ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compareStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L64:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L26
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L34
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L20
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L66
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L66:
  movl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compareStr(const char s1[], const char s2[]) {
  int i = 0, answer;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0')
    ++i;
  if (s1[i] < s2[i])
    answer = -1;
  else if (s1[i] == s2[i])
    answer = 0;
  else
    answer = 1;
  return answer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compareStr>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  test   %dl,%dl
  setne  %r8b
  cmp    %cl,%dl
  sete   %al
  test   %al,%r8b
  je     L20
  test   %cl,%cl
  je     L20
  mov    $0x1,%eax
L5:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  setne  %r9b
  cmp    %cl,%dl
  sete   %r8b
  test   %r8b,%r9b
  je     L20
  test   %cl,%cl
  jne    L5
L20:
  mov    $0xffffffff,%eax
  cmp    %cl,%dl
  jl     L15
  setne  %al
  movzbl %al,%eax
L15:
  ret
```

assistant: ```c
int compareStr(const char s1[], const char s2[]) {
  int i = 0, answer;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0')
    ++i;
  if (s1[i] < s2[i])
    answer = -1;
  else if (s1[i] == s2[i])
    answer = 0;
  else
    answer = 1;
  return answer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compareStr>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L39
  jmp    L23
  nopl   (%rax)
L30:
  test   %cl,%cl
  je     L23
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L23
L39:
  test   %dl,%dl
  jne    L30
L23:
  xor    %eax,%eax
  cmp    %cl,%dl
  mov    $0xffffffff,%edx
  setne  %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compareStr(const char s1[], const char s2[]) {
  int i = 0, answer;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0')
    ++i;
  if (s1[i] < s2[i])
    answer = -1;
  else if (s1[i] == s2[i])
    answer = 0;
  else
    answer = 1;
  return answer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compareStr>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L3
  jmp    L19
  nopl   (%rax)
L8:
  test   %cl,%cl
  je     L19
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L19
L3:
  test   %dl,%dl
  jne    L8
L19:
  xor    %eax,%eax
  cmp    %cl,%dl
  mov    $0xffffffff,%edx
  setne  %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compareStr(const char s1[], const char s2[]) {
  int i = 0, answer;
  while (s1[i] == s2[i] && s1[i] != '\0' && s2[i] != '\0')
    ++i;
  if (s1[i] < s2[i])
    answer = -1;
  else if (s1[i] == s2[i])
    answer = 0;
  else
    answer = 1;
  return answer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x38(%rbp)
  movl   $0xffffffff,-0x34(%rbp)
  movl   $0xffffffff,-0x30(%rbp)
  movl   $0xffffffff,-0x2c(%rbp)
  movl   $0xffffffff,-0x28(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L3
L11:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <xoroshiro128plus@plt>
  mov    %rax,%rbx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <xoroshiro128plus_32@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x3c(%rbp)
L3:
  cmpl   $0x3b9ac9ff,-0x3c(%rbp)
  jle    L11
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string

tool: D4: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xoroshiro128plus(s) == xoroshiro128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  movl   $0xffffffff,0x18(%rsp)
  movl   $0xffffffff,0x1c(%rsp)
  mov    $0x3b9aca00,%ebp
  lea    0x8(%rsp),%r12
L8:
  mov    %r12,%rdi
  call   <xoroshiro128plus@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rdi
  call   <xoroshiro128plus_32@plt>
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L8
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xoroshiro128plus(s) == xoroshiro128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x3b9aca00,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  movq   $0xffffffffffffffff,0x8(%rsp)
  movq   $0xffffffffffffffff,0x10(%rsp)
  movq   $0xffffffffffffffff,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdi
  call   <xoroshiro128plus@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <xoroshiro128plus_32@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L0
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xoroshiro128plus(s) == xoroshiro128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  pcmpeqd %xmm0,%xmm0
  push   %r12
  push   %rbp
  mov    $0x3b9aca00,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r13,%rdi
  call   <xoroshiro128plus@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <xoroshiro128plus_32@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  sub    $0x1,%ebp
  jne    L13
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: byte[8]
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: {"D14": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: D13: test succeeded


assistant: ```c
int main(void) {
  uint64_t s[] = {0xFFFFFFFFFFFFFFFFULL, 0xFFFFFFFFFFFFFFFFULL};
  uint32_t s32[] = {0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU, 0xFFFFFFFFU};
  for (int i = 0; i < 1000000000; i++) {
    assert(xoroshiro128plus(s) == xoroshiro128plus_32(s32));
  }
  printf("test succeeded\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<genImpar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L11:
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void genImpar(int n) {
  int i, impar;
  for (i = 0; i < n; i++) {
    impar = 2 * i + 1;
    printf("%d ", impar);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<genImpar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L2
  lea    0x1(%rdi,%rdi,1),%r12d
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
L17:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %r12d,%ebx
  jne    L17
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: %d 

assistant: ```c
void genImpar(int n) {
  int i, impar;
  for (i = 0; i < n; i++) {
    impar = 2 * i + 1;
    printf("%d ", impar);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<genImpar>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r12
  lea    0x1(%rdi,%rdi,1),%r12d
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   (%rax)
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L13
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: %d 

assistant: ```c
void genImpar(int n) {
  int i, impar;
  for (i = 0; i < n; i++) {
    impar = 2 * i + 1;
    printf("%d ", impar);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<genImpar>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r12
  lea    0x1(%rdi,%rdi,1),%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   (%rax)
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L6
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: %d 

assistant: ```c
void genImpar(int n) {
  int i, impar;
  for (i = 0; i < n; i++) {
    impar = 2 * i + 1;
    printf("%d ", impar);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L14
  mov    -0x4(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <g@plt>
  jmp    L12
L14:
  mov    -0x4(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <g@plt>
L12:
  nop
  leave
  ret
```

assistant: ```c
int f(int a) {
  if (a > 0)
    g(a, 3);
  else
    g(a, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L14
  mov    $0x3,%esi
  call   <g@plt>
L16:
  add    $0x8,%rsp
  ret
L14:
  mov    $0x5,%esi
  call   <g@plt>
  jmp    L16
```

assistant: ```c
int f(int a) {
  if (a > 0)
    g(a, 3);
  else
    g(a, 5);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  test   %edi,%edi
  jle    L9
  mov    $0x3,%esi
  jmp    1050 <g@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x5,%esi
  jmp    1050 <g@plt>
```

assistant: ```c
int f(int a) {
  if (a > 0)
    g(a, 3);
  else
    g(a, 5);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jle    L2
  mov    $0x3,%esi
  jmp    1050 <g@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x5,%esi
  jmp    1050 <g@plt>
```

assistant: ```c
int f(int a) {
  if (a > 0)
    g(a, 3);
  else
    g(a, 5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L8:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L8
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D13: %d

tool: D16: %d


assistant: ```c
int main() {
  int range, sum = 0, tmp;
  scanf("%d", &range);
  for (int a = 0; a < range; ++a) {
    scanf("%d", &tmp);
    sum += tmp;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L11
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D6(%rip),%r12
L9:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L9
L3:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x0,%ebp
  jmp    L3
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D6: %d

tool: D9: %d


assistant: ```c
int main() {
  int range, sum = 0, tmp;
  scanf("%d", &range);
  for (int a = 0; a < range; ++a) {
    scanf("%d", &tmp);
    sum += tmp;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L22
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r13
L33:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %ebx,(%rsp)
  jg     L33
L29:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  xor    %ebp,%ebp
  jmp    L29
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D7: %d

tool: D16: %d


assistant: ```c
int main() {
  int range, sum = 0, tmp;
  scanf("%d", &range);
  for (int a = 0; a < range; ++a) {
    scanf("%d", &tmp);
    sum += tmp;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L29
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r13
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  cmp    %ebx,(%rsp)
  jg     L14
L18:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  xor    %ebp,%ebp
  jmp    L18
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D10: %d

tool: D1: %d


assistant: ```c
int main() {
  int range, sum = 0, tmp;
  scanf("%d", &range);
  for (int a = 0; a < range; ++a) {
    scanf("%d", &tmp);
    sum += tmp;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int Abs(int val) {
  if (val < 0)
    return -val;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int Abs(int val) {
  if (val < 0)
    return -val;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int Abs(int val) {
  if (val < 0)
    return -val;
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int Abs(int val) {
  if (val < 0)
    return -val;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_leap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L6
L19:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int is_leap(int year) {
  if (year % 100 == 0) {
    return year % 400 == 0;
  }
  return year % 4 == 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_leap>:
  endbr64
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  test   $0x3,%dil
  sete   %dl
  movzbl %dl,%edx
  cmp    %eax,%edi
  je     L0
L2:
  mov    %edx,%eax
  ret
L0:
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edi
  sete   %dl
  movzbl %dl,%edx
  jmp    L2
```

assistant: ```c
int is_leap(int year) {
  if (year % 100 == 0) {
    return year % 400 == 0;
  }
  return year % 4 == 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_leap>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  xor    %r8d,%r8d
  add    $0x51eb850,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  and    $0x3,%edi
  sete   %r8b
  cmp    $0x28f5c28,%edx
  ja     L1
  ror    $0x4,%eax
  xor    %r8d,%r8d
  cmp    $0xa3d70a,%eax
  setbe  %r8b
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_leap(int year) {
  if (year % 100 == 0) {
    return year % 400 == 0;
  }
  return year % 4 == 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_leap>:
  endbr64
  imul   $0xc28f5c29,%edi,%eax
  xor    %r8d,%r8d
  add    $0x51eb850,%eax
  mov    %eax,%edx
  ror    $0x2,%edx
  and    $0x3,%edi
  sete   %r8b
  cmp    $0x28f5c28,%edx
  ja     L0
  ror    $0x4,%eax
  xor    %r8d,%r8d
  cmp    $0xa3d70a,%eax
  setbe  %r8b
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int is_leap(int year) {
  if (year % 100 == 0) {
    return year % 400 == 0;
  }
  return year % 4 == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bubblesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L29:
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L25:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L23
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1,-0xc(%rbp)
L23:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L25
L2:
  cmpl   $0x0,-0xc(%rbp)
  jne    L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubblesort(int *arr, int low, int high) {
  int didsort = 1;
  int count = 0;
  while (didsort) {
    didsort = 0;
    count++;
    int i;
    for (i = 0; i < high; i++) {
      if (arr[i] > arr[i + 1]) {
        swap(arr, i, i + 1);
        didsort = 1;
      }
    }
  }
}
```