ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readConditionBlockAndCount>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  lea    D38(%rip),%r13
  lea    D54(%rip),%r12
  lea    D36(%rip),%r15
L10:
  lea    D21(%rip),%r14
  jmp    L83
L99:
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L52
L77:
  lea    0x10(%rsp),%rdi
  lea    D59(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L88
L83:
  lea    0x10(%rsp),%rbx
L9:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  test   %ebp,%ebp
  je     L99
  cmp    $0x1,%ebp
  jne    L77
  lea    0x10(%rsp),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L77
L52:
  lea    0x10(%rsp),%rdi
  lea    D21(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L96
L61:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    0x8(%rsp),%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L88:
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  mov    $0x0,%esi
  call   <readConditionBlockAndCount>
  imul   0x8(%rsp),%eax
  mov    %eax,0x8(%rsp)
  jmp    L10
L96:
  mov    0xc(%rsp),%edi
  add    $0x1,%edi
  mov    $0x1,%esi
  call   <readConditionBlockAndCount>
  add    %eax,0x8(%rsp)
  jmp    L61
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D54
type_infered: string
name: extract_symbolic_data
arguments: tag: D36
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D59
type_infered: string

tool: D38: %s

tool: D54: S

tool: D36: END_IF

tool: D21: ELSE

tool: D59: IF

assistant: ```c
int readConditionBlockAndCount(int level, int kind_block) {
  char word[100 + 1];
  int count = 1;
  while (1) {
    scanf("%s", word);
    if (strcmp(word, "S") == 0)
      continue;
    if (kind_block == 0 && strcmp(word, "ELSE") == 0)
      break;
    if (kind_block == 1 && strcmp(word, "END_IF") == 0)
      break;
    if (strcmp(word, "IF") == 0)
      count *= readConditionBlockAndCount(level + 1, 0);
  }
  if (strcmp(word, "ELSE") == 0)
    count += readConditionBlockAndCount(level + 1, 1);
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readConditionBlockAndCount>:
  endbr64
  push   %r15
  push   %r14
  lea    D38(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x88,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  nopl   0x0(%rax)
L61:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L61
  test   %ebx,%ebx
  je     L80
  cmp    $0x1,%ebx
  jne    L55
  lea    D33(%rip),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L68
L55:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
  mov    0xc(%rsp),%eax
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <readConditionBlockAndCount>
  imul   0x8(%rsp),%eax
  mov    %eax,0x8(%rsp)
  jmp    L61
  nopl   0x0(%rax)
L80:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L55
L68:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L4
L7:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    0x8(%rsp),%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    0xc(%rsp),%edi
  mov    $0x1,%esi
  add    $0x1,%edi
  call   <readConditionBlockAndCount>
  add    %eax,0x8(%rsp)
  jmp    L7
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D33
type_guessed: string

tool: D38: ELSE

tool: D15: IF

tool: D37: %s

tool: D9: S

tool: D33: END_IF

assistant: ```c
int readConditionBlockAndCount(int level, int kind_block) {
  char word[100 + 1];
  int count = 1;
  while (1) {
    scanf("%s", word);
    if (strcmp(word, "S") == 0)
      continue;
    if (kind_block == 0 && strcmp(word, "ELSE") == 0)
      break;
    if (kind_block == 1 && strcmp(word, "END_IF") == 0)
      break;
    if (strcmp(word, "IF") == 0)
      count *= readConditionBlockAndCount(level + 1, 0);
  }
  if (strcmp(word, "ELSE") == 0)
    count += readConditionBlockAndCount(level + 1, 1);
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readConditionBlockAndCount>:
  endbr64
  push   %r15
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x88,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  nopl   0x0(%rax)
L76:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L76
  test   %ebx,%ebx
  je     L0
  cmp    $0x1,%ebx
  jne    L14
  lea    D17(%rip),%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L65
L14:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L76
  mov    0xc(%rsp),%eax
  xor    %esi,%esi
  lea    0x1(%rax),%edi
  call   <readConditionBlockAndCount>
  imul   0x8(%rsp),%eax
  mov    %eax,0x8(%rsp)
  jmp    L76
  nopl   0x0(%rax)
L0:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
L65:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L94
L9:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    0x8(%rsp),%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    0xc(%rsp),%edi
  mov    $0x1,%esi
  add    $0x1,%edi
  call   <readConditionBlockAndCount>
  add    %eax,0x8(%rsp)
  jmp    L9
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string

tool: D12: ELSE

tool: D11: IF

tool: D21: %s

tool: D25: S

tool: D17: END_IF

assistant: ```c
int readConditionBlockAndCount(int level, int kind_block) {
  char word[100 + 1];
  int count = 1;
  while (1) {
    scanf("%s", word);
    if (strcmp(word, "S") == 0)
      continue;
    if (kind_block == 0 && strcmp(word, "ELSE") == 0)
      break;
    if (kind_block == 1 && strcmp(word, "END_IF") == 0)
      break;
    if (strcmp(word, "IF") == 0)
      count *= readConditionBlockAndCount(level + 1, 0);
  }
  if (strcmp(word, "ELSE") == 0)
    count += readConditionBlockAndCount(level + 1, 1);
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L6
L7:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L29
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  test   %rax,%rax
  jne    L7
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 && (*s1 == *s2) && n--) {
    s1++;
    s2++;
  }
  return *s1 - *s2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  add    %rdi,%rdx
L26:
  cmp    %al,(%rsi)
  jne    L20
  cmp    %rdi,%rdx
  je     L20
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
L20:
  movsbl %al,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 && (*s1 == *s2) && n--) {
    s1++;
    s2++;
  }
  return *s1 - *s2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  add    %rdi,%rdx
  test   %al,%al
  jne    L43
  jmp    L32
L31:
  cmp    %rdi,%rdx
  je     L2
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rcx
  test   %al,%al
  je     L52
  mov    %rcx,%rsi
L43:
  movsbl (%rsi),%ecx
  cmp    %al,%cl
  je     L31
L2:
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  movsbl 0x1(%rsi),%ecx
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
L32:
  movsbl (%rsi),%ecx
  xor    %eax,%eax
  jmp    L2
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 && (*s1 == *s2) && n--) {
    s1++;
    s2++;
  }
  return *s1 - *s2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  add    %rdi,%rdx
  test   %al,%al
  jne    L30
  jmp    L52
L24:
  cmp    %rdi,%rdx
  je     L53
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rcx
  test   %al,%al
  je     L33
  mov    %rcx,%rsi
L30:
  movsbl (%rsi),%ecx
  cmp    %al,%cl
  je     L24
L53:
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  movsbl 0x1(%rsi),%ecx
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
L52:
  movsbl (%rsi),%ecx
  xor    %eax,%eax
  jmp    L53
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  while (*s1 && (*s1 == *s2) && n--) {
    s1++;
    s2++;
  }
  return *s1 - *s2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CG_ForceModelChange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L17:
  mov    -0xc(%rbp),%eax
  add    $0x220,%eax
  mov    %eax,%edi
  call   <CG_ConfigString@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <CG_NewClientInfo@plt>
  jmp    L22
L16:
  nop
L22:
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x3f,-0xc(%rbp)
  jle    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void CG_ForceModelChange(void) {
  int i;
  for (i = 0; i < 64; i++) {
    const char *clientInfo;
    clientInfo = CG_ConfigString(((32 + 256) + 256) + i);
    if (!clientInfo[0]) {
      continue;
    }
    CG_NewClientInfo(i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CG_ForceModelChange>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  jmp    L39
L34:
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  je     L32
L39:
  lea    0x220(%rbx),%edi
  call   <CG_ConfigString@plt>
  cmpb   $0x0,(%rax)
  je     L34
  mov    %ebx,%edi
  call   <CG_NewClientInfo@plt>
  jmp    L34
L32:
  pop    %rbx
  ret
```

assistant: ```c
void CG_ForceModelChange(void) {
  int i;
  for (i = 0; i < 64; i++) {
    const char *clientInfo;
    clientInfo = CG_ConfigString(((32 + 256) + 256) + i);
    if (!clientInfo[0]) {
      continue;
    }
    CG_NewClientInfo(i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CG_ForceModelChange>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  lea    0x220(%rbx),%edi
  call   <CG_ConfigString@plt>
  cmpb   $0x0,(%rax)
  je     L0
  mov    %ebx,%edi
  call   <CG_NewClientInfo@plt>
L0:
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  jne    L11
  pop    %rbx
  ret
```

assistant: ```c
void CG_ForceModelChange(void) {
  int i;
  for (i = 0; i < 64; i++) {
    const char *clientInfo;
    clientInfo = CG_ConfigString(((32 + 256) + 256) + i);
    if (!clientInfo[0]) {
      continue;
    }
    CG_NewClientInfo(i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CG_ForceModelChange>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  lea    0x220(%rbx),%edi
  call   <CG_ConfigString@plt>
  cmpb   $0x0,(%rax)
  je     L7
  mov    %ebx,%edi
  call   <CG_NewClientInfo@plt>
L7:
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void CG_ForceModelChange(void) {
  int i;
  for (i = 0; i < 64; i++) {
    const char *clientInfo;
    clientInfo = CG_ConfigString(((32 + 256) + 256) + i);
    if (!clientInfo[0]) {
      continue;
    }
    CG_NewClientInfo(i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L82
L76:
  addq   $0x1,-0x18(%rbp)
L82:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L76
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x9,%eax
  cmp    $0x4,%eax
  jbe    L76
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2b,%eax
  je     L14
  cmp    $0x2d,%eax
  jne    L69
  movl   $0xffffffff,-0xc(%rbp)
L14:
  addq   $0x1,-0x18(%rbp)
  jmp    L69
L34:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L69:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L34
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L75
L25:
  mov    -0x8(%rbp),%rax
L75:
  pop    %rbp
  ret
```

assistant: ```c
long long int atoll(const char *s) {
  long long int v = 0;
  int sign = 1;
  while (*s == ' ' || (unsigned int)(*s - 9) < 5u) {
    ++s;
  }
  switch (*s) {
  case '-':
    sign = -1;
  case '+':
    ++s;
  }
  while ((unsigned int)(*s - '0') < 10u) {
    v = v * 10 + *s - '0';
    ++s;
  }
  return sign == -1 ? -v : v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atoll>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L38
  cmp    $0x20,%al
  jne    L59
L38:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L38
  cmp    $0x20,%al
  je     L38
L59:
  cmp    $0x2b,%al
  je     L28
  mov    $0x1,%esi
  cmp    $0x2d,%al
  jne    L39
  mov    $0xffffffff,%esi
L27:
  add    $0x1,%rdi
L39:
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  mov    $0x0,%ecx
  cmp    $0x9,%edx
  ja     L51
L76:
  lea    (%rcx,%rcx,4),%rdx
  movsbq %al,%rax
  lea    -0x30(%rax,%rdx,2),%rcx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L76
L51:
  mov    %rcx,%rax
  neg    %rax
  cmp    $0xffffffff,%esi
  cmove  %rax,%rcx
  mov    %rcx,%rax
  ret
L28:
  mov    $0x1,%esi
  jmp    L27
```

assistant: ```c
long long int atoll(const char *s) {
  long long int v = 0;
  int sign = 1;
  while (*s == ' ' || (unsigned int)(*s - 9) < 5u) {
    ++s;
  }
  switch (*s) {
  case '-':
    sign = -1;
  case '+':
    ++s;
  }
  while ((unsigned int)(*s - '0') < 10u) {
    v = v * 10 + *s - '0';
    ++s;
  }
  return sign == -1 ? -v : v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<atoll>:
  endbr64
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
L35:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L9
  cmp    $0x20,%al
  je     L9
  cmp    $0x2b,%al
  je     L25
  cmp    $0x2d,%al
  je     L22
  movsbq (%rdi),%rax
  mov    %rdi,%rcx
  mov    $0x1,%edi
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L88
L41:
  xor    %r8d,%r8d
  nopl   (%rax)
L85:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rcx
  lea    (%rax,%rdx,2),%rsi
  movsbq (%rcx),%rax
  lea    -0x30(%rsi),%r8
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L85
  mov    $0x30,%eax
  sub    %rsi,%rax
  cmp    $0xffffffff,%edi
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movsbq 0x1(%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1,%edi
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L41
L88:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L22:
  movsbq 0x1(%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L88
  mov    $0xffffffff,%edi
  jmp    L41
```

assistant: ```c
long long int atoll(const char *s) {
  long long int v = 0;
  int sign = 1;
  while (*s == ' ' || (unsigned int)(*s - 9) < 5u) {
    ++s;
  }
  switch (*s) {
  case '-':
    sign = -1;
  case '+':
    ++s;
  }
  while ((unsigned int)(*s - '0') < 10u) {
    v = v * 10 + *s - '0';
    ++s;
  }
  return sign == -1 ? -v : v;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoll>:
  endbr64
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L47:
  add    $0x1,%rdi
L89:
  movsbq (%rdi),%rax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L47
  cmp    $0x20,%al
  je     L47
  cmp    $0x2b,%al
  je     L18
  cmp    $0x2d,%al
  je     L95
  movsbl %al,%edx
  mov    %rdi,%rcx
  mov    $0x1,%edi
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L15
L73:
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L20:
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rcx
  lea    (%rax,%rdx,2),%rsi
  movsbq (%rcx),%rax
  lea    -0x30(%rsi),%r8
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L20
  mov    $0x30,%eax
  sub    %rsi,%rax
  cmp    $0xffffffff,%edi
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  movsbq 0x1(%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1,%edi
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L73
L15:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L95:
  movsbq 0x1(%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    %rdx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L15
  mov    $0xffffffff,%edi
  jmp    L73
```

assistant: ```c
long long int atoll(const char *s) {
  long long int v = 0;
  int sign = 1;
  while (*s == ' ' || (unsigned int)(*s - 9) < 5u) {
    ++s;
  }
  switch (*s) {
  case '-':
    sign = -1;
  case '+':
    ++s;
  }
  while ((unsigned int)(*s - '0') < 10u) {
    v = v * 10 + *s - '0';
    ++s;
  }
  return sign == -1 ? -v : v;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L28
L21:
  lea    -0x30(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L28:
  cmpl   $0x1,-0x34(%rbp)
  jle    L21
  movl   $0x0,-0x34(%rbp)
  jmp    L30
L9:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  movzbl -0x35(%rbp),%edx
  mov    %dl,-0x1c(%rbp,%rax,1)
L30:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x35(%rbp)
  cmpb   $0xa,-0x35(%rbp)
  jne    L9
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,-0x1c(%rbp,%rax,1)
  lea    -0x30(%rbp),%rax
  lea    0x14(%rax),%rcx
  lea    -0x30(%rbp),%rax
  lea    0xa(%rax),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D6: %s

tool: D10: %s%s%s


assistant: ```c
main() {
  char b[3][10], c;
  int i;
  for (i = 0; i < 2; i++)
    scanf("%s", b[i]);
  i = 0;
  while ((c = getchar()) != '\n')
    b[2][i++] = c;
  b[2][i] = '\0';
  printf("%s%s%s\n", b[0], b[1], b[2]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xa(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    0x13(%rsp),%r12
  jmp    L23
L28:
  mov    %al,(%r12,%rbx,1)
L23:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L28
  movslq %ebp,%rbp
  movb   $0x0,0x14(%rsp,%rbp,1)
  mov    %rsp,%rsi
  lea    0x14(%rsp),%rcx
  lea    0xa(%rsp),%rdx
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D8: %s

tool: D18: %s%s%s


assistant: ```c
main() {
  char b[3][10], c;
  int i;
  for (i = 0; i < 2; i++)
    scanf("%s", b[i]);
  i = 0;
  while ((c = getchar()) != '\n')
    b[2][i++] = c;
  b[2][i] = '\0';
  printf("%s%s%s\n", b[0], b[1], b[2]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0xa(%rsp),%r13
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  lea    0x13(%rsp),%rbp
  call   <scanf@plt>
  jmp    L23
  nop
L13:
  mov    %al,0x0(%rbp,%r14,1)
L23:
  xor    %eax,%eax
  movslq %r14d,%rbx
  add    $0x1,%r14
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L13
  lea    0x14(%rsp),%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  movb   $0x0,0x14(%rsp,%rbx,1)
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D13: %s

tool: D4: %s%s%s


assistant: ```c
main() {
  char b[3][10], c;
  int i;
  for (i = 0; i < 2; i++)
    scanf("%s", b[i]);
  i = 0;
  while ((c = getchar()) != '\n')
    b[2][i++] = c;
  b[2][i] = '\0';
  printf("%s%s%s\n", b[0], b[1], b[2]);
}
```