ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<idris_utf8_charlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L74
  mov    $0x1,%eax
  jmp    L83
L74:
  cmpl   $0xf4,-0x4(%rbp)
  jle    L65
  cmpl   $0xff,-0x4(%rbp)
  jle    L75
L65:
  cmpl   $0xc0,-0x4(%rbp)
  je     L75
  cmpl   $0xc1,-0x4(%rbp)
  jne    L51
L75:
  mov    $0x1,%eax
  jmp    L83
L51:
  movl   $0x1,-0x8(%rbp)
  jmp    L50
L35:
  addl   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L35
  mov    -0x8(%rbp),%eax
L83:
  pop    %rbp
  ret
```

assistant: ```c
int idris_utf8_charlen(char *s) {
  int init = (int)s[0];
  if ((init & 0x80) == 0) {
    return 1;
  }
  if ((init > 244 && init < 256) || (init == 192) || (init == 193)) {
    return 1;
  }
  int i = 1;
  while ((s[i] & 0xc0) == 0x80) {
    i++;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<idris_utf8_charlen>:
  endbr64
  mov    $0x1,%ecx
  cmpb   $0x0,(%rdi)
  jns    L38
  movsbl 0x1(%rdi),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  jne    L28
  mov    $0x2,%eax
L35:
  mov    %eax,%ecx
  movsbl (%rdi,%rax,1),%edx
  and    $0xc0,%edx
  add    $0x1,%rax
  cmp    $0x80,%edx
  je     L35
L38:
  mov    %ecx,%eax
  ret
L28:
  mov    $0x1,%ecx
  jmp    L38
```

assistant: ```c
int idris_utf8_charlen(char *s) {
  int init = (int)s[0];
  if ((init & 0x80) == 0) {
    return 1;
  }
  if ((init > 244 && init < 256) || (init == 192) || (init == 193)) {
    return 1;
  }
  int i = 1;
  while ((s[i] & 0xc0) == 0x80) {
    i++;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<idris_utf8_charlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    $0x1,%r8d
  jns    L16
  movsbl 0x1(%rdi),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  jne    L16
  mov    $0x2,%eax
  nopl   0x0(%rax)
L6:
  movsbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L6
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int idris_utf8_charlen(char *s) {
  int init = (int)s[0];
  if ((init & 0x80) == 0) {
    return 1;
  }
  if ((init > 244 && init < 256) || (init == 192) || (init == 193)) {
    return 1;
  }
  int i = 1;
  while ((s[i] & 0xc0) == 0x80) {
    i++;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<idris_utf8_charlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    $0x1,%r8d
  jns    L17
  movsbl 0x1(%rdi),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  jne    L17
  mov    $0x2,%eax
  nopl   0x0(%rax)
L23:
  movsbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L23
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int idris_utf8_charlen(char *s) {
  int init = (int)s[0];
  if ((init & 0x80) == 0) {
    return 1;
  }
  if ((init > 244 && init < 256) || (init == 192) || (init == 193)) {
    return 1;
  }
  int i = 1;
  while ((s[i] & 0xc0) == 0x80) {
    i++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<safestrcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  jmp    L18
L19:
  nop
L25:
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
L2:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L18:
  pop    %rbp
  ret
```

assistant: ```c
char *safestrcpy(char *s, const char *t, size_t n) {
  char *os = s;
  if (n <= 0)
    return os;
  while (--n > 0 && (*s++ = *t++) != 0)
    ;
  *s = 0;
  return os;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<safestrcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L21
  lea    -0x1(%rsi,%rdx,1),%r8
  mov    %rdi,%rdx
L22:
  cmp    %r8,%rsi
  je     L27
  add    $0x1,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rsi),%ecx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  jne    L22
L27:
  movb   $0x0,(%rdx)
L21:
  ret
```

assistant: ```c
char *safestrcpy(char *s, const char *t, size_t n) {
  char *os = s;
  if (n <= 0)
    return os;
  while (--n > 0 && (*s++ = *t++) != 0)
    ;
  *s = 0;
  return os;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<safestrcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L28
  lea    -0x1(%rsi,%rdx,1),%r8
  mov    %rdi,%rdx
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L13:
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  je     L29
L23:
  cmp    %r8,%rsi
  jne    L13
L29:
  movb   $0x0,(%rdx)
L28:
  ret
```

assistant: ```c
char *safestrcpy(char *s, const char *t, size_t n) {
  char *os = s;
  if (n <= 0)
    return os;
  while (--n > 0 && (*s++ = *t++) != 0)
    ;
  *s = 0;
  return os;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<safestrcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L26
  lea    -0x1(%rsi,%rdx,1),%r8
  mov    %rdi,%rdx
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L37:
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  je     L8
L12:
  cmp    %r8,%rsi
  jne    L37
L8:
  movb   $0x0,(%rdx)
L26:
  ret
```

assistant: ```c
char *safestrcpy(char *s, const char *t, size_t n) {
  char *os = s;
  if (n <= 0)
    return os;
  while (--n > 0 && (*s++ = *t++) != 0)
    ;
  *s = 0;
  return os;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_ble8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t read_ble8(const void *src) {
  const uint8_t *s = src;
  return *s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_ble8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t read_ble8(const void *src) {
  const uint8_t *s = src;
  return *s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_ble8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t read_ble8(const void *src) {
  const uint8_t *s = src;
  return *s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_ble8>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
uint8_t read_ble8(const void *src) {
  const uint8_t *s = src;
  return *s;
}
```
user: What is the c source code of the assembly code below:

```asm
<cg_dot>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%r8
  pxor   %xmm1,%xmm1
  test   %rdx,%rdx
  jle    L11
  movabs $0x6666666666666667,%rdx
  mov    %r8,%rax
  imul   %rdx
  sar    %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %r8,%rdx
  sub    %rax,%rdx
  test   %rdx,%rdx
  jle    L2
  pxor   %xmm1,%xmm1
  mov    $0x0,%edi
L27:
  movsd  (%rcx,%rdi,8),%xmm0
  mulsd  (%rsi,%rdi,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  jne    L27
  cmp    %rdx,%r8
  jle    L11
L40:
  movsd  (%rcx,%rdx,8),%xmm0
  mulsd  (%rsi,%rdx,8),%xmm0
  movsd  0x8(%rcx,%rdx,8),%xmm2
  mulsd  0x8(%rsi,%rdx,8),%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x10(%rcx,%rdx,8),%xmm2
  mulsd  0x10(%rsi,%rdx,8),%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x18(%rcx,%rdx,8),%xmm2
  mulsd  0x18(%rsi,%rdx,8),%xmm2
  addsd  %xmm2,%xmm0
  movsd  0x20(%rcx,%rdx,8),%xmm2
  mulsd  0x20(%rsi,%rdx,8),%xmm2
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x5,%rdx
  cmp    %rdx,%r8
  jg     L40
L11:
  movapd %xmm1,%xmm0
  ret
L2:
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  jmp    L40
```

assistant: ```c
double cg_dot(double *x, double *y, long int n) {
  long int i, n5;
  double t;
  t = ((double)0);
  if (n <= 0)
    return (t);
  n5 = n % 5;
  for (i = 0; i < n5; i++)
    t += x[i] * y[i];
  for (; i < n; i += 5) {
    t += x[i] * y[i] + x[i + 1] * y[i + 1] + x[i + 2] * y[i + 2] + x[i + 3] * y[i + 3] + x[i + 4] * y[i + 4];
  }
  return (t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cg_dot>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%r8
  pxor   %xmm2,%xmm2
  test   %rdx,%rdx
  jle    L27
  mov    %r8,%rax
  pxor   %xmm2,%xmm2
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %r8,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %r8,%rdx
  sub    %rax,%rdx
  je     L26
  xor    %edi,%edi
L18:
  movsd  (%rcx,%rdi,8),%xmm0
  mulsd  (%rsi,%rdi,8),%xmm0
  add    $0x1,%rdi
  addsd  %xmm0,%xmm2
  cmp    %rdi,%rdx
  jne    L18
  cmp    %rdx,%r8
  jle    L27
  nopw   0x0(%rax,%rax,1)
L26:
  movsd  (%rcx,%rdx,8),%xmm0
  movsd  0x8(%rcx,%rdx,8),%xmm1
  mulsd  (%rsi,%rdx,8),%xmm0
  mulsd  0x8(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rcx,%rdx,8),%xmm1
  mulsd  0x10(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x18(%rcx,%rdx,8),%xmm1
  mulsd  0x18(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x20(%rcx,%rdx,8),%xmm1
  mulsd  0x20(%rsi,%rdx,8),%xmm1
  add    $0x5,%rdx
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  cmp    %rdx,%r8
  jg     L26
L27:
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double cg_dot(double *x, double *y, long int n) {
  long int i, n5;
  double t;
  t = ((double)0);
  if (n <= 0)
    return (t);
  n5 = n % 5;
  for (i = 0; i < n5; i++)
    t += x[i] * y[i];
  for (; i < n; i += 5) {
    t += x[i] * y[i] + x[i + 1] * y[i + 1] + x[i + 2] * y[i + 2] + x[i + 3] * y[i + 3] + x[i + 4] * y[i + 4];
  }
  return (t);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cg_dot>:
  endbr64
  mov    %rdi,%rcx
  pxor   %xmm2,%xmm2
  mov    %rdx,%rdi
  test   %rdx,%rdx
  jle    L54
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  je     L60
  cmp    $0x1,%rdx
  je     L26
  movupd (%rcx),%xmm0
  movupd (%rsi),%xmm3
  pxor   %xmm2,%xmm2
  mov    %rdx,%rax
  shr    %rax
  mulpd  %xmm3,%xmm0
  addsd  %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm2
  cmp    $0x2,%rax
  je     L13
  cmp    $0x2,%rdx
  je     L51
  mov    $0x2,%eax
L1:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  %xmm0,%xmm2
  jmp    L51
  nopl   (%rax)
L42:
  movsd  (%rcx,%rdx,8),%xmm0
  movsd  0x8(%rcx,%rdx,8),%xmm1
  mulsd  (%rsi,%rdx,8),%xmm0
  mulsd  0x8(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rcx,%rdx,8),%xmm1
  mulsd  0x10(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x18(%rcx,%rdx,8),%xmm1
  mulsd  0x18(%rsi,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x20(%rcx,%rdx,8),%xmm1
  mulsd  0x20(%rsi,%rdx,8),%xmm1
  add    $0x5,%rdx
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
L51:
  cmp    %rdx,%rdi
  jg     L42
L54:
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L13:
  movupd 0x10(%rsi),%xmm0
  movupd 0x10(%rcx),%xmm4
  mulpd  %xmm4,%xmm0
  movapd %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  jmp    L51
  nopl   0x0(%rax)
L60:
  pxor   %xmm2,%xmm2
  jmp    L42
L26:
  pxor   %xmm2,%xmm2
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
double cg_dot(double *x, double *y, long int n) {
  long int i, n5;
  double t;
  t = ((double)0);
  if (n <= 0)
    return (t);
  n5 = n % 5;
  for (i = 0; i < n5; i++)
    t += x[i] * y[i];
  for (; i < n; i += 5) {
    t += x[i] * y[i] + x[i + 1] * y[i + 1] + x[i + 2] * y[i + 2] + x[i + 3] * y[i + 3] + x[i + 4] * y[i + 4];
  }
  return (t);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tokenise@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: select _col1, col2, colC from test      where city = "Auckland" ;

assistant: ```c
int main() {
  char *foo = "select _col1, col2, colC from test      where city = \"Auckland\" ;";
  tokenise(foo);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <tokenise@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: select _col1, col2, colC from test      where city = "Auckland" ;

assistant: ```c
int main() {
  char *foo = "select _col1, col2, colC from test      where city = \"Auckland\" ;";
  tokenise(foo);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <tokenise@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: select _col1, col2, colC from test      where city = "Auckland" ;

assistant: ```c
int main() {
  char *foo = "select _col1, col2, colC from test      where city = \"Auckland\" ;";
  tokenise(foo);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <tokenise@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: select _col1, col2, colC from test      where city = "Auckland" ;

assistant: ```c
int main() {
  char *foo = "select _col1, col2, colC from test      where city = \"Auckland\" ;";
  tokenise(foo);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pr_SL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  jmp    L14
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L14:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D17: SL:ACAS inoperative


tool: D18: SL:ACAS operating at sensitivity level:%d


assistant: ```c
void pr_SL(FILE *fp, uint8_t SL) {
  if (SL == 0)
    fprintf(fp, "SL:ACAS inoperative\n");
  else
    fprintf(fp, "SL:ACAS operating at sensitivity level:%d\n", SL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pr_SL>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L13
  mov    %rdi,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <fwrite@plt>
L0:
  add    $0x8,%rsp
  ret
L13:
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D15: SL:ACAS inoperative


tool: D2: SL:ACAS operating at sensitivity level:%d


assistant: ```c
void pr_SL(FILE *fp, uint8_t SL) {
  if (SL == 0)
    fprintf(fp, "SL:ACAS inoperative\n");
  else
    fprintf(fp, "SL:ACAS operating at sensitivity level:%d\n", SL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pr_SL>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  jne    L1
  mov    %rdi,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  jmp    1070 <fwrite@plt>
  nopl   (%rax)
L1:
  lea    D15(%rip),%rsi
  xor    %eax,%eax
  jmp    1060 <fprintf@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D8: SL:ACAS inoperative


tool: D15: SL:ACAS operating at sensitivity level:%d


assistant: ```c
void pr_SL(FILE *fp, uint8_t SL) {
  if (SL == 0)
    fprintf(fp, "SL:ACAS inoperative\n");
  else
    fprintf(fp, "SL:ACAS operating at sensitivity level:%d\n", SL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pr_SL>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  jne    L4
  mov    %rdi,%rcx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  jmp    1070 <fwrite@plt>
  nopl   (%rax)
L4:
  lea    D10(%rip),%rsi
  xor    %eax,%eax
  jmp    1060 <fprintf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D18: SL:ACAS inoperative


tool: D10: SL:ACAS operating at sensitivity level:%d


assistant: ```c
void pr_SL(FILE *fp, uint8_t SL) {
  if (SL == 0)
    fprintf(fp, "SL:ACAS inoperative\n");
  else
    fprintf(fp, "SL:ACAS operating at sensitivity level:%d\n", SL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<last_dig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x2,%eax
  add    %edx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  lea    (%rcx,%rax,1),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L15
L18:
  mov    -0x4(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int last_dig(int *egn) {
  int eq = 0;
  eq = ((2 * egn[0]) + (4 * egn[1]) + (8 * egn[2]) + (5 * egn[3]) + (10 * egn[4]) + (9 * egn[5]) + (7 * egn[6]) + (3 * egn[7]) + (6 * egn[8])) % 11;
  if (eq == 10)
    return 0;
  return eq;
}
```
user: Translate the below assembly code into C programming language:

```asm
<last_dig>:
  endbr64
  mov    0x4(%rdi),%ecx
  mov    (%rdi),%edx
  lea    (%rdx,%rcx,2),%edx
  mov    0x8(%rdi),%ecx
  lea    (%rdx,%rcx,4),%ecx
  mov    0xc(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    0x10(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rcx,%rdx,2),%edx
  mov    0x14(%rdi),%ecx
  lea    (%rcx,%rcx,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rdi),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rdi),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  mov    0x20(%rdi),%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rdx,%rax,2),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int last_dig(int *egn) {
  int eq = 0;
  eq = ((2 * egn[0]) + (4 * egn[1]) + (8 * egn[2]) + (5 * egn[3]) + (10 * egn[4]) + (9 * egn[5]) + (7 * egn[6]) + (3 * egn[7]) + (6 * egn[8])) % 11;
  if (eq == 10)
    return 0;
  return eq;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<last_dig>:
  endbr64
  mov    0x4(%rdi),%ecx
  mov    (%rdi),%edx
  mov    0x20(%rdi),%eax
  lea    (%rdx,%rcx,2),%edx
  mov    0x8(%rdi),%ecx
  lea    (%rax,%rax,2),%eax
  lea    (%rdx,%rcx,4),%ecx
  mov    0xc(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    0x10(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rcx,%rdx,2),%edx
  mov    0x14(%rdi),%ecx
  lea    (%rcx,%rcx,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rdi),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rdi),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  lea    (%rdx,%rax,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int last_dig(int *egn) {
  int eq = 0;
  eq = ((2 * egn[0]) + (4 * egn[1]) + (8 * egn[2]) + (5 * egn[3]) + (10 * egn[4]) + (9 * egn[5]) + (7 * egn[6]) + (3 * egn[7]) + (6 * egn[8])) % 11;
  if (eq == 10)
    return 0;
  return eq;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<last_dig>:
  endbr64
  mov    0x4(%rdi),%ecx
  mov    (%rdi),%edx
  mov    0x20(%rdi),%eax
  lea    (%rdx,%rcx,2),%edx
  mov    0x8(%rdi),%ecx
  lea    (%rax,%rax,2),%eax
  lea    (%rdx,%rcx,4),%ecx
  mov    0xc(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rcx,2),%ecx
  mov    0x10(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rcx,%rdx,2),%edx
  mov    0x14(%rdi),%ecx
  lea    (%rcx,%rcx,8),%ecx
  add    %ecx,%edx
  mov    0x18(%rdi),%ecx
  lea    (%rdx,%rcx,8),%edx
  sub    %ecx,%edx
  mov    0x1c(%rdi),%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%edx
  lea    (%rdx,%rax,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int last_dig(int *egn) {
  int eq = 0;
  eq = ((2 * egn[0]) + (4 * egn[1]) + (8 * egn[2]) + (5 * egn[3]) + (10 * egn[4]) + (9 * egn[5]) + (7 * egn[6]) + (3 * egn[7]) + (6 * egn[8])) % 11;
  if (eq == 10)
    return 0;
  return eq;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L9
L3:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rdi
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  mov    %rdi,%rdx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L3
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Recv(int socket, void *buffer, socklen_t size, int flag) {
  void *ptr = buffer;
  int received = 0, bytes = -1;
  while ((bytes = recv(socket, ptr, size - received, flag)) > 0) {
    received += bytes;
    ptr += bytes;
  }
  return received;
}
```