ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<UARTDivisorValCompute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  andl   $0x7,-0x1c(%rbp)
  cmpl   $0x5,-0x1c(%rbp)
  je     L26
  cmpl   $0x5,-0x1c(%rbp)
  ja     L101
  cmpl   $0x4,-0x1c(%rbp)
  je     L53
  cmpl   $0x4,-0x1c(%rbp)
  ja     L101
  cmpl   $0x1,-0x1c(%rbp)
  jbe    L10
  cmpl   $0x3,-0x1c(%rbp)
  je     L43
  jmp    L101
L10:
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,-0x4(%rbp)
  jmp    L7
L43:
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,-0x4(%rbp)
  jmp    L7
L53:
  mov    -0x20(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  div    %edi
  mov    %eax,-0x4(%rbp)
  jmp    L7
L26:
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L101:
  nop
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int UARTDivisorValCompute(unsigned int moduleClk, unsigned int baudRate, unsigned int modeFlag, unsigned int mirOverSampRate) {
  (void)mirOverSampRate;
  unsigned int divisorValue = 0;
  modeFlag &= (0x00000007u);
  switch (modeFlag) {
  case ((0x0u)):
  case ((0x1u)):
    divisorValue = (moduleClk) / (16 * baudRate);
    break;
  case ((0x3u)):
    divisorValue = (moduleClk) / (13 * baudRate);
    break;
  case ((0x4u)):
    divisorValue = (moduleClk) / (mirOverSampRate * baudRate);
    break;
  case ((0x5u)):
    divisorValue = 0;
    break;
  default:
    break;
  }
  return divisorValue;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UARTDivisorValCompute>:
  endbr64
  mov    %edx,%r8d
  and    $0x7,%r8d
  cmp    $0x3,%r8d
  je     L38
  mov    %edx,%eax
  and    $0x4,%eax
  jne    L27
  test   $0x6,%dl
  jne    L8
  shl    $0x4,%esi
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  ret
L8:
  ret
L27:
  cmp    $0x4,%r8d
  jne    L19
  imul   %esi,%ecx
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  ret
L19:
  mov    $0x0,%eax
  ret
L38:
  lea    (%rsi,%rsi,2),%eax
  lea    (%rsi,%rax,4),%ecx
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  ret
```

assistant: ```c
unsigned int UARTDivisorValCompute(unsigned int moduleClk, unsigned int baudRate, unsigned int modeFlag, unsigned int mirOverSampRate) {
  (void)mirOverSampRate;
  unsigned int divisorValue = 0;
  modeFlag &= (0x00000007u);
  switch (modeFlag) {
  case ((0x0u)):
  case ((0x1u)):
    divisorValue = (moduleClk) / (16 * baudRate);
    break;
  case ((0x3u)):
    divisorValue = (moduleClk) / (13 * baudRate);
    break;
  case ((0x4u)):
    divisorValue = (moduleClk) / (mirOverSampRate * baudRate);
    break;
  case ((0x5u)):
    divisorValue = 0;
    break;
  default:
    break;
  }
  return divisorValue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTDivisorValCompute>:
  endbr64
  mov    %edx,%r8d
  and    $0x7,%r8d
  cmp    $0x3,%r8d
  je     L21
  mov    %edx,%eax
  and    $0x4,%eax
  jne    L29
  and    $0x6,%edx
  jne    L30
  shl    $0x4,%esi
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  cmp    $0x4,%r8d
  jne    L32
  imul   %esi,%ecx
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  ret
L30:
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    (%rsi,%rsi,2),%eax
  xor    %edx,%edx
  lea    (%rsi,%rax,4),%ecx
  mov    %edi,%eax
  div    %ecx
  ret
```

assistant: ```c
unsigned int UARTDivisorValCompute(unsigned int moduleClk, unsigned int baudRate, unsigned int modeFlag, unsigned int mirOverSampRate) {
  (void)mirOverSampRate;
  unsigned int divisorValue = 0;
  modeFlag &= (0x00000007u);
  switch (modeFlag) {
  case ((0x0u)):
  case ((0x1u)):
    divisorValue = (moduleClk) / (16 * baudRate);
    break;
  case ((0x3u)):
    divisorValue = (moduleClk) / (13 * baudRate);
    break;
  case ((0x4u)):
    divisorValue = (moduleClk) / (mirOverSampRate * baudRate);
    break;
  case ((0x5u)):
    divisorValue = 0;
    break;
  default:
    break;
  }
  return divisorValue;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UARTDivisorValCompute>:
  endbr64
  mov    %edx,%r8d
  and    $0x7,%r8d
  cmp    $0x3,%r8d
  je     L9
  mov    %edx,%eax
  and    $0x4,%eax
  jne    L0
  and    $0x6,%edx
  jne    L30
  shl    $0x4,%esi
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    $0x4,%r8d
  jne    L14
  imul   %esi,%ecx
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  ret
L30:
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  lea    (%rsi,%rsi,2),%eax
  xor    %edx,%edx
  lea    (%rsi,%rax,4),%ecx
  mov    %edi,%eax
  div    %ecx
  ret
```

assistant: ```c
unsigned int UARTDivisorValCompute(unsigned int moduleClk, unsigned int baudRate, unsigned int modeFlag, unsigned int mirOverSampRate) {
  (void)mirOverSampRate;
  unsigned int divisorValue = 0;
  modeFlag &= (0x00000007u);
  switch (modeFlag) {
  case ((0x0u)):
  case ((0x1u)):
    divisorValue = (moduleClk) / (16 * baudRate);
    break;
  case ((0x3u)):
    divisorValue = (moduleClk) / (13 * baudRate);
    break;
  case ((0x4u)):
    divisorValue = (moduleClk) / (mirOverSampRate * baudRate);
    break;
  case ((0x5u)):
    divisorValue = 0;
    break;
  default:
    break;
  }
  return divisorValue;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_42_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_42_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_42_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_42_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_42_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_42_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_42_0_0>:
  endbr64
  and    %esi,%edx
  not    %edx
  and    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_42_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T & S;
  stk2 = ~stk2;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setup_multistage_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ipow@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <calculate_number_of_nodes@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L75
L29:
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L53
L27:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L56
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L5
L56:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L5:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L53:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L75:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L29
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L17:
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0xc(%rbp)
L45:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void setup_multistage_tree(int md, int Nr, int Nh, int *nk) {
  int num_scenarios = ipow(md, Nr);
  int num_nodes = calculate_number_of_nodes(md, Nr, Nh);
  int nodes_in_next_stage;
  int nodes_in_stage = 1;
  int idx = 0;
  for (int kk = 0; kk < Nh; kk++) {
    nodes_in_next_stage = 0;
    for (int ii = 0; ii < nodes_in_stage; ii++) {
      if (kk < Nr) {
        nk[idx + ii] = md;
      } else {
        nk[idx + ii] = 1;
      }
      nodes_in_next_stage += nk[idx + ii];
    }
    idx += nodes_in_stage;
    nodes_in_stage = nodes_in_next_stage;
  }
  for (int ii = 0; ii < nodes_in_stage; ii++) {
    nk[idx + ii] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setup_multistage_tree>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    %rcx,%rbx
  call   <ipow@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <calculate_number_of_nodes@plt>
  mov    $0x0,%esi
  mov    $0x0,%r9d
  mov    $0x1,%r10d
  mov    $0x0,%r11d
  mov    $0x1,%ecx
  test   %r13d,%r13d
  jg     L20
  jmp    L7
L26:
  movslq %eax,%r8
  movl   $0x1,(%rbx,%r8,4)
L88:
  add    (%rdx),%ecx
  add    $0x4,%rdx
  add    $0x1,%eax
  cmp    %edi,%eax
  je     L49
L4:
  cmp    %esi,%ebp
  jle    L26
  movslq %eax,%r8
  mov    %r12d,(%rbx,%r8,4)
  jmp    L88
L49:
  add    %r10d,%r9d
  add    $0x1,%esi
  cmp    %esi,%r13d
  je     L83
  mov    %ecx,%r10d
L20:
  mov    %r11d,%ecx
  test   %r10d,%r10d
  jle    L49
  movslq %r9d,%rax
  lea    (%rbx,%rax,4),%rdx
  mov    %r9d,%eax
  lea    (%r10,%r9,1),%edi
  mov    %r11d,%ecx
  jmp    L4
L83:
  test   %ecx,%ecx
  jle    L19
L7:
  movslq %r9d,%r9
  lea    (%rbx,%r9,4),%rdx
  mov    $0x0,%eax
L78:
  movl   $0x0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L78
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void setup_multistage_tree(int md, int Nr, int Nh, int *nk) {
  int num_scenarios = ipow(md, Nr);
  int num_nodes = calculate_number_of_nodes(md, Nr, Nh);
  int nodes_in_next_stage;
  int nodes_in_stage = 1;
  int idx = 0;
  for (int kk = 0; kk < Nh; kk++) {
    nodes_in_next_stage = 0;
    for (int ii = 0; ii < nodes_in_stage; ii++) {
      if (kk < Nr) {
        nk[idx + ii] = md;
      } else {
        nk[idx + ii] = 1;
      }
      nodes_in_next_stage += nk[idx + ii];
    }
    idx += nodes_in_stage;
    nodes_in_stage = nodes_in_next_stage;
  }
  for (int ii = 0; ii < nodes_in_stage; ii++) {
    nk[idx + ii] = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setup_multistage_tree>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <ipow@plt>
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <calculate_number_of_nodes@plt>
  test   %ebx,%ebx
  jle    L28
  xor    %edi,%edi
  xor    %r8d,%r8d
  mov    $0x1,%edx
  mov    $0x1,%r9d
  lea    0x4(%rbp),%r10
  nopl   0x0(%rax,%rax,1)
L79:
  movslq %r8d,%rcx
  add    %edx,%r8d
  test   %edx,%edx
  jle    L25
  sub    $0x1,%edx
  lea    0x0(%rbp,%rcx,4),%rax
  add    %rcx,%rdx
  cmp    %edi,%r13d
  mov    %r9d,%ecx
  cmovg  %r12d,%ecx
  lea    (%r10,%rdx,4),%rsi
  xor    %edx,%edx
  nopl   (%rax)
L56:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  add    %ecx,%edx
  cmp    %rax,%rsi
  jne    L56
  add    $0x1,%edi
  cmp    %edi,%ebx
  jg     L79
L17:
  test   %edx,%edx
  jle    L65
  add    $0x8,%rsp
  movslq %edx,%rdx
  movslq %r8d,%r8
  xor    %esi,%esi
  pop    %rbx
  lea    0x0(%rbp,%r8,4),%rdi
  shl    $0x2,%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <memset@plt>
L28:
  movl   $0x0,0x0(%rbp)
L65:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  add    $0x1,%edi
  cmp    %edi,%ebx
  jle    L65
  add    $0x1,%edi
  xor    %edx,%edx
  cmp    %edi,%ebx
  jg     L79
  jmp    L17
```

assistant: ```c
void setup_multistage_tree(int md, int Nr, int Nh, int *nk) {
  int num_scenarios = ipow(md, Nr);
  int num_nodes = calculate_number_of_nodes(md, Nr, Nh);
  int nodes_in_next_stage;
  int nodes_in_stage = 1;
  int idx = 0;
  for (int kk = 0; kk < Nh; kk++) {
    nodes_in_next_stage = 0;
    for (int ii = 0; ii < nodes_in_stage; ii++) {
      if (kk < Nr) {
        nk[idx + ii] = md;
      } else {
        nk[idx + ii] = 1;
      }
      nodes_in_next_stage += nk[idx + ii];
    }
    idx += nodes_in_stage;
    nodes_in_stage = nodes_in_next_stage;
  }
  for (int ii = 0; ii < nodes_in_stage; ii++) {
    nk[idx + ii] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L3:
  movl   $0x0,-0x14(%rbp)
  jmp    L27
L48:
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x16(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x2,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  movzwl -0x16(%rbp),%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L27:
  cmpl   $0x0,-0x14(%rbp)
  je     L48
  addl   $0x2,-0x10(%rbp)
L29:
  cmpl   $0x0,-0x10(%rbp)
  je     L3
  mov    -0xc(%rbp),%eax
  lea    0x13eacf17(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = copy11;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 334155543UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  rol    $0x10,%eax
  lea    0x13eacf17(%rax),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = copy11;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 334155543UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x275ac5ad,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = copy11;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 334155543UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x275ac5ad,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = copy11;
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 334155543UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmdline_args_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <cmdline_args_internal@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cmdline_args_ext(int argc, char **argv, struct cmdline_args_info *args_info, struct cmdline_args_params *params) {
  int result;
  result = cmdline_args_internal(argc, argv, args_info, params, 0);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmdline_args_ext>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  call   <cmdline_args_internal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmdline_args_ext(int argc, char **argv, struct cmdline_args_info *args_info, struct cmdline_args_params *params) {
  int result;
  result = cmdline_args_internal(argc, argv, args_info, params, 0);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmdline_args_ext>:
  endbr64
  xor    %r8d,%r8d
  jmp    1050 <cmdline_args_internal@plt>
```

assistant: ```c
int cmdline_args_ext(int argc, char **argv, struct cmdline_args_info *args_info, struct cmdline_args_params *params) {
  int result;
  result = cmdline_args_internal(argc, argv, args_info, params, 0);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmdline_args_ext>:
  endbr64
  xor    %r8d,%r8d
  jmp    1050 <cmdline_args_internal@plt>
```

assistant: ```c
int cmdline_args_ext(int argc, char **argv, struct cmdline_args_info *args_info, struct cmdline_args_params *params) {
  int result;
  result = cmdline_args_internal(argc, argv, args_info, params, 0);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xy1y2_to_xyz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  sub    $0x2000,%eax
  imul   $0x12c,%eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  movzwl (%rdx),%edx
  movzwl %dx,%edx
  sub    %edx,%eax
  imul   $0x6c4,%eax,%eax
  mov    -0x10(%rbp),%rdx
  add    $0x4,%rdx
  movslq %eax,%rcx
  imul   $0x66666667,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x2,%ecx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x4000(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  imul   $0x12c,%ecx,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xy1y2_to_xyz(unsigned short int *xy1y2, signed int *xyz) {
  xyz[0] = ((xy1y2[0] - 8192) * 300);
  xyz[1] = (((xy1y2[1] - xy1y2[2]) * 1732) / 10);
  xyz[2] = (((-xy1y2[2] - xy1y2[2]) + 16384) * 300);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xy1y2_to_xyz>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0x2000,%eax
  imul   $0x12c,%eax,%eax
  mov    %eax,(%rsi)
  movzwl 0x2(%rdi),%eax
  movzwl 0x4(%rdi),%edx
  sub    %edx,%eax
  imul   $0x6c4,%eax,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,0x4(%rsi)
  movzwl 0x4(%rdi),%edx
  mov    %edx,%eax
  neg    %eax
  sub    %edx,%eax
  add    $0x4000,%eax
  imul   $0x12c,%eax,%eax
  mov    %eax,0x8(%rsi)
  ret
```

assistant: ```c
void xy1y2_to_xyz(unsigned short int *xy1y2, signed int *xyz) {
  xyz[0] = ((xy1y2[0] - 8192) * 300);
  xyz[1] = (((xy1y2[1] - xy1y2[2]) * 1732) / 10);
  xyz[2] = (((-xy1y2[2] - xy1y2[2]) + 16384) * 300);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xy1y2_to_xyz>:
  endbr64
  movzwl (%rdi),%eax
  mov    %rsi,%rcx
  sub    $0x2000,%eax
  imul   $0x12c,%eax,%eax
  mov    %eax,(%rsi)
  movzwl 0x4(%rdi),%esi
  movzwl 0x2(%rdi),%eax
  sub    %esi,%eax
  imul   $0x6c4,%eax,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %esi,%eax
  neg    %eax
  mov    %edx,0x4(%rcx)
  sub    %esi,%eax
  add    $0x4000,%eax
  imul   $0x12c,%eax,%eax
  mov    %eax,0x8(%rcx)
  ret
```

assistant: ```c
void xy1y2_to_xyz(unsigned short int *xy1y2, signed int *xyz) {
  xyz[0] = ((xy1y2[0] - 8192) * 300);
  xyz[1] = (((xy1y2[1] - xy1y2[2]) * 1732) / 10);
  xyz[2] = (((-xy1y2[2] - xy1y2[2]) + 16384) * 300);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xy1y2_to_xyz>:
  endbr64
  movzwl (%rdi),%eax
  mov    %rsi,%rcx
  movzwl 0x4(%rdi),%esi
  sub    $0x2000,%eax
  imul   $0x12c,%eax,%eax
  movd   %eax,%xmm0
  movzwl 0x2(%rdi),%eax
  sub    %esi,%eax
  imul   $0x6c4,%eax,%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  mov    %esi,%eax
  neg    %eax
  movd   %edx,%xmm1
  sub    %esi,%eax
  punpckldq %xmm1,%xmm0
  add    $0x4000,%eax
  movq   %xmm0,(%rcx)
  imul   $0x12c,%eax,%eax
  mov    %eax,0x8(%rcx)
  ret
```

assistant: ```c
void xy1y2_to_xyz(unsigned short int *xy1y2, signed int *xyz) {
  xyz[0] = ((xy1y2[0] - 8192) * 300);
  xyz[1] = (((xy1y2[1] - xy1y2[2]) * 1732) / 10);
  xyz[2] = (((-xy1y2[2] - xy1y2[2]) + 16384) * 300);
}
```