ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L60
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %rdx,%r14
  test   %rdi,%rdi
  je     L60
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L34
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L96
  test   %r14,%r14
  lea    D0(%rip),%rax
  cmovne %r14,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    $0x0,%r13d
  movslq %ebx,%rbx
  jmp    L11
L79:
  lea    (%rax,%rbx,1),%rbp
  add    $0x1,%r13d
L11:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L79
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r14d,%ebx
  mov    %r14d,%eax
  sub    0xc(%rsp),%eax
  imul   %r13d,%eax
  lea    0x1(%rax,%rdx,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L96
  test   %r13d,%r13d
  je     L118
  mov    %rax,%r14
  movslq %ebx,%rax
  mov    %rax,0x18(%rsp)
L50:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  sub    %r12,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rdx
  lea    (%rax,%rdx,1),%rdi
  mov    0x10(%rsp),%rsi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rcx
  lea    (%rax,%rcx,1),%r14
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  add    %rbx,%r12
  sub    $0x1,%r13d
  jne    L50
L6:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L96:
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L118:
  mov    %rax,%r14
  jmp    L6
L60:
  mov    $0x0,%ebp
  jmp    L96
L34:
  mov    $0x0,%ebp
  jmp    L96
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; (tmp = (strstr(ins, rep))); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L56
  mov    %rdi,%r15
  test   %rdi,%rdi
  je     L56
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <strlen@plt>
  movslq %eax,%r14
  mov    %r14d,0xc(%rsp)
  test   %r14d,%r14d
  je     L56
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L56
  test   %r12,%r12
  lea    D5(%rip),%rax
  cmove  %rax,%r12
  xor    %ebx,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,0x10(%rsp)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L47:
  lea    (%rax,%r14,1),%r13
  add    $0x1,%ebx
L8:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L47
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r14d
  mov    %eax,%r8d
  mov    %r14d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r8,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L56
  lea    -0x1(%rbx),%r13d
  test   %ebx,%ebx
  je     L101
  movslq %r14d,%rax
  mov    %rcx,%r14
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r15,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  sub    %r15,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r14
  add    %rbx,%r15
  sub    $0x1,%r13d
  jae    L26
L9:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L99:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L56:
  movq   $0x0,0x18(%rsp)
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L101:
  mov    0x18(%rsp),%r14
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; (tmp = (strstr(ins, rep))); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L89
  mov    %rdi,%r15
  test   %rdi,%rdi
  je     L89
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <strlen@plt>
  movslq %eax,%r14
  mov    %r14d,0xc(%rsp)
  test   %r14d,%r14d
  je     L89
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L89
  test   %r12,%r12
  lea    D3(%rip),%rax
  cmove  %rax,%r12
  xor    %ebx,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,0x10(%rsp)
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L35:
  lea    (%rax,%r14,1),%r13
  add    $0x1,%ebx
L22:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L35
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r14d
  mov    %eax,%r8d
  mov    %r14d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r8,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L89
  lea    -0x1(%rbx),%r13d
  test   %ebx,%ebx
  je     L46
  movslq %r14d,%rax
  mov    %rcx,%r14
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r15,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  sub    %r15,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r14
  add    %rbx,%r15
  sub    $0x1,%r13d
  jae    L10
L87:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L78:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L89:
  movq   $0x0,0x18(%rsp)
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rax,%r14
  jmp    L87
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; (tmp = (strstr(ins, rep))); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<push_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **push_str(char **arr, char *str, int size) {
  char **newarr = malloc(sizeof(char *) * (size + 1));
  int i;
  newarr[0] = malloc(sizeof(char) * strlen(str));
  strcpy(newarr[0], str);
  for (i = 0; i < size; i++)
    newarr[i + 1] = arr[i];
  free(arr);
  return newarr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<push_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  lea    0x8(,%rdx,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %r13,%rsi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L14
  mov    %ebx,%ecx
  mov    $0x0,%eax
L7:
  mov    (%r12,%rax,8),%rdx
  mov    %rdx,0x8(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L7
L14:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **push_str(char **arr, char *str, int size) {
  char **newarr = malloc(sizeof(char *) * (size + 1));
  int i;
  newarr[0] = malloc(sizeof(char) * strlen(str));
  strcpy(newarr[0], str);
  for (i = 0; i < size; i++)
    newarr[i + 1] = arr[i];
  free(arr);
  return newarr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<push_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x8(,%rdx,8),%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,(%r12)
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L0
  movslq %ebx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  mov    0x0(%rbp,%rax,8),%rcx
  mov    %rcx,0x8(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L8
L0:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **push_str(char **arr, char *str, int size) {
  char **newarr = malloc(sizeof(char *) * (size + 1));
  int i;
  newarr[0] = malloc(sizeof(char) * strlen(str));
  strcpy(newarr[0], str);
  for (i = 0; i < size; i++)
    newarr[i + 1] = arr[i];
  free(arr);
  return newarr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<push_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  lea    0x8(,%rbx,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,(%r12)
  mov    %rax,%rdi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L37
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L68
  cmp    %rbp,%r12
  je     L68
  mov    %ebx,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L33:
  movdqu 0x0(%rbp,%rax,1),%xmm0
  movups %xmm0,0x8(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L33
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebx
  je     L37
  mov    0x0(%rbp,%rax,8),%rdx
  mov    %rdx,0x8(%r12,%rax,8)
L37:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L68:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L67:
  mov    0x0(%rbp,%rax,8),%rdx
  mov    %rdx,0x8(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L67
  jmp    L37
```

assistant: ```c
char **push_str(char **arr, char *str, int size) {
  char **newarr = malloc(sizeof(char *) * (size + 1));
  int i;
  newarr[0] = malloc(sizeof(char) * strlen(str));
  strcpy(newarr[0], str);
  for (i = 0; i < size; i++)
    newarr[i + 1] = arr[i];
  free(arr);
  return newarr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ffrprt@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
L9:
  nop
  leave
  ret
```

assistant: ```c
void printerror(int status) {
  if (status) {
    ffrprt(stderr, status);
    exit(status);
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printerror>:
  endbr64
  test   %edi,%edi
  jne    L4
  ret
L4:
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <ffrprt@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void printerror(int status) {
  if (status) {
    ffrprt(stderr, status);
    exit(status);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printerror>:
  endbr64
  test   %edi,%edi
  jne    L8
  ret
  nopl   0x0(%rax)
L8:
  mov    D5(%rip),%rax
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  mov    (%rax),%edi
  call   <ffrprt@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void printerror(int status) {
  if (status) {
    ffrprt(stderr, status);
    exit(status);
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<printerror>:
  endbr64
  test   %edi,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L7:
  mov    D6(%rip),%rax
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  mov    (%rax),%edi
  call   <ffrprt@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

assistant: ```c
void printerror(int status) {
  if (status) {
    ffrprt(stderr, status);
    exit(status);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<searchRightMost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L1:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L42
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L42
  mov    -0x4(%rbp),%eax
  jmp    L89
L42:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L31
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  je     L79
  mov    -0x4(%rbp),%eax
  jmp    L89
L79:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L32
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L92
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <searchRightMost>
  jmp    L32
L92:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <searchRightMost>
L32:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L1
  mov    $0xffffffff,%eax
L89:
  leave
  ret
```

assistant: ```c
int searchRightMost(int list[], int left, int right, int key) {
  int middle = 0;
  while (left <= right) {
    middle = left + (right - left) / 2;
    if (middle == right && list[middle] == key)
      return middle;
    if (key == list[middle]) {
      if (list[middle + 1] != key)
        return middle;
      else
        left = middle + 1;
    } else if (key > list[middle]) {
      left = middle + 1;
      searchRightMost(list, left, right, key);
    } else {
      right = middle - 1;
      searchRightMost(list, left, right, key);
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<searchRightMost>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r12d
  cmp    %edx,%esi
  jle    L86
  mov    $0xffffffff,%eax
  jmp    L87
L0:
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  je     L78
L24:
  cmp    %edx,%r12d
  jle    L19
  lea    0x1(%rax),%ebp
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <searchRightMost>
L12:
  cmp    %ebx,%ebp
  jg     L18
L86:
  mov    %ebx,%edx
  sub    %ebp,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ebp,%eax
  cmp    %ebx,%eax
  je     L0
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  jne    L24
  cmp    %r12d,0x4(%r13,%rcx,1)
  jne    L87
  lea    0x1(%rax),%ebp
  jmp    L12
L19:
  lea    -0x1(%rax),%ebx
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <searchRightMost>
  jmp    L12
L18:
  mov    $0xffffffff,%eax
L87:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L78:
  mov    %ebx,%eax
  jmp    L87
```

assistant: ```c
int searchRightMost(int list[], int left, int right, int key) {
  int middle = 0;
  while (left <= right) {
    middle = left + (right - left) / 2;
    if (middle == right && list[middle] == key)
      return middle;
    if (key == list[middle]) {
      if (list[middle + 1] != key)
        return middle;
      else
        left = middle + 1;
    } else if (key > list[middle]) {
      left = middle + 1;
      searchRightMost(list, left, right, key);
    } else {
      right = middle - 1;
      searchRightMost(list, left, right, key);
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<searchRightMost>:
  endbr64
  cmp    %edx,%esi
  jg     L24
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L18:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  jne    L54
  cmp    %r12d,0x4(%r13,%rcx,1)
  jne    L90
  lea    0x1(%rax),%ebp
  cmp    %ebp,%ebx
  jl     L52
L3:
  mov    %ebx,%eax
  sub    %ebp,%eax
  sar    %eax
  add    %ebp,%eax
  cmp    %ebx,%eax
  jne    L18
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  je     L90
L54:
  cmp    %edx,%r12d
  jle    L78
  lea    0x1(%rax),%ebp
L71:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <searchRightMost>
  cmp    %ebp,%ebx
  jge    L3
L52:
  mov    $0xffffffff,%eax
L90:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L78:
  lea    -0x1(%rax),%ebx
  jmp    L71
L24:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int searchRightMost(int list[], int left, int right, int key) {
  int middle = 0;
  while (left <= right) {
    middle = left + (right - left) / 2;
    if (middle == right && list[middle] == key)
      return middle;
    if (key == list[middle]) {
      if (list[middle + 1] != key)
        return middle;
      else
        left = middle + 1;
    } else if (key > list[middle]) {
      left = middle + 1;
      searchRightMost(list, left, right, key);
    } else {
      right = middle - 1;
      searchRightMost(list, left, right, key);
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<searchRightMost>:
  endbr64
  cmp    %edx,%esi
  jg     L48
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L5:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  jne    L29
  cmp    %r12d,0x4(%r13,%rcx,1)
  jne    L68
  lea    0x1(%rax),%ebp
  cmp    %ebp,%ebx
  jl     L28
L41:
  mov    %ebx,%eax
  sub    %ebp,%eax
  sar    %eax
  add    %ebp,%eax
  cmp    %ebx,%eax
  jne    L5
  movslq %ebx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  cmp    %r12d,%edx
  je     L68
L29:
  cmp    %edx,%r12d
  jle    L25
  lea    0x1(%rax),%ebp
L51:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <searchRightMost>
  cmp    %ebp,%ebx
  jge    L41
L28:
  mov    $0xffffffff,%eax
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L25:
  lea    -0x1(%rax),%ebx
  jmp    L51
L48:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int searchRightMost(int list[], int left, int right, int key) {
  int middle = 0;
  while (left <= right) {
    middle = left + (right - left) / 2;
    if (middle == right && list[middle] == key)
      return middle;
    if (key == list[middle]) {
      if (list[middle + 1] != key)
        return middle;
      else
        left = middle + 1;
    } else if (key > list[middle]) {
      left = middle + 1;
      searchRightMost(list, left, right, key);
    } else {
      right = middle - 1;
      searchRightMost(list, left, right, key);
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<timlib_trim_trailing_character>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *timlib_trim_trailing_character(char *source_destination, char character) {
  char *end_ptr;
  end_ptr = source_destination + strlen(source_destination) - 1;
  if (*end_ptr == character)
    *end_ptr = '\0';
  return source_destination;
}
```