ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <read_and_write@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D22: First error, go beyond memory boundaries {%d}


tool: D5: Second error, forget to free memory {%d}


tool: D8: Third error, free memory twice {%d}


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int buff_size = 10;
  int *buff = NULL;
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("First error, go beyond memory boundaries {%d}\n", read_and_write(buff, buff_size + 10, rand()));
  free(buff);
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Second error, forget to free memory {%d}\n", read_and_write(buff, buff_size, rand()));
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Third error, free memory twice {%d}\n", read_and_write(buff, buff_size, rand()));
  free(buff);
  free(buff);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D2
datatype: string

tool: D6: First error, go beyond memory boundaries {%d}


tool: D15: Second error, forget to free memory {%d}


tool: D2: Third error, free memory twice {%d}


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int buff_size = 10;
  int *buff = NULL;
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("First error, go beyond memory boundaries {%d}\n", read_and_write(buff, buff_size + 10, rand()));
  free(buff);
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Second error, forget to free memory {%d}\n", read_and_write(buff, buff_size, rand()));
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Third error, free memory twice {%d}\n", read_and_write(buff, buff_size, rand()));
  free(buff);
  free(buff);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  mov    %eax,%edx
  call   <read_and_write@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D19: First error, go beyond memory boundaries {%d}


tool: D24: Second error, forget to free memory {%d}


tool: D21: Third error, free memory twice {%d}


assistant: ```c
int main(int argc, char *argv[]) {
  srand(time(NULL));
  int buff_size = 10;
  int *buff = NULL;
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("First error, go beyond memory boundaries {%d}\n", read_and_write(buff, buff_size + 10, rand()));
  free(buff);
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Second error, forget to free memory {%d}\n", read_and_write(buff, buff_size, rand()));
  buff = (int *)malloc(sizeof(int) * buff_size);
  printf("Third error, free memory twice {%d}\n", read_and_write(buff, buff_size, rand()));
  free(buff);
  free(buff);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maxDifference>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L17
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L17:
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L23
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maxDifference(int *arr, int ele, int size) {
  int i;
  int maxDiff = 0;
  for (i = 0; i < size; i++) {
    if (maxDiff < (arr[ele] - arr[i]))
      maxDiff = arr[ele] - arr[i];
  }
  return maxDiff;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<maxDifference>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%edx
L0:
  mov    %r8d,%ecx
  sub    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L0
L19:
  mov    %edx,%eax
  ret
L15:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int maxDifference(int *arr, int ele, int size) {
  int i;
  int maxDiff = 0;
  for (i = 0; i < size; i++) {
    if (maxDiff < (arr[ele] - arr[i]))
      maxDiff = arr[ele] - arr[i];
  }
  return maxDiff;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maxDifference>:
  endbr64
  test   %edx,%edx
  jle    L4
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  mov    (%rdi,%rsi,4),%esi
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %esi,%edx
  sub    (%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int maxDifference(int *arr, int ele, int size) {
  int i;
  int maxDiff = 0;
  for (i = 0; i < size; i++) {
    if (maxDiff < (arr[ele] - arr[i]))
      maxDiff = arr[ele] - arr[i];
  }
  return maxDiff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maxDifference>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L43
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  mov    (%rdi,%rsi,4),%edi
  cmp    $0x2,%eax
  jbe    L6
  mov    %edx,%esi
  movd   %edi,%xmm5
  pxor   %xmm2,%xmm2
  mov    %rcx,%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm5,%xmm3
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rcx,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L18:
  movdqu (%rax),%xmm4
  movdqa %xmm3,%xmm0
  add    $0x10,%rax
  psubd  %xmm4,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rsi,%rax
  jne    L18
  movdqa %xmm2,%xmm0
  mov    %edx,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L68
L21:
  movslq %esi,%r8
  mov    %edi,%r10d
  sub    (%rcx,%r8,4),%r10d
  lea    0x0(,%r8,4),%r9
  lea    0x1(%rsi),%r8d
  cmp    %r10d,%eax
  cmovl  %r10d,%eax
  cmp    %r8d,%edx
  jle    L38
  mov    %edi,%r8d
  sub    0x4(%rcx,%r9,1),%r8d
  cmp    %r8d,%eax
  cmovl  %r8d,%eax
  add    $0x2,%esi
  cmp    %esi,%edx
  jle    L38
  sub    0x8(%rcx,%r9,1),%edi
  cmp    %edi,%eax
  cmovl  %edi,%eax
  ret
L43:
  xor    %eax,%eax
L38:
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  ret
L6:
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L21
```

assistant: ```c
int maxDifference(int *arr, int ele, int size) {
  int i;
  int maxDiff = 0;
  for (i = 0; i < size; i++) {
    if (maxDiff < (arr[ele] - arr[i]))
      maxDiff = arr[ele] - arr[i];
  }
  return maxDiff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<canonicalise_item>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: /

assistant: ```c
void canonicalise_item(char *item_name, char *path, int path_len, char **item_p) {
  int newsize;
  char *non_canonicalised_item;
  unsigned long item_name_len = strlen(item_name);
  newsize = (int)(path_len + 1 + item_name_len + 1);
  non_canonicalised_item = malloc(sizeof(char) * (newsize));
  check_malloc((void *)non_canonicalised_item);
  strcpy(non_canonicalised_item, path);
  strcat(non_canonicalised_item, "/");
  strcat(non_canonicalised_item, item_name);
  *item_p = strdup(non_canonicalised_item);
  free(non_canonicalised_item);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<canonicalise_item>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %rcx,%r12
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: /

assistant: ```c
void canonicalise_item(char *item_name, char *path, int path_len, char **item_p) {
  int newsize;
  char *non_canonicalised_item;
  unsigned long item_name_len = strlen(item_name);
  newsize = (int)(path_len + 1 + item_name_len + 1);
  non_canonicalised_item = malloc(sizeof(char) * (newsize));
  check_malloc((void *)non_canonicalised_item);
  strcpy(non_canonicalised_item, path);
  strcat(non_canonicalised_item, "/");
  strcat(non_canonicalised_item, item_name);
  *item_p = strdup(non_canonicalised_item);
  free(non_canonicalised_item);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<canonicalise_item>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: /

assistant: ```c
void canonicalise_item(char *item_name, char *path, int path_len, char **item_p) {
  int newsize;
  char *non_canonicalised_item;
  unsigned long item_name_len = strlen(item_name);
  newsize = (int)(path_len + 1 + item_name_len + 1);
  non_canonicalised_item = malloc(sizeof(char) * (newsize));
  check_malloc((void *)non_canonicalised_item);
  strcpy(non_canonicalised_item, path);
  strcat(non_canonicalised_item, "/");
  strcat(non_canonicalised_item, item_name);
  *item_p = strdup(non_canonicalised_item);
  free(non_canonicalised_item);
}
```
user: What is the c source code of the assembly code below:

```asm
<canonicalise_item>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <check_malloc@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <free@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: /

assistant: ```c
void canonicalise_item(char *item_name, char *path, int path_len, char **item_p) {
  int newsize;
  char *non_canonicalised_item;
  unsigned long item_name_len = strlen(item_name);
  newsize = (int)(path_len + 1 + item_name_len + 1);
  non_canonicalised_item = malloc(sizeof(char) * (newsize));
  check_malloc((void *)non_canonicalised_item);
  strcpy(non_canonicalised_item, path);
  strcat(non_canonicalised_item, "/");
  strcat(non_canonicalised_item, item_name);
  *item_p = strdup(non_canonicalised_item);
  free(non_canonicalised_item);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edi
  call   <user_byte@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x6,-0x8(%rbp)
  jmp    L92
L109:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L41
  cmp    $0x2,%eax
  jg     L107
  test   %eax,%eax
  je     L30
  cmp    $0x1,%eax
  je     L18
  jmp    L107
L30:
  addl   $0x2,-0x14(%rbp)
  jmp    L13
L18:
  addl   $0x1,-0x14(%rbp)
  jmp    L13
L41:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L90
  mov    $0x1,%eax
  jmp    L21
L107:
  mov    $0x0,%eax
  jmp    L21
L90:
  nop
L13:
  subl   $0x2,-0x8(%rbp)
L92:
  cmpl   $0x0,-0x8(%rbp)
  jns    L109
  mov    $0x0,%eax
L21:
  leave
  ret
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0)
        return true;
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%r12d
  call   <user_byte@plt>
  mov    %eax,%ebp
  mov    $0x6,%ebx
  jmp    L6
L69:
  add    $0x2,%r12d
L4:
  sub    $0x2,%ebx
  cmp    $0xfffffffe,%ebx
  je     L67
L6:
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L46
  cmp    $0x2,%eax
  je     L23
  test   %eax,%eax
  je     L69
  mov    $0x0,%eax
L71:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  add    $0x1,%r12d
  jmp    L4
L23:
  lea    0x1(%r12),%r13d
  mov    %r12d,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  je     L12
  mov    %r13d,%r12d
  jmp    L4
L67:
  mov    $0x0,%eax
  jmp    L71
L12:
  mov    $0x1,%eax
  jmp    L71
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0)
        return true;
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r13
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x8,%rsp
  call   <user_byte@plt>
  mov    %ebx,%ecx
  mov    %eax,%ebp
  mov    %ebp,%edx
  sar    %cl,%edx
  and    $0x3,%edx
  cmp    $0x1,%edx
  je     L34
L63:
  cmp    $0x2,%edx
  je     L15
  test   %edx,%edx
  je     L5
L67:
  xor    %eax,%eax
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x2,%r12d
L25:
  sub    $0x2,%ebx
  cmp    $0xfffffffe,%ebx
  je     L67
  mov    %ebp,%edx
  mov    %ebx,%ecx
  sar    %cl,%edx
  and    $0x3,%edx
  cmp    $0x1,%edx
  jne    L63
L34:
  add    $0x1,%r12d
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r12d,%edi
  lea    0x1(%r12),%r13d
  call   <user_byte@plt>
  test   %eax,%eax
  je     L42
  mov    %r13d,%r12d
  jmp    L25
L42:
  mov    $0x1,%eax
  jmp    L66
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0)
        return true;
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <user_byte@plt>
  mov    %eax,%ebx
  sar    $0x6,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L136
  cmp    $0x2,%eax
  je     L188
  test   %eax,%eax
  je     L25
L212:
  xor    %eax,%eax
L183:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  add    $0x3,%ebp
L23:
  mov    %ebx,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L119
L31:
  cmp    $0x2,%eax
  je     L185
  test   %eax,%eax
  jne    L212
  lea    0x2(%rbp),%r12d
L194:
  mov    %ebx,%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L138
L34:
  cmp    $0x2,%eax
  je     L125
  test   %eax,%eax
  jne    L212
  lea    0x2(%r12),%ebp
L6:
  and    $0x3,%ebx
  cmp    $0x1,%ebx
  je     L212
  cmp    $0x2,%ebx
  jne    L212
  mov    %ebp,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L212
L159:
  mov    $0x1,%eax
  jmp    L183
  nopw   0x0(%rax,%rax,1)
L188:
  mov    %r12d,%edi
  add    $0x2,%ebp
  call   <user_byte@plt>
  test   %eax,%eax
  je     L159
  mov    %ebx,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L31
L119:
  mov    %ebx,%eax
  lea    0x1(%rbp),%r12d
  sar    $0x2,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L34
L138:
  lea    0x1(%r12),%ebp
  jmp    L6
  nopl   0x0(%rax)
L136:
  add    $0x2,%ebp
  jmp    L23
L185:
  mov    %ebp,%edi
  lea    0x1(%rbp),%r12d
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L194
  jmp    L159
  nopl   (%rax)
L125:
  mov    %r12d,%edi
  lea    0x1(%r12),%ebp
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L6
  jmp    L159
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0)
        return true;
      break;
    default:
      return false;
    }
  }
  return false;
}
```