ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%rdi
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x28(%rsp),%r12
  call   <puts@plt>
  mov    %r14,%rbx
  mov    %r14,%rbp
  nopl   0x0(%rax)
L25:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L25
  mov    %r14,%rdi
  lea    D22(%rip),%rbp
  call   <hiElm@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D39
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string
name: unpack_data
arguments: tag: D25
type_infered: string

tool: D12: Please input 10 integers for arr[]:

tool: D39: %d

tool: D22: 
%d

tool: D25: 
Elements of arr[] are now:

assistant: ```c
int main() {
  int arr[10], hi, i;
  printf("Please input 10 integers for arr[]:\n");
  for (i = 0; i < 10; i++) {
    scanf("%d", &arr[i]);
  }
  hiElm(arr);
  printf("\nElements of arr[] are now:");
  for (i = 0; i < 10; i++) {
    printf("\n%d", arr[i]);
  }
  getchar();
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%rdi
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x28(%rsp),%r12
  call   <puts@plt>
  mov    %r14,%rbx
  mov    %r14,%rbp
  nopl   0x0(%rax)
L17:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L17
  mov    %r14,%rdi
  lea    D20(%rip),%rbp
  call   <hiElm@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L22:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L22
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D20
type_infered: string
name: parse_data
arguments: tag: D2
type_infered: string

tool: D1: Please input 10 integers for arr[]:

tool: D34: %d

tool: D20: 
%d

tool: D2: 
Elements of arr[] are now:

assistant: ```c
int main() {
  int arr[10], hi, i;
  printf("Please input 10 integers for arr[]:\n");
  for (i = 0; i < 10; i++) {
    scanf("%d", &arr[i]);
  }
  hiElm(arr);
  printf("\nElements of arr[] are now:");
  for (i = 0; i < 10; i++) {
    printf("\n%d", arr[i]);
  }
  getchar();
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ucs4toutf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L66
L10:
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L52
L63:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L27
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x75,%al
  jne    L27
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <do_ucs4toutf8@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x1c(%rbp),%edx
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <s_realloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  call   <snprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <s_free@plt>
  addq   $0x5,-0x10(%rbp)
  jmp    L17
L27:
  mov    -0x1c(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <s_realloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
  nop
L17:
  addq   $0x1,-0x10(%rbp)
L52:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
  mov    -0x18(%rbp),%rax
L66:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %s

assistant: ```c
char *ucs4toutf8(const char *from) {
  if (!from) {
    return NULL;
  }
  char *out = NULL;
  int outlen = 0;
  const char *c;
  for (c = from; *c != '\0'; ++c) {
    char *s;
    if (*c == '\\' && *(c + 1) == 'u') {
      s = do_ucs4toutf8(c);
      out = s_realloc(out, outlen + strlen(s) + 1);
      snprintf(out + outlen, strlen(s) + 1, "%s", s);
      outlen = strlen(out);
      s_free(s);
      c += 5;
    } else {
      out = s_realloc(out, outlen + 2);
      out[outlen] = *c;
      out[outlen + 1] = '\0';
      outlen++;
      continue;
    }
  }
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ucs4toutf8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L4
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
  jmp    L29
L67:
  lea    0x2(%rbp),%esi
  mov    %rbx,%rdi
  call   <s_realloc@plt>
  mov    %rax,%rbx
  movslq %ebp,%rax
  movzbl (%r12),%edx
  mov    %dl,(%rbx,%rax,1)
  movb   $0x0,0x1(%rbx,%rax,1)
  add    $0x1,%ebp
  mov    %r12,%rax
L75:
  lea    0x1(%rax),%r12
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L58
L29:
  cmp    $0x5c,%al
  jne    L67
  cmpb   $0x75,0x1(%r12)
  jne    L67
  mov    %r12,%rdi
  call   <do_ucs4toutf8@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%esi
  mov    %rbx,%rdi
  call   <s_realloc@plt>
  mov    %rax,%rbx
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  movslq %ebp,%rdi
  add    %rbx,%rdi
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r14,%rdi
  call   <s_free@plt>
  lea    0x5(%r12),%rax
  jmp    L75
L4:
  mov    %rdi,%rbx
  jmp    L58
L21:
  mov    $0x0,%ebx
L58:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: %s

assistant: ```c
char *ucs4toutf8(const char *from) {
  if (!from) {
    return NULL;
  }
  char *out = NULL;
  int outlen = 0;
  const char *c;
  for (c = from; *c != '\0'; ++c) {
    char *s;
    if (*c == '\\' && *(c + 1) == 'u') {
      s = do_ucs4toutf8(c);
      out = s_realloc(out, outlen + strlen(s) + 1);
      snprintf(out + outlen, strlen(s) + 1, "%s", s);
      outlen = strlen(out);
      s_free(s);
      c += 5;
    } else {
      out = s_realloc(out, outlen + 2);
      out[outlen] = *c;
      out[outlen + 1] = '\0';
      outlen++;
      continue;
    }
  }
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ucs4toutf8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L29
  movzbl (%rdi),%eax
  mov    %rdi,%r13
  test   %al,%al
  je     L29
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    D2(%rip),%r12
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    0x2(%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <s_realloc@plt>
  mov    %rax,%rbp
  movzbl 0x0(%r13),%eax
  movb   $0x0,0x1(%rbp,%r14,1)
  mov    %al,0x0(%rbp,%r14,1)
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L68
L78:
  movslq %ebx,%r14
  cmp    $0x5c,%al
  jne    L21
  cmpb   $0x75,0x1(%r13)
  jne    L21
  mov    %r13,%rdi
  call   <do_ucs4toutf8@plt>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <s_realloc@plt>
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r15,%rcx
  mov    %r12,%rdx
  lea    0x0(%rbp,%r14,1),%rdi
  lea    0x1(%rax),%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <s_free@plt>
  lea    0x5(%r13),%rax
  lea    0x1(%rax),%r13
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L78
L68:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L29:
  xor    %ebp,%ebp
  jmp    L68
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: %s

assistant: ```c
char *ucs4toutf8(const char *from) {
  if (!from) {
    return NULL;
  }
  char *out = NULL;
  int outlen = 0;
  const char *c;
  for (c = from; *c != '\0'; ++c) {
    char *s;
    if (*c == '\\' && *(c + 1) == 'u') {
      s = do_ucs4toutf8(c);
      out = s_realloc(out, outlen + strlen(s) + 1);
      snprintf(out + outlen, strlen(s) + 1, "%s", s);
      outlen = strlen(out);
      s_free(s);
      c += 5;
    } else {
      out = s_realloc(out, outlen + 2);
      out[outlen] = *c;
      out[outlen + 1] = '\0';
      outlen++;
      continue;
    }
  }
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ucs4toutf8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L43
  movzbl (%rdi),%eax
  mov    %rdi,%r13
  test   %al,%al
  je     L43
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    D0(%rip),%r12
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    0x2(%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <s_realloc@plt>
  mov    %rax,%rbp
  movzbl 0x0(%r13),%eax
  movb   $0x0,0x1(%rbp,%r14,1)
  mov    %al,0x0(%rbp,%r14,1)
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L32
L41:
  movslq %ebx,%r14
  cmp    $0x5c,%al
  jne    L7
  cmpb   $0x75,0x1(%r13)
  jne    L7
  mov    %r13,%rdi
  call   <do_ucs4toutf8@plt>
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x1(%rbx,%rax,1),%esi
  call   <s_realloc@plt>
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r15,%rcx
  mov    %r12,%rdx
  lea    0x0(%rbp,%r14,1),%rdi
  lea    0x1(%rax),%esi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <s_free@plt>
  lea    0x5(%r13),%rax
  lea    0x1(%rax),%r13
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L41
L32:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L43:
  xor    %ebp,%ebp
  jmp    L32
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: %s

assistant: ```c
char *ucs4toutf8(const char *from) {
  if (!from) {
    return NULL;
  }
  char *out = NULL;
  int outlen = 0;
  const char *c;
  for (c = from; *c != '\0'; ++c) {
    char *s;
    if (*c == '\\' && *(c + 1) == 'u') {
      s = do_ucs4toutf8(c);
      out = s_realloc(out, outlen + strlen(s) + 1);
      snprintf(out + outlen, strlen(s) + 1, "%s", s);
      outlen = strlen(out);
      s_free(s);
      c += 5;
    } else {
      out = s_realloc(out, outlen + 2);
      out[outlen] = *c;
      out[outlen + 1] = '\0';
      outlen++;
      continue;
    }
  }
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movl   $0x0,-0x3c(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L7:
  movsd  -0x38(%rbp),%xmm2
  movsd  %xmm2,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <f@plt>
  movq   %xmm0,%rbx
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <df@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movq   D25(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  addl   $0x1,-0x3c(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  ja     L7
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D35
type_guessed: string
name: unpack_data
arguments: data_label: D25
type_guessed: qword
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: {"D22": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D2: x0: 

tool: D35: %d

tool: D25: 9223372036854775807

tool: D13: %f


assistant: ```c
int main() {
  double x0;
  double x1;
  double eps = 1e-6;
  double Dx;
  int i = 0;
  printf("x0: ");
  scanf("%d", &x0);
  do {
    x1 = x0 - f(x0) / df(x0);
    Dx = fabs(x1 - x0);
    x0 = x1;
    i++;
  } while (Dx > eps);
  printf("%f\n", x1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L2:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x20(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
L10:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *p;
  for (p = str; *p != '\0' && maxlen > 0; p++, maxlen--)
    ;
  return (p - str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strnlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  test   %rsi,%rsi
  je     L13
  mov    %rdi,%rax
L29:
  add    $0x1,%rax
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    %rdi,%rdx
  je     L28
  cmpb   $0x0,(%rax)
  jne    L29
L28:
  sub    %rdi,%rax
  ret
L13:
  mov    %rdi,%rax
  jmp    L28
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *p;
  for (p = str; *p != '\0' && maxlen > 0; p++, maxlen--)
    ;
  return (p - str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%rax
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L30:
  cmpb   $0x0,(%rax)
  je     L0
L17:
  add    $0x1,%rax
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    %rdi,%rdx
  jne    L30
L0:
  sub    %rdi,%rax
  ret
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *p;
  for (p = str; *p != '\0' && maxlen > 0; p++, maxlen--)
    ;
  return (p - str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  test   %rsi,%rsi
  je     L12
  mov    %rdi,%rax
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L5:
  cmpb   $0x0,(%rax)
  je     L48
L14:
  add    $0x1,%rax
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    %rdi,%rdx
  jne    L5
L48:
  sub    %rdi,%rax
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t strnlen(const char *str, size_t maxlen) {
  const char *p;
  for (p = str; *p != '\0' && maxlen > 0; p++, maxlen--)
    ;
  return (p - str);
}
```
user: What is the c source code of the assembly code below?

```asm
<greet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L15:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D8: Whats up!

tool: D15: Not implemented

assistant: ```c
void greet(int greeting_code) {
  if (greeting_code == 0) {
    puts("Whats up!");
  } else {
    puts("Not implemented");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<greet>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L10
  lea    D8(%rip),%rdi
  call   <puts@plt>
L5:
  add    $0x8,%rsp
  ret
L10:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D8: Whats up!

tool: D18: Not implemented

assistant: ```c
void greet(int greeting_code) {
  if (greeting_code == 0) {
    puts("Whats up!");
  } else {
    puts("Not implemented");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<greet>:
  endbr64
  test   %edi,%edi
  jne    L0
  lea    D0(%rip),%rdi
  jmp    1050 <puts@plt>
  nopl   0x0(%rax)
L0:
  lea    D14(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: string
name: read_data
arguments: data_label: D14
type: string

tool: D0: Whats up!

tool: D14: Not implemented

assistant: ```c
void greet(int greeting_code) {
  if (greeting_code == 0) {
    puts("Whats up!");
  } else {
    puts("Not implemented");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<greet>:
  endbr64
  test   %edi,%edi
  jne    L9
  lea    D5(%rip),%rdi
  jmp    1050 <puts@plt>
  nopl   0x0(%rax)
L9:
  lea    D0(%rip),%rdi
  jmp    1050 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D0
datatype: string

tool: D5: Whats up!

tool: D0: Not implemented

assistant: ```c
void greet(int greeting_code) {
  if (greeting_code == 0) {
    puts("Whats up!");
  } else {
    puts("Not implemented");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getSumUtil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jg     L20
  mov    -0x38(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L20
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L55
L20:
  mov    -0x38(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L30
  mov    -0x34(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L45
L30:
  mov    $0x0,%eax
  jmp    L55
L45:
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getMid@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%r8d
  mov    -0x38(%rbp),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getSumUtil>
  mov    %eax,%ebx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  lea    (%rax,%rax,1),%r8d
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x38(%rbp),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getSumUtil>
  add    %ebx,%eax
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int getSumUtil(int *st, int ss, int se, int qs, int qe, int si) {
  if (qs <= ss && qe >= se)
    return st[si];
  if (qe < ss || qs > se)
    return 0;
  int mid = getMid(ss, se);
  return getSumUtil(st, ss, mid, qs, qe, si * 2 + 1) + getSumUtil(st, mid + 1, se, qs, qe, si * 2 + 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getSumUtil>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %ecx,%r12d
  mov    %r8d,%r13d
  mov    %r9d,%ebx
  cmp    %esi,%ecx
  jg     L55
  cmp    %edx,%r8d
  jl     L55
  movslq %r9d,%rbx
  mov    (%rdi,%rbx,4),%eax
L1:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  cmp    %r13d,%ebp
  jg     L30
  cmp    %r14d,%r12d
  jg     L30
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <getMid@plt>
  add    %ebx,%ebx
  lea    0x1(%rbx),%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %eax,0xc(%rsp)
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <getSumUtil>
  mov    %eax,%ebp
  mov    0xc(%rsp),%esi
  add    $0x1,%esi
  lea    0x2(%rbx),%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %r14d,%edx
  mov    %r15,%rdi
  call   <getSumUtil>
  add    %ebp,%eax
  jmp    L1
L30:
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
int getSumUtil(int *st, int ss, int se, int qs, int qe, int si) {
  if (qs <= ss && qe >= se)
    return st[si];
  if (qe < ss || qs > se)
    return 0;
  int mid = getMid(ss, se);
  return getSumUtil(st, ss, mid, qs, qe, si * 2 + 1) + getSumUtil(st, mid + 1, se, qs, qe, si * 2 + 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getSumUtil>:
  endbr64
  push   %r15
  mov    %edx,%r11d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  cmp    %edx,%r8d
  setge  0xf(%rsp)
  xor    %r15d,%r15d
  movzbl 0xf(%rsp),%eax
  cmp    %esi,%ecx
  jg     L75
  test   %al,%al
  jne    L37
L75:
  cmp    %ebp,%r13d
  jl     L77
  cmp    %r11d,%r12d
  jg     L77
L33:
  mov    %r11d,%esi
  mov    %ebp,%edi
  mov    %r11d,0x8(%rsp)
  add    %ebx,%ebx
  call   <getMid@plt>
  lea    0x1(%rbx),%r9d
  mov    %ebp,%esi
  mov    %r13d,%r8d
  mov    %eax,%edx
  mov    %r12d,%ecx
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <getSumUtil>
  mov    0x4(%rsp),%edx
  add    $0x2,%ebx
  mov    0x8(%rsp),%r11d
  add    %eax,%r15d
  lea    0x1(%rdx),%ebp
  cmp    %r12d,%ebp
  jl     L43
  cmpb   $0x0,0xf(%rsp)
  jne    L37
L43:
  cmp    %r13d,%ebp
  jle    L33
L77:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L37:
  movslq %ebx,%rbx
  add    (%r14,%rbx,4),%r15d
  jmp    L77
```

assistant: ```c
int getSumUtil(int *st, int ss, int se, int qs, int qe, int si) {
  if (qs <= ss && qe >= se)
    return st[si];
  if (qe < ss || qs > se)
    return 0;
  int mid = getMid(ss, se);
  return getSumUtil(st, ss, mid, qs, qe, si * 2 + 1) + getSumUtil(st, mid + 1, se, qs, qe, si * 2 + 2);
}
```