user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L100
L73:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L71
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L174
L71:
  mov    $0x1,%eax
  jmp    L93
L174:
  mov    $0x0,%eax
L93:
  cmp    $0x2710,%eax
  jle    L139
  mov    $0x0,%eax
  jmp    L134
L139:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jg     L140
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x2,%eax
  jle    L195
L140:
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L100
L195:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  cmp    $0x1,%eax
  jne    L187
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  cmp    $0x1,%eax
  jne    L187
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L100
L187:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  test   %eax,%eax
  jne    L46
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  cmp    $0x1,%eax
  je     L31
L46:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  cmp    $0x1,%eax
  jne    L205
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  test   %eax,%eax
  jne    L205
L31:
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L100
L205:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  test   %eax,%eax
  jne    L100
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ISODD@plt>
  test   %eax,%eax
  jne    L100
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L100:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L73
  mov    $0x0,%eax
L134:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L107
  call   <__stack_chk_fail@plt>
L107:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D57
data_type: string
name: extract_symbolic_data
arguments: data_tag: D50
data_type: string
name: extract_symbolic_data
arguments: data_tag: D33
data_type: string

tool: D28: %d

tool: D57: %d %d

tool: D50: No Number

tool: D33: %d


assistant: ```c
int main() {
  int t, n, m;
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &n, &m);
    if ((n || m) > 10000)
      return 0;
    if ((n || m) < 0)
      return 0;
    if ((m > n) || ((n - m) >= 3))
      printf("No Number\n");
    else {
      if ((ISODD(n) == 1) && (ISODD(m) == 1))
        printf("%d\n", m + n - 1);
      else if (((ISODD(n) == 0) && (ISODD(m) == 1)) || ((ISODD(n) == 1) && (ISODD(m) == 0)))
        printf("No Number\n");
      else if ((ISODD(n) == 0) && (ISODD(m) == 0))
        printf("%d\n", m + n);
    }
  }
  return 0;
}
```