ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D45
type: string
name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D31
type: string
name: read_data
arguments: label: D53
type: string

tool: D17: pid   = %u


tool: D45: ppid  = %u


tool: D11: uid   = %u


tool: D44: euid  = %u


tool: D31: gid   = %u


tool: D53: egid  = %u


assistant: ```c
int main(void) {
  printf("pid   = %u\n", getpid());
  printf("ppid  = %u\n", getppid());
  printf("uid   = %u\n", getuid());
  printf("euid  = %u\n", geteuid());
  printf("gid   = %u\n", getgid());
  printf("egid  = %u\n", getegid());
  sleep(10);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D45(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D54(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <geteuid@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getgid@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getegid@plt>
  lea    D30(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D45
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D54
data_type: string
name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D30
data_type: string

tool: D45: pid   = %u


tool: D0: ppid  = %u


tool: D54: uid   = %u


tool: D19: euid  = %u


tool: D20: gid   = %u


tool: D30: egid  = %u


assistant: ```c
int main(void) {
  printf("pid   = %u\n", getpid());
  printf("ppid  = %u\n", getppid());
  printf("uid   = %u\n", getuid());
  printf("euid  = %u\n", geteuid());
  printf("gid   = %u\n", getgid());
  printf("egid  = %u\n", getegid());
  sleep(10);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <geteuid@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getgid@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getegid@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D38
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D14: pid   = %u


tool: D24: ppid  = %u


tool: D23: uid   = %u


tool: D25: euid  = %u


tool: D38: gid   = %u


tool: D0: egid  = %u


assistant: ```c
int main(void) {
  printf("pid   = %u\n", getpid());
  printf("ppid  = %u\n", getppid());
  printf("uid   = %u\n", getuid());
  printf("euid  = %u\n", geteuid());
  printf("gid   = %u\n", getgid());
  printf("egid  = %u\n", getegid());
  sleep(10);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<aes_openssl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <AES_encrypt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void aes_openssl(unsigned char out[16], const unsigned char k[16], const unsigned char n[16]) {
  AES_KEY expanded;
  AES_set_encrypt_key(k, 128, &expanded);
  AES_encrypt(n, out, &expanded);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<aes_openssl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  mov    $0x80,%esi
  call   <AES_set_encrypt_key@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_openssl(unsigned char out[16], const unsigned char k[16], const unsigned char n[16]) {
  AES_KEY expanded;
  AES_set_encrypt_key(k, 128, &expanded);
  AES_encrypt(n, out, &expanded);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_openssl>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    $0x80,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_openssl(unsigned char out[16], const unsigned char k[16], const unsigned char n[16]) {
  AES_KEY expanded;
  AES_set_encrypt_key(k, 128, &expanded);
  AES_encrypt(n, out, &expanded);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aes_openssl>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    $0x80,%esi
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void aes_openssl(unsigned char out[16], const unsigned char k[16], const unsigned char n[16]) {
  AES_KEY expanded;
  AES_set_encrypt_key(k, 128, &expanded);
  AES_encrypt(n, out, &expanded);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TimerDMAEventGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x6c,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t TimerDMAEventGet(uint32_t ui32Base) {
  ;
  return ((*((volatile uint32_t *)(ui32Base + 0x0000006C))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerDMAEventGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    0x6c(%rax),%rax
  ret
```

assistant: ```c
uint32_t TimerDMAEventGet(uint32_t ui32Base) {
  ;
  return ((*((volatile uint32_t *)(ui32Base + 0x0000006C))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TimerDMAEventGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    0x6c(%rax),%rax
  ret
```

assistant: ```c
uint32_t TimerDMAEventGet(uint32_t ui32Base) {
  ;
  return ((*((volatile uint32_t *)(ui32Base + 0x0000006C))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TimerDMAEventGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    -0x8(%rsp),%rax
  mov    0x6c(%rax),%rax
  ret
```

assistant: ```c
uint32_t TimerDMAEventGet(uint32_t ui32Base) {
  ;
  return ((*((volatile uint32_t *)(ui32Base + 0x0000006C))));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L1
L28:
  subl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x8(%rbp)
  jle    L23
  cmpl   $0x0,-0x4(%rbp)
  jg     L28
L23:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    x = x - 1;
    y = y - 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L25
  test   %eax,%eax
  jle    L25
  mov    %ebx,%edx
L26:
  sub    $0x1,%edx
  lea    (%rax,%rdx,1),%ecx
  sub    %ebx,%ecx
  test   %edx,%edx
  jle    L25
  test   %ecx,%ecx
  jg     L26
L25:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    x = x - 1;
    y = y - 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    x = x - 1;
    y = y - 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x > 0 && y > 0) {
    x = x - 1;
    y = y - 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dump_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: 
 Unrecoverable error
 %s 
  Exiting now 


assistant: ```c
void dump_error(char *ss) {
  printf("\n Unrecoverable error\n %s \n  Exiting now \n", ss);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<dump_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: 
 Unrecoverable error
 %s 
  Exiting now 


assistant: ```c
void dump_error(char *ss) {
  printf("\n Unrecoverable error\n %s \n  Exiting now \n", ss);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: 
 Unrecoverable error
 %s 
  Exiting now 


assistant: ```c
void dump_error(char *ss) {
  printf("\n Unrecoverable error\n %s \n  Exiting now \n", ss);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: 
 Unrecoverable error
 %s 
  Exiting now 


assistant: ```c
void dump_error(char *ss) {
  printf("\n Unrecoverable error\n %s \n  Exiting now \n", ss);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_bind_path_router>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: UDS_ROUTER

assistant: ```c
int get_bind_path_router(char *bind_path) {
  strcpy(bind_path, "UDS_ROUTER");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_bind_path_router>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <strcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: UDS_ROUTER

assistant: ```c
int get_bind_path_router(char *bind_path) {
  strcpy(bind_path, "UDS_ROUTER");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_bind_path_router>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: UDS_ROUTER

assistant: ```c
int get_bind_path_router(char *bind_path) {
  strcpy(bind_path, "UDS_ROUTER");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_bind_path_router>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: UDS_ROUTER

assistant: ```c
int get_bind_path_router(char *bind_path) {
  strcpy(bind_path, "UDS_ROUTER");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L16
  mov    $0x1,%eax
  jmp    L3
L16:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <warp_pointer@plt>
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3)
    return 1;
  warp_pointer(atoi(argv[1]), atoi(argv[2]));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jg     L4
  ret
L4:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <warp_pointer@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3)
    return 1;
  warp_pointer(atoi(argv[1]), atoi(argv[2]));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jg     L8
  mov    $0x1,%eax
  ret
L8:
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  push   %rax
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <warp_pointer@plt>
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3)
    return 1;
  warp_pointer(atoi(argv[1]), atoi(argv[2]));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jg     L5
  mov    $0x1,%eax
  ret
L5:
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  push   %rax
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <warp_pointer@plt>
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3)
    return 1;
  warp_pointer(atoi(argv[1]), atoi(argv[2]));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<I2SOutPointerNextGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x40021028,%eax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t I2SOutPointerNextGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(0x40021000 + 0x00000028))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<I2SOutPointerNextGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    0x40021028,%rax
  ret
```

assistant: ```c
uint32_t I2SOutPointerNextGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(0x40021000 + 0x00000028))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2SOutPointerNextGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  mov    0x40021028,%rax
  ret
```

assistant: ```c
uint32_t I2SOutPointerNextGet(uint32_t ui32Base) {
  ;
  return ((*((volatile unsigned long *)(0x40021000 + 0x00000028))));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<convertBinaryToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int convertBinaryToInt(int *binar, int size) {
  int ret = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    int e = pow(2, i);
    int f = binar[i];
    ret += e * f;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertBinaryToInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L5
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L0:
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   0x0(%r13,%rbx,4),%eax
  add    %eax,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L0
L28:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%ebp
  jmp    L28
```

assistant: ```c
int convertBinaryToInt(int *binar, int size) {
  int ret = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    int e = pow(2, i);
    int f = binar[i];
    ret += e * f;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convertBinaryToInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L17
  mov    %rdi,%r13
  movslq %esi,%rbp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   (%rax)
L10:
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   0x0(%r13,%rbx,4),%eax
  add    $0x1,%rbx
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int convertBinaryToInt(int *binar, int size) {
  int ret = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    int e = pow(2, i);
    int f = binar[i];
    ret += e * f;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convertBinaryToInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L12
  mov    %rdi,%r13
  movslq %esi,%rbp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   (%rax)
L7:
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   0x0(%r13,%rbx,4),%eax
  add    $0x1,%rbx
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int convertBinaryToInt(int *binar, int size) {
  int ret = 0;
  int i = 0;
  for (i = 0; i < size; i++) {
    int e = pow(2, i);
    int f = binar[i];
    ret += e * f;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L20:
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0xa,-0xc(%rbp)
  jle    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D6: Deme un numero para imprimir su tabla del 1 al 10

tool: D26: %d

tool: D3: %d x %d = %d


assistant: ```c
void main() {
  int multiplo;
  printf("Deme un numero para imprimir su tabla del 1 al 10\n");
  scanf("%d", &multiplo);
  for (int count = 1; count <= 10; count++) {
    printf("%d x %d = %d\n", multiplo, count, multiplo * count);
  }
  return;
}
```