ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<v2s_>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl (%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%rsp)
  movswl 0x2(%rdi),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%esi
  mov    $0x0,%eax
  call   <vcall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void v2s_(vec) short vec[2];
{
  float v[2];
  v[0] = vec[0];
  v[1] = vec[1];
  vcall(v, 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<v2s_>:
  endbr64
  sub    $0x18,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl (%rdi),%eax
  cvtsi2ss %eax,%xmm0
  movswl 0x2(%rdi),%eax
  mov    %rsp,%rdi
  movss  %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  call   <vcall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void v2s_(vec) short vec[2];
{
  float v[2];
  v[0] = vec[0];
  v[1] = vec[1];
  vcall(v, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<v2s_>:
  endbr64
  sub    $0x18,%rsp
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl (%rdi),%eax
  cvtsi2ss %eax,%xmm0
  movswl 0x2(%rdi),%eax
  mov    %rsp,%rdi
  cvtsi2ss %eax,%xmm1
  xor    %eax,%eax
  unpcklps %xmm1,%xmm0
  movlps %xmm0,(%rsp)
  call   <vcall@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void v2s_(vec) short vec[2];
{
  float v[2];
  v[0] = vec[0];
  v[1] = vec[1];
  vcall(v, 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rc4_crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L18
L12:
  mov    $0x0,%eax
  call   <rc4_nextkey@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%edx
  mov    %edx,%esi
  mov    %ecx,%edx
  xor    %esi,%edx
  mov    %dl,(%rax)
L18:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L12
  nop
  nop
  leave
  ret
```

assistant: ```c
void rc4_crypt(unsigned char *stream, int len) {
  while (len--)
    *(stream++) ^= rc4_nextkey();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rc4_crypt>:
  endbr64
  test   %esi,%esi
  je     L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L16:
  mov    $0x0,%eax
  call   <rc4_nextkey@plt>
  add    $0x1,%rbx
  xor    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void rc4_crypt(unsigned char *stream, int len) {
  while (len--)
    *(stream++) ^= rc4_nextkey();
}
```
user: Translate the below assembly code into C programming language:

```asm
<rc4_crypt>:
  endbr64
  test   %esi,%esi
  je     L7
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rc4_nextkey@plt>
  xor    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void rc4_crypt(unsigned char *stream, int len) {
  while (len--)
    *(stream++) ^= rc4_nextkey();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rc4_crypt>:
  endbr64
  test   %esi,%esi
  je     L1
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rc4_nextkey@plt>
  xor    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void rc4_crypt(unsigned char *stream, int len) {
  while (len--)
    *(stream++) ^= rc4_nextkey();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<archive_extract>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa98,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0xa88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %rdi,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <wfile_make_absolute@plt>
  lea    0x600(%rsp),%rdi
  mov    %rbp,%rsi
  call   <wfile_basespec@plt>
  lea    0x200(%rsp),%r13
  mov    %r13,%rdi
  call   <wfile_abstmpnam@plt>
  mov    %r13,%rdi
  call   <wfile_makedir@plt>
  mov    $0x0,%eax
  call   <wfile_get_wd@plt>
  mov    %rax,%rsi
  lea    0x400(%rsp),%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <wfile_set_wd@plt>
  mov    %r12,%rdi
  call   <wfile_ext@plt>
  mov    %eax,%edi
  lea    D15(%rip),%rsi
  call   <stricmp@plt>
  test   %eax,%eax
  jne    L25
  mov    %rsp,%rdx
  lea    0x800(%rsp),%rdi
  mov    %rbp,%rcx
  lea    D26(%rip),%rsi
  call   <sprintf@plt>
L33:
  lea    0x800(%rsp),%rdi
  call   <system@plt>
  lea    0x400(%rsp),%rdi
  call   <wfile_set_wd@plt>
  lea    0x600(%rsp),%rdx
  lea    0x200(%rsp),%rsi
  mov    %rbx,%rdi
  call   <wfile_fullname@plt>
  mov    %rbx,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  jne    L39
L7:
  mov    0xa88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x1,%eax
  add    $0xa98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    %rsp,%rdx
  lea    0x800(%rsp),%rdi
  mov    %rbp,%rcx
  lea    D39(%rip),%rsi
  call   <sprintf@plt>
  jmp    L33
L39:
  lea    0x800(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <exit@plt>
  jmp    L7
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D39
data_type: string
name: unpack_data
arguments: tag: D36
data_type: string

tool: D15: 7z

tool: D26: 7z -r e "%s" "%s" 1> nul 2> nul

tool: D39: unzip -o -j "%s" "%s" 1> nul 2> nul

tool: D36: Internal error executing command '%s'!


assistant: ```c
int archive_extract(char *archfile, char *file_to_extract, char *tempname) {
  char archname_full[512];
  char tempdir[512];
  char cwd[512];
  char basefile[512];
  char cmd[512 + 128];
  strcpy(archname_full, archfile);
  wfile_make_absolute(archname_full);
  wfile_basespec(basefile, file_to_extract);
  wfile_abstmpnam(tempdir);
  wfile_makedir(tempdir);
  strcpy(cwd, wfile_get_wd());
  wfile_set_wd(tempdir);
  if (!stricmp(wfile_ext(archfile), "7z"))
    sprintf(cmd, "7z -r e \"%s\" \"%s\" 1> nul 2> nul", archname_full, file_to_extract);
  else
    sprintf(cmd, "unzip -o -j \"%s\" \"%s\" 1> nul 2> nul", archname_full, file_to_extract);
  system(cmd);
  wfile_set_wd(cwd);
  wfile_fullname(tempname, tempdir, basefile);
  if (wfile_status(tempname) != 1) {
    printf("Internal error executing command '%s'!\n", cmd);
    exit(10);
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<archive_extract>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x610(%rsp),%r15
  mov    %rdx,%rdi
  mov    %rdx,0x8(%rsp)
  lea    0x210(%rsp),%r12
  lea    0x410(%rsp),%rbx
  call   <strcpy@plt>
  mov    0x8(%rsp),%rdi
  call   <wfile_make_absolute@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <wfile_basespec@plt>
  mov    %r12,%rdi
  call   <wfile_abstmpnam@plt>
  mov    %r12,%rdi
  call   <wfile_makedir@plt>
  xor    %eax,%eax
  call   <wfile_get_wd@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <wfile_set_wd@plt>
  mov    %r14,%rdi
  lea    0x810(%rsp),%r14
  call   <wfile_ext@plt>
  lea    D36(%rip),%rsi
  mov    %eax,%edi
  call   <stricmp@plt>
  mov    0x8(%rsp),%rdx
  mov    %r13,%rcx
  test   %eax,%eax
  jne    L14
  lea    D7(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
L29:
  mov    %r14,%rdi
  call   <system@plt>
  mov    %rbx,%rdi
  call   <wfile_set_wd@plt>
  mov    %rbp,%rdi
  mov    %r15,%rdx
  mov    %r12,%rsi
  call   <wfile_fullname@plt>
  mov    %rbp,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  je     L27
  lea    D24(%rip),%rdi
  mov    %r14,%rsi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <exit@plt>
L27:
  mov    0xa98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xaa8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  lea    D19(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  jmp    L29
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D36
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string

tool: D36: 7z

tool: D7: 7z -r e "%s" "%s" 1> nul 2> nul

tool: D24: Internal error executing command '%s'!


tool: D19: unzip -o -j "%s" "%s" 1> nul 2> nul

assistant: ```c
int archive_extract(char *archfile, char *file_to_extract, char *tempname) {
  char archname_full[512];
  char tempdir[512];
  char cwd[512];
  char basefile[512];
  char cmd[512 + 128];
  strcpy(archname_full, archfile);
  wfile_make_absolute(archname_full);
  wfile_basespec(basefile, file_to_extract);
  wfile_abstmpnam(tempdir);
  wfile_makedir(tempdir);
  strcpy(cwd, wfile_get_wd());
  wfile_set_wd(tempdir);
  if (!stricmp(wfile_ext(archfile), "7z"))
    sprintf(cmd, "7z -r e \"%s\" \"%s\" 1> nul 2> nul", archname_full, file_to_extract);
  else
    sprintf(cmd, "unzip -o -j \"%s\" \"%s\" 1> nul 2> nul", archname_full, file_to_extract);
  system(cmd);
  wfile_set_wd(cwd);
  wfile_fullname(tempname, tempdir, basefile);
  if (wfile_status(tempname) != 1) {
    printf("Internal error executing command '%s'!\n", cmd);
    exit(10);
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isIntCL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isLongCL@plt>
  test   %rax,%rax
  je     L10
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jl     L0
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jg     L0
  mov    $0x1,%eax
  jmp    L31
L0:
  mov    $0x0,%eax
  jmp    L31
L10:
  mov    $0x0,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int isIntCL(char *input, int isVerbose) {
  if (isLongCL(input, isVerbose)) {
    char *end;
    long number = strtol(input, &end, 0);
    return INT_MIN <= number && number <= INT_MAX;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isIntCL>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <isLongCL@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  mov    D7(%rip),%rcx
  cmp    %rdx,(%rcx)
  jg     L7
  mov    D17(%rip),%rax
  cmp    %rdx,(%rax)
  setge  %al
  movzbl %al,%eax
  jmp    L7
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isIntCL(char *input, int isVerbose) {
  if (isLongCL(input, isVerbose)) {
    char *end;
    long number = strtol(input, &end, 0);
    return INT_MIN <= number && number <= INT_MAX;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isIntCL>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <isLongCL@plt>
  test   %rax,%rax
  jne    L19
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    D15(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L27
  mov    D1(%rip),%rdx
  xor    %r12d,%r12d
  cmp    %rax,(%rdx)
  setge  %r12b
  jmp    L27
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isIntCL(char *input, int isVerbose) {
  if (isLongCL(input, isVerbose)) {
    char *end;
    long number = strtol(input, &end, 0);
    return INT_MIN <= number && number <= INT_MAX;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isIntCL>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <isLongCL@plt>
  test   %rax,%rax
  jne    L20
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strtol@plt>
  mov    D17(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L3
  mov    D13(%rip),%rdx
  xor    %r12d,%r12d
  cmp    %rax,(%rdx)
  setge  %r12b
  jmp    L3
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isIntCL(char *input, int isVerbose) {
  if (isLongCL(input, isVerbose)) {
    char *end;
    long number = strtol(input, &end, 0);
    return INT_MIN <= number && number <= INT_MAX;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xf8(%rbp)
  movl   $0x0,-0xf4(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L22
L41:
  mov    -0xf8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0xf8(%rbp),%eax
  cltq
  mov    %dl,-0xf0(%rbp,%rax,1)
  addl   $0x1,-0xf8(%rbp)
L22:
  mov    -0xf8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L0
  mov    -0xf8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L41
L0:
  addl   $0x1,-0xf8(%rbp)
  jmp    L42
L50:
  mov    -0xf8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0xf4(%rbp),%eax
  cltq
  mov    %dl,-0xb0(%rbp,%rax,1)
  addl   $0x1,-0xf4(%rbp)
  addl   $0x1,-0xf8(%rbp)
L42:
  mov    -0xf8(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L50
  mov    -0xf8(%rbp),%eax
  cltq
  movb   $0x0,-0xf0(%rbp,%rax,1)
  mov    -0xf4(%rbp),%eax
  cltq
  movb   $0x0,-0xb0(%rbp,%rax,1)
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D15
data_type: string

tool: D11: Por favor, digite nome e sobrenome: 

tool: D15: Sobre nome: %s

assistant: ```c
main() {
  char nome_completo[100];
  char nome[50];
  char sobrenome[50];
  int i = 0, j = 0;
  puts("Por favor, digite nome e sobrenome: ");
  gets(nome_completo);
  while ((nome_completo[i] != ' ') && (nome_completo[i] != '\0')) {
    nome[i] = nome_completo[i];
    i++;
  }
  i++;
  while (nome_completo[i] != '\0') {
    sobrenome[j] = nome_completo[i];
    j++;
    i++;
  }
  nome[i] = '\0';
  sobrenome[j] = '\0';
  printf("Sobre nome: %s", sobrenome);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    0x40(%rsp),%rdi
  call   <gets@plt>
  testb  $0xdf,0x40(%rsp)
  je     L13
  mov    $0x1,%eax
L8:
  mov    %eax,%ecx
  movzbl 0x40(%rsp,%rax,1),%edx
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L8
L33:
  lea    0x1(%rcx),%eax
  cltq
  movzbl 0x40(%rsp,%rax,1),%edx
  test   %dl,%dl
  je     L6
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdi
  movslq %ecx,%rcx
  lea    0x40(%rsp,%rcx,1),%rsi
L58:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L58
L44:
  movslq %ecx,%rcx
  movb   $0x0,(%rsp,%rcx,1)
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0xb8,%rsp
  ret
L13:
  mov    $0x0,%ecx
  jmp    L33
L6:
  mov    $0x0,%ecx
  jmp    L44
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D12
type: string

tool: D1: Por favor, digite nome e sobrenome: 

tool: D12: Sobre nome: %s

assistant: ```c
main() {
  char nome_completo[100];
  char nome[50];
  char sobrenome[50];
  int i = 0, j = 0;
  puts("Por favor, digite nome e sobrenome: ");
  gets(nome_completo);
  while ((nome_completo[i] != ' ') && (nome_completo[i] != '\0')) {
    nome[i] = nome_completo[i];
    i++;
  }
  i++;
  while (nome_completo[i] != '\0') {
    sobrenome[j] = nome_completo[i];
    j++;
    i++;
  }
  nome[i] = '\0';
  sobrenome[j] = '\0';
  printf("Sobre nome: %s", sobrenome);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbx
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  testb  $0xdf,0x40(%rsp)
  je     L11
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L54:
  movzbl (%rbx,%rax,1),%edx
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0xdf,%edx
  jne    L54
L67:
  lea    0x1(%rcx),%eax
  cltq
  movzbl 0x40(%rsp,%rax,1),%edx
  test   %dl,%dl
  je     L25
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
  add    %rcx,%rbx
  xchg   %ax,%ax
L34:
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  jne    L34
L47:
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  xor    %ecx,%ecx
  jmp    L67
L25:
  xor    %ecx,%ecx
  jmp    L47
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string

tool: D13: Por favor, digite nome e sobrenome: 

tool: D19: Sobre nome: %s

assistant: ```c
main() {
  char nome_completo[100];
  char nome[50];
  char sobrenome[50];
  int i = 0, j = 0;
  puts("Por favor, digite nome e sobrenome: ");
  gets(nome_completo);
  while ((nome_completo[i] != ' ') && (nome_completo[i] != '\0')) {
    nome[i] = nome_completo[i];
    i++;
  }
  i++;
  while (nome_completo[i] != '\0') {
    sobrenome[j] = nome_completo[i];
    j++;
    i++;
  }
  nome[i] = '\0';
  sobrenome[j] = '\0';
  printf("Sobre nome: %s", sobrenome);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rdi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbx
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  testb  $0xdf,0x40(%rsp)
  je     L68
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl (%rbx,%rax,1),%edx
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0xdf,%edx
  jne    L45
L28:
  lea    0x1(%rcx),%eax
  cltq
  movzbl 0x40(%rsp,%rax,1),%edx
  test   %dl,%dl
  je     L19
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
  add    %rcx,%rbx
  xchg   %ax,%ax
L8:
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  jne    L8
L64:
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L68:
  xor    %ecx,%ecx
  jmp    L28
L19:
  xor    %ecx,%ecx
  jmp    L64
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string

tool: D10: Por favor, digite nome e sobrenome: 

tool: D19: Sobre nome: %s

assistant: ```c
main() {
  char nome_completo[100];
  char nome[50];
  char sobrenome[50];
  int i = 0, j = 0;
  puts("Por favor, digite nome e sobrenome: ");
  gets(nome_completo);
  while ((nome_completo[i] != ' ') && (nome_completo[i] != '\0')) {
    nome[i] = nome_completo[i];
    i++;
  }
  i++;
  while (nome_completo[i] != '\0') {
    sobrenome[j] = nome_completo[i];
    j++;
    i++;
  }
  nome[i] = '\0';
  sobrenome[j] = '\0';
  printf("Sobre nome: %s", sobrenome);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_systemcall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D0: cmd_cfgread 

tool: D5: %s

assistant: ```c
void print_systemcall(char *para, char *data, int len) {
  int i = 0;
  unsigned char *value;
  data[len] = '\0';
  printf("cmd_cfgread \n");
  printf("%s", data);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_systemcall>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  movslq %edx,%rdx
  movb   $0x0,(%rsi,%rdx,1)
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D13: cmd_cfgread 

tool: D5: %s

assistant: ```c
void print_systemcall(char *para, char *data, int len) {
  int i = 0;
  unsigned char *value;
  data[len] = '\0';
  printf("cmd_cfgread \n");
  printf("%s", data);
}
```