ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc_revbits>:
  endbr64
  cmp    $0x40,%esi
  je     L33
  mov    $0x1,%r8d
  mov    %esi,%ecx
  xor    %eax,%eax
  shl    %cl,%r8d
  test   %esi,%esi
  je     L7
L29:
  xor    %eax,%eax
  mov    $0x1,%edx
  nopl   0x0(%rax)
L12:
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   %edi,%edx
  cmovne %ecx,%eax
  add    %edx,%edx
  cmp    %edx,%r8d
  jne    L12
  ret
  nopl   0x0(%rax)
L33:
  xor    %r8d,%r8d
  jmp    L29
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
uint64_t crc_revbits(uint64_t v, int length) {
  uint64_t i;
  uint64_t ov;
  uint64_t stop;
  if (length == 64)
    stop = 0;
  else
    stop = (uint64_t)1 << length;
  ov = 0;
  for (i = 1; i != stop; i <<= 1) {
    ov <<= 1;
    if (v & i) {
      ov |= 1;
    }
  }
  return ov;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_data_avltree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <find_name_node_avltree@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L10
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_node_data_avltree@plt>
L10:
  leave
  ret
```

assistant: ```c
void *find_data_avltree(struct avl_tree *t, char *key) {
  struct avl_node *n;
  n = find_name_node_avltree(t, key);
  if (n == NULL)
    return NULL;
  return get_node_data_avltree(n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_data_avltree>:
  endbr64
  sub    $0x8,%rsp
  call   <find_name_node_avltree@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <get_node_data_avltree@plt>
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *find_data_avltree(struct avl_tree *t, char *key) {
  struct avl_node *n;
  n = find_name_node_avltree(t, key);
  if (n == NULL)
    return NULL;
  return get_node_data_avltree(n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_data_avltree>:
  endbr64
  sub    $0x8,%rsp
  call   <find_name_node_avltree@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <get_node_data_avltree@plt>
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *find_data_avltree(struct avl_tree *t, char *key) {
  struct avl_node *n;
  n = find_name_node_avltree(t, key);
  if (n == NULL)
    return NULL;
  return get_node_data_avltree(n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_data_avltree>:
  endbr64
  sub    $0x8,%rsp
  call   <find_name_node_avltree@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1070 <get_node_data_avltree@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *find_data_avltree(struct avl_tree *t, char *key) {
  struct avl_node *n;
  n = find_name_node_avltree(t, key);
  if (n == NULL)
    return NULL;
  return get_node_data_avltree(n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: i am child


assistant: ```c
int main(int argc, void **argv) {
  printf("i am child\n");
  return 1 / 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: i am child


assistant: ```c
int main(int argc, void **argv) {
  printf("i am child\n");
  return 1 / 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  ud2
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: i am child


assistant: ```c
int main(int argc, void **argv) {
  printf("i am child\n");
  return 1 / 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  ud2
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: i am child


assistant: ```c
int main(int argc, void **argv) {
  printf("i am child\n");
  return 1 / 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fd_gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %ecx,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jg     L153
  movl   $0x1,-0x44(%rbp)
L153:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L157
L92:
  mov    -0x44(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L97
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x44(%rbp)
L97:
  mov    -0x44(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jns    L116
  mov    $0xffffffff,%eax
  jmp    L88
L116:
  cmpl   $0x0,-0x20(%rbp)
  je     L119
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L152
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L158
  addq   $0x1,-0x10(%rbp)
L152:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L14
  jmp    L30
L158:
  nop
L30:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L25
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  mov    -0x34(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  test   %rax,%rax
  jns    L49
  mov    $0xffffffff,%eax
  jmp    L88
L25:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  sub    %eax,-0x24(%rbp)
L157:
  cmpl   $0x0,-0x24(%rbp)
  jg     L92
  jmp    L141
L119:
  nop
  jmp    L141
L49:
  nop
L141:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x40(%rbp),%rax
L88:
  leave
  ret
```

assistant: ```c
int fd_gets(int fd, char *buff, const int size, int once_bytes) {
  char *pDest;
  char *p;
  char *pEnd;
  int read_bytes;
  int remain_bytes;
  int rewind_bytes;
  if (once_bytes <= 0) {
    once_bytes = 1;
  }
  pDest = buff;
  remain_bytes = size - 1;
  while (remain_bytes > 0) {
    if (once_bytes > remain_bytes) {
      once_bytes = remain_bytes;
    }
    read_bytes = read(fd, pDest, once_bytes);
    if (read_bytes < 0) {
      return -1;
    }
    if (read_bytes == 0) {
      break;
    }
    pEnd = pDest + read_bytes;
    for (p = pDest; p < pEnd; p++) {
      if (*p == '\n') {
        break;
      }
    }
    if (p < pEnd) {
      pDest = p + 1;
      rewind_bytes = pEnd - pDest;
      if (lseek(fd, -1 * rewind_bytes, SEEK_CUR) < 0) {
        return -1;
      }
      break;
    }
    pDest = pEnd;
    remain_bytes -= read_bytes;
  }
  *pDest = '\0';
  return pDest - buff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fd_gets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r13
  test   %ecx,%ecx
  mov    $0x1,%eax
  cmovg  %ecx,%eax
  lea    -0x1(%rdx),%ebp
  test   %ebp,%ebp
  jle    L55
  mov    %edi,%r14d
  mov    %eax,%r12d
  mov    %rsi,%rbx
  jmp    L19
L23:
  cmp    %rbx,%rdx
  ja     L6
L107:
  sub    %eax,%ebp
  test   %ebp,%ebp
  jle    L148
  mov    %rdx,%rbx
L19:
  cmp    %ebp,%r12d
  cmovg  %ebp,%r12d
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L116
  je     L112
  movslq %eax,%rdx
  add    %rbx,%rdx
  cmp    %rbx,%rdx
  jbe    L107
L0:
  cmpb   $0xa,(%rbx)
  je     L23
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  jne    L0
  jmp    L107
L6:
  add    $0x1,%rbx
  mov    %ebx,%esi
  sub    %edx,%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    %r14d,%edi
  call   <lseek@plt>
  test   %rax,%rax
  js     L41
L112:
  movb   $0x0,(%rbx)
  mov    %ebx,%eax
  sub    %r13d,%eax
L138:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L148:
  mov    %rdx,%rbx
  jmp    L112
L55:
  mov    %rsi,%rbx
  jmp    L112
L116:
  mov    $0xffffffff,%eax
  jmp    L138
L41:
  mov    $0xffffffff,%eax
  jmp    L138
```

assistant: ```c
int fd_gets(int fd, char *buff, const int size, int once_bytes) {
  char *pDest;
  char *p;
  char *pEnd;
  int read_bytes;
  int remain_bytes;
  int rewind_bytes;
  if (once_bytes <= 0) {
    once_bytes = 1;
  }
  pDest = buff;
  remain_bytes = size - 1;
  while (remain_bytes > 0) {
    if (once_bytes > remain_bytes) {
      once_bytes = remain_bytes;
    }
    read_bytes = read(fd, pDest, once_bytes);
    if (read_bytes < 0) {
      return -1;
    }
    if (read_bytes == 0) {
      break;
    }
    pEnd = pDest + read_bytes;
    for (p = pDest; p < pEnd; p++) {
      if (*p == '\n') {
        break;
      }
    }
    if (p < pEnd) {
      pDest = p + 1;
      rewind_bytes = pEnd - pDest;
      if (lseek(fd, -1 * rewind_bytes, SEEK_CUR) < 0) {
        return -1;
      }
      break;
    }
    pDest = pEnd;
    remain_bytes -= read_bytes;
  }
  *pDest = '\0';
  return pDest - buff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fd_gets>:
  endbr64
  push   %r14
  test   %ecx,%ecx
  mov    $0x1,%eax
  push   %r13
  cmovg  %ecx,%eax
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L9
  mov    %edi,%r14d
  mov    %eax,%r13d
  mov    %rsi,%rbx
  nop
L119:
  cmp    %r12d,%r13d
  mov    %rbx,%rsi
  mov    %r14d,%edi
  cmovg  %r12d,%r13d
  mov    %r13d,%edx
  call   <read@plt>
  test   %eax,%eax
  js     L17
  je     L78
  movslq %eax,%rdx
  add    %rbx,%rdx
  cmp    %rbx,%rdx
  ja     L82
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L84:
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  je     L97
L82:
  cmpb   $0xa,(%rbx)
  jne    L84
  cmp    %rbx,%rdx
  ja     L114
L97:
  sub    %eax,%r12d
  test   %r12d,%r12d
  jle    L108
  mov    %rdx,%rbx
  jmp    L119
L114:
  add    $0x1,%rbx
  mov    D3(%rip),%rax
  mov    %r14d,%edi
  mov    %ebx,%esi
  sub    %edx,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L17
L78:
  mov    %ebx,%eax
  sub    %ebp,%eax
L71:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L108:
  mov    %edx,%eax
  mov    %rdx,%rbx
  sub    %ebp,%eax
  jmp    L71
L9:
  mov    %rsi,%rbx
  xor    %eax,%eax
  jmp    L71
```

assistant: ```c
int fd_gets(int fd, char *buff, const int size, int once_bytes) {
  char *pDest;
  char *p;
  char *pEnd;
  int read_bytes;
  int remain_bytes;
  int rewind_bytes;
  if (once_bytes <= 0) {
    once_bytes = 1;
  }
  pDest = buff;
  remain_bytes = size - 1;
  while (remain_bytes > 0) {
    if (once_bytes > remain_bytes) {
      once_bytes = remain_bytes;
    }
    read_bytes = read(fd, pDest, once_bytes);
    if (read_bytes < 0) {
      return -1;
    }
    if (read_bytes == 0) {
      break;
    }
    pEnd = pDest + read_bytes;
    for (p = pDest; p < pEnd; p++) {
      if (*p == '\n') {
        break;
      }
    }
    if (p < pEnd) {
      pDest = p + 1;
      rewind_bytes = pEnd - pDest;
      if (lseek(fd, -1 * rewind_bytes, SEEK_CUR) < 0) {
        return -1;
      }
      break;
    }
    pDest = pEnd;
    remain_bytes -= read_bytes;
  }
  *pDest = '\0';
  return pDest - buff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd_gets>:
  endbr64
  push   %r14
  test   %ecx,%ecx
  mov    $0x1,%eax
  push   %r13
  cmovg  %ecx,%eax
  push   %r12
  lea    -0x1(%rdx),%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L64
  mov    %edi,%r14d
  mov    %eax,%r13d
  mov    %rsi,%rbx
  nop
L71:
  cmp    %r12d,%r13d
  mov    %rbx,%rsi
  mov    %r14d,%edi
  cmovg  %r12d,%r13d
  mov    %r13d,%edx
  call   <read@plt>
  test   %eax,%eax
  js     L104
  je     L41
  movslq %eax,%rdx
  add    %rbx,%rdx
  cmp    %rbx,%rdx
  ja     L18
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L83:
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  je     L66
L18:
  cmpb   $0xa,(%rbx)
  jne    L83
  cmp    %rbx,%rdx
  ja     L28
L66:
  sub    %eax,%r12d
  test   %r12d,%r12d
  jle    L2
  mov    %rdx,%rbx
  jmp    L71
L28:
  add    $0x1,%rbx
  mov    D1(%rip),%rax
  mov    %r14d,%edi
  mov    %ebx,%esi
  sub    %edx,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L104
L41:
  mov    %ebx,%eax
  sub    %ebp,%eax
L16:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L104:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    %edx,%eax
  mov    %rdx,%rbx
  sub    %ebp,%eax
  jmp    L16
L64:
  mov    %rsi,%rbx
  xor    %eax,%eax
  jmp    L16
```

assistant: ```c
int fd_gets(int fd, char *buff, const int size, int once_bytes) {
  char *pDest;
  char *p;
  char *pEnd;
  int read_bytes;
  int remain_bytes;
  int rewind_bytes;
  if (once_bytes <= 0) {
    once_bytes = 1;
  }
  pDest = buff;
  remain_bytes = size - 1;
  while (remain_bytes > 0) {
    if (once_bytes > remain_bytes) {
      once_bytes = remain_bytes;
    }
    read_bytes = read(fd, pDest, once_bytes);
    if (read_bytes < 0) {
      return -1;
    }
    if (read_bytes == 0) {
      break;
    }
    pEnd = pDest + read_bytes;
    for (p = pDest; p < pEnd; p++) {
      if (*p == '\n') {
        break;
      }
    }
    if (p < pEnd) {
      pDest = p + 1;
      rewind_bytes = pEnd - pDest;
      if (lseek(fd, -1 * rewind_bytes, SEEK_CUR) < 0) {
        return -1;
      }
      break;
    }
    pDest = pEnd;
    remain_bytes -= read_bytes;
  }
  *pDest = '\0';
  return pDest - buff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_Zd_distance_squared>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_Zd_distance_squared(int xi, int xj, int xk, int yi, int yj, int yk) {
  int dsq;
  int tmp;
  tmp = xi - yi;
  dsq = tmp * tmp;
  tmp = xj - yj;
  dsq += tmp * tmp;
  tmp = xk - yk;
  dsq += tmp * tmp;
  return dsq;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_Zd_distance_squared>:
  endbr64
  sub    %ecx,%edi
  imul   %edi,%edi
  sub    %r8d,%esi
  imul   %esi,%esi
  add    %edi,%esi
  sub    %r9d,%edx
  imul   %edx,%edx
  lea    (%rdx,%rsi,1),%eax
  ret
```

assistant: ```c
int get_Zd_distance_squared(int xi, int xj, int xk, int yi, int yj, int yk) {
  int dsq;
  int tmp;
  tmp = xi - yi;
  dsq = tmp * tmp;
  tmp = xj - yj;
  dsq += tmp * tmp;
  tmp = xk - yk;
  dsq += tmp * tmp;
  return dsq;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_Zd_distance_squared>:
  endbr64
  sub    %ecx,%edi
  sub    %r8d,%esi
  sub    %r9d,%edx
  imul   %edi,%edi
  imul   %esi,%esi
  imul   %edx,%edx
  add    %edi,%esi
  lea    (%rdx,%rsi,1),%eax
  ret
```

assistant: ```c
int get_Zd_distance_squared(int xi, int xj, int xk, int yi, int yj, int yk) {
  int dsq;
  int tmp;
  tmp = xi - yi;
  dsq = tmp * tmp;
  tmp = xj - yj;
  dsq += tmp * tmp;
  tmp = xk - yk;
  dsq += tmp * tmp;
  return dsq;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_Zd_distance_squared>:
  endbr64
  sub    %ecx,%edi
  sub    %r8d,%esi
  sub    %r9d,%edx
  imul   %edi,%edi
  imul   %esi,%esi
  imul   %edx,%edx
  add    %edi,%esi
  lea    (%rdx,%rsi,1),%eax
  ret
```

assistant: ```c
int get_Zd_distance_squared(int xi, int xj, int xk, int yi, int yj, int yk) {
  int dsq;
  int tmp;
  tmp = xi - yi;
  dsq = tmp * tmp;
  tmp = xj - yj;
  dsq += tmp * tmp;
  tmp = xk - yk;
  dsq += tmp * tmp;
  return dsq;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ssim_end1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    D13(%rip),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    D6(%rip),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  add    %eax,%edx
  mov    D13(%rip),%eax
  add    %edx,%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  mov    D6(%rip),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
data_type: byte[4]
name: parse_data
arguments: tag: D6
data_type: byte[4]

tool: {"D13": [0xa0,0x01,0x00,0x00]}

tool: {"D6": [0xbb,0x99,0x03,0x00]}

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  imul   %edi,%r8d
  mov    %esi,%eax
  imul   %esi,%eax
  imul   %esi,%edi
  shl    $0x6,%ecx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm1
  mulss  %xmm1,%xmm0
  shl    $0x6,%edx
  sub    %r8d,%edx
  sub    %eax,%edx
  add    $0x399bb,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  lea    0x1a0(%r8,%rax,1),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  shl    $0x6,%ecx
  pxor   %xmm0,%xmm0
  mov    %esi,%eax
  imul   %edi,%r8d
  pxor   %xmm1,%xmm1
  shl    $0x6,%edx
  pxor   %xmm2,%xmm2
  imul   %esi,%edi
  imul   %esi,%eax
  sub    %r8d,%edx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  sub    %eax,%edx
  lea    0x1a0(%r8,%rax,1),%eax
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  add    $0x399bb,%edx
  cvtsi2ss %ecx,%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssim_end1>:
  endbr64
  mov    %edi,%r8d
  shl    $0x6,%ecx
  pxor   %xmm0,%xmm0
  mov    %esi,%eax
  imul   %edi,%r8d
  pxor   %xmm1,%xmm1
  shl    $0x6,%edx
  pxor   %xmm2,%xmm2
  imul   %esi,%edi
  imul   %esi,%eax
  sub    %r8d,%edx
  sub    %edi,%ecx
  lea    0x399bb(%rcx,%rcx,1),%ecx
  sub    %eax,%edx
  lea    0x1a0(%r8,%rax,1),%eax
  cvtsi2ss %ecx,%xmm0
  lea    0x1a0(%rdi,%rdi,1),%ecx
  add    $0x399bb,%edx
  cvtsi2ss %ecx,%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  mulss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ssim_end1(int s1, int s2, int ss, int s12) {
  static const int ssim_c1 = (int)(.01 * .01 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 + .5);
  static const int ssim_c2 = (int)(.03 * .03 * ((1 << 8) - 1) * ((1 << 8) - 1) * 64 * 63 + .5);
  int fs1 = s1;
  int fs2 = s2;
  int fss = ss;
  int fs12 = s12;
  int vars = fss * 64 - fs1 * fs1 - fs2 * fs2;
  int covar = fs12 * 64 - fs1 * fs2;
  return (float)(2 * fs1 * fs2 + ssim_c1) * (float)(2 * covar + ssim_c2) / ((float)(fs1 * fs1 + fs2 * fs2 + ssim_c1) * (float)(vars + ssim_c2));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x31,-0xa(%rbp)
  movzbl -0xa(%rbp),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  char arr[2] = "1";
  return arr[0] + arr[1];
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x31,%eax
  ret
```

assistant: ```c
int main() {
  char arr[2] = "1";
  return arr[0] + arr[1];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x31,%eax
  ret
```

assistant: ```c
int main() {
  char arr[2] = "1";
  return arr[0] + arr[1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x31,%eax
  ret
```

assistant: ```c
int main() {
  char arr[2] = "1";
  return arr[0] + arr[1];
}
```