ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L28
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  jmp    L23
  nopl   0x0(%rax)
L30:
  mov    0x0(%rbp),%eax
  add    $0x1,%r12d
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L46
L23:
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L30
L46:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  xor    %r12d,%r12d
  jmp    L46
```

assistant: ```c
int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue >= 0) {
      *intValue = (*intValue << 4) | hexValue;
      numChars++;
    } else
      break;
    (*ptr)++;
  }
  return (numChars);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L31
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  jmp    L29
  nopl   0x0(%rax)
L3:
  mov    0x0(%rbp),%eax
  add    $0x1,%r12d
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L46
L29:
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jns    L3
L46:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  xor    %r12d,%r12d
  jmp    L46
```

assistant: ```c
int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue >= 0) {
      *intValue = (*intValue << 4) | hexValue;
      numChars++;
    } else
      break;
    (*ptr)++;
  }
  return (numChars);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<double_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int double_cmp(const void *a, const void *b) {
  const double *fa = a, *fb = b;
  const double ret = *fa - *fb;
  return (ret > 0) - (ret < 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<double_cmp>:
  endbr64
  movsd  (%rdi),%xmm0
  subsd  (%rsi),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int double_cmp(const void *a, const void *b) {
  const double *fa = a, *fb = b;
  const double ret = *fa - *fb;
  return (ret > 0) - (ret < 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<double_cmp>:
  endbr64
  movsd  (%rdi),%xmm0
  subsd  (%rsi),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int double_cmp(const void *a, const void *b) {
  const double *fa = a, *fb = b;
  const double ret = *fa - *fb;
  return (ret > 0) - (ret < 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<double_cmp>:
  endbr64
  movsd  (%rdi),%xmm0
  subsd  (%rsi),%xmm0
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int double_cmp(const void *a, const void *b) {
  const double *fa = a, *fb = b;
  const double ret = *fa - *fb;
  return (ret > 0) - (ret < 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x60(%rbp)
  cmpq   $0x0,-0x60(%rbp)
  jne    L65
  mov    $0x0,%eax
  jmp    L56
L65:
  mov    -0x60(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x58(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L56
L49:
  lea    -0x50(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x58(%rbp),%rax
  mov    %eax,%edx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <canvasGetFormat@plt>
  test   %rax,%rax
  je     L2
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L56
L2:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L56:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string
name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D27
type_infered: string

tool: D0: Content-Type: text/plain;charset=us-ascii


tool: D9: NB

tool: D13: 0

tool: D27: %s

assistant: ```c
int main(int argc, char **argv) {
  printf("Content-Type: text/plain;charset=us-ascii\n\n");
  char *value = NULL;
  long number = 0;
  value = getenv("NB");
  if (!value)
    return 0;
  number = strtol(value, NULL, 0);
  if (!number)
    return 0;
  char buffer[64];
  memset(buffer, 0, 64);
  if (canvasGetFormat((int)number, buffer)) {
    printf("0\n");
    return 0;
  }
  printf("%s", buffer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L50
L7:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  mov    %rsp,%rbp
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <canvasGetFormat@plt>
  test   %rax,%rax
  jne    L24
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L24:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D35
datatype: string
name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D6
datatype: string

tool: D35: Content-Type: text/plain;charset=us-ascii


tool: D11: NB

tool: D27: %s

tool: D6: 0

assistant: ```c
int main(int argc, char **argv) {
  printf("Content-Type: text/plain;charset=us-ascii\n\n");
  char *value = NULL;
  long number = 0;
  value = getenv("NB");
  if (!value)
    return 0;
  number = strtol(value, NULL, 0);
  if (!number)
    return 0;
  char buffer[64];
  memset(buffer, 0, 64);
  if (canvasGetFormat((int)number, buffer)) {
    printf("0\n");
    return 0;
  }
  printf("%s", buffer);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L49
  mov    %rax,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L55
L49:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L55:
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <canvasGetFormat@plt>
  test   %rax,%rax
  jne    L7
  mov    %rbp,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
L7:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D24
type_infered: string
name: retrieve_data
arguments: data_label: D38
type_infered: string
name: retrieve_data
arguments: data_label: D28
type_infered: string

tool: D23: Content-Type: text/plain;charset=us-ascii


tool: D24: NB

tool: D38: %s

tool: D28: 0

assistant: ```c
int main(int argc, char **argv) {
  printf("Content-Type: text/plain;charset=us-ascii\n\n");
  char *value = NULL;
  long number = 0;
  value = getenv("NB");
  if (!value)
    return 0;
  number = strtol(value, NULL, 0);
  if (!number)
    return 0;
  char buffer[64];
  memset(buffer, 0, 64);
  if (canvasGetFormat((int)number, buffer)) {
    printf("0\n");
    return 0;
  }
  printf("%s", buffer);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L11
L14:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    $0x40,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <canvasGetFormat@plt>
  test   %rax,%rax
  jne    L23
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
L23:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L14
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D34
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D28
type: string

tool: D26: Content-Type: text/plain;charset=us-ascii


tool: D34: NB

tool: D6: %s

tool: D28: 0

assistant: ```c
int main(int argc, char **argv) {
  printf("Content-Type: text/plain;charset=us-ascii\n\n");
  char *value = NULL;
  long number = 0;
  value = getenv("NB");
  if (!value)
    return 0;
  number = strtol(value, NULL, 0);
  if (!number)
    return 0;
  char buffer[64];
  memset(buffer, 0, 64);
  if (canvasGetFormat((int)number, buffer)) {
    printf("0\n");
    return 0;
  }
  printf("%s", buffer);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<bit_ones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bit_set@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void bit_ones(uint32_t *bitmap, int bits) {
  int i;
  for (i = 0; i < bits; i++)
    bit_set(bitmap, i, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bit_ones>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
L1:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <bit_set@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

assistant: ```c
void bit_ones(uint32_t *bitmap, int bits) {
  int i;
  for (i = 0; i < bits; i++)
    bit_set(bitmap, i, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bit_ones>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%ebp
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void bit_ones(uint32_t *bitmap, int bits) {
  int i;
  for (i = 0; i < bits; i++)
    bit_set(bitmap, i, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bit_ones>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%ebp
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void bit_ones(uint32_t *bitmap, int bits) {
  int i;
  for (i = 0; i < bits; i++)
    bit_set(bitmap, i, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yesno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int yesno(const char *fmt, ...) {
  assert(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yesno>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yesno(const char *fmt, ...) {
  assert(0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yesno>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yesno(const char *fmt, ...) {
  assert(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yesno>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yesno(const char *fmt, ...) {
  assert(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hlr_strcpysFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jge    L7
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'

assistant: ```c
char *hlr_strcpysFunc(char *to, char *from, int toLengthMax) {
  if (strlen(from) > toLengthMax)
    die("hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'", toLengthMax, strlen(from), from);
  strcpy(to, from);
  return to;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hlr_strcpysFunc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L17
L16:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <die@plt>
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'

assistant: ```c
char *hlr_strcpysFunc(char *to, char *from, int toLengthMax) {
  if (strlen(from) > toLengthMax)
    die("hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'", toLengthMax, strlen(from), from);
  strcpy(to, from);
  return to;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hlr_strcpysFunc>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L16
L1:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    %r13d,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  call   <die@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'

assistant: ```c
char *hlr_strcpysFunc(char *to, char *from, int toLengthMax) {
  if (strlen(from) > toLengthMax)
    die("hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'", toLengthMax, strlen(from), from);
  strcpy(to, from);
  return to;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hlr_strcpysFunc>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L13
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    %r13d,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  call   <die@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'

assistant: ```c
char *hlr_strcpysFunc(char *to, char *from, int toLengthMax) {
  if (strlen(from) > toLengthMax)
    die("hlr_strcpys: overflow: toLengthMax=%d, strlen(from)=%d, from='%.50s...'", toLengthMax, strlen(from), from);
  strcpy(to, from);
  return to;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Row_Transformation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  je     L53
  mov    -0x34(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L8:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L8
  jmp    L6
L53:
  mov    -0x34(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L18:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rdx
  movsd  (%rdx),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L18
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Row_Transformation(double *A, double x, int row1, int row2, int ncols) {
  int i;
  double *pA1, *pA2;
  if (row1 != row2) {
    pA1 = A + row1 * ncols;
    pA2 = A + row2 * ncols;
    for (i = 0; i < ncols; i++)
      *pA2++ += x * *pA1++;
  } else {
    pA1 = A + row1 * ncols;
    for (i = 0; i < ncols; i++)
      *pA1++ += x * *pA1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Row_Transformation>:
  endbr64
  cmp    %edx,%esi
  je     L16
  imul   %ecx,%esi
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rsi
  imul   %ecx,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rdx
  test   %ecx,%ecx
  jle    L23
  mov    %ecx,%ecx
  mov    $0x0,%eax
L32:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  (%rdx,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L32
  ret
L16:
  imul   %ecx,%esi
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rax
  test   %ecx,%ecx
  jle    L23
  mov    %ecx,%ecx
  lea    (%rax,%rcx,8),%rdx
L35:
  add    $0x8,%rax
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  addsd  -0x8(%rax),%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rdx,%rax
  jne    L35
L23:
  ret
```

assistant: ```c
void Row_Transformation(double *A, double x, int row1, int row2, int ncols) {
  int i;
  double *pA1, *pA2;
  if (row1 != row2) {
    pA1 = A + row1 * ncols;
    pA2 = A + row2 * ncols;
    for (i = 0; i < ncols; i++)
      *pA2++ += x * *pA1++;
  } else {
    pA1 = A + row1 * ncols;
    for (i = 0; i < ncols; i++)
      *pA1++ += x * *pA1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Row_Transformation>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%edi
  imul   %ecx,%edi
  movslq %edi,%rdi
  lea    (%rax,%rdi,8),%rdi
  cmp    %edx,%esi
  je     L39
  imul   %ecx,%edx
  movslq %ecx,%rsi
  movslq %edx,%rdx
  lea    (%rax,%rdx,8),%rdx
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L28
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rdx,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L7
  ret
  nopl   (%rax)
L39:
  test   %ecx,%ecx
  jle    L28
  movslq %ecx,%rcx
  movsd  (%rdi),%xmm2
  lea    (%rdi,%rcx,8),%rax
  nop
L14:
  add    $0x8,%rdi
  movapd %xmm2,%xmm3
  movsd  (%rdi),%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rdi,%rax
  jne    L14
L28:
  ret
```

assistant: ```c
void Row_Transformation(double *A, double x, int row1, int row2, int ncols) {
  int i;
  double *pA1, *pA2;
  if (row1 != row2) {
    pA1 = A + row1 * ncols;
    pA2 = A + row2 * ncols;
    for (i = 0; i < ncols; i++)
      *pA2++ += x * *pA1++;
  } else {
    pA1 = A + row1 * ncols;
    for (i = 0; i < ncols; i++)
      *pA1++ += x * *pA1;
  }
}
```