ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<bx_unicode_sqlite3StrNICmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x18(%rsp),%r15
  lea    0x20(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L4:
  cmpb   $0x0,(%rdi)
  je     L21
  cmp    %eax,%ebx
  jne    L21
L38:
  xor    %esi,%esi
  mov    %r15,%rdx
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    0x20(%rsp),%rdi
  xor    %esi,%esi
  mov    %r14,%rdx
  mov    %eax,%ebx
  call   <bx_unicode_sqlite3Utf8Read@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    0x18(%rsp),%rdi
  mov    0x20(%rsp),%rdx
  mov    %rdi,%rcx
  sub    %r13,%rdx
  sub    %rbp,%rcx
  cmp    %rdx,%rcx
  cmovg  %ecx,%edx
  cmp    0xc(%rsp),%edx
  jl     L4
L21:
  mov    0xc(%rsp),%edx
  sub    %eax,%ebx
  xor    %eax,%eax
  test   %edx,%edx
  cmovns %ebx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp(const unsigned char *zLeft, const unsigned char *zRight, int N) {
  const unsigned char *a = zLeft;
  const unsigned char *b = zRight;
  signed int ua = 0, ub = 0;
  int Z = 0;
  do {
    ua = bx_unicode_sqlite3Utf8Read(a, 0, &a);
    ub = bx_unicode_sqlite3Utf8Read(b, 0, &b);
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    Z = (int)(((a - zLeft) > (b - zRight)) ? (a - zLeft) : (b - zRight));
  } while (N > Z && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bx_unicode_sqlite3StrNICmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x18(%rsp),%r15
  lea    0x20(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L6:
  cmpb   $0x0,(%rdi)
  je     L23
  cmp    %eax,%ebx
  jne    L23
L28:
  xor    %esi,%esi
  mov    %r15,%rdx
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    0x20(%rsp),%rdi
  xor    %esi,%esi
  mov    %r14,%rdx
  mov    %eax,%ebx
  call   <bx_unicode_sqlite3Utf8Read@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    0x18(%rsp),%rdi
  mov    0x20(%rsp),%rdx
  mov    %rdi,%rcx
  sub    %r13,%rdx
  sub    %rbp,%rcx
  cmp    %rdx,%rcx
  cmovg  %ecx,%edx
  cmp    0xc(%rsp),%edx
  jl     L6
L23:
  mov    0xc(%rsp),%edx
  sub    %eax,%ebx
  xor    %eax,%eax
  test   %edx,%edx
  cmovns %ebx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp(const unsigned char *zLeft, const unsigned char *zRight, int N) {
  const unsigned char *a = zLeft;
  const unsigned char *b = zRight;
  signed int ua = 0, ub = 0;
  int Z = 0;
  do {
    ua = bx_unicode_sqlite3Utf8Read(a, 0, &a);
    ub = bx_unicode_sqlite3Utf8Read(b, 0, &b);
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    Z = (int)(((a - zLeft) > (b - zRight)) ? (a - zLeft) : (b - zRight));
  } while (N > Z && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0xa4d,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L7
L5:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jbe    L47
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L14
L47:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%edx
  movzwl -0xc(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L14:
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L7:
  cmpw   $0x0,-0xc(%rbp)
  je     L5
  movzwl -0xa(%rbp),%eax
  lea    -0x11db(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)55866;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    -0x2675(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)55866;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    -0x2675(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)55866;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fbm_noise3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movss  %xmm2,-0x2c(%rbp)
  mov    %edi,-0x30(%rbp)
  movss  %xmm3,-0x34(%rbp)
  movss  %xmm4,-0x38(%rbp)
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x2c(%rbp),%xmm1
  movss  -0x28(%rbp),%xmm0
  mov    -0x24(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <noise3@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L0:
  movss  -0x14(%rbp),%xmm0
  mulss  -0x38(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x34(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0xc(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x2c(%rbp),%xmm0
  movaps %xmm0,%xmm2
  mulss  -0x14(%rbp),%xmm2
  movss  -0x28(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  -0x24(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <noise3@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x10(%rbp),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  movss  -0x8(%rbp),%xmm0
  divss  -0xc(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
datatype: byte[4]

tool: {"D19": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fbm_noise3(float x, float y, float z, int octaves, float persistence, float lacunarity) {
  float freq = 1.0f;
  float amp = 1.0f;
  float max = 1.0f;
  float total = noise3(x, y, z);
  int i;
  for (i = 1; i < octaves; ++i) {
    freq *= lacunarity;
    amp *= persistence;
    max += amp;
    total += noise3(x * freq, y * freq, z * freq) * amp;
  }
  return total / max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fbm_noise3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  mov    %edi,%r12d
  movss  %xmm3,0x18(%rsp)
  movss  %xmm4,0x1c(%rsp)
  call   <noise3@plt>
  movss  %xmm0,0x4(%rsp)
  cmp    $0x1,%r12d
  jle    L18
  mov    $0x1,%ebx
  mov    D17(%rip),%ebp
  mov    %ebp,(%rsp)
  mov    %ebp,0x8(%rsp)
L9:
  movss  0x8(%rsp),%xmm5
  mulss  0x1c(%rsp),%xmm5
  movss  %xmm5,0x8(%rsp)
  movss  (%rsp),%xmm6
  mulss  0x18(%rsp),%xmm6
  movd   %ebp,%xmm7
  movss  %xmm6,(%rsp)
  addss  %xmm6,%xmm7
  movd   %xmm7,%ebp
  movss  0xc(%rsp),%xmm0
  mulss  %xmm5,%xmm0
  movss  0x14(%rsp),%xmm2
  mulss  %xmm5,%xmm2
  movss  0x10(%rsp),%xmm1
  mulss  %xmm5,%xmm1
  call   <noise3@plt>
  mulss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L9
L15:
  movss  0x4(%rsp),%xmm0
  movd   %ebp,%xmm4
  divss  %xmm4,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    D17(%rip),%ebp
  jmp    L15
```

tool_calls: name: read_data
arguments: data_tag: D17
type: byte[4]

tool: {"D17": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fbm_noise3(float x, float y, float z, int octaves, float persistence, float lacunarity) {
  float freq = 1.0f;
  float amp = 1.0f;
  float max = 1.0f;
  float total = noise3(x, y, z);
  int i;
  for (i = 1; i < octaves; ++i) {
    freq *= lacunarity;
    amp *= persistence;
    max += amp;
    total += noise3(x * freq, y * freq, z * freq) * amp;
  }
  return total / max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fbm_noise3>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x38,%rsp
  movss  %xmm0,0x1c(%rsp)
  movss  %xmm1,0x20(%rsp)
  movss  %xmm2,0x24(%rsp)
  movss  %xmm3,0x28(%rsp)
  movss  %xmm4,0x2c(%rsp)
  call   <noise3@plt>
  movaps %xmm0,%xmm5
  cmp    $0x1,%ebp
  jle    L10
  movss  D4(%rip),%xmm6
  mov    $0x1,%ebx
  movaps %xmm6,%xmm4
  movaps %xmm6,%xmm3
  xchg   %ax,%ax
L9:
  mulss  0x2c(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm0
  add    $0x1,%ebx
  movss  %xmm5,0x18(%rsp)
  mulss  0x28(%rsp),%xmm4
  movss  0x24(%rsp),%xmm2
  movss  0x20(%rsp),%xmm1
  mulss  %xmm3,%xmm0
  movss  %xmm3,0xc(%rsp)
  mulss  %xmm3,%xmm2
  addss  %xmm4,%xmm6
  movss  %xmm4,0x14(%rsp)
  mulss  %xmm3,%xmm1
  movss  %xmm6,0x10(%rsp)
  call   <noise3@plt>
  movss  0x14(%rsp),%xmm4
  cmp    %ebx,%ebp
  movss  0x18(%rsp),%xmm5
  movss  0xc(%rsp),%xmm3
  movss  0x10(%rsp),%xmm6
  mulss  %xmm4,%xmm0
  addss  %xmm0,%xmm5
  jne    L9
  divss  %xmm6,%xmm5
L10:
  add    $0x38,%rsp
  movaps %xmm5,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fbm_noise3(float x, float y, float z, int octaves, float persistence, float lacunarity) {
  float freq = 1.0f;
  float amp = 1.0f;
  float max = 1.0f;
  float total = noise3(x, y, z);
  int i;
  for (i = 1; i < octaves; ++i) {
    freq *= lacunarity;
    amp *= persistence;
    max += amp;
    total += noise3(x * freq, y * freq, z * freq) * amp;
  }
  return total / max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fbm_noise3>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x38,%rsp
  movss  %xmm0,0x1c(%rsp)
  movss  %xmm1,0x20(%rsp)
  movss  %xmm2,0x24(%rsp)
  movss  %xmm3,0x28(%rsp)
  movss  %xmm4,0x2c(%rsp)
  call   <noise3@plt>
  movaps %xmm0,%xmm5
  cmp    $0x1,%ebp
  jle    L7
  movss  D7(%rip),%xmm6
  mov    $0x1,%ebx
  movaps %xmm6,%xmm4
  movaps %xmm6,%xmm3
  xchg   %ax,%ax
L0:
  mulss  0x2c(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm0
  add    $0x1,%ebx
  movss  %xmm5,0x18(%rsp)
  mulss  0x28(%rsp),%xmm4
  movss  0x24(%rsp),%xmm2
  movss  0x20(%rsp),%xmm1
  mulss  %xmm3,%xmm0
  movss  %xmm3,0xc(%rsp)
  mulss  %xmm3,%xmm2
  addss  %xmm4,%xmm6
  movss  %xmm4,0x14(%rsp)
  mulss  %xmm3,%xmm1
  movss  %xmm6,0x10(%rsp)
  call   <noise3@plt>
  movss  0x14(%rsp),%xmm4
  cmp    %ebx,%ebp
  movss  0x18(%rsp),%xmm5
  movss  0xc(%rsp),%xmm3
  movss  0x10(%rsp),%xmm6
  mulss  %xmm4,%xmm0
  addss  %xmm0,%xmm5
  jne    L0
  divss  %xmm6,%xmm5
L7:
  add    $0x38,%rsp
  movaps %xmm5,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float fbm_noise3(float x, float y, float z, int octaves, float persistence, float lacunarity) {
  float freq = 1.0f;
  float amp = 1.0f;
  float max = 1.0f;
  float total = noise3(x, y, z);
  int i;
  for (i = 1; i < octaves; ++i) {
    freq *= lacunarity;
    amp *= persistence;
    max += amp;
    total += noise3(x * freq, y * freq, z * freq) * amp;
  }
  return total / max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trio_signbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <trio_fpclassify_and_signbit@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int trio_signbit(double number) {
  int is_negative;
  (void)trio_fpclassify_and_signbit(number, &is_negative);
  return is_negative;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trio_signbit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <trio_fpclassify_and_signbit@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int trio_signbit(double number) {
  int is_negative;
  (void)trio_fpclassify_and_signbit(number, &is_negative);
  return is_negative;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trio_signbit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <trio_fpclassify_and_signbit@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int trio_signbit(double number) {
  int is_negative;
  (void)trio_fpclassify_and_signbit(number, &is_negative);
  return is_negative;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trio_signbit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <trio_fpclassify_and_signbit@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int trio_signbit(double number) {
  int is_negative;
  (void)trio_fpclassify_and_signbit(number, &is_negative);
  return is_negative;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hex_get_from_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x30(%rbp)
  jge    L11
  mov    $0xffffffff,%eax
  jmp    L6
L11:
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L32:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <hex_get_from_bcd@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x14(%rbp)
  jl     L32
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int hex_get_from_char(unsigned char *in, int in_len, unsigned char *hex_out_buf, int hex_out_buf_len) {
  int i;
  if (in_len / 2 > hex_out_buf_len) {
    return -1;
  }
  for (i = 0; i < in_len / 2; i++) {
    hex_out_buf[i] = hex_get_from_bcd(&in[i * 2]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex_get_from_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  add    %esi,%r12d
  sar    %r12d
  cmp    %ecx,%r12d
  jg     L47
  mov    %rdx,%r13
  cmp    $0x1,%esi
  jle    L6
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L7:
  mov    %rbp,%rdi
  call   <hex_get_from_bcd@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  add    $0x2,%rbp
  cmp    %ebx,%r12d
  jg     L7
  mov    $0x0,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    $0xffffffff,%eax
  jmp    L19
L6:
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
int hex_get_from_char(unsigned char *in, int in_len, unsigned char *hex_out_buf, int hex_out_buf_len) {
  int i;
  if (in_len / 2 > hex_out_buf_len) {
    return -1;
  }
  for (i = 0; i < in_len / 2; i++) {
    hex_out_buf[i] = hex_get_from_bcd(&in[i * 2]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hex_get_from_char>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    %ecx,%r12d
  jg     L26
  mov    %rdx,%r13
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  cmp    $0x1,%esi
  jle    L3
  nopl   (%rax)
L1:
  mov    %rbp,%rdi
  add    $0x2,%rbp
  call   <hex_get_from_bcd@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L1
L3:
  xor    %eax,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int hex_get_from_char(unsigned char *in, int in_len, unsigned char *hex_out_buf, int hex_out_buf_len) {
  int i;
  if (in_len / 2 > hex_out_buf_len) {
    return -1;
  }
  for (i = 0; i < in_len / 2; i++) {
    hex_out_buf[i] = hex_get_from_bcd(&in[i * 2]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_get_from_char>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    %ecx,%r12d
  jg     L28
  mov    %rdx,%r13
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  cmp    $0x1,%esi
  jle    L0
  nopl   (%rax)
L31:
  mov    %rbp,%rdi
  add    $0x2,%rbp
  call   <hex_get_from_bcd@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L31
L0:
  xor    %eax,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int hex_get_from_char(unsigned char *in, int in_len, unsigned char *hex_out_buf, int hex_out_buf_len) {
  int i;
  if (in_len / 2 > hex_out_buf_len) {
    return -1;
  }
  for (i = 0; i < in_len / 2; i++) {
    hex_out_buf[i] = hex_get_from_bcd(&in[i * 2]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<restar_1_svc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,D10(%rip)
  lea    D10(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *restar_1_svc(int a, int b, struct svc_req *rqstp) {
  static int r;
  r = a - b;
  return (&r);
}
```
user: What is the c source code of the assembly code below?

```asm
<restar_1_svc>:
  endbr64
  sub    %esi,%edi
  mov    %edi,D12(%rip)
  lea    D12(%rip),%rax
  ret
```

assistant: ```c
int *restar_1_svc(int a, int b, struct svc_req *rqstp) {
  static int r;
  r = a - b;
  return (&r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<restar_1_svc>:
  endbr64
  sub    %esi,%edi
  lea    D19(%rip),%rax
  mov    %edi,D7(%rip)
  ret
```

assistant: ```c
int *restar_1_svc(int a, int b, struct svc_req *rqstp) {
  static int r;
  r = a - b;
  return (&r);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<restar_1_svc>:
  endbr64
  sub    %esi,%edi
  lea    D6(%rip),%rax
  mov    %edi,D9(%rip)
  ret
```

assistant: ```c
int *restar_1_svc(int a, int b, struct svc_req *rqstp) {
  static int r;
  r = a - b;
  return (&r);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xf4000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x260,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xf4250(%rbp),%rax
  mov    $0xf4241,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0xf4258(%rbp)
  jmp    L19
L58:
  mov    -0xf4258(%rbp),%eax
  cltq
  movzbl -0xf4250(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L46
  mov    -0xf4258(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  mov    -0xf4258(%rbp),%eax
  mov    %eax,%edi
  call   <generate_next_num@plt>
  mov    %eax,-0xf4254(%rbp)
  cmpl   $0xf4240,-0xf4254(%rbp)
  jg     L13
  mov    -0xf4254(%rbp),%eax
  cltq
  movb   $0x1,-0xf4250(%rbp,%rax,1)
L13:
  addl   $0x1,-0xf4258(%rbp)
L19:
  cmpl   $0xf4240,-0xf4258(%rbp)
  jle    L58
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %u


assistant: ```c
int main() {
  char check_self_num[1000001];
  int i, next;
  memset(&check_self_num[0], 0x0, sizeof(char) * 1000001);
  for (i = 1; i < 1000001; i++) {
    if (check_self_num[i] == 0x0) {
      printf("%u\n", i);
    }
    next = generate_next_num(i);
    if (next < 1000001) {
      check_self_num[next] = 0x1;
    }
  }
  return 0;
}
```