ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPermissible>:
  endbr64
  mov    %esi,%ecx
  or     %edx,%ecx
  mov    $0x0,%eax
  cmp    $0x7,%ecx
  jbe    L18
L3:
  ret
L18:
  movslq %esi,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rdi
  movslq %edx,%rdx
  cmpl   $0x0,(%rdi,%rdx,4)
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

assistant: ```c
int isPermissible(int board[8][8], int row, int col) {
  if (row < 0 || row >= 8 || col < 0 || col >= 8) {
    return 0;
  }
  if (board[row][col] != 0) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPermissible>:
  endbr64
  mov    %esi,%ecx
  xor    %eax,%eax
  or     %edx,%ecx
  cmp    $0x7,%ecx
  jbe    L3
  ret
L3:
  movslq %esi,%rsi
  movslq %edx,%rdx
  xor    %eax,%eax
  shl    $0x5,%rsi
  add    %rsi,%rdi
  mov    (%rdi,%rdx,4),%edx
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int col) {
  if (row < 0 || row >= 8 || col < 0 || col >= 8) {
    return 0;
  }
  if (board[row][col] != 0) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPermissible>:
  endbr64
  mov    %esi,%ecx
  xor    %eax,%eax
  or     %edx,%ecx
  cmp    $0x7,%ecx
  jbe    L9
  ret
L9:
  movslq %esi,%rsi
  movslq %edx,%rdx
  xor    %eax,%eax
  shl    $0x5,%rsi
  add    %rsi,%rdi
  mov    (%rdi,%rdx,4),%edx
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int isPermissible(int board[8][8], int row, int col) {
  if (row < 0 || row >= 8 || col < 0 || col >= 8) {
    return 0;
  }
  if (board[row][col] != 0) {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<shuffle_classes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <my_calloc@plt>
  mov    %rax,%r12
  mov    $0x2,%eax
  test   %r12,%r12
  je     L88
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <my_calloc@plt>
  mov    %rax,%r15
  mov    $0x2,%eax
  test   %r15,%r15
  je     L88
  test   %r13d,%r13d
  jle    L64
  mov    $0x0,%ebp
  lea    -0x1(%rbx),%r14d
L32:
  mov    %r14d,%edi
  call   <random_long@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L32
L64:
  test   %ebx,%ebx
  jle    L14
  mov    %r12,%r14
  mov    %ebx,%eax
  lea    (%r12,%rax,4),%rdx
  mov    %r12,%rax
L11:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L60
L22:
  lea    0x1(%rax),%edx
  cmp    %ebx,%edx
  mov    %edx,%eax
  cmovge %ebp,%eax
L78:
  movslq %eax,%rdx
  lea    (%r12,%rdx,4),%rdx
  cmpl   $0xffffffff,(%rdx)
  jne    L22
  mov    %r13d,(%rdx)
  lea    0x1(%r13),%eax
  cmp    %eax,%ebx
  je     L72
  mov    %eax,%r13d
L60:
  lea    -0x1(%rbx),%edi
  call   <random_long@plt>
  jmp    L78
L72:
  mov    $0x0,%eax
L30:
  movslq (%r14),%rdx
  mov    %eax,(%r15,%rdx,4)
  mov    %eax,%edx
  add    $0x1,%eax
  add    $0x4,%r14
  cmp    %edx,%r13d
  jne    L30
L14:
  mov    (%rsp),%rax
  mov    %r12,(%rax)
  mov    0x8(%rsp),%rax
  mov    %r15,(%rax)
  mov    $0x0,%eax
L88:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int shuffle_classes(int a_seed, int a_num_classes, int **a_table, int **inverted_table) {
  int the_error = 0;
  int *t, *inv_t;
  int i, j;
  t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (t == NULL)
    return 2;
  inv_t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (inv_t == NULL)
    return 2;
  for (i = 0; i < a_seed; i++)
    j = random_long(a_num_classes - 1);
  for (i = 0; i < a_num_classes; i++)
    t[i] = -1;
  for (i = 0; i < a_num_classes; i++) {
    j = random_long(a_num_classes - 1);
    while (t[j] != -1)
      if (j + 1 < a_num_classes)
        j += 1;
      else
        j = 0;
    t[j] = i;
  }
  for (i = 0; i < a_num_classes; i++)
    inv_t[t[i]] = i;
  *a_table = t;
  *inverted_table = inv_t;
  return the_error;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shuffle_classes>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  mov    $0x4,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r14d,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <my_calloc@plt>
  test   %rax,%rax
  je     L22
  mov    $0x4,%esi
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <my_calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L22
  lea    -0x1(%r14),%r15d
  xor    %r13d,%r13d
  test   %ebp,%ebp
  jle    L83
  nopl   (%rax)
L16:
  mov    %r15d,%edi
  add    $0x1,%r13d
  call   <random_long@plt>
  cmp    %r13d,%ebp
  jne    L16
L83:
  test   %r14d,%r14d
  jle    L10
  movslq %r14d,%rdx
  mov    $0xff,%esi
  mov    %r12,%rdi
  xor    %r15d,%r15d
  shl    $0x2,%rdx
  lea    -0x1(%r14),%ebp
  call   <memset@plt>
  nopl   0x0(%rax)
L32:
  mov    %ebp,%edi
  call   <random_long@plt>
  jmp    L91
  nopl   0x0(%rax)
L81:
  lea    0x1(%rax),%edx
  xor    %eax,%eax
  cmp    %r14d,%edx
  cmovl  %edx,%eax
L91:
  movslq %eax,%rdx
  lea    (%r12,%rdx,4),%rdx
  cmpl   $0xffffffff,(%rdx)
  jne    L81
  lea    0x1(%r15),%eax
  mov    %r15d,(%rdx)
  cmp    %eax,%r14d
  je     L27
  mov    %eax,%r15d
  jmp    L32
L27:
  mov    %r12,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L80:
  movslq (%rdx),%rsi
  add    $0x4,%rdx
  mov    %eax,(%rbx,%rsi,4)
  mov    %eax,%esi
  add    $0x1,%eax
  cmp    %esi,%r15d
  jne    L80
L10:
  mov    (%rsp),%rax
  mov    %r12,(%rax)
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  add    $0x18,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int shuffle_classes(int a_seed, int a_num_classes, int **a_table, int **inverted_table) {
  int the_error = 0;
  int *t, *inv_t;
  int i, j;
  t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (t == NULL)
    return 2;
  inv_t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (inv_t == NULL)
    return 2;
  for (i = 0; i < a_seed; i++)
    j = random_long(a_num_classes - 1);
  for (i = 0; i < a_num_classes; i++)
    t[i] = -1;
  for (i = 0; i < a_num_classes; i++) {
    j = random_long(a_num_classes - 1);
    while (t[j] != -1)
      if (j + 1 < a_num_classes)
        j += 1;
      else
        j = 0;
    t[j] = i;
  }
  for (i = 0; i < a_num_classes; i++)
    inv_t[t[i]] = i;
  *a_table = t;
  *inverted_table = inv_t;
  return the_error;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shuffle_classes>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  mov    $0x4,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r14d,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <my_calloc@plt>
  test   %rax,%rax
  je     L76
  mov    $0x4,%esi
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <my_calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L76
  lea    -0x1(%r14),%r15d
  xor    %r13d,%r13d
  test   %ebp,%ebp
  jle    L10
  nopl   (%rax)
L16:
  mov    %r15d,%edi
  add    $0x1,%r13d
  call   <random_long@plt>
  cmp    %r13d,%ebp
  jne    L16
L10:
  test   %r14d,%r14d
  jle    L55
  movslq %r14d,%rdx
  mov    $0xff,%esi
  mov    %r12,%rdi
  xor    %r15d,%r15d
  shl    $0x2,%rdx
  lea    -0x1(%r14),%ebp
  call   <memset@plt>
  nopl   0x0(%rax)
L81:
  mov    %ebp,%edi
  call   <random_long@plt>
  jmp    L40
  nopl   0x0(%rax)
L27:
  lea    0x1(%rax),%edx
  xor    %eax,%eax
  cmp    %r14d,%edx
  cmovl  %edx,%eax
L40:
  movslq %eax,%rdx
  lea    (%r12,%rdx,4),%rdx
  cmpl   $0xffffffff,(%rdx)
  jne    L27
  lea    0x1(%r15),%eax
  mov    %r15d,(%rdx)
  cmp    %eax,%r14d
  je     L22
  mov    %eax,%r15d
  jmp    L81
L22:
  mov    %r12,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L34:
  movslq (%rdx),%rsi
  add    $0x4,%rdx
  mov    %eax,(%rbx,%rsi,4)
  mov    %eax,%esi
  add    $0x1,%eax
  cmp    %esi,%r15d
  jne    L34
L55:
  mov    (%rsp),%rax
  mov    %r12,(%rax)
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  add    $0x18,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int shuffle_classes(int a_seed, int a_num_classes, int **a_table, int **inverted_table) {
  int the_error = 0;
  int *t, *inv_t;
  int i, j;
  t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (t == NULL)
    return 2;
  inv_t = (int *)my_calloc((a_num_classes), sizeof(int));
  if (inv_t == NULL)
    return 2;
  for (i = 0; i < a_seed; i++)
    j = random_long(a_num_classes - 1);
  for (i = 0; i < a_num_classes; i++)
    t[i] = -1;
  for (i = 0; i < a_num_classes; i++) {
    j = random_long(a_num_classes - 1);
    while (t[j] != -1)
      if (j + 1 < a_num_classes)
        j += 1;
      else
        j = 0;
    t[j] = i;
  }
  for (i = 0; i < a_num_classes; i++)
    inv_t[t[i]] = i;
  *a_table = t;
  *inverted_table = inv_t;
  return the_error;
}
```
user: Translate the below assembly code into C programming language:

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <error_exit@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *safe_malloc(size_t size, char *error_message) {
  void *result = malloc(size);
  if (!result)
    error_exit(errno, error_message);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <error_exit@plt>
  jmp    L12
```

assistant: ```c
void *safe_malloc(size_t size, char *error_message) {
  void *result = malloc(size);
  if (!result)
    error_exit(errno, error_message);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<safe_malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    D6(%rip),%rax
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <error_exit@plt>
  jmp    L19
```

assistant: ```c
void *safe_malloc(size_t size, char *error_message) {
  void *result = malloc(size);
  if (!result)
    error_exit(errno, error_message);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    D3(%rip),%rax
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <error_exit@plt>
  jmp    L6
```

assistant: ```c
void *safe_malloc(size_t size, char *error_message) {
  void *result = malloc(size);
  if (!result)
    error_exit(errno, error_message);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L66
L43:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L57:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L39
  mov    -0x4(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L39
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L39
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L39:
  mov    -0x4(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L16:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L57
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x8(%rbp)
L66:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L43
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D34
data_type: string
name: extract_symbolic_data
arguments: label: D45
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D39
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D34: %s = [...


tool: D45:          0

tool: D6:   % 9.4f

tool: D39: ,

tool: D4: ];

assistant: ```c
void printmatrix(char *name, double *A, int m, int n, int sparse) {
  int i, j;
  printf("%s = [...\n", name);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      if ((sparse == 1) && (A[i + j * m] == 0))
        printf("         0");
      else
        printf("  % 9.4f", A[i + j * m]);
    printf(",\n");
  }
  printf("];\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,0x8(%rsp)
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  lea    D8(%rip),%r15
  test   %ebx,%ebx
  jg     L88
L0:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  movslq %ebx,%rax
  movsd  (%r12,%rax,8),%xmm0
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L81:
  add    $0x1,%ebp
  add    0x8(%rsp),%ebx
  cmp    %ebp,%r13d
  je     L56
L50:
  cmp    $0x1,%r14d
  jne    L40
  movslq %ebx,%rax
  pxor   %xmm1,%xmm1
  ucomisd (%r12,%rax,8),%xmm1
  jp     L40
  jne    L40
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L81
L56:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  je     L0
L88:
  mov    0xc(%rsp),%ebx
  mov    $0x0,%ebp
  test   %r13d,%r13d
  jg     L50
  jmp    L56
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D32
type_guessed: string
name: parse_data
arguments: tag: D40
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string

tool: D3: %s = [...


tool: D8:   % 9.4f

tool: D32: ];

tool: D40:          0

tool: D38: ,

assistant: ```c
void printmatrix(char *name, double *A, int m, int n, int sparse) {
  int i, j;
  printf("%s = [...\n", name);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      if ((sparse == 1) && (A[i + j * m] == 0))
        printf("         0");
      else
        printf("  % 9.4f", A[i + j * m]);
    printf(",\n");
  }
  printf("];\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printmatrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L83
  movslq %r12d,%rax
  lea    D46(%rip),%r13
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  lea    0x0(,%rax,8),%r12
  nopl   0x0(%rax)
L32:
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  xor    %r15d,%r15d
  lea    (%rax,%rcx,8),%r14
  test   %ebx,%ebx
  jg     L1
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15d
  add    %r12,%r14
  call   <printf@plt>
  cmp    %r15d,%ebx
  je     L21
L1:
  movsd  (%r14),%xmm0
  cmp    $0x1,%ebp
  jne    L65
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L65
  jne    L65
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r15d
  add    %r12,%r14
  call   <printf@plt>
  cmp    %r15d,%ebx
  jne    L1
  nopl   0x0(%rax)
L21:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L32
L83:
  add    $0x28,%rsp
  lea    D13(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D46
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D28
type: string
name: parse_data
arguments: data_tag: D13
type: string

tool: D4: %s = [...


tool: D46:   % 9.4f

tool: D15:          0

tool: D28: ,

tool: D13: ];

assistant: ```c
void printmatrix(char *name, double *A, int m, int n, int sparse) {
  int i, j;
  printf("%s = [...\n", name);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      if ((sparse == 1) && (A[i + j * m] == 0))
        printf("         0");
      else
        printf("  % 9.4f", A[i + j * m]);
    printf(",\n");
  }
  printf("];\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printmatrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  lea    D30(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %edx,0x8(%rsp)
  mov    %r8d,0xc(%rsp)
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L89
  mov    %r13,(%rsp)
  movslq %r14d,%rbp
  lea    D38(%rip),%r12
  xor    %r14d,%r14d
  shl    $0x3,%rbp
  xchg   %ax,%ax
L97:
  test   %ebx,%ebx
  jle    L24
  cmpl   $0x1,0xc(%rsp)
  je     L25
  mov    (%rsp),%r15
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L78:
  movsd  (%r15),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%r13d
  add    %rbp,%r15
  call   <printf@plt>
  cmp    %ebx,%r13d
  jne    L78
L24:
  lea    D25(%rip),%rdi
  add    $0x1,%r14d
  call   <puts@plt>
  addq   $0x8,(%rsp)
  cmp    %r14d,0x8(%rsp)
  jne    L97
L89:
  add    $0x18,%rsp
  lea    D35(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L25:
  mov    (%rsp),%r13
  xor    %r15d,%r15d
  jmp    L5
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L51:
  add    $0x1,%r15d
  add    %rbp,%r13
  cmp    %r15d,%ebx
  je     L24
L5:
  movsd  0x0(%r13),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L23
  jne    L23
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L51
```

tool_calls: name: parse_data
arguments: tag: D30
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string
name: parse_data
arguments: tag: D49
type_guessed: string

tool: D30: %s = [...


tool: D38:   % 9.4f

tool: D25: ,

tool: D35: ];

tool: D49:          0

assistant: ```c
void printmatrix(char *name, double *A, int m, int n, int sparse) {
  int i, j;
  printf("%s = [...\n", name);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      if ((sparse == 1) && (A[i + j * m] == 0))
        printf("         0");
      else
        printf("  % 9.4f", A[i + j * m]);
    printf(",\n");
  }
  printf("];\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Cyc_Position_segment_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L30
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  jmp    L38
L30:
  nop
  cmpl   $0x0,-0x18(%rbp)
  jne    L17
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  jmp    L38
L17:
  nop
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
unsigned Cyc_Position_segment_join(unsigned s1, unsigned s2) {
  unsigned _T0;
  unsigned _T1;
  unsigned _T2;
  if (s1 != 0U)
    goto _TL0;
  _T0 = s2;
  return _T0;
_TL0:
  if (s2 != 0U)
    goto _TL2;
  _T1 = s1;
  return _T1;
_TL2:
  _T2 = s1;
  return _T2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Cyc_Position_segment_join>:
  endbr64
  test   %edi,%edi
  mov    %edi,%eax
  cmove  %esi,%eax
  ret
```

assistant: ```c
unsigned Cyc_Position_segment_join(unsigned s1, unsigned s2) {
  unsigned _T0;
  unsigned _T1;
  unsigned _T2;
  if (s1 != 0U)
    goto _TL0;
  _T0 = s2;
  return _T0;
_TL0:
  if (s2 != 0U)
    goto _TL2;
  _T1 = s1;
  return _T1;
_TL2:
  _T2 = s1;
  return _T2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_Position_segment_join>:
  endbr64
  test   %edi,%edi
  mov    %edi,%eax
  cmove  %esi,%eax
  ret
```

assistant: ```c
unsigned Cyc_Position_segment_join(unsigned s1, unsigned s2) {
  unsigned _T0;
  unsigned _T1;
  unsigned _T2;
  if (s1 != 0U)
    goto _TL0;
  _T0 = s2;
  return _T0;
_TL0:
  if (s2 != 0U)
    goto _TL2;
  _T1 = s1;
  return _T1;
_TL2:
  _T2 = s1;
  return _T2;
}
```
user: What is the c source code of the assembly code below?

```asm
<memfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void memfree(void *heap, void *ptr) {
  (void)heap;
  free(ptr);
}
```
user: What is the c source code of the assembly code below?

```asm
<memfree>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void memfree(void *heap, void *ptr) {
  (void)heap;
  free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memfree>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void memfree(void *heap, void *ptr) {
  (void)heap;
  free(ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memfree>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void memfree(void *heap, void *ptr) {
  (void)heap;
  free(ptr);
}
```