ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <verrc@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void err(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrc(eval, errno, fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<err>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    %r12d,%edi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void err(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrc(eval, errno, fmt, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<err>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void err(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrc(eval, errno, fmt, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<err>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%edi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void err(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  verrc(eval, errno, fmt, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  movl   $0x0,-0x10(%rbp)
L4:
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x10(%rbp)
  jmp    L4
```

assistant: ```c
int main() {
  int i = 0, x = 0, y = 0;
  int n = nondet_int();
  __ESBMC_assume(n > 0);
  for (i = 0; 1; i++) {
    assert(x == 0);
  }
  assert(x == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <__ESBMC_assume@plt>
L6:
  mov    $0x1,%edi
  call   <assert@plt>
  jmp    L6
```

assistant: ```c
int main() {
  int i = 0, x = 0, y = 0;
  int n = nondet_int();
  __ESBMC_assume(n > 0);
  for (i = 0; 1; i++) {
    assert(x == 0);
  }
  assert(x == 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <__ESBMC_assume@plt>
  nopl   0x0(%rax)
L1:
  mov    $0x1,%edi
  call   <assert@plt>
  jmp    L1
```

assistant: ```c
int main() {
  int i = 0, x = 0, y = 0;
  int n = nondet_int();
  __ESBMC_assume(n > 0);
  for (i = 0; 1; i++) {
    assert(x == 0);
  }
  assert(x == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setg   %dil
  call   <__ESBMC_assume@plt>
  nopl   0x0(%rax)
L7:
  mov    $0x1,%edi
  call   <assert@plt>
  jmp    L7
```

assistant: ```c
int main() {
  int i = 0, x = 0, y = 0;
  int n = nondet_int();
  __ESBMC_assume(n > 0);
  for (i = 0; 1; i++) {
    assert(x == 0);
  }
  assert(x == 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<EncodeString>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  mov    %esi,%r13d
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D9(%rip),%r14
  jmp    L68
L8:
  cmp    $0x5f,%al
  je     L31
  mov    %eax,%edx
  lea    -0x3a(%rax),%ecx
  cmp    $0x6,%cl
  jbe    L135
  sub    $0x30,%eax
  cmp    $0x4a,%al
  ja     L135
  lea    -0x5b(%rdx),%eax
  cmp    $0x5,%al
  jbe    L135
L31:
  movslq %ebx,%rax
  add    %r12,%rax
  cmpb   $0x20,(%rax)
  je     L11
L148:
  add    $0x1,%ebx
  movslq %ebx,%rbp
  add    %r12,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L7
L68:
  cmp    $0x20,%al
  je     L31
  cmp    $0x2a,%al
  je     L31
  cmp    $0x2e,%al
  jg     L8
  cmp    $0x2c,%al
  jg     L31
L135:
  mov    %r13d,%ecx
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L121
  movsbl 0x0(%rbp),%edx
  lea    0x4(%rsp),%rdi
  mov    %r14,%rsi
  call   <sprintf@plt>
  lea    0x1(%rbx),%eax
  movzbl 0x4(%rsp),%edx
  mov    %dl,0x0(%rbp)
  add    $0x2,%ebx
  cltq
  movzbl 0x5(%rsp),%edx
  mov    %dl,(%r12,%rax,1)
  movslq %ebx,%rax
  movzbl 0x6(%rsp),%edx
  mov    %dl,(%r12,%rax,1)
  jmp    L31
L11:
  movb   $0x2b,(%rax)
  jmp    L148
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
L37:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L116
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L121:
  mov    $0xffffffff,%eax
  jmp    L37
L116:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %%%2x

assistant: ```c
int EncodeString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if (((sString[i] != ' ') && (sString[i] != '*') && (sString[i] != '-') && (sString[i] != '_') && (sString[i] != '.')) && ((sString[i] < '0') || ((sString[i] > '9') && (sString[i] < 'A')) || ((sString[i] > 'Z') && (sString[i] < 'a')) || (sString[i] > 'z'))) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    if (sString[i] == ' ') {
      sString[i] = '+';
    }
    i++;
  }
  return strlen(sString);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<EncodeString>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
  mov    %esi,%r12d
  mov    %rdi,%rbp
  lea    D8(%rip),%r13
  xor    %ebx,%ebx
  jmp    L141
  nop
L3:
  cmp    $0x2e,%al
  jg     L15
  cmp    $0x2c,%al
  jg     L144
L59:
  mov    %r12d,%ecx
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L126
  movsbl 0x0(%rbp),%edx
  lea    0x4(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  movzbl 0x4(%rsp),%edx
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
  cltq
  mov    %dl,0x0(%rbp)
  movzbl 0x5(%rsp),%edx
  mov    %dl,(%r14,%rax,1)
  movzbl 0x6(%rsp),%edx
  movslq %ebx,%rax
  add    %r14,%rax
  mov    %dl,(%rax)
  xchg   %ax,%ax
L56:
  cmp    $0x20,%dl
  jne    L29
  movb   $0x2b,(%rax)
L29:
  add    $0x1,%ebx
  movslq %ebx,%rbp
  add    %r14,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L35
L141:
  cmp    $0x20,%al
  je     L144
  cmp    $0x2a,%al
  jne    L3
L144:
  movslq %ebx,%rax
  add    %r14,%rax
  movzbl (%rax),%edx
  jmp    L56
L15:
  cmp    $0x5f,%al
  je     L144
  lea    -0x3a(%rax),%edx
  cmp    $0x6,%dl
  jbe    L59
  lea    -0x30(%rax),%edx
  cmp    $0x4a,%dl
  ja     L59
  sub    $0x5b,%eax
  cmp    $0x5,%al
  jbe    L59
  jmp    L144
  nopl   0x0(%rax)
L35:
  mov    %r14,%rdi
  call   <strlen@plt>
L147:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L155
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L126:
  mov    $0xffffffff,%eax
  jmp    L147
L155:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: %%%2x

assistant: ```c
int EncodeString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if (((sString[i] != ' ') && (sString[i] != '*') && (sString[i] != '-') && (sString[i] != '_') && (sString[i] != '.')) && ((sString[i] < '0') || ((sString[i] > '9') && (sString[i] < 'A')) || ((sString[i] > 'Z') && (sString[i] < 'a')) || (sString[i] > 'z'))) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    if (sString[i] == ' ') {
      sString[i] = '+';
    }
    i++;
  }
  return strlen(sString);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EncodeString>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L92
  jmp    L88
  xchg   %ax,%ax
L120:
  cmp    $0x2e,%al
  jg     L38
  cmp    $0x2c,%al
  jg     L18
L81:
  mov    %r12d,%ecx
  mov    $0x2,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <BufferDiff@plt>
  test   %rax,%rax
  js     L77
  movsbl 0x0(%rbp),%edx
  lea    0x4(%rsp),%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  movzbl 0x4(%rsp),%edx
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
  cltq
  mov    %dl,0x0(%rbp)
  movzbl 0x5(%rsp),%edx
  mov    %dl,(%r14,%rax,1)
  movzbl 0x6(%rsp),%eax
  movslq %ebx,%rdx
  add    %r14,%rdx
  mov    %al,(%rdx)
L86:
  cmp    $0x20,%al
  jne    L18
  movb   $0x2b,(%rdx)
L18:
  add    $0x1,%ebx
  movslq %ebx,%rbp
  add    %r14,%rbp
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L88
L92:
  cmp    $0x20,%al
  je     L107
  cmp    $0x2a,%al
  jne    L120
L107:
  movslq %ebx,%rdx
  add    %r14,%rdx
  jmp    L86
  cs nopw 0x0(%rax,%rax,1)
L38:
  cmp    $0x5f,%al
  je     L18
  lea    -0x3a(%rax),%edx
  cmp    $0x6,%dl
  jbe    L81
  lea    -0x30(%rax),%edx
  cmp    $0x4a,%dl
  ja     L81
  sub    $0x5b,%eax
  cmp    $0x5,%al
  jbe    L81
  jmp    L18
  nopl   0x0(%rax)
L88:
  mov    %r14,%rdi
  call   <strlen@plt>
L156:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L77:
  mov    $0xffffffff,%eax
  jmp    L156
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string

tool: D2: %%%2x

assistant: ```c
int EncodeString(char *sString, int dMaxSize) {
  int i;
  char sAccum[4];
  i = 0;
  while (sString[i] != 0) {
    if (((sString[i] != ' ') && (sString[i] != '*') && (sString[i] != '-') && (sString[i] != '_') && (sString[i] != '.')) && ((sString[i] < '0') || ((sString[i] > '9') && (sString[i] < 'A')) || ((sString[i] > 'Z') && (sString[i] < 'a')) || (sString[i] > 'z'))) {
      if (BufferDiff(sString, i, 2, dMaxSize) < 0) {
        return -1;
      }
      sprintf(sAccum, "%%%2x", sString[i]);
      sString[i++] = sAccum[0];
      sString[i++] = sAccum[1];
      sString[i] = sAccum[2];
    }
    if (sString[i] == ' ') {
      sString[i] = '+';
    }
    i++;
  }
  return strlen(sString);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_pointer_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x348(%rbp)
  jmp    L3
L29:
  mov    -0x348(%rbp),%eax
  cltq
  movl   $0x0,-0x340(%rbp,%rax,4)
  addl   $0x1,-0x348(%rbp)
L3:
  cmpl   $0xc7,-0x348(%rbp)
  jle    L29
  movl   $0x0,-0x348(%rbp)
  jmp    L65
L52:
  mov    -0x348(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x344(%rbp)
  jmp    L28
L59:
  lea    -0x340(%rbp),%rdx
  mov    -0x348(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <pointer_hash@plt>
  mov    %rax,%rbx
  lea    -0x340(%rbp),%rdx
  mov    -0x344(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <pointer_hash@plt>
  cmp    %rax,%rbx
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x344(%rbp)
L28:
  cmpl   $0xc7,-0x344(%rbp)
  jle    L59
  addl   $0x1,-0x348(%rbp)
L65:
  cmpl   $0xc7,-0x348(%rbp)
  jle    L52
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void test_pointer_hash(void) {
  int array[200];
  int i, j;
  for (i = 0; i < 200; ++i) {
    array[i] = 0;
  }
  for (i = 0; i < 200; ++i) {
    for (j = i + 1; j < 200; ++j) {
      assert(pointer_hash(&array[i]) != pointer_hash(&array[j]));
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_pointer_hash>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x320(%rsp),%rdx
L48:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L48
  mov    $0x0,%r13d
  mov    $0x1,%r14d
  mov    $0x1,%ebx
  mov    %rsp,%r12
  jmp    L31
L17:
  mov    %r14d,%r13d
  mov    %ebx,%r14d
L31:
  movslq %r13d,%rax
  lea    (%r12,%rax,4),%rdi
  call   <pointer_hash@plt>
  mov    %rax,%rbp
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rdi
  call   <pointer_hash@plt>
  cmp    %rax,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%ebx
  cmp    $0xc7,%ebx
  jle    L31
  lea    0x1(%r14),%ebx
  cmp    $0xc7,%ebx
  jle    L17
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_pointer_hash(void) {
  int array[200];
  int i, j;
  for (i = 0; i < 200; ++i) {
    array[i] = 0;
  }
  for (i = 0; i < 200; ++i) {
    for (j = i + 1; j < 200; ++j) {
      assert(pointer_hash(&array[i]) != pointer_hash(&array[j]));
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_pointer_hash>:
  endbr64
  push   %r14
  mov    $0x64,%ecx
  mov    $0x1,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L23:
  lea    (%r12,%r13,4),%rdi
  call   <pointer_hash@plt>
  mov    %rax,%rbp
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rdi
  call   <pointer_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbp
  setne  %dil
  add    $0x1,%ebx
  call   <assert@plt>
  cmp    $0xc8,%ebx
  jne    L23
  lea    0x1(%r14),%ebx
  cmp    $0xc7,%r14d
  je     L13
  movslq %r14d,%r13
  mov    %ebx,%r14d
  jmp    L23
  xchg   %ax,%ax
L13:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_pointer_hash(void) {
  int array[200];
  int i, j;
  for (i = 0; i < 200; ++i) {
    array[i] = 0;
  }
  for (i = 0; i < 200; ++i) {
    for (j = i + 1; j < 200; ++j) {
      assert(pointer_hash(&array[i]) != pointer_hash(&array[j]));
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_pointer_hash>:
  endbr64
  push   %r14
  mov    $0x64,%ecx
  mov    $0x1,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L7:
  lea    (%r12,%r13,4),%rdi
  call   <pointer_hash@plt>
  mov    %rax,%rbp
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rdi
  call   <pointer_hash@plt>
  xor    %edi,%edi
  cmp    %rax,%rbp
  setne  %dil
  add    $0x1,%ebx
  call   <assert@plt>
  cmp    $0xc8,%ebx
  jne    L7
  lea    0x1(%r14),%ebx
  cmp    $0xc7,%r14d
  je     L15
  movslq %r14d,%r13
  mov    %ebx,%r14d
  jmp    L7
  xchg   %ax,%ax
L15:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_pointer_hash(void) {
  int array[200];
  int i, j;
  for (i = 0; i < 200; ++i) {
    array[i] = 0;
  }
  for (i = 0; i < 200; ++i) {
    for (j = i + 1; j < 200; ++j) {
      assert(pointer_hash(&array[i]) != pointer_hash(&array[j]));
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int s, int c) {
  int a1, a2, a3, a4, x1, x2, x3, x4, x;
  a1 = 2 * s;
  x1 = c + a1;
  a2 = 4 * s;
  x2 = c + a2;
  a3 = 7 * s;
  x3 = c + a3;
  a4 = 5 * s;
  x4 = c + a4;
  x = x1 + x2 + x3 + x4;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%edx
  add    %edx,%esi
  lea    (%rdx,%rsi,1),%eax
  add    %edx,%edi
  add    %eax,%edi
  add    %esi,%eax
  add    %edi,%eax
  sub    %edx,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
int f(int s, int c) {
  int a1, a2, a3, a4, x1, x2, x3, x4, x;
  a1 = 2 * s;
  x1 = c + a1;
  a2 = 4 * s;
  x2 = c + a2;
  a3 = 7 * s;
  x3 = c + a3;
  a4 = 5 * s;
  x4 = c + a4;
  x = x1 + x2 + x3 + x4;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%edx
  add    %edx,%esi
  add    %edx,%edi
  lea    (%rdx,%rsi,1),%eax
  add    %eax,%edi
  add    %esi,%eax
  add    %edi,%eax
  sub    %edx,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
int f(int s, int c) {
  int a1, a2, a3, a4, x1, x2, x3, x4, x;
  a1 = 2 * s;
  x1 = c + a1;
  a2 = 4 * s;
  x2 = c + a2;
  a3 = 7 * s;
  x3 = c + a3;
  a4 = 5 * s;
  x4 = c + a4;
  x = x1 + x2 + x3 + x4;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  lea    (%rdi,%rdi,1),%edx
  add    %edx,%esi
  add    %edx,%edi
  lea    (%rdx,%rsi,1),%eax
  add    %eax,%edi
  add    %esi,%eax
  add    %edi,%eax
  sub    %edx,%edi
  add    %edi,%eax
  ret
```

assistant: ```c
int f(int s, int c) {
  int a1, a2, a3, a4, x1, x2, x3, x4, x;
  a1 = 2 * s;
  x1 = c + a1;
  a2 = 4 * s;
  x2 = c + a2;
  a3 = 7 * s;
  x3 = c + a3;
  a4 = 5 * s;
  x4 = c + a4;
  x = x1 + x2 + x3 + x4;
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm1
  movss  D4(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: byte[4]

tool: D18: %f

tool: {"D4": [0x00,0x00,0x7a,0x44]}

assistant: ```c
main() {
  float metroCubico;
  scanf("%f", &metroCubico);
  printf("%f", metroCubico * 1000);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  D10(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: byte[4]

tool: D11: %f

tool: {"D10": [0x00,0x00,0x7a,0x44]}

assistant: ```c
main() {
  float metroCubico;
  scanf("%f", &metroCubico);
  printf("%f", metroCubico * 1000);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  D14(%rip),%xmm0
  mov    %rbp,%rdi
  mulss  0x4(%rsp),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: byte[4]

tool: D15: %f

tool: {"D14": [0x00,0x00,0x7a,0x44]}

assistant: ```c
main() {
  float metroCubico;
  scanf("%f", &metroCubico);
  printf("%f", metroCubico * 1000);
  return 0;
}
```