user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x64(%rbp)
  movl   $0x0,-0x60(%rbp)
  movl   $0x0,-0x5c(%rbp)
  cmpl   $0x1,-0x74(%rbp)
  jle    L69
  mov    -0x80(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x60(%rbp)
L69:
  cmpl   $0x2,-0x74(%rbp)
  jle    L92
  mov    -0x80(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x5c(%rbp)
L92:
  cmpl   $0x3,-0x74(%rbp)
  jle    L66
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L72:
  cmp    %rdx,%rsp
  je     L93
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L72
L93:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L89
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L89:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x80(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    -0x48(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x1,-0x58(%rbp)
  movl   $0x4,-0x54(%rbp)
  jmp    L33
L27:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x48(%rbp),%rax
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  mov    %rcx,(%rax,%rdx,8)
  addl   $0x1,-0x58(%rbp)
  addl   $0x1,-0x54(%rbp)
L33:
  mov    -0x54(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L27
  mov    -0x48(%rbp),%rax
  mov    -0x58(%rbp),%edx
  movslq %edx,%rdx
  movq   $0x0,(%rax,%rdx,8)
  mov    -0x5c(%rbp),%edx
  mov    -0x60(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <daemon@plt>
  mov    %eax,-0x64(%rbp)
  cmpl   $0xffffffff,-0x64(%rbp)
  je     L6
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execv@plt>
  mov    %eax,-0x64(%rbp)
L6:
  mov    %rbx,%rsp
  jmp    L61
L66:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L61:
  mov    -0x64(%rbp),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: daemon nochdir noclose command...


assistant: ```c
int main(int argc, char **argv) {
  int result = -1;
  int nochdir = 0;
  int noclose = 0;
  if (1 < argc)
    nochdir = strtol(argv[1], NULL, 10);
  if (2 < argc)
    noclose = strtol(argv[2], NULL, 10);
  if (3 < argc) {
    int i, j;
    char *path;
    char *eargv[argc];
    path = argv[3];
    eargv[0] = basename(path);
    for (i = 1, j = 4; j < argc; i++, j++)
      eargv[i] = argv[j];
    eargv[i] = NULL;
    if (-1 != (result = daemon(nochdir, noclose)))
      result = execv(path, eargv);
  } else
    printf("daemon nochdir noclose command...\n");
  return result;
}
```