
  movzbl (%rbx,%rax,1),%esi
  mov    %eax,%r8d
  cmp    %sil,0x0(%rbp,%rax,1)
  je     L65
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L18:
  jne    L126
  test   %r12d,%r12d
  jle    L139
  xor    %eax,%eax
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L118:
  add    $0x1,%rax
  cmp    %r12,%rax
  je     L139
L33:
  movzbl 0x0(%rbp,%rax,1),%edi
  mov    %eax,%r8d
  cmp    %dil,(%rbx,%rax,1)
  je     L118
  jmp    L126
L139:
  mov    $0xffffffff,%r8d
  jmp    L126
```

assistant: ```c
int index_of_first_difference(char *s1, char *s2) {
  int i, len1, len2;
  len1 = str_length(s1);
  len2 = str_length(s2);
  if (len1 > len2) {
    for (i = 0; i < len2; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
  } else if (len2 > len1) {
    for (i = 0; i < len1; i++) {
      if (s2[i] != s1[i]) {
        return i;
      }
    }
  } else if (len1 == len2) {
    for (i = 0; i < len1; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
    return (-1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<index_of_first_difference>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <str_length@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <str_length@plt>
  cmp    %eax,%r12d
  jle    L83
  test   %eax,%eax
  jle    L29
  cltq
  xor    %edx,%edx
  jmp    L57
  nopl   (%rax)
L37:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L29
L57:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %edx,%r8d
  cmp    %cl,(%rbx,%rdx,1)
  je     L37
L29:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L83:
  jge    L137
  test   %r12d,%r12d
  jle    L29
  xor    %eax,%eax
  jmp    L150
  nopl   0x0(%rax,%rax,1)
L97:
  add    $0x1,%rax
  cmp    %rax,%r12
  je     L29
L150:
  movzbl (%rbx,%rax,1),%esi
  mov    %eax,%r8d
  cmp    %sil,0x0(%rbp,%rax,1)
  je     L97
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L137:
  jne    L29
  test   %r12d,%r12d
  jle    L166
  xor    %eax,%eax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L128:
  add    $0x1,%rax
  cmp    %r12,%rax
  je     L166
L32:
  movzbl 0x0(%rbp,%rax,1),%edi
  mov    %eax,%r8d
  cmp    %dil,(%rbx,%rax,1)
  je     L128
  jmp    L29
L166:
  mov    $0xffffffff,%r8d
  jmp    L29
```

assistant: ```c
int index_of_first_difference(char *s1, char *s2) {
  int i, len1, len2;
  len1 = str_length(s1);
  len2 = str_length(s2);
  if (len1 > len2) {
    for (i = 0; i < len2; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
  } else if (len2 > len1) {
    for (i = 0; i < len1; i++) {
      if (s2[i] != s1[i]) {
        return i;
      }
    }
  } else if (len1 == len2) {
    for (i = 0; i < len1; i++) {
      if (s1[i] != s2[i]) {
        return i;
      }
    }
    return (-1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<difftimespec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    (%rdi),%rax
  mov    0x8(%rdi),%ecx
  mov    (%rsi),%rdx
  mov    0x8(%rsi),%esi
  cmp    %rdx,%rax
  je     L37
  jl     L15
  sub    %rdx,%rax
  mov    %rax,(%rbx)
  sub    %esi,%ecx
  mov    %ecx,0x8(%rbx)
  mov    $0xffffffff,%ebp
  js     L5
L21:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  movq   $0x0,(%rbx)
  sub    %ecx,%esi
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <labs@plt>
  mov    %eax,0x8(%rbx)
  jmp    L21
L15:
  sub    %rax,%rdx
  mov    %rdx,(%rbx)
  sub    %ecx,%esi
  mov    %esi,0x8(%rbx)
  mov    $0x1,%ebp
  jns    L21
  sub    $0x1,%rdx
  mov    %rdx,(%rbx)
  add    $0x3b9aca00,%esi
  mov    %esi,0x8(%rbx)
  jmp    L21
L5:
  sub    $0x1,%rax
  mov    %rax,(%rbx)
  add    $0x3b9aca00,%ecx
  mov    %ecx,0x8(%rbx)
  jmp    L21
```

assistant: ```c
int difftimespec(const struct timespec *ts1, const struct timespec *ts2, struct timespec *ts) {
  const struct timespec _ts1 = *ts1;
  const struct timespec _ts2 = *ts2;
  if (_ts1.tv_sec == _ts2.tv_sec) {
    ts->tv_sec = 0;
    ts->tv_nsec = labs(_ts2.tv_nsec - _ts1.tv_nsec);
    return _ts2.tv_nsec - _ts1.tv_nsec;
  }
  if (_ts1.tv_sec < _ts2.tv_sec) {
    do {
      (ts)->tv_sec = (&_ts2)->tv_sec - (&_ts1)->tv_sec;
      (ts)->tv_nsec = (&_ts2)->tv_nsec - (&_ts1)->tv_nsec;
      if ((ts)->tv_nsec < 0) {
        (ts)->tv_sec--;
        (ts)->tv_nsec += 1000000000L;
      }
    } while (0);
    return 1;
  }
  do {
    (ts)->tv_sec = (&_ts1)->tv_sec - (&_ts2)->tv_sec;
    (ts)->tv_nsec = (&_ts1)->tv_nsec - (&_ts2)->tv_nsec;
    if ((ts)->tv_nsec < 0) {
      (ts)->tv_sec--;
      (ts)->tv_nsec += 1000000000L;
    }
  } while (0);
  return -1;
}
```