ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_strchrnul>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  and    $0xff,%esi
  jne    L39
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L80:
  movzbl (%r12),%eax
  test   %al,%al
  je     L32
  cmp    %esi,%eax
  je     L32
  add    $0x1,%r12
L39:
  test   $0x7,%r12b
  jne    L80
  mov    D5(%rip),%rax
  xor    %edx,%edx
  movslq %esi,%r9
  mov    (%r12),%rcx
  mov    (%rax),%r8
  mov    $0xffffffffffffffff,%rax
  div    %r8
  shr    %r8
  add    $0x1,%r8
  imul   %rax,%r9
  imul   %rax,%r8
  mov    %r9,%rdi
  xor    %rcx,%rdi
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x8(%r12),%rcx
  add    $0x8,%r12
  mov    %rcx,%rdi
  xor    %r9,%rdi
L78:
  mov    %rcx,%rdx
  not    %rcx
  sub    %rax,%rdx
  and    %rcx,%rdx
  mov    %rdi,%rcx
  not    %rdi
  sub    %rax,%rcx
  and    %rdi,%rcx
  or     %rcx,%rdx
  test   %r8,%rdx
  je     L25
  movzbl (%r12),%eax
  test   %al,%al
  je     L32
L29:
  cmp    %esi,%eax
  je     L32
  movzbl 0x1(%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  jne    L29
L32:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  call   <my_strlen@plt>
  cltq
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *my_strchrnul(const char *s, int c) {
  size_t *w, k;
  c = (unsigned char)c;
  if (!c)
    return (char *)s + my_strlen(s);
  for (; (uintptr_t)s % (sizeof(size_t)); s++)
    if (!*s || *(unsigned char *)s == c)
      return (char *)s;
  k = ((size_t)-1 / UCHAR_MAX) * c;
  for (w = (void *)s; !((*w) - ((size_t)-1 / UCHAR_MAX) & ~(*w) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))) && !((*w ^ k) - ((size_t)-1 / UCHAR_MAX) & ~(*w ^ k) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); w++)
    ;
  for (s = (void *)w; *s && *(unsigned char *)s != c; s++)
    ;
  return (char *)s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L27
L3:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x40,%eax
  jg     L24
  addl   $0x1,-0x10(%rbp)
L24:
  addl   $0x1,-0x18(%rbp)
L27:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L3
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  mov    -0x20(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D58
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D58: How many grades will you be entering? 

tool: D23: %i

tool: D24: Enter grade #%i

tool: D33: 
Grade average = %.2f


tool: D5: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i", i);
    scanf("%i", &grade);
    gradeTotal = gradeTotal + grade;
    if (grade < 65)
      ++failureCount;
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L10
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D23(%rip),%r15
  lea    0x4(%rsp),%r14
  lea    D15(%rip),%r13
L32:
  mov    %ebx,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  movzbl %al,%eax
  add    %eax,%ebp
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L32
L33:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L33
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D45
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string
name: unpack_data
arguments: data_tag: D46
type_guessed: string

tool: D45: How many grades will you be entering? 

tool: D15: %i

tool: D23: Enter grade #%i

tool: D17: 
Grade average = %.2f


tool: D46: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i", i);
    scanf("%i", &grade);
    gradeTotal = gradeTotal + grade;
    if (grade < 65)
      ++failureCount;
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D42(%rip),%rdi
  push   %r14
  push   %r13
  lea    D43(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L24
  mov    $0x1,%ebx
  lea    D16(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L27:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L27
L24:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D31(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D43
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D31
type_infered: string
name: parse_data
arguments: data_tag: D33
type_infered: string

tool: D42: How many grades will you be entering? 

tool: D43: %i

tool: D16: Enter grade #%i

tool: D31: 
Grade average = %.2f


tool: D33: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i", i);
    scanf("%i", &grade);
    gradeTotal = gradeTotal + grade;
    if (grade < 65)
      ++failureCount;
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D18(%rip),%rdi
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L22
  mov    $0x1,%ebx
  lea    D13(%rip),%r15
  lea    0x4(%rsp),%r14
  nopl   (%rax)
L26:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%r12d
  cmp    $0x41,%eax
  setl   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%ebp
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jge    L26
L22:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D48(%rip),%rdi
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D48
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: string

tool: D18: How many grades will you be entering? 

tool: D17: %i

tool: D13: Enter grade #%i

tool: D48: 
Grade average = %.2f


tool: D31: Number of failures = %i


assistant: ```c
int main(void) {
  int numberOfGrades, i, grade;
  int gradeTotal = 0;
  int failureCount = 0;
  float average;
  printf("How many grades will you be entering? ");
  scanf("%i", &numberOfGrades);
  for (i = 1; i <= numberOfGrades; ++i) {
    printf("Enter grade #%i", i);
    scanf("%i", &grade);
    gradeTotal = gradeTotal + grade;
    if (grade < 65)
      ++failureCount;
  }
  average = (float)gradeTotal / numberOfGrades;
  printf("\nGrade average = %.2f\n", average);
  printf("Number of failures = %i\n", failureCount);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usageError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <usage@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <everror@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: Bad usage

assistant: ```c
void usageError(void) {
  usage();
  everror("Bad usage");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usageError>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <usage@plt>
  lea    D0(%rip),%rdi
  call   <everror@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: Bad usage

assistant: ```c
void usageError(void) {
  usage();
  everror("Bad usage");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usageError>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <usage@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <everror@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: Bad usage

assistant: ```c
void usageError(void) {
  usage();
  everror("Bad usage");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usageError>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <usage@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <everror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: Bad usage

assistant: ```c
void usageError(void) {
  usage();
  everror("Bad usage");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TwoFish__b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  andl   $0x3,-0x8(%rbp)
  jmp    L3
L12:
  sarl   $0x8,-0x4(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jg     L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int8_t TwoFish__b(u_int32_t x, int n) {
  n &= 3;
  while (n-- > 0)
    x >>= 8;
  return (u_int8_t)x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TwoFish__b>:
  endbr64
  mov    %edi,%eax
  and    $0x3,%esi
  lea    -0x1(%rsi),%edx
  jle    L10
L14:
  sar    $0x8,%eax
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L14
L10:
  ret
```

assistant: ```c
u_int8_t TwoFish__b(u_int32_t x, int n) {
  n &= 3;
  while (n-- > 0)
    x >>= 8;
  return (u_int8_t)x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TwoFish__b>:
  endbr64
  and    $0x3,%esi
  mov    %edi,%eax
  lea    -0x1(%rsi),%edx
  je     L6
L10:
  sar    $0x8,%eax
  sub    $0x1,%edx
  jae    L10
L6:
  ret
```

assistant: ```c
u_int8_t TwoFish__b(u_int32_t x, int n) {
  n &= 3;
  while (n-- > 0)
    x >>= 8;
  return (u_int8_t)x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TwoFish__b>:
  endbr64
  mov    %esi,%edx
  mov    %edi,%eax
  and    $0x3,%edx
  je     L18
  sar    $0x8,%eax
  and    $0x2,%esi
  je     L18
  mov    %edi,%eax
  sar    $0x10,%edi
  sar    $0x18,%eax
  cmp    $0x3,%edx
  cmovne %edi,%eax
L18:
  ret
```

assistant: ```c
u_int8_t TwoFish__b(u_int32_t x, int n) {
  n &= 3;
  while (n-- > 0)
    x >>= 8;
  return (u_int8_t)x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<intPow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L16:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int intPow(int base, int exp) {
  int result = 1;
  while ((exp--) > 0) {
    result *= base;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<intPow>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %esi,%esi
  jle    L19
  mov    $0x1,%edx
L2:
  imul   %edi,%edx
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L2
L0:
  mov    %edx,%eax
  ret
L19:
  mov    $0x1,%edx
  jmp    L0
```

assistant: ```c
int intPow(int base, int exp) {
  int result = 1;
  while ((exp--) > 0) {
    result *= base;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intPow>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L17
  nopl   0x0(%rax)
L7:
  imul   %edi,%r8d
  sub    $0x1,%eax
  jae    L7
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int intPow(int base, int exp) {
  int result = 1;
  while ((exp--) > 0) {
    result *= base;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intPow>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L13
  nopl   0x0(%rax)
L12:
  imul   %edi,%r8d
  sub    $0x1,%eax
  jae    L12
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int intPow(int base, int exp) {
  int result = 1;
  while ((exp--) > 0) {
    result *= base;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L20
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L52
L20:
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jne    L44
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L52
L44:
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  jne    L60
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L52
L60:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L52:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D47
datatype: string
name: read_data
arguments: label: D45
datatype: string
name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D20
datatype: string

tool: D36: Enter Choice (1 - 3) : 

tool: D47: %d

tool: D45: 
Choice is 1

tool: D4: 
Choice is 2

tool: D23: 
Choice is 3

tool: D20: 
Invalid Choice 

assistant: ```c
main() {
  int x;
  x = 0;
  printf("Enter Choice (1 - 3) : ");
  scanf("%d", &x);
  if (x == 1)
    printf("\nChoice is 1");
  else if (x == 2)
    printf("\nChoice is 2");
  else if (x == 3)
    printf("\nChoice is 3");
  else
    printf("\nInvalid Choice ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D50(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L23
  cmp    $0x2,%eax
  je     L44
  cmp    $0x3,%eax
  je     L59
  lea    D11(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L44:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L59:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D50
type_infered: string
name: unpack_data
arguments: tag: D46
type_infered: string
name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D44
type_infered: string
name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D21
type_infered: string

tool: D50: Enter Choice (1 - 3) : 

tool: D46: %d

tool: D11: 
Invalid Choice 

tool: D44: 
Choice is 1

tool: D19: 
Choice is 2

tool: D21: 
Choice is 3

assistant: ```c
main() {
  int x;
  x = 0;
  printf("Enter Choice (1 - 3) : ");
  scanf("%d", &x);
  if (x == 1)
    printf("\nChoice is 1");
  else if (x == 2)
    printf("\nChoice is 2");
  else if (x == 3)
    printf("\nChoice is 3");
  else
    printf("\nInvalid Choice ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D50(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L6
  cmp    $0x2,%eax
  je     L52
  cmp    $0x3,%eax
  je     L42
  lea    D13(%rip),%rdi
  call   <printf@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L42:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L6:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L52:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D50
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D21
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string

tool: D50: Enter Choice (1 - 3) : 

tool: D34: %d

tool: D13: 
Invalid Choice 

tool: D21: 
Choice is 3

tool: D17: 
Choice is 1

tool: D20: 
Choice is 2

assistant: ```c
main() {
  int x;
  x = 0;
  printf("Enter Choice (1 - 3) : ");
  scanf("%d", &x);
  if (x == 1)
    printf("\nChoice is 1");
  else if (x == 2)
    printf("\nChoice is 2");
  else if (x == 3)
    printf("\nChoice is 3");
  else
    printf("\nInvalid Choice ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D55(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L29
  cmp    $0x2,%eax
  je     L46
  cmp    $0x3,%eax
  je     L62
  lea    D18(%rip),%rdi
  call   <printf@plt>
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L62:
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L29:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L46:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D55
type_infered: string
name: unpack_data
arguments: tag: D43
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D52
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D49
type_infered: string

tool: D55: Enter Choice (1 - 3) : 

tool: D43: %d

tool: D18: 
Invalid Choice 

tool: D52: 
Choice is 3

tool: D27: 
Choice is 1

tool: D49: 
Choice is 2

assistant: ```c
main() {
  int x;
  x = 0;
  printf("Enter Choice (1 - 3) : ");
  scanf("%d", &x);
  if (x == 1)
    printf("\nChoice is 1");
  else if (x == 2)
    printf("\nChoice is 2");
  else if (x == 3)
    printf("\nChoice is 3");
  else
    printf("\nInvalid Choice ");
}
```