ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<httpclient_base64enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x333231307a797877,%rax
  movabs $0x2f2b393837363534,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x3d,-0x10(%rbp)
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L48
L65:
  mov    -0x58(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x70(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x58(%rbp)
  addl   $0x8,-0x54(%rbp)
  jmp    L34
L33:
  mov    -0x54(%rbp),%eax
  sub    $0x6,%eax
  mov    -0x58(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0x5c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x5c(%rbp)
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  subl   $0x6,-0x54(%rbp)
L34:
  cmpl   $0x5,-0x54(%rbp)
  jg     L33
  addq   $0x1,-0x70(%rbp)
L48:
  mov    -0x70(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  cmpl   $0x0,-0x54(%rbp)
  jle    L35
  mov    $0x6,%eax
  sub    -0x54(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x58(%rbp)
  mov    -0x58(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0x5c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x5c(%rbp)
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  jmp    L35
L75:
  mov    -0x5c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x5c(%rbp)
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3d,(%rax)
L35:
  mov    -0x5c(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L75
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
void httpclient_base64enc(char *out, const char *in) {
  const char code[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
  int i = 0, x = 0, l = 0;
  for (; *in; in++) {
    x = x << 8 | *in;
    for (l += 8; l >= 6; l -= 6) {
      out[i++] = code[(x >> (l - 6)) & 0x3f];
    }
  }
  if (l > 0) {
    x <<= 6 - l;
    out[i++] = code[x & 0x3f];
  }
  for (; i % 4;) {
    out[i++] = '=';
  }
  out[i] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<httpclient_base64enc>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x333231307a797877,%rax
  movabs $0x2f2b393837363534,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movw   $0x3d,0x40(%rsp)
  movzbl (%rsi),%eax
  test   %al,%al
  je     L87
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x0,%edi
L34:
  shl    $0x8,%r8d
  movsbl %al,%eax
  or     %eax,%r8d
  add    $0x8,%ecx
  cmp    $0x5,%ecx
  jle    L89
  movslq %edi,%rdx
  add    %r9,%rdx
L28:
  sub    $0x6,%ecx
  add    $0x1,%edi
  mov    %r8d,%eax
  sar    %cl,%eax
  and    $0x3f,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    $0x5,%ecx
  jg     L28
L89:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L34
  test   %ecx,%ecx
  jle    L30
  movslq %edi,%rdx
  mov    $0x6,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    %cl,%r8d
  and    $0x3f,%r8d
  movzbl (%rsp,%r8,1),%eax
  mov    %al,(%r9,%rdx,1)
  lea    0x1(%rdi),%edi
L30:
  test   $0x3,%dil
  je     L3
  lea    0x1(%rdi),%eax
  cltq
L50:
  mov    %eax,%edi
  movb   $0x3d,-0x1(%r9,%rax,1)
  mov    %eax,%edx
  and    $0x3,%edx
  add    $0x1,%rax
  test   %edx,%edx
  jne    L50
L3:
  movslq %edi,%rdi
  movb   $0x0,(%r9,%rdi,1)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x58,%rsp
  ret
L87:
  mov    $0x0,%edi
  jmp    L3
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void httpclient_base64enc(char *out, const char *in) {
  const char code[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
  int i = 0, x = 0, l = 0;
  for (; *in; in++) {
    x = x << 8 | *in;
    for (l += 8; l >= 6; l -= 6) {
      out[i++] = code[(x >> (l - 6)) & 0x3f];
    }
  }
  if (l > 0) {
    x <<= 6 - l;
    out[i++] = code[x & 0x3f];
  }
  for (; i % 4;) {
    out[i++] = '=';
  }
  out[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<httpclient_base64enc>:
  endbr64
  sub    $0x58,%rsp
  movdqa D28(%rip),%xmm0
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x3d,%eax
  movaps %xmm0,(%rsp)
  movdqa D32(%rip),%xmm0
  mov    %ax,0x40(%rsp)
  movsbl (%rsi),%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D24(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D16(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  test   %al,%al
  je     L9
  mov    %rsi,%r10
  xor    %ecx,%ecx
  xor    %edi,%edi
  xor    %esi,%esi
  nopl   0x0(%rax)
L62:
  shl    $0x8,%edi
  movslq %esi,%rdx
  add    $0x8,%ecx
  or     %eax,%edi
  add    %r9,%rdx
  xchg   %ax,%ax
L6:
  sub    $0x6,%ecx
  mov    %edi,%eax
  mov    %esi,%r8d
  add    $0x1,%rdx
  sar    %cl,%eax
  add    $0x1,%esi
  and    $0x3f,%eax
  movzbl (%rsp,%rax,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    $0x5,%ecx
  jg     L6
  movsbl 0x1(%r10),%eax
  add    $0x1,%r10
  test   %al,%al
  jne    L62
  mov    %esi,%eax
  test   %ecx,%ecx
  je     L79
  mov    $0x6,%edx
  movslq %esi,%rsi
  lea    0x2(%r8),%eax
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    %cl,%edi
  and    $0x3f,%edi
  movzbl (%rsp,%rdi,1),%edx
  mov    %dl,(%r9,%rsi,1)
L79:
  test   $0x3,%al
  je     L25
  add    $0x1,%eax
  cltq
  nopl   0x0(%rax)
L35:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%r9,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0x3,%edx
  test   %edx,%edx
  jne    L35
  add    %rcx,%r9
L9:
  movb   $0x0,(%r9)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x58,%rsp
  ret
L25:
  cltq
  add    %rax,%r9
  jmp    L9
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
type_infered: byte[16]
name: disassemble_data
arguments: tag: D32
type_infered: byte[16]
name: disassemble_data
arguments: tag: D24
type_infered: byte[16]
name: disassemble_data
arguments: tag: D16
type_infered: byte[16]

tool: {"D28": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D32": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D24": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D16": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
void httpclient_base64enc(char *out, const char *in) {
  const char code[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
  int i = 0, x = 0, l = 0;
  for (; *in; in++) {
    x = x << 8 | *in;
    for (l += 8; l >= 6; l -= 6) {
      out[i++] = code[(x >> (l - 6)) & 0x3f];
    }
  }
  if (l > 0) {
    x <<= 6 - l;
    out[i++] = code[x & 0x3f];
  }
  for (; i % 4;) {
    out[i++] = '=';
  }
  out[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<httpclient_base64enc>:
  endbr64
  sub    $0x58,%rsp
  movdqa D11(%rip),%xmm0
  movsbl (%rsi),%ecx
  mov    $0x3d,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %dx,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D36(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  test   %cl,%cl
  je     L8
  mov    %rsi,%r9
  xor    %r10d,%r10d
  xor    %edx,%edx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %edx,%ecx
  movslq %r8d,%r8
  add    $0x1,%r9
  sub    $0x4,%r10d
  and    $0x3f,%ecx
  add    $0x2,%eax
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,(%rdi,%r8,1)
  movsbl (%r9),%ecx
  test   %cl,%cl
  je     L76
L44:
  shl    $0x8,%edx
  movslq %eax,%r11
  lea    0x1(%rax),%r8d
  or     %ecx,%edx
  lea    0x2(%r10),%ecx
  mov    %edx,%esi
  sar    %cl,%esi
  and    $0x3f,%esi
  movzbl (%rsp,%rsi,1),%esi
  mov    %sil,(%rdi,%r11,1)
  cmp    $0x5,%ecx
  jg     L28
  add    $0x1,%r9
  mov    %ecx,%r10d
  mov    %r8d,%eax
  movsbl (%r9),%ecx
  test   %cl,%cl
  jne    L44
  nopl   0x0(%rax)
L76:
  test   %r10d,%r10d
  je     L83
  mov    $0x6,%ecx
  movslq %eax,%rsi
  add    $0x1,%eax
  sub    %r10d,%ecx
  shl    %cl,%edx
  and    $0x3f,%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,(%rdi,%rsi,1)
L83:
  test   $0x3,%al
  je     L49
  add    $0x1,%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %eax,%edx
  movb   $0x3d,-0x1(%rdi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  and    $0x3,%edx
  test   %edx,%edx
  jne    L35
  add    %rcx,%rdi
L8:
  movb   $0x0,(%rdi)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
L49:
  cltq
  add    %rax,%rdi
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type: byte[16]
name: retrieve_data
arguments: data_tag: D9
type: byte[16]
name: retrieve_data
arguments: data_tag: D36
type: byte[16]
name: retrieve_data
arguments: data_tag: D19
type: byte[16]

tool: {"D11": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D9": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D36": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D19": [0x77,0x78,0x79,0x7a,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x2b,0x2f]}

assistant: ```c
void httpclient_base64enc(char *out, const char *in) {
  const char code[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
  int i = 0, x = 0, l = 0;
  for (; *in; in++) {
    x = x << 8 | *in;
    for (l += 8; l >= 6; l -= 6) {
      out[i++] = code[(x >> (l - 6)) & 0x3f];
    }
  }
  if (l > 0) {
    x <<= 6 - l;
    out[i++] = code[x & 0x3f];
  }
  for (; i % 4;) {
    out[i++] = '=';
  }
  out[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<getPasswordLengthInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzwl -0xa(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string

tool: D0: 
Enter a password length between 1 to 32 inclusive. 0 to go back: 

tool: D11: %hi

assistant: ```c
short getPasswordLengthInput(void) {
  printf("\nEnter a password length between 1 to 32 inclusive. 0 to go back: ");
  short input;
  scanf("%hi", &input);
  return input;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getPasswordLengthInput>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D3: 
Enter a password length between 1 to 32 inclusive. 0 to go back: 

tool: D0: %hi

assistant: ```c
short getPasswordLengthInput(void) {
  printf("\nEnter a password length between 1 to 32 inclusive. 0 to go back: ");
  short input;
  scanf("%hi", &input);
  return input;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getPasswordLengthInput>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D5
type_infered: string

tool: D0: 
Enter a password length between 1 to 32 inclusive. 0 to go back: 

tool: D5: %hi

assistant: ```c
short getPasswordLengthInput(void) {
  printf("\nEnter a password length between 1 to 32 inclusive. 0 to go back: ");
  short input;
  scanf("%hi", &input);
  return input;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getPasswordLengthInput>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x6(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movzwl 0x6(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D2: 
Enter a password length between 1 to 32 inclusive. 0 to go back: 

tool: D15: %hi

assistant: ```c
short getPasswordLengthInput(void) {
  printf("\nEnter a password length between 1 to 32 inclusive. 0 to go back: ");
  short input;
  scanf("%hi", &input);
  return input;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L3
L39:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L32
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L39
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D16: %d

tool: D3: Sum: %d

assistant: ```c
int main() {
  int x, y, sum = 0;
  scanf("%d", &x);
  scanf("%d", &y);
  while (x <= y) {
    if (x % 2 == 1)
      sum += x;
    x++;
  }
  printf("Sum: %d", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edi
  cmp    %edi,%eax
  jg     L7
  lea    0x1(%rdi),%r8d
  mov    $0x0,%esi
  jmp    L36
L12:
  mov    %edx,%eax
L36:
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  lea    (%rsi,%rax,1),%ecx
  cmp    $0x1,%edx
  cmove  %ecx,%esi
  lea    0x1(%rax),%edx
  cmp    %edi,%eax
  jne    L12
  mov    %r8d,(%rsp)
L22:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  mov    $0x0,%esi
  jmp    L22
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D5: %d

tool: D15: Sum: %d

assistant: ```c
int main() {
  int x, y, sum = 0;
  scanf("%d", &x);
  scanf("%d", &y);
  while (x <= y) {
    if (x % 2 == 1)
      sum += x;
    x++;
  }
  printf("Sum: %d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edi
  cmp    %edi,%eax
  jg     L39
  lea    0x1(%rdi),%r8d
  xor    %esi,%esi
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %edx,%eax
L28:
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  lea    (%rsi,%rax,1),%ecx
  cmp    $0x1,%edx
  lea    0x1(%rax),%edx
  cmove  %ecx,%esi
  cmp    %edi,%eax
  jne    L19
  mov    %r8d,(%rsp)
L48:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L39:
  xor    %esi,%esi
  jmp    L48
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D11
data_type: string

tool: D1: %d

tool: D11: Sum: %d

assistant: ```c
int main() {
  int x, y, sum = 0;
  scanf("%d", &x);
  scanf("%d", &y);
  while (x <= y) {
    if (x % 2 == 1)
      sum += x;
    x++;
  }
  printf("Sum: %d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edi
  cmp    %edi,%ecx
  jg     L88
  mov    %edi,%eax
  sub    %ecx,%eax
  lea    0x1(%rax),%r8d
  cmp    $0x2,%eax
  jbe    L7
  movd   %ecx,%xmm7
  mov    %r8d,%eax
  pxor   %xmm3,%xmm3
  xor    %edx,%edx
  pshufd $0x0,%xmm7,%xmm2
  movdqa D7(%rip),%xmm6
  paddd  D9(%rip),%xmm2
  shr    $0x2,%eax
  movdqa D32(%rip),%xmm5
  nopl   (%rax)
L6:
  movdqa %xmm2,%xmm1
  add    $0x1,%edx
  paddd  %xmm6,%xmm2
  movdqa %xmm1,%xmm4
  movdqa %xmm1,%xmm0
  psrld  $0x1f,%xmm4
  paddd  %xmm4,%xmm0
  pand   %xmm5,%xmm0
  psubd  %xmm4,%xmm0
  pcmpeqd %xmm5,%xmm0
  pand   %xmm1,%xmm0
  paddd  %xmm0,%xmm3
  cmp    %eax,%edx
  jne    L6
  movdqa %xmm3,%xmm0
  mov    %r8d,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm3
  add    %eax,%ecx
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%esi
  cmp    %eax,%r8d
  je     L25
L26:
  mov    %ecx,%edx
  lea    0x1(%rcx),%r8d
  shr    $0x1f,%edx
  lea    (%rcx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rsi,%rcx,1),%edx
  cmp    $0x1,%eax
  cmove  %edx,%esi
  cmp    %edi,%r8d
  jg     L25
  mov    %r8d,%eax
  mov    $0x2,%r9d
  cltd
  idiv   %r9d
  sub    $0x1,%edx
  je     L55
L86:
  add    $0x2,%ecx
  cmp    %ecx,%edi
  jl     L25
  mov    %ecx,%eax
  mov    $0x2,%r8d
  cltd
  idiv   %r8d
  sub    $0x1,%edx
  je     L2
L25:
  add    $0x1,%edi
  mov    %edi,(%rsp)
L46:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L55:
  add    %r8d,%esi
  jmp    L86
L2:
  add    %ecx,%esi
  jmp    L25
L88:
  xor    %esi,%esi
  jmp    L46
L7:
  xor    %esi,%esi
  jmp    L26
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D7
datatype: byte[16]
name: parse_data
arguments: data_label: D9
datatype: byte[16]
name: parse_data
arguments: data_label: D32
datatype: byte[16]
name: parse_data
arguments: data_label: D38
datatype: string

tool: D15: %d

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D32": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D38: Sum: %d

assistant: ```c
int main() {
  int x, y, sum = 0;
  scanf("%d", &x);
  scanf("%d", &y);
  while (x <= y) {
    if (x % 2 == 1)
      sum += x;
    x++;
  }
  printf("Sum: %d", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nrf_set_mode_prx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xd(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <nrf_read_register@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L22
  mov    -0xc(%rbp),%eax
  jmp    L15
L22:
  movzbl -0xd(%rbp),%eax
  or     $0x1,%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <nrf_write_register@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x8c,%edi
  call   <timer_wait_us@plt>
  mov    -0xc(%rbp),%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int nrf_set_mode_prx(char *retstatus) {
  char confreg = 0;
  int ret;
  ret = nrf_read_register(0x00, &confreg, retstatus);
  if (ret < 0)
    return ret;
  confreg |= 0x01;
  ret = nrf_write_register(0x00, confreg, retstatus);
  timer_wait_us(140);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nrf_set_mode_prx>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    %rdi,%rdx
  mov    $0x0,%edi
  call   <nrf_read_register@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L12
  movzbl 0x7(%rsp),%esi
  or     $0x1,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  mov    %rbp,%rdx
  mov    $0x0,%edi
  call   <nrf_write_register@plt>
  mov    %eax,%ebx
  mov    $0x8c,%edi
  call   <timer_wait_us@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nrf_set_mode_prx(char *retstatus) {
  char confreg = 0;
  int ret;
  ret = nrf_read_register(0x00, &confreg, retstatus);
  if (ret < 0)
    return ret;
  confreg |= 0x01;
  ret = nrf_write_register(0x00, confreg, retstatus);
  timer_wait_us(140);
  return ret;
}
```