ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testLESolv1@plt>
  xor    %eax,%eax
  call   <testLESolv2@plt>
  xor    %eax,%eax
  call   <testLESolv3@plt>
  xor    %eax,%eax
  call   <testLESolv4@plt>
  xor    %eax,%eax
  call   <testOLS1@plt>
  xor    %eax,%eax
  call   <TestPolyFit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testLESolv1();
  testLESolv2();
  testLESolv3();
  testLESolv4();
  testOLS1();
  TestPolyFit();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned xmask = (~(~0 << n)) << (p - n + 1);
  return x ^ xmask;
}
```
user: What is the c source code of the assembly code below?

```asm
<invert>:
  endbr64
  mov    %edx,%ecx
  mov    $0xffffffff,%eax
  shl    %cl,%eax
  not    %eax
  sub    %edx,%esi
  lea    0x1(%rsi),%ecx
  shl    %cl,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned xmask = (~(~0 << n)) << (p - n + 1);
  return x ^ xmask;
}
```
user: What is the c source code of the assembly code below?

```asm
<invert>:
  endbr64
  mov    %edx,%ecx
  mov    $0xffffffff,%eax
  sub    %edx,%esi
  shl    %cl,%eax
  lea    0x1(%rsi),%ecx
  not    %eax
  shl    %cl,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned xmask = (~(~0 << n)) << (p - n + 1);
  return x ^ xmask;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<invert>:
  endbr64
  mov    %edx,%ecx
  mov    $0xffffffff,%eax
  sub    %edx,%esi
  shl    %cl,%eax
  lea    0x1(%rsi),%ecx
  not    %eax
  shl    %cl,%eax
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned invert(unsigned x, int p, int n) {
  unsigned xmask = (~(~0 << n)) << (p - n + 1);
  return x ^ xmask;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x5,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L8
L11:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x5,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L11
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_array(int32_t *a, uint32_t n) {
  uint32_t i;
  int32_t x;
  x = 5;
  for (i = 0; i < n; i++) {
    a[i] = x;
    x += 5;
  }
  a[i] = INT32_MAX;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_array>:
  endbr64
  test   %rsi,%rsi
  je     L2
  mov    %rdi,%rdx
  lea    0x5(%rsi,%rsi,4),%ecx
  mov    $0x5,%eax
L12:
  mov    %eax,(%rdx)
  add    $0x5,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L12
L2:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi,%rsi,4)
  ret
```

assistant: ```c
void init_array(int32_t *a, uint32_t n) {
  uint32_t i;
  int32_t x;
  x = 5;
  for (i = 0; i < n; i++) {
    a[i] = x;
    x += 5;
  }
  a[i] = INT32_MAX;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<init_array>:
  endbr64
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rdx
  lea    0x5(%rsi,%rsi,4),%ecx
  mov    $0x5,%eax
  nopl   (%rax)
L10:
  mov    %eax,(%rdx)
  add    $0x5,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L10
  lea    (%rdi,%rsi,4),%rdi
L4:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void init_array(int32_t *a, uint32_t n) {
  uint32_t i;
  int32_t x;
  x = 5;
  for (i = 0; i < n; i++) {
    a[i] = x;
    x += 5;
  }
  a[i] = INT32_MAX;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insertionSortD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L43
L24:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L16
L28:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  subq   $0x1,-0x18(%rbp)
L16:
  cmpq   $0x0,-0x18(%rbp)
  js     L5
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jl     L28
L5:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x20(%rbp)
L43:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jle    L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertionSortD(long list[], long start, long end, double v[]) {
  for (long x = start + 1; x <= end; x++) {
    long val = list[x];
    double td = v[x];
    long j = x - 1;
    while (j >= 0 && val < list[j]) {
      list[j + 1] = list[j];
      v[j + 1] = v[j];
      j--;
    }
    list[j + 1] = val;
    v[j + 1] = td;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insertionSortD>:
  endbr64
  mov    %rdi,%r8
  cmp    %rdx,%rsi
  jl     L10
L33:
  ret
L0:
  add    $0x1,%rax
  mov    %r9,(%r8,%rax,8)
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  je     L33
L10:
  mov    0x8(%r8,%rsi,8),%r9
  movsd  0x8(%rcx,%rsi,8),%xmm1
  mov    %rsi,%rax
  test   %rsi,%rsi
  js     L0
L22:
  mov    (%r8,%rax,8),%rdi
  cmp    %r9,%rdi
  jle    L0
  mov    %rdi,0x8(%r8,%rax,8)
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,0x8(%rcx,%rax,8)
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L22
  jmp    L0
```

assistant: ```c
void insertionSortD(long list[], long start, long end, double v[]) {
  for (long x = start + 1; x <= end; x++) {
    long val = list[x];
    double td = v[x];
    long j = x - 1;
    while (j >= 0 && val < list[j]) {
      list[j + 1] = list[j];
      v[j + 1] = v[j];
      j--;
    }
    list[j + 1] = val;
    v[j + 1] = td;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertionSortD>:
  endbr64
  mov    %rdi,%r9
  cmp    %rdx,%rsi
  jge    L18
  nopl   0x0(%rax)
L30:
  mov    0x8(%r9,%rsi,8),%r10
  movsd  0x8(%rcx,%rsi,8),%xmm1
  mov    %rsi,%rax
  mov    %rsi,%rdi
  test   %rsi,%rsi
  jns    L59
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L23:
  movsd  (%rcx,%rax,8),%xmm0
  mov    %r8,0x8(%r9,%rax,8)
  movsd  %xmm0,0x8(%rcx,%rax,8)
  lea    -0x1(%rdi),%rax
  test   %rdi,%rdi
  je     L37
L59:
  mov    (%r9,%rax,8),%r8
  mov    %rax,%rdi
  cmp    %r10,%r8
  jg     L23
L39:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %r10,(%r9,%rdi,8)
  movsd  %xmm1,(%rcx,%rdi,8)
  cmp    %rsi,%rdx
  jne    L30
L18:
  ret
  nopl   0x0(%rax)
L37:
  mov    $0xffffffffffffffff,%rdi
  jmp    L39
```

assistant: ```c
void insertionSortD(long list[], long start, long end, double v[]) {
  for (long x = start + 1; x <= end; x++) {
    long val = list[x];
    double td = v[x];
    long j = x - 1;
    while (j >= 0 && val < list[j]) {
      list[j + 1] = list[j];
      v[j + 1] = v[j];
      j--;
    }
    list[j + 1] = val;
    v[j + 1] = td;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertionSortD>:
  endbr64
  mov    %rdi,%r9
  cmp    %rdx,%rsi
  jge    L33
  nopl   0x0(%rax)
L13:
  mov    0x8(%r9,%rsi,8),%r10
  movsd  0x8(%rcx,%rsi,8),%xmm1
  mov    %rsi,%rax
  mov    %rsi,%rdi
  test   %rsi,%rsi
  jns    L1
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L44:
  movsd  (%rcx,%rax,8),%xmm0
  mov    %r8,0x8(%r9,%rax,8)
  movsd  %xmm0,0x8(%rcx,%rax,8)
  lea    -0x1(%rdi),%rax
  test   %rdi,%rdi
  je     L36
L1:
  mov    (%r9,%rax,8),%r8
  mov    %rax,%rdi
  cmp    %r10,%r8
  jg     L44
L31:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %r10,(%r9,%rdi,8)
  movsd  %xmm1,(%rcx,%rdi,8)
  cmp    %rsi,%rdx
  jne    L13
L33:
  ret
  nopl   0x0(%rax)
L36:
  mov    $0xffffffffffffffff,%rdi
  jmp    L31
```

assistant: ```c
void insertionSortD(long list[], long start, long end, double v[]) {
  for (long x = start + 1; x <= end; x++) {
    long val = list[x];
    double td = v[x];
    long j = x - 1;
    while (j >= 0 && val < list[j]) {
      list[j + 1] = list[j];
      v[j + 1] = v[j];
      j--;
    }
    list[j + 1] = val;
    v[j + 1] = td;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<filename_without_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x2e,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <last_char_pos@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <initialize_string@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <add_to_string@plt>
  jmp    L2
L1:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <substr@plt>
L2:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void filename_without_extension(char *variable, const char *filename) {
  int index;
  last_char_pos(&index, filename, '.');
  if (index == 0) {
    initialize_string(variable);
    add_to_string(variable, filename);
  } else {
    substr(variable, filename, index);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filename_without_extension>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x2e,%edx
  call   <last_char_pos@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L8
  mov    %rbp,%rdi
  call   <initialize_string@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <add_to_string@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <substr@plt>
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filename_without_extension(char *variable, const char *filename) {
  int index;
  last_char_pos(&index, filename, '.');
  if (index == 0) {
    initialize_string(variable);
    add_to_string(variable, filename);
  } else {
    substr(variable, filename, index);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<filename_without_extension>:
  endbr64
  push   %r12
  mov    $0x2e,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <last_char_pos@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L18
  mov    %r12,%rdi
  call   <initialize_string@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <add_to_string@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <substr@plt>
  jmp    L27
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filename_without_extension(char *variable, const char *filename) {
  int index;
  last_char_pos(&index, filename, '.');
  if (index == 0) {
    initialize_string(variable);
    add_to_string(variable, filename);
  } else {
    substr(variable, filename, index);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<filename_without_extension>:
  endbr64
  push   %r12
  mov    $0x2e,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <last_char_pos@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L25
  mov    %r12,%rdi
  call   <initialize_string@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <add_to_string@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <substr@plt>
  jmp    L8
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void filename_without_extension(char *variable, const char *filename) {
  int index;
  last_char_pos(&index, filename, '.');
  if (index == 0) {
    initialize_string(variable);
    add_to_string(variable, filename);
  } else {
    substr(variable, filename, index);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char *org, char *dest) {
  char temp = *org;
  *org = *dest;
  *dest = temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *org, char *dest) {
  char temp = *org;
  *org = *dest;
  *dest = temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *org, char *dest) {
  char temp = *org;
  *org = *dest;
  *dest = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *org, char *dest) {
  char temp = *org;
  *org = *dest;
  *dest = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x1e,-0x34(%rbp)
  jle    L15
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L21
L15:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D8: Digite um nome: 

tool: D1: 
Erro

tool: D0: 
Nome: %s


assistant: ```c
main() {
  char nome[40];
  int tot;
  printf("Digite um nome: ");
  gets(nome);
  tot = strlen(nome);
  if (tot > 30)
    printf("\nErro");
  else
    printf("\nNome: %s\n", nome);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1e,%eax
  jle    L1
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D10: Digite um nome: 

tool: D19: 
Erro

tool: D16: 
Nome: %s


assistant: ```c
main() {
  char nome[40];
  int tot;
  printf("Digite um nome: ");
  gets(nome);
  tot = strlen(nome);
  if (tot > 30)
    printf("\nErro");
  else
    printf("\nNome: %s\n", nome);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1e,%eax
  jle    L16
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L16:
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string

tool: D26: Digite um nome: 

tool: D0: 
Erro

tool: D11: 
Nome: %s


assistant: ```c
main() {
  char nome[40];
  int tot;
  printf("Digite um nome: ");
  gets(nome);
  tot = strlen(nome);
  if (tot > 30)
    printf("\nErro");
  else
    printf("\nNome: %s\n", nome);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1e,%eax
  jle    L24
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D10: Digite um nome: 

tool: D22: 
Erro

tool: D7: 
Nome: %s


assistant: ```c
main() {
  char nome[40];
  int tot;
  printf("Digite um nome: ");
  gets(nome);
  tot = strlen(nome);
  if (tot > 30)
    printf("\nErro");
  else
    printf("\nNome: %s\n", nome);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L0
L9:
  mov    -0x18(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
char *basename(char *path) {
  char *p;
  p = strrchr(path, '/');
  return p ? p + 1 : path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *basename(char *path) {
  char *p;
  p = strrchr(path, '/');
  return p ? p + 1 : path;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *basename(char *path) {
  char *p;
  p = strrchr(path, '/');
  return p ? p + 1 : path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *basename(char *path) {
  char *p;
  p = strrchr(path, '/');
  return p ? p + 1 : path;
}
```