ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<SameNecklace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L5
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%rbx
  je     L13
L58:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L58
  mov    %rsp,%r13
  mov    $0x200,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L58
  nopl   (%rax)
L5:
  xor    %eax,%eax
  jmp    L58
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: 

assistant: ```c
bool SameNecklace(char *src, char *shifted) {
  if (!src || !shifted || strlen(shifted) != strlen(src)) {
    return false;
  }
  if (strcmp(shifted, "") == 0) {
    return true;
  }
  char searchStr[256 * 2];
  memset(searchStr, '\0', sizeof(searchStr));
  strcpy(searchStr, shifted);
  strcat(searchStr, shifted);
  return strstr(searchStr, src) ? true : false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<a16toi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L25
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L25:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  mov    %eax,-0x8(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int a16toi(char *s) {
  int i, t;
  int sum = 0;
  for (i = 0; s[i]; i++) {
    if (s[i] <= '9')
      t = s[i] - '0';
    else
      t = s[i] - 'a' + 10;
    sum = sum * 16 + t;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<a16toi>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L46
  add    $0x1,%rdi
  mov    $0x0,%eax
  jmp    L14
L0:
  movsbl %dl,%edx
  sub    $0x57,%edx
L47:
  shl    $0x4,%eax
  add    %edx,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L22
L14:
  cmp    $0x39,%dl
  jg     L0
  movsbl %dl,%edx
  sub    $0x30,%edx
  jmp    L47
L22:
  ret
L46:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int a16toi(char *s) {
  int i, t;
  int sum = 0;
  for (i = 0; s[i]; i++) {
    if (s[i] <= '9')
      t = s[i] - '0';
    else
      t = s[i] - 'a' + 10;
    sum = sum * 16 + t;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a16toi>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L32
  add    $0x1,%rdi
  xor    %eax,%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x30,%edx
L43:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L23
L15:
  cmp    $0x39,%dl
  jle    L17
  sub    $0x57,%edx
  movsbl %dl,%edx
  jmp    L43
  nopl   0x0(%rax)
L23:
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
int a16toi(char *s) {
  int i, t;
  int sum = 0;
  for (i = 0; s[i]; i++) {
    if (s[i] <= '9')
      t = s[i] - '0';
    else
      t = s[i] - 'a' + 10;
    sum = sum * 16 + t;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a16toi>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L38
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  shl    $0x4,%eax
  cmp    $0x39,%dl
  jg     L30
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,1),%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L22
  ret
  nopl   0x0(%rax)
L30:
  sub    $0x57,%edx
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L22
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int a16toi(char *s) {
  int i, t;
  int sum = 0;
  for (i = 0; s[i]; i++) {
    if (s[i] <= '9')
      t = s[i] - '0';
    else
      t = s[i] - 'a' + 10;
    sum = sum * 16 + t;
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x44(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string

tool: D0: %m/%d/%Y %H:%M:%S> 

assistant: ```c
void timestamp(int fd) {
  time_t now;
  struct tm *time_struct;
  int length;
  char time_buffer[40];
  time(&now);
  time_struct = localtime((const time_t *)&now);
  length = strftime(time_buffer, 40, "%m/%d/%Y %H:%M:%S> ", time_struct);
  write(fd, time_buffer, length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timestamp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    0x10(%rsp),%rbp
  lea    D5(%rip),%rdx
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: %m/%d/%Y %H:%M:%S> 

assistant: ```c
void timestamp(int fd) {
  time_t now;
  struct tm *time_struct;
  int length;
  char time_buffer[40];
  time(&now);
  time_struct = localtime((const time_t *)&now);
  length = strftime(time_buffer, 40, "%m/%d/%Y %H:%M:%S> ", time_struct);
  write(fd, time_buffer, length);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<timestamp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  lea    0x10(%rsp),%r12
  call   <localtime@plt>
  lea    D6(%rip),%rdx
  mov    $0x28,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: %m/%d/%Y %H:%M:%S> 

assistant: ```c
void timestamp(int fd) {
  time_t now;
  struct tm *time_struct;
  int length;
  char time_buffer[40];
  time(&now);
  time_struct = localtime((const time_t *)&now);
  length = strftime(time_buffer, 40, "%m/%d/%Y %H:%M:%S> ", time_struct);
  write(fd, time_buffer, length);
}
```
user: What is the c source code of the assembly code below?

```asm
<timestamp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  lea    0x10(%rsp),%r12
  call   <localtime@plt>
  lea    D9(%rip),%rdx
  mov    $0x28,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %m/%d/%Y %H:%M:%S> 

assistant: ```c
void timestamp(int fd) {
  time_t now;
  struct tm *time_struct;
  int length;
  char time_buffer[40];
  time(&now);
  time_struct = localtime((const time_t *)&now);
  length = strftime(time_buffer, 40, "%m/%d/%Y %H:%M:%S> ", time_struct);
  write(fd, time_buffer, length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L19
  jmp    L6
L24:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L24
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strncpy(char *dest, char *src, unsigned int n) {
  unsigned int i;
  i = 0;
  while ((src[i] != '\0') && (i < n)) {
    dest[i] = src[i];
    i++;
  }
  while (i < n) {
    dest[i] = '\0';
    i++;
  }
  return (dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strncpy>:
  endbr64
  mov    %rdi,%r8
  movzbl (%rsi),%ecx
  test   %edx,%edx
  je     L66
  test   %cl,%cl
  je     L66
  mov    $0x0,%eax
  mov    $0x0,%edi
L35:
  mov    %cl,(%r8,%rdi,1)
  add    $0x1,%eax
  mov    %eax,%edi
  movzbl (%rsi,%rdi,1),%ecx
  cmp    %eax,%edx
  jbe    L36
  test   %cl,%cl
  jne    L35
L36:
  cmp    %eax,%edx
  jbe    L31
  mov    %eax,%esi
  lea    (%r8,%rsi,1),%rcx
  lea    0x1(%r8,%rsi,1),%rsi
  sub    $0x1,%edx
  sub    %eax,%edx
  lea    (%rsi,%rdx,1),%rax
L21:
  movb   $0x0,(%rcx)
  add    $0x1,%rcx
  cmp    %rax,%rcx
  jne    L21
L31:
  mov    %r8,%rax
  ret
L66:
  mov    $0x0,%eax
  jmp    L36
```

assistant: ```c
char *ft_strncpy(char *dest, char *src, unsigned int n) {
  unsigned int i;
  i = 0;
  while ((src[i] != '\0') && (i < n)) {
    dest[i] = src[i];
    i++;
  }
  while (i < n) {
    dest[i] = '\0';
    i++;
  }
  return (dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%ecx
  mov    %rdi,%r12
  test   %cl,%cl
  je     L31
  test   %edx,%edx
  je     L53
  lea    -0x1(%rdx),%r8d
  mov    $0x1,%eax
  add    $0x2,%r8
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L53
L19:
  mov    %cl,-0x1(%r12,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%edi
  test   %cl,%cl
  jne    L49
L20:
  cmp    %edi,%edx
  jbe    L53
  sub    $0x1,%edx
  xor    %esi,%esi
  sub    %edi,%edx
  add    %r12,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L53:
  mov    %r12,%rax
  pop    %r12
  ret
L31:
  xor    %edi,%edi
  jmp    L20
```

assistant: ```c
char *ft_strncpy(char *dest, char *src, unsigned int n) {
  unsigned int i;
  i = 0;
  while ((src[i] != '\0') && (i < n)) {
    dest[i] = src[i];
    i++;
  }
  while (i < n) {
    dest[i] = '\0';
    i++;
  }
  return (dest);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%ecx
  mov    %rdi,%r12
  test   %cl,%cl
  je     L18
  test   %edx,%edx
  je     L68
  lea    -0x1(%rdx),%r8d
  mov    $0x1,%eax
  add    $0x2,%r8
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L68
L8:
  mov    %cl,-0x1(%r12,%rax,1)
  movzbl (%rsi,%rax,1),%ecx
  mov    %eax,%edi
  test   %cl,%cl
  jne    L5
L39:
  cmp    %edi,%edx
  jbe    L68
  sub    $0x1,%edx
  xor    %esi,%esi
  sub    %edi,%edx
  add    %r12,%rdi
  add    $0x1,%rdx
  call   <memset@plt>
L68:
  mov    %r12,%rax
  pop    %r12
  ret
L18:
  xor    %edi,%edi
  jmp    L39
```

assistant: ```c
char *ft_strncpy(char *dest, char *src, unsigned int n) {
  unsigned int i;
  i = 0;
  while ((src[i] != '\0') && (i < n)) {
    dest[i] = src[i];
    i++;
  }
  while (i < n) {
    dest[i] = '\0';
    i++;
  }
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L65
L80:
  addq   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L82
  movl   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L58
L82:
  movl   $0x0,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L58
  addq   $0x1,-0x8(%rbp)
  jmp    L58
L94:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L94
L60:
  cmpl   $0x0,-0x18(%rbp)
  je     L73
  negq   -0x10(%rbp)
L73:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long atol(const char *ptr) {
  long acc = 0;
  const char *s = ptr;
  int neg, c;
  while (*s == ' ' || *s == '\t')
    s++;
  if (*s == '-') {
    neg = 1;
    s++;
  } else {
    neg = 0;
    if (*s == '+')
      s++;
  }
  while (*s) {
    if (*s < '0' || *s > '9')
      break;
    c = *s - '0';
    acc = acc * 10 + c;
    s++;
  }
  if (neg)
    acc = -acc;
  return acc;
}
```
user: What is the c source code of the assembly code below:

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L27
  cmp    $0x9,%al
  jne    L86
L27:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L27
  cmp    $0x9,%al
  je     L27
L86:
  cmp    $0x2d,%al
  je     L99
  cmp    $0x2b,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movzbl (%rdi),%eax
  mov    $0x0,%esi
  test   %al,%al
  je     L37
L104:
  mov    $0x0,%edx
L1:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L24
  lea    (%rdx,%rdx,4),%rdx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
L24:
  test   %esi,%esi
  je     L13
L39:
  neg    %rdx
L13:
  mov    %rdx,%rax
  ret
L99:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdi
  mov    $0x1,%esi
  mov    $0x0,%edx
  test   %al,%al
  jne    L104
  jmp    L39
L37:
  mov    $0x0,%edx
  jmp    L13
```

assistant: ```c
long atol(const char *ptr) {
  long acc = 0;
  const char *s = ptr;
  int neg, c;
  while (*s == ' ' || *s == '\t')
    s++;
  if (*s == '-') {
    neg = 1;
    s++;
  } else {
    neg = 0;
    if (*s == '+')
      s++;
  }
  while (*s) {
    if (*s < '0' || *s > '9')
      break;
    c = *s - '0';
    acc = acc * 10 + c;
    s++;
  }
  if (neg)
    acc = -acc;
  return acc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L107
  cmp    $0x20,%al
  jne    L106
  nop
L107:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L107
  cmp    $0x9,%al
  je     L107
L106:
  cmp    $0x2d,%al
  je     L129
  cmp    $0x2b,%al
  je     L26
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  test   %al,%al
  je     L100
L110:
  xor    %r8d,%r8d
  jmp    L137
  cs nopw 0x0(%rax,%rax,1)
L112:
  movsbq %al,%rax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  test   %al,%al
  je     L136
L137:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L112
L136:
  mov    %r8,%rax
  neg    %rax
  test   %ecx,%ecx
  cmovne %rax,%r8
L79:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L26:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L100
  mov    %rdx,%rdi
  xor    %ecx,%ecx
  jmp    L110
  nopl   0x0(%rax,%rax,1)
L129:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  test   %al,%al
  jne    L110
L100:
  xor    %r8d,%r8d
  jmp    L79
```

assistant: ```c
long atol(const char *ptr) {
  long acc = 0;
  const char *s = ptr;
  int neg, c;
  while (*s == ' ' || *s == '\t')
    s++;
  if (*s == '-') {
    neg = 1;
    s++;
  } else {
    neg = 0;
    if (*s == '+')
      s++;
  }
  while (*s) {
    if (*s < '0' || *s > '9')
      break;
    c = *s - '0';
    acc = acc * 10 + c;
    s++;
  }
  if (neg)
    acc = -acc;
  return acc;
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L133
  cmp    $0x20,%al
  jne    L41
  nop
L133:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L133
  cmp    $0x9,%al
  je     L133
L41:
  cmp    $0x2d,%al
  je     L54
  cmp    $0x2b,%al
  je     L1
  xor    %ecx,%ecx
  test   %al,%al
  je     L79
L40:
  xor    %r8d,%r8d
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L122:
  movsbq %al,%rax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8
  movzbl (%rdi),%eax
  test   %al,%al
  je     L106
L42:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L122
L106:
  mov    %r8,%rax
  neg    %rax
  test   %ecx,%ecx
  cmovne %rax,%r8
L18:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L79
  mov    %rdx,%rdi
  xor    %ecx,%ecx
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L54:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  test   %al,%al
  jne    L40
L79:
  xor    %r8d,%r8d
  jmp    L18
```

assistant: ```c
long atol(const char *ptr) {
  long acc = 0;
  const char *s = ptr;
  int neg, c;
  while (*s == ' ' || *s == '\t')
    s++;
  if (*s == '-') {
    neg = 1;
    s++;
  } else {
    neg = 0;
    if (*s == '+')
      s++;
  }
  while (*s) {
    if (*s < '0' || *s > '9')
      break;
    c = *s - '0';
    acc = acc * 10 + c;
    s++;
  }
  if (neg)
    acc = -acc;
  return acc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x14,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L29:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0xc,-0x8(%rbp)
  jle    L29
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
L2:
  cmpl   $0x64,-0x10(%rbp)
  jle    L9
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 6;
  int c = 20;
  while (a <= 100) {
    int i;
    a = b;
    for (i = 0; i <= 12; i++) {
      a++;
    }
    b = b + c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 6;
  int c = 20;
  while (a <= 100) {
    int i;
    a = b;
    for (i = 0; i <= 12; i++) {
      a++;
    }
    b = b + c;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 6;
  int c = 20;
  while (a <= 100) {
    int i;
    a = b;
    for (i = 0; i <= 12; i++) {
      a++;
    }
    b = b + c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 6;
  int c = 20;
  while (a <= 100) {
    int i;
    a = b;
    for (i = 0; i <= 12; i++) {
      a++;
    }
    b = b + c;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sub_by_ptr_mm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <by_ptr_mm@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  nop
  leave
  ret
```

assistant: ```c
void sub_by_ptr_mm(uint32_t x) {
  by_ptr_mm(x);
  sub();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sub_by_ptr_mm>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_mm@plt>
  mov    $0x0,%eax
  call   <sub@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sub_by_ptr_mm(uint32_t x) {
  by_ptr_mm(x);
  sub();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sub_by_ptr_mm>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_mm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sub@plt>
```

assistant: ```c
void sub_by_ptr_mm(uint32_t x) {
  by_ptr_mm(x);
  sub();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sub_by_ptr_mm>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_mm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sub@plt>
```

assistant: ```c
void sub_by_ptr_mm(uint32_t x) {
  by_ptr_mm(x);
  sub();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<backtrack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <remaining_moves@plt>
  cmp    $0x1,%eax
  jle    L2
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2a,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L7
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L2:
  nop
  leave
  ret
```

assistant: ```c
void backtrack(int n, int index, char *board, int *top, char **stack) {
  if (remaining_moves(n, board) > 1) {
    board[index] = '*';
    for (int i = 0; i < n * n; i++) {
      stack[*top][i] = board[i];
    }
    *top += 1;
  }
}
```