ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<zero>:
  endbr64
  test   %edi,%edi
  jle    L8
  test   %esi,%esi
  jle    L8
  push   %r13
  movslq %edx,%rdx
  movslq %esi,%rsi
  push   %r12
  lea    0x0(,%rdx,4),%r13
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L29:
  mov    %rcx,%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %r13,%rcx
  cmp    %ebx,%r12d
  jne    L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  ret
```

assistant: ```c
void zero(int M, int N, int step, int matrix[M][step]) {
  for (int i = 0; i < M; i++) {
    for (int j = 0; j < N; j++) {
      matrix[i][j] = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<UARTRxErrorGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x7f,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x14,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x9e,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int UARTRxErrorGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x14)))) & ((0x00000080u) | (0x00000010u) | (0x00000008u) | (0x00000004u) | (0x00000002u)));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UARTRxErrorGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x7f,%esi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x14(%ebx),%eax
  mov    %edx,0xc(%ebx)
  and    $0x9e,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int UARTRxErrorGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x14)))) & ((0x00000080u) | (0x00000010u) | (0x00000008u) | (0x00000004u) | (0x00000002u)));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTRxErrorGet>:
  endbr64
  push   %rbx
  mov    $0x7f,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x14(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x9e,%eax
  ret
```

assistant: ```c
unsigned int UARTRxErrorGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x14)))) & ((0x00000080u) | (0x00000010u) | (0x00000008u) | (0x00000004u) | (0x00000002u)));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: What is the c source code of the assembly code below:

```asm
<UARTRxErrorGet>:
  endbr64
  push   %rbx
  mov    $0x7f,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x14(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x9e,%eax
  ret
```

assistant: ```c
unsigned int UARTRxErrorGet(unsigned int baseAdd) {
  unsigned int lcrRegValue = 0;
  unsigned int retVal = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  retVal = ((*((volatile unsigned int *)(baseAdd + (0x14)))) & ((0x00000080u) | (0x00000010u) | (0x00000008u) | (0x00000004u) | (0x00000002u)));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x30(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L39
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L39
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L2
L39:
  movsd  -0x20(%rbp),%xmm1
  movsd  D46(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x30(%rbp),%xmm1
  comisd %xmm1,%xmm0
  ja     L4
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L4
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm3
  movsd  -0x20(%rbp),%xmm2
  mulsd  %xmm2,%xmm3
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D46(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L13
L4:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L56
L13:
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm3
  movsd  -0x20(%rbp),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log10@plt>
  movq   %xmm0,%rbx
  movsd  -0x20(%rbp),%xmm1
  movsd  D46(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <log10@plt>
  movq   %rbx,%xmm4
  divsd  %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L56:
  mov    $0x0,%eax
L2:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D52
data_type: string
name: unpack_data
arguments: data_label: D36
data_type: string
name: unpack_data
arguments: data_label: D46
data_type: byte[8]
name: unpack_data
arguments: data_label: D24
data_type: string
name: unpack_data
arguments: data_label: D50
data_type: string

tool: D52: %lf%lf%lf

tool: D36: 0.0

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D24: God

tool: D50: %.1f

assistant: ```c
int main() {
  double d, p, r;
  scanf("%lf%lf%lf", &d, &p, &r);
  if (d == 0) {
    printf("0.0\n");
    return 0;
  }
  if (d * (1 + r) - p > d || p - d * r < 0 || p / (p - d * r) < 1)
    printf("God\n");
  else {
    printf("%.1f", log10(p / (p - d * r)) / log10(1 + r));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  ucomisd D52(%rip),%xmm0
  jp     L38
  je     L67
L38:
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movapd %xmm3,%xmm1
  addsd  D67(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  ja     L3
  mulsd  %xmm3,%xmm0
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L3
  divsd  %xmm1,%xmm2
  movsd  D67(%rip),%xmm0
  comisd %xmm2,%xmm0
  jbe    L59
L3:
  lea    D11(%rip),%rdi
  call   <puts@plt>
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L67:
  lea    D48(%rip),%rdi
  call   <puts@plt>
  jmp    L63
L59:
  cvttsd2si %xmm2,%edi
  call   <log10@plt>
  movq   %xmm0,%rbx
  movsd  D67(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <log10@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L63
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D42
type: string
name: unpack_data
arguments: data_tag: D52
type: byte[8]
name: unpack_data
arguments: data_tag: D67
type: byte[8]
name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D48
type: string
name: unpack_data
arguments: data_tag: D21
type: string

tool: D42: %lf%lf%lf

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D11: God

tool: D48: 0.0

tool: D21: %.1f

assistant: ```c
int main() {
  double d, p, r;
  scanf("%lf%lf%lf", &d, &p, &r);
  if (d == 0) {
    printf("0.0\n");
    return 0;
  }
  if (d * (1 + r) - p > d || p - d * r < 0 || p / (p - d * r) < 1)
    printf("God\n");
  else {
    printf("%.1f", log10(p / (p - d * r)) / log10(1 + r));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  ucomisd %xmm3,%xmm0
  jp     L36
  je     L11
L36:
  movsd  0x20(%rsp),%xmm5
  movsd  D16(%rip),%xmm4
  movsd  0x18(%rsp),%xmm2
  movapd %xmm5,%xmm1
  addsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  ja     L51
  mulsd  %xmm5,%xmm0
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  comisd %xmm1,%xmm3
  ja     L51
  divsd  %xmm1,%xmm2
  comisd %xmm2,%xmm4
  jbe    L64
L51:
  lea    D20(%rip),%rdi
  call   <puts@plt>
L41:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L11:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L41
L64:
  cvttsd2si %xmm2,%edi
  call   <log10@plt>
  mov    D16(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  movq   %rax,%xmm4
  addsd  0x20(%rsp),%xmm4
  cvttsd2si %xmm4,%edi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D50(%rip),%rdi
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  jmp    L41
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D16
datatype: byte[8]
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D50
datatype: string

tool: D21: %lf%lf%lf

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D20: God

tool: D26: 0.0

tool: D50: %.1f

assistant: ```c
int main() {
  double d, p, r;
  scanf("%lf%lf%lf", &d, &p, &r);
  if (d == 0) {
    printf("0.0\n");
    return 0;
  }
  if (d * (1 + r) - p > d || p - d * r < 0 || p / (p - d * r) < 1)
    printf("God\n");
  else {
    printf("%.1f", log10(p / (p - d * r)) / log10(1 + r));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D32(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  ucomisd %xmm3,%xmm0
  jp     L7
  je     L42
L7:
  movsd  0x20(%rsp),%xmm5
  movsd  D10(%rip),%xmm4
  movsd  0x18(%rsp),%xmm2
  movapd %xmm5,%xmm1
  addsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  ja     L22
  mulsd  %xmm5,%xmm0
  movapd %xmm2,%xmm1
  subsd  %xmm0,%xmm1
  comisd %xmm1,%xmm3
  ja     L22
  divsd  %xmm1,%xmm2
  comisd %xmm2,%xmm4
  jbe    L38
L22:
  lea    D50(%rip),%rdi
  call   <puts@plt>
L73:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L42:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  jmp    L73
L38:
  cvttsd2si %xmm2,%edi
  call   <log10@plt>
  mov    D10(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  movq   %rax,%xmm4
  addsd  0x20(%rsp),%xmm4
  cvttsd2si %xmm4,%edi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D21(%rip),%rdi
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  jmp    L73
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D32
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D50
type_infered: string
name: disassemble_data
arguments: data_label: D43
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: string

tool: D32: %lf%lf%lf

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D50: God

tool: D43: 0.0

tool: D21: %.1f

assistant: ```c
int main() {
  double d, p, r;
  scanf("%lf%lf%lf", &d, &p, &r);
  if (d == 0) {
    printf("0.0\n");
    return 0;
  }
  if (d * (1 + r) - p > d || p - d * r < 0 || p / (p - d * r) < 1)
    printf("God\n");
  else {
    printf("%.1f", log10(p / (p - d * r)) / log10(1 + r));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<lexer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  sub    $0x20,%eax
  cmp    $0x23,%eax
  ja     L152
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L54
  mov    $0x1,%eax
  jmp    L54
  mov    $0x1,%eax
  jmp    L54
  mov    $0x2,%eax
  jmp    L54
  mov    $0x3,%eax
  jmp    L54
  mov    $0x4,%eax
  jmp    L54
  mov    $0x5,%eax
  jmp    L54
  mov    $0x6,%eax
  jmp    L54
  mov    $0x7,%eax
  jmp    L54
  mov    $0x8,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0x9,%eax
  jmp    L54
  mov    $0xa,%eax
  jmp    L54
L152:
  mov    $0xb,%eax
L54:
  pop    %rbp
  ret
```

assistant: ```c
int lexer(char string) {
  switch (string) {
  case 'A':
    return 1;
  case 'B':
    return 1;
  case 'C':
    return 1;
  case '=':
    return 2;
  case '+':
    return 3;
  case '-':
    return 4;
  case '*':
    return 5;
  case '/':
    return 6;
  case '(':
    return 7;
  case ')':
    return 8;
  case '1':
    return 9;
  case '2':
    return 9;
  case '3':
    return 9;
  case '4':
    return 9;
  case '5':
    return 9;
  case '6':
    return 9;
  case '7':
    return 9;
  case '8':
    return 9;
  case '9':
    return 9;
  case '0':
    return 9;
  case ' ':
    return 10;
  default:
    return 11;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lexer>:
  endbr64
  sub    $0x20,%edi
  cmp    $0x23,%dil
  ja     L8
  movzbl %dil,%edi
  lea    D3(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
L8:
  mov    $0xb,%eax
  ret
  mov    $0x1,%eax
  ret
```

assistant: ```c
int lexer(char string) {
  switch (string) {
  case 'A':
    return 1;
  case 'B':
    return 1;
  case 'C':
    return 1;
  case '=':
    return 2;
  case '+':
    return 3;
  case '-':
    return 4;
  case '*':
    return 5;
  case '/':
    return 6;
  case '(':
    return 7;
  case ')':
    return 8;
  case '1':
    return 9;
  case '2':
    return 9;
  case '3':
    return 9;
  case '4':
    return 9;
  case '5':
    return 9;
  case '6':
    return 9;
  case '7':
    return 9;
  case '8':
    return 9;
  case '9':
    return 9;
  case '0':
    return 9;
  case ' ':
    return 10;
  default:
    return 11;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lexer>:
  endbr64
  sub    $0x20,%edi
  mov    $0xb,%eax
  cmp    $0x23,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D8(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L6:
  ret
```

assistant: ```c
int lexer(char string) {
  switch (string) {
  case 'A':
    return 1;
  case 'B':
    return 1;
  case 'C':
    return 1;
  case '=':
    return 2;
  case '+':
    return 3;
  case '-':
    return 4;
  case '*':
    return 5;
  case '/':
    return 6;
  case '(':
    return 7;
  case ')':
    return 8;
  case '1':
    return 9;
  case '2':
    return 9;
  case '3':
    return 9;
  case '4':
    return 9;
  case '5':
    return 9;
  case '6':
    return 9;
  case '7':
    return 9;
  case '8':
    return 9;
  case '9':
    return 9;
  case '0':
    return 9;
  case ' ':
    return 10;
  default:
    return 11;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<lexer>:
  endbr64
  sub    $0x20,%edi
  mov    $0xb,%eax
  cmp    $0x23,%dil
  ja     L3
  movzbl %dil,%edi
  lea    D7(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L3:
  ret
```

assistant: ```c
int lexer(char string) {
  switch (string) {
  case 'A':
    return 1;
  case 'B':
    return 1;
  case 'C':
    return 1;
  case '=':
    return 2;
  case '+':
    return 3;
  case '-':
    return 4;
  case '*':
    return 5;
  case '/':
    return 6;
  case '(':
    return 7;
  case ')':
    return 8;
  case '1':
    return 9;
  case '2':
    return 9;
  case '3':
    return 9;
  case '4':
    return 9;
  case '5':
    return 9;
  case '6':
    return 9;
  case '7':
    return 9;
  case '8':
    return 9;
  case '9':
    return 9;
  case '0':
    return 9;
  case ' ':
    return 10;
  default:
    return 11;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bin2bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x40,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x30(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  cmpq   $0x0,-0x30(%rbp)
  je     L9
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L20
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
L9:
  mov    -0x30(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: %ld

assistant: ```c
long *bin2bits(long bin, long *bits) {
  size_t i = 0;
  size_t length = sizeof(bin) * 8;
  char *buffer = malloc(sizeof(*buffer) * length);
  bits = realloc(bits, sizeof(*bits) * length);
  if ((buffer != NULL) && (bits != NULL)) {
    snprintf(buffer, length, "%ld", bin);
    while (*buffer) {
      bits[i] = *buffer - '0';
      i++;
      buffer++;
    }
  }
  return bits;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bin2bits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x200,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L33
  test   %rax,%rax
  jne    L24
L33:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    %r12,%rcx
  lea    D1(%rip),%rdx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L33
  mov    $0x0,%edx
L2:
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  mov    %rax,(%rbx,%rdx,8)
  add    $0x1,%rdx
  movzbl 0x0(%rbp,%rdx,1),%eax
  test   %al,%al
  jne    L2
  jmp    L33
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %ld

assistant: ```c
long *bin2bits(long bin, long *bits) {
  size_t i = 0;
  size_t length = sizeof(bin) * 8;
  char *buffer = malloc(sizeof(*buffer) * length);
  bits = realloc(bits, sizeof(*bits) * length);
  if ((buffer != NULL) && (bits != NULL)) {
    snprintf(buffer, length, "%ld", bin);
    while (*buffer) {
      bits[i] = *buffer - '0';
      i++;
      buffer++;
    }
  }
  return bits;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bin2bits>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x40,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    $0x200,%esi
  mov    %rax,%rbx
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L36
  test   %rax,%rax
  jne    L11
L36:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  lea    D9(%rip),%rdx
  mov    %r13,%rcx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L36
  xor    %ecx,%ecx
L20:
  sub    $0x30,%edx
  movslq %edx,%rdx
  mov    %rdx,(%r12,%rcx,8)
  add    $0x1,%rcx
  movsbl (%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L20
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: %ld

assistant: ```c
long *bin2bits(long bin, long *bits) {
  size_t i = 0;
  size_t length = sizeof(bin) * 8;
  char *buffer = malloc(sizeof(*buffer) * length);
  bits = realloc(bits, sizeof(*bits) * length);
  if ((buffer != NULL) && (bits != NULL)) {
    snprintf(buffer, length, "%ld", bin);
    while (*buffer) {
      bits[i] = *buffer - '0';
      i++;
      buffer++;
    }
  }
  return bits;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bin2bits>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x40,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    $0x200,%esi
  mov    %rax,%rbx
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L34
  test   %rax,%rax
  jne    L2
L34:
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nop
L2:
  lea    D0(%rip),%rdx
  mov    %r13,%rcx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L34
  xor    %ecx,%ecx
L29:
  sub    $0x30,%edx
  movslq %edx,%rdx
  mov    %rdx,(%r12,%rcx,8)
  add    $0x1,%rcx
  movsbl (%rbx,%rcx,1),%edx
  test   %dl,%dl
  jne    L29
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: %ld

assistant: ```c
long *bin2bits(long bin, long *bits) {
  size_t i = 0;
  size_t length = sizeof(bin) * 8;
  char *buffer = malloc(sizeof(*buffer) * length);
  bits = realloc(bits, sizeof(*bits) * length);
  if ((buffer != NULL) && (bits != NULL)) {
    snprintf(buffer, length, "%ld", bin);
    while (*buffer) {
      bits[i] = *buffer - '0';
      i++;
      buffer++;
    }
  }
  return bits;
}
```