ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<dtoa_calcdecimal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r14d
  mov    %edx,0xc(%rsp)
  mov    $0x45,%esi
  call   <index@plt>
  movl   $0x0,0x8(%rsp)
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,0x8(%rsp)
L25:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <index@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L41
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%r15
  sub    %rbx,%r15
  mov    %r12d,%edx
  sub    %r15d,%edx
  lea    0x1(%rbp),%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  test   %r13d,%r13d
  jle    L37
  movslq %r13d,%r13
  movb   $0x30,-0x1(%rbp,%r13,1)
L37:
  mov    0x8(%rsp),%eax
  add    %r15d,%eax
L2:
  mov    0xc(%rsp),%edx
  add    %eax,%edx
  cmp    %r14d,%edx
  jge    L4
  test   %edx,%edx
  jns    L17
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    0x8(%rsp),%eax
  jmp    L2
L17:
  movslq %edx,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  jmp    L4
```

assistant: ```c
int dtoa_calcdecimal(char *p, int str_size, int ndigits) {
  char *e;
  char *o;
  int x;
  int l;
  e = index(p, 'E');
  if (e == NULL)
    x = 0;
  else {
    *e = (char)0;
    x = atoi(e + 1);
  }
  l = strlen(p);
  o = index(p, '.');
  if (o == NULL)
    x += strlen(p);
  else {
    int m = strlen(o);
    memmove(o, o + 1, l - (o - p));
    if (m > 0)
      o[m - 1] = '0';
    x += o - p;
  }
  if ((x + ndigits >= 0) && (x + ndigits < str_size))
    p[x + ndigits] = (char)0;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dtoa_calcdecimal>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  mov    $0x45,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <index@plt>
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
L19:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <index@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r13,%r8
  mov    %r14d,%edx
  lea    0x1(%r13),%rsi
  sub    %r12,%r8
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  sub    %r8d,%edx
  mov    %r8,(%rsp)
  call   <memmove@plt>
  movslq 0xc(%rsp),%rcx
  mov    (%rsp),%r8
  test   %ecx,%ecx
  jle    L22
  movb   $0x30,-0x1(%r13,%rcx,1)
L22:
  lea    (%rbx,%r8,1),%eax
L50:
  add    %eax,%ebp
  js     L37
  cmp    %r15d,%ebp
  jl     L55
L37:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  jmp    L50
```

assistant: ```c
int dtoa_calcdecimal(char *p, int str_size, int ndigits) {
  char *e;
  char *o;
  int x;
  int l;
  e = index(p, 'E');
  if (e == NULL)
    x = 0;
  else {
    *e = (char)0;
    x = atoi(e + 1);
  }
  l = strlen(p);
  o = index(p, '.');
  if (o == NULL)
    x += strlen(p);
  else {
    int m = strlen(o);
    memmove(o, o + 1, l - (o - p));
    if (m > 0)
      o[m - 1] = '0';
    x += o - p;
  }
  if ((x + ndigits >= 0) && (x + ndigits < str_size))
    p[x + ndigits] = (char)0;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dtoa_calcdecimal>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  mov    $0x45,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <index@plt>
  test   %rax,%rax
  je     L53
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
L53:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  mov    %eax,%r14d
  call   <index@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L21
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r13,%r8
  mov    %r14d,%edx
  lea    0x1(%r13),%rsi
  sub    %r12,%r8
  mov    %r13,%rdi
  mov    %eax,0xc(%rsp)
  sub    %r8d,%edx
  mov    %r8,(%rsp)
  call   <memmove@plt>
  movslq 0xc(%rsp),%rcx
  mov    (%rsp),%r8
  test   %ecx,%ecx
  jle    L3
  movb   $0x30,-0x1(%r13,%rcx,1)
L3:
  lea    (%rbx,%r8,1),%eax
L31:
  add    %eax,%ebp
  js     L33
  cmp    %r15d,%ebp
  jl     L43
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  jmp    L31
```

assistant: ```c
int dtoa_calcdecimal(char *p, int str_size, int ndigits) {
  char *e;
  char *o;
  int x;
  int l;
  e = index(p, 'E');
  if (e == NULL)
    x = 0;
  else {
    *e = (char)0;
    x = atoi(e + 1);
  }
  l = strlen(p);
  o = index(p, '.');
  if (o == NULL)
    x += strlen(p);
  else {
    int m = strlen(o);
    memmove(o, o + 1, l - (o - p));
    if (m > 0)
      o[m - 1] = '0';
    x += o - p;
  }
  if ((x + ndigits >= 0) && (x + ndigits < str_size))
    p[x + ndigits] = (char)0;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int a;
  int *q = malloc(sizeof(int));
  *q = 0;
  a = 0;
  foo(&a);
  foo(q);
  assert(a < 2);
  assert(*q < 2);
  assert(a > 1);
  assert(*q > 1);
  assert(a > 0);
  assert(*q > 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <foo@plt>
  mov    %rbx,%rdi
  call   <foo@plt>
  cmpl   $0x1,0x4(%rsp)
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,(%rbx)
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x4(%rsp)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,(%rbx)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x0,0x4(%rsp)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x0,(%rbx)
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int *q = malloc(sizeof(int));
  *q = 0;
  a = 0;
  foo(&a);
  foo(q);
  assert(a < 2);
  assert(*q < 2);
  assert(a > 1);
  assert(*q > 1);
  assert(a > 0);
  assert(*q > 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0x4(%rsp),%rdi
  movl   $0x0,(%rax)
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    %rbx,%rdi
  call   <foo@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  setle  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  setle  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  setg   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  mov    (%rbx),%edx
  xor    %edi,%edi
  test   %edx,%edx
  setg   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int *q = malloc(sizeof(int));
  *q = 0;
  a = 0;
  foo(&a);
  foo(q);
  assert(a < 2);
  assert(*q < 2);
  assert(a > 1);
  assert(*q > 1);
  assert(a > 0);
  assert(*q > 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  lea    0x4(%rsp),%rdi
  movl   $0x0,(%rax)
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
  call   <foo@plt>
  mov    %rbx,%rdi
  call   <foo@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  setle  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  setle  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x4(%rsp)
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  setg   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <assert@plt>
  mov    (%rbx),%edx
  xor    %edi,%edi
  test   %edx,%edx
  setg   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a;
  int *q = malloc(sizeof(int));
  *q = 0;
  a = 0;
  foo(&a);
  foo(q);
  assert(a < 2);
  assert(*q < 2);
  assert(a > 1);
  assert(*q > 1);
  assert(a > 0);
  assert(*q > 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<drawpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpb   $0x0,-0x14(%rbp)
  je     L6
  movb   $0x23,-0xa(%rbp)
  jmp    L5
L6:
  movb   $0x20,-0xa(%rbp)
L5:
  movb   $0x0,-0x9(%rbp)
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdi
  call   <putstring@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void drawpos(char c) {
  char s[2];
  if (c)
    s[0] = '#';
  else
    s[0] = ' ';
  s[1] = 0;
  putstring(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawpos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%dil
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
  add    $0x23,%eax
  mov    %al,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x6(%rsp),%rdi
  call   <putstring@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void drawpos(char c) {
  char s[2];
  if (c)
    s[0] = '#';
  else
    s[0] = ' ';
  s[1] = 0;
  putstring(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<drawpos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%dil
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
  add    $0x23,%eax
  mov    %al,0x6(%rsp)
  call   <putstring@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void drawpos(char c) {
  char s[2];
  if (c)
    s[0] = '#';
  else
    s[0] = ' ';
  s[1] = 0;
  putstring(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawpos>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%dil
  lea    0x6(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
  add    $0x23,%eax
  mov    %al,0x6(%rsp)
  call   <putstring@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void drawpos(char c) {
  char s[2];
  if (c)
    s[0] = '#';
  else
    s[0] = ' ';
  s[1] = 0;
  putstring(s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L25
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isshuixh@plt>
  test   %rax,%rax
  je     L31
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L31:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
L25:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string

tool: D3: %d

tool: D25: Yes


tool: D21: No


assistant: ```c
int main(int argc, char const *argv[]) {
  int num;
  scanf("%d", &num);
  getchar();
  while (num) {
    if (isshuixh(num))
      printf("Yes\n");
    else
      printf("No\n");
    scanf("%d", &num);
    getchar();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L33
  lea    D10(%rip),%r13
  lea    D22(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D23(%rip),%rbx
  jmp    L30
L45:
  mov    %r13,%rdi
  call   <printf@plt>
L57:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L33
L30:
  call   <isshuixh@plt>
  test   %rax,%rax
  je     L45
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L57
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string

tool: D23: %d

tool: D10: No


tool: D22: Yes


assistant: ```c
int main(int argc, char const *argv[]) {
  int num;
  scanf("%d", &num);
  getchar();
  while (num) {
    if (isshuixh(num))
      printf("Yes\n");
    else
      printf("No\n");
    scanf("%d", &num);
    getchar();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L7
  lea    D12(%rip),%r13
  lea    D19(%rip),%r12
  jmp    L55
  nopl   0x0(%rax)
L49:
  mov    %r12,%rdi
  call   <printf@plt>
L0:
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L7
L55:
  call   <isshuixh@plt>
  test   %rax,%rax
  jne    L49
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L0
  xchg   %ax,%ax
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D16: %d

tool: D12: No


tool: D19: Yes


assistant: ```c
int main(int argc, char const *argv[]) {
  int num;
  scanf("%d", &num);
  getchar();
  while (num) {
    if (isshuixh(num))
      printf("Yes\n");
    else
      printf("No\n");
    scanf("%d", &num);
    getchar();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L10
  lea    D19(%rip),%r13
  lea    D0(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L25:
  call   <isshuixh@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L9
  mov    %r13,%rdi
L9:
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jne    L25
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D24: %d

tool: D19: No


tool: D0: Yes


assistant: ```c
int main(int argc, char const *argv[]) {
  int num;
  scanf("%d", &num);
  getchar();
  while (num) {
    if (isshuixh(num))
      printf("Yes\n");
    else
      printf("No\n");
    scanf("%d", &num);
    getchar();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L149
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  jmp    L54
L149:
  mov    $0x0,%eax
L54:
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L119
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L119
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L119
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L42
L122:
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L236
  subq   $0x1,-0x10(%rbp)
L42:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L122
  jmp    L231
L236:
  nop
L231:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L119
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L155
L185:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L135
  subq   $0x1,-0x18(%rbp)
L155:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L185
  jmp    L9
L135:
  nop
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L119
  movq   $0x0,-0x18(%rbp)
L119:
  cmpq   $0x0,-0x18(%rbp)
  je     L164
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L100
L193:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L5
  subq   $0x1,-0x8(%rbp)
L100:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L193
  jmp    L49
L5:
  nop
L49:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L183
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jne    L145
  addq   $0x1,-0x18(%rbp)
  jmp    L183
L145:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L183:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L178
L164:
  lea    D2(%rip),%rax
  mov    %rax,-0x28(%rbp)
L178:
  mov    -0x28(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: .

assistant: ```c
char *dirname(char *path) {
  static const char dot[] = ".";
  char *last_slash;
  last_slash = path != NULL ? strrchr(path, '/') : NULL;
  if (last_slash != NULL && last_slash != path && last_slash[1] == '\0') {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp != path) {
      for (last_slash = runp; (last_slash != path); last_slash--) {
        if (*last_slash == '/')
          break;
      }
      if (*last_slash != '/')
        last_slash = NULL;
    }
  }
  if (last_slash != NULL) {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp == path) {
      if (last_slash == path + 1)
        ++last_slash;
      else
        last_slash = path + 1;
    }
    last_slash[0] = '\0';
  } else
    path = (char *)dot;
  return path;
}
```