user: 这段汇编代码用C语言表示是什么样的？

```asm
<ifft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fht@plt>
  mov    -0x54(%rbp),%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fht@plt>
  movl   $0x1,-0x4c(%rbp)
  mov    -0x54(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x48(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x44(%rbp)
  jmp    L14
L19:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x28(%rbp),%xmm1
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x28(%rbp),%xmm1
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x8(%rbp),%xmm1
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4c(%rbp)
  subl   $0x1,-0x48(%rbp)
L14:
  mov    -0x4c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: f64

tool: D8: 0.5

assistant: ```c
void ifft(n, real, imag) int n;
double *real, *imag;
{
  double a, b, c, d;
  double q, r, s, t;
  int i, j, k;
  fht(real, n);
  fht(imag, n);
  for (i = 1, j = n - 1, k = n / 2; i < k; i++, j--) {
    a = real[i];
    b = real[j];
    q = a + b;
    r = a - b;
    c = imag[i];
    d = imag[j];
    s = c + d;
    t = c - d;
    imag[i] = (s + r) * 0.5;
    imag[j] = (s - r) * 0.5;
    real[i] = (q - t) * 0.5;
    real[j] = (q + t) * 0.5;
  }
}
```