ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L1
  lea    0x4(%rsp),%r12
  lea    D7(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %rbp,%rdi
  lea    0x1(%rax),%esi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L26
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D4: %d

tool: D7: %d


assistant: ```c
int main() {
  int i, j, t, n;
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    printf("%d\n", n + 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L17:
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  lea    0x1(%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <sin@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L10:
  cmpl   $0x1312cff,-0xc(%rbp)
  jle    L17
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void *thread(void *arg) {
  int i;
  double *res = (double *)arg;
  for (i = 0; i < 20000000; i++) {
    *res += sin(M_PI * (1 + 4 * i) / 2);
  }
  pthread_exit(NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<thread>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  mov    D1(%rip),%r12
L8:
  mov    %ebx,%eax
  imul   (%r12),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x4,%ebx
  cmp    $0x4c4b401,%ebx
  jne    L8
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *thread(void *arg) {
  int i;
  double *res = (double *)arg;
  for (i = 0; i < 20000000; i++) {
    *res += sin(M_PI * (1 + 4 * i) / 2);
  }
  pthread_exit(NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<thread>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp),%eax
  imul   %ebx,%eax
  add    $0x4,%ebx
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%r12),%xmm0
  movsd  %xmm0,(%r12)
  cmp    $0x4c4b401,%ebx
  jne    L0
  xor    %edi,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *thread(void *arg) {
  int i;
  double *res = (double *)arg;
  for (i = 0; i < 20000000; i++) {
    *res += sin(M_PI * (1 + 4 * i) / 2);
  }
  pthread_exit(NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<thread>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0x0(%rbp),%eax
  imul   %ebx,%eax
  add    $0x4,%ebx
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%r12),%xmm0
  movsd  %xmm0,(%r12)
  cmp    $0x4c4b401,%ebx
  jne    L5
  xor    %edi,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *thread(void *arg) {
  int i;
  double *res = (double *)arg;
  for (i = 0; i < 20000000; i++) {
    *res += sin(M_PI * (1 + 4 * i) / 2);
  }
  pthread_exit(NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L7:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x8,-0xc(%rbp)
  je     L44
  cmpl   $0x7f,-0xc(%rbp)
  jne    L34
L44:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L66
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  subq   $0x1,-0x8(%rbp)
L66:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L69
L34:
  cmpl   $0xd,-0xc(%rbp)
  jne    L10
  mov    $0xa,%edi
  call   <putc@plt>
  jmp    L15
L10:
  cmpl   $0xa,-0xc(%rbp)
  jne    L37
  mov    $0xa,%edi
  call   <putc@plt>
  jmp    L15
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L69:
  jmp    L7
L15:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8:  

assistant: ```c
void gets(char *buf) {
  char *t;
  int i;
  t = buf;
  while (1) {
    i = getch();
    if ((i == '\b') || (i == 127)) {
      if (t > buf) {
        puts("\b \b");
        t--;
      }
      *t = 0;
      continue;
    }
    if (i == '\r') {
      putc('\n');
      break;
    }
    if (i == '\n') {
      putc('\n');
      break;
    }
    putc(i);
    *t++ = i;
  }
  *t = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rdi,%rbp
  lea    D2(%rip),%r13
  jmp    L27
L86:
  cmp    %r12,%rbp
  ja     L48
L45:
  movb   $0x0,0x0(%rbp)
L27:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  je     L86
  cmp    $0x7f,%eax
  je     L86
  cmp    $0xd,%eax
  je     L12
  cmp    $0xa,%eax
  je     L71
  mov    %eax,%edi
  call   <putc@plt>
  mov    %bl,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L27
L48:
  mov    %r13,%rdi
  call   <puts@plt>
  sub    $0x1,%rbp
  jmp    L45
L12:
  mov    $0xa,%edi
  call   <putc@plt>
L29:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    $0xa,%edi
  call   <putc@plt>
  jmp    L29
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2:  

assistant: ```c
void gets(char *buf) {
  char *t;
  int i;
  t = buf;
  while (1) {
    i = getch();
    if ((i == '\b') || (i == 127)) {
      if (t > buf) {
        puts("\b \b");
        t--;
      }
      *t = 0;
      continue;
    }
    if (i == '\r') {
      putc('\n');
      break;
    }
    if (i == '\n') {
      putc('\n');
      break;
    }
    putc(i);
    *t++ = i;
  }
  *t = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gets>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  je     L59
L56:
  cmp    $0x7f,%eax
  je     L59
  cmp    $0xd,%eax
  je     L10
  cmp    $0xa,%eax
  je     L10
  mov    %eax,%edi
  add    $0x1,%rbp
  call   <putc@plt>
  mov    %bl,-0x1(%rbp)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  jne    L56
L59:
  cmp    %r12,%rbp
  ja     L72
L11:
  movb   $0x0,0x0(%rbp)
  jmp    L2
  nopl   0x0(%rax)
L72:
  mov    %r13,%rdi
  sub    $0x1,%rbp
  call   <puts@plt>
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0xa,%edi
  call   <putc@plt>
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6:  

assistant: ```c
void gets(char *buf) {
  char *t;
  int i;
  t = buf;
  while (1) {
    i = getch();
    if ((i == '\b') || (i == 127)) {
      if (t > buf) {
        puts("\b \b");
        t--;
      }
      *t = 0;
      continue;
    }
    if (i == '\r') {
      putc('\n');
      break;
    }
    if (i == '\n') {
      putc('\n');
      break;
    }
    putc(i);
    *t++ = i;
  }
  *t = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gets>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  je     L3
L4:
  cmp    $0x7f,%eax
  je     L3
  cmp    $0xd,%eax
  je     L35
  cmp    $0xa,%eax
  je     L35
  mov    %eax,%edi
  add    $0x1,%rbp
  call   <putc@plt>
  mov    %bl,-0x1(%rbp)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  jne    L4
L3:
  cmp    %r12,%rbp
  ja     L24
L49:
  movb   $0x0,0x0(%rbp)
  jmp    L50
  nopl   0x0(%rax)
L24:
  mov    %r13,%rdi
  sub    $0x1,%rbp
  call   <puts@plt>
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    $0xa,%edi
  call   <putc@plt>
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2:  

assistant: ```c
void gets(char *buf) {
  char *t;
  int i;
  t = buf;
  while (1) {
    i = getch();
    if ((i == '\b') || (i == 127)) {
      if (t > buf) {
        puts("\b \b");
        t--;
      }
      *t = 0;
      continue;
    }
    if (i == '\r') {
      putc('\n');
      break;
    }
    if (i == '\n') {
      putc('\n');
      break;
    }
    putc(i);
    *t++ = i;
  }
  *t = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_devfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x2,%ecx
  mov    %rax,%rdi
  call   <parse_msgstring@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <verbose@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: parse_devfile: devfile = %s


assistant: ```c
int parse_devfile(char *msgbuf, size_t msglen, char **devfile) {
  int ret;
  ret = parse_msgstring(msgbuf, msglen, devfile, 2);
  verbose(1, "parse_devfile: devfile = %s\n", *devfile);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_devfile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    $0x2,%ecx
  call   <parse_msgstring@plt>
  mov    %eax,%ebp
  mov    (%rbx),%rdx
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <verbose@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: parse_devfile: devfile = %s


assistant: ```c
int parse_devfile(char *msgbuf, size_t msglen, char **devfile) {
  int ret;
  ret = parse_msgstring(msgbuf, msglen, devfile, 2);
  verbose(1, "parse_devfile: devfile = %s\n", *devfile);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_devfile>:
  endbr64
  push   %r12
  mov    $0x2,%ecx
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <parse_msgstring@plt>
  mov    (%rbx),%rdx
  mov    $0x1,%edi
  lea    D9(%rip),%rsi
  mov    %eax,%r12d
  call   <verbose@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: parse_devfile: devfile = %s


assistant: ```c
int parse_devfile(char *msgbuf, size_t msglen, char **devfile) {
  int ret;
  ret = parse_msgstring(msgbuf, msglen, devfile, 2);
  verbose(1, "parse_devfile: devfile = %s\n", *devfile);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_devfile>:
  endbr64
  push   %r12
  mov    $0x2,%ecx
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <parse_msgstring@plt>
  mov    (%rbx),%rdx
  mov    $0x1,%edi
  lea    D4(%rip),%rsi
  mov    %eax,%r12d
  call   <verbose@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: parse_devfile: devfile = %s


assistant: ```c
int parse_devfile(char *msgbuf, size_t msglen, char **devfile) {
  int ret;
  ret = parse_msgstring(msgbuf, msglen, devfile, 2);
  verbose(1, "parse_devfile: devfile = %s\n", *devfile);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<px_malloc0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *px_malloc0(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  memset(mem, 0, size);
  return mem;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<px_malloc0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *px_malloc0(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  memset(mem, 0, size);
  return mem;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<px_malloc0>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *px_malloc0(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  memset(mem, 0, size);
  return mem;
}
```
user: What is the c source code of the assembly code below:

```asm
<px_malloc0>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *px_malloc0(size_t size) {
  void *mem = malloc(size);
  assert(mem != NULL);
  memset(mem, 0, size);
  return mem;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L94
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L138
L94:
  mov    $0xffffffff,%eax
  jmp    L45
L138:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  ja     L16
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L57
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jbe    L57
L16:
  mov    $0xffffffff,%eax
  jmp    L45
L57:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jbe    L69
  mov    $0xffffffff,%eax
  jmp    L45
L69:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L73
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L138
L73:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L95
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jae    L61
L95:
  mov    $0xffffffff,%eax
  jmp    L45
L61:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int parse_uint(const char *str, unsigned int *result, unsigned int min_value, unsigned int max_value) {
  unsigned int value = 0;
  if (*str < '0' || *str > '9')
    return -1;
  do {
    unsigned int addition = *str - '0';
    if (value > UINT_MAX / 10 || (value == UINT_MAX / 10 && addition > UINT_MAX % 10))
      return -1;
    value = value * 10 + addition;
    if (value > max_value)
      return -1;
    ++str;
  } while (*str >= '0' && *str <= '9');
  if (*str || value < min_value)
    return -1;
  *result = value;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_uint>:
  endbr64
  mov    %edx,%r11d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L123
  push   %rbx
  mov    %rsi,%r10
  mov    %ecx,%r8d
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    D8(%rip),%rdx
  mov    (%rdx),%esi
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%ecx
  mov    $0x0,%edx
  movslq %esi,%r9
  imul   $0x66666667,%r9,%r9
  sar    $0x22,%r9
  mov    %esi,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%r9d
  lea    (%r9,%r9,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%esi
  mov    %esi,%r9d
  jmp    L54
L2:
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%edx
  cmp    %r8d,%edx
  ja     L105
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L92
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    %ecx,%edx
  ja     L74
L54:
  cmp    %edx,%ecx
  jne    L2
  cmp    %eax,%r9d
  jae    L2
  mov    $0xffffffff,%eax
  jmp    L61
L92:
  cmp    %r11d,%edx
  jb     L36
  test   %al,%al
  jne    L36
  mov    %edx,(%r10)
  mov    $0x0,%eax
  jmp    L61
L123:
  mov    $0xffffffff,%eax
  ret
L74:
  mov    $0xffffffff,%eax
L61:
  pop    %rbx
  ret
L105:
  mov    $0xffffffff,%eax
  jmp    L61
L36:
  mov    $0xffffffff,%eax
  jmp    L61
```

assistant: ```c
int parse_uint(const char *str, unsigned int *result, unsigned int min_value, unsigned int max_value) {
  unsigned int value = 0;
  if (*str < '0' || *str > '9')
    return -1;
  do {
    unsigned int addition = *str - '0';
    if (value > UINT_MAX / 10 || (value == UINT_MAX / 10 && addition > UINT_MAX % 10))
      return -1;
    value = value * 10 + addition;
    if (value > max_value)
      return -1;
    ++str;
  } while (*str >= '0' && *str <= '9');
  if (*str || value < min_value)
    return -1;
  *result = value;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_uint>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r11d
  mov    %rsi,%r10
  mov    %ecx,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L19
  mov    D6(%rip),%rax
  movsbl %dl,%edx
  movslq (%rax),%rcx
  mov    %rcx,%r9
  imul   $0x66666667,%rcx,%rcx
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L46:
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  cmp    %r8d,%eax
  ja     L19
  movzbl 0x1(%rdi),%esi
  add    $0x1,%rdi
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  ja     L85
  movsbl %dl,%edx
  cmp    %ecx,%eax
  ja     L19
L55:
  cmp    %eax,%ecx
  jne    L46
  cmp    %edx,%r9d
  jae    L46
L19:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L85:
  test   %sil,%sil
  jne    L19
  cmp    %r11d,%eax
  jb     L19
  mov    %eax,(%r10)
  xor    %eax,%eax
  ret
```

assistant: ```c
int parse_uint(const char *str, unsigned int *result, unsigned int min_value, unsigned int max_value) {
  unsigned int value = 0;
  if (*str < '0' || *str > '9')
    return -1;
  do {
    unsigned int addition = *str - '0';
    if (value > UINT_MAX / 10 || (value == UINT_MAX / 10 && addition > UINT_MAX % 10))
      return -1;
    value = value * 10 + addition;
    if (value > max_value)
      return -1;
    ++str;
  } while (*str >= '0' && *str <= '9');
  if (*str || value < min_value)
    return -1;
  *result = value;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_uint>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r11d
  mov    %rsi,%r10
  mov    %ecx,%r8d
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L25
  mov    D8(%rip),%rax
  movsbl %dl,%edx
  movslq (%rax),%rcx
  mov    %rcx,%r9
  imul   $0x66666667,%rcx,%rcx
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L51:
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  cmp    %r8d,%eax
  ja     L25
  movzbl 0x1(%rdi),%esi
  add    $0x1,%rdi
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  ja     L43
  movsbl %dl,%edx
  cmp    %ecx,%eax
  ja     L25
L13:
  cmp    %eax,%ecx
  jne    L51
  cmp    %edx,%r9d
  jae    L51
L25:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L43:
  test   %sil,%sil
  jne    L25
  cmp    %r11d,%eax
  jb     L25
  mov    %eax,(%r10)
  xor    %eax,%eax
  ret
```

assistant: ```c
int parse_uint(const char *str, unsigned int *result, unsigned int min_value, unsigned int max_value) {
  unsigned int value = 0;
  if (*str < '0' || *str > '9')
    return -1;
  do {
    unsigned int addition = *str - '0';
    if (value > UINT_MAX / 10 || (value == UINT_MAX / 10 && addition > UINT_MAX % 10))
      return -1;
    value = value * 10 + addition;
    if (value > max_value)
      return -1;
    ++str;
  } while (*str >= '0' && *str <= '9');
  if (*str || value < min_value)
    return -1;
  *result = value;
  return 0;
}
```