ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dynmacro>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L64
  movsbl 0x1(%r12),%edi
  lea    0x1(%r12),%rbp
  test   %dil,%dil
  jne    L36
  jmp    L30
  nop
L41:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L30
L36:
  call   <isalpha@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <isdigit@plt>
  or     %eax,%ebx
  jne    L41
L30:
  mov    %rbp,%rbx
  jmp    L50
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbx
L50:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  cmpb   $0x3a,(%rbx)
  je     L20
L64:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmpb   $0x3d,0x1(%rbx)
  jne    L64
  movzbl 0x0(%rbp),%r13d
  movb   $0x0,0x0(%rbp)
  lea    0x2(%rbx),%rdi
  call   <copys@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  mov    %eax,%esi
  call   <setvar@plt>
  mov    %r13b,0x0(%rbp)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dynmacro(char *line) {
  char *s;
  char endc, *endp;
  if (!isalpha(line[0]))
    return 0;
  for (s = line + 1; *s && (isalpha(*s) | isdigit(*s)); ++s)
    ;
  endp = s;
  while (isspace(*s))
    ++s;
  if (s[0] != ':' || s[1] != '=')
    return 0;
  endc = *endp;
  *endp = '\0';
  setvar(line, copys(s + 2), 1);
  *endp = endc;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rawgettable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x2,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x0,%eax
  call   <lua_rawgettable@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rawgettable(void) {
  lua_pushobject(luaL_nonnullarg(1));
  lua_pushobject(luaL_nonnullarg(2));
  lua_pushobject(lua_rawgettable());
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rawgettable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x2,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x0,%eax
  call   <lua_rawgettable@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void rawgettable(void) {
  lua_pushobject(luaL_nonnullarg(1));
  lua_pushobject(luaL_nonnullarg(2));
  lua_pushobject(lua_rawgettable());
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rawgettable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x2,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  xor    %eax,%eax
  call   <lua_rawgettable@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <lua_pushobject@plt>
```

assistant: ```c
void rawgettable(void) {
  lua_pushobject(luaL_nonnullarg(1));
  lua_pushobject(luaL_nonnullarg(2));
  lua_pushobject(lua_rawgettable());
}
```
user: Translate the below assembly code into C programming language:

```asm
<rawgettable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  mov    $0x2,%edi
  call   <luaL_nonnullarg@plt>
  mov    %eax,%edi
  call   <lua_pushobject@plt>
  xor    %eax,%eax
  call   <lua_rawgettable@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <lua_pushobject@plt>
```

assistant: ```c
void rawgettable(void) {
  lua_pushobject(luaL_nonnullarg(1));
  lua_pushobject(luaL_nonnullarg(2));
  lua_pushobject(lua_rawgettable());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1f,-0x4(%rbp)
  movl   $0x80000000,-0x8(%rbp)
  jmp    L8
L30:
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L10
  mov    -0x4(%rbp),%eax
  jmp    L21
L10:
  subl   $0x1,-0x4(%rbp)
  shrl   -0x8(%rbp)
L8:
  cmpl   $0x0,-0x4(%rbp)
  jne    L30
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bsr>:
  endbr64
  test   %edi,%edi
  js     L24
  mov    $0x40000000,%edx
  mov    $0x1e,%eax
L16:
  test   %edx,%edi
  jne    L10
  shr    %edx
  sub    $0x1,%eax
  jne    L16
  ret
L24:
  mov    $0x1f,%eax
L10:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bsr>:
  endbr64
  mov    $0x1f,%eax
  mov    $0x80000000,%edx
  jmp    L9
L8:
  shr    %edx
  sub    $0x1,%eax
  je     L21
L9:
  test   %edx,%edi
  je     L8
L21:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bsr>:
  endbr64
  mov    $0x1f,%eax
  mov    $0x80000000,%edx
  jmp    L2
L23:
  shr    %edx
  sub    $0x1,%eax
  je     L27
L2:
  test   %edx,%edi
  je     L23
L27:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vcross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vcopy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void vcross(const float v1[3], const float v2[3], float cross[3]) {
  float temp[3];
  temp[0] = (v1[1] * v2[2]) - (v1[2] * v2[1]);
  temp[1] = (v1[2] * v2[0]) - (v1[0] * v2[2]);
  temp[2] = (v1[0] * v2[1]) - (v1[1] * v2[0]);
  vcopy(temp, cross);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vcross>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdx,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movss  0x4(%rdi),%xmm2
  movss  0x8(%rsi),%xmm3
  movss  0x8(%rdi),%xmm1
  movss  0x4(%rsi),%xmm0
  movaps %xmm2,%xmm4
  mulss  %xmm3,%xmm4
  movaps %xmm1,%xmm5
  mulss  %xmm0,%xmm5
  subss  %xmm5,%xmm4
  movss  %xmm4,0xc(%rsp)
  movss  (%rsi),%xmm4
  movss  (%rdi),%xmm5
  mulss  %xmm4,%xmm1
  mulss  %xmm5,%xmm3
  subss  %xmm3,%xmm1
  movss  %xmm1,0x10(%rsp)
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    %rax,%rsi
  call   <vcopy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vcross(const float v1[3], const float v2[3], float cross[3]) {
  float temp[3];
  temp[0] = (v1[1] * v2[2]) - (v1[2] * v2[1]);
  temp[1] = (v1[2] * v2[0]) - (v1[0] * v2[2]);
  temp[2] = (v1[0] * v2[1]) - (v1[1] * v2[0]);
  vcopy(temp, cross);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vcross>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rax
  movss  0x4(%rdi),%xmm2
  mov    %rdx,%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  movss  0x8(%rdi),%xmm1
  movss  0x8(%rax),%xmm3
  movss  0x4(%rax),%xmm0
  movaps %xmm2,%xmm4
  mulss  %xmm3,%xmm4
  movaps %xmm1,%xmm5
  mulss  %xmm0,%xmm5
  subss  %xmm5,%xmm4
  movss  (%rdi),%xmm5
  lea    0xc(%rsp),%rdi
  mulss  %xmm5,%xmm3
  movss  %xmm4,0xc(%rsp)
  movss  (%rax),%xmm4
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm1
  mulss  %xmm4,%xmm2
  subss  %xmm3,%xmm1
  subss  %xmm2,%xmm0
  movss  %xmm1,0x10(%rsp)
  movss  %xmm0,0x14(%rsp)
  call   <vcopy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vcross(const float v1[3], const float v2[3], float cross[3]) {
  float temp[3];
  temp[0] = (v1[1] * v2[2]) - (v1[2] * v2[1]);
  temp[1] = (v1[2] * v2[0]) - (v1[0] * v2[2]);
  temp[2] = (v1[0] * v2[1]) - (v1[1] * v2[0]);
  vcopy(temp, cross);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vcross>:
  endbr64
  mov    %rsi,%rax
  sub    $0x28,%rsp
  movss  (%rdi),%xmm5
  movss  0x8(%rdi),%xmm3
  movss  (%rax),%xmm4
  movss  0x8(%rax),%xmm2
  mov    %rdx,%rsi
  movq   0x4(%rdi),%xmm1
  movq   0x4(%rax),%xmm0
  unpcklps %xmm5,%xmm3
  lea    0x8(%rsp),%rdi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  unpcklps %xmm4,%xmm2
  mulps  %xmm1,%xmm2
  mulps  %xmm0,%xmm3
  mulss  %xmm4,%xmm1
  mulss  %xmm5,%xmm0
  subps  %xmm3,%xmm2
  subss  %xmm1,%xmm0
  movlps %xmm2,0x8(%rsp)
  movss  %xmm0,0x10(%rsp)
  call   <vcopy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vcross(const float v1[3], const float v2[3], float cross[3]) {
  float temp[3];
  temp[0] = (v1[1] * v2[2]) - (v1[2] * v2[1]);
  temp[1] = (v1[2] * v2[0]) - (v1[0] * v2[2]);
  temp[2] = (v1[0] * v2[1]) - (v1[1] * v2[0]);
  vcopy(temp, cross);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<grid_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L22:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L27
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void grid_copy(int rmin, int rmax, int cmin, int cmax, double **grid, double **next_grid) {
#pragma offload_transfer target(mic) in(grid : length(nrows + 2 * ncols + 2) ALLOC) in(next_grid : length(nrows + 2 * ncols + 2) ALLOC)
#pragma offload target(mic) in(grid : REUSE)in(next_grid : REUSE)
  {
    int i, j;
#pragma omp parallel for private(i, j)
    for (i = rmin; i <= rmax; i++) {
      for (j = cmin; j <= cmax; j++) {
        grid[i][j] = next_grid[i][j];
      }
    }
  }
#pragma offload_transfer target(mic) nocopy(grid, next_grid : length(nrows + 2 * ncols + 2) FREE)
}
```
user: Translate the below assembly code into C programming language:

```asm
<grid_copy>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%r10d
  mov    %ecx,%r11d
  cmp    %esi,%edi
  jg     L7
  movslq %edi,%rdx
  lea    0x0(,%rdx,8),%rsi
  lea    (%r9,%rsi,1),%rcx
  add    %r8,%rsi
  sub    %edi,%eax
  add    %rdx,%rax
  lea    0x8(%r9,%rax,8),%r9
  movslq %r10d,%rax
  lea    0x0(,%rax,8),%r8
  mov    %r11d,%edx
  sub    %r10d,%edx
  lea    0x1(%rax,%rdx,1),%rdi
  shl    $0x3,%rdi
  jmp    L12
L52:
  mov    (%rcx),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    (%rsi),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L52
L43:
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %r9,%rcx
  je     L7
L12:
  mov    %r8,%rax
  cmp    %r11d,%r10d
  jle    L52
  jmp    L43
L7:
  ret
```

assistant: ```c
void grid_copy(int rmin, int rmax, int cmin, int cmax, double **grid, double **next_grid) {
#pragma offload_transfer target(mic) in(grid : length(nrows + 2 * ncols + 2) ALLOC) in(next_grid : length(nrows + 2 * ncols + 2) ALLOC)
#pragma offload target(mic) in(grid : REUSE)in(next_grid : REUSE)
  {
    int i, j;
#pragma omp parallel for private(i, j)
    for (i = rmin; i <= rmax; i++) {
      for (j = cmin; j <= cmax; j++) {
        grid[i][j] = next_grid[i][j];
      }
    }
  }
#pragma offload_transfer target(mic) nocopy(grid, next_grid : length(nrows + 2 * ncols + 2) FREE)
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<grid_copy>:
  endbr64
  mov    %esi,%r11d
  mov    %edx,%r10d
  cmp    %esi,%edi
  jg     L7
  movslq %edi,%rdi
  nopl   0x0(%rax)
L14:
  cmp    %ecx,%r10d
  jg     L26
  mov    (%r9,%rdi,8),%rsi
  mov    (%r8,%rdi,8),%rdx
  movslq %r10d,%rax
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jge    L16
L26:
  add    $0x1,%rdi
  cmp    %edi,%r11d
  jge    L14
L7:
  ret
```

assistant: ```c
void grid_copy(int rmin, int rmax, int cmin, int cmax, double **grid, double **next_grid) {
#pragma offload_transfer target(mic) in(grid : length(nrows + 2 * ncols + 2) ALLOC) in(next_grid : length(nrows + 2 * ncols + 2) ALLOC)
#pragma offload target(mic) in(grid : REUSE)in(next_grid : REUSE)
  {
    int i, j;
#pragma omp parallel for private(i, j)
    for (i = rmin; i <= rmax; i++) {
      for (j = cmin; j <= cmax; j++) {
        grid[i][j] = next_grid[i][j];
      }
    }
  }
#pragma offload_transfer target(mic) nocopy(grid, next_grid : length(nrows + 2 * ncols + 2) FREE)
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<grid_copy>:
  endbr64
  movslq %edi,%r10
  cmp    %esi,%r10d
  jg     L7
  push   %r15
  mov    %edx,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  cmp    %ecx,%edx
  jg     L17
  mov    %ecx,%edi
  mov    %esi,%ebp
  movslq %edx,%rsi
  mov    %r8,%r13
  sub    %edx,%edi
  mov    %rsi,-0x10(%rsp)
  mov    %r9,%r14
  lea    0x0(,%rsi,8),%r9
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%edi
  lea    0x8(%r9),%r15
  mov    %edi,%edx
  mov    %edi,-0x18(%rsp)
  and    $0xfffffffe,%edi
  shr    %edx
  mov    %edi,-0x14(%rsp)
  lea    -0x1(%rdx),%r8d
  lea    (%rax,%rdi,1),%edx
  add    $0x1,%r8
  movslq %edx,%rdx
  shl    $0x4,%r8
  shl    $0x3,%rdx
  nopw   0x0(%rax,%rax,1)
L74:
  mov    (%r14,%r10,8),%rcx
  mov    0x0(%r13,%r10,8),%rsi
  lea    (%rcx,%r15,1),%rax
  lea    (%rsi,%r9,1),%rdi
  cmp    %rax,%rdi
  je     L86
  cmpl   $0x2,-0x1c(%rsp)
  lea    (%rcx,%r9,1),%r11
  seta   %r12b
  xor    %eax,%eax
  test   %r12b,%r12b
  je     L86
  nopw   0x0(%rax,%rax,1)
L37:
  movupd (%r11,%rax,1),%xmm1
  movups %xmm1,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L37
  mov    -0x14(%rsp),%edi
  cmp    %edi,-0x18(%rsp)
  je     L64
  movsd  (%rcx,%rdx,1),%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
L64:
  add    $0x1,%r10
  cmp    %r10d,%ebp
  jge    L74
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L86:
  mov    -0x10(%rsp),%rax
  nopl   (%rax)
L33:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebx
  jge    L33
  jmp    L64
L7:
  ret
```

assistant: ```c
void grid_copy(int rmin, int rmax, int cmin, int cmax, double **grid, double **next_grid) {
#pragma offload_transfer target(mic) in(grid : length(nrows + 2 * ncols + 2) ALLOC) in(next_grid : length(nrows + 2 * ncols + 2) ALLOC)
#pragma offload target(mic) in(grid : REUSE)in(next_grid : REUSE)
  {
    int i, j;
#pragma omp parallel for private(i, j)
    for (i = rmin; i <= rmax; i++) {
      for (j = cmin; j <= cmax; j++) {
        grid[i][j] = next_grid[i][j];
      }
    }
  }
#pragma offload_transfer target(mic) nocopy(grid, next_grid : length(nrows + 2 * ncols + 2) FREE)
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L56
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L95
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L61
L95:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L40
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L40
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L61
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L10
  nop
L78:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L78
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L17
  nop
L3:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L3
L17:
  mov    $0x30,%eax
L61:
  leave
  ret
```

assistant: ```c
int getop(char *arg) {
  if (*arg == '-') {
    if (!isdigit(*(arg + 1))) {
      return *arg;
    } else {
      *arg++;
    }
  } else if (!isdigit(*arg) && *arg != '.')
    return *arg;
  if (isdigit(*arg))
    while (isdigit(*++arg))
      ;
  if (*arg == '.')
    while (isdigit(*++arg))
      ;
  return '0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  cmp    $0x2d,%dil
  je     L24
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L16
  movzbl (%rbx),%eax
  cmp    $0x2e,%al
  je     L16
  movsbl %al,%eax
  jmp    L28
L24:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L95
  add    $0x1,%rbx
L16:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L41
L65:
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L65
L41:
  mov    $0x30,%eax
  cmpb   $0x2e,(%rbx)
  je     L100
L28:
  pop    %rbx
  ret
L95:
  movsbl (%rbx),%eax
  jmp    L28
L100:
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L100
  mov    $0x30,%eax
  jmp    L28
```

assistant: ```c
int getop(char *arg) {
  if (*arg == '-') {
    if (!isdigit(*(arg + 1))) {
      return *arg;
    } else {
      *arg++;
    }
  } else if (!isdigit(*arg) && *arg != '.')
    return *arg;
  if (isdigit(*arg))
    while (isdigit(*++arg))
      ;
  if (*arg == '.')
    while (isdigit(*++arg))
      ;
  return '0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  je     L37
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L34
  movsbl (%rbx),%eax
  mov    %eax,%edi
  cmp    $0x2e,%al
  je     L50
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x1,%rbx
L34:
  movsbl (%rbx),%edi
L50:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L53
  cmpb   $0x2e,(%rbx)
  je     L38
L55:
  mov    $0x30,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L38:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L38
  jmp    L55
  nopl   0x0(%rax)
L37:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L45
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L50
L45:
  movsbl (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int getop(char *arg) {
  if (*arg == '-') {
    if (!isdigit(*(arg + 1))) {
      return *arg;
    } else {
      *arg++;
    }
  } else if (!isdigit(*arg) && *arg != '.')
    return *arg;
  if (isdigit(*arg))
    while (isdigit(*++arg))
      ;
  if (*arg == '.')
    while (isdigit(*++arg))
      ;
  return '0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  cmp    $0x2d,%dil
  je     L85
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L6
  movsbl (%rbx),%eax
  mov    %eax,%edi
  cmp    $0x2e,%al
  je     L49
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L64:
  add    $0x1,%rbx
L6:
  movsbl (%rbx),%edi
L49:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L64
  cmpb   $0x2e,(%rbx)
  je     L62
L71:
  mov    $0x30,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L62:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L62
  jmp    L71
  nopl   0x0(%rax)
L85:
  movsbl 0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L86
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  jmp    L49
L86:
  movsbl (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int getop(char *arg) {
  if (*arg == '-') {
    if (!isdigit(*(arg + 1))) {
      return *arg;
    } else {
      *arg++;
    }
  } else if (!isdigit(*arg) && *arg != '.')
    return *arg;
  if (isdigit(*arg))
    while (isdigit(*++arg))
      ;
  if (*arg == '.')
    while (isdigit(*++arg))
      ;
  return '0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<model_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <filesize@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0xffffffffffffffff,-0x20(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L10
L0:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <read_file_to_mem@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_filename_ext@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <model_from_mem_buf@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
struct model *model_from_file(const char *fpath) {
  long filesz = filesize(fpath);
  if (filesz == -1)
    return 0;
  unsigned char *data_buf = malloc(filesz);
  read_file_to_mem(fpath, data_buf, filesz);
  const char *ext = get_filename_ext(fpath);
  struct model *m = model_from_mem_buf(data_buf, filesz, ext);
  free(data_buf);
  return m;
}
```