ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0xf0(%rsp)
  lea    0x10(%rsp),%rax
  lea    0xf0(%rsp),%rcx
  lea    0xe4(%rsp),%rdi
L23:
  mov    (%rax),%edx
  mov    %edx,%esi
  add    (%rcx),%esi
  mov    %esi,0x4(%rax)
  add    $0x1,%edx
  mov    %edx,0x4(%rcx)
  add    $0x4,%rax
  add    $0x4,%rcx
  cmp    %rdi,%rax
  jne    L23
  movl   $0x36,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  lea    D15(%rip),%rbx
  lea    D3(%rip),%r12
  jmp    L14
L16:
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  mov    %esi,%edx
  add    0xf0(%rsp,%rax,4),%edx
  mov    %r12,%rdi
  call   <printf@plt>
L14:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L16
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x1d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D3
datatype: string

tool: D15: %d

tool: D3: %u %u


assistant: ```c
int main(void) {
  unsigned int numMale[53 + 1], numFemale[53 + 1];
  int year;
  numMale[0] = 0;
  numFemale[0] = 1;
  for (year = 1; year <= 53; year++) {
    numMale[year] = numMale[year - 1] + numFemale[year - 1];
    numFemale[year] = numMale[year - 1] + 1;
  }
  while (1) {
    scanf("%d", &year);
    if (year < 0)
      break;
    printf("%u %u\n", numMale[year], numMale[year] + numFemale[year]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  xor    %ecx,%ecx
  push   %rbp
  push   %rbx
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  lea    0xf4(%rsp),%rsi
  movl   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rax
  movl   $0x1,0xf0(%rsp)
  lea    0xe4(%rsp),%rdi
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x4,%rsi
L14:
  mov    (%rax),%ebx
  add    %edx,%ecx
  add    $0x4,%rax
  mov    %ecx,(%rax)
  lea    0x1(%rbx),%edx
  mov    %edx,(%rsi)
  cmp    %rdi,%rax
  jne    L42
  movl   $0x36,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  lea    D19(%rip),%rbx
  lea    D7(%rip),%r12
  jmp    L19
  nopl   (%rax)
L6:
  mov    0x10(%rsp,%rax,4),%esi
  mov    0xf0(%rsp,%rax,4),%edx
  mov    %r12,%rdi
  add    %esi,%edx
  call   <printf@plt>
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  test   %eax,%eax
  jns    L6
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x1d0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string

tool: D19: %d

tool: D7: %u %u


assistant: ```c
int main(void) {
  unsigned int numMale[53 + 1], numFemale[53 + 1];
  int year;
  numMale[0] = 0;
  numFemale[0] = 1;
  for (year = 1; year <= 53; year++) {
    numMale[year] = numMale[year - 1] + numFemale[year - 1];
    numFemale[year] = numMale[year - 1] + 1;
  }
  while (1) {
    scanf("%d", &year);
    if (year < 0)
      break;
    printf("%u %u\n", numMale[year], numMale[year] + numFemale[year]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%esi
  xor    %ecx,%ecx
  push   %rbp
  push   %rbx
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  mov    $0x1,%eax
  lea    0xf0(%rsp),%rdi
  movl   $0x1,0xf0(%rsp)
  lea    0x10(%rsp),%r8
L29:
  add    %ecx,%eax
  add    $0x1,%ecx
  movslq %esi,%rdx
  mov    %ecx,-0x8(%rdi,%rsi,4)
  add    %eax,%ecx
  movd   %eax,%xmm0
  add    $0x1,%eax
  movd   %ecx,%xmm1
  mov    %eax,-0x4(%rdi,%rsi,4)
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%r8,%rsi,4)
  add    $0x2,%rsi
  cmp    $0x37,%rsi
  jne    L29
  lea    -0x1(%rdx),%eax
  movl   $0x36,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  cltq
  lea    D5(%rip),%rbx
  lea    D9(%rip),%r12
  mov    0x10(%rsp,%rax,4),%ecx
  add    0xf0(%rsp,%rax,4),%ecx
  mov    %ecx,0x10(%rsp,%rdx,4)
  mov    0x10(%rsp,%rax,4),%eax
  add    $0x1,%eax
  mov    %eax,0xf0(%rsp,%rdx,4)
  jmp    L6
  nop
L8:
  mov    0x10(%rsp,%rax,4),%esi
  mov    0xf0(%rsp,%rax,4),%edx
  mov    %r12,%rdi
  add    %esi,%edx
  call   <printf@plt>
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0xc(%rsp),%rax
  test   %eax,%eax
  jns    L8
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x1d0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string

tool: D5: %d

tool: D9: %u %u


assistant: ```c
int main(void) {
  unsigned int numMale[53 + 1], numFemale[53 + 1];
  int year;
  numMale[0] = 0;
  numFemale[0] = 1;
  for (year = 1; year <= 53; year++) {
    numMale[year] = numMale[year - 1] + numFemale[year - 1];
    numFemale[year] = numMale[year - 1] + 1;
  }
  while (1) {
    scanf("%d", &year);
    if (year < 0)
      break;
    printf("%u %u\n", numMale[year], numMale[year] + numFemale[year]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_fullname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %edi,-0x114(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x114(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    -0x120(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x110(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fullname@plt>
  mov    %rax,%rdi
  call   <report_status@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <report_status@plt>
  jmp    L1
L4:
  nop
L1:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void cmd_fullname(int nargs, char **args) {
  char string[256];
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(2);
  report_status(fullname(args[0], string));
  report_status(string);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmd_fullname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L10
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <fullname@plt>
  mov    %rax,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
L10:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_fullname(int nargs, char **args) {
  char string[256];
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(2);
  report_status(fullname(args[0], string));
  report_status(string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_fullname>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L17
  mov    $0x2,%edi
  mov    %rsp,%rbp
  call   <report_count@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <fullname@plt>
  mov    %rax,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
L17:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_fullname(int nargs, char **args) {
  char string[256];
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(2);
  report_status(fullname(args[0], string));
  report_status(string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmd_fullname>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L19
  mov    $0x2,%edi
  mov    %rsp,%rbp
  call   <report_count@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <fullname@plt>
  mov    %rax,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
L19:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cmd_fullname(int nargs, char **args) {
  char string[256];
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(2);
  report_status(fullname(args[0], string));
  report_status(string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<put_dec_full>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%r8d
  shr    $0x4,%r8d
  and    $0xf,%r8d
  mov    %esi,%ecx
  shr    $0x8,%ecx
  and    $0xf,%ecx
  mov    %esi,%edi
  shr    $0xc,%edi
  lea    (%r8,%rcx,1),%edx
  add    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  and    $0xf,%esi
  lea    (%rsi,%rdx,2),%esi
  imul   $0xcd,%esi,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%esi
  add    $0x30,%esi
  mov    %sil,(%rax)
  lea    (%rdi,%rdi,8),%esi
  add    %r8d,%esi
  lea    (%rcx,%rcx,4),%r8d
  add    %r8d,%esi
  add    %esi,%edx
  imul   $0xcd,%edx,%esi
  shr    $0xb,%esi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  lea    (%rsi,%rcx,2),%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%ecx
  shr    $0x7,%ecx
  lea    (%rcx,%rcx,4),%esi
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,0x2(%rax)
  lea    (%rcx,%rdi,4),%ecx
  imul   $0xcd,%ecx,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,0x3(%rax)
  add    $0x30,%edx
  mov    %dl,0x4(%rax)
  add    $0x5,%rax
  ret
```

assistant: ```c
char *put_dec_full(char *buf, unsigned q) {
  unsigned d3, d2, d1, d0;
  d1 = (q >> 4) & 0xf;
  d2 = (q >> 8) & 0xf;
  d3 = (q >> 12);
  d0 = 6 * (d3 + d2 + d1) + (q & 0xf);
  q = (d0 * 0xcd) >> 11;
  d0 = d0 - 10 * q;
  *buf++ = d0 + '0';
  d1 = q + 9 * d3 + 5 * d2 + d1;
  q = (d1 * 0xcd) >> 11;
  d1 = d1 - 10 * q;
  *buf++ = d1 + '0';
  d2 = q + 2 * d2;
  q = (d2 * 0xd) >> 7;
  d2 = d2 - 10 * q;
  *buf++ = d2 + '0';
  d3 = q + 4 * d3;
  q = (d3 * 0xcd) >> 11;
  d3 = d3 - 10 * q;
  *buf++ = d3 + '0';
  *buf++ = q + '0';
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<put_dec_full>:
  endbr64
  mov    %esi,%r8d
  mov    %esi,%ecx
  mov    %rdi,%rax
  mov    %esi,%edi
  shr    $0x4,%r8d
  shr    $0x8,%ecx
  and    $0xf,%esi
  add    $0x5,%rax
  and    $0xf,%ecx
  and    $0xf,%r8d
  shr    $0xc,%edi
  lea    (%r8,%rcx,1),%edx
  add    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rsi,%rdx,2),%esi
  imul   $0xcd,%esi,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%esi
  add    $0x30,%esi
  mov    %sil,-0x5(%rax)
  lea    (%rdi,%rdi,8),%esi
  add    %r8d,%esi
  lea    (%rcx,%rcx,4),%r8d
  add    %r8d,%esi
  add    %esi,%edx
  imul   $0xcd,%edx,%esi
  shr    $0xb,%esi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,-0x4(%rax)
  lea    (%rsi,%rcx,2),%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%ecx
  shr    $0x7,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%rcx,%rdi,4),%ecx
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,-0x3(%rax)
  imul   $0xcd,%ecx,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%esi
  add    $0x30,%edx
  add    %esi,%esi
  mov    %dl,-0x1(%rax)
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x2(%rax)
  ret
```

assistant: ```c
char *put_dec_full(char *buf, unsigned q) {
  unsigned d3, d2, d1, d0;
  d1 = (q >> 4) & 0xf;
  d2 = (q >> 8) & 0xf;
  d3 = (q >> 12);
  d0 = 6 * (d3 + d2 + d1) + (q & 0xf);
  q = (d0 * 0xcd) >> 11;
  d0 = d0 - 10 * q;
  *buf++ = d0 + '0';
  d1 = q + 9 * d3 + 5 * d2 + d1;
  q = (d1 * 0xcd) >> 11;
  d1 = d1 - 10 * q;
  *buf++ = d1 + '0';
  d2 = q + 2 * d2;
  q = (d2 * 0xd) >> 7;
  d2 = d2 - 10 * q;
  *buf++ = d2 + '0';
  d3 = q + 4 * d3;
  q = (d3 * 0xcd) >> 11;
  d3 = d3 - 10 * q;
  *buf++ = d3 + '0';
  *buf++ = q + '0';
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<put_dec_full>:
  endbr64
  mov    %esi,%r8d
  mov    %esi,%ecx
  mov    %rdi,%rax
  mov    %esi,%edi
  shr    $0x4,%r8d
  shr    $0x8,%ecx
  and    $0xf,%esi
  add    $0x5,%rax
  and    $0xf,%ecx
  and    $0xf,%r8d
  shr    $0xc,%edi
  lea    (%r8,%rcx,1),%edx
  add    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rsi,%rdx,2),%esi
  imul   $0xcd,%esi,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%esi
  add    $0x30,%esi
  mov    %sil,-0x5(%rax)
  lea    (%rdi,%rdi,8),%esi
  add    %r8d,%esi
  lea    (%rcx,%rcx,4),%r8d
  add    %r8d,%esi
  add    %esi,%edx
  imul   $0xcd,%edx,%esi
  shr    $0xb,%esi
  lea    (%rsi,%rsi,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,-0x4(%rax)
  lea    (%rsi,%rcx,2),%edx
  lea    (%rdx,%rdx,2),%ecx
  lea    (%rdx,%rcx,4),%ecx
  shr    $0x7,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%rcx,%rdi,4),%ecx
  add    %esi,%esi
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,-0x3(%rax)
  imul   $0xcd,%ecx,%edx
  shr    $0xb,%edx
  lea    (%rdx,%rdx,4),%esi
  add    $0x30,%edx
  add    %esi,%esi
  mov    %dl,-0x1(%rax)
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x2(%rax)
  ret
```

assistant: ```c
char *put_dec_full(char *buf, unsigned q) {
  unsigned d3, d2, d1, d0;
  d1 = (q >> 4) & 0xf;
  d2 = (q >> 8) & 0xf;
  d3 = (q >> 12);
  d0 = 6 * (d3 + d2 + d1) + (q & 0xf);
  q = (d0 * 0xcd) >> 11;
  d0 = d0 - 10 * q;
  *buf++ = d0 + '0';
  d1 = q + 9 * d3 + 5 * d2 + d1;
  q = (d1 * 0xcd) >> 11;
  d1 = d1 - 10 * q;
  *buf++ = d1 + '0';
  d2 = q + 2 * d2;
  q = (d2 * 0xd) >> 7;
  d2 = d2 - 10 * q;
  *buf++ = d2 + '0';
  d3 = q + 4 * d3;
  q = (d3 * 0xcd) >> 11;
  d3 = d3 - 10 * q;
  *buf++ = d3 + '0';
  *buf++ = q + '0';
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cubeByValue@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D17: The original value of number is %d

tool: D8: The new value of number is %d

assistant: ```c
int main(void) {
  int number = 5;
  printf("The original value of number is %d", number);
  number = cubeByValue(number);
  printf("The new value of number is %d", number);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <cubeByValue@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D6: The original value of number is %d

tool: D2: The new value of number is %d

assistant: ```c
int main(void) {
  int number = 5;
  printf("The original value of number is %d", number);
  number = cubeByValue(number);
  printf("The new value of number is %d", number);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <cubeByValue@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D7
data_type: string

tool: D17: The original value of number is %d

tool: D7: The new value of number is %d

assistant: ```c
int main(void) {
  int number = 5;
  printf("The original value of number is %d", number);
  number = cubeByValue(number);
  printf("The new value of number is %d", number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <cubeByValue@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D11: The original value of number is %d

tool: D8: The new value of number is %d

assistant: ```c
int main(void) {
  int number = 5;
  printf("The original value of number is %d", number);
  number = cubeByValue(number);
  printf("The new value of number is %d", number);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L34
L21:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L11:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x2,-0x14(%rbp)
  jle    L11
  addl   $0x1,-0x18(%rbp)
L34:
  cmpl   $0x6,-0x18(%rbp)
  jle    L21
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D6
datatype: string
name: read_data
arguments: data_label: D5
datatype: string

tool: D27: svariancewd

tool: D6: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "svariancewd", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D14(%rip),%r15
  jmp    L32
L12:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L15
L32:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L17:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L17
  jmp    L12
L15:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D14: svariancewd

tool: D23: # c::%s:len=%d


tool: D3: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "svariancewd", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```