ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_uint3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
uint32_t read_uint3(const char *buf) {
  uint32_t tmp = 0;
  memcpy(&tmp, buf, 3);
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_uint3>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x3,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t read_uint3(const char *buf) {
  uint32_t tmp = 0;
  memcpy(&tmp, buf, 3);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_uint3>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t read_uint3(const char *buf) {
  uint32_t tmp = 0;
  memcpy(&tmp, buf, 3);
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_uint3>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t read_uint3(const char *buf) {
  uint32_t tmp = 0;
  memcpy(&tmp, buf, 3);
  return tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
L8:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b ^= a ^= b ^= a %= b)
    ;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
L8:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L8
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b ^= a ^= b ^= a %= b)
    ;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L5
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b ^= a ^= b ^= a %= b)
    ;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L1
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (b ^= a ^= b ^= a %= b)
    ;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L26
L14:
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x5,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jle    L41
  mov    -0x14(%rbp),%eax
  cmp    $0x2,%eax
  jle    L41
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jg     L14
L41:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D10
type: string

tool: D1:  %d %d %d

tool: D10: %d

assistant: ```c
int main() {
  int A, B, C, qtd = 0;
  scanf(" %d %d %d", &A, &B, &C);
  while ((A >= 2) && (B >= 3) && (C >= 5)) {
    A -= 2;
    B -= 3;
    C -= 5;
    qtd++;
  }
  printf("%d", qtd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L58
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x0,%r10d
  mov    $0x0,%edi
  mov    $0x1,%esi
L44:
  cmp    $0x2,%edx
  jle    L48
  cmp    $0x4,%ecx
  jle    L133
  sub    $0x2,%eax
  sub    $0x3,%edx
  sub    $0x5,%ecx
  add    $0x1,%edi
  mov    %esi,%r10d
  mov    %esi,%r9d
  mov    %esi,%r8d
  cmp    $0x1,%eax
  jle    L125
  mov    %eax,%ebx
  jmp    L44
L125:
  mov    %ecx,0x14(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %eax,0xc(%rsp)
L136:
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L48:
  test   %r8b,%r8b
  je     L17
  mov    %ecx,0x14(%rsp)
L17:
  test   %r9b,%r9b
  je     L78
  mov    %edx,0x10(%rsp)
L78:
  test   %r10b,%r10b
  je     L136
  mov    %ebx,0xc(%rsp)
  jmp    L136
L133:
  test   %r8b,%r8b
  je     L65
  mov    %ecx,0x14(%rsp)
L65:
  test   %r9b,%r9b
  je     L20
  mov    %edx,0x10(%rsp)
L20:
  test   %r10b,%r10b
  je     L136
  mov    %ebx,0xc(%rsp)
  jmp    L136
L58:
  mov    $0x0,%edi
  jmp    L136
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D5:  %d %d %d

tool: D0: %d

assistant: ```c
int main() {
  int A, B, C, qtd = 0;
  scanf(" %d %d %d", &A, &B, &C);
  while ((A >= 2) && (B >= 3) && (C >= 5)) {
    A -= 2;
    B -= 3;
    C -= 5;
    qtd++;
  }
  printf("%d", qtd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D19(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L0
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  xor    %edi,%edi
  xor    %esi,%esi
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L48:
  cmp    $0x4,%ecx
  jle    L8
  sub    $0x2,%eax
  sub    $0x3,%edx
  sub    $0x5,%ecx
  add    $0x1,%esi
  mov    $0x1,%edi
  cmp    $0x1,%eax
  jle    L29
  mov    %eax,%ebx
L76:
  cmp    $0x2,%edx
  jg     L48
L8:
  test   %dil,%dil
  je     L39
  mov    %ecx,0x14(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %ebx,0xc(%rsp)
L39:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L29:
  mov    %ecx,0x14(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %eax,0xc(%rsp)
  jmp    L39
L0:
  xor    %esi,%esi
  jmp    L39
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D19:  %d %d %d

tool: D2: %d

assistant: ```c
int main() {
  int A, B, C, qtd = 0;
  scanf(" %d %d %d", &A, &B, &C);
  while ((A >= 2) && (B >= 3) && (C >= 5)) {
    A -= 2;
    B -= 3;
    C -= 5;
    qtd++;
  }
  printf("%d", qtd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x1,%eax
  jle    L85
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  xor    %edi,%edi
  xor    %esi,%esi
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L54:
  cmp    $0x4,%ecx
  jle    L44
  sub    $0x2,%eax
  sub    $0x3,%edx
  sub    $0x5,%ecx
  add    $0x1,%esi
  mov    $0x1,%edi
  cmp    $0x1,%eax
  jle    L63
  mov    %eax,%ebx
L24:
  cmp    $0x2,%edx
  jg     L54
L44:
  test   %dil,%dil
  je     L29
  mov    %ecx,0x14(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %ebx,0xc(%rsp)
L29:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L63:
  mov    %ecx,0x14(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %eax,0xc(%rsp)
  jmp    L29
L85:
  xor    %esi,%esi
  jmp    L29
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string

tool: D0:  %d %d %d

tool: D19: %d

assistant: ```c
int main() {
  int A, B, C, qtd = 0;
  scanf(" %d %d %d", &A, &B, &C);
  while ((A >= 2) && (B >= 3) && (C >= 5)) {
    A -= 2;
    B -= 3;
    C -= 5;
    qtd++;
  }
  printf("%d", qtd);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nuke_dirent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x54(%rbp),%edx
  add    %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L6:
  cmp    %rdx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L18:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L31
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L31:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x50(%rbp),%esi
  mov    -0x40(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <nuke@plt>
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: %s/%s

assistant: ```c
int nuke_dirent(int len, const char *dir, const char *name) {
  int bytes = len + strlen(name) + 2;
  char path[bytes];
  int xlen;
  xlen = snprintf(path, bytes, "%s/%s", dir, name);
  assert(xlen < bytes);
  return nuke(path);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nuke_dirent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  lea    0x2(%r13,%rax,1),%r13d
  movslq %r13d,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L9:
  cmp    %rdx,%rsp
  je     L24
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L24:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L8
  orq    $0x0,-0x8(%rsp,%rax,1)
L8:
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D1(%rip),%rdx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <snprintf@plt>
  cmp    %eax,%r13d
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rsp,%rdi
  call   <nuke@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %s/%s

assistant: ```c
int nuke_dirent(int len, const char *dir, const char *name) {
  int bytes = len + strlen(name) + 2;
  char path[bytes];
  int xlen;
  xlen = snprintf(path, bytes, "%s/%s", dir, name);
  assert(xlen < bytes);
  return nuke(path);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nuke_dirent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x2(%r13,%rax,1),%r13d
  movslq %r13d,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L39
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L1
L39:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L36
L6:
  lea    D9(%rip),%rdx
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <snprintf@plt>
  xor    %edi,%edi
  cmp    %eax,%r13d
  setg   %dil
  call   <assert@plt>
  mov    %rsp,%rdi
  call   <nuke@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L36:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: %s/%s

assistant: ```c
int nuke_dirent(int len, const char *dir, const char *name) {
  int bytes = len + strlen(name) + 2;
  char path[bytes];
  int xlen;
  xlen = snprintf(path, bytes, "%s/%s", dir, name);
  assert(xlen < bytes);
  return nuke(path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nuke_dirent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x2(%r13,%rax,1),%r13d
  movslq %r13d,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L7
L31:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L31
L7:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L45
L10:
  lea    D8(%rip),%rdx
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13d,%esi
  mov    %rsp,%rdi
  call   <snprintf@plt>
  xor    %edi,%edi
  cmp    %eax,%r13d
  setg   %dil
  call   <assert@plt>
  mov    %rsp,%rdi
  call   <nuke@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L45:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L10
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: %s/%s

assistant: ```c
int nuke_dirent(int len, const char *dir, const char *name) {
  int bytes = len + strlen(name) + 2;
  char path[bytes];
  int xlen;
  xlen = snprintf(path, bytes, "%s/%s", dir, name);
  assert(xlen < bytes);
  return nuke(path);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<generate_board_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x80(%rbp),%rax
  mov    $0x68,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0xa8(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x88(%rbp)
  cmpq   $0x0,-0x88(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x98(%rbp)
  jmp    L37
L73:
  mov    -0xa8(%rbp),%rax
  shl    $0x3,%rax
  mov    -0x98(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x88(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x98(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addq   $0x1,-0x98(%rbp)
L37:
  mov    -0x98(%rbp),%rax
  cmp    -0xa8(%rbp),%rax
  jb     L73
  movq   $0x0,-0x98(%rbp)
  jmp    L30
L44:
  movq   $0x0,-0x90(%rbp)
  jmp    L33
L2:
  mov    -0xb0(%rbp),%rax
  call   *%rax
  mov    %al,-0x99(%rbp)
  jmp    L48
L20:
  mov    -0xb0(%rbp),%rax
  call   *%rax
  mov    %al,-0x99(%rbp)
L48:
  movzbl -0x99(%rbp),%eax
  sub    $0x61,%eax
  movzbl %al,%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  mov    %eax,%eax
  cmp    %rax,-0xa8(%rbp)
  jb     L20
  movzbl -0x99(%rbp),%eax
  sub    $0x61,%eax
  movzbl %al,%eax
  movslq %eax,%rdx
  mov    -0x80(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x80(%rbp,%rax,4)
  mov    -0x98(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x90(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x99(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x90(%rbp)
L33:
  mov    -0x90(%rbp),%rax
  cmp    -0xa8(%rbp),%rax
  jb     L2
  addq   $0x1,-0x98(%rbp)
L30:
  mov    -0x98(%rbp),%rax
  cmp    -0xa8(%rbp),%rax
  jb     L44
  mov    -0x88(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **generate_board_aux(size_t n, char (*letter_gen)(void)) {
  unsigned letters_used[26];
  memset(letters_used, 0, sizeof(letters_used));
  char **board = malloc(n * sizeof(*board));
  assert(board != NULL);
  size_t i;
  for (i = 0; i < n; i++) {
    board[i] = malloc(n * sizeof(board[i]));
    assert(board[i] != NULL);
  }
  for (i = 0; i < n; i++) {
    size_t j;
    for (j = 0; j < n; j++) {
      char letter = (*letter_gen)();
      while (letters_used[(unsigned char)(letter - 'a')] > n) {
        letter = (*letter_gen)();
      }
      letters_used[(unsigned char)(letter - 'a')]++;
      board[i][j] = letter;
    }
  }
  return board;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<generate_board_aux>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x68,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x0(,%r12,8),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L87
  mov    $0x0,%ebx
L45:
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15,%rbx,8)
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%r14
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L45
  mov    $0x0,%r13d
  jmp    L22
L65:
  mov    %rax,%r12
L3:
  call   *%rbp
  mov    %eax,%edx
  lea    -0x61(%rdx),%eax
  movzbl %al,%esi
  movzbl %al,%eax
  mov    (%rsp,%rax,4),%eax
  mov    %eax,%ecx
  cmp    %rcx,%rbx
  jae    L53
L5:
  call   *%rbp
  mov    %eax,%edx
  lea    -0x61(%rdx),%eax
  movzbl %al,%esi
  movzbl %al,%eax
  mov    (%rsp,%rax,4),%eax
  mov    %eax,%ecx
  cmp    %rbx,%rcx
  ja     L5
L53:
  movslq %esi,%rsi
  add    $0x1,%eax
  mov    %eax,(%rsp,%rsi,4)
  mov    (%r15,%r13,8),%rax
  mov    %dl,(%rax,%r12,1)
  lea    0x1(%r12),%rax
  cmp    %r12,%r14
  jne    L65
  lea    0x1(%r13),%rax
  cmp    %r13,%r14
  je     L87
  mov    %rax,%r13
L22:
  mov    $0x0,%r12d
  jmp    L3
L87:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %r15,%rax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **generate_board_aux(size_t n, char (*letter_gen)(void)) {
  unsigned letters_used[26];
  memset(letters_used, 0, sizeof(letters_used));
  char **board = malloc(n * sizeof(*board));
  assert(board != NULL);
  size_t i;
  for (i = 0; i < n; i++) {
    board[i] = malloc(n * sizeof(board[i]));
    assert(board[i] != NULL);
  }
  for (i = 0; i < n; i++) {
    size_t j;
    for (j = 0; j < n; j++) {
      char letter = (*letter_gen)();
      while (letters_used[(unsigned char)(letter - 'a')] > n) {
        letter = (*letter_gen)();
      }
      letters_used[(unsigned char)(letter - 'a')]++;
      board[i][j] = letter;
    }
  }
  return board;
}
```