ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yyerror>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: %s 

assistant: ```c
void yyerror(char *fmt, ...) {
  va_list ap;
  char msg[128];
  va_start(ap, fmt);
  vsprintf(msg, fmt, ap);
  va_end(ap);
  printf("%s ", msg);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lk_hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <lk_hlist_unhashed@plt>
  test   %eax,%eax
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__lk_hlist_del@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <INIT_LK_HLIST_NODE@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void lk_hlist_del_init(struct lk_hlist_node *n) {
  if (!lk_hlist_unhashed(n)) {
    __lk_hlist_del(n);
    INIT_LK_HLIST_NODE(n);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lk_hlist_del_init>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <lk_hlist_unhashed@plt>
  test   %eax,%eax
  je     L13
L19:
  pop    %rbx
  ret
L13:
  mov    %rbx,%rdi
  call   <__lk_hlist_del@plt>
  mov    %rbx,%rdi
  call   <INIT_LK_HLIST_NODE@plt>
  jmp    L19
```

assistant: ```c
void lk_hlist_del_init(struct lk_hlist_node *n) {
  if (!lk_hlist_unhashed(n)) {
    __lk_hlist_del(n);
    INIT_LK_HLIST_NODE(n);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lk_hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <lk_hlist_unhashed@plt>
  test   %eax,%eax
  je     L2
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <__lk_hlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <INIT_LK_HLIST_NODE@plt>
```

assistant: ```c
void lk_hlist_del_init(struct lk_hlist_node *n) {
  if (!lk_hlist_unhashed(n)) {
    __lk_hlist_del(n);
    INIT_LK_HLIST_NODE(n);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<lk_hlist_del_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <lk_hlist_unhashed@plt>
  test   %eax,%eax
  je     L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <__lk_hlist_del@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <INIT_LK_HLIST_NODE@plt>
```

assistant: ```c
void lk_hlist_del_init(struct lk_hlist_node *n) {
  if (!lk_hlist_unhashed(n)) {
    __lk_hlist_del(n);
    INIT_LK_HLIST_NODE(n);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<outer_connect_failed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <msglog@plt>
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <stop_session@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: [%i.?] <connect failed>


assistant: ```c
int outer_connect_failed(int sesno, struct pollfd *in_fd, struct pollfd *out_fd, struct _session *sess) {
  msglog(1, "[%i.?] <connect failed>\n", sesno);
  return stop_session(sesno, in_fd, out_fd, sess);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outer_connect_failed>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %edi,%edx
  lea    D8(%rip),%rsi
  mov    $0x1,%edi
  call   <msglog@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <stop_session@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: [%i.?] <connect failed>


assistant: ```c
int outer_connect_failed(int sesno, struct pollfd *in_fd, struct pollfd *out_fd, struct _session *sess) {
  msglog(1, "[%i.?] <connect failed>\n", sesno);
  return stop_session(sesno, in_fd, out_fd, sess);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<outer_connect_failed>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %edi,%edx
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <msglog@plt>
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <stop_session@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: [%i.?] <connect failed>


assistant: ```c
int outer_connect_failed(int sesno, struct pollfd *in_fd, struct pollfd *out_fd, struct _session *sess) {
  msglog(1, "[%i.?] <connect failed>\n", sesno);
  return stop_session(sesno, in_fd, out_fd, sess);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<outer_connect_failed>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %edi,%edx
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <msglog@plt>
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <stop_session@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: [%i.?] <connect failed>


assistant: ```c
int outer_connect_failed(int sesno, struct pollfd *in_fd, struct pollfd *out_fd, struct _session *sess) {
  msglog(1, "[%i.?] <connect failed>\n", sesno);
  return stop_session(sesno, in_fd, out_fd, sess);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   1070 <sys$testcode@plt>
  mov    $0x0,%eax
  call   1060 <sys$testcode2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  sys$testcode();
  sys$testcode2();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   1070 <sys$testcode@plt>
  mov    $0x0,%eax
  call   1060 <sys$testcode2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  sys$testcode();
  sys$testcode2();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   1070 <sys$testcode@plt>
  xor    %eax,%eax
  call   1060 <sys$testcode2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  sys$testcode();
  sys$testcode2();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   1070 <sys$testcode@plt>
  xor    %eax,%eax
  call   1060 <sys$testcode2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  sys$testcode();
  sys$testcode2();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
L45:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L11
  mov    $0x0,%eax
  call   <rand@plt>
  and    $0x64,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L24
L0:
  jmp    L45
L4:
  nop
L24:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_guessed: string
name: parse_data
arguments: data_label: D49
type_guessed: string
name: parse_data
arguments: data_label: D33
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D42
type_guessed: string

tool: D14: 
	Greatest common divisor program


tool: D49: So let's say we have 2 numbers..

tool: D33: 	%d  and  %d


tool: D28: Their greatest common divisor would be...

tool: D42: 	    %d



assistant: ```c
int main(void) {
  srand((unsigned)time(NULL));
  int nr1 = rand() % 100;
  int nr2 = rand() % 100;
  int temp;
  while (1) {
    if (nr1 == nr2) {
      nr2 = rand() & 100;
      continue;
    } else if (nr2 > nr1) {
      temp = nr2;
      nr2 = nr1;
      nr1 = temp;
      break;
    } else
      break;
  }
  puts("\n\tGreatest common divisor program\n");
  puts("So let's say we have 2 numbers..");
  printf("\t%d  and  %d\n", nr1, nr2);
  puts("Their greatest common divisor would be...");
  printf("\t    %d\n\n", gcd(nr1, nr2));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  cltd
  sub    %edx,%ebp
  imul   $0x64,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbx
  imul   $0x51eb851f,%rbx,%rbx
  sar    $0x25,%rbx
  cltd
  sub    %edx,%ebx
  imul   $0x64,%ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  cmp    %eax,%ebp
  je     L33
L10:
  cmp    %ebx,%ebp
  jge    L20
  mov    %ebp,%eax
  mov    %ebx,%ebp
  mov    %eax,%ebx
L20:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  mov    $0x0,%eax
  call   <rand@plt>
  and    $0x64,%eax
  mov    %eax,%ebx
  cmp    %eax,%ebp
  jne    L10
  jmp    L33
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D24
type_guessed: string
name: parse_data
arguments: data_tag: D45
type_guessed: string
name: parse_data
arguments: data_tag: D35
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string

tool: D11: 
	Greatest common divisor program


tool: D24: So let's say we have 2 numbers..

tool: D45: 	%d  and  %d


tool: D35: Their greatest common divisor would be...

tool: D13: 	    %d



assistant: ```c
int main(void) {
  srand((unsigned)time(NULL));
  int nr1 = rand() % 100;
  int nr2 = rand() % 100;
  int temp;
  while (1) {
    if (nr1 == nr2) {
      nr2 = rand() & 100;
      continue;
    } else if (nr2 > nr1) {
      temp = nr2;
      nr2 = nr1;
      nr1 = temp;
      break;
    } else
      break;
  }
  puts("\n\tGreatest common divisor program\n");
  puts("So let's say we have 2 numbers..");
  printf("\t%d  and  %d\n", nr1, nr2);
  puts("Their greatest common divisor would be...");
  printf("\t    %d\n\n", gcd(nr1, nr2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%r12
  cltd
  imul   $0x51eb851f,%r12,%r12
  sar    $0x25,%r12
  sub    %edx,%r12d
  imul   $0x64,%r12d,%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  cltd
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  sub    %edx,%ebp
  imul   $0x64,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  cmp    %eax,%r12d
  je     L38
L10:
  cmp    %ebp,%r12d
  jge    L21
  xchg   %ebp,%r12d
L21:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <gcd@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L38:
  xor    %eax,%eax
  call   <rand@plt>
  and    $0x64,%eax
  mov    %eax,%ebp
  cmp    %eax,%r12d
  jne    L10
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D49
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D29
type_infered: string

tool: D14: 
	Greatest common divisor program


tool: D49: So let's say we have 2 numbers..

tool: D36: 	%d  and  %d


tool: D1: Their greatest common divisor would be...

tool: D29: 	    %d



assistant: ```c
int main(void) {
  srand((unsigned)time(NULL));
  int nr1 = rand() % 100;
  int nr2 = rand() % 100;
  int temp;
  while (1) {
    if (nr1 == nr2) {
      nr2 = rand() & 100;
      continue;
    } else if (nr2 > nr1) {
      temp = nr2;
      nr2 = nr1;
      nr1 = temp;
      break;
    } else
      break;
  }
  puts("\n\tGreatest common divisor program\n");
  puts("So let's say we have 2 numbers..");
  printf("\t%d  and  %d\n", nr1, nr2);
  puts("Their greatest common divisor would be...");
  printf("\t    %d\n\n", gcd(nr1, nr2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%r12
  cltd
  imul   $0x51eb851f,%r12,%r12
  sar    $0x25,%r12
  sub    %edx,%r12d
  imul   $0x64,%r12d,%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rbp
  cltd
  imul   $0x51eb851f,%rbp,%rbp
  sar    $0x25,%rbp
  sub    %edx,%ebp
  imul   $0x64,%ebp,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  cmp    %eax,%r12d
  je     L21
L32:
  cmp    %ebp,%r12d
  jge    L1
  xchg   %ebp,%r12d
L1:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <gcd@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L21:
  xor    %eax,%eax
  call   <rand@plt>
  and    $0x64,%eax
  mov    %eax,%ebp
  cmp    %eax,%r12d
  jne    L32
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D36
data_type: string
name: disassemble_data
arguments: data_label: D38
data_type: string
name: disassemble_data
arguments: data_label: D47
data_type: string
name: disassemble_data
arguments: data_label: D33
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string

tool: D36: 
	Greatest common divisor program


tool: D38: So let's say we have 2 numbers..

tool: D47: 	%d  and  %d


tool: D33: Their greatest common divisor would be...

tool: D10: 	    %d



assistant: ```c
int main(void) {
  srand((unsigned)time(NULL));
  int nr1 = rand() % 100;
  int nr2 = rand() % 100;
  int temp;
  while (1) {
    if (nr1 == nr2) {
      nr2 = rand() & 100;
      continue;
    } else if (nr2 > nr1) {
      temp = nr2;
      nr2 = nr1;
      nr1 = temp;
      break;
    } else
      break;
  }
  puts("\n\tGreatest common divisor program\n");
  puts("So let's say we have 2 numbers..");
  printf("\t%d  and  %d\n", nr1, nr2);
  puts("Their greatest common divisor would be...");
  printf("\t    %d\n\n", gcd(nr1, nr2));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L4:
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x2,-0xc(%rbp)
  jle    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D6: signbit

tool: D21: # c::%s


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "signbit");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D17(%rip),%r13
  lea    D13(%rip),%r12
  lea    D4(%rip),%rbp
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string

tool: D17: signbit

tool: D13: # c::%s


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "signbit");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D17(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L6
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D17: signbit

tool: D2: # c::%s


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "signbit");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D19(%rip),%r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L8
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D29
type_guessed: string

tool: D19: signbit

tool: D27: # c::%s


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "signbit");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<fstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fstat(int _fd, struct stat *_sbuf) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fstat>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fstat(int _fd, struct stat *_sbuf) {
  errno = ENOSYS;
  return -1;
}
```