user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D25(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  lea    D111(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D168(%rip),%xmm1
  mov    D47(%rip),%eax
  movd   %eax,%xmm0
  lea    D198(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D168(%rip),%xmm1
  mov    D47(%rip),%eax
  movd   %eax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D153(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D168(%rip),%xmm1
  mov    D47(%rip),%eax
  movd   %eax,%xmm0
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D168(%rip),%xmm1
  mov    D47(%rip),%eax
  movd   %eax,%xmm0
  lea    D183(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  D168(%rip),%xmm1
  mov    D47(%rip),%eax
  movd   %eax,%xmm0
  lea    D191(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D182(%rip),%rax
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_infered: byte[4]
name: parse_data
arguments: data_tag: D111
type_infered: string
name: parse_data
arguments: data_tag: D168
type_infered: byte[4]
name: parse_data
arguments: data_tag: D47
type_infered: byte[4]
name: parse_data
arguments: data_tag: D198
type_infered: string
name: parse_data
arguments: data_tag: D53
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D153
type_infered: string
name: parse_data
arguments: data_tag: D58
type_infered: string
name: parse_data
arguments: data_tag: D98
type_infered: string
name: parse_data
arguments: data_tag: D183
type_infered: string
name: parse_data
arguments: data_tag: D191
type_infered: string
name: parse_data
arguments: data_tag: D182
type_infered: string

tool: {"D25": [0x42,0x5d,0x24,0x3a]}

tool: D111: Base 10

tool: {"D168": [0x00,0x3c,0x3a,0x47]}

tool: {"D47": [0x00,0x00,0x48,0x42]}

tool: D198: I must deliver %d pods to %d locations



tool: D53: Base 16

tool: D15: I must deliver 0x%x pods to 0x%X locations



tool: D153: Base 8

tool: D58: I must deliver %o pods to %o locations



tool: D98: Scientific representation

tool: D183: I must deliver %E pods to %E locations


tool: D191: I must deliver %G pods to %g locations



tool: D182: 	*Test for scientific to integer (e=g=f=d)
	  float var = 6.27E-4 = 	%e = %g , %f , %d

assistant: ```c
int main() {
  float var = 6.27E-4;
  puts("Base 10");
  printf("I must deliver %d pods to %d locations\r\n\n", 50, 0xBA3C);
  puts("Base 16");
  printf("I must deliver 0x%x pods to 0x%X locations\n\n", 50, 0xBA3C);
  puts("Base 8");
  printf("I must deliver %o pods to %o locations\n\n", 50, 0xBA3C);
  puts("Scientific representation");
  printf("I must deliver %E pods to %E locations\n", (float)50, (float)0xBA3C);
  printf("I must deliver %G pods to %g locations\n\n", (float)50, (float)0xBA3C);
  printf("\t\*Test for scientific to integer (e=g=f=d)\n\t  float var = 6.27E-4 = \t%e = %g , %f , %d", var, var, var, var);
  return (0);
}
```