ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<printBits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L79:
  mov    $0x31,%edi
  shr    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L62
L72:
  test   %ebx,%r12d
  jne    L79
  mov    $0x30,%edi
  shr    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L72
L62:
  mov    $0xa,%edi
  mov    $0x20,%ebp
  mov    $0x1,%ebx
  call   <putchar@plt>
  lea    D7(%rip),%r12
  jmp    L63
  nopl   0x0(%rax)
L58:
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L33
L63:
  cmp    $0xffffffff,%ebx
  jne    L58
  xor    %eax,%eax
  mov    $0x9,%esi
  mov    %r12,%rdi
  mov    $0x8,%ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L63
L33:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %i

assistant: ```c
void printBits(unsigned int bitmap) {
  unsigned i;
  int count = 0, j, k = 1;
  for (i = 1 << 31; i > 0; i = i / 2, count++) {
    (bitmap & i) ? printf("1") : printf("0");
  }
  printf("\n");
  for (j = 32; j > 0; j--, k--) {
    if (k < 0) {
      k = 9;
    }
    printf("%i", k);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printBits>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    $0x80000000,%ebx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L56:
  mov    $0x31,%edi
  shr    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  je     L72
L2:
  test   %ebx,%r12d
  jne    L56
  mov    $0x30,%edi
  shr    %ebx
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L2
L72:
  mov    $0xa,%edi
  mov    $0x20,%ebx
  lea    D7(%rip),%r12
  call   <putchar@plt>
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    -0x1(%rsi),%ebp
  call   <printf@plt>
  mov    %ebx,%eax
  sub    $0x1,%eax
  je     L87
  cmp    $0xffffffff,%ebp
  jne    L60
  xor    %eax,%eax
  mov    $0x9,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x2,%ebx
  je     L87
  mov    $0x8,%esi
  jmp    L73
  nopl   0x0(%rax)
L60:
  mov    %ebp,%esi
  mov    %eax,%ebx
  jmp    L73
  cs nopw 0x0(%rax,%rax,1)
L87:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: %i

assistant: ```c
void printBits(unsigned int bitmap) {
  unsigned i;
  int count = 0, j, k = 1;
  for (i = 1 << 31; i > 0; i = i / 2, count++) {
    (bitmap & i) ? printf("1") : printf("0");
  }
  printf("\n");
  for (j = 32; j > 0; j--, k--) {
    if (k < 0) {
      k = 9;
    }
    printf("%i", k);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addEntryName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L9
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L9:
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x5,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int addEntryName(char *output, char *name) {
  int q;
  for (q = 0; q < 6; q++) {
    if (name[q] != 0x00) {
      output[q] = name[q];
    } else {
      output[q] = ' ';
    }
  }
  return q;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addEntryName>:
  endbr64
  mov    $0x0,%eax
  mov    $0x20,%ecx
L7:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  cmove  %ecx,%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L7
  ret
```

assistant: ```c
int addEntryName(char *output, char *name) {
  int q;
  for (q = 0; q < 6; q++) {
    if (name[q] != 0x00) {
      output[q] = name[q];
    } else {
      output[q] = ' ';
    }
  }
  return q;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addEntryName>:
  endbr64
  xor    %eax,%eax
  mov    $0x20,%ecx
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  cmove  %ecx,%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L6
  ret
```

assistant: ```c
int addEntryName(char *output, char *name) {
  int q;
  for (q = 0; q < 6; q++) {
    if (name[q] != 0x00) {
      output[q] = name[q];
    } else {
      output[q] = ' ';
    }
  }
  return q;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<addEntryName>:
  endbr64
  movzbl (%rsi),%edx
  mov    $0x20,%eax
  test   %dl,%dl
  cmove  %eax,%edx
  mov    %dl,(%rdi)
  movzbl 0x1(%rsi),%edx
  test   %dl,%dl
  cmove  %eax,%edx
  mov    %dl,0x1(%rdi)
  movzbl 0x2(%rsi),%edx
  test   %dl,%dl
  cmove  %eax,%edx
  mov    %dl,0x2(%rdi)
  movzbl 0x3(%rsi),%edx
  test   %dl,%dl
  cmove  %eax,%edx
  mov    %dl,0x3(%rdi)
  movzbl 0x4(%rsi),%edx
  test   %dl,%dl
  cmove  %eax,%edx
  mov    %dl,0x4(%rdi)
  movzbl 0x5(%rsi),%edx
  test   %dl,%dl
  cmove  %eax,%edx
  mov    $0x6,%eax
  mov    %dl,0x5(%rdi)
  ret
```

assistant: ```c
int addEntryName(char *output, char *name) {
  int q;
  for (q = 0; q < 6; q++) {
    if (name[q] != 0x00) {
      output[q] = name[q];
    } else {
      output[q] = ' ';
    }
  }
  return q;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<displayBoard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movl   $0x0,-0x20(%rbp)
  jmp    L9
L34:
  movl   $0x0,-0x1c(%rbp)
  jmp    L0
L3:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x20(%rbp)
L9:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L34
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: %c 

assistant: ```c
void displayBoard(int s, char wordSearch[s][s]) {
  for (int i = 0; i < s; i++) {
    for (int j = 0; j < s; j++) {
      printf("%c ", wordSearch[i][j]);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<displayBoard>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movslq %edi,%rax
  mov    %rax,0x8(%rsp)
  test   %edi,%edi
  jle    L0
  mov    %edi,%r14d
  lea    -0x1(%rdi),%r15d
  lea    0x1(%rsi,%r15,1),%rbp
  mov    $0x0,%r13d
  lea    D9(%rip),%r12
L5:
  mov    %rbp,%rbx
  sub    %r15,%rbx
  sub    $0x1,%rbx
L10:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x8(%rsp),%rbp
  cmp    %r13d,%r14d
  jne    L5
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: %c 

assistant: ```c
void displayBoard(int s, char wordSearch[s][s]) {
  for (int i = 0; i < s; i++) {
    for (int j = 0; j < s; j++) {
      printf("%c ", wordSearch[i][j]);
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<displayBoard>:
  endbr64
  push   %r15
  movslq %edi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  test   %eax,%eax
  jle    L29
  lea    -0x1(%rax),%r14d
  mov    %rax,%r13
  xor    %r12d,%r12d
  lea    0x1(%rsi,%r14,1),%rbx
  lea    D9(%rip),%rbp
  nopl   0x0(%rax)
L2:
  mov    %rbx,%rdx
  sub    %r14,%rdx
  lea    -0x1(%rdx),%r15
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L10
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L2
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %c 

assistant: ```c
void displayBoard(int s, char wordSearch[s][s]) {
  for (int i = 0; i < s; i++) {
    for (int j = 0; j < s; j++) {
      printf("%c ", wordSearch[i][j]);
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<displayBoard>:
  endbr64
  push   %r15
  movslq %edi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  test   %eax,%eax
  jle    L0
  lea    -0x1(%rax),%r14d
  mov    %rax,%r13
  xor    %r12d,%r12d
  lea    0x1(%rsi,%r14,1),%rbx
  lea    D6(%rip),%rbp
  nopl   0x0(%rax)
L29:
  mov    %rbx,%rdx
  sub    %r14,%rdx
  lea    -0x1(%rdx),%r15
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%r15),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L18
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L29
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: %c 

assistant: ```c
void displayBoard(int s, char wordSearch[s][s]) {
  for (int i = 0; i < s; i++) {
    for (int j = 0; j < s; j++) {
      printf("%c ", wordSearch[i][j]);
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L22
L5:
  movq   $0x0,-0x18(%rbp)
  jmp    L23
L41:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x1c(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L60
  cmpl   $0xa,-0x1c(%rbp)
  je     L60
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L41
L60:
  cmpq   $0x0,-0x8(%rbp)
  jne    L62
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L22
L62:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
char *getstr() {
  int c;
  size_t n;
  char *s, *t;
  if (!(s = t = malloc(1)))
    return NULL;
  for (n = 0; (c = getchar()) != EOF && c - '\n' && (t = realloc(s, n + 2)); s[n++] = c)
    s = t;
  if (!t) {
    free(s);
    return NULL;
  }
  s[n] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L43
  mov    $0x0,%ebp
  jmp    L65
L41:
  mov    %bl,(%rax,%rbp,1)
  mov    %rax,%r12
  lea    0x1(%rbp),%rbp
L65:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  je     L25
  cmp    $0xa,%ebx
  je     L25
  lea    0x2(%rbp),%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  jne    L41
L50:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
  jmp    L43
L25:
  test   %r12,%r12
  je     L50
  movb   $0x0,(%r12,%rbp,1)
L43:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getstr() {
  int c;
  size_t n;
  char *s, *t;
  if (!(s = t = malloc(1)))
    return NULL;
  for (n = 0; (c = getchar()) != EOF && c - '\n' && (t = realloc(s, n + 2)); s[n++] = c)
    s = t;
  if (!t) {
    free(s);
    return NULL;
  }
  s[n] = '\0';
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getstr>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    D0(%rip),%r13
  xor    %ebp,%ebp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L39:
  cmp    $0xa,%eax
  je     L34
  lea    0x2(%rbp),%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L5
  mov    %bl,(%rax,%rbp,1)
  mov    %rax,%r12
  add    $0x1,%rbp
L29:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  jne    L39
L34:
  movb   $0x0,(%r12,%rbp,1)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *getstr() {
  int c;
  size_t n;
  char *s, *t;
  if (!(s = t = malloc(1)))
    return NULL;
  for (n = 0; (c = getchar()) != EOF && c - '\n' && (t = realloc(s, n + 2)); s[n++] = c)
    s = t;
  if (!t) {
    free(s);
    return NULL;
  }
  s[n] = '\0';
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getstr>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    D9(%rip),%r13
  xor    %ebp,%ebp
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    $0xa,%eax
  je     L0
  lea    0x2(%rbp),%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L9
  mov    %bl,(%rax,%rbp,1)
  mov    %rax,%r12
  add    $0x1,%rbp
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%r13)
  jne    L41
L0:
  movb   $0x0,(%r12,%rbp,1)
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *getstr() {
  int c;
  size_t n;
  char *s, *t;
  if (!(s = t = malloc(1)))
    return NULL;
  for (n = 0; (c = getchar()) != EOF && c - '\n' && (t = realloc(s, n + 2)); s[n++] = c)
    s = t;
  if (!t) {
    free(s);
    return NULL;
  }
  s[n] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_input@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <heap_sort@plt>
  cmpl   $0x0,-0x14(%rbp)
  jne    L3
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <set_output@plt>
  jmp    L5
L3:
  mov    -0x14(%rbp),%eax
L5:
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  int n = 0, *array;
  int err = get_input(&n, &array);
  heap_sort(array, n);
  err = !err ? set_output(&n, array) : err;
  free(array);
  return err;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <get_input@plt>
  mov    %eax,%ebx
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <heap_sort@plt>
  test   %ebx,%ebx
  je     L26
L17:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L26:
  lea    0xc(%rsp),%rdi
  mov    0x10(%rsp),%rsi
  call   <set_output@plt>
  mov    %eax,%ebx
  jmp    L17
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int n = 0, *array;
  int err = get_input(&n, &array);
  heap_sort(array, n);
  err = !err ? set_output(&n, array) : err;
  free(array);
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdi
  call   <get_input@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  mov    %eax,%r12d
  call   <heap_sort@plt>
  test   %r12d,%r12d
  je     L26
L27:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <set_output@plt>
  mov    %eax,%r12d
  jmp    L27
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int n = 0, *array;
  int err = get_input(&n, &array);
  heap_sort(array, n);
  err = !err ? set_output(&n, array) : err;
  free(array);
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%rdi
  call   <get_input@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  mov    %eax,%r12d
  call   <heap_sort@plt>
  test   %r12d,%r12d
  je     L5
L4:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <set_output@plt>
  mov    %eax,%r12d
  jmp    L4
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int n = 0, *array;
  int err = get_input(&n, &array);
  heap_sort(array, n);
  err = !err ? set_output(&n, array) : err;
  free(array);
  return err;
}
```
user: What is the c source code of the assembly code below?

```asm
<radixsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getmax@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <countsort@plt>
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  test   %eax,%eax
  jg     L12
  nop
  leave
  ret
```

assistant: ```c
radixsort(int a[], int n) {
  int i, exp = 1;
  int m = getmax(a, n);
  for (i = 0; m / exp > 0; exp = exp * 10) {
    countsort(a, n, exp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<radixsort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  call   <getmax@plt>
  test   %eax,%eax
  jle    L12
  mov    %eax,%ebp
  mov    $0x1,%ebx
L7:
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <countsort@plt>
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %eax,%eax
  jg     L7
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
radixsort(int a[], int n) {
  int i, exp = 1;
  int m = getmax(a, n);
  for (i = 0; m / exp > 0; exp = exp * 10) {
    countsort(a, n, exp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<radixsort>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getmax@plt>
  test   %eax,%eax
  jle    L14
  mov    %eax,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L0:
  mov    %ebx,%edx
  mov    %r13d,%esi
  lea    (%rbx,%rbx,4),%ebx
  mov    %r12,%rdi
  call   <countsort@plt>
  mov    %ebp,%eax
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  test   %eax,%eax
  jne    L0
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
radixsort(int a[], int n) {
  int i, exp = 1;
  int m = getmax(a, n);
  for (i = 0; m / exp > 0; exp = exp * 10) {
    countsort(a, n, exp);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<radixsort>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getmax@plt>
  test   %eax,%eax
  jle    L17
  mov    %eax,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L5:
  mov    %ebx,%edx
  mov    %r13d,%esi
  lea    (%rbx,%rbx,4),%ebx
  mov    %r12,%rdi
  call   <countsort@plt>
  mov    %ebp,%eax
  add    %ebx,%ebx
  cltd
  idiv   %ebx
  test   %eax,%eax
  jne    L5
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
radixsort(int a[], int n) {
  int i, exp = 1;
  int m = getmax(a, n);
  for (i = 0; m / exp > 0; exp = exp * 10) {
    countsort(a, n, exp);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<countSetBitsMethod1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L9:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int countSetBitsMethod1(int n) {
  unsigned int count = 0;
  while (n) {
    n &= (n - 1);
    count++;
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<countSetBitsMethod1>:
  endbr64
  test   %edi,%edi
  je     L22
  mov    $0x0,%edx
L19:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jne    L19
L0:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
unsigned int countSetBitsMethod1(int n) {
  unsigned int count = 0;
  while (n) {
    n &= (n - 1);
    count++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<countSetBitsMethod1>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L14
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L19
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int countSetBitsMethod1(int n) {
  unsigned int count = 0;
  while (n) {
    n &= (n - 1);
    count++;
  }
  return count;
}
```