ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsprintf(str, format, ap);
  va_end(ap);
  return strlen(str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsprintf(str, format, ap);
  va_end(ap);
  return strlen(str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsprintf(str, format, ap);
  va_end(ap);
  return strlen(str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *str, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  vsprintf(str, format, ap);
  va_end(ap);
  return strlen(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ti_ad_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ti_ad_start(double const *options) {
  (void)options;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ti_ad_start>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ti_ad_start(double const *options) {
  (void)options;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ti_ad_start>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int ti_ad_start(double const *options) {
  (void)options;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ti_ad_start>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int ti_ad_start(double const *options) {
  (void)options;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ResExistFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  movl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: r

assistant: ```c
int ResExistFile(char *fileName) {
  int retval = 0;
  FILE *tmpFile;
  tmpFile = fopen(fileName, "r");
  if (tmpFile) {
    fclose(tmpFile);
    retval = 1;
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ResExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L2
  call   <fclose@plt>
  mov    $0x1,%eax
L2:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: r

assistant: ```c
int ResExistFile(char *fileName) {
  int retval = 0;
  FILE *tmpFile;
  tmpFile = fopen(fileName, "r");
  if (tmpFile) {
    fclose(tmpFile);
    retval = 1;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ResExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  call   <fclose@plt>
  mov    $0x1,%eax
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: r

assistant: ```c
int ResExistFile(char *fileName) {
  int retval = 0;
  FILE *tmpFile;
  tmpFile = fopen(fileName, "r");
  if (tmpFile) {
    fclose(tmpFile);
    retval = 1;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ResExistFile>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  call   <fclose@plt>
  mov    $0x1,%eax
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: r

assistant: ```c
int ResExistFile(char *fileName) {
  int retval = 0;
  FILE *tmpFile;
  tmpFile = fopen(fileName, "r");
  if (tmpFile) {
    fclose(tmpFile);
    retval = 1;
  }
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<y162rgb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%r12d
  mov    -0x30(%rbp),%rax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%rax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,%ebx
  jmp    L18
L5:
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%r13d
  mov    %r12d,%eax
  lea    -0x1(%rax),%r12d
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  lea    0x0(%r13,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%r13d
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %r13d,%edx
  mov    %dl,(%rax)
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %r13d,%edx
  mov    %dl,(%rax)
  mov    %ebx,%eax
  lea    -0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %r13d,%edx
  mov    %dl,(%rax)
L18:
  test   %r12d,%r12d
  jg     L5
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void y162rgb(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = NumPixels + (NumPixels << 1) - 1;
  register int y;
  while (i > 0) {
    y = src[i--];
    y = (y + (src[i--] << 8)) >> (bits - 8);
    dest[j--] = y;
    dest[j--] = y;
    dest[j--] = y;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<y162rgb>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  lea    -0x1(%rax),%r8d
  lea    -0x1(%rax,%rdx,1),%edx
  test   %r8d,%r8d
  jle    L2
  movslq %r8d,%r8
  add    %r8,%rdi
  movslq %edx,%r8
  lea    (%rsi,%r8,1),%rdx
  lea    -0x3(%rsi,%r8,1),%r8
  sub    $0x2,%eax
  shr    %eax
  mov    %eax,%eax
  lea    (%rax,%rax,2),%rax
  sub    %rax,%r8
  sub    $0x8,%ecx
L19:
  movzbl -0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%esi
  add    %esi,%eax
  sar    %cl,%eax
  mov    %al,(%rdx)
  mov    %al,-0x1(%rdx)
  mov    %al,-0x2(%rdx)
  sub    $0x2,%rdi
  sub    $0x3,%rdx
  cmp    %r8,%rdx
  jne    L19
L2:
  ret
```

assistant: ```c
void y162rgb(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = NumPixels + (NumPixels << 1) - 1;
  register int y;
  while (i > 0) {
    y = src[i--];
    y = (y + (src[i--] << 8)) >> (bits - 8);
    dest[j--] = y;
    dest[j--] = y;
    dest[j--] = y;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<y162rgb>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  mov    %rsi,%r8
  lea    -0x1(%rax),%r9d
  lea    -0x1(%rax,%rdx,1),%edx
  test   %r9d,%r9d
  jle    L16
  movslq %r9d,%r9
  sub    $0x2,%eax
  sub    $0x8,%ecx
  lea    (%rdi,%r9,1),%rsi
  shr    %eax
  movslq %edx,%rdi
  lea    (%r8,%rdi,1),%rdx
  lea    (%rax,%rax,2),%rax
  lea    -0x3(%r8,%rdi,1),%r8
  sub    %rax,%r8
  nopl   0x0(%rax)
L14:
  movzbl -0x1(%rsi),%eax
  movzbl (%rsi),%edi
  sub    $0x3,%rdx
  sub    $0x2,%rsi
  shl    $0x8,%eax
  add    %edi,%eax
  sar    %cl,%eax
  mov    %al,0x3(%rdx)
  mov    %al,0x2(%rdx)
  mov    %al,0x1(%rdx)
  cmp    %rdx,%r8
  jne    L14
L16:
  ret
```

assistant: ```c
void y162rgb(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = NumPixels + (NumPixels << 1) - 1;
  register int y;
  while (i > 0) {
    y = src[i--];
    y = (y + (src[i--] << 8)) >> (bits - 8);
    dest[j--] = y;
    dest[j--] = y;
    dest[j--] = y;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<y162rgb>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  mov    %rsi,%r8
  lea    -0x1(%rax),%r9d
  lea    -0x1(%rax,%rdx,1),%edx
  test   %r9d,%r9d
  jle    L11
  movslq %r9d,%r9
  sub    $0x2,%eax
  sub    $0x8,%ecx
  lea    (%rdi,%r9,1),%rsi
  shr    %eax
  movslq %edx,%rdi
  lea    (%r8,%rdi,1),%rdx
  lea    (%rax,%rax,2),%rax
  lea    -0x3(%r8,%rdi,1),%r8
  sub    %rax,%r8
  nopl   0x0(%rax)
L6:
  movzbl -0x1(%rsi),%eax
  movzbl (%rsi),%edi
  sub    $0x3,%rdx
  sub    $0x2,%rsi
  shl    $0x8,%eax
  add    %edi,%eax
  sar    %cl,%eax
  mov    %al,0x3(%rdx)
  mov    %al,0x2(%rdx)
  mov    %al,0x1(%rdx)
  cmp    %rdx,%r8
  jne    L6
L11:
  ret
```

assistant: ```c
void y162rgb(unsigned char *src, unsigned char *dest, unsigned long long int NumPixels, int bits) {
  register int i = (NumPixels << 1) - 1;
  register int j = NumPixels + (NumPixels << 1) - 1;
  register int y;
  while (i > 0) {
    y = src[i--];
    y = (y + (src[i--] << 8)) >> (bits - 8);
    dest[j--] = y;
    dest[j--] = y;
    dest[j--] = y;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jg     L17
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L17:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jb     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void chomp(char *str) {
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (str[i] <= 0x0d) {
      str[i] = '\0';
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chomp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L33
L7:
  add    $0x1,%ebx
L33:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L14
  mov    %ebx,%eax
  add    %rbp,%rax
  cmpb   $0xd,(%rax)
  jg     L7
  movb   $0x0,(%rax)
  jmp    L7
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *str) {
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (str[i] <= 0x0d) {
      str[i] = '\0';
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L22
  nopl   0x0(%rax)
L3:
  mov    %ebx,%eax
  add    %rbp,%rax
  cmpb   $0xd,(%rax)
  jg     L14
  movb   $0x0,(%rax)
L14:
  add    $0x1,%ebx
L22:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *str) {
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (str[i] <= 0x0d) {
      str[i] = '\0';
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax)
L13:
  mov    %ebx,%eax
  add    %rbp,%rax
  cmpb   $0xd,(%rax)
  jg     L20
  movb   $0x0,(%rax)
L20:
  add    $0x1,%ebx
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *str) {
  for (unsigned int i = 0; i < strlen(str); i++) {
    if (str[i] <= 0x0d) {
      str[i] = '\0';
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unpointerfy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L59
L44:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xc0,%al
  jne    L24
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <pointerFollower@plt>
  mov    %rax,-0x8(%rbp)
  addl   $0x2,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L39
L49:
  addl   $0x1,-0x14(%rbp)
L39:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x18(%rbp)
  jmp    L59
L24:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L59:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L44
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *unpointerfy(unsigned char *response, int initLocation, int size) {
  int currentLocation = initLocation;
  unsigned char *fixedResponse = (unsigned char *)calloc(size * 5, sizeof(char));
  int bytesAdded = 0;
  memset(fixedResponse, 0, size * 5);
  while (currentLocation < size) {
    if (*(response + currentLocation) == 0xc0) {
      unsigned char *tmpnamebuf = (unsigned char *)calloc(100, sizeof(unsigned char));
      memset(tmpnamebuf, 0, 100);
      tmpnamebuf = pointerFollower(response, *(response + currentLocation + 1), currentLocation);
      currentLocation += 2;
      int i = 0;
      while (tmpnamebuf[i] != '\0') {
        i++;
      }
      memcpy(fixedResponse + bytesAdded, tmpnamebuf, i);
      bytesAdded += i + 1;
    } else {
      memcpy(fixedResponse + bytesAdded, response + currentLocation, 1);
      currentLocation++;
      bytesAdded++;
    }
  }
  return fixedResponse;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unpointerfy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    (%rdx,%rdx,4),%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,%r15
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmp    %r12d,%ebx
  jge    L62
  mov    $0x0,%ebp
  jmp    L11
L13:
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    $0x64,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl 0x1(%r13,%r14,1),%esi
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <pointerFollower@plt>
  mov    %rax,%rsi
  add    $0x2,%ebx
  cmpb   $0x0,(%rax)
  je     L40
  mov    $0x1,%edx
L6:
  mov    %edx,%r14d
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rsi,%rdx,1)
  jne    L6
L77:
  movslq %ebp,%rdi
  add    %r15,%rdi
  mov    %r14d,%edx
  call   <memcpy@plt>
  lea    0x1(%rbp,%r14,1),%ebp
L20:
  cmp    %r12d,%ebx
  jge    L62
L11:
  movslq %ebx,%r14
  lea    0x0(%r13,%r14,1),%rsi
  cmpb   $0xc0,(%rsi)
  je     L13
  movslq %ebp,%rdi
  add    %r15,%rdi
  mov    $0x1,%edx
  call   <memcpy@plt>
  add    $0x1,%ebx
  add    $0x1,%ebp
  jmp    L20
L40:
  mov    $0x0,%r14d
  jmp    L77
L62:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *unpointerfy(unsigned char *response, int initLocation, int size) {
  int currentLocation = initLocation;
  unsigned char *fixedResponse = (unsigned char *)calloc(size * 5, sizeof(char));
  int bytesAdded = 0;
  memset(fixedResponse, 0, size * 5);
  while (currentLocation < size) {
    if (*(response + currentLocation) == 0xc0) {
      unsigned char *tmpnamebuf = (unsigned char *)calloc(100, sizeof(unsigned char));
      memset(tmpnamebuf, 0, 100);
      tmpnamebuf = pointerFollower(response, *(response + currentLocation + 1), currentLocation);
      currentLocation += 2;
      int i = 0;
      while (tmpnamebuf[i] != '\0') {
        i++;
      }
      memcpy(fixedResponse + bytesAdded, tmpnamebuf, i);
      bytesAdded += i + 1;
    } else {
      memcpy(fixedResponse + bytesAdded, response + currentLocation, 1);
      currentLocation++;
      bytesAdded++;
    }
  }
  return fixedResponse;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unpointerfy>:
  endbr64
  push   %r15
  lea    (%rdx,%rdx,4),%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %r15d,%edi
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x1,%esi
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <calloc@plt>
  xor    %esi,%esi
  mov    %r15d,%edx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memset@plt>
  cmp    %ebp,%ebx
  jge    L1
  xor    %r12d,%r12d
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x1,%r12d
  call   <memcpy@plt>
  cmp    0xc(%rsp),%ebx
  jge    L1
L36:
  movslq %ebx,%r15
  movslq %r12d,%rbp
  lea    0x0(%r13,%r15,1),%rsi
  add    %r14,%rbp
  cmpb   $0xc0,(%rsi)
  jne    L6
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  xor    %esi,%esi
  mov    $0x64,%edx
  mov    %rax,%rdi
  call   <memset@plt>
  movzbl 0x1(%r13,%r15,1),%esi
  mov    %ebx,%edx
  mov    %r13,%rdi
  add    $0x2,%ebx
  call   <pointerFollower@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rsi
  je     L7
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %edx,%r8d
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rsi,%rdx,1)
  jne    L57
  lea    0x1(%r8),%r15d
L2:
  mov    %r8d,%edx
  mov    %rbp,%rdi
  add    %r15d,%r12d
  call   <memcpy@plt>
  cmp    0xc(%rsp),%ebx
  jl     L36
L1:
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%r15d
  xor    %r8d,%r8d
  jmp    L2
```

assistant: ```c
unsigned char *unpointerfy(unsigned char *response, int initLocation, int size) {
  int currentLocation = initLocation;
  unsigned char *fixedResponse = (unsigned char *)calloc(size * 5, sizeof(char));
  int bytesAdded = 0;
  memset(fixedResponse, 0, size * 5);
  while (currentLocation < size) {
    if (*(response + currentLocation) == 0xc0) {
      unsigned char *tmpnamebuf = (unsigned char *)calloc(100, sizeof(unsigned char));
      memset(tmpnamebuf, 0, 100);
      tmpnamebuf = pointerFollower(response, *(response + currentLocation + 1), currentLocation);
      currentLocation += 2;
      int i = 0;
      while (tmpnamebuf[i] != '\0') {
        i++;
      }
      memcpy(fixedResponse + bytesAdded, tmpnamebuf, i);
      bytesAdded += i + 1;
    } else {
      memcpy(fixedResponse + bytesAdded, response + currentLocation, 1);
      currentLocation++;
      bytesAdded++;
    }
  }
  return fixedResponse;
}
```