ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r14
  lea    0x14(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  lea    D57(%rip),%rsi
  call   <sscanf@plt>
  mov    0x14(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L31
  mov    %r13,%rbx
  mov    D59(%rip),%ebp
  mov    $0x0,%r12d
  lea    D32(%rip),%r15
L64:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  movd   %ebp,%xmm2
  addss  (%rbx),%xmm2
  movd   %xmm2,%ebp
  add    $0x1,%r12d
  mov    0x14(%rsp),%eax
  add    $0x4,%rbx
  cmp    %r12d,%eax
  jg     L64
L51:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movd   %ebp,%xmm4
  divss  %xmm0,%xmm4
  movss  %xmm4,0x8(%rsp)
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L12
  mov    %r13,%rax
  mov    %ecx,%edx
  lea    0x0(%r13,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L1:
  movss  (%rax),%xmm1
  subss  0x8(%rsp),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L34:
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %r13,%rdi
  call   <free@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  mov    D59(%rip),%ebp
  jmp    L51
L12:
  pxor   %xmm0,%xmm0
  jmp    L34
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D57
type_guessed: string
name: parse_data
arguments: data_tag: D59
type_guessed: f32
name: parse_data
arguments: data_tag: D32
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string

tool: D0: rb

tool: D57: %d

tool: D59: 0

tool: D32: %f

tool: D38: %f	%f

assistant: ```c
int main(int argc, char *argv[]) {
  float *val;
  int N_VAL;
  FILE *obj;
  int i;
  float avg, sd;
  obj = fopen(argv[1], "rb");
  sscanf(argv[2], "%d", &N_VAL);
  val = (float *)malloc(N_VAL * sizeof(float));
  avg = 0.0;
  sd = 0.0;
  for (i = 0; i < N_VAL; i++) {
    fscanf(obj, "%f", &val[i]);
    avg += val[i];
  }
  avg /= N_VAL;
  fclose(obj);
  for (i = 0; i < N_VAL; i++) {
    sd += (val[i] - avg) * (val[i] - avg);
  }
  sd /= N_VAL;
  sd = sqrt(sd);
  free(val);
  printf("%f\t%f", avg, sd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0x8(%rsi),%rdi
  lea    D36(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    0x10(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  lea    D9(%rip),%rsi
  mov    %rax,%r14
  call   <sscanf@plt>
  mov    0x14(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L66
  pxor   %xmm3,%xmm3
  mov    %r12,%rbx
  lea    D6(%rip),%r13
  xor    %ebp,%ebp
  movd   %xmm3,%r15d
  movaps %xmm3,%xmm2
  nopl   0x0(%rax)
L8:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  movss  %xmm2,0x8(%rsp)
  call   <fscanf@plt>
  mov    0x14(%rsp),%eax
  add    $0x1,%ebp
  add    $0x4,%rbx
  movss  0x8(%rsp),%xmm2
  addss  -0x4(%rbx),%xmm2
  cmp    %ebp,%eax
  jg     L8
L69:
  pxor   %xmm1,%xmm1
  mov    %r14,%rdi
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm2
  movss  %xmm2,0x8(%rsp)
  call   <fclose@plt>
  mov    0x14(%rsp),%ecx
  movss  0x8(%rsp),%xmm2
  test   %ecx,%ecx
  jle    L42
  mov    %ecx,%edx
  mov    %r12,%rax
  movd   %r15d,%xmm0
  lea    (%r12,%rdx,4),%rdx
L62:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  subss  %xmm2,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L62
L60:
  pxor   %xmm1,%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtsi2ss %ecx,%xmm1
  divss  %xmm1,%xmm0
  call   <sqrt@plt>
  mov    %r12,%rdi
  movss  %xmm0,0x8(%rsp)
  call   <free@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  lea    D18(%rip),%rdi
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  pxor   %xmm4,%xmm4
  movd   %xmm4,%r15d
  movaps %xmm4,%xmm2
  jmp    L69
L42:
  movd   %r15d,%xmm0
  jmp    L60
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D36
type_guessed: string
name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D36: rb

tool: D9: %d

tool: D6: %f

tool: D18: %f	%f

assistant: ```c
int main(int argc, char *argv[]) {
  float *val;
  int N_VAL;
  FILE *obj;
  int i;
  float avg, sd;
  obj = fopen(argv[1], "rb");
  sscanf(argv[2], "%d", &N_VAL);
  val = (float *)malloc(N_VAL * sizeof(float));
  avg = 0.0;
  sd = 0.0;
  for (i = 0; i < N_VAL; i++) {
    fscanf(obj, "%f", &val[i]);
    avg += val[i];
  }
  avg /= N_VAL;
  fclose(obj);
  for (i = 0; i < N_VAL; i++) {
    sd += (val[i] - avg) * (val[i] - avg);
  }
  sd /= N_VAL;
  sd = sqrt(sd);
  free(val);
  printf("%f\t%f", avg, sd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sock_sendmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sock_vsendmsg@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sock_sendmsg(struct sock *sock, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = sock_vsendmsg(sock, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_sendmsg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <sock_vsendmsg@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sock_sendmsg(struct sock *sock, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = sock_vsendmsg(sock, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sock_sendmsg>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <sock_vsendmsg@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sock_sendmsg(struct sock *sock, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = sock_vsendmsg(sock, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_sendmsg>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <sock_vsendmsg@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sock_sendmsg(struct sock *sock, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  int ret = sock_vsendmsg(sock, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dsInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%edi
  call   <semaphoreInit@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L38
L25:
  mov    $0x0,%edi
  call   <semaphoreInit@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L38
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <setSize@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setCap@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setReadLock@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setWriteLock@plt>
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
int dsInit(void *mem, int cap) {
  int rsemid, wsemid;
  rsemid = semaphoreInit((0));
  if (rsemid == -1)
    return -1;
  wsemid = semaphoreInit((0));
  if (wsemid == -1)
    return -1;
  setSize(mem, 0);
  setCap(mem, cap);
  setReadLock(mem, rsemid);
  setWriteLock(mem, wsemid);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dsInit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x0,%edi
  call   <semaphoreInit@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L27
  mov    $0x0,%edi
  call   <semaphoreInit@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L13
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <setSize@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <setCap@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setReadLock@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <setWriteLock@plt>
  mov    $0x0,%ebx
L27:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %eax,%ebx
  jmp    L27
```

assistant: ```c
int dsInit(void *mem, int cap) {
  int rsemid, wsemid;
  rsemid = semaphoreInit((0));
  if (rsemid == -1)
    return -1;
  wsemid = semaphoreInit((0));
  if (wsemid == -1)
    return -1;
  setSize(mem, 0);
  setCap(mem, cap);
  setReadLock(mem, rsemid);
  setWriteLock(mem, wsemid);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dsInit>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <semaphoreInit@plt>
  cmp    $0xffffffff,%eax
  je     L29
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <semaphoreInit@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%eax
  je     L29
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <setSize@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <setCap@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <setReadLock@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <setWriteLock@plt>
  xor    %eax,%eax
L19:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int dsInit(void *mem, int cap) {
  int rsemid, wsemid;
  rsemid = semaphoreInit((0));
  if (rsemid == -1)
    return -1;
  wsemid = semaphoreInit((0));
  if (wsemid == -1)
    return -1;
  setSize(mem, 0);
  setCap(mem, cap);
  setReadLock(mem, rsemid);
  setWriteLock(mem, wsemid);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dsInit>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <semaphoreInit@plt>
  cmp    $0xffffffff,%eax
  je     L23
  xor    %edi,%edi
  mov    %eax,%r12d
  call   <semaphoreInit@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%eax
  je     L23
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <setSize@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <setCap@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <setReadLock@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <setWriteLock@plt>
  xor    %eax,%eax
L21:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L23:
  mov    $0xffffffff,%eax
  jmp    L21
```

assistant: ```c
int dsInit(void *mem, int cap) {
  int rsemid, wsemid;
  rsemid = semaphoreInit((0));
  if (rsemid == -1)
    return -1;
  wsemid = semaphoreInit((0));
  if (wsemid == -1)
    return -1;
  setSize(mem, 0);
  setCap(mem, cap);
  setReadLock(mem, rsemid);
  setWriteLock(mem, wsemid);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x10(%rbp)
  movl   $0x8,-0xc(%rbp)
  lea    -0x1c(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <plusOne@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x2,%eax
  je     L29
  lea    D47(%rip),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L10
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L10:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L27
  lea    D55(%rip),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L27:
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D47
type_infered: string
name: parse_data
arguments: label: D46
type_infered: string
name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D55
type_infered: string
name: parse_data
arguments: label: D68
type_infered: string

tool: D47: carry

tool: D46: assert fail: %s


tool: D2: r1[0]

tool: D55: r1[1]

tool: D68: everything is fine!

assistant: ```c
int main(int argc, char *argv[]) {
  int h1[] = {9};
  int h2[] = {8};
  int x;
  int *r1 = plusOne(h1, 1, &x);
  if (!(x == 2)) {
    printf("assert fail: %s\n", "carry");
    exit(-1);
  };
  if (!(r1[0] == 1)) {
    printf("assert fail: %s\n", "r1[0]");
    exit(-1);
  };
  if (!(r1[1] == 0)) {
    printf("assert fail: %s\n", "r1[1]");
    exit(-1);
  };
  printf("everything is fine!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x9,0x4(%rsp)
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rdi
  mov    $0x1,%esi
  call   <plusOne@plt>
  mov    %rax,%rbx
  cmpl   $0x2,(%rsp)
  jne    L0
L63:
  cmpl   $0x1,(%rbx)
  jne    L27
L4:
  cmpl   $0x0,0x4(%rbx)
  jne    L10
L53:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  lea    D26(%rip),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L63
L27:
  lea    D31(%rip),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L4
L10:
  lea    D43(%rip),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L53
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D33
datatype: string
name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D45
datatype: string
name: read_data
arguments: data_label: D31
datatype: string
name: read_data
arguments: data_label: D43
datatype: string

tool: D33: everything is fine!

tool: D26: carry

tool: D45: assert fail: %s


tool: D31: r1[0]

tool: D43: r1[1]

assistant: ```c
int main(int argc, char *argv[]) {
  int h1[] = {9};
  int h2[] = {8};
  int x;
  int *r1 = plusOne(h1, 1, &x);
  if (!(x == 2)) {
    printf("assert fail: %s\n", "carry");
    exit(-1);
  };
  if (!(r1[0] == 1)) {
    printf("assert fail: %s\n", "r1[0]");
    exit(-1);
  };
  if (!(r1[1] == 0)) {
    printf("assert fail: %s\n", "r1[1]");
    exit(-1);
  };
  printf("everything is fine!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rdi
  movl   $0x9,0x4(%rsp)
  call   <plusOne@plt>
  cmpl   $0x2,(%rsp)
  mov    %rax,%rbx
  je     L8
  lea    D57(%rip),%rdi
  lea    D47(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L8:
  cmpl   $0x1,(%rbx)
  je     L37
  lea    D57(%rip),%rdi
  lea    D3(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L37:
  mov    0x4(%rbx),%eax
  test   %eax,%eax
  jne    L33
L49:
  lea    D62(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L33:
  lea    D35(%rip),%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L49
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D57
data_type: string
name: unpack_data
arguments: tag: D47
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string
name: unpack_data
arguments: tag: D62
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string

tool: D57: assert fail: %s


tool: D47: carry

tool: D3: r1[0]

tool: D62: everything is fine!

tool: D35: r1[1]

assistant: ```c
int main(int argc, char *argv[]) {
  int h1[] = {9};
  int h2[] = {8};
  int x;
  int *r1 = plusOne(h1, 1, &x);
  if (!(x == 2)) {
    printf("assert fail: %s\n", "carry");
    exit(-1);
  };
  if (!(r1[0] == 1)) {
    printf("assert fail: %s\n", "r1[0]");
    exit(-1);
  };
  if (!(r1[1] == 0)) {
    printf("assert fail: %s\n", "r1[1]");
    exit(-1);
  };
  printf("everything is fine!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rdi
  movl   $0x9,0x4(%rsp)
  call   <plusOne@plt>
  cmpl   $0x2,(%rsp)
  mov    %rax,%rbx
  je     L31
  lea    D24(%rip),%rdi
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L31:
  cmpl   $0x1,(%rbx)
  je     L37
  lea    D24(%rip),%rdi
  lea    D34(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L37:
  mov    0x4(%rbx),%eax
  test   %eax,%eax
  jne    L25
L32:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L25:
  lea    D45(%rip),%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L32
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string
name: parse_data
arguments: data_label: D26
type_guessed: string
name: parse_data
arguments: data_label: D45
type_guessed: string

tool: D24: assert fail: %s


tool: D8: carry

tool: D34: r1[0]

tool: D26: everything is fine!

tool: D45: r1[1]

assistant: ```c
int main(int argc, char *argv[]) {
  int h1[] = {9};
  int h2[] = {8};
  int x;
  int *r1 = plusOne(h1, 1, &x);
  if (!(x == 2)) {
    printf("assert fail: %s\n", "carry");
    exit(-1);
  };
  if (!(r1[0] == 1)) {
    printf("assert fail: %s\n", "r1[0]");
    exit(-1);
  };
  if (!(r1[1] == 0)) {
    printf("assert fail: %s\n", "r1[1]");
    exit(-1);
  };
  printf("everything is fine!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L48
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L41:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L36:
  cmpl   $0x0,-0x8(%rbp)
  jle    L11
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L41
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int insertSort(int arr[], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    int x = arr[i];
    j = i;
    while (j > 0 && arr[j - 1] > x) {
      arr[j] = arr[j - 1];
      j -= 1;
    }
    arr[j] = x;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertSort>:
  endbr64
  test   %esi,%esi
  jle    L43
  mov    (%rdi),%r8d
  lea    0x4(%rdi),%r10
  mov    $0x0,%r9d
  mov    $0x0,%edx
  jmp    L49
L40:
  mov    %r9d,%edx
L65:
  add    $0x4,%r10
L49:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  cmp    %r9d,%esi
  je     L43
  mov    (%r10),%r8d
  test   %r9d,%r9d
  jle    L40
  mov    %r10,%rax
  mov    %r9d,%edx
L42:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L65
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L42
  jmp    L65
L43:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int insertSort(int arr[], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    int x = arr[i];
    j = i;
    while (j > 0 && arr[j - 1] > x) {
      arr[j] = arr[j - 1];
      j -= 1;
    }
    arr[j] = x;
  }
  return 0;
}
```