ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0xd,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <serialport_read_until@plt>
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: read: %s


assistant: ```c
void read_line(int fd) {
  char buf[256];
  memset(buf, 0, 256);
  serialport_read_until(fd, buf, '\r');
  printf("read: %s\n", buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_line>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %edi,%r12d
  mov    $0x100,%edx
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    $0xd,%edx
  call   <serialport_read_until@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: read: %s


assistant: ```c
void read_line(int fd) {
  char buf[256];
  memset(buf, 0, 256);
  serialport_read_until(fd, buf, '\r');
  printf("read: %s\n", buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_line>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    %edi,%r12d
  mov    $0x100,%edx
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    $0xd,%edx
  call   <serialport_read_until@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: read: %s


assistant: ```c
void read_line(int fd) {
  char buf[256];
  memset(buf, 0, 256);
  serialport_read_until(fd, buf, '\r');
  printf("read: %s\n", buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<conv_d16_to_i32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x5c(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L19
L14:
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,%eax
  add    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  sar    $0x20,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x10,%rax
  mov    %eax,%eax
  add    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  sar    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  sar    $0x20,%rax
  add    %rdx,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  addl   $0x1,-0x34(%rbp)
L19:
  mov    -0x5c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jl     L14
  mov    -0x28(%rbp),%rax
  mov    %eax,%eax
  add    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  sar    $0x20,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x10,%rax
  mov    %eax,%eax
  add    %rax,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%rdx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void conv_d16_to_i32(unsigned int *i32, double *d16, long long *tmp, int ilen) {
  int i;
  long long t, t1, a, b, c, d;
  t1 = 0;
  a = (long long)d16[0];
  b = (long long)d16[1];
  for (i = 0; i < ilen - 1; i++) {
    c = (long long)d16[2 * i + 2];
    t1 += (unsigned int)a;
    t = (a >> 32);
    d = (long long)d16[2 * i + 3];
    t1 += (b & 0xffff) << 16;
    t += (b >> 16) + (t1 >> 32);
    i32[i] = (unsigned int)t1;
    t1 = t;
    a = c;
    b = d;
  }
  t1 += (unsigned int)a;
  t = (a >> 32);
  t1 += (b & 0xffff) << 16;
  i32[i] = (unsigned int)t1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<conv_d16_to_i32>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  cvttsd2si (%rsi),%r9
  cvttsd2si 0x8(%rsi),%r8
  cmp    $0x1,%ecx
  jle    L5
  mov    %ecx,%r11d
  lea    0x10(%rsi),%rcx
  lea    -0x2(%r11),%eax
  shl    $0x4,%rax
  lea    0x20(%rsi,%rax,1),%rbx
  mov    $0x0,%eax
L24:
  mov    %r9,%rdx
  cvttsd2si (%rcx),%r9
  mov    %edx,%esi
  add    %rax,%rsi
  sar    $0x20,%rdx
  mov    %rdx,%rbp
  mov    %r8,%rax
  cvttsd2si 0x8(%rcx),%r8
  mov    %rax,%rdx
  shl    $0x10,%rdx
  mov    %edx,%edx
  add    %rsi,%rdx
  sar    $0x10,%rax
  mov    %rdx,%rsi
  sar    $0x20,%rsi
  add    %rsi,%rax
  add    %rbp,%rax
  mov    %edx,(%rdi)
  add    $0x10,%rcx
  add    $0x4,%rdi
  cmp    %rbx,%rcx
  jne    L24
  sub    $0x1,%r11d
L0:
  mov    %r9d,%r9d
  add    %rax,%r9
  movslq %r11d,%r11
  shl    $0x10,%r8
  mov    %r8d,%r8d
  add    %r9,%r8
  mov    %r8d,(%r10,%r11,4)
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%eax
  mov    $0x0,%r11d
  jmp    L0
```

assistant: ```c
void conv_d16_to_i32(unsigned int *i32, double *d16, long long *tmp, int ilen) {
  int i;
  long long t, t1, a, b, c, d;
  t1 = 0;
  a = (long long)d16[0];
  b = (long long)d16[1];
  for (i = 0; i < ilen - 1; i++) {
    c = (long long)d16[2 * i + 2];
    t1 += (unsigned int)a;
    t = (a >> 32);
    d = (long long)d16[2 * i + 3];
    t1 += (b & 0xffff) << 16;
    t += (b >> 16) + (t1 >> 32);
    i32[i] = (unsigned int)t1;
    t1 = t;
    a = c;
    b = d;
  }
  t1 += (unsigned int)a;
  t = (a >> 32);
  t1 += (b & 0xffff) << 16;
  i32[i] = (unsigned int)t1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<conv_d16_to_i32>:
  endbr64
  push   %rbp
  mov    %rdi,%r11
  push   %rbx
  cvttsd2si (%rsi),%r10
  lea    -0x1(%rcx),%ebx
  cvttsd2si 0x8(%rsi),%r9
  test   %ebx,%ebx
  jle    L7
  lea    -0x2(%rcx),%eax
  lea    0x10(%rsi),%rdi
  mov    %r11,%r8
  shl    $0x4,%rax
  lea    0x20(%rsi,%rax,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  mov    %r10,%rdx
  cvttsd2si (%rdi),%r10
  add    $0x10,%rdi
  add    $0x4,%r8
  mov    %edx,%ecx
  sar    $0x20,%rdx
  add    %rax,%rcx
  mov    %r9,%rax
  mov    %rdx,%rbp
  mov    %rax,%rdx
  sar    $0x10,%rax
  cvttsd2si -0x8(%rdi),%r9
  shl    $0x10,%rdx
  mov    %edx,%edx
  add    %rcx,%rdx
  mov    %rdx,%rcx
  mov    %edx,-0x4(%r8)
  sar    $0x20,%rcx
  add    %rcx,%rax
  add    %rbp,%rax
  cmp    %rdi,%rsi
  jne    L1
  movslq %ebx,%rbx
  lea    (%r11,%rbx,4),%r11
L12:
  mov    %r10d,%r10d
  shl    $0x10,%r9
  pop    %rbx
  pop    %rbp
  add    %rax,%r10
  mov    %r9d,%r9d
  add    %r10,%r9
  mov    %r9d,(%r11)
  ret
L7:
  xor    %eax,%eax
  jmp    L12
```

assistant: ```c
void conv_d16_to_i32(unsigned int *i32, double *d16, long long *tmp, int ilen) {
  int i;
  long long t, t1, a, b, c, d;
  t1 = 0;
  a = (long long)d16[0];
  b = (long long)d16[1];
  for (i = 0; i < ilen - 1; i++) {
    c = (long long)d16[2 * i + 2];
    t1 += (unsigned int)a;
    t = (a >> 32);
    d = (long long)d16[2 * i + 3];
    t1 += (b & 0xffff) << 16;
    t += (b >> 16) + (t1 >> 32);
    i32[i] = (unsigned int)t1;
    t1 = t;
    a = c;
    b = d;
  }
  t1 += (unsigned int)a;
  t = (a >> 32);
  t1 += (b & 0xffff) << 16;
  i32[i] = (unsigned int)t1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<conv_d16_to_i32>:
  endbr64
  push   %rbp
  mov    %rdi,%r11
  push   %rbx
  cvttsd2si (%rsi),%r10
  lea    -0x1(%rcx),%ebx
  cvttsd2si 0x8(%rsi),%r9
  test   %ebx,%ebx
  jle    L24
  lea    -0x2(%rcx),%eax
  lea    0x10(%rsi),%rdi
  mov    %r11,%r8
  shl    $0x4,%rax
  lea    0x20(%rsi,%rax,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  mov    %r10,%rdx
  cvttsd2si (%rdi),%r10
  add    $0x10,%rdi
  add    $0x4,%r8
  mov    %edx,%ecx
  sar    $0x20,%rdx
  add    %rax,%rcx
  mov    %r9,%rax
  mov    %rdx,%rbp
  mov    %rax,%rdx
  sar    $0x10,%rax
  cvttsd2si -0x8(%rdi),%r9
  shl    $0x10,%rdx
  mov    %edx,%edx
  add    %rcx,%rdx
  mov    %rdx,%rcx
  mov    %edx,-0x4(%r8)
  sar    $0x20,%rcx
  add    %rcx,%rax
  add    %rbp,%rax
  cmp    %rdi,%rsi
  jne    L26
  movslq %ebx,%rbx
  lea    (%r11,%rbx,4),%r11
L13:
  mov    %r10d,%r10d
  shl    $0x10,%r9
  pop    %rbx
  pop    %rbp
  add    %rax,%r10
  mov    %r9d,%r9d
  add    %r10,%r9
  mov    %r9d,(%r11)
  ret
L24:
  xor    %eax,%eax
  jmp    L13
```

assistant: ```c
void conv_d16_to_i32(unsigned int *i32, double *d16, long long *tmp, int ilen) {
  int i;
  long long t, t1, a, b, c, d;
  t1 = 0;
  a = (long long)d16[0];
  b = (long long)d16[1];
  for (i = 0; i < ilen - 1; i++) {
    c = (long long)d16[2 * i + 2];
    t1 += (unsigned int)a;
    t = (a >> 32);
    d = (long long)d16[2 * i + 3];
    t1 += (b & 0xffff) << 16;
    t += (b >> 16) + (t1 >> 32);
    i32[i] = (unsigned int)t1;
    t1 = t;
    a = c;
    b = d;
  }
  t1 += (unsigned int)a;
  t = (a >> 32);
  t1 += (b & 0xffff) << 16;
  i32[i] = (unsigned int)t1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x740,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2738(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x0,-0x2734(%rbp)
  jmp    L30
L28:
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2728(%rbp)
  mov    -0x2728(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x2724(%rbp)
  mov    -0x2724(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x2728(%rbp)
  je     L54
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L25
L54:
  movl   $0x0,-0x2730(%rbp)
  jmp    L22
L18:
  mov    -0x2730(%rbp),%eax
  mov    %eax,-0x272c(%rbp)
  jmp    L75
L12:
  mov    -0x272c(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x2724(%rbp),%eax
  add    %eax,-0x272c(%rbp)
L75:
  mov    -0x272c(%rbp),%eax
  cmp    -0x2728(%rbp),%eax
  jl     L12
  addl   $0x1,-0x2730(%rbp)
L22:
  mov    -0x2730(%rbp),%eax
  cmp    -0x2724(%rbp),%eax
  jl     L18
  mov    $0xa,%edi
  call   <putchar@plt>
L25:
  addl   $0x1,-0x2734(%rbp)
L30:
  mov    -0x2738(%rbp),%eax
  cmp    %eax,-0x2734(%rbp)
  jl     L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D13
type: string

tool: D2: %d

tool: D13: INVALID

assistant: ```c
int main() {
  int t, i;
  char s[10005];
  scanf("%d", &t);
  getchar();
  for (i = 0; i < t; i++) {
    int j, len, root, k;
    gets(s);
    len = strlen(s);
    root = sqrt(len);
    if (root * root != len) {
      printf("INVALID\n");
      continue;
    }
    for (j = 0; j < root; j++) {
      for (k = j; k < len; k += root) {
        printf("%c", s[k]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x748,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2738(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L77
  movl   $0x0,0xc(%rsp)
  jmp    L33
L119:
  test   %eax,%eax
  jle    L107
  mov    %eax,%r15d
  mov    $0x0,%r14d
  movslq %eax,%r12
  jmp    L0
L97:
  movsbl (%rbx,%r13,1),%edi
  call   <putchar@plt>
  add    %r12,%rbx
  cmp    %ebx,%ebp
  jg     L97
L3:
  add    $0x1,%r14
  cmp    %r15,%r14
  je     L107
L0:
  mov    %r14,%rbx
  lea    0x20(%rsp),%r13
  cmp    %r14d,%ebp
  jg     L97
  jmp    L3
L107:
  mov    $0xa,%edi
  call   <putchar@plt>
L112:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jle    L77
L33:
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebp,%edx
  je     L119
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L112
L77:
  mov    0x2738(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x2748,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string

tool: D1: %d

tool: D16: INVALID

assistant: ```c
int main() {
  int t, i;
  char s[10005];
  scanf("%d", &t);
  getchar();
  for (i = 0; i < t; i++) {
    int j, len, root, k;
    gets(s);
    len = strlen(s);
    root = sqrt(len);
    if (root * root != len) {
      printf("INVALID\n");
      continue;
    }
    for (j = 0; j < root; j++) {
      for (k = j; k < len; k += root) {
        printf("%c", s[k]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L50
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r12
  jmp    L7
  xchg   %ax,%ax
L90:
  lea    D16(%rip),%rdi
  add    $0x1,%r14d
  call   <puts@plt>
  cmp    %r14d,0xc(%rsp)
  jle    L50
L7:
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebp,%edx
  jne    L90
  test   %eax,%eax
  jle    L59
  movslq %eax,%rbx
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r13,%r15
  cmp    %r13d,%ebp
  jle    L15
L11:
  movsbl (%r12,%r15,1),%edi
  add    %rbx,%r15
  call   <putchar@plt>
  cmp    %r15d,%ebp
  jg     L11
L15:
  add    $0x1,%r13
  cmp    %rbx,%r13
  jne    L20
L59:
  mov    $0xa,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  cmp    %r14d,0xc(%rsp)
  jg     L7
L50:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x2738,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string

tool: D18: %d

tool: D16: INVALID

assistant: ```c
int main() {
  int t, i;
  char s[10005];
  scanf("%d", &t);
  getchar();
  for (i = 0; i < t; i++) {
    int j, len, root, k;
    gets(s);
    len = strlen(s);
    root = sqrt(len);
    if (root * root != len) {
      printf("INVALID\n");
      continue;
    }
    for (j = 0; j < root; j++) {
      for (k = j; k < len; k += root) {
        printf("%c", s[k]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x748,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2738(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L50
  movl   $0x0,0xc(%rsp)
  lea    0x20(%rsp),%r12
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jle    L50
L54:
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <sqrt@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %ebp,%edx
  jne    L4
  test   %eax,%eax
  jle    L47
  test   %ebp,%ebp
  je     L47
  cmp    %eax,%ebp
  mov    %eax,%r14d
  movslq %eax,%rbx
  cmovle %ebp,%r14d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L63:
  mov    %r13,%r15
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl (%r12,%r15,1),%edi
  add    %rbx,%r15
  call   <putchar@plt>
  cmp    %r15d,%ebp
  jg     L28
  add    $0x1,%r13
  cmp    %r13d,%r14d
  jg     L63
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L54
L50:
  mov    0x2738(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x2748,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string

tool: D12: %d

tool: D18: INVALID

assistant: ```c
int main() {
  int t, i;
  char s[10005];
  scanf("%d", &t);
  getchar();
  for (i = 0; i < t; i++) {
    int j, len, root, k;
    gets(s);
    len = strlen(s);
    root = sqrt(len);
    if (root * root != len) {
      printf("INVALID\n");
      continue;
    }
    for (j = 0; j < root; j++) {
      for (k = j; k < len; k += root) {
        printf("%c", s[k]);
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ss>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D13(%rip),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L19
  mov    D29(%rip),%rax
  jmp    L13
L19:
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbx
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
L13:
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: byte[8]

tool: {"D11": [0x14,0xae,0x47,0xe1,0x9a,0x53,0xea,0x40]}

tool: D10: 230000

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x52,0x0c,0x41]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double ss(double Q2) {
  double a2 = 232.2 * 232.2;
  double mi2 = 230000;
  if (Q2 <= 232000)
    return 0;
  else
    return log(log(Q2 / a2) / log(mi2 / a2));
}
```
user: What is the c source code of the assembly code below?

```asm
<ss>:
  endbr64
  movsd  D20(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L6
  pxor   %xmm0,%xmm0
  ret
L6:
  sub    $0x8,%rsp
  divsd  D25(%rip),%xmm0
  call   <log@plt>
  divsd  D8(%rip),%xmm0
  call   <log@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
type: byte[8]
name: retrieve_data
arguments: tag: D25
type: byte[8]
name: retrieve_data
arguments: tag: D8
type: byte[8]

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x52,0x0c,0x41]}

tool: {"D25": [0x14,0xae,0x47,0xe1,0x9a,0x53,0xea,0x40]}

tool: {"D8": [0x6f,0x68,0xc7,0x90,0xce,0x35,0xf7,0x3f]}

assistant: ```c
double ss(double Q2) {
  double a2 = 232.2 * 232.2;
  double mi2 = 230000;
  if (Q2 <= 232000)
    return 0;
  else
    return log(log(Q2 / a2) / log(mi2 / a2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ss>:
  endbr64
  movsd  D25(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L8
  pxor   %xmm0,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  sub    $0x8,%rsp
  divsd  D17(%rip),%xmm0
  call   <log@plt>
  divsd  D5(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1050 <log@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: byte[8]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x52,0x0c,0x41]}

tool: {"D17": [0x14,0xae,0x47,0xe1,0x9a,0x53,0xea,0x40]}

tool: {"D5": [0x6f,0x68,0xc7,0x90,0xce,0x35,0xf7,0x3f]}

assistant: ```c
double ss(double Q2) {
  double a2 = 232.2 * 232.2;
  double mi2 = 230000;
  if (Q2 <= 232000)
    return 0;
  else
    return log(log(Q2 / a2) / log(mi2 / a2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ss>:
  endbr64
  movsd  D3(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L5
  pxor   %xmm0,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  divsd  D18(%rip),%xmm0
  call   <log@plt>
  divsd  D16(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1050 <log@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: byte[8]
name: unpack_data
arguments: data_tag: D18
datatype: byte[8]
name: unpack_data
arguments: data_tag: D16
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x52,0x0c,0x41]}

tool: {"D18": [0x14,0xae,0x47,0xe1,0x9a,0x53,0xea,0x40]}

tool: {"D16": [0x6f,0x68,0xc7,0x90,0xce,0x35,0xf7,0x3f]}

assistant: ```c
double ss(double Q2) {
  double a2 = 232.2 * 232.2;
  double mi2 = 230000;
  if (Q2 <= 232000)
    return 0;
  else
    return log(log(Q2 / a2) / log(mi2 / a2));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  add    $0x5,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  c = a * b + 5;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  c = a * b + 5;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  c = a * b + 5;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int b;
  int c;
  c = a * b + 5;
  return c;
}
```