ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D15(%rip),%rbx
  lea    0x14(%rbx),%r12
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D15
type: string

tool: D14: %d 

tool: D15: 

assistant: ```c
void f() {
  static const unsigned a[5] = {1, 2, 3, 4, 5};
  for (int i = 0; i < 5; i++) {
    int b[1] = {0};
    printf("%d ", a[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<charToLettre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0xf,%eax
  ja     L85
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x30,%eax
  jmp    L85
  mov    $0x31,%eax
  jmp    L85
  mov    $0x32,%eax
  jmp    L85
  mov    $0x33,%eax
  jmp    L85
  mov    $0x34,%eax
  jmp    L85
  mov    $0x35,%eax
  jmp    L85
  mov    $0x36,%eax
  jmp    L85
  mov    $0x37,%eax
  jmp    L85
  mov    $0x38,%eax
  jmp    L85
  mov    $0x39,%eax
  jmp    L85
  mov    $0x61,%eax
  jmp    L85
  mov    $0x62,%eax
  jmp    L85
  mov    $0x63,%eax
  jmp    L85
  mov    $0x64,%eax
  jmp    L85
  mov    $0x65,%eax
  jmp    L85
  mov    $0x66,%eax
  jmp    L85
L85:
  pop    %rbp
  ret
```

assistant: ```c
char charToLettre(char valeur) {
  switch (valeur) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'a';
    break;
  case 11:
    return 'b';
    break;
  case 12:
    return 'c';
  case 13:
    return 'd';
    break;
  case 14:
    return 'e';
    break;
  case 15:
    return 'f';
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<charToLettre>:
  endbr64
  cmp    $0xf,%dil
  ja     L9
  movzbl %dil,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x61,%eax
  ret
  mov    $0x62,%eax
  ret
  mov    $0x63,%eax
  ret
  mov    $0x64,%eax
  ret
  mov    $0x65,%eax
  ret
  mov    $0x66,%eax
  ret
L9:
  ret
  mov    $0x30,%eax
  ret
  mov    $0x32,%eax
  ret
```

assistant: ```c
char charToLettre(char valeur) {
  switch (valeur) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'a';
    break;
  case 11:
    return 'b';
    break;
  case 12:
    return 'c';
  case 13:
    return 'd';
    break;
  case 14:
    return 'e';
    break;
  case 15:
    return 'f';
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<charToLettre>:
  endbr64
  cmp    $0xf,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D7(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
char charToLettre(char valeur) {
  switch (valeur) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'a';
    break;
  case 11:
    return 'b';
    break;
  case 12:
    return 'c';
  case 13:
    return 'd';
    break;
  case 14:
    return 'e';
    break;
  case 15:
    return 'f';
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<charToLettre>:
  endbr64
  cmp    $0xf,%dil
  ja     L0
  movzbl %dil,%edi
  lea    D6(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
char charToLettre(char valeur) {
  switch (valeur) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'a';
    break;
  case 11:
    return 'b';
    break;
  case 12:
    return 'c';
  case 13:
    return 'd';
    break;
  case 14:
    return 'e';
    break;
  case 15:
    return 'f';
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SU_Centered>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fNewMemory@plt>
  test   %rax,%rax
  je     L78
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L41
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl -0x30(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L41:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  movl   $0x0,-0x1c(%rbp)
  jmp    L66
L46:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L66:
  mov    -0x20(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L46
  jmp    L40
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl -0x30(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L40:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L80
L78:
  mov    $0x0,%eax
L80:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
char *SU_Centered(char *The_String, int In_The_Width, char With_The_Filler) {
  int Left_Margin;
  int Right_Margin;
  int i;
  int j;
  char *Centered_String;
  ;
  if (fNewMemory((void **)&Centered_String, In_The_Width + 1)) {
    Left_Margin = (In_The_Width - (int)strlen(The_String)) / 2;
    Right_Margin = (int)strlen(The_String) + Left_Margin;
    for (i = 0; i < Left_Margin; i++) {
      Centered_String[i] = With_The_Filler;
    }
    j = 0;
    for (i = i; i < Right_Margin; i++) {
      Centered_String[i] = The_String[j++];
    }
    for (i = i; i < In_The_Width; i++) {
      Centered_String[i] = With_The_Filler;
    }
    Centered_String[i] = '\0';
    return Centered_String;
  } else
    return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SU_Centered>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsi),%esi
  mov    %rsp,%rdi
  call   <fNewMemory@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L53
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebp,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  lea    (%rdx,%rax,1),%esi
  cmp    $0x1,%ecx
  jle    L102
  mov    $0x0,%eax
L42:
  mov    (%rsp),%rcx
  mov    %bl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L42
  test   %edx,%edx
  mov    $0x1,%eax
  cmovle %eax,%edx
L89:
  cmp    %edx,%esi
  jle    L54
  movslq %edx,%rcx
  lea    -0x1(%rsi),%eax
  sub    %edx,%eax
  lea    0x1(%rcx,%rax,1),%rdi
  mov    %rcx,%rax
  sub    %rcx,%r12
L12:
  movzbl (%r12,%rax,1),%ecx
  mov    (%rsp),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
L73:
  cmp    %esi,%ebp
  jle    L2
  movslq %esi,%rax
  lea    -0x1(%rbp),%edx
  sub    %esi,%edx
  lea    0x1(%rax,%rdx,1),%rcx
L87:
  mov    (%rsp),%rdx
  mov    %bl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L87
L106:
  movslq %ebp,%rbp
  mov    (%rsp),%rax
  movb   $0x0,(%rax,%rbp,1)
  mov    (%rsp),%rax
L53:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L102:
  mov    $0x0,%edx
  jmp    L89
L54:
  mov    %edx,%esi
  jmp    L73
L2:
  mov    %esi,%ebp
  jmp    L106
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *SU_Centered(char *The_String, int In_The_Width, char With_The_Filler) {
  int Left_Margin;
  int Right_Margin;
  int i;
  int j;
  char *Centered_String;
  ;
  if (fNewMemory((void **)&Centered_String, In_The_Width + 1)) {
    Left_Margin = (In_The_Width - (int)strlen(The_String)) / 2;
    Right_Margin = (int)strlen(The_String) + Left_Margin;
    for (i = 0; i < Left_Margin; i++) {
      Centered_String[i] = With_The_Filler;
    }
    j = 0;
    for (i = i; i < Right_Margin; i++) {
      Centered_String[i] = The_String[j++];
    }
    for (i = i; i < In_The_Width; i++) {
      Centered_String[i] = With_The_Filler;
    }
    Centered_String[i] = '\0';
    return Centered_String;
  } else
    return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SU_Centered>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  add    $0x1,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fNewMemory@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L11
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  lea    (%rdx,%rax,1),%edi
  xor    %eax,%eax
  cmp    $0x1,%ecx
  jle    L60
  nopl   0x0(%rax)
L70:
  mov    (%rsp),%rcx
  mov    %bpl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L70
  mov    $0x1,%eax
  test   %edx,%edx
  cmovle %eax,%edx
  movslq %edx,%rax
L58:
  cmp    %edx,%edi
  jle    L19
  lea    -0x1(%rdi),%ecx
  movslq %edx,%rax
  sub    %edx,%ecx
  sub    %rax,%rbx
  lea    0x1(%rax,%rcx,1),%rsi
  nopl   (%rax)
L84:
  movzbl (%rbx,%rax,1),%ecx
  mov    (%rsp),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L84
  movslq %edi,%rax
L8:
  cmp    %edi,%r12d
  jle    L94
  movslq %edi,%rdx
  lea    -0x1(%r12),%esi
  sub    %edi,%esi
  lea    0x1(%rdx),%rax
  add    %rax,%rsi
  jmp    L29
  nop
L51:
  add    $0x1,%rax
L29:
  mov    (%rsp),%rcx
  mov    %bpl,(%rcx,%rdx,1)
  mov    %rax,%rdx
  cmp    %rsi,%rax
  jne    L51
  movslq %r12d,%rax
L94:
  mov    (%rsp),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    (%rsp),%rax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L77
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L60:
  xor    %edx,%edx
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edx,%edi
  jmp    L8
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *SU_Centered(char *The_String, int In_The_Width, char With_The_Filler) {
  int Left_Margin;
  int Right_Margin;
  int i;
  int j;
  char *Centered_String;
  ;
  if (fNewMemory((void **)&Centered_String, In_The_Width + 1)) {
    Left_Margin = (In_The_Width - (int)strlen(The_String)) / 2;
    Right_Margin = (int)strlen(The_String) + Left_Margin;
    for (i = 0; i < Left_Margin; i++) {
      Centered_String[i] = With_The_Filler;
    }
    j = 0;
    for (i = i; i < Right_Margin; i++) {
      Centered_String[i] = The_String[j++];
    }
    for (i = i; i < In_The_Width; i++) {
      Centered_String[i] = With_The_Filler;
    }
    Centered_String[i] = '\0';
    return Centered_String;
  } else
    return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SU_Centered>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  add    $0x1,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fNewMemory@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L28
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12d,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  lea    (%rdx,%rax,1),%edi
  xor    %eax,%eax
  cmp    $0x1,%ecx
  jle    L1
  nopl   0x0(%rax)
L35:
  mov    (%rsp),%rcx
  mov    %bpl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L35
  mov    $0x1,%eax
  test   %edx,%edx
  cmovle %eax,%edx
  movslq %edx,%rax
L96:
  cmp    %edx,%edi
  jle    L39
  lea    -0x1(%rdi),%ecx
  movslq %edx,%rax
  sub    %edx,%ecx
  sub    %rax,%rbx
  lea    0x1(%rax,%rcx,1),%rsi
  nopl   (%rax)
L2:
  movzbl (%rbx,%rax,1),%ecx
  mov    (%rsp),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
  movslq %edi,%rax
L87:
  cmp    %edi,%r12d
  jle    L34
  movslq %edi,%rdx
  lea    -0x1(%r12),%esi
  sub    %edi,%esi
  lea    0x1(%rdx),%rax
  add    %rax,%rsi
  jmp    L70
  nop
L84:
  add    $0x1,%rax
L70:
  mov    (%rsp),%rcx
  mov    %bpl,(%rcx,%rdx,1)
  mov    %rax,%rdx
  cmp    %rax,%rsi
  jne    L84
  movslq %r12d,%rax
L34:
  mov    (%rsp),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    (%rsp),%rax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L91
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  xor    %edx,%edx
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %edx,%edi
  jmp    L87
L91:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *SU_Centered(char *The_String, int In_The_Width, char With_The_Filler) {
  int Left_Margin;
  int Right_Margin;
  int i;
  int j;
  char *Centered_String;
  ;
  if (fNewMemory((void **)&Centered_String, In_The_Width + 1)) {
    Left_Margin = (In_The_Width - (int)strlen(The_String)) / 2;
    Right_Margin = (int)strlen(The_String) + Left_Margin;
    for (i = 0; i < Left_Margin; i++) {
      Centered_String[i] = With_The_Filler;
    }
    j = 0;
    for (i = i; i < Right_Margin; i++) {
      Centered_String[i] = The_String[j++];
    }
    for (i = i; i < In_The_Width; i++) {
      Centered_String[i] = With_The_Filler;
    }
    Centered_String[i] = '\0';
    return Centered_String;
  } else
    return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<generate_traps_h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <generate_trap_h@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <generate_trap_h@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xe,%esi
  mov    %rax,%rdi
  call   <generate_trap_h@plt>
  nop
  leave
  ret
```

assistant: ```c
void generate_traps_h(const char *path) {
  generate_trap_h(path, 1);
  generate_trap_h(path, 13);
  generate_trap_h(path, 14);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<generate_traps_h>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%esi
  call   <generate_trap_h@plt>
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <generate_trap_h@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <generate_trap_h@plt>
  pop    %rbx
  ret
```

assistant: ```c
void generate_traps_h(const char *path) {
  generate_trap_h(path, 1);
  generate_trap_h(path, 13);
  generate_trap_h(path, 14);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate_traps_h>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <generate_trap_h@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  call   <generate_trap_h@plt>
  mov    %rbp,%rdi
  mov    $0xe,%esi
  pop    %rbp
  jmp    1050 <generate_trap_h@plt>
```

assistant: ```c
void generate_traps_h(const char *path) {
  generate_trap_h(path, 1);
  generate_trap_h(path, 13);
  generate_trap_h(path, 14);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generate_traps_h>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <generate_trap_h@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  call   <generate_trap_h@plt>
  mov    %rbp,%rdi
  mov    $0xe,%esi
  pop    %rbp
  jmp    1050 <generate_trap_h@plt>
```

assistant: ```c
void generate_traps_h(const char *path) {
  generate_trap_h(path, 1);
  generate_trap_h(path, 13);
  generate_trap_h(path, 14);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copyImage2To32>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rcx
  mov    %edx,%ebx
  mov    0x38(%rsp),%r14d
  mov    0x40(%rsp),%r10
  lea    0x1f(%rdx,%rdx,1),%r13d
  sar    $0x5,%r13d
  shl    $0x2,%r13d
  lea    (%r8,%r8,1),%eax
  sar    $0x5,%eax
  shl    $0x2,%eax
  cltq
  movslq %r9d,%rdx
  movslq %r13d,%rsi
  imul   %rsi,%rdx
  add    %rdx,%rax
  not    %r8d
  and    $0xf,%r8d
  shl    $0x5,%ebx
  sar    $0x3,%ebx
  mov    0x30(%rsp),%r12d
  shl    $0x5,%r12d
  sar    $0x3,%r12d
  cmp    %r14d,%r9d
  jge    L70
  mov    %rdi,%r11
  lea    (%r8,%r8,1),%ebp
  movslq %r12d,%rdx
  movslq %ebx,%rbx
  lea    (%rcx,%rdx,1),%r8
  mov    %rsi,%r13
  add    %rax,%r11
  mov    %rdx,%r12
  jmp    L59
L14:
  cmp    %rdi,%rdx
  jae    L3
L54:
  mov    (%rsi),%eax
  shr    %cl,%eax
  and    $0x3,%eax
  mov    (%r10,%rax,4),%eax
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  sub    $0x2,%ecx
  jns    L14
  add    $0x4,%rsi
  mov    $0x1e,%ecx
  jmp    L14
L3:
  add    $0x1,%r9d
  add    %rbx,%r8
  add    %r13,%r11
  cmp    %r9d,%r14d
  je     L70
L59:
  mov    %r11,%rsi
  mov    %r8,%rdx
  sub    %r12,%rdx
  mov    %r8,%rdi
  cmp    %rdx,%r8
  jbe    L3
  mov    %ebp,%ecx
  jmp    L54
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void copyImage2To32(int *fromImageData, int *toImageData, int width, int height, int affectedL, int affectedT, int affectedR, int affectedB, unsigned int *stColors) {
  long scanLine2, firstWord2, firstShift2;
  long scanLine32, firstWord32, lastWord32;
  int line;
  scanLine2 = ((((width) * (2) + 31) >> 5) << 2);
  firstWord2 = scanLine2 * affectedT + ((((affectedL) * (2)) >> 5) << 2);
  firstShift2 = 30 - ((affectedL & 15) * 2);
  scanLine32 = ((((width) * (32) + 31) >> 5) << 2);
  firstWord32 = 0;
  lastWord32 = ((((affectedR) * (32)) >> 5) << 2);
  for (line = affectedT; line < affectedB; line++) {
    register unsigned int *from = (unsigned int *)((long)fromImageData + firstWord2);
    register unsigned int *to = (unsigned int *)((long)toImageData + firstWord32);
    register unsigned int *limit = (unsigned int *)((long)toImageData + lastWord32);
    register int shift = firstShift2;
    while (to < limit) {
      *to = stColors[(*from >> shift) & 3];
      to++;
      shift -= 2;
      if (shift < 0) {
        shift = 30;
        from++;
      }
    }
    firstWord2 += scanLine2;
    firstWord32 += scanLine32;
    lastWord32 += scanLine32;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyImage2To32>:
  endbr64
  push   %r13
  lea    (%r8,%r8,1),%eax
  not    %r8d
  push   %r12
  lea    0x1f(%rdx,%rdx,1),%r12d
  sar    $0x5,%eax
  and    $0xf,%r8d
  sar    $0x5,%r12d
  push   %rbp
  shl    $0x2,%eax
  shl    $0x2,%r12d
  push   %rbx
  mov    %edx,%ebx
  movslq %r9d,%rdx
  movslq %r12d,%r12
  cltq
  mov    0x30(%rsp),%r13d
  shl    $0x5,%ebx
  imul   %r12,%rdx
  mov    0x38(%rsp),%r10
  sar    $0x3,%ebx
  add    %rdx,%rax
  mov    0x28(%rsp),%edx
  shl    $0x5,%edx
  sar    $0x3,%edx
  cmp    %r13d,%r9d
  jge    L45
  mov    %rdi,%r11
  movslq %edx,%rdx
  lea    (%r8,%r8,1),%ebp
  movslq %ebx,%rbx
  mov    %rsi,%r8
  lea    (%rsi,%rdx,1),%rdi
  add    %rax,%r11
  nop
L49:
  mov    %r11,%rsi
  mov    %r8,%rdx
  mov    %ebp,%ecx
  cmp    %r8,%rdi
  jbe    L31
  nopl   (%rax)
L47:
  mov    (%rsi),%eax
  add    $0x4,%rdx
  shr    %cl,%eax
  and    $0x3,%eax
  mov    (%r10,%rax,4),%eax
  mov    %eax,-0x4(%rdx)
  sub    $0x2,%ecx
  jns    L25
  add    $0x4,%rsi
  mov    $0x1e,%ecx
L25:
  cmp    %rdx,%rdi
  ja     L47
L31:
  add    $0x1,%r9d
  add    %rbx,%r8
  add    %rbx,%rdi
  add    %r12,%r11
  cmp    %r9d,%r13d
  jne    L49
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copyImage2To32(int *fromImageData, int *toImageData, int width, int height, int affectedL, int affectedT, int affectedR, int affectedB, unsigned int *stColors) {
  long scanLine2, firstWord2, firstShift2;
  long scanLine32, firstWord32, lastWord32;
  int line;
  scanLine2 = ((((width) * (2) + 31) >> 5) << 2);
  firstWord2 = scanLine2 * affectedT + ((((affectedL) * (2)) >> 5) << 2);
  firstShift2 = 30 - ((affectedL & 15) * 2);
  scanLine32 = ((((width) * (32) + 31) >> 5) << 2);
  firstWord32 = 0;
  lastWord32 = ((((affectedR) * (32)) >> 5) << 2);
  for (line = affectedT; line < affectedB; line++) {
    register unsigned int *from = (unsigned int *)((long)fromImageData + firstWord2);
    register unsigned int *to = (unsigned int *)((long)toImageData + firstWord32);
    register unsigned int *limit = (unsigned int *)((long)toImageData + lastWord32);
    register int shift = firstShift2;
    while (to < limit) {
      *to = stColors[(*from >> shift) & 3];
      to++;
      shift -= 2;
      if (shift < 0) {
        shift = 30;
        from++;
      }
    }
    firstWord2 += scanLine2;
    firstWord32 += scanLine32;
    lastWord32 += scanLine32;
  }
}
```