user: 这段汇编代码用C语言表示是什么样的？

```asm
<parse_server_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L22
  mov    $0x0,%eax
  call   <print_usage_details@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L55
L22:
  cmpl   $0x2,-0x24(%rbp)
  jne    L89
  mov    -0x38(%rbp),%rax
  movl   $0x457,(%rax)
  mov    $0x0,%eax
  jmp    L55
L89:
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0x7,%edx
  lea    D41(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x6,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    0x7(%rax),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L59
L41:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L29
  mov    $0x0,%eax
  call   <print_usage_details@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L55
L29:
  addl   $0x1,-0x14(%rbp)
L59:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffff,-0xc(%rbp)
  jle    L84
  mov    $0x0,%eax
  call   <print_usage_details@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L55
L84:
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L54
L8:
  mov    -0x38(%rbp),%rax
  movl   $0x457,(%rax)
L54:
  mov    $0x0,%eax
L55:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D41
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string

tool: D1: Starting a server


tool: D33: Had less than 2 arguments
.

tool: D41: --port=

tool: D17: Found a character in the port number


tool: D18: Port number was greater than 65535


assistant: ```c
int parse_server_args(int argc, char **argv, int *server_port) {
  int numPortChars, counter;
  char *szPort;
  int iPort;
  if (argc < 2) {
    print_usage_details();
    printf("Starting a server\n");
    printf("Had less than 2 arguments\n.");
    return -1;
  } else if (argc == 2) {
    *server_port = 1111;
    return 0;
  }
  if (strncmp(argv[2], "--port=", 7) == 0) {
    numPortChars = strlen(argv[2]) - 7 + 1;
    szPort = malloc(numPortChars * sizeof(char));
    strncpy(szPort, argv[2] + 7, numPortChars);
    szPort[numPortChars] = '\0';
    counter = 0;
    while (szPort[counter] != '\0') {
      if (!isdigit(szPort[counter])) {
        print_usage_details();
        printf("Found a character in the port number\n");
        return -1;
      }
      counter++;
    }
    iPort = atoi(szPort);
    if (iPort > 65535) {
      print_usage_details();
      printf("Port number was greater than 65535\n");
      return -1;
    }
    *server_port = iPort;
    free(szPort);
  } else
    *server_port = 1111;
  return 0;
}
```