ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<min_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L6:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L67
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  jmp    L46
L67:
  mov    -0x1c(%rbp),%eax
L46:
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L17
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L17
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L42
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L24
L42:
  movl   $0x1,-0xc(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L11
  cmpl   $0x0,-0xc(%rbp)
  je     L6
L11:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void min_down(int arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<min_down>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ecx
  mov    %edx,%r10d
  mov    $0x1,%ebp
  jmp    L78
L82:
  mov    %ebp,%edx
  cmp    %r10d,%eax
  jge    L24
  mov    %r12d,%esi
  mov    0x0(%r13),%r14d
  cmp    %r14d,(%rdi,%r15,4)
  jle    L24
L60:
  mov    %ebp,%edx
  cmp    %esi,%ecx
  je     L24
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%edx
  mov    %r8d,(%rax)
  mov    %edx,(%r9)
  mov    %esi,%ecx
L78:
  lea    (%rcx,%rcx,1),%eax
  cmp    %r10d,%eax
  setle  %r11b
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rbx
  movslq %ecx,%rsi
  lea    (%rdi,%rsi,4),%r9
  lea    0x4(%rdi,%rdx,4),%r13
  lea    0x1(%rax),%r12d
  mov    $0x0,%edx
  mov    %rsi,%r15
  movslq %eax,%r14
  mov    %r14,-0x8(%rsp)
L24:
  test   %edx,%edx
  jne    L30
  test   %r11b,%r11b
  je     L30
  mov    (%r9),%r8d
  cmp    %r8d,(%rbx)
  jge    L82
  mov    %eax,%esi
  cmp    %r10d,%eax
  jge    L60
  mov    0x0(%r13),%esi
  mov    -0x8(%rsp),%rdx
  cmp    %esi,(%rdi,%rdx,4)
  mov    %r12d,%esi
  cmovle %eax,%esi
  jmp    L60
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void min_down(int arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<min_down>:
  endbr64
  lea    (%rsi,%rsi,1),%ecx
  mov    %rdi,%rax
  cmp    %edx,%ecx
  jg     L90
L23:
  movslq %ecx,%rdi
  mov    (%rax,%rdi,4),%r10d
  lea    0x0(,%rdi,4),%r11
  movslq %esi,%rdi
  lea    (%rax,%rdi,4),%r9
  mov    (%r9),%r8d
  cmp    %r8d,%r10d
  jge    L71
  mov    %ecx,%edi
  cmp    %ecx,%edx
  jle    L45
  cmp    0x4(%rax,%r11,1),%r10d
  jg     L19
L45:
  cmp    %esi,%edi
  je     L86
  movslq %edi,%rcx
  lea    (%rax,%rcx,4),%rcx
  mov    (%rcx),%esi
  mov    %r8d,(%rcx)
  lea    (%rdi,%rdi,1),%ecx
  mov    %esi,(%r9)
  cmp    %edx,%ecx
  jg     L9
  mov    %edi,%esi
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L71:
  cmp    %ecx,%edx
  jle    L86
  cmp    0x4(%rax,%r11,1),%r8d
  jle    L86
L19:
  lea    0x1(%rcx),%edi
  jmp    L45
L86:
  ret
  nopl   0x0(%rax)
L90:
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void min_down(int arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<min_down>:
  endbr64
  lea    (%rsi,%rsi,1),%ecx
  mov    %rdi,%rax
  cmp    %edx,%ecx
  jg     L28
L37:
  movslq %ecx,%rdi
  mov    (%rax,%rdi,4),%r10d
  lea    0x0(,%rdi,4),%r11
  movslq %esi,%rdi
  lea    (%rax,%rdi,4),%r9
  mov    (%r9),%r8d
  cmp    %r8d,%r10d
  jge    L88
  mov    %ecx,%edi
  cmp    %ecx,%edx
  jle    L30
  cmp    0x4(%rax,%r11,1),%r10d
  jg     L24
L30:
  cmp    %esi,%edi
  je     L73
  movslq %edi,%rcx
  lea    (%rax,%rcx,4),%rcx
  mov    (%rcx),%esi
  mov    %r8d,(%rcx)
  lea    (%rdi,%rdi,1),%ecx
  mov    %esi,(%r9)
  cmp    %edx,%ecx
  jg     L34
  mov    %edi,%esi
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L88:
  cmp    %ecx,%edx
  jle    L73
  cmp    0x4(%rax,%r11,1),%r8d
  jle    L73
L24:
  lea    0x1(%rcx),%edi
  jmp    L30
L73:
  ret
  nopl   0x0(%rax)
L28:
  ret
  nopl   0x0(%rax)
L34:
  ret
```

assistant: ```c
void min_down(int arr[], int i, int n) {
  int flag = 0;
  while (i * 2 <= n && flag == 0) {
    int t = arr[i * 2] < arr[i] ? i * 2 : i;
    if (i * 2 + 1 <= n && arr[t] > arr[i * 2 + 1])
      t = i * 2 + 1;
    if (t != i) {
      int temp = arr[t];
      arr[t] = arr[i];
      arr[i] = temp;
      i = t;
    } else
      flag = 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<U_PMF_RECORD_SIZE_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L0
L21:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rsi
  lea    -0x10(%rbp),%rax
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <U_PMF_SERIAL_get@plt>
  mov    -0x14(%rbp),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int U_PMF_RECORD_SIZE_get(const char *contents) {
  if (!contents) {
    return (0);
  }
  int Size;
  const char *from = contents + 4;
  U_PMF_SERIAL_get(&from, &Size, 4, 1, 1);
  return (Size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<U_PMF_RECORD_SIZE_get>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  add    $0x4,%rdi
  mov    %rdi,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0x4,%edx
  call   <U_PMF_SERIAL_get@plt>
  mov    0xc(%rsp),%eax
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int U_PMF_RECORD_SIZE_get(const char *contents) {
  if (!contents) {
    return (0);
  }
  int Size;
  const char *from = contents + 4;
  U_PMF_SERIAL_get(&from, &Size, 4, 1, 1);
  return (Size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<U_PMF_RECORD_SIZE_get>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  add    $0x4,%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    %rdi,0x10(%rsp)
  mov    $0x4,%edx
  lea    0x10(%rsp),%rdi
  call   <U_PMF_SERIAL_get@plt>
  mov    0xc(%rsp),%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int U_PMF_RECORD_SIZE_get(const char *contents) {
  if (!contents) {
    return (0);
  }
  int Size;
  const char *from = contents + 4;
  U_PMF_SERIAL_get(&from, &Size, 4, 1, 1);
  return (Size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<U_PMF_RECORD_SIZE_get>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  add    $0x4,%rdi
  lea    0xc(%rsp),%rsi
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    %rdi,0x10(%rsp)
  mov    $0x4,%edx
  lea    0x10(%rsp),%rdi
  call   <U_PMF_SERIAL_get@plt>
  mov    0xc(%rsp),%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int U_PMF_RECORD_SIZE_get(const char *contents) {
  if (!contents) {
    return (0);
  }
  int Size;
  const char *from = contents + 4;
  U_PMF_SERIAL_get(&from, &Size, 4, 1, 1);
  return (Size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nist_ctr_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <nist_ctr_drbg_instantiate_initialize@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  mov    -0x4(%rbp),%eax
  jmp    L19
L29:
  mov    $0x0,%eax
  call   <nist_ctr_drbg_block_cipher_df_initialize@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  jmp    L19
L4:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int nist_ctr_initialize() {
  int err;
  err = nist_ctr_drbg_instantiate_initialize();
  if (err)
    return err;
  err = nist_ctr_drbg_block_cipher_df_initialize();
  if (err)
    return err;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nist_ctr_initialize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nist_ctr_drbg_instantiate_initialize@plt>
  test   %eax,%eax
  je     L4
L15:
  add    $0x8,%rsp
  ret
L4:
  call   <nist_ctr_drbg_block_cipher_df_initialize@plt>
  jmp    L15
```

assistant: ```c
int nist_ctr_initialize() {
  int err;
  err = nist_ctr_drbg_instantiate_initialize();
  if (err)
    return err;
  err = nist_ctr_drbg_block_cipher_df_initialize();
  if (err)
    return err;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<nist_ctr_initialize>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nist_ctr_drbg_instantiate_initialize@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  jmp    1060 <nist_ctr_drbg_block_cipher_df_initialize@plt>
```

assistant: ```c
int nist_ctr_initialize() {
  int err;
  err = nist_ctr_drbg_instantiate_initialize();
  if (err)
    return err;
  err = nist_ctr_drbg_block_cipher_df_initialize();
  if (err)
    return err;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nist_ctr_initialize>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nist_ctr_drbg_instantiate_initialize@plt>
  test   %eax,%eax
  je     L7
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  jmp    1060 <nist_ctr_drbg_block_cipher_df_initialize@plt>
```

assistant: ```c
int nist_ctr_initialize() {
  int err;
  err = nist_ctr_drbg_instantiate_initialize();
  if (err)
    return err;
  err = nist_ctr_drbg_block_cipher_df_initialize();
  if (err)
    return err;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fstrndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L10:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L30
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x6e,%eax
  jne    L30
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  jmp    L18
L30:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L18:
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fstrndup(char *src, int size) {
  char *ret = calloc(size + 1, sizeof(char));
  int i, j = 0;
  for (i = 0; i < size; i++) {
    if (src[i] == '\\')
      switch (src[++i]) {
      case 'n':
        ret[j++] = '\n';
        continue;
      }
    ret[j++] = src[i];
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fstrndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x1(%rsi),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L13
  mov    %rax,%rcx
  mov    $0x0,%edx
  jmp    L41
L38:
  movslq %edx,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%rcx)
L2:
  add    $0x1,%edx
  add    $0x1,%rcx
  cmp    %edx,%ebp
  jle    L13
L41:
  movslq %edx,%rsi
  cmpb   $0x5c,(%rbx,%rsi,1)
  jne    L38
  add    $0x1,%edx
  movslq %edx,%rsi
  cmpb   $0x6e,(%rbx,%rsi,1)
  jne    L38
  movb   $0xa,(%rcx)
  jmp    L2
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *fstrndup(char *src, int size) {
  char *ret = calloc(size + 1, sizeof(char));
  int i, j = 0;
  for (i = 0; i < size; i++) {
    if (src[i] == '\\')
      switch (src[++i]) {
      case 'n':
        ret[j++] = '\n';
        continue;
      }
    ret[j++] = src[i];
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fstrndup>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi),%edi
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L23
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0xa,%edi
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  cmp    $0x5c,%cl
  jne    L1
  add    $0x1,%edx
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  cmp    $0x6e,%cl
  cmove  %edi,%ecx
L1:
  add    $0x1,%edx
  mov    %cl,(%rsi)
  add    $0x1,%rsi
  cmp    %edx,%ebp
  jg     L8
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *fstrndup(char *src, int size) {
  char *ret = calloc(size + 1, sizeof(char));
  int i, j = 0;
  for (i = 0; i < size; i++) {
    if (src[i] == '\\')
      switch (src[++i]) {
      case 'n':
        ret[j++] = '\n';
        continue;
      }
    ret[j++] = src[i];
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fstrndup>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi),%edi
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L28
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0xa,%edi
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  cmp    $0x5c,%cl
  jne    L19
  add    $0x1,%edx
  movslq %edx,%rcx
  movzbl (%rbx,%rcx,1),%ecx
  cmp    $0x6e,%cl
  cmove  %edi,%ecx
L19:
  add    $0x1,%edx
  mov    %cl,(%rsi)
  add    $0x1,%rsi
  cmp    %edx,%ebp
  jg     L8
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *fstrndup(char *src, int size) {
  char *ret = calloc(size + 1, sizeof(char));
  int i, j = 0;
  for (i = 0; i < size; i++) {
    if (src[i] == '\\')
      switch (src[++i]) {
      case 'n':
        ret[j++] = '\n';
        continue;
      }
    ret[j++] = src[i];
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L6
  call   <abort@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void *memcpy(void *a, const void *b, long unsigned int len) {
  if (a == b)
    __builtin_abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy>:
  endbr64
  cmp    %rdi,%rsi
  je     L5
  ret
L5:
  sub    $0x8,%rsp
  call   <abort@plt>
```

assistant: ```c
void *memcpy(void *a, const void *b, long unsigned int len) {
  if (a == b)
    __builtin_abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memcpy>:
  endbr64
  cmp    %rdi,%rsi
  je     1060 <memcpy.cold>
  ret
```

assistant: ```c
void *memcpy(void *a, const void *b, long unsigned int len) {
  if (a == b)
    __builtin_abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  cmp    %rdi,%rsi
  je     1060 <memcpy.cold>
  ret
```

assistant: ```c
void *memcpy(void *a, const void *b, long unsigned int len) {
  if (a == b)
    __builtin_abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inttogray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L15
L16:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  shr    %eax
  and    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  shll   -0x8(%rbp)
L15:
  cmpl   $0x80,-0x8(%rbp)
  jbe    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int inttogray(unsigned int x) {
  unsigned int y, r = 0;
  for (y = 1; y <= 0x80; y <<= 1)
    r |= ((x + y) >> 1) & y;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inttogray>:
  endbr64
  mov    $0x8,%ecx
  mov    $0x0,%esi
  mov    $0x1,%edx
L7:
  lea    (%rdi,%rdx,1),%eax
  shr    %eax
  and    %edx,%eax
  or     %eax,%esi
  add    %edx,%edx
  sub    $0x1,%ecx
  jne    L7
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int inttogray(unsigned int x) {
  unsigned int y, r = 0;
  for (y = 1; y <= 0x80; y <<= 1)
    r |= ((x + y) >> 1) & y;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inttogray>:
  endbr64
  mov    $0x8,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  lea    (%rdi,%rdx,1),%eax
  shr    %eax
  and    %edx,%eax
  add    %edx,%edx
  or     %eax,%r8d
  sub    $0x1,%ecx
  jne    L4
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int inttogray(unsigned int x) {
  unsigned int y, r = 0;
  for (y = 1; y <= 0x80; y <<= 1)
    r |= ((x + y) >> 1) & y;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inttogray>:
  endbr64
  lea    0x1(%rdi),%ecx
  lea    0x2(%rdi),%edx
  mov    %edi,%eax
  shr    %ecx
  shr    %edx
  sub    $0xffffff80,%eax
  and    $0x2,%edx
  and    $0x1,%ecx
  shr    %eax
  or     %edx,%ecx
  lea    0x4(%rdi),%edx
  and    $0x80,%eax
  shr    %edx
  and    $0x4,%edx
  or     %ecx,%edx
  lea    0x8(%rdi),%ecx
  shr    %ecx
  and    $0x8,%ecx
  or     %edx,%ecx
  lea    0x10(%rdi),%edx
  shr    %edx
  and    $0x10,%edx
  or     %ecx,%edx
  lea    0x20(%rdi),%ecx
  shr    %ecx
  and    $0x20,%ecx
  or     %edx,%ecx
  lea    0x40(%rdi),%edx
  shr    %edx
  and    $0x40,%edx
  or     %ecx,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int inttogray(unsigned int x) {
  unsigned int y, r = 0;
  for (y = 1; y <= 0x80; y <<= 1)
    r |= ((x + y) >> 1) & y;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char str[]) {
  int c, i, j;
  for (i = 0, j = strlen(str) - 1; i < j; i += 1, j -= 1) {
    c = str[i];
    str[i] = str[j];
    str[j] = c;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L2
  cltq
  mov    $0x0,%edx
L4:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L4
L2:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char str[]) {
  int c, i, j;
  for (i = 0, j = strlen(str) - 1; i < j; i += 1, j -= 1) {
    c = str[i];
    str[i] = str[j];
    str[j] = c;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L15
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L2
L15:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char str[]) {
  int c, i, j;
  for (i = 0, j = strlen(str) - 1; i < j; i += 1, j -= 1) {
    c = str[i];
    str[i] = str[j];
    str[j] = c;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L17
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L14
L17:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char str[]) {
  int c, i, j;
  for (i = 0, j = strlen(str) - 1; i < j; i += 1, j -= 1) {
    c = str[i];
    str[i] = str[j];
    str[j] = c;
  }
}
```