ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<insertQuotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L10
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L0
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertQuotes(int begin, int end, char *str, int n) {
  int k;
  for (k = n + 2; k > end; k--) {
    str[k] = str[k - 2];
  }
  for (k = end + 1; k > begin; k--) {
    str[k] = str[k - 1];
  }
  str[begin] = '"';
  str[end] = '"';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertQuotes>:
  endbr64
  mov    %rdx,%r8
  mov    %ecx,%edx
  lea    0x2(%rcx),%eax
  cmp    %esi,%eax
  jle    L33
  cltq
  add    %r8,%rax
  movslq %ecx,%rcx
  lea    0x1(%r8,%rcx,1),%rcx
  sub    %esi,%edx
  lea    0x1(%rdx),%edx
  sub    %rdx,%rcx
L25:
  movzbl -0x2(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L25
L33:
  lea    0x1(%rsi),%eax
  cmp    %edi,%eax
  jle    L12
  cltq
  add    %r8,%rax
  movslq %esi,%rcx
  add    %r8,%rcx
  mov    %esi,%edx
  sub    %edi,%edx
  sub    %rdx,%rcx
L3:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L3
L12:
  movslq %edi,%rdi
  movb   $0x22,(%r8,%rdi,1)
  movslq %esi,%rsi
  movb   $0x22,(%r8,%rsi,1)
  ret
```

assistant: ```c
void insertQuotes(int begin, int end, char *str, int n) {
  int k;
  for (k = n + 2; k > end; k--) {
    str[k] = str[k - 2];
  }
  for (k = end + 1; k > begin; k--) {
    str[k] = str[k - 1];
  }
  str[begin] = '"';
  str[end] = '"';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertQuotes>:
  endbr64
  push   %r12
  lea    0x2(%rcx),%eax
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%eax
  jle    L15
  cltq
  sub    %ebx,%ecx
  lea    0x1(%rcx),%edx
  lea    -0x2(%rax),%rsi
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L15:
  lea    0x1(%rbx),%eax
  cmp    %ebp,%eax
  jle    L11
  cltq
  mov    %ebx,%edx
  sub    %ebp,%edx
  lea    -0x1(%rax),%rsi
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L11:
  movb   $0x22,(%r12,%rbp,1)
  movb   $0x22,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insertQuotes(int begin, int end, char *str, int n) {
  int k;
  for (k = n + 2; k > end; k--) {
    str[k] = str[k - 2];
  }
  for (k = end + 1; k > begin; k--) {
    str[k] = str[k - 1];
  }
  str[begin] = '"';
  str[end] = '"';
}
```
user: What is the c source code of the assembly code below?

```asm
<insertQuotes>:
  endbr64
  push   %r12
  lea    0x2(%rcx),%eax
  mov    %rdx,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%eax
  jle    L0
  cltq
  sub    %ebx,%ecx
  lea    0x1(%rcx),%edx
  lea    -0x2(%rax),%rsi
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L0:
  lea    0x1(%rbx),%eax
  cmp    %ebp,%eax
  jle    L6
  cltq
  mov    %ebx,%edx
  sub    %ebp,%edx
  lea    -0x1(%rax),%rsi
  sub    %rdx,%rsi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L6:
  movb   $0x22,(%r12,%rbp,1)
  movb   $0x22,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insertQuotes(int begin, int end, char *str, int n) {
  int k;
  for (k = n + 2; k > end; k--) {
    str[k] = str[k - 2];
  }
  for (k = end + 1; k > begin; k--) {
    str[k] = str[k - 1];
  }
  str[begin] = '"';
  str[end] = '"';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x989680,-0x10(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L12
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
L12:
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L11:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10000000;
  if (argc >= 2) {
    n = atoi(argv[1]);
  }
  long r = 0;
  int i;
  for (i = 0; i < n; i++) {
    r += i;
  }
  printf("%ld\n", r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x989680,%eax
  cmp    $0x1,%edi
  jg     L28
L8:
  mov    $0x0,%edx
  mov    $0x0,%esi
L9:
  add    %rdx,%rsi
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L9
L10:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L28:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jg     L8
  mov    $0x0,%esi
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: D5: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10000000;
  if (argc >= 2) {
    n = atoi(argv[1]);
  }
  long r = 0;
  int i;
  for (i = 0; i < n; i++) {
    r += i;
  }
  printf("%ld\n", r);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x989680,%eax
  cmp    $0x1,%edi
  jg     L7
L30:
  xor    %edx,%edx
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L33:
  add    %rdx,%rsi
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L33
L3:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jg     L30
  xor    %esi,%esi
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10000000;
  if (argc >= 2) {
    n = atoi(argv[1]);
  }
  long r = 0;
  int i;
  for (i = 0; i < n; i++) {
    r += i;
  }
  printf("%ld\n", r);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    $0x989680,%edi
  mov    $0x989680,%eax
  cmp    $0x1,%r8d
  jg     L43
L46:
  mov    %edi,%ecx
  movdqa D20(%rip),%xmm2
  xor    %edx,%edx
  pxor   %xmm0,%xmm0
  movdqa D11(%rip),%xmm6
  shr    $0x2,%ecx
  pxor   %xmm5,%xmm5
  xchg   %ax,%ax
L20:
  movdqa %xmm2,%xmm1
  movdqa %xmm5,%xmm3
  paddd  %xmm6,%xmm2
  add    $0x1,%edx
  pcmpgtd %xmm1,%xmm3
  movdqa %xmm1,%xmm4
  punpckldq %xmm3,%xmm4
  punpckhdq %xmm3,%xmm1
  paddq  %xmm4,%xmm0
  paddq  %xmm1,%xmm0
  cmp    %ecx,%edx
  jne    L20
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  and    $0x3,%edi
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rsi
  je     L11
L55:
  movslq %edx,%rcx
  add    %rcx,%rsi
  lea    0x1(%rdx),%ecx
  cmp    %eax,%ecx
  jge    L11
  movslq %ecx,%rcx
  add    %rcx,%rsi
  lea    0x2(%rdx),%ecx
  cmp    %eax,%ecx
  jge    L11
  movslq %ecx,%rcx
  add    $0x3,%edx
  add    %rcx,%rsi
  cmp    %edx,%eax
  jle    L11
  movslq %edx,%rdx
  add    %rdx,%rsi
L11:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L43:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jle    L35
  mov    %eax,%edi
  cmp    $0x4,%eax
  jg     L46
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    L55
L35:
  xor    %esi,%esi
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D11
type_guessed: byte[16]
name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: {"D20": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D6: %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10000000;
  if (argc >= 2) {
    n = atoi(argv[1]);
  }
  long r = 0;
  int i;
  for (i = 0; i < n; i++) {
    r += i;
  }
  printf("%ld\n", r);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<novaGeracao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L79:
  movl   $0x0,-0x8(%rbp)
  jmp    L123
L46:
  mov    -0x28(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <quantidadeDeVizinhos@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L68
  cmpl   $0x3,-0x4(%rbp)
  je     L116
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L111
L116:
  cmpl   $0x3,-0x4(%rbp)
  jne    L111
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L111
L68:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L111
  cmpl   $0x1,-0x4(%rbp)
  jle    L32
  cmpl   $0x3,-0x4(%rbp)
  jle    L100
L32:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L111
L100:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L111:
  addl   $0x1,-0x8(%rbp)
L123:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L46
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L79
  nop
  nop
  leave
  ret
```

assistant: ```c
void novaGeracao(int **geracao1, int **geracao2, int linha, int coluna) {
  int i, j, vizinhos;
  for (i = 0; i < linha; i++) {
    for (j = 0; j < coluna; j++) {
      vizinhos = quantidadeDeVizinhos(geracao1, i, j, linha, coluna);
      if (geracao1[i][j] == 0) {
        if (vizinhos != 3) {
          geracao2[i][j] = 0;
        } else if (vizinhos == 3) {
          geracao2[i][j] = 1;
        }
      } else if (geracao1[i][j] == 1) {
        if (vizinhos < 2 || vizinhos > 3) {
          geracao2[i][j] = 0;
        } else {
          geracao2[i][j] = 1;
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<novaGeracao>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x4(%rsp)
  test   %edx,%edx
  jle    L60
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %ecx,%r13d
  mov    %edx,%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%ebp
  mov    %ecx,%r14d
  jmp    L15
L79:
  mov    (%r15,%rbp,8),%rax
  movl   $0x0,(%rax,%rcx,1)
L17:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L45
L67:
  mov    %r13d,%r8d
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    (%rsp),%esi
  mov    %r12,%rdi
  call   <quantidadeDeVizinhos@plt>
  lea    0x0(,%rbx,4),%rcx
  mov    (%r12,%rbp,8),%rdx
  mov    (%rdx,%rbx,4),%edx
  test   %edx,%edx
  jne    L22
  cmp    $0x3,%eax
  jne    L79
  mov    (%r15,%rbp,8),%rax
  movl   $0x1,(%rax,%rcx,1)
  jmp    L17
L22:
  cmp    $0x1,%edx
  jne    L17
  sub    $0x2,%eax
  cmp    $0x1,%eax
  jbe    L96
  mov    (%r15,%rbp,8),%rax
  movl   $0x0,(%rax,%rcx,1)
  jmp    L17
L96:
  mov    (%r15,%rbp,8),%rax
  movl   $0x1,(%rax,%rcx,1)
  jmp    L17
L45:
  add    $0x1,%rbp
  cmp    0x8(%rsp),%rbp
  je     L60
L15:
  mov    %ebp,(%rsp)
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L67
  jmp    L45
L60:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void novaGeracao(int **geracao1, int **geracao2, int linha, int coluna) {
  int i, j, vizinhos;
  for (i = 0; i < linha; i++) {
    for (j = 0; j < coluna; j++) {
      vizinhos = quantidadeDeVizinhos(geracao1, i, j, linha, coluna);
      if (geracao1[i][j] == 0) {
        if (vizinhos != 3) {
          geracao2[i][j] = 0;
        } else if (vizinhos == 3) {
          geracao2[i][j] = 1;
        }
      } else if (geracao1[i][j] == 1) {
        if (vizinhos < 2 || vizinhos > 3) {
          geracao2[i][j] = 0;
        } else {
          geracao2[i][j] = 1;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<novaGeracao>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  test   %edx,%edx
  jle    L6
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %rax,0x18(%rsp)
  movslq %ecx,%rax
  xor    %r14d,%r14d
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r14d,%ebp
  xor    %ebx,%ebx
  test   %r15d,%r15d
  jg     L8
  jmp    L40
  nopl   0x0(%rax)
L24:
  mov    0x10(%rsp),%rsi
  add    (%rsi,%r14,8),%rdx
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%rdx)
L63:
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  je     L40
L8:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r15d,%r8d
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <quantidadeDeVizinhos@plt>
  mov    0x0(%r13,%r14,8),%rcx
  lea    0x0(,%rbx,4),%rdx
  mov    (%rcx,%rbx,4),%ecx
  test   %ecx,%ecx
  je     L24
  cmp    $0x1,%ecx
  jne    L63
  mov    0x10(%rsp),%rdi
  sub    $0x2,%eax
  add    (%rdi,%r14,8),%rdx
  cmp    $0x2,%eax
  setb   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  mov    %eax,(%rdx)
  cmp    %rbx,0x8(%rsp)
  jne    L8
  nopl   0x0(%rax)
L40:
  add    $0x1,%r14
  cmp    %r14,0x18(%rsp)
  jne    L49
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void novaGeracao(int **geracao1, int **geracao2, int linha, int coluna) {
  int i, j, vizinhos;
  for (i = 0; i < linha; i++) {
    for (j = 0; j < coluna; j++) {
      vizinhos = quantidadeDeVizinhos(geracao1, i, j, linha, coluna);
      if (geracao1[i][j] == 0) {
        if (vizinhos != 3) {
          geracao2[i][j] = 0;
        } else if (vizinhos == 3) {
          geracao2[i][j] = 1;
        }
      } else if (geracao1[i][j] == 1) {
        if (vizinhos < 2 || vizinhos > 3) {
          geracao2[i][j] = 0;
        } else {
          geracao2[i][j] = 1;
        }
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<novaGeracao>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  test   %edx,%edx
  jle    L79
  mov    %ecx,%r15d
  test   %ecx,%ecx
  jle    L79
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %edx,%r12d
  xor    %r14d,%r14d
  mov    %rax,0x18(%rsp)
  movslq %ecx,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %r14d,%ebp
  xor    %ebx,%ebx
  jmp    L15
  nop
L23:
  mov    0x10(%rsp),%rsi
  add    (%rsi,%r14,8),%rdx
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,(%rdx)
L52:
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  je     L38
L15:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r15d,%r8d
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <quantidadeDeVizinhos@plt>
  mov    0x0(%r13,%r14,8),%rcx
  lea    0x0(,%rbx,4),%rdx
  mov    (%rcx,%rbx,4),%ecx
  test   %ecx,%ecx
  je     L23
  cmp    $0x1,%ecx
  jne    L52
  mov    0x10(%rsp),%rdi
  sub    $0x2,%eax
  add    (%rdi,%r14,8),%rdx
  cmp    $0x2,%eax
  setb   %al
  add    $0x1,%rbx
  movzbl %al,%eax
  mov    %eax,(%rdx)
  cmp    %rbx,0x8(%rsp)
  jne    L15
  nopl   0x0(%rax)
L38:
  add    $0x1,%r14
  cmp    %r14,0x18(%rsp)
  jne    L59
L79:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void novaGeracao(int **geracao1, int **geracao2, int linha, int coluna) {
  int i, j, vizinhos;
  for (i = 0; i < linha; i++) {
    for (j = 0; j < coluna; j++) {
      vizinhos = quantidadeDeVizinhos(geracao1, i, j, linha, coluna);
      if (geracao1[i][j] == 0) {
        if (vizinhos != 3) {
          geracao2[i][j] = 0;
        } else if (vizinhos == 3) {
          geracao2[i][j] = 1;
        }
      } else if (geracao1[i][j] == 1) {
        if (vizinhos < 2 || vizinhos > 3) {
          geracao2[i][j] = 0;
        } else {
          geracao2[i][j] = 1;
        }
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<radixsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L40
L83:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L84
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
L84:
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L83
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L78
L44:
  addl   $0x1,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L78:
  cmpl   $0x0,-0x8(%rbp)
  jne    L44
  jmp    L21
L37:
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L15:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x4(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <enqueue@plt>
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dequeue@plt>
L21:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L37
  nop
  nop
  leave
  ret
```

assistant: ```c
void radixsort(int *a, int n, int queue[][10], int *head) {
  int max = a[0], x, k = 10, i, temp;
  for (i = 1; i < n; i++) {
    if (max < a[i])
      max = a[i];
  }
  temp = max;
  max = 0;
  while (temp) {
    max = max + 1;
    temp = temp / 10;
  }
  while (max--) {
    for (i = 0; i < n; i++) {
      x = (a[i] * 10 / k) % 10;
      enqueue(queue, x, a[i], head);
    }
    k = k * 10;
    dequeue(queue, head, a);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<radixsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L91
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L26:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L26
L91:
  test   %edx,%edx
  je     L80
  mov    $0x0,%ecx
L90:
  mov    %ecx,%r15d
  add    $0x1,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L90
  test   %ecx,%ecx
  je     L80
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%eax
  mov    (%rsp),%rbx
  lea    0x4(%rbx,%rax,4),%r14
  mov    $0xa,%ebp
  jmp    L60
L47:
  mov    (%rbx),%edi
  lea    (%rdi,%rdi,4),%eax
  add    %eax,%eax
  cltd
  idiv   %ebp
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  mov    %r13,%rcx
  mov    %edi,%edx
  mov    %r12,%rdi
  call   <enqueue@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r14
  jne    L47
L31:
  lea    0x0(%rbp,%rbp,4),%ebp
  add    %ebp,%ebp
  mov    (%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <dequeue@plt>
  lea    -0x1(%r15),%eax
  test   %r15d,%r15d
  je     L80
  mov    %eax,%r15d
L60:
  mov    (%rsp),%rbx
  cmpl   $0x0,0xc(%rsp)
  jg     L47
  jmp    L31
L80:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void radixsort(int *a, int n, int queue[][10], int *head) {
  int max = a[0], x, k = 10, i, temp;
  for (i = 1; i < n; i++) {
    if (max < a[i])
      max = a[i];
  }
  temp = max;
  max = 0;
  while (temp) {
    max = max + 1;
    temp = temp / 10;
  }
  while (max--) {
    for (i = 0; i < n; i++) {
      x = (a[i] * 10 / k) % 10;
      enqueue(queue, x, a[i], head);
    }
    k = k * 10;
    dequeue(queue, head, a);
  }
}
```