user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L29
L62:
  lea    -0xd0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xd4(%rbp)
L29:
  mov    -0xe0(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jl     L62
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xd8(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xdc(%rbp),%rax
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xe0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xd4(%rbp)
  jmp    L55
L75:
  mov    -0xd4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%edx
  movslq %ecx,%rax
  mov    %edx,-0xd0(%rbp,%rax,4)
  subl   $0x1,-0xd4(%rbp)
L55:
  mov    -0xd8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xd4(%rbp)
  jge    L75
  mov    -0xd8(%rbp),%eax
  sub    $0x1,%eax
  mov    -0xdc(%rbp),%edx
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L39
L1:
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xe0(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jge    L47
  mov    $0x2c,%edi
  call   <putchar@plt>
L47:
  addl   $0x1,-0xd4(%rbp)
L39:
  mov    -0xe0(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jle    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D50
type_guessed: string
name: unpack_data
arguments: data_label: D68
type_guessed: string
name: unpack_data
arguments: data_label: D66
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D93
type_guessed: string

tool: D34: Enter the size of array

tool: D50: %d

tool: D68: Enter the elements of array

tool: D66: Enter the location where you wish to insert an element

tool: D5: Enter the element which you want to insert

tool: D93: You entered array

assistant: ```c
int main() {
  int i, n, arr[50], insert, position;
  printf("Enter the size of array\n");
  scanf("%d", &n);
  printf("Enter the elements of array\n");
  for (i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Enter the location where you wish to insert an element\n");
  scanf("%d", &position);
  printf("Enter the element which you want to insert\n");
  scanf("%d", &insert);
  for (i = n - 1; i >= position - 1; i--)
    arr[i + 1] = arr[i];
  arr[position - 1] = insert;
  printf("You entered array\n");
  for (i = 0; i < n + 1; i++) {
    printf("%d", arr[i]);
    if (i < n)
      printf(",");
  }
  return 0;
}
```